From c9defa4ce8a06fd2491b1ca1f7bdc0ba0dd2cc87 Mon Sep 17 00:00:00 2001 From: ganler Date: Sat, 19 Oct 2024 23:16:20 -0500 Subject: [PATCH] upload evalperf results --- ...i--Yi-Coder-9B-Chat_vllm_temp_1.0_evalperf_results.brief.json | 1 + ...wen2.5-14B-Instruct_vllm_temp_1.0_evalperf_results.brief.json | 1 + ...wen2.5-32B-Instruct_vllm_temp_1.0_evalperf_results.brief.json | 1 + ...wen2.5-72B-Instruct_vllm_temp_1.0_evalperf_results.brief.json | 1 + ...Qwen2.5-7B-Instruct_vllm_temp_1.0_evalperf_results.brief.json | 1 + ...5-Coder-7B-Instruct_vllm_temp_1.0_evalperf_results.brief.json | 1 + ...er-V2-Lite-Instruct_vllm_temp_1.0_evalperf_results.brief.json | 1 + ...-coder-33b-instruct_vllm_temp_1.0_evalperf_results.brief.json | 1 + ...coder-6.7b-instruct_vllm_temp_1.0_evalperf_results.brief.json | 1 + .../deepseek-chat_openai_temp_1.0_evalperf_results.brief.json | 1 + ...ini-1.5-flash-002_google_temp_1.0_evalperf_results.brief.json | 1 + ...emini-1.5-pro-002_google_temp_1.0_evalperf_results.brief.json | 1 + ...gle--gemma-2-27b-it_vllm_temp_1.0_evalperf_results.brief.json | 1 + ...ogle--gemma-2-9b-it_vllm_temp_1.0_evalperf_results.brief.json | 1 + ...gpt-4o-2024-08-06_openai_temp_1.0_evalperf_results.brief.json | 1 + ...o-mini-2024-07-18_openai_temp_1.0_evalperf_results.brief.json | 1 + ...Magicoder-S-DS-6.7B_vllm_temp_1.0_evalperf_results.brief.json | 1 + ...ma-3.1-70B-Instruct_vllm_temp_1.0_evalperf_results.brief.json | 1 + ...ama-3.1-8B-Instruct_vllm_temp_1.0_evalperf_results.brief.json | 1 + ...-Codestral-22B-v0.1_vllm_temp_1.0_evalperf_results.brief.json | 1 + ...Large-Instruct-2407_vllm_temp_1.0_evalperf_results.brief.json | 1 + ...-Nemo-Instruct-2407_vllm_temp_1.0_evalperf_results.brief.json | 1 + ...Small-Instruct-2409_vllm_temp_1.0_evalperf_results.brief.json | 1 + 23 files changed, 23 insertions(+) create mode 100644 results/evalperf/01-ai--Yi-Coder-9B-Chat_vllm_temp_1.0_evalperf_results.brief.json create mode 100644 results/evalperf/Qwen--Qwen2.5-14B-Instruct_vllm_temp_1.0_evalperf_results.brief.json create mode 100644 results/evalperf/Qwen--Qwen2.5-32B-Instruct_vllm_temp_1.0_evalperf_results.brief.json create mode 100644 results/evalperf/Qwen--Qwen2.5-72B-Instruct_vllm_temp_1.0_evalperf_results.brief.json create mode 100644 results/evalperf/Qwen--Qwen2.5-7B-Instruct_vllm_temp_1.0_evalperf_results.brief.json create mode 100644 results/evalperf/Qwen--Qwen2.5-Coder-7B-Instruct_vllm_temp_1.0_evalperf_results.brief.json create mode 100644 results/evalperf/deepseek-ai--DeepSeek-Coder-V2-Lite-Instruct_vllm_temp_1.0_evalperf_results.brief.json create mode 100644 results/evalperf/deepseek-ai--deepseek-coder-33b-instruct_vllm_temp_1.0_evalperf_results.brief.json create mode 100644 results/evalperf/deepseek-ai--deepseek-coder-6.7b-instruct_vllm_temp_1.0_evalperf_results.brief.json create mode 100644 results/evalperf/deepseek-chat_openai_temp_1.0_evalperf_results.brief.json create mode 100644 results/evalperf/gemini-1.5-flash-002_google_temp_1.0_evalperf_results.brief.json create mode 100644 results/evalperf/gemini-1.5-pro-002_google_temp_1.0_evalperf_results.brief.json create mode 100644 results/evalperf/google--gemma-2-27b-it_vllm_temp_1.0_evalperf_results.brief.json create mode 100644 results/evalperf/google--gemma-2-9b-it_vllm_temp_1.0_evalperf_results.brief.json create mode 100644 results/evalperf/gpt-4o-2024-08-06_openai_temp_1.0_evalperf_results.brief.json create mode 100644 results/evalperf/gpt-4o-mini-2024-07-18_openai_temp_1.0_evalperf_results.brief.json create mode 100644 results/evalperf/ise-uiuc--Magicoder-S-DS-6.7B_vllm_temp_1.0_evalperf_results.brief.json create mode 100644 results/evalperf/meta-llama--Llama-3.1-70B-Instruct_vllm_temp_1.0_evalperf_results.brief.json create mode 100644 results/evalperf/meta-llama--Llama-3.1-8B-Instruct_vllm_temp_1.0_evalperf_results.brief.json create mode 100644 results/evalperf/mistralai--Codestral-22B-v0.1_vllm_temp_1.0_evalperf_results.brief.json create mode 100644 results/evalperf/mistralai--Mistral-Large-Instruct-2407_vllm_temp_1.0_evalperf_results.brief.json create mode 100644 results/evalperf/mistralai--Mistral-Nemo-Instruct-2407_vllm_temp_1.0_evalperf_results.brief.json create mode 100644 results/evalperf/mistralai--Mistral-Small-Instruct-2409_vllm_temp_1.0_evalperf_results.brief.json diff --git a/results/evalperf/01-ai--Yi-Coder-9B-Chat_vllm_temp_1.0_evalperf_results.brief.json b/results/evalperf/01-ai--Yi-Coder-9B-Chat_vllm_temp_1.0_evalperf_results.brief.json new file mode 100644 index 0000000..b42ab99 --- /dev/null +++ b/results/evalperf/01-ai--Yi-Coder-9B-Chat_vllm_temp_1.0_evalperf_results.brief.json @@ -0,0 +1 @@ +{"date": "2024-10-19 16:28", "config": {"n_samples": 100, "temperature": 1.0, "min_correct": 10, "max_profile": 20}, "summary": {"dps": 83.60305818801254, "dps_norm": 78.76801867108128, "pass@1": 78.80508474576271}, "eval": {"HumanEval/9": {"dps": 70.56782334384857, "dps_norm": 65.55555555555556, "pass@1": 100.0, "profiled": [{"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n if not numbers:\n return []\n\n result = [numbers[0]]\n max_num = numbers[0]\n\n for number in numbers[1:]:\n max_num = max(number, max_num)\n result.append(max_num)\n\n return result", "matching_cluster_idx": 4}, {"solution": "from typing import List, Tuple\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" \n From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n\n max_numbers = [numbers[0]]\n\n for num in numbers[1:]:\n max_numbers.append(max(max_numbers[-1], num))\n\n return max_numbers", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n max_nums = []\n max_so_far = float('-inf')\n\n for num in numbers:\n max_so_far = max(max_so_far, num)\n max_nums.append(max_so_far)\n \n return max_nums", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n \"\"\"\n max_numbers = []\n max_number = float('-inf')\n for number in numbers:\n if number > max_number:\n max_number = number\n max_numbers.append(max_number)\n return max_numbers", "matching_cluster_idx": 8}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n max_list = []\n max_num = float('-inf')\n for number in numbers:\n if number > max_num:\n max_num = number\n max_list.append(max_num)\n return max_list", "matching_cluster_idx": 8}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n\n if not numbers:\n return []\n\n max_numbers = [numbers[0]]\n for num in numbers[1:]:\n max_numbers.append(max(num, max_numbers[-1]))\n\n return max_numbers", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n \"\"\"\n result = []\n max_num = float('-inf')\n\n for num in numbers:\n max_num = max(max_num, num)\n result.append(max_num)\n\n return result", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n \"\"\"\n if not numbers:\n return []\n \n max_values = [numbers[0]]\n \n for i in range(1, len(numbers)):\n max_values.append(max(max_values[-1], numbers[i]))\n \n return max_values", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n max_list = []\n if numbers:\n max_so_far = numbers[0]\n max_list.append(max_so_far)\n for num in numbers[1:]:\n max_so_far = max(max_so_far, num)\n max_list.append(max_so_far)\n return max_list", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n \"\"\"\n\n # Check if the input list is empty\n if not numbers:\n return []\n\n # Initialize rolling_max list with the first element of numbers\n rolling_max_list = [numbers[0]]\n\n # Iterate over the rest of the numbers\n for i in range(1, len(numbers)):\n # If the current number is larger than the last element in the rolling_max_list\n if numbers[i] > rolling_max_list[-1]:\n # Add it to the rolling_max_list\n rolling_max_list.append(numbers[i])\n else:\n # Otherwise, add the last element again\n rolling_max_list.append(rolling_max_list[-1])\n\n return rolling_max_list", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n result = []\n max_num = float('-inf')\n for num in numbers:\n max_num = max(num, max_num)\n result.append(max_num)\n return result", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n \"\"\"\n if not numbers: # if the input list is empty, return an empty list\n return []\n\n max_list = []\n max_val = numbers[0]\n\n for num in numbers:\n max_val = max(num, max_val)\n max_list.append(max_val)\n\n return max_list", "matching_cluster_idx": 4}, {"solution": "from typing import List, Tuple\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n result = []\n max_num = float('-inf')\n\n for number in numbers:\n max_num = max(max_num, number)\n result.append(max_num)\n\n return result", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n max_numbers = []\n max_val = float('-inf')\n \n for num in numbers:\n max_val = max(max_val, num)\n max_numbers.append(max_val)\n\n return max_numbers", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n max_list = []\n max_value = float('-inf')\n for num in numbers:\n max_value = max(num, max_value)\n max_list.append(max_value)\n return max_list", "matching_cluster_idx": 4}, {"solution": "from typing import List, Tuple\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n rolling_max_list = []\n for i, num in enumerate(numbers):\n if i == 0:\n rolling_max_list.append(num)\n else:\n rolling_max_list.append(max(num, rolling_max_list[-1]))\n return rolling_max_list", "matching_cluster_idx": 4}, {"solution": "from typing import List, Tuple\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if len(numbers) == 0:\n return []\n \n max_list = [numbers[0]]\n max_val = numbers[0]\n \n for num in numbers[1:]:\n max_val = max(max_val, num)\n max_list.append(max_val)\n\n return max_list", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n max_list = []\n max_value = None\n\n for num in numbers:\n if max_value is None:\n max_value = num\n else:\n max_value = max(max_value, num)\n max_list.append(max_value)\n\n return max_list", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n\n result = [numbers[0]]\n max_num = numbers[0]\n\n for num in numbers[1:]:\n if num > max_num:\n max_num = num\n result.append(max_num)\n\n return result", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef rolling_max(numbers: List[int]) -> List[int]:\n max_nums = []\n max_num = float('-inf')\n\n for num in numbers:\n if num > max_num:\n max_num = num\n max_nums.append(max_num)\n\n return max_nums", "matching_cluster_idx": 8}]}, "HumanEval/0": {"dps": 50.058139534883715, "dps_norm": 56.42857142857143, "pass@1": 99.0, "profiled": [{"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n numbers.sort() # Sort the list in ascending order\n \n # Check if adjacent numbers are closer than the threshold\n for i in range(len(numbers) - 1):\n if numbers[i + 1] - numbers[i] < threshold:\n return True\n \n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n numbers.sort()\n for i in range(1, len(numbers)):\n if numbers[i] - numbers[i-1] < threshold:\n return True\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\nimport numpy as np\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n sorted_numbers = sorted(numbers)\n for i in range(1, len(sorted_numbers)):\n if sorted_numbers[i] - sorted_numbers[i - 1] < threshold:\n return True\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n \n numbers.sort()\n\n for i in range(1, len(numbers)):\n if numbers[i] - numbers[i - 1] < threshold:\n return True\n\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n numbers.sort()\n for i in range(1, len(numbers)):\n if numbers[i] - numbers[i - 1] < threshold:\n return True\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n numbers.sort()\n for i in range(1, len(numbers)):\n if numbers[i] - numbers[i - 1] < threshold:\n return True\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n \"\"\"\n numbers.sort()\n for i in range(len(numbers) - 1):\n if numbers[i+1] - numbers[i] < threshold:\n return True\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n numbers.sort()\n for i in range(1, len(numbers)):\n if numbers[i] - numbers[i-1] < threshold:\n return True\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n \"\"\"\n numbers.sort()\n for i in range(1, len(numbers)):\n if numbers[i] - numbers[i - 1] < threshold:\n return True\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n numbers.sort()\n for i in range(1, len(numbers)):\n if numbers[i] - numbers[i-1] < threshold:\n return True\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n numbers.sort()\n for i in range(1, len(numbers)):\n if numbers[i] - numbers[i-1] < threshold:\n return True\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\nimport numpy as np\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n \"\"\"\n sorted_numbers = sorted(numbers)\n for i in range(len(sorted_numbers)-1):\n if np.abs(sorted_numbers[i+1] - sorted_numbers[i]) < threshold:\n return True\n return False", "matching_cluster_idx": 2}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n numbers.sort()\n for i in range(1, len(numbers)):\n if numbers[i] - numbers[i-1] < threshold:\n return True\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\nimport numpy as np\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n \"\"\"\n\n n = len(numbers)\n # sort the list\n numbers.sort()\n \n # check for every consecutive pair if they are closer to each other than the threshold\n for i in range(1, n):\n if numbers[i] - numbers[i-1] < threshold:\n return True\n \n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n numbers.sort()\n for i in range(1, len(numbers)):\n if numbers[i] - numbers[i-1] < threshold:\n return True\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\nimport itertools\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n \n # if the list contains less than 2 numbers, we return False by default\n if len(numbers) < 2:\n return False\n\n # sort the numbers\n numbers.sort()\n\n # check pairs of neighbouring numbers in the sorted list\n for num1, num2 in itertools.pairwise(numbers):\n if abs(num1 - num2) < threshold:\n return True\n\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n numbers.sort()\n for i in range(1, len(numbers)):\n if numbers[i] - numbers[i - 1] < threshold:\n return True\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n \"\"\"\n numbers.sort()\n for i in range(1, len(numbers)):\n if numbers[i] - numbers[i - 1] < threshold:\n return True\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n numbers.sort()\n for i in range(1, len(numbers)):\n if numbers[i] - numbers[i-1] < threshold:\n return True\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n numbers.sort()\n \n for i in range(1, len(numbers)):\n if numbers[i] - numbers[i - 1] < threshold:\n return True\n \n return False", "matching_cluster_idx": 3}]}, "HumanEval/4": {"dps": 25.838607594936708, "dps_norm": 70.83333333333334, "pass@1": 98.0, "profiled": [{"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n mean = sum(numbers) / len(numbers)\n differences = [abs(x - mean) for x in numbers]\n mad = sum(differences) / len(differences)\n return mad", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n mean = sum(numbers) / len(numbers)\n abs_diffs = [abs(x - mean) for x in numbers]\n mad = sum(abs_diffs) / len(abs_diffs)\n return mad", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n mean = sum(numbers) / len(numbers)\n abs_diffs = [abs(num - mean) for num in numbers]\n return sum(abs_diffs) / len(abs_diffs)", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n mean = sum(numbers) / len(numbers)\n return sum(abs(x - mean) for x in numbers) / len(numbers)", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n mean = sum(numbers) / len(numbers)\n abs_diff = [abs(x - mean) for x in numbers]\n mad = sum(abs_diff) / len(abs_diff)\n return mad", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n n = len(numbers)\n x_mean = sum(numbers) / n\n return sum(abs(x - x_mean) for x in numbers) / n", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n \n # Calculate the mean of the list\n mean = sum(numbers) / len(numbers)\n\n # Calculate the absolute differences from the mean\n differences = [abs(num - mean) for num in numbers]\n\n # Return the mean of the differences\n return sum(differences) / len(differences)", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n # calculate the mean of the numbers\n mean = sum(numbers) / len(numbers)\n\n # calculate absolute differences from the mean\n differences = [abs(x - mean) for x in numbers]\n\n # calculate the mean of these differences, which is MAD\n mad = sum(differences) / len(differences)\n\n return mad", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" \n For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n mean = sum(numbers) / len(numbers)\n return sum(abs(x - mean) for x in numbers) / len(numbers)", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\"\n For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n # Compute the mean of the list\n mean_val = sum(numbers) / len(numbers)\n \n # Compute absolute differences between each element and mean\n diffs = [abs(num - mean_val) for num in numbers]\n \n # Return the mean value of those absolute differences as MAD\n return sum(diffs) / len(diffs)", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n\n # check if the list is empty\n if not numbers:\n return 0.0\n\n # calculate the mean of the numbers\n mean = sum(numbers) / len(numbers)\n\n # calculate the absolute differences from the mean\n differences = [abs(num - mean) for num in numbers]\n\n # return the mean of the absolute differences as the MAD\n return sum(differences) / len(differences)", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if len(numbers) == 0:\n raise ValueError(\"numbers must not be an empty list\")\n \n mean = sum(numbers) / len(numbers)\n differences = [abs(x - mean) for x in numbers]\n mad = sum(differences) / len(differences)\n\n return mad", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n\n # Check if the list is empty\n if not numbers:\n return 0.0\n\n # Calculate the mean\n mean = sum(numbers) / len(numbers)\n\n # Calculate absolute differences\n differences = [abs(x - mean) for x in numbers]\n\n # Calculate Mean Absolute Deviation\n mad = sum(differences) / len(differences)\n\n return mad", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n mean = sum(numbers) / len(numbers)\n return sum(abs(x - mean) for x in numbers) / len(numbers)", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n mean = sum(numbers) / len(numbers)\n deviations = [abs(num - mean) for num in numbers]\n mad = sum(deviations) / len(deviations)\n return mad", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n \n # Calculate the mean of the list of numbers\n mean = sum(numbers) / len(numbers)\n \n # Calculate the absolute differences between each number and the mean\n differences = [abs(num - mean) for num in numbers]\n \n # Calculate the mean absolute deviation and return it\n mad = sum(differences) / len(differences)\n \n return mad", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n # Calculate the mean\n mean = sum(numbers) / len(numbers)\n \n # Calculate absolute differences and their average\n abs_diffs = [abs(x - mean) for x in numbers]\n mad = sum(abs_diffs) / len(abs_diffs)\n \n return mad", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n # compute the mean of the list\n mean = sum(numbers) / len(numbers)\n \n # compute absolute differences from the mean\n diffs = [abs(x - mean) for x in numbers]\n \n # return the mean of the absolute differences\n return sum(diffs) / len(diffs)", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n mean = sum(numbers) / len(numbers)\n abs_diffs = [abs(x - mean) for x in numbers]\n mad = sum(abs_diffs) / len(abs_diffs)\n return mad", "matching_cluster_idx": 3}, {"solution": "from typing import List\nimport statistics\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n mean = statistics.mean(numbers)\n abs_diffs = [abs(num - mean) for num in numbers]\n return statistics.mean(abs_diffs)", "matching_cluster_idx": 0}]}, "HumanEval/16": {"dps": 96.74418604651163, "dps_norm": 97.22222222222223, "pass@1": 99.0, "profiled": [{"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n return len(set(string.lower()))", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n return len(set(string.lower()))", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n return len(set(string.lower()))", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n return len(set(string.lower()))", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n return len(set(string.lower()))", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n return len(set(string.lower()))", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n return len(set(string.lower()))", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lower case to disregard case\n lower_string = string.lower()\n # Convert the string to a set to remove duplicates, then return the length\n distinct_chars = set(lower_string)\n return len(distinct_chars)", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n return len(set(string.lower()))", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n return len(set(string.lower()))", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n return len(set(string.lower()))", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n \"\"\"\n return len(set(string.lower()))", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n return len(set(string.lower()))", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n return len(set(string.lower()))", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n return len(set(string.lower()))", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n distinct_chars = set()\n for char in string.lower():\n distinct_chars.add(char)\n return len(distinct_chars)", "matching_cluster_idx": 3}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n return len(set(string.lower()))", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n return len(set(string.lower()))", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n return len(set(string.lower()))", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n return len(set(string.lower()))", "matching_cluster_idx": 8}]}, "HumanEval/20": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n if len(numbers) < 2:\n raise ValueError(\"Input list should contain at least two numbers.\")\n numbers.sort()\n min_diff = float('inf')\n result = (None, None)\n for i in range(len(numbers)-1):\n diff = numbers[i+1] - numbers[i]\n if diff < min_diff:\n min_diff = diff\n result = (numbers[i], numbers[i+1])\n return result", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n sorted_numbers = sorted(numbers)\n min_diff = float('inf')\n res = None\n\n for i in range(1, len(sorted_numbers)):\n diff = sorted_numbers[i] - sorted_numbers[i-1]\n if diff < min_diff:\n min_diff = diff\n res = (sorted_numbers[i-1], sorted_numbers[i])\n\n return res", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n \"\"\"\n if len(numbers) < 2:\n raise ValueError(\"At least two numbers are required.\")\n \n numbers.sort()\n \n min_diff = float('inf')\n result = None\n \n for i in range(len(numbers) - 1):\n diff = numbers[i + 1] - numbers[i]\n if diff < min_diff:\n min_diff = diff\n result = (numbers[i], numbers[i + 1])\n \n return result", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n numbers.sort()\n min_diff = float('inf')\n result = (None, None)\n for i in range(1, len(numbers)):\n if numbers[i] - numbers[i-1] < min_diff:\n min_diff = numbers[i] - numbers[i-1]\n result = (numbers[i-1], numbers[i])\n return result", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n # sort the list in ascending order\n numbers.sort()\n \n # initialize the minimum difference to be the maximum float number\n min_diff = float('inf')\n result = (None, None)\n \n # for each pair of numbers\n for i in range(1, len(numbers)):\n # calculate the difference\n diff = numbers[i] - numbers[i-1]\n \n # if the difference is less than the minimum difference found so far,\n # then update the minimum difference and save the pair of numbers\n if diff < min_diff:\n min_diff = diff\n result = (numbers[i-1], numbers[i])\n \n return result", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n if len(numbers) < 2:\n raise ValueError(\"The list of numbers must contain at least two elements.\")\n \n numbers.sort()\n \n min_diff = float('inf')\n result = None\n\n for i in range(1, len(numbers)):\n diff = numbers[i] - numbers[i - 1]\n if diff < min_diff:\n min_diff = diff\n result = (numbers[i - 1], numbers[i])\n\n return result", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n numbers.sort()\n min_diff = float('inf')\n closest_pair = None\n for i in range(len(numbers) - 1):\n diff = numbers[i + 1] - numbers[i]\n if diff < min_diff:\n min_diff = diff\n closest_pair = (numbers[i], numbers[i + 1])\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n \"\"\"\n # First, sort the numbers.\n numbers.sort()\n\n # Initialize smallest_difference to be the difference between the first two numbers,\n # and closest_pair to be the first two numbers.\n smallest_difference = numbers[1] - numbers[0]\n closest_pair = (numbers[0], numbers[1])\n\n # Iterate over the pairs of numbers in the list.\n for i in range(1, len(numbers) - 1):\n difference = numbers[i+1] - numbers[i]\n if difference < smallest_difference:\n smallest_difference = difference\n closest_pair = (numbers[i], numbers[i+1])\n\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n numbers.sort()\n min_diff = float('inf')\n result = None\n\n for i in range(1, len(numbers)):\n diff = numbers[i] - numbers[i-1]\n if diff < min_diff:\n min_diff = diff\n result = (numbers[i-1], numbers[i])\n\n return result", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n numbers.sort()\n min_diff = float('inf')\n result = None\n for i in range(1, len(numbers)):\n if numbers[i] - numbers[i - 1] < min_diff:\n min_diff = numbers[i] - numbers[i - 1]\n result = (numbers[i - 1], numbers[i])\n return result", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n sorted_numbers = sorted(numbers)\n min_diff = float('inf')\n result = None\n\n for i in range(len(sorted_numbers) - 1):\n diff = sorted_numbers[i + 1] - sorted_numbers[i]\n if diff < min_diff:\n min_diff = diff\n result = (sorted_numbers[i], sorted_numbers[i + 1])\n\n return result", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n # Sort the list in increasing order\n numbers.sort()\n \n # Initially, set closest pair as the first two numbers\n closest_pair = (numbers[0], numbers[1])\n min_diff = numbers[1] - numbers[0]\n\n # Iterate over the list, starting from the second number\n for i in range(1, len(numbers) - 1):\n # Compute the difference between the current number and the next one\n diff = numbers[i + 1] - numbers[i]\n\n # If the difference is smaller than the current smallest difference,\n # update the closest pair and the minimum difference\n if diff < min_diff:\n closest_pair = (numbers[i], numbers[i + 1])\n min_diff = diff\n\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n # Sort the list in ascending order\n sorted_numbers = sorted(numbers)\n # Initialize minimum difference and closest elements\n min_diff = float('inf')\n closest_elements = None\n # Iterate over pairs of elements\n for i in range(1, len(sorted_numbers)):\n # Calculate the difference between current pair\n diff = sorted_numbers[i] - sorted_numbers[i - 1]\n # If the difference is smaller than the current minimum, update closest elements\n if diff < min_diff:\n min_diff = diff\n closest_elements = (sorted_numbers[i - 1], sorted_numbers[i])\n return closest_elements", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n \"\"\"\n # Sort the list\n numbers.sort()\n\n # Initialize the minimum difference and the closest pair\n min_diff = float('inf')\n closest_pair = None\n\n # Traverse the list to find the closest pair\n for i in range(1, len(numbers)):\n diff = numbers[i] - numbers[i-1]\n if diff < min_diff:\n min_diff = diff\n closest_pair = (numbers[i-1], numbers[i])\n\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n numbers.sort()\n min_diff = float('inf')\n result = None\n\n for i in range(len(numbers) - 1):\n diff = numbers[i + 1] - numbers[i]\n if diff < min_diff:\n min_diff = diff\n result = (numbers[i], numbers[i + 1])\n\n return result", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n assert len(numbers) >= 2, \"List of numbers must contain at least two elements\"\n\n # Sort the numbers\n numbers.sort()\n\n # Initialize minimum difference and closest pair\n min_diff = float('inf')\n closest_pair = (None, None)\n\n # Scan through the list to find the closest pair\n for i in range(1, len(numbers)):\n diff = numbers[i] - numbers[i-1]\n if diff < min_diff:\n min_diff = diff\n closest_pair = (numbers[i-1], numbers[i])\n\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n sorted_numbers = sorted(numbers)\n diff = float('inf')\n result = (None, None)\n for i in range(len(sorted_numbers)-1):\n if sorted_numbers[i+1] - sorted_numbers[i] < diff:\n diff = sorted_numbers[i+1] - sorted_numbers[i]\n result = (sorted_numbers[i], sorted_numbers[i+1])\n return result", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n numbers.sort()\n min_diff = float('inf')\n result = (None, None)\n for i in range(1, len(numbers)):\n diff = numbers[i] - numbers[i - 1]\n if diff < min_diff:\n min_diff = diff\n result = (numbers[i - 1], numbers[i])\n return result", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n # First we sort the list\n numbers.sort()\n\n # We initialize the closest pair with the first two elements\n closest_pair = (numbers[0], numbers[1])\n min_diff = abs(numbers[1] - numbers[0])\n\n # We iterate over the list to find any pair with smaller difference\n for i in range(1, len(numbers) - 1):\n diff = abs(numbers[i+1] - numbers[i])\n if diff < min_diff:\n min_diff = diff\n closest_pair = (numbers[i], numbers[i+1])\n\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n numbers.sort()\n diff = float('inf')\n result = (None, None)\n for i in range(1, len(numbers)):\n if numbers[i] - numbers[i-1] < diff:\n diff = numbers[i] - numbers[i-1]\n result = (numbers[i-1], numbers[i])\n return result", "matching_cluster_idx": 8}]}, "HumanEval/24": {"dps": 68.26530612244898, "dps_norm": 25.625, "pass@1": 99.0, "profiled": [{"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n for i in range(n - 1, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 1}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n for i in range(n-1, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 1}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n for i in range(n-1, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 1}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n for i in range(n-1, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 1}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n \"\"\"\n # check the input is a positive integer\n if not isinstance(n, int) or n < 1:\n raise ValueError(\"Input must be a positive integer.\")\n\n # start from n - 1 and iterate backwards until we find a divisor\n for i in range(n - 1, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 0}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n for i in range(n-1, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 1}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n for i in range(n - 1, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 1}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n for i in range(n-1, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 1}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n for i in range(n-1, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 1}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n for i in range(n - 1, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 1}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n for i in range(n-1, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 1}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n for i in range(n-1, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 1}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n for i in range(n-1, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 1}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n for i in range(n-1, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 1}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n for i in range(n - 1, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 1}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n # iterate from n-1 down to 1\n for i in range(n-1, 0, -1):\n # check if i is a divisor of n\n if n % i == 0:\n return i\n # if no divisor found (which is not possible for n>1), return None\n return None", "matching_cluster_idx": 0}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n for i in range(n-1, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 1}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n # Starting from half of the given number, decrement until a divisor is found\n for i in range(n // 2, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 4}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n for i in range(n - 1, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 1}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n for i in range(n - 1, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 1}]}, "HumanEval/26": {"dps": 66.6, "dps_norm": 76.25, "pass@1": 70.0, "profiled": [{"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n \"\"\"\n \n counts = {}\n for num in numbers:\n if num not in counts:\n counts[num] = 1\n else:\n counts[num] += 1\n\n unique_numbers = [num for num in numbers if counts[num] == 1]\n\n return unique_numbers", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n no_dups = []\n for num in numbers:\n if numbers.count(num) == 1:\n no_dups.append(num)\n return no_dups", "matching_cluster_idx": 0}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n num_counts = {}\n for num in numbers:\n if num in num_counts:\n num_counts[num] += 1\n else:\n num_counts[num] = 1\n\n unique_numbers = [num for num in numbers if num_counts[num] == 1]\n return unique_numbers", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n unique_numbers = []\n for num in numbers:\n if numbers.count(num) == 1:\n unique_numbers.append(num)\n return unique_numbers", "matching_cluster_idx": 0}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n numbers_count = {}\n result = []\n\n for number in numbers:\n if number in numbers_count:\n numbers_count[number] += 1\n else:\n numbers_count[number] = 1\n\n for number in numbers:\n if numbers_count[number] == 1:\n result.append(number)\n \n return result", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n # Create an empty dictionary to count the occurrences of each number\n num_dict = {}\n for num in numbers:\n if num in num_dict:\n num_dict[num] += 1\n else:\n num_dict[num] = 1\n\n # Create a new list with numbers that occur only once\n unique_nums = [num for num in numbers if num_dict[num] == 1]\n\n return unique_nums", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n occurrence = {}\n no_duplicates = []\n \n for num in numbers:\n if num not in occurrence:\n occurrence[num] = 1\n no_duplicates.append(num)\n else:\n occurrence[num] += 1\n if num in no_duplicates:\n no_duplicates.remove(num)\n \n return no_duplicates", "matching_cluster_idx": 2}, {"solution": "from typing import List\nfrom collections import Counter\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n num_counts = Counter(numbers)\n return [num for num in numbers if num_counts[num] == 1]", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n count_dict = {}\n result = []\n for num in numbers:\n if num not in count_dict:\n count_dict[num] = 1\n result.append(num)\n else:\n count_dict[num] += 1\n if num in result:\n result.remove(num)\n return result", "matching_cluster_idx": 2}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" \n From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n counts = {}\n result = []\n \n for num in numbers:\n if num in counts:\n counts[num] += 1\n else:\n counts[num] = 1\n result.append(num)\n\n return [num for num in result if counts[num] == 1]", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n result = []\n for num in numbers:\n if numbers.count(num) == 1:\n result.append(num)\n return result", "matching_cluster_idx": 0}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n \"\"\"\n # create a dictionary where key is the number and value is its frequency\n num_freq = {}\n\n for num in numbers:\n if num in num_freq:\n num_freq[num] += 1\n else:\n num_freq[num] = 1\n\n # create a new list with numbers that appear only once\n unique_numbers = [num for num in numbers if num_freq[num] == 1]\n\n return unique_numbers", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\"\n From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n \"\"\"\n counts = {}\n for num in numbers:\n if num in counts:\n counts[num] += 1\n else:\n counts[num] = 1\n\n return [num for num in numbers if counts[num] == 1]", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n count_dict = {}\n result = []\n for num in numbers:\n if num not in count_dict:\n count_dict[num] = 1\n result.append(num)\n else:\n count_dict[num] += 1\n if num in result:\n result.remove(num)\n return result", "matching_cluster_idx": 2}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n # initialize an empty dictionary to store numbers and their occurrences\n num_dict = {}\n # initialize an empty list to store numbers left after removal of duplicates\n numbers_left = []\n\n for num in numbers:\n # if the number has already been encountered\n if num in num_dict:\n # increment its count\n num_dict[num] += 1\n else:\n # add the number to the dictionary and its count as 1\n num_dict[num] = 1\n\n # iterate over the numbers in the input list\n for num in numbers:\n # if the number count in the dictionary is 1 (i.e., it occurs only once in the list)\n if num_dict[num] == 1:\n # add it to the list of numbers left\n numbers_left.append(num)\n\n # return the list of numbers left\n return numbers_left", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" \n From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n \"\"\"\n result = []\n for num in numbers:\n if numbers.count(num) == 1:\n result.append(num)\n return result", "matching_cluster_idx": 0}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n seen = {}\n result = []\n \n for num in numbers:\n if num not in seen:\n seen[num] = 1\n result.append(num)\n else:\n seen[num] += 1\n if seen[num] > 1 and num in result:\n result.remove(num)\n\n return result", "matching_cluster_idx": 2}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n occurrences = {}\n unique_numbers = []\n for num in numbers:\n if num not in occurrences:\n occurrences[num] = 1\n unique_numbers.append(num)\n else:\n occurrences[num] += 1\n\n return [num for num in unique_numbers if occurrences[num] == 1]", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n result = []\n for number in numbers:\n if numbers.count(number) == 1:\n result.append(number)\n return result", "matching_cluster_idx": 0}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n count_map = {}\n result = []\n for num in numbers:\n if num not in count_map:\n count_map[num] = 1\n result.append(num)\n else:\n count_map[num] += 1\n return [num for num in result if count_map[num] == 1]", "matching_cluster_idx": 3}]}, "HumanEval/31": {"dps": 69.36708860759494, "dps_norm": 80.0, "pass@1": 97.0, "profiled": [{"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n False\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n < 2:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True", "matching_cluster_idx": 5}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n False\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n < 2:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True", "matching_cluster_idx": 5}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n \"\"\"\n # Handle the cases where n is less than 2\n if n < 2:\n return False\n # Check for factors up to the square root of n\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True", "matching_cluster_idx": 5}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n False\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n if n <= 1:\n return False\n\n for i in range(2, int(n**0.5)+1):\n if n % i == 0:\n return False\n return True", "matching_cluster_idx": 5}, {"solution": "def is_prime(n):\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\"\"\"\n # Check if n is a positive integer\n if n <= 1 or not isinstance(n, int):\n return False\n # Check if n is divisible by any number up to the square root of n\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True", "matching_cluster_idx": 5}, {"solution": "def is_prime(n):\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n \"\"\"\n if n < 2:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True", "matching_cluster_idx": 5}, {"solution": "def is_prime(n):\n if n < 2:\n return False\n for i in range(2, int(n**0.5)+1):\n if n % i == 0:\n return False\n return True", "matching_cluster_idx": 5}, {"solution": "def is_prime(n):\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n \"\"\"\n if n < 2: # 0 and 1 are not primes\n return False\n for i in range(2, int(n**0.5)+1): # range starts from 2 to sqrt(n)\n if n % i == 0:\n return False\n return True", "matching_cluster_idx": 5}, {"solution": "def is_prime(n):\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n False\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n < 2:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True", "matching_cluster_idx": 5}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n False\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n < 2:\n return False\n for i in range(2, int(n ** 0.5) + 1):\n if n % i == 0:\n return False\n return True", "matching_cluster_idx": 5}, {"solution": "def is_prime(n):\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True", "matching_cluster_idx": 5}, {"solution": "def is_prime(n):\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\"\"\"\n # numbers less than 2 are not prime\n if n < 2:\n return False\n\n # 2 and 3 are prime\n if n < 4:\n return True\n\n # numbers divisible by 2 or 3 are not prime\n if n % 2 == 0 or n % 3 == 0:\n return False\n\n # we have already checked divisibility by 2 and 3. Now, we will check for\n # divisibility by any numbers from 5 to square root of n\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n False\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n elif n <= 3:\n return True\n elif n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n False\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n < 2:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True", "matching_cluster_idx": 5}]}, "HumanEval/33": {"dps": 83.39120370370371, "dps_norm": 79.54545454545455, "pass@1": 96.0, "profiled": [{"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indices that are not divisible by three, while its values at the indices that are divisible by three are equal\n to the values of the corresponding indices of l, but sorted.\n \"\"\"\n div_by_three = sorted([l[i] for i in range(0, len(l), 3)])\n result = l.copy()\n for i, val in enumerate(div_by_three):\n result[i*3] = val\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \n # Creating a separate list of elements which are on the indices divisible by three\n sorted_elements = sorted(l[i] for i in range(0, len(l), 3))\n \n # Creating the transformed list:\n l_prime = []\n for i in range(len(l)):\n if i % 3 == 0: # If index divisible by 3, get the sorted element\n l_prime.append(sorted_elements.pop(0))\n else: # If index not divisible by 3, copy the original element\n l_prime.append(l[i])\n \n return l_prime", "matching_cluster_idx": 6}, {"solution": "def sort_third(l: list):\n div_by_three = sorted([l[i] for i in range(0, len(l), 3)])\n return [div_by_three.pop(0) if i%3 == 0 else l[i] for i in range(len(l))]", "matching_cluster_idx": 6}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n \"\"\"\n\n # Gather the elements at index divisible by 3\n to_sort = [l[i] for i in range(len(l)) if i % 3 == 0]\n\n # Sort the gathered elements\n to_sort.sort()\n\n # Initialize the resulting list\n result = l.copy()\n\n # Insert the sorted elements back into the list at index divisible by 3\n for i, value in zip(range(0, len(result), 3), to_sort):\n result[i] = value\n\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n third_elements = sorted([l[i] for i in range(0, len(l), 3)])\n result = l.copy()\n result[::3] = third_elements\n return result", "matching_cluster_idx": 9}, {"solution": "def sort_third(l: list):\n \"\"\"\n This function takes a list l and returns a list l' such that\n l' is identical to l in the indices that are not divisible by three, while its values at the indices that are divisible by three are equal\n to the values of the corresponding indices of l, but sorted.\n \"\"\"\n # Creating a new list with elements at indices divisible by 3\n div_by_3 = [l[i] for i in range(0, len(l), 3)]\n # Sorting the list at indices divisible by 3\n div_by_3.sort()\n # Replacing the elements at indices divisible by 3 in the original list with sorted ones\n for i, val in enumerate(div_by_3):\n l[i * 3] = val\n return l", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n div3_indexes = [i for i in range(0, len(l), 3)]\n div3_values = sorted([l[i] for i in div3_indexes])\n l_copy = l.copy()\n for i, j in zip(div3_indexes, div3_values):\n l_copy[i] = j\n return l_copy", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indices that are not divisible by three, while its values at the indices that are divisible by three are equal\n to the values of the corresponding indices of l, but sorted.\n \"\"\"\n # Get the values at indices divisible by 3\n div_by_three = [l[i] for i in range(0, len(l), 3)]\n # Sort them\n div_by_three.sort()\n # Replace the values in l at indices divisible by 3 with the sorted ones\n for i, val in enumerate(div_by_three):\n l[i*3] = val\n return l", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"\n This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indices that are divisible by three are equal\n to the values of the corresponding indices of l, but sorted.\n\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n\n # Get a list of elements at indices divisible by 3\n div_by_three = [l[i] for i in range(0, len(l), 3)]\n\n # Sort these elements\n div_by_three.sort()\n\n # Construct the result list\n result = l.copy()\n for i, value in zip(range(0, len(l), 3), div_by_three):\n result[i] = value\n\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n # get the elements at the indices divisible by three, sort them\n div_by_three = sorted(l[i] for i in range(0, len(l), 3))\n\n # replace the elements at the indices divisible by three with the sorted ones\n for i, val in zip(range(0, len(l), 3), div_by_three):\n l[i] = val\n\n return l", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n divisible_by_three_indices = [index for index in range(0, len(l), 3)]\n divisible_by_three_values = sorted([l[index] for index in divisible_by_three_indices])\n\n l_prime = l.copy()\n for index, value in zip(divisible_by_three_indices, divisible_by_three_values):\n l_prime[index] = value\n\n return l_prime", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n # First, let's filter out elements at positions divisible by 3\n div_three = [l[i] for i in range(0, len(l), 3)]\n # Now, we sort this list\n div_three.sort()\n # Let's replace elements at positions divisible by 3 in original list with sorted elements\n for i in range(0, len(l), 3):\n l[i] = div_three.pop(0)\n return l", "matching_cluster_idx": 8}, {"solution": "def sort_third(l):\n third_elements = sorted([l[i] for i in range(0, len(l), 3)])\n result = l.copy()\n for i, j in enumerate(range(0, len(l), 3)):\n result[j] = third_elements[i]\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n # Get the elements at index divisible by three, sorted\n sorted_by_threes = sorted(x for i, x in enumerate(l) if i % 3 == 0)\n \n # Recreate the list, swapping in the sorted values at index divisible by three\n l_prime = [sorted_by_threes.pop(0) if i % 3 == 0 else x for i, x in enumerate(l)]\n \n return l_prime", "matching_cluster_idx": 6}, {"solution": "def sort_third(l: list):\n div3_indexes = [i for i in range(len(l)) if i % 3 == 0]\n div3_values = [l[i] for i in div3_indexes]\n div3_values.sort()\n\n l_prime = l.copy()\n for new_val, i in zip(div3_values, div3_indexes):\n l_prime[i] = new_val\n\n return l_prime", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list) -> list:\n third_elements = sorted([l[i] for i in range(0, len(l), 3)])\n result = l.copy()\n for i, e in enumerate(third_elements):\n result[i*3] = e\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indices that are not divisible by three, while its values at the indices that are divisible by three are equal\n to the values of the corresponding indices of l, but sorted.\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n # Extract the elements at indices divisible by 3\n div_by_3 = [l[i] for i in range(0, len(l), 3)]\n \n # Sort these elements\n div_by_3.sort()\n \n # Replace the elements at indices divisible by 3 in the original list with the sorted elements\n for i, val in enumerate(div_by_3):\n l[i*3] = val\n \n return l", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n third_elements = sorted([l[i] for i in range(0, len(l), 3)])\n for i, val in enumerate(third_elements):\n l[i*3] = val\n return l", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n # Create a sorted list of the elements at index divisible by 3\n sorted_at_3 = sorted(l[i] for i in range(0, len(l), 3))\n\n # Replace the elements at index divisible by 3 in the original list with the sorted elements\n for i, val in zip(range(0, len(l), 3), sorted_at_3):\n l[i] = val\n\n return l", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n third_elements = sorted([l[i] for i in range(0, len(l), 3)])\n for i, val in enumerate(third_elements):\n l[i*3] = val\n return l", "matching_cluster_idx": 8}]}, "HumanEval/34": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(list(set(l)))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n # convert the list to a set to remove duplicates then sort and convert back to list\n return sorted(list(set(l)))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(list(set(l)))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(list(set(l)))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(list(set(l)))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(list(set(l)))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(list(set(l)))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(list(set(l)))", "matching_cluster_idx": 4}]}, "HumanEval/36": {"dps": 96.77419354838709, "dps_norm": 71.42857142857143, "pass@1": 100.0, "profiled": [{"solution": "def fizz_buzz(n: int) -> int:\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n \"\"\"\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int):\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\"\"\"\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n # Initialize count of digit 7 to 0\n count = 0\n for i in range(n):\n # Check if i is divisible by 11 or 13\n if i % 11 == 0 or i % 13 == 0:\n # Count appearances of 7 in i\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int):\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n\n :param n: upper bound (exclusive) of the range of integers to check\n :return: count of digit 7 in numbers within the specified range that are divisible by either 11 or 13\n \"\"\"\n\n count = 0 # variable to hold the count of digit 7\n\n for num in range(n): # iterate through all numbers less than n\n if num % 11 == 0 or num % 13 == 0: # check if the number is divisible by either 11 or 13\n count += str(num).count('7') # increment the count by the number of times 7 appears in the number\n\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\"\"\"\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\"\"\"\n return sum(str(i).count('7') for i in range(n) if i % 11 == 0 or i % 13 == 0)", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n \"\"\"\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int):\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n count = 0\n for i in range(1, n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}]}, "HumanEval/37": {"dps": 95.18003273322422, "dps_norm": 90.5, "pass@1": 99.0, "profiled": [{"solution": "def sort_even(l):\n even_indices_elements = sorted([l[i] for i in range(0, len(l), 2)])\n result = l.copy()\n result[::2] = even_indices_elements\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n # Extract even-indexed items and sort\n sorted_evens = sorted([l[i] for i in range(0, len(l), 2)])\n # Initialize a new list to hold result\n result = [None]*len(l)\n # Fill result with sorted even-indexed items and keep original odd-indexed items\n result[::2] = sorted_evens\n result[1::2] = l[1::2]\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list) -> list:\n \"\"\"\n This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n \"\"\"\n # Extract values at even indices\n evens = [l[i] for i in range(0, len(l), 2)]\n\n # Sort the extracted values\n evens.sort()\n\n # Create a new list and populate it with sorted even values and original odd values\n sorted_l = [None] * len(l)\n sorted_l[::2] = evens\n sorted_l[1::2] = l[1::2]\n\n return sorted_l", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n # Create a new list with elements at the even indices of l, retaining the order.\n even_elements = [l[i] for i in range(0, len(l), 2)]\n # Sort the even_elements list.\n even_elements.sort()\n # Create a new list to store the resulting list.\n result = l.copy()\n # Replace the elements at the even indices of result with the sorted elements.\n for i, val in enumerate(even_elements):\n result[2 * i] = val\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n # Prepare two lists to store even and odd indexed elements separately.\n evens = []\n odds = []\n for i in range(len(l)):\n if i % 2 == 0:\n evens.append(l[i])\n else:\n odds.append(l[i])\n \n # Sort the even indexed elements.\n evens.sort()\n\n # Reconstruct the list by alternately picking from the sorted evens and the originals.\n l_prime = []\n for i in range(len(l)):\n if i % 2 == 0:\n l_prime.append(evens.pop(0))\n else:\n l_prime.append(odds.pop(0))\n return l_prime", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n evens = sorted([l[i] for i in range(0, len(l), 2)])\n l[::2] = evens\n return l", "matching_cluster_idx": 8}, {"solution": "def sort_even(l):\n even_list = sorted(l[i] for i in range(0, len(l), 2))\n result = l.copy()\n result[::2] = even_list\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n even_list = sorted(l[::2])\n for i, elem in enumerate(l[::2]):\n l[2 * i] = even_list[i]\n return l", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n \"\"\"\n \n # Extracting the elements at even indices\n even_indices_elements = [l[i] for i in range(0, len(l), 2)]\n \n # Sorting the even_indices_elements\n even_indices_elements.sort()\n \n # Replacing the elements at even indices with the sorted elements\n for i, e in enumerate(even_indices_elements):\n l[i * 2] = e\n \n return l", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indices, while its values at the even indices are equal\n to the values of the even indices of l, but sorted.\n \"\"\"\n # Grab the even-indexed items and sort them\n sorted_evens = sorted(l[i] for i in range(0, len(l), 2))\n\n # Initialize the new list l'\n l_prime = l.copy()\n\n # Replace the even-indexed items in l' with the sorted items\n l_prime[::2] = sorted_evens\n\n return l_prime", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indices, while its values at the even indices are equal\n to the values of the even indices of l, but sorted.\n \"\"\"\n\n # Separate the values at the even indices\n even_indices_values = [l[i] for i in range(0, len(l), 2)]\n\n # Sort the values at the even indices\n even_indices_values.sort()\n\n # Reconstruct the list with sorted values at even indices\n result = [None] * len(l)\n result[::2] = even_indices_values\n result[1::2] = l[1::2]\n\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l):\n evens = sorted(l[::2])\n l[::2] = evens\n return l", "matching_cluster_idx": 9}, {"solution": "def sort_even(l: list):\n even_elements = sorted([l[i] for i in range(0, len(l), 2)])\n l[::2] = even_elements\n return l", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n even_items = sorted([l[i] for i in range(0, len(l), 2)])\n l[::2] = even_items\n return l", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n evens = sorted([l[i] for i in range(0, len(l), 2)])\n l[::2] = evens\n return l", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n # Extract even index elements and sort them\n sorted_evens = sorted(l[i] for i in range(0, len(l), 2))\n\n # Insert sorted even index elements back into the list\n l[::2] = sorted_evens\n\n return l", "matching_cluster_idx": 8}, {"solution": "def sort_even(l):\n evens = sorted([l[i] for i in range(0, len(l), 2)])\n l[::2] = evens\n return l", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indices, while its values at the even indices are equal\n to the values of the even indices of l, but sorted.\n \"\"\"\n\n # Creating a separate list for even indexed elements, excluding those in odd positions.\n even_indexed_elements = [l[i] for i in range(0, len(l), 2)]\n\n # Sorting the elements of the even indexed elements list.\n even_indexed_elements.sort()\n\n # Replacing the even indexed elements in the original list with the sorted ones.\n for i in range(0, len(l), 2):\n l[i] = even_indexed_elements.pop(0)\n\n return l", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n even_indices_items = sorted([l[i] for i in range(0, len(l), 2)])\n result = l.copy()\n result[::2] = even_indices_items\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list) -> list:\n \"\"\"\n This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indices, while its values at the even indices are equal\n to the values of the even indices of l, but sorted.\n \"\"\"\n # Sort the elements at even indices of the list\n even_indices_sorted = sorted(l[i] for i in range(0, len(l), 2))\n\n # Initialize the new list\n result = l[:]\n\n # Replace the elements at even indices of the new list with the sorted elements\n result[::2] = even_indices_sorted\n\n return result", "matching_cluster_idx": 8}]}, "HumanEval/49": {"dps": 93.88235294117646, "dps_norm": 98.0, "pass@1": 97.0, "profiled": [{"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int):\n \"\"\"Return 2^n modulo p (be aware of numerics).\n\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\n\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n return 2**n % p", "matching_cluster_idx": 3}, {"solution": "def modp(n: int, p: int):\n \"\"\"Return 2^n modulo p (be aware of numerics).\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n return 2**n % p", "matching_cluster_idx": 3}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"\n Return 2^n modulo p (be aware of numerics).\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int):\n \"\"\"Return 2^n modulo p (be aware of numerics).\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int):\n \"\"\"Return 2^n modulo p (be aware of numerics).\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int):\n \"\"\"Return 2^n modulo p (be aware of numerics).\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int):\n \"\"\"Return 2^n modulo p (be aware of numerics).\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n # use python's built-in pow function with three arguments\n # pow(2, n, p) calculates (2 ** n) % p but more efficiently and without numeric issues\n return pow(2, n, p)", "matching_cluster_idx": 4}]}, "HumanEval/51": {"dps": 87.70531400966183, "dps_norm": 70.625, "pass@1": 100.0, "profiled": [{"solution": "def remove_vowels(text):\n vowels = ['a', 'e', 'i', 'o', 'u', 'A', 'E', 'I', 'O', 'U']\n # Converting string to list for easy mutation\n text_list = list(text)\n # Removing vowels\n text_list = [char for char in text_list if char not in vowels]\n # Converting list back to string\n text = \"\".join(text_list)\n return text", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = 'aeiouAEIOU'\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n vowels = 'aeiouAEIOU'\n text_without_vowels = ''\n \n for char in text:\n if char not in vowels:\n text_without_vowels += char\n return text_without_vowels", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n return ''.join([char for char in text if char.lower() not in {'a', 'e', 'i', 'o', 'u'}])", "matching_cluster_idx": 1}, {"solution": "def remove_vowels(text):\n vowels = 'aeiouAEIOU'\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n \"\"\"\n vowels = 'aeiouAEIOU'\n no_vowels_text = ''.join([char for char in text if char not in vowels])\n return no_vowels_text", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n return ''.join([char for char in text if char.lower() not in 'aeiou'])", "matching_cluster_idx": 2}, {"solution": "def remove_vowels(text):\n vowels = 'aeiouAEIOU'\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = 'aeiouAEIOU'\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = 'aeiouAEIOU'\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n vowels = ['a', 'e', 'i', 'o', 'u', 'A', 'E', 'I', 'O', 'U']\n text_without_vowels = \"\".join([char for char in text if char not in vowels])\n return text_without_vowels", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n vowels = 'aeiouAEIOU'\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n vowels = ['a', 'e', 'i', 'o', 'u', 'A', 'E', 'I', 'O', 'U']\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n vowels = ['a', 'e', 'i', 'o', 'u', 'A', 'E', 'I', 'O', 'U']\n return ''.join([letter for letter in text if letter not in vowels])", "matching_cluster_idx": 5}, {"solution": "import doctest\ndef remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = 'aeiouAEIOU'\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = 'aeiouAEIOU'\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n \"\"\"\n vowels = 'aeiouAEIOU'\n return ''.join([letter for letter in text if letter not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n vowels = 'aeiouAEIOU'\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n vowels = ['a', 'e', 'i', 'o', 'u', 'A', 'E', 'I', 'O', 'U']\n text_without_vowels = \"\".join([char for char in text if char not in vowels])\n return text_without_vowels", "matching_cluster_idx": 5}, {"solution": "import doctest\ndef remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = 'aeiouAEIOU'\n return ''.join([letter for letter in text if letter not in vowels])", "matching_cluster_idx": 5}]}, "HumanEval/54": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 76.0, "profiled": [{"solution": "def same_chars(s0: str, s1: str) -> bool:\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \"\"\"\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \"\"\"\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n return sorted(set(s0)) == sorted(set(s1))", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \"\"\"\n # Use set operation to eliminate duplicate characters, and check if two sets are equal.\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \"\"\"\n # Convert strings to sets and compare.\n # If the sets are equal, then all characters in one string are present in the other\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \"\"\"\n # using sets to eliminate repeated characters and check equality\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n return sorted(set(s0)) == sorted(set(s1))", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \"\"\"\n # Convert each string to a set of characters.\n # Two sets are equal if they have the same elements, regardless of their order.\n # Therefore, this function checks if two strings have the same characters.\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \"\"\"\n # Use sets to get unique characters in each string, then compare if they are equal\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \"\"\"\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str):\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \"\"\"\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \"\"\"\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str):\n \"\"\"\n Check if two words have the same characters.\n \"\"\"\n # convert both strings to sets and compare\n return set(s0) == set(s1)", "matching_cluster_idx": 6}]}, "HumanEval/58": {"dps": 92.51968503937007, "dps_norm": 83.33333333333333, "pass@1": 100.0, "profiled": [{"solution": "def common(l1: list, l2: list):\n return sorted(set(l1) & set(l2))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n\n # get intersection of lists and sort\n return sorted(list(set(l1) & set(l2)))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n \"\"\"\n # Calculate the intersection of the two lists and sort the result\n return sorted(list(set(l1) & set(l2)))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n return sorted(list(set(l1) & set(l2)))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n return sorted(set(l1) & set(l2))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n\n \"\"\"\n common_elements = set(l1) & set(l2)\n return sorted(list(common_elements))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n\n \"\"\"\n return sorted(list(set(l1) & set(l2)))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list) -> list:\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n\n \"\"\"\n # use set intersection and list sorting to get unique sorted common elements\n return sorted(list(set(l1) & set(l2)))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n # Using set data type and in-built intersection function of Python.\n common_elements = list(set(l1) & set(l2))\n # Sorts the list in increasing order.\n common_elements.sort()\n return common_elements", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n\n \"\"\"\n return sorted(list(set(l1) & set(l2)))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n\n \"\"\"\n common_set = set(l1) & set(l2) # find common elements\n return sorted(list(common_set)) # sort and return", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n return sorted(list(set(l1) & set(l2)))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n \"\"\"\n return sorted(list(set(l1) & set(l2)))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n\n \"\"\"\n return sorted(list(set(l1) & set(l2)))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\"\"\"\n return sorted(list(set(l1) & set(l2)))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n\n \"\"\"\n return sorted(list(set(l1) & set(l2)))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n\n \"\"\"\n return sorted(list(set(l1) & set(l2)))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n \"\"\"\n # Find common elements by using set intersection\n common_elements = set(l1) & set(l2)\n\n # Return the sorted list\n return sorted(list(common_elements))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n \"\"\"\n # Finding common elements by converting each list into set\n common_elements = set(l1) & set(l2)\n\n # Converting set to list and sorting it\n sorted_common_elements = sorted(list(common_elements))\n\n return sorted_common_elements", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n\n \"\"\"\n return sorted(list(set(l1) & set(l2)))", "matching_cluster_idx": 4}]}, "HumanEval/59": {"dps": 90.83333333333333, "dps_norm": 95.55555555555556, "pass@1": 97.0, "profiled": [{"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\"\"\"\n largest = -1\n while n % 2 == 0:\n largest = 2\n n //= 2\n\n for i in range(3, int(n**0.5) + 1, 2):\n while n % i == 0:\n largest = i\n n //= i\n\n if n > 2:\n largest = n\n return largest", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"\n Return the largest prime factor of n. Assume n > 1 and is not a prime.\n \"\"\"\n def is_prime(num: int) -> bool:\n \"\"\"\n Check if a number is prime.\n \"\"\"\n if num <= 1:\n return False\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n return False\n return True\n\n largest_factor = None\n\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n factor = n // i\n if is_prime(factor):\n largest_factor = factor\n break\n elif is_prime(i):\n largest_factor = i\n\n return largest_factor", "matching_cluster_idx": 7}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\"\"\"\n i = 2\n while i * i <= n:\n if n % i:\n i += 1\n else:\n n //= i\n return n", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\"\"\"\n\n # Start from the smallest prime number (2)\n i = 2\n\n # While i * i is less or equal to n\n while i * i <= n:\n # If n can be evenly divided by i\n if n % i:\n i += 1\n # If n can be evenly divided by i\n else:\n n //= i\n return n", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\"\"\"\n i = 2\n while i * i <= n:\n if n % i:\n i += 1\n else:\n n //= i\n return n", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\"\"\"\n i = 2\n while i * i <= n:\n if n % i:\n i += 1\n else:\n n //= i\n return n", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n def is_prime(num: int) -> bool:\n \"\"\"Check if a number is prime.\"\"\"\n if num <= 1:\n return False\n if num == 2:\n return True\n if num % 2 == 0:\n return False\n sqrt_num = int(num**0.5) + 1\n for i in range(3, sqrt_num, 2):\n if num % i == 0:\n return False\n return True\n\n largest_factor = None\n while n % 2 == 0:\n largest_factor = 2\n n //= 2\n for i in range(3, int(n**0.5) + 1, 2):\n while n % i == 0:\n if is_prime(i):\n largest_factor = i\n n //= i\n if n > 2 and is_prime(n):\n largest_factor = n\n\n return largest_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n i = 2\n while i * i <= n:\n if n % i:\n i += 1\n else:\n n //= i\n return n", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\"\"\"\n\n def is_prime(num):\n \"\"\"Check if a number is prime.\"\"\"\n if num < 2:\n return False\n for i in range(2, int(num**0.5)+1):\n if num % i == 0:\n return False\n return True\n\n factor = 2\n while factor * factor <= n:\n if n % factor:\n factor += 1\n else:\n n //= factor\n return n", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n i = 2\n while i * i <= n:\n if n % i:\n i += 1\n else:\n n //= i\n return n", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n def is_prime(num: int) -> bool:\n \"\"\"Check if the given number is prime.\"\"\"\n for i in range(2, int(num ** 0.5) + 1):\n if num % i == 0:\n return False\n return True\n\n factor = 2\n while factor * factor <= n:\n if n % factor:\n factor += 1\n else:\n n //= factor\n return n if is_prime(n) else factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\"\"\"\n largest_prime = -1\n \n while n % 2 == 0:\n largest_prime = 2\n n //= 2\n\n for i in range(3, int(n ** 0.5) + 1, 2):\n while n % i== 0:\n largest_prime = i\n n //= i\n \n if n > 2:\n largest_prime = n\n \n return largest_prime", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n def is_prime(num: int) -> bool:\n if num < 2:\n return False\n for i in range(2, int(num**0.5)+1):\n if num % i == 0:\n return False\n return True\n\n factor = 2\n largest = 1\n while n > 1:\n if n % factor == 0 and is_prime(factor):\n largest = factor\n while n % factor == 0:\n n /= factor\n factor += 1\n return largest", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\"\"\"\n # Start from the smallest prime, which is 2.\n i = 2\n while i * i <= n:\n if n % i:\n i += 1\n else:\n n //= i\n return n", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\"\"\"\n def is_prime(num: int) -> bool:\n \"\"\"Check if a number is prime.\"\"\"\n if num == 2:\n return True\n if num < 2 or num % 2 == 0:\n return False\n for i in range(3, int(num**0.5)+1, 2):\n if num % i == 0:\n return False\n return True\n\n i = 2\n while i * i <= n:\n if n % i:\n i += 1\n else:\n n //= i\n return n if is_prime(n) else i", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n def is_prime(n):\n if n <= 1 or (n % 2 == 0 and n > 2): \n return False\n return all(n % i for i in range(3, int(n**0.5) + 1, 2))\n\n def get_factors(n):\n factors = []\n for i in range(2, n+1):\n if n % i == 0:\n factors.append(i)\n return factors\n\n factors = get_factors(n)\n prime_factors = [factor for factor in factors if is_prime(factor)]\n\n return max(prime_factors)", "matching_cluster_idx": 1}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\"\"\"\n i = 2\n while i * i <= n:\n if n % i:\n i += 1\n else:\n n //= i\n return n", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\"\"\"\n largest = -1\n while n % 2 == 0:\n largest = 2\n n //= 2\n for i in range(3, int(n**0.5) + 1, 2):\n while n % i == 0:\n largest = i\n n //= i\n if n > 2:\n largest = n\n return largest", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n \"\"\"\n i = 2\n while i * i <= n:\n if n % i:\n i += 1\n else:\n n //= i\n return n", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\"\"\"\n i = 2\n while i * i <= n:\n if n % i:\n i += 1\n else:\n n //= i\n return n", "matching_cluster_idx": 8}]}, "HumanEval/64": {"dps": 67.29634002361276, "dps_norm": 52.27272727272727, "pass@1": 11.0, "profiled": [{"solution": "def vowels_count(s):\n count = 0\n for i in range(len(s)):\n ch = s[i].lower()\n if ch in ['a', 'e', 'i', 'o', 'u']:\n count += 1\n if ch == 'y' and i == len(s) - 1:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def vowels_count(s):\n s = s.lower()\n count = sum(1 for char in s if char in 'aeiou')\n if s.endswith('y'):\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n # Make the string lowercase so it's easier to compare\n s = s.lower()\n\n # Initialize counter\n count = 0\n\n # Loop through each letter in string and increment count if it's a vowel\n for i in range(len(s)):\n if s[i] in ['a', 'e', 'i', 'o', 'u']:\n count += 1\n elif s[i] == 'y' and i == len(s) - 1: # 'y' is a vowel only when it's at the end of the word\n count += 1\n\n return count", "matching_cluster_idx": 3}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = ['a', 'e', 'i', 'o', 'u']\n count = 0\n for i in range(len(s)):\n # check if letter is a vowel\n if s[i].lower() in vowels:\n count += 1\n # check if 'y' is a vowel\n elif s[i].lower() == 'y' and i == len(s) - 1:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = \"aeiou\"\n s = s.lower()\n count = sum(1 for char in s if char in vowels)\n # add an extra count for 'y' only when it's at the end\n if s.endswith('y'):\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n s = s.lower()\n vowels = 'aeiou'\n count = sum(1 for char in s if char in vowels)\n \n # check for 'y' at end of word\n if s.endswith('y'):\n count += 1\n \n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n vowels = 'aeiou'\n s = s.lower()\n count = sum(1 for c in s if c in vowels)\n # add extra count if last character of string is 'y'\n if s.endswith('y'):\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = ['a', 'e', 'i', 'o', 'u']\n count = 0\n s = s.lower()\n for i in range(len(s)):\n if s[i] in vowels:\n count += 1\n if i == len(s) - 1 and s[i] == 'y':\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = set('aeiouAEIOU')\n s_endswith_y = s.endswith('y') or s.endswith('Y')\n return sum(1 for c in s if c in vowels) + s_endswith_y", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n \"\"\"Return the number of vowels in a string.\"\"\"\n s = s.lower()\n vowels = 'aeiou'\n count = sum(1 for char in s if char in vowels)\n\n # If the string ends with y, count it as a vowel.\n if s.endswith('y'):\n count += 1\n\n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n vowels = 'aeiou'\n s = s.lower()\n count = sum(1 for c in s if c in vowels)\n # check 'y' at the end of string\n if s.endswith('y'):\n count += 1\n return count", "matching_cluster_idx": 4}]}, "HumanEval/74": {"dps": 98.04878048780488, "dps_norm": 88.88888888888889, "pass@1": 100.0, "profiled": [{"solution": "def total_match(lst1, lst2):\n # Calculate total chars in each list\n total_chars_lst1 = sum(len(i) for i in lst1)\n total_chars_lst2 = sum(len(i) for i in lst2)\n \n # Return the list with fewer total chars or lst1 if equal\n return lst1 if total_chars_lst1 <= total_chars_lst2 else lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n len1 = sum([len(s) for s in lst1])\n len2 = sum([len(s) for s in lst2])\n return lst1 if len1 <= len2 else lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n # calculate sum of characters in each list\n sum_lst1 = sum(len(word) for word in lst1)\n sum_lst2 = sum(len(word) for word in lst2)\n \n # return the list with the smaller character sum, or lst1 if they are equal\n return lst1 if sum_lst1 <= sum_lst2 else lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n sum_lst1 = sum([len(x) for x in lst1])\n sum_lst2 = sum([len(x) for x in lst2])\n \n if sum_lst1 <= sum_lst2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n total_chars_lst1 = sum([len(i) for i in lst1])\n total_chars_lst2 = sum([len(i) for i in lst2])\n\n if total_chars_lst1 <= total_chars_lst2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n sum_lst1 = sum([len(i) for i in lst1])\n sum_lst2 = sum([len(i) for i in lst2])\n \n if sum_lst1 <= sum_lst2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n # calculate the total characters in each list\n total_chars_lst1 = sum(len(item) for item in lst1)\n total_chars_lst2 = sum(len(item) for item in lst2)\n\n # return the list with the fewer total characters or lst1 if they are the same\n if total_chars_lst1 <= total_chars_lst2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n len_lst1 = sum(len(item) for item in lst1)\n len_lst2 = sum(len(item) for item in lst2)\n return lst1 if len_lst1 <= len_lst2 else lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n chars_lst1 = sum(len(i) for i in lst1)\n chars_lst2 = sum(len(i) for i in lst2)\n\n if chars_lst1 <= chars_lst2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n \n # Helper function to calculate total characters in a list\n def total_chars(lst):\n return sum(len(s) for s in lst)\n\n return lst1 if total_chars(lst1) <= total_chars(lst2) else lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n total_chars_lst1 = sum([len(x) for x in lst1])\n total_chars_lst2 = sum([len(x) for x in lst2])\n \n if total_chars_lst1 <= total_chars_lst2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n def char_count(lst):\n return sum([len(i) for i in lst])\n\n return lst1 if char_count(lst1) <= char_count(lst2) else lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n total_chars_lst1 = sum(len(s) for s in lst1)\n total_chars_lst2 = sum(len(s) for s in lst2)\n \n if total_chars_lst1 <= total_chars_lst2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n # find total chars in lst1\n total_chars_lst1 = sum(len(word) for word in lst1)\n\n # find total chars in lst2\n total_chars_lst2 = sum(len(word) for word in lst2)\n\n # return the list with fewer total chars or lst1 if they are equal\n if total_chars_lst1 <= total_chars_lst2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n \n # Compute the total number of chars in both lists\n total_chars_lst1 = sum(len(s) for s in lst1)\n total_chars_lst2 = sum(len(s) for s in lst2)\n \n # Return the list with fewer total chars, or lst1 if they are equal\n if total_chars_lst1 <= total_chars_lst2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n total_chars1 = sum(len(word) for word in lst1)\n total_chars2 = sum(len(word) for word in lst2)\n\n if total_chars1 <= total_chars2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n len_lst1 = sum(len(i) for i in lst1)\n len_lst2 = sum(len(i) for i in lst2)\n\n return lst1 if len_lst1 <= len_lst2 else lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n total_chars_lst1 = sum(len(word) for word in lst1)\n total_chars_lst2 = sum(len(word) for word in lst2)\n\n if total_chars_lst1 <= total_chars_lst2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n # Calculate the total characters in both lists\n total_chars_lst1 = sum(len(i) for i in lst1)\n total_chars_lst2 = sum(len(i) for i in lst2)\n\n # Check which list has less characters and return it\n if total_chars_lst1 <= total_chars_lst2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n len1 = sum(len(s) for s in lst1)\n len2 = sum(len(s) for s in lst2)\n return lst1 if len1 <= len2 else lst2", "matching_cluster_idx": 7}]}, "HumanEval/85": {"dps": 86.33663366336633, "dps_norm": 53.333333333333336, "pass@1": 100.0, "profiled": [{"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices.\"\"\"\n return sum(value for index, value in enumerate(lst) if index % 2 != 0 and value % 2 == 0)", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n return sum(lst[i] for i in range(len(lst)) if i % 2 and lst[i] % 2 == 0)", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n # Iterating over elements and their indices in the list\n # if the index is odd and the element is even - add it to the sum\n return sum(value for index, value in enumerate(lst) if index % 2 and not value % 2)", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n return sum(lst[i] for i in range(len(lst)) if i % 2 != 0 and lst[i] % 2 == 0)", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices..\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n return sum(el for idx, el in enumerate(lst) if idx % 2 != 0 and el % 2 == 0)", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n # initialize sum\n sum = 0\n\n # go through the list, checking every element at odd index\n for i in range(1, len(lst), 2):\n\n # if element is even, add it to the sum\n if lst[i] % 2 == 0:\n sum += lst[i]\n\n # return the calculated sum\n return sum", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n return sum(value for index, value in enumerate(lst) if index % 2 and value % 2 == 0)", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n return sum(lst[i] for i in range(len(lst)) if i % 2 != 0 and lst[i] % 2 == 0)", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n result = 0\n for i in range(len(lst)):\n if i % 2 != 0 and lst[i] % 2 == 0:\n result += lst[i]\n return result", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n return sum(lst[i] for i in range(1, len(lst), 2) if lst[i] % 2 == 0)", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n result = 0\n for i in range(len(lst)):\n if i % 2 != 0 and lst[i] % 2 == 0:\n result += lst[i]\n return result", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n result = 0\n for i in range(len(lst)):\n if i % 2 != 0 and lst[i] % 2 == 0:\n result += lst[i]\n return result", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n return sum(lst[i] for i in range(1, len(lst), 2) if lst[i] % 2 == 0)\nlst = [4, 2, 6, 7]", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices..\n\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n return sum(el for idx, el in enumerate(lst) if idx % 2 and el % 2 == 0)", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices.\n \n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n return sum(el for i, el in enumerate(lst) if i % 2 != 0 and el % 2 == 0)", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n total = 0\n for i in range(len(lst)):\n if i % 2 != 0 and lst[i] % 2 == 0:\n total += lst[i]\n return total", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n return sum(lst[i] for i in range(1, len(lst), 2) if lst[i] % 2 == 0)", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices..\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n return sum(v for i, v in enumerate(lst) if i % 2 and v % 2 == 0)", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices..\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n return sum(el for i, el in enumerate(lst) if i % 2 and el % 2 == 0)", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n return sum(el for idx, el in enumerate(lst) if idx % 2 and not el % 2)", "matching_cluster_idx": 2}]}, "HumanEval/86": {"dps": 85.20408163265306, "dps_norm": 88.0, "pass@1": 81.0, "profiled": [{"solution": "def anti_shuffle(s):\n words = s.split(' ')\n ordered_words = [''.join(sorted(word)) for word in words]\n return ' '.join(ordered_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n \"\"\"\n words = s.split(' ')\n shuffled_words = [''.join(sorted(word)) for word in words]\n return ' '.join(shuffled_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n words = s.split(' ')\n ordered_words = [''.join(sorted(word)) for word in words]\n return ' '.join(ordered_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n return \" \".join(\"\".join(sorted(word)) for word in s.split(\" \"))", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n\n words = s.split(' ')\n ordered_words = [''.join(sorted(word)) for word in words]\n return ' '.join(ordered_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n\n words = s.split(' ')\n ordered_words = [''.join(sorted(word)) for word in words]\n return ' '.join(ordered_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n # Splitting the input string into a list of words\n words = s.split(' ')\n \n # Sorting each character in each word and joining them back together\n words = [''.join(sorted(word)) for word in words]\n \n # Joining all the words back together with a space character\n sorted_s = ' '.join(words)\n \n # Returning the sorted string\n return sorted_s", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n words = s.split(\" \")\n ordered_words = [\"\".join(sorted(word)) for word in words]\n return \" \".join(ordered_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n words = s.split(' ')\n ordered_words = [''.join(sorted(word)) for word in words]\n return ' '.join(ordered_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n words = s.split(' ')\n ordered_words = [''.join(sorted(word)) for word in words]\n return ' '.join(ordered_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n # List of characters in the string s\n chars = list(s)\n\n # Index of the start of the current word\n word_start = 0\n\n # Iterate over the indices of the list chars\n for i in range(len(chars)):\n # If the current character is a space, sort the characters that make up the word so far\n if chars[i] == ' ':\n chars[word_start:i] = sorted(chars[word_start:i])\n # Update the index of the start of the next word\n word_start = i + 1\n # If this is the last character in the string, sort the characters that make up the last word\n elif i == len(chars) - 1:\n chars[word_start:i+1] = sorted(chars[word_start:i+1])\n # Convert the list of characters back into a string\n sorted_s = \"\".join(chars)\n\n # Return the ordered string\n return sorted_s", "matching_cluster_idx": 0}, {"solution": "def anti_shuffle(s):\n \"\"\"\n This function takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n words = s.split(' ')\n ordered_words = [''.join(sorted(word)) for word in words]\n return ' '.join(ordered_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n \n def sort_word(word):\n \"\"\"\n A helper function that sorts a word.\n \"\"\"\n return ''.join(sorted(word))\n\n words = s.split(' ')\n sorted_words = [sort_word(word) for word in words]\n\n return ' '.join(sorted_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n words = s.split(' ')\n sorted_words = [''.join(sorted(word)) for word in words]\n return ' '.join(sorted_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n This function takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n words = s.split(' ')\n result = []\n for word in words:\n sorted_chars = sorted(word, key=lambda c: (c.islower(), c))\n result.append(''.join(sorted_chars))\n return ' '.join(result)", "matching_cluster_idx": -1}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n words = s.split(' ')\n ordered_words = [''.join(sorted(word)) for word in words]\n return ' '.join(ordered_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n \n words = s.split(' ')\n ordered_words = [''.join(sorted(word)) for word in words]\n return ' '.join(ordered_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n This function takes a string as input and returns an ordered version of it.\n \"\"\"\n # Initialize an empty string to store the result\n result = ''\n # Initialize an empty string to store each word temporarily\n word = ''\n # Iterate through each character in the string\n for char in s:\n # If the character is not a space, append it to the current word\n if char != ' ':\n word += char\n # If the character is a space, process the current word and add it to the result\n else:\n result += ''.join(sorted(word)) + ' '\n word = ''\n # Process the last word in the string\n result += ''.join(sorted(word))\n return result", "matching_cluster_idx": 1}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n \n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n words = s.split(' ')\n ordered_words = [''.join(sorted(word)) for word in words]\n return ' '.join(ordered_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n words = s.split(' ')\n result = []\n\n for word in words:\n sorted_word = ''.join(sorted(word))\n result.append(sorted_word)\n\n return ' '.join(result)", "matching_cluster_idx": 4}]}, "HumanEval/87": {"dps": 82.88184438040346, "dps_norm": 55.0, "pass@1": 98.0, "profiled": [{"solution": "def get_row(lst, x):\n coords = [(i, j) for i, row in enumerate(lst) for j, e in enumerate(row) if e == x]\n return sorted(coords, key=lambda t: (t[0], -t[1]))", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n result = [(i, j) for i, row in enumerate(lst) for j, val in enumerate(row) if val == x]\n result.sort(key=lambda x: (x[0], -x[1]))\n return result", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n res = []\n for i, row in enumerate(lst):\n for j, elem in enumerate(row):\n if elem == x:\n res.append((i, j))\n return sorted(res, key=lambda t: (t[0], -t[1]))", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n coordinates = [(i, j) for i, row in enumerate(lst) for j, elem in enumerate(row) if elem == x]\n return sorted(coordinates, key=lambda x: (x[0], -x[1]))", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n result = []\n for i, row in enumerate(lst):\n for j, element in enumerate(row):\n if element == x:\n result.append((i, j))\n result.sort(key=lambda y: (y[0], -y[1]))\n return result", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n result = []\n for row_index, row in enumerate(lst):\n for col_index, col in enumerate(row):\n if col == x:\n result.append((row_index, col_index))\n return sorted(result, key=lambda y: (y[0], -y[1]))", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n result = [(i, j) for i, row in enumerate(lst) for j, num in enumerate(row) if num == x]\n return sorted(result, key=lambda coord: (coord[0], -coord[1]))", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n coords = [(i, j) for i, row in enumerate(lst) for j, element in enumerate(row) if element == x]\n coords.sort(key=lambda coord: (coord[0], -coord[1]))\n return coords", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n coordinates = []\n for i in range(len(lst)):\n for j in range(len(lst[i])):\n if lst[i][j] == x:\n coordinates.append((i, j))\n \n return sorted(coordinates, key=lambda y: (y[0], -y[1]))", "matching_cluster_idx": 2}, {"solution": "def get_row(lst, x):\n coordinates = []\n for i, row in enumerate(lst):\n for j, value in enumerate(row):\n if value == x:\n coordinates.append((i, j))\n return sorted(coordinates, key=lambda coordinate: (coordinate[0], -coordinate[1]))", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n result = [(i, j) for i, row in enumerate(lst) for j, e in enumerate(row) if e == x]\n return sorted(result, key=lambda r: (r[0], -r[1]))", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n coords = []\n for i, row in enumerate(lst):\n for j, col in enumerate(row):\n if col == x:\n coords.append((i, j))\n return sorted(coords, key=lambda x: (x[0], -x[1]))", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n coords = []\n for i, row in enumerate(lst):\n for j, val in enumerate(row):\n if val == x:\n coords.append((i, j))\n return sorted(coords, key=lambda x: (x[0], -x[1]))", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n result = []\n for i in range(len(lst)):\n for j in range(len(lst[i])):\n if lst[i][j] == x:\n result.append((i, j))\n # sort by row in ascending order and by column in descending order\n result.sort(key=lambda tup: (tup[0], -tup[1]))\n return result", "matching_cluster_idx": 2}, {"solution": "def get_row(lst, x):\n coordinates = []\n for i in range(len(lst)):\n for j in range(len(lst[i])):\n if lst[i][j] == x:\n coordinates.append((i, j))\n return sorted(sorted(coordinates, key=lambda y: y[1], reverse=True), key=lambda y: y[0])", "matching_cluster_idx": 2}, {"solution": "def get_row(lst, x):\n coordinates = [(i, j) for i, row in enumerate(lst) for j, val in enumerate(row) if val == x]\n return sorted(coordinates, key=lambda y: (y[0], -y[1]))", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n coordinates = [(i, j) for i, row in enumerate(lst) for j, element in enumerate(row) if element == x]\n return sorted(coordinates, key=lambda y: (y[0], -y[1]))", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n coordinates = [(i, j) for i, inner_list in enumerate(lst) for j, element in enumerate(inner_list) if element == x]\n return sorted(coordinates, key=lambda tup: (tup[0], -tup[1]))", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n result = []\n for i, l in enumerate(lst):\n for j, num in enumerate(l):\n if num == x:\n result.append((i,j))\n result.sort(key = lambda x: (x[0], -x[1]))\n return result", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n result = []\n for row_index, row in enumerate(lst):\n for column_index, element in enumerate(row):\n if element == x:\n result.append((row_index, column_index))\n return sorted(result, key=lambda x: (x[0], -x[1]))", "matching_cluster_idx": 3}]}, "HumanEval/89": {"dps": 96.64948453608248, "dps_norm": 28.571428571428573, "pass@1": 60.0, "profiled": [{"solution": "def encrypt(s):\n result = \"\"\n for char in s:\n if 'a' <= char <= 'z':\n result += chr(((ord(char) - ord('a') + 4) % 26) + ord('a'))\n elif 'A' <= char <= 'Z':\n result += chr(((ord(char) - ord('A') + 4) % 26) + ord('A'))\n else:\n result += char\n return result", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n alphabet = 'abcdefghijklmnopqrstuvwxyz'\n encrypted = ''\n for char in s:\n if char.lower() in alphabet: # ensure char is a letter, not a digit or special character\n char_index = (alphabet.index(char.lower()) + 4) % 26 # rotate and handle wrapping\n # maintain original case\n if char.isupper():\n encrypted += alphabet[char_index].upper()\n else:\n encrypted += alphabet[char_index]\n else:\n encrypted += char # non-letter characters remain the same\n return encrypted", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n \"\"\"\n # create empty string to store encrypted text\n encrypted_text = ''\n\n # iterate through each character in the string\n for char in s:\n # check if character is an uppercase or lowercase letter\n if 'A' <= char <= 'Z':\n # shift character down by four places\n encrypted_char = chr((ord(char) - 65 + 4) % 26 + 65)\n elif 'a' <= char <= 'z':\n # shift character down by four places\n encrypted_char = chr((ord(char) - 97 + 4) % 26 + 97)\n else:\n # if character is not a letter, keep it as it is\n encrypted_char = char\n\n # append encrypted character to the encrypted text string\n encrypted_text += encrypted_char\n\n return encrypted_text", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n result = ''\n for char in s:\n if 'a' <= char <= 'z':\n new_char = chr(((ord(char) - ord('a') + 4) % 26) + ord('a'))\n else:\n new_char = char\n result += new_char\n return result", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n result = \"\"\n for i in s:\n char_num = ord(i)\n if char_num >= 97 and char_num <= 122: # Check if char is lowercase letter\n result += chr((char_num - 97 + 4) % 26 + 97) # Shift down by two multiplied to two places\n elif char_num >= 65 and char_num <= 90: # Check if char is uppercase letter\n result += chr((char_num - 65 + 4) % 26 + 65) # Shift down by two multiplied to two places\n else: \n result += i # If not a letter, just add the char to result\n return result", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n result = \"\"\n for char in s:\n # Get ascii value of char and add 4 (2*2).\n ascii_val = ord(char) + 4\n if char.islower():\n # If ascii value goes beyond 'z', subtract 26 to cycle back to 'a'.\n if ascii_val > ord('z'):\n ascii_val -= 26\n elif char.isupper():\n # If ascii value goes beyond 'Z', subtract 26 to cycle back to 'A'.\n if ascii_val > ord('Z'):\n ascii_val -= 26\n else:\n # If char is not a letter, don't change it.\n ascii_val = ord(char)\n result += chr(ascii_val)\n return result", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n result = \"\"\n for i in s:\n x = ord(i)\n if x >= 97 and x <= 122: #Lowercase letters\n result += chr(((x - 97 + 4) % 26) + 97)\n elif x >= 65 and x <= 90: #Uppercase letters\n result += chr(((x - 65 + 4) % 26) + 65)\n else: #Non-alphabetic characters\n result += i\n return result", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n result = ''\n for letter in s:\n if 'a' <= letter <= 'z':\n result += chr((ord(letter) - ord('a') + 4) % 26 + ord('a'))\n elif 'A' <= letter <= 'Z':\n result += chr((ord(letter) - ord('A') + 4) % 26 + ord('A'))\n else:\n result += letter\n return result", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n result = \"\"\n for char in s:\n if 'a' <= char <= 'z':\n result += chr((ord(char) - ord('a') + 4) % 26 + ord('a'))\n elif 'A' <= char <= 'Z':\n result += chr((ord(char) - ord('A') + 4) % 26 + ord('A'))\n else:\n result += char\n return result", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n result = \"\"\n for char in s:\n if char.isalpha():\n shift = 4 if char.islower() else 4\n new_char = chr((ord(char) - ord('a') + shift) % 26 + ord('a')) if char.islower() else chr((ord(char) - ord('A') + shift) % 26 + ord('A'))\n result += new_char\n else:\n result += char\n return result", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n result = \"\"\n for letter in s:\n if 'a' <= letter <= 'z':\n result += chr((ord(letter) - ord('a') + 4) % 26 + ord('a'))\n elif 'A' <= letter <= 'Z':\n result += chr((ord(letter) - ord('A') + 4) % 26 + ord('A'))\n else:\n result += letter\n return result", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n result = \"\"\n for char in s:\n if 'a' <= char <= 'z':\n result += chr((ord(char) - ord('a') + 4) % 26 + ord('a'))\n elif 'A' <= char <= 'Z':\n result += chr((ord(char) - ord('A') + 4) % 26 + ord('A'))\n else:\n result += char\n return result", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n result = \"\"\n for char in s:\n if 'a' <= char <= 'z':\n result += chr((ord(char) - ord('a') + 4) % 26 + ord('a'))\n elif 'A' <= char <= 'Z':\n result += chr((ord(char) - ord('A') + 4) % 26 + ord('A'))\n else:\n result += char\n return result", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n result = \"\"\n for char in s:\n if 'a' <= char <= 'z':\n shifted_index = (ord(char) - ord('a') + 4) % 26\n result += chr(shifted_index + ord('a'))\n else:\n result += char\n return result", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n result = \"\"\n for c in s:\n char_code = ord(c)\n if 'a' <= c <= 'z':\n result += chr((char_code - ord('a') + 4) % 26 + ord('a'))\n elif 'A' <= c <= 'Z':\n result += chr((char_code - ord('A') + 4) % 26 + ord('A'))\n else:\n result += c\n return result", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n result = \"\"\n for char in s:\n if char.isalpha():\n start = ord('a') if char.islower() else ord('A')\n new_char = chr((ord(char) - start + 4) % 26 + start)\n result += new_char\n else:\n result += char\n return result", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n encrypted = \"\"\n for char in s:\n if 'a' <= char <= 'z':\n encrypted += chr(((ord(char) - ord('a') + 4) % 26) + ord('a'))\n elif 'A' <= char <= 'Z':\n encrypted += chr(((ord(char) - ord('A') + 4) % 26) + ord('A'))\n else:\n encrypted += char\n return encrypted", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n encrypted_str = \"\"\n for i in s:\n ascii_val = ord(i)\n if ascii_val >= 97 and ascii_val <= 122:\n encrypted_str += chr(((ascii_val - 97 + 4) % 26) + 97)\n else:\n encrypted_str += i\n return encrypted_str", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n result = \"\"\n for char in s:\n if 'a' <= char <= 'z':\n result += chr((ord(char) - ord('a') + 4) % 26 + ord('a'))\n elif 'A' <= char <= 'Z':\n result += chr((ord(char) - ord('A') + 4) % 26 + ord('A'))\n else:\n result += char\n return result", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n result = \"\"\n for char in s:\n if 'a' <= char <= 'z':\n result += chr((ord(char) - ord('a') + 4) % 26 + ord('a'))\n else:\n result += char\n return result", "matching_cluster_idx": 1}]}, "HumanEval/90": {"dps": 65.50583657587549, "dps_norm": 58.333333333333336, "pass@1": 72.0, "profiled": [{"solution": "def next_smallest(lst):\n # Remove duplicates\n lst = list(set(lst))\n \n # Check if list has less than 2 elements\n if len(lst) < 2:\n return None\n \n # If list has 2 or more elements, sort the list\n lst.sort()\n \n # Return the second smallest element\n return lst[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n if len(lst) < 2:\n return None\n else:\n lst.sort()\n smallest = lst[0]\n for num in lst:\n if num > smallest:\n return num\n return None", "matching_cluster_idx": 11}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n\n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n unique_lst = list(set(lst))\n\n if len(unique_lst) < 2:\n return None\n else:\n unique_lst.sort()\n return unique_lst[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n if len(lst) < 2:\n return None\n \n smallest = second_smallest = float('inf')\n\n for num in lst:\n if num < smallest:\n second_smallest = smallest\n smallest = num\n elif num < second_smallest and num > smallest:\n second_smallest = num\n \n if second_smallest == float('inf'):\n return None\n else:\n return second_smallest", "matching_cluster_idx": 5}, {"solution": "def next_smallest(lst):\n \"\"\"\n Return the 2nd smallest element of a list.\n Return None if there is no such element.\n\n >>> next_smallest([1, 2, 3, 4, 5])\n 2\n\n >>> next_smallest([5, 1, 4, 3, 2])\n 2\n\n >>> next_smallest([])\n None\n\n >>> next_smallest([1, 1])\n None\n \"\"\"\n \n # Ensure the list has at least two distinct elements\n if len(set(lst)) < 2:\n return None\n\n # Sort the list and return the second element\n return sorted(set(lst))[1]", "matching_cluster_idx": 5}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \"\"\"\n \n if len(lst) < 2:\n return None\n\n smallest = second_smallest = float('inf')\n for num in lst:\n if num < smallest:\n second_smallest = smallest\n smallest = num\n elif smallest < num < second_smallest:\n second_smallest = num\n\n return second_smallest if second_smallest != float('inf') else None", "matching_cluster_idx": 5}, {"solution": "def next_smallest(lst):\n if len(lst) < 2:\n return None\n \n smallest = second_smallest = float('inf')\n for num in lst:\n if num < smallest:\n second_smallest = smallest\n smallest = num\n elif smallest < num < second_smallest:\n second_smallest = num\n \n return None if second_smallest == float('inf') else second_smallest", "matching_cluster_idx": 5}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n # create a sorted copy of the input list\n sorted_list = sorted(lst)\n \n # edge cases\n if len(sorted_list) < 2:\n return None\n\n # find the smallest unique number in the sorted list\n for i in range(1, len(sorted_list)):\n if sorted_list[i] > sorted_list[0]:\n return sorted_list[i]\n \n # if no second unique smallest number exists, return None\n return None", "matching_cluster_idx": 10}, {"solution": "def next_smallest(lst):\n if len(lst) < 2:\n return None\n \n smallest = min(lst)\n lst = [x for x in lst if x != smallest]\n \n if len(lst) == 0:\n return None\n \n return min(lst)", "matching_cluster_idx": 3}, {"solution": "def next_smallest(lst):\n if len(lst) < 2: # If the list has less than 2 elements, return None.\n return None\n else: # If the list has 2 or more elements, find and return the 2nd smallest element.\n sorted_lst = sorted(set(lst)) # Removing duplicates first then sorting the list.\n if len(sorted_lst) < 2: # If after removing duplicates, list has less than 2 elements, return None.\n return None\n else: # If after removing duplicates, list has 2 or more elements, return the 2nd smallest element.\n return sorted_lst[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n if len(lst) < 2:\n return None\n\n smallest = second_smallest = float('inf')\n\n for num in lst:\n if num < smallest:\n second_smallest = smallest\n smallest = num\n elif num < second_smallest and num > smallest:\n second_smallest = num\n\n if second_smallest == float('inf'):\n return None\n\n return second_smallest", "matching_cluster_idx": 5}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n # Remove duplicates from the list\n lst = list(set(lst))\n \n # Sort the list in ascending order\n lst.sort()\n \n # If the list has at least 2 elements, return the 2nd smallest element\n if len(lst) >= 2:\n return lst[1]\n else:\n return None", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n if len(lst) < 2:\n return None\n smallest = second_smallest = float('inf')\n for num in lst:\n if num < smallest:\n second_smallest = smallest\n smallest = num\n elif smallest < num < second_smallest:\n second_smallest = num\n return None if second_smallest == float('inf') else second_smallest", "matching_cluster_idx": 5}, {"solution": "def next_smallest(lst):\n if len(lst) < 2:\n return None\n \n lst.sort()\n smallest = lst[0]\n for num in lst:\n if num > smallest:\n return num\n return None", "matching_cluster_idx": 11}, {"solution": "def next_smallest(lst):\n if len(lst) < 2:\n return None\n else:\n lst = list(set(lst)) # Removing duplicates\n lst.sort()\n if len(lst) < 2:\n return None\n else:\n return lst[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n if len(lst) < 2:\n return None\n \n smallest = second_smallest = float('inf')\n for num in lst:\n if num < smallest:\n second_smallest, smallest = smallest, num\n elif smallest < num < second_smallest:\n second_smallest = num\n\n return None if second_smallest == float('inf') else second_smallest", "matching_cluster_idx": 5}, {"solution": "def next_smallest(lst):\n \"\"\"\n This function returns the 2nd smallest element of the list.\n If there is no such element, it returns None.\n \"\"\"\n if len(lst) < 2:\n return None\n smallest = second_smallest = float('inf')\n for num in lst:\n if num < smallest:\n second_smallest = smallest\n smallest = num\n elif smallest < num < second_smallest:\n second_smallest = num\n if second_smallest == float('inf'):\n return None\n return second_smallest", "matching_cluster_idx": 5}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n \n smallest = second_smallest = float('inf')\n for num in lst:\n if num < smallest:\n second_smallest = smallest\n smallest = num\n elif num < second_smallest and num > smallest:\n second_smallest = num\n \n return second_smallest if second_smallest != float('inf') else None", "matching_cluster_idx": 5}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \"\"\"\n if len(lst) < 2:\n return None\n\n smallest = second_smallest = float('inf')\n\n for num in lst:\n if num < smallest:\n second_smallest = smallest\n smallest = num\n elif smallest < num < second_smallest:\n second_smallest = num\n\n if second_smallest == float('inf'):\n return None\n\n return second_smallest", "matching_cluster_idx": 5}, {"solution": "def next_smallest(lst):\n if len(lst) < 2:\n return None\n \n smallest = second_smallest = float('inf')\n \n for num in lst:\n if num < smallest:\n second_smallest, smallest = smallest, num\n elif smallest < num < second_smallest:\n second_smallest = num\n \n return None if second_smallest == float('inf') else second_smallest", "matching_cluster_idx": 5}]}, "HumanEval/113": {"dps": 98.98580121703854, "dps_norm": 66.66666666666667, "pass@1": 58.0, "profiled": [{"solution": "def odd_count(lst):\n result = []\n for i, string in enumerate(lst):\n num_odd_digits = sum(1 for digit in string if int(digit) % 2 != 0)\n result.append(f\"the number of odd elements {num_odd_digits}n the str{num_odd_digits}ng {num_odd_digits} of the {num_odd_digits}nput.\")\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n result = []\n for i, s in enumerate(lst):\n odd_count = sum(1 for c in s if int(c) % 2 != 0)\n result.append(f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\")\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n result = []\n for index, string in enumerate(lst):\n # Count the odd digits in the string\n odd_digits_count = sum(int(digit) % 2 for digit in string)\n \n # Prepare the output string\n output_string = \"the number of odd elements {}n the str{}ng {} of the {}nput.\".format(odd_digits_count, odd_digits_count, odd_digits_count, odd_digits_count)\n\n # Add the output string to the result\n result.append(output_string)\n\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\"\"\"\n\n # Function to count odd digits in a string\n def count_odd_digits(s):\n return sum(int(ch) % 2 for ch in s)\n\n # Create the result list\n result = []\n\n # Loop over the input list\n for i, s in enumerate(lst):\n # Count the number of odd digits in the string\n count = count_odd_digits(s)\n\n # Create the output string and add it to the result list\n result.append(f\"the number of odd elements {count}n the str{count}ng {count} of the {count}nput.\")\n\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n def count_odd_in_str(s):\n return len([int(i) for i in s if int(i) % 2 != 0])\n\n def replace_number_in_str(s, count):\n new_str = \"the number of odd elements {}n the str{}ng {} of the {}nput.\"\n return new_str.format(count, count, count, count)\n\n return [replace_number_in_str(i, count_odd_in_str(i)) for i in lst]", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n result = []\n for idx, string in enumerate(lst):\n odd_count = len([char for char in string if int(char) % 2 != 0])\n new_string = \"the number of odd elements {}n the str{}ng {} of the {}nput.\".format(odd_count, odd_count, odd_count, odd_count)\n result.append(new_string)\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n res = []\n for i, s in enumerate(lst):\n odd_digits_in_s = sum(int(c) % 2 for c in s)\n string_replaced = \"the number of odd elements {}n the str{}ng {} of the {}nput.\".format(odd_digits_in_s, odd_digits_in_s, odd_digits_in_s, odd_digits_in_s)\n res.append(string_replaced)\n return res", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\"\"\"\n\n result = []\n for idx, string in enumerate(lst):\n # count odd digits in the string\n odd_digits_count = sum(int(char) % 2 for char in string)\n \n # create a new string with replaced numbers and add to the result list\n replaced_str = \"the number of odd elements {}n the str{}ng {} of the {}nput.\".format(\n odd_digits_count, odd_digits_count, odd_digits_count, odd_digits_count)\n result.append(replaced_str)\n \n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n output = []\n for i in range(len(lst)):\n count = 0\n for j in lst[i]:\n if int(j) % 2 != 0:\n count += 1\n s = \"the number of odd elements {}n the str{}ng {} of the {}nput.\".format(count, count, count, count)\n output.append(s)\n return output", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n result = []\n for i, s in enumerate(lst):\n odd_digits_count = sum(int(c) % 2 for c in s)\n sentence = f\"the number of odd elements {odd_digits_count}n the str{odd_digits_count}ng {odd_digits_count} of the {odd_digits_count}nput.\"\n result.append(sentence)\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n result = []\n for i, s in enumerate(lst):\n odd_digits = sum(int(c) % 2 for c in s)\n result.append(\"the number of odd elements {}n the str{}ng {} of the {}nput.\".format(odd_digits, odd_digits, odd_digits, odd_digits))\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n def count_odd(n):\n count = 0\n for digit in n:\n if int(digit) % 2 != 0:\n count += 1\n return count\n\n result = []\n for i in range(len(lst)):\n odd_num = count_odd(lst[i])\n string = \"the number of odd elements {}n the str{}ng {} of the {}nput.\".format(odd_num, odd_num, odd_num, odd_num)\n result.append(string)\n\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n result = []\n for i, string in enumerate(lst):\n odd_count_in_string = sum(int(digit) % 2 for digit in string)\n result.append(f\"the number of odd elements {odd_count_in_string}n the str{odd_count_in_string}ng {odd_count_in_string} of the {odd_count_in_string}nput.\")\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n output = []\n for idx, string in enumerate(lst):\n num_odds = len([int(ch) for ch in string if int(ch) % 2 == 1])\n formatted_string = \"the number of odd elements {}n the str{}ng {} of the {}nput.\".format(num_odds, num_odds, num_odds, num_odds)\n output.append(formatted_string)\n return output", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n output = []\n for i in range(len(lst)):\n num_odds = sum([int(char) % 2 for char in lst[i]])\n output.append(f\"the number of odd elements {num_odds}n the str{num_odds}ng {num_odds} of the {num_odds}nput.\")\n return output", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n result = []\n for idx, string in enumerate(lst):\n count = sum(int(c) % 2 for c in string)\n result.append(f\"the number of odd elements {count}n the str{count}ng {count} of the {count}nput.\")\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n # list of odd digits\n odd_digits = ['1', '3', '5', '7', '9']\n\n # list to hold results\n results = []\n\n for i in range(len(lst)):\n # count of odd digits in the i'th string\n count = sum(1 for d in lst[i] if d in odd_digits)\n\n # create the output string and add to results\n result_string = \"the number of odd elements {}n the str{}ng {} of the {}nput.\".format(count, count, count, count)\n results.append(result_string)\n\n return results", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n result = []\n for i, s in enumerate(lst):\n odd_nums = sum(int(c) % 2 for c in s)\n result.append(f\"the number of odd elements {odd_nums}n the str{odd_nums}ng {odd_nums} of the {odd_nums}nput.\")\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n result = []\n for i in range(len(lst)):\n count = sum(1 for ch in lst[i] if int(ch) % 2 != 0)\n new_string = \"the number of odd elements {}n the str{}ng {} of the {}nput.\".format(count, count, count, count)\n result.append(new_string)\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n results = []\n\n def count_odds(number_str):\n return len([int(ch) for ch in number_str if int(ch) % 2 != 0])\n\n for index, number_str in enumerate(lst):\n odd_number = count_odds(number_str)\n formatted_string = f\"the number of odd elements {odd_number}n the str{odd_number}ng {odd_number} of the {odd_number}nput.\"\n results.append(formatted_string)\n\n return results", "matching_cluster_idx": 3}]}, "HumanEval/119": {"dps": null, "dps_norm": null, "pass@1": 6.0, "profiled": []}, "HumanEval/120": {"dps": 97.41379310344827, "dps_norm": 99.28571428571429, "pass@1": 31.0, "profiled": [{"solution": "def maximum(arr, k):\n arr.sort(reverse=True)\n return sorted(arr[:k])", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n arr.sort(reverse=True)\n return sorted(arr[:k])", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n arr.sort(reverse = True)\n return sorted(arr[:k])", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n arr.sort(reverse = True)\n return sorted(arr[:k])", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n arr.sort(reverse = True)\n return sorted(arr[:k])", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n arr.sort(reverse = True)\n return sorted(arr[:k])", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n arr.sort(reverse=True)\n return sorted(arr[:k])", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n arr.sort(reverse=True)\n return sorted(arr[:k])", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n arr.sort(reverse=True)\n return sorted(arr[:k])", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n if k == 0:\n return []\n\n arr.sort()\n arr = arr[len(arr)-k:]\n\n return sorted(arr)", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n arr.sort(reverse = True)\n return sorted(arr[:k])", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n arr.sort(reverse=True)\n return sorted(arr[:k])", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n arr.sort(reverse=True)\n return sorted(arr[:k])", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n arr.sort(reverse=True)\n return sorted(arr[:k])", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n arr.sort(reverse=True)\n return sorted(arr[:k])", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n # sort the array in reverse order\n sorted_arr = sorted(arr, reverse=True)\n \n # slice first k elements\n max_k_nums = sorted_arr[:k]\n\n # sort the result in ascending order\n result = sorted(max_k_nums)\n\n return result", "matching_cluster_idx": 5}, {"solution": "def maximum(arr, k):\n arr.sort(reverse=True)\n return sorted(arr[:k])", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n arr.sort(reverse=True)\n return sorted(arr[:k])", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n arr.sort(reverse=True)\n return sorted(arr[:k])", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n arr.sort(reverse=True)\n return sorted(arr[:k])", "matching_cluster_idx": 6}]}, "HumanEval/121": {"dps": 83.36322869955157, "dps_norm": 62.142857142857146, "pass@1": 100.0, "profiled": [{"solution": "def solution(lst):\n return sum(value for index, value in enumerate(lst) if index % 2 == 0 and value % 2 == 1)", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n Examples:\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==>0\n \"\"\"\n return sum(value for idx, value in enumerate(lst) if idx % 2 == 0 and value % 2 == 1)", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\"\"\"\n \n # sum of odd numbers in even positions\n return sum(num for idx, num in enumerate(lst) if idx % 2 == 0 and num % 2 == 1)", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n return sum(lst[i] for i in range(0, len(lst), 2) if lst[i] % 2 == 1)", "matching_cluster_idx": 4}, {"solution": "def solution(lst):\n return sum(lst[i] for i in range(0, len(lst), 2) if lst[i] % 2 == 1)", "matching_cluster_idx": 4}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n\n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==>0\n \"\"\"\n return sum(value for index, value in enumerate(lst) if index % 2 == 0 and value % 2 != 0)", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n Examples:\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n return sum(value for index, value in enumerate(lst) if index % 2 == 0 and value % 2 == 1)", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n total = 0\n for i in range(0, len(lst), 2):\n if lst[i] % 2 == 1:\n total += lst[i]\n return total", "matching_cluster_idx": 4}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==>0\n \"\"\"\n result = 0\n for i in range(0, len(lst), 2):\n if lst[i] % 2 != 0:\n result += lst[i]\n return result", "matching_cluster_idx": 4}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n Examples:\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n return sum(el for idx, el in enumerate(lst) if idx % 2 == 0 and el % 2 == 1)", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n\n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==>0\n \"\"\"\n return sum(value for index, value in enumerate(lst) if index % 2 == 0 and value % 2 == 1)", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n Examples:\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n return sum(value for index, value in enumerate(lst) if index % 2 == 0 and value % 2 == 1)", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n return sum(x for i, x in enumerate(lst) if i % 2 == 0 and x % 2 == 1)", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n return sum(lst[i] for i in range(0, len(lst), 2) if lst[i] % 2 == 1)", "matching_cluster_idx": 4}, {"solution": "def solution(lst):\n return sum(value for index, value in enumerate(lst) if index % 2 == 0 and value % 2 == 1)", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n total = 0\n for idx, num in enumerate(lst):\n if idx % 2 == 0 and num % 2 == 1:\n total += num\n return total", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\"\"\"\n\n # Check if the list is empty\n if not lst:\n return 0\n \n # Initialize the sum\n odd_sum = 0\n\n # Loop through the list\n for i in range(0, len(lst), 2):\n # If the element is odd, add it to the sum\n if lst[i] % 2 != 0:\n odd_sum += lst[i]\n\n return odd_sum", "matching_cluster_idx": 4}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\"\"\"\n \n return sum(num for i, num in enumerate(lst) if i % 2 == 0 and num % 2 == 1)", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n return sum(lst[i] for i in range(0, len(lst), 2) if lst[i] % 2 != 0)", "matching_cluster_idx": 4}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\"\"\"\n return sum(value for index, value in enumerate(lst) if index % 2 == 0 and value % 2 == 1)", "matching_cluster_idx": 3}]}, "HumanEval/149": {"dps": 85.82677165354332, "dps_norm": 57.142857142857146, "pass@1": 89.0, "profiled": [{"solution": "def sorted_list_sum(lst):\n # Deleting the strings that have odd lengths\n lst = [word for word in lst if len(word) % 2 == 0]\n # Sorting by length of each word and then alphabetically\n lst.sort(key = lambda x: (len(x), x))\n return lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n # Delete the strings with odd lengths\n lst = [i for i in lst if len(i) % 2 == 0]\n # Sort the list by length, then alphabetically\n lst.sort(key=lambda s: (len(s), s))\n return lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n # delete strings with odd lengths\n lst = [x for x in lst if len(x) % 2 == 0]\n\n # sort the list first by length, then alphabetically\n lst.sort(key=lambda x: (len(x), x))\n\n return lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n # delete the strings that have odd lengths\n lst = [x for x in lst if len(x) % 2 == 0]\n\n # sort the list by length of each word and then alphabetically for same length words\n lst.sort(key=lambda s: (len(s), s))\n\n return lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n # delete strings with odd lengths\n lst = [s for s in lst if len(s) % 2 == 0]\n\n # sort by length and then alphabetically\n lst.sort(key=lambda s: (len(s), s))\n\n return lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n # Delete strings with odd lengths\n lst = [word for word in lst if len(word) % 2 == 0]\n\n # Sort the list by length and then alphabetically\n lst.sort(key = lambda x: (len(x), x))\n\n return lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n # Removing strings with odd lengths\n lst = [i for i in lst if len(i) % 2 == 0]\n # Sorting the list by length and then alphabetically\n lst.sort(key=lambda s: (len(s), s))\n return lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n lst = [i for i in lst if len(i) % 2 == 0] # Filters out strings of odd lengths.\n lst.sort(key=lambda x: (len(x), x)) # Sorts by string length and then alphabetically.\n return lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n # Remove elements with odd length\n lst = [word for word in lst if len(word) % 2 == 0]\n # Sort list by length of word, then alphabetically for same length words\n lst.sort(key=lambda x: (len(x), x))\n return lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n return sorted([i for i in lst if len(i) % 2 == 0], key=lambda x: (len(x), x))", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n # filter out strings of odd lengths\n lst = [i for i in lst if len(i) % 2 == 0]\n # sort the list first by length of each word, then alphabetically\n lst.sort(key=lambda x: (len(x), x))\n return lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n # Delete strings that have odd lengths\n lst = [word for word in lst if len(word) % 2 == 0]\n # Sort the list first by length of each word, then alphabetically\n lst.sort(key=lambda x: (len(x), x))\n return lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n # Remove strings with odd lengths\n lst = [s for s in lst if len(s) % 2 == 0]\n # Sort the list first by length and then alphabetically\n lst.sort(key=lambda s: (len(s), s))\n return lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n # Filter out strings with odd lengths\n lst = [word for word in lst if len(word) % 2 == 0]\n \n # Sort the list first by length, then alphabetically\n lst.sort(key=lambda word: (len(word), word))\n \n return lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n # delete the strings that have odd lengths\n lst = [word for word in lst if len(word) % 2 == 0]\n # sort by length and then alphabetically\n lst.sort(key=lambda x: (len(x), x))\n return lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n # Removing strings that have odd lengths\n lst = [word for word in lst if len(word) % 2 == 0]\n \n # Sorting by length of each word and alphabetically if they have the same length\n lst.sort(key=lambda x: (len(x), x))\n \n return lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n # Filter out strings with odd lengths\n lst = [x for x in lst if len(x) % 2 == 0]\n\n # Sort the list by length and then alphabetically\n lst.sort(key = lambda x: (len(x), x))\n\n return lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n # Keep only the strings with even lengths\n lst = [s for s in lst if len(s) % 2 == 0]\n # Sort the list by length first, then alphabetically\n lst.sort(key=lambda s: (len(s), s))\n return lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n # delete the strings that have odd lengths\n lst = [word for word in lst if len(word) % 2 == 0]\n # sort the list by length of each word, and then alphabetically\n lst.sort(key=lambda x: (len(x), x))\n return lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n # Filtered out odd length strings\n lst = [i for i in lst if len(i) % 2 == 0]\n # Sorted by length and then alphabetically\n lst.sort(key=lambda s: (len(s), s))\n return lst", "matching_cluster_idx": 3}]}, "Mbpp/3": {"dps": 75.21186440677965, "dps_norm": 84.375, "pass@1": 93.0, "profiled": [{"solution": "def is_not_prime(n):\n \"\"\"\n This function checks if a number is not a prime number.\n :param n: int\n :return: bool\n \"\"\"\n # First it checks if the number is less than 2 (the smallest prime number)\n if n < 2:\n return True\n # Then it checks if the number can be divided by any number up to its square root\n for i in range(2, int(n**0.5)+1):\n if n % i == 0:\n return True\n return False", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(n):\n \"\"\"Function to check if a number is not prime\"\"\"\n if n <= 1:\n return True\n elif n <= 3:\n return False\n elif n % 2 == 0 or n % 3 == 0:\n return True\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return True\n i += 6\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n if n < 2:\n return True\n for i in range(2, int(n**0.5)+1):\n if n % i == 0:\n return True\n return False", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(n):\n \"\"\"\n This function determines if a number is not prime.\n \"\"\"\n # check if the input is less than 2\n if n < 2:\n return True\n # check if the number has any divisors other than 1 and itself.\n for i in range(2, int(n**0.5)+1):\n if n % i == 0:\n return True\n return False", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(n):\n if n <= 1:\n return True\n elif n <= 3:\n return False\n elif n % 2 == 0 or n % 3 == 0:\n return True\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return True\n i += 6\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n \"\"\"\n Checks if a number is not prime.\n :param n: The number to check.\n :return: True if the number is not prime, False otherwise.\n \"\"\"\n if n < 2:\n return True\n for i in range(2, int(n ** 0.5) + 1):\n if n % i == 0:\n return True\n return False", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(n):\n if n <= 1:\n return True\n for i in range(2, n):\n if n % i == 0:\n return True\n return False", "matching_cluster_idx": 0}, {"solution": "def is_not_prime(n):\n if n <= 1:\n return True\n elif n <= 3:\n return False\n elif n % 2 == 0 or n % 3 == 0:\n return True\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return True\n i += 6\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n if n <= 1:\n return True\n elif n <= 3:\n return False\n elif n % 2 == 0 or n % 3 == 0:\n return True\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return True\n i += 6\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n \"\"\"\n Check if the number is a non-prime number.\n A non-prime number is any number that is not a natural number greater than 1 that has no positive divisors other than 1 and itself.\n\n Args:\n n (int): The number to check.\n\n Returns:\n bool: True if the number is non-prime, False if the number is prime.\n \"\"\"\n if n <= 1 or (n % 1 > 0):\n return True\n for i in range(2, int(n ** 0.5) + 1):\n if n % i == 0:\n return True\n return False", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(n):\n if n <= 1:\n return True\n if n <= 3:\n return False\n if n % 2 == 0 or n % 3 == 0:\n return True\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return True\n i += 6\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n if n <= 1:\n return True\n if n <= 3:\n return False\n if n % 2 == 0 or n % 3 == 0:\n return True\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return True\n i += 6\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n if n <= 1 or (n % 2 == 0 and n > 2): \n return True\n for i in range(3, int(n**0.5) + 1, 2):\n if n % i == 0:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n \"\"\"\n Function to check if the number is non-prime\n \"\"\"\n if n <= 1:\n return True\n elif n <= 3:\n return False\n elif n % 2 == 0 or n % 3 == 0:\n return True\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return True\n i += 6\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n \"\"\"\n A function to check if a number is not a prime number.\n \"\"\"\n if n <= 1: \n return True\n if n <= 3: \n return False\n if n % 2 == 0 or n % 3 == 0: \n return True\n i = 5\n while i * i <= n: \n if n % i == 0 or n % (i + 2) == 0: \n return True\n i += 6\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n \"\"\"\n Return True if the given number is not prime, False otherwise.\n \"\"\"\n if n <= 1:\n return True\n for i in range(2, int(n**0.5)+1):\n if n % i == 0:\n return True\n return False", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(n):\n \"\"\"\n This function checks if a number is not a prime number.\n \"\"\"\n # numbers less than 2 are not prime\n if n < 2:\n return True\n\n # 2 and 3 are prime\n if n <= 3:\n return False\n\n # check if n is divisible by 2 or 3\n if n % 2 == 0 or n % 3 == 0:\n return True\n\n i = 5\n while i * i <= n:\n # check divisibility by potential factors\n if n % i == 0 or n % (i + 2) == 0:\n return True\n i += 6\n\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n if n < 2:\n return True\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return True\n return False", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(n):\n \"\"\"\n Check if a number is not prime\n \"\"\"\n if n < 2:\n return True\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return True\n return False", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(n):\n if n < 2:\n return True\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return True\n return False", "matching_cluster_idx": 5}]}, "Mbpp/4": {"dps": 95.22184300341297, "dps_norm": 83.33333333333333, "pass@1": 97.0, "profiled": [{"solution": "def heap_queue_largest(nums, n):\n import heapq\n return heapq.nlargest(n, nums)", "matching_cluster_idx": 9}, {"solution": "def heap_queue_largest(numbers, n):\n import heapq\n return heapq.nlargest(n, numbers)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(numbers, n):\n return heapq.nlargest(n, numbers)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n largest_nums = heapq.nlargest(n, nums)\n return largest_nums", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(lst, n):\n return heapq.nlargest(n, lst)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(lst, n):\n return heapq.nlargest(n, lst)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(lst, n):\n \"\"\"\n Function to find the n largest integers from a given list of numbers, returned in descending order.\n \"\"\"\n \n # Using nlargest function of heapq module\n return heapq.nlargest(n, lst)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(lst, n):\n return heapq.nlargest(n, lst)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(numbers, n):\n largest_nums = heapq.nlargest(n, numbers)\n return largest_nums", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n # Using the inbuilt heapq module to find the n largest numbers\n n_largest = heapq.nlargest(n, nums)\n return n_largest", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(lst, n):\n \"\"\"\n Function to find n largest integers from a given list of numbers, returned in descending order.\n \"\"\"\n largest_nums = heapq.nlargest(n, lst)\n return largest_nums", "matching_cluster_idx": 9}, {"solution": "def heap_queue_largest(lst, n):\n import heapq\n return heapq.nlargest(n, lst)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(lst,n):\n # Use heapq largest function to find the 'n' largest elements \n return heapq.nlargest(n, lst)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n return heapq.nlargest(n, nums)", "matching_cluster_idx": 9}, {"solution": "def heap_queue_largest(numbers, n):\n import heapq\n return heapq.nlargest(n, numbers)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(numbers, n):\n \"\"\"Function to find the n largest integers from a given list of numbers, returned in descending order\"\"\"\n largest_numbers = heapq.nlargest(n, numbers)\n return largest_numbers", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(numbers, n):\n \"\"\"\n This function uses 'heapq.nlargest' to find the 'n' largest numbers in 'numbers' list.\n It then returns these numbers in descending order.\n \"\"\"\n return heapq.nlargest(n, numbers)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n return heapq.nlargest(n, nums)", "matching_cluster_idx": 9}, {"solution": "def heap_queue_largest(nums, n):\n import heapq\n return heapq.nlargest(n, nums)", "matching_cluster_idx": 9}, {"solution": "def heap_queue_largest(num_list, n):\n import heapq\n return heapq.nlargest(n, num_list)", "matching_cluster_idx": 9}]}, "Mbpp/9": {"dps": 97.27891156462584, "dps_norm": 60.0, "pass@1": 11.0, "profiled": [{"solution": "def find_Rotations(string):\n # Form a double String \n doubleString = string + string\n \n n = len(string)\n \n for i in range(1,n+1):\n # Get the rotated string\n rotatedString = doubleString[i: n+i]\n # Check if rotated string is same as original string\n if string == rotatedString:\n return i\n return n", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(string):\n # Create double string\n double_string = string * 2\n\n # check each rotation\n for i in range(1, len(string) + 1):\n # rotate the string by i\n rotated_string = double_string[i:i + len(string)]\n # if the rotated string is the same as the input string,\n # then return the number of rotations, which is i\n if rotated_string == string:\n return i", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(str):\n # create a temporary string with value = 2*str\n tmp = str * 2\n n = len(str)\n \n # Try all rotations of 'str'\n for i in range(1, n + 1):\n rotation = tmp[i: n+i]\n\n # If after rotation, we get the original string back\n if str == rotation:\n return i\n return n", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(string):\n # Concatenate the input string with itself\n temp = string + string\n\n # For each rotation of the input string\n for i in range(1, len(string) + 1):\n\n # Slice the temp string from the beginning up to the current index\n rotated_str = temp[i: i + len(string)]\n\n # If the rotation matches the input string, return the number of rotations\n if rotated_str == string:\n return i", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(str):\n # create a temporary string\n temp = str + str\n\n # consider all rotations of given string\n for i in range(1, len(str) + 1):\n # compare current rotation with given string\n if (str == temp[i: len(str) + i]):\n # return number of rotations\n return i\n return len(str)", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(string):\n # concatenate the input string to itself.\n tmp = string + string\n \n # do binary search in the rotated string array.\n n = len(string)\n for i in range(1, n + 1):\n s = tmp[i: n+i]\n if s == string:\n return i\n \n # if no rotation is possible.\n return -1", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(string):\n # doubling the string and creating an array \n double_string = string + string\n for i in range(1, len(string) + 1):\n # using slicing operation to generate the rotated string\n rotated_string = double_string[i: i + len(string)]\n if rotated_string == string:\n return i", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(str):\n # Concatenate str to str\n tmp = str + str\n \n # Consider all rotations of str\n # starting from the 2nd character\n for i in range(1, len(str) + 1):\n rotatedString = tmp[i : i + len(str)]\n \n # If rotated string matches with original string\n if str == rotatedString:\n return i\n \n # If no such rotation matches\n return len(str)", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(str):\n '''\n The function finds the minimum number of rotations required to get the same string\n '''\n\n # If all characters in input string are same, \n # then return 1, as rotating the same string \n # will always result in the same string\n if (len(set(str)) == 1):\n return 1\n\n # To store all rotations of string\n temp = str + str\n n = len(str)\n\n for i in range(1, n + 1):\n # To get the current rotation of str\n curr = temp[i : n + i]\n\n # If the current rotation is same as the given string\n if (str == curr):\n # Returning number of rotations\n return i", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(str):\n \"\"\"\n This function returns the minimum number of rotations \n required to get the same string.\n \"\"\"\n if len(str) == 0:\n return 0\n\n # Create a temp string with value str.str\n temp = str + str\n\n # Now start doing comparisons\n n = len(str)\n for i in range(1, n + 1):\n # See if first n characters of temp match with str\n if temp[i: i + n] == str:\n return i\n return n", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(string):\n double_string = string * 2\n for i in range(1, len(string) + 1):\n if string == double_string[i:i + len(string)]:\n return i", "matching_cluster_idx": 5}]}, "Mbpp/11": {"dps": 95.55555555555556, "dps_norm": 97.77777777777777, "pass@1": 45.0, "profiled": [{"solution": "def remove_Occ(string, char):\n \"\"\"Remove the first and last occurrence of char in string\"\"\"\n first = string.find(char)\n if first != -1:\n last = string.rfind(char)\n string = string[:first] + string[first+1:last] + string[last+1:]\n return string", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(input_string, character):\n first_occurrence = input_string.find(character)\n last_occurrence = input_string.rfind(character)\n if first_occurrence != -1 and last_occurrence != -1:\n return input_string[:first_occurrence] + input_string[first_occurrence+1:last_occurrence] + input_string[last_occurrence+1:]\n else:\n return input_string", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(s, c):\n first = s.find(c)\n last = s.rfind(c)\n \n if first == last == -1:\n return s\n elif first == last:\n return s[:first] + s[first+1:]\n else:\n return s[:first] + s[first+1:last] + s[last+1:]", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(s: str, char: str) -> str:\n if char not in s:\n return s\n s = s.replace(char, '', 1) # Removes first occurrence\n s = s[::-1].replace(char, '', 1) # Removes last occurrence\n return s[::-1]", "matching_cluster_idx": 4}, {"solution": "def remove_Occ(str, char):\n first_occ = str.find(char)\n last_occ = str.rfind(char)\n \n if first_occ == -1 or last_occ == -1: # if char not found in the string\n return str\n\n # remove first and last occurrence of the character\n return str[:first_occ] + str[first_occ+1:last_occ] + str[last_occ+1:]", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(string, char):\n # Find the first and last occurrence of the given character\n first = string.find(char)\n last = string.rfind(char)\n\n # If the character is not found, return the original string\n if first == -1:\n return string\n\n # If the first and last occurrence are the same (i.e., the character only appears once), remove it from the string\n if first == last:\n return string.replace(char, \"\")\n\n # Otherwise, remove the first and last occurrence of the character\n return string[:first] + string[first+1:last] + string[last+1:]", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(s, c):\n first = s.find(c)\n last = s.rfind(c)\n if first == -1:\n return s\n return s[:first] + s[first+1:last] + s[last+1:]", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(input_string, character):\n first_occurrence = input_string.find(character)\n last_occurrence = input_string.rfind(character)\n\n if first_occurrence == -1: # Character not found in string\n return input_string\n else:\n return input_string[:first_occurrence] + input_string[first_occurrence+1:last_occurrence] + input_string[last_occurrence+1:]", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(s, c):\n first_occ = s.find(c)\n last_occ = s.rfind(c)\n if first_occ == -1 or last_occ == -1:\n return s\n return s[:first_occ] + s[first_occ+1:last_occ] + s[last_occ+1:]", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(str1, char1):\n first_occurrence = str1.find(char1)\n last_occurrence = str1.rfind(char1)\n\n if first_occurrence != -1 and last_occurrence != -1:\n str1 = str1[:first_occurrence] + str1[first_occurrence + 1:last_occurrence] + str1[last_occurrence + 1:]\n\n return str1", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(input_string, character):\n first_occurrence = input_string.find(character)\n last_occurrence = input_string.rfind(character)\n \n # For edge cases where the character does not exist in the string\n if first_occurrence == -1:\n return input_string\n\n # For the case where first and last occurrence are the same character in the same position\n if first_occurrence == last_occurrence:\n return input_string[:first_occurrence] + input_string[first_occurrence + 1:]\n\n return input_string[:first_occurrence] + input_string[first_occurrence + 1:last_occurrence] + input_string[last_occurrence + 1:]", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(input_string, target_char):\n first_occurrence = input_string.find(target_char)\n last_occurrence = input_string.rfind(target_char)\n \n # If the target_char doesn't exist in the string\n if first_occurrence == -1:\n return input_string\n else:\n # Remove the first and last occurrence\n return input_string[:first_occurrence] + input_string[first_occurrence+1:last_occurrence] + input_string[last_occurrence+1:]", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(s, c):\n first = s.find(c)\n last = s.rfind(c)\n \n if first == last == -1: # If character not found in string\n return s\n elif first == last: # If character occurs only once\n return s[:first] + s[first + 1:]\n else:\n return s[:first] + s[first + 1:last] + s[last + 1:]", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(s, c):\n first = s.find(c)\n last = s.rfind(c)\n if first == last == -1: # If character is not found in string\n return s\n return s[:first] + s[first+1:last] + s[last+1:]", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(string: str, char: str) -> str:\n first_occurrence = string.find(char)\n last_occurrence = string.rfind(char)\n \n if first_occurrence == -1 or last_occurrence == -1: # if the char doesn't exist or only occurs once\n return string\n\n return string[:first_occurrence] + string[first_occurrence + 1:last_occurrence] + string[last_occurrence + 1:]", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(input_string, char_to_remove):\n first_occurrence = input_string.find(char_to_remove)\n last_occurrence = input_string.rfind(char_to_remove)\n \n if first_occurrence != -1 and last_occurrence != -1:\n new_string = input_string[:first_occurrence] + input_string[first_occurrence+1:last_occurrence] + input_string[last_occurrence+1:]\n return new_string\n else:\n return input_string", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(s, ch):\n first_occ = s.find(ch)\n last_occ = s.rfind(ch)\n \n if first_occ == -1 or last_occ == -1:\n return s\n \n return s[:first_occ] + s[first_occ+1:last_occ] + s[last_occ+1:]", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(input_string, char_to_remove):\n #Find the first and last occurrence of the character.\n first_occ = input_string.find(char_to_remove)\n last_occ = input_string.rfind(char_to_remove)\n\n #Check if the character occurs in the string.\n if first_occ != -1:\n #Remove the first and last occurrence.\n input_string = input_string[:first_occ] + input_string[first_occ + 1:last_occ] + input_string[last_occ + 1:]\n\n return input_string", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(s, c):\n first = s.find(c)\n last = s.rfind(c)\n \n if first == -1 or last == -1: # If character is not found in the string\n return s\n \n return s[:first] + s[first+1:last] + s[last+1:]", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(string, char):\n first_occurrence = string.find(char)\n last_occurrence = string.rfind(char)\n \n if first_occurrence == -1 or last_occurrence == -1: \n return string\n else:\n return string[:first_occurrence] + string[first_occurrence+1:last_occurrence] + string[last_occurrence+1:]", "matching_cluster_idx": 8}]}, "Mbpp/12": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 99.0, "profiled": [{"solution": "def sort_matrix(matrix):\n return sorted(matrix, key=sum)", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(m):\n # Sort the matrix by the sum of its rows in ascending order\n return sorted(m, key=sum)", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(m):\n m.sort(key=sum)\n return m", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n return sorted(matrix, key=sum)", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(mat):\n # Sort the matrix in ascending order according to the sum of its rows\n return sorted(mat, key=sum)", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # The function computes the sum of the rows in each row, sorts the rows based on the row sum\n # and returns the sorted matrix\n return sorted(matrix, key=sum)", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n return sorted(matrix, key=sum)", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n return sorted(matrix, key=sum)", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n return sorted(matrix, key=sum)", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Calculate sum of each row and sort matrix based on those sums\n return sorted(matrix, key=sum)", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n return sorted(matrix, key=sum)", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n return sorted(matrix, key=sum)", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n return sorted(matrix, key=sum)", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Calculate sum of each row\n sums = [sum(row) for row in matrix]\n # Sort the matrix based on row sums\n matrix = [x for _,x in sorted(zip(sums, matrix))]\n return matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # First, calculate the sum of each row and store in a list of tuples where the first element is the sum \n # and the second element is the row itself\n sum_rows = [(sum(row), row) for row in matrix]\n\n # Then sort this list of tuples, the rows with the smallest sum will be at the front\n sum_rows.sort()\n\n # Finally, we extract the sorted rows and return as a new matrix\n sorted_matrix = [row for _, row in sum_rows]\n return sorted_matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Sort the matrix by the sum of its rows\n return sorted(matrix, key=sum)", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # sort the matrix by the sum of each row\n return sorted(matrix, key=sum)", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n return sorted(matrix, key=sum)", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Calculate the sum of each row and sort the matrix based on these sums.\n return sorted(matrix, key=sum)", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n return sorted(matrix, key=sum)", "matching_cluster_idx": 15}]}, "Mbpp/16": {"dps": null, "dps_norm": null, "pass@1": 4.0, "profiled": []}, "Mbpp/19": {"dps": 64.64646464646465, "dps_norm": 80.0, "pass@1": 83.0, "profiled": [{"solution": "def test_duplicate(nums):\n \"\"\"\n The function checks if the input list contains duplicate elements.\n \n Parameters:\n nums (list): the list of numbers to be checked\n \n Returns:\n bool: True if there is at least one duplicate element in the list. False if all elements are unique.\n \"\"\"\n if len(nums) == len(set(nums)):\n return False\n else:\n return True", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(nums):\n \"\"\"\n The function checks if a list of integers contains any duplicate element.\n \n Arguments:\n nums {list} -- List of integers\n \n Returns:\n bool -- True if the list has duplicate elements, False otherwise\n \"\"\"\n if len(nums) == len(set(nums)):\n return False\n else:\n return True", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(array):\n \"\"\"\n Check if an array contains duplicate elements.\n \"\"\"\n return len(array) != len(set(array))", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(arr):\n if len(arr) == len(set(arr)):\n return False\n else:\n return True", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(nums):\n \"\"\"Function to check if an array contains duplicate elements.\"\"\"\n if len(nums) == len(set(nums)):\n return False\n else:\n return True", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(nums):\n if len(nums) == len(set(nums)):\n return False\n else:\n return True", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(nums):\n if len(nums) == len(set(nums)):\n return False\n else:\n return True", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(arr):\n \"\"\"\n This function will check if an array contains any duplicates.\n It converts the given array into a set and then checks if the length of the set is less than the length of the given array.\n If yes, it means that there were some duplicate elements in the array.\n \"\"\"\n \n # Create a set from the input array\n arr_set = set(arr)\n \n # If lengths of the set and array are equal, there are no duplicates.\n if len(arr_set) == len(arr):\n return False\n else:\n # If lengths are not equal, there are duplicates.\n return True", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(arr):\n \"\"\"\n Function to find whether a given array of integers contains any duplicate element.\n \"\"\"\n if len(arr) == len(set(arr)):\n return False\n else:\n return True", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(arr):\n if len(arr) == len(set(arr)):\n return False\n else:\n return True", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(num_array):\n if len(num_array) == len(set(num_array)):\n return False\n else:\n return True", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(arr):\n \"\"\"Function to test if array has any duplicate elements.\"\"\"\n return len(arr) != len(set(arr))", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(input_list):\n if len(input_list) == len(set(input_list)):\n return False\n else:\n return True", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(nums):\n if len(nums) == len(set(nums)):\n return False\n else:\n return True", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(input_list):\n return len(input_list) != len(set(input_list))", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(lst):\n \"\"\"\n Check if a list contains any duplicate elements\n \"\"\"\n if len(lst) == len(set(lst)):\n return False\n else:\n return True", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(array):\n \"\"\"\n Function to find if an array of integers contains any duplicate.\n\n Parameters:\n array (list): A list of integers.\n \n Returns:\n bool: True if the array contains duplicate elements. False otherwise.\n \"\"\"\n return len(array) != len(set(array))", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(arr):\n if len(arr) == len(set(arr)):\n return False\n else:\n return True", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(arr):\n if len(arr) == len(set(arr)):\n return False\n else:\n return True", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(lst):\n if len(lst) == len(set(lst)):\n return False\n else:\n return True", "matching_cluster_idx": 11}]}, "Mbpp/62": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def smallest_num(numbers):\n return min(numbers)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(list):\n return min(list)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(lst):\n return min(lst)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(lst):\n return min(lst)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(list_num):\n return min(list_num)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(lst):\n return min(lst)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(num_list):\n return min(num_list)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(nums):\n return min(nums)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(lst):\n return min(lst)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(lst):\n \"\"\"\n This function takes a list of numbers as input and returns the smallest number in the list.\n \"\"\"\n return min(lst)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(num_list):\n return min(num_list)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(lst):\n return min(lst)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(num_list):\n return min(num_list)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(lst):\n return min(lst)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(lst):\n return min(lst)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(lst):\n return min(lst)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(lst):\n return min(lst)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(num_list):\n return min(num_list)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(lst):\n return min(lst)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(lst):\n return min(lst)", "matching_cluster_idx": 4}]}, "Mbpp/75": {"dps": 93.21428571428572, "dps_norm": 68.33333333333334, "pass@1": 100.0, "profiled": [{"solution": "def find_tuples(lst, k):\n result = [t for t in lst if all(x % k == 0 for x in t)]\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(lst, k):\n return [t for t in lst if all(i % k == 0 for i in t)]", "matching_cluster_idx": 5}, {"solution": "def find_tuples(lst, k):\n result = [t for t in lst if all(x % k == 0 for x in t)]\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(lst, k):\n \"\"\"Finds tuples which have all elements divisible by k from a given list of tuples.\n \n Args:\n lst: List of tuples.\n k: Integer divisor.\n\n Returns:\n List of tuples where all elements are divisible by k.\n \"\"\"\n return [t for t in lst if all(x % k == 0 for x in t)]", "matching_cluster_idx": 5}, {"solution": "def find_tuples(lst, k):\n return [t for t in lst if all(i % k == 0 for i in t)]", "matching_cluster_idx": 5}, {"solution": "def find_tuples(lst, k):\n result = [t for t in lst if all(x % k == 0 for x in t)]\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(lst, k):\n return [t for t in lst if all(x % k == 0 for x in t)]", "matching_cluster_idx": 5}, {"solution": "def find_tuples(lst, k):\n return [t for t in lst if all(i % k == 0 for i in t)]", "matching_cluster_idx": 5}, {"solution": "def find_tuples(t_list, k):\n return [t for t in t_list if all(i % k == 0 for i in t)]", "matching_cluster_idx": 5}, {"solution": "def find_tuples(lst, k):\n result = [t for t in lst if all(i % k == 0 for i in t)]\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(lst, k):\n return [t for t in lst if all(i % k == 0 for i in t)]", "matching_cluster_idx": 5}, {"solution": "def find_tuples(lst, k):\n return [t for t in lst if all(i % k == 0 for i in t)]", "matching_cluster_idx": 5}, {"solution": "def find_tuples(lst, k):\n return [t for t in lst if all(i % k == 0 for i in t)]", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples, k):\n result = [t for t in tuples if all(i % k == 0 for i in t)]\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuple_list, k):\n return [t for t in tuple_list if all(i % k == 0 for i in t)]", "matching_cluster_idx": 5}, {"solution": "def find_tuples(lst, k):\n return [t for t in lst if all(i % k == 0 for i in t)]", "matching_cluster_idx": 5}, {"solution": "def find_tuples(t_list, k):\n #result list to store tuples that meet the criteria\n result = []\n #iterate over each tuple in the list\n for t in t_list:\n #all function returns True if all elements in iterable (tuple) are True\n #we use a map object where every element is checked if it is divisible by k\n if all(map(lambda x: x % k == 0, t)):\n result.append(t)\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(lst, k):\n return [t for t in lst if all(x % k == 0 for x in t)]", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples, k):\n # list to store results\n result = []\n for tuple in tuples:\n # Boolean flag to store if tuple contains only elements divisible by k\n is_divisible = True\n for element in tuple:\n # if element not divisible by k, set is_divisible to False and break\n if element % k != 0:\n is_divisible = False\n break\n # if is_divisible is True, append tuple to result\n if is_divisible:\n result.append(tuple)\n return result", "matching_cluster_idx": 8}, {"solution": "def find_tuples(list_of_tuples, k):\n return [t for t in list_of_tuples if all(x % k == 0 for x in t)]", "matching_cluster_idx": 5}]}, "Mbpp/88": {"dps": 96.56862745098039, "dps_norm": 85.71428571428571, "pass@1": 100.0, "profiled": [{"solution": "def freq_count(lst):\n freq_dict = {}\n for element in lst:\n if element in freq_dict:\n freq_dict[element] += 1\n else:\n freq_dict[element] = 1\n return freq_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n freqs = {}\n for i in lst:\n if i in freqs:\n freqs[i] += 1\n else:\n freqs[i] = 1\n return freqs", "matching_cluster_idx": 5}, {"solution": "def freq_count(input_list):\n freq_dict = {}\n for i in input_list:\n if i in freq_dict:\n freq_dict[i] += 1\n else:\n freq_dict[i] = 1\n return freq_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n freq_dict = {}\n for i in lst:\n if i in freq_dict:\n freq_dict[i] += 1\n else:\n freq_dict[i] = 1\n return freq_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n freq_dict = {}\n for i in lst:\n if i in freq_dict:\n freq_dict[i] += 1\n else:\n freq_dict[i] = 1\n return freq_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(input_list):\n output_dict = {}\n for item in input_list:\n if item in output_dict:\n output_dict[item] += 1\n else:\n output_dict[item] = 1\n return output_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n frequency_dict = {}\n for element in lst:\n if element in frequency_dict:\n frequency_dict[element] += 1\n else:\n frequency_dict[element] = 1\n return frequency_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(input_list):\n freq_dict = {}\n for item in input_list:\n if item in freq_dict:\n freq_dict[item] += 1\n else:\n freq_dict[item] = 1\n return freq_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n freq_dict = {}\n for elem in lst:\n if elem in freq_dict:\n freq_dict[elem] += 1\n else:\n freq_dict[elem] = 1\n return freq_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n # Initialize an empty dictionary to store the frequency count\n freq_dict = {}\n\n # Iterate over the list\n for element in lst:\n # If the element is not in the dictionary, add it with a count of 1\n if element not in freq_dict:\n freq_dict[element] = 1\n # If the element is already in the dictionary, increment its count by 1\n else:\n freq_dict[element] += 1\n\n # Return the dictionary\n return freq_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n freq_dict = {}\n for i in lst:\n if i in freq_dict:\n freq_dict[i] += 1\n else:\n freq_dict[i] = 1\n return freq_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n # Create an empty dictionary to hold the frequency counts\n freq_dict = {}\n \n # Iterate over each element in the input list\n for element in lst:\n # If the element is already in the dictionary, increment its count\n if element in freq_dict:\n freq_dict[element] += 1\n # Otherwise, add the element to the dictionary with a count of 1\n else:\n freq_dict[element] = 1\n \n # Return the frequency dictionary\n return freq_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n freq_dict = {}\n for i in lst:\n if i in freq_dict:\n freq_dict[i] += 1\n else:\n freq_dict[i] = 1\n return freq_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(input_list):\n freq_dict = {}\n for i in input_list:\n if i in freq_dict:\n freq_dict[i] += 1\n else:\n freq_dict[i] = 1\n return freq_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n freq = {}\n for ele in lst:\n if ele in freq:\n freq[ele] += 1\n else:\n freq[ele] = 1\n return freq", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n freq_dict = {}\n for i in lst:\n if i in freq_dict:\n freq_dict[i] += 1\n else:\n freq_dict[i] = 1\n return freq_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n freqs = {}\n for element in lst:\n if element in freqs:\n freqs[element] += 1\n else:\n freqs[element] = 1\n return freqs", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n freq_dict = {}\n for i in lst:\n if i in freq_dict:\n freq_dict[i] += 1\n else:\n freq_dict[i] = 1\n return freq_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n freq_dict = {}\n for i in lst:\n if i in freq_dict:\n freq_dict[i] += 1\n else:\n freq_dict[i] = 1\n return freq_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n frequency = {}\n for ele in lst:\n if ele in frequency:\n frequency[ele] += 1\n else:\n frequency[ele] = 1\n return frequency", "matching_cluster_idx": 5}]}, "Mbpp/90": {"dps": null, "dps_norm": null, "pass@1": 0.0, "profiled": []}, "Mbpp/94": {"dps": 78.04878048780488, "dps_norm": 60.0, "pass@1": 98.0, "profiled": [{"solution": "def index_minimum(input_list):\n # find the tuple with the smallest second value\n smallest = min(input_list, key=lambda x: x[1])\n # return the first value of that tuple\n return smallest[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(lst):\n return min(lst, key=lambda x: x[1])[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(lst):\n return min(lst, key=lambda x: x[1])[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(list_of_tuples):\n return min(list_of_tuples, key=lambda x: x[1])[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(t_list):\n # sort the list of tuples by the second value of each tuple\n sorted_list = sorted(t_list, key=lambda x: x[1])\n # return the first value of the tuple with the smallest second value\n return sorted_list[0][0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(tuples_list):\n smallest_tuple = min(tuples_list, key=lambda x: x[1])\n return smallest_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(tuples_list):\n return min(tuples_list, key=lambda x: x[1])[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(lst):\n return min(lst, key=lambda x: x[1])[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(tuples):\n # The \"key\" argument of \"min\" is a function that gets applied to each item \n # before comparing them. Here, it gives the second element of each tuple\n smallest_tuple = min(tuples, key=lambda x: x[1])\n # Return the first value of the smallest tuple\n return smallest_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(tuple_list):\n \"\"\"\n Given a list of tuples, return the first value of the tuple with the smallest second value.\n \"\"\"\n # Check if the list is not empty\n if tuple_list:\n # Return the first value of the tuple with the smallest second value.\n return min(tuple_list, key=lambda x: x[1])[0]\n else:\n return None", "matching_cluster_idx": 2}, {"solution": "def index_minimum(lst):\n return min(lst, key=lambda x:x[1])[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(list_of_tuples):\n \"\"\"Return the first value of the tuple with the smallest second value\"\"\"\n return min(list_of_tuples, key=lambda x: x[1])[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(lst):\n return min(lst, key=lambda x: x[1])[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(list_of_tuples):\n # Use min function with a key to get the tuple with the smallest second value\n min_tuple = min(list_of_tuples, key=lambda x: x[1])\n # Return the first value of the tuple\n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(lst):\n return min(lst, key=lambda x: x[1])[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(lst):\n return min(lst, key=lambda x:x[1])[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(list_of_tuples):\n smallest_second_value = min(list_of_tuples, key=lambda x: x[1])\n return smallest_second_value[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(tuples):\n # Find the index of the tuple with the smallest second value\n index_min = min(range(len(tuples)), key=lambda i: tuples[i][1])\n \n # Return the first value of the tuple with the smallest second value\n return tuples[index_min][0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(tuples_list):\n return min(tuples_list, key=lambda x: x[1])[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(tuples):\n return min(tuples, key=lambda x: x[1])[0]", "matching_cluster_idx": 2}]}, "Mbpp/96": {"dps": 91.1111111111111, "dps_norm": 77.14285714285714, "pass@1": 93.0, "profiled": [{"solution": "def divisor(n):\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n count += 2\n if i * i == n:\n count -= 1\n return count", "matching_cluster_idx": 6}, {"solution": "def divisor(n):\n count = 0\n for i in range(1, int(n**0.5)+1):\n if n % i == 0:\n count += 2 if n / i != i else 1\n return count", "matching_cluster_idx": 6}, {"solution": "def divisor(n):\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n count = 0\n for i in range(1, int(n ** 0.5) + 1):\n if n % i == 0:\n count += 2 if n / i != i else 1\n return count", "matching_cluster_idx": 6}, {"solution": "def divisor(n):\n count = 0\n for i in range(1, int(n**0.5)+1):\n if n % i == 0:\n # In case of a divisor pair, say (2, 10), we increment the count by 2.\n count += 2\n # In case n is a perfect square, we have counted its square root twice.\n if n == i*i:\n count -= 1\n return count", "matching_cluster_idx": 6}, {"solution": "def divisor(n):\n count = 0\n for i in range(1, int(n**0.5)+1):\n if n % i == 0:\n if n/i == i:\n count = count + 1\n else:\n count = count + 2\n return count", "matching_cluster_idx": 6}, {"solution": "def divisor(n):\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n if i == n//i:\n count = count + 1\n else:\n count = count + 2\n return count", "matching_cluster_idx": 6}, {"solution": "def divisor(n):\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n # If divisors are equal\n if i * i == n:\n count += 1\n else: # Otherwise\n count += 2\n return count", "matching_cluster_idx": 6}, {"solution": "def divisor(n):\n count = 0\n for i in range(1, int(n**0.5)+1): \n if n % i == 0: \n count += 2 if n/i != i else 1\n return count", "matching_cluster_idx": 6}, {"solution": "def divisor(n):\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n count += 2 # counting both i and n/i\n # check if n is a perfect square and reduce the count by 1\n if n**0.5 == i:\n count -= 1\n return count", "matching_cluster_idx": 6}, {"solution": "def divisor(n):\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n # In case of a divisor pair (i, n//i)\n count += 2 if i != n//i else 1\n return count", "matching_cluster_idx": 6}, {"solution": "def divisor(n):\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n count += 2\n if i == n // i:\n count -= 1\n return count", "matching_cluster_idx": 6}, {"solution": "def divisor(n):\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(num):\n count = 0\n for i in range(1, num+1):\n if num % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n count = 0\n for i in range(1, int(n**0.5)+1): \n if n % i == 0:\n if n / i == i:\n count += 1\n else:\n count += 2\n return count", "matching_cluster_idx": 6}]}, "Mbpp/97": {"dps": 90.35897435897436, "dps_norm": 81.25, "pass@1": 100.0, "profiled": [{"solution": "def frequency_lists(lst):\n flatten_list = [item for sublist in lst for item in sublist]\n return {i: flatten_list.count(i) for i in flatten_list}", "matching_cluster_idx": 1}, {"solution": "def frequency_lists(lst):\n flat_list = [item for sublist in lst for item in sublist]\n frequency_dict = {}\n for i in flat_list:\n if i in frequency_dict:\n frequency_dict[i] += 1\n else:\n frequency_dict[i] = 1\n return frequency_dict", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lst):\n flat_list = [item for sublist in lst for item in sublist]\n freq = {}\n for item in flat_list:\n if item in freq:\n freq[item] += 1\n else:\n freq[item] = 1\n return freq", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(list_of_lists):\n \"\"\"\n Function that takes a list of lists and returns a dictionary with the frequency of each element.\n\n Args:\n list_of_lists: list of lists with integers\n\n Returns:\n Dictionary with integers as keys and frequency as values.\n\n \"\"\"\n from collections import Counter\n flattened_list = [num for sublist in list_of_lists for num in sublist]\n return dict(Counter(flattened_list))", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(list_of_lists):\n # Flatten the list of lists\n flat_list = [element for sublist in list_of_lists for element in sublist]\n\n # Create a dictionary to store element frequencies\n freq_dict = {}\n\n # Iterate over the flat list and update frequencies in dictionary\n for element in flat_list:\n if element in freq_dict:\n freq_dict[element] += 1\n else:\n freq_dict[element] = 1\n\n return freq_dict", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(list_of_lists):\n from collections import Counter\n flat_list = [item for sublist in list_of_lists for item in sublist]\n return dict(Counter(flat_list))", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lst):\n \"\"\"\n This function finds the frequency of each element in a flattened list of lists and returns the results in a dictionary.\n \"\"\"\n flattened_lst = [i for sublist in lst for i in sublist]\n freq_dict = {}\n for item in flattened_lst:\n if (item in freq_dict):\n freq_dict[item] += 1\n else:\n freq_dict[item] = 1\n return freq_dict", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lst):\n freq_dict = {}\n for sublist in lst:\n for item in sublist:\n if item in freq_dict:\n freq_dict[item] += 1\n else:\n freq_dict[item] = 1\n return freq_dict", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lst):\n flatten_list = [item for sublist in lst for item in sublist]\n frequency = {}\n for i in flatten_list:\n if i in frequency:\n frequency[i] += 1\n else:\n frequency[i] = 1\n return frequency", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lst):\n flattened = [item for sublist in lst for item in sublist]\n frequency = {}\n for i in flattened:\n if i in frequency:\n frequency[i] += 1\n else:\n frequency[i] = 1\n return frequency", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lsts):\n freq_dict = {}\n for lst in lsts:\n for ele in lst:\n if ele in freq_dict:\n freq_dict[ele] += 1\n else:\n freq_dict[ele] = 1\n return freq_dict", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lists):\n freq_dict = {}\n for sublist in lists:\n for item in sublist:\n if item in freq_dict:\n freq_dict[item] += 1\n else:\n freq_dict[item] = 1\n return freq_dict", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lsts):\n from collections import Counter\n flattened_list = [item for sublist in lsts for item in sublist]\n return dict(Counter(flattened_list))", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lst):\n # Flatten the list of lists\n flat_list = [item for sublist in lst for item in sublist]\n\n # Create a dictionary and populate it with the count of each element\n freq_dict = {}\n for i in flat_list:\n if i in freq_dict:\n freq_dict[i] += 1\n else:\n freq_dict[i] = 1\n\n return freq_dict", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(list_of_lists):\n flattened_list = [elem for sublist in list_of_lists for elem in sublist]\n frequency_dict = {}\n for elem in flattened_list:\n if elem in frequency_dict:\n frequency_dict[elem] += 1\n else:\n frequency_dict[elem] = 1\n return frequency_dict", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(ll):\n \"\"\"Return the frequency of each element in a flattened list of lists.\n\n Parameters:\n ll (list): a list of lists\n\n Returns:\n dict: a dictionary where keys are the elements in the list of lists,\n and values are their frequencies.\n \"\"\"\n # Flatten the list of lists\n flat_list = [item for sublist in ll for item in sublist]\n \n # Initialize an empty dictionary\n freq_dict = {}\n \n # Iterate over the flattened list\n for i in flat_list:\n # If the item is already in the dictionary, increment its count\n if i in freq_dict:\n freq_dict[i] += 1\n # If the item is not in the dictionary, add it with a count of 1\n else:\n freq_dict[i] = 1\n \n return freq_dict", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lists):\n frequency = {}\n for sublist in lists:\n for item in sublist:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n return frequency", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lst):\n flattened_list = [item for sublist in lst for item in sublist]\n frequency_dict = {}\n for i in flattened_list:\n if i in frequency_dict:\n frequency_dict[i] += 1\n else:\n frequency_dict[i] = 1\n return frequency_dict", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(ll):\n # Flatten the list of lists\n flat_list = [item for sublist in ll for item in sublist]\n\n # Create a dictionary with the frequency of each element\n freq_dict = {}\n for elem in flat_list:\n if elem in freq_dict:\n freq_dict[elem] += 1\n else:\n freq_dict[elem] = 1\n\n return freq_dict", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lst):\n flattened = [num for sublist in lst for num in sublist]\n result = {num: flattened.count(num) for num in flattened}\n return result", "matching_cluster_idx": 1}]}, "Mbpp/106": {"dps": 54.51298701298701, "dps_norm": 85.83333333333333, "pass@1": 90.0, "profiled": [{"solution": "def add_lists(lst, tpl):\n return tuple(tpl) + tuple(lst)", "matching_cluster_idx": 4}, {"solution": "def add_lists(lst, tpl):\n \"\"\"Appends a list to a tuple and returns a new tuple.\"\"\"\n # Convert the tuple to a list so we can append the elements from the input list\n new_tpl = list(tpl)\n \n # Append each element from the input list to the new list\n for item in lst:\n new_tpl.append(item)\n \n # Convert the new list back to a tuple and return\n return tuple(new_tpl)", "matching_cluster_idx": 2}, {"solution": "def add_lists(lst, tpl):\n return tpl + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tpl):\n \"\"\"\n Convert the given list to a tuple and append it to the given tuples.\n :param lst: The list to append.\n :param tpl: The tuple to append to.\n :return: The appended tuple.\n \"\"\"\n return tuple(tpl) + tuple(lst)", "matching_cluster_idx": 4}, {"solution": "def add_lists(lst, tpl):\n return tpl + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tpl):\n \"\"\"Appends the list to the end of the tuple and return the combined tuple\"\"\"\n return tpl + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(list_to_append, tuple_to_append_to):\n # Convert tuple to list\n temp_list = list(tuple_to_append_to)\n \n # Append given list to the above list\n temp_list.extend(list_to_append)\n \n # Convert the above list back to tuple and return\n return tuple(temp_list)", "matching_cluster_idx": 4}, {"solution": "def add_lists(lst, tpl):\n return tuple(list(tpl) + lst)", "matching_cluster_idx": 3}, {"solution": "def add_lists(list_to_append, tuple_to_append_to):\n # Convert the tuple to a list\n temp_list = list(tuple_to_append_to)\n \n # Append the given list to this list\n temp_list.extend(list_to_append)\n \n # Convert the list back to a tuple and return\n return tuple(temp_list)", "matching_cluster_idx": 4}, {"solution": "def add_lists(lst, tup):\n # convert tuple to list\n tup_list = list(tup)\n\n # append the given list to the tuple\n tup_list.extend(lst)\n\n # convert the list back to tuple\n new_tup = tuple(tup_list)\n\n return new_tup", "matching_cluster_idx": 4}, {"solution": "def add_lists(list_to_append, tuple_to_append_to):\n # Convert tuple to list\n tuple_as_list = list(tuple_to_append_to)\n \n # Append list to tuple (which is really list now)\n tuple_as_list.extend(list_to_append)\n \n # Convert back to tuple and return\n return tuple(tuple_as_list)", "matching_cluster_idx": 4}, {"solution": "def add_lists(list_to_append, tuple_to_append_to):\n \"\"\"Appends a list to a tuple.\"\"\"\n \n # Convert the tuple to a list\n temp_list = list(tuple_to_append_to)\n \n # Extend the list with the elements of the other list\n temp_list.extend(list_to_append)\n \n # Return the extended list as a tuple\n return tuple(temp_list)", "matching_cluster_idx": 4}, {"solution": "def add_lists(lst, tpl):\n return tuple(tpl) + tuple(lst)", "matching_cluster_idx": 4}, {"solution": "def add_lists(lst, tpl):\n return tuple(tpl) + tuple(lst)", "matching_cluster_idx": 4}, {"solution": "def add_lists(lst, tpl):\n # convert tuple to list\n list_converted = list(tpl)\n \n # extend the converted list by given list\n list_converted.extend(lst)\n \n # convert the list back to tuple\n tuple_final = tuple(list_converted)\n \n return tuple_final", "matching_cluster_idx": 4}, {"solution": "def add_lists(list_to_append, tuple_to_append_to):\n return tuple_to_append_to + tuple(list_to_append)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tpl):\n return tuple(tpl) + tuple(lst)", "matching_cluster_idx": 4}, {"solution": "def add_lists(lst, tpl):\n # Convert the list to a tuple\n tpl_list = tuple(lst)\n \n # Concatenate the tuples\n result = tpl + tpl_list\n \n return result", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tpl):\n # convert tuple to list\n tpl = list(tpl)\n \n # append the list to the tuple\n tpl.extend(lst)\n \n # return the final tuple\n return tuple(tpl)", "matching_cluster_idx": 4}, {"solution": "def add_lists(lst, tpl):\n return tpl + tuple(lst)", "matching_cluster_idx": 5}]}, "Mbpp/108": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 92.0, "profiled": [{"solution": "def merge_sorted_list(list1, list2, list3):\n \"\"\"Function to merge and sort three lists.\"\"\"\n \n # Merge the three lists\n merged_list = list1 + list2 + list3\n \n # Sort the merged list\n merged_list.sort()\n \n return merged_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Concatenate the three lists\n combined_list = list1 + list2 + list3\n # Sort and return the combined list\n return sorted(combined_list)", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Merges the lists and sorts them\n merged_list = sorted(list1 + list2 + list3)\n return merged_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Merging the three lists\n merged_list = list1 + list2 + list3\n # Sorting the merged list\n sorted_list = sorted(merged_list)\n return sorted_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(lst1, lst2, lst3):\n return sorted(lst1 + lst2 + lst3)", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Combine all lists\n combined_list = list1 + list2 + list3\n \n # Sort the combined list\n sorted_list = sorted(combined_list)\n \n return sorted_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(lst1, lst2, lst3):\n result = lst1 + lst2 + lst3\n result.sort()\n return result", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(l1,l2,l3):\n # concatenate three lists\n l = l1 + l2 + l3\n # sort and return the list\n return sorted(l)", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n combined_list = list1 + list2 + list3\n return sorted(combined_list)", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(lst1, lst2, lst3):\n merged_lst = lst1 + lst2 + lst3\n merged_lst.sort()\n return merged_lst", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(lst1, lst2, lst3):\n # merge lists\n merged_lst = lst1 + lst2 + lst3\n # sort the list\n sorted_lst = sorted(merged_lst)\n # return the sorted list\n return sorted_lst", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n merged_list = list1 + list2 + list3\n merged_list.sort()\n return merged_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(lst1, lst2, lst3):\n return sorted(lst1 + lst2 + lst3)", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # combine three lists\n combined = list1 + list2 + list3\n # sort the combined list\n combined.sort()\n return combined", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(lst1, lst2, lst3):\n # combine three lists\n lst = lst1 + lst2 + lst3\n \n # sort the combined list\n lst.sort()\n\n return lst", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(lst1, lst2, lst3):\n # merge three lists\n merged = lst1 + lst2 + lst3\n # sort the merged list\n sorted_lst = sorted(merged)\n return sorted_lst", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n combined_list = list1 + list2 + list3\n combined_list.sort()\n return combined_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n merged_list = sorted(list1 + list2 + list3)\n return merged_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(l1, l2, l3):\n return sorted(l1 + l2 + l3)", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n merged_list = list1 + list2 + list3\n merged_list.sort()\n return merged_list", "matching_cluster_idx": 10}]}, "Mbpp/111": {"dps": 43.03076923076923, "dps_norm": 75.625, "pass@1": 97.0, "profiled": [{"solution": "def common_in_nested_lists(nested_lists):\n # Convert each list in the nested list to a set.\n # Then convert the nested_lists variable to a set of sets for future use.\n nested_sets = [set(lst) for lst in nested_lists]\n\n # Use the intersection function provided by set object to find the common elements.\n # This works because for set intersection, order doesn't matter.\n common_elements = set.intersection(*nested_sets)\n\n return list(common_elements)", "matching_cluster_idx": 4}, {"solution": "def common_in_nested_lists(nested_lists):\n # Start by converting the first list to a set\n common_elements = set(nested_lists[0])\n \n # Iterate over the remaining lists\n for lst in nested_lists[1:]:\n # Update the set by keeping only elements present in the current list\n common_elements = common_elements.intersection(set(lst))\n \n # Return the common elements as a list\n return list(common_elements)", "matching_cluster_idx": 5}, {"solution": "def common_in_nested_lists(nested_lists):\n \"\"\"\n This function takes a list of nested lists as input. It finds the common elements in\n all the nested lists and returns them in a list.\n \"\"\"\n return list(set.intersection(*map(set, nested_lists)))", "matching_cluster_idx": 5}, {"solution": "def common_in_nested_lists(nested_list):\n if len(nested_list) == 0:\n return []\n\n common = set(nested_list[0])\n for lst in nested_list[1:]:\n common &= set(lst)\n return list(common)", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n # Convert each sub-list to a set and find the intersection of all sets\n return list(set.intersection(*map(set, nested_lists)))", "matching_cluster_idx": 4}, {"solution": "def common_in_nested_lists(nested_lists):\n # Using set intersection\n common_elements = set(nested_lists[0])\n for lst in nested_lists:\n common_elements &= set(lst)\n return list(common_elements)", "matching_cluster_idx": 5}, {"solution": "def common_in_nested_lists(lst):\n \"\"\"\n This function takes a list of lists as input and returns a set of common elements in all lists.\n \n Parameter:\n lst (list): A list of lists.\n \n Returns:\n set: A set of common elements in all lists.\n \"\"\"\n return set(lst[0]).intersection(*lst)", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(lists):\n \"\"\"\n This function takes a list of lists and returns a list of common elements.\n \"\"\"\n sets = [set(lst) for lst in lists]\n common_elements = sets[0].intersection(*sets)\n return list(common_elements)", "matching_cluster_idx": 5}, {"solution": "def common_in_nested_lists(nested_list):\n # return the intersection of all lists in the nested list, converted back to a list\n return list(set.intersection(*map(set, nested_list)))", "matching_cluster_idx": 4}, {"solution": "def common_in_nested_lists(lst):\n # Intersection of all lists\n common_elements = set(lst[0]).intersection(*lst)\n return list(common_elements)", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n # Convert each list to a set. Then, find the intersection of all sets.\n return list(set.intersection(*map(set, nested_lists)))", "matching_cluster_idx": 4}, {"solution": "def common_in_nested_lists(nested_lists):\n common_elements = set(nested_lists[0])\n for lst in nested_lists:\n common_elements = common_elements.intersection(set(lst))\n return list(common_elements)", "matching_cluster_idx": 5}, {"solution": "def common_in_nested_lists(lst):\n # convert lists of lists to set of sets\n set_lst = list(map(set, lst))\n # find intersection of all sets\n common_elements = set.intersection(*set_lst)\n return list(common_elements)", "matching_cluster_idx": 4}, {"solution": "def common_in_nested_lists(lst):\n return list(set(lst[0]).intersection(*lst))", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n return list(set.intersection(*map(set, nested_lists)))", "matching_cluster_idx": 5}, {"solution": "def common_in_nested_lists(nested_list):\n # Convert each list to set for comparison\n set_list = [set(lst) for lst in nested_list]\n\n # Return the intersection of all sets\n return list(set.intersection(*set_list))", "matching_cluster_idx": 5}, {"solution": "def common_in_nested_lists(nested_lists):\n \"\"\"Return common elements in a nested list.\"\"\"\n return list(set.intersection(*map(set, nested_lists)))", "matching_cluster_idx": 4}, {"solution": "def common_in_nested_lists(lists):\n if not lists:\n return []\n common_elements = set(lists[0])\n for lst in lists[1:]:\n common_elements &= set(lst)\n return list(common_elements)\nlists = [[12, 18, 23, 25, 45], [7, 12, 18, 24, 28], [1, 5, 8, 12, 15, 16, 18]]", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(lists):\n \"\"\"Return the common elements in a list of nested lists.\"\"\"\n if not lists:\n return []\n common_elements = set(lists[0])\n for lst in lists[1:]:\n common_elements = common_elements & set(lst)\n return list(common_elements)", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n # Convert each inner list into a set, then find the intersection of all sets.\n common_elements = set(nested_lists[0])\n for l in nested_lists[1:]:\n common_elements &= set(l)\n return list(common_elements)", "matching_cluster_idx": 6}]}, "Mbpp/123": {"dps": 99.62686567164178, "dps_norm": 85.71428571428571, "pass@1": 86.0, "profiled": [{"solution": "def proper_divisors(n):\n divisors = [1]\n for i in range(2, int(n**0.5)+1):\n if n % i == 0:\n if n // i == i:\n divisors.append(i)\n else:\n divisors.extend([i, n // i])\n return divisors\ndef amicable_numbers_sum(n):\n result = 0\n for i in range(2, n+1):\n div_sum = sum(proper_divisors(i))\n if i != div_sum and sum(proper_divisors(div_sum)) == i:\n result += i\n return result", "matching_cluster_idx": 11}, {"solution": "def proper_divisors(n):\n divisors = [1]\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n if i*i != n:\n divisors.extend([i, n // i])\n else:\n divisors.append(i)\n return divisors\ndef amicable_numbers_sum(n):\n if n < 220:\n return 0\n divisor_sums = [0]*(n+1)\n for i in range(2, n+1):\n divisor_sums[i] = sum(proper_divisors(i))\n total = 0\n for i in range(2, n+1):\n if divisor_sums[i] <= n and i != divisor_sums[i] and i == divisor_sums[divisor_sums[i]]:\n total += i\n return total", "matching_cluster_idx": 11}, {"solution": "def proper_divisors(n):\n divisors = [1]\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n if n // i == i:\n divisors.append(i)\n else:\n divisors.extend([i, n // i])\n return divisors\ndef amicable_numbers_sum(limit):\n total_sum = 0\n for num in range(2, limit + 1):\n divisor_sum = sum(proper_divisors(num))\n if divisor_sum != num and sum(proper_divisors(divisor_sum)) == num:\n total_sum += num\n return total_sum", "matching_cluster_idx": 11}, {"solution": "def sum_of_proper_divisors(n):\n result = 1\n i = 2\n while i * i <= n:\n if (n % i == 0):\n if (i == (n / i)):\n result = result + i\n else:\n result = result + (i + n//i)\n i += 1\n return result\ndef amicable_numbers_sum(num):\n result = 0\n for i in range(2, num + 1):\n sum1 = sum_of_proper_divisors(i)\n if (sum1 != i):\n sum2 = sum_of_proper_divisors(sum1)\n if (i == sum2):\n result += i\n return result", "matching_cluster_idx": 11}, {"solution": "def sum_of_proper_divisors(n):\n result = 1\n for i in range(2, int(n ** 0.5) + 1):\n if n % i == 0:\n result += i\n if i * i != n: # If i is not a square root of n\n result += n // i\n return result\ndef amicable_numbers_sum(limit):\n result = 0\n for i in range(2, limit + 1):\n j = sum_of_proper_divisors(i)\n if j > i and sum_of_proper_divisors(j) == i:\n result += i + j\n return result", "matching_cluster_idx": 11}, {"solution": "def proper_divisors(n):\n divisors = [1]\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n if i * i != n:\n divisors.extend([i, n // i])\n else:\n divisors.append(i)\n return divisors\ndef amicable_numbers_sum(max_number):\n sums_of_divisors = [0]*(max_number+1)\n for i in range(1, max_number+1):\n sums_of_divisors[i] = sum(proper_divisors(i))\n\n result = 0\n for i in range(1, max_number+1):\n j = sums_of_divisors[i]\n if j != i and j <= max_number and sums_of_divisors[j] == i:\n result += i\n\n return result", "matching_cluster_idx": 11}, {"solution": "def amicable_numbers_sum(num):\n def divisors_sum(n):\n result = 1\n lim = int(n ** 0.5)\n for i in range(2, lim + 1):\n if n % i == 0:\n if i == (n / i):\n result = result + i\n else:\n result = result + (i + n // i)\n return result\n\n result = 0\n for a in range(2, num + 1):\n b = divisors_sum(a)\n if a != b and divisors_sum(b) == a:\n result += a\n\n return result", "matching_cluster_idx": 11}, {"solution": "def proper_divisors(n):\n divisors = [1]\n for i in range(2, int(n**0.5)+1):\n if n % i:\n continue\n if i * i != n:\n divisors.extend([i, n//i])\n else:\n divisors.append(i)\n return divisors\ndef amicable_numbers_sum(n):\n result = 0\n for i in range(1, n+1):\n sum1 = sum(proper_divisors(i))\n sum2 = sum(proper_divisors(sum1))\n if i == sum2 and i != sum1:\n result += i\n return result", "matching_cluster_idx": 11}, {"solution": "def proper_divisors(n):\n \"\"\"Find the sum of the proper divisors of n.\"\"\"\n result = 1\n upper_bound = int(n**0.5)\n for i in range(2, upper_bound + 1):\n if n % i == 0:\n result += i\n if i * i != n:\n result += n // i\n return result\ndef amicable_numbers_sum(limit):\n \"\"\"Find the sum of all amicable numbers up to the specified limit.\"\"\"\n result = 0\n for i in range(1, limit + 1):\n j = proper_divisors(i)\n if i != j and proper_divisors(j) == i:\n result += i\n return result", "matching_cluster_idx": 11}, {"solution": "def proper_divisors_sum(n):\n \"\"\"Returns the sum of proper divisors of n\"\"\"\n result = 1\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n result += i\n if i * i != n: # If i is not the square root of n\n result += n // i\n return result\ndef amicable_numbers_sum(limit):\n \"\"\"Returns the sum of all amicable numbers up to the given limit\"\"\"\n result = 0\n for i in range(2, limit+1):\n j = proper_divisors_sum(i)\n if i != j and proper_divisors_sum(j) == i:\n result += i\n return result", "matching_cluster_idx": 11}, {"solution": "def sum_of_divisors(n):\n sum = 1\n i = 2\n while i * i <= n:\n if n % i:\n i += 1\n else:\n if i * (n // i) == n:\n sum = sum + i + n//i\n else:\n sum = sum + i\n i += 1\n return sum\ndef amicable_numbers_sum(max_num):\n sum = 0\n for num in range(1, max_num):\n temp_num = sum_of_divisors(num)\n if sum_of_divisors(temp_num) == num and temp_num != num:\n sum += num\n return sum", "matching_cluster_idx": 11}, {"solution": "def sum_of_proper_divisors(n):\n result = 1\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n result += i\n if i * i != n:\n result += n // i\n return result\ndef amicable_numbers_sum(limit):\n sums = [0]*(limit+1)\n for i in range(1, limit+1):\n sums[i] = sum_of_proper_divisors(i)\n\n total = 0\n for i in range(2, limit+1):\n if sums[i] <= limit and i != sums[i] and i == sums[sums[i]]:\n total += i\n return total", "matching_cluster_idx": 11}, {"solution": "def proper_divisors(n):\n result = []\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n result.append(i)\n if i * i != n and i != 1:\n result.append(n // i)\n return result\ndef is_amicable(n):\n sum_divisors = sum(proper_divisors(n))\n if sum_divisors == n or sum(proper_divisors(sum_divisors)) != n:\n return False\n return True\ndef amicable_numbers_sum(n):\n result = 0\n for i in range(1, n + 1):\n if is_amicable(i):\n result += i\n return result", "matching_cluster_idx": 11}, {"solution": "def divisors(n):\n divs = [1]\n for i in range(2,int(n**0.5)+1):\n if n%i == 0:\n if n/i == i:\n divs.append(i)\n else:\n divs.extend([i, n//i])\n return divs\ndef amicable_numbers_sum(limit):\n sums = [0]*(limit+1)\n for i in range(1, limit+1):\n sums[i] = sum(divisors(i))\n\n total = 0\n for i in range(2, limit+1):\n if sums[i] <= limit and i != sums[i] and i == sums[sums[i]]:\n total += i\n\n return total", "matching_cluster_idx": 11}, {"solution": "def amicable_numbers_sum(n):\n def divisors(num): \n divs = [1] \n for i in range(2, int(num**0.5)+1):\n if num % i == 0:\n if num//i == i:\n divs.append(i)\n else:\n divs.extend([i, num//i])\n return divs \n\n def is_amicable(a):\n b = sum(divisors(a))\n return a != b and sum(divisors(b)) == a\n\n return sum(x for x in range(2, n+1) if is_amicable(x))", "matching_cluster_idx": 11}, {"solution": "def proper_divisors(n):\n divisors = [1]\n for i in range(2, int(n**0.5)+1):\n if n % i:\n continue\n if i * i != n:\n divisors.extend([i, n // i])\n else:\n divisors.append(i)\n return divisors\ndef is_amicable(n):\n sum1 = sum(proper_divisors(n))\n if sum1 == n or n == 1:\n return False\n sum2 = sum(proper_divisors(sum1))\n return n == sum2\ndef amicable_numbers_sum(limit):\n total = 0\n for num in range(1, limit+1):\n if is_amicable(num):\n total += num\n return total", "matching_cluster_idx": 11}, {"solution": "def proper_divisors(n):\n \"\"\"Returns the sum of the proper divisors of n\"\"\"\n result = 1\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n result += i\n if i * i != n:\n result += n // i\n return result\ndef amicable_numbers_sum(upper_limit):\n \"\"\"Returns the sum of all amicable numbers up to upper_limit\"\"\"\n result = 0\n for a in range(2, upper_limit + 1):\n b = proper_divisors(a)\n if a != b and proper_divisors(b) == a:\n result += a\n return result", "matching_cluster_idx": 11}, {"solution": "def divisors_sum(n):\n \"\"\"Find the sum of divisors of a number\"\"\"\n result = 1\n i = 2\n while i * i <= n:\n if n % i:\n i += 1\n else:\n if i * (n // i) == n:\n result = result + i + n//i\n i += 1\n return result\ndef amicable_numbers_sum(limit):\n \"\"\"Find the sum of all amicable numbers from 1 to a specified number\"\"\"\n result = 0\n for i in range(2, limit+1):\n j = divisors_sum(i)\n if j > i and divisors_sum(j) == i:\n result += i + j\n return result", "matching_cluster_idx": 11}, {"solution": "def proper_divisors(n):\n \"\"\"Returns the sum of proper divisors of n\"\"\"\n result = 1\n for i in range(2, int(n ** 0.5) + 1):\n if n % i == 0:\n result += i\n if i * i != n:\n result += n // i\n return result\ndef is_amicable(n):\n \"\"\"Checks if a number is amicable\"\"\"\n pair = proper_divisors(n)\n return pair != n and proper_divisors(pair) == n\ndef amicable_numbers_sum(upper_limit):\n \"\"\"Sum all amicable numbers from 1 to a specified number\"\"\"\n result = 0\n for i in range(2, upper_limit + 1):\n if is_amicable(i):\n result += i\n return result", "matching_cluster_idx": 11}, {"solution": "def proper_divisors_sum(n):\n sum = 1\n for i in range(2, int(n**0.5) + 1):\n if n % i:\n continue\n if i * i != n:\n sum = sum + i + n//i\n else:\n sum = sum + i\n return sum\ndef amicable_numbers_sum(limit):\n sum = 0\n for i in range(2, limit + 1):\n j = proper_divisors_sum(i)\n if j > i and proper_divisors_sum(j) == i:\n sum += (i + j)\n return sum", "matching_cluster_idx": 11}]}, "Mbpp/128": {"dps": 99.5475113122172, "dps_norm": 80.0, "pass@1": 100.0, "profiled": [{"solution": "def long_words(n, sentence):\n words = sentence.split()\n return [word for word in words if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, str):\n words = str.split()\n return [word for word in words if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, string):\n words = string.split()\n return [word for word in words if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, words):\n words_list = words.split()\n return [word for word in words_list if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n words = sentence.split()\n long_words = [word for word in words if len(word) > n]\n return long_words", "matching_cluster_idx": 3}, {"solution": "def long_words(n, words):\n return [word for word in words.split() if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n # Split the sentence into words\n words = sentence.split()\n\n # Filter words that are longer than n characters\n long_words = [word for word in words if len(word) > n]\n\n return long_words", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n words = sentence.split()\n return [word for word in words if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n \"\"\"\n Function to find words that are longer than n characters from a given sentence.\n :param n: an integer specifying the minimum length of the word\n :param sentence: a string of words separated by spaces\n :return: a list of words in the sentence that are longer than n characters\n \"\"\"\n words = sentence.split(\" \")\n return [word for word in words if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, words_str):\n word_list = words_str.split()\n return [word for word in word_list if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n words = sentence.split()\n return [word for word in words if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n words = sentence.split()\n return [word for word in words if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, words):\n return [word for word in words.split() if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n words = sentence.split()\n result = [word for word in words if len(word) > n]\n return result", "matching_cluster_idx": 3}, {"solution": "def long_words(n, words):\n words_list = words.split(\" \")\n return [word for word in words_list if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n \"\"\"Find words longer than n characters from a given list.\"\"\"\n words = sentence.split()\n return [word for word in words if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n words = sentence.split()\n return [word for word in words if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, string):\n # Splitting the string into words and storing them in a list\n words = string.split()\n # Using list comprehension to find words longer than n characters\n long_words = [word for word in words if len(word) > n]\n return long_words", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n words = sentence.split()\n result = [word for word in words if len(word) > n]\n return result", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n words = sentence.split()\n return [word for word in words if len(word) > n]", "matching_cluster_idx": 3}]}, "Mbpp/129": {"dps": 72.39795918367346, "dps_norm": 93.66666666666667, "pass@1": 41.0, "profiled": [{"solution": "def magic_square_test(matrix):\n n = len(matrix)\n \n # Calculate the sum of the first row for comparison\n first_row_sum = sum(matrix[0])\n\n # Check the sum of each row\n for row in matrix:\n if sum(row) != first_row_sum:\n return False\n\n # Check the sum of each column\n for j in range(n):\n column_sum = 0\n for i in range(n):\n column_sum += matrix[i][j]\n if column_sum != first_row_sum:\n return False\n\n # Check the sum of the first diagonal\n diagonal_sum = sum(matrix[i][i] for i in range(n))\n if diagonal_sum != first_row_sum:\n return False\n\n # Check the sum of the second diagonal\n diagonal_sum = sum(matrix[i][n-i-1] for i in range(n))\n if diagonal_sum != first_row_sum:\n return False\n\n # If all checks pass, it's a magic square\n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n n = len(matrix)\n # check rows and columns length\n for i in range(n):\n if len(matrix[i]) != n:\n return False\n\n # calculate the magic constant (sum of each line for a magic square)\n magic_constant = sum(matrix[0])\n\n # check sum of each row and each column\n for i in range(n):\n if sum(matrix[i]) != magic_constant:\n return False\n if sum([row[i] for row in matrix]) != magic_constant:\n return False\n\n # check sum of both diagonals\n if sum(matrix[i][i] for i in range(n)) != magic_constant:\n return False\n if sum(matrix[i][n-i-1] for i in range(n)) != magic_constant:\n return False\n\n # if all the checks passed, it's a magic square\n return True", "matching_cluster_idx": 13}, {"solution": "def magic_square_test(square):\n # Calculate the length of the square\n n = len(square)\n\n # Calculate the sum of the elements in a row, a column or the two diagonals\n magicsum = sum(square[0])\n\n # Test sum of rows\n for row in square:\n if sum(row) != magicsum:\n return False\n\n # Test sum of columns\n for i in range(n):\n if sum(row[i] for row in square) != magicsum:\n return False\n\n # Test sum of diagonals\n if sum(square[i][i] for i in range(n)) != magicsum:\n return False\n\n if sum(square[i][n-i-1] for i in range(n)) != magicsum:\n return False\n\n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n # Get the length of the matrix\n n = len(matrix)\n\n # Get the sum of the first row, to be used for comparison\n first_row_sum = sum(matrix[0])\n\n # Check rows sums\n for row in matrix:\n if sum(row) != first_row_sum:\n return False\n\n # Check columns sums\n for i in range(n):\n if sum(row[i] for row in matrix) != first_row_sum:\n return False\n\n # Check diagonals sums\n if sum(matrix[i][i] for i in range(n)) != first_row_sum:\n return False\n if sum(matrix[i][n-i-1] for i in range(n)) != first_row_sum:\n return False\n\n # If all checks passed, it is a magic square\n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n # Calculate the required sum\n total_sum = sum(matrix[0])\n\n # Check the sum of the rows\n for row in matrix:\n if sum(row) != total_sum:\n return False\n\n # Check the sum of the columns\n for col in range(len(matrix[0])):\n if sum(row[col] for row in matrix) != total_sum:\n return False\n\n # Check the sum of the diagonals\n if sum(matrix[i][i] for i in range(len(matrix))) != total_sum:\n return False\n if sum(matrix[i][len(matrix)-i-1] for i in range(len(matrix))) != total_sum:\n return False\n\n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n # Get the size of the matrix\n n = len(matrix)\n\n # Calculate the magic constant (which should be the same for all rows, columns, and diagonals)\n magic_constant = sum(matrix[0])\n\n # Check all rows\n for row in matrix:\n if sum(row) != magic_constant:\n return False\n\n # Check all columns\n for i in range(n):\n if sum(row[i] for row in matrix) != magic_constant:\n return False\n\n # Check both diagonals\n if sum(matrix[i][i] for i in range(n)) != magic_constant:\n return False\n if sum(matrix[i][n-i-1] for i in range(n)) != magic_constant:\n return False\n\n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n # Check if matrix is square\n if len(matrix) == 0 or len(matrix) != len(matrix[0]):\n return False\n \n # Calculate the magic constant (the sum in any row, column or diagonal)\n magic_constant = sum(matrix[0])\n \n # Check sum of each row\n for row in matrix:\n if sum(row) != magic_constant:\n return False\n \n # Check sum of each column\n for col in range(len(matrix)):\n if sum(row[col] for row in matrix) != magic_constant:\n return False\n \n # Check sum of diagonals\n if sum(matrix[i][i] for i in range(len(matrix))) != magic_constant:\n return False\n if sum(matrix[i][len(matrix)-i-1] for i in range(len(matrix))) != magic_constant:\n return False\n\n # If all checks pass, it's a magic square\n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(square):\n n = len(square)\n\n # calculate the sum of any row, any column or any diagonal\n standard_sum = sum(square[0])\n\n # check all rows and columns\n for i in range(n):\n if sum(square[i]) != standard_sum or sum(square[j][i] for j in range(n)) != standard_sum:\n return False\n\n # check both diagonals\n if sum(square[i][i] for i in range(n)) != standard_sum or sum(square[i][n-i-1] for i in range(n)) != standard_sum:\n return False\n\n # all checks passed\n return True", "matching_cluster_idx": 13}, {"solution": "def magic_square_test(matrix):\n n = len(matrix)\n \n # Calculate the sum of the first row for comparison\n sum_row = sum(matrix[0])\n \n # Check rows\n for row in matrix:\n if sum(row) != sum_row:\n return False\n\n # Check columns\n for i in range(n):\n if sum(matrix[j][i] for j in range(n)) != sum_row:\n return False\n\n # Check diagonals\n if sum(matrix[i][i] for i in range(n)) != sum_row:\n return False\n if sum(matrix[i][n-i-1] for i in range(n)) != sum_row:\n return False\n\n # If all rows, columns and diagonals sum to the same value, it is a magic square\n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n n = len(matrix)\n\n # Check all row lengths are the same\n if any(len(row) != n for row in matrix):\n return False\n\n # Calculate the magic constant (sum of one row/col/diag)\n magic_constant = sum(matrix[0])\n\n # Check all rows and columns\n for i in range(n):\n if sum(row[i] for row in matrix) != magic_constant or sum(matrix[i]) != magic_constant:\n return False\n\n # Check both diagonals\n if sum(matrix[i][i] for i in range(n)) != magic_constant or sum(matrix[i][n-i-1] for i in range(n)) != magic_constant:\n return False\n\n return True", "matching_cluster_idx": 13}, {"solution": "def magic_square_test(matrix):\n #Calculate the length of the matrix\n n = len(matrix)\n #Create a list to hold the sums\n sum_list = []\n #Calculate the sum of the first row as reference\n magic_sum = sum(matrix[0])\n \n #Check the sum of each row\n for row in matrix:\n if sum(row) != magic_sum:\n return False\n sum_list.append(magic_sum)\n \n #Check the sum of each column\n for column in range(n):\n if sum(row[column] for row in matrix) != magic_sum:\n return False\n sum_list.append(magic_sum)\n \n #Check the sum of the main diagonal\n if sum(matrix[i][i] for i in range(n)) != magic_sum:\n return False\n sum_list.append(magic_sum)\n \n #Check the sum of the secondary diagonal\n if sum(matrix[i][n-i-1] for i in range(n)) != magic_sum:\n return False\n sum_list.append(magic_sum)\n\n #If passed all tests, return True\n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n s = sum(matrix[0])\n\n # Check the sums of the rows\n for row in matrix:\n if sum(row) != s:\n return False\n\n # Check the sums of the columns\n for i in range(len(matrix)):\n if sum(row[i] for row in matrix) != s:\n return False\n\n # Check the sum of the first diagonal\n if sum(matrix[i][i] for i in range(len(matrix))) != s:\n return False\n\n # Check the sum of the second diagonal\n if sum(matrix[i][len(matrix)-i-1] for i in range(len(matrix))) != s:\n return False\n\n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n # Checking that input matrix is N x N\n n = len(matrix)\n for row in matrix:\n if len(row) != n:\n return False\n\n # Calculating the target sum (the \"magic constant\")\n magic_constant = sum(matrix[i][i] for i in range(n))\n\n # Checking rows\n for row in matrix:\n if sum(row) != magic_constant:\n return False\n\n # Checking columns\n for i in range(n):\n if sum(matrix[j][i] for j in range(n)) != magic_constant:\n return False\n\n # Checking diagonals\n if sum(matrix[i][i] for i in range(n)) != magic_constant:\n return False\n if sum(matrix[i][n-i-1] for i in range(n)) != magic_constant:\n return False\n\n return True", "matching_cluster_idx": 13}, {"solution": "def magic_square_test(matrix):\n # Get the length of the matrix\n N = len(matrix)\n\n # Calculate the sum of any row, column or diagonal\n target_sum = sum(matrix[0])\n\n # Check rows and columns\n for i in range(N):\n if sum(matrix[i]) != target_sum:\n return False\n if sum([row[i] for row in matrix]) != target_sum:\n return False\n\n # Check diagonals\n if sum(matrix[i][i] for i in range(N)) != target_sum:\n return False\n if sum(matrix[i][N-i-1] for i in range(N)) != target_sum:\n return False\n\n return True", "matching_cluster_idx": 13}, {"solution": "def magic_square_test(matrix):\n # Function to check if a given matrix is a magic square\n\n # The number of rows and columns in the input matrix must be equal\n # Otherwise, it's not a magic square by definition\n if len(matrix) == 0 or len(matrix) != len(matrix[0]):\n return False\n\n n = len(matrix)\n \n # Create a list of the sums of each row, column and the two main diagonals\n sums = []\n \n # Sum of each row\n sums += [sum(row) for row in matrix]\n \n # Sum of each column\n sums += [sum(matrix[i][j] for i in range(n)) for j in range(n)]\n \n # Sum of the main diagonal\n sums.append(sum(matrix[i][i] for i in range(n)))\n \n # Sum of the secondary diagonal\n sums.append(sum(matrix[i][n-i-1] for i in range(n)))\n \n # If all sums are equal, the matrix is a magic square\n return len(set(sums)) == 1", "matching_cluster_idx": 4}, {"solution": "def magic_square_test(matrix):\n # Check if the matrix is square\n N = len(matrix)\n for row in matrix:\n if len(row) != N:\n return False\n\n # Calculate the magic constant (sum of one row/column/diagonal)\n magic_constant = sum(matrix[i][i] for i in range(N))\n\n # Check rows and columns\n for i in range(N):\n if sum(matrix[i]) != magic_constant or sum(matrix[j][i] for j in range(N)) != magic_constant:\n return False\n\n # Check diagonals\n if sum(matrix[i][N-i-1] for i in range(N)) != magic_constant:\n return False\n\n # All checks passed\n return True", "matching_cluster_idx": 13}, {"solution": "def magic_square_test(matrix):\n # Finding the length of the matrix\n size = len(matrix)\n # Calculating the sum of the first row\n total_sum = sum(matrix[0])\n # Comparing the sum of the each row with total_sum\n for row in matrix:\n if sum(row) != total_sum:\n return False\n # Comparing the sum of the each column with total_sum\n for column in range(size):\n column_sum = sum(row[column] for row in matrix)\n if column_sum != total_sum:\n return False\n # Comparing the sum of the main diagonal with total_sum\n diagonal_sum = sum(matrix[i][i] for i in range(size))\n if diagonal_sum != total_sum:\n return False\n # Comparing the sum of the other diagonal with total_sum\n diagonal_sum = sum(matrix[i][size-i-1] for i in range(size))\n if diagonal_sum != total_sum:\n return False\n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n # Calculate the size of the square\n n = len(matrix)\n\n # Define the sum of a row or column or diagonal\n sum_of_row_or_col_or_diagonal = sum(matrix[0])\n\n # Checking if all the rows and columns sums are equal\n for i in range(n):\n if sum(matrix[i]) != sum_of_row_or_col_or_diagonal:\n return False\n if sum(matrix[j][i] for j in range(n)) != sum_of_row_or_col_or_diagonal:\n return False\n\n # Checking if the sum of both main diagonals are equal\n if sum(matrix[i][i] for i in range(n)) != sum_of_row_or_col_or_diagonal:\n return False\n if sum(matrix[i][n-i-1] for i in range(n)) != sum_of_row_or_col_or_diagonal:\n return False\n\n # If all checks passed, the square is a magic square\n return True", "matching_cluster_idx": 13}, {"solution": "def magic_square_test(matrix):\n n = len(matrix)\n magic_number = sum(matrix[0])\n\n # Check rows and columns\n for i in range(n):\n if sum(matrix[i]) != magic_number or sum(matrix[j][i] for j in range(n)) != magic_number:\n return False\n\n # Check diagonals\n if sum(matrix[i][i] for i in range(n)) != magic_number or sum(matrix[i][n-i-1] for i in range(n)) != magic_number:\n return False\n\n return True", "matching_cluster_idx": 13}, {"solution": "def magic_square_test(matrix):\n n = len(matrix)\n \n # calculate the sum of the first row elements. this sum should be the same for all rows, columns and diagonals\n first_row_sum = sum(matrix[0])\n \n # function to check if sums of all rows, columns and both diagonals are the same as the first row sum\n def sums_are_the_same(matrix, first_row_sum, n):\n for i in range(n):\n if sum(matrix[i]) != first_row_sum: # check the sum of rows\n return False\n if sum(matrix[j][i] for j in range(n)) != first_row_sum: # check the sum of columns\n return False\n if sum(matrix[i][i] for i in range(n)) != first_row_sum: # check the sum of main diagonal\n return False\n if sum(matrix[i][n-i-1] for i in range(n)) != first_row_sum: # check the sum of second diagonal\n return False\n return True\n \n return sums_are_the_same(matrix, first_row_sum, n)", "matching_cluster_idx": 13}]}, "Mbpp/130": {"dps": 76.1322869955157, "dps_norm": 68.33333333333334, "pass@1": 71.0, "profiled": [{"solution": "def max_occurrences(lst):\n from collections import Counter\n counter = Counter(lst)\n return counter.most_common(1)[0][0]", "matching_cluster_idx": 4}, {"solution": "def max_occurrences(list):\n counts = {}\n for item in list:\n if item in counts:\n counts[item] += 1\n else:\n counts[item] = 1\n max_count = max(counts.values())\n for key, value in counts.items():\n if value == max_count:\n return key", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(lst):\n from collections import Counter\n count_dict = Counter(lst)\n max_count = max(list(count_dict.values()))\n max_freq_item = [item for item, count in count_dict.items() if count == max_count]\n return max_freq_item[0]", "matching_cluster_idx": 4}, {"solution": "def max_occurrences(lst):\n \"\"\" \n Finds the item with maximum frequency in a given list.\n\n Args:\n lst: a list of integers\n\n Returns:\n The item with maximum frequency. If there are multiple items with \n maximum frequency, it returns the first one it encounters.\n \"\"\"\n\n # Dictionary to store frequency of each item\n freq_dict = {}\n\n # Loop through the list and update frequency count\n for item in lst:\n if item in freq_dict:\n freq_dict[item] += 1\n else:\n freq_dict[item] = 1\n\n # Get the item with maximum frequency\n max_freq_item = max(freq_dict, key=freq_dict.get)\n\n return max_freq_item", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(lst):\n \"\"\"\n Function that finds item with maximum frequency in a given list.\n \"\"\"\n # Initialize dictionary to hold item frequencies\n frequencies = {}\n # Iterate over the list\n for item in lst:\n # If item exists in the dictionary, increment its count\n if item in frequencies:\n frequencies[item] += 1\n # Else, add the item to the dictionary with a count of 1\n else:\n frequencies[item] = 1\n # Find and return the item with the maximum frequency\n return max(frequencies, key=frequencies.get)", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(lst):\n \"\"\"Function to find the item with maximum frequency in a given list.\"\"\"\n frequency_dict = {}\n for item in lst:\n if item in frequency_dict:\n frequency_dict[item] += 1\n else:\n frequency_dict[item] = 1\n max_frequency = max(list(frequency_dict.values()))\n for key, value in frequency_dict.items():\n if value == max_frequency:\n return key", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(lst):\n count_dict = {}\n for item in lst:\n if item in count_dict:\n count_dict[item] += 1\n else:\n count_dict[item] = 1\n max_count = max(count_dict.values())\n for item, count in count_dict.items():\n if count == max_count:\n return item", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(lst):\n count_dict = {}\n for num in lst:\n if num in count_dict:\n count_dict[num] += 1\n else:\n count_dict[num] = 1\n return max(count_dict, key=count_dict.get)", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(lst):\n \"\"\"Return item with maximum frequency in a given list.\"\"\"\n # Create a dictionary to count frequency of each item in list\n frequency = {}\n for item in lst:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n \n # Find item with maximum frequency\n max_item = max(frequency, key=frequency.get)\n \n return max_item", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(input_list):\n \"\"\"Return the item with maximum frequency in a given list.\"\"\"\n frequency_dict = {}\n for item in input_list:\n if item in frequency_dict:\n frequency_dict[item] += 1\n else:\n frequency_dict[item] = 1\n \n max_frequency = max(frequency_dict.values())\n for item, frequency in frequency_dict.items():\n if frequency == max_frequency:\n return item", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(lst):\n count_dict = {}\n for i in lst:\n if i in count_dict:\n count_dict[i] += 1\n else:\n count_dict[i] = 1\n max_freq = max(count_dict.values())\n for key, value in count_dict.items():\n if value == max_freq:\n return key", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(lst):\n \"\"\"\n This function accepts a list of integers and returns the item with maximum frequency.\n \"\"\"\n from collections import Counter\n count = Counter(lst)\n return count.most_common(1)[0][0]", "matching_cluster_idx": 4}, {"solution": "def max_occurrences(lst):\n freq_dict = {}\n for i in lst:\n if i in freq_dict:\n freq_dict[i] += 1\n else:\n freq_dict[i] = 1\n max_freq = max(freq_dict.values())\n for key, value in freq_dict.items():\n if value == max_freq:\n return key", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(lst):\n # create a dictionary to hold item frequencies\n freq_dict = {}\n for item in lst:\n if item in freq_dict:\n freq_dict[item] += 1\n else:\n freq_dict[item] = 1\n\n # find the item with maximum frequency\n max_freq = max(freq_dict.values())\n for item, freq in freq_dict.items():\n if freq == max_freq:\n return item", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(lst):\n \"\"\"\n Function to find the item with maximum frequency in a given list.\n \n Parameters:\n lst (list): input list\n \n Returns:\n int: item with maximum frequency\n \"\"\"\n count_dict = {}\n for i in lst:\n if i in count_dict:\n count_dict[i] += 1\n else:\n count_dict[i] = 1\n max_value = max(list(count_dict.values()))\n max_freq_items = [k for k, v in count_dict.items() if v == max_value]\n return max_freq_items[0]", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(lst):\n \"\"\"Return the item with maximum frequency in the given list\"\"\"\n from collections import Counter\n counter = Counter(lst)\n return counter.most_common(1)[0][0]", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(lst):\n from collections import Counter\n counter = Counter(lst)\n return counter.most_common(1)[0][0]", "matching_cluster_idx": 4}, {"solution": "def max_occurrences(list):\n \"\"\"\n Function to find the item with maximum frequency in a given list.\n \"\"\"\n count_dict = {}\n for num in list:\n if num in count_dict:\n count_dict[num] += 1\n else:\n count_dict[num] = 1\n\n max_freq = max(count_dict.values())\n max_freq_item = [k for k, v in count_dict.items() if v == max_freq]\n\n return max_freq_item[0]", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(lst):\n max_count = 0\n max_item = None\n for item in lst:\n count = lst.count(item)\n if count > max_count:\n max_count = count\n max_item = item\n return max_item", "matching_cluster_idx": 1}, {"solution": "def max_occurrences(lst):\n \"\"\"\n This function returns the item with maximum frequency in a given list.\n \"\"\"\n counts = {}\n for item in lst:\n if item in counts:\n counts[item] += 1\n else:\n counts[item] = 1\n return max(counts, key=counts.get)", "matching_cluster_idx": 3}]}, "Mbpp/137": {"dps": null, "dps_norm": null, "pass@1": 4.0, "profiled": []}, "Mbpp/140": {"dps": 66.08695652173913, "dps_norm": 71.25, "pass@1": 96.0, "profiled": [{"solution": "def extract_singly(lst):\n return set([num for sublist in lst for num in sublist])", "matching_cluster_idx": 5}, {"solution": "def extract_singly(list_of_lists):\n # flatten the list of lists into a single list\n flattened_list = [num for sublist in list_of_lists for num in sublist]\n # convert the list into a set to remove duplicates and return\n return set(flattened_list)", "matching_cluster_idx": 5}, {"solution": "def extract_singly(list_of_tuples):\n flat_list = []\n for tpl in list_of_tuples:\n for num in tpl:\n flat_list.append(num)\n return set(flat_list)", "matching_cluster_idx": 4}, {"solution": "def extract_singly(nested_list):\n # Flatten the list of lists\n flattened_list = [num for sublist in nested_list for num in sublist]\n \n # Return the set of unique numbers\n return set(flattened_list)", "matching_cluster_idx": 5}, {"solution": "def extract_singly(lst):\n # Converts each tuple into a list and then combines all of the lists into one.\n combined_lst = [num for sublist in lst for num in sublist]\n # Converts the combined list into a set to remove any duplicate numbers.\n return set(combined_lst)", "matching_cluster_idx": 5}, {"solution": "def extract_singly(lst):\n # initializing empty list\n result = []\n # iterate over all the nested lists in the input list\n for sub_list in lst:\n # iterate over all elements in each nested list\n for item in sub_list:\n # add each item to the result list\n result.append(item)\n # return the list as a set to remove any duplicates and convert it to a list\n return list(set(result))", "matching_cluster_idx": 4}, {"solution": "def extract_singly(lst):\n return set(num for sublist in lst for num in sublist)", "matching_cluster_idx": 5}, {"solution": "def extract_singly(lst):\n # Use set to keep unique values\n result = set()\n for sublist in lst:\n for number in sublist:\n result.add(number)\n return result", "matching_cluster_idx": 4}, {"solution": "def extract_singly(lst):\n # Using set to eliminate duplicates, then turning the list into a set\n return set(num for sublist in lst for num in sublist)", "matching_cluster_idx": 4}, {"solution": "def extract_singly(list_of_lists):\n # Using a set to remove duplicates\n flat_set = set()\n for sub_list in list_of_lists:\n for item in sub_list:\n flat_set.add(item)\n return flat_set", "matching_cluster_idx": 3}, {"solution": "def extract_singly(list_of_lists):\n # Using list comprehension to flatten the list of lists and \n # converting the result to a set to eliminate duplicate values.\n return set(num for sublist in list_of_lists for num in sublist)", "matching_cluster_idx": 5}, {"solution": "def extract_singly(lst):\n return set([num for sublist in lst for num in sublist])", "matching_cluster_idx": 5}, {"solution": "def extract_singly(lst_lst):\n return set([num for sublist in lst_lst for num in sublist])", "matching_cluster_idx": 5}, {"solution": "def extract_singly(lst):\n return set(num for sublist in lst for num in sublist)", "matching_cluster_idx": 5}, {"solution": "def extract_singly(lst):\n result = set()\n for t in lst:\n for item in t:\n result.add(item)\n return result", "matching_cluster_idx": 4}, {"solution": "def extract_singly(lst):\n return set([num for sublist in lst for num in sublist])", "matching_cluster_idx": 5}, {"solution": "def extract_singly(list_of_lists):\n flattened_list = [number for sublist in list_of_lists for number in sublist]\n return set(flattened_list)", "matching_cluster_idx": 5}, {"solution": "def extract_singly(lst_of_lst):\n # Use set to avoid duplicates\n unique_elements = set()\n \n # Iterate over each sublist\n for sublist in lst_of_lst:\n # Extend the unique elements set with new elements from the sublist\n unique_elements.update(sublist)\n \n # Return the final unique elements set\n return unique_elements", "matching_cluster_idx": 7}, {"solution": "def extract_singly(list_of_lists):\n return set(num for sublist in list_of_lists for num in sublist)", "matching_cluster_idx": 5}, {"solution": "def extract_singly(lst):\n # Initialize an empty list to collect elements\n numbers = []\n \n # Loop over the outer list\n for sublist in lst:\n # Loop over the inner tuples\n for num in sublist:\n numbers.append(num)\n \n # Return a set of the collected elements\n return set(numbers)", "matching_cluster_idx": 4}]}, "Mbpp/141": {"dps": 64.05895691609977, "dps_norm": 40.625, "pass@1": 53.0, "profiled": [{"solution": "def pancake_sort(lst):\n def flip(arr, i):\n start = 0\n while start < i:\n arr[start], arr[i] = arr[i], arr[start]\n start += 1\n i -= 1\n\n def findMaxIndex(arr, n):\n maxIndex = 0\n for i in range(0, n):\n if arr[i] > arr[maxIndex]:\n maxIndex = i\n return maxIndex\n\n n = len(lst)\n while n > 0:\n maxIndex = findMaxIndex(lst, n)\n if maxIndex != n-1:\n flip(lst, maxIndex)\n flip(lst, n-1)\n n -= 1\n return lst", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(lst):\n for i in range(len(lst)):\n min_index = i\n for j in range(i+1, len(lst)):\n if lst[min_index] > lst[j]:\n min_index = j\n lst[i], lst[min_index] = lst[min_index], lst[i]\n return lst", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(nums):\n for i in range(len(nums)):\n # get the minimum value index in the remaining list\n min_val_index = nums[i:].index(min(nums[i:]))\n # place the minimum value at the current index\n nums[i], nums[min_val_index + i] = nums[min_val_index + i], nums[i]\n return nums", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(lst):\n n = len(lst)\n for i in range(n):\n min_idx = lst.index(min(lst[i:]), i, n)\n if min_idx != i:\n lst[i:min_idx+1] = lst[i:min_idx+1][::-1]\n return lst", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(lst):\n \"\"\"Sort list using Pancake Sort method.\"\"\"\n for i in range(len(lst)):\n min_idx = i\n for j in range(i+1, len(lst)):\n if lst[j] < lst[min_idx]:\n min_idx = j\n\n # Swap the found minimum element with the first element of remaining list\n lst[i], lst[min_idx] = lst[min_idx], lst[i]\n \n return lst", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(lst):\n for i in range(len(lst)):\n min_index = i\n for j in range(i+1, len(lst)):\n if lst[min_index] > lst[j]:\n min_index = j\n lst[i], lst[min_index] = lst[min_index], lst[i]\n return lst", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(lst):\n for i in range(len(lst)):\n min_index = i\n for j in range(i+1, len(lst)):\n if lst[j] < lst[min_index]:\n min_index = j\n \n lst[i], lst[min_index] = lst[min_index], lst[i]\n return lst", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(lst):\n for i in range(len(lst)):\n minimum = i\n for j in range(i+1, len(lst)):\n if lst[j] < lst[minimum]:\n minimum = j\n lst[i], lst[minimum] = lst[minimum], lst[i]\n return lst", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(lst):\n \"\"\"Return sorted list with the classic pancake sort method.\"\"\"\n \n def flip(lst, k):\n \"\"\"Return lst reversed up to k.\"\"\"\n return lst[:k][::-1] + lst[k:]\n \n n = len(lst)\n result = []\n \n for i in range(n, 0, -1):\n # Find max in lst[:i]\n max_index = lst[:i].index(max(lst[:i]))\n \n if max_index != i - 1:\n # Flip the max value to the beginning\n lst = flip(lst, max_index + 1)\n # Flip the max value to the end\n lst = flip(lst, i)\n \n result.append(lst[i - 1])\n \n return result[::-1]", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(lst):\n for i in range(len(lst)):\n min_idx = i\n for j in range(i + 1, len(lst)):\n if lst[j] < lst[min_idx]:\n min_idx = j\n lst[i], lst[min_idx] = lst[min_idx], lst[i]\n return lst", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(arr):\n def flip(arr, k):\n left = 0\n right = k - 1\n while left < right:\n arr[left], arr[right] = arr[right], arr[left]\n left += 1\n right -= 1\n\n n = len(arr)\n for i in range(n, 0, -1):\n max_index = arr.index(max(arr[:i]))\n if max_index != i - 1:\n flip(arr, max_index + 1)\n flip(arr, i)\n return arr", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(arr):\n for i in range(len(arr)):\n min_idx = i\n for j in range(i+1, len(arr)):\n if arr[min_idx] > arr[j]:\n min_idx = j\n arr[i], arr[min_idx] = arr[min_idx], arr[i]\n return arr", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(lst):\n for i in range(len(lst)):\n minimum = i\n for j in range(i+1, len(lst)):\n if lst[j] < lst[minimum]:\n minimum = j\n lst[i], lst[minimum] = lst[minimum], lst[i]\n return lst", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(lst):\n for i in range(len(lst)):\n min_index = i\n for j in range(i+1, len(lst)):\n if lst[j] < lst[min_index]:\n min_index = j\n lst[i], lst[min_index] = lst[min_index], lst[i]\n return lst", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(arr):\n def flip(arr, i):\n start = 0\n while start < i:\n arr[start], arr[i] = arr[i], arr[start]\n start += 1\n i -= 1\n\n def find_max_index(arr, n):\n max_index = 0\n for i in range(1, n):\n if arr[i] > arr[max_index]:\n max_index = i\n return max_index\n\n n = len(arr)\n while n > 1:\n max_index = find_max_index(arr, n)\n if max_index != n - 1:\n flip(arr, max_index)\n flip(arr, n - 1)\n n -= 1\n return arr", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(lst):\n for i in range(len(lst)):\n min_index = i\n for j in range(i + 1, len(lst)):\n if lst[j] < lst[min_index]:\n min_index = j\n \n lst[i], lst[min_index] = lst[min_index], lst[i]\n \n return lst", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(nums):\n for i in range(len(nums)):\n # Find the maximum element in remaining unsorted array\n max_idx = nums.index(max(nums[:len(nums) - i]))\n\n # If the maximum number is not at the end of the array\n if max_idx != len(nums) - i:\n # Flip the maximum number to the start of the array\n nums[:max_idx + 1] = nums[:max_idx + 1][::-1]\n\n # Flip the maximum number to the correct position\n nums[:len(nums) - i] = nums[:len(nums) - i][::-1]\n\n return nums", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(lst):\n for i in range(len(lst)):\n minimum = i\n for j in range(i + 1, len(lst)):\n if lst[j] < lst[minimum]:\n minimum = j\n \n lst[i], lst[minimum] = lst[minimum], lst[i]\n\n return lst", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(lst):\n for i in range(len(lst)):\n min_idx = i\n for j in range(i+1, len(lst)):\n if lst[j] < lst[min_idx]:\n min_idx = j\n lst[i], lst[min_idx] = lst[min_idx], lst[i]\n return lst", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(lst):\n for i in range(len(lst)):\n minimum = i + lst[i:].index(min(lst[i:]))\n if minimum != i:\n lst[i], lst[minimum] = lst[minimum], lst[i]\n return lst", "matching_cluster_idx": 3}]}, "Mbpp/166": {"dps": 94.39999999999999, "dps_norm": 50.0, "pass@1": 98.0, "profiled": [{"solution": "def find_even_pair(lst):\n \"\"\"\n Function that counts the number of pairs of integers in a list that xor to an even number.\n \"\"\"\n count = 0\n for i in range(len(lst)):\n for j in range(i+1, len(lst)):\n if (lst[i] ^ lst[j]) & 1 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(lst):\n count = 0\n n = len(lst)\n \n for i in range(0, n):\n for j in range(i + 1, n):\n if (lst[i] ^ lst[j]) & 1 == 0:\n count += 1\n \n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(lst):\n count = 0\n for i in range(len(lst)):\n for j in range(i + 1, len(lst)):\n if (lst[i] ^ lst[j]) & 1 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(lst):\n n = len(lst)\n count = 0\n for i in range(0, n):\n for j in range(i + 1, n):\n if (lst[i] ^ lst[j]) & 1 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(lst):\n count = 0\n for i in range(len(lst)):\n for j in range(i+1, len(lst)):\n if (lst[i] ^ lst[j]) & 1 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(lst):\n count = 0\n n = len(lst)\n\n for i in range(0, n):\n for j in range(i + 1, n):\n if (lst[i] ^ lst[j]) & 1 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(lst):\n count = 0\n n = len(lst)\n\n for i in range(0, n):\n for j in range(i + 1, n):\n if (lst[i] ^ lst[j]) & 1 == 0:\n count += 1\n\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(lst):\n count = 0\n for i in range(len(lst)):\n for j in range(i + 1, len(lst)):\n if (lst[i] ^ lst[j]) & 1 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(arr):\n count = 0\n n = len(arr)\n\n for i in range(0, n):\n for j in range(i+1, n):\n if ((arr[i] ^ arr[j]) % 2 == 0):\n count += 1\n\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(lst):\n even_pairs = 0\n for i in range(len(lst)):\n for j in range(i + 1, len(lst)):\n if (lst[i] ^ lst[j]) & 1 == 0:\n even_pairs += 1\n return even_pairs", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(arr):\n count = 0\n n = len(arr)\n\n # Select two elements from array\n for i in range(0, n):\n for j in range(i+1, n):\n # XOR the two selected elements and check if it's an even number\n if (arr[i] ^ arr[j]) & 1 == 0:\n count += 1\n\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(lst):\n pair_count = 0\n for i in range(len(lst)):\n for j in range(i+1, len(lst)):\n if (lst[i] ^ lst[j]) % 2 == 0:\n pair_count += 1\n return pair_count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(lst):\n n = len(lst)\n count = 0\n for i in range(0, n):\n for j in range(i + 1, n):\n if (lst[i] ^ lst[j]) & 1 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(lst):\n count = 0\n for i in range(len(lst)):\n for j in range(i + 1, len(lst)):\n if (lst[i] ^ lst[j]) & 1 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(lst):\n '''\n Function to count the number of pairs of integers in a list that xor to an even number\n '''\n \n # Initialize the result\n result = 0\n \n # Loop through the list\n for i in range(len(lst)):\n for j in range(i + 1, len(lst)):\n # If the xor of the pair is even, increment the result\n if (lst[i] ^ lst[j]) & 1 == 0:\n result += 1\n \n return result", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(lst):\n even_count = 0\n for i in range(len(lst)):\n for j in range(i+1, len(lst)):\n if (lst[i] ^ lst[j]) & 1 == 0:\n even_count += 1\n return even_count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(lst):\n # Creating a variable to store the count\n count = 0\n \n # Loop through the list\n for i in range(len(lst)):\n for j in range(i+1, len(lst)):\n # Check if xor is even\n if (lst[i] ^ lst[j]) & 1 == 0:\n count += 1\n \n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(lst):\n count = 0\n for i in range(len(lst)):\n for j in range(i+1, len(lst)):\n if (lst[i] ^ lst[j]) & 1 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(lst):\n count = 0\n n = len(lst)\n for i in range(0, n):\n for j in range(i+1, n):\n if (lst[i] ^ lst[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(lst):\n even_pair_count = 0\n for i in range(len(lst)):\n for j in range(i+1, len(lst)):\n if (lst[i] ^ lst[j]) & 1 == 0:\n even_pair_count += 1\n return even_pair_count", "matching_cluster_idx": 1}]}, "Mbpp/170": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 82.0, "profiled": [{"solution": "def sum_range_list(num_list, start_index, end_index):\n \"\"\"Function to calculate the sum of a list from a start index to an end index\"\"\"\n return sum(num_list[start_index:end_index+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(lst, index1, index2):\n return sum(lst[index1:index2+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(num_list, start_index, end_index):\n return sum(num_list[start_index:end_index+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(lst, i, j):\n return sum(lst[i:j+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(lst, start_index, end_index):\n \"\"\"\n Function to calculate the sum of list items within a specified range of indices\n \n Parameters:\n lst (list): List of numbers\n start_index (int): Starting index of the range\n end_index (int): Ending index of the range\n \n Returns:\n int: Sum of list elements within the range of indices\n \"\"\"\n \n return sum(lst[start_index:end_index+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(lst, start, end):\n # The function returns the sum of the elements in a list between two indices (inclusive).\n return sum(lst[start:end+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(num_list, start_index, end_index):\n \"\"\"\n The function takes a list of numbers and two indices as parameters. \n It returns the sum of the numbers in the list within the range specified by the two indices.\n \n :param num_list: list of numbers\n :param start_index: start of range index\n :param end_index: end of range index\n :returns: sum of numbers within the range\n \"\"\"\n return sum(num_list[start_index:end_index+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(num_list, start_index, end_index):\n return sum(num_list[start_index:end_index+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(numbers, start_index, end_index):\n return sum(numbers[start_index:end_index+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(nums, start_index, end_index):\n return sum(nums[start_index:end_index+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(lst, start_index, end_index):\n return sum(lst[start_index:end_index+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(lst, start_index, end_index):\n return sum(lst[start_index:end_index+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(nums, start_index, end_index):\n return sum(nums[start_index:end_index+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(numbers, start_index, end_index):\n return sum(numbers[start_index:end_index+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(lst, i, j):\n return sum(lst[i:j+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(lst, start, end):\n \"\"\"\n This function receives a list and two indices as parameters.\n It returns the sum of elements of the list from the start index to the end index (inclusive).\n :param lst: list\n :param start: int\n :param end: int\n :return: int\n \"\"\"\n return sum(lst[start:end+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(lst, start, end):\n return sum(lst[start:end+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(numbers, start_index, end_index):\n \"\"\"\n This function returns the sum of the elements in the input list that lie \n between the start_index and end_index (both inclusive)\n \"\"\"\n return sum(numbers[start_index:end_index+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(num_list, start_index, end_index):\n return sum(num_list[start_index:end_index+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(lst, start, end):\n return sum(lst[start:end+1])", "matching_cluster_idx": 7}]}, "Mbpp/226": {"dps": 83.10077519379844, "dps_norm": 71.42857142857143, "pass@1": 100.0, "profiled": [{"solution": "def odd_values_string(s):\n return s[::2]", "matching_cluster_idx": 5}, {"solution": "def odd_values_string(s):\n return s[::2]", "matching_cluster_idx": 5}, {"solution": "def odd_values_string(s):\n return s[::2]", "matching_cluster_idx": 5}, {"solution": "def odd_values_string(my_string):\n result = \"\"\n for i in range(len(my_string)):\n if i % 2 == 0:\n result = result + my_string[i]\n return result", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(s):\n \"\"\"This function returns a string of characters\n with even index values of a given string\"\"\"\n return s[::2]", "matching_cluster_idx": 5}, {"solution": "def odd_values_string(s):\n return s[::2]", "matching_cluster_idx": 5}, {"solution": "def odd_values_string(s):\n return s[::2]", "matching_cluster_idx": 5}, {"solution": "def odd_values_string(str):\n result = \"\"\n for i in range(len(str)):\n if i % 2 == 0:\n result = result + str[i]\n return result", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(s):\n return s[::2]", "matching_cluster_idx": 5}, {"solution": "def odd_values_string(s):\n return s[::2]", "matching_cluster_idx": 5}, {"solution": "def odd_values_string(str):\n return str[::2]", "matching_cluster_idx": 5}, {"solution": "def odd_values_string(s):\n return s[::2]", "matching_cluster_idx": 5}, {"solution": "def odd_values_string(s):\n return s[::2]", "matching_cluster_idx": 5}, {"solution": "def odd_values_string(s):\n return s[::2]", "matching_cluster_idx": 5}, {"solution": "def odd_values_string(s):\n return s[::2]", "matching_cluster_idx": 5}, {"solution": "def odd_values_string(str):\n result = \"\"\n for i in range(len(str)):\n if i % 2 == 0:\n result = result + str[i]\n return result", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(s):\n return s[::2]", "matching_cluster_idx": 5}, {"solution": "def odd_values_string(str):\n return str[::2]", "matching_cluster_idx": 5}, {"solution": "def odd_values_string(s):\n result = \"\"\n for i in range(len(s)):\n if i % 2 == 0:\n result = result + s[i]\n return result", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(s):\n return s[::2]", "matching_cluster_idx": 5}]}, "Mbpp/230": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def replace_blank(input_string, replacement_char):\n return input_string.replace(' ', replacement_char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string, character):\n return input_string.replace(\" \", character)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(s, c):\n return s.replace(\" \", c)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(s, c):\n return s.replace(' ', c)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_str, char):\n \"\"\"\n Function to replace blank spaces in a string with a given character.\n \"\"\"\n return input_str.replace(' ', char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(s, c):\n return s.replace(' ', c)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(string, char):\n return string.replace(' ', char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(s, c):\n return s.replace(' ', c)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(s, ch):\n return s.replace(\" \", ch)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string, char):\n return input_string.replace(' ', char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(s, c):\n return s.replace(\" \", c)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string, replacement_char):\n return input_string.replace(' ', replacement_char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(s, c):\n return s.replace(\" \", c)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string, replace_char):\n return input_string.replace(\" \", replace_char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string, replace_with):\n return input_string.replace(' ', replace_with)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(my_string, my_char):\n \"\"\"\n This function replaces blank spaces in the string with a given character and returns the string.\n \n :param my_string: a string that will be processed.\n :param my_char: a character that will replace spaces in the string.\n :return: the string with spaces replaced by the given character.\n \"\"\"\n return my_string.replace(' ', my_char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(str_input, char_input):\n return str_input.replace(\" \", char_input)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_str, replace_char):\n return input_str.replace(' ', replace_char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(s, ch):\n return s.replace(' ', ch)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(string, character):\n return string.replace(' ', character)", "matching_cluster_idx": 7}]}, "Mbpp/239": {"dps": 89.36781609195403, "dps_norm": 85.83333333333333, "pass@1": 12.0, "profiled": [{"solution": "def get_total_number_of_sequences(m, n):\n # Create a DP table to store the results\n dp = [[0 for _ in range(m + 1)] for _ in range(n + 1)]\n \n # Initialize the first row with 1's\n for j in range(m + 1):\n dp[1][j] = 1\n\n # Fill up the DP table\n for i in range(2, n + 1):\n for j in range(1, m + 1):\n for k in range(2 * j, m + 1):\n dp[i][j] += dp[i - 1][k]\n \n # The total number of sequences of length 'n' is the sum of the last row\n return sum(dp[n])", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n # The base case, when n is 0 or 1\n if n <= 1:\n return m\n # Creating a memoization table to store previously computed values\n memo = [[0 for _ in range(n+1)] for _ in range(m+1)]\n # Initializing the base cases\n for i in range(m+1):\n memo[i][0] = 1\n memo[i][1] = i\n # Computing the other values\n for i in range(2, m+1):\n for j in range(2, n+1):\n if j > i:\n break\n else:\n # Using the formula: memo[i][j] = memo[i-1][j] + memo[i//2][j-1]\n memo[i][j] = memo[i-1][j] + memo[i//2][j-1]\n # Returning the result\n return memo[m][n]", "matching_cluster_idx": 8}, {"solution": "def get_total_number_of_sequences(m, n):\n # Create a 2D DP table filled with 0's\n dp = [[0 for _ in range(n+1)] for _ in range(m+1)]\n\n # Initialize the table for the base case\n for i in range(1, m+1):\n dp[i][1] = 1\n\n # Fill up the DP table\n for i in range(1, m+1):\n for j in range(2, n+1):\n for k in range(2*i, m+1):\n dp[k][j] += dp[i][j-1]\n\n # Get the total number of sequences\n res = 0\n for i in range(1, m+1):\n res += dp[i][n]\n\n return res", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n # initial dp array\n dp = [[0 for _ in range(n+1)] for __ in range(m+1)]\n dp[0][0] = 1\n for i in range(1, m+1):\n dp[i][0] = 1\n for j in range(1, min(i, n)+1):\n dp[i][j] = dp[i-1][j] + dp[i//2][j-1]\n\n return dp[m][n]", "matching_cluster_idx": 8}, {"solution": "def get_total_number_of_sequences(m, n):\n dp = [[0 for _ in range(n+1)] for _ in range(m+1)]\n dp[0][0] = 1\n for i in range(1, m+1):\n dp[i][0] = 1\n for j in range(1, n+1):\n dp[i][j] = dp[i-1][j] + dp[i//2][j-1]\n return dp[m][n]", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n # Initialize a 2D array dp with dimensions (m+1) x (n+1)\n dp = [[0] * (n + 1) for _ in range(m + 1)]\n \n # For each number i from 1 to m, set the base case where sequence length is 1 to i\n for i in range(1, m + 1):\n dp[i][1] = i\n \n # For each sequence length j from 2 to n, and for each number i from 1 to m\n for j in range(2, n + 1):\n for i in range(1, m + 1):\n # The number of possible sequences of length j ending with number i \n # is the sum of number of possible sequences of length j-1 for numbers \n # that are twice smaller than i, which can be calculated using prefix sum\n dp[i][j] = dp[i - 1][j] + dp[max(i // 2, i - m)][j - 1]\n \n # Return the number of possible sequences of length n ending with number m\n return dp[m][n]", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n # Initializing a 2D DP table of size (m+1)*(n+1)\n dp = [[0]*(n+1) for _ in range(m+1)]\n\n # When n = 1, there are m possibilities\n for i in range(1, m+1):\n dp[i][1] = i\n\n # When m < n, there are no possibilities\n for j in range(2, n+1):\n for i in range(j, m+1):\n dp[i][j] = dp[i-1][j] + dp[i//2][j-1]\n\n return dp[m][n]", "matching_cluster_idx": 8}, {"solution": "def get_total_number_of_sequences(m, n):\n # Create a 2D array dp of size (m+1) x (n+1) to store the count of sequences\n dp = [[0] * (n + 1) for _ in range(m + 1)]\n\n # There is one sequence of length 1: [1], [2], ..., [m]\n for i in range(1, m + 1):\n dp[i][1] = 1\n\n for i in range(1, m + 1):\n for j in range(2, n + 1):\n # Each new element can be at least twice the previous one\n # Hence, start from i*2 to m\n for k in range(i * 2, m + 1):\n dp[k][j] += dp[i][j - 1]\n\n # Sum up the counts of sequences of length n for all possible values of m\n total = sum(dp[i][n] for i in range(1, m + 1))\n\n return total", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n if n == 1:\n return m - 1\n\n # Initiate the DP table\n dp = [[0] * (n+1) for _ in range(m+1)]\n for i in range(m+1):\n dp[i][1] = i # When n == 1, there are i possibilities for sequence starting with any number < m.\n\n # Fill the DP table\n for seq_length in range(2, n+1):\n for max_element in range(2, m+1):\n dp[max_element][seq_length] = dp[max_element-1][seq_length] + dp[max_element//2][seq_length-1]\n\n return dp[m][n]", "matching_cluster_idx": 8}, {"solution": "def get_total_number_of_sequences(m, n):\n # Initialize a 2D array with size (m+1) x (n+1) filled with zero\n dp = [[0] * (n + 1) for _ in range(m + 1)]\n\n # Fill up the array using dynamic programming\n for i in range(1, m + 1):\n dp[i][1] = i\n for j in range(2, n + 1):\n dp[i][j] = dp[i // 2][j - 1] + dp[i - 1][j]\n\n return dp[m][n]", "matching_cluster_idx": 8}, {"solution": "def get_total_number_of_sequences(m, n):\n # initialize a DP array\n dp = [[0] * (m + 1) for _ in range(n + 1)]\n \n # base case: sequence of length 1 with elements from 1 to m\n for i in range(1, m + 1):\n dp[1][i] = i\n\n # fill up the DP array\n for i in range(2, n + 1):\n prefix_sum = 0\n for j in range(2, m + 1):\n prefix_sum += dp[i - 1][j // 2]\n dp[i][j] = prefix_sum\n\n return dp[n][m]", "matching_cluster_idx": 8}, {"solution": "def get_total_number_of_sequences(m, n):\n dp = [[0] * (n + 1) for _ in range(m + 1)]\n dp[0][0] = 1\n for i in range(1, m + 1):\n dp[i][0] = 1\n for j in range(1, n + 1):\n dp[i][j] = dp[i - 1][j] + dp[i // 2][j - 1]\n return dp[m][n]", "matching_cluster_idx": 8}]}, "Mbpp/240": {"dps": 56.21951219512196, "dps_norm": 72.77777777777777, "pass@1": 89.0, "profiled": [{"solution": "def replace_list(list1, list2):\n # Remove the last element of the first list\n list1 = list1[:-1]\n # Add the second list elements to the first list\n list1.extend(list2)\n return list1", "matching_cluster_idx": 6}, {"solution": "def replace_list(list1, list2):\n # Remove the last element of list1\n list1 = list1[:-1]\n # Append list2 to list1\n list1.extend(list2)\n return list1", "matching_cluster_idx": 6}, {"solution": "def replace_list(list1, list2):\n list1[:] = list1[:-1] + list2\n return list1", "matching_cluster_idx": 4}, {"solution": "def replace_list(list1, list2):\n list1[:] = list1[:-1] + list2\n return list1", "matching_cluster_idx": 4}, {"solution": "def replace_list(list1, list2):\n list1.pop() # remove the last element of the list1\n list1.extend(list2) # add the elements of list2 to list1\n return list1", "matching_cluster_idx": 8}, {"solution": "def replace_list(l1, l2):\n l1[:] = l1[:-1] + l2\n return l1", "matching_cluster_idx": 4}, {"solution": "def replace_list(list1, list2):\n # Remove the last element of list1\n list1 = list1[:-1]\n # Append list2 to list1\n return list1 + list2", "matching_cluster_idx": 5}, {"solution": "def replace_list(list1, list2):\n list1[:] = list1[:-1] + list2\n return list1", "matching_cluster_idx": 4}, {"solution": "def replace_list(list1, list2):\n # removing last element from list1\n list1 = list1[:-1]\n # appending list2 to list1\n list1.extend(list2)\n return list1", "matching_cluster_idx": 6}, {"solution": "def replace_list(list1, list2):\n # replace the last element of list1 with all elements in list2\n list1 = list1[:-1] + list2\n return list1", "matching_cluster_idx": 5}, {"solution": "def replace_list(list1, list2):\n list1[:] = list1[:-1] + list2\n return list1", "matching_cluster_idx": 4}, {"solution": "def replace_list(list1, list2):\n # removes last element of list1\n list1 = list1[:-1]\n # concatenate list1 and list2\n list1.extend(list2)\n return list1", "matching_cluster_idx": 6}, {"solution": "def replace_list(list1, list2):\n # Replaces the last element of the first list with the elements of the second list\n del list1[-1]\n return list1 + list2", "matching_cluster_idx": 6}, {"solution": "def replace_list(list1, list2):\n # Remove last element of the first list\n list1 = list1[:-1]\n # Add elements of the second list to the first\n list1.extend(list2)\n return list1", "matching_cluster_idx": 6}, {"solution": "def replace_list(list1, list2):\n # Remove the last element from the first list\n list1 = list1[:-1]\n # Extend the first list with the elements of the second list\n list1.extend(list2)\n return list1", "matching_cluster_idx": 6}, {"solution": "def replace_list(list1, list2):\n # remove last element of list1\n list1 = list1[:-1]\n # extend list1 with elements of list2\n list1.extend(list2)\n return list1", "matching_cluster_idx": 6}, {"solution": "def replace_list(list1, list2):\n # remove the last element from the first list\n list1 = list1[:-1]\n # add the elements of the second list to the first list\n list1.extend(list2)\n return list1", "matching_cluster_idx": 6}, {"solution": "def replace_list(list1, list2):\n list1.pop()\n list1.extend(list2)\n return list1", "matching_cluster_idx": 8}, {"solution": "def replace_list(list1, list2):\n # remove last element from list1\n list1 = list1[:-1]\n # add elements of list2 to list1\n return list1 + list2", "matching_cluster_idx": 5}, {"solution": "def replace_list(list1, list2):\n list1.pop() # Remove the last element of the first list\n return list1 + list2 # Combine the two lists", "matching_cluster_idx": 6}]}, "Mbpp/251": {"dps": 85.05747126436782, "dps_norm": 76.66666666666666, "pass@1": 86.0, "profiled": [{"solution": "def insert_element(lst, ele):\n result = []\n for item in lst:\n result.append(ele)\n result.append(item)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(list_input, element):\n return [val for item in list_input for val in (element, item)]", "matching_cluster_idx": 5}, {"solution": "def insert_element(list, element):\n result = []\n for i in list:\n result.append(element)\n result.append(i)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(input_list, element):\n return [item for element_in_list in input_list for item in (element, element_in_list)]", "matching_cluster_idx": 5}, {"solution": "def insert_element(input_list, element):\n result = []\n for item in input_list:\n result.append(element)\n result.append(item)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, ele):\n result = []\n for item in lst:\n result.append(ele)\n result.append(item)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(input_list, element):\n result_list = []\n for item in input_list:\n result_list.append(element)\n result_list.append(item)\n return result_list", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, elem):\n result = []\n for item in lst:\n result.append(elem)\n result.append(item)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, elem):\n result = []\n for i in lst:\n result.extend([elem, i])\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(input_list, element):\n result = []\n for i in input_list:\n result.append(element)\n result.append(i)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(input_list, element):\n output_list = []\n for item in input_list:\n output_list.append(element)\n output_list.append(item)\n return output_list", "matching_cluster_idx": 6}, {"solution": "def insert_element(input_list, element):\n result = []\n for item in input_list:\n result.append(element)\n result.append(item)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n result = []\n for item in lst:\n result.append(element)\n result.append(item)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(input_list, insert_item):\n result_list = []\n for item in input_list:\n result_list.append(insert_item)\n result_list.append(item)\n return result_list", "matching_cluster_idx": 6}, {"solution": "def insert_element(input_list, elem):\n result = []\n for i in input_list:\n result.append(elem)\n result.append(i)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, ele):\n result = []\n for i in lst:\n result.append(ele)\n result.append(i)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n result = []\n for i in lst:\n result.append(element)\n result.append(i)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(input_list, element):\n result_list = []\n for item in input_list:\n result_list.append(element)\n result_list.append(item)\n return result_list", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, elem):\n result = []\n for item in lst:\n result.append(elem)\n result.append(item)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, elem):\n result = []\n for item in lst:\n result.append(elem)\n result.append(item)\n return result", "matching_cluster_idx": 6}]}, "Mbpp/256": {"dps": 50.970319634703195, "dps_norm": 45.88235294117647, "pass@1": 87.0, "profiled": [{"solution": "def count_Primes_nums(n):\n if n < 2:\n return 0\n\n primes = [True] * n\n primes[0] = primes[1] = False\n for ind, val in enumerate(primes):\n if val is True:\n primes[ind*2::ind] = [False] * (((n - 1)//ind) - 1)\n return sum(primes)", "matching_cluster_idx": 14}, {"solution": "def count_Primes_nums(n: int) -> int:\n \"\"\"\n This function receives a non-negative number and returns the number of\n prime numbers less than the given non-negative number.\n \"\"\"\n\n def is_prime(num):\n \"\"\"\n This helper function checks if a given number is prime.\n \"\"\"\n if num <= 1:\n return False\n\n for i in range(2, num):\n if num % i == 0:\n return False\n\n return True\n\n # Count the number of prime numbers less than 'n'\n count = 0\n for i in range(2, n):\n if is_prime(i):\n count += 1\n\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Primes_nums(n):\n def is_prime(x):\n if x < 2:\n return False\n for i in range(2, int(x**0.5) + 1):\n if x % i == 0:\n return False\n return True\n\n count = 0\n for i in range(n):\n if is_prime(i):\n count += 1\n return count", "matching_cluster_idx": 8}, {"solution": "def count_Primes_nums(n):\n if n < 2:\n return 0\n sieve = [1] * n\n sieve[0] = sieve[1] = 0\n for i in range(2, int(n**0.5) + 1):\n if sieve[i]:\n for j in range(i*i, n, i):\n sieve[j] = 0\n return sum(sieve)", "matching_cluster_idx": 14}, {"solution": "def count_Primes_nums(n):\n def is_prime(num):\n if num < 2:\n return False\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n return False\n return True\n\n primes_count = 0\n for num in range(n):\n if is_prime(num):\n primes_count += 1\n return primes_count", "matching_cluster_idx": 8}, {"solution": "def count_Primes_nums(n: int) -> int:\n \"\"\"\n Function to count prime numbers less than n\n \"\"\"\n if n < 2:\n return 0\n\n primes = [0, 0] + [1]*(n-2)\n p = 2\n while p * p <= n:\n if primes[p] == 1:\n for i in range(p*p, n, p):\n primes[i] = 0\n p += 1\n\n return sum(primes)", "matching_cluster_idx": 14}, {"solution": "def count_Primes_nums(n):\n def is_prime(num):\n if num < 2:\n return False\n for i in range(2,int(num**0.5)+1):\n if num%i==0:\n return False\n return True\n\n count = 0\n for i in range(n):\n if is_prime(i):\n count += 1\n return count", "matching_cluster_idx": 8}, {"solution": "def count_Primes_nums(n):\n def is_prime(num):\n if num < 2:\n return False\n for i in range(2,num):\n if num%i == 0:\n return False\n return True\n primes = [i for i in range(n) if is_prime(i)]\n return len(primes)", "matching_cluster_idx": 2}, {"solution": "def count_Primes_nums(n):\n def is_prime(num):\n if num < 2:\n return False\n for i in range(2,num):\n if num%i == 0:\n return False\n return True\n\n count = 0\n for i in range(n):\n if is_prime(i):\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Primes_nums(num):\n def is_prime(n):\n if n < 2:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True\n\n primes = [x for x in range(2, num) if is_prime(x)]\n return len(primes)", "matching_cluster_idx": 8}, {"solution": "def count_Primes_nums(n):\n def is_prime(num):\n if num < 2:\n return False\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n return False\n return True\n\n count = 0\n for i in range(n):\n if is_prime(i):\n count += 1\n return count", "matching_cluster_idx": 8}, {"solution": "def count_Primes_nums(n: int) -> int:\n def is_prime(num):\n \"\"\"Utility function to check if a number is prime\"\"\"\n if num < 2:\n return False\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n return False\n return True\n\n count = 0\n for i in range(n):\n if is_prime(i):\n count += 1\n return count", "matching_cluster_idx": 8}, {"solution": "def count_Primes_nums(n: int) -> int:\n def is_prime(num):\n if num < 2:\n return False\n for i in range(2, num):\n if num % i == 0:\n return False\n return True\n\n count = 0\n for i in range(n):\n if is_prime(i):\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Primes_nums(n):\n def is_prime(num):\n if num < 2:\n return False\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n return False\n return True\n\n count = 0\n for i in range(n):\n if is_prime(i):\n count += 1\n\n return count", "matching_cluster_idx": 8}, {"solution": "def count_Primes_nums(num):\n def is_prime(n):\n if n <= 1 or (n % 2 == 0 and n > 2): \n return False\n return all(n % i for i in range(3, int(n**0.5) + 1, 2))\n\n primes = [n for n in range(num) if is_prime(n)]\n return len(primes)", "matching_cluster_idx": 9}, {"solution": "def count_Primes_nums(n):\n '''Return the number of prime numbers less than n.'''\n\n # Helper function to check if a number is prime\n def is_prime(num):\n if num < 2:\n return False\n for i in range(2, num):\n if num % i == 0:\n return False\n return True\n\n # Count the primes\n count = 0\n for i in range(n):\n if is_prime(i):\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Primes_nums(n: int) -> int:\n if n < 2:\n return 0\n\n sieve = [True] * n\n sieve[0] = sieve[1] = False\n for current_prime in range(2, int(n ** 0.5) + 1):\n if sieve[current_prime]:\n for multiple in range(current_prime * current_prime, n, current_prime):\n sieve[multiple] = False\n\n return sum(sieve)", "matching_cluster_idx": 14}, {"solution": "def count_Primes_nums(n):\n def is_prime(num):\n if num < 2:\n return False\n for i in range(2,num):\n if num % i == 0:\n return False\n return True\n\n primes = [i for i in range(2,n) if is_prime(i)]\n return len(primes)", "matching_cluster_idx": 1}, {"solution": "def count_Primes_nums(n: int) -> int:\n def is_prime(num):\n if num <= 1:\n return False\n for i in range(2, num):\n if num % i == 0:\n return False\n return True\n\n count = 0\n for i in range(2, n):\n if is_prime(i):\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Primes_nums(n):\n def is_prime(num):\n if num < 2:\n return False\n for i in range(2,num):\n if num % i == 0:\n return False\n return True\n\n count = 0\n for i in range(n):\n if is_prime(i):\n count += 1\n\n return count", "matching_cluster_idx": 2}]}, "Mbpp/265": {"dps": 67.5, "dps_norm": 80.83333333333333, "pass@1": 95.0, "profiled": [{"solution": "def list_split(lst, n):\n splits = [[] for _ in range(n)]\n for i, element in enumerate(lst):\n splits[i % n].append(element)\n return splits", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n return [lst[i::n] for i in range(n)]", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n return [lst[i::n] for i in range(n)]", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n result = [[] for _ in range(n)]\n for i, item in enumerate(lst):\n result[i%n].append(item)\n return result", "matching_cluster_idx": 4}, {"solution": "def list_split(l, n):\n return [l[i::n] for i in range(n)]", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n \"\"\"\n Split a list into sublists for every nth element.\n\n Arguments:\n lst: Input list\n n: Number of elements in each sublist\n\n Returns:\n A list of sublists\n \"\"\"\n return [lst[i::n] for i in range(n)]", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n return [lst[i::n] for i in range(n)]", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n res = []\n for i in range(n):\n sublist = [lst[x] for x in range(i, len(lst), n)]\n res.append(sublist)\n return res", "matching_cluster_idx": 1}, {"solution": "def list_split(lst, n):\n return [lst[i::n] for i in range(n)]", "matching_cluster_idx": 4}, {"solution": "def list_split(input_list, n):\n list_len = len(input_list)\n output_lists = [ [] for _ in range(n) ]\n for i in range(list_len):\n output_lists[i%n].append(input_list[i])\n return output_lists", "matching_cluster_idx": 4}, {"solution": "def list_split(input_list, n):\n lists = [[] for _ in range(n)]\n for i, value in enumerate(input_list):\n lists[i % n].append(value)\n return lists", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n return [lst[i::n] for i in range(n)]", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n return [lst[i::n] for i in range(n)]", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n return [lst[i::n] for i in range(n)]", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n return [lst[i::n] for i in range(n)]", "matching_cluster_idx": 4}, {"solution": "def list_split(l, n):\n return [l[i::n] for i in range(n)]", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n return [lst[i::n] for i in range(n)]", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n return [lst[i::n] for i in range(n)]", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n return [lst[i::n] for i in range(n)]", "matching_cluster_idx": 4}, {"solution": "def list_split(input_list, n):\n result = []\n for i in range(n):\n result.append(input_list[i::n])\n return result", "matching_cluster_idx": 4}]}, "Mbpp/281": {"dps": 94.0, "dps_norm": 81.81818181818181, "pass@1": 100.0, "profiled": [{"solution": "def all_unique(lst):\n if len(lst) == len(set(lst)):\n return True\n else:\n return False", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n if len(lst) == len(set(lst)):\n return True\n else:\n return False", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n This function checks if the elements in a given list are unique or not.\n :param lst: List of elements\n :return: True if all elements are unique, False otherwise\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n if len(lst) == len(set(lst)):\n return True\n return False", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n Function that checks if all elements in a list are unique\n :param lst: List of elements\n :return: True if all elements are unique, False otherwise\n \"\"\"\n if len(lst) == len(set(lst)):\n return True\n else:\n return False", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n if len(lst) == len(set(lst)):\n return True\n else:\n return False", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n The function checks if the elements in the list are unique.\n\n Parameters:\n lst (list): a list of elements\n\n Returns:\n bool: True if all elements are unique, False otherwise\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n if len(lst) == len(set(lst)):\n return True\n else:\n return False", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n Check if all elements in a list are unique.\n\n Parameters:\n lst (list): a list of elements\n\n Returns:\n bool: True if all elements are unique, False otherwise\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n if len(lst) == len(set(lst)):\n return True\n else:\n return False", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}]}, "Mbpp/296": {"dps": 28.205128205128204, "dps_norm": 66.66666666666667, "pass@1": 100.0, "profiled": [{"solution": "def get_Inv_Count(arr):\n n = len(arr)\n inv_count = 0\n for i in range(n):\n for j in range(i + 1, n):\n if (arr[i] > arr[j]):\n inv_count += 1\n return inv_count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n n = len(arr)\n inv_count = 0\n for i in range(n):\n for j in range(i + 1, n):\n if (arr[i] > arr[j]):\n inv_count += 1\n return inv_count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n n = len(arr)\n inv_count = 0\n for i in range(n):\n for j in range(i + 1, n):\n if (arr[i] > arr[j]):\n inv_count += 1\n return inv_count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n n = len(arr)\n inv_count = 0\n for i in range(n):\n for j in range(i + 1, n):\n if (arr[i] > arr[j]):\n inv_count += 1\n return inv_count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n n = len(arr)\n inv_count = 0\n for i in range(n):\n for j in range(i + 1, n):\n if (arr[i] > arr[j]):\n inv_count += 1\n return inv_count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n n = len(arr)\n inv_count = 0\n for i in range(n):\n for j in range(i + 1, n):\n if (arr[i] > arr[j]):\n inv_count += 1\n return inv_count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n n = len(arr)\n inv_count = 0\n for i in range(n):\n for j in range(i + 1, n):\n if (arr[i] > arr[j]):\n inv_count += 1\n return inv_count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n n = len(arr)\n inv_count = 0\n for i in range(n):\n for j in range(i + 1, n):\n if (arr[i] > arr[j]):\n inv_count += 1\n return inv_count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n inv_count = 0\n n = len(arr)\n for i in range(n):\n for j in range(i + 1, n):\n if (arr[i] > arr[j]):\n inv_count += 1\n return inv_count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n n = len(arr)\n inv_count = 0\n for i in range(n):\n for j in range(i + 1, n):\n if (arr[i] > arr[j]):\n inv_count += 1\n return inv_count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n n = len(arr)\n inv_count = 0\n for i in range(n):\n for j in range(i + 1, n):\n if (arr[i] > arr[j]):\n inv_count += 1\n return inv_count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n n = len(arr)\n inv_count = 0\n for i in range(n):\n for j in range(i + 1, n):\n if (arr[i] > arr[j]):\n inv_count += 1\n return inv_count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n inv_count = 0\n n = len(arr)\n for i in range(n):\n for j in range(i + 1, n):\n if (arr[i] > arr[j]):\n inv_count += 1\n return inv_count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n inv_count = 0\n n = len(arr)\n for i in range(n):\n for j in range(i + 1, n):\n if (arr[i] > arr[j]):\n inv_count += 1\n return inv_count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n n = len(arr)\n inv_count = 0\n for i in range(n):\n for j in range(i + 1, n):\n if (arr[i] > arr[j]):\n inv_count += 1\n return inv_count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n n = len(arr)\n inv_count = 0\n for i in range(n):\n for j in range(i + 1, n):\n if (arr[i] > arr[j]):\n inv_count += 1\n return inv_count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n n = len(arr)\n inv_count = 0\n for i in range(n):\n for j in range(i + 1, n):\n if (arr[i] > arr[j]):\n inv_count += 1\n return inv_count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n n = len(arr)\n inv_count = 0\n for i in range(n):\n for j in range(i + 1, n):\n if (arr[i] > arr[j]):\n inv_count += 1\n return inv_count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n n = len(arr)\n inv_count = 0\n for i in range(n):\n for j in range(i + 1, n):\n if (arr[i] > arr[j]):\n inv_count += 1\n return inv_count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n n = len(arr)\n inv_count = 0\n for i in range(n):\n for j in range(i + 1, n):\n if (arr[i] > arr[j]):\n inv_count += 1\n return inv_count", "matching_cluster_idx": 3}]}, "Mbpp/308": {"dps": 90.96551724137932, "dps_norm": 65.0, "pass@1": 93.0, "profiled": [{"solution": "def large_product(list1, list2, n):\n # Create a list of products for each pair of values from two lists\n products = [a*b for a in list1 for b in list2]\n # Sort the list in descending order and return the first n elements\n return sorted(products, reverse=True)[:n]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n from itertools import product\n from heapq import nlargest\n\n # Compute products for each pair of numbers from both lists\n products = [a * b for a, b in product(list1, list2)]\n\n # Return the n largest products\n return nlargest(n, products)", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n from heapq import nlargest\n from operator import mul\n\n products = [mul(a, b) for a in list1 for b in list2]\n return nlargest(n, products)", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, num):\n # Create a list of products by multiplying each element in list1 with each element in list2\n products = [i*j for i in list1 for j in list2]\n # Sort the list of products in descending order\n products.sort(reverse=True)\n # Return the first 'num' elements from the sorted list of products\n return products[:num]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n # Calculate products\n products = [i*j for i in list1 for j in list2]\n\n # Sort the products in descending order\n products.sort(reverse=True)\n\n # Return the first 'n' products\n return products[:n]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n from itertools import product\n from operator import mul\n from heapq import nlargest\n return nlargest(n, [mul(*pair) for pair in product(list1, list2)])", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n import heapq\n \n # Generate all possible pairs of factors\n pairs = [(i*j, i, j) for i in list1 for j in list2]\n \n # Use a heap to get the n largest products\n return [x[0] for x in heapq.nlargest(n, pairs)]", "matching_cluster_idx": 3}, {"solution": "def large_product(list_a, list_b, k):\n # Generate pairs of products\n products = [(a * b) for a in list_a for b in list_b]\n # Sort the products in descending order\n products.sort(reverse=True)\n # Return the top k largest products\n return products[:k]", "matching_cluster_idx": 3}, {"solution": "def large_product(lst1, lst2, num):\n \"\"\"\n This function returns the specified number of largest products from two given lists.\n \"\"\"\n import heapq\n # Multiply each element in lst1 with each element in lst2 and store results in a heap\n heap = [a * b for a in lst1 for b in lst2]\n # Get the n largest elements from the heap\n return heapq.nlargest(num, heap)", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n products = [a*b for a in list1 for b in list2]\n products.sort(reverse=True)\n return products[:n]", "matching_cluster_idx": 3}, {"solution": "def large_product(lst1, lst2, n):\n from itertools import product\n from heapq import nlargest\n return nlargest(n, (x * y for x, y in product(lst1, lst2)))", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n import heapq\n\n # Make a list of tuples from the two lists\n pairs = [(i, j) for i in list1 for j in list2]\n # Use a heap to find the n largest products\n largest_products = heapq.nlargest(n, pairs, key=lambda x: x[0]*x[1])\n # Return a list of the products themselves\n return [i*j for i, j in largest_products]", "matching_cluster_idx": 2}, {"solution": "import itertools\nimport heapq\ndef large_product(list1, list2, N):\n \"\"\"\n The function returns the N largest products that can be formed from elements\n of two lists.\n \"\"\"\n # get all pairs\n pairs = list(itertools.product(list1, list2))\n \n # get the product of each pair and create a list of tuples (product, pair)\n pair_products = [(pair[0]*pair[1], pair) for pair in pairs]\n \n # use a min-heap with size N to find the N largest products\n largest_N_products = heapq.nlargest(N, pair_products)\n \n return [product[0] for product in largest_N_products]", "matching_cluster_idx": 2}, {"solution": "import itertools\ndef large_product(list1, list2, n):\n # Get all possible product combinations\n product_combinations = [a*b for a,b in itertools.product(list1,list2)]\n # Sort the combinations in descending order\n product_combinations.sort(reverse=True)\n # Return the first 'n' largest combinations\n return product_combinations[:n]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n products = []\n for i in list1:\n for j in list2:\n products.append(i * j)\n products.sort(reverse=True)\n return products[:n]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, count):\n import heapq\n h = []\n for i in list1:\n for j in list2:\n heapq.heappush(h, i*j)\n return sorted(heapq.nlargest(count, h), reverse=True)", "matching_cluster_idx": 3}, {"solution": "def large_product(l1, l2, n):\n import heapq\n l = []\n for i in l1:\n for j in l2:\n l.append(i * j)\n largest = heapq.nlargest(n, l)\n return largest", "matching_cluster_idx": 3}, {"solution": "def large_product(lst1, lst2, num):\n import heapq\n \n products = [-a*b for a in lst1 for b in lst2]\n return [-x for x in heapq.nsmallest(num, products)]", "matching_cluster_idx": 3}, {"solution": "def large_product(lst1, lst2, n):\n # Find all possible products\n products = [x*y for x in lst1 for y in lst2]\n # Sort the products in descending order\n products.sort(reverse=True)\n # Return the first n elements (largest products)\n return products[:n]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, num):\n import heapq\n from itertools import product\n \n prod_list = [-a*b for a, b in product(list1, list2)]\n return [-i for i in heapq.nsmallest(num, prod_list)]", "matching_cluster_idx": 3}]}, "Mbpp/392": {"dps": 96.05633802816901, "dps_norm": 98.84615384615384, "pass@1": 83.0, "profiled": [{"solution": "def get_max_sum(n, dp = {}):\n \"\"\"\n Function to find the maximum sum possible by using the given equation f(n) = max( (f(n/2) + f(n/3) + f(n/4) + f(n/5)), n)\n\n :param n: input number \n :param dp: dictionary to store intermediate results\n :return: maximum sum\n \"\"\"\n if n == 0:\n return 0\n\n if n in dp:\n return dp[n]\n\n dp[n] = max(get_max_sum(n//2) + get_max_sum(n//3) + get_max_sum(n//4) + get_max_sum(n//5), n)\n return dp[n]", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n, memo = {}):\n # If result is already computed, return it\n if n in memo:\n return memo[n]\n \n # Base case\n if n == 0:\n return 0\n \n # Recursive case\n result = max(get_max_sum(n//2) + get_max_sum(n//3) + get_max_sum(n//4) + get_max_sum(n//5), n)\n \n # Memoize the result and return it\n memo[n] = result\n return result", "matching_cluster_idx": 12}, {"solution": "memo = {0: 0, 1: 1}\ndef get_max_sum(n):\n if n not in memo:\n memo[n] = max(n, get_max_sum(n//2) + get_max_sum(n//3) + get_max_sum(n//4) + get_max_sum(n//5))\n return memo[n]", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n, memo={}):\n if n in memo:\n return memo[n]\n if n == 0:\n return 0\n else:\n res = max(get_max_sum(n//2) + get_max_sum(n//3) + get_max_sum(n//4) + get_max_sum(n//5), n)\n memo[n] = res\n return res", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n, memo = {}):\n \"\"\"\n A function to find the maximum sum possible by using the given equation f(n) = max( (f(n/2) + f(n/3) + f(n/4) + f(n/5)), n).\n \"\"\"\n if n in memo:\n return memo[n]\n \n if n == 0:\n return 0\n\n else:\n memo[n] = max(get_max_sum(n//2) + get_max_sum(n//3) + get_max_sum(n//4) + get_max_sum(n//5), n)\n return memo[n]", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n, memo = {}):\n \"\"\"\n Function to calculate the maximum sum possible using the given equation.\n Assumes that n is a positive integer.\n \"\"\"\n if n in memo:\n return memo[n]\n if n == 0:\n return 0\n else:\n memo[n] = max(get_max_sum(n//2) + get_max_sum(n//3) + get_max_sum(n//4) + get_max_sum(n//5), n)\n return memo[n]", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n, memo = {}):\n if n in memo: \n return memo[n]\n if n < 2: \n result = n\n else: \n result = max(sum(get_max_sum(n // div, memo) for div in range(2, 6)), n)\n memo[n] = result\n return result", "matching_cluster_idx": 11}, {"solution": "def get_max_sum(n, memo = {}):\n \"\"\"\n Function to find the maximum sum possible by using the given equation f(n) = max( (f(n/2) + f(n/3) + f(n/4) + f(n/5)), n).\n \"\"\"\n if n == 0:\n return 0\n if n not in memo:\n memo[n] = max(get_max_sum(n//2) + get_max_sum(n//3) + get_max_sum(n//4) + get_max_sum(n//5), n)\n return memo[n]", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n, memo = {}):\n if n == 0:\n return 0\n\n # check if calculated before\n if n not in memo:\n # Calculate max sum\n memo[n] = max(\n get_max_sum(n//2, memo) + get_max_sum(n//3, memo) + get_max_sum(n//4, memo) + get_max_sum(n//5, memo),\n n\n )\n return memo[n]", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n, memo={}):\n \"\"\"Find the maximum sum possible using the given function.\"\"\"\n # If the value is in the memo, use it\n if n in memo:\n return memo[n]\n # if the value is 0, then return 0\n elif n == 0:\n return 0\n # Otherwise, calculate the maximum sum\n else:\n memo[n] = max(get_max_sum(n//2)+get_max_sum(n//3)+get_max_sum(n//4)+get_max_sum(n//5), n)\n return memo[n]", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n, memo = {}):\n if n in memo: return memo[n]\n if n == 0: return 0\n result = max(get_max_sum(n//2) + get_max_sum(n//3) + get_max_sum(n//4) + get_max_sum(n//5), n)\n memo[n] = result\n return result", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n, memo={}):\n # if result is already calculated, return it\n if n in memo:\n return memo[n]\n # base case\n elif n < 2:\n return n\n else:\n # recursive case: calculate result and save to memo\n memo[n] = max(get_max_sum(n//2) + get_max_sum(n//3) + get_max_sum(n//4) + get_max_sum(n//5), n)\n return memo[n]", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n, memo = {}):\n \"\"\"\n This function calculates the maximum sum by applying the given equation.\n It uses memoization for reducing the time complexity by not doing repeated work.\n \"\"\"\n\n # base case\n if n == 0: \n return 0\n\n # check if the result is already calculated\n if n not in memo:\n\n # recursive case\n memo[n] = max(get_max_sum(n//2) + get_max_sum(n//3) + get_max_sum(n//4) + get_max_sum(n//5), n)\n\n # return the stored result\n return memo[n]", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n, memo={}):\n if n in memo:\n return memo[n]\n elif n == 0:\n return 0\n else:\n memo[n] = max(get_max_sum(n // 2) + get_max_sum(n // 3) + get_max_sum(n // 4) + get_max_sum(n // 5), n)\n return memo[n]", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n, memo={0:0, 1:1}):\n \"\"\"\n Function to calculate the maximum sum.\n \"\"\"\n if n not in memo:\n memo[n] = max(get_max_sum(n//2) + get_max_sum(n//3) + get_max_sum(n//4) + get_max_sum(n//5), n)\n return memo[n]", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n, memo={}):\n if n in memo:\n return memo[n]\n if n == 0:\n return 0\n else:\n res = max(get_max_sum(n//2) + get_max_sum(n//3) + get_max_sum(n//4) + get_max_sum(n//5), n)\n memo[n] = res\n return res", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n, dp=None):\n if dp == None:\n dp = [-1 for _ in range(n+1)]\n\n if n <= 0:\n return 0\n if dp[n] != -1:\n return dp[n]\n\n dp[n] = max(get_max_sum(n//2, dp) + get_max_sum(n//3, dp) + get_max_sum(n//4, dp) + get_max_sum(n//5, dp), n)\n return dp[n]", "matching_cluster_idx": 10}, {"solution": "cache = {}\ndef get_max_sum(n):\n \"\"\"\n This function uses a top-down dynamic programming approach with memoization\n to compute the maximum sum as per the equation f(n) = max( (f(n/2) + f(n/3) + f(n/4) + f(n/5)), n)\n \"\"\"\n global cache\n\n # Base case\n if n == 0:\n return 0\n \n # Return the cached result if already computed\n if n in cache:\n return cache[n]\n\n # Recursively compute the max sum\n max_sum = max(get_max_sum(n//2) + get_max_sum(n//3) + get_max_sum(n//4) + get_max_sum(n//5), n)\n\n # Cache the result\n cache[n] = max_sum\n \n return max_sum", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n, cache=None):\n if cache is None: cache = dict()\n if n in cache: return cache[n]\n if n < 2: return n\n cache[n] = max(get_max_sum(n // 2, cache) + get_max_sum(n // 3, cache) + get_max_sum(n // 4, cache) + get_max_sum(n // 5, cache), n)\n return cache[n]", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n, memo={}):\n \"\"\"\n Function to find the maximum sum possible by using the given equation f(n) = max( (f(n/2) + f(n/3) + f(n/4) + f(n/5)), n).\n \"\"\"\n if n in memo: \n return memo[n]\n elif n == 0: \n return 0\n else:\n memo[n] = max(get_max_sum(n//2)+get_max_sum(n//3)+get_max_sum(n//4)+get_max_sum(n//5), n)\n return memo[n]", "matching_cluster_idx": 12}]}, "Mbpp/395": {"dps": 98.08429118773947, "dps_norm": 75.0, "pass@1": 100.0, "profiled": [{"solution": "def first_non_repeating_character(input_string):\n \"\"\"Return the first non-repeating character in a string\"\"\"\n character_frequency = {}\n for character in input_string:\n if character in character_frequency:\n character_frequency[character] += 1\n else:\n character_frequency[character] = 1\n for character in input_string:\n if character_frequency[character] == 1:\n return character\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n # Create a dictionary to store character frequencies\n freq = {}\n for char in s:\n if char in freq:\n freq[char] += 1\n else:\n freq[char] = 1\n \n # Check the characters in the string in order\n for char in s:\n if freq[char] == 1:\n return char\n \n # If no non-repeating character found, return None\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n # Create a dictionary to store the count of each character in the string\n char_count = {}\n \n # Iterate through the string, updating the character count in the dictionary\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n \n # Iterate through the string again, checking if the count of each character in the dictionary is 1\n for char in s:\n if char_count[char] == 1:\n return char\n \n # If no non-repeated characters are found, return None\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(string):\n frequency = {}\n for char in string:\n if char not in frequency:\n frequency[char] = 1\n else:\n frequency[char] += 1\n for char in string:\n if frequency[char] == 1:\n return char\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n frequency = {} \n # Get frequency of each character in string\n for char in s: \n if char in frequency: \n frequency[char] += 1 \n else: \n frequency[char] = 1 \n \n # Loop through string to find first character with frequency 1\n for char in s: \n if frequency[char] == 1: \n return char\n \n # If there is no non-repeating character, return None\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(string):\n char_count = {}\n for char in string:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n\n for char in string:\n if char_count[char] == 1:\n return char\n\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(string):\n # Create a dictionary to keep track of character frequencies\n char_freq = {}\n \n for char in string:\n if char in char_freq:\n char_freq[char] += 1\n else:\n char_freq[char] = 1\n \n # Iterate over string and check if char count in dict is 1\n for char in string:\n if char_freq[char] == 1:\n return char\n \n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n count = {}\n # first, count the frequency of each character\n for ch in s:\n if ch in count:\n count[ch] += 1\n else:\n count[ch] = 1\n # then, check each character in the string if it's the first one that appears only once\n for ch in s:\n if count[ch] == 1:\n return ch\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(input_string):\n character_count = {}\n\n for character in input_string:\n if character in character_count:\n character_count[character] += 1\n else:\n character_count[character] = 1\n\n for character in input_string:\n if character_count[character] == 1:\n return character\n\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n # Create a dictionary to store character frequency\n frequency = {}\n\n for char in s:\n if char not in frequency:\n frequency[char] = 1\n else:\n frequency[char] += 1\n\n for char in s:\n if frequency[char] == 1:\n return char\n\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n char_count = {}\n \n # Count the occurrence of each character\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n \n # Scan string and find first char with count 1\n for char in s:\n if char_count[char] == 1:\n return char\n \n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(string):\n # Using dictionary to hold character counts\n character_counts = {}\n\n # First loop through the string to count character occurrences\n for char in string:\n if char in character_counts:\n character_counts[char] += 1\n else:\n character_counts[char] = 1\n\n # Second loop through the string to find first non-repeating character\n for char in string:\n if character_counts[char] == 1:\n return char\n\n # Return None if no non-repeating characters found\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n char_count = {}\n for char in s:\n if char not in char_count:\n char_count[char] = 1\n else:\n char_count[char] += 1\n for char in s:\n if char_count[char] == 1:\n return char\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(string):\n \"\"\"Return first non-repeated character from given string\"\"\"\n character_count = {}\n\n # counting frequency of each character\n for character in string:\n if character in character_count:\n character_count[character] += 1\n else:\n character_count[character] = 1\n\n # iterating over string to find first character with count 1\n for character in string:\n if character_count[character] == 1:\n return character\n\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n char_counts = {}\n for char in s:\n if char in char_counts:\n char_counts[char] += 1\n else:\n char_counts[char] = 1\n for char in s:\n if char_counts[char] == 1:\n return char\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(string):\n # create a dictionary to store character frequency\n frequency = {}\n\n # count frequency of each character\n for char in string:\n if char in frequency:\n frequency[char] += 1\n else:\n frequency[char] = 1\n\n # find first character with frequency 1\n for char in string:\n if frequency[char] == 1:\n return char\n\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(string):\n char_count = {}\n for char in string:\n if char not in char_count:\n char_count[char] = 1\n else:\n char_count[char] += 1\n for char in string:\n if char_count[char] == 1:\n return char\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n char_count = {}\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n for char in s:\n if char_count[char] == 1:\n return char\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(string):\n char_order = []\n char_count = {}\n\n for char in string:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n char_order.append(char)\n\n for char in char_order:\n if char_count[char] == 1:\n return char\n\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(input_string):\n char_count = {}\n \n for char in input_string:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n \n for char in input_string:\n if char_count[char] == 1:\n return char\n \n return None", "matching_cluster_idx": 5}]}, "Mbpp/405": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def check_tuplex(tuplex, element):\n return element in tuplex", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tup, val):\n return val in tup", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, element):\n return element in tuplex", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, element):\n return element in tuplex", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex,element):\n return element in tuplex", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, element):\n return element in tuplex", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, element):\n return element in tuplex", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(t, x):\n return x in t", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, element):\n return element in tuplex", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, element):\n return element in tuplex", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, element):\n return element in tuplex", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, element):\n return element in tuplex", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, element):\n return element in tuplex", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, item):\n if item in tuplex:\n return True\n return False", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, element):\n return element in tuplex", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(t, x):\n return x in t", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, item):\n return item in tuplex", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, element):\n return element in tuplex", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, element):\n return element in tuplex", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, element):\n return element in tuplex", "matching_cluster_idx": 3}]}, "Mbpp/414": {"dps": 85.24844720496894, "dps_norm": 86.66666666666666, "pass@1": 100.0, "profiled": [{"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Function to check if any value from one sequence exists in another sequence\n \n Inputs: \n seq1: First sequence \n seq2: Second sequence\n \n Returns: \n True if any value from the first sequence exists in the second \n False otherwise\n \"\"\"\n for i in seq1:\n if i in seq2:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Function to check whether any value in sequence1 exists in sequence2\n \"\"\"\n for item in seq1:\n if item in seq2:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n This function checks if any value in the first sequence exists in the second sequence.\n \n Arguments:\n seq1: a sequence like object (list, tuple, set)\n seq2: a sequence like object (list, tuple, set)\n \n Return:\n A boolean value. It's True if seq1 and seq2 have at least one common element, otherwise False.\n \"\"\"\n return not set(seq1).isdisjoint(seq2)", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n for i in seq1:\n if i in seq2:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n for i in seq1:\n if i in seq2:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n for item in seq1:\n if item in seq2:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n for i in seq1:\n if i in seq2:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"Return True if any element in the first sequence exists in the second sequence.\"\"\"\n for elem in seq1:\n if elem in seq2:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"Check if any value in the first sequence exists in the second sequence.\"\"\"\n for val in seq1:\n if val in seq2:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(list1, list2):\n \"\"\"\n Checks if any value in the first list exists in the second list.\n \n Args:\n list1 (list): A list of elements.\n list2 (list): Another list of elements.\n \n Returns:\n bool: Whether any element from list1 exists in list2.\n \"\"\"\n for i in list1:\n if i in list2:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n This function checks if any value in the first sequence exists in the second sequence.\n Returns True if any overlap is found. Otherwise, it returns False.\n \"\"\"\n for item in seq1:\n if item in seq2:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n # Check if any value from seq1 exists in seq2\n return any(val in seq2 for val in seq1)", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n for i in seq1:\n if i in seq2:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Function that checks if any element in the first sequence\n exists in the second sequence\n \"\"\"\n return any(item in seq2 for item in seq1)", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n This function takes two sequences as input and returns True if any value in \n the first sequence exists in the second sequence, else returns False.\n \"\"\"\n for i in seq1:\n if i in seq2:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(sequence1, sequence2):\n for element in sequence1:\n if element in sequence2:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n for i in seq1:\n if i in seq2:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n for i in seq1:\n for j in seq2:\n if i == j:\n return True\n return False", "matching_cluster_idx": 4}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Checks whether any value in the first sequence exists in the second sequence.\n Returns a boolean value accordingly.\n \"\"\"\n for val in seq1:\n if val in seq2:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n return not set(seq1).isdisjoint(set(seq2))", "matching_cluster_idx": 6}]}, "Mbpp/421": {"dps": 15.226337448559672, "dps_norm": 71.42857142857143, "pass@1": 100.0, "profiled": [{"solution": "def concatenate_tuple(t):\n return '-'.join(str(e) for e in t)", "matching_cluster_idx": 4}, {"solution": "def concatenate_tuple(t):\n return '-'.join(str(x) for x in t)", "matching_cluster_idx": 4}, {"solution": "def concatenate_tuple(t):\n return '-'.join(str(x) for x in t)", "matching_cluster_idx": 4}, {"solution": "def concatenate_tuple(tup, delimiter='-'):\n return delimiter.join(str(x) for x in tup)", "matching_cluster_idx": 4}, {"solution": "def concatenate_tuple(t, delimiter='-'):\n \"\"\"\n Concatenate each element of a tuple by a specified delimiter\n \n :param t: Input tuple\n :param delimiter: Delimiter to join the elements\n :return: String concatenated with the specified delimiter\n \"\"\"\n return delimiter.join(str(i) for i in t)", "matching_cluster_idx": 4}, {"solution": "def concatenate_tuple(my_tuple, delimiter='-'):\n return delimiter.join(str(element) for element in my_tuple)", "matching_cluster_idx": 4}, {"solution": "def concatenate_tuple(t):\n return '-'.join(str(x) for x in t)", "matching_cluster_idx": 4}, {"solution": "def concatenate_tuple(t):\n return '-'.join(str(x) for x in t)", "matching_cluster_idx": 4}, {"solution": "def concatenate_tuple(t, delimiter='-'):\n return delimiter.join(str(x) for x in t)", "matching_cluster_idx": 4}, {"solution": "def concatenate_tuple(t, delimiter='-'):\n return delimiter.join(str(i) for i in t)", "matching_cluster_idx": 4}, {"solution": "def concatenate_tuple(t, delimiter='-'):\n return delimiter.join(str(i) for i in t)", "matching_cluster_idx": 4}, {"solution": "def concatenate_tuple(input_tuple):\n \"\"\"\n A function to concatenate each element of a tuple by the delimiter.\n \"\"\"\n return '-'.join(str(element) for element in input_tuple)", "matching_cluster_idx": 4}, {"solution": "def concatenate_tuple(tup, delimiter='-'):\n return delimiter.join(str(item) for item in tup)", "matching_cluster_idx": 4}, {"solution": "def concatenate_tuple(t, delimiter=\"-\"):\n return delimiter.join(str(x) for x in t)", "matching_cluster_idx": 4}, {"solution": "def concatenate_tuple(t, delimiter='-'):\n return delimiter.join(str(i) for i in t)", "matching_cluster_idx": 4}, {"solution": "def concatenate_tuple(input_tuple, delimiter=\"-\"):\n return delimiter.join(str(i) for i in input_tuple)", "matching_cluster_idx": 4}, {"solution": "def concatenate_tuple(t):\n \"\"\" \n This function takes a tuple and concatenate each element by the delimiter.\n \n Arguments:\n t {tuple} -- input tuple\n \n Returns:\n str -- concatenated string\n \"\"\"\n return '-'.join(str(e) for e in t)", "matching_cluster_idx": 4}, {"solution": "def concatenate_tuple(t, delimiter=\"-\"):\n return delimiter.join(str(i) for i in t)", "matching_cluster_idx": 4}, {"solution": "def concatenate_tuple(t, delimiter='-'):\n return delimiter.join(str(x) for x in t)", "matching_cluster_idx": 4}, {"solution": "def concatenate_tuple(tup, delimiter='-'):\n return delimiter.join(str(elem) for elem in tup)", "matching_cluster_idx": 4}]}, "Mbpp/424": {"dps": 63.71841155234657, "dps_norm": 85.0, "pass@1": 100.0, "profiled": [{"solution": "def extract_rear(strings):\n return [s[-1] for s in strings]", "matching_cluster_idx": 3}, {"solution": "def extract_rear(input_tuple):\n return [s[-1] for s in input_tuple]", "matching_cluster_idx": 3}, {"solution": "def extract_rear(input_tuple):\n output_list = [s[-1] for s in input_tuple]\n return output_list", "matching_cluster_idx": 3}, {"solution": "def extract_rear(input_tuple):\n return [s[-1] for s in input_tuple]", "matching_cluster_idx": 3}, {"solution": "def extract_rear(input_tuple):\n output_list = [s[-1] for s in input_tuple]\n return output_list", "matching_cluster_idx": 3}, {"solution": "def extract_rear(tup):\n return [s[-1] for s in tup]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(tup):\n return [s[-1] for s in tup]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(t):\n return [s[-1] for s in t]", "matching_cluster_idx": 3}, {"solution": "def extract_rear(t):\n return [s[-1] for s in t]", "matching_cluster_idx": 3}, {"solution": "def extract_rear(tuple_of_strings):\n return [s[-1] for s in tuple_of_strings]", "matching_cluster_idx": 3}, {"solution": "def extract_rear(input_tuple):\n return [s[-1] for s in input_tuple]", "matching_cluster_idx": 3}, {"solution": "def extract_rear(strings):\n return [s[-1] for s in strings]", "matching_cluster_idx": 3}, {"solution": "def extract_rear(tuple_str):\n return [s[-1] for s in tuple_str]", "matching_cluster_idx": 3}, {"solution": "def extract_rear(words):\n return [word[-1] for word in words]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(input_tuple):\n return [s[-1] for s in input_tuple]", "matching_cluster_idx": 3}, {"solution": "def extract_rear(t):\n return [s[-1] for s in t]", "matching_cluster_idx": 3}, {"solution": "def extract_rear(input_tuple):\n return [s[-1] for s in input_tuple]", "matching_cluster_idx": 3}, {"solution": "def extract_rear(input_tuple):\n \"\"\"\n This function extracts and returns a list of the last character of each string in the given tuple.\n \n :param input_tuple: tuple of strings\n :return: list of last characters of the strings in the input_tuple\n \"\"\"\n return [s[-1] for s in input_tuple]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(t):\n return [s[-1] for s in t]", "matching_cluster_idx": 3}, {"solution": "def extract_rear(input_tuple):\n return [string[-1] for string in input_tuple]", "matching_cluster_idx": 4}]}, "Mbpp/425": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 86.0, "profiled": [{"solution": "def count_element_in_list(lst, elem):\n count = 0\n for sublist in lst:\n if elem in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, ele):\n count = 0\n for sublist in lst:\n if ele in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(sublists, element):\n count = 0\n for sublist in sublists:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(sublists, element):\n count = 0\n for sublist in sublists:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(main_list,element):\n count = 0\n for sub_list in main_list:\n if element in sub_list:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(list_of_lists, element):\n count = 0\n for sublist in list_of_lists:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(sublists, element):\n count = 0\n for sublist in sublists:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(sublists, element):\n return sum(1 for sublist in sublists if element in sublist)", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(sublists, target):\n count = 0\n for sublist in sublists:\n if target in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(sublists, element):\n count = 0\n for sublist in sublists:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(sublists, target):\n count = 0\n for sublist in sublists:\n if target in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(sublists, element):\n count = 0\n for sublist in sublists:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(main_list, element):\n count = 0\n for sublist in main_list:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(sublists, element):\n count = 0\n for sublist in sublists:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(sublists, target):\n count = 0\n for sublist in sublists:\n if target in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(sublists, element):\n count = 0\n for sublist in sublists:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, el):\n count = 0\n for sublist in lst:\n if el in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(sublists, element):\n count = 0\n for sublist in sublists:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(input_list, element):\n count = 0\n for sublist in input_list:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(sublists, element):\n return sum(element in sublist for sublist in sublists)", "matching_cluster_idx": 4}]}, "Mbpp/428": {"dps": 81.36363636363636, "dps_norm": 55.0, "pass@1": 100.0, "profiled": [{"solution": "def shell_sort(arr):\n gap = len(arr) // 2\n \n while gap > 0:\n for i in range(gap, len(arr)):\n temp = arr[i]\n j = i\n \n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n \n arr[j] = temp\n gap //= 2\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2\n\n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n\n arr[j] = temp\n gap //= 2\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n gap = len(arr) // 2\n while gap > 0:\n for i in range(gap, len(arr)):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2\n \n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(input_list):\n gap = len(input_list) // 2\n while gap > 0:\n for i in range(gap, len(input_list)):\n temp = input_list[i]\n j = i\n while j >= gap and input_list[j - gap] > temp:\n input_list[j] = input_list[j - gap]\n j -= gap\n input_list[j] = temp\n gap //= 2\n return input_list", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n gap = len(arr) // 2\n while gap > 0:\n for i in range(gap, len(arr)):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n gap = len(arr) // 2\n\n while gap > 0:\n for i in range(gap, len(arr)):\n temp = arr[i]\n j = i\n\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n \n arr[j] = temp\n \n gap //= 2\n \n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(array):\n gap = len(array) // 2\n\n while gap > 0:\n for i in range(gap, len(array)):\n temp = array[i]\n j = i\n\n while j >= gap and array[j - gap] > temp:\n array[j] = array[j - gap]\n j -= gap\n array[j] = temp\n gap = gap // 2\n return array", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2\n\n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2\n\n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(array):\n n = len(array)\n gap = n//2\n while gap > 0:\n for i in range(gap,n):\n temp = array[i]\n j = i\n while j >= gap and array[j-gap] >temp:\n array[j] = array[j-gap]\n j -= gap\n array[j] = temp\n gap //= 2\n return array", "matching_cluster_idx": 3}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n//2\n\n while gap > 0:\n for i in range(gap,n):\n temp = arr[i]\n j = i\n while j >= gap and arr[j-gap] >temp:\n arr[j] = arr[j-gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n//2\n \n while gap > 0:\n for i in range(gap,n):\n temp = arr[i]\n j = i\n while j >= gap and arr[j-gap] >temp:\n arr[j] = arr[j-gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n \n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(array):\n n = len(array)\n gap = n // 2\n\n while gap > 0:\n for i in range(gap, n):\n temp = array[i]\n j = i\n\n while j >= gap and array[j - gap] > temp:\n array[j] = array[j - gap]\n j -= gap\n\n array[j] = temp\n gap //= 2\n\n return array", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n gap = len(arr) // 2\n while gap > 0:\n for i in range(gap, len(arr)):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n gap = len(arr) // 2\n while gap > 0:\n for i in range(gap, len(arr)):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n gap = len(arr) // 2\n while gap > 0:\n for i in range(gap, len(arr)):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(input_list):\n gap = len(input_list) // 2\n while gap > 0:\n for i in range(gap, len(input_list)):\n temp = input_list[i]\n j = i\n while j >= gap and input_list[j - gap] > temp:\n input_list[j] = input_list[j - gap]\n j = j-gap\n input_list[j] = temp\n gap = gap // 2\n return input_list", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n//2\n while gap > 0:\n for i in range(gap,n):\n temp = arr[i]\n j = i\n while j >= gap and arr[j-gap] >temp:\n arr[j] = arr[j-gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n # Start with a big gap, then reduce the gap\n n = len(arr)\n gap = n//2\n \n # Do a gapped insertion sort for this gap size.\n # The first gap elements a[0..gap-1] are already in gapped order \n # keep adding one more element until the entire array is gap sorted\n while gap > 0:\n \n # Add a[gap...n] elements to the elements that have been gap sorted\n for i in range(gap,n):\n \n # add a[i] to the elements that have been gap sorted\n temp = arr[i]\n \n # shift earlier gap-sorted elements up until the correct\n # location for a[i] is found\n j = i\n while j >= gap and arr[j-gap] >temp:\n arr[j] = arr[j-gap]\n j -= gap\n \n # put temp (the original a[i]) in its correct location\n arr[j] = temp\n gap //= 2\n return arr", "matching_cluster_idx": 4}]}, "Mbpp/433": {"dps": 69.46808510638297, "dps_norm": 70.0, "pass@1": 26.0, "profiled": [{"solution": "def check_greater(arr, num):\n \"\"\"\n This function checks if all elements in a list are smaller than a number.\n\n Args:\n arr (list): a list of integers\n num (int): a number\n\n Returns:\n bool: True if all elements in arr are smaller than num, False otherwise\n \"\"\"\n return all(i < num for i in arr)", "matching_cluster_idx": 2}, {"solution": "def check_greater(arr, num):\n \"\"\"Return True if all elements in the array are smaller than num, else False.\"\"\"\n for i in arr:\n if i >= num:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def check_greater(array, number):\n return all(x < number for x in array)", "matching_cluster_idx": 2}, {"solution": "def check_greater(arr, num):\n \"\"\"\n This function checks if the given number is greater than all elements in a given list.\n \n :param arr: List of integers\n :param num: An integer\n :return: Boolean (True if num > all elements in arr, False otherwise)\n \"\"\"\n for i in arr:\n if i >= num:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def check_greater(array, number):\n \"\"\"Return True if all elements in array are less than number.\"\"\"\n for i in array:\n if i >= number:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def check_greater(arr, num):\n # return False if all elements in the array are less than num\n return all(i < num for i in arr)", "matching_cluster_idx": 2}, {"solution": "def check_greater(arr, num):\n \"\"\"\n This function checks if the entered number is greater than the elements of a given array.\n It returns True if the number is greater than all elements of the array, otherwise False.\n \"\"\"\n for element in arr:\n if num <= element:\n return False\n return True", "matching_cluster_idx": 3}, {"solution": "def check_greater(arr, num):\n return all(i < num for i in arr)", "matching_cluster_idx": 2}, {"solution": "def check_greater(arr, num):\n for element in arr:\n if num <= element:\n return False\n return True", "matching_cluster_idx": 3}, {"solution": "def check_greater(arr, num):\n return all(i < num for i in arr)", "matching_cluster_idx": 2}, {"solution": "def check_greater(arr, num):\n return all(i < num for i in arr)", "matching_cluster_idx": 2}, {"solution": "def check_greater(arr, num):\n return all(i < num for i in arr)", "matching_cluster_idx": 2}, {"solution": "def check_greater(arr, num):\n return all(i < num for i in arr)", "matching_cluster_idx": 2}, {"solution": "def check_greater(arr, num):\n return all(i < num for i in arr)", "matching_cluster_idx": 2}, {"solution": "def check_greater(array, number):\n \"\"\"\n Checks if the entered number is greater than all elements in the array.\n\n Parameters:\n array (list): A list of integers.\n number (int): A single integer.\n\n Returns:\n bool: True if the number is greater than all elements in the array, False otherwise.\n \"\"\"\n return all(number > i for i in array)", "matching_cluster_idx": 2}, {"solution": "def check_greater(array, num):\n return all(i < num for i in array)", "matching_cluster_idx": 2}, {"solution": "def check_greater(arr, num):\n for element in arr:\n if num <= element:\n return False\n return True", "matching_cluster_idx": 3}, {"solution": "def check_greater(arr, num):\n return all(i < num for i in arr)", "matching_cluster_idx": 2}, {"solution": "def check_greater(array, num):\n for element in array:\n if num <= element:\n return False\n return True", "matching_cluster_idx": 3}, {"solution": "def check_greater(array, num):\n \"\"\"\n This function checks whether all elements in the given array are less than a specific number.\n\n :param array: a list of integers.\n :param num: an integer.\n :returns: True if all elements in the array are less than num, False otherwise.\n \"\"\"\n return all(i < num for i in array)", "matching_cluster_idx": 2}]}, "Mbpp/437": {"dps": 68.6029411764706, "dps_norm": 22.0, "pass@1": 56.0, "profiled": [{"solution": "def remove_odd(string):\n return ''.join([string[i] for i in range(len(string)) if i%2==1])", "matching_cluster_idx": 1}, {"solution": "def remove_odd(s):\n return ''.join([s[i] for i in range(len(s)) if (i+1)%2==0])", "matching_cluster_idx": 0}, {"solution": "def remove_odd(string):\n return ''.join([char for index, char in enumerate(string) if (index+1) % 2 == 0])", "matching_cluster_idx": 0}, {"solution": "def remove_odd(s):\n return ''.join([s[i] for i in range(len(s)) if (i+1)%2 == 0])", "matching_cluster_idx": 0}, {"solution": "def remove_odd(s):\n return ''.join([s[i] for i in range(len(s)) if (i+1)%2==0])", "matching_cluster_idx": 0}, {"solution": "def remove_odd(s):\n return \"\".join([s[i] for i in range(len(s)) if (i+1) % 2 == 0])", "matching_cluster_idx": 0}, {"solution": "def remove_odd(s):\n return \"\".join(c for i, c in enumerate(s) if (i+1) % 2 == 0)", "matching_cluster_idx": 0}, {"solution": "def remove_odd(input_string):\n output_string = \"\"\n for i in range(len(input_string)):\n if (i+1) % 2 == 0: # Even index (Python uses 0-based indexing)\n output_string += input_string[i]\n return output_string", "matching_cluster_idx": -1}, {"solution": "def remove_odd(input_string):\n return ''.join([input_string[i] for i in range(len(input_string)) if i % 2 == 1])", "matching_cluster_idx": 1}, {"solution": "def remove_odd(string):\n return ''.join([char for index, char in enumerate(string) if (index + 1) % 2 == 0])", "matching_cluster_idx": 0}, {"solution": "def remove_odd(s):\n return ''.join([s[i] for i in range(len(s)) if (i+1)%2==0])", "matching_cluster_idx": 0}, {"solution": "def remove_odd(s):\n return ''.join([s[i] for i in range(len(s)) if (i+1) % 2 == 0])", "matching_cluster_idx": 0}, {"solution": "def remove_odd(s):\n return ''.join(s[i] for i in range(len(s)) if i%2==1)", "matching_cluster_idx": 0}, {"solution": "def remove_odd(s):\n return \"\".join([s[i] for i in range(len(s)) if i % 2 == 1])", "matching_cluster_idx": 1}, {"solution": "def remove_odd(input_string):\n return ''.join([input_string[i] for i in range(len(input_string)) if (i+1) % 2 == 0])", "matching_cluster_idx": 0}, {"solution": "def remove_odd(s):\n # Using list comprehension to remove odd characters\n return ''.join([s[i] for i in range(len(s)) if (i+1)%2==0])", "matching_cluster_idx": 0}, {"solution": "def remove_odd(string):\n return ''.join([char for index, char in enumerate(string) if (index + 1) % 2 == 0])", "matching_cluster_idx": 0}, {"solution": "def remove_odd(input_str):\n return ''.join([input_str[i] for i in range(len(input_str)) if (i+1)%2==0])", "matching_cluster_idx": 0}, {"solution": "def remove_odd(input_string):\n return ''.join([input_string[i] for i in range(len(input_string)) if (i+1)%2 == 0])", "matching_cluster_idx": 0}, {"solution": "def remove_odd(input_string):\n \"\"\"\n Function to remove odd characters in a string.\n \"\"\"\n return ''.join([input_string[i] for i in range(len(input_string)) if (i+1)%2 == 0])", "matching_cluster_idx": 0}]}, "Mbpp/440": {"dps": null, "dps_norm": null, "pass@1": 0.0, "profiled": []}, "Mbpp/446": {"dps": null, "dps_norm": null, "pass@1": 9.0, "profiled": []}, "Mbpp/451": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 99.0, "profiled": [{"solution": "def remove_whitespaces(input_string):\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(s):\n return s.replace(' ', '')", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_str):\n return input_str.replace(' ', '')", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string):\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string):\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(s):\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_str):\n return input_str.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(s):\n return s.replace(' ', '')", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(s):\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string):\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(s):\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(string):\n return string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string):\n return input_string.replace(' ', '')", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(s):\n return s.replace(' ', '')", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string):\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(s):\n return s.replace(' ', '')", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string):\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string):\n return input_string.replace(' ', '')", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(s):\n return s.replace(' ', '')", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string):\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}]}, "Mbpp/456": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def reverse_string_list(lst):\n return [s[::-1] for s in lst]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(lst):\n return [s[::-1] for s in lst]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(lst):\n return [s[::-1] for s in lst]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(lst):\n return [s[::-1] for s in lst]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(input_list):\n reversed_list = [s[::-1] for s in input_list]\n return reversed_list", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(lst):\n return [s[::-1] for s in lst]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(input_list):\n return [s[::-1] for s in input_list]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(list_of_strings):\n return [s[::-1] for s in list_of_strings]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(list_of_strings):\n return [s[::-1] for s in list_of_strings]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(input_list):\n return [x[::-1] for x in input_list]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(lst):\n return [s[::-1] for s in lst]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(str_list):\n return [s[::-1] for s in str_list]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(lst):\n return [s[::-1] for s in lst]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(input_list):\n # Function to reverse a string\n def reverse_string(input_string):\n return input_string[::-1]\n\n # Apply the reverse_string function to each item in the list\n return [reverse_string(item) for item in input_list]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(lst):\n return [s[::-1] for s in lst]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(str_list):\n return [s[::-1] for s in str_list]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(list_of_strings):\n \"\"\"Reverse each string in a given list of string values.\"\"\"\n return [s[::-1] for s in list_of_strings]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(lst):\n return [s[::-1] for s in lst]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(lst):\n return [i[::-1] for i in lst]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(lst):\n return [s[::-1] for s in lst]", "matching_cluster_idx": 4}]}, "Mbpp/460": {"dps": 97.40384615384616, "dps_norm": 99.0, "pass@1": 100.0, "profiled": [{"solution": "def Extract(lst):\n return [sublist[0] for sublist in lst]", "matching_cluster_idx": 4}, {"solution": "def Extract(lists):\n return [sub[0] for sub in lists]", "matching_cluster_idx": 4}, {"solution": "def Extract(lst):\n return [sub_lst[0] for sub_lst in lst]", "matching_cluster_idx": 4}, {"solution": "def Extract(sublists):\n return [sublist[0] for sublist in sublists]", "matching_cluster_idx": 4}, {"solution": "def Extract(list_of_lists):\n return [sub_list[0] for sub_list in list_of_lists]", "matching_cluster_idx": 4}, {"solution": "def Extract(lst):\n return [sub[0] for sub in lst]", "matching_cluster_idx": 4}, {"solution": "def Extract(input_list):\n output_list = [sublist[0] for sublist in input_list]\n return output_list", "matching_cluster_idx": 4}, {"solution": "def Extract(lst):\n result = [sub_lst[0] for sub_lst in lst]\n return result", "matching_cluster_idx": 4}, {"solution": "def Extract(lst):\n return [sub_list[0] for sub_list in lst]", "matching_cluster_idx": 4}, {"solution": "def Extract(my_list):\n return [sublist[0] for sublist in my_list]", "matching_cluster_idx": 3}, {"solution": "def Extract(lst):\n return [sublist[0] for sublist in lst]", "matching_cluster_idx": 4}, {"solution": "def Extract(sublists):\n \"\"\"\n This function takes a list of sublists as input. It returns a new list that contains the first\n element from each sublist.\n \n Parameters:\n sublists (list of lists): The list containing sublists.\n \n Returns:\n list: A new list that contains the first element of each sublist.\n \n Example:\n Extract([[1, 2], [3, 4, 5], [6, 7, 8, 9]]) returns [1, 3, 6]\n \"\"\"\n return [sublist[0] for sublist in sublists]", "matching_cluster_idx": 4}, {"solution": "def Extract(input_list):\n output_list = [sublist[0] for sublist in input_list]\n return output_list", "matching_cluster_idx": 4}, {"solution": "def Extract(lst):\n return [sub_lst[0] for sub_lst in lst]", "matching_cluster_idx": 4}, {"solution": "def Extract(lst):\n return [sublist[0] for sublist in lst]", "matching_cluster_idx": 4}, {"solution": "def Extract(l):\n return [x[0] for x in l]", "matching_cluster_idx": 4}, {"solution": "def Extract(lst):\n return [sub_lst[0] for sub_lst in lst]", "matching_cluster_idx": 4}, {"solution": "def Extract(lst):\n return [sub_lst[0] for sub_lst in lst]", "matching_cluster_idx": 4}, {"solution": "def Extract(sublists):\n return [sublist[0] for sublist in sublists]", "matching_cluster_idx": 4}, {"solution": "def Extract(lst):\n return [sublist[0] for sublist in lst]", "matching_cluster_idx": 4}]}, "Mbpp/474": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def replace_char(input_string, char_to_replace, replacement_char):\n return input_string.replace(char_to_replace, replacement_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(input_string, old_char, new_char):\n \"\"\"\n This function takes three parameters, a string and two characters.\n It replaces all occurrences of the old character in the string with the new character.\n \"\"\"\n return input_string.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, old, new):\n return s.replace(old, new)", "matching_cluster_idx": 6}, {"solution": "def replace_char(input_str, old_char, new_char):\n \"\"\"\n Replaces all occurrences of a specified character in a string with another specified character.\n\n Args:\n input_str (str): The original string.\n old_char (str): The character to replace.\n new_char (str): The new character to replace the old character.\n\n Returns:\n The modified string with characters replaced.\n \"\"\"\n\n return input_str.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(input_str, old_char, new_char):\n return input_str.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(input_string, char_to_replace, new_char):\n return input_string.replace(char_to_replace, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, old, new):\n return s.replace(old, new)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, char_to_replace, replacement_char):\n return s.replace(char_to_replace, replacement_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, old, new):\n return s.replace(old, new)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, old, new):\n return s.replace(old, new)", "matching_cluster_idx": 6}, {"solution": "def replace_char(input_string, char_to_replace, replacement_char):\n return input_string.replace(char_to_replace, replacement_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(string, old_char, new_char):\n return string.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(input_string, old_char, new_char):\n return input_string.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, old, new):\n return s.replace(old, new)", "matching_cluster_idx": 6}, {"solution": "def replace_char(string, old_char, new_char):\n return string.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(input_str, old_char, new_char):\n return input_str.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, old, new):\n return s.replace(old, new)", "matching_cluster_idx": 6}, {"solution": "def replace_char(input_str, old_char, new_char):\n return input_str.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, old, new):\n return s.replace(old, new)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, char_to_replace, replacement_char):\n return s.replace(char_to_replace, replacement_char)", "matching_cluster_idx": 6}]}, "Mbpp/476": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def big_sum(arr):\n return min(arr) + max(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n return max(arr) + min(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(num_list):\n return min(num_list) + max(num_list)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n return min(arr) + max(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n return min(arr) + max(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n return min(arr) + max(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(array):\n \"\"\"\n The function takes an array as input and returns the sum\n of the largest and smallest values in the array.\n \"\"\"\n if len(array) < 1:\n raise ValueError(\"Input array should not be empty.\")\n return min(array) + max(array)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n return min(arr) + max(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n # If array is empty\n if not arr:\n return 0\n\n # If array has only one element\n if len(arr) == 1:\n return 2 * arr[0]\n\n min_val = min(arr)\n max_val = max(arr)\n return min_val + max_val", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n return max(arr) + min(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(nums):\n \"\"\"\n This function finds the sum of the largest and smallest value in a given array.\n \n Args:\n nums (list): list of integers\n \n Returns:\n int: sum of smallest and largest numbers in the list\n \"\"\"\n \n if len(nums) == 0: # if the list is empty, return 0\n return 0\n \n return min(nums) + max(nums)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n \"\"\"Returns the sum of the largest and smallest value in a given list.\"\"\"\n return min(arr) + max(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(num_list):\n return min(num_list) + max(num_list)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n return min(arr) + max(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n if len(arr) == 0:\n return 0\n max_val = max(arr)\n min_val = min(arr)\n return max_val + min_val", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n \"\"\"\n Function to find the sum of the largest and smallest value in a given array\n \"\"\"\n \n # Check if the list is not empty\n assert len(arr) > 0, \"List cannot be empty\"\n \n # Return the sum of the largest and smallest value in the list\n return min(arr) + max(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n return max(arr) + min(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n return max(arr) + min(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(lst):\n return max(lst) + min(lst)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n return min(arr) + max(arr)", "matching_cluster_idx": 5}]}, "Mbpp/477": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def is_lower(s):\n \"\"\"Convert the given string to lower case.\n \n Args:\n s (str): the string to convert\n\n Returns:\n str: the string converted to lower case\n \"\"\"\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n \"\"\"\n This function converts the given string to lower case.\n \"\"\"\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(input_str):\n return input_str.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(input_string):\n return input_string.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n \"\"\"\n This function takes a string as input and returns the string in lower case.\n \"\"\"\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(input_string):\n return input_string.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(input_str):\n return input_str.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n \"\"\"\n Convert the given string to lower case.\n \"\"\"\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(str):\n return str.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(input_string):\n return input_string.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n \"\"\"\n Convert a given string to lower case.\n \"\"\"\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(input_string):\n \"\"\"\n This function will convert the given string to lower case.\n \"\"\"\n try:\n return input_string.lower()\n except AttributeError:\n raise ValueError(\"The input value is not a string\")", "matching_cluster_idx": 4}, {"solution": "def is_lower(input_str):\n return input_str.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(string):\n return string.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n \"\"\"\n This function converts a given string to lower case.\n It uses Python's lower() method which converts all uppercase characters in a string into lowercase characters and returns it.\n \"\"\"\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(input_str):\n return input_str.lower()", "matching_cluster_idx": 4}]}, "Mbpp/563": {"dps": 80.32786885245902, "dps_norm": 80.0, "pass@1": 25.0, "profiled": [{"solution": "import re\ndef extract_values(s):\n pattern = r'\"([^\"]*)\"'\n matches = re.findall(pattern, s)\n return matches", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(input_string):\n return re.findall(r'\"(.*?)\"', input_string)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(input_str):\n return re.findall(r'\"([^\"]*)\"', input_str)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(input_string):\n return re.findall(r'\"([^\"]*)\"', input_string)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(s):\n pattern = r'\"(.*?)\"'\n return re.findall(pattern, s)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(string):\n return re.findall(r'\"([^\"]*)\"', string)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(string):\n return re.findall(r'\"([^\"]*)\"', string)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(str_input):\n pattern = r'\"([^\"]*)\"'\n matches = re.findall(pattern, str_input)\n return matches", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(string):\n return re.findall(r'\"([^\"]*)\"', string)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(s):\n return re.findall(r'\"([^\"]*)\"', s)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(input_string):\n pattern = '\"([^\"]*)\"'\n matches = re.findall(pattern, input_string)\n return matches", "matching_cluster_idx": 8}, {"solution": "def extract_values(s):\n # initialize an empty list to store the extracted values\n values = []\n \n # initialize an empty string to accumulate characters within quotes\n accumulator = ''\n\n # initialize a flag to track whether we are currently within quotes\n within_quotes = False\n\n for char in s:\n if char == '\"':\n # toggle whether we are within quotes\n within_quotes = not within_quotes\n if within_quotes:\n # start of a value, clear the accumulator\n accumulator = ''\n else:\n # end of a value, append it to the list and reset the accumulator\n values.append(accumulator)\n \n elif within_quotes:\n # accumulate characters when within quotes\n accumulator += char\n\n return values", "matching_cluster_idx": 6}, {"solution": "import re\ndef extract_values(s):\n return re.findall(r'\"([^\"]*)\"', s)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(s):\n return re.findall(r'\"([^\"]*)\"', s)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(str_with_quotes):\n pattern = r'\"(.*?)\"'\n matches = re.findall(pattern, str_with_quotes)\n return matches", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(input_string):\n pattern = '\"([^\"]*)\"'\n match = re.findall(pattern, input_string)\n return match", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(input_str):\n pattern = r'\"([^\"]*)\"'\n return re.findall(pattern, input_str)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(input_string):\n # Regular expression to match values within quotes\n regex = r'\"([^\"]*)\"'\n \n # re.findall function returns all non-overlapping matches of pattern in string, as a list of strings\n # The string is scanned left-to-right, and matches are returned in the order found\n return re.findall(regex, input_string)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(input_str):\n return re.findall(r'\"(.*?)\"', input_str)", "matching_cluster_idx": 8}, {"solution": "def extract_values(s):\n values = []\n in_quotes = False\n current_word = ''\n for character in s:\n if character == '\"':\n in_quotes = not in_quotes\n if in_quotes is False:\n values.append(current_word)\n current_word = ''\n elif in_quotes:\n current_word += character\n return values", "matching_cluster_idx": 6}]}, "Mbpp/572": {"dps": null, "dps_norm": null, "pass@1": 5.0, "profiled": []}, "Mbpp/578": {"dps": 92.98412698412699, "dps_norm": 71.81818181818183, "pass@1": 100.0, "profiled": [{"solution": "def interleave_lists(list1, list2, list3):\n return [val for pair in zip(list1, list2, list3) for val in pair]", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(list1, list2, list3):\n return [item for sublist in zip(list1, list2, list3) for item in sublist]", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(l1, l2, l3):\n return [item for sublist in zip(l1, l2, l3) for item in sublist]", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(list1, list2, list3):\n return [item for sublist in zip(list1, list2, list3) for item in sublist]", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(l1, l2, l3):\n return [item for sublist in zip(l1, l2, l3) for item in sublist]", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(list1, list2, list3):\n return [item for sublist in zip(list1, list2, list3) for item in sublist]", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(list1, list2, list3):\n interleaved_list = [item for sublist in zip(list1, list2, list3) for item in sublist]\n return interleaved_list", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(list1, list2, list3):\n return [item for sublist in zip(list1, list2, list3) for item in sublist]", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(l1, l2, l3):\n return [val for tup in zip(l1, l2, l3) for val in tup]", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(list1, list2, list3):\n return [item for sublist in zip(list1, list2, list3) for item in sublist]", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(list1, list2, list3):\n interleave_list = []\n for i in range(len(list1)):\n interleave_list.append(list1[i])\n interleave_list.append(list2[i])\n interleave_list.append(list3[i])\n return interleave_list", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n # Zip function is used to combine lists of same length\n # List comprehension is used to flatten into single list\n return [item for sublist in zip(list1, list2, list3) for item in sublist]", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(l1, l2, l3):\n return [item for sublist in zip(l1, l2, l3) for item in sublist]", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(list1, list2, list3):\n return [val for pair in zip(list1, list2, list3) for val in pair]", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(l1, l2, l3):\n return [x for t in zip(l1, l2, l3) for x in t]", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(list1, list2, list3):\n assert len(list1) == len(list2) == len(list3), \"All lists should be of the same length\"\n return [item for sublist in zip(list1, list2, list3) for item in sublist]\nlist1 = [1,2,3,4,5,6,7]\nlist2 = [10,20,30,40,50,60,70]\nlist3 = [100,200,300,400,500,600,700]", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(lst1, lst2, lst3):\n interleaved_lst = [item for sublist in zip(lst1, lst2, lst3) for item in sublist]\n return interleaved_lst", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(list1, list2, list3):\n result = []\n for i in range(len(list1)):\n result.append(list1[i])\n result.append(list2[i])\n result.append(list3[i])\n return result", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n return [element for tup in zip(list1, list2, list3) for element in tup]", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(list1, list2, list3):\n return [val for pair in zip(list1, list2, list3) for val in pair]", "matching_cluster_idx": 7}]}, "Mbpp/586": {"dps": 98.83040935672514, "dps_norm": 87.5, "pass@1": 100.0, "profiled": [{"solution": "def split_Arr(lst,n):\n return lst[n:] + lst[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr,n):\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr,n):\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(input_list, split_index):\n if split_index > len(input_list):\n return \"Error: Split index larger than list length.\"\n else:\n return input_list[split_index:] + input_list[:split_index]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n # We return the list 'arr' by slicing it at index 'n' and concatenating the two slices in reverse order.\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr,n):\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr,n):\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(input_list, n):\n return input_list[n:] + input_list[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(lst,n):\n return lst[n:] + lst[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(lst, n):\n return lst[n:] + lst[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr,n):\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(lst, n):\n return lst[n:] + lst[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr,n):\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}]}, "Mbpp/587": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def list_tuple(lst):\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n \"\"\"Converts a list into a tuple.\"\"\"\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(input_list):\n return tuple(input_list)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(input_list):\n return tuple(input_list)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(l):\n return tuple(l)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n return tuple(lst)", "matching_cluster_idx": 3}]}, "Mbpp/588": {"dps": 97.13302752293578, "dps_norm": 99.16666666666667, "pass@1": 100.0, "profiled": [{"solution": "def big_diff(input_list):\n # Function to find the difference between largest and smallest value in a given list\n return max(input_list) - min(input_list)", "matching_cluster_idx": 5}, {"solution": "def big_diff(l):\n if len(l) == 0:\n return 0\n min_val = l[0]\n max_val = l[0]\n for val in l:\n if val < min_val:\n min_val = val\n if val > max_val:\n max_val = val\n return max_val - min_val", "matching_cluster_idx": 4}, {"solution": "def big_diff(nums):\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(lst):\n return max(lst) - min(lst)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(input_list):\n return max(input_list) - min(input_list)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(lst):\n return max(lst) - min(lst)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(lst):\n return max(lst) - min(lst)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n return max(nums) - min(nums)", "matching_cluster_idx": 5}]}, "Mbpp/592": {"dps": 60.00000000000001, "dps_norm": 55.0, "pass@1": 27.0, "profiled": [{"solution": "import math\ndef sum_Of_product(n):\n total = 0\n for i in range(n):\n total += math.comb(n, i) * math.comb(n, i+1)\n return total", "matching_cluster_idx": 5}, {"solution": "def binom(n, k):\n \"\"\"Return binomial coefficient of n and k.\"\"\"\n result = 1\n for i in range(min(k, n-k)):\n result = result * (n - i) // (i + 1)\n return result\ndef sum_Of_product(n):\n \"\"\"Find the sum of the product of consecutive binomial coefficients.\"\"\"\n total = 0\n for i in range(n):\n total += binom(n, i) * binom(n, i+1)\n return total", "matching_cluster_idx": 4}, {"solution": "def sum_Of_product(n):\n binomial = [1, 1]\n for i in range(2, n+1):\n temp = [1]\n for j in range(len(binomial)-1):\n temp.append(binomial[j] + binomial[j + 1])\n temp.append(1)\n binomial = temp\n\n result = 0\n for i in range(len(binomial)-1):\n result += binomial[i] * binomial[i + 1]\n\n return result", "matching_cluster_idx": 6}, {"solution": "import math\ndef sum_Of_product(n):\n sum = 0\n for i in range(n):\n sum += math.comb(n, i) * math.comb(n, i+1)\n return sum", "matching_cluster_idx": 5}, {"solution": "def binomial_coeff(n, k):\n res = 1\n if (k > n - k):\n k = n - k\n for x in range(0 , k):\n res = res * (n - x)\n res = res // (x + 1)\n return res\ndef sum_Of_product(n):\n result = 0\n for i in range(n):\n result += binomial_coeff(n, i) * binomial_coeff(n, i+1)\n return result", "matching_cluster_idx": 4}, {"solution": "def binomial_coeff(n, k):\n result = 1\n if (k > n - k):\n k = n - k\n for x in range(0 , k):\n result = result * (n - x)\n result = result // (x + 1)\n return result\ndef sum_Of_product(n):\n sum = 0\n for i in range(n):\n sum += binomial_coeff(n, i) * binomial_coeff(n, i+1)\n return sum", "matching_cluster_idx": 4}, {"solution": "def sum_Of_product(n):\n binomial_coefficients = [0]*(n+1)\n binomial_coefficients[0] = 1\n for i in range(1, n+1):\n for j in range(i, 0, -1):\n binomial_coefficients[j] = binomial_coefficients[j] + binomial_coefficients[j-1]\n \n sum_of_products = 0\n for i in range(1, n+1):\n sum_of_products += binomial_coefficients[i-1]*binomial_coefficients[i]\n\n return sum_of_products", "matching_cluster_idx": 6}, {"solution": "def binomial_coeff(n, k):\n result = 1\n if (k > n - k):\n k = n - k\n for x in range(0 , k):\n result = result * (n - x)\n result = result // (x + 1)\n return result\ndef sum_Of_product(n):\n res = 0\n for i in range(n):\n res += binomial_coeff(n, i) * binomial_coeff(n, i+1)\n return res", "matching_cluster_idx": 4}, {"solution": "def binomial_coeff(n, k):\n res = 1\n if (k > n - k):\n k = n - k\n for i in range(k):\n res = res * (n - i)\n res = res // (i + 1)\n\n return res\ndef sum_Of_product(n):\n sum = 0\n for i in range(n):\n sum += binomial_coeff(n, i) * binomial_coeff(n, i + 1)\n return sum", "matching_cluster_idx": 4}, {"solution": "def sum_Of_product(n):\n if n <= 0:\n return \"Input must be a positive integer.\"\n \n def binom_coeff(n, k):\n # Function to find binomial coefficient\n res = 1\n if (k > n - k):\n k = n - k\n for x in range(0 , k):\n res = res * (n - x)\n res = res // (x + 1)\n return res\n\n total = 0\n for i in range(n):\n total += binom_coeff(n, i) * binom_coeff(n, i + 1)\n return total", "matching_cluster_idx": 4}, {"solution": "def binomial_coeff(n, k):\n res = 1\n \n if (k > n - k):\n k = n - k\n\n for x in range(0 , k):\n res = res * (n - x)\n res = res // (x + 1)\n\n return res\ndef sum_Of_product(n):\n sum = 0\n for i in range(n):\n sum += binomial_coeff(n, i) * binomial_coeff(n, i+1)\n return sum", "matching_cluster_idx": 4}, {"solution": "import math\ndef sum_Of_product(n):\n total = 0\n for i in range(n):\n total += math.comb(n, i) * math.comb(n, i + 1)\n return total", "matching_cluster_idx": 5}, {"solution": "def binomial_coeff(n, k):\n res = 1\n if (k > n - k):\n k = n - k\n for i in range(k):\n res = res * (n - i)\n res = res // (i + 1)\n return res\ndef sum_Of_product(n):\n sum = 0\n for i in range(1, n + 1):\n sum += (binomial_coeff(n, i) * binomial_coeff(n, i - 1))\n return sum", "matching_cluster_idx": 4}, {"solution": "import math\ndef sum_Of_product(n):\n total_sum = 0\n for i in range(n):\n total_sum += math.comb(n, i) * math.comb(n, i+1)\n return total_sum", "matching_cluster_idx": 5}, {"solution": "def sum_Of_product(n):\n def binom_coef(n, k): # compute binomial coefficient n over k\n if k > n:\n return 0\n if k > n - k:\n k = n - k\n result = 1\n for i in range(k):\n result *= n - i\n result //= i + 1\n return result\n\n total = 0\n for i in range(n):\n total += binom_coef(n, i) * binom_coef(n, i+1)\n return total", "matching_cluster_idx": 4}, {"solution": "def sum_Of_product(n):\n from math import comb # this function helps to compute binomial coefficients\n sum = 0\n for i in range(n+1):\n if i == 0:\n continue\n sum += comb(n, i) * comb(n, i-1)\n return sum", "matching_cluster_idx": 5}, {"solution": "def sum_Of_product(n):\n import math\n total = 0\n for i in range(n):\n total += math.comb(n, i) * math.comb(n, i + 1)\n return total", "matching_cluster_idx": 5}, {"solution": "import math\ndef sum_Of_product(n):\n total = 0\n for i in range(n):\n total += math.comb(n, i) * math.comb(n, i+1)\n return total", "matching_cluster_idx": 5}, {"solution": "def sum_Of_product(n):\n # Initialize array to store binomial coefficients\n C = [[0 for x in range(n+1)] for x in range(n+1)]\n\n # Calculate value of Binomial Coefficient in bottom up manner\n for i in range(n+1):\n for j in range(min(i, n)+1):\n # Base Cases\n if j == 0 or j == i:\n C[i][j] = 1\n # Calculate value using previously stored values\n else:\n C[i][j] = C[i-1][j-1] + C[i-1][j]\n\n # Calculate the sum of the product of consecutive binomial coefficients\n sum = 0\n for i in range(n):\n sum += C[n][i] * C[n][i+1]\n\n return sum", "matching_cluster_idx": 3}, {"solution": "def binomial_coeff(n, k):\n result = 1\n if (k > n - k):\n k = n - k\n for x in range(0 , k):\n result = result * (n - x)\n result = result // (x + 1)\n\n return result\ndef sum_Of_product(n):\n total = 0\n for i in range(n):\n total += binomial_coeff(n, i) * binomial_coeff(n, i+1)\n return total", "matching_cluster_idx": 4}]}, "Mbpp/597": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 42.0, "profiled": [{"solution": "def find_kth(arr1, arr2, k):\n # Merge the sorted arrays\n merged = sorted(arr1 + arr2)\n # Return kth element\n return merged[k-1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(a, b, k):\n merged = sorted(a + b)\n return merged[k - 1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(arr1, arr2, k):\n \"\"\"Function to find kth element in two sorted arrays.\"\"\"\n # Merge two sorted arrays\n merged = sorted(arr1 + arr2)\n # Return kth element\n return merged[k - 1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(arr1, arr2, k):\n # merge two lists into one\n merged = arr1 + arr2\n # sort the merged list\n merged.sort()\n # return the kth element\n return merged[k-1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(arr1, arr2, k):\n # Merging two arrays\n arr = arr1 + arr2\n \n # Sorting the array\n arr.sort()\n \n # Return kth element\n return arr[k-1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(arr1, arr2, k):\n # Merge both arrays\n merge_arr = sorted(arr1 + arr2)\n # Return kth element\n return merge_arr[k-1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(arr1, arr2, k):\n combined = sorted(arr1 + arr2)\n return combined[k-1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(arr1, arr2, k):\n combined = sorted(arr1 + arr2)\n return combined[k - 1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(arr1, arr2, k):\n \"\"\"\n Function to find kth element in two sorted arrays.\n \"\"\"\n combined = sorted(arr1 + arr2)\n if k <= len(combined):\n return combined[k-1]\n else:\n return None", "matching_cluster_idx": 3}, {"solution": "def find_kth(arr1, arr2, k):\n # combine both arrays into one\n arr = arr1 + arr2\n # sort the combined array\n arr.sort()\n # return the kth element (list indices start at 0)\n return arr[k-1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(arr1, arr2, k):\n arr1.extend(arr2)\n arr1.sort()\n return arr1[k-1] if k <= len(arr1) else None", "matching_cluster_idx": 3}, {"solution": "def find_kth(arr1, arr2, k):\n # Merge the two arrays\n merged = sorted(arr1 + arr2)\n\n # Check if k is within the bounds of the merged list\n if k <= len(merged):\n # Return the kth element in the merged list\n return merged[k - 1]\n else:\n return \"Error: k is out of bounds\"", "matching_cluster_idx": 3}, {"solution": "def find_kth(arr1, arr2, k):\n # Merge the arrays\n arr = arr1 + arr2\n arr.sort()\n # Return the kth element\n return arr[k - 1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(arr1, arr2, k):\n # Concatenate the two sorted arrays\n merged = arr1 + arr2\n \n # Sort the merged array\n merged.sort()\n\n # Return the kth element (remember that indexing starts at 0)\n return merged[k-1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(arr1, arr2, k):\n combined_arr = sorted(arr1 + arr2)\n if len(combined_arr) < k:\n return \"Error: k is larger than the total number of elements\"\n else:\n return combined_arr[k - 1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(arr1, arr2, k):\n '''Function to find kth element from two sorted arrays.\n\n :param arr1: list of integers.\n :param arr2: list of integers.\n :param k: the kth element to find.\n\n :return: integer, the kth element in the combined array.\n '''\n\n combined_array = sorted(arr1 + arr2)\n \n if k <= len(combined_array):\n return combined_array[k-1]\n else:\n raise ValueError(\"k is greater than the total number of elements in the combined array\")", "matching_cluster_idx": 3}, {"solution": "def find_kth(arr1, arr2, k):\n # merge two sorted arrays\n sorted_arr = sorted(arr1 + arr2)\n\n # check if k is within the length of the sorted array\n if k <= len(sorted_arr):\n return sorted_arr[k-1]\n\n return None", "matching_cluster_idx": 3}, {"solution": "def find_kth(arr1, arr2, k):\n sorted_arr = sorted(arr1 + arr2)\n return sorted_arr[k-1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(list1, list2, k):\n combined_list = sorted(list1 + list2)\n if k <= len(combined_list):\n return combined_list[k - 1]\n else:\n return \"Kth element does not exist\"", "matching_cluster_idx": 3}, {"solution": "def find_kth(arr1, arr2, k):\n # merging two arrays\n arr = arr1 + arr2\n # sort array\n arr.sort()\n # return kth element\n return arr[k - 1]", "matching_cluster_idx": 3}]}, "Mbpp/604": {"dps": 90.45454545454545, "dps_norm": 98.0, "pass@1": 53.0, "profiled": [{"solution": "def reverse_words(s):\n return ' '.join(reversed(s.split()))", "matching_cluster_idx": 4}, {"solution": "def reverse_words(input_string):\n words = input_string.split()\n reversed_words = words[::-1]\n return ' '.join(reversed_words)", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n return ' '.join(s.split()[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(input_str):\n # This function splits the input string into words, reverse the order of the words,\n # then join them back together with a space between each word.\n words = input_str.split()\n words = words[::-1]\n output_str = ' '.join(words)\n return output_str", "matching_cluster_idx": 4}, {"solution": "def reverse_words(input_str):\n return \" \".join(input_str.split()[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n return ' '.join(s.split()[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n return ' '.join(reversed(s.split()))", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n return ' '.join(reversed(s.split()))", "matching_cluster_idx": 4}, {"solution": "def reverse_words(input_str):\n words = input_str.split()\n reversed_words = words[::-1]\n output_str = ' '.join(reversed_words)\n return output_str", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n return ' '.join(s.split()[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(input_string):\n \"\"\"Reverse words in a string\"\"\"\n # Split the string into a list of words\n words = input_string.split()\n \n # Reverse the order of the words\n words.reverse()\n \n # Join the words back into a string\n output_string = ' '.join(words)\n \n return output_string", "matching_cluster_idx": 4}, {"solution": "def reverse_words(input_string):\n words = input_string.split()\n words = words[::-1]\n return ' '.join(words)", "matching_cluster_idx": 4}, {"solution": "def reverse_words(string):\n return ' '.join(string.split()[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(input_string):\n return \" \".join(input_string.split()[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n return ' '.join(s.split()[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(input_str):\n return ' '.join(input_str.split()[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n return ' '.join(s.split()[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n words = s.split()\n return ' '.join(reversed(words))", "matching_cluster_idx": 3}, {"solution": "def reverse_words(input_string):\n words = input_string.split()\n reversed_words = ' '.join(reversed(words))\n return reversed_words", "matching_cluster_idx": 3}, {"solution": "def reverse_words(input_string):\n # Splitting the string into list of words\n words = input_string.split()\n # Reversing the order of words and joining them back into a string\n output_string = ' '.join(words[::-1])\n return output_string", "matching_cluster_idx": 4}]}, "Mbpp/610": {"dps": 49.951690821256044, "dps_norm": 60.0, "pass@1": 15.0, "profiled": [{"solution": "def remove_kth_element(lst, k):\n return lst[:k-1] + lst[k:]", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(input_list, k):\n #Check if k is not greater than the length of the list\n if k <= len(input_list):\n del input_list[k-1]\n return input_list", "matching_cluster_idx": 6}, {"solution": "def remove_kth_element(lst, k):\n return lst[:k-1] + lst[k:]", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(lst, k):\n # if k is greater than the length of list, simply return the list.\n if k > len(lst):\n return lst\n else:\n # remove the k'th element\n del lst[k-1]\n return lst", "matching_cluster_idx": 6}, {"solution": "def remove_kth_element(lst, k):\n return [value for index, value in enumerate(lst, start=1) if index != k]", "matching_cluster_idx": 2}, {"solution": "def remove_kth_element(input_list, k):\n # if the list is empty or k is out of range, return the original list\n if not input_list or k > len(input_list):\n return input_list\n else:\n # create a copy of the list\n result = input_list[:]\n # remove the k'th element\n result.pop(k-1)\n return result", "matching_cluster_idx": 4}, {"solution": "def remove_kth_element(lst, k):\n # check if k is valid\n if k <= 0 or k > len(lst):\n return lst\n\n return lst[:k-1] + lst[k:]", "matching_cluster_idx": 2}, {"solution": "def remove_kth_element(lst, k):\n return lst[:k-1] + lst[k:]", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(input_list, k):\n if k > len(input_list):\n return \"Error: k is greater than the length of the list\"\n else:\n return input_list[:k-1] + input_list[k:]", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(input_list, k):\n \"\"\"\n Function to remove kth element from the input list.\n\n Parameters:\n input_list (list): a list of elements\n k (int): the position of the element to be removed (1-indexed)\n\n Returns:\n list: a list with the kth element removed\n \"\"\"\n # Validate the inputs\n if not isinstance(input_list, list) or not all(isinstance(i, int) for i in input_list):\n raise ValueError('input_list must be a list of integers')\n if not isinstance(k, int) or k <= 0 or k > len(input_list):\n raise ValueError('k must be an integer between 1 and the length of the input_list')\n\n # Remove the kth element from the list\n output_list = input_list[:k-1] + input_list[k:]\n return output_list", "matching_cluster_idx": 2}, {"solution": "def remove_kth_element(lst, k):\n return [value for index, value in enumerate(lst, start=1) if index != k]", "matching_cluster_idx": 2}, {"solution": "def remove_kth_element(lst, k):\n return lst[:k-1] + lst[k:]", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(lst, k):\n return lst[:k-1] + lst[k:]", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(lst, k):\n return lst[:k-1] + lst[k:]", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(lst, k):\n # Validate input\n if not isinstance(lst, list) or not isinstance(k, int) or k <= 0 or k > len(lst):\n raise ValueError(\"Invalid input.\")\n\n # Remove k'th element\n new_lst = lst[:k - 1] + lst[k:]\n return new_lst", "matching_cluster_idx": 3}]}, "Mbpp/611": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 99.0, "profiled": [{"solution": "def max_of_nth(matrix, n):\n return max(column[n] for column in matrix)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n return max(row[n] for row in matrix)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n return max(row[n] for row in matrix)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n return max(row[n] for row in matrix)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n return max(row[n] for row in matrix)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, column_index):\n return max(row[column_index] for row in matrix)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n # Take the nth element of each sublist, store in a new list\n nth_elements = [sublist[n] for sublist in matrix]\n # Return the maximum of the new list\n return max(nth_elements)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n return max(column[n] for column in matrix)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n return max(row[n] for row in matrix)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n return max(row[n] for row in matrix)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n \"\"\"\n Function to return max of n'th column\n :param matrix: list of lists\n :param n: column number\n :return: max of n'th column\n \"\"\"\n return max(row[n] for row in matrix)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n # Use list comprehension to create a new list with n'th elements of each sublist\n nth_column = [sublist[n] for sublist in matrix]\n # Use built-in max function to find the maximum value\n return max(nth_column)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n return max(row[n] for row in matrix)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n return max(row[n] for row in matrix)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n return max(row[n] for row in matrix)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n return max(row[n] for row in matrix)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n \"\"\"Return max of nth column in the matrix.\"\"\"\n return max(row[n] for row in matrix)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n column = [row[n] for row in matrix]\n return max(column)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n return max(row[n] for row in matrix)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n \"\"\"\n This function takes a matrix represented as a list of lists and an index n.\n It returns the max of the n'th column of the matrix.\n \"\"\"\n column = [row[n] for row in matrix]\n return max(column)", "matching_cluster_idx": 5}]}, "Mbpp/631": {"dps": 64.02777777777777, "dps_norm": 71.25, "pass@1": 91.0, "profiled": [{"solution": "def replace_spaces(s):\n return_string = ''\n for c in s:\n if c.isspace():\n return_string += '_'\n elif c == '_':\n return_string += ' '\n else:\n return_string += c\n return return_string", "matching_cluster_idx": 1}, {"solution": "def replace_spaces(string):\n \"\"\"Function to replace spaces with underscores and vice versa in a given string\"\"\"\n new_string = ''\n for char in string:\n if char == ' ':\n new_string += '_'\n elif char == '_':\n new_string += ' '\n else:\n new_string += char\n return new_string", "matching_cluster_idx": 1}, {"solution": "def replace_spaces(s):\n if \" \" in s:\n s = s.replace(\" \", \"_\")\n elif \"_\" in s:\n s = s.replace(\"_\", \" \")\n return s", "matching_cluster_idx": 7}, {"solution": "def replace_spaces(input_string):\n # Check if input string contains whitespace\n if ' ' in input_string:\n # If contains whitespace, replace with underscore\n output_string = input_string.replace(' ', '_')\n # Else, check if input string contains underscore\n elif '_' in input_string:\n # If contains underscore, replace with whitespace\n output_string = input_string.replace('_', ' ')\n # If input string does not contain any underscore or whitespace, return it as it is\n else:\n return input_string\n return output_string", "matching_cluster_idx": 7}, {"solution": "def replace_spaces(input_string):\n result = ''\n for char in input_string:\n if char == ' ':\n result += '_'\n elif char == '_':\n result += ' '\n else:\n result += char\n return result", "matching_cluster_idx": 1}, {"solution": "def replace_spaces(input_string):\n # Replace spaces with underscore\n if ' ' in input_string:\n replaced = input_string.replace(' ', '_')\n # Replace underscore with spaces\n elif '_' in input_string:\n replaced = input_string.replace('_', ' ')\n # If no spaces or underscore present return original string\n else:\n replaced = input_string\n return replaced", "matching_cluster_idx": 7}, {"solution": "def replace_spaces(string):\n \"\"\"\n This function replaces spaces with underscores and underscores with spaces in a given string.\n\n :param string: input string\n :return: modified string\n \"\"\"\n \n # Create an empty string for the result\n result = \"\"\n\n # Iterate through each character in the input string\n for char in string:\n # If the character is a space, add an underscore to the result\n if char == ' ':\n result += '_'\n # If the character is an underscore, add a space to the result\n elif char == '_':\n result += ' '\n # Otherwise, add the character as is to the result\n else:\n result += char\n\n return result", "matching_cluster_idx": 1}, {"solution": "def replace_spaces(input_string):\n if \" \" in input_string:\n return input_string.replace(\" \", \"_\")\n elif \"_\" in input_string:\n return input_string.replace(\"_\", \" \")\n else:\n return input_string", "matching_cluster_idx": 7}, {"solution": "def replace_spaces(s):\n result = ''\n for char in s:\n if char == ' ':\n result += '_'\n elif char == '_':\n result += ' '\n else:\n result += char\n return result", "matching_cluster_idx": 1}, {"solution": "def replace_spaces(s):\n \"\"\"\n Replace whitespaces with an underscore and vice versa in a given string.\n \"\"\"\n result = ''\n for char in s:\n if char == ' ':\n result += '_'\n elif char == '_':\n result += ' '\n else:\n result += char\n return result", "matching_cluster_idx": 1}, {"solution": "def replace_spaces(text):\n # Replace spaces with underscore if no underscore present in text\n if '_' not in text:\n return text.replace(' ', '_')\n else:\n # Replace underscore with space if underscore is present in text\n return text.replace('_', ' ')", "matching_cluster_idx": 7}, {"solution": "def replace_spaces(s):\n \"\"\"\n This function replaces whitespaces with underscore and vice versa in the given string\n \"\"\"\n if \" \" in s:\n return s.replace(\" \", \"_\")\n elif \"_\" in s:\n return s.replace(\"_\", \" \")\n else:\n return s", "matching_cluster_idx": 7}, {"solution": "def replace_spaces(s):\n # First, we check if the string contains a whitespace\n if ' ' in s:\n # If it does, we replace whitespaces with underscores\n s = s.replace(' ', '_')\n else:\n # If it doesn't, we replace underscores with spaces\n s = s.replace('_', ' ')\n return s", "matching_cluster_idx": 7}, {"solution": "def replace_spaces(input_string):\n # Check if the string contains whitespaces\n if ' ' in input_string:\n # Replace whitespaces with underscore\n return input_string.replace(' ', '_')\n else:\n # Replace underscores with whitespace\n return input_string.replace('_', ' ')", "matching_cluster_idx": 7}, {"solution": "def replace_spaces(s):\n # Determine if whitespace should be replaced with underscore ('_') or vice versa\n # by counting the number of each character in the string\n underscore_count = s.count('_')\n space_count = s.count(' ')\n \n # If more underscores than spaces, replace underscores with spaces\n if underscore_count > space_count:\n return s.replace('_', ' ')\n # If more spaces than underscores, replace spaces with underscores\n else:\n return s.replace(' ', '_')", "matching_cluster_idx": 4}, {"solution": "def replace_spaces(input_str):\n output_str = input_str.replace(' ', '_') if ' ' in input_str else input_str.replace('_', ' ')\n return output_str", "matching_cluster_idx": 7}, {"solution": "def replace_spaces(input_string):\n if '_' in input_string:\n return input_string.replace('_', ' ')\n else:\n return input_string.replace(' ', '_')", "matching_cluster_idx": 7}, {"solution": "def replace_spaces(string):\n # check if there's a whitespace in the string\n if ' ' in string:\n # replace whitespaces with an underscore\n return string.replace(' ', '_')\n else:\n # replace underscores with a whitespace\n return string.replace('_', ' ')", "matching_cluster_idx": 7}, {"solution": "def replace_spaces(s):\n \"\"\" \n This function replaces spaces with underscores and vice versa in a given string.\n \n Arguments:\n s {string} -- input string\n \n Returns:\n string -- modified string\n \"\"\"\n \n # define a helper function that checks if the character is a space or underscore\n def is_space_or_underscore(c):\n return c == ' ' or c == '_'\n \n # check if the input string is empty\n if not s:\n return s\n \n # create a list of characters from the input string\n chars = list(s)\n \n # check each character in the string\n for i in range(len(chars)):\n # if the character is a space or underscore, swap it\n if is_space_or_underscore(chars[i]):\n chars[i] = '_' if chars[i] == ' ' else ' '\n \n # join the characters back into a string and return it\n return ''.join(chars)", "matching_cluster_idx": 0}, {"solution": "def replace_spaces(s):\n # Check if the string contains whitespaces\n if ' ' in s:\n # Replace whitespaces with underscore\n return s.replace(' ', '_')\n else:\n # If no whitespaces, replace underscore with whitespace\n return s.replace('_', ' ')", "matching_cluster_idx": 7}]}, "Mbpp/632": {"dps": 90.28142589118198, "dps_norm": 95.71428571428571, "pass@1": 100.0, "profiled": [{"solution": "def move_zero(lst):\n # Create two lists, one with zeros and another with non-zeros\n zeros = [i for i in lst if i == 0]\n non_zeros = [i for i in lst if i != 0]\n \n # Return the concatenation of the two lists\n return non_zeros + zeros", "matching_cluster_idx": 6}, {"solution": "def move_zero(lst):\n # Count the number of zeros\n zero_count = lst.count(0)\n \n # Remove all zeros from list\n lst = [element for element in lst if element != 0]\n \n # Add the number of zeros to the end of the list\n lst.extend([0]*zero_count)\n \n return lst", "matching_cluster_idx": 6}, {"solution": "def move_zero(lst):\n return [non_zero for non_zero in lst if non_zero!=0] + [zero for zero in lst if zero==0]", "matching_cluster_idx": 6}, {"solution": "def move_zero(lst):\n count = lst.count(0)\n lst = [i for i in lst if i != 0]\n lst.extend([0]*count)\n return lst", "matching_cluster_idx": 6}, {"solution": "def move_zero(arr):\n # Count the zeros\n zero_count = arr.count(0)\n \n # Remove all zeros from the list\n while 0 in arr:\n arr.remove(0)\n\n # Add the zeros at the end of the list\n arr.extend([0]*zero_count)\n return arr", "matching_cluster_idx": 3}, {"solution": "def move_zero(list):\n no_zeros = [i for i in list if i != 0]\n zeros = [i for i in list if i == 0]\n return no_zeros + zeros", "matching_cluster_idx": 6}, {"solution": "def move_zero(input_list):\n result = [i for i in input_list if i!=0]\n result += [0] * input_list.count(0)\n return result", "matching_cluster_idx": 6}, {"solution": "def move_zero(arr):\n return [i for i in arr if i!=0] + [i for i in arr if i==0]", "matching_cluster_idx": 6}, {"solution": "def move_zero(arr):\n # filter zero elements from the list and then extend the list with zero elements\n return [i for i in arr if i != 0] + [i for i in arr if i == 0]", "matching_cluster_idx": 6}, {"solution": "def move_zero(lst):\n result = [i for i in lst if i!=0]\n result += [0]*lst.count(0)\n return result", "matching_cluster_idx": 6}, {"solution": "def move_zero(lst):\n zero_lst = [i for i in lst if i != 0]\n zero_lst.extend([0] * lst.count(0))\n return zero_lst", "matching_cluster_idx": 6}, {"solution": "def move_zero(lst):\n return [num for num in lst if num != 0] + [num for num in lst if num == 0]", "matching_cluster_idx": 6}, {"solution": "def move_zero(arr):\n \"\"\"\n This function moves all zeroes to the end of the list.\n \n Parameters:\n arr (list): a list of numbers\n\n Returns:\n list: the list after moving zeroes to the end\n \"\"\"\n \n # Count the number of zeros\n count = arr.count(0)\n \n # Remove all zeros from the list\n while 0 in arr: arr.remove(0)\n\n # Extend the list with zeros\n arr.extend([0]*count)\n \n return arr", "matching_cluster_idx": 3}, {"solution": "def move_zero(nums):\n # list comprehension is used to create a new list\n # that includes all non-zero elements\n # then we simply add the appropriate number of zeroes to the end\n return [num for num in nums if num != 0] + [0] * nums.count(0)", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n # list comprehension to separate zeroes from non-zeroes \n # then concatenates both lists\n return [i for i in nums if i!=0] + [i for i in nums if i==0]", "matching_cluster_idx": 6}, {"solution": "def move_zero(lst):\n # Using list comprehension to separate zeros and non-zeros\n return [non_zero for non_zero in lst if non_zero!=0] + [zero for zero in lst if zero==0]", "matching_cluster_idx": 6}, {"solution": "def move_zero(input_list):\n # Count the number of zeros in the list\n zero_count = input_list.count(0)\n \n # Remove all zeros from the list\n input_list = [value for value in input_list if value != 0]\n \n # Extend the list with the counted number of zeros\n input_list.extend([0]*zero_count)\n \n return input_list", "matching_cluster_idx": 6}, {"solution": "def move_zero(lst):\n # count number of zeros\n zero_count = lst.count(0)\n # remove all zeros from the list\n lst = [i for i in lst if i != 0]\n # append zeros at the end of the list\n lst.extend([0]*zero_count)\n return lst", "matching_cluster_idx": 6}, {"solution": "def move_zero(lst):\n count = lst.count(0)\n lst = [value for value in lst if value != 0]\n lst.extend([0]*count)\n return lst", "matching_cluster_idx": 6}, {"solution": "def move_zero(arr):\n return [num for num in arr if num != 0] + [num for num in arr if num == 0]", "matching_cluster_idx": 6}]}, "Mbpp/633": {"dps": null, "dps_norm": null, "pass@1": 1.0, "profiled": []}, "Mbpp/644": {"dps": 74.65425531914893, "dps_norm": 76.0, "pass@1": 100.0, "profiled": [{"solution": "def reverse_Array_Upto_K(arr, k):\n return arr[:k][::-1] + arr[k:]", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n #Reverse the array from index 0 to k\n arr[:k] = arr[:k][::-1]\n return arr", "matching_cluster_idx": 13}, {"solution": "def reverse_Array_Upto_K(input_list, k):\n # Reverse the sublist from index 0 to k\n input_list[:k] = reversed(input_list[:k])\n return input_list", "matching_cluster_idx": 12}, {"solution": "def reverse_Array_Upto_K(arr, k):\n return arr[:k][::-1] + arr[k:]", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(array, k):\n return array[:k][::-1] + array[k:]", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n return arr[:k][::-1] + arr[k:]", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(input_array, k):\n return input_array[:k][::-1] + input_array[k:]", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n Function to reverse an array up to a given position\n \"\"\"\n # reverse array upto k\n arr[:k] = arr[:k][::-1]\n return arr", "matching_cluster_idx": 13}, {"solution": "def reverse_Array_Upto_K(arr, k):\n return arr[:k][::-1] + arr[k:]", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n # slicing the array from 0 to k and reverse it. \n # After that, append the rest of the array from k to end.\n return arr[:k][::-1] + arr[k:]", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n return arr[:k][::-1] + arr[k:]", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n # Python slicing is the easiest way to reverse the array up to k\n return arr[:k][::-1] + arr[k:]", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n return arr[:k][::-1] + arr[k:]", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n return arr[:k][::-1] + arr[k:]", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, K):\n return arr[:K][::-1] + arr[K:]", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(array, k):\n return array[:k][::-1] + array[k:]", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n return arr[:k][::-1] + arr[k:]", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n return arr[:k][::-1] + arr[k:]", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(array, k):\n return array[:k][::-1] + array[k:]", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n This function takes in a list and an integer as input. The function then slices the list upto the integer,\n reverses the slice, and then concatenates the reversed slice with the remaining elements of the list.\n \n Parameters:\n arr (list): The list to be reversed up to position k\n k (int): The position up to which the list is to be reversed\n\n Returns:\n list: The reversed list upto a given position.\n \"\"\"\n \n # Slice the list upto k, reverse the slice and concatenate the reversed slice with the remaining list\n return arr[:k][::-1] + arr[k:]", "matching_cluster_idx": 10}]}, "Mbpp/720": {"dps": 93.84615384615384, "dps_norm": 98.0, "pass@1": 100.0, "profiled": [{"solution": "def add_dict_to_tuple(tup, dic):\n \"\"\"\n This function adds a dictionary to the tuple.\n :param tup: tuple\n :param dic: dictionary\n :return: tuple\n \"\"\"\n return tup + (dic,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(tup, dictionary):\n return tup + (dictionary,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(t, d):\n return t + (d,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(t, d):\n return t + (d,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(t, d):\n return t + (d,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(t, d):\n return t + (d,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(t, d):\n return t + (d,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(t, d):\n return t + (d,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(t, d):\n \"\"\"\n This function adds a dictionary to a tuple.\n \n Parameters:\n t (tuple): the initial tuple\n d (dict): the dictionary to be added\n \n Returns:\n tuple: a new tuple consisting of the elements of the initial tuple and the dictionary\n \"\"\"\n return t + (d,)\nt = (4, 5, 6)\nd = {\"MSAM\" : 1, \"is\" : 2, \"best\" : 3}", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(t, d):\n \"\"\"\n This function adds a dictionary to the tuple.\n \"\"\"\n return t + (d,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(input_tuple, input_dict):\n return input_tuple + (input_dict,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(t, d):\n \"\"\" \n Function to add a dictionary to the tuple\n \"\"\"\n return t + (d,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(t, d):\n return t + (d,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(t, d):\n return t + (d,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(tuple_input, dict_input):\n return tuple_input + (dict_input,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(t, d):\n return t + (d,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(tup, dic):\n # Convert the tuple to a list\n temp = list(tup)\n # Append the dictionary to the list\n temp.append(dic)\n # Convert the list back to a tuple\n result = tuple(temp)\n # Return the resulting tuple\n return result", "matching_cluster_idx": 3}, {"solution": "def add_dict_to_tuple(tup, dic):\n return tup + (dic,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(input_tuple, input_dict):\n # convert tuple to list\n list_temp = list(input_tuple)\n \n # append the dictionary to the list\n list_temp.append(input_dict)\n \n # convert the list back to tuple\n output_tuple = tuple(list_temp)\n \n return output_tuple", "matching_cluster_idx": 3}, {"solution": "def add_dict_to_tuple(input_tuple, input_dict):\n return input_tuple + (input_dict,)", "matching_cluster_idx": 4}]}, "Mbpp/725": {"dps": 75.71721311475409, "dps_norm": 75.0, "pass@1": 16.0, "profiled": [{"solution": "import re\ndef extract_quotation(s):\n return re.findall(r'\"([^\"]*)\"', s)", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(s):\n return re.findall(r'\"([^\"]*)\"', s)", "matching_cluster_idx": 5}, {"solution": "def extract_quotation(s):\n result = []\n is_in_quotes = False\n word = ''\n for char in s:\n if char == '\"':\n is_in_quotes = not is_in_quotes\n if not is_in_quotes:\n result.append(word)\n word = ''\n elif is_in_quotes:\n word += char\n return result", "matching_cluster_idx": 2}, {"solution": "import re\ndef extract_quotation(string):\n return re.findall(r'\"([^\"]*)\"', string)", "matching_cluster_idx": 6}, {"solution": "import re\ndef extract_quotation(input_string):\n return re.findall(r'\"([^\"]*)\"', input_string)", "matching_cluster_idx": 6}, {"solution": "import re\ndef extract_quotation(input_str):\n return re.findall(r'\"(.*?)\"', input_str)", "matching_cluster_idx": 4}, {"solution": "import re\ndef extract_quotation(s):\n return re.findall(r'\"([^\"]*)\"', s)", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(s):\n return re.findall(r'\"([^\"]*)\"', s)", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(input_string):\n pattern = re.compile('\"([^\"]*)\"')\n return pattern.findall(input_string)", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(text):\n return re.findall(r'\"([^\"]*)\"', text)", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(s):\n \"\"\"Extract values between quotation marks in the given string.\"\"\"\n return re.findall(r'\"(.*?)\"', s)", "matching_cluster_idx": 4}, {"solution": "import re\ndef extract_quotation(string):\n return re.findall(r'\"(.*?)\"', string)", "matching_cluster_idx": 4}, {"solution": "import re\ndef extract_quotation(input_string):\n return re.findall(r'\"([^\"]*)\"', input_string)", "matching_cluster_idx": 6}, {"solution": "import re\ndef extract_quotation(input_string):\n return re.findall(r'\"([^\"]*)\"', input_string)", "matching_cluster_idx": 6}, {"solution": "import re\ndef extract_quotation(string):\n return re.findall(r'\"([^\"]*)\"', string)", "matching_cluster_idx": 6}, {"solution": "import re\ndef extract_quotation(string):\n return re.findall(r'\"([^\"]*)\"', string)", "matching_cluster_idx": 6}]}, "Mbpp/732": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 99.0, "profiled": [{"solution": "def replace_specialchar(input_string):\n output_string = input_string.replace(' ', ':').replace(',', ':').replace('.', ':')\n return output_string", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(s):\n s = s.replace(' ', ':').replace(',', ':').replace('.', ':')\n return s", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(s):\n return s.replace(' ', ':').replace(',', ':').replace('.', ':')", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(str):\n return str.replace(\" \", \":\").replace(\",\", \":\").replace(\".\", \":\")", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(s):\n return s.replace(' ', ':').replace(',', ':').replace('.', ':')", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(input_string):\n input_string = input_string.replace(' ', ':').replace(',', ':').replace('.', ':')\n return input_string", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(string):\n return string.replace(\" \", \":\").replace(\",\", \":\").replace(\".\", \":\")", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(input_str):\n return input_str.replace(' ', ':').replace(',', ':').replace('.', ':')", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(s):\n s = s.replace(' ', ':')\n s = s.replace(',', ':')\n s = s.replace('.', ':')\n return s", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(s):\n return s.replace(' ', ':').replace(',', ':').replace('.', ':')", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(input_str):\n # Replaces spaces, commas, and dots with a colon.\n return input_str.replace(' ', ':').replace(',', ':').replace('.', ':')", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(s):\n s = s.replace(' ', ':')\n s = s.replace(',', ':')\n s = s.replace('.', ':')\n return s", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(string):\n string = string.replace(' ', ':')\n string = string.replace(',', ':')\n string = string.replace('.', ':')\n return string", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(s):\n s = s.replace(' ', ':')\n s = s.replace(',', ':')\n s = s.replace('.', ':')\n return s", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(str):\n str = str.replace(\" \", \":\")\n str = str.replace(\",\", \":\")\n str = str.replace(\".\", \":\")\n return str", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(input_string):\n # replace all occurrences of spaces, commas, or dots with a colon\n return input_string.replace(' ', ':').replace(',', ':').replace('.', ':')", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(input_string):\n output_string = input_string.replace(' ', ':').replace(',', ':').replace('.', ':')\n return output_string", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(input_string):\n return input_string.replace(' ', ':').replace(',', ':').replace('.', ':')", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(input_string):\n output_string = input_string.replace(\" \",\":\").replace(\",\",\":\").replace(\".\",\":\")\n return output_string", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(input_string):\n output_string = input_string.replace(' ', ':').replace(',', ':').replace('.', ':')\n return output_string", "matching_cluster_idx": 9}]}, "Mbpp/740": {"dps": 83.63636363636364, "dps_norm": 66.66666666666667, "pass@1": 100.0, "profiled": [{"solution": "def tuple_to_dict(input_tuple):\n return {input_tuple[i]: input_tuple[i+1] for i in range(0, len(input_tuple), 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(t):\n return {t[i]: t[i + 1] for i in range(0, len(t) - 1, 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(t):\n \"\"\"Convert the given tuple to a key-value dictionary using adjacent elements.\"\"\"\n return {t[i]: t[i + 1] for i in range(0, len(t), 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(t):\n return {t[i]: t[i + 1] for i in range(0, len(t) - 1, 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(t):\n return {t[i]: t[i + 1] for i in range(0, len(t), 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(tup):\n return {tup[i]: tup[i+1] for i in range(0, len(tup), 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(t):\n return {t[i]: t[i + 1] for i in range(0, len(t), 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(t):\n return {t[i]: t[i + 1] for i in range(0, len(t), 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(input_tuple):\n return {input_tuple[i]: input_tuple[i + 1] for i in range(0, len(input_tuple), 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(t):\n return {t[i]: t[i+1] for i in range(0, len(t), 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(input_tuple):\n \"\"\" \n Function to convert tuple to dictionary.\n \n Parameters:\n input_tuple (tuple): Input tuple\n \n Returns:\n dict: Dictionary created from the tuple\n \"\"\"\n return {input_tuple[i]: input_tuple[i + 1] for i in range(0, len(input_tuple) - 1, 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(tpl):\n return {tpl[i]: tpl[i+1] for i in range(0, len(tpl), 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(tup):\n return {tup[i]: tup[i + 1] for i in range(0, len(tup), 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(input_tuple):\n return {input_tuple[i]: input_tuple[i + 1] for i in range(0, len(input_tuple), 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(t):\n return {t[i]: t[i+1] for i in range(0, len(t), 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(input_tuple):\n return {input_tuple[i]: input_tuple[i + 1] for i in range(0, len(input_tuple) - 1, 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(t):\n return {t[i]: t[i + 1] for i in range(0, len(t), 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(t):\n return {t[i]: t[i+1] for i in range(0, len(t), 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(t):\n return {t[i]: t[i + 1] for i in range(0, len(t), 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(t):\n return {t[i]: t[i+1] for i in range(0, len(t), 2)}", "matching_cluster_idx": 5}]}, "Mbpp/744": {"dps": 91.60958904109589, "dps_norm": 94.16666666666667, "pass@1": 100.0, "profiled": [{"solution": "def check_none(t):\n \"\"\"\n This function checks if the tuple `t` has any None values.\n \"\"\"\n return None in t", "matching_cluster_idx": 5}, {"solution": "def check_none(tup):\n return None in tup", "matching_cluster_idx": 5}, {"solution": "def check_none(t):\n \"\"\"\n This function takes a tuple as input and returns True if the tuple contains any None value, else it returns False.\n \"\"\"\n return None in t", "matching_cluster_idx": 4}, {"solution": "def check_none(tup):\n return None in tup", "matching_cluster_idx": 5}, {"solution": "def check_none(t):\n return None in t", "matching_cluster_idx": 4}, {"solution": "def check_none(data):\n return None in data", "matching_cluster_idx": 5}, {"solution": "def check_none(t):\n \"\"\"This function checks if the given tuple has any None value or not.\"\"\"\n return None in t", "matching_cluster_idx": 4}, {"solution": "def check_none(tup):\n return None in tup", "matching_cluster_idx": 5}, {"solution": "def check_none(input_tuple):\n return None in input_tuple", "matching_cluster_idx": 5}, {"solution": "def check_none(t):\n return None in t", "matching_cluster_idx": 4}, {"solution": "def check_none(my_tuple):\n return None in my_tuple", "matching_cluster_idx": 5}, {"solution": "def check_none(tup):\n \"\"\"\n Check if the given tuple has any None value.\n :param tup: Tuple to check\n :return: True if the tuple contains None, False otherwise\n \"\"\"\n return None in tup", "matching_cluster_idx": 5}, {"solution": "def check_none(input_tuple):\n return None in input_tuple", "matching_cluster_idx": 5}, {"solution": "def check_none(tup):\n \"\"\"Return True if None is in the given tuple, else False.\"\"\"\n return None in tup", "matching_cluster_idx": 5}, {"solution": "def check_none(t):\n return None in t", "matching_cluster_idx": 4}, {"solution": "def check_none(t):\n \"\"\"\n This function checks if the given tuple has any None value or not.\n \"\"\"\n return None in t", "matching_cluster_idx": 5}, {"solution": "def check_none(t):\n return None in t", "matching_cluster_idx": 4}, {"solution": "def check_none(tup):\n return None in tup", "matching_cluster_idx": 5}, {"solution": "def check_none(t):\n return None in t", "matching_cluster_idx": 4}, {"solution": "def check_none(input_tuple):\n return None in input_tuple", "matching_cluster_idx": 5}]}, "Mbpp/750": {"dps": 59.625850340136054, "dps_norm": 65.0, "pass@1": 100.0, "profiled": [{"solution": "def add_tuple(lst, tpl):\n return lst + list(tpl)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(lst, tup):\n # Convert the tuple to a list.\n tup_list = list(tup)\n # Extend the original list with the contents of the tuple.\n lst.extend(tup_list)\n # Return the modified list.\n return lst", "matching_cluster_idx": 3}, {"solution": "def add_tuple(lst, tpl):\n lst.extend(tpl)\n return lst", "matching_cluster_idx": 4}, {"solution": "def add_tuple(list_a, tuple_b):\n return list_a + list(tuple_b)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(list_val, tuple_val):\n return list_val + list(tuple_val)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(input_list, input_tuple):\n # convert tuple to list\n tuple_list = list(input_tuple)\n \n # extend the initial list by the list form the tuple\n input_list.extend(tuple_list)\n \n # return the extended list\n return input_list", "matching_cluster_idx": 3}, {"solution": "def add_tuple(lst, tpl):\n lst.extend(tpl)\n return lst", "matching_cluster_idx": 4}, {"solution": "def add_tuple(lst, tpl):\n \"\"\"Add a tuple to a list.\"\"\"\n lst.extend(tpl)\n return lst", "matching_cluster_idx": 4}, {"solution": "def add_tuple(list_to_add_to, tuple_to_add):\n list_to_add_to.extend(tuple_to_add)\n return list_to_add_to", "matching_cluster_idx": 4}, {"solution": "def add_tuple(lst, tpl):\n \"\"\"Function to add a tuple to a list\"\"\"\n lst.extend(tpl)\n return lst", "matching_cluster_idx": 4}, {"solution": "def add_tuple(list_a, tuple_b):\n # Convert the tuple to a list, then concatenate with original list.\n list_b = list(tuple_b)\n list_a.extend(list_b)\n return list_a", "matching_cluster_idx": 3}, {"solution": "def add_tuple(list_input, tuple_input):\n return list_input + list(tuple_input)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(list_arg, tuple_arg):\n # This function adds a tuple to a list\n return list_arg + list(tuple_arg)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(list_to, tuple_to_add):\n return list_to + list(tuple_to_add)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(list_val, tuple_val):\n \"\"\"\n Function to add a tuple to a list.\n \n Parameters:\n list_val (list): The original list\n tuple_val (tuple): The tuple to be added to the list\n \n Returns:\n list: The list with the tuple added\n \"\"\"\n return list_val + list(tuple_val)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(input_list, input_tuple):\n \"\"\"\n This function adds the given tuple to the given list.\n :param input_list: list of integers\n :param input_tuple: tuple of integers\n :return: a new list that is a result of adding the tuple to the list\n \"\"\"\n input_list.extend(input_tuple)\n return input_list", "matching_cluster_idx": 4}, {"solution": "def add_tuple(lst, tpl):\n # add tuple to the list using the extend method\n lst.extend(tpl)\n return lst", "matching_cluster_idx": 4}, {"solution": "def add_tuple(list_in, tuple_in):\n return list_in + list(tuple_in)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(lst, tup):\n return lst + list(tup)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(list_input, tuple_input):\n # Convert the tuple to a list\n tuple_list = list(tuple_input)\n \n # Extend the input list with the elements of the tuple\n list_input.extend(tuple_list)\n \n return list_input", "matching_cluster_idx": 3}]}, "Mbpp/753": {"dps": 49.328859060402685, "dps_norm": 62.5, "pass@1": 96.0, "profiled": [{"solution": "def min_k(records, k):\n records.sort(key=lambda x: x[1])\n return records[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(tuples, k):\n return sorted(tuples, key=lambda x: x[1])[:k]", "matching_cluster_idx": 1}, {"solution": "def min_k(lst, k):\n # Sort the list by the second element of each tuple\n sorted_lst = sorted(lst, key=lambda x: x[1])\n \n # Return the first k elements of sorted list\n return sorted_lst[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(tuples, k):\n # use the inbuilt 'sorted' function to sort the tuples by the second element\n # use [:k] to get the first 'k' elements from the sorted list\n return sorted(tuples, key=lambda x: x[1])[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(records, k):\n return sorted(records, key=lambda x: x[1])[:k]", "matching_cluster_idx": 1}, {"solution": "def min_k(tuples_list, k):\n sorted_list = sorted(tuples_list, key=lambda x: x[1])\n return sorted_list[:k]", "matching_cluster_idx": 1}, {"solution": "def min_k(tup_list, k):\n sorted_list = sorted(tup_list, key=lambda x: x[1])\n return sorted_list[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(tuples, k):\n # Sort the list of tuples based on the second item of each tuple \n sorted_tuples = sorted(tuples, key=lambda x: x[1])\n # Return the first 'k' elements of the sorted list\n return sorted_tuples[:k]", "matching_cluster_idx": 1}, {"solution": "def min_k(lst, k):\n lst.sort(key = lambda x: x[1])\n return lst[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(tuples, k):\n tuples.sort(key=lambda x: x[1])\n return tuples[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(lst, k):\n # Sort the tuple list based on the second element of each tuple\n sorted_list = sorted(lst, key=lambda x: x[1])\n \n # Return the first k elements of sorted list\n return sorted_list[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(tup_list, k):\n # sort the tuple list by the second item of the tuple\n sorted_list = sorted(tup_list, key=lambda x: x[1])\n # return the first 'k' items of the sorted list\n return sorted_list[:k]", "matching_cluster_idx": 1}, {"solution": "def min_k(tuples, k):\n # Sort the tuples by the second element (i.e., the number)\n sorted_tuples = sorted(tuples, key=lambda x: x[1])\n \n # Return the first k tuples\n return sorted_tuples[:k]", "matching_cluster_idx": 1}, {"solution": "def min_k(tuple_list, k):\n # sort the list based on the second element of each tuple\n tuple_list.sort(key=lambda x: x[1])\n # return the first k elements of the sorted list\n return tuple_list[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(tuples, k):\n # Sort tuple list by the second element of each tuple and then slice first k elements\n return sorted(tuples, key=lambda x: x[1])[:k]", "matching_cluster_idx": 1}, {"solution": "def min_k(lst, k):\n \"\"\"\n Function to find minimum k records from tuple list.\n :param lst: Tuple List\n :param k: Number of minimum records to return\n :returns: List of k minimum records\n \"\"\"\n # sort the list by the second element of each tuple\n sorted_list = sorted(lst, key=lambda x: x[1])\n\n # return the first k elements of the sorted list\n return sorted_list[:k]", "matching_cluster_idx": 1}, {"solution": "def min_k(tuples_list, k):\n sorted_tuples_list = sorted(tuples_list, key=lambda x: x[1])\n return sorted_tuples_list[:k]", "matching_cluster_idx": 1}, {"solution": "def min_k(lst, k):\n # sort the list in increasing order of the second element of each tuple\n lst.sort(key=lambda x: x[1])\n\n # return the first k elements of the sorted list\n return lst[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(records, k):\n # Sort the list of records based on the second item in each tuple.\n records.sort(key=lambda x: x[1])\n \n # Return the first k items of sorted list.\n return records[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(tuples, k):\n return sorted(tuples, key=lambda x: x[1])[:k]", "matching_cluster_idx": 1}]}, "Mbpp/754": {"dps": 87.06896551724138, "dps_norm": 87.5, "pass@1": 47.0, "profiled": [{"solution": "def extract_index_list(l1, l2, l3):\n common = []\n for i in range(min(len(l1),len(l2),len(l3))):\n if l1[i] == l2[i] == l3[i]:\n common.append(l1[i])\n return common", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n # A list to store common elements\n common_elements = []\n\n # The zip function is used to iterate over three lists simultaneously\n for i, (e1, e2, e3) in enumerate(zip(l1, l2, l3)):\n # Checking if the elements are the same and the indices are the same\n if e1 == e2 == e3:\n common_elements.append(e1)\n\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n common_elements = []\n for i in range(min(len(l1),len(l2),len(l3))):\n if (l1[i] == l2[i] == l3[i]):\n common_elements.append(l1[i])\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n common_elements = []\n for i in range(min(len(l1),len(l2),len(l3))): # To avoid index error, we limit the iteration based on the shortest list length\n if l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n common = []\n for i, j, k in zip(l1, l2, l3):\n if i == j == k:\n common.append(i)\n return common", "matching_cluster_idx": 7}, {"solution": "def extract_index_list(l1, l2, l3):\n common_elements = []\n min_length = min(len(l1), len(l2), len(l3))\n \n for i in range(min_length):\n if l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n \n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n common_elements = []\n for i in range(min(len(l1), len(l2), len(l3))):\n if l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n common_list = [e1 for e1, e2, e3 in zip(l1, l2, l3) if e1 == e2 == e3]\n return common_list", "matching_cluster_idx": 7}, {"solution": "def extract_index_list(l1, l2, l3):\n \"\"\"This function finds common elements under the same index in three lists\"\"\"\n common_list = []\n for i in range(min(len(l1), len(l2), len(l3))):\n if l1[i] == l2[i] == l3[i]:\n common_list.append(l1[i])\n return common_list", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n common_elements = []\n for i in range(min(len(l1), len(l2), len(l3))):\n if l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n common_elements = []\n for i in range(min(len(l1), len(l2), len(l3))): # Find the common index among the three lists\n if l1[i] == l2[i] == l3[i]: # If the elements at the same index are the same\n common_elements.append(l1[i]) # Append it to the list of common elements\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n \"\"\"\n The function accepts three lists and returns a list with common elements at the same index in these lists.\n \"\"\"\n common_elements = []\n \n # Determine the minimum length among the lists to avoid index errors.\n min_length = min(len(l1), len(l2), len(l3))\n \n for i in range(min_length):\n # Check if an element at index i is the same in all lists.\n if l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n \n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n # zip the lists to have each tuple contain the elements at the same index\n zipped_lists = list(zip(l1, l2, l3))\n\n # the common_elements list will store the elements that are the same at the same index in all three lists\n common_elements = []\n\n # iterate over the zipped list to check the equality of elements at each index\n for elems in zipped_lists:\n # if all elements in the tuple are the same, that element is common\n if len(set(elems)) == 1:\n common_elements.append(elems[0])\n\n return common_elements", "matching_cluster_idx": 3}, {"solution": "def extract_index_list(l1, l2, l3):\n common_elements = []\n for i in range(min(len(l1), len(l2), len(l3))):\n if l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n return [l1[i] for i in range(min(len(l1), len(l2), len(l3))) if l1[i] == l2[i] == l3[i]]", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n common_elements = []\n for i in range(min(len(l1), len(l2), len(l3))):\n if l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n return [e1 for e1, e2, e3 in zip(l1, l2, l3) if e1 == e2 == e3]", "matching_cluster_idx": 7}, {"solution": "def extract_index_list(l1, l2, l3):\n common = []\n for i in range(min(len(l1), len(l2), len(l3))):\n if l1[i] == l2[i] == l3[i]:\n common.append(l1[i])\n return common", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n common = []\n for a, b, c in zip(l1, l2, l3):\n if a == b == c:\n common.append(a)\n return common", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n return [l1[i] for i in range(min(len(l1), len(l2), len(l3))) if l1[i] == l2[i] == l3[i]]", "matching_cluster_idx": 6}]}, "Mbpp/755": {"dps": 86.15044247787611, "dps_norm": 94.16666666666667, "pass@1": 34.0, "profiled": [{"solution": "def second_smallest(numbers):\n unique_numbers = list(set(numbers)) # Remove duplicate numbers\n unique_numbers.sort() # Sort the numbers\n if len(unique_numbers) < 2: # If the list contains less than 2 unique numbers\n return None\n else:\n return unique_numbers[1] # Return the second smallest number", "matching_cluster_idx": 5}, {"solution": "def second_smallest(nums):\n nums = list(set(nums)) # Remove any duplicate numbers\n nums.sort() # Sort the numbers in ascending order\n if len(nums) < 2:\n return None\n else:\n return nums[1] # Return the second smallest number", "matching_cluster_idx": 5}, {"solution": "def second_smallest(nums):\n nums = list(set(nums)) # remove duplicates\n nums.sort() # sort the list\n if len(nums) < 2:\n return None\n else:\n return nums[1] # return the second element which is the second smallest", "matching_cluster_idx": 5}, {"solution": "def second_smallest(nums):\n \"\"\"Find the second smallest number in a list.\"\"\"\n if len(nums) < 2:\n return None\n smallest = second_smallest = float('inf')\n for num in nums:\n if num < smallest:\n second_smallest = smallest\n smallest = num\n elif smallest < num < second_smallest:\n second_smallest = num\n return second_smallest if second_smallest != float('inf') else None", "matching_cluster_idx": 3}, {"solution": "def second_smallest(numbers):\n unique_numbers = list(set(numbers))\n unique_numbers.sort()\n return unique_numbers[1] if len(unique_numbers) > 1 else None", "matching_cluster_idx": 5}, {"solution": "def second_smallest(lst):\n # Initialise the smallest and second smallest \n smallest = float('inf')\n second_smallest = float('inf')\n\n for num in lst:\n # If current element is smaller than smallest \n if num < smallest:\n # Then update the second smallest \n second_smallest = smallest\n # And update the smallest\n smallest = num\n # If current element is in between smallest \n # And second smallest\n elif num < second_smallest and num != smallest:\n # Then update the second_smallest\n second_smallest = num\n\n # In case when there is no second_smallest\n if second_smallest == float('inf'):\n return None\n else:\n return second_smallest", "matching_cluster_idx": 4}, {"solution": "def second_smallest(nums):\n if len(nums)<2:\n return None\n smallest = min(nums)\n nums = [x for x in nums if x != smallest]\n second_smallest = min(nums) if nums else None\n return second_smallest", "matching_cluster_idx": 3}, {"solution": "def second_smallest(nums):\n nums = list(set(nums)) # remove duplicates\n nums.sort()\n return nums[1] if len(nums) > 1 else None", "matching_cluster_idx": 5}, {"solution": "def second_smallest(lst):\n unique_lst = list(set(lst))\n unique_lst.sort()\n return unique_lst[1] if len(unique_lst) > 1 else None", "matching_cluster_idx": 5}, {"solution": "def second_smallest(numbers):\n # check if the list has less than two elements\n if len(numbers) < 2:\n return None\n\n # initialize the smallest and second smallest numbers\n smallest = second_smallest_number = float('inf')\n\n for num in numbers:\n # skip the current number if it is larger than the second smallest number\n if num > second_smallest_number:\n continue\n # update the smallest number if a smaller number is found\n elif num < smallest:\n second_smallest_number = smallest\n smallest = num\n # otherwise update the second smallest number if a smaller number is found\n elif num < second_smallest_number and num != smallest:\n second_smallest_number = num\n \n return second_smallest_number if second_smallest_number != float('inf') else None", "matching_cluster_idx": 4}, {"solution": "def second_smallest(nums):\n nums = list(set(nums)) # remove duplicates\n nums.sort() # sort in ascending order\n if len(nums) < 2:\n return None\n else:\n return nums[1] # return the second smallest number", "matching_cluster_idx": 5}, {"solution": "def second_smallest(nums):\n nums = list(set(nums))\n nums.sort()\n return nums[1] if len(nums) > 1 else None", "matching_cluster_idx": 5}, {"solution": "def second_smallest(nums):\n nums = list(set(nums))\n nums.sort()\n return nums[1] if len(nums) > 1 else None", "matching_cluster_idx": 5}, {"solution": "def second_smallest(nums):\n nums = list(set(nums)) # remove duplicates\n nums.sort() # sort list\n if len(nums) >= 2:\n return nums[1] # return second element\n else:\n return None # if the list has less than 2 distinct numbers", "matching_cluster_idx": 5}, {"solution": "def second_smallest(numbers):\n numbers = list(set(numbers)) # remove duplicates\n numbers.sort()\n try:\n return numbers[1]\n except IndexError:\n return None", "matching_cluster_idx": 5}, {"solution": "def second_smallest(nums):\n nums = list(set(nums)) # remove duplicates\n nums.sort()\n if len(nums) < 2:\n return None\n else:\n return nums[1]", "matching_cluster_idx": 5}, {"solution": "def second_smallest(nums):\n # Put the numbers in a set to remove duplicates and sort in ascending order\n nums = sorted(set(nums))\n if len(nums) < 2:\n return None # return None if less than 2 unique numbers exist\n return nums[1] # return the second number", "matching_cluster_idx": 5}, {"solution": "def second_smallest(nums):\n unique_nums = list(set(nums))\n unique_nums.sort()\n return unique_nums[1] if len(unique_nums) > 1 else None", "matching_cluster_idx": 5}, {"solution": "def second_smallest(nums):\n nums = list(set(nums)) # remove duplicates\n nums.sort() # sort the list in ascending order\n if len(nums) < 2: # if the list has less than two elements\n return None # return None\n else:\n return nums[1] # return the second element", "matching_cluster_idx": 5}, {"solution": "def second_smallest(numbers):\n \"\"\"\n This function takes a list of numbers and returns the second smallest number in that list.\n If the list has less than 2 elements, it returns None.\n \"\"\"\n # If the list has less than 2 elements, return None\n if len(numbers) < 2:\n return None\n\n # Initialize the smallest and second smallest with the largest possible integer\n smallest = second_smallest = float('inf')\n\n # Traverse the list\n for num in numbers:\n # If the current number is smaller than the smallest number,\n # then update the second smallest with the value of the smallest,\n # and update the smallest with the current number\n if num < smallest:\n second_smallest = smallest\n smallest = num\n # If the current number is in between the smallest and the second smallest,\n # then update the second smallest with the current number\n elif num < second_smallest and num != smallest:\n second_smallest = num\n\n # If the second smallest remains as initialized,\n # then there was no second distinct number\n if second_smallest == float('inf'):\n return None\n else:\n return second_smallest", "matching_cluster_idx": 4}]}, "Mbpp/757": {"dps": 63.64485981308412, "dps_norm": 18.46153846153846, "pass@1": 93.0, "profiled": [{"solution": "def count_reverse_pairs(lst):\n return sum(1 for i in range(len(lst)) for j in range(i+1, len(lst)) if lst[i] == lst[j][::-1] or lst[j] == lst[i][::-1])", "matching_cluster_idx": 0}, {"solution": "def count_reverse_pairs(input_list):\n count = 0\n for i in range(len(input_list)):\n for j in range(i+1, len(input_list)):\n if input_list[i] == input_list[j][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(input_list):\n pair_count = 0\n for i in range(len(input_list)):\n for j in range(i+1, len(input_list)):\n if input_list[i][::-1] == input_list[j] or input_list[j][::-1] == input_list[i]:\n pair_count += 1\n return pair_count", "matching_cluster_idx": 0}, {"solution": "def count_reverse_pairs(str_list):\n count = 0\n for i in range(len(str_list)):\n for j in range(i + 1, len(str_list)):\n if str_list[i] == str_list[j][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(lst):\n return sum(1 for i in range(len(lst)) for j in range(i+1, len(lst)) if lst[i] == lst[j][::-1] or lst[j] == lst[i][::-1])", "matching_cluster_idx": 0}, {"solution": "def count_reverse_pairs(input_list):\n count = 0\n for i in range(len(input_list)):\n for j in range(i+1, len(input_list)):\n if input_list[i][::-1] == input_list[j] or input_list[j][::-1] == input_list[i]:\n count += 1\n return count", "matching_cluster_idx": 0}, {"solution": "def count_reverse_pairs(input_list):\n count = 0\n for i in range(len(input_list)):\n for j in range(i+1, len(input_list)):\n if input_list[i] == input_list[j][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(lst):\n count = 0\n for i in range(len(lst)):\n for j in range(i+1, len(lst)):\n if lst[i] == lst[j][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(input_list):\n count = 0\n for i in range(len(input_list)):\n for j in range(i + 1, len(input_list)):\n if input_list[i] == input_list[j][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(input_list):\n pair_count = 0\n for i in range(len(input_list)):\n for j in range(i+1, len(input_list)):\n if input_list[i] == input_list[j][::-1]:\n pair_count += 1\n return pair_count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(lst):\n count = 0\n for i in range(len(lst)):\n for j in range(i + 1, len(lst)):\n if lst[i] == lst[j][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(lst):\n count = 0\n for i in range(len(lst)):\n for j in range(i+1, len(lst)):\n if lst[i][::-1] == lst[j] or lst[j][::-1] == lst[i]:\n count += 1\n return count", "matching_cluster_idx": 0}, {"solution": "def count_reverse_pairs(str_list):\n count = 0\n for i in range(len(str_list)):\n for j in range(i + 1, len(str_list)):\n if str_list[i] == str_list[j][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(string_list):\n pair_counter = 0\n for i in range(len(string_list)):\n for j in range(i + 1, len(string_list)):\n if string_list[i] == string_list[j][::-1]:\n pair_counter += 1\n return pair_counter", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(lst):\n count = 0\n for i in range(len(lst)):\n for j in range(i+1, len(lst)):\n if lst[i] == lst[j][::-1] or lst[j] == lst[i][::-1]:\n count += 1\n return count", "matching_cluster_idx": 0}, {"solution": "def count_reverse_pairs(lst):\n return sum(1 for i in range(len(lst)) for j in range(i + 1, len(lst)) if lst[i] == lst[j][::-1])", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(string_list):\n count = 0\n for i, string1 in enumerate(string_list):\n for string2 in string_list[i+1:]:\n if string1 == string2[::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(lst):\n pairs = 0\n for i in range(len(lst)):\n for j in range(i + 1, len(lst)):\n if lst[i] == lst[j][::-1]:\n pairs += 1\n return pairs", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(s_list):\n count = 0\n for i in range(len(s_list)):\n for j in range(i+1, len(s_list)):\n if s_list[i] == s_list[j][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(string_list):\n pair_count = 0\n for i in range(len(string_list)):\n for j in range(i+1, len(string_list)):\n if string_list[i] == string_list[j][::-1]:\n pair_count += 1\n return pair_count", "matching_cluster_idx": 2}]}, "Mbpp/758": {"dps": 81.87258687258687, "dps_norm": 81.25, "pass@1": 99.0, "profiled": [{"solution": "def unique_sublists(lst):\n result = {}\n for sublist in lst:\n sublist_tuple = tuple(sublist)\n if sublist_tuple in result:\n result[sublist_tuple] += 1\n else:\n result[sublist_tuple] = 1\n return result", "matching_cluster_idx": 5}, {"solution": "def unique_sublists(lst):\n result = {}\n for sublist in lst:\n sublist_tuple = tuple(sublist)\n if sublist_tuple in result:\n result[sublist_tuple] += 1\n else:\n result[sublist_tuple] = 1\n return result", "matching_cluster_idx": 5}, {"solution": "def unique_sublists(lst):\n dic = {}\n for sublist in lst:\n sublist_tuple = tuple(sublist)\n if sublist_tuple in dic:\n dic[sublist_tuple] += 1\n else:\n dic[sublist_tuple] = 1\n return dic", "matching_cluster_idx": 5}, {"solution": "def unique_sublists(lst):\n result = {}\n for sublist in lst:\n tuple_sublist = tuple(sublist)\n if tuple_sublist not in result:\n result[tuple_sublist] = 1\n else:\n result[tuple_sublist] += 1\n return result", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(lst):\n output = {}\n for sublist in lst:\n # Convert list to tuple for hashing purposes\n sublist_tuple = tuple(sublist)\n if sublist_tuple in output:\n output[sublist_tuple] += 1\n else:\n output[sublist_tuple] = 1\n return output", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(lst):\n result = {}\n for sublist in lst:\n tuple_sublist = tuple(sublist)\n if tuple_sublist in result:\n result[tuple_sublist] += 1\n else:\n result[tuple_sublist] = 1\n return result", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(lst):\n result = {}\n for sublist in lst:\n sublist_tuple = tuple(sublist)\n if sublist_tuple in result:\n result[sublist_tuple] += 1\n else:\n result[sublist_tuple] = 1\n return result", "matching_cluster_idx": 5}, {"solution": "def unique_sublists(lst):\n result = {}\n for sublist in lst:\n sublist_tuple = tuple(sublist)\n if sublist_tuple in result:\n result[sublist_tuple] += 1\n else:\n result[sublist_tuple] = 1\n return result", "matching_cluster_idx": 5}, {"solution": "def unique_sublists(lst):\n dict_result = {}\n for sublist in lst:\n sublist_tuple = tuple(sublist)\n if sublist_tuple in dict_result:\n dict_result[sublist_tuple] += 1\n else:\n dict_result[sublist_tuple] = 1\n return dict_result", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(lst):\n result = {}\n for sublist in lst:\n tuple_sublist = tuple(sublist)\n if tuple_sublist in result:\n result[tuple_sublist] += 1\n else:\n result[tuple_sublist] = 1\n return result", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(lst):\n \"\"\"\n This function counts the number of occurrences of sublists within a main list.\n It converts sublists to tuples to ensure immutability, and use a dictionary to count occurrences.\n \"\"\"\n \n # convert all lists to tuples\n lst_tuples = [tuple(sublist) for sublist in lst]\n \n # create an empty dictionary\n dict_sublists = {}\n \n # iterate over the list of tuples\n for tpl in lst_tuples:\n # if the tuple is not in the dictionary, add it with a value of 1\n # if it is in the dictionary, increment the value by 1\n if tpl not in dict_sublists:\n dict_sublists[tpl] = 1\n else:\n dict_sublists[tpl] += 1\n \n # return the dictionary\n return dict_sublists", "matching_cluster_idx": 5}, {"solution": "def unique_sublists(lst):\n result_dict = {}\n for sublist in lst:\n tuple_sublist = tuple(sublist)\n if tuple_sublist in result_dict:\n result_dict[tuple_sublist] += 1\n else:\n result_dict[tuple_sublist] = 1\n return result_dict", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(lst):\n # Initialize empty dictionary\n result = {}\n\n # Go through every list (sub_lst) in the list (lst)\n for sub_lst in lst:\n # Convert each list to a tuple\n tpl = tuple(sub_lst)\n \n # If the tuple is not yet in the dictionary, add it and initialize its value to 1\n # If the tuple is already in the dictionary, increment its value by 1\n if tpl not in result:\n result[tpl] = 1\n else:\n result[tpl] += 1\n\n # Return the resulting dictionary\n return result", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(lst):\n counts = {}\n for sublist in lst:\n # convert list to tuple because lists are not hashable and cannot be keys in a dictionary\n sublist_tuple = tuple(sublist)\n if sublist_tuple in counts:\n counts[sublist_tuple] += 1\n else:\n counts[sublist_tuple] = 1\n return counts", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(lst):\n dict_counter = {}\n for sublist in lst:\n tuple_sublist = tuple(sublist)\n if tuple_sublist in dict_counter:\n dict_counter[tuple_sublist] += 1\n else:\n dict_counter[tuple_sublist] = 1\n return dict_counter", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(lst):\n # Converting each sublist to a tuple and creating a dictionary\n # where keys are tuples and values are their counts\n return {tuple(i): lst.count(i) for i in lst}", "matching_cluster_idx": 3}, {"solution": "def unique_sublists(lst):\n result = {}\n for sublist in lst:\n tuple_sublist = tuple(sublist)\n if tuple_sublist in result:\n result[tuple_sublist] += 1\n else:\n result[tuple_sublist] = 1\n return result", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(input_list):\n result = {}\n for sublist in input_list:\n sublist_tuple = tuple(sublist)\n if sublist_tuple in result:\n result[sublist_tuple] += 1\n else:\n result[sublist_tuple] = 1\n return result", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(lst):\n result = {}\n for sublist in lst:\n sublist_tuple = tuple(sublist)\n if sublist_tuple in result:\n result[sublist_tuple] += 1\n else:\n result[sublist_tuple] = 1\n return result", "matching_cluster_idx": 5}, {"solution": "def unique_sublists(lst):\n result = {}\n for l in lst:\n t = tuple(l)\n if t in result:\n result[t] += 1\n else:\n result[t] = 1\n return result", "matching_cluster_idx": 6}]}, "Mbpp/760": {"dps": 99.27007299270073, "dps_norm": 87.5, "pass@1": 81.0, "profiled": [{"solution": "def unique_Element(lst):\n return len(set(lst)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(nums):\n return len(set(nums)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(lst):\n return len(set(lst)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(input_list):\n \"\"\"Check if a list of numbers contains only one distinct element.\"\"\"\n return len(set(input_list)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(numbers):\n return len(set(numbers)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(numbers):\n return len(set(numbers)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(nums):\n return len(set(nums)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(num_list):\n # Converts the list to a set.\n # In Python, a set only holds unique elements.\n # Thus, if the length of the set is 1, the original list only contains one distinct element.\n return len(set(num_list)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(lst):\n return len(set(lst)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(nums):\n return len(set(nums)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(lst):\n return len(set(lst)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(nums):\n return len(set(nums)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(num_list):\n \"\"\"\n This function checks if a list contains only one distinct element.\n \n Parameters:\n num_list (list): A list of numbers.\n\n Returns:\n bool: True if the list contains only one distinct element, False otherwise.\n \"\"\"\n return len(set(num_list)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(lst):\n \"\"\"\n This function checks whether a list of numbers contains only one distinct element or not.\n \"\"\"\n return len(set(lst)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(list):\n return len(set(list)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(num_list):\n return len(set(num_list)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(lst):\n return len(set(lst)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(lst):\n \"\"\"\n This function checks whether a list contains only one distinct element or not.\n :param lst: A list of numbers.\n :return: True if the list contains only one distinct element, False otherwise.\n \"\"\"\n return len(set(lst)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(list):\n return len(set(list)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(lst):\n return len(set(lst)) == 1", "matching_cluster_idx": 6}]}, "Mbpp/764": {"dps": 88.88888888888889, "dps_norm": 50.0, "pass@1": 100.0, "profiled": [{"solution": "def number_ctr(s):\n return sum(c.isdigit() for c in s)", "matching_cluster_idx": 2}, {"solution": "def number_ctr(str1):\n ctr = 0\n for char in str1:\n if char.isdigit():\n ctr += 1\n return ctr", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n return sum(c.isdigit() for c in s)", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n return sum(c.isdigit() for c in s)", "matching_cluster_idx": 2}, {"solution": "def number_ctr(str):\n return sum(c.isdigit() for c in str)", "matching_cluster_idx": 2}, {"solution": "def number_ctr(input_str):\n count = sum(c.isdigit() for c in input_str)\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n return sum(c.isdigit() for c in s)", "matching_cluster_idx": 2}, {"solution": "def number_ctr(input_string):\n count = 0\n for i in input_string:\n if i.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(input_string):\n count = sum(1 for char in input_string if char.isdigit())\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(input_string):\n return sum(c.isdigit() for c in input_string)", "matching_cluster_idx": 2}, {"solution": "def number_ctr(input_str):\n return sum(c.isdigit() for c in input_str)", "matching_cluster_idx": 2}, {"solution": "def number_ctr(input_str):\n return sum(c.isdigit() for c in input_str)", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n count = sum(c.isdigit() for c in s)\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(string):\n \"\"\"\n This function takes in a string and returns the count of digits in that string.\n \"\"\"\n return sum(c.isdigit() for c in string)", "matching_cluster_idx": 2}, {"solution": "def number_ctr(input_string):\n count = sum(1 for char in input_string if char.isdigit())\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(input_string):\n return sum(1 for char in input_string if char.isdigit())", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n return sum(c.isdigit() for c in s)", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n return sum(c.isdigit() for c in s)", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n return sum(c.isdigit() for c in s)", "matching_cluster_idx": 2}, {"solution": "def number_ctr(input_string):\n return sum(c.isdigit() for c in input_string)", "matching_cluster_idx": 2}]}, "Mbpp/766": {"dps": 79.11214953271028, "dps_norm": 65.83333333333334, "pass@1": 100.0, "profiled": [{"solution": "def pair_wise(l):\n return [(l[i], l[i+1]) for i in range(len(l)-1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n return [(lst[i], lst[i+1]) for i in range(len(lst)-1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n return [(lst[i], lst[i + 1]) for i in range(len(lst) - 1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n return [(lst[i], lst[i+1]) for i in range(len(lst)-1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n return [(lst[i], lst[i + 1]) for i in range(len(lst) - 1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n return [(lst[i], lst[i + 1]) for i in range(len(lst) - 1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(input_list):\n return [(input_list[i], input_list[i + 1]) for i in range(len(input_list) - 1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(input_list):\n return [(input_list[i], input_list[i + 1]) for i in range(len(input_list)-1)]", "matching_cluster_idx": 2}, {"solution": "def pair_wise(lst):\n return [(lst[i], lst[i+1]) for i in range(len(lst)-1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n return [(lst[i], lst[i+1]) for i in range(len(lst)-1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n return [(lst[i], lst[i + 1]) for i in range(len(lst) - 1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n return [(lst[i], lst[i+1]) for i in range(len(lst)-1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(input_list):\n return [(input_list[i], input_list[i + 1]) for i in range(len(input_list) - 1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n return [(lst[i], lst[i+1]) for i in range(len(lst)-1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(input_list):\n return [(input_list[i], input_list[i+1]) for i in range(len(input_list)-1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(input_list):\n return [(input_list[i], input_list[i + 1]) for i in range(len(input_list) - 1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n return [(lst[i], lst[i+1]) for i in range(len(lst)-1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n return [(lst[i], lst[i + 1]) for i in range(len(lst) - 1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n return [(lst[i], lst[i + 1]) for i in range(len(lst) - 1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n return [(lst[i], lst[i + 1]) for i in range(len(lst) - 1)]", "matching_cluster_idx": 3}]}, "Mbpp/775": {"dps": 75.67999999999999, "dps_norm": 52.857142857142854, "pass@1": 91.0, "profiled": [{"solution": "def odd_position(nums):\n for i in range(len(nums)):\n if i % 2 != 0 and nums[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 2}, {"solution": "def odd_position(lst):\n for i in range(len(lst)):\n # only check for odd indexes\n if i % 2 != 0:\n # check if the element on the odd index is also odd\n if lst[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 2}, {"solution": "def odd_position(lst):\n for i in range(1, len(lst), 2):\n if lst[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n for i in range(len(lst)):\n if i % 2 != 0 and lst[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 2}, {"solution": "def odd_position(nums):\n for i in range(len(nums)):\n if i % 2 != 0 and nums[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 2}, {"solution": "def odd_position(lst):\n for i in range(len(lst)):\n if i % 2 != 0 and lst[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 2}, {"solution": "def odd_position(nums):\n # check every odd indexed element\n for i in range(1, len(nums), 2):\n # if the element at odd index is not odd\n if nums[i] % 2 == 0:\n # return False and stop checking\n return False\n # If the function hasn't returned yet, all odd-indexed elements are odd\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(input_list):\n for i in range(1, len(input_list), 2):\n if input_list[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n for i in range(len(lst)):\n if i % 2 != 0 and lst[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 2}, {"solution": "def odd_position(lst):\n for i in range(len(lst)):\n if i % 2 != 0 and lst[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 2}, {"solution": "def odd_position(l):\n for i in range(1, len(l), 2):\n if l[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(l):\n for i in range(len(l)):\n if i % 2 != 0 and l[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 2}, {"solution": "def odd_position(lst):\n return all(num % 2 == 1 for num in lst[1::2])", "matching_cluster_idx": 4}, {"solution": "def odd_position(nums):\n # Iterate over the list using step size of 2, starting at index 1\n for i in range(1, len(nums), 2):\n # Check if the number at the odd position is even\n if nums[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n # check each item in list if its index is odd and the item itself is even\n for i in range(len(lst)):\n if i % 2 != 0 and lst[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 2}, {"solution": "def odd_position(lst):\n for i in range(len(lst)):\n if i%2 != 0 and lst[i]%2 == 0:\n return False\n return True", "matching_cluster_idx": 2}, {"solution": "def odd_position(numbers):\n for i in range(len(numbers)):\n if i % 2 != 0 and numbers[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 2}, {"solution": "def odd_position(lst):\n \"\"\"Check whether every odd index contains odd number.\"\"\"\n for i in range(len(lst)):\n if i % 2 != 0 and lst[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 2}, {"solution": "def odd_position(lst):\n for i in range(len(lst)):\n if i % 2 != 0 and lst[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 2}, {"solution": "def odd_position(lst):\n # Check if the element in the odd position is odd\n for i in range(1, len(lst), 2):\n if lst[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}]}, "Mbpp/777": {"dps": null, "dps_norm": null, "pass@1": 5.0, "profiled": []}, "Mbpp/781": {"dps": 95.8267716535433, "dps_norm": 83.0, "pass@1": 98.0, "profiled": [{"solution": "def count_divisors(n):\n count = 0\n for i in range(1, int(n**0.5)+1):\n if n % i == 0:\n # If divisors are equal, count only once\n if n // i == i:\n count += 1\n else: \n # Otherwise count both\n count += 2\n return count % 2 == 0", "matching_cluster_idx": 4}, {"solution": "def count_divisors(n):\n count = 0\n for i in range(1, int(n ** 0.5) + 1):\n if n % i == 0:\n # In case of a divisor pair like (2, 4)\n if i == n // i:\n count += 1\n else: # (2, 5) for number 10\n count += 2\n return count % 2 == 0", "matching_cluster_idx": 4}, {"solution": "def count_divisors(n):\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n # If divisors are equal, add only once\n if i == (n // i):\n count += 1\n else: # Otherwise add twice\n count += 2\n\n return count % 2 == 0", "matching_cluster_idx": 3}, {"solution": "def count_divisors(n):\n divisor_count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n divisor_count += 1\n return divisor_count % 2 == 0", "matching_cluster_idx": 1}, {"solution": "def count_divisors(n):\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n if n/i == i: # If divisors are equal, count only once\n count += 1\n else: # Otherwise, count both divisors\n count += 2\n return count % 2 == 0", "matching_cluster_idx": 4}, {"solution": "def count_divisors(n):\n count = 0\n for i in range(1, int(n**0.5)+1):\n if n % i == 0:\n if n / i == i:\n count = count + 1\n else:\n count = count + 2\n return count % 2 == 0", "matching_cluster_idx": 4}, {"solution": "def count_divisors(n):\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n count += 2 if n // i != i else 1\n return count % 2 == 0", "matching_cluster_idx": 4}, {"solution": "def count_divisors(n):\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n # If divisors are equal, count only one\n if n / i == i:\n count += 1\n else: # Otherwise count both\n count += 2\n return count % 2 == 0", "matching_cluster_idx": 4}, {"solution": "def count_divisors(n):\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count % 2 == 0", "matching_cluster_idx": 1}, {"solution": "def count_divisors(n):\n count = 0\n for i in range(1, int(n**0.5)+1):\n if n % i == 0:\n count += 2\n if i*i == n:\n count -= 1\n return count % 2 == 0", "matching_cluster_idx": 3}, {"solution": "def count_divisors(n):\n cnt = 0\n for i in range(1, n + 1):\n if n % i == 0:\n cnt += 1\n return cnt % 2 == 0", "matching_cluster_idx": 1}, {"solution": "def count_divisors(n):\n count = 0\n for i in range(1, int(n ** 0.5) + 1):\n if n % i == 0:\n if i == n / i:\n count += 1\n else:\n count += 2\n return count % 2 == 0", "matching_cluster_idx": 4}, {"solution": "def count_divisors(n):\n count = 0\n for i in range(1, int(n**0.5)+1):\n if n % i == 0:\n if n / i == i:\n count = count + 1\n else:\n count = count + 2\n if count % 2 == 0:\n return True\n else:\n return False", "matching_cluster_idx": 4}, {"solution": "def count_divisors(n):\n divisors_count = 0\n for i in range(1, int(n ** 0.5) + 1):\n if n % i == 0:\n divisors_count += 2 if i != n // i else 1\n return divisors_count % 2 == 0", "matching_cluster_idx": 4}, {"solution": "def count_divisors(n):\n count = 0\n for i in range(1, int(n**0.5)+1):\n if n % i == 0:\n if i == n/i:\n count += 1\n else:\n count += 2\n return count % 2 == 0", "matching_cluster_idx": 4}, {"solution": "def count_divisors(n):\n \"\"\"\n This function returns whether the count of divisors for a given number is even or not.\n \n Args:\n n (int): the number to be checked\n\n Returns:\n bool: whether the count of divisors is even\n \"\"\"\n div_count = 0\n for i in range(1, int(n ** 0.5) + 1):\n if n % i == 0:\n # If divisors are equal then add only one\n if n / i == i:\n div_count += 1\n else: # Otherwise add both\n div_count += 2\n\n return div_count % 2 == 0", "matching_cluster_idx": 4}, {"solution": "def count_divisors(n):\n count = 0\n for i in range(1, int(n ** 0.5) + 1):\n if n % i == 0:\n if i == n // i:\n count += 1\n else:\n count += 2\n return count % 2 == 0", "matching_cluster_idx": 4}, {"solution": "def count_divisors(num):\n \"\"\"\n This function receives a number and returns whether the count of its divisors is even.\n \"\"\"\n count = 0\n for i in range(1, num + 1):\n if num % i == 0:\n count += 1\n return count % 2 == 0", "matching_cluster_idx": 1}, {"solution": "def count_divisors(n):\n \"\"\" \n Function to check whether the count of divisors is even\n \"\"\"\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n if n / i == i:\n count = count + 1\n else:\n count = count + 2\n return count % 2 == 0", "matching_cluster_idx": 4}, {"solution": "def count_divisors(num):\n count = 0\n for i in range(1, num + 1):\n if num % i == 0:\n count += 1\n return count % 2 == 0", "matching_cluster_idx": 1}]}, "Mbpp/800": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def remove_all_spaces(string):\n return string.replace(' ', '')", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n return input_string.replace(' ', '')", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(s):\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_str):\n return input_str.replace(' ', '')", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n return input_string.replace(' ', '')", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(s):\n return s.replace(' ', '')", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n return input_string.replace(' ', '')", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(s):\n return s.replace(' ', '')", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(s):\n return s.replace(' ', '')", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(s):\n return s.replace(' ', '')", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(str):\n return str.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(s):\n return s.replace(' ', '')", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n return input_string.replace(' ', '')", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(s):\n return s.replace(' ', '')", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n \"\"\"\n Remove all spaces from the input string and return the result.\n \"\"\"\n return input_string.replace(' ', '')", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(s):\n return s.replace(' ', '')", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_str):\n return input_str.replace(' ', '')", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n return input_string.replace(' ', '')", "matching_cluster_idx": 4}]}, "Mbpp/805": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 95.0, "profiled": [{"solution": "def max_sum_list(lst):\n return max(lst, key=sum)", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lst):\n max_sum = float('-inf')\n max_list = None\n for sublist in lst:\n sublist_sum = sum(sublist)\n if sublist_sum > max_sum:\n max_sum = sublist_sum\n max_list = sublist\n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(list_of_lists):\n return max(list_of_lists, key=sum)", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lst):\n return max(lst, key=sum)", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n # Use the max function with the sum function as key\n return max(lists, key=sum)", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(list_of_lists):\n return max(list_of_lists, key=sum)", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(list_of_lists):\n \"\"\"\n Returns the list in a list of lists whose sum of elements is the highest.\n \"\"\"\n return max(list_of_lists, key=sum)", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(list_of_lists):\n return max(list_of_lists, key=sum)", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lst):\n return max(lst, key=sum)", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n return max(lists, key=sum)", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lst):\n return max(lst, key=sum)", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(list_of_lists):\n \"\"\"\n Returns the list in a list of lists whose sum of elements is the highest.\n\n Args:\n list_of_lists (list): A list of lists of integers.\n\n Returns:\n list: The list whose sum of elements is the highest.\n \"\"\"\n return max(list_of_lists, key=sum)", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(list_of_lists):\n max_list = max(list_of_lists, key=sum)\n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lst):\n return max(lst, key=sum)", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lst):\n return max(lst, key=sum)", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n return max(lists, key=sum)", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n # using max function with key as sum for getting the list with max sum of elements\n return max(lists, key=sum)", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n return max(lists, key=sum)", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lst):\n return max(lst, key=sum)", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(list_of_lists):\n return max(list_of_lists, key=sum)", "matching_cluster_idx": 4}]}, "Mbpp/808": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def check_K(tup, k):\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(tuples, k):\n return k in tuples", "matching_cluster_idx": 5}, {"solution": "def check_K(tuples, k):\n return k in tuples", "matching_cluster_idx": 5}, {"solution": "def check_K(t, k):\n \"\"\"\n This function checks if a given tuple contains the specified value.\n :param t: a tuple of numbers\n :param k: the value to check for\n :return: True if the value is in the tuple; False otherwise\n \"\"\"\n return k in t", "matching_cluster_idx": 5}, {"solution": "def check_K(input_tuple, k):\n return k in input_tuple", "matching_cluster_idx": 5}, {"solution": "def check_K(input_tuple, k):\n return k in input_tuple", "matching_cluster_idx": 5}, {"solution": "def check_K(tuples, k):\n return k in tuples", "matching_cluster_idx": 5}, {"solution": "def check_K(tuples, k):\n return k in tuples", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(t, k):\n return k in t", "matching_cluster_idx": 5}, {"solution": "def check_K(t, k):\n return k in t", "matching_cluster_idx": 5}, {"solution": "def check_K(t, k):\n return k in t", "matching_cluster_idx": 5}, {"solution": "def check_K(tuple, k):\n return k in tuple", "matching_cluster_idx": 5}, {"solution": "def check_K(input_tuple, k):\n return k in input_tuple", "matching_cluster_idx": 5}, {"solution": "def check_K(t, k):\n return k in t", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(t, k):\n return k in t", "matching_cluster_idx": 5}, {"solution": "def check_K(tpl, k):\n return k in tpl", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n return k in tup", "matching_cluster_idx": 5}]}}} \ No newline at end of file diff --git a/results/evalperf/Qwen--Qwen2.5-14B-Instruct_vllm_temp_1.0_evalperf_results.brief.json b/results/evalperf/Qwen--Qwen2.5-14B-Instruct_vllm_temp_1.0_evalperf_results.brief.json new file mode 100644 index 0000000..47b5fc3 --- /dev/null +++ b/results/evalperf/Qwen--Qwen2.5-14B-Instruct_vllm_temp_1.0_evalperf_results.brief.json @@ -0,0 +1 @@ +{"date": "2024-10-19 16:30", "config": {"n_samples": 100, "temperature": 1.0, "min_correct": 10, "max_profile": 20}, "summary": {"dps": 82.48566826452165, "dps_norm": 77.66575182191508, "pass@1": 82.48305084745763}, "eval": {"HumanEval/9": {"dps": 98.15457413249212, "dps_norm": 97.77777777777777, "pass@1": 65.0, "profiled": [{"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n \"\"\"\n if not numbers:\n return []\n \n # Initialize the rolling max list with the first element of the input list\n max_till_now = [numbers[0]]\n \n # Iterate through the numbers, updating the rolling max list\n for num in numbers[1:]:\n current_max = max(max_till_now[-1], num)\n max_till_now.append(current_max)\n \n return max_till_now", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n \"\"\"\n if not numbers:\n return []\n \n max_so_far = numbers[0]\n rolling_maxima = [max_so_far]\n \n for number in numbers[1:]:\n if number > max_so_far:\n max_so_far = number\n rolling_maxima.append(max_so_far)\n \n return rolling_maxima", "matching_cluster_idx": 8}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n \"\"\"\n if not numbers:\n return []\n \n max_so_far = numbers[0]\n rolling_maxes = [max_so_far]\n \n for number in numbers[1:]:\n if number > max_so_far:\n max_so_far = number\n rolling_maxes.append(max_so_far)\n \n return rolling_maxes", "matching_cluster_idx": 8}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\"\n From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n \"\"\"\n if not numbers:\n return []\n \n max_so_far = numbers[0]\n rolling_max_list = [max_so_far]\n \n for num in numbers[1:]:\n if num > max_so_far:\n max_so_far = num\n rolling_max_list.append(max_so_far)\n \n return rolling_max_list", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\"\n From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n \n :param numbers: List[int] - A list of integers.\n :return: List[int] - A list of rolling maximum elements.\n \"\"\"\n if not numbers:\n return []\n \n max_so_far = numbers[0]\n rolling_max_list = [max_so_far]\n \n for number in numbers[1:]:\n if number > max_so_far:\n max_so_far = number\n rolling_max_list.append(max_so_far)\n \n return rolling_max_list", "matching_cluster_idx": 8}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n \"\"\"\n if not numbers:\n return []\n \n max_so_far = numbers[0]\n rolling_maxes = [max_so_far]\n \n for number in numbers[1:]:\n if number > max_so_far:\n max_so_far = number\n rolling_maxes.append(max_so_far)\n \n return rolling_maxes", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n \"\"\"\n if not numbers:\n return []\n \n max_so_far = numbers[0]\n rolling_max_list = [max_so_far]\n \n for num in numbers[1:]:\n if num > max_so_far:\n max_so_far = num\n rolling_max_list.append(max_so_far)\n \n return rolling_max_list", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n \n max_so_far = numbers[0]\n rolling_max_list = [max_so_far]\n \n for number in numbers[1:]:\n if number > max_so_far:\n max_so_far = number\n rolling_max_list.append(max_so_far)\n \n return rolling_max_list", "matching_cluster_idx": 8}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\"From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n \"\"\"\n if not numbers:\n return []\n \n max_so_far = numbers[0]\n result = [max_so_far]\n \n for number in numbers[1:]:\n if number > max_so_far:\n max_so_far = number\n result.append(max_so_far)\n \n return result", "matching_cluster_idx": 8}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n \"\"\"\n if not numbers:\n return []\n \n result = [numbers[0]]\n current_max = numbers[0]\n \n for number in numbers[1:]:\n if number > current_max:\n current_max = number\n result.append(current_max)\n \n return result", "matching_cluster_idx": 8}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n \n max_till_now = numbers[0]\n rolling_max_values = []\n \n for num in numbers:\n if num > max_till_now:\n max_till_now = num\n rolling_max_values.append(max_till_now)\n \n return rolling_max_values", "matching_cluster_idx": 8}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\"From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n \n max_so_far = numbers[0]\n rolling_max_list = [max_so_far]\n \n for num in numbers[1:]:\n if num > max_so_far:\n max_so_far = num\n rolling_max_list.append(max_so_far)\n \n return rolling_max_list", "matching_cluster_idx": 8}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\"\n From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n \"\"\"\n if not numbers:\n return []\n \n max_so_far = numbers[0]\n rolling_max_list = [max_so_far]\n \n for num in numbers[1:]:\n if num > max_so_far:\n max_so_far = num\n rolling_max_list.append(max_so_far)\n \n return rolling_max_list", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\"\n From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n \n :param numbers: List of integers\n :return: List of rolling maximums\n \n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n \n max_so_far = numbers[0]\n rolling_maxes = [max_so_far]\n \n for number in numbers[1:]:\n if number > max_so_far:\n max_so_far = number\n rolling_maxes.append(max_so_far)\n \n return rolling_maxes", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\"From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n \n max_so_far = numbers[0]\n rolling_max_list = [max_so_far]\n \n for number in numbers[1:]:\n if number > max_so_far:\n max_so_far = number\n rolling_max_list.append(max_so_far)\n \n return rolling_max_list", "matching_cluster_idx": 8}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\"\n From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n \"\"\"\n if not numbers:\n return []\n \n max_until_now = numbers[0]\n result = [max_until_now]\n \n for number in numbers[1:]:\n if number > max_until_now:\n max_until_now = number\n result.append(max_until_now)\n \n return result", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n\n max_so_far = numbers[0]\n rolling_max_list = [max_so_far]\n\n for number in numbers[1:]:\n if number > max_so_far:\n max_so_far = number\n rolling_max_list.append(max_so_far)\n\n return rolling_max_list", "matching_cluster_idx": 8}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\"From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n \"\"\"\n if not numbers:\n return []\n \n max_so_far = numbers[0]\n rolling_max_list = [max_so_far]\n \n for num in numbers[1:]:\n if num > max_so_far:\n max_so_far = num\n rolling_max_list.append(max_so_far)\n \n return rolling_max_list", "matching_cluster_idx": 8}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\"\n From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n \n :param numbers: List of integers.\n :return: List of rolling maximums.\n \"\"\"\n if not numbers:\n return []\n \n max_so_far = numbers[0]\n rolling_maxes = [max_so_far]\n \n for number in numbers[1:]:\n if number > max_so_far:\n max_so_far = number\n rolling_maxes.append(max_so_far)\n \n return rolling_maxes", "matching_cluster_idx": 8}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\"\n From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n \n :param numbers: List[int] - A list of integers.\n :return: List[int] - A list of rolling maximums.\n \"\"\"\n if not numbers:\n return []\n \n max_so_far = numbers[0]\n rolling_maxes = [max_so_far]\n \n for num in numbers[1:]:\n if num > max_so_far:\n max_so_far = num\n rolling_maxes.append(max_so_far)\n \n return rolling_maxes", "matching_cluster_idx": 8}]}, "HumanEval/0": {"dps": 42.20930232558139, "dps_norm": 55.714285714285715, "pass@1": 61.0, "profiled": [{"solution": "from typing import *\nfrom itertools import combinations\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\"Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n \"\"\"\n # Generate all possible pairs of numbers\n for num1, num2 in combinations(numbers, 2):\n # Check if the absolute difference between any pair is less than the threshold\n if abs(num1 - num2) < threshold:\n return True\n return False", "matching_cluster_idx": 5}, {"solution": "from typing import List\nimport doctest\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\"\n Check if in given list of numbers, any two numbers are closer to each other than given threshold.\n \n :param numbers: List of float numbers\n :param threshold: A float value representing the closeness threshold\n :return: A boolean value indicating if any two numbers are closer than the threshold\n \n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n # Sort the list to make it easier to find close numbers\n sorted_numbers = sorted(numbers)\n \n # Loop through the sorted list to compare each adjacent pair\n for i in range(len(sorted_numbers) - 1):\n if sorted_numbers[i + 1] - sorted_numbers[i] < threshold:\n return True\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\nimport doctest\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\"\n Check if in given list of numbers, are any two numbers closer to each other than given threshold.\n \n :param numbers: List of floating point numbers.\n :param threshold: A floating point threshold.\n :return: True if any two numbers are closer to each other than the threshold, False otherwise.\n \n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n # Sort the list to make comparison easier\n sorted_numbers = sorted(numbers)\n \n # Iterate through the list and check the difference between consecutive numbers\n for i in range(len(sorted_numbers) - 1):\n if sorted_numbers[i + 1] - sorted_numbers[i] < threshold:\n return True\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\nfrom itertools import combinations\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\"\n Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n \n :param numbers: List of floating-point numbers.\n :param threshold: A floating-point number representing the threshold for closeness.\n :return: True if any two numbers in the list are closer to each other than the threshold, False otherwise.\n \"\"\"\n # Generate all possible pairs of numbers in the list\n for num1, num2 in combinations(numbers, 2):\n if abs(num1 - num2) < threshold:\n return True\n return False", "matching_cluster_idx": 5}, {"solution": "from typing import List\nimport doctest\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\"\n Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n \n :param numbers: List of floating point numbers.\n :param threshold: A floating point threshold value.\n :return: True if any two numbers in the list are closer to each other than the threshold, False otherwise.\n \"\"\"\n # Sort the numbers first to make comparison easier\n numbers.sort()\n \n # Iterate through the sorted list and check the difference between adjacent elements\n for i in range(len(numbers) - 1):\n if numbers[i + 1] - numbers[i] < threshold:\n return True\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\nimport math\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\"\n Check if in given list of numbers, are any two numbers closer to each other than given threshold.\n \n :param numbers: List of floating point numbers\n :param threshold: A floating point threshold\n :return: True if any two numbers are closer than the threshold, otherwise False\n \"\"\"\n # First, sort the list to make comparison easier\n numbers.sort()\n \n # Iterate through the sorted list and check the difference between adjacent numbers\n for i in range(1, len(numbers)):\n if numbers[i] - numbers[i-1] < threshold:\n return True\n \n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\nimport math\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\"\n Check if in given list of numbers, are any two numbers closer to each other than given threshold.\n \n :param numbers: List of floating point numbers\n :param threshold: A floating point number representing the threshold distance\n :return: True if any two numbers are closer than the threshold, else False\n \"\"\"\n if len(numbers) < 2:\n return False\n \n # Sort the list to make it easier to find close numbers\n numbers.sort()\n \n for i in range(len(numbers) - 1):\n if abs(numbers[i] - numbers[i + 1]) < threshold:\n return True\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\nimport itertools\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\"\n Check if in given list of numbers, are any two numbers closer to each other than given threshold.\n \n :param numbers: List of floating point numbers.\n :param threshold: A floating point threshold to compare the distance between any two elements.\n :return: True if any two numbers in the list are closer to each other than the threshold, otherwise False.\n \"\"\"\n # Sort the list to make distance checking easier\n sorted_numbers = sorted(numbers)\n \n # Iterate through the sorted list and check the distance between consecutive elements\n for num1, num2 in zip(sorted_numbers, sorted_numbers[1:]):\n if abs(num1 - num2) < threshold:\n return True\n return False", "matching_cluster_idx": 2}, {"solution": "from typing import List\nimport doctest\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\"\n Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n \n :param numbers: List of floating point numbers\n :param threshold: A positive float representing the closeness threshold\n :return: True if any two numbers are closer than the threshold, otherwise False\n \n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n # Sort the list first to make it easier to find close elements\n numbers.sort()\n \n # Iterate through the list and check if the difference between consecutive numbers is less than the threshold\n for i in range(len(numbers) - 1):\n if numbers[i + 1] - numbers[i] < threshold:\n return True\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\nimport itertools\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\"\n Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n \n :param numbers: List of float numbers\n :param threshold: A float threshold to compare the distance between any two numbers\n :return: True if any two numbers are closer than the threshold, otherwise False\n \n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n # Sort the list first to make it easier to find close elements\n sorted_numbers = sorted(numbers)\n \n # Iterate through each pair of adjacent elements\n for num1, num2 in itertools.pairwise(sorted_numbers):\n # Check if the distance between the two elements is less than the threshold\n if abs(num1 - num2) < threshold:\n return True\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import *\nfrom typing import List\nimport doctest\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\"\n Check if in a given list of numbers, any two numbers are closer to each other than the given threshold.\n \n :param numbers: List of floating-point numbers.\n :param threshold: A floating-point number representing the distance threshold.\n :return: True if any two numbers in the list are closer to each other than the threshold, False otherwise.\n \"\"\"\n # Sort the list to make it easier to compare adjacent numbers\n sorted_numbers = sorted(numbers)\n # Iterate through the sorted list and check the difference between consecutive numbers\n for i in range(len(sorted_numbers) - 1):\n if abs(sorted_numbers[i] - sorted_numbers[i + 1]) < threshold:\n return True\n return False", "matching_cluster_idx": 2}, {"solution": "from typing import List\nimport doctest\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\"\n Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n \n :param numbers: List of float numbers\n :param threshold: A float value representing the threshold distance\n :return: True if any two numbers are closer than the threshold, otherwise False\n \n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n # Sort the list to make comparison easier\n sorted_numbers = sorted(numbers)\n \n # Iterate through the sorted list and check if any two consecutive numbers are closer than the threshold\n for i in range(len(sorted_numbers) - 1):\n if sorted_numbers[i + 1] - sorted_numbers[i] < threshold:\n return True\n \n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\nimport math\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\"\n Check if in given list of numbers, any two numbers are closer to each other than\n given threshold.\n \n :param numbers: List of floating point numbers.\n :param threshold: Threshold value for closeness.\n :return: True if any two numbers are closer than the threshold, otherwise False.\n \"\"\"\n # Sort the list to ensure we only need to check adjacent elements for closeness\n sorted_numbers = sorted(numbers)\n \n # Iterate through the sorted list and check the difference between adjacent elements\n for i in range(1, len(sorted_numbers)):\n if sorted_numbers[i] - sorted_numbers[i-1] < threshold:\n return True\n \n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\nimport math\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\"\n Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n \n :param numbers: List of float numbers.\n :param threshold: A float value as threshold.\n :return: True if any two numbers are closer to each other than the threshold, False otherwise.\n \"\"\"\n if len(numbers) < 2:\n return False\n \n # Sorting the list to ensure adjacent elements can be compared\n sorted_numbers = sorted(numbers)\n \n # Checking if adjacent elements are closer than the threshold\n for i in range(len(sorted_numbers) - 1):\n if math.fabs(sorted_numbers[i+1] - sorted_numbers[i]) < threshold:\n return True\n return False", "matching_cluster_idx": 2}, {"solution": "from typing import List\nimport math\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\"\n Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n \n :param numbers: List of float numbers.\n :param threshold: A float number representing the threshold for closeness.\n :return: True if any two numbers in the list are closer than the threshold, False otherwise.\n \"\"\"\n # Sort the list to make it easier to check pairs\n numbers.sort()\n \n # Iterate through the list, checking the distance between adjacent elements\n for i in range(1, len(numbers)):\n if numbers[i] - numbers[i-1] < threshold:\n return True\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\nimport math\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\"\n Check if in given list of numbers, are any two numbers closer to each other than given threshold.\n \n :param numbers: List of floating-point numbers.\n :param threshold: A floating-point number representing the minimum distance between any two numbers.\n :return: True if any two numbers are closer than the threshold, otherwise False.\n \"\"\"\n if len(numbers) < 2:\n return False\n \n # Sort the list to make distance checking easier\n numbers.sort()\n \n # Iterate through the sorted list to check the distance between consecutive numbers\n for i in range(len(numbers) - 1):\n if numbers[i + 1] - numbers[i] < threshold:\n return True\n \n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\nimport unittest\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\"\n Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n \"\"\"\n # First, sort the list to make comparison easier\n sorted_numbers = sorted(numbers)\n # Then, for each adjacent pair, check if the difference is less than the threshold\n for i in range(len(sorted_numbers) - 1):\n if sorted_numbers[i + 1] - sorted_numbers[i] < threshold:\n return True\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\nimport doctest\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\"\n Check if in given list of numbers, are any two numbers closer to each other than given threshold.\n \n :param numbers: List of floating point numbers.\n :param threshold: A floating point number representing the threshold.\n :return: True if any two numbers are closer to each other than the threshold, otherwise False.\n \n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n sorted_numbers = sorted(numbers)\n for i in range(len(sorted_numbers) - 1):\n if sorted_numbers[i + 1] - sorted_numbers[i] < threshold:\n return True\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\nimport math\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\"\n Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n \"\"\"\n if len(numbers) < 2:\n return False\n \n # Sort the numbers to make checking pairs easier\n sorted_numbers = sorted(numbers)\n \n # Iterate through the sorted list and check if adjacent elements are closer than the threshold\n for i in range(len(sorted_numbers) - 1):\n if math.fabs(sorted_numbers[i+1] - sorted_numbers[i]) < threshold:\n return True\n return False", "matching_cluster_idx": 2}, {"solution": "from typing import List\nfrom math import inf\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\"\n Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n \"\"\"\n # Sort the list to make comparison easier\n sorted_numbers = sorted(numbers)\n # Initialize minimum distance with infinity\n min_distance = inf\n \n # Iterate through the list comparing adjacent elements\n for i in range(len(sorted_numbers) - 1):\n # Calculate the distance between adjacent elements\n distance = sorted_numbers[i + 1] - sorted_numbers[i]\n # Update minimum distance if current distance is smaller\n if distance < min_distance:\n min_distance = distance\n \n # Check if minimum distance is less than the threshold\n return min_distance < threshold", "matching_cluster_idx": 1}]}, "HumanEval/4": {"dps": 24.050632911392405, "dps_norm": 40.0, "pass@1": 100.0, "profiled": [{"solution": "from typing import List\nfrom statistics import mean\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\"\n For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n \"\"\"\n # Calculate the mean of the dataset\n dataset_mean = mean(numbers)\n # Calculate the absolute differences between each element and the mean\n absolute_differences = [abs(x - dataset_mean) for x in numbers]\n # Calculate the mean of these absolute differences\n mad = mean(absolute_differences)\n return mad", "matching_cluster_idx": 0}, {"solution": "from typing import List\nfrom statistics import mean\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\"\n For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n \"\"\"\n if not numbers:\n return 0.0\n \n x_mean = mean(numbers)\n mad = mean(abs(x - x_mean) for x in numbers)\n \n return mad", "matching_cluster_idx": 0}, {"solution": "from typing import List\nfrom statistics import mean\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\"\n For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n \n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if not numbers:\n return 0.0\n \n avg = mean(numbers)\n return mean(abs(x - avg) for x in numbers)", "matching_cluster_idx": 0}, {"solution": "from typing import List\nfrom statistics import mean\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\"\n For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if not numbers:\n return 0.0\n \n # Calculate the mean of the dataset\n mean_value = mean(numbers)\n \n # Calculate the absolute differences between each element and the mean\n abs_diffs = [abs(x - mean_value) for x in numbers]\n \n # Calculate the mean of these absolute differences\n mad = mean(abs_diffs)\n \n return mad", "matching_cluster_idx": 0}, {"solution": "from typing import List\nfrom statistics import mean\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\"\n For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n \n :param numbers: List of floating point numbers\n :return: Mean Absolute Deviation as a float\n \"\"\"\n if not numbers:\n raise ValueError(\"Input list cannot be empty\")\n \n x_mean = mean(numbers)\n return mean(abs(x - x_mean) for x in numbers)", "matching_cluster_idx": 0}, {"solution": "from typing import List\nfrom statistics import mean\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\"\n For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n \n Args:\n numbers: List[float] - A list of input numbers\n \n Returns:\n float - The Mean Absolute Deviation of the input numbers\n \n Examples:\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n # Calculate mean of the numbers\n x_mean = mean(numbers)\n # Calculate absolute differences from the mean\n abs_diffs = [abs(x - x_mean) for x in numbers]\n # Return mean of absolute differences\n return mean(abs_diffs)", "matching_cluster_idx": 0}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\"\n For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n \"\"\"\n if not numbers:\n return 0.0\n \n mean_value = sum(numbers) / len(numbers)\n absolute_deviations = [abs(x - mean_value) for x in numbers]\n mad = sum(absolute_deviations) / len(numbers)\n return mad", "matching_cluster_idx": 3}, {"solution": "from typing import List\nfrom statistics import mean\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\"\n For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n \n :param numbers: List of numbers for which MAD is to be calculated\n :return: Mean Absolute Deviation as a float\n \"\"\"\n if not numbers:\n raise ValueError(\"The input list cannot be empty\")\n \n # Calculate the mean of the list\n mean_value = mean(numbers)\n # Calculate the absolute differences from the mean\n absolute_differences = [abs(x - mean_value) for x in numbers]\n # Calculate the mean of these absolute differences\n mad = mean(absolute_differences)\n \n return mad", "matching_cluster_idx": 0}, {"solution": "from typing import List\nfrom statistics import mean\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\"\n For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if not numbers:\n return 0.0 # Handle empty list to avoid division by zero\n\n mean_value = mean(numbers)\n absolute_differences = [abs(x - mean_value) for x in numbers]\n mad = mean(absolute_differences)\n return mad", "matching_cluster_idx": 0}, {"solution": "from typing import List\nfrom statistics import mean\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\"\n For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n \"\"\"\n if not numbers:\n return 0.0\n \n x_mean = mean(numbers)\n return mean(abs(x - x_mean) for x in numbers)", "matching_cluster_idx": 0}, {"solution": "from typing import List\nfrom statistics import mean\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\"\n For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n \n Args:\n numbers (List[float]): A list of floating point numbers\n \n Returns:\n float: The mean absolute deviation of the given numbers\n \"\"\"\n # Calculate the mean of the dataset\n numbers_mean = mean(numbers)\n \n # Calculate the absolute deviations from the mean\n absolute_deviations = [abs(num - numbers_mean) for num in numbers]\n \n # Calculate the mean of the absolute deviations\n mad = mean(absolute_deviations)\n \n return mad", "matching_cluster_idx": 0}, {"solution": "from typing import List\nfrom statistics import mean\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\"\n For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n \n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if not numbers:\n return 0.0 # Return 0 for an empty list or handle as required\n \n avg = mean(numbers)\n mad = sum(abs(num - avg) for num in numbers) / len(numbers)\n return mad", "matching_cluster_idx": 0}, {"solution": "from typing import List\nfrom statistics import mean\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\"\n For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n \"\"\"\n if not numbers:\n return 0.0\n \n # Calculate the mean of the dataset\n numbers_mean = mean(numbers)\n \n # Calculate the absolute differences between each number and the mean\n absolute_differences = [abs(number - numbers_mean) for number in numbers]\n \n # Calculate the mean of these absolute differences\n mad = mean(absolute_differences)\n return mad", "matching_cluster_idx": 0}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\"\n For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n \"\"\"\n if not numbers:\n raise ValueError(\"The input list cannot be empty.\")\n \n mean_value = sum(numbers) / len(numbers)\n mad = sum(abs(x - mean_value) for x in numbers) / len(numbers)\n return mad", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\"\n For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n \n :param numbers: List of input numbers\n :return: Mean Absolute Deviation as a float\n \"\"\"\n if not numbers:\n raise ValueError(\"Input list cannot be empty\")\n \n mean_value = sum(numbers) / len(numbers)\n absolute_deviations = [abs(x - mean_value) for x in numbers]\n return sum(absolute_deviations) / len(absolute_deviations)", "matching_cluster_idx": 3}, {"solution": "from typing import List\nfrom statistics import mean\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\"\n For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n \"\"\"\n # Calculate the mean of the dataset\n average = mean(numbers)\n # Calculate the absolute difference of each element from the mean\n absolute_differences = [abs(number - average) for number in numbers]\n # Calculate the mean of these absolute differences\n mad = mean(absolute_differences)\n return mad", "matching_cluster_idx": 0}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\"\n For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n \n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if not numbers:\n return 0.0\n \n mean_value = sum(numbers) / len(numbers)\n absolute_differences = [abs(x - mean_value) for x in numbers]\n return sum(absolute_differences) / len(absolute_differences)", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\"\n For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n \n :param numbers: List of numbers for which we calculate the Mean Absolute Deviation.\n :return: The Mean Absolute Deviation as a float.\n \"\"\"\n if not numbers:\n raise ValueError(\"The input list cannot be empty.\")\n \n mean_value = sum(numbers) / len(numbers)\n absolute_deviations = [abs(x - mean_value) for x in numbers]\n return sum(absolute_deviations) / len(numbers)", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\"\n For a given list of input numbers, calculate the Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n \"\"\"\n # Calculate the mean of the numbers\n mean_value = sum(numbers) / len(numbers)\n # Calculate the sum of absolute differences from the mean\n abs_diff_sum = sum(abs(x - mean_value) for x in numbers)\n # Calculate the mean absolute deviation\n mad = abs_diff_sum / len(numbers)\n return mad", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\"\n For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n \"\"\"\n if not numbers:\n return 0.0\n \n mean_value = sum(numbers) / len(numbers)\n absolute_differences = [abs(x - mean_value) for x in numbers]\n return sum(absolute_differences) / len(absolute_differences)", "matching_cluster_idx": 4}]}, "HumanEval/16": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n \"\"\"\n # Convert the string to lowercase to ignore case differences and use a set to store unique characters\n unique_chars = set(string.lower())\n # Return the number of unique characters\n return len(unique_chars)", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\"\n Given a string, find out how many distinct characters (regardless of case) does it consist of\n \"\"\"\n # Normalize the string to lowercase to ensure case-insensitive comparison\n normalized_string = string.lower()\n # Use a set to store unique characters\n unique_characters = set(normalized_string)\n # The number of unique characters is the size of the set\n return len(unique_characters)", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\"\n Given a string, find out how many distinct characters (regardless of case) does it consist of\n \n Args:\n string (str): The input string.\n \n Returns:\n int: The number of distinct characters in the string, case-insensitive.\n \"\"\"\n # Convert the string to lowercase to make the search case-insensitive\n lower_case_string = string.lower()\n \n # Use a set to store unique characters\n unique_chars = set(lower_case_string)\n \n # The number of unique characters is the size of the set\n return len(unique_chars)", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n \"\"\"\n # Convert the string to lowercase to ignore case differences\n lower_string = string.lower()\n \n # Use a set to store distinct characters\n distinct_chars = set(lower_string)\n \n # Return the number of distinct characters\n return len(distinct_chars)", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n \"\"\"\n # Convert the string to lowercase to ignore case differences and then to a set to remove duplicates\n distinct_chars = set(string.lower())\n return len(distinct_chars)", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\"\n Given a string, find out how many distinct characters (regardless of case) does it consist of\n \"\"\"\n # Convert the string to lowercase to ensure case-insensitivity and remove duplicates by converting to a set\n distinct_chars = set(string.lower())\n # Return the number of distinct characters\n return len(distinct_chars)", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\"\n Given a string, find out how many distinct characters (regardless of case) does it consist of.\n \n :param string: Input string\n :return: Number of distinct characters in the string, case-insensitive\n \"\"\"\n # Convert the string to lower case to make the function case-insensitive\n lower_case_string = string.lower()\n # Use a set to store unique characters\n distinct_chars = set(lower_case_string)\n # Return the number of distinct characters\n return len(distinct_chars)", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\"\n Given a string, find out how many distinct characters (regardless of case) does it consist of\n \n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lowercase to ignore case differences\n lower_case_string = string.lower()\n \n # Use a set to store unique characters\n unique_characters = set(lower_case_string)\n \n # Return the number of unique characters\n return len(unique_characters)", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\"\n Given a string, find out how many distinct characters (regardless of case) does it consist of\n \"\"\"\n # Convert the string to lowercase to ignore case differences\n lower_case_string = string.lower()\n \n # Use a set to store distinct characters\n distinct_chars = set(lower_case_string)\n \n # The number of distinct characters is the size of the set\n return len(distinct_chars)", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n \"\"\"\n # Convert the string to lowercase to ignore case differences and then convert to a set to find unique characters\n distinct_chars = set(string.lower())\n return len(distinct_chars)", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\"\n Given a string, find out how many distinct characters (regardless of case) does it consist of\n \"\"\"\n # Convert the string to lowercase to ensure case-insensitivity\n lowercase_string = string.lower()\n # Use a set to store distinct characters\n distinct_chars = set(lowercase_string)\n # Return the number of distinct characters\n return len(distinct_chars)", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lower case to make the character comparison case-insensitive\n lower_string = string.lower()\n # Use a set to store unique characters\n distinct_chars = set(lower_string)\n # The number of distinct characters is the size of the set\n return len(distinct_chars)", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\"\n Given a string, find out how many distinct characters (regardless of case) does it consist of\n \n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lowercase to ignore case and use a set to store unique characters\n distinct_chars = set(string.lower())\n return len(distinct_chars)", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\"\n Given a string, find out how many distinct characters (regardless of case) does it consist of.\n \n Args:\n string (str): The input string.\n \n Returns:\n int: The number of distinct characters in the string, case-insensitive.\n \"\"\"\n # Convert string to lowercase to make the count case-insensitive\n lower_case_string = string.lower()\n # Use a set to store distinct characters\n distinct_characters = set(lower_case_string)\n # Return the number of distinct characters\n return len(distinct_characters)", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\"\n Given a string, find out how many distinct characters (regardless of case) does it consist of.\n \n :param string: Input string\n :return: Number of distinct characters in the string, case-insensitive\n \"\"\"\n # Convert the string to lowercase to ignore case and remove duplicates by converting to a set\n distinct_chars = set(string.lower())\n # Return the number of distinct characters\n return len(distinct_chars)", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n \"\"\"\n # Convert the string to lowercase to make the case-insensitive comparison possible\n lower_string = string.lower()\n # Use a set to store unique characters\n unique_chars = set(lower_string)\n # The number of unique characters is the size of the set\n return len(unique_chars)", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\"\n Given a string, find out how many distinct characters (regardless of case) does it consist of.\n \n :param string: Input string\n :return: Number of distinct characters in the string, case-insensitive\n \n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lowercase to make the search case-insensitive and remove duplicates by converting to a set\n unique_chars = set(string.lower())\n \n # Return the count of unique characters\n return len(unique_chars)", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\"\n Given a string, find out how many distinct characters (regardless of case) does it consist of\n \"\"\"\n # Convert the string to lowercase to ensure case-insensitive comparison\n lower_string = string.lower()\n \n # Use a set to store unique characters\n distinct_chars = set(lower_string)\n \n # Return the number of unique characters\n return len(distinct_chars)", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\"\n Given a string, find out how many distinct characters (regardless of case) it consists of\n \"\"\"\n # Convert the string to lowercase to ignore case differences and then use a set to store unique characters\n unique_chars = set(string.lower())\n return len(unique_chars)", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n \"\"\"\n # Convert the string to lowercase to ignore case differences and then convert to a set to remove duplicates\n distinct_chars = set(string.lower())\n # Return the number of unique characters\n return len(distinct_chars)", "matching_cluster_idx": 8}]}, "HumanEval/20": {"dps": 88.4503631961259, "dps_norm": 95.0, "pass@1": 100.0, "profiled": [{"solution": "from typing import *\nfrom typing import List, Tuple\nimport heapq\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\"\n From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n \"\"\"\n # Sort the list to make it easier to find the closest elements\n sorted_numbers = sorted(numbers)\n \n # Initialize variables to store the closest pair and the smallest difference found so far\n closest_pair = (sorted_numbers[0], sorted_numbers[1])\n smallest_diff = sorted_numbers[1] - sorted_numbers[0]\n \n # Iterate through the sorted list to find the pair with the smallest difference\n for i in range(1, len(sorted_numbers) - 1):\n current_diff = sorted_numbers[i + 1] - sorted_numbers[i]\n if current_diff < smallest_diff:\n smallest_diff = current_diff\n closest_pair = (sorted_numbers[i], sorted_numbers[i + 1])\n \n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import *\nfrom typing import List, Tuple\nimport heapq\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n \"\"\"\n # Sort the list to ensure that the closest elements will be next to each other.\n numbers_sorted = sorted(numbers)\n \n # Use a min heap to keep track of the two closest elements.\n min_heap = []\n for i in range(len(numbers_sorted) - 1):\n heapq.heappush(min_heap, (numbers_sorted[i+1] - numbers_sorted[i], numbers_sorted[i], numbers_sorted[i+1]))\n \n # The root of the heap will be the pair with the smallest difference.\n closest_diff, smallest, largest = heapq.heappop(min_heap)\n \n return (smallest, largest)", "matching_cluster_idx": 5}, {"solution": "from typing import *\nfrom typing import List, Tuple\nimport math\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n \"\"\"\n numbers.sort() # Sort the numbers first\n \n min_diff = math.inf # Initialize minimum difference to infinity\n closest_pair: Tuple[float, float] = (0.0, 0.0)\n \n # Iterate through the list to find the closest pair\n for i in range(len(numbers) - 1):\n diff = numbers[i + 1] - numbers[i]\n if diff < min_diff:\n min_diff = diff\n closest_pair = (numbers[i], numbers[i + 1])\n \n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import *\nfrom typing import List, Tuple\nimport math\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\"From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\"\"\"\n numbers.sort() # Sort the list to make it easier to find the closest elements\n min_diff = math.inf # Initialize the minimum difference to infinity\n closest_pair = (0.0, 0.0) # Initialize the closest pair of numbers\n \n # Iterate through the sorted list to find the closest elements\n for i in range(len(numbers) - 1):\n current_diff = numbers[i + 1] - numbers[i]\n if current_diff < min_diff:\n min_diff = current_diff\n closest_pair = (numbers[i], numbers[i + 1])\n \n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import *\nfrom typing import List, Tuple\nimport sys\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n \"\"\"\n # Sort the list to make it easier to find the closest elements\n sorted_numbers = sorted(numbers)\n \n # Initialize variables to store the closest pair and their difference\n closest_pair = (sorted_numbers[0], sorted_numbers[1])\n smallest_difference = abs(sorted_numbers[1] - sorted_numbers[0])\n \n # Iterate through the sorted list to find the closest pair\n for i in range(1, len(sorted_numbers) - 1):\n difference = abs(sorted_numbers[i + 1] - sorted_numbers[i])\n if difference < smallest_difference:\n smallest_difference = difference\n closest_pair = (sorted_numbers[i], sorted_numbers[i + 1])\n \n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import *\nfrom typing import List, Tuple\nimport heapq\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\"\n From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n \"\"\"\n # Sort the list to make it easier to find the closest elements\n numbers.sort()\n \n # Use a min heap to keep track of the smallest pair\n min_heap = []\n \n # Iterate through the sorted list and push the difference and the pair to the heap\n for i in range(len(numbers) - 1):\n diff = numbers[i + 1] - numbers[i]\n heapq.heappush(min_heap, (diff, numbers[i], numbers[i + 1]))\n \n # The root of the heap is the pair with the smallest difference\n smallest_diff, num1, num2 = heapq.heappop(min_heap)\n \n return (num1, num2)", "matching_cluster_idx": 5}, {"solution": "from typing import *\nfrom typing import List, Tuple\nimport heapq\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n \"\"\"\n # First sort the list to make it easier to find the closest elements\n sorted_numbers = sorted(numbers)\n \n # Use a min heap to keep track of the closest pair\n closest_pair = []\n heapq.heapify(closest_pair)\n \n # Iterate through the sorted list to find the closest pair\n for i in range(1, len(sorted_numbers)):\n # Calculate the distance between consecutive elements\n distance = sorted_numbers[i] - sorted_numbers[i-1]\n \n # If this is the first iteration, just add the pair\n if not closest_pair:\n heapq.heappush(closest_pair, (-distance, sorted_numbers[i-1], sorted_numbers[i]))\n else:\n # Push the current pair if it's closer than the current closest pair in the heap\n if distance < -closest_pair[0][0]:\n heapq.heappushpop(closest_pair, (-distance, sorted_numbers[i-1], sorted_numbers[i]))\n \n # Return the closest pair from the heap\n _, a, b = closest_pair[0]\n return a, b", "matching_cluster_idx": 8}, {"solution": "from typing import *\nfrom typing import List, Tuple\nimport heapq\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\"\n From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n \"\"\"\n # Sort the list first to ensure the closest elements are adjacent\n numbers.sort()\n \n # Initialize variables to store the closest pair and the smallest gap found\n closest_pair: Tuple[float, float] = (numbers[0], numbers[1])\n min_gap: float = abs(numbers[0] - numbers[1])\n \n # Iterate through the sorted list to find the pair with the smallest gap\n for i in range(1, len(numbers) - 1):\n current_gap: float = abs(numbers[i] - numbers[i + 1])\n if current_gap < min_gap:\n min_gap = current_gap\n closest_pair = (numbers[i], numbers[i + 1])\n # Ensure the smaller number comes first\n if closest_pair[0] > closest_pair[1]:\n closest_pair = (closest_pair[1], closest_pair[0])\n \n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n \"\"\"\n # Sort the list first to ensure that the closest numbers will be next to each other\n numbers_sorted = sorted(numbers)\n closest_pair = (numbers_sorted[0], numbers_sorted[1])\n min_distance = abs(closest_pair[1] - closest_pair[0])\n\n # Iterate through the sorted list to find the pair with the smallest difference\n for i in range(1, len(numbers_sorted) - 1):\n current_distance = abs(numbers_sorted[i + 1] - numbers_sorted[i])\n if current_distance < min_distance:\n min_distance = current_distance\n closest_pair = (numbers_sorted[i], numbers_sorted[i + 1])\n \n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import *\nfrom typing import List, Tuple\nimport sys\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\"From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\"\"\"\n # Sort the list first to make sure we can easily find the closest elements\n numbers.sort()\n \n # Initialize variables to store the closest pair and the smallest difference found\n closest_pair = (numbers[0], numbers[1])\n min_diff = sys.maxsize # Start with the largest possible difference\n \n # Iterate through the sorted list to find the closest pair\n for i in range(len(numbers) - 1):\n # Calculate the difference between consecutive elements\n diff = numbers[i + 1] - numbers[i]\n # Update the closest pair if a smaller difference is found\n if diff < min_diff:\n min_diff = diff\n closest_pair = (numbers[i], numbers[i + 1])\n \n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import *\nfrom typing import List, Tuple\nimport heapq\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\"From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n \"\"\"\n # Sort the list first to ensure close elements are adjacent\n numbers.sort()\n \n # Initialize the closest pair as the first two elements and the minimum difference\n closest_pair = (numbers[0], numbers[1])\n min_diff = abs(numbers[1] - numbers[0])\n \n # Loop through the sorted list to find the pair with the smallest difference\n for i in range(len(numbers) - 1):\n diff = abs(numbers[i + 1] - numbers[i])\n if diff < min_diff:\n min_diff = diff\n closest_pair = (numbers[i], numbers[i + 1])\n \n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import *\nfrom typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n \"\"\"\n # First, sort the list to ensure we can easily find the closest pair\n sorted_numbers = sorted(numbers)\n \n # Initialize variables to store the closest pair and their difference\n closest_pair: Tuple[float, float] = (sorted_numbers[0], sorted_numbers[1])\n min_diff = abs(sorted_numbers[1] - sorted_numbers[0])\n \n # Iterate through the sorted list to find the closest pair\n for i in range(len(sorted_numbers) - 1):\n current_diff = abs(sorted_numbers[i] - sorted_numbers[i + 1])\n if current_diff < min_diff:\n min_diff = current_diff\n closest_pair = (sorted_numbers[i], sorted_numbers[i + 1])\n \n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import *\nfrom typing import List, Tuple\nimport heapq\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\"\n From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n \"\"\"\n # First, sort the list\n sorted_numbers = sorted(numbers)\n \n # Initialize variables to store the closest pair and the minimum difference found\n closest_pair = (sorted_numbers[0], sorted_numbers[1])\n min_diff = abs(sorted_numbers[0] - sorted_numbers[1])\n \n # Iterate through the sorted list to find the closest pair\n for i in range(1, len(sorted_numbers) - 1):\n current_diff = abs(sorted_numbers[i] - sorted_numbers[i + 1])\n if current_diff < min_diff:\n min_diff = current_diff\n closest_pair = (sorted_numbers[i], sorted_numbers[i + 1])\n \n # Ensure the pair is in order (smaller, larger)\n return tuple(sorted(closest_pair))", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\"\n From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n \"\"\"\n # First, sort the list\n sorted_numbers = sorted(numbers)\n \n # Initialize variables to store the closest pair and the smallest difference found\n closest_pair: Tuple[float, float] = (sorted_numbers[0], sorted_numbers[1])\n min_diff = abs(sorted_numbers[1] - sorted_numbers[0])\n \n # Iterate through the sorted list to find the pair with the smallest difference\n for i in range(1, len(sorted_numbers) - 1):\n current_diff = abs(sorted_numbers[i + 1] - sorted_numbers[i])\n if current_diff < min_diff:\n min_diff = current_diff\n closest_pair = (sorted_numbers[i], sorted_numbers[i + 1])\n \n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n \"\"\"\n # First, sort the list of numbers to make it easier to find the closest pair\n sorted_numbers = sorted(numbers)\n \n # Initialize the closest pair with the first two elements\n closest_pair = (sorted_numbers[0], sorted_numbers[1])\n \n # Iterate through the list to find the pair with the smallest difference\n for i in range(len(sorted_numbers) - 1):\n if sorted_numbers[i + 1] - sorted_numbers[i] < closest_pair[1] - closest_pair[0]:\n closest_pair = (sorted_numbers[i], sorted_numbers[i + 1])\n \n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import *\nfrom typing import List, Tuple\nimport heapq\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\"From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n \"\"\"\n # Sort the list to ensure that the closest elements are next to each other\n sorted_numbers = sorted(numbers)\n # Initialize the closest pair with the first two elements\n closest_pair = (sorted_numbers[0], sorted_numbers[1])\n # Initialize the minimum difference to a high value\n min_diff = abs(sorted_numbers[0] - sorted_numbers[1])\n \n # Iterate through the sorted list to find the closest pair\n for i in range(1, len(sorted_numbers) - 1):\n diff = abs(sorted_numbers[i] - sorted_numbers[i + 1])\n if diff < min_diff:\n min_diff = diff\n closest_pair = (sorted_numbers[i], sorted_numbers[i + 1])\n \n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import *\nfrom typing import List, Tuple\nimport heapq\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\"\n From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n \"\"\"\n # Sort the list to ensure that the closest numbers are next to each other\n sorted_numbers = sorted(numbers)\n \n # Initialize variables to store the closest pair\n closest_pair = (sorted_numbers[0], sorted_numbers[1])\n min_distance = abs(sorted_numbers[1] - sorted_numbers[0])\n \n # Iterate through the list to find the pair with the smallest distance\n for i in range(1, len(sorted_numbers) - 1):\n current_distance = abs(sorted_numbers[i + 1] - sorted_numbers[i])\n if current_distance < min_distance:\n min_distance = current_distance\n closest_pair = (sorted_numbers[i], sorted_numbers[i + 1])\n \n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import *\nfrom typing import List, Tuple\nimport heapq\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n \"\"\"\n # Sort the list to ensure the closest elements are next to each other\n sorted_numbers = sorted(numbers)\n \n # Initialize variables to store the closest pair found\n closest_pair = (sorted_numbers[0], sorted_numbers[1])\n min_gap = abs(sorted_numbers[1] - sorted_numbers[0])\n \n # Iterate through the sorted list to find the closest pair\n for i in range(1, len(sorted_numbers) - 1):\n current_gap = abs(sorted_numbers[i + 1] - sorted_numbers[i])\n if current_gap < min_gap:\n min_gap = current_gap\n closest_pair = (sorted_numbers[i], sorted_numbers[i + 1])\n \n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import *\nfrom typing import List, Tuple\nimport heapq\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n \"\"\"\n # Sort the list to make it easier to find the closest elements\n sorted_numbers = sorted(numbers)\n # Use a min heap to find the two closest elements efficiently\n min_heap = []\n for i in range(len(sorted_numbers) - 1):\n diff = sorted_numbers[i + 1] - sorted_numbers[i]\n heapq.heappush(min_heap, (diff, sorted_numbers[i], sorted_numbers[i + 1]))\n \n # The top of the heap will be the smallest difference, hence the closest elements\n _, smallest, second_smallest = heapq.heappop(min_heap)\n return (smallest, second_smallest)", "matching_cluster_idx": 5}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n \"\"\"\n # First, sort the list to make it easier to find the closest elements\n sorted_numbers = sorted(numbers)\n \n # Initialize variables to store the closest pair found so far\n closest_pair = (sorted_numbers[0], sorted_numbers[1])\n min_distance = abs(sorted_numbers[1] - sorted_numbers[0])\n \n # Iterate through the sorted list to find the pair with the smallest distance\n for i in range(1, len(sorted_numbers) - 1):\n current_distance = abs(sorted_numbers[i + 1] - sorted_numbers[i])\n \n if current_distance < min_distance:\n min_distance = current_distance\n closest_pair = (sorted_numbers[i], sorted_numbers[i + 1])\n \n return closest_pair", "matching_cluster_idx": 8}]}, "HumanEval/24": {"dps": 51.904761904761905, "dps_norm": 30.625, "pass@1": 97.0, "profiled": [{"solution": "def largest_divisor(n: int) -> int:\n \"\"\"\n For a given number n, find the largest number that divides n evenly, smaller than n\n \n :param n: Integer, the number to find the largest divisor for.\n :return: Integer, the largest divisor of n that is smaller than n itself.\n \"\"\"\n # Start from n-1 and go downwards\n for divisor in range(n - 1, 0, -1):\n if n % divisor == 0:\n return divisor\n return None # This line will never be reached if n > 1", "matching_cluster_idx": 1}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\"\n For a given number n, find the largest number that divides n evenly, smaller than n.\n \n :param n: An integer\n :return: The largest divisor of n that is smaller than n\n \"\"\"\n # Start from n-1 and go down to 1\n for i in range(n - 1, 0, -1):\n if n % i == 0:\n return i\n return None # If no divisor is found, return None", "matching_cluster_idx": 0}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\"\n For a given number n, find the largest number that divides n evenly, smaller than n.\n \n :param n: An integer for which the largest divisor is to be found.\n :return: The largest divisor of n that is smaller than n itself.\n \"\"\"\n # Start from n-1 and go down to 1 to find the largest divisor\n for i in range(n - 1, 0, -1):\n if n % i == 0:\n return i\n return None # In case no divisor is found, though it should not happen for n > 1", "matching_cluster_idx": 0}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\"\n For a given number n, find the largest number that divides n evenly, smaller than n.\n \n :param n: Integer for which to find the largest divisor smaller than itself\n :return: The largest divisor of n that is smaller than n\n \"\"\"\n for i in range(n // 2, 0, -1):\n if n % i == 0:\n return i\n return 1 # If no divisor is found (which theoretically won't happen for n > 1), return 1 as fallback", "matching_cluster_idx": 3}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\"\n For a given number n, find the largest number that divides n evenly, smaller than n\n \n :param n: An integer\n :return: The largest divisor of n, smaller than n\n \n >>> largest_divisor(15)\n 5\n \"\"\"\n # Start checking from n-1 and go downwards\n for i in range(n-1, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 0}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\"\n For a given number n, find the largest number that divides n evenly, smaller than n.\n \n Parameters:\n n (int): The input number to find the largest divisor for.\n \n Returns:\n int: The largest divisor of n smaller than n itself.\n \"\"\"\n # Start checking from n-1 and go downwards\n for i in range(n-1, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 0}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\"\n For a given number n, find the largest number that divides n evenly, smaller than n.\n \n :param n: Integer, the number to find the largest divisor for.\n :return: Integer, the largest divisor of n that is smaller than n itself.\n \"\"\"\n # Start checking from n-1 and go downwards\n for i in range(n-1, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 0}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\"\n For a given number n, find the largest number that divides n evenly, smaller than n.\n \n :param n: Integer for which the largest divisor is to be found.\n :return: The largest divisor of n, smaller than n itself.\n \"\"\"\n # Starting from the largest possible divisor smaller than n, which is n-1\n for divisor in range(n - 1, 0, -1):\n if n % divisor == 0:\n return divisor", "matching_cluster_idx": 0}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\"\n For a given number n, find the largest number that divides n evenly, smaller than n.\n\n :param n: An integer for which to find the largest divisor smaller than itself.\n :return: The largest divisor of n that is smaller than n itself.\n \"\"\"\n for i in range(n // 2, 0, -1): # Start from half of n and go down to 1\n if n % i == 0:\n return i # Return the first (largest) divisor found", "matching_cluster_idx": 3}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\"\n For a given number n, find the largest number that divides n evenly, smaller than n\n \n :param n: An integer\n :return: The largest divisor of n that is smaller than n\n \"\"\"\n # Start checking from n-1 down to 1 to find the largest divisor\n for i in range(n - 1, 0, -1):\n if n % i == 0:\n return i\n return 1 # If no divisor is found, return 1 (though every number is divisible by 1)", "matching_cluster_idx": 0}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\"\n For a given number n, find the largest number that divides n evenly, smaller than n\n \n :param n: The number for which to find the largest divisor.\n :return: The largest divisor of n smaller than n itself.\n \"\"\"\n # Starting from n//2 and going down to 1, find the first number that divides n evenly\n for i in range(n // 2, 0, -1):\n if n % i == 0:\n return i\n return 1 # If no divisor found, return 1, which is always a divisor", "matching_cluster_idx": 3}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\"\n For a given number n, find the largest number that divides n evenly, smaller than n.\n \n :param n: Integer for which to find the largest divisor.\n :return: The largest divisor of n that is smaller than n.\n \"\"\"\n # Start from n/2 and go downwards to find the largest divisor\n for i in range(n // 2, 0, -1):\n if n % i == 0:\n return i\n # If no divisor is found (which shouldn't happen for n > 1), return 1\n return 1", "matching_cluster_idx": 3}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\"\n For a given number n, find the largest number that divides n evenly, smaller than n.\n \n :param n: An integer for which to find the largest divisor\n :return: The largest divisor of n that is smaller than n itself\n \"\"\"\n # Start checking from n//2 and go down to 1\n for i in range(n // 2, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 3}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\"\n For a given number n, find the largest number that divides n evenly, smaller than n\n \n :param n: Integer, the number to find the divisor for\n :return: Integer, the largest divisor of n that is smaller than n\n \"\"\"\n # Start from n-1 and go down to 1 to find the largest divisor\n for i in range(n - 1, 0, -1):\n if n % i == 0:\n return i\n return None # Fallback return if no divisor is found, though this shouldn't happen for n > 1", "matching_cluster_idx": 0}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\"\n For a given number n, find the largest number that divides n evenly, smaller than n.\n \n :param n: Integer for which to find the largest divisor smaller than itself.\n :return: The largest divisor of n that is smaller than n.\n \"\"\"\n # Start from n-1 and go down to 1 to find the largest divisor\n for i in range(n-1, 0, -1):\n if n % i == 0:\n return i\n return None # This line should theoretically never be reached for n > 1", "matching_cluster_idx": 0}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\"\n For a given number n, find the largest number that divides n evenly, smaller than n.\n \n :param n: An integer, the number to find the largest divisor for.\n :return: An integer, the largest divisor of n that is smaller than n.\n \"\"\"\n # Start from n // 2 and go down to 1\n for i in range(n // 2, 0, -1):\n if n % i == 0:\n return i\n return 1 # If no divisor is found, return 1 (every number is divisible by 1)", "matching_cluster_idx": 3}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\"\n For a given number n, find the largest number that divides n evenly, smaller than n.\n \n :param n: An integer, the number for which to find the largest divisor\n :return: An integer, the largest divisor of n that is smaller than n\n \n >>> largest_divisor(15)\n 5\n \"\"\"\n # Start from n-1 and go downwards to find the largest divisor\n for i in range(n-1, 0, -1):\n if n % i == 0:\n return i\n return None # Return None if no divisor is found, which theoretically should not happen", "matching_cluster_idx": 1}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\"\n For a given number n, find the largest number that divides n evenly, smaller than n.\n \n :param n: An integer, the number to find the largest divisor for.\n :return: The largest divisor of n that is smaller than n.\n \"\"\"\n # Start checking from n//2 and go downwards to find the largest divisor\n for i in range(n // 2, 0, -1):\n if n % i == 0:\n return i\n # If no divisor is found (which happens if n is 1 or less), return None\n return None", "matching_cluster_idx": 3}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\"\n For a given number n, find the largest number that divides n evenly, smaller than n.\n \n :param n: An integer number.\n :return: The largest divisor of n, which is smaller than n itself.\n \"\"\"\n # Start from the largest possible divisor which is n // 2\n for i in range(n // 2, 0, -1):\n if n % i == 0:\n return i\n return 1 # If no divisor is found, return 1, which is technically correct for any n > 1", "matching_cluster_idx": 3}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\"\n For a given number n, find the largest number that divides n evenly, smaller than n.\n \n :param n: Integer for which the largest divisor smaller than itself is to be found.\n :return: The largest divisor of n that is smaller than n itself.\n \"\"\"\n # Start from n//2 and go downwards to find the largest divisor\n for i in range(n//2, 0, -1):\n if n % i == 0:\n return i\n # If no divisor is found, return 1, though this case will not occur for n > 1\n return 1", "matching_cluster_idx": 3}]}, "HumanEval/26": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\"\n From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n \n :param numbers: List of integers which may contain duplicates\n :return: List of integers with duplicates removed\n \"\"\"\n # Dictionary to keep track of counts\n count_dict = {}\n result = []\n \n # First pass: count occurrences\n for number in numbers:\n if number in count_dict:\n count_dict[number] += 1\n else:\n count_dict[number] = 1\n \n # Second pass: add numbers to result if they occur once\n for number in numbers:\n if count_dict[number] == 1:\n result.append(number)\n \n return result", "matching_cluster_idx": 3}, {"solution": "from typing import *\nfrom collections import Counter\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\"\n From a list of integers, remove all elements that occur more than once.\n Keep the order of elements left the same as in the input.\n \n :param numbers: List[int] - A list of integers.\n :return: List[int] - A list with duplicates removed.\n \"\"\"\n # Count the occurrences of each number\n num_counts = Counter(numbers)\n # Filter the list to include only elements that occur once\n return [num for num in numbers if num_counts[num] == 1]", "matching_cluster_idx": 3}, {"solution": "from typing import *\nfrom collections import Counter\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\"\n From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n \"\"\"\n # Count occurrences of each number\n num_counts = Counter(numbers)\n # Filter out numbers that occur more than once and preserve the order\n result = [num for num in numbers if num_counts[num] == 1]\n return result", "matching_cluster_idx": 3}, {"solution": "from typing import *\nfrom collections import Counter\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\"\n From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n \n :param numbers: List of integers\n :return: List of integers without elements occurring more than once\n \"\"\"\n # Count occurrences of each number\n num_counts = Counter(numbers)\n \n # Filter numbers that occur exactly once and maintain the original order\n return [num for num in numbers if num_counts[num] == 1]", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\"\n From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n \n :param numbers: List of integers.\n :return: A list of integers with duplicates removed.\n \"\"\"\n # Dictionary to hold the count of each number\n count = {}\n result = []\n \n # Count the occurrences of each number\n for number in numbers:\n if number in count:\n count[number] += 1\n else:\n count[number] = 1\n \n # Add numbers that occur exactly once to the result list\n for number in numbers:\n if count[number] == 1:\n result.append(number)\n \n return result", "matching_cluster_idx": 3}, {"solution": "from typing import *\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\"\n From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n \n Args:\n numbers: List[int] - A list of integers.\n \n Returns:\n List[int] - A list of integers without elements occurring more than once.\n \"\"\"\n # Count the occurrence of each number\n counts = {}\n for number in numbers:\n if number in counts:\n counts[number] += 1\n else:\n counts[number] = 1\n \n # Filter out elements occurring more than once\n result = [number for number in numbers if counts[number] == 1]\n \n return result", "matching_cluster_idx": 3}, {"solution": "from typing import *\nfrom collections import Counter\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\"\n From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n \n :param numbers: List of integers potentially containing duplicates.\n :return: List of integers with all duplicates removed.\n \"\"\"\n # Count occurrences of each number\n num_counts = Counter(numbers)\n # Filter numbers that occur only once, preserving the order\n return [num for num in numbers if num_counts[num] == 1]", "matching_cluster_idx": 3}, {"solution": "from typing import *\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\"\n From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n \n :param numbers: List of integers.\n :return: List of integers with duplicates removed.\n \"\"\"\n count_map = {}\n output = []\n \n # Count occurrences of each number\n for number in numbers:\n if number in count_map:\n count_map[number] += 1\n else:\n count_map[number] = 1\n \n # Add numbers to output that occur exactly once\n for number in numbers:\n if count_map[number] == 1:\n output.append(number)\n \n return output", "matching_cluster_idx": 3}, {"solution": "from typing import *\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\"\n From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n \n :param numbers: List of integers\n :return: List of integers with duplicates removed\n \"\"\"\n count_map = {}\n result = []\n \n # Count occurrences of each number\n for number in numbers:\n if number in count_map:\n count_map[number] += 1\n else:\n count_map[number] = 1\n \n # Add to result if it occurs exactly once\n for number in numbers:\n if count_map[number] == 1:\n result.append(number)\n \n return result", "matching_cluster_idx": 3}, {"solution": "from typing import *\nfrom collections import Counter\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\"\n From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n \n :param numbers: List of integers.\n :return: List of integers with duplicates removed.\n \"\"\"\n # Count the occurrences of each number\n num_counts = Counter(numbers)\n \n # Filter out numbers that occur more than once, maintaining original order\n return [num for num in numbers if num_counts[num] == 1]", "matching_cluster_idx": 3}, {"solution": "from typing import *\nfrom collections import Counter\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\"\n From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n \n :param numbers: List of integers.\n :return: List of integers with duplicates removed.\n \"\"\"\n # Count the occurrences of each number\n num_counts = Counter(numbers)\n \n # Filter numbers that occur only once and maintain their order\n result = [number for number in numbers if num_counts[number] == 1]\n \n return result", "matching_cluster_idx": 3}, {"solution": "from typing import *\nfrom collections import Counter\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\"\n From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n \n :param numbers: List[int] - a list of integers which may contain duplicates\n :return: List[int] - a list of integers without elements that occur more than once, preserving original order\n \"\"\"\n # Count occurrences of each number\n num_counts = Counter(numbers)\n # Filter out numbers that occur more than once, preserving order\n return [num for num in numbers if num_counts[num] == 1]", "matching_cluster_idx": 3}, {"solution": "from typing import *\nfrom collections import Counter\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\"\n From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n \n :param numbers: List of integers.\n :return: A list of integers without duplicates.\n \"\"\"\n # Count the occurrences of each number\n count = Counter(numbers)\n # Filter numbers that occur exactly once, preserving the order\n return [num for num in numbers if count[num] == 1]", "matching_cluster_idx": 3}, {"solution": "from typing import *\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\"\n From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n \n :param numbers: List of integers.\n :return: List of integers with duplicates removed.\n \"\"\"\n count_map = {}\n result = []\n \n # Count occurrences of each number\n for number in numbers:\n if number in count_map:\n count_map[number] += 1\n else:\n count_map[number] = 1\n \n # Add elements that occur exactly once to the result list\n for number in numbers:\n if count_map[number] == 1:\n result.append(number)\n \n return result", "matching_cluster_idx": 3}, {"solution": "from typing import *\nfrom collections import Counter\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\"\n From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n \n :param numbers: List of integers.\n :return: A list of integers with all duplicates removed.\n \"\"\"\n # Count the occurrence of each number\n count = Counter(numbers)\n # Filter the list to include only those numbers that occur once\n return [num for num in numbers if count[num] == 1]", "matching_cluster_idx": 3}, {"solution": "from typing import *\nfrom collections import Counter\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\"\n From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n \n :param numbers: List[int] - Input list of integers\n :return: List[int] - List with duplicates removed\n \"\"\"\n # Count the occurrences of each number\n num_counts = Counter(numbers)\n \n # Filter out numbers that appear more than once and maintain original order\n unique_numbers = [num for num in numbers if num_counts[num] == 1]\n \n return unique_numbers", "matching_cluster_idx": 3}, {"solution": "from typing import List\nfrom collections import Counter\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\"\n From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n \n :param numbers: List of integers.\n :return: A list of integers with duplicates removed.\n \"\"\"\n # Count the occurrences of each number\n num_counts = Counter(numbers)\n # Filter out numbers that appear more than once and maintain the original order\n return [num for num in numbers if num_counts[num] == 1]", "matching_cluster_idx": 3}, {"solution": "from typing import *\nfrom collections import Counter\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\"\n From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n \n :param numbers: List of integers.\n :return: List of integers with duplicates removed.\n \"\"\"\n # Count the occurrences of each number\n count = Counter(numbers)\n \n # Filter the numbers, only keep those that occur once\n return [num for num in numbers if count[num] == 1]", "matching_cluster_idx": 3}, {"solution": "from typing import *\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\"\n From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n \n :param numbers: List of integers\n :return: A list of integers without duplicates, preserving the original order\n \n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n count_dict = {}\n result = []\n for number in numbers:\n count_dict[number] = count_dict.get(number, 0) + 1\n for number in numbers:\n if count_dict[number] == 1:\n result.append(number)\n return result", "matching_cluster_idx": 3}, {"solution": "from typing import List\nfrom collections import Counter\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\"\n From a list of integers, remove all elements that occur more than once.\n Keep the order of elements left the same as in the input.\n \n :param numbers: List of integers.\n :return: List of integers with all duplicates removed.\n \"\"\"\n # Count the occurrences of each number\n num_counts = Counter(numbers)\n # Filter numbers that occur only once and maintain original order\n return [num for num in numbers if num_counts[num] == 1]", "matching_cluster_idx": 3}]}, "HumanEval/31": {"dps": 77.72151898734177, "dps_norm": 80.0, "pass@1": 100.0, "profiled": [{"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\"\"\"\n if n < 2:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n \"\"\"\n if n < 2:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\"\"\"\n if n < 2:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n \"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\"\"\"\n if n < 2:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n \"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n \"\"\"\n if n < 2:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\"\"\"\n if n < 2:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}]}, "HumanEval/33": {"dps": 97.22222222222223, "dps_norm": 81.81818181818181, "pass@1": 15.0, "profiled": [{"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n \"\"\"\n # Extract elements at indices divisible by 3\n indices_divisible_by_three = [i for i in range(len(l)) if i % 3 == 0]\n # Extract and sort values at indices divisible by 3\n sorted_values = sorted([l[i] for i in indices_divisible_by_three])\n \n # Create a new list to hold the result\n result = l[:]\n # Place sorted values back into the result list at indices divisible by 3\n for index, value in zip(indices_divisible_by_three, sorted_values):\n result[index] = value\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n \"\"\"\n # Extract elements at indices divisible by three\n indices_divisible_by_three = [i for i in range(len(l)) if i % 3 == 0]\n # Extract and sort elements at indices divisible by three\n values_to_sort = sorted([l[i] for i in indices_divisible_by_three])\n \n # Create a copy of the original list to preserve non-sorted indices\n sorted_list = l[:]\n # Place sorted elements back into the correct indices\n for i, value in zip(indices_divisible_by_three, values_to_sort):\n sorted_list[i] = value\n \n return sorted_list", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n \"\"\"\n # Extract elements at indices divisible by 3\n indices_divisible_by_three = [i for i in range(len(l)) if i % 3 == 0]\n elements_to_sort = sorted(l[i] for i in indices_divisible_by_three)\n \n # Replace elements in the list at indices divisible by 3 with sorted ones\n l_prime = l[:]\n for original_index, sorted_element in zip(indices_divisible_by_three, elements_to_sort):\n l_prime[original_index] = sorted_element\n \n return l_prime", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"\n This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n \"\"\"\n # Extract the elements at indices divisible by 3\n indices = [i for i in range(len(l)) if i % 3 == 0]\n # Extract the values corresponding to these indices\n values = [l[i] for i in indices]\n # Sort these extracted values\n sorted_values = sorted(values)\n \n # Create a new list with the sorted values placed back at their original indices\n result = l[:]\n for idx, val in zip(indices, sorted_values):\n result[idx] = val\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"\n This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n \"\"\"\n # Extract elements whose indices are divisible by three\n indices_div_by_three = [i for i in range(len(l)) if i % 3 == 0]\n # Extract and sort values at those indices\n sorted_values = sorted(l[i] for i in indices_div_by_three)\n \n # Create a new list to hold the final sorted list\n result = l[:]\n # Replace the values at the sorted indices with sorted values\n for i, val in zip(indices_div_by_three, sorted_values):\n result[i] = val\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n \"\"\"\n # Extract the elements at indices divisible by 3\n indices_divisible_by_three = [i for i in range(len(l)) if i % 3 == 0]\n elements_to_sort = [l[i] for i in indices_divisible_by_three]\n \n # Sort the extracted elements\n elements_to_sort.sort()\n \n # Place the sorted elements back into their original positions\n result = l[:]\n for original_index, sorted_element in zip(indices_divisible_by_three, elements_to_sort):\n result[original_index] = sorted_element\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n \"\"\"\n # Extract elements at indices divisible by three\n indices_div_by_three = [i for i in range(len(l)) if i % 3 == 0]\n elements_div_by_three = sorted([l[i] for i in indices_div_by_three])\n \n # Replace elements at these indices in the original list with the sorted ones\n l_prime = l[:]\n for index, element in zip(indices_div_by_three, elements_div_by_three):\n l_prime[index] = element\n \n return l_prime", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n \"\"\"\n # Extract elements at indices divisible by three\n indices_div_by_three = [i for i in range(len(l)) if i % 3 == 0]\n elements_to_sort = sorted([l[i] for i in indices_div_by_three])\n \n # Place sorted elements back at their respective indices\n result = l[:]\n for i, val in zip(indices_div_by_three, elements_to_sort):\n result[i] = val\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n \"\"\"\n # Extract elements at indices divisible by three\n indices_div_by_three = [i for i in range(len(l)) if i % 3 == 0]\n # Extract values at those indices\n values_at_indices = [l[i] for i in indices_div_by_three]\n # Sort those values\n sorted_values = sorted(values_at_indices)\n \n # Replace the values at those indices in the original list with sorted values\n result = l[:]\n for i, val in zip(indices_div_by_three, sorted_values):\n result[i] = val\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n \"\"\"\n # Extract elements at indices divisible by three\n indices_div_three = [i for i in range(len(l)) if i % 3 == 0]\n # Extract corresponding values\n values_div_three = [l[i] for i in indices_div_three]\n # Sort those values\n sorted_values = sorted(values_div_three)\n \n # Create a new list based on the original list l\n l_prime = l[:]\n # Replace elements at indices divisible by three with sorted values\n for i, val in zip(indices_div_three, sorted_values):\n l_prime[i] = val\n \n return l_prime", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n \"\"\"\n # Extract elements at indices divisible by three\n indices_divisible_by_three = [i for i in range(len(l)) if i % 3 == 0]\n elements_to_sort = [l[i] for i in indices_divisible_by_three]\n \n # Sort the extracted elements\n elements_to_sort.sort()\n \n # Create a new list to hold the sorted elements at indices divisible by three\n result = l[:]\n for i, element in zip(indices_divisible_by_three, elements_to_sort):\n result[i] = element\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n \"\"\"\n # Extract elements at indices divisible by three\n indices = [i for i in range(len(l)) if i % 3 == 0]\n # Sort the extracted elements\n sorted_indices_values = sorted(l[i] for i in indices)\n \n # Create a copy of the list to avoid modifying the original list\n l_prime = l[:]\n # Replace the elements at the extracted indices with the sorted values\n for i, value in zip(indices, sorted_indices_values):\n l_prime[i] = value\n \n return l_prime", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n \"\"\"\n # Extract elements at indices divisible by three\n indices_div_three = [i for i in range(len(l)) if i % 3 == 0]\n # Extract these elements and sort them\n sorted_elements = sorted([l[i] for i in indices_div_three])\n \n # Create a copy of the original list to modify\n result = l[:]\n # Replace the elements at indices divisible by three with sorted ones\n for i, sorted_val in zip(indices_div_three, sorted_elements):\n result[i] = sorted_val\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n \"\"\"\n # Extract the elements at indices divisible by 3\n indices_div_by_three = [i for i in range(len(l)) if i % 3 == 0]\n elements_at_div_by_three = sorted([l[i] for i in indices_div_by_three])\n \n # Create the resulting list l'\n l_prime = l[:]\n for i, sorted_value in zip(indices_div_by_three, elements_at_div_by_three):\n l_prime[i] = sorted_value\n \n return l_prime", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n \"\"\"\n # Extract elements at indices divisible by three\n indices_div_by_three = [i for i in range(len(l)) if i % 3 == 0]\n # Extract elements that are at these indices\n elements_to_sort = [l[i] for i in indices_div_by_three]\n # Sort these elements\n elements_to_sort.sort()\n \n # Create a new list to hold the sorted values\n sorted_list = l[:]\n \n # Replace elements at indices divisible by three with sorted elements\n for i, element in zip(indices_div_by_three, elements_to_sort):\n sorted_list[i] = element\n \n return sorted_list", "matching_cluster_idx": 8}]}, "HumanEval/34": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def unique(l: list):\n \"\"\"\n Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n # Convert list to a set to remove duplicates, then convert back to sorted list\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"\n Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"\n Return sorted unique elements in a list\n \"\"\"\n # Convert the list to a set to remove duplicates, then convert back to a list and sort it\n return sorted(list(set(l)))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n # Using set to remove duplicates and sorting the result\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"\n Return sorted unique elements in a list\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"\n Return sorted unique elements in a list\n \n :param l: List of elements\n :return: Sorted list with unique elements\n \"\"\"\n # Using set to remove duplicates and sorting the result\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n # Convert the list to a set to remove duplicates, then convert back to a list and sort it\n return sorted(list(set(l)))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n # Convert list to a set to remove duplicates, then convert it back to a sorted list\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n # Using set to remove duplicates and then converting it back to sorted list\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n # Use a set to remove duplicates and then convert back to a sorted list\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"\n Return sorted unique elements in a list\n \"\"\"\n # Using set to remove duplicates and then converting it back to a sorted list\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"\n Return sorted unique elements in a list\n \n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n # Using set to remove duplicates and sorted to sort the elements\n return sorted(set(l))", "matching_cluster_idx": 4}]}, "HumanEval/36": {"dps": 92.74193548387096, "dps_norm": 70.71428571428572, "pass@1": 92.0, "profiled": [{"solution": "def fizz_buzz(n: int):\n \"\"\"\n Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n \n :param n: The upper limit (non-inclusive) for checking numbers.\n :return: The count of digit '7' appearances in numbers less than n and divisible by 11 or 13.\n \"\"\"\n count = 0\n for i in range(1, n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int):\n \"\"\"\n Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n \n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n for i in range(1, n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int):\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n \"\"\"\n count = 0\n for i in range(1, n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"\n Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n \n :param n: Upper limit integer (exclusive).\n :return: The count of digit 7 appearances in numbers less than n that are divisible by 11 or 13.\n \"\"\"\n count = 0\n for i in range(1, n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int):\n \"\"\"\n Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n for i in range(1, n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int):\n \"\"\"\n Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n \n :param n: Integer, the upper limit (exclusive) for checking divisibility.\n :return: Integer, count of digit 7 appearances in numbers less than n that are divisible by 11 or 13.\n \"\"\"\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int):\n \"\"\"\n Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n \n :param n: Upper limit integer (exclusive)\n :return: Number of times digit 7 appears in numbers less than n and divisible by 11 or 13.\n \"\"\"\n def divisible_by_11_or_13(x: int):\n \"\"\"Check if x is divisible by 11 or 13.\"\"\"\n return x % 11 == 0 or x % 13 == 0\n \n count = 0\n for i in range(n):\n if divisible_by_11_or_13(i):\n count += str(i).count('7')\n return count", "matching_cluster_idx": 3}, {"solution": "def fizz_buzz(n: int):\n \"\"\"\n Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n \n :param n: Upper limit (exclusive) to check for numbers divisible by 11 or 13\n :return: The count of digit 7 appearances\n \"\"\"\n count = 0\n for i in range(1, n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int):\n \"\"\"\n Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n for i in range(1, n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int):\n \"\"\"\n Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n \n :param n: Upper limit (exclusive) for checking numbers\n :return: Count of digit 7 appearances in numbers less than n and divisible by 11 or 13\n \"\"\"\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int):\n \"\"\"\n Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n \n :param n: Upper limit integer (exclusive).\n :return: Count of digit 7 appearances.\n \"\"\"\n count = 0\n for i in range(1, n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int):\n \"\"\"\n Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n \n :param n: Upper limit (non-inclusive) to check for numbers divisible by 11 or 13.\n :return: Count of digit 7 appearances in such numbers.\n \"\"\"\n count = 0\n for i in range(1, n):\n if i % 11 == 0 or i % 13 == 0:\n for digit in str(i):\n if digit == '7':\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_sevens(divisor: int) -> int:\n \"\"\"Helper function to count the number of 7s in a given number.\"\"\"\n return str(divisor).count('7')\ndef fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\"\"\"\n return sum(count_sevens(i) for i in range(n) if i % 11 == 0 or i % 13 == 0)", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int):\n \"\"\"\n Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n \n :param n: Upper limit (exclusive) for checking numbers\n :return: Count of occurrences of the digit 7 in numbers less than n divisible by 11 or 13\n \"\"\"\n count = 0\n for i in range(1, n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int):\n \"\"\"\n Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n \n :param n: Upper limit (exclusive)\n :return: Number of times the digit 7 appears in numbers less than n that are divisible by 11 or 13\n \"\"\"\n count = 0\n for i in range(1, n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int):\n \"\"\"\n Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n \n :param n: Upper limit (exclusive)\n :return: Count of digit 7 appearances\n \"\"\"\n count = 0\n for i in range(1, n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int):\n \"\"\"\n Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n \n :param n: Upper limit integer (exclusive).\n :return: Count of digit '7' appearances in numbers less than n and divisible by 11 or 13.\n \"\"\"\n count = 0\n for i in range(1, n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int):\n \"\"\"\n Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n \n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n for i in range(1, n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int):\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int):\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n \"\"\"\n count = 0\n for i in range(1, n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}]}, "HumanEval/37": {"dps": 95.18003273322422, "dps_norm": 90.5, "pass@1": 84.0, "profiled": [{"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n \"\"\"\n # Extract the even-index elements and sort them.\n even_elements = sorted((l[i] for i in range(0, len(l), 2)))\n \n # Create a new list to store the result.\n result = l[:]\n \n # Replace the even-index elements of the result with the sorted even-index elements.\n for i, val in enumerate(even_elements):\n result[i * 2] = val\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n \"\"\"\n # Extract elements at even indices and sort them\n even_indices_elements = sorted(l[::2])\n \n # Result list initialized as a copy of the original list\n result = l[:]\n \n # Replace elements at even indices with sorted elements\n for i, sorted_val in enumerate(even_indices_elements):\n result[i * 2] = sorted_val\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n \"\"\"\n # Extract elements at even indices\n even_indices_elements = sorted(l[::2])\n \n # Counter for elements in the sorted even_indices_elements\n even_counter = 0\n \n # Create a new list to store the result\n result = []\n \n for i in range(len(l)):\n if i % 2 == 0:\n # If the index is even, take the next smallest element from the sorted even list\n result.append(even_indices_elements[even_counter])\n even_counter += 1\n else:\n # If the index is odd, keep the original element\n result.append(l[i])\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"\n This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n \"\"\"\n # Extract elements at even indices (0-based)\n even_indices_elements = sorted([l[i] for i in range(len(l)) if i % 2 == 0])\n \n # Iterate through the list and replace even-indexed elements with sorted values\n result = []\n even_index = 0\n for i in range(len(l)):\n if i % 2 == 0:\n result.append(even_indices_elements[even_index])\n even_index += 1\n else:\n result.append(l[i])\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n \"\"\"\n # Extract elements at even indices and sort them\n even_indices_elements = sorted(l[i] for i in range(len(l)) if i % 2 == 0)\n \n # Counter for the sorted even indices elements\n even_index_counter = 0\n \n # Create the new list with sorted even indices\n l_prime = l.copy()\n for i in range(len(l_prime)):\n if i % 2 == 0:\n l_prime[i] = even_indices_elements[even_index_counter]\n even_index_counter += 1\n \n return l_prime", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n \"\"\"\n # Extract even-indexed elements\n even_indices_elements = sorted([l[i] for i in range(len(l)) if i % 2 == 0])\n # Prepare an iterator from the sorted elements\n sorted_iter = iter(even_indices_elements)\n \n # Create a new list with sorted even-indexed elements and unchanged odd-indexed elements\n result = [next(sorted_iter) if i % 2 == 0 else l[i] for i in range(len(l))]\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n \"\"\"\n # Extract even indices elements and sort them\n even_elements = sorted((l[i] for i in range(len(l)) if i % 2 == 0))\n \n # List to hold the new elements based on sorted even indices\n sorted_list = []\n even_index = 0 # To keep track of the index for the sorted even elements\n \n for i in range(len(l)):\n if i % 2 == 0:\n # For even indices, use the sorted elements\n sorted_list.append(even_elements[even_index])\n even_index += 1\n else:\n # For odd indices, keep the original values\n sorted_list.append(l[i])\n \n return sorted_list", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n \"\"\"\n # Extract elements at even indices and sort them\n even_indices_values = sorted(l[i] for i in range(len(l)) if i % 2 == 0)\n \n # Initialize an empty list to store the result\n result = []\n even_index = 0\n \n # Reconstruct the list with sorted even indices values and original odd indices values\n for i in range(len(l)):\n if i % 2 == 0:\n result.append(even_indices_values[even_index])\n even_index += 1\n else:\n result.append(l[i])\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n \"\"\"\n # Extract the even indexed elements (0-based indexing), sort them\n even_indexed_elements_sorted = sorted(l[::2])\n \n # Result list initialized with the same elements as l\n result = l[:]\n \n # Replace the even indexed elements of result with the sorted elements\n result[::2] = even_indexed_elements_sorted\n \n return result", "matching_cluster_idx": 9}, {"solution": "def sort_even(l: list):\n \"\"\"\n This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n \"\"\"\n # Extract elements at even indices\n even_indices_elements = sorted(l[::2])\n \n # Initialize an empty list to hold the result\n result = []\n even_index = 0\n \n for i in range(len(l)):\n if i % 2 == 0:\n # If the index is even, append the next sorted even-index element\n result.append(even_indices_elements[even_index])\n even_index += 1\n else:\n # If the index is odd, append the original odd-index element\n result.append(l[i])\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n \"\"\"\n # Extract the elements at even indices\n even_index_elements = sorted(l[::2])\n \n # Iterate through the list and replace the elements at even indices\n result = l[:]\n for i, value in enumerate(even_index_elements):\n result[2*i] = value\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n \"\"\"\n # Extracting the even index elements from the list\n even_indices_elements = sorted((l[i] for i in range(len(l)) if i % 2 == 0))\n \n # Iterating through the list and replacing even index elements with the sorted ones\n result = l[:]\n even_index = 0\n for i in range(len(result)):\n if i % 2 == 0:\n result[i] = even_indices_elements[even_index]\n even_index += 1\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n \"\"\"\n # Extract even-index elements and sort them\n even_elements = sorted((l[i] for i in range(len(l)) if i % 2 == 0))\n \n # Generate the result list\n result = []\n even_elements_index = 0\n for i in range(len(l)):\n if i % 2 == 0:\n # Use the sorted element at even index\n result.append(even_elements[even_elements_index])\n even_elements_index += 1\n else:\n # Keep the original element at odd index\n result.append(l[i])\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"\n This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n \"\"\"\n # Extract elements at even indices\n even_indices_elements = sorted(l[::2])\n \n # Initialize an empty list to store the result\n result = []\n \n even_index = 0 # Index to keep track of the sorted even index elements\n \n for i in range(len(l)):\n if i % 2 == 0:\n # For even indices, append from the sorted even indices elements\n result.append(even_indices_elements[even_index])\n even_index += 1\n else:\n # For odd indices, just append the original value\n result.append(l[i])\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"\n This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n \"\"\"\n # Extract the even indexed elements and sort them\n even_elements = sorted(l[::2])\n \n # Initialize an empty list to store the result\n result = []\n even_index = 0\n \n for i in range(len(l)):\n if i % 2 == 0:\n # Use the sorted even indexed elements for even positions\n result.append(even_elements[even_index])\n even_index += 1\n else:\n # Keep the odd indexed elements as they are\n result.append(l[i])\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n \"\"\"\n # Extracting elements at even indices\n even_indices_elements = sorted(l[i] for i in range(len(l)) if i % 2 == 0)\n \n # Creating a new list l' where elements at even indices are sorted, and odd indices are unchanged\n l_prime = []\n even_elements_index = 0\n for i in range(len(l)):\n if i % 2 == 0:\n l_prime.append(even_indices_elements[even_elements_index])\n even_elements_index += 1\n else:\n l_prime.append(l[i])\n \n return l_prime", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n \"\"\"\n # Extract elements at even indices and sort them\n even_indices_elements = sorted(l[::2])\n \n # Iterator for the sorted even index elements\n even_indices_iter = iter(even_indices_elements)\n \n # Rebuild the list with sorted elements at even indices\n result = [next(even_indices_iter) if i % 2 == 0 else element for i, element in enumerate(l)]\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n \"\"\"\n # Extract elements at even indices\n even_indices_elements = sorted(l[::2])\n \n # Initialize the list to be returned\n result = l[:]\n \n # Insert sorted even-index elements back into the result list\n for index, value in enumerate(even_indices_elements):\n result[2 * index] = value\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"\n This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n \"\"\"\n # Extract the elements at even indices and sort them\n even_indices_elements = sorted(l[::2])\n \n # Initialize an index for the sorted elements\n even_index = 0\n \n # Create a new list to hold the result\n result = l.copy() # Copy the original list to keep odd indices unchanged\n \n # Iterate through the list and replace elements at even indices with sorted ones\n for i in range(0, len(result), 2):\n result[i] = even_indices_elements[even_index]\n even_index += 1\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n \"\"\"\n # Extract the even indexed elements\n even_indexed_elements = [l[i] for i in range(len(l)) if i % 2 == 0]\n # Sort the extracted elements\n even_indexed_elements.sort()\n\n # Create a new list initialized with None to hold the final result\n l_prime = [None] * len(l)\n\n # Place the odd indexed elements in their correct positions\n for i in range(len(l)):\n if i % 2 != 0:\n l_prime[i] = l[i]\n \n # Place the sorted even indexed elements in their correct positions\n for i in range(len(l)):\n if i % 2 == 0:\n l_prime[i] = even_indexed_elements.pop(0)\n \n return l_prime", "matching_cluster_idx": 8}]}, "HumanEval/49": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def modp(n: int, p: int) -> int:\n \"\"\"\n Return 2^n modulo p (be aware of numerics).\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"\n Return 2^n modulo p (be aware of numerics).\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"\n Return 2^n modulo p (be aware of numerics).\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"\n Return 2^n modulo p (be aware of numerics).\n \n Args:\n n (int): The exponent to which 2 is raised.\n p (int): The modulo value.\n \n Returns:\n int: The result of 2^n modulo p.\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"\n Return 2^n modulo p (be aware of numerics).\n \n Args:\n n (int): The exponent to which 2 is raised.\n p (int): The modulus.\n\n Returns:\n int: The result of (2^n) mod p.\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"\n Return 2^n modulo p (be aware of numerics).\n \n Args:\n n (int): The exponent to which 2 is raised.\n p (int): The modulus.\n\n Returns:\n int: 2^n modulo p.\n \"\"\"\n # Calculate 2^n modulo p using Python's built-in pow function for efficiency\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"\n Return 2^n modulo p (be aware of numerics).\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"\n Return 2^n modulo p (be aware of numerics).\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"\n Return 2^n modulo p (be aware of numerics).\n \n Args:\n n (int): The exponent to raise 2 to.\n p (int): The modulus.\n \n Returns:\n int: The result of (2^n) % p.\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"\n Return 2^n modulo p (be aware of numerics).\n \n Args:\n n (int): The exponent to which 2 is raised.\n p (int): The modulus.\n\n Returns:\n int: The result of 2^n modulo p.\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"\n Return 2^n modulo p (be aware of numerics).\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"\n Return 2^n modulo p (be aware of numerics).\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int):\n \"\"\"\n Return 2^n modulo p (be aware of numerics).\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"\n Return 2^n modulo p (be aware of numerics).\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"\n Return 2^n modulo p (be aware of numerics).\n \"\"\"\n # This function calculates 2^n modulo p using Python's built-in power operator\n # which is efficient and handles large numbers gracefully.\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"\n Return 2^n modulo p (be aware of numerics).\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"\n Return 2^n modulo p (be aware of numerics).\n \n Args:\n n (int): The exponent to raise 2 by.\n p (int): The modulo value.\n \n Returns:\n int: The result of (2^n) % p.\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"\n Return 2^n modulo p (be aware of numerics).\n \n Args:\n n (int): The exponent to which 2 is raised.\n p (int): The modulus.\n \n Returns:\n int: The result of (2^n) % p.\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"\n Return 2^n modulo p (be aware of numerics).\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"\n Return 2^n modulo p (be aware of numerics).\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}]}, "HumanEval/51": {"dps": 96.13526570048309, "dps_norm": 75.0, "pass@1": 100.0, "profiled": [{"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes a string and returns a string without vowels.\n \"\"\"\n vowels = 'aeiouAEIOU'\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n \"\"\"\n vowels = 'aeiouAEIOU'\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = set(\"aeiouAEIOU\")\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes a string and returns a string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\\\nghijklm\")\n 'bcdf\\\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes a string and returns a string without vowels.\n \"\"\"\n vowels = 'aeiouAEIOU'\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes a string and returns a string without vowels.\n \"\"\"\n vowels = \"aeiouAEIOU\"\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes a string and returns the string without vowels.\n \"\"\"\n vowels = 'aeiouAEIOU'\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n \"\"\"\n vowels = 'aeiouAEIOU'\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n \"\"\"\n vowels = 'aeiouAEIOU'\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes a string and returns a string without vowels.\n \"\"\"\n vowels = 'aeiouAEIOU'\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n \"\"\"\n vowels = \"aeiouAEIOU\"\n return \"\".join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes a string and returns a string without vowels.\n \"\"\"\n vowels = 'aeiouAEIOU'\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes a string and returns a string without vowels.\n \"\"\"\n vowels = 'aeiouAEIOU'\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = set(\"aeiouAEIOU\")\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n \"\"\"\n vowels = \"aeiouAEIOU\"\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n \"\"\"\n vowels = 'aeiouAEIOU'\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n result = ''.join([char for char in text if char not in vowels])\n return result", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n \"\"\"\n vowels = 'aeiouAEIOU'\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}]}, "HumanEval/54": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 93.0, "profiled": [{"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \"\"\"\n # Convert strings to sets of characters to eliminate duplicates and then compare\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \n Args:\n s0 (str): The first word to compare.\n s1 (str): The second word to compare.\n \n Returns:\n bool: True if both words have the same set of characters, False otherwise.\n \"\"\"\n # Convert both strings to sets to remove duplicates and compare\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \"\"\"\n # Convert both strings to character sets and compare them\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \n Args:\n s0 (str): The first string.\n s1 (str): The second string.\n \n Returns:\n bool: True if both strings contain the same characters, False otherwise.\n \"\"\"\n # Using set to store unique characters of both strings\n set_s0 = set(s0)\n set_s1 = set(s1)\n \n # Check if both sets are equal\n return set_s0 == set_s1", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \n Args:\n s0 (str): The first string to compare.\n s1 (str): The second string to compare.\n \n Returns:\n bool: True if both strings have the same characters, False otherwise.\n \"\"\"\n # Convert both strings to sets of characters and compare\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \"\"\"\n # Convert both strings to character sets and compare them\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \n Args:\n s0 (str): The first word to compare.\n s1 (str): The second word to compare.\n \n Returns:\n bool: True if both words are composed of the same set of characters, False otherwise.\n \"\"\"\n # Convert each string to a set of characters and compare them\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \n Args:\n s0 (str): The first word.\n s1 (str): The second word.\n \n Returns:\n bool: True if both words are composed of the same characters, False otherwise.\n \"\"\"\n # Remove all occurrences of each character in s0 from s1 and vice versa\n # If the resulting strings are empty, then s0 and s1 have the same characters\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \"\"\"\n # Convert both strings to character sets and compare them\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')\n True\n >>> same_chars('abcd', 'dddddddabc')\n True\n >>> same_chars('dddddddabc', 'abcd')\n True\n >>> same_chars('eabcd', 'dddddddabc')\n False\n >>> same_chars('abcd', 'dddddddabce')\n False\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')\n False\n \"\"\"\n # Convert both strings to sets and compare if they are equal\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \"\"\"\n # Convert both strings to character sets and compare\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \"\"\"\n # Convert both strings to sets of characters and compare them\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \n Args:\n s0 (str): The first string to compare.\n s1 (str): The second string to compare.\n \n Returns:\n bool: True if both strings are composed of the same characters (regardless of frequency or order), False otherwise.\n \"\"\"\n # Convert both strings to sets of characters\n set_s0 = set(s0)\n set_s1 = set(s1)\n \n # Check if both sets are equal\n return set_s0 == set_s1", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \n Args:\n s0 (str): The first string.\n s1 (str): The second string.\n \n Returns:\n bool: True if both strings contain the same unique characters, False otherwise.\n \"\"\"\n # Convert both strings to sets of characters to eliminate duplicates and compare\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \"\"\"\n # Convert both strings to character sets and compare\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \"\"\"\n # Convert strings to sets of characters\n set0 = set(s0)\n set1 = set(s1)\n \n # Check if sets are equal, meaning both strings have the same unique characters\n return set0 == set1", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \n Args:\n s0 (str): The first input string.\n s1 (str): The second input string.\n \n Returns:\n bool: True if both strings are made up of the same characters, False otherwise.\n \"\"\"\n # Convert both strings into sets of characters and compare them\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \n Args:\n s0 (str): The first string.\n s1 (str): The second string.\n \n Returns:\n bool: True if both strings are composed of the same characters, False otherwise.\n \"\"\"\n # Convert both strings to sets of characters and compare them\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \"\"\"\n # Convert both strings to sets and compare them\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \"\"\"\n # Convert both strings into sets of characters\n set_s0 = set(s0)\n set_s1 = set(s1)\n \n # Check if both sets are equal\n return set_s0 == set_s1", "matching_cluster_idx": 6}]}, "HumanEval/58": {"dps": 92.51968503937007, "dps_norm": 83.33333333333333, "pass@1": 100.0, "profiled": [{"solution": "def common(l1: list, l2: list):\n \"\"\"\n Return sorted unique common elements for two lists.\n \n :param l1: First list of integers.\n :param l2: Second list of integers.\n :return: Sorted list of unique common elements.\n \"\"\"\n # Use set intersection to find common elements and convert back to sorted list\n return sorted(list(set(l1) & set(l2)))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"\n Return sorted unique common elements for two lists.\n \"\"\"\n # Convert lists to sets to remove duplicates and find common elements\n common_set = set(l1).intersection(set(l2))\n # Convert the set back to a sorted list\n return sorted(list(common_set))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"\n Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n # Convert both lists to sets to remove duplicates and find common elements\n common_elements = set(l1) & set(l2)\n # Convert the set back to a list and sort it\n return sorted(list(common_elements))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"\n Return sorted unique common elements for two lists.\n \n Args:\n l1 (list): First list of integers.\n l2 (list): Second list of integers.\n \n Returns:\n list: Sorted list of unique common elements.\n \"\"\"\n # Convert both lists to sets to remove duplicates and find common elements\n common_elements = set(l1).intersection(set(l2))\n # Return the sorted list of common elements\n return sorted(list(common_elements))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"\n Return sorted unique common elements for two lists.\n \"\"\"\n # Convert lists to sets to remove duplicates and find intersection\n set1 = set(l1)\n set2 = set(l2)\n common_elements = set1.intersection(set2)\n \n # Convert the set back to a sorted list\n result = sorted(list(common_elements))\n return result", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\"\"\"\n # Use set intersection to find common elements and sort them\n return sorted(list(set(l1) & set(l2)))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"\n Return sorted unique common elements for two lists.\n \n Args:\n l1: First list of integers.\n l2: Second list of integers.\n \n Returns:\n A sorted list of unique integers that are common to both input lists.\n \"\"\"\n # Convert both lists to sets to remove duplicates and find intersection\n common_elements = set(l1) & set(l2)\n # Convert the set back to a sorted list\n return sorted(list(common_elements))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"\n Return sorted unique common elements for two lists.\n \n Args:\n l1 (list): First list of elements.\n l2 (list): Second list of elements.\n \n Returns:\n list: A sorted list of unique common elements between l1 and l2.\n \"\"\"\n # Convert both lists to sets to remove duplicates and find intersection\n common_elements = set(l1).intersection(l2)\n # Convert the set back to a sorted list\n return sorted(list(common_elements))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"\n Return sorted unique common elements for two lists.\n \"\"\"\n # Convert both lists to sets to remove duplicates and find intersection\n common_elements = set(l1) & set(l2)\n # Convert the set back to a sorted list\n return sorted(common_elements)", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"\n Return sorted unique common elements for two lists.\n \n Args:\n l1 (list): The first list of elements.\n l2 (list): The second list of elements.\n \n Returns:\n list: A sorted list of unique common elements.\n \"\"\"\n # Convert both lists to sets to remove duplicates and find common elements\n common_elements = set(l1).intersection(l2)\n # Return a sorted list of the common elements\n return sorted(list(common_elements))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n \"\"\"\n # Convert lists to sets to remove duplicates and find common elements\n common_elements = set(l1) & set(l2)\n # Return sorted list of common elements\n return sorted(list(common_elements))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"\n Return sorted unique common elements for two lists.\n \n Args:\n l1 (list): First list of integers.\n l2 (list): Second list of integers.\n \n Returns:\n list: A list containing the sorted unique common elements between l1 and l2.\n \"\"\"\n # Convert both lists to sets to remove duplicates and find common elements\n common_elements = set(l1) & set(l2)\n # Convert the set back to a list and sort it\n return sorted(list(common_elements))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\"\"\"\n # Use set intersection to find common elements and then sort the result\n return sorted(set(l1) & set(l2))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"\n Return sorted unique common elements for two lists.\n \n Args:\n l1 (list): The first list of integers.\n l2 (list): The second list of integers.\n \n Returns:\n list: A sorted list containing the unique common elements from both input lists.\n \"\"\"\n # Use set intersection to find common elements and then convert the result back to a sorted list\n return sorted(list(set(l1) & set(l2)))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n \"\"\"\n # Use set intersection to find common elements and then sort them\n return sorted(list(set(l1) & set(l2)))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"\n Return sorted unique common elements for two lists.\n \n Args:\n l1 (list): First list of elements.\n l2 (list): Second list of elements.\n \n Returns:\n list: A sorted list containing unique common elements from both lists.\n \"\"\"\n # Convert lists to sets to remove duplicates and find intersection\n common_elements = set(l1) & set(l2)\n # Return the sorted list of common elements\n return sorted(common_elements)", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"\n Return sorted unique common elements for two lists.\n \n Args:\n l1 (list): The first list of elements.\n l2 (list): The second list of elements.\n \n Returns:\n list: A sorted list of unique common elements from the two lists.\n \"\"\"\n # Convert both lists to sets to remove duplicates and find common elements\n set1 = set(l1)\n set2 = set(l2)\n \n # Find the intersection of both sets\n common_elements = set1.intersection(set2)\n \n # Convert the set back to a sorted list\n result_list = sorted(list(common_elements))\n \n return result_list", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"\n Return sorted unique common elements for two lists.\n \n Args:\n l1 (list): The first list.\n l2 (list): The second list.\n \n Returns:\n list: A sorted list of unique common elements.\n \"\"\"\n # Use set intersection to find common elements and then convert it back to a sorted list\n return sorted(list(set(l1) & set(l2)))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"\n Return sorted unique common elements for two lists.\n \"\"\"\n # Convert both lists to sets to remove duplicates and find common elements\n common_elements = set(l1) & set(l2)\n # Convert the set back to a sorted list\n return sorted(list(common_elements))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"\n Return sorted unique common elements for two lists.\n \"\"\"\n # Use set intersection to find common elements\n common_elements = set(l1) & set(l2)\n # Return sorted list of common elements\n return sorted(list(common_elements))", "matching_cluster_idx": 4}]}, "HumanEval/59": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 91.0, "profiled": [{"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n \"\"\"\n i = 2\n while i * i <= n:\n if n % i:\n i += 1\n else:\n n //= i\n return n", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"\n Return the largest prime factor of n. Assume n > 1 and is not a prime.\n \"\"\"\n i = 2\n while i * i <= n:\n if n % i:\n i += 1\n else:\n n //= i\n return n", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"\n Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n # Start with the smallest prime factor\n factor = 2\n last_factor = 1\n # Divide n by all 2s first\n while n % factor == 0:\n last_factor = factor\n n //= factor\n # Now n must be odd, so we can skip one element (Note i = i + 2)\n factor = 3\n max_factor = n ** 0.5 # We only need to check up to the square root of n\n while factor <= max_factor:\n while n % factor == 0:\n last_factor = factor\n n //= factor\n max_factor = n ** 0.5 # Update the max factor limit\n factor += 2\n # If n is a prime number greater than 2\n if n > 1:\n last_factor = n\n return last_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n \"\"\"\n # Start with the smallest prime factor\n factor = 2\n last_factor = 1\n while n > 1:\n if n % factor == 0:\n last_factor = factor\n n //= factor\n else:\n factor += 1\n # Optimization: only check up to the square root of n\n if factor * factor > n:\n if n > 1:\n last_factor = n\n break\n return last_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n # Start with the smallest prime factor\n factor = 2\n last_factor = 1\n while n > 1:\n if n % factor == 0:\n last_factor = factor\n n //= factor\n # After dividing by factor, make sure to skip even numbers\n while n % factor == 0:\n n //= factor\n factor = factor + 1 if factor == 2 else factor + 2\n else:\n factor = factor + 1 if factor == 2 else factor + 2\n return last_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n # Start with the smallest prime factor\n factor = 2\n last_factor = 1\n while n > 1:\n if n % factor == 0:\n last_factor = factor\n n //= factor\n else:\n factor += 1\n # Optimization: only check odd factors after checking 2\n if factor * factor > n:\n if n > 1:\n last_factor = n\n break\n return last_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"\n Return the largest prime factor of n. Assume n > 1 and is not a prime.\n \"\"\"\n def is_prime(x):\n if x <= 1:\n return False\n if x == 2 or x == 3:\n return True\n if x % 2 == 0 or x % 3 == 0:\n return False\n i = 5\n while i * i <= x:\n if x % i == 0 or x % (i + 2) == 0:\n return False\n i += 6\n return True\n \n factor = 2\n last_prime = 1\n while n > 1:\n if n % factor == 0:\n last_prime = factor\n n //= factor\n while n % factor == 0:\n n //= factor\n factor += 1 if factor == 2 else 2\n return last_prime", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"\n Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n # Start with the smallest prime factor\n factor = 2\n last_factor = 1\n while n > 1:\n if n % factor == 0:\n last_factor = factor\n n //= factor\n else:\n factor += 1\n # Optimization: No need to check even numbers after 2\n if factor * factor > n:\n if n > 1:\n last_factor = n\n break\n return last_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"\n Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n # Initialize the smallest prime factor\n factor = 2\n last_factor = 1\n # Divide n by its smallest prime factors\n while n > 1:\n if n % factor == 0:\n last_factor = factor\n n //= factor # Use integer division\n else:\n factor += 1\n # Optimization: only check up to the square root of n\n if factor * factor > n:\n if n > 1:\n last_factor = n # The remaining n is a prime\n break\n return last_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"\n Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n # Start with the smallest prime factor\n factor = 2\n last_factor = 1\n while n > 1:\n if n % factor == 0:\n last_factor = factor\n n //= factor\n else:\n factor += 1\n # Optimization: only check up to the square root of n\n if factor * factor > n:\n if n > 1:\n last_factor = n\n break\n return last_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"\n Return the largest prime factor of n. Assume n > 1 and is not a prime.\n \"\"\"\n i = 2\n while i * i <= n:\n if n % i:\n i += 1\n else:\n n //= i\n return n", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"\n Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n factor = 2\n last_factor = 1\n while n > 1:\n if n % factor == 0:\n last_factor = factor\n n //= factor\n else:\n factor += 1\n if factor * factor > n: # if factor is larger than the square root of n\n if n > last_factor: # n is prime now\n last_factor = n\n break\n return last_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n # Initialize the smallest prime factor\n factor = 2\n last_factor = 1\n while n > 1:\n if n % factor == 0:\n last_factor = factor\n n //= factor\n else:\n factor += 1\n # Optimization: if factor squared is greater than n, n is a prime\n if factor * factor > n:\n if n > 1:\n last_factor = n\n break\n return last_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n \"\"\"\n i = 2\n while i * i <= n:\n if n % i:\n i += 1\n else:\n n //= i\n return n", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"\n Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n factor = 2 # Start with the smallest prime number\n last_factor = 1\n while n > 1:\n if n % factor == 0:\n last_factor = factor\n n //= factor\n else:\n factor += 1\n if factor * factor > n: # Check if factor is the last factor\n if n > 1:\n last_factor = n # n is prime and is the last factor\n break\n return last_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"\n Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n # Start with the smallest prime factor\n factor = 2\n last_factor = 1\n while n > 1:\n if n % factor == 0:\n last_factor = factor\n n //= factor\n else:\n factor += 1\n # Optimization: Only check up to the square root of n\n if factor * factor > n:\n if n > 1:\n return n\n else:\n return last_factor\n return last_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"\n Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n # Start with the smallest prime factor\n factor = 2\n last_factor = 1\n while n > 1:\n if n % factor == 0:\n last_factor = factor\n n //= factor\n else:\n factor += 1\n # Optimization: Only check odd numbers after 2\n if factor * factor > n:\n if n > 1:\n last_factor = n\n break\n return last_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"\n Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n # Function to find the largest prime factor\n def find_largest_prime_factor(number):\n largest_factor = 1\n # Divide n by 2 to remove all even factors\n while number % 2 == 0:\n largest_factor = 2\n number //= 2\n # Now n must be odd, start from 3 and remove all factors\n factor = 3\n while number != 1:\n while number % factor == 0:\n largest_factor = factor\n number //= factor\n factor += 2\n return largest_factor\n\n return find_largest_prime_factor(n)", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n # Start with the smallest prime factor\n factor = 2\n last_factor = 1\n # Divide n by factor as long as it's divisible, then move to the next factor\n while factor * factor <= n:\n if n % factor == 0:\n last_factor = factor\n n //= factor # Use integer division\n else:\n factor += 1\n # If n is not 1, it means n is a prime number and the largest prime factor.\n if n > 1:\n last_factor = n\n return last_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"\n Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n # Start with the smallest prime factor\n factor = 2\n last_factor = 1\n while n > 1:\n if n % factor == 0:\n last_factor = factor\n n //= factor\n else:\n factor += 1\n # Optimization: once factor exceeds the square root of n, n must be prime\n if factor * factor > n:\n if n > 1:\n return n\n else:\n return last_factor\n return last_factor", "matching_cluster_idx": 8}]}, "HumanEval/64": {"dps": 89.48051948051948, "dps_norm": 61.875, "pass@1": 97.0, "profiled": [{"solution": "def vowels_count(s):\n \"\"\"\n Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n \n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = 'aeiou'\n count = sum(1 for char in s.lower() if char in vowels)\n if s and s[-1].lower() == 'y':\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n \"\"\"\n Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = \"aeiouAEIOU\"\n count = 0\n for char in s:\n if char in vowels:\n count += 1\n if s and s[-1] in 'yY':\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n \"\"\"\n Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n \n :param s: The input string.\n :return: The number of vowels in the string.\n \"\"\"\n vowels = set('aeiouAEIOU')\n count = sum(1 for c in s if c in vowels)\n \n # Check if 'y' or 'Y' is at the end and add to count if true\n if s and (s[-1] == 'y' or s[-1] == 'Y'):\n count += 1\n \n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n \"\"\"\n Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n \"\"\"\n vowels = 'aeiouAEIOU'\n count = sum(1 for char in s if char in vowels)\n if s and s[-1].lower() == 'y':\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n \n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = 'aeiou'\n count = sum(1 for char in s.lower() if char in vowels)\n \n # Check if 'y' is at the end of the word and add to the count if true\n if s.lower().endswith('y'):\n count += 1\n \n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n \"\"\"\n Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = set(\"aeiouAEIOU\")\n count = sum(1 for c in s if c in vowels)\n \n # Check if the last character is 'y' or 'Y' and add it to the count if true\n if s and (s[-1] == 'y' or s[-1] == 'Y'):\n count += 1\n \n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n \"\"\"\n Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n \n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = 'aeiouAEIOU'\n count = sum(1 for char in s if char in vowels)\n \n # Check if the last character is 'y' or 'Y' and it's not followed by any other characters\n if s and (s[-1] == 'y' or s[-1] == 'Y'):\n count += 1\n \n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n \"\"\"\n Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = 'aeiouAEIOU'\n count = 0\n \n for char in s:\n if char in vowels:\n count += 1\n \n if s and s[-1].lower() == 'y':\n count += 1\n \n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n \"\"\"\n Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = set('aeiouAEIOU')\n count = sum(1 for char in s if char in vowels)\n \n # Check if 'y' or 'Y' is at the end of the string and add to count if true\n if s and (s[-1] == 'y' or s[-1] == 'Y'):\n count += 1\n \n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = {'a', 'e', 'i', 'o', 'u', 'A', 'E', 'I', 'O', 'U'}\n count = sum(1 for char in s if char in vowels)\n \n # Check if the last character is 'y' or 'Y' and increment the count if true\n if s and s[-1] in {'y', 'Y'}:\n count += 1\n \n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n \"\"\"\n Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n \"\"\"\n vowels = set('aeiouAEIOU')\n count = 0\n for i, char in enumerate(s):\n if char in vowels:\n count += 1\n elif char == 'y' or char == 'Y':\n if i == len(s) - 1:\n count += 1\n return count", "matching_cluster_idx": 3}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n \"\"\"\n vowels = 'aeiouAEIOU'\n count = sum(1 for char in s if char in vowels)\n \n # Check if 'y' or 'Y' is at the end of the word and count it as a vowel if true\n if s and (s[-1] == 'y' or s[-1] == 'Y'):\n count += 1\n \n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n \"\"\"\n Returns the number of vowels in the string.\n Vowels considered are 'a', 'e', 'i', 'o', 'u', and 'y' if it's at the end of the word.\n \n :param s: Input string\n :return: Number of vowels in the string\n \"\"\"\n vowels = 'aeiou'\n count = sum(1 for char in s.lower() if char in vowels)\n \n # Check if 'y' is at the end and add to the count if true\n if s.lower().endswith('y'):\n count += 1\n \n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n \"\"\"\n Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = 'aeiou'\n count = 0\n for char in s.lower():\n if char in vowels:\n count += 1\n # Check if the last character is 'y' or 'Y', and count it as a vowel\n if s and s[-1].lower() == 'y':\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n \"\"\"\n Returns the number of vowels in the given word.\n Vowels considered are 'a', 'e', 'i', 'o', 'u'.\n 'y' is considered a vowel if it is at the end of the word.\n \n :param s: A string representing the word.\n :return: The number of vowels in the string.\n \"\"\"\n vowels = {'a', 'e', 'i', 'o', 'u'}\n count = sum(1 for char in s.lower() if char in vowels)\n \n if s.lower().endswith('y'):\n count += 1\n \n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n \"\"\"\n Takes a string s as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. If 'y' is at the end of the word,\n it is also considered a vowel.\n \"\"\"\n vowels = \"aeiouAEIOU\"\n count = sum(1 for char in s if char in vowels)\n \n # Check if 'y' or 'Y' is at the end and increment count if so\n if s and (s[-1] == 'y' or s[-1] == 'Y'):\n count += 1\n \n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n \"\"\"\n Takes a string representing a word as input and returns the number of vowels in the string.\n Vowels are 'a', 'e', 'i', 'o', 'u', and 'y' is considered a vowel only if it is at the end of the word.\n \n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n # Convert the string to lowercase to ensure the case-insensitivity of the check.\n s = s.lower()\n vowels = 'aeiou'\n count = sum(1 for char in s if char in vowels)\n \n # Check if the last character is 'y' and if so, increment the count by 1.\n if s and s[-1] == 'y':\n count += 1\n \n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = 'aeiouAEIOU'\n count = 0\n for char in s:\n if char in vowels:\n count += 1\n if s and s[-1] in 'yY':\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n \"\"\"\n Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n \n :param s: The string to count vowels in.\n :return: The number of vowels in the string.\n \"\"\"\n vowels = \"aeiouAEIOU\"\n count = 0\n \n for char in s:\n if char in vowels:\n count += 1\n \n if s and s[-1].lower() == 'y':\n count += 1\n \n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n \"\"\"\n Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n \n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = 'aeiouAEIOU'\n count = sum(1 for char in s if char in vowels)\n if s and s[-1].lower() == 'y':\n count += 1\n return count", "matching_cluster_idx": 4}]}, "HumanEval/74": {"dps": 98.04878048780488, "dps_norm": 88.88888888888889, "pass@1": 87.0, "profiled": [{"solution": "def total_match(lst1, lst2):\n '''\n Function to compare two lists of strings based on the total number of characters in each list.\n Returns the list with fewer characters, or the first list if they are equal.\n '''\n # Calculate the total number of characters in each list\n total_chars_lst1 = sum(len(word) for word in lst1)\n total_chars_lst2 = sum(len(word) for word in lst2)\n\n # Compare and return the appropriate list\n if total_chars_lst1 <= total_chars_lst2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n # Calculate total number of characters in both lists\n count1 = sum(len(word) for word in lst1)\n count2 = sum(len(word) for word in lst2)\n\n # Return the list with fewer total characters, otherwise return the first list\n return lst1 if count1 <= count2 else lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n This function compares two lists of strings based on the total number of characters\n and returns the list with fewer characters. If both lists have the same number of\n characters, it returns the first list.\n '''\n def total_chars(lst):\n return sum(len(word) for word in lst)\n\n total_chars_lst1 = total_chars(lst1)\n total_chars_lst2 = total_chars(lst2)\n\n return lst1 if total_chars_lst1 <= total_chars_lst2 else lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n This function accepts two lists of strings and returns the list that has\n a total number of characters less than the other list. If the two lists\n have the same number of characters, it returns the first list.\n '''\n def total_chars(lst):\n return sum(len(s) for s in lst)\n\n total1 = total_chars(lst1)\n total2 = total_chars(lst2)\n\n if total1 <= total2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Accepts two lists of strings and returns the one with a smaller total character count.\n If counts are equal, returns the first list.\n '''\n def total_chars(lst):\n return sum(len(s) for s in lst)\n \n if total_chars(lst1) <= total_chars(lst2):\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n If the two lists have the same number of chars, return the first list.\n '''\n def total_chars(strings):\n return sum(len(s) for s in strings)\n\n total1 = total_chars(lst1)\n total2 = total_chars(lst2)\n \n return lst1 if total1 <= total2 else lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n\n # Calculate the total number of characters in both lists\n total_chars_lst1 = sum(len(word) for word in lst1)\n total_chars_lst2 = sum(len(word) for word in lst2)\n \n # Compare the total number of characters and return the appropriate list\n return lst1 if total_chars_lst1 <= total_chars_lst2 else lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n \n if the two lists have the same number of chars, return the first list.\n '''\n\n def total_chars(lst):\n return sum(len(s) for s in lst)\n\n chars_lst1 = total_chars(lst1)\n chars_lst2 = total_chars(lst2)\n\n return lst1 if chars_lst1 <= chars_lst2 else lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n This function compares two lists of strings based on the total number of characters\n and returns the list with fewer total characters. If both lists have the same number\n of characters, it returns the first list.\n '''\n\n def count_chars(lst):\n return sum(len(s) for s in lst)\n\n count1 = count_chars(lst1)\n count2 = count_chars(lst2)\n\n if count1 <= count2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n This function takes two lists of strings as input and returns the list with fewer total characters.\n If both lists have the same number of characters, it returns the first list.\n '''\n\n def count_chars(lst):\n return sum(len(s) for s in lst)\n\n count1 = count_chars(lst1)\n count2 = count_chars(lst2)\n\n return lst1 if count1 <= count2 else lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n # Calculate total number of characters in each list\n total_chars_lst1 = sum(len(word) for word in lst1)\n total_chars_lst2 = sum(len(word) for word in lst2)\n \n # Compare and return the appropriate list\n return lst2 if total_chars_lst2 < total_chars_lst1 else lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n This function takes two lists of strings and returns the list with fewer total characters.\n If both lists have the same number of characters, it returns the first list.\n '''\n def total_chars(lst):\n return sum(len(s) for s in lst)\n \n if total_chars(lst1) <= total_chars(lst2):\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n # Calculate total number of characters in lst1\n total_chars_lst1 = sum(len(word) for word in lst1)\n # Calculate total number of characters in lst2\n total_chars_lst2 = sum(len(word) for word in lst2)\n \n # Return the list with fewer total characters, or lst1 if equal\n if total_chars_lst1 <= total_chars_lst2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n # Calculate the total number of characters in each list\n total_chars_lst1 = sum(len(s) for s in lst1)\n total_chars_lst2 = sum(len(s) for s in lst2)\n\n # Return the list with fewer total characters, return lst1 if equal\n return lst1 if total_chars_lst1 <= total_chars_lst2 else lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n # Calculate the total number of characters in each list\n total_chars_lst1 = sum(len(word) for word in lst1)\n total_chars_lst2 = sum(len(word) for word in lst2)\n \n # Compare the total number of characters and return the appropriate list\n if total_chars_lst1 <= total_chars_lst2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n # Calculate the total number of characters in each list\n total_chars_lst1 = sum(len(s) for s in lst1)\n total_chars_lst2 = sum(len(s) for s in lst2)\n\n # Compare the totals and return the appropriate list\n if total_chars_lst1 <= total_chars_lst2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Function that compares two lists based on total characters in strings and returns\n the list with fewer total characters, or the first list if they are equal.\n '''\n def total_chars(lst):\n # Helper function to calculate total characters in a list of strings\n return sum(len(s) for s in lst)\n\n # Calculate the total number of characters in both lists\n total_chars_lst1 = total_chars(lst1)\n total_chars_lst2 = total_chars(lst2)\n\n # Return the list with fewer characters, or the first list if equal\n return lst1 if total_chars_lst1 <= total_chars_lst2 else lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n def total_chars(lst):\n return sum(len(s) for s in lst)\n\n total1 = total_chars(lst1)\n total2 = total_chars(lst2)\n\n return lst1 if total1 <= total2 else lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n def total_chars(lst):\n return sum(len(s) for s in lst)\n \n total1 = total_chars(lst1)\n total2 = total_chars(lst2)\n \n return lst1 if total1 <= total2 else lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n def total_chars(lst):\n return sum(len(string) for string in lst)\n \n total_chars_lst1 = total_chars(lst1)\n total_chars_lst2 = total_chars(lst2)\n \n if total_chars_lst1 <= total_chars_lst2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}]}, "HumanEval/85": {"dps": 91.68316831683168, "dps_norm": 60.0, "pass@1": 100.0, "profiled": [{"solution": "def add(lst):\n \"\"\"\n Given a non-empty list of integers lst, return the sum of even elements that are at odd indices.\n \n :param lst: List[int] - a non-empty list of integers\n :return: int - sum of even elements at odd indices\n \n Examples:\n add([4, 2, 6, 7]) ==> 2\n \"\"\"\n return sum(lst[i] for i in range(1, len(lst), 2) if lst[i] % 2 == 0)", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"\n Given a non-empty list of integers lst, return the sum of even elements that are at odd indices.\n\n :param lst: List[int] - a non-empty list of integers\n :return: int - the sum of even elements that are at odd indices\n \n Examples:\n add([4, 2, 6, 7]) ==> 2\n \"\"\"\n return sum(lst[i] for i in range(1, len(lst), 2) if lst[i] % 2 == 0)", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"\n Given a non-empty list of integers lst, return the sum of even elements that are at odd indices.\n \n Args:\n lst (List[int]): A non-empty list of integers.\n \n Returns:\n int: Sum of even elements at odd indices.\n \"\"\"\n return sum(lst[i] for i in range(1, len(lst), 2) if lst[i] % 2 == 0)", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"\n Given a non-empty list of integers lst, return the sum of even elements that are at odd indices.\n \n Args:\n lst (list): A non-empty list of integers.\n \n Returns:\n int: The sum of even elements at odd indices.\n \n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n return sum(lst[i] for i in range(1, len(lst), 2) if lst[i] % 2 == 0)", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"\n Given a non-empty list of integers lst, return the sum of the even elements that are at odd indices.\n \n Args:\n lst: A list of integers.\n \n Returns:\n int: The sum of even elements at odd indices.\n \n Examples:\n >>> add([4, 2, 6, 7]) \n 2\n >>> add([1, 3, 5, 7])\n 0\n >>> add([10, 22, 33, 47, 50, 60])\n 22\n \"\"\"\n # Initialize sum to 0\n total = 0\n # Iterate through the list, considering only odd indices\n for i in range(1, len(lst), 2):\n if lst[i] % 2 == 0:\n total += lst[i]\n return total", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"\n Given a non-empty list of integers lst. add the even elements that are at odd indices.\n \n Args:\n lst: List[int] -- a list of integers\n \n Returns:\n int -- sum of even elements that are at odd indices\n \"\"\"\n return sum(lst[i] for i in range(1, len(lst), 2) if lst[i] % 2 == 0)", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"\n Given a non-empty list of integers lst, return the sum of even elements that are at odd indices.\n \n :param lst: List of integers\n :return: Sum of even elements at odd indices\n \"\"\"\n return sum(lst[i] for i in range(1, len(lst), 2) if lst[i] % 2 == 0)", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"\n Given a non-empty list of integers lst, return the sum of even elements that are at odd indices.\n\n :param lst: List of integers\n :return: Sum of even elements at odd indices\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n return sum(lst[i] for i in range(1, len(lst), 2) if lst[i] % 2 == 0)", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"\n Given a non-empty list of integers lst, return the sum of even elements that are at odd indices.\n \n :param lst: List[int] - a non-empty list of integers\n :return: int - sum of even elements at odd indices\n \n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n return sum(lst[i] for i in range(1, len(lst), 2) if lst[i] % 2 == 0)", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"\n Given a non-empty list of integers lst, return the sum of even elements that are at odd indices.\n\n Args:\n lst (List[int]): A non-empty list of integers.\n\n Returns:\n int: The sum of even elements at odd indices.\n \"\"\"\n return sum(lst[i] for i in range(1, len(lst), 2) if lst[i] % 2 == 0)", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"\n Given a non-empty list of integers lst, add the even elements that are at odd indices.\n \n Parameters:\n lst (list): A non-empty list of integers.\n \n Returns:\n int: The sum of even elements that are at odd indices.\n \"\"\"\n # Initialize sum to 0\n sum_even_odd_indices = 0\n \n # Iterate through the list with index\n for index, value in enumerate(lst):\n # Check if the index is odd and the value is even\n if index % 2 != 0 and value % 2 == 0:\n sum_even_odd_indices += value\n \n return sum_even_odd_indices", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"\n Given a non-empty list of integers lst, add the even elements that are at odd indices.\n \n :param lst: List[int] - a non-empty list of integers\n :return: int - the sum of even elements at odd indices\n \n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n # Sum even elements at odd indices\n return sum(x for i, x in enumerate(lst) if i % 2 != 0 and x % 2 == 0)", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"\n Given a non-empty list of integers lst, return the sum of the even elements that are at odd indices.\n \n :param lst: List[int] - A non-empty list of integers\n :return: int - Sum of even elements at odd indices\n \n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n return sum(val for idx, val in enumerate(lst) if idx % 2 != 0 and val % 2 == 0)", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"\n Given a non-empty list of integers lst, return the sum of even elements that are at odd indices.\n \n Parameters:\n lst (list): A non-empty list of integers\n \n Returns:\n int: The sum of even elements at odd indices\n \n Examples:\n >>> add([4, 2, 6, 7])\n 2\n >>> add([1, 3, 5, 7, 9, 11])\n 0\n >>> add([2, 4, 6, 8, 10])\n 4\n \"\"\"\n return sum(x for i, x in enumerate(lst) if i % 2 != 0 and x % 2 == 0)", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"\n Given a non-empty list of integers lst, add the even elements that are at odd indices.\n \n Parameters:\n lst (List[int]): A non-empty list of integers\n \n Returns:\n int: The sum of even elements at odd indices\n \n Examples:\n >>> add([4, 2, 6, 7])\n 2\n >>> add([1, 4, 2, 3, 6])\n 0\n \"\"\"\n return sum(num for i, num in enumerate(lst) if i % 2 != 0 and num % 2 == 0)", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"\n Given a non-empty list of integers lst, return the sum of even elements that are at odd indices.\n\n :param lst: List of integers\n :return: Sum of even elements at odd indices\n\n Examples:\n add([4, 2, 6, 7]) ==> 2\n \"\"\"\n return sum(lst[i] for i in range(1, len(lst), 2) if lst[i] % 2 == 0)", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"\n Given a non-empty list of integers lst, the function adds the even elements that are at odd indices.\n \n Args:\n lst (list): A non-empty list of integers.\n \n Returns:\n int: The sum of even elements at odd indices.\n \n Examples:\n add([4, 2, 6, 7]) ==> 2\n \"\"\"\n # Initialize the sum to 0\n total = 0\n \n # Iterate through the list, checking only odd indices (1, 3, 5, ...)\n for i in range(1, len(lst), 2):\n if lst[i] % 2 == 0:\n total += lst[i]\n \n return total", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"\n Given a non-empty list of integers lst, return the sum of even elements that are at odd indices.\n \n Args:\n lst (List[int]): A non-empty list of integers.\n \n Returns:\n int: The sum of even elements at odd indices.\n \n Examples:\n add([4, 2, 6, 7]) ==> 2\n \"\"\"\n # Initialize sum to 0\n total_sum = 0\n \n # Iterate through the list, considering only odd indices\n for i in range(1, len(lst), 2):\n if lst[i] % 2 == 0:\n total_sum += lst[i]\n \n return total_sum", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"\n Given a non-empty list of integers lst, return the sum of the even elements that are at odd indices.\n \n :param lst: List[int] - a non-empty list of integers\n :return: int - sum of the even elements at odd indices\n \n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n return sum(lst[i] for i in range(1, len(lst), 2) if lst[i] % 2 == 0)", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"\n Given a non-empty list of integers lst, return the sum of even elements that are at odd indices.\n \n Args:\n lst: A list of integers.\n \n Returns:\n int: The sum of even elements at odd indices.\n \n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n # Initialize the sum to 0\n result = 0\n \n # Iterate through the list, starting from index 1 to only consider odd indices\n for i in range(1, len(lst), 2):\n # Check if the element at the current odd index is even\n if lst[i] % 2 == 0:\n # Add the even element to the result\n result += lst[i]\n \n return result", "matching_cluster_idx": 3}]}, "HumanEval/86": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 29.0, "profiled": [{"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n \"\"\"\n def sort_word(word):\n return ''.join(sorted(word))\n \n words = s.split(' ')\n ordered_words = [sort_word(word) for word in words]\n return ' '.join(ordered_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n \"\"\"\n def sort_word(word):\n return ''.join(sorted(word))\n \n words = s.split(' ')\n ordered_words = [sort_word(word) if word else word for word in words]\n return ' '.join(ordered_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n \"\"\"\n def sort_word(word):\n return ''.join(sorted(word))\n \n words = s.split(' ')\n sorted_words = [sort_word(word) if word else '' for word in words]\n return ' '.join(sorted_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n \"\"\"\n def sort_word(word):\n return ''.join(sorted(word))\n \n words = s.split(' ')\n sorted_words = [sort_word(word) if word else '' for word in words]\n return ' '.join(sorted_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n \"\"\"\n def sort_word(word):\n return ''.join(sorted(word))\n \n words = s.split(' ')\n ordered_words = [sort_word(word) for word in words]\n return ' '.join(ordered_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n \"\"\"\n def sort_word(word):\n return ''.join(sorted(word))\n \n words = s.split(' ')\n sorted_words = [sort_word(word) if word else '' for word in words]\n return ' '.join(sorted_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n \"\"\"\n # Split the sentence into words\n words = s.split(' ')\n \n # Sort each word and reconstruct the words list\n sorted_words = [''.join(sorted(w)) for w in words]\n \n # Join the sorted words back into a sentence\n return ' '.join(sorted_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n \"\"\"\n def sort_word(word):\n return ''.join(sorted(word))\n\n words = s.split(' ')\n sorted_words = [sort_word(word) for word in words]\n return ' '.join(sorted_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n This function takes a string and returns an ordered version of it.\n The ordered version of the string is obtained by sorting the characters\n in each word while maintaining the order of words and spaces.\n \"\"\"\n # Split the input string into words\n words = s.split(' ')\n \n # Initialize an empty list to hold the ordered words\n ordered_words = []\n \n # Iterate through each word in the list\n for word in words:\n # Sort the characters of the word\n sorted_word = ''.join(sorted(word))\n # Append the sorted word to the list\n ordered_words.append(sorted_word)\n \n # Join the ordered words back into a single string\n result = ' '.join(ordered_words)\n \n return result", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Replaces each word in the input string with an ordered version of itself.\n The ordered version of a word is a version where all characters are sorted\n in ascending order based on ASCII value.\n The order of words and blank spaces in the sentence is kept unchanged.\n \"\"\"\n # Split the string into words\n words = s.split(' ')\n \n # Sort each word and then join them back into a list\n sorted_words = [''.join(sorted(word)) for word in words]\n \n # Join the list back into a string with spaces\n return ' '.join(sorted_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n This function takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n \"\"\"\n def sort_word(word):\n return ''.join(sorted(word))\n \n words = s.split(' ')\n sorted_words = [sort_word(word) if word else '' for word in words]\n return ' '.join(sorted_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n \"\"\"\n def sort_word(word):\n return ''.join(sorted(word))\n \n words = s.split(' ')\n sorted_words = [sort_word(word) if word else '' for word in words]\n return ' '.join(sorted_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n \"\"\"\n # Split the input string into words\n words = s.split(' ')\n \n # Initialize an empty list to store the ordered words\n ordered_words = []\n \n # Loop through each word in the words list\n for word in words:\n # Sort the word by ascending order of characters and join them back into a string\n sorted_word = ''.join(sorted(word))\n ordered_words.append(sorted_word)\n \n # Join the ordered words back into a single string with spaces in between\n result = ' '.join(ordered_words)\n return result", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n This function takes a string and returns an ordered version of it.\n The ordered version of the string is a new string where all characters\n in each word are sorted in ascending ASCII order, while the order\n of words and spaces in the sentence is maintained.\n \"\"\"\n def sort_word(word):\n return ''.join(sorted(word))\n \n # Split the string into words and spaces\n words = s.split(' ')\n # Sort each word and reconstruct the string\n sorted_words = [sort_word(word) if word else '' for word in words]\n # Join the sorted words back into a string with spaces\n return ' '.join(sorted_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n \"\"\"\n def sort_word(word):\n return ''.join(sorted(word))\n \n words = s.split(' ')\n sorted_words = [sort_word(word) if word else word for word in words]\n return ' '.join(sorted_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Replaces each word in the input string with an ordered version of itself,\n where all characters in each word are sorted in ascending ASCII value order.\n Maintains the original order of words and spaces.\n \n :param s: String to be transformed\n :return: String with each word ordered by ASCII value of its characters\n \"\"\"\n return ' '.join(''.join(sorted(word)) for word in s.split(' '))", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n This function takes a string and returns an ordered version of it.\n An ordered version of a string is a version where all words in the string\n are sorted internally based on the ASCII values of their characters,\n but the order of words and spaces is maintained.\n \"\"\"\n # Split the string into words, sort each word, and then join them back\n return ' '.join(''.join(sorted(word)) for word in s.split(' '))", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n \"\"\"\n # Splitting the string into words\n words = s.split(' ')\n \n # Sorting each word and reassembling the string\n sorted_words = [''.join(sorted(word)) for word in words]\n \n # Joining the sorted words back with spaces\n return ' '.join(sorted_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n \"\"\"\n # Split the string into words\n words = s.split(' ')\n \n # Sort each word individually while keeping the order of words\n sorted_words = [''.join(sorted(word)) for word in words]\n \n # Join the sorted words back into a single string\n return ' '.join(sorted_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n \"\"\"\n def sort_word(word):\n return ''.join(sorted(word))\n \n words = s.split(' ')\n ordered_words = [sort_word(word) for word in words]\n return ' '.join(ordered_words)", "matching_cluster_idx": 4}]}, "HumanEval/87": {"dps": 93.94812680115274, "dps_norm": 57.142857142857146, "pass@1": 84.0, "profiled": [{"solution": "def get_row(lst, x):\n \"\"\"\n Finds all occurrences of integer x in the 2D list 'lst',\n returns a list of tuples representing the coordinates of these occurrences.\n Coordinates are sorted by row in ascending order and by column in descending order within the same row.\n \"\"\"\n # Find all occurrences of x and store their coordinates\n occurrences = [(row_index, column_index) \n for row_index, row in enumerate(lst) \n for column_index, value in enumerate(row) \n if value == x]\n \n # Sort by row in ascending order, then by column in descending order within the same row\n occurrences.sort(key=lambda tup: (tup[0], -tup[1]))\n \n return occurrences", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n This function takes a 2D list `lst` and an integer `x`. It searches for all occurrences of `x`\n in `lst` and returns their positions as a list of tuples, where each tuple represents a coordinate\n (row, column) starting from 0. The coordinates are first sorted by row in ascending order, then\n by column in descending order within the same row.\n \"\"\"\n # Find all occurrences of x and store their coordinates\n positions = [(i, j) for i, row in enumerate(lst) for j, value in enumerate(row) if value == x]\n\n # Sort by row in ascending order and then by column in descending order\n positions.sort(key=lambda p: (p[0], -p[1]))\n\n return positions", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n Finds occurrences of x in a 2D list, and returns a sorted list of tuples\n representing coordinates of those occurrences. Coordinates are sorted by row\n in ascending order and by column in descending order within the same row.\n \"\"\"\n # Initialize the result list\n result = []\n # Loop through the rows and columns of the given 2D list\n for row_idx, row in enumerate(lst):\n for col_idx, value in enumerate(row):\n if value == x:\n # Append the coordinate if the value matches x\n result.append((row_idx, col_idx))\n \n # Sort the result first by row in ascending order and then by column in descending order\n result.sort(key=lambda coord: (coord[0], -coord[1]))\n return result", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n This function finds occurrences of x in a 2D list and returns the coordinates in a sorted list of tuples.\n \"\"\"\n # Find all occurrences of x and store their coordinates\n occurrences = [(i, j) for i, row in enumerate(lst) for j, value in enumerate(row) if value == x]\n \n # Sort by row in ascending order, then by column in descending order for items in the same row\n occurrences.sort(key=lambda y: (y[0], -y[1]))\n \n return occurrences", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n This function finds the occurrences of a given integer x in a 2D list (lst)\n and returns the positions of these occurrences in a list of tuples.\n Each tuple represents the coordinates (row, column) of the found value, starting at 0.\n The result is sorted by rows in ascending order, and by columns in descending order for each row.\n \"\"\"\n # Collect all positions of x into a list of tuples (row, column)\n positions = [(i, j) for i, row in enumerate(lst) for j, val in enumerate(row) if val == x]\n \n # Sort positions by row in ascending order, and then by column in descending order within each row\n # This is achieved by sorting by i (row) in ascending order, then by -j (column in descending) order\n sorted_positions = sorted(positions, key=lambda pos: (pos[0], -pos[1]))\n \n return sorted_positions", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n This function finds all occurrences of the integer x in the 2D list (lst),\n and returns a sorted list of tuples indicating their positions.\n Each tuple contains two integers: (row, column) where row and column start at 0.\n The list is sorted first by rows in ascending order and then by columns in descending order within the same row.\n \"\"\"\n # Finding the occurrences\n occurrences = [(i, j) for i, row in enumerate(lst) for j, val in enumerate(row) if val == x]\n \n # Sorting by row in ascending order and then by column in descending order\n occurrences.sort(key=lambda pos: (pos[0], -pos[1]))\n \n return occurrences", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n # Find all occurrences of x and their coordinates\n coordinates = [(i, j) for i, row in enumerate(lst) for j, value in enumerate(row) if value == x]\n \n # Sort by rows in ascending order and columns in descending order within the same row\n sorted_coordinates = sorted(coordinates, key=lambda a: (a[0], -a[1]))\n \n return sorted_coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n Given a 2D list with varying row lengths and an integer x,\n find the integer x in the list, and return list of tuples,\n where each tuple is a coordinate (row, column) starting with 0.\n The coordinates are sorted by rows in ascending and then by columns in descending order.\n \"\"\"\n coordinates = []\n for row_index, row in enumerate(lst):\n for col_index, value in enumerate(row):\n if value == x:\n coordinates.append((row_index, col_index))\n \n # Sort by row in ascending order and then by column in descending order\n coordinates.sort(key=lambda tup: (tup[0], -tup[1]))\n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n Find the integer x in the nested lists and return the coordinates\n as a list of tuples sorted by rows in ascending and columns in descending order.\n \"\"\"\n # Find all occurrences of x and store their positions as (row, column) tuples\n positions = [(i, j) for i, row in enumerate(lst) for j, val in enumerate(row) if val == x]\n \n # Sort the positions by row in ascending order and by column in descending order\n sorted_positions = sorted(positions, key=lambda pos: (pos[0], -pos[1]))\n \n return sorted_positions", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n This function searches for all occurrences of x in a 2D list (lst),\n returning the coordinates in a specific order.\n \"\"\"\n coordinates = []\n for row_idx, row in enumerate(lst):\n for col_idx, value in enumerate(row):\n if value == x:\n coordinates.append((row_idx, col_idx))\n \n # Sort by row in ascending order, then by column in descending order for rows with the same index\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n Finds the coordinates of integer x in a 2D list (lst),\n where each row may have a different number of columns.\n Coordinates are returned as a sorted list of tuples [(x1, y1), ...].\n The list is sorted by rows in ascending order and by columns in descending order within each row.\n \"\"\"\n # Extract coordinates where the value matches x\n coordinates = [(row_index, column_index) \n for row_index, row in enumerate(lst) \n for column_index, value in enumerate(row) \n if value == x]\n \n # Sort by row in ascending order, then by column in descending order\n coordinates.sort(key=lambda tup: (tup[0], -tup[1]))\n \n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n # Find all coordinates where x is present and store them in a list\n coordinates = [(i, j) for i, row in enumerate(lst) for j, val in enumerate(row) if val == x]\n \n # Sort the coordinates first by row in ascending order, then by column in descending order\n # We use -j to achieve descending order of columns\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n \n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n This function searches for the integer x in the given 2D list lst and\n returns a list of coordinates (row, column) where x is found. The coordinates\n are sorted first by row in ascending order, then by column in descending order.\n \"\"\"\n # Collect positions where x is found\n positions = []\n for row_idx, row in enumerate(lst):\n for col_idx, value in enumerate(row):\n if value == x:\n positions.append((row_idx, col_idx))\n \n # Sort by row in ascending order, then by column in descending order\n positions.sort(key=lambda pos: (pos[0], -pos[1]))\n return positions", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n Searches for integer x in a nested list representing a non-uniform 2D matrix,\n and returns coordinates sorted by row in ascending order and by column in descending order.\n \"\"\"\n # Find all occurrences of x in the nested list and store their coordinates\n coordinates = [(i, j) for i, row in enumerate(lst) for j, value in enumerate(row) if value == x]\n \n # Sort the coordinates first by row in ascending order, then by column in descending order\n coordinates.sort(key=lambda y: (y[0], -y[1]))\n \n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n # Find coordinates of x in the list\n coordinates = [(i, j) for i, row in enumerate(lst) for j, val in enumerate(row) if val == x]\n # Sort coordinates by row ascending and column descending\n coordinates.sort(key=lambda c: (c[0], -c[1]))\n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n # Find all occurrences of x in the 2D list and record their coordinates\n coordinates = []\n for row_idx, row in enumerate(lst):\n for col_idx, value in enumerate(row):\n if value == x:\n coordinates.append((row_idx, col_idx))\n \n # Sort by row in ascending order, then by column in descending order within the same row\n coordinates.sort(key=lambda x: (-x[0], x[1]), reverse=True)\n # Sorting by row in ascending order directly\n # Sorting by column in descending order needs a reversed comparison in the sort function\n \n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \"\"\"\n # Find all occurrences of x in the 2D list and store them as (row, col) tuples\n occurrences = [(i, j) for i, row in enumerate(lst) for j, val in enumerate(row) if val == x]\n \n # Sort occurrences first by row in ascending order, then by column in descending order\n occurrences.sort(key=lambda coord: (coord[0], -coord[1]))\n \n return occurrences", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n Finds all occurrences of integer x in the nested list and returns their coordinates\n sorted by row in ascending order and by column in descending order within each row.\n \"\"\"\n # Collect coordinates of all occurrences of x\n coordinates = [(i, j) for i, row in enumerate(lst) for j, value in enumerate(row) if value == x]\n\n # Sort coordinates by row in ascending and then by column in descending order within the row\n coordinates.sort(key=lambda coord: (-coord[0], coord[1]), reverse=True)\n coordinates.sort(key=lambda coord: coord[0])\n\n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n Finds occurrences of integer x in a 2D list and returns their coordinates\n sorted by rows in ascending order and by columns in descending order within the same row.\n \"\"\"\n result = []\n # Iterate through each row in the list\n for row_idx, row in enumerate(lst):\n # Find all occurrences of x in the current row\n for col_idx, value in enumerate(row):\n if value == x:\n result.append((row_idx, col_idx))\n # Sort by row in ascending order and by column in descending order within the same row\n result.sort(key=lambda tup: (tup[0], -tup[1]))\n return result", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n Find the coordinates of integer x in the given 2D list and return a sorted list of tuples.\n \"\"\"\n # List to store the coordinates\n coordinates = []\n \n # Iterate through the rows and columns to find x\n for row_idx, row in enumerate(lst):\n for col_idx, elem in enumerate(row):\n if elem == x:\n # If found, append the coordinate to the list\n coordinates.append((row_idx, col_idx))\n \n # Sort the list of tuples first by row in ascending order, then by column in descending order\n sorted_coordinates = sorted(coordinates, key=lambda coord: (coord[0], -coord[1]))\n \n return sorted_coordinates", "matching_cluster_idx": 3}]}, "HumanEval/89": {"dps": 96.64948453608248, "dps_norm": 28.571428571428573, "pass@1": 98.0, "profiled": [{"solution": "def encrypt(s):\n \"\"\"Encrypts the input string by rotating the alphabet down by 4 places.\"\"\"\n result = []\n for char in s:\n if char.isalpha(): # Check if the character is a letter\n # Determine the shifted character, preserving the case\n shifted = chr(((ord(char.lower()) - 97 + 4) % 26) + 97)\n # Append the correctly cased shifted character to the result\n result.append(shifted.upper() if char.isupper() else shifted)\n else:\n # If the character is not a letter, just add it to the result\n result.append(char)\n return ''.join(result)", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Encrypts a string by rotating the alphabet down by 4 places.\"\"\"\n encrypted_string = []\n for char in s:\n if char.isalpha(): # Check if the character is a letter\n # Determine the offset and apply rotation\n offset = 65 if char.isupper() else 97\n rotated_char = chr(((ord(char) - offset + 4) % 26) + offset)\n encrypted_string.append(rotated_char)\n else:\n # Non-alphabetic characters are added as is\n encrypted_string.append(char)\n return ''.join(encrypted_string)", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Encrypts a string by shifting each letter down by four places.\"\"\"\n result = []\n for char in s:\n if char.isalpha():\n # Determine the ASCII code for 'a' or 'A' depending on the case\n base = ord('a') if char.islower() else ord('A')\n # Calculate the shifted character, wrapping around the alphabet if necessary\n shifted_char = chr((ord(char) - base + 4) % 26 + base)\n result.append(shifted_char)\n else:\n result.append(char)\n return ''.join(result)", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Encrypt a string by rotating the alphabet down by four places.\"\"\"\n result = []\n for char in s:\n if char.isalpha():\n base = ord('a') if char.islower() else ord('A')\n # Calculate the new character after rotation\n new_char = chr((ord(char) - base + 4) % 26 + base)\n result.append(new_char)\n else:\n result.append(char)\n return ''.join(result)", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Encrypts a given string by shifting each letter down the alphabet by 4 places.\"\"\"\n result = []\n for char in s:\n if 'a' <= char <= 'z':\n # Calculate the new character in the alphabet, wrapping around if necessary.\n new_char = chr(((ord(char) - ord('a') + 4) % 26) + ord('a'))\n result.append(new_char)\n elif 'A' <= char <= 'Z':\n # Calculate the new character in the alphabet, wrapping around if necessary.\n new_char = chr(((ord(char) - ord('A') + 4) % 26) + ord('A'))\n result.append(new_char)\n else:\n # Non-alphabetic characters are added unchanged.\n result.append(char)\n return ''.join(result)", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Encrypts a string by shifting each letter down by 4 places in the alphabet.\"\"\"\n result = \"\"\n for char in s:\n if char.isalpha():\n offset = 65 if char.isupper() else 97\n new_char = chr((ord(char) - offset + 4) % 26 + offset)\n result += new_char\n else:\n result += char\n return result", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Encrypts a string by shifting each letter down the alphabet by 4 places.\"\"\"\n result = []\n for char in s:\n if char.isalpha(): # Check if the character is a letter\n start = 'a' if char.islower() else 'A'\n # Calculate the shifted character\n shifted_char = chr((ord(char) - ord(start) + 4) % 26 + ord(start))\n result.append(shifted_char)\n else:\n result.append(char)\n return ''.join(result)", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Encrypts a string by rotating the alphabet down by four places.\"\"\"\n result = []\n for char in s:\n if 'a' <= char <= 'z':\n # Calculate the new character\n new_char = chr(((ord(char) - ord('a') + 4) % 26) + ord('a'))\n result.append(new_char)\n elif 'A' <= char <= 'Z':\n # Calculate the new character for uppercase letters\n new_char = chr(((ord(char) - ord('A') + 4) % 26) + ord('A'))\n result.append(new_char)\n else:\n # Non-alphabetic characters are added unchanged\n result.append(char)\n return ''.join(result)", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n def shift_char(c):\n if 'a' <= c <= 'z':\n return chr((ord(c) - ord('a') + 4) % 26 + ord('a'))\n elif 'A' <= c <= 'Z':\n return chr((ord(c) - ord('A') + 4) % 26 + ord('A'))\n else:\n return c\n\n return ''.join(shift_char(c) for c in s)", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Encrypts a string by rotating the alphabet by 4 places.\"\"\"\n def rotate_char(c):\n if 'a' <= c <= 'z':\n return chr((ord(c) - ord('a') + 4) % 26 + ord('a'))\n elif 'A' <= c <= 'Z':\n return chr((ord(c) - ord('A') + 4) % 26 + ord('A'))\n else:\n return c\n \n return ''.join(rotate_char(c) for c in s)", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Encrypts the input string by shifting each letter down by four places in the alphabet.\"\"\"\n result = []\n for char in s:\n if 'a' <= char <= 'z':\n # Calculate new character in the alphabet cycle\n new_char = chr(((ord(char) - ord('a') + 4) % 26) + ord('a'))\n result.append(new_char)\n elif 'A' <= char <= 'Z':\n # Calculate new character in the alphabet cycle for uppercase\n new_char = chr(((ord(char) - ord('A') + 4) % 26) + ord('A'))\n result.append(new_char)\n else:\n # Non-alphabetic characters are not changed\n result.append(char)\n return ''.join(result)", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Encrypts the input string by rotating the alphabet down by four places.\"\"\"\n def rotate_char(c):\n if 'a' <= c <= 'z':\n return chr((ord(c) - ord('a') + 4) % 26 + ord('a'))\n elif 'A' <= c <= 'Z':\n return chr((ord(c) - ord('A') + 4) % 26 + ord('A'))\n else:\n return c\n \n return ''.join(rotate_char(c) for c in s)", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Encrypts a string by rotating the alphabet down by 4 places.\"\"\"\n def rotate_char(c):\n if c.isalpha():\n base = ord('a') if c.islower() else ord('A')\n return chr((ord(c) - base + 4) % 26 + base)\n return c\n \n return ''.join(rotate_char(c) for c in s)", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Encrypts a string by rotating the alphabet down by four places.\"\"\"\n def shift(c):\n if 'a' <= c <= 'z':\n return chr((ord(c) - ord('a') + 4) % 26 + ord('a'))\n elif 'A' <= c <= 'Z':\n return chr((ord(c) - ord('A') + 4) % 26 + ord('A'))\n else:\n return c\n\n return ''.join(shift(c) for c in s)", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Encrypts the given string by rotating the alphabet down by four places.\"\"\"\n # Define the alphabet and the rotation amount\n alphabet = \"abcdefghijklmnopqrstuvwxyz\"\n rotation = 4\n \n encrypted_text = \"\"\n \n for char in s:\n if char in alphabet:\n # Find the new character in the alphabet after rotation\n new_position = (alphabet.index(char) + rotation) % len(alphabet)\n encrypted_text += alphabet[new_position]\n else:\n # If the character is not in the alphabet, keep it as is\n encrypted_text += char\n \n return encrypted_text", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Encrypts a string by rotating the alphabet down by 4 places.\"\"\"\n def rotate_char(c):\n if c.isalpha():\n start = 'a' if c.islower() else 'A'\n # Calculate the position of the character in the alphabet (0-25 for a-z, A-Z)\n offset = ord(start)\n # Rotate the character by 4 positions and wrap around the alphabet if necessary\n return chr((ord(c) - offset + 4) % 26 + offset)\n else:\n return c\n \n return ''.join(rotate_char(c) for c in s)", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Encrypts the input string by shifting each letter down by 4 places in the alphabet.\"\"\"\n result = []\n for char in s:\n if char.isalpha():\n # Determine the base ('A' or 'a') and calculate the new shifted character\n base = ord('A') if char.isupper() else ord('a')\n # Shift character by 4 places, wrapping around using modulo 26 if necessary\n new_char_code = (ord(char) - base + 4) % 26 + base\n result.append(chr(new_char_code))\n else:\n # Non-alphabetic characters are added unchanged\n result.append(char)\n return ''.join(result)", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Encrypt a string by rotating the alphabet down by 4 places.\"\"\"\n result = []\n for char in s:\n if 'a' <= char <= 'z':\n # Calculate new character position\n new_pos = (ord(char) - ord('a') + 4) % 26 + ord('a')\n result.append(chr(new_pos))\n else:\n # If character is not a lowercase letter, keep it as is\n result.append(char)\n return ''.join(result)", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Encrypts a string by shifting each letter down by 4 places in the alphabet.\"\"\"\n encrypted = []\n for char in s:\n if 'a' <= char <= 'z': # Lowercase letters\n offset = ord('a')\n elif 'A' <= char <= 'Z': # Uppercase letters\n offset = ord('A')\n else:\n encrypted.append(char) # Non-alphabet characters are appended as is\n continue\n \n # Calculate new character after rotation\n new_char = chr(((ord(char) - offset + 4) % 26) + offset)\n encrypted.append(new_char)\n \n return ''.join(encrypted)", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Encrypts a string by shifting each letter down by 4 places in the alphabet.\"\"\"\n result = []\n for char in s:\n if char.isalpha():\n shift = 65 if char.isupper() else 97\n encrypted_char = chr((ord(char) - shift + 4) % 26 + shift)\n result.append(encrypted_char)\n else:\n result.append(char)\n return ''.join(result)", "matching_cluster_idx": 1}]}, "HumanEval/90": {"dps": 83.96887159533074, "dps_norm": 57.5, "pass@1": 100.0, "profiled": [{"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n unique_sorted_lst = sorted(set(lst))\n if len(unique_sorted_lst) < 2:\n return None\n else:\n return unique_sorted_lst[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n unique_elements = set(lst)\n if len(unique_elements) < 2:\n return None\n sorted_unique_elements = sorted(unique_elements)\n return sorted_unique_elements[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \"\"\"\n if len(lst) < 2:\n return None\n\n unique_elements = set(lst)\n if len(unique_elements) < 2:\n return None\n\n # Convert the set back to a list and sort it to find the 2nd smallest\n sorted_unique = sorted(list(unique_elements))\n return sorted_unique[1]", "matching_cluster_idx": 5}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n \n smallest = second_smallest = float('inf')\n for number in lst:\n if number < smallest:\n second_smallest = smallest\n smallest = number\n elif smallest < number < second_smallest:\n second_smallest = number\n \n return second_smallest if second_smallest != float('inf') else None", "matching_cluster_idx": 5}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \"\"\"\n # Remove duplicates by converting to a set, then back to a sorted list\n unique_sorted_lst = sorted(set(lst))\n \n # Check if there are at least 2 unique elements\n if len(unique_sorted_lst) < 2:\n return None\n else:\n # Return the 2nd smallest element\n return unique_sorted_lst[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n # Remove duplicates and sort the list\n unique_sorted_lst = sorted(set(lst))\n \n # Check if there are at least 2 unique elements\n if len(unique_sorted_lst) < 2:\n return None\n else:\n return unique_sorted_lst[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n # Remove duplicates and sort the list\n unique_sorted_lst = sorted(set(lst))\n \n # Check if there are at least 2 unique elements\n if len(unique_sorted_lst) < 2:\n return None\n else:\n return unique_sorted_lst[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n unique_elements = set(lst)\n if len(unique_elements) < 2:\n return None\n return sorted(unique_elements)[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n Finds the 2nd smallest element of the list.\n Returns None if there is no such element.\n \"\"\"\n unique_elements = set(lst)\n if len(unique_elements) < 2:\n return None\n else:\n sorted_elements = sorted(unique_elements)\n return sorted_elements[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n # Remove duplicates and sort the list\n sorted_unique_lst = sorted(set(lst))\n \n # Check if there are at least two unique elements\n if len(sorted_unique_lst) < 2:\n return None\n else:\n # Return the second smallest element\n return sorted_unique_lst[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n # Convert list to a set to remove duplicates and then back to a sorted list.\n unique_sorted_list = sorted(set(lst))\n \n # Check if there are at least 2 distinct elements.\n if len(unique_sorted_list) < 2:\n return None\n else:\n # Return the second element in the sorted list.\n return unique_sorted_list[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n \n # Convert the list to a set to remove duplicates and then back to a sorted list\n unique_sorted_list = sorted(set(lst))\n \n if len(unique_sorted_list) < 2:\n return None\n \n return unique_sorted_list[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n \n # Remove duplicates and sort the list\n unique_sorted_lst = sorted(set(lst))\n \n # Check if there is a second smallest element\n if len(unique_sorted_lst) < 2:\n return None\n \n return unique_sorted_lst[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n unique_lst = list(set(lst))\n if len(unique_lst) < 2:\n return None\n unique_lst.sort()\n return unique_lst[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n unique_numbers = list(set(lst))\n unique_numbers.sort()\n if len(unique_numbers) < 2:\n return None\n else:\n return unique_numbers[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \"\"\"\n # Remove duplicates and sort the list\n unique_sorted_lst = sorted(set(lst))\n \n # Check if there are at least 2 distinct elements\n if len(unique_sorted_lst) < 2:\n return None\n else:\n # Return the second element which is the 2nd smallest\n return unique_sorted_lst[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \"\"\"\n # Removing duplicates and sorting the list\n unique_sorted_lst = sorted(set(lst))\n \n # Checking if there are at least two unique elements\n if len(unique_sorted_lst) < 2:\n return None\n else:\n # Return the second smallest element\n return unique_sorted_lst[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n unique_sorted_lst = sorted(set(lst))\n if len(unique_sorted_lst) < 2:\n return None\n return unique_sorted_lst[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n Finds the second smallest element in a list of integers.\n Returns None if there is no such element.\n \"\"\"\n unique_elements = list(set(lst))\n if len(unique_elements) < 2:\n return None\n unique_elements.sort()\n return unique_elements[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n # First, we remove duplicates by converting the list to a set and then back to a list\n unique_lst = list(set(lst))\n \n # If there are less than 2 unique elements, there's no 2nd smallest element\n if len(unique_lst) < 2:\n return None\n \n # Sort the list to find the 2nd smallest element\n unique_lst.sort()\n \n # Return the 2nd smallest element\n return unique_lst[1]", "matching_cluster_idx": 6}]}, "HumanEval/113": {"dps": 98.98580121703854, "dps_norm": 66.66666666666667, "pass@1": 99.0, "profiled": [{"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n \"\"\"\n def count_odds(s):\n return sum(1 for c in s if int(c) % 2 != 0)\n\n result = []\n for s in lst:\n odd_number = count_odds(s)\n formatted_string = f\"the number of odd elements {odd_number}n the str{odd_number}ng {odd_number} of the {odd_number}nput.\"\n result.append(formatted_string)\n return result", "matching_cluster_idx": 3}, {"solution": "def count_odds_in_string(s):\n \"\"\"Helper function to count the number of odd digits in a string.\"\"\"\n return sum(1 for char in s if int(char) % 2 != 0)\ndef odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be a sentence indicating the number of odd\n elements in the i'th string of the input, with the numbers replaced by the count of\n odd digits.\n\n :param lst: List of strings consisting of digits.\n :return: List of formatted strings indicating the number of odd elements.\n \"\"\"\n result = []\n for s in lst:\n odd_count = count_odds_in_string(s)\n formatted_string = f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\"\n result.append(formatted_string)\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n \"\"\"\n def count_odds(s):\n \"\"\"Helper function to count the number of odd digits in a string.\"\"\"\n return sum(1 for digit in s if int(digit) % 2 != 0)\n \n result = []\n for s in lst:\n odds = count_odds(s)\n formatted_str = f\"the number of odd elements {odds}n the str{odds}ng {odds} of the {odds}nput.\"\n result.append(formatted_str)\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"\n Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n \"\"\"\n result = []\n for s in lst:\n odd_digits_count = sum(1 for digit in s if int(digit) % 2 != 0)\n formatted_string = f\"the number of odd elements {odd_digits_count}n the str{odd_digits_count}ng {odd_digits_count} of the {odd_digits_count}nput.\"\n result.append(formatted_string)\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n \"\"\"\n def count_odd_digits(s):\n \"\"\"Count the number of odd digits in a string.\"\"\"\n return sum(1 for digit in s if int(digit) % 2 != 0)\n\n result = []\n for s in lst:\n odd_count = count_odd_digits(s)\n formatted_str = f'the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.'\n result.append(formatted_str)\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n \"\"\"\n def count_odds(s):\n \"\"\"Helper function to count the number of odd digits in a string.\"\"\"\n return sum(int(digit) % 2 != 0 for digit in s)\n\n result = []\n for s in lst:\n num_odds = count_odds(s)\n formatted_string = f\"the number of odd elements {num_odds}n the str{num_odds}ng {num_odds} of the {num_odds}nput.\"\n result.append(formatted_string)\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n \"\"\"\n def count_odds(s):\n # Count the number of odd digits in the string s\n return sum(1 for c in s if int(c) % 2 != 0)\n \n result = []\n for s in lst:\n # Count how many odd digits are in the current string\n odd_digits_count = count_odds(s)\n # Construct the result string with the count of odd digits in place of 'i'\n result.append(f'the number of odd elements {odd_digits_count}n the str{odd_digits_count}ng {odd_digits_count} of the {odd_digits_count}nput.')\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n \"\"\"\n def count_odds(s):\n return sum(1 for char in s if int(char) % 2 != 0)\n \n result = []\n for s in lst:\n odd_digits = count_odds(s)\n result.append(f\"the number of odd elements {odd_digits}n the str{odd_digits}ng {odd_digits} of the {odd_digits}nput.\")\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"\n Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n \"\"\"\n def count_odds(s):\n \"\"\"Count the number of odd digits in a string.\"\"\"\n return sum(1 for digit in s if int(digit) % 2 != 0)\n\n result = []\n for s in lst:\n odds = count_odds(s)\n formatted_string = f\"the number of odd elements {odds}n the str{odds}ng {odds} of the {odds}nput.\"\n result.append(formatted_string)\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n result = []\n for string in lst:\n # Count the number of odd digits in the string\n odd_count = sum(int(digit) % 2 != 0 for digit in string)\n # Create the required output string with the odd count replacing 'i's\n output = \"the number of odd elements {0}n the str{0}ng {0} of the {0}nput.\".format(odd_count)\n result.append(output)\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n \"\"\"\n result = []\n for s in lst:\n # Count the number of odd digits in the string\n odd_count = sum(1 for digit in s if int(digit) % 2 != 0)\n # Replace 'i's in the template string with the odd_count\n formatted_string = f'the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.'\n result.append(formatted_string)\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n \"\"\"\n def count_odds(s):\n \"\"\"Helper function to count the number of odd digits in a string.\"\"\"\n return sum(1 for char in s if int(char) % 2 != 0)\n \n result = []\n for s in lst:\n odd_digits_count = count_odds(s)\n result_str = f\"the number of odd elements {odd_digits_count}n the str{odd_digits_count}ng {odd_digits_count} of the {odd_digits_count}nput.\"\n result.append(result_str)\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the\n number of odd digits in the i'th string of the input.\n \"\"\"\n result = []\n for string in lst:\n # Count the number of odd digits in the string\n odd_count = sum(1 for digit in string if int(digit) % 2 != 0)\n # Replace 'i' with the count of odd digits\n formatted_string = f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\"\n result.append(formatted_string)\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n \"\"\"\n def count_odds(s):\n \"\"\"Counts the number of odd digits in a string.\"\"\"\n return sum(1 for digit in s if int(digit) % 2 != 0)\n \n result = []\n for s in lst:\n odd_digits = count_odds(s)\n result.append(f\"the number of odd elements {odd_digits}n the str{odd_digits}ng {odd_digits} of the {odd_digits}nput.\")\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"\n Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n \"\"\"\n def count_odds(s):\n \"\"\"Helper function to count the number of odd digits in a string.\"\"\"\n return sum(1 for char in s if int(char) % 2 != 0)\n \n result = []\n for s in lst:\n odd_digits = count_odds(s)\n result.append(f\"the number of odd elements {odd_digits}n the str{odd_digits}ng {odd_digits} of the {odd_digits}nput.\")\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the\n number of odd digits in the i'th string of the input.\n \"\"\"\n def count_odds(s):\n \"\"\"Count the number of odd digits in a string.\"\"\"\n return sum(1 for char in s if int(char) % 2 != 0)\n \n result = []\n for s in lst:\n num_odds = count_odds(s)\n result.append(f\"the number of odd elements {num_odds}n the str{num_odds}ng {num_odds} of the {num_odds}nput.\")\n return result", "matching_cluster_idx": 3}, {"solution": "def count_odd_digits(s):\n \"\"\"Helper function to count the number of odd digits in a string.\"\"\"\n return sum(1 for char in s if int(char) % 2 != 0)\ndef odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n :param lst: List of strings, each string consists only of digits.\n :return: A list of strings as per the problem description.\n \"\"\"\n result = []\n for s in lst:\n odd_count = count_odd_digits(s)\n result.append(f'the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.')\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n \"\"\"\n def count_odds(s):\n \"\"\"Count the number of odd digits in a string.\"\"\"\n return sum(1 for char in s if int(char) % 2 != 0)\n\n result = []\n for s in lst:\n odd_digits = count_odds(s)\n message = f\"the number of odd elements {odd_digits}n the str{odd_digits}ng {odd_digits} of the {odd_digits}nput.\"\n result.append(message)\n return result", "matching_cluster_idx": 3}, {"solution": "def count_odd_digits(s):\n \"\"\"Helper function to count the number of odd digits in a string.\"\"\"\n return sum(1 for char in s if int(char) % 2 != 0)\ndef odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\"\"\"\n result = []\n for s in lst:\n odd_count = count_odd_digits(s)\n result.append(f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\")\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n \"\"\"\n result = []\n for string in lst:\n count = sum(1 for digit in string if int(digit) % 2 != 0)\n result.append(f\"the number of odd elements {count}n the str{count}ng {count} of the {count}nput.\")\n return result", "matching_cluster_idx": 3}]}, "HumanEval/119": {"dps": 50.58139534883721, "dps_norm": 60.0, "pass@1": 37.0, "profiled": [{"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n '''\n # Check both possible concatenations\n for s in [lst[0] + lst[1], lst[1] + lst[0]]:\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n else:\n balance -= 1\n if balance < 0:\n break # Early exit if close parentheses exceed open parentheses\n else:\n if balance == 0: # If all parentheses are balanced\n return 'Yes'\n return 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n '''\n open_paren, close_paren = lst[0], lst[1]\n \n # Check if concatenating in one order balances parentheses\n if is_balanced(open_paren + close_paren):\n return 'Yes'\n \n # Check if concatenating in the other order balances parentheses\n if is_balanced(close_paren + open_paren):\n return 'Yes'\n \n return 'No'\ndef is_balanced(s):\n '''\n Helper function to check if parentheses in the string s are balanced.\n '''\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n else:\n balance -= 1\n # If balance is negative, there's a closing parenthesis without a matching opening parenthesis\n if balance < 0:\n return False\n # For the string to be good, balance should be zero (all parentheses are matched)\n return balance == 0", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n '''\n # Count the total number of open and close parentheses\n total_open = total_close = 0\n for s in lst:\n open_count = s.count('(')\n close_count = s.count(')')\n total_open += open_count\n total_close += close_count\n\n # If total number of open and close parentheses are equal\n if total_open != total_close:\n return 'No'\n\n # Check if concatenating in one order results in a balanced string\n for s1, s2 in [(lst[0], lst[1]), (lst[1], lst[0])]:\n open_count = 0\n for char in s1 + s2:\n if char == '(':\n open_count += 1\n elif char == ')':\n open_count -= 1\n if open_count < 0:\n break\n else:\n if open_count == 0:\n return 'Yes'\n\n return 'No'", "matching_cluster_idx": 0}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n '''\n # Count the number of open and close parentheses in both strings\n open_count = lst[0].count('(') + lst[1].count('(')\n close_count = lst[0].count(')') + lst[1].count(')')\n \n # Check if the total count of open and close parentheses are the same\n if open_count != close_count:\n return 'No'\n \n # Check both possible concatenations\n for s1, s2 in (lst, reversed(lst)):\n balance = 0\n for char in s1 + s2:\n if char == '(':\n balance += 1\n else:\n balance -= 1\n # If at any point balance is negative, parentheses are not balanced\n if balance < 0:\n break\n # If we didn't break out of the loop, balance should be 0 at the end\n if balance == 0:\n return 'Yes'\n return 'No'", "matching_cluster_idx": 0}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n '''\n # Count the number of opening and closing parentheses in both strings\n open_count = lst[0].count('(') + lst[1].count('(')\n close_count = lst[0].count(')') + lst[1].count(')')\n \n # Check the order of concatenation\n # If string 0 has more closing than opening, switch the order\n if lst[0].count(')') > lst[0].count('('):\n lst = [lst[1], lst[0]]\n \n # Check the balance of parentheses after concatenation in the possible order\n balance = 0\n for s in lst:\n for c in s:\n if c == '(':\n balance += 1\n else:\n balance -= 1\n if balance < 0:\n return 'No'\n return 'Yes' if balance == 0 else 'No'", "matching_cluster_idx": 0}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n '''\n\n def is_balanced(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n else:\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n a, b = lst\n if is_balanced(a + b) or is_balanced(b + a):\n return 'Yes'\n else:\n return 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n '''\n a, b = lst\n # Check if the total number of open and close parentheses are the same\n total_balance = (a.count('(') + b.count('(')) - (a.count(')') + b.count(')'))\n \n # If total is unbalanced, return 'No'\n if total_balance != 0:\n return 'No'\n \n # Check if string a followed by b is balanced\n balance = 0\n for char in a + b:\n balance += 1 if char == '(' else -1\n if balance < 0: # Early exit if unbalanced\n break\n \n if balance == 0: # If a + b is balanced, return 'Yes'\n return 'Yes'\n \n # Check if string b followed by a is balanced\n balance = 0\n for char in b + a:\n balance += 1 if char == '(' else -1\n if balance < 0: # Early exit if unbalanced\n break\n \n return 'Yes' if balance == 0 else 'No'", "matching_cluster_idx": 0}, {"solution": "def match_parens(lst):\n '''\n Checks if it is possible to concatenate two strings of parentheses in some order\n to form a balanced string.\n \n Parameters:\n lst (list): A list of two strings, each string consists of open '(' or close ')' parentheses.\n \n Returns:\n str: 'Yes' if a good string can be formed, 'No' otherwise.\n '''\n\n # Count the total number of opening and closing parentheses\n total_open = lst[0].count('(') + lst[1].count('(')\n total_close = lst[0].count(')') + lst[1].count(')')\n\n # Check if the total number of opening and closing parentheses is the same\n if total_open != total_close:\n return 'No'\n\n # Function to check if a string is balanced\n def is_balanced(s):\n balance = 0\n for p in s:\n if p == '(':\n balance += 1\n else:\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n # Check if any order of concatenation results in a balanced string\n return 'Yes' if is_balanced(lst[0] + lst[1]) or is_balanced(lst[1] + lst[0]) else 'No'", "matching_cluster_idx": 0}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n '''\n # Count open and close parentheses\n open_paren_count = lst[0].count('(') + lst[1].count('(')\n close_paren_count = lst[0].count(')') + lst[1].count(')')\n \n # Check if total number of open and close parentheses is equal\n if open_paren_count != close_paren_count:\n return 'No'\n \n # Check both concatenation orders\n if is_good(lst[0] + lst[1]) or is_good(lst[1] + lst[0]):\n return 'Yes'\n return 'No'\ndef is_good(s):\n '''\n Helper function to check if a string has balanced parentheses.\n '''\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n else:\n balance -= 1\n if balance < 0:\n return False\n return balance == 0", "matching_cluster_idx": 0}, {"solution": "def match_parens(lst):\n '''\n This function checks if it's possible to concatenate two strings of parentheses\n in some order such that the resulting string is balanced.\n '''\n # Check all combinations by concatenating in both possible orders\n for order in [lst, lst[::-1]]:\n balance = 0\n for c in ''.join(order):\n if c == '(':\n balance += 1\n else:\n balance -= 1\n # If balance is negative at any point, parentheses are not balanced\n if balance < 0:\n break\n # If balance is zero, parentheses are balanced\n else:\n if balance == 0:\n return 'Yes'\n return 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n '''\n a, b = lst\n # check if concatenating a + b or b + a forms a balanced string\n if balanced(a + b) or balanced(b + a):\n return 'Yes'\n else:\n return 'No'\ndef balanced(s):\n # helper function to check if a string of parentheses is balanced\n count = 0\n for c in s:\n if c == '(':\n count += 1\n elif c == ')':\n count -= 1\n if count < 0:\n return False\n return count == 0", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n '''\n def is_balanced(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n else: # char == ')'\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n s1, s2 = lst\n open_count_s1, close_count_s1 = s1.count('('), s1.count(')')\n open_count_s2, close_count_s2 = s2.count('('), s2.count(')')\n\n # Case 1: s1 has more closing parentheses, s2 has more opening parentheses\n # Case 2: s2 has more closing parentheses, s1 has more opening parentheses\n if (close_count_s1 > open_count_s1 and close_count_s2 > open_count_s2) or \\\n (close_count_s2 > open_count_s2 and close_count_s1 > open_count_s1):\n return 'No'\n \n # Check both possible concatenations\n if is_balanced(s1 + s2) or is_balanced(s2 + s1):\n return 'Yes'\n return 'No'", "matching_cluster_idx": 0}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n '''\n\n def is_balanced(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n else:\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n # Swap if the first string has more closing parentheses\n if lst[0].count(')') > lst[0].count('('):\n lst[0], lst[1] = lst[1], lst[0]\n\n return 'Yes' if is_balanced(''.join(lst)) else 'No'", "matching_cluster_idx": 0}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n '''\n\n def is_balanced(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n else:\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n str1, str2 = lst\n if is_balanced(str1 + str2) or is_balanced(str2 + str1):\n return 'Yes'\n else:\n return 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n '''\n\n # Extract the two strings\n first, second = lst\n\n # Check if concatenating in the first order works\n if is_balanced(first + second):\n return 'Yes'\n \n # Check if concatenating in the second order works\n if is_balanced(second + first):\n return 'Yes'\n \n return 'No'\ndef is_balanced(s):\n '''\n Helper function to check if a string of parentheses is balanced.\n '''\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n elif char == ')':\n balance -= 1\n if balance < 0:\n return False\n return balance == 0", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n '''\n\n def are_parentheses_balanced(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n else:\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n a, b = lst\n # Check both possible concatenations\n if are_parentheses_balanced(a + b) or are_parentheses_balanced(b + a):\n return 'Yes'\n else:\n return 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n '''\n # Check all possible concatenations\n def is_balanced(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n else:\n if balance == 0:\n return False\n balance -= 1\n return balance == 0\n\n # Check both possible concatenation orders\n first_then_second = lst[0] + lst[1]\n second_then_first = lst[1] + lst[0]\n\n if is_balanced(first_then_second) or is_balanced(second_then_first):\n return 'Yes'\n else:\n return 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n '''\n a, b = lst\n # Check if concatenating a first and then b results in a good string\n if balanced(a + b):\n return 'Yes'\n # Check if concatenating b first and then a results in a good string\n if balanced(b + a):\n return 'Yes'\n return 'No'\ndef balanced(s):\n '''\n Helper function to check if a string of parentheses is balanced.\n '''\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n elif char == ')':\n balance -= 1\n if balance < 0:\n return False\n return balance == 0", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n '''\n # Count the total number of opening and closing parentheses\n total_open = lst[0].count('(') + lst[1].count('(')\n total_close = lst[0].count(')') + lst[1].count(')')\n \n # If the total number of opening parentheses does not match closing ones, return 'No'\n if total_open != total_close:\n return 'No'\n \n # Try concatenating in both possible orders\n for order in [0, 1]: # order 0 for [0] + [1], order 1 for [1] + [0]\n open_count, balance = 0, 0\n # First check the balance if the first string is concatenated first\n for ch in lst[order]:\n if ch == '(':\n open_count += 1\n else:\n balance += 1\n if balance > open_count:\n break\n # Then, check the balance of the second string\n if balance <= open_count:\n remaining_balance = open_count - balance\n for ch in lst[1 - order]:\n if ch == '(':\n remaining_balance += 1\n else:\n remaining_balance -= 1\n if remaining_balance < 0:\n break\n if remaining_balance == 0:\n return 'Yes'\n return 'No'", "matching_cluster_idx": 0}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n '''\n str1, str2 = lst\n # Count the total number of '(' and ')'\n total_open = str1.count('(') + str2.count('(')\n total_close = str1.count(')') + str2.count(')')\n \n # Check if it's possible to balance the parentheses by concatenating in some order\n if total_open == total_close:\n # Try both orders\n if (valid_parens(str1 + str2) or valid_parens(str2 + str1)):\n return 'Yes'\n return 'No'\ndef valid_parens(s):\n balance = 0\n for c in s:\n if c == '(':\n balance += 1\n else:\n balance -= 1\n if balance < 0:\n return False\n return balance == 0", "matching_cluster_idx": 0}]}, "HumanEval/120": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 36.0, "profiled": [{"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n with the maximum k numbers in arr.\n \"\"\"\n # First, sort the array in ascending order\n sorted_arr = sorted(arr, reverse=True)\n # Then, take the first k elements\n max_k_elements = sorted_arr[:k]\n # Finally, sort these k elements in ascending order before returning\n return sorted(max_k_elements)", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n with the maximum k numbers in arr.\n \"\"\"\n # Sort the array in descending order and take the first k elements\n sorted_arr = sorted(arr, reverse=True)[:k]\n # Return the sorted list of the top k elements\n return sorted(sorted_arr)", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n with the maximum k numbers in arr.\n \"\"\"\n # Sort the array in ascending order\n sorted_arr = sorted(arr, reverse=True)\n # Slice the first k elements and sort them in ascending order before returning\n return sorted(sorted_arr[:k])", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n with the maximum k numbers in arr.\n \"\"\"\n # Sort the array in descending order and take the first k elements\n sorted_arr = sorted(arr, reverse=True)[:k]\n # Return the result sorted in ascending order\n return sorted(sorted_arr)", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n with the maximum k numbers in arr.\n \"\"\"\n # First, sort the array in ascending order\n sorted_arr = sorted(arr, reverse=True)\n # Then, slice the first k elements from the sorted array\n top_k = sorted_arr[:k]\n # Return the sorted list of the top k elements\n return sorted(top_k)", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n with the maximum k numbers in arr.\n \"\"\"\n # First, sort the array in ascending order\n sorted_arr = sorted(arr, reverse=True)\n # Then, slice the first k elements to get the largest k numbers\n top_k = sorted_arr[:k]\n # Finally, sort the result to meet the requirement\n return sorted(top_k)", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n with the maximum k numbers in arr.\n \"\"\"\n # Sort the array in descending order and take the first k elements\n result = sorted(arr, reverse=True)[:k]\n # Sort the result list in ascending order before returning\n return sorted(result)", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n with the maximum k numbers in arr.\n \"\"\"\n # Sort the array in ascending order\n sorted_arr = sorted(arr, reverse=True)\n # Slice the first k elements and sort them in ascending order before returning\n return sorted(sorted_arr[:k])", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n with the maximum k numbers in arr.\n \"\"\"\n # Sort the array in ascending order\n sorted_arr = sorted(arr, reverse=True)\n # Return the first k elements from the sorted array\n return sorted(sorted_arr[:k])", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n with the maximum k numbers in arr.\n \"\"\"\n # Sort the array in descending order and take the first k elements\n sorted_arr = sorted(arr, reverse=True)[:k]\n # Return the sorted list of the maximum k numbers\n return sorted(sorted_arr)", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n with the maximum k numbers in arr.\n \"\"\"\n # Sort the array in ascending order\n sorted_arr = sorted(arr, reverse=True)\n # Slice the first k elements and sort them in ascending order\n result = sorted(sorted_arr[:k])\n return result", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n with the maximum k numbers in arr.\n \"\"\"\n # Sort the array in descending order and take the first k elements\n sorted_arr = sorted(arr, reverse=True)[:k]\n # Return the result sorted in ascending order\n return sorted(sorted_arr)", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n with the maximum k numbers in arr.\n \"\"\"\n # Sort the array in ascending order\n sorted_arr = sorted(arr, reverse=True)\n # Return the first k elements\n return sorted(sorted_arr[:k])", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n with the maximum k numbers in arr.\n \"\"\"\n # Sort the array in descending order and take the first k elements\n sorted_arr = sorted(arr, reverse=True)[:k]\n # Sort the result in ascending order before returning\n return sorted(sorted_arr)", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n with the maximum k numbers in arr.\n \"\"\"\n # Sort the array in descending order and slice the first k elements\n sorted_arr = sorted(arr, reverse=True)[:k]\n # Return the result sorted in ascending order\n return sorted(sorted_arr)", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n with the maximum k numbers in arr.\n \"\"\"\n # Sort the array in ascending order\n sorted_arr = sorted(arr, reverse=True)\n # Slice the first k elements and sort them\n result = sorted(sorted_arr[:k])\n return result", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n with the maximum k numbers in arr.\n \"\"\"\n # Sort the array in ascending order\n arr_sorted = sorted(arr, reverse=True)\n # Slice the first k elements from the sorted array\n result = arr_sorted[:k]\n # Return the result sorted in ascending order\n return sorted(result)", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n with the maximum k numbers in arr.\n \"\"\"\n # Sort the array in ascending order\n arr_sorted = sorted(arr, reverse=True)\n \n # Slice the first k elements and sort them in ascending order\n result = sorted(arr_sorted[:k])\n \n return result", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n with the maximum k numbers in arr.\n \"\"\"\n # Sort the array in descending order\n sorted_arr = sorted(arr, reverse=True)\n # Slice the first k elements from the sorted array\n max_k_elements = sorted_arr[:k]\n # Return the result sorted in ascending order\n return sorted(max_k_elements)", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n with the maximum k numbers in arr.\n \"\"\"\n # Sort the array in ascending order first\n sorted_arr = sorted(arr, reverse=True)\n # Slice the first k elements from the sorted array\n result = sorted_arr[:k]\n # Return the result sorted in ascending order\n return sorted(result)", "matching_cluster_idx": 6}]}, "HumanEval/121": {"dps": 90.22421524663677, "dps_norm": 68.57142857142857, "pass@1": 92.0, "profiled": [{"solution": "def solution(lst):\n \"\"\"\n Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n :param lst: List[int] - a non-empty list of integers\n :return: int - sum of odd elements at even indices\n \"\"\"\n return sum(lst[i] for i in range(0, len(lst), 2) if lst[i] % 2 != 0)", "matching_cluster_idx": 4}, {"solution": "def solution(lst):\n \"\"\"\n Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n return sum(lst[i] for i in range(0, len(lst), 2) if lst[i] % 2 != 0)", "matching_cluster_idx": 4}, {"solution": "def solution(lst):\n \"\"\"\n Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n :param lst: List of integers\n :return: Sum of odd elements at even positions\n \"\"\"\n # Initialize sum to 0\n total = 0\n \n # Iterate through the list, considering only even indices\n for i in range(0, len(lst), 2):\n # Check if the element at the even index is odd\n if lst[i] % 2 != 0:\n # Add it to the total sum\n total += lst[i]\n \n return total", "matching_cluster_idx": 4}, {"solution": "def solution(lst):\n \"\"\"\n Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n :param lst: List of integers\n :return: Sum of odd elements in even positions\n \"\"\"\n return sum(lst[i] for i in range(0, len(lst), 2) if lst[i] % 2 != 0)", "matching_cluster_idx": 4}, {"solution": "def solution(lst):\n \"\"\"\n Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n Parameters:\n lst (list): A list of integers.\n \n Returns:\n int: The sum of all odd elements at even indices.\n \"\"\"\n return sum(val for idx, val in enumerate(lst) if idx % 2 == 0 and val % 2 != 0)", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n \"\"\"\n Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n :param lst: List[int] - A non-empty list of integers.\n :return: int - The sum of odd elements in even positions.\n \"\"\"\n return sum(lst[i] for i in range(0, len(lst), 2) if lst[i] % 2 != 0)", "matching_cluster_idx": 4}, {"solution": "def solution(lst):\n \"\"\"\n Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n :param lst: List[int] -- a list of integers\n :return: int -- the sum of odd elements at even indices\n \"\"\"\n return sum(val for idx, val in enumerate(lst) if idx % 2 == 0 and val % 2 == 1)", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n \"\"\"\n Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n Parameters:\n lst (list): A list of integers.\n \n Returns:\n int: The sum of odd elements at even indices.\n \"\"\"\n return sum(lst[i] for i in range(0, len(lst), 2) if lst[i] % 2 != 0)", "matching_cluster_idx": 4}, {"solution": "def solution(lst):\n \"\"\"\n Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n Parameters:\n lst (list): A list of integers.\n \n Returns:\n int: The sum of all odd elements that are in even positions.\n \"\"\"\n return sum(lst[i] for i in range(0, len(lst), 2) if lst[i] % 2 != 0)", "matching_cluster_idx": 4}, {"solution": "def solution(lst):\n \"\"\"\n Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n Parameters:\n lst (list): A non-empty list of integers\n \n Returns:\n int: The sum of odd elements in even positions\n \"\"\"\n # Initialize the sum to 0\n sum_of_odds = 0\n # Iterate over the list, considering only even positions (0-based index)\n for index in range(0, len(lst), 2):\n # Check if the current element is odd\n if lst[index] % 2 != 0:\n # Add the odd element to the sum\n sum_of_odds += lst[index]\n return sum_of_odds", "matching_cluster_idx": 4}, {"solution": "def solution(lst):\n \"\"\"\n Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n Parameters:\n lst (list): A list of integers.\n \n Returns:\n int: The sum of odd elements at even indices.\n \"\"\"\n # Initialize the sum\n sum_odd_even = 0\n \n # Iterate over the list with index\n for index, value in enumerate(lst):\n # Check if the position is even and the element is odd\n if index % 2 == 0 and value % 2 != 0:\n sum_odd_even += value\n \n return sum_odd_even", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n \"\"\"\n Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n Args:\n lst (list of int): A non-empty list of integers.\n \n Returns:\n int: The sum of odd elements at even positions.\n \"\"\"\n return sum(lst[i] for i in range(0, len(lst), 2) if lst[i] % 2 != 0)", "matching_cluster_idx": 4}, {"solution": "def solution(lst):\n \"\"\"\n Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n Examples:\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n # Initialize sum of odd elements in even positions\n sum_odd_in_even = 0\n \n # Iterate over elements at even indices (considering 0-based indexing)\n for i in range(0, len(lst), 2):\n if lst[i] % 2 != 0:\n sum_odd_in_even += lst[i]\n \n return sum_odd_in_even", "matching_cluster_idx": 4}, {"solution": "def solution(lst):\n \"\"\"\n Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==>0\n \"\"\"\n # Initialize the sum to zero\n sum_odd = 0\n \n # Iterate over the list, starting from the first element (index 0, which is considered an even position)\n for i in range(0, len(lst), 2):\n # Check if the element at the current even position is odd\n if lst[i] % 2 != 0:\n # Add the odd element to the sum\n sum_odd += lst[i]\n \n return sum_odd", "matching_cluster_idx": 4}, {"solution": "def solution(lst):\n \"\"\"\n Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n :param lst: List of integers\n :return: Sum of odd elements at even indices\n \"\"\"\n return sum(val for idx, val in enumerate(lst) if idx % 2 == 0 and val % 2 != 0)", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n \"\"\"\n Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n Args:\n lst: List[int] -- a list of integers\n \n Returns:\n int -- the sum of odd elements at even indices\n \"\"\"\n return sum(lst[i] for i in range(0, len(lst), 2) if lst[i] % 2 != 0)", "matching_cluster_idx": 4}, {"solution": "def solution(lst):\n \"\"\"\n Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n Examples:\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n return sum(lst[i] for i in range(0, len(lst), 2) if lst[i] % 2 != 0)", "matching_cluster_idx": 4}, {"solution": "def solution(lst):\n \"\"\"\n Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n Parameters:\n lst (list): A non-empty list of integers\n \n Returns:\n int: The sum of all odd elements in even positions\n \"\"\"\n # Initialize sum to 0\n sum_odd = 0\n \n # Iterate over the list, starting from the first element (index 0) and step by 2 to get even positions\n for i in range(0, len(lst), 2):\n # Check if the current element is odd\n if lst[i] % 2 != 0:\n # Add the odd element to the sum\n sum_odd += lst[i]\n \n return sum_odd", "matching_cluster_idx": 4}, {"solution": "def solution(lst):\n \"\"\"\n Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n Parameters:\n lst (list): A non-empty list of integers.\n \n Returns:\n int: The sum of odd elements in even positions.\n \"\"\"\n return sum(lst[i] for i in range(0, len(lst), 2) if lst[i] % 2 != 0)", "matching_cluster_idx": 4}, {"solution": "def solution(lst):\n \"\"\"\n Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n Args:\n lst (list): A non-empty list of integers\n \n Returns:\n int: The sum of all odd elements that are in even positions\n \"\"\"\n # Initialize the sum to 0\n total_sum = 0\n \n # Iterate over the list, considering only even indices (0-based indexing)\n for index in range(0, len(lst), 2):\n # Check if the element at the even index is odd\n if lst[index] % 2 != 0:\n # Add the odd element to the total sum\n total_sum += lst[index]\n \n return total_sum", "matching_cluster_idx": 4}]}, "HumanEval/149": {"dps": 85.82677165354332, "dps_norm": 57.142857142857146, "pass@1": 100.0, "profiled": [{"solution": "def sorted_list_sum(lst):\n \"\"\"\n Deletes strings with odd lengths from a list of strings,\n returns the resulted list sorted by string length,\n with alphabetical sorting used as a tiebreaker for strings of equal length.\n \n :param lst: List of strings to be processed.\n :return: Sorted list of strings with even lengths.\n \"\"\"\n # Filter out strings with odd lengths\n even_length_strings = [s for s in lst if len(s) % 2 == 0]\n # Sort the list by length, and alphabetically for strings of the same length\n sorted_list = sorted(even_length_strings, key=lambda x: (len(x), x))\n return sorted_list", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"\n This function takes a list of strings, removes those with odd lengths,\n and returns a sorted list of the remaining strings first by length then alphabetically.\n \"\"\"\n # Filter out strings with odd lengths\n even_length_strings = [s for s in lst if len(s) % 2 == 0]\n \n # Sort the list by length and then alphabetically\n even_length_strings.sort(key=lambda x: (len(x), x))\n \n return even_length_strings", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"Filters out strings with odd lengths and sorts the list.\"\"\"\n # Filter out strings with odd lengths\n even_length_strings = [s for s in lst if len(s) % 2 == 0]\n # Sort the list first by length and then alphabetically\n sorted_list = sorted(even_length_strings, key=lambda x: (len(x), x))\n return sorted_list", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"\n Deletes strings of odd lengths from the input list and returns the list sorted\n by the length of the strings in ascending order. For strings of equal length, \n they are sorted alphabetically.\n \n Parameters:\n lst (list of str): The input list of strings.\n \n Returns:\n list: A sorted list of strings with even lengths.\n \"\"\"\n # Filter out strings with odd lengths\n even_length_strings = [s for s in lst if len(s) % 2 == 0]\n \n # Sort the list by string length and then alphabetically\n even_length_strings.sort(key=lambda x: (len(x), x))\n \n return even_length_strings", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"\n This function accepts a list of strings, removes strings with odd lengths,\n and returns the remaining list of strings sorted by ascending length.\n If two strings have the same length, they are sorted alphabetically.\n \"\"\"\n # Remove strings with odd lengths\n even_length_strings = [word for word in lst if len(word) % 2 == 0]\n \n # Sort the list by length, and then alphabetically for words of the same length\n even_length_strings.sort(key=lambda x: (len(x), x))\n \n return even_length_strings", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"\n This function accepts a list of strings, removes strings with odd lengths,\n and returns a sorted list of the remaining strings by their lengths.\n If two strings have the same length, they are sorted alphabetically.\n \"\"\"\n # Remove strings with odd lengths\n even_length_strings = [s for s in lst if len(s) % 2 == 0]\n \n # Sort the list by string length, then alphabetically\n sorted_list = sorted(even_length_strings, key=lambda x: (len(x), x))\n \n return sorted_list", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"\n Deletes strings with odd lengths from the given list and returns\n the resulted list sorted by string length and alphabetically for\n strings of the same length.\n \"\"\"\n # Filter out strings with odd lengths\n even_length_strings = [word for word in lst if len(word) % 2 == 0]\n \n # Sort by length, then alphabetically for strings of the same length\n sorted_strings = sorted(even_length_strings, key=lambda x: (len(x), x))\n \n return sorted_strings", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"\n Accepts a list of strings as a parameter, deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order.\n The list is always a list of strings and never an array of numbers, and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n You may assume that all words will have the same length.\n \"\"\"\n # Filter out strings with odd lengths\n even_length_lst = [word for word in lst if len(word) % 2 == 0]\n \n # Sort the list by length, then alphabetically\n even_length_lst.sort(key=lambda x: (len(x), x))\n \n return even_length_lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"\n Accepts a list of strings, deletes the strings that have odd lengths,\n and returns the resulted list with a sorted order.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function returns a list of strings in sorted order.\n \"\"\"\n # Remove strings with odd lengths\n even_length_lst = [s for s in lst if len(s) % 2 == 0]\n \n # Sort the list first by length, then alphabetically\n sorted_lst = sorted(even_length_lst, key=lambda s: (len(s), s))\n \n return sorted_lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"\n This function accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order,\n ascending by the length of each word, and then alphabetically if lengths are the same.\n \"\"\"\n # Filter out strings with odd lengths\n filtered_lst = [word for word in lst if len(word) % 2 == 0]\n # Sort the list by length and then alphabetically\n sorted_lst = sorted(filtered_lst, key=lambda x: (len(x), x))\n return sorted_lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"\n Accepts a list of strings as a parameter, removes strings with odd lengths,\n and returns a sorted list based on the length of the strings.\n In case of a tie in lengths, the list is sorted alphabetically.\n \n Parameters:\n lst (list): A list of strings\n \n Returns:\n list: A sorted list of strings by length and alphabetically\n \"\"\"\n # Remove strings with odd lengths\n even_length_lst = [s for s in lst if len(s) % 2 == 0]\n \n # Sort the list by length and then alphabetically\n sorted_lst = sorted(even_length_lst, key=lambda x: (len(x), x))\n \n return sorted_lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"\n Accepts a list of strings, removes strings with odd lengths,\n and returns a sorted list of strings by their lengths and alphabetically.\n \"\"\"\n # Filter out strings with odd lengths\n even_length_strings = [s for s in lst if len(s) % 2 == 0]\n \n # Sort the filtered list first by length and then alphabetically\n sorted_strings = sorted(even_length_strings, key=lambda x: (len(x), x))\n \n return sorted_strings", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"\n Accepts a list of strings, removes strings with odd lengths,\n and returns a sorted list based on string length and alphabetical order.\n \"\"\"\n # Remove strings with odd lengths\n even_length_strings = [s for s in lst if len(s) % 2 == 0]\n \n # Sort strings first by length, then alphabetically\n sorted_strings = sorted(even_length_strings, key=lambda x: (len(x), x))\n \n return sorted_strings", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"\n Accepts a list of strings, removes strings with odd lengths,\n and returns the list sorted first by the length of each string\n (in ascending order) and then alphabetically for strings of the same length.\n \"\"\"\n # Remove strings with odd lengths\n even_length_strings = [s for s in lst if len(s) % 2 == 0]\n \n # Sort the list by string length, then alphabetically\n sorted_list = sorted(even_length_strings, key=lambda x: (len(x), x))\n \n return sorted_list", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"\n This function accepts a list of strings, removes strings with odd lengths,\n and returns the remaining list sorted by string length. If two strings have\n the same length, it sorts them alphabetically.\n \"\"\"\n # Remove strings with odd lengths\n even_length_strings = [word for word in lst if len(word) % 2 == 0]\n \n # Sort the list by string length, then alphabetically if lengths are equal\n sorted_list = sorted(even_length_strings, key=lambda x: (len(x), x))\n \n return sorted_list", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order,\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n You may assume that all words will have the same length.\n For example:\n assert list_sort([\"aa\", \"a\", \"aaa\"]) => [\"aa\"]\n assert list_sort([\"ab\", \"a\", \"aaa\", \"cd\"]) => [\"ab\", \"cd\"]\n \"\"\"\n # Filter out strings with odd lengths\n even_length_strings = [word for word in lst if len(word) % 2 == 0]\n \n # Sort the list by length, then alphabetically if lengths are equal\n even_length_strings.sort(key=lambda x: (len(x), x))\n \n return even_length_strings", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"\n Accepts a list of strings, removes strings with odd lengths,\n and returns a sorted list of the remaining strings.\n The list is sorted first by length of each word in ascending order.\n For words of the same length, it sorts alphabetically.\n \"\"\"\n # Filter out strings with odd lengths\n filtered_list = [s for s in lst if len(s) % 2 == 0]\n \n # Sort the list by string length in ascending order,\n # and then alphabetically for strings of the same length\n sorted_list = sorted(filtered_list, key=lambda x: (len(x), x))\n \n return sorted_list", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"\n Accepts a list of strings, deletes strings with odd lengths,\n and returns a sorted list by ascending word length.\n If two words have the same length, it sorts them alphabetically.\n \"\"\"\n # Remove strings with odd lengths\n even_length_strings = [s for s in lst if len(s) % 2 == 0]\n \n # Sort by length, then alphabetically for equal lengths\n sorted_list = sorted(even_length_strings, key=lambda s: (len(s), s))\n \n return sorted_list", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"\n This function accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order.\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word,\n and you should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function returns a list of strings in sorted order.\n \"\"\"\n # Filter out strings with odd lengths\n filtered_list = [word for word in lst if len(word) % 2 == 0]\n \n # Sort the list by length, and alphabetically for strings of the same length\n sorted_list = sorted(filtered_list, key=lambda x: (len(x), x))\n \n return sorted_list", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"\n Removes strings of odd lengths from the list, then returns a sorted list.\n The list is sorted first by the length of the strings, and then alphabetically if the lengths are equal.\n \n Parameters:\n lst (list): A list of strings\n \n Returns:\n list: A sorted list of strings with even lengths\n \"\"\"\n # Remove strings with odd lengths\n even_length_strings = [s for s in lst if len(s) % 2 == 0]\n \n # Sort the list by length, and then alphabetically for strings of the same length\n sorted_lst = sorted(even_length_strings, key=lambda x: (len(x), x))\n \n return sorted_lst", "matching_cluster_idx": 3}]}, "Mbpp/3": {"dps": 62.03389830508475, "dps_norm": 73.75, "pass@1": 99.0, "profiled": [{"solution": "def is_not_prime(num):\n \"\"\"\n This function checks if a number is not a prime number.\n \n Args:\n num : int\n The number to check.\n \n Returns:\n bool\n True if the number is not a prime number, False otherwise.\n \"\"\"\n if num < 2:\n return True\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n return True\n return False", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(n):\n \"\"\"Returns True if n is not a prime number.\"\"\"\n if n <= 1:\n return True\n if n <= 3:\n return False\n if n % 2 == 0 or n % 3 == 0:\n return True\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return True\n i += 6\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n \"\"\"\n Function to check if a number is not prime.\n Returns True if the number is not prime, False otherwise.\n \"\"\"\n if n <= 1:\n return True\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return True\n return False", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(num):\n \"\"\"\n Checks if a number is not a prime number.\n \n Parameters:\n num (int): The number to be checked.\n \n Returns:\n bool: True if the number is not a prime, False otherwise.\n \"\"\"\n if num <= 1:\n return True # Numbers less than or equal to 1 are not prime\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n return True # Found a divisor, num is not prime\n return False", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(num):\n \"\"\"\n Checks if the given number is not a prime number.\n \n Parameters:\n num (int): The number to check.\n \n Returns:\n bool: True if the number is not a prime, False if it is a prime number or less than 2.\n \"\"\"\n if num <= 1:\n return True\n for i in range(2, num):\n if num % i == 0:\n return True\n return False", "matching_cluster_idx": 0}, {"solution": "def is_not_prime(num):\n \"\"\"Check if the given number is not a prime number.\"\"\"\n if num <= 1:\n return True\n for i in range(2, int(num ** 0.5) + 1):\n if num % i == 0:\n return True\n return False", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(num):\n \"\"\"\n Check if a number is not a prime number.\n \n Parameters:\n num (int): The number to check.\n \n Returns:\n bool: True if the number is not prime, False otherwise.\n \"\"\"\n if num <= 1:\n return True\n if num <= 3:\n return False\n if num % 2 == 0 or num % 3 == 0:\n return True\n \n i = 5\n while i * i <= num:\n if num % i == 0 or num % (i + 2) == 0:\n return True\n i += 6\n \n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(num):\n \"\"\"\n This function checks if the given number is not a prime number.\n \n Args:\n num (int): The number to be checked.\n \n Returns:\n bool: True if the number is not a prime number, False otherwise.\n \"\"\"\n if num <= 1:\n return True # Numbers less than or equal to 1 are not prime\n if num <= 3:\n return False # 2 and 3 are prime numbers\n \n # Check if the number is divisible by 2 or 3\n if num % 2 == 0 or num % 3 == 0:\n return True\n \n # Check divisibility from 5 to the square root of num\n for i in range(5, int(num**0.5) + 1, 6):\n if num % i == 0 or num % (i + 2) == 0:\n return True\n \n return False # The number is a prime number", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(num):\n \"\"\"\n This function checks if a number is not a prime number.\n \n Args:\n num (int): The number to check.\n \n Returns:\n bool: True if the number is not a prime number, False otherwise.\n \"\"\"\n if num <= 1:\n return True\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n return True\n return False", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(num):\n \"\"\"\n This function checks if a number is not a prime number.\n \n Parameters:\n num (int): The number to check.\n \n Returns:\n bool: True if the number is not prime, False otherwise.\n \"\"\"\n if num <= 1:\n return True # Numbers less than or equal to 1 are not prime.\n if num <= 3:\n return False # 2 and 3 are prime numbers.\n \n # Check divisibility from 2 to the square root of num.\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n return True\n return False", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(num):\n \"\"\"\n Check if the provided number is not a prime number.\n \n Parameters:\n num (int): The number to check.\n \n Returns:\n bool: True if the number is not a prime number, False otherwise.\n \"\"\"\n if num < 2:\n return True # Numbers less than 2 are not prime\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n return True\n return False", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(num):\n \"\"\"\n This function checks if a given number is not a prime number.\n \n Parameters:\n num (int): The number to check.\n \n Returns:\n bool: True if the number is not prime, False otherwise.\n \"\"\"\n if num <= 1:\n return True\n for i in range(2, num):\n if num % i == 0:\n return True\n return False", "matching_cluster_idx": 1}, {"solution": "def is_not_prime(num):\n \"\"\"\n This function checks if a given number is not a prime number.\n \n Parameters:\n num (int): The number to check.\n \n Returns:\n bool: True if the number is not a prime number, False otherwise.\n \"\"\"\n if num <= 1:\n return True\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n return True\n return False", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(num):\n \"\"\"\n Check if a given number is not a prime number.\n \n Parameters:\n num (int): The number to check.\n \n Returns:\n bool: True if the number is not prime, False otherwise.\n \"\"\"\n if num <= 1:\n return True # 0 and 1 are not prime numbers\n if num <= 3:\n return False # 2 and 3 are prime numbers\n if num % 2 == 0 or num % 3 == 0:\n return True # Eliminate multiples of 2 and 3\n i = 5\n while i * i <= num:\n if num % i == 0 or num % (i + 2) == 0:\n return True\n i += 6\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(num):\n \"\"\"\n Check if a number is not a prime number.\n \n Parameters:\n num (int): The number to check.\n \n Returns:\n bool: True if the number is not prime, False if the number is prime.\n \"\"\"\n if num <= 1:\n return True\n for i in range(2, num):\n if num % i == 0:\n return True\n return False", "matching_cluster_idx": 0}, {"solution": "def is_not_prime(num):\n \"\"\"\n Function to check if a number is not a prime number.\n \n Parameters:\n num (int): The number to check.\n \n Returns:\n bool: True if the number is not prime, False otherwise.\n \"\"\"\n if num <= 1:\n return True # 0 and 1 are not prime numbers\n if num <= 3:\n return False # 2 and 3 are prime numbers\n if num % 2 == 0 or num % 3 == 0:\n return True # Exclude multiples of 2 and 3\n i = 5\n while i * i <= num:\n if num % i == 0 or num % (i + 2) == 0:\n return True\n i += 6\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(num):\n \"\"\"\n Checks if a given number is not a prime number.\n \n Parameters:\n num (int): The number to check.\n \n Returns:\n bool: True if the number is not prime, False otherwise.\n \"\"\"\n if num <= 1:\n return True\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n return True\n return False", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(num):\n \"\"\"\n Check if a number is not a prime number.\n \n Parameters:\n num (int): The number to check.\n \n Returns:\n bool: True if the number is not prime, False otherwise.\n \"\"\"\n if num <= 1:\n return True\n for i in range(2, int(num ** 0.5) + 1):\n if num % i == 0:\n return True\n return False", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(num):\n \"\"\"\n Check if a number is not a prime number.\n \n Parameters:\n num (int): The number to check.\n \n Returns:\n bool: True if the number is not a prime number, False otherwise.\n \"\"\"\n if num <= 1:\n return True\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n return True\n return False", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(num):\n \"\"\"\n Function to check if a number is not prime.\n \n Parameters:\n - num: The number to check.\n \n Returns:\n - True if the number is not prime, False otherwise.\n \"\"\"\n if num <= 1:\n return True\n if num == 2:\n return False\n if num % 2 == 0:\n return True\n \n for i in range(3, int(num**0.5) + 1, 2):\n if num % i == 0:\n return True\n \n return False", "matching_cluster_idx": 7}]}, "Mbpp/4": {"dps": 95.22184300341297, "dps_norm": 83.33333333333333, "pass@1": 91.0, "profiled": [{"solution": "def heap_queue_largest(nums, n):\n # Convert the list into a min heap using heapq\n import heapq\n min_heap = nums[:n]\n heapq.heapify(min_heap)\n \n # Iterate over the rest of the numbers and maintain the heap size\n for num in nums[n:]:\n if num > min_heap[0]:\n heapq.heapreplace(min_heap, num)\n \n # Convert the min heap to a sorted list in descending order\n result = [heapq.heappop(min_heap) for _ in range(len(min_heap))]\n result.sort(reverse=True)\n return result", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n # Use heapq to convert the list into a heap in-place, then pop the n largest elements\n return heapq.nlargest(n, nums)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n # Use heapq's nlargest function to find the n largest numbers\n largest_nums = heapq.nlargest(n, nums)\n return largest_nums", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n # Using heapq to find the n largest elements in the list\n largest_n = heapq.nlargest(n, nums)\n return largest_n", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(numbers, n):\n # Use the heap queue algorithm to find the n largest elements\n largest_n = heapq.nlargest(n, numbers)\n return largest_n", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n # Use heapq to find the n largest elements in the list\n n_largest = heapq.nlargest(n, nums)\n # Return the elements in descending order\n return n_largest", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n # Use heapq to find the n largest elements and return them in descending order\n n_largest = heapq.nlargest(n, nums)\n return sorted(n_largest, reverse=True)", "matching_cluster_idx": 9}, {"solution": "def heap_queue_largest(nums, n):\n # Import the heap queue module\n import heapq\n \n # Use nlargest function from heapq to find n largest numbers\n largest_nums = heapq.nlargest(n, nums)\n \n # Return the result\n return largest_nums", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n # Utilize heapq to find n largest elements in the list\n largest_n = heapq.nlargest(n, nums)\n # Return the result sorted in descending order\n return sorted(largest_n, reverse=True)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n # Use heapq to find n largest elements and then sort them in descending order\n largest_n_elements = heapq.nlargest(n, nums)\n largest_n_elements.sort(reverse=True)\n return largest_n_elements", "matching_cluster_idx": 9}, {"solution": "def heap_queue_largest(nums, n):\n # Convert the list into a min heap of size n\n min_heap = nums[:n]\n import heapq\n heapq.heapify(min_heap)\n \n # Iterate over the remaining elements\n for num in nums[n:]:\n # If the current number is larger than the smallest in the heap\n if num > min_heap[0]:\n # Replace the smallest element in the heap\n heapq.heapreplace(min_heap, num)\n \n # Convert the heap into a sorted list in descending order\n return sorted(min_heap, reverse=True)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n # Utilize heapq to convert the list into a min heap with the n largest elements\n largest_nums = heapq.nlargest(n, nums)\n # Return the n largest elements sorted in descending order\n return sorted(largest_nums, reverse=True)", "matching_cluster_idx": 9}, {"solution": "def heap_queue_largest(nums, n):\n # Using the heap queue algorithm to find the n largest elements\n import heapq\n # Transform list into a heap, then pop the largest n elements\n n_largest = heapq.nlargest(n, nums)\n # Return the n largest elements in descending order\n return n_largest", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n # Use heapq to find the n largest elements and then sort them in descending order\n largest_n = heapq.nlargest(n, nums)\n largest_n.sort(reverse=True)\n return largest_n", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n \"\"\"\n Function to find the n largest integers from a given list of numbers, returned in descending order.\n \n Args:\n nums : List of integers.\n n : Number of maximum integers to find.\n \n Returns:\n List of n largest integers in descending order.\n \"\"\"\n # Using heapq.nlargest to find the n largest numbers\n largest_nums = heapq.nlargest(n, nums)\n # Returning the result in descending order\n return largest_nums", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n # Use nlargest from heapq to find the n largest numbers\n largest_nums = heapq.nlargest(n, nums)\n return largest_nums", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n # Utilize heapq to find the n largest elements in the list\n n_largest = heapq.nlargest(n, nums)\n # Return the n largest elements sorted in descending order\n return sorted(n_largest, reverse=True)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n # Use heapq.nlargest to find the n largest numbers in the list\n largest_nums = heapq.nlargest(n, nums)\n # Return the result as a list\n return largest_nums", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n # Use heapq to find the n largest elements in the list\n n_largest = heapq.nlargest(n, nums)\n # Return the n largest elements in descending order\n return n_largest", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(numbers, n):\n # Use heapq to find the n largest elements in the list\n largest_n = heapq.nlargest(n, numbers)\n # Return the result in descending order\n return largest_n", "matching_cluster_idx": 9}]}, "Mbpp/9": {"dps": 92.58503401360544, "dps_norm": 59.0, "pass@1": 76.0, "profiled": [{"solution": "def find_Rotations(s):\n # If the string is empty or has only one character, return 1 as the minimum rotation\n if len(s) <= 1:\n return 1\n \n # Double the string to simulate the rotation effect\n doubled_s = s + s\n \n # Iterate through each possible rotation length\n for i in range(1, len(s)):\n # Check if the substring starting from the i-th character matches the original string\n if doubled_s[i:i+len(s)] == s:\n return i\n \n # If no rotation found within the length of the string, return the length of the string\n return len(s)", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(s):\n \"\"\"\n This function calculates the minimum number of rotations (greater than 0) required\n to get the same string.\n \n Parameters:\n s (str): The input string.\n \n Returns:\n int: The minimum number of rotations required to get the same string.\n \"\"\"\n \n # Double the string to handle rotations easily\n doubled_s = s + s\n # Iterate through possible rotation points\n for i in range(1, len(s) + 1):\n # Check if the rotated substring matches the original string\n if doubled_s[i:i+len(s)] == s:\n return i\n return len(s) # In the worst case, return the length of the string", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(s):\n \"\"\"\n Finds the minimum number of rotations required to get the same string.\n \n Parameters:\n s (str): The input string.\n \n Returns:\n int: The minimum number of rotations (greater than 0) to get the same string.\n \"\"\"\n \n # Double the string to simulate rotation\n doubled_s = s + s\n # Check each possible rotation from 1 to len(s)\n for i in range(1, len(s) + 1):\n # Check if the rotated substring matches the original string\n if doubled_s[i:i+len(s)] == s:\n return i\n return len(s)", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(s):\n \"\"\"\n This function calculates the minimum number of rotations (greater than 0) required to get the same string.\n \n Parameters:\n s (str): The input string.\n \n Returns:\n int: The minimum number of rotations required.\n \"\"\"\n \n # Store the original string in a temporary variable\n temp = s\n \n # Iterate over the length of the string\n for i in range(1, len(s)):\n # Rotate the string by moving the first character to the end\n s = s[1:] + s[0]\n \n # If the rotated string matches the original stored string, return the number of rotations\n if s == temp:\n return i\n \n # If the string doesn't repeat in any rotation, return the length of the string\n return len(s)", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(s):\n \"\"\"\n Finds the minimum number of rotations (greater than 0) required to get the same string.\n \n Parameters:\n s (str): The input string for which rotations need to be checked.\n \n Returns:\n int: The minimum number of rotations required to get the same string.\n \"\"\"\n \n # Double the string to handle rotations easily\n doubled_s = s + s\n # Length of the original string\n length = len(s)\n \n # Iterate through each possible rotation\n for i in range(1, length + 1):\n # Check if the rotated substring matches the original string\n if doubled_s[i:i+length] == s:\n return i\n return length", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(s):\n \"\"\"\n Finds the minimum number of rotations (greater than 0) required to get the same string.\n \n Parameters:\n s (str): The input string.\n \n Returns:\n int: The minimum number of rotations required to get the same string.\n \"\"\"\n # Double the string to account for rotations\n double_s = s + s\n # Check for each possible rotation\n for i in range(1, len(s) + 1):\n rotated_s = double_s[i:i+len(s)]\n if rotated_s == s:\n return i\n # If no rotation matches, the original string must be invariant under rotation\n return len(s)", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(s):\n \"\"\"\n This function calculates the minimum number of rotations needed to get the same string.\n A rotation is defined as moving the last character of the string to the front.\n \n Parameters:\n s (str): The input string to be rotated.\n \n Returns:\n int: The minimum number of rotations required to get the same string.\n \"\"\"\n \n # Double the string to simulate rotations\n doubled_s = s + s\n # Length of the original string\n n = len(s)\n \n # Iterate through possible rotation points\n for i in range(1, n):\n # Check if the substring from the current point till the end forms the original string\n if doubled_s[i:i+n] == s:\n return i\n \n # If no rotation is needed to get the same string, return the length of the string\n return n", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(s):\n \"\"\"\n Finds the minimum number of rotations (greater than 0) required to get the same string.\n \n Parameters:\n s (str): The input string to find rotations for.\n \n Returns:\n int: The minimum number of rotations required to get the same string.\n \"\"\"\n \n # Double the string and check for the first occurrence of the original string\n doubled_s = s + s\n for i in range(1, len(s)):\n if doubled_s[i:i+len(s)] == s:\n return i\n return len(s)", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(s):\n \"\"\"\n This function finds the minimum number of rotations (greater than 0) required to get the same string.\n \n Parameters:\n s (str): The input string to rotate.\n \n Returns:\n int: The minimum number of rotations required to get the same string.\n \"\"\"\n \n # Double the string to simulate rotations\n doubled_s = s + s\n # Iterate through each possible rotation\n for i in range(1, len(s)):\n # Check if the rotated substring matches the original string\n if doubled_s[i:i+len(s)] == s:\n return i\n # If no rotation other than 0 is possible, return the length of the string\n return len(s)", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(s):\n \"\"\"\n This function calculates the minimum number of rotations needed to get the same string.\n A rotation means taking the last character of the string and moving it to the front.\n \n Parameters:\n s (str): The input string.\n \n Returns:\n int: The minimum number of rotations required to get the same string.\n \"\"\"\n \n # The string repeats itself after len(s) rotations, thus the range is set to len(s)\n for i in range(1, len(s) + 1):\n # Check if the rotated string matches the original string\n if s == s[i:] + s[:i]:\n return i\n return len(s) # The string will always match after 'len(s)' rotations if not earlier", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(s):\n \"\"\"\n Finds the minimum number of rotations (greater than 0) required to get the same string.\n \n Parameters:\n s (str): The input string.\n \n Returns:\n int: The minimum number of rotations required.\n \"\"\"\n doubled_string = s + s\n for i in range(1, len(s) + 1):\n if doubled_string[i:i+len(s)] == s:\n return i\n return len(s)", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(s):\n \"\"\"\n This function takes a string 's' as input and returns the minimum number of rotations (greater than 0) required\n to get the same string.\n \n Args:\n s (str): The input string.\n \n Returns:\n int: The minimum number of rotations required.\n \"\"\"\n \n # If the string is empty or a single character, return 1 as the minimum rotation\n if len(s) <= 1:\n return 1\n \n # Iterate through possible rotation points\n for i in range(1, len(s)):\n # Check if the string matches when rotated from the current point\n if s[i:] + s[:i] == s:\n return i\n \n # If no rotation is found (which shouldn't happen as at least 1 full rotation is possible), return the length of the string\n return len(s)", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(s):\n \"\"\"\n Finds the minimum number of rotations (greater than 0) required to get the same string.\n \n Args:\n s (str): The input string.\n \n Returns:\n int: The minimum number of rotations required.\n \"\"\"\n # Double the string to handle rotations easily\n doubled_s = s + s\n # Find the first occurrence of the original string in the doubled string\n for i in range(1, len(s) + 1):\n if doubled_s[i:i+len(s)] == s:\n return i\n # Return the length of the string if no rotation found (shouldn't happen in this problem)\n return len(s)", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(s):\n \"\"\"\n Find the minimum number of rotations (greater than 0) required to get the same string.\n \n Args:\n s : str\n The input string for which to find the minimum number of rotations.\n \n Returns:\n int\n The minimum number of rotations required.\n \"\"\"\n # Double the string to simulate rotations\n double_s = s + s\n # Find the smallest rotation that results in the original string\n for i in range(1, len(s)):\n if double_s[i:i+len(s)] == s:\n return i\n # If no rotation found, return the length of the string (full rotation)\n return len(s)", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(s):\n \"\"\"\n Finds the minimum number of rotations (greater than 0) required to get the same string.\n \n Parameters:\n s (str): The input string for which rotations are to be checked.\n \n Returns:\n int: The minimum number of rotations required to get the same string.\n \"\"\"\n \n # Double the string to simulate rotations\n double_s = s + s\n n = len(s)\n \n # Check each possible rotation\n for i in range(1, n):\n rotated_s = double_s[i:i+n]\n if rotated_s == s:\n return i\n return n", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(s):\n \"\"\"\n Finds the minimum number of rotations (greater than 0) required to get the same string.\n \n Args:\n s (str): The input string to be rotated.\n \n Returns:\n int: The minimum number of rotations required to get the same string.\n \"\"\"\n # Double the string to account for all possible rotations\n doubled_s = s + s\n # Check each rotation starting from the first character\n for i in range(1, len(s) + 1):\n # If the rotated substring matches the original string, return the rotation count\n if doubled_s[i:i+len(s)] == s:\n return i\n return len(s) # If no proper rotation exists, return the length of the string", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(s):\n \"\"\"\n Finds the minimum number of rotations (greater than 0) required to get the same string.\n \n Args:\n s (str): The input string.\n \n Returns:\n int: The minimum number of rotations required to get the same string.\n \"\"\"\n double_s = s + s\n for i in range(1, len(s) + 1):\n if double_s[i:i+len(s)] == s:\n return i\n return len(s)", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(s):\n \"\"\"\n Finds the minimum number of rotations (greater than 0) required to get the same string.\n \n Parameters:\n s (str): The input string to check rotations for.\n \n Returns:\n int: The minimum number of rotations required to get the same string.\n \"\"\"\n # Double the string to facilitate checking rotations\n doubled_s = s + s\n # Find the position of the original string in the doubled string (excluding the first occurrence)\n min_rotations = len(s)\n for i in range(1, len(s)):\n # Check if the substring starting from i is the original string\n if doubled_s[i:i+len(s)] == s:\n min_rotations = i\n break\n return min_rotations", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(s):\n \"\"\"\n Finds the minimum number of rotations required to get the same string.\n \n Parameters:\n s (str): The input string.\n \n Returns:\n int: The minimum number of rotations required to get the same string.\n \"\"\"\n # Double the string and check for the first occurrence of the original string\n doubled_s = s + s\n # The minimum rotation would be from the start of the string, so we can just\n # find the position of the string in the doubled string and exclude the first character\n for i in range(1, len(s)):\n if doubled_s[i:i+len(s)] == s:\n return i\n return len(s)", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(s):\n \"\"\"\n This function finds the minimum number of rotations (greater than 0) required to get the same string.\n \n Parameters:\n s (str): The input string.\n \n Returns:\n int: The minimum number of rotations required.\n \"\"\"\n \n # Double the string and remove the first and last character\n doubled_s = s + s\n rotated_s = doubled_s[1:-1]\n \n # Check the substrings of the length of the original string\n for i in range(len(s), len(rotated_s) + 1):\n if rotated_s[i-len(s):i] == s:\n return i // len(s)\n \n return len(s)", "matching_cluster_idx": 5}]}, "Mbpp/11": {"dps": 32.635351820411245, "dps_norm": 68.42105263157895, "pass@1": 19.0, "profiled": [{"solution": "def remove_Occ(string, char):\n # Remove the first occurrence of the character\n if char in string:\n string = string.replace(char, '', 1)\n \n # Remove the last occurrence of the character\n if char in string:\n reversed_char = char[::-1] # The[::-1] is not necessary for single characters, but kept for clarity.\n string = string[::-1].replace(reversed_char, '', 1)[::-1]\n \n return string", "matching_cluster_idx": 4}, {"solution": "def remove_Occ(str, char):\n # Remove the first occurrence of the character\n first_occurrence = str.find(char)\n if first_occurrence != -1:\n str = str[:first_occurrence] + str[first_occurrence + 1:]\n \n # Remove the last occurrence of the character\n last_occurrence = str.rfind(char)\n if last_occurrence != -1:\n str = str[:last_occurrence] + str[last_occurrence + 1:]\n \n return str", "matching_cluster_idx": 7}, {"solution": "def remove_Occ(string, character):\n # Check if the character is not in the string to avoid errors\n if character not in string:\n return string\n \n # Find the first occurrence index and the last occurrence index\n first_occurrence = string.find(character)\n last_occurrence = string.rfind(character)\n \n # Construct the new string without the first and last occurrence of the character\n result = string[:first_occurrence] + string[first_occurrence+1:last_occurrence] + string[last_occurrence+1:]\n \n return result", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(s, ch):\n # Find the first occurrence of the character\n first_occurrence = s.find(ch)\n # If the character is not found, return the original string\n if first_occurrence == -1:\n return s\n \n # Find the last occurrence of the character\n last_occurrence = s.rfind(ch)\n \n # If first and last occurrences are at the same position, remove one instance\n if first_occurrence == last_occurrence:\n return s[:first_occurrence] + s[first_occurrence+1:]\n \n # Construct the string without the first and last occurrence of the character\n return s[:first_occurrence] + s[first_occurrence+1:last_occurrence] + s[last_occurrence+1:]", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(string, char):\n # Find the first occurrence of the character and remove it\n first_occurrence = string.find(char)\n if first_occurrence != -1:\n string = string[:first_occurrence] + string[first_occurrence+1:]\n \n # Find the last occurrence of the character and remove it\n last_occurrence = string.rfind(char)\n if last_occurrence != -1:\n string = string[:last_occurrence] + string[last_occurrence+1:]\n \n return string", "matching_cluster_idx": 7}, {"solution": "def remove_Occ(input_str, char):\n # Count occurrences of the character in the input string\n count = input_str.count(char)\n \n # If the character is not present at all, return the original string\n if count == 0:\n return input_str\n \n # If the character is present only once, return the string without that character\n if count == 1:\n return input_str.replace(char, \"\", 1)\n \n # Find the indices of the first and last occurrences of the character\n first_occurrence = input_str.index(char)\n last_occurrence = input_str.rindex(char)\n \n # Return the modified string with the first and last occurrence removed\n return input_str[:first_occurrence] + input_str[first_occurrence+1:last_occurrence] + input_str[last_occurrence+1:]", "matching_cluster_idx": 5}, {"solution": "def remove_Occ(string, char):\n # Check if the character is in the string\n if string.find(char) == -1:\n return string\n \n # Remove the first occurrence of the character\n string = string.replace(char, '', 1)\n \n # Remove the last occurrence of the character\n reversed_string = string[::-1]\n reversed_string = reversed_string.replace(char, '', 1)\n result = reversed_string[::-1]\n \n return result", "matching_cluster_idx": 4}, {"solution": "def remove_Occ(s, char):\n # Check if the character is present in the string\n if s.find(char) == -1:\n return s\n \n # Find the first and last occurrence of the character\n first_occurrence = s.find(char)\n last_occurrence = s.rfind(char)\n \n # Construct the result by slicing the string\n # Skip the first occurrence and everything after the last occurrence of the character\n return s[:first_occurrence] + s[first_occurrence+1:last_occurrence] + s[last_occurrence+1:]", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(string, char):\n # Find the first occurrence of the character\n first_occurrence = string.find(char)\n # Find the last occurrence of the character\n last_occurrence = string.rfind(char)\n \n # If the character is not found at all, return the original string\n if first_occurrence == -1:\n return string\n \n # If the first and last occurrence are the same (only one occurrence), remove it\n if first_occurrence == last_occurrence:\n return string[:first_occurrence] + string[first_occurrence+1:]\n # Otherwise, remove the first and last occurrence\n else:\n return string[:first_occurrence] + string[first_occurrence+1:last_occurrence] + string[last_occurrence+1:]", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(string, char):\n # Check if the character exists in the string\n if string.find(char) == -1:\n return string\n \n # Remove first occurrence\n string = string.replace(char, '', 1)\n \n # Remove last occurrence\n string = string[::-1].replace(char[::-1], '', 1)[::-1]\n \n return string", "matching_cluster_idx": 4}, {"solution": "def remove_Occ(string, char):\n # Find the first occurrence of the character and remove it\n first_occurrence = string.find(char)\n if first_occurrence != -1:\n string = string[:first_occurrence] + string[first_occurrence+1:]\n \n # Find the last occurrence of the character and remove it\n last_occurrence = string.rfind(char)\n if last_occurrence != -1:\n string = string[:last_occurrence] + string[last_occurrence+1:]\n \n return string", "matching_cluster_idx": 7}, {"solution": "def remove_Occ(str, ch):\n # Convert the string to a list to allow modification\n str_list = list(str)\n \n # Find the first occurrence of the character and remove it\n first_occurrence = None\n for i, c in enumerate(str_list):\n if c == ch:\n first_occurrence = i\n break\n \n if first_occurrence is not None:\n del str_list[first_occurrence]\n \n # Find the last occurrence of the character and remove it\n last_occurrence = None\n for i in range(len(str_list) - 1, -1, -1):\n if str_list[i] == ch:\n last_occurrence = i\n break\n \n if last_occurrence is not None:\n del str_list[last_occurrence]\n \n # Join the list back to a string and return it\n return ''.join(str_list)", "matching_cluster_idx": 1}, {"solution": "def remove_Occ(string, char):\n # Find the first occurrence of the character and remove it\n first_occurrence = string.find(char)\n if first_occurrence != -1:\n string = string[:first_occurrence] + string[first_occurrence + 1:]\n \n # Find the last occurrence of the character and remove it\n last_occurrence = string.rfind(char)\n if last_occurrence != -1:\n string = string[:last_occurrence] + string[last_occurrence + 1:]\n \n return string", "matching_cluster_idx": 7}, {"solution": "def remove_Occ(string, character):\n # Count occurrences of the character\n count = string.count(character)\n \n # If the character appears at least twice\n if count >= 2:\n # Find the first and last occurrence of the character\n start = string.index(character)\n end = string.rindex(character)\n \n # Remove the first and last occurrence\n string = string[:start] + string[start+1:end] + string[end+1:]\n \n # If the character appears only once, remove that single occurrence\n elif count == 1:\n string = string.replace(character, \"\", 1)\n \n return string", "matching_cluster_idx": 5}, {"solution": "def remove_Occ(string, char):\n # Find the indices of all occurrences of the character\n indices = [i for i, ltr in enumerate(string) if ltr == char]\n \n # If there are at least two occurrences of the character\n if len(indices) > 1:\n # Remove the first and last occurrence\n string = string[:indices[0]] + string[indices[0]+1:indices[-1]] + string[indices[-1]+1:]\n elif len(indices) == 1:\n # If there is only one occurrence, remove that\n string = string[:indices[0]] + string[indices[-1]+1:]\n \n return string", "matching_cluster_idx": -1}, {"solution": "def remove_Occ(s, char):\n # Count all occurrences of the character\n occurrences = [i for i, ltr in enumerate(s) if ltr == char]\n \n # Check if the character is present in the string\n if not occurrences:\n return s\n \n # If there's only one occurrence, remove it\n if len(occurrences) == 1:\n return s[:occurrences[0]] + s[occurrences[0]+1:]\n \n # Remove the first and last occurrence\n first_occurrence = occurrences[0]\n last_occurrence = occurrences[-1]\n return s[:first_occurrence] + s[first_occurrence+1:last_occurrence] + s[last_occurrence+1:]", "matching_cluster_idx": -1}, {"solution": "def remove_Occ(str, char):\n # Check if the character is in the string\n if str.find(char) == -1:\n return str # Return the original string if the character is not found\n \n # Remove first occurrence of the character\n str = str.replace(char, '', 1)\n \n # Remove last occurrence of the character\n str = str[::-1] # Reverse the string\n str = str.replace(char, '', 1) # Remove the first occurrence (last occurrence in the original string)\n str = str[::-1] # Reverse the string back\n \n return str", "matching_cluster_idx": 3}, {"solution": "def remove_Occ(s, char):\n # Find the first occurrence of the character and remove it\n first_occurrence = s.find(char)\n if first_occurrence != -1:\n s = s[:first_occurrence] + s[first_occurrence+1:]\n \n # Find the last occurrence of the character and remove it\n last_occurrence = s.rfind(char)\n if last_occurrence != -1:\n s = s[:last_occurrence] + s[last_occurrence+1:]\n \n return s", "matching_cluster_idx": 7}, {"solution": "def remove_Occ(string, char):\n # Remove the first occurrence of the character\n first_occurrence = string.find(char)\n if first_occurrence != -1:\n string = string[:first_occurrence] + string[first_occurrence + 1:]\n \n # Remove the last occurrence of the character\n last_occurrence = string.rfind(char)\n if last_occurrence != -1:\n string = string[:last_occurrence] + string[last_occurrence + 1:]\n \n return string", "matching_cluster_idx": 7}]}, "Mbpp/12": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def sort_matrix(matrix):\n \"\"\"\n Sorts the given matrix in ascending order based on the sum of its rows.\n \n Parameters:\n matrix (list of list of int): The matrix to be sorted.\n \n Returns:\n list of list of int: The sorted matrix.\n \"\"\"\n # Sort the matrix based on the sum of each row\n sorted_matrix = sorted(matrix, key=sum)\n return sorted_matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Sort the matrix based on the sum of each row\n return sorted(matrix, key=sum)", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"\n Sorts a given matrix in ascending order based on the sum of its rows.\n \n Parameters:\n matrix (list of list of int): The matrix to be sorted.\n \n Returns:\n list of list of int: The sorted matrix.\n \"\"\"\n # Sort the matrix based on the sum of its rows\n sorted_matrix = sorted(matrix, key=sum)\n return sorted_matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Sort the matrix based on the sum of each row\n sorted_matrix = sorted(matrix, key=sum)\n return sorted_matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"\n Sorts a given matrix in ascending order according to the sum of its rows.\n \n Parameters:\n matrix (list of list of int): The input matrix to be sorted.\n \n Returns:\n list of list of int: The sorted matrix.\n \"\"\"\n # Sort the matrix based on the sum of each row\n sorted_matrix = sorted(matrix, key=sum)\n \n return sorted_matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Sort the matrix based on the sum of elements in each row\n return sorted(matrix, key=sum)", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Sort the matrix based on the sum of elements in each row\n sorted_matrix = sorted(matrix, key=sum)\n return sorted_matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"\n Sorts a given matrix in ascending order based on the sum of its rows.\n \n Parameters:\n matrix (list of list of int): The matrix to be sorted.\n \n Returns:\n list of list of int: The sorted matrix.\n \"\"\"\n # Sorting the matrix based on the sum of its rows\n sorted_matrix = sorted(matrix, key=sum)\n return sorted_matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"\n Sorts the given matrix in ascending order based on the sum of each row.\n \n Parameters:\n matrix (list of list of int): The matrix to be sorted.\n \n Returns:\n list of list of int: The sorted matrix.\n \"\"\"\n # Sorting the matrix based on the sum of each row\n sorted_matrix = sorted(matrix, key=sum)\n return sorted_matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Sort the matrix based on the sum of each row\n sorted_matrix = sorted(matrix, key=sum)\n return sorted_matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Sort the matrix based on the sum of each row\n return sorted(matrix, key=sum)", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"\n Sorts a given matrix in ascending order based on the sum of its rows.\n \n Parameters:\n matrix (list of list of int): The input matrix to be sorted.\n \n Returns:\n list of list of int: The sorted matrix.\n \"\"\"\n # Sorting the matrix based on the sum of elements in each row\n sorted_matrix = sorted(matrix, key=sum)\n return sorted_matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Sort the matrix based on the sum of elements in each row\n sorted_matrix = sorted(matrix, key=sum)\n return sorted_matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Sorting the matrix based on the sum of each row\n sorted_matrix = sorted(matrix, key=sum)\n return sorted_matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"\n Sorts the given matrix in ascending order based on the sum of each row.\n \n Parameters:\n matrix (list of list of int): The matrix to be sorted.\n \n Returns:\n list of list of int: The sorted matrix.\n \"\"\"\n # Sort the matrix based on the sum of each row\n sorted_matrix = sorted(matrix, key=sum)\n return sorted_matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"\n Sorts the rows of a given matrix in ascending order according to the sum of its rows.\n\n Parameters:\n matrix (list of lists of int): The input matrix.\n\n Returns:\n list of lists of int: The sorted matrix.\n \"\"\"\n # Sort the matrix based on the sum of each row\n sorted_matrix = sorted(matrix, key=sum)\n return sorted_matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"\n Sorts a given matrix in ascending order based on the sum of its rows.\n \n Parameters:\n matrix (list of list of int): The matrix to be sorted.\n \n Returns:\n list of list of int: The sorted matrix.\n \"\"\"\n # Sorting the matrix based on the sum of each row\n sorted_matrix = sorted(matrix, key=sum)\n return sorted_matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"\n Sorts a given matrix in ascending order based on the sum of each row.\n \n Parameters:\n matrix (list of list of int): The input matrix to be sorted.\n \n Returns:\n list of list of int: The sorted matrix.\n \"\"\"\n # Sort the matrix based on the sum of each row\n sorted_matrix = sorted(matrix, key=sum)\n \n return sorted_matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"\n Sorts a given matrix in ascending order according to the sum of its rows.\n \n Parameters:\n matrix (list of list of int): The input matrix to be sorted.\n \n Returns:\n list of list of int: The sorted matrix.\n \"\"\"\n # Sort the matrix based on the sum of each row\n sorted_matrix = sorted(matrix, key=sum)\n return sorted_matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"\n Sorts a given matrix in ascending order based on the sum of its rows.\n \n Parameters:\n matrix (list of list of int): The input matrix to be sorted.\n \n Returns:\n list of list of int: The sorted matrix.\n \"\"\"\n # Sorting the matrix based on the sum of each row\n sorted_matrix = sorted(matrix, key=sum)\n return sorted_matrix", "matching_cluster_idx": 15}]}, "Mbpp/16": {"dps": null, "dps_norm": null, "pass@1": 1.0, "profiled": []}, "Mbpp/19": {"dps": 94.6969696969697, "dps_norm": 97.0, "pass@1": 97.0, "profiled": [{"solution": "def test_duplicate(nums):\n # Use a set to track seen numbers\n seen = set()\n \n # Iterate through the list\n for num in nums:\n # If number is already in set, a duplicate exists\n if num in seen:\n return True\n # Add the number to the set\n seen.add(num)\n \n # If no duplicates were found, return False\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(nums):\n # Use set to find duplicates\n if len(nums) > len(set(nums)):\n return True\n return False", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(nums):\n # Use a set to track seen numbers\n seen = set()\n \n for num in nums:\n # Check if the number is already in the set\n if num in seen:\n return True\n seen.add(num)\n \n # No duplicates found\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(arr):\n # Use a set to track seen elements\n seen = set()\n \n # Iterate through each element in the array\n for num in arr:\n # Check if the element is already in the set\n if num in seen:\n return True\n seen.add(num)\n \n # Return False if no duplicates are found\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(nums):\n # Use a set to track seen numbers\n seen = set()\n \n for num in nums:\n # Check if the number is already in the set\n if num in seen:\n return True\n seen.add(num)\n \n # Return False if no duplicates were found\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(arr):\n # Use a set to track seen elements\n seen = set()\n \n # Iterate through the array\n for num in arr:\n # If the number is already in the set, a duplicate is found\n if num in seen:\n return True\n # Otherwise, add the number to the set\n seen.add(num)\n \n # If no duplicates are found, return False\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(arr):\n # Create a set to track seen elements\n seen = set()\n \n # Iterate through the array\n for num in arr:\n # Check if the number is already in the set\n if num in seen:\n return True\n # Add the number to the set\n seen.add(num)\n \n # Return False if no duplicates were found\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(nums):\n # Using set to find duplicates\n seen = set()\n for num in nums:\n if num in seen:\n return True\n seen.add(num)\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(nums):\n # Use a set to track seen numbers and check for duplicates\n seen = set()\n for num in nums:\n if num in seen:\n return True\n seen.add(num)\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(nums):\n # Using set to check for duplicates as it stores unique elements\n if len(nums) > len(set(nums)):\n return True\n return False", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(nums):\n # Use a set to track seen numbers\n seen = set()\n \n # Iterate through the list\n for num in nums:\n # Check if the number is already in the set\n if num in seen:\n return True\n # Add the number to the set\n seen.add(num)\n \n # No duplicates found\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(arr):\n # Use a set to track seen numbers\n seen = set()\n \n for num in arr:\n # If num is already in seen, a duplicate exists\n if num in seen:\n return True\n # Add the current number to the seen set\n seen.add(num)\n \n # If no duplicates are found, return False\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(nums):\n # Use a set to track seen numbers\n seen = set()\n \n for num in nums:\n # If the number is already in the set, a duplicate is found\n if num in seen:\n return True\n # Add the number to the set\n seen.add(num)\n \n # No duplicates found\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(arr):\n # Using a set to track seen elements\n seen = set()\n \n for num in arr:\n if num in seen:\n return True\n seen.add(num)\n \n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(nums):\n # Use set to find duplicates\n return len(nums) != len(set(nums))", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(arr):\n # Use a set to track seen elements\n seen = set()\n \n for num in arr:\n # If the number is already in the set, a duplicate is found\n if num in seen:\n return True\n seen.add(num)\n \n # No duplicates found\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(nums):\n # Create a set to store unique elements\n unique_elements = set()\n \n # Iterate through the list of numbers\n for num in nums:\n # Check if the number is already in the set\n if num in unique_elements:\n return True\n # Add the number to the set if it's not already present\n unique_elements.add(num)\n \n # Return False if no duplicates were found\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(arr):\n # Use a set to track seen elements\n seen = set()\n \n # Iterate through the array\n for num in arr:\n # Check if the element is already in the set\n if num in seen:\n return True\n seen.add(num)\n \n # If no duplicates were found, return False\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(arr):\n # Create a set to store seen elements\n seen = set()\n \n # Iterate through each element in the array\n for num in arr:\n # Check if the element is already in the set\n if num in seen:\n return True\n # Add the element to the set\n seen.add(num)\n \n # If no duplicates are found, return False\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(arr):\n # Use a set to track seen elements\n seen = set()\n \n for number in arr:\n if number in seen:\n return True\n seen.add(number)\n \n return False", "matching_cluster_idx": 14}]}, "Mbpp/62": {"dps": 89.5, "dps_norm": 93.0, "pass@1": 100.0, "profiled": [{"solution": "def smallest_num(arr):\n # Use the min function to find the smallest number in the list\n return min(arr)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(numbers):\n \"\"\"\n Finds the smallest number in a given list of numbers.\n \n Parameters:\n - numbers (list): A list of numbers.\n \n Returns:\n int: The smallest number in the list.\n \"\"\"\n return min(numbers)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(lst):\n \"\"\"\n Finds the smallest number in a given list of numbers.\n\n Parameters:\n lst (list): A list of numbers.\n\n Returns:\n int: The smallest number in the list.\n \"\"\"\n # Initialize min_num with the first element of the list\n min_num = lst[0]\n \n # Iterate through the list to find the minimum number\n for num in lst:\n if num < min_num:\n min_num = num\n \n return min_num", "matching_cluster_idx": 3}, {"solution": "def smallest_num(lst):\n return min(lst)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(lst):\n \"\"\"\n Finds the smallest number in the given list.\n \n Parameters:\n lst (list): A list of integers.\n \n Returns:\n int: The smallest integer in the list.\n \"\"\"\n # Using Python's built-in min function for simplicity\n return min(lst)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(nums):\n # Use the min function to find the smallest number in the list\n return min(nums)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(lst):\n \"\"\"\n This function takes a list of numbers and returns the smallest one.\n \n Parameters:\n lst (list): A list of numbers (integers or floats).\n \n Returns:\n int or float: The smallest number in the list.\n \"\"\"\n # Initialize min_num with the first element of the list\n min_num = lst[0]\n \n # Iterate through each number in the list\n for num in lst:\n # If a number less than min_num is found, update min_num\n if num < min_num:\n min_num = num\n \n return min_num", "matching_cluster_idx": 3}, {"solution": "def smallest_num(lst):\n return min(lst)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(arr):\n # Use the min function to find the smallest element in the list\n return min(arr)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(lst):\n \"\"\"\n Finds the smallest number in a given list of integers.\n \n Parameters:\n lst (list): A list of integers.\n \n Returns:\n int: The smallest integer in the list.\n \"\"\"\n # Using the min function to find the smallest number in the list\n return min(lst)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(lst):\n # Return the smallest number in the list using the min function\n return min(lst)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(lst):\n \"\"\"\n This function returns the smallest number in a given list.\n \n Parameters:\n lst (list): A list of integers.\n \n Returns:\n int: The smallest integer in the given list.\n \"\"\"\n # Initialize min_num with the first element of the list\n min_num = lst[0]\n \n # Iterate through all elements in the list\n for num in lst:\n # If num is less than min_num, update min_num\n if num < min_num:\n min_num = num\n \n return min_num", "matching_cluster_idx": 3}, {"solution": "def smallest_num(lst):\n # Use the min function to find the smallest number in the list\n return min(lst)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(lst):\n \"\"\"\n Finds the smallest number in a given list.\n \n Parameters:\n - lst: List of integers\n \n Returns:\n The smallest integer in the list.\n \"\"\"\n # Initially set the smallest to the first element of the list\n smallest = lst[0]\n \n # Iterate through each number in the list\n for num in lst:\n # If current number is smaller than the smallest, update smallest\n if num < smallest:\n smallest = num\n \n return smallest", "matching_cluster_idx": 3}, {"solution": "def smallest_num(lst):\n \"\"\"\n Finds the smallest number in a given list.\n \n Parameters:\n lst (list): A list of numbers.\n \n Returns:\n int/float: The smallest number in the list.\n \"\"\"\n # Initialize the smallest number as the first element in the list\n smallest = lst[0]\n \n # Iterate through the list to find the smallest number\n for num in lst:\n if num < smallest:\n smallest = num\n \n return smallest", "matching_cluster_idx": 3}, {"solution": "def smallest_num(lst):\n \"\"\"\n Finds the smallest number in a given list.\n \n Parameters:\n lst (list): A list of integers.\n \n Returns:\n int: The smallest integer in the list.\n \"\"\"\n # Initialize minimum with the first element of the list\n min_num = lst[0]\n \n # Iterate through the list to find the smallest number\n for num in lst:\n if num < min_num:\n min_num = num\n \n return min_num", "matching_cluster_idx": 3}, {"solution": "def smallest_num(lst):\n \"\"\"\n Finds the smallest number in the given list.\n\n Parameters:\n lst (list): A list of integers.\n\n Returns:\n int: The smallest integer in the list.\n \"\"\"\n # Use the min function to find the smallest element in the list\n return min(lst)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(lst):\n # Use min function to find the smallest number in the list\n return min(lst)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(lst):\n # Find the smallest number in the list\n return min(lst)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(lst):\n \"\"\"\n Find and return the smallest number in the given list.\n \n :param lst: List of integers\n :return: The smallest integer in the list\n \"\"\"\n # Initialize min_num with the first element of the list\n min_num = lst[0]\n \n # Iterate through the list to find the minimum value\n for num in lst:\n if num < min_num:\n min_num = num\n \n return min_num", "matching_cluster_idx": 3}]}, "Mbpp/75": {"dps": 92.85714285714286, "dps_norm": 66.66666666666667, "pass@1": 99.0, "profiled": [{"solution": "def find_tuples(lst, k):\n \"\"\"\n Finds tuples where all elements are divisible by k.\n \n Parameters:\n lst (list of tuples): The list of tuples to filter.\n k (int): The divisor.\n \n Returns:\n list: A list of tuples where each element is divisible by k.\n \"\"\"\n # Use list comprehension to filter tuples\n filtered_tuples = [tup for tup in lst if all(x % k == 0 for x in tup)]\n return filtered_tuples", "matching_cluster_idx": 5}, {"solution": "def find_tuples(lst, k):\n \"\"\"\n Finds tuples which have all elements divisible by k from the given list of tuples.\n \n Parameters:\n lst (list of tuples): The list containing tuples.\n k (int): The divisor.\n \n Returns:\n list: A list containing only tuples where all elements are divisible by k.\n \"\"\"\n # Filter tuples where all elements are divisible by k\n result = [t for t in lst if all(x % k == 0 for x in t)]\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n \"\"\"\n Finds tuples from the given list of tuples where all elements are divisible by k.\n \n Parameters:\n tuples_list (list of tuples): The list containing tuples.\n k (int): The divisor to check against each element in the tuples.\n \n Returns:\n list: A list of tuples where each element is divisible by k.\n \"\"\"\n # Filter tuples where all elements are divisible by k\n result = [t for t in tuples_list if all(x % k == 0 for x in t)]\n \n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(lst, k):\n \"\"\"\n Finds tuples from the given list where all elements are divisible by k.\n \n Parameters:\n lst (list of tuples): The list of tuples to filter.\n k (int): The divisor to check divisibility against.\n \n Returns:\n list: A list of tuples where all elements are divisible by k.\n \"\"\"\n # Filter the list of tuples based on divisibility\n result = [tup for tup in lst if all(x % k == 0 for x in tup)]\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n \"\"\"\n This function receives a list of tuples and an integer k. It returns a list of tuples where all elements are divisible by k.\n \n :param tuples_list: List of tuples containing integer elements\n :param k: Integer value to check divisibility\n :return: Filtered list of tuples with all elements divisible by k\n \"\"\"\n # Filter tuples to include only those where all elements are divisible by k\n filtered_tuples = [t for t in tuples_list if all(i % k == 0 for i in t)]\n \n return filtered_tuples", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n \"\"\"\n This function takes a list of tuples and an integer k as inputs and returns a list of tuples where all elements are divisible by k.\n \n :param tuples_list: List of tuples containing integer elements.\n :param k: An integer by which all elements in the tuples are checked for divisibility.\n :return: A list of tuples where each element is divisible by k.\n \"\"\"\n # Filter out the tuples where all elements are divisible by k\n divisible_tuples = [tup for tup in tuples_list if all(element % k == 0 for element in tup)]\n \n return divisible_tuples", "matching_cluster_idx": 5}, {"solution": "def find_tuples(lst, k):\n \"\"\"\n Finds tuples within a list where all elements are divisible by k.\n\n Parameters:\n lst (list of tuples): The list of tuples to search through.\n k (int): The divisor to check divisibility against.\n\n Returns:\n list: A list containing only the tuples where all elements are divisible by k.\n \"\"\"\n # Use a list comprehension to filter tuples based on divisibility condition\n return [t for t in lst if all(x % k == 0 for x in t)]", "matching_cluster_idx": 5}, {"solution": "def find_tuples(lst, k):\n \"\"\"\n Finds tuples in the given list where all elements are divisible by k.\n\n Parameters:\n lst (list of tuples): The list of tuples to filter.\n k (int): The divisor to check for divisibility.\n\n Returns:\n list: A list of tuples where each element is divisible by k.\n \"\"\"\n # Use list comprehension to filter tuples\n filtered_tuples = [t for t in lst if all(x % k == 0 for x in t)]\n return filtered_tuples", "matching_cluster_idx": 5}, {"solution": "def find_tuples(test_list, k):\n # Filter tuples where all elements are divisible by k\n res = [sub for sub in test_list if all(i % k == 0 for i in sub)]\n return res", "matching_cluster_idx": 5}, {"solution": "def find_tuples(lst, k):\n \"\"\"\n Finds tuples from a list where all elements are divisible by k.\n \n Parameters:\n lst (list of tuples): A list of tuples to be filtered.\n k (int): The divisor to check divisibility against.\n \n Returns:\n list: A list of tuples where each element is divisible by k.\n \"\"\"\n # Filter tuples where all elements are divisible by k\n filtered_tuples = [tup for tup in lst if all(x % k == 0 for x in tup)]\n return filtered_tuples", "matching_cluster_idx": 5}, {"solution": "def find_tuples(lst, k):\n \"\"\"\n Finds and returns tuples from a list where all elements are divisible by k.\n \n Parameters:\n lst : list of tuples\n A list containing tuples.\n k : int\n The divisor.\n \n Returns:\n list\n A list of tuples where each element in the tuple is divisible by k.\n \"\"\"\n # Filter tuples where all elements are divisible by k\n result = [t for t in lst if all(i % k == 0 for i in t)]\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(lst, k):\n \"\"\"\n Finds tuples in the list which have all elements divisible by k.\n \n Parameters:\n lst (list of tuples): A list of tuples to be filtered.\n k (int): The divisor against which to check the elements of the tuples.\n \n Returns:\n list: A list of tuples where each element of the tuples is divisible by k.\n \"\"\"\n # Filter tuples where all elements are divisible by k\n result = [tup for tup in lst if all(element % k == 0 for element in tup)]\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n \"\"\"\n Finds tuples from the given list of tuples which have all elements divisible by k.\n \n :param tuples_list: List of tuples to be filtered.\n :param k: Divisor to check divisibility by.\n :return: A list of tuples where each element is divisible by k.\n \"\"\"\n # Filter tuples where all elements are divisible by k\n filtered_tuples = [t for t in tuples_list if all(element % k == 0 for element in t)]\n return filtered_tuples", "matching_cluster_idx": 5}, {"solution": "def find_tuples(lst, k):\n \"\"\"\n Find tuples from a given list of tuples where all elements are divisible by k.\n \n :param lst: List of tuples to be filtered\n :param k: The divisor to check divisibility against\n :return: A list of tuples with all elements divisible by k\n \"\"\"\n # Filter tuples where all elements are divisible by k\n result = [t for t in lst if all(x % k == 0 for x in t)]\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(input_list, k):\n \"\"\"\n Finds tuples from the given list where all elements are divisible by k.\n \n Parameters:\n input_list (list of tuples): The list containing tuples to be filtered.\n k (int): The divisor to check divisibility against.\n \n Returns:\n list: A list of tuples from input_list where all elements are divisible by k.\n \"\"\"\n # Filter tuples where all elements are divisible by k\n filtered_tuples = [t for t in input_list if all(x % k == 0 for x in t)]\n \n return filtered_tuples", "matching_cluster_idx": 5}, {"solution": "def find_tuples(lst, k):\n \"\"\"\n Finds tuples which have all elements divisible by k from the given list of tuples.\n \n Parameters:\n lst (list of tuples): The list of tuples to be filtered.\n k (int): The divisor to check the divisibility of elements in tuples.\n \n Returns:\n list: A list of tuples where each tuple has all elements divisible by k.\n \"\"\"\n # Use a list comprehension to filter tuples\n filtered_tuples = [t for t in lst if all(x % k == 0 for x in t)]\n return filtered_tuples", "matching_cluster_idx": 5}, {"solution": "def find_tuples(test_list, k):\n # Use list comprehension to filter tuples where all elements are divisible by k\n res = [sub for sub in test_list if all(i % k == 0 for i in sub)]\n return res", "matching_cluster_idx": 5}, {"solution": "def find_tuples(lst, k):\n \"\"\"\n Finds tuples which have all elements divisible by k from the given list of tuples.\n \n Parameters:\n lst (list of tuples): The input list containing tuples of integers.\n k (int): The divisor.\n \n Returns:\n list: A list of tuples that have all elements divisible by k.\n \"\"\"\n # Filter the list to include only those tuples where all elements are divisible by k\n result = [tup for tup in lst if all(x % k == 0 for x in tup)]\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n \"\"\"\n Finds tuples which have all elements divisible by k from the given list of tuples.\n \n Parameters:\n tuples_list (list): A list of tuples, each containing integers.\n k (int): An integer to check divisibility by.\n \n Returns:\n list: A list of tuples where each tuple's elements are all divisible by k.\n \"\"\"\n # Filter tuples where all elements are divisible by k\n result = [t for t in tuples_list if all(x % k == 0 for x in t)]\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(lst, k):\n \"\"\"\n Finds tuples which have all elements divisible by k from the given list of tuples.\n \n Parameters:\n lst (list of tuples): The list of tuples to be filtered.\n k (int): The divisor to check divisibility against.\n \n Returns:\n list: A list of tuples where all elements in each tuple are divisible by k.\n \"\"\"\n # Use list comprehension to filter tuples\n filtered_tuples = [t for t in lst if all(i % k == 0 for i in t)]\n return filtered_tuples", "matching_cluster_idx": 5}]}, "Mbpp/88": {"dps": 51.666666666666664, "dps_norm": 65.71428571428571, "pass@1": 100.0, "profiled": [{"solution": "def freq_count(lst):\n from collections import defaultdict\n \n # Initialize a dictionary to hold the frequency of each element\n frequency_dict = defaultdict(int)\n \n # Iterate through the list and count the frequency of each element\n for element in lst:\n frequency_dict[element] += 1\n \n # Convert defaultdict to a regular dict before returning\n return dict(frequency_dict)", "matching_cluster_idx": 3}, {"solution": "def freq_count(nums):\n \"\"\"\n Get the frequency of all the elements in a list, returned as a dictionary.\n \n Parameters:\n nums (list): A list of integers.\n \n Returns:\n dict: A dictionary where keys are the unique elements from the list and values are their frequencies.\n \"\"\"\n frequency_dict = {}\n for num in nums:\n if num in frequency_dict:\n frequency_dict[num] += 1\n else:\n frequency_dict[num] = 1\n return frequency_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(arr):\n from collections import defaultdict\n \n # Initialize a dictionary to store the frequency of each element\n freq_dict = defaultdict(int)\n \n # Iterate through each element in the list and count its frequency\n for elem in arr:\n freq_dict[elem] += 1\n \n return dict(freq_dict)", "matching_cluster_idx": 3}, {"solution": "def freq_count(arr):\n from collections import defaultdict\n \n # Initialize a dictionary to store the frequency of elements\n freq_dict = defaultdict(int)\n \n # Iterate through the list and count the frequency of each element\n for element in arr:\n freq_dict[element] += 1\n \n return dict(freq_dict)", "matching_cluster_idx": 3}, {"solution": "def freq_count(list_of_numbers):\n \"\"\"\n Given a list, returns a dictionary with the frequency of each element.\n \n Args:\n list_of_numbers (list): A list of elements.\n \n Returns:\n dict: A dictionary where each key is an element from the list and its value is the frequency.\n \"\"\"\n frequency_dict = {}\n for item in list_of_numbers:\n if item in frequency_dict:\n frequency_dict[item] += 1\n else:\n frequency_dict[item] = 1\n return frequency_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n from collections import defaultdict\n \n # Initialize a dictionary to hold the frequency of each element\n freq_dict = defaultdict(int)\n \n # Iterate over the list and count the frequency of each element\n for element in lst:\n freq_dict[element] += 1\n \n # Convert defaultdict to a regular dictionary before returning\n return dict(freq_dict)", "matching_cluster_idx": 3}, {"solution": "def freq_count(nums):\n from collections import defaultdict\n \n # Initialize a dictionary to store the frequency of each element\n freq_dict = defaultdict(int)\n \n # Iterate through the list and count the frequency of each element\n for num in nums:\n freq_dict[num] += 1\n \n return dict(freq_dict)", "matching_cluster_idx": 3}, {"solution": "def freq_count(nums):\n from collections import defaultdict\n \n # Initialize a dictionary to store the frequency of each element\n frequency_dict = defaultdict(int)\n \n # Iterate over the list and count the frequency of each element\n for num in nums:\n frequency_dict[num] += 1\n \n return dict(frequency_dict)", "matching_cluster_idx": 3}, {"solution": "def freq_count(arr):\n \"\"\"\n Get the frequency of all the elements in a list and return it as a dictionary.\n \n Parameters:\n arr (list): The input list of elements.\n \n Returns:\n dict: A dictionary with elements as keys and their frequencies as values.\n \"\"\"\n # Use a dictionary to keep track of the frequency of each element\n freq_dict = {}\n for element in arr:\n if element in freq_dict:\n freq_dict[element] += 1\n else:\n freq_dict[element] = 1\n return freq_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(arr):\n from collections import defaultdict\n \n # Initialize a default dictionary to hold the frequency of each element\n frequency = defaultdict(int)\n \n # Iterate through each element in the list and update its count in the dictionary\n for element in arr:\n frequency[element] += 1\n \n return dict(frequency)", "matching_cluster_idx": 3}, {"solution": "def freq_count(nums):\n \"\"\"\n Get the frequency of all the elements in the list `nums`.\n \n Args:\n nums (list): The list of elements.\n \n Returns:\n dict: A dictionary where keys are the unique elements from `nums` and values are their frequencies.\n \"\"\"\n frequency_dict = {}\n for num in nums:\n if num in frequency_dict:\n frequency_dict[num] += 1\n else:\n frequency_dict[num] = 1\n return frequency_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(arr):\n \"\"\"\n Returns the frequency of all the elements in a list as a dictionary.\n \n Parameters:\n arr (list): The input list of elements.\n \n Returns:\n dict: A dictionary where keys are the elements of the list and values are their frequencies.\n \"\"\"\n # Use dictionary comprehension to count the frequency of each element\n return {i: arr.count(i) for i in arr}", "matching_cluster_idx": 0}, {"solution": "def freq_count(lst):\n # Initialize an empty dictionary to store the frequency of each element\n frequency = {}\n \n # Iterate through each element in the list\n for item in lst:\n # If the element is already in the dictionary, increment its count\n if item in frequency:\n frequency[item] += 1\n # If the element is not in the dictionary, add it with a count of 1\n else:\n frequency[item] = 1\n \n # Return the dictionary containing the frequency of each element\n return frequency", "matching_cluster_idx": 5}, {"solution": "def freq_count(arr):\n \"\"\"\n Returns the frequency of all elements in a given list as a dictionary.\n \n :param arr: List of elements whose frequencies are to be counted.\n :return: Dictionary containing elements and their frequency in the list.\n \"\"\"\n freq_dict = {}\n for element in arr:\n if element in freq_dict:\n freq_dict[element] += 1\n else:\n freq_dict[element] = 1\n return freq_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(nums):\n \"\"\"\n This function takes a list of elements and returns a dictionary with each unique element as a key and their frequency as values.\n \n :param nums: List of elements.\n :return: A dictionary with the frequency of each element in the input list.\n \"\"\"\n # Using the dictionary constructor to convert list items to dictionary keys\n # with their counts as values\n freq_dict = dict()\n for num in nums:\n if num in freq_dict:\n freq_dict[num] += 1\n else:\n freq_dict[num] = 1\n \n return freq_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n \"\"\"\n This function takes a list as input and returns a dictionary\n containing elements of the list as keys and their frequencies as values.\n \"\"\"\n # Using dictionary comprehension to count the frequency of each element in the list\n return {item: lst.count(item) for item in set(lst)}", "matching_cluster_idx": 2}, {"solution": "def freq_count(nums):\n from collections import defaultdict\n \n # Initialize a dictionary to hold the frequency of each element\n frequency_dict = defaultdict(int)\n \n # Iterate over the list to count the frequency of each element\n for num in nums:\n frequency_dict[num] += 1\n \n return dict(frequency_dict)", "matching_cluster_idx": 3}, {"solution": "def freq_count(arr):\n from collections import defaultdict\n \n # Initialize a dictionary to store the frequency of each element\n frequency_dict = defaultdict(int)\n \n # Iterate through the list and count the frequency of each element\n for element in arr:\n frequency_dict[element] += 1\n \n return dict(frequency_dict)", "matching_cluster_idx": 3}, {"solution": "def freq_count(nums):\n from collections import defaultdict\n \n # Initialize a default dictionary to hold frequencies\n freq_dict = defaultdict(int)\n \n # Iterate over the list and count occurrences of each element\n for num in nums:\n freq_dict[num] += 1\n \n # Convert defaultdict to a regular dictionary before returning\n return dict(freq_dict)", "matching_cluster_idx": 3}, {"solution": "def freq_count(arr):\n frequency_dict = {}\n for element in arr:\n if element in frequency_dict:\n frequency_dict[element] += 1\n else:\n frequency_dict[element] = 1\n return frequency_dict", "matching_cluster_idx": 5}]}, "Mbpp/90": {"dps": 81.5609756097561, "dps_norm": 87.14285714285714, "pass@1": 100.0, "profiled": [{"solution": "def len_log(words):\n # Initialize maximum length variable\n max_length = 0\n \n # Iterate through each word in the list\n for word in words:\n # Update max_length if the current word's length is greater\n if len(word) > max_length:\n max_length = len(word)\n \n return max_length", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n # Find the length of the longest word by using the max function with key=len\n longest_length = max(len(word) for word in words)\n return longest_length", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n # Initialize maximum length to 0\n max_len = 0\n \n # Iterate through each word in the list\n for word in words:\n # Update maximum length if current word's length is greater\n if len(word) > max_len:\n max_len = len(word)\n \n return max_len", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n \"\"\"\n Function to find the length of the longest word in a list.\n \n Parameters:\n words (list): A list of words.\n \n Returns:\n int: The length of the longest word.\n \"\"\"\n max_length = 0\n for word in words:\n if len(word) > max_length:\n max_length = len(word)\n return max_length", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n \"\"\"\n This function takes a list of words and returns the length of the longest word.\n \n Args:\n words (list): A list of words (strings).\n \n Returns:\n int: The length of the longest word.\n \"\"\"\n # Using the max function with a key that returns the length of each word\n longest_length = max(len(word) for word in words)\n return longest_length", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n # Find the maximum length among the words using the max function with key=len\n max_length = max(len(word) for word in words)\n return max_length", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n max_length = 0\n for word in words:\n if len(word) > max_length:\n max_length = len(word)\n return max_length", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n \"\"\"\n This function takes a list of words and returns the length of the longest word.\n \n Parameters:\n words (list): A list of words.\n \n Returns:\n int: The length of the longest word.\n \"\"\"\n max_length = 0\n \n for word in words:\n if len(word) > max_length:\n max_length = len(word)\n \n return max_length", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n if not words:\n return 0 # Return 0 if the list is empty\n \n # Use the max function with key=len to find the longest word's length\n return max(len(word) for word in words)", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n # Use the max function with a generator expression to find the longest word length\n longest_length = max(len(word) for word in words)\n return longest_length", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n max_length = 0\n # Iterate through each word in the list to find the maximum length\n for word in words:\n if len(word) > max_length:\n max_length = len(word)\n return max_length", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n # Use max function with key parameter to find the maximum length among the words\n longest_word_length = max(words, key=len)\n return len(longest_word_length)", "matching_cluster_idx": 6}, {"solution": "def len_log(words):\n \"\"\"\n Finds the length of the longest word in a list of words.\n \n Parameters:\n words (list): A list of words (strings).\n \n Returns:\n int: The length of the longest word.\n \"\"\"\n # Use max function with key=len to find the longest word\n longest_word = max(words, key=len)\n return len(longest_word)", "matching_cluster_idx": 6}, {"solution": "def len_log(words):\n # Find the maximum length of words in the list\n max_length = max(len(word) for word in words)\n return max_length", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n \"\"\"\n Find the length of the longest word in a list of words.\n \n Parameters:\n words (list): A list of words as strings\n \n Returns:\n int: The length of the longest word in the list\n \"\"\"\n # Initialize the maximum length variable\n max_length = 0\n \n # Iterate through each word in the list\n for word in words:\n # Update the maximum length if the current word is longer\n if len(word) > max_length:\n max_length = len(word)\n \n return max_length", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n if not words:\n return 0\n \n # Initialize max_length with a value less than any possible word length\n max_length = -1\n \n # Iterate through each word in the list to find the maximum length\n for word in words:\n if len(word) > max_length:\n max_length = len(word)\n \n return max_length", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n # Find the length of the longest word in the list\n longest_length = max(len(word) for word in words)\n return longest_length", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n \"\"\"\n This function takes a list of words and returns the length of the longest word.\n \n Parameters:\n words (list): A list of words (strings).\n \n Returns:\n int: The length of the longest word.\n \"\"\"\n # Use max with a generator expression to find the longest word\n longest_length = max(len(word) for word in words)\n return longest_length", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n # Find the maximum length of words in the list\n max_length = max(len(word) for word in words)\n return max_length", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n \"\"\"\n Finds the length of the longest word in a list of words.\n \n Parameters:\n words (list): A list of words (strings).\n \n Returns:\n int: The length of the longest word.\n \"\"\"\n # Initialize the maximum length to 0\n max_length = 0\n \n # Iterate through the list of words\n for word in words:\n # Update the maximum length if the current word's length is greater\n if len(word) > max_length:\n max_length = len(word)\n \n return max_length", "matching_cluster_idx": 5}]}, "Mbpp/94": {"dps": 78.04878048780488, "dps_norm": 60.0, "pass@1": 99.0, "profiled": [{"solution": "def index_minimum(items):\n # Find the tuple with the smallest second value\n min_item = min(items, key=lambda x: x[1])\n # Return the first value of the tuple with the smallest second value\n return min_item[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(test_list):\n # Find the tuple with the smallest second value\n min_tuple = min(test_list, key=lambda x: x[1])\n # Return the first value of that tuple\n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(tuples_list):\n # Find the tuple with the smallest second value\n min_tuple = min(tuples_list, key=lambda x: x[1])\n # Return the first value of the found tuple\n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(tuples_list):\n # Find the tuple with the smallest second value\n min_tuple = min(tuples_list, key=lambda x: x[1])\n # Return the first value of the found tuple\n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(tuples_list):\n # Find the tuple with the smallest second value\n min_tuple = min(tuples_list, key=lambda x: x[1])\n # Return the first value of the found tuple\n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(test_list):\n \"\"\"\n This function takes a list of tuples and returns the first value of the tuple with the smallest second value.\n \n Parameters:\n test_list (list): A list of tuples where each tuple contains at least two items.\n \n Returns:\n str: The first value of the tuple with the smallest second value.\n \"\"\"\n # Finding the tuple with the smallest second value\n min_tuple = min(test_list, key=lambda x: x[1])\n # Returning the first value of the tuple\n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(tuples_list):\n # Find the tuple with the smallest second element\n min_tuple = min(tuples_list, key=lambda x: x[1])\n # Return the first element of that tuple\n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(tuple_list):\n # Find the tuple with the smallest second value\n min_tuple = min(tuple_list, key=lambda x: x[1])\n # Return the first value of that tuple\n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(tuple_list):\n # Find the tuple with the smallest second value\n min_tuple = min(tuple_list, key=lambda x: x[1])\n # Return the first value of the found tuple\n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(tuple_list):\n # Find the tuple with the smallest second value\n min_tuple = min(tuple_list, key=lambda x: x[1])\n # Return the first value of the found tuple\n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(input_list):\n # Find the tuple with the smallest second value\n min_tuple = min(input_list, key=lambda x: x[1])\n # Return the first value of the tuple with the smallest second value\n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(tuples_list):\n # Find the tuple with the smallest second element\n min_tuple = min(tuples_list, key=lambda x: x[1])\n # Return the first element of that tuple\n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(tuple_list):\n # Find the tuple with the smallest second value and return its first value\n return min(tuple_list, key=lambda x: x[1])[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(tuples_list):\n # Find the tuple with the smallest second element\n min_tuple = min(tuples_list, key=lambda x: x[1])\n # Return the first element of the found tuple\n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(tuples_list):\n # Find the tuple with the smallest second value\n min_tuple = min(tuples_list, key=lambda x: x[1])\n # Return the first value of that tuple\n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(tuples_list):\n # Find the tuple with the smallest second element\n min_tuple = min(tuples_list, key=lambda x: x[1])\n # Return the first element of the found tuple\n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(tuples_list):\n # Find the tuple with the smallest second value\n min_tuple = min(tuples_list, key=lambda x: x[1])\n # Return the first value of the found tuple\n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(item_list):\n # Find the tuple with the smallest second value\n min_item = min(item_list, key=lambda item: item[1])\n # Return the first value of the found tuple\n return min_item[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(tuple_list):\n # Find the tuple with the smallest second element\n min_tuple = min(tuple_list, key=lambda x: x[1])\n # Return the first value of this tuple\n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(tuple_list):\n \"\"\"\n Given a list of tuples, returns the first value of the tuple with the smallest second value.\n \n :param tuple_list: List of tuples where each tuple contains at least two elements.\n :return: The first value of the tuple with the smallest second value.\n \"\"\"\n # Find the tuple with the smallest second value\n smallest_tuple = min(tuple_list, key=lambda x: x[1])\n # Return the first value of the found tuple\n return smallest_tuple[0]", "matching_cluster_idx": 2}]}, "Mbpp/96": {"dps": 53.194444444444436, "dps_norm": 53.57142857142857, "pass@1": 100.0, "profiled": [{"solution": "def divisor(n):\n count = 0\n # Loop through all numbers from 1 to n to check if they are divisors of n\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def divisor(n):\n \"\"\"\n Finds the number of divisors of a given integer n.\n \n Parameters:\n n (int): The integer to find the divisors for.\n \n Returns:\n int: The number of divisors of the integer n.\n \"\"\"\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def divisor(n):\n \"\"\"\n Finds the number of divisors of a given integer n.\n \n Parameters:\n n (int): The integer to find divisors for.\n \n Returns:\n int: The number of divisors of n.\n \"\"\"\n count = 0\n for i in range(1, int(n ** 0.5) + 1):\n if n % i == 0:\n # If divisors are equal, count only once\n if n // i == i:\n count += 1\n else:\n # Count both divisors\n count += 2\n return count", "matching_cluster_idx": 6}, {"solution": "def divisor(n):\n count = 0\n # Loop through all numbers from 1 to n\n for i in range(1, n + 1):\n # If i is a divisor of n, increment count\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n count = 0\n # Loop through all numbers from 1 to n to check if they are divisors of n\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def divisor(n):\n \"\"\"\n Function to find the number of divisors of a given integer.\n \n Parameters:\n n (int): The integer to find the divisors for.\n \n Returns:\n int: The number of divisors.\n \"\"\"\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n if n // i == i:\n count += 1\n else:\n count += 2\n return count", "matching_cluster_idx": 6}, {"solution": "def divisor(n):\n \"\"\"\n Function to find the number of divisors of a given integer.\n \n Parameters:\n n (int): The integer to find divisors for.\n \n Returns:\n int: The number of divisors of the given integer.\n \"\"\"\n count = 0\n for i in range(1, int(n ** 0.5) + 1):\n if n % i == 0:\n # If divisors are equal, count only once\n if n // i == i:\n count += 1\n else:\n # Count both divisors\n count += 2\n return count", "matching_cluster_idx": 6}, {"solution": "def divisor(n):\n count = 0\n # Loop through all numbers from 1 to n\n for i in range(1, n + 1):\n # If i is a divisor of n, increment count\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n # Initialize count to 0 to keep track of divisors\n count = 0\n # Loop through all numbers from 1 to n\n for i in range(1, n + 1):\n # If i is a divisor of n, increment count\n if n % i == 0:\n count += 1\n # Return the total number of divisors\n return count", "matching_cluster_idx": 1}, {"solution": "def divisor(n):\n \"\"\"\n Find the number of divisors of a given integer n.\n \n Parameters:\n n (int): The integer whose divisors are to be counted.\n \n Returns:\n int: The number of divisors of n.\n \"\"\"\n count = 0\n # Iterate from 1 to the square root of n\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n # If divisors are equal, count only once\n if n // i == i:\n count += 1\n else: \n # Count both divisors\n count += 2\n return count", "matching_cluster_idx": 6}, {"solution": "def divisor(n):\n count = 0\n # Loop through all numbers from 1 to n\n for i in range(1, n + 1):\n # Check if i is a divisor of n\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n count = 0\n # Loop to check for divisors\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n # If divisors are equal, count only once\n if n // i == i:\n count += 1\n else: \n # Count both divisors\n count += 2\n return count", "matching_cluster_idx": 6}, {"solution": "def divisor(n):\n # Initialize count to 0 to store the number of divisors\n count = 0\n \n # Iterate from 1 to n to check for divisors\n for i in range(1, n + 1):\n # If i is a divisor of n, increment count\n if n % i == 0:\n count += 1\n \n # Return the total count of divisors\n return count", "matching_cluster_idx": 1}, {"solution": "def divisor(n):\n # Initialize divisor count to 0\n count = 0\n \n # Loop through all numbers from 1 to n\n for i in range(1, n + 1):\n # Check if i is a divisor of n\n if n % i == 0:\n count += 1 # Increment count if i is a divisor\n \n return count # Return the total count of divisors", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n count = 0\n # Iterate from 1 to n to find all divisors\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n # Initialize the count of divisors\n count = 0\n \n # Iterate through all possible divisors\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n \n return count", "matching_cluster_idx": 1}, {"solution": "def divisor(n):\n count = 0\n # Loop from 1 to n and count divisors\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def divisor(n):\n \"\"\"\n Finds the number of divisors of a given integer n.\n \n Parameters:\n n (int): The integer whose divisors are to be counted.\n \n Returns:\n int: The number of divisors of n.\n \"\"\"\n count = 0\n # Loop through all numbers from 1 to n to check divisibility\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def divisor(n):\n \"\"\"\n Finds the number of divisors of a given integer n.\n \n Parameters:\n n (int): The integer to find divisors for.\n \n Returns:\n int: The number of divisors of n.\n \"\"\"\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n # If divisors are equal, count only once\n if n // i == i:\n count += 1\n else:\n # Count both divisors\n count += 2\n return count", "matching_cluster_idx": 6}, {"solution": "def divisor(n):\n # Initialize count of divisors\n count = 0\n \n # Loop through all numbers from 1 to n\n for i in range(1, n + 1):\n # If i is a divisor of n, increment count\n if n % i == 0:\n count += 1\n \n return count", "matching_cluster_idx": 1}]}, "Mbpp/97": {"dps": 99.65811965811966, "dps_norm": 87.5, "pass@1": 100.0, "profiled": [{"solution": "def frequency_lists(list_of_lists):\n from collections import defaultdict\n \n # Initialize a dictionary to keep track of the frequency of each element\n frequency_dict = defaultdict(int)\n \n # Iterate through each sublist in the list of lists\n for sublist in list_of_lists:\n # Iterate through each element in the sublist\n for element in sublist:\n # Increment the frequency of the element\n frequency_dict[element] += 1\n \n return dict(frequency_dict)", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lists):\n from collections import defaultdict\n \n # Initialize a default dictionary to store frequencies\n frequency_dict = defaultdict(int)\n \n # Iterate over each sublist in the main list\n for sublist in lists:\n # Iterate over each element in the sublist\n for element in sublist:\n # Increment the count of the element in the dictionary\n frequency_dict[element] += 1\n \n # Convert defaultdict to a regular dictionary before returning\n return dict(frequency_dict)", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lists):\n from collections import defaultdict\n \n # Flatten the list of lists into a single list\n flattened_list = [item for sublist in lists for item in sublist]\n \n # Use defaultdict to count the frequency of each element\n frequency_dict = defaultdict(int)\n for item in flattened_list:\n frequency_dict[item] += 1\n \n # Convert defaultdict back to a regular dict before returning\n return dict(frequency_dict)", "matching_cluster_idx": 6}, {"solution": "from collections import defaultdict\nfrom itertools import chain\ndef frequency_lists(list_of_lists):\n \"\"\"\n Finds the frequency of each element in a flattened list of lists.\n \n Args:\n list_of_lists (list of list of int): A list containing multiple sublists of integers.\n \n Returns:\n dict: A dictionary with each unique element as keys and their frequency counts as values.\n \"\"\"\n # Flatten the list of lists\n flat_list = list(chain(*list_of_lists))\n # Use defaultdict to count the frequency of each element\n frequency_dict = defaultdict(int)\n for item in flat_list:\n frequency_dict[item] += 1\n return dict(frequency_dict)", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(nested_list):\n from collections import defaultdict\n \n # Initialize a default dictionary to store frequencies\n frequency_dict = defaultdict(int)\n \n # Iterate over each sublist in the nested list\n for sublist in nested_list:\n # Iterate over each element in the sublist\n for element in sublist:\n # Increment the count of the element in the dictionary\n frequency_dict[element] += 1\n \n # Convert defaultdict to a regular dictionary before returning\n return dict(frequency_dict)", "matching_cluster_idx": 6}, {"solution": "from collections import defaultdict\nfrom typing import List\ndef frequency_lists(arr: List[List[int]]) -> dict:\n \"\"\"\n Finds the frequency of each element in a flattened list of lists and returns the result in a dictionary.\n \n Parameters:\n arr (List[List[int]]): The list of lists containing integers.\n \n Returns:\n dict: A dictionary with elements as keys and their frequencies as values.\n \"\"\"\n frequency_dict = defaultdict(int)\n for sublist in arr:\n for element in sublist:\n frequency_dict[element] += 1\n \n return dict(frequency_dict)", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(list_of_lists):\n from collections import defaultdict\n \n # Initialize a dictionary to hold the frequency of each element\n frequency_dict = defaultdict(int)\n \n # Flatten the list of lists and count the frequency of each element\n for sublist in list_of_lists:\n for element in sublist:\n frequency_dict[element] += 1\n \n return dict(frequency_dict)", "matching_cluster_idx": 6}, {"solution": "from collections import defaultdict\nfrom itertools import chain\ndef frequency_lists(nested_list):\n \"\"\"\n Find the frequency of each element in a flattened list of lists and return the result in a dictionary.\n \n :param nested_list: List of lists containing integers.\n :return: Dictionary with elements as keys and their frequency as values.\n \"\"\"\n # Flatten the list of lists and count the frequency of each element\n flattened_list = list(chain(*nested_list))\n frequency_dict = defaultdict(int)\n for item in flattened_list:\n frequency_dict[item] += 1\n \n # Convert defaultdict to dict for the expected output format\n return dict(frequency_dict)", "matching_cluster_idx": 6}, {"solution": "from collections import defaultdict\nfrom typing import List\ndef frequency_lists(lists: List[List[int]]) -> dict:\n \"\"\"\n Finds the frequency of each element in a flattened list of lists and returns the result in a dictionary.\n \n :param lists: List of lists containing integers.\n :return: Dictionary with elements as keys and their frequencies as values.\n \"\"\"\n frequency_dict = defaultdict(int)\n for sublist in lists:\n for item in sublist:\n frequency_dict[item] += 1\n \n return frequency_dict", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lists):\n from collections import defaultdict\n \n # Flatten the list of lists and count the frequency of each element\n frequency_dict = defaultdict(int)\n for sublist in lists:\n for item in sublist:\n frequency_dict[item] += 1\n \n # Convert defaultdict to a regular dict for the output\n return dict(frequency_dict)", "matching_cluster_idx": 6}, {"solution": "from collections import defaultdict\nfrom typing import List\ndef frequency_lists(arr: List[List[int]]) -> dict:\n \"\"\"\n Finds frequency of each element in a flattened list of lists, returned in a dictionary.\n \n Parameters:\n arr (List[List[int]]): A list of lists containing integers.\n \n Returns:\n dict: A dictionary containing the frequency of each element.\n \"\"\"\n # Flatten the list of lists and use defaultdict to count occurrences\n flattened_list = [item for sublist in arr for item in sublist]\n frequency_dict = defaultdict(int)\n \n for item in flattened_list:\n frequency_dict[item] += 1\n \n return dict(frequency_dict)", "matching_cluster_idx": 6}, {"solution": "from collections import defaultdict\nfrom typing import List\ndef frequency_lists(lst: List[List[int]]) -> dict:\n \"\"\"\n Finds frequency of each element in a flattened list of lists, returned in a dictionary.\n \n Parameters:\n lst (List[List[int]]): A list of lists of integers.\n \n Returns:\n dict: A dictionary mapping each element to its frequency.\n \"\"\"\n frequency_dict = defaultdict(int)\n for sublist in lst:\n for element in sublist:\n frequency_dict[element] += 1\n return dict(frequency_dict)", "matching_cluster_idx": 6}, {"solution": "from collections import defaultdict\nfrom typing import List\ndef frequency_lists(arr: List[List[int]]) -> dict:\n \"\"\"\n Finds the frequency of each element in a flattened list of lists, returned in a dictionary.\n \n Parameters:\n arr (List[List[int]]): A list of lists containing integer elements.\n \n Returns:\n dict: A dictionary where keys are the elements from the list and values are their frequencies.\n \"\"\"\n # Initialize a dictionary to keep track of element frequencies\n frequency_dict = defaultdict(int)\n \n # Iterate through each list in the input list of lists\n for sublist in arr:\n for element in sublist:\n # Increment the count of the element in the dictionary\n frequency_dict[element] += 1\n \n return dict(frequency_dict)", "matching_cluster_idx": 6}, {"solution": "from collections import defaultdict\nfrom itertools import chain\ndef frequency_lists(lists):\n # Flatten the list of lists into a single list\n flattened_list = list(chain(*lists))\n \n # Use defaultdict to count the frequency of each element\n frequency_dict = defaultdict(int)\n for item in flattened_list:\n frequency_dict[item] += 1\n \n # Convert defaultdict to a regular dictionary for the output\n return dict(frequency_dict)", "matching_cluster_idx": 6}, {"solution": "from collections import defaultdict\nfrom itertools import chain\ndef frequency_lists(lists):\n frequency_dict = defaultdict(int)\n # Flatten the list of lists and count the frequency of each element\n for item in chain.from_iterable(lists):\n frequency_dict[item] += 1\n return dict(frequency_dict)", "matching_cluster_idx": 6}, {"solution": "from collections import defaultdict\nfrom typing import List\ndef frequency_lists(nested_list: List[List[int]]) -> dict:\n \"\"\"\n Finds the frequency of each element in a flattened list of lists.\n \n Parameters:\n nested_list (List[List[int]]): A list of lists containing integers.\n \n Returns:\n dict: A dictionary where keys are elements from the nested list and values are their frequencies.\n \"\"\"\n # Initialize a dictionary to keep track of frequencies\n frequency_dict = defaultdict(int)\n \n # Flatten the list of lists and count each element\n for sublist in nested_list:\n for element in sublist:\n frequency_dict[element] += 1\n \n return dict(frequency_dict)", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(list_of_lists):\n from collections import Counter\n \n # Flatten the list of lists and count the frequency of each element\n flat_list = [item for sublist in list_of_lists for item in sublist]\n element_frequency = Counter(flat_list)\n \n return element_frequency", "matching_cluster_idx": 6}, {"solution": "from collections import defaultdict\nfrom typing import List\ndef frequency_lists(lists: List[List[int]]) -> dict:\n \"\"\"\n Finds the frequency of each element in a flattened list of lists.\n \n Args:\n lists: A list of lists containing integers.\n \n Returns:\n A dictionary mapping each integer to its frequency across the flattened list of lists.\n \"\"\"\n frequency_dict = defaultdict(int)\n for sublist in lists:\n for item in sublist:\n frequency_dict[item] += 1\n return dict(frequency_dict)", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lists):\n from collections import defaultdict\n \n # Initialize a dictionary to hold the frequency of each element\n frequency_dict = defaultdict(int)\n \n # Iterate through each sublist in the list of lists\n for sublist in lists:\n # Iterate through each element in the sublist\n for element in sublist:\n # Increment the count of the element in the dictionary\n frequency_dict[element] += 1\n \n return dict(frequency_dict)", "matching_cluster_idx": 6}, {"solution": "from collections import defaultdict\nfrom typing import List\ndef frequency_lists(lists: List[List[int]]) -> dict:\n \"\"\"\n Function to find frequency of each element in a flattened list of lists,\n returned in a dictionary.\n \n Args:\n lists: A list of lists containing integers.\n \n Returns:\n A dictionary with each element and its frequency in the flattened list of lists.\n \"\"\"\n # Initialize a dictionary to keep track of element counts\n counts = defaultdict(int)\n \n # Iterate over each sublist and then each item to count frequencies\n for sublist in lists:\n for item in sublist:\n counts[item] += 1\n \n # Convert defaultdict to a regular dictionary for the output\n return dict(counts)", "matching_cluster_idx": 6}]}, "Mbpp/106": {"dps": 27.62987012987013, "dps_norm": 71.66666666666667, "pass@1": 100.0, "profiled": [{"solution": "def add_lists(lst, tpl):\n \"\"\"\n Append elements of a list to a tuple.\n \n :param lst: List of elements to be appended\n :param tpl: Tuple to which elements are appended\n :return: New tuple with elements of list appended to the original tuple\n \"\"\"\n # Convert the tuple to a list, append the list, then convert back to tuple\n result = tuple(list(tpl) + lst)\n return result", "matching_cluster_idx": 3}, {"solution": "def add_lists(lst, tpl):\n \"\"\"\n Appends elements of a list to a tuple.\n \n Parameters:\n lst (list): The list whose elements are to be appended.\n tpl (tuple): The tuple to which elements are to be appended.\n \n Returns:\n tuple: A new tuple with elements of the original tuple followed by elements of the list.\n \"\"\"\n # Convert the tuple to a list, append the list 'lst' to it, then convert back to a tuple\n result = tuple(list(tpl) + lst)\n return result", "matching_cluster_idx": 2}, {"solution": "def add_lists(lst, tpl):\n \"\"\"\n Appends the elements of a list to a tuple.\n\n Parameters:\n lst (list): The list whose elements are to be appended.\n tpl (tuple): The tuple to which the list elements will be added.\n\n Returns:\n tuple: A new tuple with elements of the original tuple followed by elements of the list.\n \"\"\"\n # Convert the tuple to a list to facilitate concatenation\n converted_tpl = list(tpl)\n # Extend the converted tuple list with the elements of the list\n converted_tpl.extend(lst)\n # Convert back to tuple and return\n return tuple(converted_tpl)", "matching_cluster_idx": 4}, {"solution": "def add_lists(lst, tpl):\n \"\"\"\n Append the elements of the given list to the end of the given tuple.\n \n Args:\n lst : list of elements to be appended\n tpl : tuple to which elements are to be appended\n \n Returns:\n tuple : new tuple with elements of the original tuple followed by elements of the list\n \"\"\"\n # Convert the tuple to a list to facilitate appending\n temp_list = list(tpl)\n \n # Append the elements of the list to the temporary list\n temp_list.extend(lst)\n \n # Convert back to tuple and return\n return tuple(temp_list)", "matching_cluster_idx": 4}, {"solution": "def add_lists(lst, tpl):\n \"\"\"\n Append elements of a list to the given tuple.\n\n Parameters:\n - lst: A list of elements to be appended.\n - tpl: The original tuple to which elements will be appended.\n\n Returns:\n - A new tuple consisting of elements from the original tuple followed by all elements in the list.\n \"\"\"\n # Convert the tuple to a list to easily append list elements\n new_tpl = list(tpl)\n \n # Append list elements to the new list\n new_tpl.extend(lst)\n \n # Convert back to tuple and return\n return tuple(new_tpl)", "matching_cluster_idx": 4}, {"solution": "def add_lists(lst, tpl):\n \"\"\"\n Append elements from the given list to the given tuple and return a new tuple.\n \n :param lst: List of elements to be appended\n :param tpl: Tuple to which elements are appended\n :return: New tuple with elements of the list appended at the end\n \"\"\"\n # Convert the tuple to a list, append list to it and convert back to tuple\n return tuple(list(tpl) + lst)", "matching_cluster_idx": 3}, {"solution": "def add_lists(lst, tpl):\n # Convert the tuple to a list to easily append the list elements\n temp_list = list(tpl)\n # Extend the list with elements from the given list\n temp_list.extend(lst)\n # Convert back to a tuple and return\n return tuple(temp_list)", "matching_cluster_idx": 4}, {"solution": "def add_lists(lst, tpl):\n \"\"\"\n Appends elements of a list to a tuple and returns a new tuple.\n \n :param lst: List whose elements are to be appended.\n :param tpl: Tuple to which elements from the list are to be appended.\n :return: New tuple with elements of the tuple followed by elements of the list.\n \"\"\"\n # Convert the tuple to a list, append the list, then convert back to a tuple\n combined = list(tpl) + lst\n return tuple(combined)", "matching_cluster_idx": 2}, {"solution": "def add_lists(lst, tpl):\n \"\"\"\n Append the given list to the given tuple.\n \n Parameters:\n lst (list): The list to append to the tuple.\n tpl (tuple): The original tuple to which the list will be appended.\n \n Returns:\n tuple: The new tuple with the original elements followed by the elements from the list.\n \"\"\"\n # Convert the list to a tuple\n lst_to_tuple = tuple(lst)\n \n # Append lst_to_tuple to tpl and return the result\n return tpl + lst_to_tuple", "matching_cluster_idx": 4}, {"solution": "def add_lists(lst, tpl):\n # Combine the tuple with the list and return a new tuple\n return tpl + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tpl):\n \"\"\"\n Append the given list to the given tuple and return the result as a new tuple.\n \n :param lst: List to be appended\n :param tpl: Original tuple\n :return: A new tuple with the list appended to the original tuple\n \"\"\"\n # Convert the list to a tuple to allow concatenation with another tuple\n lst_as_tuple = tuple(lst)\n # Concatenate the original tuple with the converted list tuple\n result = tpl + lst_as_tuple\n return result", "matching_cluster_idx": 4}, {"solution": "def add_lists(lst, tpl):\n \"\"\"\n Append the given list to the given tuple and return a new tuple.\n \n Parameters:\n lst (list): The list to be appended.\n tpl (tuple): The tuple to which the list is appended.\n \n Returns:\n tuple: A new tuple containing elements of the original tuple followed by elements of the list.\n \"\"\"\n # Convert the tuple to a list, append the list, and convert back to a tuple\n return tuple(list(tpl) + lst)", "matching_cluster_idx": 3}, {"solution": "def add_lists(list_to_append, tuple_to_add):\n \"\"\"\n Appends elements of a list to a tuple and returns the result as a tuple.\n \n :param list_to_append: List containing elements to be appended to the tuple.\n :param tuple_to_add: Tuple to which the list's elements will be appended.\n :return: A new tuple with elements of the tuple_to_add followed by elements of the list_to_append.\n \"\"\"\n # Convert the tuple to a list to facilitate concatenation\n tuple_as_list = list(tuple_to_add)\n \n # Append the list to the list created from tuple\n tuple_as_list.extend(list_to_append)\n \n # Convert the combined list back to a tuple\n result_tuple = tuple(tuple_as_list)\n \n return result_tuple", "matching_cluster_idx": 4}, {"solution": "def add_lists(lst, tpl):\n # Convert the tuple to a list for easier manipulation\n tpl_list = list(tpl)\n # Extend the list with the elements from the tuple\n tpl_list.extend(lst)\n # Convert back to tuple and return\n return tuple(tpl_list)", "matching_cluster_idx": 4}, {"solution": "def add_lists(lst, tpl):\n \"\"\"\n Append elements of a list to a tuple and return a new tuple.\n \n Parameters:\n lst (list): The list whose elements are to be appended.\n tpl (tuple): The tuple to which the list elements are to be added.\n \n Returns:\n tuple: A new tuple with elements of the original tuple followed by elements of the list.\n \"\"\"\n # Convert tuple to list, append list, then convert back to tuple\n combined = list(tpl) + lst\n return tuple(combined)", "matching_cluster_idx": 2}, {"solution": "def add_lists(lst, tpl):\n \"\"\"\n Append the elements of a list to a tuple and return the new tuple.\n \n :param lst: List to be appended\n :param tpl: Original tuple\n :return: New tuple with the list elements appended\n \"\"\"\n # Convert the tuple to a list, extend it with the given list, and convert back to a tuple\n result = list(tpl)\n result.extend(lst)\n return tuple(result)", "matching_cluster_idx": 4}, {"solution": "def add_lists(lst, tpl):\n \"\"\"\n Append elements of a list to a tuple.\n\n Parameters:\n - lst: The list whose elements are to be appended.\n - tpl: The original tuple to which elements will be added.\n\n Returns:\n - A new tuple containing elements of the original tuple followed by elements of the list.\n \"\"\"\n # Convert the tuple to a list, extend it with the given list, then convert back to a tuple\n result = tuple(list(tpl) + lst)\n return result", "matching_cluster_idx": 2}, {"solution": "def add_lists(lst, tup):\n \"\"\"\n Append the elements of a list to the elements of a tuple.\n \n :param lst: List of elements to append\n :param tup: Tuple to which the list elements are appended\n :return: New tuple with elements of the original tuple followed by elements of the list\n \"\"\"\n # Convert tuple to list, append the list, then convert back to tuple\n combined_list = list(tup) + lst\n return tuple(combined_list)", "matching_cluster_idx": 2}, {"solution": "def add_lists(lst, tup):\n \"\"\"\n Append the given list to the given tuple and return the result as a tuple.\n \n Args:\n lst : list\n The list to be appended to the tuple.\n tup : tuple\n The original tuple to which the list will be appended.\n \n Returns:\n tuple\n A new tuple with elements of the original tuple followed by elements of the list.\n \"\"\"\n # Convert the tuple and list into a single list, then convert it into a tuple\n result = tuple(list(tup) + lst)\n return result", "matching_cluster_idx": 2}, {"solution": "def add_lists(lst, tpl):\n \"\"\"\n Appends the elements of a given list to the elements of a given tuple.\n \n :param lst: List containing elements to append\n :param tpl: Tuple to which the elements from list are to be appended\n :return: A new tuple with the elements from the original tuple followed by the elements from the list\n \"\"\"\n # Convert the tuple to a list to easily append the other list\n temp_list = list(tpl)\n \n # Append the list elements to the temporary list\n temp_list.extend(lst)\n \n # Convert the temporary list back to a tuple to maintain the original type\n result_tuple = tuple(temp_list)\n \n return result_tuple", "matching_cluster_idx": 4}]}, "Mbpp/108": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 99.0, "profiled": [{"solution": "def merge_sorted_list(list1, list2, list3):\n # Concatenate all three lists\n merged_list = list1 + list2 + list3\n # Sort the concatenated list\n merged_list.sort()\n return merged_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Combine all three lists\n combined_list = list1 + list2 + list3\n # Sort the combined list\n combined_list.sort()\n return combined_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Combine all three lists into one\n combined_list = list1 + list2 + list3\n # Sort the combined list\n combined_list.sort()\n # Return the sorted list\n return combined_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Combine all lists into one\n combined_list = list1 + list2 + list3\n # Sort the combined list\n sorted_list = sorted(combined_list)\n return sorted_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Combine all three lists into one\n combined_list = list1 + list2 + list3\n # Sort the combined list\n combined_list.sort()\n return combined_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(lst1, lst2, lst3):\n # Combine the three lists\n combined_list = lst1 + lst2 + lst3\n # Sort the combined list\n sorted_list = sorted(combined_list)\n return sorted_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Combine all lists into one\n combined_list = list1 + list2 + list3\n # Sort the combined list\n sorted_list = sorted(combined_list)\n return sorted_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Concatenate all three lists\n merged_list = list1 + list2 + list3\n # Sort the merged list\n merged_list.sort()\n return merged_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n \"\"\"\n Merge three sorted lists into one sorted list.\n \"\"\"\n # Combine all lists into one list\n combined_list = list1 + list2 + list3\n # Sort the combined list\n combined_list.sort()\n return combined_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Combine all lists into one\n combined_list = list1 + list2 + list3\n # Sort the combined list\n sorted_list = sorted(combined_list)\n return sorted_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Combine all lists and sort the combined list\n combined_list = list1 + list2 + list3\n combined_list.sort()\n return combined_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Combine all lists into one and sort it\n combined_list = sorted(list1 + list2 + list3)\n return combined_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Combine all three lists into one\n combined_list = list1 + list2 + list3\n # Sort the combined list\n combined_list.sort()\n return combined_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Concatenate all three lists\n merged_list = list1 + list2 + list3\n # Sort the concatenated list\n merged_list.sort()\n return merged_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Combine all lists into one\n combined_list = list1 + list2 + list3\n # Sort the combined list\n sorted_list = sorted(combined_list)\n return sorted_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Combine all lists into one and sort it\n combined_list = sorted(list1 + list2 + list3)\n return combined_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(lst1, lst2, lst3):\n # Merge the three lists\n merged_list = lst1 + lst2 + lst3\n # Sort the merged list\n sorted_list = sorted(merged_list)\n return sorted_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Merge the three lists into one\n merged_list = list1 + list2 + list3\n # Sort the merged list\n merged_list.sort()\n return merged_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Combine all lists into one\n combined_list = list1 + list2 + list3\n # Sort the combined list\n sorted_list = sorted(combined_list)\n return sorted_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Combine all three lists into one\n combined_list = list1 + list2 + list3\n # Sort the combined list\n combined_list.sort()\n return combined_list", "matching_cluster_idx": 10}]}, "Mbpp/111": {"dps": 87.64615384615385, "dps_norm": 86.25, "pass@1": 100.0, "profiled": [{"solution": "def common_in_nested_lists(lists):\n \"\"\"\n Finds the common elements across all nested lists.\n \n Args:\n lists: A list of lists containing integers.\n \n Returns:\n A set containing common integers across all provided lists.\n \"\"\"\n # Start with the first list's elements as potential common elements\n common_elements = set(lists[0])\n \n # Iterate through the rest of the lists\n for lst in lists[1:]:\n # Update common_elements with the intersection of the current set of common elements and the current list\n common_elements.intersection_update(lst)\n \n return common_elements", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(lists):\n \"\"\"\n Find the common elements in the given nested lists.\n \n :param lists: List of lists containing integers.\n :return: A set of integers that are common in all given nested lists.\n \"\"\"\n # Convert the first list to a set to start the intersection process\n common_elements = set(lists[0])\n \n # Iterate through the rest of the lists and keep updating the set of common elements\n for lst in lists[1:]:\n common_elements &= set(lst)\n \n # If common elements set becomes empty, break the loop as no further intersection is possible\n if not common_elements:\n break\n \n return common_elements", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(lists):\n \"\"\"\n Finds the common elements in given nested lists.\n \n Args:\n lists : List[List[int]]\n A list containing multiple lists of integers.\n \n Returns:\n List[int]\n A list containing the common elements found in all the lists.\n \"\"\"\n if not lists:\n return []\n \n # Start with the set of elements from the first list\n common_elements = set(lists[0])\n \n # Iterate through the rest of the lists and keep only the common elements\n for lst in lists[1:]:\n common_elements.intersection_update(lst)\n \n return list(common_elements)", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(lists):\n \"\"\"\n Find common elements in given nested lists.\n \n Parameters:\n lists (List[List[int]]): A list containing multiple nested integer lists.\n \n Returns:\n List[int]: A list of integers representing the common elements in the nested lists.\n \"\"\"\n # Convert the first sublist to a set for initial comparison\n common_elements = set(lists[0])\n \n # Iterate through each sublist starting from the second one\n for sublist in lists[1:]:\n # Update the common_elements set by finding intersection with current sublist\n common_elements.intersection_update(sublist)\n \n # Return the sorted list of common elements\n return sorted(common_elements)", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(lists):\n \"\"\"\n Finds the common elements in given nested lists.\n \n Parameters:\n lists (list of lists): A list containing multiple nested lists.\n \n Returns:\n list: A list of common elements found in all nested lists.\n \"\"\"\n # Initialize a set with all elements from the first list\n common_elements = set(lists[0])\n \n # Iterate through the rest of the lists and update the common_elements set\n for lst in lists[1:]:\n common_elements &= set(lst) # Intersection with each list\n \n return list(common_elements)", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n \"\"\"\n Finds the common elements in the given nested lists.\n \n Parameters:\n - nested_lists (List[List]): A list containing multiple nested lists.\n \n Returns:\n List: A list of common elements found in all nested lists.\n \"\"\"\n # Convert the first sublist to a set for initialization\n common_elements = set(nested_lists[0])\n \n # Iterate through the rest of the sublists\n for sublist in nested_lists[1:]:\n # Convert each sublist to a set and retain only common elements\n common_elements.intersection_update(set(sublist))\n \n # Return the result as a sorted list\n return sorted(common_elements)", "matching_cluster_idx": 5}, {"solution": "def common_in_nested_lists(lists):\n \"\"\"\n Finds the common elements in given nested lists.\n \n Args:\n lists (list of list of int): A list containing multiple lists of integers.\n \n Returns:\n list: A list of integers that are common in all of the provided lists.\n \"\"\"\n if not lists:\n return []\n \n # Convert the first list to a set to start finding common elements\n common_elements = set(lists[0])\n \n # Intersect with each of the other lists\n for lst in lists[1:]:\n common_elements.intersection_update(lst)\n \n # Convert back to list to match expected return type\n return list(common_elements)", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(lists):\n \"\"\"\n Finds common elements in given nested lists.\n \n Args:\n lists (list of list of int): A list containing multiple nested lists of integers.\n \n Returns:\n list: A list of integers that are common across all nested lists.\n \"\"\"\n if not lists:\n return []\n \n # Convert the first list to a set for comparison\n common_elements = set(lists[0])\n \n # Iterate over the rest of the lists\n for lst in lists[1:]:\n # Intersection operation to find common elements\n common_elements.intersection_update(lst)\n \n # Convert back to list before returning\n return list(common_elements)", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(lists):\n \"\"\"\n Finds common elements in the given nested list.\n \n Args:\n lists : list of lists of integers\n \n Returns:\n set of integers that are common in all the sublists\n \"\"\"\n # Start with the first sublist's set of elements\n common_elements = set(lists[0])\n \n # Intersect with each subsequent sublist's set of elements\n for sublist in lists[1:]:\n common_elements.intersection_update(sublist)\n \n return common_elements", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(lists):\n # Use set intersection to find common elements across all sublists\n common_elements = set.intersection(*map(set, lists))\n return list(common_elements)", "matching_cluster_idx": 5}, {"solution": "def common_in_nested_lists(lists):\n \"\"\"\n Finds the common elements in given nested lists.\n \n Parameters:\n - lists: A list of lists containing integer elements.\n \n Returns:\n A set containing the common elements found in all the sublists.\n \"\"\"\n # If the input list is empty, return an empty set\n if not lists:\n return set()\n \n # Initialize common_elements with the first sublist's set of elements\n common_elements = set(lists[0])\n \n # Iterate through the remaining sublists to find common elements\n for sublist in lists[1:]:\n common_elements.intersection_update(sublist)\n \n return common_elements", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(lists):\n \"\"\"\n Finds the common elements in given nested lists.\n \n Args:\n lists : List of lists containing integers.\n \n Returns:\n Set of common integers found in all provided lists.\n \"\"\"\n # Start with the first list for comparison\n common_elements = set(lists[0])\n \n # Iterate through the rest of the lists\n for lst in lists[1:]:\n # Update the set of common elements with the intersection operation\n common_elements.intersection_update(lst)\n \n return common_elements", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n \"\"\"\n Finds the common elements in given nested lists.\n \n Parameters:\n nested_lists (list of list of int): The input nested list containing integer elements.\n \n Returns:\n set: A set containing the common elements found in all nested lists.\n \"\"\"\n # Convert the first list to a set to initialize the common elements\n common_elements = set(nested_lists[0])\n \n # Iterate through the rest of the lists\n for lst in nested_lists[1:]:\n # Keep only the elements that are also in the current list\n common_elements.intersection_update(lst)\n \n return common_elements", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n \"\"\"\n Finds common elements in given nested lists.\n \n Parameters:\n nested_lists (list of lists): A list containing multiple nested lists.\n \n Returns:\n list: A list of common elements found in all nested lists.\n \"\"\"\n # Convert the first list to a set for the initial comparison\n common_elements = set(nested_lists[0])\n \n # Iterate through the rest of the lists\n for lst in nested_lists[1:]:\n # Take the intersection of the current set of common elements with the set of the current list\n common_elements.intersection_update(lst)\n \n return list(common_elements)", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n \"\"\"\n Find the common elements in the given nested lists.\n \n Parameters:\n nested_lists (list of lists): A list containing multiple nested lists.\n \n Returns:\n list: A list of common elements found in all nested lists.\n \"\"\"\n # Convert the first list to a set for initial intersection\n common_elements = set(nested_lists[0])\n \n # Iterate through the remaining lists and find common elements\n for lst in nested_lists[1:]:\n common_elements.intersection_update(lst)\n \n return list(common_elements)", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(lists):\n \"\"\"\n Finds the common elements in given nested lists.\n \n Parameters:\n lists (list of list of int): A list containing multiple lists of integers.\n \n Returns:\n set: A set containing the common elements found in all lists.\n \"\"\"\n # Start with the set of all elements in the first list\n common_elements = set(lists[0])\n \n # Iterate through the rest of the lists\n for lst in lists[1:]:\n # Keep only elements that are also found in the current list\n common_elements.intersection_update(lst)\n \n return common_elements", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(lists):\n # Convert the first list to a set for initial common elements\n common_elements = set(lists[0])\n \n # Iterate over the remaining lists\n for lst in lists[1:]:\n # Update common_elements with the intersection of the current set and the current list\n common_elements.intersection_update(set(lst))\n \n # Return the sorted list of common elements to maintain consistent order\n return sorted(common_elements)", "matching_cluster_idx": 5}, {"solution": "def common_in_nested_lists(lists):\n \"\"\"\n Finds common elements in given nested lists.\n \n Args:\n lists: A list of lists, each containing integers.\n \n Returns:\n A list of integers that are common in all the given lists.\n \"\"\"\n # Start with the first list as the initial intersection\n common_elements = set(lists[0])\n \n # Iterate over the rest of the lists and find the intersection\n for lst in lists[1:]:\n common_elements.intersection_update(lst)\n \n return list(common_elements)", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(lists):\n \"\"\"\n Finds the common elements in given nested lists.\n \n Parameters:\n lists (list of list of int): A list containing multiple nested integer lists.\n \n Returns:\n set: A set containing the common integers found in all nested lists.\n \"\"\"\n # Starting with the set of all elements from the first list\n common_elements = set(lists[0])\n \n # Iteratively updating common_elements to keep only the common elements\n for lst in lists[1:]:\n common_elements &= set(lst)\n \n return common_elements", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(lists):\n \"\"\"\n Finds the common elements in given nested lists.\n \n Parameters:\n lists (list of lists): A nested list of integers.\n \n Returns:\n set: A set containing common elements found in all nested lists.\n \"\"\"\n # Start with the entire universe of the first list\n common_elements = set(lists[0])\n \n # Narrow down the universe by checking against all other lists\n for lst in lists[1:]:\n # Keep only elements that exist in the current list\n common_elements.intersection_update(lst)\n \n # If at any point, the set is empty, there are no common elements\n if not common_elements:\n break\n \n return common_elements", "matching_cluster_idx": 7}]}, "Mbpp/123": {"dps": 99.62686567164178, "dps_norm": 85.71428571428571, "pass@1": 46.0, "profiled": [{"solution": "def sum_of_proper_divisors(n):\n \"\"\"Return the sum of proper divisors of n.\"\"\"\n divisors = [1] # 1 is a proper divisor of any n > 1\n for i in range(2, int(n ** 0.5) + 1):\n if n % i == 0:\n divisors.append(i)\n if i != n // i:\n divisors.append(n // i)\n return sum(divisors)\ndef are_amicable(a, b):\n \"\"\"Check if a and b are amicable.\"\"\"\n return sum_of_proper_divisors(a) == b and sum_of_proper_divisors(b) == a and a != b\ndef amicable_numbers_sum(limit):\n \"\"\"Return the sum of all amicable numbers from 1 to the specified limit.\"\"\"\n amicable_set = set()\n for num in range(2, limit + 1):\n partner = sum_of_proper_divisors(num)\n if are_amicable(num, partner):\n amicable_set.update([num, partner])\n return sum(amicable_set)", "matching_cluster_idx": 11}, {"solution": "def amicable_numbers_sum(n):\n def sum_of_proper_divisors(x):\n total = 1 # 1 is a proper divisor of all natural numbers\n sqrt_x = int(x ** 0.5)\n \n for i in range(2, sqrt_x + 1):\n if x % i == 0:\n total += i\n if i != x // i:\n total += x // i\n return total\n \n amicable_sum = 0\n amicable_set = set()\n \n for num in range(2, n + 1):\n if num not in amicable_set:\n partner = sum_of_proper_divisors(num)\n if num == sum_of_proper_divisors(partner) and num != partner:\n amicable_sum += num + partner\n amicable_set.update([num, partner])\n \n return amicable_sum", "matching_cluster_idx": 11}, {"solution": "def sum_of_divisors(n):\n # Calculate the sum of divisors of n, excluding n itself\n sum_div = 1\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n sum_div += i\n if i != n // i:\n sum_div += n // i\n return sum_div\ndef amicable_numbers_sum(max_num):\n # Sum all amicable numbers from 1 to max_num\n amicable_sum = 0\n for num in range(2, max_num + 1):\n partner = sum_of_divisors(num)\n if partner > num and sum_of_divisors(partner) == num:\n amicable_sum += num + partner\n return amicable_sum", "matching_cluster_idx": 11}, {"solution": "def amicable_numbers_sum(n):\n def sum_of_divisors(x):\n divisors_sum = 1 # 1 is a proper divisor of all numbers\n # Only iterate up to sqrt(x) to reduce computation\n for i in range(2, int(x**0.5) + 1):\n if x % i == 0:\n divisors_sum += i\n if i != x // i: # Avoid adding the square root twice for perfect squares\n divisors_sum += x // i\n return divisors_sum\n \n amicable_numbers = set()\n \n for num in range(2, n + 1):\n partner = sum_of_divisors(num)\n if partner > num and partner <= n and sum_of_divisors(partner) == num:\n amicable_numbers.update([num, partner])\n \n return sum(amicable_numbers)", "matching_cluster_idx": 11}, {"solution": "def sum_of_proper_divisors(n):\n divisors_sum = 1 # Start with 1 since it's a proper divisor for all n > 1\n sqrt_n = int(n ** 0.5)\n for i in range(2, sqrt_n + 1):\n if n % i == 0:\n divisors_sum += i\n if i != n // i:\n divisors_sum += n // i\n return divisors_sum\ndef amicable_numbers_sum(limit):\n # List to mark if a number is part of an amicable pair\n is_amicable = [False] * (limit + 1)\n for i in range(2, limit + 1):\n if not is_amicable[i]:\n sum_div_i = sum_of_proper_divisors(i)\n sum_div_j = sum_of_proper_divisors(sum_div_i)\n # Check if i and sum_div_i form an amicable pair\n if i == sum_div_j and i != sum_div_i:\n is_amicable[i] = True\n is_amicable[sum_div_i] = True\n \n # Calculate the sum of all amicable numbers within the limit\n amicable_sum = sum(i for i in range(2, limit + 1) if is_amicable[i])\n return amicable_sum", "matching_cluster_idx": 11}, {"solution": "def sum_of_proper_divisors(n):\n \"\"\"Return the sum of proper divisors of n.\"\"\"\n divisors_sum = 1 # Start with 1 because it's a proper divisor of all natural numbers\n for i in range(2, int(n ** 0.5) + 1):\n if n % i == 0:\n divisors_sum += i\n if i != n // i: # Add the complementary divisor if it's not the square root\n divisors_sum += n // i\n return divisors_sum\ndef amicable_numbers_sum(upper_limit):\n \"\"\"Sum all amicable numbers from 1 to upper_limit.\"\"\"\n amicable_pairs = []\n for num in range(2, upper_limit + 1):\n partner = sum_of_proper_divisors(num)\n if partner > num and sum_of_proper_divisors(partner) == num:\n amicable_pairs.extend([num, partner])\n return sum(set(amicable_pairs)) # Use set to avoid counting duplicates", "matching_cluster_idx": 11}, {"solution": "def amicable_numbers_sum(n):\n \"\"\"\n Finds the sum of all amicable numbers from 1 to n.\n \n An amicable pair (a, b) consists of two integers where the sum of proper divisors of a equals b\n and the sum of proper divisors of b equals a, with a != b.\n \n :param n: The upper limit (inclusive) to search for amicable numbers.\n :return: The sum of all amicable numbers within the range [1, n].\n \"\"\"\n def sum_of_proper_divisors(x):\n divisors_sum = 1 # Start with 1 since it's a proper divisor of all natural numbers > 1\n for i in range(2, int(x ** 0.5) + 1):\n if x % i == 0:\n divisors_sum += i\n if x // i != i: # Avoid adding the square root twice for perfect squares\n divisors_sum += x // i\n return divisors_sum\n\n amicable_set = set()\n for number in range(2, n + 1):\n pair = sum_of_proper_divisors(number)\n if sum_of_proper_divisors(pair) == number and number != pair and number <= n:\n amicable_set.add(number)\n amicable_set.add(pair)\n \n return sum(amicable_set)", "matching_cluster_idx": 11}, {"solution": "def amicable_numbers_sum(n):\n def sum_proper_divisors(x):\n # Sum of proper divisors of x\n divisors_sum = 1 # 1 is a proper divisor of all natural numbers\n # Loop to find and sum other proper divisors\n for i in range(2, int(x ** 0.5) + 1):\n if x % i == 0:\n divisors_sum += i\n if i != x // i:\n divisors_sum += x // i\n return divisors_sum\n \n # List to store amicable numbers\n amicable = set()\n \n # Finding amicable pairs below n\n for i in range(2, n):\n partner = sum_proper_divisors(i)\n if i != partner and i == sum_proper_divisors(partner) and partner < n:\n amicable.update([i, partner])\n \n # Returning the sum of amicable numbers\n return sum(amicable)", "matching_cluster_idx": 11}, {"solution": "def amicable_numbers_sum(n):\n def sum_of_proper_divisors(num):\n divisors_sum = 1\n # Only iterate up to the square root of num to find divisors\n for i in range(2, int(num ** 0.5) + 1):\n if num % i == 0:\n divisors_sum += i\n if i != num // i:\n divisors_sum += num // i\n return divisors_sum\n \n amicable_pairs = []\n for a in range(2, n + 1):\n b = sum_of_proper_divisors(a)\n if b > a and sum_of_proper_divisors(b) == a:\n amicable_pairs.append((a, b))\n \n # Ensure that each number is included only once in the sum\n unique_amicables = set(num for pair in amicable_pairs for num in pair)\n return sum(unique_amicables)", "matching_cluster_idx": 11}, {"solution": "def sum_of_proper_divisors(n):\n divisors_sum = 1 # Start with 1 because it's always a proper divisor\n # Only need to check up to sqrt(n) because divisors come in pairs\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n divisors_sum += i\n if i != n // i: # Avoid adding the square root twice for perfect squares\n divisors_sum += n // i\n return divisors_sum\ndef amicable_numbers_sum(limit):\n # Array to store sum of divisors\n sum_div = [0] * (limit + 1)\n for i in range(1, limit + 1):\n sum_div[i] = sum_of_proper_divisors(i)\n # Calculate the sum of all amicable numbers up to limit\n total_sum = 0\n for i in range(2, limit + 1):\n ami_pair = sum_div[i]\n # Check if it's a valid amicable pair\n if ami_pair <= 1 or ami_pair > limit or sum_div[ami_pair] != i or ami_pair == i:\n continue\n total_sum += i\n return total_sum", "matching_cluster_idx": 11}, {"solution": "def sum_of_divisors(n):\n # Calculate the sum of all divisors of n\n sum_div = 1\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n if i == n // i:\n sum_div += i\n else:\n sum_div += i + n // i\n return sum_div\ndef amicable_numbers_sum(n):\n # Store the sum of divisors of each number up to n\n sum_divisors = [0] * (n + 1)\n for i in range(1, n + 1):\n sum_divisors[i] = sum_of_divisors(i)\n \n # Calculate the sum of all amicable numbers up to n\n result = 0\n for i in range(1, n + 1):\n if sum_divisors[i] <= n and sum_divisors[i] != i and sum_of_divisors(sum_divisors[i]) == i:\n result += i\n return result", "matching_cluster_idx": 11}, {"solution": "def sum_of_proper_divisors(n):\n \"\"\"\n Returns the sum of all proper divisors of a given number n.\n \"\"\"\n divisors_sum = 1 # Start with 1 because it's a proper divisor of all numbers\n for i in range(2, int(n ** 0.5) + 1):\n if n % i == 0:\n divisors_sum += i\n if i != n // i:\n divisors_sum += n // i\n return divisors_sum\ndef amicable_numbers_sum(max_num):\n \"\"\"\n Returns the sum of all amicable numbers from 1 to a specified number.\n \"\"\"\n # Create a dictionary to store the sum of proper divisors for each number\n sum_of_divisors = {}\n for i in range(1, max_num + 1):\n sum_of_divisors[i] = sum_of_proper_divisors(i)\n \n amicable_sum = 0\n for i in range(2, max_num + 1):\n # Check if the number is amicable\n if sum_of_divisors[i] <= max_num and sum_of_divisors[i] != i and sum_of_divisors[sum_of_divisors[i]] == i:\n amicable_sum += i\n return amicable_sum", "matching_cluster_idx": 11}, {"solution": "def amicable_numbers_sum(n):\n \"\"\"\n Calculates the sum of all amicable numbers from 1 to n.\n \n :param n: The upper limit of the range to check for amicable numbers (inclusive).\n :return: The sum of all amicable numbers within the specified range.\n \"\"\"\n def divisor_sum(x):\n \"\"\"\n Helper function to calculate the sum of proper divisors of a given number.\n \n :param x: The number to find the proper divisors of.\n :return: The sum of proper divisors of x.\n \"\"\"\n divs = 1 # Start with 1 since it is a proper divisor of all numbers\n sqrt_x = int(x**0.5) # Square root of x for loop limit\n for i in range(2, sqrt_x + 1):\n if x % i == 0:\n divs += i\n if i != x // i: # Add the complementary divisor if it's not a perfect square\n divs += x // i\n return divs\n \n amicable = set()\n for i in range(2, n + 1):\n ai = divisor_sum(i)\n if divisor_sum(ai) == i and i != ai:\n amicable.add(i)\n amicable.add(ai)\n \n return sum(amicable)", "matching_cluster_idx": 11}, {"solution": "def amicable_numbers_sum(n):\n \"\"\"\n Returns the sum of all amicable numbers from 1 to n.\n \"\"\"\n def sum_of_proper_divisors(x):\n # Return the sum of proper divisors of x\n total = 1 # 1 is a proper divisor of all natural numbers\n for i in range(2, int(x**0.5) + 1):\n if x % i == 0:\n total += i\n if i != x // i:\n total += x // i\n return total\n \n amicable_pairs = set()\n for num in range(2, n + 1):\n partner = sum_of_proper_divisors(num)\n if sum_of_proper_divisors(partner) == num and num != partner and num <= n:\n amicable_pairs.add(num)\n amicable_pairs.add(partner)\n \n return sum(amicable_pairs)", "matching_cluster_idx": 11}, {"solution": "def d(n):\n # Calculate the sum of proper divisors of n\n sum = 1\n i = 2\n while i * i <= n:\n if n % i:\n i += 1\n else:\n if i * (n // i) == n:\n sum = sum + i + (n//i)\n i += 1\n return sum\ndef amicable_numbers_sum(number):\n # Initialize an array to keep track of the sum of proper divisors for each number\n sum_proper_divisors = [0] * (number + 1)\n for i in range(1, number + 1):\n sum_proper_divisors[i] = d(i)\n \n # Find and sum all amicable numbers up to the specified number\n total_sum = 0\n for i in range(2, number + 1):\n if sum_proper_divisors[i] <= number and sum_proper_divisors[i] != i and sum_proper_divisors[sum_proper_divisors[i]] == i:\n total_sum += i\n return total_sum", "matching_cluster_idx": 11}, {"solution": "def amicable_numbers_sum(limit):\n \"\"\"\n Sum all amicable numbers from 1 to the specified limit.\n \n >>> amicable_numbers_sum(999)\n 504\n \"\"\"\n def sum_of_divisors(n):\n # Sum proper divisors of n (excluding the number itself)\n sum_div = 1 # 1 is a proper divisor of all numbers > 1\n square_root = int(n**0.5)\n \n for i in range(2, square_root + 1):\n if n % i == 0:\n sum_div += i\n if i != n // i:\n sum_div += n // i\n return sum_div\n \n amicable_sum = 0\n amicable_set = set()\n \n for num in range(2, limit + 1):\n partner = sum_of_divisors(num)\n if partner > num and partner <= limit:\n if sum_of_divisors(partner) == num:\n amicable_sum += num + partner\n amicable_set.add(num)\n amicable_set.add(partner)\n \n return amicable_sum", "matching_cluster_idx": 11}, {"solution": "def sum_of_proper_divisors(n):\n # Return the sum of proper divisors of n (excluding n itself)\n divisors_sum = 1 # Start with 1 because it is a proper divisor of all n > 1\n sqrt_n = int(n**0.5)\n for i in range(2, sqrt_n + 1):\n if n % i == 0:\n divisors_sum += i\n if i != n // i:\n divisors_sum += n // i\n return divisors_sum\ndef amicable_numbers_sum(upper_limit):\n # Create a list to store amicable pairs\n amicable_pairs = []\n for number in range(2, upper_limit):\n partner = sum_of_proper_divisors(number)\n if sum_of_proper_divisors(partner) == number and number != partner:\n # Check if both numbers are within range and are not already added\n if number < upper_limit and partner < upper_limit and (partner, number) not in amicable_pairs:\n amicable_pairs.append((number, partner))\n # Calculate the sum of all unique amicable numbers\n return sum(number for pair in amicable_pairs for number in pair)", "matching_cluster_idx": 11}, {"solution": "def amicable_numbers_sum(limit):\n \"\"\"\n Function to sum all amicable numbers from 1 to a specified number.\n \n >>> amicable_numbers_sum(999)\n 504\n \"\"\"\n def sum_of_divisors(n):\n total = 1 # Start with 1 because it's always a divisor\n sqrt_n = int(n**0.5)\n for i in range(2, sqrt_n + 1):\n if n % i == 0:\n total += i\n if i != n // i:\n total += n // i\n return total\n \n # Track the sum of amicable numbers\n amicable_sum = 0\n # Dictionary to hold sum of divisors for each number\n divisors_sum = {}\n \n for num in range(2, limit + 1):\n if num not in divisors_sum:\n divisors_sum[num] = sum_of_divisors(num)\n \n if divisors_sum[num] <= limit and divisors_sum[num] != num:\n pair = divisors_sum[num]\n if sum_of_divisors(pair) == num and pair not in divisors_sum:\n # Add both numbers if they form an amicable pair\n amicable_sum += num + pair\n divisors_sum[pair] = num # Mark this number to avoid recount\n \n return amicable_sum", "matching_cluster_idx": 11}, {"solution": "def sum_of_proper_divisors(n):\n # Return the sum of proper divisors of n\n divisors_sum = 1 # Start with 1, which is a proper divisor for all n > 1\n sqrt_n = int(n ** 0.5)\n \n for i in range(2, sqrt_n + 1):\n if n % i == 0:\n divisors_sum += i\n if i != n // i:\n divisors_sum += n // i\n \n return divisors_sum\ndef are_amicable(a, b):\n # Check if two numbers are amicable\n return sum_of_proper_divisors(a) == b and sum_of_proper_divisors(b) == a and a != b\ndef amicable_numbers_sum(max_num):\n # Calculate the sum of all amicable numbers less than max_num\n total_sum = 0\n amicable_numbers = set()\n \n for num in range(2, max_num):\n if num not in amicable_numbers:\n partner = sum_of_proper_divisors(num)\n if are_amicable(num, partner):\n total_sum += num + partner\n amicable_numbers.add(num)\n amicable_numbers.add(partner)\n \n return total_sum", "matching_cluster_idx": 11}, {"solution": "def sum_of_proper_divisors(n):\n divisors = [1] # Start with 1 since it's a proper divisor for all n > 1\n for i in range(2, int(n ** 0.5) + 1):\n if n % i == 0:\n divisors.append(i)\n if i != n // i:\n divisors.append(n // i)\n return sum(divisors)\ndef amicable_numbers_sum(upper_limit):\n sum_amicables = 0\n for num in range(2, upper_limit + 1):\n partner = sum_of_proper_divisors(num)\n if sum_of_proper_divisors(partner) == num and num != partner:\n sum_amicables += num\n return sum_amicables", "matching_cluster_idx": 11}]}, "Mbpp/128": {"dps": 99.5475113122172, "dps_norm": 80.0, "pass@1": 100.0, "profiled": [{"solution": "def long_words(n, str1):\n # Split the input string into words\n words = str1.split(\" \")\n result = []\n \n # Iterate through the list of words\n for word in words:\n # Check if the word's length is greater than n\n if len(word) > n:\n # If it is, append the word to the result list\n result.append(word)\n \n # Return the list of words longer than n characters\n return result", "matching_cluster_idx": 3}, {"solution": "def long_words(n, text):\n \"\"\"\n This function takes a number n and a string text as input.\n It returns a list of words from the text that are longer than n characters.\n \n Parameters:\n n (int): The minimum length a word must be to be included in the output.\n text (str): The text to split into words and filter based on length.\n \n Returns:\n list: A list of words longer than n characters.\n \"\"\"\n # Split the text into words\n words = text.split()\n \n # Filter words that are longer than n characters\n filtered_words = [word for word in words if len(word) > n]\n \n return filtered_words", "matching_cluster_idx": 3}, {"solution": "def long_words(n, phrase):\n # Split the phrase into words\n words = phrase.split()\n # Filter words longer than n characters\n result = [word for word in words if len(word) > n]\n return result", "matching_cluster_idx": 3}, {"solution": "def long_words(n, phrase):\n \"\"\"\n Extract words from a phrase that are longer than n characters.\n \n Parameters:\n n (int): The minimum length of words to extract.\n phrase (str): The phrase from which to extract words.\n \n Returns:\n list: A list of words longer than n characters.\n \"\"\"\n # Split the phrase into words\n words = phrase.split()\n \n # Filter words based on the length criterion\n long_words = [word for word in words if len(word) > n]\n \n return long_words", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n # Split the sentence into words\n words = sentence.split(\" \")\n \n # Filter words longer than n characters\n result = [word for word in words if len(word) > n]\n \n return result", "matching_cluster_idx": 3}, {"solution": "def long_words(n, phrase):\n # Split the phrase into words\n words = phrase.split(' ')\n # Filter words longer than n characters\n result = [word for word in words if len(word) > n]\n return result", "matching_cluster_idx": 3}, {"solution": "def long_words(n, phrase):\n # Split the phrase into words\n words = phrase.split(' ')\n # Filter words longer than n characters\n long_words = [word for word in words if len(word) > n]\n return long_words", "matching_cluster_idx": 3}, {"solution": "def long_words(n, phrase):\n # Split the phrase into words\n words = phrase.split(\" \")\n \n # Filter words longer than n characters\n filtered_words = [word for word in words if len(word) > n]\n \n return filtered_words", "matching_cluster_idx": 3}, {"solution": "def long_words(n, phrase):\n \"\"\"\n Finds words that are longer than n characters from a given list of words.\n \n Parameters:\n n (int): The minimum length of words to be considered.\n phrase (str): A string containing the list of words separated by spaces.\n \n Returns:\n list: A list of words from the phrase that are longer than n characters.\n \"\"\"\n # Split the phrase into a list of words\n words_list = phrase.split(\" \")\n \n # Filter the list to include only words longer than n characters\n filtered_words = [word for word in words_list if len(word) > n]\n \n return filtered_words", "matching_cluster_idx": 3}, {"solution": "def long_words(n, phrase):\n # Split the phrase into words\n words = phrase.split()\n # Filter words longer than n characters\n result = [word for word in words if len(word) > n]\n return result", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n # Split the sentence into words\n words = sentence.split(\" \")\n # Filter words longer than n characters\n result = [word for word in words if len(word) > n]\n return result", "matching_cluster_idx": 3}, {"solution": "def long_words(n, phrase):\n \"\"\"\n Extracts words longer than n characters from a given phrase.\n \n Parameters:\n n (int): The minimum length of words to return.\n phrase (str): The phrase from which to extract words.\n \n Returns:\n list: A list of words from the phrase that are longer than n characters.\n \"\"\"\n # Split the phrase into words\n words = phrase.split()\n \n # Filter the words based on their length\n long_words = [word for word in words if len(word) > n]\n \n return long_words", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n # Split the sentence into words\n words = sentence.split(\" \")\n \n # Filter words that are longer than n characters\n filtered_words = [word for word in words if len(word) > n]\n \n return filtered_words", "matching_cluster_idx": 3}, {"solution": "def long_words(n, phrase):\n \"\"\"\n Finds words that are longer than n characters from a given phrase.\n \n Parameters:\n n (int): The minimum length of words to be included in the result.\n phrase (str): The phrase from which to extract words.\n \n Returns:\n list: A list of words from the phrase that are longer than n characters.\n \"\"\"\n # Split the phrase into words and filter based on length\n return [word for word in phrase.split(\" \") if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, phrase):\n # Split the phrase into words\n words = phrase.split(\" \")\n \n # Filter words longer than n characters\n filtered_words = [word for word in words if len(word) > n]\n \n return filtered_words", "matching_cluster_idx": 3}, {"solution": "def long_words(n, phrase):\n \"\"\"\n Finds words in the given phrase that are longer than n characters.\n \n Parameters:\n n (int): The minimum length of words to be returned.\n phrase (str): The string from which to extract words.\n \n Returns:\n list: A list of words longer than n characters from the phrase.\n \"\"\"\n # Split the phrase into words based on spaces\n words = phrase.split(' ')\n \n # Filter words based on length\n result = [word for word in words if len(word) > n]\n \n return result", "matching_cluster_idx": 3}, {"solution": "def long_words(n, phrase):\n \"\"\"\n Finds words that are longer than n characters from a given list of words.\n \n Parameters:\n n (int): The minimum length of the words to be returned.\n phrase (str): The phrase containing the words.\n \n Returns:\n list: A list of words longer than n characters.\n \"\"\"\n # Split the phrase into words\n words = phrase.split(\" \")\n \n # Filter words based on the length and return them\n return [word for word in words if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, phrase):\n # Split the phrase into words\n words = phrase.split()\n \n # Filter words that are longer than n characters\n result = [word for word in words if len(word) > n]\n \n return result", "matching_cluster_idx": 3}, {"solution": "def long_words(n, phrase):\n # Split the phrase into words\n words_list = phrase.split(\" \")\n # Filter words longer than n characters and return them in a list\n return [word for word in words_list if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n # Split the sentence into words\n words = sentence.split(\" \")\n \n # Filter words that are longer than n characters\n result = [word for word in words if len(word) > n]\n \n return result", "matching_cluster_idx": 3}]}, "Mbpp/129": {"dps": 89.84693877551021, "dps_norm": 98.66666666666667, "pass@1": 58.0, "profiled": [{"solution": "def magic_square_test(matrix):\n # Calculate the sum of the first row to establish the magic constant\n magic_constant = sum(matrix[0])\n \n # Check the sums of rows and columns\n for i in range(len(matrix)):\n if sum(matrix[i]) != magic_constant or sum(row[i] for row in matrix) != magic_constant:\n return False\n \n # Check the sums of the diagonals\n if sum(matrix[i][i] for i in range(len(matrix))) != magic_constant:\n return False\n if sum(matrix[i][len(matrix)-i-1] for i in range(len(matrix))) != magic_constant:\n return False\n \n # If all checks pass, it's a magic square\n return True", "matching_cluster_idx": 13}, {"solution": "def magic_square_test(matrix):\n # Extracting the dimensions of the matrix\n n = len(matrix)\n \n # Calculate the sum of the first row to establish the magic constant\n magic_sum = sum(matrix[0])\n \n # Checking sums of all rows\n for row in matrix:\n if sum(row) != magic_sum:\n return False\n \n # Checking sums of all columns\n for col in range(n):\n if sum(matrix[row][col] for row in range(n)) != magic_sum:\n return False\n \n # Checking sum of the main diagonal\n if sum(matrix[i][i] for i in range(n)) != magic_sum:\n return False\n \n # Checking sum of the secondary diagonal\n if sum(matrix[i][n - 1 - i] for i in range(n)) != magic_sum:\n return False\n \n # If all checks pass, it's a magic square\n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n # Calculate the sum of the first row to set the magic constant\n magic_constant = sum(matrix[0])\n \n # Function to check if all elements in a list are equal to the magic constant\n def check_list(lst):\n return all(sum(row) == magic_constant for row in lst)\n \n # Check rows and columns\n if not check_list(matrix) or not check_list(zip(*matrix)):\n return False\n \n # Check diagonals\n diagonal1 = [matrix[i][i] for i in range(len(matrix))]\n diagonal2 = [matrix[i][len(matrix)-1-i] for i in range(len(matrix))]\n \n if sum(diagonal1) != magic_constant or sum(diagonal2) != magic_constant:\n return False\n \n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n # Extract the size of the matrix and calculate the expected sum of a row/column/diagonal\n size = len(matrix)\n expected_sum = sum(matrix[0])\n \n # Check rows and columns\n for i in range(size):\n if sum(matrix[i]) != expected_sum or sum(row[i] for row in matrix) != expected_sum:\n return False\n \n # Check diagonals\n if sum(matrix[i][i] for i in range(size)) != expected_sum or sum(matrix[i][size-1-i] for i in range(size)) != expected_sum:\n return False\n \n return True", "matching_cluster_idx": 13}, {"solution": "def magic_square_test(matrix):\n # Calculate the sum of the first row to establish the magic constant\n magic_constant = sum(matrix[0])\n \n # Helper function to calculate the sum of the numbers in a list\n def sum_row_column(arr):\n return sum(arr)\n \n # Check if any row or column doesn't sum to the magic constant\n for i in range(len(matrix)):\n if sum_row_column(matrix[i]) != magic_constant or sum_row_column([matrix[j][i] for j in range(len(matrix))]) != magic_constant:\n return False\n \n # Check the sum of the primary diagonal\n if sum([matrix[i][i] for i in range(len(matrix))]) != magic_constant:\n return False\n \n # Check the sum of the secondary diagonal\n if sum([matrix[i][len(matrix)-i-1] for i in range(len(matrix))]) != magic_constant:\n return False\n \n return True", "matching_cluster_idx": 13}, {"solution": "def magic_square_test(matrix):\n # Calculate the sum of the first row to set a target sum\n target_sum = sum(matrix[0])\n \n # Check sums of all rows\n for row in matrix:\n if sum(row) != target_sum:\n return False\n \n # Check sums of all columns\n for col in range(len(matrix)):\n if sum(matrix[row][col] for row in range(len(matrix))) != target_sum:\n return False\n \n # Check sum of the main diagonal\n if sum(matrix[i][i] for i in range(len(matrix))) != target_sum:\n return False\n \n # Check sum of the secondary diagonal\n if sum(matrix[i][len(matrix)-1-i] for i in range(len(matrix))) != target_sum:\n return False\n \n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n # Calculate the sum of the first row to set as the target sum\n target_sum = sum(matrix[0])\n \n # Check sums of rows\n for row in matrix:\n if sum(row) != target_sum:\n return False\n \n # Check sums of columns\n for col in range(len(matrix)):\n if sum(matrix[row][col] for row in range(len(matrix))) != target_sum:\n return False\n \n # Check sum of the main diagonal\n if sum(matrix[i][i] for i in range(len(matrix))) != target_sum:\n return False\n \n # Check sum of the secondary diagonal\n if sum(matrix[i][len(matrix)-1-i] for i in range(len(matrix))) != target_sum:\n return False\n \n # If all checks pass, it's a magic square\n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n n = len(matrix)\n # Calculate the sum of the first row to set the magic constant\n magic_sum = sum(matrix[0])\n \n # Check the sum of each row\n for row in matrix:\n if sum(row) != magic_sum:\n return False\n \n # Check the sum of each column\n for col in range(n):\n if sum(matrix[row][col] for row in range(n)) != magic_sum:\n return False\n \n # Check the sum of the main diagonal\n if sum(matrix[i][i] for i in range(n)) != magic_sum:\n return False\n \n # Check the sum of the secondary diagonal\n if sum(matrix[i][n - 1 - i] for i in range(n)) != magic_sum:\n return False\n \n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n n = len(matrix)\n \n # Calculate the sum of the first row to set a target sum\n target_sum = sum(matrix[0])\n \n # Check sums of each row\n for row in matrix:\n if sum(row) != target_sum:\n return False\n \n # Check sums of each column\n for col in range(n):\n if sum(matrix[row][col] for row in range(n)) != target_sum:\n return False\n \n # Check sum of the main diagonal\n if sum(matrix[i][i] for i in range(n)) != target_sum:\n return False\n \n # Check sum of the secondary diagonal\n if sum(matrix[i][n-i-1] for i in range(n)) != target_sum:\n return False\n \n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n # Calculate the sum of the first row to establish the magic constant\n magic_constant = sum(matrix[0])\n \n # Check the sum of each row\n for row in matrix:\n if sum(row) != magic_constant:\n return False\n \n # Check the sum of each column\n for col in range(len(matrix)):\n if sum(matrix[row][col] for row in range(len(matrix))) != magic_constant:\n return False\n \n # Check the sum of the main diagonal\n if sum(matrix[i][i] for i in range(len(matrix))) != magic_constant:\n return False\n \n # Check the sum of the secondary diagonal\n if sum(matrix[i][len(matrix)-1-i] for i in range(len(matrix))) != magic_constant:\n return False\n \n # If all checks pass, it's a magic square\n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n # Calculate the sum of the first row to establish the magic constant\n magic_sum = sum(matrix[0])\n \n # Check rows and columns\n for i in range(len(matrix)):\n if sum(matrix[i]) != magic_sum or sum(row[i] for row in matrix) != magic_sum:\n return False\n \n # Check diagonals\n if sum(matrix[i][i] for i in range(len(matrix))) != magic_sum:\n return False\n if sum(matrix[i][len(matrix)-1-i] for i in range(len(matrix))) != magic_sum:\n return False\n \n return True", "matching_cluster_idx": 13}, {"solution": "def magic_square_test(matrix):\n # Calculate the sum of the first row to set the magic constant\n magic_sum = sum(matrix[0])\n \n # Check the sum of each row\n for row in matrix:\n if sum(row) != magic_sum:\n return False\n \n # Check the sum of each column\n for col in range(len(matrix)):\n if sum(matrix[row][col] for row in range(len(matrix))) != magic_sum:\n return False\n \n # Check the sum of the main diagonal\n if sum(matrix[i][i] for i in range(len(matrix))) != magic_sum:\n return False\n \n # Check the sum of the secondary diagonal\n if sum(matrix[i][len(matrix)-1-i] for i in range(len(matrix))) != magic_sum:\n return False\n \n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n n = len(matrix)\n magic_constant = sum(matrix[0])\n \n # Check sum of each row\n for row in matrix:\n if sum(row) != magic_constant:\n return False\n \n # Check sum of each column\n for col in range(n):\n if sum(matrix[row][col] for row in range(n)) != magic_constant:\n return False\n \n # Check sum of the main diagonal\n if sum(matrix[i][i] for i in range(n)) != magic_constant:\n return False\n \n # Check sum of the secondary diagonal\n if sum(matrix[i][n - 1 - i] for i in range(n)) != magic_constant:\n return False\n \n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n # Calculate the sum of the first row to set as target sum\n side_len = len(matrix)\n target_sum = sum(matrix[0])\n \n # Check the sum of each row\n for row in matrix:\n if sum(row) != target_sum:\n return False\n \n # Check the sum of each column\n for col in range(side_len):\n if sum(matrix[row][col] for row in range(side_len)) != target_sum:\n return False\n \n # Check the sum of the main diagonal\n if sum(matrix[i][i] for i in range(side_len)) != target_sum:\n return False\n \n # Check the sum of the secondary diagonal\n if sum(matrix[i][~i] for i in range(side_len)) != target_sum:\n return False\n \n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n n = len(matrix)\n # Calculate the sum of the first row to establish the magic constant\n magic_sum = sum(matrix[0])\n \n # Check sums of rows\n for row in matrix:\n if sum(row) != magic_sum:\n return False\n \n # Check sums of columns\n for col in range(n):\n if sum(matrix[row][col] for row in range(n)) != magic_sum:\n return False\n \n # Check sum of the main diagonal\n if sum(matrix[i][i] for i in range(n)) != magic_sum:\n return False\n \n # Check sum of the secondary diagonal\n if sum(matrix[i][n - 1 - i] for i in range(n)) != magic_sum:\n return False\n \n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n def is_magic(square):\n # Calculate the sum of the first row to set a target sum\n target_sum = sum(square[0])\n \n # Check sums of all rows\n for row in square:\n if sum(row) != target_sum:\n return False\n \n # Check sums of all columns\n for col in range(len(square)):\n if sum(matrix[row][col] for row in range(len(square))) != target_sum:\n return False\n \n # Check sum of the main diagonal\n if sum(square[i][i] for i in range(len(square))) != target_sum:\n return False\n \n # Check sum of the secondary diagonal\n if sum(square[i][~i] for i in range(len(square))) != target_sum:\n return False\n \n return True\n \n return is_magic(matrix)", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n # Calculate the sum of the first row to establish a baseline\n magic_sum = sum(matrix[0])\n \n # Check the sum of each row against the magic sum\n for row in matrix:\n if sum(row) != magic_sum:\n return False\n \n # Check the sum of each column against the magic sum\n for col in range(len(matrix)):\n if sum(matrix[row][col] for row in range(len(matrix))) != magic_sum:\n return False\n \n # Check the sum of the main diagonal against the magic sum\n if sum(matrix[i][i] for i in range(len(matrix))) != magic_sum:\n return False\n \n # Check the sum of the secondary diagonal against the magic sum\n if sum(matrix[i][len(matrix) - 1 - i] for i in range(len(matrix))) != magic_sum:\n return False\n \n # If all checks pass, it is a magic square\n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n # Calculate the sum of the first row to set a target sum\n target_sum = sum(matrix[0])\n \n # Check sums of rows\n for row in matrix:\n if sum(row) != target_sum:\n return False\n \n # Check sums of columns\n for col in range(len(matrix)):\n if sum(matrix[row][col] for row in range(len(matrix))) != target_sum:\n return False\n \n # Check sum of the main diagonal\n if sum(matrix[i][i] for i in range(len(matrix))) != target_sum:\n return False\n \n # Check sum of the secondary diagonal\n if sum(matrix[i][len(matrix)-1-i] for i in range(len(matrix))) != target_sum:\n return False\n \n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n n = len(matrix)\n # Calculate the sum of the first row to establish the magic constant\n magic_sum = sum(matrix[0])\n \n # Check sums of each row\n for row in matrix:\n if sum(row) != magic_sum:\n return False\n \n # Check sums of each column\n for col in range(n):\n if sum(matrix[row][col] for row in range(n)) != magic_sum:\n return False\n \n # Check sum of the main diagonal\n if sum(matrix[i][i] for i in range(n)) != magic_sum:\n return False\n \n # Check sum of the secondary diagonal\n if sum(matrix[i][n-1-i] for i in range(n)) != magic_sum:\n return False\n \n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n n = len(matrix)\n # Calculate the magic constant (sum of one row)\n magic_constant = sum(matrix[0])\n \n # Function to check if all items in a list are equal to the magic constant\n def is_magic(lst):\n return all(sum(row) == magic_constant for row in lst)\n \n # Check rows and columns\n if not is_magic(matrix) or not is_magic(zip(*matrix)):\n return False\n \n # Check diagonals\n diagonal1 = sum(matrix[i][i] for i in range(n))\n diagonal2 = sum(matrix[i][n-i-1] for i in range(n))\n \n if diagonal1 != magic_constant or diagonal2 != magic_constant:\n return False\n \n return True", "matching_cluster_idx": 14}]}, "Mbpp/130": {"dps": 75.88565022421525, "dps_norm": 67.5, "pass@1": 84.0, "profiled": [{"solution": "from collections import defaultdict\ndef max_occurrences(nums):\n occurrence_dict = defaultdict(int)\n \n # Count the occurrences of each item\n for num in nums:\n occurrence_dict[num] += 1\n \n # Find the item with the maximum frequency\n max_item = max(occurrence_dict, key=occurrence_dict.get)\n \n return max_item", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(items):\n from collections import defaultdict\n \n # Use a dictionary to count the occurrences of each item\n occurrences = defaultdict(int)\n for item in items:\n occurrences[item] += 1\n \n # Find and return the item with maximum occurrences\n return max(occurrences, key=occurrences.get)", "matching_cluster_idx": 3}, {"solution": "from collections import defaultdict\ndef max_occurrences(nums):\n \"\"\"\n Finds the item with the maximum frequency in a given list.\n \n Args:\n nums : List[int]\n The list of integers to analyze.\n \n Returns:\n int\n The integer with the highest frequency in the list.\n \"\"\"\n # Using defaultdict to count occurrences of each number\n frequency_counter = defaultdict(int)\n for num in nums:\n frequency_counter[num] += 1\n \n # Finding the number with maximum occurrences\n max_occurrence_num = max(frequency_counter, key=frequency_counter.get)\n return max_occurrence_num", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(lst):\n from collections import defaultdict\n \n # Create a default dictionary to hold the frequency of each item\n freq_map = defaultdict(int)\n \n # Populate the frequency map\n for item in lst:\n freq_map[item] += 1\n \n # Find the item with the maximum frequency\n max_occurrence_item = max(freq_map.items(), key=lambda x: x[1])[0]\n \n return max_occurrence_item", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(arr):\n from collections import defaultdict\n \n # Initialize a dictionary to keep track of frequencies\n frequency_dict = defaultdict(int)\n \n # Count the frequency of each item in the array\n for item in arr:\n frequency_dict[item] += 1\n \n # Find the item with the maximum frequency\n max_freq_item = max(frequency_dict, key=frequency_dict.get)\n \n return max_freq_item", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(items):\n from collections import defaultdict\n \n # Dictionary to store the frequency of each item\n frequency_dict = defaultdict(int)\n \n # Counting the frequency of each item in the list\n for item in items:\n frequency_dict[item] += 1\n \n # Finding the item with the maximum frequency\n max_frequency_item = max(frequency_dict, key=frequency_dict.get)\n \n return max_frequency_item", "matching_cluster_idx": 3}, {"solution": "from collections import defaultdict\ndef max_occurrences(nums):\n \"\"\"\n Finds the item with the maximum frequency in a given list.\n \n Parameters:\n nums (list): The list of numbers to analyze.\n \n Returns:\n int: The item with the maximum frequency.\n \"\"\"\n # Dictionary to store the frequency of each number\n frequency_dict = defaultdict(int)\n \n # Count the frequency of each number in the list\n for num in nums:\n frequency_dict[num] += 1\n \n # Find and return the number with the maximum frequency\n max_frequency_num = max(frequency_dict, key=frequency_dict.get)\n return max_frequency_num", "matching_cluster_idx": 3}, {"solution": "from collections import defaultdict\ndef max_occurrences(nums):\n \"\"\"\n Find the item with the maximum frequency in the given list.\n \n Args:\n nums: List of integers.\n \n Returns:\n int: The element with the maximum frequency in the list.\n \"\"\"\n # Initialize a dictionary to keep track of occurrences\n occurrence_dict = defaultdict(int)\n \n # Count the occurrences of each element\n for num in nums:\n occurrence_dict[num] += 1\n \n # Find the element with maximum frequency\n max_freq_num = max(occurrence_dict, key=occurrence_dict.get)\n \n return max_freq_num", "matching_cluster_idx": 3}, {"solution": "from collections import defaultdict\ndef max_occurrences(items):\n item_count = defaultdict(int)\n # Count occurrences of each item\n for item in items:\n item_count[item] += 1\n # Find the item with maximum occurrences\n return max(item_count.items(), key=lambda x: x[1])[0]", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(lst):\n from collections import defaultdict\n \n # Dictionary to keep count of occurrences of each item\n occurrence_dict = defaultdict(int)\n \n # Counting occurrences of each item in the list\n for item in lst:\n occurrence_dict[item] += 1\n \n # Finding the item with the maximum frequency\n max_occurrence_item = max(occurrence_dict, key=occurrence_dict.get)\n \n return max_occurrence_item", "matching_cluster_idx": 3}, {"solution": "from collections import defaultdict\ndef max_occurrences(nums):\n \"\"\"\n Find the item with the maximum frequency in the given list.\n \n Parameters:\n nums (list): The list of numbers to analyze.\n \n Returns:\n int: The number with the maximum frequency in the list.\n \"\"\"\n count_map = defaultdict(int)\n \n # Count the occurrences of each number\n for num in nums:\n count_map[num] += 1\n \n # Find the number with maximum frequency\n max_count = 0\n max_num = None\n for num, count in count_map.items():\n if count > max_count:\n max_count = count\n max_num = num\n \n return max_num", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(nums):\n from collections import defaultdict\n \n # Create a dictionary to store the frequency of each item\n frequency_dict = defaultdict(int)\n for num in nums:\n frequency_dict[num] += 1\n \n # Find the item with the maximum frequency\n max_freq_item = max(frequency_dict, key=frequency_dict.get)\n \n return max_freq_item", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(items):\n from collections import defaultdict\n \n # Dictionary to store the frequency of each item\n frequency_dict = defaultdict(int)\n \n # Count the frequency of each item in the list\n for item in items:\n frequency_dict[item] += 1\n \n # Find and return the item with the maximum frequency\n max_occurrence_item = max(frequency_dict, key=frequency_dict.get)\n return max_occurrence_item", "matching_cluster_idx": 3}, {"solution": "from collections import defaultdict\ndef max_occurrences(nums):\n # Create a dictionary to keep track of the count of each item\n count_dict = defaultdict(int)\n for num in nums:\n count_dict[num] += 1\n \n # Initialize the maximum frequency and the item with maximum frequency\n max_freq = 0\n max_item = None\n \n # Iterate through the dictionary to find the item with the maximum frequency\n for item, freq in count_dict.items():\n if freq > max_freq:\n max_freq = freq\n max_item = item\n \n return max_item", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(nums):\n from collections import Counter\n \n # Count the occurrence of each number in the list\n num_counts = Counter(nums)\n \n # Find the number with maximum frequency\n max_freq_num = num_counts.most_common(1)[0][0]\n \n return max_freq_num", "matching_cluster_idx": 4}, {"solution": "from collections import defaultdict\ndef max_occurrences(nums):\n \"\"\"\n Finds the item with the maximum frequency in a given list.\n \n Parameters:\n nums (list): The list of numbers to analyze.\n \n Returns:\n int: The item with the maximum frequency in the list.\n \"\"\"\n # Using defaultdict to count the occurrences of each number in the list\n num_count = defaultdict(int)\n for num in nums:\n num_count[num] += 1\n \n # Finding the item with the maximum frequency\n max_freq_item = max(num_count, key=num_count.get)\n return max_freq_item", "matching_cluster_idx": 3}, {"solution": "from collections import defaultdict\ndef max_occurrences(nums):\n \"\"\"\n Find the item with the maximum frequency in a given list.\n \n Parameters:\n nums (list): The list of numbers.\n \n Returns:\n int: The item with the highest frequency in the list.\n \"\"\"\n # Initialize a dictionary to store the frequency of each element\n frequency_dict = defaultdict(int)\n \n # Iterate through the list and count occurrences of each item\n for num in nums:\n frequency_dict[num] += 1\n \n # Find the item with the maximum frequency\n max_occurrence_item = max(frequency_dict, key=frequency_dict.get)\n \n return max_occurrence_item", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(arr):\n from collections import defaultdict\n \n # Dictionary to store the frequency of each item\n frequency = defaultdict(int)\n \n # Calculate the frequency of each item in the array\n for item in arr:\n frequency[item] += 1\n \n # Find and return the item with the maximum frequency\n return max(frequency, key=frequency.get)", "matching_cluster_idx": 3}, {"solution": "from collections import defaultdict\ndef max_occurrences(nums):\n # Dictionary to store the frequency of each number\n frequency_dict = defaultdict(int)\n for num in nums:\n frequency_dict[num] += 1\n \n # Find the item with maximum frequency\n max_occurrence_item = max(frequency_dict, key=frequency_dict.get)\n return max_occurrence_item", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(items):\n from collections import defaultdict\n \n # Dictionary to store the frequency of each item\n frequency_dict = defaultdict(int)\n \n # Count the frequency of each item\n for item in items:\n frequency_dict[item] += 1\n \n # Find the item with the maximum frequency\n max_occurrence_item = max(frequency_dict, key=frequency_dict.get)\n \n return max_occurrence_item", "matching_cluster_idx": 3}]}, "Mbpp/137": {"dps": 64.24731182795698, "dps_norm": 71.875, "pass@1": 12.0, "profiled": [{"solution": "from typing import List\nimport math\ndef zero_count(arr: List[int]) -> float:\n \"\"\"\n Calculates the ratio of zeroes to non-zeroes in the given array of integers.\n \n Parameters:\n arr (List[int]): The input list of integers.\n \n Returns:\n float: The ratio of zeroes to non-zeroes.\n \"\"\"\n zero_count = arr.count(0)\n non_zero_count = len(arr) - zero_count\n if non_zero_count == 0:\n return float('inf') # Avoid division by zero\n \n return zero_count / non_zero_count", "matching_cluster_idx": 7}, {"solution": "from typing import List\nimport math\ndef zero_count(arr: List[int]) -> float:\n \"\"\"\n Calculates the ratio of zeroes to non-zeroes in the given list of integers.\n \n Parameters:\n arr (List[int]): The list of integers.\n \n Returns:\n float: The ratio of zeroes to non-zeroes in the list.\n \"\"\"\n # Count the total number of zeroes and non-zeroes\n total_zeroes = arr.count(0)\n total_non_zeroes = len(arr) - total_zeroes\n \n # Calculate the ratio of zeroes to non-zeroes\n if total_non_zeroes == 0: # To avoid division by zero\n return float('inf') # Ratio would be infinity if no non-zeroes are present\n else:\n ratio = total_zeroes / total_non_zeroes\n \n return ratio", "matching_cluster_idx": 7}, {"solution": "from typing import List\nimport math\ndef zero_count(arr: List[int]) -> float:\n \"\"\"\n Calculates the ratio of zeroes to non-zeroes in an array of integers.\n \n Parameters:\n arr (List[int]): The input array of integers.\n \n Returns:\n float: The ratio of zeroes to non-zeroes.\n \"\"\"\n zero_count = arr.count(0)\n non_zero_count = len(arr) - zero_count\n \n # Avoid division by zero\n if non_zero_count == 0:\n return float('inf')\n \n return zero_count / non_zero_count", "matching_cluster_idx": 7}, {"solution": "import math\ndef zero_count(arr):\n zero_count = 0\n non_zero_count = 0\n \n # Count zeros and non-zeros\n for num in arr:\n if num == 0:\n zero_count += 1\n else:\n non_zero_count += 1\n \n # Calculate the ratio of zeros to non-zeros\n if non_zero_count == 0:\n return float('inf') # Return infinity if there are no non-zero elements\n else:\n return zero_count / non_zero_count", "matching_cluster_idx": 3}, {"solution": "from typing import List\nimport math\ndef zero_count(arr: List[int]) -> float:\n \"\"\"\n Finds the ratio of zeroes to non-zeroes in an array of integers.\n \n Parameters:\n arr (List[int]): The list of integers to analyze.\n \n Returns:\n float: The ratio of zeroes to non-zeroes in the array.\n \"\"\"\n zero = 0\n non_zero = 0\n \n # Count zeroes and non-zeroes\n for num in arr:\n if num == 0:\n zero += 1\n else:\n non_zero += 1\n \n # Avoid division by zero if there are no non-zero elements\n if non_zero == 0:\n return float('inf')\n \n ratio = zero / non_zero\n return ratio", "matching_cluster_idx": 3}, {"solution": "import math\ndef zero_count(arr):\n zero_count = 0\n non_zero_count = 0\n \n # Counting zeroes and non-zero elements\n for num in arr:\n if num == 0:\n zero_count += 1\n else:\n non_zero_count += 1\n \n # Handling division by zero error\n if non_zero_count == 0:\n return float('inf') # or 0, depending on how you interpret the ratio\n \n # Calculating and returning the ratio\n ratio = zero_count / non_zero_count\n return ratio", "matching_cluster_idx": 3}, {"solution": "import math\ndef zero_count(arr):\n zero_count = 0\n non_zero_count = 0\n \n for num in arr:\n if num == 0:\n zero_count += 1\n else:\n non_zero_count += 1\n \n # Avoid division by zero\n if non_zero_count == 0:\n return float('inf') # or any other value that indicates no non-zero elements\n \n return zero_count / non_zero_count", "matching_cluster_idx": 3}, {"solution": "import math\nimport statistics\ndef zero_count(nums):\n \"\"\"\n Calculate the ratio of zeroes to non-zeroes in a list of integers.\n \n Parameters:\n nums (list): A list of integers.\n \n Returns:\n float: The ratio of zeroes to non-zeroes.\n \"\"\"\n # Count the number of zeroes and non-zeroes in the list\n zeroes = sum(num == 0 for num in nums)\n non_zeroes = len(nums) - zeroes\n \n # Calculate the ratio of zeroes to non-zeroes\n if non_zeroes == 0:\n return float('inf')\n else:\n ratio = zeroes / non_zeroes\n return ratio", "matching_cluster_idx": 4}, {"solution": "from typing import List\nimport math\ndef zero_count(arr: List[int]) -> float:\n \"\"\"\n Calculates the ratio of zeroes to non-zeroes in an array of integers.\n \n Parameters:\n arr (List[int]): The input list of integers.\n \n Returns:\n float: The ratio of zeroes to non-zeroes.\n \"\"\"\n total_elements = len(arr)\n zero_elements = arr.count(0)\n \n if total_elements == 0:\n return 0\n \n non_zero_elements = total_elements - zero_elements\n \n if non_zero_elements == 0:\n return float('inf') # Ratio is infinity if there are no non-zero elements\n \n ratio = zero_elements / non_zero_elements\n \n return ratio", "matching_cluster_idx": 6}, {"solution": "import math\nfrom typing import List\ndef zero_count(nums: List[int]) -> float:\n \"\"\"\n Calculate the ratio of zeroes to non-zeroes in a list of integers.\n \n Parameters:\n nums (List[int]): The list of integers to evaluate.\n \n Returns:\n float: The ratio of zeroes to non-zeroes.\n \"\"\"\n zero_count = nums.count(0)\n non_zero_count = len(nums) - zero_count\n \n if non_zero_count == 0:\n return float('inf')\n else:\n return zero_count / non_zero_count", "matching_cluster_idx": 7}, {"solution": "from typing import List\nimport math\ndef zero_count(arr: List[int]) -> float:\n \"\"\"\n Finds the ratio of zeroes to non-zeroes in an array of integers.\n \n Parameters:\n arr (List[int]): The array of integers to analyze.\n \n Returns:\n float: The ratio of zeroes to non-zeroes in the array.\n \"\"\"\n \n zero_nums = sum(1 for a in arr if a == 0)\n non_zero_nums = sum(1 for a in arr if a != 0)\n \n # Check if the array only contains zeroes to avoid division by zero\n if non_zero_nums == 0:\n return float('inf') # or any value indicating all elements are zero\n \n ratio = zero_nums / non_zero_nums\n return ratio", "matching_cluster_idx": 0}, {"solution": "from typing import List\nimport math\ndef zero_count(arr: List[int]) -> float:\n \"\"\"\n Calculates the ratio of zeroes to non-zeroes in an array of integers.\n \n Parameters:\n arr (List[int]): The array of integers to be evaluated.\n \n Returns:\n float: The ratio of zeroes to non-zeroes in the array.\n \"\"\"\n total_elements = len(arr)\n zero_elements = arr.count(0)\n \n non_zero_elements = total_elements - zero_elements\n \n # Avoid division by zero\n if non_zero_elements == 0:\n return float('inf')\n \n ratio = zero_elements / non_zero_elements\n \n return ratio", "matching_cluster_idx": 7}]}, "Mbpp/140": {"dps": 64.22360248447205, "dps_norm": 73.75, "pass@1": 100.0, "profiled": [{"solution": "def extract_singly(list_of_tuples):\n \"\"\"\n Flattens a list of tuples into a set of unique numbers.\n \n Parameters:\n list_of_tuples (list of tuples): A list containing tuples of numbers.\n \n Returns:\n set: A set containing all the numbers from the input tuples, with duplicates removed.\n \"\"\"\n # Flatten the list of tuples and convert to a set to remove duplicates\n result_set = set()\n for tup in list_of_tuples:\n result_set.update(tup)\n return result_set", "matching_cluster_idx": 6}, {"solution": "def extract_singly(list_of_tuples):\n # Initialize an empty set to store unique elements\n result_set = set()\n \n # Iterate through each tuple in the list\n for tup in list_of_tuples:\n # Add all elements of the tuple to the set\n # This will automatically handle duplicates, as sets cannot have duplicate entries\n result_set.update(tup)\n \n # Return the final set of unique elements\n return result_set", "matching_cluster_idx": 6}, {"solution": "def extract_singly(lst):\n result = set()\n for sublist in lst:\n result.update(sublist)\n return result", "matching_cluster_idx": 6}, {"solution": "def extract_singly(list_of_lists):\n # Flatten the list of lists into a single set\n return {element for sublist in list_of_lists for element in sublist}", "matching_cluster_idx": 5}, {"solution": "def extract_singly(input_lists):\n # Flatten the list of lists into a set to remove duplicates and unify the data structure\n result_set = set()\n for sublist in input_lists:\n for number in sublist:\n result_set.add(number)\n return result_set", "matching_cluster_idx": 4}, {"solution": "def extract_singly(lists):\n # Initialize an empty set to store unique elements\n result_set = set()\n \n # Iterate through each tuple in the list\n for tup in lists:\n # Update the set with elements from the tuple, ensuring uniqueness\n result_set.update(tup)\n \n return result_set", "matching_cluster_idx": 6}, {"solution": "def extract_singly(list_of_tuples):\n # Initialize an empty set to store unique elements\n singly_set = set()\n \n # Iterate through each tuple in the list_of_tuples\n for tup in list_of_tuples:\n # Add each element in the tuple to the set\n for element in tup:\n singly_set.add(element)\n \n # Return the set containing all unique elements\n return singly_set", "matching_cluster_idx": 4}, {"solution": "def extract_singly(lists):\n result_set = set()\n for lst in lists:\n for item in lst:\n result_set.add(item)\n return result_set", "matching_cluster_idx": 3}, {"solution": "def extract_singly(list_of_tuples):\n result_set = set()\n for tuples in list_of_tuples:\n for item in tuples:\n result_set.add(item)\n return result_set", "matching_cluster_idx": 4}, {"solution": "def extract_singly(lists):\n # Initialize an empty set to hold the unique elements\n result_set = set()\n \n # Iterate through each tuple in the list of tuples\n for tup in lists:\n # Add each element of the tuple to the set\n for item in tup:\n result_set.add(item)\n \n # Return the final set of elements\n return result_set", "matching_cluster_idx": 4}, {"solution": "def extract_singly(list_of_tuples):\n \"\"\"\n Flattens the list of tuples into a set of numbers.\n \n Parameters:\n - list_of_tuples: List of tuples containing integers.\n \n Returns:\n A set of integers extracted from the given list of tuples.\n \"\"\"\n # Initialize an empty set\n result_set = set()\n \n # Iterate through each tuple in the list\n for tup in list_of_tuples:\n # Add elements of the tuple to the set\n result_set.update(tup)\n \n return result_set", "matching_cluster_idx": 6}, {"solution": "def extract_singly(input_lists):\n # Flatten the list of tuples into a single set\n result_set = set()\n for tup in input_lists:\n for item in tup:\n result_set.add(item)\n return result_set", "matching_cluster_idx": 4}, {"solution": "def extract_singly(lists):\n # Initialize an empty set to store unique elements\n result_set = set()\n \n # Iterate through each tuple in the list\n for tup in lists:\n # Add elements from the tuple to the set\n result_set.update(tup)\n \n return list(result_set)", "matching_cluster_idx": 6}, {"solution": "def extract_singly(list_of_tuples):\n \"\"\"\n Flattens the list of tuples into a set of numbers.\n \n Parameters:\n list_of_tuples (list of tuples): The list containing tuples of numbers.\n \n Returns:\n set: A set of numbers extracted from the list of tuples.\n \"\"\"\n # Initialize an empty set to store the numbers\n numbers_set = set()\n \n # Iterate through each tuple in the list\n for tuples in list_of_tuples:\n # Add all elements from the tuple to the set\n for number in tuples:\n numbers_set.add(number)\n \n return numbers_set", "matching_cluster_idx": 4}, {"solution": "def extract_singly(list_of_lists):\n # Use set comprehension to flatten the list and remove duplicates\n result_set = {item for sublist in list_of_lists for item in sublist}\n return result_set", "matching_cluster_idx": 5}, {"solution": "def extract_singly(lst_of_tup):\n result_set = set()\n for tup in lst_of_tup:\n result_set.update(tup)\n return list(result_set)", "matching_cluster_idx": 6}, {"solution": "def extract_singly(lst):\n result_set = set()\n for sublist in lst:\n for element in sublist:\n result_set.add(element)\n return list(result_set)", "matching_cluster_idx": 3}, {"solution": "def extract_singly(list_of_tuples):\n result_set = set()\n for tup in list_of_tuples:\n # Extend the result set with the current tuple's elements\n result_set.update(tup)\n return result_set", "matching_cluster_idx": 6}, {"solution": "def extract_singly(list_of_tuples):\n result_set = set()\n for tup in list_of_tuples:\n for num in tup:\n result_set.add(num)\n return result_set", "matching_cluster_idx": 4}, {"solution": "def extract_singly(list_of_tuples):\n result_set = set()\n for tup in list_of_tuples:\n result_set.update(tup)\n return result_set", "matching_cluster_idx": 6}]}, "Mbpp/141": {"dps": 61.7687074829932, "dps_norm": 40.0, "pass@1": 77.0, "profiled": [{"solution": "def pancake_sort(arr):\n \"\"\"\n Sorts a given list of elements using pancake sort algorithm.\n \n Parameters:\n arr (list): The list of elements to be sorted.\n \n Returns:\n list: The sorted list.\n \"\"\"\n \n def flip(sublist, k):\n \"\"\"\n Flips the first k elements of the sublist.\n \n Parameters:\n sublist (list): The sublist to be flipped.\n k (int): The number of elements to flip from the beginning.\n \"\"\"\n sublist[:k] = sublist[:k][::-1]\n \n len_arr = len(arr)\n \n # Begin from the end of array and move the largest unsorted element\n # to its proper position in each iteration\n for curr_size in range(len_arr, 1, -1):\n # Find the maximum element in arr[0..curr_size-1]\n max_idx = arr.index(max(arr[:curr_size]))\n \n # Move the maximum element to the end of current array if it's not\n if max_idx != curr_size-1:\n # Bring the largest number to the beginning if it's not already at the beginning\n if max_idx != 0:\n flip(arr, max_idx + 1)\n \n # Now move the largest number to its correct position\n flip(arr, curr_size)\n \n return arr", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(arr):\n \"\"\"\n Sorts an array using the Pancake Sorting algorithm.\n \n Parameters:\n arr (list): The list of elements to be sorted.\n \n Returns:\n list: The sorted list.\n \"\"\"\n def flip(arr, i):\n \"\"\"\n Flips elements in the array from start to i (inclusive).\n \"\"\"\n start = 0\n while start < i:\n arr[start], arr[i] = arr[i], arr[start]\n start += 1\n i -= 1\n \n # Loop over the array from the last index down to the second\n for size in range(len(arr), 1, -1):\n # Find the index of the maximum value in the current sublist\n max_index = arr.index(max(arr[:size]))\n # Move the maximum number to the end of the current sublist\n if max_index + 1 != size:\n # Bring the max element to the front if it's not already there\n if max_index != 0:\n flip(arr, max_index)\n # Now bring the max element to its correct position (at the end of the sublist)\n flip(arr, size - 1)\n return arr", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(arr):\n \"\"\"\n Sorts a list of elements using the pancake sort algorithm.\n \n :param arr: List of elements to be sorted.\n :return: Sorted list of elements.\n \"\"\"\n def flip(arr, i):\n \"\"\"\n Flips elements from the start to the specified index i.\n \n :param arr: List of elements.\n :param i: Index to flip elements to.\n \"\"\"\n start = 0\n while start < i:\n temp = arr[start]\n arr[start] = arr[i]\n arr[i] = temp\n start += 1\n i -= 1\n\n # Finding the maximum element in arr\n cur = len(arr)\n while cur > 1:\n # Moving the maximum element to the end of the array by flipping\n max_index = arr.index(max(arr[:cur]))\n flip(arr, max_index)\n flip(arr, cur-1)\n cur -= 1\n return arr", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(arr):\n \"\"\"\n Sorts an array using the pancake sorting algorithm.\n \n Parameters:\n arr (list): The list of elements to be sorted.\n \n Returns:\n list: The sorted list.\n \"\"\"\n \n def flip(sublist, k):\n \"\"\"\n Flips the first k elements of the input list.\n \n Parameters:\n sublist (list): The list of elements to be flipped.\n k (int): The number of elements to flip from the beginning.\n \n Returns:\n list: The list after flipping the first k elements.\n \"\"\"\n sublist[:k] = sublist[:k][::-1]\n return sublist\n \n n = len(arr)\n \n # Begin from the end of array\n while n > 1:\n # Find the maximum number in arr[0..n-1]\n max_idx = arr.index(max(arr[0:n]))\n \n # Move the maximum number to the end of the current array segment\n if max_idx != n-1:\n # Bring the max element to the beginning\n arr = flip(arr, max_idx + 1)\n # Now bring the max element to its place\n arr = flip(arr, n)\n # Reduce the size of current segment by one\n n -= 1\n return arr", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(arr):\n \"\"\"\n Sorts a list of elements using pancake sort algorithm.\n \n :param arr: List of integers to be sorted\n :return: Sorted list of integers\n \"\"\"\n n = len(arr)\n \n # Helper function to flip elements of arr from index 0 to i\n def flip(arr, i):\n start = 0\n while start < i:\n temp = arr[start]\n arr[start] = arr[i]\n arr[i] = temp\n start += 1\n i -= 1\n \n # Function to find the index of the maximum element in arr[0..n-1]\n def find_max(arr, n):\n mi = 0\n for i in range(n):\n if arr[i] > arr[mi]:\n mi = i\n return mi\n \n # Sorts arr[0..n-1] using pancake sort\n for size in range(n, 1, -1):\n # Find index of the maximum element in arr[0..size-1]\n mi = find_max(arr, size)\n \n if mi != size - 1:\n # Move the maximum element to the beginning if it's not already at the beginning\n if mi != 0:\n flip(arr, mi)\n # Move the maximum element to its correct position\n flip(arr, size - 1)\n \n return arr", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(arr):\n \"\"\"\n Sorts a list of elements using the pancake sort algorithm.\n \n :param arr: List of elements to be sorted.\n :return: Sorted list of elements.\n \"\"\"\n def flip(sublist, k):\n \"\"\"\n Flips the first k elements of the input list.\n \"\"\"\n i = 0\n while i < k / 2:\n sublist[i], sublist[k - i - 1] = sublist[k - i - 1], sublist[i]\n i += 1\n \n output = arr[:]\n n = len(output)\n while n > 1:\n # Find the maximum number in output array\n max_index = output.index(max(output[:n]))\n # Move the max number to the end of the array with two flips\n if max_index != n - 1:\n # Flip the max number to the beginning if it's not already there\n if max_index != 0:\n flip(output, max_index + 1)\n # Then flip it to its correct position (at the end)\n flip(output, n)\n n -= 1\n return output", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(arr):\n \"\"\"\n Sorts a given list of elements using the pancake sorting algorithm.\n \"\"\"\n n = len(arr)\n \n # Helper function to flip the array from 0 to i\n def flip(sub_arr, i):\n start = 0\n while start < i:\n sub_arr[start], sub_arr[i] = sub_arr[i], sub_arr[start]\n start += 1\n i -= 1\n \n # Perform pancake sort\n for size in range(n, 1, -1):\n # Find the index of the maximum element in the unsorted portion\n max_index = arr.index(max(arr[:size]))\n \n # Move the maximum element to the beginning if not already there\n if max_index != 0:\n flip(arr, max_index)\n \n # Move the maximum element to its correct position\n flip(arr, size - 1)\n \n return arr", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(arr):\n \"\"\"\n Sorts a given list using the Pancake Sorting algorithm.\n \n Parameters:\n arr (list): The list of elements to be sorted.\n \n Returns:\n list: The sorted list.\n \"\"\"\n \n def flip(arr, i):\n \"\"\"\n Flip the array from the beginning to the index i.\n \"\"\"\n start = 0\n while start < i:\n temp = arr[start]\n arr[start] = arr[i]\n arr[i] = temp\n start += 1\n i -= 1\n \n n = len(arr)\n \n # This code block sorts the array using the pancake sort technique.\n for size in range(n, 1, -1):\n # Finding the index of the maximum element in the array\n max_index = arr.index(max(arr[0:size]))\n # Move the maximum element to the beginning if it's not already at the beginning\n if max_index != 0:\n flip(arr, max_index)\n # Move the maximum element to its correct position (sorted subarray)\n flip(arr, size - 1)\n \n return arr", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(arr):\n def flip(sub_arr, i):\n start = 0\n while start < i:\n sub_arr[start], sub_arr[i] = sub_arr[i], sub_arr[start]\n start += 1\n i -= 1\n \n def find_max_index(sub_arr, n):\n max_index = 0\n for i in range(n):\n if sub_arr[i] > sub_arr[max_index]:\n max_index = i\n return max_index\n \n n = len(arr)\n for size in range(n, 1, -1):\n max_index = find_max_index(arr, size)\n if max_index != size - 1:\n flip(arr, max_index)\n flip(arr, size - 1)\n \n return arr", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(arr):\n \"\"\"\n Sorts the given list of elements using the pancake sort algorithm.\n \n Parameters:\n arr (list): The list of elements to be sorted.\n \n Returns:\n list: The sorted list.\n \"\"\"\n n = len(arr)\n while n > 1:\n # Find the maximum element in arr\n max_idx = arr.index(max(arr[:n]))\n # Bring the maximum element to the front if it's not already there\n if max_idx != n - 1:\n # Flip the maximum element to the front\n arr = flip(arr, max_idx)\n # Flip it into its correct position\n arr = flip(arr, n - 1)\n # Reduce the size of the current list\n n -= 1\n return arr\ndef flip(arr, k):\n \"\"\"\n Flips the first k elements of the list.\n \n Parameters:\n arr (list): The list to flip.\n k (int): The number of elements from the start of the list to flip.\n \n Returns:\n list: The list after flipping the first k elements.\n \"\"\"\n arr[:k+1] = arr[k::-1]\n return arr", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(arr):\n \"\"\"\n Sorts an array using the Pancake Sorting algorithm.\n \"\"\"\n n = len(arr)\n \n # Helper function to flip the array from 0 to i\n def flip(arr, i):\n start = 0\n while start < i:\n arr[start], arr[i] = arr[i], arr[start]\n start += 1\n i -= 1\n \n # Helper function to print array\n def print_arr(arr, n):\n for i in range(n):\n print(arr[i], end=\" \")\n \n # Start from the entire array and reduce down to a single element\n for size in range(n, 1, -1):\n # Find the maximum element in arr[0..size-1]\n max_idx = 0\n for i in range(1, size):\n if arr[i] > arr[max_idx]:\n max_idx = i\n \n # Bring the maximum number to the front if it's not already there\n if max_idx != size-1:\n # Bring the max element to front\n if max_idx != 0:\n flip(arr, max_idx)\n # Now bring the max element to its correct position\n flip(arr, size-1)\n \n return arr", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(arr):\n \"\"\"\n Sorts a list of elements using the pancake sort algorithm.\n \n Parameters:\n arr (list): The list of elements to be sorted.\n \n Returns:\n list: The sorted list.\n \"\"\"\n \n def flip(arr, i):\n \"\"\"\n Flips the subarray from the start to the index i (inclusive).\n \"\"\"\n start = 0\n while start < i:\n arr[start], arr[i] = arr[i], arr[start]\n start += 1\n i -= 1\n \n n = len(arr)\n while n > 1:\n # Find the index of the maximum element in arr[0:n]\n max_idx = arr.index(max(arr[:n]))\n # Move the maximum element to the beginning if it's not already there\n if max_idx != 0:\n flip(arr, max_idx)\n # Now flip the maximum element to its correct position\n flip(arr, n - 1)\n # Reduce the size of the current array by one\n n -= 1\n \n return arr", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(arr):\n \"\"\"\n Sorts a list of elements using the pancake sort algorithm.\n \n :param arr: List of integers to be sorted.\n :return: Sorted list of integers.\n \"\"\"\n def flip(sub_arr, k):\n \"\"\"\n Flips the first k + 1 elements of the sub_arr.\n \n :param sub_arr: List of integers.\n :param k: Index of the last element to flip.\n \"\"\"\n i = 0\n while i < k:\n sub_arr[i], sub_arr[k] = sub_arr[k], sub_arr[i]\n i += 1\n k -= 1\n \n n = len(arr)\n while n > 1:\n # Find index of the maximum element in arr[0..n-1]\n mi = arr.index(max(arr[0:n]))\n # Move the maximum element to the end by reversing twice\n if mi != n-1:\n # Bring the largest number to the beginning\n flip(arr, mi)\n # Now bring the largest number to its correct position\n flip(arr, n-1)\n # Reduce the size of the current array\n n -= 1\n return arr", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(arr):\n \"\"\"\n Sorts a given list of elements using pancake sorting algorithm.\n \"\"\"\n def flip(sublist, k):\n i = 0\n while i < k / 2:\n sublist[i], sublist[k-i-1] = sublist[k-i-1], sublist[i]\n i += 1\n \n def find_max(index):\n max_index = 0\n for i in range(index + 1):\n if arr[i] > arr[max_index]:\n max_index = i\n return max_index\n \n n = len(arr)\n while n > 1:\n max_index = find_max(n-1)\n if max_index != n-1:\n # Flip the max element to the front if it's not already at the front\n flip(arr, max_index+1)\n # Now flip it to its correct position\n flip(arr, n)\n n -= 1\n return arr", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(arr):\n \"\"\"\n Sorts an array using the Pancake Sorting algorithm.\n \n Parameters:\n arr (list): The list of elements to be sorted.\n \n Returns:\n list: The sorted list.\n \"\"\"\n def flip(arr, i):\n \"\"\"\n Flips the array up to the index i.\n \"\"\"\n start = 0\n while start < i:\n temp = arr[start]\n arr[start] = arr[i]\n arr[i] = temp\n start += 1\n i -= 1\n\n n = len(arr)\n while n > 1:\n # Find the index of the maximum element in arr[0..n-1]\n max_idx = arr.index(max(arr[0:n]))\n # Move the maximum element to the end if it's not already at the end\n if max_idx != n-1:\n # Bring the maximum element to the beginning if it's not already there\n if max_idx != 0:\n flip(arr, max_idx)\n # Now flip the maximum element to its correct position\n flip(arr, n-1)\n n -= 1\n return arr", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(arr):\n \"\"\"\n Sorts a list of elements using the Pancake Sort algorithm.\n \"\"\"\n n = len(arr)\n \n def flip(arr, i):\n start = 0\n while start < i:\n arr[start], arr[i] = arr[i], arr[start]\n start += 1\n i -= 1\n \n for size in range(n, 1, -1):\n # Find the index of the maximum element in arr[0..size-1]\n max_index = arr.index(max(arr[0:size]))\n \n # Move the maximum element to the end of the current array if it's not already at the end\n if max_index != size-1:\n # Bring the maximum element to the front if it's not there already\n if max_index != 0:\n flip(arr, max_index)\n # Now bring the maximum element to its correct position\n flip(arr, size-1)\n \n return arr", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(arr):\n \"\"\"\n Sorts a list of elements using the pancake sorting algorithm.\n \n :param arr: List of integers to be sorted.\n :return: Sorted list of integers.\n \"\"\"\n n = len(arr)\n \n # Helper function to flip the array from 0 to i\n def flip(arr, i):\n start = 0\n while start < i:\n arr[start], arr[i] = arr[i], arr[start]\n start += 1\n i -= 1\n \n # Perform pancake sort\n for size in range(n, 1, -1):\n # Find the index of the maximum element in arr[0..size-1]\n max_idx = max(range(size), key=arr.__getitem__)\n # Move the maximum element to the end of the current array if it's not already at the end\n if max_idx != size - 1:\n # Bring the maximum element to the front if it's not already there\n if max_idx != 0:\n flip(arr, max_idx)\n # Now flip the maximum element to its correct position\n flip(arr, size - 1)\n return arr", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(arr):\n \"\"\"\n Sorts a given list of elements using the Pancake Sorting algorithm.\n \"\"\"\n n = len(arr)\n \n while n > 1:\n # Find index of the maximum element in the unsorted part of the list\n mi = arr.index(max(arr[0:n]))\n # Move the maximum element to the beginning if it's not already there\n if mi != 0:\n arr = arr[mi::-1] + arr[mi+1::]\n # Move the maximum element to its correct position\n arr = arr[n-1::-1] + arr[n::]\n n -= 1\n return arr", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(arr):\n \"\"\"\n Sorts the given list of elements using the Pancake Sorting algorithm.\n \"\"\"\n def flip(sublist, k):\n i = 0\n while i < k / 2:\n sublist[i], sublist[k - i - 1] = sublist[k - i - 1], sublist[i]\n i += 1\n \n def find_max(index):\n max = 0\n for i in range(index + 1):\n if arr[i] > arr[max]:\n max = i\n return max\n \n n = len(arr)\n while n > 1:\n max_index = find_max(n - 1)\n if max_index != n - 1:\n # Flip the max element to the front if it's not already there\n if max_index != 0:\n flip(arr, max_index + 1)\n # Now flip it into its correct position\n flip(arr, n)\n n -= 1\n return arr", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(arr):\n \"\"\"\n Sorts an array using pancake sort algorithm.\n \n Parameters:\n arr (list): The list of elements to be sorted.\n \n Returns:\n list: The sorted list.\n \"\"\"\n \n def flip(arr, i):\n \"\"\"\n Flip the array from the start to the specified index.\n \"\"\"\n start = 0\n while start < i:\n temp = arr[start]\n arr[start] = arr[i]\n arr[i] = temp\n start += 1\n i -= 1\n\n def find_max(arr, n):\n \"\"\"\n Find the index of the maximum element in the array.\n \"\"\"\n mi = 0\n for i in range(0, n):\n if arr[i] > arr[mi]:\n mi = i\n return mi\n \n n = len(arr)\n curr_size = n\n \n while curr_size > 1:\n mi = find_max(arr, curr_size)\n if mi != curr_size-1:\n # To move the maximum element at the end, first move it to the beginning\n flip(arr, mi)\n # Now move the maximum element to its correct position\n flip(arr, curr_size-1)\n curr_size -= 1\n \n return arr", "matching_cluster_idx": 2}]}, "Mbpp/166": {"dps": 18.159999999999997, "dps_norm": 26.25, "pass@1": 93.0, "profiled": [{"solution": "def find_even_pair(arr):\n def is_even(num):\n # Check if the XOR of two numbers is even\n return num & 1 == 0\n \n count = 0\n # Iterate through each possible pair in the list\n for i in range(len(arr)):\n for j in range(i + 1, len(arr)):\n # If the XOR of the pair is even, increment the count\n if is_even(arr[i] ^ arr[j]):\n count += 1\n \n return count", "matching_cluster_idx": -1}, {"solution": "def find_even_pair(arr):\n def is_even(x):\n # Check if the number is even by using the mod operator\n return x % 2 == 0\n \n count = 0\n # Iterate through the list to find pairs\n for i in range(len(arr)):\n for j in range(i + 1, len(arr)):\n # Check if the XOR of the pair is even\n if is_even(arr[i] ^ arr[j]):\n count += 1\n return count", "matching_cluster_idx": 0}, {"solution": "def find_even_pair(arr):\n def is_even(x):\n # Check if the xor of two numbers is even\n return x % 2 == 0\n \n count = 0\n # Iterate through each pair of numbers in the array\n for i in range(len(arr)):\n for j in range(i + 1, len(arr)):\n # Check if the xor of the pair is even\n if is_even(arr[i] ^ arr[j]):\n count += 1\n return count", "matching_cluster_idx": 0}, {"solution": "def find_even_pair(arr):\n def is_even(num):\n # Check if the result of XOR is even by using the property that even ^ even = even and odd ^ odd = even\n return num % 2 == 0\n \n count = 0\n # Iterate through the array and count pairs with even XOR result\n for i in range(len(arr)):\n for j in range(i + 1, len(arr)):\n if is_even(arr[i] ^ arr[j]):\n count += 1\n return count", "matching_cluster_idx": 0}, {"solution": "def find_even_pair(nums):\n def is_even(n):\n # Check if a number is even using bitwise AND\n return (n & 1) == 0\n \n count = 0\n # Iterate through the list to find pairs\n for i in range(len(nums)):\n for j in range(i + 1, len(nums)):\n # Calculate XOR and check if it is even\n if is_even(nums[i] ^ nums[j]):\n count += 1\n \n return count", "matching_cluster_idx": -1}, {"solution": "def find_even_pair(nums):\n def is_even(num):\n # Check if the XOR of two numbers is even\n return num % 2 == 0\n \n count = 0\n # Iterate through the list to find all pairs\n for i in range(len(nums)):\n for j in range(i + 1, len(nums)):\n # Check if the XOR of the pair is even\n if is_even(nums[i] ^ nums[j]):\n count += 1\n return count", "matching_cluster_idx": 0}, {"solution": "def find_even_pair(arr):\n def is_even(num):\n # Check if the XOR of two numbers is even\n return num % 2 == 0\n \n count = 0\n # Iterate through the array to find pairs\n for i in range(len(arr)):\n for j in range(i + 1, len(arr)):\n if is_even(arr[i] ^ arr[j]):\n count += 1\n return count", "matching_cluster_idx": 0}, {"solution": "def find_even_pair(nums):\n # Initialize counter for even xor pairs\n even_xor_pairs = 0\n \n # Iterate through each pair of numbers in the list\n for i in range(len(nums)):\n for j in range(i + 1, len(nums)):\n # Calculate XOR and check if result is even\n if (nums[i] ^ nums[j]) % 2 == 0:\n even_xor_pairs += 1\n \n return even_xor_pairs", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(arr):\n def is_even(num):\n # Check if the XOR of two numbers is even\n return num % 2 == 0\n \n count = 0\n # Iterate through each pair of elements in the array\n for i in range(len(arr)):\n for j in range(i + 1, len(arr)):\n # Check if the XOR of the pair is even\n if is_even(arr[i] ^ arr[j]):\n count += 1\n \n return count", "matching_cluster_idx": 0}, {"solution": "def find_even_pair(lst):\n # Initialize the count of pairs that xor to an even number\n count = 0\n \n # Iterate through each pair of elements in the list\n for i in range(len(lst)):\n for j in range(i + 1, len(lst)):\n # Check if the xor of the pair is even\n if (lst[i] ^ lst[j]) % 2 == 0:\n # Increment the count if the condition is met\n count += 1\n \n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(lst):\n def is_even(x):\n # Check if the xor result of two numbers is even\n return x % 2 == 0\n \n count = 0\n # Iterate through the list and count pairs with an even xor result\n for i in range(len(lst)):\n for j in range(i + 1, len(lst)):\n if is_even(lst[i] ^ lst[j]):\n count += 1\n \n return count", "matching_cluster_idx": 0}, {"solution": "def find_even_pair(arr):\n def is_even(num):\n # Check if the XOR result is even\n return (num & 1) == 0\n \n count = 0\n # Iterate through the list and count pairs with even XOR\n for i in range(len(arr)):\n for j in range(i + 1, len(arr)):\n if is_even(arr[i] ^ arr[j]):\n count += 1\n \n return count", "matching_cluster_idx": -1}, {"solution": "def find_even_pair(lst):\n # Count of numbers that are even when XORed with any other number\n even_count = 0\n # Count of numbers that are odd when XORed with any other number\n odd_count = 0\n \n # Iterate over each number in the list\n for num in lst:\n # Check if the number is even by comparing it to itself XORed with 1\n if num ^ 1 == num + 1:\n # If even, increment the even count\n even_count += 1\n else:\n # If odd, increment the odd count\n odd_count += 1\n \n # The total number of even XOR pairs is the sum of all possible pairs within even and odd groups\n return even_count * (even_count - 1) // 2 + odd_count * (odd_count - 1) // 2", "matching_cluster_idx": 2}, {"solution": "def find_even_pair(arr):\n def is_even(x):\n # Check if the xor of two numbers is even\n return x % 2 == 0\n \n count = 0\n # Iterate through the list to count pairs with even xor\n for i in range(len(arr)):\n for j in range(i + 1, len(arr)):\n if is_even(arr[i] ^ arr[j]):\n count += 1\n \n return count", "matching_cluster_idx": 0}, {"solution": "def find_even_pair(arr):\n def is_even(x):\n # Check if the XOR of two numbers is even\n return x % 2 == 0\n \n count = 0\n # Iterate through each pair in the array\n for i in range(len(arr)):\n for j in range(i + 1, len(arr)):\n # If the XOR of the pair is even, increment the count\n if is_even(arr[i] ^ arr[j]):\n count += 1\n return count", "matching_cluster_idx": 0}, {"solution": "def find_even_pair(arr):\n def is_even(x):\n # Check if the XOR of two numbers is even\n return x % 2 == 0\n \n count = 0\n # Iterate through the array and count pairs that xor to an even number\n for i in range(len(arr)):\n for j in range(i + 1, len(arr)):\n if is_even(arr[i] ^ arr[j]):\n count += 1\n \n return count", "matching_cluster_idx": 0}, {"solution": "def find_even_pair(nums):\n def is_even(x):\n # Check if the xor of two numbers is even\n return x % 2 == 0\n \n count = 0\n for i in range(len(nums)):\n for j in range(i + 1, len(nums)):\n # Increment count if the xor of nums[i] and nums[j] is even\n if is_even(nums[i] ^ nums[j]):\n count += 1\n \n return count", "matching_cluster_idx": 0}, {"solution": "def find_even_pair(lst):\n def is_even(num):\n return num % 2 == 0\n \n count = 0\n # Iterate through each possible pair in the list\n for i in range(len(lst)):\n for j in range(i + 1, len(lst)):\n # Increment count if the XOR of the pair is even\n if is_even(lst[i] ^ lst[j]):\n count += 1\n return count", "matching_cluster_idx": 0}, {"solution": "def find_even_pair(arr):\n def is_even(x):\n # Check if a number is even using XOR operation\n return x % 2 == 0\n \n count = 0\n # Loop through each pair of numbers in the list\n for i in range(len(arr)):\n for j in range(i + 1, len(arr)):\n # Check if the XOR of the pair is even\n if is_even(arr[i] ^ arr[j]):\n count += 1\n return count", "matching_cluster_idx": 0}, {"solution": "def find_even_pair(arr):\n def is_xor_even(x, y):\n # Check if the xor of two numbers is even\n return (x ^ y) % 2 == 0\n \n count = 0\n # Iterate through each pair in the list\n for i in range(len(arr)):\n for j in range(i + 1, len(arr)):\n # Increase count if the xor of the pair is even\n if is_xor_even(arr[i], arr[j]):\n count += 1\n return count", "matching_cluster_idx": 0}]}, "Mbpp/170": {"dps": 64.71014492753623, "dps_norm": 91.875, "pass@1": 75.0, "profiled": [{"solution": "def sum_range_list(nums, start_idx, end_idx):\n \"\"\"\n Find the sum of numbers in a list within a range specified by two indices.\n \n Parameters:\n - nums: List of integers\n - start_idx: Start index of the range (inclusive)\n - end_idx: End index of the range (inclusive)\n \n Returns:\n - The sum of the numbers in the specified range\n \"\"\"\n # Ensure the indices are within the bounds of the list\n if start_idx < 0 or end_idx >= len(nums):\n raise IndexError(\"The start or end index is out of bounds.\")\n \n # Sum the range of numbers from start_idx to end_idx, inclusive\n return sum(nums[start_idx:end_idx+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(nums, start_index, end_index):\n \"\"\"\n Finds the sum of numbers in the list within the range specified by start_index and end_index (inclusive).\n \n :param nums: List of numbers\n :param start_index: Starting index of the range\n :param end_index: Ending index of the range\n :return: Sum of the numbers within the specified range\n \"\"\"\n # Calculate the sum of numbers in the specified range\n return sum(nums[start_index:end_index + 1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(nums, start_idx, end_idx):\n # Calculate the sum of elements from start_idx to end_idx (inclusive)\n return sum(nums[start_idx:end_idx + 1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(nums, start_index, end_index):\n \"\"\"\n Finds the sum of numbers in the list within the range specified by start_index and end_index.\n \n :param nums: List of numbers\n :param start_index: Starting index of the range (inclusive)\n :param end_index: Ending index of the range (inclusive)\n :return: Sum of the elements within the specified range\n \"\"\"\n # Ensure the indices are within the list bounds\n start_index = max(0, start_index)\n end_index = min(len(nums) - 1, end_index)\n \n # Compute the sum of the specified range\n return sum(nums[start_index:end_index + 1])", "matching_cluster_idx": 6}, {"solution": "def sum_range_list(nums, start_index, end_index):\n \"\"\"\n Calculate the sum of elements in the list nums from start_index to end_index (inclusive).\n \n :param nums: List of integers.\n :param start_index: Starting index for the range (inclusive).\n :param end_index: Ending index for the range (inclusive).\n :return: Sum of elements in the specified range.\n \"\"\"\n # Check if the input indices are within the bounds of the list\n if start_index < 0 or end_index >= len(nums):\n raise ValueError(\"The provided indices are out of bounds.\")\n \n # Calculate the sum of the specified range\n total_sum = sum(nums[start_index:end_index+1])\n return total_sum", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(nums, start_index, end_index):\n \"\"\"\n Calculate the sum of elements in the list nums within the range specified by start_index and end_index.\n \n :param nums: List of integers\n :param start_index: Start index of the range (inclusive)\n :param end_index: End index of the range (inclusive)\n :return: Sum of the numbers within the specified range\n \"\"\"\n # Ensure start_index is non-negative and end_index does not exceed list size\n start_index = max(0, start_index)\n end_index = min(len(nums) - 1, end_index)\n \n # Calculate and return the sum of the specified range\n return sum(nums[start_index:end_index + 1])", "matching_cluster_idx": 6}, {"solution": "def sum_range_list(nums, start_index, end_index):\n # Calculate the sum of elements from start_index to end_index (inclusive)\n return sum(nums[start_index:end_index+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(lst, start_index, end_index):\n \"\"\"\n Calculates the sum of elements in the list 'lst' from 'start_index' (inclusive) to 'end_index' (inclusive).\n \n Parameters:\n lst (list): The input list of numbers.\n start_index (int): The starting index in the list (inclusive).\n end_index (int): The ending index in the list (inclusive).\n \n Returns:\n int: The sum of elements within the specified range.\n \"\"\"\n \n # Calculate the sum of elements from start_index to end_index\n total_sum = sum(lst[start_index:end_index+1])\n return total_sum", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(lst, start_idx, end_idx):\n \"\"\"\n Calculate the sum of elements in the list from start_idx to end_idx (inclusive).\n \n :param lst: List of integers.\n :param start_idx: Start index for the sum range.\n :param end_idx: End index for the sum range.\n :return: Sum of the elements within the specified range.\n \"\"\"\n # Ensure the start index is non-negative\n start_idx = max(start_idx, 0)\n # Ensure the end index does not exceed the list length\n end_idx = min(end_idx, len(lst) - 1)\n \n # Calculate and return the sum of the specified range\n return sum(lst[start_idx:end_idx + 1])", "matching_cluster_idx": 6}, {"solution": "def sum_range_list(nums, start_idx, end_idx):\n # Ensure the start index is not negative and the end index is within bounds\n start_idx = max(0, start_idx)\n end_idx = min(len(nums) - 1, end_idx)\n \n # Calculate and return the sum of elements in the specified range\n return sum(nums[start_idx:end_idx+1])", "matching_cluster_idx": 6}, {"solution": "def sum_range_list(nums, start_idx, end_idx):\n \"\"\"\n Calculate the sum of elements in the list `nums` within the range specified by `start_idx` and `end_idx`.\n \n Parameters:\n nums (list): The list of numbers.\n start_idx (int): The starting index of the range (inclusive).\n end_idx (int): The ending index of the range (inclusive).\n \n Returns:\n int: The sum of the specified range elements.\n \"\"\"\n \n # Slice the list to get the specified range and calculate the sum\n return sum(nums[start_idx:end_idx+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(nums, start_index, end_index):\n \"\"\"\n Calculate the sum of numbers in the list nums that fall within the specified range.\n \n Parameters:\n nums (list): The list of numbers.\n start_index (int): The starting index of the range (inclusive).\n end_index (int): The ending index of the range (inclusive).\n \n Returns:\n int: The sum of numbers within the specified range.\n \"\"\"\n # Ensure that the indices are within the list boundaries\n if start_index < 0:\n start_index = 0\n if end_index >= len(nums):\n end_index = len(nums) - 1\n \n # Calculate the sum using list slicing\n return sum(nums[start_index:end_index+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(nums, start_index, end_index):\n \"\"\"\n Calculate the sum of numbers in a list within a range specified by two indices.\n \n :param nums: List of integers.\n :param start_index: Start index of the range.\n :param end_index: End index of the range.\n :return: Sum of numbers within the specified range.\n \"\"\"\n # Ensure the start index is not negative and the end index does not exceed the list length\n start_index = max(0, start_index)\n end_index = min(len(nums), end_index + 1) # +1 to make end_index inclusive\n \n # Slice the list based on the adjusted start and end indices\n sublist = nums[start_index:end_index]\n \n # Return the sum of the sliced list\n return sum(sublist)", "matching_cluster_idx": 6}, {"solution": "def sum_range_list(nums, start, end):\n \"\"\"\n Calculate the sum of elements in the list nums from start to end indices.\n \n :param nums: List of integers.\n :param start: Starting index.\n :param end: Ending index.\n :return: Sum of elements in the specified range.\n \"\"\"\n # Ensure the indices are within the bounds of the list\n start = max(0, start)\n end = min(len(nums) - 1, end)\n \n # Calculate and return the sum of the specified range\n return sum(nums[start:end + 1])", "matching_cluster_idx": 6}, {"solution": "def sum_range_list(nums, start_index, end_index):\n \"\"\"\n Calculate the sum of numbers in the list nums from start_index to end_index (inclusive).\n\n :param nums: List of integers.\n :param start_index: Start index for sum calculation (inclusive).\n :param end_index: End index for sum calculation (inclusive).\n :return: Sum of numbers within the specified range.\n \"\"\"\n # Ensure indices are within the bounds of the list\n start_index = max(0, start_index)\n end_index = min(len(nums) - 1, end_index)\n \n # Calculate and return the sum of the specified range\n return sum(nums[start_index:end_index + 1])", "matching_cluster_idx": 6}, {"solution": "def sum_range_list(nums, start_index, end_index):\n \"\"\"\n Calculates the sum of elements in the list nums from start_index (inclusive) to end_index (inclusive).\n \n :param nums: List of integers.\n :param start_index: Starting index of the range.\n :param end_index: Ending index of the range.\n :return: Sum of the specified range in the list.\n \"\"\"\n # Ensuring start_index and end_index are within the bounds of the list\n start_index = max(0, start_index)\n end_index = min(len(nums) - 1, end_index)\n \n # Calculating the sum of the specified range\n total = sum(nums[start_index:end_index+1])\n return total", "matching_cluster_idx": 6}, {"solution": "def sum_range_list(nums, start_idx, end_idx):\n \"\"\"\n Finds the sum of numbers in a list within a range specified by two indices.\n \n Parameters:\n nums (list): The list of numbers.\n start_idx (int): The starting index of the range (inclusive).\n end_idx (int): The ending index of the range (inclusive).\n \n Returns:\n int: The sum of numbers within the specified range.\n \"\"\"\n \n # Ensure the start index is not less than 0\n start_idx = max(start_idx, 0)\n # Ensure the end index is within the list bounds\n end_idx = min(end_idx, len(nums) - 1)\n \n # Slice the list from start_idx to end_idx (inclusive) and sum the elements\n return sum(nums[start_idx:end_idx+1])", "matching_cluster_idx": 6}, {"solution": "def sum_range_list(nums, start_index, end_index):\n \"\"\"\n Finds the sum of numbers in the list within a range specified by start_index and end_index.\n \n :param nums: List of integers.\n :param start_index: Start index of the range (inclusive).\n :param end_index: End index of the range (inclusive).\n :return: Sum of the specified range of numbers.\n \"\"\"\n # Ensure the indices are within the list bounds\n if start_index < 0 or end_index >= len(nums):\n raise IndexError(\"The start or end index is out of the list bounds.\")\n \n # Calculate the sum using list slicing\n return sum(nums[start_index:end_index+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(nums, start_idx, end_idx):\n \"\"\"\n Calculate the sum of numbers in the list from start_idx to end_idx, inclusive.\n \n :param nums: List of integers\n :param start_idx: Start index for the range (inclusive)\n :param end_idx: End index for the range (inclusive)\n :return: Sum of the specified range in the list\n \"\"\"\n # Ensure the indices are within the list bounds\n if start_idx < 0 or end_idx >= len(nums):\n return \"Indices out of bounds\"\n \n # Initialize sum to 0\n range_sum = 0\n \n # Calculate the sum from start_idx to end_idx, inclusive\n for i in range(start_idx, end_idx + 1):\n range_sum += nums[i]\n \n return range_sum", "matching_cluster_idx": 4}, {"solution": "def sum_range_list(nums, start_index, end_index):\n \"\"\"\n Calculate the sum of numbers in the list nums between the start_index and end_index (inclusive).\n \n :param nums: List of numbers\n :param start_index: Start index of the range\n :param end_index: End index of the range\n :return: Sum of the numbers within the specified range\n \"\"\"\n # Ensure the start index is non-negative\n start_index = max(0, start_index)\n \n # Ensure the end index does not exceed the length of the list minus one\n end_index = min(len(nums) - 1, end_index)\n \n # Calculate the sum of the sublist from start_index to end_index + 1 (to make it inclusive)\n return sum(nums[start_index:end_index + 1])", "matching_cluster_idx": 6}]}, "Mbpp/226": {"dps": 77.01550387596899, "dps_norm": 37.857142857142854, "pass@1": 99.0, "profiled": [{"solution": "def odd_values_string(s):\n result = \"\"\n for i in range(len(s)):\n # If the index is even, append the character to the result string\n if i % 2 == 0:\n result += s[i]\n return result", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(input_string):\n # Using list comprehension to iterate through string indices\n # and selecting only characters at even indices (considering the first character index as 0)\n result = ''.join([char for index, char in enumerate(input_string) if index % 2 == 0])\n return result", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(input_string):\n result = ''\n # Iterate through the string, starting from index 0\n for index in range(len(input_string)):\n # Check if the current index is even\n if index % 2 == 0:\n result += input_string[index]\n return result", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(s):\n # Use string slicing to get even indexed characters\n return s[::2]", "matching_cluster_idx": 6}, {"solution": "def odd_values_string(input_string):\n result = \"\"\n # Iterate through the string and pick characters at even indices\n for index in range(0, len(input_string), 2):\n result += input_string[index]\n return result", "matching_cluster_idx": 2}, {"solution": "def odd_values_string(input_string):\n # Initialize an empty string to store the result\n result = ''\n \n # Iterate over the string using index\n for index in range(len(input_string)):\n # Check if the index is even\n if index % 2 == 0:\n # Append the character at even index to the result\n result += input_string[index]\n \n return result", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(input_string):\n \"\"\"\n Function to remove characters at odd index values from the given string.\n \n Parameters:\n input_string (str): The string from which to remove characters at odd indices.\n \n Returns:\n str: A new string with characters at odd indices removed.\n \"\"\"\n # Initialize an empty string to hold characters at even indices\n result_string = ''\n \n # Loop through the string using index and only add characters at even indices\n for index in range(len(input_string)):\n if index % 2 == 0:\n result_string += input_string[index]\n \n return result_string", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(input_string):\n result = \"\"\n # Loop through the string, starting from index 0\n for index in range(len(input_string)):\n # Append characters with even index values to the result\n if index % 2 == 0:\n result += input_string[index]\n return result", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(s):\n result = \"\"\n for i, char in enumerate(s):\n if i % 2 == 0:\n result += char\n return result", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(input_string):\n \"\"\"\n Removes characters at odd index positions from the input string.\n \n Parameters:\n input_string (str): The string from which odd index characters will be removed.\n \n Returns:\n str: A new string with characters at odd index positions removed.\n \"\"\"\n # Using list comprehension to iterate only through even index positions (0-based indexing)\n result = input_string[::2]\n return result", "matching_cluster_idx": 5}, {"solution": "def odd_values_string(input_string):\n result = \"\"\n for index in range(len(input_string)):\n # Check if index is even to keep the character (0-based index)\n if index % 2 == 0:\n result += input_string[index]\n return result", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(input_string):\n # Use list comprehension to iterate through the string and select characters at even index positions\n result = ''.join([input_string[i] for i in range(len(input_string)) if i % 2 == 0])\n return result", "matching_cluster_idx": 1}, {"solution": "def odd_values_string(input_string):\n \"\"\"\n Removes characters at odd indices from the input string.\n \n Parameters:\n input_string (str): The string from which to remove odd-indexed characters.\n \n Returns:\n str: A new string with characters at odd indices removed.\n \"\"\"\n # Initialize an empty string to store the result\n result = ''\n \n # Iterate over the string using enumerate to get both index and character\n for index, char in enumerate(input_string):\n # Check if the index is even\n if index % 2 == 0:\n # Append the character to the result string\n result += char\n \n return result", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(input_string):\n \"\"\"\n This function takes a string as input and returns a new string after removing characters at odd indices.\n \n Args:\n input_string (str): The string from which characters at odd indices will be removed.\n \n Returns:\n str: The resulting string after removal of characters at odd indices.\n \"\"\"\n # Initialize an empty string to store the result\n result = ''\n \n # Iterate over the string, considering only even indices (which become odd in 0-indexed system after filtering)\n for index in range(0, len(input_string), 2):\n result += input_string[index]\n \n return result", "matching_cluster_idx": 1}, {"solution": "def odd_values_string(input_string):\n \"\"\"\n Removes characters which have odd index values from a given string.\n \n Parameters:\n input_string (str): The string from which characters at odd indices will be removed.\n \n Returns:\n str: The modified string with characters at odd indices removed.\n \"\"\"\n # Use string slicing to get characters at even indices\n return input_string[::2]", "matching_cluster_idx": 6}, {"solution": "def odd_values_string(input_string):\n \"\"\"\n Removes characters which have odd index values from a given string.\n \n Parameters:\n input_string (str): The string from which odd index characters are to be removed.\n \n Returns:\n str: A new string with characters at odd indices removed from the original string.\n \"\"\"\n # Using string slicing to get characters at even indices (0, 2, 4, ...)\n return input_string[::2]", "matching_cluster_idx": 6}, {"solution": "def odd_values_string(input_string):\n result = \"\"\n # Loop through the string with index\n for index, character in enumerate(input_string):\n # Check if the index is even (considering 0 as even)\n if index % 2 == 0:\n result += character\n return result", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(s):\n result = ''\n for i, char in enumerate(s):\n if i % 2 == 0:\n result += char\n return result", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(input_string):\n \"\"\"\n Remove characters from a string that have odd index values.\n \n Args:\n input_string (str): The string from which to remove characters at odd indices.\n \n Returns:\n str: A new string with characters at odd indices removed.\n \"\"\"\n # Using string slicing to keep even index characters\n return input_string[::2]", "matching_cluster_idx": 6}, {"solution": "def odd_values_string(input_string):\n \"\"\"\n This function takes a string as input and returns a new string with all characters at odd index positions removed.\n \n Args:\n input_string (str): The string from which odd-indexed characters will be removed.\n \n Returns:\n str: A new string with characters at odd index positions removed.\n \"\"\"\n result_string = \"\"\n for index in range(len(input_string)):\n if index % 2 == 0:\n result_string += input_string[index]\n return result_string", "matching_cluster_idx": 0}]}, "Mbpp/230": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def replace_blank(string, replacement_char):\n # Replace all blank spaces with the given replacement character\n modified_string = string.replace(' ', replacement_char)\n return modified_string", "matching_cluster_idx": 7}, {"solution": "def replace_blank(string, replacement):\n \"\"\"\n Replaces all blank spaces in the input string with the specified replacement character.\n \n Parameters:\n string (str): The original string containing spaces.\n replacement (str): The character used to replace blank spaces.\n \n Returns:\n str: The modified string with blank spaces replaced.\n \"\"\"\n return string.replace(' ', replacement)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(string, char):\n \"\"\"\n Replaces all blank spaces in a given string with a specified character and returns the modified string.\n \n Parameters:\n string (str): The original string that may contain blank spaces.\n char (str): The character used to replace the blank spaces.\n \n Returns:\n str: The modified string with blank spaces replaced.\n \"\"\"\n # Replacing all blank spaces in the string with the given character\n modified_string = string.replace(' ', char)\n return modified_string", "matching_cluster_idx": 7}, {"solution": "def replace_blank(string, char):\n \"\"\"\n Replaces all blank spaces in the input string with the specified character.\n \n Parameters:\n string (str): The string in which to replace blank spaces.\n char (str): The character to replace the blank spaces with.\n \n Returns:\n str: The modified string with blank spaces replaced by the character.\n \"\"\"\n return string.replace(\" \", char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(string, replacement_char):\n \"\"\"\n Replaces all blank spaces in the given string with the specified replacement character.\n \n Parameters:\n string (str): The original string containing spaces.\n replacement_char (str): The character used to replace spaces.\n \n Returns:\n str: The modified string with spaces replaced by the specified character.\n \"\"\"\n return string.replace(' ', replacement_char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(string, char):\n \"\"\"\n Replaces all blank spaces in the given string with the specified character.\n \n Parameters:\n string (str): The original string containing spaces.\n char (str): The character used to replace blank spaces.\n \n Returns:\n str: The modified string with spaces replaced.\n \"\"\"\n return string.replace(' ', char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(string, replacement_char):\n \"\"\"\n Replaces all blank spaces in the given string with the specified character.\n \n Parameters:\n - string: The original string with spaces.\n - replacement_char: The character to replace the spaces with.\n \n Returns:\n - A new string with spaces replaced.\n \"\"\"\n return string.replace(' ', replacement_char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(s, char):\n \"\"\"\n Replaces all blank spaces in the string 's' with the character 'char' and returns the modified string.\n \n Parameters:\n s (str): The input string with blank spaces.\n char (str): The character to replace the blank spaces with.\n \n Returns:\n str: The modified string with blank spaces replaced.\n \"\"\"\n return s.replace(' ', char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(string, char):\n \"\"\"\n Replaces all blank spaces in the input string with the specified character.\n\n Parameters:\n - string: The input string containing spaces to be replaced.\n - char: The character used to replace all blank spaces in the input string.\n\n Returns:\n - A new string with all blank spaces replaced by the specified character.\n \"\"\"\n # Replace all blank spaces (' ') in the string with the specified character\n modified_string = string.replace(' ', char)\n return modified_string", "matching_cluster_idx": 7}, {"solution": "def replace_blank(string, replacement_char):\n \"\"\"\n Replaces all blank spaces in the input string with the specified replacement character.\n \n Args:\n string (str): The input string with potential blank spaces.\n replacement_char (str): The character to replace the blank spaces with.\n \n Returns:\n str: The modified string with blank spaces replaced by the replacement character.\n \"\"\"\n # Use str.replace method to replace all occurrences of ' ' with replacement_char\n return string.replace(' ', replacement_char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(string, character):\n # Replace all blank spaces with the specified character\n result = string.replace(' ', character)\n return result", "matching_cluster_idx": 7}, {"solution": "def replace_blank(s, replacement_char):\n # Replace all blank spaces with the specified character\n modified_string = s.replace(' ', replacement_char)\n return modified_string", "matching_cluster_idx": 7}, {"solution": "def replace_blank(string, replacement_char):\n \"\"\"\n Replaces all blank spaces in the input string with the specified replacement character.\n \n Parameters:\n - string: The original string containing spaces to be replaced.\n - replacement_char: The character to replace the blank spaces with.\n \n Returns:\n - A new string with blank spaces replaced by the specified character.\n \"\"\"\n # Using the replace method of the string to replace spaces\n modified_string = string.replace(' ', replacement_char)\n return modified_string", "matching_cluster_idx": 7}, {"solution": "def replace_blank(string, char):\n \"\"\"\n Replaces blank spaces in the input string with the specified character and returns the modified string.\n \n Parameters:\n string (str): The input string which may contain blank spaces.\n char (str): The character used to replace the blank spaces in the input string.\n \n Returns:\n str: The modified string with blank spaces replaced by the specified character.\n \"\"\"\n return string.replace(\" \", char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(s, replace_with):\n # Replace spaces in the string with the given character\n modified_string = s.replace(' ', replace_with)\n return modified_string", "matching_cluster_idx": 7}, {"solution": "def replace_blank(s, c):\n \"\"\"\n Replaces all blank spaces in the input string with the provided character.\n \n Parameters:\n s (str): The original string containing spaces to be replaced.\n c (str): The character used to replace the spaces.\n \n Returns:\n str: The modified string with spaces replaced by the character.\n \"\"\"\n return s.replace(' ', c)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(s, char):\n \"\"\"\n Replaces blank spaces in the input string with a given character.\n \n Parameters:\n s (str): The input string containing spaces.\n char (str): The character used to replace spaces.\n \n Returns:\n str: The resulting string after replacing spaces.\n \"\"\"\n return s.replace(' ', char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(string, char):\n \"\"\"\n Replaces all blank spaces in the input string with a specified character.\n \n Parameters:\n string (str): The input string containing spaces to be replaced.\n char (str): The character used for replacing blank spaces.\n \n Returns:\n str: The modified string with spaces replaced by the specified character.\n \"\"\"\n # Replace blank spaces with the specified character\n modified_string = string.replace(\" \", char)\n return modified_string", "matching_cluster_idx": 7}, {"solution": "def replace_blank(string, char):\n \"\"\"\n Replaces blank spaces in the input string with the specified character.\n \n Parameters:\n string (str): The input string containing blank spaces.\n char (str): The character to replace blank spaces with.\n \n Returns:\n str: The modified string with blank spaces replaced by the specified character.\n \"\"\"\n # Replace all occurrences of a blank space in the string with the specified character\n modified_string = string.replace(' ', char)\n return modified_string", "matching_cluster_idx": 7}, {"solution": "def replace_blank(string, char):\n \"\"\"\n Replaces all blank spaces in the input string with a specified character.\n \n Parameters:\n string (str): The string to process.\n char (str): The character to replace blank spaces with.\n \n Returns:\n str: The modified string with all blank spaces replaced.\n \"\"\"\n # Replace all occurrences of blank spaces with the specified character\n modified_string = string.replace(\" \", char)\n return modified_string", "matching_cluster_idx": 7}]}, "Mbpp/239": {"dps": 71.03448275862068, "dps_norm": 75.0, "pass@1": 23.0, "profiled": [{"solution": "def get_total_number_of_sequences(m, n):\n # Base case: Only one way to form a sequence of length 1\n if n == 1:\n return m\n \n # Initialize a table to store results of subproblems\n dp = [[0 for _ in range(m + 1)] for _ in range(n + 1)]\n \n # Fill dp table where dp[i][j] represents the number of sequences of length i with max element j\n for i in range(1, n + 1):\n for j in range(1, m + 1):\n if i == 1:\n dp[i][j] = j\n else:\n dp[i][j] = dp[i][j - 1] + dp[i - 1][j // 2]\n \n # The answer is the sum of sequences of length n with max element up to m\n return dp[n][m]", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n # Initialize a 2D list to store the number of ways to form sequences ending with a given value\n dp = [[0 for _ in range(n + 1)] for _ in range(m + 1)]\n \n # There is exactly one way to form a sequence of length 1, which is just the number itself\n for i in range(1, m + 1):\n dp[i][1] = 1\n \n # Fill the dp table\n for length in range(2, n + 1):\n for value in range(m + 1):\n for prev_value in range(1, value // 2 + 1):\n dp[value][length] += dp[prev_value][length - 1]\n \n # The answer is the sum of ways to form sequences of length n ending with any value from 1 to m\n return sum(dp[value][n] for value in range(1, m + 1))", "matching_cluster_idx": 6}, {"solution": "def get_total_number_of_sequences(m, n):\n \"\"\"\n Finds the number of possible sequences of length n, such that each element is a positive integer,\n greater than or equal to twice the previous element but less than or equal to m.\n \n Parameters:\n m (int): The maximum value an element in the sequence can take.\n n (int): The length of the sequence.\n \n Returns:\n int: The number of possible sequences.\n \"\"\"\n \n # Initialize a table to store results of subproblems\n dp = [[0 for x in range(n+1)] for y in range(m+1)]\n \n # We can form a sequence of length 1 with numbers from 1 to m\n for i in range(1, m+1):\n dp[i][1] = 1\n \n # Fill dp table\n for i in range(1, m+1):\n for j in range(2, n+1):\n for k in range(1, (i//2) + 1):\n dp[i][j] += dp[k][j-1]\n \n # Summing up all possibilities to form a sequence of length n\n total_sequences = 0\n for i in range(1, m+1):\n total_sequences += dp[i][n]\n \n return total_sequences", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n # Base case: if n is 1, there are m possible sequences (each number from 1 to m)\n if n == 1:\n return m\n \n # Initialize a 2D array to store subproblem results\n dp = [[0 for _ in range(n + 1)] for _ in range(m + 1)]\n \n # There's only one way to form a sequence of length 1 with a single number from 1 to m\n for i in range(1, m + 1):\n dp[i][1] = 1\n \n # Fill the dp table\n for length in range(2, n + 1):\n for num in range(1, m + 1):\n for prev_num in range(1, num // 2 + 1):\n dp[num][length] += dp[prev_num][length - 1]\n \n # Sum up all ways to form a sequence of length n ending with any number from 1 to m\n total_sequences = sum(dp[i][n] for i in range(1, m + 1))\n return total_sequences", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n # Initialize a DP table with zeros\n dp = [[0 for _ in range(m + 1)] for _ in range(n + 1)]\n \n # A sequence of length 1 can end with any number from 1 to m\n for i in range(1, m + 1):\n dp[1][i] = 1\n \n # Fill the DP table\n for i in range(2, n + 1):\n for j in range(1, m + 1):\n for k in range(1, j // 2 + 1):\n dp[i][j] += dp[i - 1][k]\n \n # The result is the sum of all ways to end a sequence of length n\n return sum(dp[n])", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n def backtrack(start, n):\n # Base case: when the sequence length is 0, only one sequence is possible, the empty sequence\n if n == 0:\n return 1\n count = 0\n # Iterate through possible values starting from 'start' to 'm'\n for i in range(start, m + 1):\n # Recur with the next possible value, which is at least twice the current value\n count += backtrack(i * 2, n - 1)\n return count\n \n # Start backtracking from 1, as the smallest positive integer is 1\n return backtrack(1, n)", "matching_cluster_idx": 5}, {"solution": "def get_total_number_of_sequences(m, n):\n \"\"\"\n Finds the number of possible sequences of length n, where each element is a positive integer\n and is greater than or equal to twice the previous element but less than or equal to m.\n \n Parameters:\n m (int): The maximum value an element in the sequence can take.\n n (int): The length of the sequence.\n \n Returns:\n int: The number of possible sequences.\n \"\"\"\n \n # Initialize the dp array to store the number of sequences ending with a certain value\n dp = [0] * (m + 1)\n \n # There's only one way to form a sequence of length 1 with a single element k: the sequence [k]\n for k in range(1, m + 1):\n dp[k] = 1\n \n # For each additional position in the sequence, update the dp array\n for _ in range(2, n + 1):\n new_dp = [0] * (m + 1)\n for k in range(1, m + 1):\n for prev in range(1, k // 2 + 1):\n new_dp[k] += dp[prev]\n dp = new_dp\n \n # Sum up all the ways to form a sequence of length n ending with any value from 1 to m\n return sum(dp)", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n \"\"\"\n Calculates the total number of sequences of length n where each element is a positive integer,\n greater than or equal to twice the previous element and less than or equal to m.\n \n Args:\n m (int): The maximum allowed value for sequence elements.\n n (int): The length of the sequence.\n \n Returns:\n int: The total number of valid sequences.\n \"\"\"\n \n # Initialize a DP table where dp[i][j] will store the number of sequences of length i ending with j.\n dp = [[0 for _ in range(m + 1)] for _ in range(n + 1)]\n \n # For sequences of length 1, each valid number from 1 to m is a valid sequence.\n for num in range(1, m + 1):\n dp[1][num] = 1\n \n # Fill the DP table\n for sequence_length in range(2, n + 1):\n for current_element in range(1, m + 1):\n for previous_element in range(1, (current_element // 2) + 1):\n dp[sequence_length][current_element] += dp[sequence_length - 1][previous_element]\n \n # The answer is the sum of all sequences of length n ending with any number <= m.\n return sum(dp[n])", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n \"\"\"\n Returns the number of possible sequences of length n with the condition that each element is a positive integer\n and is greater than or equal to twice the previous element but less than or equal to m.\n \"\"\"\n # Initialize a DP table with zeros\n dp = [[0 for _ in range(n + 1)] for _ in range(m + 1)]\n \n # There's always one sequence for a sequence of length 1 (i.e., [x] where x can be anything from 1 to m)\n for i in range(1, m + 1):\n dp[i][1] = 1\n \n # Fill the DP table\n for length in range(2, n + 1):\n for current_value in range(m + 1):\n for prev_value in range(1, current_value // 2 + 1):\n dp[current_value][length] += dp[prev_value][length - 1]\n \n # Sum up all possibilities for sequences of length n\n result = sum(dp[i][n] for i in range(1, m + 1))\n return result", "matching_cluster_idx": 6}, {"solution": "def get_total_number_of_sequences(m, n):\n \"\"\"\n Finds the number of possible sequences of length n such that each element is a positive integer,\n greater than or equal to twice the previous element but less than or equal to m.\n \n Parameters:\n m (int): Maximum value an element in the sequence can take.\n n (int): Length of the sequence.\n \n Returns:\n int: Number of possible sequences.\n \"\"\"\n \n # Base case: If n is 1, each element can independently be any value from 1 to m\n if n == 1:\n return m\n \n # Initialize a DP table where dp[i][j] will store the number of sequences of length i ending with j\n dp = [[0 for _ in range(m + 1)] for _ in range(n + 1)]\n \n # If sequence length is 1, all values from 1 to m are valid\n for i in range(1, m + 1):\n dp[1][i] = 1\n \n # Fill the DP table for sequences of length greater than 1\n for i in range(2, n + 1):\n for j in range(1, m + 1):\n for k in range(1, j // 2 + 1):\n dp[i][j] += dp[i - 1][k]\n \n # The answer will be the sum of all entries in the last row, representing all valid sequences of length n\n total_sequences = sum(dp[n])\n return total_sequences", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n # Base case: if n is 1, each number from 1 to m can be a valid sequence\n if n == 1:\n return m\n \n # Initialize a 2D array to store results of subproblems\n dp = [[0 for _ in range(n + 1)] for _ in range(m + 1)]\n \n # For sequences of length 1, all numbers from 1 to m can be the first element\n for i in range(1, m + 1):\n dp[i][1] = 1\n \n # Fill the dp table\n for i in range(1, m + 1):\n for j in range(2, n + 1):\n for k in range(1, (i // 2) + 1):\n dp[i][j] += dp[k][j - 1]\n \n # Sum up all valid sequences of length n\n result = sum(dp[i][n] for i in range(1, m + 1))\n \n return result", "matching_cluster_idx": 6}, {"solution": "def get_total_number_of_sequences(m, n):\n \"\"\"\n Finds the number of possible sequences of length n, where each element is a positive integer\n and is greater than or equal to twice the previous element but less than or equal to m.\n \n Args:\n m : int - the maximum value of elements in the sequences\n n : int - the length of the sequences\n \n Returns:\n int - the total number of possible sequences\n \"\"\"\n \n # Initialize a DP table with zeros\n dp = [[0 for _ in range(n+1)] for _ in range(m+1)]\n \n # Base case initialization, only one way to form a sequence of length 1 with a single number\n for i in range(1, m+1):\n dp[i][1] = 1\n \n # Fill the DP table\n for length in range(2, n+1):\n for max_val in range(m, 1, -1):\n for prev in range(max_val//2, 0, -1):\n dp[max_val][length] += dp[prev][length-1]\n \n # Sum up all ways to form sequences of length n using numbers up to m\n total_sequences = sum(dp[i][n] for i in range(1, m+1))\n \n return total_sequences", "matching_cluster_idx": 6}, {"solution": "def get_total_number_of_sequences(m, n):\n # Base case: If length of sequence is 1, all numbers from 1 to m are valid sequences.\n if n == 1:\n return m\n \n # Initialize a table to store sub-problems results\n dp = [[0 for _ in range(m + 1)] for _ in range(n + 1)]\n \n # Fill dp table where each dp[i][j] represents the number of sequences of length i ending with j\n for i in range(1, m + 1):\n dp[1][i] = 1 # All numbers from 1 to m can be sequences of length 1\n \n for i in range(2, n + 1):\n for j in range(1, m + 1):\n for k in range(1, j // 2 + 1): # j should be at least twice k\n dp[i][j] += dp[i - 1][k]\n \n # The total number of sequences of length n is the sum of sequences ending with any number from 1 to m\n return sum(dp[n])", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n # Initialize the DP table with zeros\n dp = [[0 for _ in range(m + 1)] for _ in range(n + 1)]\n \n # Every sequence of length 1 starts with a number from 1 to m\n for i in range(1, m + 1):\n dp[1][i] = 1\n \n # Fill the DP table\n for length in range(2, n + 1):\n for max_value in range(m + 1):\n for prev_value in range(1, max_value // 2 + 1):\n dp[length][max_value] += dp[length - 1][prev_value]\n \n # Sum up all the valid sequences of length n with the maximum value up to m\n result = sum(dp[n])\n return result", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n # Initialize a DP table with dimensions (n+1) x (m+1) filled with zeros\n dp = [[0] * (m + 1) for _ in range(n + 1)]\n \n # Base case: there's 1 way to form a sequence of length 1 with a single number up to m\n for num in range(1, m + 1):\n dp[1][num] = 1\n \n # Fill the DP table\n for length in range(2, n + 1):\n for current_max in range(m + 1):\n for previous_max in range(1, (current_max // 2) + 1):\n dp[length][current_max] += dp[length - 1][previous_max]\n \n # The answer is the sum of all ways to form a sequence of length n ending with any number from 1 to m\n result = sum(dp[n][num] for num in range(1, m + 1))\n return result", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(max_value, sequence_length):\n # Base case: If the sequence length is 1, each number from 1 to max_value forms a valid sequence.\n if sequence_length == 1:\n return max_value\n \n # Initialize a DP table to store the number of sequences of different lengths up to 'sequence_length'\n # and ending with different maximum values up to 'max_value'.\n dp = [[0 for _ in range(max_value + 1)] for _ in range(sequence_length)]\n \n # For sequences of length 1, all numbers from 1 to max_value are valid.\n for i in range(1, max_value + 1):\n dp[0][i] = 1\n \n # Fill the DP table for sequences of lengths greater than 1.\n for length in range(1, sequence_length):\n total_count = 0\n for max_val in range(1, max_value + 1):\n for prev_val in range(1, (max_val // 2) + 1):\n dp[length][max_val] += dp[length - 1][prev_val]\n total_count += dp[length][max_val]\n \n # The answer is the sum of all possible sequences of the required length ending with any value up to max_value.\n result = sum(dp[sequence_length - 1][max_val] for max_val in range(1, max_value + 1))\n return result", "matching_cluster_idx": 6}, {"solution": "def get_total_number_of_sequences(m, n):\n \"\"\"\n Finds the number of possible sequences of length n, such that each element is a positive integer\n and is greater than or equal to twice the previous element but less than or equal to m.\n \n Parameters:\n m (int): The maximum value an element in the sequence can take.\n n (int): The length of the sequence.\n \n Returns:\n int: The number of possible sequences.\n \"\"\"\n \n # Initialize a DP table where dp[i][j] represents the number of sequences of length j with max element i\n dp = [[0 for _ in range(n + 1)] for _ in range(m + 1)]\n \n # Every positive integer can be a sequence of length 1\n for i in range(1, m + 1):\n dp[i][1] = 1\n \n # Fill the DP table\n for length in range(2, n + 1):\n for max_val in range(m + 1):\n for prev_val in range(1, max((max_val // 2) + 1, 1)):\n if max_val >= prev_val * 2:\n dp[max_val][length] += dp[prev_val][length - 1]\n \n # Sum up all sequences of length n\n result = sum(dp[i][n] for i in range(1, m + 1))\n \n return result", "matching_cluster_idx": 6}, {"solution": "def get_total_number_of_sequences(m, n):\n \"\"\"\n Calculates the number of sequences of length n where each element is a positive integer, \n each element is at least twice the previous element, and less than or equal to m.\n \n Parameters:\n m (int): The maximum value an element in the sequence can have.\n n (int): The length of the sequence.\n \n Returns:\n int: The total number of such sequences.\n \"\"\"\n \n # Base case: If n is 1, the number of sequences is the number of possible elements, i.e., m\n if n == 1:\n return m\n \n # Initialize DP table\n dp = [[0 for _ in range(m + 1)] for _ in range(n + 1)]\n \n # Fill the first column with 1s since there's exactly one sequence of length 1 for each value of m\n for i in range(1, m + 1):\n dp[1][i] = 1\n \n # Fill the DP table\n for length in range(2, n + 1):\n for max_val in range(1, m + 1):\n for prev_val in range(1, max_val // 2 + 1):\n dp[length][max_val] += dp[length - 1][prev_val]\n \n # Sum up all sequences that end with any value from 1 to m\n total_sequences = sum(dp[n])\n \n return total_sequences", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n \"\"\"\n Takes in positive integers m and n and returns the number of possible sequences of length n,\n such that each element is a positive integer and is greater than or equal to twice the previous element but less than or equal to m.\n \"\"\"\n # dp[i][j] represents the number of sequences of length j ending with number i\n dp = [[0 for _ in range(n + 1)] for _ in range(m + 1)]\n \n # Base case: there's one sequence of length 1 for each ending number (1 to m)\n for i in range(1, m + 1):\n dp[i][1] = 1\n \n # Fill dp table\n for length in range(2, n + 1):\n for end in range(1, m + 1):\n for prev in range(1, end // 2 + 1):\n dp[end][length] += dp[prev][length - 1]\n \n # Sum up all the sequences of length n\n return sum(dp[i][n] for i in range(1, m + 1))", "matching_cluster_idx": 6}, {"solution": "def get_total_number_of_sequences(m, n):\n # Base case: If the length of the sequence is 1, the sequence can only have a single number which is <= m\n if n == 1:\n return m\n \n # Initialize a 2D DP table with dimensions n x m+1 to store the total number of sequences\n dp_table = [[0 for _ in range(m + 1)] for _ in range(n)]\n \n # Each sequence of length 1 ending in a number i <= m can only be one sequence long\n for i in range(1, m + 1):\n dp_table[0][i] = 1\n \n # Fill the DP table for sequences of length > 1\n for i in range(1, n):\n for j in range(1, m + 1):\n for k in range(1, j // 2 + 1):\n dp_table[i][j] += dp_table[i - 1][k]\n \n # The answer is the sum of all possible sequences of length n ending in any number <= m\n return sum(dp_table[n - 1][i] for i in range(1, m + 1))", "matching_cluster_idx": 6}]}, "Mbpp/240": {"dps": 94.75609756097562, "dps_norm": 96.66666666666667, "pass@1": 92.0, "profiled": [{"solution": "def replace_list(lst1, lst2):\n # Remove the last element of the first list\n lst1.pop()\n # Extend the first list with all elements of the second list\n lst1.extend(lst2)\n return lst1", "matching_cluster_idx": 8}, {"solution": "def replace_list(lst1, lst2):\n # Remove the last element of lst1 and then extend lst1 with lst2\n lst1[-1:] = lst2\n return lst1", "matching_cluster_idx": 7}, {"solution": "def replace_list(lst1, lst2):\n # Pop the last element from the first list\n lst1.pop()\n # Extend the first list with all elements of the second list\n lst1.extend(lst2)\n return lst1", "matching_cluster_idx": 8}, {"solution": "def replace_list(lst1, lst2):\n # Pop the last element of the first list\n lst1.pop()\n # Extend the first list with all elements of the second list\n lst1.extend(lst2)\n return lst1", "matching_cluster_idx": 8}, {"solution": "def replace_list(lst1, lst2):\n # Extract all elements of lst1 except the last one\n modified_list = lst1[:-1]\n # Append the entire lst2 to the modified list\n modified_list.extend(lst2)\n return modified_list", "matching_cluster_idx": 6}, {"solution": "def replace_list(lst1, lst2):\n # Remove the last element from the first list\n lst1.pop()\n # Extend the first list with the second list\n lst1.extend(lst2)\n return lst1", "matching_cluster_idx": 8}, {"solution": "def replace_list(lst1, lst2):\n \"\"\"\n Replaces the last element of lst1 with all elements of lst2.\n \n Parameters:\n lst1 (list): The original list whose last element is to be replaced.\n lst2 (list): The list whose elements will replace the last element of lst1.\n \n Returns:\n list: A new list with the last element of lst1 replaced by all elements of lst2.\n \"\"\"\n # Remove the last element of lst1\n lst1 = lst1[:-1]\n # Extend lst1 with lst2\n lst1.extend(lst2)\n return lst1", "matching_cluster_idx": 6}, {"solution": "def replace_list(lst1, lst2):\n # Remove the last element of the first list\n lst1.pop()\n # Extend the first list with all elements of the second list\n lst1.extend(lst2)\n return lst1", "matching_cluster_idx": 8}, {"solution": "def replace_list(lst1, lst2):\n \"\"\"\n Replaces the last element of the first list with the elements of the second list.\n \n Parameters:\n lst1 (list): The first list with at least one element.\n lst2 (list): The second list whose elements will replace the last element of the first list.\n \n Returns:\n list: A new list with the last element of lst1 replaced by all elements of lst2.\n \"\"\"\n # Check if lst1 is empty to avoid index errors\n if not lst1:\n raise ValueError(\"First list cannot be empty\")\n \n # Replace the last element of lst1 with all elements of lst2\n lst1[-1:] = lst2\n return lst1", "matching_cluster_idx": 7}, {"solution": "def replace_list(lst1, lst2):\n # Remove the last element of the first list\n lst1.pop()\n # Extend the first list with all elements of the second list\n lst1.extend(lst2)\n return lst1", "matching_cluster_idx": 8}, {"solution": "def replace_list(lst1, lst2):\n # Remove the last element of lst1\n lst1.pop()\n # Extend lst1 with all elements of lst2\n lst1.extend(lst2)\n return lst1", "matching_cluster_idx": 8}, {"solution": "def replace_list(lst1, lst2):\n # Pop the last element of the first list\n lst1.pop()\n # Extend the first list with the elements of the second list\n lst1.extend(lst2)\n return lst1", "matching_cluster_idx": 8}, {"solution": "def replace_list(lst1, lst2):\n # Pop the last element of the first list\n lst1.pop()\n # Extend the first list with all elements of the second list\n lst1.extend(lst2)\n return lst1", "matching_cluster_idx": 8}, {"solution": "def replace_list(lst1, lst2):\n # Remove the last element of lst1\n lst1.pop()\n # Extend lst1 with all elements of lst2\n lst1.extend(lst2)\n return lst1", "matching_cluster_idx": 8}, {"solution": "def replace_list(lst1, lst2):\n # Pop the last element of the first list\n lst1.pop()\n # Extend the first list with all elements of the second list\n lst1.extend(lst2)\n return lst1", "matching_cluster_idx": 8}, {"solution": "def replace_list(lst1, lst2):\n \"\"\"\n Replaces the last element of the first list with the elements of the second list.\n \n Parameters:\n lst1 (list): The first list where the last element will be replaced.\n lst2 (list): The second list whose elements will replace the last element of the first list.\n \n Returns:\n list: The modified first list with the last element replaced by the elements of the second list.\n \"\"\"\n # Remove the last element of lst1\n lst1.pop()\n # Extend lst1 with all elements from lst2\n lst1.extend(lst2)\n return lst1", "matching_cluster_idx": 8}, {"solution": "def replace_list(lst1, lst2):\n \"\"\"\n Replaces the last element of the first list with the elements of the second list.\n \n Parameters:\n lst1 (list): The first list with at least one element.\n lst2 (list): The second list whose elements will replace the last element of the first list.\n \n Returns:\n list: The modified first list with its last element replaced by the second list's elements.\n \"\"\"\n # Remove the last element of lst1\n lst1.pop()\n # Extend lst1 with the elements of lst2\n lst1.extend(lst2)\n return lst1", "matching_cluster_idx": 8}, {"solution": "def replace_list(primary_list, replacement_list):\n \"\"\"\n Replaces the last element of the primary list with the elements of the replacement list.\n \n Parameters:\n primary_list (list): The original list whose last element needs to be replaced.\n replacement_list (list): The list whose elements will replace the last element of the primary list.\n \n Returns:\n list: The modified primary list with the last element replaced.\n \"\"\"\n if not primary_list:\n return replacement_list\n \n del primary_list[-1]\n primary_list.extend(replacement_list)\n return primary_list", "matching_cluster_idx": 8}, {"solution": "def replace_list(lst1, lst2):\n # Remove the last element from the first list\n lst1.pop()\n # Extend the first list with all elements from the second list\n lst1.extend(lst2)\n return lst1", "matching_cluster_idx": 8}, {"solution": "def replace_list(lst1, lst2):\n # Remove the last element of lst1\n lst1.pop()\n # Extend lst1 with all elements of lst2\n lst1.extend(lst2)\n return lst1", "matching_cluster_idx": 8}]}, "Mbpp/251": {"dps": 91.95402298850576, "dps_norm": 77.77777777777777, "pass@1": 98.0, "profiled": [{"solution": "def insert_element(lst, element):\n # Initialize an empty list to store the result\n result = []\n \n # Iterate through each item in the provided list\n for item in lst:\n # Append the element to the result list\n result.append(element)\n # Append the current item from the list to the result list\n result.append(item)\n \n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n # Initialize an empty list to store the result\n result = []\n # Iterate through each item in the input list\n for item in lst:\n # Insert the element before the current item\n result.append(element)\n result.append(item)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n # Initialize an empty list to store the result\n result = []\n # Iterate over each item in the input list\n for item in lst:\n # Insert the element before the current item\n result.append(element)\n result.append(item)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n \"\"\"\n Takes in a list and an element, inserts the element before each element in the list, and returns the resulting list.\n \n Args:\n lst : List of elements.\n element : Element to be inserted before each element of the list.\n \n Returns:\n List resulting from inserting the element before each element of the input list.\n \"\"\"\n # Initialize an empty list to store the result\n result = []\n # Insert the element before each item in the list and extend the result list\n for item in lst:\n result.append(element)\n result.append(item)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n # Initialize an empty list to store the result\n result = []\n # Iterate through each item in the input list\n for item in lst:\n # Insert the element and the item into the result list\n result.extend([element, item])\n # Return the resulting list\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, elem):\n # Insert the element before each element in the list\n # Use list comprehension to generate the new list\n return [val for pair in zip([elem]*len(lst), lst) for val in pair]", "matching_cluster_idx": 6}, {"solution": "def insert_element(input_list, element):\n \"\"\"\n Insert an element before each element in the input list and return the modified list.\n \n Parameters:\n input_list (list): The list into which the element will be inserted.\n element (any): The element to be inserted before each element in the input list.\n \n Returns:\n list: The modified list with the element inserted before each of its original elements.\n \"\"\"\n # Initialize an empty list to store the result\n modified_list = []\n \n # Iterate through each element in the input list\n for item in input_list:\n # Append the element to be inserted\n modified_list.append(element)\n # Append the current item from the input list\n modified_list.append(item)\n \n return modified_list", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n # Create a new list where 'element' is inserted before each item in 'lst'\n result = []\n for item in lst:\n result.append(element)\n result.append(item)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n \"\"\"\n Inserts an element before each element in the list and returns the modified list.\n \n Parameters:\n lst (list): The original list of elements.\n element: The element to insert before each element of the list.\n \n Returns:\n list: The new list with the element inserted before each original element.\n \"\"\"\n # Initialize an empty list to store the new elements\n modified_list = []\n \n # Iterate over each item in the input list\n for item in lst:\n # Append the element to insert and then the item itself to the modified list\n modified_list.extend([element, item])\n \n # Return the modified list\n return modified_list", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, elem):\n # Create a new list that is a copy of the input list but with the element inserted before each item\n result = []\n for item in lst:\n result.append(elem)\n result.append(item)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n # Create a new list to store the result\n result = []\n # Insert 'element' before each item in the input list\n for item in lst:\n result.append(element)\n result.append(item)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n \"\"\"\n Inserts the given element before each element in the list and returns the modified list.\n \n Parameters:\n lst (list): The original list of elements.\n element (any): The element to insert before each element in lst.\n \n Returns:\n list: The modified list with the element inserted before each original element.\n \"\"\"\n # Initialize an empty list to hold the result\n result = []\n # Iterate through each element in the input list\n for item in lst:\n # Insert the specified element followed by the current item from lst into the result list\n result.append(element)\n result.append(item)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n # Initialize an empty list to store the result\n result = []\n # Iterate through each item in the input list\n for item in lst:\n # Insert the element before each item\n result.append(element)\n result.append(item)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n # Initialize an empty list to store the result\n result = []\n # Iterate through each item in the given list\n for item in lst:\n # Insert the element before each item\n result.append(element)\n result.append(item)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n \"\"\"\n Insert an element before each element in the given list and return the resulting list.\n \n Args:\n lst: List of elements.\n element: The element to be inserted before each element in the list.\n \n Returns:\n A new list with the element inserted before each original element.\n \"\"\"\n # Initialize an empty list to store the result\n result = []\n \n # Iterate through each item in the list\n for item in lst:\n # Insert the element into the result list\n result.append(element)\n # Append the current item to the result list\n result.append(item)\n \n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n # Initialize an empty list to hold the result\n result = []\n \n # Iterate through each item in the input list\n for item in lst:\n # Insert the element before the current item\n result.append(element)\n result.append(item)\n \n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n \"\"\"\n Takes in a list and an element, inserts the element before each element in the list, and returns the resulting list.\n \n Args:\n lst : List of elements\n element : The element to be inserted before each element in the list\n \n Returns:\n A new list with the element inserted before each element in the original list.\n \"\"\"\n # Initialize an empty list to store the result\n result = []\n # Iterate over each item in the list\n for item in lst:\n # Append the specified element\n result.append(element)\n # Append the current item from the list\n result.append(item)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n \"\"\"\n Takes in a list and an element, and inserts the element before each element in the list.\n Returns the resulting list.\n \n Parameters:\n lst (list): The original list.\n element: The element to insert before each element of the list.\n \n Returns:\n list: The new list with elements inserted.\n \"\"\"\n \n # If the list is empty, return it immediately\n if not lst:\n return lst\n \n # Construct the new list by inserting 'element' before each item in 'lst'\n result = []\n for item in lst:\n result.append(element)\n result.append(item)\n \n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, elem):\n # Initialize the resulting list\n result = []\n # Iterate through each element in the input list\n for item in lst:\n # Append the given element and the current item to the result list\n result.append(elem)\n result.append(item)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n \"\"\"\n Insert the given element before each element in the given list and return the modified list.\n \n Args:\n lst : List of elements.\n element : Element to be inserted before each element in the list.\n \n Returns:\n A list with the element inserted before each of the original elements.\n \"\"\"\n # Initialize an empty list to store the result\n result = []\n \n # Iterate through each element in the provided list\n for item in lst:\n # Insert the given element, then the current item from the list\n result.extend([element, item])\n \n return result", "matching_cluster_idx": 6}]}, "Mbpp/256": {"dps": 77.70547945205479, "dps_norm": 72.94117647058823, "pass@1": 97.0, "profiled": [{"solution": "def is_prime(n):\n \"\"\"Check if a number is prime.\"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True\ndef count_Primes_nums(num):\n \"\"\"Returns the number of prime numbers less than num.\"\"\"\n count = 0\n for i in range(2, num):\n if is_prime(i):\n count += 1\n return count", "matching_cluster_idx": 10}, {"solution": "def is_prime(n):\n \"\"\"Check if a number is a prime number.\"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True\ndef count_Primes_nums(num):\n \"\"\"Returns the number of prime numbers less than a non-negative number.\"\"\"\n count = 0\n for i in range(2, num):\n if is_prime(i):\n count += 1\n return count", "matching_cluster_idx": 10}, {"solution": "def count_Primes_nums(n):\n if n <= 2:\n return 0\n \n # Initialize a list to mark prime numbers, True means prime, False means not\n is_prime = [True] * n\n is_prime[0], is_prime[1] = False, False # 0 and 1 are not prime numbers\n \n for i in range(2, int(n**0.5) + 1):\n if is_prime[i]:\n for j in range(i*i, n, i):\n is_prime[j] = False\n \n # Count the number of True values, which indicates the number of primes\n return sum(is_prime)", "matching_cluster_idx": 14}, {"solution": "def count_Primes_nums(n):\n if n <= 2:\n return 0\n count = 0\n for i in range(2, n):\n if all(i % j != 0 for j in range(2, int(i ** 0.5) + 1)):\n count += 1\n return count", "matching_cluster_idx": 6}, {"solution": "def count_Primes_nums(n):\n \"\"\"Return the number of prime numbers less than n.\"\"\"\n if n <= 2:\n return 0\n # Initialize a list to track prime status of numbers\n primes = [True] * n\n primes[0], primes[1] = False, False # 0 and 1 are not prime numbers\n \n for i in range(2, int(n**0.5) + 1):\n if primes[i]:\n for j in range(i*i, n, i):\n primes[j] = False\n \n return sum(primes)", "matching_cluster_idx": 14}, {"solution": "def is_prime(num):\n \"\"\"Check if a number is a prime number.\"\"\"\n if num <= 1:\n return False\n if num <= 3:\n return True\n if num % 2 == 0 or num % 3 == 0:\n return False\n i = 5\n while i * i <= num:\n if num % i == 0 or num % (i + 2) == 0:\n return False\n i += 6\n return True\ndef count_Primes_nums(n):\n \"\"\"Return the number of prime numbers less than the given non-negative number.\"\"\"\n count = 0\n for num in range(n):\n if is_prime(num):\n count += 1\n return count", "matching_cluster_idx": 10}, {"solution": "def count_Primes_nums(n):\n if n < 2:\n return 0\n \n # Initialize a boolean array to track prime status of numbers\n is_prime = [True] * n\n is_prime[0] = is_prime[1] = False # 0 and 1 are not prime numbers\n \n for i in range(2, int(n**0.5) + 1):\n if is_prime[i]:\n for j in range(i*i, n, i):\n is_prime[j] = False\n \n return sum(is_prime)", "matching_cluster_idx": 14}, {"solution": "def is_prime(n):\n \"\"\"Check if a number is prime.\"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True\ndef count_Primes_nums(num):\n \"\"\"Count the number of prime numbers less than the given non-negative number.\"\"\"\n count = 0\n for i in range(2, num):\n if is_prime(i):\n count += 1\n return count", "matching_cluster_idx": 10}, {"solution": "def count_Primes_nums(n):\n if n < 2:\n return 0\n \n # Initialize a list to mark prime status of numbers\n is_prime = [True] * n\n is_prime[0], is_prime[1] = False, False # 0 and 1 are not prime numbers\n \n for i in range(2, int(n**0.5) + 1):\n if is_prime[i]:\n # Mark multiples of i as non-prime\n for j in range(i*i, n, i):\n is_prime[j] = False\n \n # Count the number of primes\n return sum(is_prime)", "matching_cluster_idx": 14}, {"solution": "def is_prime(n):\n \"\"\"Check if a number is a prime number.\"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True\ndef count_Primes_nums(num):\n \"\"\"Count the number of prime numbers less than num.\"\"\"\n count = 0\n for i in range(2, num):\n if is_prime(i):\n count += 1\n return count", "matching_cluster_idx": 10}, {"solution": "def is_prime(n):\n \"\"\"Check if a number is a prime number.\"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True\ndef count_Primes_nums(n):\n \"\"\"Return the count of prime numbers less than n.\"\"\"\n count = 0\n for num in range(2, n):\n if is_prime(num):\n count += 1\n return count", "matching_cluster_idx": 10}, {"solution": "def count_Primes_nums(nums):\n \"\"\"\n Returns the number of prime numbers less than the given non-negative number.\n \n Parameters:\n nums (int): A non-negative integer to count prime numbers below.\n \n Returns:\n int: The number of prime numbers less than nums.\n \"\"\"\n def is_prime(n):\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True\n\n count = 0\n for num in range(nums):\n if is_prime(num):\n count += 1\n return count", "matching_cluster_idx": 8}, {"solution": "def count_Primes_nums(num):\n if num < 2:\n return 0\n \n # Initialize a list to mark prime numbers\n prime = [True for i in range(num)]\n p = 2\n while p * p <= num:\n # If prime[p] is not changed, then it is a prime\n if prime[p] == True:\n # Updating all multiples of p to non-prime\n for i in range(p * p, num, p):\n prime[i] = False\n p += 1\n \n # Counting prime numbers\n prime_count = sum(prime) - 2 # Subtract 2 to exclude the boolean values for 0 and 1\n return prime_count", "matching_cluster_idx": 13}, {"solution": "def count_Primes_nums(n):\n \"\"\"\n Returns the number of prime numbers less than the given non-negative number n.\n \n Parameters:\n n (int): A non-negative integer\n \n Returns:\n int: The count of prime numbers less than n\n \"\"\"\n if n <= 2:\n return 0 # There are no prime numbers less than 2\n \n # Initialize a list to mark non-prime numbers\n non_primes = [False] * n\n p = 2\n while p * p < n:\n if not non_primes[p]: # If p is prime\n # Mark all multiples of p as non-prime\n for i in range(p * p, n, p):\n non_primes[i] = True\n p += 1\n \n # Count the number of primes\n prime_count = sum(1 for i in range(2, n) if not non_primes[i])\n return prime_count", "matching_cluster_idx": 13}, {"solution": "def count_Primes_nums(n):\n \"\"\"\n Function to count the number of prime numbers less than a non-negative number n.\n \n Parameters:\n n (int): A non-negative number\n \n Returns:\n int: The number of prime numbers less than n\n \"\"\"\n if n <= 2:\n return 0\n \n # Initialize a list to keep track of prime status\n primes = [True] * n\n primes[0], primes[1] = False, False # 0 and 1 are not prime numbers\n \n for ind, value in enumerate(primes):\n if value is True:\n primes[ind*2::ind] = [False] * (((n - 1)//ind) - 1)\n \n return sum(primes)", "matching_cluster_idx": 14}, {"solution": "def is_prime(n):\n \"\"\"Check if a number is a prime number.\"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True\ndef count_Primes_nums(n):\n \"\"\"Count the number of prime numbers less than a non-negative number n.\"\"\"\n count = 0\n for num in range(2, n):\n if is_prime(num):\n count += 1\n return count", "matching_cluster_idx": 10}, {"solution": "def is_prime(n):\n \"\"\"Check if a number is a prime number.\"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True\ndef count_Primes_nums(num):\n \"\"\"Returns the count of prime numbers less than num.\"\"\"\n count = 0\n for i in range(2, num):\n if is_prime(i):\n count += 1\n return count", "matching_cluster_idx": 10}, {"solution": "def is_prime(num):\n \"\"\"Check if a number is prime.\"\"\"\n if num <= 1:\n return False\n if num <= 3:\n return True\n if num % 2 == 0 or num % 3 == 0:\n return False\n i = 5\n while i * i <= num:\n if num % i == 0 or num % (i + 2) == 0:\n return False\n i += 6\n return True\ndef count_Primes_nums(n):\n \"\"\"Returns the number of prime numbers less than a given non-negative number.\"\"\"\n count = 0\n for i in range(2, n):\n if is_prime(i):\n count += 1\n return count", "matching_cluster_idx": 10}, {"solution": "def count_Primes_nums(n):\n \"\"\"Return the number of prime numbers less than a non-negative number n.\"\"\"\n if n <= 2:\n return 0\n \n # Initialize a list to keep track of prime status of numbers\n primes = [True] * n\n primes[0], primes[1] = False, False # 0 and 1 are not prime numbers\n \n for i in range(2, int(n**0.5) + 1):\n if primes[i]:\n for j in range(i*i, n, i): # Mark multiples of i as False\n primes[j] = False\n \n # Count the number of True values, which represent prime numbers\n return sum(primes)", "matching_cluster_idx": 14}, {"solution": "def count_Primes_nums(n):\n \"\"\"\n Returns the number of prime numbers less than the given non-negative number n.\n \"\"\"\n if n <= 2:\n return 0\n \n # Initialize a list to mark prime status of numbers\n primes = [True] * n\n primes[0] = primes[1] = False\n \n # Sieve of Eratosthenes algorithm to mark non-prime numbers\n for i in range(2, int(n**0.5) + 1):\n if primes[i]:\n for j in range(i*i, n, i):\n primes[j] = False\n \n # Counting prime numbers\n return sum(primes)", "matching_cluster_idx": 14}]}, "Mbpp/265": {"dps": 70.93023255813954, "dps_norm": 83.33333333333333, "pass@1": 90.0, "profiled": [{"solution": "def list_split(input_list, n):\n \"\"\"\n Splits the given list for every nth element and returns a list of the resulting lists.\n \n :param input_list: List to be split\n :param n: Split every nth element\n :return: List of split lists\n \"\"\"\n # Initialize a list to store the resulting lists\n split_lists = [[] for _ in range(n)]\n \n # Distribute elements of the input list into the resulting lists\n for index, element in enumerate(input_list):\n split_lists[index % n].append(element)\n \n return split_lists", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n \"\"\"\n Splits a given list into multiple sublists, each containing every nth element.\n \n :param lst: List to be split\n :param n: The step size to split the list\n :return: A list of lists, where each sublist contains elements from the original list starting from the first element and then every nth element thereafter\n \"\"\"\n # Initialize the result list with empty sublists based on the step size n\n result = [[] for _ in range(n)]\n \n # Iterate through the original list and distribute elements into sublists\n for i, element in enumerate(lst):\n result[i % n].append(element)\n \n return result", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n \"\"\"\n Splits the list for every nth element and returns a list of the resulting lists.\n \n :param lst: List to be split\n :param n: The interval at which to split the list\n :return: A list of lists, each containing nth elements from the original list\n \"\"\"\n # Initialize a list to hold the result lists\n result = []\n \n # Iterate over the list in steps of n\n for i in range(n):\n # Slice the list starting from i and stepping by n, then append to result\n result.append(lst[i::n])\n \n return result", "matching_cluster_idx": 4}, {"solution": "def list_split(input_list, n):\n \"\"\"\n Splits a given list into chunks for every nth element and returns a list of the resulting lists.\n \n :param input_list: List to be split\n :param n: Step size for splitting the list\n :return: List of lists containing elements from the input list split at every nth interval\n \"\"\"\n # Create a list of lists to store the result\n result = [[] for _ in range(n)]\n # Iterate over the input list and distribute elements into the result list\n for index, element in enumerate(input_list):\n result[index % n].append(element)\n return result", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n # Ensure n is not zero to avoid division by zero error\n if n == 0:\n raise ValueError(\"n must be a non-zero integer\")\n \n # Use list comprehension to group elements by nth index\n split_list = [lst[i::n] for i in range(n)]\n return split_list", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n # Initialize the list of lists to store the results\n result = [[] for _ in range(n)]\n \n # Distribute the elements of the list into the result list according to n\n for i, item in enumerate(lst):\n result[i % n].append(item)\n \n return result", "matching_cluster_idx": 4}, {"solution": "def list_split(input_list, n):\n \"\"\"\n Splits a given list into a list of lists for every nth element.\n \n Parameters:\n input_list (list): The list to be split.\n n (int): The step size for splitting the list.\n \n Returns:\n list: A list of lists, where each sublist contains elements from the original list at intervals of n.\n \"\"\"\n return [input_list[i::n] for i in range(n)]", "matching_cluster_idx": 4}, {"solution": "def list_split(input_list, n):\n \"\"\"\n Splits the input list into chunks for every nth element.\n \n Parameters:\n input_list (list): The input list to be split.\n n (int): The interval for splitting the list.\n \n Returns:\n list: A list of lists containing the split elements.\n \"\"\"\n # Initialize the list to hold the results\n result = [[] for _ in range(n)]\n \n # Enumerate over the list and place each element in the correct sublist\n for index, item in enumerate(input_list):\n result[index % n].append(item)\n \n return result", "matching_cluster_idx": 4}, {"solution": "def list_split(input_list, n):\n \"\"\"\n Splits the given list into chunks where each chunk contains every nth element,\n starting from each index up to n-1.\n \n Args:\n input_list : List of elements.\n n : The step size to split the list.\n \n Returns:\n A list of lists, where each sublist is a split from the original list starting at a different step.\n \"\"\"\n # Initialize an empty list to store the results\n result = [[] for _ in range(n)]\n \n # Fill the result list with elements from the input_list\n for index, element in enumerate(input_list):\n result[index % n].append(element)\n \n return result", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n \"\"\"\n Splits the input list 'lst' into sublists where each sublist contains every nth element of the original list.\n \n :param lst: List to be split\n :param n: Step size for splitting the list\n :return: A list of sublists after splitting\n \"\"\"\n # Initialize a list to hold the result\n result = [[] for _ in range(n)]\n \n # Populate the result list\n for index, element in enumerate(lst):\n # Determine which sublist the current element should go into\n result[index % n].append(element)\n \n return result", "matching_cluster_idx": 4}, {"solution": "def list_split(input_list, n):\n \"\"\"\n Splits a given list for every nth element.\n \n Parameters:\n input_list (list): The list to be split.\n n (int): The interval for splitting the list.\n \n Returns:\n list: A list of lists, where each sublist contains every nth element of the input list.\n \"\"\"\n # Create a list of lists to store the result\n result = [[] for _ in range(n)]\n \n # Enumerate over the input list to get both index and item\n for index, item in enumerate(input_list):\n # Append the item to the appropriate sublist based on the index % n\n result[index % n].append(item)\n \n return result", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n \"\"\"\n Splits the input list into sublists, each containing every nth element.\n \n Parameters:\n lst (list): The input list to be split.\n n (int): The interval at which to split the list.\n \n Returns:\n list: A list of lists, each sublist contains every nth element from the original list.\n \"\"\"\n # Initialize a list to hold the resulting sublists\n split_lists = [[] for _ in range(n)]\n \n # Iterate through the input list and place elements into the corresponding sublists\n for index, element in enumerate(lst):\n split_lists[index % n].append(element)\n \n return split_lists", "matching_cluster_idx": 4}, {"solution": "def list_split(items, n):\n \"\"\"\n Splits a given list into chunks of every nth element.\n \n Parameters:\n items (list): The list to be split.\n n (int): The step size for splitting the list.\n \n Returns:\n list: A list containing the split lists.\n \"\"\"\n # Initialize a list to hold the results\n split_lists = [[] for _ in range(n)]\n \n # Iterate over the indices of the items list\n for index, item in enumerate(items):\n # Append the item to the corresponding split list based on index % n\n split_lists[index % n].append(item)\n \n return split_lists", "matching_cluster_idx": 4}, {"solution": "def list_split(input_list, n):\n \"\"\"\n Splits the input list for every nth element and returns a list of the resulting lists.\n \n Args:\n input_list (list): The list to be split.\n n (int): The step for splitting the list.\n \n Returns:\n list: A list of lists, each representing a split of the original list.\n \"\"\"\n # Initialize a list to store the resulting split lists\n result = []\n for i in range(n):\n # Use list slicing to get every nth element starting from the current index i\n sublist = input_list[i::n]\n result.append(sublist)\n return result", "matching_cluster_idx": 4}, {"solution": "def list_split(input_list, n):\n \"\"\"\n Splits the input list into sublists, each containing every nth element.\n \n Args:\n input_list : List of elements.\n n : Integer indicating the interval of splitting the list.\n \n Returns:\n A list of lists, each sublist containing every nth element of the input list.\n \"\"\"\n # Initialize a list to hold the resulting sublists\n result = []\n \n # Iterate over the range of n to get each nth subsequence\n for i in range(n):\n # Append the sliced list to the result, starting from index i, step n\n result.append(input_list[i::n])\n \n return result", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n # Initialize a list of lists to hold the chunks\n split_lists = [[] for _ in range(n)]\n \n # Enumerate over the list to get both index and value\n for index, value in enumerate(lst):\n # Determine which sub-list to add the current value to\n # by using the index modulo n\n split_lists[index % n].append(value)\n \n return split_lists", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n \"\"\"\n Splits a given list into sublists, each containing every nth element.\n \n :param lst: List to be split\n :param n: Interval for splitting the list\n :return: List of sublists\n \"\"\"\n # Create a list of lists to store the final result\n result = [[] for _ in range(n)]\n \n # Iterate over the original list and populate the result list of lists\n for index, item in enumerate(lst):\n # Determine the sublist index for the current item\n sublist_index = index % n\n # Append the item to the corresponding sublist\n result[sublist_index].append(item)\n \n return result", "matching_cluster_idx": 4}, {"solution": "def list_split(input_list, n):\n \"\"\"\n Splits a given list into a list of lists every nth element.\n \n Parameters:\n input_list (list): The list to split.\n n (int): The interval for splitting the list.\n \n Returns:\n list: A list of lists with elements at each nth interval.\n \"\"\"\n # Initialize a list to hold the split lists\n split_lists = [[] for _ in range(n)]\n \n # Iterate through the input list and distribute elements across the split_lists\n for index, item in enumerate(input_list):\n # Calculate which sub-list the current item should go into\n split_lists[index % n].append(item)\n \n return split_lists", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n \"\"\"\n Splits a list for every nth element and returns a list of the resulting lists.\n \n :param lst: The input list to be split\n :param n: The step value for splitting the list\n :return: A list of lists, each containing elements from the original list, split at nth intervals\n \"\"\"\n # Initialize the result list with empty lists for each group\n result = [[] for _ in range(n)]\n \n # Enumerate through the list to get both index and element\n for i, element in enumerate(lst):\n # Append each element to the corresponding group based on the index modulo n\n result[i % n].append(element)\n \n return result", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n # Create a list of lists to hold the chunks\n chunks = [[] for _ in range(n)]\n \n # Iterate over the list and distribute elements into chunks\n for index, element in enumerate(lst):\n # Determine which chunk the current element should go into\n chunk_index = index % n\n # Append the element to the appropriate chunk\n chunks[chunk_index].append(element)\n \n return chunks", "matching_cluster_idx": 4}]}, "Mbpp/281": {"dps": 94.05, "dps_norm": 82.27272727272727, "pass@1": 100.0, "profiled": [{"solution": "def all_unique(lst):\n # Convert the list to a set and compare lengths to determine uniqueness\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(items):\n # Check if the length of the list is equal to the length of the set of the list\n return len(items) == len(set(items))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n # Check if the length of the list is equal to the length of the set of the list\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n # Compare the length of the list with the length of the set of the list\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n # Check if the length of the set of the list is equal to the length of the list\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n # Use a set to remove duplicates and compare lengths with original list\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n # Use set to eliminate duplicates, then compare lengths\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(elements):\n # Convert the list to a set to remove duplicates and compare its length to the original list's length\n return len(elements) == len(set(elements))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(nums):\n # Using set to check for unique elements\n return len(nums) == len(set(nums))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n # Use a set to check if all elements are unique\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(nums):\n return len(nums) == len(set(nums))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n # Use a set to track seen elements\n seen = set()\n for item in lst:\n # Check if item is already in seen set\n if item in seen:\n return False\n seen.add(item)\n return True", "matching_cluster_idx": 9}, {"solution": "def all_unique(lst):\n # Use set to remove duplicates and compare lengths\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n # Use a set to track seen elements and ensure all elements in the list are unique\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(items):\n # Compare the length of the list with the length of the set of the list\n return len(items) == len(set(items))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n # Use a set to check for unique elements\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n # Check if the length of the list is equal to the length of the set of the list\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}]}, "Mbpp/296": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 91.0, "profiled": [{"solution": "def get_Inv_Count(arr):\n def merge(arr, temp, left, mid, right):\n i, j, k = left, mid, left\n inv_count = 0\n \n while i <= mid - 1 and j <= right:\n if arr[i] <= arr[j]:\n temp[k] = arr[i]\n k += 1\n i += 1\n else:\n temp[k] = arr[j]\n inv_count += (mid - i)\n k += 1\n j += 1\n \n while i <= mid - 1:\n temp[k] = arr[i]\n k += 1\n i += 1\n \n while j <= right:\n temp[k] = arr[j]\n k += 1\n j += 1\n \n for i in range(left, right + 1):\n arr[i] = temp[i]\n \n return inv_count\n \n def _get_Inv_Count(arr, temp, left, right):\n inv_count = 0\n if right > left:\n mid = int((right + left) / 2)\n inv_count = _get_Inv_Count(arr, temp, left, mid)\n inv_count += _get_Inv_Count(arr, temp, mid + 1, right)\n inv_count += merge(arr, temp, left, mid + 1, right)\n \n return inv_count\n \n return _get_Inv_Count(arr, arr[:], 0, len(arr) - 1)", "matching_cluster_idx": 5}, {"solution": "def get_Inv_Count(arr):\n def mergeAndGetInv(arr, temp, left, mid, right):\n inv_count = 0\n i = left\n j = mid\n k = left\n \n while i <= mid - 1 and j <= right:\n if arr[i] <= arr[j]:\n temp[k] = arr[i]\n k += 1\n i += 1\n else:\n temp[k] = arr[j]\n inv_count += (mid - i)\n k += 1\n j += 1\n \n while i <= mid - 1:\n temp[k] = arr[i]\n k += 1\n i += 1\n \n while j <= right:\n temp[k] = arr[j]\n k += 1\n j += 1\n \n for i in range(left, right + 1):\n arr[i] = temp[i]\n \n return inv_count\n \n def getInvCount(arr, temp, left, right):\n inv_count = 0\n if right > left:\n mid = int((right + left) / 2)\n \n inv_count += getInvCount(arr, temp, left, mid)\n inv_count += getInvCount(arr, temp, mid + 1, right)\n \n inv_count += mergeAndGetInv(arr, temp, left, mid + 1, right)\n \n return inv_count\n \n temp = arr.copy()\n return getInvCount(arr, temp, 0, len(arr) - 1)", "matching_cluster_idx": 5}, {"solution": "def get_Inv_Count(arr):\n \"\"\"Count the number of inversions in the given array.\"\"\"\n def merge(arr, temp_arr, left, mid, right):\n inv_count = 0\n i = left\n j = mid\n k = left\n while i <= mid - 1 and j <= right:\n if arr[i] <= arr[j]:\n temp_arr[k] = arr[i]\n k += 1\n i += 1\n else:\n temp_arr[k] = arr[j]\n inv_count += (mid - i)\n k += 1\n j += 1\n while i <= mid - 1:\n temp_arr[k] = arr[i]\n k += 1\n i += 1\n while j <= right:\n temp_arr[k] = arr[j]\n k += 1\n j += 1\n for loop_var in range(left, right + 1):\n arr[loop_var] = temp_arr[loop_var]\n return inv_count\n \n def _get_Inv_Count(arr, temp_arr, left, right):\n inv_count = 0\n if right > left:\n mid = (left + right) // 2\n inv_count = _get_Inv_Count(arr, temp_arr, left, mid)\n inv_count += _get_Inv_Count(arr, temp_arr, mid + 1, right)\n inv_count += merge(arr, temp_arr, left, mid + 1, right)\n return inv_count\n \n temp_arr = [0] * len(arr)\n return _get_Inv_Count(arr, temp_arr, 0, len(arr) - 1)", "matching_cluster_idx": 5}, {"solution": "def get_Inv_Count(arr):\n def merge(arr, temp, left, mid, right):\n i = left\n j = mid\n k = left\n inv_count = 0\n \n while i <= mid - 1 and j <= right:\n if arr[i] <= arr[j]:\n temp[k] = arr[i]\n i += 1\n else:\n temp[k] = arr[j]\n inv_count += (mid - i)\n j += 1\n k += 1\n \n while i <= mid - 1:\n temp[k] = arr[i]\n i += 1\n k += 1\n \n while j <= right:\n temp[k] = arr[j]\n j += 1\n k += 1\n \n for i in range(left, right + 1):\n arr[i] = temp[i]\n \n return inv_count\n \n def _merge_sort(arr, temp, left, right):\n inv_count = 0\n if right > left:\n mid = int((right + left)/2)\n inv_count += _merge_sort(arr, temp, left, mid)\n inv_count += _merge_sort(arr, temp, mid+1, right)\n inv_count += merge(arr, temp, left, mid + 1, right)\n \n return inv_count\n \n temp = [0]*len(arr)\n return _merge_sort(arr, temp, 0, len(arr) - 1)", "matching_cluster_idx": 5}, {"solution": "def get_Inv_Count(arr):\n def merge(arr, temp, left, mid, right):\n i = left # Starting index for left subarray \n j = mid + 1 # Starting index for right subarray \n k = left # Starting index to be sorted\n inv_count = 0\n \n # Conditions are checked to make sure that i and j don't exceed \n # the subarray limits\n while i <= mid and j <= right:\n if arr[i] <= arr[j]:\n temp[k] = arr[i]\n i += 1\n else:\n # Inversion will occur.\n temp[k] = arr[j]\n inv_count += (mid-i + 1)\n j += 1\n k += 1\n \n # Copy the remaining elements of left subarray, if there are any\n while i <= mid:\n temp[k] = arr[i]\n i += 1\n k += 1\n \n # Copy the remaining elements of right subarray, if there are any\n while j <= right:\n temp[k] = arr[j]\n j += 1\n k += 1\n \n # Copy the sorted subarray into Original array\n for i in range(left, right + 1):\n arr[i] = temp[i]\n \n return inv_count\n \n def _merge_sort(arr, temp, left, right):\n inv_count = 0\n if left < right:\n mid = (left + right)//2\n \n inv_count += _merge_sort(arr, temp, left, mid)\n inv_count += _merge_sort(arr, temp, mid + 1, right)\n inv_count += merge(arr, temp, left, mid, right)\n \n return inv_count\n \n # Create a temp array\n temp = [0]*len(arr)\n return _merge_sort(arr, temp, 0, len(arr) - 1)", "matching_cluster_idx": 5}, {"solution": "def merge(arr, temp, left, mid, right):\n i = left # Starting index for left subarray\n j = mid # Starting index for right subarray\n k = left # Starting index to be sorted\n inv_count = 0\n \n # Conditions are checked to ensure that i doesn't exceed mid and j doesn't exceed right\n while (i <= mid - 1 and j <= right):\n if (arr[i] <= arr[j]):\n temp[k] = arr[i]\n i += 1\n else:\n # Inversion will occur.\n temp[k] = arr[j]\n inv_count += (mid - i)\n j += 1\n k += 1\n \n # Copy the remaining elements of left subarray (if there are any) to temp\n while (i <= mid - 1):\n temp[k] = arr[i]\n i += 1\n k += 1\n\n # Copy the remaining elements of right subarray (if there are any) to temp\n while (j <= right):\n temp[k] = arr[j]\n j += 1\n k += 1\n \n # Copy back the merged elements to original array\n for i in range(left, right + 1):\n arr[i] = temp[i]\n \n return inv_count\ndef mergeSort(arr, temp, left, right):\n inv_count = 0\n if (right > left):\n # Divide the array into two parts and call _mergeSortAndCountInv()\n # and then count inversions in both arrays.\n mid = int((right + left)/2)\n \n # Inversion count will be sum of inversions in left-part, right-part\n # and number of inversions in merging\n inv_count += mergeSort(arr, temp, left, mid)\n inv_count += mergeSort(arr, temp, mid + 1, right)\n \n # Merge the two parts\n inv_count += merge(arr, temp, left, mid + 1, right)\n \n return inv_count\ndef get_Inv_Count(arr):\n # Returns the count of inversions in an array\n n = len(arr)\n temp = [0]*n\n return mergeSort(arr, temp, 0, n - 1)", "matching_cluster_idx": 5}, {"solution": "def get_Inv_Count(arr):\n def merge(arr, temp, left, mid, right):\n inv_count = 0\n i = left\n j = mid\n k = left\n \n while i <= mid - 1 and j <= right:\n if arr[i] <= arr[j]:\n temp[k] = arr[i]\n k += 1\n i += 1\n else:\n temp[k] = arr[j]\n inv_count += (mid - i)\n k += 1\n j += 1\n \n while i <= mid - 1:\n temp[k] = arr[i]\n k += 1\n i += 1\n \n while j <= right:\n temp[k] = arr[j]\n k += 1\n j += 1\n \n for i in range(left, right + 1):\n arr[i] = temp[i]\n \n return inv_count\n \n def _get_Inv_Count(arr, temp, left, right):\n inv_count = 0\n if right > left:\n mid = int((right + left) / 2)\n inv_count = _get_Inv_Count(arr, temp, left, mid)\n inv_count += _get_Inv_Count(arr, temp, mid + 1, right)\n inv_count += merge(arr, temp, left, mid + 1, right)\n \n return inv_count\n \n # Driver Code\n n = len(arr)\n temp = [0] * n\n return _get_Inv_Count(arr, temp, 0, n - 1)", "matching_cluster_idx": 5}, {"solution": "def get_Inv_Count(arr):\n def mergeAndGetCount(left, right):\n result = []\n i = j = inv_count = 0\n while i < len(left) and j < len(right):\n if left[i] <= right[j]:\n result.append(left[i])\n i += 1\n else:\n result.append(right[j])\n inv_count += len(left) - i # All remaining elements in left are inversions with right[j]\n j += 1\n result += left[i:]\n result += right[j:]\n return result, inv_count\n \n def _get_Inv_Count(arr):\n if len(arr) <= 1:\n return arr, 0\n mid = len(arr) // 2\n left, left_count = _get_Inv_Count(arr[:mid])\n right, right_count = _get_Inv_Count(arr[mid:])\n merged, split_count = mergeAndGetCount(left, right)\n return merged, left_count + right_count + split_count\n \n _, count = _get_Inv_Count(arr)\n return count", "matching_cluster_idx": 5}, {"solution": "def get_Inv_Count(arr):\n \"\"\"\n Count the number of inversions in the given array.\n An inversion is a pair of elements (arr[i], arr[j]) such that\n arr[i] > arr[j] and i < j.\n \"\"\"\n def merge_count(arr, temp, left, mid, right):\n inv_count = 0\n i = left\n j = mid\n k = left\n \n while i <= mid - 1 and j <= right:\n if arr[i] <= arr[j]:\n temp[k] = arr[i]\n i += 1\n else:\n temp[k] = arr[j]\n inv_count += (mid - i)\n j += 1\n k += 1\n \n while i <= mid - 1:\n temp[k] = arr[i]\n i += 1\n k += 1\n \n while j <= right:\n temp[k] = arr[j]\n j += 1\n k += 1\n \n for i in range(left, right + 1):\n arr[i] = temp[i]\n \n return inv_count\n \n def merge_sort_count(arr, temp, left, right):\n inv_count = 0\n if right > left:\n mid = (left + right) // 2\n inv_count += merge_sort_count(arr, temp, left, mid)\n inv_count += merge_sort_count(arr, temp, mid + 1, right)\n inv_count += merge_count(arr, temp, left, mid + 1, right)\n \n return inv_count\n \n temp = arr.copy()\n return merge_sort_count(arr, temp, 0, len(arr) - 1)", "matching_cluster_idx": 5}, {"solution": "def get_Inv_Count(arr):\n def merge(left, right):\n inv_count = 0\n i = 0\n j = 0\n temp_arr = []\n \n while i < len(left) and j < len(right):\n if left[i] <= right[j]:\n temp_arr.append(left[i])\n i += 1\n else:\n temp_arr.append(right[j])\n j += 1\n # Every time the right[j] is less than left[i], it means all remaining elements in the left subarray are inversions with right[j]\n inv_count += len(left) - i\n \n # Append remaining elements if any\n temp_arr += left[i:]\n temp_arr += right[j:]\n \n return temp_arr, inv_count\n \n def merge_sort(arr):\n if len(arr) <= 1:\n return arr, 0\n \n mid = len(arr) // 2\n left, inv_left = merge_sort(arr[:mid])\n right, inv_right = merge_sort(arr[mid:])\n \n merged, inv_merge = merge(left, right)\n \n return merged, inv_left + inv_right + inv_merge\n \n _, total_inv_count = merge_sort(arr)\n return total_inv_count", "matching_cluster_idx": 5}, {"solution": "def get_Inv_Count(arr):\n def merge(arr, temp_arr, left, mid, right):\n i = left\n j = mid\n k = left\n inv_count = 0\n \n while i <= mid - 1 and j <= right:\n if arr[i] <= arr[j]:\n temp_arr[k] = arr[i]\n i += 1\n else:\n temp_arr[k] = arr[j]\n inv_count += (mid - i)\n j += 1\n k += 1\n \n while i <= mid - 1:\n temp_arr[k] = arr[i]\n i += 1\n k += 1\n \n while j <= right:\n temp_arr[k] = arr[j]\n j += 1\n k += 1\n \n for i in range(left, right + 1):\n arr[i] = temp_arr[i]\n \n return inv_count\n \n def _get_Inv_Count(arr, temp_arr, left, right):\n inv_count = 0\n if left < right:\n mid = (left + right) // 2\n inv_count += _get_Inv_Count(arr, temp_arr, left, mid)\n inv_count += _get_Inv_Count(arr, temp_arr, mid + 1, right)\n inv_count += merge(arr, temp_arr, left, mid + 1, right)\n \n return inv_count\n \n temp_arr = [0] * len(arr)\n return _get_Inv_Count(arr, temp_arr, 0, len(arr) - 1)", "matching_cluster_idx": 5}, {"solution": "def get_Inv_Count(arr):\n def merge(arr, temp, left, mid, right):\n i, j, k = left, mid, left\n inv_count = 0\n \n while i <= mid - 1 and j <= right:\n if arr[i] <= arr[j]:\n temp[k] = arr[i]\n i += 1\n else:\n temp[k] = arr[j]\n inv_count += (mid - i)\n j += 1\n k += 1\n \n while i <= mid - 1:\n temp[k] = arr[i]\n i += 1\n k += 1\n \n while j <= right:\n temp[k] = arr[j]\n j += 1\n k += 1\n \n for i in range(left, right + 1):\n arr[i] = temp[i]\n \n return inv_count\n \n def mergeSort(arr, temp, left, right):\n inv_count = 0\n if right > left:\n mid = int((right + left) / 2)\n inv_count = mergeSort(arr, temp, left, mid)\n inv_count += mergeSort(arr, temp, mid + 1, right)\n inv_count += merge(arr, temp, left, mid + 1, right)\n \n return inv_count\n \n # Temporary array to assist in merge\n temp = [0]*len(arr)\n return mergeSort(arr, temp, 0, len(arr) - 1)", "matching_cluster_idx": 5}, {"solution": "def get_Inv_Count(arr):\n def merge(arr, temp, left, mid, right):\n inv_count = 0\n i = left\n j = mid\n k = left\n \n while i <= mid - 1 and j <= right:\n if arr[i] <= arr[j]:\n temp[k] = arr[i]\n k += 1\n i += 1\n else:\n temp[k] = arr[j]\n inv_count += (mid - i)\n k += 1\n j += 1\n \n while i <= mid - 1:\n temp[k] = arr[i]\n k += 1\n i += 1\n \n while j <= right:\n temp[k] = arr[j]\n k += 1\n j += 1\n \n for i in range(left, right + 1):\n arr[i] = temp[i]\n \n return inv_count\n \n def _mergeSort(arr, temp, left, right):\n inv_count = 0\n if right > left:\n mid = int((right + left) / 2)\n \n inv_count = _mergeSort(arr, temp, left, mid)\n inv_count += _mergeSort(arr, temp, mid + 1, right)\n inv_count += merge(arr, temp, left, mid + 1, right)\n \n return inv_count\n \n temp = [0 for i in range(len(arr))]\n return _mergeSort(arr, temp, 0, len(arr) - 1)", "matching_cluster_idx": 5}, {"solution": "def merge(arr, temp, left, mid, right):\n i = left # Starting index for left subarray\n j = mid # Starting index for right subarray\n k = left # Starting index to be sorted\n inv_count = 0\n \n while (i <= mid - 1) and (j <= right):\n if arr[i] <= arr[j]:\n temp[k] = arr[i]\n i += 1\n else:\n temp[k] = arr[j]\n inv_count += (mid - i)\n j += 1\n k += 1\n\n # Copy the remaining elements of left subarray (if any) to temp\n while i <= mid - 1:\n temp[k] = arr[i]\n i += 1\n k += 1\n\n # Copy the remaining elements of right subarray (if any) to temp\n while j <= right:\n temp[k] = arr[j]\n j += 1\n k += 1\n\n # Copy back the merged elements to original array\n for i in range(left, right + 1):\n arr[i] = temp[i]\n \n return inv_count\ndef get_Inv_Count(arr):\n temp = [0]*len(arr)\n return getInvCount(arr, temp, 0, len(arr) - 1)\ndef getInvCount(arr, temp, left, right):\n inv_count = 0\n if right > left:\n mid = int((right + left)/2)\n inv_count = getInvCount(arr, temp, left, mid)\n inv_count += getInvCount(arr, temp, mid + 1, right)\n inv_count += merge(arr, temp, left, mid + 1, right)\n \n return inv_count", "matching_cluster_idx": 5}, {"solution": "def get_Inv_Count(arr):\n \"\"\"Return the number of inversions in the array.\"\"\"\n def merge(arr, temp_arr, left, mid, right):\n inv_count = 0\n i = left\n j = mid\n k = left\n \n while i <= mid - 1 and j <= right:\n if arr[i] <= arr[j]:\n temp_arr[k] = arr[i]\n i += 1\n else:\n temp_arr[k] = arr[j]\n inv_count += (mid - i)\n j += 1\n k += 1\n \n while i <= mid - 1:\n temp_arr[k] = arr[i]\n i += 1\n k += 1\n \n while j <= right:\n temp_arr[k] = arr[j]\n j += 1\n k += 1\n \n for i in range(left, right + 1):\n arr[i] = temp_arr[i]\n \n return inv_count\n \n def _mergeSort(arr, temp_arr, left, right):\n inv_count = 0\n if left < right:\n mid = (left + right) // 2\n inv_count += _mergeSort(arr, temp_arr, left, mid)\n inv_count += _mergeSort(arr, temp_arr, mid + 1, right)\n inv_count += merge(arr, temp_arr, left, mid + 1, right)\n \n return inv_count\n \n temp_arr = [0] * len(arr)\n return _mergeSort(arr, temp_arr, 0, len(arr) - 1)", "matching_cluster_idx": 5}, {"solution": "def get_Inv_Count(arr):\n def merge_count_inversion(arr):\n if len(arr) <= 1:\n return arr, 0\n mid = len(arr) // 2\n left, a = merge_count_inversion(arr[:mid])\n right, b = merge_count_inversion(arr[mid:])\n result, c = merge_count_split_inversion(left, right)\n return result, a + b + c\n\n def merge_count_split_inversion(left, right):\n result = []\n count = 0\n i = j = 0\n while i < len(left) and j < len(right):\n if left[i] <= right[j]:\n result.append(left[i])\n i += 1\n else:\n result.append(right[j])\n count += len(left) - i # Count inversions\n j += 1\n result += left[i:]\n result += right[j:]\n return result, count\n \n _, count = merge_count_inversion(arr)\n return count", "matching_cluster_idx": 5}, {"solution": "def get_Inv_Count(arr):\n \"\"\"\n Function to count inversions in an array.\n An inversion is a pair (i, j) such that i < j and arr[i] > arr[j].\n \"\"\"\n def merge_count(arr, temp, left, mid, right):\n inv_count = 0\n i = left\n j = mid\n k = left\n \n while i <= mid - 1 and j <= right:\n if arr[i] <= arr[j]:\n temp[k] = arr[i]\n k += 1\n i += 1\n else:\n temp[k] = arr[j]\n inv_count += (mid - i)\n k += 1\n j += 1\n \n while i <= mid - 1:\n temp[k] = arr[i]\n k += 1\n i += 1\n \n while j <= right:\n temp[k] = arr[j]\n k += 1\n j += 1\n \n for i in range(left, right + 1):\n arr[i] = temp[i]\n \n return inv_count\n \n def merge_sort_count(arr, temp, left, right):\n inv_count = 0\n if right > left:\n mid = (left + right) // 2\n inv_count += merge_sort_count(arr, temp, left, mid)\n inv_count += merge_sort_count(arr, temp, mid + 1, right)\n inv_count += merge_count(arr, temp, left, mid + 1, right)\n return inv_count\n \n temp = [0 for i in range(len(arr))]\n return merge_sort_count(arr, temp, 0, len(arr) - 1)", "matching_cluster_idx": 5}, {"solution": "def get_Inv_Count(arr):\n def merge(arr, temp, left, mid, right):\n i, j, k = left, mid, left\n inv_count = 0\n \n while i <= mid - 1 and j <= right:\n if arr[i] <= arr[j]:\n temp[k] = arr[i]\n i += 1\n else:\n temp[k] = arr[j]\n inv_count += (mid - i)\n j += 1\n k += 1\n \n while i <= mid - 1:\n temp[k] = arr[i]\n i += 1\n k += 1\n \n while j <= right:\n temp[k] = arr[j]\n j += 1\n k += 1\n \n for i in range(left, right + 1):\n arr[i] = temp[i]\n \n return inv_count\n \n def _get_Inv_Count(arr, temp, left, right):\n inv_count = 0\n if right > left:\n mid = (right + left) // 2\n inv_count += _get_Inv_Count(arr, temp, left, mid)\n inv_count += _get_Inv_Count(arr, temp, mid + 1, right)\n inv_count += merge(arr, temp, left, mid + 1, right)\n \n return inv_count\n \n temp = arr.copy()\n return _get_Inv_Count(arr, temp, 0, len(arr) - 1)", "matching_cluster_idx": 5}, {"solution": "def get_Inv_Count(arr):\n def merge(arr, temp_arr, left, mid, right):\n i = left # Starting index for left subarray\n j = mid + 1 # Starting index for right subarray\n k = left # Starting index to be sorted\n inv_count = 0\n \n # Conditions are checked to ensure that i doesn't exceed mid and j doesn't exceed right\n while i <= mid and j <= right:\n if arr[i] <= arr[j]:\n temp_arr[k] = arr[i]\n i += 1\n else:\n # Inversion will occur.\n temp_arr[k] = arr[j]\n inv_count += (mid-i + 1)\n j += 1\n k += 1\n \n # Copy the remaining elements of left subarray, if there are any\n while i <= mid:\n temp_arr[k] = arr[i]\n k += 1\n i += 1\n\n # Copy the remaining elements of right subarray, if there are any\n while j <= right:\n temp_arr[k] = arr[j]\n k += 1\n j += 1\n \n # Copy the sorted subarray into Original array\n for loop_var in range(left, right + 1):\n arr[loop_var] = temp_arr[loop_var]\n \n return inv_count\n \n def _get_Inv_Count(arr, temp_arr, left, right):\n inv_count = 0\n if left < right:\n mid = (left + right)//2\n inv_count = _get_Inv_Count(arr, temp_arr, left, mid)\n inv_count += _get_Inv_Count(arr, temp_arr, mid + 1, right)\n inv_count += merge(arr, temp_arr, left, mid, right)\n \n return inv_count\n \n # Create a temporary array to store the sorted array\n temp_arr = [0]*len(arr)\n return _get_Inv_Count(arr, temp_arr, 0, len(arr) - 1)", "matching_cluster_idx": 5}, {"solution": "def get_Inv_Count(arr):\n def merge_count_split_inv(left, right):\n i, j = 0, 0\n split_inv_count = 0\n merged = []\n \n while i < len(left) and j < len(right):\n if left[i] <= right[j]:\n merged.append(left[i])\n i += 1\n else:\n merged.append(right[j])\n split_inv_count += len(left) - i # All remaining elements in left are inversions with right[j]\n j += 1\n \n merged += left[i:]\n merged += right[j:]\n \n return merged, split_inv_count\n \n def sort_count_inv(arr):\n if len(arr) <= 1:\n return arr, 0\n \n mid = len(arr) // 2\n left, left_inv = sort_count_inv(arr[:mid])\n right, right_inv = sort_count_inv(arr[mid:])\n \n merged, split_inv = merge_count_split_inv(left, right)\n \n return merged, (left_inv + right_inv + split_inv)\n \n _, count_of_inv = sort_count_inv(arr)\n return count_of_inv", "matching_cluster_idx": 5}]}, "Mbpp/308": {"dps": 88.46551724137932, "dps_norm": 65.83333333333333, "pass@1": 26.0, "profiled": [{"solution": "def large_product(lst1, lst2, n):\n # Sort the lists to optimize the product selection\n lst1.sort()\n lst2.sort(reverse=True)\n \n # Use a min-heap to keep track of the largest products\n import heapq\n \n # Generate products from the sorted lists\n products = []\n for i in lst1:\n for j in lst2:\n product = i * j\n if len(products) < n:\n heapq.heappush(products, product)\n else:\n # Push new product and pop the smallest\n heapq.heappushpop(products, product)\n \n # Return the largest products in sorted order\n return sorted(products, reverse=True)", "matching_cluster_idx": 3}, {"solution": "def large_product(lst1, lst2, top_n):\n # Sort both lists to ensure the largest products can be calculated\n lst1.sort(reverse=True)\n lst2.sort(reverse=True)\n \n # Use a heap to efficiently find the top_n products\n import heapq\n \n # Calculate all possible products and maintain a min heap of size top_n\n products = []\n for num1 in lst1:\n for num2 in lst2:\n product = num1 * num2\n if len(products) < top_n:\n heapq.heappush(products, product)\n else:\n heapq.heappushpop(products, product)\n \n # The heap contains the smallest of the top_n elements at the root,\n # So sort the products to get the top_n largest products in descending order\n products.sort(reverse=True)\n \n return products", "matching_cluster_idx": 3}, {"solution": "def large_product(lst1, lst2, k):\n # Combine the elements from both lists into pairs and calculate their products\n products = sorted([i * j for i in lst1 for j in lst2], reverse=True)[:k]\n return products", "matching_cluster_idx": 3}, {"solution": "from heapq import nlargest\nfrom itertools import product\ndef large_product(list1, list2, n):\n \"\"\"\n Finds the n largest products from two lists by selecting one factor from each list.\n \n Args:\n list1: The first list of integers.\n list2: The second list of integers.\n n: The number of largest products to return.\n \n Returns:\n A list containing the n largest products.\n \"\"\"\n # Generate all possible products of elements from list1 and list2\n all_products = [a*b for a, b in product(list1, list2)]\n # Use nlargest from heapq to find the n largest products\n largest_products = nlargest(n, all_products)\n \n return largest_products", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, num):\n # Sort both lists in descending order for easier access to largest elements\n list1.sort(reverse=True)\n list2.sort(reverse=True)\n \n # Use a set to store the unique products and avoid duplicates\n product_set = set()\n \n # Generate products of the elements from both lists\n for x in list1:\n for y in list2:\n product_set.add(x * y)\n \n # Convert the set to a list and sort it in descending order\n product_list = list(product_set)\n product_list.sort(reverse=True)\n \n # Return the required number of largest products\n return product_list[:num]", "matching_cluster_idx": 4}, {"solution": "def large_product(lst1, lst2, k):\n # Sort the first list in descending order\n lst1.sort(reverse=True)\n # Sort the second list in ascending order\n lst2.sort()\n # Use a set to store the products and avoid duplicates\n products = set()\n for num1 in lst1:\n for num2 in lst2:\n products.add(num1 * num2)\n # If the set has more than k elements, remove the smallest one\n if len(products) > k:\n products.remove(min(products))\n # Return a sorted list of the k largest products\n return sorted(products, reverse=True)[:k]", "matching_cluster_idx": 0}, {"solution": "def large_product(list1, list2, k):\n # Sort the first list in descending order to get the largest elements first\n list1.sort(reverse=True)\n \n # Sort the second list in ascending order to get the smallest elements first, which will be helpful for division if needed\n list2.sort()\n \n result = []\n # Use a set to keep track of already used index pairs to avoid duplicate products\n used_indices = set()\n \n for i in range(k):\n max_product = float('-inf')\n max_i = -1\n max_j = -1\n for i1 in range(len(list1)):\n for j1 in range(len(list2)):\n # Check if the index pair has not been used\n if (i1, j1) not in used_indices:\n product = list1[i1] * list2[j1]\n # Find the maximum product\n if product > max_product:\n max_product = product\n max_i = i1\n max_j = j1\n # Add the product to the result list\n result.append(max_product)\n # Add the used index pair to the set\n used_indices.add((max_i, max_j))\n \n return result", "matching_cluster_idx": -1}, {"solution": "def large_product(nums1, nums2, k):\n # Sort the lists in descending order to facilitate finding the largest products\n nums1.sort(reverse=True)\n nums2.sort(reverse=True)\n \n # Use a list comprehension to find the k largest products\n products = sorted([nums1[i] * nums2[j] for i in range(len(nums1)) for j in range(len(nums2))], reverse=True)[:k]\n \n return products", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, k):\n # Combine the products of all pairs from the two lists into a single list\n products = sorted([i * j for i in list1 for j in list2], reverse=True)[:k]\n return products", "matching_cluster_idx": 3}, {"solution": "from heapq import nlargest\nfrom itertools import product\ndef large_product(list1, list2, k):\n # Generate all possible products of elements from list1 and list2\n all_products = [i * j for i, j in product(list1, list2)]\n # Find the k largest products using nlargest from heapq module\n k_largest_products = nlargest(k, all_products)\n return k_largest_products", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, top_n):\n # Sort the lists to optimize the product generation process\n list1.sort()\n list2.sort(reverse=True)\n \n # Use a set to store the products to avoid duplicates\n products = set()\n \n # Generate products and add to the set\n for num1 in list1:\n for num2 in list2:\n products.add(num1 * num2)\n \n # Convert the set to a list and sort it in descending order\n sorted_products = sorted(products, reverse=True)\n \n # Return the top_n largest products\n return sorted_products[:top_n]", "matching_cluster_idx": 4}, {"solution": "from heapq import nlargest\nfrom itertools import product\ndef large_product(list1, list2, k):\n \"\"\"\n Finds the k largest products from two given lists by selecting one factor from each list.\n \n Args:\n list1: First list of integers.\n list2: Second list of integers.\n k: Number of largest products to find.\n \n Returns:\n A list of k largest products.\n \"\"\"\n # Generate all possible products from the two lists\n all_products = [a*b for a, b in product(list1, list2)]\n \n # Find the k largest products\n largest_products = nlargest(k, all_products)\n \n return largest_products", "matching_cluster_idx": 3}, {"solution": "def large_product(arr1, arr2, top_n):\n # Sort the arrays to facilitate finding the largest products\n arr1.sort()\n arr2.sort(reverse=True)\n \n products = []\n # Generate products of all pairs from both arrays\n for num1 in arr1:\n for num2 in arr2:\n products.append(num1 * num2)\n \n # Sort the generated products and slice the top_n largest ones\n products.sort(reverse=True)\n return products[:top_n]", "matching_cluster_idx": 3}, {"solution": "from heapq import nlargest\nfrom itertools import product\ndef large_product(lst1, lst2, n):\n \"\"\"\n Finds the n largest products from two given lists by selecting one factor from each list.\n \n Args:\n lst1 : List[int] - The first list of integers.\n lst2 : List[int] - The second list of integers.\n n : int - The number of largest products to return.\n \n Returns:\n List[int] - A list of the n largest products.\n \"\"\"\n # Generate all possible products\n all_products = (x * y for x, y in product(lst1, lst2))\n # Find the n largest products using nlargest function from heapq\n largest_n_products = nlargest(n, all_products)\n return list(largest_n_products)", "matching_cluster_idx": 4}, {"solution": "from itertools import product\nimport heapq\ndef large_product(list1, list2, k):\n \"\"\"\n Finds the k largest products that can be obtained by multiplying one element from list1 with one element from list2.\n \n :param list1: List of integers\n :param list2: List of integers\n :param k: Number of largest products to find\n :return: List of k largest products, in descending order\n \"\"\"\n # Generate all possible products from the two lists\n all_products = [a*b for a, b in product(list1, list2)]\n # Use heapq to find the k largest products efficiently\n k_largest_products = heapq.nlargest(k, all_products)\n # Return the k largest products in descending order\n return sorted(k_largest_products, reverse=True)", "matching_cluster_idx": 3}, {"solution": "from itertools import product\nimport heapq\ndef large_product(list1, list2, n):\n # Use a heap to find the n largest products\n largest_n_products = heapq.nlargest(n, (x * y for x, y in product(list1, list2)))\n return sorted(largest_n_products, reverse=True)", "matching_cluster_idx": 4}, {"solution": "from itertools import product\nimport heapq\ndef large_product(lst1, lst2, k):\n \"\"\"\n Find the k largest products from two given lists by selecting one factor from each list.\n \n :param lst1: List of integers\n :param lst2: List of integers\n :param k: Number of largest products to find\n :return: List of k largest products\n \"\"\"\n # Use product to get all possible combinations of factors from lst1 and lst2\n # Calculate their products and use heapq to find the k largest ones efficiently\n return heapq.nlargest(k, (x * y for x, y in product(lst1, lst2)))", "matching_cluster_idx": 4}, {"solution": "from itertools import product\nimport heapq\ndef large_product(list1, list2, top_k):\n \"\"\"\n Given two lists of numbers and an integer top_k, find the top_k largest products\n from multiplying one factor from each list.\n \n :param list1: List of integers\n :param list2: List of integers\n :param top_k: Number of top largest products to find\n :return: List of top_k largest products\n \"\"\"\n # Use product to generate all possible pairs and calculate their products\n all_products = (a*b for a, b in product(list1, list2))\n # Use heapq to find the largest top_k products efficiently\n largest_products = heapq.nlargest(top_k, all_products)\n return list(largest_products)", "matching_cluster_idx": 4}, {"solution": "from itertools import product\nimport heapq\ndef large_product(list1, list2, n):\n # Generate all possible products of one element from each list\n all_products = [x*y for x, y in product(list1, list2)]\n # Use heapq to find the n largest products\n n_largest_products = heapq.nlargest(n, all_products)\n return n_largest_products", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, top_k):\n # Sort the lists to ensure list1 contains the largest elements and list2 contains the smallest elements\n list1.sort(reverse=True)\n list2.sort(reverse=True if len(list2) % 2 == 0 else False)\n \n products = []\n for i in list1:\n for j in list2:\n products.append(i * j)\n # If the list of products reaches the top_k size, sort and trim to keep only the largest products\n if len(products) == top_k:\n products.sort(reverse=True)\n products = products[:top_k]\n \n # Final sort to ensure the result is correctly ordered before returning\n products.sort(reverse=True)\n return products[:top_k]", "matching_cluster_idx": 3}]}, "Mbpp/392": {"dps": 30.845070422535212, "dps_norm": 33.84615384615385, "pass@1": 67.0, "profiled": [{"solution": "def get_max_sum(n):\n \"\"\"\n Calculate the maximum sum using the equation f(n) = max( (f(n/2) + f(n/3) + f(n/4) + f(n/5)), n).\n \n Parameters:\n n (int): The input number to calculate the maximum sum.\n \n Returns:\n int: The calculated maximum sum.\n \"\"\"\n # Base case: if n is 0, return 0 as per the equation\n if n == 0:\n return 0\n \n # Calculate the recursive formula\n return max(get_max_sum(n // 2) + get_max_sum(n // 3) + get_max_sum(n // 4) + get_max_sum(n // 5), n)", "matching_cluster_idx": 2}, {"solution": "def get_max_sum(n):\n \"\"\"\n Calculate the maximum sum possible by using the equation f(n) = max( (f(n/2) + f(n/3) + f(n/4) + f(n/5)), n).\n \n Args:\n n (int): The input number.\n \n Returns:\n int: The maximum sum as per the given equation.\n \"\"\"\n # Base case to stop the recursion\n if n <= 1:\n return n\n \n # Calculate the sum as per the given equation\n sum_val = (get_max_sum(n // 2) + get_max_sum(n // 3) + \n get_max_sum(n // 4) + get_max_sum(n // 5))\n \n # Return the maximum of the calculated sum and n itself\n return max(sum_val, n)", "matching_cluster_idx": 3}, {"solution": "def get_max_sum(n):\n \"\"\"\n Calculate the maximum sum using the equation f(n) = max( (f(n/2) + f(n/3) + f(n/4) + f(n/5)), n).\n \n :param n: Integer value to calculate the maximum sum for.\n :return: The maximum sum as per the given equation.\n \"\"\"\n # Base case: if n is less than 6, the maximum value is n itself\n if n < 6:\n return n\n \n # Recursive calculation: calculate f(n) using the given equation\n return max(n, get_max_sum(n // 2) + get_max_sum(n // 3) + get_max_sum(n // 4) + get_max_sum(n // 5))", "matching_cluster_idx": 8}, {"solution": "def get_max_sum(n):\n \"\"\"\n Calculate the maximum sum based on the given equation f(n) = max( (f(n/2) + f(n/3) + f(n/4) + f(n/5)), n).\n \n Args:\n n : int - The input number to start the calculation with.\n \n Returns:\n int - The maximum sum calculated using the equation.\n \"\"\"\n # Base case to prevent infinite recursion and to define the start of the calculation\n if n <= 1:\n return n\n else:\n # Recursive call to calculate the value for n/2, n/3, n/4, and n/5\n return max((get_max_sum(n // 2) + get_max_sum(n // 3) + get_max_sum(n // 4) + get_max_sum(n // 5)), n)", "matching_cluster_idx": 3}, {"solution": "def get_max_sum(n):\n \"\"\"\n Calculate the maximum sum possible using the function f(n) = max((f(n/2) + f(n/3) + f(n/4) + f(n/5)), n).\n \n Args:\n n (int): The input integer for which to calculate the maximum sum.\n \n Returns:\n int: The maximum sum calculated for the given input.\n \"\"\"\n # Base case: If n is less than or equal to 5, return n as the function's result.\n if n <= 5:\n return n\n else:\n # Recursive case: Calculate the sum of f(n/2), f(n/3), f(n/4), and f(n/5),\n # and compare it with n to return the maximum value.\n return max(n, get_max_sum(n // 2) + get_max_sum(n // 3) + get_max_sum(n // 4) + get_max_sum(n // 5))", "matching_cluster_idx": 8}, {"solution": "def get_max_sum(n):\n \"\"\"\n Calculate the maximum sum using the equation f(n) = max( (f(n/2) + f(n/3) + f(n/4) + f(n/5)), n).\n \n Args:\n n (int): The input number to calculate the maximum sum for.\n \n Returns:\n int: The maximum sum possible using the given equation.\n \"\"\"\n # Base case: if n is less than 2, return n\n if n < 2:\n return n\n \n # Recursive case: calculate the maximum sum\n return max(n, get_max_sum(n // 2) + get_max_sum(n // 3) + get_max_sum(n // 4) + get_max_sum(n // 5))", "matching_cluster_idx": 3}, {"solution": "def get_max_sum(n):\n \"\"\"\n Calculate the maximum sum possible using the equation f(n) = max( (f(n/2) + f(n/3) + f(n/4) + f(n/5)), n).\n \n :param n: Integer input for which the maximum sum is to be calculated.\n :return: The maximum sum possible according to the given equation.\n \"\"\"\n # Base case\n if n <= 1:\n return n\n \n # Recursively calculate the sum according to the given equation\n sum_n = (get_max_sum(n // 2) + get_max_sum(n // 3) + get_max_sum(n // 4) + get_max_sum(n // 5))\n \n # Return the maximum of the sum calculated and n itself\n return max(sum_n, n)", "matching_cluster_idx": 3}, {"solution": "def get_max_sum(n):\n \"\"\"\n Calculate the maximum sum using the given equation f(n) = max( (f(n/2) + f(n/3) + f(n/4) + f(n/5)), n).\n \n Args:\n n (int): The input integer.\n \n Returns:\n int: The maximum sum possible using the given equation.\n \"\"\"\n # Base case: if n is less than 2, return n\n if n < 2:\n return n\n \n # Recursively calculate the sum for n/2, n/3, n/4, n/5\n return max((get_max_sum(n // 2) + get_max_sum(n // 3) + get_max_sum(n // 4) + get_max_sum(n // 5)), n)", "matching_cluster_idx": 3}, {"solution": "def get_max_sum(n):\n \"\"\"\n Calculate the maximum sum using the equation f(n) = max( (f(n/2) + f(n/3) + f(n/4) + f(n/5)), n).\n \n Parameters:\n n (int): The input integer.\n \n Returns:\n int: The maximum sum as per the given equation.\n \"\"\"\n # Base case to stop recursion\n if n <= 1:\n return n\n \n # Recursive case: compute the maximum sum\n return max(get_max_sum(n // 2) + get_max_sum(n // 3) + get_max_sum(n // 4) + get_max_sum(n // 5), n)", "matching_cluster_idx": 3}, {"solution": "def get_max_sum(n):\n \"\"\"\n Calculate the maximum sum possible using the function f(n) = max( (f(n/2) + f(n/3) + f(n/4) + f(n/5)), n).\n \n :param n: Integer input for which the maximum sum is to be calculated.\n :return: The maximum sum as per the defined function.\n \"\"\"\n # Base case: if n is less than 4, the maximum value will be n itself.\n if n < 4:\n return n\n \n # Recursive call to calculate the sum using the given formula.\n return max(n, get_max_sum(n // 2) + get_max_sum(n // 3) + get_max_sum(n // 4) + get_max_sum(n // 5))", "matching_cluster_idx": 6}, {"solution": "def get_max_sum(n):\n \"\"\"\n Calculate the maximum sum possible by using the equation f(n) = max( (f(n/2) + f(n/3) + f(n/4) + f(n/5)), n).\n \n Args:\n n (int): The input number to start the calculation.\n \n Returns:\n int: The maximum sum calculated using the equation.\n \"\"\"\n # Base case to prevent infinite recursion and potential stack overflow\n if n <= 1:\n return n\n \n # Recursively calculate the sum using the given equation\n sum_except_n = get_max_sum(n // 2) + get_max_sum(n // 3) + get_max_sum(n // 4) + get_max_sum(n // 5)\n \n # Return the maximum between n and the calculated sum\n return max(sum_except_n, n)", "matching_cluster_idx": 3}, {"solution": "def get_max_sum(n):\n \"\"\"\n Calculates the maximum sum based on the formula:\n f(n) = max( (f(n/2) + f(n/3) + f(n/4) + f(n/5)), n).\n \n Args:\n n (int): The input integer for which the function calculates the maximum sum.\n \n Returns:\n int: The maximum sum calculated based on the given formula.\n \"\"\"\n # Base case: when n is 0, the function returns 0\n if n == 0:\n return 0\n \n # Recursive case: calculate the sum of f(n/2), f(n/3), f(n/4), f(n/5) and compare with n\n return max(get_max_sum(n // 2) + get_max_sum(n // 3) + get_max_sum(n // 4) + get_max_sum(n // 5), n)", "matching_cluster_idx": 2}, {"solution": "def get_max_sum(n):\n \"\"\"\n Calculate the maximum sum possible using the function f(n) = max( (f(n/2) + f(n/3) + f(n/4) + f(n/5)), n).\n \n :param n: Integer input to the function f.\n :return: Maximum sum as per the given equation.\n \"\"\"\n # Base case to stop further recursion\n if n <= 1:\n return n\n \n # Recursively calculate the function values\n div_sum = (get_max_sum(n // 2) + get_max_sum(n // 3) +\n get_max_sum(n // 4) + get_max_sum(n // 5))\n \n # Return the maximum of n and the computed div_sum\n return max(n, div_sum)", "matching_cluster_idx": 3}, {"solution": "def get_max_sum(n):\n \"\"\"\n Calculate the maximum sum possible by using the equation f(n) = max( (f(n/2) + f(n/3) + f(n/4) + f(n/5)), n).\n \n Args:\n n (int): Input integer to calculate the maximum sum.\n \n Returns:\n int: The maximum sum possible according to the given equation.\n \"\"\"\n # Base case to prevent infinite recursion\n if n <= 1:\n return n\n else:\n # Recursive calculation of the sum\n return max((get_max_sum(n // 2) + get_max_sum(n // 3) + get_max_sum(n // 4) + get_max_sum(n // 5)), n)", "matching_cluster_idx": 3}, {"solution": "def get_max_sum(n):\n \"\"\"\n Calculate the maximum sum by recursively applying the formula f(n) = max( (f(n/2) + f(n/3) + f(n/4) + f(n/5)), n).\n \n Parameters:\n n (int): The input integer value.\n \n Returns:\n int: The maximum sum possible by applying the formula.\n \"\"\"\n # Base case to prevent infinite recursion and improve performance\n if n <= 1:\n return n\n else:\n # Recursively calculate the maximum sum\n return max((get_max_sum(n//2) + get_max_sum(n//3) + get_max_sum(n//4) + get_max_sum(n//5)), n)", "matching_cluster_idx": 3}, {"solution": "def get_max_sum(n):\n \"\"\"\n Calculate the maximum sum using the equation f(n) = max( (f(n/2) + f(n/3) + f(n/4) + f(n/5)), n).\n \n Args:\n n (int): Input integer to calculate the maximum sum for.\n \n Returns:\n int: The maximum sum calculated using the given equation.\n \"\"\"\n # Base case: if n is less than or equal to 1, return n itself\n if n <= 1:\n return n\n \n # Recursive call to calculate the maximum sum using the given equation\n return max(n, get_max_sum(n // 2) + get_max_sum(n // 3) + get_max_sum(n // 4) + get_max_sum(n // 5))", "matching_cluster_idx": 3}, {"solution": "def get_max_sum(n):\n \"\"\"\n Calculates the maximum sum using the equation f(n) = max( (f(n/2) + f(n/3) + f(n/4) + f(n/5)), n).\n \n Args:\n n (int): The input number to apply the function on.\n \n Returns:\n int: The maximum sum obtained from the given equation.\n \"\"\"\n # Base case: if n is 0, return 0\n if n == 0:\n return 0\n # Recursive case: calculate the maximum between n and the sum of f(n/2), f(n/3), f(n/4), f(n/5)\n return max(n, get_max_sum(n // 2) + get_max_sum(n // 3) + get_max_sum(n // 4) + get_max_sum(n // 5))", "matching_cluster_idx": 2}, {"solution": "def get_max_sum(n):\n \"\"\"\n Calculate the maximum sum possible by recursively applying the given equation:\n f(n) = max( (f(n/2) + f(n/3) + f(n/4) + f(n/5)), n)\n \n Args:\n n (int): The input integer for which the maximum sum is to be calculated.\n \n Returns:\n int: The maximum sum as per the defined equation.\n \"\"\"\n # Base case: if n is 0, return 0\n if n == 0:\n return 0\n \n # Calculate the recursive sum\n recursive_sum = get_max_sum(n // 2) + get_max_sum(n // 3) + get_max_sum(n // 4) + get_max_sum(n // 5)\n \n # Return the maximum of recursive_sum and n itself\n return max(recursive_sum, n)", "matching_cluster_idx": 2}, {"solution": "def get_max_sum(n):\n \"\"\"\n Calculates the maximum sum using the equation f(n) = max( (f(n/2) + f(n/3) + f(n/4) + f(n/5)), n).\n \n Parameters:\n n (int): The input integer to calculate the maximum sum for.\n \n Returns:\n int: The calculated maximum sum.\n \"\"\"\n # Base case: when n is reduced to 0, return 0 as there's no value to add.\n if n == 0:\n return 0\n \n # Calculate the sum using the provided equation and compare it with n itself.\n # Use integer division (//) for the recursive calls to handle integer division properly.\n calculate_sum = get_max_sum(n // 2) + get_max_sum(n // 3) + get_max_sum(n // 4) + get_max_sum(n // 5)\n \n # Return the maximum of the calculated sum and n itself.\n return max(calculate_sum, n)", "matching_cluster_idx": 2}, {"solution": "def get_max_sum(n):\n \"\"\"\n Calculate the maximum sum possible by using the equation f(n) = max( (f(n/2) + f(n/3) + f(n/4) + f(n/5)), n).\n \n Args:\n n (int): The input integer for the function.\n \n Returns:\n int: The maximum sum calculated using the provided equation.\n \"\"\"\n # Base case to stop the recursion\n if n <= 1:\n return n\n \n # Recursively calculate the sum as per the given equation\n return max(n, get_max_sum(n // 2) + get_max_sum(n // 3) + get_max_sum(n // 4) + get_max_sum(n // 5))", "matching_cluster_idx": 3}]}, "Mbpp/395": {"dps": 98.08429118773947, "dps_norm": 75.0, "pass@1": 100.0, "profiled": [{"solution": "def first_non_repeating_character(s):\n char_count = {}\n \n # Count the occurrence of each character\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n \n # Find the first character with a count of 1\n for char in s:\n if char_count[char] == 1:\n return char\n \n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n char_count = {}\n \n # Count the occurrence of each character\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n \n # Find the first character with a count of 1\n for char in s:\n if char_count[char] == 1:\n return char\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n \"\"\"\n Finds the first non-repeating character in a given string.\n \n Parameters:\n s (str): The input string.\n \n Returns:\n char: The first non-repeating character, or None if all characters repeat.\n \"\"\"\n char_count = {}\n \n # Count the occurrences of each character in the string\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n \n # Find the first character that appears only once\n for char in s:\n if char_count[char] == 1:\n return char\n \n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n from collections import OrderedDict\n \n # Using OrderedDict to remember the order of insertion and count occurrences\n char_order = OrderedDict()\n \n # Counting occurrences of each character\n for char in s:\n if char in char_order:\n char_order[char] += 1\n else:\n char_order[char] = 1\n \n # Finding the first non-repeating character\n for char in char_order:\n if char_order[char] == 1:\n return char\n \n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n char_count = {}\n \n # Count the occurrences of each character\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n \n # Find the first non-repeating character\n for char in s:\n if char_count[char] == 1:\n return char\n \n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n char_count = {}\n \n # Count the occurrences of each character\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n \n # Find the first character with a count of 1\n for char in s:\n if char_count[char] == 1:\n return char\n \n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n char_count = {}\n \n # Count the occurrences of each character\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n \n # Find the first character that appears only once\n for char in s:\n if char_count[char] == 1:\n return char\n \n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n \"\"\"\n Finds the first non-repeating character in a given string.\n \n Parameters:\n s (str): The input string to search through.\n \n Returns:\n str: The first non-repeating character in the string, or None if there is no such character.\n \"\"\"\n # Dictionary to store the count of each character\n char_count = {}\n \n # First pass: count occurrences of each character\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n \n # Second pass: find the first character with a count of 1\n for char in s:\n if char_count[char] == 1:\n return char\n \n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(input_string):\n from collections import OrderedDict\n \n # Using OrderedDict to preserve the order of characters and count their occurrences\n char_order = OrderedDict()\n \n # Counting occurrences of each character\n for char in input_string:\n if char in char_order:\n char_order[char] += 1\n else:\n char_order[char] = 1\n \n # Finding the first character with a count of 1\n for char, count in char_order.items():\n if count == 1:\n return char\n \n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n \"\"\"\n Find the first non-repeating character in a given string.\n \n Parameters:\n s (str): The input string.\n \n Returns:\n char: The first non-repeating character or None if no such character exists.\n \"\"\"\n char_count = {}\n \n # Count the occurrence of each character\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n \n # Find the first character with a count of 1\n for char in s:\n if char_count[char] == 1:\n return char\n \n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n \"\"\"\n Finds the first non-repeating character in a given string.\n \n Parameters:\n s (str): The input string to search within.\n \n Returns:\n str or None: The first non-repeating character, or None if there is none.\n \"\"\"\n \n # Dictionary to count occurrences of each character\n char_count = {}\n \n # First pass: count occurrences\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n \n # Second pass: find the first character with a count of 1\n for char in s:\n if char_count[char] == 1:\n return char\n \n # If no non-repeating character is found, return None\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n from collections import OrderedDict\n \n # Using OrderedDict to remember the order of insertion and count occurrences\n char_order = OrderedDict()\n \n # Count occurrences of each character\n for char in s:\n if char in char_order:\n char_order[char] += 1\n else:\n char_order[char] = 1\n \n # Find the first character with a count of 1\n for char in char_order:\n if char_order[char] == 1:\n return char\n \n # If no non-repeating character is found, return None\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n char_count = {}\n \n # Count the occurrence of each character in the string\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n \n # Find the first character that appears only once\n for char in s:\n if char_count[char] == 1:\n return char\n \n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n char_count = {}\n \n # Count occurrences of each character\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n \n # Find the first character that appears only once\n for char in s:\n if char_count[char] == 1:\n return char\n \n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n \"\"\"\n This function takes a string as input and returns the first non-repeating character.\n If all characters repeat or the string is empty, it returns None.\n \"\"\"\n char_count = {}\n \n # Count the occurrence of each character in the string\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n \n # Find the first character that has only one occurrence\n for char in s:\n if char_count[char] == 1:\n return char\n \n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n \"\"\"\n Finds the first non-repeating character in a given string.\n \n Parameters:\n s (str): The input string to search within.\n \n Returns:\n str: The first non-repeating character, or None if there is no such character.\n \"\"\"\n \n # Dictionary to store the count of each character\n char_count = {}\n \n # First pass: count the occurrence of each character\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n \n # Second pass: find the first non-repeating character\n for char in s:\n if char_count[char] == 1:\n return char\n \n # If no non-repeating character was found\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n \"\"\"\n Finds the first non-repeating character in a given string.\n \n Parameters:\n s (str): The input string to search for the first non-repeating character.\n \n Returns:\n char: The first non-repeating character if found, otherwise returns None.\n \"\"\"\n char_count = {}\n \n # Count the occurrences of each character in the string\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n \n # Find the first character that appears only once\n for char in s:\n if char_count[char] == 1:\n return char\n \n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n from collections import OrderedDict\n \n # Use OrderedDict to remember the order of characters\n char_order = OrderedDict()\n \n # Count the occurrences of each character\n for char in s:\n if char in char_order:\n char_order[char] += 1\n else:\n char_order[char] = 1\n \n # Find the first character with a count of 1\n for char, count in char_order.items():\n if count == 1:\n return char\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n \"\"\"\n Finds the first non-repeating character in a given string.\n \n :param s: String to search within\n :return: The first non-repeating character or None if all characters repeat\n \"\"\"\n char_count = {}\n \n # Count occurrences of each character\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n \n # Identify the first non-repeating character\n for char in s:\n if char_count[char] == 1:\n return char\n \n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n char_count = {}\n \n # Count the occurrences of each character\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n \n # Find the first non-repeating character\n for char in s:\n if char_count[char] == 1:\n return char\n \n return None", "matching_cluster_idx": 5}]}, "Mbpp/405": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def check_tuplex(tuplex, element):\n # Check if the element is in the tuple\n return element in tuplex", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(test_tup, key):\n # Check if the key exists in the tuple\n return key in test_tup", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(test_tup, key):\n # Check if the key is in the tuple by using the 'in' keyword\n return key in test_tup", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(test_tup, key):\n \"\"\"\n Check whether an element exists within a given tuple.\n \n Parameters:\n - test_tup: A tuple to be checked.\n - key: The element to search for within the tuple.\n \n Returns:\n - True if the element is found in the tuple, False otherwise.\n \"\"\"\n # Check if the key exists in the tuple\n return key in test_tup", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(test_tup, key):\n # Check if the key exists in the tuple\n return key in test_tup", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(test_tup, key):\n # Check if the key exists in the tuple\n return key in test_tup", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(test_tup, elem):\n \"\"\"\n Check whether an element exists within a tuple.\n\n Parameters:\n test_tup (tuple): The tuple to search in.\n elem: The element to search for.\n\n Returns:\n bool: True if the element is found, False otherwise.\n \"\"\"\n # Check if the element is in the tuple\n return elem in test_tup", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(test_tup, elem):\n # Check if the element exists in the tuple\n res = elem in test_tup\n return res", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(test_tup, key):\n # Check if the key exists in the tuple by using the 'in' keyword\n return key in test_tup", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(input_tuple, element):\n \"\"\"\n Check if an element exists within a given tuple.\n\n Parameters:\n input_tuple (tuple): The tuple to check the element in.\n element (any): The element to check for in the tuple.\n\n Returns:\n bool: True if the element exists in the tuple, False otherwise.\n \"\"\"\n return element in input_tuple", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(test_tup, key):\n # Check if the key is present in the tuple\n return key in test_tup", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(test_tup, key):\n # Check if the key exists in the tuple\n return key in test_tup", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(test_tup, key):\n # Check if the key exists in the tuple\n return key in test_tup", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(test_tup, key):\n # Check if the key exists in the tuple\n return key in test_tup", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(input_tuple, element):\n # Check if the element exists in the tuple\n return element in input_tuple", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(input_tuple, element):\n # Check if the element exists in the tuple\n return element in input_tuple", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(test_tup, key):\n # Check if the key exists in the tuple\n return key in test_tup", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(test_tup, elem):\n \"\"\"\n Check if the given element exists within the given tuple.\n\n :param test_tup: Tuple in which to search for the element.\n :param elem: Element to search for in the tuple.\n :return: True if the element is found in the tuple, False otherwise.\n \"\"\"\n # Check if the element is in the tuple\n return elem in test_tup", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(input_tuple, element):\n \"\"\"\n Check whether an element exists within a tuple.\n\n Parameters:\n input_tuple (tuple): The tuple to check within.\n element : The element to search for in the tuple.\n\n Returns:\n bool: True if the element is found within the tuple, False otherwise.\n \"\"\"\n return element in input_tuple", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(test_tup, key):\n # Check if the key exists in the tuple\n return key in test_tup", "matching_cluster_idx": 3}]}, "Mbpp/414": {"dps": 72.79503105590062, "dps_norm": 81.66666666666667, "pass@1": 99.0, "profiled": [{"solution": "def overlapping(sequence1, sequence2):\n \"\"\"\n Check if there is any value in sequence1 that exists in sequence2.\n \n Parameters:\n sequence1 (iterable): The first sequence to check.\n sequence2 (iterable): The second sequence to check against.\n \n Returns:\n bool: True if there is at least one common value, False otherwise.\n \"\"\"\n # Convert both sequences to sets to take advantage of O(1) average time complexity for membership tests\n set1 = set(sequence1)\n set2 = set(sequence2)\n \n # Check for any common element using set intersection\n return bool(set1 & set2)", "matching_cluster_idx": 5}, {"solution": "def overlapping(seq1, seq2):\n # Check if any value in seq1 exists in seq2\n return any(value in seq2 for value in seq1)", "matching_cluster_idx": 7}, {"solution": "def overlapping(sequence1, sequence2):\n \"\"\"\n Check whether any value from sequence1 exists in sequence2.\n \n Parameters:\n - sequence1: A list of elements.\n - sequence2: Another list of elements.\n \n Returns:\n - True if any element from sequence1 exists in sequence2.\n - False otherwise.\n \"\"\"\n # Convert sequence2 into a set for efficient lookups\n set_sequence2 = set(sequence2)\n \n # Check if any element in sequence1 exists in set_sequence2\n for item in sequence1:\n if item in set_sequence2:\n return True\n \n # If no element from sequence1 exists in sequence2\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Check whether any value in the first sequence exists in the second sequence.\n \n Parameters:\n seq1 (list): The first list of values.\n seq2 (list): The second list of values.\n \n Returns:\n bool: True if there is at least one common element, otherwise False.\n \"\"\"\n # Convert the second sequence to a set for O(1) lookups\n set_seq2 = set(seq2)\n \n # Check if any element in the first sequence is in the set of second sequence\n return any(element in set_seq2 for element in seq1)", "matching_cluster_idx": 7}, {"solution": "def overlapping(sequence1, sequence2):\n \"\"\"\n Check if there is any overlap (common value) between two sequences.\n \n Parameters:\n sequence1 (list): The first sequence to check.\n sequence2 (list): The second sequence to check.\n \n Returns:\n bool: True if there is any overlap, otherwise False.\n \"\"\"\n # Using set intersection to find any common elements\n return bool(set(sequence1) & set(sequence2))", "matching_cluster_idx": 5}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Check whether any value in seq1 exists in seq2.\n \n Parameters:\n seq1 (list): The first list of elements.\n seq2 (list): The second list of elements.\n \n Returns:\n bool: True if any value in seq1 exists in seq2, otherwise False.\n \"\"\"\n # Convert both sequences into sets and check for intersection\n return bool(set(seq1) & set(seq2))", "matching_cluster_idx": 5}, {"solution": "def overlapping(sequence1, sequence2):\n # Convert the sequences to sets to remove duplicates and allow for O(1) average time complexity for lookups\n set1 = set(sequence1)\n set2 = set(sequence2)\n \n # Check if there is any common element between the two sets\n for item in set1:\n if item in set2:\n return True\n return False", "matching_cluster_idx": 6}, {"solution": "def overlapping(sequence1, sequence2):\n \"\"\"\n Checks whether any value in sequence1 exists in sequence2.\n \n Parameters:\n - sequence1: A list or tuple of elements.\n - sequence2: A list or tuple of elements.\n \n Returns:\n - True if there is at least one common element between sequence1 and sequence2.\n - False otherwise.\n \"\"\"\n # Convert both sequences to sets for efficient lookup and perform intersection\n common_elements = set(sequence1) & set(sequence2)\n \n # Return True if intersection is not empty, else False\n return bool(common_elements)", "matching_cluster_idx": 5}, {"solution": "def overlapping(sequence1, sequence2):\n \"\"\"\n Check if any value from sequence1 exists in sequence2.\n \n Parameters:\n sequence1 (list): The first sequence to check values from.\n sequence2 (list): The second sequence to check for overlapping values.\n \n Returns:\n bool: True if there is at least one overlapping value, otherwise False.\n \"\"\"\n # Convert sequence2 to a set for O(1) lookup times\n set_sequence2 = set(sequence2)\n \n # Check if any value in sequence1 exists in sequence2\n for value in sequence1:\n if value in set_sequence2:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Check if there is any value in seq1 that is also in seq2.\n \n Parameters:\n - seq1: A sequence of elements.\n - seq2: Another sequence of elements.\n \n Returns:\n - bool: True if any value from seq1 exists in seq2, otherwise False.\n \"\"\"\n # Convert seq2 into a set for O(1) average time complexity lookups\n set_seq2 = set(seq2)\n \n # Check each item in seq1 to see if it is in set_seq2\n for item in seq1:\n if item in set_seq2:\n return True\n \n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n # Create a set from the first sequence for faster lookup\n set_seq1 = set(seq1)\n \n # Check if there is any value in seq2 that exists in set_seq1\n for value in seq2:\n if value in set_seq1:\n return True\n \n # If no common value is found, return False\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(sequence1, sequence2):\n \"\"\"\n Check if there is any value in sequence1 that exists in sequence2.\n \n Parameters:\n sequence1 (list): The first list of elements.\n sequence2 (list): The second list of elements.\n \n Returns:\n bool: True if any value from sequence1 exists in sequence2, False otherwise.\n \"\"\"\n # Convert sequence2 into a set for O(1) average-time complexity lookups\n set_sequence2 = set(sequence2)\n \n # Check if any value in sequence1 exists in set_sequence2\n for value in sequence1:\n if value in set_sequence2:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(sequence1, sequence2):\n # Check if there is any common value between the two sequences\n return any(value in sequence2 for value in sequence1)", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Checks if there is any common value between two sequences.\n \n Args:\n seq1 : List[int]\n The first sequence of integers.\n seq2 : List[int]\n The second sequence of integers.\n \n Returns:\n bool\n True if there is at least one common value, False otherwise.\n \"\"\"\n # Convert seq1 to a set for O(1) look-up times\n set_seq1 = set(seq1)\n \n # Check if any value in seq2 is in set_seq1\n for value in seq2:\n if value in set_seq1:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(sequence1, sequence2):\n \"\"\"\n Check if there is any value in sequence1 that exists in sequence2.\n \n Args:\n sequence1: A list of integers.\n sequence2: A list of integers.\n \n Returns:\n A boolean value, True if any value in sequence1 exists in sequence2, otherwise False.\n \"\"\"\n # Convert both sequences to sets and check for intersection\n return bool(set(sequence1) & set(sequence2))", "matching_cluster_idx": 5}, {"solution": "def overlapping(sequence1, sequence2):\n \"\"\"\n Check if there is any value in sequence1 that also exists in sequence2.\n \n Args:\n sequence1: A list of elements.\n sequence2: Another list of elements.\n \n Returns:\n A boolean value, True if there is at least one common element, otherwise False.\n \"\"\"\n # Convert both sequences to sets to remove duplicates and allow set operations\n set1 = set(sequence1)\n set2 = set(sequence2)\n \n # Check for intersection\n if set1 & set2:\n return True\n else:\n return False", "matching_cluster_idx": 5}, {"solution": "def overlapping(sequence1, sequence2):\n \"\"\"\n Checks if there is any common value between two sequences.\n \n Parameters:\n - sequence1: A sequence (list, tuple, etc.) of elements.\n - sequence2: A sequence (list, tuple, etc.) of elements.\n \n Returns:\n - True if there is at least one common value between the two sequences, False otherwise.\n \"\"\"\n # Convert the second sequence to a set for faster lookups\n set_sequence2 = set(sequence2)\n \n # Check if any value in sequence1 exists in sequence2\n for value in sequence1:\n if value in set_sequence2:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(sequence1, sequence2):\n # Check if there's any common element between the two sequences\n return any(element in sequence2 for element in sequence1)", "matching_cluster_idx": 7}, {"solution": "def overlapping(sequence1, sequence2):\n \"\"\"\n Check whether any value from sequence1 exists in sequence2.\n \n Parameters:\n sequence1 (list): The first list to check for overlapping values.\n sequence2 (list): The second list to check against for overlapping values.\n \n Returns:\n bool: True if there is at least one overlapping value, otherwise False.\n \"\"\"\n # Convert sequence2 to a set for O(1) lookups\n set_sequence2 = set(sequence2)\n \n # Check if there is any value in sequence1 that is also in set_sequence2\n for value in sequence1:\n if value in set_sequence2:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(sequence1, sequence2):\n \"\"\"\n Check whether any value in sequence1 exists in sequence2.\n \n Parameters:\n sequence1 (iterable): The first sequence of elements.\n sequence2 (iterable): The second sequence of elements.\n \n Returns:\n bool: True if there is at least one common element, otherwise False.\n \"\"\"\n # Convert sequence2 to a set for O(1) average time complexity lookups\n set_sequence2 = set(sequence2)\n \n # Check if any element of sequence1 is in set_sequence2\n for element in sequence1:\n if element in set_sequence2:\n return True\n return False", "matching_cluster_idx": 7}]}, "Mbpp/421": {"dps": 80.78189300411523, "dps_norm": 89.28571428571428, "pass@1": 100.0, "profiled": [{"solution": "def concatenate_tuple(tup, delimiter='-'):\n # Join tuple elements into a string with the specified delimiter\n result = delimiter.join(map(str, tup))\n return result", "matching_cluster_idx": 5}, {"solution": "def concatenate_tuple(test_tup):\n # Use delimiter '-' to join all elements of the tuple after converting them to string\n res = '-'.join(map(str, test_tup))\n return res", "matching_cluster_idx": 5}, {"solution": "def concatenate_tuple(tup, delimiter='-'):\n # Convert all elements in the tuple to string and join them with the delimiter\n result = delimiter.join(map(str, tup))\n return result", "matching_cluster_idx": 6}, {"solution": "def concatenate_tuple(test_tup):\n # Join the tuple elements into a string with the specified delimiter\n res = '-'.join(map(str, test_tup))\n return res", "matching_cluster_idx": 6}, {"solution": "def concatenate_tuple(tup, delimiter='-'):\n # Convert tuple elements to strings and join them with the delimiter\n return delimiter.join(map(str, tup))", "matching_cluster_idx": 6}, {"solution": "def concatenate_tuple(tup, delimiter='-'):\n \"\"\"\n Concatenate tuple elements into a string, separated by a delimiter.\n \n Parameters:\n - tup: The input tuple.\n - delimiter: The delimiter to use for concatenating the elements.\n \n Returns:\n - A string of concatenated tuple elements.\n \"\"\"\n # Convert each element of the tuple to string and join them using the delimiter\n result = delimiter.join(map(str, tup))\n return result", "matching_cluster_idx": 5}, {"solution": "def concatenate_tuple(tup, delimiter=\"-\"):\n # Join the tuple elements into a string with the specified delimiter\n return delimiter.join(map(str, tup))", "matching_cluster_idx": 6}, {"solution": "def concatenate_tuple(test_tup):\n # Use join method with a tuple converted to a string for each element\n res = '-'.join(map(str, test_tup))\n return res", "matching_cluster_idx": 5}, {"solution": "def concatenate_tuple(tup, delimiter='-'):\n \"\"\"\n Concatenates each element of a given tuple using a specified delimiter.\n \n :param tup: The input tuple containing elements to be concatenated.\n :param delimiter: The string to be used as a delimiter between elements.\n :return: A string with elements of the tuple concatenated by the delimiter.\n \"\"\"\n # Convert tuple elements to strings and join them with the delimiter\n result = delimiter.join(map(str, tup))\n return result", "matching_cluster_idx": 5}, {"solution": "def concatenate_tuple(tup, delimiter='-'):\n \"\"\"\n Concatenates each element of a tuple using a specified delimiter.\n \n :param tup: Tuple containing elements to be concatenated.\n :param delimiter: String to be used as a delimiter between elements.\n :return: A string with tuple elements concatenated by the delimiter.\n \"\"\"\n # Convert tuple elements to strings and join them with the delimiter\n return delimiter.join(map(str, tup))", "matching_cluster_idx": 5}, {"solution": "def concatenate_tuple(tup, delimiter='-'):\n \"\"\"\n Concatenates elements of a tuple using a specified delimiter.\n \n Parameters:\n tup (tuple): The input tuple.\n delimiter (str): The delimiter used for concatenation.\n \n Returns:\n str: A string that concatenates all elements of the input tuple separated by the delimiter.\n \"\"\"\n # Joining the tuple elements using the specified delimiter. \n # str() is used to convert all elements to string before joining.\n return delimiter.join(map(str, tup))", "matching_cluster_idx": 5}, {"solution": "def concatenate_tuple(tup, delimiter='-'):\n # Join tuple elements into a string with specified delimiter\n result = delimiter.join(map(str, tup))\n return result", "matching_cluster_idx": 5}, {"solution": "def concatenate_tuple(test_tup):\n # Use join method with a '-' delimiter on a generator expression that converts each element to a string\n res = '-'.join(str(ele) for ele in test_tup)\n return res", "matching_cluster_idx": 4}, {"solution": "def concatenate_tuple(test_tup):\n # Use join method to concatenate tuple elements with '-' as delimiter\n res = '-'.join(map(str, test_tup))\n return res", "matching_cluster_idx": 6}, {"solution": "def concatenate_tuple(t):\n # Join tuple elements into a string separated by \"-\"\n result = \"-\".join(map(str, t))\n return result", "matching_cluster_idx": 6}, {"solution": "def concatenate_tuple(tup):\n delimiter = \"-\"\n # Join tuple elements using the specified delimiter, converting non-string elements to string\n result = delimiter.join(map(str, tup))\n return result", "matching_cluster_idx": 5}, {"solution": "def concatenate_tuple(tup, delimiter='-'):\n # Convert all elements in the tuple to strings\n str_elements = map(str, tup)\n # Join the string elements with the specified delimiter\n concatenated_str = delimiter.join(str_elements)\n return concatenated_str", "matching_cluster_idx": 5}, {"solution": "def concatenate_tuple(tup, delimiter='-'):\n # Convert each element of the tuple to string and join them using the delimiter\n result = delimiter.join(map(str, tup))\n return result", "matching_cluster_idx": 5}, {"solution": "def concatenate_tuple(test_tup):\n # Convert all elements to strings and join them with a hyphen\n res = '-'.join(map(str, test_tup))\n return res", "matching_cluster_idx": 5}, {"solution": "def concatenate_tuple(tup, delimiter='-'):\n \"\"\"\n Joins tuple elements into a string with a specified delimiter.\n \n Parameters:\n tup (tuple): The tuple to be joined.\n delimiter (str): The delimiter to use between elements (default is '-').\n \n Returns:\n str: The concatenated string with elements separated by the delimiter.\n \"\"\"\n # Convert tuple elements to strings and join them with the delimiter\n result = delimiter.join(map(str, tup))\n return result", "matching_cluster_idx": 5}]}, "Mbpp/424": {"dps": 54.04332129963899, "dps_norm": 81.0, "pass@1": 100.0, "profiled": [{"solution": "def extract_rear(input_tuple):\n # Use list comprehension to iterate over each string in the tuple and get the last character\n return [s[-1] for s in input_tuple]", "matching_cluster_idx": 3}, {"solution": "def extract_rear(tup):\n \"\"\"\n Extracts the last character from each string in the tuple.\n \n Parameters:\n - tup: A tuple of strings\n \n Returns:\n A list containing the last character of each string from the input tuple.\n \"\"\"\n # Use a list comprehension to extract the last character from each string in the tuple\n return [s[-1] for s in tup]", "matching_cluster_idx": 3}, {"solution": "def extract_rear(tup):\n \"\"\"\n Extracts the last character of each string in the given tuple.\n\n Parameters:\n - tup (tuple): A tuple containing strings.\n\n Returns:\n - list: A list of the last characters of each string in the tuple.\n \"\"\"\n # Use a list comprehension to extract the last character of each string in the tuple\n return [item[-1] for item in tup]", "matching_cluster_idx": 3}, {"solution": "def extract_rear(input_tuple):\n # Use a list comprehension to extract the last character of each string in the tuple\n return [item[-1] for item in input_tuple]", "matching_cluster_idx": 3}, {"solution": "def extract_rear(input_tuple):\n # Use a list comprehension to extract the last character from each string in the tuple\n return [string[-1] for string in input_tuple]", "matching_cluster_idx": 3}, {"solution": "def extract_rear(input_tuple):\n # Use list comprehension to iterate over each string in the tuple,\n # and retrieve the last character using slicing.\n return [s[-1] for s in input_tuple]", "matching_cluster_idx": 3}, {"solution": "def extract_rear(input_tuple):\n \"\"\"\n Extracts the last character of each string in the given tuple.\n \n Parameters:\n input_tuple (tuple): A tuple containing strings.\n \n Returns:\n list: A list of the last characters of each string in the input tuple.\n \"\"\"\n # Use a list comprehension to extract the last character from each string\n return [item[-1] for item in input_tuple]", "matching_cluster_idx": 3}, {"solution": "def extract_rear(test_tup):\n # Use a list comprehension to extract the last character from each string in the tuple\n res = [sub[-1] for sub in test_tup]\n return res", "matching_cluster_idx": 3}, {"solution": "def extract_rear(input_tuple):\n # Use a list comprehension to extract the last character of each string in the tuple\n return [item[-1] for item in input_tuple]", "matching_cluster_idx": 3}, {"solution": "def extract_rear(input_tuple):\n \"\"\"\n Extracts the last character from each string within the given tuple.\n \n Parameters:\n input_tuple (tuple): A tuple containing strings.\n \n Returns:\n list: A list containing the last character of each string in the input tuple.\n \"\"\"\n # Extracting the last character of each string in the tuple\n return [item[-1] for item in input_tuple]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(test_tup):\n # Use a list comprehension to iterate over each element in the tuple\n # and extract the last character using slicing.\n res = [sub[-1:] for sub in test_tup]\n return res", "matching_cluster_idx": 3}, {"solution": "def extract_rear(input_tuple):\n # Use a list comprehension to extract the last character from each string in the tuple\n result = [s[-1] for s in input_tuple]\n return result", "matching_cluster_idx": 3}, {"solution": "def extract_rear(input_tuple):\n # Use a list comprehension to extract the last character of each string in the tuple\n return [item[-1] for item in input_tuple]", "matching_cluster_idx": 3}, {"solution": "def extract_rear(tup):\n # Extract the last character of each string in the tuple\n return [s[-1] for s in tup]", "matching_cluster_idx": 3}, {"solution": "def extract_rear(input_tuple):\n # Use a list comprehension to extract the last character of each string in the tuple\n return [s[-1] for s in input_tuple]", "matching_cluster_idx": 3}, {"solution": "def extract_rear(input_tuple):\n # Use list comprehension to extract the last character of each string in the tuple\n return [s[-1] for s in input_tuple]", "matching_cluster_idx": 3}, {"solution": "def extract_rear(input_tuple):\n # Extract the last character of each string in the tuple\n return [s[-1] for s in input_tuple]", "matching_cluster_idx": 3}, {"solution": "def extract_rear(input_tuple):\n # Use list comprehension to extract the last character of each string in the tuple\n return [s[-1] for s in input_tuple]", "matching_cluster_idx": 3}, {"solution": "def extract_rear(input_tuple):\n # Use a list comprehension to iterate through the tuple and get the last character of each string\n return [s[-1] for s in input_tuple]", "matching_cluster_idx": 3}, {"solution": "def extract_rear(input_tuple):\n \"\"\"\n Extracts the last character of each string in the given tuple.\n \n Parameters:\n input_tuple (tuple): A tuple of strings.\n \n Returns:\n list: A list containing the last character of each string in the input tuple.\n \"\"\"\n # Extracting the last character of each string in the tuple\n result = [s[-1] for s in input_tuple]\n \n return result", "matching_cluster_idx": 3}]}, "Mbpp/425": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def count_element_in_list(lists, element):\n count = 0\n for sublist in lists:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, element):\n count = 0\n # Iterate through each sublist in the list\n for sublist in lst:\n # Check if the element is in the current sublist\n if element in sublist:\n # Increment count if the element is found\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lists, element):\n count = 0\n # Iterate through each sublist in the main list\n for sublist in lists:\n # Check if the element is in the current sublist\n if element in sublist:\n count += 1 # Increment the count if the element is found\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, element):\n # Count sublists that contain the specified element\n count = sum(element in sublist for sublist in lst)\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, element):\n # Initialize a counter to keep track of the number of sublists containing the element\n sublist_count = 0\n \n # Iterate through each sublist in the given list\n for sublist in lst:\n # Check if the element is in the current sublist\n if element in sublist:\n # If yes, increment the counter\n sublist_count += 1\n \n return sublist_count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lists, element):\n count = 0\n # Iterate through each sublist in the list\n for sublist in lists:\n # Check if the element is in the current sublist\n if element in sublist:\n # Increment count if the element is found\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, element):\n # Initialize counter to zero\n count = 0\n \n # Iterate through each sublist in the main list\n for sublist in lst:\n # Check if the element is in the current sublist\n if element in sublist:\n # Increment count if the element is found\n count += 1\n \n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, element):\n # Initialize a counter to keep track of the number of sublists containing the element\n count = 0\n \n # Iterate through each sublist in the provided list\n for sublist in lst:\n # If the element is in the sublist, increment the counter\n if element in sublist:\n count += 1\n \n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, element):\n # Initialize a counter to keep track of the number of sublists containing the element\n count = 0\n \n # Iterate through each sublist in the given list\n for sublist in lst:\n # Check if the element is in the current sublist\n if element in sublist:\n # If it is, increment the counter\n count += 1\n \n # Return the final count of sublists that contain the element\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lists, element):\n # Count sublists containing the specified element\n count = sum(element in sublist for sublist in lists)\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lists, element):\n count = 0\n for sublist in lists:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, element):\n count = 0\n # Iterate through each sublist in the given list\n for sublist in lst:\n # Check if the element is in the current sublist\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, element):\n # Initialize the counter to zero\n count = 0\n \n # Loop through each sublist in the provided list\n for sublist in lst:\n # Check if the element is in the current sublist\n if element in sublist:\n # If yes, increment the counter\n count += 1\n \n # Return the final count\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, element):\n count = 0\n # Iterate through each sublist in the list\n for sublist in lst:\n # Check if the element is in the current sublist\n if element in sublist:\n # Increment count if the element is found\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lists, element):\n count = 0\n # Iterate through each sublist in the list\n for sublist in lists:\n # Check if the element is in the current sublist\n if element in sublist:\n count += 1 # Increment count if the element is found\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(list_of_lists, element):\n count = 0\n # Iterate through each sublist in the list of lists\n for sublist in list_of_lists:\n # Check if the element is present in the sublist\n if element in sublist:\n # If present, increment the count\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, element):\n count = 0\n # Iterate through each sublist in the given list\n for sublist in lst:\n # Check if the element is in the current sublist\n if element in sublist:\n # If yes, increment the count\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lists, element):\n # Count the number of sublists containing the specified element\n count = sum(element in sublist for sublist in lists)\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lists, element):\n # Count the number of sublists that contain the specified element\n count = sum(element in sublist for sublist in lists)\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(nested_list, element):\n # Initialize a counter to zero\n count = 0\n \n # Iterate through each sublist in the nested list\n for sublist in nested_list:\n # Check if the element is in the current sublist\n if element in sublist:\n # Increment the counter if the element is found\n count += 1\n \n # Return the final count of sublists containing the element\n return count", "matching_cluster_idx": 4}]}, "Mbpp/428": {"dps": 84.29752066115702, "dps_norm": 55.55555555555556, "pass@1": 100.0, "profiled": [{"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2\n \n # Start with a big gap, then reduce the gap\n while gap > 0:\n # Do a gapped insertion sort for this gap size.\n # The first gap elements a[0..gap-1] are already in gapped order\n # keep adding one more element until the entire array is gap sorted\n for i in range(gap, n):\n temp = arr[i]\n j = i\n # Shift earlier gap-sorted elements up until the correct location for arr[i] is found\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n # Put temp (the original arr[i]) in its correct location\n arr[j] = temp\n gap //= 2\n \n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n \"\"\"\n Function to perform shell sort on the given array.\n \n Parameters:\n arr (list): The array to be sorted.\n \n Returns:\n list: The sorted array.\n \"\"\"\n n = len(arr)\n gap = n // 2\n\n # Start with a big gap, then reduce the gap\n while gap > 0:\n # Do a gapped insertion sort for this gap size.\n # The first gap elements arr[0..gap-1] are already in gapped order\n # keep adding one more element until the entire array is gap sorted\n for i in range(gap, n):\n temp = arr[i]\n # shift earlier gap-sorted elements up until the correct location for arr[i] is found\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n # put temp (the original arr[i]) in its correct location\n arr[j] = temp\n gap //= 2\n \n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2\n \n # Start with a big gap, then reduce the gap\n while gap > 0:\n # Do a gapped insertion sort for this gap size\n for i in range(gap, n):\n temp = arr[i]\n j = i\n # Shift earlier gap-sorted elements up until the correct location for arr[i] is found\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n # Put temp (the original arr[i]) in its correct location\n arr[j] = temp\n gap //= 2\n \n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2\n \n # Start with a big gap, then reduce the gap\n while gap > 0:\n # Do a gapped insertion sort for this gap size.\n # The first gap elements a[0..gap-1] are already in gapped order\n # keep adding one more element until the entire array is gap sorted\n for i in range(gap, n):\n temp = arr[i]\n j = i\n # Shift earlier gap-sorted elements up until the correct location for arr[i] is found\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n # Put temp (the original a[i]) in its correct location\n arr[j] = temp\n gap //= 2\n \n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n # Start with a big gap, then reduce the gap\n n = len(arr)\n gap = n // 2\n \n # Do a gapped insertion sort for this gap size.\n # The first gap elements a[0..gap-1] are already in gapped order\n # keep adding one more element until the entire array is gap sorted\n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n # Shift earlier gap-sorted elements up until the correct location for arr[i] is found\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n # Put temp (the original a[i]) in its correct location\n arr[j] = temp\n gap //= 2\n \n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2\n \n # Keep halving the gap and run the insertion sort on elements that are 'gap' distance apart\n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n # Sort elements that are 'gap' distance apart\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n # Reduce the gap for the next element\n gap //= 2\n \n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2\n \n # Start with a big gap, then reduce the gap\n while gap > 0:\n # Do a gapped insertion sort for this gap size.\n # The first gap elements arr[0..gap-1] are already in gapped order\n # keep adding one more element until the entire array is gap sorted\n for i in range(gap, n):\n temp = arr[i]\n j = i\n # shift earlier gap-sorted elements up until the correct location for arr[i] is found\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n # put temp (the original arr[i]) in its correct location\n arr[j] = temp\n gap //= 2\n \n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2\n \n # Start with a big gap, then reduce the gap\n while gap > 0:\n # Do a gapped insertion sort for this gap size.\n # The first gap elements a[0..gap-1] are already in gapped order\n # keep adding one more element until the entire array is gap sorted\n for i in range(gap, n):\n temp = arr[i]\n j = i\n # Shift earlier gap-sorted elements up until the correct location\n # for arr[i] is found\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n # Put temp (the original a[i]) in its correct location\n arr[j] = temp\n gap //= 2\n \n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n # Start with a big gap, then reduce the gap\n n = len(arr)\n gap = n // 2\n \n # Do a gapped insertion sort for this gap size.\n # The first gap elements arr[0..gap-1] are already in gapped order\n # keep adding one more element until the entire array is gap sorted\n while gap > 0:\n for i in range(gap, n):\n # add arr[i] to the elements that have been gap sorted\n # save arr[i] in temp and make a hole at position i\n temp = arr[i]\n \n # shift earlier gap-sorted elements up until the correct location for arr[i] is found\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n \n # put temp (the original arr[i]) in its correct location\n arr[j] = temp\n \n gap //= 2\n \n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2\n \n # Keep sorting until the gap is zero\n while gap > 0:\n # Perform insertion sort with the gap\n for i in range(gap, n):\n temp = arr[i]\n j = i\n # Swap elements if the element at the gap is lower\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n \n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2\n \n # Start with a big gap, then reduce the gap\n while gap > 0:\n # Perform insertion sort with elements that are 'gap' apart\n for i in range(gap, n):\n temp = arr[i]\n j = i\n # Shift earlier gap-sorted elements up until the correct location for arr[i] is found\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n # Put temp (the original arr[i]) in its correct location\n arr[j] = temp\n # Reduce the gap for the next element\n gap //= 2\n \n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2 # Initial gap size\n\n # Keep making passes through the array until the gap size is 0\n while gap > 0:\n # Perform insertion sort with elements that are 'gap' distance apart\n for i in range(gap, n):\n temp = arr[i]\n j = i\n # Shift earlier gap-sorted elements up until the correct location for arr[i] is found\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n # Put temp (the original arr[i]) in its correct location\n arr[j] = temp\n # Decrease the gap for the next stage\n gap //= 2\n \n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2\n\n # Start with a big gap, then reduce the gap\n while gap > 0:\n # Do a gapped insertion sort for this gap size.\n # The first gap elements a[0..gap-1] are already in gapped order\n # keep adding one more element until the entire array is gap sorted\n for i in range(gap, n):\n temp = arr[i]\n j = i\n # Shift earlier gap-sorted elements up until the correct location for arr[i] is found\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n # Put temp (the original a[i]) in its correct location\n arr[j] = temp\n gap //= 2 # Reduce the gap for the next element\n\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n \"\"\"\n Function to perform shell sort on the given array.\n \n Parameters:\n arr (list): The list of numbers to be sorted.\n \n Returns:\n list: The sorted list.\n \"\"\"\n n = len(arr)\n gap = n // 2\n \n # Start with a big gap, then reduce the gap\n while gap > 0:\n # Do a gapped insertion sort for this gap size.\n # The first gap elements a[0..gap-1] are already in gapped order\n # keep adding one more element until the entire array is gap sorted\n for i in range(gap, n):\n temp = arr[i]\n j = i\n # Shift earlier gap-sorted elements up until the correct location for arr[i] is found\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n # Put temp (the original arr[i]) in its correct location\n arr[j] = temp\n gap //= 2\n \n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2 # Initial gap size\n \n # Start with a big gap, then reduce the gap\n while gap > 0:\n # Do a gapped insertion sort for this gap size\n # The first gap elements arr[0..gap-1] are already in gapped order\n # keep adding one more element until the entire array is gap sorted\n for i in range(gap, n):\n temp = arr[i]\n j = i\n # Shift earlier gap-sorted elements up until the correct location for arr[i] is found\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n # Put temp (the original arr[i]) in its correct location\n arr[j] = temp\n # Reduce the gap for the next element\n gap //= 2\n \n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n \"\"\"\n Function to sort an array using Shell Sort.\n \"\"\"\n # Start with a big gap, then reduce the gap\n n = len(arr)\n gap = n // 2\n \n # Do a gapped insertion sort for this gap size.\n # The first gap elements a[0..gap-1] are already in gapped order\n # keep adding one more element until the entire array is gap sorted\n while gap > 0:\n for i in range(gap, n):\n # add a[i] to the elements that have been gap sorted\n # save a[i] in temp and make a hole at position i\n temp = arr[i]\n # shift earlier gap-sorted elements up until the correct location for a[i] is found\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n # put temp (the original a[i]) in its correct location\n arr[j] = temp\n gap //= 2\n \n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n \"\"\"\n Sorts an array using shell sort.\n \n Parameters:\n arr (list): The list of elements to be sorted.\n \n Returns:\n list: The sorted list.\n \"\"\"\n n = len(arr)\n gap = n // 2\n \n # Start with a big gap, then reduce the gap\n while gap > 0:\n # Do a gapped insertion sort for this gap size.\n # The first gap elements a[0..gap-1] are already in gapped order\n # keep adding one more element until the entire array is gap sorted\n for i in range(gap, n):\n temp = arr[i]\n # Shift earlier gap-sorted elements up until the correct location\n # for arr[i] is found\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n # Put temp (the original a[i]) in its correct location\n arr[j] = temp\n gap //= 2\n \n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2\n \n # Keep looping until gap is zero\n while gap > 0:\n # Perform insertion sort with elements that are 'gap' apart\n for i in range(gap, n):\n temp = arr[i]\n j = i\n # Sort sub-list\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n \n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2\n \n # Start with a big gap, then reduce the gap\n while gap > 0:\n # Do a gapped insertion sort for this gap size\n for i in range(gap, n):\n temp = arr[i]\n j = i\n # Shift earlier gap-sorted elements up until the correct location for arr[i] is found\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n # Put temp (the original arr[i]) in its correct location\n arr[j] = temp\n gap //= 2\n \n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n \"\"\"\n Sorts an array using Shell sort algorithm.\n \n Parameters:\n arr (list): The list of elements to be sorted.\n \n Returns:\n list: The sorted list.\n \"\"\"\n n = len(arr)\n gap = n // 2\n \n # Start with a big gap, then reduce the gap\n while gap > 0:\n # Do a gapped insertion sort for this gap size.\n # The first gap elements a[0..gap-1] are already in gapped order\n # keep adding one more element until the entire array is gap sorted\n for i in range(gap, n):\n temp = arr[i]\n # shift earlier gap-sorted elements up until the correct location for arr[i] is found\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n # put temp (the original a[i]) in its correct location\n arr[j] = temp\n gap //= 2\n \n return arr", "matching_cluster_idx": 4}]}, "Mbpp/433": {"dps": 69.41489361702128, "dps_norm": 69.0, "pass@1": 100.0, "profiled": [{"solution": "def check_greater(arr, num):\n # Check if the given number is greater than all elements in the array\n for element in arr:\n if num <= element:\n return False\n return True", "matching_cluster_idx": 3}, {"solution": "def check_greater(arr, num):\n # Check if the number is greater than all elements in the array\n return all(x < num for x in arr)", "matching_cluster_idx": 2}, {"solution": "def check_greater(arr, num):\n # Check if the given number is greater than all elements in the array\n return all(x < num for x in arr)", "matching_cluster_idx": 2}, {"solution": "def check_greater(arr, num):\n # Check if the given number is greater than all elements in the array\n for element in arr:\n if num <= element:\n return False\n return True", "matching_cluster_idx": 3}, {"solution": "def check_greater(arr, num):\n # Check if the given number is greater than all elements in the array\n return all(x < num for x in arr)", "matching_cluster_idx": 2}, {"solution": "def check_greater(arr, num):\n # Check if the number is greater than all elements in the array\n return all(x < num for x in arr)", "matching_cluster_idx": 2}, {"solution": "def check_greater(arr, num):\n # Check if the given number is greater than all elements in the array\n return all(x < num for x in arr)", "matching_cluster_idx": 2}, {"solution": "def check_greater(arr, num):\n # Check if the given number is greater than all elements in the array\n for element in arr:\n if num <= element:\n return False\n return True", "matching_cluster_idx": 3}, {"solution": "def check_greater(arr, x):\n # Check if the number x is greater than all elements in the array\n return all(item < x for item in arr)", "matching_cluster_idx": 2}, {"solution": "def check_greater(arr, num):\n # Check if the number is greater than all elements in the array\n return all(x < num for x in arr)", "matching_cluster_idx": 2}, {"solution": "def check_greater(arr, num):\n # Check if the number is greater than all elements in the array\n return all(x < num for x in arr)", "matching_cluster_idx": 2}, {"solution": "def check_greater(arr, num):\n # Check if the number is greater than all elements in the array\n return all(x < num for x in arr)", "matching_cluster_idx": 2}, {"solution": "def check_greater(arr, num):\n # Check if the number is greater than all elements in the array\n return all(x < num for x in arr)", "matching_cluster_idx": 2}, {"solution": "def check_greater(arr, num):\n # Check if the number is greater than all elements in the array\n for element in arr:\n if num <= element:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def check_greater(arr, num):\n # Check if the number is greater than all elements in the array\n for element in arr:\n if num <= element:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def check_greater(arr, num):\n # Check if the number is greater than all elements in the array\n for element in arr:\n if num <= element:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def check_greater(arr, num):\n # Check if the number is greater than all elements in the array\n return all(x < num for x in arr)", "matching_cluster_idx": 2}, {"solution": "def check_greater(arr, num):\n # Check if the number is greater than all elements in the array\n return all(x < num for x in arr)", "matching_cluster_idx": 2}, {"solution": "def check_greater(arr, num):\n # Check if the given number is greater than all elements in the array\n return all(x < num for x in arr)", "matching_cluster_idx": 2}, {"solution": "def check_greater(array, num):\n # Check if the given number is greater than all elements in the array\n return all(x < num for x in array)", "matching_cluster_idx": 2}]}, "Mbpp/437": {"dps": 70.58823529411765, "dps_norm": 20.0, "pass@1": 15.0, "profiled": [{"solution": "def remove_odd(s):\n # Using list comprehension to filter out odd indexed characters\n # +1 to make it 1-indexed for the condition\n result = [char for index, char in enumerate(s) if (index + 1) % 2 == 0]\n # Joining the list back to a string\n return ''.join(result)", "matching_cluster_idx": 0}, {"solution": "def remove_odd(s):\n # Using list comprehension to filter out odd indexed characters (0-based index)\n return ''.join([c for i, c in enumerate(s) if i % 2 == 1])", "matching_cluster_idx": 0}, {"solution": "def remove_odd(input_string):\n # Initialize an empty string to store even-positioned characters\n result = ''\n # Iterate through the string, starting from index 1 to include the first character\n for i in range(1, len(input_string) + 1):\n # Check if the index is even\n if i % 2 == 0:\n # Append the character at the current index to the result\n result += input_string[i - 1]\n return result", "matching_cluster_idx": 0}, {"solution": "def remove_odd(s):\n # Use a list comprehension to filter out characters at odd indices\n return ''.join([c for i, c in enumerate(s) if i % 2 == 1])", "matching_cluster_idx": 0}, {"solution": "def remove_odd(s):\n # Using list comprehension to filter out odd indexed characters (0-based index)\n return ''.join([char for index, char in enumerate(s) if index % 2 == 1])", "matching_cluster_idx": 0}, {"solution": "def remove_odd(input_string):\n \"\"\"Remove odd characters in a string.\"\"\"\n # Using list comprehension to filter out odd-indexed characters (0-based index)\n result = ''.join([char for index, char in enumerate(input_string) if index % 2 == 1])\n return result", "matching_cluster_idx": 0}, {"solution": "def remove_odd(s):\n # Use list comprehension to filter out odd-indexed characters (0-based index)\n # and then join them back into a string\n return ''.join([char for index, char in enumerate(s) if index % 2 == 1])", "matching_cluster_idx": 0}, {"solution": "def remove_odd(s):\n # Use list comprehension to filter out odd indexed characters\n # In Python, string indexing starts at 0, so even indices correspond to odd positions in the string\n result = ''.join([char for index, char in enumerate(s) if index % 2 == 1])\n return result", "matching_cluster_idx": 0}, {"solution": "def remove_odd(input_string):\n # Use list comprehension to filter out odd indexed characters\n # Indices are adjusted by 1 to match human counting (starting from 1)\n return ''.join([char for index, char in enumerate(input_string) if index % 2 == 1])", "matching_cluster_idx": 0}, {"solution": "def remove_odd(input_string):\n \"\"\"Remove odd characters from the input string.\"\"\"\n # Use list comprehension to filter out characters at odd indices\n result = ''.join([char for index, char in enumerate(input_string) if index % 2 == 1])\n return result", "matching_cluster_idx": 0}, {"solution": "def remove_odd(s):\n # Use a list comprehension to filter out odd-indexed characters (0-based index)\n # Convert the result back to a string using ''.join()\n return ''.join([c for i, c in enumerate(s) if i % 2 == 1])", "matching_cluster_idx": 0}, {"solution": "def remove_odd(input_string):\n # Use a list comprehension to filter out characters at odd indices\n result = ''.join([char for index, char in enumerate(input_string) if index % 2 == 1])\n return result", "matching_cluster_idx": 0}, {"solution": "def remove_odd(input_string):\n # Filter out odd characters (1-indexed) by keeping even indices (0-indexed)\n return ''.join([char for index, char in enumerate(input_string) if index % 2 == 1])", "matching_cluster_idx": 0}, {"solution": "def remove_odd(s):\n # Use list comprehension to filter out odd-indexed characters and join them back into a string\n return ''.join([char for index, char in enumerate(s) if index % 2 == 1])", "matching_cluster_idx": 0}, {"solution": "def remove_odd(s):\n # Use list comprehension to filter out odd indexed characters (0-based index)\n result = ''.join([c for i, c in enumerate(s) if i % 2 == 1])\n return result", "matching_cluster_idx": 0}]}, "Mbpp/440": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 18.0, "profiled": [{"solution": "import re\ndef find_adverb_position(sentence):\n # Use regex to find the first adverb in the sentence\n match = re.search(r'\\w+ly', sentence)\n if match:\n # Extract start and end position and the adverb itself\n position = (match.start(), match.end(), match.group())\n else:\n position = None\n return position", "matching_cluster_idx": 3}, {"solution": "import re\nimport unittest\ndef find_adverb_position(sentence):\n # Use regular expression to find the first adverb in the sentence\n match = re.search(r'\\w+ly', sentence)\n # Check if an adverb was found\n if match:\n # Return a tuple with the start and end position of the adverb, and the adverb itself\n return (match.start(), match.end(), match.group())\n else:\n return None", "matching_cluster_idx": 3}, {"solution": "import re\nfrom typing import Tuple\ndef find_adverb_position(sentence: str) -> Tuple[int, int, str]:\n \"\"\"\n Find the first adverb and its position in a given sentence.\n \n Parameters:\n sentence (str): The sentence to search within.\n \n Returns:\n Tuple[int, int, str]: A tuple containing the start index, end index, and the adverb found in the sentence.\n \"\"\"\n # Regular expression to find adverbs (ending with 'ly')\n pattern = r'\\w+ly'\n match = re.search(pattern, sentence)\n \n if match:\n start, end = match.span()\n return start, end, match.group()\n else:\n return None", "matching_cluster_idx": 3}, {"solution": "import re\ndef find_adverb_position(sentence):\n # Regular expression to match adverbs ending in 'ly'\n regex = r\"\\w+ly\"\n \n # Search for the first occurrence of an adverb in the sentence\n match = re.search(regex, sentence)\n \n # If an adverb is found, return its span (start and end positions) and the adverb itself\n if match:\n span = match.span()\n return (span[0], span[1], sentence[span[0]:span[1]])\n else:\n return None", "matching_cluster_idx": 3}, {"solution": "import re\ndef find_adverb_position(sentence):\n # Regular expression to find adverbs\n adverb_pattern = r'\\w+ly'\n \n # Find the first occurrence of an adverb in the sentence\n match = re.search(adverb_pattern, sentence)\n \n # If an adverb is found, return the tuple with start position, end position, and adverb\n if match:\n return (match.start(), match.end(), match.group(0))\n else:\n return None", "matching_cluster_idx": 3}, {"solution": "import re\ndef find_adverb_position(sentence):\n # Use regular expression to find the first adverb\n match = re.search(r'\\w+ly', sentence)\n if match:\n # Return the start position, end position, and the adverb itself\n return (match.start(), match.end(), match.group())\n return None", "matching_cluster_idx": 3}, {"solution": "import re\ndef find_adverb_position(sentence):\n # Regular expression to match adverbs ending with 'ly'\n adverb_pattern = r'\\w+ly'\n match = re.search(adverb_pattern, sentence)\n \n # Check if an adverb was found\n if match:\n start_position = match.start()\n end_position = match.end()\n return start_position, end_position, match.group()\n else:\n return None", "matching_cluster_idx": 3}, {"solution": "import re\ndef find_adverb_position(sentence):\n # Regular expression to match adverbs, typically ending with 'ly'\n adverb_pattern = r'\\w+ly'\n \n # Find the first match in the sentence\n match = re.search(adverb_pattern, sentence)\n \n # If a match is found, return the position and the word\n if match:\n return match.start(), match.end(), match.group()\n else:\n return None", "matching_cluster_idx": 3}, {"solution": "import re\ndef find_adverb_position(sentence):\n # Regular expression to match adverbs ending in 'ly'\n adverb_pattern = r\"\\w+ly\"\n \n # Find the first occurrence of an adverb in the sentence\n match = re.search(adverb_pattern, sentence)\n \n # If a match is found, return its span and matched text\n if match:\n start, end = match.span()\n return start, end, match.group()\n else:\n # If no adverb is found, return None\n return None", "matching_cluster_idx": 3}, {"solution": "import re\ndef find_adverb_position(sentence):\n # Use regular expression to find the first adverb in the sentence\n match = re.search(r'\\w+ly', sentence)\n \n # Check if an adverb was found and return the appropriate result\n if match:\n start = match.start()\n end = match.end()\n adverb = match.group()\n return start, end, adverb\n else:\n return None", "matching_cluster_idx": 3}, {"solution": "import re\ndef find_adverb_position(sentence):\n # Regular expression to match adverbs, typically ending in 'ly'\n pattern = r\"\\w+ly\"\n \n # Search for the first occurrence of an adverb in the sentence\n match = re.search(pattern, sentence)\n \n # Check if an adverb was found\n if match:\n # Return the start and end position, along with the adverb found\n return (match.start(), match.end(), match.group())\n else:\n # Return None if no adverb is found\n return None", "matching_cluster_idx": 3}, {"solution": "import re\nfrom typing import Tuple\ndef find_adverb_position(sentence: str) -> Tuple[int, int, str]:\n \"\"\"\n Finds the first adverb in a given sentence and returns its position and the word itself.\n An adverb is identified by the regex pattern r'\\w+ly'.\n \n :param sentence: A string representing the sentence to search in.\n :return: A tuple containing the start position, end position, and the adverb found.\n \"\"\"\n # Compile the regex to find adverbs\n adverb_pattern = re.compile(r'\\w+ly')\n \n # Search for the first occurrence of an adverb\n match = adverb_pattern.search(sentence)\n \n if match:\n # If an adverb is found, return its start, end, and the word itself\n start_pos = match.start()\n end_pos = match.end()\n adverb = match.group()\n return start_pos, end_pos, adverb\n else:\n # If no adverb is found, return None\n return None", "matching_cluster_idx": 3}, {"solution": "import re\ndef find_adverb_position(sentence):\n # Regular expression to match adverbs ending in 'ly'\n pattern = r'\\w+ly'\n match = re.search(pattern, sentence)\n if match:\n # Return the start and end position of the adverb, and the adverb itself\n return (match.start(), match.end(), match.group(0))\n else:\n return None", "matching_cluster_idx": 3}, {"solution": "import re\nfrom typing import Tuple\ndef find_adverb_position(sentence: str) -> Tuple[int, int, str]:\n \"\"\"\n Finds the first adverb in the given sentence and returns its start position,\n end position, and the adverb itself.\n \n :param sentence: The sentence to search for the first adverb.\n :return: A tuple containing the start position, end position, and the adverb.\n \"\"\"\n # Regular expression pattern to match adverbs that typically end in 'ly'\n pattern = r'\\w+ly'\n \n match = re.search(pattern, sentence)\n \n if match:\n start, end = match.span()\n return start, end, sentence[start:end]\n else:\n return None", "matching_cluster_idx": 3}, {"solution": "import re\ndef find_adverb_position(sentence):\n # Regular expression to match adverbs typically ending with 'ly'\n pattern = r'\\w+ly'\n match = re.search(pattern, sentence)\n \n # If there is a match, return the start and end positions and the matched word\n if match:\n return match.start(), match.end(), match.group()\n else:\n return None", "matching_cluster_idx": 3}, {"solution": "import re\nfrom typing import Tuple\ndef find_adverb_position(sentence: str) -> Tuple[int, int, str]:\n \"\"\"\n Finds the first adverb and its positions in the given sentence.\n \n Parameters:\n sentence (str): The sentence to search for the first adverb.\n \n Returns:\n Tuple[int, int, str]: A tuple containing the start index, end index (exclusive), and the adverb itself.\n \"\"\"\n # Regular expression to find adverbs ending in 'ly'\n pattern = r\"\\w+ly\"\n \n # Search for the first adverb in the sentence\n match = re.search(pattern, sentence)\n \n # If an adverb is found, return its position and the adverb itself\n if match:\n start, end = match.span()\n return start, end, match.group()\n else:\n # Return None if no adverb is found\n return None", "matching_cluster_idx": 3}, {"solution": "import re\ndef find_adverb_position(sentence):\n # Regular expression to match adverbs typically ending with 'ly'\n pattern = r'\\w+ly'\n \n # Search the sentence for the first match of an adverb\n match = re.search(pattern, sentence)\n \n # If an adverb is found, return the start and end positions along with the adverb\n if match:\n start, end = match.span()\n return start, end, match.group()\n else:\n # Return None if no adverb is found\n return None", "matching_cluster_idx": 3}, {"solution": "import re\nimport unittest\ndef find_adverb_position(sentence):\n # Regular expression to find adverbs, typically ending in 'ly'\n adverb_pattern = re.compile(r'\\w+ly')\n \n # Search for the first occurrence of an adverb in the sentence\n match = adverb_pattern.search(sentence)\n \n # If an adverb is found, return its span and the adverb itself\n if match:\n span = match.span()\n adverb = match.group()\n return (span[0], span[1], adverb)\n else:\n # If no adverb is found, return None\n return None", "matching_cluster_idx": 3}]}, "Mbpp/446": {"dps": 96.45320197044335, "dps_norm": 64.0, "pass@1": 49.0, "profiled": [{"solution": "def count_Occurrence(test_tup, test_list):\n # Initialize a counter for occurrences\n count = 0\n \n # Iterate through the list to check each element's occurrence in the tuple\n for ele in test_list:\n count += test_tup.count(ele)\n \n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tup, lst):\n \"\"\"\n Counts the total occurrences of each element in the list 'lst' within the tuple 'tup'.\n \n Parameters:\n tup (tuple): The tuple in which to count occurrences.\n lst (list): The list containing the elements to count in the tuple.\n \n Returns:\n int: The total number of occurrences of all elements in 'lst' within 'tup'.\n \"\"\"\n # Initialize a counter\n count = 0\n \n # Iterate through each element in the list\n for element in lst:\n # Count the occurrences of the element in the tuple and add to the total count\n count += tup.count(element)\n \n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(test_tup, lst):\n # Count the occurrence of each element in the tuple and sum the counts of the elements in the list\n return sum(test_tup.count(ele) for ele in lst)", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(test_tup, test_list):\n # Initialize a counter to 0\n counter = 0\n \n # Iterate through each item in the list\n for ele in test_list:\n # Check if the element is in the tuple and update the counter\n counter += test_tup.count(ele)\n \n return counter", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(test_tup, test_list):\n # Initialize a counter to zero\n counter = 0\n \n # Loop through each element in the list\n for element in test_list:\n # If the element is in the tuple, count the occurrences and add to counter\n counter += test_tup.count(element)\n \n return counter", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(input_tuple, elements_list):\n # Initialize a counter variable\n count = 0\n \n # Loop through each element in the elements_list\n for element in elements_list:\n # Count occurrences of the element in the input_tuple\n count += input_tuple.count(element)\n \n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(test_tup, list_k):\n # Count occurrences of elements in the list within the tuple\n res = sum(map(test_tup.count, list_k))\n return res", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(input_tuple, elements_to_count):\n # Initialize a counter to zero\n total_occurrences = 0\n \n # Iterate through each element in the list `elements_to_count`\n for element in elements_to_count:\n # Use the count method of the tuple to find how many times `element` occurs in `input_tuple`\n # Add this count to `total_occurrences`\n total_occurrences += input_tuple.count(element)\n \n # Return the total number of occurrences of the elements in `elements_to_count`\n return total_occurrences", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(test_tup, tar_list):\n # Count the occurrence of all elements in tar_list within the tuple test_tup\n res = sum(map(test_tup.count, tar_list))\n return res", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(test_tup, test_list):\n # Count the occurrence of each element in the tuple\n element_count = {}\n for element in test_tup:\n if element in element_count:\n element_count[element] += 1\n else:\n element_count[element] = 1\n \n # Sum the count of elements that are present in the list\n sum_occurrences = sum(element_count.get(element, 0) for element in test_list)\n \n return sum_occurrences", "matching_cluster_idx": 4}, {"solution": "def count_Occurrence(test_tup, test_list):\n # Count the occurrence of each element in the tuple\n element_counts = {}\n for element in test_tup:\n if element in element_counts:\n element_counts[element] += 1\n else:\n element_counts[element] = 1\n \n # Sum the occurrences of the specified elements in the list\n return sum(element_counts.get(elem, 0) for elem in test_list)", "matching_cluster_idx": 4}, {"solution": "def count_Occurrence(test_tup, search_list):\n # Count occurrences of each element in search_list within test_tup\n count = sum(test_tup.count(element) for element in search_list)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(test_tup, test_list):\n # Count occurrences of each element in the tuple that are also in the list\n return sum(map(lambda el: test_tup.count(el), test_list))", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(test_tup, IP_list):\n \"\"\"\n This function counts the occurrences of all elements in IP_list within test_tup.\n \n Parameters:\n test_tup (tuple): The tuple in which to count occurrences.\n IP_list (list): The list of elements whose occurrences need to be counted.\n \n Returns:\n int: The total count of occurrences of elements in IP_list within test_tup.\n \"\"\"\n # Using sum() and map() to count occurrences of each element in IP_list within the tuple\n return sum([test_tup.count(ele) for ele in IP_list])", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(test_tup, IP_list):\n # Initialize a counter to zero\n counter = 0\n \n # Iterate through the elements in the list\n for ele in IP_list:\n # Count occurrences of the element in the tuple and add it to the counter\n counter += test_tup.count(ele)\n \n return counter", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(test_tup, list_k):\n # Count occurrences of each element in the tuple that is also in list_k\n res = sum(map(lambda el: test_tup.count(el), list_k))\n return res", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(test_tup, test_list):\n # Count the occurrence of each element in the tuple that is also in test_list\n return sum(map(lambda ele: test_tup.count(ele), test_list))", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(test_tup, test_list):\n # Count occurrences of each element in the tuple that is also in the list\n res = sum(map(lambda el: test_tup.count(el), test_list))\n return res", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(test_tup, test_list):\n # Count the occurrences of each element in the tuple that is also in the list\n res = sum(map(test_list.count, test_tup))\n return res", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(test_tup, test_list):\n # Count occurrences of each element in the tuple that is also in the list\n res = sum(map(test_list.count, test_tup))\n return res", "matching_cluster_idx": 2}]}, "Mbpp/451": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 77.0, "profiled": [{"solution": "def remove_whitespaces(s):\n # Using str.replace() to remove whitespaces\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(s):\n # Use str.replace to replace all spaces with an empty string\n no_spaces = s.replace(\" \", \"\")\n return no_spaces", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(string):\n # Use the replace method to substitute spaces with an empty string\n no_whitespaces = string.replace(\" \", \"\")\n return no_whitespaces", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(s):\n # Use the replace method to eliminate spaces from the string\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(s):\n # Use the replace method to remove all spaces from the string\n return s.replace(' ', '')", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(s):\n # Use the replace method to substitute spaces with an empty string\n no_spaces = s.replace(\" \", \"\")\n return no_spaces", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(s):\n # Use str.replace() method to replace all whitespaces with no character\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(s):\n # Using the replace method to eliminate spaces\n result = s.replace(\" \", \"\")\n return result", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string):\n # Use the replace method to remove all spaces from the input string\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string):\n # Use the replace method to eliminate all whitespace characters\n result = input_string.replace(\" \", \"\")\n return result", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string):\n # Use the replace method to remove all whitespaces\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string):\n # Use the replace method to remove all whitespaces from the input string\n no_space_str = input_string.replace(\" \", \"\")\n return no_space_str", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(s):\n # Use the replace method to substitute spaces with an empty string\n no_spaces = s.replace(\" \", \"\")\n return no_spaces", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(s):\n # Use the replace method to eliminate spaces\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string):\n # Use the replace method to remove all whitespace characters\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string):\n # Use str.replace() method to remove all whitespace characters\n result = input_string.replace(\" \", \"\")\n return result", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(s):\n # Use the replace method to remove all spaces from the string\n return s.replace(' ', '')", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(s):\n # Use the replace method to eliminate all whitespace characters from the string\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string):\n # Use the replace method to remove all spaces from the input string\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string):\n # Use the replace method to remove all whitespaces from the input string\n no_whitespaces = input_string.replace(\" \", \"\")\n return no_whitespaces", "matching_cluster_idx": 4}]}, "Mbpp/456": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def reverse_string_list(items):\n # Use a list comprehension to reverse each string in the list\n return [item[::-1] for item in items]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(lst):\n \"\"\"\n Reverses each string in a given list of strings.\n \n Parameters:\n lst (list): A list of strings to be reversed.\n \n Returns:\n list: A list of reversed strings.\n \"\"\"\n return [s[::-1] for s in lst]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(items):\n # Use list comprehension to reverse each string in the list\n return [item[::-1] for item in items]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(lst):\n # Reverse each string in the list using a list comprehension\n return [s[::-1] for s in lst]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(lst):\n \"\"\"\n Reverses each string in the given list of string values.\n \n Parameters:\n lst (list): A list of strings.\n \n Returns:\n list: A list containing each string from the input list reversed.\n \"\"\"\n # Use list comprehension to reverse each string in the list\n return [s[::-1] for s in lst]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(lst):\n \"\"\"\n Reverses each string in a given list of string values.\n \n Parameters:\n lst (list): A list of string values.\n \n Returns:\n list: A list where each string is reversed.\n \"\"\"\n return [s[::-1] for s in lst]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n \"\"\"\n Reverse each string in the given list of string values.\n \n Parameters:\n string_list (list): A list of string values.\n \n Returns:\n list: A new list containing the reversed strings.\n \"\"\"\n # Use list comprehension to reverse each string in the list\n return [s[::-1] for s in string_list]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(lst):\n # Use list comprehension to reverse each string in the input list\n return [s[::-1] for s in lst]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(lst):\n \"\"\"\n Reverses each string in a given list of string values.\n \n Parameters:\n lst (list): A list of string values.\n \n Returns:\n list: A list with each string from the input list reversed.\n \"\"\"\n # Reverse each string in the list using list comprehension\n reversed_list = [s[::-1] for s in lst]\n return reversed_list", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(lst):\n \"\"\"\n Reverses each string in a given list of string values.\n \n Parameters:\n lst (list): A list of strings to be reversed.\n \n Returns:\n list: A list containing the reversed strings.\n \"\"\"\n return [s[::-1] for s in lst]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(lst):\n \"\"\"\n Reverses each string in the given list of string values.\n \n Parameters:\n lst (list): A list of strings to be reversed.\n \n Returns:\n list: A list of reversed strings.\n \"\"\"\n # Reverse each string in the list using list comprehension\n reversed_list = [s[::-1] for s in lst]\n return reversed_list", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(items):\n # Use list comprehension to reverse each string in the list\n reversed_items = [item[::-1] for item in items]\n return reversed_items", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(lst):\n \"\"\"\n Reverses each string in the given list of string values.\n \n Parameters:\n lst (list): A list of string values.\n \n Returns:\n list: A list of reversed strings.\n \"\"\"\n return [s[::-1] for s in lst]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(lst):\n # Use list comprehension to reverse each string in the input list\n return [s[::-1] for s in lst]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(items):\n # Use list comprehension to reverse each string in the list\n return [item[::-1] for item in items]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n \"\"\"\n Reverse each string in a given list of string values.\n \n Parameters:\n string_list (list): A list of strings to be reversed.\n \n Returns:\n list: A new list with each string reversed.\n \"\"\"\n # Use list comprehension to reverse each string in the list\n return [s[::-1] for s in string_list]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n # Use list comprehension to reverse each string in the list\n reversed_list = [s[::-1] for s in string_list]\n return reversed_list", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(lst):\n # Use list comprehension to reverse each string in the list\n return [s[::-1] for s in lst]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(input_list):\n \"\"\"\n Reverses each string in a given list of string values\n \n Parameters:\n input_list (list): A list of string values\n \n Returns:\n list: A list containing each string from input_list reversed\n \"\"\"\n # Reverse each string in the list using list comprehension\n reversed_list = [s[::-1] for s in input_list]\n return reversed_list", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(str_list):\n \"\"\"\n Reverses each string in a given list of string values.\n \n Parameters:\n str_list (list): A list of strings to be reversed.\n \n Returns:\n list: A list containing the reversed strings.\n \"\"\"\n # Use list comprehension to reverse each string in the list\n reversed_list = [s[::-1] for s in str_list]\n return reversed_list", "matching_cluster_idx": 4}]}, "Mbpp/460": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def Extract(list_of_lists):\n # Use list comprehension to extract the first element of each sublist\n return [sublist[0] for sublist in list_of_lists]", "matching_cluster_idx": 4}, {"solution": "def Extract(lst):\n # Use list comprehension to get the first element of each sublist\n return [sub[0] for sub in lst]", "matching_cluster_idx": 4}, {"solution": "def Extract(lst):\n # Use list comprehension to get the first element of each sublist\n return [sublist[0] for sublist in lst]", "matching_cluster_idx": 4}, {"solution": "def Extract(lst):\n # Use list comprehension to extract the first element of each sublist\n return [sub[0] for sub in lst]", "matching_cluster_idx": 4}, {"solution": "def Extract(lst_of_lsts):\n # Use list comprehension to extract the first element from each sublist\n return [sublist[0] for sublist in lst_of_lsts]", "matching_cluster_idx": 4}, {"solution": "def Extract(lst):\n # Use list comprehension to get the first element of each sublist\n return [x[0] for x in lst]", "matching_cluster_idx": 4}, {"solution": "def Extract(lst):\n # Use list comprehension to extract the first element of each sublist\n return [sub[0] for sub in lst]", "matching_cluster_idx": 4}, {"solution": "def Extract(lst_of_lsts):\n # Use list comprehension to extract the first element of each sublist\n return [sublist[0] for sublist in lst_of_lsts]", "matching_cluster_idx": 4}, {"solution": "def Extract(lst):\n # Use list comprehension to extract the first element of each sublist\n return [sublist[0] for sublist in lst]", "matching_cluster_idx": 4}, {"solution": "def Extract(lst):\n # Extract the first element of each sublist\n result = [x[0] for x in lst]\n return result", "matching_cluster_idx": 4}, {"solution": "def Extract(lst):\n # Use list comprehension to get the first element of each sublist\n return [x[0] for x in lst]", "matching_cluster_idx": 4}, {"solution": "def Extract(lst):\n # Use list comprehension to extract the first element of each sublist\n return [x[0] for x in lst]", "matching_cluster_idx": 4}, {"solution": "def Extract(lst):\n # Use list comprehension to extract the first element of each sublist\n return [sublst[0] for sublst in lst]", "matching_cluster_idx": 4}, {"solution": "def Extract(list_of_lists):\n # Use list comprehension to extract the first element of each sublist\n return [sublist[0] for sublist in list_of_lists]", "matching_cluster_idx": 4}, {"solution": "def Extract(lst):\n # Use list comprehension to extract the first element of each sublist\n return [sub[0] for sub in lst]", "matching_cluster_idx": 4}, {"solution": "def Extract(lst):\n # Use list comprehension to get the first element of each sublist\n return [sub_lst[0] for sub_lst in lst]", "matching_cluster_idx": 4}, {"solution": "def Extract(lst_of_lsts):\n # Use list comprehension to iterate through each sublist and extract the first element\n return [sublist[0] for sublist in lst_of_lsts]", "matching_cluster_idx": 4}, {"solution": "def Extract(lst):\n # Use list comprehension to get the first element from each sublist\n return [x[0] for x in lst]", "matching_cluster_idx": 4}, {"solution": "def Extract(lst):\n # Use list comprehension to extract the first element from each sublist\n return [sub[0] for sub in lst]", "matching_cluster_idx": 4}, {"solution": "def Extract(list_of_lists):\n # Use list comprehension to extract the first element of each sublist\n return [sublist[0] for sublist in list_of_lists]", "matching_cluster_idx": 4}]}, "Mbpp/474": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def replace_char(input_str, old_char, new_char):\n # Replace all occurrences of old_char with new_char in the input string\n result = input_str.replace(old_char, new_char)\n return result", "matching_cluster_idx": 6}, {"solution": "def replace_char(string, old_char, new_char):\n # Replace all occurrences of old_char with new_char in the string\n result = string.replace(old_char, new_char)\n return result", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, old_char, new_char):\n # Replace all occurrences of old_char with new_char in the string s\n return s.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(input_str, old_char, new_char):\n # Replace all occurrences of old_char with new_char in the input string\n modified_str = input_str.replace(old_char, new_char)\n return modified_str", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, old_char, new_char):\n # Replace occurrences of old_char with new_char in the string s\n return s.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, old_char, new_char):\n \"\"\"\n Replaces all occurrences of old_char with new_char in the given string s.\n \n Parameters:\n s (str): The input string.\n old_char (str): The character in the string to be replaced.\n new_char (str): The character to replace all occurrences of old_char.\n \n Returns:\n str: The modified string after replacements.\n \"\"\"\n return s.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(input_string, target_char, replacement_char):\n # Replace all occurrences of target_char with replacement_char\n modified_string = input_string.replace(target_char, replacement_char)\n return modified_string", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, old_char, new_char):\n \"\"\"\n Replace all occurrences of old_char with new_char in the given string s.\n \n Parameters:\n s (str): The input string.\n old_char (str): The character to be replaced.\n new_char (str): The character to replace with.\n \n Returns:\n str: A new string with characters replaced.\n \"\"\"\n # Replace occurrences of old_char with new_char\n return s.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(string, old_char, new_char):\n # Replace occurrences of old_char with new_char in the string\n return string.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, old_char, new_char):\n # Replace occurrences of old_char with new_char in the string s\n return s.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(string, old_char, new_char):\n \"\"\"\n Replace occurrences of a specified character in a string with another character.\n \n Parameters:\n string (str): The original string.\n old_char (str): The character to be replaced.\n new_char (str): The character to replace with.\n \n Returns:\n str: A new string with the specified characters replaced.\n \"\"\"\n # Using the str.replace() method to replace the occurrences of old_char with new_char\n return string.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, old_char, new_char):\n # Replace occurrences of old_char with new_char in the string s\n return s.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, old_char, new_char):\n \"\"\"\n Replaces all occurrences of 'old_char' in the string 's' with 'new_char'.\n \n Parameters:\n s (str): The original string.\n old_char (str): The character to be replaced.\n new_char (str): The new character to replace with.\n \n Returns:\n str: The modified string after replacement.\n \"\"\"\n # Replace all occurrences of old_char with new_char in the string\n modified_str = s.replace(old_char, new_char)\n return modified_str", "matching_cluster_idx": 6}, {"solution": "def replace_char(string, old_char, new_char):\n # Replace all occurrences of old_char with new_char in the string\n return string.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(string, old_char, new_char):\n # Replace occurrences of old_char with new_char in the given string\n replaced_string = string.replace(old_char, new_char)\n return replaced_string", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, old_char, new_char):\n \"\"\"\n Replaces occurrences of old_char with new_char in the string s.\n \n Parameters:\n s (str): The input string.\n old_char (str): The character in the string to be replaced.\n new_char (str): The character to replace old_char with.\n \n Returns:\n str: The modified string with old_char replaced by new_char.\n \"\"\"\n return s.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, old_char, new_char):\n # Replace occurrences of old_char with new_char in the string\n return s.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, old_char, new_char):\n \"\"\"\n Replace occurrences of a specified character in a string with another character.\n\n :param s: The original string.\n :param old_char: The character to be replaced.\n :param new_char: The new character to replace the old character.\n :return: A new string with the specified character replaced.\n \"\"\"\n return s.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, old_char, new_char):\n \"\"\"\n Replace occurrences of old_char in the string s with new_char.\n \n Parameters:\n s (str): The original string.\n old_char (str): The character in the string to be replaced.\n new_char (str): The character to replace old_char with.\n \n Returns:\n str: The modified string with old_char replaced by new_char.\n \"\"\"\n # Replace occurrences of old_char with new_char\n replaced_string = s.replace(old_char, new_char)\n return replaced_string", "matching_cluster_idx": 6}, {"solution": "def replace_char(string, old_char, new_char):\n # Replace all occurrences of old_char with new_char in the string\n modified_string = string.replace(old_char, new_char)\n return modified_string", "matching_cluster_idx": 6}]}, "Mbpp/476": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def big_sum(nums):\n # Find the maximum and minimum values in the list and return their sum\n return max(nums) + min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n # Find the maximum and minimum values in the array\n max_value = max(arr)\n min_value = min(arr)\n \n # Calculate the sum of the maximum and minimum values\n return max_value + min_value", "matching_cluster_idx": 5}, {"solution": "def big_sum(nums):\n # Find the maximum and minimum values in the array\n max_val = max(nums)\n min_val = min(nums)\n \n # Return the sum of the maximum and minimum values\n return max_val + min_val", "matching_cluster_idx": 5}, {"solution": "def big_sum(nums):\n \"\"\"\n Find the sum of the largest and smallest values in a given array.\n \n Parameters:\n nums (list): A list of integers.\n \n Returns:\n int: The sum of the largest and smallest values in the array.\n \"\"\"\n # Find the maximum and minimum values in the list\n max_value = max(nums)\n min_value = min(nums)\n \n # Return the sum of the maximum and minimum values\n return max_value + min_value", "matching_cluster_idx": 5}, {"solution": "def big_sum(nums):\n # Find the minimum and maximum values in the list\n min_val = min(nums)\n max_val = max(nums)\n \n # Return the sum of the minimum and maximum values\n return min_val + max_val", "matching_cluster_idx": 5}, {"solution": "def big_sum(nums):\n \"\"\"\n Calculate the sum of the largest and smallest values in a given array.\n \n Parameters:\n nums (list): A list of integers.\n \n Returns:\n int: The sum of the largest and smallest values in the list.\n \"\"\"\n # Using min() and max() to find the smallest and largest values in the array\n smallest = min(nums)\n largest = max(nums)\n \n # Return the sum of the smallest and largest value\n return smallest + largest", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n \"\"\"\n Finds the sum of the largest and smallest value in a given array.\n \n Parameters:\n arr (list): A list of integers.\n \n Returns:\n int: The sum of the largest and smallest integers in the list.\n \"\"\"\n # Find the maximum and minimum elements in the array\n max_val = max(arr)\n min_val = min(arr)\n \n # Return the sum of the maximum and minimum values\n return max_val + min_val", "matching_cluster_idx": 5}, {"solution": "def big_sum(nums):\n # Calculate and return the sum of the maximum and minimum values in the list\n return max(nums) + min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_sum(nums):\n # Calculate the sum of the maximum and minimum values in the list\n return max(nums) + min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n \"\"\"\n Finds the sum of the largest and smallest value in a given array.\n \n Parameters:\n arr (list): A list of integers.\n \n Returns:\n int: The sum of the largest and smallest value in the array.\n \"\"\"\n # Calculate and return the sum of the max and min values in the array\n return max(arr) + min(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n \"\"\"\n Finds the sum of the largest and smallest value in a given array.\n \n Parameters:\n arr (list): A list of integers.\n \n Returns:\n int: The sum of the largest and smallest value in the array.\n \"\"\"\n # Finding the minimum and maximum elements in the array\n min_val = min(arr)\n max_val = max(arr)\n \n # Returning the sum of the minimum and maximum values\n return min_val + max_val", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n \"\"\"\n Finds the sum of the largest and smallest value in a given array.\n \n Parameters:\n arr (list): A list of integers.\n \n Returns:\n int: Sum of the largest and smallest value in the given list.\n \"\"\"\n # Find the smallest and largest values in the array\n smallest_value = min(arr)\n largest_value = max(arr)\n \n # Calculate the sum of the smallest and largest values\n result = smallest_value + largest_value\n \n return result", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n # Calculate the sum of the maximum and minimum values in the array\n return max(arr) + min(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(nums):\n # Find the maximum and minimum values in the list and return their sum\n return max(nums) + min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n # Find the minimum and maximum elements in the array\n min_element = min(arr)\n max_element = max(arr)\n \n # Return the sum of the minimum and maximum elements\n return min_element + max_element", "matching_cluster_idx": 5}, {"solution": "def big_sum(nums):\n # Find the maximum and minimum values in the list\n max_val = max(nums)\n min_val = min(nums)\n \n # Return the sum of the maximum and minimum values\n return max_val + min_val", "matching_cluster_idx": 5}, {"solution": "def big_sum(nums):\n \"\"\"\n Calculates the sum of the largest and smallest value in a given array.\n \n Parameters:\n nums (list): A list of integers.\n \n Returns:\n int: The sum of the largest and smallest integers in the list.\n \"\"\"\n # Calculate the sum of the maximum and minimum values in the list\n total = max(nums) + min(nums)\n return total", "matching_cluster_idx": 5}, {"solution": "def big_sum(nums):\n # Find the maximum and minimum values in the array\n max_val = max(nums)\n min_val = min(nums)\n \n # Return the sum of the maximum and minimum values\n return max_val + min_val", "matching_cluster_idx": 5}, {"solution": "def big_sum(nums):\n \"\"\"\n Finds the sum of the largest and smallest value in a given array.\n \n Parameters:\n nums (list): A list of integers.\n \n Returns:\n int: The sum of the largest and smallest values in the list.\n \"\"\"\n # Finding the largest and smallest value in the list\n largest = max(nums)\n smallest = min(nums)\n \n # Returning the sum of the largest and smallest value\n return largest + smallest", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n # Find the minimum and maximum elements in the array\n min_element = min(arr)\n max_element = max(arr)\n \n # Calculate the sum of the minimum and maximum elements\n result = min_element + max_element\n \n return result", "matching_cluster_idx": 5}]}, "Mbpp/477": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def is_lower(s):\n # Use the built-in lower() method to convert string to lower case\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n # Convert the string to lower case\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n # Convert the given string to lower case\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n # Convert the input string to lower case\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n # Convert the given string to lower case\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n # Use the built-in lower() method to convert the string to lower case\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n # Use the lower() method to convert the string to lower case\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(input_str):\n \"\"\"\n Converts the given string to lower case.\n \n Parameters:\n input_str (str): The string to convert to lower case.\n \n Returns:\n str: The lower case string.\n \"\"\"\n return input_str.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n # Use the lower() method to convert the string to lower case\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n # Convert the given string to lower case\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n # Use the lower() method to convert the string to lower case\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n # Convert the given string to lower case\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n # Convert the string to lower case\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(input_string):\n # Convert the given string to lower case\n result = input_string.lower()\n return result", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n # Convert the given string to lower case using the lower() method\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(input_string):\n # Convert the input string to lower case\n result = input_string.lower()\n return result", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n # Convert the string to lower case\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n # Convert the string to lower case\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n # Use the lower() method to convert the string to lower case\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n # Convert the given string to lower case\n return s.lower()", "matching_cluster_idx": 4}]}, "Mbpp/563": {"dps": 85.24590163934427, "dps_norm": 81.81818181818181, "pass@1": 100.0, "profiled": [{"solution": "import re\ndef extract_values(s):\n # Use regular expression to find all substrings that are enclosed in quotation marks\n values = re.findall(r'\"(.*?)\"', s)\n return values", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(input_string):\n # Use regular expression to find all occurrences of text within double quotes\n return re.findall(r'\"(.*?)\"', input_string)", "matching_cluster_idx": 8}, {"solution": "import re\nfrom typing import List\ndef extract_values(s: str) -> List[str]:\n # Use regular expression to find all substrings enclosed in double quotes\n return re.findall(r'\"(.*?)\"', s)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(input_string):\n # Use regex to find all substrings between double quotes\n return re.findall(r'\"(.*?)\"', input_string)", "matching_cluster_idx": 8}, {"solution": "import re\nfrom typing import List\ndef extract_values(s: str) -> List[str]:\n # Use regular expression to find all substrings enclosed in double quotes\n return re.findall(r'\"(.*?)\"', s)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(s):\n # Use regular expression to find all substrings enclosed in double quotes\n return re.findall(r'\"(.*?)\"', s)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(input_string):\n # Using regular expression to find all occurrences of text within double quotes\n return re.findall(r'\"(.*?)\"', input_string)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(input_string):\n # Use regular expression to find all substrings enclosed in double quotes\n return re.findall(r'\"(.*?)\"', input_string)", "matching_cluster_idx": 8}, {"solution": "import re\nfrom typing import List\ndef extract_values(input_str: str) -> List[str]:\n \"\"\"\n Extracts substrings enclosed in double quotes from the input string.\n \n Args:\n input_str (str): The string from which substrings enclosed in double quotes are to be extracted.\n \n Returns:\n List[str]: A list containing the substrings enclosed in double quotes.\n \"\"\"\n # Use regular expression to find all substrings enclosed in double quotes\n return re.findall(r'\"(.*?)\"', input_str)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(s):\n # Use regex to find all substrings enclosed in double quotes\n return re.findall(r'\"(.*?)\"', s)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(input_string):\n # Using regular expression to find all substrings enclosed in double quotes\n return re.findall(r'\"(.*?)\"', input_string)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(input_string):\n # Use regular expression to find all substrings between double quotes\n return re.findall(r'\"(.*?)\"', input_string)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(input_string):\n # Using regular expression to find all occurrences of text within double quotes\n return re.findall(r'\"(.*?)\"', input_string)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(input_string):\n # Use regex to find all occurrences of text within double quotes\n return re.findall(r'\"(.*?)\"', input_string)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(s):\n # Use regular expression to find all occurrences of text within double quotes\n return re.findall(r'\"(.*?)\"', s)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(input_string):\n # Use regular expression to find all substrings enclosed in double quotes\n return re.findall(r'\"(.*?)\"', input_string)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(input_string):\n # Use regular expression to find all substrings between quotation marks\n return re.findall(r'\\\"(.*?)\\\"', input_string)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(s):\n # Use regular expression to find all substrings between double quotes\n return re.findall(r'\"(.*?)\"', s)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(input_string):\n # Use regular expression to find all substrings enclosed in double quotes\n return re.findall(r'\"(.*?)\"', input_string)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(input_string):\n # Using regular expression to find all substrings enclosed in double quotes\n matches = re.findall(r'\"(.*?)\"', input_string)\n return matches", "matching_cluster_idx": 8}]}, "Mbpp/572": {"dps": 94.07407407407408, "dps_norm": 90.0, "pass@1": 65.0, "profiled": [{"solution": "def two_unique_nums(nums):\n from collections import Counter\n \n # Count the occurrences of each number\n num_counts = Counter(nums)\n \n # Filter out numbers that occur more than once\n result = [num for num in nums if num_counts[num] == 1]\n \n return result", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(nums):\n from collections import Counter\n \n # Count the frequency of each number\n num_count = Counter(nums)\n \n # Filter numbers that appear only once\n unique_nums = [num for num in num_count if num_count[num] == 1]\n \n return unique_nums", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(nums):\n from collections import Counter\n \n # Count occurrences of each number\n num_counts = Counter(nums)\n \n # Filter numbers that appear exactly once\n unique_nums = [num for num in nums if num_counts[num] == 1]\n \n return unique_nums", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(numbers):\n from collections import Counter\n \n # Count the occurrences of each number\n num_counts = Counter(numbers)\n \n # Filter out numbers that appear more than once\n unique_nums = [num for num, count in num_counts.items() if count == 1]\n \n return unique_nums", "matching_cluster_idx": 6}, {"solution": "def two_unique_nums(nums):\n from collections import Counter\n \n # Count the occurrences of each number\n num_counts = Counter(nums)\n \n # Filter out numbers that appear more than once\n unique_nums = [num for num, count in num_counts.items() if count == 1]\n \n return unique_nums", "matching_cluster_idx": 6}, {"solution": "def two_unique_nums(nums):\n from collections import Counter\n \n # Count occurrences of each number\n num_count = Counter(nums)\n \n # Filter out numbers that appear more than once\n result = [num for num in nums if num_count[num] == 1]\n \n return result", "matching_cluster_idx": 5}, {"solution": "def remove_duplicates(lst):\n # Use a set to track unique numbers and a list to track numbers to be removed\n seen = set()\n to_remove = []\n \n # Iterate through the list and identify duplicates\n for num in lst:\n if num in seen:\n to_remove.append(num)\n else:\n seen.add(num)\n \n # Create a new list without duplicates\n result = [num for num in lst if num not in to_remove]\n return result\ndef two_unique_nums(lst):\n # Call the remove_duplicates function to solve the problem\n return remove_duplicates(lst)", "matching_cluster_idx": 3}, {"solution": "def two_unique_nums(nums):\n from collections import Counter\n \n # Count the occurrences of each number\n num_counts = Counter(nums)\n \n # Filter out numbers that appear more than once\n unique_nums = [num for num, count in num_counts.items() if count == 1]\n \n return unique_nums", "matching_cluster_idx": 6}, {"solution": "def two_unique_nums(nums):\n from collections import Counter\n \n # Count the occurrences of each number\n num_counts = Counter(nums)\n \n # Filter out numbers that appear more than once\n unique_nums = [num for num, count in num_counts.items() if count == 1]\n \n return unique_nums", "matching_cluster_idx": 6}, {"solution": "def two_unique_nums(nums):\n \"\"\"\n Removes duplicate numbers from a given list of integers and returns a list of numbers that appear only once.\n \n :param nums: List of integers which may contain duplicates\n :return: A list of unique integers from the input list\n \"\"\"\n # Using a dictionary to count occurrences of each number\n num_count = {}\n for num in nums:\n if num in num_count:\n num_count[num] += 1\n else:\n num_count[num] = 1\n \n # Extracting numbers that appear only once\n result = [num for num, count in num_count.items() if count == 1]\n \n return result", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(nums):\n from collections import Counter\n \n # Count the frequency of each number in the list\n num_counts = Counter(nums)\n \n # Filter out numbers that appear more than once\n result = [num for num in nums if num_counts[num] == 1]\n \n return result", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(nums):\n from collections import Counter\n \n # Count the occurrences of each number\n num_counts = Counter(nums)\n \n # Filter numbers that appear exactly once\n unique_nums = [num for num in nums if num_counts[num] == 1]\n \n return unique_nums", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(nums):\n from collections import Counter\n \n # Count the frequency of each number in the list\n num_counts = Counter(nums)\n \n # Filter numbers that appear only once and return them as a list\n unique_nums = [num for num, count in num_counts.items() if count == 1]\n \n return unique_nums", "matching_cluster_idx": 6}, {"solution": "def two_unique_nums(nums):\n from collections import Counter\n \n # Count the occurrences of each number\n num_counts = Counter(nums)\n \n # Filter out numbers that appear more than once\n result = [num for num in nums if num_counts[num] == 1]\n \n return result", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(nums):\n from collections import Counter\n \n # Count the occurrences of each number\n num_counts = Counter(nums)\n \n # Filter out numbers that appear more than once\n unique_nums = [num for num, count in num_counts.items() if count == 1]\n \n return unique_nums", "matching_cluster_idx": 6}, {"solution": "def two_unique_nums(nums):\n from collections import Counter\n \n # Count the occurrences of each number\n num_count = Counter(nums)\n \n # Filter out numbers that occur more than once\n unique_nums = [num for num in nums if num_count[num] == 1]\n \n return unique_nums", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(nums):\n from collections import Counter\n \n # Count the occurrences of each number\n num_counts = Counter(nums)\n \n # Filter numbers that appear exactly once\n unique_nums = [num for num, count in num_counts.items() if count == 1]\n \n return unique_nums", "matching_cluster_idx": 6}, {"solution": "def two_unique_nums(nums):\n from collections import Counter\n \n # Count the occurrences of each number in the list\n num_count = Counter(nums)\n \n # Filter and return the numbers that appear exactly once\n return [num for num in nums if num_count[num] == 1]", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(nums):\n from collections import Counter\n \n # Count the frequency of each number in the list\n num_counts = Counter(nums)\n \n # Filter out numbers that appear more than once\n unique_nums = [num for num, count in num_counts.items() if count == 1]\n \n return unique_nums", "matching_cluster_idx": 6}, {"solution": "def two_unique_nums(nums):\n from collections import Counter\n \n # Count the frequency of each number in the list\n num_counts = Counter(nums)\n \n # Filter out numbers that appear more than once and return the rest\n return [num for num in nums if num_counts[num] == 1]", "matching_cluster_idx": 5}]}, "Mbpp/578": {"dps": 64.17460317460318, "dps_norm": 65.0, "pass@1": 99.0, "profiled": [{"solution": "def interleave_lists(list1, list2, list3):\n # Initialize an empty list to store the interleaved elements\n interleaved_list = []\n # Iterate through the indices of the lists\n for i in range(len(list1)):\n # Append the elements from each list at the current index\n interleaved_list.append(list1[i])\n interleaved_list.append(list2[i])\n interleaved_list.append(list3[i])\n # Return the resulting interleaved list\n return interleaved_list", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"\n Interleave three lists of the same length into a single flat list.\n \n Args:\n list1: A list of elements.\n list2: A list of elements.\n list3: A list of elements.\n \n Returns:\n A single flat list where elements from the three lists are interleaved.\n \"\"\"\n # Check if the lists are of the same length\n if not (len(list1) == len(list2) == len(list3)):\n raise ValueError(\"All input lists must be of the same length\")\n \n result = []\n for i in range(len(list1)):\n result.append(list1[i])\n result.append(list2[i])\n result.append(list3[i])\n return result", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"\n Interleave three lists of the same length into a single flat list.\n \n Args:\n list1, list2, list3: Lists of the same length to be interleaved.\n \n Returns:\n A single flat list with elements interleaved from the three input lists.\n \"\"\"\n # Use zip to pair elements from all three lists and then flatten the result\n interleaved = [item for sublist in zip(list1, list2, list3) for item in sublist]\n return interleaved", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(list1, list2, list3):\n result = []\n for i in range(len(list1)):\n result.append(list1[i])\n result.append(list2[i])\n result.append(list3[i])\n return result", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"\n Interleave three lists of the same length into a single flat list.\n \n Args:\n list1, list2, list3: Three lists of equal length containing numeric values.\n \n Returns:\n A single flat list with elements interleaved from the three input lists.\n \"\"\"\n # Using zip to pair elements from all three lists and then flattening it\n interleaved_list = [item for sublist in zip(list1, list2, list3) for item in sublist]\n return interleaved_list", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"\n Interleave three lists of the same length into a single flat list.\n \n Args:\n list1, list2, list3: Three lists of integers of the same length.\n \n Returns:\n A single flat list containing elements from all three lists interleaved.\n \"\"\"\n interleaved_list = []\n for i in range(len(list1)):\n interleaved_list.append(list1[i])\n interleaved_list.append(list2[i])\n interleaved_list.append(list3[i])\n return interleaved_list", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n result = []\n for i in range(len(list1)):\n result.append(list1[i])\n result.append(list2[i])\n result.append(list3[i])\n return result", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"\n Interleave three lists of the same length into a single flat list.\n \n Args:\n list1 : List of elements.\n list2 : List of elements.\n list3 : List of elements.\n \n Returns:\n list: A single flat list with elements interleaved from list1, list2, and list3.\n \"\"\"\n result = []\n for i in range(len(list1)):\n result.extend([list1[i], list2[i], list3[i]])\n return result", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(lst1, lst2, lst3):\n \"\"\"\n Interleaves three lists of the same length into a single flat list.\n \"\"\"\n result = []\n for i in range(len(lst1)):\n result.append(lst1[i])\n result.append(lst2[i])\n result.append(lst3[i])\n return result", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n # Initialize an empty list to store the interleaved results\n interleaved = []\n \n # Ensure all lists have the same length\n assert len(list1) == len(list2) == len(list3), \"All input lists must have the same length\"\n \n # Iterate through the indices of the input lists\n for i in range(len(list1)):\n # Interleave elements from all three lists\n interleaved.append(list1[i])\n interleaved.append(list2[i])\n interleaved.append(list3[i])\n \n return interleaved", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(lst1, lst2, lst3):\n \"\"\"\n Interleave three lists of the same length into a single flat list.\n \"\"\"\n interleaved_list = []\n for i in range(len(lst1)):\n interleaved_list.append(lst1[i])\n interleaved_list.append(lst2[i])\n interleaved_list.append(lst3[i])\n return interleaved_list", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n result = []\n for i in range(len(list1)):\n result.extend([list1[i], list2[i], list3[i]])\n return result", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"\n Interleave three lists of the same length into a single flat list.\n \n Args:\n list1 : List of elements.\n list2 : List of elements.\n list3 : List of elements.\n \n Returns:\n list : A single flat list interleaving elements from the three input lists.\n \"\"\"\n # Ensure the lists are of the same length\n assert len(list1) == len(list2) == len(list3), \"All lists must be of the same length\"\n \n # Use a list comprehension to interleave the lists\n interleaved_list = [element for triplet in zip(list1, list2, list3) for element in triplet]\n \n return interleaved_list", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(lst1, lst2, lst3):\n result = []\n for i in range(len(lst1)):\n result.append(lst1[i])\n result.append(lst2[i])\n result.append(lst3[i])\n return result", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"\n Interleave 3 lists of the same length into a single flat list.\n \n Args:\n list1 : List of elements.\n list2 : List of elements.\n list3 : List of elements.\n \n Returns:\n A single flat list with elements interleaved from list1, list2, and list3.\n \"\"\"\n result = []\n for i in range(len(list1)):\n result.extend([list1[i], list2[i], list3[i]])\n return result", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n interleaved_list = []\n for i in range(len(list1)):\n interleaved_list.append(list1[i])\n interleaved_list.append(list2[i])\n interleaved_list.append(list3[i])\n return interleaved_list", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(lst1, lst2, lst3):\n \"\"\"\n Interleave three lists of equal length into a single flat list.\n \n :param lst1: First list of elements\n :param lst2: Second list of elements\n :param lst3: Third list of elements\n :return: A single flat list with elements interleaved from the three lists\n \"\"\"\n result = []\n for i in range(len(lst1)):\n result.append(lst1[i])\n result.append(lst2[i])\n result.append(lst3[i])\n return result", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"\n Interleave three lists of the same length into a single flat list.\n \n Parameters:\n list1 (list): The first list to interleave.\n list2 (list): The second list to interleave.\n list3 (list): The third list to interleave.\n \n Returns:\n list: A single flat list interleaved from the input lists.\n \"\"\"\n result = []\n for i in range(len(list1)):\n result.append(list1[i])\n result.append(list2[i])\n result.append(list3[i])\n return result", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"\n Interleave three lists of the same length into a single flat list.\n \n Args:\n list1: First list of elements.\n list2: Second list of elements.\n list3: Third list of elements.\n \n Returns:\n A single flat list with elements interleaved from the three input lists.\n \"\"\"\n interleaved_list = []\n for i in range(len(list1)):\n interleaved_list.append(list1[i])\n interleaved_list.append(list2[i])\n interleaved_list.append(list3[i])\n return interleaved_list", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"\n Interleave three lists of the same length into a single flat list.\n \n Args:\n list1 : list\n The first input list.\n list2 : list\n The second input list.\n list3 : list\n The third input list.\n \n Returns:\n list\n The interleaved flat list.\n \"\"\"\n interleaved_list = []\n for i in range(len(list1)):\n interleaved_list.append(list1[i])\n interleaved_list.append(list2[i])\n interleaved_list.append(list3[i])\n return interleaved_list", "matching_cluster_idx": 6}]}, "Mbpp/586": {"dps": 98.83040935672514, "dps_norm": 87.5, "pass@1": 69.0, "profiled": [{"solution": "def split_Arr(lst, n):\n \"\"\"\n Splits the list at the nth element and adds the first part to the end.\n \n Parameters:\n lst (list): The list to be manipulated.\n n (int): The index at which to split the list.\n \n Returns:\n list: The manipulated list with the first part added to the end.\n \"\"\"\n if n <= 0 or n > len(lst):\n return lst # Return the original list if n is invalid\n \n # Split the list and rearrange\n first_part = lst[:n]\n second_part = lst[n:]\n return second_part + first_part", "matching_cluster_idx": 6}, {"solution": "def split_Arr(lst, n):\n \"\"\"\n Splits a list at the nth element and adds the first part to the end.\n \n Parameters:\n lst (list): The input list to be split and rearranged.\n n (int): The position at which to split the list.\n \n Returns:\n list: The rearranged list with the first part appended to the end.\n \"\"\"\n # Ensure the split index is valid\n if n <= 0 or n > len(lst):\n return lst\n \n # Split the list into two parts at the nth element\n first_part = lst[:n]\n second_part = lst[n:]\n \n # Concatenate the second part with the first part\n result = second_part + first_part\n \n return result", "matching_cluster_idx": 6}, {"solution": "def split_Arr(lst, n):\n \"\"\"\n Split a list at the nth element and add the first part to the end.\n \n Parameters:\n lst (list): The input list to be manipulated.\n n (int): The position at which to split the list.\n \n Returns:\n list: The manipulated list with the first part appended to the end.\n \"\"\"\n if n > 0 and n <= len(lst): # Ensure n is valid\n # Split the list and concatenate it accordingly\n return lst[n:] + lst[:n]\n else:\n # If n is not valid, return the original list\n return lst", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"\n Split a list at the nth element and add the first part to the end.\n \n Parameters:\n arr (list): The list to be modified.\n n (int): The index at which the list will be split.\n \n Returns:\n list: The modified list with the first part moved to the end.\n \"\"\"\n # Ensure n is within the bounds of the list\n if n < 0 or n >= len(arr):\n return arr\n \n # Split and rearrange the list\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"\n Splits a list at the nth element and moves the first part to the end of the list.\n \n Parameters:\n arr (list): The input list to be modified.\n n (int): The position at which the list should be split.\n \n Returns:\n list: The modified list with the first part moved to the end.\n \"\"\"\n if n < 1 or n > len(arr):\n return arr\n \n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"\n Splits a list at the nth element and moves the first part of the list to the end of the list.\n \n Parameters:\n arr (list): The input list of elements.\n n (int): The position at which to split the list.\n \n Returns:\n list: The modified list with the first part moved to the end.\n \"\"\"\n # Ensure n is a positive integer and within the bounds of the list\n n = n % len(arr) if arr else 0\n \n # Split the array and concatenate the parts in the new order\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(lst, n):\n \"\"\"\n Splits the list at the nth element and adds the first part to the end.\n\n Parameters:\n lst (list): The input list to be modified.\n n (int): The index at which to split the list.\n\n Returns:\n list: The modified list with the first part added to the end.\n \"\"\"\n if n >= len(lst) or n < 0:\n return lst # Return the original list if n is invalid\n \n # Split the list into two parts and concatenate them in the required order\n return lst[n:] + lst[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"\n Splits a list at the nth element and appends the first part to the end of the list.\n \n Parameters:\n arr (list): The list to be split and rearranged.\n n (int): The index at which to split the list.\n \n Returns:\n list: The rearranged list with the first part appended to the end.\n \"\"\"\n # Ensure n is within bounds\n if n < 0 or n >= len(arr):\n return arr\n \n # Split the array\n front = arr[:n]\n back = arr[n:]\n \n # Concatenate back with front\n result = back + front\n \n return result", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"\n Splits a list at the nth element and adds the first part to the end.\n \n Parameters:\n arr (list): The list to be manipulated.\n n (int): The index at which to split the list.\n \n Returns:\n list: The manipulated list with the first part added to the end.\n \"\"\"\n # Ensure n is within the bounds of the list\n n = n % len(arr) if arr else 0\n \n # Split the array into two parts and concatenate with the second part first\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(lst, n):\n \"\"\"\n Split the list at the nth element and move the first part to the end.\n \n Parameters:\n lst (list): The input list to be rearranged.\n n (int): The index at which to split the list.\n \n Returns:\n list: The rearranged list with the first part moved to the end.\n \"\"\"\n # Ensure n is within the bounds of the list length\n if n >= len(lst):\n return lst\n # Split the list and rearrange\n return lst[n:] + lst[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"\n Splits a list at the nth element and appends the first part to the end.\n\n Parameters:\n arr (list): The input list to be split and rearranged.\n n (int): The index at which the list will be split.\n\n Returns:\n list: The rearranged list with the first part added to the end.\n \"\"\"\n # Ensure n is within the bounds of the list\n if n > 0 and n < len(arr):\n # Split the list into two parts\n first_part = arr[:n]\n second_part = arr[n:]\n # Concatenate the second part with the first part\n return second_part + first_part\n else:\n # Return the original array if n is out of bounds\n return arr", "matching_cluster_idx": 6}, {"solution": "def split_Arr(lst, n):\n \"\"\"\n Splits the list at the nth element and appends the first part to the end.\n\n Parameters:\n lst (list): The list to be manipulated.\n n (int): The position at which to split the list.\n\n Returns:\n list: The modified list with the first part appended to the end.\n \"\"\"\n if n <= 0 or n > len(lst):\n return lst\n \n # Splitting the list into two parts\n first_part = lst[:n]\n second_part = lst[n:]\n \n # Joining the second part with the first part at the end\n return second_part + first_part", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"\n Split the list at the nth element and append the first part to the end.\n \n :param arr: List of elements to be rearranged.\n :param n: The index at which to split the list.\n :return: The rearranged list with the first part added to the end.\n \"\"\"\n # Ensure n is within the bounds of the list\n if n > 0 and n <= len(arr):\n # Split the list and concatenate parts in the new order\n return arr[n:] + arr[:n]\n else:\n # Return the original list if n is out of bounds\n return arr", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"\n Splits the list at the nth element and adds the first part to the end.\n \n Parameters:\n arr (list): The list of elements to be rearranged.\n n (int): The index at which to split the list.\n \n Returns:\n list: The rearranged list with the first part moved to the end.\n \"\"\"\n if n > 0 and n < len(arr): # Check if n is a valid index\n return arr[n:] + arr[:n]\n return arr", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"\n Splits the list at the nth element and moves the first part to the end.\n \n Parameters:\n arr (list): The list to be split and rearranged.\n n (int): The index at which to split the list.\n \n Returns:\n list: The rearranged list with the first part moved to the end.\n \"\"\"\n # Ensure n is within the bounds of the list\n if n > 0 and n < len(arr):\n # Split the list into two parts and concatenate them in reversed order\n return arr[n:] + arr[:n]\n else:\n # If n is out of bounds, return the original list\n return arr", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"\n Splits a list at the nth element and appends the first part to the end.\n\n Parameters:\n arr (list): The input list to be rearranged.\n n (int): The index at which to split the list.\n\n Returns:\n list: The rearranged list with the first part moved to the end.\n \"\"\"\n # Ensure n is within the bounds of the list\n if n > 0 and n <= len(arr):\n # Split the list at the nth element and rearrange\n return arr[n:] + arr[:n]\n else:\n # If n is out of bounds, return the original list\n return arr", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"\n Split a list at the nth element and move the first part to the end.\n \n Parameters:\n arr (list): The input list.\n n (int): The index at which to split the list.\n \n Returns:\n list: The modified list with the first part moved to the end.\n \"\"\"\n if n >= 0 and n < len(arr): # Check if n is within the list bounds\n return arr[n:] + arr[:n]\n else:\n return arr # Return original array if n is out of bounds", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"\n Splits the given list at the nth element and adds the first part to the end.\n \n Parameters:\n arr (list): The input list.\n n (int): The position at which to split the list.\n \n Returns:\n list: The modified list with the first part moved to the end.\n \"\"\"\n if n > 0 and n <= len(arr):\n # Perform the split and rearrangement\n return arr[n:] + arr[:n]\n else:\n # If n is out of bounds, return the original list\n return arr", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"\n Splits the list at the nth element and moves the first part to the end.\n \n Parameters:\n arr (list): The input list.\n n (int): The index at which to split the list.\n \n Returns:\n list: The modified list with the first part moved to the end.\n \"\"\"\n # Ensure n is within the bounds of the list\n if n > 0 and n <= len(arr):\n # Split the list into two parts\n first_part = arr[:n]\n second_part = arr[n:]\n # Concatenate the parts in reverse order\n result = second_part + first_part\n return result\n else:\n # Return the original list if n is out of bounds\n return arr", "matching_cluster_idx": 6}, {"solution": "def split_Arr(lst, n):\n \"\"\"\n Splits a list at the nth element and moves the first part to the end.\n \n Parameters:\n lst (list): The input list to be manipulated.\n n (int): The index at which the list will be split.\n \n Returns:\n list: A new list with the first part moved to the end after the split.\n \"\"\"\n if n <= 0 or n > len(lst):\n return lst\n \n # Split the list into two parts\n first_part = lst[:n]\n second_part = lst[n:]\n \n # Concatenate the second part with the first part\n result = second_part + first_part\n \n return result", "matching_cluster_idx": 6}]}, "Mbpp/587": {"dps": 56.08108108108108, "dps_norm": 87.5, "pass@1": 100.0, "profiled": [{"solution": "def list_tuple(lst):\n \"\"\"\n Converts the given list to a tuple.\n \n Parameters:\n lst (list): The list to be converted.\n \n Returns:\n tuple: A tuple containing the elements of the list.\n \"\"\"\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n \"\"\"\n Converts a given list to a tuple.\n \n Parameters:\n lst (list): The list to be converted.\n \n Returns:\n tuple: The converted tuple from the list.\n \"\"\"\n return tuple(lst)", "matching_cluster_idx": 2}, {"solution": "def list_tuple(lst):\n \"\"\"\n Convert a given list to a tuple.\n\n Parameters:\n lst (list): The list to be converted.\n\n Returns:\n tuple: The converted tuple.\n \"\"\"\n # Convert the list to a tuple using the tuple() function\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n # Convert the given list to a tuple\n return tuple(lst)", "matching_cluster_idx": 2}, {"solution": "def list_tuple(lst):\n \"\"\"\n Converts a given list to a tuple.\n \n Parameters:\n lst (list): The list to be converted.\n \n Returns:\n tuple: The converted tuple.\n \"\"\"\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n # Convert the given list to a tuple\n return tuple(lst)", "matching_cluster_idx": 2}, {"solution": "def list_tuple(lst):\n # Convert the input list to a tuple\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n # Convert the given list to a tuple\n return tuple(lst)", "matching_cluster_idx": 2}, {"solution": "def list_tuple(lst):\n # Convert the list to a tuple\n return tuple(lst)", "matching_cluster_idx": 2}, {"solution": "def list_tuple(lst):\n \"\"\"\n Convert a list to a tuple.\n \n Parameters:\n lst (list): The list to be converted to a tuple.\n \n Returns:\n tuple: A tuple containing the elements of the input list.\n \"\"\"\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n # Convert the list to a tuple\n return tuple(lst)", "matching_cluster_idx": 2}, {"solution": "def list_tuple(lst):\n # Convert the given list to a tuple\n return tuple(lst)", "matching_cluster_idx": 2}, {"solution": "def list_tuple(lst):\n \"\"\"\n Converts a given list to a tuple.\n \n Parameters:\n lst (list): The list to be converted.\n \n Returns:\n tuple: The converted tuple from the list.\n \"\"\"\n return tuple(lst)", "matching_cluster_idx": 2}, {"solution": "def list_tuple(lst):\n \"\"\"\n Converts a given list to a tuple.\n \n Parameters:\n lst (list): The list to be converted.\n \n Returns:\n tuple: A tuple containing the elements of the list.\n \"\"\"\n # Convert the input list to a tuple\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n \"\"\"\n Converts a given list to a tuple.\n \n Parameters:\n lst (list): The list to be converted.\n \n Returns:\n tuple: A tuple containing the elements of the input list.\n \"\"\"\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n \"\"\"\n Converts a given list to a tuple.\n\n Parameters:\n lst (list): The list to be converted.\n\n Returns:\n tuple: The converted tuple.\n \"\"\"\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n \"\"\"\n Converts a given list to a tuple.\n \n Parameters:\n lst (list): The list to be converted.\n \n Returns:\n tuple: A tuple containing the elements of the input list.\n \"\"\"\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n # Convert the list to a tuple\n return tuple(lst)", "matching_cluster_idx": 2}, {"solution": "def list_tuple(input_list):\n # Convert the input list to a tuple\n result = tuple(input_list)\n return result", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n # Convert the list to a tuple\n return tuple(lst)", "matching_cluster_idx": 2}]}, "Mbpp/588": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def big_diff(nums):\n # Calculate the difference between the maximum and minimum values in the list\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n # Find the maximum and minimum values in the list\n max_val = max(nums)\n min_val = min(nums)\n \n # Calculate and return the difference\n return max_val - min_val", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n # Find the maximum and minimum values in the list\n max_val = max(nums)\n min_val = min(nums)\n \n # Calculate and return the difference\n return max_val - min_val", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n # Calculate the difference between the maximum and minimum values in the list\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n # Find the maximum and minimum values in the list\n max_value = max(nums)\n min_value = min(nums)\n \n # Calculate the difference between the maximum and minimum values\n return max_value - min_value", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n # Find the maximum and minimum values in the list\n max_value = max(nums)\n min_value = min(nums)\n \n # Return the difference between the maximum and minimum values\n return max_value - min_value", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n # Find the maximum and minimum values in the list\n max_val = max(nums)\n min_val = min(nums)\n \n # Calculate the difference between the maximum and minimum values\n return max_val - min_val", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n # Find the maximum and minimum values in the list\n max_val = max(nums)\n min_val = min(nums)\n \n # Calculate the difference between the maximum and minimum values\n difference = max_val - min_val\n \n return difference", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n # Find the maximum and minimum values in the list\n max_val = max(nums)\n min_val = min(nums)\n \n # Calculate the difference between the maximum and minimum values\n return max_val - min_val", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n # Find the maximum and minimum values in the list\n max_val = max(nums)\n min_val = min(nums)\n \n # Calculate the difference between the maximum and minimum values\n difference = max_val - min_val\n \n return difference", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n # Find the maximum value in the list\n max_val = max(nums)\n # Find the minimum value in the list\n min_val = min(nums)\n # Return the difference between the maximum and minimum values\n return max_val - min_val", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n # Find the maximum and minimum values in the list\n max_value = max(nums)\n min_value = min(nums)\n \n # Calculate the difference between the maximum and minimum values\n difference = max_value - min_value\n \n return difference", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n # Find the maximum value in the list\n max_val = max(nums)\n # Find the minimum value in the list\n min_val = min(nums)\n # Calculate the difference between the maximum and minimum values\n difference = max_val - min_val\n return difference", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n # Find the maximum value in the list\n max_val = max(nums)\n # Find the minimum value in the list\n min_val = min(nums)\n # Return the difference between the maximum and minimum values\n return max_val - min_val", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n # Find the maximum and minimum values in the list\n max_val = max(nums)\n min_val = min(nums)\n \n # Calculate the difference between the maximum and minimum values\n difference = max_val - min_val\n \n return difference", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n # Find the maximum and minimum values in the list\n max_val = max(nums)\n min_val = min(nums)\n \n # Calculate the difference between the maximum and minimum values\n diff = max_val - min_val\n \n return diff", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n # Find the maximum and minimum values in the list\n max_val = max(nums)\n min_val = min(nums)\n \n # Calculate and return the difference\n return max_val - min_val", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n # Find the maximum and minimum values in the list\n max_val = max(nums)\n min_val = min(nums)\n \n # Return the difference between the maximum and minimum values\n return max_val - min_val", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n # Find the maximum and minimum values in the list\n max_val = max(nums)\n min_val = min(nums)\n \n # Calculate the difference between the maximum and minimum values\n return max_val - min_val", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n # Find the maximum value in the list\n max_val = max(nums)\n # Find the minimum value in the list\n min_val = min(nums)\n # Return the difference between the maximum and minimum values\n return max_val - min_val", "matching_cluster_idx": 5}]}, "Mbpp/592": {"dps": 45.53333333333334, "dps_norm": 43.5, "pass@1": 49.0, "profiled": [{"solution": "from math import factorial\ndef sum_Of_product(n):\n \"\"\"\n This function calculates the sum of the product of consecutive binomial coefficients,\n i.e., C(n, 0)*C(n, 1) + C(n, 1)*C(n, 2) + ... + C(n, n-1)*C(n, n), where C(n, k) denotes n choose k.\n \n Parameters:\n n (int): The number of items to choose from.\n \n Returns:\n int: The sum of the products of consecutive binomial coefficients.\n \"\"\"\n sum_product = 0\n for k in range(n):\n binom_coeff_current = factorial(n) // (factorial(k) * factorial(n - k))\n binom_coeff_next = factorial(n) // (factorial(k + 1) * factorial(n - k - 1))\n sum_product += binom_coeff_current * binom_coeff_next\n return sum_product", "matching_cluster_idx": 2}, {"solution": "from math import factorial\ndef sum_Of_product(n):\n \"\"\"\n This function calculates the sum of the product of consecutive binomial coefficients\n for a given non-negative integer n. The binomial coefficient C(n, k) is calculated as\n factorial(n) / (factorial(k) * factorial(n - k)).\n \n Parameters:\n n (int): A non-negative integer representing the number of terms to calculate.\n \n Returns:\n int: The sum of the product of consecutive binomial coefficients.\n \"\"\"\n def binomial_coefficient(n, k):\n \"\"\"Helper function to calculate binomial coefficient.\"\"\"\n return factorial(n) // (factorial(k) * factorial(n - k))\n \n total_sum = 0\n for k in range(n):\n # Calculate the product of consecutive binomial coefficients\n product = binomial_coefficient(n, k) * binomial_coefficient(n, k + 1)\n total_sum += product\n \n return total_sum", "matching_cluster_idx": 2}, {"solution": "from math import comb\ndef sum_Of_product(n):\n \"\"\"\n Calculates the sum of the product of consecutive binomial coefficients.\n \n Args:\n n : int\n The upper limit for the binomial coefficient calculation.\n \n Returns:\n int\n The sum of the product of consecutive binomial coefficients.\n \"\"\"\n total = 0\n for i in range(n):\n total += comb(n, i) * comb(n, i + 1)\n return total", "matching_cluster_idx": 5}, {"solution": "import math\ndef sum_Of_product(n):\n \"\"\"\n This function calculates the sum of the product of consecutive binomial coefficients\n for a given non-negative integer n.\n \n Args:\n n (int): A non-negative integer representing the number of terms in the binomial expansion.\n \n Returns:\n int: The sum of the product of consecutive binomial coefficients.\n \"\"\"\n # Initialize sum to 0\n total_sum = 0\n \n # Iterate through all k from 0 to n-1\n for k in range(n):\n # Calculate product of binomial coefficients C(k, n) * C(k+1, n)\n product = math.comb(n, k) * math.comb(n, k + 1)\n # Add the product to the total sum\n total_sum += product\n \n return total_sum", "matching_cluster_idx": 5}, {"solution": "from math import factorial\ndef binomial_coefficient(n, k):\n \"\"\"\n Calculate the binomial coefficient C(n, k) which is 'n choose k'.\n \"\"\"\n return factorial(n) // (factorial(k) * factorial(n - k))\ndef sum_Of_product(n):\n \"\"\"\n Finds the sum of the product of consecutive binomial coefficients.\n Args:\n n (int): The number of terms in the sequence of binomial coefficients.\n Returns:\n int: The sum of the product of consecutive binomial coefficients.\n \"\"\"\n # Calculate the sum of products of consecutive binomial coefficients\n sum_product = sum(binomial_coefficient(n, k) * binomial_coefficient(n, k + 1) for k in range(n))\n return sum_product", "matching_cluster_idx": 1}, {"solution": "from math import comb\ndef sum_Of_product(n):\n \"\"\"\n Calculate the sum of the product of consecutive binomial coefficients for a given n.\n \n Args:\n n (int): The number of terms in the sequence of binomial coefficients.\n \n Returns:\n int: The sum of the product of consecutive binomial coefficients.\n \"\"\"\n # Initialize sum to 0\n total_sum = 0\n \n # Iterate through the range from 0 to n-1\n for i in range(n):\n # Calculate the product of binomial coefficients (n choose i) and (n choose i+1)\n product = comb(n, i) * comb(n, i + 1)\n # Add the product to the total sum\n total_sum += product\n \n return total_sum", "matching_cluster_idx": 5}, {"solution": "def sum_Of_product(n):\n \"\"\"\n Calculate the sum of the product of consecutive binomial coefficients for a given n.\n \n Args:\n n (int): A non-negative integer representing the range of binomial coefficients.\n \n Returns:\n int: The sum of the product of consecutive binomial coefficients.\n \"\"\"\n # Helper function to compute binomial coefficient C(n, k)\n def binomial_coefficient(n, k):\n if k > n - k:\n k = n - k\n res = 1\n for i in range(k):\n res *= (n - i)\n res //= (i + 1)\n return res\n \n # Calculate the sum of product of consecutive binomial coefficients\n sum_product = 0\n for k in range(n):\n sum_product += binomial_coefficient(n, k) * binomial_coefficient(n, k + 1)\n \n return sum_product", "matching_cluster_idx": 4}, {"solution": "from math import factorial\ndef binomial_coefficient(n, k):\n \"\"\"\n Helper function to calculate binomial coefficient.\n \"\"\"\n return factorial(n) // (factorial(k) * factorial(n - k))\ndef sum_Of_product(n):\n \"\"\"\n Function to find the sum of the product of consecutive binomial coefficients\n up to n.\n \n Parameters:\n n (int): The number up to which the sum of products is calculated.\n \n Returns:\n int: The sum of products of consecutive binomial coefficients.\n \"\"\"\n # Initialize sum to 0\n sum_products = 0\n \n # Iterate from 0 to n-1 to calculate the sum of products of consecutive binomial coefficients\n for i in range(n):\n sum_products += binomial_coefficient(n, i) * binomial_coefficient(n, i + 1)\n \n return sum_products", "matching_cluster_idx": 1}, {"solution": "from math import comb\ndef sum_Of_product(n):\n \"\"\"\n Calculate the sum of the product of consecutive binomial coefficients.\n \n Args:\n n : int. The upper limit of the range for binomial coefficients.\n \n Returns:\n int. The sum of the products of consecutive binomial coefficients.\n \"\"\"\n total_sum = 0\n for i in range(n):\n total_sum += comb(n, i) * comb(n, i + 1)\n return total_sum", "matching_cluster_idx": 5}, {"solution": "from math import comb\ndef sum_Of_product(n):\n \"\"\"\n This function calculates the sum of the product of consecutive binomial coefficients.\n \n Parameters:\n n (int): The number of terms in the sequence of binomial coefficients.\n \n Returns:\n int: The sum of the product of consecutive binomial coefficients.\n \"\"\"\n # Calculate the sum of products of consecutive binomial coefficients\n total_sum = sum(comb(n, k) * comb(n, k + 1) for k in range(n))\n return total_sum", "matching_cluster_idx": 4}, {"solution": "import math\ndef sum_Of_product(n):\n \"\"\"\n This function calculates the sum of the product of consecutive binomial coefficients\n for a given positive integer n.\n \n Parameters:\n n (int): A positive integer\n \n Returns:\n int: The sum of the product of consecutive binomial coefficients\n \"\"\"\n # Initialize sum to 0\n total_sum = 0\n \n # Loop through all r from 0 to n-1\n for r in range(n):\n # Calculate the product of C(r, n) and C(r+1, n)\n product = math.comb(n, r) * math.comb(n, r + 1)\n # Add the product to the total sum\n total_sum += product\n \n return total_sum", "matching_cluster_idx": 5}, {"solution": "from math import factorial\ndef binomial_coefficient(n, k):\n \"\"\"\n Calculate the binomial coefficient, also known as \"n choose k\".\n \"\"\"\n return factorial(n) // (factorial(k) * factorial(n - k))\ndef sum_Of_product(n):\n \"\"\"\n Calculate the sum of the product of consecutive binomial coefficients.\n For example, the sum would be C(n, 0)*C(n, 1) + C(n, 1)*C(n, 2) + ... + C(n, n-1)*C(n, n)\n where C(n, k) is the binomial coefficient for n and k.\n \"\"\"\n sum_product = 0\n for k in range(n):\n sum_product += binomial_coefficient(n, k) * binomial_coefficient(n, k + 1)\n return sum_product", "matching_cluster_idx": 2}, {"solution": "def sum_Of_product(n):\n def binomial_coefficient(n, k):\n # Calculate binomial coefficient C(n, k)\n if k > n - k:\n k = n - k\n result = 1\n for i in range(1, k + 1):\n result *= n - (k - i)\n result //= i\n return result\n \n result_sum = 0\n # Iterate through the range to calculate the sum of products of consecutive binomial coefficients\n for i in range(0, n):\n result_sum += binomial_coefficient(n, i) * binomial_coefficient(n, i + 1)\n \n return result_sum", "matching_cluster_idx": 4}, {"solution": "def sum_Of_product(n):\n def factorial(num):\n \"\"\"Helper function to calculate factorial of a number.\"\"\"\n result = 1\n for i in range(2, num + 1):\n result *= i\n return result\n \n def binomial_coefficient(n, k):\n \"\"\"Helper function to calculate binomial coefficient C(n, k).\"\"\"\n return factorial(n) // (factorial(k) * factorial(n - k))\n \n # Calculate the sum of the product of consecutive binomial coefficients\n total_sum = sum(binomial_coefficient(n, k) * binomial_coefficient(n, k + 1) for k in range(n))\n return total_sum", "matching_cluster_idx": 0}, {"solution": "import math\ndef sum_Of_product(n):\n \"\"\"\n This function calculates the sum of the product of consecutive binomial coefficients\n for a given non-negative integer n.\n \n Parameters:\n n (int): A non-negative integer representing the number of terms in the sequence.\n \n Returns:\n int: The sum of the product of consecutive binomial coefficients.\n \"\"\"\n total_sum = 0\n for i in range(n + 1):\n # Calculate the product of C(n, i) * C(n, i + 1) and add it to the total sum\n product = math.comb(n, i) * math.comb(n, i + 1)\n total_sum += product\n return total_sum", "matching_cluster_idx": 5}, {"solution": "import math\ndef sum_Of_product(n):\n \"\"\"\n Calculates the sum of the product of consecutive binomial coefficients for a given n.\n \n Args:\n n (int): The number of terms to consider.\n \n Returns:\n int: The sum of the product of consecutive binomial coefficients.\n \"\"\"\n total_sum = 0\n for i in range(n + 1):\n # Calculate the product of binomial coefficients (n choose i) and (n choose i+1)\n product = math.comb(n, i) * math.comb(n, i + 1)\n total_sum += product\n return total_sum", "matching_cluster_idx": 5}, {"solution": "import math\ndef sum_Of_product(n):\n \"\"\"\n Calculate the sum of the product of consecutive binomial coefficients.\n \n Args:\n n : int. The upper limit for the binomial coefficients to consider.\n \n Returns:\n int. The sum of the product of each pair of consecutive binomial coefficients C(n, k) * C(n, k+1).\n \"\"\"\n total_sum = 0\n for k in range(n):\n # Calculate C(n, k) * C(n, k+1) and add it to the total sum\n total_sum += math.comb(n, k) * math.comb(n, k + 1)\n return total_sum", "matching_cluster_idx": 5}, {"solution": "from math import factorial\ndef binomial_coefficient(n, k):\n \"\"\"\n Helper function to calculate the binomial coefficient (n choose k)\n \"\"\"\n return factorial(n) // (factorial(k) * factorial(n - k))\ndef sum_Of_product(n):\n \"\"\"\n Function to find the sum of the product of consecutive binomial coefficients.\n Example:\n >>> sum_Of_product(3)\n 15\n \"\"\"\n total_sum = 0\n for i in range(n):\n total_sum += binomial_coefficient(n, i) * binomial_coefficient(n, i + 1)\n return total_sum", "matching_cluster_idx": 2}, {"solution": "from math import comb\ndef sum_Of_product(n):\n \"\"\"\n This function calculates the sum of the product of consecutive binomial coefficients\n up to n.\n \n Args:\n n (int): The upper limit for the binomial coefficients.\n \n Returns:\n int: The sum of the product of consecutive binomial coefficients.\n \"\"\"\n return sum(comb(n, k) * comb(n, k + 1) for k in range(n))", "matching_cluster_idx": 4}, {"solution": "from math import factorial\ndef binomial_coefficient(n, k):\n \"\"\"\n Helper function to calculate binomial coefficient.\n \"\"\"\n return factorial(n) // (factorial(k) * factorial(n - k))\ndef sum_Of_product(n):\n \"\"\"\n Function to find the sum of the product of consecutive binomial coefficients.\n For example:\n sum_Of_product(3) should return 15.\n \"\"\"\n return sum(binomial_coefficient(n, k) * binomial_coefficient(n, k + 1) for k in range(n))", "matching_cluster_idx": 1}]}, "Mbpp/597": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 13.0, "profiled": [{"solution": "def find_kth(nums1, nums2, k):\n \"\"\"\n Find the kth element from the merged sorted array of nums1 and nums2.\n \n :param nums1: List of integers, sorted in non-decreasing order.\n :param nums2: List of integers, sorted in non-decreasing order.\n :param k: Integer representing the kth position (1-based index).\n :return: The kth smallest element from the merged sorted array of nums1 and nums2.\n \"\"\"\n # Merge the two lists and sort the combined list\n merged_list = sorted(nums1 + nums2)\n \n # Return the k-1 indexed element as list index starts from 0\n return merged_list[k-1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(nums1, nums2, k):\n \"\"\"\n Find the kth element from two given sorted arrays.\n \n Args:\n nums1: First sorted list of integers.\n nums2: Second sorted list of integers.\n k: The kth position to find.\n \n Returns:\n The kth element from the two sorted arrays combined.\n \"\"\"\n # Combine the two lists and sort them\n combined = sorted(nums1 + nums2)\n # Return the k-1 indexed element (since k is 1-based index)\n return combined[k-1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(arr1, arr2, k):\n # Combine both arrays\n combined_array = arr1 + arr2\n # Sort the combined array\n combined_array.sort()\n # Return the k-1 indexed element as list indices are 0-based\n return combined_array[k-1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(nums1, nums2, k):\n # Combine the two arrays\n combined = nums1 + nums2\n # Sort the combined array\n combined.sort()\n # Return the kth element (index k-1)\n return combined[k-1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(nums1, nums2, k):\n \"\"\"\n Find the kth element from the union of two sorted arrays.\n \n Args:\n nums1 : List[int] - First sorted array.\n nums2 : List[int] - Second sorted array.\n k : int - The kth position to find.\n \n Returns:\n int - The kth smallest element in the combined sorted array.\n \"\"\"\n # Merge the two sorted arrays and sort the resulting list\n combined = sorted(nums1 + nums2)\n \n # Return the kth smallest element, adjusting k to be zero-indexed\n return combined[k - 1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(arr1, arr2, k):\n # Validate the input to ensure k is within the range of the combined array lengths\n if k < 1 or k > len(arr1) + len(arr2):\n return None\n \n # Merge and sort the arrays to find the kth element\n merged_array = sorted(arr1 + arr2)\n \n # Return the k-1 indexed element since list indices start from 0\n return merged_array[k-1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(nums1, nums2, k):\n # Combine both lists and sort the resulting list\n combined_sorted = sorted(nums1 + nums2)\n \n # Return the kth element in zero-indexed form\n return combined_sorted[k-1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(nums1, nums2, k):\n # Combine the two lists\n merged_list = sorted(nums1 + nums2)\n # Return the kth element (index k-1)\n return merged_list[k-1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(nums1, nums2, k):\n \"\"\"\n Find the kth element from two sorted arrays.\n \n Args:\n nums1: List[int] - first sorted array.\n nums2: List[int] - second sorted array.\n k: int - the kth position to find.\n \n Returns:\n int - the kth element from the two sorted arrays.\n \"\"\"\n # Merge the two lists and sort the combined list\n merged_list = sorted(nums1 + nums2)\n \n # Return the k-1 indexed element from the sorted combined list\n return merged_list[k-1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(nums1, nums2, k):\n # Combine the two arrays\n combined = sorted(nums1 + nums2)\n \n # Check if k is within the bounds of the combined array\n if k > len(combined) or k <= 0:\n return None\n \n # Return the kth element (0-based indexing)\n return combined[k - 1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(nums1, nums2, k):\n # Combine the two lists into one\n combined_list = sorted(nums1 + nums2)\n \n # Return the kth element (index k-1)\n return combined_list[k - 1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(nums1, nums2, k):\n # Combine both lists\n combined_list = sorted(nums1 + nums2)\n \n # Check if k is within the valid range\n if k <= 0 or k > len(combined_list):\n return None\n \n # Return the kth element (1-indexed)\n return combined_list[k - 1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(nums1, nums2, k):\n \"\"\"\n Find the kth element from the sorted arrays nums1 and nums2.\n \n Parameters:\n nums1 (List[int]): First sorted array.\n nums2 (List[int]): Second sorted array.\n k (int): The kth position to find.\n \n Returns:\n int: The kth smallest element from the combined sorted array of nums1 and nums2.\n \"\"\"\n # Merge the two sorted arrays and return the k-1 indexed element as Python uses 0-based indexing\n merged_array = sorted(nums1 + nums2)\n return merged_array[k-1]", "matching_cluster_idx": 3}]}, "Mbpp/604": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 94.0, "profiled": [{"solution": "def reverse_words(s):\n # Split the input string into words, reverse the list of words, and join them back with spaces\n return ' '.join(s.split()[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n \"\"\"\n Reverse the order of words in a given string.\n \n Parameters:\n s (str): The input string containing words separated by spaces.\n \n Returns:\n str: A new string with the order of words reversed.\n \"\"\"\n # Split the string into words, reverse the list of words, and then join them back together\n return \" \".join(s.split()[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n # Split the string into words, reverse the list of words, then join them back together\n return ' '.join(s.split()[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n \"\"\"\n Reverses the order of words in a given string.\n \n Parameters:\n s (str): The input string containing words separated by spaces.\n \n Returns:\n str: The string with the order of words reversed.\n \"\"\"\n # Split the string into words, reverse the list of words, and then join them back together with spaces\n return ' '.join(s.split()[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n # Split the input string into words, reverse the list of words, and then join them back with a space\n return ' '.join(s.split()[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n # Split the string into words, reverse the list of words, and then join them back with a space\n return ' '.join(s.split()[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n # Split the string into words, reverse the list of words, and then join them back with a space\n return ' '.join(s.split()[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n # Split the string into words, reverse the list of words, and join them back together\n return ' '.join(s.split()[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n # Split the string into words, reverse the list of words, and join them back into a string\n return ' '.join(s.split()[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n # Split the string into words based on spaces, reverse the list of words, then join them back with a space\n return ' '.join(s.split()[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n \"\"\"\n Reverses words separated by spaces in a given string.\n \n Parameters:\n s (str): The input string containing words separated by spaces.\n \n Returns:\n str: The string with the order of words reversed.\n \"\"\"\n # Split the string into words, reverse the list of words, and join them back into a string\n return ' '.join(s.split()[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n # Split the string into words, reverse the list of words, and join them back into a string\n return ' '.join(s.split()[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n # Split the string into words, reverse the list of words, and then join them back with a space\n return ' '.join(s.split()[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n \"\"\"\n Reverses the order of words in a given string.\n \n Parameters:\n s (str): The input string containing words separated by spaces.\n \n Returns:\n str: A string with the order of words reversed.\n \"\"\"\n # Split the string into words, reverse the list of words, and then join them back together with spaces\n return ' '.join(s.split()[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n \"\"\"\n Reverses the order of words in a given string.\n \n Parameters:\n s (str): The input string containing words separated by spaces.\n \n Returns:\n str: A new string with the order of words reversed.\n \"\"\"\n # Split the string into words, reverse the list of words, and join them back into a string\n return ' '.join(s.split()[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n \"\"\"\n Reverse the order of words in a given string.\n \n Parameters:\n s (str): The input string containing words separated by spaces.\n \n Returns:\n str: A string with the order of words reversed.\n \"\"\"\n # Split the string into words, reverse the list of words, and join them back into a string\n return ' '.join(s.split()[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n # Split the input string by spaces, reverse the list of words, and join them back together with spaces\n return ' '.join(s.split()[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n \"\"\"\n Reverses the order of words separated by spaces in a given string.\n \n Parameters:\n s (str): The input string containing words separated by spaces.\n \n Returns:\n str: The string with the order of words reversed.\n \"\"\"\n # Split the string into words, reverse the list of words, and then join them back with a space\n reversed_str = ' '.join(s.split()[::-1])\n return reversed_str", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n # Split the string into words, reverse the list of words, and join them back into a string\n return ' '.join(s.split()[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n # Split the string into words, reverse the list of words, and then join them back together\n return ' '.join(s.split()[::-1])", "matching_cluster_idx": 4}]}, "Mbpp/610": {"dps": 71.08695652173914, "dps_norm": 70.0, "pass@1": 41.0, "profiled": [{"solution": "def remove_kth_element(lst, k):\n \"\"\"\n Removes the k'th element from the list and returns a new list without modifying the original list.\n \n Args:\n lst: List from which the k'th element is to be removed.\n k: Index of the element to remove (1-based index).\n \n Returns:\n A new list with the k'th element removed.\n \"\"\"\n # Convert 1-based index to 0-based index\n k = k - 1\n \n # Create a new list without the k'th element\n new_lst = lst[:k] + lst[k+1:]\n \n return new_lst", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(lst, k):\n \"\"\"\n Returns a list with the same elements as the input list, but with the k'th element removed.\n \n Parameters:\n lst (list): The input list.\n k (int): The index of the element to be removed, where the first element is at index 1.\n \n Returns:\n list: The resulting list with the k'th element removed.\n \"\"\"\n # Adjust k to work with zero-based indexing\n return lst[:k-1] + lst[k:]", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(lst, k):\n \"\"\"\n Removes the k'th element from the given list.\n \n Parameters:\n lst (list): The input list from which an element will be removed.\n k (int): The index of the element to remove (1-based index).\n \n Returns:\n list: A new list with the k'th element removed.\n \"\"\"\n # Convert 1-based index to 0-based index\n k = k - 1\n # Remove the k'th element\n lst = lst[:k] + lst[k+1:]\n return lst", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(lst, k):\n \"\"\"\n Returns a list with the same elements as the input list, but without the k'th element.\n \n Parameters:\n lst (list): The input list of elements.\n k (int): The index of the element to be removed (1-based index).\n \n Returns:\n list: The new list with the k'th element removed.\n \"\"\"\n # Convert 1-based index to 0-based index\n k = k - 1\n # Remove the k'th element and return the new list\n lst = lst[:k] + lst[k+1:]\n return lst", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(lst, k):\n \"\"\"\n Returns a list with the same elements, but the k'th element removed.\n \n Parameters:\n lst (list): The original list of elements.\n k (int): The index of the element to remove (1-based index).\n \n Returns:\n list: A new list with the k'th element removed.\n \"\"\"\n # Convert 1-based index to 0-based index\n k = k - 1\n # Check if k is within the bounds of the list\n if k < 0 or k >= len(lst):\n return lst # Return the original list if out of bounds\n \n # Remove the k'th element and return the list\n return lst[:k] + lst[k+1:]", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(lst, k):\n \"\"\"\n Takes a list and returns a new list with the k'th element removed.\n \n Parameters:\n lst (list): The original list of elements.\n k (int): The index of the element to remove (1-based index).\n \n Returns:\n list: A new list with the k'th element removed.\n \"\"\"\n # Adjust k to 0-based index\n k = k - 1\n # Check if k is within bounds\n if k < 0 or k >= len(lst):\n raise ValueError(\"The value of k is out of the bounds of the list.\")\n \n # Remove the k'th element and return the new list\n return lst[:k] + lst[k+1:]", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(nums, k):\n \"\"\"\n Takes a list nums and an index k, and returns the list with the k'th element removed.\n \n Parameters:\n nums (list): The input list.\n k (int): The 1-based index of the element to remove.\n \n Returns:\n list: The list after removing the k'th element.\n \"\"\"\n # Adjust k to be 0-based index\n k -= 1\n # Remove the k'th element and return the modified list\n del nums[k]\n return nums", "matching_cluster_idx": 6}, {"solution": "def remove_kth_element(lst, k):\n \"\"\"\n Removes the k'th element from the list and returns a new list.\n \n Parameters:\n lst (list): The input list from which the k'th element will be removed.\n k (int): The 1-based index of the element to remove.\n \n Returns:\n list: The new list with the k'th element removed.\n \"\"\"\n # Convert 1-based index to 0-based index\n k -= 1\n # Create a new list excluding the k'th element\n new_lst = lst[:k] + lst[k+1:]\n return new_lst", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(lst, k):\n \"\"\"\n Returns a list with the k'th element removed.\n \n Parameters:\n lst (list): The original list from which an element will be removed.\n k (int): The index of the element to be removed (1-based index).\n \n Returns:\n list: A new list with the k'th element removed.\n \"\"\"\n # Convert 1-based index to 0-based index\n k = k - 1\n # Remove the k'th element and return the new list\n return lst[:k] + lst[k+1:]", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(lst, k):\n \"\"\"\n Function to remove the k'th element from a list and return the modified list.\n \n Parameters:\n lst (list): The input list from which an element is to be removed.\n k (int): The index (1-based) of the element to remove.\n \n Returns:\n list: The modified list after removing the k'th element.\n \"\"\"\n # Convert 1-based index to 0-based index\n k -= 1\n # Remove the k'th element and return the list\n del lst[k]\n return lst", "matching_cluster_idx": 6}, {"solution": "def remove_kth_element(lst, k):\n \"\"\"\n Removes the k'th element from the list and returns the modified list.\n \n Parameters:\n lst (list): The input list.\n k (int): The index of the element to remove (1-based index).\n \n Returns:\n list: The list with the k'th element removed.\n \"\"\"\n # Convert 1-based index to 0-based index\n k -= 1\n \n # Remove the k'th element from the list\n lst.pop(k)\n \n return lst", "matching_cluster_idx": 6}, {"solution": "def remove_kth_element(lst, k):\n \"\"\"\n Removes the k'th element from the list and returns the modified list.\n \n Parameters:\n lst (list): The input list from which the k'th element is to be removed.\n k (int): The index (1-based) of the element to be removed from the list.\n \n Returns:\n list: The list with the k'th element removed.\n \"\"\"\n # Convert 1-based index to 0-based index\n k = k - 1\n # Remove the k'th element and return the list\n del lst[k]\n return lst", "matching_cluster_idx": 6}, {"solution": "def remove_kth_element(lst, k):\n \"\"\"\n Removes the k'th element from the list and returns a new list with the remaining elements.\n \n Args:\n lst : List of elements from which one will be removed.\n k : The 1-based index of the element to remove.\n \n Returns:\n A new list with the k'th element removed.\n \"\"\"\n # Ensure k is within the bounds of the list indices (0-based)\n if 0 < k <= len(lst):\n # Return the list with the k-1 element removed\n return lst[:k-1] + lst[k:]\n else:\n # If k is out of bounds, return the original list\n return lst", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(lst, k):\n \"\"\"\n Takes a list and returns a list with the k'th element removed.\n \n Parameters:\n lst (list): The input list from which the k'th element will be removed.\n k (int): The index (1-based) of the element to remove.\n \n Returns:\n list: A new list with the k'th element removed.\n \"\"\"\n # Convert 1-based index to 0-based index\n k = k - 1\n # Remove the k'th element from the list\n lst = lst[:k] + lst[k+1:]\n return lst", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(nums, k):\n # Create a list without the k'th element\n # The k'th element is removed by slicing the list into two parts and then merging them\n return nums[:k-1] + nums[k:]", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(lst, k):\n \"\"\"\n Returns a list with the same elements as the input list, but the k'th element removed.\n \n Parameters:\n lst (list): The input list.\n k (int): The index of the element to remove (1-based index).\n \n Returns:\n list: A new list with the k'th element removed.\n \"\"\"\n # Convert 1-based index to 0-based index\n k -= 1\n # Remove the k'th element and return the new list\n return lst[:k] + lst[k+1:]", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(lst, k):\n \"\"\"\n Removes the k'th element from the list and returns the modified list.\n \n Parameters:\n lst (list): The input list from which the element will be removed.\n k (int): The index of the element to be removed (1-based index).\n \n Returns:\n list: The modified list with the k'th element removed.\n \"\"\"\n # Convert 1-based index to 0-based index\n k = k - 1\n # Remove the k'th element and return the list\n del lst[k]\n return lst", "matching_cluster_idx": 6}, {"solution": "def remove_kth_element(lst, k):\n \"\"\"\n Returns a list with the same elements as the input list, but the k'th element is removed.\n \n Parameters:\n lst (list): The input list of elements.\n k (int): The index of the element to be removed (1-based index).\n \n Returns:\n list: The new list with the k'th element removed.\n \"\"\"\n # Convert 1-based index to 0-based index\n k -= 1\n # Remove the k'th element\n removed = lst[:k] + lst[k+1:]\n return removed", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(lst, k):\n \"\"\"\n Returns a list with the same elements as the input list, but the k'th element removed.\n \n Parameters:\n lst (list): The input list.\n k (int): The index of the element to be removed, assuming a 1-based index.\n \n Returns:\n list: A list with the k'th element removed.\n \"\"\"\n # Convert 1-based index to 0-based index\n k = k - 1\n # Remove the k'th element from the list and return the updated list\n lst.pop(k)\n return lst", "matching_cluster_idx": 6}, {"solution": "def remove_kth_element(lst, k):\n \"\"\"\n Removes the k'th element from the given list and returns a new list with the remaining elements.\n \n :param lst: List of elements from which the k'th element needs to be removed.\n :param k: The index (1-based) of the element to remove.\n :return: A new list with the k'th element removed.\n \"\"\"\n # Convert 1-based index to 0-based index\n k = k - 1\n # Remove the k'th element using list slicing\n return lst[:k] + lst[k+1:]", "matching_cluster_idx": 3}]}, "Mbpp/611": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def max_of_nth(matrix, n):\n # Use list comprehension to get the n'th column of the matrix\n nth_column = [row[n] for row in matrix]\n # Return the maximum value of the n'th column\n return max(nth_column)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n # Use a generator expression to extract the n'th element from each row and find the maximum value\n return max(row[n] for row in matrix)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n # Extract the n'th column from the matrix and find its maximum value\n return max(row[n] for row in matrix)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n # Use a generator expression to get the nth element of each row and find the max value\n return max(row[n] for row in matrix)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n # Extract the n'th column from each row and find the maximum value\n return max(row[n] for row in matrix)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n # Extract the n'th column from each row and return the maximum value\n return max(row[n] for row in matrix)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n # Use a generator expression to extract the n'th element from each row and find the maximum value\n return max(row[n] for row in matrix)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n # Use a generator expression to find the maximum value in the n'th column\n return max(row[n] for row in matrix)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n # Use list comprehension to extract the n'th column and find the maximum value\n return max(row[n] for row in matrix)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n # Extract the n'th column from the matrix and find the maximum value\n return max(row[n] for row in matrix)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n # Use a generator expression to extract the n'th column and find its maximum value\n return max(row[n] for row in matrix)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n # Extract the n'th column from each row of the matrix and find the maximum value.\n return max(row[n] for row in matrix)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n # Use a generator expression to extract the n'th column and find the maximum value\n return max(row[n] for row in matrix)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n # Use list comprehension to extract the n'th column and find the max value\n return max(row[n] for row in matrix)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n # Use list comprehension to extract the n'th column and find its maximum value\n return max(row[n] for row in matrix)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n # Extract the n'th column from each row in the matrix\n column_values = [row[n] for row in matrix]\n # Return the maximum value in the n'th column\n return max(column_values)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n # Use list comprehension to extract the n'th column and find the maximum value\n return max(row[n] for row in matrix)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n # Use list comprehension to extract the n'th column and find the max value\n return max(row[n] for row in matrix)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n # Use a generator expression to find the maximum value in the specified column\n return max(row[n] for row in matrix)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n # Use a generator expression to get the nth column and find its maximum value\n return max(row[n] for row in matrix)", "matching_cluster_idx": 5}]}, "Mbpp/631": {"dps": 16.597222222222218, "dps_norm": 33.75, "pass@1": 85.0, "profiled": [{"solution": "def replace_spaces(s):\n result = ''\n for char in s:\n if char == ' ':\n result += '_'\n elif char == '_':\n result += ' '\n else:\n result += char\n return result", "matching_cluster_idx": 1}, {"solution": "def replace_spaces(input_string):\n result = ''\n for char in input_string:\n if char == ' ':\n result += '_'\n elif char == '_':\n result += ' '\n else:\n result += char\n return result", "matching_cluster_idx": 1}, {"solution": "def replace_spaces(input_string):\n result = ''\n for char in input_string:\n if char == ' ':\n result += '_'\n elif char == '_':\n result += ' '\n else:\n result += char\n return result", "matching_cluster_idx": 1}, {"solution": "def replace_spaces(input_string):\n # Translate function to replace ' ' with '_' and '_' with ' '\n translation_table = input_string.maketrans(\"_ \", \" _\")\n # Using translate with the translation table\n replaced_string = input_string.translate(translation_table)\n return replaced_string", "matching_cluster_idx": 6}, {"solution": "def replace_spaces(input_string):\n result = \"\"\n for char in input_string:\n if char == \" \":\n result += \"_\"\n elif char == \"_\":\n result += \" \"\n else:\n result += char\n return result", "matching_cluster_idx": 1}, {"solution": "def replace_spaces(input_string):\n result = ''\n for char in input_string:\n if char == ' ':\n result += '_'\n elif char == '_':\n result += ' '\n else:\n result += char\n return result", "matching_cluster_idx": 1}, {"solution": "def replace_spaces(input_string):\n # Replace whitespaces with underscores and vice versa\n result = input_string.replace(' ', 'XX').replace('_', ' ').replace('XX', '_')\n return result", "matching_cluster_idx": 3}, {"solution": "def replace_spaces(s):\n result = \"\"\n for char in s:\n if char == \" \":\n result += \"_\"\n elif char == \"_\":\n result += \" \"\n else:\n result += char\n return result", "matching_cluster_idx": 1}, {"solution": "def replace_spaces(s):\n result = ''\n for char in s:\n if char == ' ':\n result += '_'\n elif char == '_':\n result += ' '\n else:\n result += char\n return result", "matching_cluster_idx": 1}, {"solution": "def replace_spaces(input_string):\n result = []\n for char in input_string:\n if char == ' ':\n result.append('_')\n elif char == '_':\n result.append(' ')\n else:\n result.append(char)\n return ''.join(result)", "matching_cluster_idx": 3}, {"solution": "def replace_spaces(input_string):\n result = ''\n for char in input_string:\n if char == ' ':\n result += '_'\n elif char == '_':\n result += ' '\n else:\n result += char\n return result", "matching_cluster_idx": 1}, {"solution": "def replace_spaces(s):\n result = \"\"\n for char in s:\n if char == \" \":\n result += \"_\"\n elif char == \"_\":\n result += \" \"\n else:\n result += char\n return result", "matching_cluster_idx": 1}, {"solution": "def replace_spaces(input_string):\n result = ''\n for char in input_string:\n if char == ' ':\n result += '_'\n elif char == '_':\n result += ' '\n else:\n result += char\n return result", "matching_cluster_idx": 1}, {"solution": "def replace_spaces(input_string):\n result = ''\n for char in input_string:\n if char == ' ':\n result += '_'\n elif char == '_':\n result += ' '\n else:\n result += char\n return result", "matching_cluster_idx": 1}, {"solution": "def replace_spaces(input_string):\n result = ''\n for char in input_string:\n if char == ' ':\n result += '_'\n elif char == '_':\n result += ' '\n else:\n result += char\n return result", "matching_cluster_idx": 1}, {"solution": "def replace_spaces(input_string):\n result = []\n for char in input_string:\n if char == ' ':\n result.append('_')\n elif char == '_':\n result.append(' ')\n else:\n result.append(char)\n return ''.join(result)", "matching_cluster_idx": 3}, {"solution": "def replace_spaces(input_string):\n # Replace whitespaces with underscores and vice versa\n replaced_string = input_string.replace(' ', '#').replace('_', ' ').replace('#', '_')\n return replaced_string", "matching_cluster_idx": 4}, {"solution": "def replace_spaces(input_string):\n result = ''\n for char in input_string:\n if char == ' ':\n result += '_'\n elif char == '_':\n result += ' '\n else:\n result += char\n return result", "matching_cluster_idx": 1}, {"solution": "def replace_spaces(input_string):\n result = ''\n for char in input_string:\n if char == ' ':\n result += '_'\n elif char == '_':\n result += ' '\n else:\n result += char\n return result", "matching_cluster_idx": 1}, {"solution": "def replace_spaces(input_string):\n result = ''\n for char in input_string:\n if char == ' ':\n result += '_'\n elif char == '_':\n result += ' '\n else:\n result += char\n return result", "matching_cluster_idx": 1}]}, "Mbpp/632": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def move_zero(nums):\n # Function to move all zeroes to the end of the given list\n non_zero = [num for num in nums if num != 0]\n zeros = [0] * (len(nums) - len(non_zero))\n return non_zero + zeros", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n # Separate non-zero elements and count the zeros\n non_zeros = [num for num in nums if num != 0]\n zeros = [0] * nums.count(0)\n \n # Concatenate non-zero elements with zeros\n result = non_zeros + zeros\n \n return result", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n # List to store non-zero elements\n non_zero = []\n # Counter for zero elements\n zero_count = 0\n \n # Iterate over the list and separate non-zero and zero elements\n for num in nums:\n if num != 0:\n non_zero.append(num)\n else:\n zero_count += 1\n \n # Append the required number of zeros to the non-zero list\n non_zero.extend([0] * zero_count)\n \n return non_zero", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n # Initialize a pointer for the position to insert the next non-zero element\n insert_pos = 0\n \n # Move all non-zero elements to the front of the list\n for num in nums:\n if num != 0:\n nums[insert_pos] = num\n insert_pos += 1\n \n # Fill the remaining positions with zeroes\n while insert_pos < len(nums):\n nums[insert_pos] = 0\n insert_pos += 1\n \n return nums", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n # List to store non-zero elements\n non_zeros = []\n # Counter for zeros\n zeros = 0\n \n # Separate non-zero and zero elements\n for num in nums:\n if num != 0:\n non_zeros.append(num)\n else:\n zeros += 1\n \n # Extend the list with zeros at the end\n non_zeros.extend([0] * zeros)\n \n return non_zeros", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n # Create a list with all non-zero elements\n non_zeros = [num for num in nums if num != 0]\n # Append zeros to the list\n zeros = [num for num in nums if num == 0]\n # Combine non-zero elements with zeros at the end\n result = non_zeros + zeros\n return result", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n # List to store non-zero elements\n non_zero = []\n # Counter for zeros in the input list\n zero_count = 0\n \n # Separating non-zero and zero elements\n for num in nums:\n if num != 0:\n non_zero.append(num)\n else:\n zero_count += 1\n \n # Appending zeros to the end\n non_zero.extend([0] * zero_count)\n \n return non_zero", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n # Create a list with all non-zero elements\n non_zeros = [num for num in nums if num != 0]\n # Append the necessary number of zeroes to the list\n non_zeros.extend([0] * (len(nums) - len(non_zeros)))\n return non_zeros", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n # Initialize a pointer for the position to insert the next non-zero element\n insert_pos = 0\n \n # Iterate through the list and move non-zero elements to the front\n for i in range(len(nums)):\n if nums[i] != 0:\n nums[insert_pos] = nums[i]\n insert_pos += 1\n \n # Fill the remaining positions with zeroes\n for i in range(insert_pos, len(nums)):\n nums[i] = 0\n \n return nums", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n # Separate non-zero and zero elements\n non_zero = [num for num in nums if num != 0]\n zeros = [num for num in nums if num == 0]\n \n # Concatenate non-zero elements with zero elements\n result = non_zero + zeros\n return result", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n # Using list comprehension to separate non-zero elements and zero elements\n non_zero = [num for num in nums if num != 0]\n zero = [num for num in nums if num == 0]\n \n # Concatenating non-zero list with zero list to move all zeroes to the end\n result = non_zero + zero\n return result", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n # Create a list with all non-zero elements\n non_zero = [num for num in nums if num != 0]\n # Append zeros to the list\n zeros = [num for num in nums if num == 0]\n # Combine non-zero elements with zeros\n non_zero.extend(zeros)\n return non_zero", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n # Initialize a pointer for the position to insert the next non-zero element\n insert_pos = 0\n \n # Move all non-zero elements to the front, tracking their positions\n for num in nums:\n if num != 0:\n nums[insert_pos] = num\n insert_pos += 1\n \n # Fill the remaining positions with zeros\n for i in range(insert_pos, len(nums)):\n nums[i] = 0\n \n return nums", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n # Initialize a pointer for the position to insert the next non-zero element\n j = 0\n \n # Move all non-zero elements to the front of the list\n for num in nums:\n if num != 0:\n nums[j] = num\n j += 1\n \n # Fill the rest of the list with zeros\n while j < len(nums):\n nums[j] = 0\n j += 1\n \n return nums", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n # Initialize a pointer for the position to insert the next non-zero element\n pos = 0\n \n # Move all non-zero elements to the front of the list\n for num in nums:\n if num != 0:\n nums[pos] = num\n pos += 1\n \n # Fill the remaining positions with zeros\n for i in range(pos, len(nums)):\n nums[i] = 0\n \n return nums", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n # Initialize a pointer to keep track of the position to insert the next non-zero element\n insert_pos = 0\n \n # Iterate through the list and move non-zero elements to the insert_pos\n for num in nums:\n if num != 0:\n nums[insert_pos] = num\n insert_pos += 1\n \n # Fill the rest of the list with zeros\n while insert_pos < len(nums):\n nums[insert_pos] = 0\n insert_pos += 1\n \n return nums", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n # List to store non-zero elements\n non_zero = []\n # Counter for zero elements\n count_zeros = 0\n \n # Iterate through the list and separate non-zero and zero elements\n for num in nums:\n if num != 0:\n non_zero.append(num)\n else:\n count_zeros += 1\n \n # Append zero elements to the non-zero list\n non_zero.extend([0] * count_zeros)\n \n return non_zero", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n # Use list comprehensions to separate non-zero and zero elements\n non_zero = [num for num in nums if num != 0]\n zero = [num for num in nums if num == 0]\n \n # Concatenate non-zero and zero lists\n result = non_zero + zero\n return result", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n # Function to move all zeroes to the end of the list\n non_zero_index = 0 # Index for the position to insert the next non-zero element\n for i in range(len(nums)):\n if nums[i] != 0:\n nums[non_zero_index] = nums[i]\n non_zero_index += 1\n \n # Fill the remaining part of the list with zeroes\n for i in range(non_zero_index, len(nums)):\n nums[i] = 0\n \n return nums", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n # Function to move all zeroes to the end of the list\n non_zeros = [num for num in nums if num != 0]\n zeros = [num for num in nums if num == 0]\n return non_zeros + zeros", "matching_cluster_idx": 6}]}, "Mbpp/633": {"dps": 96.09756097560975, "dps_norm": 63.33333333333333, "pass@1": 29.0, "profiled": [{"solution": "def pair_xor_Sum(nums, n):\n \"\"\"\n Calculate the sum of XOR of all pairs of numbers in the given list.\n \n Parameters:\n nums (list): The list of integers.\n n (int): The number of elements in the list.\n \n Returns:\n int: The sum of XOR of all pairs.\n \"\"\"\n # Initialize the sum of XORs to 0\n sum_xor = 0\n \n # Calculate the sum of XORs for all pairs\n for i in range(n):\n if i < n:\n for j in range(i, n):\n sum_xor += nums[i] ^ nums[j]\n \n return sum_xor", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(nums, n):\n \"\"\"\n Calculate the sum of XOR of all pairs of numbers in the given list.\n \n :param nums: List of integers.\n :param n: Number of elements in nums.\n :return: Sum of XOR of all pairs in nums.\n \"\"\"\n # Initialize sum to 0\n sum = 0\n \n # Iterate through all pairs (i, j) where i < j\n for i in range(n):\n for j in range(i + 1, n):\n # Add the XOR of nums[i] and nums[j] to sum\n sum += nums[i] ^ nums[j]\n \n return sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(nums, n):\n \"\"\"\n Calculate the sum of xor of all pairs of numbers in the given list.\n \n :param nums: List of integers\n :param n: Number of elements in the list\n :return: Sum of xor of all pairs\n \"\"\"\n # Sum to store the final result\n sum_xor = 0\n \n # Calculate the sum of xor for all pairs\n for i in range(n):\n for j in range(i + 1, n):\n sum_xor += nums[i] ^ nums[j]\n \n return sum_xor", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(nums, n):\n \"\"\"\n Calculate the sum of xor of all pairs of numbers in the given list.\n \n :param nums: List of integers\n :param n: Number of elements in the list\n :return: Sum of xor of all pairs\n \"\"\"\n # Initialize the sum to 0\n sum_xor = 0\n \n # Iterate through each bit position (0 to 31)\n for bit in range(32):\n # Count numbers with the current bit set\n count_set_bit = 0\n for i in range(n):\n # Increment count if the current bit is set in the current number\n if nums[i] & (1 << bit):\n count_set_bit += 1\n # Calculate contributions of this bit position to the final sum\n sum_xor += (n - count_set_bit) * count_set_bit * (1 << bit)\n \n return sum_xor", "matching_cluster_idx": 4}, {"solution": "def pair_xor_Sum(nums, n):\n \"\"\"\n Calculate the sum of XOR of all pairs of numbers in the given list.\n \n :param nums: List of integers\n :param n: Number of elements in the list\n :return: Sum of XOR of all pairs of numbers\n \"\"\"\n # Sum of all XOR pairs can be calculated efficiently\n # by considering the contribution of each bit position\n xor_sum = 0\n for bit in range(32): # Maximum 32 bits for an integer\n count_set_bit = 0\n # Count numbers with the ith bit set\n for i in range(n):\n if nums[i] & (1 << bit):\n count_set_bit += 1\n # Contribution of this bit to the final XOR sum\n xor_sum += (n - count_set_bit) * count_set_bit * (1 << bit)\n return xor_sum", "matching_cluster_idx": 4}, {"solution": "def pair_xor_Sum(nums, n):\n \"\"\"\n Calculate the sum of xor of all pairs of numbers in the given list.\n \n :param nums: List of integers.\n :param n: Number of elements in the list.\n :return: Sum of xor of all pairs.\n \"\"\"\n # Initialize the sum\n total_xor_sum = 0\n \n # Iterate through each bit position (0 to 31, since the maximum integer is 10^9)\n for bit_position in range(32):\n # Count the number of elements with the current bit set\n bit_set_count = 0\n for i in range(n):\n if nums[i] & (1 << bit_position):\n bit_set_count += 1\n \n # Calculate the contribution of the current bit to the total xor sum\n # There are bit_set_count elements with the current bit set\n # There are n - bit_set_count elements without the current bit set\n # Each pair (set, not set) contributes 2^bit_position to the xor sum\n bit_contribution = (bit_set_count * (n - bit_set_count)) << bit_position\n total_xor_sum += bit_contribution\n \n return total_xor_sum", "matching_cluster_idx": 3}, {"solution": "def pair_xor_Sum(nums, n):\n \"\"\"\n Calculate the sum of XOR of all pairs of numbers in the given list.\n \n :param nums: List of integers\n :param n: Number of elements in the list\n :return: Sum of XOR of all pairs\n \"\"\"\n sum_xor = 0\n for i in range(32): # Iterate over each bit position\n count_bit_set = 0\n for j in range(n): # Count numbers with the i-th bit set\n if (nums[j] & (1 << i)):\n count_bit_set += 1\n # Sum of XOR is contributed by pairs with different bits at i-th position\n sum_xor += ((n - count_bit_set) * count_bit_set) * (1 << i)\n return sum_xor", "matching_cluster_idx": 4}, {"solution": "def pair_xor_Sum(nums, n):\n \"\"\"\n Calculate the sum of XOR of all pairs of numbers in the given list.\n \n :param nums: List of integers\n :param n: Number of elements in nums\n :return: Sum of XOR of all pairs of numbers\n \"\"\"\n # Calculate the sum of XOR for all pairs\n total_xor = 0\n for i in range(n):\n for j in range(i + 1, n):\n total_xor += nums[i] ^ nums[j]\n return total_xor", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(nums, n):\n \"\"\"\n Calculates the sum of XOR of all pairs of numbers in the given list.\n \n Parameters:\n nums (list): The list of integers.\n n (int): The length of the list.\n \n Returns:\n int: The sum of XOR of all pairs.\n \"\"\"\n # Initialize the sum to 0\n total_sum = 0\n \n # Iterate through each number in the list\n for i in range(n):\n # For each number, iterate through the rest of the list\n for j in range(i + 1, n):\n # Calculate the XOR of the current pair and add it to the total sum\n total_sum += nums[i] ^ nums[j]\n \n return total_sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(nums, n):\n \"\"\"\n Calculate the sum of xor of all pairs of numbers in the given list.\n \n Parameters:\n nums (list): The list of integers.\n n (int): The length of the list nums.\n \n Returns:\n int: The sum of xor of all pairs.\n \"\"\"\n # Initialize the sum of xor to 0\n xor_sum = 0\n \n # Calculate the sum of xor for all pairs\n for i in range(n):\n for j in range(i + 1, n):\n xor_sum += nums[i] ^ nums[j]\n \n return xor_sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(arr, n):\n \"\"\"\n Calculate the sum of xor of all pairs of numbers in the given list.\n \n :param arr: List of integers\n :param n: Number of elements in arr\n :return: Sum of xor of all pairs\n \"\"\"\n # Sum of XOR can be broken down using the count of set bits at each position\n result = 0\n for i in range(0, 32):\n # Counting the bits in the current position\n count = 0\n for j in range(0, n):\n if (arr[j] & (1 << i)):\n count += 1\n # Sum of combinations of pairs\n result += (n - count) * count * (1 << i)\n return result", "matching_cluster_idx": 4}, {"solution": "def pair_xor_Sum(nums, n):\n \"\"\"\n Calculate the sum of xor of all pairs of numbers in the given list.\n \n :param nums: List of integers.\n :param n: Number of elements in the list.\n :return: Sum of xor for all pairs.\n \"\"\"\n # Initialize the sum of xor values\n xor_sum = 0\n \n # Iterate through each number in the list\n for i in range(n):\n # XOR with all other numbers and add to the sum\n for j in range(i + 1, n):\n xor_sum += nums[i] ^ nums[j]\n \n return xor_sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(nums, n):\n \"\"\"\n Calculate the sum of XOR of all pairs of numbers in the given list.\n \n :param nums: List of integers.\n :param n: Number of elements in the list.\n :return: Sum of XOR of all pairs.\n \"\"\"\n sum_xor = 0\n for i in range(32): # Since integers can be at max 32 bit\n count = 0\n for j in range(n):\n if (nums[j] >> i) & 1: # Check if the i-th bit is set\n count += 1\n sum_xor += (count * (n - count) * (1 << i))\n return sum_xor", "matching_cluster_idx": 4}, {"solution": "def pair_xor_Sum(nums, n):\n \"\"\"\n Calculate the sum of XOR of all pairs of numbers in the given list.\n \n :param nums: List of integers.\n :param n: Length of the list nums.\n :return: Sum of XOR of all pairs of numbers in nums.\n \"\"\"\n # Calculate the sum of all elements as a starting point for the total XOR sum\n total_xor_sum = 0\n for i in range(32): # Iterate over each bit position\n count = 0\n for j in range(n):\n if nums[j] & (1 << i): # Check if the bit at position i is set in nums[j]\n count += 1\n # Each bit's contribution to the final XOR sum\n total_xor_sum += (count * (n - count) * (1 << i))\n \n return total_xor_sum", "matching_cluster_idx": 4}, {"solution": "def pair_xor_Sum(arr, n):\n \"\"\"\n Calculate the sum of XOR of all pairs of numbers in the given list.\n \n :param arr: List of integers\n :param n: Number of elements in arr\n :return: Sum of XOR of all pairs\n \"\"\"\n # Sum to store the final result\n sum_xor = 0\n \n # Iterate through each bit position from 0 to 31 (assuming 32-bit integers)\n for i in range(32):\n # Count of elements having ith bit set\n count = 0\n \n # Iterate through each element in arr to check if ith bit is set\n for j in range(n):\n if (arr[j] & (1 << i)) != 0:\n count += 1\n \n # Calculate contribution of current bit to total XOR sum\n sum_bit = count * (n - count) * (1 << i)\n \n # Add the contribution of current bit to the final sum\n sum_xor += sum_bit\n \n return sum_xor", "matching_cluster_idx": 3}, {"solution": "def pair_xor_Sum(nums, n):\n \"\"\"\n Calculate the sum of XOR of all pairs of numbers in the given list.\n \n :param nums: List of integers\n :param n: Length of the list\n :return: Sum of XOR of all pairs\n \"\"\"\n # Calculate the sum of XOR for all pairs\n sum_xor = 0\n for i in range(n):\n for j in range(i + 1, n):\n sum_xor += nums[i] ^ nums[j]\n return sum_xor", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(arr, n):\n \"\"\"\n Calculate the sum of xor of all pairs of numbers in the given list.\n \n :param arr: List of integers\n :param n: Length of the list arr\n :return: Sum of xor of all pairs\n \"\"\"\n # Initialize sum to store the result\n sum = 0\n \n # Iterate through each element in the array\n for i in range(n):\n # For each element, iterate through the subsequent elements\n for j in range(i + 1, n):\n # Add the XOR of the pair to the sum\n sum += arr[i] ^ arr[j]\n \n return sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(nums, n):\n \"\"\"\n Calculate the sum of xor of all pairs of numbers in the given list.\n \n :param nums: List of integers\n :param n: Number of elements in nums\n :return: Sum of xor of all pairs in nums\n \"\"\"\n # Initialize sum to 0\n sum = 0\n \n # Iterate through each number in the list\n for i in range(n):\n # XOR current number with all subsequent numbers and add to sum\n for j in range(i + 1, n):\n sum += nums[i] ^ nums[j]\n \n return sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(nums, n):\n \"\"\"\n Calculates the sum of XOR of all pairs of numbers in the given list.\n \n Parameters:\n nums (list): The list of integers.\n n (int): The size of the list, which is assumed to be equal to the length of nums.\n \n Returns:\n int: The sum of XOR of all pairs in the list.\n \"\"\"\n # Calculate the sum of XOR for all pairs\n sum_xor = 0\n for i in range(n):\n for j in range(i + 1, n):\n sum_xor += nums[i] ^ nums[j]\n return sum_xor", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(nums, n):\n \"\"\"\n Calculate the sum of XOR of all pairs of numbers in the given list.\n \n :param nums: List of integers.\n :param n: Number of elements in the list.\n :return: Sum of XOR of all pairs.\n \"\"\"\n sum_xor = 0\n for i in range(32): # Iterate through each bit position\n count_bit_set = 0\n for j in range(n): # Count how many numbers have the i-th bit set\n if nums[j] & (1 << i):\n count_bit_set += 1\n sum_xor += (n - count_bit_set) * count_bit_set * (1 << i)\n return sum_xor", "matching_cluster_idx": 4}]}, "Mbpp/644": {"dps": 36.75531914893617, "dps_norm": 59.333333333333336, "pass@1": 68.0, "profiled": [{"solution": "def reverse_Array_Upto_K(nums, k):\n # Reverse the elements from the start of the list up to index k-1\n left, right = 0, k - 1\n while left < right:\n nums[left], nums[right] = nums[right], nums[left]\n left += 1\n right -= 1\n return nums", "matching_cluster_idx": 6}, {"solution": "def reverse_Array_Upto_K(arr, k):\n # Ensure k is within bounds and is positive\n k = min(k, len(arr))\n \n # Reverse the part of the array up to index k\n for i in range(k // 2):\n arr[i], arr[k - i - 1] = arr[k - i - 1], arr[i]\n \n return arr", "matching_cluster_idx": 6}, {"solution": "def reverse_Array_Upto_K(arr, k):\n # Reverse elements from the start up to but not including the k-th element\n start = 0\n k -= 1 # Adjust k to be a zero-based index\n while start < k:\n # Swap the elements\n arr[start], arr[k] = arr[k], arr[start]\n start += 1\n k -= 1\n return arr", "matching_cluster_idx": 7}, {"solution": "def reverse_Array_Upto_K(arr, k):\n # Reverse elements from start to k (exclusive)\n arr[:k] = arr[:k][::-1]\n return arr", "matching_cluster_idx": 13}, {"solution": "def reverse_Array_Upto_K(arr, k):\n # Reverse the elements in the array up to the given position k\n left, right = 0, min(k - 1, len(arr) - 1) # Ensure k is within array bounds\n while left < right:\n arr[left], arr[right] = arr[right], arr[left]\n left += 1\n right -= 1\n return arr", "matching_cluster_idx": 7}, {"solution": "def reverse_Array_Upto_K(arr, k):\n # Ensure k is within the valid range\n k = min(k, len(arr))\n \n # Reverse the first k elements of the array\n for i in range(k // 2):\n arr[i], arr[k - i - 1] = arr[k - i - 1], arr[i]\n \n return arr", "matching_cluster_idx": 6}, {"solution": "def reverse_Array_Upto_K(arr, k):\n # Reverse elements from start to the given position k (exclusive)\n start = 0\n end = k - 1\n \n while start < end:\n # Swap the elements at start and end\n arr[start], arr[end] = arr[end], arr[start]\n \n # Move towards the middle of the array\n start += 1\n end -= 1\n \n return arr", "matching_cluster_idx": 7}, {"solution": "def reverse_Array_Upto_K(arr, k):\n # Convert k to 0-based index\n k -= 1\n \n # Reverse elements from start to k (inclusive)\n start, end = 0, k\n while start < end:\n # Swap elements at start and end\n arr[start], arr[end] = arr[end], arr[start]\n start += 1\n end -= 1\n \n return arr", "matching_cluster_idx": 7}, {"solution": "def reverse_Array_Upto_K(arr, k):\n # Convert the index to 0-based\n k -= 1\n \n # Ensure k is within the bounds of the array\n if k >= 0:\n # Reverse elements from the start up to k (inclusive)\n start = 0\n while start < k:\n arr[start], arr[k] = arr[k], arr[start]\n start += 1\n k -= 1\n \n return arr", "matching_cluster_idx": 7}, {"solution": "def reverse_Array_Upto_K(arr, k):\n # Ensure k is within the valid range and adjusted for zero-based indexing\n k = min(k - 1, len(arr) - 1)\n \n # Reverse elements from the start up to k (inclusive)\n start, end = 0, k\n while start < end:\n arr[start], arr[end] = arr[end], arr[start]\n start += 1\n end -= 1\n \n return arr", "matching_cluster_idx": 7}, {"solution": "def reverse_Array_Upto_K(arr, k):\n # Reverse elements from the start to the given position k\n for i in range(k // 2):\n # Swap elements at positions i and k-i-1\n arr[i], arr[k - i - 1] = arr[k - i - 1], arr[i]\n return arr", "matching_cluster_idx": 6}, {"solution": "def reverse_Array_Upto_K(arr, k):\n # Convert k to 0-based index\n k = k - 1\n \n # Reverse elements from start to k (inclusive)\n start = 0\n while start < k:\n arr[start], arr[k] = arr[k], arr[start]\n start += 1\n k -= 1\n \n return arr", "matching_cluster_idx": 7}, {"solution": "def reverse_Array_Upto_K(arr, k):\n # Reverse the first k elements of the array\n arr[:k] = arr[:k][::-1]\n return arr", "matching_cluster_idx": 13}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n Reverse elements of the array up to a given position k (exclusive) and return the modified array.\n \n :param arr: List of integers representing the input array\n :param k: Integer representing the position up to which the array should be reversed (exclusive)\n :return: List of integers with the first k elements reversed and the rest unchanged\n \"\"\"\n # Ensure k does not exceed the array length\n k = min(k, len(arr))\n \n # Reverse elements from the start to k\n start, end = 0, k - 1\n while start < end:\n arr[start], arr[end] = arr[end], arr[start]\n start += 1\n end -= 1\n \n return arr", "matching_cluster_idx": 7}, {"solution": "def reverse_Array_Upto_K(arr, k):\n # Ensure the given position k is within the array bounds\n k = min(k, len(arr))\n \n # Reverse elements from the start up to position k\n arr[:k] = arr[:k][::-1]\n \n # Return the modified array\n return arr", "matching_cluster_idx": 13}, {"solution": "def reverse_Array_Upto_K(arr, k):\n # Reverse the elements from the start of the array to the given position k (exclusive)\n start = 0\n end = k - 1\n \n # Swap elements to reverse the array up to position k\n while start < end:\n arr[start], arr[end] = arr[end], arr[start]\n start += 1\n end -= 1\n \n return arr", "matching_cluster_idx": 7}, {"solution": "def reverse_Array_Upto_K(arr, k):\n # Reverse the first k+1 elements of the array\n arr[:k] = arr[:k][::-1]\n return arr", "matching_cluster_idx": 13}, {"solution": "def reverse_Array_Upto_K(arr, k):\n # Reverse elements from start to k (exclusive)\n for i in range(k // 2):\n # Swap elements symmetrically around the center of the k elements\n arr[i], arr[k - 1 - i] = arr[k - 1 - i], arr[i]\n return arr", "matching_cluster_idx": 6}, {"solution": "def reverse_Array_Upto_K(arr, k):\n # Reverse the elements of the array up to the given position k\n start = 0\n end = k - 1\n \n while start < end:\n # Swap elements at start and end positions\n arr[start], arr[end] = arr[end], arr[start]\n start += 1\n end -= 1\n \n return arr", "matching_cluster_idx": 7}, {"solution": "def reverse_Array_Upto_K(arr, k):\n # Helper function to reverse elements in the array from start to k\n def reverse(start, end):\n while start < end:\n arr[start], arr[end] = arr[end], arr[start]\n start, end = start + 1, end - 1\n \n # Reversing elements up to position k (0-indexed, hence k-1)\n reverse(0, k - 1)\n return arr", "matching_cluster_idx": 6}]}, "Mbpp/720": {"dps": 50.76923076923077, "dps_norm": 84.0, "pass@1": 100.0, "profiled": [{"solution": "def add_dict_to_tuple(input_tuple, input_dict):\n \"\"\"Add a dictionary to the tuple, the output should be a tuple.\"\"\"\n # Convert the tuple to a list, add the dictionary to it, then convert back to a tuple\n updated_list = list(input_tuple)\n updated_list.append(input_dict)\n return tuple(updated_list)", "matching_cluster_idx": 3}, {"solution": "def add_dict_to_tuple(test_tup, test_dict):\n \"\"\"\n Adds a dictionary to the tuple and returns the updated tuple.\n \n Parameters:\n test_tup (tuple): The original tuple to be updated.\n test_dict (dict): The dictionary to be added to the tuple.\n \n Returns:\n tuple: The updated tuple with the dictionary added to the end.\n \"\"\"\n # Convert the tuple to a list to allow modifications\n temp_list = list(test_tup)\n \n # Append the dictionary to the list\n temp_list.append(test_dict)\n \n # Convert the list back to a tuple and return it\n return tuple(temp_list)", "matching_cluster_idx": 3}, {"solution": "def add_dict_to_tuple(tup, dictionary):\n \"\"\"Add a dictionary to a tuple and return as a new tuple.\"\"\"\n # Convert the tuple to a list to facilitate modifications\n tup = list(tup)\n # Append the dictionary to the list\n tup.append(dictionary)\n # Convert the list back to a tuple and return\n return tuple(tup)", "matching_cluster_idx": 3}, {"solution": "def add_dict_to_tuple(tup, dictionary):\n \"\"\"\n Adds a dictionary to the given tuple and returns a new tuple.\n \n :param tup: The original tuple to which the dictionary will be added.\n :param dictionary: The dictionary to add to the tuple.\n :return: A new tuple containing all the elements of the original tuple and the dictionary.\n \"\"\"\n # Convert the tuple to a list to allow the addition of the dictionary\n tup = list(tup)\n # Append the dictionary to the list\n tup.append(dictionary)\n # Convert the list back to a tuple\n return tuple(tup)", "matching_cluster_idx": 3}, {"solution": "def add_dict_to_tuple(t, d):\n \"\"\"\n Adds a dictionary to a tuple and returns a new tuple with the dictionary included.\n \n :param t: The original tuple\n :param d: The dictionary to be added to the tuple\n :return: A new tuple with the dictionary added\n \"\"\"\n # Convert the tuple to a list, append the dictionary, then convert back to a tuple\n t = list(t)\n t.append(d)\n return tuple(t)", "matching_cluster_idx": 3}, {"solution": "def add_dict_to_tuple(test_t, test_dict):\n \"\"\"\n Add a dictionary to a tuple and return a new tuple with the dictionary included.\n \n :param test_t: Tuple to which the dictionary needs to be added.\n :param test_dict: Dictionary to add to the tuple.\n :return: A new tuple with the dictionary included.\n \"\"\"\n # Convert the tuple to a list, add the dictionary, and convert back to a tuple\n new_tuple = test_t + (test_dict,)\n return new_tuple", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(input_tuple, input_dict):\n \"\"\"Add a dictionary to the tuple and return the new tuple.\n \n :param input_tuple: The initial tuple.\n :param input_dict: The dictionary to be added.\n :return: A new tuple with the dictionary added as the last element.\n \"\"\"\n # Convert the tuple to a list to allow modification\n input_tuple_list = list(input_tuple)\n # Append the dictionary to the list\n input_tuple_list.append(input_dict)\n # Convert the list back to a tuple\n return tuple(input_tuple_list)", "matching_cluster_idx": 3}, {"solution": "def add_dict_to_tuple(tup, dictionary):\n \"\"\"\n Add a dictionary to the tuple. The output should be a tuple.\n \n Parameters:\n tup (tuple): The original tuple.\n dictionary (dict): The dictionary to be added.\n \n Returns:\n tuple: The new tuple with the dictionary added as its last element.\n \"\"\"\n # Convert the tuple to a list, add the dictionary, and convert back to a tuple\n tup = list(tup)\n tup.append(dictionary)\n return tuple(tup)", "matching_cluster_idx": 3}, {"solution": "def add_dict_to_tuple(test_tup, test_dict):\n \"\"\"\n Adds a dictionary to a tuple and returns a new tuple with the dictionary included.\n \n Parameters:\n test_tup (tuple): The original tuple to which the dictionary will be added.\n test_dict (dict): The dictionary to be added to the tuple.\n \n Returns:\n tuple: A new tuple containing all elements from the original tuple and the dictionary.\n \"\"\"\n # Adding the dictionary to the tuple and converting list back to tuple\n res = test_tup + (test_dict, )\n return res", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(tup, dictionary):\n \"\"\"\n Adds a dictionary to a tuple and returns a new tuple containing all the elements.\n \n :param tup: The original tuple\n :param dictionary: The dictionary to be added\n :return: A new tuple with all the original elements and the dictionary added to it\n \"\"\"\n # Convert the tuple to a list to allow modifications\n modified_list = list(tup)\n # Append the dictionary to the list\n modified_list.append(dictionary)\n # Convert the list back to a tuple\n result_tuple = tuple(modified_list)\n return result_tuple", "matching_cluster_idx": 3}, {"solution": "def add_dict_to_tuple(input_tuple, input_dict):\n \"\"\"Add a dictionary to the tuple and return the new tuple\"\"\"\n # Convert the tuple to a list, add the dictionary, then convert back to a tuple\n new_list = list(input_tuple)\n new_list.append(input_dict)\n return tuple(new_list)", "matching_cluster_idx": 3}, {"solution": "def add_dict_to_tuple(t, d):\n \"\"\"\n Adds a dictionary to a tuple and returns a new tuple that includes the dictionary.\n\n Parameters:\n t (tuple): The original tuple.\n d (dict): The dictionary to be added.\n\n Returns:\n tuple: The extended tuple containing the original elements and the dictionary.\n \"\"\"\n # Convert the tuple to a list to allow modification\n t_list = list(t)\n # Append the dictionary to the list\n t_list.append(d)\n # Convert the list back to a tuple\n return tuple(t_list)", "matching_cluster_idx": 3}, {"solution": "def add_dict_to_tuple(tup, dictionary):\n \"\"\"\n Adds a dictionary to the tuple and returns the updated tuple.\n \n Parameters:\n - tup: The original tuple.\n - dictionary: The dictionary to be added to the tuple.\n \n Returns:\n A tuple with the dictionary added to it.\n \"\"\"\n return tup + (dictionary,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(input_tuple, dictionary):\n \"\"\"\n Adds a dictionary to a tuple and returns the updated tuple.\n \n :param input_tuple: Tuple to which the dictionary will be added.\n :param dictionary: Dictionary to be added to the tuple.\n :return: Updated tuple containing all elements from the original tuple and the dictionary as the last element.\n \"\"\"\n # Convert the tuple to a list to allow modification\n input_list = list(input_tuple)\n \n # Add the dictionary to the list\n input_list.append(dictionary)\n \n # Convert the list back to a tuple and return\n return tuple(input_list)", "matching_cluster_idx": 3}, {"solution": "def add_dict_to_tuple(test_tup, test_dict):\n \"\"\"\n Adds a dictionary to a tuple and returns a new tuple with the dictionary included.\n \n Parameters:\n test_tup (tuple): The input tuple.\n test_dict (dict): The dictionary to be added to the tuple.\n \n Returns:\n tuple: A new tuple containing the original tuple elements followed by the dictionary.\n \"\"\"\n # Convert the tuple to a list to allow for easier modification\n list_tup = list(test_tup)\n \n # Append the dictionary to the list\n list_tup.append(test_dict)\n \n # Convert the list back to a tuple\n result_tup = tuple(list_tup)\n \n return result_tup", "matching_cluster_idx": 3}, {"solution": "def add_dict_to_tuple(tup, dictionary):\n \"\"\"\n Adds a dictionary to the tuple and returns a new tuple.\n \"\"\"\n # Convert the tuple to a list to allow modifications\n modified_list = list(tup)\n \n # Append the dictionary to the list\n modified_list.append(dictionary)\n \n # Convert the list back to a tuple and return\n return tuple(modified_list)", "matching_cluster_idx": 3}, {"solution": "def add_dict_to_tuple(test_tup, test_dict):\n \"\"\"\n Adds a dictionary to the given tuple and returns a new tuple with the dictionary appended.\n \n :param test_tup: Tuple to which the dictionary will be added.\n :param test_dict: Dictionary to add to the tuple.\n :return: A new tuple with the dictionary appended.\n \"\"\"\n # Convert tuple to list, append dictionary, then convert back to tuple\n result = test_tup + (test_dict,)\n return result", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(input_tuple, input_dict):\n \"\"\"Adds a dictionary to a tuple and returns the resulting tuple.\"\"\"\n # Convert the tuple to a list, add the dictionary to the list, then convert back to a tuple\n modified_list = list(input_tuple)\n modified_list.append(input_dict)\n result_tuple = tuple(modified_list)\n return result_tuple", "matching_cluster_idx": 3}, {"solution": "def add_dict_to_tuple(tup, my_dict):\n \"\"\"\n This function takes a tuple and a dictionary as arguments and returns a new tuple\n with the dictionary appended to the original tuple.\n \"\"\"\n # Convert the tuple to a list, append the dictionary, then convert back to a tuple\n new_tup = list(tup)\n new_tup.append(my_dict)\n return tuple(new_tup)", "matching_cluster_idx": 3}, {"solution": "def add_dict_to_tuple(input_tuple, input_dict):\n \"\"\"Adds a dictionary to a tuple and returns the new tuple.\n \n :param input_tuple: The original tuple to add the dictionary to.\n :param input_dict: The dictionary to be added to the tuple.\n :return: A new tuple with the dictionary included.\n \"\"\"\n # Convert the tuple to a list to allow modification\n input_list = list(input_tuple)\n # Append the dictionary to the list\n input_list.append(input_dict)\n # Convert the list back to a tuple and return it\n return tuple(input_list)", "matching_cluster_idx": 3}]}, "Mbpp/725": {"dps": 73.22404371584699, "dps_norm": 75.0, "pass@1": 100.0, "profiled": [{"solution": "import re\nfrom typing import List\ndef extract_quotation(s: str) -> List[str]:\n \"\"\"\n Extract values between quotation marks \" \" from the given string.\n \n Parameters:\n s (str): The input string containing values within quotation marks.\n \n Returns:\n List[str]: A list of values found between quotation marks.\n \"\"\"\n return re.findall(r'\"(.*?)\"', s)", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(text):\n # Use regular expression to find all substrings enclosed in double quotes\n return re.findall(r'\"(.*?)\"', text)", "matching_cluster_idx": 5}, {"solution": "import re\nfrom typing import List\ndef extract_quotation(text: str) -> List[str]:\n \"\"\"\n Extracts and returns values between quotation marks \" \" from the given string.\n \n Args:\n text (str): The input string containing values within quotation marks.\n \n Returns:\n List[str]: A list of values that were found within quotation marks.\n \"\"\"\n # Using regular expression to find all occurrences of text within quotation marks\n return re.findall(r'\"(.*?)\"', text)", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(s):\n # Use regex to find all substrings enclosed in double quotes\n return re.findall(r'\"(.*?)\"', s)", "matching_cluster_idx": 5}, {"solution": "import re\nfrom typing import List\ndef extract_quotation(input_string: str) -> List[str]:\n # Use regex to find all substrings enclosed in double quotes\n return re.findall(r'\"(.*?)\"', input_string)", "matching_cluster_idx": 5}, {"solution": "import re\nfrom typing import List\ndef extract_quotation(s: str) -> List[str]:\n \"\"\"\n Extracts values between quotation marks \" \" from the given string.\n \n Parameters:\n s (str): The input string from which to extract quoted values.\n \n Returns:\n List[str]: A list of strings extracted from between quotation marks.\n \"\"\"\n # Use regular expression to find all occurrences of text within quotation marks\n return re.findall(r'\"(.*?)\"', s)", "matching_cluster_idx": 5}, {"solution": "import re\nfrom typing import List\ndef extract_quotation(s: str) -> List[str]:\n \"\"\"\n Extracts values between quotation marks \" \" from the given string.\n \n Parameters:\n s (str): The input string containing quoted values.\n \n Returns:\n List[str]: A list of strings containing the values found between quotation marks.\n \"\"\"\n # Use regular expression to find all substrings within double quotes\n return re.findall(r'\"(.*?)\"', s)", "matching_cluster_idx": 5}, {"solution": "import re\nfrom typing import List\ndef extract_quotation(text: str) -> List[str]:\n \"\"\"\n Extracts values between quotation marks \" \" from the given string.\n \n Parameters:\n text (str): The input string containing values enclosed in quotation marks.\n \n Returns:\n List[str]: A list of values that are enclosed in quotation marks.\n \"\"\"\n # Use regex to find all occurrences of text within quotation marks\n return re.findall(r'\"(.*?)\"', text)", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(text):\n # Use regular expression to find all substrings enclosed in double quotes\n return re.findall(r'\"(.*?)\"', text)", "matching_cluster_idx": 5}, {"solution": "import re\nfrom typing import List\ndef extract_quotation(s: str) -> List[str]:\n \"\"\"\n Extracts values between quotation marks \" \" from the given string.\n \n Parameters:\n s (str): The input string from which values enclosed in quotation marks are to be extracted.\n \n Returns:\n List[str]: A list of values extracted between quotation marks.\n \"\"\"\n # Regular expression to match text between double quotes\n matches = re.findall(r'\"(.*?)\"', s)\n return matches", "matching_cluster_idx": 5}, {"solution": "import re\nfrom typing import List\ndef extract_quotation(text: str) -> List[str]:\n # Use regex to find all substrings enclosed in double quotes\n return re.findall(r'\"(.*?)\"', text)", "matching_cluster_idx": 5}, {"solution": "import re\nfrom typing import List\ndef extract_quotation(text: str) -> List[str]:\n \"\"\"\n Extracts values between quotation marks in the given string.\n \n Args:\n text (str): The input string containing values within quotation marks.\n \n Returns:\n List[str]: A list of strings extracted from between quotation marks.\n \"\"\"\n return re.findall(r'\"(.*?)\"', text)", "matching_cluster_idx": 5}, {"solution": "import re\nfrom typing import List\ndef extract_quotation(input_string: str) -> List[str]:\n # Using regular expression to find all substrings enclosed in double quotes\n return re.findall(r'\"(.*?)\"', input_string)", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(s):\n # Use regular expression to find all substrings enclosed in double quotes\n return re.findall(r'\"(.*?)\"', s)", "matching_cluster_idx": 5}, {"solution": "import re\nfrom typing import List\ndef extract_quotation(s: str) -> List[str]:\n # Use regular expression to find all substrings enclosed in double quotes\n return re.findall(r'\"(.*?)\"', s)", "matching_cluster_idx": 5}, {"solution": "import re\nfrom typing import List\ndef extract_quotation(text: str) -> List[str]:\n \"\"\"\n Extracts all substrings enclosed in double quotes from the given string.\n \n Args:\n text (str): The string to extract substrings from.\n \n Returns:\n List[str]: A list of substrings found within double quotes.\n \"\"\"\n # Using regular expression to find all substrings enclosed in double quotes\n return re.findall(r'\"(.*?)\"', text)", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(s):\n # Use regular expression to find all substrings enclosed in double quotes\n return re.findall(r'\"(.*?)\"', s)", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(text):\n # Use regular expression to find all substrings enclosed in double quotes\n return re.findall(r'\"(.*?)\"', text)", "matching_cluster_idx": 5}, {"solution": "import re\nfrom typing import List\ndef extract_quotation(text: str) -> List[str]:\n # Use regular expression to find all substrings enclosed in double quotes\n return re.findall(r'\"(.*?)\"', text)", "matching_cluster_idx": 5}, {"solution": "import re\nfrom typing import List\ndef extract_quotation(s: str) -> List[str]:\n \"\"\"\n Extracts values between quotation marks \" \" in the given string.\n \n Args:\n s (str): The input string containing values between quotation marks.\n \n Returns:\n List[str]: A list containing the values found between quotation marks.\n \"\"\"\n return re.findall(r'\"(.*?)\"', s)", "matching_cluster_idx": 5}]}, "Mbpp/732": {"dps": 50.71705426356589, "dps_norm": 70.5, "pass@1": 64.0, "profiled": [{"solution": "import re\ndef replace_specialchar(s):\n # Use re.sub() to replace all occurrences of spaces, commas, or dots with a colon\n return re.sub(r'[ ,.]', ':', s)", "matching_cluster_idx": 4}, {"solution": "def replace_specialchar(s):\n # Replace spaces, commas, and dots with a colon\n return s.replace(' ', ':').replace(',', ':').replace('.', ':')", "matching_cluster_idx": 9}, {"solution": "import re\ndef replace_specialchar(s):\n # Replace spaces, commas, and dots with colons\n return re.sub(r'[ ,.]', ':', s)", "matching_cluster_idx": 4}, {"solution": "def replace_specialchar(s):\n # Replace spaces, commas, and dots with a colon\n for char in [' ', ',', '.']:\n s = s.replace(char, ':')\n return s", "matching_cluster_idx": 9}, {"solution": "import re\ndef replace_specialchar(s):\n # Use regular expression to replace spaces, commas, or dots with a colon\n return re.sub(r'[ ,.]', ':', s)", "matching_cluster_idx": 4}, {"solution": "def replace_specialchar(s):\n import re\n \n # Replace spaces, commas, and dots with colons\n result = re.sub(r'[ ,.]', ':', s)\n return result", "matching_cluster_idx": 4}, {"solution": "import re\ndef replace_specialchar(s):\n # Using regular expression to replace spaces, commas, or dots with a colon\n result = re.sub(r'[ ,.]', ':', s)\n return result", "matching_cluster_idx": 4}, {"solution": "import re\ndef replace_specialchar(s):\n # Replace spaces, commas, and dots with a colon\n result = re.sub(r'[ ,.]', ':', s)\n return result", "matching_cluster_idx": 4}, {"solution": "def replace_specialchar(s):\n # Replace spaces, commas, and dots with a colon\n return s.replace(' ', ':').replace(',', ':').replace('.', ':')", "matching_cluster_idx": 9}, {"solution": "import re\ndef replace_specialchar(text):\n # Use regex to replace spaces, commas, and dots with a colon\n return re.sub(r'[ ,.]', ':', text)", "matching_cluster_idx": 4}, {"solution": "def replace_specialchar(s):\n # Replace spaces, commas, or dots with a colon\n return ':'.join(s.split(' ')).replace(',',':').replace('.',':')", "matching_cluster_idx": 7}, {"solution": "def replace_specialchar(s):\n # Replace spaces, commas, and dots with a colon\n return s.replace(' ', ':').replace(',', ':').replace('.', ':')", "matching_cluster_idx": 9}, {"solution": "import re\ndef replace_specialchar(s):\n # Use regular expression to replace all occurrences of spaces, commas, or dots with a colon\n return re.sub('[ ,.]', ':', s)", "matching_cluster_idx": 4}, {"solution": "import re\ndef replace_specialchar(s):\n # Use regular expression to replace spaces, commas, or dots with a colon\n return re.sub(r'[ ,.]', ':', s)", "matching_cluster_idx": 4}, {"solution": "def replace_specialchar(s):\n # Replace spaces, commas, and dots with colons\n result = s.replace(' ', ':').replace(',', ':').replace('.', ':')\n return result", "matching_cluster_idx": 9}, {"solution": "import re\ndef replace_specialchar(s):\n # Replace all occurrences of spaces, commas, or dots with a colon\n return re.sub(r'[ ,.]', ':', s)", "matching_cluster_idx": 4}, {"solution": "import re\ndef replace_specialchar(s):\n # Using regular expression to replace spaces, commas, or dots with a colon\n return re.sub(r'[ ,.]', ':', s)", "matching_cluster_idx": 4}, {"solution": "def replace_specialchar(s):\n # Replace spaces, commas, and dots with a colon\n return s.replace(' ', ':').replace(',', ':').replace('.', ':')", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(s):\n # Replace spaces, commas, and dots with colons\n for char in [' ', ',', '.']:\n s = s.replace(char, ':')\n return s", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(s):\n # Replace spaces, commas, and dots with a colon\n return ':'.join(s.split(' ')).replace(',',':').replace('.',':')", "matching_cluster_idx": 7}]}, "Mbpp/740": {"dps": 91.96363636363637, "dps_norm": 84.44444444444444, "pass@1": 100.0, "profiled": [{"solution": "def tuple_to_dict(tup):\n \"\"\"\n Convert the given tuple to a key-value dictionary using adjacent elements.\n \n Parameters:\n - tup: A tuple of elements.\n \n Returns:\n A dictionary where each key-value pair consists of adjacent elements from the tuple.\n \"\"\"\n # Initialize an empty dictionary to store the key-value pairs\n result_dict = {}\n \n # Ensure the tuple has an even number of elements by trimming the last element if necessary\n if len(tup) % 2 != 0:\n tup = tup[:-1]\n \n # Iterate over the tuple in steps of 2 to create key-value pairs\n for i in range(0, len(tup), 2):\n key = tup[i]\n value = tup[i+1]\n result_dict[key] = value\n \n return result_dict", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(input_tuple):\n \"\"\"\n Converts a given tuple to a key-value dictionary using adjacent elements.\n \n Parameters:\n input_tuple (tuple): The input tuple from which to create a dictionary.\n \n Returns:\n dict: A dictionary created from adjacent elements of the input tuple.\n \"\"\"\n # Ensure the tuple has an even number of elements for key-value pairing\n if len(input_tuple) % 2 != 0:\n input_tuple = input_tuple[:-1] # Remove the last element if odd-length\n \n # Create the dictionary by pairing elements\n result_dict = dict(zip(input_tuple[::2], input_tuple[1::2]))\n return result_dict", "matching_cluster_idx": 8}, {"solution": "def tuple_to_dict(test_tup):\n # Use zip to pair up elements from the tuple and convert the result to a dictionary\n res = dict(zip(test_tup[::2], test_tup[1::2]))\n return res", "matching_cluster_idx": 8}, {"solution": "def tuple_to_dict(tup):\n # Use dictionary comprehension to iterate over the tuple in steps of 2\n return {tup[i]: tup[i + 1] for i in range(0, len(tup) - 1, 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(input_tuple):\n # Create a dictionary by pairing every two consecutive elements\n return dict(zip(input_tuple[::2], input_tuple[1::2]))", "matching_cluster_idx": 8}, {"solution": "def tuple_to_dict(tup):\n \"\"\"\n Converts the given tuple to a key-value dictionary using adjacent elements.\n \n Parameters:\n - tup: The tuple from which to create the dictionary.\n \n Returns:\n - A dictionary where each key is an element from the tuple and the next element is its value.\n \"\"\"\n # Ensure the tuple has at least two elements to form a key-value pair\n if len(tup) < 2:\n return {}\n \n # Create dictionary by pairing adjacent elements\n return dict(zip(tup[::2], tup[1::2]))", "matching_cluster_idx": 8}, {"solution": "def tuple_to_dict(t):\n # Use zip to pair up every two elements and convert to dict\n return dict(zip(t[::2], t[1::2]))", "matching_cluster_idx": 8}, {"solution": "def tuple_to_dict(input_tuple):\n # Create a dictionary by zipping every two elements in the tuple\n return dict(zip(input_tuple[::2], input_tuple[1::2]))", "matching_cluster_idx": 8}, {"solution": "def tuple_to_dict(tup):\n # Initialize an empty dictionary to store the key-value pairs\n result_dict = {}\n \n # Iterate through the tuple, stepping by 2 to ensure adjacent elements are used\n for i in range(0, len(tup) - 1, 2):\n # Use the first element as the key and the second as the value\n result_dict[tup[i]] = tup[i + 1]\n \n return result_dict", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(tup):\n # Initialize an empty dictionary to store the result\n result_dict = {}\n \n # Iterate through the tuple, stepping by 2 to pair elements\n for i in range(0, len(tup) - 1, 2):\n # Add each pair to the dictionary\n result_dict[tup[i]] = tup[i + 1]\n \n # Handle the case where the tuple has an odd number of elements\n if len(tup) % 2 != 0:\n result_dict[tup[-1]] = None # Or handle as needed for odd length tuples\n \n return result_dict", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(tup):\n \"\"\"\n Converts a tuple into a dictionary with adjacent elements as key-value pairs.\n \n Parameters:\n - tup: A tuple of elements.\n \n Returns:\n - A dictionary where each key-value pair is formed from adjacent elements in the tuple.\n \"\"\"\n # Initialize an empty dictionary to store key-value pairs\n result_dict = {}\n \n # Ensure the length of the tuple is even to form key-value pairs\n if len(tup) % 2 != 0:\n tup = tup[:-1] # Trim the last element if necessary\n \n # Iterate over the tuple with steps of 2 to form key-value pairs\n for i in range(0, len(tup), 2):\n key = tup[i]\n value = tup[i+1]\n result_dict[key] = value\n \n return result_dict", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(tup):\n \"\"\"\n Converts a given tuple to a key-value dictionary using adjacent elements.\n \n Parameters:\n tup (tuple): A tuple with an even number of elements.\n \n Returns:\n dict: A dictionary with keys and values from adjacent elements of the tuple.\n \"\"\"\n # Initialize an empty dictionary to store the key-value pairs\n result_dict = {}\n \n # Ensure the tuple has an even number of elements\n if len(tup) % 2 != 0:\n raise ValueError(\"Tuple must contain an even number of elements.\")\n \n # Iterate through the tuple and populate the dictionary\n for i in range(0, len(tup), 2):\n key = tup[i]\n value = tup[i + 1]\n result_dict[key] = value\n \n return result_dict", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(tup):\n \"\"\"\n Converts a given tuple to a key-value dictionary using adjacent elements.\n \n Parameters:\n tup (tuple): The input tuple with an even number of elements.\n \n Returns:\n dict: A dictionary where each key-value pair comes from adjacent elements in the tuple.\n \"\"\"\n # Ensure the tuple has an even number of elements\n if len(tup) % 2 != 0:\n raise ValueError(\"The input tuple must contain an even number of elements.\")\n \n # Convert the tuple to a dictionary using a dictionary comprehension\n return {tup[i]: tup[i + 1] for i in range(0, len(tup), 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(input_tuple):\n # Create a dictionary from consecutive pairs in the tuple\n result_dict = dict(zip(input_tuple[::2], input_tuple[1::2]))\n return result_dict", "matching_cluster_idx": 8}, {"solution": "def tuple_to_dict(input_tuple):\n # Initialize an empty dictionary to store the key-value pairs\n result_dict = {}\n \n # Loop through the tuple in steps of 2 to create key-value pairs\n for i in range(0, len(input_tuple) - 1, 2):\n # Add key-value pairs to the dictionary\n result_dict[input_tuple[i]] = input_tuple[i + 1]\n \n # If the tuple has an odd number of elements, add the last element as a key with None as the value\n if len(input_tuple) % 2 != 0:\n result_dict[input_tuple[-1]] = None\n \n return result_dict", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(tup):\n \"\"\"\n Converts a given tuple into a dictionary with adjacent elements as keys and values.\n \n Parameters:\n - tup (tuple): The input tuple\n \n Returns:\n - dict: A dictionary formed from adjacent elements of the input tuple.\n \"\"\"\n # Ensure the tuple has at least two elements\n if len(tup) < 2:\n return {}\n \n # Use dictionary comprehension to pair up adjacent elements\n return {tup[i]: tup[i+1] for i in range(0, len(tup) - 1, 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(tup):\n if not tup or len(tup) % 2 != 0:\n return {}\n return dict(zip(tup[::2], tup[1::2]))", "matching_cluster_idx": 8}, {"solution": "def tuple_to_dict(tup):\n # Use zip to pair up adjacent elements and convert to dictionary\n return dict(zip(tup[::2], tup[1::2]))", "matching_cluster_idx": 8}, {"solution": "def tuple_to_dict(tup):\n \"\"\"\n Converts the given tuple into a dictionary with adjacent elements as key-value pairs.\n \n Parameters:\n tup (tuple): A tuple with an even number of elements.\n \n Returns:\n dict: A dictionary created by pairing adjacent elements from the tuple.\n \"\"\"\n # Ensure the tuple has an even number of elements for key-value pairing\n if len(tup) % 2 != 0:\n raise ValueError(\"Tuple must contain an even number of elements for key-value pairing\")\n \n # Convert the tuple into a dictionary using dictionary comprehension and zip\n return {key: value for key, value in zip(tup[::2], tup[1::2])}", "matching_cluster_idx": 7}, {"solution": "def tuple_to_dict(input_tuple):\n # Use zip to pair up adjacent elements and then convert to a dictionary\n return dict(zip(input_tuple[::2], input_tuple[1::2]))", "matching_cluster_idx": 8}]}, "Mbpp/744": {"dps": 89.72602739726027, "dps_norm": 92.5, "pass@1": 100.0, "profiled": [{"solution": "def check_none(test_tuple):\n # Check if any element in the tuple is None\n return None in test_tuple", "matching_cluster_idx": 5}, {"solution": "def check_none(test_tuple):\n # Check if any element in the tuple is None\n return None in test_tuple", "matching_cluster_idx": 5}, {"solution": "def check_none(test_tuple):\n # Check if any element in the tuple is None\n return None in test_tuple", "matching_cluster_idx": 5}, {"solution": "def check_none(test_tuple):\n # Check if None is in the tuple\n return None in test_tuple", "matching_cluster_idx": 5}, {"solution": "def check_none(test_tuple):\n # Check if any element in the tuple is None\n return None in test_tuple", "matching_cluster_idx": 5}, {"solution": "def check_none(test_tuple):\n # Check if any element in the tuple is None\n return None in test_tuple", "matching_cluster_idx": 5}, {"solution": "def check_none(test_tuple):\n # Check if any element in the tuple is None\n return any(element is None for element in test_tuple)", "matching_cluster_idx": 2}, {"solution": "def check_none(test_tuple):\n # Check if any element in the tuple is None\n return any(elem is None for elem in test_tuple)", "matching_cluster_idx": 2}, {"solution": "def check_none(test_tuple):\n # Check if None is in the tuple\n return None in test_tuple", "matching_cluster_idx": 5}, {"solution": "def check_none(data):\n # Check if any element in the tuple is None\n return None in data", "matching_cluster_idx": 5}, {"solution": "def check_none(input_tuple):\n # Check if any element in the tuple is None\n return None in input_tuple", "matching_cluster_idx": 5}, {"solution": "def check_none(test_tuple):\n # Check if any element in the tuple is None\n return None in test_tuple", "matching_cluster_idx": 5}, {"solution": "def check_none(test_tuple):\n # Check if any element in the tuple is None\n return any(element is None for element in test_tuple)", "matching_cluster_idx": 2}, {"solution": "def check_none(test_tuple):\n # Check if any element in the tuple is None\n return None in test_tuple", "matching_cluster_idx": 5}, {"solution": "def check_none(test_tuple):\n # Check if any element in the tuple is None\n return None in test_tuple", "matching_cluster_idx": 5}, {"solution": "def check_none(test_tuple):\n # Check if None is in the tuple\n return None in test_tuple", "matching_cluster_idx": 5}, {"solution": "def check_none(test_tuple):\n # Check if any element in the tuple is None\n return None in test_tuple", "matching_cluster_idx": 5}, {"solution": "def check_none(test_tuple):\n # Check if None is in the tuple\n return None in test_tuple", "matching_cluster_idx": 5}, {"solution": "def check_none(test_tuple):\n # Check if 'None' is in the tuple\n return None in test_tuple", "matching_cluster_idx": 5}, {"solution": "def check_none(test_tuple):\n # Check if None is in the tuple\n return None in test_tuple", "matching_cluster_idx": 5}]}, "Mbpp/750": {"dps": 70.23809523809524, "dps_norm": 70.83333333333333, "pass@1": 96.0, "profiled": [{"solution": "def add_tuple(lst, tpl):\n \"\"\"\n Adds all elements of the tuple to the list.\n \n Parameters:\n lst (list): The list to which elements from the tuple will be added.\n tpl (tuple): The tuple containing elements to add to the list.\n \n Returns:\n list: Updated list containing all previous elements plus all elements from the tuple.\n \"\"\"\n for element in tpl:\n lst.append(element)\n return lst", "matching_cluster_idx": 0}, {"solution": "def add_tuple(input_list, input_tuple):\n # Extend the list with the elements from the tuple\n input_list.extend(input_tuple)\n return input_list", "matching_cluster_idx": 5}, {"solution": "def add_tuple(lst, tup):\n \"\"\"\n Add elements of the given tuple to the given list.\n \n Parameters:\n lst (list): The list to which the tuple elements are to be added.\n tup (tuple): The tuple whose elements are to be added to the list.\n \n Returns:\n list: The list with elements of the tuple added to it.\n \"\"\"\n # Add each element of the tuple to the list\n lst.extend(tup)\n return lst", "matching_cluster_idx": 5}, {"solution": "def add_tuple(numbers_list, tuple_values):\n # Convert the tuple to a list and concatenate it to the original list\n return numbers_list + list(tuple_values)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(input_list, input_tuple):\n # Extend the list with the elements of the tuple\n input_list.extend(input_tuple)\n return input_list", "matching_cluster_idx": 5}, {"solution": "def add_tuple(input_list, input_tuple):\n # Convert the tuple to a list and concatenate with the existing list\n return input_list + list(input_tuple)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(lst, tpl):\n \"\"\"\n Add elements from the given tuple to the given list.\n \n Args:\n lst : list of numbers\n tpl : tuple of numbers\n \n Returns:\n list: The list after appending the elements from the tuple.\n \"\"\"\n # Convert tuple to list and extend the original list with it\n result_list = lst.extend(list(tpl))\n # Since list.extend() returns None, we return the modified list directly\n return lst if result_list is None else result_list", "matching_cluster_idx": 3}, {"solution": "def add_tuple(input_list, input_tuple):\n # Convert tuple to a list and concatenate it to the original list\n result_list = input_list + list(input_tuple)\n return result_list", "matching_cluster_idx": 2}, {"solution": "def add_tuple(input_list, input_tuple):\n # Convert the tuple to a list and use the '+' operator to concatenate the lists\n result = input_list + list(input_tuple)\n return result", "matching_cluster_idx": 2}, {"solution": "def add_tuple(lst, tpl):\n \"\"\"\n Adds elements of a tuple to a list and returns the modified list.\n \n :param lst: List to which elements will be added.\n :param tpl: Tuple containing elements to be added to the list.\n :return: The modified list with elements of the tuple appended to it.\n \"\"\"\n # Extend the list with elements from the tuple\n lst.extend(tpl)\n return lst", "matching_cluster_idx": 5}, {"solution": "def add_tuple(lst, tpl):\n \"\"\"\n Adds elements of the given tuple to the given list.\n \n Args:\n lst : list of elements\n tpl : tuple of elements to be added to the list\n \n Returns:\n list: A new list containing all elements from the original list and the tuple.\n \"\"\"\n # Create a copy of the list to avoid modifying the original list\n result_list = lst[:]\n # Extend the list with the elements from the tuple\n result_list.extend(tpl)\n return result_list", "matching_cluster_idx": 2}, {"solution": "def add_tuple(input_list, input_tuple):\n # Extend the list with elements from the tuple\n input_list.extend(input_tuple)\n return input_list", "matching_cluster_idx": 5}, {"solution": "def add_tuple(list_data, tuple_data):\n # Convert the tuple to a list and extend the original list with it\n list_to_add = list(tuple_data)\n list_data.extend(list_to_add)\n return list_data", "matching_cluster_idx": 3}, {"solution": "def add_tuple(input_list, input_tuple):\n # Extend the list with elements from the tuple\n input_list.extend(input_tuple)\n return input_list", "matching_cluster_idx": 5}, {"solution": "def add_tuple(lst, tple):\n # Extend the list with elements from the tuple\n lst.extend(tple)\n return lst", "matching_cluster_idx": 5}, {"solution": "def add_tuple(lst, tpl):\n \"\"\"\n Adds elements from the given tuple to the given list.\n \n Parameters:\n lst (list): The list to which elements will be added.\n tpl (tuple): The tuple whose elements will be added to the list.\n \n Returns:\n list: The modified list containing elements from both the original list and tuple.\n \"\"\"\n # Using the extend method to add tuple elements to the list\n lst.extend(tpl)\n return lst", "matching_cluster_idx": 5}, {"solution": "def add_tuple(input_list, input_tuple):\n # Convert the tuple to a list and concatenate it with the given list\n updated_list = input_list + list(input_tuple)\n return updated_list", "matching_cluster_idx": 2}, {"solution": "def add_tuple(lst, tup):\n \"\"\"\n Add elements of the given tuple to the given list.\n \n Parameters:\n - lst (list): The original list to which elements will be added.\n - tup (tuple): The tuple whose elements will be added to the list.\n \n Returns:\n - list: A new list containing all elements of the original list followed by all elements of the tuple.\n \"\"\"\n # Create a copy of the list to avoid modifying the original list\n new_list = lst[:]\n # Extend the new list with the elements of the tuple\n new_list.extend(tup)\n return new_list", "matching_cluster_idx": 2}, {"solution": "def add_tuple(input_list, input_tuple):\n # Convert the tuple to a list and concatenate it to the existing list\n return input_list + list(input_tuple)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(input_list, input_tuple):\n # Convert the tuple into a list and extend the original list with it\n list_from_tuple = list(input_tuple)\n input_list.extend(list_from_tuple)\n return input_list", "matching_cluster_idx": 3}]}, "Mbpp/753": {"dps": 97.31543624161074, "dps_norm": 75.0, "pass@1": 100.0, "profiled": [{"solution": "def min_k(test_list, K):\n # Sorting the list based on the second element of tuples\n sorted_list = sorted(test_list, key=lambda x: x[1])\n \n # Slicing the first K elements from the sorted list\n result = sorted_list[:K]\n return result", "matching_cluster_idx": 2}, {"solution": "def min_k(test_list, k):\n # Sorting the list based on the second item of tuples\n sorted_list = sorted(test_list, key=lambda x: x[1])\n # Slicing the first k elements from the sorted list\n result = sorted_list[:k]\n return result", "matching_cluster_idx": 2}, {"solution": "def min_k(test_list, K):\n # Sort the list based on the second element of tuples\n sorted_list = sorted(test_list, key=lambda x: x[1])\n \n # Return the first K elements from the sorted list\n return sorted_list[:K]", "matching_cluster_idx": 2}, {"solution": "def min_k(test_list, K):\n # Sorting the list based on the second element of tuples\n sorted_list = sorted(test_list, key=lambda x: x[1])\n \n # Slicing the first K elements from the sorted list\n result = sorted_list[:K]\n \n return result", "matching_cluster_idx": 2}, {"solution": "def min_k(test_list, K):\n # Sorting the list based on the second element of tuples\n sorted_list = sorted(test_list, key=lambda x: x[1])\n \n # Slicing the first K elements from the sorted list\n result = sorted_list[:K]\n \n return result", "matching_cluster_idx": 2}, {"solution": "def min_k(test_list, K):\n # Sorting the list based on the second item of tuples\n sorted_list = sorted(test_list, key=lambda x: x[1])\n # Slicing the first K elements from the sorted list\n result = sorted_list[:K]\n return result", "matching_cluster_idx": 2}, {"solution": "def min_k(test_list, K):\n # Sort the list based on the second item (score) of each tuple\n sorted_list = sorted(test_list, key=lambda x: x[1])\n # Return the first K elements from the sorted list\n return sorted_list[:K]", "matching_cluster_idx": 2}, {"solution": "def min_k(test_list, K):\n # Sort the list based on the second element of tuples\n sorted_list = sorted(test_list, key=lambda x: x[1])\n # Return the first K elements from the sorted list\n return sorted_list[:K]", "matching_cluster_idx": 2}, {"solution": "def min_k(test_list, K):\n # Sorting the list based on the second element of tuples\n sorted_list = sorted(test_list, key=lambda x: x[1])\n \n # Slicing the first K elements from the sorted list\n result = sorted_list[:K]\n \n return result", "matching_cluster_idx": 2}, {"solution": "def min_k(test_list, K):\n # Sorting the list based on the second element of tuples\n sorted_list = sorted(test_list, key=lambda x: x[1])\n # Slicing the first K elements from the sorted list\n result = sorted_list[:K]\n return result", "matching_cluster_idx": 2}, {"solution": "def min_k(test_list, K):\n # Sort the list based on the second element (score) of each tuple\n sorted_list = sorted(test_list, key=lambda x: x[1])\n # Return the first K elements from the sorted list\n return sorted_list[:K]", "matching_cluster_idx": 2}, {"solution": "def min_k(test_tup, K):\n # Sort the tuple list based on the second item in each tuple\n sorted_tup = sorted(test_tup, key=lambda x: x[1])\n \n # Return the first K elements from the sorted list\n return sorted_tup[:K]", "matching_cluster_idx": 2}, {"solution": "def min_k(test_list, K):\n # Sorting the list based on the second element of tuples\n sorted_list = sorted(test_list, key=lambda x: x[1])\n # Slicing the first K elements from the sorted list\n result = sorted_list[:K]\n return result", "matching_cluster_idx": 2}, {"solution": "def min_k(test_list, K):\n # Sort the list based on the second item of the tuple\n sorted_list = sorted(test_list, key=lambda x: x[1])\n # Return the first K elements from the sorted list\n return sorted_list[:K]", "matching_cluster_idx": 2}, {"solution": "def min_k(test_list, k):\n # Sort the list based on the second item of each tuple\n sorted_list = sorted(test_list, key=lambda x: x[1])\n # Return the first k elements of the sorted list\n return sorted_list[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(test_list, K):\n # Sorting the list based on the second element of tuples\n sorted_list = sorted(test_list, key=lambda x: x[1])\n # Slicing the first K elements from the sorted list\n result = sorted_list[:K]\n return result", "matching_cluster_idx": 2}, {"solution": "def min_k(test_list, K):\n # Sorting the list based on the second element of tuples\n sorted_list = sorted(test_list, key=lambda x: x[1])\n \n # Slicing the first K elements from the sorted list\n result = sorted_list[:K]\n return result", "matching_cluster_idx": 2}, {"solution": "def min_k(record_list, k):\n # Sort the list based on the second item of tuples in ascending order\n sorted_list = sorted(record_list, key=lambda x: x[1])\n # Return the first k elements from the sorted list\n return sorted_list[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(test_list, K):\n # Sort the list based on the second element of tuples\n sorted_list = sorted(test_list, key=lambda x: x[1])\n \n # Return the first K elements from the sorted list\n return sorted_list[:K]", "matching_cluster_idx": 2}, {"solution": "def min_k(test_list, K):\n # Sort the list based on the second element of tuples\n sorted_list = sorted(test_list, key=lambda x: x[1])\n # Return the first K elements from the sorted list\n return sorted_list[:K]", "matching_cluster_idx": 2}]}, "Mbpp/754": {"dps": 92.75862068965517, "dps_norm": 91.25, "pass@1": 87.0, "profiled": [{"solution": "def extract_index_list(l1, l2, l3):\n # Use list comprehension to iterate through all three lists simultaneously\n # Check if the elements at the same index in all three lists are equal\n return [x for x, y, z in zip(l1, l2, l3) if x == y == z]", "matching_cluster_idx": 7}, {"solution": "def extract_index_list(list1, list2, list3):\n \"\"\"\n Finds common elements in the same index from three lists.\n \n Parameters:\n - list1: First list of integers.\n - list2: Second list of integers.\n - list3: Third list of integers.\n \n Returns:\n A list containing the common elements at the same index in all three input lists.\n \"\"\"\n # Calculate the minimum length to avoid index out of range errors\n min_length = min(len(list1), len(list2), len(list3))\n \n # Extract elements that are common at the same index\n common_elements = [list1[i] for i in range(min_length) if list1[i] == list2[i] == list3[i]]\n \n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n # Use list comprehension to iterate through the indices of the lists and compare elements at those indices\n common_elements = [x for (x, y, z) in zip(l1, l2, l3) if x == y == z]\n return common_elements", "matching_cluster_idx": 7}, {"solution": "def extract_index_list(l1, l2, l3):\n # Use list comprehension to find common elements at the same index\n result = [x for x, y, z in zip(l1, l2, l3) if x == y == z]\n return result", "matching_cluster_idx": 7}, {"solution": "def extract_index_list(l1, l2, l3):\n # Initialize an empty list to store common elements\n common_elements = []\n \n # Iterate through indices of the lists\n for i in range(min(len(l1), len(l2), len(l3))):\n # Check if elements at the current index in all three lists are the same\n if l1[i] == l2[i] == l3[i]:\n # If so, append the element to the common_elements list\n common_elements.append(l1[i])\n \n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n # Use list comprehension to iterate through the lengths of the shortest list\n # Check if the element at the same index in all three lists are the same\n common_elements = [l1[i] for i in range(min(len(l1), len(l2), len(l3))) if l1[i] == l2[i] == l3[i]]\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n # Initialize an empty list to store the common elements\n common_elements = []\n \n # Iterate through the lists using index i\n for i in range(min(len(l1), len(l2), len(l3))):\n # Check if the elements at index i are the same in all three lists\n if l1[i] == l2[i] == l3[i]:\n # If they are, append the element to the common_elements list\n common_elements.append(l1[i])\n \n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n # Use list comprehension to find elements that are common at the same index in all three lists\n common_elements = [e1 for e1, e2, e3 in zip(l1, l2, l3) if e1 == e2 == e3]\n return common_elements", "matching_cluster_idx": 7}, {"solution": "def extract_index_list(l1, l2, l3):\n # Find the minimum length to avoid index out of range error\n min_len = min(len(l1), len(l2), len(l3))\n \n # Extract common elements by comparing elements at the same index\n common_elements = [l1[i] for i in range(min_len) if l1[i] == l2[i] == l3[i]]\n \n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n # Initialize an empty list to store common elements\n common_elements = []\n \n # Iterate through the lists up to the length of the shortest list\n for i in range(min(len(l1), len(l2), len(l3))):\n # Check if elements at the current index are the same in all lists\n if l1[i] == l2[i] == l3[i]:\n # Add the common element to the list\n common_elements.append(l1[i])\n \n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n # Initialize an empty list to store common elements\n result = []\n \n # Get the length of the smallest list\n min_length = min(len(l1), len(l2), len(l3))\n \n # Iterate through the indices up to the length of the smallest list\n for i in range(min_length):\n # Check if the elements at index i are the same in all three lists\n if l1[i] == l2[i] == l3[i]:\n # If they are the same, add the element to the result list\n result.append(l1[i])\n \n return result", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n # Initialize an empty list to store common elements\n common_elements = []\n \n # Iterate through indices of the lists\n for i in range(min(len(l1), len(l2), len(l3))):\n # Check if elements at index i are the same in all three lists\n if l1[i] == l2[i] == l3[i]:\n # If true, append the element to the common_elements list\n common_elements.append(l1[i])\n \n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n # Initialize an empty list to store common elements\n common_elements = []\n \n # Iterate through the indices of the lists up to the minimum length\n for i in range(min(len(l1), len(l2), len(l3))):\n # Check if the elements at the current index in all three lists are the same\n if l1[i] == l2[i] == l3[i]:\n # If so, append this element to the common_elements list\n common_elements.append(l1[i])\n \n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n # Use list comprehension to iterate through all three lists simultaneously using zip\n # Check if elements at the same index in all three lists are equal\n # If so, add to the common_elements list\n common_elements = [val for val, val2, val3 in zip(l1, l2, l3) if val == val2 == val3]\n \n return common_elements", "matching_cluster_idx": 7}, {"solution": "def extract_index_list(list1, list2, list3):\n # Use list comprehension to iterate through the indices of the lists and check for common elements\n common_elements = [list1[i] for i in range(min(len(list1), len(list2), len(list3))) if list1[i] == list2[i] and list2[i] == list3[i]]\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n # Initialize an empty list to store common elements\n common_elements = []\n \n # Iterate through all three lists to find common elements\n for i in range(min(len(l1), len(l2), len(l3))):\n # If elements at index i in all three lists are the same, append to common_elements list\n if l1[i] == l2[i] and l2[i] == l3[i]:\n common_elements.append(l1[i])\n \n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n # Initialize an empty list to store common elements\n common_elements = []\n \n # Determine the length of the shortest list to avoid index out of range errors\n min_length = min(len(l1), len(l2), len(l3))\n \n # Iterate through the lists up to the length of the shortest list\n for i in range(min_length):\n # If elements at the same index in all three lists are equal, add to the result list\n if l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n \n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n # Use list comprehension to filter common elements by index\n return [a for a, b, c in zip(l1, l2, l3) if a == b == c]", "matching_cluster_idx": 7}, {"solution": "def extract_index_list(list1, list2, list3):\n # Initialize an empty list to store common elements\n common_elements = []\n \n # Determine the minimum length among the three lists\n min_length = min(len(list1), len(list2), len(list3))\n \n # Iterate through the lists up to the minimum length\n for i in range(min_length):\n # Check if the elements at the current index are the same in all three lists\n if list1[i] == list2[i] == list3[i]:\n common_elements.append(list1[i])\n \n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n # Initialize an empty list to store the common elements\n common_elements = []\n \n # Determine the minimum length of the three lists to avoid index out of range errors\n min_length = min(len(l1), len(l2), len(l3))\n \n # Iterate through the lists up to the minimum length\n for i in range(min_length):\n # Check if the elements at the same index are the same across all three lists\n if l1[i] == l2[i] == l3[i]:\n # If so, append the element to the common_elements list\n common_elements.append(l1[i])\n \n return common_elements", "matching_cluster_idx": 6}]}, "Mbpp/755": {"dps": 83.00884955752213, "dps_norm": 90.83333333333333, "pass@1": 27.0, "profiled": [{"solution": "def second_smallest(numbers):\n \"\"\"\n Find the second smallest number in the given list.\n \n :param numbers: List of integers\n :return: The second smallest integer in the list\n \"\"\"\n # Removing duplicates by converting list to a set and then back to list\n unique_numbers = list(set(numbers))\n # Sorting the list to find the second smallest number\n unique_numbers.sort()\n # Return the second element if it exists, else return None\n return unique_numbers[1] if len(unique_numbers) >= 2 else None", "matching_cluster_idx": 5}, {"solution": "def second_smallest(numbers):\n # Remove duplicates by converting the list to a set, then back to a list\n unique_numbers = list(set(numbers))\n \n # If there are less than 2 unique elements, return None as no second smallest can exist\n if len(unique_numbers) < 2:\n return None\n \n # Sort the list of unique numbers\n unique_numbers.sort()\n \n # Return the second element which is the second smallest\n return unique_numbers[1]", "matching_cluster_idx": 5}, {"solution": "def second_smallest(numbers):\n \"\"\"\n Finds the second smallest number in a given list.\n \n Parameters:\n numbers (list): A list of integers.\n \n Returns:\n int: The second smallest integer in the list.\n \"\"\"\n \n # Initialize the smallest and second smallest variables with a very large value\n first = second = float('inf')\n \n for num in numbers:\n if num <= first:\n # Update the smallest and second smallest accordingly\n if num < first:\n second = first\n first = num\n elif num < second:\n # Update the second smallest if a new number is between smallest and second smallest\n second = num\n \n return second if second < float('inf') else None", "matching_cluster_idx": 3}, {"solution": "def second_smallest(numbers):\n # First, remove duplicates by converting the list to a set, then back to a list\n unique_numbers = list(set(numbers))\n \n # If there are less than 2 unique numbers, return None as we cannot find a second smallest\n if len(unique_numbers) < 2:\n return None\n \n # Sort the list of unique numbers\n unique_numbers.sort()\n \n # Return the second element in the sorted list\n return unique_numbers[1]", "matching_cluster_idx": 5}, {"solution": "def second_smallest(numbers):\n # Sort the list of numbers\n sorted_numbers = sorted(numbers)\n \n # Initialize the second smallest variable with None\n second_smallest = None\n \n # Iterate through the sorted list and find the second smallest unique number\n for i in range(1, len(sorted_numbers)):\n if sorted_numbers[i] != sorted_numbers[i-1]:\n # Return the first unique number after the smallest number\n return sorted_numbers[i]\n return second_smallest", "matching_cluster_idx": 2}, {"solution": "def second_smallest(numbers):\n # Remove duplicates by converting the list to a set, then back to a list\n unique_numbers = list(set(numbers))\n \n # Sort the list in ascending order\n unique_numbers.sort()\n \n # Return the second element if it exists\n return unique_numbers[1] if len(unique_numbers) > 1 else None", "matching_cluster_idx": 5}, {"solution": "def second_smallest(numbers):\n \"\"\"\n Finds the second smallest number in a given list of numbers.\n \n Parameters:\n numbers (list): A list of integers.\n \n Returns:\n int: The second smallest integer in the list.\n \"\"\"\n \n # Remove duplicates by converting to a set, then convert back to a list\n unique_numbers = list(set(numbers))\n \n # If there are less than 2 unique numbers, return None as second smallest does not exist\n if len(unique_numbers) < 2:\n return None\n \n # Sort the list to find the second smallest number\n unique_numbers.sort()\n \n # Return the second smallest number\n return unique_numbers[1]", "matching_cluster_idx": 5}, {"solution": "def second_smallest(numbers):\n \"\"\"\n Find the second smallest number in a given list of numbers.\n \n :param numbers: List of numbers from which to find the second smallest.\n :return: The second smallest number in the list.\n \"\"\"\n # First, we sort the list in ascending order.\n sorted_numbers = sorted(numbers)\n \n # We remove duplicates by converting to a set and back to a sorted list.\n unique_sorted_numbers = sorted(set(sorted_numbers))\n \n # If there are less than 2 unique elements, we cannot find a second smallest.\n if len(unique_sorted_numbers) < 2:\n return None\n \n # Return the second element in the sorted unique list.\n return unique_sorted_numbers[1]", "matching_cluster_idx": 1}, {"solution": "def second_smallest(numbers):\n # Remove duplicates and sort the list\n unique_numbers = sorted(set(numbers))\n # Check if there are at least 2 unique elements\n if len(unique_numbers) < 2:\n return None # or raise an error if you prefer\n # Return the second element in the sorted unique list\n return unique_numbers[1]", "matching_cluster_idx": 5}, {"solution": "def second_smallest(numbers):\n # Remove duplicates by converting the list to a set, then back to a list\n unique_numbers = list(set(numbers))\n \n # Sort the list to get the smallest and second smallest numbers\n unique_numbers.sort()\n \n # Return the second smallest number, if there's at least two unique numbers\n if len(unique_numbers) > 1:\n return unique_numbers[1]\n else:\n # If there's only one unique number, return None or raise an error\n return None", "matching_cluster_idx": 5}, {"solution": "def second_smallest(numbers):\n # Remove duplicates and sort the list\n unique_numbers = sorted(set(numbers))\n \n # Check if there are at least 2 unique elements\n if len(unique_numbers) < 2:\n return None # or raise an exception, depending on the requirement\n \n # Return the second element in the sorted unique list\n return unique_numbers[1]", "matching_cluster_idx": 5}, {"solution": "def second_smallest(numbers):\n \"\"\"\n Find the second smallest number in a given list of numbers.\n \n :param numbers: List of numbers\n :return: The second smallest number in the list\n \"\"\"\n # Ensure the list has at least 2 unique elements\n if len(set(numbers)) < 2:\n return None # Or raise an exception, depending on the requirement\n \n # Convert to set to remove duplicates, then back to sorted list\n unique_numbers = sorted(set(numbers))\n \n # Return the second item in the sorted list\n return unique_numbers[1]", "matching_cluster_idx": 4}, {"solution": "def second_smallest(numbers):\n # Remove duplicates by converting the list to a set, then back to a list\n unique_numbers = list(set(numbers))\n \n # If there are less than 2 unique numbers, return None as we can't find a second smallest\n if len(unique_numbers) < 2:\n return None\n \n # Sort the list of unique numbers\n unique_numbers.sort()\n \n # Return the second element which is the second smallest number\n return unique_numbers[1]", "matching_cluster_idx": 5}, {"solution": "def second_smallest(numbers):\n # Remove duplicates and sort the list\n unique_numbers = sorted(set(numbers))\n # Check if there are at least 2 unique numbers\n if len(unique_numbers) < 2:\n return None # Return None or an appropriate value if the list doesn't have enough unique elements\n else:\n # Return the second element which is the second smallest\n return unique_numbers[1]", "matching_cluster_idx": 5}, {"solution": "def second_smallest(numbers):\n # Remove duplicates and sort the list\n unique_numbers = sorted(set(numbers))\n # Check if there are at least 2 unique numbers\n if len(unique_numbers) < 2:\n return None # or raise an exception, depending on error handling policy\n # Return the second element in the sorted unique list\n return unique_numbers[1]", "matching_cluster_idx": 5}, {"solution": "def second_smallest(numbers):\n # Remove duplicates and sort the list\n unique_numbers = sorted(set(numbers))\n # Check if there are at least 2 unique numbers\n if len(unique_numbers) < 2:\n return None # or raise an exception, depending on requirements\n # Return the second element in the sorted unique list\n return unique_numbers[1]", "matching_cluster_idx": 5}, {"solution": "def second_smallest(numbers):\n # Ensure there are at least 2 unique elements\n if len(numbers) < 2:\n return None\n \n # Remove duplicates and sort the list\n unique_numbers = sorted(set(numbers))\n \n # Check if there are at least 2 unique numbers\n if len(unique_numbers) < 2:\n return None\n \n # Return the second smallest number\n return unique_numbers[1]", "matching_cluster_idx": 5}, {"solution": "def second_smallest(numbers):\n # Remove duplicates and sort the list\n unique_numbers = sorted(set(numbers))\n # Check if there are at least 2 unique elements\n if len(unique_numbers) < 2:\n return None # or raise an error, depending on the requirements\n \n # Return the second element in the sorted unique list\n return unique_numbers[1]", "matching_cluster_idx": 5}, {"solution": "def second_smallest(numbers):\n \"\"\"\n Finds the second smallest number in a given list.\n \n Args:\n numbers: List of integers.\n \n Returns:\n The second smallest integer in the list.\n \"\"\"\n # Ensure the list has at least 2 unique elements\n if len(set(numbers)) < 2:\n return None\n \n # Remove duplicates and sort the list\n sorted_unique_numbers = sorted(set(numbers))\n \n # Return the second element in the sorted list\n return sorted_unique_numbers[1]", "matching_cluster_idx": 4}, {"solution": "def second_smallest(numbers):\n \"\"\"\n Finds the second smallest element in the given list of numbers.\n \n Args:\n numbers : List[int]\n A list of integers from which to find the second smallest number.\n \n Returns:\n int\n The second smallest integer in the provided list.\n \"\"\"\n # First, remove duplicates by converting the list to a set, then back to a list\n unique_numbers = list(set(numbers))\n \n # If there are less than 2 unique elements, return None as we cannot find a second smallest\n if len(unique_numbers) < 2:\n return None\n \n # Sort the list to find the second smallest element\n unique_numbers.sort()\n \n # Return the second smallest element\n return unique_numbers[1]", "matching_cluster_idx": 5}]}, "Mbpp/757": {"dps": 85.04672897196262, "dps_norm": 34.23076923076923, "pass@1": 56.0, "profiled": [{"solution": "def count_reverse_pairs(words):\n count = 0\n # Iterate through the list to find reverse string pairs\n for i in range(len(words)):\n for j in range(i + 1, len(words)):\n if words[i] == words[j][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(words):\n \"\"\"\n Counts the number of pairs of reverse strings in the given list.\n \n Parameters:\n words (list): A list of strings.\n \n Returns:\n int: The number of pairs of reverse strings.\n \"\"\"\n count = 0\n for i in range(len(words)):\n for j in range(i + 1, len(words)):\n if words[j] == words[i][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(words):\n def is_reverse_pair(word1, word2):\n return word1 == word2[::-1]\n \n count = 0\n # Iterate through each pair of words in the list\n for i in range(len(words)):\n for j in range(i + 1, len(words)):\n if is_reverse_pair(words[i], words[j]):\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(words):\n \"\"\"\n Counts the number of pairs of words in the list where one word is the reverse of the other.\n \n :param words: List of strings to be checked for reverse pairs.\n :return: The count of reverse string pairs found in the list.\n \"\"\"\n count = 0\n # Iterate through each word in the list\n for i in range(len(words)):\n # Compare the current word with the rest of the words in the list\n for j in range(i + 1, len(words)):\n # Check if the current word is the reverse of the other word\n if words[i] == words[j][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(words):\n def is_reverse_pair(s1, s2):\n # Check if one string is the reverse of the other\n return s1 == s2[::-1]\n \n count = 0\n # Loop through all unique pairs in the list\n for i in range(len(words)):\n for j in range(i + 1, len(words)):\n if is_reverse_pair(words[i], words[j]):\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(words):\n def is_reverse_pair(word1, word2):\n # Check if word2 is the reverse of word1\n return word1 == word2[::-1]\n \n count = 0\n # Iterate through the list of words to find reverse pairs\n for i in range(len(words)):\n for j in range(i + 1, len(words)):\n if is_reverse_pair(words[i], words[j]):\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(words):\n def is_reverse(s1, s2):\n # Check if one string is the reverse of the other\n return s1 == s2[::-1]\n \n count = 0\n # Iterate through each pair of strings in the list\n for i in range(len(words)):\n for j in range(i + 1, len(words)):\n if is_reverse(words[i], words[j]):\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(words):\n count = 0\n # Iterate through each word in the list\n for i in range(len(words)):\n for j in range(i + 1, len(words)):\n # Check if the second word is the reverse of the first word\n if words[j] == words[i][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(words):\n \"\"\"\n Counts the number of pairs of strings in the list that are reverses of each other.\n \n :param words: List of strings to be checked for reverse pairs\n :return: The number of reverse string pairs in the list\n \"\"\"\n reverse_pairs_count = 0\n for i in range(len(words)):\n for j in range(i + 1, len(words)):\n if words[i] == words[j][::-1]:\n reverse_pairs_count += 1\n return reverse_pairs_count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(words):\n count = 0\n # Loop through each word in the list\n for i in range(len(words)):\n # Compare with the rest of the words in the list\n for j in range(i + 1, len(words)):\n # Check if the second word is the reverse of the first word\n if words[i] == words[j][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(arr):\n def is_reverse_pair(s1, s2):\n # Check if s2 is the reverse of s1\n return s1 == s2[::-1]\n \n count = 0\n # Generate all unique pairs and check if they are reverse pairs\n for i in range(len(arr)):\n for j in range(i + 1, len(arr)):\n if is_reverse_pair(arr[i], arr[j]):\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(words):\n \"\"\"\n Counts the number of pairs of reverse strings in the given list of strings.\n \n Parameters:\n words (list): A list of strings to be checked for reverse pairs.\n \n Returns:\n int: The number of reverse string pairs found in the list.\n \"\"\"\n count = 0\n for i in range(len(words)):\n for j in range(i + 1, len(words)):\n if words[j] == words[i][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(words):\n \"\"\"\n Counts the pairs of reverse strings in the given list.\n \n Parameters:\n words (list): A list of strings to be checked.\n \n Returns:\n int: The count of pairs of reverse strings.\n \"\"\"\n \n # Initialize the reverse pair count to zero\n reverse_pair_count = 0\n \n # Create a dictionary to store each word and its count\n word_count = {}\n \n # Iterate through each word in the input list\n for word in words:\n # Check if the reverse of the word exists in the dictionary\n if word[::-1] in word_count:\n # Increase the reverse pair count by the frequency of the reverse word\n reverse_pair_count += word_count[word[::-1]]\n \n # Update the count of the current word in the dictionary\n if word in word_count:\n word_count[word] += 1\n else:\n word_count[word] = 1\n \n return reverse_pair_count", "matching_cluster_idx": 12}, {"solution": "def count_reverse_pairs(words):\n \"\"\"\n Counts the number of pairs of words that are reverses of each other.\n \n :param words: List of strings to be checked.\n :return: The number of pairs of reverse strings.\n \"\"\"\n reverse_pairs_count = 0\n \n # Use a dictionary to keep track of word occurrences and their reverse occurrences.\n word_count = {}\n \n for word in words:\n # Check if the word is the reverse of any word seen before.\n if word[::-1] in word_count:\n reverse_pairs_count += word_count[word[::-1]]\n \n # Update the dictionary with the current word.\n if word not in word_count:\n word_count[word] = 0\n word_count[word] += 1\n \n return reverse_pairs_count", "matching_cluster_idx": 11}, {"solution": "def count_reverse_pairs(words):\n \"\"\"\n Counts the pairs of reverse strings in the given list of strings.\n \n Parameters:\n words (list): A list of strings.\n \n Returns:\n int: The number of pairs of reverse strings.\n \"\"\"\n reverse_pairs_count = 0\n # Create a dictionary to store words and their counts\n word_dict = {}\n \n for word in words:\n # Check if the reverse word is already in the dictionary\n if word[::-1] in word_dict:\n reverse_pairs_count += word_dict[word[::-1]]\n # Update the dictionary with the current word\n if word in word_dict:\n word_dict[word] += 1\n else:\n word_dict[word] = 1\n \n return reverse_pairs_count", "matching_cluster_idx": 12}, {"solution": "def count_reverse_pairs(words):\n \"\"\"\n Counts the number of pairs of words where one is the reverse of the other.\n \n :param words: List of strings to be checked for reverse pairs\n :return: Number of reverse string pairs found\n \"\"\"\n count = 0\n # Iterate through each word in the list\n for i in range(len(words)):\n for j in range(i + 1, len(words)):\n # Check if the second word is the reverse of the first\n if words[j] == words[i][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(words):\n \"\"\"\n Counts the number of pairs of reverse strings in the given list of strings.\n \n Parameters:\n words (list): A list of strings to be checked for reverse pairs.\n \n Returns:\n int: The number of pairs of reverse strings in the list.\n \"\"\"\n # Counting pairs of reverse strings\n count = 0\n for i in range(len(words)):\n for j in range(i + 1, len(words)):\n if words[j] == words[i][::-1]: # Check if reverse of words[i] is in words\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(words):\n \"\"\"\n Counts the number of pairs of reverse strings in the given list of strings.\n \n Parameters:\n words (list): A list of strings.\n \n Returns:\n int: The number of pairs of reverse strings.\n \"\"\"\n # Initialize counter for reverse string pairs\n reverse_pairs_count = 0\n \n # Loop through the list of words to find reverse pairs\n for i in range(len(words)):\n for j in range(i + 1, len(words)):\n if words[j] == words[i][::-1]: # Check if the current pair is reverse of each other\n reverse_pairs_count += 1\n \n return reverse_pairs_count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(words):\n count = 0\n # Iterate through the list to find reverse string pairs\n for i in range(len(words)):\n for j in range(i + 1, len(words)):\n if words[j] == words[i][::-1]: # Check if reverse of words[i] is words[j]\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(words):\n \"\"\"\n Counts the number of pairs of words where one word is the reverse of the other.\n \n :param words: List of strings to be checked for reverse pairs\n :return: Number of reverse word pairs\n \"\"\"\n count = 0\n # Iterate through the list of words\n for i in range(len(words)):\n for j in range(i + 1, len(words)):\n # Check if one word is the reverse of the other\n if words[i] == words[j][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}]}, "Mbpp/758": {"dps": 65.61776061776061, "dps_norm": 75.625, "pass@1": 94.0, "profiled": [{"solution": "def unique_sublists(lst):\n from collections import defaultdict\n \n # Dictionary to hold the count of each tuple\n count_dict = defaultdict(int)\n \n # Convert each list in the input list to a tuple and count occurrences\n for sublist in lst:\n count_dict[tuple(sublist)] += 1\n \n # Convert defaultdict to a regular dict for the output\n return dict(count_dict)", "matching_cluster_idx": 5}, {"solution": "def unique_sublists(lst):\n from collections import defaultdict\n \n # Convert each sublist in the input list to a tuple and count their occurrences\n count_dict = defaultdict(int)\n for sublist in lst:\n count_dict[tuple(sublist)] += 1\n \n return dict(count_dict)", "matching_cluster_idx": 5}, {"solution": "def unique_sublists(lst):\n from collections import defaultdict\n \n # Dictionary to store the count of each tuple\n count_dict = defaultdict(int)\n \n # Iterate over each sublist in the list\n for sublist in lst:\n # Convert the sublist into a tuple and update its count in the dictionary\n count_dict[tuple(sublist)] += 1\n \n # Convert defaultdict to a regular dictionary\n return dict(count_dict)", "matching_cluster_idx": 5}, {"solution": "def unique_sublists(lst):\n from collections import defaultdict\n \n # Dictionary to hold the tuple as key and its count as value\n sublist_count = defaultdict(int)\n \n # Convert each sublist into a tuple and count its occurrences\n for sublist in lst:\n tuple_sublist = tuple(sublist)\n sublist_count[tuple_sublist] += 1\n \n # Convert defaultdict back to a regular dict before returning\n return dict(sublist_count)", "matching_cluster_idx": 5}, {"solution": "def unique_sublists(lst):\n from collections import defaultdict\n \n # Initialize a dictionary to count the occurrences\n count_dict = defaultdict(int)\n \n # Iterate through the list and count occurrences of each tuple\n for sublist in lst:\n # Convert each sublist to a tuple and increment its count in the dictionary\n count_dict[tuple(sublist)] += 1\n \n return dict(count_dict)", "matching_cluster_idx": 5}, {"solution": "def unique_sublists(lst):\n from collections import defaultdict\n \n # Convert each sublist to a tuple and count occurrences\n counts = defaultdict(int)\n for sublist in lst:\n counts[tuple(sublist)] += 1\n \n # Convert defaultdict to a regular dictionary for the output\n return dict(counts)", "matching_cluster_idx": 5}, {"solution": "from collections import defaultdict\ndef unique_sublists(lst):\n result = defaultdict(int)\n for sublist in lst:\n # Convert list to tuple and count its occurrences\n result[tuple(sublist)] += 1\n return dict(result)", "matching_cluster_idx": 5}, {"solution": "def unique_sublists(lst):\n from collections import defaultdict\n \n # Use a dictionary to count occurrences of each tuple\n counter = defaultdict(int)\n for sublist in lst:\n # Convert each sublist to a tuple and count its occurrences\n counter[tuple(sublist)] += 1\n \n # Convert the defaultdict to a regular dict before returning\n return dict(counter)", "matching_cluster_idx": 5}, {"solution": "def unique_sublists(lst):\n from collections import defaultdict\n \n # Initialize a dictionary to store the counts of each tuple\n count_dict = defaultdict(int)\n \n # Iterate through each sublist in the input list\n for sublist in lst:\n # Convert the sublist to a tuple and increment its count in the dictionary\n count_dict[tuple(sublist)] += 1\n \n return dict(count_dict)", "matching_cluster_idx": 5}, {"solution": "def unique_sublists(lst):\n from collections import defaultdict\n \n # Initialize a dictionary to store the count of each tuple\n count_dict = defaultdict(int)\n \n # Iterate over each sublist in the given list and convert it to a tuple\n for sublist in lst:\n tuple_sublist = tuple(sublist)\n # Increment the count for this tuple in the dictionary\n count_dict[tuple_sublist] += 1\n \n return count_dict", "matching_cluster_idx": 5}, {"solution": "def unique_sublists(lst):\n from collections import defaultdict\n \n # Dictionary to hold the count of each tuple\n count_dict = defaultdict(int)\n \n # Iterate over the list and convert each sublist to a tuple\n for sublist in lst:\n # Convert the sublist to a tuple and increment its count in the dictionary\n count_dict[tuple(sublist)] += 1\n \n return count_dict", "matching_cluster_idx": 5}, {"solution": "def unique_sublists(lst):\n from collections import defaultdict\n \n # Using a dictionary to keep count of tuples\n count_dict = defaultdict(int)\n \n # Iterating through each sublist in the provided list\n for sublist in lst:\n # Converting the sublist to a tuple and counting its occurrences\n count_dict[tuple(sublist)] += 1\n \n # Converting the dictionary to the required format with tuple keys\n result = dict(count_dict)\n return result", "matching_cluster_idx": 5}, {"solution": "def unique_sublists(lst):\n from collections import defaultdict\n \n # Convert lists within the list to tuples and count their occurrences\n counter = defaultdict(int)\n for sublist in lst:\n counter[tuple(sublist)] += 1\n \n # Convert defaultdict to a regular dictionary before returning\n return dict(counter)", "matching_cluster_idx": 5}, {"solution": "def unique_sublists(lst):\n from collections import defaultdict\n \n # Initialize a dictionary to store the counts\n count_dict = defaultdict(int)\n \n # Iterate through each sublist in the given list\n for sublist in lst:\n # Convert each sublist to a tuple and count its occurrences\n count_dict[tuple(sublist)] += 1\n \n # Convert defaultdict to a regular dict before returning\n return dict(count_dict)", "matching_cluster_idx": 5}, {"solution": "def unique_sublists(lst):\n from collections import defaultdict\n \n # Initialize a dictionary to count tuples\n count_dict = defaultdict(int)\n \n # Iterate over each sublist in the input list\n for sublist in lst:\n # Convert each sublist to a tuple and count its occurrences\n count_dict[tuple(sublist)] += 1\n \n # Convert defaultdict to a regular dictionary for the output\n return dict(count_dict)", "matching_cluster_idx": 5}, {"solution": "def unique_sublists(lst):\n from collections import defaultdict\n \n # Initialize a dictionary to keep count of tuples\n count_dict = defaultdict(int)\n \n # Convert each list to a tuple and count occurrences\n for sublist in lst:\n converted_tuple = tuple(sublist)\n count_dict[converted_tuple] += 1\n \n # Convert defaultdict to a regular dictionary for the output\n return dict(count_dict)", "matching_cluster_idx": 5}, {"solution": "def unique_sublists(lst):\n from collections import defaultdict\n \n # Convert each sublist into a tuple to make them hashable\n # and use a defaultdict to count occurrences of each tuple\n count = defaultdict(int)\n for sublist in lst:\n tuple_sublist = tuple(sublist)\n count[tuple_sublist] += 1\n \n return dict(count)", "matching_cluster_idx": 5}, {"solution": "def unique_sublists(lst):\n from collections import defaultdict\n \n # Create a dictionary to hold the count of each tuple\n count_dict = defaultdict(int)\n \n # Iterate over each sublist in the input list, convert it to a tuple and count its occurrences\n for sublist in lst:\n count_dict[tuple(sublist)] += 1\n \n # Convert defaultdict to a regular dictionary for the output\n return dict(count_dict)", "matching_cluster_idx": 5}, {"solution": "def unique_sublists(lst):\n from collections import defaultdict\n \n # Convert lists within the list to tuples for hashability\n tuple_list = [tuple(sublist) for sublist in lst]\n \n # Use a dictionary to count occurrences of each tuple\n count_dict = defaultdict(int)\n for item in tuple_list:\n count_dict[item] += 1\n \n return count_dict", "matching_cluster_idx": 5}, {"solution": "def unique_sublists(input_list):\n # Convert each sublist to a tuple and count their occurrences\n sublist_counts = {}\n for sublist in input_list:\n sublist_tup = tuple(sublist)\n if sublist_tup in sublist_counts:\n sublist_counts[sublist_tup] += 1\n else:\n sublist_counts[sublist_tup] = 1\n return sublist_counts", "matching_cluster_idx": 6}]}, "Mbpp/760": {"dps": 90.65693430656934, "dps_norm": 83.75, "pass@1": 98.0, "profiled": [{"solution": "def unique_Element(arr):\n # Check if the set of the array length is 1, meaning all elements are the same\n if len(set(arr)) == 1:\n return True\n else:\n return False", "matching_cluster_idx": 6}, {"solution": "def unique_Element(nums):\n # Check if the length of the set of the list is 1\n return len(set(nums)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(nums):\n # Check if the length of the set of nums is 1\n return len(set(nums)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(nums):\n # Check if the length of the set of nums is 1\n return len(set(nums)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(nums):\n # Check if the length of the set of numbers is 1\n return len(set(nums)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(nums):\n # Check if the length of the set of nums is 1\n return len(set(nums)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(nums):\n # Check if all elements in the list are the same by comparing each element to the first one\n return all(x == nums[0] for x in nums)", "matching_cluster_idx": 3}, {"solution": "def unique_Element(nums):\n # Check if the length of the set of nums is 1\n return len(set(nums)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(nums):\n # Check if the length of the set of nums is 1\n if len(set(nums)) == 1:\n return True\n else:\n return False", "matching_cluster_idx": 6}, {"solution": "def unique_Element(arr):\n # Check if the length of the set of the array is 1\n return len(set(arr)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(lst):\n # Check if the length of the list is 1 or if the set of the list contains only one element\n return len(lst) == 1 or len(set(lst)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(nums):\n # Check if the length of the set of nums is 1\n return len(set(nums)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(nums):\n # Check if all elements in the list are the same\n return all(x == nums[0] for x in nums)", "matching_cluster_idx": 3}, {"solution": "def unique_Element(nums):\n # Check if the length of the set of the list is 1\n return len(set(nums)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(arr):\n # Check if the length of the set of the array equals 1\n if len(set(arr)) == 1:\n return True\n else:\n return False", "matching_cluster_idx": 6}, {"solution": "def unique_Element(nums):\n # Check if the length of the set of numbers is 1\n if len(set(nums)) == 1:\n return True\n else:\n return False", "matching_cluster_idx": 6}, {"solution": "def unique_Element(nums):\n # Check if the length of the set of numbers is 1\n return len(set(nums)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(nums):\n # Check if the length of the set of nums is 1\n return len(set(nums)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(nums):\n # Check if the length of the set of nums is 1\n if len(set(nums)) == 1:\n return True\n else:\n return False", "matching_cluster_idx": 6}, {"solution": "def unique_Element(nums):\n # Check if the length of the set of nums is 1\n if len(set(nums)) == 1:\n return True\n else:\n return False", "matching_cluster_idx": 6}]}, "Mbpp/764": {"dps": 88.88888888888889, "dps_norm": 50.0, "pass@1": 100.0, "profiled": [{"solution": "def number_ctr(s):\n count = 0\n for char in s:\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n count = 0\n for char in s:\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(str):\n # Initialize counter to 0\n count = 0\n \n # Iterate through each character in the string\n for char in str:\n # Check if the character is a digit\n if char.isdigit():\n # Increment counter if the character is a digit\n count += 1\n \n # Return the final count of digits\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n count = 0\n # Iterating through each character in the string\n for char in s:\n # Checking if the character is a digit\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n count = 0\n for char in s:\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n count = 0\n # Iterate through each character in the string\n for char in s:\n # Check if the character is a digit\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n count = 0\n for char in s:\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(input_string):\n count = 0\n for char in input_string:\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(input_str):\n count = 0\n # Iterating through each character in the string\n for char in input_str:\n # Check if the character is a digit\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(str):\n # Initialize count to 0\n count = 0\n # Loop through each character in the string\n for i in range(len(str)):\n # Check if the character is a digit\n if str[i].isdigit():\n count += 1 # Increment count if the character is a digit\n return count # Return the total count of digits", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n num_count = 0\n for char in s:\n if char.isdigit():\n num_count += 1\n return num_count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(input_str):\n \"\"\"Counts the number of digits in a given string.\"\"\"\n # Using a generator expression to iterate through each character in the string\n # and check if it's a digit, then summing the True values (1s) to get the count\n digit_count = sum(char.isdigit() for char in input_str)\n return digit_count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n \"\"\"Counts the number of digits in a given string.\"\"\"\n count = 0\n for char in s:\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n count = 0\n # Iterate through each character in the string\n for char in s:\n # Check if the character is a digit\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(str):\n # Initialize count to 0\n count = 0\n \n # Iterate through each character in the string\n for char in str:\n # Check if the character is a digit\n if char.isdigit():\n # Increment count if character is a digit\n count += 1\n \n # Return the total count of digits\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n num_count = 0\n # Iterate through each character in the string\n for char in s:\n # Check if the character is a digit\n if char.isdigit():\n num_count += 1\n return num_count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n count = 0\n # Iterate through each character in the string\n for char in s:\n # Check if the character is a digit\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n count = 0\n for char in s:\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n # Initialize counter for digits\n count = 0\n \n # Iterate through each character in the string\n for char in s:\n # Check if the character is a digit\n if char.isdigit():\n count += 1\n \n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n # Initialize counter for digits\n digit_count = 0\n \n # Iterate through each character in the string\n for char in s:\n # Check if the character is a digit\n if char.isdigit():\n digit_count += 1\n \n return digit_count", "matching_cluster_idx": 2}]}, "Mbpp/766": {"dps": 76.96261682242991, "dps_norm": 73.33333333333333, "pass@1": 88.0, "profiled": [{"solution": "def pair_wise(arr):\n \"\"\"\n Function to return a list of all pairs of consecutive items in a given list.\n \n Parameters:\n arr (list): The input list of numbers.\n \n Returns:\n list: A list of tuples, each containing a pair of consecutive numbers.\n \"\"\"\n # Initialize an empty list to store the pairs\n pairs = []\n # Loop through the list to create pairs\n for i in range(len(arr) - 1):\n pairs.append((arr[i], arr[i + 1]))\n return pairs", "matching_cluster_idx": 2}, {"solution": "def pair_wise(lst):\n \"\"\"\n Function to return a list of all pairs of consecutive items in a given list.\n \n Parameters:\n lst (list): The list to process\n \n Returns:\n list: A list of tuples with consecutive items\n \"\"\"\n return [(lst[i], lst[i+1]) for i in range(len(lst)-1)]", "matching_cluster_idx": 2}, {"solution": "def pair_wise(arr):\n # Use zip to pair each element with the next one, including the last element with None if the list is empty or has only one element\n return list(zip(arr, arr[1:]))", "matching_cluster_idx": 5}, {"solution": "def pair_wise(arr):\n \"\"\"\n Returns a list of all pairs of consecutive items in a given list.\n \n :param arr: List of integers.\n :return: List of tuples, each containing a pair of consecutive items.\n \"\"\"\n # Use zip to pair each element with the next one, including the last element with None if necessary\n return list(zip(arr, arr[1:]))", "matching_cluster_idx": 5}, {"solution": "def pair_wise(nums):\n \"\"\"\n Generate a list of tuples containing pairs of consecutive items from the input list.\n \n Args:\n nums: A list of integers.\n \n Returns:\n A list of tuples, each containing a pair of consecutive items from the input list.\n \"\"\"\n # Use zip to pair each element with its successor and convert the result to a list of tuples\n result = list(zip(nums, nums[1:]))\n return result", "matching_cluster_idx": 5}, {"solution": "def pair_wise(arr):\n # Create pairs of consecutive items using zip and list slicing\n return list(zip(arr, arr[1:]))", "matching_cluster_idx": 5}, {"solution": "def pair_wise(arr):\n \"\"\"\n Returns a list of all pairs of consecutive items in a given list.\n \n Parameters:\n arr (list): The input list containing numerical elements.\n \n Returns:\n list: A list of tuples, each containing a pair of consecutive items from the input list.\n \"\"\"\n # Using list comprehension to create pairs of consecutive items\n return [(arr[i], arr[i+1]) for i in range(len(arr)-1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n \"\"\"\n Generates a list of tuples containing pairs of consecutive items from the given list.\n \n :param lst: List of elements.\n :return: List of tuples, each containing a pair of consecutive items.\n \"\"\"\n # Generate pairs of consecutive items\n return [(lst[i], lst[i+1]) for i in range(len(lst) - 1)]", "matching_cluster_idx": 2}, {"solution": "def pair_wise(lst):\n \"\"\"\n Returns a list of tuples with each tuple containing a pair of consecutive items from the input list.\n \n :param lst: List of items\n :return: List of tuples with consecutive items\n \"\"\"\n # Generate pairs of consecutive items\n return [(lst[i], lst[i+1]) for i in range(len(lst)-1)]", "matching_cluster_idx": 2}, {"solution": "def pair_wise(arr):\n \"\"\"\n Function to return a list of all pairs of consecutive items in a given list.\n \n Parameters:\n arr (list): The input list of integers.\n \n Returns:\n list: A list of tuples, where each tuple contains a pair of consecutive items from the input list.\n \"\"\"\n # Check if the list is empty or has only one element\n if len(arr) <= 1:\n return []\n \n # Generate pairs of consecutive items\n pairs = [(arr[i], arr[i+1]) for i in range(len(arr) - 1)]\n return pairs", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n \"\"\"\n Returns a list of tuples containing pairs of consecutive items from the given list.\n \n Args:\n lst : List of elements\n \n Returns:\n List of tuples containing pairs of consecutive items.\n \"\"\"\n # Use zip to pair up consecutive elements\n return list(zip(lst[:-1], lst[1:]))", "matching_cluster_idx": 4}, {"solution": "def pair_wise(arr):\n \"\"\"\n Returns a list of all pairs of consecutive items in a given list.\n \n Parameters:\n arr (list): The input list of elements.\n \n Returns:\n list: A list of tuples where each tuple contains a pair of consecutive items.\n \"\"\"\n # Initialize an empty list to store the result\n result = []\n # Loop through the array up to the second last element\n for i in range(len(arr) - 1):\n # Append the tuple of the current and next item to the result list\n result.append((arr[i], arr[i+1]))\n return result", "matching_cluster_idx": 2}, {"solution": "def pair_wise(lst):\n \"\"\"\n This function takes a list and returns a list of tuples containing all pairs of consecutive items.\n \n Args:\n lst : List of elements\n \n Returns:\n List of tuples with each tuple containing a pair of consecutive items from the input list\n \"\"\"\n # Generate pairs of consecutive items using zip and list slicing\n return list(zip(lst, lst[1:]))", "matching_cluster_idx": 5}, {"solution": "def pair_wise(arr):\n \"\"\"\n Generates a list of tuples containing all consecutive pairs from the given list.\n \n :param arr: List of elements.\n :return: List of tuples, each containing a pair of consecutive elements.\n \"\"\"\n # Check if the list has fewer than 2 elements, in which case return an empty list.\n if len(arr) < 2:\n return []\n \n # Use list comprehension to generate pairs of consecutive elements.\n return [(arr[i], arr[i+1]) for i in range(len(arr) - 1)]", "matching_cluster_idx": 2}, {"solution": "def pair_wise(arr):\n # Generate pairs of consecutive items using list comprehension\n return [(arr[i], arr[i + 1]) for i in range(len(arr) - 1)]", "matching_cluster_idx": 2}, {"solution": "def pair_wise(arr):\n \"\"\"\n Generates a list of tuples where each tuple contains a pair of consecutive items from the input list.\n \n :param arr: List of integers from which to generate consecutive pairs.\n :return: List of tuples, each containing a pair of consecutive items.\n \"\"\"\n # Generate pairs by zipping the original list with itself offset by one\n return list(zip(arr, arr[1:]))", "matching_cluster_idx": 5}, {"solution": "def pair_wise(nums):\n \"\"\"\n Generates a list of tuples containing consecutive pairs from the input list.\n \n Args:\n nums: List of numbers\n \n Returns:\n A list of tuples where each tuple contains a pair of consecutive numbers.\n \"\"\"\n # Generate consecutive pairs and return them as a list of tuples\n return [(nums[i], nums[i+1]) for i in range(len(nums)-1)]", "matching_cluster_idx": 2}, {"solution": "def pair_wise(nums):\n # Initialize an empty list to store the pairs\n result = []\n \n # Iterate through the list, stopping one element before the end\n for i in range(len(nums) - 1):\n # Append the current element and the next element as a tuple to the result list\n result.append((nums[i], nums[i + 1]))\n \n return result", "matching_cluster_idx": 2}, {"solution": "def pair_wise(nums):\n \"\"\"\n This function takes a list of integers and returns a list of tuples where each tuple contains \n a pair of consecutive items from the input list.\n \n Args:\n nums : List[int] - A list of integers.\n \n Returns:\n List[Tuple[int, int]] - A list of tuples with pairs of consecutive items.\n \"\"\"\n return list(zip(nums, nums[1:]))", "matching_cluster_idx": 5}, {"solution": "def pair_wise(lst):\n \"\"\"\n Returns a list of all pairs of consecutive items in a given list.\n \n Parameters:\n lst (list): The input list of integers.\n \n Returns:\n list: A list of tuples where each tuple contains a pair of consecutive items.\n \"\"\"\n # Create pairs of consecutive elements using zip\n pairs = list(zip(lst, lst[1:]))\n return pairs", "matching_cluster_idx": 5}]}, "Mbpp/775": {"dps": 92.96, "dps_norm": 70.0, "pass@1": 100.0, "profiled": [{"solution": "def odd_position(arr):\n # Iterate through the array, checking only odd indices\n for i in range(1, len(arr), 2):\n # If the number at an odd index is not odd, return False\n if arr[i] % 2 == 0:\n return False\n # If all odd indices contain odd numbers, return True\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(arr):\n # Check each odd index for odd numbers\n for i in range(1, len(arr), 2):\n if arr[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(arr):\n # Iterate through the list, checking only odd indices\n for i in range(1, len(arr), 2):\n # If the number at the odd index is not odd, return False\n if arr[i] % 2 == 0:\n return False\n # If all numbers at odd indices are odd, return True\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(arr):\n # Check if every element at an odd index is odd\n for i in range(1, len(arr), 2):\n if arr[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(arr):\n # Check if every element at an odd index is odd\n return all(arr[i] % 2 != 0 for i in range(1, len(arr), 2))", "matching_cluster_idx": 2}, {"solution": "def odd_position(arr):\n # Iterate through the list, checking only odd indices\n for i in range(1, len(arr), 2):\n # If the number at the odd index is not odd, return False\n if arr[i] % 2 == 0:\n return False\n # If all numbers at odd indices are odd, return True\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(arr):\n # Check each element at odd index to ensure it's odd\n for i in range(1, len(arr), 2):\n if arr[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(arr):\n # Iterate through the list, checking only odd indices\n for i in range(1, len(arr), 2):\n # If the number at the odd index is not odd, return False\n if arr[i] % 2 == 0:\n return False\n # If all odd indices contain odd numbers, return True\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(arr):\n # Iterate through the list, checking only odd indices\n for i in range(1, len(arr), 2):\n # If the number at the current odd index is not odd, return False\n if arr[i] % 2 == 0:\n return False\n # If all numbers at odd indices are odd, return True\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(arr):\n # Check if every element at an odd index is odd\n for i in range(1, len(arr), 2):\n if arr[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(arr):\n # Iterate through the list, checking only odd indices\n for i in range(1, len(arr), 2):\n # If the number at the odd index is not odd, return False\n if arr[i] % 2 == 0:\n return False\n # If all numbers at odd indices are odd, return True\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(arr):\n # Iterate over the list, checking only elements at odd indices\n for i in range(1, len(arr), 2):\n # If the element at the current odd index is not odd, return False\n if arr[i] % 2 == 0:\n return False\n # If all elements at odd indices are odd, return True\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(arr):\n # Check each element at an odd index to see if it is odd\n for i in range(1, len(arr), 2):\n if arr[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(arr):\n # Iterate through the list, checking only odd indices\n for i in range(1, len(arr), 2):\n # If the number at an odd index is not odd, return False\n if arr[i] % 2 == 0:\n return False\n # If all numbers at odd indices are odd, return True\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(arr):\n # Check if every element at an odd index is odd\n for i in range(1, len(arr), 2):\n if arr[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(arr):\n # Iterate over the list, checking every odd index\n for i in range(1, len(arr), 2):\n # If the number at the odd index is not odd, return False\n if arr[i] % 2 == 0:\n return False\n # If all odd indices have odd numbers, return True\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(arr):\n # Iterate through the list, checking only odd indices\n for i in range(1, len(arr), 2):\n # If an element at an odd index is not odd, return False\n if arr[i] % 2 == 0:\n return False\n # If all elements at odd indices are odd, return True\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n # Check each element at odd index positions\n for index in range(1, len(lst), 2):\n if lst[index] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(arr):\n # Iterate through the list, checking only odd indices\n for i in range(1, len(arr), 2):\n # If the number at the odd index is not odd, return False\n if arr[i] % 2 == 0:\n return False\n # If all numbers at odd indices are odd, return True\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(arr):\n # Check if every element at an odd index is odd\n for i in range(1, len(arr), 2):\n if arr[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}]}, "Mbpp/777": {"dps": null, "dps_norm": null, "pass@1": 0.0, "profiled": []}, "Mbpp/781": {"dps": 90.66929133858267, "dps_norm": 57.0, "pass@1": 95.0, "profiled": [{"solution": "def count_divisors(n):\n # Initialize count of divisors\n count = 0\n \n # Loop from 1 to n to find all divisors of n\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n \n # Check if the count of divisors is even\n return count % 2 == 0", "matching_cluster_idx": 1}, {"solution": "def count_divisors(n):\n # Initialize count of divisors\n count = 0\n \n # Loop through all numbers from 1 to n\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n \n # Check if the count of divisors is even\n return count % 2 == 0", "matching_cluster_idx": 1}, {"solution": "def count_divisors(n):\n # Initialize count of divisors\n count = 0\n \n # Check for divisors from 1 to n\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n \n # Return True if count of divisors is even, otherwise False\n return count % 2 == 0", "matching_cluster_idx": 1}, {"solution": "def count_divisors(n):\n # Initialize divisor count to 0\n divisor_count = 0\n \n # Iterate over possible divisors from 1 to n\n for i in range(1, n + 1):\n if n % i == 0:\n divisor_count += 1\n \n # Check if the count of divisors is even\n return divisor_count % 2 == 0", "matching_cluster_idx": 1}, {"solution": "def count_divisors(n):\n # Initialize a set to store divisors, starting with 1 and the number itself\n divisors = {1, n}\n \n # Loop from 2 to the square root of n to find all divisors\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n # If i is a divisor, add both i and n/i to the set\n divisors.add(i)\n divisors.add(n // i)\n \n # Return True if the number of divisors is even, False otherwise\n return len(divisors) % 2 == 0", "matching_cluster_idx": 3}, {"solution": "def count_divisors(n):\n # Initialize count to 0\n count = 0\n \n # Loop through all numbers from 1 to n\n for i in range(1, n + 1):\n # If i is a divisor of n, increment count\n if n % i == 0:\n count += 1\n \n # Check if the count of divisors is even\n return count % 2 == 0", "matching_cluster_idx": 1}, {"solution": "def count_divisors(n):\n # Initialize count of divisors\n count = 0\n \n # Loop to find divisors\n for i in range(1, int(n ** 0.5) + 1):\n if n % i == 0:\n # If divisors are equal, count only once\n if n // i == i:\n count += 1\n else:\n # Count both divisors\n count += 2\n \n # Check if count is even\n return count % 2 == 0", "matching_cluster_idx": 4}, {"solution": "def count_divisors(n):\n # Initialize divisor count\n count = 0\n # Loop through possible divisors\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n # If divisors are equal, count only once\n if n // i == i:\n count += 1\n else:\n # Count both i and n//i\n count += 2\n # Check if count of divisors is even\n return count % 2 == 0", "matching_cluster_idx": 4}, {"solution": "def count_divisors(n):\n # Initialize divisor count to 0\n divisor_count = 0\n \n # Iterate through all possible divisors\n for i in range(1, n + 1):\n if n % i == 0:\n divisor_count += 1\n \n # Check if the count of divisors is even\n return divisor_count % 2 == 0", "matching_cluster_idx": 1}, {"solution": "def count_divisors(n):\n # Initialize count of divisors\n count = 0\n \n # Loop through numbers from 1 to n to find divisors\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n \n # Check if the count of divisors is even\n return count % 2 == 0", "matching_cluster_idx": 1}, {"solution": "def count_divisors(n):\n # Initialize count to 0\n count = 0\n \n # Iterate through all numbers from 1 to n\n for i in range(1, n + 1):\n # If n is divisible by i, increment count\n if n % i == 0:\n count += 1\n \n # Check if the count of divisors is even\n return count % 2 == 0", "matching_cluster_idx": 1}, {"solution": "def count_divisors(n):\n # Initialize divisor count\n count = 0\n \n # Loop through possible divisors\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n # If divisors are equal, count only once\n if n // i == i:\n count += 1\n else:\n # Count both divisors\n count += 2\n \n # Check if count of divisors is even\n return count % 2 == 0", "matching_cluster_idx": 4}, {"solution": "def count_divisors(n):\n # Initialize count of divisors\n count = 0\n \n # Loop to check for divisors from 1 to n\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n \n # Check if count of divisors is even\n return count % 2 == 0", "matching_cluster_idx": 1}, {"solution": "def count_divisors(n):\n # Initialize count of divisors\n count = 0\n \n # Loop through possible divisors\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n # If divisors are equal, count only once\n if n // i == i:\n count += 1\n else:\n # Count both divisors\n count += 2\n \n # Check if count of divisors is even\n return count % 2 == 0", "matching_cluster_idx": 4}, {"solution": "def count_divisors(n):\n # Initialize count of divisors\n count = 0\n \n # Loop to count divisors\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n \n # Check if count of divisors is even\n return count % 2 == 0", "matching_cluster_idx": 1}, {"solution": "def count_divisors(n):\n # Initialize count of divisors\n count = 0\n \n # Loop to count divisors\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n # If divisors are equal, count only once\n if n // i == i:\n count += 1\n else:\n # Count both divisors\n count += 2\n \n # Check if count of divisors is even\n return count % 2 == 0", "matching_cluster_idx": 4}, {"solution": "def count_divisors(n):\n # Initialize divisor count to 0\n count = 0\n \n # Loop through all numbers from 1 to n to find divisors\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n \n # Check if the count of divisors is even\n return count % 2 == 0", "matching_cluster_idx": 1}, {"solution": "def count_divisors(n):\n # Initialize a list to hold divisors\n divisors = []\n \n # Loop through possible divisors from 1 to n\n for i in range(1, n + 1):\n if n % i == 0:\n # If i is a divisor of n, add it to the list\n divisors.append(i)\n \n # Check if the count of divisors is even\n return len(divisors) % 2 == 0", "matching_cluster_idx": 1}, {"solution": "def count_divisors(n):\n # Initialize divisor count\n count = 0\n \n # Iterate through all numbers from 1 to n\n for i in range(1, n + 1):\n # If i is a divisor of n, increment count\n if n % i == 0:\n count += 1\n \n # Check if the count is even\n return count % 2 == 0", "matching_cluster_idx": 1}, {"solution": "def count_divisors(n):\n # Initialize divisor count\n count = 0\n \n # Iterate from 1 to n to find all divisors\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n \n # Check if the count of divisors is even\n return count % 2 == 0", "matching_cluster_idx": 1}]}, "Mbpp/800": {"dps": 91.34328358208955, "dps_norm": 96.0, "pass@1": 93.0, "profiled": [{"solution": "def remove_all_spaces(input_string):\n # Use the replace method to eliminate all spaces from the input string\n no_space_string = input_string.replace(\" \", \"\")\n return no_space_string", "matching_cluster_idx": 3}, {"solution": "def remove_all_spaces(input_string):\n # Remove all whitespaces from the input string\n no_spaces_string = input_string.replace(\" \", \"\")\n return no_spaces_string", "matching_cluster_idx": 3}, {"solution": "def remove_all_spaces(input_string):\n # Using the replace method to remove all spaces from the input string\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n # Remove all whitespaces from the input string\n result = input_string.replace(\" \", \"\")\n return result", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n # Use the replace method to remove all spaces from the string\n return input_string.replace(' ', '')", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n # Use the replace method to eliminate all spaces from the input_string\n no_space_string = input_string.replace(\" \", \"\")\n return no_space_string", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(s):\n # Using the replace method to remove all spaces\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(s):\n # Use the replace method to remove all spaces from the string\n return s.replace(' ', '')", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n # Use the replace method to remove all whitespace characters\n result = input_string.replace(\" \", \"\")\n return result", "matching_cluster_idx": 3}, {"solution": "def remove_all_spaces(input_string):\n # Use the replace method to eliminate all spaces from the input string\n result_string = input_string.replace(\" \", \"\")\n return result_string", "matching_cluster_idx": 3}, {"solution": "def remove_all_spaces(s):\n # Use the replace method to remove all whitespaces\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(s):\n # Use the replace method to eliminate spaces from the string\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n # Using the replace method to eliminate spaces\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(s):\n # Use the replace method to remove all spaces from the string\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n # Using the replace method to remove all spaces\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n # Remove all whitespaces from the input string\n result = input_string.replace(\" \", \"\")\n return result", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(s):\n # Use the replace method to eliminate all whitespace characters\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n # Use the replace method to remove all spaces from the input string\n return input_string.replace(' ', '')", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n # Using the replace method to remove all whitespaces\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n # Use the replace method to remove all spaces from the input string\n return input_string.replace(' ', '')", "matching_cluster_idx": 4}]}, "Mbpp/805": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def max_sum_list(list_of_lists):\n # Initialize max_list and max_sum\n max_list = []\n max_sum = float('-inf')\n \n # Iterate through each list in the list_of_lists\n for lst in list_of_lists:\n # Calculate the sum of the current list\n current_sum = sum(lst)\n # Update max_list and max_sum if the current list has a greater sum\n if current_sum > max_sum:\n max_sum = current_sum\n max_list = lst\n \n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n \"\"\"\n Returns the list in a list of lists whose sum of elements is the highest.\n \n Parameters:\n lists (list of lists): A list containing multiple lists of numbers.\n \n Returns:\n list: The list with the highest sum of elements.\n \"\"\"\n # Calculate the sum of each sublist and return the one with the maximum sum\n return max(lists, key=sum)", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n \"\"\"\n Returns the list in a list of lists whose sum of elements is the highest.\n \n :param lists: List of lists containing integers\n :return: List with the highest sum of elements\n \"\"\"\n # Find the list with the maximum sum of elements\n max_list = max(lists, key=sum)\n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n \"\"\"\n Returns the list in a list of lists whose sum of elements is the highest.\n \n :param lists: List of lists containing integers\n :return: The list with the highest sum of elements\n \"\"\"\n # Use max function with a key that calculates the sum of each list\n return max(lists, key=sum)", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(list_of_lists):\n \"\"\"\n Finds and returns the list within a list of lists that has the highest sum of elements.\n \n :param list_of_lists: List of lists containing integer elements.\n :return: The list from the list of lists with the highest sum of elements.\n \"\"\"\n # Using max function with key parameter set to sum to find the list with the highest sum\n return max(list_of_lists, key=sum)", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n \"\"\"\n Returns the list in a list of lists whose sum of elements is the highest.\n \n Args:\n lists: A list of lists containing integer elements.\n \n Returns:\n A list whose sum of elements is the highest among all lists.\n \"\"\"\n # Find and return the list with the maximum sum of elements\n return max(lists, key=sum)", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n \"\"\"\n Returns the list within a list of lists where the sum of its elements is the highest.\n \n :param lists: List of lists containing integers.\n :return: A list whose sum of elements is the highest among all lists.\n \"\"\"\n # Using max function with key parameter to find the list with the maximum sum\n return max(lists, key=sum)", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n \"\"\"\n Returns the list in a list of lists whose sum of elements is the highest.\n\n Parameters:\n lists (list of lists): A list containing multiple lists of numbers.\n\n Returns:\n list: The list from the input whose sum of elements is the highest.\n \"\"\"\n return max(lists, key=sum)", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(list_of_lists):\n # Use the max function with a key that calculates the sum of each sublist\n return max(list_of_lists, key=sum)", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n \"\"\"\n Returns the list from the input list of lists with the maximum sum of elements.\n \"\"\"\n # Find the list with the maximum sum using max function with key=sum\n max_list = max(lists, key=sum)\n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(list_of_lists):\n \"\"\"\n Returns the list from the given list of lists where the sum of its elements is the highest.\n \n Args:\n list_of_lists (list of lists of int): A list containing lists of integers.\n \n Returns:\n list of int: The list with the highest sum of elements.\n \"\"\"\n # Initialize maximum sum and the list with the maximum sum\n max_sum = float('-inf')\n max_list = []\n \n # Iterate through each list in the list of lists\n for sublist in list_of_lists:\n # Calculate the sum of the current sublist\n current_sum = sum(sublist)\n # Update max_sum and max_list if the current sum is greater than max_sum\n if current_sum > max_sum:\n max_sum = current_sum\n max_list = sublist\n \n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n # Use max function with a key that computes the sum of elements in each list\n return max(lists, key=sum)", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(list_of_lists):\n \"\"\"\n This function returns the list within a list of lists whose sum of elements is the highest.\n \n :param list_of_lists: List of lists containing integers.\n :return: A list whose sum is the highest among all lists.\n \"\"\"\n # Initialize the max_sum to a very small number and the list with max_sum as an empty list\n max_sum = float('-inf')\n max_list = []\n \n # Iterate through each list in the list_of_lists\n for lst in list_of_lists:\n # Calculate the sum of the current list\n current_sum = sum(lst)\n # Check if this sum is greater than the max_sum found so far\n if current_sum > max_sum:\n max_sum = current_sum\n max_list = lst\n \n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(list_of_lists):\n \"\"\"\n Returns the list from a list of lists whose sum of elements is the highest.\n \n Args:\n list_of_lists (list of lists): A list containing multiple lists of integers.\n \n Returns:\n list: The list from the input whose sum of elements is the highest.\n \"\"\"\n # Initialize a variable to keep track of the list with the highest sum found so far\n max_list = None\n # Initialize a variable to keep track of the highest sum found so far\n max_sum = float('-inf')\n \n for sublist in list_of_lists:\n # Calculate the sum of the current sublist\n current_sum = sum(sublist)\n # Update the max_list and max_sum if the current sum is greater than max_sum\n if current_sum > max_sum:\n max_sum = current_sum\n max_list = sublist\n \n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(list_of_lists):\n \"\"\"\n Returns the list within a list of lists whose sum of elements is the highest.\n \n Parameters:\n list_of_lists (list of list of int): The list containing lists of integers.\n \n Returns:\n list: The list with the highest sum of elements.\n \"\"\"\n return max(list_of_lists, key=sum)", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(list_of_lists):\n # Find the list with the maximum sum of elements\n max_list = max(list_of_lists, key=sum)\n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(list_of_lists):\n # Find the list with the maximum sum of elements\n max_list = max(list_of_lists, key=sum)\n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(list_of_lists):\n # Initialize maximum sum and the corresponding list\n max_sum = float('-inf')\n max_list = []\n \n # Iterate through each list in the list of lists\n for lst in list_of_lists:\n # Calculate the sum of the current list\n current_sum = sum(lst)\n # Update max_sum and max_list if the current list's sum is greater\n if current_sum > max_sum:\n max_sum = current_sum\n max_list = lst\n \n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(list_of_lists):\n return max(list_of_lists, key=sum)", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n # Find the list with the maximum sum of elements\n max_list = max(lists, key=sum)\n return max_list", "matching_cluster_idx": 4}]}, "Mbpp/808": {"dps": 86.14035087719299, "dps_norm": 96.66666666666667, "pass@1": 100.0, "profiled": [{"solution": "def check_K(test_tup, K):\n # Check if K is in the tuple\n res = K in test_tup\n return res", "matching_cluster_idx": 4}, {"solution": "def check_K(tup, k):\n # Check if k is in the tuple\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n # Check if k is in the tuple\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(test_tup, K):\n # Check if K is in the tuple\n return K in test_tup", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n # Check if k is in the tuple\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n # Check if k is in the tuple\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(test_tup, K):\n # Check if the tuple contains the value K\n return K in test_tup", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n # Check if k is in the tuple\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n # Check if k is in the tuple\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n # Check if k is in the tuple\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(t, k):\n # Check if the tuple contains the specified value k\n return k in t", "matching_cluster_idx": 5}, {"solution": "def check_K(test_tup, K):\n # Check if K is in the tuple\n res = K in test_tup\n return res", "matching_cluster_idx": 4}, {"solution": "def check_K(tup, k):\n # Check if k is in the tuple\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(t, k):\n # Check if k is in the tuple\n return k in t", "matching_cluster_idx": 5}, {"solution": "def check_K(test_tup, K):\n # Check if the tuple contains the specified element K\n res = K in test_tup\n return res", "matching_cluster_idx": 4}, {"solution": "def check_K(test_tup, K):\n # Check if the tuple contains the element K\n return K in test_tup", "matching_cluster_idx": 5}, {"solution": "def check_K(test_tup, K):\n # Check if K is in the tuple\n res = K in test_tup\n return res", "matching_cluster_idx": 4}, {"solution": "def check_K(test_tup, K):\n # Check if K is in the tuple\n return K in test_tup", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n # Check if k is in the tuple\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n # Check if the element k is in the tuple\n return k in tup", "matching_cluster_idx": 5}]}}} \ No newline at end of file diff --git a/results/evalperf/Qwen--Qwen2.5-32B-Instruct_vllm_temp_1.0_evalperf_results.brief.json b/results/evalperf/Qwen--Qwen2.5-32B-Instruct_vllm_temp_1.0_evalperf_results.brief.json new file mode 100644 index 0000000..26975eb --- /dev/null +++ b/results/evalperf/Qwen--Qwen2.5-32B-Instruct_vllm_temp_1.0_evalperf_results.brief.json @@ -0,0 +1 @@ +{"date": "2024-10-19 16:28", "config": {"n_samples": 100, "temperature": 1.0, "min_correct": 10, "max_profile": 20}, "summary": {"dps": 83.54712283112897, "dps_norm": 78.3588319852899, "pass@1": 87.5677966101695}, "eval": {"HumanEval/9": {"dps": 83.9589905362776, "dps_norm": 91.11111111111111, "pass@1": 100.0, "profiled": [{"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\"From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n\n Args:\n numbers (List[int]): A list of integers.\n\n Returns:\n List[int]: A list of integers representing the rolling maximum up to each index in the input list.\n \"\"\"\n if not numbers:\n return []\n \n max_so_far = numbers[0]\n result = []\n\n for number in numbers:\n if number > max_so_far:\n max_so_far = number\n result.append(max_so_far)\n \n return result", "matching_cluster_idx": 8}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\"From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n\n Args:\n numbers (List[int]): A list of integers.\n\n Returns:\n List[int]: A list of integers representing the rolling maximums.\n \"\"\"\n if not numbers:\n return []\n\n result = [numbers[0]]\n current_max = numbers[0]\n for number in numbers[1:]:\n if number > current_max:\n current_max = number\n result.append(current_max)\n \n return result", "matching_cluster_idx": 7}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n \"\"\"\n if not numbers:\n return []\n \n max_so_far = numbers[0]\n result = []\n\n for number in numbers:\n if number > max_so_far:\n max_so_far = number\n result.append(max_so_far)\n\n return result", "matching_cluster_idx": 8}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\"From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\"\"\"\n if not numbers:\n return []\n \n max_so_far = numbers[0]\n result = [max_so_far]\n \n for num in numbers[1:]:\n if num > max_so_far:\n max_so_far = num\n result.append(max_so_far)\n \n return result", "matching_cluster_idx": 7}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n \"\"\"\n if not numbers:\n return []\n \n max_list = [numbers[0]]\n current_max = numbers[0]\n \n for number in numbers[1:]:\n if number > current_max:\n current_max = number\n max_list.append(current_max)\n \n return max_list", "matching_cluster_idx": 7}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\"From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\"\"\"\n if not numbers:\n return []\n \n max_list = [numbers[0]] # Initialize the rolling max list with the first element\n current_max = numbers[0] # Initialize current_max with the first element\n \n for num in numbers[1:]:\n if num > current_max:\n current_max = num # Update current_max if the current number is greater\n max_list.append(current_max) # Append the current_max to the max_list\n \n return max_list", "matching_cluster_idx": 7}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n \"\"\"\n if not numbers:\n return []\n \n max_so_far = numbers[0]\n result = []\n \n for number in numbers:\n if number > max_so_far:\n max_so_far = number\n result.append(max_so_far)\n \n return result", "matching_cluster_idx": 8}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\"From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\"\"\"\n if not numbers:\n return []\n \n result = [numbers[0]]\n for number in numbers[1:]:\n result.append(max(result[-1], number))\n return result", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\"From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n \n Args:\n numbers (List[int]): The list of integers.\n \n Returns:\n List[int]: A list of rolling maximums.\n \"\"\"\n if not numbers:\n return []\n \n max_so_far = numbers[0]\n rolling_maxes = [max_so_far]\n \n for num in numbers[1:]:\n if num > max_so_far:\n max_so_far = num\n rolling_maxes.append(max_so_far)\n \n return rolling_maxes", "matching_cluster_idx": 7}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\"From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\"\"\"\n if not numbers:\n return []\n\n result = [numbers[0]]\n current_max = numbers[0]\n\n for number in numbers[1:]:\n if number > current_max:\n current_max = number\n result.append(current_max)\n\n return result", "matching_cluster_idx": 7}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\"From a given list of integers, generate a list of rolling maximum element found until the given moment in the sequence.\n\n Args:\n numbers: List of integers.\n\n Returns:\n A list of rolling maximum integers found until each moment in the sequence.\n \"\"\"\n if not numbers:\n return []\n \n result = []\n current_max = numbers[0]\n \n for number in numbers:\n if number > current_max:\n current_max = number\n result.append(current_max)\n \n return result", "matching_cluster_idx": 8}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\"From a given list of integers, generate a list of rolling maximum element found until the given moment\n in the sequence.\n\n Args:\n numbers (List[int]): The input list of integers.\n\n Returns:\n List[int]: The list of rolling maximums.\n\n Examples:\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n \n max_list = [numbers[0]]\n current_max = numbers[0]\n \n for number in numbers[1:]:\n if number > current_max:\n current_max = number\n max_list.append(current_max)\n \n return max_list", "matching_cluster_idx": 7}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\"From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\"\"\"\n if not numbers:\n return []\n \n max_list = [numbers[0]]\n current_max = numbers[0]\n \n for number in numbers[1:]:\n if number > current_max:\n current_max = number\n max_list.append(current_max)\n \n return max_list", "matching_cluster_idx": 8}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\"From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n\n Args:\n numbers: A list of integers.\n\n Returns:\n A list of integers representing the rolling maximums.\n \"\"\"\n if not numbers:\n return []\n\n max_val = numbers[0]\n result = [max_val]\n\n for number in numbers[1:]:\n if number > max_val:\n max_val = number\n result.append(max_val)\n\n return result", "matching_cluster_idx": 8}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\"From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n \"\"\"\n if not numbers:\n return []\n\n max_list = [numbers[0]]\n current_max = numbers[0]\n\n for number in numbers[1:]:\n if number > current_max:\n current_max = number\n max_list.append(current_max)\n\n return max_list", "matching_cluster_idx": 7}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\"From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n \"\"\"\n if not numbers:\n return []\n \n result = [numbers[0]]\n current_max = numbers[0]\n for number in numbers[1:]:\n if number > current_max:\n current_max = number\n result.append(current_max)\n \n return result", "matching_cluster_idx": 7}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until the given moment\n in the sequence.\n \"\"\"\n if not numbers:\n return []\n\n max_list = [numbers[0]]\n current_max = numbers[0]\n\n for number in numbers[1:]:\n if number > current_max:\n current_max = number\n max_list.append(current_max)\n\n return max_list", "matching_cluster_idx": 7}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\"From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n\n max_list = [numbers[0]]\n current_max = numbers[0]\n for number in numbers[1:]:\n if number > current_max:\n current_max = number\n max_list.append(current_max)\n \n return max_list", "matching_cluster_idx": 7}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\"From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n \"\"\"\n if not numbers:\n return []\n \n max_so_far = numbers[0]\n result = []\n\n for number in numbers:\n if number > max_so_far:\n max_so_far = number\n result.append(max_so_far)\n \n return result", "matching_cluster_idx": 8}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\"From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n \n result = [numbers[0]]\n current_max = numbers[0]\n \n for number in numbers[1:]:\n if number > current_max:\n current_max = number\n result.append(current_max)\n \n return result", "matching_cluster_idx": 7}]}, "HumanEval/0": {"dps": 52.325581395348834, "dps_norm": 57.142857142857146, "pass@1": 100.0, "profiled": [{"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n \"\"\"\n # Sort the list to make it easier to find close elements\n sorted_numbers = sorted(numbers)\n \n # Iterate through the sorted list to find if any adjacent elements are closer than the threshold\n for i in range(len(sorted_numbers) - 1):\n if abs(sorted_numbers[i] - sorted_numbers[i + 1]) < threshold:\n return True\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n \"\"\"\n # Sort the list to make comparison easier\n sorted_numbers = sorted(numbers)\n \n # Compare each adjacent pair in the sorted list\n for i in range(len(sorted_numbers) - 1):\n if sorted_numbers[i + 1] - sorted_numbers[i] < threshold:\n return True\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n # Sort the list to bring closer numbers next to each other\n sorted_numbers = sorted(numbers)\n \n # Check the difference between adjacent numbers\n for i in range(len(sorted_numbers) - 1):\n if sorted_numbers[i + 1] - sorted_numbers[i] < threshold:\n return True\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\"\n Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n\n :param numbers: List of numbers.\n :param threshold: Threshold value.\n :return: True if there are any two numbers closer than the threshold, False otherwise.\n \"\"\"\n numbers.sort() # Sort the numbers to compare adjacent elements\n for i in range(len(numbers) - 1):\n if numbers[i+1] - numbers[i] < threshold:\n return True\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\"Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n \"\"\"\n # Sort the list to make it easier to find closest elements\n sorted_numbers = sorted(numbers)\n \n # Iterate through the sorted list and check the difference between consecutive elements\n for i in range(1, len(sorted_numbers)):\n if sorted_numbers[i] - sorted_numbers[i - 1] < threshold:\n return True\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n \"\"\"\n # Sort the list to bring closer numbers adjacent to each other\n numbers.sort()\n \n # Iterate through the list to check if any adjacent numbers are closer than the threshold\n for i in range(len(numbers) - 1):\n if abs(numbers[i] - numbers[i + 1]) < threshold:\n return True\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n\n Args:\n numbers: A list of floating-point numbers.\n threshold: A floating-point number representing the maximum allowed distance between any two numbers.\n\n Returns:\n A boolean value indicating if there are any two numbers in the list closer to each other than the given threshold.\n\n Examples:\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n numbers.sort() # Sorting the numbers to make it easier to find close elements\n for i in range(len(numbers) - 1):\n if numbers[i + 1] - numbers[i] < threshold:\n return True\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n \"\"\"\n # Sort the list to make comparison easier\n sorted_numbers = sorted(numbers)\n \n # Iterate through the sorted list to check the difference between consecutive elements\n for i in range(1, len(sorted_numbers)):\n if sorted_numbers[i] - sorted_numbers[i-1] < threshold:\n return True\n \n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n \"\"\"\n # Sort the list to make it easier to check closeness\n numbers.sort()\n \n # Iterate through the list to check the difference between consecutive numbers\n for i in range(len(numbers) - 1):\n if abs(numbers[i] - numbers[i + 1]) < threshold:\n return True\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\"Check if in the given list of numbers, any two numbers are closer to each other than the given threshold.\n\n :param numbers: List of floating-point numbers.\n :param threshold: A floating-point number representing the maximum allowed distance between any two numbers.\n :return: True if any two numbers are closer to each other than the threshold, otherwise False.\n \"\"\"\n # Sort the list to ensure we only need to check adjacent elements for the condition.\n numbers.sort()\n \n # Iterate through the list and check if any two adjacent elements are closer than the threshold.\n for i in range(len(numbers) - 1):\n if abs(numbers[i] - numbers[i + 1]) < threshold:\n return True\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n \"\"\"\n # Sort the list of numbers to bring closer numbers adjacent to each other\n numbers.sort()\n \n # Iterate through the sorted list to check the difference between adjacent elements\n for i in range(len(numbers) - 1):\n if abs(numbers[i] - numbers[i + 1]) < threshold:\n return True\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n \"\"\"\n # Sort the list to make it easier to find close elements\n numbers.sort()\n\n # Iterate through the sorted list to check for any two consecutive elements\n # that are closer than the given threshold\n for i in range(len(numbers) - 1):\n if abs(numbers[i] - numbers[i + 1]) < threshold:\n return True\n\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n \"\"\"\n # Sort the list to make sure that any two close numbers will be adjacent\n numbers.sort()\n\n # Iterate through the list and check the difference between adjacent elements\n for i in range(len(numbers) - 1):\n if abs(numbers[i] - numbers[i + 1]) < threshold:\n return True\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\"Check if in given list of numbers, any two numbers are closer to each other than\n the given threshold.\n\n Args:\n numbers: A list of floating-point numbers.\n threshold: A floating-point number representing the distance threshold.\n\n Returns:\n A boolean indicating whether there are any two numbers in the list closer to\n each other than the threshold.\n\n Examples:\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n numbers.sort()\n for i in range(len(numbers) - 1):\n if abs(numbers[i] - numbers[i + 1]) < threshold:\n return True\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\"Check if in given list of numbers, any two numbers are closer to each other than given threshold.\"\"\"\n # Sort the list to ensure that the closest elements are adjacent\n sorted_numbers = sorted(numbers)\n \n # Iterate through the list and check if any two adjacent elements are closer than the threshold\n for i in range(len(sorted_numbers) - 1):\n if sorted_numbers[i + 1] - sorted_numbers[i] < threshold:\n return True\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in the given list of numbers, any two numbers are closer to each other\n than the given threshold.\n \"\"\"\n # First, sort the numbers to make comparison easier\n numbers.sort()\n \n # Compare each adjacent pair of numbers\n for i in range(len(numbers) - 1):\n if abs(numbers[i] - numbers[i + 1]) < threshold:\n return True\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n \"\"\"\n # Sort the list to ensure that the closest numbers are next to each other\n numbers.sort()\n\n # Iterate through the list and check if any two consecutive numbers are closer than the threshold\n for i in range(len(numbers) - 1):\n if abs(numbers[i] - numbers[i + 1]) < threshold:\n return True\n\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n \"\"\"\n # Sort the numbers to bring the closest elements next to each other\n numbers.sort()\n\n # Iterate through the list and check if any two adjacent elements are closer than the threshold\n for i in range(len(numbers) - 1):\n if abs(numbers[i] - numbers[i + 1]) < threshold:\n return True\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n \"\"\"\n # Sort the list of numbers to ensure that the elements we compare are the closest pairs\n numbers.sort()\n\n # Iterate through the sorted list and check the difference between consecutive elements\n for i in range(len(numbers) - 1):\n if numbers[i+1] - numbers[i] < threshold:\n return True\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\"Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n \n Args:\n numbers: A list of floating-point numbers.\n threshold: The threshold distance to check for closeness between elements.\n \n Returns:\n A boolean value indicating if any two elements are closer than the threshold.\n \n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n # Sort the numbers to easily find the closest pairs\n numbers.sort()\n\n # Iterate through the sorted list and check the difference between consecutive elements\n for i in range(len(numbers) - 1):\n if abs(numbers[i] - numbers[i + 1]) < threshold:\n return True\n return False", "matching_cluster_idx": 3}]}, "HumanEval/4": {"dps": 8.655063291139241, "dps_norm": 30.833333333333336, "pass@1": 100.0, "profiled": [{"solution": "from typing import List\nfrom math import fabs\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if not numbers:\n return 0.0\n \n mean_value = sum(numbers) / len(numbers)\n total_deviation = sum(fabs(x - mean_value) for x in numbers)\n \n return total_deviation / len(numbers)", "matching_cluster_idx": 3}, {"solution": "from typing import List\nfrom statistics import mean\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\"Calculate Mean Absolute Deviation around the mean of this dataset.\n Mean Absolute Deviation (MAD) is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n \n :param numbers: List of input numbers\n :return: Mean Absolute Deviation as a float\n \n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n >>> mean_absolute_deviation([5.0, 7.0, 3.0])\n 1.3333333333333333\n \"\"\"\n # Calculate the mean of the numbers\n mean_value = mean(numbers)\n # Calculate the sum of absolute differences from the mean\n total_deviation = sum(abs(x - mean_value) for x in numbers)\n # Calculate the mean of those deviations\n return total_deviation / len(numbers)", "matching_cluster_idx": 0}, {"solution": "from typing import List\nfrom statistics import mean\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n mean_value = mean(numbers)\n # Calculate the absolute differences from the mean and then take their mean.\n return mean([abs(x - mean_value) for x in numbers])", "matching_cluster_idx": 0}, {"solution": "from typing import List\nfrom statistics import mean\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if not numbers:\n return 0.0 # Return 0 if the list is empty\n\n avg = mean(numbers)\n return mean(abs(x - avg) for x in numbers)", "matching_cluster_idx": 0}, {"solution": "from typing import List\nfrom statistics import mean\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n \"\"\"\n if not numbers:\n return 0.0\n\n mean_value = mean(numbers)\n deviations = [abs(x - mean_value) for x in numbers]\n return mean(deviations)", "matching_cluster_idx": 0}, {"solution": "from typing import List\nfrom functools import reduce\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n # Calculate mean of the numbers\n mean_value = sum(numbers) / len(numbers)\n\n # Calculate the sum of absolute differences between each element and mean\n absolute_differences_sum = reduce(lambda a, b: a + abs(b - mean_value), numbers, 0)\n\n # Calculate and return the Mean Absolute Deviation\n return absolute_differences_sum / len(numbers)", "matching_cluster_idx": 3}, {"solution": "from typing import List\nfrom statistics import mean\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n \"\"\"\n if not numbers:\n return 0.0 # Avoid division by zero if the list is empty\n \n mean_value = mean(numbers)\n total_deviation = sum(abs(x - mean_value) for x in numbers)\n return total_deviation / len(numbers)", "matching_cluster_idx": 0}, {"solution": "from typing import List\nfrom statistics import mean\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\"For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if not numbers:\n return 0.0\n \n mean_value = mean(numbers)\n deviations = [abs(x - mean_value) for x in numbers]\n return mean(deviations)", "matching_cluster_idx": 0}, {"solution": "from typing import List\nfrom statistics import mean\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\"For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if not numbers: # Handle empty list case\n return 0.0\n\n mean_value = mean(numbers)\n deviations = [abs(x - mean_value) for x in numbers]\n return mean(deviations)", "matching_cluster_idx": 0}, {"solution": "from typing import List\nfrom statistics import mean\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if not numbers: # Handle empty list case\n return 0.0\n mean_value = mean(numbers)\n return sum(abs(x - mean_value) for x in numbers) / len(numbers)", "matching_cluster_idx": 0}, {"solution": "from typing import List\nfrom functools import reduce\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if not numbers:\n raise ValueError(\"Input list cannot be empty\")\n\n mean_value = sum(numbers) / len(numbers)\n # Calculate the mean absolute deviation\n mad = sum(abs(x - mean_value) for x in numbers) / len(numbers)\n return mad", "matching_cluster_idx": 5}, {"solution": "from typing import List\nfrom math import fsum\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n \n Args:\n numbers: List[float] - A list of floating-point numbers.\n\n Returns:\n float - The mean absolute deviation of the dataset.\n\n Example:\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n n = len(numbers)\n if n == 0:\n return 0.0\n mean_value = fsum(numbers) / n\n total_deviation = fsum(abs(x - mean_value) for x in numbers)\n return total_deviation / n", "matching_cluster_idx": 3}, {"solution": "from typing import List\nfrom statistics import mean\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n mean_value = mean(numbers)\n deviations = [abs(x - mean_value) for x in numbers]\n return mean(deviations)", "matching_cluster_idx": 0}, {"solution": "from typing import List\nfrom functools import reduce\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n # Calculate the mean of the dataset\n mean_value = sum(numbers) / len(numbers)\n \n # Calculate the absolute difference of each element from the mean\n absolute_diff = [abs(x - mean_value) for x in numbers]\n \n # Calculate the mean of these absolute differences\n mad = sum(absolute_diff) / len(numbers)\n \n return mad", "matching_cluster_idx": 3}, {"solution": "from typing import List\nfrom statistics import mean\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if not numbers:\n raise ValueError(\"The list of numbers cannot be empty.\")\n \n mean_value = mean(numbers)\n deviations = [abs(x - mean_value) for x in numbers]\n return mean(deviations)", "matching_cluster_idx": 0}, {"solution": "from typing import List\nfrom statistics import mean\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if not numbers:\n return 0.0\n\n mean_value = mean(numbers)\n return mean(abs(x - mean_value) for x in numbers)", "matching_cluster_idx": 0}, {"solution": "from typing import List\nfrom statistics import mean\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if not numbers:\n return 0.0\n mean_value = mean(numbers)\n mad = sum(abs(x - mean_value) for x in numbers) / len(numbers)\n return mad", "matching_cluster_idx": 0}, {"solution": "from typing import List\nfrom statistics import mean\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n # Calculate the mean of the dataset\n mean_value = mean(numbers)\n \n # Calculate the absolute deviations from the mean\n absolute_deviations = [abs(x - mean_value) for x in numbers]\n \n # Calculate the mean of the absolute deviations\n mad = mean(absolute_deviations)\n \n return mad", "matching_cluster_idx": 0}, {"solution": "from typing import List\nfrom statistics import mean\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n mean_value = mean(numbers)\n deviations = [abs(x - mean_value) for x in numbers]\n mad = mean(deviations)\n return mad", "matching_cluster_idx": 0}, {"solution": "from typing import List\nfrom statistics import mean\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n \"\"\"\n if not numbers:\n return 0.0\n\n avg = mean(numbers)\n total_diff = sum(abs(x - avg) for x in numbers)\n return total_diff / len(numbers)", "matching_cluster_idx": 0}]}, "HumanEval/16": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 99.0, "profiled": [{"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n return len(set(string.lower()))", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lower case to make the comparison case-insensitive\n string = string.lower()\n # Use a set to store unique characters and calculate the size of the set\n return len(set(string))", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\"Given a string, find out how many distinct characters (regardless of case) does it consist of\"\"\"\n # Convert the string to lowercase to ignore case and then use a set to find unique characters\n distinct_chars = set(string.lower())\n return len(distinct_chars)", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\"Given a string, find out how many distinct characters (regardless of case) does it consist of.\"\"\"\n # Convert the string to lower case to ignore the case and create a set to get distinct characters\n distinct_chars = set(string.lower())\n # Return the number of distinct characters\n return len(distinct_chars)", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lower case and then use a set to find unique characters\n unique_chars = set(string.lower())\n return len(unique_chars)", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\"Given a string, find out how many distinct characters (regardless of case) does it consist of\n\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n return len(set(string.lower()))", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\"Given a string, find out how many distinct characters (regardless of case) does it consist of\"\"\"\n # Convert string to lower case to ensure case insensitivity and use set to find unique characters\n unique_chars = set(string.lower())\n return len(unique_chars)", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\"Given a string, find out how many distinct characters (regardless of case) does it consist of\"\"\"\n if not string:\n return 0\n # Convert string to lower case to ignore case and create a set of characters to get distinct ones\n distinct_chars = set(string.lower())\n return len(distinct_chars)", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\"Given a string, find out how many distinct characters (regardless of case) does it consist of\"\"\"\n if not string:\n return 0\n \n # Convert string to lowercase to make the function case-insensitive\n string = string.lower()\n # Use a set to store unique characters\n unique_chars = set(string)\n # Return the count of unique characters\n return len(unique_chars)", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\"Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert to lower case to ensure case insensitivity and then create a set of characters\n distinct_chars = set(string.lower())\n return len(distinct_chars)", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n return len(set(string.lower()))", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\"Given a string, find out how many distinct characters (regardless of case) does it consist of\"\"\"\n # Convert the string to lower case to ignore case and then use a set to find distinct characters\n distinct_chars = set(string.lower())\n return len(distinct_chars)", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n \"\"\"\n # Convert the string to lower case to ensure case insensitivity\n string = string.lower()\n # Use a set to store distinct characters\n distinct_chars = set(string)\n # Return the number of distinct characters\n return len(distinct_chars)", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\"Given a string, find out how many distinct characters (regardless of case) does it consist of\"\"\"\n # Convert the string to lower case to ignore case and create a set to store distinct characters\n distinct_chars = set(string.lower())\n return len(distinct_chars)", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\"Given a string, find out how many distinct characters (regardless of case) does it consist of\n \n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert to lower case and then create a set to eliminate duplicates\n distinct_chars = set(string.lower())\n # Return the count of distinct characters\n return len(distinct_chars)", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lower case to ignore case differences\n # Use a set to store unique characters\n unique_chars = set(string.lower())\n return len(unique_chars)", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n \"\"\"\n # Convert the string to lower case to ignore the case and then create a set to store unique characters\n unique_chars = set(string.lower())\n # Return the number of unique characters\n return len(unique_chars)", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert string to lower case to ignore case and then use set to find unique characters\n return len(set(string.lower()))", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\"Given a string, find out how many distinct characters (regardless of case) does it consist of\"\"\"\n # Convert the string to lower case to ensure case insensitivity\n string = string.lower()\n # Use a set to store distinct characters\n distinct_chars = set(string)\n # Return the number of distinct characters\n return len(distinct_chars)", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\"Given a string, find out how many distinct characters (regardless of case) does it consist of.\"\"\"\n # Normalize the string to lower case and create a set to store unique characters\n unique_chars = set(string.lower())\n return len(unique_chars)", "matching_cluster_idx": 8}]}, "HumanEval/20": {"dps": 56.84019370460048, "dps_norm": 71.11111111111111, "pass@1": 98.0, "profiled": [{"solution": "from typing import List, Tuple\nfrom functools import cmp_to_key\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n \n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n # Sort the numbers first\n sorted_numbers = sorted(numbers)\n \n # Initialize closest pair and the smallest difference with the first pair\n closest_pair = (sorted_numbers[0], sorted_numbers[1])\n smallest_diff = sorted_numbers[1] - sorted_numbers[0]\n \n # Iterate over the sorted list to find the closest pair\n for i in range(1, len(sorted_numbers) - 1):\n diff = sorted_numbers[i + 1] - sorted_numbers[i]\n if diff < smallest_diff:\n smallest_diff = diff\n closest_pair = (sorted_numbers[i], sorted_numbers[i + 1])\n \n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\nfrom itertools import combinations\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\"From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n # Sort the numbers to facilitate comparison\n sorted_numbers = sorted(numbers)\n \n # Initialize the variables to store the closest elements and their difference\n closest_pair = (sorted_numbers[0], sorted_numbers[1])\n smallest_diff = abs(sorted_numbers[1] - sorted_numbers[0])\n \n # Iterate through the list to find the closest elements\n for num1, num2 in combinations(sorted_numbers, 2):\n if (diff := abs(num2 - num1)) < smallest_diff:\n smallest_diff = diff\n closest_pair = (num1, num2)\n \n return closest_pair", "matching_cluster_idx": 3}, {"solution": "from typing import List, Tuple\nfrom itertools import combinations\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\"From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n # Sort the list to make sure we're comparing consecutive elements only\n sorted_numbers = sorted(numbers)\n closest_pair = min(combinations(sorted_numbers, 2), key=lambda pair: abs(pair[1] - pair[0]))\n return closest_pair", "matching_cluster_idx": 3}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\"From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n sorted_numbers = sorted(numbers)\n closest_pair = (sorted_numbers[0], sorted_numbers[1])\n smallest_difference = sorted_numbers[1] - sorted_numbers[0]\n\n for i in range(1, len(sorted_numbers) - 1):\n current_difference = sorted_numbers[i + 1] - sorted_numbers[i]\n if current_difference < smallest_difference:\n smallest_difference = current_difference\n closest_pair = (sorted_numbers[i], sorted_numbers[i + 1])\n\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\"From a supplied list of numbers (of length at least two), select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n\n :param numbers: List of float numbers.\n :return: A tuple of two closest numbers (smaller, larger).\n \"\"\"\n if len(numbers) < 2:\n raise ValueError(\"The list must contain at least two numbers.\")\n \n sorted_numbers = sorted(numbers)\n closest_pair = (sorted_numbers[0], sorted_numbers[1])\n min_difference = abs(sorted_numbers[1] - sorted_numbers[0])\n\n for i in range(1, len(sorted_numbers) - 1):\n current_difference = abs(sorted_numbers[i + 1] - sorted_numbers[i])\n if current_difference < min_difference:\n min_difference = current_difference\n closest_pair = (sorted_numbers[i], sorted_numbers[i + 1])\n\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\nfrom itertools import combinations\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\"From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n \n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n # Sort the list to ensure pairs are in increasing order\n sorted_numbers = sorted(numbers)\n \n # Initialize variables to keep track of the closest pair\n min_distance = float('inf')\n closest_pair = (sorted_numbers[0], sorted_numbers[1])\n \n # Iterate over adjacent pairs of numbers\n for num1, num2 in combinations(sorted_numbers, 2):\n # Calculate the distance between the numbers\n distance = abs(num2 - num1)\n \n # Update closest pair if a new closest distance is found\n if distance < min_distance:\n min_distance = distance\n closest_pair = (num1, num2)\n \n return closest_pair", "matching_cluster_idx": 3}, {"solution": "from typing import List, Tuple\nfrom typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n \"\"\"\n if len(numbers) < 2:\n raise ValueError(\"List must contain at least two elements.\")\n\n sorted_numbers = sorted(numbers)\n closest_pair = (sorted_numbers[0], sorted_numbers[1])\n smallest_diff = abs(sorted_numbers[1] - sorted_numbers[0])\n\n for i in range(1, len(sorted_numbers) - 1):\n current_diff = abs(sorted_numbers[i+1] - sorted_numbers[i])\n if current_diff < smallest_diff:\n smallest_diff = current_diff\n closest_pair = (sorted_numbers[i], sorted_numbers[i+1])\n\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\nfrom math import inf\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\"From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n \"\"\"\n # First, sort the list to make it easier to find the closest elements\n sorted_numbers = sorted(numbers)\n \n # Initialize the closest pair with the first two elements\n closest_pair = (sorted_numbers[0], sorted_numbers[1])\n smallest_difference = abs(sorted_numbers[1] - sorted_numbers[0])\n \n # Iterate through the sorted list to find the pair with the smallest difference\n for i in range(len(sorted_numbers) - 1):\n current_diff = abs(sorted_numbers[i + 1] - sorted_numbers[i])\n if current_diff < smallest_difference:\n smallest_difference = current_diff\n closest_pair = (sorted_numbers[i], sorted_numbers[i + 1])\n \n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\"From a supplied list of numbers (of length at least two), select and return two that are the closest to each other and return them in order (smaller number, larger number).\n\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n if len(numbers) < 2:\n raise ValueError(\"The list must contain at least two elements.\")\n \n # Sort the numbers to make comparison easier\n numbers.sort()\n \n # Initialize variables to store the closest elements\n closest_pair = (numbers[0], numbers[1])\n min_diff = abs(numbers[1] - numbers[0])\n \n # Iterate through the list to find the pair with the smallest difference\n for i in range(1, len(numbers) - 1):\n current_diff = abs(numbers[i + 1] - numbers[i])\n if current_diff < min_diff:\n min_diff = current_diff\n closest_pair = (numbers[i], numbers[i + 1])\n \n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\nfrom math import inf\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\"From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n \n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n if len(numbers) < 2:\n raise ValueError(\"The list must contain at least two numbers.\")\n \n # Sort the list to find the closest elements more easily\n sorted_numbers = sorted(numbers)\n \n # Initialize minimum difference with infinity\n min_diff = inf\n closest_pair = (sorted_numbers[0], sorted_numbers[1])\n \n # Iterate through the list and find the minimum difference between two consecutive elements\n for i in range(len(sorted_numbers) - 1):\n diff = sorted_numbers[i + 1] - sorted_numbers[i]\n if diff < min_diff:\n min_diff = diff\n closest_pair = (sorted_numbers[i], sorted_numbers[i + 1])\n \n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\nfrom itertools import combinations\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\"From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n # Sort the list to ensure pairs are considered in order\n sorted_numbers = sorted(numbers)\n # Find the minimum difference and the corresponding pair\n min_diff = float('inf')\n closest_pair = ()\n for a, b in combinations(sorted_numbers, 2):\n diff = abs(b - a)\n if diff < min_diff:\n min_diff = diff\n closest_pair = (a, b)\n return closest_pair", "matching_cluster_idx": 3}, {"solution": "from typing import List, Tuple\nfrom itertools import combinations\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\"From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n \"\"\"\n # Sort the numbers to make it easier to find the closest pair\n numbers.sort()\n \n # Calculate differences between adjacent elements\n closest_pair = min(combinations(numbers, 2), key=lambda pair: abs(pair[1] - pair[0]))\n \n return closest_pair", "matching_cluster_idx": 3}, {"solution": "from typing import List, Tuple\nfrom math import inf\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n \"\"\"\n # Ensure the list is sorted to avoid any order dependency for difference calculation.\n numbers.sort()\n \n # Initialize the minimum difference to a very high value.\n min_diff = inf\n closest_pair = (0, 0)\n \n # Iterate over the list to find the smallest difference between two adjacent numbers.\n for i in range(len(numbers) - 1):\n diff = numbers[i + 1] - numbers[i]\n if diff < min_diff:\n min_diff = diff\n closest_pair = (numbers[i], numbers[i + 1])\n \n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\nfrom itertools import combinations\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\"From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n \n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n # Sort the numbers to simplify finding the closest elements\n sorted_numbers = sorted(numbers)\n \n # Initialize the closest pair with the first pair and calculate the initial difference\n closest_pair = (sorted_numbers[0], sorted_numbers[1])\n min_diff = abs(closest_pair[1] - closest_pair[0])\n \n # Iterate through each pair to find the smallest difference\n for x, y in combinations(sorted_numbers, 2):\n diff = y - x\n if diff < min_diff:\n min_diff = diff\n closest_pair = (x, y)\n \n return closest_pair", "matching_cluster_idx": 4}, {"solution": "from typing import List, Tuple\nfrom itertools import combinations\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\"From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n # Sort the numbers to make sure pairs are in ascending order\n sorted_numbers = sorted(numbers)\n\n # Create pairs using combinations and find the closest pair\n closest_pair = min(combinations(sorted_numbers, 2), key=lambda pair: abs(pair[1] - pair[0]))\n\n return closest_pair", "matching_cluster_idx": 3}, {"solution": "from typing import List, Tuple\nfrom itertools import combinations\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\"From a supplied list of numbers (of length at least two), select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n # Sort the list to ensure the closest elements are adjacent\n sorted_numbers = sorted(numbers)\n \n # Initialize with the first pair of elements\n closest_pair = (sorted_numbers[0], sorted_numbers[1])\n smallest_diff = abs(closest_pair[1] - closest_pair[0])\n \n # Iterate over each pair to find the closest\n for num1, num2 in combinations(sorted_numbers, 2):\n if abs(num2 - num1) < smallest_diff:\n smallest_diff = abs(num2 - num1)\n closest_pair = (num1, num2)\n \n return closest_pair", "matching_cluster_idx": 4}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\"From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n \"\"\"\n if len(numbers) < 2:\n raise ValueError(\"Input list must contain at least two elements.\")\n \n # Sort the numbers to make finding the closest elements easier\n sorted_numbers = sorted(numbers)\n \n # Initialize variables to store the closest pair and the smallest difference found\n closest_pair = (sorted_numbers[0], sorted_numbers[1])\n smallest_difference = abs(sorted_numbers[1] - sorted_numbers[0])\n \n # Iterate through the sorted numbers to find the pair with the smallest difference\n for i in range(1, len(sorted_numbers) - 1):\n current_difference = abs(sorted_numbers[i + 1] - sorted_numbers[i])\n if current_difference < smallest_difference:\n smallest_difference = current_difference\n closest_pair = (sorted_numbers[i], sorted_numbers[i + 1])\n \n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\nfrom itertools import combinations\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\"From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n \n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n # Sort the numbers\n sorted_numbers = sorted(numbers)\n \n # Use itertools.combinations to generate all possible pairs\n # And find the pair with the smallest difference\n closest = min(combinations(sorted_numbers, 2), key=lambda pair: abs(pair[1] - pair[0]))\n \n return closest", "matching_cluster_idx": 3}, {"solution": "from typing import List, Tuple\nfrom itertools import combinations\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n \n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n # Sort the numbers to ensure they are in order.\n numbers.sort()\n \n # Use combinations to pair each element with its adjacent one after sorting.\n # This guarantees that the closest pairs are compared, as the list is sorted.\n closest_pair = min(combinations(numbers, 2), key=lambda pair: abs(pair[1] - pair[0]))\n \n return closest_pair", "matching_cluster_idx": 3}, {"solution": "from typing import List, Tuple\nfrom itertools import combinations\nimport math\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\"From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n # Sort the list of numbers\n sorted_numbers = sorted(numbers)\n closest_pair = None\n min_diff = math.inf\n \n # Iterate over pairs of successive numbers to find the minimum difference\n for first, second in combinations(sorted_numbers, 2):\n # Since the list is sorted, no need to keep track of pairs with same difference,\n # we just take the first occurrence.\n if second - first < min_diff:\n min_diff = second - first\n closest_pair = (first, second)\n \n return closest_pair", "matching_cluster_idx": 4}]}, "HumanEval/24": {"dps": 96.32653061224491, "dps_norm": 61.875, "pass@1": 100.0, "profiled": [{"solution": "def largest_divisor(n: int) -> int:\n \"\"\"For a given number n, find the largest number that divides n evenly, smaller than n\"\"\"\n for divisor in range(n // 2, 0, -1):\n if n % divisor == 0:\n return divisor\n return 1 # If no divisor found, return 1 (this case is for n=1 or n=2)", "matching_cluster_idx": 4}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\"For a given number n, find the largest number that divides n evenly, smaller than n.\"\"\"\n for i in range(n // 2, 0, -1):\n if n % i == 0:\n return i\n return 1 # If no divisor is found, return 1, which is a trivial divisor for all n", "matching_cluster_idx": 4}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\"For a given number n, find the largest number that divides n evenly, smaller than n\n \n >>> largest_divisor(15)\n 5\n >>> largest_divisor(28)\n 14\n \"\"\"\n for i in range(n // 2, 0, -1):\n if n % i == 0:\n return i\n return 1", "matching_cluster_idx": 4}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n \"\"\"\n for divisor in range(n // 2, 0, -1):\n if n % divisor == 0:\n return divisor\n return 1 # If no divisor is found, return 1, as every number is divisible by 1.", "matching_cluster_idx": 4}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n \"\"\"\n for i in range(n // 2, 0, -1):\n if n % i == 0:\n return i\n return 1 # If no divisor is found, return 1, as every number is divisible by 1.", "matching_cluster_idx": 4}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\"For a given number n, find the largest number that divides n evenly, smaller than n\"\"\"\n for divisor in range(n // 2, 0, -1):\n if n % divisor == 0:\n return divisor\n return 1 # If no divisor is found, return 1 (trivial case)", "matching_cluster_idx": 4}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\"For a given number n, find the largest number that divides n evenly, smaller than n\"\"\"\n for i in range(n // 2, 0, -1):\n if n % i == 0:\n return i\n return 1 # If no divisor found, return 1 as every number is divisible by 1", "matching_cluster_idx": 4}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\"For a given number n, find the largest number that divides n evenly, smaller than n\"\"\"\n for i in range(n // 2, 0, -1):\n if n % i == 0:\n return i\n return 1 # If no divisor found, which happens only if n is 1", "matching_cluster_idx": 4}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\"For a given number n, find the largest number that divides n evenly, smaller than n.\"\"\"\n for divisor in range(n // 2, 0, -1):\n if n % divisor == 0:\n return divisor\n return 1 # If no divisor is found, return 1. Note: For n > 1, 1 is always a divisor.", "matching_cluster_idx": 4}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\"For a given number n, find the largest number that divides n evenly, smaller than n\n\n Args:\n n (int): A positive integer\n\n Returns:\n int: The largest divisor of n, smaller than n\n\n Examples:\n >>> largest_divisor(15)\n 5\n >>> largest_divisor(28)\n 14\n \"\"\"\n for divisor in range(n // 2, 0, -1):\n if n % divisor == 0:\n return divisor\n return 1 # If no divisor is found, n is prime, so return 1.", "matching_cluster_idx": 3}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\"For a given number n, find the largest number that divides n evenly, smaller than n.\"\"\"\n for i in range(n // 2, 0, -1):\n if n % i == 0:\n return i\n return 1 # If no divisor is found, return 1, as every number is divisible by 1.", "matching_cluster_idx": 4}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\"For a given number n, find the largest number that divides n evenly, smaller than n.\"\"\"\n for i in range(n // 2, 0, -1):\n if n % i == 0:\n return i\n return 1 # If no divisor is found, return 1, which trivially divides n.", "matching_cluster_idx": 4}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\"For a given number n, find the largest number that divides n evenly, smaller than n\"\"\"\n for i in range(n // 2, 0, -1):\n if n % i == 0:\n return i\n return 1 # If no divisor is found, return 1, as every number is divisible by 1", "matching_cluster_idx": 4}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\"For a given number n, find the largest number that divides n evenly, smaller than n\"\"\"\n for i in range(n // 2, 0, -1):\n if n % i == 0:\n return i\n return 1 # If no divisor found, return 1, which trivially divides n evenly.", "matching_cluster_idx": 4}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n\n >>> largest_divisor(15)\n 5\n >>> largest_divisor(16)\n 8\n >>> largest_divisor(17)\n 1\n \"\"\"\n for i in range(n // 2, 0, -1):\n if n % i == 0:\n return i\n return 1", "matching_cluster_idx": 4}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\"For a given number n, find the largest number that divides n evenly, smaller than n\"\"\"\n for i in range(n // 2, 0, -1):\n if n % i == 0:\n return i\n return 1 # If no divisor is found other than 1, return 1 (every number is divisible by 1)", "matching_cluster_idx": 4}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\"For a given number n, find the largest number that divides n evenly, smaller than n\n\n Args:\n n (int): The number to find the largest divisor for.\n\n Returns:\n int: The largest divisor of n, smaller than n.\n\n Examples:\n >>> largest_divisor(15)\n 5\n >>> largest_divisor(28)\n 14\n \"\"\"\n for divisor in range(n // 2, 0, -1):\n if n % divisor == 0:\n return divisor\n return 1 # This case is for prime numbers, where the largest divisor < n is 1.", "matching_cluster_idx": 4}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\"For a given number n, find the largest number that divides n evenly, smaller than n\"\"\"\n for i in range(n//2, 0, -1):\n if n % i == 0:\n return i\n return 1 # If no divisor is found other than 1, return 1", "matching_cluster_idx": 4}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\"For a given number n, find the largest number that divides n evenly, smaller than n\"\"\"\n for i in range(n // 2, 0, -1):\n if n % i == 0:\n return i\n return 1 # If no divisor is found, return 1, as every number is divisible by 1", "matching_cluster_idx": 4}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\"For a given number n, find the largest number that divides n evenly, smaller than n\"\"\"\n for i in range(n//2, 0, -1):\n if n % i == 0:\n return i\n return 1 # If no divisor found, return 1 (applies to the case where n is 1 or 2)", "matching_cluster_idx": 4}]}, "HumanEval/26": {"dps": 45.2, "dps_norm": 71.25, "pass@1": 88.0, "profiled": [{"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\"From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n >>> remove_duplicates([1, 2, 3, 4, 5])\n [1, 2, 3, 4, 5]\n >>> remove_duplicates([1, 1, 2, 2, 3, 3])\n []\n \"\"\"\n seen = set()\n result = []\n for number in numbers:\n if number not in seen:\n # Check if number appears more than once\n if numbers.count(number) == 1:\n result.append(number)\n else:\n seen.add(number)\n return result", "matching_cluster_idx": 0}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n seen = set()\n result = []\n for number in numbers:\n if number not in seen:\n seen.add(number)\n result.append(number)\n else:\n # Remove from result if it's already there\n if number in result:\n result.remove(number)\n return result", "matching_cluster_idx": 2}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\"From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n >>> remove_duplicates([4, 5, 5, 4, 6, 6, 7])\n [7]\n >>> remove_duplicates([10, 20, 20, 10, 30])\n [30]\n \"\"\"\n seen = set()\n result = []\n for num in numbers:\n if num not in seen:\n seen.add(num)\n result.append(num)\n return [num for num in result if numbers.count(num) == 1]", "matching_cluster_idx": 0}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\"From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n >>> remove_duplicates([10, 20, 20, 10, 30])\n [30]\n >>> remove_duplicates([4, 5, 6, 4, 5, 7])\n [6, 7]\n \"\"\"\n occurrence = {}\n for num in numbers:\n if num in occurrence:\n occurrence[num] += 1\n else:\n occurrence[num] = 1\n \n return [num for num in numbers if occurrence[num] == 1]", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\"From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n seen = set()\n result = []\n for number in numbers:\n if number not in seen:\n result.append(number)\n seen.add(number)\n else:\n # If we see it again, remove it from the result if present\n if number in result:\n result.remove(number)\n return result", "matching_cluster_idx": 2}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\"From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n >>> remove_duplicates([4, 5, 5, 4, 2])\n [2]\n >>> remove_duplicates([10, 20, 30])\n [10, 20, 30]\n \"\"\"\n count_map = {}\n for num in numbers:\n count_map[num] = count_map.get(num, 0) + 1\n\n return [num for num in numbers if count_map[num] == 1]", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\"From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n seen = set()\n result = []\n for number in numbers:\n if number not in seen:\n result.append(number)\n seen.add(number)\n else:\n if number in result:\n result = [n for n in result if n != number]\n seen.add(number)\n return result", "matching_cluster_idx": 0}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\"From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n seen = set()\n result = []\n for number in numbers:\n if number not in seen:\n result.append(number)\n seen.add(number)\n else:\n # Remove the number from the final result if it was already seen\n if number in result:\n result.remove(number)\n return result", "matching_cluster_idx": 2}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\"From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n seen = set()\n result = []\n for number in numbers:\n if number not in seen:\n seen.add(number)\n result.append(number)\n else:\n # If the number is encountered again, remove it from the result list\n result = [n for n in result if n != number]\n return result", "matching_cluster_idx": 0}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\"From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n >>> remove_duplicates([4, 5, 5, 4, 6, 7])\n [6, 7]\n >>> remove_duplicates([10, 10, 10])\n []\n >>> remove_duplicates([1, 2, 3])\n [1, 2, 3]\n \"\"\"\n seen = set()\n unique = []\n for number in numbers:\n if number not in seen:\n # Add number to the unique list only if it's not seen before\n seen.add(number)\n unique.append(number)\n else:\n # If the number is already seen, remove it from the unique list\n if number in unique:\n unique.remove(number)\n return unique", "matching_cluster_idx": 2}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\"From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n >>> remove_duplicates([4, 5, 5, 4, 6, 7, 8, 6, 8])\n [7]\n \"\"\"\n seen = set()\n unique = []\n for number in numbers:\n if number not in seen:\n seen.add(number)\n unique.append(number)\n elif number in unique:\n unique.remove(number)\n return unique", "matching_cluster_idx": 2}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\"From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n \"\"\"\n occurrence = {}\n for number in numbers:\n occurrence[number] = occurrence.get(number, 0) + 1\n\n return [number for number in numbers if occurrence[number] == 1]", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n seen = set()\n result = []\n for number in numbers:\n if number not in seen:\n result.append(number)\n seen.add(number)\n else:\n # Remove the element if it appears more than once\n if number in result:\n result.remove(number)\n return result", "matching_cluster_idx": 2}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\"From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n \"\"\"\n # Track occurrences of each number\n count = {}\n for number in numbers:\n if number in count:\n count[number] += 1\n else:\n count[number] = 1\n\n # Include in result only numbers that occurred once\n result = [number for number in numbers if count[number] == 1]\n \n return result", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\"From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n seen = set()\n unique_elements = []\n for number in numbers:\n if number not in seen:\n unique_elements.append(number)\n seen.add(number)\n else:\n # Remove the element from the unique list if it's a duplicate\n if number in unique_elements:\n unique_elements.remove(number)\n return unique_elements", "matching_cluster_idx": 2}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\"From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n \"\"\"\n seen = set()\n result = []\n for number in numbers:\n if number not in seen:\n result.append(number)\n seen.add(number)\n elif number in result:\n result.remove(number)\n seen.add(number)\n return result", "matching_cluster_idx": 2}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\"From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n >>> remove_duplicates([5, 5, 6, 7, 8, 8])\n [6, 7]\n >>> remove_duplicates([9, 10, 9, 10, 11])\n [11]\n >>> remove_duplicates([])\n []\n >>> remove_duplicates([1, 1, 1, 1, 1])\n []\n \"\"\"\n # Count the occurrence of each number\n num_counts = {}\n for num in numbers:\n num_counts[num] = num_counts.get(num, 0) + 1\n\n # Return numbers that occur exactly once\n return [num for num in numbers if num_counts[num] == 1]", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\"From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n seen = set()\n result = []\n for number in numbers:\n if number not in seen:\n result.append(number)\n seen.add(number)\n else:\n # Remove the number from the result if it was added before\n if number in result:\n result.remove(number)\n return result", "matching_cluster_idx": 2}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\"From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n \"\"\"\n seen = set()\n result = []\n for number in numbers:\n if number not in seen:\n result.append(number)\n seen.add(number)\n elif number in result:\n result.remove(number)\n return result", "matching_cluster_idx": 2}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\"From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n >>> remove_duplicates([4, 5, 5, 4, 6, 7])\n [6, 7]\n >>> remove_duplicates([10, 10, 11, 12, 11, 13])\n [12, 13]\n \"\"\"\n seen = set()\n unique = []\n for num in numbers:\n if num not in seen:\n # Add number to unique list only if it hasn't been seen before\n unique.append(num)\n seen.add(num)\n else:\n # If the number has been seen before, ensure it's not kept in unique list\n if num in unique:\n unique.remove(num)\n return unique", "matching_cluster_idx": 2}]}, "HumanEval/31": {"dps": 97.46835443037975, "dps_norm": 87.5, "pass@1": 100.0, "profiled": [{"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "import math\ndef is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n \n Args:\n n (int): The number to check for primality.\n \n Returns:\n bool: True if n is prime, False otherwise.\n \"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "import math\ndef is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "import math\ndef is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "import math\ndef is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}]}, "HumanEval/33": {"dps": 92.60416666666667, "dps_norm": 80.9090909090909, "pass@1": 97.0, "profiled": [{"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n \"\"\"\n # Extracting elements at indices divisible by three\n divisible_by_three = [l[i] for i in range(0, len(l), 3)]\n # Sorting the extracted elements\n divisible_by_three.sort()\n \n # Creating the result list\n result = l[:]\n # Replacing the values at indices divisible by three with sorted values\n for i, value in enumerate(divisible_by_three):\n result[i*3] = value\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n \"\"\"\n # Extract the elements at indices divisible by three and sort them\n indices_div_by_three = [i for i in range(len(l)) if i % 3 == 0]\n elements_div_by_three = sorted(l[i] for i in indices_div_by_three)\n \n # Create the new list l' based on the requirements\n l_prime = l[:]\n for i, idx in enumerate(indices_div_by_three):\n l_prime[idx] = elements_div_by_three[i]\n \n return l_prime", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n \"\"\"\n # Extract elements at indices divisible by three\n divisible_by_three = [l[i] for i in range(0, len(l), 3)]\n # Sort these elements\n divisible_by_three_sorted = sorted(divisible_by_three)\n \n # Create the resulting list\n l_prime = []\n sort_index = 0\n for i in range(len(l)):\n if i % 3 == 0:\n l_prime.append(divisible_by_three_sorted[sort_index])\n sort_index += 1\n else:\n l_prime.append(l[i])\n return l_prime", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indices that are not divisible by three, while its values at the indices that are divisible by three are equal\n to the values of the corresponding indices of l, but sorted.\n \n Examples:\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n # Extract the elements at indices divisible by three\n divisible_by_three = [l[i] for i in range(0, len(l), 3)]\n # Sort these elements\n sorted_elements = sorted(divisible_by_three)\n \n # Generate the new list with sorted elements at the correct positions\n result_list = [sorted_elements.pop(0) if i % 3 == 0 else l[i] for i in range(len(l))]\n \n return result_list", "matching_cluster_idx": 6}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n \"\"\"\n # Extract values at indices divisible by three and sort them\n divisible_by_three_sorted = sorted([l[i] for i in range(len(l)) if i % 3 == 0])\n \n # Create the result list\n result = l[:]\n sorted_index = 0\n \n # Replace the values at indices divisible by three with sorted values\n for i in range(len(result)):\n if i % 3 == 0:\n result[i] = divisible_by_three_sorted[sorted_index]\n sorted_index += 1\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n\n :param l: The input list.\n :return: The modified list l'.\n \"\"\"\n # Extract elements at indices divisible by 3\n divisible_by_three = [l[i] for i in range(0, len(l), 3)]\n # Sort these elements\n sorted_divisible_by_three = sorted(divisible_by_three)\n # Initialize the output list as a copy of the input list\n l_prime = l[:]\n # Place the sorted elements back into their original positions\n for i, value in enumerate(sorted_divisible_by_three):\n l_prime[i*3] = value\n return l_prime", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indices that are not divisible by three, while its values at the indices that are divisible by three are equal\n to the values of the corresponding indices of l, but sorted.\n \n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n \n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n # Extract the elements at indices divisible by 3 (0-indexed)\n divisible_by_three = [l[i] for i in range(0, len(l), 3)]\n # Sort the extracted elements\n sorted_elements = sorted(divisible_by_three)\n \n # Prepare the output list\n result = l[:]\n \n # Replace the elements at indices divisible by 3 with the sorted ones\n for i, value in enumerate(sorted_elements):\n result[i * 3] = value\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n \"\"\"\n # Extract values at indices divisible by three\n divisible_by_three = [l[i] for i in range(0, len(l), 3)]\n # Sort these values\n sorted_values = sorted(divisible_by_three)\n \n # Create a new list to hold the result\n result = l[:]\n # Replace values at indices divisible by three with sorted values\n for i, value in enumerate(sorted_values):\n result[i*3] = value\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indices that are not divisible by three, while its values at the indices that are divisible by three are equal\n to the values of the corresponding indices of l, but sorted.\n \n Examples:\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n # Extract elements at indices divisible by three\n divisible_by_three = [l[i] for i in range(len(l)) if i % 3 == 0]\n # Sort these extracted elements\n divisible_by_three.sort()\n \n # Construct the result list\n result = []\n sorted_index = 0\n for i in range(len(l)):\n if i % 3 == 0:\n # Replace the element if the index is divisible by three\n result.append(divisible_by_three[sorted_index])\n sorted_index += 1\n else:\n # Keep the original element\n result.append(l[i])\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n \"\"\"\n # Extract elements at indices divisible by three\n divisible_by_three = [l[i] for i in range(0, len(l), 3)]\n # Sort the extracted elements\n divisible_by_three.sort()\n\n # Construct the resulting list\n result = []\n sort_index = 0\n for i in range(len(l)):\n if i % 3 == 0:\n result.append(divisible_by_three[sort_index])\n sort_index += 1\n else:\n result.append(l[i])\n\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n \"\"\"\n # Extract elements at indices divisible by three\n divisible_by_three = [l[i] for i in range(0, len(l), 3)]\n # Sort these extracted elements\n divisible_by_three.sort()\n \n # Initialize an empty list to hold the new sorted list\n l_prime = []\n # Counter for the sorted divisible_by_three list\n sorted_index = 0\n \n for i in range(len(l)):\n if i % 3 == 0:\n # Replace the element at indices divisible by three with sorted values\n l_prime.append(divisible_by_three[sorted_index])\n sorted_index += 1\n else:\n # Keep other elements as they are\n l_prime.append(l[i])\n \n return l_prime", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indices that are not divisible by three, while its values at the indices that are divisible by three are equal\n to the values of the corresponding indices of l, but sorted.\n \"\"\"\n # Extract elements whose indices are divisible by three\n divisible_by_three = [l[i] for i in range(len(l)) if i % 3 == 0]\n \n # Sort the extracted elements\n sorted_divisible_by_three = sorted(divisible_by_three)\n \n # Construct the resulting list\n result = l[:]\n sorted_idx = 0\n for i in range(len(result)):\n if i % 3 == 0:\n result[i] = sorted_divisible_by_three[sorted_idx]\n sorted_idx += 1\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n \"\"\"\n # Extract elements at indices divisible by three and sort them\n divisible_by_three_sorted = sorted([l[i] for i in range(len(l)) if i % 3 == 0])\n \n # Construct the result list\n result = []\n sorted_index = 0\n for i in range(len(l)):\n if i % 3 == 0:\n result.append(divisible_by_three_sorted[sorted_index])\n sorted_index += 1\n else:\n result.append(l[i])\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indices that are not divisible by three, while its values at the indices that are divisible by three are equal\n to the values of the corresponding indices of l, but sorted.\n \"\"\"\n # Extract elements at indices divisible by three\n divisible_by_three = [l[i] for i in range(len(l)) if i % 3 == 0]\n # Sort the extracted elements\n sorted_divisible_by_three = sorted(divisible_by_three)\n \n # Construct the new list\n l_prime = []\n sorted_index = 0\n for i in range(len(l)):\n if i % 3 == 0:\n l_prime.append(sorted_divisible_by_three[sorted_index])\n sorted_index += 1\n else:\n l_prime.append(l[i])\n \n return l_prime", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n # Extract the values at indices divisible by 3\n divisible_by_three = [l[i] for i in range(0, len(l), 3)]\n # Sort those values\n divisible_by_three_sorted = sorted(divisible_by_three)\n \n # Create the output list by copying the original list\n l_prime = l[:]\n # Replace the values at indices divisible by 3 with the sorted ones\n for i, value in enumerate(divisible_by_three_sorted):\n l_prime[i * 3] = value\n \n return l_prime", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n \"\"\"\n # Extract elements at indices divisible by three\n divisible_by_three = [l[i] for i in range(0, len(l), 3)]\n # Sort the extracted elements\n divisible_by_three.sort()\n \n # Construct the new list l'\n l_prime = l.copy()\n for i, value in enumerate(divisible_by_three):\n l_prime[i * 3] = value\n \n return l_prime", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indices that are not divisible by three, while its values at the indices that are divisible by three are equal\n to the values of the corresponding indices of l, but sorted.\n \"\"\"\n # Extract elements at indices divisible by three (0-indexed)\n divisible_by_three = [l[i] for i in range(0, len(l), 3)]\n # Sort the extracted elements\n divisible_by_three.sort()\n \n # Construct the new list\n l_prime = []\n sort_index = 0\n for i in range(len(l)):\n if i % 3 == 0:\n l_prime.append(divisible_by_three[sort_index])\n sort_index += 1\n else:\n l_prime.append(l[i])\n \n return l_prime", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n \"\"\"\n # Extract elements at indices divisible by three\n divisible_by_three = [l[i] for i in range(len(l)) if i % 3 == 0]\n # Sort these elements\n divisible_by_three.sort()\n \n # Create the resulting list\n result = []\n sorted_index = 0\n for i in range(len(l)):\n if i % 3 == 0:\n # Replace every third element with the sorted ones\n result.append(divisible_by_three[sorted_index])\n sorted_index += 1\n else:\n result.append(l[i])\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n \"\"\"\n # Extract elements at indices divisible by 3 (0-indexed, so these are every third element starting from 0)\n divisible_by_three = [l[i] for i in range(0, len(l), 3)]\n # Sort these elements\n sorted_divisible_by_three = sorted(divisible_by_three)\n \n # Create a new list with the same length as the original one\n result = l[:]\n # Replace every third element with the corresponding element from the sorted list\n for i, val in enumerate(sorted_divisible_by_three):\n result[i*3] = val\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n # Extract elements at indices divisible by three\n divisible_by_three = [l[i] for i in range(len(l)) if i % 3 == 0]\n # Sort the extracted elements\n divisible_by_three.sort()\n \n # Build the new list l'\n l_prime = []\n sort_index = 0\n for i in range(len(l)):\n if i % 3 == 0:\n l_prime.append(divisible_by_three[sort_index])\n sort_index += 1\n else:\n l_prime.append(l[i])\n \n return l_prime", "matching_cluster_idx": 8}]}, "HumanEval/34": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n # Convert the list to a set to remove duplicates, then sort and return the result\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list.\n \n Args:\n l (list): The list from which to extract unique elements.\n \n Returns:\n list: A list of sorted unique elements.\n \n Example:\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n\n Args:\n l (list): A list of elements\n\n Returns:\n list: A sorted list of unique elements\n\n Examples:\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}]}, "HumanEval/36": {"dps": 96.77419354838709, "dps_norm": 71.42857142857143, "pass@1": 100.0, "profiled": [{"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n \n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n for i in range(1, n):\n if (i % 11 == 0 or i % 13 == 0) and '7' in str(i):\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n for i in range(1, n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"\n Returns the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n \n :param n: An integer limit\n :return: Count of digit 7 appearances\n \"\"\"\n count = 0\n for i in range(1, n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\"\"\"\n count = 0\n for i in range(1, n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n for i in range(1, n):\n if (i % 11 == 0 or i % 13 == 0) and '7' in str(i):\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\"\"\"\n count = 0\n for i in range(1, n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n for i in range(1, n):\n if (i % 11 == 0 or i % 13 == 0) and '7' in str(i):\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n \"\"\"\n count = 0\n for i in range(1, n):\n if (i % 11 == 0 or i % 13 == 0) and '7' in str(i):\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n \n Args:\n n (int): The upper limit (exclusive) to check for numbers.\n \n Returns:\n int: The count of digit 7 appearances in numbers less than n and divisible by 11 or 13.\n \"\"\"\n count = 0\n for i in range(1, n):\n if (i % 11 == 0 or i % 13 == 0) and '7' in str(i):\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"\n Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n \n :param n: An integer to check against.\n :return: Count of digit 7 appearances in numbers less than n and divisible by 11 or 13.\n \"\"\"\n count = 0\n for i in range(1, n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\"\"\"\n count = 0\n for i in range(1, n):\n if (i % 11 == 0 or i % 13 == 0) and '7' in str(i):\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\"\"\"\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\"\"\"\n count = 0\n for i in range(n):\n if (i % 11 == 0 or i % 13 == 0) and '7' in str(i):\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n for i in range(n):\n if (i % 11 == 0 or i % 13 == 0) and '7' in str(i):\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\"\"\"\n count = 0\n for i in range(1, n):\n if (i % 11 == 0 or i % 13 == 0) and '7' in str(i):\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"\n Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n \n :param n: Upper limit (non-inclusive) for searching numbers divisible by 11 or 13.\n :return: Count of digit 7 appearances in qualifying numbers.\n \"\"\"\n count = 0\n for i in range(1, n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n for i in range(1, n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n \"\"\"\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"\n Returns the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n \n :param n: Upper limit to search for numbers with the digit 7.\n :return: Number of times the digit 7 appears in numbers less than n and divisible by 11 or 13.\n \"\"\"\n count = 0\n for i in range(1, n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"\n Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}]}, "HumanEval/37": {"dps": 95.18003273322422, "dps_norm": 90.5, "pass@1": 100.0, "profiled": [{"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Extract the even index elements and sort them\n even_elements = sorted(l[i] for i in range(0, len(l), 2))\n \n # Create a new list with the correct elements\n result = []\n even_idx = 0\n for i in range(len(l)):\n if i % 2 == 0:\n result.append(even_elements[even_idx])\n even_idx += 1\n else:\n result.append(l[i])\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n \"\"\"\n # Extract the elements at even indices\n even_indices_elements = [l[i] for i in range(0, len(l), 2)]\n # Sort the elements at even indices\n sorted_even = sorted(even_indices_elements)\n \n # Construct the result list\n result = []\n even_idx = 0\n for idx in range(len(l)):\n if idx % 2 == 0:\n # Place the sorted element at the even index\n result.append(sorted_even[even_idx])\n even_idx += 1\n else:\n # Place the original element at the odd index\n result.append(l[idx])\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Extract elements at even indices\n even_indices_values = [l[i] for i in range(0, len(l), 2)]\n # Sort the extracted values\n sorted_even_indices_values = sorted(even_indices_values)\n \n # Construct the new list\n l_prime = []\n even_index = 0\n for i in range(len(l)):\n if i % 2 == 0:\n l_prime.append(sorted_even_indices_values[even_index])\n even_index += 1\n else:\n l_prime.append(l[i])\n return l_prime", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n \n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Extract even-index elements and sort them\n even_elements = sorted(l[::2])\n \n # Prepare a result list with the same size as the input\n result = [None] * len(l)\n \n # Place sorted even-index elements back into the result list\n result[::2] = even_elements\n \n # Copy odd-index elements directly from the input list\n result[1::2] = l[1::2]\n \n return result", "matching_cluster_idx": 9}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Extract even indices values and sort them\n even_indices_values = [l[i] for i in range(0, len(l), 2)]\n even_indices_values_sorted = sorted(even_indices_values)\n \n # Create a new list to store the final result\n sorted_list = []\n even_index = 0\n \n for i in range(len(l)):\n if i % 2 == 0:\n # Place the sorted even index value\n sorted_list.append(even_indices_values_sorted[even_index])\n even_index += 1\n else:\n # Keep the odd index value as is\n sorted_list.append(l[i])\n \n return sorted_list", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Extract the even-index elements and sort them\n even_sorted = sorted(l[i] for i in range(0, len(l), 2))\n \n # Prepare a list to hold the result\n result = l[:]\n \n # Put the sorted even-index elements back into their original positions\n even_idx = 0\n for i in range(0, len(l), 2):\n result[i] = even_sorted[even_idx]\n even_idx += 1\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Extract the even-indexed elements and sort them\n even_sorted = sorted(l[i] for i in range(0, len(l), 2))\n \n # Construct the new list\n l_prime = []\n even_idx = 0\n for i in range(len(l)):\n if i % 2 == 0:\n l_prime.append(even_sorted[even_idx])\n even_idx += 1\n else:\n l_prime.append(l[i])\n \n return l_prime", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Extract the even-index elements and sort them\n even_elements = sorted(l[i] for i in range(0, len(l), 2))\n \n # Create the resulting list l' with the same size as l\n l_prime = l[:]\n \n # Replace even indices in l' with the sorted even-index elements\n for i, value in enumerate(even_elements):\n l_prime[i * 2] = value\n \n return l_prime", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n \"\"\"\n # Extract the even-indexed elements and sort them.\n even_elements = sorted(l[i] for i in range(0, len(l), 2))\n \n # Construct the resulting list.\n result_list = []\n even_idx = 0\n for i in range(len(l)):\n if i % 2 == 0:\n # Place the sorted even-indexed element.\n result_list.append(even_elements[even_idx])\n even_idx += 1\n else:\n # Place the original odd-indexed element.\n result_list.append(l[i])\n \n return result_list", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n \n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Extract even-index elements and sort them\n even_elements = sorted(l[i] for i in range(0, len(l), 2))\n \n # Create the result list\n result = []\n even_idx = 0\n \n for i in range(len(l)):\n if i % 2 == 0:\n # Place the next sorted even-index element\n result.append(even_elements[even_idx])\n even_idx += 1\n else:\n # Copy the odd-index elements as is\n result.append(l[i])\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\"\"\"\n # Extract even-index elements and sort them\n even_elements = sorted(l[i] for i in range(0, len(l), 2))\n \n # Construct the result list\n result = []\n even_idx = 0\n for idx in range(len(l)):\n if idx % 2 == 0:\n # Insert the next sorted even element\n result.append(even_elements[even_idx])\n even_idx += 1\n else:\n # Copy the odd-indexed element as is\n result.append(l[idx])\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Extract the even-indexed elements and sort them\n even_elements = sorted(l[::2])\n \n # Create a new list to store the result\n result = []\n even_idx = 0\n \n # Iterate through the original list and construct the result list\n for idx in range(len(l)):\n if idx % 2 == 0:\n # For even indices, get the next element from the sorted even_elements\n result.append(even_elements[even_idx])\n even_idx += 1\n else:\n # For odd indices, just copy the element from the original list\n result.append(l[idx])\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Extract even index elements and sort them\n even_elements_sorted = sorted(l[i] for i in range(0, len(l), 2))\n \n # Create the result list, copying odd indices from l\n # and placing sorted even elements back at even indices\n result = [None] * len(l)\n even_index = 0\n for i in range(len(l)):\n if i % 2 == 0:\n result[i] = even_elements_sorted[even_index]\n even_index += 1\n else:\n result[i] = l[i]\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Extract the even-indexed elements and sort them\n even_elements = sorted(l[i] for i in range(0, len(l), 2))\n\n # Create a new list with sorted even-indexed elements and original odd-indexed elements\n result = [even_elements.pop(0) if i % 2 == 0 else l[i] for i in range(len(l))]\n\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Extracting even index elements\n even_indices_elements = [l[i] for i in range(0, len(l), 2)]\n # Sorting the even index elements\n sorted_even_indices_elements = sorted(even_indices_elements)\n \n # Creating the result list\n result = []\n even_index_counter = 0\n for i in range(len(l)):\n if i % 2 == 0:\n # For even index, place the sorted value\n result.append(sorted_even_indices_elements[even_index_counter])\n even_index_counter += 1\n else:\n # For odd index, keep the original value\n result.append(l[i])\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\"\"\"\n # Extracting even indices\n even_indices_values = [l[i] for i in range(0, len(l), 2)]\n # Sorting the values at the even indices\n even_indices_values.sort()\n\n # Building the result list\n result = []\n even_counter = 0\n for i in range(len(l)):\n if i % 2 == 0:\n result.append(even_indices_values[even_counter])\n even_counter += 1\n else:\n result.append(l[i])\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Extract even-index elements and sort them\n even_elements = sorted(l[i] for i in range(0, len(l), 2))\n \n # Initialize the result list with None to later fill with correct values\n result = [None] * len(l)\n \n # Fill in the even indices with sorted elements\n even_iter = iter(even_elements)\n for i in range(0, len(l), 2):\n result[i] = next(even_iter)\n \n # Fill in the odd indices with the original list's elements\n for i in range(1, len(l), 2):\n result[i] = l[i]\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n \"\"\"\n # Extract elements at even indices and sort them\n even_indices_values_sorted = sorted(l[i] for i in range(0, len(l), 2))\n \n # Create the result list by placing sorted even indices and unchanged odd indices\n result_list = [even_indices_values_sorted.pop(0) if i % 2 == 0 else l[i] for i in range(len(l))]\n \n return result_list", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n \"\"\"\n # Extract the elements at even indices\n even_indices_elements = [l[i] for i in range(0, len(l), 2)]\n # Sort the extracted elements\n sorted_even_indices_elements = sorted(even_indices_elements)\n \n # Create a new list to store the result\n l_prime = []\n # Counter for the sorted even indices elements\n sorted_counter = 0\n \n for i in range(len(l)):\n if i % 2 == 0:\n # Even index, append from sorted even indices elements\n l_prime.append(sorted_even_indices_elements[sorted_counter])\n sorted_counter += 1\n else:\n # Odd index, directly append the original value\n l_prime.append(l[i])\n \n return l_prime", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n \n Example usage:\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Extract elements at even indices and sort them.\n sorted_evens = sorted(l[i] for i in range(0, len(l), 2))\n \n # Generate the result list.\n result = []\n even_idx = 0 # Track the position in sorted_evens.\n \n for i in range(len(l)):\n if i % 2 == 0:\n # At even indices, use sorted values.\n result.append(sorted_evens[even_idx])\n even_idx += 1\n else:\n # At odd indices, use original value.\n result.append(l[i])\n \n return result", "matching_cluster_idx": 8}]}, "HumanEval/49": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\n \"\"\"\n # Use Python's built-in pow function with three arguments for efficiency and numeric stability\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\"\"\"\n # Use Python's built-in pow function which efficiently computes (x^y) % z\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p.\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\"\"\"\n # Use Python's built-in pow function which efficiently handles large powers modulo a number\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\n\n Args:\n n (int): The exponent to raise 2 by.\n p (int): The modulo value.\n\n Returns:\n int: The result of (2^n) % p.\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\"\"\"\n # Using Python's built-in pow function to handle large numbers efficiently\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\"\"\"\n # Use Python's built-in pow function for efficient modular exponentiation\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}]}, "HumanEval/51": {"dps": 91.35265700483092, "dps_norm": 71.875, "pass@1": 100.0, "profiled": [{"solution": "import doctest\ndef remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes a string and returns a string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\\\nghijklm\")\n 'bcdf\\\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = 'aeiouAEIOU'\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n \"\"\"\n vowels = \"aeiouAEIOU\"\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "import string\ndef remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n \"\"\"\n vowels = 'aeiouAEIOU'\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes a string and returns the string without vowels.\n \n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n \"\"\"\n vowels = \"aeiouAEIOU\"\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\\\nghijklm\")\n 'bcdf\\\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes a string and returns a string without vowels.\n \"\"\"\n vowels = 'aeiouAEIOU'\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes a string and returns the string without vowels.\n \"\"\"\n vowels = 'aeiouAEIOU'\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "import string\ndef remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes a string and returns the string without vowels.\n \"\"\"\n vowels = 'aeiouAEIOU'\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes a string and returns a string without vowels.\n \n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = 'aeiouAEIOU'\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n vowels = \"aeiouAEIOU\"\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\\\nghijklm\")\n 'bcdf\\\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = 'aeiouAEIOU'\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n \"\"\"\n vowels = 'aeiouAEIOU'\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "import doctest\ndef remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes a string and returns a string without vowels.\n \n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\\\nghijklm\")\n 'bcdf\\\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n \"\"\"\n vowels = 'aeiouAEIOU'\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\\\nghijklm\")\n 'bcdf\\\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = 'aeiouAEIOU'\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes a string and returns a string without vowels.\n \"\"\"\n # Define a set of vowels\n vowels = set('aeiouAEIOU')\n \n # Use list comprehension to filter out vowels and join the result into a new string\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\\\nghijklm\")\n 'bcdf\\\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n result = ''.join([char for char in text if char not in vowels])\n return result", "matching_cluster_idx": 5}, {"solution": "import re\ndef remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\\\nghijklm\")\n 'bcdf\\\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n return re.sub(r'[AEIOUaeiou]', '', text)", "matching_cluster_idx": 0}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n \"\"\"\n vowels = 'aeiouAEIOU'\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}]}, "HumanEval/54": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 95.0, "profiled": [{"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \"\"\"\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \n Args:\n s0 (str): The first string to compare.\n s1 (str): The second string to compare.\n \n Returns:\n bool: True if both strings contain exactly the same characters, False otherwise.\n \"\"\"\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \"\"\"\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "from collections import Counter\ndef same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \n :param s0: First string to compare\n :param s1: Second string to compare\n :return: True if both strings consist of the same characters, False otherwise\n \"\"\"\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "from collections import Counter\ndef same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \n This function checks if both strings s0 and s1 are composed of the same set of characters,\n regardless of their order or the number of occurrences of each character.\n \n Args:\n s0 (str): The first string to be checked.\n s1 (str): The second string to be checked.\n \n Returns:\n bool: True if both strings are composed of the same characters, False otherwise.\n \"\"\"\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "from collections import Counter\ndef same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \"\"\"\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \n :param s0: First string.\n :param s1: Second string.\n :return: True if both strings contain the same characters, False otherwise.\n \"\"\"\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "from collections import Counter\ndef same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \n Args:\n s0 (str): First string to compare.\n s1 (str): Second string to compare.\n \n Returns:\n bool: True if both strings have the same set of characters, False otherwise.\n \"\"\"\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \"\"\"\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "from collections import Counter\ndef same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \"\"\"\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "from collections import Counter\ndef same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \n Parameters:\n s0 (str): The first string to compare.\n s1 (str): The second string to compare.\n \n Returns:\n bool: True if both strings contain the same set of characters, False otherwise.\n \"\"\"\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "from collections import Counter\ndef same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \"\"\"\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "from collections import Counter\ndef same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters, regardless of their frequency.\n \"\"\"\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \"\"\"\n # Convert strings to sets and compare\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \"\"\"\n # Use sets to check if both strings contain the same unique characters\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \n Args:\n s0 (str): The first word.\n s1 (str): The second word.\n \n Returns:\n bool: True if both words contain the same characters, False otherwise.\n \"\"\"\n # Convert both strings to sets to remove duplicates and allow comparison of unique characters\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters, disregarding the frequency and order of characters.\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')\n True\n >>> same_chars('abcd', 'dddddddabc')\n True\n >>> same_chars('dddddddabc', 'abcd')\n True\n >>> same_chars('eabcd', 'dddddddabc')\n False\n >>> same_chars('abcd', 'dddddddabce')\n False\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')\n False\n \"\"\"\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "from collections import Counter\ndef same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \"\"\"\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \n This function compares two strings to determine if they contain exactly the same characters\n (ignoring frequency and order).\n\n :param s0: First string to compare.\n :param s1: Second string to compare.\n :return: True if both strings have the same characters, False otherwise.\n \"\"\"\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \n This function checks if two strings contain the same set of characters, regardless of order or frequency.\n\n :param s0: First string to compare\n :param s1: Second string to compare\n :return: True if both strings contain the same characters, False otherwise\n \"\"\"\n return set(s0) == set(s1)", "matching_cluster_idx": 6}]}, "HumanEval/58": {"dps": 93.26771653543307, "dps_norm": 85.0, "pass@1": 100.0, "profiled": [{"solution": "def common(l1: list, l2: list) -> list:\n \"\"\"Return sorted unique common elements for two lists.\n \n Args:\n l1: First list of integers.\n l2: Second list of integers.\n \n Returns:\n A list of integers that are common and unique to both l1 and l2, sorted in ascending order.\n \n Examples:\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n # Convert both lists to sets to remove duplicates and find intersection\n common_set = set(l1).intersection(set(l2))\n # Return the sorted list of common elements\n return sorted(list(common_set))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n \n Args:\n l1: First list of integers.\n l2: Second list of integers.\n \n Returns:\n A list containing sorted unique common elements of l1 and l2.\n \n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n # Convert both lists to sets and use set intersection to find common elements\n common_elements = set(l1).intersection(set(l2))\n # Return the sorted list of common elements\n return sorted(list(common_elements))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list) -> list:\n \"\"\"Return sorted unique common elements for two lists.\n \n Examples:\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n # Convert both lists to sets to remove duplicates and find common elements\n set1 = set(l1)\n set2 = set(l2)\n # Find intersection of both sets to get common elements\n common_elements = set1.intersection(set2)\n # Return sorted list of common elements\n return sorted(list(common_elements))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list) -> list:\n \"\"\"Return sorted unique common elements for two lists.\n \"\"\"\n # Use set intersection to find common elements and sort the result\n return sorted(list(set(l1) & set(l2)))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list) -> list:\n \"\"\"Return sorted unique common elements for two lists.\n\n Args:\n l1: First list of elements.\n l2: Second list of elements.\n\n Returns:\n A list of sorted unique elements that are common to both input lists.\n\n Examples:\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n # Find the intersection of two lists and convert to set to remove duplicates, then sort the result\n return sorted(set(l1).intersection(set(l2)))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n # Use set intersection to find common elements and then sort the result.\n return sorted(list(set(l1) & set(l2)))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list) -> list:\n \"\"\"Return sorted unique common elements for two lists.\n \n Examples:\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n # Convert both lists to sets and find the intersection to get common elements\n common_elements = set(l1).intersection(set(l2))\n # Return the sorted list of common elements\n return sorted(common_elements)", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list) -> list:\n \"\"\"Return sorted unique common elements for two lists.\n \n Examples:\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n # Convert both lists to sets to remove duplicates and find intersection\n set1 = set(l1)\n set2 = set(l2)\n # Intersect the two sets and convert back to a sorted list\n return sorted(list(set1.intersection(set2)))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list) -> list:\n \"\"\"Return sorted unique common elements for two lists.\"\"\"\n # Find common elements using set intersection and return sorted list\n return sorted(list(set(l1) & set(l2)))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n \n Args:\n l1: A list of integers.\n l2: A list of integers.\n \n Returns:\n A sorted list containing the unique common elements between l1 and l2.\n \n Examples:\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n # Find common elements\n common_elements = set(l1).intersection(l2)\n \n # Return sorted list\n return sorted(common_elements)", "matching_cluster_idx": 5}, {"solution": "def common(l1: list, l2: list) -> list:\n \"\"\"Return sorted unique common elements for two lists.\n \n Args:\n l1: First list of integers.\n l2: Second list of integers.\n \n Returns:\n A list of integers that are common in both lists, sorted and unique.\n \n Examples:\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n # Using set intersection to find common elements and then sorting the result\n return sorted(list(set(l1) & set(l2)))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n \n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n # Convert both lists to sets to remove duplicates and find intersection\n common_elements = set(l1) & set(l2)\n # Return the sorted list of the intersection elements\n return sorted(list(common_elements))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list) -> list:\n \"\"\"Return sorted unique common elements for two lists.\"\"\"\n # Find common elements using set intersection\n common_elements = set(l1).intersection(l2)\n # Return the sorted list of common elements\n return sorted(common_elements)", "matching_cluster_idx": 5}, {"solution": "def common(l1: list, l2: list) -> list:\n \"\"\"Return sorted unique common elements for two lists.\n \n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n # Use set intersection to find common elements and then sort them\n return sorted(set(l1) & set(l2))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list) -> list:\n \"\"\"Return sorted unique common elements for two lists.\n \n Args:\n l1 (list): The first list.\n l2 (list): The second list.\n \n Returns:\n list: A sorted list of unique elements common to both lists.\n \n Examples:\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n # Find unique elements in both lists by converting them to sets\n set1 = set(l1)\n set2 = set(l2)\n \n # Find intersection of both sets to get common elements\n common_set = set1.intersection(set2)\n \n # Convert the set back to a sorted list and return it\n return sorted(list(common_set))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n \n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n # Convert lists to sets to remove duplicates and find intersection\n common_elements = list(set(l1) & set(l2))\n # Return sorted list of common elements\n return sorted(common_elements)", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list) -> list:\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n # Converting both lists to sets to remove duplicates and find intersection\n common_elements = set(l1).intersection(set(l2))\n # Returning the sorted list of common elements\n return sorted(common_elements)", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n \n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n # Convert both lists to sets and find the intersection\n common_set = set(l1) & set(l2)\n # Convert the set back to a sorted list and return\n return sorted(list(common_set))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n # Convert both lists to sets to find unique common elements\n common_elements = set(l1) & set(l2)\n # Return the sorted list of common elements\n return sorted(list(common_elements))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n \n Args:\n l1: First list of elements.\n l2: Second list of elements.\n \n Returns:\n A list containing the sorted unique elements that are common in both lists.\n \n Examples:\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n # Using set intersection to find common elements and then sorting them\n result = sorted(set(l1).intersection(set(l2)))\n return result", "matching_cluster_idx": 4}]}, "HumanEval/59": {"dps": 95.71180555555556, "dps_norm": 98.88888888888889, "pass@1": 99.0, "profiled": [{"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"\n Return the largest prime factor of n. Assume n > 1 and is not a prime.\n \"\"\"\n # Initialize the largest prime factor\n largest_prime = -1\n \n # Divide n by 2 to remove all even factors\n while n % 2 == 0:\n largest_prime = 2\n n //= 2\n \n # Now n must be odd. Start from 3 and check for factors\n for i in range(3, int(n**0.5) + 1, 2):\n # While i divides n, remove i and set largest_prime to i\n while n % i == 0:\n largest_prime = i\n n //= i\n \n # If n becomes a prime number greater than 2\n if n > 2:\n largest_prime = n\n \n return largest_prime", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n i = 2\n while i * i <= n:\n if n % i:\n i += 1\n else:\n n //= i\n return n", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n i = 2\n largest_factor = 1\n while i * i <= n:\n if n % i:\n i += 1\n else:\n n //= i\n largest_factor = i\n if n > 1:\n largest_factor = n\n return largest_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"\n Return the largest prime factor of n. Assume n > 1 and is not a prime.\n \n Parameters:\n n (int): The integer to find the largest prime factor for.\n \n Returns:\n int: The largest prime factor of n.\n \"\"\"\n i = 2\n # While i^2 is less than or equal to n, do the iteration\n while i * i <= n:\n # If n is divisible by i, divide n by i\n if n % i:\n i += 1\n else:\n n //= i\n # After the loop, n should be the largest prime factor\n return n", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n i = 2\n largest_prime = 2\n \n while i * i <= n:\n if n % i == 0:\n largest_prime = i\n n //= i\n else:\n i += 1\n\n if n > largest_prime:\n largest_prime = n\n\n return largest_prime", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"\n Return the largest prime factor of n. Assume n > 1 and is not a prime.\n \n :param n: Integer to find the largest prime factor of.\n :return: The largest prime factor of n.\n \"\"\"\n i = 2\n largest_factor = 1\n while i * i <= n:\n if n % i:\n i += 1\n else:\n n //= i\n largest_factor = i\n if n > 1:\n largest_factor = n\n return largest_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n # Initialize the largest prime factor\n largest_prime = -1\n \n # Divide n by 2 to remove all even factors\n while n % 2 == 0:\n largest_prime = 2\n n //= 2\n \n # n must be odd at this point, so a skip of 2 (i = i + 2) can be used\n for i in range(3, int(n**0.5) + 1, 2):\n # While i divides n, remove i and set largest_prime to i\n while n % i == 0:\n largest_prime = i\n n = n // i\n \n # This condition is to check if n is a prime number greater than 2\n if n > 2:\n largest_prime = n\n \n return largest_prime", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n \n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n # Initialize the largest prime factor\n largest_factor = 2\n # Divide n by 2 to remove all even factors\n while n % 2 == 0:\n n = n // 2\n \n # n must be odd at this point, so a skip of 2 (i = i + 2) can be used\n factor = 3\n while factor * factor <= n:\n # While factor divides n, remove it and update largest_factor\n while n % factor == 0:\n largest_factor = factor\n n = n // factor\n factor += 2\n \n # This condition is to check if n is a prime number greater than 2\n if n > 2:\n largest_factor = n\n \n return largest_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n i = 2\n while i * i <= n:\n if n % i:\n i += 1\n else:\n n //= i\n return n", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"\n Return the largest prime factor of n. Assume n > 1 and is not a prime.\n \n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n # Initialize the smallest prime factor\n factor = 2\n last_factor = 1\n while n > 1:\n if n % factor == 0:\n last_factor = factor\n n //= factor\n while n % factor == 0:\n n //= factor\n factor += 1\n return last_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n # Initialize the smallest prime factor\n factor = 2\n last_factor = 1\n while n > 1:\n # While 'n' is divisible by 'factor', divide 'n' by 'factor'\n while n % factor == 0:\n last_factor = factor\n n //= factor\n # Increment the factor, skip even numbers after 2\n factor += 1 if factor == 2 else 2\n # Optimization: if factor*factor > n, then n is prime\n if factor * factor > n:\n if n > 1:\n last_factor = n\n break\n return last_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n # Initialize the largest prime factor variable\n largest_factor = -1\n \n # Divide n by 2 to remove all even factors\n while n % 2 == 0:\n largest_factor = 2\n n = n // 2\n \n # Now n must be odd, start from 3 and check for factors\n factor = 3\n while factor * factor <= n:\n while n % factor == 0:\n largest_factor = factor\n n = n // factor\n factor += 2\n \n # If n is a prime number greater than 2\n if n > 2:\n largest_factor = n\n \n return largest_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"\n Return the largest prime factor of n. Assume n > 1 and is not a prime.\n \n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n i = 2\n largest_factor = 1\n while i * i <= n:\n if n % i:\n i += 1\n else:\n n //= i\n largest_factor = i\n if n > 1:\n largest_factor = n\n return largest_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"\n Return the largest prime factor of n. Assume n > 1 and is not a prime.\n \n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n # Initialize the largest prime factor variable\n largest_prime = -1\n \n # Divide n by 2 to remove all even factors\n while n % 2 == 0:\n largest_prime = 2\n n = n // 2\n\n # n must be odd at this point, so we can skip one element (Note i = i + 2)\n for i in range(3, int(n**0.5) + 1, 2):\n # While i divides n, print i and divide n\n while n % i == 0:\n largest_prime = i\n n = n // i\n\n # This condition is to check if n is a prime number greater than 2\n if n > 2:\n largest_prime = n\n\n return largest_prime", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n i = 2\n while i * i <= n:\n if n % i:\n i += 1\n else:\n n //= i\n return n", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"\n Return the largest prime factor of n. Assume n > 1 and is not a prime.\n \n :param n: Integer greater than 1 and not a prime.\n :return: Largest prime factor of n.\n \"\"\"\n # Initialize the largest prime factor variable\n largest_prime = -1\n \n # Divide n by 2 to remove all even factors\n while n % 2 == 0:\n largest_prime = 2\n n = n // 2\n \n # n must be odd at this point, so we can skip one element (Note i = i + 2)\n factor = 3\n while factor * factor <= n:\n while n % factor == 0:\n largest_prime = factor\n n = n // factor\n factor += 2\n \n # This condition is to handle the case when n is a prime number\n # greater than 2\n if n > 2:\n largest_prime = n\n \n return largest_prime", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n \n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n def is_prime(number):\n if number <= 1:\n return False\n if number <= 3:\n return True\n if number % 2 == 0 or number % 3 == 0:\n return False\n i = 5\n while i * i <= number:\n if number % i == 0 or number % (i + 2) == 0:\n return False\n i += 6\n return True\n\n # Start from the smallest prime factor\n factor = 2\n last_factor = 1\n while n > 1:\n while n % factor == 0:\n last_factor = factor\n n //= factor\n factor += 1\n if is_prime(factor):\n if n % factor == 0:\n last_factor = factor\n n //= factor\n return last_factor", "matching_cluster_idx": 6}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n # Initialize the largest prime factor\n largest_prime = -1\n \n # Divide n by 2 to remove all even factors\n while n % 2 == 0:\n largest_prime = 2\n n //= 2\n \n # Now n must be odd, start checking for factors from 3 onwards\n factor = 3\n while factor * factor <= n:\n while n % factor == 0:\n largest_prime = factor\n n //= factor\n factor += 2\n \n # If n becomes a prime number > 2\n if n > 2:\n largest_prime = n\n \n return largest_prime", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n i = 2\n while i * i <= n:\n if n % i:\n i += 1\n else:\n n //= i\n return n", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n # Initialize the largest prime factor\n largest_prime = -1\n \n # Divide n by 2 to remove all even factors\n while n % 2 == 0:\n largest_prime = 2\n n //= 2\n \n # Now n must be odd, start from 3 and remove all factors\n factor = 3\n while factor * factor <= n:\n while n % factor == 0:\n largest_prime = factor\n n //= factor\n factor += 2\n \n # If n became a prime number greater than 2\n if n > 2:\n largest_prime = n\n \n return largest_prime", "matching_cluster_idx": 8}]}, "HumanEval/64": {"dps": 92.20779220779221, "dps_norm": 62.5, "pass@1": 93.0, "profiled": [{"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = 'aeiouAEIOU'\n count = sum(1 for char in s if char in vowels)\n if s.endswith('y') or s.endswith('Y'):\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = set('aeiouAEIOU')\n count = sum(1 for char in s if char in vowels)\n if s.endswith(('y', 'Y')):\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n # Define the vowels set\n vowels = set(\"aeiouAEIOU\")\n # Count the vowels in the string\n count = sum(1 for char in s if char in vowels)\n # Check if 'y' or 'Y' is at the end and add to count if true\n if s and (s[-1] in \"yY\"):\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = \"aeiou\"\n count = sum(1 for char in s.lower() if char in vowels)\n if s.endswith('Y') or s.endswith('y'):\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = \"aeiouAEIOU\"\n count = sum(1 for char in s if char in vowels)\n if s.endswith('y') or s.endswith('Y'):\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = 'aeiouAEIOU'\n count = sum(1 for char in s if char in vowels)\n if s.endswith(('y', 'Y')):\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = 'aeiouAEIOU'\n count = sum(1 for char in s if char in vowels)\n if s.endswith('y') or s.endswith('Y'):\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = 'aeiouAEIOU'\n count = sum(1 for char in s if char in vowels)\n if s and s[-1] in 'yY':\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n \"\"\"Count the number of vowels in the string.\n Vowels include 'a', 'e', 'i', 'o', 'u', and 'y' only if it is at the end of the word.\n \n :param s: The input string representing a word.\n :return: The number of vowels in the string.\n \"\"\"\n # Convert the string to lower case to make the function case-insensitive\n s = s.lower()\n # Define a set of vowels\n vowels = set('aeiou')\n # Initialize a counter for the number of vowels\n count = 0\n # Iterate over each character in the string\n for char in s:\n # If the character is a vowel, increment the count\n if char in vowels:\n count += 1\n # Check if the last character is 'y', if so, add 1 to the count\n if s and s[-1] == 'y':\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = 'aeiouAEIOU'\n count = sum(1 for char in s if char in vowels)\n if s.endswith('y') or s.endswith('Y'):\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = 'aeiouAEIOU'\n count = sum(1 for char in s if char in vowels)\n if s and s[-1].lower() == 'y':\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n \"\"\"Count the number of vowels in the string. 'y' is considered a vowel\n only if it is at the end of the word.\n \n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n >>> vowels_count(\"rhythm\")\n 0\n >>> vowels_count(\"SYZYGY\")\n 1\n >>> vowels_count(\"aeiouy\")\n 6\n >>> vowels_count(\"bcdfghjkl\")\n 0\n \"\"\"\n vowels = 'aeiou'\n count = sum(1 for char in s.lower() if char in vowels)\n # Check if 'y' at the end and not already counted\n if s and s[-1].lower() == 'y' and s[-1].lower() not in vowels:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = 'aeiouAEIOU'\n count = sum(1 for char in s if char in vowels)\n if s.endswith('y') or s.endswith('Y'):\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n \"\"\"Return the number of vowels in the string.\n Vowels are 'a', 'e', 'i', 'o', 'u', and 'y' only at the end of the word.\n \n Args:\n s (str): The input string.\n\n Returns:\n int: The number of vowels in the string.\n \"\"\"\n vowels = 'aeiouAEIOU'\n count = sum(1 for char in s if char in vowels)\n if s and s[-1] in 'yY':\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = set('aeiouAEIOU')\n count = sum(1 for char in s if char in vowels)\n if s and s[-1] in 'yY':\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n \"\"\"Returns the number of vowels in the string. Vowels are 'a', 'e', 'i', 'o', 'u',\n and 'y' only when it is at the end of the given word.\n \n Args:\n s (str): A string representing a word.\n\n Returns:\n int: The number of vowels in the string.\n \"\"\"\n vowels = 'aeiou'\n count = sum(1 for char in s.lower() if char in vowels)\n if s and s.lower()[-1] == 'y':\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = set('aeiouAEIOU')\n count = sum(1 for char in s if char in vowels)\n if s and s[-1].lower() == 'y':\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n # Define the vowels and initialize a counter\n vowels = 'aeiouAEIOU'\n count = 0\n \n # Iterate through each character in the string\n for char in s:\n if char in vowels:\n count += 1\n \n # Check if the last character is 'y' or 'Y'\n if s and s[-1] in 'yY':\n count += 1\n \n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = 'aeiou'\n count = sum(1 for char in s.lower() if char in vowels)\n if s and s[-1].lower() == 'y':\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n \"\"\"Return the number of vowels in the string. Vowels in this case are\n 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a vowel, but only when it\n is at the end of the given word.\n\n :param s: A string representing a word.\n :return: An integer representing the number of vowels in the string.\n \"\"\"\n vowels = set('aeiouAEIOU')\n count = sum(1 for char in s if char in vowels)\n if s and s[-1].lower() == 'y':\n count += 1\n return count", "matching_cluster_idx": 4}]}, "HumanEval/74": {"dps": 98.04878048780488, "dps_norm": 88.88888888888889, "pass@1": 100.0, "profiled": [{"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n count_lst1 = sum(len(s) for s in lst1)\n count_lst2 = sum(len(s) for s in lst2)\n \n if count_lst1 <= count_lst2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n # Calculate the total number of characters in each list\n total_chars_lst1 = sum(len(s) for s in lst1)\n total_chars_lst2 = sum(len(s) for s in lst2)\n\n # Compare the total number of characters and return the appropriate list\n if total_chars_lst1 < total_chars_lst2:\n return lst1\n elif total_chars_lst1 > total_chars_lst2:\n return lst2\n else:\n return lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n '''\n # Calculate the total number of characters in each list\n total_chars_lst1 = sum(len(s) for s in lst1)\n total_chars_lst2 = sum(len(s) for s in lst2)\n \n # Compare the total number of characters and return the appropriate list\n if total_chars_lst1 <= total_chars_lst2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n len_lst1 = sum(len(word) for word in lst1)\n len_lst2 = sum(len(word) for word in lst2)\n\n if len_lst1 <= len_lst2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n '''\n # Calculate the total number of characters in each list\n total_chars_lst1 = sum(len(word) for word in lst1)\n total_chars_lst2 = sum(len(word) for word in lst2)\n \n # Compare the total number of characters and return the appropriate list\n if total_chars_lst1 <= total_chars_lst2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n '''\n # Calculate the total number of characters in each list\n total_chars_lst1 = sum(len(s) for s in lst1)\n total_chars_lst2 = sum(len(s) for s in lst2)\n\n # Return the list with fewer total characters or the first list if they are equal\n if total_chars_lst1 <= total_chars_lst2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n # Calculate the total number of characters in each list\n total_chars_lst1 = sum(len(s) for s in lst1)\n total_chars_lst2 = sum(len(s) for s in lst2)\n\n # Compare the total characters and return the appropriate list\n if total_chars_lst1 <= total_chars_lst2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n count_lst1 = sum(len(s) for s in lst1)\n count_lst2 = sum(len(s) for s in lst2)\n \n if count_lst1 <= count_lst2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n # Count total number of characters in each list\n count1 = sum(len(word) for word in lst1)\n count2 = sum(len(word) for word in lst2)\n \n # Return the list with fewer total characters, or the first list if equal\n if count1 <= count2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n # Calculate the total number of characters in each list\n total_chars_lst1 = sum(len(s) for s in lst1)\n total_chars_lst2 = sum(len(s) for s in lst2)\n \n # Compare the total number of characters and return the appropriate list\n if total_chars_lst1 <= total_chars_lst2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n '''\n # Calculate total number of characters in each list\n total_chars_lst1 = sum(len(word) for word in lst1)\n total_chars_lst2 = sum(len(word) for word in lst2)\n\n # Compare total number of characters and return the appropriate list\n if total_chars_lst1 <= total_chars_lst2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n len1 = sum(len(s) for s in lst1)\n len2 = sum(len(s) for s in lst2)\n \n if len1 <= len2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n # Count the total number of characters in each list\n count1 = sum(len(s) for s in lst1)\n count2 = sum(len(s) for s in lst2)\n \n # Return the list with fewer total characters, or the first list if equal\n if count1 <= count2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n '''\n # Calculate the total number of chars in each list\n total_chars_lst1 = sum(len(s) for s in lst1)\n total_chars_lst2 = sum(len(s) for s in lst2)\n \n # Compare and return the appropriate list\n if total_chars_lst1 < total_chars_lst2:\n return lst1\n elif total_chars_lst1 > total_chars_lst2:\n return lst2\n else:\n return lst1 # Return the first list if they have the same number of chars", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n '''\n # Calculate the total number of characters in lst1\n total_chars_lst1 = sum(len(s) for s in lst1)\n # Calculate the total number of characters in lst2\n total_chars_lst2 = sum(len(s) for s in lst2)\n \n # Compare the totals and return the appropriate list\n if total_chars_lst1 < total_chars_lst2:\n return lst1\n elif total_chars_lst1 > total_chars_lst2:\n return lst2\n else:\n return lst1 # Return the first list if the totals are equal", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n # Calculate total number of characters in each list\n count1 = sum(len(word) for word in lst1)\n count2 = sum(len(word) for word in lst2)\n \n # Return the list with fewer total characters, or the first list if equal\n return lst1 if count1 <= count2 else lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n # Calculate the total number of characters in each list\n total_chars_lst1 = sum(len(s) for s in lst1)\n total_chars_lst2 = sum(len(s) for s in lst2)\n\n # Compare and return the list with fewer total characters, or the first one if equal\n if total_chars_lst1 <= total_chars_lst2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n # Calculate the total number of characters in each list\n total_chars_lst1 = sum(len(s) for s in lst1)\n total_chars_lst2 = sum(len(s) for s in lst2)\n \n # Compare and return the list with fewer total characters, or the first list if they are equal\n if total_chars_lst1 <= total_chars_lst2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n '''\n # Calculate the total number of chars in both lists\n total_chars_lst1 = sum(len(s) for s in lst1)\n total_chars_lst2 = sum(len(s) for s in lst2)\n\n # Return the list with the fewer total chars, or the first list if they are equal\n if total_chars_lst1 <= total_chars_lst2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n '''\n # Calculate total number of characters in both lists\n total_chars_lst1 = sum(len(s) for s in lst1)\n total_chars_lst2 = sum(len(s) for s in lst2)\n\n # Return the list with fewer total characters, or the first list if equal\n if total_chars_lst1 <= total_chars_lst2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}]}, "HumanEval/85": {"dps": 91.68316831683168, "dps_norm": 60.0, "pass@1": 100.0, "profiled": [{"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n # Initialize the sum to zero\n total_sum = 0\n \n # Loop through the list, starting from index 1 (the second element), stepping by 2\n for i in range(1, len(lst), 2):\n # Check if the element at the odd index is even\n if lst[i] % 2 == 0:\n total_sum += lst[i]\n \n return total_sum", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"\n Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n # Initialize the sum to zero\n sum_even_at_odd_indices = 0\n \n # Loop through the list with index\n for index in range(1, len(lst), 2): # Start from 1 to consider odd indices\n # Check if the element at the current odd index is even\n if lst[index] % 2 == 0:\n # Add the even number to the sum\n sum_even_at_odd_indices += lst[index]\n \n return sum_even_at_odd_indices", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2\n \"\"\"\n total_sum = 0\n for i in range(1, len(lst), 2): # Start from 1 to check odd indices\n if lst[i] % 2 == 0:\n total_sum += lst[i]\n return total_sum", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n # Initialize sum to zero\n total_sum = 0\n \n # Iterate over the list with index\n for index in range(1, len(lst), 2): # Start from 1 to ensure we check odd indices\n if lst[index] % 2 == 0:\n total_sum += lst[index]\n \n return total_sum", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n return sum(x for i, x in enumerate(lst) if i % 2 != 0 and x % 2 == 0)", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n return sum(lst[i] for i in range(1, len(lst), 2) if lst[i] % 2 == 0)", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"\n Adds the even elements that are at odd indices in the given list of integers.\n \n :param lst: List of integers\n :return: Sum of even elements at odd indices\n \"\"\"\n # Initialize the sum\n sum_even = 0\n \n # Iterate through the list, starting from index 1 (second element), stepping by 2\n for i in range(1, len(lst), 2):\n # Check if the element at the current odd index is even\n if lst[i] % 2 == 0:\n # Add it to the sum\n sum_even += lst[i]\n \n return sum_even", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. Add the even elements that are at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n # Initialize sum of even elements at odd indices\n sum_even_at_odd_indices = 0\n\n # Loop through the list with index\n for index in range(len(lst)):\n # Check if the index is odd and the element at that index is even\n if index % 2 != 0 and lst[index] % 2 == 0:\n sum_even_at_odd_indices += lst[index]\n \n return sum_even_at_odd_indices", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n total = 0\n # Loop through the list, starting from the second element (index 1)\n for i in range(1, len(lst), 2):\n if lst[i] % 2 == 0:\n total += lst[i]\n return total", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"\n Given a non-empty list of integers lst, adds the even elements that are at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2\n \"\"\"\n # Initialize the sum to zero\n total = 0\n \n # Loop through the list, starting from the second element, with a step of 2\n for i in range(1, len(lst), 2):\n # Check if the current element is even\n if lst[i] % 2 == 0:\n # Add the even element to the total\n total += lst[i]\n \n # Return the total sum of even elements at odd indices\n return total", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"\n Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2\n \"\"\"\n # Initialize the sum to zero\n sum_even_at_odd_indices = 0\n\n # Iterate through the list, starting from index 1 and incrementing by 2 to only check odd indices\n for i in range(1, len(lst), 2):\n if lst[i] % 2 == 0:\n sum_even_at_odd_indices += lst[i]\n \n return sum_even_at_odd_indices", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"\n Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Parameters:\n lst (list of int): A non-empty list of integers.\n\n Returns:\n int: The sum of even elements that are at odd indices in the list.\n \"\"\"\n # Initialize sum to 0\n sum_even_at_odd_indices = 0\n\n # Iterate over the list\n for index, value in enumerate(lst):\n # Check if the index is odd and the value is even\n if index % 2 != 0 and value % 2 == 0:\n # Add the value to the sum\n sum_even_at_odd_indices += value\n\n return sum_even_at_odd_indices", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n total = 0\n for index in range(len(lst)):\n if index % 2 != 0 and lst[index] % 2 == 0:\n total += lst[index]\n return total", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n # Initialize a variable to hold the sum of even elements at odd indices\n sum_even_odd_indices = 0\n\n # Iterate over the list with index\n for index, value in enumerate(lst):\n # Check if the index is odd and the value at that index is even\n if index % 2 != 0 and value % 2 == 0:\n # Add the value to the sum\n sum_even_odd_indices += value\n\n return sum_even_odd_indices", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"\n Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n # Initialize the sum of even elements at odd indices\n sum_even_at_odd_indices = 0\n \n # Iterate over the list using index and value\n for index, value in enumerate(lst):\n # Check if the index is odd and the value is even\n if index % 2 != 0 and value % 2 == 0:\n sum_even_at_odd_indices += value\n \n return sum_even_at_odd_indices", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n # Initialize the sum of even elements at odd indices\n sum_even_at_odd_indices = 0\n\n # Iterate over the list with both index and value\n for index, value in enumerate(lst):\n # Check if the index is odd and the value is even\n if index % 2 != 0 and value % 2 == 0:\n sum_even_at_odd_indices += value\n\n return sum_even_at_odd_indices", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n # Initialize sum to zero\n total = 0\n \n # Iterate over the list, starting from the first odd index (1)\n for index in range(1, len(lst), 2):\n # Check if the current element is even\n if lst[index] % 2 == 0:\n # Add it to the total\n total += lst[index]\n \n # Return the total sum of even elements at odd indices\n return total", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n # Initialize the sum to 0\n sum_even_at_odd_indices = 0\n \n # Loop through the list using index\n for index in range(len(lst)):\n # Check if the index is odd and the element at that index is even\n if index % 2 != 0 and lst[index] % 2 == 0:\n # Add the element to the sum\n sum_even_at_odd_indices += lst[index]\n \n # Return the sum of even elements at odd indices\n return sum_even_at_odd_indices", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"\n Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n # Initialize sum to store the sum of even elements at odd indices\n even_sum = 0\n\n # Iterate through the list by index\n for index in range(1, len(lst), 2): # Start from 1 to target odd indices\n if lst[index] % 2 == 0: # Check if element is even\n even_sum += lst[index]\n\n return even_sum", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. Add the even elements that are at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n # Initialize sum\n total = 0\n \n # Iterate through the list, starting from index 1, and considering every other element (odd indices)\n for i in range(1, len(lst), 2):\n if lst[i] % 2 == 0:\n total += lst[i]\n \n return total", "matching_cluster_idx": 3}]}, "HumanEval/86": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 90.0, "profiled": [{"solution": "def anti_shuffle(s):\n \"\"\"\n Takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n :param s: String to be ordered\n :return: Ordered string version\n \"\"\"\n # Split the string into words\n words = s.split(' ')\n # Initialize a list to hold the ordered words\n ordered_words = []\n # Iterate over each word\n for word in words:\n # Sort the characters in the word and join them back into a string\n sorted_word = ''.join(sorted(word))\n # Append the sorted word to the list\n ordered_words.append(sorted_word)\n # Join the words back into a string with spaces in between\n ordered_sentence = ' '.join(ordered_words)\n return ordered_sentence", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n \"\"\"\n # Split the input string into words based on spaces\n words = s.split(' ')\n \n # Initialize an empty list to hold the transformed words\n transformed_words = []\n\n # Iterate over each word\n for word in words:\n # Convert the word into a list of characters, sort it, then join back into a string\n sorted_word = ''.join(sorted(word))\n # Append the transformed word to the list\n transformed_words.append(sorted_word)\n\n # Join the transformed words back into a single string, separated by spaces\n ordered_s = ' '.join(transformed_words)\n \n return ordered_s", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n # Split the string into words\n words = s.split(' ')\n \n # Transform each word by sorting the characters\n ordered_words = [''.join(sorted(word)) for word in words]\n \n # Join the ordered words back into a string with spaces\n return ' '.join(ordered_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n :param s: input string\n :return: ordered version of the input string\n \"\"\"\n # Split the input string into words based on spaces\n words = s.split(' ')\n # For each word, sort the characters and reconstruct the word\n ordered_words = [''.join(sorted(word)) for word in words]\n # Join the ordered words back into a string with spaces in between\n ordered_string = ' '.join(ordered_words)\n return ordered_string", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n \"\"\"\n # Split the input string into words based on space delimiter\n words = s.split(' ')\n \n # Initialize a list to hold the transformed words\n ordered_words = []\n \n # Loop through each word to rearrange its characters\n for word in words:\n # Sort the characters of the word based on ascii value and join them back\n ordered_word = ''.join(sorted(word))\n # Append the ordered word to the list of ordered words\n ordered_words.append(ordered_word)\n \n # Join the ordered words back into a single string with spaces in between\n ordered_sentence = ' '.join(ordered_words)\n \n return ordered_sentence", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n \"\"\"\n # Split the input string into words\n words = s.split(' ')\n \n # Sort the characters in each word and join them back\n ordered_words = [''.join(sorted(word)) for word in words]\n \n # Join the ordered words back into a single string\n ordered_string = ' '.join(ordered_words)\n \n return ordered_string", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Takes a string and returns an ordered version of it.\n The ordered version is where characters in each word are arranged in\n ascending order based on ascii value, preserving the order of words and blank spaces.\n \"\"\"\n def sort_word(word):\n \"\"\"Sorts a single word based on ascii value.\"\"\"\n return ''.join(sorted(word))\n \n # Splitting the string into words based on space\n words = s.split(' ')\n # Sorting each word and joining them back together with spaces\n sorted_words = [sort_word(word) for word in words]\n # Joining the sorted words back into a sentence\n return ' '.join(sorted_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n def sort_chars(word):\n return ''.join(sorted(word))\n\n return ' '.join([sort_chars(w) for w in s.split(' ')])", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n This function takes a string and returns a version of it where each word\n (words are separated by spaces) is reordered so that characters within\n each word are sorted in ascending ASCII order.\n The function keeps the original order of words and spaces.\n \n Parameters:\n s (str): The input string to be processed.\n \n Returns:\n str: The processed string with each word's characters sorted.\n \"\"\"\n # Split the string into words, keeping the spaces intact\n words = s.split(' ')\n # Sort characters in each word\n sorted_words = [''.join(sorted(word)) for word in words]\n # Join the sorted words back into a string\n return ' '.join(sorted_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Takes a string and returns an ordered version of it.\n Ordered version means all characters in each word (separated by space)\n are arranged in ascending order based on ascii value.\n Blank spaces and order of words are preserved.\n \"\"\"\n # Split the string into words while preserving spaces\n words = s.split(' ')\n \n # Sort characters in each word and join them back to form a sorted word\n ordered_words = [''.join(sorted(word)) for word in words]\n \n # Join the ordered words back into a single string\n ordered_str = ' '.join(ordered_words)\n \n return ordered_str", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n def sort_word(word):\n # Sort the characters in the word and return the new word.\n return ''.join(sorted(word))\n \n # Split the string into words, sort each word, and join them back.\n return ' '.join(sort_word(word) for word in s.split(' '))", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n \"\"\"\n # Split the string into words\n words = s.split(' ')\n # For each word, sort the characters and join them back\n sorted_words = [''.join(sorted(word)) for word in words]\n # Join the sorted words back into a single string\n return ' '.join(sorted_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Takes a string and returns an ordered version of it.\n The words in the ordered string have their characters sorted in ascending order based on ASCII value.\n The order of words and blank spaces in the sentence is preserved.\n \"\"\"\n # Split the input string into words\n words = s.split(' ')\n # Sort each word's characters and join them back into a word\n sorted_words = [''.join(sorted(word)) for word in words]\n # Join the sorted words back into a sentence\n ordered_string = ' '.join(sorted_words)\n return ordered_string", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Takes a string and returns an ordered version of it.\n In the ordered version, characters in each word are sorted based on ascii value.\n Spaces and the order of words are preserved.\n \"\"\"\n # Split the input string into words\n words = s.split(' ')\n \n # Initialize an empty list to store the modified words\n ordered_words = []\n \n # Loop through each word in the list\n for word in words:\n # Sort the characters in the word based on ascii value and join them back into a string\n sorted_word = ''.join(sorted(word))\n # Append the ordered word to the list\n ordered_words.append(sorted_word)\n \n # Join the ordered words back into a string with spaces in between\n ordered_s = ' '.join(ordered_words)\n \n # Return the ordered string\n return ordered_s", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n \"\"\"\n return ' '.join(''.join(sorted(word)) for word in s.split(' '))", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Writes a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n \"\"\"\n # Splitting the string into words\n words = s.split(' ')\n # Processing each word to sort the characters\n ordered_words = [''.join(sorted(word)) for word in words]\n # Joining the words back into a single string\n return ' '.join(ordered_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n # Split the string into words\n words = s.split(' ')\n # Order each word and maintain the order of words\n ordered_words = [''.join(sorted(word)) for word in words]\n # Join the ordered words back into a string\n return ' '.join(ordered_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n words = s.split(' ')\n ordered_words = [\"\".join(sorted(word)) for word in words]\n return ' '.join(ordered_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters are arranged in ascending\n order based on ascii value.\n Note: Keeps the order of words and blank spaces in the sentence.\n\n :param s: The input string to be transformed.\n :return: The transformed string with ordered characters in each word.\n \"\"\"\n # Split the input string into words, keeping the order and blank spaces\n words = s.split(' ')\n # Transform each word by sorting its characters\n transformed_words = [''.join(sorted(word)) for word in words]\n # Join the transformed words back into a string\n return ' '.join(transformed_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n \"\"\"\n # Split the input string into words\n words = s.split(' ')\n \n # Initialize the list that will hold the transformed words\n ordered_words = []\n \n # Iterate over each word in the input string\n for word in words:\n # Sort the characters of the word and join them back into a string\n ordered_word = ''.join(sorted(word))\n # Append the ordered word to the list of ordered words\n ordered_words.append(ordered_word)\n \n # Join the ordered words back into a single string with spaces\n result = ' '.join(ordered_words)\n \n return result", "matching_cluster_idx": 4}]}, "HumanEval/87": {"dps": 93.94812680115274, "dps_norm": 57.142857142857146, "pass@1": 97.0, "profiled": [{"solution": "def get_row(lst, x):\n \"\"\"\n Find occurrences of integer x in a nested list and return their coordinates sorted.\n \"\"\"\n # List to store coordinates of the found elements.\n coordinates = []\n\n # Iterate through the list to find the occurrences of x.\n for row_index, row in enumerate(lst):\n for col_index, value in enumerate(row):\n if value == x:\n coordinates.append((row_index, col_index))\n\n # Sort coordinates by row in ascending order and then by column in descending order within each row.\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n\n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n Given a 2D list and an integer x, this function finds the integer x in the list\n and returns a sorted list of tuples (coordinates), where each tuple is a (row, column)\n coordinate of x. The coordinates are sorted by row in ascending order and by column in\n descending order within the same row.\n \"\"\"\n # Find the coordinates of x\n coordinates = [(i, j) for i, row in enumerate(lst) for j, value in enumerate(row) if value == x]\n\n # Sort the coordinates by row in ascending and by column in descending order\n sorted_coordinates = sorted(coordinates, key=lambda coord: (coord[0], -coord[1]))\n\n return sorted_coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n Finds integers x in the given nested list and returns their coordinates\n sorted by row in ascending order and column in descending order within rows.\n \"\"\"\n # Find coordinates of x in the list\n coordinates = []\n for row_idx, row in enumerate(lst):\n for col_idx, value in enumerate(row):\n if value == x:\n coordinates.append((row_idx, col_idx))\n \n # Sort coordinates by row in ascending order, column in descending order within rows\n sorted_coordinates = sorted(coordinates, key=lambda coord: (coord[0], -coord[1]))\n \n return sorted_coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n Searches for integer x in the given 2D list (lst) and returns\n a list of tuples representing coordinates of the found items.\n Coordinates are sorted by rows in ascending order and by columns\n in descending order within each row.\n \"\"\"\n found_items = []\n \n # Loop through each row and its index\n for row_index, row in enumerate(lst):\n # Loop through each column and its index in the row\n for col_index, value in enumerate(row):\n # If the value matches the integer x, store the coordinates\n if value == x:\n found_items.append((row_index, col_index))\n \n # Sort the list of found items by row in ascending order\n # and by column in descending order within each row\n found_items.sort(key=lambda item: (item[0], -item[1]))\n \n return found_items", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n This function searches through a 2D list with variable column lengths\n and finds all occurrences of the integer x, returning their coordinates\n as tuples. Coordinates are sorted by rows in ascending order and by columns\n in descending order within each row.\n \"\"\"\n # List to hold the coordinates of found x values\n coordinates = []\n \n # Loop through each row in the list\n for row_index, row in enumerate(lst):\n # Loop through each column in the row\n for col_index, value in enumerate(row):\n # If the value matches x, add its coordinates to the list\n if value == x:\n coordinates.append((row_index, col_index))\n \n # Sort the coordinates: by row in ascending order, then by column in descending order\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n \n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n Finds the occurrence of integer x in the given nested list and returns the coordinates\n sorted by row in ascending order and by column in descending order within each row.\n \n :param lst: A 2D list with potentially varying column lengths.\n :param x: The integer to find in the list.\n :return: A list of tuples with coordinates of found x values.\n \"\"\"\n coordinates = []\n for row_index, row in enumerate(lst):\n for col_index, value in enumerate(row):\n if value == x:\n coordinates.append((row_index, col_index))\n # Sort by row in ascending order and column in descending order\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n Searches for the occurrences of integer x in the given nested list and returns\n the coordinates of these occurrences sorted by rows in ascending order and\n by columns in descending order within the same row.\n \"\"\"\n result = []\n # Iterate over the list to find occurrences of x\n for row_idx, row in enumerate(lst):\n for col_idx, value in enumerate(row):\n if value == x:\n result.append((row_idx, col_idx))\n # Sort the result based on row in ascending order\n # and by column in descending order within each row\n result.sort(key=lambda coord: (coord[0], -coord[1]))\n return result", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n Finds all occurrences of integer x in the given 2D list (lst),\n and returns a list of their coordinates sorted by specified criteria.\n \"\"\"\n # This list will hold tuples of (row, column) indices\n coordinates = []\n\n # Iterate over the list with row index and row itself\n for row_idx, row in enumerate(lst):\n # Iterate over the row with column index and column value\n for col_idx, value in enumerate(row):\n # If the value matches x, add the indices to coordinates\n if value == x:\n coordinates.append((row_idx, col_idx))\n \n # Sort coordinates by row in ascending order, column in descending order\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n\n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n Finds the integer x in the nested list and returns the coordinates of x.\n The coordinates are sorted by rows in ascending order and by columns in descending order.\n \"\"\"\n # Find coordinates of x\n coordinates = []\n for row_idx, row in enumerate(lst):\n for col_idx, elem in enumerate(row):\n if elem == x:\n coordinates.append((row_idx, col_idx))\n \n # Sort coordinates initially by rows in ascending order,\n # and then by columns in descending order within each row\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n \n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n Searches for occurrences of x in the 2D list lst and returns the coordinates in a specified format.\n \"\"\"\n # Collecting the coordinates where the element equals to x\n coordinates = [(row_index, col_index) for row_index, row in enumerate(lst)\n for col_index, element in enumerate(row) if element == x]\n \n # Sorting the coordinates\n # First by row in ascending order, then by column in descending order within each row\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n \n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n Searches for the integer x in a 2D list (nested lists) and returns the coordinates of x in the list.\n The coordinates are sorted by rows in ascending order and by columns in descending order within each row.\n \"\"\"\n result = []\n for row_idx, row in enumerate(lst):\n for col_idx, value in enumerate(row):\n if value == x:\n result.append((row_idx, col_idx))\n # Sorting by row in ascending order and by column in descending order\n result.sort(key=lambda coord: (coord[0], -coord[1]))\n return result", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \"\"\"\n # Initialize a list to store the coordinates\n coordinates = []\n\n # Iterate over the list with both index and row\n for row_index, row in enumerate(lst):\n # Iterate over the row to find the value x\n for col_index, value in enumerate(row):\n if value == x:\n # Append the found coordinate as a tuple to the list\n coordinates.append((row_index, col_index))\n \n # Sort the coordinates by row in ascending and by column in descending order\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n\n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n This function finds occurrences of integer x in a 2D nested list,\n where rows may have different lengths. It returns a list of coordinates,\n where each coordinate is a tuple (row, column). Coordinates are sorted\n by rows in ascending order, and within each row, by columns in descending order.\n \"\"\"\n # Initialize an empty list to store the coordinates\n coordinates = []\n\n # Iterate through each row in the list\n for row_index, row in enumerate(lst):\n # Iterate through each element in the row\n for col_index, elem in enumerate(row):\n # If the element is equal to the given integer x, add its coordinate to the list\n if elem == x:\n coordinates.append((row_index, col_index))\n \n # Sort coordinates by row in ascending order and by column in descending order\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n\n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n coordinates = []\n for i, row in enumerate(lst):\n for j, value in enumerate(row):\n if value == x:\n coordinates.append((i, j))\n \n # Sort by row in ascending order and by column in descending order within each row\n return sorted(coordinates, key=lambda coord: (coord[0], -coord[1]))", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n Finds the integer x in a nested list and returns the coordinates of each occurrence.\n Sorts the coordinates by rows in ascending order and within rows by columns in descending order.\n \"\"\"\n # Initialize an empty list to store the coordinates of found integers.\n coordinates = []\n \n # Iterate over the list with both row index and its content.\n for row_index, row in enumerate(lst):\n # Iterate over the row with both column index and its content.\n for col_index, element in enumerate(row):\n # Check if the element matches the integer x.\n if element == x:\n # If yes, append its coordinate to the coordinates list.\n coordinates.append((row_index, col_index))\n \n # Sort coordinates by row in ascending order.\n # Within the same row, sort by column in descending order.\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n \n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n Finds the coordinates of integer x in the 2D list 'lst',\n and returns a list of tuples sorted by rows in ascending order\n and by columns in descending order within each row.\n \"\"\"\n coordinates = []\n for row_idx, row in enumerate(lst):\n for col_idx, item in enumerate(row):\n if item == x:\n coordinates.append((row_idx, col_idx))\n \n # Sort the coordinates by row in ascending order and by column in descending order\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n \n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n Finds occurrences of x in the given 2D list and returns their coordinates.\n Sorts the coordinates first by rows in ascending order and then by columns in descending order within each row.\n \"\"\"\n coordinates = []\n \n for row_index, row in enumerate(lst):\n for col_index, value in enumerate(row):\n if value == x:\n coordinates.append((row_index, col_index))\n \n # Sorting by row in ascending order, then by column in descending order within the same row\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n \n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n Given a 2D list and an integer x, return a list of tuples with\n coordinates of occurrences of x in the list. Coordinates are sorted\n first by rows in ascending order and then by columns in descending order.\n \"\"\"\n coordinates = []\n for row_index, row in enumerate(lst):\n for col_index, item in enumerate(row):\n if item == x:\n coordinates.append((row_index, col_index))\n \n # Sort by row in ascending order and then by column in descending order\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n Given a 2D list (nested lists) and an integer x, find all occurrences of x,\n and return a list of tuples indicating the coordinates of those occurrences.\n The coordinates are sorted by rows in ascending order, and within each row,\n sorted by columns in descending order.\n \"\"\"\n coordinates = []\n # Iterate over the list to find the occurrences of x\n for i, row in enumerate(lst):\n for j, val in enumerate(row):\n if val == x:\n coordinates.append((i, j))\n # Sorting the coordinates as specified\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n Searches for integer x in a 2D list (nested lists) and returns the coordinates\n of each occurrence of x, sorted by rows in ascending order and columns in descending order.\n \"\"\"\n # Find and collect the coordinates\n coordinates = [(i, j) for i, sublist in enumerate(lst) for j, value in enumerate(sublist) if value == x]\n \n # Sort the coordinates first by rows (ascending) then by columns (descending)\n sorted_coordinates = sorted(coordinates, key=lambda coord: (coord[0], -coord[1]))\n \n return sorted_coordinates", "matching_cluster_idx": 3}]}, "HumanEval/89": {"dps": 97.15206185567011, "dps_norm": 45.0, "pass@1": 99.0, "profiled": [{"solution": "def encrypt(s):\n \"\"\"Encrypts a string by rotating the alphabet by four places.\"\"\"\n # Define the alphabet and the rotated alphabet\n alphabet = 'abcdefghijklmnopqrstuvwxyz'\n rotated_alphabet = 'efghijklmnopqrstuvwxyzabcd'\n \n # Create a translation table\n translation_table = str.maketrans(alphabet, rotated_alphabet)\n \n # Encrypt the string using the translation table\n encrypted_string = s.translate(translation_table)\n \n return encrypted_string", "matching_cluster_idx": 6}, {"solution": "def encrypt(s):\n \"\"\"Encrypts the input string by rotating the alphabet letters \n by four places down (2*2).\n \"\"\"\n # Define the alphabet\n alphabet = 'abcdefghijklmnopqrstuvwxyz'\n encrypted_s = ''\n for char in s:\n if char in alphabet:\n # Find the original index and apply the shift, wrapping around if necessary\n shifted_index = (alphabet.index(char) + 4) % len(alphabet)\n encrypted_s += alphabet[shifted_index]\n else:\n # Handle characters not in the alphabet (like spaces or punctuation)\n encrypted_s += char\n return encrypted_s", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Encrypt a string by rotating the alphabet.\n \n The rotation is such that each letter is replaced by a letter\n two times two places down the alphabet. Wraps around the end\n of the alphabet.\n \n Args:\n s (str): The input string to encrypt.\n \n Returns:\n str: The encrypted string.\n \"\"\"\n alphabet = 'abcdefghijklmnopqrstuvwxyz'\n shift = 2 * 2 # Two multiplied by two\n encrypted_str = ''\n \n for char in s:\n if char in alphabet:\n # Find the index of the current character and apply the shift\n new_index = (alphabet.index(char) + shift) % len(alphabet)\n encrypted_str += alphabet[new_index]\n else:\n # If character is not a lowercase letter, just append it as is\n encrypted_str += char\n \n return encrypted_str", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Encrypts a string by rotating the alphabet.\n \n The alphabet is rotated by 4 places (2*2) to the right.\n Only lowercase alphabetic characters are encrypted.\n \n Parameters:\n s (str): The string to be encrypted.\n \n Returns:\n str: The encrypted string.\n \"\"\"\n shift = 4 # Two multiplied by two\n encrypted = []\n \n for char in s:\n if 'a' <= char <= 'z':\n # Calculate the new character after shifting\n new_char = chr(((ord(char) - ord('a') + shift) % 26) + ord('a'))\n encrypted.append(new_char)\n else:\n # Non-alphabetic characters are not encrypted\n encrypted.append(char)\n \n return ''.join(encrypted)", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Encrypt a string by rotating the alphabet by 4 places.\"\"\"\n result = []\n for char in s:\n if 'a' <= char <= 'z':\n # Calculate the new position, with wrap around using modulo\n new_char = chr(((ord(char) - ord('a') + 4) % 26) + ord('a'))\n result.append(new_char)\n else:\n # Non-alphabet characters are kept as is\n result.append(char)\n return ''.join(result)", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Encrypts the given string by rotating the alphabet down by four places.\n \n Args:\n s (str): The string to be encrypted.\n \n Returns:\n str: The encrypted string.\n \"\"\"\n # The alphabet string\n alphabet = 'abcdefghijklmnopqrstuvwxyz'\n # The encrypted alphabet string, rotated down by four places\n rotated_alphabet = alphabet[4:] + alphabet[:4]\n # The encrypted string\n encrypted_string = ''\n for char in s:\n if char in alphabet:\n index = alphabet.index(char)\n encrypted_string += rotated_alphabet[index]\n else:\n encrypted_string += char # Append non-alphabetic characters as they are\n \n return encrypted_string", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Encrypts a given string by rotating the alphabet by 4 places.\"\"\"\n # Define the alphabet\n alphabet = 'abcdefghijklmnopqrstuvwxyz'\n encrypted = ''\n \n # Loop through each character in the input string\n for char in s:\n if char in alphabet:\n # Find the new position after shifting 4 places down\n new_pos = (alphabet.index(char) + 4) % 26\n encrypted += alphabet[new_pos]\n else:\n # If the character is not in the alphabet, leave it as is\n encrypted += char\n return encrypted", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Encrypts a given string s by rotating the alphabet.\n \n Each letter in the input string is shifted down by 4 places\n (2 multiplied by 2) in the alphabet. The alphabet wraps around\n such that after 'z', it continues from 'a'.\n \n Args:\n s (str): The string to be encrypted.\n \n Returns:\n str: The encrypted string.\n \"\"\"\n encrypted = []\n for char in s:\n if 'a' <= char <= 'z':\n # Calculate the new character after shifting\n new_char = chr(((ord(char) - ord('a') + 4) % 26) + ord('a'))\n encrypted.append(new_char)\n else:\n # If not a letter, append as it is\n encrypted.append(char)\n return ''.join(encrypted)", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Encrypts the input string s by rotating each letter down the alphabet \n by 4 places (2 * 2).\n \"\"\"\n # Define the alphabet and an empty result string\n alphabet = 'abcdefghijklmnopqrstuvwxyz'\n result = ''\n \n # Iterate over each character in the input string\n for char in s:\n if char in alphabet:\n # Calculate the new position, wrap around using modulo\n new_pos = (alphabet.index(char) + 4) % 26\n result += alphabet[new_pos]\n else:\n # Handle non-alphabetic characters by leaving them as-is\n result += char\n \n return result", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Encrypts the input string by rotating the alphabet.\n Each character is shifted by four places down the alphabet.\n \"\"\"\n # Define the alphabet and the shifted alphabet\n alphabet = 'abcdefghijklmnopqrstuvwxyz'\n shifted_alphabet = alphabet[4:] + alphabet[:4]\n \n # Create a dictionary to map each letter to its encrypted version\n encryption_map = dict(zip(alphabet, shifted_alphabet))\n \n # Encrypt the input string\n encrypted_string = ''.join(encryption_map.get(c, c) for c in s)\n \n return encrypted_string", "matching_cluster_idx": 2}, {"solution": "def encrypt(s):\n \"\"\"Encrypts the given string by rotating the alphabet by 4 places.\n \n Args:\n s (str): The input string to encrypt.\n \n Returns:\n str: The encrypted string with the alphabet rotated by 4 places.\n \"\"\"\n # Define the alphabet and the rotated alphabet\n alphabet = 'abcdefghijklmnopqrstuvwxyz'\n rotated_alphabet = alphabet[4:] + alphabet[:4]\n \n # Create a translation table\n translation_table = str.maketrans(alphabet, rotated_alphabet)\n \n # Translate the input string using the translation table\n encrypted_string = s.translate(translation_table)\n \n return encrypted_string", "matching_cluster_idx": 5}, {"solution": "def encrypt(s):\n \"\"\"Encrypts the input string by rotating the alphabet by four places.\"\"\"\n encrypted_str = \"\"\n for char in s:\n # Check if character is a lowercase letter\n if 'a' <= char <= 'z':\n # Calculate the new character, wrapping around the alphabet if necessary\n new_char = chr(((ord(char) - ord('a') + 4) % 26) + ord('a'))\n encrypted_str += new_char\n else:\n # If the character is not a lowercase letter, leave it unchanged\n encrypted_str += char\n return encrypted_str", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Encrypt a given string by rotating the alphabet by four places.\"\"\"\n # Define the alphabet and the rotated alphabet\n alphabet = 'abcdefghijklmnopqrstuvwxyz'\n rotated_alphabet = alphabet[4:] + alphabet[:4]\n \n # Create a translation table between the normal and rotated alphabets\n translation_table = str.maketrans(alphabet, rotated_alphabet)\n \n # Translate the input string using the translation table\n encrypted_string = s.translate(translation_table)\n \n return encrypted_string", "matching_cluster_idx": 5}, {"solution": "def encrypt(s):\n \"\"\"Encrypts a given string by rotating the alphabet down by four places.\n \n Args:\n s (str): The string to be encrypted.\n \n Returns:\n str: The encrypted string.\n \"\"\"\n alphabet = 'abcdefghijklmnopqrstuvwxyz'\n encrypted_str = ''\n for char in s:\n if char in alphabet:\n new_index = (alphabet.index(char) + 4) % len(alphabet)\n encrypted_str += alphabet[new_index]\n else:\n encrypted_str += char # Keep non-alphabet characters as is.\n return encrypted_str", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Encrypts the input string with a rotated alphabet. The rotation\n is defined as a shift down by two multiplied by two places.\n \n Args:\n s (str): The input string to be encrypted.\n\n Returns:\n str: The encrypted string.\n \"\"\"\n # Define the shift value\n shift = 2 * 2\n \n # Convert the string to the encrypted string\n encrypted_string = \"\"\n for char in s:\n if char.isalpha():\n # Calculate the shifted character\n shifted_char = ord(char) + shift\n # Wrap around if necessary\n if char.islower():\n if shifted_char > ord('z'):\n shifted_char -= 26\n elif char.isupper():\n if shifted_char > ord('Z'):\n shifted_char -= 26\n encrypted_string += chr(shifted_char)\n else:\n # If not an alphabet character, keep as is\n encrypted_string += char\n\n return encrypted_string", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Encrypts the input string by rotating the alphabet by four places.\n \n Args:\n s (str): The input string to be encrypted.\n \n Returns:\n str: The encrypted string.\n \"\"\"\n # Define the alphabet and the rotated alphabet by four places\n alphabet = 'abcdefghijklmnopqrstuvwxyz'\n rotated_alphabet = alphabet[4:] + alphabet[:4]\n \n # Create a translation table\n translation_table = str.maketrans(alphabet, rotated_alphabet)\n \n # Translate the input string using the translation table\n encrypted_string = s.translate(translation_table)\n \n return encrypted_string", "matching_cluster_idx": 5}, {"solution": "def encrypt(s):\n \"\"\"Encrypts a given string by rotating the alphabet down by four places.\"\"\"\n # Define the alphabet\n alphabet = 'abcdefghijklmnopqrstuvwxyz'\n encrypted_str = ''\n \n # Iterate through each character in the string\n for char in s:\n if char in alphabet:\n # Find the current character's index and apply the shift\n index = (alphabet.index(char) + 4) % len(alphabet)\n encrypted_str += alphabet[index]\n else:\n # Keep non-alphabetic characters as is\n encrypted_str += char\n \n return encrypted_str", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Encrypt a string with a rotated alphabet.\n \n The alphabet is rotated by 4 places down (2 multiplied by 2).\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n alphabet = 'abcdefghijklmnopqrstuvwxyz'\n rotated_alphabet = alphabet[4:] + alphabet[:4] # Rotate by 4 places\n encrypted_string = ''\n \n for char in s:\n if char in alphabet:\n index = alphabet.index(char)\n encrypted_string += rotated_alphabet[index]\n else:\n encrypted_string += char # Non-alphabet characters remain unchanged\n \n return encrypted_string", "matching_cluster_idx": 1}, {"solution": "def encrypt(s: str) -> str:\n \"\"\"\n Encrypts a given string by rotating the alphabet by four places.\n Each letter in the input string is replaced by the letter four places\n down the alphabet.\n \n Parameters:\n s (str): The input string to be encrypted.\n \n Returns:\n str: The encrypted string.\n \"\"\"\n alphabet = 'abcdefghijklmnopqrstuvwxyz'\n encrypted_str = ''\n for char in s:\n if char in alphabet:\n new_pos = (alphabet.index(char) + 4) % 26\n encrypted_str += alphabet[new_pos]\n else:\n encrypted_str += char\n return encrypted_str", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Encrypts a string by rotating the alphabet by 4 places.\"\"\"\n # Define the alphabet and the rotated alphabet\n original_alphabet = 'abcdefghijklmnopqrstuvwxyz'\n rotated_alphabet = 'efghijklmnopqrstuvwxyzabcd'\n\n # Create a translation table\n translation_table = str.maketrans(original_alphabet, rotated_alphabet)\n\n # Translate the input string using the translation table\n encrypted_string = s.translate(translation_table)\n\n return encrypted_string", "matching_cluster_idx": 6}]}, "HumanEval/90": {"dps": 87.54863813229572, "dps_norm": 58.333333333333336, "pass@1": 100.0, "profiled": [{"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n # Convert the list to a set to remove duplicates and then back to a sorted list\n unique_sorted_lst = sorted(set(lst))\n \n # Check if the list has at least two unique elements\n if len(unique_sorted_lst) < 2:\n return None\n else:\n return unique_sorted_lst[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n # Remove duplicates by converting to a set, then back to a sorted list\n unique_sorted_lst = sorted(set(lst))\n \n # Check if there are at least 2 unique elements\n if len(unique_sorted_lst) < 2:\n return None\n else:\n # Return the second element in the sorted list\n return unique_sorted_lst[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n # Remove duplicates and check if we have at least 2 unique elements\n unique_lst = list(set(lst))\n if len(unique_lst) < 2:\n return None\n # Sort the list and return the 2nd element\n unique_lst.sort()\n return unique_lst[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n # Remove duplicates by converting to a set, then back to list for sorting\n unique_lst = sorted(set(lst))\n \n # Check if there are at least 2 unique elements\n if len(unique_lst) < 2:\n return None\n else:\n # Return the second smallest element\n return unique_lst[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n # Remove duplicates and sort the list\n sorted_unique_lst = sorted(set(lst))\n \n # Check if the list has at least 2 unique elements\n if len(sorted_unique_lst) < 2:\n return None\n else:\n return sorted_unique_lst[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n # Remove duplicates to handle cases where all elements are the same\n unique_lst = list(set(lst))\n # Check if there are at least 2 unique elements\n if len(unique_lst) < 2:\n return None\n # Sort the unique list and return the second element\n unique_lst.sort()\n return unique_lst[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n # Remove duplicates and check if there's a second smallest element\n unique_elements = list(set(lst))\n \n if len(unique_elements) < 2:\n return None\n \n unique_elements.sort()\n return unique_elements[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n\n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n unique_numbers = list(set(lst))\n if len(unique_numbers) < 2:\n return None\n unique_numbers.sort()\n return unique_numbers[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n if len(lst) < 2:\n return None\n\n unique_elements = list(set(lst))\n if len(unique_elements) < 2:\n return None\n \n unique_elements.sort()\n return unique_elements[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n # Remove duplicates and sort the list\n unique_lst = sorted(set(lst))\n \n # Check if there is a second smallest element\n if len(unique_lst) < 2:\n return None\n else:\n return unique_lst[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n # Remove duplicates and sort the list\n unique_lst = sorted(set(lst))\n # Check if there's at least 2 unique elements\n if len(unique_lst) < 2:\n return None\n else:\n return unique_lst[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n Finds the second smallest element in a list of integers.\n Returns None if there is no such element.\n \"\"\"\n if len(lst) < 2:\n return None\n unique_elements = list(set(lst))\n if len(unique_elements) < 2:\n return None\n unique_elements.sort()\n return unique_elements[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n if len(lst) < 2:\n return None\n unique_elements = set(lst)\n if len(unique_elements) < 2:\n return None\n sorted_elements = sorted(unique_elements)\n return sorted_elements[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n # Convert the list into a set to remove duplicates then back to list\n unique_list = list(set(lst))\n \n # Check if we have at least 2 unique elements\n if len(unique_list) < 2:\n return None\n \n # Sort the unique elements to find the second smallest\n unique_list.sort()\n \n # Return the second element in the sorted unique list\n return unique_list[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n \n unique_elements = list(set(lst))\n if len(unique_elements) < 2:\n return None\n \n unique_elements.sort()\n return unique_elements[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n Finds the 2nd smallest element in the list lst.\n \n :param lst: List of integers.\n :return: The 2nd smallest element if exists, otherwise None.\n \"\"\"\n if len(lst) < 2:\n return None\n unique_elements = set(lst)\n if len(unique_elements) < 2:\n return None\n sorted_elements = sorted(unique_elements)\n return sorted_elements[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n # Check if the list is too short to have a 2nd smallest element\n if len(lst) < 2:\n return None\n\n # Convert the list to a set to remove duplicates, then back to a sorted list\n unique_sorted_lst = sorted(set(lst))\n \n # Check if after removing duplicates we have at least two different elements\n if len(unique_sorted_lst) < 2:\n return None\n \n # Return the second element from the sorted unique list\n return unique_sorted_lst[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n # Remove duplicates and handle empty list or list with a single element\n unique_lst = list(set(lst))\n if len(unique_lst) < 2:\n return None\n \n # Sort the list and return the second element\n unique_lst.sort()\n return unique_lst[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n # Remove duplicates by converting to a set, then back to a sorted list\n unique_sorted_lst = sorted(set(lst))\n \n # Check if there is a second smallest element\n if len(unique_sorted_lst) < 2:\n return None\n else:\n return unique_sorted_lst[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n # Remove duplicates by converting to a set then back to a list\n unique_lst = list(set(lst))\n \n # Check if there are at least two unique elements\n if len(unique_lst) < 2:\n return None\n \n # Sort the list and return the second item\n unique_lst.sort()\n return unique_lst[1]", "matching_cluster_idx": 6}]}, "HumanEval/113": {"dps": 98.98580121703854, "dps_norm": 66.66666666666667, "pass@1": 97.0, "profiled": [{"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n \"\"\"\n result = []\n for string in lst:\n odd_count = sum(1 for digit in string if int(digit) % 2 != 0)\n result.append(f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\")\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n \"\"\"\n result = []\n for string in lst:\n count = sum(1 for digit in string if int(digit) % 2 != 0)\n output_string = f\"the number of odd elements {count}n the str{count}ng {count} of the {count}nput.\"\n result.append(output_string)\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n \"\"\"\n output = []\n for string in lst:\n odd_count = sum(1 for digit in string if int(digit) % 2 != 0)\n template = \"the number of odd elements {0}n the str{0}ng {0} of the {0}nput.\"\n result = template.format(odd_count)\n output.append(result)\n return output", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n \"\"\"\n result = []\n template = \"the number of odd elements {}n the str{}ng {} of the {}nput.\"\n \n for string in lst:\n # Count the number of odd digits in the current string\n odd_count = sum(1 for digit in string if int(digit) % 2 != 0)\n # Use the counted odd number in the template replacing all occurrences of '{}'\n result.append(template.format(odd_count, odd_count, odd_count, odd_count))\n \n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"\n Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n \"\"\"\n result = []\n for s in lst:\n odd_count = sum(int(digit) % 2 for digit in s)\n result.append(f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\")\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n \"\"\"\n output = []\n template = \"the number of odd elements {}n the str{}ng {} of the {}nput.\"\n for s in lst:\n odd_count = sum(int(digit) % 2 for digit in s)\n output.append(template.format(odd_count, odd_count, odd_count, odd_count))\n return output", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"\n Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n \"\"\"\n result = []\n for string in lst:\n # Count the number of odd digits in the current string\n odd_digits_count = sum(int(char) % 2 for char in string)\n # Construct the resulting string with replaced numbers\n template = f\"the number of odd elements {odd_digits_count}n the str{odd_digits_count}ng {odd_digits_count} of the {odd_digits_count}nput.\"\n result.append(template)\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"\n Given a list of strings, where each string consists of only digits, \n return a list. Each element i of the output should be \n \"the number of odd elements in the string i of the input.\" \n where all the i's should be replaced by the number of odd digits \n in the i'th string of the input.\n \"\"\"\n output = []\n for s in lst:\n # Count the number of odd digits in the string\n odd_count = sum(1 for c in s if int(c) % 2 != 0)\n \n # Create the output string with the odd count replacing i\n output_str = f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\"\n output.append(output_str)\n return output", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n \"\"\"\n result = []\n for s in lst:\n # Count the number of odd digits in the string\n odd_count = sum(1 for char in s if int(char) % 2 != 0)\n # Create the result string replacing 'i' with odd_count\n result_str = f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\"\n result.append(result_str)\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n \"\"\"\n # Define the template string\n template = \"the number of odd elements {}n the str{}ng {} of the {}nput.\"\n result = []\n \n # Iterate through each string in the list\n for string in lst:\n # Count the odd numbers in the string\n odd_count = sum(1 for digit in string if int(digit) % 2 != 0)\n # Replace all instances of the odd count in the template string\n result_string = template.format(odd_count, odd_count, odd_count, odd_count)\n # Append the formatted string to the result list\n result.append(result_string)\n \n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"\n Takes a list of strings containing only digits and returns a list of strings\n where each element describes the number of odd digits in the corresponding\n string of the input list with all 'i's replaced by the count of odd digits.\n \n Args:\n lst (list): List of strings containing only digit characters.\n \n Returns:\n list: List of strings describing the odd digit count in each input string.\n \"\"\"\n result = []\n for s in lst:\n odd_digits = sum(1 for char in s if int(char) % 2 != 0)\n output_str = f\"the number of odd elements {odd_digits}n the str{odd_digits}ng {odd_digits} of the {odd_digits}nput.\"\n result.append(output_str)\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n \"\"\"\n output = []\n for s in lst:\n odd_count = sum(1 for char in s if int(char) % 2 != 0)\n formatted_string = f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\"\n output.append(formatted_string)\n return output", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n \"\"\"\n result = []\n for s in lst:\n odd_count = sum(1 for char in s if int(char) % 2 != 0)\n output_str = f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\"\n result.append(output_str)\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n \"\"\"\n result = []\n for num_str in lst:\n odd_count = sum(1 for digit in num_str if int(digit) % 2 != 0)\n template = \"the number of odd elements {}n the str{}ng {} of the {}nput.\"\n result.append(template.format(odd_count, odd_count, odd_count, odd_count))\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n \"\"\"\n output = []\n for s in lst:\n count = sum(1 for c in s if int(c) % 2 != 0)\n result = f\"the number of odd elements {count}n the str{count}ng {count} of the {count}nput.\"\n output.append(result)\n return output", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"\n Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n \"\"\"\n output = []\n template = \"the number of odd elements {}n the str{}ng {} of the {}nput.\"\n for string in lst:\n odd_count = sum(1 for digit in string if int(digit) % 2 != 0)\n output.append(template.format(odd_count, odd_count, odd_count, odd_count))\n return output", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n \"\"\"\n result = []\n template = \"the number of odd elements {}n the str{}ng {} of the {}nput.\"\n for string in lst:\n odd_count = sum(1 for digit in string if int(digit) % 2 != 0)\n result.append(template.format(odd_count, odd_count, odd_count, odd_count))\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n \"\"\"\n result = []\n for s in lst:\n count = sum(1 for char in s if int(char) % 2 != 0)\n template = \"the number of odd elements {}n the str{}ng {} of the {}nput.\"\n result.append(template.format(count, count, count, count))\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"\n Given a list of strings (each string consists of only digits), returns a list.\n Each element in the output corresponds to an element in the input list and\n is a string stating the number of odd digits in the input string, with 'i' in\n the sentence replaced by the count of odd digits.\n \"\"\"\n result = []\n for s in lst:\n odd_digits_count = sum(1 for c in s if int(c) % 2 != 0)\n output_str = f\"the number of odd elements {odd_digits_count}n the str{odd_digits_count}ng {odd_digits_count} of the {odd_digits_count}nput.\"\n result.append(output_str)\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits,\n return a list of formatted strings based on the number of odd digits.\"\"\"\n result = []\n for s in lst:\n odd_count = sum(1 for c in s if int(c) % 2 != 0)\n result.append(f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\")\n return result", "matching_cluster_idx": 3}]}, "HumanEval/119": {"dps": 40.542635658914726, "dps_norm": 49.333333333333336, "pass@1": 15.0, "profiled": [{"solution": "def match_parens(lst):\n # Check both concatenation orders\n for order in [lst, lst[::-1]]:\n balance = 0\n for char in ''.join(order):\n if char == '(':\n balance += 1\n else:\n balance -= 1\n # If at any point the balance goes negative, parentheses are not balanced\n if balance < 0:\n break\n else: # If the loop didn't break, check if the balance is zero\n if balance == 0:\n return 'Yes'\n return 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n\n def is_balanced(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n else:\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n # Try both possible concatenations\n return 'Yes' if is_balanced(lst[0] + lst[1]) or is_balanced(lst[1] + lst[0]) else 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n # Function to check balance of parentheses in a string\n def is_balanced(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n else:\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n # Concatenate in both possible orders and check if either is balanced\n if is_balanced(lst[0] + lst[1]) or is_balanced(lst[1] + lst[0]):\n return 'Yes'\n else:\n return 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n def is_good(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n elif char == ')':\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n # Try concatenating in both possible orders\n if is_good(lst[0] + lst[1]) or is_good(lst[1] + lst[0]):\n return 'Yes'\n else:\n return 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n open_count = lst[0].count('(') + lst[1].count('(')\n close_count = lst[0].count(')') + lst[1].count(')')\n \n # The string can be balanced if and only if the number of\n # open and close parentheses are equal\n if open_count != close_count:\n return 'No'\n \n # Check if concatenation in either order is balanced\n if is_balanced(lst[0] + lst[1]) or is_balanced(lst[1] + lst[0]):\n return 'Yes'\n else:\n return 'No'\ndef is_balanced(s):\n '''\n Helper function to check if the string s has balanced parentheses.\n '''\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n else:\n balance -= 1\n # If at any point balance is negative, we have more closing\n # parenthesis before opening ones, thus not balanced\n if balance < 0:\n return False\n return balance == 0", "matching_cluster_idx": 0}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n open_count = lst[0].count('(') + lst[1].count('(')\n close_count = lst[0].count(')') + lst[1].count(')')\n\n # For the string to be balanced, open and close counts must be equal\n if open_count != close_count:\n return 'No'\n\n # Check if concatenating in either order results in a valid string\n for s1, s2 in [(lst[0], lst[1]), (lst[1], lst[0])]:\n balance = 0\n for char in s1 + s2:\n if char == '(':\n balance += 1\n else:\n balance -= 1\n if balance < 0:\n break\n if balance == 0:\n return 'Yes'\n \n return 'No'", "matching_cluster_idx": 0}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n def is_good(str):\n balance = 0\n for char in str:\n if char == '(':\n balance += 1\n else:\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n s1, s2 = lst\n open_count_s1, close_count_s1 = s1.count('('), s1.count(')')\n open_count_s2, close_count_s2 = s2.count('('), s2.count(')')\n\n # Try concatenating in both orders\n if is_good(s1 + s2) or is_good(s2 + s1):\n return 'Yes'\n else:\n return 'No'", "matching_cluster_idx": 0}, {"solution": "def match_parens(lst):\n # Counters for open and close parentheses\n open_count, close_count = 0, 0\n \n # Count open and close parentheses in both strings\n for s in lst:\n for char in s:\n if char == '(':\n open_count += 1\n else:\n close_count += 1\n \n # Check if they can form a balanced string\n # If total open and close parentheses are equal\n # and no prefix has more closing parentheses than opening ones\n if open_count != close_count:\n return 'No'\n \n # Check if any of the strings is valid by itself\n # or by appending one to the other\n for string_order in [lst, lst[::-1]]:\n balance = 0\n for s in string_order:\n for char in s:\n if char == '(':\n balance += 1\n else:\n balance -= 1\n if balance < 0:\n break\n if balance < 0:\n break\n if balance == 0:\n return 'Yes'\n \n return 'No'", "matching_cluster_idx": -1}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n open_count = lst[0].count('(') + lst[1].count('(')\n close_count = lst[0].count(')') + lst[1].count(')')\n \n # Check if total number of open and close parentheses are equal\n if open_count != close_count:\n return 'No'\n \n # Check if concatenation in any order results in a balanced string\n for order in [lst, lst[::-1]]:\n balance = 0\n for s in order:\n for char in s:\n if char == '(':\n balance += 1\n else:\n balance -= 1\n # If balance goes negative, parentheses are not balanced\n if balance < 0:\n break\n if balance < 0:\n break\n if balance == 0:\n return 'Yes'\n return 'No'", "matching_cluster_idx": 0}, {"solution": "def match_parens(lst):\n '''\n Checks if it is possible to concatenate two strings consisting of only\n parentheses in some order to form a balanced string.\n Returns 'Yes' if possible, 'No' otherwise.\n '''\n # Counters for open and close parentheses\n open_count = 0\n close_count = 0\n \n # Count the number of open and close parentheses in both strings\n for s in lst:\n for char in s:\n if char == '(':\n open_count += 1\n else:\n close_count += 1\n \n # A balanced string must have the same number of open and close parentheses\n if open_count != close_count:\n return 'No'\n \n # Check the first combination\n balance = 0\n for char in lst[0] + lst[1]:\n if char == '(':\n balance += 1\n else:\n balance -= 1\n if balance < 0:\n break\n if balance == 0:\n return 'Yes'\n \n # Check the second combination\n balance = 0\n for char in lst[1] + lst[0]:\n if char == '(':\n balance += 1\n else:\n balance -= 1\n if balance < 0:\n break\n if balance == 0:\n return 'Yes'\n \n return 'No'", "matching_cluster_idx": -1}, {"solution": "def match_parens(lst):\n # Function to check if the given string of parentheses is balanced\n def is_balanced(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n else:\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n # Concatenate in both possible orders and check if either is balanced\n str1, str2 = lst\n if is_balanced(str1 + str2) or is_balanced(str2 + str1):\n return 'Yes'\n return 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n # Count open and closed parentheses in both strings\n open_parens = sum(s.count('(') for s in lst)\n close_parens = sum(s.count(')') for s in lst)\n \n # If the numbers of open and close parentheses are not equal, it cannot be balanced\n if open_parens != close_parens:\n return 'No'\n \n # Check if any of the two concatenated strings is balanced\n for s in [lst[0] + lst[1], lst[1] + lst[0]]:\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n else:\n balance -= 1\n # If balance goes negative, then there are more closing brackets than opening ones\n if balance < 0:\n break\n else:\n # If loop didn't break, balance is not negative at any point and is zero at the end\n if balance == 0:\n return 'Yes'\n return 'No'", "matching_cluster_idx": 0}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n first, second = lst[0], lst[1]\n balance = 0\n # Check if both strings can be concatenated in either order to be balanced\n for char in first + second:\n if char == '(':\n balance += 1\n else:\n balance -= 1\n if balance < 0:\n break\n # If balance is not zero, the first order doesn't work; try reversing the order\n if balance != 0:\n balance = 0\n for char in second + first:\n if char == '(':\n balance += 1\n else:\n balance -= 1\n if balance < 0:\n break\n return 'Yes' if balance == 0 else 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n open_count = lst[0].count('(') + lst[1].count('(')\n close_count = lst[0].count(')') + lst[1].count(')')\n \n # If total open and close parentheses are not equal, they can't be balanced\n if open_count != close_count:\n return 'No'\n \n # Check both possible concatenations\n for strings in [lst, lst[::-1]]:\n balance = 0\n for char in ''.join(strings):\n if char == '(':\n balance += 1\n else:\n balance -= 1\n # If at any point balance is negative, it means there are more closing\n # parentheses than opening ones before, which makes it unbalanced\n if balance < 0:\n break\n else:\n # If the loop didn't break, it means we found a balanced string\n return 'Yes'\n \n return 'No'", "matching_cluster_idx": 0}, {"solution": "def match_parens(lst):\n '''\n Function to check if it's possible to concatenate two given strings\n of parentheses in some order to form a balanced string.\n '''\n # Counting open and close parentheses in both strings\n open_parentheses = lst[0].count('(') + lst[1].count('(')\n close_parentheses = lst[0].count(')') + lst[1].count(')')\n \n # If the total number of open parentheses is not equal to the total\n # number of close parentheses, then it's impossible to form a balanced string\n if open_parentheses != close_parentheses:\n return 'No'\n \n # Check concatenation in both orders\n for order in (lst, lst[::-1]):\n balance = 0\n for s in order:\n for char in s:\n if char == '(':\n balance += 1\n else:\n balance -= 1\n # If balance goes negative, parentheses are not balanced\n if balance < 0:\n break\n if balance < 0:\n break\n else:\n return 'Yes'\n \n return 'No'", "matching_cluster_idx": 0}]}, "HumanEval/120": {"dps": 58.62068965517241, "dps_norm": 88.57142857142857, "pass@1": 47.0, "profiled": [{"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n \"\"\"\n # Sort the array in descending order and slice the first k elements\n sorted_arr = sorted(arr, reverse=True)[:k]\n # Return the sorted_arr in ascending order as the final result\n return sorted(sorted_arr)", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n \"\"\"\n # Sort the array in descending order and slice the top k elements\n sorted_arr = sorted(arr, reverse=True)[:k]\n # Return the sorted list of length k\n return sorted(sorted_arr)", "matching_cluster_idx": 5}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n\n :param arr: List[int], a list of integers.\n :param k: int, the number of maximum values to return.\n :return: List[int], a sorted list of the k largest numbers in arr.\n \"\"\"\n # Sort the array in descending order and take the first k elements.\n sorted_arr = sorted(arr, reverse=True)[:k]\n # Return the sorted list of the k largest numbers.\n return sorted(sorted_arr)", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n \"\"\"\n # Sort the array in descending order and slice the first k elements\n sorted_arr = sorted(arr, reverse=True)[:k]\n # Sort the sliced list in ascending order to match the expected output format\n return sorted(sorted_arr)", "matching_cluster_idx": 5}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n \"\"\"\n # Sort the array in ascending order and then take the last k elements\n sorted_arr = sorted(arr, reverse=True)[:k]\n # Return the sorted list of the maximum k elements\n return sorted(sorted_arr)", "matching_cluster_idx": 5}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n \"\"\"\n # Sort the array in descending order\n sorted_arr = sorted(arr, reverse=True)\n # Slice the first k elements\n max_k_elements = sorted_arr[:k]\n # Sort the result before returning\n return sorted(max_k_elements)", "matching_cluster_idx": 5}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n \"\"\"\n # Sort the array in descending order and slice the first k elements\n sorted_arr = sorted(arr, reverse=True)[:k]\n # Sort the result in ascending order before returning as per the examples\n return sorted(sorted_arr)", "matching_cluster_idx": 5}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n \"\"\"\n if k == 0:\n return []\n # Sort the array in descending order and slice the first k elements\n sorted_arr = sorted(arr, reverse=True)[:k]\n # Return the sorted list of k maximum elements\n return sorted(sorted_arr)", "matching_cluster_idx": 5}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n\n :param arr: List[int] - a list of integers.\n :param k: int - a positive integer indicating the number of maximum elements to return.\n :return: List[int] - a sorted list of the maximum k elements.\n \"\"\"\n # Check edge cases\n if k == 0:\n return []\n if k >= len(arr):\n k = len(arr)\n \n # Sort the array and return the last k elements\n arr.sort()\n return arr[-k:]", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n \"\"\"\n # Sort the array in descending order\n sorted_arr = sorted(arr, reverse=True)\n # Take the first k elements\n result = sorted_arr[:k]\n # Return the result sorted in ascending order\n return sorted(result)", "matching_cluster_idx": 5}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n\n Example 1:\n\n Input: arr = [-3, -4, 5], k = 3\n Output: [-4, -3, 5]\n\n Example 2:\n\n Input: arr = [4, -4, 4], k = 2\n Output: [4, 4]\n\n Example 3:\n\n Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1\n Output: [2]\n\n Note:\n 1. The length of the array will be in the range of [1, 1000].\n 2. The elements in the array will be in the range of [-1000, 1000].\n 3. 0 <= k <= len(arr)\n \"\"\"\n # Sort the array in ascending order and slice the last k elements\n sorted_arr = sorted(arr, reverse=True)[:k]\n # Return the k largest elements in ascending order\n return sorted(sorted_arr)", "matching_cluster_idx": 5}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n \"\"\"\n # Sort the array in descending order and pick the first k elements\n sorted_arr = sorted(arr, reverse=True)[:k]\n # Return the sorted list of length k in ascending order\n return sorted(sorted_arr)", "matching_cluster_idx": 5}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n \"\"\"\n # Sort the array and take the last k elements\n sorted_arr = sorted(arr, reverse=True)[:k]\n # Return the sorted list of the k largest elements\n return sorted(sorted_arr)", "matching_cluster_idx": 5}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n \"\"\"\n if k == 0:\n return []\n \n # Sort the array in ascending order\n arr.sort()\n \n # Slice the last k elements, which are the largest\n result = arr[-k:]\n \n # Return the result in ascending order\n return result", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n \"\"\"\n # Sort the array in descending order and slice the first k elements\n sorted_arr = sorted(arr, reverse=True)\n top_k_elements = sorted_arr[:k]\n \n # Sort the top_k_elements before returning to meet the output requirement\n return sorted(top_k_elements)", "matching_cluster_idx": 5}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n \"\"\"\n # Sort the array in descending order\n sorted_arr = sorted(arr, reverse=True)\n # Slice the first k elements\n result = sorted_arr[:k]\n # Return the sorted (ascending) list of the result\n return sorted(result)", "matching_cluster_idx": 5}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n \"\"\"\n # Sort the array in descending order and slice the first k elements\n sorted_arr = sorted(arr, reverse=True)[:k]\n # Return the sorted (ascending) top k elements\n return sorted(sorted_arr)", "matching_cluster_idx": 5}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n \"\"\"\n # Sort the array in descending order\n sorted_arr = sorted(arr, reverse=True)\n # Take the first k elements\n result = sorted_arr[:k]\n # Return the result sorted in ascending order as per the example\n return sorted(result)", "matching_cluster_idx": 5}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n \"\"\"\n # Sort the array in descending order and then slice it to get the top k elements\n sorted_arr = sorted(arr, reverse=True)[:k]\n # Return the sorted (ascending order) result as required\n return sorted(sorted_arr)", "matching_cluster_idx": 5}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n \"\"\"\n # Sort the array in descending order\n sorted_arr = sorted(arr, reverse=True)\n \n # Take the first k elements from the sorted array\n max_k_elements = sorted_arr[:k]\n \n # Return the k elements sorted in ascending order\n return sorted(max_k_elements)", "matching_cluster_idx": 5}]}, "HumanEval/121": {"dps": 84.12556053811659, "dps_norm": 62.85714285714286, "pass@1": 91.0, "profiled": [{"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n\n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n # Sum of all odd elements in even positions (0-indexed list, so these are actually odd positions in 1-indexed perspective)\n return sum(lst[i] for i in range(0, len(lst), 2) if lst[i] % 2 != 0)", "matching_cluster_idx": 4}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n\n Examples:\n >>> solution([5, 8, 7, 1])\n 12\n >>> solution([3, 3, 3, 3, 3])\n 9\n >>> solution([30, 13, 24, 321])\n 0\n \"\"\"\n # Sum odd elements at even positions. List indices start at 0 in Python,\n # so we use step 2 to iterate over even indices (0, 2, 4, ...),\n # and check if the element is odd before adding it to the sum.\n return sum(x for i, x in enumerate(lst) if i % 2 == 0 and x % 2 == 1)", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n\n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==>0\n \"\"\"\n # Initialize sum of odd elements in even positions\n sum_odds = 0\n \n # Iterate over the list, starting from the first element (index 0), with a step of 2 to cover even positions\n for i in range(0, len(lst), 2):\n # Check if the element is odd\n if lst[i] % 2 != 0:\n # Add it to the sum\n sum_odds += lst[i]\n \n return sum_odds", "matching_cluster_idx": 4}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n\n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==>0\n \"\"\"\n # Initialize the sum to zero\n sum_odd = 0\n # Loop over the elements in the list, starting from the first element (index 0) and stepping by 2 for even positions\n for i in range(0, len(lst), 2):\n # Check if the element at the current even position is odd\n if lst[i] % 2 != 0:\n # Add it to the sum\n sum_odd += lst[i]\n # Return the computed sum\n return sum_odd", "matching_cluster_idx": 4}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n\n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==>0\n \"\"\"\n # Initialize the sum to 0\n total_sum = 0\n \n # Iterate over the list with index\n for index, value in enumerate(lst):\n # Check if the index is even and the value is odd\n if index % 2 == 0 and value % 2 != 0:\n total_sum += value\n \n return total_sum", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n\n Examples:\n >>> solution([5, 8, 7, 1])\n 12\n >>> solution([3, 3, 3, 3, 3])\n 9\n >>> solution([30, 13, 24, 321])\n 0\n \"\"\"\n # Sum all odd elements at even positions (0-based index)\n return sum(value for index, value in enumerate(lst) if index % 2 == 0 and value % 2 != 0)", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n\n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==>0\n \"\"\"\n # Initialize sum to 0\n total_sum = 0\n \n # Iterate through list with index starting at 0 (even position) and step by 2 (even positions)\n for i in range(0, len(lst), 2):\n # Check if the element at the even position is odd\n if lst[i] % 2 != 0:\n # Add odd element to the sum\n total_sum += lst[i]\n \n return total_sum", "matching_cluster_idx": 4}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n\n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n # Initialize the sum to zero\n total_sum = 0\n \n # Loop through the list using index, to check for positions\n for index in range(len(lst)):\n # Check if the index is even and the element is odd\n if index % 2 == 0 and lst[index] % 2 != 0:\n total_sum += lst[index]\n \n return total_sum", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n\n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==>0\n \"\"\"\n # Initialize sum to 0\n total_sum = 0\n \n # Iterate through the list, starting from the first element (index 0), considering every second element\n for i in range(0, len(lst), 2):\n # Check if the current element is odd\n if lst[i] % 2 != 0:\n total_sum += lst[i]\n \n return total_sum", "matching_cluster_idx": 4}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n\n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n # We use list comprehension to filter the elements where:\n # - the index is even (index % 2 == 0 considering Python's 0-based indexing)\n # - the element at that index is odd (element % 2 != 0)\n # Then we sum them up.\n return sum(lst[i] for i in range(len(lst)) if i % 2 == 0 and lst[i] % 2 != 0)", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n\n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n # Initialize the sum to 0\n sum_of_odds = 0\n \n # Iterate through the list with index\n for i in range(len(lst)):\n # Check if the index is even and the element is odd\n if i % 2 == 0 and lst[i] % 2 == 1:\n sum_of_odds += lst[i]\n \n return sum_of_odds", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n\n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==>0\n \"\"\"\n # Sum all odd elements that are in even positions (0-based index, so actual even positions are odd in 1-based index)\n return sum(element for index, element in enumerate(lst) if index % 2 == 0 and element % 2 != 0)", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n\n Examples:\n >>> solution([5, 8, 7, 1])\n 12\n >>> solution([3, 3, 3, 3, 3])\n 9\n >>> solution([30, 13, 24, 321])\n 0\n \"\"\"\n # Initialize sum to 0\n sum_of_odds = 0\n # Iterate through the list, starting from index 0 (first element) and stepping by 2 (even positions)\n for i in range(0, len(lst), 2):\n # Check if the element at the even position is odd\n if lst[i] % 2 != 0:\n # Add it to the sum\n sum_of_odds += lst[i]\n return sum_of_odds", "matching_cluster_idx": 4}, {"solution": "def solution(lst):\n \"\"\"\n Given a non-empty list of integers, returns the sum of all of the odd elements that are in even positions.\n \n Parameters:\n lst (list): A list of integers\n \n Returns:\n int: The sum of odd elements that are in even positions.\n \n Examples:\n >>> solution([5, 8, 7, 1])\n 12\n >>> solution([3, 3, 3, 3, 3])\n 9\n >>> solution([30, 13, 24, 321])\n 0\n \"\"\"\n # Since list indices are 0-based in Python, we need to iterate over the list\n # using indices that represent even positions from a 1-based perspective, which\n # are actually odd in the 0-based index system.\n return sum(element for index, element in enumerate(lst) if index % 2 == 0 and element % 2 != 0)", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==>0\n \"\"\"\n # Initialize the sum to 0\n total = 0\n\n # Loop through the list with index and value\n for index, value in enumerate(lst):\n # Check if the index is even and the value is odd\n if index % 2 == 0 and value % 2 != 0:\n # Add the value to the total\n total += value\n\n # Return the computed sum\n return total", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n\n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n # Initialize the sum to 0\n sum_of_odds = 0\n \n # Loop through the list, considering only even indices (0, 2, 4, ...)\n for i in range(0, len(lst), 2):\n # Check if the element at the even index is odd\n if lst[i] % 2 != 0:\n # Add it to the sum\n sum_of_odds += lst[i]\n \n return sum_of_odds", "matching_cluster_idx": 4}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==>0\n \"\"\"\n # Initialize the sum to zero\n sum_odd_even_positions = 0\n \n # Iterate through the list, considering only even positions (index 0, 2, 4, ...)\n for index in range(0, len(lst), 2):\n # Check if the element is odd\n if lst[index] % 2 != 0:\n # Add it to the sum\n sum_odd_even_positions += lst[index]\n \n return sum_odd_even_positions", "matching_cluster_idx": 4}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n\n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n # Initialize sum\n total_sum = 0\n \n # Iterate over the list with index and element\n for index, value in enumerate(lst):\n # Check if the index is even (0-based) and the element is odd\n if index % 2 == 0 and value % 2 != 0:\n total_sum += value\n \n return total_sum", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n \"\"\"\n Given a non-empty list of integers, returns the sum of all of the odd elements that are in even positions.\n \n Parameters:\n lst (list): A list of integers.\n\n Returns:\n int: The sum of all odd elements that are in even positions.\n \"\"\"\n # Start the sum at 0\n total = 0\n\n # Iterate through the list, indexing by position\n for index in range(len(lst)):\n # Check if the position is even and the element is odd\n if index % 2 == 0 and lst[index] % 2 != 0:\n total += lst[index]\n\n return total", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n\n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==>0\n \"\"\"\n return sum(x for i, x in enumerate(lst) if i % 2 == 0 and x % 2 != 0)", "matching_cluster_idx": 3}]}, "HumanEval/149": {"dps": 86.53543307086615, "dps_norm": 59.28571428571429, "pass@1": 100.0, "profiled": [{"solution": "def sorted_list_sum(lst):\n \"\"\"Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order,\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n You may assume that all words will have the same length.\n \"\"\"\n # Remove strings with odd lengths and sort the resulting list\n filtered_list = [word for word in lst if len(word) % 2 == 0]\n sorted_list = sorted(filtered_list, key=lambda x: (len(x), x))\n return sorted_list", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order,\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n You may assume that all words will have the same length.\n \"\"\"\n # Remove strings with odd lengths\n filtered_list = [s for s in lst if len(s) % 2 == 0]\n # Sort the list by length, then alphabetically\n filtered_list.sort(key=lambda x: (len(x), x))\n return filtered_list", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n # Filter out strings with odd lengths\n even_length_strings = [s for s in lst if len(s) % 2 == 0]\n \n # Sort the list first by the length of the strings, then alphabetically\n sorted_list = sorted(even_length_strings, key=lambda x: (len(x), x))\n \n return sorted_list", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n # Filter out strings with odd lengths\n filtered_list = [s for s in lst if len(s) % 2 == 0]\n # Sort the list by length of the string, and alphabetically for strings of same length\n sorted_list = sorted(filtered_list, key=lambda x: (len(x), x))\n return sorted_list", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order,\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n You may assume that all words will have the same length.\"\"\"\n # Filter out the strings with odd lengths\n even_length_strings = [s for s in lst if len(s) % 2 == 0]\n # Sort the list by length and alphabetically\n sorted_list = sorted(even_length_strings, key=lambda x: (len(x), x))\n return sorted_list", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n # Keep only the strings with even lengths and sort by length, then alphabetically if lengths are equal\n even_length_strings = [s for s in lst if len(s) % 2 == 0]\n sorted_strings = sorted(even_length_strings, key=lambda x: (len(x), x))\n return sorted_strings", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"Sorts the list of strings by their length in ascending order,\n removing strings with odd lengths, and then alphabetically if lengths are equal.\"\"\"\n # Remove strings with odd lengths and sort the resulting list\n sorted_lst = sorted([s for s in lst if len(s) % 2 == 0], key=lambda x: (len(x), x))\n return sorted_lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"\n This function accepts a list of strings, removes strings with odd lengths,\n and returns the list sorted by string lengths in ascending order.\n Strings of the same length are sorted alphabetically.\n \"\"\"\n # Filter out strings with odd lengths\n even_length_strings = [s for s in lst if len(s) % 2 == 0]\n\n # Sort the list: first by length, then alphabetically\n even_length_strings.sort(key=lambda x: (len(x), x))\n \n return even_length_strings", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n # Filter out strings with odd lengths and sort the remaining\n return sorted([s for s in lst if len(s) % 2 == 0], key=lambda x: (len(x), x))", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"Sorts a list of strings by length and alphabetically,\n excluding strings of odd length.\"\"\"\n # Filter out strings of odd length\n filtered_list = [s for s in lst if len(s) % 2 == 0]\n # Sort the list by length, then alphabetically if lengths are the same\n sorted_list = sorted(filtered_list, key=lambda x: (len(x), x))\n return sorted_list", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"\n Accepts a list of strings as a parameter, deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order.\n The list is always a list of strings and never an array of numbers, and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n \n Parameters:\n lst (list): A list of strings.\n\n Returns:\n list: A sorted list of strings with even lengths.\n \"\"\"\n # Remove strings with odd lengths\n even_length_strings = [s for s in lst if len(s) % 2 == 0]\n \n # Sort the list by length, and alphabetically if lengths are equal\n even_length_strings.sort(key=lambda x: (len(x), x))\n \n return even_length_strings", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"\n This function accepts a list of strings, removes strings with odd lengths,\n and returns the resulting list sorted first by the length of the strings,\n then alphabetically if lengths are equal.\n \n :param lst: List of strings\n :return: Sorted list of strings with even lengths\n \"\"\"\n # Filter out strings with odd lengths\n even_length_strings = [string for string in lst if len(string) % 2 == 0]\n \n # Sort the list by length and then alphabetically if lengths are equal\n even_length_strings.sort(key=lambda x: (len(x), x))\n \n return even_length_strings", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"\n Function that deletes strings with odd lengths from a list of strings and returns\n the list sorted first by the length of the strings and then alphabetically if the\n lengths are equal.\n \n Parameters:\n lst (list): The input list of strings.\n \n Returns:\n list: A list of strings sorted by the defined criteria.\n \"\"\"\n # Remove strings with odd lengths\n filtered_lst = [word for word in lst if len(word) % 2 == 0]\n \n # Sort the list by length, and then alphabetically\n sorted_lst = sorted(filtered_lst, key=lambda x: (len(x), x))\n \n return sorted_lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"Returns a sorted list of strings based on the specified criteria.\"\"\"\n # Keep only strings with even lengths\n even_length_strings = [s for s in lst if len(s) % 2 == 0]\n \n # Sort the list first alphabetically, then by length (which is already even)\n even_length_strings.sort()\n even_length_strings.sort(key=len)\n\n return even_length_strings", "matching_cluster_idx": 6}, {"solution": "def sorted_list_sum(lst):\n \"\"\"Sorts and returns a list of strings with only even-length words, sorted by ascending length and alphabetically if lengths are equal.\"\"\"\n # Remove strings with odd lengths\n lst = [word for word in lst if len(word) % 2 == 0]\n \n # Sort the list by length first, then alphabetically\n lst.sort(key=lambda x: (len(x), x))\n \n return lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"Sorts and returns a list of strings after removing the ones with odd lengths.\"\"\"\n # Filter out strings with odd lengths\n filtered_list = [string for string in lst if len(string) % 2 == 0]\n # Sort the list by length and then alphabetically\n sorted_list = sorted(filtered_list, key=lambda x: (len(x), x))\n return sorted_list", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"Sorts a list of strings by the length of each string and alphabetically if lengths are equal.\n Removes strings with odd lengths before sorting.\n \n Args:\n lst (list): The list of strings to be processed.\n \n Returns:\n list: A sorted list of strings with even lengths.\n \"\"\"\n # Filter out strings with odd lengths\n even_length_strings = [s for s in lst if len(s) % 2 == 0]\n \n # Sort the list first alphabetically, then by length\n sorted_list = sorted(even_length_strings, key=lambda x: (len(x), x))\n \n return sorted_list", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order,\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n You may assume that all words will have the same length.\n \"\"\"\n # Filter out strings with odd lengths\n filtered_list = [word for word in lst if len(word) % 2 == 0]\n # Sort the list by length, and then alphabetically\n sorted_list = sorted(filtered_list, key=lambda x: (len(x), x))\n return sorted_list", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order,\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n You may assume that all words will have the same length.\n For example:\n assert list_sort([\"aa\", \"a\", \"aaa\"]) => [\"aa\"]\n assert list_sort([\"ab\", \"a\", \"aaa\", \"cd\"]) => [\"ab\", \"cd\"]\n \"\"\"\n # Remove strings with odd lengths\n filtered_lst = [word for word in lst if len(word) % 2 == 0]\n \n # Sort the list by length and alphabetically if the lengths are the same\n sorted_lst = sorted(filtered_lst, key=lambda x: (len(x), x))\n \n return sorted_lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"\n Returns a sorted list of strings, excluding those with odd lengths.\n \n Args:\n lst (list): A list of strings.\n \n Returns:\n list: A sorted list of strings with even lengths.\n \"\"\"\n # Filter out strings with odd lengths\n even_length_strings = [s for s in lst if len(s) % 2 == 0]\n # Sort the list by length (ascending), then alphabetically\n sorted_list = sorted(even_length_strings, key=lambda x: (len(x), x))\n return sorted_list", "matching_cluster_idx": 3}]}, "Mbpp/3": {"dps": 88.98305084745763, "dps_norm": 93.75, "pass@1": 100.0, "profiled": [{"solution": "def is_not_prime(n):\n \"\"\"\n Determines if a number is not a prime number.\n\n :param n: Integer to check.\n :return: True if n is not a prime number, False otherwise.\n \"\"\"\n if n <= 1:\n return True # 1 and numbers less than 1 are not prime\n if n <= 3:\n return False # 2 and 3 are prime numbers\n if n % 2 == 0 or n % 3 == 0:\n return True # divisible by 2 or 3, thus not a prime number\n \n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return True\n i += 6\n \n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n \"\"\"\n Check if a number is not a prime number.\n \n Parameters:\n n (int): The number to check\n \n Returns:\n bool: True if the number is not prime, False otherwise.\n \"\"\"\n if n <= 1:\n return True # 0 and 1 are not prime numbers\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return True\n return False", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(n):\n \"\"\"\n Check if a number is not a prime number.\n\n Args:\n n (int): The number to check.\n\n Returns:\n bool: True if the number is not prime, False otherwise.\n \"\"\"\n if n <= 1:\n return True # 0 and 1 are not prime numbers\n if n <= 3:\n return False # 2 and 3 are prime numbers\n \n # Check if n is divisible by 2 or 3\n if n % 2 == 0 or n % 3 == 0:\n return True\n \n # Check for divisors up to the square root of n\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return True\n i += 6\n \n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n \"\"\"\n Check if a number is not prime.\n \n Parameters:\n n (int): The number to check.\n \n Returns:\n bool: True if n is not prime, False otherwise.\n \"\"\"\n if n <= 1:\n return True # 0 and 1 are not prime numbers\n if n <= 3:\n return False # 2 and 3 are prime numbers\n if n % 2 == 0 or n % 3 == 0:\n return True # multiples of 2 and 3 are not prime (except 2 and 3)\n \n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return True\n i += 6\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n \"\"\"\n Check if a number is not prime.\n\n :param n: Integer to check\n :return: True if the number is not prime, False otherwise.\n \"\"\"\n if n <= 1:\n return True\n if n <= 3:\n return False\n if n % 2 == 0 or n % 3 == 0:\n return True\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return True\n i += 6\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n \"\"\"\n Check if a number is not a prime number.\n \n Parameters:\n n (int): The number to check\n \n Returns:\n bool: True if the number is not a prime, False otherwise.\n \"\"\"\n if n <= 1:\n return True # 0 and 1 are not prime numbers\n \n # Starting from 2 to the square root of n, check if n is divisible by any number\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return True # n is not a prime number\n return False", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(n):\n \"\"\"\n Check if a number is not a prime number.\n\n :param n: Integer to check.\n :return: True if n is not a prime number, False otherwise.\n \"\"\"\n if n <= 1:\n return True # 0 and 1 are not prime numbers\n if n <= 3:\n return False # 2 and 3 are prime numbers\n if n % 2 == 0 or n % 3 == 0:\n return True # multiples of 2 or 3 are not prime numbers\n \n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return True\n i += 6\n \n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n if n < 2:\n return True\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return True\n return False", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(n):\n \"\"\"\n Check if a number is not a prime number.\n \n Parameters:\n n (int): The number to check.\n \n Returns:\n bool: True if the number is not a prime number, False otherwise.\n \"\"\"\n if n <= 1:\n return True # 0 and 1 are not prime numbers\n if n <= 3:\n return False # 2 and 3 are prime numbers\n if n % 2 == 0 or n % 3 == 0:\n return True # Numbers divisible by 2 or 3 are not prime\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return True\n i += 6\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n if n <= 1:\n return True # 0 and 1 are not considered prime numbers\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return True # The number is not prime\n return False # The number is prime", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(n):\n \"\"\"\n Check if a number is not a prime number.\n\n Parameters:\n n (int): The number to check.\n\n Returns:\n bool: True if the number is not prime, False if it is prime.\n \"\"\"\n if n <= 1:\n return True # 0 and 1 are not prime numbers\n if n <= 3:\n return False # 2 and 3 are prime numbers\n if n % 2 == 0 or n % 3 == 0:\n return True # multiples of 2 and 3 are not prime, except for 2 and 3 themselves\n \n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return True\n i += 6\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n \"\"\"\n Checks if a number is not prime.\n \n Parameters:\n n (int): The number to check\n \n Returns:\n bool: True if the number is not prime, False if it is prime\n \"\"\"\n if n <= 1:\n return True # 0 and 1 are not prime numbers\n if n <= 3:\n return False # 2 and 3 are prime numbers\n if n % 2 == 0 or n % 3 == 0:\n return True # Eliminate even numbers and multiples of 3\n \n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return True\n i += 6\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n \"\"\"\n This function checks if a number is not prime.\n \n Args:\n n (int): The number to check.\n \n Returns:\n bool: True if the number is not prime, False otherwise.\n \"\"\"\n if n <= 1:\n return True # 0 and 1 are not prime numbers\n if n <= 3:\n return False # 2 and 3 are prime numbers\n \n if n % 2 == 0 or n % 3 == 0:\n return True # multiples of 2 and 3 are not prime\n \n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return True # divisors found, not a prime\n i += 6\n \n return False # no divisors found, a prime number", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n \"\"\"\n Check if a number is not a prime.\n\n :param n: Integer to check\n :return: True if the number is not prime, False otherwise\n \"\"\"\n if n <= 1:\n return True # 0, 1 and negative numbers are not prime\n if n <= 3:\n return False # 2 and 3 are prime numbers\n\n # This is checked so that we can skip middle five numbers in below loop\n if n % 2 == 0 or n % 3 == 0:\n return True\n\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return True\n i += 6\n\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n \"\"\"\n Function to check if a number is not a prime number.\n \n Parameters:\n n (int): The number to check\n \n Returns:\n bool: True if the number is not prime, False otherwise\n \"\"\"\n if n <= 1:\n return True # 0 and 1 are not prime numbers by definition\n if n == 2:\n return False # 2 is the only even prime number\n if n % 2 == 0:\n return True # Any other even number is not a prime\n for i in range(3, int(n**0.5) + 1, 2): # Test only odd factors\n if n % i == 0:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n \"\"\"\n Check if a number is not a prime number.\n\n :param n: Integer to check\n :return: True if n is not a prime number, False otherwise.\n \"\"\"\n if n <= 1:\n return True # 0 and 1 are not prime numbers\n if n <= 3:\n return False # 2 and 3 are prime numbers\n if n % 2 == 0 or n % 3 == 0:\n return True # multiples of 2 or 3 are not primes\n\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return True\n i += 6\n\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n \"\"\"\n Check if a number is not a prime number.\n\n :param n: Integer to check\n :return: True if the number is not prime, False if the number is prime.\n \"\"\"\n if n <= 1:\n return True # 0 and 1 are not prime numbers\n if n <= 3:\n return False # 2 and 3 are prime numbers\n \n # This is checked so that we can skip middle five numbers in below loop\n if n % 2 == 0 or n % 3 == 0:\n return True\n \n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return True\n i += 6\n \n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n \"\"\"\n Check if a number is not a prime number.\n \n Parameters:\n n (int): The number to check.\n \n Returns:\n bool: True if the number is not a prime, False otherwise.\n \"\"\"\n if n <= 1:\n return True # 0 and 1 are not prime numbers\n if n <= 3:\n return False # 2 and 3 are prime numbers\n if n % 2 == 0 or n % 3 == 0:\n return True # If divisible by 2 or 3, it's not prime\n \n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return True\n i += 6\n \n return False # The number is a prime number", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n \"\"\"\n Check if a number is not a prime number.\n\n Args:\n n (int): The number to check.\n\n Returns:\n bool: True if the number is not a prime number, False otherwise.\n \"\"\"\n if n <= 1:\n return True # 0 and 1 are not prime numbers\n if n == 2:\n return False # 2 is the only even prime number\n if n % 2 == 0:\n return True # other even numbers are not primes\n \n # We only need to check for factors up to the square root of n\n for i in range(3, int(n**0.5) + 1, 2):\n if n % i == 0:\n return True # found a factor, so n is not prime\n return False # no factors found, n is prime", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n \"\"\"\n Check if a number is not prime.\n\n Args:\n n: Integer to check.\n\n Returns:\n True if the number is not prime, False otherwise.\n \"\"\"\n if n <= 1:\n return True\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return True\n return False", "matching_cluster_idx": 5}]}, "Mbpp/4": {"dps": 95.22184300341297, "dps_norm": 83.33333333333333, "pass@1": 98.0, "profiled": [{"solution": "import heapq\ndef heap_queue_largest(nums, n):\n \"\"\"\n Function to find the n largest integers from a given list of numbers.\n Returns these numbers in descending order.\n\n :param nums: List of integers\n :param n: The number of largest elements to return\n :return: A list of n largest integers from nums in descending order\n \"\"\"\n # Use heapq's nlargest method to find the n largest numbers\n largest_nums = heapq.nlargest(n, nums)\n return largest_nums", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n \"\"\"\n Finds the n largest numbers in the given list and returns them in descending order.\n \n Args:\n nums (list): The list of numbers to search through.\n n (int): The number of largest elements to find.\n \n Returns:\n list: A list of the n largest numbers from the given list, in descending order.\n \"\"\"\n # Use heapq's nlargest function to find the n largest elements\n largest_n = heapq.nlargest(n, nums)\n return largest_n", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n \"\"\"\n Find the n largest integers from a given list of numbers, returned in descending order.\n \n :param nums: List of integers.\n :param n: Number of largest elements to return.\n :return: A list of n largest integers in descending order.\n \"\"\"\n # Use nlargest method from heapq to find the n largest elements\n largest_n = heapq.nlargest(n, nums)\n return largest_n", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n \"\"\"\n Function to find the n largest numbers in a given list, returned in descending order.\n \n Parameters:\n nums (list): List of integers.\n n (int): The number of largest elements to find.\n \n Returns:\n list: A list of n largest integers from the input list, sorted in descending order.\n \"\"\"\n # Use heapq's nlargest method to find the n largest numbers\n largest_nums = heapq.nlargest(n, nums)\n return largest_nums", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n \"\"\"\n Returns a list of the n largest integers from the input list `nums` in descending order.\n \n Args:\n nums (List[int]): The list of integers.\n n (int): The number of top elements to return.\n \n Returns:\n List[int]: A list of the n largest integers from `nums`, sorted in descending order.\n \"\"\"\n # Use heapq.nlargest to find the n largest elements\n largest_n = heapq.nlargest(n, nums)\n return largest_n", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n # Use nlargest method from heapq module to find n largest numbers\n largest_n = heapq.nlargest(n, nums)\n return largest_n", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n \"\"\"\n Returns the n largest numbers from the given list `nums` in descending order.\n \n :param nums: List[int] - The list of numbers to find the largest n elements.\n :param n: int - The number of largest elements to find.\n :return: List[int] - The n largest elements in descending order.\n \"\"\"\n # Using nlargest from heapq to find the n largest elements\n largest_n = heapq.nlargest(n, nums)\n return largest_n", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n \"\"\"\n Find the n largest integers from the given list of numbers, returned in descending order.\n \n :param nums: List[int] - a list of integers\n :param n: int - the number of largest elements to find\n :return: List[int] - a list of the n largest integers in descending order\n \"\"\"\n # Use nlargest from heapq to find the n largest elements\n largest_n = heapq.nlargest(n, nums)\n return largest_n", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n # Use nlargest from heapq to find the n largest elements\n largest_n = heapq.nlargest(n, nums)\n return largest_n", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n \"\"\"\n This function finds the n largest integers from the given list of numbers\n using a heap queue algorithm and returns them in descending order.\n \n :param nums: List of integers\n :param n: Number of top largest elements to return\n :return: A list of the n largest integers in descending order\n \"\"\"\n # Using nlargest from heapq to find the n largest elements\n largest_nums = heapq.nlargest(n, nums)\n return largest_nums", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n \"\"\"\n Find the n largest integers from a given list of numbers, returned in descending order.\n \n :param nums: List of integers\n :param n: Number of top integers to retrieve\n :return: A list of n largest integers from nums, sorted in descending order\n \"\"\"\n # Use nlargest method from heapq to find the top n largest numbers\n largest_n = heapq.nlargest(n, nums)\n return largest_n", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n \"\"\"\n Find the n largest integers from a given list of numbers and return them in descending order.\n \n :param nums: List of integers.\n :param n: Number of largest elements to return.\n :return: A list of the n largest integers in descending order.\n \"\"\"\n # Use nlargest to get the n largest elements\n largest_nums = heapq.nlargest(n, nums)\n return largest_nums", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n \"\"\"\n Function to find the n largest numbers from the list 'nums' and return them in descending order.\n \n :param nums: List of integers.\n :param n: Number of largest elements to return.\n :return: A list of n largest integers in descending order.\n \"\"\"\n # Use nlargest from heapq to find the n largest numbers\n largest_nums = heapq.nlargest(n, nums)\n return largest_nums", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n # Use nlargest to find the n largest numbers in the list\n largest_nums = heapq.nlargest(n, nums)\n return largest_nums", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n # Use heapq's nlargest function to find the n largest numbers in the list\n largest_nums = heapq.nlargest(n, nums)\n return largest_nums", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n # Use nlargest method from heapq module to find n largest elements\n largest_n = heapq.nlargest(n, nums)\n return largest_n", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n \"\"\"\n Finds the n largest integers from the given list of numbers and returns them in descending order.\n \n :param nums: List of integers from which the n largest are to be found.\n :param n: Number of top elements to find.\n :return: A list of the n largest integers from the given list, in descending order.\n \"\"\"\n # Use heapq's nlargest method to find the n largest elements\n largest_n = heapq.nlargest(n, nums)\n return largest_n", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n \"\"\"\n Finds the n largest numbers in a list and returns them in descending order.\n \n :param nums: List of integers.\n :param n: Number of largest elements to find.\n :return: A list of n largest elements in descending order.\n \"\"\"\n # Using heapq to find the n largest numbers\n largest_n = heapq.nlargest(n, nums)\n return largest_n", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n \"\"\"\n This function finds the n largest integers in a list of numbers using the heapq module\n and returns them in descending order.\n \n :param nums: List of integers\n :param n: Number of largest integers to return\n :return: A list of n largest integers, sorted in descending order\n \"\"\"\n # Use nlargest method from heapq to get the n largest numbers\n largest_n = heapq.nlargest(n, nums)\n return largest_n", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n # Use nlargest from heapq to find the n largest numbers\n largest_n = heapq.nlargest(n, nums)\n return largest_n", "matching_cluster_idx": 9}]}, "Mbpp/9": {"dps": 97.27891156462584, "dps_norm": 60.0, "pass@1": 95.0, "profiled": [{"solution": "def find_Rotations(s):\n # Double the string to account for all possible rotations\n temp = s + s\n n = len(s)\n \n # Iterate through the string to check for the smallest rotation that gives the original string\n for i in range(1, n + 1):\n # If the substring matches the original string\n if temp[i:i+n] == s:\n return i\n \n # If no rotation found (which should not happen for non-empty string)\n return -1", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(s):\n # Concatenate the string with itself to cover all possible rotations\n temp = s + s\n \n # Initialize minimum rotations variable with string length\n min_rotations = len(s)\n \n # Loop through all possible rotations of the string\n for i in range(1, len(s) + 1):\n # Extract substring corresponding to the current rotation\n rotated_str = temp[i : i + len(s)]\n \n # If the rotated string matches the original string, update minimum rotations\n if rotated_str == s:\n min_rotations = i\n break\n \n return min_rotations", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(s):\n # Concatenate the string with itself to account for all possible rotations\n temp = s + s\n # Initialize the minimum number of rotations to the length of the string\n n = len(s)\n # Iterate through the concatenated string to check for the first occurrence of the original string\n for i in range(1, n + 1):\n # Extract the substring corresponding to the rotation\n sub_str = temp[i : i + n]\n # Check if the substring is equal to the original string\n if sub_str == s:\n # Return the index as the number of rotations needed\n return i\n \n # If no rotations found (should not happen since a match is guaranteed at n rotations)\n return n", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(s):\n # Double the string to simulate infinite rotation\n double_s = s + s\n # Start with a rotation of 1\n min_rotations = 1\n \n for i in range(1, len(s)):\n # Check if the rotated string is equal to the original string\n if double_s[i:i+len(s)] == s:\n return min_rotations\n min_rotations += 1\n # If no rotation was found to produce the same string, return the maximum rotation (which is the length of the string)\n return len(s)", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(s):\n # Concatenate the string with itself\n temp = s + s\n \n # Start with a rotation count of 1\n n = 1\n \n # Loop to find the minimum number of rotations to get the same string\n for i in range(1, len(s)):\n # Extract substring from temp to check if it matches the original string\n substring = temp[i:i+len(s)]\n \n # If the substring matches the original string, return the rotation count\n if s == substring:\n return n\n # Increment the rotation count\n n += 1\n \n # If no rotation gives the original string, return the length of the string\n return len(s)", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(s):\n n = len(s)\n # Concatenate the string with itself to cover all rotations\n temp = s + s\n # Check for rotations, minimum value is 1\n for i in range(1, n + 1):\n # If the substring from index 'i' to 'i+n' matches the original string, return i\n if temp[i:i+n] == s:\n return i\n # If no rotations found that match the original string, return 0\n return 0", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(s):\n # Concatenate the string with itself to handle rotations\n temp = s + s\n n = len(s)\n \n # Iterate through possible rotations\n for i in range(1, n + 1):\n # Extract substring of same length as original string\n sub_str = temp[i: i + n]\n \n # Check if the substring matches the original string\n if sub_str == s:\n return i\n \n return n # Default to the length of the string if no earlier match was found", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(s):\n # Create a temp string by adding original string to itself\n temp = s + s\n \n # Remove the first character from the temp string as a rotation of 0 is not considered\n n = len(s)\n for i in range(1, n+1):\n # Check if the substring from i to i+n is equal to the original string\n if temp[i:i+n] == s:\n return i", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(s):\n # Concatenate the string with itself to handle rotations\n temp = s + s\n n = len(s)\n \n # Iterate through the possible rotations\n for i in range(1, n+1):\n # Extract substring that represents the current rotation\n substring = temp[i: i + n]\n \n # Check if the rotated substring matches the original string\n if s == substring:\n return i\n \n # If no rotation results in the original string, return -1\n return -1", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(s):\n # Concatenate the string with itself\n temp = s + s\n \n # Iterate from 1 to the length of the original string\n for i in range(1, len(s) + 1):\n # Get the substring from index i to the length of the original string\n substring = temp[i: i + len(s)]\n \n # Check if the substring is equal to the original string\n if substring == s:\n return i # Return the rotation count if they are equal\n \n return -1 # Return -1 if no rotations were found", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(s):\n n = len(s)\n temp = s + s\n # Loop from 1 to n to find the minimum rotations\n for i in range(1, n + 1):\n # Get the substring from position i to i+n\n substring = temp[i: i + n]\n # Check if this substring is equal to the original string\n if s == substring:\n return i\n return n # If no rotation is found, return the length of the string", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(s):\n # Double the string to simulate infinite rotations\n temp = s + s\n n = len(s)\n \n # Iterate through the string to find the minimum rotation\n for i in range(1, n + 1):\n # Check if the substring from index i equals the original string\n if temp[i: i + n] == s:\n return i\n \n return n", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(s):\n n = len(s)\n # Concatenate the string with itself to simplify rotation simulation\n temp = s + s\n \n # Start with the minimum possible rotation (greater than 0)\n for i in range(1, n + 1):\n # Get the substring that represents the rotated string\n sub = temp[i : i + n]\n \n # Check if the substring matches the original string\n if s == sub:\n return i\n \n return n # If no rotation gives the original string, return the length of the string", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(s):\n # Concatenate the string with itself\n temp = s + s\n n = len(s)\n # Loop through the string\n for i in range(1, n + 1):\n # Get the substring that is a rotation of the original string\n substring = temp[i: i + n]\n # Check if the substring matches the original string\n if s == substring:\n return i\n return n # If no rotation is found, return the length of the string", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(s):\n # Concatenate the string with itself\n temp = s + s\n # Iterate through the string, the maximum rotations needed will be the length of the string\n for i in range(1, len(s) + 1):\n # Extract the substring from index i to i+len(s)\n substring = temp[i: i + len(s)]\n # If the substring matches the original string, return the number of rotations\n if substring == s:\n return i\n # If no rotations form the original string, return -1, though the problem guarantees a solution\n return -1", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(s):\n n = len(s)\n # Concatenate the string with itself to simulate infinite rotations\n temp = s + s\n \n # Iterate over the string from the second character to the end\n for i in range(1, n + 1):\n # Check if the substring of length n starting at index i is equal to the original string\n if temp[i:i + n] == s:\n return i", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(s):\n # Concatenate the string with itself\n temp = s + s\n n = len(s)\n \n # Iterate through the string\n for i in range(1, n + 1):\n # Check if the substring matches the original string\n if temp[i:i + n] == s:\n return i", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(s):\n # Create a temporary string by concatenating the original string\n temp = s + s\n n = len(s)\n \n # Iterate over the string, starting from the first character\n for i in range(1, n+1):\n # Get the substring from position i to i+len(s)\n substring = temp[i: i + n]\n # Check if the substring equals the original string\n if substring == s:\n # If yes, return the index which denotes the number of rotations\n return i", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(s):\n # Double the string to simulate rotations\n temp = s + s\n \n # For each possible rotation, check if it matches the original string\n for index in range(1, len(s) + 1):\n # Slice the doubled string to get the current rotation\n substring = temp[index:index+len(s)]\n \n # Check if the rotation matches the original string\n if substring == s:\n return index\n \n # If no rotation (other than 0) matches, return 0 (which isn't possible with this constraint)\n return 0", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(s):\n # Concatenate the string with itself to handle rotations\n temp = s + s\n # Iterate through the string to find the minimum rotations needed\n for i in range(1, len(s) + 1):\n # Extract substring of the original length\n substring = temp[i: i + len(s)]\n # Check if substring is equal to the original string\n if substring == s:\n return i\n return len(s)", "matching_cluster_idx": 5}]}, "Mbpp/11": {"dps": 45.16129032258065, "dps_norm": 76.11111111111111, "pass@1": 65.0, "profiled": [{"solution": "def remove_Occ(s, char):\n # Find the first occurrence of the character\n first_occ = s.find(char)\n \n # Find the last occurrence of the character\n last_occ = s.rfind(char)\n \n # If the character is not found at all, return the original string\n if first_occ == -1 or last_occ == -1:\n return s\n \n # Build the new string without the first and last occurrence\n new_s = s[:first_occ] + s[first_occ+1:last_occ] + s[last_occ+1:]\n \n return new_s", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(input_string, char):\n # Convert the string to a list for easier manipulation\n str_list = list(input_string)\n \n # Find and remove the first occurrence of the character\n if char in str_list:\n str_list.remove(char)\n \n # Reverse the list to find and remove the last occurrence\n str_list.reverse()\n if char in str_list:\n str_list.remove(char)\n \n # Reverse the list back to the original order and join to form a string\n str_list.reverse()\n result_string = ''.join(str_list)\n \n return result_string", "matching_cluster_idx": 1}, {"solution": "def remove_Occ(s, char):\n # Find the first occurrence of the character\n first_occurrence = s.find(char)\n # Find the last occurrence of the character\n last_occurrence = s.rfind(char)\n \n # If both the first and last occurrence positions are valid (i.e., character exists in the string)\n if first_occurrence != -1 and last_occurrence != -1:\n # If the first and last occurrence are the same, remove just once\n if first_occurrence == last_occurrence:\n return s[:first_occurrence] + s[first_occurrence+1:]\n # If they are different, remove both occurrences\n else:\n return s[:first_occurrence] + s[first_occurrence+1:last_occurrence] + s[last_occurrence+1:]\n # If the character is not found, return the original string\n return s", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(string, char):\n # Find the index of the first occurrence of the character\n first_index = string.find(char)\n \n # If the character is not found, return the original string\n if first_index == -1:\n return string\n \n # Find the index of the last occurrence of the character\n last_index = string.rfind(char)\n \n # If first and last are the same, we only remove one occurrence\n if first_index == last_index:\n return string[:first_index] + string[first_index+1:]\n \n # If they are different, remove both\n part1 = string[:first_index]\n part2 = string[first_index+1:last_index]\n part3 = string[last_index+1:]\n \n return part1 + part2 + part3", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(s, char):\n # Find the first occurrence of the character\n first = s.find(char)\n # If the character does not exist, return the original string\n if first == -1:\n return s\n # Find the last occurrence of the character\n last = s.rfind(char)\n # Create a new string with the first and last occurrence removed\n # Check if the first and last occurrence are the same\n if first == last:\n return s[:first] + s[first+1:]\n else:\n return s[:first] + s[first+1:last] + s[last+1:]", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(s, char):\n # Find the first occurrence of the character and remove it\n first_index = s.find(char)\n if first_index != -1:\n s = s[:first_index] + s[first_index+1:]\n else:\n return s # Return original string if character not found\n \n # Find the last occurrence of the character and remove it\n last_index = s.rfind(char)\n if last_index != -1:\n s = s[:last_index] + s[last_index+1:]\n \n return s", "matching_cluster_idx": 7}, {"solution": "def remove_Occ(s, char):\n # Check if the character exists in the string and remove its first occurrence\n if char in s:\n s = s.replace(char, '', 1)\n # Check again and remove the last occurrence\n if char in s:\n s = s[::-1].replace(char, '', 1)[::-1]\n return s", "matching_cluster_idx": 4}, {"solution": "def remove_Occ(s, ch):\n # First occurrence index\n first_index = s.find(ch)\n \n # Last occurrence index\n last_index = s.rfind(ch)\n \n # If character is not found in string, return the original string\n if first_index == -1 or last_index == -1:\n return s\n \n # Construct new string without first and last occurrence of the character\n new_str = s[:first_index] + s[first_index + 1:last_index] + s[last_index + 1:]\n \n return new_str", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(string, char):\n # Find the first occurrence of the character\n first_index = string.find(char)\n # Find the last occurrence of the character\n last_index = string.rfind(char)\n \n # Construct the new string without the first and last occurrence of the character\n if first_index != -1 and last_index != -1:\n return string[:first_index] + string[first_index+1:last_index] + string[last_index+1:]\n else:\n return string", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(s, char):\n # Find the first occurrence\n first = s.find(char)\n # Find the last occurrence\n last = s.rfind(char)\n \n # If the character exists in the string\n if first != -1 and last != -1:\n # Create the new string excluding the first and last occurrence\n new_s = s[:first] + s[first+1:last] + s[last+1:]\n return new_s\n else:\n # Return the original string if the character is not found\n return s", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(input_str, char):\n # Convert the string into a list for manipulation\n str_list = list(input_str)\n \n # Find the index of the first occurrence of the character and remove it\n try:\n first_index = str_list.index(char)\n del str_list[first_index]\n except ValueError:\n # If the character is not found, return the original string\n return input_str\n \n # Reverse the list to find the last occurrence more easily\n str_list.reverse()\n \n # Find the index of the last occurrence and remove it (which is now first after reversing)\n try:\n last_index = str_list.index(char)\n del str_list[last_index]\n except ValueError:\n # If the character is not found again, simply return the list without further changes\n pass\n \n # Reverse the list back to the original order and join the elements to form a string\n str_list.reverse()\n return ''.join(str_list)", "matching_cluster_idx": 1}, {"solution": "def remove_Occ(s, char):\n # Find the first occurrence of the character\n first = s.find(char)\n # If the character is not found, return the original string\n if first == -1:\n return s\n # Replace the first occurrence of the character\n s = s[:first] + s[first+1:]\n \n # Find the last occurrence of the character in the modified string\n last = s.rfind(char)\n # Replace the last occurrence of the character\n if last != -1:\n s = s[:last] + s[last+1:]\n \n return s", "matching_cluster_idx": 7}, {"solution": "def remove_Occ(s, char):\n # Convert the string to a list to modify individual elements\n s_list = list(s)\n found = False\n # Find the first occurrence\n for i in range(len(s_list)):\n if s_list[i] == char and not found:\n s_list[i] = ''\n found = True\n break\n # Find the last occurrence\n for i in reversed(range(len(s_list))):\n if s_list[i] == char:\n s_list[i] = ''\n break\n # Convert the list back to a string\n return ''.join(s_list)", "matching_cluster_idx": 1}, {"solution": "def remove_Occ(string, char):\n # Find the first occurrence\n first_index = string.find(char)\n if first_index == -1:\n return string\n \n # Remove the first occurrence\n string = string[:first_index] + string[first_index + 1:]\n \n # Find the last occurrence, which will be the first occurrence in the reversed string\n last_index = string.rfind(char)\n if last_index != -1:\n # Remove the last occurrence\n string = string[:last_index] + string[last_index + 1:]\n \n return string", "matching_cluster_idx": 7}, {"solution": "def remove_Occ(s, char):\n # Check if the character is in the string\n if char in s:\n # Find the first occurrence of the character\n first_occ = s.find(char)\n # Find the last occurrence of the character\n last_occ = s.rfind(char)\n # If the character appears more than once, remove both first and last occurrences\n if first_occ != last_occ:\n # Construct the string without the first occurrence of the character\n s = s[:first_occ] + s[first_occ + 1:]\n # Adjust last_occ for the shift in index due to the removal of the first occurrence\n last_occ -= 1\n # Construct the string without the last occurrence of the character\n s = s[:last_occ] + s[last_occ + 1:]\n else:\n # If the character only appears once, just remove that single occurrence\n s = s[:first_occ] + s[first_occ + 1:]\n # Return the modified string\n return s", "matching_cluster_idx": 7}, {"solution": "def remove_Occ(s, char):\n # Convert the string into a list to allow modification\n str_list = list(s)\n \n # Initialize a counter for occurrences\n found = False\n \n # Find and remove the first occurrence\n for i in range(len(str_list)):\n if str_list[i] == char and not found:\n del str_list[i]\n found = True\n break\n \n # If char is not found, just return the original string\n if not found:\n return s\n \n # Reverse the list to find and remove the last occurrence\n for i in range(len(str_list)-1, -1, -1):\n if str_list[i] == char:\n del str_list[i]\n break\n \n # Convert the list back to string and return\n return ''.join(str_list)", "matching_cluster_idx": 1}, {"solution": "def remove_Occ(input_str, char_to_remove):\n # Remove first occurrence\n first_removed = input_str.replace(char_to_remove, '', 1)\n # Reverse the string and remove last occurrence (which is first now in the reversed string)\n reversed_str = first_removed[::-1]\n last_removed_reversed = reversed_str.replace(char_to_remove, '', 1)\n # Reverse the string again to get the original order\n final_str = last_removed_reversed[::-1]\n return final_str", "matching_cluster_idx": 4}, {"solution": "def remove_Occ(string, char):\n # Find the first occurrence of the character\n first_occurrence = string.find(char)\n if first_occurrence != -1:\n # Remove the first occurrence\n string = string[:first_occurrence] + string[first_occurrence + 1:]\n \n # Find the last occurrence of the character\n last_occurrence = string.rfind(char)\n if last_occurrence != -1:\n # Remove the last occurrence\n string = string[:last_occurrence] + string[last_occurrence + 1:]\n \n return string", "matching_cluster_idx": 7}, {"solution": "def remove_Occ(string, char):\n # Find the index of the first occurrence\n first_index = string.find(char)\n # If the character is not found, return the original string\n if first_index == -1:\n return string\n # Remove the first occurrence\n string = string[:first_index] + string[first_index+1:]\n # Find the index of the last occurrence\n last_index = string.rfind(char)\n # If the character is not found, return the string after removing the first occurrence\n if last_index == -1:\n return string\n # Remove the last occurrence\n string = string[:last_index] + string[last_index+1:]\n return string", "matching_cluster_idx": 7}, {"solution": "def remove_Occ(string, char):\n # Remove first occurrence\n first_index = string.find(char)\n if first_index != -1:\n string = string[:first_index] + string[first_index + 1:]\n \n # Remove last occurrence (from the end of the string)\n last_index = string.rfind(char)\n if last_index != -1:\n string = string[:last_index] + string[last_index + 1:]\n \n return string", "matching_cluster_idx": 7}]}, "Mbpp/12": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def sort_matrix(matrix):\n # Sorting the matrix based on the sum of its rows\n sorted_matrix = sorted(matrix, key=sum)\n return sorted_matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Sort the matrix based on the sum of its rows\n sorted_matrix = sorted(matrix, key=sum)\n return sorted_matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Sorts the matrix based on the sum of its rows\n sorted_matrix = sorted(matrix, key=sum)\n return sorted_matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"\n Sorts a given matrix in ascending order according to the sum of its rows.\n \n :param matrix: List of lists containing the matrix to be sorted\n :return: Sorted matrix based on row sums\n \"\"\"\n # Sorting the matrix based on the sum of each row\n sorted_matrix = sorted(matrix, key=sum)\n return sorted_matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Sorts the matrix based on the sum of its rows\n sorted_matrix = sorted(matrix, key=sum)\n return sorted_matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Sort the matrix based on the sum of its rows\n sorted_matrix = sorted(matrix, key=sum)\n return sorted_matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Sort the matrix based on the sum of each row\n sorted_matrix = sorted(matrix, key=sum)\n return sorted_matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Sorting the matrix based on the sum of its rows\n sorted_matrix = sorted(matrix, key=sum)\n return sorted_matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Sorts the matrix based on the sum of its rows\n sorted_matrix = sorted(matrix, key=sum)\n return sorted_matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Sort the matrix based on the sum of its rows\n sorted_matrix = sorted(matrix, key=sum)\n return sorted_matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Sorting the matrix based on the sum of its rows\n sorted_matrix = sorted(matrix, key=sum)\n return sorted_matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"\n Sorts a given matrix in ascending order based on the sum of its rows.\n \n :param matrix: List of lists, where each sublist represents a row in the matrix.\n :return: The sorted matrix.\n \"\"\"\n # Sorting the matrix based on the sum of elements in each row\n sorted_matrix = sorted(matrix, key=sum)\n return sorted_matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Sort the matrix based on the sum of each row\n sorted_matrix = sorted(matrix, key=sum)\n return sorted_matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Sort the matrix based on the sum of its rows\n sorted_matrix = sorted(matrix, key=sum)\n return sorted_matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Sort the matrix by the sum of its rows\n sorted_matrix = sorted(matrix, key=sum)\n return sorted_matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Sort the matrix based on the sum of each row\n sorted_matrix = sorted(matrix, key=sum)\n return sorted_matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"\n Sorts a given matrix in ascending order according to the sum of its rows.\n \n :param matrix: List of lists representing the matrix\n :return: Sorted matrix\n \"\"\"\n # Sorting the matrix based on the sum of its rows\n sorted_matrix = sorted(matrix, key=sum)\n return sorted_matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Sorts the matrix based on the sum of its rows\n sorted_matrix = sorted(matrix, key=sum)\n return sorted_matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Sort the matrix based on the sum of its rows\n sorted_matrix = sorted(matrix, key=sum)\n return sorted_matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Sort the matrix based on the sum of its rows\n sorted_matrix = sorted(matrix, key=sum)\n return sorted_matrix", "matching_cluster_idx": 15}]}, "Mbpp/16": {"dps": null, "dps_norm": null, "pass@1": 9.0, "profiled": []}, "Mbpp/19": {"dps": 75.25252525252526, "dps_norm": 86.0, "pass@1": 100.0, "profiled": [{"solution": "def test_duplicate(arr):\n # Using a set to track unique elements\n seen = set()\n for num in arr:\n if num in seen:\n return True\n seen.add(num)\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(arr):\n # Convert list to set to remove duplicates and compare lengths\n return len(arr) != len(set(arr))", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(arr):\n # Using a set to find duplicates\n seen = set()\n for number in arr:\n if number in seen:\n return True\n seen.add(number)\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(arr):\n # Convert the array to a set and compare lengths\n return len(arr) != len(set(arr))", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(arr):\n # Use set to track seen elements\n seen = set()\n for num in arr:\n if num in seen:\n return True\n seen.add(num)\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(arr):\n # Convert list to set and compare lengths\n return len(arr) != len(set(arr))", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(arr):\n # Convert the list to a set to remove duplicates\n # Compare the length of the set with the list\n return len(set(arr)) != len(arr)", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(arr):\n # Using a set to track seen elements\n seen = set()\n for num in arr:\n if num in seen:\n return True\n seen.add(num)\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(arr):\n # Convert list to set to remove duplicates and compare lengths\n return len(arr) != len(set(arr))", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(arr):\n # Using set to check for duplicates\n return len(arr) != len(set(arr))", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(arr):\n # Using a set to track seen elements\n seen = set()\n for num in arr:\n if num in seen:\n return True\n seen.add(num)\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(arr):\n # Using set to find duplicates\n return len(arr) != len(set(arr))", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(nums):\n # Convert list to set to remove duplicates\n # Compare length of set and original list\n return len(set(nums)) != len(nums)", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(arr):\n # Using set to remove duplicates and compare its length with the list's length\n return len(arr) != len(set(arr))", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(arr):\n # Convert list to a set to remove duplicates\n # If length of set and list is different, there are duplicates\n return len(set(arr)) != len(arr)", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(arr):\n # Using set to check for duplicates\n return len(arr) != len(set(arr))", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(arr):\n # Using a set to track unique elements\n seen = set()\n for num in arr:\n if num in seen:\n return True\n seen.add(num)\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(arr):\n # Convert the list to a set and compare lengths\n return len(arr) != len(set(arr))", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(arr):\n # Using set to find duplicates\n return len(arr) != len(set(arr))", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(nums):\n # Using set to remove duplicates and comparing lengths\n return len(nums) != len(set(nums))", "matching_cluster_idx": 11}]}, "Mbpp/62": {"dps": 73.38461538461539, "dps_norm": 83.0, "pass@1": 100.0, "profiled": [{"solution": "def smallest_num(lst):\n # Using min function to find the smallest element in the list\n return min(lst)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(lst):\n # Initialize the smallest number as the first number in the list\n smallest = lst[0]\n # Iterate through the list to find the smallest number\n for num in lst:\n if num < smallest:\n smallest = num\n return smallest", "matching_cluster_idx": 3}, {"solution": "def smallest_num(lst):\n # Initialize smallest with the first element\n smallest = lst[0]\n \n # Iterate through the list to find the smallest element\n for num in lst:\n if num < smallest:\n smallest = num\n \n return smallest", "matching_cluster_idx": 3}, {"solution": "def smallest_num(lst):\n # Initialize smallest with the first element of the list\n smallest = lst[0]\n # Iterate through the list to find the smallest number\n for num in lst:\n if num < smallest:\n smallest = num\n return smallest", "matching_cluster_idx": 3}, {"solution": "def smallest_num(lst):\n # Initialize the smallest number to the first element of the list\n smallest = lst[0]\n # Iterate over the list to find the smallest number\n for num in lst:\n if num < smallest:\n smallest = num\n return smallest", "matching_cluster_idx": 3}, {"solution": "def smallest_num(lst):\n # Initialize smallest with the first element of the list\n smallest = lst[0]\n # Iterate through the list to find the smallest element\n for num in lst:\n if num < smallest:\n smallest = num\n return smallest", "matching_cluster_idx": 3}, {"solution": "def smallest_num(lst):\n # Initialize the smallest number as the first element\n smallest = lst[0]\n \n # Iterate through the list to find the smallest number\n for num in lst:\n if num < smallest:\n smallest = num\n return smallest", "matching_cluster_idx": 3}, {"solution": "def smallest_num(lst):\n # Initialize the smallest number to the first element of the list\n smallest = lst[0]\n # Iterate through the list to find the smallest number\n for num in lst:\n if num < smallest:\n smallest = num\n return smallest", "matching_cluster_idx": 3}, {"solution": "def smallest_num(lst):\n \"\"\"\n Find the smallest number in a list.\n\n :param lst: List of integers\n :return: The smallest integer in the list\n \"\"\"\n if not lst:\n return None\n min_num = lst[0]\n for num in lst:\n if num < min_num:\n min_num = num\n return min_num", "matching_cluster_idx": 3}, {"solution": "def smallest_num(lst):\n # Using min function to find the smallest number in the list\n return min(lst)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(lst):\n \"\"\"\n Finds the smallest number in a list.\n\n :param lst: List of integers\n :return: The smallest integer in the list\n \"\"\"\n if not lst: # Check if the list is empty\n return None # Return None if the list is empty\n smallest = lst[0]\n for num in lst:\n if num < smallest:\n smallest = num\n return smallest", "matching_cluster_idx": 3}, {"solution": "def smallest_num(lst):\n # Use min function to find the smallest number in the list\n return min(lst)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(lst):\n # Initialize the smallest element as the first element\n smallest = lst[0]\n \n # Iterate through the list to find the smallest element\n for num in lst:\n if num < smallest:\n smallest = num\n \n return smallest", "matching_cluster_idx": 3}, {"solution": "def smallest_num(lst):\n # Initialize the smallest number as the first element of the list\n smallest = lst[0]\n # Iterate through the list starting from the second element\n for num in lst[1:]:\n # If a smaller number is found, update the smallest variable\n if num < smallest:\n smallest = num\n return smallest", "matching_cluster_idx": 2}, {"solution": "def smallest_num(lst):\n # Use the min function to find the smallest element in the list\n return min(lst)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(lst):\n # Initialize smallest with the first element of the list\n smallest = lst[0]\n \n # Iterate through the list to find the smallest number\n for num in lst:\n if num < smallest:\n smallest = num\n \n return smallest", "matching_cluster_idx": 3}, {"solution": "def smallest_num(lst):\n # Initialize the smallest number as the first element of the list\n smallest = lst[0]\n # Iterate through the list to find the smallest number\n for num in lst:\n if num < smallest:\n smallest = num\n return smallest", "matching_cluster_idx": 3}, {"solution": "def smallest_num(lst):\n # Initialize smallest as the first element of the list\n smallest = lst[0]\n # Iterate through all the elements in the list\n for num in lst:\n # Update smallest if a smaller number is found\n if num < smallest:\n smallest = num\n return smallest", "matching_cluster_idx": 3}, {"solution": "def smallest_num(lst):\n # Initialize the smallest number to the first element of the list\n smallest = lst[0]\n \n # Iterate through all elements in the list\n for num in lst:\n # Update the smallest number if a smaller number is found\n if num < smallest:\n smallest = num\n return smallest", "matching_cluster_idx": 3}, {"solution": "def smallest_num(lst):\n # Initialize smallest with the first element of the list\n smallest = lst[0]\n # Iterate through each number in the list\n for num in lst:\n # Update smallest if the current number is smaller\n if num < smallest:\n smallest = num\n return smallest", "matching_cluster_idx": 3}]}, "Mbpp/75": {"dps": 92.85714285714286, "dps_norm": 66.66666666666667, "pass@1": 100.0, "profiled": [{"solution": "def find_tuples(test_list, k):\n # Filter the list of tuples where all elements are divisible by k\n res = [sub for sub in test_list if all(ele % k == 0 for ele in sub)]\n return res", "matching_cluster_idx": 5}, {"solution": "def find_tuples(test_list, k):\n # Using list comprehension to filter tuples where all elements are divisible by k\n res = [sub for sub in test_list if all(ele % k == 0 for ele in sub)]\n return res", "matching_cluster_idx": 5}, {"solution": "def find_tuples(test_list, k):\n # Filter tuples where all elements are divisible by k\n res = [sub for sub in test_list if all(ele % k == 0 for ele in sub)]\n return res", "matching_cluster_idx": 5}, {"solution": "def find_tuples(test_list, k):\n # Filter tuples where all elements are divisible by k\n res = [sub for sub in test_list if all(ele % k == 0 for ele in sub)]\n return res", "matching_cluster_idx": 5}, {"solution": "def find_tuples(test_list, k):\n # Filter tuples where all elements are divisible by k\n res = [sub for sub in test_list if all(ele % k == 0 for ele in sub)]\n return res", "matching_cluster_idx": 5}, {"solution": "def find_tuples(test_list, k):\n # Filter tuples where all elements are divisible by k\n res = [sub for sub in test_list if all(ele % k == 0 for ele in sub)]\n return res", "matching_cluster_idx": 5}, {"solution": "def find_tuples(test_list, k):\n # Filter tuples where all elements are divisible by k\n res = [sub for sub in test_list if all(ele % k == 0 for ele in sub)]\n return res", "matching_cluster_idx": 5}, {"solution": "def find_tuples(test_list, k):\n # Filter tuples where all elements are divisible by k\n res = [sub for sub in test_list if all(el % k == 0 for el in sub)]\n return res", "matching_cluster_idx": 5}, {"solution": "def find_tuples(test_list, k):\n # Use list comprehension to filter tuples where all elements are divisible by k\n res = [sub for sub in test_list if all(ele % k == 0 for ele in sub)]\n return res", "matching_cluster_idx": 5}, {"solution": "def find_tuples(test_list, k):\n # Using list comprehension to filter tuples where all elements are divisible by k\n res = [sub for sub in test_list if all(ele % k == 0 for ele in sub)]\n return res", "matching_cluster_idx": 5}, {"solution": "def find_tuples(test_list, k):\n # Filter tuples where all elements are divisible by k\n res = [sub for sub in test_list if all(ele % k == 0 for ele in sub)]\n return res", "matching_cluster_idx": 5}, {"solution": "def find_tuples(test_list, k):\n # Filter tuples where all elements are divisible by k\n res = [sub for sub in test_list if all(ele % k == 0 for ele in sub)]\n return res", "matching_cluster_idx": 5}, {"solution": "def find_tuples(test_list, k):\n # Use list comprehension to filter out the tuples\n # Check if all elements in the tuple are divisible by k\n res = [sub for sub in test_list if all(ele % k == 0 for ele in sub)]\n return res", "matching_cluster_idx": 5}, {"solution": "def find_tuples(test_list, k):\n # Filter the list of tuples based on whether all elements in each tuple are divisible by k\n res = [sub for sub in test_list if all(ele % k == 0 for ele in sub)]\n return res", "matching_cluster_idx": 5}, {"solution": "def find_tuples(test_list, k):\n # Filter tuples where all elements are divisible by k\n res = [sub for sub in test_list if all(ele % k == 0 for ele in sub)]\n return res", "matching_cluster_idx": 5}, {"solution": "def find_tuples(test_list, k):\n # Use list comprehension to filter tuples where all elements are divisible by k\n res = [sub for sub in test_list if all(ele % k == 0 for ele in sub)]\n return res", "matching_cluster_idx": 5}, {"solution": "def find_tuples(test_list, k):\n # Use list comprehension to filter tuples where all elements are divisible by k\n res = [ele for ele in test_list if all(e % k == 0 for e in ele)]\n return res", "matching_cluster_idx": 5}, {"solution": "def find_tuples(test_list, k):\n # Use list comprehension to filter out tuples where all elements are divisible by k\n res = [sub for sub in test_list if all(ele % k == 0 for ele in sub)]\n return res", "matching_cluster_idx": 5}, {"solution": "def find_tuples(test_list, k):\n # Use list comprehension to filter tuples where all elements are divisible by k\n res = [sub for sub in test_list if all(ele % k == 0 for ele in sub)]\n return res", "matching_cluster_idx": 5}, {"solution": "def find_tuples(test_list, k):\n # Use list comprehension to filter tuples where all elements are divisible by k\n res = [sub for sub in test_list if all(ele % k == 0 for ele in sub)]\n return res", "matching_cluster_idx": 5}]}, "Mbpp/88": {"dps": 96.56862745098039, "dps_norm": 85.71428571428571, "pass@1": 100.0, "profiled": [{"solution": "def freq_count(lst):\n # Initialize an empty dictionary to hold the frequencies\n freq_dict = {}\n \n # Iterate over the list\n for item in lst:\n # If the item is already in the dictionary, increment its count\n if item in freq_dict:\n freq_dict[item] += 1\n # Otherwise, add the item to the dictionary with a count of 1\n else:\n freq_dict[item] = 1\n \n return freq_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n # Initialize an empty dictionary to store the frequencies\n freq_dict = {}\n # Iterate over each element in the list\n for item in lst:\n # If the element is not in the dictionary, add it with a count of 1\n # Otherwise, increment the count of the element\n if item in freq_dict:\n freq_dict[item] += 1\n else:\n freq_dict[item] = 1\n return freq_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n # Initialize an empty dictionary to store frequencies\n freq_dict = {}\n \n # Iterate through each element in the list\n for item in lst:\n # Update the frequency count for each element\n if item in freq_dict:\n freq_dict[item] += 1\n else:\n freq_dict[item] = 1\n \n return freq_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n # Creating an empty dictionary to hold frequencies\n freq_dict = {}\n # Iterating over each element in the list\n for elem in lst:\n # If the element is already in the dictionary, increment its frequency\n if elem in freq_dict:\n freq_dict[elem] += 1\n # Otherwise, add the element to the dictionary with frequency 1\n else:\n freq_dict[elem] = 1\n # Returning the populated dictionary\n return freq_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n # Initialize an empty dictionary to hold the frequency count\n freq_dict = {}\n \n # Iterate over each element in the list\n for item in lst:\n # If the item is already in the dictionary, increment its count\n if item in freq_dict:\n freq_dict[item] += 1\n # If the item is not in the dictionary, add it with a count of 1\n else:\n freq_dict[item] = 1\n \n # Return the populated dictionary\n return freq_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n # Initialize an empty dictionary to store the frequency of elements\n freq_dict = {}\n \n # Iterate through the list to count the frequency of each element\n for item in lst:\n if item in freq_dict:\n freq_dict[item] += 1\n else:\n freq_dict[item] = 1\n \n return freq_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n # Create an empty dictionary to store the frequency of elements\n freq_dict = {}\n \n # Iterate through the list to count the frequency of each element\n for elem in lst:\n if elem in freq_dict:\n freq_dict[elem] += 1\n else:\n freq_dict[elem] = 1\n \n return freq_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n # Create an empty dictionary to store the frequency of elements\n freq_dict = {}\n \n # Iterate through the list and count the frequency of each element\n for item in lst:\n if item in freq_dict:\n freq_dict[item] += 1\n else:\n freq_dict[item] = 1\n \n # Return the dictionary containing elements and their frequencies\n return freq_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n # Initialize an empty dictionary to store frequencies\n freq_dict = {}\n \n # Loop through each element in the list\n for elem in lst:\n # If the element is already in the dictionary, increment its count\n if elem in freq_dict:\n freq_dict[elem] += 1\n # Otherwise, add the element to the dictionary with a count of 1\n else:\n freq_dict[elem] = 1\n \n # Return the dictionary containing the frequencies\n return freq_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n # Dictionary to hold the frequency of elements\n freq_dict = {}\n # Iterate over the list and update the frequency\n for elem in lst:\n if elem in freq_dict:\n freq_dict[elem] += 1\n else:\n freq_dict[elem] = 1\n return freq_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n # Create an empty dictionary to store the frequency of elements\n freq_dict = {}\n \n # Iterate over the list to count the frequency of each element\n for item in lst:\n if item in freq_dict:\n freq_dict[item] += 1\n else:\n freq_dict[item] = 1\n \n return freq_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n # Initialize an empty dictionary to store frequency counts\n freq_dict = {}\n \n # Iterate through the list and count the frequency of each element\n for item in lst:\n if item in freq_dict:\n freq_dict[item] += 1\n else:\n freq_dict[item] = 1\n \n return freq_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n # Initialize an empty dictionary to store the frequency of elements\n freq_dict = {}\n \n # Loop through each element in the list\n for element in lst:\n # If the element is not yet in the dictionary, add it with a count of 1\n # Otherwise, increment its count\n if element in freq_dict:\n freq_dict[element] += 1\n else:\n freq_dict[element] = 1\n \n # Return the dictionary containing elements and their frequencies\n return freq_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n # Initialize an empty dictionary to store the frequency of elements\n freq_dict = {}\n \n # Iterate over each element in the list\n for item in lst:\n # If the element is already in the dictionary, increment its count\n if item in freq_dict:\n freq_dict[item] += 1\n # Otherwise, add the element to the dictionary with a count of 1\n else:\n freq_dict[item] = 1\n \n return freq_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n freq_dict = {}\n for item in lst:\n if item in freq_dict:\n freq_dict[item] += 1\n else:\n freq_dict[item] = 1\n return freq_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n # Create an empty dictionary to store the frequency of elements\n freq_dict = {}\n # Iterate over each element in the list\n for item in lst:\n # If the item is not in the dictionary, add it with a count of 1\n # If the item is already in the dictionary, increment its count\n if item in freq_dict:\n freq_dict[item] += 1\n else:\n freq_dict[item] = 1\n return freq_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n # Initialize an empty dictionary to hold the counts\n frequency_dict = {}\n \n # Iterate through each element in the list\n for elem in lst:\n # If the element is already in the dictionary, increment its count\n if elem in frequency_dict:\n frequency_dict[elem] += 1\n # Otherwise, add the element to the dictionary with a count of 1\n else:\n frequency_dict[elem] = 1\n \n # Return the completed dictionary\n return frequency_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n # Create an empty dictionary to store the frequencies\n freq_dict = {}\n \n # Iterate over each element in the list\n for item in lst:\n # If the item is not in the dictionary, add it with a count of 1\n if item not in freq_dict:\n freq_dict[item] = 1\n # If the item is already in the dictionary, increment its count\n else:\n freq_dict[item] += 1\n \n return freq_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n freq_dict = {}\n for num in lst:\n if num in freq_dict:\n freq_dict[num] += 1\n else:\n freq_dict[num] = 1\n return freq_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n # Initialize an empty dictionary to hold the counts\n frequency_dict = {}\n \n # Iterate over each element in the list\n for item in lst:\n # If the element is already in the dictionary, increment its count\n if item in frequency_dict:\n frequency_dict[item] += 1\n # Otherwise, add it to the dictionary with a count of 1\n else:\n frequency_dict[item] = 1\n \n return frequency_dict", "matching_cluster_idx": 5}]}, "Mbpp/90": {"dps": 76.73170731707317, "dps_norm": 85.0, "pass@1": 100.0, "profiled": [{"solution": "def len_log(lst):\n # Find the length of the longest word in the list\n max_length = max(len(word) for word in lst)\n return max_length", "matching_cluster_idx": 5}, {"solution": "def len_log(lst):\n # Find the length of the longest word in the list\n return max(len(word) for word in lst)", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n # Initialize max_length to zero\n max_length = 0\n # Iterate through each word in the list\n for word in words:\n # Update max_length if the length of the current word is greater than max_length\n if len(word) > max_length:\n max_length = len(word)\n return max_length", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n # Find the length of the longest word in the list\n max_length = 0\n for word in words:\n if len(word) > max_length:\n max_length = len(word)\n return max_length", "matching_cluster_idx": 5}, {"solution": "def len_log(lst):\n # Calculate the length of the longest word in the list\n max_length = max(len(word) for word in lst)\n return max_length", "matching_cluster_idx": 5}, {"solution": "def len_log(lst):\n # Find the maximum length among all words in the list\n max_length = max(len(word) for word in lst)\n return max_length", "matching_cluster_idx": 5}, {"solution": "def len_log(lst):\n # Find the length of the longest word in the list\n max_length = 0\n for word in lst:\n if len(word) > max_length:\n max_length = len(word)\n return max_length", "matching_cluster_idx": 5}, {"solution": "def len_log(lst):\n # Find the maximum length of the words in the list\n max_length = max(len(word) for word in lst)\n return max_length", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n # Initialize maximum length to 0\n max_length = 0\n # Iterate over each word in the list\n for word in words:\n # Update max_length if the length of the current word is greater\n if len(word) > max_length:\n max_length = len(word)\n return max_length", "matching_cluster_idx": 5}, {"solution": "def len_log(lst):\n # Find the maximum length of the words in the list\n max_length = max(len(word) for word in lst)\n return max_length", "matching_cluster_idx": 5}, {"solution": "def len_log(lst):\n # Find the maximum length among all words in the list\n max_length = max(len(word) for word in lst)\n return max_length", "matching_cluster_idx": 5}, {"solution": "def len_log(words_list):\n # Find the length of the longest word in the list\n max_length = max(len(word) for word in words_list)\n return max_length", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n # Calculate the maximum length among the words\n max_length = max(len(word) for word in words)\n return max_length", "matching_cluster_idx": 4}, {"solution": "def len_log(lst):\n # Find the length of the longest word in the list\n max_length = max(len(word) for word in lst)\n return max_length", "matching_cluster_idx": 5}, {"solution": "def len_log(lst):\n # Initialize the maximum length variable\n max_len = 0\n # Iterate through each word in the list\n for word in lst:\n # Update max_len if the current word's length is greater\n if len(word) > max_len:\n max_len = len(word)\n return max_len", "matching_cluster_idx": 5}, {"solution": "def len_log(lst):\n # Find the maximum length among the elements of the list\n max_len = max(len(word) for word in lst)\n return max_len", "matching_cluster_idx": 5}, {"solution": "def len_log(lst):\n # Find the maximum length among all the words in the list\n max_length = max(len(word) for word in lst)\n return max_length", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n # Calculate the length of the longest word\n max_length = max(len(word) for word in words)\n return max_length", "matching_cluster_idx": 5}, {"solution": "def len_log(lst):\n # Find the maximum length among the elements in the list\n max_len = max(len(x) for x in lst)\n return max_len", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n # Initialize max_length to zero\n max_length = 0\n \n # Iterate through each word in the list\n for word in words:\n # Update max_length if the current word's length is greater\n if len(word) > max_length:\n max_length = len(word)\n \n return max_length", "matching_cluster_idx": 5}]}, "Mbpp/94": {"dps": 78.04878048780488, "dps_norm": 60.0, "pass@1": 100.0, "profiled": [{"solution": "def index_minimum(test_list):\n # Find the tuple with the smallest second value\n min_tuple = min(test_list, key=lambda x: x[1])\n # Return the first value of that tuple\n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(test_list):\n # Finding the tuple with the minimum second value\n min_tuple = min(test_list, key=lambda x: x[1])\n # Returning the first value of the found tuple\n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(test_list):\n # Find the tuple with the minimum value in the second position\n min_tuple = min(test_list, key=lambda x: x[1])\n # Return the first value of the found tuple\n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(test_list):\n # Find the tuple with the smallest second value\n min_tuple = min(test_list, key=lambda x: x[1])\n # Return the first value of the tuple with the smallest second value\n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(test_list):\n # Find the tuple with the smallest second value\n min_tuple = min(test_list, key=lambda x: x[1])\n # Return the first value of that tuple\n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(test_list):\n # Find the tuple with the minimum second value\n min_tuple = min(test_list, key=lambda x: x[1])\n # Return the first value of that tuple\n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(test_list):\n # Find the tuple with the smallest second value and return its first value\n return min(test_list, key=lambda x: x[1])[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(test_list):\n # Find the tuple with the smallest second value\n min_tuple = min(test_list, key=lambda x: x[1])\n # Return the first value of the found tuple\n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(test_list):\n # Find the tuple with the smallest second value\n min_tuple = min(test_list, key=lambda x: x[1])\n # Return the first value of that tuple\n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(test_list):\n # Find the tuple with the minimum second value\n min_tuple = min(test_list, key=lambda x: x[1])\n # Return the first value of the tuple\n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(test_list):\n # Find the tuple with the smallest second value\n min_tuple = min(test_list, key=lambda x: x[1])\n # Return the first value of that tuple\n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(test_list):\n # Find the tuple with the minimum second value and return its first value\n return min(test_list, key=lambda x: x[1])[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(test_list):\n # Find the tuple with the minimum second value\n min_tuple = min(test_list, key=lambda x: x[1])\n # Return the first value of that tuple\n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(test_list):\n # Find the tuple with the smallest second value and return its first value\n return min(test_list, key=lambda x: x[1])[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(test_list):\n # Find the tuple with the minimum second value\n min_tuple = min(test_list, key=lambda x: x[1])\n # Return the first value of the found tuple\n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(test_list):\n # Find the tuple with the smallest second value\n min_tuple = min(test_list, key=lambda x: x[1])\n # Return the first value of the found tuple\n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(test_list):\n # Find the tuple with the smallest second value\n min_tuple = min(test_list, key=lambda x: x[1])\n # Return the first value of the found tuple\n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(test_list):\n # Find the tuple with the minimum second value\n min_tuple = min(test_list, key=lambda x: x[1])\n # Return the first value of that tuple\n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(test_list):\n # Finding the tuple with the smallest second value\n min_tuple = min(test_list, key=lambda x: x[1])\n # Returning the first value of the tuple\n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(test_list):\n # Finding the tuple with the smallest second value\n min_tuple = min(test_list, key=lambda x: x[1])\n # Returning the first value of that tuple\n return min_tuple[0]", "matching_cluster_idx": 2}]}, "Mbpp/96": {"dps": 77.77777777777777, "dps_norm": 42.857142857142854, "pass@1": 100.0, "profiled": [{"solution": "def divisor(n):\n # Initialize count of divisors\n count = 0\n \n # Loop through all numbers from 1 to n (inclusive) \n for i in range(1, n + 1):\n # If 'i' is a divisor of 'n', increment count\n if n % i == 0:\n count += 1\n \n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n \"\"\"\n Counts the number of divisors of a given integer n.\n \n Parameters:\n n (int): The integer to find the divisors of.\n\n Returns:\n int: The number of divisors of n.\n \"\"\"\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n # Initialize the count of divisors\n count = 0\n # Iterate through possible divisors\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n # Initialize the count of divisors\n count = 0\n \n # Loop from 1 to n (inclusive) to check for divisors\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n \n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n \"\"\"\n This function calculates the number of divisors of a given integer n.\n \n Parameters:\n n (int): The integer whose divisors are to be counted.\n \n Returns:\n int: The number of divisors of the given integer.\n \"\"\"\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n \"\"\"\n Calculate the number of divisors of a given integer n.\n \n :param n: Integer to find the number of divisors for\n :return: Number of divisors of n\n \"\"\"\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n # Initialize count of divisors\n count = 0\n # Loop through all numbers from 1 to n (inclusive)\n for i in range(1, n + 1):\n # If n is divisible by i, increment the count\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n # Initialize a counter to count divisors\n count = 0\n # Loop through all numbers from 1 to n (inclusive)\n for i in range(1, n + 1):\n # If i is a divisor of n, increment the counter\n if n % i == 0:\n count += 1\n # Return the total number of divisors found\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n \"\"\"\n This function takes an integer n as input and returns the number of divisors of n.\n \n :param n: Integer to find divisors for\n :return: The number of divisors of n\n \"\"\"\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n # Initialize the count of divisors\n count = 0\n # Iterate over all possible divisors\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n # Initialize count of divisors\n count = 0\n # Loop through possible divisors\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n # Initialize a counter for divisors\n count = 0\n # Loop through all numbers from 1 to n (inclusive)\n for i in range(1, n + 1):\n # If i is a divisor of n, increment the count\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}]}, "Mbpp/97": {"dps": 99.65811965811966, "dps_norm": 87.5, "pass@1": 100.0, "profiled": [{"solution": "def frequency_lists(lst):\n # Flatten the list of lists\n flat_list = [item for sublist in lst for item in sublist]\n \n # Create a dictionary to hold the frequencies\n frequency_dict = {}\n for item in flat_list:\n if item in frequency_dict:\n frequency_dict[item] += 1\n else:\n frequency_dict[item] = 1\n return frequency_dict", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lst):\n # Create an empty dictionary to store frequency of each element\n frequency = {}\n \n # Iterate through each sublist\n for sublist in lst:\n # Iterate through each element in the sublist\n for elem in sublist:\n # Increment the count for the element, start at 0 if not already in the dictionary\n frequency[elem] = frequency.get(elem, 0) + 1\n \n return frequency", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lst):\n # Initialize an empty dictionary to store frequencies\n freq_dict = {}\n \n # Iterate over each list within the list of lists\n for sublist in lst:\n # Iterate over each element in the sublist\n for elem in sublist:\n # If the element is in the dictionary, increment its count\n if elem in freq_dict:\n freq_dict[elem] += 1\n # Otherwise, add the element to the dictionary with a count of 1\n else:\n freq_dict[elem] = 1\n \n # Return the dictionary with frequencies\n return freq_dict", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lst):\n # Initialize an empty dictionary to hold frequencies\n frequency_dict = {}\n \n # Iterate over each sublist\n for sublist in lst:\n # Iterate over each item in the sublist\n for item in sublist:\n # If the item is in the dictionary, increment its count\n if item in frequency_dict:\n frequency_dict[item] += 1\n # Otherwise, add the item with a count of 1\n else:\n frequency_dict[item] = 1\n \n return frequency_dict", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lists):\n # Initialize an empty dictionary to hold the frequencies\n frequency = {}\n \n # Loop through each sublist in the list of lists\n for sublist in lists:\n # Loop through each element in the sublist\n for item in sublist:\n # If the item is not in the dictionary, add it with a count of 1\n if item not in frequency:\n frequency[item] = 1\n else:\n # If the item is already in the dictionary, increment its count by 1\n frequency[item] += 1\n \n return frequency", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lst):\n # Initialize an empty dictionary to store the frequency of each element\n frequency_dict = {}\n \n # Iterate through each sublist in the main list\n for sublist in lst:\n # Iterate through each element in the sublist\n for element in sublist:\n # If the element is already in the dictionary, increment its count\n if element in frequency_dict:\n frequency_dict[element] += 1\n # Otherwise, add the element to the dictionary with a count of 1\n else:\n frequency_dict[element] = 1\n \n return frequency_dict", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lst):\n from collections import defaultdict\n\n # Initialize a default dictionary to hold the counts\n frequency_dict = defaultdict(int)\n \n # Iterate over each sublist in the list of lists\n for sublst in lst:\n # Iterate over each element in the sublist\n for element in sublst:\n # Increment the count of the element in the dictionary\n frequency_dict[element] += 1\n \n # Convert the defaultdict to a regular dict before returning\n return dict(frequency_dict)", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lists):\n # Initialize an empty dictionary to store frequencies\n frequency_dict = {}\n # Flatten the list of lists and iterate over each element\n for sublist in lists:\n for item in sublist:\n # Update the count of the item in the dictionary\n if item in frequency_dict:\n frequency_dict[item] += 1\n else:\n frequency_dict[item] = 1\n return frequency_dict", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lst):\n # Initialize an empty dictionary to store the frequency of each element\n frequency_dict = {}\n \n # Iterate over each sublist in the list of lists\n for sublist in lst:\n # Iterate over each element in the sublist\n for element in sublist:\n # Update the count of the element in the dictionary\n if element in frequency_dict:\n frequency_dict[element] += 1\n else:\n frequency_dict[element] = 1\n \n return frequency_dict", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lists):\n # Initialize an empty dictionary to keep track of frequencies\n frequency_dict = {}\n \n # Iterate over each sublist and then over each element in the sublist\n for sublist in lists:\n for item in sublist:\n # Update the dictionary with the frequency of each item\n if item in frequency_dict:\n frequency_dict[item] += 1\n else:\n frequency_dict[item] = 1\n \n return frequency_dict", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lst):\n from collections import defaultdict\n \n # Initialize a default dictionary to hold the frequency of each element\n frequency = defaultdict(int)\n \n # Iterate over each sublist and each element within it\n for sublist in lst:\n for item in sublist:\n frequency[item] += 1\n \n return dict(frequency)", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lists):\n # Import Counter from collections\n from collections import Counter\n \n # Flatten the list of lists\n flattened_list = [item for sublist in lists for item in sublist]\n \n # Count the frequency of each element\n frequency_dict = Counter(flattened_list)\n \n return dict(frequency_dict)", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lists):\n # Initialize an empty dictionary to store the frequencies\n frequency_dict = {}\n \n # Flatten the list of lists and calculate frequencies\n for sublist in lists:\n for item in sublist:\n if item in frequency_dict:\n frequency_dict[item] += 1\n else:\n frequency_dict[item] = 1\n \n return frequency_dict", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lst):\n # Importing Counter from collections to count frequency of elements\n from collections import Counter\n \n # Flatten the list of lists\n flat_list = [item for sublist in lst for item in sublist]\n \n # Count the frequency of each element in the flattened list\n freq = Counter(flat_list)\n \n return dict(freq)", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lst):\n # Flatten the list of lists\n flat_list = [item for sublist in lst for item in sublist]\n # Create an empty dictionary to store the frequency of each element\n freq_dict = {}\n # Iterate through the flat list\n for item in flat_list:\n if item in freq_dict:\n freq_dict[item] += 1\n else:\n freq_dict[item] = 1\n return freq_dict", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lst):\n from collections import defaultdict\n # Create a dictionary to hold the frequencies\n frequency_dict = defaultdict(int)\n \n # Iterate through each list in the list of lists\n for sublist in lst:\n # Iterate through each element in the sublist\n for element in sublist:\n # Increment the count of the element in the dictionary\n frequency_dict[element] += 1\n \n return dict(frequency_dict)", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lists):\n from collections import Counter\n # Flatten the list of lists\n flat_list = [item for sublist in lists for item in sublist]\n # Count the frequency of each element\n freq_dict = Counter(flat_list)\n return dict(freq_dict)", "matching_cluster_idx": 6}, {"solution": "from collections import Counter\ndef frequency_lists(lists):\n # Flatten the list of lists\n flat_list = [item for sublist in lists for item in sublist]\n # Count the frequency of each item\n frequency = Counter(flat_list)\n return dict(frequency)", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lists):\n # Initialize an empty dictionary to store the frequency of elements\n frequency = {}\n \n # Iterate over each list in the lists\n for sublist in lists:\n # Iterate over each element in the sublist\n for element in sublist:\n # If the element is not in the frequency dictionary, set its count to 0\n if element not in frequency:\n frequency[element] = 0\n # Increment the count for the element\n frequency[element] += 1\n \n return frequency", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lists):\n # Flatten the list of lists into a single list\n flattened_list = [item for sublist in lists for item in sublist]\n \n # Create a dictionary to store the frequency of each element\n frequency_dict = {}\n \n # Iterate over each element in the flattened list\n for element in flattened_list:\n # If the element is not yet in the dictionary, initialize it with 1\n if element not in frequency_dict:\n frequency_dict[element] = 1\n # If the element is already in the dictionary, increment the count\n else:\n frequency_dict[element] += 1\n \n return frequency_dict", "matching_cluster_idx": 6}]}, "Mbpp/106": {"dps": 49.15584415584416, "dps_norm": 83.33333333333333, "pass@1": 96.0, "profiled": [{"solution": "def add_lists(lst, t):\n # Convert the tuple to a list to append the given list\n t_lst = list(t)\n t_lst.extend(lst)\n # Convert back to a tuple\n result = tuple(t_lst)\n return result", "matching_cluster_idx": 4}, {"solution": "def add_lists(lst, tup):\n # Extend the tuple by adding the list elements to the end\n return tup + tuple(lst)", "matching_cluster_idx": 4}, {"solution": "def add_lists(list1, tuple1):\n # Converting tuple to list to perform addition operation\n temp_list = list(tuple1)\n # Appending list elements to the temporary list\n temp_list.extend(list1)\n # Converting list back to tuple\n result_tuple = tuple(temp_list)\n return result_tuple", "matching_cluster_idx": 4}, {"solution": "def add_lists(lst, tup):\n # Append each element of the list to the tuple\n result = tup + tuple(lst)\n return result", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tup):\n # Convert the tuple to a list, concatenate it with the given list, then convert it back to a tuple\n result = tuple(list(tup) + lst)\n return result", "matching_cluster_idx": 3}, {"solution": "def add_lists(lst, tup):\n # Converting tuple to list to append the given list\n temp = list(tup)\n temp.extend(lst)\n # Converting the list back to tuple\n result = tuple(temp)\n return result", "matching_cluster_idx": 4}, {"solution": "def add_lists(lst, tpl):\n # Convert the tuple to a list, append the given list, and then convert it back to a tuple\n return tpl + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tup):\n # Convert the list to a tuple and concatenate it with the given tuple\n result = tup + tuple(lst)\n return result", "matching_cluster_idx": 4}, {"solution": "def add_lists(lst, tup):\n # Convert the tuple to a list, concatenate it with the given list, and convert back to a tuple\n new_tup = tup + tuple(lst)\n return new_tup", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tup):\n # Convert the list to a tuple and concatenate it to the given tuple\n return tup + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tup):\n # Convert the tuple to a list, extend it with the given list, and convert it back to a tuple\n result = list(tup) + lst\n return tuple(result)", "matching_cluster_idx": 3}, {"solution": "def add_lists(lst, tup):\n # Append list elements to the tuple\n result = tup + tuple(lst)\n return result", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tup):\n # Convert the tuple to a list, extend it with the given list, and convert back to a tuple\n result = list(tup) + lst\n return tuple(result)", "matching_cluster_idx": 3}, {"solution": "def add_lists(lst, tup):\n # Convert the tuple to a list, concatenate it with the given list, then convert back to tuple\n return tup + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(list1, tuple1):\n # Convert the tuple to a list, append the given list to it\n result = list(tuple1) + list1\n # Convert the result back to a tuple\n return tuple(result)", "matching_cluster_idx": 3}, {"solution": "def add_lists(lst, tup):\n # Convert the tuple to a list, append the given list, and convert back to a tuple\n new_tup = tup + tuple(lst)\n return new_tup", "matching_cluster_idx": 4}, {"solution": "def add_lists(lst, tup):\n # Convert list to tuple and concatenate\n result = tup + tuple(lst)\n return result", "matching_cluster_idx": 4}, {"solution": "def add_lists(input_list, input_tuple):\n # Convert tuple to a list, concatenate the input list, and convert back to tuple\n combined_tuple = tuple(list(input_tuple) + input_list)\n return combined_tuple", "matching_cluster_idx": 3}, {"solution": "def add_lists(lst, tup):\n # Convert the tuple to a list, append the given list, and convert back to a tuple\n result = list(tup) + lst\n return tuple(result)", "matching_cluster_idx": 3}, {"solution": "def add_lists(lst, tup):\n # Convert tuple to a list, append the given list, and then convert it back to a tuple\n new_tup = tup + tuple(lst)\n return new_tup", "matching_cluster_idx": 4}]}, "Mbpp/108": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def merge_sorted_list(list1, list2, list3):\n # Merge the three lists into one\n merged_list = list1 + list2 + list3\n # Sort the merged list\n merged_list.sort()\n return merged_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Merge the three lists into one\n merged_list = list1 + list2 + list3\n # Sort the merged list\n sorted_list = sorted(merged_list)\n return sorted_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Combine all three lists into one\n combined_list = list1 + list2 + list3\n # Sort the combined list\n combined_list.sort()\n return combined_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Merge the three lists\n merged_list = list1 + list2 + list3\n # Sort the merged list\n merged_list.sort()\n return merged_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Merge the lists into one\n merged_list = list1 + list2 + list3\n # Sort the merged list\n merged_list.sort()\n return merged_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Merging all three lists into one\n merged_list = list1 + list2 + list3\n # Sorting the merged list\n merged_list.sort()\n return merged_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Merge all three lists into one\n merged_list = list1 + list2 + list3\n # Sort the merged list\n merged_list.sort()\n return merged_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(lst1, lst2, lst3):\n # Merging the three lists\n merged_list = lst1 + lst2 + lst3\n # Sorting the merged list\n merged_list.sort()\n return merged_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(lst1, lst2, lst3):\n # Combine the three lists into one\n merged_list = lst1 + lst2 + lst3\n # Sort the combined list\n merged_list.sort()\n return merged_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Merge the three lists into one\n merged_list = list1 + list2 + list3\n # Sort the merged list\n sorted_list = sorted(merged_list)\n return sorted_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(lst1, lst2, lst3):\n # Merging the three lists\n merged_list = lst1 + lst2 + lst3\n # Sorting the merged list\n merged_list.sort()\n return merged_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Merge all three lists into one\n merged_list = list1 + list2 + list3\n # Sort the merged list\n merged_list.sort()\n return merged_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Merge all three lists into one\n merged_list = list1 + list2 + list3\n # Sort the merged list\n merged_list.sort()\n return merged_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Merge all three lists into one\n merged_list = list1 + list2 + list3\n # Sort the merged list\n sorted_list = sorted(merged_list)\n return sorted_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Merging all three lists\n merged_list = list1 + list2 + list3\n # Sorting the merged list\n merged_list.sort()\n return merged_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Merge the three lists into one\n merged_list = list1 + list2 + list3\n # Sort the merged list\n sorted_list = sorted(merged_list)\n return sorted_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Merging all three lists into one\n merged_list = list1 + list2 + list3\n # Sorting the merged list\n merged_list.sort()\n return merged_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Combine all three lists into one\n merged_list = list1 + list2 + list3\n # Sort the combined list\n merged_list.sort()\n return merged_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Combine all three lists into one\n combined_list = list1 + list2 + list3\n # Sort the combined list\n sorted_list = sorted(combined_list)\n return sorted_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(lst1, lst2, lst3):\n # Concatenate all three lists\n merged_list = lst1 + lst2 + lst3\n # Sort the merged list\n merged_list.sort()\n return merged_list", "matching_cluster_idx": 10}]}, "Mbpp/111": {"dps": 91.53846153846155, "dps_norm": 86.25, "pass@1": 100.0, "profiled": [{"solution": "def common_in_nested_lists(nested_lists):\n # Convert each sublist into a set and find intersection of all sets\n common_elements = set(nested_lists[0]).intersection(*nested_lists[1:])\n return list(common_elements)", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n # Convert each sublist into a set and calculate the intersection\n common_elements = set(nested_lists[0]).intersection(*nested_lists[1:])\n return list(common_elements)", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n # Using set intersection to find common elements across all lists\n common_elements = set(nested_lists[0])\n for lst in nested_lists[1:]:\n common_elements.intersection_update(lst)\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n # Convert the first list to a set\n common_elements = set(nested_lists[0])\n \n # Intersect with the rest of the lists to find common elements\n for lst in nested_lists[1:]:\n common_elements.intersection_update(lst)\n \n return common_elements", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n # Find the intersection of all lists in the nested list\n common_elements = set(nested_lists[0])\n for lst in nested_lists[1:]:\n common_elements.intersection_update(lst)\n \n return list(common_elements)", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n # Convert each sublist into a set and calculate intersection\n common_elements = set.intersection(*map(set, nested_lists))\n return list(common_elements)", "matching_cluster_idx": 5}, {"solution": "def common_in_nested_lists(nested_lists):\n # Use set intersection to find common elements\n common_elements = set(nested_lists[0])\n for lst in nested_lists[1:]:\n common_elements.intersection_update(lst)\n return list(common_elements)", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n # Convert the first list to a set for comparison\n common_elements = set(nested_lists[0])\n \n # Iterate through the rest of the lists and find common elements\n for sublist in nested_lists[1:]:\n common_elements.intersection_update(sublist)\n \n return common_elements", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n # Convert each sublist into a set and calculate the intersection of all sets\n common_elements = set(nested_lists[0]).intersection(*nested_lists[1:])\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(lists):\n # Convert the first list in the nested list to a set\n common_elements = set(lists[0])\n \n # Iterate over the rest of the lists in the nested list\n for lst in lists[1:]:\n # Update common_elements with the intersection of itself and the current list (converted to a set)\n common_elements.intersection_update(lst)\n \n return list(common_elements)", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n # Convert the first list to a set to initiate intersection\n common_elements = set(nested_lists[0])\n \n # Iterate over the rest of the lists and find the intersection\n for sublist in nested_lists[1:]:\n common_elements.intersection_update(sublist)\n \n return common_elements", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n # Convert the first list to a set for comparison\n common_elements = set(nested_lists[0])\n # Iterate through each list in the nested list\n for lst in nested_lists[1:]:\n # Update the set of common elements with the intersection of itself and the current list\n common_elements.intersection_update(lst)\n # Return the set of common elements\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(lst):\n # Convert the first sublist to a set\n common_elements = set(lst[0])\n \n # Iterate over the rest of the sublists\n for sublist in lst[1:]:\n # Convert the sublist to a set and find intersection with the accumulated common elements\n common_elements.intersection_update(sublist)\n \n return common_elements", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n # Convert each sublist into a set and find intersection\n common_elements = set(nested_lists[0]).intersection(*nested_lists[1:])\n return list(common_elements)", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n # Use set intersection to find common elements\n common_elements = set(nested_lists[0])\n for lst in nested_lists[1:]:\n common_elements.intersection_update(lst)\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n # Convert the first list in the nested lists to a set\n common_elements = set(nested_lists[0])\n \n # Iterate over the rest of the lists to find common elements\n for lst in nested_lists[1:]:\n # Update the common_elements set with the intersection of itself and the current list\n common_elements.intersection_update(lst)\n \n return common_elements", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n # Use set intersection to find common elements across all sublists\n common_elements = set(nested_lists[0])\n for lst in nested_lists[1:]:\n common_elements &= set(lst)\n return list(common_elements)", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n # Convert each sublist into a set and then find the intersection of these sets\n common_elements = set.intersection(*map(set, nested_lists))\n return list(common_elements)", "matching_cluster_idx": 5}, {"solution": "def common_in_nested_lists(nested_lists):\n # Convert each list to a set and calculate the intersection of all sets\n common_elements = set(nested_lists[0]).intersection(*nested_lists[1:])\n return list(common_elements)", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n # Convert each sublist to a set and find intersection\n common_elements = set(nested_lists[0]).intersection(*nested_lists[1:])\n return list(common_elements)", "matching_cluster_idx": 6}]}, "Mbpp/123": {"dps": 99.62686567164178, "dps_norm": 85.71428571428571, "pass@1": 73.0, "profiled": [{"solution": "def amicable_numbers_sum(limit):\n # Initialize the sum of amicable numbers to 0\n amicable_sum = 0\n # Iterate through each number from 2 up to the limit\n for num in range(2, limit + 1):\n # If the number is part of an amicable pair, add it to the sum\n if is_amicable(num):\n amicable_sum += num\n return amicable_sum\ndef proper_divisors_sum(n):\n # Find the sum of proper divisors of n\n divisors_sum = 1 # 1 is a proper divisor of all natural numbers\n # Check for divisors from 2 up to the square root of n\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n divisors_sum += i\n # Add the quotient if it's different from i\n if i != n // i:\n divisors_sum += n // i\n return divisors_sum\ndef is_amicable(n):\n # Check if a number n is part of an amicable pair\n # Find the sum of proper divisors of n\n sum_n = proper_divisors_sum(n)\n # If the sum of proper divisors of n equals the sum of proper divisors of this sum and is not equal to n itself, then it's amicable\n return sum_n != n and n == proper_divisors_sum(sum_n)", "matching_cluster_idx": 11}, {"solution": "def divisors_sum(n):\n \"\"\"Helper function to calculate the sum of proper divisors of n.\"\"\"\n total = 1 # 1 is a proper divisor for all n > 1\n for i in range(2, int(n ** 0.5) + 1):\n if n % i == 0:\n total += i\n if i != n // i: # add the quotient only if it's different from i\n total += n // i\n return total\ndef amicable_numbers_sum(limit):\n \"\"\"\n Returns the sum of all amicable numbers up to a specified limit.\n \n An amicable pair (a, b) consists of two integers for which the sum of proper divisors\n of each is equal to the other integer. For instance, (220, 284) is an amicable pair.\n \"\"\"\n amicable_sum = 0\n for num in range(2, limit + 1):\n sum_of_divs = divisors_sum(num)\n if sum_of_divs > num and sum_of_divs <= limit and divisors_sum(sum_of_divs) == num:\n amicable_sum += num + sum_of_divs\n return amicable_sum", "matching_cluster_idx": 11}, {"solution": "def amicable_numbers_sum(limit):\n # Initialize the sum of amicable numbers\n sum_amicable = 0\n \n # Function to calculate sum of proper divisors of n\n def sum_proper_divisors(n):\n sum_div = 1 # Initialize with 1 since it's a proper divisor\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n sum_div += i\n if i != n // i: # Avoid adding the square root twice for perfect squares\n sum_div += n // i\n return sum_div\n \n # Iterate through numbers to find amicable pairs\n for num in range(2, limit + 1):\n sum_div1 = sum_proper_divisors(num)\n if sum_div1 > num and sum_div1 <= limit: # Ensure we do not go out of bounds\n sum_div2 = sum_proper_divisors(sum_div1)\n if sum_div2 == num:\n sum_amicable += num + sum_div1 # Add both numbers in the pair\n \n return sum_amicable", "matching_cluster_idx": 11}, {"solution": "def sum_of_divisors(n):\n \"\"\"\n This function calculates the sum of proper divisors of a number n.\n \"\"\"\n total = 1 # start with 1 because it's a proper divisor of all numbers\n root = int(n**0.5)\n for i in range(2, root + 1):\n if n % i == 0:\n total += i\n if i != n // i:\n total += n // i\n return total\ndef amicable_numbers_sum(limit):\n \"\"\"\n This function finds the sum of all amicable numbers under a certain limit.\n Amicable numbers are two different numbers so related that the sum of the proper divisors\n of each is equal to the other number.\n \"\"\"\n amicable_sum = 0\n for num in range(2, limit):\n partner = sum_of_divisors(num)\n if partner > num and sum_of_divisors(partner) == num:\n amicable_sum += num + partner\n return amicable_sum", "matching_cluster_idx": 11}, {"solution": "def proper_divisors_sum(n):\n divisors_sum = 1 # 1 is a proper divisor for any n > 1\n sqrt_n = int(n ** 0.5)\n for i in range(2, sqrt_n + 1):\n if n % i == 0:\n divisors_sum += i\n if i != n // i:\n divisors_sum += n // i\n return divisors_sum\ndef amicable_numbers_sum(limit):\n sum_of_amicable = 0\n for num in range(2, limit + 1):\n partner = proper_divisors_sum(num)\n if partner > num and proper_divisors_sum(partner) == num:\n sum_of_amicable += num + partner\n return sum_of_amicable", "matching_cluster_idx": 11}, {"solution": "def sum_divisors(n):\n total = 1 # 1 is a divisor for all numbers\n sqrt_n = int(n**0.5)\n for i in range(2, sqrt_n + 1):\n if n % i == 0:\n total += i\n if i != n // i:\n total += n // i\n return total\ndef amicable_numbers_sum(limit):\n \"\"\"\n Function to sum all amicable numbers from 1 to a specified limit.\n Amicable numbers are two different numbers so related that the sum of the proper divisors\n of each is equal to the other number.\n \"\"\"\n sum_dict = {i: sum_divisors(i) for i in range(1, limit + 1)}\n amicable_sum = 0\n for i in range(2, limit + 1):\n sum_i = sum_dict[i]\n if sum_i != i and sum_i <= limit and sum_dict.get(sum_i, 0) == i:\n amicable_sum += i\n return amicable_sum", "matching_cluster_idx": 11}, {"solution": "def amicable_numbers_sum(limit):\n \"\"\"\n Calculate the sum of all amicable numbers up to a specified limit.\n\n Args:\n - limit (int): The upper limit for finding amicable numbers.\n\n Returns:\n - int: The sum of all amicable numbers up to the limit.\n \"\"\"\n def sum_of_divisors(n):\n # Return the sum of all proper divisors of n\n total = 1\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n if i == n // i:\n total += i\n else:\n total += i + n // i\n return total\n\n # Generate a list of the sum of divisors for each number up to the limit\n sum_of_divs = [sum_of_divisors(i) for i in range(limit + 1)]\n\n # Find and sum all amicable numbers\n amicable_sum = 0\n for i in range(2, limit + 1):\n if (sum_of_divs[i] < limit + 1 and \n sum_of_divs[i] != i and \n sum_of_divs[sum_of_divs[i]] == i):\n amicable_sum += i\n \n return amicable_sum", "matching_cluster_idx": 11}, {"solution": "def amicable_numbers_sum(limit):\n \"\"\"\n This function calculates the sum of all amicable numbers up to a given limit.\n \n Args:\n limit (int): The upper bound for the search of amicable numbers.\n \n Returns:\n int: The sum of all amicable numbers up to the given limit.\n \"\"\"\n \n def sum_of_divisors(n):\n \"\"\"Calculate the sum of the proper divisors of n.\"\"\"\n divisors_sum = 1 # 1 is a proper divisor of all numbers\n sqrt_n = int(n ** 0.5)\n for i in range(2, sqrt_n + 1):\n if n % i == 0:\n divisors_sum += i\n if i != n // i:\n divisors_sum += n // i\n return divisors_sum\n\n # Dictionary to hold sums of divisors for encountered numbers\n sums_of_divisors = {}\n\n total_sum = 0\n for number in range(2, limit + 1):\n if number not in sums_of_divisors:\n sum_divisors = sum_of_divisors(number)\n sums_of_divisors[number] = sum_divisors\n\n if sum_divisors <= limit and sum_divisors != number:\n if sum_divisors in sums_of_divisors and sums_of_divisors[sum_divisors] == number:\n total_sum += number + sum_divisors\n # Once a pair is found, set their values to 0 to avoid recounting\n sums_of_divisors[number] = 0\n sums_of_divisors[sum_divisors] = 0\n\n return total_sum", "matching_cluster_idx": 11}, {"solution": "def amicable_numbers_sum(limit):\n # This function calculates the sum of all amicable numbers below the given limit.\n \n def sum_of_divisors(n):\n # Helper function to find the sum of proper divisors of n\n divisors_sum = 1 # 1 is a proper divisor of any n > 1\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n divisors_sum += i\n if i != n // i:\n divisors_sum += n // i\n return divisors_sum\n \n total_sum = 0\n for num in range(2, limit):\n # Calculate the sum of proper divisors of the current number\n ami_pair = sum_of_divisors(num)\n # Check if the ami_pair is within the limit and is different from num\n if ami_pair < limit and ami_pair != num and sum_of_divisors(ami_pair) == num:\n # Add only if they are not already added (only once per pair)\n if ami_pair > num:\n total_sum += num + ami_pair\n return total_sum", "matching_cluster_idx": 11}, {"solution": "def amicable_numbers_sum(limit):\n def sum_of_proper_divisors(n):\n # Start with 1 because it is a proper divisor of any number\n total = 1\n # Loop from 2 to the square root of n to find proper divisors\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n # Add both divisors if they are not the same\n total += i\n if i != n // i:\n total += n // i\n return total\n \n amicable_sum = 0\n # Loop through numbers from 2 to the specified limit\n for num in range(2, limit):\n # Find sum of proper divisors of current number\n sum1 = sum_of_proper_divisors(num)\n # Check if sum of proper divisors of sum1 equals to the current number\n if sum1 > num and sum_of_proper_divisors(sum1) == num:\n amicable_sum += num + sum1\n \n return amicable_sum", "matching_cluster_idx": 11}, {"solution": "def proper_divisors(n):\n divisors = [1]\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n divisors.append(i)\n if i != n // i:\n divisors.append(n // i)\n return divisors\ndef amicable_numbers_sum(limit):\n # Store the sum of proper divisors for each number\n div_sum = [sum(proper_divisors(i)) for i in range(limit + 1)]\n # Track amicable numbers to avoid recounting\n amicable = set()\n for i in range(2, limit + 1):\n if div_sum[i] < limit + 1 and i == div_sum[div_sum[i]] and i != div_sum[i]:\n amicable.add(i)\n return sum(amicable)", "matching_cluster_idx": 11}, {"solution": "def amicable_numbers_sum(limit):\n \"\"\"\n Calculate the sum of all amicable numbers up to a given limit.\n An amicable pair (a, b) consists of two integers for which the sum of proper divisors (excluding the number itself) of each is equal to the other number.\n \"\"\"\n def sum_of_divisors(n):\n \"\"\"\n Helper function to calculate sum of proper divisors of n.\n \"\"\"\n divisors_sum = 1 # 1 is a proper divisor for all n > 1\n sqrt_n = int(n ** 0.5)\n for i in range(2, sqrt_n + 1):\n if n % i == 0:\n divisors_sum += i\n if i != n // i:\n divisors_sum += n // i\n return divisors_sum\n\n amicable_sum = 0\n for num in range(2, limit):\n # Find the sum of proper divisors\n divisor_sum = sum_of_divisors(num)\n # Check if the number is amicable and the counterpart is within the limit\n if divisor_sum != num and divisor_sum < limit and sum_of_divisors(divisor_sum) == num:\n amicable_sum += num\n\n return amicable_sum", "matching_cluster_idx": 11}, {"solution": "def proper_divisors_sum(n):\n \"\"\"\n Function to calculate sum of proper divisors of a number.\n \"\"\"\n divisors_sum = 1 # 1 is a proper divisor for all n > 1\n for i in range(2, int(n ** 0.5) + 1):\n if n % i == 0:\n divisors_sum += i\n if i != n // i: # Add the quotient only if it's different from i\n divisors_sum += n // i\n return divisors_sum\ndef amicable_numbers_sum(limit):\n \"\"\"\n Function to sum all amicable numbers from 1 to a specified number.\n \"\"\"\n amicable_sums = {}\n total_sum = 0\n for i in range(2, limit + 1):\n if i not in amicable_sums:\n ami_pair = proper_divisors_sum(i)\n if ami_pair != i and proper_divisors_sum(ami_pair) == i:\n amicable_sums[i] = ami_pair\n amicable_sums[ami_pair] = i\n total_sum += i + ami_pair\n return total_sum", "matching_cluster_idx": 11}, {"solution": "def get_proper_divisors_sum(n):\n \"\"\"\n Helper function to calculate the sum of proper divisors of n.\n \"\"\"\n div_sum = 1 # 1 is a proper divisor for all n > 1\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n div_sum += i\n if i != n // i:\n div_sum += n // i\n return div_sum\ndef amicable_numbers_sum(limit):\n \"\"\"\n Function to sum all amicable numbers from 1 to the specified limit.\n \"\"\"\n sum_of_divisors = [get_proper_divisors_sum(i) for i in range(limit)]\n amicable_sum = 0\n for i in range(2, limit):\n if sum_of_divisors[i] < limit and i == sum_of_divisors[sum_of_divisors[i]] and i != sum_of_divisors[i]:\n amicable_sum += i\n return amicable_sum", "matching_cluster_idx": 11}, {"solution": "def sum_of_divisors(n):\n \"\"\"\n Calculate the sum of proper divisors of n.\n \"\"\"\n total = 1 # 1 is a proper divisor of any n > 1\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n total += i\n if i != n // i:\n total += n // i\n return total\ndef amicable_numbers_sum(limit):\n \"\"\"\n Sum all amicable numbers up to a given limit.\n \"\"\"\n if limit < 220:\n return 0 # 220 is the smallest amicable number\n \n # Calculate the sum of divisors for each number in the range\n divisor_sums = [sum_of_divisors(i) for i in range(limit + 1)]\n \n # Identify and sum the amicable numbers\n amicable_sum = 0\n for a in range(220, limit + 1):\n b = divisor_sums[a]\n if b > a and b <= limit and divisor_sums[b] == a:\n amicable_sum += a + b # Add both numbers in the pair\n \n return amicable_sum", "matching_cluster_idx": 11}, {"solution": "def sum_divisors(n):\n \"\"\"\n Function to calculate the sum of divisors of n excluding n itself.\n \"\"\"\n total = 1 # 1 is always a divisor\n sqrt_n = int(n ** 0.5)\n for i in range(2, sqrt_n + 1):\n if n % i == 0:\n total += i\n if i != n // i: # Add the divisor pair if not a perfect square\n total += n // i\n return total\ndef amicable_numbers_sum(limit):\n \"\"\"\n Calculates the sum of all amicable numbers up to the specified limit.\n \"\"\"\n amicable_sum = 0\n for num in range(2, limit + 1):\n partner = sum_divisors(num)\n if partner > num and sum_divisors(partner) == num:\n amicable_sum += num + partner\n return amicable_sum", "matching_cluster_idx": 11}, {"solution": "def amicable_numbers_sum(n):\n \"\"\"\n Function to calculate the sum of all amicable numbers up to a specified limit n.\n Amicable numbers are a pair of numbers each of which is the sum of the divisors of the other.\n \"\"\"\n def sum_of_divisors(x):\n \"\"\"Returns the sum of all proper divisors of x.\"\"\"\n divisors_sum = 1 # 1 is a proper divisor for all x > 1\n sqrt_x = int(x ** 0.5)\n for divisor in range(2, sqrt_x + 1):\n if x % divisor == 0:\n divisors_sum += divisor\n if divisor != x // divisor:\n divisors_sum += x // divisor\n return divisors_sum\n \n amicable_sum = 0\n for i in range(2, n):\n sum_div_i = sum_of_divisors(i)\n if sum_div_i > i and sum_div_i < n and sum_of_divisors(sum_div_i) == i:\n amicable_sum += i + sum_div_i\n \n return amicable_sum", "matching_cluster_idx": 11}, {"solution": "def amicable_numbers_sum(limit):\n \"\"\"\n Calculate the sum of all amicable numbers under the specified limit.\n \n An amicable pair consists of two integers for which the sum of proper divisors \n (excluding the number itself) of each is equal to the other number.\n \n Parameters:\n limit (int): The upper limit for identifying amicable numbers.\n \n Returns:\n int: The sum of all amicable numbers under the limit.\n \"\"\"\n \n def sum_of_divisors(n):\n \"\"\"Calculate sum of proper divisors of n.\"\"\"\n divisors_sum = 1 # Start with 1 as it's a divisor for all n > 1\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n divisors_sum += i\n if i != n // i: # Add the quotient only if it's not the square root\n divisors_sum += n // i\n return divisors_sum\n\n amicable_sum = 0\n for num in range(2, limit):\n partner = sum_of_divisors(num)\n if partner > num and num == sum_of_divisors(partner):\n amicable_sum += num + partner\n \n return amicable_sum", "matching_cluster_idx": 11}, {"solution": "def sum_of_divisors(n):\n # Calculate the sum of divisors for a given number\n result = 1\n i = 2\n while i * i <= n:\n count = 1\n current_sum = 1\n current_term = 1\n while n % i == 0:\n count += 1\n current_sum += current_term * i\n current_term *= i\n n //= i\n result *= current_sum\n i += 1\n if n != 1:\n result *= (1 + n)\n return result\ndef amicable_numbers_sum(number):\n # Sum all amicable numbers up to the specified number\n amicable_sum = 0\n for each in range(2, number):\n sum_divisors = sum_of_divisors(each) - each\n sum_divisors_of_sum = sum_of_divisors(sum_divisors) - sum_divisors\n if each == sum_divisors_of_sum and sum_divisors < each and sum_divisors != each:\n amicable_sum += each + sum_divisors\n return amicable_sum", "matching_cluster_idx": 11}, {"solution": "def sum_divisors(n):\n total = 1\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n total += i\n if i != n // i:\n total += n // i\n return total\ndef amicable_numbers_sum(max_num):\n \"\"\"\n This function finds the sum of all amicable numbers up to max_num.\n Amicable numbers are two different numbers so related that the sum of the proper divisors of each is equal to the other number.\n \n :param max_num: The upper limit of the range to check for amicable numbers.\n :return: The sum of all amicable numbers found.\n \"\"\"\n amicable_sum = 0\n for num in range(2, max_num):\n partner = sum_divisors(num)\n if partner > num and sum_divisors(partner) == num:\n amicable_sum += num + partner\n return amicable_sum", "matching_cluster_idx": 11}]}, "Mbpp/128": {"dps": 99.5475113122172, "dps_norm": 80.0, "pass@1": 100.0, "profiled": [{"solution": "def long_words(n, word_list):\n # Split the string into a list of words\n words = word_list.split()\n # Use list comprehension to filter words longer than n characters\n long_words_list = [word for word in words if len(word) > n]\n return long_words_list", "matching_cluster_idx": 3}, {"solution": "def long_words(n, s):\n # Split the string into words and filter out those shorter than or equal to n\n result = [word for word in s.split() if len(word) > n]\n return result", "matching_cluster_idx": 3}, {"solution": "def long_words(n, s):\n # Split the string into a list of words\n word_list = s.split()\n # Use list comprehension to filter words longer than n characters\n long_words_list = [word for word in word_list if len(word) > n]\n return long_words_list", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n # Split the sentence into words and filter based on length > n\n words = sentence.split()\n long_words_list = [word for word in words if len(word) > n]\n return long_words_list", "matching_cluster_idx": 3}, {"solution": "def long_words(n, s):\n # Split the string into words and filter based on length\n words = s.split()\n long_words_list = [word for word in words if len(word) > n]\n return long_words_list", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n # Split the sentence into words\n words = sentence.split()\n # Filter out words longer than n characters\n result = [word for word in words if len(word) > n]\n return result", "matching_cluster_idx": 3}, {"solution": "def long_words(n, string):\n # Split the string into words\n words = string.split()\n # Use list comprehension to filter words longer than n characters\n long_words_list = [word for word in words if len(word) > n]\n return long_words_list", "matching_cluster_idx": 3}, {"solution": "def long_words(n, s):\n # Split the string into words\n word_list = s.split()\n # Use list comprehension to filter words longer than n characters\n long_words_list = [word for word in word_list if len(word) > n]\n return long_words_list", "matching_cluster_idx": 3}, {"solution": "def long_words(n, s):\n # Split the string into words\n word_list = s.split()\n # Filter words that are longer than n characters\n result = [word for word in word_list if len(word) > n]\n return result", "matching_cluster_idx": 3}, {"solution": "def long_words(n, word_list):\n # Split the word_list string into a list of words\n words = word_list.split()\n # Use list comprehension to filter out words longer than n characters\n long_words_list = [word for word in words if len(word) > n]\n # Return the filtered list of words\n return long_words_list", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n # Split the sentence into words\n words = sentence.split()\n # Use list comprehension to filter words longer than n characters\n return [word for word in words if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, string):\n # Split the string into words\n words = string.split()\n # Filter words that are longer than n characters\n long_words_list = [word for word in words if len(word) > n]\n # Return the list of long words\n return long_words_list", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n # Split the sentence into words\n words = sentence.split()\n # Filter out words shorter than or equal to n characters\n result = [word for word in words if len(word) > n]\n return result", "matching_cluster_idx": 3}, {"solution": "def long_words(n, s):\n # Split the string into a list of words\n words = s.split()\n # Use list comprehension to find words longer than n characters\n long_words_list = [word for word in words if len(word) > n]\n return long_words_list", "matching_cluster_idx": 3}, {"solution": "def long_words(n, s):\n # Split the string into words\n words = s.split()\n \n # Use list comprehension to filter words longer than n\n long_words_list = [word for word in words if len(word) > n]\n \n return long_words_list", "matching_cluster_idx": 3}, {"solution": "def long_words(n, text):\n # Split the text into a list of words\n words = text.split()\n # Filter out words that are longer than n characters\n long_words_list = [word for word in words if len(word) > n]\n # Return the list of words longer than n\n return long_words_list", "matching_cluster_idx": 3}, {"solution": "def long_words(n, text):\n # Split the text into a list of words\n words = text.split()\n # Filter the words to keep only those longer than n characters\n long_words = [word for word in words if len(word) > n]\n return long_words", "matching_cluster_idx": 3}, {"solution": "def long_words(n, text):\n # Split the input string into words\n words = text.split()\n # Filter out words that are longer than n characters\n long_words_list = [word for word in words if len(word) > n]\n return long_words_list", "matching_cluster_idx": 3}, {"solution": "def long_words(n, text):\n # Split the text into words\n words = text.split()\n # Filter words that are longer than n characters\n result = [word for word in words if len(word) > n]\n return result", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n # Split the sentence into words\n words = sentence.split()\n # Use list comprehension to filter out words longer than n characters\n long_words_list = [word for word in words if len(word) > n]\n return long_words_list", "matching_cluster_idx": 3}]}, "Mbpp/129": {"dps": 89.84693877551021, "dps_norm": 98.66666666666667, "pass@1": 84.0, "profiled": [{"solution": "def magic_square_test(matrix):\n # Calculate the sum of the first row to use as a reference\n expected_sum = sum(matrix[0])\n \n # Check the sums of all rows\n for row in matrix:\n if sum(row) != expected_sum:\n return False\n \n # Check the sums of all columns\n for col in range(len(matrix)):\n if sum(matrix[row][col] for row in range(len(matrix))) != expected_sum:\n return False\n \n # Check the sum of the main diagonal\n if sum(matrix[i][i] for i in range(len(matrix))) != expected_sum:\n return False\n \n # Check the sum of the secondary diagonal\n if sum(matrix[i][len(matrix)-1-i] for i in range(len(matrix))) != expected_sum:\n return False\n \n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(mat):\n # Calculate the size of the matrix\n n = len(mat)\n \n # Calculate the sum of the first row to use as a reference\n magic_sum = sum(mat[0])\n \n # Check the sums of all rows\n for row in mat:\n if sum(row) != magic_sum:\n return False\n \n # Check the sums of all columns\n for col in range(n):\n if sum(mat[row][col] for row in range(n)) != magic_sum:\n return False\n \n # Check the sum of the main diagonal\n if sum(mat[i][i] for i in range(n)) != magic_sum:\n return False\n \n # Check the sum of the secondary diagonal\n if sum(mat[i][n - 1 - i] for i in range(n)) != magic_sum:\n return False\n \n # If all checks pass, it's a magic square\n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(mat):\n # Calculate the sum of the first row to define the target sum\n target_sum = sum(mat[0])\n \n # Check rows and columns\n for i in range(len(mat)):\n if sum(mat[i]) != target_sum or sum(mat[j][i] for j in range(len(mat))) != target_sum:\n return False\n \n # Check diagonals\n if sum(mat[i][i] for i in range(len(mat))) != target_sum or sum(mat[i][len(mat)-1-i] for i in range(len(mat))) != target_sum:\n return False\n\n return True", "matching_cluster_idx": 13}, {"solution": "def magic_square_test(matrix):\n # Calculate the sum of the first row to set as the benchmark\n target_sum = sum(matrix[0])\n \n # Check sum of each row\n for row in matrix:\n if sum(row) != target_sum:\n return False\n \n # Check sum of each column\n for col in range(len(matrix)):\n if sum(matrix[row][col] for row in range(len(matrix))) != target_sum:\n return False\n \n # Check sum of the main diagonal\n if sum(matrix[i][i] for i in range(len(matrix))) != target_sum:\n return False\n \n # Check sum of the secondary diagonal\n if sum(matrix[i][len(matrix)-1-i] for i in range(len(matrix))) != target_sum:\n return False\n \n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n # Calculate the sum of the first row to set as a reference\n magic_sum = sum(matrix[0])\n n = len(matrix)\n \n # Check rows and columns\n for i in range(n):\n if sum(matrix[i]) != magic_sum or sum(row[i] for row in matrix) != magic_sum:\n return False\n \n # Check diagonals\n if sum(matrix[i][i] for i in range(n)) != magic_sum or sum(matrix[i][n-i-1] for i in range(n)) != magic_sum:\n return False\n \n return True", "matching_cluster_idx": 13}, {"solution": "def magic_square_test(matrix):\n # Calculate the sum of the first row to set as the base sum\n base_sum = sum(matrix[0])\n \n # Check the sum of each row\n for row in matrix:\n if sum(row) != base_sum:\n return False\n \n # Check the sum of each column\n for col_idx in range(len(matrix[0])):\n col_sum = sum(row[col_idx] for row in matrix)\n if col_sum != base_sum:\n return False\n \n # Check the sum of the main diagonal\n main_diagonal_sum = sum(matrix[idx][idx] for idx in range(len(matrix)))\n if main_diagonal_sum != base_sum:\n return False\n \n # Check the sum of the secondary diagonal\n secondary_diagonal_sum = sum(matrix[idx][len(matrix)-1-idx] for idx in range(len(matrix)))\n if secondary_diagonal_sum != base_sum:\n return False\n \n # If all checks pass, it is a magic square\n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(mat):\n # Calculate the sum of the first row to set as the reference\n magic_sum = sum(mat[0])\n \n # Check the sums of all rows\n for row in mat:\n if sum(row) != magic_sum:\n return False\n \n # Check the sums of all columns\n for col in range(len(mat)):\n if sum(mat[row][col] for row in range(len(mat))) != magic_sum:\n return False\n \n # Check the sum of the main diagonal\n if sum(mat[i][i] for i in range(len(mat))) != magic_sum:\n return False\n \n # Check the sum of the secondary diagonal\n if sum(mat[i][len(mat)-1-i] for i in range(len(mat))) != magic_sum:\n return False\n \n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n # Calculate the sum of the first row to set as a benchmark\n magic_sum = sum(matrix[0])\n \n # Check sum of each row\n for row in matrix:\n if sum(row) != magic_sum:\n return False\n \n # Check sum of each column\n for col in range(len(matrix[0])):\n if sum(row[col] for row in matrix) != magic_sum:\n return False\n \n # Check sum of the main diagonal\n if sum(matrix[i][i] for i in range(len(matrix))) != magic_sum:\n return False\n \n # Check sum of the secondary diagonal\n if sum(matrix[i][len(matrix)-i-1] for i in range(len(matrix))) != magic_sum:\n return False\n \n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n # Extracting the size of the matrix\n n = len(matrix)\n \n # Creating a list of all row sums, column sums, and diagonal sums\n # Calculate the sum of the first row to use as a reference\n sum_first_row = sum(matrix[0])\n \n # Check row sums\n for row in matrix:\n if sum(row) != sum_first_row:\n return False\n \n # Check column sums\n for col in range(n):\n if sum(matrix[row][col] for row in range(n)) != sum_first_row:\n return False\n \n # Check diagonals sums\n if sum(matrix[i][i] for i in range(n)) != sum_first_row:\n return False\n if sum(matrix[i][n-1-i] for i in range(n)) != sum_first_row:\n return False\n \n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(mat):\n # Size of the matrix\n n = len(mat)\n \n # Calculate the sum of the first row to establish the target sum\n target_sum = sum(mat[0])\n\n # Check the sum of each row\n for row in mat:\n if sum(row) != target_sum:\n return False\n\n # Check the sum of each column\n for col in range(n):\n if sum(mat[row][col] for row in range(n)) != target_sum:\n return False\n\n # Check the sum of the main diagonal\n if sum(mat[i][i] for i in range(n)) != target_sum:\n return False\n\n # Check the sum of the secondary diagonal\n if sum(mat[i][n - 1 - i] for i in range(n)) != target_sum:\n return False\n\n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(mat):\n # Calculate the size of the matrix\n n = len(mat)\n \n # Calculate the sum of the first row to use as a reference\n magic_sum = sum(mat[0])\n \n # Check sums of rows\n for row in mat:\n if sum(row) != magic_sum:\n return False\n \n # Check sums of columns\n for col in range(n):\n if sum(mat[row][col] for row in range(n)) != magic_sum:\n return False\n \n # Check the sum of the main diagonal\n if sum(mat[i][i] for i in range(n)) != magic_sum:\n return False\n \n # Check the sum of the secondary diagonal\n if sum(mat[i][n-i-1] for i in range(n)) != magic_sum:\n return False\n \n # If all checks passed, it's a magic square\n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(mat):\n # Get the size of the matrix\n n = len(mat)\n \n # Calculate the sum of the first row to use as a reference\n magic_sum = sum(mat[0])\n \n # Check the sums of all rows\n for row in mat:\n if sum(row) != magic_sum:\n return False\n \n # Check the sums of all columns\n for col in range(n):\n if sum(mat[row][col] for row in range(n)) != magic_sum:\n return False\n \n # Check the sum of the main diagonal\n if sum(mat[i][i] for i in range(n)) != magic_sum:\n return False\n \n # Check the sum of the secondary diagonal\n if sum(mat[i][n - 1 - i] for i in range(n)) != magic_sum:\n return False\n \n # If all checks passed, it's a magic square\n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(mat):\n # Get the size of the matrix\n n = len(mat)\n \n # Calculate the sum of the first row to set as the magic constant\n magic_sum = sum(mat[0])\n \n # Check the sums of all rows\n for i in range(n):\n if sum(mat[i]) != magic_sum:\n return False\n \n # Check the sums of all columns\n for j in range(n):\n if sum(mat[i][j] for i in range(n)) != magic_sum:\n return False\n \n # Check the sum of the main diagonal\n if sum(mat[i][i] for i in range(n)) != magic_sum:\n return False\n \n # Check the sum of the secondary diagonal\n if sum(mat[i][n-i-1] for i in range(n)) != magic_sum:\n return False\n \n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(mat):\n # Sum of the first row to compare with other sums\n sum1 = sum(mat[0])\n \n n = len(mat)\n \n # Check sums of all rows\n for i in range(n):\n if sum(mat[i]) != sum1:\n return False\n \n # Check sums of all columns\n for i in range(n):\n col_sum = sum(row[i] for row in mat)\n if col_sum != sum1:\n return False\n \n # Check sum of the main diagonal\n main_diag_sum = sum(mat[i][i] for i in range(n))\n if main_diag_sum != sum1:\n return False\n \n # Check sum of the secondary diagonal\n sec_diag_sum = sum(mat[i][n-1-i] for i in range(n))\n if sec_diag_sum != sum1:\n return False\n \n # If all checks pass\n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(mat):\n # Sum of the first row to compare with other sums\n sum_check = sum(mat[0])\n \n # Check sum of each row\n for row in mat:\n if sum(row) != sum_check:\n return False\n \n # Check sum of each column\n for col in range(len(mat)):\n if sum(mat[row][col] for row in range(len(mat))) != sum_check:\n return False\n \n # Check sum of the main diagonal\n if sum(mat[i][i] for i in range(len(mat))) != sum_check:\n return False\n \n # Check sum of the secondary diagonal\n if sum(mat[i][len(mat)-1-i] for i in range(len(mat))) != sum_check:\n return False\n \n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(mat):\n # The size of the matrix (assuming it's a square matrix)\n size = len(mat)\n \n # Sum of the first row to compare with others\n target_sum = sum(mat[0])\n \n # Check all rows\n for row in mat:\n if sum(row) != target_sum:\n return False\n \n # Check all columns\n for col in range(size):\n if sum(mat[row][col] for row in range(size)) != target_sum:\n return False\n \n # Check the main diagonal\n if sum(mat[i][i] for i in range(size)) != target_sum:\n return False\n \n # Check the secondary diagonal\n if sum(mat[i][size - 1 - i] for i in range(size)) != target_sum:\n return False\n \n # If all checks passed\n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n # Calculate the size of the matrix (n x n)\n n = len(matrix)\n \n # Calculate the sum of the first row to establish the 'magic' constant\n magic_sum = sum(matrix[0])\n \n # Check rows and columns\n for i in range(n):\n if sum(matrix[i]) != magic_sum or sum(matrix[j][i] for j in range(n)) != magic_sum:\n return False\n \n # Check diagonals\n if sum(matrix[i][i] for i in range(n)) != magic_sum or sum(matrix[i][n-i-1] for i in range(n)) != magic_sum:\n return False\n \n return True", "matching_cluster_idx": 13}, {"solution": "def magic_square_test(mat):\n # Calculate the sum of the first row to set as the reference\n magic_sum = sum(mat[0])\n \n # Check sum of each row\n for row in mat:\n if sum(row) != magic_sum:\n return False\n \n # Check sum of each column\n for col in range(len(mat)):\n if sum(row[col] for row in mat) != magic_sum:\n return False\n \n # Check sum of the main diagonal\n if sum(mat[i][i] for i in range(len(mat))) != magic_sum:\n return False\n \n # Check sum of the secondary diagonal\n if sum(mat[i][len(mat)-1-i] for i in range(len(mat))) != magic_sum:\n return False\n \n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(mat):\n # Get the size of the matrix (n x n)\n n = len(mat)\n \n # Calculate the sum of the first row to use as a reference sum\n target_sum = sum(mat[0])\n \n # Check sum of each row\n for row in mat:\n if sum(row) != target_sum:\n return False\n \n # Check sum of each column\n for col in range(n):\n if sum(mat[row][col] for row in range(n)) != target_sum:\n return False\n \n # Check sum of the main diagonal\n if sum(mat[i][i] for i in range(n)) != target_sum:\n return False\n \n # Check sum of the secondary diagonal\n if sum(mat[i][n-1-i] for i in range(n)) != target_sum:\n return False\n \n # If all checks pass, the matrix is a magic square\n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(mat):\n # Function to calculate the sum of each row, column, or diagonal\n def calculate_sum(data):\n return sum(data)\n \n size = len(mat)\n if size == 0:\n return False\n\n # Calculating the sum of the first row to set as a reference\n magic_sum = calculate_sum(mat[0])\n \n # Check rows and columns\n for i in range(size):\n if calculate_sum(mat[i]) != magic_sum or calculate_sum(row[i] for row in mat) != magic_sum:\n return False\n \n # Check diagonals\n if calculate_sum(mat[i][i] for i in range(size)) != magic_sum:\n return False\n if calculate_sum(mat[i][size - 1 - i] for i in range(size)) != magic_sum:\n return False\n \n return True", "matching_cluster_idx": 13}]}, "Mbpp/130": {"dps": 81.99551569506727, "dps_norm": 71.66666666666667, "pass@1": 97.0, "profiled": [{"solution": "def max_occurrences(lst):\n # Create a dictionary to keep count of each item's frequency\n frequency_dict = {}\n \n # Iterate through the list to populate the frequency dictionary\n for item in lst:\n if item in frequency_dict:\n frequency_dict[item] += 1\n else:\n frequency_dict[item] = 1\n \n # Find the item with the maximum frequency\n max_frequency_item = max(frequency_dict, key=frequency_dict.get)\n return max_frequency_item", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(lst):\n # Dictionary to keep track of occurrences of each element\n occurrences = {}\n for item in lst:\n if item in occurrences:\n occurrences[item] += 1\n else:\n occurrences[item] = 1\n \n # Finding the item with the maximum occurrences\n max_item = lst[0]\n max_count = occurrences[max_item]\n for item in occurrences:\n if occurrences[item] > max_count:\n max_item = item\n max_count = occurrences[item]\n \n return max_item", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(lst):\n # Dictionary to keep the count of each element\n frequency = {}\n for item in lst:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n \n # Finding the element with maximum frequency\n max_freq_item = None\n max_freq = 0\n for item, count in frequency.items():\n if count > max_freq:\n max_freq = count\n max_freq_item = item\n \n return max_freq_item", "matching_cluster_idx": 3}, {"solution": "from collections import Counter\ndef max_occurrences(lst):\n # Count the frequency of each element\n frequency = Counter(lst)\n # Find the maximum frequency\n max_freq = max(frequency.values())\n # Find the item(s) with the maximum frequency\n max_items = [item for item, count in frequency.items() if count == max_freq]\n # Assuming there's at least one item with the maximum frequency, return one\n return max_items[0]", "matching_cluster_idx": 4}, {"solution": "def max_occurrences(lst):\n # Dictionary to count occurrences of each element\n frequency = {}\n for item in lst:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n \n # Find the item with maximum frequency\n max_freq_item = None\n max_freq_count = 0\n for item, count in frequency.items():\n if count > max_freq_count:\n max_freq_count = count\n max_freq_item = item\n \n return max_freq_item", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(lst):\n # Create a dictionary to count frequency of each item\n frequency_dict = {}\n for item in lst:\n if item in frequency_dict:\n frequency_dict[item] += 1\n else:\n frequency_dict[item] = 1\n \n # Find the item with the maximum frequency\n max_item = lst[0]\n max_count = 1\n for key, value in frequency_dict.items():\n if value > max_count:\n max_count = value\n max_item = key\n \n return max_item", "matching_cluster_idx": 3}, {"solution": "from collections import Counter\ndef max_occurrences(lst):\n # Count the frequency of each item in the list\n freq_counter = Counter(lst)\n # Find the item with the maximum frequency\n max_freq_item = freq_counter.most_common(1)[0][0]\n return max_freq_item", "matching_cluster_idx": 4}, {"solution": "from collections import defaultdict\ndef max_occurrences(lst):\n # Create a dictionary to keep track of frequency\n frequency = defaultdict(int)\n \n # Iterate over the list to populate the frequency dictionary\n for item in lst:\n frequency[item] += 1\n \n # Find the item with the maximum frequency\n max_item = max(frequency, key=frequency.get)\n \n return max_item", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(lst):\n # Dictionary to store the frequency of each element\n frequency_dict = {}\n \n # Calculate the frequency of each element\n for item in lst:\n if item in frequency_dict:\n frequency_dict[item] += 1\n else:\n frequency_dict[item] = 1\n \n # Find the item with the maximum frequency\n max_item = lst[0]\n max_count = frequency_dict[max_item]\n for item, count in frequency_dict.items():\n if count > max_count:\n max_count = count\n max_item = item\n \n return max_item", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(lst):\n # Create a dictionary to keep track of occurrences\n frequency_dict = {}\n \n # Iterate through the list to populate the dictionary with frequencies\n for item in lst:\n if item in frequency_dict:\n frequency_dict[item] += 1\n else:\n frequency_dict[item] = 1\n \n # Find the item with the maximum occurrence in the dictionary\n max_freq_item = max(frequency_dict, key=frequency_dict.get)\n \n return max_freq_item", "matching_cluster_idx": 3}, {"solution": "from collections import Counter\ndef max_occurrences(lst):\n \"\"\"\n Finds the item with the maximum frequency in the given list.\n \n If there are multiple items with the same maximum frequency, it returns\n the first one encountered.\n \n Parameters:\n lst (list): The list to check for frequency of items.\n \n Returns:\n int: The item with the highest frequency.\n \"\"\"\n # Count the frequency of each item in the list\n frequency_counter = Counter(lst)\n # Find the item with maximum frequency\n max_freq_item = max(frequency_counter, key=frequency_counter.get)\n return max_freq_item", "matching_cluster_idx": 4}, {"solution": "def max_occurrences(lst):\n # Dictionary to keep track of occurrences of each element\n occurrences = {}\n for item in lst:\n if item in occurrences:\n occurrences[item] += 1\n else:\n occurrences[item] = 1\n \n # Initialize variables to track the max frequency and corresponding item\n max_freq = 0\n max_item = None\n \n # Iterate through occurrences to find the item with max frequency\n for item, freq in occurrences.items():\n if freq > max_freq:\n max_freq = freq\n max_item = item\n \n return max_item", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(lst):\n # Dictionary to hold frequency of each item\n frequency_dict = {}\n \n # Populate the dictionary with frequencies\n for item in lst:\n if item in frequency_dict:\n frequency_dict[item] += 1\n else:\n frequency_dict[item] = 1\n \n # Finding the item with maximum occurrences\n max_item = None\n max_count = 0\n for item, count in frequency_dict.items():\n if count > max_count:\n max_count = count\n max_item = item\n \n return max_item", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(lst):\n # Dictionary to count occurrences\n occurrences = {}\n \n # Counting occurrences of each element\n for item in lst:\n if item in occurrences:\n occurrences[item] += 1\n else:\n occurrences[item] = 1\n \n # Finding the element with maximum occurrence\n max_occurrence = 0\n max_element = None\n for key, value in occurrences.items():\n if value > max_occurrence:\n max_occurrence = value\n max_element = key\n \n return max_element", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(lst):\n # Initialize a dictionary to store the frequency of each item\n freq_dict = {}\n for item in lst:\n if item in freq_dict:\n freq_dict[item] += 1\n else:\n freq_dict[item] = 1\n \n # Find the item with the maximum frequency\n max_freq_item = None\n max_freq = 0\n for item, freq in freq_dict.items():\n if freq > max_freq:\n max_freq = freq\n max_freq_item = item\n \n return max_freq_item", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(lst):\n # Dictionary to store the frequency of each item\n frequency_dict = {}\n \n # Iterate over each item in the list and count occurrences\n for item in lst:\n if item in frequency_dict:\n frequency_dict[item] += 1\n else:\n frequency_dict[item] = 1\n \n # Initialize variables to track the item with maximum frequency\n max_item = lst[0]\n max_count = frequency_dict[max_item]\n \n # Iterate over frequency_dict to find the item with the maximum count\n for item, count in frequency_dict.items():\n if count > max_count:\n max_count = count\n max_item = item\n \n return max_item", "matching_cluster_idx": 3}, {"solution": "from collections import Counter\ndef max_occurrences(lst):\n # Using Counter to count occurrences of each element\n count = Counter(lst)\n # Finding the element with maximum frequency\n max_freq = max(count.values())\n # Getting all elements with the maximum frequency\n max_elements = [k for k, v in count.items() if v == max_freq]\n # Return the first element with the highest frequency\n return max_elements[0]", "matching_cluster_idx": 4}, {"solution": "from collections import Counter\ndef max_occurrences(lst):\n # Count the occurrences of each element in the list\n occurrences = Counter(lst)\n # Find the element with the maximum occurrences\n max_occurrence_value = max(occurrences.values())\n # Get all items with maximum occurrences\n max_occurrence_items = [item for item, count in occurrences.items() if count == max_occurrence_value]\n # If there is a tie, return the first element from the list\n return max_occurrence_items[0]", "matching_cluster_idx": 4}, {"solution": "def max_occurrences(lst):\n # Initialize a dictionary to hold the frequency of elements\n frequency_dict = {}\n # Iterate over each element in the list\n for element in lst:\n # If the element is already in the dictionary, increment its count\n if element in frequency_dict:\n frequency_dict[element] += 1\n else:\n # Otherwise, initialize its count to 1\n frequency_dict[element] = 1\n \n # Find the element with the maximum frequency\n max_freq_item = max(frequency_dict, key=frequency_dict.get)\n return max_freq_item", "matching_cluster_idx": 3}, {"solution": "from collections import Counter\ndef max_occurrences(lst):\n # Use Counter to count the occurrences of each item in the list\n count = Counter(lst)\n # Find the item with the maximum occurrence\n max_item = max(count, key=count.get)\n return max_item", "matching_cluster_idx": 4}]}, "Mbpp/137": {"dps": 99.99999999999999, "dps_norm": 100.0, "pass@1": 86.0, "profiled": [{"solution": "import math\ndef zero_count(arr):\n \"\"\"\n This function calculates the ratio of zeroes to non-zeroes in an array of integers.\n \n :param arr: List[int] - A list of integers.\n :return: float - The ratio of zeroes to non-zeroes.\n \"\"\"\n zero_count = arr.count(0)\n non_zero_count = len(arr) - zero_count\n return zero_count / non_zero_count if non_zero_count != 0 else float('inf')", "matching_cluster_idx": 7}, {"solution": "import math\ndef zero_count(arr):\n \"\"\"\n Calculates the ratio of zeroes to non-zeroes in an array of integers.\n\n :param arr: List[int] - an array of integers\n :return: float - ratio of zeroes to non-zeroes\n \"\"\"\n zero_count = arr.count(0)\n non_zero_count = len(arr) - zero_count\n if non_zero_count == 0:\n return float('inf') # Return infinity if there are no non-zero elements\n return zero_count / non_zero_count", "matching_cluster_idx": 7}, {"solution": "import math\ndef zero_count(arr):\n \"\"\"\n This function takes an array of integers as input and returns the ratio of zeroes to non-zeroes.\n \n Parameters:\n arr (list): List of integers.\n \n Returns:\n float: Ratio of zeroes to non-zeroes.\n \"\"\"\n num_zeros = arr.count(0)\n num_non_zeros = len(arr) - num_zeros\n if num_non_zeros == 0:\n return float('inf')\n ratio = num_zeros / num_non_zeros\n return ratio", "matching_cluster_idx": 7}, {"solution": "import math\ndef zero_count(arr):\n \"\"\"\n Calculates the ratio of zeroes to non-zeroes in an array of integers.\n\n :param arr: List[int], the input array of integers.\n :return: float, the ratio of zeroes to non-zeroes in the array.\n \"\"\"\n num_zeros = arr.count(0)\n num_non_zeros = len(arr) - num_zeros\n \n # Avoid division by zero if there are no non-zero numbers\n if num_non_zeros == 0:\n return float('inf') if num_zeros > 0 else 0\n \n return num_zeros / num_non_zeros", "matching_cluster_idx": 7}, {"solution": "import math\ndef zero_count(arr):\n \"\"\"\n Calculates the ratio of zeroes to non-zeroes in an array of integers.\n\n :param arr: List of integers\n :return: Ratio of zeroes to non-zeroes as a float.\n \"\"\"\n zeroes = arr.count(0)\n non_zeroes = len(arr) - zeroes\n if non_zeroes == 0:\n return float('inf') # If there are no non-zeroes, return infinity\n return zeroes / non_zeroes", "matching_cluster_idx": 7}, {"solution": "import math\ndef zero_count(arr):\n \"\"\"\n Calculate the ratio of zeroes to non-zeroes in an array of integers.\n\n :param arr: List of integers\n :return: The ratio of zeroes to non-zeroes as a float.\n \"\"\"\n zero_count = arr.count(0)\n non_zero_count = len(arr) - zero_count\n if non_zero_count == 0:\n return float('inf') # Avoid division by zero\n return zero_count / non_zero_count", "matching_cluster_idx": 7}, {"solution": "import math\ndef zero_count(arr):\n \"\"\"\n This function calculates the ratio of zeroes to non-zeroes in an array of integers.\n \n Parameters:\n arr (list): A list of integers.\n\n Returns:\n float: The ratio of zeroes to non-zeroes in the array.\n \"\"\"\n zero_count = arr.count(0)\n non_zero_count = len(arr) - zero_count\n \n if non_zero_count == 0:\n return float('inf') # If there are no non-zero elements, return infinity\n \n ratio = zero_count / non_zero_count\n return ratio", "matching_cluster_idx": 7}, {"solution": "import math\ndef zero_count(arr):\n \"\"\"\n This function calculates the ratio of zeroes to non-zeroes in an array of integers.\n \n Parameters:\n arr (list of int): The array of integers.\n \n Returns:\n float: The ratio of zeroes to non-zeroes.\n \"\"\"\n zero_count = arr.count(0)\n non_zero_count = len(arr) - zero_count\n \n # Avoid division by zero\n if non_zero_count == 0:\n return float('inf')\n \n return zero_count / non_zero_count", "matching_cluster_idx": 7}, {"solution": "import math\ndef zero_count(arr):\n \"\"\"\n Calculate the ratio of zeroes to non-zeroes in an array of integers.\n\n :param arr: List[int] - the input array of integers\n :return: float - the ratio of zeroes to non-zeroes\n \"\"\"\n zero_count = arr.count(0)\n non_zero_count = len(arr) - zero_count\n if non_zero_count == 0:\n return float('inf') # to avoid division by zero\n return zero_count / non_zero_count", "matching_cluster_idx": 7}, {"solution": "import math\ndef zero_count(arr):\n \"\"\"\n Calculates the ratio of zeroes to non-zeroes in an array of integers.\n\n Parameters:\n arr (list of int): The input array of integers.\n\n Returns:\n float: The ratio of zeroes to non-zeroes.\n \"\"\"\n zero_count = arr.count(0)\n non_zero_count = len(arr) - zero_count\n if non_zero_count == 0:\n return float('inf') # Return infinity if there are no non-zero elements\n return zero_count / non_zero_count", "matching_cluster_idx": 7}, {"solution": "import math\ndef zero_count(arr):\n \"\"\"\n This function takes an array of integers and returns the ratio of zeroes to non-zeroes.\n \n :param arr: List[int] - a list of integers\n :return: float - the ratio of zeroes to non-zeroes\n \"\"\"\n zero_count = arr.count(0)\n non_zero_count = len(arr) - zero_count\n if non_zero_count == 0:\n return float('inf') # If there are no non-zeroes, ratio should be infinite\n return zero_count / non_zero_count", "matching_cluster_idx": 7}, {"solution": "import math\ndef zero_count(arr):\n \"\"\"\n Calculates the ratio of zeroes to non-zeroes in an array of integers.\n\n :param arr: List[int], a list of integers.\n :return: float, ratio of zeroes to non-zeroes.\n \"\"\"\n zero_count = arr.count(0)\n non_zero_count = len(arr) - zero_count\n if non_zero_count == 0:\n return float('inf') # If there are no non-zero elements, the ratio tends to infinity\n return zero_count / non_zero_count", "matching_cluster_idx": 7}, {"solution": "import math\ndef zero_count(arr):\n \"\"\"\n This function calculates the ratio of zeroes to non-zeroes in an array of integers.\n \n :param arr: List of integers\n :return: Ratio of zeroes to non-zeroes as a float\n \"\"\"\n zero_count = arr.count(0)\n non_zero_count = len(arr) - zero_count\n ratio = zero_count / non_zero_count if non_zero_count != 0 else float('inf')\n return ratio", "matching_cluster_idx": 7}, {"solution": "import math\ndef zero_count(arr):\n \"\"\"\n This function takes an array of integers as input and returns the ratio of zeroes to non-zeroes.\n \n :param arr: List of integers\n :return: Ratio of zeroes to non-zeroes as a float.\n \"\"\"\n zero_count = arr.count(0)\n non_zero_count = len(arr) - zero_count\n if non_zero_count == 0:\n return float('inf') # Return infinity if all elements are zeroes to avoid division by zero.\n return zero_count / non_zero_count", "matching_cluster_idx": 7}, {"solution": "import math\ndef zero_count(arr):\n \"\"\"\n Function to calculate the ratio of zeroes to non-zeroes in an array.\n \n Parameters:\n arr (list): List of integers.\n \n Returns:\n float: Ratio of zeroes to non-zeroes.\n \"\"\"\n zero_count = arr.count(0)\n non_zero_count = len(arr) - zero_count\n return zero_count / non_zero_count if non_zero_count != 0 else float('inf')", "matching_cluster_idx": 7}, {"solution": "import math\ndef zero_count(arr):\n \"\"\"\n Calculate the ratio of zeroes to non-zeroes in an array of integers.\n\n :param arr: List of integers\n :return: Ratio of zeroes to non-zeroes as a float\n \"\"\"\n zero_count = arr.count(0)\n non_zero_count = len(arr) - zero_count\n if non_zero_count == 0:\n return float('inf') # If there are no non-zeroes, the ratio is infinite\n return zero_count / non_zero_count", "matching_cluster_idx": 7}, {"solution": "import math\ndef zero_count(arr):\n # Count the number of zeroes\n zero_count = arr.count(0)\n \n # Count the number of non-zero elements\n non_zero_count = len(arr) - zero_count\n \n # Calculate the ratio of zeroes to non-zeroes\n ratio = zero_count / non_zero_count if non_zero_count != 0 else float('inf')\n \n return ratio", "matching_cluster_idx": 7}, {"solution": "import math\ndef zero_count(arr):\n \"\"\"\n This function takes an array of integers and returns the ratio of zeroes to non-zeroes.\n \n :param arr: List of integers\n :return: Ratio of zeroes to non-zeroes as a float\n \"\"\"\n zero_count = arr.count(0)\n non_zero_count = len(arr) - zero_count\n # Avoid division by zero if there are no non-zero elements\n if non_zero_count == 0:\n return float('inf') # or some other appropriate value to indicate this case\n return zero_count / non_zero_count", "matching_cluster_idx": 7}, {"solution": "import math\ndef zero_count(arr):\n \"\"\"\n Calculates the ratio of zeroes to non-zeroes in an array of integers.\n \n Parameters:\n arr (list of int): The input array of integers.\n \n Returns:\n float: The ratio of zeroes to non-zeroes.\n \"\"\"\n zero_count = arr.count(0)\n non_zero_count = len(arr) - zero_count\n \n # To avoid division by zero, we check if there are any non-zeroes.\n if non_zero_count == 0:\n return float('inf') # Infinite ratio if no non-zero elements are present\n \n return zero_count / non_zero_count", "matching_cluster_idx": 7}, {"solution": "import math\ndef zero_count(arr):\n \"\"\"\n Calculates the ratio of zeroes to non-zeroes in the array of integers.\n \n Parameters:\n arr (list): List of integers\n \n Returns:\n float: The ratio of zeroes to non-zeroes.\n \"\"\"\n zero_count = arr.count(0)\n non_zero_count = len(arr) - zero_count\n if non_zero_count == 0:\n return float('inf') # if all elements are zero, ratio is infinite\n return zero_count / non_zero_count", "matching_cluster_idx": 7}]}, "Mbpp/140": {"dps": 79.17701863354037, "dps_norm": 78.75, "pass@1": 100.0, "profiled": [{"solution": "def extract_singly(list_of_tuples):\n # Flatten the list of tuples and convert to a set\n flattened_set = set(number for sublist in list_of_tuples for number in sublist)\n return flattened_set", "matching_cluster_idx": 4}, {"solution": "def extract_singly(lst):\n # Flatten the list of tuples and convert to a set\n result = {item for sublist in lst for item in sublist}\n return result", "matching_cluster_idx": 5}, {"solution": "def extract_singly(input_list):\n # Flatten the list of tuples into a single set\n result_set = set()\n for item in input_list:\n result_set.update(item)\n return list(result_set)", "matching_cluster_idx": 6}, {"solution": "def extract_singly(list_of_tuples):\n # Flatten the list of tuples into a single set\n return {item for sublist in list_of_tuples for item in sublist}", "matching_cluster_idx": 5}, {"solution": "def extract_singly(list_of_tuples):\n # Flatten the list of tuples into a set to remove duplicates\n flat_set = set(num for tup in list_of_tuples for num in tup)\n return flat_set", "matching_cluster_idx": 5}, {"solution": "def extract_singly(input_list):\n # Flatten the list of tuples into a single set\n result_set = set()\n for item in input_list:\n result_set.update(item)\n return list(result_set)", "matching_cluster_idx": 6}, {"solution": "def extract_singly(list_of_tuples):\n # Flatten the list of tuples into a set of elements\n flattened_set = {element for sublist in list_of_tuples for element in sublist}\n return flattened_set", "matching_cluster_idx": 5}, {"solution": "def extract_singly(lst):\n # Create a set from the flattened list of lists\n result_set = set()\n for sublist in lst:\n for item in sublist:\n result_set.add(item)\n return result_set", "matching_cluster_idx": 4}, {"solution": "def extract_singly(input_list):\n # Flatten the list of tuples and convert to a set\n return {item for sublist in input_list for item in sublist}", "matching_cluster_idx": 5}, {"solution": "def extract_singly(nested_list):\n # Flatten the list of tuples and convert to a set\n result_set = set()\n for sublist in nested_list:\n for element in sublist:\n result_set.add(element)\n return list(result_set)", "matching_cluster_idx": 3}, {"solution": "def extract_singly(list_of_tuples):\n # Convert list of tuples to a set of unique elements\n unique_elements = set()\n for tup in list_of_tuples:\n unique_elements.update(tup)\n return list(unique_elements)", "matching_cluster_idx": 6}, {"solution": "def extract_singly(list_of_tuples):\n # Convert each tuple in the list to a set and combine them using union\n flattened_set = set()\n for tup in list_of_tuples:\n flattened_set.update(tup)\n return flattened_set", "matching_cluster_idx": 7}, {"solution": "def extract_singly(test_list):\n # Flatten the list of tuples and convert to a set to remove duplicates\n return set([ele for sub in test_list for ele in sub])", "matching_cluster_idx": 5}, {"solution": "def extract_singly(lst):\n # Flatten the list of tuples into a single list and then convert to a set\n return set([item for sublist in lst for item in sublist])", "matching_cluster_idx": 5}, {"solution": "def extract_singly(list_of_tuples):\n # Convert list of tuples into a single set containing all elements\n result_set = set()\n for tup in list_of_tuples:\n result_set.update(tup)\n return list(result_set)", "matching_cluster_idx": 6}, {"solution": "def extract_singly(list_of_tuples):\n # Initialize an empty set to store unique elements\n unique_elements = set()\n \n # Iterate over each tuple in the list\n for tup in list_of_tuples:\n # Update the set with elements of the current tuple\n unique_elements.update(tup)\n \n return unique_elements", "matching_cluster_idx": 6}, {"solution": "def extract_singly(list_of_tuples):\n # Flatten the list of tuples into a single set\n flattened_set = set()\n for tuple_ in list_of_tuples:\n flattened_set.update(tuple_)\n return list(flattened_set)", "matching_cluster_idx": 6}, {"solution": "def extract_singly(list_of_tuples):\n # Flatten the list of tuples into a set\n result_set = set()\n for tup in list_of_tuples:\n result_set.update(tup)\n return result_set", "matching_cluster_idx": 7}, {"solution": "def extract_singly(lst_of_lsts):\n # Flatten the list of tuples into a set\n flat_set = {item for sublist in lst_of_lsts for item in sublist}\n return flat_set", "matching_cluster_idx": 5}, {"solution": "def extract_singly(tuples_list):\n # Flatten the list of tuples and convert to a set\n result_set = {item for sublist in tuples_list for item in sublist}\n return result_set", "matching_cluster_idx": 5}]}, "Mbpp/141": {"dps": 68.63945578231294, "dps_norm": 41.875, "pass@1": 83.0, "profiled": [{"solution": "def pancake_sort(arr):\n \"\"\"\n Sorts an array using the pancake sorting algorithm.\n\n Pancake sorting is a variation of the sorting problem in which the only allowed operation is to \n reverse the elements of some prefix of the sequence.\n\n Parameters:\n arr (list): The list of integers to be sorted.\n\n Returns:\n list: The sorted list.\n \"\"\"\n def flip(sub_list, i):\n \"\"\"Reverse the elements of the list up to index i\"\"\"\n start = 0\n while start < i:\n sub_list[start], sub_list[i] = sub_list[i], sub_list[start]\n start += 1\n i -= 1\n\n def find_max(sub_list, n):\n \"\"\"Find the index of the maximum element in sub_list up to n\"\"\"\n index = 0\n for j in range(n):\n if sub_list[j] > sub_list[index]:\n index = j\n return index\n \n n = len(arr)\n while n > 1:\n max_idx = find_max(arr, n)\n flip(arr, max_idx)\n flip(arr, n - 1)\n n -= 1\n\n return arr", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(arr):\n \"\"\"\n Sorts an array using the pancake sorting algorithm.\n \n Parameters:\n arr (list): The list to be sorted.\n \n Returns:\n list: The sorted list.\n \"\"\"\n def flip(sub_arr, i):\n \"\"\"Reverses the sublist from 0 to i of sub_arr.\"\"\"\n start = 0\n while start < i:\n sub_arr[start], sub_arr[i] = sub_arr[i], sub_arr[start]\n start += 1\n i -= 1\n\n curr_size = len(arr)\n while curr_size > 1:\n # Find the index of the maximum element in arr[0..curr_size-1]\n max_index = arr.index(max(arr[0:curr_size]))\n \n # Move the maximum element to the end of the current array if not already at the end\n if max_index != curr_size - 1:\n # Move it to the beginning if it's not already there\n if max_index != 0:\n flip(arr, max_index)\n # Move it to its final position\n flip(arr, curr_size - 1)\n \n # Reduce the current size of the array\n curr_size -= 1\n \n return arr", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(arr):\n def flip(sub_arr, i):\n start = 0\n while start < i:\n sub_arr[start], sub_arr[i] = sub_arr[i], sub_arr[start]\n start += 1\n i -= 1\n\n def find_max_index(arr, n):\n idx = 0\n for i in range(n):\n if arr[i] > arr[idx]:\n idx = i\n return idx\n\n n = len(arr)\n while n > 1:\n max_idx = find_max_index(arr, n)\n flip(arr, max_idx)\n flip(arr, n - 1)\n n -= 1\n\n return arr", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(arr):\n \"\"\"\n Sorts an array using the Pancake Sort algorithm.\n \n This function flips the largest unsorted element to the beginning of the array,\n then flips it to its correct position at the end of the unsorted section.\n This process is repeated until the entire array is sorted.\n \n :param arr: List of elements to be sorted.\n :return: Sorted list.\n \"\"\"\n def flip(sub_arr, i):\n \"\"\"Reverses the first i elements of the list sub_arr.\"\"\"\n start = 0\n while start < i:\n sub_arr[start], sub_arr[i] = sub_arr[i], sub_arr[start]\n start += 1\n i -= 1\n \n n = len(arr)\n for size in range(n, 1, -1):\n # Find the index of the maximum element in the unsorted part of arr\n max_index = arr.index(max(arr[:size]))\n if max_index + 1 != size:\n # Flip the largest unsorted element to the start if it's not already there\n if max_index != 0:\n flip(arr, max_index)\n # Flip it to its sorted position\n flip(arr, size - 1)\n return arr", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(arr):\n \"\"\"\n Perform pancake sort on the given list.\n \n Pancake sorting is the colloquial term for the mathematical problem of sorting a disordered stack of pancakes \n in order of size when a spatula can be inserted at any point in the stack and used to flip all pancakes above it. \n A pancake number is the minimum number of flips required for a given number of pancakes. The problem was first posed \n by Bill Gates and Christos Papadimitriou.\n \n :param arr: List of integers to be sorted.\n :return: Sorted list of integers.\n \"\"\"\n n = len(arr)\n\n while n > 1:\n # Find the index of the maximum element\n max_idx = arr.index(max(arr[0:n]))\n \n if max_idx != n - 1:\n # Flip the array from 0 to max_idx\n arr = arr[:max_idx+1][::-1] + arr[max_idx+1:]\n # Flip the entire array to move the maximum element to its correct position\n arr = arr[:n][::-1] + arr[n:]\n \n n -= 1\n\n return arr", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(arr):\n \"\"\"\n Sorts an array using the pancake sorting algorithm.\n \n Parameters:\n arr (list): The list of integers to sort.\n \n Returns:\n list: The sorted list of integers.\n \"\"\"\n \n def flip(sub_arr, i):\n \"\"\"Flip the sub-array from 0 to i.\"\"\"\n start = 0\n while start < i:\n sub_arr[start], sub_arr[i] = sub_arr[i], sub_arr[start]\n start += 1\n i -= 1\n \n n = len(arr)\n while n > 1:\n # Find index of the maximum element in arr[0:n]\n max_index = arr.index(max(arr[0:n]))\n \n # Move the maximum element to the end of the current array if it's not already there\n if max_index != n - 1:\n # Flip the array up to the max index\n flip(arr, max_index)\n # Flip the entire array to move the max element to the end\n flip(arr, n - 1)\n \n # Reduce n by 1 since the last element is now sorted\n n -= 1\n \n return arr", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(arr):\n \"\"\"\n Sort an array by repeatedly flipping sublists, similar to sorting a stack of pancakes.\n \n :param arr: List of integers to be sorted\n :return: Sorted list of integers\n \"\"\"\n def flip(sub_list, i):\n \"\"\"Flip (reverse) the sublist from start to index i.\"\"\"\n start = 0\n while start < i:\n sub_list[start], sub_list[i] = sub_list[i], sub_list[start]\n start += 1\n i -= 1\n\n cur = len(arr)\n while cur > 1:\n # Find the index of the maximum element in the remaining sublist\n mi = arr.index(max(arr[0:cur]))\n # Flip the sublist so the maximum element goes to the start\n flip(arr, mi)\n # Flip the entire sublist so the maximum element goes to the end\n flip(arr, cur - 1)\n cur -= 1\n return arr", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(arr):\n \"\"\"\n Perform a pancake sort on the given list.\n \n :param arr: List to be sorted\n :return: The sorted list\n \"\"\"\n def flip(sublist, i):\n start = 0\n while start < i:\n sublist[start], sublist[i] = sublist[i], sublist[start]\n start += 1\n i -= 1\n\n n = len(arr)\n \n while n > 1:\n # Find the index of the maximum element in arr[0..n-1]\n max_index = arr.index(max(arr[0:n]))\n \n # Bring the maximum element to the beginning of the array\n flip(arr, max_index)\n \n # Now move the maximum element to its correct position\n flip(arr, n - 1)\n \n n -= 1\n \n return arr", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(arr):\n \"\"\"\n Sorts an array using the pancake sort algorithm.\n \n Pancake sorting involves flipping the elements of the array to move the largest element to its correct position.\n It works by iterating through the array from the last element to the first and finding the index of the maximum element\n within the current unsorted portion of the array. It then flips the array twice to move the maximum element to its\n correct position.\n \n :param arr: List of integers to be sorted.\n :return: The sorted list.\n \"\"\"\n def flip(sub_arr, i):\n start = 0\n while start < i:\n sub_arr[start], sub_arr[i] = sub_arr[i], sub_arr[start]\n start += 1\n i -= 1\n \n n = len(arr)\n while n > 1:\n max_index = arr.index(max(arr[0:n]))\n flip(arr, max_index)\n flip(arr, n - 1)\n n -= 1\n \n return arr", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(arr):\n \"\"\"\n Sort an array using the pancake sort algorithm.\n \n The function sorts an array of integers in ascending order using the\n pancake sort technique, which involves flipping parts of the list to \n move the largest (or smallest) unsorted element to its final position.\n\n :param arr: List of integers to be sorted.\n :return: The sorted list.\n \"\"\"\n def flip(sublist, k):\n \"\"\"\n Flip the elements of the sublist up to index k.\n\n :param sublist: The list to flip.\n :param k: The number of elements to flip.\n \"\"\"\n sublist[:k] = sublist[:k][::-1]\n \n n = len(arr)\n while n > 1:\n # Find index of maximum element in arr[0:n]\n max_idx = arr.index(max(arr[0:n]))\n # Move the maximum element to the end of the current array\n if max_idx != n - 1:\n # Flip the list from 0 to max_idx\n flip(arr, max_idx + 1)\n # Flip the entire list to move the maximum element to the end\n flip(arr, n)\n n -= 1\n return arr", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(arr):\n \"\"\"\n Sort a list of elements using pancake sort algorithm.\n \"\"\"\n def flip(sub_arr, i):\n \"\"\"Flip the sub-array from start to i.\"\"\"\n start = 0\n while start < i:\n sub_arr[start], sub_arr[i] = sub_arr[i], sub_arr[start]\n start += 1\n i -= 1\n\n n = len(arr)\n while n > 1:\n # Find the index of the maximum element in arr[0...n-1]\n max_idx = arr.index(max(arr[0:n]))\n # Move the maximum element to the end of the array\n if max_idx != n-1:\n # Flip the array from 0 to max_idx\n flip(arr, max_idx)\n # Flip the entire array to move the maximum number to the end\n flip(arr, n-1)\n n -= 1\n return arr", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(arr):\n \"\"\"\n Sorts an array using the pancake sorting algorithm.\n \n Parameters:\n arr (list): The input list to be sorted.\n \n Returns:\n list: The sorted list.\n \"\"\"\n def flip(sublist, i):\n \"\"\"Helper function to flip the sublist from 0 to i.\"\"\"\n start = 0\n while start < i:\n sublist[start], sublist[i] = sublist[i], sublist[start]\n start += 1\n i -= 1\n \n n = len(arr)\n while n > 1:\n # Find index of the maximum element in arr[0...n-1]\n max_idx = arr.index(max(arr[0:n]))\n \n # Move the maximum element to end of current array if it's not already at the end\n if max_idx != n - 1:\n # Flip the array from 0 to max_idx\n flip(arr, max_idx)\n # Flip the entire array to move max element at the end\n flip(arr, n - 1)\n n -= 1\n return arr", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(arr):\n \"\"\"\n Sort an array using the Pancake Sort algorithm.\n \n The function sorts an array in ascending order by flipping sublists \n of the array. A flip means to reverse the order of the first k elements \n of the array, where k is a positive integer less than or equal to the length \n of the array.\n \n :param arr: List[int] - The array to be sorted.\n :return: List[int] - The sorted array.\n \"\"\"\n def flip(sub_list, k):\n \"\"\"\n Flip the first k elements of the sub_list.\n \n :param sub_list: List[int] - The sub-list to be flipped.\n :param k: int - The number of elements from the start to flip.\n \"\"\"\n i = 0\n while i < k // 2:\n sub_list[i], sub_list[k-i-1] = sub_list[k-i-1], sub_list[i]\n i += 1\n \n n = len(arr)\n while n > 1:\n # Find the index of the maximum element in the remaining sublist\n max_idx = arr.index(max(arr[0:n]))\n if max_idx != n - 1:\n # Flip the sublist to move the maximum element to the beginning\n flip(arr, max_idx+1)\n # Flip the entire sublist to move the maximum element to the end\n flip(arr, n)\n n -= 1\n return arr", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(arr):\n \"\"\"\n Sorts an array using the Pancake Sort algorithm.\n \n The function repeatedly finds the maximum element, flips the array at that element,\n and then flips the entire unsorted section of the array to move the maximum element\n to its correct position at the end of the array. This process is repeated until the\n array is sorted.\n \n Parameters:\n arr (list): The list of elements to be sorted.\n \n Returns:\n list: The sorted list.\n \"\"\"\n def flip(sublist, i):\n # Reverses the first i elements of the sublist\n sublist[:i] = sublist[:i][::-1]\n \n cur = len(arr)\n while cur > 1:\n # Find the index of the maximum element in arr[0:cur]\n mi = arr.index(max(arr[0:cur]))\n if mi != cur - 1:\n # Flip the maximum number to the beginning\n flip(arr, mi+1)\n # Flip it to its destination\n flip(arr, cur)\n cur -= 1\n return arr", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(arr):\n \"\"\"\n Sorts an array using the pancake sorting algorithm.\n \n Parameters:\n arr (list): The list of elements to be sorted.\n \n Returns:\n list: The sorted list.\n \"\"\"\n def flip(sub_list, i):\n \"\"\"Reverse elements in the list up to index i.\"\"\"\n sub_list[:i+1] = sub_list[:i+1][::-1]\n \n arr_len = len(arr)\n for size in range(arr_len, 1, -1):\n max_index = max(range(size), key=arr.__getitem__)\n if max_index+1 != size:\n # Move the maximum element to the beginning if it's not already there.\n if max_index != 0:\n flip(arr, max_index)\n # Move the maximum element to its correct position.\n flip(arr, size-1)\n return arr", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(arr):\n \"\"\"\n Sorts an array using the pancake sorting algorithm.\n This algorithm flips sublists of the array to move the largest element to its correct position.\n\n :param arr: List of elements to be sorted.\n :return: The sorted list.\n \"\"\"\n def flip(sub_arr, i):\n \"\"\"\n Reverses the elements of sub_arr up to index i.\n \n :param sub_arr: The sub-array to flip.\n :param i: The index up to which to flip.\n :return: The flipped sub-array up to i.\n \"\"\"\n start = 0\n while start < i:\n sub_arr[start], sub_arr[i] = sub_arr[i], sub_arr[start]\n start += 1\n i -= 1\n return sub_arr\n\n n = len(arr)\n\n while n > 1:\n # Find the index of the maximum element in arr[0..n-1]\n max_idx = arr.index(max(arr[0:n]))\n if max_idx != n - 1:\n # Flip the array from 0 to max_idx\n arr = flip(arr, max_idx)\n # Flip the entire array to move the max element to the end\n arr = flip(arr, n - 1)\n n -= 1\n\n return arr", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(arr):\n \"\"\"\n Sort the array using the pancake sort technique.\n \n :param arr: List of integers to be sorted\n :return: The sorted list of integers\n \"\"\"\n def flip(sublist, k):\n \"\"\"\n Reverse the first k elements of the sublist.\n \n :param sublist: The list to be flipped\n :param k: The index to which the sublist needs to be flipped\n \"\"\"\n i = 0\n while i < k // 2:\n sublist[i], sublist[k - i - 1] = sublist[k - i - 1], sublist[i]\n i += 1\n\n cur = len(arr)\n while cur > 1:\n # Find the index of the maximum element in arr[:cur]\n mi = arr.index(max(arr[0:cur]))\n if mi != cur - 1:\n # Flip arr[0:mi + 1] (to move max to the beginning)\n flip(arr, mi + 1)\n # Flip arr[0:cur] (to move max to its correct position)\n flip(arr, cur)\n cur -= 1\n return arr", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(arr):\n \"\"\"\n Sorts an array using the pancake sorting algorithm.\n \n :param arr: List of integers to be sorted.\n :return: The sorted list of integers.\n \"\"\"\n def flip(sublist, k):\n \"\"\"Helper function to reverse the first k elements of the sublist.\"\"\"\n sublist[:k] = sublist[:k][::-1]\n \n n = len(arr)\n while n > 1:\n # Find index of the maximum element in the list\n max_index = arr.index(max(arr[0:n]))\n \n # Move the maximum element to the beginning of the array\n flip(arr, max_index + 1)\n \n # Move the maximum element to its correct position at the end\n flip(arr, n)\n \n n -= 1\n return arr", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(arr):\n \"\"\"\n Sorts an array using the Pancake sorting algorithm.\n The function flips the elements of the array to sort it.\n \n :param arr: List of integers to be sorted.\n :return: The sorted list.\n \"\"\"\n def flip(sub_arr, i):\n \"\"\"Reverse elements in the list up to index i.\"\"\"\n sub_arr[:i+1] = sub_arr[:i+1][::-1]\n \n for size in range(len(arr), 1, -1):\n # Find the index of the maximum element in the remaining sublist\n max_index = arr.index(max(arr[:size]))\n \n # Move the maximum element to the beginning of the sublist if it's not already there\n if max_index != size - 1:\n # If the maximum is not at the beginning, flip it to the beginning\n if max_index != 0:\n flip(arr, max_index)\n # Flip it into its final position\n flip(arr, size - 1)\n return arr", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(arr):\n \"\"\"\n Sort the array using pancake sort algorithm.\n \n Pancake sorting is the colloquial term for the mathematical problem of sorting a disordered stack of pancakes in order of size when a spatula can be inserted at any point in the stack and used to flip all pancakes above it. A pancake number is the minimum number of flips required for a given number of pancakes. In this case, we are sorting a list of numbers.\n \"\"\"\n def flip(sublist, k):\n \"\"\"Flip the sublist from 0 to k.\"\"\"\n sublist[:k+1] = sublist[:k+1][::-1]\n \n def find_max(arr, n):\n \"\"\"Find the index of the maximum element in the first n elements of arr.\"\"\"\n return max(range(n), key=arr.__getitem__)\n \n cur_size = len(arr)\n while cur_size > 1:\n max_idx = find_max(arr, cur_size)\n if max_idx != cur_size - 1:\n # Flip the maximum number to the beginning if it's not already at the end.\n flip(arr, max_idx)\n # Flip it to the current position at the end.\n flip(arr, cur_size - 1)\n cur_size -= 1\n return arr", "matching_cluster_idx": 3}]}, "Mbpp/166": {"dps": 94.39999999999999, "dps_norm": 50.0, "pass@1": 100.0, "profiled": [{"solution": "def find_even_pair(nums):\n \"\"\"\n Counts the number of pairs of integers in the list that XOR to an even number.\n \n :param nums: List of integers\n :return: Count of pairs that XOR to an even number\n \"\"\"\n even_xor_count = 0\n for i in range(len(nums)):\n for j in range(i + 1, len(nums)):\n if (nums[i] ^ nums[j]) % 2 == 0:\n even_xor_count += 1\n return even_xor_count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(nums):\n # Initialize count of even XOR pairs\n even_xor_pairs = 0\n \n # Iterate through each possible pair in the list\n for i in range(len(nums)):\n for j in range(i + 1, len(nums)):\n # Calculate XOR of the pair\n xor_result = nums[i] ^ nums[j]\n # Check if XOR result is even\n if xor_result % 2 == 0:\n even_xor_pairs += 1\n \n return even_xor_pairs", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(nums):\n count = 0\n # Iterate through the list with two loops to check every pair\n for i in range(len(nums)):\n for j in range(i + 1, len(nums)):\n # If the XOR of the pair is even, increment count\n if (nums[i] ^ nums[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(nums):\n # Initialize the count to 0\n count = 0\n # Get the length of the list\n n = len(nums)\n \n # Iterate through the list to get all possible pairs\n for i in range(n):\n for j in range(i + 1, n):\n # If the XOR of the pair is even, increment the count\n if (nums[i] ^ nums[j]) % 2 == 0:\n count += 1\n \n # Return the total count of pairs with even XOR\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(lst):\n \"\"\"\n Count the number of pairs of integers in the list that XOR to an even number.\n \n :param lst: List of integers\n :return: Number of pairs that XOR to an even number\n \"\"\"\n even_pair_count = 0\n n = len(lst)\n # Iterate through the list to find pairs\n for i in range(n):\n for j in range(i + 1, n):\n # Check if the XOR of the pair is even\n if (lst[i] ^ lst[j]) % 2 == 0:\n even_pair_count += 1\n return even_pair_count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(lst):\n \"\"\"\n Counts the number of unique pairs in the list that XOR to an even number.\n \n :param lst: List of integers\n :return: Count of pairs that XOR to an even number\n \"\"\"\n even_count = 0\n # Iterate over each unique pair\n for i in range(len(lst)):\n for j in range(i + 1, len(lst)):\n # Check if xor is even\n if (lst[i] ^ lst[j]) % 2 == 0:\n even_count += 1\n return even_count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(arr):\n # Initialize the count of pairs\n count = 0\n # Iterate through the array to find pairs\n for i in range(len(arr)):\n for j in range(i + 1, len(arr)):\n # Check if the XOR of the pair is even\n if (arr[i] ^ arr[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(nums):\n even_pairs_count = 0\n n = len(nums)\n # Iterate through the list to find all pairs\n for i in range(n):\n for j in range(i + 1, n):\n # Check if the XOR of the pair is even\n if (nums[i] ^ nums[j]) % 2 == 0:\n even_pairs_count += 1\n return even_pairs_count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(nums):\n even_count = 0\n n = len(nums)\n \n # Iterate through each pair in the list\n for i in range(n):\n for j in range(i + 1, n):\n # Check if xor of the pair is even\n if (nums[i] ^ nums[j]) % 2 == 0:\n even_count += 1\n \n return even_count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(lst):\n # Initialize counter for pairs\n even_pair_count = 0\n \n # Iterate through the list to find pairs\n for i in range(len(lst)):\n for j in range(i + 1, len(lst)):\n # XOR the pair and check if the result is even\n if (lst[i] ^ lst[j]) % 2 == 0:\n even_pair_count += 1\n \n return even_pair_count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(nums):\n # Initialize the count of pairs\n count = 0\n # Iterate over the list to get the first element of the pair\n for i in range(len(nums)):\n # Iterate over the list to get the second element of the pair\n for j in range(i + 1, len(nums)):\n # Check if xor of the pair is even\n if (nums[i] ^ nums[j]) % 2 == 0:\n # Increment count if xor is even\n count += 1\n # Return the count of pairs with even xor\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(nums):\n # Initialize counter for pairs with even XOR\n even_xor_pairs = 0\n \n # Iterate through the list for the first element of the pair\n for i in range(len(nums)):\n # Iterate through the list for the second element of the pair\n for j in range(i + 1, len(nums)):\n # Check if the XOR of the pair is even\n if (nums[i] ^ nums[j]) % 2 == 0:\n # If true, increment the counter\n even_xor_pairs += 1\n \n # Return the total count of pairs with even XOR\n return even_xor_pairs", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(arr):\n # Initialize the counter for even XOR pairs\n even_xor_pairs = 0\n # Get the length of the list\n n = len(arr)\n # Loop through each element\n for i in range(n):\n for j in range(i + 1, n):\n # If the XOR of the pair is even, increment the counter\n if (arr[i] ^ arr[j]) % 2 == 0:\n even_xor_pairs += 1\n return even_xor_pairs", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(nums):\n # Initialize counter for even XOR pairs\n even_xor_pairs = 0\n \n # Iterate through each number in the list\n for i in range(len(nums)):\n for j in range(i + 1, len(nums)):\n # Check if the XOR of the pair is even\n if (nums[i] ^ nums[j]) % 2 == 0:\n even_xor_pairs += 1\n \n return even_xor_pairs", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(nums):\n # Initialize the count of pairs\n even_pair_count = 0\n \n # Iterate through the list to get all possible pairs\n for i in range(len(nums)):\n for j in range(i + 1, len(nums)):\n # Check if xor of the pair is even\n if (nums[i] ^ nums[j]) % 2 == 0:\n even_pair_count += 1\n \n return even_pair_count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(nums):\n even_count = 0\n n = len(nums)\n \n # Iterate through each possible pair in the list\n for i in range(n):\n for j in range(i + 1, n):\n # Check if the XOR of the pair is even\n if (nums[i] ^ nums[j]) % 2 == 0:\n even_count += 1\n \n return even_count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(nums):\n \"\"\"\n Counts the number of pairs of integers in the list nums that XOR to an even number.\n \n :param nums: List of integers\n :return: Count of pairs that XOR to an even number\n \"\"\"\n even_count = 0\n # Iterate through the list to get all possible pairs\n for i in range(len(nums)):\n for j in range(i + 1, len(nums)):\n # Check if XOR of the pair is even\n if (nums[i] ^ nums[j]) % 2 == 0:\n even_count += 1\n return even_count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(arr):\n # Initialize counter for pairs\n even_pairs_count = 0\n \n # Iterate through the array for all possible pairs\n for i in range(len(arr)):\n for j in range(i + 1, len(arr)):\n # XOR the pair and check if the result is even\n if (arr[i] ^ arr[j]) % 2 == 0:\n even_pairs_count += 1\n \n return even_pairs_count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(nums):\n # Initialize the count of pairs\n count = 0\n \n # Iterate over the list to get pairs\n for i in range(len(nums)):\n for j in range(i + 1, len(nums)):\n # Check if the xor of the pair is even\n if (nums[i] ^ nums[j]) % 2 == 0:\n count += 1\n \n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(nums):\n even_pairs = 0\n n = len(nums)\n for i in range(n):\n for j in range(i + 1, n):\n if (nums[i] ^ nums[j]) % 2 == 0:\n even_pairs += 1\n return even_pairs", "matching_cluster_idx": 1}]}, "Mbpp/170": {"dps": 93.6231884057971, "dps_norm": 98.75, "pass@1": 98.0, "profiled": [{"solution": "def sum_range_list(lst, start_index, end_index):\n # Calculate the sum of the sublist defined by the given range\n return sum(lst[start_index:end_index + 1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(lst, start, end):\n # Calculate sum of elements in the specified range\n return sum(lst[start:end+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(lst, start, end):\n # Ensure the indices are within the bounds of the list\n start = max(0, start)\n end = min(len(lst) - 1, end)\n # Compute the sum of elements between the indices\n return sum(lst[start:end+1])", "matching_cluster_idx": 6}, {"solution": "def sum_range_list(lst, start, end):\n # Calculate the sum of elements within the specified range\n total_sum = sum(lst[start:end+1])\n return total_sum", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(lst, start_index, end_index):\n # Calculate the sum of the specified range in the list\n return sum(lst[start_index:end_index + 1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(lst, start, end):\n # Calculate the sum of the sublist from start index to end index inclusive\n sublist = lst[start:end+1]\n return sum(sublist)", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(lst, start_index, end_index):\n # Calculate the sum of elements within the specified range\n return sum(lst[start_index:end_index + 1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(lst, start, end):\n # Calculate the sum of elements from start to end index\n total_sum = sum(lst[start:end+1])\n return total_sum", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(lst, start_idx, end_idx):\n # Calculate the sum of elements within the specified range\n return sum(lst[start_idx:end_idx+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(lst, start_index, end_index):\n # Calculate the sum of elements from start_index to end_index inclusive\n sub_list_sum = sum(lst[start_index:end_index + 1])\n return sub_list_sum", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(lst, start, end):\n # Calculate the sum of the sublist from start to end (inclusive)\n sublist_sum = sum(lst[start:end+1])\n return sublist_sum", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(lst, start, end):\n # Calculate the sum of elements from start to end (inclusive)\n return sum(lst[start:end+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(lst, start_idx, end_idx):\n # Calculate the sum of elements in the specified range\n total_sum = sum(lst[start_idx:end_idx+1])\n return total_sum", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(lst, start_index, end_index):\n # Calculate the sum of elements between the given indices\n return sum(lst[start_index:end_index + 1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(lst, start_idx, end_idx):\n # Ensure indices are within the bounds of the list\n start_idx = max(0, start_idx)\n end_idx = min(len(lst) - 1, end_idx)\n \n # Calculate the sum of the specified range\n return sum(lst[start_idx:end_idx + 1])", "matching_cluster_idx": 6}, {"solution": "def sum_range_list(lst, start_index, end_index):\n # Calculate the sum of the specified range in the list\n return sum(lst[start_index:end_index+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(lst, start, end):\n # Calculate the sum of the sublist specified by the indices\n sublist_sum = sum(lst[start:end+1])\n return sublist_sum", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(nums, start_idx, end_idx):\n # Calculate the sum of the sublist defined by the start and end indices\n sublist_sum = sum(nums[start_idx:end_idx + 1])\n return sublist_sum", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(lst, start_index, end_index):\n # Calculate the sum of elements within the specified range\n return sum(lst[start_index:end_index+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(lst, start, end):\n # Calculate sum of elements from index 'start' to 'end'\n total_sum = sum(lst[start:end+1])\n return total_sum", "matching_cluster_idx": 7}]}, "Mbpp/226": {"dps": 79.57364341085271, "dps_norm": 48.57142857142857, "pass@1": 100.0, "profiled": [{"solution": "def odd_values_string(s):\n # Extract characters with even index (odd position in human terms)\n return s[::2]", "matching_cluster_idx": 6}, {"solution": "def odd_values_string(s):\n # Select characters that have even index values (which correspond to odd positions in human counting)\n return s[::2]", "matching_cluster_idx": 6}, {"solution": "def odd_values_string(s):\n # Return a new string formed by characters at even indices from the original string\n return s[::2]", "matching_cluster_idx": 6}, {"solution": "def odd_values_string(s):\n # Initialize an empty string to store the result\n result = ''\n \n # Iterate through the string and select characters at even indices\n for i in range(len(s)):\n if i % 2 == 0:\n result += s[i]\n \n return result", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(s):\n # Initialize an empty result string\n result = ''\n \n # Iterate over the string and take only characters with even index values (odd positions)\n for i in range(len(s)):\n if i % 2 == 0:\n result += s[i]\n \n return result", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(input_str):\n # Using list comprehension to construct a string from characters at even indices (0-based)\n result = ''.join([input_str[i] for i in range(len(input_str)) if i % 2 == 0])\n return result", "matching_cluster_idx": 1}, {"solution": "def odd_values_string(s):\n # Use slicing to get characters at even indices (0-based index)\n return s[::2]", "matching_cluster_idx": 5}, {"solution": "def odd_values_string(s):\n # Return characters from the string which are at even index positions\n return s[::2]", "matching_cluster_idx": 5}, {"solution": "def odd_values_string(s):\n # Using list comprehension to filter out characters at odd indices\n result = ''.join([s[i] for i in range(len(s)) if i % 2 == 0])\n return result", "matching_cluster_idx": 1}, {"solution": "def odd_values_string(s):\n # Initialize an empty result string\n result = ''\n # Iterate through the string using the index\n for index in range(len(s)):\n # Check if the index is even (since indexing starts from 0)\n if index % 2 == 0:\n # Append the character at the even index to the result string\n result += s[index]\n # Return the result string\n return result", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(s):\n # Select characters at even indices (0-based index, so these are the odd positions in 1-based terms)\n result = s[::2]\n return result", "matching_cluster_idx": 5}, {"solution": "def odd_values_string(str):\n # Initialize an empty result string\n result = ''\n \n # Iterate over the string, considering only even indices (0-based)\n for i in range(len(str)):\n if i % 2 == 0:\n result += str[i]\n \n return result", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(input_string):\n # Extract characters with even index values (odd positions in human counting)\n return ''.join([input_string[i] for i in range(len(input_string)) if i % 2 == 0])", "matching_cluster_idx": 1}, {"solution": "def odd_values_string(str):\n # Initialize an empty string to hold the result\n result = ''\n # Iterate over the string with index\n for i in range(len(str)):\n # Check if index is even (since we want characters at odd positions based on human count)\n if i % 2 == 0:\n # Append the character at this index to the result string\n result += str[i]\n return result", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(s):\n # Initialize an empty string to store the result\n result = ''\n # Iterate through the string, considering only even indices (0, 2, 4, ...)\n for i in range(0, len(s), 2):\n result += s[i]\n return result", "matching_cluster_idx": 1}, {"solution": "def odd_values_string(s):\n # Return the string made up of characters at even indices (0-based)\n return s[::2]", "matching_cluster_idx": 5}, {"solution": "def odd_values_string(str):\n # Initialize an empty result string\n result_string = ''\n \n # Loop through the string, checking the index\n for i in range(len(str)):\n # Append character if its index is even (since index starts at 0, even indexes correspond to odd positions)\n if i % 2 == 0:\n result_string += str[i]\n \n return result_string", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(s):\n # Use slicing to get characters at even indices (0-based indexing)\n return s[::2]", "matching_cluster_idx": 5}, {"solution": "def odd_values_string(str):\n # Initialize an empty result string\n result = ''\n # Iterate over the string with index\n for i in range(len(str)):\n # Check if index is even (0, 2, 4, ...)\n if i % 2 == 0:\n # Append character at even index to result string\n result += str[i]\n return result", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(s):\n # Return a new string that includes characters at even indices\n return ''.join([s[i] for i in range(len(s)) if i % 2 == 0])", "matching_cluster_idx": 1}]}, "Mbpp/230": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def replace_blank(s, char):\n return s.replace(\" \", char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(s, char):\n # Replace blank spaces with the given character\n return s.replace(' ', char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(s, ch):\n # Replace blank spaces with the provided character\n return s.replace(' ', ch)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(s, char):\n # Replace blank spaces in the string with the provided character\n return s.replace(' ', char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(s, ch):\n # Replace spaces in the string 's' with the character 'ch'\n return s.replace(' ', ch)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(s, char):\n return s.replace(' ', char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(s, char):\n # Replace blank spaces with the given character\n return s.replace(' ', char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_str, replace_char):\n # Replace all blank spaces in the input string with the replace character\n return input_str.replace(' ', replace_char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(s, char):\n # Replace all blank spaces with the specified character\n return s.replace(' ', char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(s, char):\n # Replace blank spaces with the given character\n return s.replace(' ', char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(string, char):\n # Replace spaces with the specified character\n result_string = string.replace(' ', char)\n return result_string", "matching_cluster_idx": 7}, {"solution": "def replace_blank(string, character):\n # Replace blank spaces with the given character\n return string.replace(\" \", character)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(s, char):\n # Replace blank spaces with the given character\n return s.replace(' ', char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(string, character):\n # Replace blank spaces in the string with the specified character\n return string.replace(' ', character)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string, replace_char):\n # Replace spaces in the input_string with replace_char\n return input_string.replace(' ', replace_char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(s, char):\n # Replace spaces in the string with the specified character\n return s.replace(' ', char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(s, char):\n # Replace blank spaces with the given character\n return s.replace(' ', char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(s, ch):\n # Replace spaces with the character 'ch'\n return s.replace(' ', ch)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(s, char):\n # Replace blank spaces in the string with the specified character\n return s.replace(' ', char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(s, char):\n # Replace blank spaces with the specified character\n return s.replace(' ', char)", "matching_cluster_idx": 7}]}, "Mbpp/239": {"dps": 73.62068965517241, "dps_norm": 76.5, "pass@1": 54.0, "profiled": [{"solution": "def get_total_number_of_sequences(m, n):\n # Initialize a 2D DP table with dimensions (m+1) x (n+1)\n # dp[i][j] represents the number of sequences of length j ending with a number less than or equal to i\n dp = [[0 for _ in range(n+1)] for _ in range(m+1)]\n \n # Fill the table with base cases and recursive cases\n for i in range(1, m+1):\n dp[i][1] = 1 # There is exactly one sequence of length 1 for each number i: the sequence [i]\n\n for j in range(2, n+1):\n for i in range(1, m+1):\n for x in range(1, i//2 + 1):\n dp[i][j] += dp[x][j-1]\n \n # Sum up all the sequences of length n\n result = sum(dp[i][n] for i in range(1, m+1))\n \n return result", "matching_cluster_idx": 6}, {"solution": "def get_total_number_of_sequences(m, n):\n # Initialize a DP table with dimensions (n+1) x (m+1)\n dp = [[0 for _ in range(m + 1)] for _ in range(n + 1)]\n \n # Base case: There's one sequence of length 1 for each possible value\n for i in range(1, m + 1):\n dp[1][i] = 1\n \n # Fill the DP table\n for length in range(2, n + 1): # Sequence length from 2 to n\n for max_val in range(1, m + 1): # Maximum possible value in sequence\n # Calculate the sum of sequences ending with values less than or equal to half of max_val\n for prev_val in range(1, (max_val // 2) + 1):\n dp[length][max_val] += dp[length - 1][prev_val]\n \n # Sum up all possibilities for sequences of length n\n total_sequences = sum(dp[n])\n \n return total_sequences", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n # Base case: If the length of the sequence is 1, any number from 1 to m is a valid sequence.\n if n == 1:\n return m\n \n # Initialize a 2D list with 0s to store the count of sequences for lengths 1 to n.\n sequence_counts = [[0] * (n + 1) for _ in range(m + 1)]\n \n # For sequences of length 1, every number from 1 to m is a valid sequence, so count is 1.\n for i in range(1, m + 1):\n sequence_counts[i][1] = 1\n \n # Fill the sequence_counts table.\n for length in range(2, n + 1): # For each length from 2 to n\n for current_val in range(1, m + 1): # For each possible value from 1 to m\n # The count of sequences ending with 'current_val' is the sum of counts of all\n # possible previous values in the sequence which are less than or equal to half of 'current_val'.\n for prev_val in range(1, current_val // 2 + 1):\n sequence_counts[current_val][length] += sequence_counts[prev_val][length - 1]\n \n # The total count of sequences of length n is the sum of counts ending with any value from 1 to m.\n total_sequences = sum(sequence_counts[i][n] for i in range(1, m + 1))\n \n return total_sequences", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n # Initialize a DP table\n dp = [[0 for _ in range(n + 1)] for _ in range(m + 1)]\n \n # Initialize base case\n for i in range(1, m + 1):\n dp[i][1] = 1\n \n # Fill the DP table\n for length in range(2, n + 1):\n for current in range(1, m + 1):\n for prev in range(1, current // 2 + 1):\n dp[current][length] += dp[prev][length - 1]\n \n # Sum up all the ways to form a sequence of length n with numbers up to m\n total_sequences = sum(dp[i][n] for i in range(1, m + 1))\n \n return total_sequences", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n # Initialize a DP table with zeros\n dp = [[0 for _ in range(n + 1)] for _ in range(m + 1)]\n \n # Base case: For each number from 1 to m, there is one sequence of length 1\n for i in range(1, m + 1):\n dp[i][1] = 1\n \n # Fill the DP table\n for length in range(2, n + 1):\n for end in range(1, m + 1):\n for prev in range(1, (end // 2) + 1):\n dp[end][length] += dp[prev][length - 1]\n \n # Sum up all possible sequences ending with any number from 1 to m\n total_sequences = sum(dp[i][n] for i in range(1, m + 1))\n return total_sequences", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n # Initialize a 2D DP array with zeros\n dp = [[0 for _ in range(n + 1)] for __ in range(m + 1)]\n \n # Base case initialization\n for i in range(m + 1):\n dp[i][1] = i\n \n # Fill the DP table\n for j in range(2, n + 1):\n for i in range(2, m + 1):\n dp[i][j] = dp[i - 1][j] + dp[i // 2][j - 1]\n\n return dp[m][n]", "matching_cluster_idx": 8}, {"solution": "def get_total_number_of_sequences(m, n):\n # Initialize the dp array with zeros\n dp = [[0 for _ in range(n + 1)] for _ in range(m + 1)]\n \n # Set base case, for each m, there's 1 sequence of length 1 (the number itself)\n for i in range(1, m + 1):\n dp[i][1] = 1\n \n # Fill the dp table\n for i in range(1, m + 1):\n for j in range(2, n + 1):\n for k in range(1, (i // 2) + 1):\n dp[i][j] += dp[k][j - 1]\n \n # Sum up all the possible sequences of length n for numbers up to m\n result = sum(dp[i][n] for i in range(1, m + 1))\n \n return result", "matching_cluster_idx": 6}, {"solution": "def get_total_number_of_sequences(m, n):\n # Initialize a DP array with size m+1, set all values to 0\n dp = [0] * (m + 1)\n \n # Start filling the DP table from the first possible value to m\n for i in range(1, m + 1):\n dp[i] = 1 # Every number itself is a sequence of length 1\n \n for length in range(2, n + 1): # For each sequence length from 2 to n\n new_dp = [0] * (m + 1) # Create a new DP array for this length\n \n for i in range(1, m + 1):\n for j in range(1, i // 2 + 1):\n new_dp[i] += dp[j] # Add all possible sequences ending with j that can be followed by i\n \n dp = new_dp # Update the DP array for the next iteration\n \n return sum(dp) # Sum of all possible sequences of length n", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n # Initialize a 2D list with dimensions (m+1) x (n+1) filled with zeros\n dp = [[0 for _ in range(n+1)] for _ in range(m+1)]\n \n # Fill the dp table with base cases: Any sequence of length 1 is 1\n for i in range(1, m+1):\n dp[i][1] = 1\n \n # Fill the dp table for sequences of length 2 to n\n for i in range(1, m+1):\n for j in range(2, n+1):\n # Sum the number of sequences ending with each number less than or equal to half of i\n for k in range(1, (i//2) + 1):\n dp[i][j] += dp[k][j-1]\n \n # Sum all the ways to form sequences of length n with the last element being from 1 to m\n total_sequences = sum(dp[i][n] for i in range(1, m+1))\n return total_sequences", "matching_cluster_idx": 6}, {"solution": "def get_total_number_of_sequences(m, n):\n # Initialize a 2D list to store subproblem solutions\n dp = [[0 for _ in range(n + 1)] for _ in range(m + 1)]\n \n # Initialize the base case for subproblem solutions\n for i in range(m + 1):\n dp[i][1] = 1\n \n # Fill the dp table\n for j in range(2, n + 1): # For every length j from 2 to n\n for i in range(1, m + 1): # For every value i from 1 to m\n for x in range(1, i // 2 + 1): # For every possible previous element x\n dp[i][j] += dp[x][j - 1]\n \n # Sum all possible sequences ending with any number from 1 to m\n total_sequences = sum(dp[i][n] for i in range(1, m + 1))\n return total_sequences", "matching_cluster_idx": 6}, {"solution": "def get_total_number_of_sequences(m, n):\n # Initialize a 2D list with base case values, 1 for all m and n=1\n dp = [[0 for _ in range(n + 1)] for _ in range(m + 1)]\n for i in range(1, m + 1):\n dp[i][1] = 1\n \n # Fill the dp table\n for j in range(2, n + 1): # For each length from 2 to n\n for i in range(1, m + 1): # For each possible maximum value from 1 to m\n for k in range(1, i // 2 + 1): # For each possible previous value\n dp[i][j] += dp[k][j - 1]\n \n # Sum up all possible sequences of length n with maximum value from 1 to m\n total_sequences = sum(dp[i][n] for i in range(1, m + 1))\n return total_sequences", "matching_cluster_idx": 6}, {"solution": "def get_total_number_of_sequences(m, n):\n def dfs(current_length, prev):\n if current_length == n:\n return 1\n total_sequences = 0\n for i in range(2 * prev, m + 1):\n total_sequences += dfs(current_length + 1, i)\n return total_sequences\n\n total_sequences = 0\n for i in range(1, m + 1):\n total_sequences += dfs(1, i)\n return total_sequences", "matching_cluster_idx": 5}, {"solution": "def get_total_number_of_sequences(m, n):\n # Initialize a 2D list dp with dimensions (n+1) x (m+1) filled with zeros\n dp = [[0 for _ in range(m + 1)] for _ in range(n + 1)]\n \n # Fill the dp table\n for i in range(1, n + 1): # for each sequence length\n for j in range(1, m + 1): # for each possible max value\n if i == 1:\n # For sequence length 1, there's exactly 1 sequence for each j\n dp[i][j] = j\n else:\n # dp[i][j] is the sum of dp[i-1][k] for all k <= j//2\n dp[i][j] = dp[i][j - 1] + (dp[i - 1][j // 2] if j > 1 else 0)\n \n # The answer is the total for sequence length n with max value m\n return dp[n][m]", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n # Initialize a 2D list to store subproblems' results\n dp = [[0] * (n + 1) for _ in range(m + 1)]\n \n # Initialize the base case where sequence length is 1\n for i in range(1, m + 1):\n dp[i][1] = 1\n \n # Fill the dp array\n for length in range(2, n + 1): # length of sequence\n for last in range(1, m + 1): # last element in sequence\n # Sum up all possible sequences ending with last and of length (length-1)\n for prev in range(1, last // 2 + 1):\n dp[last][length] += dp[prev][length - 1]\n \n # Sum up all possible sequences of length n with last element up to m\n result = sum(dp[i][n] for i in range(1, m + 1))\n return result", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n # Create a 2D list to store the count of sequences\n dp = [[0 for _ in range(n + 1)] for __ in range(m + 1)]\n \n # Initialize the base case: sequences of length 1\n for i in range(1, m + 1):\n dp[i][1] = 1\n \n # Fill the dp table\n for length in range(2, n + 1):\n for last in range(1, m + 1):\n total = 0\n for prev in range(1, (last // 2) + 1):\n total += dp[prev][length - 1]\n dp[last][length] = total\n \n # Sum all sequences of length n\n result = 0\n for i in range(1, m + 1):\n result += dp[i][n]\n \n return result", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n # Initialize a DP table with zeros\n dp = [[0 for _ in range(n+1)] for _ in range(m+1)]\n \n # Each single number is a valid sequence for n = 1\n for i in range(1, m+1):\n dp[i][1] = 1\n \n # Fill the DP table\n for j in range(2, n+1): # For each sequence length\n for i in range(1, m+1): # For each value i\n for k in range(1, (i // 2) + 1): # Find all possible previous elements\n dp[i][j] += dp[k][j-1]\n \n # Sum up all the sequences of length n\n total_sequences = sum(dp[i][n] for i in range(1, m+1))\n \n return total_sequences", "matching_cluster_idx": 6}, {"solution": "def get_total_number_of_sequences(m, n):\n # Initialize a 2D DP array with zeros\n dp = [[0 for _ in range(n+1)] for _ in range(m+1)]\n \n # Fill the DP table\n for i in range(1, m+1):\n dp[i][1] = 1 # With sequence length 1, every number is a valid sequence\n \n for j in range(2, n+1):\n for i in range(1, m+1):\n for k in range(1, (i // 2) + 1):\n dp[i][j] += dp[k][j-1]\n \n # Sum up all the sequences that end with any number from 1 to m\n total_sequences = sum(dp[i][n] for i in range(1, m+1))\n \n return total_sequences", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n # Initialize the memoization table\n dp = [[0 for _ in range(n+1)] for _ in range(m+1)]\n \n # Base case: There's one way to form a sequence of length 1 for each number\n for i in range(1, m+1):\n dp[i][1] = 1\n \n # Fill the dp table\n for length in range(2, n+1):\n for num in range(1, m+1):\n # Sum up all valid sequences ending with a number less than num//2\n for prev_num in range(1, num//2 + 1):\n dp[num][length] += dp[prev_num][length - 1]\n \n # Sum up all possible sequences of length n\n total_sequences = sum(dp[i][n] for i in range(1, m+1))\n return total_sequences", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n # Initialize a DP table\n dp = [[0 for _ in range(n + 1)] for _ in range(m + 1)]\n \n # Base case: for sequence length 1, there are 'm' possibilities\n for i in range(1, m + 1):\n dp[i][1] = i\n\n # Fill the DP table\n for length in range(2, n + 1):\n for value in range(1, m + 1):\n dp[value][length] = dp[value - 1][length]\n if value >= 2 * (length - 1):\n dp[value][length] += dp[value // 2][length - 1]\n \n # The answer will be in dp[m][n]\n return dp[m][n]", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n # Initialize a 2D list for dynamic programming\n # dp[i][j] will store the number of sequences of length i ending with a number j\n dp = [[0 for _ in range(m + 1)] for _ in range(n + 1)]\n \n # There is 1 sequence of length 1 ending with each number from 1 to m\n for j in range(1, m + 1):\n dp[1][j] = 1\n \n # Fill the dp table\n for length in range(2, n + 1):\n for last_num in range(1, m + 1):\n for prev_num in range(1, (last_num // 2) + 1):\n dp[length][last_num] += dp[length - 1][prev_num]\n \n # Sum up all sequences of length n\n total_sequences = sum(dp[n])\n return total_sequences", "matching_cluster_idx": 7}]}, "Mbpp/240": {"dps": 100.00000000000001, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def replace_list(list1, list2):\n # Remove the last element of the first list\n del list1[-1]\n # Extend list1 with all elements of list2\n list1.extend(list2)\n return list1", "matching_cluster_idx": 8}, {"solution": "def replace_list(lst1, lst2):\n # Remove the last element from the first list\n lst1.pop()\n # Extend the first list with all elements from the second list\n lst1.extend(lst2)\n return lst1", "matching_cluster_idx": 8}, {"solution": "def replace_list(list1, list2):\n # Remove the last element of the first list\n list1.pop()\n # Extend the first list with all elements from the second list\n list1.extend(list2)\n return list1", "matching_cluster_idx": 8}, {"solution": "def replace_list(lst1, lst2):\n # Remove the last element of the first list\n lst1.pop()\n # Extend the first list with the second list\n lst1.extend(lst2)\n return lst1", "matching_cluster_idx": 8}, {"solution": "def replace_list(lst1, lst2):\n # Remove the last element of the first list\n lst1.pop()\n # Extend the first list with all elements from the second list\n lst1.extend(lst2)\n return lst1", "matching_cluster_idx": 8}, {"solution": "def replace_list(lst1, lst2):\n # Remove the last element of the first list\n lst1.pop()\n # Extend the first list with all elements of the second list\n lst1.extend(lst2)\n return lst1", "matching_cluster_idx": 8}, {"solution": "def replace_list(lst1, lst2):\n # Remove the last element from the first list\n lst1.pop()\n # Extend lst1 with the elements of lst2\n lst1.extend(lst2)\n return lst1", "matching_cluster_idx": 8}, {"solution": "def replace_list(first_list, second_list):\n # Remove the last element from the first list\n first_list.pop()\n # Extend the first list with the elements of the second list\n first_list.extend(second_list)\n return first_list", "matching_cluster_idx": 8}, {"solution": "def replace_list(lst1, lst2):\n # Remove the last element of lst1\n lst1.pop()\n # Extend lst1 with all elements of lst2\n lst1.extend(lst2)\n return lst1", "matching_cluster_idx": 8}, {"solution": "def replace_list(first_list, second_list):\n # Remove the last element of the first list\n first_list.pop()\n # Extend the first list with all elements from the second list\n first_list.extend(second_list)\n return first_list", "matching_cluster_idx": 8}, {"solution": "def replace_list(lst1, lst2):\n # Remove the last element of the first list\n lst1.pop()\n # Extend the first list with the elements from the second list\n lst1.extend(lst2)\n return lst1", "matching_cluster_idx": 8}, {"solution": "def replace_list(lst1, lst2):\n # Remove the last element from the first list\n lst1.pop()\n # Extend the first list with all elements of the second list\n lst1.extend(lst2)\n return lst1", "matching_cluster_idx": 8}, {"solution": "def replace_list(lst1, lst2):\n # Remove the last element of the first list\n lst1.pop()\n # Extend the first list with all elements of the second list\n lst1.extend(lst2)\n return lst1", "matching_cluster_idx": 8}, {"solution": "def replace_list(first_list, second_list):\n # Remove the last element of the first list\n first_list.pop()\n # Extend the first list with all elements of the second list\n first_list.extend(second_list)\n return first_list", "matching_cluster_idx": 8}, {"solution": "def replace_list(lst1, lst2):\n # Remove the last element from the first list\n lst1.pop()\n # Extend the first list with the elements of the second list\n lst1.extend(lst2)\n return lst1", "matching_cluster_idx": 8}, {"solution": "def replace_list(lst1, lst2):\n # Remove the last element from lst1\n lst1.pop()\n # Extend lst1 with all elements from lst2\n lst1.extend(lst2)\n return lst1", "matching_cluster_idx": 8}, {"solution": "def replace_list(list1, list2):\n # Remove the last element from the first list\n list1.pop()\n # Extend the first list with the elements of the second list\n list1.extend(list2)\n return list1", "matching_cluster_idx": 8}, {"solution": "def replace_list(lst1, lst2):\n # Remove the last element from the first list\n lst1.pop()\n # Extend the first list with all elements from the second list\n lst1.extend(lst2)\n return lst1", "matching_cluster_idx": 8}, {"solution": "def replace_list(lst1, lst2):\n # Remove the last element of the first list\n lst1.pop()\n # Extend the first list with the elements of the second list\n lst1.extend(lst2)\n return lst1", "matching_cluster_idx": 8}, {"solution": "def replace_list(list1, list2):\n # Remove the last element of the first list\n list1.pop()\n # Extend the first list with all elements of the second list\n list1.extend(list2)\n return list1", "matching_cluster_idx": 8}]}, "Mbpp/251": {"dps": 87.95977011494254, "dps_norm": 76.66666666666666, "pass@1": 100.0, "profiled": [{"solution": "def insert_element(lst, elem):\n # Initialize an empty list to store the result\n result = []\n # Iterate through each element in the list\n for item in lst:\n # Append the element and then the item to the result list\n result.append(elem)\n result.append(item)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n # Initialize an empty list to store the result\n result = []\n # Iterate through each element in the list\n for item in lst:\n # Append the 'element' and the current item to the result list\n result.append(element)\n result.append(item)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n # Initialize an empty list to store the result\n result = []\n # Iterate over each item in the input list\n for item in lst:\n # Append the element to be inserted before each item\n result.append(element)\n # Append the original item\n result.append(item)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n # Initialize an empty result list\n result = []\n \n # Iterate through each item in the original list\n for item in lst:\n # Append the element and the item to the result list\n result.append(element)\n result.append(item)\n \n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, elem):\n # Create a new list to store the result\n result = []\n # Iterate through the input list and insert 'elem' before each element\n for item in lst:\n result.append(elem)\n result.append(item)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, ele):\n # Initialize an empty list to store the result\n result = []\n # Iterate through each item in the original list\n for item in lst:\n # Append the element first, then the item\n result.append(ele)\n result.append(item)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n # Initialize an empty list to store the result\n result = []\n # Loop through each item in the input list\n for item in lst:\n # Append the element and the item to the result list\n result.append(element)\n result.append(item)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, elem):\n # Initialize an empty list to store the result\n result = []\n # Iterate over each element in the input list\n for item in lst:\n # Append the element and the current item to the result list\n result.append(elem)\n result.append(item)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n # Initialize an empty list to store the result\n result = []\n # Loop through each item in the input list\n for item in lst:\n # Append the specified element to the result list\n result.append(element)\n # Append the current item from the list to the result list\n result.append(item)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n # Initialize an empty list to store the result\n result = []\n # Iterate over each item in the input list\n for item in lst:\n # Append the element and then the item to the result list\n result.append(element)\n result.append(item)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, elem):\n # Initialize an empty result list\n result = []\n # Iterate over each item in the input list\n for item in lst:\n # Append the element before each item\n result.append(elem)\n result.append(item)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n # Initialize an empty list to store the result\n result = []\n # Iterate over each item in the input list\n for item in lst:\n # Append the element and the item to the result list\n result.append(element)\n result.append(item)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, elem):\n # Initialize an empty list to store the results\n result = []\n # Iterate over each element in the list\n for item in lst:\n # Append the specified element and the current list item to the result list\n result.append(elem)\n result.append(item)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n # Initialize an empty list to store the result\n result = []\n # Iterate over each element in the list\n for i in lst:\n # Append the additional element\n result.append(element)\n # Append the current element from the list\n result.append(i)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, elem):\n # Create a new list to store the result\n result = []\n # Iterate through each element in the original list\n for i in range(len(lst)):\n # Insert the element before the current element\n result.append(elem)\n result.append(lst[i])\n return result", "matching_cluster_idx": 4}, {"solution": "def insert_element(lst, element):\n # Initialize an empty list to store the result\n result = []\n # Iterate through each item in the input list\n for item in lst:\n # Append the element and the item to the result list\n result.append(element)\n result.append(item)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, elem):\n # Initialize an empty list to hold the result\n result = []\n # Loop through each element in the list\n for el in lst:\n # Append the element 'elem' and then the current element 'el' to the result list\n result.append(elem)\n result.append(el)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n # Initialize an empty list to store the result\n result = []\n # Iterate over each item in the given list\n for item in lst:\n # Append the given element to the result list\n result.append(element)\n # Append the item to the result list\n result.append(item)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n # Initialize an empty list to hold the result\n result = []\n # Iterate over each item in the input list\n for item in lst:\n # Append the element and the item to the result list\n result.append(element)\n result.append(item)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, elem):\n # Initialize an empty list to store the results\n result = []\n # Iterate through each element in the input list\n for item in lst:\n # Append the additional element and then the current list element to the result list\n result.extend([elem, item])\n # Return the result list\n return result", "matching_cluster_idx": 6}]}, "Mbpp/256": {"dps": 51.41552511415525, "dps_norm": 48.52941176470588, "pass@1": 100.0, "profiled": [{"solution": "def is_prime(num):\n \"\"\"Check if a number is a prime number.\"\"\"\n if num <= 1:\n return False\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n return False\n return True\ndef count_Primes_nums(n):\n \"\"\"Count the prime numbers less than the given non-negative number.\"\"\"\n # Initialize counter for prime numbers\n prime_count = 0\n \n # Iterate through numbers less than n\n for num in range(2, n):\n if is_prime(num):\n prime_count += 1\n \n return prime_count", "matching_cluster_idx": 8}, {"solution": "def is_prime(num):\n if num <= 1:\n return False\n for i in range(2, num):\n if num % i == 0:\n return False\n return True\ndef count_Primes_nums(n):\n count = 0\n for num in range(2, n):\n if is_prime(num):\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def is_prime(num):\n \"\"\"Helper function to check if a number is prime.\"\"\"\n if num <= 1:\n return False\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n return False\n return True\ndef count_Primes_nums(n):\n \"\"\"\n Takes in a non-negative number and returns the number of prime numbers less than the given non-negative number.\n \"\"\"\n count = 0\n for num in range(2, n):\n if is_prime(num):\n count += 1\n return count", "matching_cluster_idx": 8}, {"solution": "def is_prime(num):\n \"\"\"Helper function to check if a number is prime.\"\"\"\n if num <= 1:\n return False\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n return False\n return True\ndef count_Primes_nums(n):\n \"\"\"\n Takes a non-negative number and returns the count of prime numbers less than n.\n \n Args:\n n (int): A non-negative number\n \n Returns:\n int: The count of prime numbers less than n\n \"\"\"\n count = 0\n for num in range(2, n):\n if is_prime(num):\n count += 1\n return count", "matching_cluster_idx": 8}, {"solution": "def is_prime(num):\n if num <= 1:\n return False\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n return False\n return True\ndef count_Primes_nums(n):\n count = 0\n for num in range(2, n):\n if is_prime(num):\n count += 1\n return count", "matching_cluster_idx": 8}, {"solution": "def count_Primes_nums(n):\n # Initialize the count of primes\n count = 0\n \n # Loop through all numbers up to n to check if they are prime\n for num in range(2, n):\n i = 2\n # Check if num is prime\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n break\n else:\n count += 1\n return count", "matching_cluster_idx": 8}, {"solution": "def count_Primes_nums(n):\n # Define a helper function to check if a number is prime\n def is_prime(num):\n if num <= 1:\n return False\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n return False\n return True\n\n # Count the number of primes less than n\n count = 0\n for i in range(2, n):\n if is_prime(i):\n count += 1\n return count", "matching_cluster_idx": 8}, {"solution": "def count_Primes_nums(n):\n # Handle edge cases where the input is less than or equal to 2\n prime_counter = 0\n for num in range(2, n):\n for i in range(2, num):\n if (num % i) == 0:\n break\n else:\n prime_counter += 1\n return prime_counter", "matching_cluster_idx": 2}, {"solution": "def is_prime(num):\n \"\"\"\n Helper function to check if a number is prime.\n \"\"\"\n if num <= 1:\n return False\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n return False\n return True\ndef count_Primes_nums(n):\n \"\"\"\n Returns the count of prime numbers less than the given non-negative number.\n \"\"\"\n count = 0\n for i in range(2, n):\n if is_prime(i):\n count += 1\n return count", "matching_cluster_idx": 8}, {"solution": "def is_prime(num):\n \"\"\"Helper function to check if a number is prime.\"\"\"\n if num <= 1:\n return False\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n return False\n return True\ndef count_Primes_nums(n):\n \"\"\"\n Takes in a non-negative number and returns the number of prime numbers less than the given non-negative number.\n \"\"\"\n count = 0\n for num in range(2, n):\n if is_prime(num):\n count += 1\n return count", "matching_cluster_idx": 8}, {"solution": "def count_Primes_nums(n):\n \"\"\"\n Counts the number of prime numbers less than a given non-negative integer n.\n\n :param n: A non-negative integer\n :return: Count of prime numbers less than n\n \"\"\"\n count = 0\n for num in range(2, n):\n i = 2\n while(i <= num ** 0.5):\n if num % i == 0:\n break\n i += 1\n else:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def is_prime(n):\n \"\"\"Helper function to check if a number is prime.\"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True\ndef count_Primes_nums(n):\n \"\"\"\n Takes in a non-negative number and returns the number of prime numbers less than the given number.\n \n :param n: Non-negative number\n :return: Number of prime numbers less than n\n \"\"\"\n count = 0\n for num in range(2, n):\n if is_prime(num):\n count += 1\n return count", "matching_cluster_idx": 10}, {"solution": "def is_prime(n):\n \"\"\"\n Helper function to check if a number is a prime.\n \"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True\ndef count_Primes_nums(num):\n \"\"\"\n Takes in a non-negative number and returns the count of prime numbers less than the given number.\n \"\"\"\n count = 0\n for n in range(2, num):\n if is_prime(n):\n count += 1\n return count", "matching_cluster_idx": 8}, {"solution": "def is_prime(n):\n \"\"\"Helper function to check if a number is a prime number.\"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True\ndef count_Primes_nums(n):\n \"\"\"\n Takes in a non-negative number and returns the number of prime numbers less than the given non-negative number.\n \n :param n: A non-negative integer\n :return: The count of prime numbers less than n\n \"\"\"\n count = 0\n for num in range(2, n):\n if is_prime(num):\n count += 1\n return count", "matching_cluster_idx": 8}, {"solution": "def count_Primes_nums(n):\n # Initialize a counter for prime numbers\n count = 0\n # Iterate over each number from 2 to n-1\n for num in range(2, n):\n # Assume number is prime\n is_prime = True\n # Check if the number is divisible by any number less than itself\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n # If divisible, it's not a prime number\n is_prime = False\n break\n # If number is prime, increment count\n if is_prime:\n count += 1\n return count", "matching_cluster_idx": 8}, {"solution": "def is_prime(num):\n \"\"\"Helper function to check if a number is a prime number.\"\"\"\n if num <= 1:\n return False\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n return False\n return True\ndef count_Primes_nums(n):\n \"\"\"\n Takes in a non-negative number and returns the number of prime numbers less than the given non-negative number.\n \n :param n: Non-negative number\n :return: Count of prime numbers less than n\n \"\"\"\n count = 0\n for num in range(2, n):\n if is_prime(num):\n count += 1\n return count", "matching_cluster_idx": 8}, {"solution": "def is_prime(num):\n \"\"\"Helper function to check if a number is prime.\"\"\"\n if num <= 1:\n return False\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n return False\n return True\ndef count_Primes_nums(n):\n \"\"\"\n Takes in a non-negative number and returns the number of prime numbers less than the given non-negative number.\n \"\"\"\n count = 0\n for num in range(2, n):\n if is_prime(num):\n count += 1\n return count", "matching_cluster_idx": 8}, {"solution": "def count_Primes_nums(n):\n # Initialize a counter for prime numbers\n prime_counter = 0\n \n # Loop through the range from 2 up to but not including n\n for num in range(2, n):\n # Assume the number is prime\n is_prime = True\n # Check if there's any number from 2 to num-1 that divides num\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n # If found, num is not prime\n is_prime = False\n break\n # If num is prime, increase the counter\n if is_prime:\n prime_counter += 1\n \n return prime_counter", "matching_cluster_idx": 8}, {"solution": "def count_Primes_nums(n):\n # Initialize a counter for prime numbers\n prime_nums = 0\n \n # Iterate over the range from 2 to n (exclusive)\n for num in range(2, n):\n # Assume the number is prime until proven otherwise\n is_prime = True\n \n # Check if num is divisible by any number up to its square root\n for i in range(2, int(num ** 0.5) + 1):\n if num % i == 0:\n is_prime = False\n break\n \n # If is_prime is still True, we found a prime number\n if is_prime:\n prime_nums += 1\n \n return prime_nums", "matching_cluster_idx": 8}, {"solution": "def is_prime(num):\n \"\"\"Helper function to check if a number is prime.\"\"\"\n if num <= 1:\n return False\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n return False\n return True\ndef count_Primes_nums(n):\n \"\"\"\n Takes in a non-negative number and returns the number of prime numbers less than the given non-negative number.\n \"\"\"\n count = 0\n for num in range(2, n):\n if is_prime(num):\n count += 1\n return count", "matching_cluster_idx": 8}]}, "Mbpp/265": {"dps": 61.97674418604651, "dps_norm": 77.5, "pass@1": 65.0, "profiled": [{"solution": "def list_split(lst, n):\n # Create a list of lists to hold the split lists\n split_lists = [[] for _ in range(n)]\n # Iterate over the list, splitting it\n for i, item in enumerate(lst):\n split_lists[i % n].append(item)\n return split_lists", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n # Calculate the number of sublists needed\n num_sublists = (len(lst) + n - 1) // n\n # Initialize the list of sublists\n result = [[] for _ in range(n)]\n \n # Iterate over the list and distribute the elements into the sublists\n for index, value in enumerate(lst):\n sublist_index = index % n\n result[sublist_index].append(value)\n \n return result", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n # Initialize an empty list to hold the split lists\n result = []\n # Loop through n times\n for i in range(n):\n # Generate each split list and add it to the result\n result.append(lst[i::n])\n return result", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n # Initialize a list of empty lists, one for each column\n result = [[] for _ in range(n)]\n \n # Iterate over the original list, appending items to the appropriate column\n for index, item in enumerate(lst):\n result[index % n].append(item)\n \n return result", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n result = []\n for i in range(n):\n result.append(lst[i::n])\n return result", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n # Initialize an empty list to hold the split lists\n result = []\n # Iterate over the range of n to create sublists for every nth element\n for i in range(n):\n # Use list comprehension to slice the list starting from i and stepping by n\n result.append([lst[j] for j in range(i, len(lst), n)])\n return result", "matching_cluster_idx": 1}, {"solution": "def list_split(lst, n):\n # Initialize an empty list to hold the resulting sublists\n result = []\n # Loop through each index up to n to create sublists\n for i in range(n):\n # Add elements starting from index i, stepping by n\n result.append(lst[i::n])\n return result", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n # Initialize an empty list to hold the final sublists\n result = []\n\n # Loop through the list in steps of n\n for i in range(n):\n # Use list slicing to select every nth element starting at i\n sublist = lst[i::n]\n # Add the sublist to the result\n result.append(sublist)\n\n return result", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n # Initialize the list of lists\n result = []\n \n # Loop through n times\n for i in range(n):\n # Select every nth element starting from index i\n temp = lst[i::n]\n # Add the temporary list to the result\n result.append(temp)\n \n return result", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n # Using list comprehension and slicing to achieve the split\n return [lst[i::n] for i in range(n)]", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n result = []\n for i in range(n):\n result.append(lst[i::n])\n return result", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n result = []\n for i in range(n):\n result.append(lst[i::n])\n return result", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n # Initialize an empty list to hold the final lists\n result = []\n \n # Loop through each index up to n to create sublists\n for i in range(n):\n # Use list comprehension to create each sublist starting at index i and taking every nth element\n sublist = [lst[j] for j in range(i, len(lst), n)]\n # Append the sublist to the result list\n result.append(sublist)\n \n return result", "matching_cluster_idx": 1}, {"solution": "def list_split(lst, n):\n # Initialize an empty list to hold the resulting sublists\n result = []\n # Loop through n times to create each sublist\n for i in range(n):\n # Use list slicing to select every nth element starting from i\n sublist = lst[i::n]\n # Append the sublist to the result list\n result.append(sublist)\n return result", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n result = []\n for i in range(n):\n result.append(lst[i::n])\n return result", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n # Initialize an empty list to store the resulting lists\n result = []\n # Loop through each index from 0 to n-1 to extract every nth element\n for i in range(n):\n # Extract every nth element starting from index i\n split_list = lst[i::n]\n # Append the extracted list to the result\n result.append(split_list)\n # Return the final list of lists\n return result", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n result = []\n for i in range(n):\n result.append(lst[i::n])\n return result", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n # Calculate the number of resulting lists we will have\n num_lists = (len(lst) + n - 1) // n\n result = []\n \n # Loop through each position up to n (columns in the split list)\n for i in range(n):\n # For each position i, collect every nth element starting from i\n sublist = lst[i::n]\n result.append(sublist)\n \n return result", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n # Initialize an empty list to store the split lists\n result = []\n # Loop over each index from 0 to n-1 to create sublists\n for i in range(n):\n # Create a sublist starting from index i and stepping by n\n sub_list = lst[i::n]\n # Append the sublist to the result list\n result.append(sub_list)\n return result", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n # Initialize an empty list to hold the final sublists\n result = []\n \n # Loop through each index up to n\n for i in range(n):\n # Initialize an empty list to hold the current sublist\n sub_list = []\n # Loop through the original list starting from i and stepping by n\n for j in range(i, len(lst), n):\n # Add the jth element of the original list to the current sublist\n sub_list.append(lst[j])\n # Add the current sublist to the result\n result.append(sub_list)\n \n return result", "matching_cluster_idx": 3}]}, "Mbpp/281": {"dps": 94.0, "dps_norm": 81.81818181818181, "pass@1": 100.0, "profiled": [{"solution": "def all_unique(lst):\n # Convert list to set to remove duplicates, compare lengths\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n # Check if the length of the list is equal to the length of the set created from the list\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n # Converting list to set removes duplicates\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n # Compare the length of the list with the length of the set created from the list\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n # Convert the list to a set to remove duplicates\n # Compare the length of the list with the length of the set\n # If the lengths are equal, all elements are unique\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n # Convert list to set to remove duplicates\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n # Check if the length of the list is equal to the length of the set of the list\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n # Convert list to a set to remove duplicates and compare lengths\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n # Convert list to a set to remove duplicates\n # If length of set is same as length of list, all elements are unique\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n # Convert the list to a set to remove duplicates and compare lengths\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n # Convert the list to a set to remove duplicates\n # If the length of the list and set are the same, all elements are unique\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n # Convert list to a set and compare lengths to check uniqueness\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n # Create a set from the list and compare its length with the list's length\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n # Check if all elements are unique by comparing lengths of list and set\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n # Convert list to a set to remove duplicates and compare lengths\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n # Convert list to set and compare lengths to check for uniqueness\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n # Convert the list to a set to remove duplicates and compare lengths\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n # Convert list to set to remove duplicates, then compare lengths\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n # Convert the list to a set and compare its length with the original list\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n # Convert list to set and compare lengths\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}]}, "Mbpp/296": {"dps": 42.56410256410256, "dps_norm": 73.33333333333334, "pass@1": 82.0, "profiled": [{"solution": "def get_Inv_Count(arr):\n inv_count = 0\n for i in range(len(arr)):\n for j in range(i + 1, len(arr)):\n if arr[i] > arr[j]:\n inv_count += 1\n return inv_count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n # Initialize inversion count\n inv_count = 0\n\n # Iterate through the array\n for i in range(len(arr)):\n for j in range(i + 1, len(arr)):\n # Count inversions where arr[i] > arr[j]\n if arr[i] > arr[j]:\n inv_count += 1\n\n return inv_count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n # Initialize the count to 0\n count = 0\n \n # Iterate through each element in the array\n for i in range(len(arr)):\n # For each element, compare with all the elements after it\n for j in range(i + 1, len(arr)):\n # If the current element is greater than the element after it, it's an inversion\n if arr[i] > arr[j]:\n count += 1\n \n return count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n n = len(arr)\n inv_count = 0\n for i in range(n):\n for j in range(i + 1, n):\n if arr[i] > arr[j]:\n inv_count += 1\n return inv_count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n # Initialize count of inversions\n inv_count = 0\n n = len(arr)\n \n # Iterate through the array\n for i in range(n):\n for j in range(i + 1, n):\n # Count inversions\n if arr[i] > arr[j]:\n inv_count += 1\n \n return inv_count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n def merge_sort(arr, temp_arr, left, right):\n inv_count = 0\n if left < right:\n mid = (left + right) // 2\n inv_count += merge_sort(arr, temp_arr, left, mid)\n inv_count += merge_sort(arr, temp_arr, mid + 1, right)\n inv_count += merge(arr, temp_arr, left, mid, right)\n return inv_count\n\n def merge(arr, temp_arr, left, mid, right):\n i = left\n j = mid + 1\n k = left\n inv_count = 0\n \n while i <= mid and j <= right:\n if arr[i] <= arr[j]:\n temp_arr[k] = arr[i]\n i += 1\n else:\n temp_arr[k] = arr[j]\n inv_count += (mid - i + 1)\n j += 1\n k += 1\n \n while i <= mid:\n temp_arr[k] = arr[i]\n i += 1\n k += 1\n \n while j <= right:\n temp_arr[k] = arr[j]\n j += 1\n k += 1\n \n for loop_var in range(left, right + 1):\n arr[loop_var] = temp_arr[loop_var]\n \n return inv_count\n \n temp_arr = [0] * len(arr)\n return merge_sort(arr, temp_arr, 0, len(arr) - 1)", "matching_cluster_idx": 5}, {"solution": "def get_Inv_Count(arr):\n # This function will count the inversions in the array\n n = len(arr)\n inv_count = 0\n for i in range(n):\n for j in range(i + 1, n):\n if arr[i] > arr[j]:\n inv_count += 1\n return inv_count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n # Initialize count\n count = 0\n \n # Loop through the array to find inversions\n for i in range(len(arr)):\n for j in range(i + 1, len(arr)):\n if arr[i] > arr[j]:\n count += 1\n \n return count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n def merge_count_split_inv(left, right):\n result = []\n count = 0\n i, j = 0, 0\n while i < len(left) and j < len(right):\n if left[i] <= right[j]:\n result.append(left[i])\n i += 1\n else:\n result.append(right[j])\n count += len(left) - i # All remaining elements in left are inversions\n j += 1\n result += left[i:]\n result += right[j:]\n return result, count\n\n def sort_count(arr):\n if len(arr) <= 1:\n return arr, 0\n else:\n middle = len(arr) // 2\n left, inv_left = sort_count(arr[:middle])\n right, inv_right = sort_count(arr[middle:])\n result, inv_split = merge_count_split_inv(left, right)\n count = inv_left + inv_right + inv_split\n return result, count\n\n _, count = sort_count(arr)\n return count", "matching_cluster_idx": 5}, {"solution": "def get_Inv_Count(arr):\n n = len(arr)\n inv_count = 0\n for i in range(n):\n for j in range(i + 1, n):\n if arr[i] > arr[j]:\n inv_count += 1\n return inv_count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n inv_count = 0\n for i in range(len(arr)):\n for j in range(i + 1, len(arr)):\n if arr[i] > arr[j]:\n inv_count += 1\n return inv_count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n def merge_sort(arr, temp_arr, left, right):\n inv_count = 0\n if left < right:\n mid = (left + right) // 2\n inv_count += merge_sort(arr, temp_arr, left, mid)\n inv_count += merge_sort(arr, temp_arr, mid + 1, right)\n inv_count += merge(arr, temp_arr, left, mid, right)\n return inv_count\n\n def merge(arr, temp_arr, left, mid, right):\n i = left # Starting index of left subarray\n j = mid + 1 # Starting index of right subarray\n k = left # Starting index of to be sorted subarray\n inv_count = 0\n\n while i <= mid and j <= right:\n if arr[i] <= arr[j]:\n temp_arr[k] = arr[i]\n k += 1\n i += 1\n else:\n temp_arr[k] = arr[j]\n inv_count += (mid - i + 1)\n k += 1\n j += 1\n\n while i <= mid:\n temp_arr[k] = arr[i]\n k += 1\n i += 1\n\n while j <= right:\n temp_arr[k] = arr[j]\n k += 1\n j += 1\n\n for loop_var in range(left, right + 1):\n arr[loop_var] = temp_arr[loop_var]\n\n return inv_count\n\n # Auxiliary array\n temp_arr = [0] * len(arr)\n return merge_sort(arr, temp_arr, 0, len(arr) - 1)", "matching_cluster_idx": 5}, {"solution": "def get_Inv_Count(arr):\n # Initialize count\n inv_count = 0\n # Initialize the length of the array\n n = len(arr)\n # Iterate through the array\n for i in range(n):\n for j in range(i + 1, n):\n # Count inversions\n if arr[i] > arr[j]:\n inv_count += 1\n return inv_count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n # Initialize the count of inversions to 0\n inv_count = 0\n # Iterate through the array elements\n for i in range(len(arr)):\n for j in range(i + 1, len(arr)):\n # If an inversion is found, increment the count\n if arr[i] > arr[j]:\n inv_count += 1\n return inv_count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n # Initialize count to 0\n count = 0\n # Iterate through each element in the array\n for i in range(len(arr)):\n # Compare with all the elements following the current element\n for j in range(i + 1, len(arr)):\n # If an inversion is found, increment the count\n if arr[i] > arr[j]:\n count += 1\n return count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n # This function counts the number of inversions in the array\n inv_count = 0\n for i in range(len(arr)):\n for j in range(i + 1, len(arr)):\n if arr[i] > arr[j]:\n inv_count += 1\n return inv_count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n # Function to use in merge step\n def merge(arr, temp_arr, left, mid, right):\n i = left # Starting index for left subarray\n j = mid + 1 # Starting index for right subarray\n k = left # Initial index for merged array\n inv_count = 0\n\n # Conditions are checked to ensure that i doesn't exceed mid and j doesn't exceed right\n while i <= mid and j <= right:\n if arr[i] <= arr[j]:\n temp_arr[k] = arr[i]\n i += 1\n else:\n # Inversion will occur here due to right subarray value being lower than left subarray\n temp_arr[k] = arr[j]\n inv_count += (mid-i + 1)\n j += 1\n k += 1\n\n # Copy the remaining elements of left subarray into temporary array\n while i <= mid:\n temp_arr[k] = arr[i]\n k += 1\n i += 1\n\n # Copy the remaining elements of right subarray into temporary array\n while j <= right:\n temp_arr[k] = arr[j]\n k += 1\n j += 1\n\n # Copy the sorted subarray into original array\n for loop_var in range(left, right + 1):\n arr[loop_var] = temp_arr[loop_var]\n \n return inv_count\n \n # Merge sort function\n def merge_sort(arr, temp_arr, left, right):\n # A variable to store inversion counts in\n inv_count = 0\n if left < right:\n mid = (left + right)//2\n inv_count += merge_sort(arr, temp_arr, left, mid) # Inversion count from left subarray\n inv_count += merge_sort(arr, temp_arr, mid + 1, right) # Inversion count from right subarray\n inv_count += merge(arr, temp_arr, left, mid, right) # Merging arrays and getting inversion count in the process\n return inv_count\n \n # Create a temporary array\n n = len(arr)\n temp_arr = [0]*n\n return merge_sort(arr, temp_arr, 0, n-1)", "matching_cluster_idx": 5}, {"solution": "def get_Inv_Count(arr):\n # Initialize the count of inversions to 0\n inv_count = 0\n # Iterate through each element in the array\n for i in range(len(arr)):\n # Compare the current element with all elements after it\n for j in range(i + 1, len(arr)):\n # If an inversion is found, increment the count\n if arr[i] > arr[j]:\n inv_count += 1\n # Return the total count of inversions\n return inv_count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n # Initialize the inversion count to 0\n inv_count = 0\n # Traverse all elements in the array\n for i in range(len(arr)):\n for j in range(i + 1, len(arr)):\n # If an inversion is found, increment the count\n if arr[i] > arr[j]:\n inv_count += 1\n return inv_count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n # Initialize the count of inversions to 0\n inv_count = 0\n \n # Iterate over the array to find inversions\n for i in range(len(arr)):\n for j in range(i + 1, len(arr)):\n # If the current element is greater than the next element, it's an inversion\n if arr[i] > arr[j]:\n inv_count += 1\n \n return inv_count", "matching_cluster_idx": 3}]}, "Mbpp/308": {"dps": 83.32758620689656, "dps_norm": 66.66666666666667, "pass@1": 56.0, "profiled": [{"solution": "def large_product(list1, list2, k):\n \"\"\"\n Finds the k largest products from two given lists by selecting one factor from each list.\n \n :param list1: First list of integers\n :param list2: Second list of integers\n :param k: Number of largest products to return\n :return: List of k largest products\n \"\"\"\n from heapq import nlargest\n \n # Generate all possible products between the two lists\n products = [x*y for x in list1 for y in list2]\n \n # Find the k largest products\n largest_products = nlargest(k, products)\n \n return largest_products", "matching_cluster_idx": 4}, {"solution": "def large_product(nums1, nums2, k):\n # Multiply every element of nums1 with every element of nums2\n products = [i * j for i in nums1 for j in nums2]\n # Sort the products in descending order\n products.sort(reverse=True)\n # Return the first k elements\n return products[:k]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, num):\n # Initialize a list to store the products\n products = []\n \n # Iterate through each element in the first list\n for i in list1:\n # For each element in the first list, iterate through elements in the second list\n for j in list2:\n # Compute the product of the two elements\n product = i * j\n # Add the product to the list\n products.append(product)\n \n # Sort the list of products in descending order\n products.sort(reverse=True)\n \n # Return the first 'num' elements from the sorted list\n return products[:num]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n # Initialize an empty list to store the products\n products = []\n \n # Loop through each element in list1 and list2\n for i in list1:\n for j in list2:\n # Calculate the product of the elements\n product = i * j\n \n # Append the product to the products list\n products.append(product)\n \n # Sort the products list in descending order\n products.sort(reverse=True)\n \n # Return the first 'n' largest products\n return products[:n]", "matching_cluster_idx": 3}, {"solution": "from heapq import nlargest\ndef large_product(list1, list2, k):\n # Calculate all possible products\n products = [x*y for x in list1 for y in list2]\n # Find the k largest products using nlargest from heapq module\n largest_products = nlargest(k, products)\n return largest_products", "matching_cluster_idx": 4}, {"solution": "from heapq import nlargest\nfrom itertools import product\ndef large_product(list1, list2, k):\n # Generate all possible products from the two lists\n products = [p[0]*p[1] for p in product(list1, list2)]\n # Use nlargest to find the k largest products\n largest_products = nlargest(k, products)\n return largest_products", "matching_cluster_idx": 3}, {"solution": "def large_product(nums1, nums2, k):\n \"\"\"\n Finds the k largest products from two given lists by selecting one factor from each list.\n \n Parameters:\n nums1 (list): First list of integers.\n nums2 (list): Second list of integers.\n k (int): Number of largest products to find.\n \n Returns:\n list: List containing the k largest products.\n \"\"\"\n # Calculate all possible products\n products = [x * y for x in nums1 for y in nums2]\n # Sort the products in descending order\n products.sort(reverse=True)\n # Return the first k products\n return products[:k]", "matching_cluster_idx": 3}, {"solution": "def large_product(nums1, nums2, k):\n # Calculate all possible products from the two lists\n products = sorted([x * y for x in nums1 for y in nums2], reverse=True)[:k]\n return products", "matching_cluster_idx": 3}, {"solution": "import heapq\ndef large_product(list1, list2, k):\n # Sort the lists to facilitate finding the largest products\n list1.sort(reverse=True)\n list2.sort(reverse=True)\n \n # Initialize a heap queue\n product_heap = []\n \n # Iterate over each pair of elements to generate products\n for num1 in list1:\n for num2 in list2:\n # Push the product into the heap\n heapq.heappush(product_heap, num1 * num2)\n # Keep the heap size <= k\n if len(product_heap) > k:\n heapq.heappop(product_heap)\n \n # Since the heap is min-heap, the largest elements are at the bottom.\n # Therefore, we need to reverse the order of the heap to get the largest products.\n return sorted(product_heap, reverse=True)", "matching_cluster_idx": 1}, {"solution": "import heapq\nfrom typing import List\ndef large_product(list1: List[int], list2: List[int], k: int) -> List[int]:\n \"\"\"\n Find the top k largest products from two lists by picking one element from each list.\n \n :param list1: First list of integers.\n :param list2: Second list of integers.\n :param k: Number of top largest products to find.\n :return: A list of the top k largest products.\n \"\"\"\n # Heap to keep track of the largest k products\n min_heap = []\n \n # Loop through both lists and calculate the product\n for num1 in list1:\n for num2 in list2:\n product = num1 * num2\n if len(min_heap) < k:\n heapq.heappush(min_heap, product)\n else:\n # Push new element and pop the smallest if current product is larger\n heapq.heappushpop(min_heap, product)\n \n # Since it's a min heap, the elements are in ascending order, we need to reverse it\n return sorted(min_heap, reverse=True)", "matching_cluster_idx": 2}, {"solution": "def large_product(list1, list2, k):\n # Multiply each element of list1 with each element of list2\n products = [x * y for x in list1 for y in list2]\n # Sort the products list in descending order\n products.sort(reverse=True)\n # Return the first k elements from the sorted list\n return products[:k]", "matching_cluster_idx": 3}, {"solution": "import heapq\ndef large_product(nums1, nums2, k):\n # Sort the lists in reverse order to have largest elements first\n nums1.sort(reverse=True)\n nums2.sort(reverse=True)\n \n # Use a heap to keep track of the k largest products\n heap = []\n \n # Iterate over each combination and push the product onto the heap\n for num1 in nums1:\n for num2 in nums2:\n if len(heap) < k:\n heapq.heappush(heap, num1 * num2)\n else:\n # If the current product is larger than the smallest product in the heap,\n # replace it to ensure the heap always contains the k largest products\n heapq.heappushpop(heap, num1 * num2)\n \n # Convert the heap to a sorted list (largest products first)\n result = sorted(heap, reverse=True)\n return result", "matching_cluster_idx": 2}, {"solution": "from heapq import nlargest\nfrom itertools import product\ndef large_product(list1, list2, k):\n # Calculate the product of each possible pair\n products = [x*y for x, y in product(list1, list2)]\n # Find the 'k' largest products using nlargest from heapq\n largest_products = nlargest(k, products)\n return largest_products", "matching_cluster_idx": 3}, {"solution": "def large_product(nums1, nums2, k):\n # Initialize an empty list to store the products\n products = []\n \n # Iterate through both lists and compute the products\n for num1 in nums1:\n for num2 in nums2:\n products.append(num1 * num2)\n \n # Sort the products in descending order and slice the first 'k' elements\n products.sort(reverse=True)\n return products[:k]", "matching_cluster_idx": 3}, {"solution": "from heapq import nlargest\ndef large_product(list1, list2, n):\n # Calculate all possible products of pairs\n products = [x*y for x in list1 for y in list2]\n # Find 'n' largest products\n largest_products = nlargest(n, products)\n return largest_products", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef large_product(list1: List[int], list2: List[int], k: int) -> List[int]:\n \"\"\"\n Find the k largest products of pairs where one element is from list1 and another from list2.\n \n Parameters:\n list1 (List[int]): First list of integers.\n list2 (List[int]): Second list of integers.\n k (int): Number of largest products to return.\n \n Returns:\n List[int]: List containing the k largest products.\n \"\"\"\n # Compute all products\n products = [x * y for x in list1 for y in list2]\n \n # Sort the products in descending order\n sorted_products = sorted(products, reverse=True)\n \n # Get the first k products\n return sorted_products[:k]", "matching_cluster_idx": 3}, {"solution": "import heapq\ndef large_product(nums1, nums2, k):\n # Sort the lists in descending order to get the largest products first\n nums1.sort(reverse=True)\n nums2.sort(reverse=True)\n \n result = []\n # Generate the k largest products by multiplying the largest elements\n for i in nums1:\n for j in nums2:\n if len(result) < k:\n heapq.heappush(result, i * j)\n else:\n # Keep only the k largest products\n heapq.heappushpop(result, i * j)\n \n # The heap contains the k largest products but not necessarily sorted\n result.sort(reverse=True)\n return result", "matching_cluster_idx": 2}, {"solution": "from heapq import nlargest\ndef large_product(list1, list2, k):\n # Calculate all possible products of pairs from both lists\n products = [x * y for x in list1 for y in list2]\n # Find the k largest products using nlargest function from heapq module\n largest_products = nlargest(k, products)\n return largest_products", "matching_cluster_idx": 4}, {"solution": "from heapq import nlargest\ndef large_product(list1, list2, k):\n # Calculate the product of every possible pair from list1 and list2\n products = [x*y for x in list1 for y in list2]\n # Find the k largest products\n largest_products = nlargest(k, products)\n return largest_products", "matching_cluster_idx": 4}, {"solution": "def large_product(list1, list2, k):\n # Generate all possible products\n products = [x*y for x in list1 for y in list2]\n # Sort the products in descending order\n products.sort(reverse=True)\n # Return the first k products\n return products[:k]", "matching_cluster_idx": 3}]}, "Mbpp/392": {"dps": 93.68544600938966, "dps_norm": 95.38461538461539, "pass@1": 88.0, "profiled": [{"solution": "def get_max_sum(n):\n # Initialize a memoization array with -1\n memo = [-1 for _ in range(n + 1)]\n \n # Define a recursive function to calculate the max sum\n def recursive_max_sum(n):\n # Base case\n if n == 0:\n return 0\n if n == 1:\n return 1\n \n # If value already computed, return it\n if memo[n] != -1:\n return memo[n]\n \n # Calculate the value considering the equation\n result = max((recursive_max_sum(n // 2) + recursive_max_sum(n // 3) +\n recursive_max_sum(n // 4) + recursive_max_sum(n // 5)), n)\n \n # Store the computed value in memo\n memo[n] = result\n return result\n \n # Call the recursive function with the given number\n return recursive_max_sum(n)", "matching_cluster_idx": 10}, {"solution": "def get_max_sum(n):\n # Create a memoization dictionary to store the results of subproblems\n memo = {0: 0}\n \n # Define a helper function to calculate the maximum sum recursively\n def max_sum(x):\n # If the value has been computed, return it\n if x in memo:\n return memo[x]\n # Calculate the maximum sum for the current value of x\n memo[x] = max(x, max_sum(x//2) + max_sum(x//3) + max_sum(x//4) + max_sum(x//5))\n return memo[x]\n \n # Call the helper function with the original value of n\n return max_sum(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n # Dictionary to store the computed values for memoization\n memo = {}\n \n def f(n):\n # Base case\n if n == 0:\n return 0\n # Return memoized value if already computed\n if n in memo:\n return memo[n]\n # Calculate the maximum of the given equation\n memo[n] = max(n, f(n//2) + f(n//3) + f(n//4) + f(n//5))\n return memo[n]\n \n return f(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n # Create a memoization array to store calculated values\n memo = {}\n\n def f(n):\n # Base case\n if n < 2:\n return n\n\n # Check if the result for n is already computed\n if n in memo:\n return memo[n]\n\n # Calculate the value according to the function\n result = max((f(n // 2) + f(n // 3) + f(n // 4) + f(n // 5)), n)\n\n # Store the result in the memoization dictionary\n memo[n] = result\n return result\n \n return f(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n # Dictionary to store the calculated values\n memo = {}\n \n def f(n):\n # If the value is already computed, return it\n if n in memo:\n return memo[n]\n # Compute the value only if n is greater than or equal to 2\n if n >= 2:\n result = max(f(n // 2) + f(n // 3) + f(n // 4) + f(n // 5), n)\n else:\n result = n\n # Store the computed value in the dictionary\n memo[n] = result\n return result\n \n return f(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n # Create a dictionary to store the computed results\n memo = {}\n \n def max_sum_helper(n):\n # Base case\n if n < 2:\n return n\n \n # Check if the value is already computed\n if n in memo:\n return memo[n]\n \n # Calculate the value based on the given equation\n result = max(n, max_sum_helper(n//2) + max_sum_helper(n//3) + max_sum_helper(n//4) + max_sum_helper(n//5))\n \n # Store the result in the dictionary for future reference\n memo[n] = result\n \n return result\n \n # Call the helper function with the initial value\n return max_sum_helper(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n # A dictionary to store the computed values of the function for optimization\n memo = {0: 0, 1: 1}\n \n def helper(n):\n # If the value is already computed, return it\n if n in memo:\n return memo[n]\n \n # Compute the value if not computed already\n result = max(n, helper(n // 2) + helper(n // 3) + helper(n // 4) + helper(n // 5))\n \n # Store the computed value in the dictionary\n memo[n] = result\n \n return result\n \n return helper(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n # Define a memoization dictionary\n memo = {}\n \n def f(n):\n # If the value is already computed, return it\n if n in memo:\n return memo[n]\n \n # If n is less than 1, return 0 (base case)\n if n < 1:\n return 0\n \n # Compute the value using the given formula\n result = max((f(n // 2) + f(n // 3) + f(n // 4) + f(n // 5)), n)\n \n # Save the computed value in the dictionary\n memo[n] = result\n \n # Return the computed value\n return result\n \n return f(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n # Initialize a dictionary to store the results of subproblems\n memo = {}\n \n def f(n):\n # Base case\n if n < 2:\n return n\n \n # Check if the result is already computed\n if n in memo:\n return memo[n]\n \n # Recursive calls to find the maximum sum\n result = max(n, f(n // 2) + f(n // 3) + f(n // 4) + f(n // 5))\n \n # Store the result in memo dictionary\n memo[n] = result\n \n return result\n \n return f(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n # Dictionary to store the computed values for dynamic programming\n memo = {0: 0, 1: 1}\n \n def dp(x):\n # If the value is already computed, return it\n if x in memo:\n return memo[x]\n \n # Otherwise, compute the value using the equation and store it\n memo[x] = max(x, dp(x // 2) + dp(x // 3) + dp(x // 4) + dp(x // 5))\n \n return memo[x]\n \n return dp(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n # Create a memoization dictionary to store the results of subproblems\n memo = {}\n\n def max_sum_recursion(n):\n # Base case: if n is less than or equal to 1, return n\n if n <= 1:\n return n\n # If the result is already computed and stored, return it\n if n in memo:\n return memo[n]\n # Compute the maximum sum recursively and store it in memo before returning\n memo[n] = max((max_sum_recursion(n // 2) + max_sum_recursion(n // 3) + max_sum_recursion(n // 4) + max_sum_recursion(n // 5)), n)\n return memo[n]\n \n # Call the recursive function with the input n\n return max_sum_recursion(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n # Dictionary to store the computed values to avoid redundant calculations\n memo = {}\n\n def f(n):\n # If the value is already computed, return it\n if n in memo:\n return memo[n]\n # If n is less than or equal to 1, the maximum sum is n itself\n if n <= 1:\n return n\n # Calculate the value and store it in the dictionary\n memo[n] = max((f(n // 2) + f(n // 3) + f(n // 4) + f(n // 5)), n)\n return memo[n]\n \n return f(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n # Initialize the memoization dictionary with base case\n memo = {0: 0, 1: 1}\n \n def helper(x):\n # If the value is not in memo, calculate it\n if x not in memo:\n # Calculate the maximum sum using the given equation\n memo[x] = max(x, helper(int(x/2)) + helper(int(x/3)) + helper(int(x/4)) + helper(int(x/5)))\n return memo[x]\n \n # Calculate the maximum sum for the given input\n return helper(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n # Dictionary to store the results of subproblems\n memo = {0: 0, 1: 1}\n \n def helper(n):\n # If the value is already computed, return it\n if n in memo:\n return memo[n]\n # Compute the value if not computed before\n memo[n] = max(n, helper(n // 2) + helper(n // 3) + helper(n // 4) + helper(n // 5))\n return memo[n]\n \n # Call the helper function with the input value\n return helper(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n # Memoization dictionary to store results of subproblems\n memo = {}\n \n def calculate_max_sum(n):\n # Check if the result for the given value of n is already computed\n if n in memo:\n return memo[n]\n # If n is less than or equal to 1, the maximum sum is n itself\n if n <= 1:\n return n\n # Calculate the maximum sum using the provided formula\n max_sum = max((calculate_max_sum(n // 2) + calculate_max_sum(n // 3) + calculate_max_sum(n // 4) + calculate_max_sum(n // 5)), n)\n # Store the result in the memoization dictionary\n memo[n] = max_sum\n return max_sum\n \n return calculate_max_sum(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n # Dictionary to store the computed values to avoid recomputation\n memo = {0: 0}\n \n def f(x):\n # Check if the value is already computed\n if x not in memo:\n # Recursive call to compute the value using the given equation\n memo[x] = max((f(x // 2) + f(x // 3) + f(x // 4) + f(x // 5)), x)\n return memo[x]\n \n # Start the recursive computation with the given input n\n return f(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n # Dictionary to store the computed maximum sums to avoid recomputation\n memo = {0: 0}\n\n def find_max_sum(n):\n # Check if the result is already computed\n if n in memo:\n return memo[n]\n \n # Compute the result if not already computed\n result = max(n, find_max_sum(n // 2) + find_max_sum(n // 3) + find_max_sum(n // 4) + find_max_sum(n // 5))\n memo[n] = result\n return result\n \n return find_max_sum(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n # Create a dictionary to store the computed results for subproblems\n memo = {}\n \n def find_max_sum(n):\n # If n is 0 or 1, return n since f(0) = 0, f(1) = 1\n if n == 0 or n == 1:\n return n\n # If the result is already computed, return it\n if n in memo:\n return memo[n]\n # Compute the result using the given formula\n result = max((find_max_sum(n // 2) + find_max_sum(n // 3) + find_max_sum(n // 4) + find_max_sum(n // 5)), n)\n # Store the result in the memo dictionary\n memo[n] = result\n return result\n \n return find_max_sum(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n # Dictionary to store the computed values for reuse\n memo = {}\n\n def helper(n):\n # Base case: if n is less than or equal to 1, return n\n if n <= 1:\n return n\n \n # If the value is already computed, return it\n if n in memo:\n return memo[n]\n \n # Recursive calls for the equation f(n) = max( (f(n/2) + f(n/3) + f(n/4) + f(n/5)), n)\n memo[n] = max((helper(n//2) + helper(n//3) + helper(n//4) + helper(n//5)), n)\n \n # Return the computed value for n\n return memo[n]\n \n # Start the process with the given number n\n return helper(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n # Base case for recursion\n if n == 0:\n return 0\n \n # Calculate the maximum of the given equation and n itself\n max_sum = max((get_max_sum(n // 2) + get_max_sum(n // 3) + get_max_sum(n // 4) + get_max_sum(n // 5)), n)\n \n return max_sum", "matching_cluster_idx": 2}]}, "Mbpp/395": {"dps": 98.08429118773947, "dps_norm": 75.0, "pass@1": 100.0, "profiled": [{"solution": "def first_non_repeating_character(s):\n # Create a dictionary to store the count of each character\n char_count = {}\n \n # Count the occurrence of each character in the string\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n \n # Find the first character that has only one occurrence\n for char in s:\n if char_count[char] == 1:\n return char\n \n # If no non-repeating character was found, return None\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n \"\"\"\n Finds the first non-repeated character in the given string.\n \n :param s: Input string\n :return: The first non-repeated character or None if all characters repeat\n \"\"\"\n char_count = {}\n # Count occurrence of each character\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n # Find the first character that appears only once\n for char in s:\n if char_count[char] == 1:\n return char\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n \"\"\"\n Finds the first non-repeated character in a given string.\n \n Parameters:\n s (str): The string to search through.\n \n Returns:\n str or None: The first non-repeated character, or None if no such character exists.\n \"\"\"\n char_count = {}\n # Count the occurrence of each character\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n\n # Find the first character that appears only once\n for char in s:\n if char_count[char] == 1:\n return char\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n \"\"\"\n Finds the first non-repeated character in a given string.\n \n :param s: The input string\n :return: The first non-repeated character or None if all characters are repeated\n \"\"\"\n char_count = {}\n \n # Count the occurrence of each character in the string\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n \n # Find the first character that appears only once\n for char in s:\n if char_count[char] == 1:\n return char\n \n # Return None if no non-repeated character found\n return None", "matching_cluster_idx": 5}, {"solution": "from collections import OrderedDict\ndef first_non_repeating_character(s):\n # Dictionary to store character counts\n char_count = OrderedDict()\n \n # Count each character in the string\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n \n # Find the first character with a count of 1\n for char, count in char_count.items():\n if count == 1:\n return char\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n \"\"\"\n Finds the first non-repeated character in a given string.\n\n :param s: Input string\n :return: The first non-repeated character or None if all characters are repeated\n \"\"\"\n char_count = {}\n # Count occurrence of each character\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n \n # Find the first character that appears only once\n for char in s:\n if char_count[char] == 1:\n return char\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n \"\"\"\n Finds the first non-repeated character in a given string.\n \n :param s: String to search in\n :return: The first non-repeated character, or None if all characters are repeated.\n \"\"\"\n # Create a dictionary to keep track of the character counts\n char_count = {}\n \n # Counting the occurrence of each character\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n \n # Finding the first character with a count of 1\n for char in s:\n if char_count[char] == 1:\n return char\n \n # If no non-repeated character is found\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n # Create a dictionary to store the count of each character\n char_count = {}\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n \n # Iterate through the string to find the first character with a count of 1\n for char in s:\n if char_count[char] == 1:\n return char\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n # Create a dictionary to store the frequency of each character\n char_count = {}\n \n # Count the occurrences of each character in the string\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n \n # Find the first character that has only one occurrence\n for char in s:\n if char_count[char] == 1:\n return char\n \n # If no non-repeated character is found, return None\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n # Creating a dictionary to store the count of each character\n count = {}\n \n # Counting occurrences of each character\n for char in s:\n if char in count:\n count[char] += 1\n else:\n count[char] = 1\n \n # Finding the first character with count 1\n for char in s:\n if count[char] == 1:\n return char\n return None", "matching_cluster_idx": 5}, {"solution": "from collections import Counter\ndef first_non_repeating_character(s):\n \"\"\"\n Finds the first non-repeated character in a given string.\n \n :param s: Input string\n :return: The first non-repeated character or None if all characters repeat\n \"\"\"\n freq = Counter(s)\n for char in s:\n if freq[char] == 1:\n return char\n return None", "matching_cluster_idx": 5}, {"solution": "from collections import Counter\ndef first_non_repeating_character(s):\n \"\"\"\n This function finds the first non-repeated character in the given string.\n It uses the Counter class to count occurrences of each character, and then\n iterates through the string to find the first character with a count of 1.\n \n :param s: String to search\n :return: The first non-repeated character or None if there is no such character\n \"\"\"\n # Count the occurrences of each character in the string\n char_count = Counter(s)\n \n # Find and return the first character that has a count of 1\n for char in s:\n if char_count[char] == 1:\n return char\n \n # If no non-repeating character found, return None\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n # Create a dictionary to store character frequencies\n char_count = {}\n \n # Count the frequency of each character in the string\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n \n # Find the first character with a frequency of 1\n for char in s:\n if char_count[char] == 1:\n return char\n \n # If no non-repeated character is found, return None\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n \"\"\"\n This function finds the first non-repeated character in a given string.\n If all characters repeat, it returns None.\n \n :param s: String to search\n :return: The first non-repeating character or None\n \"\"\"\n char_count = {}\n \n # Count the occurrences of each character\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n \n # Find the first character that has only one occurrence\n for char in s:\n if char_count[char] == 1:\n return char\n \n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n # Dictionary to store character counts\n char_count = {}\n \n # Count occurrence of each character in the string\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n \n # Find the first non-repeated character\n for char in s:\n if char_count[char] == 1:\n return char\n \n # If no non-repeating character is found, return None\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n # Dictionary to store character counts\n char_count = {}\n \n # Count occurrences of each character\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n \n # Find the first non-repeated character\n for char in s:\n if char_count[char] == 1:\n return char\n \n # If there is no non-repeated character, return None\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n # Dictionary to store character frequency\n count = {}\n # Iterate through the string and update character count\n for char in s:\n if char in count:\n count[char] += 1\n else:\n count[char] = 1\n # Find the first non-repeating character\n for char in s:\n if count[char] == 1:\n return char\n # If there is no non-repeating character, return None\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n # Dictionary to store character counts\n char_count = {}\n \n # Count the occurrences of each character\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n \n # Find the first character that has only one occurrence\n for char in s:\n if char_count[char] == 1:\n return char\n \n # If no non-repeating character was found, return None\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n # Dictionary to store character frequencies\n freq = {}\n for char in s:\n if char in freq:\n freq[char] += 1\n else:\n freq[char] = 1\n \n # Finding the first non-repeated character\n for char in s:\n if freq[char] == 1:\n return char\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n \"\"\"\n Finds the first non-repeated character in a given string.\n \n Parameters:\n s (str): The input string.\n \n Returns:\n str or None: The first non-repeated character, or None if no such character exists.\n \"\"\"\n char_count = {}\n \n # Counting occurrences of each character\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n \n # Finding the first character with a count of 1\n for char in s:\n if char_count[char] == 1:\n return char\n \n return None", "matching_cluster_idx": 5}]}, "Mbpp/405": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def check_tuplex(test_tup, element):\n \"\"\"\n Check if the specified element exists in the given tuple.\n\n Parameters:\n test_tup (tuple): The tuple to search in.\n element: The element to search for in the tuple.\n\n Returns:\n bool: True if the element is found in the tuple, False otherwise.\n \"\"\"\n return element in test_tup", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(test_tup, element):\n \"\"\"\n Checks if the specified element exists in the given tuple.\n\n :param test_tup: Tuple to search within.\n :param element: Element to search for.\n :return: True if the element exists in the tuple, False otherwise.\n \"\"\"\n return element in test_tup", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(test_tup, element):\n \"\"\"\n Check if the element exists within the tuple.\n\n :param test_tup: tuple to search the element in\n :param element: element to search for\n :return: True if element is found, False otherwise\n \"\"\"\n return element in test_tup", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(test_tup, element):\n \"\"\"\n Function to check if an element exists within a tuple.\n\n Parameters:\n test_tup (tuple): The tuple to check.\n element (any): The element to look for within the tuple.\n\n Returns:\n bool: True if the element exists in the tuple, False otherwise.\n \"\"\"\n return element in test_tup", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(test_tup, element):\n \"\"\"\n Check if an element exists within a given tuple.\n\n Parameters:\n test_tup (tuple): The tuple to search within.\n element: The element to search for in the tuple.\n\n Returns:\n bool: True if the element is found in the tuple, False otherwise.\n \"\"\"\n return element in test_tup", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(test_tup, element):\n \"\"\"\n Check if the specified element exists within the given tuple.\n \n Parameters:\n test_tup (tuple): The tuple to be searched.\n element (any): The element to search for in the tuple.\n \n Returns:\n bool: True if the element is found in the tuple, False otherwise.\n \"\"\"\n return element in test_tup", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(test_tup, element):\n \"\"\"\n Check if the element exists in the given tuple.\n\n :param test_tup: The tuple to search in.\n :param element: The element to search for.\n :return: True if the element is found in the tuple, False otherwise.\n \"\"\"\n return element in test_tup", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(test_tup, element):\n \"\"\"\n Check if the element exists within the provided tuple.\n \n Parameters:\n test_tup (tuple): The tuple to search through.\n element (any): The element to find within the tuple.\n \n Returns:\n bool: True if the element is found in the tuple, False otherwise.\n \"\"\"\n return element in test_tup", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(test_tup, element):\n \"\"\"\n Check if an element exists within the given tuple.\n \n Parameters:\n test_tup (tuple): The tuple to check.\n element (Any): The element to look for within the tuple.\n \n Returns:\n bool: True if the element is found, False otherwise.\n \"\"\"\n return element in test_tup", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tup, element):\n # Check if the element exists in the tuple\n return element in tup", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(test_tup, element):\n \"\"\"\n Check if the element exists within the given tuple.\n\n Parameters:\n test_tup (tuple): The tuple to be searched.\n element (Any): The element to search for within the tuple.\n\n Returns:\n bool: True if the element is found in the tuple, False otherwise.\n \"\"\"\n return element in test_tup", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tup, element):\n # Check if the element exists in the tuple\n return element in tup", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(test_tup, element):\n \"\"\"\n Check if the given element exists in the tuple.\n\n Parameters:\n test_tup (tuple): The tuple to check.\n element: The element to look for in the tuple.\n\n Returns:\n bool: True if the element is found in the tuple, False otherwise.\n \"\"\"\n return element in test_tup", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(test_tup, element):\n \"\"\"\n This function checks if an element exists within a given tuple.\n\n Parameters:\n test_tup (tuple): The tuple to be searched.\n element (any): The element to search for in the tuple.\n\n Returns:\n bool: True if the element is found, False otherwise.\n \"\"\"\n return element in test_tup", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(test_tup, element):\n \"\"\"\n Check whether an element exists within a tuple.\n\n :param test_tup: The tuple to check.\n :param element: The element to look for in the tuple.\n :return: True if the element exists in the tuple, False otherwise.\n \"\"\"\n return element in test_tup", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(test_tup, element):\n \"\"\"\n Check if the element exists in the given tuple.\n \n Parameters:\n test_tup (tuple): The tuple to search.\n element: The element to search for in the tuple.\n \n Returns:\n bool: True if the element exists in the tuple, False otherwise.\n \"\"\"\n return element in test_tup", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tup, element):\n # Check if the element is in the tuple\n return element in tup", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(test_tup, element):\n \"\"\"\n Check if the specified element exists within the provided tuple.\n\n Parameters:\n test_tup (tuple): The tuple in which to search for the element.\n element (Any): The element to search for within the tuple.\n\n Returns:\n bool: True if the element exists in the tuple, False otherwise.\n \"\"\"\n # Check if the element is in the tuple\n return element in test_tup", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(test_tup, element):\n \"\"\"\n Check if an element exists in the given tuple.\n\n Parameters:\n test_tup (tuple): The tuple to be checked.\n element: The element to check for in the tuple.\n\n Returns:\n bool: True if the element exists in the tuple, False otherwise.\n \"\"\"\n return element in test_tup", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, element):\n # Check if the element is in the tuple\n return element in tuplex", "matching_cluster_idx": 3}]}, "Mbpp/414": {"dps": 77.79503105590062, "dps_norm": 83.33333333333333, "pass@1": 100.0, "profiled": [{"solution": "def overlapping(seq1, seq2):\n # Check if any value of seq1 is in seq2\n return any(x in seq2 for x in seq1)", "matching_cluster_idx": 7}, {"solution": "def overlapping(s1, s2):\n # Check if any element of s1 is in s2\n for i in s1:\n if i in s2:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(list1, list2):\n # Convert both lists to sets and check for intersection\n return bool(set(list1) & set(list2))", "matching_cluster_idx": 5}, {"solution": "def overlapping(seq1, seq2):\n # Check if any element in seq1 is in seq2\n return any(x in seq2 for x in seq1)", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n # Check if there is any common element between two sequences\n return any(elem in seq2 for elem in seq1)", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n # Convert the sequences to sets and find intersection\n return bool(set(seq1) & set(seq2))", "matching_cluster_idx": 5}, {"solution": "def overlapping(seq1, seq2):\n # Check if any element of seq1 is in seq2\n return any(x in seq2 for x in seq1)", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n # Check if any element in seq1 exists in seq2\n return any(elem in seq2 for elem in seq1)", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n # Check if any value in seq1 exists in seq2\n return any(value in seq2 for value in seq1)", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n # Check if any element in seq1 is also in seq2\n for item in seq1:\n if item in seq2:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n # Check if there's any common element in both sequences\n return any(x in seq2 for x in seq1)", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n # Check if any value in seq1 is present in seq2\n return any(value in seq2 for value in seq1)", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n # Check if any element in seq1 exists in seq2\n for item in seq1:\n if item in seq2:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n # Check if any element in seq1 exists in seq2\n return any(element in seq2 for element in seq1)", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n # Check if any element in seq1 is in seq2\n return any(element in seq2 for element in seq1)", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n # Check if any element in seq1 is also in seq2\n return any(element in seq2 for element in seq1)", "matching_cluster_idx": 7}, {"solution": "def overlapping(list1, list2):\n # Convert lists to sets and check intersection\n set1 = set(list1)\n set2 = set(list2)\n # If intersection is not empty, return True, else False\n if set1.intersection(set2):\n return True\n else:\n return False", "matching_cluster_idx": 5}, {"solution": "def overlapping(lst1, lst2):\n # Converting lists to sets and finding intersection\n return bool(set(lst1) & set(lst2))", "matching_cluster_idx": 5}, {"solution": "def overlapping(list1, list2):\n # Converting both lists to sets and checking intersection\n return bool(set(list1) & set(list2))", "matching_cluster_idx": 5}, {"solution": "def overlapping(seq1, seq2):\n # Check for any common element in both sequences\n for i in seq1:\n if i in seq2:\n return True\n return False", "matching_cluster_idx": 7}]}, "Mbpp/421": {"dps": 65.7201646090535, "dps_norm": 87.14285714285714, "pass@1": 100.0, "profiled": [{"solution": "def concatenate_tuple(tup):\n # Convert all elements in the tuple to strings and join them with the delimiter\n return '-'.join(map(str, tup))", "matching_cluster_idx": 6}, {"solution": "def concatenate_tuple(tup, delimiter='-'):\n \"\"\"\n Concatenate each element of a tuple into a string, separated by the delimiter.\n \n :param tup: Tuple of elements to concatenate\n :param delimiter: The delimiter to use between each element\n :return: Concatenated string\n \"\"\"\n # Convert each element in the tuple to a string and join them with the delimiter\n result = delimiter.join(map(str, tup))\n return result", "matching_cluster_idx": 6}, {"solution": "def concatenate_tuple(tup):\n # Convert each element in the tuple to a string and join them with a delimiter\n return '-'.join(str(element) for element in tup)", "matching_cluster_idx": 4}, {"solution": "def concatenate_tuple(input_tuple):\n # Convert tuple elements to string and join them using '-'\n result = '-'.join(map(str, input_tuple))\n return result", "matching_cluster_idx": 6}, {"solution": "def concatenate_tuple(tup):\n # Convert all elements of tuple to string and join with '-'\n return '-'.join(str(i) for i in tup)", "matching_cluster_idx": 4}, {"solution": "def concatenate_tuple(tup):\n # Convert each element of the tuple to string and join them with the delimiter '-'\n return '-'.join(str(element) for element in tup)", "matching_cluster_idx": 4}, {"solution": "def concatenate_tuple(tup):\n # Convert each element of the tuple to a string and join them with the delimiter '-'\n return '-'.join(map(str, tup))", "matching_cluster_idx": 6}, {"solution": "def concatenate_tuple(test_tup):\n # Convert each element in the tuple to a string and join them with a delimiter\n result = '-'.join(str(element) for element in test_tup)\n return result", "matching_cluster_idx": 4}, {"solution": "def concatenate_tuple(tup):\n # Convert all elements of the tuple to string and join them with '-'\n return '-'.join(map(str, tup))", "matching_cluster_idx": 5}, {"solution": "def concatenate_tuple(tup, delimiter='-'):\n \"\"\"\n Concatenates each element of the input tuple into a string, separated by the specified delimiter.\n \n Parameters:\n tup (tuple): The input tuple.\n delimiter (str): The delimiter to use for concatenation.\n \n Returns:\n str: A string with each element of the tuple concatenated, separated by the delimiter.\n \"\"\"\n # Convert all elements of the tuple to string and join with the delimiter\n result = delimiter.join(map(str, tup))\n return result", "matching_cluster_idx": 6}, {"solution": "def concatenate_tuple(input_tuple):\n # Convert each element in the tuple to string and join them with '-'\n result = '-'.join(map(str, input_tuple))\n return result", "matching_cluster_idx": 6}, {"solution": "def concatenate_tuple(tup, delimiter='-'):\n \"\"\"\n Concatenates each element of a tuple using a specified delimiter.\n \n :param tup: A tuple of elements to concatenate.\n :param delimiter: The delimiter used for concatenation.\n :return: A string with elements concatenated by the delimiter.\n \"\"\"\n # Convert all elements in the tuple to strings and join them with the delimiter\n return delimiter.join(map(str, tup))", "matching_cluster_idx": 5}, {"solution": "def concatenate_tuple(tup):\n # Convert all elements in the tuple to strings and join with the delimiter '-'\n return '-'.join(map(str, tup))", "matching_cluster_idx": 6}, {"solution": "def concatenate_tuple(tup):\n # Convert all elements to string and join them with the delimiter '-'\n return '-'.join(str(element) for element in tup)", "matching_cluster_idx": 4}, {"solution": "def concatenate_tuple(tup, delimiter='-'):\n \"\"\"\n Concatenate elements of a tuple using a specified delimiter.\n \n :param tup: Tuple of elements to concatenate\n :param delimiter: The delimiter to use for concatenation\n :return: A string with elements concatenated by the delimiter\n \"\"\"\n # Convert all elements to strings and join them with the delimiter\n return delimiter.join(map(str, tup))", "matching_cluster_idx": 5}, {"solution": "def concatenate_tuple(tup):\n # Convert all elements in the tuple to string and join them with '-'\n return '-'.join(str(element) for element in tup)", "matching_cluster_idx": 4}, {"solution": "def concatenate_tuple(tup):\n # Convert each element in the tuple to a string and then join them with a delimiter\n return '-'.join(map(str, tup))", "matching_cluster_idx": 5}, {"solution": "def concatenate_tuple(test_tup):\n # Convert each element of the tuple to a string and join with the delimiter '-'\n result = '-'.join(map(str, test_tup))\n return result", "matching_cluster_idx": 6}, {"solution": "def concatenate_tuple(test_tup):\n # Convert each element of the tuple to string and join them with the delimiter '-'\n result = '-'.join(map(str, test_tup))\n return result", "matching_cluster_idx": 6}, {"solution": "def concatenate_tuple(input_tuple):\n # Convert each element of the tuple to a string and then join them with the delimiter\n return '-'.join(str(element) for element in input_tuple)", "matching_cluster_idx": 4}]}, "Mbpp/424": {"dps": 51.624548736462096, "dps_norm": 80.0, "pass@1": 100.0, "profiled": [{"solution": "def extract_rear(tup):\n # Use list comprehension to iterate over each string in the tuple\n # and extract the last character.\n return [s[-1] for s in tup]", "matching_cluster_idx": 3}, {"solution": "def extract_rear(tup):\n # Extract the last character from each string in the tuple\n return [s[-1] for s in tup]", "matching_cluster_idx": 3}, {"solution": "def extract_rear(tup):\n # Extract the last character of each string in the tuple\n return [s[-1] for s in tup]", "matching_cluster_idx": 3}, {"solution": "def extract_rear(test):\n # Extract the last character from each string in the tuple\n result = [s[-1] for s in test]\n return result", "matching_cluster_idx": 3}, {"solution": "def extract_rear(tup):\n \"\"\"\n Extract the last character of each string in the given tuple.\n\n :param tup: Tuple containing strings.\n :return: List of the last characters of each string in the tuple.\n \"\"\"\n # Extracting the last character of each string in the tuple\n rear_elements = [s[-1] for s in tup]\n return rear_elements", "matching_cluster_idx": 3}, {"solution": "def extract_rear(tup):\n # Extract the last character of each string in the tuple\n return [s[-1] for s in tup]", "matching_cluster_idx": 3}, {"solution": "def extract_rear(input_tuple):\n # Extract the last character of each string in the tuple\n return [s[-1] for s in input_tuple]", "matching_cluster_idx": 3}, {"solution": "def extract_rear(test):\n # Extract the last character of each string in the tuple and return as a list\n result = [item[-1] for item in test]\n return result", "matching_cluster_idx": 3}, {"solution": "def extract_rear(input_tuple):\n \"\"\"\n Extracts the last character of each string within the given tuple.\n\n :param input_tuple: A tuple containing strings\n :return: A list containing the last character of each string in the tuple\n \"\"\"\n return [s[-1] for s in input_tuple]", "matching_cluster_idx": 3}, {"solution": "def extract_rear(test):\n # Extracting the last character of each string in the tuple\n result = [s[-1] for s in test]\n return result", "matching_cluster_idx": 3}, {"solution": "def extract_rear(tup):\n # Use list comprehension to extract the last character of each string in the tuple\n return [s[-1] for s in tup]", "matching_cluster_idx": 3}, {"solution": "def extract_rear(tup):\n \"\"\"\n Extracts the last character from each string in the given tuple.\n\n :param tup: A tuple containing strings.\n :return: A list containing the last character of each string in the tuple.\n \"\"\"\n # Extract the last character of each string in the tuple\n result = [item[-1] for item in tup]\n \n return result", "matching_cluster_idx": 3}, {"solution": "def extract_rear(test_tuple):\n # Extract the last character of each string in the tuple\n result = [sub[-1] for sub in test_tuple]\n return result", "matching_cluster_idx": 3}, {"solution": "def extract_rear(tup):\n # Extract the last character of each string in the tuple\n return [s[-1] for s in tup]", "matching_cluster_idx": 3}, {"solution": "def extract_rear(tup):\n # Extract the last character of each string in the tuple\n return [s[-1] for s in tup]", "matching_cluster_idx": 3}, {"solution": "def extract_rear(input_tuple):\n # Using list comprehension to extract the last character from each string in the tuple\n return [item[-1] for item in input_tuple]", "matching_cluster_idx": 3}, {"solution": "def extract_rear(tup):\n # Extract the last character of each string in the tuple\n return [s[-1] for s in tup]", "matching_cluster_idx": 3}, {"solution": "def extract_rear(test):\n # Extract the last character from each string in the tuple\n result = [item[-1] for item in test]\n return result", "matching_cluster_idx": 3}, {"solution": "def extract_rear(test):\n # Use a list comprehension to get the last character of each string in the tuple\n result = [s[-1] for s in test]\n return result", "matching_cluster_idx": 3}, {"solution": "def extract_rear(tup):\n # Extract the last character of each string in the tuple\n result = [s[-1] for s in tup]\n return result", "matching_cluster_idx": 3}]}, "Mbpp/425": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def count_element_in_list(lst, element):\n # Count how many sublists contain the element\n count = sum(element in sublist for sublist in lst)\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, element):\n # Count the number of sublists containing the specified element\n return sum(element in sublist for sublist in lst)", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, element):\n # Initialize counter to 0\n count = 0\n # Iterate through each sublist in the main list\n for sublist in lst:\n # Check if the element is in the current sublist\n if element in sublist:\n # Increment the counter if element is found\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, element):\n # Count how many sublists contain the specified element\n return sum(element in sublist for sublist in lst)", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, element):\n # Initialize a counter for the number of sublists containing the element\n count = 0\n \n # Iterate through each sublist in the list\n for sublist in lst:\n # Check if the element is present in the sublist\n if element in sublist:\n # Increment the counter if the element is found\n count += 1\n \n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, element):\n # Initialize counter\n count = 0\n \n # Iterate through each sublist\n for sublist in lst:\n # Check if the element is in the current sublist\n if element in sublist:\n count += 1\n \n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, element):\n # Count the number of sublists containing the specified element\n return sum(element in sublist for sublist in lst)", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, element):\n # Count how many sublists contain the specified element\n return sum(element in sublist for sublist in lst)", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, element):\n # Count how many sublists contain the element\n count = sum(element in sublist for sublist in lst)\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, element):\n count = 0\n for sublist in lst:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, element):\n # Count the number of sublists containing the element\n count = sum(element in sublist for sublist in lst)\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, element):\n # Count how many sublists contain the specified element\n return sum(element in sublist for sublist in lst)", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, element):\n # Count how many sublists contain the given element\n return sum(element in sublist for sublist in lst)", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, element):\n # Initialize a counter to keep track of the sublists containing the element\n count = 0\n \n # Iterate over each sublist in the main list\n for sublist in lst:\n # Check if the element is in the sublist\n if element in sublist:\n # Increment the count if the element is found in the sublist\n count += 1\n \n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, element):\n # Count the number of sublists containing the element\n return sum(element in sublist for sublist in lst)", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, element):\n # Count how many sublists contain the specified element\n return sum(element in sublist for sublist in lst)", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, element):\n # Count how many sublists contain the element\n count = sum(element in sublist for sublist in lst)\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, element):\n count = 0\n for sublist in lst:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, element):\n # Count the number of sublists containing the element\n return sum(element in sublist for sublist in lst)", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, element):\n # Count how many sublists contain the specified element\n return sum(1 for sublist in lst if element in sublist)", "matching_cluster_idx": 4}]}, "Mbpp/428": {"dps": 84.29752066115702, "dps_norm": 55.55555555555556, "pass@1": 100.0, "profiled": [{"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2\n \n # Start with a big gap, then reduce the gap\n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n # Shift earlier gap-sorted elements up until the correct location for arr[i] is found\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n # Put temp (the original arr[i]) in its correct location\n arr[j] = temp\n gap //= 2\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2\n\n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2\n\n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n\n arr[j] = temp\n gap //= 2\n\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n # Start with a big gap, then reduce the gap\n n = len(arr)\n gap = n//2\n \n # Do a gapped insertion sort for this gap size.\n # The first gap elements a[0..gap-1] are already in gapped order\n # keep adding one more element until the entire array is gap sorted\n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n # shift earlier gap-sorted elements up until the correct location for arr[i] is found\n j = i\n while j >= gap and arr[j-gap] > temp:\n arr[j] = arr[j-gap]\n j -= gap\n # put temp (the original arr[i]) in its correct location\n arr[j] = temp\n gap //= 2\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2\n \n # Start with a big gap, then reduce the gap\n while gap > 0:\n # Do a gapped insertion sort for this gap size.\n for i in range(gap, n):\n temp = arr[i]\n j = i\n # Shift earlier gap-sorted elements up until the correct location for arr[i] is found\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n \n # Put temp (the original arr[i]) in its correct location\n arr[j] = temp\n gap //= 2\n \n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n \"\"\"\n Sorts an array using the Shell sort algorithm.\n \n Shell sort is an in-place comparison sort. It can be seen as either a generalization of sorting by exchange (bubble sort)\n or sorting by insertion (insertion sort). The method starts by sorting pairs of elements far apart from each other,\n then progressively reducing the gap between elements to be compared.\n\n Parameters:\n arr (list): The list of elements to be sorted.\n\n Returns:\n list: The sorted list.\n \"\"\"\n n = len(arr)\n gap = n // 2 # Initial gap size\n\n # Start with a big gap, then reduce the gap\n while gap > 0:\n # Do a gapped insertion sort for this gap size.\n # The first gap elements arr[0..gap-1] are already in gapped order\n # keep adding one more element until the entire array is gap sorted\n for i in range(gap, n):\n temp = arr[i]\n\n # Shift earlier gap-sorted elements up until the correct location for arr[i] is found\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n\n # Put temp (the original arr[i]) in its correct location\n arr[j] = temp\n gap //= 2\n\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n # Start with a big gap, then reduce the gap\n n = len(arr)\n gap = n // 2\n \n # Do a gapped insertion sort for this gap size.\n # The first gap elements a[0..gap-1] are already in gapped order\n # keep adding one more element until the entire array is gap sorted\n while gap > 0:\n for i in range(gap, n):\n # add arr[i] to the elements that have been gap sorted\n # save arr[i] in temp and make a hole at position i\n temp = arr[i]\n \n # shift earlier gap-sorted elements up until the correct location for arr[i] is found\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n \n # put temp (the original arr[i]) in its correct location\n arr[j] = temp\n gap //= 2\n \n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2\n \n # Start with a big gap, then reduce the gap\n while gap > 0:\n # Do a gapped insertion sort for this gap size.\n for i in range(gap, n):\n # add arr[i] to the elements that have been gap sorted\n # save arr[i] in temp and make a hole at position i\n temp = arr[i]\n # shift earlier gap-sorted elements up until the correct location for arr[i] is found\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n # put temp (the original arr[i]) in its correct location\n arr[j] = temp\n gap //= 2\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n \"\"\"\n Sorts an array using the Shell sort algorithm.\n\n :param arr: List of integers to be sorted.\n :return: Sorted list of integers.\n \"\"\"\n n = len(arr)\n gap = n // 2\n\n # Start with a big gap, then reduce the gap\n while gap > 0:\n # Do a gapped insertion sort for this gap size.\n for i in range(gap, n):\n # add arr[i] to the elements that have been gap sorted\n # save arr[i] in temp and make a hole at position i\n temp = arr[i]\n\n # shift earlier gap-sorted elements up until the correct location for arr[i] is found\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n\n # put temp (the original arr[i]) in its correct location\n arr[j] = temp\n gap //= 2\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2\n \n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n \n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n \n arr[j] = temp\n gap //= 2\n \n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2\n \n # Start with a big gap, then reduce the gap\n while gap > 0:\n # Do a gapped insertion sort for this gap size.\n # The first gap elements arr[0..gap-1] are already in gapped order\n # keep adding one more element until the entire array is gap sorted\n for i in range(gap, n):\n temp = arr[i]\n # Shift earlier gap-sorted elements up until the correct location for arr[i] is found\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n # Put temp (the original arr[i]) in its correct location\n arr[j] = temp\n gap //= 2\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2\n\n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n # Start with a big gap, then reduce the gap\n n = len(arr)\n gap = n // 2\n\n # Do a gapped insertion sort for this gap size.\n # The first gap elements a[0..gap-1] are already in gapped order\n # keep adding one more element until the entire array is gap sorted\n while gap > 0:\n for i in range(gap, n):\n # add a[i] to the elements that have been gap sorted\n # save a[i] in temp and make a hole at position i\n temp = arr[i]\n # shift earlier gap-sorted elements up until the correct location for a[i] is found\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n # put temp (the original a[i]) in its correct location\n arr[j] = temp\n gap //= 2\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n # Start with a big gap, then reduce the gap\n n = len(arr)\n gap = n // 2\n \n # Do a gapped insertion sort for this gap size.\n # The first gap elements arr[0..gap-1] are already in gapped order\n # keep adding one more element until the entire array is gap sorted\n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n \n # Shift earlier gap-sorted elements up until the correct location for arr[i] is found\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n \n # Put temp (the original arr[i]) in its correct location\n arr[j] = temp\n gap //= 2\n \n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n \"\"\"\n Sorts an array using shell sort algorithm.\n \n :param arr: List of elements to be sorted\n :return: Sorted list\n \"\"\"\n n = len(arr)\n gap = n // 2\n \n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n \n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n \n arr[j] = temp\n gap //= 2\n \n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n \"\"\"\n Sorts the given array using the shell sort algorithm.\n \n :param arr: List of elements to be sorted\n :return: Sorted list\n \"\"\"\n n = len(arr)\n gap = n // 2\n \n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n \n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2\n\n # Start with a big gap, then reduce the gap\n while gap > 0:\n # Do a gapped insertion sort for this gap size.\n # The first gap elements a[0..gap-1] are already in gapped order\n # keep adding one more element until the entire array is gap sorted\n for i in range(gap, n):\n temp = arr[i]\n # shift earlier gap-sorted elements up until the correct location for a[i] is found\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n # put temp (the original a[i]) in its correct location\n arr[j] = temp\n gap //= 2\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2\n\n # Start with a big gap, then reduce the gap\n while gap > 0:\n # Do a gapped insertion sort for this gap size.\n # The first gap elements arr[0..gap-1] are already in gapped order\n # keep adding one more element until the entire array is gap sorted\n for i in range(gap, n):\n temp = arr[i]\n # Shift earlier gap-sorted elements up until the correct location for arr[i] is found\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n # Put temp (the original arr[i]) in its correct location\n arr[j] = temp\n gap //= 2\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2\n \n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2\n\n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n\n return arr", "matching_cluster_idx": 4}]}, "Mbpp/433": {"dps": 68.08510638297872, "dps_norm": 76.0, "pass@1": 100.0, "profiled": [{"solution": "def check_greater(arr, num):\n # Check if the number is greater than all elements in the array\n for element in arr:\n if num <= element:\n return False\n return True", "matching_cluster_idx": 3}, {"solution": "def check_greater(arr, num):\n # Check if all elements in the array are less than the given number\n return all(x < num for x in arr)", "matching_cluster_idx": 2}, {"solution": "def check_greater(arr, num):\n # Check if the number is greater than all elements in the array\n for element in arr:\n if num <= element:\n return False\n return True", "matching_cluster_idx": 3}, {"solution": "def check_greater(arr, num):\n # Check if the number is greater than all elements in the array\n for element in arr:\n if num <= element:\n return False\n return True", "matching_cluster_idx": 3}, {"solution": "def check_greater(arr, num):\n # Check if the number is greater than all elements in the array\n for i in arr:\n if num <= i:\n return False\n return True", "matching_cluster_idx": 3}, {"solution": "def check_greater(arr, num):\n # Check if the number is greater than any element in the array\n for i in arr:\n if num <= i:\n return False\n return True", "matching_cluster_idx": 3}, {"solution": "def check_greater(arr, num):\n # Check if the number is greater than all elements in the array\n for element in arr:\n if num <= element:\n return False\n return True", "matching_cluster_idx": 3}, {"solution": "def check_greater(arr, num):\n # Check if the number is greater than all elements in the array\n return all(num > x for x in arr)", "matching_cluster_idx": 2}, {"solution": "def check_greater(arr, num):\n # Check if all elements in the array are less than the given number\n for element in arr:\n if num <= element:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def check_greater(arr, num):\n # Check if the entered number is greater than all elements in the array\n return all(x < num for x in arr)", "matching_cluster_idx": 2}, {"solution": "def check_greater(arr, num):\n # Check if num is greater than all elements in the array\n for element in arr:\n if num <= element:\n return False\n return True", "matching_cluster_idx": 3}, {"solution": "def check_greater(arr, num):\n # Check if all elements in the array are less than the given number\n return all(x < num for x in arr)", "matching_cluster_idx": 2}, {"solution": "def check_greater(arr, num):\n # Check if the number is greater than all elements in the array\n for element in arr:\n if num <= element:\n return False\n return True", "matching_cluster_idx": 3}, {"solution": "def check_greater(arr, num):\n # Check if the given number is greater than all elements in the array\n for elem in arr:\n if num <= elem:\n return False\n return True", "matching_cluster_idx": 3}, {"solution": "def check_greater(arr, num):\n # Check if the given number is greater than all elements in the array\n for item in arr:\n if num <= item:\n return False\n return True", "matching_cluster_idx": 3}, {"solution": "def check_greater(arr, num):\n # Check if num is greater than all elements in the array\n return all(num > x for x in arr)", "matching_cluster_idx": 2}, {"solution": "def check_greater(arr, num):\n # Check if any number in the array is greater than or equal to num\n for element in arr:\n if element >= num:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def check_greater(arr, num):\n # Check if the number is greater than all elements in the array\n for i in arr:\n if num <= i:\n return False\n return True", "matching_cluster_idx": 3}, {"solution": "def check_greater(arr, num):\n # Check if the number is greater than all elements in the array\n for element in arr:\n if num <= element:\n return False\n return True", "matching_cluster_idx": 3}, {"solution": "def check_greater(arr, num):\n # Check if all elements in the array are less than the number\n return all(x < num for x in arr)", "matching_cluster_idx": 2}]}, "Mbpp/437": {"dps": 81.39705882352942, "dps_norm": 57.0, "pass@1": 93.0, "profiled": [{"solution": "def remove_odd(s):\n # New string to store the result\n result = ''\n # Iterate through the string, considering only even indices (0-based)\n for i in range(len(s)):\n if i % 2 != 0:\n result += s[i]\n return result", "matching_cluster_idx": 0}, {"solution": "def remove_odd(s):\n # Create a new string using characters at even indices\n return s[1::2]", "matching_cluster_idx": 4}, {"solution": "def remove_odd(input_string):\n # Initialize an empty result string\n result_string = \"\"\n \n # Loop through the string using enumerate to get both index and character\n for index, char in enumerate(input_string):\n # Check if the index is even (since string indices start at 0)\n if index % 2 != 0:\n # Append the character at the odd index to the result string\n result_string += char\n return result_string", "matching_cluster_idx": 0}, {"solution": "def remove_odd(s):\n # Using list comprehension to select even index characters only\n return ''.join([s[i] for i in range(len(s)) if i % 2 == 1])", "matching_cluster_idx": 1}, {"solution": "def remove_odd(s):\n # Select characters at even indices (0-based)\n return s[1::2]", "matching_cluster_idx": 3}, {"solution": "def remove_odd(s):\n # Create a new string with characters at even indices (0-based)\n return s[1::2]", "matching_cluster_idx": 3}, {"solution": "def remove_odd(s):\n # Keep characters at even indices (odd positions considering 1-based indexing)\n return s[1::2]", "matching_cluster_idx": 3}, {"solution": "def remove_odd(s):\n # Keep characters at even indices (considering the first position as 0)\n return s[1::2]", "matching_cluster_idx": 3}, {"solution": "def remove_odd(input_string):\n # Initialize an empty string to store the result\n result = \"\"\n \n # Loop through the string, starting from index 1 (2nd character) and take every 2nd character\n for i in range(1, len(input_string) + 1):\n if i % 2 == 0:\n result += input_string[i-1]\n \n return result", "matching_cluster_idx": 0}, {"solution": "def remove_odd(s):\n # Create a new string with characters at even indices of the original string\n result = ''.join([s[i] for i in range(len(s)) if i % 2 == 1])\n return result", "matching_cluster_idx": 1}, {"solution": "def remove_odd(input_string):\n # This list comprehension collects characters from the input_string\n # that are at even indices (0, 2, 4, ...) as Python uses 0-based indexing\n result = ''.join([input_string[i] for i in range(len(input_string)) if i % 2 == 1])\n return result", "matching_cluster_idx": 1}, {"solution": "def remove_odd(s):\n # Use list comprehension to select only even-indexed characters\n result = ''.join([s[i] for i in range(len(s)) if i % 2 == 1])\n return result", "matching_cluster_idx": 1}, {"solution": "def remove_odd(s):\n # Create a new string by keeping characters at even indices only\n return s[1::2]", "matching_cluster_idx": 3}, {"solution": "def remove_odd(s):\n # Create a string to hold even indexed characters\n result = ''\n # Loop through the string and add characters at even indices to the result\n for i in range(1, len(s) + 1):\n if i % 2 == 0:\n result += s[i-1]\n return result", "matching_cluster_idx": 0}, {"solution": "def remove_odd(s):\n # Keep characters at even indices (0-based, so these are actually odd positions in 1-based counting)\n return s[1::2]", "matching_cluster_idx": 3}, {"solution": "def remove_odd(s):\n # Collect every character with an even index (which corresponds to odd positions)\n return ''.join([s[i] for i in range(1, len(s), 2)])", "matching_cluster_idx": 2}, {"solution": "def remove_odd(s):\n # Keep only the characters at even indices (0-indexed)\n return s[1::2]", "matching_cluster_idx": 3}, {"solution": "def remove_odd(s):\n # Initialize an empty result string\n result = ''\n \n # Iterate over the string with index\n for index in range(len(s)):\n # Check if the index is even\n if index % 2 == 1:\n # Append character to result if index is odd (1-based thinking)\n result += s[index]\n \n # Return the result string with odd indexed characters\n return result", "matching_cluster_idx": 0}, {"solution": "def remove_odd(s):\n # Select every character at even index (0-based index)\n return s[1::2]", "matching_cluster_idx": 3}, {"solution": "def remove_odd(s):\n # Keep characters at even indices (odd positions if counting from 1)\n return s[1::2]", "matching_cluster_idx": 3}]}, "Mbpp/440": {"dps": null, "dps_norm": null, "pass@1": 3.0, "profiled": []}, "Mbpp/446": {"dps": 96.05911330049261, "dps_norm": 60.0, "pass@1": 36.0, "profiled": [{"solution": "def count_Occurrence(test_tup, test_list):\n # Initialize the count to zero\n res = 0\n # Loop through each element in the list and add its occurrence count in the tuple to res\n for ele in test_list:\n res += test_tup.count(ele)\n return res", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(test_tup, test_list):\n # Count the occurrences of each element in the tuple\n count = sum(test_tup.count(ele) for ele in test_list)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(test_tup, test_list):\n # Initialize the count to 0\n result = 0\n # Iterate over each element in the list\n for elem in test_list:\n # Add the number of occurrences of the element in the tuple to the result\n result += test_tup.count(elem)\n return result", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(test_tup, elements_list):\n # Count the occurrence of each element in the tuple\n occurrence = sum(test_tup.count(elem) for elem in elements_list)\n return occurrence", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(test_tup, test_list):\n # Count the occurrence of elements in the tuple that are present in the list\n res = sum(test_tup.count(ele) for ele in test_list)\n return res", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(test_tup, test_list):\n # Using sum and a generator expression to count occurrences\n res = sum(test_tup.count(ele) for ele in test_list)\n return res", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(test_tup, test_list):\n # Count the occurrence of elements from test_list in test_tup\n res = sum(test_tup.count(ele) for ele in test_list)\n return res", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(test_tup, test_list):\n # Count the occurrences of elements in the list within the tuple\n res = sum(test_tup.count(ele) for ele in test_list)\n return res", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(test_tup, test_list):\n # Initialize a counter to zero\n occurrence_count = 0\n \n # Iterate over each element in the test_list\n for element in test_list:\n # Add the count of each element in the test_tup to the occurrence_count\n occurrence_count += test_tup.count(element)\n \n return occurrence_count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(test_tup, test_list):\n # Count the occurrence of elements in the tuple that are also in the list\n res = sum(test_tup.count(ele) for ele in test_list)\n return res", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(test_tup, test_list):\n # Count the occurrences of each element from test_list in test_tup\n result = sum(test_tup.count(element) for element in test_list)\n return result", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(test_tup, test_list):\n # Count the occurrences of each element in the tuple\n occurrence_count = sum(test_tup.count(element) for element in test_list)\n return occurrence_count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(test_tup, test_list):\n # Initialize the count to 0\n res = 0\n # Iterate over each element in the provided list\n for ele in test_list:\n # Add the number of occurrences of the element in the tuple to the count\n res += test_tup.count(ele)\n return res", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(test_tup, test_list):\n # Count occurrences of each element in the list within the tuple\n res = sum(test_tup.count(ele) for ele in test_list)\n return res", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(test_tup, test_list):\n # Using sum and count method to calculate occurrences\n res = sum([test_tup.count(ele) for ele in test_list])\n return res", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(test_tup, test_list):\n # Initialize count to 0\n count = 0\n # Iterate over each element in the list\n for elem in test_list:\n # Add the count of the element in the tuple to the total count\n count += test_tup.count(elem)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(test_tup, test_list):\n # Count the occurrence of each element in the tuple\n occurrence_dict = {elem: test_tup.count(elem) for elem in test_tup}\n # Sum the counts for the elements in the provided list\n result = sum(occurrence_dict[elem] for elem in test_list if elem in occurrence_dict)\n return result", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(test_tup, test_list):\n # Initialize count to 0\n res = 0\n # Iterate over the elements of the list\n for ele in test_list:\n # Add the count of each element in the tuple to the total count\n res += test_tup.count(ele)\n return res", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(test_tup, test_list):\n # Initialize the occurrence counter to 0\n occurrence = 0\n \n # Iterate through each element in the list and count its occurrence in the tuple\n for element in test_list:\n occurrence += test_tup.count(element)\n \n return occurrence", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(test_tup, test_list):\n # Initialize a counter to zero\n count = 0\n \n # Iterate over each element in the list\n for element in test_list:\n # Add the number of times the element occurs in the tuple to the counter\n count += test_tup.count(element)\n \n # Return the total count\n return count", "matching_cluster_idx": 2}]}, "Mbpp/451": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 43.0, "profiled": [{"solution": "def remove_whitespaces(input_string):\n # Remove all whitespaces from the input string\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string):\n # Using replace() to remove all whitespaces\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(s):\n # Removing all whitespaces from the string using replace\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(s):\n # Using replace() method to remove all whitespaces\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string):\n # Remove all whitespaces from the input_string\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(s):\n # Using replace() to remove all whitespaces\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string):\n # Replace all whitespace characters with no space, effectively removing them\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(s):\n # Using the replace method to remove all whitespace characters\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string):\n # Using str.replace() to remove all spaces\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string):\n # Using str.replace() to remove all spaces from the input string\n no_space_string = input_string.replace(\" \", \"\")\n # Returning the string without spaces\n return no_space_string", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(s):\n # Using join and replace to remove all whitespaces\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string):\n # Using the replace method to remove whitespaces\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string):\n # Remove all whitespaces from the string using replace method\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string):\n # Using str.replace() method to replace spaces with no space\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(s):\n # Using str.replace method to remove all whitespaces\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(s):\n # Using replace to remove all whitespaces\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string):\n # Using replace to remove all spaces\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_str):\n # Using the built-in str.replace() method to remove whitespaces\n return input_str.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string):\n # Removing all whitespaces from the input string\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(s):\n # Using the string replace method to remove all whitespace characters\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}]}, "Mbpp/456": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def reverse_string_list(lst):\n # Reverse each string in the list using a list comprehension\n reversed_list = [s[::-1] for s in lst]\n return reversed_list", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(input_list):\n # Reverse each string in the list using list comprehension\n reversed_list = [s[::-1] for s in input_list]\n return reversed_list", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n # Reverse each string in the list\n return [s[::-1] for s in string_list]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(lst):\n # Using list comprehension to reverse each string in the list\n return [s[::-1] for s in lst]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(lst):\n # Use list comprehension to reverse each string in the list\n reversed_list = [s[::-1] for s in lst]\n return reversed_list", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(lst):\n # Reverse each string in the list\n return [s[::-1] for s in lst]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(lst):\n # Reverse each string in the list and return the new list\n return [s[::-1] for s in lst]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(input_list):\n # List comprehension to reverse each string in the list\n reversed_list = [s[::-1] for s in input_list]\n return reversed_list", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(str_list):\n # Using list comprehension to reverse each string in the list\n reversed_list = [s[::-1] for s in str_list]\n return reversed_list", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(list_of_strings):\n # Reversing each string in the list\n reversed_list = [s[::-1] for s in list_of_strings]\n return reversed_list", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n # Using list comprehension to reverse each string in the list\n return [s[::-1] for s in string_list]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(input_list):\n # Use list comprehension to reverse each string in the list\n reversed_list = [s[::-1] for s in input_list]\n return reversed_list", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(list1):\n # Reverse each string in the list using list comprehension\n return [s[::-1] for s in list1]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n # Reverse each string in the list using list comprehension\n return [s[::-1] for s in string_list]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(lst):\n \"\"\"\n This function takes a list of strings and returns a new list with each string reversed.\n \n :param lst: List of strings to be reversed\n :return: A new list containing the reversed strings\n \"\"\"\n return [s[::-1] for s in lst]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n # Reverse each string in the list using list comprehension\n reversed_list = [s[::-1] for s in string_list]\n return reversed_list", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(lst):\n # Using list comprehension to reverse each string in the list\n reversed_list = [s[::-1] for s in lst]\n return reversed_list", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(input_list):\n # Using list comprehension to reverse each string in the list\n reversed_list = [s[::-1] for s in input_list]\n return reversed_list", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(lst):\n # Reverse each string in the list and return the new list\n return [s[::-1] for s in lst]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(input_list):\n # Reverse each string in the list\n return [s[::-1] for s in input_list]", "matching_cluster_idx": 4}]}, "Mbpp/460": {"dps": 81.82692307692308, "dps_norm": 93.0, "pass@1": 100.0, "profiled": [{"solution": "def Extract(lst):\n # Extract first element of each sublist using list comprehension\n return [sublist[0] for sublist in lst]", "matching_cluster_idx": 3}, {"solution": "def Extract(sublists):\n # Extract the first element of each sublist\n return [sublist[0] for sublist in sublists]", "matching_cluster_idx": 3}, {"solution": "def Extract(sublists):\n # List comprehension to get the first element of each sublist\n return [sublist[0] for sublist in sublists]", "matching_cluster_idx": 4}, {"solution": "def Extract(lst):\n # Extract first element of each sublist using list comprehension\n return [sub[0] for sub in lst]", "matching_cluster_idx": 3}, {"solution": "def Extract(sublists):\n # List comprehension to get the first element of each sublist\n return [sublist[0] for sublist in sublists]", "matching_cluster_idx": 4}, {"solution": "def Extract(lst):\n # Use list comprehension to extract the first element of each sublist\n return [sublist[0] for sublist in lst]", "matching_cluster_idx": 3}, {"solution": "def Extract(lst):\n # Extract the first element of each sublist\n return [sublist[0] for sublist in lst]", "matching_cluster_idx": 4}, {"solution": "def Extract(lst):\n # Use list comprehension to get the first element of each sublist\n return [sublist[0] for sublist in lst]", "matching_cluster_idx": 4}, {"solution": "def Extract(sublists):\n # Extract the first element from each sublist using list comprehension\n return [sublist[0] for sublist in sublists]", "matching_cluster_idx": 4}, {"solution": "def Extract(lst):\n # Extract the first element of each sublist\n return [sub[0] for sub in lst]", "matching_cluster_idx": 3}, {"solution": "def Extract(sublists):\n # Extract the first element of each sublist\n return [sublist[0] for sublist in sublists]", "matching_cluster_idx": 3}, {"solution": "def Extract(lst):\n # Extract the first element of each sublist in the list\n return [sublist[0] for sublist in lst]", "matching_cluster_idx": 4}, {"solution": "def Extract(lst):\n # Extract the first element of each sublist in the given list\n return [sublist[0] for sublist in lst]", "matching_cluster_idx": 4}, {"solution": "def Extract(lst):\n # Extract the first element of each sublist\n return [sublist[0] for sublist in lst]", "matching_cluster_idx": 4}, {"solution": "def Extract(lst):\n # Use list comprehension to get the first element of each sublist\n return [sub[0] for sub in lst]", "matching_cluster_idx": 4}, {"solution": "def Extract(sublists):\n # Use list comprehension to get the first element of each sublist\n return [sublist[0] for sublist in sublists]", "matching_cluster_idx": 4}, {"solution": "def Extract(lst):\n # Extracting the first element from each sublist\n result = [sublist[0] for sublist in lst]\n return result", "matching_cluster_idx": 4}, {"solution": "def Extract(sublists):\n # Extract the first element of each sublist using list comprehension\n return [sublist[0] for sublist in sublists]", "matching_cluster_idx": 4}, {"solution": "def Extract(sublists):\n # Extract the first element from each sublist\n result = [sublist[0] for sublist in sublists]\n return result", "matching_cluster_idx": 3}, {"solution": "def Extract(lst):\n # Extract the first element of each sublist\n return [sublist[0] for sublist in lst]", "matching_cluster_idx": 4}]}, "Mbpp/474": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def replace_char(input_string, old_char, new_char):\n # Replace all occurrences of old_char with new_char in input_string\n return input_string.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, old_char, new_char):\n # Replace all occurrences of old_char with new_char in s\n return s.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(string, old_char, new_char):\n # Replace all occurrences of old_char with new_char in the string\n new_string = string.replace(old_char, new_char)\n return new_string", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, old_char, new_char):\n # Replace occurrences of old_char with new_char in the string s\n return s.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(input_string, old_char, new_char):\n # Replace all occurrences of old_char with new_char in input_string\n replaced_string = input_string.replace(old_char, new_char)\n return replaced_string", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, old_char, new_char):\n # Replace occurrences of old_char with new_char in string s\n return s.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, old_char, new_char):\n # Replace all occurrences of old_char with new_char in the string s\n return s.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, old_char, new_char):\n # Replace all occurrences of old_char with new_char\n return s.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, old_char, new_char):\n # Replace occurrences of old_char with new_char in s\n return s.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(input_string, old_char, new_char):\n # Replace occurrences of old_char with new_char in input_string\n replaced_string = input_string.replace(old_char, new_char)\n return replaced_string", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, old_char, new_char):\n # Replace occurrences of old_char with new_char in the string s\n return s.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, old_char, new_char):\n # Replace all occurrences of old_char with new_char in the string s\n return s.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(string, old_char, new_char):\n # Replace occurrences of old_char with new_char in the string\n return string.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, old_char, new_char):\n # Replaces all occurrences of old_char with new_char in string s\n return s.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(string, old_char, new_char):\n # Replace occurrences of old_char with new_char in the string\n return string.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, old_char, new_char):\n # Replace occurrences of old_char with new_char in the string s\n return s.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(input_string, old_char, new_char):\n # Replace occurrences of old_char with new_char in the input_string\n return input_string.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, old_char, new_char):\n # Replace occurrences of old_char with new_char in s\n return s.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, old_char, new_char):\n # Replace all occurrences of old_char with new_char in the string s\n return s.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(input_string, old_char, new_char):\n # Replace all occurrences of old_char with new_char in input_string\n return input_string.replace(old_char, new_char)", "matching_cluster_idx": 6}]}, "Mbpp/476": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def big_sum(arr):\n # Find the minimum and maximum values in the array\n min_val = min(arr)\n max_val = max(arr)\n \n # Calculate the sum of the minimum and maximum values\n sum_val = min_val + max_val\n \n return sum_val", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n # Calculate the sum of the largest and smallest value in the array\n return min(arr) + max(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n # Find the minimum value in the array\n min_val = min(arr)\n # Find the maximum value in the array\n max_val = max(arr)\n # Return the sum of the minimum and maximum values\n return min_val + max_val", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n # Find the maximum and minimum values in the array\n max_val = max(arr)\n min_val = min(arr)\n # Return the sum of maximum and minimum values\n return max_val + min_val", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n # Find the smallest and largest elements in the array\n smallest = min(arr)\n largest = max(arr)\n \n # Return their sum\n return smallest + largest", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n # Check if the array is empty\n if not arr:\n return 0\n \n # Find the smallest and largest values in the array\n smallest = min(arr)\n largest = max(arr)\n \n # Return the sum of smallest and largest values\n return smallest + largest", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n # Calculate the sum of the largest and smallest value in the array\n return min(arr) + max(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n # Find the minimum and maximum values in the array\n min_val = min(arr)\n max_val = max(arr)\n \n # Return the sum of the minimum and maximum values\n return min_val + max_val", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n # Find the smallest value in the array\n min_val = min(arr)\n # Find the largest value in the array\n max_val = max(arr)\n # Return the sum of the smallest and largest values\n return min_val + max_val", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n # Find the minimum and maximum values in the array\n min_val = min(arr)\n max_val = max(arr)\n \n # Return the sum of the minimum and maximum values\n return min_val + max_val", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n # Find the minimum and maximum values in the array\n min_val = min(arr)\n max_val = max(arr)\n \n # Return their sum\n return min_val + max_val", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n # Find the minimum and maximum in the array\n min_val = min(arr)\n max_val = max(arr)\n \n # Return their sum\n return min_val + max_val", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n # Find the maximum value in the array\n max_val = max(arr)\n # Find the minimum value in the array\n min_val = min(arr)\n # Return the sum of the maximum and minimum values\n return max_val + min_val", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n # Find the maximum value in the array\n max_val = max(arr)\n # Find the minimum value in the array\n min_val = min(arr)\n # Return the sum of max and min values\n return max_val + min_val", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n # Find the minimum value in the array\n min_value = min(arr)\n # Find the maximum value in the array\n max_value = max(arr)\n # Return the sum of the minimum and maximum values\n return min_value + max_value", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n # Check if the list is empty\n if not arr:\n return 0\n # Find the largest and smallest value in the list\n max_val = max(arr)\n min_val = min(arr)\n # Return the sum of the largest and smallest value\n return max_val + min_val", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n # Find the minimum value in the array\n min_val = min(arr)\n # Find the maximum value in the array\n max_val = max(arr)\n # Return the sum of the minimum and maximum values\n return min_val + max_val", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n # Find the minimum and maximum values in the array\n min_val = min(arr)\n max_val = max(arr)\n \n # Return the sum of the largest and smallest values\n return min_val + max_val", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n # Calculate the sum of the largest and smallest values in the array\n return max(arr) + min(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n # Find the minimum value in the array\n min_val = min(arr)\n # Find the maximum value in the array\n max_val = max(arr)\n # Return the sum of the minimum and maximum value\n return min_val + max_val", "matching_cluster_idx": 5}]}, "Mbpp/477": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def is_lower(s):\n # Convert the given string to lower case\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n # Convert the given string to lower case\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n # Convert string s to lower case\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n # Convert the given string to lower case\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n # Convert the input string to lowercase\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n # Convert the given string to lowercase\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n # Convert the string to lower case\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n # Convert the entire string to lower case\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n # Convert the string to lower case\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n # Convert the string to lowercase\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n # Convert the given string to lower case\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n # Convert the string to lowercase\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n # Convert the input string to lower case\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n # Convert the given string to lower case\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n # Convert the given string to lowercase\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n # Convert the entire string to lower case\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n # Convert the string to lower case\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n # Convert the string s to lower case\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n # Convert the given string to lower case\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n # Converts the entire string to lower case\n return s.lower()", "matching_cluster_idx": 4}]}, "Mbpp/563": {"dps": 85.24590163934427, "dps_norm": 81.81818181818181, "pass@1": 100.0, "profiled": [{"solution": "import re\ndef extract_values(s):\n # Find all occurrences of text enclosed in double quotes\n return re.findall(r'\"(.*?)\"', s)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(input_string):\n # Using regular expression to find all values enclosed in double quotes\n return re.findall(r'\"(.*?)\"', input_string)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(input_string):\n # Using regex to find all values within quotes\n return re.findall(r'\"(.*?)\"', input_string)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(input_string):\n # Regular expression to find all text within double quotes\n pattern = '\"(.*?)\"'\n # Find all non-overlapping matches of the pattern in the string\n matches = re.findall(pattern, input_string)\n return matches", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(s):\n # Use regex to find all patterns enclosed in double quotes\n matches = re.findall(r'\"(.*?)\"', s)\n return matches", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(input_string):\n # Use regular expression to find all substrings enclosed in double quotes\n result = re.findall(r'\"(.*?)\"', input_string)\n return result", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(s):\n # Use regular expression to find all patterns enclosed by double quotes\n return re.findall(r'\"(.*?)\"', s)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(s):\n # Use regex to find all occurrences of text between double quotes\n return re.findall(r'\"(.*?)\"', s)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(input_string):\n # Use regular expression to find all quoted values\n return re.findall(r'\\\"(.*?)\\\"', input_string)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(input_string):\n # Using regular expression to find all strings enclosed in double quotes\n matches = re.findall(r'\"(.*?)\"', input_string)\n return matches", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(input_string):\n # Using regular expression to find all patterns within double quotes\n matches = re.findall(r'\"(.*?)\"', input_string)\n return matches", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(input_string):\n # Regular expression to find patterns within double quotes\n pattern = '\"(.*?)\"'\n # Find all non-overlapping matches of pattern in the string\n matches = re.findall(pattern, input_string)\n return matches", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(input_string):\n # Use regular expression to find all matches of text enclosed in double quotes\n return re.findall(r'\"(.*?)\"', input_string)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(input_string):\n # Use regular expression to find all matches between quotation marks\n matches = re.findall(r'\"(.*?)\"', input_string)\n return matches", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(input_string):\n # Regular expression to find text within double quotes\n pattern = '\"(.*?)\"'\n # Find all matches in the input string\n matches = re.findall(pattern, input_string)\n return matches", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(input_string):\n # Regular expression to find all text within quotes\n pattern = '\"(.*?)\"'\n # Find all non-overlapping matches of the pattern in the string\n matches = re.findall(pattern, input_string)\n return matches", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(s):\n # Regular expression to find all the values within quotation marks\n return re.findall(r'\"(.*?)\"', s)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(s):\n # Using regular expression to find all substrings enclosed in double quotes\n return re.findall(r'\"(.*?)\"', s)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(s):\n # Regular expression pattern to match text within double quotes\n pattern = '\"(.*?)\"'\n # Find all occurrences of the pattern\n matches = re.findall(pattern, s)\n return matches", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(input_string):\n # Use regular expression to find all strings enclosed in double quotes\n result = re.findall(r'\"(.*?)\"', input_string)\n return result", "matching_cluster_idx": 8}]}, "Mbpp/572": {"dps": 95.30864197530865, "dps_norm": 86.42857142857142, "pass@1": 91.0, "profiled": [{"solution": "def two_unique_nums(lst):\n # Count the occurrence of each number\n count = {}\n for num in lst:\n if num in count:\n count[num] += 1\n else:\n count[num] = 1\n \n # Collect numbers that occur exactly once\n result = [num for num, cnt in count.items() if cnt == 1]\n return result", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(lst):\n # Calculate the frequency of each item in the list\n freq = {}\n for item in lst:\n freq[item] = freq.get(item, 0) + 1\n \n # Extract items that have frequency of 1\n result = [item for item, count in freq.items() if count == 1]\n \n return result", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(lst):\n # Find the count of each element in the list\n counts = {}\n for num in lst:\n if num in counts:\n counts[num] += 1\n else:\n counts[num] = 1\n \n # Select elements that have a count of 1\n return [num for num in lst if counts[num] == 1]", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(lst):\n # Create a dictionary to hold the frequency of each element\n frequency = {}\n for num in lst:\n if num in frequency:\n frequency[num] += 1\n else:\n frequency[num] = 1\n \n # Collect elements that appear exactly once\n result = [num for num, count in frequency.items() if count == 1]\n \n return result", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(nums):\n # Create a dictionary to count occurrences of each number\n count_dict = {}\n for num in nums:\n if num in count_dict:\n count_dict[num] += 1\n else:\n count_dict[num] = 1\n \n # Collect numbers that appear exactly once\n result = [num for num, count in count_dict.items() if count == 1]\n \n return result", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(lst):\n # Count the occurrences of each number\n num_counts = {}\n for num in lst:\n num_counts[num] = num_counts.get(num, 0) + 1\n \n # Collect numbers that occur only once\n unique_nums = [num for num, count in num_counts.items() if count == 1]\n \n return unique_nums", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(lst):\n # Count the frequency of each element\n from collections import Counter\n freq = Counter(lst)\n \n # Extract elements that occur exactly once\n unique = [item for item, count in freq.items() if count == 1]\n \n return unique", "matching_cluster_idx": 6}, {"solution": "def two_unique_nums(lst):\n # Count the occurrence of each number in the list\n counts = {}\n for num in lst:\n if num in counts:\n counts[num] += 1\n else:\n counts[num] = 1\n \n # Create a new list with numbers that appear only once\n unique_nums = [num for num in lst if counts[num] == 1]\n return unique_nums", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(lst):\n # Calculate the occurrence of each number\n num_counts = {}\n for num in lst:\n if num in num_counts:\n num_counts[num] += 1\n else:\n num_counts[num] = 1\n \n # Filter out the numbers that appear more than once\n unique_nums = [num for num, count in num_counts.items() if count == 1]\n \n return unique_nums", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(arr):\n # Create a dictionary to count occurrences of each element\n count_dict = {}\n for num in arr:\n if num in count_dict:\n count_dict[num] += 1\n else:\n count_dict[num] = 1\n \n # Collect numbers that appear exactly once in the input list\n unique_nums = [num for num, count in count_dict.items() if count == 1]\n \n return unique_nums", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(nums):\n # Count the occurrences of each number\n num_counts = {}\n for num in nums:\n if num in num_counts:\n num_counts[num] += 1\n else:\n num_counts[num] = 1\n \n # Collect numbers that occur exactly once\n unique_nums = [num for num in nums if num_counts[num] == 1]\n \n return unique_nums", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(lst):\n # Create a dictionary to hold the count of each number\n count_dict = {}\n for num in lst:\n if num in count_dict:\n count_dict[num] += 1\n else:\n count_dict[num] = 1\n \n # Filter out the numbers that appear more than once\n result = [num for num, count in count_dict.items() if count == 1]\n return result", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(lst):\n # Create a dictionary to count occurrences of each number\n num_count = {}\n for num in lst:\n if num in num_count:\n num_count[num] += 1\n else:\n num_count[num] = 1\n \n # Append numbers that appear exactly once to the result list\n result = [num for num, count in num_count.items() if count == 1]\n return result", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(lst):\n # Dictionary to hold the count of each element\n count = {}\n for num in lst:\n if num in count:\n count[num] += 1\n else:\n count[num] = 1\n \n # List to hold the unique elements that appear exactly once\n result = [num for num in count if count[num] == 1]\n \n return result", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(nums):\n # Calculate the occurrence of each number\n num_count = {}\n for num in nums:\n if num in num_count:\n num_count[num] += 1\n else:\n num_count[num] = 1\n \n # Extract numbers that occur exactly once\n result = [num for num, count in num_count.items() if count == 1]\n \n return result", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(lst):\n # Create a dictionary to keep track of counts\n count_dict = {}\n # Iterate through the list to populate the dictionary\n for num in lst:\n if num in count_dict:\n count_dict[num] += 1\n else:\n count_dict[num] = 1\n \n # Use list comprehension to filter out numbers that appear only once\n return [num for num, count in count_dict.items() if count == 1]", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(lst):\n # Count the occurrences of each item in the list\n count_dict = {}\n for item in lst:\n if item in count_dict:\n count_dict[item] += 1\n else:\n count_dict[item] = 1\n \n # Append items to the result list if they occur only once\n result = [item for item, count in count_dict.items() if count == 1]\n return result", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(lst):\n # Count the occurrences of each number in the list\n count_dict = {}\n for num in lst:\n if num in count_dict:\n count_dict[num] += 1\n else:\n count_dict[num] = 1\n \n # Create a list of numbers that occur exactly once\n unique_nums = [num for num, count in count_dict.items() if count == 1]\n \n return unique_nums", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(lst):\n # Count the occurrence of each element in the list\n element_count = {}\n for num in lst:\n if num in element_count:\n element_count[num] += 1\n else:\n element_count[num] = 1\n \n # Return elements that appear only once\n return [num for num in lst if element_count[num] == 1]", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(nums):\n # Create a dictionary to count occurrences of each number\n num_count = {}\n for num in nums:\n if num in num_count:\n num_count[num] += 1\n else:\n num_count[num] = 1\n \n # Collect numbers that occur only once\n unique_nums = [num for num, count in num_count.items() if count == 1]\n \n return unique_nums", "matching_cluster_idx": 5}]}, "Mbpp/578": {"dps": 96.82539682539682, "dps_norm": 72.72727272727273, "pass@1": 100.0, "profiled": [{"solution": "def interleave_lists(list1, list2, list3):\n # Interleave the three lists into one using zip and list comprehension\n interleaved = [item for sublist in zip(list1, list2, list3) for item in sublist]\n return interleaved", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(lst1, lst2, lst3):\n # Use zip to pair elements from each list and then flatten the pairs into a single list\n result = [item for sublist in zip(lst1, lst2, lst3) for item in sublist]\n return result", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(list1, list2, list3):\n # Interleave the three lists using zip and list comprehension\n interleaved = [item for sublist in zip(list1, list2, list3) for item in sublist]\n return interleaved", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(list1, list2, list3):\n # Use zip to combine the lists and a list comprehension to flatten the list of tuples\n interleaved = [item for tuple_items in zip(list1, list2, list3) for item in tuple_items]\n return interleaved", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(list1, list2, list3):\n # Use zip to interleave the elements from each list and then flatten the resulting list of tuples\n interleaved_list = [item for sublist in zip(list1, list2, list3) for item in sublist]\n return interleaved_list", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(lst1, lst2, lst3):\n # Use zip to interleave and list comprehension to flatten\n interleaved_list = [item for sublist in zip(lst1, lst2, lst3) for item in sublist]\n return interleaved_list", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(list1, list2, list3):\n # Interleave the three lists by concatenating corresponding elements\n interleaved = [val for pair in zip(list1, list2, list3) for val in pair]\n return interleaved", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(list1, list2, list3):\n # Combine the three lists into a single flat list by interleaving\n interleaved_list = [item for sublist in zip(list1, list2, list3) for item in sublist]\n return interleaved_list", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(list1, list2, list3):\n # Combine the lists by zipping them together and then flattening the result\n interleaved = [item for sublist in zip(list1, list2, list3) for item in sublist]\n return interleaved", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(list1, list2, list3):\n # Combine the lists by zipping them together and then flattening the result\n interleaved = [item for sublist in zip(list1, list2, list3) for item in sublist]\n return interleaved", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(list1, list2, list3):\n # Zip the lists together, transpose with *, and flatten\n result = [item for sublist in zip(list1, list2, list3) for item in sublist]\n return result", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(list1, list2, list3):\n # Use zip to pair elements from each list and then flatten the result\n return [item for sublist in zip(list1, list2, list3) for item in sublist]", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(list1, list2, list3):\n # Interleave the three lists\n interleaved = [item for sublist in zip(list1, list2, list3) for item in sublist]\n return interleaved", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(list1, list2, list3):\n # Combine the elements from each list by zipping them together and then flattening the result\n interleaved = [item for sublist in zip(list1, list2, list3) for item in sublist]\n return interleaved", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(list1, list2, list3):\n # Zip the lists together and flatten the result\n interleaved_list = [item for sublist in zip(list1, list2, list3) for item in sublist]\n return interleaved_list", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(list1, list2, list3):\n # Using zip to interleave and list comprehension to flatten the output\n interleaved = [item for sublist in zip(list1, list2, list3) for item in sublist]\n return interleaved", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(list1, list2, list3):\n # Interleave the three lists into a single flat list\n interleaved_list = [item for sublist in zip(list1, list2, list3) for item in sublist]\n return interleaved_list", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(list1, list2, list3):\n # Combine the lists by zipping them together, then flatten the result\n interleaved = [item for sublist in zip(list1, list2, list3) for item in sublist]\n return interleaved", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(list1, list2, list3):\n # Interleave the elements of all three lists and flatten the result\n interleaved = [item for sublist in zip(list1, list2, list3) for item in sublist]\n return interleaved", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(lst1, lst2, lst3):\n # Interleave the three lists into a single flat list\n result = [item for sublist in zip(lst1, lst2, lst3) for item in sublist]\n return result", "matching_cluster_idx": 7}]}, "Mbpp/586": {"dps": 98.83040935672514, "dps_norm": 87.5, "pass@1": 98.0, "profiled": [{"solution": "def split_Arr(arr, n):\n # Split the array into two parts\n first_part = arr[:n]\n second_part = arr[n:]\n # Concatenate the second part with the first part\n result = second_part + first_part\n return result", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n # Split the array into two parts\n first_part = arr[:n]\n second_part = arr[n:]\n \n # Add the first part to the end of the second part\n result = second_part + first_part\n return result", "matching_cluster_idx": 6}, {"solution": "def split_Arr(lst, n):\n # Split the list into two parts at the nth element\n first_part = lst[:n]\n second_part = lst[n:]\n \n # Add the first part to the end of the second part\n result = second_part + first_part\n return result", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n # Split the array at the nth element and rearrange\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n # Split the array into two halves at the nth element\n first_half = arr[:n]\n second_half = arr[n:]\n \n # Concatenate the second half with the first half\n result = second_half + first_half\n return result", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n # Splitting the list into two parts\n first_part = arr[:n]\n second_part = arr[n:]\n \n # Adding the first part to the end of the second part\n result = second_part + first_part\n return result", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n # Split the list into two parts and concatenate them in reversed order\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n # Splitting the array at nth element\n first_part = arr[:n]\n second_part = arr[n:]\n \n # Adding the first part to the end of the second part\n result = second_part + first_part\n return result", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n # Split the array into two halves at the nth element\n first_half = arr[:n]\n second_half = arr[n:]\n \n # Combine the second half with the first half\n return second_half + first_half", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n # Split the array into two parts\n first_part = arr[:n]\n second_part = arr[n:]\n \n # Add the first part to the end of the second part\n new_arr = second_part + first_part\n return new_arr", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n # Split the list into two parts at the nth element\n first_part = arr[:n]\n second_part = arr[n:]\n \n # Concatenate the two parts, with the second part first\n result = second_part + first_part\n return result", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n # Slicing the list to get the two parts\n first_part = arr[:n]\n second_part = arr[n:]\n # Combining the two parts in reverse order\n return second_part + first_part", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n # Splitting the list at nth element and swapping the parts\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(lst, n):\n # Split the list at the nth element and concatenate the parts\n return lst[n:] + lst[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n # Split the array into two parts\n first_part = arr[:n]\n second_part = arr[n:]\n \n # Join the two parts, swapping their order\n result = second_part + first_part\n return result", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n # Split the array into two parts\n first_part = arr[:n]\n second_part = arr[n:]\n \n # Add the first part to the end of the second part\n result = second_part + first_part\n return result", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n # Splitting the array into two halves\n first_half = arr[:n]\n second_half = arr[n:]\n \n # Combining the two halves in desired order\n result = second_half + first_half\n return result", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n # Split the list into two parts at the nth element\n first_part = arr[:n]\n second_part = arr[n:]\n \n # Concatenate the second part with the first part and return\n return second_part + first_part", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n # Split the list into two parts and then concatenate them in reverse order\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n # Split the list into two parts\n first_part = arr[:n]\n second_part = arr[n:]\n \n # Add the first part to the end of the second part\n result = second_part + first_part\n return result", "matching_cluster_idx": 6}]}, "Mbpp/587": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 98.0, "profiled": [{"solution": "def list_tuple(input_list):\n # Convert the list to a tuple\n result = tuple(input_list)\n return result", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n # Convert the list to a tuple using the tuple constructor\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n # Convert the list to a tuple\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n # Convert list to tuple\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n # Convert the list to a tuple\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(input_list):\n # Convert the list to a tuple\n result_tuple = tuple(input_list)\n return result_tuple", "matching_cluster_idx": 3}, {"solution": "def list_tuple(input_list):\n # Convert the list to a tuple\n result = tuple(input_list)\n return result", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n # Convert the list to a tuple\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n # Convert the list to a tuple\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n # Convert the list to a tuple\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n # Convert list to tuple\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n # Convert the list to a tuple\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n # Convert the list to a tuple\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n # Convert the list to a tuple\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n # Convert list to tuple using the tuple() function\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(input_list):\n # Convert list to tuple\n return tuple(input_list)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(input_list):\n # Convert list to tuple\n result = tuple(input_list)\n return result", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n # Convert the list to a tuple using the tuple constructor\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(input_list):\n # Convert the list to a tuple using the tuple() constructor\n return tuple(input_list)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n # Convert the list to a tuple\n return tuple(lst)", "matching_cluster_idx": 3}]}, "Mbpp/588": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def big_diff(nums):\n # Find the maximum and minimum values in the list\n max_val = max(nums)\n min_val = min(nums)\n \n # Calculate the difference between the max and min values\n diff = max_val - min_val\n \n return diff", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n # Find the maximum and minimum values in the list\n max_val = max(nums)\n min_val = min(nums)\n \n # Calculate the difference\n difference = max_val - min_val\n \n return difference", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n # Find the maximum and minimum values in the list\n max_val = max(nums)\n min_val = min(nums)\n \n # Calculate the difference\n diff = max_val - min_val\n \n return diff", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n # Calculate the difference between max and min values in the list\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n # Find the difference between the maximum and minimum value in the list\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n # Find the maximum and minimum values in the list\n max_num = max(nums)\n min_num = min(nums)\n \n # Calculate the difference between the max and min values\n diff = max_num - min_num\n \n return diff", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n # Find the maximum and minimum value in the list\n max_val = max(nums)\n min_val = min(nums)\n \n # Return the difference between the maximum and minimum value\n return max_val - min_val", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n # Find the difference between the largest and smallest value in the list\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n # Find the largest and smallest value in the list\n max_val = max(nums)\n min_val = min(nums)\n \n # Calculate the difference between the largest and smallest value\n return max_val - min_val", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n # Calculate the difference between max and min value in the list\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n # Find the maximum value in the list\n max_value = max(nums)\n # Find the minimum value in the list\n min_value = min(nums)\n # Return the difference between the max and min values\n return max_value - min_value", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n # Find the maximum and minimum values in the list\n max_num = max(nums)\n min_num = min(nums)\n \n # Calculate the difference\n diff = max_num - min_num\n \n return diff", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n # Calculate the difference between the max and min values in the list\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n # Find the largest and smallest value in the list\n max_val = max(nums)\n min_val = min(nums)\n \n # Return the difference\n return max_val - min_val", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n # Check if the list is empty\n if not nums:\n return 0\n # Find the difference between the maximum and minimum values\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n # Find the maximum value in the list\n max_val = max(nums)\n # Find the minimum value in the list\n min_val = min(nums)\n # Calculate the difference\n diff = max_val - min_val\n return diff", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n # Find the maximum value in the list\n max_val = max(nums)\n # Find the minimum value in the list\n min_val = min(nums)\n # Calculate the difference between the max and min value\n return max_val - min_val", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n # Find the maximum value in the list\n max_val = max(nums)\n # Find the minimum value in the list\n min_val = min(nums)\n # Calculate the difference\n diff = max_val - min_val\n return diff", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n # Find the maximum and minimum values in the list\n max_val = max(nums)\n min_val = min(nums)\n \n # Calculate the difference\n difference = max_val - min_val\n \n return difference", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n # Find the difference between the largest and smallest values\n return max(nums) - min(nums)", "matching_cluster_idx": 5}]}, "Mbpp/592": {"dps": 59.866666666666674, "dps_norm": 51.0, "pass@1": 51.0, "profiled": [{"solution": "from math import comb\ndef sum_Of_product(n):\n # Calculate the sum of product of consecutive binomial coefficients\n total_sum = sum(comb(n, k) * comb(n, k+1) for k in range(n))\n return total_sum", "matching_cluster_idx": 4}, {"solution": "from math import comb\ndef sum_Of_product(n):\n # Calculate the sum of the product of consecutive binomial coefficients\n total_sum = sum(comb(n, k) * comb(n, k+1) for k in range(n))\n return total_sum", "matching_cluster_idx": 5}, {"solution": "from math import comb\ndef sum_Of_product(n):\n # Calculate the sum of the product of consecutive binomial coefficients\n return sum(comb(n, k) * comb(n, k+1) for k in range(n))", "matching_cluster_idx": 5}, {"solution": "from math import factorial\ndef sum_Of_product(n):\n # Initialize the sum to 0\n sum_product = 0\n \n # Calculate the sum of the product of consecutive binomial coefficients\n for r in range(n):\n # Calculate the binomial coefficients for the current value of r and r + 1\n product = (factorial(n) // (factorial(r) * factorial(n - r))) * \\\n (factorial(n) // (factorial(r + 1) * factorial(n - r - 1)))\n # Add the product to the sum\n sum_product += product\n \n return sum_product", "matching_cluster_idx": 2}, {"solution": "from math import comb\ndef sum_Of_product(n):\n # Initialize sum to store the cumulative product of binomial coefficients\n sum_product = 0\n # Iterate through the range to calculate the product of consecutive binomial coefficients\n for r in range(0, n + 1):\n product = comb(n, r) * comb(n, r + 1) if r + 1 <= n else 0\n sum_product += product\n return sum_product", "matching_cluster_idx": 4}, {"solution": "from math import comb\ndef sum_Of_product(n):\n # Initialize sum\n total_sum = 0\n \n # Calculate the sum of product of consecutive binomial coefficients\n for i in range(n+1):\n total_sum += comb(n, i) * comb(n, i+1)\n \n return total_sum", "matching_cluster_idx": 4}, {"solution": "def sum_Of_product(n):\n # Initialize the sum\n sum_of_products = 0\n \n # Calculate the sum of the product of consecutive binomial coefficients\n for r in range(n + 1):\n product = binomial_coefficient(n, r) * binomial_coefficient(n, r + 1) if r + 1 <= n else 0\n sum_of_products += product\n \n return sum_of_products\ndef binomial_coefficient(n, k):\n # Function to calculate the binomial coefficient C(n, k)\n if k > n:\n return 0\n if k == 0 or k == n:\n return 1\n k = min(k, n - k) # Take advantage of symmetry\n c = 1\n for i in range(k):\n c = c * (n - i) // (i + 1)\n return c", "matching_cluster_idx": 4}, {"solution": "from math import factorial\ndef sum_Of_product(n):\n # Initialize sum to 0\n sum_product = 0\n \n # Loop through the range of n\n for k in range(n):\n # Calculate the product of two consecutive binomial coefficients\n # binomial coefficient formula: C(n, k) = n! / (k!(n-k)!)\n # Here we calculate C(n, k) * C(n, k+1)\n product = (factorial(n) // (factorial(k) * factorial(n - k))) * \\\n (factorial(n) // (factorial(k + 1) * factorial(n - k - 1)))\n # Add product to sum_product\n sum_product += product\n \n return sum_product", "matching_cluster_idx": 2}, {"solution": "from math import comb\ndef sum_Of_product(n):\n # Initialize sum\n total_sum = 0\n \n # Calculate the sum of product of consecutive binomial coefficients\n for k in range(n + 1):\n total_sum += comb(n, k) * comb(n, k + 1)\n \n return total_sum", "matching_cluster_idx": 5}, {"solution": "from math import comb\ndef sum_Of_product(n):\n # Calculate the sum of the product of consecutive binomial coefficients\n total_sum = sum(comb(n, k) * comb(n, k+1) for k in range(n))\n return total_sum", "matching_cluster_idx": 5}, {"solution": "def sum_Of_product(n):\n # Calculate the sum of the product of consecutive binomial coefficients\n total_sum = 0\n for k in range(n):\n total_sum += (calculate_binomial_coeff(n, k) * calculate_binomial_coeff(n, k + 1))\n return total_sum\ndef calculate_binomial_coeff(n, k):\n # Calculate binomial coefficient C(n, k)\n result = 1\n for i in range(k):\n result *= (n - i)\n result //= (i + 1)\n return result", "matching_cluster_idx": 3}, {"solution": "from math import comb\ndef sum_Of_product(n):\n # Initialize sum\n total_sum = 0\n \n # Loop through each value from 0 to n-1\n for k in range(n):\n # Calculate the product of consecutive binomial coefficients\n product = comb(n, k) * comb(n, k + 1)\n # Add the product to the total sum\n total_sum += product\n \n return total_sum", "matching_cluster_idx": 5}, {"solution": "from math import factorial\ndef sum_Of_product(n):\n # Calculate the sum of the product of consecutive binomial coefficients\n sum = 0\n for i in range(n+1):\n # Calculate the binomial coefficient for (n choose i)\n binom_coeff = factorial(n) // (factorial(i) * factorial(n - i))\n # Calculate the binomial coefficient for (n choose i+1)\n if i+1 <= n:\n next_binom_coeff = factorial(n) // (factorial(i+1) * factorial(n - (i+1)))\n else:\n next_binom_coeff = 0\n # Add the product of the consecutive binomial coefficients to the sum\n sum += binom_coeff * next_binom_coeff\n return sum", "matching_cluster_idx": 1}, {"solution": "from functools import reduce\ndef sum_Of_product(n):\n # Calculate the sum of the product of consecutive binomial coefficients\n total_sum = 0\n for r in range(n + 1):\n # Calculate binomial coefficient for (n choose r) * (n choose r+1)\n # Using the formula C(n, k) = n! / (k! * (n-k)!)\n binom_coeff1 = binom_coeff(n, r)\n binom_coeff2 = binom_coeff(n, r + 1) if r + 1 <= n else 0\n total_sum += binom_coeff1 * binom_coeff2\n return total_sum\ndef binom_coeff(n, k):\n # Calculate binomial coefficient using factorial\n if k > n:\n return 0\n if k == 0 or k == n:\n return 1\n k = min(k, n - k) # Take advantage of symmetry\n num = reduce(lambda x, y: x*y, range(n, n-k, -1), 1)\n den = reduce(lambda x, y: x*y, range(1, k + 1), 1)\n return num // den", "matching_cluster_idx": 3}, {"solution": "from math import comb\ndef sum_Of_product(n):\n # Initialize sum\n total_sum = 0\n \n # Loop through to calculate the sum of products\n for k in range(n + 1):\n total_sum += comb(n, k) * comb(n, k + 1)\n \n return total_sum", "matching_cluster_idx": 5}, {"solution": "from math import comb\ndef sum_Of_product(n):\n # Initialize sum\n total_sum = 0\n \n # Calculate the sum of product of consecutive binomial coefficients\n for i in range(1, n + 1):\n total_sum += comb(n, i - 1) * comb(n, i)\n \n return total_sum", "matching_cluster_idx": 5}, {"solution": "from math import comb\ndef sum_Of_product(n):\n # Calculate the sum of the product of consecutive binomial coefficients\n total_sum = sum(comb(n, k) * comb(n, k + 1) for k in range(n))\n return total_sum", "matching_cluster_idx": 5}, {"solution": "from math import comb\ndef sum_Of_product(n):\n # Calculate the sum of the product of consecutive binomial coefficients\n total_sum = sum(comb(n, k) * comb(n, k+1) for k in range(n))\n return total_sum", "matching_cluster_idx": 5}, {"solution": "from math import comb\ndef sum_Of_product(n):\n # Calculate the sum of the product of consecutive binomial coefficients\n total_sum = sum(comb(n, k) * comb(n, k + 1) for k in range(n))\n return total_sum", "matching_cluster_idx": 5}, {"solution": "from math import comb\ndef sum_Of_product(n):\n # Calculate the sum of the product of consecutive binomial coefficients\n total_sum = sum(comb(n, k) * comb(n, k+1) for k in range(n))\n return total_sum", "matching_cluster_idx": 5}]}, "Mbpp/597": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 55.0, "profiled": [{"solution": "def find_kth(arr1, arr2, k):\n # Merge two sorted arrays\n merged_array = sorted(arr1 + arr2)\n \n # Since we are asked for kth element, we subtract 1\n # for zero-based indexing\n if k > 0 and k <= len(merged_array):\n return merged_array[k - 1]\n else:\n return None # or raise an error for invalid k", "matching_cluster_idx": 3}, {"solution": "def find_kth(nums1, nums2, k):\n \"\"\"\n Find the kth element from the union of two sorted arrays.\n\n :param nums1: First sorted array.\n :param nums2: Second sorted array.\n :param k: The kth position (1-based index) to find in the union of nums1 and nums2.\n :return: The kth element in the union of the two arrays.\n \"\"\"\n # Merge the arrays and sort (though the input arrays are already sorted, they need to be merged)\n merged = sorted(nums1 + nums2)\n \n # Retrieve the kth element (0-based index for list access)\n return merged[k - 1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(arr1, arr2, k):\n # Merge the two arrays\n merged_array = sorted(arr1 + arr2)\n # Get the kth element (adjusting for 0-index)\n return merged_array[k-1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(arr1, arr2, k):\n # Merge the two sorted arrays\n merged_array = sorted(arr1 + arr2)\n # Return the kth element\n return merged_array[k-1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(arr1, arr2, k):\n # Merge the two sorted arrays\n merged_arr = sorted(arr1 + arr2)\n # Return the k-th element\n return merged_arr[k-1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(arr1, arr2, k):\n # Merge two sorted arrays\n merged_array = sorted(arr1 + arr2)\n \n # Check if k is within the bounds of the merged array\n if k > 0 and k <= len(merged_array):\n # Return the (k-1)th element as list indices are zero-based\n return merged_array[k - 1]\n else:\n # Return None or raise an error if k is out of bounds\n return None", "matching_cluster_idx": 3}, {"solution": "def find_kth(nums1, nums2, k):\n \"\"\"\n Finds the kth element from two sorted arrays.\n\n :param nums1: First sorted array\n :param nums2: Second sorted array\n :param k: The 1-based index of the desired element\n :return: The kth element\n \"\"\"\n # Merge two sorted arrays\n merged = sorted(nums1 + nums2)\n # Check if k is within the bounds of the merged list\n if k > len(merged) or k <= 0:\n return None # or raise an error\n # Return the k-1 indexed element as list index starts from 0\n return merged[k - 1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(arr1, arr2, k):\n # Merge the two arrays and sort the merged array\n merged_array = sorted(arr1 + arr2)\n \n # Check if k is within the bounds of the merged array\n if k > 0 and k <= len(merged_array):\n # Return the (k-1)th element (since list indices are 0-based)\n return merged_array[k - 1]\n else:\n # If k is out of bounds, return an error message\n return \"Index out of bounds\"", "matching_cluster_idx": 3}, {"solution": "def find_kth(nums1, nums2, k):\n # Merge the two sorted arrays into one sorted array\n merged = sorted(nums1 + nums2)\n \n # Access the k-1 index to get the kth element\n # since array index starts at 0\n return merged[k-1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(arr1, arr2, k):\n # Merge the two arrays and sort the merged array\n merged_arr = sorted(arr1 + arr2)\n \n # Return the k-th element (index k-1 as indexing starts from 0)\n return merged_arr[k-1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(nums1, nums2, k):\n \"\"\"\n Finds the kth element in the combined sorted list of two sorted arrays.\n \n Parameters:\n nums1 (List[int]): First sorted list.\n nums2 (List[int]): Second sorted list.\n k (int): The 1-based index of the element to find.\n \n Returns:\n int: The kth element in the combined sorted list.\n \"\"\"\n # Merge the two arrays and sort\n merged_nums = sorted(nums1 + nums2)\n \n # Check if k is within the bounds of the merged list\n if k > 0 and k <= len(merged_nums):\n # Lists are 0-indexed, so the kth element is at position k-1\n return merged_nums[k - 1]\n else:\n raise IndexError(\"k is out of bounds of the merged list.\")", "matching_cluster_idx": 3}, {"solution": "def find_kth(nums1, nums2, k):\n # Merge the two sorted arrays\n merged_array = sorted(nums1 + nums2)\n # Return the kth element (adjusting for 0-indexing)\n return merged_array[k - 1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(arr1, arr2, k):\n # Merge the two sorted arrays into one sorted array\n merged_array = sorted(arr1 + arr2)\n \n # Find the kth element (adjusting for 0-index)\n return merged_array[k-1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(arr1, arr2, k):\n # Combine both sorted arrays\n merged_array = sorted(arr1 + arr2)\n # Return the kth element (considering 1-based index)\n return merged_array[k-1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(arr1, arr2, k):\n # Merge the two sorted arrays\n merged = sorted(arr1 + arr2)\n # Return the k-th element (adjusting for 0-indexing)\n return merged[k - 1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(arr1, arr2, k):\n \"\"\"\n Finds the kth element from two sorted arrays.\n \n Parameters:\n arr1 (List[int]): First sorted array.\n arr2 (List[int]): Second sorted array.\n k (int): The kth element to find.\n \n Returns:\n int: The kth element from the combined sorted arrays.\n \"\"\"\n # Merge two sorted arrays\n merged = sorted(arr1 + arr2)\n # Return the kth element (0-indexed, so k-1)\n return merged[k - 1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(nums1, nums2, k):\n \"\"\"\n Finds the k-th element from two sorted arrays.\n \n Args:\n nums1: List[int] -- first sorted array.\n nums2: List[int] -- second sorted array.\n k: int -- the k-th position (1-indexed) to find in the merged array.\n \n Returns:\n int -- the k-th element from the merged array.\n \"\"\"\n # Merge two sorted arrays\n merged = sorted(nums1 + nums2)\n # Return k-th element, adjusting for 0-indexing\n return merged[k - 1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(arr1, arr2, k):\n # Merge the two sorted arrays\n merged = sorted(arr1 + arr2)\n \n # Check if k is within the bounds of the merged array\n if k > 0 and k <= len(merged):\n # Return the k-th element (1-based index)\n return merged[k - 1]\n else:\n # Return None if k is out of bounds\n return None", "matching_cluster_idx": 3}, {"solution": "def find_kth(arr1, arr2, k):\n # Merge the two sorted arrays\n merged_arr = sorted(arr1 + arr2)\n # Find the kth element (0-based index)\n return merged_arr[k-1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(arr1, arr2, k):\n # Merge two sorted arrays\n merged_array = sorted(arr1 + arr2)\n \n # Since indexing in array starts from 0, subtract 1 from k\n # to get the correct index.\n return merged_array[k - 1]", "matching_cluster_idx": 3}]}, "Mbpp/604": {"dps": 95.22727272727273, "dps_norm": 99.0, "pass@1": 50.0, "profiled": [{"solution": "def reverse_words(s):\n # Split the string into words\n words = s.split()\n # Reverse the list of words\n words = words[::-1]\n # Join the words back into a single string\n reversed_s = ' '.join(words)\n return reversed_s", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n # Split the string into words, reverse the list of words and join them with spaces\n return ' '.join(s.split()[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(sentence):\n # Split the sentence into words, reverse the list of words, and join them with spaces\n words = sentence.split()\n reversed_words = ' '.join(reversed(words))\n return reversed_words", "matching_cluster_idx": 3}, {"solution": "def reverse_words(s):\n # Split the string by spaces, reverse the list of words, and join them back with spaces\n return ' '.join(s.split()[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(sentence):\n # Split the sentence into words, reverse the list of words, and join them back into a string\n return ' '.join(sentence.split()[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n # Split the string by spaces, reverse the list of words, and join them back with spaces\n return ' '.join(s.split()[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n # Split the string into words, reverse the list of words, and join them back with spaces\n return ' '.join(s.split()[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n # Split the string into words, reverse the list, and join back into a string\n return ' '.join(s.split()[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n # Split the string by spaces, reverse the list of words and join them back with spaces\n return ' '.join(s.split()[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n # Split the string by spaces, reverse the list of words and join them back with spaces\n return ' '.join(s.split()[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n # Split the string into words\n words = s.split()\n # Reverse the list of words\n reversed_words = words[::-1]\n # Join the words back into a string\n reversed_string = ' '.join(reversed_words)\n return reversed_string", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n # Split the string into words\n words = s.split()\n # Reverse the list of words\n words.reverse()\n # Join the words back into a string\n return ' '.join(words)", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n # Split the string by spaces, reverse the list of words and join them back with spaces\n return ' '.join(s.split()[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n # Split the string by spaces into words, reverse the list of words, and join them back with spaces\n return ' '.join(s.split()[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n # Split the string into words\n words = s.split()\n # Reverse the list of words\n reversed_words = words[::-1]\n # Join the words back into a string with spaces\n result = ' '.join(reversed_words)\n return result", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n # Split the string into words, reverse the list of words, and join them back into a string\n return ' '.join(s.split()[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n # Split the string into words, reverse the list of words, and join them back together with spaces\n return ' '.join(s.split()[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n # Split the string by spaces, reverse the list of words, and then join them back together with spaces\n return ' '.join(s.split()[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n # Split the string into words using space as a delimiter\n words = s.split()\n # Reverse the list of words\n reversed_words = words[::-1]\n # Join the words back into a string with spaces in between\n reversed_string = ' '.join(reversed_words)\n return reversed_string", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n # Split the string by spaces, reverse the list of words, and join them back with spaces\n return ' '.join(s.split()[::-1])", "matching_cluster_idx": 4}]}, "Mbpp/610": {"dps": 62.489343563512364, "dps_norm": 63.02521008403362, "pass@1": 17.0, "profiled": [{"solution": "def remove_kth_element(lst, k):\n # Adjust k to be zero-indexed\n k_adjusted = k - 1\n # Remove the k'th element by list slicing\n return lst[:k_adjusted] + lst[k_adjusted+1:]", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(lst, k):\n # If k is 0 or negative, the function won't remove any element\n if k <= 0:\n return lst\n # Remove the k'th element and return the new list\n return lst[:k-1] + lst[k:]", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(lst, k):\n # Remove the k'th element by slicing the list and excluding the k'th index\n return lst[:k-1] + lst[k:]", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(lst, k):\n # Copy the list to avoid modifying the original list\n new_list = lst[:]\n # Remove the k'th element (list is 0-indexed, so k-1 for k'th element)\n if k > 0 and k <= len(new_list):\n del new_list[k-1]\n return new_list", "matching_cluster_idx": 5}, {"solution": "def remove_kth_element(lst, k):\n # Remove the k'th element from the list\n return lst[:k-1] + lst[k:]", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(lst, k):\n # Create a new list without the k'th element\n return lst[:k-1] + lst[k:]", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(lst, k):\n # Remove the k'th element from the list\n return lst[:k-1] + lst[k:]", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(lst, k):\n # Remove the k'th element from the list\n return lst[:k-1] + lst[k:]", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(lst, k):\n # Remove the k'th element from the list\n # Note: Python list index starts at 0, so we remove the element at index (k-1)\n del lst[k-1]\n return lst", "matching_cluster_idx": 6}, {"solution": "def remove_kth_element(lst, k):\n # Remove the k'th element from the list\n return lst[:k-1] + lst[k:]", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(lst, k):\n # Copy the list to avoid modifying the original list\n new_lst = lst[:]\n # Remove the k'th element by index k-1\n new_lst.pop(k-1)\n return new_lst", "matching_cluster_idx": 5}, {"solution": "def remove_kth_element(lst, k):\n # Remove the k'th element by slicing the list\n return lst[:k-1] + lst[k:]", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(lst, k):\n # Adjust k to be zero-indexed\n k -= 1\n if 0 <= k < len(lst):\n # Remove the k'th element\n return lst[:k] + lst[k+1:]\n else:\n # If k is out of bounds, return the original list\n return lst", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(lst, k):\n # Remove the k'th element by slicing the list and excluding the k'th index\n return lst[:k-1] + lst[k:]", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(lst, k):\n # Remove the k'th element from the list\n return lst[:k-1] + lst[k:]", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(lst, k):\n # Remove the k'th element from the list\n # Note: Python uses 0-based indexing, so the k'th element is at index k-1\n return lst[:k-1] + lst[k:]", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(lst, k):\n # Remove the k'th element from the list\n return lst[:k-1] + lst[k:]", "matching_cluster_idx": 3}]}, "Mbpp/611": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 68.0, "profiled": [{"solution": "def max_of_nth(matrix, n):\n # Extract the n-th column from the matrix\n nth_column = [row[n] for row in matrix]\n # Return the maximum value from the n-th column\n return max(nth_column)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n # Ensure that the column index is within the bounds of the matrix\n if not all(len(row) > n for row in matrix):\n return None # Return None if column index is out of bounds\n \n # Extract the n'th column and find the maximum value\n nth_column = [row[n] for row in matrix]\n return max(nth_column)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n # Extract the n'th column from the matrix\n nth_column = [row[n] for row in matrix]\n # Find and return the max value in the n'th column\n return max(nth_column)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n # Extract the n'th column from the matrix and find the max value\n return max(row[n] for row in matrix)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n # Extract the nth column from the matrix\n nth_column = [row[n] for row in matrix]\n # Return the maximum value in the nth column\n return max(nth_column)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n # Extract the n'th column values and find the max\n return max(row[n] for row in matrix)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n # Extract the n-th column from the matrix and find the max value\n return max(row[n] for row in matrix)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n # Extract the n-th column and find the maximum value\n return max(row[n] for row in matrix)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n # Get the n'th column from the matrix\n nth_column = [row[n] for row in matrix]\n # Return the maximum value of the n'th column\n return max(nth_column)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n # Ensure the nth column exists in the matrix\n if n >= len(matrix[0]):\n return None # or raise an error, depending on how you want to handle invalid n values\n # Use a list comprehension to collect n'th column items and find the max\n return max(row[n] for row in matrix)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n # Initialize max_value with the first element of the n-th column\n max_value = matrix[0][n]\n # Iterate through each row in the matrix\n for row in matrix:\n # Update max_value if the current element in the n-th column is greater\n if row[n] > max_value:\n max_value = row[n]\n return max_value", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n # Extract the n'th column from the matrix\n nth_column = [row[n] for row in matrix]\n # Return the max value of the n'th column\n return max(nth_column)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n # Extract the n'th column from the matrix and find the max value\n return max(row[n] for row in matrix)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n # Extract the nth column from the matrix and find the max value\n return max(row[n] for row in matrix)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n # Get the nth column from the matrix\n nth_column = [row[n] for row in matrix]\n # Return the maximum value from the nth column\n return max(nth_column)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n # Ensure the column index is within the bounds of the matrix\n if not all(len(row) > n for row in matrix):\n return None # Return None if the column index is out of bounds\n \n # Use a generator expression to fetch the nth element from each row and find the max\n max_value = max(row[n] for row in matrix)\n return max_value", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n # Check if the matrix is empty or n is out of bounds\n if not matrix or n >= len(matrix[0]):\n return None\n # Use list comprehension to get the nth column and find the maximum value\n return max(row[n] for row in matrix)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n # Ensure the column index n is within the bounds of the matrix\n if not all(len(row) > n for row in matrix):\n return None # Return None if the column index is out of bounds\n \n # Use list comprehension to gather elements of the nth column and find the max\n return max(row[n] for row in matrix)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n # Return the maximum value from the n'th column of the matrix\n return max(row[n] for row in matrix)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n # Extract the n-th column values\n nth_column_values = [row[n] for row in matrix]\n # Return the maximum value of the n-th column\n return max(nth_column_values)", "matching_cluster_idx": 5}]}, "Mbpp/631": {"dps": 48.40277777777777, "dps_norm": 43.125, "pass@1": 61.0, "profiled": [{"solution": "def replace_spaces(s):\n # Replace whitespace with underscore and vice versa\n return ''.join('_' if c == ' ' else ' ' if c == '_' else c for c in s)", "matching_cluster_idx": 3}, {"solution": "def replace_spaces(s):\n # Replace underscores with a placeholder\n s = s.replace('_', 'TEMP_PLACEHOLDER')\n # Replace spaces with underscores\n s = s.replace(' ', '_')\n # Replace placeholder with spaces\n s = s.replace('TEMP_PLACEHOLDER', ' ')\n return s", "matching_cluster_idx": 4}, {"solution": "def replace_spaces(s):\n # Replace whitespaces with underscores and vice versa\n result = []\n for char in s:\n if char == ' ':\n result.append('_')\n elif char == '_':\n result.append(' ')\n else:\n result.append(char)\n return ''.join(result)", "matching_cluster_idx": 3}, {"solution": "def replace_spaces(s):\n \"\"\"\n Replaces all whitespaces in the string with underscores and vice versa.\n \n :param s: Input string to process.\n :return: Modified string with whitespaces replaced by underscores and vice versa.\n \"\"\"\n result = ''\n for char in s:\n if char == ' ':\n result += '_'\n elif char == '_':\n result += ' '\n else:\n result += char\n return result", "matching_cluster_idx": 2}, {"solution": "def replace_spaces(s):\n # Replace spaces with underscores and vice versa\n result = ''\n for char in s:\n if char == ' ':\n result += '_'\n elif char == '_':\n result += ' '\n else:\n result += char\n return result", "matching_cluster_idx": 2}, {"solution": "def replace_spaces(s):\n \"\"\"\n This function takes a string and replaces all whitespace characters with underscores\n and all underscores with whitespace characters.\n\n :param s: The input string.\n :return: The modified string with spaces and underscores swapped.\n \"\"\"\n # Replace all spaces with a temporary placeholder that is unlikely to appear in input\n temp_str = s.replace(' ', '\\t')\n \n # Replace all underscores with spaces\n temp_str = temp_str.replace('_', ' ')\n \n # Replace the temporary placeholder with underscores\n return temp_str.replace('\\t', '_')", "matching_cluster_idx": 4}, {"solution": "def replace_spaces(s):\n \"\"\"\n Replace whitespaces with underscores and vice versa in the input string.\n\n :param s: String in which replacements are to be made.\n :return: Modified string with replacements.\n \"\"\"\n modified_string = \"\"\n for char in s:\n if char == ' ':\n modified_string += '_'\n elif char == '_':\n modified_string += ' '\n else:\n modified_string += char\n return modified_string", "matching_cluster_idx": 2}, {"solution": "def replace_spaces(s):\n # Replace spaces with underscores and vice versa\n result = ''\n for char in s:\n if char == ' ':\n result += '_'\n elif char == '_':\n result += ' '\n else:\n result += char\n return result", "matching_cluster_idx": 2}, {"solution": "def replace_spaces(s):\n \"\"\"\n This function takes a string s and replaces all the whitespaces with underscores and all the underscores with whitespaces.\n \n :param s: A string to be transformed.\n :return: A transformed string with whitespaces and underscores swapped.\n \"\"\"\n transformed_string = \"\"\n for char in s:\n if char == \" \":\n transformed_string += \"_\"\n elif char == \"_\":\n transformed_string += \" \"\n else:\n transformed_string += char\n return transformed_string", "matching_cluster_idx": 2}, {"solution": "def replace_spaces(s):\n \"\"\"\n This function takes a string s and replaces all whitespace characters with underscores\n and all underscores with whitespace characters.\n \n :param s: The input string to be modified.\n :return: A string with whitespaces replaced by underscores and underscores replaced by whitespaces.\n \"\"\"\n modified_str = ''\n for char in s:\n if char == ' ':\n modified_str += '_'\n elif char == '_':\n modified_str += ' '\n else:\n modified_str += char\n return modified_str", "matching_cluster_idx": 2}, {"solution": "def replace_spaces(s):\n \"\"\"\n Replaces all whitespaces with underscores and all underscores with whitespaces in the given string.\n\n :param s: The input string to process.\n :return: A new string with whitespaces replaced by underscores and vice versa.\n \"\"\"\n return s.replace(\" \", \"temp\").replace(\"_\", \" \").replace(\"temp\", \"_\")", "matching_cluster_idx": 3}, {"solution": "def replace_spaces(s):\n # Replace whitespaces with underscores and vice versa\n result = ''\n for char in s:\n if char == ' ':\n result += '_'\n elif char == '_':\n result += ' '\n else:\n result += char\n return result", "matching_cluster_idx": 2}, {"solution": "def replace_spaces(s):\n # Replace spaces with underscores and vice versa\n result = ''\n for char in s:\n if char == ' ':\n result += '_'\n elif char == '_':\n result += ' '\n else:\n result += char\n return result", "matching_cluster_idx": 2}, {"solution": "def replace_spaces(s):\n # Replace spaces with underscores and underscores with spaces\n result = []\n for char in s:\n if char == ' ':\n result.append('_')\n elif char == '_':\n result.append(' ')\n else:\n result.append(char)\n return ''.join(result)", "matching_cluster_idx": 3}, {"solution": "def replace_spaces(s):\n # Replace whitespaces with underscores and vice versa\n result = ''\n for char in s:\n if char == ' ':\n result += '_'\n elif char == '_':\n result += ' '\n else:\n result += char\n return result", "matching_cluster_idx": 2}, {"solution": "def replace_spaces(s):\n # Replace whitespace with underscore and underscore with whitespace\n result = []\n for char in s:\n if char == ' ':\n result.append('_')\n elif char == '_':\n result.append(' ')\n else:\n result.append(char)\n return ''.join(result)", "matching_cluster_idx": 3}, {"solution": "def replace_spaces(s):\n # Replace spaces with underscores and vice versa\n result = ''\n for char in s:\n if char == ' ':\n result += '_'\n elif char == '_':\n result += ' '\n else:\n result += char\n return result", "matching_cluster_idx": 2}, {"solution": "def replace_spaces(s):\n # Replace spaces with underscores and vice versa\n result = ''\n for char in s:\n if char == ' ':\n result += '_'\n elif char == '_':\n result += ' '\n else:\n result += char\n return result", "matching_cluster_idx": 2}, {"solution": "def replace_spaces(s):\n # Replace whitespaces with underscores and vice versa\n modified_string = ''\n for char in s:\n if char == ' ':\n modified_string += '_'\n elif char == '_':\n modified_string += ' '\n else:\n modified_string += char\n return modified_string", "matching_cluster_idx": 2}, {"solution": "def replace_spaces(s):\n # Replace spaces with underscores and vice versa\n modified_str = ''\n for char in s:\n if char == ' ':\n modified_str += '_'\n elif char == '_':\n modified_str += ' '\n else:\n modified_str += char\n return modified_str", "matching_cluster_idx": 2}]}, "Mbpp/632": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def move_zero(arr):\n # List to keep track of non-zero elements\n non_zero = []\n # Counter for zero elements\n zero_count = 0\n \n # Separate zeroes and non-zeroes\n for num in arr:\n if num == 0:\n zero_count += 1\n else:\n non_zero.append(num)\n \n # Add zeroes at the end of the non_zero list\n non_zero.extend([0] * zero_count)\n \n return non_zero", "matching_cluster_idx": 6}, {"solution": "def move_zero(arr):\n # Count the zeroes in the array\n zero_count = arr.count(0)\n # Remove all zeroes from the array\n arr = [i for i in arr if i != 0]\n # Extend the array with the number of zeroes removed\n arr.extend([0] * zero_count)\n return arr", "matching_cluster_idx": 6}, {"solution": "def move_zero(lst):\n # List to keep track of non-zero elements\n non_zero = [i for i in lst if i != 0]\n # Count the zeroes in the list\n zero_count = lst.count(0)\n # Extend the non-zero list with the zeroes counted\n non_zero.extend([0] * zero_count)\n return non_zero", "matching_cluster_idx": 6}, {"solution": "def move_zero(arr):\n # Count the number of zeros in the list\n zero_count = arr.count(0)\n \n # Filter out the zeros from the list\n arr = [i for i in arr if i != 0]\n \n # Append the number of zeros counted at the end of the list\n arr.extend([0] * zero_count)\n \n return arr", "matching_cluster_idx": 6}, {"solution": "def move_zero(arr):\n # List to hold non-zero elements\n non_zero = []\n # Count the number of zero elements\n zero_count = arr.count(0)\n \n # Append all non-zero elements to the non_zero list\n for num in arr:\n if num != 0:\n non_zero.append(num)\n \n # Extend the non_zero list with zeros at the end\n non_zero.extend([0] * zero_count)\n \n return non_zero", "matching_cluster_idx": 6}, {"solution": "def move_zero(arr):\n # List to store non-zero elements\n non_zero = []\n # Counter for zero elements\n zero_count = arr.count(0)\n \n # Iterate through the list and append non-zero elements to non_zero\n for num in arr:\n if num != 0:\n non_zero.append(num)\n \n # Append zeroes to the end of the non_zero list\n non_zero.extend([0] * zero_count)\n \n return non_zero", "matching_cluster_idx": 6}, {"solution": "def move_zero(arr):\n # List to store non-zero elements\n non_zero = [i for i in arr if i != 0]\n # List to count the zeros\n zero = [i for i in arr if i == 0]\n # Concatenating non-zero elements with zeros at the end\n return non_zero + zero", "matching_cluster_idx": 6}, {"solution": "def move_zero(arr):\n # List to store non-zero elements\n non_zero = []\n # Counter for zero elements\n zero_count = arr.count(0)\n \n # Loop through array and add non-zero elements to the new list\n for num in arr:\n if num != 0:\n non_zero.append(num)\n \n # Append zeros at the end of the non_zero list\n non_zero.extend([0]*zero_count)\n \n return non_zero", "matching_cluster_idx": 6}, {"solution": "def move_zero(arr):\n # List comprehension that creates a new list with all non-zero values\n non_zero = [i for i in arr if i != 0]\n # Append zeros to the non_zero list based on the number of zeros in the original list\n non_zero.extend([0] * arr.count(0))\n return non_zero", "matching_cluster_idx": 6}, {"solution": "def move_zero(arr):\n # List comprehension that separates non-zero and zero elements\n return [i for i in arr if i != 0] + [i for i in arr if i == 0]", "matching_cluster_idx": 6}, {"solution": "def move_zero(arr):\n # Count the number of zeros in the list\n zero_count = arr.count(0)\n \n # Remove all zeros from the list\n arr = [i for i in arr if i != 0]\n \n # Append zeros at the end\n arr.extend([0] * zero_count)\n \n return arr", "matching_cluster_idx": 6}, {"solution": "def move_zero(lst):\n # List comprehension to first collect all non-zero elements\n non_zeros = [i for i in lst if i != 0]\n # Count the number of zeros in the original list and append that many zeros to the non_zeros list\n zeros = [0] * (len(lst) - len(non_zeros))\n # Return the combined list of non-zeros followed by zeros\n return non_zeros + zeros", "matching_cluster_idx": 6}, {"solution": "def move_zero(arr):\n # List to store non-zero elements\n non_zero = [i for i in arr if i != 0]\n # Count the number of zero elements in the array\n zero_count = arr.count(0)\n # Extend the non-zero list with the zero_count number of zeroes\n non_zero.extend([0] * zero_count)\n return non_zero", "matching_cluster_idx": 6}, {"solution": "def move_zero(arr):\n # List to hold non-zero elements\n non_zero = [i for i in arr if i != 0]\n # Count the number of zeroes\n zero_count = arr.count(0)\n # Append zeroes at the end of the non_zero list\n non_zero.extend([0] * zero_count)\n return non_zero", "matching_cluster_idx": 6}, {"solution": "def move_zero(arr):\n # Initialize a list to hold the result\n result = []\n # Count the zeroes in the array\n zero_count = arr.count(0)\n # Iterate over the array\n for num in arr:\n # If the number is not zero, append it to the result\n if num != 0:\n result.append(num)\n # Extend the result list with the number of zeroes counted\n result.extend([0]*zero_count)\n return result", "matching_cluster_idx": 6}, {"solution": "def move_zero(arr):\n # List to store non-zero elements\n non_zero = [i for i in arr if i != 0]\n # List to store zeroes\n zeroes = [0] * arr.count(0)\n # Combine non-zero elements and zeroes\n result = non_zero + zeroes\n return result", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n # Count the number of zeros in the list\n zero_count = nums.count(0)\n # Filter out zeros and create a new list\n non_zero = [num for num in nums if num != 0]\n # Extend the non-zero list with zeros\n non_zero.extend([0] * zero_count)\n return non_zero", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n # List to store non-zero elements\n non_zero = [num for num in nums if num != 0]\n # Count the zeroes in the original list\n zero_count = nums.count(0)\n # Extend the non_zero list with zeroes\n non_zero.extend([0] * zero_count)\n return non_zero", "matching_cluster_idx": 6}, {"solution": "def move_zero(arr):\n # List to store non-zero elements\n non_zero = [i for i in arr if i != 0]\n # Count the number of zeros in the original list\n zero_count = arr.count(0)\n # Append zeros to the end of the non_zero list\n non_zero.extend([0]*zero_count)\n return non_zero", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n # Non-zero elements are collected here\n non_zero = [num for num in nums if num != 0]\n \n # Zero elements are collected here\n zero = [num for num in nums if num == 0]\n \n # Combine non-zero elements with zero elements\n return non_zero + zero", "matching_cluster_idx": 6}]}, "Mbpp/633": {"dps": 90.44715447154472, "dps_norm": 56.666666666666664, "pass@1": 69.0, "profiled": [{"solution": "def pair_xor_Sum(arr, n):\n # Initialize result \n result = 0\n \n # Iterate through each bit position\n for i in range(0, 32): \n # Count of zeroes \n countZero = 0\n \n # Iterate through all numbers \n for j in range(0, n): \n # If ith bit is set \n if (arr[j] & (1 << i)): \n countZero += 1\n \n # Count of ones \n countOne = n - countZero \n \n # XOR of a pair \n result += (countZero * countOne * (1 << i)) \n \n return result", "matching_cluster_idx": 4}, {"solution": "def pair_xor_Sum(arr, n):\n # Initialize the result to 0\n result = 0\n \n # Iterate over each bit position\n for i in range(0, 32):\n # Count the number of elements with ith bit set\n count = 0\n for j in range(n):\n if (arr[j] & (1 << i)):\n count += 1\n \n # There are 'count' numbers with ith bit set\n # So, there will be 'count*(n-count)' pairs with ith bit set in one and not in other\n # Every such pair will add 2^i to the xor-sum\n result += (count * (n - count)) * (1 << i)\n \n return result", "matching_cluster_idx": 4}, {"solution": "def pair_xor_Sum(arr, n):\n # Initialize result \n xor_sum = 0\n \n # Calculate sum of xor of all pairs\n for i in range(n):\n for j in range(i + 1, n):\n xor_sum += arr[i] ^ arr[j]\n \n return xor_sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(arr, n):\n # Initialize result \n xor_sum = 0\n \n # Calculate xor sum of all pairs \n for i in range(n):\n for j in range(i + 1, n):\n xor_sum += arr[i] ^ arr[j]\n \n return xor_sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(arr, n):\n xor_sum = 0\n # Iterate through each pair and calculate xor sum\n for i in range(n):\n for j in range(i + 1, n):\n xor_sum += arr[i] ^ arr[j]\n return xor_sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(nums, n):\n # Initialize result to 0\n result = 0\n \n # Iterate over the bits position\n for i in range(0, 32):\n # Count the number of elements with i-th bit set\n count = 0\n for j in range(n):\n if (nums[j] & (1 << i)):\n count += 1\n \n # Add to result, the count of pairs where i-th bit is different\n # count * (n - count) is the number of pairs with different i-th bits\n result += (count * (n - count) * (1 << i))\n \n return result", "matching_cluster_idx": 3}, {"solution": "def pair_xor_Sum(nums, n):\n # Initialize sum\n xor_sum = 0\n \n # Iterate through all pairs\n for i in range(n):\n for j in range(i + 1, n):\n # XOR the pair and add to sum\n xor_sum += nums[i] ^ nums[j]\n \n return xor_sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(arr, n):\n # Initialize result \n res = 0\n # iterate over all bits \n for i in range(0, 32):\n # count of zeros and ones \n cz, co = 0, 0\n # iterate over all elements \n for j in range(0, n):\n # if jth bit is set \n if (arr[j] & (1 << i)):\n co += 1 # increment count of ones \n else:\n cz += 1 # increment count of zeros \n # XOR of pair of i'th bit will be 1 \n # if one is set and other is not set \n res += (1 << i) * cz * co\n return res", "matching_cluster_idx": 3}, {"solution": "def pair_xor_Sum(nums, n):\n # Initialize the result to 0\n result = 0\n \n # Iterate through the list and compute the sum of xor for all pairs\n for i in range(n):\n for j in range(i+1, n):\n # Calculate the xor of the pair (nums[i], nums[j])\n xor_pair = nums[i] ^ nums[j]\n # Add the xor result to the total result\n result += xor_pair\n \n return result", "matching_cluster_idx": 1}, {"solution": "def pair_xor_Sum(arr, n):\n # Initialize result \n xor_sum = 0\n \n # Calculate the sum of XOR for all pairs\n for i in range(n):\n for j in range(i + 1, n):\n xor_sum += arr[i] ^ arr[j]\n \n return xor_sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(arr, n):\n # Initialize result \n xor_sum = 0\n \n # Calculate the sum of xor of all pairs\n for i in range(n):\n for j in range(i+1, n):\n xor_sum += arr[i] ^ arr[j]\n \n return xor_sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(arr, n):\n # Initialize result \n result = 0\n \n # Calculate XORs of all pairs \n for i in range(n):\n for j in range(i + 1, n):\n result += arr[i] ^ arr[j]\n \n return result", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(arr, n):\n # Initialize result \n result = 0\n \n # Iterate through each bit position\n for i in range(0, 32):\n \n # Count of zeros and ones at ith bit position\n count_zero = 0\n count_one = 0\n \n # Iterate through all elements in the array\n for j in range(0, n):\n # If ith bit is set\n if (arr[j] & (1 << i)):\n count_one += 1\n else:\n count_zero += 1\n \n # Add to the result, the number of pairs that have different ith bit\n result += (count_zero * count_one * (1 << i))\n \n return result", "matching_cluster_idx": 3}, {"solution": "def pair_xor_Sum(arr, n):\n # Initialize result \n result = 0\n \n # Calculate the sum of XOR of all pairs\n for i in range(n):\n for j in range(i+1, n):\n result += arr[i] ^ arr[j]\n \n return result", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(arr, n):\n # Initialize result \n xor_sum = 0\n \n # Calculate the XOR for each pair and add it to the result\n for i in range(n):\n for j in range(i + 1, n):\n xor_sum += arr[i] ^ arr[j]\n \n return xor_sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(arr, n):\n # Initialize result \n result = 0\n \n # Calculate XOR of all pairs\n for i in range(0, n):\n for j in range(i+1, n):\n result += arr[i] ^ arr[j]\n \n return result", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(arr, n):\n # Initialize result \n res = 0\n \n # Calculate the sum of xor for all pairs\n for i in range(n):\n for j in range(i + 1, n):\n res += arr[i] ^ arr[j]\n \n return res", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(arr, n):\n # Initialize result \n res = 0\n \n # Calculate XOR of all pairs \n for i in range(0, n):\n for j in range(i+1, n):\n res += arr[i] ^ arr[j]\n \n return res", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(arr, n):\n # Initialize result \n result = 0\n \n # Iterate over each bit position \n for i in range(0, 32):\n # Count of 1s in i-th position \n ones = 0\n \n # Check each element of array for set bit \n for j in range(0, n):\n if (arr[j] & (1 << i)):\n ones += 1\n \n # Count of zeros in i-th position is \n # complement of ones. \n zeros = n - ones\n \n # Add to the result, the value of ones * zeros * 2^i \n result += (ones * zeros * (1 << i))\n \n # Return result \n return result", "matching_cluster_idx": 3}, {"solution": "def pair_xor_Sum(arr, n):\n # Initialize result \n result = 0\n \n # Iterate through every bit position \n for i in range(0, 32):\n \n # Count of zeroes \n zero = 0\n \n # Iterate through all numbers \n for j in range(n):\n if (arr[j] & 1) == 0:\n zero += 1\n arr[j] = arr[j] >> 1\n \n # Count of ones \n one = n - zero \n \n # Update result \n result += (one * zero) * (1 << i)\n \n return result", "matching_cluster_idx": 3}]}, "Mbpp/644": {"dps": 89.33510638297871, "dps_norm": 88.0, "pass@1": 100.0, "profiled": [{"solution": "def reverse_Array_Upto_K(arr, k):\n # Reverse the subarray from the start to the k-th index\n arr[:k] = arr[:k][::-1]\n return arr", "matching_cluster_idx": 13}, {"solution": "def reverse_Array_Upto_K(arr, k):\n # Reverse the sub-array up to the given position k\n arr[:k] = arr[:k][::-1]\n return arr", "matching_cluster_idx": 13}, {"solution": "def reverse_Array_Upto_K(arr, k):\n # Reversing the array up to the k-th position\n reversed_part = arr[:k][::-1]\n # Keeping the rest of the array intact\n remaining_part = arr[k:]\n # Combining the reversed part and the remaining part\n arr = reversed_part + remaining_part\n return arr", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n # Reverse the sub-array up to the given position k-1\n arr[:k] = arr[:k][::-1]\n return arr", "matching_cluster_idx": 13}, {"solution": "def reverse_Array_Upto_K(arr, k):\n # Reverse the portion of the array up to index k\n arr[:k] = arr[:k][::-1]\n return arr", "matching_cluster_idx": 13}, {"solution": "def reverse_Array_Upto_K(arr, k):\n # Reverse the sub-array up to k and concatenate with the rest of the array\n return arr[:k][::-1] + arr[k:]", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n # Reverse the portion of the array up to index k\n arr[:k] = arr[:k][::-1]\n return arr", "matching_cluster_idx": 13}, {"solution": "def reverse_Array_Upto_K(arr, k):\n # Reversing the portion of the array up to the given position k\n arr[:k] = arr[:k][::-1]\n return arr", "matching_cluster_idx": 13}, {"solution": "def reverse_Array_Upto_K(arr, k):\n # Reverse the portion of the array from the start up to k\n return arr[:k][::-1] + arr[k:]", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n # Reversing the array up to the given position\n arr[:k] = arr[:k][::-1]\n return arr", "matching_cluster_idx": 13}, {"solution": "def reverse_Array_Upto_K(arr, k):\n # Reverse the sub-array up to the given position k\n arr[:k] = arr[:k][::-1]\n return arr", "matching_cluster_idx": 13}, {"solution": "def reverse_Array_Upto_K(arr, k):\n # Reverse the portion of the array up to k-1\n arr[:k] = arr[:k][::-1]\n return arr", "matching_cluster_idx": 13}, {"solution": "def reverse_Array_Upto_K(arr, k):\n # Reversing the sub-array up to k\n arr[:k] = arr[:k][::-1]\n return arr", "matching_cluster_idx": 13}, {"solution": "def reverse_Array_Upto_K(arr, k):\n # Reverse the subarray from the start to the given position k-1\n arr[:k] = arr[:k][::-1]\n return arr", "matching_cluster_idx": 13}, {"solution": "def reverse_Array_Upto_K(arr, k):\n # Reverse the subarray up to k\n arr[:k] = arr[:k][::-1]\n return arr", "matching_cluster_idx": 13}, {"solution": "def reverse_Array_Upto_K(arr, k):\n # Reverse the array up to position k\n return arr[:k][::-1] + arr[k:]", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n # Reverse the sub-array up to the given position k\n arr[:k] = reversed(arr[:k])\n return arr", "matching_cluster_idx": 12}, {"solution": "def reverse_Array_Upto_K(arr, k):\n # Reverse the portion of the array up to k\n arr[:k] = arr[:k][::-1]\n return arr", "matching_cluster_idx": 13}, {"solution": "def reverse_Array_Upto_K(arr, k):\n # Reverse the subarray up to the given position k\n return arr[:k][::-1] + arr[k:]", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n # Reverse the sub-array from the start to the k-th element\n arr[:k] = arr[:k][::-1]\n return arr", "matching_cluster_idx": 13}]}, "Mbpp/720": {"dps": 52.11538461538461, "dps_norm": 84.0, "pass@1": 100.0, "profiled": [{"solution": "def add_dict_to_tuple(input_tuple, input_dict):\n # Convert the tuple to a list to append the dictionary to it\n temp_list = list(input_tuple)\n temp_list.append(input_dict)\n \n # Convert the list back to a tuple and return\n return tuple(temp_list)", "matching_cluster_idx": 3}, {"solution": "def add_dict_to_tuple(input_tuple, input_dict):\n # Convert tuple to list, append dictionary to the list, and then convert back to tuple\n updated_list = list(input_tuple)\n updated_list.append(input_dict)\n return tuple(updated_list)", "matching_cluster_idx": 3}, {"solution": "def add_dict_to_tuple(test_tup, test_dict):\n # Convert the tuple to a list to allow modification\n temp_list = list(test_tup)\n # Append the dictionary to the list\n temp_list.append(test_dict)\n # Convert the list back to a tuple\n res = tuple(temp_list)\n return res", "matching_cluster_idx": 3}, {"solution": "def add_dict_to_tuple(input_tuple, input_dict):\n # Convert the tuple to a list to allow modifications\n temp_list = list(input_tuple)\n \n # Append the dictionary to the list\n temp_list.append(input_dict)\n \n # Convert the list back to a tuple\n output_tuple = tuple(temp_list)\n \n return output_tuple", "matching_cluster_idx": 3}, {"solution": "def add_dict_to_tuple(input_tuple, input_dict):\n # Convert the input tuple to a list to enable modifications\n temp_list = list(input_tuple)\n # Append the dictionary to the list\n temp_list.append(input_dict)\n # Convert the list back to a tuple and return\n output_tuple = tuple(temp_list)\n return output_tuple", "matching_cluster_idx": 3}, {"solution": "def add_dict_to_tuple(test_tup, test_dict):\n # Converting tuple to list to append the dictionary\n temp_list = list(test_tup)\n temp_list.append(test_dict)\n # Converting the list back to a tuple\n res = tuple(temp_list)\n return res", "matching_cluster_idx": 3}, {"solution": "def add_dict_to_tuple(input_tuple, input_dict):\n # Convert the input tuple to a list to append the dictionary and then convert it back to a tuple\n temp_list = list(input_tuple)\n temp_list.append(input_dict)\n return tuple(temp_list)", "matching_cluster_idx": 3}, {"solution": "def add_dict_to_tuple(test_tup, test_dict):\n # Adding dictionary to tuple using tuple concatenation\n res = test_tup + (test_dict,)\n return res", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(test_tup, test_dict):\n # Convert the tuple to a list, append the dictionary, and then convert back to a tuple\n res = tuple(list(test_tup) + [test_dict])\n return res", "matching_cluster_idx": 2}, {"solution": "def add_dict_to_tuple(test_tup, test_dict):\n # Convert the tuple to a list to use list methods\n temp_list = list(test_tup)\n # Append the dictionary to the list\n temp_list.append(test_dict)\n # Convert the list back to a tuple\n res = tuple(temp_list)\n return res", "matching_cluster_idx": 3}, {"solution": "def add_dict_to_tuple(test_tup, test_dict):\n # Adding the dictionary to the end of the tuple\n res = test_tup + (test_dict,)\n return res", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(test_tup, test_dict):\n # Adding dictionary to tuple by concatenating it\n res = test_tup + (test_dict,)\n return res", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(tup, dictionary):\n # Convert the tuple into a list to allow modifications\n temp_list = list(tup)\n \n # Add the dictionary to the end of the list\n temp_list.append(dictionary)\n \n # Convert the list back into a tuple and return it\n return tuple(temp_list)", "matching_cluster_idx": 3}, {"solution": "def add_dict_to_tuple(test_tup, test_dict):\n # Convert the tuple to a list to allow modifications\n temp_list = list(test_tup)\n \n # Add the dictionary to the list\n temp_list.append(test_dict)\n \n # Convert the list back to a tuple\n res = tuple(temp_list)\n return res", "matching_cluster_idx": 3}, {"solution": "def add_dict_to_tuple(input_tuple, dictionary):\n # Convert the tuple to a list to allow modifications\n temp_list = list(input_tuple)\n \n # Append the dictionary to the list\n temp_list.append(dictionary)\n \n # Convert the list back to a tuple\n updated_tuple = tuple(temp_list)\n \n return updated_tuple", "matching_cluster_idx": 3}, {"solution": "def add_dict_to_tuple(test_tup, test_dict):\n # Adding the dictionary to the tuple by converting it to a tuple with one element and concatenating\n res = test_tup + (test_dict,)\n return res", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(test_tup, test_dict):\n # Convert tuple to list and append the dictionary\n temp_list = list(test_tup)\n temp_list.append(test_dict)\n \n # Convert list back to tuple\n res = tuple(temp_list)\n return res", "matching_cluster_idx": 3}, {"solution": "def add_dict_to_tuple(test_tup, test_dict):\n # Convert tuple to list to allow modification\n temp_list = list(test_tup)\n \n # Append the dictionary to the list\n temp_list.append(test_dict)\n \n # Convert list back to tuple\n res = tuple(temp_list)\n \n return res", "matching_cluster_idx": 3}, {"solution": "def add_dict_to_tuple(test_tup, test_dict):\n # Convert tuple to list to allow modifications\n temp_list = list(test_tup)\n # Append dictionary to the list\n temp_list.append(test_dict)\n # Convert list back to tuple\n result_tuple = tuple(temp_list)\n return result_tuple", "matching_cluster_idx": 3}, {"solution": "def add_dict_to_tuple(test_tup, test_dict):\n # Convert the tuple to a list, append the dictionary, then convert back to a tuple\n res = test_tup + (test_dict,)\n return res", "matching_cluster_idx": 4}]}, "Mbpp/725": {"dps": 46.99453551912568, "dps_norm": 62.5, "pass@1": 100.0, "profiled": [{"solution": "import re\ndef extract_quotation(text):\n # Using regular expression to find all content between double quotes\n return re.findall(r'\"(.*?)\"', text)", "matching_cluster_idx": 4}, {"solution": "import re\ndef extract_quotation(s):\n # Use regular expression to find all occurrences of text within double quotes\n return re.findall(r'\"(.*?)\"', s)", "matching_cluster_idx": 4}, {"solution": "import re\ndef extract_quotation(s):\n # Using regular expression to find all patterns that start and end with double quotes\n # and capturing the content inside the quotes with a group.\n return re.findall(r'\"(.*?)\"', s)", "matching_cluster_idx": 4}, {"solution": "import re\ndef extract_quotation(text):\n # Find all occurrences of text between quotation marks\n matches = re.findall(r'\"(.*?)\"', text)\n return matches", "matching_cluster_idx": 4}, {"solution": "import re\ndef extract_quotation(s):\n # Using regular expression to find all instances between quotes\n return re.findall(r'\"(.*?)\"', s)", "matching_cluster_idx": 4}, {"solution": "import re\ndef extract_quotation(s):\n # Use regular expression to find all patterns that match text within quotes\n return re.findall(r'\"(.*?)\"', s)", "matching_cluster_idx": 4}, {"solution": "import re\ndef extract_quotation(s):\n # Find all occurrences of text enclosed in double quotes\n matches = re.findall(r'\"(.*?)\"', s)\n return matches", "matching_cluster_idx": 4}, {"solution": "import re\ndef extract_quotation(input_string):\n # Find all occurrences of text between double quotes\n result = re.findall(r'\"(.*?)\"', input_string)\n return result", "matching_cluster_idx": 4}, {"solution": "import re\ndef extract_quotation(s):\n # Use regular expression to find all substrings enclosed in quotation marks\n return re.findall(r'\"(.*?)\"', s)", "matching_cluster_idx": 4}, {"solution": "import re\ndef extract_quotation(s):\n # Regular expression to find all occurrences of text between double quotes\n return re.findall(r'\"(.*?)\"', s)", "matching_cluster_idx": 4}, {"solution": "import re\ndef extract_quotation(s):\n # Find all patterns that match the double-quoted text\n matches = re.findall(r'\"(.*?)\"', s)\n return matches", "matching_cluster_idx": 4}, {"solution": "import re\ndef extract_quotation(input_string):\n # Regular expression to find strings enclosed in double quotes\n pattern = r'\"(.*?)\"'\n # Find all non-overlapping matches of pattern in the string\n result = re.findall(pattern, input_string)\n return result", "matching_cluster_idx": 4}, {"solution": "import re\ndef extract_quotation(input_string):\n # Use regular expression to find all patterns surrounded by quotes\n matches = re.findall(r'\"(.*?)\"', input_string)\n return matches", "matching_cluster_idx": 4}, {"solution": "import re\ndef extract_quotation(input_string):\n # Using regular expression to find all substrings enclosed in double quotes\n matches = re.findall(r'\"(.*?)\"', input_string)\n return matches", "matching_cluster_idx": 4}, {"solution": "import re\ndef extract_quotation(input_string):\n # Regular expression to find all matches of text enclosed in double quotes\n matches = re.findall(r'\"(.*?)\"', input_string)\n return matches", "matching_cluster_idx": 4}, {"solution": "import re\ndef extract_quotation(text):\n # Use regular expression to find all matches of text within double quotes\n matches = re.findall(r'\"(.*?)\"', text)\n return matches", "matching_cluster_idx": 4}, {"solution": "import re\ndef extract_quotation(s):\n # Use regular expression to find all matches within quotation marks\n return re.findall(r'\"(.*?)\"', s)", "matching_cluster_idx": 4}, {"solution": "import re\ndef extract_quotation(s):\n # Using regular expression to find all patterns between double quotes\n return re.findall(r'\"(.*?)\"', s)", "matching_cluster_idx": 4}, {"solution": "import re\ndef extract_quotation(text):\n # Using regular expression to find all matches of text enclosed in quotes\n return re.findall(r'\"(.*?)\"', text)", "matching_cluster_idx": 4}, {"solution": "import re\ndef extract_quotation(text):\n # Find all substrings that are enclosed in double quotes\n matches = re.findall(r'\"(.*?)\"', text)\n return matches", "matching_cluster_idx": 4}]}, "Mbpp/732": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def replace_specialchar(s):\n # Replace spaces, commas, and dots with a colon\n return s.replace(' ', ':').replace(',', ':').replace('.', ':')", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(s):\n # Replace spaces, commas, and dots with a colon\n return s.replace(' ', ':').replace(',', ':').replace('.', ':')", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(s):\n # Replace spaces, commas, and dots with a colon\n result = s.replace(' ', ':').replace(',', ':').replace('.', ':')\n return result", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(input_string):\n # Replace spaces, commas, and dots with colons\n for char in [' ', ',', '.']:\n input_string = input_string.replace(char, ':')\n return input_string", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(text):\n # Replace spaces, commas, and dots with colons\n for char in (' ', ',', '.'):\n text = text.replace(char, ':')\n return text", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(s):\n # Replace spaces, commas, and dots with colons\n for char in [' ', ',', '.']:\n s = s.replace(char, ':')\n return s", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(s):\n # Replace spaces, commas, and dots with a colon\n return s.replace(' ', ':').replace(',', ':').replace('.', ':')", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(text):\n # Replace spaces, commas, and dots with colons\n return text.replace(' ', ':').replace(',', ':').replace('.', ':')", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(input_string):\n # Replace space, comma, and dot with colon\n result_string = input_string.replace(' ', ':').replace(',', ':').replace('.', ':')\n return result_string", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(input_string):\n # Replace spaces, commas, and dots with a colon\n return input_string.replace(' ', ':').replace(',', ':').replace('.', ':')", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(s):\n # Replace spaces, commas, and dots with a colon\n for char in [' ', ',', '.']:\n s = s.replace(char, ':')\n return s", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(text):\n # Replace spaces, commas, and dots with colons\n result = text.replace(' ', ':').replace(',', ':').replace('.', ':')\n return result", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(text):\n # Replace spaces, commas, and dots with a colon\n for char in [' ', ',', '.']:\n text = text.replace(char, ':')\n return text", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(text):\n # Replace spaces, commas, and dots with a colon\n for char in [' ', ',', '.']:\n text = text.replace(char, ':')\n return text", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(input_string):\n # Replace spaces, commas, and dots with a colon\n for char in [' ', ',', '.']:\n input_string = input_string.replace(char, ':')\n return input_string", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(s):\n # Replace spaces, commas, and dots with a colon\n return s.replace(' ', ':').replace(',', ':').replace('.', ':')", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(s):\n # Replace spaces, commas, and dots with colons\n result = s.replace(' ', ':').replace(',', ':').replace('.', ':')\n return result", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(s):\n # Replace spaces, commas, and dots with colon\n return s.replace(' ', ':').replace(',', ':').replace('.', ':')", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(text):\n # Replace spaces, commas, and dots with colons\n result = text.replace(\" \", \":\").replace(\",\", \":\").replace(\".\", \":\")\n return result", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(s):\n # Replace spaces, commas, and dots with a colon\n for char in [' ', ',', '.']:\n s = s.replace(char, ':')\n return s", "matching_cluster_idx": 9}]}, "Mbpp/740": {"dps": 86.9090909090909, "dps_norm": 73.33333333333334, "pass@1": 100.0, "profiled": [{"solution": "def tuple_to_dict(input_tuple):\n # Check if the length of the tuple is even\n if len(input_tuple) % 2 != 0:\n raise ValueError(\"Input tuple must have an even number of elements to form key-value pairs.\")\n \n # Convert the tuple to a dictionary with adjacent elements as key-value pairs\n return {input_tuple[i]: input_tuple[i + 1] for i in range(0, len(input_tuple), 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(tup):\n # Check if the tuple has an even number of elements\n if len(tup) % 2 != 0:\n raise ValueError(\"Tuple must contain an even number of elements\")\n \n # Create a dictionary by zipping every two elements together\n result_dict = {tup[i]: tup[i + 1] for i in range(0, len(tup), 2)}\n return result_dict", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(tup):\n # Check if the length of the tuple is odd, which means not all elements can form pairs\n if len(tup) % 2 != 0:\n raise ValueError(\"Input tuple length must be even to form pairs\")\n \n # Create a dictionary by using the zip function with sliced tuples\n # Slice the tuple to even indices for keys and odd indices for values\n result_dict = dict(zip(tup[::2], tup[1::2]))\n \n return result_dict", "matching_cluster_idx": 8}, {"solution": "def tuple_to_dict(tup):\n # Check if the tuple has an even number of elements\n if len(tup) % 2 != 0:\n raise ValueError(\"Tuple must contain an even number of elements.\")\n \n # Use zip to pair every two elements from the tuple, and convert to a dictionary\n it = iter(tup)\n res_dict = dict(zip(it, it))\n \n return res_dict", "matching_cluster_idx": 8}, {"solution": "def tuple_to_dict(tup):\n # Check if the tuple has an even number of elements\n if len(tup) % 2 != 0:\n raise ValueError(\"Tuple must contain an even number of elements\")\n \n # Iterate over the tuple in steps of 2 to create key-value pairs\n return {tup[i]: tup[i + 1] for i in range(0, len(tup), 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(tup):\n # Convert the tuple into a dictionary by taking elements in pairs\n return {tup[i]: tup[i + 1] for i in range(0, len(tup), 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(tup):\n # Check if the length of the tuple is even, ensuring there are no unpaired elements\n if len(tup) % 2 != 0:\n raise ValueError(\"Tuple must contain an even number of elements.\")\n \n # Convert the tuple to a dictionary by pairing adjacent elements\n return dict(zip(tup[::2], tup[1::2]))", "matching_cluster_idx": 8}, {"solution": "def tuple_to_dict(tup):\n # Check if the tuple has an even number of elements\n if len(tup) % 2 != 0:\n raise ValueError(\"Tuple must have an even number of elements.\")\n \n # Create dictionary using dictionary comprehension\n # Iterate over the tuple by steps of 2 and create key-value pairs\n return {tup[i]: tup[i+1] for i in range(0, len(tup), 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(tup):\n # Check if the tuple has an even number of elements\n if len(tup) % 2 != 0:\n raise ValueError(\"Tuple must contain an even number of elements\")\n \n # Create the dictionary by taking elements in pairs\n return dict(zip(tup[::2], tup[1::2]))", "matching_cluster_idx": 8}, {"solution": "def tuple_to_dict(tup):\n # Check if the tuple has an even number of elements\n if len(tup) % 2 != 0:\n raise ValueError(\"Tuple must have an even number of elements.\")\n \n # Use dictionary comprehension to create the dictionary\n return {tup[i]: tup[i + 1] for i in range(0, len(tup), 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(input_tuple):\n # Check if the length of the tuple is even, which is required for key-value pairs\n if len(input_tuple) % 2 != 0:\n raise ValueError(\"Tuple length must be even to form key-value pairs.\")\n \n # Create a dictionary using a dictionary comprehension\n result_dict = {input_tuple[i]: input_tuple[i + 1] for i in range(0, len(input_tuple), 2)}\n \n return result_dict", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(tup):\n # Check if the tuple has an even number of elements\n if len(tup) % 2 != 0:\n raise ValueError(\"Tuple must contain an even number of elements.\")\n \n # Create a dictionary from the tuple elements\n return {tup[i]: tup[i + 1] for i in range(0, len(tup), 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(input_tuple):\n # Check if the length of the tuple is even\n if len(input_tuple) % 2 != 0:\n raise ValueError(\"Tuple must contain an even number of elements.\")\n \n # Convert tuple to dictionary by taking elements in pairs\n return {input_tuple[i]: input_tuple[i + 1] for i in range(0, len(input_tuple), 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(tup):\n # Ensure the tuple has an even number of elements for key-value pairs\n if len(tup) % 2 != 0:\n raise ValueError(\"Tuple must contain an even number of elements\")\n \n # Convert tuple to dictionary by taking elements in pairs\n return {tup[i]: tup[i + 1] for i in range(0, len(tup), 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(tup):\n # Check if the tuple has an even number of elements\n if len(tup) % 2 != 0:\n raise ValueError(\"Tuple must have an even number of elements.\")\n \n # Create a dictionary using tuple elements as keys and values\n return {tup[i]: tup[i + 1] for i in range(0, len(tup), 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(tup):\n # Check if the tuple has an even number of elements\n if len(tup) % 2 != 0:\n raise ValueError(\"Tuple should contain an even number of elements\")\n \n # Convert tuple to dictionary by pairing every two elements\n res = {tup[i]: tup[i + 1] for i in range(0, len(tup), 2)}\n return res", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(tup):\n # Check if the tuple has even number of elements\n if len(tup) % 2 != 0:\n raise ValueError(\"Tuple must contain an even number of elements\")\n \n # Use dictionary comprehension to create a dictionary from the tuple\n return {tup[i]: tup[i + 1] for i in range(0, len(tup), 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(tup):\n # Check if the tuple has an even number of elements\n if len(tup) % 2 != 0:\n raise ValueError(\"Tuple must have an even number of elements\")\n \n # Use dictionary comprehension to pair up adjacent elements\n return {tup[i]: tup[i + 1] for i in range(0, len(tup), 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(tup):\n # Ensure the tuple has an even number of elements\n if len(tup) % 2 != 0:\n raise ValueError(\"Tuple must have an even number of elements\")\n \n # Convert tuple to dictionary using a dictionary comprehension\n return {tup[i]: tup[i + 1] for i in range(0, len(tup), 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(tup):\n # Check if the tuple has an even number of elements\n if len(tup) % 2 != 0:\n raise ValueError(\"Tuple must have an even number of elements\")\n # Create the dictionary by iterating over the tuple in steps of 2\n return {tup[i]: tup[i + 1] for i in range(0, len(tup), 2)}", "matching_cluster_idx": 5}]}, "Mbpp/744": {"dps": 29.006849315068493, "dps_norm": 43.333333333333336, "pass@1": 100.0, "profiled": [{"solution": "def check_none(test_tuple):\n # Check if any element in the tuple is None\n return any(ele is None for ele in test_tuple)", "matching_cluster_idx": 2}, {"solution": "def check_none(test_tuple):\n # Check if any element in the tuple is None\n return any(element is None for element in test_tuple)", "matching_cluster_idx": 2}, {"solution": "def check_none(test_tuple):\n # Iterate through each element in the tuple\n for element in test_tuple:\n # Check if the current element is None\n if element is None:\n # If None is found, return True\n return True\n # If no None is found, return False\n return False", "matching_cluster_idx": 4}, {"solution": "def check_none(test_tup):\n # Check if any element in the tuple is None\n return any(ele is None for ele in test_tup)", "matching_cluster_idx": 2}, {"solution": "def check_none(test_tup):\n # Check if there is any None value in the tuple\n return any(element is None for element in test_tup)", "matching_cluster_idx": 2}, {"solution": "def check_none(test_tup):\n # Check if any element in the tuple is None\n return any(ele is None for ele in test_tup)", "matching_cluster_idx": 2}, {"solution": "def check_none(test_tup):\n # Check if any element in the tuple is None\n return any(ele is None for ele in test_tup)", "matching_cluster_idx": 2}, {"solution": "def check_none(test_tuple):\n # Check if there is any None value in the tuple\n return any(isinstance(element, type(None)) for element in test_tuple)", "matching_cluster_idx": -1}, {"solution": "def check_none(test_tup):\n # Check if there is any None value in the tuple\n return any(isinstance(elem, type(None)) for elem in test_tup)", "matching_cluster_idx": -1}, {"solution": "def check_none(test_tup):\n # Check if any element in the tuple is None\n return any(ele is None for ele in test_tup)", "matching_cluster_idx": 2}, {"solution": "def check_none(test_tup):\n # Check if None is in the tuple\n return None in test_tup", "matching_cluster_idx": 4}, {"solution": "def check_none(test_tup):\n \"\"\"\n This function checks if the given tuple has any None value or not.\n \n Parameters:\n test_tup (tuple): The tuple to be checked.\n \n Returns:\n bool: True if there is any None value in the tuple, False otherwise.\n \"\"\"\n return any(isinstance(x, type(None)) for x in test_tup)", "matching_cluster_idx": -1}, {"solution": "def check_none(test_tup):\n \"\"\"\n Check if there is any None value in the tuple.\n\n :param test_tup: Tuple to be checked.\n :return: True if any None value is found in the tuple, False otherwise.\n \"\"\"\n # Check for the presence of None in the tuple\n return any(ele is None for ele in test_tup)", "matching_cluster_idx": 1}, {"solution": "def check_none(test_tup):\n # Check if any element in the tuple is None\n return any(ele is None for ele in test_tup)", "matching_cluster_idx": 2}, {"solution": "def check_none(test_tup):\n # Check if any element in the tuple is None\n return any(ele is None for ele in test_tup)", "matching_cluster_idx": 2}, {"solution": "def check_none(test_tuple):\n # Check if None is in the tuple\n return None in test_tuple", "matching_cluster_idx": 4}, {"solution": "def check_none(test_tup):\n # Check if any element in the tuple is None\n return any(ele is None for ele in test_tup)", "matching_cluster_idx": 2}, {"solution": "def check_none(test_tuple):\n # Check if there's any None value in the tuple\n return any(ele is None for ele in test_tuple)", "matching_cluster_idx": 1}, {"solution": "def check_none(test_tup):\n # Check if any element in the tuple is None\n return any(element is None for element in test_tup)", "matching_cluster_idx": 2}, {"solution": "def check_none(test_tuple):\n # Check if there is any None value in the tuple\n return any(isinstance(x, type(None)) for x in test_tuple)", "matching_cluster_idx": -1}]}, "Mbpp/750": {"dps": 88.29931972789116, "dps_norm": 93.33333333333333, "pass@1": 100.0, "profiled": [{"solution": "def add_tuple(lst, tup):\n # Extend the list with the elements of the tuple\n lst.extend(tup)\n return lst", "matching_cluster_idx": 5}, {"solution": "def add_tuple(lst, tup):\n # Extend the list with elements from the tuple\n lst.extend(tup)\n return lst", "matching_cluster_idx": 5}, {"solution": "def add_tuple(lst, tup):\n # Extend the list by converting the tuple to a list and concatenating\n lst.extend(list(tup))\n return lst", "matching_cluster_idx": 4}, {"solution": "def add_tuple(lst, tup):\n # Extend the list with the elements of the tuple\n lst.extend(tup)\n return lst", "matching_cluster_idx": 5}, {"solution": "def add_tuple(lst, tup):\n # Extend the list with elements from the tuple\n lst.extend(tup)\n return lst", "matching_cluster_idx": 5}, {"solution": "def add_tuple(lst, tup):\n # Extending the list with elements from the tuple\n lst.extend(tup)\n return lst", "matching_cluster_idx": 5}, {"solution": "def add_tuple(lst, tup):\n # Extend the list with the elements of the tuple\n lst.extend(tup)\n return lst", "matching_cluster_idx": 5}, {"solution": "def add_tuple(lst, tup):\n # Extending the list with the tuple's elements\n lst.extend(tup)\n return lst", "matching_cluster_idx": 5}, {"solution": "def add_tuple(lst, tup):\n # Extend the list with the elements of the tuple\n lst.extend(tup)\n return lst", "matching_cluster_idx": 5}, {"solution": "def add_tuple(lst, tup):\n # Converting the tuple to a list and extending the original list\n lst.extend(list(tup))\n return lst", "matching_cluster_idx": 4}, {"solution": "def add_tuple(lst, tup):\n # Extend the list with the elements from the tuple\n lst.extend(tup)\n return lst", "matching_cluster_idx": 4}, {"solution": "def add_tuple(lst, tpl):\n # Convert the tuple to a list, then extend the original list\n lst.extend(list(tpl))\n return lst", "matching_cluster_idx": 4}, {"solution": "def add_tuple(lst, tpl):\n # Convert tuple to list and extend the original list with its elements\n lst.extend(list(tpl))\n return lst", "matching_cluster_idx": 4}, {"solution": "def add_tuple(lst, tup):\n # Convert the tuple to a list and extend the original list with it\n lst.extend(list(tup))\n return lst", "matching_cluster_idx": 4}, {"solution": "def add_tuple(lst, tup):\n # Convert tuple to list and extend the original list\n lst.extend(list(tup))\n return lst", "matching_cluster_idx": 4}, {"solution": "def add_tuple(lst, tup):\n # Extend the list with elements from the tuple\n lst.extend(tup)\n return lst", "matching_cluster_idx": 5}, {"solution": "def add_tuple(lst, tup):\n # Extend the list with the elements of the tuple\n lst.extend(tup)\n return lst", "matching_cluster_idx": 5}, {"solution": "def add_tuple(lst, tup):\n # Extend the list with the elements of the tuple\n lst.extend(tup)\n return lst", "matching_cluster_idx": 5}, {"solution": "def add_tuple(lst, tup):\n # Extend the list by converting the tuple to a list and adding it\n lst.extend(list(tup))\n return lst", "matching_cluster_idx": 4}, {"solution": "def add_tuple(lst, tup):\n # Extend the list with the tuple's elements\n lst.extend(tup)\n return lst", "matching_cluster_idx": 5}]}, "Mbpp/753": {"dps": 30.134228187919465, "dps_norm": 57.5, "pass@1": 100.0, "profiled": [{"solution": "def min_k(test_list, k):\n # Sort the list based on the second item of each tuple\n sorted_list = sorted(test_list, key=lambda x: x[1])\n # Return the first k elements from the sorted list\n return sorted_list[:k]", "matching_cluster_idx": 1}, {"solution": "def min_k(lst, k):\n \"\"\"\n This function finds the minimum k records from a list of tuples based on the second element of the tuple.\n :param lst: List of tuples\n :param k: Number of minimum records to find\n :return: List of k minimum records\n \"\"\"\n # Sort the list based on the second element of each tuple\n sorted_lst = sorted(lst, key=lambda x: x[1])\n # Return the first k elements\n return sorted_lst[:k]", "matching_cluster_idx": 1}, {"solution": "def min_k(test_list, k):\n \"\"\"\n Finds the k minimum records from a list of tuples based on the second item in the tuples.\n\n Parameters:\n test_list (list): The list of tuples to be processed.\n k (int): The number of minimum records to find.\n\n Returns:\n list: A list of k minimum records.\n \"\"\"\n # Sorting the list of tuples based on the second item\n sorted_list = sorted(test_list, key=lambda x: x[1])\n # Slicing the sorted list to get the first k elements\n return sorted_list[:k]", "matching_cluster_idx": 1}, {"solution": "def min_k(test_list, k):\n \"\"\"\n Finds the minimum k records from a list of tuples based on the second item in each tuple.\n \n Parameters:\n test_list (list of tuples): The input list to search within.\n k (int): The number of minimum records to find.\n \n Returns:\n list of tuples: A list containing the k tuples with the smallest second item.\n \"\"\"\n # Sort the list by the second item in each tuple and then slice the first k elements\n sorted_list = sorted(test_list, key=lambda x: x[1])\n return sorted_list[:k]", "matching_cluster_idx": 1}, {"solution": "def min_k(test_list, k):\n \"\"\"\n Function to find the minimum k records from a given list of tuples based on the second element of the tuples.\n \n Args:\n test_list: List of tuples where sorting is to be performed based on the second element of each tuple.\n k: Number of minimum records to retrieve from the list.\n \n Returns:\n A list of tuples containing the minimum k records.\n \"\"\"\n # Sort the list based on the second element of each tuple\n sorted_test_list = sorted(test_list, key=lambda x: x[1])\n \n # Return the first k elements from the sorted list\n return sorted_test_list[:k]", "matching_cluster_idx": 1}, {"solution": "def min_k(test_list, k):\n \"\"\"\n This function finds the minimum k records from a list of tuples, sorting them based on the second item in the tuple.\n \n :param test_list: The list of tuples to search through.\n :param k: The number of minimum records to find.\n :return: A list of tuples containing the minimum k records.\n \"\"\"\n # Sort the list based on the second item of each tuple\n sorted_list = sorted(test_list, key=lambda x: x[1])\n # Return the first k items from the sorted list\n return sorted_list[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(test_list, k):\n # Sort the list of tuples based on the second element in the tuple in ascending order\n sorted_list = sorted(test_list, key=lambda x: x[1])\n # Get the first k elements from the sorted list\n min_k_elements = sorted_list[:k]\n return min_k_elements", "matching_cluster_idx": 1}, {"solution": "def min_k(test_list, k):\n # Sort the list of tuples by the second item in each tuple and slice the first k elements\n return sorted(test_list, key=lambda x: x[1])[:k]", "matching_cluster_idx": 1}, {"solution": "def min_k(test_list, k):\n # Sort the list of tuples by the second item in each tuple and return the first k items\n return sorted(test_list, key=lambda x: x[1])[:k]\ntest_list = [('Manjeet', 10), ('Akshat', 4), ('Akash', 2), ('Nikhil', 8)]\nk = 2", "matching_cluster_idx": 2}, {"solution": "def min_k(tup, k):\n # Sort the list of tuples by the second item in each tuple\n # in ascending order and slice the first k elements\n return sorted(tup, key=lambda x: x[1])[:k]", "matching_cluster_idx": 1}, {"solution": "def min_k(test_list, k):\n \"\"\"\n Find the k minimum records in a list of tuples based on the second element of the tuples.\n \n :param test_list: List of tuples where each tuple contains at least two elements.\n :param k: Number of minimum records to return.\n :return: A list of k tuples with the smallest second element values.\n \"\"\"\n # Sort the list based on the second element of the tuples\n sorted_list = sorted(test_list, key=lambda x: x[1])\n # Get the first k elements\n return sorted_list[:k]", "matching_cluster_idx": 1}, {"solution": "def min_k(tup, k):\n # Sort the tuple list based on the second element of each tuple and take the first k elements\n return sorted(tup, key=lambda x: x[1])[:k]", "matching_cluster_idx": 1}, {"solution": "def min_k(test_list, k):\n # Sort the list of tuples based on the second item (index 1) in each tuple\n sorted_list = sorted(test_list, key=lambda x: x[1])\n # Slice the list to get the first k elements\n return sorted_list[:k]", "matching_cluster_idx": 1}, {"solution": "def min_k(test_list, k):\n \"\"\"\n This function takes a list of tuples and an integer k, then returns the k tuples\n with the smallest second elements.\n \n :param test_list: List of tuples, each containing a string and an integer\n :param k: Number of minimum records to find\n :return: List of k tuples with the smallest second elements\n \"\"\"\n # Sort the list based on the second element of each tuple\n sorted_list = sorted(test_list, key=lambda x: x[1])\n # Return the first k elements from the sorted list\n return sorted_list[:k]", "matching_cluster_idx": 1}, {"solution": "def min_k(test_list, k):\n \"\"\"\n Find the minimum k records from a list of tuples based on the second element of each tuple.\n \n Parameters:\n test_list (list of tuples): The list of tuples to search through.\n k (int): The number of minimum records to find.\n\n Returns:\n list of tuples: The k minimum records from the list based on the second element of the tuples.\n \"\"\"\n # Sort the list based on the second element of each tuple and slice the first k elements\n return sorted(test_list, key=lambda x: x[1])[:k]\ntest_list = [('Manjeet', 10), ('Akshat', 4), ('Akash', 2), ('Nikhil', 8)]\nk = 2", "matching_cluster_idx": 1}, {"solution": "def min_k(test_list, k):\n \"\"\"\n Find the k tuples with the smallest second element in a given list of tuples.\n\n :param test_list: A list of tuples.\n :param k: The number of minimum tuples to find.\n :return: A list of tuples with the smallest second elements.\n \"\"\"\n # Sort the list of tuples based on the second element in each tuple\n sorted_list = sorted(test_list, key=lambda x: x[1])\n # Return the first k elements of the sorted list\n return sorted_list[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(tup_list, k):\n \"\"\"\n Finds the k tuples with the smallest second element in the list of tuples.\n \n :param tup_list: List of tuples, where each tuple contains a string and an integer\n :param k: Number of minimum records to return\n :return: List of k tuples with the smallest second element\n \"\"\"\n # Sort the list of tuples based on the second element of each tuple\n sorted_tuples = sorted(tup_list, key=lambda x: x[1])\n # Return the first k elements from the sorted list\n return sorted_tuples[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(tuples_list, k):\n # Sort the list of tuples based on the second item of each tuple\n sorted_tuples = sorted(tuples_list, key=lambda x: x[1])\n # Return the first k elements from the sorted list\n return sorted_tuples[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(tuples_list, k):\n \"\"\"\n This function takes a list of tuples and an integer k as input.\n It returns a list of the k tuples with the smallest second value.\n \n :param tuples_list: List of tuples, where each tuple contains at least two elements\n :param k: Integer indicating the number of minimum tuples to return\n :return: List of k tuples with the smallest second value\n \"\"\"\n # Sort the list of tuples based on the second element of each tuple\n sorted_tuples = sorted(tuples_list, key=lambda x: x[1])\n # Return the first k elements from the sorted list\n return sorted_tuples[:k]", "matching_cluster_idx": 1}, {"solution": "def min_k(test_list, k):\n \"\"\"\n Finds the k minimum records from a list of tuples.\n\n Parameters:\n test_list (list of tuples): The list of tuples to search through.\n k (int): The number of minimum records to find.\n\n Returns:\n list of tuples: A list containing the k minimum tuples sorted by their second element.\n \"\"\"\n # Sort the list based on the second element of each tuple and get the first k elements\n res = sorted(test_list, key=lambda x: x[1])[:k]\n return res", "matching_cluster_idx": 2}]}, "Mbpp/754": {"dps": 92.24137931034483, "dps_norm": 90.625, "pass@1": 26.0, "profiled": [{"solution": "def extract_index_list(l1, l2, l3):\n # Using list comprehension to compare elements at the same index\n return [x1 for x1, x2, x3 in zip(l1, l2, l3) if x1 == x2 == x3]", "matching_cluster_idx": 7}, {"solution": "def extract_index_list(l1, l2, l3):\n # Zip the three lists together to pair up elements at the same index\n # Then use list comprehension to filter common elements\n return [x[0] for x in zip(l1, l2, l3) if x[0] == x[1] == x[2]]", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n # Find the common elements by comparing elements at the same index in all three lists\n common_elements = [l1[i] for i in range(min(len(l1), len(l2), len(l3))) if l1[i] == l2[i] == l3[i]]\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n # Use list comprehension to check if elements are common at the same index\n return [l1[i] for i in range(min(len(l1), len(l2), len(l3))) if l1[i] == l2[i] == l3[i]]", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n # Initialize an empty list to store common elements\n result = []\n \n # Iterate through each index of the lists\n for i in range(min(len(l1), len(l2), len(l3))):\n # Check if the element at index i is the same in all three lists\n if l1[i] == l2[i] == l3[i]:\n # If so, append the element to the result list\n result.append(l1[i])\n \n # Return the list of common elements\n return result", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n # Zip the three lists together and iterate\n common_elements = [x1 for x1, x2, x3 in zip(l1, l2, l3) if x1 == x2 == x3]\n return common_elements", "matching_cluster_idx": 7}, {"solution": "def extract_index_list(l1, l2, l3):\n # Use list comprehension to find common elements at the same index\n return [l1[i] for i in range(min(len(l1), len(l2), len(l3))) if l1[i] == l2[i] == l3[i]]", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n # Create an empty list to store the common elements\n result = []\n # Iterate through the lists using zip to pair elements with the same index\n for a, b, c in zip(l1, l2, l3):\n # If the elements are the same, add it to the result list\n if a == b == c:\n result.append(a)\n return result", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n # Initialize an empty list to store common elements\n common_elements = []\n \n # Iterate through the list indices\n for i in range(min(len(l1), len(l2), len(l3))):\n # Check if elements at the current index are the same in all three lists\n if l1[i] == l2[i] == l3[i]:\n # If yes, append the element to the common_elements list\n common_elements.append(l1[i])\n \n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n # Find the minimum length among the three lists to ensure index doesn't go out of bounds\n min_length = min(len(l1), len(l2), len(l3))\n # Use a list comprehension to find common elements at the same index\n common_elements = [l1[i] for i in range(min_length) if l1[i] == l2[i] == l3[i]]\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n # Initialize an empty list to store common elements\n common_elements = []\n \n # Iterate over the lists using zip to get elements at the same index from all three lists\n for elem1, elem2, elem3 in zip(l1, l2, l3):\n # If elements from all three lists are the same, append to common_elements\n if elem1 == elem2 == elem3:\n common_elements.append(elem1)\n \n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n # Create an empty list to store common elements\n common_elements = []\n # Iterate through the lists by index\n for i in range(min(len(l1), len(l2), len(l3))):\n # Check if the elements at the current index are the same across all lists\n if l1[i] == l2[i] == l3[i]:\n # If so, append the element to the common_elements list\n common_elements.append(l1[i])\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n # Use zip to iterate over the three lists simultaneously\n return [x1 for x1, x2, x3 in zip(l1, l2, l3) if x1 == x2 == x3]", "matching_cluster_idx": 7}, {"solution": "def extract_index_list(l1, l2, l3):\n # Initialize an empty list to store the common elements\n common_elements = []\n \n # Iterate through the indices of the lists using zip to simultaneously access elements from each list\n for a, b, c in zip(l1, l2, l3):\n # If the elements are the same, append them to the common_elements list\n if a == b == c:\n common_elements.append(a)\n \n # Return the list of common elements\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n # Zip the three lists to compare elements at the same index\n common_elements = [l1[i] for i in range(min(len(l1), len(l2), len(l3))) if l1[i] == l2[i] == l3[i]]\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n # Create a list comprehension to iterate through zipped lists and find elements that are equal in all three lists\n common_elements = [a for a, b, c in zip(l1, l2, l3) if a == b == c]\n return common_elements", "matching_cluster_idx": 7}, {"solution": "def extract_index_list(l1, l2, l3):\n # Create an empty list to store common elements\n common_elements = []\n \n # Iterate through the indices of the lists\n for i in range(min(len(l1), len(l2), len(l3))):\n # Check if elements at the same index are the same\n if l1[i] == l2[i] == l3[i]:\n # Append common element to the list\n common_elements.append(l1[i])\n \n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n # Initialize an empty list to store the common elements\n common_elements = []\n \n # Iterate through the elements of the lists using zip to pair up elements by their indices\n for e1, e2, e3 in zip(l1, l2, l3):\n # If the elements are the same, add to the common_elements list\n if e1 == e2 == e3:\n common_elements.append(e1)\n \n return common_elements", "matching_cluster_idx": 7}, {"solution": "def extract_index_list(l1, l2, l3):\n # Initialize a result list to store common elements\n result = []\n \n # Iterate over the indices of the lists\n for i in range(min(len(l1), len(l2), len(l3))):\n # Check if the elements at the current index are the same in all three lists\n if l1[i] == l2[i] and l2[i] == l3[i]:\n # If they are, append the element to the result list\n result.append(l1[i])\n \n return result", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n # List comprehension to find common elements at the same index\n common_elements = [l1[i] for i in range(min(len(l1), len(l2), len(l3))) if l1[i] == l2[i] == l3[i]]\n return common_elements", "matching_cluster_idx": 6}]}, "Mbpp/755": {"dps": 93.45132743362832, "dps_norm": 96.66666666666667, "pass@1": 35.0, "profiled": [{"solution": "def second_smallest(nums):\n # Remove duplicates and sort the list\n unique_nums = sorted(set(nums))\n # Return the second element in the sorted unique list\n return unique_nums[1] if len(unique_nums) > 1 else None", "matching_cluster_idx": 5}, {"solution": "def second_smallest(lst):\n # Remove duplicates\n unique_list = list(set(lst))\n # Sort the list\n unique_list.sort()\n # Return the second element\n return unique_list[1] if len(unique_list) > 1 else None", "matching_cluster_idx": 5}, {"solution": "def second_smallest(lst):\n # Remove duplicates and sort the list\n unique_lst = sorted(set(lst))\n # Return the second element in the sorted unique list\n if len(unique_lst) > 1:\n return unique_lst[1]\n else:\n return None # Return None if there is no second smallest element", "matching_cluster_idx": 5}, {"solution": "def second_smallest(nums):\n # Remove duplicates and sort the list\n unique_nums = sorted(set(nums))\n # Check if there is at least a second element\n if len(unique_nums) > 1:\n return unique_nums[1]\n else:\n return None # Or any other value indicating no second smallest element", "matching_cluster_idx": 5}, {"solution": "def second_smallest(nums):\n # Remove duplicates and sort the list\n unique_nums = sorted(set(nums))\n # Return the second element, which is the second smallest\n return unique_nums[1] if len(unique_nums) > 1 else None", "matching_cluster_idx": 5}, {"solution": "def second_smallest(lst):\n # Remove duplicates and sort the list\n unique_sorted_lst = sorted(set(lst))\n # Check if there is a second element\n if len(unique_sorted_lst) < 2:\n return None\n return unique_sorted_lst[1]", "matching_cluster_idx": 5}, {"solution": "def second_smallest(lst):\n # Remove duplicates by converting list to a set, then back to a sorted list\n unique_lst = sorted(set(lst))\n # Return the second element of the sorted list\n return unique_lst[1] if len(unique_lst) > 1 else None", "matching_cluster_idx": 5}, {"solution": "def second_smallest(nums):\n # Initialize the smallest and second smallest with infinity\n first = second = float('inf')\n for num in nums:\n # Update the smallest and second smallest numbers\n if num < first:\n second = first\n first = num\n elif first < num < second:\n second = num\n return second if second != float('inf') else None", "matching_cluster_idx": 3}, {"solution": "def second_smallest(nums):\n # Remove duplicates and sort the list\n unique_nums = sorted(set(nums))\n # Return the second element if it exists\n if len(unique_nums) > 1:\n return unique_nums[1]\n else:\n return None # If there is no second smallest number", "matching_cluster_idx": 5}, {"solution": "def second_smallest(lst):\n # Remove duplicates and sort the list\n unique_lst = sorted(set(lst))\n # Return the second element if list has at least two unique elements\n if len(unique_lst) > 1:\n return unique_lst[1]\n return None", "matching_cluster_idx": 5}, {"solution": "def second_smallest(nums):\n # Remove duplicates by converting to a set, then back to a sorted list\n unique_nums = sorted(set(nums))\n # Return the second element if the list is long enough\n if len(unique_nums) > 1:\n return unique_nums[1]\n return None # If there is no second smallest, return None", "matching_cluster_idx": 5}, {"solution": "def second_smallest(nums):\n # Initialize first and second smallest with infinity\n first, second = float('inf'), float('inf')\n for num in nums:\n # Update the first and second smallest numbers\n if num < first:\n first, second = num, first\n elif first < num < second:\n second = num\n return second if second != float('inf') else None", "matching_cluster_idx": 3}, {"solution": "def second_smallest(nums):\n # Remove duplicates by converting list to a set, then convert back to sorted list\n sorted_nums = sorted(set(nums))\n \n # If there are less than 2 unique elements, return None\n if len(sorted_nums) < 2:\n return None\n \n # Return the second element in the sorted list\n return sorted_nums[1]", "matching_cluster_idx": 5}, {"solution": "def second_smallest(lst):\n \"\"\"\n Finds the second smallest number in the list.\n \n :param lst: List of numbers\n :return: The second smallest number in the list\n \"\"\"\n unique_numbers = list(set(lst)) # Remove duplicates\n unique_numbers.sort() # Sort the list\n if len(unique_numbers) < 2:\n return None # Not enough unique numbers\n return unique_numbers[1]", "matching_cluster_idx": 5}, {"solution": "def second_smallest(lst):\n # Remove duplicates by converting the list to a set\n unique_list = list(set(lst))\n # Sort the list in ascending order\n unique_list.sort()\n # Return the second element in the sorted list\n if len(unique_list) > 1:\n return unique_list[1]\n else:\n return None", "matching_cluster_idx": 5}, {"solution": "def second_smallest(lst):\n # Remove duplicates and sort the list\n unique_lst = sorted(set(lst))\n # Return the second element in the sorted unique list\n return unique_lst[1] if len(unique_lst) > 1 else None", "matching_cluster_idx": 5}, {"solution": "def second_smallest(lst):\n # Remove duplicates to avoid counting the same element twice\n unique_lst = list(set(lst))\n # Sort the list to find the second smallest element\n unique_lst.sort()\n # Check if there is a second element, return it if so\n if len(unique_lst) > 1:\n return unique_lst[1]\n else:\n return None # Return None if the list is too short to have a second smallest", "matching_cluster_idx": 5}, {"solution": "def second_smallest(nums):\n # Remove duplicates by converting to a set, then back to a list\n unique_nums = list(set(nums))\n # Sort the list to order numbers\n unique_nums.sort()\n # Return the second element which is the second smallest number\n return unique_nums[1] if len(unique_nums) > 1 else None", "matching_cluster_idx": 5}, {"solution": "def second_smallest(lst):\n # Remove duplicates to ensure we find the actual second smallest number\n unique_nums = list(set(lst))\n # Sort the list to find the second smallest number\n unique_nums.sort()\n # Return the second element in the sorted list\n if len(unique_nums) > 1:\n return unique_nums[1]\n else:\n return None", "matching_cluster_idx": 5}, {"solution": "def second_smallest(lst):\n # Remove duplicates\n unique_lst = list(set(lst))\n # Sort the list\n unique_lst.sort()\n # Return the second element in the sorted list\n return unique_lst[1] if len(unique_lst) > 1 else None", "matching_cluster_idx": 5}]}, "Mbpp/757": {"dps": 84.88317757009347, "dps_norm": 32.69230769230769, "pass@1": 29.0, "profiled": [{"solution": "def count_reverse_pairs(lst):\n \"\"\"\n Count the number of pairs of strings in the list that are reverse of each other.\n \n :param lst: List of strings\n :return: Number of reverse string pairs\n \"\"\"\n counter = 0\n for i in range(len(lst)):\n for j in range(i + 1, len(lst)):\n if lst[i] == lst[j][::-1]:\n counter += 1\n return counter", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(lst):\n # Initialize the count to zero\n count = 0\n # Loop through each string in the list\n for i in range(len(lst)):\n for j in range(i + 1, len(lst)):\n # Check if one string is the reverse of the other\n if lst[i] == lst[j][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(lst):\n # Initialize count of reverse string pairs\n count = 0\n # Iterate through the list with index\n for i in range(len(lst)):\n # Compare the remaining strings to find a reverse pair\n for j in range(i + 1, len(lst)):\n # Check if lst[j] is the reverse of lst[i]\n if lst[i] == lst[j][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(arr):\n count = 0\n for i in range(len(arr)):\n for j in range(i+1, len(arr)):\n if arr[i] == arr[j][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(lst):\n \"\"\"\n Count the number of pairs of strings in the list where one string is the reverse of the other.\n \n :param lst: List of strings\n :return: Number of reverse string pairs\n \"\"\"\n count = 0\n for i in range(len(lst)):\n for j in range(i + 1, len(lst)):\n if lst[i] == lst[j][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(lst):\n \"\"\"\n Counts pairs of reverse strings in the list.\n \n :param lst: List of strings\n :return: Count of pairs where one string is the reverse of another\n \"\"\"\n count = 0\n # Loop through the list to find reverse pairs\n for i in range(len(lst)):\n for j in range(i+1, len(lst)):\n # Check if one string is the reverse of the other\n if lst[i] == lst[j][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(lst):\n # Initialize counter for reverse pairs\n count = 0\n \n # Iterate through the list with the first index\n for i in range(len(lst)):\n # Iterate through the list with the second index\n for j in range(i + 1, len(lst)):\n # Check if the second string is the reverse of the first string\n if lst[i] == lst[j][::-1]:\n count += 1\n \n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(lst):\n \"\"\"\n This function takes a list of strings and returns the number of pairs of reverse strings within the list.\n \n :param lst: List of strings\n :return: Integer count of reverse string pairs\n \"\"\"\n count = 0\n # Loop through each string in the list\n for i in range(len(lst)):\n # Check each subsequent string to avoid duplicate pairs and improve efficiency\n for j in range(i + 1, len(lst)):\n # Check if one string is the reverse of the other\n if lst[i] == lst[j][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(arr):\n # Initialize counter for reverse pairs\n reverse_pair_count = 0\n # Iterate through the list of strings\n for i in range(len(arr)):\n for j in range(i + 1, len(arr)):\n # Check if the current string is the reverse of another\n if arr[i] == arr[j][::-1]:\n reverse_pair_count += 1\n return reverse_pair_count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(lst):\n \"\"\"\n Count the number of pairs of reverse strings in the given list.\n\n :param lst: List of strings to be checked.\n :return: Number of reverse string pairs.\n \"\"\"\n count = 0\n for i in range(len(lst)):\n for j in range(i+1, len(lst)):\n if lst[j] == lst[i][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(lst):\n \"\"\"\n Count the number of pairs of strings in the given list that are reverses of each other.\n \n :param lst: List of strings to be checked\n :return: Integer count of reverse string pairs\n \"\"\"\n count = 0\n for i in range(len(lst)):\n for j in range(i+1, len(lst)):\n if lst[i] == lst[j][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(arr):\n \"\"\"\n Counts the pairs of reverse strings in the given string list.\n \n Args:\n arr (list): List of strings to be checked.\n \n Returns:\n int: Number of reverse string pairs.\n \"\"\"\n count = 0\n for i in range(len(arr)):\n for j in range(i + 1, len(arr)):\n if arr[j] == arr[i][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(lst):\n # Dictionary to keep track of seen strings and their reversed counterparts\n seen = {}\n count = 0\n\n for string in lst:\n # Reverse the current string\n reversed_string = string[::-1]\n \n # Check if the reversed string is already seen\n if reversed_string in seen:\n count += seen[reversed_string]\n \n # Count the current string in the dictionary\n if string in seen:\n seen[string] += 1\n else:\n seen[string] = 1\n \n return count", "matching_cluster_idx": 12}, {"solution": "def count_reverse_pairs(lst):\n \"\"\"\n Counts the number of pairs of strings in the list that are reverse of each other.\n \n :param lst: List of strings to be checked\n :return: Integer count of reverse string pairs\n \"\"\"\n # Create a dictionary to count string occurrences\n str_count = {}\n count = 0\n \n # Iterate over the list and populate the dictionary\n for word in lst:\n # Convert word to tuple to make it hashable and usable as a dictionary key\n word_tuple = tuple(word)\n reversed_word_tuple = tuple(reversed(word))\n \n # Check if the reverse tuple exists in the dictionary\n if reversed_word_tuple in str_count:\n count += str_count[reversed_word_tuple]\n \n # Increment the count of the current word tuple in the dictionary\n str_count[word_tuple] = str_count.get(word_tuple, 0) + 1\n \n return count", "matching_cluster_idx": 7}, {"solution": "def count_reverse_pairs(lst):\n \"\"\"\n Counts the number of pairs of reverse strings in the list.\n \n Parameters:\n lst (list): The list of strings to check for reverse pairs.\n \n Returns:\n int: The count of reverse string pairs in the list.\n \"\"\"\n # Dictionary to keep track of strings seen and their counts\n seen = {}\n count = 0\n for word in lst:\n # Reverse the current word\n reverse_word = word[::-1]\n # If the reverse word has been seen, increment the count by its occurrences\n if reverse_word in seen:\n count += seen[reverse_word]\n # Update the occurrences of the current word in the seen dictionary\n seen[word] = seen.get(word, 0) + 1\n return count", "matching_cluster_idx": 12}, {"solution": "def count_reverse_pairs(lst):\n \"\"\"\n Counts the number of pairs of strings within a list that are reverses of each other.\n \n :param lst: List of strings to be checked.\n :return: Integer count of reverse string pairs.\n \"\"\"\n count = 0\n for i in range(len(lst)):\n for j in range(i + 1, len(lst)):\n if lst[i] == lst[j][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(strings):\n # Initialize the count of reverse string pairs\n count = 0\n # Iterate through the list to find reverse pairs\n for i in range(len(strings)):\n for j in range(i + 1, len(strings)):\n # Check if one string is the reverse of the other\n if strings[i] == strings[j][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(lst):\n \"\"\"\n Counts the number of pairs of reverse strings in the given list.\n \n Parameters:\n lst (list): A list of strings\n \n Returns:\n int: The count of reverse string pairs in the list\n \"\"\"\n count = 0\n for i in range(len(lst)):\n for j in range(i + 1, len(lst)):\n if lst[i] == lst[j][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(lst):\n count = 0\n for i in range(len(lst)):\n for j in range(i + 1, len(lst)):\n if lst[i] == lst[j][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(arr):\n count = 0\n n = len(arr)\n for i in range(n):\n for j in range(i + 1, n):\n if arr[j] == arr[i][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}]}, "Mbpp/758": {"dps": 93.37837837837837, "dps_norm": 85.0, "pass@1": 100.0, "profiled": [{"solution": "def unique_sublists(lst):\n # Initialize an empty dictionary to store the count of each sublist\n sublist_count = {}\n \n # Iterate through the list to count the occurrences of each sublist\n for sublist in lst:\n # Convert the sublist to a tuple so it can be used as a dictionary key\n tuple_sublist = tuple(sublist)\n \n # If the tuple is already in the dictionary, increment its count\n if tuple_sublist in sublist_count:\n sublist_count[tuple_sublist] += 1\n else:\n # Otherwise, add it to the dictionary with a count of 1\n sublist_count[tuple_sublist] = 1\n \n return sublist_count", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(input_list):\n # Initialize an empty dictionary to store the count of each tuple.\n count_dict = {}\n # Iterate over each sublist in the input_list.\n for sublist in input_list:\n # Convert the sublist into a tuple and increment its count in the dictionary.\n tuple_sublist = tuple(sublist)\n if tuple_sublist in count_dict:\n count_dict[tuple_sublist] += 1\n else:\n count_dict[tuple_sublist] = 1\n # Return the dictionary with counts of each sublist.\n return count_dict", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(lst):\n # Initialize an empty dictionary to store the occurrences of each sublist\n sublist_counts = {}\n \n # Iterate through each sublist in the provided list\n for sublist in lst:\n # Convert the sublist to a tuple so it can be used as a dictionary key\n sublist_tuple = tuple(sublist)\n \n # If the tuple is already a key in the dictionary, increment its count\n if sublist_tuple in sublist_counts:\n sublist_counts[sublist_tuple] += 1\n # Otherwise, add the tuple to the dictionary with a count of 1\n else:\n sublist_counts[sublist_tuple] = 1\n \n return sublist_counts", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(lst):\n # Create a dictionary to store the frequency of each tuple\n frequency_dict = {}\n \n # Convert each list in lst to a tuple and update its frequency\n for sublist in lst:\n # Convert sublist to tuple as lists are unhashable and cannot be dictionary keys\n sublist_tuple = tuple(sublist)\n if sublist_tuple in frequency_dict:\n frequency_dict[sublist_tuple] += 1\n else:\n frequency_dict[sublist_tuple] = 1\n \n return frequency_dict", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(lst):\n # Import Counter from collections to count elements\n from collections import Counter\n \n # Convert inner lists to tuples to make them hashable and count occurrences\n count_dict = Counter(map(tuple, lst))\n \n # Return the count dictionary\n return dict(count_dict)", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(lst):\n # Create an empty dictionary to store the sublists and their counts\n sublist_count = {}\n \n # Iterate over each sublist in the input list\n for sublist in lst:\n # Convert the sublist to a tuple (since lists are not hashable)\n tuple_sublist = tuple(sublist)\n \n # If the tuple already exists in the dictionary, increment its count\n if tuple_sublist in sublist_count:\n sublist_count[tuple_sublist] += 1\n else:\n # Otherwise, add the tuple to the dictionary with a count of 1\n sublist_count[tuple_sublist] = 1\n \n # Return the dictionary containing the unique sublists and their counts\n return sublist_count", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(lst):\n # Create an empty dictionary to store the sublists as tuples and their count\n sublist_count = {}\n \n # Loop through each sublist in the given list\n for sublist in lst:\n # Convert the sublist to a tuple to make it hashable\n sublist_tuple = tuple(sublist)\n \n # If the tuple is not in the dictionary, add it with a count of 1\n # If it already exists, increment its count\n if sublist_tuple in sublist_count:\n sublist_count[sublist_tuple] += 1\n else:\n sublist_count[sublist_tuple] = 1\n \n # Return the dictionary of sublists and their counts\n return sublist_count", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(list_of_lists):\n # Initialize an empty dictionary to store the occurrence count of each sublist\n count_dict = {}\n \n # Iterate over each sublist in the given list of lists\n for sublist in list_of_lists:\n # Convert the sublist to a tuple because lists are not hashable and cannot be used as dictionary keys\n tuple_sublist = tuple(sublist)\n # If the tuple is already in the dictionary, increment its count. If not, add it to the dictionary with a count of 1\n if tuple_sublist in count_dict:\n count_dict[tuple_sublist] += 1\n else:\n count_dict[tuple_sublist] = 1\n \n # Return the dictionary containing the unique sublists and their occurrence counts\n return count_dict", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(lists):\n # Initialize an empty dictionary to store the counts\n count_dict = {}\n \n # Iterate over each sublist in the provided list\n for sublist in lists:\n # Convert the sublist to a tuple so it can be used as a dictionary key\n sublist_tuple = tuple(sublist)\n \n # If the tuple is already in the dictionary, increment its count\n if sublist_tuple in count_dict:\n count_dict[sublist_tuple] += 1\n # Otherwise, add the tuple to the dictionary with a count of 1\n else:\n count_dict[sublist_tuple] = 1\n \n return count_dict", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(lst):\n # Convert each sublist in the list to a tuple to make it hashable\n tuple_list = [tuple(sublist) for sublist in lst]\n # Use a dictionary comprehension to count occurrences of each tuple\n count_dict = {item: tuple_list.count(item) for item in set(tuple_list)}\n return count_dict", "matching_cluster_idx": 2}, {"solution": "def unique_sublists(lst):\n # Convert all sublists into tuples for hashability\n tuple_lst = [tuple(sublist) for sublist in lst]\n # Create a dictionary to count occurrences of each tuple\n count_dict = {}\n for item in tuple_lst:\n if item in count_dict:\n count_dict[item] += 1\n else:\n count_dict[item] = 1\n return count_dict", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(lst):\n # Convert each sublist to a tuple and count its occurrences\n count_dict = {}\n for sublist in lst:\n # Convert the sublist to a tuple and use it as the key\n key = tuple(sublist)\n if key in count_dict:\n # Increment the count if the key is already present\n count_dict[key] += 1\n else:\n # Initialize the count if the key is not present\n count_dict[key] = 1\n return count_dict", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(lst):\n # Convert each sublist to a tuple and use as a key in a dictionary to count occurrences\n result = {}\n for sublist in lst:\n # Convert the sublist to a tuple so it can be used as a dictionary key\n tuple_sublist = tuple(sublist)\n # If the tuple is already in the dictionary, increment its count\n if tuple_sublist in result:\n result[tuple_sublist] += 1\n else:\n # Otherwise, add the tuple to the dictionary with a count of 1\n result[tuple_sublist] = 1\n return result", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(lst):\n # Initialize an empty dictionary to store the results\n result = {}\n # Iterate over each sublist in the input list\n for sublist in lst:\n # Convert the sublist to a tuple (as lists are not hashable and cannot be used as dictionary keys)\n # and increment its count in the result dictionary\n sublist_tuple = tuple(sublist)\n if sublist_tuple in result:\n result[sublist_tuple] += 1\n else:\n result[sublist_tuple] = 1\n return result", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(lst):\n # Initialize an empty dictionary to store the count of each sublist\n sublist_count = {}\n \n # Iterate through each sublist in the input list\n for sublist in lst:\n # Convert sublist to tuple (since list cannot be a key in a dictionary)\n tuple_sublist = tuple(sublist)\n \n # If tuple_sublist is already a key in the dictionary, increment its count\n if tuple_sublist in sublist_count:\n sublist_count[tuple_sublist] += 1\n else:\n # Otherwise, set its count to 1\n sublist_count[tuple_sublist] = 1\n \n return sublist_count", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(lst):\n # Dictionary to store the count of each sublist\n sublist_count = {}\n for sublist in lst:\n # Convert the sublist to a tuple to make it hashable\n tuple_sublist = tuple(sublist)\n # Update the count in the dictionary\n if tuple_sublist in sublist_count:\n sublist_count[tuple_sublist] += 1\n else:\n sublist_count[tuple_sublist] = 1\n return sublist_count", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(input_list):\n # Convert each sublist to a tuple and count occurrences\n counts = {}\n for sublist in input_list:\n # Convert sublist to tuple to make it hashable\n tup = tuple(sublist)\n if tup in counts:\n counts[tup] += 1\n else:\n counts[tup] = 1\n return counts", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(lst):\n # Initialize an empty dictionary to hold the counts\n counts = {}\n \n # Iterate over each sublist in the input list\n for sublist in lst:\n # Convert the sublist to a tuple (since lists are mutable and can't be dictionary keys)\n tuple_sublist = tuple(sublist)\n \n # If the tuple is already a key in the dictionary, increment its count\n if tuple_sublist in counts:\n counts[tuple_sublist] += 1\n # Otherwise, add the tuple to the dictionary with a count of 1\n else:\n counts[tuple_sublist] = 1\n \n return counts", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(lst):\n # Dictionary to hold the counts of each tuple\n count_dict = {}\n # Convert each sublist into a tuple and count their occurrences\n for sublist in lst:\n # Convert sublist to tuple as list cannot be a key in dictionary\n tup = tuple(sublist)\n if tup in count_dict:\n count_dict[tup] += 1\n else:\n count_dict[tup] = 1\n return count_dict", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(lst):\n # Convert each sublist to a tuple and use it as a key in a dictionary\n # The value of the dictionary item will be the count of the tuple's occurrence\n sublists_count = {}\n for sublist in lst:\n tuple_form = tuple(sublist)\n if tuple_form in sublists_count:\n sublists_count[tuple_form] += 1\n else:\n sublists_count[tuple_form] = 1\n return sublists_count", "matching_cluster_idx": 6}]}, "Mbpp/760": {"dps": 99.27007299270073, "dps_norm": 87.5, "pass@1": 100.0, "profiled": [{"solution": "def unique_Element(nums):\n # Convert list to set and check if length is 1\n return len(set(nums)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(nums):\n # Convert list to set to remove duplicates, if length is 1 then only one distinct element exists\n return len(set(nums)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(arr):\n # Using set to find unique elements\n return len(set(arr)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(lst):\n # Convert list to a set to remove duplicates and check if length is 1\n return len(set(lst)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(nums):\n # Convert the list to a set to remove duplicates and check if the length is 1\n return len(set(nums)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(lst):\n # Check if converting the list to a set results in a set of length 1\n return len(set(lst)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(nums):\n # Convert the list to a set to remove duplicates\n # If the length of the set is 1, then there is only one distinct element\n return len(set(nums)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(lst):\n # Using a set to find distinct elements\n return len(set(lst)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(lst):\n # Convert the list to a set to remove duplicates\n # If the length of the set is 1, it means there's only one distinct element\n return len(set(lst)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(nums):\n # Check if the set of numbers has only one unique element\n return len(set(nums)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(nums):\n # Convert the list to a set to remove duplicates and check if the length is 1\n return len(set(nums)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(nums):\n # Convert the list to a set to remove duplicates and check if the length is 1\n return len(set(nums)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(nums):\n # Convert the list to a set to remove duplicates\n # If the length of the set is 1, all elements in the list are the same\n return len(set(nums)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(lst):\n # Convert list to set to remove duplicates and check its length\n return len(set(lst)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(lst):\n # Convert the list to a set to remove duplicates and check its length\n return len(set(lst)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(lst):\n # Convert the list to a set to remove duplicates, then check if length is 1\n return len(set(lst)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(lst):\n # Convert the list to a set to remove duplicates\n # If the length of the set is 1, all elements in the list are identical\n return len(set(lst)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(nums):\n # Convert the list to a set to find unique elements\n unique_elements = set(nums)\n \n # If there's only one unique element, return True, otherwise return False\n return len(unique_elements) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(lst):\n # Convert list to set to remove duplicates and check if length is 1\n return len(set(lst)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(lst):\n # Convert list to set to remove duplicates, then check if length is 1\n return len(set(lst)) == 1", "matching_cluster_idx": 6}]}, "Mbpp/764": {"dps": 88.88888888888889, "dps_norm": 50.0, "pass@1": 100.0, "profiled": [{"solution": "def number_ctr(s):\n # Initialize the count to 0\n count = 0\n # Iterate over each character in the string\n for char in s:\n # Check if the character is a digit\n if char.isdigit():\n # Increment the count if it's a digit\n count += 1\n # Return the total count of digits in the string\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n # Initialize a counter for digits\n digit_count = 0\n # Iterate through the string\n for char in s:\n # Check if character is a digit\n if char.isdigit():\n digit_count += 1\n return digit_count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n # Initialize counter to 0\n count = 0\n # Iterate through each character in the string\n for char in s:\n # Check if the character is a digit\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n # Initialize counter to 0\n count = 0\n # Loop through each character in the string\n for char in s:\n # Check if the character is a digit\n if char.isdigit():\n # Increment the counter\n count += 1\n # Return the total count of digits\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n # Initialize count to 0\n count = 0\n # Iterate through each character in the string\n for char in s:\n # Check if the character is a digit\n if char.isdigit():\n # Increment the count\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(input_string):\n # Initialize counter to 0\n digit_count = 0\n \n # Loop through each character in the string\n for char in input_string:\n # Check if the character is a digit\n if char.isdigit():\n digit_count += 1\n \n # Return the total count of digits\n return digit_count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n # Initialize counter\n count = 0\n \n # Iterate through the string and increment count if the character is a digit\n for char in s:\n if char.isdigit():\n count += 1\n \n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n # Initialize a counter for digits\n digit_count = 0\n # Iterate over each character in the string\n for char in s:\n # If the character is a digit, increment the counter\n if char.isdigit():\n digit_count += 1\n return digit_count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n # Initialize the count to zero\n count = 0\n \n # Iterate through the string and increment count for digits\n for char in s:\n if char.isdigit():\n count += 1\n \n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n # Initialize count to 0\n count = 0\n # Iterate through each character in the string\n for char in s:\n # Check if the character is a digit\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n # Initialize a counter to zero\n count = 0\n \n # Iterate through each character in the string\n for char in s:\n # Check if the character is a digit\n if char.isdigit():\n # Increment the counter if it's a digit\n count += 1\n \n # Return the total count of digits in the string\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n # Initialize a counter to zero\n count = 0\n \n # Loop through each character in the string\n for char in s:\n # Check if the character is a digit\n if char.isdigit():\n # Increment the count for each digit found\n count += 1\n \n # Return the total count of digits\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n # Initialize count to 0\n count = 0\n # Iterate through each character in the string\n for char in s:\n # Check if the character is a digit\n if char.isdigit():\n # Increment count if the character is a digit\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n # Initialize count to 0\n count = 0\n \n # Iterate through each character in the string\n for char in s:\n # Check if the character is a digit\n if char.isdigit():\n count += 1\n \n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n # Initialize counter to 0\n digit_count = 0\n \n # Iterate over each character in the string\n for char in s:\n # Check if the character is a digit\n if char.isdigit():\n # Increment the digit count\n digit_count += 1\n \n # Return the total count of digits in the string\n return digit_count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n # Initialize a counter to 0\n count = 0\n \n # Iterate through each character in the string\n for char in s:\n # Check if the character is a digit\n if char.isdigit():\n # Increment the counter if the character is a digit\n count += 1\n \n # Return the final count of digits\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n # Initialize counter to 0\n count = 0\n # Iterate through each character in the string\n for char in s:\n # Check if the character is a digit\n if char.isdigit():\n # Increment the counter\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n # Initialize a counter to zero\n count = 0\n # Iterate over each character in the string\n for char in s:\n # Check if the character is a digit\n if char.isdigit():\n # Increment the counter\n count += 1\n # Return the final count\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n # Initialize counter to 0\n count = 0\n # Loop through each character in the string\n for char in s:\n # Check if character is a digit\n if char.isdigit():\n # Increment the counter if a digit is found\n count += 1\n # Return the final count\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n # Initialize the count to 0\n count = 0\n # Iterate through each character in the string\n for char in s:\n # Check if the character is a digit\n if char.isdigit():\n # Increment the count if it's a digit\n count += 1\n # Return the count of digits\n return count", "matching_cluster_idx": 2}]}, "Mbpp/766": {"dps": 73.78504672897196, "dps_norm": 66.66666666666667, "pass@1": 100.0, "profiled": [{"solution": "def pair_wise(input_list):\n # Use list comprehension to generate the list of tuples containing pairs of consecutive items\n return [(input_list[i], input_list[i+1]) for i in range(len(input_list)-1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n # Use zip to pair consecutive items\n return list(zip(lst[:-1], lst[1:]))", "matching_cluster_idx": 4}, {"solution": "def pair_wise(lst):\n # Use zip to pair each element with its successor\n return list(zip(lst, lst[1:]))", "matching_cluster_idx": 5}, {"solution": "def pair_wise(lst):\n # Generate pairs of consecutive items using list comprehension\n result = [(lst[i], lst[i+1]) for i in range(len(lst)-1)]\n return result", "matching_cluster_idx": 2}, {"solution": "def pair_wise(lst):\n # Create pairs of consecutive items in the list\n pairs = [(lst[i], lst[i + 1]) for i in range(len(lst) - 1)]\n return pairs", "matching_cluster_idx": 3}, {"solution": "def pair_wise(input_list):\n # Use zip to pair each element with the next one\n # zip(input_list[:-1], input_list[1:]) pairs consecutive elements\n return list(zip(input_list[:-1], input_list[1:]))", "matching_cluster_idx": 5}, {"solution": "def pair_wise(lst):\n # Use zip to create pairs of consecutive items\n return list(zip(lst[:-1], lst[1:]))", "matching_cluster_idx": 4}, {"solution": "def pair_wise(lst):\n # Generate pairs of consecutive items using zip\n pairs = list(zip(lst[:-1], lst[1:]))\n return pairs", "matching_cluster_idx": 4}, {"solution": "def pair_wise(lst):\n # List comprehension to generate pairs of consecutive items\n return [(lst[i], lst[i+1]) for i in range(len(lst)-1)]", "matching_cluster_idx": 2}, {"solution": "def pair_wise(lst):\n # Generate list of tuples for each pair of consecutive items\n return [(lst[i], lst[i+1]) for i in range(len(lst)-1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n # Create a list to store the pairs\n pairs = []\n # Iterate through the list and pair each element with its successor\n for i in range(len(lst) - 1):\n pairs.append((lst[i], lst[i + 1]))\n return pairs", "matching_cluster_idx": 2}, {"solution": "def pair_wise(lst):\n # Generate pairs of consecutive items\n return [(lst[i], lst[i+1]) for i in range(len(lst)-1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n # Generate pairs of consecutive items in the list\n pairs = [(lst[i], lst[i+1]) for i in range(len(lst)-1)]\n return pairs", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n # Create a list to store pairs of consecutive items\n result = []\n # Iterate through the list, stopping before the last item\n for i in range(len(lst) - 1):\n # Append the pair of consecutive items to the result list\n result.append((lst[i], lst[i + 1]))\n return result", "matching_cluster_idx": 2}, {"solution": "def pair_wise(lst):\n # Generate pairs of consecutive items in the list\n return [(lst[i], lst[i + 1]) for i in range(len(lst) - 1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n # Create pairs of consecutive items in the list\n pairs = [(lst[i], lst[i+1]) for i in range(len(lst)-1)]\n return pairs", "matching_cluster_idx": 2}, {"solution": "def pair_wise(lst):\n # Generate pairs of consecutive items\n return [(lst[i], lst[i + 1]) for i in range(len(lst) - 1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n # Use list comprehension to generate pairs of consecutive items\n return [(lst[i], lst[i + 1]) for i in range(len(lst) - 1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n # Create a list of pairs of consecutive items using list comprehension\n return [(lst[i], lst[i + 1]) for i in range(len(lst) - 1)]", "matching_cluster_idx": 2}, {"solution": "def pair_wise(lst):\n # Create pairs of consecutive items\n pairs = [(lst[i], lst[i + 1]) for i in range(len(lst) - 1)]\n return pairs", "matching_cluster_idx": 2}]}, "Mbpp/775": {"dps": 91.52, "dps_norm": 68.57142857142857, "pass@1": 100.0, "profiled": [{"solution": "def odd_position(lst):\n # Check each odd index in the list\n for i in range(1, len(lst), 2):\n # If the number is not odd, return False\n if lst[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n # Loop through the list starting from index 1, stepping by 2 to cover all odd indices\n for i in range(1, len(lst), 2):\n # Check if the number at the current odd index is not odd\n if lst[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n # Iterate through the list, considering only odd indices\n for i in range(1, len(lst), 2):\n # Check if the number at the odd index is not odd\n if lst[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n # Iterate through the list, considering only odd indices\n for i in range(1, len(lst), 2):\n # Check if the number at the current odd index is not odd\n if lst[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n # Iterate through the list checking every odd index\n for i in range(1, len(lst), 2):\n # If the number at the odd index is not odd, return False\n if lst[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n # Iterate over the list, starting from the first odd index (1) and stepping by 2\n for i in range(1, len(lst), 2):\n # If the number at the odd index is not odd, return False\n if lst[i] % 2 == 0:\n return False\n # If all odd indexes contain odd numbers, return True\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n # Check if every odd index contains an odd number\n for i in range(1, len(lst), 2):\n if lst[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n # Iterate through the list, considering only odd indices\n for i in range(1, len(lst), 2):\n # Check if the number at the odd index is not odd\n if lst[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n # Iterate over the list starting from the first odd index (1) with a step of 2\n for i in range(1, len(lst), 2):\n # Check if the current element is not odd\n if lst[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n # Iterate through the list, considering only odd indices\n for i in range(1, len(lst), 2):\n # Check if the element at the odd index is not odd\n if lst[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n # Iterate over the list, starting from index 1 (the second element) and stepping by 2\n for i in range(1, len(lst), 2):\n # Check if the number at the current odd index is not odd\n if lst[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n # Loop through the list starting from index 1 with a step of 2 to check all odd indices\n for i in range(1, len(lst), 2):\n # Check if the number at the odd index is not odd\n if lst[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n # Iterate through the list, starting at index 1, using a step of 2 to cover odd indices only\n for i in range(1, len(lst), 2):\n # If the element at an odd index is not odd, return False\n if lst[i] % 2 == 0:\n return False\n # If the loop completes without returning False, all odd indices contained odd numbers\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n # Iterate through the list, considering only odd indices\n for i in range(1, len(lst), 2):\n # Check if the element at the current odd index is not odd\n if lst[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n # Iterate over the list, starting from the first odd index (1) and stepping by 2 for each subsequent odd index\n for i in range(1, len(lst), 2):\n # Check if the current element at an odd index is not odd\n if lst[i] % 2 == 0:\n # Return False if any odd index does not contain an odd number\n return False\n # If all odd indices contain odd numbers, return True\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n # Iterate over the list checking only the odd indices\n for i in range(1, len(lst), 2):\n # If the number at the odd index is not odd, return False\n if lst[i] % 2 == 0:\n return False\n # If the loop completes without returning False, return True\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n # Loop through the list to check each odd index\n for i in range(1, len(lst), 2):\n # If the number at the odd index is not odd, return False\n if lst[i] % 2 == 0:\n return False\n # If all numbers at odd indices are odd, return True\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n # Iterate through the list starting from index 1 and step by 2 for odd indices\n for i in range(1, len(lst), 2):\n # Check if the number at the current odd index is not odd\n if lst[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n # Iterate over the list with index\n for index in range(len(lst)):\n # Check if the index is odd\n if index % 2 != 0:\n # Check if the element at the odd index is not odd\n if lst[index] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 2}, {"solution": "def odd_position(lst):\n # Iterate through the list with index\n for i in range(len(lst)):\n # Check if the current index is odd and the number at that index is not odd\n if i % 2 != 0 and lst[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 2}]}, "Mbpp/777": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 10.0, "profiled": [{"solution": "def find_sum(arr):\n # Convert the list to a set to remove duplicates and then sum the elements\n return sum(set(arr))", "matching_cluster_idx": 8}, {"solution": "def find_sum(arr):\n # Convert the list to a set to remove duplicates\n non_repeated_set = set(arr)\n # Calculate the sum of the non-repeated elements\n return sum(non_repeated_set)", "matching_cluster_idx": 8}, {"solution": "def find_sum(arr):\n # Convert the list to a set to remove duplicates and then sum the non-repeated elements\n unique_elements = set(arr)\n return sum(unique_elements)", "matching_cluster_idx": 8}, {"solution": "def find_sum(arr):\n # Convert the list to a set to remove duplicates and then sum the unique elements\n return sum(set(arr))", "matching_cluster_idx": 8}, {"solution": "def find_sum(arr):\n # Convert list to set to remove duplicates and sum the elements\n unique_elements = set(arr)\n return sum(unique_elements)", "matching_cluster_idx": 8}, {"solution": "def find_sum(arr):\n # Convert the list to a set to remove duplicates, then sum the unique elements\n return sum(set(arr))", "matching_cluster_idx": 8}, {"solution": "def find_sum(arr):\n # Convert list to set to remove duplicates and then sum\n unique_elements = set(arr)\n total_sum = sum(unique_elements)\n return total_sum", "matching_cluster_idx": 8}, {"solution": "def find_sum(arr):\n # Convert list to a set to remove duplicates\n non_repeated_set = set(arr)\n # Calculate the sum of non-repeated elements\n total_sum = sum(non_repeated_set)\n return total_sum", "matching_cluster_idx": 8}, {"solution": "def find_sum(arr):\n # Convert list to a set to remove duplicates and then sum all elements\n return sum(set(arr))", "matching_cluster_idx": 8}, {"solution": "def find_sum(arr):\n # Convert the list to a set to remove duplicates\n # Then calculate the sum of the unique elements\n return sum(set(arr))", "matching_cluster_idx": 8}]}, "Mbpp/781": {"dps": 41.496062992125985, "dps_norm": 29.0, "pass@1": 100.0, "profiled": [{"solution": "def count_divisors(n):\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count % 2 == 0", "matching_cluster_idx": 0}, {"solution": "def count_divisors(n):\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count % 2 == 0", "matching_cluster_idx": 0}, {"solution": "def count_divisors(n):\n # Initialize a counter for divisors\n count = 0\n \n # Loop through possible divisors from 1 to n (inclusive)\n for i in range(1, n + 1):\n # Check if i is a divisor of n\n if n % i == 0:\n count += 1\n \n # Return True if the count of divisors is even, False otherwise\n return count % 2 == 0", "matching_cluster_idx": 1}, {"solution": "def count_divisors(n):\n # Initialize count of divisors\n count = 0\n \n # Loop from 1 to n to check for divisors\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n \n # Return True if count of divisors is even, else False\n return count % 2 == 0", "matching_cluster_idx": 1}, {"solution": "def count_divisors(n):\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count % 2 == 0", "matching_cluster_idx": 0}, {"solution": "def count_divisors(n):\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count % 2 == 0", "matching_cluster_idx": 0}, {"solution": "def count_divisors(n):\n # Initialize the count of divisors to 0\n count = 0\n # Loop from 1 to n (inclusive) to check for divisors\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n # Check if the count of divisors is even\n return count % 2 == 0", "matching_cluster_idx": 1}, {"solution": "def count_divisors(n):\n # Initialize the count of divisors\n count = 0\n # Loop through all possible divisors\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n # Check if the count of divisors is even\n return count % 2 == 0", "matching_cluster_idx": 1}, {"solution": "def count_divisors(n):\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count % 2 == 0", "matching_cluster_idx": 0}, {"solution": "def count_divisors(n):\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count % 2 == 0", "matching_cluster_idx": 0}, {"solution": "def count_divisors(n):\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count % 2 == 0", "matching_cluster_idx": 0}, {"solution": "def count_divisors(n):\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count % 2 == 0", "matching_cluster_idx": 0}, {"solution": "def count_divisors(n):\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n # Check if the count of divisors is even\n return count % 2 == 0", "matching_cluster_idx": 1}, {"solution": "def count_divisors(n):\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n # Check if count of divisors is even\n return count % 2 == 0", "matching_cluster_idx": 1}, {"solution": "def count_divisors(n):\n # Initialize divisor count\n count = 0\n # Loop through all numbers from 1 to n (inclusive) to count divisors\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n # Check if the count of divisors is even\n return count % 2 == 0", "matching_cluster_idx": 1}, {"solution": "def count_divisors(n):\n # Initialize count of divisors\n count = 0\n # Loop through all numbers from 1 to n\n for i in range(1, n + 1):\n # If i is a divisor of n, increment count\n if n % i == 0:\n count += 1\n # Check if count of divisors is even\n return count % 2 == 0", "matching_cluster_idx": 1}, {"solution": "def count_divisors(n):\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count % 2 == 0", "matching_cluster_idx": 0}, {"solution": "def count_divisors(n):\n count = 0\n # Iterate over possible divisors\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n # Check if the count of divisors is even\n return count % 2 == 0", "matching_cluster_idx": 1}, {"solution": "def count_divisors(n):\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count % 2 == 0", "matching_cluster_idx": 0}, {"solution": "def count_divisors(n):\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count % 2 == 0", "matching_cluster_idx": 0}]}, "Mbpp/800": {"dps": 80.0, "dps_norm": 88.0, "pass@1": 67.0, "profiled": [{"solution": "def remove_all_spaces(input_string):\n # Remove all whitespaces from the input string\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n # Replace spaces with no space using the translate method\n result_string = input_string.replace(\" \", \"\")\n return result_string", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n # Remove all whitespaces from the string\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_str):\n # Remove all whitespaces from the string\n return input_str.replace(' ', '')", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n # Replace whitespaces with no space using str.replace()\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n # Replace spaces using the str.replace() method\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 3}, {"solution": "def remove_all_spaces(input_string):\n # Replace spaces with no space using the string replace method\n no_space_string = input_string.replace(\" \", \"\")\n return no_space_string", "matching_cluster_idx": 3}, {"solution": "def remove_all_spaces(input_string):\n # Remove all whitespaces from the string\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n # Replace all whitespace characters with no space\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 3}, {"solution": "def remove_all_spaces(input_string):\n # Replace spaces with no space (effectively removing them)\n no_spaces = input_string.replace(\" \", \"\")\n return no_spaces", "matching_cluster_idx": 3}, {"solution": "def remove_all_spaces(input_string):\n # Removing spaces from the input string\n no_space_string = input_string.replace(' ', '')\n return no_space_string", "matching_cluster_idx": 3}, {"solution": "def remove_all_spaces(input_str):\n # Removing all whitespaces using replace\n return input_str.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n # Remove all whitespaces from the string\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n # Remove all whitespaces from the string\n return input_string.replace(' ', '')", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n # Using join and list comprehension to remove spaces\n return ''.join([char for char in input_string if char != ' '])", "matching_cluster_idx": 0}, {"solution": "def remove_all_spaces(s):\n # Removing all whitespaces from the string\n return s.replace(\" \", \"\")", "matching_cluster_idx": 3}, {"solution": "def remove_all_spaces(input_string):\n # Remove all whitespaces using str.replace\n no_space_string = input_string.replace(\" \", \"\")\n return no_space_string", "matching_cluster_idx": 3}, {"solution": "def remove_all_spaces(input_string):\n # Remove all whitespaces from the string\n result_string = input_string.replace(\" \", \"\")\n return result_string", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n # Remove all spaces from the string using replace function\n return input_string.replace(' ', '')", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n # Remove all spaces using translate and str.maketrans\n no_spaces = input_string.translate(str.maketrans('', '', ' '))\n return no_spaces", "matching_cluster_idx": 3}]}, "Mbpp/805": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def max_sum_list(lists):\n # Initialize max_sum and max_list to keep track of the list with the highest sum\n max_sum = float('-inf')\n max_list = []\n \n # Iterate through each list in the list of lists\n for lst in lists:\n # Calculate the sum of the current list\n current_sum = sum(lst)\n \n # If the current sum is greater than max_sum, update max_sum and max_list\n if current_sum > max_sum:\n max_sum = current_sum\n max_list = lst\n \n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n # Find the list with the maximum sum\n max_sum_list = max(lists, key=sum)\n return max_sum_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n # Find the list with the maximum sum of elements\n max_sum = max(lists, key=sum)\n return max_sum", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n # Find the list with the maximum sum\n max_sum = max(lists, key=sum)\n return max_sum", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n # Find the list with the maximum sum of its elements\n max_sum = max(lists, key=sum)\n return max_sum", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n # Find the list with the maximum sum of elements\n max_list = max(lists, key=sum)\n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n # Initialize the maximum sum and the list with the maximum sum\n max_sum = float('-inf')\n max_list = []\n \n # Iterate over each list in the list of lists\n for lst in lists:\n # Calculate the sum of the current list\n current_sum = sum(lst)\n \n # Update the maximum sum and the list with the maximum sum if needed\n if current_sum > max_sum:\n max_sum = current_sum\n max_list = lst\n \n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n # Find the list with the maximum sum\n max_sum_list = max(lists, key=sum)\n return max_sum_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n # Initialize the maximum sum and the list with the maximum sum\n max_sum = float('-inf')\n max_list = []\n \n # Iterate through each list in the list of lists\n for sublist in lists:\n # Calculate the sum of the current list\n current_sum = sum(sublist)\n # If the sum of the current list is greater than the max_sum, update max_sum and max_list\n if current_sum > max_sum:\n max_sum = current_sum\n max_list = sublist\n \n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n # Find the list with the maximum sum of elements\n max_sum = max(lists, key=sum)\n return max_sum", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n # Initialize max_sum and max_list\n max_sum = float('-inf')\n max_list = []\n \n # Iterate through each list in the lists\n for lst in lists:\n # Calculate the sum of the current list\n current_sum = sum(lst)\n \n # Update max_sum and max_list if current_sum is greater than max_sum\n if current_sum > max_sum:\n max_sum = current_sum\n max_list = lst\n \n # Return the list with the highest sum\n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(list_of_lists):\n # Find the list with the maximum sum\n max_sum_list = max(list_of_lists, key=sum)\n return max_sum_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n # Calculate the sum of each list and pair it with the original list\n paired_lists = [(sum(lst), lst) for lst in lists]\n # Find the pair with the maximum sum, and return the corresponding list\n return max(paired_lists, key=lambda x: x[0])[1]", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(list_of_lists):\n # Find the list with the maximum sum of elements\n max_sum_list = max(list_of_lists, key=sum)\n return max_sum_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n # Initialize maximum sum and the list with the maximum sum\n max_sum = float('-inf')\n max_list = []\n \n # Iterate through each list in the input lists\n for sublist in lists:\n # Calculate the sum of the current list\n current_sum = sum(sublist)\n # Update maximum sum and list if current list's sum is greater than max_sum\n if current_sum > max_sum:\n max_sum = current_sum\n max_list = sublist\n \n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n # Find the list with the maximum sum\n max_sum = max(lists, key=sum)\n return max_sum", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n # Initialize max_sum to a very low number\n max_sum = float('-inf')\n # Initialize the list that has the maximum sum to None\n max_list = None\n \n # Iterate over each list in the lists\n for lst in lists:\n # Calculate the sum of the current list\n current_sum = sum(lst)\n # If the current_sum is greater than max_sum, update max_sum and max_list\n if current_sum > max_sum:\n max_sum = current_sum\n max_list = lst\n \n # Return the list with the maximum sum\n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(list_of_lists):\n # Initialize max_sum and max_list to store the highest sum and corresponding list\n max_sum = float('-inf')\n max_list = []\n \n # Iterate over each list in the list of lists\n for lst in list_of_lists:\n # Calculate the sum of elements of the current list\n current_sum = sum(lst)\n # Update max_sum and max_list if the current list's sum is greater than max_sum\n if current_sum > max_sum:\n max_sum = current_sum\n max_list = lst\n \n # Return the list with the highest sum\n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(list_of_lists):\n # Find the list with the maximum sum\n max_sum_list = max(list_of_lists, key=sum)\n return max_sum_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n # Find the list with the maximum sum\n return max(lists, key=sum)", "matching_cluster_idx": 4}]}, "Mbpp/808": {"dps": 44.56140350877193, "dps_norm": 86.66666666666666, "pass@1": 99.0, "profiled": [{"solution": "def check_K(test_tup, K):\n \"\"\"\n This function checks if the given tuple contains the specified element K.\n\n :param test_tup: Tuple in which to check the presence of K\n :param K: Element to check in the tuple\n :return: True if K is in test_tup, False otherwise\n \"\"\"\n # Checking if K is present in the tuple and returning the result\n return K in test_tup", "matching_cluster_idx": 5}, {"solution": "def check_K(test_tup, K):\n # Checking if K is present in the tuple\n res = K in test_tup\n return res", "matching_cluster_idx": 4}, {"solution": "def check_K(test_tup, k):\n \"\"\"\n This function checks if the given tuple contains the specified element k.\n \n :param test_tup: Tuple to be checked.\n :param k: Element to look for in the tuple.\n :return: True if k is found in the tuple, False otherwise.\n \"\"\"\n # Check if k is in the tuple\n return k in test_tup", "matching_cluster_idx": 5}, {"solution": "def check_K(test_tup, K):\n # Check if K is in the tuple test_tup\n return K in test_tup", "matching_cluster_idx": 4}, {"solution": "def check_K(test_tup, K):\n \"\"\"\n Check if the given tuple contains the element K.\n\n Parameters:\n test_tup (tuple): The tuple to check.\n K (int): The element to search for in the tuple.\n\n Returns:\n bool: True if K is found in the tuple, False otherwise.\n \"\"\"\n # Check if K is in the tuple\n res = K in test_tup\n return res", "matching_cluster_idx": 4}, {"solution": "def check_K(test_tup, k):\n \"\"\"\n This function checks if the given tuple contains the specified value k.\n \n :param test_tup: Tuple to be checked\n :param k: The value to look for in the tuple\n :return: True if k is found in test_tup, False otherwise\n \"\"\"\n # Check if k is in the tuple\n return k in test_tup", "matching_cluster_idx": 5}, {"solution": "def check_K(test_tup, k):\n # Check if k is present in the tuple test_tup\n return k in test_tup", "matching_cluster_idx": 4}, {"solution": "def check_K(test_tup, K):\n \"\"\"\n This function checks if the given tuple contains the specified element K.\n\n :param test_tup: The tuple to be checked\n :param K: The element to search for within the tuple\n :return: True if K is found in the tuple, False otherwise\n \"\"\"\n # Checking if K is in the given tuple\n return K in test_tup", "matching_cluster_idx": 4}, {"solution": "def check_K(test_tup, K):\n # Check if K is in the tuple test_tup\n return K in test_tup", "matching_cluster_idx": 4}, {"solution": "def check_K(test_tup, k):\n \"\"\"\n Function to check if the tuple contains the specified value k.\n \n Parameters:\n test_tup (tuple): The tuple to check.\n k (any): The value to look for in the tuple.\n \n Returns:\n bool: True if k is found in the tuple, False otherwise.\n \"\"\"\n return k in test_tup", "matching_cluster_idx": 4}, {"solution": "def check_K(test_tup, k):\n \"\"\"\n Check if the given tuple contains the specified value k.\n \n Parameters:\n test_tup (tuple): The tuple to be checked.\n k (any): The value to check for in the tuple.\n \n Returns:\n bool: True if k is found in test_tup, False otherwise.\n \"\"\"\n # Checking if k is in the tuple\n return k in test_tup", "matching_cluster_idx": 4}, {"solution": "def check_K(test_tup, k):\n # Check if k is present in the tuple test_tup\n return k in test_tup", "matching_cluster_idx": 4}, {"solution": "def check_K(test_tup, K):\n \"\"\"\n Check if the tuple contains the given element K.\n\n Parameters:\n test_tup (tuple): The tuple to search within.\n K (int): The element to search for in the tuple.\n\n Returns:\n bool: True if K is in test_tup, False otherwise.\n \"\"\"\n return K in test_tup", "matching_cluster_idx": 5}, {"solution": "def check_K(test_tup, k):\n \"\"\"\n Function to check if the given tuple contains the specified element 'k'.\n\n :param test_tup: The tuple to be checked.\n :param k: The element to search for in the tuple.\n :return: True if 'k' is found in the tuple, False otherwise.\n \"\"\"\n # Check if k is in the tuple\n return k in test_tup", "matching_cluster_idx": 4}, {"solution": "def check_K(test_tup, K):\n # Check if K is in the tuple test_tup\n return K in test_tup", "matching_cluster_idx": 4}, {"solution": "def check_K(test_tup, k):\n \"\"\"\n This function checks if the given tuple contains the specified value k.\n\n :param test_tup: The input tuple to be checked.\n :param k: The value to check for in the tuple.\n :return: True if k is found in the tuple, False otherwise.\n \"\"\"\n # Check if k is in the tuple\n res = k in test_tup\n return res", "matching_cluster_idx": 4}, {"solution": "def check_K(test_tup, k):\n \"\"\"\n Check if the tuple test_tup contains the element k.\n \n Parameters:\n test_tup (tuple): The tuple to check.\n k (int): The element to look for in the tuple.\n \n Returns:\n bool: True if k is found in test_tup, False otherwise.\n \"\"\"\n # Check if k is in the tuple test_tup\n return k in test_tup", "matching_cluster_idx": 4}, {"solution": "def check_K(test_tup, K):\n \"\"\"\n Check if K is present in the given tuple.\n\n :param test_tup: Tuple to be checked.\n :param K: Element to search for within the tuple.\n :return: True if K is present in the tuple, False otherwise.\n \"\"\"\n # Checking if K is in the tuple\n return K in test_tup", "matching_cluster_idx": 4}, {"solution": "def check_K(test_tup, k):\n \"\"\"\n This function checks if the provided tuple contains the specified element k.\n \n :param test_tup: Tuple to be searched\n :param k: Element to search for in the tuple\n :return: True if k is found in the tuple, False otherwise\n \"\"\"\n # Checking if k is in the tuple\n return k in test_tup", "matching_cluster_idx": 4}, {"solution": "def check_K(test_tup, K):\n # Check if K is in the tuple\n return K in test_tup", "matching_cluster_idx": 4}]}}} \ No newline at end of file diff --git a/results/evalperf/Qwen--Qwen2.5-72B-Instruct_vllm_temp_1.0_evalperf_results.brief.json b/results/evalperf/Qwen--Qwen2.5-72B-Instruct_vllm_temp_1.0_evalperf_results.brief.json new file mode 100644 index 0000000..b4d8b12 --- /dev/null +++ b/results/evalperf/Qwen--Qwen2.5-72B-Instruct_vllm_temp_1.0_evalperf_results.brief.json @@ -0,0 +1 @@ +{"date": "2024-10-19 16:29", "config": {"n_samples": 100, "temperature": 1.0, "min_correct": 10, "max_profile": 20}, "summary": {"dps": 84.69258296490358, "dps_norm": 79.00610315513151, "pass@1": 88.27966101694915}, "eval": {"HumanEval/9": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n \n max_so_far = numbers[0]\n result = [max_so_far]\n \n for number in numbers[1:]:\n if number > max_so_far:\n max_so_far = number\n result.append(max_so_far)\n \n return result", "matching_cluster_idx": 8}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n \n max_so_far = numbers[0]\n result = [max_so_far]\n \n for number in numbers[1:]:\n if number > max_so_far:\n max_so_far = number\n result.append(max_so_far)\n \n return result", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n \n max_so_far = numbers[0]\n result = [max_so_far]\n \n for number in numbers[1:]:\n if number > max_so_far:\n max_so_far = number\n result.append(max_so_far)\n \n return result", "matching_cluster_idx": 8}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n \n max_so_far = numbers[0]\n result = []\n \n for number in numbers:\n if number > max_so_far:\n max_so_far = number\n result.append(max_so_far)\n \n return result", "matching_cluster_idx": 8}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n \n max_so_far = numbers[0]\n result = [max_so_far]\n \n for number in numbers[1:]:\n if number > max_so_far:\n max_so_far = number\n result.append(max_so_far)\n \n return result", "matching_cluster_idx": 8}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n \n max_so_far = numbers[0]\n result = [max_so_far]\n \n for number in numbers[1:]:\n if number > max_so_far:\n max_so_far = number\n result.append(max_so_far)\n \n return result", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n \n max_so_far = numbers[0]\n result = [max_so_far]\n \n for num in numbers[1:]:\n if num > max_so_far:\n max_so_far = num\n result.append(max_so_far)\n \n return result", "matching_cluster_idx": 8}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n \n max_so_far = numbers[0]\n result = [max_so_far]\n \n for number in numbers[1:]:\n if number > max_so_far:\n max_so_far = number\n result.append(max_so_far)\n \n return result", "matching_cluster_idx": 8}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n \n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n\n max_so_far = numbers[0]\n result = []\n\n for number in numbers:\n if number > max_so_far:\n max_so_far = number\n result.append(max_so_far)\n\n return result", "matching_cluster_idx": 8}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n \n max_so_far = numbers[0]\n result = []\n \n for number in numbers:\n if number > max_so_far:\n max_so_far = number\n result.append(max_so_far)\n \n return result", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n \n max_so_far = numbers[0]\n result = [max_so_far]\n \n for num in numbers[1:]:\n if num > max_so_far:\n max_so_far = num\n result.append(max_so_far)\n \n return result", "matching_cluster_idx": 8}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n \n max_so_far = numbers[0]\n result = [max_so_far]\n \n for number in numbers[1:]:\n if number > max_so_far:\n max_so_far = number\n result.append(max_so_far)\n \n return result", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n \n max_so_far = numbers[0]\n result = [max_so_far]\n \n for num in numbers[1:]:\n if num > max_so_far:\n max_so_far = num\n result.append(max_so_far)\n \n return result", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n \n max_so_far = numbers[0]\n result = [max_so_far]\n \n for number in numbers[1:]:\n if number > max_so_far:\n max_so_far = number\n result.append(max_so_far)\n \n return result", "matching_cluster_idx": 8}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n \n max_so_far = numbers[0]\n result = [max_so_far]\n \n for number in numbers[1:]:\n if number > max_so_far:\n max_so_far = number\n result.append(max_so_far)\n \n return result", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n \n max_so_far = numbers[0]\n result = [max_so_far]\n \n for num in numbers[1:]:\n if num > max_so_far:\n max_so_far = num\n result.append(max_so_far)\n \n return result", "matching_cluster_idx": 8}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n \n Example:\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n \n max_so_far = numbers[0]\n result = []\n \n for number in numbers:\n if number > max_so_far:\n max_so_far = number\n result.append(max_so_far)\n \n return result", "matching_cluster_idx": 8}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n \n :param numbers: List of integers.\n :return: List of rolling maximums.\n \n Example:\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n \n max_so_far = numbers[0]\n result = [max_so_far]\n \n for num in numbers[1:]:\n if num > max_so_far:\n max_so_far = num\n result.append(max_so_far)\n \n return result", "matching_cluster_idx": 8}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n \n max_so_far = numbers[0]\n result = []\n \n for number in numbers:\n if number > max_so_far:\n max_so_far = number\n result.append(max_so_far)\n \n return result", "matching_cluster_idx": 8}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n \n max_so_far = numbers[0]\n result = [max_so_far]\n \n for num in numbers[1:]:\n if num > max_so_far:\n max_so_far = num\n result.append(max_so_far)\n \n return result", "matching_cluster_idx": 8}]}, "HumanEval/0": {"dps": 52.325581395348834, "dps_norm": 57.142857142857146, "pass@1": 98.0, "profiled": [{"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\"\n Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n \n Args:\n numbers: List of floating-point numbers.\n threshold: A floating-point number representing the threshold.\n \n Returns:\n A boolean value indicating if any two numbers in the list are closer to each other than the threshold.\n \"\"\"\n # Sort the list to make it easier to find close elements\n sorted_numbers = sorted(numbers)\n \n # Iterate through the sorted list and check the difference between adjacent elements\n for i in range(1, len(sorted_numbers)):\n if sorted_numbers[i] - sorted_numbers[i - 1] < threshold:\n return True\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\"\n Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n \n :param numbers: List of floating-point numbers.\n :param threshold: A floating-point number representing the threshold.\n :return: True if any two numbers are closer to each other than the threshold, False otherwise.\n \"\"\"\n # Sort the list to make it easier to check adjacent elements\n sorted_numbers = sorted(numbers)\n \n # Iterate through the sorted list and check the difference between adjacent elements\n for i in range(1, len(sorted_numbers)):\n if sorted_numbers[i] - sorted_numbers[i - 1] < threshold:\n return True\n \n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n \"\"\"\n # Sort the list to make comparison easier\n numbers.sort()\n \n # Iterate through the sorted list and check the difference between consecutive elements\n for i in range(len(numbers) - 1):\n if numbers[i + 1] - numbers[i] < threshold:\n return True\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\"\n Check if in the given list of numbers, are any two numbers closer to each other than the given threshold.\n \n :param numbers: List of floating-point numbers.\n :param threshold: A floating-point number representing the threshold.\n :return: True if any two numbers are closer than the threshold, False otherwise.\n \"\"\"\n # Sort the list to ensure that we only need to compare adjacent elements\n numbers.sort()\n \n # Iterate through the list and check the difference between adjacent elements\n for i in range(len(numbers) - 1):\n if abs(numbers[i] - numbers[i + 1]) < threshold:\n return True\n \n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\"\n Check if in the given list of numbers, are any two numbers closer to each other than\n the given threshold.\n \n :param numbers: List of floating point numbers\n :param threshold: A floating point number representing the threshold\n :return: True if any two numbers are closer than the threshold, otherwise False\n \"\"\"\n # Sort the list to make it easier to check adjacent elements\n sorted_numbers = sorted(numbers)\n \n # Iterate through the sorted list and check the difference between adjacent elements\n for i in range(len(sorted_numbers) - 1):\n if sorted_numbers[i + 1] - sorted_numbers[i] < threshold:\n return True\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\"\n Check if in the given list of numbers, are any two numbers closer to each other than\n the given threshold.\n \n :param numbers: List of floating-point numbers.\n :param threshold: A floating-point number representing the threshold.\n :return: True if any two numbers are closer than the threshold, False otherwise.\n \"\"\"\n # Sort the list to make it easier to find close elements\n sorted_numbers = sorted(numbers)\n \n # Iterate through the sorted list and check the difference between adjacent elements\n for i in range(len(sorted_numbers) - 1):\n if sorted_numbers[i + 1] - sorted_numbers[i] < threshold:\n return True\n \n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\"\n Check if in the given list of numbers, are any two numbers closer to each other than\n the given threshold.\n \n :param numbers: List of floating-point numbers.\n :param threshold: A floating-point number representing the threshold.\n :return: True if any two numbers are closer than the threshold, False otherwise.\n \"\"\"\n # Sort the list to make it easier to find close elements\n numbers.sort()\n \n # Iterate through the sorted list and check the difference between adjacent elements\n for i in range(1, len(numbers)):\n if numbers[i] - numbers[i - 1] < threshold:\n return True\n \n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\"\n Check if in the given list of numbers, any two numbers are closer to each other than\n the given threshold.\n \n :param numbers: List of floating-point numbers.\n :param threshold: A floating-point number representing the threshold.\n :return: True if any two numbers are closer than the threshold, otherwise False.\n \"\"\"\n # Sort the list to make it easier to check adjacent elements\n numbers.sort()\n \n # Iterate through the sorted list and check the difference between adjacent elements\n for i in range(len(numbers) - 1):\n if abs(numbers[i] - numbers[i + 1]) < threshold:\n return True\n \n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n \"\"\"\n # Sort the list to make sure that any two adjacent elements are the closest pair\n numbers.sort()\n \n # Iterate through the sorted list and check the difference between adjacent elements\n for i in range(len(numbers) - 1):\n if abs(numbers[i] - numbers[i + 1]) < threshold:\n return True\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\"\n Check if in the given list of numbers, any two numbers are closer to each other than the given threshold.\n \n :param numbers: List of floating-point numbers.\n :param threshold: A floating-point number representing the threshold.\n :return: True if any two numbers are closer than the threshold, False otherwise.\n \"\"\"\n # Sort the list to make it easier to check adjacent elements\n sorted_numbers = sorted(numbers)\n \n # Iterate through the sorted list and check the difference between adjacent elements\n for i in range(len(sorted_numbers) - 1):\n if abs(sorted_numbers[i] - sorted_numbers[i + 1]) < threshold:\n return True\n \n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n \"\"\"\n numbers.sort() # Sort the list to make comparisons easier\n for i in range(len(numbers) - 1):\n if abs(numbers[i] - numbers[i + 1]) < threshold:\n return True\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\"\n Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n \n Args:\n numbers: A list of floating-point numbers.\n threshold: A floating-point number representing the threshold.\n \n Returns:\n A boolean value indicating if any two numbers in the list are closer to each other than the threshold.\n \"\"\"\n # Sort the list to make the comparison more efficient\n numbers.sort()\n \n # Iterate through the sorted list and check the difference between consecutive elements\n for i in range(len(numbers) - 1):\n if numbers[i + 1] - numbers[i] < threshold:\n return True\n \n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\"\n Check if in the given list of numbers, any two numbers are closer to each other than\n the given threshold.\n \n :param numbers: List of floating-point numbers.\n :param threshold: A floating-point number representing the threshold.\n :return: True if any two numbers are closer to each other than the threshold, False otherwise.\n \"\"\"\n numbers.sort() # Sort the list to make comparison easier\n for i in range(len(numbers) - 1):\n if abs(numbers[i] - numbers[i + 1]) < threshold:\n return True\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\"\n Check if in the given list of numbers, are any two numbers closer to each other than\n the given threshold.\n \n :param numbers: List of floating-point numbers.\n :param threshold: A floating-point number representing the threshold.\n :return: True if any two numbers are closer than the threshold, False otherwise.\n \"\"\"\n # Sort the list to make it easier to find close elements\n numbers.sort()\n \n # Iterate through the sorted list and check the difference between consecutive elements\n for i in range(len(numbers) - 1):\n if numbers[i + 1] - numbers[i] < threshold:\n return True\n \n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\"\n Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n \n :param numbers: List of floating-point numbers.\n :param threshold: A floating-point number representing the threshold.\n :return: True if any two numbers are closer than the threshold, False otherwise.\n \"\"\"\n # Sort the list to ensure that we only need to check adjacent elements\n sorted_numbers = sorted(numbers)\n \n # Iterate through the sorted list and check the difference between adjacent elements\n for i in range(len(sorted_numbers) - 1):\n if sorted_numbers[i + 1] - sorted_numbers[i] < threshold:\n return True\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\nimport math\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\"\n Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n \n :param numbers: List of floating-point numbers.\n :param threshold: A floating-point number representing the threshold.\n :return: True if any two numbers are closer to each other than the threshold, False otherwise.\n \"\"\"\n # Sort the list to make it easier to check for close elements\n numbers.sort()\n \n # Iterate through the sorted list and check the difference between adjacent elements\n for i in range(len(numbers) - 1):\n if numbers[i + 1] - numbers[i] < threshold:\n return True\n \n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n \"\"\"\n numbers.sort() # Sort the list to make comparison easier\n for i in range(len(numbers) - 1):\n if abs(numbers[i] - numbers[i + 1]) < threshold:\n return True\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\"\n Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n \n :param numbers: List of floating-point numbers.\n :param threshold: A floating-point number representing the threshold.\n :return: True if any two numbers are closer to each other than the threshold, False otherwise.\n \"\"\"\n # Sort the list to make it easier to find close elements\n numbers.sort()\n \n # Iterate through the sorted list and check the difference between consecutive elements\n for i in range(1, len(numbers)):\n if numbers[i] - numbers[i - 1] < threshold:\n return True\n \n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n \"\"\"\n # Sort the list to ensure that we only need to check adjacent elements\n sorted_numbers = sorted(numbers)\n \n # Iterate through the sorted list and check the difference between adjacent elements\n for i in range(len(sorted_numbers) - 1):\n if abs(sorted_numbers[i] - sorted_numbers[i + 1]) < threshold:\n return True\n \n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n \"\"\"\n numbers.sort() # Sort the list to make comparisons easier\n for i in range(len(numbers) - 1):\n if numbers[i + 1] - numbers[i] < threshold:\n return True\n return False", "matching_cluster_idx": 3}]}, "HumanEval/4": {"dps": 95.14240506329114, "dps_norm": 95.83333333333333, "pass@1": 100.0, "profiled": [{"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if not numbers:\n return 0.0\n \n # Calculate the mean of the numbers\n mean_value = sum(numbers) / len(numbers)\n \n # Calculate the mean absolute deviation\n mad = sum(abs(x - mean_value) for x in numbers) / len(numbers)\n \n return mad", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if not numbers:\n return 0.0\n\n # Calculate the mean of the numbers\n mean_value = sum(numbers) / len(numbers)\n \n # Calculate the mean absolute deviation\n mad = sum(abs(x - mean_value) for x in numbers) / len(numbers)\n \n return mad", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if not numbers:\n return 0.0\n \n mean_value = sum(numbers) / len(numbers)\n mad = sum(abs(x - mean_value) for x in numbers) / len(numbers)\n return mad", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if not numbers:\n return 0.0\n \n mean_value = sum(numbers) / len(numbers)\n mad = sum(abs(x - mean_value) for x in numbers) / len(numbers)\n \n return mad", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n # Calculate the mean of the numbers\n mean_value = sum(numbers) / len(numbers)\n \n # Calculate the absolute differences from the mean\n abs_diffs = [abs(x - mean_value) for x in numbers]\n \n # Calculate the mean of these absolute differences\n mad = sum(abs_diffs) / len(numbers)\n \n return mad", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if not numbers:\n return 0.0\n \n mean_value = sum(numbers) / len(numbers)\n mad = sum(abs(x - mean_value) for x in numbers) / len(numbers)\n return mad", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if not numbers:\n return 0.0\n\n # Calculate the mean of the numbers\n mean_value = sum(numbers) / len(numbers)\n \n # Calculate the absolute differences from the mean\n abs_differences = [abs(x - mean_value) for x in numbers]\n \n # Calculate the mean of the absolute differences\n mad = sum(abs_differences) / len(abs_differences)\n \n return mad", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if not numbers:\n return 0.0\n\n # Calculate the mean of the numbers\n mean_value = sum(numbers) / len(numbers)\n \n # Calculate the mean absolute deviation\n mad = sum(abs(x - mean_value) for x in numbers) / len(numbers)\n \n return mad", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if not numbers:\n return 0.0\n \n # Calculate the mean of the numbers\n mean_value = sum(numbers) / len(numbers)\n \n # Calculate the mean absolute deviation\n mad = sum(abs(x - mean_value) for x in numbers) / len(numbers)\n \n return mad", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if not numbers:\n return 0.0\n\n # Calculate the mean of the numbers\n mean = sum(numbers) / len(numbers)\n \n # Calculate the absolute differences from the mean\n abs_differences = [abs(x - mean) for x in numbers]\n \n # Calculate the mean of the absolute differences\n mad = sum(abs_differences) / len(numbers)\n \n return mad", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if not numbers:\n return 0.0\n\n # Calculate the mean of the numbers\n mean_value = sum(numbers) / len(numbers)\n \n # Calculate the Mean Absolute Deviation\n mad = sum(abs(x - mean_value) for x in numbers) / len(numbers)\n \n return mad", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if not numbers:\n return 0.0\n\n # Calculate the mean of the numbers\n mean_value = sum(numbers) / len(numbers)\n \n # Calculate the mean absolute deviation\n mad = sum(abs(x - mean_value) for x in numbers) / len(numbers)\n \n return mad", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if not numbers:\n return 0.0\n \n # Calculate the mean of the numbers\n mean = sum(numbers) / len(numbers)\n \n # Calculate the mean absolute deviation\n mad = sum(abs(x - mean) for x in numbers) / len(numbers)\n \n return mad", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if not numbers:\n return 0.0\n \n mean_value = sum(numbers) / len(numbers)\n mad = sum(abs(x - mean_value) for x in numbers) / len(numbers)\n return mad", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if not numbers:\n return 0.0\n \n # Calculate the mean of the numbers\n mean_value = sum(numbers) / len(numbers)\n \n # Calculate the absolute differences from the mean\n absolute_differences = [abs(x - mean_value) for x in numbers]\n \n # Calculate the mean of the absolute differences\n mad = sum(absolute_differences) / len(numbers)\n \n return mad", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if not numbers:\n return 0.0 # Handle empty list case\n \n mean_value = sum(numbers) / len(numbers)\n mad = sum(abs(x - mean_value) for x in numbers) / len(numbers)\n \n return mad", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if not numbers:\n return 0.0\n \n mean_value = sum(numbers) / len(numbers)\n mad = sum(abs(x - mean_value) for x in numbers) / len(numbers)\n return mad", "matching_cluster_idx": 5}, {"solution": "from typing import List\nfrom statistics import mean\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if not numbers:\n return 0.0\n\n x_mean = mean(numbers)\n mad = sum(abs(x - x_mean) for x in numbers) / len(numbers)\n return mad", "matching_cluster_idx": 0}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if not numbers:\n return 0.0\n\n # Calculate the mean of the numbers\n mean_value = sum(numbers) / len(numbers)\n \n # Calculate the Mean Absolute Deviation\n mad = sum(abs(x - mean_value) for x in numbers) / len(numbers)\n \n return mad", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n # Calculate the mean of the numbers\n mean = sum(numbers) / len(numbers)\n \n # Calculate the absolute differences from the mean\n absolute_differences = [abs(x - mean) for x in numbers]\n \n # Calculate the mean of the absolute differences\n mad = sum(absolute_differences) / len(numbers)\n \n return mad", "matching_cluster_idx": 5}]}, "HumanEval/16": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\"\n Given a string, find out how many distinct characters (regardless of case) does it consist of.\n \n Parameters:\n string (str): The input string.\n \n Returns:\n int: The number of distinct characters in the string, case-insensitive.\n \n Examples:\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lowercase to make the comparison case-insensitive\n string = string.lower()\n \n # Use a set to store unique characters\n unique_chars = set(string)\n \n # Return the number of unique characters\n return len(unique_chars)", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\"\n Given a string, find out how many distinct characters (regardless of case) it consists of.\n \n Args:\n string (str): The input string to analyze.\n \n Returns:\n int: The number of distinct characters, case-insensitive.\n \n Examples:\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lower case to ensure case insensitivity\n lower_case_string = string.lower()\n \n # Use a set to store unique characters\n unique_chars = set(lower_case_string)\n \n # Return the number of unique characters\n return len(unique_chars)", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\"\n Given a string, find out how many distinct characters (regardless of case) does it consist of.\n \n Args:\n string (str): The input string to analyze.\n \n Returns:\n int: The number of distinct characters in the string, ignoring case.\n \n Examples:\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lowercase to ignore case differences\n lower_string = string.lower()\n \n # Use a set to store unique characters\n unique_chars = set(lower_string)\n \n # Return the number of unique characters\n return len(unique_chars)", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\"\n Given a string, find out how many distinct characters (regardless of case) does it consist of.\n \n Args:\n string (str): The input string to analyze.\n \n Returns:\n int: The number of distinct characters in the string, ignoring case.\n \n Examples:\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lowercase to ignore case\n string = string.lower()\n \n # Use a set to store unique characters\n unique_chars = set(string)\n \n # Return the number of unique characters\n return len(unique_chars)", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\"\n Given a string, find out how many distinct characters (regardless of case) it consists of.\n \n Args:\n string (str): The input string to analyze.\n \n Returns:\n int: The number of distinct characters in the string, ignoring case.\n \n Examples:\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lowercase to ignore case differences\n string = string.lower()\n \n # Use a set to store unique characters\n unique_chars = set(string)\n \n # The length of the set is the number of distinct characters\n return len(unique_chars)", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\"\n Given a string, find out how many distinct characters (regardless of case) it consists of.\n \n Args:\n string (str): The input string to check.\n \n Returns:\n int: The number of distinct characters in the string, case-insensitive.\n \n Examples:\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lowercase to ignore case differences\n string = string.lower()\n \n # Use a set to store unique characters\n unique_chars = set(string)\n \n # Return the number of unique characters\n return len(unique_chars)", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\"\n Given a string, find out how many distinct characters (regardless of case) does it consist of.\n \n Args:\n string (str): The input string.\n \n Returns:\n int: The number of distinct characters in the string, ignoring case.\n \n Examples:\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lowercase to ignore case differences\n string = string.lower()\n # Use a set to store distinct characters\n distinct_chars = set(string)\n # Return the number of distinct characters\n return len(distinct_chars)", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\"\n Given a string, find out how many distinct characters (regardless of case) it consists of.\n \n :param string: The input string to analyze.\n :return: The number of distinct characters in the string, ignoring case.\n \n Examples:\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lowercase to ignore case differences\n string = string.lower()\n # Use a set to store unique characters\n unique_chars = set(string)\n # Return the number of unique characters\n return len(unique_chars)", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\"\n Given a string, find out how many distinct characters (regardless of case) does it consist of.\n \n Args:\n string (str): The input string to analyze.\n \n Returns:\n int: The number of distinct characters in the string, case-insensitive.\n \n Examples:\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lowercase to ignore case differences\n string = string.lower()\n \n # Use a set to store distinct characters\n distinct_chars = set(string)\n \n # Return the number of distinct characters\n return len(distinct_chars)", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\"\n Given a string, find out how many distinct characters (regardless of case) does it consist of.\n \n Args:\n string (str): The input string.\n \n Returns:\n int: The number of distinct characters, ignoring case.\n \n Examples:\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lowercase to ignore case differences\n string = string.lower()\n \n # Use a set to store unique characters\n unique_chars = set(string)\n \n # Return the number of unique characters\n return len(unique_chars)", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\"\n Given a string, find out how many distinct characters (regardless of case) it consists of.\n \n :param string: The input string.\n :return: The number of distinct characters, ignoring case.\n \n Examples:\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lowercase to ignore case and then use a set to find distinct characters\n distinct_chars = set(string.lower())\n return len(distinct_chars)", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\"\n Given a string, find out how many distinct characters (regardless of case) does it consist of.\n \n Parameters:\n string (str): The input string.\n \n Returns:\n int: The number of distinct characters in the string, ignoring case.\n \n Examples:\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lowercase to ignore case differences\n string = string.lower()\n \n # Use a set to store distinct characters\n distinct_chars = set(string)\n \n # Return the number of distinct characters\n return len(distinct_chars)", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\"\n Given a string, find out how many distinct characters (regardless of case) does it consist of.\n \n Args:\n string (str): The input string to analyze.\n \n Returns:\n int: The number of distinct characters in the string, case-insensitive.\n \n Examples:\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lowercase to ensure case-insensitivity\n string = string.lower()\n \n # Use a set to store unique characters\n unique_chars = set(string)\n \n # The number of unique characters is the length of the set\n return len(unique_chars)", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\"\n Given a string, find out how many distinct characters (regardless of case) does it consist of.\n \n Args:\n string (str): The input string to analyze.\n \n Returns:\n int: The number of distinct characters in the string, case-insensitive.\n \n Examples:\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lowercase to ignore case differences\n string = string.lower()\n \n # Use a set to keep track of distinct characters\n distinct_chars = set(string)\n \n # Return the number of distinct characters\n return len(distinct_chars)", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\"\n Given a string, find out how many distinct characters (regardless of case) does it consist of.\n \n Parameters:\n string (str): The input string to evaluate.\n \n Returns:\n int: The number of distinct characters in the string, case-insensitive.\n \n Examples:\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lowercase to ignore case differences and use a set to find unique characters\n unique_chars = set(string.lower())\n return len(unique_chars)", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\"\n Given a string, find out how many distinct characters (regardless of case) does it consist of.\n \n :param string: The input string.\n :return: The number of distinct characters in the string, case-insensitive.\n \n Examples:\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lowercase to make it case-insensitive\n string = string.lower()\n \n # Use a set to store unique characters\n distinct_chars = set(string)\n \n # Return the number of unique characters\n return len(distinct_chars)", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\"\n Given a string, find out how many distinct characters (regardless of case) does it consist of.\n \n Parameters:\n string (str): The input string.\n \n Returns:\n int: The number of distinct characters in the string, ignoring case.\n \n Examples:\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lowercase to ignore case\n string = string.lower()\n \n # Use a set to store unique characters\n unique_chars = set(string)\n \n # Return the number of unique characters\n return len(unique_chars)", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\"\n Given a string, find out how many distinct characters (regardless of case) does it consist of.\n \n Args:\n string (str): The input string to analyze.\n \n Returns:\n int: The number of distinct characters in the string, case-insensitive.\n \n Examples:\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lowercase to ignore case differences\n string = string.lower()\n \n # Use a set to store unique characters\n unique_chars = set(string)\n \n # Return the number of unique characters\n return len(unique_chars)", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\"\n Given a string, find out how many distinct characters (regardless of case) it consists of.\n \n Args:\n string (str): The input string to analyze.\n \n Returns:\n int: The number of distinct characters in the string, ignoring case.\n \n Examples:\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lowercase to ignore case differences\n string = string.lower()\n \n # Use a set to store unique characters\n unique_chars = set(string)\n \n # Return the number of unique characters\n return len(unique_chars)", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\"\n Given a string, find out how many distinct characters (regardless of case) it consists of.\n \n Args:\n string (str): The input string.\n \n Returns:\n int: The number of distinct characters in the string, ignoring case.\n \n Examples:\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lowercase to ignore case differences\n string = string.lower()\n \n # Use a set to store distinct characters\n distinct_chars = set(string)\n \n # Return the number of distinct characters\n return len(distinct_chars)", "matching_cluster_idx": 8}]}, "HumanEval/20": {"dps": 96.05326876513317, "dps_norm": 97.22222222222223, "pass@1": 100.0, "profiled": [{"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\"\n From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n \n :param numbers: List of floating-point numbers.\n :return: A tuple containing the two closest numbers in ascending order.\n \"\"\"\n # Sort the list to make finding the closest pair easier\n sorted_numbers = sorted(numbers)\n \n # Initialize variables to store the closest pair and the smallest difference found\n closest_pair = (sorted_numbers[0], sorted_numbers[1])\n smallest_diff = abs(sorted_numbers[1] - sorted_numbers[0])\n \n # Iterate through the sorted list to find the closest pair\n for i in range(1, len(sorted_numbers) - 1):\n diff = abs(sorted_numbers[i + 1] - sorted_numbers[i])\n if diff < smallest_diff:\n smallest_diff = diff\n closest_pair = (sorted_numbers[i], sorted_numbers[i + 1])\n \n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\"\n From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n \n :param numbers: List of floating-point numbers.\n :return: A tuple containing the two closest numbers in ascending order.\n \"\"\"\n # Sort the list to make it easier to find the closest pair\n sorted_numbers = sorted(numbers)\n \n # Initialize variables to store the closest pair and the smallest difference\n closest_pair = (sorted_numbers[0], sorted_numbers[1])\n smallest_difference = abs(sorted_numbers[1] - sorted_numbers[0])\n \n # Iterate through the sorted list to find the pair with the smallest difference\n for i in range(1, len(sorted_numbers) - 1):\n current_difference = abs(sorted_numbers[i + 1] - sorted_numbers[i])\n if current_difference < smallest_difference:\n smallest_difference = current_difference\n closest_pair = (sorted_numbers[i], sorted_numbers[i + 1])\n \n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n \"\"\"\n # Sort the list to ensure that we can find the closest elements by comparing adjacent elements\n sorted_numbers = sorted(numbers)\n \n # Initialize the closest pair with the first two elements and their difference\n closest_diff = abs(sorted_numbers[1] - sorted_numbers[0])\n closest_pair = (sorted_numbers[0], sorted_numbers[1])\n \n # Iterate through the sorted list to find the pair with the smallest difference\n for i in range(1, len(sorted_numbers) - 1):\n current_diff = abs(sorted_numbers[i + 1] - sorted_numbers[i])\n if current_diff < closest_diff:\n closest_diff = current_diff\n closest_pair = (sorted_numbers[i], sorted_numbers[i + 1])\n \n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\"\n From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n \"\"\"\n # Sort the list to make it easier to find the closest elements\n sorted_numbers = sorted(numbers)\n \n # Initialize variables to store the closest pair and the smallest difference\n closest_pair = (sorted_numbers[0], sorted_numbers[1])\n smallest_diff = abs(sorted_numbers[1] - sorted_numbers[0])\n \n # Iterate through the sorted list to find the closest pair\n for i in range(1, len(sorted_numbers) - 1):\n current_diff = abs(sorted_numbers[i + 1] - sorted_numbers[i])\n if current_diff < smallest_diff:\n smallest_diff = current_diff\n closest_pair = (sorted_numbers[i], sorted_numbers[i + 1])\n \n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n \"\"\"\n # Sort the list to ensure that the closest elements are adjacent in the list\n sorted_numbers = sorted(numbers)\n \n # Initialize variables to store the closest elements and their difference\n closest_diff = float('inf')\n closest_pair = (None, None)\n \n # Iterate through the sorted list to find the closest pair\n for i in range(len(sorted_numbers) - 1):\n current_diff = sorted_numbers[i + 1] - sorted_numbers[i]\n if current_diff < closest_diff:\n closest_diff = current_diff\n closest_pair = (sorted_numbers[i], sorted_numbers[i + 1])\n \n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\nimport sys\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n \"\"\"\n # Sort the list to make finding the closest elements easier\n numbers.sort()\n \n # Initialize variables to store the closest pair and their difference\n closest_diff = sys.maxsize\n closest_pair = (0.0, 0.0)\n \n # Iterate through the sorted list to find the closest pair\n for i in range(len(numbers) - 1):\n diff = numbers[i + 1] - numbers[i]\n if diff < closest_diff:\n closest_diff = diff\n closest_pair = (numbers[i], numbers[i + 1])\n \n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n \"\"\"\n # Sort the list to make finding the closest elements easier\n sorted_numbers = sorted(numbers)\n \n # Initialize variables to store the closest pair and the smallest difference found\n closest_pair = (sorted_numbers[0], sorted_numbers[1])\n smallest_diff = abs(sorted_numbers[1] - sorted_numbers[0])\n \n # Iterate through the sorted list to find the closest pair\n for i in range(1, len(sorted_numbers) - 1):\n current_diff = abs(sorted_numbers[i + 1] - sorted_numbers[i])\n if current_diff < smallest_diff:\n smallest_diff = current_diff\n closest_pair = (sorted_numbers[i], sorted_numbers[i + 1])\n \n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\"\n From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n \n Parameters:\n numbers (List[float]): A list of numbers.\n \n Returns:\n Tuple[float, float]: A tuple containing the two closest numbers in ascending order.\n \"\"\"\n # Sort the list to make finding the closest pair easier\n sorted_numbers = sorted(numbers)\n \n # Initialize variables to store the closest pair and the smallest difference found\n closest_pair = (sorted_numbers[0], sorted_numbers[1])\n smallest_difference = abs(sorted_numbers[1] - sorted_numbers[0])\n \n # Iterate through the sorted list to find the closest pair\n for i in range(1, len(sorted_numbers) - 1):\n current_difference = abs(sorted_numbers[i + 1] - sorted_numbers[i])\n if current_difference < smallest_difference:\n smallest_difference = current_difference\n closest_pair = (sorted_numbers[i], sorted_numbers[i + 1])\n \n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n \"\"\"\n # Sort the list to make it easier to find the closest elements\n numbers.sort()\n \n # Initialize the closest elements and their difference\n closest_diff = float('inf')\n closest_pair = (numbers[0], numbers[1])\n \n # Iterate through the list to find the closest pair\n for i in range(len(numbers) - 1):\n diff = numbers[i + 1] - numbers[i]\n if diff < closest_diff:\n closest_diff = diff\n closest_pair = (numbers[i], numbers[i + 1])\n \n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n \"\"\"\n # Sort the list to make finding the closest elements easier\n sorted_numbers = sorted(numbers)\n \n # Initialize variables to store the closest pair and the smallest difference found\n closest_pair = (sorted_numbers[0], sorted_numbers[1])\n smallest_difference = abs(sorted_numbers[1] - sorted_numbers[0])\n \n # Iterate through the sorted list to find the pair with the smallest difference\n for i in range(1, len(sorted_numbers) - 1):\n current_difference = abs(sorted_numbers[i + 1] - sorted_numbers[i])\n if current_difference < smallest_difference:\n smallest_difference = current_difference\n closest_pair = (sorted_numbers[i], sorted_numbers[i + 1])\n \n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\"\n From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n \n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n # Sort the list to make finding the closest elements easier\n sorted_numbers = sorted(numbers)\n \n # Initialize variables to store the closest elements and their difference\n closest_diff = float('inf')\n closest_elements = (None, None)\n \n # Iterate through the sorted list to find the closest pair\n for i in range(len(sorted_numbers) - 1):\n diff = sorted_numbers[i + 1] - sorted_numbers[i]\n if diff < closest_diff:\n closest_diff = diff\n closest_elements = (sorted_numbers[i], sorted_numbers[i + 1])\n \n return closest_elements", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\"\n From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n \n :param numbers: List of floating-point numbers.\n :return: A tuple containing the two closest numbers.\n \"\"\"\n # Sort the list to make finding the closest pair easier\n sorted_numbers = sorted(numbers)\n \n # Initialize variables to store the closest pair and the smallest difference found\n closest_pair = (sorted_numbers[0], sorted_numbers[1])\n smallest_diff = abs(sorted_numbers[1] - sorted_numbers[0])\n \n # Iterate through the sorted list to find the pair with the smallest difference\n for i in range(1, len(sorted_numbers) - 1):\n current_diff = abs(sorted_numbers[i + 1] - sorted_numbers[i])\n if current_diff < smallest_diff:\n smallest_diff = current_diff\n closest_pair = (sorted_numbers[i], sorted_numbers[i + 1])\n \n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n \"\"\"\n # Sort the list to make finding the closest pair easier\n sorted_numbers = sorted(numbers)\n \n # Initialize the closest pair with the first two elements\n closest_pair = (sorted_numbers[0], sorted_numbers[1])\n min_diff = abs(sorted_numbers[1] - sorted_numbers[0])\n \n # Iterate through the sorted list to find the closest pair\n for i in range(1, len(sorted_numbers) - 1):\n diff = abs(sorted_numbers[i + 1] - sorted_numbers[i])\n if diff < min_diff:\n min_diff = diff\n closest_pair = (sorted_numbers[i], sorted_numbers[i + 1])\n \n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n \"\"\"\n # Sort the list to make it easier to find the closest elements\n numbers.sort()\n \n # Initialize variables to store the closest pair and the smallest difference found\n closest_pair = (numbers[0], numbers[1])\n smallest_diff = abs(numbers[1] - numbers[0])\n \n # Iterate through the sorted list to find the pair with the smallest difference\n for i in range(1, len(numbers) - 1):\n current_diff = abs(numbers[i + 1] - numbers[i])\n if current_diff < smallest_diff:\n smallest_diff = current_diff\n closest_pair = (numbers[i], numbers[i + 1])\n \n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n \"\"\"\n # Sort the list to ensure that the closest elements are adjacent\n numbers.sort()\n \n # Initialize variables to store the closest pair and the smallest difference\n closest_pair = (numbers[0], numbers[1])\n smallest_diff = abs(numbers[1] - numbers[0])\n \n # Iterate through the sorted list to find the closest pair\n for i in range(1, len(numbers) - 1):\n diff = abs(numbers[i + 1] - numbers[i])\n if diff < smallest_diff:\n smallest_diff = diff\n closest_pair = (numbers[i], numbers[i + 1])\n \n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n \"\"\"\n # Sort the list to make finding the closest elements easier\n sorted_numbers = sorted(numbers)\n \n # Initialize variables to store the closest elements and their difference\n closest_diff = float('inf')\n closest_elements = (None, None)\n \n # Iterate through the sorted list to find the closest pair\n for i in range(len(sorted_numbers) - 1):\n diff = sorted_numbers[i + 1] - sorted_numbers[i]\n if diff < closest_diff:\n closest_diff = diff\n closest_elements = (sorted_numbers[i], sorted_numbers[i + 1])\n \n return closest_elements", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n \"\"\"\n # Sort the list to make it easier to find the closest elements\n sorted_numbers = sorted(numbers)\n \n # Initialize variables to store the closest pair and the smallest difference found\n closest_pair = (sorted_numbers[0], sorted_numbers[1])\n smallest_diff = abs(sorted_numbers[1] - sorted_numbers[0])\n \n # Iterate through the sorted list to find the closest pair\n for i in range(1, len(sorted_numbers) - 1):\n current_diff = abs(sorted_numbers[i + 1] - sorted_numbers[i])\n if current_diff < smallest_diff:\n smallest_diff = current_diff\n closest_pair = (sorted_numbers[i], sorted_numbers[i + 1])\n \n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\"\n From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n \n :param numbers: List of floating-point numbers.\n :return: A tuple containing the two closest numbers in ascending order.\n \"\"\"\n # Sort the list to make finding the closest pair easier\n sorted_numbers = sorted(numbers)\n \n # Initialize variables to store the closest pair and their difference\n closest_diff = float('inf')\n closest_pair = (None, None)\n \n # Iterate through the sorted list to find the closest pair\n for i in range(len(sorted_numbers) - 1):\n current_diff = sorted_numbers[i + 1] - sorted_numbers[i]\n if current_diff < closest_diff:\n closest_diff = current_diff\n closest_pair = (sorted_numbers[i], sorted_numbers[i + 1])\n \n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n \"\"\"\n # Sort the list to make it easier to find the closest elements\n numbers.sort()\n \n # Initialize the closest pair with the first two elements\n closest_pair = (numbers[0], numbers[1])\n min_distance = abs(numbers[1] - numbers[0])\n \n # Iterate through the sorted list to find the closest pair\n for i in range(1, len(numbers) - 1):\n current_distance = abs(numbers[i + 1] - numbers[i])\n if current_distance < min_distance:\n min_distance = current_distance\n closest_pair = (numbers[i], numbers[i + 1])\n \n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\nimport sys\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n \"\"\"\n # Initialize the closest pair and the smallest difference\n closest_pair = (numbers[0], numbers[1])\n smallest_diff = abs(numbers[1] - numbers[0])\n\n # Iterate through the list to find the closest pair\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n current_diff = abs(numbers[i] - numbers[j])\n if current_diff < smallest_diff:\n smallest_diff = current_diff\n closest_pair = (min(numbers[i], numbers[j]), max(numbers[i], numbers[j]))\n\n return closest_pair", "matching_cluster_idx": 3}]}, "HumanEval/24": {"dps": 65.68027210884354, "dps_norm": 28.125, "pass@1": 100.0, "profiled": [{"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n for i in range(n - 1, 0, -1):\n if n % i == 0:\n return i\n return 1 # If no divisor is found, return 1 (every number is divisible by 1)", "matching_cluster_idx": 1}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n # Start checking from n-1 down to 1\n for i in range(n - 1, 0, -1):\n if n % i == 0:\n return i\n # If no divisor is found, which theoretically shouldn't happen, return 1\n return 1", "matching_cluster_idx": 1}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n for i in range(n - 1, 0, -1):\n if n % i == 0:\n return i\n return 1 # Every number is divisible by 1", "matching_cluster_idx": 0}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n for i in range(n // 2, 0, -1):\n if n % i == 0:\n return i\n return 1 # Every number is divisible by 1", "matching_cluster_idx": 4}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n for i in range(n - 1, 0, -1):\n if n % i == 0:\n return i\n return 1 # If no divisor found, return 1 (every number is divisible by 1)", "matching_cluster_idx": 1}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n # Start checking from n-1 down to 1\n for i in range(n - 1, 0, -1):\n if n % i == 0:\n return i\n return 1 # If no divisor is found, return 1 (every number is divisible by 1)", "matching_cluster_idx": 1}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\"\n For a given number n, find the largest number that divides n evenly, smaller than n.\n \n Parameters:\n n (int): The number for which to find the largest divisor.\n \n Returns:\n int: The largest divisor of n that is smaller than n.\n \n Example:\n >>> largest_divisor(15)\n 5\n \"\"\"\n for i in range(n - 1, 0, -1):\n if n % i == 0:\n return i\n return 1 # If no divisor other than 1 is found, return 1 (n is prime)", "matching_cluster_idx": 1}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n for i in range(n - 1, 0, -1):\n if n % i == 0:\n return i\n return 1 # If no divisor is found, 1 is always a divisor", "matching_cluster_idx": 1}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n # Start from the largest possible divisor, which is n-1, and go downwards\n for i in range(n - 1, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 1}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n # Start from the largest number smaller than n and decrement until a divisor is found\n for i in range(n - 1, 0, -1):\n if n % i == 0:\n return i\n return 1 # If no divisor is found, return 1 (every number is divisible by 1)", "matching_cluster_idx": 1}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n for i in range(n // 2, 0, -1):\n if n % i == 0:\n return i\n return 1 # If no divisor is found, return 1 (which is always a divisor)", "matching_cluster_idx": 4}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n if n <= 1:\n return 0 # No divisors smaller than 1 or 0\n \n for i in range(n - 1, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 0}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n for i in range(n // 2, 0, -1):\n if n % i == 0:\n return i\n return 1 # Every number is divisible by 1", "matching_cluster_idx": 4}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n # Start checking from n-1 down to 1\n for i in range(n - 1, 0, -1):\n if n % i == 0:\n return i\n return 1 # Every number is divisible by 1", "matching_cluster_idx": 1}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n for i in range(n - 1, 0, -1):\n if n % i == 0:\n return i\n return 1 # Every number is divisible by 1, so return 1 if no other divisor is found", "matching_cluster_idx": 0}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n # Start checking from n-1 down to 1 to find the largest divisor\n for i in range(n - 1, 0, -1):\n if n % i == 0:\n return i\n return 1 # If no divisor is found, return 1 (every number is divisible by 1)", "matching_cluster_idx": 1}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n for i in range(n - 1, 0, -1):\n if n % i == 0:\n return i\n return 1 # If no divisor is found, 1 is the smallest possible divisor of any integer", "matching_cluster_idx": 1}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\"\n For a given number n, find the largest number that divides n evenly, smaller than n.\n \n Args:\n n (int): The number to find the largest divisor for.\n \n Returns:\n int: The largest divisor of n that is smaller than n.\n \n Examples:\n >>> largest_divisor(15)\n 5\n >>> largest_divisor(28)\n 14\n >>> largest_divisor(17)\n 1\n \"\"\"\n for i in range(n - 1, 0, -1):\n if n % i == 0:\n return i\n return 1 # If no divisor other than 1 is found, return 1", "matching_cluster_idx": 1}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n for i in range(n - 1, 0, -1):\n if n % i == 0:\n return i\n return 1 # If no divisor is found, return 1 (every number is divisible by 1)", "matching_cluster_idx": 1}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n for i in range(n - 1, 0, -1):\n if n % i == 0:\n return i\n return 1 # Every number is divisible by 1", "matching_cluster_idx": 0}]}, "HumanEval/26": {"dps": 96.4, "dps_norm": 98.75, "pass@1": 100.0, "profiled": [{"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n # Track the occurrence of each number\n count_map = {}\n for number in numbers:\n if number in count_map:\n count_map[number] += 1\n else:\n count_map[number] = 1\n \n # Build the result list with numbers that occur exactly once\n result = []\n for number in numbers:\n if count_map[number] == 1:\n result.append(number)\n \n return result", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\"\n From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n \n :param numbers: List of integers\n :return: A new list with duplicates removed, maintaining original order of non-duplicate elements.\n \"\"\"\n seen = set()\n result = []\n for number in numbers:\n if number not in seen:\n seen.add(number)\n result.append(number)\n else:\n if number in result:\n result.remove(number)\n return result", "matching_cluster_idx": 2}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n seen = set()\n duplicates = set()\n \n # Identify duplicates\n for number in numbers:\n if number in seen:\n duplicates.add(number)\n else:\n seen.add(number)\n \n # Filter out duplicates\n return [number for number in numbers if number not in duplicates]", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n # Track the occurrence of each number\n count_dict = {}\n for num in numbers:\n if num in count_dict:\n count_dict[num] += 1\n else:\n count_dict[num] = 1\n \n # Filter out numbers that occur more than once\n result = [num for num in numbers if count_dict[num] == 1]\n \n return result", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n seen = set()\n duplicates = set()\n result = []\n\n for number in numbers:\n if number in seen:\n duplicates.add(number)\n else:\n seen.add(number)\n\n for number in numbers:\n if number not in duplicates:\n result.append(number)\n\n return result", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\"\n From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n \n :param numbers: List of integers.\n :return: A new list with duplicates removed.\n \"\"\"\n seen = set()\n duplicates = set()\n result = []\n\n for number in numbers:\n if number in seen:\n duplicates.add(number)\n else:\n seen.add(number)\n\n for number in numbers:\n if number not in duplicates:\n result.append(number)\n\n return result", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n # Track the count of each number\n count_map = {}\n for number in numbers:\n if number in count_map:\n count_map[number] += 1\n else:\n count_map[number] = 1\n \n # Filter out numbers that occur more than once\n result = [number for number in numbers if count_map[number] == 1]\n \n return result", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\"\n From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n # Track seen elements and their counts\n seen = {}\n for number in numbers:\n seen[number] = seen.get(number, 0) + 1\n \n # Filter out elements that occur more than once, maintaining original order\n result = [number for number in numbers if seen[number] == 1]\n \n return result", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n # Track the occurrence of each element\n count_dict = {}\n for number in numbers:\n if number in count_dict:\n count_dict[number] += 1\n else:\n count_dict[number] = 1\n \n # Build the result list with elements that occur only once\n result = []\n for number in numbers:\n if count_dict[number] == 1:\n result.append(number)\n \n return result", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\"\n From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n \n :param numbers: List of integers.\n :return: List of integers with duplicates removed.\n \"\"\"\n # Track the count of each number\n count_dict = {}\n for number in numbers:\n count_dict[number] = count_dict.get(number, 0) + 1\n \n # Filter out numbers that occur more than once\n result = [number for number in numbers if count_dict[number] == 1]\n \n return result", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n seen = set()\n duplicates = set()\n result = []\n\n for number in numbers:\n if number in seen:\n duplicates.add(number)\n else:\n seen.add(number)\n\n for number in numbers:\n if number not in duplicates:\n result.append(number)\n\n return result", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n \"\"\"\n # Track the count of each element\n count = {}\n for num in numbers:\n if num in count:\n count[num] += 1\n else:\n count[num] = 1\n \n # Filter out elements that occur more than once\n result = [num for num in numbers if count[num] == 1]\n \n return result", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n # Track the frequency of each number\n frequency = {}\n for num in numbers:\n if num in frequency:\n frequency[num] += 1\n else:\n frequency[num] = 1\n \n # Filter out numbers that occur more than once\n result = [num for num in numbers if frequency[num] == 1]\n \n return result", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\"\n From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n \n Example:\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n # Track the occurrence of each number\n count = {}\n for number in numbers:\n if number in count:\n count[number] += 1\n else:\n count[number] = 1\n \n # Filter out numbers that occur more than once\n result = [number for number in numbers if count[number] == 1]\n \n return result", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\"\n From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n \n :param numbers: List of integers.\n :return: A new list with duplicates removed.\n \"\"\"\n seen = set()\n duplicates = set()\n result = []\n\n for number in numbers:\n if number in seen:\n duplicates.add(number)\n else:\n seen.add(number)\n\n for number in numbers:\n if number not in duplicates:\n result.append(number)\n\n return result", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\"\n From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n \n :param numbers: List of integers.\n :return: List of integers with duplicates removed.\n \"\"\"\n # Track the count of each number\n count_map = {}\n for number in numbers:\n if number in count_map:\n count_map[number] += 1\n else:\n count_map[number] = 1\n \n # Build the result list with only numbers that appear once\n result = [number for number in numbers if count_map[number] == 1]\n \n return result", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n seen = set()\n duplicates = set()\n result = []\n\n for num in numbers:\n if num in seen:\n duplicates.add(num)\n else:\n seen.add(num)\n\n for num in numbers:\n if num not in duplicates:\n result.append(num)\n\n return result", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n \"\"\"\n # Create a dictionary to count occurrences of each number\n count_dict = {}\n for number in numbers:\n if number in count_dict:\n count_dict[number] += 1\n else:\n count_dict[number] = 1\n \n # Filter out numbers that occur more than once and maintain the order\n result = [number for number in numbers if count_dict[number] == 1]\n \n return result", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n # Create a dictionary to count occurrences of each number\n count_dict = {}\n for number in numbers:\n if number in count_dict:\n count_dict[number] += 1\n else:\n count_dict[number] = 1\n \n # Create a list to store the result, only adding numbers that occur once\n result = []\n for number in numbers:\n if count_dict[number] == 1:\n result.append(number)\n \n return result", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n \"\"\"\n # Track the occurrence of each number\n count_map = {}\n for number in numbers:\n if number in count_map:\n count_map[number] += 1\n else:\n count_map[number] = 1\n\n # Filter out numbers that occur more than once, preserving order\n result = [number for number in numbers if count_map[number] == 1]\n \n return result", "matching_cluster_idx": 3}]}, "HumanEval/31": {"dps": 97.46835443037975, "dps_norm": 87.5, "pass@1": 100.0, "profiled": [{"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}]}, "HumanEval/33": {"dps": 97.22222222222223, "dps_norm": 81.81818181818181, "pass@1": 27.0, "profiled": [{"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n \"\"\"\n # Extract elements at indices divisible by three (0-based indexing)\n divisible_by_three = [l[i] for i in range(len(l)) if (i % 3) == 0]\n \n # Sort the extracted elements\n divisible_by_three.sort()\n \n # Create a new list with the sorted elements at the correct positions\n l_prime = l.copy()\n for i, value in zip(range(0, len(l), 3), divisible_by_three):\n l_prime[i] = value\n \n return l_prime", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n \"\"\"\n # Extract elements at indices divisible by three (0-based)\n divisible_by_three = [l[i] for i in range(len(l)) if (i % 3) == 0]\n \n # Sort the extracted elements\n divisible_by_three_sorted = sorted(divisible_by_three)\n \n # Create a new list with the sorted elements at the correct positions\n l_prime = l.copy()\n for i, value in enumerate(divisible_by_three_sorted):\n l_prime[i * 3] = value\n \n return l_prime", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"\n This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n \n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n # Extract elements at indices divisible by 3\n divisible_by_three = [l[i] for i in range(len(l)) if (i % 3 == 0)]\n \n # Sort the extracted elements\n sorted_divisible_by_three = sorted(divisible_by_three)\n \n # Create a new list l' that is a copy of l\n l_prime = l[:]\n \n # Replace elements at indices divisible by 3 with the sorted values\n for i, value in zip(range(0, len(l), 3), sorted_divisible_by_three):\n l_prime[i] = value\n \n return l_prime", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"\n This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n \n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n # Extract elements at indices divisible by 3\n elements_at_divisible_by_three = [l[i] for i in range(len(l)) if (i % 3 == 0)]\n \n # Sort these elements\n sorted_elements = sorted(elements_at_divisible_by_three)\n \n # Create a new list with the sorted elements placed back in their original positions\n result = l.copy()\n sorted_index = 0\n for i in range(len(l)):\n if i % 3 == 0:\n result[i] = sorted_elements[sorted_index]\n sorted_index += 1\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n \"\"\"\n # Extract elements at indices divisible by 3\n divisible_by_three = [l[i] for i in range(len(l)) if (i % 3 == 0)]\n \n # Sort these elements\n sorted_divisible_by_three = sorted(divisible_by_three)\n \n # Create a new list to store the result\n l_prime = []\n \n # Counter for the sorted elements\n sorted_index = 0\n \n for i in range(len(l)):\n if i % 3 == 0:\n l_prime.append(sorted_divisible_by_three[sorted_index])\n sorted_index += 1\n else:\n l_prime.append(l[i])\n \n return l_prime", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n \"\"\"\n # Extract elements at indices divisible by 3\n divisible_by_three = [l[i] for i in range(len(l)) if (i % 3 == 0)]\n \n # Sort the extracted elements\n sorted_divisible_by_three = sorted(divisible_by_three)\n \n # Replace elements in the original list with the sorted elements\n l_prime = l[:]\n for i, value in zip(range(0, len(l), 3), sorted_divisible_by_three):\n l_prime[i] = value\n \n return l_prime", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"\n This function takes a list l and returns a list l' such that\n l' is identical to l in the indices that are not divisible by three, while its values at the indices that are divisible by three are equal\n to the values of the corresponding indices of l, but sorted.\n \"\"\"\n # Extract elements at indices divisible by 3\n divisible_by_three = [l[i] for i in range(len(l)) if (i % 3) == 0]\n \n # Sort the extracted elements\n sorted_divisible_by_three = sorted(divisible_by_three)\n \n # Create a new list with the sorted elements at the correct positions\n result = l.copy()\n for i, value in zip(range(0, len(l), 3), sorted_divisible_by_three):\n result[i] = value\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"\n This function takes a list l and returns a list l' such that\n l' is identical to l in the indices that are not divisible by three, while its values at the indices that are divisible by three are equal\n to the values of the corresponding indices of l, but sorted.\n \n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n # Extract elements at indices divisible by 3 and sort them\n divisible_by_three = sorted([l[i] for i in range(0, len(l), 3)])\n \n # Create a new list to store the result\n result = l.copy()\n \n # Replace elements at indices divisible by 3 with the sorted elements\n for i, value in zip(range(0, len(l), 3), divisible_by_three):\n result[i] = value\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"\n This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n \n Examples:\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n # Extract elements at indices divisible by three\n third_elements = [l[i] for i in range(len(l)) if (i % 3 == 0)]\n \n # Sort the extracted elements\n sorted_third_elements = sorted(third_elements)\n \n # Create a new list to store the result\n l_prime = []\n \n # Index for the sorted third elements\n sorted_index = 0\n \n for i in range(len(l)):\n if i % 3 == 0:\n l_prime.append(sorted_third_elements[sorted_index])\n sorted_index += 1\n else:\n l_prime.append(l[i])\n \n return l_prime", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"\n This function takes a list l and returns a list l' such that\n l' is identical to l in the indices that are not divisible by three, while its values at the indices that are divisible by three are equal\n to the values of the corresponding indices of l, but sorted.\n \"\"\"\n # Extract elements at indices divisible by 3\n divisible_by_three = [l[i] for i in range(len(l)) if (i % 3 == 0)]\n \n # Sort the extracted elements\n divisible_by_three_sorted = sorted(divisible_by_three)\n \n # Create a new list to store the result\n result = l.copy()\n \n # Replace elements at indices divisible by 3 with the sorted elements\n for i, value in zip(range(0, len(l), 3), divisible_by_three_sorted):\n result[i] = value\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"\n This function takes a list l and returns a list l' such that\n l' is identical to l in the indices that are not divisible by three, while its values at the indices that are divisible by three are equal\n to the values of the corresponding indices of l, but sorted.\n \"\"\"\n # Extract elements at indices divisible by 3\n divisible_by_three = [l[i] for i in range(len(l)) if (i % 3 == 0)]\n \n # Sort the extracted elements\n sorted_divisible_by_three = sorted(divisible_by_three)\n \n # Create the new list l' with the same elements as l\n l_prime = l.copy()\n \n # Replace elements at indices divisible by 3 with the sorted elements\n sorted_index = 0\n for i in range(len(l_prime)):\n if i % 3 == 0:\n l_prime[i] = sorted_divisible_by_three[sorted_index]\n sorted_index += 1\n \n return l_prime", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n \"\"\"\n # Extract elements at indices divisible by three (including index 0)\n divisible_by_three = [l[i] for i in range(len(l)) if (i % 3 == 0)]\n \n # Sort the extracted elements\n divisible_by_three_sorted = sorted(divisible_by_three)\n \n # Create a new list with the sorted elements placed back at the correct indices\n l_prime = l.copy()\n for i, value in enumerate(divisible_by_three_sorted):\n l_prime[i * 3] = value\n \n return l_prime", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n \"\"\"\n # Extract elements at indices divisible by three\n indices_div_by_three = [i for i in range(len(l)) if (i % 3 == 0)]\n elements_div_by_three = [l[i] for i in indices_div_by_three]\n \n # Sort the extracted elements\n sorted_elements = sorted(elements_div_by_three)\n \n # Create a new list with the sorted elements placed back\n l_prime = l.copy()\n for idx, value in zip(indices_div_by_three, sorted_elements):\n l_prime[idx] = value\n \n return l_prime", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"\n This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n \"\"\"\n # Extract the elements at indices divisible by three\n indices_div_by_three = [i for i in range(len(l)) if (i % 3) == 0]\n elements_div_by_three = [l[i] for i in indices_div_by_three]\n \n # Sort the extracted elements\n elements_div_by_three_sorted = sorted(elements_div_by_three)\n \n # Create a new list with the sorted elements in the correct positions\n l_prime = l.copy()\n for i, idx in enumerate(indices_div_by_three):\n l_prime[idx] = elements_div_by_three_sorted[i]\n \n return l_prime", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"\n This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n \n Examples:\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n # Extract elements at indices divisible by 3\n divisible_by_three = [l[i] for i in range(len(l)) if (i % 3 == 0)]\n \n # Sort the extracted elements\n sorted_divisible_by_three = sorted(divisible_by_three)\n \n # Create the new list with sorted elements at the correct positions\n result = l[:]\n for i, val in enumerate(sorted_divisible_by_three):\n result[3 * i] = val\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n \"\"\"\n # Extract elements at indices divisible by 3\n divisible_by_three = [l[i] for i in range(0, len(l), 3)]\n \n # Sort the extracted elements\n sorted_divisible_by_three = sorted(divisible_by_three)\n \n # Create a new list l' with the same elements as l\n l_prime = l[:]\n \n # Replace elements at indices divisible by 3 with the sorted elements\n for i, value in zip(range(0, len(l), 3), sorted_divisible_by_three):\n l_prime[i] = value\n \n return l_prime", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"\n This function takes a list l and returns a list l' such that\n l' is identical to l in the indices that are not divisible by three, while its values at the indices that are divisible by three are equal\n to the values of the corresponding indices of l, but sorted.\n \"\"\"\n # Extract elements at indices divisible by 3\n divisible_by_three = [l[i] for i in range(len(l)) if (i % 3 == 0)]\n \n # Sort these elements\n sorted_divisible_by_three = sorted(divisible_by_three)\n \n # Create the new list l'\n l_prime = l.copy()\n \n # Replace elements at indices divisible by 3 with sorted elements\n for i, value in zip(range(0, len(l), 3), sorted_divisible_by_three):\n l_prime[i] = value\n \n return l_prime", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n \"\"\"\n # Extract elements at indices divisible by three\n third_elements = [l[i] for i in range(len(l)) if (i % 3 == 0)]\n \n # Sort the extracted elements\n sorted_third_elements = sorted(third_elements)\n \n # Create a new list with the sorted elements in the correct positions\n l_prime = l.copy()\n for i, value in zip(range(0, len(l), 3), sorted_third_elements):\n l_prime[i] = value\n \n return l_prime", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"\n This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n \n :param l: List of elements\n :return: Modified list according to the problem description\n \n Examples:\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n # Extract elements at indices divisible by 3\n divisible_by_three = [l[i] for i in range(len(l)) if (i % 3 == 0)]\n \n # Sort the extracted elements\n sorted_divisible_by_three = sorted(divisible_by_three)\n \n # Replace elements in the original list with sorted elements at indices divisible by 3\n j = 0\n for i in range(len(l)):\n if i % 3 == 0:\n l[i] = sorted_divisible_by_three[j]\n j += 1\n \n return l", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n \"\"\"\n # Extract elements at indices divisible by three\n third_indices = [i for i in range(len(l)) if (i % 3 == 0)]\n third_elements = [l[i] for i in third_indices]\n \n # Sort the extracted elements\n third_elements_sorted = sorted(third_elements)\n \n # Create a new list with the sorted elements at the correct positions\n l_prime = l.copy()\n for idx, value in zip(third_indices, third_elements_sorted):\n l_prime[idx] = value\n \n return l_prime", "matching_cluster_idx": 8}]}, "HumanEval/34": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n # Convert the list to a set to remove duplicates, then convert it back to a sorted list\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n # Convert the list to a set to remove duplicates, then convert back to a list and sort it\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n # Convert the list to a set to remove duplicates, then convert back to a list and sort it\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n # Convert the list to a set to remove duplicates, then convert back to a list and sort it\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n # Convert the list to a set to remove duplicates, then convert back to a list and sort it\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n # Convert the list to a set to remove duplicates, then convert back to a list and sort it\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n # Use set to remove duplicates and then convert back to list\n unique_set = set(l)\n # Sort the unique elements\n unique_sorted_list = sorted(unique_set)\n return unique_sorted_list", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n # Convert the list to a set to remove duplicates, then convert back to a list and sort it\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n # Convert the list to a set to remove duplicates, then convert back to a sorted list\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n # Convert the list to a set to remove duplicates, then convert back to a list and sort it\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n # Convert the list to a set to remove duplicates, then convert back to a list and sort it\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}]}, "HumanEval/36": {"dps": 96.77419354838709, "dps_norm": 71.42857142857143, "pass@1": 100.0, "profiled": [{"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"\n Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n \n :param n: The upper limit (non-inclusive).\n :return: The count of digit 7 appearances.\n \"\"\"\n count = 0\n for i in range(1, n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"\n Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n \"\"\"\n count = 0\n for i in range(1, n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"\n Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n \n :param n: The upper limit (exclusive) to check for numbers.\n :return: The count of digit 7 appearances in numbers less than n and divisible by 11 or 13.\n \"\"\"\n count = 0\n for i in range(1, n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"\n Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n \n :param n: The upper limit (non-inclusive) to check for numbers.\n :return: The count of digit 7 appearances in numbers less than n and divisible by 11 or 13.\n \"\"\"\n count = 0\n for i in range(1, n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"\n Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n \"\"\"\n count = 0\n for i in range(1, n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"\n Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n \"\"\"\n count = 0\n for i in range(1, n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"\n Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n \"\"\"\n count = 0\n for i in range(1, n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"\n Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n \"\"\"\n count = 0\n for i in range(1, n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"\n Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n \n :param n: The upper limit (exclusive) for checking the numbers.\n :return: The count of the digit 7 in numbers less than n and divisible by 11 or 13.\n \"\"\"\n count = 0\n for i in range(1, n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"\n Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n \"\"\"\n count = 0\n for i in range(1, n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"\n Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n \n :param n: The upper limit (non-inclusive).\n :return: The count of digit 7 appearances.\n \"\"\"\n count = 0\n for i in range(1, n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"\n Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n \n :param n: The upper limit (non-inclusive) for checking numbers.\n :return: The count of the digit 7 in numbers less than n and divisible by 11 or 13.\n \"\"\"\n count = 0\n for i in range(1, n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"\n Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n \"\"\"\n count = 0\n for i in range(1, n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"\n Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n \n :param n: An integer specifying the upper limit (exclusive).\n :return: The count of digit 7 appearances in numbers less than n and divisible by 11 or 13.\n \"\"\"\n count = 0\n for i in range(1, n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"\n Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n \n :param n: The upper limit (exclusive) to check for numbers.\n :return: The count of digit 7 appearances in numbers less than n and divisible by 11 or 13.\n \"\"\"\n count = 0\n for i in range(1, n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"\n Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n \n :param n: The upper limit (exclusive) to check for numbers.\n :return: The count of digit 7 appearances in numbers less than n and divisible by 11 or 13.\n \"\"\"\n count = 0\n for i in range(1, n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"\n Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n \n :param n: The upper limit (non-inclusive) to check for numbers divisible by 11 or 13.\n :return: The count of digit 7 appearances in numbers less than n that are divisible by 11 or 13.\n \"\"\"\n count = 0\n for i in range(1, n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"\n Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n \"\"\"\n count = 0\n for i in range(1, n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"\n Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n \n :param n: The upper limit (exclusive) for checking numbers.\n :return: The count of digit 7 appearances in numbers less than n and divisible by 11 or 13.\n \"\"\"\n count = 0\n for i in range(1, n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"\n Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n \"\"\"\n count = 0\n for i in range(1, n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}]}, "HumanEval/37": {"dps": 95.18003273322422, "dps_norm": 90.5, "pass@1": 100.0, "profiled": [{"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Extract even indices elements and sort them\n even_elements = sorted(l[::2])\n \n # Create the result list\n result = []\n even_idx = 0\n for i in range(len(l)):\n if i % 2 == 0:\n result.append(even_elements[even_idx])\n even_idx += 1\n else:\n result.append(l[i])\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Extract even-index elements\n even_elements = [l[i] for i in range(0, len(l), 2)]\n \n # Sort the even-index elements\n even_elements_sorted = sorted(even_elements)\n \n # Create the new list with sorted even indices\n result = l[:]\n for i, value in zip(range(0, len(l), 2), even_elements_sorted):\n result[i] = value\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Extract even-indexed elements and sort them\n even_elements = sorted(l[::2])\n \n # Reconstruct the list with sorted even-indexed elements\n l_prime = []\n even_index = 0\n for i in range(len(l)):\n if i % 2 == 0:\n l_prime.append(even_elements[even_index])\n even_index += 1\n else:\n l_prime.append(l[i])\n \n return l_prime", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Extract even indices values and sort them\n even_indices_values = sorted([l[i] for i in range(0, len(l), 2)])\n \n # Create the new list with the sorted even indices values and the original odd indices values\n l_prime = []\n even_index = 0\n for i in range(len(l)):\n if i % 2 == 0:\n l_prime.append(even_indices_values[even_index])\n even_index += 1\n else:\n l_prime.append(l[i])\n \n return l_prime", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Extract the even indices elements and sort them\n even_indices_elements = sorted([l[i] for i in range(0, len(l), 2)])\n \n # Create a new list to hold the sorted result\n sorted_list = []\n \n # Iterate over the original list and place elements in the new list\n even_index = 0\n for i in range(len(l)):\n if i % 2 == 0:\n # Place the sorted even index element\n sorted_list.append(even_indices_elements[even_index])\n even_index += 1\n else:\n # Place the original odd index element\n sorted_list.append(l[i])\n \n return sorted_list", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Extract even-indexed elements\n even_indices = l[::2]\n \n # Sort the even-indexed elements\n sorted_even_indices = sorted(even_indices)\n \n # Create the result list with the same length as the original list\n result = l[:]\n \n # Replace the even-indexed elements with the sorted ones\n for i, value in enumerate(sorted_even_indices):\n result[2 * i] = value\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Extract the elements at even indices\n even_elements = [l[i] for i in range(0, len(l), 2)]\n \n # Sort the even elements\n even_elements_sorted = sorted(even_elements)\n \n # Create a new list to store the result\n result = []\n \n # Counter for the sorted even elements\n even_counter = 0\n \n for i in range(len(l)):\n if i % 2 == 0:\n # Append the next sorted even element\n result.append(even_elements_sorted[even_counter])\n even_counter += 1\n else:\n # Append the original odd element\n result.append(l[i])\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Extract even indices and sort them\n even_indices = [l[i] for i in range(len(l)) if i % 2 == 0]\n even_indices_sorted = sorted(even_indices)\n \n # Create a new list to store the result\n result = []\n even_index = 0\n \n for i in range(len(l)):\n if i % 2 == 0:\n result.append(even_indices_sorted[even_index])\n even_index += 1\n else:\n result.append(l[i])\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Extract even-indexed elements and sort them\n even_elements = sorted([l[i] for i in range(0, len(l), 2)])\n \n # Create the new list with sorted even-indexed elements\n result = []\n even_idx = 0\n for i in range(len(l)):\n if i % 2 == 0:\n result.append(even_elements[even_idx])\n even_idx += 1\n else:\n result.append(l[i])\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n \"\"\"\n # Extract even-indexed elements and sort them\n even_elements = sorted(l[i] for i in range(0, len(l), 2))\n \n # Create a new list to store the result\n l_prime = []\n \n # Iterate through the original list and build the new list\n even_index = 0\n for i in range(len(l)):\n if i % 2 == 0:\n l_prime.append(even_elements[even_index])\n even_index += 1\n else:\n l_prime.append(l[i])\n \n return l_prime", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Extract even indices values and sort them\n even_indices_values = sorted(l[i] for i in range(0, len(l), 2))\n \n # Create a new list with the same length as the original\n result = l[:]\n \n # Replace even indices in the result list with the sorted values\n for i, value in zip(range(0, len(result), 2), even_indices_values):\n result[i] = value\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Extract even-indexed elements\n even_elements = [l[i] for i in range(0, len(l), 2)]\n \n # Sort the even-indexed elements\n even_elements_sorted = sorted(even_elements)\n \n # Create the new list with sorted even-indexed elements\n l_prime = []\n even_idx = 0\n for i in range(len(l)):\n if i % 2 == 0:\n l_prime.append(even_elements_sorted[even_idx])\n even_idx += 1\n else:\n l_prime.append(l[i])\n \n return l_prime", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Extract even-indexed elements\n even_indices = [i for i in range(len(l)) if i % 2 == 0]\n even_values = [l[i] for i in even_indices]\n \n # Sort the even-indexed elements\n even_values_sorted = sorted(even_values)\n \n # Create the new list with sorted even-indexed elements\n l_prime = l.copy()\n for idx, value in zip(even_indices, even_values_sorted):\n l_prime[idx] = value\n \n return l_prime", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Extract even indices and sort them\n even_indices_values = sorted(l[i] for i in range(0, len(l), 2))\n \n # Create a new list to store the result\n l_prime = l.copy()\n \n # Replace even indices in l_prime with sorted values\n for i, value in zip(range(0, len(l), 2), even_indices_values):\n l_prime[i] = value\n \n return l_prime", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Extract even-index elements and sort them\n even_elements = sorted(l[::2])\n \n # Create a new list to hold the result\n result = []\n \n # Alternate between even and odd index elements\n for i in range(len(l)):\n if i % 2 == 0:\n result.append(even_elements.pop(0))\n else:\n result.append(l[i])\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Extract even indices and sort them\n even_indices = [l[i] for i in range(0, len(l), 2)]\n even_indices_sorted = sorted(even_indices)\n \n # Create a new list with sorted even indices and original odd indices\n l_prime = []\n even_idx = 0\n for i in range(len(l)):\n if i % 2 == 0:\n l_prime.append(even_indices_sorted[even_idx])\n even_idx += 1\n else:\n l_prime.append(l[i])\n \n return l_prime", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Extract even-index elements and sort them\n even_elements = sorted(l[::2])\n \n # Reconstruct the list with sorted even-index elements\n l_prime = []\n even_idx = 0\n for i in range(len(l)):\n if i % 2 == 0:\n l_prime.append(even_elements[even_idx])\n even_idx += 1\n else:\n l_prime.append(l[i])\n \n return l_prime", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Extract even-indexed elements\n even_elements = [l[i] for i in range(0, len(l), 2)]\n \n # Sort the even-indexed elements\n even_elements_sorted = sorted(even_elements)\n \n # Create a new list to hold the result\n result = []\n \n # Reconstruct the list with sorted even-indexed elements\n even_index = 0\n for i in range(len(l)):\n if i % 2 == 0:\n result.append(even_elements_sorted[even_index])\n even_index += 1\n else:\n result.append(l[i])\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Extract even-indexed elements and sort them\n even_elements = sorted(l[::2])\n # Create the result list with the same length as the input list\n result = [None] * len(l)\n # Place the sorted even-indexed elements back into the result list\n result[::2] = even_elements\n # Place the odd-indexed elements from the original list into the result list\n result[1::2] = l[1::2]\n return result", "matching_cluster_idx": 9}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Extract even indices\n even_indices = [i for i in range(len(l)) if i % 2 == 0]\n # Extract the values at even indices and sort them\n even_values_sorted = sorted([l[i] for i in even_indices])\n \n # Create the new list with sorted even indices\n l_prime = l.copy()\n for i, value in zip(even_indices, even_values_sorted):\n l_prime[i] = value\n \n return l_prime", "matching_cluster_idx": 8}]}, "HumanEval/49": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def modp(n: int, p: int) -> int:\n \"\"\"\n Return 2^n modulo p (be aware of numerics).\n \n Examples:\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n # Efficiently compute 2^n modulo p using modular exponentiation\n result = pow(2, n, p)\n return result", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\"\"\"\n # Use the built-in pow function with three arguments to efficiently compute (2^n) % p\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"\n Return 2^n modulo p (be aware of numerics).\n \n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"\n Return 2^n modulo p (be aware of numerics).\n \n Parameters:\n n (int): The exponent to raise 2 by.\n p (int): The modulus.\n \n Returns:\n int: The result of (2^n) % p.\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"\n Return 2^n modulo p (be aware of numerics).\n \n Examples:\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n # Efficiently compute 2^n modulo p using Python's built-in pow function\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"\n Return 2^n modulo p (be aware of numerics).\n \n Examples:\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"\n Return 2^n modulo p (be aware of numerics).\n \n Args:\n n (int): The exponent to raise 2 by.\n p (int): The modulus.\n \n Returns:\n int: The result of 2^n modulo p.\n \n Examples:\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"\n Return 2^n modulo p (be aware of numerics).\n \n Parameters:\n n (int): The exponent to which 2 is raised.\n p (int): The modulus.\n \n Returns:\n int: The result of 2^n modulo p.\n \n Examples:\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"\n Return 2^n modulo p (be aware of numerics).\n \n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n # Efficiently compute 2^n modulo p using the pow function\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"\n Return 2^n modulo p (be aware of numerics).\n \n Examples:\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"\n Return 2^n modulo p (be aware of numerics).\n \n :param n: The exponent to which 2 is raised.\n :param p: The modulus.\n :return: The result of (2^n) % p.\n \"\"\"\n # Using pow with three arguments to efficiently compute (2^n) % p\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"\n Return 2^n modulo p (be aware of numerics).\n \n :param n: The exponent to which 2 is raised.\n :param p: The modulus.\n :return: The result of 2^n modulo p.\n \"\"\"\n # Using Python's built-in pow function for efficient modular exponentiation\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"\n Return 2^n modulo p (be aware of numerics).\n \n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"\n Return 2^n modulo p (be aware of numerics).\n \n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n # Using pow for efficient modular exponentiation\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"\n Return 2^n modulo p (be aware of numerics).\n \n Parameters:\n n (int): The exponent.\n p (int): The modulus.\n \n Returns:\n int: The result of 2^n modulo p.\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"\n Return 2^n modulo p (be aware of numerics).\n \n :param n: Exponent to which 2 is raised.\n :param p: Modulus.\n :return: Result of (2^n) % p.\n \"\"\"\n # Using pow function for better performance and handling large numbers\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"\n Return 2^n modulo p (be aware of numerics).\n \n Examples:\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"\n Return 2^n modulo p (be aware of numerics).\n \n :param n: Exponent to which 2 is raised.\n :param p: Modulus.\n :return: 2^n modulo p.\n \n Examples:\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"\n Return 2^n modulo p (be aware of numerics).\n \n :param n: Exponent to which 2 is raised.\n :param p: Modulus.\n :return: 2^n modulo p.\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"\n Return 2^n modulo p.\n \n This function computes 2 raised to the power of n, then takes the result modulo p.\n It handles large numbers efficiently using Python's built-in pow function with three arguments.\n \n Args:\n n (int): The exponent to which 2 is raised.\n p (int): The modulus.\n \n Returns:\n int: The result of (2^n) % p.\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}]}, "HumanEval/51": {"dps": 96.13526570048309, "dps_norm": 75.0, "pass@1": 100.0, "profiled": [{"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = 'aeiouAEIOU'\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes a string and returns a string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes a string and returns a string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "import doctest\ndef remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = 'aeiouAEIOU'\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes a string and returns a string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "import doctest\ndef remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes a string and returns a string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes a string and returns a string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes a string and returns a string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes a string and returns a string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\\\nghijklm\")\n 'bcdf\\\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}]}, "HumanEval/54": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \"\"\"\n # Convert strings to sets to remove duplicates and compare\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \"\"\"\n # Convert both strings to sets to compare the unique characters\n set_s0 = set(s0)\n set_s1 = set(s1)\n \n # Check if the sets are equal\n return set_s0 == set_s1", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \"\"\"\n # Convert strings to sets to remove duplicates and compare\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \"\"\"\n # Convert both strings to sets of characters to remove duplicates and check if they are equal\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \"\"\"\n # Convert both strings to sets to remove duplicates and compare\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \"\"\"\n # Create a set of characters for each string\n set_s0 = set(s0)\n set_s1 = set(s1)\n \n # Check if the sets are equal\n return set_s0 == set_s1", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \"\"\"\n # Convert both strings to sets to remove duplicates and compare\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \"\"\"\n # Convert strings to sets of characters to compare\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \"\"\"\n # Convert both strings to sets of characters and compare\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \"\"\"\n # Convert strings to sets to remove duplicates and compare\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \"\"\"\n # Convert strings to sets to compare unique characters\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \"\"\"\n # Convert strings to sets to remove duplicates and compare\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \"\"\"\n # Convert strings to sets to remove duplicates and compare\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \"\"\"\n # Convert both strings to sets to remove duplicate characters and compare\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \"\"\"\n # Convert both strings to sets to remove duplicates and compare\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \"\"\"\n # Create sets of characters from both strings\n set_s0 = set(s0)\n set_s1 = set(s1)\n \n # Check if the sets are equal\n return set_s0 == set_s1", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \"\"\"\n # Create sets from the strings to remove duplicates and compare\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \"\"\"\n # Convert both strings to sets to compare unique characters\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \"\"\"\n # Create sets of characters from both strings\n set_s0 = set(s0)\n set_s1 = set(s1)\n \n # Check if the sets are equal\n if set_s0 == set_s1:\n return True\n else:\n return False", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \"\"\"\n # Convert strings to sets to remove duplicates and then compare\n return set(s0) == set(s1)", "matching_cluster_idx": 6}]}, "HumanEval/58": {"dps": 92.51968503937007, "dps_norm": 83.33333333333333, "pass@1": 100.0, "profiled": [{"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n # Convert both lists to sets to remove duplicates and find common elements\n set1 = set(l1)\n set2 = set(l2)\n common_elements = set1.intersection(set2)\n \n # Convert the set of common elements back to a sorted list\n return sorted(list(common_elements))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n # Convert the lists to sets to remove duplicates and find the intersection\n common_elements = set(l1).intersection(set(l2))\n # Return the sorted list of common elements\n return sorted(common_elements)", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n # Convert both lists to sets to remove duplicates and then find the intersection\n common_elements = set(l1).intersection(set(l2))\n # Return the sorted list of common elements\n return sorted(common_elements)", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list) -> list:\n \"\"\"\n Return sorted unique common elements for two lists.\n \n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n # Convert both lists to sets to remove duplicates and find common elements\n common_elements = set(l1) & set(l2)\n # Convert the set back to a sorted list\n return sorted(common_elements)", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n # Convert the lists to sets to remove duplicates and find common elements\n set1 = set(l1)\n set2 = set(l2)\n common_elements = set1.intersection(set2)\n \n # Return the sorted list of common elements\n return sorted(common_elements)", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n\n \"\"\"\n # Convert both lists to sets to remove duplicates and find common elements\n common_elements = set(l1) & set(l2)\n # Return the sorted list of common elements\n return sorted(common_elements)", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n # Convert both lists to sets to remove duplicates and then find intersection\n common_elements = set(l1).intersection(set(l2))\n # Return the sorted list of common elements\n return sorted(common_elements)", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n # Convert lists to sets to find unique elements and then find intersection\n common_elements = set(l1) & set(l2)\n # Return the sorted list of common elements\n return sorted(common_elements)", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n # Convert the lists to sets to find unique elements\n set1 = set(l1)\n set2 = set(l2)\n \n # Find the intersection of the two sets\n common_elements = set1 & set2\n \n # Return the sorted list of common elements\n return sorted(common_elements)", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n # Convert both lists to sets to remove duplicates and find intersection\n common_elements = set(l1) & set(l2)\n # Return the sorted list of common elements\n return sorted(common_elements)", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n # Convert lists to sets to find unique elements\n set1 = set(l1)\n set2 = set(l2)\n \n # Find the intersection of the two sets\n common_elements = set1.intersection(set2)\n \n # Convert the set back to a sorted list\n return sorted(list(common_elements))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n\n \"\"\"\n # Convert lists to sets to find common elements\n set1 = set(l1)\n set2 = set(l2)\n \n # Find intersection of the two sets\n common_elements = set1 & set2\n \n # Return the sorted list of common elements\n return sorted(common_elements)", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n # Convert lists to sets to remove duplicates and find intersection\n common_elements = set(l1).intersection(set(l2))\n # Return the sorted list of common elements\n return sorted(common_elements)", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n \n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n # Convert both lists to sets to remove duplicates and find intersection\n set1 = set(l1)\n set2 = set(l2)\n common_elements = set1 & set2\n \n # Convert the set back to a sorted list\n return sorted(common_elements)", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n # Convert lists to sets to find unique elements and then find the intersection\n common_elements = set(l1) & set(l2)\n # Return the sorted list of common elements\n return sorted(common_elements)", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list) -> list:\n \"\"\"\n Return sorted unique common elements for two lists.\n \n :param l1: First list of elements.\n :param l2: Second list of elements.\n :return: A sorted list of unique common elements.\n \"\"\"\n # Convert both lists to sets to remove duplicates and then find the intersection\n common_elements = set(l1) & set(l2)\n # Convert the set back to a sorted list\n return sorted(common_elements)", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n # Convert both lists to sets to remove duplicates and find common elements\n set1 = set(l1)\n set2 = set(l2)\n \n # Find the intersection of the two sets\n common_elements = set1.intersection(set2)\n \n # Return the sorted list of common elements\n return sorted(common_elements)", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n # Convert both lists to sets to remove duplicates and find common elements\n common_elements = set(l1) & set(l2)\n # Return the sorted list of common elements\n return sorted(common_elements)", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n # Convert lists to sets to find unique elements\n set1 = set(l1)\n set2 = set(l2)\n \n # Find the intersection of the two sets\n common_elements = set1.intersection(set2)\n \n # Convert the set of common elements back to a sorted list\n return sorted(common_elements)", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n # Convert both lists to sets to remove duplicates and then find the intersection\n common_elements = set(l1) & set(l2)\n # Return the sorted list of common elements\n return sorted(list(common_elements))", "matching_cluster_idx": 4}]}, "HumanEval/59": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"\n Return the largest prime factor of n. Assume n > 1 and is not a prime.\n \n Args:\n n (int): The number to find the largest prime factor of.\n \n Returns:\n int: The largest prime factor of n.\n \"\"\"\n factor = 2\n last_factor = 1\n while n > 1:\n if n % factor == 0:\n last_factor = factor\n n //= factor\n else:\n factor += 1\n return last_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"\n Return the largest prime factor of n. Assume n > 1 and is not a prime.\n \n :param n: An integer greater than 1 and not a prime.\n :return: The largest prime factor of n.\n \"\"\"\n factor = 2\n last_factor = 1\n while n > 1:\n if n % factor == 0:\n last_factor = factor\n n //= factor\n while n % factor == 0:\n n //= factor\n factor += 1\n return last_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"\n Return the largest prime factor of n. Assume n > 1 and is not a prime.\n \n :param n: An integer greater than 1 and not a prime.\n :return: The largest prime factor of n.\n \"\"\"\n factor = 2\n last_factor = 1\n while n > 1:\n if n % factor == 0:\n last_factor = factor\n n //= factor\n while n % factor == 0:\n n //= factor\n factor += 1\n return last_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"\n Return the largest prime factor of n. Assume n > 1 and is not a prime.\n \n :param n: An integer greater than 1 and not a prime number.\n :return: The largest prime factor of n.\n \"\"\"\n factor = 2\n last_factor = 1\n while n > 1:\n if n % factor == 0:\n last_factor = factor\n n //= factor\n while n % factor == 0:\n n //= factor\n factor += 1\n return last_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"\n Return the largest prime factor of n. Assume n > 1 and is not a prime.\n \n :param n: An integer greater than 1 and not a prime number.\n :return: The largest prime factor of n.\n \"\"\"\n factor = 2\n last_factor = 1\n while n > 1:\n if n % factor == 0:\n last_factor = factor\n n //= factor\n while n % factor == 0:\n n //= factor\n factor += 1\n else:\n factor += 1\n return last_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"\n Return the largest prime factor of n. Assume n > 1 and is not a prime.\n \n :param n: An integer greater than 1 and not a prime.\n :return: The largest prime factor of n.\n \"\"\"\n factor = 2\n last_factor = 1\n while n > 1:\n if n % factor == 0:\n last_factor = factor\n n //= factor\n while n % factor == 0:\n n //= factor\n factor += 1\n return last_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"\n Return the largest prime factor of n. Assume n > 1 and is not a prime.\n \n :param n: An integer greater than 1 and not a prime number.\n :return: The largest prime factor of n.\n \"\"\"\n factor = 2\n last_factor = 1\n while n > 1:\n if n % factor == 0:\n last_factor = factor\n n //= factor\n while n % factor == 0:\n n //= factor\n factor += 1\n return last_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"\n Return the largest prime factor of n. Assume n > 1 and is not a prime.\n \n :param n: An integer greater than 1 and not a prime number.\n :return: The largest prime factor of n.\n \"\"\"\n factor = 2\n last_factor = 1\n while n > 1:\n if n % factor == 0:\n last_factor = factor\n n //= factor\n while n % factor == 0:\n n //= factor\n factor += 1\n return last_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"\n Return the largest prime factor of n. Assume n > 1 and is not a prime.\n \n :param n: The number to find the largest prime factor of.\n :return: The largest prime factor of n.\n \"\"\"\n factor = 2\n last_factor = 1\n while n > 1:\n if n % factor == 0:\n last_factor = factor\n n //= factor\n while n % factor == 0:\n n //= factor\n factor += 1\n else:\n factor += 1\n return last_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"\n Return the largest prime factor of n. Assume n > 1 and is not a prime.\n \n :param n: An integer greater than 1 and not a prime number.\n :return: The largest prime factor of n.\n \"\"\"\n # Initialize the smallest prime factor\n factor = 2\n last_factor = 1\n \n # Divide n by 2 as many times as possible\n while n % factor == 0:\n last_factor = factor\n n //= factor\n \n # Move to the next potential factors\n factor = 3\n while factor * factor <= n:\n if n % factor == 0:\n last_factor = factor\n n //= factor\n else:\n factor += 2\n \n # If n is not 1 by now, it must be a prime number greater than the last factor found\n if n > 1:\n last_factor = n\n \n return last_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"\n Return the largest prime factor of n. Assume n > 1 and is not a prime.\n \n :param n: An integer greater than 1 and not a prime.\n :return: The largest prime factor of n.\n \"\"\"\n factor = 2\n last_factor = 1\n while n > 1:\n if n % factor == 0:\n last_factor = factor\n n //= factor\n while n % factor == 0:\n n //= factor\n factor += 1\n return last_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"\n Return the largest prime factor of n. Assume n > 1 and is not a prime.\n \n :param n: An integer greater than 1 and not a prime.\n :return: The largest prime factor of n.\n \"\"\"\n # Initialize the smallest prime factor\n factor = 2\n last_factor = 1\n while n > 1:\n if n % factor == 0:\n last_factor = factor\n n //= factor\n else:\n factor += 1\n if factor * factor > n:\n if n > 1:\n last_factor = n\n break\n return last_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n factor = 2\n last_factor = 1\n while n > 1:\n if n % factor == 0:\n last_factor = factor\n n //= factor\n while n % factor == 0:\n n //= factor\n factor += 1\n return last_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"\n Return the largest prime factor of n. Assume n > 1 and is not a prime.\n \n :param n: An integer greater than 1 and not a prime.\n :return: The largest prime factor of n.\n \"\"\"\n factor = 2\n last_factor = 1\n while n > 1:\n if n % factor == 0:\n last_factor = factor\n n //= factor\n while n % factor == 0:\n n //= factor\n factor += 1\n return last_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"\n Return the largest prime factor of n. Assume n > 1 and is not a prime.\n \n :param n: An integer greater than 1 and not a prime.\n :return: The largest prime factor of n.\n \"\"\"\n # Initialize the smallest prime factor\n factor = 2\n last_factor = 1\n while factor * factor <= n:\n if n % factor == 0:\n last_factor = factor\n n //= factor\n else:\n factor += 1\n if n > 1:\n last_factor = n\n return last_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"\n Return the largest prime factor of n. Assume n > 1 and is not a prime.\n \n :param n: An integer greater than 1 and not a prime.\n :return: The largest prime factor of n.\n \"\"\"\n factor = 2\n last_factor = 1\n while n > 1:\n if n % factor == 0:\n last_factor = factor\n n //= factor\n while n % factor == 0:\n n //= factor\n factor += 1\n return last_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"\n Return the largest prime factor of n. Assume n > 1 and is not a prime.\n \n :param n: An integer greater than 1 and not a prime.\n :return: The largest prime factor of n.\n \"\"\"\n factor = 2\n last_factor = 1\n while n > 1:\n if n % factor == 0:\n last_factor = factor\n n //= factor\n while n % factor == 0:\n n //= factor\n factor = 2\n else:\n factor += 1\n return last_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"\n Return the largest prime factor of n. Assume n > 1 and is not a prime.\n \n :param n: An integer greater than 1 and not a prime.\n :return: The largest prime factor of n.\n \"\"\"\n factor = 2\n last_factor = 1\n while n > 1:\n if n % factor == 0:\n last_factor = factor\n n //= factor\n while n % factor == 0:\n n //= factor\n factor += 1\n else:\n factor += 1\n return last_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"\n Return the largest prime factor of n. Assume n > 1 and is not a prime.\n \n :param n: An integer greater than 1 and not a prime.\n :return: The largest prime factor of n.\n \"\"\"\n factor = 2\n last_factor = 1\n while n > 1:\n if n % factor == 0:\n last_factor = factor\n n //= factor\n else:\n factor += 1\n return last_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"\n Return the largest prime factor of n. Assume n > 1 and is not a prime.\n \n :param n: An integer greater than 1 and not a prime.\n :return: The largest prime factor of n.\n \"\"\"\n factor = 2\n last_factor = 1\n while n > 1:\n if n % factor == 0:\n last_factor = factor\n n //= factor\n while n % factor == 0:\n n //= factor\n factor += 1\n return last_factor", "matching_cluster_idx": 8}]}, "HumanEval/64": {"dps": 92.20779220779221, "dps_norm": 62.5, "pass@1": 98.0, "profiled": [{"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = \"aeiou\"\n count = 0\n s = s.lower() # Convert to lowercase to handle uppercase letters\n\n for char in s:\n if char in vowels:\n count += 1\n\n # Check if the last character is 'y'\n if s.endswith('y'):\n count += 1\n\n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n # Convert the string to lowercase to simplify the checks\n s = s.lower()\n # Define the vowels\n vowels = \"aeiou\"\n count = 0\n \n # Count the vowels in the string\n for char in s:\n if char in vowels:\n count += 1\n \n # Check if the last character is 'y' and add it to the count if it is\n if s.endswith('y'):\n count += 1\n \n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n # Convert the string to lowercase to simplify the comparison\n s = s.lower()\n # Define the vowels\n vowels = \"aeiou\"\n # Initialize the count of vowels\n count = 0\n # Iterate over the characters in the string\n for char in s:\n if char in vowels:\n count += 1\n # Check if the last character is 'y' and add to the count if true\n if s.endswith('y'):\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n # Convert the string to lowercase to handle both uppercase and lowercase inputs\n s = s.lower()\n # Define the set of vowels\n vowels = set('aeiou')\n # Initialize the count of vowels\n count = 0\n\n # Count the vowels in the string\n for char in s:\n if char in vowels:\n count += 1\n\n # Check if the last character is 'y' and add to count if true\n if s.endswith('y'):\n count += 1\n\n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = \"aeiouAEIOU\"\n count = 0\n for char in s:\n if char in vowels:\n count += 1\n if s and s[-1] in \"yY\":\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = \"aeiou\"\n count = 0\n s = s.lower() # Convert to lowercase to simplify checks\n\n # Count the vowels in the string\n for char in s:\n if char in vowels:\n count += 1\n\n # Check if the last character is 'y'\n if s.endswith('y'):\n count += 1\n\n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n # Convert the string to lowercase to make the function case-insensitive\n s = s.lower()\n \n # Define the vowels and initialize the count\n vowels = \"aeiou\"\n count = 0\n \n # Count the vowels in the string\n for char in s:\n if char in vowels:\n count += 1\n \n # Check if the last character is 'y' and add to the count if true\n if s.endswith('y'):\n count += 1\n \n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n # Convert the string to lowercase to handle both uppercase and lowercase letters\n s = s.lower()\n # Define the vowels and a variable to count them\n vowels = 'aeiou'\n count = 0\n \n # Count the vowels in the string\n for char in s:\n if char in vowels:\n count += 1\n \n # Check if 'y' is at the end of the string and add to the count if true\n if s.endswith('y'):\n count += 1\n \n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = \"aeiouAEIOU\"\n count = sum(1 for char in s if char in vowels)\n \n # Check if the last character is 'y' or 'Y'\n if s and s[-1] in \"yY\":\n count += 1\n \n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = \"aeiou\"\n count = 0\n s_lower = s.lower()\n\n for char in s_lower:\n if char in vowels:\n count += 1\n\n if s_lower.endswith('y'):\n count += 1\n\n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = \"aeiou\"\n count = 0\n s = s.lower() # Convert the string to lowercase to simplify checks\n\n # Count the vowels in the string\n for char in s:\n if char in vowels:\n count += 1\n\n # Check if the last character is 'y'\n if s.endswith('y'):\n count += 1\n\n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n # Convert the string to lowercase to handle both uppercase and lowercase letters\n s = s.lower()\n # Define the vowels and a variable to count them\n vowels = 'aeiou'\n count = 0\n \n # Count the vowels in the string\n for char in s:\n if char in vowels:\n count += 1\n \n # Check if the last character is 'y' and add to count if it is\n if s.endswith('y'):\n count += 1\n \n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = \"aeiouAEIOU\"\n count = 0\n for char in s:\n if char in vowels:\n count += 1\n if s and s[-1] in \"yY\":\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = \"aeiouAEIOU\"\n count = 0\n for char in s:\n if char in vowels:\n count += 1\n if s and s[-1] in \"yY\":\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = \"aeiouAEIOU\"\n count = 0\n for char in s:\n if char in vowels:\n count += 1\n if s and s[-1] in \"yY\":\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = 'aeiou'\n count = 0\n s = s.lower() # Convert to lowercase to handle both uppercase and lowercase letters\n\n for char in s:\n if char in vowels:\n count += 1\n\n if s and s[-1] == 'y': # Check if the last character is 'y'\n count += 1\n\n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = \"aeiouAEIOU\"\n count = 0\n for char in s:\n if char in vowels:\n count += 1\n if s and s[-1] in \"yY\":\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = 'aeiouAEIOU'\n count = 0\n for char in s:\n if char in vowels:\n count += 1\n if s and s[-1] in 'yY':\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = \"aeiouAEIOU\"\n count = 0\n for char in s:\n if char in vowels:\n count += 1\n if s and s[-1] in \"yY\":\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = \"aeiouAEIOU\"\n count = 0\n for char in s:\n if char in vowels:\n count += 1\n if s and s[-1] in \"yY\":\n count += 1\n return count", "matching_cluster_idx": 4}]}, "HumanEval/74": {"dps": 98.04878048780488, "dps_norm": 88.88888888888889, "pass@1": 100.0, "profiled": [{"solution": "def total_match(lst1, lst2):\n # Calculate the total number of characters in each list\n total_chars_lst1 = sum(len(s) for s in lst1)\n total_chars_lst2 = sum(len(s) for s in lst2)\n \n # Compare the total number of characters and return the appropriate list\n if total_chars_lst1 <= total_chars_lst2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n # Calculate the total number of characters in each list\n total_chars_lst1 = sum(len(s) for s in lst1)\n total_chars_lst2 = sum(len(s) for s in lst2)\n\n # Compare the total number of characters and return the appropriate list\n if total_chars_lst1 <= total_chars_lst2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n # Calculate the total number of characters in each list\n total_chars_lst1 = sum(len(s) for s in lst1)\n total_chars_lst2 = sum(len(s) for s in lst2)\n \n # Compare the total number of characters and return the appropriate list\n if total_chars_lst1 <= total_chars_lst2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n # Calculate the total number of characters in each list\n total_chars_lst1 = sum(len(s) for s in lst1)\n total_chars_lst2 = sum(len(s) for s in lst2)\n \n # Compare the total number of characters and return the appropriate list\n if total_chars_lst1 <= total_chars_lst2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n # Calculate the total number of characters in each list\n total_chars_lst1 = sum(len(s) for s in lst1)\n total_chars_lst2 = sum(len(s) for s in lst2)\n \n # Return the list with fewer total characters, or the first list if they are equal\n if total_chars_lst1 <= total_chars_lst2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n # Calculate the total number of characters in each list\n total_chars1 = sum(len(s) for s in lst1)\n total_chars2 = sum(len(s) for s in lst2)\n \n # Compare the total number of characters and return the appropriate list\n if total_chars1 <= total_chars2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n # Calculate the total number of characters in each list\n total_chars_lst1 = sum(len(s) for s in lst1)\n total_chars_lst2 = sum(len(s) for s in lst2)\n \n # Compare the total number of characters and return the appropriate list\n if total_chars_lst1 <= total_chars_lst2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n # Calculate the total number of characters in each list\n len1 = sum(len(s) for s in lst1)\n len2 = sum(len(s) for s in lst2)\n \n # Return the list with fewer characters, or the first list if they are equal\n return lst1 if len1 <= len2 else lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n # Calculate the total number of characters in each list\n total_chars_lst1 = sum(len(s) for s in lst1)\n total_chars_lst2 = sum(len(s) for s in lst2)\n \n # Compare the total number of characters and return the appropriate list\n if total_chars_lst1 <= total_chars_lst2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n # Calculate the total number of characters in each list\n total_chars_lst1 = sum(len(s) for s in lst1)\n total_chars_lst2 = sum(len(s) for s in lst2)\n \n # Compare the total number of characters and return the appropriate list\n if total_chars_lst1 <= total_chars_lst2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n # Calculate the total number of characters in each list\n total_chars_lst1 = sum(len(s) for s in lst1)\n total_chars_lst2 = sum(len(s) for s in lst2)\n\n # Compare the total number of characters and return the appropriate list\n if total_chars_lst1 <= total_chars_lst2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n # Calculate the total number of characters in each list\n total_chars_lst1 = sum(len(s) for s in lst1)\n total_chars_lst2 = sum(len(s) for s in lst2)\n \n # Compare the total number of characters and return the appropriate list\n if total_chars_lst1 <= total_chars_lst2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n # Calculate the total number of characters in each list\n total_chars_lst1 = sum(len(s) for s in lst1)\n total_chars_lst2 = sum(len(s) for s in lst2)\n \n # Compare the total number of characters and return the appropriate list\n if total_chars_lst1 <= total_chars_lst2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n # Calculate the total number of characters in each list\n total_chars_lst1 = sum(len(s) for s in lst1)\n total_chars_lst2 = sum(len(s) for s in lst2)\n \n # Compare the total number of characters and return the appropriate list\n if total_chars_lst1 <= total_chars_lst2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n # Calculate the total number of characters in each list\n total_chars_lst1 = sum(len(s) for s in lst1)\n total_chars_lst2 = sum(len(s) for s in lst2)\n\n # Compare the total number of characters and return the appropriate list\n if total_chars_lst1 <= total_chars_lst2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n # Calculate the total number of characters in each list\n total_chars_lst1 = sum(len(s) for s in lst1)\n total_chars_lst2 = sum(len(s) for s in lst2)\n \n # Compare the total number of characters and return the appropriate list\n if total_chars_lst1 <= total_chars_lst2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n # Calculate the total number of characters in each list\n total_chars_lst1 = sum(len(s) for s in lst1)\n total_chars_lst2 = sum(len(s) for s in lst2)\n \n # Compare the total number of characters and return the appropriate list\n if total_chars_lst1 <= total_chars_lst2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n # Calculate the total number of characters in each list\n total_chars_lst1 = sum(len(s) for s in lst1)\n total_chars_lst2 = sum(len(s) for s in lst2)\n \n # Compare the total number of characters and return the appropriate list\n if total_chars_lst1 <= total_chars_lst2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n # Calculate the total number of characters in each list\n total_chars_lst1 = sum(len(s) for s in lst1)\n total_chars_lst2 = sum(len(s) for s in lst2)\n \n # Return the list with fewer characters, or the first list if they are equal\n if total_chars_lst1 <= total_chars_lst2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n # Calculate the total number of characters in each list\n total_chars_lst1 = sum(len(s) for s in lst1)\n total_chars_lst2 = sum(len(s) for s in lst2)\n \n # Return the list with fewer total characters, or the first list if they are equal\n if total_chars_lst1 <= total_chars_lst2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}]}, "HumanEval/85": {"dps": 91.01485148514851, "dps_norm": 59.16666666666667, "pass@1": 100.0, "profiled": [{"solution": "def add(lst):\n \"\"\"\n Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2\n \"\"\"\n # Initialize the sum to zero\n result = 0\n \n # Iterate over the list, checking only odd indices\n for i in range(1, len(lst), 2):\n if lst[i] % 2 == 0:\n result += lst[i]\n \n return result", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"\n Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2\n \"\"\"\n # Initialize the sum of even elements at odd indices\n result = 0\n \n # Iterate over the list, considering only odd indices\n for i in range(1, len(lst), 2):\n if lst[i] % 2 == 0:\n result += lst[i]\n \n return result", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"\n Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2\n \"\"\"\n # Initialize the sum to 0\n total = 0\n \n # Iterate through the list, considering only odd indices\n for i in range(1, len(lst), 2):\n # Check if the element at the current odd index is even\n if lst[i] % 2 == 0:\n # Add the even element to the total\n total += lst[i]\n \n return total", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"\n Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2\n \"\"\"\n result = 0\n for i in range(1, len(lst), 2): # Start from index 1 and increment by 2 to check odd indices\n if lst[i] % 2 == 0: # Check if the element at the odd index is even\n result += lst[i]\n return result", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"\n Given a non-empty list of integers lst, add the even elements that are at odd indices.\n \n Examples:\n add([4, 2, 6, 7]) ==> 2\n \"\"\"\n # Initialize the sum of even elements at odd indices\n result = 0\n \n # Iterate through the list with index and value\n for index, value in enumerate(lst):\n # Check if the index is odd and the value is even\n if index % 2 != 0 and value % 2 == 0:\n result += value\n \n return result", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"\n Given a non-empty list of integers lst, add the even elements that are at odd indices.\n \n Examples:\n add([4, 2, 6, 7]) ==> 2\n \"\"\"\n # Initialize the sum of even elements at odd indices\n even_sum = 0\n \n # Iterate over the list with index and value\n for index, value in enumerate(lst):\n # Check if the index is odd and the value is even\n if index % 2 != 0 and value % 2 == 0:\n even_sum += value\n \n return even_sum", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"\n Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n result = 0\n for i in range(1, len(lst), 2): # Start from index 1 and step by 2 to get odd indices\n if lst[i] % 2 == 0: # Check if the element at the odd index is even\n result += lst[i]\n return result", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"\n Given a non-empty list of integers lst. Add the even elements that are at odd indices.\n \n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n # Initialize the sum to 0\n result = 0\n \n # Iterate through the list, checking only odd indices\n for i in range(1, len(lst), 2):\n if lst[i] % 2 == 0:\n result += lst[i]\n \n return result", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"\n Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2\n \"\"\"\n # Initialize the sum to 0\n total = 0\n \n # Iterate through the list with index\n for index, value in enumerate(lst):\n # Check if the index is odd and the value is even\n if index % 2 != 0 and value % 2 == 0:\n # Add the value to the total\n total += value\n \n return total", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"\n Given a non-empty list of integers lst, add the even elements that are at odd indices.\n \n Examples:\n add([4, 2, 6, 7]) ==> 2\n \"\"\"\n # Initialize the sum to 0\n result = 0\n \n # Iterate over the list using enumerate to get both index and value\n for index, value in enumerate(lst):\n # Check if the index is odd and the value is even\n if index % 2 != 0 and value % 2 == 0:\n result += value\n \n return result", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"\n Given a non-empty list of integers lst, add the even elements that are at odd indices.\n \n Examples:\n add([4, 2, 6, 7]) ==> 2\n \"\"\"\n # Initialize the sum to 0\n result = 0\n \n # Iterate over the list, considering only odd indices\n for i in range(1, len(lst), 2):\n # Check if the element at the current index is even\n if lst[i] % 2 == 0:\n # Add the even element to the result\n result += lst[i]\n \n return result", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"\n Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2\n \"\"\"\n # Initialize a variable to store the sum of even elements at odd indices\n result = 0\n\n # Iterate over the list with both index and value using enumerate\n for index, value in enumerate(lst):\n # Check if the index is odd and the value is even\n if index % 2 != 0 and value % 2 == 0:\n # Add the value to the result\n result += value\n\n return result", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"\n Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n # Initialize the sum to zero\n result = 0\n \n # Iterate over the list, considering only odd indices\n for i in range(1, len(lst), 2):\n # Check if the element at the current index is even\n if lst[i] % 2 == 0:\n # Add the even element to the result\n result += lst[i]\n \n return result", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"\n Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2\n \"\"\"\n result = 0\n for i in range(1, len(lst), 2): # Start from index 1 and step by 2 to get odd indices\n if lst[i] % 2 == 0: # Check if the element at the odd index is even\n result += lst[i]\n return result", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"\n Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2\n \"\"\"\n # Initialize the sum of even elements at odd indices\n even_sum = 0\n \n # Iterate through the list, starting from the first odd index (1) and increment by 2\n for i in range(1, len(lst), 2):\n # Check if the element at the current index is even\n if lst[i] % 2 == 0:\n # Add the even element to the sum\n even_sum += lst[i]\n \n return even_sum", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"\n Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n # Initialize the sum to zero\n result = 0\n \n # Iterate over the list with index and value\n for index, value in enumerate(lst):\n # Check if the index is odd and the value is even\n if index % 2 != 0 and value % 2 == 0:\n result += value\n \n return result", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"\n Given a non-empty list of integers lst. add the even elements that are at odd indices.\n \n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n # Initialize the sum to 0\n result = 0\n \n # Iterate over the list, but only consider elements at odd indices\n for i in range(1, len(lst), 2):\n # Check if the element at the current index is even\n if lst[i] % 2 == 0:\n # Add the even element to the result\n result += lst[i]\n \n return result", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"\n Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2\n \"\"\"\n # Initialize the sum to zero\n result = 0\n \n # Iterate over the list with index and value\n for index, value in enumerate(lst):\n # Check if the index is odd and the value is even\n if index % 2 != 0 and value % 2 == 0:\n result += value\n \n return result", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"\n Given a non-empty list of integers lst, add the even elements that are at odd indices.\n \n Examples:\n add([4, 2, 6, 7]) ==> 2\n \"\"\"\n # Initialize the sum to 0\n result = 0\n \n # Iterate through the list with index\n for index, value in enumerate(lst):\n # Check if the index is odd and the value is even\n if index % 2 != 0 and value % 2 == 0:\n result += value\n \n return result", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"\n Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2\n \"\"\"\n # Initialize the sum to 0\n result = 0\n \n # Iterate over the list with index and value\n for index, value in enumerate(lst):\n # Check if the index is odd and the value is even\n if index % 2 != 0 and value % 2 == 0:\n result += value\n \n return result", "matching_cluster_idx": 2}]}, "HumanEval/86": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 16.0, "profiled": [{"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n # Split the string into words\n words = s.split(' ')\n \n # Process each word to sort its characters\n sorted_words = [''.join(sorted(word)) for word in words]\n \n # Join the sorted words back into a string\n return ' '.join(sorted_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n # Split the string into words\n words = s.split(' ')\n \n # Process each word to sort its characters\n sorted_words = [''.join(sorted(word)) for word in words]\n \n # Join the sorted words back into a single string\n return ' '.join(sorted_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n # Split the string into words\n words = s.split(' ')\n \n # Process each word to sort its characters\n sorted_words = [''.join(sorted(word)) for word in words]\n \n # Join the sorted words back into a single string with spaces\n result = ' '.join(sorted_words)\n \n return result", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n # Split the string into words\n words = s.split(' ')\n \n # Process each word\n ordered_words = []\n for word in words:\n # Sort the characters in the word\n sorted_word = ''.join(sorted(word))\n ordered_words.append(sorted_word)\n \n # Join the ordered words back into a string\n result = ' '.join(ordered_words)\n \n return result", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n # Split the string into words\n words = s.split(' ')\n \n # Process each word to sort its characters\n sorted_words = [''.join(sorted(word)) for word in words]\n \n # Join the sorted words back into a single string\n result = ' '.join(sorted_words)\n \n return result", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n # Split the string into words\n words = s.split(' ')\n \n # Sort each word's characters and join them back together\n sorted_words = [''.join(sorted(word)) for word in words]\n \n # Join the sorted words back into a string with spaces\n return ' '.join(sorted_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n # Split the string into words\n words = s.split(' ')\n \n # Process each word to sort its characters\n sorted_words = [''.join(sorted(word)) for word in words]\n \n # Join the processed words back into a string\n result = ' '.join(sorted_words)\n \n return result", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n # Split the string into words\n words = s.split(' ')\n \n # Process each word to sort its characters\n ordered_words = [''.join(sorted(word)) for word in words]\n \n # Join the processed words back into a single string\n result = ' '.join(ordered_words)\n \n return result", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n # Split the string into words while preserving the original spaces\n words = s.split(' ')\n # Sort the characters of each word\n sorted_words = [''.join(sorted(word)) for word in words]\n # Join the sorted words back together with spaces\n return ' '.join(sorted_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n # Split the string into words while preserving spaces\n words = s.split(' ')\n # Sort each word's characters and rejoin them\n sorted_words = [''.join(sorted(word)) for word in words]\n # Join the sorted words back into a string with spaces\n return ' '.join(sorted_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n # Split the string into words\n words = s.split(' ')\n \n # Sort the characters in each word and join them back\n sorted_words = [''.join(sorted(word)) for word in words]\n \n # Join the sorted words back into a string with spaces\n result = ' '.join(sorted_words)\n \n return result", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n # Split the string into words\n words = s.split(' ')\n \n # Sort the characters in each word and join them back\n sorted_words = [''.join(sorted(word)) for word in words]\n \n # Join the sorted words back into a string with spaces\n result = ' '.join(sorted_words)\n \n return result", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n # Split the string into words\n words = s.split(' ')\n \n # Process each word to sort its characters\n ordered_words = []\n for word in words:\n # Sort the characters in the word\n sorted_word = ''.join(sorted(word))\n ordered_words.append(sorted_word)\n \n # Join the ordered words back into a string, preserving the original spaces\n result = ' '.join(ordered_words)\n return result", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n # Split the string into words while preserving spaces\n words = s.split(' ')\n \n # Sort the characters in each word and join them back\n sorted_words = [''.join(sorted(word)) for word in words]\n \n # Join the sorted words back into a string\n result = ' '.join(sorted_words)\n \n return result", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n # Split the string into words\n words = s.split(' ')\n \n # Process each word to sort its characters\n sorted_words = [''.join(sorted(word)) for word in words]\n \n # Join the processed words back into a string\n return ' '.join(sorted_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n # Split the string into words and spaces\n words = s.split(' ')\n \n # Process each word to sort its characters\n ordered_words = [''.join(sorted(word)) for word in words]\n \n # Join the processed words back together\n return ' '.join(ordered_words)", "matching_cluster_idx": 4}]}, "HumanEval/87": {"dps": 93.94812680115274, "dps_norm": 57.142857142857146, "pass@1": 97.0, "profiled": [{"solution": "def get_row(lst, x):\n \"\"\"\n Finds the occurrences of an integer x in a 2D list and returns their coordinates.\n The coordinates are sorted by rows in ascending order and by columns in descending order within each row.\n \"\"\"\n # Initialize an empty list to store the coordinates\n coordinates = []\n \n # Iterate over the list with both index and row\n for row_idx, row in enumerate(lst):\n # Find the occurrences of x in the current row and store their column indices\n col_indices = [col_idx for col_idx, value in enumerate(row) if value == x]\n # Sort the column indices in descending order\n col_indices.sort(reverse=True)\n # Add the coordinates to the list\n coordinates.extend([(row_idx, col_idx) for col_idx in col_indices])\n \n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n Finds all occurrences of x in a 2D list and returns a list of tuples\n representing their coordinates. The coordinates are sorted by rows in\n ascending order and by columns in descending order within each row.\n \"\"\"\n # Initialize an empty list to store the coordinates\n coordinates = []\n \n # Iterate through each row and its index\n for row_idx, row in enumerate(lst):\n # Find the occurrences of x in the current row and store their indices\n col_indices = [col_idx for col_idx, value in enumerate(row) if value == x]\n # Sort the column indices in descending order\n col_indices.sort(reverse=True)\n # Append the (row, column) tuples to the coordinates list\n for col_idx in col_indices:\n coordinates.append((row_idx, col_idx))\n \n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n Finds the integer x in the given 2D list and returns a list of tuples representing\n the coordinates (row, column) of each occurrence of x. The coordinates are sorted\n by rows in ascending order and by columns in descending order within each row.\n \"\"\"\n # Initialize an empty list to store the coordinates\n coordinates = []\n\n # Iterate through each row in the list\n for row_idx, row in enumerate(lst):\n # Iterate through each element in the row\n for col_idx, value in enumerate(row):\n # If the value matches x, add the coordinate to the list\n if value == x:\n coordinates.append((row_idx, col_idx))\n\n # Sort the coordinates by row in ascending order, and by column in descending order within each row\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n\n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n Finds the integer x in a 2D list (matrix) where each row can have a different number of columns.\n Returns a list of tuples representing the coordinates (row, column) of x, sorted by row in ascending\n order and by column in descending order within each row.\n \n :param lst: List of lists representing the 2D data structure.\n :param x: The integer to find in the 2D list.\n :return: List of tuples with the coordinates of x.\n \"\"\"\n coordinates = []\n for row_idx, row in enumerate(lst):\n for col_idx, value in enumerate(row):\n if value == x:\n coordinates.append((row_idx, col_idx))\n \n # Sort by row in ascending order and then by column in descending order within each row\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n \n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n Finds all occurrences of x in a 2D list and returns a list of tuples\n with coordinates sorted by row in ascending order and columns in descending order.\n \"\"\"\n coordinates = []\n for i, row in enumerate(lst):\n for j, value in enumerate(row):\n if value == x:\n coordinates.append((i, j))\n # Sort by row in ascending order, then by column in descending order within each row\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n Find occurrences of integer x in the 2D list lst and return a list of tuples representing the coordinates.\n Each tuple is (row, column), with both row and column indices starting from 0.\n The result is sorted by rows in ascending order, and by columns in descending order within each row.\n \n :param lst: List of lists representing the 2D data.\n :param x: Integer to find in the 2D list.\n :return: List of tuples (row, column) for each occurrence of x.\n \"\"\"\n result = []\n for i, row in enumerate(lst):\n for j, value in enumerate(row):\n if value == x:\n result.append((i, j))\n \n # Sort by row in ascending order, and by column in descending order within each row\n result.sort(key=lambda coord: (coord[0], -coord[1]))\n \n return result", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n Finds the integer x in the nested list lst and returns a list of tuples representing\n the coordinates (row, column) of x. The coordinates are sorted by rows in ascending order,\n and within each row, by columns in descending order.\n \"\"\"\n # Initialize an empty list to store the coordinates\n coordinates = []\n \n # Iterate over the list with enumerate to get both index and row\n for row_index, row in enumerate(lst):\n # For each row, find the columns where the value equals x\n for col_index in range(len(row)):\n if row[col_index] == x:\n # Append the (row, column) tuple to the coordinates list\n coordinates.append((row_index, col_index))\n \n # Sort the coordinates first by row in ascending order, then by column in descending order\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n \n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n Finds the integer x in a 2D list (lst) and returns the coordinates\n of all occurrences of x, sorted by row in ascending order and\n by column in descending order within each row.\n \n Parameters:\n lst (list of list of int): The 2D list to search.\n x (int): The integer to find in the list.\n \n Returns:\n list of tuples: A list of coordinates (row, column) where x is found.\n \"\"\"\n result = []\n for row_idx, row in enumerate(lst):\n for col_idx, value in enumerate(row):\n if value == x:\n result.append((row_idx, col_idx))\n \n # Sort by row in ascending order, then by column in descending order\n result.sort(key=lambda coord: (coord[0], -coord[1]))\n \n return result", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n Finds all occurrences of an integer x in a 2D list and returns a list of tuples\n representing the coordinates (row, column) of each occurrence. The coordinates\n are sorted first by row in ascending order, and then by column in descending order\n within each row.\n \n :param lst: List of lists representing the 2D data.\n :param x: The integer to find in the 2D list.\n :return: A list of tuples (row, column) for each occurrence of x.\n \"\"\"\n coordinates = []\n for row_idx, row in enumerate(lst):\n for col_idx, value in enumerate(row):\n if value == x:\n coordinates.append((row_idx, col_idx))\n \n # Sort by row in ascending order, and then by column in descending order within each row\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n \n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n Finds the integer x in a 2D list and returns the coordinates of x in a list of tuples.\n Each tuple represents the (row, column) of the found element, with sorting as specified.\n \n :param lst: List of lists representing the 2D data.\n :param x: Integer to find in the 2D list.\n :return: List of tuples with coordinates of x, sorted by rows (ascending) and columns (descending).\n \"\"\"\n # Find all occurrences of x and store their coordinates\n coordinates = []\n for row_idx, row in enumerate(lst):\n for col_idx, value in enumerate(row):\n if value == x:\n coordinates.append((row_idx, col_idx))\n \n # Sort the coordinates by row in ascending order, and by column in descending order within each row\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n \n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n Finds all occurrences of an integer x in a 2D list and returns their coordinates.\n Coordinates are sorted by rows in ascending order and by columns in descending order within the same row.\n \n :param lst: List of lists representing the 2D data.\n :param x: The integer to find in the 2D list.\n :return: A list of tuples, where each tuple is a coordinate (row, column).\n \"\"\"\n coordinates = []\n for row_idx, row in enumerate(lst):\n for col_idx, value in enumerate(row):\n if value == x:\n coordinates.append((row_idx, col_idx))\n \n # Sort by row in ascending order, then by column in descending order within the same row\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n \n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \"\"\"\n # Find all occurrences of x and store their coordinates\n coordinates = []\n for row_idx, row in enumerate(lst):\n for col_idx, value in enumerate(row):\n if value == x:\n coordinates.append((row_idx, col_idx))\n \n # Sort the coordinates by row in ascending order, and by column in descending order within the same row\n sorted_coordinates = sorted(coordinates, key=lambda coord: (coord[0], -coord[1]))\n \n return sorted_coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n # Initialize an empty list to store the coordinates\n coordinates = []\n \n # Iterate through the list to find the occurrences of x\n for row_index, row in enumerate(lst):\n # Find all occurrences of x in the current row\n for col_index in reversed(range(len(row))):\n if row[col_index] == x:\n coordinates.append((row_index, col_index))\n \n # Sort the coordinates by row in ascending order and by column in descending order\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n \n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n Finds the integer x in the 2D list lst and returns a list of tuples representing\n the coordinates (row, column) of x, sorted by row in ascending order and by column\n in descending order within each row.\n \"\"\"\n # Find all occurrences of x and store their coordinates\n coordinates = []\n for row_idx, row in enumerate(lst):\n for col_idx, value in enumerate(row):\n if value == x:\n coordinates.append((row_idx, col_idx))\n \n # Sort coordinates by row in ascending order and by column in descending order within each row\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n \n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n Finds the integer x in the 2D list and returns a list of tuples representing the coordinates.\n The coordinates are sorted by row in ascending order, and by column in descending order within each row.\n \"\"\"\n # Initialize an empty list to store the coordinates\n coordinates = []\n \n # Iterate over each row in the list\n for row_idx, row in enumerate(lst):\n # Find the columns where the value is x and store the coordinates\n for col_idx, value in enumerate(row):\n if value == x:\n coordinates.append((row_idx, col_idx))\n \n # Sort the coordinates by row in ascending order, and by column in descending order within each row\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n \n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n Finds the integer x in a 2D list (lst) and returns a list of tuples representing the coordinates of x.\n The coordinates are sorted by rows in ascending order, and by columns in descending order within the same row.\n \n :param lst: List of lists, representing the 2D data structure.\n :param x: Integer to find in the 2D list.\n :return: List of tuples, where each tuple is (row, column) of the found integer.\n \"\"\"\n # Initialize an empty list to store the coordinates\n coordinates = []\n \n # Iterate over the rows and columns of the 2D list\n for row_idx, row in enumerate(lst):\n for col_idx, value in enumerate(row):\n if value == x:\n # Append the coordinate as a tuple (row, column)\n coordinates.append((row_idx, col_idx))\n \n # Sort the coordinates by row in ascending order, and by column in descending order within the same row\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n \n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n Finds occurrences of an integer x in a 2D list and returns a list of tuples\n representing the coordinates of x, sorted by row in ascending order and by\n column in descending order within each row.\n \n :param lst: 2D list of integers\n :param x: Integer to find in the list\n :return: List of tuples (row, column) of x's positions\n \"\"\"\n coordinates = []\n for row_idx, row in enumerate(lst):\n # Find all occurrences of x in the current row and append their coordinates\n for col_idx in range(len(row) - 1, -1, -1):\n if row[col_idx] == x:\n coordinates.append((row_idx, col_idx))\n \n # Sort the coordinates by row in ascending order and by column in descending order\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n Finds occurrences of integer x in the 2D list lst and returns a list of tuples\n representing the coordinates (row, column) of each occurrence. The coordinates\n are sorted by rows in ascending order and by columns in descending order within\n each row.\n \n :param lst: List of lists, where each inner list represents a row.\n :param x: Integer to search for in the 2D list.\n :return: List of tuples (row, column) indicating the positions of x.\n \"\"\"\n # Initialize an empty list to store the coordinates\n coordinates = []\n \n # Iterate through each row and its index\n for row_idx, row in enumerate(lst):\n # Find all occurrences of x in the current row and store their indices\n col_indices = [col_idx for col_idx, value in enumerate(row) if value == x]\n # Add the coordinates (row_idx, col_idx) to the coordinates list\n # Sort the column indices in descending order before adding\n for col_idx in sorted(col_indices, reverse=True):\n coordinates.append((row_idx, col_idx))\n \n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n # Initialize an empty list to store the coordinates\n coordinates = []\n \n # Iterate over the list to find occurrences of x\n for row_idx, row in enumerate(lst):\n # Find all columns where x appears in the current row\n col_indices = [col_idx for col_idx, value in enumerate(row) if value == x]\n # Add the coordinates to the list, sorting columns in descending order\n coordinates.extend((row_idx, col_idx) for col_idx in sorted(col_indices, reverse=True))\n \n # Sort the coordinates by rows in ascending order\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n \n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n Finds all occurrences of x in the 2D list lst and returns a list of tuples\n where each tuple represents the coordinates (row, column) of the occurrences.\n The rows are sorted in ascending order, and the columns in each row are sorted\n in descending order.\n \"\"\"\n # Initialize an empty list to store the coordinates\n coordinates = []\n \n # Iterate over the list to find all occurrences of x\n for row_idx, row in enumerate(lst):\n for col_idx, value in enumerate(row):\n if value == x:\n # Append the coordinates as a tuple\n coordinates.append((row_idx, col_idx))\n \n # Sort the coordinates by row in ascending order\n # and by column in descending order within the same row\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n \n return coordinates", "matching_cluster_idx": 3}]}, "HumanEval/89": {"dps": 97.07474226804125, "dps_norm": 46.42857142857143, "pass@1": 100.0, "profiled": [{"solution": "def encrypt(s):\n \"\"\"\n Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places (i.e., shift by 4 places).\n \"\"\"\n # Define the alphabet and the shifted alphabet\n alphabet = 'abcdefghijklmnopqrstuvwxyz'\n shift = 4\n shifted_alphabet = alphabet[shift:] + alphabet[:shift]\n \n # Create a translation table\n translation_table = str.maketrans(alphabet, shifted_alphabet)\n \n # Encrypt the string using the translation table\n encrypted_string = s.translate(translation_table)\n \n return encrypted_string", "matching_cluster_idx": 6}, {"solution": "def encrypt(s):\n \"\"\"\n Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places (i.e., 4 places).\n \"\"\"\n # Define the alphabet and the shift amount\n alphabet = 'abcdefghijklmnopqrstuvwxyz'\n shift = 4\n encrypted = ''\n\n # Loop through each character in the input string\n for char in s:\n if char in alphabet:\n # Find the current position of the character in the alphabet\n index = alphabet.index(char)\n # Calculate the new position with the shift\n new_index = (index + shift) % 26\n # Append the new character to the encrypted string\n encrypted += alphabet[new_index]\n else:\n # If the character is not in the alphabet, leave it unchanged\n encrypted += char\n\n return encrypted", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"\n Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places (i.e., 4 places).\n \"\"\"\n # Define the alphabet and the shift amount\n alphabet = 'abcdefghijklmnopqrstuvwxyz'\n shift = 4\n encrypted = ''\n \n # Loop through each character in the input string\n for char in s:\n if char in alphabet:\n # Find the index of the character in the alphabet\n index = alphabet.index(char)\n # Calculate the new index after the shift\n new_index = (index + shift) % 26\n # Append the new character to the encrypted string\n encrypted += alphabet[new_index]\n else:\n # If the character is not in the alphabet, leave it unchanged\n encrypted += char\n \n return encrypted", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"\n Encrypts a given string by rotating the alphabet such that each letter\n is shifted down by four places (2 * 2).\n \n :param s: The input string to be encrypted.\n :return: The encrypted string.\n \"\"\"\n # Define the alphabet and the encrypted alphabet\n alphabet = 'abcdefghijklmnopqrstuvwxyz'\n shift = 4\n encrypted_alphabet = alphabet[shift:] + alphabet[:shift]\n \n # Create a translation table\n translation_table = str.maketrans(alphabet, encrypted_alphabet)\n \n # Translate the input string using the translation table\n encrypted_string = s.translate(translation_table)\n \n return encrypted_string", "matching_cluster_idx": 5}, {"solution": "def encrypt(s):\n \"\"\"\n Encrypts a given string by shifting each letter down by 2 * 2 = 4 places in the alphabet.\n \n Parameters:\n s (str): The input string to be encrypted.\n \n Returns:\n str: The encrypted string.\n \"\"\"\n # Define the alphabet and the shift amount\n alphabet = 'abcdefghijklmnopqrstuvwxyz'\n shift = 4\n \n # Initialize the encrypted string\n encrypted_string = ''\n \n # Loop through each character in the input string\n for char in s:\n if char in alphabet:\n # Find the new position with the shift, wrapping around the alphabet\n new_index = (alphabet.index(char) + shift) % 26\n encrypted_string += alphabet[new_index]\n else:\n # If the character is not in the alphabet, leave it as is\n encrypted_string += char\n \n return encrypted_string", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"\n Encrypts a given string by rotating the alphabet such that each letter\n shifts down by 4 places (2 * 2).\n \n Parameters:\n s (str): The string to be encrypted.\n \n Returns:\n str: The encrypted string.\n \"\"\"\n # Define the alphabet and the encrypted alphabet with a shift of 4\n alphabet = 'abcdefghijklmnopqrstuvwxyz'\n shifted_alphabet = alphabet[4:] + alphabet[:4]\n \n # Create a translation table for the encryption\n translation_table = str.maketrans(alphabet, shifted_alphabet)\n \n # Encrypt the string using the translation table\n encrypted_string = s.translate(translation_table)\n \n return encrypted_string", "matching_cluster_idx": 5}, {"solution": "def encrypt(s):\n \"\"\"\n Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places (i.e., shift by 4 places).\n \"\"\"\n # Define the alphabet and the shifted alphabet\n alphabet = 'abcdefghijklmnopqrstuvwxyz'\n shift = 4\n shifted_alphabet = alphabet[shift:] + alphabet[:shift]\n \n # Create a translation table\n translation_table = str.maketrans(alphabet, shifted_alphabet)\n \n # Translate the input string using the translation table\n encrypted_string = s.translate(translation_table)\n \n return encrypted_string", "matching_cluster_idx": 5}, {"solution": "def encrypt(s):\n \"\"\"\n Encrypts a string by shifting each letter down by 2 * 2 = 4 places in the alphabet.\n \n Args:\n s (str): The input string to be encrypted.\n \n Returns:\n str: The encrypted string.\n \"\"\"\n # Define the alphabet and the shift amount\n alphabet = 'abcdefghijklmnopqrstuvwxyz'\n shift = 4\n \n # Create a dictionary to map each letter to its shifted counterpart\n shift_map = {char: alphabet[(i + shift) % 26] for i, char in enumerate(alphabet)}\n \n # Encrypt the input string\n encrypted = ''.join(shift_map.get(char, char) for char in s)\n \n return encrypted", "matching_cluster_idx": 2}, {"solution": "def encrypt(s):\n \"\"\"\n Encrypts a string by shifting each letter down the alphabet by 2*2 (4 places).\n \n Parameters:\n s (str): The input string to encrypt.\n \n Returns:\n str: The encrypted string.\n \"\"\"\n # Define the alphabet and the shift amount\n alphabet = 'abcdefghijklmnopqrstuvwxyz'\n shift = 4\n \n # Initialize the result string\n encrypted = ''\n \n # Loop through each character in the input string\n for char in s:\n # Check if the character is a lowercase letter\n if char in alphabet:\n # Find the new position by adding the shift and wrapping around the alphabet\n new_index = (alphabet.index(char) + shift) % 26\n encrypted += alphabet[new_index]\n else:\n # If the character is not a letter, keep it as is\n encrypted += char\n \n return encrypted", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"\n Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n \"\"\"\n # Define the alphabet and the shifted alphabet\n alphabet = 'abcdefghijklmnopqrstuvwxyz'\n shift = 2 * 2 # The shift is 4 places\n shifted_alphabet = alphabet[shift:] + alphabet[:shift]\n \n # Encrypt the string by mapping each character to its shifted counterpart\n encrypted = ''.join([shifted_alphabet[alphabet.index(c)] if c in alphabet else c for c in s])\n \n return encrypted", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"\n Encrypts a given string by shifting each letter down by 4 places in the alphabet.\n Wraps around if the shift goes beyond 'z'.\n \n :param s: The string to be encrypted.\n :return: The encrypted string.\n \"\"\"\n # Define the alphabet and the shift amount\n alphabet = 'abcdefghijklmnopqrstuvwxyz'\n shift = 2 * 2 # Shift by 4 places\n \n # Create a shifted version of the alphabet\n shifted_alphabet = alphabet[shift:] + alphabet[:shift]\n \n # Create a dictionary for the mapping from original to shifted characters\n encryption_dict = {char: shifted_char for char, shifted_char in zip(alphabet, shifted_alphabet)}\n \n # Encrypt the input string\n encrypted_string = ''.join(encryption_dict.get(char, char) for char in s)\n \n return encrypted_string", "matching_cluster_idx": 2}, {"solution": "def encrypt(s):\n \"\"\"\n Encrypts a given string by shifting each letter down by 4 places in the alphabet.\n \n :param s: The string to be encrypted.\n :return: The encrypted string.\n \"\"\"\n # Define the alphabet\n alphabet = 'abcdefghijklmnopqrstuvwxyz'\n encrypted_string = ''\n \n for char in s:\n if char in alphabet:\n # Find the index of the character in the alphabet\n index = alphabet.index(char)\n # Shift the index by 4 places and wrap around using modulo\n new_index = (index + 4) % 26\n # Append the new character to the encrypted string\n encrypted_string += alphabet[new_index]\n else:\n # If the character is not in the alphabet, keep it as is\n encrypted_string += char\n \n return encrypted_string", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"\n Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places (i.e., 4 places).\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n # Define the alphabet and the shift value\n alphabet = 'abcdefghijklmnopqrstuvwxyz'\n shift = 4\n encrypted = ''\n\n # Iterate through each character in the input string\n for char in s:\n if char in alphabet:\n # Find the current position of the character in the alphabet\n current_index = alphabet.index(char)\n # Calculate the new position with the shift, wrapping around if necessary\n new_index = (current_index + shift) % 26\n # Append the shifted character to the encrypted string\n encrypted += alphabet[new_index]\n else:\n # If the character is not in the alphabet, leave it unchanged\n encrypted += char\n\n return encrypted", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"\n Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places (i.e., 4 places).\n \"\"\"\n # Define the alphabet and the rotation value\n alphabet = 'abcdefghijklmnopqrstuvwxyz'\n rotation = 2 * 2 # 4 places\n\n # Initialize the encrypted string\n encrypted = ''\n\n # Iterate over each character in the input string\n for char in s:\n if char in alphabet:\n # Find the new position of the character after rotation\n new_pos = (alphabet.index(char) + rotation) % 26\n encrypted += alphabet[new_pos]\n else:\n # If the character is not in the alphabet, leave it unchanged\n encrypted += char\n\n return encrypted", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"\n Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n \"\"\"\n # Define the alphabet and the shift value\n alphabet = 'abcdefghijklmnopqrstuvwxyz'\n shift = 2 * 2 # Shift by 4 places\n\n # Initialize the result string\n result = ''\n\n # Iterate over each character in the input string\n for char in s:\n if char in alphabet:\n # Find the new position after the shift\n new_index = (alphabet.index(char) + shift) % 26\n # Append the shifted character to the result\n result += alphabet[new_index]\n else:\n # If the character is not in the alphabet, append it as is\n result += char\n\n return result", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"\n Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n # Define the rotation factor\n rotation = 2 * 2\n \n # Define the alphabet and the rotated alphabet\n alphabet = 'abcdefghijklmnopqrstuvwxyz'\n rotated_alphabet = alphabet[rotation:] + alphabet[:rotation]\n \n # Create a translation table\n translation_table = str.maketrans(alphabet, rotated_alphabet)\n \n # Encrypt the string\n encrypted_string = s.translate(translation_table)\n \n return encrypted_string", "matching_cluster_idx": 5}, {"solution": "def encrypt(s):\n \"\"\"\n Encrypts the given string by shifting each letter down by 4 places in the alphabet.\n \n :param s: The input string to be encrypted.\n :return: The encrypted string.\n \"\"\"\n # Define the alphabet\n alphabet = 'abcdefghijklmnopqrstuvwxyz'\n # Create a dictionary to map each letter to its encrypted counterpart\n shift = 4 # 2 * 2 as specified\n shifted_alphabet = alphabet[shift:] + alphabet[:shift]\n encryption_dict = {char: shifted_char for char, shifted_char in zip(alphabet, shifted_alphabet)}\n \n # Encrypt the input string\n encrypted = ''.join(encryption_dict.get(char, char) for char in s)\n \n return encrypted", "matching_cluster_idx": 2}, {"solution": "def encrypt(s):\n \"\"\"\n Encrypts a string by rotating the alphabet such that each letter\n is shifted down by 4 places (2 multiplied by 2).\n \n Args:\n s (str): The input string to be encrypted.\n \n Returns:\n str: The encrypted string.\n \"\"\"\n # Define the alphabet\n alphabet = 'abcdefghijklmnopqrstuvwxyz'\n # Create a dictionary for the encryption mapping\n encryption_dict = {char: alphabet[(i + 4) % 26] for i, char in enumerate(alphabet)}\n \n # Encrypt the string\n encrypted = ''.join(encryption_dict.get(char, char) for char in s)\n \n return encrypted", "matching_cluster_idx": 2}, {"solution": "def encrypt(s):\n \"\"\"\n Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places (i.e., 4 places).\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n # Define the alphabet and the rotation amount\n alphabet = 'abcdefghijklmnopqrstuvwxyz'\n rotation = 4 # 2 * 2\n\n # Initialize the encrypted string\n encrypted = ''\n\n # Iterate through each character in the input string\n for char in s:\n if char in alphabet:\n # Find the index of the character in the alphabet\n index = alphabet.index(char)\n # Calculate the new index after rotation\n new_index = (index + rotation) % 26\n # Append the new character to the encrypted string\n encrypted += alphabet[new_index]\n else:\n # If the character is not in the alphabet, leave it unchanged\n encrypted += char\n\n return encrypted", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"\n Encrypts a given string by shifting each letter down by four places in the alphabet.\n \n Args:\n s (str): The input string to be encrypted.\n \n Returns:\n str: The encrypted string.\n \"\"\"\n result = []\n for char in s:\n if char.isalpha():\n shift = 4 # 2 * 2 as specified\n if char.islower():\n start = ord('a')\n new_char = chr((ord(char) - start + shift) % 26 + start)\n else:\n start = ord('A')\n new_char = chr((ord(char) - start + shift) % 26 + start)\n result.append(new_char)\n else:\n result.append(char)\n return ''.join(result)", "matching_cluster_idx": 1}]}, "HumanEval/90": {"dps": 58.50194552529183, "dps_norm": 51.666666666666664, "pass@1": 99.0, "profiled": [{"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n Examples:\n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n # If the list has less than 2 elements, return None\n if len(lst) < 2:\n return None\n \n # Initialize the smallest and second smallest with None\n smallest = second_smallest = None\n \n for num in lst:\n if smallest is None or num < smallest:\n second_smallest = smallest\n smallest = num\n elif num != smallest and (second_smallest is None or num < second_smallest):\n second_smallest = num\n \n return second_smallest", "matching_cluster_idx": 4}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n Examples:\n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n # If the list has less than 2 elements, return None\n if len(lst) < 2:\n return None\n \n # Initialize the smallest and second smallest elements\n first, second = float('inf'), float('inf')\n \n for num in lst:\n # Update the smallest and second smallest elements\n if num < first:\n second, first = first, num\n elif first < num < second:\n second = num\n \n # If the second smallest element was never updated, return None\n return second if second != float('inf') else None", "matching_cluster_idx": 5}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n Examples:\n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n # Remove duplicates to ensure we have distinct elements\n unique_lst = list(set(lst))\n \n # If there are less than 2 unique elements, return None\n if len(unique_lst) < 2:\n return None\n \n # Sort the list to find the second smallest element\n unique_lst.sort()\n \n # Return the second smallest element\n return unique_lst[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n Examples:\n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n # Check if the list is empty or has less than 2 unique elements\n if len(lst) < 2 or len(set(lst)) < 2:\n return None\n \n # Initialize the smallest and second smallest elements\n first, second = float('inf'), float('inf')\n \n for num in lst:\n # Update the first and second smallest elements\n if num < first:\n second = first\n first = num\n elif first < num < second:\n second = num\n \n # Return the second smallest element if found\n return second if second != float('inf') else None", "matching_cluster_idx": 4}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n \n unique_lst = list(set(lst))\n if len(unique_lst) < 2:\n return None\n \n unique_lst.sort()\n return unique_lst[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n\n # Initialize the smallest and second smallest with infinity\n smallest = second_smallest = float('inf')\n \n for num in lst:\n if num < smallest:\n second_smallest = smallest\n smallest = num\n elif smallest < num < second_smallest:\n second_smallest = num\n\n # Check if second_smallest was updated from its initial value\n return second_smallest if second_smallest != float('inf') else None", "matching_cluster_idx": 5}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n Examples:\n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n\n unique_lst = set(lst)\n if len(unique_lst) < 2:\n return None\n\n return sorted(unique_lst)[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None # Not enough elements to find the 2nd smallest\n \n # Remove duplicates and sort the list\n unique_lst = sorted(set(lst))\n \n # Check if there are at least 2 unique elements\n if len(unique_lst) < 2:\n return None # No 2nd smallest element\n \n return unique_lst[1] # Return the 2nd smallest element", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n Examples:\n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n \n # Initialize the smallest and second smallest with infinity\n smallest, second_smallest = float('inf'), float('inf')\n \n for number in lst:\n # Update smallest and second smallest accordingly\n if number < smallest:\n smallest, second_smallest = number, smallest\n elif smallest < number < second_smallest:\n second_smallest = number\n \n # If second_smallest is still infinity, it means there was no second smallest element\n if second_smallest == float('inf'):\n return None\n \n return second_smallest", "matching_cluster_idx": 5}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n \n # Initialize the smallest and second smallest with None\n smallest = second_smallest = None\n \n for num in lst:\n if smallest is None or num < smallest:\n second_smallest = smallest\n smallest = num\n elif num != smallest and (second_smallest is None or num < second_smallest):\n second_smallest = num\n \n return second_smallest", "matching_cluster_idx": 4}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n Examples:\n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n \n # Initialize the smallest and second smallest with infinity\n smallest = second_smallest = float('inf')\n \n for num in lst:\n if num < smallest:\n smallest, second_smallest = num, smallest\n elif smallest < num < second_smallest:\n second_smallest = num\n \n # If second_smallest is still infinity, it means there was no second smallest element\n if second_smallest == float('inf'):\n return None\n else:\n return second_smallest", "matching_cluster_idx": 5}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n\n unique_lst = set(lst)\n if len(unique_lst) < 2:\n return None\n\n return sorted(unique_lst)[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n \n # Use a set to remove duplicates\n unique_elements = set(lst)\n \n # If there are less than 2 unique elements, return None\n if len(unique_elements) < 2:\n return None\n \n # Convert the set back to a sorted list\n sorted_elements = sorted(unique_elements)\n \n # Return the second smallest element\n return sorted_elements[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n \n # Initialize the smallest and second smallest\n first, second = float('inf'), float('inf')\n \n for num in lst:\n if num < first:\n second = first\n first = num\n elif first < num < second:\n second = num\n \n # If second is still infinity, it means there was no second smallest element\n return second if second != float('inf') else None", "matching_cluster_idx": 5}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n Examples:\n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n \n # Initialize the smallest and second smallest with max values\n first, second = float('inf'), float('inf')\n \n for number in lst:\n # Update the smallest and second smallest numbers\n if number < first:\n second = first\n first = number\n elif first < number < second:\n second = number\n \n # If second smallest is still infinity, it means there was no second smallest number\n return second if second != float('inf') else None", "matching_cluster_idx": 5}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n Examples:\n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n # Check if the list has less than 2 unique elements\n unique_elements = set(lst)\n if len(unique_elements) < 2:\n return None\n \n # Remove the smallest element\n smallest = min(unique_elements)\n unique_elements.remove(smallest)\n \n # Return the next smallest element\n return min(unique_elements)", "matching_cluster_idx": 5}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n # Check if the list is empty or has less than 2 unique elements\n if len(lst) < 2:\n return None\n\n # Use a set to remove duplicates and then convert back to a list\n unique_lst = list(set(lst))\n \n # If there are less than 2 unique elements, return None\n if len(unique_lst) < 2:\n return None\n\n # Sort the list to find the 2nd smallest element\n unique_lst.sort()\n \n # Return the 2nd smallest element\n return unique_lst[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n Examples:\n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n \n # Initialize the smallest and second smallest\n first, second = float('inf'), float('inf')\n \n for number in lst:\n if number < first:\n second = first\n first = number\n elif first < number < second:\n second = number\n \n return second if second != first and second != float('inf') else None", "matching_cluster_idx": 5}, {"solution": "def next_smallest(lst):\n \"\"\"\n Returns the 2nd smallest element of the list.\n If the list is empty or all elements are the same, returns None.\n \"\"\"\n if len(lst) < 2:\n return None\n \n unique_elements = set(lst)\n if len(unique_elements) < 2:\n return None\n \n unique_elements.remove(min(lst))\n return min(unique_elements)", "matching_cluster_idx": 5}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n Examples:\n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n # If the list has less than 2 elements, return None\n if len(lst) < 2:\n return None\n \n # Convert the list to a set to remove duplicates\n unique_lst = set(lst)\n \n # If there are less than 2 unique elements, return None\n if len(unique_lst) < 2:\n return None\n \n # Find the smallest and second smallest elements\n smallest = min(unique_lst)\n unique_lst.remove(smallest)\n second_smallest = min(unique_lst)\n \n return second_smallest", "matching_cluster_idx": 5}]}, "HumanEval/113": {"dps": 98.98580121703854, "dps_norm": 66.66666666666667, "pass@1": 100.0, "profiled": [{"solution": "def odd_count(lst):\n \"\"\"\n Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n result = []\n for s in lst:\n odd_count = sum(1 for char in s if int(char) % 2 != 0)\n result.append(f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\")\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"\n Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n \n :param lst: List of strings, each string containing only digits\n :return: List of strings with the number of odd digits replaced in the template\n \"\"\"\n result = []\n for s in lst:\n # Count the number of odd digits in the string\n odd_count = sum(1 for char in s if int(char) % 2 != 0)\n # Replace the 'i' in the template with the odd_count\n output_str = f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\"\n result.append(output_str)\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"\n Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n output = []\n for s in lst:\n count = sum(int(d) % 2 != 0 for d in s)\n output.append(f\"the number of odd elements {count}n the str{count}ng {count} of the {count}nput.\")\n return output", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"\n Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n \n Args:\n lst (list of str): A list of strings, each containing only digits.\n \n Returns:\n list of str: A list of strings as described.\n \"\"\"\n result = []\n for s in lst:\n odd_count = sum(1 for char in s if int(char) % 2 != 0)\n result.append(f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\")\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"\n Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n result = []\n for s in lst:\n # Count the number of odd digits in the string\n odd_count = sum(1 for char in s if int(char) % 2 != 0)\n # Replace 'i' in the template string with the count\n output = f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\"\n result.append(output)\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"\n Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3', '11111111'])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n result = []\n for s in lst:\n # Count the number of odd digits in the string\n odd_count = sum(1 for digit in s if int(digit) % 2 != 0)\n # Replace 'i' in the template string with the odd_count\n result.append(f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\")\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"\n Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n \n :param lst: List of strings, each string contains only digits\n :return: List of strings as per the problem statement\n \"\"\"\n result = []\n for item in lst:\n # Count the number of odd digits in the string\n odd_count = sum(1 for char in item if int(char) % 2 != 0)\n # Replace 'i' in the template string with the count of odd digits\n result.append(f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\")\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"\n Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n \"\"\"\n result = []\n for s in lst:\n count = sum(int(d) % 2 != 0 for d in s)\n result.append(f\"the number of odd elements {count}n the str{count}ng {count} of the {count}nput.\")\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"\n Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n \n :param lst: List of strings containing only digits\n :return: List of strings with the count of odd digits\n \"\"\"\n result = []\n for s in lst:\n odd_count = sum(1 for char in s if int(char) % 2 != 0)\n result.append(f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\")\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"\n Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n \n :param lst: List of strings containing only digits\n :return: List of formatted strings as described\n \"\"\"\n result = []\n for string in lst:\n count = sum(1 for char in string if int(char) % 2 != 0)\n result.append(f\"the number of odd elements {count}n the str{count}ng {count} of the {count}nput.\")\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"\n Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n \n :param lst: List of strings containing only digits\n :return: List of strings with the number of odd digits replaced in the template\n \"\"\"\n result = []\n for s in lst:\n # Count the number of odd digits in the string\n odd_count = sum(1 for c in s if int(c) % 2 != 0)\n # Replace the 'i's in the template with the odd_count\n output = f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\"\n result.append(output)\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"\n Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n \n Args:\n lst (list of str): A list of strings, each string consists of only digits.\n \n Returns:\n list of str: A list of strings with the specified format.\n \"\"\"\n result = []\n for s in lst:\n count = sum(1 for c in s if int(c) % 2 != 0)\n result.append(f\"the number of odd elements {count}n the str{count}ng {count} of the {count}nput.\")\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"\n Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n :param lst: List of strings, each string consists of digits.\n :return: List of strings with the number of odd digits in each input string.\n \"\"\"\n result = []\n for s in lst:\n # Count the number of odd digits in the string\n odd_count = sum(1 for char in s if int(char) % 2 != 0)\n # Replace 'i' in the template string with the count of odd digits\n result.append(f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\")\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"\n Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n :param lst: List of strings, each string containing only digits\n :return: List of strings with the count of odd digits in each input string\n \"\"\"\n result = []\n for s in lst:\n # Count the number of odd digits in the string\n odd_count = sum(1 for char in s if int(char) % 2 != 0)\n # Replace the 'i' in the template string with the count of odd digits\n result.append(f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\")\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"\n Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n result = []\n for string in lst:\n odd_count = sum(1 for char in string if int(char) % 2 != 0)\n result.append(f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\")\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"\n Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n result = []\n for s in lst:\n count = sum(1 for char in s if int(char) % 2 != 0)\n result.append(f\"the number of odd elements {count}n the str{count}ng {count} of the {count}nput.\")\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"\n Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n \"\"\"\n result = []\n for s in lst:\n # Count the number of odd digits in the string\n odd_count = sum(1 for char in s if int(char) % 2 != 0)\n # Replace 'i' in the template string with the count of odd digits\n result.append(f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\")\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"\n Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n :param lst: List of strings, each string containing only digits.\n :return: List of strings with the specified format.\n \"\"\"\n result = []\n for s in lst:\n # Count the number of odd digits in the string\n odd_count = sum(1 for char in s if int(char) % 2 != 0)\n # Replace 'i' in the template string with the count of odd digits\n output_string = f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\"\n result.append(output_string)\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"\n Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n result = []\n for s in lst:\n # Count the number of odd digits in the string\n odd_count = sum(1 for digit in s if int(digit) % 2 != 0)\n # Replace 'i' with the count of odd digits\n output = f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\"\n result.append(output)\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"\n Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n \"\"\"\n # Define the output list\n result = []\n \n # Iterate over each string in the input list\n for s in lst:\n # Count the number of odd digits in the current string\n odd_count = sum(1 for char in s if int(char) % 2 != 0)\n \n # Construct the output string by replacing 'i' with the count of odd digits\n output_str = f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\"\n \n # Append the constructed string to the result list\n result.append(output_str)\n \n return result", "matching_cluster_idx": 3}]}, "HumanEval/119": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 81.0, "profiled": [{"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n # Function to check if a string of parentheses is balanced\n def is_balanced(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n elif char == ')':\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n # Try both possible concatenations\n if is_balanced(lst[0] + lst[1]) or is_balanced(lst[1] + lst[0]):\n return 'Yes'\n else:\n return 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n \n def is_balanced(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n else:\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n \n s1, s2 = lst\n return 'Yes' if is_balanced(s1 + s2) or is_balanced(s2 + s1) else 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n # Check if concatenating in either order results in a balanced string\n def is_balanced(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n else:\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n # Try both possible concatenations\n if is_balanced(lst[0] + lst[1]) or is_balanced(lst[1] + lst[0]):\n return 'Yes'\n else:\n return 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n \n # Function to check if a string is balanced\n def is_balanced(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n else:\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n # Check both possible concatenations\n first_concat = lst[0] + lst[1]\n second_concat = lst[1] + lst[0]\n\n if is_balanced(first_concat) or is_balanced(second_concat):\n return 'Yes'\n else:\n return 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n def is_balanced(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n else:\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n # Try both possible concatenations\n if is_balanced(lst[0] + lst[1]) or is_balanced(lst[1] + lst[0]):\n return 'Yes'\n else:\n return 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n '''\n \n def is_balanced(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n else:\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n # Check both possible concatenations\n if is_balanced(lst[0] + lst[1]) or is_balanced(lst[1] + lst[0]):\n return 'Yes'\n else:\n return 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n '''\n \n def is_balanced(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n else:\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n str1, str2 = lst\n return 'Yes' if is_balanced(str1 + str2) or is_balanced(str2 + str1) else 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n def is_balanced(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n else:\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n # Try both possible concatenations\n if is_balanced(lst[0] + lst[1]):\n return 'Yes'\n if is_balanced(lst[1] + lst[0]):\n return 'Yes'\n return 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n '''\n def is_balanced(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n else:\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n # Check both possible concatenations\n if is_balanced(lst[0] + lst[1]) or is_balanced(lst[1] + lst[0]):\n return 'Yes'\n else:\n return 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n '''\n def is_balanced(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n else:\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n # Check both possible concatenations\n if is_balanced(lst[0] + lst[1]):\n return 'Yes'\n if is_balanced(lst[1] + lst[0]):\n return 'Yes'\n return 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n '''\n # Try concatenating in both possible orders\n for order in [lst, lst[::-1]]:\n combined = ''.join(order)\n balance = 0\n for char in combined:\n if char == '(':\n balance += 1\n else:\n balance -= 1\n if balance < 0:\n break\n if balance == 0:\n return 'Yes'\n return 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n '''\n Check if it is possible to concatenate the two strings in some order\n so that the resulting string will have balanced parentheses.\n \n :param lst: List containing two strings of parentheses\n :return: 'Yes' if a good string can be formed, 'No' otherwise\n '''\n # Unpack the two strings from the list\n str1, str2 = lst\n \n # Check if concatenating in one order results in a balanced string\n if is_balanced(str1 + str2):\n return 'Yes'\n # Check if concatenating in the reverse order results in a balanced string\n if is_balanced(str2 + str1):\n return 'Yes'\n \n return 'No'\ndef is_balanced(s):\n '''\n Helper function to check if a string of parentheses is balanced.\n \n :param s: String of parentheses\n :return: True if the string is balanced, False otherwise\n '''\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n elif char == ')':\n balance -= 1\n if balance < 0:\n return False\n return balance == 0", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n '''\n def is_balanced(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n else:\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n # Try both possible concatenations\n if is_balanced(lst[0] + lst[1]) or is_balanced(lst[1] + lst[0]):\n return 'Yes'\n else:\n return 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n '''\n def is_balanced(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n else:\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n # Try concatenating in both possible orders\n if is_balanced(lst[0] + lst[1]) or is_balanced(lst[1] + lst[0]):\n return 'Yes'\n else:\n return 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n def is_balanced(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n elif char == ')':\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n # Check both possible concatenations\n if is_balanced(lst[0] + lst[1]):\n return 'Yes'\n if is_balanced(lst[1] + lst[0]):\n return 'Yes'\n return 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n '''\n Checks if it is possible to concatenate two strings in some order to form a balanced parentheses string.\n \n Parameters:\n lst (list): A list containing two strings of parentheses.\n \n Returns:\n str: 'Yes' if a balanced string can be formed, 'No' otherwise.\n '''\n # Try concatenating in both possible orders\n for first, second in [(lst[0], lst[1]), (lst[1], lst[0])]:\n balance = 0\n # Check if the concatenated string is balanced\n for char in first + second:\n if char == '(':\n balance += 1\n else:\n balance -= 1\n # If balance goes negative, it means there are more closing parentheses\n if balance < 0:\n break\n # If balance is zero, the string is balanced\n if balance == 0:\n return 'Yes'\n return 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n # Function to check if a string has balanced parentheses\n def is_balanced(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n else:\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n # Check both possible concatenations\n first_concat = lst[0] + lst[1]\n second_concat = lst[1] + lst[0]\n\n if is_balanced(first_concat) or is_balanced(second_concat):\n return 'Yes'\n else:\n return 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n '''\n Check if it is possible to concatenate two strings in some order to form a good string.\n A good string is one where all parentheses are balanced.\n \n :param lst: List of two strings consisting of '(' and ')' only.\n :return: 'Yes' if a good string can be formed, 'No' otherwise.\n '''\n str1, str2 = lst\n # Check if concatenating in one order forms a good string\n if is_balanced(str1 + str2):\n return 'Yes'\n # Check if concatenating in the other order forms a good string\n if is_balanced(str2 + str1):\n return 'Yes'\n return 'No'\ndef is_balanced(s):\n '''\n Check if the given string has balanced parentheses.\n \n :param s: String consisting of '(' and ')' only.\n :return: True if the string is balanced, False otherwise.\n '''\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n else:\n balance -= 1\n if balance < 0:\n return False\n return balance == 0", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n def is_balanced(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n else:\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n # Try both possible concatenations\n if is_balanced(lst[0] + lst[1]) or is_balanced(lst[1] + lst[0]):\n return 'Yes'\n else:\n return 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n '''\n # Define a helper function to check if a string is balanced\n def is_balanced(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n else:\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n # Check both possible concatenations\n if is_balanced(lst[0] + lst[1]):\n return 'Yes'\n if is_balanced(lst[1] + lst[0]):\n return 'Yes'\n \n return 'No'", "matching_cluster_idx": 4}]}, "HumanEval/120": {"dps": 89.65517241379311, "dps_norm": 97.14285714285714, "pass@1": 37.0, "profiled": [{"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n \"\"\"\n if k == 0:\n return []\n \n # Sort the array in descending order and take the first k elements\n max_k_elements = sorted(arr, reverse=True)[:k]\n \n # Return the result sorted in ascending order\n return sorted(max_k_elements)", "matching_cluster_idx": 5}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n \"\"\"\n # Sort the array in descending order and slice the first k elements\n sorted_arr = sorted(arr, reverse=True)[:k]\n # Return the sorted list of the k largest elements in ascending order\n return sorted(sorted_arr)", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n \"\"\"\n if k == 0:\n return []\n \n # Sort the array in ascending order\n sorted_arr = sorted(arr)\n \n # Get the last k elements from the sorted array\n max_k_elements = sorted_arr[-k:]\n \n # Return the sorted list of the maximum k elements\n return sorted(max_k_elements)", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n \"\"\"\n if k == 0:\n return []\n \n # Sort the array in descending order\n sorted_arr = sorted(arr, reverse=True)\n \n # Take the first k elements and sort them in ascending order\n result = sorted_arr[:k]\n result.sort()\n \n return result", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n \"\"\"\n if k == 0:\n return []\n # Sort the array in ascending order and take the last k elements\n sorted_arr = sorted(arr)\n return sorted_arr[-k:]", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n \"\"\"\n if k == 0:\n return []\n # Sort the array in ascending order and slice the last k elements\n return sorted(arr)[-k:]", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n \"\"\"\n if k == 0:\n return []\n \n # Sort the array in descending order and slice the first k elements\n max_k_elements = sorted(arr, reverse=True)[:k]\n \n # Return the result sorted in ascending order\n return sorted(max_k_elements)", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n \"\"\"\n if k == 0:\n return []\n # Sort the array in descending order and take the first k elements\n max_k = sorted(arr, reverse=True)[:k]\n # Return the result sorted in ascending order\n return sorted(max_k)", "matching_cluster_idx": 5}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n \"\"\"\n # Sort the array in descending order and then slice the first k elements\n # Finally, sort the result in ascending order to match the expected output\n return sorted(sorted(arr, reverse=True)[:k])", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n \"\"\"\n # Sort the array in ascending order\n arr.sort()\n \n # If k is 0, return an empty list\n if k == 0:\n return []\n \n # Return the last k elements of the sorted array\n return arr[-k:]", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n \"\"\"\n # Sort the array in ascending order\n arr.sort()\n \n # If k is 0, return an empty list\n if k == 0:\n return []\n \n # Return the last k elements of the sorted array, which are the largest k elements\n return arr[-k:]", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n \"\"\"\n if k == 0:\n return []\n # Sort the array in ascending order\n sorted_arr = sorted(arr)\n # Get the last k elements (which are the largest k elements)\n max_k_elements = sorted_arr[-k:]\n # Return the sorted list of these k elements\n return sorted(max_k_elements)", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n \"\"\"\n # Sort the array in descending order to get the largest elements at the beginning\n sorted_arr = sorted(arr, reverse=True)\n \n # Take the first k elements from the sorted array and sort them in ascending order\n result = sorted(sorted_arr[:k])\n \n return result", "matching_cluster_idx": 5}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n \"\"\"\n # Sort the array in descending order and take the first k elements\n max_k_elements = sorted(arr, reverse=True)[:k]\n # Return the result sorted in ascending order\n return sorted(max_k_elements)", "matching_cluster_idx": 5}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n \"\"\"\n if k == 0:\n return []\n # Sort the array in ascending order and slice the last k elements\n sorted_arr = sorted(arr)\n return sorted_arr[-k:]", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n \"\"\"\n # Sort the array in descending order\n sorted_arr = sorted(arr, reverse=True)\n \n # Take the first k elements from the sorted array\n top_k = sorted_arr[:k]\n \n # Sort the top k elements in ascending order before returning\n return sorted(top_k)", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n \"\"\"\n # Sort the array in descending order and take the first k elements\n max_k = sorted(arr, reverse=True)[:k]\n # Return the sorted list of the k maximum elements\n return sorted(max_k)", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n \"\"\"\n # Sort the array in descending order and slice the top k elements\n sorted_arr = sorted(arr, reverse=True)\n top_k = sorted_arr[:k]\n \n # Return the result sorted in ascending order\n return sorted(top_k)", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n \"\"\"\n # Sort the array in descending order and take the first k elements\n max_k = sorted(arr, reverse=True)[:k]\n # Sort the result in ascending order before returning\n return sorted(max_k)", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n \"\"\"\n # Sort the array in descending order\n sorted_arr = sorted(arr, reverse=True)\n \n # Take the first k elements and sort them in ascending order for the result\n result = sorted(sorted_arr[:k])\n \n return result", "matching_cluster_idx": 6}]}, "HumanEval/121": {"dps": 88.69955156950672, "dps_norm": 67.14285714285714, "pass@1": 100.0, "profiled": [{"solution": "def solution(lst):\n \"\"\"\n Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n # Initialize the sum of odd elements in even positions\n sum_odd_even_pos = 0\n \n # Iterate over the list with index\n for i, num in enumerate(lst):\n # Check if the position is even (0-based index) and the number is odd\n if i % 2 == 0 and num % 2 != 0:\n sum_odd_even_pos += num\n \n return sum_odd_even_pos", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n \"\"\"\n Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n Examples:\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n # Sum of odd elements at even positions\n return sum(lst[i] for i in range(0, len(lst), 2) if lst[i] % 2 != 0)", "matching_cluster_idx": 4}, {"solution": "def solution(lst):\n \"\"\"\n Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n # Initialize the sum of odd elements at even positions\n sum_odd_at_even = 0\n \n # Iterate through the list with index and value\n for index, value in enumerate(lst):\n # Check if the index is even and the value is odd\n if index % 2 == 0 and value % 2 != 0:\n sum_odd_at_even += value\n \n return sum_odd_at_even", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n \"\"\"\n Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n Examples:\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n # Initialize the sum of odd elements in even positions\n sum_odd = 0\n \n # Iterate through the list, considering only even indices\n for i in range(0, len(lst), 2):\n # Check if the element at the current index is odd\n if lst[i] % 2 != 0:\n # Add the odd element to the sum\n sum_odd += lst[i]\n \n # Return the final sum\n return sum_odd", "matching_cluster_idx": 4}, {"solution": "def solution(lst):\n \"\"\"\n Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n # Initialize the sum of odd elements in even positions\n sum_odd_elements = 0\n \n # Iterate through the list, considering only even positions (index 0, 2, 4, ...)\n for i in range(0, len(lst), 2):\n # Check if the element at the current position is odd\n if lst[i] % 2 != 0:\n # Add the odd element to the sum\n sum_odd_elements += lst[i]\n \n return sum_odd_elements", "matching_cluster_idx": 4}, {"solution": "def solution(lst):\n \"\"\"\n Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n Examples:\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n # Initialize the sum to zero\n sum_odd = 0\n \n # Iterate over the list, considering only even indices\n for i in range(0, len(lst), 2):\n # Check if the element at the even index is odd\n if lst[i] % 2 != 0:\n # Add the odd element to the sum\n sum_odd += lst[i]\n \n return sum_odd", "matching_cluster_idx": 4}, {"solution": "def solution(lst):\n \"\"\"\n Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n Examples:\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n # Initialize the sum of odd elements at even positions\n sum_odd = 0\n \n # Iterate over the list, considering only even indices\n for i in range(0, len(lst), 2):\n # Check if the element at the current index is odd\n if lst[i] % 2 != 0:\n # Add the odd element to the sum\n sum_odd += lst[i]\n \n return sum_odd", "matching_cluster_idx": 4}, {"solution": "def solution(lst):\n \"\"\"\n Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n Examples:\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n # Initialize the sum to 0\n sum_odd_elements = 0\n \n # Iterate through the list with index and value\n for index, value in enumerate(lst):\n # Check if the position is even and the element is odd\n if index % 2 == 0 and value % 2 != 0:\n sum_odd_elements += value\n \n return sum_odd_elements", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n \"\"\"\n Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n Examples:\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n # Initialize the sum to zero\n sum_odd_elements = 0\n \n # Iterate over the list with index\n for index, value in enumerate(lst):\n # Check if the position is even and the element is odd\n if index % 2 == 0 and value % 2 != 0:\n sum_odd_elements += value\n \n return sum_odd_elements", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n \"\"\"\n Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n Examples:\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n # Initialize the sum of odd elements in even positions\n sum_odd_elements = 0\n \n # Iterate through the list, considering only even indices (0, 2, 4, ...)\n for i in range(0, len(lst), 2):\n # Check if the element at the current index is odd\n if lst[i] % 2 != 0:\n # Add the odd element to the sum\n sum_odd_elements += lst[i]\n \n return sum_odd_elements", "matching_cluster_idx": 4}, {"solution": "def solution(lst):\n \"\"\"\n Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n Examples:\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n # Sum odd elements at even indices\n return sum(lst[i] for i in range(0, len(lst), 2) if lst[i] % 2 != 0)", "matching_cluster_idx": 4}, {"solution": "def solution(lst):\n \"\"\"\n Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n Examples:\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n # Sum of odd elements at even indices\n return sum(lst[i] for i in range(0, len(lst), 2) if lst[i] % 2 != 0)", "matching_cluster_idx": 4}, {"solution": "def solution(lst):\n \"\"\"\n Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n Examples:\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n # Initialize the sum of odd elements\n sum_odd = 0\n \n # Iterate over the list, considering only even indices\n for i in range(0, len(lst), 2):\n # Check if the element at the current index is odd\n if lst[i] % 2 != 0:\n # Add the odd element to the sum\n sum_odd += lst[i]\n \n return sum_odd", "matching_cluster_idx": 4}, {"solution": "def solution(lst):\n \"\"\"\n Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n Examples:\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n # Initialize the sum of odd elements in even positions\n sum_odd_elements = 0\n \n # Iterate over the list, considering only even positions\n for i in range(0, len(lst), 2):\n # Check if the element at the even position is odd\n if lst[i] % 2 != 0:\n # Add the odd element to the sum\n sum_odd_elements += lst[i]\n \n return sum_odd_elements", "matching_cluster_idx": 4}, {"solution": "def solution(lst):\n \"\"\"\n Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n Examples:\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n # Initialize the sum of odd elements in even positions\n sum_odd = 0\n \n # Iterate through the list, considering only even indices\n for i in range(0, len(lst), 2):\n # Check if the element at the current index is odd\n if lst[i] % 2 != 0:\n # Add the odd element to the sum\n sum_odd += lst[i]\n \n return sum_odd", "matching_cluster_idx": 4}, {"solution": "def solution(lst):\n \"\"\"\n Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n Examples:\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n # Initialize the sum of odd elements in even positions\n sum_odd_elements = 0\n \n # Iterate over the list, considering only even positions\n for i in range(0, len(lst), 2):\n # Check if the element at the even position is odd\n if lst[i] % 2 != 0:\n sum_odd_elements += lst[i]\n \n return sum_odd_elements", "matching_cluster_idx": 4}, {"solution": "def solution(lst):\n \"\"\"\n Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n Examples:\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n # Initialize the sum of odd elements in even positions\n sum_odd = 0\n \n # Iterate through the list, considering only even positions (0, 2, 4, ...)\n for i in range(0, len(lst), 2):\n # Check if the element at the current position is odd\n if lst[i] % 2 != 0:\n # Add the odd element to the sum\n sum_odd += lst[i]\n \n return sum_odd", "matching_cluster_idx": 4}, {"solution": "def solution(lst):\n \"\"\"\n Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n Examples:\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n # Initialize the sum of odd elements at even positions\n sum_odd_at_even = 0\n \n # Iterate over the list, considering only even indices (0, 2, 4, ...)\n for i in range(0, len(lst), 2):\n # Check if the element at the even index is odd\n if lst[i] % 2 != 0:\n # Add the odd element to the sum\n sum_odd_at_even += lst[i]\n \n return sum_odd_at_even", "matching_cluster_idx": 4}, {"solution": "def solution(lst):\n \"\"\"\n Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n # Initialize the sum of odd elements in even positions\n sum_odd_even_pos = 0\n \n # Iterate through the list with index and value\n for i, value in enumerate(lst):\n # Check if the index is even and the value is odd\n if i % 2 == 0 and value % 2 != 0:\n sum_odd_even_pos += value\n \n return sum_odd_even_pos", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n \"\"\"\n Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n Examples:\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n # Initialize the sum to 0\n sum_odd = 0\n \n # Iterate over the list with both index and value\n for index, value in enumerate(lst):\n # Check if the position is even (index is odd) and the value is odd\n if index % 2 == 0 and value % 2 != 0:\n sum_odd += value\n \n return sum_odd", "matching_cluster_idx": 3}]}, "HumanEval/149": {"dps": 85.82677165354332, "dps_norm": 57.142857142857146, "pass@1": 100.0, "profiled": [{"solution": "def sorted_list_sum(lst):\n \"\"\"\n Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order.\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n You may assume that all words will have the same length.\n For example:\n assert sorted_list_sum([\"aa\", \"a\", \"aaa\"]) => [\"aa\"]\n assert sorted_list_sum([\"ab\", \"a\", \"aaa\", \"cd\"]) => [\"ab\", \"cd\"]\n \"\"\"\n # Filter out strings with odd lengths\n filtered_lst = [s for s in lst if len(s) % 2 == 0]\n \n # Sort the list by length and then alphabetically\n sorted_lst = sorted(filtered_lst, key=lambda x: (len(x), x))\n \n return sorted_lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"\n This function accepts a list of strings, removes strings with odd lengths,\n and returns the resulting list sorted first by length and then alphabetically.\n \n :param lst: List of strings\n :return: Sorted list of strings with even lengths\n \"\"\"\n # Filter out strings with odd lengths\n filtered_lst = [s for s in lst if len(s) % 2 == 0]\n \n # Sort the list first by length, then alphabetically\n sorted_lst = sorted(filtered_lst, key=lambda x: (len(x), x))\n \n return sorted_lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"\n Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order,\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n You may assume that all words will have the same length.\n For example:\n assert list_sort([\"aa\", \"a\", \"aaa\"]) => [\"aa\"]\n assert list_sort([\"ab\", \"a\", \"aaa\", \"cd\"]) => [\"ab\", \"cd\"]\n \"\"\"\n \n # Filter out strings with odd lengths\n filtered_lst = [s for s in lst if len(s) % 2 == 0]\n \n # Sort the list by length and then alphabetically\n sorted_lst = sorted(filtered_lst, key=lambda x: (len(x), x))\n \n return sorted_lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"\n Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order.\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n You may assume that all words will have the same length.\n For example:\n assert sorted_list_sum([\"aa\", \"a\", \"aaa\"]) => [\"aa\"]\n assert sorted_list_sum([\"ab\", \"a\", \"aaa\", \"cd\"]) => [\"ab\", \"cd\"]\n \"\"\"\n # Filter out strings with odd lengths\n filtered_list = [s for s in lst if len(s) % 2 == 0]\n \n # Sort the list by length and then alphabetically\n sorted_list = sorted(filtered_list, key=lambda x: (len(x), x))\n \n return sorted_list", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"\n This function accepts a list of strings, removes strings with odd lengths,\n and returns the resulting list in sorted order. The sorting is first by the\n length of the strings in ascending order, and then alphabetically for strings\n of the same length.\n \n :param lst: List of strings\n :return: Sorted list of strings with even lengths\n \"\"\"\n # Filter out strings with odd lengths\n even_length_strings = [s for s in lst if len(s) % 2 == 0]\n \n # Sort the list by length and then alphabetically\n even_length_strings.sort(key=lambda x: (len(x), x))\n \n return even_length_strings", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"\n This function takes a list of strings, removes strings with odd lengths,\n and returns a sorted list. The list is sorted by the length of the strings\n in ascending order. If two strings have the same length, they are sorted\n alphabetically.\n \n Parameters:\n lst (list): A list of strings\n \n Returns:\n list: A sorted list of strings with even lengths\n \"\"\"\n # Remove strings with odd lengths\n even_length_lst = [word for word in lst if len(word) % 2 == 0]\n \n # Sort the list by length and then alphabetically\n even_length_lst.sort(key=lambda word: (len(word), word))\n \n return even_length_lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"\n Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order.\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n You may assume that all words will have the same length.\n For example:\n assert sorted_list_sum([\"aa\", \"a\", \"aaa\"]) => [\"aa\"]\n assert sorted_list_sum([\"ab\", \"a\", \"aaa\", \"cd\"]) => [\"ab\", \"cd\"]\n \"\"\"\n # Filter out strings with odd lengths\n filtered_lst = [s for s in lst if len(s) % 2 == 0]\n \n # Sort the list by length and then alphabetically\n sorted_lst = sorted(filtered_lst, key=lambda x: (len(x), x))\n \n return sorted_lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"\n Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order.\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n You may assume that all words will have the same length.\n For example:\n assert sorted_list_sum([\"aa\", \"a\", \"aaa\"]) => [\"aa\"]\n assert sorted_list_sum([\"ab\", \"a\", \"aaa\", \"cd\"]) => [\"ab\", \"cd\"]\n \"\"\"\n # Filter out strings with odd lengths\n filtered_lst = [word for word in lst if len(word) % 2 == 0]\n \n # Sort the list by length of each word, and alphabetically if lengths are equal\n sorted_lst = sorted(filtered_lst, key=lambda x: (len(x), x))\n \n return sorted_lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"\n This function accepts a list of strings, removes strings with odd lengths,\n and returns the remaining strings in ascending order by length and alphabetically\n if the lengths are the same.\n \"\"\"\n # Filter out strings with odd lengths\n even_length_lst = [s for s in lst if len(s) % 2 == 0]\n \n # Sort the list first by length, then alphabetically\n sorted_lst = sorted(even_length_lst, key=lambda x: (len(x), x))\n \n return sorted_lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"\n Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order.\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n You may assume that all words will have the same length.\n For example:\n assert sorted_list_sum([\"aa\", \"a\", \"aaa\"]) == [\"aa\"]\n assert sorted_list_sum([\"ab\", \"a\", \"aaa\", \"cd\"]) == [\"ab\", \"cd\"]\n \"\"\"\n \n # Filter out strings with odd lengths\n filtered_list = [word for word in lst if len(word) % 2 == 0]\n \n # Sort the list first by length, then alphabetically\n sorted_list = sorted(filtered_list, key=lambda x: (len(x), x))\n \n return sorted_list", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"\n Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order.\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n You may assume that all words will have the same length.\n For example:\n assert list_sort([\"aa\", \"a\", \"aaa\"]) => [\"aa\"]\n assert list_sort([\"ab\", \"a\", \"aaa\", \"cd\"]) => [\"ab\", \"cd\"]\n \"\"\"\n \n # Filter out strings with odd lengths\n filtered_lst = [word for word in lst if len(word) % 2 == 0]\n \n # Sort the list by length and then alphabetically\n sorted_lst = sorted(filtered_lst, key=lambda x: (len(x), x))\n \n return sorted_lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"\n Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order,\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n You may assume that all words will have the same length.\n For example:\n assert sorted_list_sum([\"aa\", \"a\", \"aaa\"]) => [\"aa\"]\n assert sorted_list_sum([\"ab\", \"a\", \"aaa\", \"cd\"]) => [\"ab\", \"cd\"]\n \"\"\"\n # Filter out strings with odd lengths\n filtered_lst = [s for s in lst if len(s) % 2 == 0]\n \n # Sort the list by length and then alphabetically\n sorted_lst = sorted(filtered_lst, key=lambda x: (len(x), x))\n \n return sorted_lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"\n Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order.\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n You may assume that all words will have the same length.\n For example:\n assert sorted_list_sum([\"aa\", \"a\", \"aaa\"]) => [\"aa\"]\n assert sorted_list_sum([\"ab\", \"a\", \"aaa\", \"cd\"]) => [\"ab\", \"cd\"]\n \"\"\"\n # Filter out strings with odd lengths\n filtered_lst = [word for word in lst if len(word) % 2 == 0]\n \n # Sort the list by length, then alphabetically\n sorted_lst = sorted(filtered_lst, key=lambda x: (len(x), x))\n \n return sorted_lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"\n Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order,\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n You may assume that all words will have the same length.\n For example:\n assert sorted_list_sum([\"aa\", \"a\", \"aaa\"]) => [\"aa\"]\n assert sorted_list_sum([\"ab\", \"a\", \"aaa\", \"cd\"]) => [\"ab\", \"cd\"]\n \"\"\"\n # Filter out strings with odd lengths\n filtered_lst = [s for s in lst if len(s) % 2 == 0]\n \n # Sort the list by length and then alphabetically\n sorted_lst = sorted(filtered_lst, key=lambda x: (len(x), x))\n \n return sorted_lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"\n Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order,\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n You may assume that all words will have the same length.\n For example:\n assert sorted_list_sum([\"aa\", \"a\", \"aaa\"]) => [\"aa\"]\n assert sorted_list_sum([\"ab\", \"a\", \"aaa\", \"cd\"]) => [\"ab\", \"cd\"]\n \"\"\"\n # Filter out strings with odd lengths\n filtered_lst = [s for s in lst if len(s) % 2 == 0]\n \n # Sort the list by length, then alphabetically\n sorted_lst = sorted(filtered_lst, key=lambda x: (len(x), x))\n \n return sorted_lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"\n Accepts a list of strings, deletes strings with odd lengths,\n and returns the resulted list sorted by length and alphabetically.\n \n :param lst: List of strings\n :return: Sorted list of strings with even lengths\n \"\"\"\n # Filter out strings with odd lengths\n filtered_lst = [word for word in lst if len(word) % 2 == 0]\n \n # Sort the list first by length, then alphabetically\n sorted_lst = sorted(filtered_lst, key=lambda x: (len(x), x))\n \n return sorted_lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"\n This function takes a list of strings, removes those with odd lengths,\n and returns the remaining strings sorted first by their length and then alphabetically.\n \n :param lst: List of strings\n :return: Sorted list of strings with even lengths\n \"\"\"\n # Filter out strings with odd lengths\n even_length_lst = [s for s in lst if len(s) % 2 == 0]\n \n # Sort the list by length and then alphabetically\n sorted_lst = sorted(even_length_lst, key=lambda x: (len(x), x))\n \n return sorted_lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"\n Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order.\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n You may assume that all words will have the same length.\n For example:\n assert sorted_list_sum([\"aa\", \"a\", \"aaa\"]) => [\"aa\"]\n assert sorted_list_sum([\"ab\", \"a\", \"aaa\", \"cd\"]) => [\"ab\", \"cd\"]\n \"\"\"\n # Filter out strings with odd lengths\n filtered_lst = [word for word in lst if len(word) % 2 == 0]\n \n # Sort the list by length and then alphabetically\n sorted_lst = sorted(filtered_lst, key=lambda x: (len(x), x))\n \n return sorted_lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"\n Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order.\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n You may assume that all words will have the same length.\n For example:\n assert sorted_list_sum([\"aa\", \"a\", \"aaa\"]) => [\"aa\"]\n assert sorted_list_sum([\"ab\", \"a\", \"aaa\", \"cd\"]) => [\"ab\", \"cd\"]\n \"\"\"\n # Filter out strings with odd lengths\n filtered_lst = [word for word in lst if len(word) % 2 == 0]\n \n # Sort the list first by length, then alphabetically\n sorted_lst = sorted(filtered_lst, key=lambda x: (len(x), x))\n \n return sorted_lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"\n This function accepts a list of strings, deletes the strings that have odd lengths,\n and returns the resulted list with a sorted order.\n The list is sorted first by the length of each word in ascending order, and then\n alphabetically for words of the same length.\n \n :param lst: List of strings\n :return: Sorted list of strings with even lengths\n \"\"\"\n # Filter out strings with odd lengths\n filtered_lst = [s for s in lst if len(s) % 2 == 0]\n \n # Sort the list by length, then alphabetically\n sorted_lst = sorted(filtered_lst, key=lambda x: (len(x), x))\n \n return sorted_lst", "matching_cluster_idx": 3}]}, "Mbpp/3": {"dps": 69.15254237288136, "dps_norm": 82.5, "pass@1": 100.0, "profiled": [{"solution": "def is_not_prime(n):\n # 1 is not considered a prime number\n if n <= 1:\n return True\n # 2 and 3 are prime numbers\n if n <= 3:\n return False\n # If the number is divisible by 2 or 3, it is not prime\n if n % 2 == 0 or n % 3 == 0:\n return True\n # Check for divisors up to the square root of n\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return True\n i += 6\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n # Handle edge cases for numbers less than 2\n if n <= 1:\n return True\n # Check divisibility from 2 to the square root of n\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return True\n return False", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(n):\n # Check if the number is less than 2 (not a prime number)\n if n < 2:\n return True\n # Check divisibility from 2 to the square root of n\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return True\n return False", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(n):\n # 1 is not considered a prime number\n if n <= 1:\n return True\n # 2 and 3 are prime numbers\n if n <= 3:\n return False\n # Eliminate numbers divisible by 2 or 3\n if n % 2 == 0 or n % 3 == 0:\n return True\n # Check for factors up to the square root of n\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return True\n i += 6\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n # A number is not prime if it is less than 2 or if it has any divisors other than 1 and itself\n if n < 2:\n return True\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return True\n return False", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(n):\n # 1 is not considered a prime number\n if n <= 1:\n return True\n # 2 is the only even prime number\n if n == 2:\n return False\n # All other even numbers are not primes\n if n % 2 == 0:\n return True\n # Check for factors from 3 to the square root of n\n for i in range(3, int(n**0.5) + 1, 2):\n if n % i == 0:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n # Check if the number is less than 2, which is not a prime number\n if n < 2:\n return True\n # Check divisibility from 2 to the square root of n\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return True\n return False", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(n):\n # Check if the number is less than 2 (0 and 1 are not prime)\n if n < 2:\n return True\n # Check for factors other than 1 and the number itself\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return True\n return False", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(n):\n # 0 and 1 are not prime numbers\n if n <= 1:\n return True\n # 2 is a prime number\n if n == 2:\n return False\n # Even numbers greater than 2 are not prime\n if n % 2 == 0:\n return True\n # Check for factors from 3 to the square root of n\n for i in range(3, int(n**0.5) + 1, 2):\n if n % i == 0:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n # Check if the number is less than 2 (not prime)\n if n < 2:\n return True\n # Check for any divisor from 2 to the square root of n\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return True\n return False", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(n):\n # Check if the number is less than 2, which is not prime\n if n < 2:\n return True\n # Check divisibility from 2 to the square root of n\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return True\n return False", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(n):\n # A number is non-prime if it has any divisor other than 1 and itself\n if n <= 1:\n return True # 1 and numbers less than 1 are not considered prime\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return True # Found a divisor, hence n is not prime\n return False # No divisors found, n is prime", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(n):\n # Check if the number is less than 2 (0 and 1 are not prime)\n if n < 2:\n return True\n # Check for factors other than 1 and the number itself\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return True\n return False", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(n):\n # Check if the number is less than 2, which is not prime\n if n < 2:\n return True\n # Check for factors other than 1 and the number itself\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return True\n return False", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(n):\n # 0 and 1 are not prime numbers\n if n <= 1:\n return True\n # 2 is a prime number\n if n == 2:\n return False\n # Even numbers greater than 2 are not prime\n if n % 2 == 0:\n return True\n # Check for factors from 3 to the square root of n\n for i in range(3, int(n**0.5) + 1, 2):\n if n % i == 0:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n # 0 and 1 are not prime numbers\n if n <= 1:\n return True\n # 2 is a prime number\n if n == 2:\n return False\n # Even numbers greater than 2 are not prime\n if n % 2 == 0:\n return True\n # Check for factors from 3 to the square root of n\n for i in range(3, int(n**0.5) + 1, 2):\n if n % i == 0:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n # Check if the number is less than 2, which means it's not prime\n if n < 2:\n return True\n # Check divisibility from 2 to the square root of n\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return True\n return False", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(n):\n # Handle the special cases where n is less than 2\n if n < 2:\n return True\n # Check divisibility from 2 to the square root of n\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return True\n return False", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(n):\n # Check if the number is less than 2\n if n < 2:\n return True\n # Check divisibility from 2 to the square root of n\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return True\n return False", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(n):\n # Check if the number is less than 2, which means it's not prime\n if n < 2:\n return True\n # Check for factors other than 1 and the number itself\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return True\n # If no factors found, the number is prime\n return False", "matching_cluster_idx": 5}]}, "Mbpp/4": {"dps": 95.22184300341297, "dps_norm": 83.33333333333333, "pass@1": 99.0, "profiled": [{"solution": "import heapq\ndef heap_queue_largest(nums, n):\n # Use heapq.nlargest to find the n largest numbers in the list\n largest_nums = heapq.nlargest(n, nums)\n # Return the result sorted in descending order\n return sorted(largest_nums, reverse=True)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n # Use heapq.nlargest to find the n largest elements and then sort them in descending order\n largest_nums = heapq.nlargest(n, nums)\n return sorted(largest_nums, reverse=True)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n # Use heapq.nlargest to find the n largest elements\n largest_nums = heapq.nlargest(n, nums)\n # Return the result in descending order\n return largest_nums", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n # Use heapq.nlargest to find the n largest numbers in the list\n largest_nums = heapq.nlargest(n, nums)\n # Return the result sorted in descending order\n return sorted(largest_nums, reverse=True)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n # Use heapq.nlargest to find the n largest elements in the list\n largest_nums = heapq.nlargest(n, nums)\n # Return the result in descending order\n return largest_nums", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n # Use nlargest from heapq to find the n largest numbers\n largest_nums = heapq.nlargest(n, nums)\n # Return the result in descending order\n return sorted(largest_nums, reverse=True)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n # Use heapq to find the n largest elements\n largest_nums = heapq.nlargest(n, nums)\n # Return the result in descending order\n return sorted(largest_nums, reverse=True)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n # Use heapq.nlargest to find the n largest elements\n largest_nums = heapq.nlargest(n, nums)\n # Return the result sorted in descending order\n return sorted(largest_nums, reverse=True)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n # Use heapq.nlargest to find the n largest numbers\n largest_nums = heapq.nlargest(n, nums)\n # Return the result in descending order\n return largest_nums", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n # Use heapq.nlargest to find the n largest elements and sort them in descending order\n largest_n = heapq.nlargest(n, nums)\n return sorted(largest_n, reverse=True)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n # Use heapq.nlargest to find the n largest numbers in the list\n largest_numbers = heapq.nlargest(n, nums)\n # Return the result in descending order\n return largest_numbers", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n # Use heapq.nlargest to find the n largest numbers in the list\n largest_nums = heapq.nlargest(n, nums)\n # Return the result in descending order\n return largest_nums", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n # Use nlargest from heapq to find the n largest numbers\n largest_nums = heapq.nlargest(n, nums)\n # Return the result in descending order\n return largest_nums", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n # Use heapq.nlargest to find the n largest numbers in the list\n largest_nums = heapq.nlargest(n, nums)\n # Return the result sorted in descending order\n return sorted(largest_nums, reverse=True)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n # Use heapq.nlargest to get the n largest numbers from the list\n largest_nums = heapq.nlargest(n, nums)\n # Return the result sorted in descending order\n return sorted(largest_nums, reverse=True)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n # Use heapq.nlargest to find the n largest elements\n largest_nums = heapq.nlargest(n, nums)\n # Return the result in descending order\n return sorted(largest_nums, reverse=True)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n # Use heapq.nlargest to find the n largest elements in the list\n largest_nums = heapq.nlargest(n, nums)\n # Return the result in descending order\n return largest_nums", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n # Use heapq to find the n largest numbers in the list\n largest_n = heapq.nlargest(n, nums)\n # Return the result in descending order\n return sorted(largest_n, reverse=True)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n # Use heapq.nlargest to find the n largest numbers in the list\n largest_nums = heapq.nlargest(n, nums)\n # Return the result sorted in descending order\n return sorted(largest_nums, reverse=True)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n # Use heapq.nlargest to find the n largest numbers in the list\n largest_nums = heapq.nlargest(n, nums)\n # Return the list sorted in descending order\n return sorted(largest_nums, reverse=True)", "matching_cluster_idx": 9}]}, "Mbpp/9": {"dps": 83.19727891156462, "dps_norm": 57.0, "pass@1": 98.0, "profiled": [{"solution": "def find_Rotations(s):\n # Double the string to simulate infinite rotations\n temp = s + s\n # Length of the original string\n n = len(s)\n \n # Iterate through possible rotations\n for i in range(1, n + 1):\n # Extract the substring of length n starting from index i\n rotated = temp[i:i + n]\n # Check if the rotated string matches the original string\n if rotated == s:\n return i\n # If no rotation results in the same string, return the length of the string\n return n", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(s):\n # Initialize the number of rotations\n rotations = 1\n \n # Loop until the string is rotated back to its original form\n while rotations < len(s):\n # Rotate the string by one position\n rotated_s = s[rotations:] + s[:rotations]\n \n # Check if the rotated string matches the original string\n if rotated_s == s:\n return rotations\n \n # Increment the number of rotations\n rotations += 1\n \n # If no valid rotation found, return the length of the string\n return len(s)", "matching_cluster_idx": 3}, {"solution": "def find_Rotations(s):\n # Length of the string\n n = len(s)\n \n # Iterate through possible rotations\n for i in range(1, n + 1):\n # Generate the rotated string\n rotated_s = s[i:] + s[:i]\n \n # Check if the rotated string matches the original string\n if rotated_s == s:\n return i\n \n # If no rotation matches, return the length of the string\n return n", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(s):\n # Initialize the number of rotations\n n = len(s)\n rotations = 1\n \n # Loop through the string to check for rotations\n while rotations < n:\n # Rotate the string by one position\n rotated_s = s[rotations:] + s[:rotations]\n \n # Check if the rotated string is the same as the original string\n if rotated_s == s:\n return rotations\n \n # Increment the number of rotations\n rotations += 1\n \n # If no rotation results in the same string, return the length of the string\n return n", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(s):\n # Double the string to handle rotations\n double_s = s + s\n # Length of the original string\n n = len(s)\n \n # Iterate over possible rotations\n for i in range(1, n + 1):\n # Get the substring of length n starting from i\n rotated = double_s[i:i + n]\n # Check if the rotated substring is equal to the original string\n if rotated == s:\n return i\n # If no rotation results in the same string, return the length of the string\n return n", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(s):\n # Concatenate the string with itself\n temp = s + s\n # Length of the string\n n = len(s)\n \n # Check for the minimum number of rotations\n for i in range(1, n + 1):\n # Generate the substring of length n starting from i\n substring = temp[i:i + n]\n # If the substring matches the original string, return the number of rotations\n if substring == s:\n return i\n # If no rotation results in the original string, return 0 (though this case won't occur for non-empty strings)\n return 0", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(s):\n # Double the string to handle rotations\n temp = s + s\n # Length of the original string\n n = len(s)\n \n # Iterate through possible rotations\n for i in range(1, n + 1):\n # Extract the substring from the doubled string\n substring = temp[i: i + n]\n # Check if the substring matches the original string\n if substring == s:\n return i\n # If no rotation matches, return the length of the string\n return n", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(s):\n # Append the string to itself to handle rotations\n temp = s + s\n # Length of the original string\n n = len(s)\n \n # Iterate through possible rotations\n for i in range(1, n + 1):\n # Generate the rotated string\n rotated = temp[i: i + n]\n # Check if the rotated string matches the original string\n if rotated == s:\n return i\n return 0", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(s):\n # Concatenate the string with itself to handle rotations\n temp = s + s\n # Length of the original string\n n = len(s)\n \n # Iterate through the possible rotations\n for i in range(1, n + 1):\n # Extract the substring of length n starting from i\n substring = temp[i:i + n]\n # Check if the substring matches the original string\n if substring == s:\n return i\n # If no rotation matches, return the length of the string\n return n", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(s):\n # Iterate through the string to find the minimum rotations\n for i in range(1, len(s)):\n # Rotate the string by i positions\n rotated = s[i:] + s[:i]\n # Check if the rotated string is the same as the original\n if rotated == s:\n return i\n # If no rotation results in the same string, return the length of the string\n return len(s)", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(s):\n # Double the input string to simulate all possible rotations\n temp = s + s\n # Length of the input string\n n = len(s)\n # Iterate over the doubled string to find the minimum rotation\n for i in range(1, n + 1):\n # Extract the substring of length n starting from index i\n substring = temp[i: i + n]\n # Check if the substring is equal to the original string\n if substring == s:\n return i\n # If no rotation results in the original string, return the length of the string\n return n", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(s):\n # Concatenate the string with itself to handle rotations\n temp = s + s\n # Length of the string\n n = len(s)\n \n # Iterate through possible rotation points\n for i in range(1, n + 1):\n # Generate the rotated string\n rotated = temp[i:i + n]\n # Check if the rotated string is the same as the original string\n if rotated == s:\n return i\n # If no rotation matches, return the length of the string\n return n", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(s):\n # Double the input string to handle rotations\n temp = s + s\n # Length of the input string\n n = len(s)\n \n # Iterate through the string to find the minimum rotations\n for i in range(1, n + 1):\n # Extract the substring of length n starting from index i\n substring = temp[i:i + n]\n # If the substring matches the original string, return the rotation count\n if substring == s:\n return i\n # If no rotation matches, return the length of the string\n return n", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(s):\n # Append the string to itself to handle rotations\n temp = s + s\n # Length of the string\n n = len(s)\n \n # Iterate over the possible rotations\n for i in range(1, n + 1):\n # Generate the rotated string\n rotated = temp[i:i + n]\n # Check if the rotated string matches the original string\n if rotated == s:\n return i\n # If no rotation matches, return the length of the string\n return n", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(s):\n # Double the input string to handle rotations\n temp = s + s\n # Length of the input string\n n = len(s)\n \n # Iterate through the possible rotations\n for i in range(1, n + 1):\n # Generate the rotated string\n substring = temp[i: i + n]\n # Check if the rotated string matches the original string\n if substring == s:\n return i\n # If no valid rotation is found, return the length of the string\n return n", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(s):\n # Double the input string to simulate infinite rotations\n temp = s + s\n # Length of the input string\n n = len(s)\n \n # Iterate through possible rotations\n for i in range(1, n + 1):\n # Extract the substring of length n starting from index i\n substring = temp[i:i + n]\n # Check if the substring matches the original string\n if substring == s:\n return i\n return n # In case no valid rotation is found, return the length of the string", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(s):\n # Append the string to itself to handle rotations\n temp = s + s\n # Length of the original string\n n = len(s)\n \n # Iterate through possible rotations\n for i in range(1, n + 1):\n # Extract the rotated substring\n substring = temp[i:i + n]\n # Check if the rotated substring matches the original string\n if substring == s:\n return i\n return n # If no rotation matches, return the length of the string", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(s):\n # Concatenate the string with itself\n concatenated = s + s\n # Length of the original string\n n = len(s)\n \n # Iterate through possible rotations\n for i in range(1, n + 1):\n # Extract the rotated substring\n rotated = concatenated[i : i + n]\n # Check if the rotated substring matches the original string\n if rotated == s:\n return i\n # If no rotation matches, return 0 (though this case won't occur for non-empty strings)\n return 0", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(s):\n # Concatenate the string with itself\n temp = s + s\n # Length of the original string\n n = len(s)\n \n # Iterate through the string to find the minimum rotations\n for i in range(1, n + 1):\n # Generate the substring of length n starting from i\n substring = temp[i:i + n]\n # Check if the substring is equal to the original string\n if substring == s:\n return i\n # If no rotations found, return the length of the string\n return n", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(s):\n # Get the length of the string\n n = len(s)\n \n # Iterate over possible rotations\n for i in range(1, n + 1):\n # Generate the rotated string\n rotated = s[i:] + s[:i]\n \n # Check if the rotated string is the same as the original\n if rotated == s:\n return i # Return the number of rotations\n \n # If no rotation results in the same string, return 0 (though this case should not occur for valid input)\n return 0", "matching_cluster_idx": 4}]}, "Mbpp/11": {"dps": 62.22222222222222, "dps_norm": 93.88888888888889, "pass@1": 89.0, "profiled": [{"solution": "def remove_Occ(s, ch):\n # Find and remove the first occurrence of the character\n first_occ = s.find(ch)\n if first_occ != -1:\n s = s[:first_occ] + s[first_occ + 1:]\n \n # Find and remove the last occurrence of the character\n last_occ = s.rfind(ch)\n if last_occ != -1:\n s = s[:last_occ] + s[last_occ + 1:]\n \n return s", "matching_cluster_idx": 7}, {"solution": "def remove_Occ(s, ch):\n # Find the index of the first occurrence of the character\n first_occurrence = s.find(ch)\n \n # Find the index of the last occurrence of the character\n last_occurrence = s.rfind(ch)\n \n # If the character is not found, return the original string\n if first_occurrence == -1 or last_occurrence == -1:\n return s\n \n # If the first and last occurrences are the same, remove only one occurrence\n if first_occurrence == last_occurrence:\n return s[:first_occurrence] + s[first_occurrence + 1:]\n \n # Remove the first and last occurrences of the character\n return s[:first_occurrence] + s[first_occurrence + 1:last_occurrence] + s[last_occurrence + 1:]", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(s, ch):\n # Find the index of the first occurrence of the character\n first_occurrence = s.find(ch)\n \n # Find the index of the last occurrence of the character\n last_occurrence = s.rfind(ch)\n \n # If the character is not found, return the original string\n if first_occurrence == -1 or last_occurrence == -1:\n return s\n \n # Construct the new string by removing the first and last occurrence\n result = s[:first_occurrence] + s[first_occurrence + 1:last_occurrence] + s[last_occurrence + 1:]\n \n return result", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(s, ch):\n # Find the index of the first occurrence of ch\n first = s.find(ch)\n # Find the index of the last occurrence of ch\n last = s.rfind(ch)\n \n # Remove the first and last occurrence of ch\n if first != -1 and last != -1:\n return s[:first] + s[first+1:last] + s[last+1:]\n else:\n return s", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(s, ch):\n # Remove the first occurrence of the character\n for i in range(len(s)):\n if s[i] == ch:\n s = s[:i] + s[i+1:]\n break\n \n # Remove the last occurrence of the character\n for i in range(len(s) - 1, -1, -1):\n if s[i] == ch:\n s = s[:i] + s[i+1:]\n break\n \n return s", "matching_cluster_idx": 7}, {"solution": "def remove_Occ(s, char):\n # Find the index of the first occurrence of the character\n first_occurrence = s.find(char)\n # Find the index of the last occurrence of the character\n last_occurrence = s.rfind(char)\n \n # If the character is not found, return the original string\n if first_occurrence == -1:\n return s\n \n # If the first and last occurrences are the same, remove that single occurrence\n if first_occurrence == last_occurrence:\n return s[:first_occurrence] + s[first_occurrence + 1:]\n \n # Remove the first and last occurrences of the character\n return s[:first_occurrence] + s[first_occurrence + 1:last_occurrence] + s[last_occurrence + 1:]", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(s, ch):\n # Find the first occurrence of the character and remove it\n first_occurrence = s.find(ch)\n if first_occurrence != -1:\n s = s[:first_occurrence] + s[first_occurrence + 1:]\n \n # Find the last occurrence of the character and remove it\n last_occurrence = s.rfind(ch)\n if last_occurrence != -1:\n s = s[:last_occurrence] + s[last_occurrence + 1:]\n \n return s", "matching_cluster_idx": 7}, {"solution": "def remove_Occ(s, ch):\n # Find and remove the first occurrence of the character\n for i in range(len(s)):\n if s[i] == ch:\n s = s[:i] + s[i+1:]\n break\n \n # Find and remove the last occurrence of the character\n for i in range(len(s) - 1, -1, -1):\n if s[i] == ch:\n s = s[:i] + s[i+1:]\n break\n \n return s", "matching_cluster_idx": 7}, {"solution": "def remove_Occ(s, ch):\n # Find the index of the first occurrence of the character\n first_occurrence = s.find(ch)\n # Find the index of the last occurrence of the character\n last_occurrence = s.rfind(ch)\n \n # If the character does not exist in the string, return the original string\n if first_occurrence == -1 or last_occurrence == -1:\n return s\n \n # If the first and last occurrences are the same, remove that character\n if first_occurrence == last_occurrence:\n return s[:first_occurrence] + s[first_occurrence + 1:]\n \n # Remove the first and last occurrences of the character\n return s[:first_occurrence] + s[first_occurrence + 1:last_occurrence] + s[last_occurrence + 1:]", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(s, ch):\n # Find the first occurrence of the character\n first_occurrence = s.find(ch)\n \n # Find the last occurrence of the character\n last_occurrence = s.rfind(ch)\n \n # Remove the first and last occurrence of the character\n if first_occurrence != -1 and last_occurrence != -1:\n s = s[:first_occurrence] + s[first_occurrence+1:last_occurrence] + s[last_occurrence+1:]\n \n return s", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(s, ch):\n # Find the first occurrence of the character and remove it\n for i in range(len(s)):\n if s[i] == ch:\n s = s[:i] + s[i+1:]\n break\n \n # Find the last occurrence of the character and remove it\n for i in range(len(s) - 1, -1, -1):\n if s[i] == ch:\n s = s[:i] + s[i+1:]\n break\n \n return s", "matching_cluster_idx": 7}, {"solution": "def remove_Occ(s, ch):\n # Remove the first occurrence of the character\n for i in range(len(s)):\n if s[i] == ch:\n s = s[:i] + s[i+1:]\n break\n \n # Remove the last occurrence of the character\n for i in range(len(s) - 1, -1, -1):\n if s[i] == ch:\n s = s[:i] + s[i+1:]\n break\n \n return s", "matching_cluster_idx": 7}, {"solution": "def remove_Occ(s, ch):\n # Remove the first occurrence of the character\n for i in range(len(s)):\n if s[i] == ch:\n s = s[:i] + s[i+1:]\n break\n \n # Remove the last occurrence of the character\n for i in range(len(s) - 1, -1, -1):\n if s[i] == ch:\n s = s[:i] + s[i+1:]\n break\n \n return s", "matching_cluster_idx": 7}, {"solution": "def remove_Occ(s, ch):\n # Check if the character is in the string\n if ch in s:\n # Remove the first occurrence\n for i in range(len(s)):\n if s[i] == ch:\n s = s[:i] + s[i+1:]\n break\n \n # Remove the last occurrence\n for i in range(len(s) - 1, -1, -1):\n if s[i] == ch:\n s = s[:i] + s[i+1:]\n break\n \n return s", "matching_cluster_idx": 6}, {"solution": "def remove_Occ(s, ch):\n # Remove the first occurrence of the character\n for i in range(len(s)):\n if s[i] == ch:\n s = s[:i] + s[i+1:]\n break\n \n # Remove the last occurrence of the character\n for i in range(len(s) - 1, -1, -1):\n if s[i] == ch:\n s = s[:i] + s[i+1:]\n break\n \n return s", "matching_cluster_idx": 7}, {"solution": "def remove_Occ(s, ch):\n # Find the index of the first occurrence of ch\n first_occurrence = s.find(ch)\n # Find the index of the last occurrence of ch\n last_occurrence = s.rfind(ch)\n \n # If the character is not found, return the original string\n if first_occurrence == -1:\n return s\n \n # If the first and last occurrence are the same, remove one instance of the character\n if first_occurrence == last_occurrence:\n return s[:first_occurrence] + s[first_occurrence + 1:]\n \n # Remove the first and last occurrences of the character\n return s[:first_occurrence] + s[first_occurrence + 1:last_occurrence] + s[last_occurrence + 1:]", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(s, ch):\n # Find the index of the first occurrence of the character\n first_occurrence = s.find(ch)\n \n # Find the index of the last occurrence of the character\n last_occurrence = s.rfind(ch)\n \n # If the character does not exist in the string, return the original string\n if first_occurrence == -1 or last_occurrence == -1:\n return s\n \n # If the first and last occurrence is the same, it means the character appears only once\n if first_occurrence == last_occurrence:\n return s[:first_occurrence] + s[first_occurrence + 1:]\n \n # Remove the first and last occurrence of the character\n return s[:first_occurrence] + s[first_occurrence + 1:last_occurrence] + s[last_occurrence + 1:]", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(s, ch):\n # Find the index of the first occurrence of the character\n first_occurrence = s.find(ch)\n \n # Find the index of the last occurrence of the character\n last_occurrence = s.rfind(ch)\n \n # If the character is not found, return the original string\n if first_occurrence == -1 or last_occurrence == -1:\n return s\n \n # If the first and last occurrences are the same, remove one character\n if first_occurrence == last_occurrence:\n return s[:first_occurrence] + s[first_occurrence + 1:]\n \n # Remove the first and last occurrences of the character\n return s[:first_occurrence] + s[first_occurrence + 1:last_occurrence] + s[last_occurrence + 1:]", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(s, ch):\n # Remove the first occurrence of the character\n for i in range(len(s)):\n if s[i] == ch:\n s = s[:i] + s[i+1:]\n break\n \n # Remove the last occurrence of the character\n for i in range(len(s) - 1, -1, -1):\n if s[i] == ch:\n s = s[:i] + s[i+1:]\n break\n \n return s", "matching_cluster_idx": 7}, {"solution": "def remove_Occ(s, ch):\n # Find the index of the first occurrence of the character\n first_index = s.find(ch)\n \n # Find the index of the last occurrence of the character\n last_index = s.rfind(ch)\n \n # If the character is not found, return the original string\n if first_index == -1 or last_index == -1:\n return s\n \n # If the character is found, remove the first and last occurrences\n return s[:first_index] + s[first_index + 1:last_index] + s[last_index + 1:]", "matching_cluster_idx": 8}]}, "Mbpp/12": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def sort_matrix(matrix):\n # Sort the matrix based on the sum of each row\n matrix.sort(key=sum)\n return matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Sort the matrix based on the sum of each row\n matrix.sort(key=sum)\n return matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Sort the matrix based on the sum of each row\n matrix.sort(key=sum)\n return matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Sort the matrix based on the sum of each row\n sorted_matrix = sorted(matrix, key=sum)\n return sorted_matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Sort the matrix based on the sum of each row\n matrix.sort(key=sum)\n return matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Sort the matrix based on the sum of each row\n matrix.sort(key=sum)\n return matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Sort the matrix based on the sum of each row\n matrix.sort(key=sum)\n return matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Sort the matrix based on the sum of each row\n sorted_matrix = sorted(matrix, key=sum)\n return sorted_matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Sort the matrix based on the sum of each row\n matrix.sort(key=sum)\n return matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Sort the matrix based on the sum of each row\n sorted_matrix = sorted(matrix, key=sum)\n return sorted_matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Sort the matrix based on the sum of each row\n sorted_matrix = sorted(matrix, key=sum)\n return sorted_matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Sort the matrix based on the sum of each row\n sorted_matrix = sorted(matrix, key=sum)\n return sorted_matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Sort the matrix based on the sum of each row\n matrix.sort(key=sum)\n return matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Sort the matrix based on the sum of each row\n matrix.sort(key=sum)\n return matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Sort the matrix based on the sum of each row\n matrix.sort(key=sum)\n return matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Sort the matrix based on the sum of each row\n sorted_matrix = sorted(matrix, key=sum)\n return sorted_matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Sort the matrix based on the sum of elements in each row\n matrix.sort(key=sum)\n return matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Sort the matrix based on the sum of each row\n matrix.sort(key=sum)\n return matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Sort the matrix based on the sum of each row\n sorted_matrix = sorted(matrix, key=sum)\n return sorted_matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Sort the matrix based on the sum of each row\n matrix.sort(key=sum)\n return matrix", "matching_cluster_idx": 15}]}, "Mbpp/16": {"dps": null, "dps_norm": null, "pass@1": 0.0, "profiled": []}, "Mbpp/19": {"dps": 85.85858585858585, "dps_norm": 92.0, "pass@1": 100.0, "profiled": [{"solution": "def test_duplicate(arr):\n # Convert the list to a set and compare lengths\n return len(arr) != len(set(arr))", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(arr):\n # Use a set to track unique elements\n seen = set()\n \n for num in arr:\n # If the number is already in the set, a duplicate is found\n if num in seen:\n return True\n # Add the number to the set\n seen.add(num)\n \n # No duplicates found\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(arr):\n # Convert the list to a set and compare its length to the original list\n return len(arr) != len(set(arr))", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(arr):\n # Using a set to track seen elements\n seen = set()\n for num in arr:\n if num in seen:\n return True # Duplicate found\n seen.add(num)\n return False # No duplicates found", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(arr):\n # Using a set to track seen elements\n seen = set()\n \n for num in arr:\n if num in seen:\n return True # Duplicate found\n seen.add(num)\n \n return False # No duplicates found", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(arr):\n # Create an empty set to track seen elements\n seen = set()\n \n # Iterate through each element in the array\n for num in arr:\n # If the element is already in the set, a duplicate is found\n if num in seen:\n return True\n # Add the element to the set\n seen.add(num)\n \n # If no duplicates are found, return False\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(arr):\n # Use a set to track seen elements\n seen = set()\n \n # Iterate through the array\n for num in arr:\n # If the element is already in the set, we have a duplicate\n if num in seen:\n return True\n # Add the element to the set\n seen.add(num)\n \n # If no duplicates were found, return False\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(arr):\n # Using a set to track seen elements\n seen = set()\n \n for num in arr:\n # If the element is already in the set, a duplicate is found\n if num in seen:\n return True\n # Add the element to the set\n seen.add(num)\n \n # No duplicates found\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(arr):\n # Convert the list to a set to remove duplicates\n unique_elements = set(arr)\n \n # If the length of the set is less than the original list, there were duplicates\n return len(unique_elements) != len(arr)", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(arr):\n # Create an empty set to keep track of seen elements\n seen = set()\n \n # Iterate through each element in the array\n for num in arr:\n # If the element is already in the set, return True (duplicate found)\n if num in seen:\n return True\n # Otherwise, add the element to the set\n seen.add(num)\n \n # If no duplicates are found, return False\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(arr):\n # Use a set to track seen elements\n seen = set()\n \n # Iterate over each element in the array\n for num in arr:\n # If the element is already in the set, a duplicate is found\n if num in seen:\n return True\n # Otherwise, add the element to the set\n seen.add(num)\n \n # If no duplicates are found, return False\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(arr):\n # Create an empty set to store elements\n seen = set()\n \n # Iterate through the array\n for num in arr:\n # If the element is already in the set, return True (duplicate found)\n if num in seen:\n return True\n # Add the element to the set\n seen.add(num)\n \n # If no duplicates are found, return False\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(arr):\n # Convert the list to a set and compare the lengths\n # If lengths differ, there are duplicates\n return len(arr) != len(set(arr))", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(arr):\n # Convert the list to a set to remove duplicates\n # If the length of the set is less than the original list, there were duplicates\n return len(set(arr)) != len(arr)", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(nums):\n # Use a set to track seen elements\n seen = set()\n \n # Iterate through the list of numbers\n for num in nums:\n # If the number is already in the set, a duplicate is found\n if num in seen:\n return True\n # Add the number to the set\n seen.add(num)\n \n # If no duplicates are found, return False\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(arr):\n # Convert the list to a set to remove duplicates\n unique_elements = set(arr)\n \n # If the lengths of the set and the original list differ, there were duplicates\n return len(arr) != len(unique_elements)", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(arr):\n # Create an empty set to keep track of seen elements\n seen = set()\n \n # Iterate through the array\n for element in arr:\n # If the element is already in the set, we have a duplicate\n if element in seen:\n return True\n # Otherwise, add the element to the set\n seen.add(element)\n \n # If we reach this point, no duplicates were found\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(arr):\n # Create an empty set to store elements\n seen = set()\n \n # Iterate through each element in the array\n for num in arr:\n # If the element is already in the set, a duplicate is found\n if num in seen:\n return True\n # Otherwise, add the element to the set\n seen.add(num)\n \n # If no duplicates are found, return False\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(arr):\n # Convert the list to a set and compare its length with the original list\n return len(arr) != len(set(arr))", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(arr):\n # Convert the list to a set and compare lengths\n # If there are duplicates, the set will be smaller\n return len(arr) != len(set(arr))", "matching_cluster_idx": 11}]}, "Mbpp/62": {"dps": 88.0, "dps_norm": 92.0, "pass@1": 100.0, "profiled": [{"solution": "def smallest_num(lst):\n # Use the min function to find the smallest number in the list\n return min(lst)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(lst):\n # Check if the list is empty\n if not lst:\n return None # Return None if the list is empty\n \n # Initialize the smallest number with the first element of the list\n smallest = lst[0]\n \n # Iterate through the list to find the smallest number\n for num in lst:\n if num < smallest:\n smallest = num\n \n return smallest", "matching_cluster_idx": 3}, {"solution": "def smallest_num(lst):\n # Check if the list is empty\n if not lst:\n return None # Return None for an empty list\n \n # Initialize min_num with the first element of the list\n min_num = lst[0]\n \n # Iterate through the list to find the smallest number\n for num in lst:\n if num < min_num:\n min_num = num\n \n return min_num", "matching_cluster_idx": 3}, {"solution": "def smallest_num(lst):\n # Check if the list is empty to avoid ValueError from min()\n if not lst:\n return None # or raise an exception, depending on requirements\n # Use the built-in min() function to find the smallest number\n return min(lst)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(lst):\n # Check if the list is empty\n if not lst:\n return None\n \n # Initialize min_value with the first element of the list\n min_value = lst[0]\n \n # Iterate through the list to find the smallest number\n for num in lst:\n if num < min_value:\n min_value = num\n \n return min_value", "matching_cluster_idx": 3}, {"solution": "def smallest_num(lst):\n # Check if the list is empty to avoid ValueError from min()\n if not lst:\n return None # or raise an exception, depending on the desired behavior\n # Use the built-in min function to find the smallest number in the list\n return min(lst)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(lst):\n # Check if the list is empty to avoid calling min() on an empty list\n if not lst:\n return None # or raise an exception, e.g., raise ValueError(\"List is empty\")\n \n # Use the min function to find the smallest number in the list\n return min(lst)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(numbers):\n # Use the min function to find the smallest number in the list\n return min(numbers)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(lst):\n # Check if the list is empty\n if not lst:\n return None # Return None for an empty list\n\n # Initialize the smallest number with the first element of the list\n smallest = lst[0]\n\n # Iterate through the list to find the smallest number\n for num in lst:\n if num < smallest:\n smallest = num\n\n return smallest", "matching_cluster_idx": 3}, {"solution": "def smallest_num(lst):\n # Use the min function to find the smallest number in the list\n return min(lst)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(lst):\n # Check if the list is empty\n if not lst:\n return None # Return None or an appropriate value for an empty list\n\n # Initialize the smallest number with the first element of the list\n smallest = lst[0]\n\n # Iterate through the list to find the smallest number\n for num in lst:\n if num < smallest:\n smallest = num\n\n return smallest", "matching_cluster_idx": 3}, {"solution": "def smallest_num(lst):\n # Use the min function to find the smallest number in the list\n return min(lst)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(lst):\n # Use the built-in min function to find the smallest number in the list\n return min(lst)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(lst):\n # Check if the list is empty\n if not lst:\n return None # Return None for empty list\n \n # Initialize smallest with the first element of the list\n smallest = lst[0]\n \n # Iterate through the list to find the smallest number\n for num in lst:\n if num < smallest:\n smallest = num\n \n return smallest", "matching_cluster_idx": 3}, {"solution": "def smallest_num(lst):\n # Initialize the minimum with the first element of the list\n min_num = lst[0]\n \n # Iterate through the list to find the smallest number\n for num in lst:\n if num < min_num:\n min_num = num\n \n return min_num", "matching_cluster_idx": 3}, {"solution": "def smallest_num(lst):\n # Check if the list is empty\n if not lst:\n return None # or raise an error, depending on the desired behavior\n \n # Initialize the smallest number with the first element of the list\n smallest = lst[0]\n \n # Iterate through the list to find the smallest number\n for num in lst:\n if num < smallest:\n smallest = num\n \n return smallest", "matching_cluster_idx": 3}, {"solution": "def smallest_num(lst):\n # Check if the list is empty to avoid calling min() on an empty list\n if not lst:\n return None\n # Use the min() function to find the smallest number in the list\n return min(lst)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(lst):\n # Use the min function to find the smallest number in the list\n return min(lst)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(numbers):\n # Use the min function to find the smallest number in the list\n return min(numbers)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(lst):\n # Use the min function to find the smallest number in the list\n return min(lst)", "matching_cluster_idx": 4}]}, "Mbpp/75": {"dps": 92.85714285714286, "dps_norm": 66.66666666666667, "pass@1": 100.0, "profiled": [{"solution": "def find_tuples(test_list, K):\n # Initialize an empty list to store the result\n res = []\n \n # Iterate through each tuple in the list\n for tup in test_list:\n # Check if all elements in the tuple are divisible by K\n if all(ele % K == 0 for ele in tup):\n # If so, add the tuple to the result list\n res.append(tup)\n \n return res", "matching_cluster_idx": 5}, {"solution": "def find_tuples(test_list, k):\n # Create a result list to store tuples where all elements are divisible by k\n result = []\n # Iterate through each tuple in the test_list\n for tup in test_list:\n # Check if all elements in the tuple are divisible by k\n if all(ele % k == 0 for ele in tup):\n # If true, add the tuple to the result list\n result.append(tup)\n # Return the result list\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(test_list, K):\n # Initialize an empty list to store the result\n result = []\n \n # Iterate through each tuple in the list\n for tup in test_list:\n # Check if all elements in the tuple are divisible by K\n if all(x % K == 0 for x in tup):\n # If so, add the tuple to the result list\n result.append(tup)\n \n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(test_list, K):\n # Initialize an empty list to store the result\n result = []\n \n # Iterate through each tuple in the list\n for tuple_ in test_list:\n # Check if all elements in the tuple are divisible by K\n if all(element % K == 0 for element in tuple_):\n # If so, add the tuple to the result list\n result.append(tuple_)\n \n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(test_list, K):\n # Initialize an empty list to store the result\n res = []\n # Iterate through each tuple in the given list\n for tup in test_list:\n # Use a generator expression to check if all elements in the tuple are divisible by K\n if all(ele % K == 0 for ele in tup):\n # If all elements are divisible by K, append the tuple to the result list\n res.append(tup)\n # Return the final list of tuples\n return res", "matching_cluster_idx": 5}, {"solution": "def find_tuples(test_list, K):\n # Initialize an empty list to store the result\n res = []\n \n # Iterate through each tuple in the list\n for tup in test_list:\n # Check if all elements in the tuple are divisible by K\n if all(ele % K == 0 for ele in tup):\n # If so, add the tuple to the result list\n res.append(tup)\n \n return res", "matching_cluster_idx": 5}, {"solution": "def find_tuples(test_list, K):\n # Filter tuples where all elements are divisible by K\n res = [sub for sub in test_list if all(ele % K == 0 for ele in sub)]\n return res", "matching_cluster_idx": 5}, {"solution": "def find_tuples(test_list, K):\n # Create a new list to store tuples where all elements are divisible by K\n res = []\n # Iterate through each tuple in the list\n for tuple_ in test_list:\n # Check if all elements in the tuple are divisible by K\n if all(x % K == 0 for x in tuple_):\n # If so, add the tuple to the result list\n res.append(tuple_)\n # Return the list of tuples where all elements are divisible by K\n return res", "matching_cluster_idx": 5}, {"solution": "def find_tuples(test_list, K):\n # Initialize an empty list to store the result\n res = []\n # Iterate through each tuple in the list\n for tup in test_list:\n # Check if all elements in the tuple are divisible by K using all() and a generator expression\n if all(ele % K == 0 for ele in tup):\n # If all elements are divisible by K, add the tuple to the result list\n res.append(tup)\n # Return the list of tuples where all elements are divisible by K\n return res", "matching_cluster_idx": 5}, {"solution": "def find_tuples(test_list, K):\n # Filter tuples where all elements are divisible by K\n res = [sub for sub in test_list if all(ele % K == 0 for ele in sub)]\n return res", "matching_cluster_idx": 5}, {"solution": "def find_tuples(test_list, K):\n # Initialize an empty list to store the result\n res = []\n \n # Iterate through each tuple in the provided list\n for tup in test_list:\n # Check if all elements in the tuple are divisible by K\n if all(ele % K == 0 for ele in tup):\n # If so, add the tuple to the result list\n res.append(tup)\n \n # Return the list of tuples that satisfy the condition\n return res", "matching_cluster_idx": 5}, {"solution": "def find_tuples(test_list, K):\n # Initialize an empty list to store tuples where all elements are divisible by K\n res = []\n # Iterate through each tuple in the list\n for tup in test_list:\n # Check if all elements in the tuple are divisible by K\n if all(x % K == 0 for x in tup):\n # If so, add the tuple to the result list\n res.append(tup)\n # Return the list of tuples\n return res", "matching_cluster_idx": 5}, {"solution": "def find_tuples(test_list, k):\n # Create a new list to store tuples where all elements are divisible by k\n res = []\n for tup in test_list:\n # Check if all elements in the tuple are divisible by k\n if all(ele % k == 0 for ele in tup):\n res.append(tup)\n return res", "matching_cluster_idx": 5}, {"solution": "def find_tuples(test_list, K):\n # Filter tuples where all elements are divisible by K\n res = [sub for sub in test_list if all(ele % K == 0 for ele in sub)]\n return res", "matching_cluster_idx": 5}, {"solution": "def find_tuples(test_list, K):\n # Initialize an empty list to store the result\n result = []\n \n # Iterate through each tuple in the list\n for tup in test_list:\n # Check if all elements in the tuple are divisible by K\n if all(ele % K == 0 for ele in tup):\n # If so, add the tuple to the result list\n result.append(tup)\n \n # Return the final result list\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(test_list, k):\n # Initialize an empty list to store the resulting tuples\n res = []\n \n # Iterate through each tuple in the provided list\n for tup in test_list:\n # Check if all elements in the tuple are divisible by k\n if all(ele % k == 0 for ele in tup):\n # If so, add the tuple to the result list\n res.append(tup)\n \n # Return the list of tuples where all elements are divisible by k\n return res", "matching_cluster_idx": 5}, {"solution": "def find_tuples(test_list, k):\n # Create a new list to store tuples that meet the criteria\n result = []\n # Iterate through each tuple in the list\n for tup in test_list:\n # Check if all elements in the tuple are divisible by k\n if all(ele % k == 0 for ele in tup):\n # If so, add the tuple to the result list\n result.append(tup)\n # Return the list of tuples that meet the criteria\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(test_list, K):\n # Initialize an empty list to store the resulting tuples\n res = []\n # Iterate through each tuple in the list\n for tup in test_list:\n # Check if all elements in the tuple are divisible by K\n if all(x % K == 0 for x in tup):\n # If so, add the tuple to the result list\n res.append(tup)\n # Return the list of tuples\n return res", "matching_cluster_idx": 5}, {"solution": "def find_tuples(test_list, k):\n # Filter tuples where all elements are divisible by k\n res = [sub for sub in test_list if all(ele % k == 0 for ele in sub)]\n return res", "matching_cluster_idx": 5}, {"solution": "def find_tuples(test_list, K):\n # Initialize an empty list to store the resulting tuples\n res = []\n \n # Iterate through each tuple in the provided list\n for tup in test_list:\n # Check if all elements in the tuple are divisible by K\n if all(ele % K == 0 for ele in tup):\n # If so, add the tuple to the result list\n res.append(tup)\n \n # Return the list of tuples where all elements are divisible by K\n return res", "matching_cluster_idx": 5}]}, "Mbpp/88": {"dps": 96.56862745098039, "dps_norm": 85.71428571428571, "pass@1": 100.0, "profiled": [{"solution": "def freq_count(lst):\n # Initialize an empty dictionary to store the frequency of each element\n frequency = {}\n \n # Iterate over each element in the list\n for item in lst:\n # If the element is already in the dictionary, increment its count\n if item in frequency:\n frequency[item] += 1\n # Otherwise, add the element to the dictionary with a count of 1\n else:\n frequency[item] = 1\n \n # Return the frequency dictionary\n return frequency", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n # Initialize an empty dictionary to store the frequency of elements\n freq_dict = {}\n \n # Iterate through each element in the list\n for item in lst:\n # If the item is already in the dictionary, increment its count\n if item in freq_dict:\n freq_dict[item] += 1\n # If the item is not in the dictionary, add it with a count of 1\n else:\n freq_dict[item] = 1\n \n return freq_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n # Initialize an empty dictionary to store the frequency of each element\n frequency = {}\n \n # Iterate over each element in the list\n for item in lst:\n # If the element is already in the dictionary, increment its count\n if item in frequency:\n frequency[item] += 1\n # Otherwise, add the element to the dictionary with a count of 1\n else:\n frequency[item] = 1\n \n # Return the frequency dictionary\n return frequency", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n # Initialize an empty dictionary to store the frequency of elements\n freq = {}\n \n # Iterate through the list\n for item in lst:\n # If the item is already in the dictionary, increment its count\n if item in freq:\n freq[item] += 1\n # If the item is not in the dictionary, add it with a count of 1\n else:\n freq[item] = 1\n \n return freq", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n # Initialize an empty dictionary to store the frequency of elements\n freq = {}\n \n # Iterate over each element in the list\n for item in lst:\n # If the element is already in the dictionary, increment its count\n if item in freq:\n freq[item] += 1\n # If the element is not in the dictionary, add it with a count of 1\n else:\n freq[item] = 1\n \n # Return the dictionary containing the frequency of each element\n return freq", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n # Initialize an empty dictionary to store the frequency of elements\n frequency = {}\n \n # Iterate through each element in the list\n for item in lst:\n # If the element is already in the dictionary, increment its count\n if item in frequency:\n frequency[item] += 1\n # If the element is not in the dictionary, add it with a count of 1\n else:\n frequency[item] = 1\n \n # Return the dictionary containing the frequency of each element\n return frequency", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n # Initialize an empty dictionary to store the frequency of each element\n frequency = {}\n \n # Iterate over each element in the list\n for item in lst:\n # If the element is already in the dictionary, increment its count\n if item in frequency:\n frequency[item] += 1\n # If the element is not in the dictionary, add it with a count of 1\n else:\n frequency[item] = 1\n \n # Return the dictionary containing the frequency of each element\n return frequency", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n # Initialize an empty dictionary to store the frequency of elements\n freq = {}\n \n # Iterate through each element in the list\n for item in lst:\n # If the item is already in the dictionary, increment its count\n if item in freq:\n freq[item] += 1\n # If the item is not in the dictionary, add it with a count of 1\n else:\n freq[item] = 1\n \n return freq", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n # Initialize an empty dictionary to store the frequency of each element\n freq_dict = {}\n \n # Iterate over each element in the list\n for item in lst:\n # If the element is already in the dictionary, increment its count\n if item in freq_dict:\n freq_dict[item] += 1\n # Otherwise, add the element to the dictionary with a count of 1\n else:\n freq_dict[item] = 1\n \n return freq_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n # Initialize an empty dictionary to store the frequency of elements\n frequency = {}\n \n # Iterate over each element in the list\n for item in lst:\n # If the element is already in the dictionary, increment its count\n if item in frequency:\n frequency[item] += 1\n # If the element is not in the dictionary, add it with a count of 1\n else:\n frequency[item] = 1\n \n # Return the frequency dictionary\n return frequency", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n # Initialize an empty dictionary to store the frequency of elements\n frequency = {}\n \n # Iterate over each element in the list\n for item in lst:\n # If the element is already in the dictionary, increment its count\n if item in frequency:\n frequency[item] += 1\n # Otherwise, add the element to the dictionary with a count of 1\n else:\n frequency[item] = 1\n \n # Return the frequency dictionary\n return frequency", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n # Initialize an empty dictionary to store the frequency of each element\n frequency = {}\n \n # Iterate over each element in the list\n for item in lst:\n # If the item is already in the dictionary, increment its count\n if item in frequency:\n frequency[item] += 1\n # If the item is not in the dictionary, add it with a count of 1\n else:\n frequency[item] = 1\n \n return frequency", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n # Initialize an empty dictionary to store the frequency of each element\n frequency = {}\n \n # Iterate through each element in the list\n for item in lst:\n # If the item is already in the dictionary, increment its count\n if item in frequency:\n frequency[item] += 1\n # If the item is not in the dictionary, add it with a count of 1\n else:\n frequency[item] = 1\n \n # Return the dictionary containing the frequency of each element\n return frequency", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n # Initialize an empty dictionary to store the frequency of each element\n frequency = {}\n \n # Iterate over each element in the list\n for item in lst:\n # If the element is already in the dictionary, increment its count\n if item in frequency:\n frequency[item] += 1\n # Otherwise, add the element to the dictionary with a count of 1\n else:\n frequency[item] = 1\n \n # Return the dictionary containing the frequency of each element\n return frequency", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n # Initialize an empty dictionary to store the frequency of elements\n freq = {}\n \n # Iterate over each element in the list\n for item in lst:\n # If the element is already in the dictionary, increment its count\n if item in freq:\n freq[item] += 1\n # If the element is not in the dictionary, add it with a count of 1\n else:\n freq[item] = 1\n \n return freq", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n # Initialize an empty dictionary to store the frequency of each element\n freq = {}\n \n # Iterate over each element in the list\n for item in lst:\n # If the element is already in the dictionary, increment its count\n if item in freq:\n freq[item] += 1\n # Otherwise, add the element to the dictionary with a count of 1\n else:\n freq[item] = 1\n \n return freq", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n # Initialize an empty dictionary to store the frequency of each element\n frequency = {}\n \n # Iterate over each element in the list\n for item in lst:\n # If the element is already in the dictionary, increment its count\n if item in frequency:\n frequency[item] += 1\n # Otherwise, add the element to the dictionary with a count of 1\n else:\n frequency[item] = 1\n \n return frequency", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n # Initialize an empty dictionary to store the frequency of each element\n freq = {}\n \n # Iterate over each element in the list\n for item in lst:\n # If the element is already in the dictionary, increment its count\n if item in freq:\n freq[item] += 1\n # Otherwise, add the element to the dictionary with a count of 1\n else:\n freq[item] = 1\n \n return freq", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n # Initialize an empty dictionary to store the frequency of each element\n frequency = {}\n \n # Iterate over each element in the list\n for item in lst:\n # If the item is already in the dictionary, increment its count\n if item in frequency:\n frequency[item] += 1\n # If the item is not in the dictionary, add it with a count of 1\n else:\n frequency[item] = 1\n \n return frequency", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n # Initialize an empty dictionary to store the frequency of each element\n frequency = {}\n \n # Iterate through each element in the list\n for item in lst:\n # If the element is already in the dictionary, increment its count\n if item in frequency:\n frequency[item] += 1\n # Otherwise, add the element to the dictionary with a count of 1\n else:\n frequency[item] = 1\n \n # Return the dictionary containing the frequency of each element\n return frequency", "matching_cluster_idx": 5}]}, "Mbpp/90": {"dps": 86.6829268292683, "dps_norm": 90.71428571428571, "pass@1": 58.0, "profiled": [{"solution": "def len_log(words):\n # Find the longest word in the list and return its length\n return len(max(words, key=len))", "matching_cluster_idx": 6}, {"solution": "def len_log(words):\n # Find the longest word in the list and return its length\n return len(max(words, key=len))", "matching_cluster_idx": 6}, {"solution": "def len_log(words):\n # Initialize the maximum length to 0\n max_length = 0\n \n # Iterate through each word in the list\n for word in words:\n # Update the maximum length if the current word is longer\n if len(word) > max_length:\n max_length = len(word)\n \n return max_length", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n # Find the longest word in the list and return its length\n return max(len(word) for word in words)", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n # Initialize a variable to keep track of the maximum length\n max_length = 0\n \n # Iterate through each word in the list\n for word in words:\n # Update max_length if the current word's length is greater\n if len(word) > max_length:\n max_length = len(word)\n \n # Return the maximum length found\n return max_length", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n # Find the longest word in the list and return its length\n return len(max(words, key=len))", "matching_cluster_idx": 6}, {"solution": "def len_log(words):\n # Find the longest word in the list and return its length\n return max(len(word) for word in words)", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n # Find the longest word in the list and return its length\n return max(len(word) for word in words)", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n # Find the longest word in the list and return its length\n return max(len(word) for word in words)", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n # Find the longest word by using the max function with key=len\n longest_word = max(words, key=len)\n # Return the length of the longest word\n return len(longest_word)", "matching_cluster_idx": 6}, {"solution": "def len_log(words):\n # Find the longest word in the list and return its length\n longest_word = max(words, key=len)\n return len(longest_word)", "matching_cluster_idx": 6}, {"solution": "def len_log(words):\n # Find the longest word in the list and return its length\n return len(max(words, key=len))", "matching_cluster_idx": 6}, {"solution": "def len_log(words):\n # Find the length of the longest word in the list\n longest_length = 0\n for word in words:\n if len(word) > longest_length:\n longest_length = len(word)\n return longest_length", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n # Find the longest word in the list and return its length\n if not words: # Check if the list is empty\n return 0\n longest_word = max(words, key=len)\n return len(longest_word)", "matching_cluster_idx": 6}, {"solution": "def len_log(words):\n # Find the longest word in the list and return its length\n longest_length = 0\n for word in words:\n if len(word) > longest_length:\n longest_length = len(word)\n return longest_length", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n # Initialize a variable to keep track of the maximum length\n max_length = 0\n \n # Iterate through each word in the list\n for word in words:\n # Update max_length if the current word's length is greater\n if len(word) > max_length:\n max_length = len(word)\n \n # Return the maximum length found\n return max_length", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n # Find the longest word in the list and return its length\n return max(len(word) for word in words)", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n # Find the longest word in the list and return its length\n return max(len(word) for word in words)", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n # Initialize a variable to keep track of the maximum length\n max_length = 0\n \n # Iterate through each word in the list\n for word in words:\n # Update max_length if the current word's length is greater\n if len(word) > max_length:\n max_length = len(word)\n \n # Return the maximum length found\n return max_length", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n # Find the longest word in the list and return its length\n return max(len(word) for word in words)", "matching_cluster_idx": 5}]}, "Mbpp/94": {"dps": 78.04878048780488, "dps_norm": 60.0, "pass@1": 99.0, "profiled": [{"solution": "def index_minimum(test_list):\n # Find the tuple with the smallest second value\n min_tuple = min(test_list, key=lambda x: x[1])\n # Return the first element of that tuple\n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(test_list):\n # Find the tuple with the smallest second value\n min_tuple = min(test_list, key=lambda x: x[1])\n # Return the first value of the found tuple\n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(test_list):\n # Find the tuple with the smallest second value and return its first value\n return min(test_list, key=lambda x: x[1])[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(test_list):\n # Find the tuple with the smallest second value\n min_tuple = min(test_list, key=lambda x: x[1])\n # Return the first value of the found tuple\n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(test_list):\n # Find the tuple with the smallest second value\n min_tuple = min(test_list, key=lambda x: x[1])\n # Return the first value of the found tuple\n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(test_list):\n # Find the tuple with the smallest second value\n min_tuple = min(test_list, key=lambda x: x[1])\n # Return the first element of the tuple with the smallest second value\n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(test_list):\n # Find the tuple with the smallest second value\n min_tuple = min(test_list, key=lambda x: x[1])\n # Return the first value of the found tuple\n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(test_list):\n # Find the tuple with the smallest second value\n min_tuple = min(test_list, key=lambda x: x[1])\n # Return the first element of that tuple\n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(test_list):\n # Find the tuple with the smallest second value and return its first value\n return min(test_list, key=lambda x: x[1])[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(test_list):\n # Find the tuple with the smallest second value and return its first value\n return min(test_list, key=lambda x: x[1])[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(test_list):\n # Find the tuple with the smallest second value\n min_tuple = min(test_list, key=lambda x: x[1])\n # Return the first value of that tuple\n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(test_list):\n # Find the tuple with the smallest second value\n min_tuple = min(test_list, key=lambda x: x[1])\n # Return the first value of the found tuple\n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(test_list):\n # Find the tuple with the smallest second value\n min_tuple = min(test_list, key=lambda x: x[1])\n # Return the first value of that tuple\n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(test_list):\n # Find the tuple with the smallest second value\n min_tuple = min(test_list, key=lambda x: x[1])\n # Return the first value of the found tuple\n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(test_list):\n # Find the tuple with the smallest second value\n min_tuple = min(test_list, key=lambda x: x[1])\n # Return the first value of the found tuple\n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(test_list):\n # Find the tuple with the smallest second value and return its first value\n return min(test_list, key=lambda x: x[1])[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(test_list):\n # Find the tuple with the smallest second value and return its first value\n return min(test_list, key=lambda x: x[1])[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(test_list):\n # Find the tuple with the smallest second value and return its first value\n return min(test_list, key=lambda x: x[1])[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(test_list):\n # Find the tuple with the smallest second value\n min_tuple = min(test_list, key=lambda x: x[1])\n # Return the first value of the tuple with the smallest second value\n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(test_list):\n # Find the tuple with the smallest second value\n min_tuple = min(test_list, key=lambda x: x[1])\n # Return the first value of the found tuple\n return min_tuple[0]", "matching_cluster_idx": 2}]}, "Mbpp/96": {"dps": 77.77777777777777, "dps_norm": 42.857142857142854, "pass@1": 100.0, "profiled": [{"solution": "def divisor(n):\n # Initialize the count of divisors\n count = 0\n # Loop through numbers from 1 to n to check for divisors\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n # Initialize a counter for the divisors\n count = 0\n # Loop through numbers from 1 to n (inclusive)\n for i in range(1, n + 1):\n # If i is a divisor of n, increment the counter\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n # Initialize the count of divisors\n count = 0\n \n # Loop through numbers from 1 to n\n for i in range(1, n + 1):\n # If i is a divisor of n, increment the count\n if n % i == 0:\n count += 1\n \n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n # Initialize count of divisors\n count = 0\n \n # Loop through numbers from 1 to n\n for i in range(1, n + 1):\n # If i is a divisor of n, increment count\n if n % i == 0:\n count += 1\n \n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n # Initialize a count variable to keep track of the number of divisors\n count = 0\n \n # Loop through all numbers from 1 to n (inclusive)\n for i in range(1, n + 1):\n # If i is a divisor of n, increment the count\n if n % i == 0:\n count += 1\n \n # Return the total number of divisors\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n # Initialize a counter to keep track of divisors\n count = 0\n # Loop through all numbers from 1 to n (inclusive)\n for i in range(1, n + 1):\n # If i is a divisor of n, increment the counter\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n # Initialize the count of divisors\n count = 0\n # Loop through all numbers from 1 to n to check for divisors\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n # Initialize a counter for divisors\n count = 0\n # Loop through numbers from 1 to n (inclusive)\n for i in range(1, n + 1):\n # If i is a divisor of n, increment the counter\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n # Initialize the count of divisors\n count = 0\n # Loop through all numbers from 1 to n\n for i in range(1, n + 1):\n # If i is a divisor of n, increment the count\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n # Initialize a counter to count the divisors\n count = 0\n \n # Iterate through numbers from 1 to n (inclusive)\n for i in range(1, n + 1):\n # If i is a divisor of n, increment the counter\n if n % i == 0:\n count += 1\n \n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n # Initialize a counter for the divisors\n count = 0\n # Loop through all numbers from 1 to n to check for divisors\n for i in range(1, n + 1):\n if n % i == 0: # If i is a divisor of n\n count += 1 # Increment the count\n return count # Return the total count of divisors", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n # Initialize the count of divisors\n count = 0\n # Loop through numbers from 1 to n\n for i in range(1, n + 1):\n # If i is a divisor of n, increment the count\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n # Initialize a counter for the divisors\n count = 0\n # Loop through numbers from 1 to n\n for i in range(1, n + 1):\n # If i is a divisor of n, increment the counter\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n # Initialize a counter to keep track of divisors\n count = 0\n # Loop through numbers from 1 to n (inclusive)\n for i in range(1, n + 1):\n # If i is a divisor of n, increment the counter\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n # Initialize a counter to keep track of divisors\n count = 0\n # Loop through numbers from 1 to n\n for i in range(1, n + 1):\n # If i is a divisor of n, increment the counter\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n # Initialize a count variable to store the number of divisors\n count = 0\n \n # Loop through all numbers from 1 to n (inclusive)\n for i in range(1, n + 1):\n # If i is a divisor of n, increment the count\n if n % i == 0:\n count += 1\n \n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n # Initialize a counter to keep track of divisors\n count = 0\n # Loop through numbers from 1 to n (inclusive)\n for i in range(1, n + 1):\n # If i is a divisor of n, increment the counter\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n # Initialize a counter to keep track of the number of divisors\n count = 0\n # Loop through all numbers from 1 to n (inclusive)\n for i in range(1, n + 1):\n # If i is a divisor of n, increment the counter\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n # Initialize the count of divisors to 0\n count = 0\n # Loop through numbers from 1 to n (inclusive)\n for i in range(1, n + 1):\n # If i is a divisor of n, increment the count\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n # Initialize a counter for divisors\n count = 0\n # Loop through numbers from 1 to n (inclusive)\n for i in range(1, n + 1):\n # If i is a divisor of n, increment the count\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}]}, "Mbpp/97": {"dps": 99.6923076923077, "dps_norm": 88.75, "pass@1": 99.0, "profiled": [{"solution": "def frequency_lists(lists):\n # Initialize an empty dictionary to store the frequency of each element\n frequency = {}\n \n # Iterate through each sublist in the list of lists\n for sublist in lists:\n # Iterate through each element in the sublist\n for element in sublist:\n # If the element is already in the dictionary, increment its count\n if element in frequency:\n frequency[element] += 1\n # Otherwise, add the element to the dictionary with a count of 1\n else:\n frequency[element] = 1\n \n # Return the dictionary containing the frequency of each element\n return frequency", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lists):\n # Initialize an empty dictionary to store the frequency of each element\n frequency = {}\n \n # Iterate over each sublist in the list of lists\n for sublist in lists:\n # Iterate over each element in the sublist\n for element in sublist:\n # If the element is already in the dictionary, increment its count\n if element in frequency:\n frequency[element] += 1\n # If the element is not in the dictionary, add it with a count of 1\n else:\n frequency[element] = 1\n \n return frequency", "matching_cluster_idx": 6}, {"solution": "from collections import Counter\nfrom typing import List, Dict\ndef frequency_lists(lists: List[List[int]]) -> Dict[int, int]:\n # Flatten the list of lists and count the frequency of each element\n flattened_list = [item for sublist in lists for item in sublist]\n frequency_dict = dict(Counter(flattened_list))\n return frequency_dict", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lists):\n # Initialize an empty dictionary to store the frequency of each element\n frequency_dict = {}\n \n # Iterate over each sublist in the list of lists\n for sublist in lists:\n # Iterate over each element in the sublist\n for item in sublist:\n # If the item is already in the dictionary, increment its count\n if item in frequency_dict:\n frequency_dict[item] += 1\n # Otherwise, add the item to the dictionary with a count of 1\n else:\n frequency_dict[item] = 1\n \n # Return the dictionary containing the frequency of each element\n return frequency_dict", "matching_cluster_idx": 6}, {"solution": "from collections import Counter\nfrom typing import List, Dict\ndef frequency_lists(lists: List[List[int]]) -> Dict[int, int]:\n # Flatten the list of lists into a single list\n flattened_list = [item for sublist in lists for item in sublist]\n \n # Use Counter to count the frequency of each element\n frequency_dict = dict(Counter(flattened_list))\n \n return frequency_dict", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lists):\n # Initialize an empty dictionary to store the frequency of each element\n frequency = {}\n \n # Iterate through each list in the list of lists\n for sublist in lists:\n # Iterate through each element in the sublist\n for element in sublist:\n # If the element is already in the dictionary, increment its count\n if element in frequency:\n frequency[element] += 1\n # Otherwise, add the element to the dictionary with a count of 1\n else:\n frequency[element] = 1\n \n return frequency", "matching_cluster_idx": 6}, {"solution": "from collections import Counter\nfrom typing import List, Dict\ndef frequency_lists(lists: List[List[int]]) -> Dict[int, int]:\n # Flatten the list of lists using a list comprehension\n flattened_list = [item for sublist in lists for item in sublist]\n \n # Use Counter to count the frequency of each element\n frequency = Counter(flattened_list)\n \n # Convert Counter object to a dictionary\n return dict(frequency)", "matching_cluster_idx": 6}, {"solution": "from collections import Counter\nfrom typing import List, Dict\ndef frequency_lists(lists: List[List[int]]) -> Dict[int, int]:\n # Flatten the list of lists into a single list\n flattened_list = [item for sublist in lists for item in sublist]\n \n # Use Counter to count the frequency of each element\n frequency = Counter(flattened_list)\n \n # Convert the Counter object to a dictionary\n return dict(frequency)", "matching_cluster_idx": 6}, {"solution": "from collections import Counter\ndef frequency_lists(lists):\n # Flatten the list of lists and count the frequency of each element\n return dict(Counter(item for sublist in lists for item in sublist))", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lists):\n # Initialize an empty dictionary to store the frequency of each element\n frequency_dict = {}\n \n # Iterate over each sublist in the list of lists\n for sublist in lists:\n # Iterate over each element in the sublist\n for element in sublist:\n # If the element is already in the dictionary, increment its count\n if element in frequency_dict:\n frequency_dict[element] += 1\n # Otherwise, add the element to the dictionary with a count of 1\n else:\n frequency_dict[element] = 1\n \n return frequency_dict", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lists):\n # Initialize an empty dictionary to store the frequency of each element\n frequency = {}\n \n # Iterate through each sublist in the list of lists\n for sublist in lists:\n # Iterate through each element in the sublist\n for element in sublist:\n # If the element is already in the dictionary, increment its count\n if element in frequency:\n frequency[element] += 1\n # Otherwise, add the element to the dictionary with a count of 1\n else:\n frequency[element] = 1\n \n return frequency", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lists):\n # Initialize an empty dictionary to store the frequency of each element\n frequency = {}\n \n # Iterate through each list in the list of lists\n for sublist in lists:\n # Iterate through each element in the sublist\n for item in sublist:\n # If the item is already in the dictionary, increment its count\n if item in frequency:\n frequency[item] += 1\n # Otherwise, add the item to the dictionary with a count of 1\n else:\n frequency[item] = 1\n \n return frequency", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lists):\n # Create an empty dictionary to store the frequency of each element\n frequency_dict = {}\n \n # Iterate over each sublist in the list of lists\n for sublist in lists:\n # Iterate over each element in the sublist\n for element in sublist:\n # If the element is already in the dictionary, increment its count\n if element in frequency_dict:\n frequency_dict[element] += 1\n # If the element is not in the dictionary, add it with a count of 1\n else:\n frequency_dict[element] = 1\n \n return frequency_dict", "matching_cluster_idx": 6}, {"solution": "from collections import Counter\nfrom itertools import chain\ndef frequency_lists(lists):\n # Flatten the list of lists and count the frequency of each element\n frequency_dict = dict(Counter(chain(*lists)))\n return frequency_dict", "matching_cluster_idx": 7}, {"solution": "def frequency_lists(lists):\n # Initialize an empty dictionary to store the frequency of each element\n frequency = {}\n \n # Iterate through each list in the list of lists\n for sublist in lists:\n # Iterate through each element in the sublist\n for element in sublist:\n # If the element is already in the dictionary, increment its count\n if element in frequency:\n frequency[element] += 1\n # Otherwise, add the element to the dictionary with a count of 1\n else:\n frequency[element] = 1\n \n return frequency", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lists):\n # Initialize an empty dictionary to store the frequency of each element\n frequency = {}\n \n # Iterate over each sublist in the list of lists\n for sublist in lists:\n # Iterate over each element in the sublist\n for element in sublist:\n # If the element is already in the dictionary, increment its count\n if element in frequency:\n frequency[element] += 1\n # If the element is not in the dictionary, add it with a count of 1\n else:\n frequency[element] = 1\n \n return frequency", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lists):\n # Initialize an empty dictionary to store the frequency of each element\n frequency = {}\n \n # Iterate over each sublist in the list of lists\n for sublist in lists:\n # Iterate over each element in the sublist\n for element in sublist:\n # If the element is already in the dictionary, increment its count\n if element in frequency:\n frequency[element] += 1\n # Otherwise, add the element to the dictionary with a count of 1\n else:\n frequency[element] = 1\n \n # Return the dictionary containing the frequency of each element\n return frequency", "matching_cluster_idx": 6}, {"solution": "from collections import Counter\nfrom typing import List, Dict\ndef frequency_lists(lists: List[List[int]]) -> Dict[int, int]:\n # Flatten the list of lists using a list comprehension\n flattened_list = [item for sublist in lists for item in sublist]\n \n # Use Counter to count the frequency of each element in the flattened list\n frequency_dict = dict(Counter(flattened_list))\n \n return frequency_dict", "matching_cluster_idx": 6}, {"solution": "from collections import Counter\ndef frequency_lists(lists):\n # Flatten the list of lists into a single list\n flat_list = [item for sublist in lists for item in sublist]\n # Count the frequency of each element in the flattened list\n frequency_dict = dict(Counter(flat_list))\n return frequency_dict", "matching_cluster_idx": 6}, {"solution": "from collections import Counter\nfrom itertools import chain\ndef frequency_lists(lists):\n # Flatten the list of lists and count the frequency of each element\n return dict(Counter(chain.from_iterable(lists)))", "matching_cluster_idx": 7}]}, "Mbpp/106": {"dps": 15.681818181818182, "dps_norm": 62.5, "pass@1": 100.0, "profiled": [{"solution": "def add_lists(lst, tpl):\n # Convert the tuple to a list, append the given list, and convert back to a tuple\n return tuple(list(tpl) + lst)", "matching_cluster_idx": 2}, {"solution": "def add_lists(lst, tpl):\n # Convert the tuple to a list, append the given list, and convert it back to a tuple\n return tuple(list(tpl) + lst)", "matching_cluster_idx": 2}, {"solution": "def add_lists(lst, tup):\n # Convert the tuple to a list, append the new list, and convert back to a tuple\n result = list(tup) + lst\n return tuple(result)", "matching_cluster_idx": 2}, {"solution": "def add_lists(lst, tpl):\n # Convert the tuple to a list\n tpl_list = list(tpl)\n # Extend the converted list with the given list\n tpl_list.extend(lst)\n # Convert the list back to a tuple\n result = tuple(tpl_list)\n return result", "matching_cluster_idx": 4}, {"solution": "def add_lists(lst, tpl):\n # Convert the tuple to a list to allow modification\n tpl_list = list(tpl)\n # Extend the converted list with the given list\n tpl_list.extend(lst)\n # Convert the list back to a tuple\n return tuple(tpl_list)", "matching_cluster_idx": 4}, {"solution": "def add_lists(lst, tpl):\n # Convert the tuple to a list, add the given list, and convert it back to a tuple\n return tuple(list(tpl) + lst)", "matching_cluster_idx": 3}, {"solution": "def add_lists(lst, tpl):\n # Convert the tuple to a list to allow appending\n temp_list = list(tpl)\n # Extend the temporary list with the given list\n temp_list.extend(lst)\n # Convert the temporary list back to a tuple\n return tuple(temp_list)", "matching_cluster_idx": 4}, {"solution": "def add_lists(lst, tpl):\n # Convert the tuple to a list, append the new list, and convert back to a tuple\n return tuple(list(tpl) + lst)", "matching_cluster_idx": 3}, {"solution": "def add_lists(lst, tpl):\n # Convert the tuple to a list, append the new list, and convert back to a tuple\n result = list(tpl) + lst\n return tuple(result)", "matching_cluster_idx": 2}, {"solution": "def add_lists(lst, tpl):\n # Convert the tuple to a list to allow appending\n tpl_list = list(tpl)\n # Extend the converted list with the given list\n tpl_list.extend(lst)\n # Convert the list back to a tuple and return it\n return tuple(tpl_list)", "matching_cluster_idx": 4}, {"solution": "def add_lists(lst, tpl):\n # Convert the tuple to a list, append the given list, and convert it back to a tuple\n return tuple(list(tpl) + lst)", "matching_cluster_idx": 2}, {"solution": "def add_lists(lst, tpl):\n # Convert the tuple to a list, append the given list, and convert back to a tuple\n return tuple(list(tpl) + lst)", "matching_cluster_idx": 2}, {"solution": "def add_lists(lst, tpl):\n # Convert the tuple to a list, append the given list, and convert back to a tuple\n return tuple(list(tpl) + lst)", "matching_cluster_idx": 2}, {"solution": "def add_lists(lst, tup):\n # Convert the tuple to a list, append the given list, and convert back to a tuple\n result = list(tup) + lst\n return tuple(result)", "matching_cluster_idx": 2}, {"solution": "def add_lists(lst, tup):\n # Convert the tuple to a list to allow appending\n new_tup = list(tup)\n # Extend the new list with the elements from the given list\n new_tup.extend(lst)\n # Convert the list back to a tuple\n return tuple(new_tup)", "matching_cluster_idx": 4}, {"solution": "def add_lists(lst, tup):\n # Convert the tuple to a list, append the given list, and convert it back to a tuple\n result = list(tup) + lst\n return tuple(result)", "matching_cluster_idx": 2}, {"solution": "def add_lists(lst, tpl):\n # Convert the tuple to a list, add the given list, and convert back to a tuple\n return tuple(list(tpl) + lst)", "matching_cluster_idx": 3}, {"solution": "def add_lists(lst, tpl):\n # Convert the tuple to a list, append the given list, and convert back to a tuple\n return tuple(list(tpl) + lst)", "matching_cluster_idx": 2}, {"solution": "def add_lists(lst, tpl):\n # Convert the tuple to a list, append the given list, and convert back to a tuple\n return tuple(list(tpl) + lst)", "matching_cluster_idx": 2}, {"solution": "def add_lists(lst, tpl):\n # Convert the tuple to a list\n tpl_list = list(tpl)\n # Extend the list with the elements of the given list\n tpl_list.extend(lst)\n # Convert the extended list back to a tuple\n return tuple(tpl_list)", "matching_cluster_idx": 4}]}, "Mbpp/108": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def merge_sorted_list(list1, list2, list3):\n # Combine the three lists into one\n combined_list = list1 + list2 + list3\n # Sort the combined list\n sorted_list = sorted(combined_list)\n return sorted_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Combine the three lists\n combined_list = list1 + list2 + list3\n # Sort the combined list\n sorted_list = sorted(combined_list)\n return sorted_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Combine the three lists into one\n combined_list = list1 + list2 + list3\n # Sort the combined list\n sorted_list = sorted(combined_list)\n return sorted_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Combine the three lists\n combined_list = list1 + list2 + list3\n # Sort the combined list\n sorted_list = sorted(combined_list)\n return sorted_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Combine all three lists into one\n combined_list = list1 + list2 + list3\n \n # Sort the combined list\n combined_list.sort()\n \n return combined_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Combine all three lists\n combined_list = list1 + list2 + list3\n \n # Sort the combined list\n sorted_list = sorted(combined_list)\n \n return sorted_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Combine all three lists into one\n combined_list = list1 + list2 + list3\n # Sort the combined list\n sorted_list = sorted(combined_list)\n return sorted_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Combine the three lists into one\n combined_list = list1 + list2 + list3\n # Sort the combined list\n sorted_list = sorted(combined_list)\n return sorted_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Combine the three lists into one\n combined_list = list1 + list2 + list3\n # Sort the combined list\n sorted_list = sorted(combined_list)\n return sorted_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Combine the three lists\n combined_list = list1 + list2 + list3\n # Sort the combined list\n combined_list.sort()\n return combined_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Combine the three lists\n combined_list = list1 + list2 + list3\n # Sort the combined list\n sorted_list = sorted(combined_list)\n return sorted_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Combine the three lists into one\n combined_list = list1 + list2 + list3\n # Sort the combined list\n combined_list.sort()\n return combined_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Combine the three lists into one\n combined_list = list1 + list2 + list3\n \n # Sort the combined list\n combined_list.sort()\n \n return combined_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Merge the three lists\n merged_list = list1 + list2 + list3\n # Sort the merged list\n merged_list.sort()\n return merged_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Combine the three lists into one\n combined_list = list1 + list2 + list3\n # Sort the combined list\n sorted_list = sorted(combined_list)\n return sorted_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Combine the three lists into one\n combined_list = list1 + list2 + list3\n # Sort the combined list\n combined_list.sort()\n return combined_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Merge the three lists\n merged_list = list1 + list2 + list3\n # Sort the merged list\n merged_list.sort()\n return merged_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Combine the three lists into one\n combined_list = list1 + list2 + list3\n # Sort the combined list\n sorted_list = sorted(combined_list)\n return sorted_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Combine the three lists into one\n combined_list = list1 + list2 + list3\n # Sort the combined list\n sorted_list = sorted(combined_list)\n return sorted_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Combine all three lists into one\n combined_list = list1 + list2 + list3\n # Sort the combined list\n sorted_list = sorted(combined_list)\n return sorted_list", "matching_cluster_idx": 10}]}, "Mbpp/111": {"dps": 75.84615384615385, "dps_norm": 83.75, "pass@1": 100.0, "profiled": [{"solution": "def common_in_nested_lists(lists):\n # Use set intersection to find common elements across all sublists\n common_elements = set(lists[0]).intersection(*lists[1:])\n return list(common_elements)", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(lists):\n # Use set intersection to find common elements across all lists\n common_elements = set(lists[0]).intersection(*lists[1:])\n return list(common_elements)", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n # Use set intersection to find common elements\n common_elements = set(nested_lists[0]).intersection(*nested_lists[1:])\n return list(common_elements)", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n # Use set.intersection to find common elements across all nested lists\n common_elements = set.intersection(*map(set, nested_lists))\n return list(common_elements)", "matching_cluster_idx": 5}, {"solution": "def common_in_nested_lists(nested_lists):\n # Use a set to store the common elements\n common_elements = set(nested_lists[0])\n \n # Iterate over the remaining lists\n for lst in nested_lists[1:]:\n # Update the common_elements set by keeping only the elements that are also in the current list\n common_elements.intersection_update(lst)\n \n return list(common_elements)", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n # Use a set to store the common elements starting with the first list\n common_elements = set(nested_lists[0])\n \n # Iterate over the remaining lists\n for lst in nested_lists[1:]:\n # Update the common_elements set by taking the intersection with the current list\n common_elements.intersection_update(lst)\n \n return list(common_elements)", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(lists):\n # Use set intersection to find common elements across all sublists\n common_elements = set(lists[0]).intersection(*lists[1:])\n return list(common_elements)", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(lists):\n # Use set.intersection to find common elements across all lists\n common_elements = set.intersection(*map(set, lists))\n return list(common_elements)", "matching_cluster_idx": 5}, {"solution": "def common_in_nested_lists(nested_lists):\n # Use set intersection to find common elements across all lists\n common_elements = set(nested_lists[0]).intersection(*nested_lists[1:])\n return list(common_elements)", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(lists):\n # Convert each sublist to a set and find the intersection of all sets\n common_elements = set.intersection(*map(set, lists))\n return list(common_elements)", "matching_cluster_idx": 5}, {"solution": "def common_in_nested_lists(lists):\n # Use set intersection to find common elements across all lists\n common_elements = set(lists[0]).intersection(*lists[1:])\n return list(common_elements)", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(lists):\n # Use set intersection to find common elements\n common_elements = set(lists[0]).intersection(*lists[1:])\n return list(common_elements)", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(lists):\n # Use set intersection to find common elements across all lists\n common_elements = set.intersection(*map(set, lists))\n return list(common_elements)", "matching_cluster_idx": 5}, {"solution": "def common_in_nested_lists(lists):\n # Use set intersection to find common elements in all sublists\n common_elements = set(lists[0]).intersection(*lists[1:])\n return list(common_elements)", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(lists):\n # Convert the first list to a set for comparison\n common_elements = set(lists[0])\n \n # Iterate through the rest of the lists\n for lst in lists[1:]:\n # Update the common_elements set by finding intersection with the current list\n common_elements.intersection_update(lst)\n \n # Return the set of common elements\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(lists):\n # Use set.intersection to find common elements across all lists\n common_elements = set(lists[0]).intersection(*lists[1:])\n return list(common_elements)", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n # Use a set to store the common elements\n common_elements = set(nested_lists[0])\n \n # Iterate through the rest of the lists and update the common_elements set\n for lst in nested_lists[1:]:\n common_elements.intersection_update(lst)\n \n return list(common_elements)", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(lists):\n # Use set intersection to find common elements across all lists\n common_elements = set.intersection(*map(set, lists))\n return list(common_elements)", "matching_cluster_idx": 5}, {"solution": "def common_in_nested_lists(lists):\n # Use set intersection to find common elements\n common_elements = set(lists[0]).intersection(*lists[1:])\n return list(common_elements)", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(lists):\n # Convert each sublist into a set to remove duplicates and for easier comparison\n sets = [set(sublist) for sublist in lists]\n \n # Use the intersection method to find common elements across all sets\n common_elements = sets[0].intersection(*sets[1:])\n \n return list(common_elements)", "matching_cluster_idx": 5}]}, "Mbpp/123": {"dps": 99.63619402985074, "dps_norm": 86.07142857142857, "pass@1": 33.0, "profiled": [{"solution": "def amicable_numbers_sum(num):\n # Helper function to calculate the sum of proper divisors of a number\n def sum_of_divisors(n):\n divisors_sum = 1 # Start with 1, which is a proper divisor of all numbers\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n divisors_sum += i\n if i != n // i:\n divisors_sum += n // i\n return divisors_sum\n \n # Initialize the sum of amicable numbers\n amicable_sum = 0\n \n # Iterate through all numbers from 1 to num\n for i in range(1, num + 1):\n # Calculate the sum of proper divisors of i\n sum_div_i = sum_of_divisors(i)\n # Check if sum_div_i is an amicable number with i\n if sum_div_i != i and sum_of_divisors(sum_div_i) == i:\n amicable_sum += i\n \n return amicable_sum", "matching_cluster_idx": 11}, {"solution": "def amicable_numbers_sum(num):\n # Function to calculate the sum of proper divisors of n\n def sum_of_divisors(n):\n divisors_sum = 1 # Start with 1, which is a proper divisor of all integers\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n divisors_sum += i\n if i != n // i:\n divisors_sum += n // i\n return divisors_sum\n \n # Initialize the sum of amicable numbers\n amicable_sum = 0\n \n # Iterate through numbers from 1 to num\n for i in range(2, num + 1):\n # Calculate the sum of proper divisors of i\n sum1 = sum_of_divisors(i)\n # Check if sum1 is different from i and sum1 is within the range\n if sum1 != i and sum1 <= num:\n # Calculate the sum of proper divisors of sum1\n sum2 = sum_of_divisors(sum1)\n # Check if sum2 is equal to i\n if sum2 == i:\n amicable_sum += i\n \n return amicable_sum", "matching_cluster_idx": 11}, {"solution": "def amicable_numbers_sum(num):\n # Function to calculate the sum of proper divisors of a number\n def sum_of_divisors(n):\n total = 1 # Start with 1, which is a proper divisor of any n > 1\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n total += i\n if i != n // i:\n total += n // i\n return total\n \n # Initialize the sum of amicable numbers\n amicable_sum = 0\n \n # Iterate through each number from 2 to num\n for i in range(2, num + 1):\n # Calculate the sum of divisors of i\n sum_div_i = sum_of_divisors(i)\n # Check if sum_div_i is different from i and if i is the sum of divisors of sum_div_i\n if sum_div_i != i and sum_of_divisors(sum_div_i) == i:\n amicable_sum += i\n \n return amicable_sum", "matching_cluster_idx": 11}, {"solution": "def amicable_numbers_sum(num):\n # Function to calculate the sum of proper divisors of a number\n def sum_of_divisors(n):\n total = 1 # Start with 1 because it is a proper divisor of any number\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n total += i\n if i != n // i:\n total += n // i\n return total\n \n # Initialize the sum of amicable numbers\n amicable_sum = 0\n \n # Iterate through numbers from 1 to num\n for i in range(2, num + 1):\n # Calculate the sum of divisors of the current number\n sum_div = sum_of_divisors(i)\n # Check if the sum of divisors is different from the number and if it forms an amicable pair\n if sum_div != i and sum_of_divisors(sum_div) == i:\n amicable_sum += i\n \n return amicable_sum", "matching_cluster_idx": 11}, {"solution": "def amicable_numbers_sum(num):\n # Function to calculate the sum of proper divisors of a given number\n def sum_of_divisors(n):\n divisors_sum = 1 # 1 is a proper divisor of all numbers\n for i in range(2, int(n ** 0.5) + 1):\n if n % i == 0:\n divisors_sum += i\n if i != n // i:\n divisors_sum += n // i\n return divisors_sum\n \n # Initialize the sum of amicable numbers\n amicable_sum = 0\n \n # Iterate through all numbers from 1 to num\n for i in range(2, num + 1):\n # Calculate the sum of proper divisors of i\n sum1 = sum_of_divisors(i)\n # Calculate the sum of proper divisors of sum1\n sum2 = sum_of_divisors(sum1)\n # Check if they are amicable numbers and not the same number\n if sum2 == i and sum1 != i:\n amicable_sum += i\n \n return amicable_sum", "matching_cluster_idx": 11}, {"solution": "def amicable_numbers_sum(num):\n # Function to calculate the sum of proper divisors of a number\n def sum_of_divisors(n):\n total = 1 # Start with 1, which is a proper divisor of all integers\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n total += i\n if i != n // i:\n total += n // i\n return total\n \n # Initialize the sum of amicable numbers\n amicable_sum = 0\n \n # Iterate through each number from 1 to num\n for i in range(2, num + 1):\n # Calculate the sum of proper divisors of i\n sum_div_i = sum_of_divisors(i)\n # Check if sum_div_i is different from i and if i is the sum of proper divisors of sum_div_i\n if sum_div_i != i and sum_of_divisors(sum_div_i) == i:\n amicable_sum += i\n \n return amicable_sum", "matching_cluster_idx": 11}, {"solution": "def amicable_numbers_sum(n):\n # Function to calculate the sum of proper divisors of a number\n def sum_of_divisors(x):\n total = 1 # Start with 1 because it is a proper divisor of every number\n for i in range(2, int(x**0.5) + 1):\n if x % i == 0:\n total += i\n if i != x // i:\n total += x // i\n return total\n \n # Initialize the sum of amicable numbers\n amicable_sum = 0\n \n # Iterate through numbers from 1 to n\n for i in range(2, n + 1):\n # Calculate the sum of proper divisors of the current number\n sum_div = sum_of_divisors(i)\n # Check if the sum of proper divisors is different from the current number\n if sum_div != i and sum_of_divisors(sum_div) == i:\n # If it is an amicable number, add it to the sum\n amicable_sum += i\n \n return amicable_sum", "matching_cluster_idx": 11}, {"solution": "def amicable_numbers_sum(num):\n # Function to calculate the sum of proper divisors of n\n def sum_of_divisors(n):\n total = 1 # Start with 1 because it is a proper divisor of any number\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n total += i\n if i != n // i:\n total += n // i\n return total\n \n # Set to store amicable numbers\n amicable_numbers = set()\n \n # Loop through each number from 2 to num\n for i in range(2, num + 1):\n sum_div_i = sum_of_divisors(i)\n if sum_div_i > i and sum_of_divisors(sum_div_i) == i:\n amicable_numbers.add(i)\n amicable_numbers.add(sum_div_i)\n \n # Return the sum of all amicable numbers found\n return sum(amicable_numbers)", "matching_cluster_idx": 11}, {"solution": "def amicable_numbers_sum(num):\n # Initialize the sum of amicable numbers\n amicable_sum = 0\n \n # Helper function to calculate the sum of proper divisors of a number\n def sum_of_divisors(n):\n divisors_sum = 1 # Start with 1, which is a proper divisor of all numbers\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n divisors_sum += i\n if i != n // i:\n divisors_sum += n // i\n return divisors_sum\n \n # Iterate through each number from 1 to num\n for i in range(2, num + 1):\n # Calculate the sum of proper divisors of i\n sum_div_i = sum_of_divisors(i)\n # Check if the sum of proper divisors of sum_div_i equals i and they are not the same number\n if sum_div_i != i and sum_of_divisors(sum_div_i) == i:\n amicable_sum += i\n \n return amicable_sum", "matching_cluster_idx": 11}, {"solution": "def amicable_numbers_sum(num):\n # Helper function to calculate the sum of divisors of a number\n def sum_of_divisors(n):\n total = 1 # Start with 1, which is a divisor of any number\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n total += i\n if i != n // i:\n total += n // i\n return total\n \n # Initialize the sum of amicable numbers\n amicable_sum = 0\n \n # Iterate through numbers from 1 to num\n for i in range(1, num + 1):\n # Calculate the sum of divisors of the current number\n sum_div_i = sum_of_divisors(i)\n # Check if the sum of divisors is different from the current number\n if sum_div_i != i:\n # Calculate the sum of divisors of the sum of divisors\n sum_div_sum_div_i = sum_of_divisors(sum_div_i)\n # Check if the sum of divisors of the sum of divisors equals the current number\n if sum_div_sum_div_i == i:\n # If so, add the current number to the sum of amicable numbers\n amicable_sum += i\n \n return amicable_sum", "matching_cluster_idx": 11}, {"solution": "def amicable_numbers_sum(n):\n # Function to calculate the sum of proper divisors of a number\n def sum_of_divisors(x):\n total = 1 # Start with 1, which is a proper divisor of any number\n for i in range(2, int(x**0.5) + 1):\n if x % i == 0:\n total += i\n if i != x // i:\n total += x // i\n return total\n \n # Initialize the sum of amicable numbers\n amicable_sum = 0\n \n # Iterate through numbers from 2 to n\n for num in range(2, n + 1):\n # Calculate the sum of proper divisors of the current number\n sum_div = sum_of_divisors(num)\n \n # Check if the sum of proper divisors of sum_div equals the current number\n # and that the current number is not equal to sum_div\n if sum_div > 1 and sum_div <= n and sum_of_divisors(sum_div) == num and sum_div != num:\n amicable_sum += num\n \n return amicable_sum", "matching_cluster_idx": 11}, {"solution": "def amicable_numbers_sum(num):\n # Function to calculate the sum of proper divisors of n\n def sum_of_divisors(n):\n total = 1 # Start with 1, which is a proper divisor of all integers\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n total += i\n if i != n // i: # Avoid adding the square root twice for perfect squares\n total += n // i\n return total\n \n # Initialize the sum of amicable numbers\n amicable_sum = 0\n \n # Iterate through all numbers up to the given number\n for i in range(2, num + 1):\n # Calculate the sum of proper divisors of the current number\n sum_div = sum_of_divisors(i)\n # Check if the sum of proper divisors is a different number and forms an amicable pair\n if sum_div != i and sum_of_divisors(sum_div) == i:\n amicable_sum += i\n \n return amicable_sum", "matching_cluster_idx": 11}, {"solution": "def amicable_numbers_sum(num):\n # Helper function to calculate the sum of proper divisors of a number\n def sum_of_divisors(n):\n divisors_sum = 1 # Start with 1, which is a proper divisor of any n > 1\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n divisors_sum += i\n if i != n // i:\n divisors_sum += n // i\n return divisors_sum\n \n # Initialize the sum of amicable numbers\n amicable_sum = 0\n \n # Iterate through numbers from 2 to num\n for i in range(2, num + 1):\n # Calculate the sum of proper divisors of i\n sum_div_i = sum_of_divisors(i)\n # Check if sum_div_i is different from i and if it is an amicable number\n if sum_div_i != i and sum_of_divisors(sum_div_i) == i:\n amicable_sum += i\n \n return amicable_sum", "matching_cluster_idx": 11}, {"solution": "def amicable_numbers_sum(num):\n # Function to calculate the sum of proper divisors of n\n def sum_of_divisors(n):\n total = 1 # 1 is a proper divisor of all numbers\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n total += i\n if i != n // i:\n total += n // i\n return total\n \n # Initialize the sum of amicable numbers\n amicable_sum = 0\n \n # Iterate through all numbers from 1 to num\n for i in range(2, num + 1):\n # Calculate the sum of proper divisors of i\n sum_div_i = sum_of_divisors(i)\n \n # Check if the sum of proper divisors of sum_div_i equals i and i is not equal to sum_div_i\n if sum_div_i != i and sum_of_divisors(sum_div_i) == i:\n amicable_sum += i\n \n return amicable_sum", "matching_cluster_idx": 11}, {"solution": "def amicable_numbers_sum(num):\n # Function to compute the sum of proper divisors of a given number\n def sum_proper_divisors(n):\n divisors_sum = 1 # Start with 1, which is a proper divisor of all numbers\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n divisors_sum += i\n if i != n // i:\n divisors_sum += n // i\n return divisors_sum\n \n # Initialize the sum of amicable numbers\n amicable_sum = 0\n \n # Iterate through numbers from 1 to num\n for i in range(2, num + 1):\n # Calculate the sum of proper divisors of i\n sum_divisors_i = sum_proper_divisors(i)\n # Check if the sum of proper divisors of sum_divisors_i equals i and i is not equal to sum_divisors_i\n if i != sum_divisors_i and sum_proper_divisors(sum_divisors_i) == i:\n amicable_sum += i\n \n return amicable_sum", "matching_cluster_idx": 11}, {"solution": "def amicable_numbers_sum(num):\n # Initialize a list to store the sum of divisors for each number\n divisors_sum = [0] * (num + 1)\n \n # Calculate the sum of divisors for each number from 1 to num\n for i in range(1, num + 1):\n for j in range(i * 2, num + 1, i):\n divisors_sum[j] += i\n \n # Initialize the sum of amicable numbers\n amicable_sum = 0\n \n # Check for amicable pairs and sum them\n for i in range(1, num + 1):\n if divisors_sum[i] <= num and divisors_sum[i] != i and divisors_sum[divisors_sum[i]] == i:\n amicable_sum += i\n \n return amicable_sum", "matching_cluster_idx": 12}, {"solution": "def amicable_numbers_sum(num):\n # Function to calculate the sum of proper divisors of n\n def sum_of_divisors(n):\n divisors_sum = 1 # Start with 1, which is a proper divisor of any n > 1\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n divisors_sum += i\n if i != n // i: # Avoid adding the square root twice for perfect squares\n divisors_sum += n // i\n return divisors_sum\n \n amicable_sum = 0\n for i in range(2, num + 1):\n # Calculate the sum of proper divisors of i\n sum_div_i = sum_of_divisors(i)\n # Check if sum_div_i is an amicable pair with i\n if sum_div_i > i and sum_of_divisors(sum_div_i) == i:\n amicable_sum += i + sum_div_i\n \n return amicable_sum", "matching_cluster_idx": 11}, {"solution": "def amicable_numbers_sum(num):\n # Function to calculate the sum of divisors of a number\n def sum_of_divisors(n):\n total = 1 # Start with 1 as it is a divisor of all numbers\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n total += i\n if i != n // i:\n total += n // i\n return total\n \n # Initialize the sum of amicable numbers\n amicable_sum = 0\n \n # Iterate through numbers from 1 to num\n for i in range(2, num + 1):\n # Calculate the sum of divisors of the current number\n sum_div = sum_of_divisors(i)\n # Check if the sum of divisors is different from the current number and is within the range\n if sum_div != i and sum_div <= num:\n # Calculate the sum of divisors of the sum of divisors\n sum_div_div = sum_of_divisors(sum_div)\n # Check if the sum of divisors of the sum of divisors equals the current number\n if sum_div_div == i:\n amicable_sum += i\n \n return amicable_sum", "matching_cluster_idx": 11}, {"solution": "def amicable_numbers_sum(num):\n # Helper function to calculate the sum of proper divisors of a number\n def sum_of_divisors(n):\n divisors_sum = 1 # Start with 1 as it is a proper divisor\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n divisors_sum += i\n if i != n // i:\n divisors_sum += n // i\n return divisors_sum\n \n # Initialize the sum of amicable numbers\n amicable_sum = 0\n \n # Iterate through each number from 1 to num\n for i in range(2, num + 1):\n # Calculate the sum of proper divisors of the current number\n sum_div_i = sum_of_divisors(i)\n \n # Check if the sum of proper divisors is different from the current number\n if sum_div_i != i:\n # Calculate the sum of proper divisors of the sum of proper divisors\n sum_div_sum_div_i = sum_of_divisors(sum_div_i)\n \n # Check if the current number is an amicable number\n if sum_div_sum_div_i == i:\n amicable_sum += i\n \n return amicable_sum", "matching_cluster_idx": 11}, {"solution": "def amicable_numbers_sum(num):\n # Function to calculate the sum of proper divisors of a number\n def sum_of_divisors(n):\n total = 1 # 1 is a proper divisor of any number\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n total += i\n if i != n // i:\n total += n // i\n return total\n \n # Set to store amicable numbers\n amicable_set = set()\n \n # Loop through each number from 2 to num\n for i in range(2, num + 1):\n # Calculate the sum of proper divisors of i\n sum_div_i = sum_of_divisors(i)\n # Check if sum_div_i is an amicable number with i\n if sum_div_i > i and sum_of_divisors(sum_div_i) == i:\n amicable_set.add(i)\n amicable_set.add(sum_div_i)\n \n # Return the sum of all unique amicable numbers found\n return sum(amicable_set)", "matching_cluster_idx": 11}]}, "Mbpp/128": {"dps": 99.5475113122172, "dps_norm": 80.0, "pass@1": 100.0, "profiled": [{"solution": "def long_words(n, word_list):\n # Split the input string into a list of words\n words = word_list.split()\n \n # Use list comprehension to filter words longer than n characters\n long_words_list = [word for word in words if len(word) > n]\n \n return long_words_list", "matching_cluster_idx": 3}, {"solution": "def long_words(n, string):\n # Split the string into a list of words\n words = string.split()\n # Filter words that are longer than n characters\n long_words_list = [word for word in words if len(word) > n]\n return long_words_list", "matching_cluster_idx": 3}, {"solution": "def long_words(n, string):\n # Split the string into a list of words\n words = string.split()\n \n # Filter words that are longer than n characters\n long_words_list = [word for word in words if len(word) > n]\n \n return long_words_list", "matching_cluster_idx": 3}, {"solution": "def long_words(n, word_list):\n # Split the input string into a list of words\n words = word_list.split()\n \n # Filter the words that have more than n characters\n long_words_list = [word for word in words if len(word) > n]\n \n return long_words_list", "matching_cluster_idx": 3}, {"solution": "def long_words(n, word_list):\n # Initialize an empty list to store words longer than n characters\n result = []\n \n # Split the input string into a list of words\n words = word_list.split()\n \n # Iterate through each word in the list\n for word in words:\n # Check if the length of the word is greater than n\n if len(word) > n:\n # If so, add the word to the result list\n result.append(word)\n \n # Return the list of words longer than n characters\n return result", "matching_cluster_idx": 3}, {"solution": "def long_words(n, word_list):\n # Split the input string into a list of words\n words = word_list.split()\n \n # Filter words that are longer than n characters\n long_words_list = [word for word in words if len(word) > n]\n \n return long_words_list", "matching_cluster_idx": 3}, {"solution": "def long_words(n, word_list):\n # Split the input string into a list of words\n words = word_list.split()\n # Use a list comprehension to filter out words shorter than or equal to n characters\n long_words_list = [word for word in words if len(word) > n]\n return long_words_list", "matching_cluster_idx": 3}, {"solution": "def long_words(n, word_list):\n # Initialize an empty list to store words longer than n characters\n longer_words = []\n \n # Split the input string into individual words\n words = word_list.split()\n \n # Iterate through each word in the list\n for word in words:\n # Check if the length of the word is greater than n\n if len(word) > n:\n # If true, append the word to the longer_words list\n longer_words.append(word)\n \n # Return the list of words longer than n characters\n return longer_words", "matching_cluster_idx": 3}, {"solution": "def long_words(n, word_list):\n # Split the input string into a list of words\n words = word_list.split()\n # Filter words that are longer than n characters\n long_words_list = [word for word in words if len(word) > n]\n return long_words_list", "matching_cluster_idx": 3}, {"solution": "def long_words(n, word_list):\n # Split the input string into a list of words\n words = word_list.split()\n \n # Filter words that are longer than n characters\n long_words_list = [word for word in words if len(word) > n]\n \n return long_words_list", "matching_cluster_idx": 3}, {"solution": "def long_words(n, lst):\n # Use a list comprehension to filter words longer than n characters\n return [word for word in lst.split() if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, word_list):\n # Initialize an empty list to store words longer than n characters\n longer_words = []\n \n # Split the input string into a list of words\n words = word_list.split()\n \n # Iterate through each word in the list\n for word in words:\n # Check if the length of the word is greater than n\n if len(word) > n:\n # If so, add the word to the longer_words list\n longer_words.append(word)\n \n # Return the list of words longer than n characters\n return longer_words", "matching_cluster_idx": 3}, {"solution": "def long_words(n, word_list):\n # Split the input string into a list of words\n words = word_list.split()\n # Filter and return words longer than n characters\n return [word for word in words if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, word_list):\n # Use a list comprehension to filter words longer than n characters\n result = [word for word in word_list.split() if len(word) > n]\n return result", "matching_cluster_idx": 3}, {"solution": "def long_words(n, string):\n # Split the input string into a list of words\n words = string.split()\n # Filter the words based on the length criteria\n long_words_list = [word for word in words if len(word) > n]\n return long_words_list", "matching_cluster_idx": 3}, {"solution": "def long_words(n, word_list):\n # Initialize an empty list to store words longer than n characters\n longer_words = []\n \n # Split the input string into a list of words\n words = word_list.split()\n \n # Iterate through each word in the list\n for word in words:\n # Check if the length of the word is greater than n\n if len(word) > n:\n # If so, append the word to the longer_words list\n longer_words.append(word)\n \n # Return the list of words that are longer than n characters\n return longer_words", "matching_cluster_idx": 3}, {"solution": "def long_words(n, string):\n # Split the string into a list of words\n words = string.split()\n \n # Filter words that are longer than n characters\n long_words_list = [word for word in words if len(word) > n]\n \n return long_words_list", "matching_cluster_idx": 3}, {"solution": "def long_words(n, word_list):\n # Split the input string into a list of words\n words = word_list.split()\n # Filter words that are longer than n characters\n longer_words = [word for word in words if len(word) > n]\n return longer_words", "matching_cluster_idx": 3}, {"solution": "def long_words(n, word_list):\n # Use list comprehension to filter words longer than n characters\n result = [word for word in word_list.split() if len(word) > n]\n return result", "matching_cluster_idx": 3}, {"solution": "def long_words(n, word_list):\n # Use list comprehension to filter words longer than n characters\n result = [word for word in word_list.split() if len(word) > n]\n return result", "matching_cluster_idx": 3}]}, "Mbpp/129": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def magic_square_test(matrix):\n # Calculate the sum of the first row to use as a reference\n target_sum = sum(matrix[0])\n \n # Check the sum of each row\n for row in matrix:\n if sum(row) != target_sum:\n return False\n \n # Check the sum of each column\n for col in range(len(matrix[0])):\n if sum(matrix[row][col] for row in range(len(matrix))) != target_sum:\n return False\n \n # Check the sum of the main diagonal\n if sum(matrix[i][i] for i in range(len(matrix))) != target_sum:\n return False\n \n # Check the sum of the secondary diagonal\n if sum(matrix[i][len(matrix) - 1 - i] for i in range(len(matrix))) != target_sum:\n return False\n \n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n # Calculate the sum of the first row to set the target sum\n target_sum = sum(matrix[0])\n \n # Check the sum of each row\n for row in matrix:\n if sum(row) != target_sum:\n return False\n \n # Check the sum of each column\n for col in range(len(matrix)):\n if sum(matrix[row][col] for row in range(len(matrix))) != target_sum:\n return False\n \n # Check the sum of the main diagonal\n if sum(matrix[i][i] for i in range(len(matrix))) != target_sum:\n return False\n \n # Check the sum of the secondary diagonal\n if sum(matrix[i][len(matrix) - 1 - i] for i in range(len(matrix))) != target_sum:\n return False\n \n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n # Calculate the sum of the first row to set the target sum\n target_sum = sum(matrix[0])\n \n # Check the sum of each row\n for row in matrix:\n if sum(row) != target_sum:\n return False\n \n # Check the sum of each column\n for col in range(len(matrix)):\n if sum(matrix[row][col] for row in range(len(matrix))) != target_sum:\n return False\n \n # Check the sum of the main diagonal\n if sum(matrix[i][i] for i in range(len(matrix))) != target_sum:\n return False\n \n # Check the sum of the secondary diagonal\n if sum(matrix[i][len(matrix) - 1 - i] for i in range(len(matrix))) != target_sum:\n return False\n \n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n # Calculate the sum of the first row to set as the target sum\n target_sum = sum(matrix[0])\n \n # Check the sums of each row\n for row in matrix:\n if sum(row) != target_sum:\n return False\n \n # Check the sums of each column\n for col in range(len(matrix)):\n if sum(matrix[row][col] for row in range(len(matrix))) != target_sum:\n return False\n \n # Check the sum of the main diagonal\n if sum(matrix[i][i] for i in range(len(matrix))) != target_sum:\n return False\n \n # Check the sum of the secondary diagonal\n if sum(matrix[i][len(matrix) - 1 - i] for i in range(len(matrix))) != target_sum:\n return False\n \n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n # Calculate the sum of the first row to establish the magic constant\n magic_constant = sum(matrix[0])\n \n # Check the sum of each row\n for row in matrix:\n if sum(row) != magic_constant:\n return False\n \n # Check the sum of each column\n for col in range(len(matrix)):\n if sum(matrix[row][col] for row in range(len(matrix))) != magic_constant:\n return False\n \n # Check the sum of the main diagonal\n if sum(matrix[i][i] for i in range(len(matrix))) != magic_constant:\n return False\n \n # Check the sum of the secondary diagonal\n if sum(matrix[i][len(matrix) - 1 - i] for i in range(len(matrix))) != magic_constant:\n return False\n \n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n # Calculate the sum of the first row to use as the reference sum\n magic_sum = sum(matrix[0])\n \n # Check sums of all rows\n for row in matrix:\n if sum(row) != magic_sum:\n return False\n \n # Check sums of all columns\n for col in range(len(matrix)):\n if sum(matrix[row][col] for row in range(len(matrix))) != magic_sum:\n return False\n \n # Check the sum of the main diagonal\n if sum(matrix[i][i] for i in range(len(matrix))) != magic_sum:\n return False\n \n # Check the sum of the secondary diagonal\n if sum(matrix[i][len(matrix) - 1 - i] for i in range(len(matrix))) != magic_sum:\n return False\n \n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n # Calculate the target sum using the first row\n target_sum = sum(matrix[0])\n \n # Check sums of all rows\n for row in matrix:\n if sum(row) != target_sum:\n return False\n \n # Check sums of all columns\n for col in range(len(matrix)):\n if sum(matrix[row][col] for row in range(len(matrix))) != target_sum:\n return False\n \n # Check the main diagonal sum\n if sum(matrix[i][i] for i in range(len(matrix))) != target_sum:\n return False\n \n # Check the secondary diagonal sum\n if sum(matrix[i][len(matrix) - 1 - i] for i in range(len(matrix))) != target_sum:\n return False\n \n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n # Calculate the target sum using the first row\n target_sum = sum(matrix[0])\n \n # Check sums of each row\n for row in matrix:\n if sum(row) != target_sum:\n return False\n \n # Check sums of each column\n for col in range(len(matrix)):\n if sum(matrix[row][col] for row in range(len(matrix))) != target_sum:\n return False\n \n # Check sum of the main diagonal\n if sum(matrix[i][i] for i in range(len(matrix))) != target_sum:\n return False\n \n # Check sum of the secondary diagonal\n if sum(matrix[i][len(matrix) - 1 - i] for i in range(len(matrix))) != target_sum:\n return False\n \n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n # Calculate the sum of the first row to use it as a reference\n magic_sum = sum(matrix[0])\n \n # Check the sum of each row\n for row in matrix:\n if sum(row) != magic_sum:\n return False\n \n # Check the sum of each column\n for col in range(len(matrix)):\n if sum(matrix[row][col] for row in range(len(matrix))) != magic_sum:\n return False\n \n # Check the sum of the main diagonal\n if sum(matrix[i][i] for i in range(len(matrix))) != magic_sum:\n return False\n \n # Check the sum of the secondary diagonal\n if sum(matrix[i][len(matrix) - 1 - i] for i in range(len(matrix))) != magic_sum:\n return False\n \n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n # Calculate the sum of the first row to use as a reference\n magic_sum = sum(matrix[0])\n \n # Check the sums of all rows\n for row in matrix:\n if sum(row) != magic_sum:\n return False\n \n # Check the sums of all columns\n for col in range(len(matrix)):\n if sum(matrix[row][col] for row in range(len(matrix))) != magic_sum:\n return False\n \n # Check the sum of the main diagonal\n if sum(matrix[i][i] for i in range(len(matrix))) != magic_sum:\n return False\n \n # Check the sum of the secondary diagonal\n if sum(matrix[i][len(matrix) - 1 - i] for i in range(len(matrix))) != magic_sum:\n return False\n \n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n # Calculate the sum of the first row to set a target sum\n target_sum = sum(matrix[0])\n \n # Check the sum of each row\n for row in matrix:\n if sum(row) != target_sum:\n return False\n \n # Check the sum of each column\n for col in range(len(matrix)):\n if sum(matrix[row][col] for row in range(len(matrix))) != target_sum:\n return False\n \n # Check the sum of the main diagonal\n if sum(matrix[i][i] for i in range(len(matrix))) != target_sum:\n return False\n \n # Check the sum of the secondary diagonal\n if sum(matrix[i][len(matrix) - 1 - i] for i in range(len(matrix))) != target_sum:\n return False\n \n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n # Calculate the sum of the first row to use as a reference\n target_sum = sum(matrix[0])\n \n # Check the sum of each row\n for row in matrix:\n if sum(row) != target_sum:\n return False\n \n # Check the sum of each column\n for col in range(len(matrix)):\n if sum(matrix[row][col] for row in range(len(matrix))) != target_sum:\n return False\n \n # Check the sum of the main diagonal\n if sum(matrix[i][i] for i in range(len(matrix))) != target_sum:\n return False\n \n # Check the sum of the secondary diagonal\n if sum(matrix[i][len(matrix) - 1 - i] for i in range(len(matrix))) != target_sum:\n return False\n \n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n # Calculate the sum of the first row to set the target sum\n target_sum = sum(matrix[0])\n \n # Check the sum of each row\n for row in matrix:\n if sum(row) != target_sum:\n return False\n \n # Check the sum of each column\n for col in range(len(matrix)):\n if sum(matrix[row][col] for row in range(len(matrix))) != target_sum:\n return False\n \n # Check the sum of the main diagonal\n if sum(matrix[i][i] for i in range(len(matrix))) != target_sum:\n return False\n \n # Check the sum of the secondary diagonal\n if sum(matrix[i][len(matrix) - 1 - i] for i in range(len(matrix))) != target_sum:\n return False\n \n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n # Calculate the sum of the first row to set the target sum\n target_sum = sum(matrix[0])\n \n # Check the sums of all rows\n for row in matrix:\n if sum(row) != target_sum:\n return False\n \n # Check the sums of all columns\n for col in range(len(matrix)):\n if sum(matrix[row][col] for row in range(len(matrix))) != target_sum:\n return False\n \n # Check the sum of the main diagonal\n if sum(matrix[i][i] for i in range(len(matrix))) != target_sum:\n return False\n \n # Check the sum of the secondary diagonal\n if sum(matrix[i][len(matrix) - 1 - i] for i in range(len(matrix))) != target_sum:\n return False\n \n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n # Calculate the sum of the first row to set the magic sum\n magic_sum = sum(matrix[0])\n \n # Check the sums of the rows\n for row in matrix:\n if sum(row) != magic_sum:\n return False\n \n # Check the sums of the columns\n for col in range(len(matrix)):\n if sum(matrix[row][col] for row in range(len(matrix))) != magic_sum:\n return False\n \n # Check the sum of the main diagonal\n if sum(matrix[i][i] for i in range(len(matrix))) != magic_sum:\n return False\n \n # Check the sum of the secondary diagonal\n if sum(matrix[i][len(matrix) - 1 - i] for i in range(len(matrix))) != magic_sum:\n return False\n \n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n # Calculate the sum of the first row to set as the magic constant\n magic_constant = sum(matrix[0])\n \n # Check the sum of each row\n for row in matrix:\n if sum(row) != magic_constant:\n return False\n \n # Check the sum of each column\n for col in range(len(matrix)):\n if sum(matrix[row][col] for row in range(len(matrix))) != magic_constant:\n return False\n \n # Check the sum of the main diagonal\n if sum(matrix[i][i] for i in range(len(matrix))) != magic_constant:\n return False\n \n # Check the sum of the secondary diagonal\n if sum(matrix[i][len(matrix) - 1 - i] for i in range(len(matrix))) != magic_constant:\n return False\n \n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n # Calculate the sum of the first row to use as the reference magic sum\n magic_sum = sum(matrix[0])\n \n # Check the sums of all rows\n for row in matrix:\n if sum(row) != magic_sum:\n return False\n \n # Check the sums of all columns\n for col in range(len(matrix)):\n if sum(matrix[row][col] for row in range(len(matrix))) != magic_sum:\n return False\n \n # Check the sum of the main diagonal\n if sum(matrix[i][i] for i in range(len(matrix))) != magic_sum:\n return False\n \n # Check the sum of the secondary diagonal\n if sum(matrix[i][len(matrix) - 1 - i] for i in range(len(matrix))) != magic_sum:\n return False\n \n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n # Calculate the sum of the first row to set as the target sum\n target_sum = sum(matrix[0])\n \n # Check the sum of each row\n for row in matrix:\n if sum(row) != target_sum:\n return False\n \n # Check the sum of each column\n for col in range(len(matrix)):\n if sum(matrix[row][col] for row in range(len(matrix))) != target_sum:\n return False\n \n # Check the sum of the main diagonal\n if sum(matrix[i][i] for i in range(len(matrix))) != target_sum:\n return False\n \n # Check the sum of the secondary diagonal\n if sum(matrix[i][len(matrix) - 1 - i] for i in range(len(matrix))) != target_sum:\n return False\n \n # If all checks pass, the matrix is a magic square\n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n # Calculate the sum of the first row to set as the target sum\n target_sum = sum(matrix[0])\n \n # Check the sum of each row\n for row in matrix:\n if sum(row) != target_sum:\n return False\n \n # Check the sum of each column\n for col in range(len(matrix)):\n if sum(matrix[row][col] for row in range(len(matrix))) != target_sum:\n return False\n \n # Check the sum of the main diagonal\n if sum(matrix[i][i] for i in range(len(matrix))) != target_sum:\n return False\n \n # Check the sum of the secondary diagonal\n if sum(matrix[i][len(matrix) - 1 - i] for i in range(len(matrix))) != target_sum:\n return False\n \n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n # Calculate the sum of the first row to use as a reference\n magic_sum = sum(matrix[0])\n \n # Check the sum of each row\n for row in matrix:\n if sum(row) != magic_sum:\n return False\n \n # Check the sum of each column\n for col in range(len(matrix)):\n if sum(matrix[row][col] for row in range(len(matrix))) != magic_sum:\n return False\n \n # Check the sum of the main diagonal\n if sum(matrix[i][i] for i in range(len(matrix))) != magic_sum:\n return False\n \n # Check the sum of the secondary diagonal\n if sum(matrix[i][len(matrix) - 1 - i] for i in range(len(matrix))) != magic_sum:\n return False\n \n return True", "matching_cluster_idx": 14}]}, "Mbpp/130": {"dps": 77.10762331838565, "dps_norm": 68.33333333333334, "pass@1": 100.0, "profiled": [{"solution": "def max_occurrences(lst):\n # Create a dictionary to count the frequency of each item in the list\n frequency = {}\n for item in lst:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n \n # Find the item with the maximum frequency\n max_freq_item = max(frequency, key=frequency.get)\n \n return max_freq_item", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(lst):\n # Create a dictionary to store the frequency of each item\n frequency = {}\n for item in lst:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n \n # Find the item with the maximum frequency\n max_item = None\n max_count = 0\n for item, count in frequency.items():\n if count > max_count:\n max_item = item\n max_count = count\n \n return max_item", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(lst):\n # Create a dictionary to count the frequency of each item in the list\n frequency = {}\n for item in lst:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n \n # Find the item with the maximum frequency\n max_item = None\n max_count = 0\n for item, count in frequency.items():\n if count > max_count:\n max_count = count\n max_item = item\n \n return max_item", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(lst):\n # Create a dictionary to count the frequency of each item in the list\n frequency = {}\n for item in lst:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n \n # Find the item with the maximum frequency\n max_item = None\n max_count = 0\n for item, count in frequency.items():\n if count > max_count:\n max_count = count\n max_item = item\n \n return max_item", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(lst):\n # Dictionary to store the frequency of each item\n frequency = {}\n \n # Iterate over the list and count the frequency of each item\n for item in lst:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n \n # Find the item with the maximum frequency\n max_item = None\n max_count = 0\n for item, count in frequency.items():\n if count > max_count:\n max_count = count\n max_item = item\n \n return max_item", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(lst):\n # Dictionary to store the frequency of each item\n frequency = {}\n \n # Iterate over the list and count occurrences of each item\n for item in lst:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n \n # Find the item with the maximum frequency\n max_item = max(frequency, key=frequency.get)\n \n return max_item", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(lst):\n # Dictionary to store the frequency of each item\n frequency = {}\n for item in lst:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n \n # Find the item with the maximum frequency\n max_item = None\n max_count = 0\n for item, count in frequency.items():\n if count > max_count:\n max_item = item\n max_count = count\n \n return max_item", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(lst):\n # Create a dictionary to count occurrences of each item\n frequency = {}\n for item in lst:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n \n # Find the item with the maximum frequency\n max_item = max(frequency, key=frequency.get)\n \n return max_item", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(lst):\n # Initialize an empty dictionary to store the frequency of each item\n frequency = {}\n \n # Iterate over each item in the list\n for item in lst:\n # If the item is already in the dictionary, increment its count\n if item in frequency:\n frequency[item] += 1\n # Otherwise, add the item to the dictionary with a count of 1\n else:\n frequency[item] = 1\n \n # Find the item with the maximum frequency\n max_item = max(frequency, key=frequency.get)\n \n # Return the item with the maximum frequency\n return max_item", "matching_cluster_idx": 3}, {"solution": "from collections import Counter\ndef max_occurrences(lst):\n # Use Counter to count the frequency of each item in the list\n frequency = Counter(lst)\n # Find the item with the maximum frequency\n # If multiple items have the same maximum frequency, return the first one encountered\n max_freq_item = max(frequency, key=frequency.get)\n return max_freq_item", "matching_cluster_idx": 4}, {"solution": "def max_occurrences(lst):\n # Create a dictionary to count the frequency of each item\n frequency = {}\n for item in lst:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n \n # Find the item with the maximum frequency\n max_item = None\n max_count = 0\n for item, count in frequency.items():\n if count > max_count:\n max_item = item\n max_count = count\n \n return max_item", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(lst):\n # Create a dictionary to store the frequency of each item\n frequency = {}\n for item in lst:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n \n # Find the item with the maximum frequency\n max_item = None\n max_count = 0\n for item, count in frequency.items():\n if count > max_count:\n max_count = count\n max_item = item\n \n return max_item", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(lst):\n # Dictionary to store the frequency of each item\n frequency = {}\n \n # Iterate through the list and count the occurrences of each item\n for item in lst:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n \n # Find the item with the maximum frequency\n max_freq_item = max(frequency, key=frequency.get)\n \n return max_freq_item", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(lst):\n # Initialize an empty dictionary to store the frequency of each item\n frequency = {}\n \n # Iterate over the list to count the frequency of each item\n for item in lst:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n \n # Find the item with the maximum frequency\n max_freq_item = max(frequency, key=frequency.get)\n \n return max_freq_item", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(lst):\n # Dictionary to store the frequency of each item\n frequency = {}\n \n # Iterate over the list to populate the frequency dictionary\n for item in lst:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n \n # Find the item with the maximum frequency\n max_item = max(frequency, key=frequency.get)\n \n return max_item", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(lst):\n # Initialize a dictionary to count the occurrences of each item\n count = {}\n \n # Iterate over the list to populate the count dictionary\n for item in lst:\n if item in count:\n count[item] += 1\n else:\n count[item] = 1\n \n # Find the item with the maximum frequency\n max_item = max(count, key=count.get)\n \n return max_item", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(lst):\n # Create a dictionary to count the frequency of each item\n frequency = {}\n for item in lst:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n \n # Find the item with the maximum frequency\n max_item = None\n max_count = 0\n for item, count in frequency.items():\n if count > max_count:\n max_item = item\n max_count = count\n \n return max_item", "matching_cluster_idx": 3}, {"solution": "from collections import Counter\ndef max_occurrences(lst):\n # Count the frequency of each item in the list\n frequency = Counter(lst)\n \n # Find the item with the maximum frequency\n max_item = max(frequency, key=frequency.get)\n \n return max_item", "matching_cluster_idx": 4}, {"solution": "def max_occurrences(lst):\n # Dictionary to store the frequency of each item\n frequency = {}\n \n # Iterate over the list and count the occurrences of each item\n for item in lst:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n \n # Find the item with the maximum frequency\n max_freq_item = max(frequency, key=frequency.get)\n \n return max_freq_item", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(lst):\n # Create a dictionary to count the frequency of each item in the list\n frequency = {}\n for item in lst:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n \n # Find the item with the maximum frequency\n max_item = None\n max_count = 0\n for item, count in frequency.items():\n if count > max_count:\n max_item = item\n max_count = count\n \n return max_item", "matching_cluster_idx": 3}]}, "Mbpp/137": {"dps": 56.29032258064515, "dps_norm": 69.375, "pass@1": 57.0, "profiled": [{"solution": "import math\ndef zero_count(arr):\n # Initialize counters for zeroes and non-zeroes\n zero_count = 0\n non_zero_count = 0\n \n # Iterate through the array to count zeroes and non-zeroes\n for num in arr:\n if num == 0:\n zero_count += 1\n else:\n non_zero_count += 1\n \n # Calculate the ratio of zeroes to non-zeroes\n if non_zero_count == 0:\n return float('inf') # Return infinity if there are no non-zero elements\n else:\n return zero_count / non_zero_count", "matching_cluster_idx": 3}, {"solution": "import math\ndef zero_count(arr):\n # Initialize counters for zeroes and non-zeroes\n zero_count = 0\n non_zero_count = 0\n \n # Iterate through the array to count zeroes and non-zeroes\n for num in arr:\n if num == 0:\n zero_count += 1\n else:\n non_zero_count += 1\n \n # Calculate the ratio of zeroes to non-zeroes\n if non_zero_count == 0:\n return float('inf') # Return infinity if there are no non-zero elements\n else:\n return zero_count / non_zero_count", "matching_cluster_idx": 3}, {"solution": "import math\ndef zero_count(arr):\n # Count the number of zeroes in the array\n zero_count = arr.count(0)\n \n # Calculate the total number of elements in the array\n total_count = len(arr)\n \n # Calculate the number of non-zero elements\n non_zero_count = total_count - zero_count\n \n # Calculate the ratio of zeroes to non-zeroes\n if non_zero_count == 0:\n return float('inf') # Return infinity if there are no non-zero elements\n ratio = zero_count / non_zero_count\n \n return ratio", "matching_cluster_idx": 6}, {"solution": "import math\ndef zero_count(arr):\n # Count the number of zeroes in the array\n zero_count = arr.count(0)\n # Count the number of non-zeroes in the array\n non_zero_count = len(arr) - zero_count\n # Calculate the ratio of zeroes to non-zeroes\n if non_zero_count == 0:\n return float('inf') # Avoid division by zero\n ratio = zero_count / non_zero_count\n return ratio", "matching_cluster_idx": 6}, {"solution": "import math\ndef zero_count(arr):\n # Count the number of zeroes in the array\n zero_count = arr.count(0)\n \n # Count the number of non-zero elements in the array\n non_zero_count = len(arr) - zero_count\n \n # Calculate the ratio of zeroes to non-zeroes\n if non_zero_count == 0:\n return float('inf') # Avoid division by zero\n else:\n ratio = zero_count / non_zero_count\n return ratio", "matching_cluster_idx": 6}, {"solution": "import math\ndef zero_count(arr):\n # Count the number of zeroes in the array\n zero_count = arr.count(0)\n \n # Count the number of non-zero elements in the array\n non_zero_count = len(arr) - zero_count\n \n # Calculate the ratio of zeroes to non-zeroes\n if non_zero_count == 0:\n return float('inf') # Handle the case where there are no non-zero elements\n ratio = zero_count / non_zero_count\n \n return ratio", "matching_cluster_idx": 6}, {"solution": "import math\ndef zero_count(arr):\n # Initialize counters for zeroes and non-zeroes\n zero_count = 0\n non_zero_count = 0\n \n # Iterate through the array to count zeroes and non-zeroes\n for num in arr:\n if num == 0:\n zero_count += 1\n else:\n non_zero_count += 1\n \n # Calculate the ratio of zeroes to non-zeroes\n if non_zero_count == 0:\n return float('inf') # Avoid division by zero\n ratio = zero_count / non_zero_count\n \n return ratio", "matching_cluster_idx": 3}, {"solution": "import math\ndef zero_count(arr):\n # Initialize counters for zeroes and non-zeroes\n zero_count = 0\n non_zero_count = 0\n \n # Iterate through the array to count zeroes and non-zeroes\n for num in arr:\n if num == 0:\n zero_count += 1\n else:\n non_zero_count += 1\n \n # Calculate the ratio of zeroes to non-zeroes\n if non_zero_count == 0:\n return float('inf') # Avoid division by zero\n else:\n ratio = zero_count / non_zero_count\n return ratio", "matching_cluster_idx": 3}, {"solution": "import math\ndef zero_count(arr):\n # Initialize counters for zeroes and non-zeroes\n zero_count = 0\n non_zero_count = 0\n \n # Iterate through the array to count zeroes and non-zeroes\n for num in arr:\n if num == 0:\n zero_count += 1\n else:\n non_zero_count += 1\n \n # Calculate the ratio of zeroes to non-zeroes\n if non_zero_count == 0:\n return float('inf') # Avoid division by zero\n ratio = zero_count / non_zero_count\n \n return ratio", "matching_cluster_idx": 3}, {"solution": "import math\ndef zero_count(arr):\n # Count the number of zeroes in the array\n zero_count = arr.count(0)\n \n # Count the number of non-zero elements in the array\n non_zero_count = len(arr) - zero_count\n \n # Calculate the ratio of zeroes to non-zeroes\n if non_zero_count == 0:\n # If there are no non-zero elements, the ratio is undefined\n return float('inf')\n else:\n ratio = zero_count / non_zero_count\n return ratio", "matching_cluster_idx": 6}, {"solution": "import math\ndef zero_count(arr):\n # Initialize counters for zeroes and non-zeroes\n zero_count = 0\n non_zero_count = 0\n \n # Iterate through the array to count zeroes and non-zeroes\n for num in arr:\n if num == 0:\n zero_count += 1\n else:\n non_zero_count += 1\n \n # Calculate the ratio of zeroes to non-zeroes\n if non_zero_count == 0:\n return float('inf') # Handle the case where there are no non-zero elements\n else:\n return zero_count / non_zero_count", "matching_cluster_idx": 3}, {"solution": "import math\ndef zero_count(arr):\n # Initialize counters for zeroes and non-zeroes\n zero_count = 0\n non_zero_count = 0\n \n # Iterate through the array to count zeroes and non-zeroes\n for num in arr:\n if num == 0:\n zero_count += 1\n else:\n non_zero_count += 1\n \n # Calculate the ratio of zeroes to non-zeroes\n if non_zero_count == 0:\n return float('inf') # Avoid division by zero\n else:\n return zero_count / non_zero_count", "matching_cluster_idx": 3}, {"solution": "import math\ndef zero_count(arr):\n # Count the number of zeroes in the array\n zero_count = arr.count(0)\n \n # Count the number of non-zeroes in the array\n non_zero_count = len(arr) - zero_count\n \n # Calculate the ratio of zeroes to non-zeroes\n if non_zero_count == 0:\n return float('inf') # Return infinity if there are no non-zero elements\n else:\n return zero_count / non_zero_count", "matching_cluster_idx": 6}, {"solution": "import math\ndef zero_count(arr):\n # Count the number of zeroes in the array\n zero_count = arr.count(0)\n \n # Count the number of non-zero elements in the array\n non_zero_count = len(arr) - zero_count\n \n # Calculate the ratio of zeroes to non-zeroes\n if non_zero_count == 0:\n return float('inf') # Return infinity if there are no non-zero elements\n else:\n ratio = zero_count / non_zero_count\n \n return ratio", "matching_cluster_idx": 6}, {"solution": "import math\ndef zero_count(arr):\n # Initialize counters for zeroes and non-zeroes\n zero_count = 0\n non_zero_count = 0\n \n # Iterate through the array to count zeroes and non-zeroes\n for num in arr:\n if num == 0:\n zero_count += 1\n else:\n non_zero_count += 1\n \n # Calculate the ratio of zeroes to non-zeroes\n if non_zero_count == 0:\n return float('inf') # Handle division by zero\n ratio = zero_count / non_zero_count\n \n return ratio", "matching_cluster_idx": 3}, {"solution": "import math\ndef zero_count(arr):\n # Count the number of zeroes in the array\n zero_count = arr.count(0)\n \n # Count the number of non-zero elements in the array\n non_zero_count = len(arr) - zero_count\n \n # Calculate the ratio of zeroes to non-zeroes\n if non_zero_count == 0:\n return float('inf') # Avoid division by zero\n else:\n return zero_count / non_zero_count", "matching_cluster_idx": 7}, {"solution": "import math\ndef zero_count(arr):\n # Initialize counters for zeroes and non-zeroes\n zero_count = 0\n non_zero_count = 0\n \n # Iterate through the array to count zeroes and non-zeroes\n for num in arr:\n if num == 0:\n zero_count += 1\n else:\n non_zero_count += 1\n \n # Calculate the ratio of zeroes to non-zeroes\n if non_zero_count == 0:\n return float('inf') # Avoid division by zero\n else:\n ratio = zero_count / non_zero_count\n return ratio", "matching_cluster_idx": 3}, {"solution": "import math\ndef zero_count(arr):\n # Count the number of zeroes in the array\n zero_count = arr.count(0)\n \n # Count the number of non-zero elements in the array\n non_zero_count = len(arr) - zero_count\n \n # Calculate the ratio of zeroes to non-zeroes\n if non_zero_count == 0:\n return float('inf') # If there are no non-zero elements, the ratio is undefined (return infinity)\n else:\n ratio = zero_count / non_zero_count\n \n return ratio", "matching_cluster_idx": 6}, {"solution": "import math\ndef zero_count(arr):\n # Initialize counters for zeroes and non-zeroes\n zero_count = 0\n non_zero_count = 0\n \n # Iterate through the array to count zeroes and non-zeroes\n for num in arr:\n if num == 0:\n zero_count += 1\n else:\n non_zero_count += 1\n \n # Calculate the ratio of zeroes to non-zeroes\n if non_zero_count == 0:\n return float('inf') # Return infinity if there are no non-zero elements\n else:\n return zero_count / non_zero_count", "matching_cluster_idx": 3}, {"solution": "import math\ndef zero_count(arr):\n # Count the number of zeroes in the array\n zero_count = arr.count(0)\n \n # Calculate the total number of elements in the array\n total_count = len(arr)\n \n # Calculate the number of non-zero elements\n non_zero_count = total_count - zero_count\n \n # Calculate the ratio of zeroes to non-zeroes\n if non_zero_count == 0:\n return float('inf') # Avoid division by zero\n ratio = zero_count / non_zero_count\n \n return ratio", "matching_cluster_idx": 6}]}, "Mbpp/140": {"dps": 78.07453416149069, "dps_norm": 86.25, "pass@1": 100.0, "profiled": [{"solution": "def extract_singly(list_of_tuples):\n # Initialize an empty set to store the unique elements\n result_set = set()\n \n # Iterate through each tuple in the list\n for tup in list_of_tuples:\n # Add each element of the tuple to the result set\n for item in tup:\n result_set.add(item)\n \n # Return the result set\n return result_set", "matching_cluster_idx": 4}, {"solution": "def extract_singly(list_of_tuples):\n # Initialize an empty set to store the unique elements\n result_set = set()\n \n # Iterate through each tuple in the list\n for t in list_of_tuples:\n # Add each element of the tuple to the set\n for item in t:\n result_set.add(item)\n \n # Return the set containing all unique elements\n return result_set", "matching_cluster_idx": 4}, {"solution": "def extract_singly(list_of_tuples):\n # Initialize an empty set to store unique elements\n result_set = set()\n \n # Iterate through each tuple in the list\n for tup in list_of_tuples:\n # Add each element of the tuple to the set\n for item in tup:\n result_set.add(item)\n \n # Return the resulting set\n return result_set", "matching_cluster_idx": 3}, {"solution": "def extract_singly(list_of_tuples):\n # Initialize an empty set to store the unique elements\n result_set = set()\n \n # Iterate over each tuple in the list\n for tup in list_of_tuples:\n # Add each element of the tuple to the set\n result_set.update(tup)\n \n # Return the set containing all unique elements\n return result_set", "matching_cluster_idx": 7}, {"solution": "def extract_singly(list_of_tuples):\n # Initialize an empty set to store the unique elements\n result_set = set()\n \n # Iterate over each tuple in the list\n for tup in list_of_tuples:\n # Add all elements of the tuple to the set\n result_set.update(tup)\n \n # Return the set containing all unique elements\n return result_set", "matching_cluster_idx": 6}, {"solution": "def extract_singly(list_of_tuples):\n # Initialize an empty set to store the unique elements\n result_set = set()\n \n # Iterate through each tuple in the list\n for tup in list_of_tuples:\n # Add each element of the tuple to the set\n result_set.update(tup)\n \n return result_set", "matching_cluster_idx": 7}, {"solution": "def extract_singly(list_of_tuples):\n # Initialize an empty set to store the unique elements\n result_set = set()\n \n # Iterate through each tuple in the list\n for tup in list_of_tuples:\n # Add each element of the tuple to the set\n for item in tup:\n result_set.add(item)\n \n # Return the set containing all unique elements\n return result_set", "matching_cluster_idx": 3}, {"solution": "def extract_singly(list_of_tuples):\n # Initialize an empty set to store the flattened elements\n result_set = set()\n \n # Iterate through each tuple in the list\n for tup in list_of_tuples:\n # Add each element of the tuple to the result set\n result_set.update(tup)\n \n # Return the set containing all unique elements\n return result_set", "matching_cluster_idx": 6}, {"solution": "def extract_singly(list_of_tuples):\n # Initialize an empty set to store the unique elements\n result_set = set()\n \n # Iterate through each tuple in the list\n for t in list_of_tuples:\n # Add each element of the tuple to the set\n result_set.update(t)\n \n # Return the resulting set\n return result_set", "matching_cluster_idx": 7}, {"solution": "def extract_singly(list_of_tuples):\n # Initialize an empty set to store the flattened elements\n result_set = set()\n \n # Iterate through each tuple in the list\n for tup in list_of_tuples:\n # Add each element in the tuple to the set\n result_set.update(tup)\n \n # Return the resulting set\n return result_set", "matching_cluster_idx": 7}, {"solution": "def extract_singly(list_of_tuples):\n # Initialize an empty set to store the unique elements\n result_set = set()\n \n # Iterate through each tuple in the list\n for tup in list_of_tuples:\n # Add each element of the tuple to the set\n for element in tup:\n result_set.add(element)\n \n # Return the resulting set\n return result_set", "matching_cluster_idx": 3}, {"solution": "def extract_singly(list_of_tuples):\n # Initialize an empty set to store the unique elements\n result_set = set()\n \n # Iterate over each tuple in the list\n for tup in list_of_tuples:\n # Update the set with the elements of the current tuple\n result_set.update(tup)\n \n # Return the resulting set\n return result_set", "matching_cluster_idx": 7}, {"solution": "def extract_singly(list_of_tuples):\n # Initialize an empty set to store the unique elements\n result_set = set()\n \n # Iterate through each tuple in the list\n for tup in list_of_tuples:\n # Add each element of the tuple to the set\n result_set.update(tup)\n \n # Return the resulting set\n return result_set", "matching_cluster_idx": 7}, {"solution": "def extract_singly(list_of_tuples):\n # Initialize an empty set to store the unique elements\n result_set = set()\n \n # Iterate through each tuple in the list\n for tup in list_of_tuples:\n # Add each element of the tuple to the set\n result_set.update(tup)\n \n # Return the set containing all unique elements\n return result_set", "matching_cluster_idx": 7}, {"solution": "def extract_singly(list_of_tuples):\n # Initialize an empty set to store the unique elements\n result_set = set()\n \n # Iterate over each tuple in the list\n for tup in list_of_tuples:\n # Update the set with the elements of the tuple\n result_set.update(tup)\n \n # Return the resulting set\n return result_set", "matching_cluster_idx": 6}, {"solution": "def extract_singly(list_of_tuples):\n # Initialize an empty set to store the unique elements\n result_set = set()\n \n # Iterate through each tuple in the list\n for tup in list_of_tuples:\n # Add each element of the tuple to the set\n result_set.update(tup)\n \n # Return the set containing all unique elements\n return result_set", "matching_cluster_idx": 7}, {"solution": "def extract_singly(list_of_tuples):\n # Initialize an empty set to store unique elements\n result_set = set()\n \n # Iterate through each tuple in the list\n for tup in list_of_tuples:\n # Update the set with the elements from the current tuple\n result_set.update(tup)\n \n # Return the set containing all unique elements\n return result_set", "matching_cluster_idx": 6}, {"solution": "def extract_singly(list_of_tuples):\n # Initialize an empty set to store the unique elements\n result_set = set()\n \n # Iterate through each tuple in the list\n for tup in list_of_tuples:\n # Add each element of the tuple to the set\n result_set.update(tup)\n \n return result_set", "matching_cluster_idx": 7}, {"solution": "def extract_singly(list_of_tuples):\n # Initialize an empty set to store the unique elements\n result_set = set()\n \n # Iterate through each tuple in the list\n for tup in list_of_tuples:\n # Add each element of the tuple to the set\n result_set.update(tup)\n \n # Return the set containing all unique elements\n return result_set", "matching_cluster_idx": 7}, {"solution": "def extract_singly(list_of_tuples):\n # Initialize an empty set to store the unique elements\n result_set = set()\n \n # Iterate through each tuple in the list\n for tup in list_of_tuples:\n # Add each element of the tuple to the set\n result_set.update(tup)\n \n # Return the set containing all unique elements\n return result_set", "matching_cluster_idx": 7}]}, "Mbpp/141": {"dps": 57.69715293524818, "dps_norm": 38.888888888888886, "pass@1": 18.0, "profiled": [{"solution": "def pancake_sort(arr):\n # Helper function to reverse elements from start to index i\n def flip(arr, i):\n start = 0\n while start < i:\n arr[start], arr[i] = arr[i], arr[start]\n start += 1\n i -= 1\n\n # Main function to perform pancake sort\n def find_max(arr, n):\n mi = 0\n for i in range(n):\n if arr[i] > arr[mi]:\n mi = i\n return mi\n\n n = len(arr)\n while n > 1:\n # Find the index of the maximum element in the current array\n mi = find_max(arr, n)\n \n # Move the maximum element to the end of the current array\n if mi != n - 1:\n # First flip the maximum element to the start\n flip(arr, mi)\n # Now flip it to the end\n flip(arr, n - 1)\n \n # Reduce the size of the current array by one\n n -= 1\n\n return arr", "matching_cluster_idx": 2}, {"solution": "def flip(arr, k):\n # Reverses the first k elements of the array\n arr[:k] = arr[:k][::-1]\n return arr\ndef find_max_index(arr, n):\n # Finds the index of the maximum element in the first n elements of the array\n max_idx = 0\n for i in range(1, n):\n if arr[i] > arr[max_idx]:\n max_idx = i\n return max_idx\ndef pancake_sort(arr):\n # Sorts the array using the pancake sort algorithm\n curr_size = len(arr)\n while curr_size > 1:\n # Find the index of the maximum element in the current array\n max_idx = find_max_index(arr, curr_size)\n \n if max_idx != curr_size - 1:\n # Move the maximum element to the beginning if it's not already there\n arr = flip(arr, max_idx + 1)\n # Now move the maximum element to its correct position\n arr = flip(arr, curr_size)\n \n # Reduce the current size of the array\n curr_size -= 1\n \n return arr", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(arr):\n # Helper function to reverse the sublist arr[0...i]\n def flip(arr, i):\n start = 0\n while start < i:\n arr[start], arr[i] = arr[i], arr[start]\n start += 1\n i -= 1\n \n # Function to find the index of the maximum element in arr[0...n-1]\n def find_max(arr, n):\n max_index = 0\n for i in range(n):\n if arr[i] > arr[max_index]:\n max_index = i\n return max_index\n \n # Main function to perform pancake sort\n n = len(arr)\n while n > 1:\n # Find the index of the maximum element in the current array\n max_index = find_max(arr, n)\n \n # Move the maximum element to the end of the current array\n if max_index != n - 1:\n # Flip the maximum element to the beginning\n flip(arr, max_index)\n # Flip it to the end\n flip(arr, n - 1)\n \n # Reduce the size of the current array\n n -= 1\n \n return arr", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(arr):\n # Helper function to reverse the order of the first k elements in the array\n def flip(arr, k):\n arr[:k] = arr[:k][::-1]\n \n # Function to find the index of the maximum element in the first n elements of the array\n def find_max_index(arr, n):\n return max(range(n), key=lambda i: arr[i])\n \n n = len(arr)\n while n > 1:\n # Find the index of the maximum element in the first n elements\n max_index = find_max_index(arr, n)\n \n # Move the maximum element to the beginning\n flip(arr, max_index + 1)\n \n # Move the maximum element to its correct position\n flip(arr, n)\n \n # Reduce the size of the array to consider\n n -= 1\n \n return arr", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(arr):\n def flip(arr, i):\n # Reverse the elements from the start up to index i\n start = 0\n while start < i:\n arr[start], arr[i] = arr[i], arr[start]\n start += 1\n i -= 1\n\n def find_max(arr, n):\n # Find the index of the maximum element in the array up to index n\n max_idx = 0\n for i in range(1, n):\n if arr[i] > arr[max_idx]:\n max_idx = i\n return max_idx\n\n n = len(arr)\n while n > 1:\n # Find the index of the maximum element in the unsorted part of the array\n max_idx = find_max(arr, n)\n \n # Move the maximum element to the end of the array\n if max_idx != n - 1:\n # Flip the array up to the max element\n flip(arr, max_idx)\n # Flip the entire unsorted part to move the max element to the end\n flip(arr, n - 1)\n \n # Reduce the size of the unsorted part of the array\n n -= 1\n\n return arr", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(arr):\n # Helper function to reverse the order of the first k elements in the array\n def flip(arr, k):\n arr[:k] = arr[:k][::-1]\n \n # Helper function to find the index of the maximum element in the first n elements\n def find_max_index(arr, n):\n return max(range(n), key=lambda i: arr[i])\n \n n = len(arr)\n while n > 1:\n # Find the index of the maximum element in the unsorted portion of the array\n max_index = find_max_index(arr, n)\n \n # Move the maximum element to the beginning\n flip(arr, max_index + 1)\n \n # Move the maximum element to its correct position\n flip(arr, n)\n \n # Reduce the size of the unsorted portion of the array\n n -= 1\n \n return arr", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(arr):\n # Helper function to reverse the order of the first k elements in arr\n def flip(arr, k):\n arr[:k] = arr[:k][::-1]\n \n # Function to find the index of the maximum element in the first n elements\n def find_max(arr, n):\n max_index = 0\n for i in range(n):\n if arr[i] > arr[max_index]:\n max_index = i\n return max_index\n \n n = len(arr)\n for size in range(n, 1, -1):\n # Find the index of the maximum element in the unsorted part of the array\n max_index = find_max(arr, size)\n \n if max_index != size - 1:\n # Flip the maximum element to the front if it's not already there\n if max_index != 0:\n flip(arr, max_index + 1)\n # Flip the maximum element to its correct position\n flip(arr, size)\n \n return arr", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(arr):\n # Helper function to reverse the order of the first k elements in the array\n def flip(arr, k):\n arr[:k] = arr[:k][::-1]\n\n # Function to find the index of the maximum element in the first n elements\n def find_max(arr, n):\n return arr.index(max(arr[:n]))\n\n n = len(arr)\n while n > 1:\n # Find the index of the maximum element in the current array\n max_index = find_max(arr, n)\n \n # Move the maximum element to the beginning\n flip(arr, max_index + 1)\n \n # Move the maximum element to its correct position\n flip(arr, n)\n \n # Reduce the size of the array to consider\n n -= 1\n\n return arr", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(arr):\n # Helper function to reverse elements from 0 to i\n def flip(arr, i):\n start = 0\n while start < i:\n temp = arr[start]\n arr[start] = arr[i]\n arr[i] = temp\n start += 1\n i -= 1\n \n # Main function to sort the array using pancake sort\n def find_max(arr, n):\n mi = 0\n for i in range(n):\n if arr[i] > arr[mi]:\n mi = i\n return mi\n \n n = len(arr)\n while n > 1:\n # Find the index of the maximum element in the unsorted part\n mi = find_max(arr, n)\n \n # Move the maximum element to the end of the current unsorted part\n flip(arr, mi)\n flip(arr, n - 1)\n \n # Reduce the size of the unsorted part\n n -= 1\n \n return arr", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(arr):\n # Helper function to reverse elements from start to index i\n def flip(arr, i):\n start = 0\n while start < i:\n arr[start], arr[i] = arr[i], arr[start]\n start += 1\n i -= 1\n\n # Main function to sort the array using pancake sort\n def find_max(arr, n):\n mi = 0\n for i in range(n):\n if arr[i] > arr[mi]:\n mi = i\n return mi\n\n n = len(arr)\n while n > 1:\n # Find the index of the maximum element in the unsorted portion\n mi = find_max(arr, n)\n \n # Move the maximum element to the beginning if it's not already there\n if mi != n - 1:\n flip(arr, mi)\n # Now flip the maximum element to its correct position\n flip(arr, n - 1)\n \n # Reduce the size of the unsorted portion\n n -= 1\n\n return arr", "matching_cluster_idx": 2}, {"solution": "def flip(arr, k):\n # Reverses the first k elements of the array\n arr[:k] = arr[:k][::-1]\n return arr\ndef find_max_index(arr, n):\n # Finds the index of the maximum element in the first n elements of the array\n max_idx = 0\n for i in range(n):\n if arr[i] > arr[max_idx]:\n max_idx = i\n return max_idx\ndef pancake_sort(arr):\n n = len(arr)\n for size in range(n, 1, -1):\n # Find the index of the maximum element in the current subarray\n max_idx = find_max_index(arr, size)\n \n # Move the maximum element to the end of the current subarray\n if max_idx != size - 1:\n # If the maximum element is not already at the end, flip it to the front\n if max_idx != 0:\n arr = flip(arr, max_idx + 1)\n # Then flip it to the end\n arr = flip(arr, size)\n return arr", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(arr):\n # Helper function to reverse the order of the first k elements in the array\n def flip(arr, k):\n arr[:k] = arr[:k][::-1]\n\n # Function to find the index of the maximum element in the first k elements\n def find_max_index(arr, k):\n return max(range(k), key=lambda i: arr[i])\n\n n = len(arr)\n for size in range(n, 1, -1):\n # Find the index of the maximum element in the current array slice\n max_index = find_max_index(arr, size)\n \n # Move the maximum element to the beginning\n flip(arr, max_index + 1)\n \n # Move the maximum element to its correct position\n flip(arr, size)\n\n return arr", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(arr):\n # Function to reverse the order of elements from the start to the ith index\n def flip(arr, i):\n start = 0\n while start < i:\n temp = arr[start]\n arr[start] = arr[i]\n arr[i] = temp\n start += 1\n i -= 1\n\n # Main function to perform pancake sort\n def find_max(arr, n):\n # Find the index of the maximum element in arr[0..n-1]\n mi = 0\n for i in range(0, n):\n if arr[i] > arr[mi]:\n mi = i\n return mi\n\n n = len(arr)\n while n > 1:\n # Find the index of the maximum element in the current array\n mi = find_max(arr, n)\n # Move the maximum element to the end of the current array\n flip(arr, mi)\n flip(arr, n - 1)\n n -= 1\n\n return arr", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(arr):\n # Helper function to reverse the order of the first k elements in the array\n def flip(arr, k):\n arr[:k] = arr[:k][::-1]\n \n # Main function to perform pancake sort\n def sort(arr):\n n = len(arr)\n # Start with the entire array and reduce the size by one after each iteration\n for size in range(n, 1, -1):\n # Find the index of the maximum element in the current subarray\n max_index = arr.index(max(arr[0:size]))\n \n # Move the maximum element to the end of the current subarray\n if max_index != size - 1:\n # Flip the maximum element to the beginning if it's not already there\n if max_index != 0:\n flip(arr, max_index + 1)\n # Flip the maximum element to the end\n flip(arr, size)\n \n # Perform the sort\n sort(arr)\n return arr", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(arr):\n # Helper function to reverse the order of the first k elements of arr\n def flip(arr, k):\n arr[:k] = arr[:k][::-1]\n \n # Function to find the index of the maximum element in the first k elements\n def find_max_index(arr, n):\n max_index = 0\n for i in range(n):\n if arr[i] > arr[max_index]:\n max_index = i\n return max_index\n\n n = len(arr)\n while n > 1:\n # Find the index of the maximum element in the unsorted portion of the array\n max_index = find_max_index(arr, n)\n \n # Move the maximum element to the beginning\n flip(arr, max_index + 1)\n \n # Move the maximum element to its correct position\n flip(arr, n)\n \n # Reduce the size of the unsorted portion of the array\n n -= 1\n \n return arr", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(arr):\n # Helper function to reverse the sublist arr[0...i]\n def flip(arr, i):\n start = 0\n while start < i:\n arr[start], arr[i] = arr[i], arr[start]\n start += 1\n i -= 1\n \n # Main function to perform pancake sort\n def find_max(arr, n):\n # Find the index of the maximum element in arr[0...n-1]\n mi = 0\n for i in range(0, n):\n if arr[i] > arr[mi]:\n mi = i\n return mi\n\n n = len(arr)\n while n > 1:\n # Find the index of the maximum element in the current array\n mi = find_max(arr, n)\n \n # Move the maximum element to the end of the current array\n if mi != n - 1:\n # Flip the maximum number to the beginning\n flip(arr, mi)\n # Flip it to the end\n flip(arr, n - 1)\n \n # Reduce the size of the current array\n n -= 1\n\n return arr", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(arr):\n # Helper function to reverse elements from 0 to index i\n def flip(arr, i):\n start = 0\n while start < i:\n arr[start], arr[i] = arr[i], arr[start]\n start += 1\n i -= 1\n \n # Main function to sort the array\n def find_max(arr, n):\n # Find the index of the maximum element in arr[0...n-1]\n mi = 0\n for i in range(n):\n if arr[i] > arr[mi]:\n mi = i\n return mi\n\n # Length of the current array\n n = len(arr)\n while n > 1:\n # Find the index of the maximum element in the current array\n max_index = find_max(arr, n)\n \n # Move the maximum element to the end of the current array\n flip(arr, max_index)\n flip(arr, n-1)\n \n # Reduce the size of the current array\n n -= 1\n\n return arr", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(arr):\n # Helper function to reverse the order of the first k elements in the array\n def flip(arr, k):\n arr[:k] = arr[:k][::-1]\n \n # Helper function to find the index of the maximum element in the first n elements of the array\n def find_max_index(arr, n):\n return max(range(n), key=lambda i: arr[i])\n \n n = len(arr)\n for size in range(n, 1, -1):\n # Find the index of the maximum element in the unsorted portion of the array\n max_index = find_max_index(arr, size)\n if max_index + 1 != size:\n # Move the maximum element to the beginning\n flip(arr, max_index + 1)\n # Move the maximum element to its correct position\n flip(arr, size)\n \n return arr", "matching_cluster_idx": 2}]}, "Mbpp/166": {"dps": 94.39999999999999, "dps_norm": 50.0, "pass@1": 100.0, "profiled": [{"solution": "def find_even_pair(arr):\n # Initialize the count of pairs\n count = 0\n \n # Iterate through each element in the array\n for i in range(len(arr)):\n for j in range(i + 1, len(arr)):\n # Check if the XOR of the pair is even\n if (arr[i] ^ arr[j]) % 2 == 0:\n count += 1\n \n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(arr):\n # Initialize the count of pairs\n count = 0\n \n # Iterate through each element in the array\n for i in range(len(arr)):\n for j in range(i + 1, len(arr)):\n # Check if the XOR of the pair is even\n if (arr[i] ^ arr[j]) % 2 == 0:\n count += 1\n \n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(arr):\n # Initialize the count of pairs\n count = 0\n \n # Iterate through each element in the array\n for i in range(len(arr)):\n for j in range(i + 1, len(arr)):\n # Check if the XOR of the pair is even\n if (arr[i] ^ arr[j]) % 2 == 0:\n count += 1\n \n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(arr):\n # Initialize the count of pairs\n count = 0\n \n # Iterate through each element in the list\n for i in range(len(arr)):\n for j in range(i + 1, len(arr)):\n # Check if the XOR of the pair is even\n if (arr[i] ^ arr[j]) % 2 == 0:\n count += 1\n \n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(arr):\n # Initialize the count of pairs\n count = 0\n # Iterate through each element in the array\n for i in range(len(arr)):\n for j in range(i + 1, len(arr)):\n # Check if the XOR of the pair is even\n if (arr[i] ^ arr[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(arr):\n # Initialize the count of pairs\n count = 0\n \n # Iterate through each pair of elements in the array\n for i in range(len(arr)):\n for j in range(i + 1, len(arr)):\n # Check if the XOR of the pair is even\n if (arr[i] ^ arr[j]) % 2 == 0:\n count += 1\n \n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(arr):\n # Initialize count of pairs that XOR to an even number\n count = 0\n \n # Iterate through the array to find all pairs\n for i in range(len(arr)):\n for j in range(i + 1, len(arr)):\n # Check if the XOR of the pair is even\n if (arr[i] ^ arr[j]) % 2 == 0:\n count += 1\n \n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(arr):\n # Initialize the count of pairs\n count = 0\n \n # Iterate through each element in the array\n for i in range(len(arr)):\n for j in range(i + 1, len(arr)):\n # Check if the XOR of the pair is even\n if (arr[i] ^ arr[j]) % 2 == 0:\n count += 1\n \n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(arr):\n # Initialize the count of pairs\n count = 0\n \n # Iterate through the list with two nested loops\n for i in range(len(arr)):\n for j in range(i + 1, len(arr)):\n # Check if the XOR of the pair is even\n if (arr[i] ^ arr[j]) % 2 == 0:\n count += 1\n \n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(arr):\n # Initialize the count of pairs\n count = 0\n \n # Iterate through the list to check each pair\n for i in range(len(arr)):\n for j in range(i + 1, len(arr)):\n # Check if the XOR of the pair is even\n if (arr[i] ^ arr[j]) % 2 == 0:\n count += 1\n \n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(arr):\n # Initialize the count of pairs\n count = 0\n \n # Iterate through each element in the array\n for i in range(len(arr)):\n for j in range(i + 1, len(arr)):\n # Check if the XOR of the pair is even\n if (arr[i] ^ arr[j]) % 2 == 0:\n count += 1\n \n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(arr):\n # Initialize the count of pairs\n count = 0\n \n # Iterate through the list to find all pairs\n for i in range(len(arr)):\n for j in range(i + 1, len(arr)):\n # Check if the XOR of the pair is even\n if (arr[i] ^ arr[j]) % 2 == 0:\n count += 1\n \n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(arr):\n # Initialize the count of pairs\n count = 0\n \n # Iterate through each pair of elements in the list\n for i in range(len(arr)):\n for j in range(i + 1, len(arr)):\n # Check if the XOR of the pair is even\n if (arr[i] ^ arr[j]) % 2 == 0:\n count += 1\n \n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(arr):\n # Initialize the count of pairs\n count = 0\n # Iterate through each element in the array\n for i in range(len(arr)):\n for j in range(i + 1, len(arr)):\n # Check if the XOR of the pair is even\n if (arr[i] ^ arr[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(arr):\n # Initialize the count of pairs\n count = 0\n \n # Iterate through each pair of elements in the array\n for i in range(len(arr)):\n for j in range(i + 1, len(arr)):\n # Check if the XOR of the pair is even\n if (arr[i] ^ arr[j]) % 2 == 0:\n count += 1\n \n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(arr):\n # Initialize count of pairs\n count = 0\n \n # Iterate through the list to find pairs\n for i in range(len(arr)):\n for j in range(i + 1, len(arr)):\n # Check if the XOR of the pair is even\n if (arr[i] ^ arr[j]) % 2 == 0:\n count += 1\n \n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(arr):\n # Initialize the count of pairs\n count = 0\n \n # Iterate through each element in the array\n for i in range(len(arr)):\n for j in range(i + 1, len(arr)):\n # Check if the XOR of the pair is even\n if (arr[i] ^ arr[j]) % 2 == 0:\n count += 1\n \n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(arr):\n # Initialize the count of pairs\n count = 0\n \n # Iterate through the list to find pairs\n for i in range(len(arr)):\n for j in range(i + 1, len(arr)):\n # Check if the XOR of the pair is even\n if (arr[i] ^ arr[j]) % 2 == 0:\n count += 1\n \n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(arr):\n # Initialize the count of pairs\n count = 0\n \n # Iterate through the list to find pairs\n for i in range(len(arr)):\n for j in range(i + 1, len(arr)):\n # Check if the XOR of the pair is even\n if (arr[i] ^ arr[j]) % 2 == 0:\n count += 1\n \n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(arr):\n # Initialize the count of pairs\n count = 0\n \n # Iterate through each element in the array\n for i in range(len(arr)):\n for j in range(i + 1, len(arr)):\n # Check if the XOR of the pair is even\n if (arr[i] ^ arr[j]) % 2 == 0:\n count += 1\n \n return count", "matching_cluster_idx": 1}]}, "Mbpp/170": {"dps": 89.78260869565217, "dps_norm": 94.375, "pass@1": 100.0, "profiled": [{"solution": "def sum_range_list(nums, start, end):\n # Initialize sum to 0\n total_sum = 0\n \n # Iterate through the list from the start index to the end index (inclusive)\n for i in range(start, end + 1):\n total_sum += nums[i]\n \n return total_sum", "matching_cluster_idx": 4}, {"solution": "def sum_range_list(nums, start, end):\n # Calculate the sum of elements in the list from index 'start' to 'end' (inclusive)\n return sum(nums[start:end+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(nums, start, end):\n # Calculate the sum of elements in the list from index 'start' to index 'end' (inclusive)\n return sum(nums[start:end + 1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(nums, start, end):\n # Calculate the sum of the numbers in the list from index 'start' to index 'end' (inclusive)\n return sum(nums[start:end+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(nums, start, end):\n # Initialize the sum to zero\n total_sum = 0\n \n # Iterate over the range from start to end (inclusive)\n for i in range(start, end + 1):\n # Add the current element to the sum\n total_sum += nums[i]\n \n return total_sum", "matching_cluster_idx": 4}, {"solution": "def sum_range_list(nums, start, end):\n # Calculate the sum of numbers in the list from index 'start' to 'end' (inclusive)\n return sum(nums[start:end+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(nums, start, end):\n # Calculate the sum of elements from index 'start' to index 'end' (inclusive)\n return sum(nums[start:end + 1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(lst, start, end):\n # Calculate the sum of elements in the list from index 'start' to 'end' (inclusive)\n return sum(lst[start:end+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(nums, start, end):\n # Ensure the start and end indices are within the list bounds\n if start < 0 or end >= len(nums) or start > end:\n return 0\n \n # Calculate the sum of the elements in the specified range\n return sum(nums[start:end+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(nums, start, end):\n # Calculate the sum of elements in the list from index 'start' to index 'end' (inclusive)\n return sum(nums[start:end+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(nums, start, end):\n # Calculate the sum of elements from index 'start' to 'end' (inclusive)\n return sum(nums[start:end + 1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(nums, start, end):\n # Ensure the start index is less than or equal to the end index\n if start > end:\n return 0\n \n # Calculate the sum of the numbers in the specified range\n return sum(nums[start:end+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(nums, start, end):\n # Calculate the sum of elements in the list from index 'start' to 'end' (inclusive)\n return sum(nums[start:end+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(nums, start, end):\n # Calculate the sum of the elements in the list from index 'start' to index 'end' (inclusive)\n return sum(nums[start:end+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(lst, start, end):\n # Sum the elements in the list from index 'start' to 'end' (inclusive)\n return sum(lst[start:end+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(nums, start, end):\n # Calculate the sum of the elements in the list from index start to end (inclusive)\n return sum(nums[start:end+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(nums, start, end):\n # Ensure the start and end indices are within the bounds of the list\n if start < 0 or end >= len(nums) or start > end:\n return 0\n \n # Calculate the sum of the elements between the specified indices\n return sum(nums[start:end+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(lst, start, end):\n # Calculate the sum of elements from the start index to the end index (inclusive)\n return sum(lst[start:end + 1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(nums, left, right):\n # Calculate the sum of the elements in the list from index 'left' to 'right' (inclusive)\n return sum(nums[left:right+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(nums, start, end):\n # Initialize sum to 0\n total_sum = 0\n \n # Iterate through the range from start to end (inclusive)\n for i in range(start, end + 1):\n # Add the number at the current index to the total sum\n total_sum += nums[i]\n \n return total_sum", "matching_cluster_idx": 4}]}, "Mbpp/226": {"dps": 68.60465116279069, "dps_norm": 15.0, "pass@1": 100.0, "profiled": [{"solution": "def odd_values_string(input_string):\n # Initialize an empty string to store the result\n result_string = ''\n \n # Iterate over the string using its indices\n for i in range(len(input_string)):\n # Check if the index is even (0-based index)\n if i % 2 == 0:\n # Append the character at the current index to the result string\n result_string += input_string[i]\n \n return result_string", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(s):\n # Initialize an empty string to store the result\n result = ''\n \n # Iterate through the string using enumerate to get both index and character\n for index, char in enumerate(s):\n # Check if the index is even (since index starts at 0, even index means odd position)\n if index % 2 == 0:\n result += char\n \n return result", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(s):\n # Initialize an empty string to store the result\n result = ''\n \n # Iterate over the string using index\n for i in range(len(s)):\n # Check if the index is even (since indexing starts at 0, even indices correspond to odd positions)\n if i % 2 == 0:\n # Append the character at the current index to the result string\n result += s[i]\n \n return result", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(s):\n # Initialize an empty string to store characters at even indices\n result = ''\n \n # Iterate over the string using enumerate to get both index and character\n for index, char in enumerate(s):\n # Check if the index is even (considering 0-based indexing)\n if index % 2 == 0:\n # Append the character to the result string\n result += char\n \n # Return the final result string\n return result", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(s):\n # Initialize an empty string to store the result\n result = ''\n \n # Iterate over the string using its indices\n for i in range(len(s)):\n # Check if the index is even (since indices start at 0)\n if i % 2 == 0:\n # Append the character at the current index to the result\n result += s[i]\n \n return result", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(input_string):\n # Initialize an empty string to store characters at even indices\n result_string = ''\n \n # Iterate through the string using enumerate to get both index and character\n for index, char in enumerate(input_string):\n # Check if the index is even (since index starts from 0, even index means odd position)\n if index % 2 == 0:\n result_string += char\n \n return result_string", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(s):\n # Initialize an empty string to store the result\n result = ''\n \n # Iterate through the string using enumerate to get both index and character\n for index, char in enumerate(s):\n # Check if the index is even (since index starts from 0, even index means odd position)\n if index % 2 == 0:\n result += char # Append the character to the result string\n \n return result", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(s):\n # Initialize an empty string to store the result\n result = ''\n \n # Iterate through the string using enumerate to get both index and character\n for index, char in enumerate(s):\n # Check if the index is even (considering 0 as an even index)\n if index % 2 == 0:\n result += char # Append the character to the result string\n \n return result", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(s):\n # Initialize an empty string to store characters at even indices\n result = ''\n \n # Iterate over the string using enumerate to get both index and character\n for i, char in enumerate(s):\n # Check if the index is even (0-based indexing)\n if i % 2 == 0:\n # Append the character to the result string\n result += char\n \n return result", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(input_string):\n # Initialize an empty string to store characters at even indices\n result = ''\n \n # Iterate over the string using enumerate to get both index and character\n for index, char in enumerate(input_string):\n # Check if the index is even (0-based index)\n if index % 2 == 0:\n # Append the character to the result string\n result += char\n \n return result", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(s):\n # Initialize an empty string to store the result\n result = ''\n \n # Iterate over the string using enumerate to get both index and character\n for index, char in enumerate(s):\n # Check if the index is even (since index starts from 0, even index corresponds to odd position)\n if index % 2 == 0:\n result += char # Append the character to the result if the index is even\n \n return result", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(input_string):\n # Initialize an empty string to store the result\n result = ''\n \n # Iterate over the string using index\n for index in range(len(input_string)):\n # Check if the index is even (since index starts from 0)\n if index % 2 == 0:\n # Append the character at the current index to the result\n result += input_string[index]\n \n return result", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(input_string):\n # Initialize an empty string to store the result\n result = ''\n \n # Iterate over the string using its index\n for index in range(len(input_string)):\n # Check if the index is even (considering index 0 as even)\n if index % 2 == 0:\n # Append the character at the current index to the result\n result += input_string[index]\n \n return result", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(s):\n # Initialize an empty string to store the result\n result = ''\n \n # Iterate over the string using enumerate to get both index and character\n for index, char in enumerate(s):\n # Check if the index is even (since index starts from 0, even index means odd position)\n if index % 2 == 0:\n # Append the character to the result\n result += char\n \n return result", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(input_string):\n # Initialize an empty string to store the result\n result = ''\n \n # Iterate over the string using enumerate to get both index and character\n for index, char in enumerate(input_string):\n # Check if the index is even (since index starts at 0, even index means odd position)\n if index % 2 == 0:\n result += char # Append the character to the result if the index is even\n \n return result", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(s):\n # Initialize an empty string to store characters at even indices\n result = ''\n \n # Iterate over the string using enumerate to get both index and character\n for index, char in enumerate(s):\n # Check if the index is even (considering 0 as even)\n if index % 2 == 0:\n # Append the character to the result string\n result += char\n \n return result", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(input_string):\n # Initialize an empty string to store the result\n result_string = ''\n \n # Iterate through the string, considering only even indices\n for i in range(0, len(input_string), 2):\n result_string += input_string[i]\n \n return result_string", "matching_cluster_idx": 1}, {"solution": "def odd_values_string(input_string):\n # Initialize an empty string to store characters at even indices\n result = ''\n \n # Iterate over the string using enumerate to get both index and character\n for index, char in enumerate(input_string):\n # Check if the index is even (since index starts from 0, even index means odd position)\n if index % 2 == 0:\n result += char\n \n return result", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(s):\n # Initialize an empty string to store the result\n result = ''\n \n # Iterate over the string using enumerate to get both index and character\n for index, char in enumerate(s):\n # Check if the index is even (since index starts from 0, even index means odd position in human terms)\n if index % 2 == 0:\n result += char # Append the character to the result string\n \n return result", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(s):\n # Initialize an empty string to store the result\n result = ''\n \n # Iterate over the string using enumerate to get both index and character\n for index, char in enumerate(s):\n # Check if the index is even (since index starts from 0, even index means odd position)\n if index % 2 == 0:\n result += char # Append the character to the result string\n \n return result", "matching_cluster_idx": 0}]}, "Mbpp/230": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def replace_blank(input_string, char):\n # Replace all blank spaces in the input_string with the specified character\n return input_string.replace(' ', char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string, replacement_char):\n # Replace all spaces in the input_string with replacement_char\n modified_string = input_string.replace(' ', replacement_char)\n return modified_string", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string, replacement_char):\n # Replace all blank spaces in the input_string with replacement_char\n return input_string.replace(' ', replacement_char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(s, char):\n # Replace all spaces in the string `s` with the character `char`\n return s.replace(' ', char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(s, char):\n # Replace all blank spaces in the string 's' with the character 'char'\n return s.replace(' ', char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(s, char):\n # Replace all spaces in the string 's' with the character 'char'\n return s.replace(' ', char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(s, ch):\n # Replace all blank spaces in the string 's' with the character 'ch'\n return s.replace(' ', ch)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string, char):\n # Replace all spaces in the input_string with the specified character\n modified_string = input_string.replace(' ', char)\n return modified_string", "matching_cluster_idx": 7}, {"solution": "def replace_blank(string, character):\n # Replace all blank spaces in the string with the specified character\n return string.replace(' ', character)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string, char):\n # Replace all spaces in the input_string with the specified character\n return input_string.replace(' ', char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string, replacement_char):\n # Replace all spaces in the input_string with the replacement_char\n return input_string.replace(' ', replacement_char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(s, char):\n # Replace all blank spaces in the string `s` with the character `char`\n return s.replace(' ', char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string, replacement_char):\n # Replace all blank spaces in the input_string with the replacement_char\n modified_string = input_string.replace(' ', replacement_char)\n return modified_string", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string, replacement_char):\n # Replace all spaces in the input_string with the replacement_char\n modified_string = input_string.replace(' ', replacement_char)\n return modified_string", "matching_cluster_idx": 7}, {"solution": "def replace_blank(s, char):\n # Replace all spaces in the string `s` with the character `char`\n return s.replace(' ', char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(s, ch):\n # Replace all spaces in the string 's' with the character 'ch'\n return s.replace(' ', ch)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string, replacement_char):\n # Replace all blank spaces in the input_string with replacement_char\n return input_string.replace(' ', replacement_char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(s, char):\n # Replace all occurrences of blank spaces in the string `s` with the character `char`\n return s.replace(' ', char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(s, ch):\n # Replace all spaces in the string 's' with the character 'ch'\n return s.replace(' ', ch)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string, char):\n # Replace all blank spaces in the input_string with the specified character\n return input_string.replace(' ', char)", "matching_cluster_idx": 7}]}, "Mbpp/239": {"dps": 70.86206896551724, "dps_norm": 74.5, "pass@1": 26.0, "profiled": [{"solution": "def get_total_number_of_sequences(m, n):\n # Initialize a DP table with dimensions (n+1) x (m+1)\n dp = [[0] * (m + 1) for _ in range(n + 1)]\n \n # Base case: There's one way to form a sequence of length 0\n for j in range(m + 1):\n dp[0][j] = 1\n \n # Fill the DP table\n for i in range(1, n + 1):\n for j in range(1, m + 1):\n dp[i][j] = dp[i][j - 1] + dp[i - 1][j // 2]\n \n # The answer is the value in dp[n][m]\n return dp[n][m]", "matching_cluster_idx": 8}, {"solution": "def get_total_number_of_sequences(m, n):\n # Initialize a 2D DP array with all zeros\n dp = [[0 for _ in range(n + 1)] for _ in range(m + 1)]\n \n # Base case: There's exactly one way to form a sequence of length 1\n for i in range(1, m + 1):\n dp[i][1] = 1\n \n # Fill the DP table\n for length in range(2, n + 1):\n for current in range(1, m + 1):\n # Sum all valid previous elements\n for previous in range(1, current // 2 + 1):\n dp[current][length] += dp[previous][length - 1]\n \n # Sum all possible sequences of length n\n result = sum(dp[i][n] for i in range(1, m + 1))\n \n return result", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n # Helper function to find the number of valid sequences using recursion\n def count_sequences(prev, remaining, m):\n # Base case: if no more elements are needed, there's one valid sequence\n if remaining == 0:\n return 1\n # Initialize the count of valid sequences\n count = 0\n # Start from the next possible element (prev * 2) up to m\n for next_val in range(max(1, 2 * prev), m + 1):\n # Recursively count the sequences with the next value\n count += count_sequences(next_val, remaining - 1, m)\n return count\n\n # Start the recursion with an initial previous value of 0\n return count_sequences(0, n, m)", "matching_cluster_idx": 3}, {"solution": "def get_total_number_of_sequences(m, n):\n # Base case: If n is 0, there is only one sequence, the empty sequence.\n if n == 0:\n return 1\n \n # Base case: If n is 1, each number from 1 to m can be a sequence.\n if n == 1:\n return m\n \n # Initialize a list to store the number of sequences ending with each number.\n dp = [0] * (m + 1)\n \n # Initialize the first row of the DP table.\n for i in range(1, m + 1):\n dp[i] = 1\n \n # Fill the DP table.\n for length in range(2, n + 1):\n new_dp = [0] * (m + 1)\n for i in range(1, m + 1):\n for j in range(1, (i // 2) + 1):\n new_dp[i] += dp[j]\n dp = new_dp\n \n # Sum up the number of sequences of length n ending with any number from 1 to m.\n return sum(dp)", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n # Base cases: if n is 0, there's only one sequence (an empty one)\n if n == 0:\n return 1\n # If n is 1, each number from 1 to m can be a valid sequence\n if n == 1:\n return m\n \n # Initialize a list to store the number of sequences\n dp = [0] * (m + 1)\n \n # There's only one sequence of length 1 for each number from 1 to m\n for i in range(1, m + 1):\n dp[i] = 1\n \n # Compute the number of sequences for lengths from 2 to n\n for length in range(2, n + 1):\n new_dp = [0] * (m + 1)\n for i in range(1, m + 1):\n # The number of sequences ending at i is the sum of sequences ending at j where 1 <= j <= i // 2\n new_dp[i] = sum(dp[j] for j in range(1, (i // 2) + 1))\n dp = new_dp\n \n # The answer is the sum of all possible sequences of length n\n return sum(dp)", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n # Base case: if n is 1, there are m possible sequences (1 to m)\n if n == 1:\n return m\n \n # Initialize a list to store the number of sequences for each starting number\n dp = [0] * (m + 1)\n \n # There is exactly one sequence of length 1 for each starting number\n for i in range(1, m + 1):\n dp[i] = 1\n \n # Calculate the number of sequences for lengths from 2 to n\n for length in range(2, n + 1):\n new_dp = [0] * (m + 1)\n for start in range(1, m + 1):\n for next_val in range(start * 2, m + 1):\n new_dp[next_val] += dp[start]\n dp = new_dp\n \n # Sum up the number of sequences starting from each number\n return sum(dp)", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n # Helper function to find the number of valid sequences\n def count_sequences(prev, remaining, memo):\n # Base case: if no more elements are left to be chosen, a valid sequence is formed\n if remaining == 0:\n return 1\n # If the current state is already computed, return the stored result\n if (prev, remaining) in memo:\n return memo[(prev, remaining)]\n \n count = 0\n # Start from the next possible number and try to build the sequence\n start = 1 if prev == 0 else (prev * 2)\n for i in range(start, m + 1):\n count += count_sequences(i, remaining - 1, memo)\n \n # Store the result in the memo dictionary\n memo[(prev, remaining)] = count\n return count\n\n # Initialize memoization dictionary\n memo = {}\n # Start the sequence with no previous element and the full length of the sequence\n return count_sequences(0, n, memo)", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n # Helper function to find the number of valid sequences\n def count_sequences(prev, remaining, memo):\n if remaining == 0:\n return 1\n if (prev, remaining) in memo:\n return memo[(prev, remaining)]\n \n count = 0\n start = prev * 2 if prev > 0 else 1\n for i in range(start, m + 1):\n count += count_sequences(i, remaining - 1, memo)\n \n memo[(prev, remaining)] = count\n return count\n \n return count_sequences(0, n, {})", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n # Base case: if n is 0, there is exactly one sequence: the empty sequence\n if n == 0:\n return 1\n # Base case: if m is 0, there are no positive integers to form sequences\n if m == 0:\n return 0\n\n # Initialize a list to store the count of sequences ending with each number\n dp = [0] * (m + 1)\n\n # There is exactly one sequence of length 1 for each number from 1 to m\n for i in range(1, m + 1):\n dp[i] = 1\n\n # Compute the number of sequences for lengths from 2 to n\n for length in range(2, n + 1):\n new_dp = [0] * (m + 1)\n for i in range(1, m + 1):\n # Sum up the sequences where the current number is at least twice the previous number\n for j in range(1, i // 2 + 1):\n new_dp[i] += dp[j]\n dp = new_dp\n\n # The result is the sum of all sequences of length n ending with any number from 1 to m\n return sum(dp)", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n # Helper function to find the number of sequences using dynamic programming\n def count_sequences(dp, m, n, last=0, start=1):\n if n == 0:\n return 1\n if dp[last][n] != -1:\n return dp[last][n]\n \n dp[last][n] = 0\n for i in range(start, m + 1):\n if i >= 2 * last:\n dp[last][n] += count_sequences(dp, m, n - 1, i, i)\n return dp[last][n]\n \n # Initialize the DP table with -1\n dp = [[-1 for _ in range(n + 1)] for _ in range(m + 1)]\n \n # Start the recursive function\n return count_sequences(dp, m, n)", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n # Helper function to count sequences\n def count_sequences(remaining_length, last_value):\n if remaining_length == 0:\n return 1\n count = 0\n for i in range(max(1, last_value * 2), m + 1):\n count += count_sequences(remaining_length - 1, i)\n return count\n\n return count_sequences(n, 0)", "matching_cluster_idx": 3}, {"solution": "def get_total_number_of_sequences(m, n):\n # Base case: if n is 1, there are m possible sequences (1 to m)\n if n == 1:\n return m\n \n # Initialize a list to store the count of valid sequences ending with each number\n dp = [0] * (m + 1)\n \n # Initialize the first row of the DP table\n for i in range(1, m + 1):\n dp[i] = 1\n \n # Fill the DP table\n for length in range(2, n + 1):\n new_dp = [0] * (m + 1)\n for end in range(1, m + 1):\n for start in range(1, (end // 2) + 1):\n new_dp[end] += dp[start]\n dp = new_dp\n \n # Sum up all possible sequences of length n\n return sum(dp)", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n # Base case: if n is 0, there's one empty sequence\n if n == 0:\n return 1\n \n # Base case: if m is less than the smallest possible value for the first element, return 0\n if m < 1:\n return 0\n \n # Recursive case: count sequences starting with 1 and those starting with a higher number\n return get_total_number_of_sequences(m // 2, n - 1) + get_total_number_of_sequences(m - 1, n)", "matching_cluster_idx": 5}, {"solution": "def get_total_number_of_sequences(m, n):\n # Base case: if n is 0, there is only one sequence: the empty sequence.\n if n == 0:\n return 1\n # Base case: if m is less than 2 * (n - 1), it's impossible to form such a sequence.\n if m < 2 * (n - 1):\n return 0\n \n # Initialize the dynamic programming table\n dp = [[0] * (m + 1) for _ in range(n + 1)]\n \n # There is exactly one way to form a sequence of length 0\n for i in range(m + 1):\n dp[0][i] = 1\n \n # Fill the DP table\n for length in range(1, n + 1):\n for value in range(1, m + 1):\n dp[length][value] = dp[length][value - 1] + dp[length - 1][value // 2]\n \n # The answer is the number of sequences of length n with maximum value m\n return dp[n][m]", "matching_cluster_idx": 9}, {"solution": "def get_total_number_of_sequences(m, n):\n # Helper function to count sequences recursively\n def count_sequences(prev, length):\n if length == 0:\n return 1\n count = 0\n start = prev * 2 if prev > 0 else 1\n for i in range(start, m + 1):\n count += count_sequences(i, length - 1)\n return count\n\n # Start the recursion with no previous element and the full length\n return count_sequences(0, n)", "matching_cluster_idx": 5}, {"solution": "def get_total_number_of_sequences(m, n):\n # Base case: If n is 0, there's only one sequence: the empty sequence.\n if n == 0:\n return 1\n \n # Base case: If n is 1, each number from 1 to m is a valid sequence.\n if n == 1:\n return m\n \n # Initialize a list to store the number of valid sequences for each starting number.\n dp = [0] * (m + 1)\n \n # For a sequence of length 1, any number from 1 to m is valid.\n for i in range(1, m + 1):\n dp[i] = 1\n \n # Calculate the number of valid sequences for lengths 2 to n.\n for length in range(2, n + 1):\n new_dp = [0] * (m + 1)\n for i in range(1, m + 1):\n for j in range(i * 2, m + 1):\n new_dp[j] += dp[i]\n dp = new_dp\n \n # Sum up all the valid sequences starting from each number.\n return sum(dp)", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n # Helper function to count sequences recursively\n def count_sequences(start, remaining_length):\n if remaining_length == 0:\n return 1\n count = 0\n for i in range(start, m + 1):\n count += count_sequences(i * 2, remaining_length - 1)\n return count\n\n # Start the sequence with the first element being 1\n return count_sequences(1, n)", "matching_cluster_idx": 5}, {"solution": "def get_total_number_of_sequences(m, n):\n # Helper function to find sequences using depth-first search (DFS)\n def dfs(start, length, m):\n if length == 0:\n return 1\n count = 0\n for i in range(start, m + 1):\n count += dfs(i * 2, length - 1, m)\n return count\n \n # Start the DFS from 1 with the full length n\n return dfs(1, n, m)", "matching_cluster_idx": 5}, {"solution": "def get_total_number_of_sequences(m, n):\n # Base case: If n is 0, there is exactly one sequence: the empty sequence.\n if n == 0:\n return 1\n # Base case: If n is 1, each number from 1 to m is a valid sequence.\n if n == 1:\n return m\n\n # Initialize the dynamic programming table\n dp = [[0 for _ in range(n + 1)] for _ in range(m + 1)]\n\n # Fill the table\n for i in range(1, m + 1):\n dp[i][1] = i # If n is 1, there are i possible sequences for each i\n\n for j in range(2, n + 1):\n for i in range(1, m + 1):\n dp[i][j] = dp[i - 1][j] # Exclude the current number\n if i >= 2:\n dp[i][j] += dp[i // 2][j - 1] # Include the current number\n\n return dp[m][n]", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n # Base case: If n is 1, there are m possible sequences (each number from 1 to m)\n if n == 1:\n return m\n \n # Base case: If m is less than 2^(n-1), no valid sequences can be formed\n if m < (1 << (n - 1)):\n return 0\n \n # Recursive case: Calculate the number of sequences by considering the last element\n return get_total_number_of_sequences(m // 2, n - 1) + get_total_number_of_sequences(m - 1, n)", "matching_cluster_idx": 9}]}, "Mbpp/240": {"dps": 93.17073170731709, "dps_norm": 96.11111111111111, "pass@1": 100.0, "profiled": [{"solution": "def replace_list(lst1, lst2):\n # Replace the last element of lst1 with all elements of lst2\n lst1[-1:] = lst2\n return lst1", "matching_cluster_idx": 7}, {"solution": "def replace_list(lst1, lst2):\n # Replace the last element of lst1 with all elements of lst2\n lst1[-1:] = lst2\n return lst1", "matching_cluster_idx": 7}, {"solution": "def replace_list(lst1, lst2):\n # Remove the last element of lst1\n lst1.pop()\n # Extend lst1 with the elements of lst2\n lst1.extend(lst2)\n return lst1", "matching_cluster_idx": 8}, {"solution": "def replace_list(lst1, lst2):\n # Remove the last element of the first list\n lst1.pop()\n # Extend the first list with the elements of the second list\n lst1.extend(lst2)\n return lst1", "matching_cluster_idx": 8}, {"solution": "def replace_list(lst1, lst2):\n # Remove the last element of the first list\n lst1.pop()\n # Extend the first list with the elements of the second list\n lst1.extend(lst2)\n return lst1", "matching_cluster_idx": 8}, {"solution": "def replace_list(lst1, lst2):\n # Replace the last element of lst1 with all elements of lst2\n lst1[-1:] = lst2\n return lst1", "matching_cluster_idx": 7}, {"solution": "def replace_list(lst1, lst2):\n # Remove the last element of lst1\n lst1.pop()\n # Extend lst1 with the elements of lst2\n lst1.extend(lst2)\n return lst1", "matching_cluster_idx": 8}, {"solution": "def replace_list(lst1, lst2):\n # Remove the last element of the first list\n lst1.pop()\n # Extend the first list with the elements of the second list\n lst1.extend(lst2)\n return lst1", "matching_cluster_idx": 8}, {"solution": "def replace_list(lst1, lst2):\n # Remove the last element of lst1\n lst1.pop()\n # Extend lst1 with all elements of lst2\n lst1.extend(lst2)\n return lst1", "matching_cluster_idx": 8}, {"solution": "def replace_list(lst1, lst2):\n # Remove the last element of lst1\n lst1.pop()\n # Extend lst1 with the elements of lst2\n lst1.extend(lst2)\n return lst1", "matching_cluster_idx": 8}, {"solution": "def replace_list(lst1, lst2):\n # Remove the last element of lst1\n lst1.pop()\n # Extend lst1 with the elements of lst2\n lst1.extend(lst2)\n return lst1", "matching_cluster_idx": 8}, {"solution": "def replace_list(lst1, lst2):\n # Remove the last element of lst1\n lst1.pop()\n # Extend lst1 with elements from lst2\n lst1.extend(lst2)\n return lst1", "matching_cluster_idx": 8}, {"solution": "def replace_list(lst1, lst2):\n # Replace the last element of lst1 with all elements of lst2\n lst1[-1:] = lst2\n return lst1", "matching_cluster_idx": 7}, {"solution": "def replace_list(lst1, lst2):\n # Remove the last element of lst1\n lst1.pop()\n # Extend lst1 with all elements of lst2\n lst1.extend(lst2)\n return lst1", "matching_cluster_idx": 8}, {"solution": "def replace_list(lst1, lst2):\n # Replace the last element of lst1 with the elements of lst2\n lst1[-1:] = lst2\n return lst1", "matching_cluster_idx": 7}, {"solution": "def replace_list(lst1, lst2):\n # Replace the last element of lst1 with all elements of lst2\n lst1[-1:] = lst2\n return lst1", "matching_cluster_idx": 7}, {"solution": "def replace_list(lst1, lst2):\n # Remove the last element of the first list\n lst1.pop()\n # Extend the first list with the elements of the second list\n lst1.extend(lst2)\n return lst1", "matching_cluster_idx": 8}, {"solution": "def replace_list(lst1, lst2):\n # Remove the last element of lst1\n lst1.pop()\n # Extend lst1 with the elements of lst2\n lst1.extend(lst2)\n return lst1", "matching_cluster_idx": 8}, {"solution": "def replace_list(lst1, lst2):\n # Replace the last element of lst1 with all elements of lst2\n lst1[-1:] = lst2\n return lst1", "matching_cluster_idx": 7}, {"solution": "def replace_list(lst1, lst2):\n # Remove the last element of lst1\n lst1.pop()\n # Extend lst1 with all elements of lst2\n lst1.extend(lst2)\n return lst1", "matching_cluster_idx": 8}]}, "Mbpp/251": {"dps": 91.95402298850576, "dps_norm": 77.77777777777777, "pass@1": 100.0, "profiled": [{"solution": "def insert_element(lst, element):\n # Initialize an empty result list\n result = []\n \n # Iterate over each item in the input list\n for item in lst:\n # Insert the element before the current item\n result.append(element)\n result.append(item)\n \n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n # Create a new list to store the result\n result = []\n # Iterate over each item in the original list\n for item in lst:\n # Insert the given element before the current item\n result.append(element)\n result.append(item)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n # Initialize an empty list to store the result\n result = []\n \n # Iterate through each item in the input list\n for item in lst:\n # Insert the element before the current item\n result.append(element)\n result.append(item)\n \n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n # Initialize an empty list to store the result\n result = []\n # Iterate through each item in the input list\n for item in lst:\n # Append the element to be inserted before the current item\n result.append(element)\n # Append the current item\n result.append(item)\n # Return the resulting list\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n # Create a new list to store the result\n result = []\n # Iterate over each item in the original list\n for item in lst:\n # Append the element to be inserted\n result.append(element)\n # Append the current item\n result.append(item)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n # Create a new list to store the result\n result = []\n # Iterate through each item in the input list\n for item in lst:\n # Insert the element before the current item\n result.append(element)\n result.append(item)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n # Create a new list to store the result\n result = []\n # Iterate through each item in the original list\n for item in lst:\n # Append the element and then the item to the result list\n result.append(element)\n result.append(item)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n # Initialize an empty list to store the result\n result = []\n \n # Iterate over each item in the input list\n for item in lst:\n # Insert the element before the current item\n result.append(element)\n result.append(item)\n \n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n # Create a new list to store the result\n result = []\n \n # Iterate through each item in the original list\n for item in lst:\n # Insert the element before the current item\n result.append(element)\n result.append(item)\n \n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n # Create a new list to store the result\n result = []\n \n # Iterate over each item in the original list\n for item in lst:\n # Insert the element before the current item\n result.append(element)\n result.append(item)\n \n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n # Initialize an empty list to store the result\n result = []\n \n # Iterate through each item in the original list\n for item in lst:\n # Insert the element before the current item\n result.append(element)\n result.append(item)\n \n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n # Initialize an empty list to store the result\n result = []\n \n # Iterate through each item in the original list\n for item in lst:\n # Insert the element before the current item\n result.append(element)\n result.append(item)\n \n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n # Create a new list to store the result\n result = []\n # Iterate through each item in the original list\n for item in lst:\n # Append the given element before the current item\n result.append(element)\n result.append(item)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n # Initialize an empty list to store the result\n result = []\n \n # Iterate through each item in the input list\n for item in lst:\n # Insert the element before the current item\n result.append(element)\n result.append(item)\n \n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n # Initialize an empty list to store the result\n result = []\n \n # Iterate over each item in the input list\n for item in lst:\n # Insert the element before the current item\n result.append(element)\n result.append(item)\n \n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n # Initialize an empty list to store the result\n result = []\n \n # Iterate through each item in the input list\n for item in lst:\n # Insert the element before the current item\n result.append(element)\n result.append(item)\n \n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n # Initialize an empty list to store the result\n result = []\n \n # Iterate through each item in the input list\n for item in lst:\n # Append the element and then the item to the result list\n result.append(element)\n result.append(item)\n \n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n # Initialize an empty list to store the result\n result = []\n \n # Iterate through each item in the input list\n for item in lst:\n # Insert the element before the current item\n result.append(element)\n result.append(item)\n \n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n # Initialize an empty list to store the result\n result = []\n \n # Iterate through each item in the input list\n for item in lst:\n # Insert the element before the current item\n result.append(element)\n result.append(item)\n \n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n # Initialize an empty list to store the result\n result = []\n \n # Iterate through each item in the input list\n for item in lst:\n # Insert the specified element before the current item\n result.append(element)\n result.append(item)\n \n return result", "matching_cluster_idx": 6}]}, "Mbpp/256": {"dps": 57.89954337899543, "dps_norm": 54.11764705882353, "pass@1": 100.0, "profiled": [{"solution": "def count_Primes_nums(n):\n # Initialize a counter for prime numbers\n count = 0\n # Iterate through each number from 2 to n-1\n for num in range(2, n):\n # Assume the number is prime\n is_prime = True\n # Check divisibility by any number from 2 to the square root of num\n for divisor in range(2, int(num**0.5) + 1):\n if num % divisor == 0:\n # If divisible, it's not a prime number\n is_prime = False\n break\n # If the number is prime, increment the counter\n if is_prime:\n count += 1\n return count", "matching_cluster_idx": 8}, {"solution": "def count_Primes_nums(n):\n # Initialize a counter for prime numbers\n count = 0\n # Iterate through numbers from 2 up to (but not including) n\n for num in range(2, n):\n # Assume the number is prime\n is_prime = True\n # Check divisibility from 2 up to the square root of num\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n # If divisible, it's not prime\n is_prime = False\n break\n # If the number is prime, increment the counter\n if is_prime:\n count += 1\n return count", "matching_cluster_idx": 8}, {"solution": "def count_Primes_nums(n):\n # Initialize the count of prime numbers\n count = 0\n \n # Helper function to check if a number is prime\n def is_prime(num):\n if num <= 1:\n return False\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n return False\n return True\n \n # Iterate through numbers less than n to count primes\n for i in range(2, n):\n if is_prime(i):\n count += 1\n \n return count", "matching_cluster_idx": 8}, {"solution": "def count_Primes_nums(n):\n # Define a helper function to check if a number is prime\n def is_prime(num):\n if num <= 1:\n return False\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n return False\n return True\n\n # Count the number of prime numbers less than n\n count = 0\n for i in range(2, n):\n if is_prime(i):\n count += 1\n\n return count", "matching_cluster_idx": 8}, {"solution": "def count_Primes_nums(n):\n # Initialize a counter for prime numbers\n count = 0\n \n # Helper function to check if a number is prime\n def is_prime(num):\n if num <= 1:\n return False\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n return False\n return True\n \n # Iterate through numbers less than n and count primes\n for i in range(2, n):\n if is_prime(i):\n count += 1\n \n return count", "matching_cluster_idx": 8}, {"solution": "def count_Primes_nums(n):\n # Initialize a counter for prime numbers\n count = 0\n \n # Helper function to check if a number is prime\n def is_prime(num):\n if num <= 1:\n return False\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n return False\n return True\n \n # Iterate through all numbers less than n and count primes\n for i in range(2, n):\n if is_prime(i):\n count += 1\n \n return count", "matching_cluster_idx": 8}, {"solution": "def is_prime(n):\n # Check if a number is prime\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True\ndef count_Primes_nums(num):\n # Count the number of prime numbers less than the given number\n count = 0\n for i in range(2, num):\n if is_prime(i):\n count += 1\n return count", "matching_cluster_idx": 10}, {"solution": "def count_Primes_nums(n):\n # Helper function to check if a number is prime\n def is_prime(num):\n if num <= 1:\n return False\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n return False\n return True\n\n # Count the number of prime numbers less than n\n count = 0\n for i in range(2, n):\n if is_prime(i):\n count += 1\n return count", "matching_cluster_idx": 8}, {"solution": "def count_Primes_nums(n):\n # Initialize a counter for prime numbers\n count = 0\n \n # Function to check if a number is prime\n def is_prime(num):\n if num <= 1:\n return False\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n return False\n return True\n \n # Iterate through numbers less than n and count primes\n for i in range(2, n):\n if is_prime(i):\n count += 1\n \n return count", "matching_cluster_idx": 8}, {"solution": "def count_Primes_nums(n):\n # Initialize a counter for prime numbers\n count = 0\n # Iterate over each number from 2 up to (but not including) n\n for num in range(2, n):\n # Assume the number is prime until proven otherwise\n is_prime = True\n # Check divisibility by all numbers from 2 to the square root of num\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n # If divisible, it's not prime\n is_prime = False\n break\n # If the number is prime, increment the counter\n if is_prime:\n count += 1\n return count", "matching_cluster_idx": 8}, {"solution": "def count_Primes_nums(n):\n # Initialize a counter for prime numbers\n count = 0\n # Loop through numbers from 2 to n-1\n for num in range(2, n):\n # Assume the number is prime\n is_prime = True\n # Check divisibility by any number from 2 to the square root of num\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n # If divisible, it's not a prime number\n is_prime = False\n break\n # If the number is prime, increment the counter\n if is_prime:\n count += 1\n return count", "matching_cluster_idx": 8}, {"solution": "def is_prime(n):\n # Check if a number is prime\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True\ndef count_Primes_nums(num):\n # Count the number of prime numbers less than the given number\n count = 0\n for i in range(2, num):\n if is_prime(i):\n count += 1\n return count", "matching_cluster_idx": 8}, {"solution": "def count_Primes_nums(n):\n # Initialize a counter for prime numbers\n count = 0\n # Iterate through each number from 2 to n-1\n for num in range(2, n):\n # Assume the number is prime\n is_prime = True\n # Check divisibility by any number from 2 to the square root of num\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n # If divisible, it's not a prime number\n is_prime = False\n break\n # If the number is prime, increment the counter\n if is_prime:\n count += 1\n return count", "matching_cluster_idx": 8}, {"solution": "def is_prime(n):\n # Check if a number is a prime number\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True\ndef count_Primes_nums(n):\n # Count the number of prime numbers less than n\n count = 0\n for i in range(2, n):\n if is_prime(i):\n count += 1\n return count", "matching_cluster_idx": 8}, {"solution": "def count_Primes_nums(n):\n # Initialize a counter for prime numbers\n count = 0\n # Loop through numbers from 2 to n-1\n for num in range(2, n):\n # Assume the number is prime\n is_prime = True\n # Check divisibility by any number from 2 to the square root of num\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n # If divisible, it's not a prime number\n is_prime = False\n break\n # If the number is prime, increment the counter\n if is_prime:\n count += 1\n return count", "matching_cluster_idx": 8}, {"solution": "def count_Primes_nums(n):\n # Initialize a counter for prime numbers\n count = 0\n # Loop through all numbers from 2 to n-1\n for num in range(2, n):\n # Assume the number is prime\n is_prime = True\n # Check divisibility from 2 to the square root of num\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n # If divisible, it's not prime\n is_prime = False\n break\n # If the number is prime, increment the counter\n if is_prime:\n count += 1\n return count", "matching_cluster_idx": 8}, {"solution": "def is_prime(n):\n # Check if a number is a prime number\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True\ndef count_Primes_nums(num):\n # Count the number of prime numbers less than the given number\n count = 0\n for i in range(2, num):\n if is_prime(i):\n count += 1\n return count", "matching_cluster_idx": 8}, {"solution": "def is_prime(n):\n # Check if a number is a prime number\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True\ndef count_Primes_nums(n):\n # Count the number of prime numbers less than n\n count = 0\n for i in range(2, n):\n if is_prime(i):\n count += 1\n return count", "matching_cluster_idx": 8}, {"solution": "def is_prime(num):\n # Check if a number is a prime number\n if num < 2:\n return False\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n return False\n return True\ndef count_Primes_nums(n):\n # Count the number of prime numbers less than n\n count = 0\n for i in range(2, n):\n if is_prime(i):\n count += 1\n return count", "matching_cluster_idx": 8}, {"solution": "def is_prime(n):\n # Check if a number is a prime number\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True\ndef count_Primes_nums(num):\n # Count the number of prime numbers less than the given number\n count = 0\n for i in range(2, num):\n if is_prime(i):\n count += 1\n return count", "matching_cluster_idx": 10}]}, "Mbpp/265": {"dps": 67.26744186046511, "dps_norm": 80.0, "pass@1": 100.0, "profiled": [{"solution": "def list_split(lst, n):\n # Create a list of lists, where each sublist contains elements at positions\n # that are multiples of the current index when divided by n\n return [lst[i::n] for i in range(n)]", "matching_cluster_idx": 5}, {"solution": "def list_split(lst, n):\n # Create a list of lists, where each sublist contains elements from the original list\n # starting from index i and taking every nth element.\n return [lst[i::n] for i in range(n)]", "matching_cluster_idx": 5}, {"solution": "def list_split(lst, n):\n # Initialize an empty list to hold the split lists\n result = []\n \n # Loop from 0 to n-1 to create n lists\n for i in range(n):\n # Use list comprehension to collect every nth element starting from i\n result.append([lst[j] for j in range(i, len(lst), n)])\n \n return result", "matching_cluster_idx": 1}, {"solution": "def list_split(lst, n):\n # Create a list of lists by slicing the original list every nth element\n result = [lst[i::n] for i in range(n)]\n return result", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n # Create an empty list of lists to hold the result\n result = [[] for _ in range(n)]\n \n # Iterate over the list, placing each element in the appropriate sublist\n for index, item in enumerate(lst):\n result[index % n].append(item)\n \n return result", "matching_cluster_idx": 3}, {"solution": "def list_split(lst, n):\n # Create a list of lists where each inner list contains elements from the original list\n # starting from index i and skipping n-1 elements each time\n result = [lst[i::n] for i in range(n)]\n return result", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n # Create a list of lists, where each inner list contains elements at positions\n # that are multiples of n, starting from the index 0 up to n-1\n result = [[] for _ in range(n)]\n for i in range(len(lst)):\n result[i % n].append(lst[i])\n \n return result", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n # Split the list for every nth element and return a list of the resulting lists\n result = [lst[i::n] for i in range(n)]\n return result", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n # Initialize an empty list to hold the result\n result = []\n \n # Loop through the range of n to create n sublists\n for i in range(n):\n # Create a sublist starting from the i-th element, taking every n-th element\n sub_list = lst[i::n]\n # Append the sublist to the result list\n result.append(sub_list)\n \n return result", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n # Initialize an empty list to store the result\n result = []\n \n # Iterate over the range of n to create sublists\n for i in range(n):\n # Use list comprehension to collect every nth element starting from i\n sublist = [lst[j] for j in range(i, len(lst), n)]\n # Append the sublist to the result list\n result.append(sublist)\n \n return result", "matching_cluster_idx": 1}, {"solution": "def list_split(lst, n):\n # Create a list of lists by splitting the original list every nth element\n result = [lst[i::n] for i in range(n)]\n return result", "matching_cluster_idx": 5}, {"solution": "def list_split(lst, n):\n # Initialize an empty list of lists to store the result\n result = []\n \n # Iterate over the range of n to create n sublists\n for i in range(n):\n # Create a sublist by slicing the original list starting from i and taking every nth element\n sublist = lst[i::n]\n # Append the sublist to the result list\n result.append(sublist)\n \n return result", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n # Create a list of lists, where each inner list contains elements from the original list\n # at positions that are multiples of n, starting from each of the first n elements.\n return [lst[i::n] for i in range(n)]", "matching_cluster_idx": 5}, {"solution": "def list_split(lst, n):\n # Create a list of lists by slicing the original list at intervals of n\n return [lst[i::n] for i in range(n)]", "matching_cluster_idx": 1}, {"solution": "def list_split(lst, n):\n # Initialize an empty list of lists to store the result\n result = []\n \n # Loop through the range of n to create n sublists\n for i in range(n):\n # Create a sublist starting from the ith element and taking every nth element\n sublist = lst[i::n]\n # Append the sublist to the result list\n result.append(sublist)\n \n return result", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n # Initialize an empty list of lists to hold the result\n result = []\n \n # Create n empty sublists in the result list\n for _ in range(n):\n result.append([])\n \n # Distribute elements of the original list into the sublists\n for index, item in enumerate(lst):\n result[index % n].append(item)\n \n return result", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n # Create a list of lists, where each inner list contains elements at positions that are multiples of n, starting from 0 to n-1\n return [lst[i::n] for i in range(n)]", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n # Split the list into sublists for every nth element\n return [lst[i::n] for i in range(n)]", "matching_cluster_idx": 5}, {"solution": "def list_split(lst, n):\n # Create a list of lists by slicing the original list at intervals of n\n result = [lst[i::n] for i in range(n)]\n return result", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n # Create a list of lists where each sublist contains elements at positions that are multiples of n, starting from 0 to n-1\n result = [lst[i::n] for i in range(n)]\n return result", "matching_cluster_idx": 5}]}, "Mbpp/281": {"dps": 94.05, "dps_norm": 82.27272727272727, "pass@1": 100.0, "profiled": [{"solution": "def all_unique(data):\n # Convert the list to a set and compare its length to the original list's length\n return len(data) == len(set(data))", "matching_cluster_idx": 8}, {"solution": "def all_unique(data):\n # Convert the list to a set to remove duplicates\n # If the length of the set is the same as the list, all elements are unique\n return len(data) == len(set(data))", "matching_cluster_idx": 8}, {"solution": "def all_unique(data):\n # Convert the list to a set and compare its length to the original list's length\n # If lengths are equal, all elements are unique\n return len(data) == len(set(data))", "matching_cluster_idx": 8}, {"solution": "def all_unique(data):\n # Convert the list to a set to remove duplicates\n # If the length of the set is the same as the length of the list, all elements are unique\n return len(data) == len(set(data))", "matching_cluster_idx": 8}, {"solution": "def all_unique(data):\n # Convert the list to a set and compare lengths\n # If lengths are the same, all elements are unique\n return len(data) == len(set(data))", "matching_cluster_idx": 8}, {"solution": "def all_unique(data):\n # Use a set to track unique elements\n seen = set()\n for item in data:\n # If the item is already in the set, return False\n if item in seen:\n return False\n # Otherwise, add the item to the set\n seen.add(item)\n # If all items are unique, return True\n return True", "matching_cluster_idx": 9}, {"solution": "def all_unique(data):\n # Convert the list to a set and compare the lengths\n # If lengths are the same, all elements are unique\n return len(data) == len(set(data))", "matching_cluster_idx": 8}, {"solution": "def all_unique(data):\n # Convert the list to a set and compare its length to the original list's length\n return len(data) == len(set(data))", "matching_cluster_idx": 8}, {"solution": "def all_unique(data):\n # Convert the list to a set and compare its length to the original list's length\n # If they are equal, all elements are unique\n return len(data) == len(set(data))", "matching_cluster_idx": 8}, {"solution": "def all_unique(data):\n # Convert the list to a set and compare its length to the original list's length\n return len(data) == len(set(data))", "matching_cluster_idx": 8}, {"solution": "def all_unique(data):\n # Convert the list to a set and compare its length to the original list's length\n return len(data) == len(set(data))", "matching_cluster_idx": 8}, {"solution": "def all_unique(data):\n # Convert the list to a set and compare its length with the original list\n return len(data) == len(set(data))", "matching_cluster_idx": 8}, {"solution": "def all_unique(data):\n # Convert the list to a set and compare its length to the original list's length\n # If they are equal, all elements are unique\n return len(data) == len(set(data))", "matching_cluster_idx": 8}, {"solution": "def all_unique(data):\n # Convert the list to a set to remove duplicates\n # If the length of the set is the same as the length of the list, all elements are unique\n return len(data) == len(set(data))", "matching_cluster_idx": 8}, {"solution": "def all_unique(data):\n # Convert the list to a set and compare lengths\n # If lengths are the same, all elements are unique\n return len(data) == len(set(data))", "matching_cluster_idx": 8}, {"solution": "def all_unique(data):\n # Convert the list to a set and compare its length to the original list's length\n # If they are the same, all elements are unique\n return len(data) == len(set(data))", "matching_cluster_idx": 8}, {"solution": "def all_unique(data):\n # Convert the list to a set and compare its length to the original list's length\n # If lengths are equal, all elements are unique\n return len(data) == len(set(data))", "matching_cluster_idx": 8}, {"solution": "def all_unique(data):\n # Convert the list to a set and compare the lengths\n # If lengths are the same, all elements are unique\n return len(data) == len(set(data))", "matching_cluster_idx": 8}, {"solution": "def all_unique(data):\n # Convert the list to a set and compare lengths\n # If lengths are the same, all elements are unique\n return len(data) == len(set(data))", "matching_cluster_idx": 8}, {"solution": "def all_unique(data):\n # Convert the list to a set and compare its length with the original list\n return len(data) == len(set(data))", "matching_cluster_idx": 8}]}, "Mbpp/296": {"dps": 28.205128205128204, "dps_norm": 66.66666666666667, "pass@1": 100.0, "profiled": [{"solution": "def get_Inv_Count(arr):\n n = len(arr)\n inv_count = 0\n for i in range(n):\n for j in range(i + 1, n):\n if arr[i] > arr[j]:\n inv_count += 1\n return inv_count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n # Initialize the inversion count to 0\n inv_count = 0\n # Iterate over each element in the array\n for i in range(len(arr)):\n # Compare the current element with all subsequent elements\n for j in range(i + 1, len(arr)):\n # If an inversion is found, increment the count\n if arr[i] > arr[j]:\n inv_count += 1\n return inv_count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n n = len(arr)\n inv_count = 0\n for i in range(n):\n for j in range(i + 1, n):\n if arr[i] > arr[j]:\n inv_count += 1\n return inv_count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n n = len(arr)\n inv_count = 0\n for i in range(n):\n for j in range(i + 1, n):\n if arr[i] > arr[j]:\n inv_count += 1\n return inv_count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n # Initialize inversion count to 0\n inv_count = 0\n # Iterate through each element in the array\n for i in range(len(arr)):\n # Compare with each subsequent element\n for j in range(i + 1, len(arr)):\n # If an inversion is found, increment the count\n if arr[i] > arr[j]:\n inv_count += 1\n return inv_count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n n = len(arr)\n inv_count = 0\n for i in range(n):\n for j in range(i + 1, n):\n if arr[i] > arr[j]:\n inv_count += 1\n return inv_count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n inv_count = 0\n n = len(arr)\n for i in range(n):\n for j in range(i + 1, n):\n if arr[i] > arr[j]:\n inv_count += 1\n return inv_count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n # Initialize the number of inversions to 0\n inv_count = 0\n # Iterate through the array\n for i in range(len(arr)):\n for j in range(i + 1, len(arr)):\n # If an inversion is found, increment the count\n if arr[i] > arr[j]:\n inv_count += 1\n return inv_count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n # Initialize inversion count to 0\n inv_count = 0\n # Iterate through each element in the array\n for i in range(len(arr)):\n # Compare the current element with the rest of the elements in the array\n for j in range(i + 1, len(arr)):\n # If an inversion is found, increment the count\n if arr[i] > arr[j]:\n inv_count += 1\n return inv_count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n # Initialize inversion count to 0\n inv_count = 0\n # Iterate through the array\n for i in range(len(arr)):\n for j in range(i + 1, len(arr)):\n # If an inversion is found, increment the count\n if arr[i] > arr[j]:\n inv_count += 1\n return inv_count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n # Initialize the inversion count to 0\n inv_count = 0\n # Iterate over each element in the array\n for i in range(len(arr)):\n # Compare the current element with all subsequent elements\n for j in range(i + 1, len(arr)):\n # If a pair (arr[i], arr[j]) forms an inversion, increment the count\n if arr[i] > arr[j]:\n inv_count += 1\n return inv_count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n # Initialize inversion count to 0\n inv_count = 0\n # Iterate through the array\n for i in range(len(arr)):\n for j in range(i + 1, len(arr)):\n # If an inversion is found, increment the count\n if arr[i] > arr[j]:\n inv_count += 1\n return inv_count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n # Initialize inversion count to 0\n inv_count = 0\n # Iterate through the array\n for i in range(len(arr)):\n for j in range(i + 1, len(arr)):\n # If an inversion is found, increment the count\n if arr[i] > arr[j]:\n inv_count += 1\n return inv_count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n n = len(arr)\n inv_count = 0\n for i in range(n):\n for j in range(i + 1, n):\n if arr[i] > arr[j]:\n inv_count += 1\n return inv_count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n inv_count = 0\n n = len(arr)\n for i in range(n):\n for j in range(i + 1, n):\n if arr[i] > arr[j]:\n inv_count += 1\n return inv_count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n # Initialize the inversion count to 0\n inv_count = 0\n # Iterate through the array\n for i in range(len(arr)):\n for j in range(i + 1, len(arr)):\n # If an inversion is found, increment the count\n if arr[i] > arr[j]:\n inv_count += 1\n return inv_count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n # Initialize inversion count\n inv_count = 0\n # Traverse through the array\n for i in range(len(arr)):\n for j in range(i + 1, len(arr)):\n # If an inversion is found, increment the count\n if arr[i] > arr[j]:\n inv_count += 1\n return inv_count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n # Initialize the inversion count to 0\n inv_count = 0\n # Iterate through the array\n for i in range(len(arr)):\n for j in range(i + 1, len(arr)):\n # If an inversion is found, increment the count\n if arr[i] > arr[j]:\n inv_count += 1\n return inv_count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n # Initialize inversion count to 0\n inv_count = 0\n # Iterate through each element in the array\n for i in range(len(arr)):\n # Compare the current element with the elements that come after it\n for j in range(i + 1, len(arr)):\n # If an inversion is found, increment the count\n if arr[i] > arr[j]:\n inv_count += 1\n return inv_count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n n = len(arr)\n inv_count = 0\n for i in range(n):\n for j in range(i + 1, n):\n if arr[i] > arr[j]:\n inv_count += 1\n return inv_count", "matching_cluster_idx": 3}]}, "Mbpp/308": {"dps": 97.58620689655173, "dps_norm": 66.66666666666667, "pass@1": 100.0, "profiled": [{"solution": "def large_product(list1, list2, num):\n # Sort both lists in descending order to get the largest values first\n list1.sort(reverse=True)\n list2.sort(reverse=True)\n \n # Generate all possible products\n products = [x * y for x in list1 for y in list2]\n \n # Sort the products in descending order\n products.sort(reverse=True)\n \n # Return the first 'num' products\n return products[:num]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, k):\n # Sort both lists in descending order to get the largest products\n list1.sort(reverse=True)\n list2.sort(reverse=True)\n \n # Initialize a list to store the products\n products = []\n \n # Calculate the product of each combination of elements from both lists\n for num1 in list1:\n for num2 in list2:\n products.append(num1 * num2)\n \n # Sort the products in descending order\n products.sort(reverse=True)\n \n # Return the first k elements from the sorted products list\n return products[:k]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, num):\n # Generate all possible products between elements of list1 and list2\n products = [x * y for x in list1 for y in list2]\n \n # Sort the products in descending order\n products.sort(reverse=True)\n \n # Return the first 'num' largest products\n return products[:num]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, num):\n # Generate all possible products between elements of list1 and list2\n products = sorted([x * y for x in list1 for y in list2], reverse=True)\n \n # Return the first 'num' largest products\n return products[:num]", "matching_cluster_idx": 3}, {"solution": "def large_product(nums1, nums2, k):\n # Initialize an empty list to store the products\n products = []\n \n # Compute the product of each pair (x, y) where x is from nums1 and y is from nums2\n for x in nums1:\n for y in nums2:\n products.append(x * y)\n \n # Sort the list of products in descending order\n products.sort(reverse=True)\n \n # Return the first k elements from the sorted list\n return products[:k]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n # Generate all possible products by taking one element from each list\n products = [x * y for x in list1 for y in list2]\n \n # Sort the products in descending order\n products.sort(reverse=True)\n \n # Return the first n largest products\n return products[:n]", "matching_cluster_idx": 3}, {"solution": "def large_product(lst1, lst2, num):\n # Generate all possible products from elements of lst1 and lst2\n products = [x * y for x in lst1 for y in lst2]\n \n # Sort the products in descending order\n products.sort(reverse=True)\n \n # Return the first 'num' elements from the sorted products\n return products[:num]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n # Sort both lists in descending order to get the largest products\n list1.sort(reverse=True)\n list2.sort(reverse=True)\n \n # Generate all possible products\n products = [x * y for x in list1 for y in list2]\n \n # Sort the products in descending order\n products.sort(reverse=True)\n \n # Return the first n products from the sorted list\n return products[:n]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, num):\n # Initialize an empty list to store the products\n products = []\n \n # Compute all possible products between elements of list1 and list2\n for i in list1:\n for j in list2:\n products.append(i * j)\n \n # Sort the products in descending order\n products.sort(reverse=True)\n \n # Return the first 'num' elements from the sorted list\n return products[:num]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, num):\n # Initialize an empty list to store the products\n products = []\n \n # Iterate through each element in the first list\n for i in list1:\n # Iterate through each element in the second list\n for j in list2:\n # Calculate the product and append it to the products list\n products.append(i * j)\n \n # Sort the products list in descending order\n products.sort(reverse=True)\n \n # Return the first 'num' elements from the sorted list\n return products[:num]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, num):\n # Initialize an empty list to store the products\n products = []\n \n # Iterate through each element in list1\n for i in list1:\n # Iterate through each element in list2\n for j in list2:\n # Calculate the product of the two elements\n product = i * j\n # Append the product to the products list\n products.append(product)\n \n # Sort the products list in descending order\n products.sort(reverse=True)\n \n # Return the first 'num' elements from the sorted products list\n return products[:num]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n # Sort both lists in descending order to get the largest products\n list1.sort(reverse=True)\n list2.sort(reverse=True)\n \n # Generate all possible products\n products = [x * y for x in list1 for y in list2]\n \n # Sort the products in descending order and get the top n products\n products.sort(reverse=True)\n return products[:n]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n # Generate all possible products from elements of list1 and list2\n products = [x * y for x in list1 for y in list2]\n \n # Sort the products in descending order\n products.sort(reverse=True)\n \n # Return the first n products from the sorted list\n return products[:n]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n # Initialize an empty list to store the products\n products = []\n \n # Iterate through each element in the first list\n for num1 in list1:\n # Iterate through each element in the second list\n for num2 in list2:\n # Calculate the product and add it to the products list\n products.append(num1 * num2)\n \n # Sort the products list in descending order\n products.sort(reverse=True)\n \n # Return the first n elements from the sorted list\n return products[:n]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n # Generate all possible products between elements of the two lists\n products = [x * y for x in list1 for y in list2]\n \n # Sort the products in descending order\n products.sort(reverse=True)\n \n # Return the first n products from the sorted list\n return products[:n]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, num):\n # Generate all possible products from the two lists\n products = sorted([x * y for x in list1 for y in list2], reverse=True)\n \n # Return the first 'num' elements from the sorted products list\n return products[:num]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, num):\n # Generate all possible products between elements of list1 and list2\n products = sorted([x * y for x in list1 for y in list2], reverse=True)\n \n # Return the first 'num' elements from the sorted products\n return products[:num]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n # Sort both lists in descending order to get the largest elements first\n list1.sort(reverse=True)\n list2.sort(reverse=True)\n \n # Initialize an empty list to store the products\n products = []\n \n # Calculate the product of each element in list1 with each element in list2\n for num1 in list1:\n for num2 in list2:\n products.append(num1 * num2)\n \n # Sort the products in descending order\n products.sort(reverse=True)\n \n # Return the first n largest products\n return products[:n]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, num):\n # Generate all possible products between elements of list1 and list2\n products = [x * y for x in list1 for y in list2]\n \n # Sort the products in descending order\n products.sort(reverse=True)\n \n # Return the first 'num' elements from the sorted products\n return products[:num]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n # Calculate all possible products\n products = [x * y for x in list1 for y in list2]\n \n # Sort the products in descending order\n products.sort(reverse=True)\n \n # Return the first n elements from the sorted list\n return products[:n]", "matching_cluster_idx": 3}]}, "Mbpp/392": {"dps": 89.15492957746478, "dps_norm": 89.23076923076923, "pass@1": 92.0, "profiled": [{"solution": "def get_max_sum(n, memo={}):\n # Check if the result is already computed and stored in memo\n if n in memo:\n return memo[n]\n \n # Base case: if n is less than or equal to 1, return n\n if n <= 1:\n return n\n \n # Compute the maximum sum using the given equation\n max_sum = max(n, get_max_sum(n // 2, memo) + get_max_sum(n // 3, memo) + get_max_sum(n // 4, memo) + get_max_sum(n // 5, memo))\n \n # Store the result in memo\n memo[n] = max_sum\n \n return max_sum", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n, memo={}):\n # Check if the result is already computed and stored in memo\n if n in memo:\n return memo[n]\n \n # Base case: if n is less than 2, the maximum sum is n itself\n if n < 2:\n return n\n \n # Compute the maximum sum using the given formula\n # Also, include n itself as a potential maximum\n max_sum = max(n, get_max_sum(n // 2, memo) + get_max_sum(n // 3, memo) + get_max_sum(n // 4, memo) + get_max_sum(n // 5, memo))\n \n # Store the computed result in memo to avoid redundant calculations\n memo[n] = max_sum\n \n return max_sum", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n # Base case: if n is less than 2, return n\n if n < 2:\n return n\n \n # Recursive case: calculate the maximum sum using the given equation\n return max(n, get_max_sum(n // 2) + get_max_sum(n // 3) + get_max_sum(n // 4) + get_max_sum(n // 5))", "matching_cluster_idx": 3}, {"solution": "def get_max_sum(n, memo={}):\n # Check if the result is already computed\n if n in memo:\n return memo[n]\n \n # Base case: if n is less than or equal to 1, return n\n if n <= 1:\n return n\n \n # Compute the maximum sum using the given equation\n max_sum = max(n, get_max_sum(n // 2, memo) + get_max_sum(n // 3, memo) + get_max_sum(n // 4, memo) + get_max_sum(n // 5, memo))\n \n # Store the result in the memo dictionary\n memo[n] = max_sum\n \n return max_sum", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n, memo={}):\n # Check if the result is already computed\n if n in memo:\n return memo[n]\n \n # Base case: if n is less than or equal to 1, the sum is n itself\n if n <= 1:\n return n\n \n # Calculate the sum using the given equation\n sum_with_division = get_max_sum(n // 2, memo) + get_max_sum(n // 3, memo) + get_max_sum(n // 4, memo) + get_max_sum(n // 5, memo)\n \n # Determine the maximum between the calculated sum and the number itself\n result = max(sum_with_division, n)\n \n # Store the result in the memo dictionary\n memo[n] = result\n \n return result", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n # Base case: if n is 0, the sum is 0\n if n == 0:\n return 0\n \n # Recursive case: calculate the sum using the given equation\n return max(n, get_max_sum(n // 2) + get_max_sum(n // 3) + get_max_sum(n // 4) + get_max_sum(n // 5))", "matching_cluster_idx": 2}, {"solution": "def get_max_sum(n, memo={}):\n # Check if the result is already computed\n if n in memo:\n return memo[n]\n \n # Base case: if n is 0 or 1, return n\n if n <= 1:\n return n\n \n # Recursive case: compute the sum of f(n/2), f(n/3), f(n/4), and f(n/5)\n max_sum = max(n, get_max_sum(n // 2, memo) + get_max_sum(n // 3, memo) + get_max_sum(n // 4, memo) + get_max_sum(n // 5, memo))\n \n # Store the result in the memo dictionary\n memo[n] = max_sum\n \n return max_sum", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n, memo={}):\n # Check if the result is already computed and stored in memo\n if n in memo:\n return memo[n]\n \n # Base case: if n is less than the smallest integer that can be divided by 2, 3, 4, and 5\n if n < 2:\n return n\n \n # Calculate the maximum sum using the given equation\n max_sum = max(n, get_max_sum(n // 2, memo) + get_max_sum(n // 3, memo) + get_max_sum(n // 4, memo) + get_max_sum(n // 5, memo))\n \n # Store the result in memo to avoid recomputation\n memo[n] = max_sum\n \n return max_sum", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n, memo={}):\n # Check if the result is already computed\n if n in memo:\n return memo[n]\n \n # Base case: if n is 0 or 1, return n\n if n <= 1:\n return n\n \n # Calculate the maximum sum using the given equation\n result = max(n, get_max_sum(n // 2, memo) + get_max_sum(n // 3, memo) + get_max_sum(n // 4, memo) + get_max_sum(n // 5, memo))\n \n # Store the result in the memo dictionary\n memo[n] = result\n \n return result", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n, memo={}):\n # Check if the result is already computed and stored in memo\n if n in memo:\n return memo[n]\n \n # Base case: if n is less than or equal to 5, return n\n if n <= 5:\n return n\n \n # Recursive case: calculate the maximum of n and the sum of f(n/2), f(n/3), f(n/4), f(n/5)\n max_sum = max(n, get_max_sum(n // 2, memo) + get_max_sum(n // 3, memo) + get_max_sum(n // 4, memo) + get_max_sum(n // 5, memo))\n \n # Store the result in memo to avoid redundant calculations\n memo[n] = max_sum\n \n return max_sum", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n, memo={}):\n # Check if the result is already computed\n if n in memo:\n return memo[n]\n \n # Base case: if n is less than or equal to 1, return n\n if n <= 1:\n return n\n \n # Compute the maximum sum using the given formula\n max_sum = max(n, get_max_sum(n // 2, memo) + get_max_sum(n // 3, memo) + get_max_sum(n // 4, memo) + get_max_sum(n // 5, memo))\n \n # Store the result in memo dictionary\n memo[n] = max_sum\n \n return max_sum", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n, memo={}):\n # Check if the result is already computed\n if n in memo:\n return memo[n]\n \n # Base case: if n is less than or equal to 1, return n\n if n <= 1:\n return n\n \n # Compute the maximum sum using the given equation\n max_sum = max(n, get_max_sum(n // 2, memo) + get_max_sum(n // 3, memo) + get_max_sum(n // 4, memo) + get_max_sum(n // 5, memo))\n \n # Store the result in memo dictionary\n memo[n] = max_sum\n \n return max_sum", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n, memo={}):\n # Check if the result is already computed\n if n in memo:\n return memo[n]\n \n # Base case: if n is 0 or 1, the sum is n itself\n if n == 0 or n == 1:\n return n\n \n # Compute the maximum sum using the given formula\n max_sum = max(n, get_max_sum(n // 2, memo) + get_max_sum(n // 3, memo) + get_max_sum(n // 4, memo) + get_max_sum(n // 5, memo))\n \n # Store the result in the memo dictionary\n memo[n] = max_sum\n \n return max_sum", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n, memo={}):\n # Base case: if n is less than or equal to 0, return 0\n if n <= 0:\n return 0\n \n # Check if the result is already computed and stored in memo\n if n in memo:\n return memo[n]\n \n # Compute the maximum sum using the given equation\n max_sum = max(n, get_max_sum(n // 2, memo) + get_max_sum(n // 3, memo) + get_max_sum(n // 4, memo) + get_max_sum(n // 5, memo))\n \n # Store the result in memo to avoid redundant calculations\n memo[n] = max_sum\n \n return max_sum", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n, memo={}):\n # Check if the result is already computed\n if n in memo:\n return memo[n]\n \n # Base case: if n is 0 or 1, the sum is n itself\n if n <= 1:\n return n\n \n # Recursive case: compute the maximum sum using the given equation\n result = max(n, get_max_sum(n // 2, memo) + get_max_sum(n // 3, memo) + get_max_sum(n // 4, memo) + get_max_sum(n // 5, memo))\n \n # Store the result in the memo dictionary to avoid redundant calculations\n memo[n] = result\n return result", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n, memo={}):\n # Check if the result is already computed and stored in memo\n if n in memo:\n return memo[n]\n \n # Base case: if n is less than 6, return n\n if n < 6:\n return n\n \n # Recursive case: compute the sum of f(n/2), f(n/3), f(n/4), and f(n/5)\n result = max(n, get_max_sum(n // 2, memo) + get_max_sum(n // 3, memo) + get_max_sum(n // 4, memo) + get_max_sum(n // 5, memo))\n \n # Store the result in memo to avoid redundant calculations\n memo[n] = result\n \n return result", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n # Base case: if n is less than or equal to 1, return n\n if n <= 1:\n return n\n \n # Recursive case: calculate the maximum sum using the given equation\n return max(n, get_max_sum(n // 2) + get_max_sum(n // 3) + get_max_sum(n // 4) + get_max_sum(n // 5))", "matching_cluster_idx": 3}, {"solution": "def get_max_sum(n, memo={}):\n # Check if the result is already computed\n if n in memo:\n return memo[n]\n \n # Base case: if n is less than 2, return n\n if n < 2:\n return n\n \n # Calculate the maximum sum using the given equation\n max_sum = max(n, get_max_sum(n // 2, memo) + get_max_sum(n // 3, memo) + get_max_sum(n // 4, memo) + get_max_sum(n // 5, memo))\n \n # Store the result in the memo dictionary\n memo[n] = max_sum\n \n return max_sum", "matching_cluster_idx": 12}, {"solution": "memo = {}\ndef get_max_sum(n):\n # Check if the result is already computed\n if n in memo:\n return memo[n]\n \n # Base case: if n is less than 2, return n\n if n < 2:\n return n\n \n # Calculate the maximum sum using the given equation\n # f(n) = max(f(n/2) + f(n/3) + f(n/4) + f(n/5), n)\n max_sum = max(get_max_sum(n // 2) + get_max_sum(n // 3) + get_max_sum(n // 4) + get_max_sum(n // 5), n)\n \n # Store the result in the memo dictionary\n memo[n] = max_sum\n \n return max_sum", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n, memo={}):\n # Base case: if n is 0 or 1, return n\n if n == 0 or n == 1:\n return n\n \n # Check if the result is already computed and stored in memo\n if n in memo:\n return memo[n]\n \n # Compute the maximum sum using the given equation\n max_sum = max(n, get_max_sum(n // 2, memo) + get_max_sum(n // 3, memo) + get_max_sum(n // 4, memo) + get_max_sum(n // 5, memo))\n \n # Store the result in memo to avoid recomputation\n memo[n] = max_sum\n \n return max_sum", "matching_cluster_idx": 12}]}, "Mbpp/395": {"dps": 98.08429118773947, "dps_norm": 75.0, "pass@1": 100.0, "profiled": [{"solution": "def first_non_repeating_character(s):\n # Dictionary to store the count of each character\n char_count = {}\n \n # First pass to count the occurrences of each character\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n \n # Second pass to find the first non-repeated character\n for char in s:\n if char_count[char] == 1:\n return char\n \n # If no non-repeated character is found, return None\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n # Dictionary to store the count of each character\n char_count = {}\n \n # Count each character in the string\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n \n # Find the first non-repeating character\n for char in s:\n if char_count[char] == 1:\n return char\n \n # If no non-repeating character is found, return None\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n # Dictionary to store the count of each character\n char_count = {}\n \n # Count the occurrences of each character\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n \n # Find the first non-repeated character\n for char in s:\n if char_count[char] == 1:\n return char\n \n # If no non-repeated character is found, return None\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n # Dictionary to store the count of each character\n char_count = {}\n \n # Iterate over the string to populate the dictionary\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n \n # Iterate over the string again to find the first non-repeating character\n for char in s:\n if char_count[char] == 1:\n return char\n \n # If no non-repeating character is found, return None\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n # Dictionary to store the count of each character\n char_count = {}\n \n # First pass: count the occurrences of each character\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n \n # Second pass: find the first character that appears only once\n for char in s:\n if char_count[char] == 1:\n return char\n \n # If no non-repeating character is found, return None\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n # Create a dictionary to keep track of character counts\n char_count = {}\n \n # Iterate over the string to populate the dictionary\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n \n # Iterate over the string again to find the first non-repeated character\n for char in s:\n if char_count[char] == 1:\n return char\n \n # If no non-repeated character is found, return None\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n # Create a dictionary to store the count of each character\n char_count = {}\n \n # Count the occurrences of each character in the string\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n \n # Find the first character with a count of 1\n for char in s:\n if char_count[char] == 1:\n return char\n \n # If no non-repeating character is found, return None\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n # Create a dictionary to store the frequency of each character\n char_count = {}\n \n # Iterate over the string to populate the dictionary\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n \n # Iterate over the string again to find the first non-repeating character\n for char in s:\n if char_count[char] == 1:\n return char\n \n # If no non-repeating character is found, return None\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n # Create a dictionary to store the count of each character\n char_count = {}\n \n # Count the occurrences of each character in the string\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n \n # Find the first character that has a count of 1\n for char in s:\n if char_count[char] == 1:\n return char\n \n # If no non-repeating character is found, return None\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n # Dictionary to store the count of each character\n char_count = {}\n \n # First pass to count the characters\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n \n # Second pass to find the first non-repeated character\n for char in s:\n if char_count[char] == 1:\n return char\n \n # If no non-repeated character is found, return None\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n # Create a dictionary to store the count of each character\n char_count = {}\n \n # Count the occurrences of each character in the string\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n \n # Find the first non-repeating character\n for char in s:\n if char_count[char] == 1:\n return char\n \n # If no non-repeating character is found, return None\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n # Dictionary to keep track of character counts\n char_count = {}\n \n # First pass: count the occurrences of each character\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n \n # Second pass: find the first character that has a count of 1\n for char in s:\n if char_count[char] == 1:\n return char\n \n # If no non-repeating character is found, return None\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n # Dictionary to store the count of each character\n char_count = {}\n \n # Count the occurrences of each character\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n \n # Find the first non-repeated character\n for char in s:\n if char_count[char] == 1:\n return char\n \n # If no non-repeated character is found, return None\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n # Dictionary to keep track of character counts\n char_count = {}\n \n # Count each character in the string\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n \n # Find the first non-repeating character\n for char in s:\n if char_count[char] == 1:\n return char\n \n # If no non-repeating character is found, return None\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n # Create a dictionary to store the count of each character\n char_count = {}\n \n # Count the occurrences of each character in the string\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n \n # Find the first character with a count of 1\n for char in s:\n if char_count[char] == 1:\n return char\n \n # If no non-repeating character is found, return None\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n # Dictionary to store the count of each character\n char_count = {}\n \n # First pass to count the characters\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n \n # Second pass to find the first non-repeating character\n for char in s:\n if char_count[char] == 1:\n return char\n \n # If no non-repeating character is found, return None\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n # Dictionary to keep track of character counts\n char_count = {}\n \n # Count each character in the string\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n \n # Find the first character that appears only once\n for char in s:\n if char_count[char] == 1:\n return char\n \n # If no non-repeating character is found, return None\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n # Create a dictionary to store the count of each character\n char_count = {}\n \n # Count the occurrences of each character in the string\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n \n # Find the first non-repeated character\n for char in s:\n if char_count[char] == 1:\n return char\n \n # If no non-repeating character is found, return None\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n # Create a dictionary to store the count of each character\n char_count = {}\n \n # Count the occurrences of each character in the string\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n \n # Find the first non-repeated character\n for char in s:\n if char_count[char] == 1:\n return char\n \n # If no non-repeated character is found, return None\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n # Create a dictionary to store the count of each character\n char_count = {}\n \n # Count the occurrences of each character in the string\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n \n # Find the first character with a count of 1\n for char in s:\n if char_count[char] == 1:\n return char\n \n # If no non-repeating character is found, return None\n return None", "matching_cluster_idx": 5}]}, "Mbpp/405": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def check_tuplex(tuplex, element):\n # Check if the element is in the tuple\n return element in tuplex", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, element):\n # Check if the element is in the tuple\n return element in tuplex", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, element):\n # Check if the element is in the tuple\n return element in tuplex", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, element):\n # Check if the element is in the tuple\n return element in tuplex", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, element):\n # Check if the element is in the tuple\n return element in tuplex", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, element):\n # Check if the element is in the tuple\n return element in tuplex", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, element):\n # The 'in' keyword checks if the element is present in the tuple\n return element in tuplex", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, element):\n # Check if the element is in the tuple\n return element in tuplex", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tup, element):\n # Check if the element is in the tuple\n return element in tup", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, element):\n # Check if the element is in the tuple\n return element in tuplex", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, element):\n # Check if the element is in the tuple\n return element in tuplex", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tup, element):\n # Check if the element is in the tuple\n return element in tup", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, element):\n # Check if the element is in the tuple\n return element in tuplex", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, element):\n # Check if the element is in the tuple\n return element in tuplex", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, element):\n # Check if the element is in the tuple\n return element in tuplex", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, element):\n # Check if the element is in the tuple\n return element in tuplex", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tup, element):\n # Check if the element is in the tuple\n return element in tup", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, element):\n # Check if the element is in the tuple\n return element in tuplex", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tup, element):\n # Check if the element is in the tuple\n return element in tup", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, element):\n # Check if the element is in the tuple\n return element in tuplex", "matching_cluster_idx": 3}]}, "Mbpp/414": {"dps": 38.47826086956522, "dps_norm": 68.33333333333334, "pass@1": 100.0, "profiled": [{"solution": "def overlapping(seq1, seq2):\n # Convert both sequences to sets and check for intersection\n return bool(set(seq1) & set(seq2))", "matching_cluster_idx": 5}, {"solution": "def overlapping(seq1, seq2):\n # Convert the sequences to sets and check for intersection\n return bool(set(seq1) & set(seq2))", "matching_cluster_idx": 5}, {"solution": "def overlapping(seq1, seq2):\n # Convert the first sequence to a set for efficient look-up\n set1 = set(seq1)\n \n # Check if any element in the second sequence is in the set\n for element in seq2:\n if element in set1:\n return True\n return False", "matching_cluster_idx": 6}, {"solution": "def overlapping(sequence1, sequence2):\n # Convert the first sequence to a set for efficient lookup\n set1 = set(sequence1)\n \n # Check if any element in the second sequence is in the set\n for element in sequence2:\n if element in set1:\n return True\n return False", "matching_cluster_idx": 6}, {"solution": "def overlapping(seq1, seq2):\n # Convert the first sequence to a set for efficient lookups\n set_seq1 = set(seq1)\n \n # Check if any element in the second sequence exists in the set\n for element in seq2:\n if element in set_seq1:\n return True\n return False", "matching_cluster_idx": 6}, {"solution": "def overlapping(seq1, seq2):\n # Convert both sequences to sets to utilize set intersection for checking overlaps\n set1 = set(seq1)\n set2 = set(seq2)\n \n # Check if there is any intersection between the two sets\n return bool(set1 & set2)", "matching_cluster_idx": 5}, {"solution": "def overlapping(seq1, seq2):\n # Use set intersection to check if there is any common element\n return bool(set(seq1) & set(seq2))", "matching_cluster_idx": 5}, {"solution": "def overlapping(seq1, seq2):\n # Use set intersection to find common elements\n return bool(set(seq1) & set(seq2))", "matching_cluster_idx": 5}, {"solution": "def overlapping(sequence1, sequence2):\n # Convert both sequences to sets to use set intersection for checking overlap\n set1 = set(sequence1)\n set2 = set(sequence2)\n \n # Check if there is any intersection between the two sets\n return bool(set1.intersection(set2))", "matching_cluster_idx": 5}, {"solution": "def overlapping(sequence1, sequence2):\n # Convert the sequences to sets and check for intersection\n return bool(set(sequence1) & set(sequence2))", "matching_cluster_idx": 5}, {"solution": "def overlapping(sequence1, sequence2):\n # Convert the sequences to sets and check for intersection\n return bool(set(sequence1) & set(sequence2))", "matching_cluster_idx": 5}, {"solution": "def overlapping(sequence1, sequence2):\n # Convert the sequences to sets and check for intersection\n return bool(set(sequence1) & set(sequence2))", "matching_cluster_idx": 5}, {"solution": "def overlapping(seq1, seq2):\n # Convert both sequences to sets and check for intersection\n return bool(set(seq1) & set(seq2))", "matching_cluster_idx": 5}, {"solution": "def overlapping(sequence1, sequence2):\n # Convert the sequences to sets and check for intersection\n return bool(set(sequence1) & set(sequence2))", "matching_cluster_idx": 5}, {"solution": "def overlapping(sequence1, sequence2):\n # Convert the sequences to sets for efficient lookup\n set1 = set(sequence1)\n set2 = set(sequence2)\n \n # Check if there is any common element between the two sets\n return bool(set1 & set2)", "matching_cluster_idx": 5}, {"solution": "def overlapping(seq1, seq2):\n # Convert the sequences to sets and check for intersection\n return bool(set(seq1) & set(seq2))", "matching_cluster_idx": 5}, {"solution": "def overlapping(sequence1, sequence2):\n # Convert both sequences to sets for efficient lookup\n set1 = set(sequence1)\n set2 = set(sequence2)\n \n # Check if there is any intersection between the two sets\n return bool(set1 & set2)", "matching_cluster_idx": 5}, {"solution": "def overlapping(seq1, seq2):\n # Convert the sequences to sets and check for intersection\n return bool(set(seq1) & set(seq2))", "matching_cluster_idx": 5}, {"solution": "def overlapping(seq1, seq2):\n # Convert both sequences to sets and check for intersection\n return bool(set(seq1) & set(seq2))", "matching_cluster_idx": 5}, {"solution": "def overlapping(seq1, seq2):\n # Use set intersection to find common elements\n common_elements = set(seq1) & set(seq2)\n # Return True if there are any common elements, otherwise False\n return bool(common_elements)", "matching_cluster_idx": 5}]}, "Mbpp/421": {"dps": 88.8477366255144, "dps_norm": 94.28571428571428, "pass@1": 100.0, "profiled": [{"solution": "def concatenate_tuple(tup):\n # Join each element of the tuple into a string, separated by the delimiter '-'\n return '-'.join(str(x) for x in tup)", "matching_cluster_idx": 4}, {"solution": "def concatenate_tuple(input_tuple):\n # Join each element of the tuple into a single string separated by '-'\n return '-'.join(map(str, input_tuple))", "matching_cluster_idx": 6}, {"solution": "def concatenate_tuple(tup):\n # Join each element of the tuple into a single string, separated by hyphens\n return '-'.join(map(str, tup))", "matching_cluster_idx": 6}, {"solution": "def concatenate_tuple(input_tuple):\n # Join the elements of the tuple into a single string separated by hyphens\n return '-'.join(map(str, input_tuple))", "matching_cluster_idx": 6}, {"solution": "def concatenate_tuple(t):\n # Convert all elements in the tuple to strings and join them using the '-' delimiter\n return '-'.join(map(str, t))", "matching_cluster_idx": 6}, {"solution": "def concatenate_tuple(input_tuple):\n # Join the elements of the tuple into a single string, separated by the delimiter '-'\n return '-'.join(map(str, input_tuple))", "matching_cluster_idx": 6}, {"solution": "def concatenate_tuple(t):\n # Join each element of the tuple into a string, using '-' as the delimiter\n return '-'.join(map(str, t))", "matching_cluster_idx": 6}, {"solution": "def concatenate_tuple(t):\n # Join each element of the tuple into a single string with '-' as the delimiter\n return '-'.join(map(str, t))", "matching_cluster_idx": 6}, {"solution": "def concatenate_tuple(tup):\n # Join each element of the tuple into a single string with '-' as the delimiter\n return '-'.join(map(str, tup))", "matching_cluster_idx": 6}, {"solution": "def concatenate_tuple(tup):\n # Join each element of the tuple into a single string, separated by '-'\n return '-'.join(map(str, tup))", "matching_cluster_idx": 6}, {"solution": "def concatenate_tuple(input_tuple):\n # Join the elements of the tuple into a single string separated by the specified delimiter\n return '-'.join(map(str, input_tuple))", "matching_cluster_idx": 5}, {"solution": "def concatenate_tuple(t):\n # Join each element of the tuple with a hyphen\n return '-'.join(map(str, t))", "matching_cluster_idx": 5}, {"solution": "def concatenate_tuple(tup):\n # Join each element of the tuple into a string with '-' as the delimiter\n return '-'.join(map(str, tup))", "matching_cluster_idx": 5}, {"solution": "def concatenate_tuple(tup):\n # Join each element of the tuple with a hyphen (-) as the delimiter\n return '-'.join(map(str, tup))", "matching_cluster_idx": 5}, {"solution": "def concatenate_tuple(t):\n # Join each element of the tuple into a string, separated by hyphens\n return '-'.join(map(str, t))", "matching_cluster_idx": 5}, {"solution": "def concatenate_tuple(tup):\n # Join each element of the tuple into a string, separated by '-'\n return '-'.join(map(str, tup))", "matching_cluster_idx": 6}, {"solution": "def concatenate_tuple(tup):\n # Join each element of the tuple into a single string, separated by the delimiter '-'\n return '-'.join(map(str, tup))", "matching_cluster_idx": 6}, {"solution": "def concatenate_tuple(tup):\n # Convert all elements to strings and join them with the specified delimiter\n return '-'.join(map(str, tup))", "matching_cluster_idx": 6}, {"solution": "def concatenate_tuple(tup):\n # Join each element of the tuple into a string, separated by '-'\n return '-'.join(map(str, tup))", "matching_cluster_idx": 6}, {"solution": "def concatenate_tuple(input_tuple):\n # Join the elements of the tuple into a single string with '-' as the delimiter\n result = '-'.join(map(str, input_tuple))\n return result", "matching_cluster_idx": 5}]}, "Mbpp/424": {"dps": 51.624548736462096, "dps_norm": 80.0, "pass@1": 100.0, "profiled": [{"solution": "def extract_rear(input_tuple):\n # Use a list comprehension to extract the last character of each string in the tuple\n rear_elements = [s[-1] for s in input_tuple]\n return rear_elements", "matching_cluster_idx": 3}, {"solution": "def extract_rear(input_tuple):\n # Extract the last character of each string in the tuple\n result = [s[-1] for s in input_tuple]\n return result", "matching_cluster_idx": 3}, {"solution": "def extract_rear(input_tuple):\n # Use a list comprehension to extract the last character of each string in the tuple\n result = [s[-1] for s in input_tuple]\n return result", "matching_cluster_idx": 3}, {"solution": "def extract_rear(t):\n # Extract the last character of each string in the tuple\n result = [s[-1] for s in t]\n return result", "matching_cluster_idx": 3}, {"solution": "def extract_rear(t):\n # Create an empty list to store the last characters\n rear_elements = []\n \n # Iterate over each string in the tuple\n for string in t:\n # Append the last character of the string to the list\n rear_elements.append(string[-1])\n \n return rear_elements", "matching_cluster_idx": 3}, {"solution": "def extract_rear(input_tuple):\n # Extract the last character of each string in the tuple\n result = [s[-1] for s in input_tuple]\n return result", "matching_cluster_idx": 3}, {"solution": "def extract_rear(input_tuple):\n # Extract the last character from each string in the tuple\n rear_elements = [s[-1] for s in input_tuple]\n return rear_elements", "matching_cluster_idx": 3}, {"solution": "def extract_rear(input_tuple):\n # Extract the last character of each string in the tuple\n rear_elements = [s[-1] for s in input_tuple]\n return rear_elements", "matching_cluster_idx": 3}, {"solution": "def extract_rear(input_tuple):\n # Extract the last character of each string in the tuple\n result = [s[-1] for s in input_tuple]\n return result", "matching_cluster_idx": 3}, {"solution": "def extract_rear(input_tuple):\n # Use a list comprehension to extract the last character of each string in the tuple\n result = [s[-1] for s in input_tuple]\n return result", "matching_cluster_idx": 3}, {"solution": "def extract_rear(input_tuple):\n # Extract the last character of each string in the tuple\n rear_elements = [s[-1] for s in input_tuple]\n return rear_elements", "matching_cluster_idx": 3}, {"solution": "def extract_rear(input_tuple):\n # Extract the last character of each string in the tuple\n result = [s[-1] for s in input_tuple]\n return result", "matching_cluster_idx": 3}, {"solution": "def extract_rear(input_tuple):\n # Use a list comprehension to extract the last character of each string in the tuple\n result = [s[-1] for s in input_tuple]\n return result", "matching_cluster_idx": 3}, {"solution": "def extract_rear(input_tuple):\n # Extract the last character from each string in the tuple\n return [s[-1] for s in input_tuple]", "matching_cluster_idx": 3}, {"solution": "def extract_rear(input_tuple):\n # Use a list comprehension to extract the last character of each string in the tuple\n rear_elements = [s[-1] for s in input_tuple]\n return rear_elements", "matching_cluster_idx": 3}, {"solution": "def extract_rear(tup):\n # Extract the last character of each string in the tuple\n result = [s[-1] for s in tup]\n return result", "matching_cluster_idx": 3}, {"solution": "def extract_rear(test_tup):\n # Extract the last character from each string in the tuple\n res = [sub[-1] for sub in test_tup]\n return res", "matching_cluster_idx": 3}, {"solution": "def extract_rear(input_tuple):\n # Using a list comprehension to extract the last character of each string in the tuple\n rear_elements = [s[-1] for s in input_tuple]\n return rear_elements", "matching_cluster_idx": 3}, {"solution": "def extract_rear(input_tuple):\n # Extract the last character of each string in the tuple\n rear_elements = [s[-1] for s in input_tuple]\n return rear_elements", "matching_cluster_idx": 3}, {"solution": "def extract_rear(input_tuple):\n # Extract the last character of each string in the tuple\n return [s[-1] for s in input_tuple]", "matching_cluster_idx": 3}]}, "Mbpp/425": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def count_element_in_list(list1, element):\n # Initialize a counter to zero\n count = 0\n \n # Iterate through each sublist in the main list\n for sublist in list1:\n # If the element is in the sublist, increment the counter\n if element in sublist:\n count += 1\n \n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(list1, element):\n # Initialize the count to zero\n count = 0\n \n # Iterate through each sublist in the main list\n for sublist in list1:\n # Check if the element is in the current sublist\n if element in sublist:\n # Increment the count if the element is found\n count += 1\n \n # Return the total count of sublists containing the element\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(list1, element):\n # Initialize a counter to keep track of sublists containing the element\n count = 0\n # Iterate through each sublist in the main list\n for sublist in list1:\n # Check if the element is in the current sublist\n if element in sublist:\n # Increment the counter if the element is found\n count += 1\n # Return the final count\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(list1, element):\n # Initialize a count to keep track of sublists containing the element\n count = 0\n # Iterate through each sublist in the main list\n for sublist in list1:\n # If the element is found in the current sublist, increment the count\n if element in sublist:\n count += 1\n # Return the final count\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, element):\n # Initialize a counter to zero\n count = 0\n \n # Iterate through each sublist in the list\n for sublist in lst:\n # Check if the element is in the current sublist\n if element in sublist:\n # Increment the counter if the element is found\n count += 1\n \n # Return the final count\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(list1, element):\n # Initialize a counter to zero\n count = 0\n \n # Iterate over each sublist in the main list\n for sublist in list1:\n # Check if the element is in the current sublist\n if element in sublist:\n # Increment the counter if the element is found\n count += 1\n \n # Return the final count\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(list1, element):\n # Initialize a counter to zero\n count = 0\n # Iterate through each sublist in the main list\n for sublist in list1:\n # Check if the element is in the current sublist\n if element in sublist:\n # Increment the counter if the element is found\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(list1, element):\n # Initialize a counter to zero\n count = 0\n # Iterate over each sublist in the main list\n for sublist in list1:\n # If the element is in the current sublist, increment the counter\n if element in sublist:\n count += 1\n # Return the final count\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, element):\n # Initialize a counter to zero\n count = 0\n # Iterate through each sublist in the main list\n for sublist in lst:\n # Check if the element is in the current sublist\n if element in sublist:\n # Increment the counter if the element is found\n count += 1\n # Return the final count\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, element):\n # Initialize a count to keep track of how many sublists contain the element\n count = 0\n \n # Iterate through each sublist in the main list\n for sublist in lst:\n # Check if the element is in the current sublist\n if element in sublist:\n # Increment the count if the element is found\n count += 1\n \n # Return the total count of sublists containing the element\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(list1, k):\n # Initialize a counter to zero\n counter = 0\n \n # Iterate through each sublist in the main list\n for sublist in list1:\n # Check if the element k is in the current sublist\n if k in sublist:\n # Increment the counter if the element is found\n counter += 1\n \n # Return the final count\n return counter", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, element):\n # Initialize a count to keep track of the number of sublists containing the element\n count = 0\n # Iterate through each sublist in the main list\n for sublist in lst:\n # Check if the element is in the current sublist\n if element in sublist:\n # If the element is found, increment the count\n count += 1\n # Return the final count\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(list1, element):\n # Initialize a counter to zero\n count = 0\n # Iterate through each sublist in the main list\n for sublist in list1:\n # Check if the element is in the current sublist\n if element in sublist:\n # Increment the counter if the element is found\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, element):\n # Initialize a count variable to zero\n count = 0\n # Iterate through each sublist in the main list\n for sublist in lst:\n # Check if the element is in the current sublist\n if element in sublist:\n # Increment the count if the element is found\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, element):\n # Initialize a counter to keep track of sublists containing the element\n count = 0\n \n # Iterate over each sublist in the list\n for sublist in lst:\n # Check if the element is in the current sublist\n if element in sublist:\n # Increment the counter if the element is found\n count += 1\n \n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, element):\n # Initialize a counter to zero\n count = 0\n # Iterate through each sublist in the main list\n for sublist in lst:\n # Check if the element is in the current sublist\n if element in sublist:\n # Increment the counter if the element is found\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(list1, element):\n # Initialize a counter for the sublists containing the element\n count = 0\n \n # Iterate through each sublist in the main list\n for sublist in list1:\n # If the element is found in the current sublist, increment the counter\n if element in sublist:\n count += 1\n \n # Return the final count\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(list1, element):\n # Initialize the count of sublists containing the element\n count = 0\n \n # Iterate through each sublist in the main list\n for sublist in list1:\n # Check if the element is in the current sublist\n if element in sublist:\n # Increment the count if the element is found\n count += 1\n \n # Return the total count of sublists containing the element\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(list1, element):\n # Initialize a count to keep track of sublists containing the element\n count = 0\n # Iterate through each sublist in the main list\n for sublist in list1:\n # Check if the element is in the current sublist\n if element in sublist:\n # Increment the count if the element is found\n count += 1\n # Return the total count of sublists containing the element\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, element):\n # Initialize a counter to keep track of sublists containing the element\n count = 0\n # Iterate through each sublist in the main list\n for sublist in lst:\n # Check if the element is in the current sublist\n if element in sublist:\n # Increment the counter if the element is found\n count += 1\n # Return the final count\n return count", "matching_cluster_idx": 4}]}, "Mbpp/428": {"dps": 84.29752066115702, "dps_norm": 55.55555555555556, "pass@1": 99.0, "profiled": [{"solution": "def shell_sort(arr):\n # Determine the initial gap size, which is about half the length of the array\n n = len(arr)\n gap = n // 2\n \n # Start with a big gap, then reduce the gap\n while gap > 0:\n # Perform a gapped insertion sort for this gap size\n for i in range(gap, n):\n temp = arr[i]\n j = i\n # Shift earlier gap-sorted elements up until the correct location for arr[i] is found\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n # Put temp (the original arr[i]) in its correct location\n arr[j] = temp\n # Reduce the gap for the next iteration\n gap //= 2\n \n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n # Determine the initial gap size\n n = len(arr)\n gap = n // 2\n\n # Start with a big gap, then reduce the gap\n while gap > 0:\n # Perform a gapped insertion sort for this gap size\n for i in range(gap, n):\n # Save arr[i] in temp and make a hole at position i\n temp = arr[i]\n j = i\n # Shift earlier gap-sorted elements up until the correct location for arr[i] is found\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n # Put temp (the original arr[i]) in its correct location\n arr[j] = temp\n # Reduce the gap for the next element\n gap //= 2\n\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n # Determine the gap sequence starting with n/2 and reducing by half each time\n n = len(arr)\n gap = n // 2\n \n # Perform the shell sort\n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n # Insert arr[i] into the sorted subarray arr[0:i-gap]\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n # Reduce the gap for the next iteration\n gap //= 2\n \n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n # Determine the initial gap using the length of the array\n n = len(arr)\n gap = n // 2\n \n # Start with a big gap, then reduce the gap\n while gap > 0:\n # Perform a gapped insertion sort for this gap size\n for i in range(gap, n):\n temp = arr[i]\n j = i\n # Shift earlier gap-sorted elements up until the correct location for arr[i] is found\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n # Put temp (the original arr[i]) in its correct location\n arr[j] = temp\n # Reduce the gap for the next element\n gap //= 2\n \n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n # Determine the initial gap size\n n = len(arr)\n gap = n // 2\n \n # Start with a big gap, then reduce the gap\n while gap > 0:\n # Do a gapped insertion sort for this gap size\n for i in range(gap, n):\n # Add arr[i] to the elements that have been gap sorted\n temp = arr[i]\n j = i\n # Shift earlier gap-sorted elements up until the correct location for arr[i] is found\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n # Put temp (the original arr[i]) in its correct location\n arr[j] = temp\n # Reduce the gap for the next element\n gap //= 2\n \n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2 # Initialize the gap size\n\n # Start with a big gap, then reduce the gap\n while gap > 0:\n # Do a gapped insertion sort for this gap size.\n for i in range(gap, n):\n temp = arr[i]\n j = i\n # Shift earlier gap-sorted elements up until the correct location for arr[i] is found\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n # Put temp (the original arr[i]) in its correct location\n arr[j] = temp\n gap //= 2 # Reduce the gap for the next element\n\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n # Determine the initial gap size, which is half the length of the array\n n = len(arr)\n gap = n // 2\n\n # Continue sorting with the current gap size until the gap is 0\n while gap > 0:\n # Perform a gapped insertion sort for this gap size\n for i in range(gap, n):\n temp = arr[i]\n j = i\n # Shift earlier gap-sorted elements up until the correct location for arr[i] is found\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n # Put temp (the original arr[i]) in its correct location\n arr[j] = temp\n # Reduce the gap for the next iteration\n gap //= 2\n\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2 # Initialize the gap size\n\n # Start with a big gap, then reduce the gap\n while gap > 0:\n # Do a gapped insertion sort for this gap size\n for i in range(gap, n):\n temp = arr[i]\n j = i\n # Shift earlier gap-sorted elements up until the correct location for arr[i] is found\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n # Put temp (the original arr[i]) in its correct location\n arr[j] = temp\n gap //= 2 # Reduce the gap for the next element\n\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2 # Initialize the gap size\n\n # Start with a big gap, then reduce the gap\n while gap > 0:\n # Perform a gapped insertion sort for this gap size.\n for i in range(gap, n):\n temp = arr[i]\n j = i\n # Shift earlier gap-sorted elements up until the correct location for arr[i] is found\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n # Put temp (the original arr[i]) in its correct location\n arr[j] = temp\n gap //= 2 # Reduce the gap for the next element\n\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n # Determine the initial gap size, which is half the length of the array\n n = len(arr)\n gap = n // 2\n \n # Continue until the gap is reduced to 0\n while gap > 0:\n # Perform a gapped insertion sort for this gap size\n for i in range(gap, n):\n temp = arr[i]\n j = i\n # Shift earlier gap-sorted elements up until the correct location for arr[i] is found\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n # Put temp (the original arr[i]) in its correct location\n arr[j] = temp\n # Reduce the gap for the next iteration\n gap //= 2\n \n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2 # Initial gap size\n\n # Gap reduction loop\n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n # Shift elements of the array\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2 # Reduce the gap\n\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n # Determine the initial gap size\n n = len(arr)\n gap = n // 2\n \n # Start with a big gap, then reduce the gap\n while gap > 0:\n # Perform a gapped insertion sort for this gap size\n for i in range(gap, n):\n # Save arr[i] in temp and make a hole at position i\n temp = arr[i]\n j = i\n # Shift earlier gap-sorted elements up until the correct location for arr[i] is found\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n # Put temp (the original arr[i]) in its correct location\n arr[j] = temp\n # Reduce the gap for the next element\n gap //= 2\n \n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n # Determine the initial gap size\n n = len(arr)\n gap = n // 2\n\n # Start with a big gap, then reduce the gap\n while gap > 0:\n # Perform a gapped insertion sort for this gap size\n for i in range(gap, n):\n # Save arr[i] in temp and make a hole at position i\n temp = arr[i]\n j = i\n # Shift earlier gap-sorted elements up until the correct location for arr[i] is found\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n # Put temp (the original arr[i]) in its correct location\n arr[j] = temp\n # Reduce the gap for the next element\n gap //= 2\n\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2 # Initialize the gap size\n\n # Start with a big gap, then reduce the gap\n while gap > 0:\n # Do a gapped insertion sort for this gap size.\n for i in range(gap, n):\n temp = arr[i]\n j = i\n # Shift earlier gap-sorted elements up until the correct location for arr[i] is found\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n # Put temp (the original arr[i]) in its correct location\n arr[j] = temp\n gap //= 2 # Reduce the gap for the next element\n\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n # Determine the initial gap size, which is the length of the array divided by 2\n n = len(arr)\n gap = n // 2\n \n # Continue with the gap sorting until the gap becomes 0\n while gap > 0:\n # Perform a gapped insertion sort for this gap size\n for i in range(gap, n):\n temp = arr[i]\n j = i\n # Shift earlier gap-sorted elements up until the correct location for arr[i] is found\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n # Put temp (the original arr[i]) in its correct location\n arr[j] = temp\n # Reduce the gap for the next element\n gap //= 2\n \n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2 # Initial gap size\n\n # Start with a big gap, then reduce the gap\n while gap > 0:\n # Do a gapped insertion sort for this gap size.\n for i in range(gap, n):\n # add arr[i] to the elements that have been gap sorted\n temp = arr[i]\n j = i\n # shift earlier gap-sorted elements up until the correct location for arr[i] is found\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n # put temp (the original arr[i]) in its correct location\n arr[j] = temp\n gap //= 2 # Reduce the gap for the next element\n\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n # Determine the gap sequence starting from the length of the array divided by 2\n n = len(arr)\n gap = n // 2\n \n # Start with a big gap, then reduce the gap\n while gap > 0:\n # Perform a gapped insertion sort for this gap size\n for i in range(gap, n):\n temp = arr[i]\n j = i\n # Shift earlier gap-sorted elements up until the correct location for arr[i] is found\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n # Put temp (the original arr[i]) in its correct location\n arr[j] = temp\n # Reduce the gap for the next iteration\n gap //= 2\n \n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2 # Initialize the gap size\n\n # Start with a big gap, then reduce the gap\n while gap > 0:\n # Perform insertion sort with the current gap\n for i in range(gap, n):\n temp = arr[i]\n j = i\n # Shift earlier gap-sorted elements up until the correct location for arr[i] is found\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n # Reduce the gap for the next element\n gap //= 2\n\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2 # Initialize the gap size to half the length of the array\n \n # Continue until the gap is reduced to 0\n while gap > 0:\n # Perform a gapped insertion sort for this gap size\n for i in range(gap, n):\n temp = arr[i]\n j = i\n # Shift earlier gap-sorted elements up until the correct location for arr[i] is found\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n # Put temp (the original arr[i]) in its correct location\n arr[j] = temp\n # Reduce the gap for the next iteration\n gap //= 2\n \n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n # Determine the initial gap size, which is half the length of the array\n n = len(arr)\n gap = n // 2\n\n # Start with a big gap, then reduce the gap\n while gap > 0:\n # Perform a gapped insertion sort for this gap size\n for i in range(gap, n):\n # Save arr[i] in temp and make a hole at position i\n temp = arr[i]\n # Shift earlier gap-sorted elements up until the correct location for arr[i] is found\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n # Put temp (the original arr[i]) in its correct location\n arr[j] = temp\n # Reduce the gap for the next element\n gap //= 2\n\n return arr", "matching_cluster_idx": 4}]}, "Mbpp/433": {"dps": 96.38297872340425, "dps_norm": 96.0, "pass@1": 100.0, "profiled": [{"solution": "def check_greater(arr, num):\n # Check if the given number is greater than all elements in the array\n for element in arr:\n if num <= element:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def check_greater(arr, num):\n # Check if the given number is greater than all elements in the array\n return all(x < num for x in arr)", "matching_cluster_idx": 2}, {"solution": "def check_greater(arr, num):\n # Check if the given number is greater than all elements in the array\n for element in arr:\n if num <= element:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def check_greater(arr, num):\n # Check if the given number is greater than all elements in the array\n return all(num > x for x in arr)", "matching_cluster_idx": 2}, {"solution": "def check_greater(arr, num):\n # Check if the given number is greater than all elements in the array\n for element in arr:\n if num <= element:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def check_greater(arr, num):\n # Check if the given number is greater than all elements in the array\n for element in arr:\n if num <= element:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def check_greater(arr, num):\n # Check if the given number is greater than all elements in the array\n for element in arr:\n if num <= element:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def check_greater(arr, num):\n # Check if the number is greater than all elements in the array\n for element in arr:\n if num <= element:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def check_greater(arr, num):\n # Check if the given number is greater than all elements in the array\n for element in arr:\n if num <= element:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def check_greater(arr, num):\n # Check if the given number is greater than all elements in the array\n for element in arr:\n if num <= element:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def check_greater(arr, num):\n # Check if the given number is greater than all elements in the array\n for element in arr:\n if num <= element:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def check_greater(arr, num):\n # Check if the given number is greater than all elements in the array\n for element in arr:\n if num <= element:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def check_greater(arr, num):\n # Check if the given number is greater than all elements in the array\n for element in arr:\n if num <= element:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def check_greater(arr, num):\n # Check if the given number is greater than all elements in the array\n for element in arr:\n if num <= element:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def check_greater(arr, num):\n # Check if the given number is greater than all elements in the array\n for element in arr:\n if num <= element:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def check_greater(arr, num):\n # Check if the number is greater than all elements in the array\n for element in arr:\n if num <= element:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def check_greater(arr, num):\n # Check if the given number is greater than all elements in the array\n for element in arr:\n if num <= element:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def check_greater(arr, num):\n # Check if the number is greater than all elements in the array\n for element in arr:\n if num <= element:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def check_greater(arr, num):\n # Check if the given number is greater than all elements in the array\n for element in arr:\n if num <= element:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def check_greater(arr, num):\n # Check if the given number is greater than all elements in the array\n for element in arr:\n if num <= element:\n return False\n return True", "matching_cluster_idx": 4}]}, "Mbpp/437": {"dps": 70.58823529411765, "dps_norm": 20.0, "pass@1": 64.0, "profiled": [{"solution": "def remove_odd(s):\n # Initialize an empty string to store the result\n result = ''\n \n # Iterate over the string using index\n for i in range(1, len(s) + 1):\n # Check if the index is even\n if i % 2 == 0:\n # Append the character at the current index (adjusted for 0-based indexing) to the result\n result += s[i - 1]\n \n return result", "matching_cluster_idx": 0}, {"solution": "def remove_odd(s):\n # Initialize an empty string to store the result\n result = \"\"\n \n # Iterate through the string using index\n for i in range(len(s)):\n # Check if the index is even (since index starts from 0, even index corresponds to odd position)\n if i % 2 == 1:\n # Append the character at the even index to the result\n result += s[i]\n \n return result", "matching_cluster_idx": 0}, {"solution": "def remove_odd(input_string):\n # Initialize an empty string to store the result\n result = \"\"\n \n # Iterate through the string using index\n for i in range(len(input_string)):\n # Check if the index is odd (considering index starts from 0)\n if i % 2 == 1:\n # Append the character at the odd index to the result\n result += input_string[i]\n \n return result", "matching_cluster_idx": 0}, {"solution": "def remove_odd(s):\n # Initialize an empty string to store the result\n result = ''\n \n # Iterate through the string using enumerate to get the index and character\n for i, char in enumerate(s):\n # Check if the index is odd (considering index starts from 0)\n if i % 2 == 1:\n # Append the character to the result if the index is odd\n result += char\n \n return result", "matching_cluster_idx": 0}, {"solution": "def remove_odd(s):\n # Initialize an empty string to store the result\n result = ''\n \n # Iterate over the string using their indices\n for i in range(len(s)):\n # Check if the index is even (0-based), which corresponds to odd positions in human terms\n if i % 2 == 1:\n # Append the character at the current index to the result\n result += s[i]\n \n return result", "matching_cluster_idx": 0}, {"solution": "def remove_odd(s):\n # Initialize an empty string to store the result\n result = ''\n \n # Iterate over the string using index\n for i in range(len(s)):\n # Check if the index is even (0-based), which corresponds to odd positions in human counting\n if i % 2 == 1:\n # Append the character at the current index to the result\n result += s[i]\n \n return result", "matching_cluster_idx": 0}, {"solution": "def remove_odd(s):\n # Initialize an empty string to store the result\n result = ''\n \n # Iterate over the string using index\n for i in range(len(s)):\n # Check if the index is even (considering 0-based indexing)\n if i % 2 == 1:\n # Append the character at the current index to the result\n result += s[i]\n \n return result", "matching_cluster_idx": 0}, {"solution": "def remove_odd(s):\n # Initialize an empty string to store even-indexed characters\n result = ''\n \n # Iterate over the string using index\n for i in range(len(s)):\n # Check if the index is even (0-based)\n if i % 2 == 1:\n # Append the character at the current index to the result string\n result += s[i]\n \n return result", "matching_cluster_idx": 0}, {"solution": "def remove_odd(s):\n # Initialize an empty string to store the result\n result = \"\"\n \n # Iterate over the string using index\n for i in range(len(s)):\n # Check if the index is even (considering 0-based indexing)\n if i % 2 == 1:\n # Append the character at the current index to the result\n result += s[i]\n \n return result", "matching_cluster_idx": 0}, {"solution": "def remove_odd(s):\n # Initialize an empty string to store the result\n result = \"\"\n \n # Iterate over the string using index\n for i in range(len(s)):\n # Check if the index is even (considering 0-based indexing)\n if i % 2 == 1:\n # Append the character at the current index to the result\n result += s[i]\n \n return result", "matching_cluster_idx": 0}, {"solution": "def remove_odd(s):\n # Initialize an empty string to store the result\n result = \"\"\n \n # Iterate over the string using index\n for i in range(len(s)):\n # Check if the index is even (considering 0-based indexing)\n if i % 2 == 1:\n # Append the character at the current index to the result\n result += s[i]\n \n return result", "matching_cluster_idx": 0}, {"solution": "def remove_odd(s):\n # Initialize an empty string to store the result\n result = \"\"\n \n # Iterate over the string using the index\n for i in range(len(s)):\n # Check if the index is even (0-based indexing)\n if i % 2 == 1:\n # Append the character at the current index to the result\n result += s[i]\n \n return result", "matching_cluster_idx": 0}, {"solution": "def remove_odd(s):\n # Initialize an empty string to store even-indexed characters\n result = ''\n \n # Iterate over the string using enumerate to get both index and character\n for i, char in enumerate(s):\n # Check if the index is odd (since index starts from 0, odd index means even position)\n if i % 2 == 1:\n result += char\n \n return result", "matching_cluster_idx": 0}, {"solution": "def remove_odd(s):\n # Initialize an empty string to store the result\n result = ''\n \n # Iterate over the string using index\n for i in range(1, len(s) + 1):\n # Check if the index is even\n if i % 2 == 0:\n # Append the character at the current index (adjusted for 0-based indexing) to the result\n result += s[i - 1]\n \n return result", "matching_cluster_idx": 0}, {"solution": "def remove_odd(s):\n # Initialize an empty string to store even-indexed characters\n result = ''\n \n # Iterate over the string using their indices\n for i in range(len(s)):\n # Check if the index is even (since indices start at 0, even indices correspond to odd positions in 1-based counting)\n if i % 2 == 1:\n # Append the character at the even index to the result string\n result += s[i]\n \n return result", "matching_cluster_idx": 0}, {"solution": "def remove_odd(s):\n # Initialize an empty string to store the result\n result = ''\n \n # Iterate over the string using index\n for i in range(len(s)):\n # Check if the index is even (0-based index)\n if i % 2 == 1:\n # Append the character at the current index to the result\n result += s[i]\n \n return result", "matching_cluster_idx": 0}, {"solution": "def remove_odd(s):\n # Initialize an empty string to store the result\n result = \"\"\n \n # Iterate through the string using index\n for i in range(len(s)):\n # Check if the index is even (0-based index), meaning the character is in an odd position\n if i % 2 == 1:\n # Append the character to the result\n result += s[i]\n \n return result", "matching_cluster_idx": 0}, {"solution": "def remove_odd(input_string):\n # Initialize an empty string to store even indexed characters\n result = ''\n # Iterate over the string using its indices\n for i in range(len(input_string)):\n # Check if the index is even (0-based index, so even index means odd position)\n if i % 2 != 0:\n # Append the character at the current index to the result string\n result += input_string[i]\n return result", "matching_cluster_idx": 0}, {"solution": "def remove_odd(s):\n # Initialize an empty string to store even-indexed characters\n result = ''\n \n # Iterate over the string using index and character\n for index, char in enumerate(s):\n # Check if the index is even (0-based indexing)\n if index % 2 == 1:\n # Append the character to the result string\n result += char\n \n return result", "matching_cluster_idx": 0}, {"solution": "def remove_odd(s):\n # Initialize an empty string to store even indexed characters\n result = ''\n \n # Iterate through the string using index\n for i in range(len(s)):\n # Check if the index is even (since indexing starts at 0, even index means odd character position)\n if i % 2 == 1:\n # Append the character at the current index to the result string\n result += s[i]\n \n return result", "matching_cluster_idx": 0}]}, "Mbpp/440": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 45.0, "profiled": [{"solution": "import re\ndef find_adverb_position(sentence):\n # Use regular expression to find all occurrences of words ending in 'ly'\n for match in re.finditer(r'\\w+ly', sentence):\n start = match.start() # Get the start position of the match\n end = match.end() # Get the end position of the match\n adverb = match.group() # Get the matched adverb\n return (start, end, adverb)\n return None # Return None if no adverb is found", "matching_cluster_idx": 3}, {"solution": "import re\ndef find_adverb_position(sentence):\n # Use regular expression to find all adverbs and their positions\n for match in re.finditer(r'\\w+ly', sentence):\n start = match.start()\n end = match.end()\n adverb = match.group()\n return (start, end, adverb)\n return None", "matching_cluster_idx": 3}, {"solution": "import re\ndef find_adverb_position(sentence):\n # Use regex to find the first adverb and its position\n match = re.search(r'\\w+ly', sentence)\n if match:\n return (match.start(), match.end(), match.group(0))\n else:\n return None", "matching_cluster_idx": 3}, {"solution": "import re\ndef find_adverb_position(sentence):\n # Use regular expression to find all adverbs and their start positions\n for match in re.finditer(r'\\w+ly', sentence):\n start = match.start()\n end = match.end()\n adverb = match.group()\n return (start, end, adverb)\n return None", "matching_cluster_idx": 3}, {"solution": "import re\ndef find_adverb_position(sentence):\n # Use regular expression to find the first adverb in the sentence\n match = re.search(r'\\w+ly', sentence)\n \n # If an adverb is found, return its start and end positions along with the adverb\n if match:\n start, end = match.span()\n adverb = match.group()\n return (start, end, adverb)\n else:\n # If no adverb is found, return None\n return None", "matching_cluster_idx": 3}, {"solution": "import re\ndef find_adverb_position(sentence):\n # Using regular expression to find the first adverb\n match = re.search(r'\\w+ly', sentence)\n if match:\n # If an adverb is found, return the start and end positions along with the adverb\n return (match.start(), match.end(), match.group(0))\n else:\n # If no adverb is found, return None\n return None", "matching_cluster_idx": 3}, {"solution": "import re\ndef find_adverb_position(sentence):\n # Use regular expression to find the first occurrence of an adverb\n match = re.search(r'\\w+ly', sentence)\n \n # If an adverb is found, return its start and end positions, and the adverb itself\n if match:\n start = match.start()\n end = match.end()\n adverb = match.group()\n return (start, end, adverb)\n else:\n return None", "matching_cluster_idx": 3}, {"solution": "import re\ndef find_adverb_position(sentence):\n # Use regular expression to find all adverbs ending in 'ly' and their starting positions\n for match in re.finditer(r'\\w+ly', sentence):\n start_pos = match.start()\n end_pos = match.end()\n adverb = match.group()\n return (start_pos, end_pos, adverb)\n # Return None if no adverb is found\n return None", "matching_cluster_idx": 3}, {"solution": "import re\ndef find_adverb_position(sentence):\n # Use regular expression to find the first adverb in the sentence\n match = re.search(r'\\w+ly', sentence)\n \n # If an adverb is found, return its start and end positions and the adverb itself\n if match:\n start = match.start()\n end = match.end()\n adverb = match.group()\n return (start, end, adverb)\n else:\n # If no adverb is found, return None\n return None", "matching_cluster_idx": 3}, {"solution": "import re\ndef find_adverb_position(sentence):\n # Use regular expression to find all adverbs and their starting positions\n for match in re.finditer(r'\\w+ly', sentence):\n start_pos = match.start()\n end_pos = match.end()\n adverb = match.group(0)\n return (start_pos, end_pos, adverb)\n return None", "matching_cluster_idx": 3}, {"solution": "import re\ndef find_adverb_position(sentence):\n # Use regular expression to find the first adverb in the sentence\n match = re.search(r'\\w+ly', sentence)\n \n if match:\n # If an adverb is found, return its start and end positions and the adverb itself\n return (match.start(), match.end(), match.group(0))\n else:\n # If no adverb is found, return None\n return None", "matching_cluster_idx": 3}, {"solution": "import re\ndef find_adverb_position(sentence):\n # Use regular expression to find adverbs\n match = re.search(r'\\w+ly', sentence)\n \n # If a match is found, return its start and end positions, and the word itself\n if match:\n return (match.start(), match.end(), match.group(0))\n else:\n return None", "matching_cluster_idx": 3}, {"solution": "import re\ndef find_adverb_position(sentence):\n # Using regular expression to find the first adverb and its position\n match = re.search(r'\\w+ly', sentence)\n if match:\n start, end = match.span()\n adverb = match.group()\n return (start, end, adverb)\n else:\n return None", "matching_cluster_idx": 3}, {"solution": "import re\ndef find_adverb_position(sentence):\n # Use regular expression to find the first adverb in the sentence\n match = re.search(r'\\w+ly', sentence)\n \n # If an adverb is found, return its start position, end position, and the adverb itself\n if match:\n start, end = match.span()\n adverb = match.group()\n return (start, end, adverb)\n else:\n # If no adverb is found, return None\n return None", "matching_cluster_idx": 3}, {"solution": "import re\ndef find_adverb_position(sentence):\n # Find all matches of words ending in 'ly' with their starting positions\n for match in re.finditer(r'\\w+ly', sentence):\n start_pos = match.start()\n end_pos = match.end()\n adverb = match.group()\n return (start_pos, end_pos, adverb)\n # Return None if no adverb is found\n return None", "matching_cluster_idx": 3}, {"solution": "import re\ndef find_adverb_position(sentence):\n # Search for the first adverb in the sentence\n match = re.search(r'\\w+ly', sentence)\n if match:\n # Return the start position, end position, and the adverb\n return (match.start(), match.end(), match.group(0))\n else:\n # Return None if no adverb is found\n return None", "matching_cluster_idx": 3}, {"solution": "import re\ndef find_adverb_position(sentence):\n # Use regular expression to find the first adverb and its position\n match = re.search(r'\\w+ly', sentence)\n if match:\n return (match.start(), match.end(), match.group(0))\n else:\n return None", "matching_cluster_idx": 3}, {"solution": "import re\ndef find_adverb_position(sentence):\n # Use regular expression to find the first occurrence of a word ending in 'ly'\n match = re.search(r'\\w+ly', sentence)\n \n # If a match is found, return the start and end positions, along with the matched adverb\n if match:\n return (match.start(), match.end(), match.group(0))\n else:\n return None", "matching_cluster_idx": 3}, {"solution": "import re\ndef find_adverb_position(sentence):\n # Using regular expression to find adverbs and their positions\n match = re.search(r'\\w+ly', sentence)\n \n # If an adverb is found, return its start and end positions along with the adverb itself\n if match:\n return (match.start(), match.end(), match.group(0))\n else:\n # Return None if no adverb is found\n return None", "matching_cluster_idx": 3}, {"solution": "import re\ndef find_adverb_position(sentence):\n # Use regular expression to find all words ending with 'ly'\n for match in re.finditer(r'\\w+ly', sentence):\n start_pos = match.start()\n end_pos = match.end()\n adverb = match.group()\n return (start_pos, end_pos, adverb)\n return None", "matching_cluster_idx": 3}]}, "Mbpp/446": {"dps": 96.05911330049261, "dps_norm": 60.0, "pass@1": 100.0, "profiled": [{"solution": "def count_Occurrence(tup, lst):\n # Initialize a counter to keep track of the occurrences\n count = 0\n \n # Iterate over each element in the list\n for item in lst:\n # Count the occurrences of the item in the tuple and add to the counter\n count += tup.count(item)\n \n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tup, lst):\n # Initialize a counter to zero\n count = 0\n \n # Iterate through each element in the list\n for item in lst:\n # Count the occurrences of the element in the tuple and add to the counter\n count += tup.count(item)\n \n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tup, lst):\n # Initialize a counter to zero\n count = 0\n \n # Iterate over each element in the list\n for item in lst:\n # Count the occurrences of the element in the tuple and add to the counter\n count += tup.count(item)\n \n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tup, lst):\n # Initialize a counter to zero\n count = 0\n # Iterate through each element in the list\n for item in lst:\n # Add the number of occurrences of the item in the tuple to the counter\n count += tup.count(item)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tup, lst):\n # Initialize a counter to zero\n count = 0\n \n # Iterate through each element in the list\n for item in lst:\n # Count occurrences of the current element in the tuple and add to the counter\n count += tup.count(item)\n \n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tup, lst):\n # Initialize a counter to keep track of the total occurrences\n count = 0\n \n # Iterate over each element in the list\n for element in lst:\n # Count how many times the element appears in the tuple\n count += tup.count(element)\n \n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tup, lst):\n # Initialize a counter to keep track of occurrences\n count = 0\n \n # Iterate over each element in the list\n for item in lst:\n # Count occurrences of the item in the tuple\n count += tup.count(item)\n \n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tup, lst):\n # Initialize a counter to keep track of occurrences\n count = 0\n # Iterate through each element in the list\n for item in lst:\n # Add the number of occurrences of the item in the tuple to the counter\n count += tup.count(item)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tup, lst):\n # Initialize a counter to keep track of occurrences\n count = 0\n \n # Iterate over each element in the list\n for element in lst:\n # Count how many times the element appears in the tuple\n count += tup.count(element)\n \n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tup, lst):\n # Initialize a counter to zero\n count = 0\n \n # Iterate over each element in the list\n for item in lst:\n # Count the occurrences of the element in the tuple and add it to the counter\n count += tup.count(item)\n \n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tup, lst):\n # Initialize a counter to zero\n count = 0\n \n # Iterate over each element in the list\n for item in lst:\n # Count how many times the element appears in the tuple\n count += tup.count(item)\n \n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tup, lst):\n # Initialize a counter to keep track of occurrences\n count = 0\n \n # Iterate over each element in the list\n for item in lst:\n # Count how many times the item appears in the tuple\n count += tup.count(item)\n \n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tup, lst):\n # Initialize a counter to zero\n count = 0\n \n # Iterate over each element in the list\n for item in lst:\n # Count the occurrences of the item in the tuple and add to the counter\n count += tup.count(item)\n \n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tup, lst):\n # Initialize a counter to keep track of occurrences\n count = 0\n \n # Iterate over each element in the list\n for item in lst:\n # Count the occurrences of the item in the tuple and add to the counter\n count += tup.count(item)\n \n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tup, lst):\n # Initialize a counter to zero\n count = 0\n \n # Iterate through each element in the list\n for element in lst:\n # Count the occurrences of the element in the tuple and add it to the counter\n count += tup.count(element)\n \n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tup, lst):\n # Initialize a counter for occurrences\n count = 0\n \n # Iterate through each element in the list\n for item in lst:\n # Count the occurrences of the element in the tuple and add to the counter\n count += tup.count(item)\n \n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tup, lst):\n # Initialize a counter to zero\n count = 0\n # Iterate over each element in the list\n for item in lst:\n # Add the number of occurrences of the item in the tuple to the count\n count += tup.count(item)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tup, lst):\n # Initialize a counter to zero\n count = 0\n \n # Iterate over each element in the list\n for item in lst:\n # Count the occurrences of the element in the tuple and add to the counter\n count += tup.count(item)\n \n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tup, lst):\n # Initialize a counter to keep track of occurrences\n count = 0\n # Iterate through each element in the list\n for item in lst:\n # Count occurrences of the item in the tuple and add to the counter\n count += tup.count(item)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tup, lst):\n # Initialize a counter to zero\n count = 0\n # Iterate over each element in the list\n for item in lst:\n # Count how many times the item appears in the tuple and add it to the counter\n count += tup.count(item)\n return count", "matching_cluster_idx": 2}]}, "Mbpp/451": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 95.0, "profiled": [{"solution": "def remove_whitespaces(input_string):\n # Use the replace method to remove all spaces\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(s):\n # Use the replace method to remove all whitespace characters\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string):\n # Use the replace method to remove all whitespace characters\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string):\n # Use the replace method to remove all spaces from the string\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string):\n # Using the str.replace() method to remove all spaces\n return input_string.replace(' ', '')", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string):\n # Use the replace method to remove all spaces from the string\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string):\n # Use the replace method to remove all whitespace characters\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string):\n # Use the replace method to remove all whitespace characters\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string):\n # Use the str.replace() method to remove all spaces\n return input_string.replace(' ', '')", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string):\n # Use the replace method to remove all whitespace characters\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string):\n # Use the replace method to remove all spaces from the input string\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string):\n # Use the replace method to remove all spaces from the string\n return input_string.replace(' ', '')", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string):\n # Use the replace method to remove all spaces from the string\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string):\n # Use the replace method to remove all spaces from the string\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string):\n # Use the replace method to remove all spaces from the string\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string):\n # Use the replace method to remove all spaces from the input string\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string):\n # Use the str.replace method to remove all whitespace characters\n return input_string.replace(' ', '')", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string):\n # Use the replace method to remove all spaces from the string\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string):\n # Use the replace method to remove all spaces from the string\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string):\n # Use the replace method to remove all spaces from the string\n return input_string.replace(' ', '')", "matching_cluster_idx": 4}]}, "Mbpp/456": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def reverse_string_list(string_list):\n # Use a list comprehension to reverse each string in the input list\n reversed_list = [s[::-1] for s in string_list]\n return reversed_list", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n # Reverse each string in the list using list comprehension\n reversed_list = [s[::-1] for s in string_list]\n return reversed_list", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(strings):\n # Reverse each string in the list using list comprehension\n reversed_strings = [s[::-1] for s in strings]\n return reversed_strings", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(strings):\n # Reverse each string in the list using a list comprehension\n reversed_strings = [s[::-1] for s in strings]\n return reversed_strings", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(lst):\n # Reverse each string in the list using a list comprehension\n return [s[::-1] for s in lst]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n # Reverse each string in the list using list comprehension\n reversed_list = [s[::-1] for s in string_list]\n return reversed_list", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n # Reverse each string in the list using a list comprehension\n reversed_list = [s[::-1] for s in string_list]\n return reversed_list", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n # Initialize an empty list to store the reversed strings\n reversed_list = []\n \n # Iterate over each string in the input list\n for string in string_list:\n # Reverse the string using slicing and append it to the reversed_list\n reversed_list.append(string[::-1])\n \n # Return the list of reversed strings\n return reversed_list", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(strings):\n # Reverse each string in the list using a list comprehension\n reversed_strings = [s[::-1] for s in strings]\n return reversed_strings", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(strings):\n # Use list comprehension to reverse each string in the list\n reversed_strings = [s[::-1] for s in strings]\n return reversed_strings", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(strings):\n # Use list comprehension to reverse each string in the list\n reversed_strings = [s[::-1] for s in strings]\n return reversed_strings", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(strings):\n # Reverse each string in the list using list comprehension\n reversed_strings = [s[::-1] for s in strings]\n return reversed_strings", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(strings):\n # Reverse each string in the list using a list comprehension\n return [s[::-1] for s in strings]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(lst):\n # Reverse each string in the list using a list comprehension\n reversed_list = [s[::-1] for s in lst]\n return reversed_list", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(strings):\n # Reverse each string in the list using list comprehension\n reversed_strings = [s[::-1] for s in strings]\n return reversed_strings", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n # Reverse each string in the list using a list comprehension\n reversed_list = [s[::-1] for s in string_list]\n return reversed_list", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(strings):\n # Reverse each string in the list using list comprehension\n reversed_strings = [s[::-1] for s in strings]\n return reversed_strings", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(strings):\n # Reverse each string in the list using list comprehension\n reversed_strings = [s[::-1] for s in strings]\n return reversed_strings", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(strings):\n # Reverse each string in the list using list comprehension\n reversed_strings = [s[::-1] for s in strings]\n return reversed_strings", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(strings):\n # Reverse each string in the list using a list comprehension\n reversed_strings = [s[::-1] for s in strings]\n return reversed_strings", "matching_cluster_idx": 4}]}, "Mbpp/460": {"dps": 48.07692307692307, "dps_norm": 80.0, "pass@1": 100.0, "profiled": [{"solution": "def Extract(list_of_lists):\n # Use list comprehension to extract the first element from each sublist\n return [sublist[0] for sublist in list_of_lists]", "matching_cluster_idx": 3}, {"solution": "def Extract(lst):\n # Use list comprehension to extract the first element of each sublist\n return [item[0] for item in lst]", "matching_cluster_idx": 3}, {"solution": "def Extract(list_of_lists):\n # Use list comprehension to extract the first element of each sublist\n return [sublist[0] for sublist in list_of_lists]", "matching_cluster_idx": 3}, {"solution": "def Extract(lst):\n # Using list comprehension to extract the first element of each sublist\n return [item[0] for item in lst]", "matching_cluster_idx": 3}, {"solution": "def Extract(lst):\n # Use list comprehension to iterate through each sublist and extract the first element\n return [item[0] for item in lst]", "matching_cluster_idx": 3}, {"solution": "def Extract(lst):\n # Using list comprehension to extract the first element of each sublist\n return [item[0] for item in lst]", "matching_cluster_idx": 3}, {"solution": "def Extract(list_of_lists):\n # Use list comprehension to iterate through each sublist and extract the first element\n return [sublist[0] for sublist in list_of_lists]", "matching_cluster_idx": 3}, {"solution": "def Extract(lst):\n # Use list comprehension to extract the first element from each sublist\n return [item[0] for item in lst]", "matching_cluster_idx": 3}, {"solution": "def Extract(list_of_lists):\n # Initialize an empty list to store the first elements\n first_elements = []\n # Iterate through each sublist in the main list\n for sublist in list_of_lists:\n # Append the first element of the sublist to the result list\n first_elements.append(sublist[0])\n return first_elements", "matching_cluster_idx": 3}, {"solution": "def Extract(lst):\n # Using list comprehension to extract the first element of each sublist\n return [item[0] for item in lst]", "matching_cluster_idx": 3}, {"solution": "def Extract(lst):\n # Use list comprehension to extract the first element from each sublist\n return [item[0] for item in lst]", "matching_cluster_idx": 3}, {"solution": "def Extract(lst):\n # Extract the first element from each sublist using list comprehension\n return [item[0] for item in lst]", "matching_cluster_idx": 3}, {"solution": "def Extract(lst):\n # Use list comprehension to extract the first element from each sublist\n return [item[0] for item in lst]", "matching_cluster_idx": 3}, {"solution": "def Extract(lst):\n # Use list comprehension to iterate through each sublist and extract the first element\n return [item[0] for item in lst]", "matching_cluster_idx": 3}, {"solution": "def Extract(lst):\n # Use list comprehension to iterate through each sublist in the list and extract the first element\n return [item[0] for item in lst]", "matching_cluster_idx": 3}, {"solution": "def Extract(lst):\n # Use list comprehension to extract the first element of each sublist\n return [item[0] for item in lst]", "matching_cluster_idx": 3}, {"solution": "def Extract(lst):\n # Using list comprehension to extract the first element of each sublist\n return [item[0] for item in lst]", "matching_cluster_idx": 3}, {"solution": "def Extract(lst):\n # Use list comprehension to extract the first element of each sublist\n return [item[0] for item in lst]", "matching_cluster_idx": 3}, {"solution": "def Extract(lst):\n # Use list comprehension to iterate through each sublist in the list and extract the first element\n return [item[0] for item in lst]", "matching_cluster_idx": 3}, {"solution": "def Extract(lst):\n # Use list comprehension to extract the first element from each sublist\n return [item[0] for item in lst]", "matching_cluster_idx": 3}]}, "Mbpp/474": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def replace_char(s, old_char, new_char):\n # Replace occurrences of old_char with new_char in the string s\n return s.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(string, old_char, new_char):\n # Replace occurrences of old_char with new_char in the string\n modified_string = string.replace(old_char, new_char)\n return modified_string", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, old_char, new_char):\n # Replace occurrences of old_char with new_char in the string s\n return s.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, old_char, new_char):\n # Replace occurrences of old_char with new_char in the string s\n return s.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, old_char, new_char):\n # Replace occurrences of old_char with new_char in the string s\n return s.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, old_char, new_char):\n \"\"\"\n Replaces all occurrences of old_char with new_char in the given string s.\n\n :param s: The original string.\n :param old_char: The character to be replaced.\n :param new_char: The character to replace with.\n :return: A new string with the replacements made.\n \"\"\"\n return s.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, old_char, new_char):\n # Replace occurrences of old_char with new_char in the string s\n return s.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(string, old_char, new_char):\n # Replace occurrences of old_char with new_char in the string\n return string.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, old_char, new_char):\n \"\"\"\n Replace all occurrences of 'old_char' in the string 's' with 'new_char'.\n\n :param s: The original string.\n :param old_char: The character to be replaced.\n :param new_char: The character to replace with.\n :return: The modified string.\n \"\"\"\n return s.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, old, new):\n # Replace occurrences of 'old' character with 'new' character in the string 's'\n return s.replace(old, new)", "matching_cluster_idx": 6}, {"solution": "def replace_char(string, old_char, new_char):\n # Replace occurrences of old_char with new_char in the string\n modified_string = string.replace(old_char, new_char)\n return modified_string", "matching_cluster_idx": 6}, {"solution": "def replace_char(input_string, old_char, new_char):\n # Replace occurrences of old_char with new_char in input_string\n modified_string = input_string.replace(old_char, new_char)\n return modified_string", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, old_char, new_char):\n # Replace occurrences of old_char with new_char in the string s\n return s.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(string, old_char, new_char):\n # Replace occurrences of old_char with new_char in the string\n modified_string = string.replace(old_char, new_char)\n return modified_string", "matching_cluster_idx": 6}, {"solution": "def replace_char(input_string, old_char, new_char):\n # Replace occurrences of old_char with new_char in input_string\n return input_string.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(string, old_char, new_char):\n # Replace occurrences of old_char with new_char in the string\n modified_string = string.replace(old_char, new_char)\n return modified_string", "matching_cluster_idx": 6}, {"solution": "def replace_char(string, old_char, new_char):\n # Replace occurrences of old_char with new_char in the string\n return string.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(string, old_char, new_char):\n # Replace occurrences of old_char with new_char in the string\n modified_string = string.replace(old_char, new_char)\n return modified_string", "matching_cluster_idx": 6}, {"solution": "def replace_char(string, old_char, new_char):\n # Replace occurrences of old_char with new_char in the string\n modified_string = string.replace(old_char, new_char)\n return modified_string", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, old_char, new_char):\n # Replace occurrences of old_char with new_char in the string s\n return s.replace(old_char, new_char)", "matching_cluster_idx": 6}]}, "Mbpp/476": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def big_sum(arr):\n # Find the maximum value in the array\n max_value = max(arr)\n # Find the minimum value in the array\n min_value = min(arr)\n # Return the sum of the maximum and minimum values\n return max_value + min_value", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n # Find the maximum and minimum values in the array\n max_value = max(arr)\n min_value = min(arr)\n \n # Calculate the sum of the maximum and minimum values\n return max_value + min_value", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n # Find the maximum and minimum values in the array\n max_value = max(arr)\n min_value = min(arr)\n \n # Return the sum of the maximum and minimum values\n return max_value + min_value", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n # Find the smallest and largest values in the array\n min_val = min(arr)\n max_val = max(arr)\n \n # Return the sum of the smallest and largest values\n return min_val + max_val", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n # Find the maximum and minimum values in the array\n max_value = max(arr)\n min_value = min(arr)\n \n # Calculate the sum of the maximum and minimum values\n result = max_value + min_value\n \n return result", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n # Find the maximum value in the array\n max_value = max(arr)\n # Find the minimum value in the array\n min_value = min(arr)\n # Return the sum of the maximum and minimum values\n return max_value + min_value", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n # Find the maximum and minimum values in the array\n max_value = max(arr)\n min_value = min(arr)\n \n # Calculate the sum of the maximum and minimum values\n total = max_value + min_value\n \n return total", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n # Find the smallest and largest values in the array\n smallest = min(arr)\n largest = max(arr)\n \n # Return the sum of the smallest and largest values\n return smallest + largest", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n # Find the smallest and largest values in the array\n min_val = min(arr)\n max_val = max(arr)\n \n # Calculate the sum of the smallest and largest values\n result = min_val + max_val\n \n return result", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n # Find the smallest and largest values in the array\n smallest = min(arr)\n largest = max(arr)\n \n # Return the sum of the smallest and largest values\n return smallest + largest", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n # Check if the array is empty to avoid errors\n if not arr:\n return 0\n \n # Find the maximum and minimum values in the array\n max_value = max(arr)\n min_value = min(arr)\n \n # Return the sum of the maximum and minimum values\n return max_value + min_value", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n # Find the maximum and minimum values in the array\n max_value = max(arr)\n min_value = min(arr)\n \n # Return the sum of the maximum and minimum values\n return max_value + min_value", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n # Find the minimum and maximum values in the array\n min_val = min(arr)\n max_val = max(arr)\n \n # Return the sum of the minimum and maximum values\n return min_val + max_val", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n # Find the maximum and minimum values in the array\n max_value = max(arr)\n min_value = min(arr)\n \n # Calculate the sum of the maximum and minimum values\n result = max_value + min_value\n \n return result", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n # Find the smallest and largest values in the array\n smallest = min(arr)\n largest = max(arr)\n \n # Return the sum of the smallest and largest values\n return smallest + largest", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n # Find the smallest value in the array\n smallest = min(arr)\n # Find the largest value in the array\n largest = max(arr)\n # Return the sum of the smallest and largest values\n return smallest + largest", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n # Find the smallest value in the array\n min_val = min(arr)\n # Find the largest value in the array\n max_val = max(arr)\n # Return the sum of the smallest and largest values\n return min_val + max_val", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n # Find the smallest and largest values in the array\n smallest = min(arr)\n largest = max(arr)\n \n # Return the sum of the smallest and largest values\n return smallest + largest", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n # Find the minimum and maximum values in the array\n min_val = min(arr)\n max_val = max(arr)\n \n # Calculate the sum of the minimum and maximum values\n result = min_val + max_val\n \n return result", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n # Find the maximum and minimum values in the array\n max_value = max(arr)\n min_value = min(arr)\n \n # Return the sum of the maximum and minimum values\n return max_value + min_value", "matching_cluster_idx": 5}]}, "Mbpp/477": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def is_lower(s):\n # Convert the given string to lower case\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n # Convert the string to lower case using the lower() method\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n # Convert the string to lower case using the `lower()` method\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n # Convert the string to lower case using the lower() method\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n # Convert the input string to lower case\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n # Convert the string to lower case using the lower() method\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n # Convert the input string to lower case\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n # Convert the string to lower case\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n # Convert the input string to lower case\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n # Convert the given string to lower case using the lower() method\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n # Convert the given string to lower case\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n # Convert the input string to lowercase\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n # Convert the string to lower case\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n # Convert the string to lower case\n lower_s = s.lower()\n return lower_s", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n # Convert the given string to lower case\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n # Convert the input string to lower case using the lower() method\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n # Convert the string to lower case using the lower() method\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n # Convert the string to lower case\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n # Convert the string to lower case\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n # Convert the string to lower case using the lower() method\n return s.lower()", "matching_cluster_idx": 4}]}, "Mbpp/563": {"dps": 85.24590163934427, "dps_norm": 81.81818181818181, "pass@1": 100.0, "profiled": [{"solution": "import re\ndef extract_values(s):\n # Use regular expression to find all substrings enclosed in double quotes\n return re.findall(r'\"(.*?)\"', s)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(string):\n # Use regular expression to find all substrings between double quotes\n values = re.findall(r'\"(.*?)\"', string)\n return values", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(string):\n # Using regular expression to find all occurrences of text within double quotes\n matches = re.findall(r'\"(.*?)\"', string)\n return matches", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(input_string):\n # Use regular expression to find all substrings enclosed in double quotes\n matches = re.findall(r'\"(.*?)\"', input_string)\n return matches", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(s):\n # Use regular expression to find all substrings enclosed in double quotes\n return re.findall(r'\"(.*?)\"', s)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(string):\n # Use regular expression to find all substrings between double quotes\n return re.findall(r'\"(.*?)\"', string)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(input_string):\n # Use regular expression to find all substrings between double quotes\n matches = re.findall(r'\"(.*?)\"', input_string)\n return matches", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(s):\n # Use regular expression to find all substrings between double quotes\n return re.findall(r'\"(.*?)\"', s)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(input_string):\n # Use regular expression to find all substrings enclosed in double quotes\n matches = re.findall(r'\"(.*?)\"', input_string)\n return matches", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(s):\n # Use regular expression to find all substrings between double quotes\n return re.findall(r'\"(.*?)\"', s)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(input_string):\n # Using regular expression to find all substrings between double quotation marks\n return re.findall(r'\"(.*?)\"', input_string)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(string):\n # Use regular expression to find all substrings enclosed in double quotes\n matches = re.findall(r'\"(.*?)\"', string)\n return matches", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(s):\n # Use regular expression to find all substrings between double quotation marks\n return re.findall(r'\"(.*?)\"', s)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(input_string):\n # Use regular expression to find all occurrences of text between double quotes\n matches = re.findall(r'\"(.*?)\"', input_string)\n return matches", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(string):\n # Use regular expression to find all substrings between double quotation marks\n matches = re.findall(r'\"(.*?)\"', string)\n return matches", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(s):\n # Use regular expression to find all substrings between double quotes\n return re.findall(r'\"(.*?)\"', s)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(input_string):\n # Use regular expression to find all occurrences of text within double quotes\n matches = re.findall(r'\"(.*?)\"', input_string)\n return matches", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(string):\n # Using regular expression to find all substrings between double quotation marks\n return re.findall(r'\"(.*?)\"', string)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(s):\n # Use regular expression to find all substrings between double quotes\n return re.findall(r'\"(.*?)\"', s)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(string):\n # Use regular expression to find all substrings between double quotes\n return re.findall(r'\"(.*?)\"', string)", "matching_cluster_idx": 8}]}, "Mbpp/572": {"dps": 95.06172839506173, "dps_norm": 85.71428571428571, "pass@1": 100.0, "profiled": [{"solution": "def two_unique_nums(nums):\n # Create a dictionary to count occurrences of each number\n count_dict = {}\n for num in nums:\n if num in count_dict:\n count_dict[num] += 1\n else:\n count_dict[num] = 1\n \n # Collect numbers that appear exactly once\n unique_nums = [num for num, count in count_dict.items() if count == 1]\n \n return unique_nums", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(nums):\n # Track the frequency of each number\n freq = {}\n for num in nums:\n if num in freq:\n freq[num] += 1\n else:\n freq[num] = 1\n \n # Collect numbers that appear exactly once\n result = [num for num in nums if freq[num] == 1]\n \n return result", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(nums):\n # Track the frequency of each number\n frequency = {}\n for num in nums:\n if num in frequency:\n frequency[num] += 1\n else:\n frequency[num] = 1\n \n # Collect numbers that appear exactly once\n result = [num for num in nums if frequency[num] == 1]\n \n return result", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(nums):\n # Track the frequency of each number\n frequency = {}\n for num in nums:\n if num in frequency:\n frequency[num] += 1\n else:\n frequency[num] = 1\n \n # Collect numbers that appear exactly once\n unique_nums = [num for num, count in frequency.items() if count == 1]\n \n return unique_nums", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(nums):\n # Track the frequency of each number\n frequency = {}\n for num in nums:\n if num in frequency:\n frequency[num] += 1\n else:\n frequency[num] = 1\n \n # Collect numbers that appear exactly once\n result = [num for num, freq in frequency.items() if freq == 1]\n \n return result", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(nums):\n # Count the occurrence of each number in the list\n count = {}\n for num in nums:\n if num in count:\n count[num] += 1\n else:\n count[num] = 1\n \n # Filter out the numbers that appear more than once\n result = [num for num in nums if count[num] == 1]\n \n return result", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(nums):\n # Create a dictionary to count occurrences of each number\n count = {}\n for num in nums:\n if num in count:\n count[num] += 1\n else:\n count[num] = 1\n \n # Collect numbers that appear exactly once\n result = [num for num in nums if count[num] == 1]\n \n return result", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(nums):\n # Count the occurrence of each number in the list\n count = {}\n for num in nums:\n if num in count:\n count[num] += 1\n else:\n count[num] = 1\n \n # Filter the numbers that appear exactly once\n result = [num for num in nums if count[num] == 1]\n \n return result", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(nums):\n # Create a dictionary to count occurrences of each number\n count = {}\n for num in nums:\n if num in count:\n count[num] += 1\n else:\n count[num] = 1\n \n # Filter the list to include only numbers that appear exactly once\n result = [num for num in nums if count[num] == 1]\n \n return result", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(nums):\n # Track the frequency of each number\n freq = {}\n for num in nums:\n if num in freq:\n freq[num] += 1\n else:\n freq[num] = 1\n \n # Filter out numbers that appear more than once\n result = [num for num in nums if freq[num] == 1]\n \n return result", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(nums):\n # Track the frequency of each number\n frequency = {}\n for num in nums:\n if num in frequency:\n frequency[num] += 1\n else:\n frequency[num] = 1\n \n # Collect numbers that appear exactly once\n result = [num for num in nums if frequency[num] == 1]\n \n return result", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(nums):\n # Track the frequency of each number\n frequency = {}\n for num in nums:\n if num in frequency:\n frequency[num] += 1\n else:\n frequency[num] = 1\n \n # Collect numbers that appear exactly once\n result = [num for num in nums if frequency[num] == 1]\n \n return result", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(nums):\n # Track the frequency of each number\n frequency = {}\n for num in nums:\n if num in frequency:\n frequency[num] += 1\n else:\n frequency[num] = 1\n \n # Collect numbers that appear exactly once\n result = [num for num in nums if frequency[num] == 1]\n \n return result", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(lst):\n # Create a dictionary to count occurrences of each number\n count_dict = {}\n for num in lst:\n if num in count_dict:\n count_dict[num] += 1\n else:\n count_dict[num] = 1\n \n # Filter the list to include only numbers that appear exactly once\n unique_nums = [num for num, count in count_dict.items() if count == 1]\n \n return unique_nums", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(nums):\n # Track the frequency of each number in the list\n frequency = {}\n for num in nums:\n if num in frequency:\n frequency[num] += 1\n else:\n frequency[num] = 1\n \n # Collect numbers that appear exactly once\n result = [num for num, count in frequency.items() if count == 1]\n \n return result", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(nums):\n # Create a dictionary to count occurrences of each number\n count = {}\n for num in nums:\n if num in count:\n count[num] += 1\n else:\n count[num] = 1\n \n # Collect numbers that appear exactly once\n result = [num for num, freq in count.items() if freq == 1]\n \n return result", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(nums):\n # Create a dictionary to count occurrences of each number\n count = {}\n for num in nums:\n if num in count:\n count[num] += 1\n else:\n count[num] = 1\n \n # Filter the numbers that appear exactly once\n unique_nums = [num for num, freq in count.items() if freq == 1]\n \n return unique_nums", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(nums):\n # Track the frequency of each number in the list\n frequency = {}\n for num in nums:\n if num in frequency:\n frequency[num] += 1\n else:\n frequency[num] = 1\n \n # Collect numbers that appear exactly once\n unique_nums = [num for num, count in frequency.items() if count == 1]\n \n return unique_nums", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(lst):\n # Dictionary to keep track of the occurrence of each number\n count_dict = {}\n for num in lst:\n if num in count_dict:\n count_dict[num] += 1\n else:\n count_dict[num] = 1\n \n # List to store numbers that appear exactly once\n result = [num for num in lst if count_dict[num] == 1]\n \n return result", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(nums):\n # Create a dictionary to count occurrences of each number\n count = {}\n for num in nums:\n if num in count:\n count[num] += 1\n else:\n count[num] = 1\n \n # Collect numbers that appear exactly once\n result = [num for num, freq in count.items() if freq == 1]\n \n return result", "matching_cluster_idx": 5}]}, "Mbpp/578": {"dps": 58.41269841269841, "dps_norm": 63.63636363636363, "pass@1": 100.0, "profiled": [{"solution": "def interleave_lists(list1, list2, list3):\n # Initialize an empty list to store the interleaved elements\n interleaved_list = []\n \n # Iterate over the indices of the lists\n for i in range(len(list1)):\n # Append elements from each list to the interleaved list\n interleaved_list.append(list1[i])\n interleaved_list.append(list2[i])\n interleaved_list.append(list3[i])\n \n return interleaved_list", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n # Initialize an empty list to store the result\n result = []\n \n # Loop through the lists and interleave their elements\n for i in range(len(list1)):\n result.append(list1[i])\n result.append(list2[i])\n result.append(list3[i])\n \n return result", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n # Initialize an empty list to store the interleaved result\n result = []\n \n # Iterate over the indices of the lists\n for i in range(len(list1)):\n # Append elements from each list to the result list\n result.append(list1[i])\n result.append(list2[i])\n result.append(list3[i])\n \n return result", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n # Initialize an empty list to store the result\n result = []\n \n # Iterate through the indices of the lists\n for i in range(len(list1)):\n # Append elements from each list in order to the result list\n result.append(list1[i])\n result.append(list2[i])\n result.append(list3[i])\n \n return result", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n # Initialize an empty list to store the result\n result = []\n \n # Iterate through the lists and interleave their elements\n for i in range(len(list1)):\n result.append(list1[i])\n result.append(list2[i])\n result.append(list3[i])\n \n return result", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n # Initialize an empty list to store the interleaved result\n result = []\n \n # Loop through the indices of the lists\n for i in range(len(list1)):\n # Append elements from each list at the current index to the result list\n result.append(list1[i])\n result.append(list2[i])\n result.append(list3[i])\n \n return result", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n # Initialize an empty list to store the interleaved elements\n result = []\n \n # Loop through the indices of the lists\n for i in range(len(list1)):\n # Append elements from each list at the current index\n result.append(list1[i])\n result.append(list2[i])\n result.append(list3[i])\n \n return result", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n # Initialize an empty list to store the interleaved result\n interleaved_list = []\n \n # Iterate over the index range of the lists\n for i in range(len(list1)):\n # Append elements from each list in order\n interleaved_list.append(list1[i])\n interleaved_list.append(list2[i])\n interleaved_list.append(list3[i])\n \n return interleaved_list", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n # Initialize an empty list to store the result\n result = []\n \n # Iterate over the indices of the lists\n for i in range(len(list1)):\n # Append elements from each list in order\n result.append(list1[i])\n result.append(list2[i])\n result.append(list3[i])\n \n return result", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n # Initialize an empty list to store the interleaved result\n result = []\n \n # Iterate through the indices of the lists\n for i in range(len(list1)):\n # Append elements from each list at the current index to the result list\n result.append(list1[i])\n result.append(list2[i])\n result.append(list3[i])\n \n return result", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n # Initialize an empty list to store the interleaved result\n result = []\n \n # Loop through the indices of the lists\n for i in range(len(list1)):\n # Append elements from each list at the current index to the result list\n result.append(list1[i])\n result.append(list2[i])\n result.append(list3[i])\n \n return result", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n # Initialize an empty list to store the result\n result = []\n # Iterate through the lists, assuming they have the same length\n for i in range(len(list1)):\n # Append elements from each list to the result list in the desired order\n result.append(list1[i])\n result.append(list2[i])\n result.append(list3[i])\n return result", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n # Initialize an empty list to store the result\n result = []\n \n # Iterate over the lists using the range of their length\n for i in range(len(list1)):\n # Append elements from each list to the result in order\n result.append(list1[i])\n result.append(list2[i])\n result.append(list3[i])\n \n return result", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n # Initialize an empty list to store the interleaved result\n result = []\n \n # Iterate through the indices of the lists\n for i in range(len(list1)):\n # Append the elements from each list in the desired order\n result.append(list1[i])\n result.append(list2[i])\n result.append(list3[i])\n \n return result", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n # Initialize an empty list to store the interleaved elements\n interleaved_list = []\n \n # Loop through the indices of the lists\n for i in range(len(list1)):\n # Append elements from each list at the current index\n interleaved_list.append(list1[i])\n interleaved_list.append(list2[i])\n interleaved_list.append(list3[i])\n \n return interleaved_list", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n # Initialize an empty list to store the result\n result = []\n \n # Iterate over the lists using their index\n for i in range(len(list1)):\n # Append elements from each list to the result list\n result.append(list1[i])\n result.append(list2[i])\n result.append(list3[i])\n \n return result", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n # Initialize an empty list to store the interleaved elements\n interleaved_list = []\n \n # Iterate over the indices of the lists\n for i in range(len(list1)):\n # Append the i-th element from each list to the interleaved list\n interleaved_list.append(list1[i])\n interleaved_list.append(list2[i])\n interleaved_list.append(list3[i])\n \n return interleaved_list", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n # Initialize an empty list to store the interleaved elements\n result = []\n \n # Loop through the indices of the lists\n for i in range(len(list1)):\n # Append elements from each list at the current index\n result.append(list1[i])\n result.append(list2[i])\n result.append(list3[i])\n \n return result", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n # Initialize an empty list to store the result\n result = []\n \n # Loop through the indices of the lists\n for i in range(len(list1)):\n # Append elements from each list to the result list\n result.append(list1[i])\n result.append(list2[i])\n result.append(list3[i])\n \n return result", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n # Initialize an empty list to store the result\n result = []\n \n # Iterate through the indices of the lists\n for i in range(len(list1)):\n # Append elements from each list to the result list\n result.append(list1[i])\n result.append(list2[i])\n result.append(list3[i])\n \n return result", "matching_cluster_idx": 6}]}, "Mbpp/586": {"dps": 98.83040935672514, "dps_norm": 87.5, "pass@1": 100.0, "profiled": [{"solution": "def split_Arr(arr, n):\n # Split the array into two parts at the nth element\n first_part = arr[:n]\n second_part = arr[n:]\n \n # Combine the second part with the first part at the end\n result = second_part + first_part\n \n return result", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n # Split the array into two parts at the nth element\n first_part = arr[:n]\n second_part = arr[n:]\n \n # Combine the second part with the first part at the end\n result = second_part + first_part\n \n return result", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n # Split the array into two parts at the nth element\n first_part = arr[:n]\n second_part = arr[n:]\n \n # Combine the second part and the first part\n result = second_part + first_part\n \n return result", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n # Split the array into two parts\n first_part = arr[:n]\n second_part = arr[n:]\n \n # Combine the second part with the first part at the end\n result = second_part + first_part\n \n return result", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n # Split the array into two parts at the nth element\n first_part = arr[:n]\n second_part = arr[n:]\n \n # Combine the second part with the first part\n result = second_part + first_part\n \n return result", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n # Split the list into two parts\n first_part = arr[:n]\n second_part = arr[n:]\n \n # Combine the second part and the first part\n result = second_part + first_part\n \n return result", "matching_cluster_idx": 6}, {"solution": "def split_Arr(lst, n):\n # Split the list into two parts at the nth element\n first_part = lst[:n]\n second_part = lst[n:]\n \n # Combine the second part with the first part\n result = second_part + first_part\n \n return result", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n # Split the array into two parts\n first_part = arr[:n]\n second_part = arr[n:]\n \n # Concatenate the second part with the first part\n result = second_part + first_part\n \n return result", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n # Split the list into two parts at the nth element\n first_part = arr[:n]\n second_part = arr[n:]\n \n # Combine the second part with the first part at the end\n result = second_part + first_part\n \n return result", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n # Split the list into two parts\n first_part = arr[:n]\n second_part = arr[n:]\n \n # Combine the second part with the first part\n result = second_part + first_part\n \n return result", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n # Split the list into two parts\n first_part = arr[:n]\n second_part = arr[n:]\n \n # Combine the second part with the first part\n result = second_part + first_part\n \n return result", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n # Split the list into two parts at the nth element\n first_part = arr[:n]\n second_part = arr[n:]\n \n # Combine the second part with the first part\n result = second_part + first_part\n \n return result", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n # Split the list into two parts at the nth element\n first_part = arr[:n]\n second_part = arr[n:]\n \n # Combine the second part with the first part at the end\n result = second_part + first_part\n \n return result", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n # Split the array into two parts at the nth element\n first_part = arr[:n]\n second_part = arr[n:]\n \n # Combine the second part with the first part to get the result\n result = second_part + first_part\n \n return result", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n # Split the array into two parts\n first_part = arr[:n]\n second_part = arr[n:]\n \n # Combine the second part with the first part at the end\n result = second_part + first_part\n \n return result", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n # Split the array into two parts\n first_part = arr[:n]\n second_part = arr[n:]\n \n # Combine the second part with the first part at the end\n result = second_part + first_part\n \n return result", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n # Split the list into two parts at the nth element\n first_part = arr[:n]\n second_part = arr[n:]\n \n # Combine the second part with the first part\n result = second_part + first_part\n \n return result", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n # Split the list into two parts at the nth element\n first_part = arr[:n]\n second_part = arr[n:]\n \n # Combine the second part with the first part at the end\n result = second_part + first_part\n \n return result", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n # Split the list into two parts at the nth element\n first_part = arr[:n]\n second_part = arr[n:]\n \n # Concatenate the second part with the first part\n result = second_part + first_part\n \n return result", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n # Split the list into two parts at the nth element\n first_part = arr[:n]\n second_part = arr[n:]\n \n # Concatenate the second part with the first part\n result = second_part + first_part\n \n return result", "matching_cluster_idx": 6}]}, "Mbpp/587": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def list_tuple(lst):\n # Convert the list to a tuple\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n # Convert the list to a tuple using the tuple() function\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n # Convert the list to a tuple\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n # Convert the list to a tuple\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n # Convert the list to a tuple\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n # Convert the list to a tuple using the tuple() function\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n # Convert the list to a tuple\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(input_list):\n # Convert the list to a tuple using the tuple() function\n return tuple(input_list)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(input_list):\n # Convert the list to a tuple using the tuple() function\n return tuple(input_list)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n # Convert the list to a tuple\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n # Convert the list to a tuple using the tuple() constructor\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n # Convert the list to a tuple using the tuple() function\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(input_list):\n # Convert the list to a tuple using the tuple() function\n converted_tuple = tuple(input_list)\n return converted_tuple", "matching_cluster_idx": 3}, {"solution": "def list_tuple(input_list):\n # Convert the list to a tuple using the tuple() function\n return tuple(input_list)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(list1):\n # Convert the list to a tuple\n return tuple(list1)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n # Convert the list to a tuple\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n # Convert the list to a tuple using the tuple() function\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n # Convert the list to a tuple\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n # Convert the list to a tuple using the tuple() function\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(input_list):\n # Convert the list to a tuple using the tuple() function\n result_tuple = tuple(input_list)\n return result_tuple", "matching_cluster_idx": 3}]}, "Mbpp/588": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def big_diff(nums):\n # Find the maximum value in the list\n max_val = max(nums)\n # Find the minimum value in the list\n min_val = min(nums)\n # Calculate the difference between the maximum and minimum values\n difference = max_val - min_val\n return difference", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n # Calculate the maximum and minimum values in the list\n max_val = max(nums)\n min_val = min(nums)\n \n # Return the difference between the maximum and minimum values\n return max_val - min_val", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n # Find the maximum and minimum values in the list\n max_val = max(nums)\n min_val = min(nums)\n \n # Calculate the difference between the maximum and minimum values\n difference = max_val - min_val\n \n return difference", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n # Find the maximum value in the list\n max_val = max(nums)\n # Find the minimum value in the list\n min_val = min(nums)\n # Calculate the difference between the maximum and minimum values\n difference = max_val - min_val\n return difference", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n # Find the maximum and minimum values in the list\n max_val = max(nums)\n min_val = min(nums)\n \n # Calculate the difference between the maximum and minimum values\n difference = max_val - min_val\n \n return difference", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n # Find the maximum and minimum values in the list\n max_val = max(nums)\n min_val = min(nums)\n \n # Calculate the difference between the maximum and minimum values\n difference = max_val - min_val\n \n return difference", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n # Calculate the maximum value in the list\n max_value = max(nums)\n # Calculate the minimum value in the list\n min_value = min(nums)\n # Return the difference between the maximum and minimum values\n return max_value - min_value", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n # Find the maximum value in the list\n max_val = max(nums)\n # Find the minimum value in the list\n min_val = min(nums)\n # Calculate the difference between the maximum and minimum values\n difference = max_val - min_val\n return difference", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n # Find the maximum and minimum values in the list\n max_val = max(nums)\n min_val = min(nums)\n \n # Calculate the difference between the maximum and minimum values\n difference = max_val - min_val\n \n return difference", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n # Find the maximum and minimum values in the list\n max_val = max(nums)\n min_val = min(nums)\n \n # Calculate the difference between the maximum and minimum values\n return max_val - min_val", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n # Find the maximum and minimum values in the list\n max_val = max(nums)\n min_val = min(nums)\n \n # Calculate the difference between the maximum and minimum values\n difference = max_val - min_val\n \n return difference", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n # Find the maximum and minimum values in the list\n max_val = max(nums)\n min_val = min(nums)\n \n # Calculate the difference between the maximum and minimum values\n difference = max_val - min_val\n \n return difference", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n # Calculate the difference between the maximum and minimum values in the list\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n # Find the maximum value in the list\n max_val = max(nums)\n # Find the minimum value in the list\n min_val = min(nums)\n # Return the difference between the maximum and minimum values\n return max_val - min_val", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n # Find the maximum and minimum values in the list\n max_val = max(nums)\n min_val = min(nums)\n \n # Calculate the difference between the maximum and minimum values\n difference = max_val - min_val\n \n return difference", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n # Calculate the difference between the maximum and minimum values in the list\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n # Find the maximum and minimum values in the list\n max_val = max(nums)\n min_val = min(nums)\n \n # Calculate the difference between the maximum and minimum values\n difference = max_val - min_val\n \n return difference", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n # Calculate the difference between the maximum and minimum values in the list\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n # Find the maximum value in the list\n max_val = max(nums)\n # Find the minimum value in the list\n min_val = min(nums)\n # Calculate the difference between the maximum and minimum values\n return max_val - min_val", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n # Find the maximum and minimum values in the list\n max_val = max(nums)\n min_val = min(nums)\n \n # Calculate the difference between the maximum and minimum values\n difference = max_val - min_val\n \n return difference", "matching_cluster_idx": 5}]}, "Mbpp/592": {"dps": 87.46666666666667, "dps_norm": 59.0, "pass@1": 97.0, "profiled": [{"solution": "import math\ndef sum_Of_product(n):\n # Initialize the sum to 0\n sum_product = 0\n \n # Iterate through the range of n to calculate the sum of products of binomial coefficients\n for k in range(n):\n # Calculate the product of two consecutive binomial coefficients\n product = math.comb(n, k) * math.comb(n, k + 1)\n # Add the product to the sum\n sum_product += product\n \n return sum_product", "matching_cluster_idx": 4}, {"solution": "from math import comb\ndef sum_Of_product(n):\n # Initialize sum to store the result\n sum_result = 0\n \n # Calculate the sum of the product of consecutive binomial coefficients\n for k in range(1, n + 1):\n sum_result += comb(n, k - 1) * comb(n, k)\n \n return sum_result", "matching_cluster_idx": 5}, {"solution": "from math import comb\ndef sum_Of_product(n):\n # Initialize the sum to 0\n total_sum = 0\n \n # Loop through the range from 0 to n-1\n for i in range(n):\n # Calculate the product of two consecutive binomial coefficients\n product = comb(n, i) * comb(n, i + 1)\n # Add the product to the total sum\n total_sum += product\n \n return total_sum", "matching_cluster_idx": 5}, {"solution": "from math import comb\ndef sum_Of_product(n):\n # Initialize the sum to 0\n sum_product = 0\n \n # Loop through all pairs of consecutive binomial coefficients\n for k in range(n + 1):\n # Calculate the product of C(n, k) and C(n, k+1)\n product = comb(n, k) * comb(n, k + 1)\n # Add the product to the sum\n sum_product += product\n \n return sum_product", "matching_cluster_idx": 5}, {"solution": "from math import comb\ndef sum_Of_product(n):\n # Initialize the sum\n total_sum = 0\n \n # Calculate the sum of the product of consecutive binomial coefficients\n for k in range(1, n + 1):\n total_sum += comb(n, k - 1) * comb(n, k)\n \n return total_sum", "matching_cluster_idx": 5}, {"solution": "import math\ndef sum_Of_product(n):\n # Initialize sum to 0\n sum = 0\n \n # Loop through the range of n\n for k in range(n):\n # Calculate the product of consecutive binomial coefficients\n product = math.comb(n, k) * math.comb(n, k + 1)\n # Add the product to the sum\n sum += product\n \n return sum", "matching_cluster_idx": 5}, {"solution": "from math import comb\ndef sum_Of_product(n):\n # Initialize sum to 0\n sum = 0\n \n # Loop through the range of n to calculate the sum of the product of consecutive binomial coefficients\n for k in range(n):\n sum += comb(n, k) * comb(n, k + 1)\n \n return sum", "matching_cluster_idx": 5}, {"solution": "from math import comb\ndef sum_Of_product(n):\n # Initialize sum to store the result\n total_sum = 0\n \n # Loop through the range to calculate the sum of products of consecutive binomial coefficients\n for k in range(n + 1):\n total_sum += comb(n, k) * comb(n, k + 1)\n \n return total_sum", "matching_cluster_idx": 5}, {"solution": "import math\ndef sum_Of_product(n):\n # Initialize sum to 0\n sum = 0\n \n # Loop through the range of n + 1\n for k in range(n + 1):\n # Calculate the product of consecutive binomial coefficients\n product = math.comb(n, k) * math.comb(n, k + 1)\n # Add the product to the sum\n sum += product\n \n return sum", "matching_cluster_idx": 5}, {"solution": "from math import comb\ndef sum_Of_product(n):\n # Initialize the sum to 0\n sum_product = 0\n \n # Iterate through the range of n to calculate the sum of products of consecutive binomial coefficients\n for k in range(n):\n sum_product += comb(n, k) * comb(n, k + 1)\n \n return sum_product", "matching_cluster_idx": 5}, {"solution": "from math import comb\ndef sum_Of_product(n):\n # Initialize the sum\n total_sum = 0\n \n # Calculate the sum of the product of consecutive binomial coefficients\n for k in range(n):\n total_sum += comb(n, k) * comb(n, k + 1)\n \n return total_sum", "matching_cluster_idx": 5}, {"solution": "from math import comb\ndef sum_Of_product(n):\n # Initialize sum to 0\n total_sum = 0\n \n # Iterate through the range from 0 to n (inclusive)\n for k in range(n + 1):\n # Calculate the product of consecutive binomial coefficients\n product = comb(n, k) * comb(n, k + 1)\n # Add the product to the total sum\n total_sum += product\n \n return total_sum", "matching_cluster_idx": 5}, {"solution": "from math import comb\ndef sum_Of_product(n):\n # Initialize the sum to 0\n total_sum = 0\n \n # Loop through the range of n + 1 to calculate the sum of the product of consecutive binomial coefficients\n for i in range(n + 1):\n total_sum += comb(n, i) * comb(n, i + 1)\n \n return total_sum", "matching_cluster_idx": 5}, {"solution": "from math import comb\ndef sum_Of_product(n):\n # Initialize the sum to 0\n sum_product = 0\n \n # Iterate through the range of n to calculate the sum of the product of consecutive binomial coefficients\n for k in range(n):\n sum_product += comb(n, k) * comb(n, k + 1)\n \n return sum_product", "matching_cluster_idx": 5}, {"solution": "from math import comb\ndef sum_Of_product(n):\n # Initialize the sum to 0\n sum_product = 0\n \n # Calculate the sum of the product of consecutive binomial coefficients\n for k in range(n):\n sum_product += comb(n, k) * comb(n, k + 1)\n \n return sum_product", "matching_cluster_idx": 5}, {"solution": "from math import comb\ndef sum_Of_product(n):\n # Initialize the sum to 0\n total_sum = 0\n \n # Loop through each k from 0 to n-1\n for k in range(n):\n # Calculate the product of binomial coefficients C(n, k) * C(n, k+1)\n product = comb(n, k) * comb(n, k + 1)\n # Add the product to the total sum\n total_sum += product\n \n return total_sum", "matching_cluster_idx": 5}, {"solution": "from math import comb\ndef sum_Of_product(n):\n # Initialize the sum to 0\n total_sum = 0\n \n # Iterate through the range 0 to n\n for k in range(n + 1):\n # Calculate the product of binomial coefficients C(n, k) * C(n, k+1)\n product = comb(n, k) * comb(n, k + 1)\n # Add the product to the total sum\n total_sum += product\n \n return total_sum", "matching_cluster_idx": 5}, {"solution": "from math import comb\ndef sum_Of_product(n):\n # Initialize sum to 0\n sum_product = 0\n \n # Iterate through the range of n+1 to include all terms\n for k in range(n + 1):\n # Calculate the product of consecutive binomial coefficients\n product = comb(n, k) * comb(n, k + 1)\n # Add the product to the sum\n sum_product += product\n \n return sum_product", "matching_cluster_idx": 5}, {"solution": "from math import comb\ndef sum_Of_product(n):\n # Initialize sum to 0\n total_sum = 0\n \n # Calculate the sum of the product of consecutive binomial coefficients\n for i in range(n + 1):\n total_sum += comb(n, i) * comb(n, i + 1)\n \n return total_sum", "matching_cluster_idx": 4}, {"solution": "from math import comb\ndef sum_Of_product(n):\n # Initialize sum to 0\n total_sum = 0\n \n # Loop through each value from 0 to n\n for k in range(n + 1):\n # Calculate the product of binomial coefficients C(n, k) * C(n, k+1)\n product = comb(n, k) * comb(n, k + 1)\n # Add the product to the total sum\n total_sum += product\n \n return total_sum", "matching_cluster_idx": 5}]}, "Mbpp/597": {"dps": null, "dps_norm": null, "pass@1": 0.0, "profiled": []}, "Mbpp/604": {"dps": 47.5, "dps_norm": 89.0, "pass@1": 100.0, "profiled": [{"solution": "def reverse_words(s):\n # Split the string into words, reverse the list of words, and join them back with a space\n return ' '.join(s.split()[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n # Split the string into words, reverse the list of words, and join them back with a space\n return ' '.join(s.split()[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n # Split the string into words, reverse the list of words, and join them back with a space\n return ' '.join(reversed(s.split()))", "matching_cluster_idx": 3}, {"solution": "def reverse_words(s):\n # Split the string into words, reverse the list of words, and join them back with a space\n return ' '.join(s.split()[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n # Split the string into words, reverse the list of words, and join them back into a string\n return ' '.join(reversed(s.split()))", "matching_cluster_idx": 3}, {"solution": "def reverse_words(s):\n # Split the string into words, reverse the list of words, and join them back into a string\n return ' '.join(s.split()[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n # Split the string into words, reverse the list of words, and join them back with a space\n return ' '.join(reversed(s.split()))", "matching_cluster_idx": 3}, {"solution": "def reverse_words(s):\n # Split the string into words, reverse the list of words, and join them back into a string\n return ' '.join(s.split()[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n # Split the string into words, reverse the list of words, and join them back with a space\n return ' '.join(s.split()[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n # Split the string into words\n words = s.split()\n # Reverse the list of words\n reversed_words = words[::-1]\n # Join the reversed list of words back into a string\n reversed_string = ' '.join(reversed_words)\n return reversed_string", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n # Split the string into words, reverse the list of words, and join them back into a string\n return ' '.join(reversed(s.split()))", "matching_cluster_idx": 3}, {"solution": "def reverse_words(s):\n # Split the string into words, reverse the list of words, and join them back into a string\n return ' '.join(reversed(s.split()))", "matching_cluster_idx": 3}, {"solution": "def reverse_words(s):\n # Split the string into words, then reverse the list of words and join them back into a string\n return ' '.join(reversed(s.split()))", "matching_cluster_idx": 3}, {"solution": "def reverse_words(s):\n # Split the string into words, reverse the list of words, and join them back with a space\n return ' '.join(s.split()[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n # Split the string into words, reverse the list of words, and join them back into a single string\n return ' '.join(reversed(s.split()))", "matching_cluster_idx": 3}, {"solution": "def reverse_words(s):\n # Split the string into words, reverse the list of words, and join them back into a string\n return ' '.join(reversed(s.split()))", "matching_cluster_idx": 3}, {"solution": "def reverse_words(s):\n # Split the string into words, reverse the list of words, and join them back into a string\n return ' '.join(reversed(s.split()))", "matching_cluster_idx": 3}, {"solution": "def reverse_words(s):\n # Split the string into words, then reverse the list of words and join them back into a string\n return ' '.join(reversed(s.split()))", "matching_cluster_idx": 3}, {"solution": "def reverse_words(s):\n # Split the string into words, reverse the list of words, and join them back with a space\n return ' '.join(s.split()[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n # Split the string into words, reverse the list of words, and join them back with a space\n return ' '.join(reversed(s.split()))", "matching_cluster_idx": 3}]}, "Mbpp/610": {"dps": null, "dps_norm": null, "pass@1": 0.0, "profiled": []}, "Mbpp/611": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def max_of_nth(matrix, n):\n # Extract the n'th column from the matrix\n column = [row[n] for row in matrix]\n # Return the maximum value from the extracted column\n return max(column)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n # Extract the n-th column from the matrix\n column = [row[n] for row in matrix]\n # Find the maximum value in the n-th column\n max_value = max(column)\n return max_value", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n # Extract the n'th column from the matrix\n column = [row[n] for row in matrix]\n # Find and return the maximum value in the n'th column\n return max(column)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n # Extract the n'th column from the matrix\n column = [row[n] for row in matrix]\n # Return the maximum value from the extracted column\n return max(column)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n # Extract the n'th column from the matrix\n column = [row[n] for row in matrix]\n # Return the maximum value in the n'th column\n return max(column)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n # Extract the n'th column by iterating over each row and selecting the n'th element\n column = [row[n] for row in matrix]\n # Return the maximum value from the extracted column\n return max(column)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n # Extract the n-th column from the matrix\n column = [row[n] for row in matrix]\n # Return the maximum value from the extracted column\n return max(column)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n # Extract the n'th column from the matrix\n column = [row[n] for row in matrix]\n # Find and return the maximum value in the column\n return max(column)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n # Extract the n-th column from the matrix\n column = [row[n] for row in matrix]\n # Return the maximum value from the extracted column\n return max(column)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n # Extract the n'th column from the matrix\n column = [row[n] for row in matrix]\n # Find and return the maximum value in the extracted column\n return max(column)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n # Extract the n'th column from the matrix\n column = [row[n] for row in matrix]\n # Find and return the maximum value in the extracted column\n return max(column)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n # Extract the n'th column from the matrix\n column = [row[n] for row in matrix]\n # Find and return the maximum value in the extracted column\n return max(column)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n # Extract the n'th column from the matrix\n column = [row[n] for row in matrix]\n # Return the maximum value from the extracted column\n return max(column)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n # Extract the n'th column from the matrix\n column = [row[n] for row in matrix]\n # Return the maximum value from the column\n return max(column)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n # Extract the n'th column from the matrix\n column = [row[n] for row in matrix]\n # Find and return the maximum value in the n'th column\n return max(column)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n # Extract the n'th column from the matrix\n column = [row[n] for row in matrix]\n \n # Return the maximum value in the extracted column\n return max(column)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n # Extract the n'th column from the matrix\n column = [row[n] for row in matrix]\n # Return the maximum value from the extracted column\n return max(column)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n # Extract the n-th column from the matrix\n column = [row[n] for row in matrix]\n # Find the maximum value in the extracted column\n return max(column)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n # Extract the n-th column from the matrix\n column = [row[n] for row in matrix]\n # Find the maximum value in the extracted column\n max_value = max(column)\n return max_value", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n # Extract the n'th column from the matrix\n column = [row[n] for row in matrix]\n # Return the maximum value from the extracted column\n return max(column)", "matching_cluster_idx": 5}]}, "Mbpp/631": {"dps": null, "dps_norm": null, "pass@1": 9.0, "profiled": []}, "Mbpp/632": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 99.0, "profiled": [{"solution": "def move_zero(nums):\n # Initialize a list to hold the non-zero elements\n non_zero = [num for num in nums if num != 0]\n # Append zeros to the end of the non_zero list\n non_zero.extend([0] * (len(nums) - len(non_zero)))\n return non_zero", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n # Initialize a list to store non-zero elements\n non_zeros = [num for num in nums if num != 0]\n # Append zeros to the end of the list\n non_zeros.extend([0] * (len(nums) - len(non_zeros)))\n return non_zeros", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n # Initialize a list to store non-zero elements\n non_zero = [num for num in nums if num != 0]\n # Append zeros to the end of the non-zero list\n non_zero.extend([0] * (len(nums) - len(non_zero)))\n return non_zero", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n # List comprehension to filter out non-zero elements\n non_zero = [num for num in nums if num != 0]\n # Append zeros to the end of the list\n non_zero.extend([0] * (len(nums) - len(non_zero)))\n return non_zero", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n # Initialize a list to store non-zero elements\n non_zero = [num for num in nums if num != 0]\n # Append zeroes to the end of the non-zero list\n non_zero.extend([0] * (len(nums) - len(non_zero)))\n return non_zero", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n # Initialize a list to hold the non-zero elements\n non_zero = [num for num in nums if num != 0]\n # Append zeroes to the end of the list\n non_zero.extend([0] * (len(nums) - len(non_zero)))\n return non_zero", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n # Initialize a list to keep non-zero elements\n non_zero = [num for num in nums if num != 0]\n # Append zeros to the end of the non_zero list\n non_zero.extend([0] * (len(nums) - len(non_zero)))\n return non_zero", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n # Initialize a list to store non-zero elements\n non_zero = [num for num in nums if num != 0]\n # Append zeros to the end of the non-zero list\n non_zero.extend([0] * (len(nums) - len(non_zero)))\n return non_zero", "matching_cluster_idx": 6}, {"solution": "def move_zero(lst):\n # Initialize pointers for the current position and the position to place the next non-zero element\n current_pos = 0\n non_zero_pos = 0\n \n # Iterate through the list\n while current_pos < len(lst):\n # If the current element is not zero, move it to the non_zero_pos and increment non_zero_pos\n if lst[current_pos] != 0:\n lst[non_zero_pos] = lst[current_pos]\n non_zero_pos += 1\n current_pos += 1\n \n # Fill the remaining positions with zeros\n while non_zero_pos < len(lst):\n lst[non_zero_pos] = 0\n non_zero_pos += 1\n \n return lst", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n # Initialize a new list to store non-zero elements\n non_zero = [num for num in nums if num != 0]\n # Append zeros to the end of the list\n non_zero.extend([0] * (len(nums) - len(non_zero)))\n return non_zero", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n # Initialize a list to store non-zero elements\n non_zero = [num for num in nums if num != 0]\n # Append zeroes to the end of the non-zero list\n non_zero.extend([0] * (len(nums) - len(non_zero)))\n return non_zero", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n # Initialize a list to store non-zero elements\n non_zeros = [num for num in nums if num != 0]\n # Append zeros to the end of the non_zeros list\n non_zeros.extend([0] * (len(nums) - len(non_zeros)))\n return non_zeros", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n # Initialize a list to store non-zero elements\n non_zero = [num for num in nums if num != 0]\n # Append zeroes to the end of the non_zero list\n non_zero.extend([0] * (len(nums) - len(non_zero)))\n return non_zero", "matching_cluster_idx": 6}, {"solution": "def move_zero(lst):\n # Initialize pointers for reading and writing\n read_index = 0\n write_index = 0\n \n # Move all non-zero elements to the front of the list\n while read_index < len(lst):\n if lst[read_index] != 0:\n lst[write_index] = lst[read_index]\n write_index += 1\n read_index += 1\n \n # Fill the rest of the list with zeroes\n while write_index < len(lst):\n lst[write_index] = 0\n write_index += 1\n \n return lst", "matching_cluster_idx": 6}, {"solution": "def move_zero(lst):\n # Initialize a list to store the non-zero elements\n non_zero = [x for x in lst if x != 0]\n # Calculate the number of zeros in the original list\n num_zeros = lst.count(0)\n # Extend the non-zero list with the zeros\n non_zero.extend([0] * num_zeros)\n return non_zero", "matching_cluster_idx": 6}, {"solution": "def move_zero(lst):\n # Initialize a new list to store non-zero elements\n non_zero = [x for x in lst if x != 0]\n # Append the required number of zeros to the end of the non-zero list\n non_zero.extend([0] * (len(lst) - len(non_zero)))\n return non_zero", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n # Initialize a list to store non-zero elements\n non_zero = [num for num in nums if num != 0]\n # Append zeroes to the end of the non_zero list\n non_zero.extend([0] * (len(nums) - len(non_zero)))\n return non_zero", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n # Initialize a list to keep non-zero elements\n non_zero = [num for num in nums if num != 0]\n # Append zeroes to the end of the list\n non_zero.extend([0] * (len(nums) - len(non_zero)))\n return non_zero", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n # Initialize a list to keep non-zero elements\n non_zeros = [num for num in nums if num != 0]\n # Append zeros to the end of the list\n non_zeros.extend([0] * (len(nums) - len(non_zeros)))\n return non_zeros", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n # Initialize a list to store non-zero elements\n non_zero = [num for num in nums if num != 0]\n # Append the required number of zeroes to the end of the list\n non_zero.extend([0] * (len(nums) - len(non_zero)))\n return non_zero", "matching_cluster_idx": 6}]}, "Mbpp/633": {"dps": 94.3089430894309, "dps_norm": 50.0, "pass@1": 100.0, "profiled": [{"solution": "def pair_xor_Sum(arr, n):\n # Initialize the sum of XORs to 0\n xor_sum = 0\n \n # Iterate through each pair of elements in the array\n for i in range(n):\n for j in range(i + 1, n):\n # Compute the XOR of the pair and add it to the sum\n xor_sum += arr[i] ^ arr[j]\n \n return xor_sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(arr, n):\n # Initialize sum to 0\n xor_sum = 0\n \n # Iterate through each pair of elements in the array\n for i in range(n):\n for j in range(i + 1, n):\n # Compute the XOR of the pair and add it to the sum\n xor_sum += arr[i] ^ arr[j]\n \n return xor_sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(arr, n):\n # Initialize the sum to 0\n xor_sum = 0\n \n # Iterate through each pair of elements in the array\n for i in range(n):\n for j in range(i + 1, n):\n # Compute the XOR of the pair and add it to the sum\n xor_sum += arr[i] ^ arr[j]\n \n return xor_sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(arr, n):\n # Initialize sum to 0\n xor_sum = 0\n \n # Iterate through each pair of elements in the array\n for i in range(n):\n for j in range(i + 1, n):\n # Compute the XOR of the pair and add it to the sum\n xor_sum += arr[i] ^ arr[j]\n \n return xor_sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(arr, n):\n # Initialize the result variable to store the sum of XOR of all pairs\n result = 0\n \n # Iterate through each element in the array\n for i in range(n):\n # For each element, iterate through the rest of the elements\n for j in range(i + 1, n):\n # Compute the XOR of the pair and add it to the result\n result += arr[i] ^ arr[j]\n \n return result", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(arr, n):\n # Initialize sum to 0\n xor_sum = 0\n \n # Iterate through each pair of elements in the array\n for i in range(n):\n for j in range(i + 1, n):\n # Calculate XOR of the pair and add it to the sum\n xor_sum += arr[i] ^ arr[j]\n \n return xor_sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(arr, n):\n # Initialize the result to store the sum of XOR values\n result = 0\n \n # Iterate through each pair of elements in the array\n for i in range(n):\n for j in range(i + 1, n):\n # Calculate the XOR of the pair and add it to the result\n result += arr[i] ^ arr[j]\n \n return result", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(arr, n):\n # Initialize the sum to 0\n xor_sum = 0\n \n # Iterate through each pair of elements in the array\n for i in range(n):\n for j in range(i + 1, n):\n # Compute the XOR of the pair and add it to the sum\n xor_sum += arr[i] ^ arr[j]\n \n return xor_sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(arr, n):\n # Initialize the sum to 0\n xor_sum = 0\n \n # Iterate through each pair of elements in the list\n for i in range(n):\n for j in range(i + 1, n):\n # Compute the XOR of the pair and add it to the sum\n xor_sum += arr[i] ^ arr[j]\n \n return xor_sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(arr, n):\n # Initialize sum to 0\n xor_sum = 0\n \n # Iterate through each pair of elements in the array\n for i in range(n):\n for j in range(i + 1, n):\n # Compute the XOR of the pair and add it to the sum\n xor_sum += arr[i] ^ arr[j]\n \n return xor_sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(arr, n):\n # Initialize sum to 0\n xor_sum = 0\n \n # Iterate through each pair of elements in the array\n for i in range(n):\n for j in range(i + 1, n):\n # Compute XOR of the pair and add to the sum\n xor_sum += arr[i] ^ arr[j]\n \n return xor_sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(arr, n):\n # Initialize the sum to 0\n xor_sum = 0\n \n # Iterate through each pair of elements in the array\n for i in range(n):\n for j in range(i + 1, n):\n # Compute the XOR of the pair and add it to the sum\n xor_sum += arr[i] ^ arr[j]\n \n return xor_sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(arr, n):\n # Initialize the result variable to store the sum of XORs\n xor_sum = 0\n \n # Iterate through each pair of elements in the array\n for i in range(n):\n for j in range(i + 1, n):\n # Compute the XOR of the pair and add it to the result\n xor_sum += arr[i] ^ arr[j]\n \n return xor_sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(arr, n):\n # Initialize the sum to 0\n xor_sum = 0\n \n # Iterate through each pair of elements in the array\n for i in range(n):\n for j in range(i + 1, n):\n # Compute the XOR of the pair and add it to the sum\n xor_sum += arr[i] ^ arr[j]\n \n return xor_sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(arr, n):\n # Initialize sum to 0\n xor_sum = 0\n \n # Iterate through each pair of elements in the list\n for i in range(n):\n for j in range(i + 1, n):\n # Calculate the XOR of the pair and add it to the sum\n xor_sum += arr[i] ^ arr[j]\n \n return xor_sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(arr, n):\n # Initialize the sum of XORs to 0\n xor_sum = 0\n \n # Iterate through each pair of elements in the array\n for i in range(n):\n for j in range(i + 1, n):\n # Compute the XOR of the pair and add it to the sum\n xor_sum += arr[i] ^ arr[j]\n \n # Return the total sum of XORs\n return xor_sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(arr, n):\n # Initialize the sum to 0\n xor_sum = 0\n \n # Iterate through each pair of elements in the array\n for i in range(n):\n for j in range(i + 1, n):\n # Compute the XOR of the pair and add it to the sum\n xor_sum += arr[i] ^ arr[j]\n \n return xor_sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(arr, n):\n # Initialize the sum of XORs to 0\n xor_sum = 0\n \n # Iterate through each pair of elements in the array\n for i in range(n):\n for j in range(i + 1, n):\n # Compute the XOR of the pair and add it to the sum\n xor_sum += arr[i] ^ arr[j]\n \n # Return the total sum of XORs\n return xor_sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(arr, n):\n # Initialize the result variable to store the sum of XOR values\n result = 0\n \n # Iterate through each element in the array\n for i in range(0, n):\n # For each element, iterate through the remaining elements\n for j in range(i + 1, n):\n # Compute the XOR of the pair and add it to the result\n result += arr[i] ^ arr[j]\n \n # Return the final result\n return result", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(arr, n):\n # Initialize sum to 0\n xor_sum = 0\n \n # Iterate through each pair of elements in the array\n for i in range(n):\n for j in range(i + 1, n):\n # Compute the XOR of the pair and add it to the sum\n xor_sum += arr[i] ^ arr[j]\n \n return xor_sum", "matching_cluster_idx": 2}]}, "Mbpp/644": {"dps": 96.27659574468083, "dps_norm": 93.33333333333333, "pass@1": 93.0, "profiled": [{"solution": "def reverse_Array_Upto_K(arr, k):\n # Reverse the portion of the array from the start up to index k (inclusive)\n arr[:k] = arr[:k][::-1]\n return arr", "matching_cluster_idx": 13}, {"solution": "def reverse_Array_Upto_K(arr, k):\n # Reverse the elements of the array from index 0 to index k-1\n arr[:k] = arr[:k][::-1]\n return arr", "matching_cluster_idx": 13}, {"solution": "def reverse_Array_Upto_K(arr, k):\n # Reverse the array from the start up to the k-th position\n arr[:k] = arr[:k][::-1]\n return arr", "matching_cluster_idx": 13}, {"solution": "def reverse_Array_Upto_K(arr, k):\n # Reverse the subarray from index 0 to index k-1\n arr[:k] = arr[:k][::-1]\n return arr", "matching_cluster_idx": 13}, {"solution": "def reverse_Array_Upto_K(arr, k):\n # Reverse the elements of the array from index 0 to index k-1\n arr[:k] = arr[:k][::-1]\n return arr", "matching_cluster_idx": 13}, {"solution": "def reverse_Array_Upto_K(arr, k):\n # Reverse the elements of the array up to the k-th position\n arr[:k] = arr[:k][::-1]\n return arr", "matching_cluster_idx": 13}, {"solution": "def reverse_Array_Upto_K(arr, k):\n # Reverse the portion of the array from index 0 to index k-1\n arr[:k] = arr[:k][::-1]\n return arr", "matching_cluster_idx": 13}, {"solution": "def reverse_Array_Upto_K(arr, k):\n # Reverse the elements of the array from index 0 to k-1\n arr[:k] = arr[:k][::-1]\n return arr", "matching_cluster_idx": 13}, {"solution": "def reverse_Array_Upto_K(arr, k):\n # Reverse the elements of the array up to index k\n arr[:k] = arr[:k][::-1]\n return arr", "matching_cluster_idx": 13}, {"solution": "def reverse_Array_Upto_K(arr, k):\n # Reverse the sub-array from index 0 to k-1\n arr[:k] = arr[:k][::-1]\n return arr", "matching_cluster_idx": 13}, {"solution": "def reverse_Array_Upto_K(arr, k):\n # Reverse the sub-array from the start to the k-th position\n arr[:k] = arr[:k][::-1]\n return arr", "matching_cluster_idx": 13}, {"solution": "def reverse_Array_Upto_K(arr, k):\n # Reverse the portion of the array from the start up to index k-1\n arr[:k] = arr[:k][::-1]\n return arr", "matching_cluster_idx": 13}, {"solution": "def reverse_Array_Upto_K(arr, k):\n # Reverse the sub-array from the start to the k-th position\n arr[:k] = arr[:k][::-1]\n return arr", "matching_cluster_idx": 13}, {"solution": "def reverse_Array_Upto_K(arr, k):\n # Reverse the subarray from the start to the k-th position\n arr[:k] = arr[:k][::-1]\n return arr", "matching_cluster_idx": 13}, {"solution": "def reverse_Array_Upto_K(arr, k):\n # Reverse the first k elements of the array\n arr[:k] = arr[:k][::-1]\n return arr", "matching_cluster_idx": 13}, {"solution": "def reverse_Array_Upto_K(arr, k):\n # Reverse the elements of the array from index 0 to index k-1\n arr[:k] = arr[:k][::-1]\n return arr", "matching_cluster_idx": 13}, {"solution": "def reverse_Array_Upto_K(arr, k):\n # Reverse the sub-array from index 0 to k-1\n arr[:k] = arr[:k][::-1]\n return arr", "matching_cluster_idx": 13}, {"solution": "def reverse_Array_Upto_K(arr, k):\n # Reverse the portion of the array from the start to index k-1\n arr[:k] = arr[:k][::-1]\n return arr", "matching_cluster_idx": 13}, {"solution": "def reverse_Array_Upto_K(arr, k):\n # Reverse the first k elements of the array\n arr[:k] = arr[:k][::-1]\n return arr", "matching_cluster_idx": 13}, {"solution": "def reverse_Array_Upto_K(arr, k):\n # Reverse the sub-array from index 0 to k\n arr[:k] = arr[:k][::-1]\n return arr", "matching_cluster_idx": 13}]}, "Mbpp/720": {"dps": 93.84615384615384, "dps_norm": 98.0, "pass@1": 100.0, "profiled": [{"solution": "def add_dict_to_tuple(tup, dictionary):\n # Create a new tuple by combining the original tuple and the dictionary\n result = tup + (dictionary,)\n return result", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(tup, dictionary):\n # Create a new tuple by concatenating the original tuple with a tuple containing the dictionary\n return tup + (dictionary,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(test_tup, test_dict):\n # Convert the tuple to a list, append the dictionary, and convert it back to a tuple\n res = test_tup + (test_dict,)\n return res", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(tup, dictionary):\n # Create a new tuple by combining the existing tuple and the dictionary\n new_tup = tup + (dictionary,)\n return new_tup", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(tup, dictionary):\n # Create a new tuple by adding the dictionary to the existing tuple\n new_tuple = tup + (dictionary,)\n return new_tuple", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(tup, dictionary):\n # Create a new tuple by adding the dictionary to the existing tuple\n result = tup + (dictionary,)\n return result", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(tup, dictionary):\n # Create a new tuple by concatenating the original tuple and the dictionary\n # The dictionary is converted to a tuple containing a single element (the dictionary itself)\n result = tup + (dictionary,)\n return result", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(tup, dictionary):\n # Create a new tuple by combining the original tuple and the dictionary\n new_tup = tup + (dictionary,)\n return new_tup", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(tup, dictionary):\n # Create a new tuple by adding the dictionary to the end of the existing tuple\n new_tup = tup + (dictionary,)\n return new_tup", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(tup, dictionary):\n # Create a new tuple by adding the dictionary to the existing tuple\n new_tup = tup + (dictionary,)\n return new_tup", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(tup, dictionary):\n # Convert the tuple to a list to add the dictionary\n temp_list = list(tup)\n temp_list.append(dictionary)\n # Convert the list back to a tuple\n return tuple(temp_list)", "matching_cluster_idx": 3}, {"solution": "def add_dict_to_tuple(tup, dictionary):\n # Create a new tuple by combining the existing tuple and the dictionary\n result = tup + (dictionary,)\n return result", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(tup, dictionary):\n # Create a new tuple by combining the original tuple and the dictionary\n result = tup + (dictionary,)\n return result", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(test_tup, test_dict):\n # Add the dictionary to the tuple\n res = test_tup + (test_dict,)\n return res", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(test_tup, test_dict):\n # Adds the dictionary to the tuple\n res = test_tup + (test_dict,)\n return res", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(tup, dictionary):\n # Create a new tuple by adding the dictionary to the existing tuple\n new_tup = tup + (dictionary,)\n return new_tup", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(tup, dictionary):\n # Add the dictionary to the end of the tuple and return the new tuple\n return tup + (dictionary,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(tup, dictionary):\n # Create a new tuple by concatenating the original tuple with a tuple containing the dictionary\n return tup + (dictionary,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(tup, dictionary):\n # Create a new tuple by adding the dictionary to the existing tuple\n result = tup + (dictionary,)\n return result", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(tup, dictionary):\n # Convert the tuple to a list to allow modification\n temp_list = list(tup)\n \n # Append the dictionary to the list\n temp_list.append(dictionary)\n \n # Convert the list back to a tuple\n result_tuple = tuple(temp_list)\n \n return result_tuple", "matching_cluster_idx": 3}]}, "Mbpp/725": {"dps": 62.73224043715847, "dps_norm": 70.0, "pass@1": 100.0, "profiled": [{"solution": "import re\ndef extract_quotation(s):\n # Use regular expression to find all substrings within double quotes\n return re.findall(r'\"(.*?)\"', s)", "matching_cluster_idx": 4}, {"solution": "import re\ndef extract_quotation(s):\n # Use regular expression to find all substrings enclosed in double quotes\n matches = re.findall(r'\"(.*?)\"', s)\n return matches", "matching_cluster_idx": 4}, {"solution": "import re\ndef extract_quotation(s):\n # Use regular expression to find all substrings enclosed in double quotes\n matches = re.findall(r'\"(.*?)\"', s)\n return matches", "matching_cluster_idx": 4}, {"solution": "import re\ndef extract_quotation(s):\n # Use regular expression to find all substrings between double quotes\n matches = re.findall(r'\"(.*?)\"', s)\n return matches", "matching_cluster_idx": 4}, {"solution": "import re\ndef extract_quotation(s):\n # Use regular expression to find all substrings enclosed in double quotes\n return re.findall(r'\"(.*?)\"', s)", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(s):\n # Use regular expression to find all substrings between double quotes\n return re.findall(r'\"(.*?)\"', s)", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(s):\n # Using regular expression to find all substrings between double quotes\n return re.findall(r'\"(.*?)\"', s)", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(s):\n # Use regular expression to find all substrings enclosed in double quotes\n matches = re.findall(r'\"(.*?)\"', s)\n return matches", "matching_cluster_idx": 4}, {"solution": "import re\ndef extract_quotation(s):\n # Use regular expression to find all substrings enclosed in double quotes\n return re.findall(r'\"(.*?)\"', s)", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(s):\n # Use regular expression to find all substrings enclosed in double quotes\n return re.findall(r'\"(.*?)\"', s)", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(text):\n # Use regular expression to find all substrings enclosed in double quotes\n matches = re.findall(r'\"(.*?)\"', text)\n return matches", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(s):\n # Use regular expression to find all substrings enclosed in double quotes\n return re.findall(r'\"(.*?)\"', s)", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(s):\n # Use regular expression to find all substrings within double quotes\n return re.findall(r'\"(.*?)\"', s)", "matching_cluster_idx": 4}, {"solution": "import re\ndef extract_quotation(s):\n # Use regular expression to find all substrings enclosed in double quotes\n matches = re.findall(r'\"(.*?)\"', s)\n return matches", "matching_cluster_idx": 4}, {"solution": "import re\ndef extract_quotation(s):\n # Use regular expression to find all substrings enclosed in double quotes\n return re.findall(r'\"(.*?)\"', s)", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(s):\n # Use regular expression to find all substrings between double quotes\n return re.findall(r'\"(.*?)\"', s)", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(s):\n # Use regular expression to find all substrings enclosed in double quotes\n matches = re.findall(r'\"(.*?)\"', s)\n return matches", "matching_cluster_idx": 4}, {"solution": "import re\ndef extract_quotation(s):\n # Using regular expression to find all substrings between double quotes\n matches = re.findall(r'\"(.*?)\"', s)\n return matches", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(s):\n # Use regular expression to find all substrings enclosed in double quotes\n return re.findall(r'\"(.*?)\"', s)", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(text):\n # Use regular expression to find all substrings enclosed in double quotes\n matches = re.findall(r'\"(.*?)\"', text)\n return matches", "matching_cluster_idx": 5}]}, "Mbpp/732": {"dps": 5.813953488372094, "dps_norm": 40.0, "pass@1": 89.0, "profiled": [{"solution": "import re\ndef replace_specialchar(text):\n # Use regular expression to replace spaces, commas, or dots with a colon\n return re.sub(r'[ ,.]', ':', text)", "matching_cluster_idx": 3}, {"solution": "import re\ndef replace_specialchar(text):\n # Use regular expression to replace spaces, commas, or dots with a colon\n return re.sub(r'[ ,.]', ':', text)", "matching_cluster_idx": 3}, {"solution": "import re\ndef replace_specialchar(text):\n # Replace spaces, commas, or dots with a colon\n result = re.sub(r'[ ,.]', ':', text)\n return result", "matching_cluster_idx": 3}, {"solution": "import re\ndef replace_specialchar(text):\n # Use regular expression to replace spaces, commas, or dots with colons\n return re.sub(r'[ ,.]', ':', text)", "matching_cluster_idx": 3}, {"solution": "import re\ndef replace_specialchar(text):\n # Use re.sub to replace spaces, commas, or dots with a colon\n modified_text = re.sub(r'[ ,.]', ':', text)\n return modified_text", "matching_cluster_idx": 3}, {"solution": "import re\ndef replace_specialchar(text):\n # Replace all occurrences of spaces, commas, or dots with a colon\n return re.sub(r'[ ,.]', ':', text)", "matching_cluster_idx": 3}, {"solution": "import re\ndef replace_specialchar(text):\n # Use re.sub to replace spaces, commas, or dots with a colon\n result = re.sub(r'[ ,.]', ':', text)\n return result", "matching_cluster_idx": 3}, {"solution": "import re\ndef replace_specialchar(text):\n # Use the re.sub() function to replace all occurrences of spaces, commas, or dots with a colon\n result = re.sub(r'[ ,.]', ':', text)\n return result", "matching_cluster_idx": 3}, {"solution": "import re\ndef replace_specialchar(text):\n # Use regular expression to replace spaces, commas, or dots with a colon\n return re.sub(r'[ ,.]', ':', text)", "matching_cluster_idx": 3}, {"solution": "import re\ndef replace_specialchar(text):\n # Use regular expression to replace spaces, commas, or dots with a colon\n return re.sub(r'[ ,.]', ':', text)", "matching_cluster_idx": 3}, {"solution": "import re\ndef replace_specialchar(text):\n # Use the re.sub function to replace spaces, commas, or dots with colons\n return re.sub(r'[ ,.]', ':', text)", "matching_cluster_idx": 3}, {"solution": "import re\ndef replace_specialchar(text):\n # Use regular expression to replace spaces, commas, or dots with a colon\n modified_text = re.sub(r'[ ,.]', ':', text)\n return modified_text", "matching_cluster_idx": 3}, {"solution": "import re\ndef replace_specialchar(text):\n # Replace all occurrences of spaces, commas, or dots with a colon\n result = re.sub(r'[ ,.]', ':', text)\n return result", "matching_cluster_idx": 3}, {"solution": "import re\ndef replace_specialchar(text):\n # Use regular expression to replace spaces, commas, or dots with a colon\n return re.sub(r'[ ,.]', ':', text)", "matching_cluster_idx": 3}, {"solution": "import re\ndef replace_specialchar(text):\n # Use regular expression to replace spaces, commas, and dots with colons\n return re.sub(r'[ ,.]', ':', text)", "matching_cluster_idx": 3}, {"solution": "import re\ndef replace_specialchar(text):\n # Use regular expression to replace spaces, commas, or dots with a colon\n return re.sub(r'[ ,.]', ':', text)", "matching_cluster_idx": 3}, {"solution": "import re\ndef replace_specialchar(text):\n # Use regular expression to replace spaces, commas, and dots with colons\n return re.sub(r'[ ,.]', ':', text)", "matching_cluster_idx": 3}, {"solution": "import re\ndef replace_specialchar(text):\n # Using regular expression to replace spaces, commas, or dots with colons\n return re.sub(r'[ ,.]', ':', text)", "matching_cluster_idx": 3}, {"solution": "import re\ndef replace_specialchar(text):\n # Use regular expression to replace spaces, commas, or dots with a colon\n return re.sub(r'[ ,.]', ':', text)", "matching_cluster_idx": 3}, {"solution": "import re\ndef replace_specialchar(text):\n # Use regular expression to replace spaces, commas, or dots with a colon\n return re.sub(r'[ ,.]', ':', text)", "matching_cluster_idx": 3}]}, "Mbpp/740": {"dps": 44.163636363636364, "dps_norm": 57.22222222222222, "pass@1": 100.0, "profiled": [{"solution": "def tuple_to_dict(input_tuple):\n # Initialize an empty dictionary to store the key-value pairs\n result_dict = {}\n \n # Iterate over the tuple in steps of 2 to get key-value pairs\n for i in range(0, len(input_tuple), 2):\n # The current element is the key, and the next element is the value\n key = input_tuple[i]\n value = input_tuple[i + 1] if i + 1 < len(input_tuple) else None\n result_dict[key] = value\n \n return result_dict", "matching_cluster_idx": 3}, {"solution": "def tuple_to_dict(input_tuple):\n # Initialize an empty dictionary to store the key-value pairs\n result_dict = {}\n \n # Iterate over the tuple in steps of 2 to get key-value pairs\n for i in range(0, len(input_tuple), 2):\n # The current element is the key, and the next element is the value\n if i + 1 < len(input_tuple):\n result_dict[input_tuple[i]] = input_tuple[i + 1]\n \n return result_dict", "matching_cluster_idx": 3}, {"solution": "def tuple_to_dict(input_tuple):\n # Initialize an empty dictionary to store the key-value pairs\n result_dict = {}\n \n # Iterate over the tuple in steps of 2 to pair elements\n for i in range(0, len(input_tuple), 2):\n # Assign the current element as the key and the next element as the value\n if i + 1 < len(input_tuple):\n result_dict[input_tuple[i]] = input_tuple[i + 1]\n \n return result_dict", "matching_cluster_idx": 3}, {"solution": "def tuple_to_dict(input_tuple):\n # Initialize an empty dictionary to store the key-value pairs\n result_dict = {}\n \n # Iterate over the tuple in steps of 2 to get key-value pairs\n for i in range(0, len(input_tuple), 2):\n # The current element is the key, and the next element is the value\n if i + 1 < len(input_tuple):\n result_dict[input_tuple[i]] = input_tuple[i + 1]\n \n return result_dict", "matching_cluster_idx": 3}, {"solution": "def tuple_to_dict(input_tuple):\n # Initialize an empty dictionary to store the result\n result_dict = {}\n \n # Iterate over the tuple in steps of 2 to get key-value pairs\n for i in range(0, len(input_tuple), 2):\n # Assign the current element as the key and the next element as the value\n if i + 1 < len(input_tuple):\n result_dict[input_tuple[i]] = input_tuple[i + 1]\n \n return result_dict", "matching_cluster_idx": 3}, {"solution": "def tuple_to_dict(input_tuple):\n # Initialize an empty dictionary to store the result\n result_dict = {}\n \n # Iterate over the tuple in steps of 2 to get key-value pairs\n for i in range(0, len(input_tuple), 2):\n # Assign the current element as the key and the next element as the value\n if i + 1 < len(input_tuple):\n result_dict[input_tuple[i]] = input_tuple[i + 1]\n \n return result_dict", "matching_cluster_idx": 3}, {"solution": "def tuple_to_dict(input_tuple):\n # Create an empty dictionary to store the key-value pairs\n result_dict = {}\n \n # Iterate over the tuple in steps of 2 to use each pair of elements as key and value\n for i in range(0, len(input_tuple), 2):\n if i + 1 < len(input_tuple): # Ensure there is a next element to use as value\n result_dict[input_tuple[i]] = input_tuple[i + 1]\n \n return result_dict", "matching_cluster_idx": 3}, {"solution": "def tuple_to_dict(input_tuple):\n # Create an empty dictionary to store the key-value pairs\n result_dict = {}\n \n # Iterate over the tuple in steps of 2 to get key-value pairs\n for i in range(0, len(input_tuple), 2):\n # The key is the current element, and the value is the next element\n if i + 1 < len(input_tuple):\n result_dict[input_tuple[i]] = input_tuple[i + 1]\n \n return result_dict", "matching_cluster_idx": 3}, {"solution": "def tuple_to_dict(input_tuple):\n # Initialize an empty dictionary to store the key-value pairs\n result_dict = {}\n \n # Iterate over the tuple in steps of 2 to get key-value pairs\n for i in range(0, len(input_tuple), 2):\n # Assign the current element as the key and the next element as the value\n if i + 1 < len(input_tuple):\n result_dict[input_tuple[i]] = input_tuple[i + 1]\n \n return result_dict", "matching_cluster_idx": 3}, {"solution": "def tuple_to_dict(test_tup):\n # Create a dictionary by zipping every second element starting from the first as keys\n # and every second element starting from the second as values\n res = dict(zip(test_tup[::2], test_tup[1::2]))\n return res", "matching_cluster_idx": 8}, {"solution": "def tuple_to_dict(tup):\n # Create a dictionary using adjacent elements from the tuple\n return {tup[i]: tup[i + 1] for i in range(0, len(tup) - 1, 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(input_tuple):\n # Create a dictionary by zipping every second element (keys) with the next element (values)\n return dict(zip(input_tuple[::2], input_tuple[1::2]))", "matching_cluster_idx": 8}, {"solution": "def tuple_to_dict(input_tuple):\n # Initialize an empty dictionary to store the result\n result_dict = {}\n \n # Iterate over the tuple in steps of 2 to get key-value pairs\n for i in range(0, len(input_tuple) - 1, 2):\n # Assign the current element as the key and the next element as the value\n result_dict[input_tuple[i]] = input_tuple[i + 1]\n \n return result_dict", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(input_tuple):\n # Initialize an empty dictionary to store the result\n result_dict = {}\n \n # Iterate over the tuple in steps of 2 to get key-value pairs\n for i in range(0, len(input_tuple), 2):\n # Use the current element as the key and the next element as the value\n if i + 1 < len(input_tuple):\n result_dict[input_tuple[i]] = input_tuple[i + 1]\n \n return result_dict", "matching_cluster_idx": 3}, {"solution": "def tuple_to_dict(input_tuple):\n # Create a dictionary from the tuple by pairing adjacent elements\n result_dict = {input_tuple[i]: input_tuple[i + 1] for i in range(0, len(input_tuple), 2)}\n return result_dict", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(input_tuple):\n # Create an empty dictionary to store the result\n result_dict = {}\n \n # Iterate over the tuple in steps of 2 to use every pair of elements as key-value pairs\n for i in range(0, len(input_tuple), 2):\n # Assign the first element of the pair as the key and the second as the value\n result_dict[input_tuple[i]] = input_tuple[i + 1]\n \n return result_dict", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(test_tup):\n # Create a dictionary by iterating over the tuple in steps of 2\n res = dict(test_tup[idx : idx + 2] for idx in range(0, len(test_tup), 2))\n return res", "matching_cluster_idx": 4}, {"solution": "def tuple_to_dict(input_tuple):\n # Create an empty dictionary to store the result\n result_dict = {}\n \n # Iterate over the tuple in steps of 2 to pair adjacent elements\n for i in range(0, len(input_tuple), 2):\n # Assign the key-value pair to the dictionary\n result_dict[input_tuple[i]] = input_tuple[i + 1]\n \n return result_dict", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(input_tuple):\n # Initialize an empty dictionary to store the key-value pairs\n output_dict = {}\n \n # Iterate over the tuple in steps of 2 to get key-value pairs\n for i in range(0, len(input_tuple), 2):\n # The current element is the key\n key = input_tuple[i]\n # The next element is the value, if it exists\n if i + 1 < len(input_tuple):\n value = input_tuple[i + 1]\n else:\n # If there's no next element, the value is None\n value = None\n # Add the key-value pair to the dictionary\n output_dict[key] = value\n \n return output_dict", "matching_cluster_idx": 3}, {"solution": "def tuple_to_dict(input_tuple):\n # Create a dictionary by iterating over the tuple in steps of 2\n # The first element in each pair is the key, and the second is the value\n return {input_tuple[i]: input_tuple[i + 1] for i in range(0, len(input_tuple), 2)}", "matching_cluster_idx": 5}]}, "Mbpp/744": {"dps": 40.99315068493151, "dps_norm": 59.166666666666664, "pass@1": 100.0, "profiled": [{"solution": "def check_none(test_tup):\n # Iterate through each element in the tuple\n for ele in test_tup:\n # Check if the element is None\n if ele == None:\n return True\n # Return False if no None is found\n return False", "matching_cluster_idx": 2}, {"solution": "def check_none(test_tup):\n # Check if any element in the tuple is None\n res = any(ele is None for ele in test_tup)\n return res", "matching_cluster_idx": 1}, {"solution": "def check_none(test_tup):\n # Check if any element in the tuple is None\n res = None in test_tup\n return res", "matching_cluster_idx": 5}, {"solution": "def check_none(test_tup):\n # Check if any element in the tuple is None\n res = any(ele is None for ele in test_tup)\n return res", "matching_cluster_idx": 1}, {"solution": "def check_none(test_tup):\n # Check if any element in the tuple is None\n res = any(ele is None for ele in test_tup)\n return res", "matching_cluster_idx": 1}, {"solution": "def check_none(test_tup):\n # Check if any element in the tuple is None\n res = any(ele is None for ele in test_tup)\n return res", "matching_cluster_idx": 1}, {"solution": "def check_none(test_tup):\n # Check if any element in the tuple is None\n res = None in test_tup\n return res", "matching_cluster_idx": 5}, {"solution": "def check_none(test_tup):\n # Check if any element in the tuple is None\n for elem in test_tup:\n if elem is None:\n return True\n return False", "matching_cluster_idx": 4}, {"solution": "def check_none(test_tup):\n # Iterate through each element in the tuple\n for element in test_tup:\n # Check if the element is None\n if element is None:\n return True\n # Return False if no None is found\n return False", "matching_cluster_idx": 4}, {"solution": "def check_none(test_tup):\n # Check if any element in the tuple is None\n res = any(ele is None for ele in test_tup)\n return res", "matching_cluster_idx": 1}, {"solution": "def check_none(test_tup):\n # Check if any element in the tuple is None\n return any(ele is None for ele in test_tup)", "matching_cluster_idx": 1}, {"solution": "def check_none(test_tup):\n # Iterate through each element in the tuple\n for ele in test_tup:\n # Check if the element is None\n if ele == None:\n return True\n # Return False if no None value is found\n return False", "matching_cluster_idx": 2}, {"solution": "def check_none(test_tup):\n # Check if any element in the tuple is None\n res = any(ele is None for ele in test_tup)\n return res", "matching_cluster_idx": 1}, {"solution": "def check_none(test_tup):\n # Check if any element in the tuple is None\n for elem in test_tup:\n if elem is None:\n return True\n return False", "matching_cluster_idx": 4}, {"solution": "def check_none(test_tuple):\n # Check if any element in the tuple is None\n for element in test_tuple:\n if element is None:\n return True\n return False", "matching_cluster_idx": 4}, {"solution": "def check_none(test_tup):\n # Check if any element in the tuple is None\n return any(ele is None for ele in test_tup)", "matching_cluster_idx": 1}, {"solution": "def check_none(test_tup):\n # Iterate through each element in the tuple\n for elem in test_tup:\n # Check if the element is None\n if elem is None:\n return True\n # Return False if no None value is found\n return False", "matching_cluster_idx": 4}, {"solution": "def check_none(test_tup):\n # Check if any element in the tuple is None\n for element in test_tup:\n if element is None:\n return True\n return False", "matching_cluster_idx": 4}, {"solution": "def check_none(test_tup):\n # Check if any element in the tuple is None\n res = any(ele is None for ele in test_tup)\n return res", "matching_cluster_idx": 1}, {"solution": "def check_none(test_tup):\n # Check if any element in the tuple is None\n for element in test_tup:\n if element is None:\n return True\n return False", "matching_cluster_idx": 4}]}, "Mbpp/750": {"dps": 85.71428571428571, "dps_norm": 85.0, "pass@1": 100.0, "profiled": [{"solution": "def add_tuple(lst, tpl):\n # Extend the list with the elements of the tuple\n return lst + list(tpl)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(lst, tpl):\n # Extend the list by adding elements from the tuple\n lst.extend(tpl)\n return lst", "matching_cluster_idx": 5}, {"solution": "def add_tuple(test_list, test_tup):\n # Extend the list with the elements of the tuple\n test_list.extend(test_tup)\n return test_list", "matching_cluster_idx": 5}, {"solution": "def add_tuple(lst, tpl):\n # Extend the list by adding all elements from the tuple\n lst.extend(tpl)\n return lst", "matching_cluster_idx": 5}, {"solution": "def add_tuple(lst, tpl):\n # Extend the list by adding elements from the tuple\n lst.extend(tpl)\n return lst", "matching_cluster_idx": 5}, {"solution": "def add_tuple(lst, tpl):\n # Extend the list with the elements of the tuple\n lst.extend(tpl)\n return lst", "matching_cluster_idx": 5}, {"solution": "def add_tuple(lst, tpl):\n # Extend the list by adding all elements of the tuple\n return lst + list(tpl)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(lst, tple):\n # Extend the list with the elements of the tuple\n lst.extend(tple)\n return lst", "matching_cluster_idx": 5}, {"solution": "def add_tuple(lst, tpl):\n # Extend the list with the elements of the tuple\n lst.extend(tpl)\n return lst", "matching_cluster_idx": 5}, {"solution": "def add_tuple(lst, tpl):\n # Extend the list by adding elements from the tuple\n return lst + list(tpl)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(lst, t):\n # Extend the list with the elements of the tuple\n lst.extend(t)\n return lst", "matching_cluster_idx": 5}, {"solution": "def add_tuple(lst, tpl):\n # Extend the list by adding all elements from the tuple\n return lst + list(tpl)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(test_list, test_tup):\n # Extend the list with the elements of the tuple\n test_list.extend(test_tup)\n return test_list", "matching_cluster_idx": 5}, {"solution": "def add_tuple(lst, tpl):\n # Extend the list with elements from the tuple\n lst.extend(tpl)\n return lst", "matching_cluster_idx": 5}, {"solution": "def add_tuple(lst, tpl):\n # Extend the list by adding elements from the tuple\n lst.extend(tpl)\n return lst", "matching_cluster_idx": 5}, {"solution": "def add_tuple(lst, tpl):\n # Extend the list by adding all elements from the tuple\n lst.extend(tpl)\n return lst", "matching_cluster_idx": 5}, {"solution": "def add_tuple(lst, tpl):\n # Extend the list by adding all elements from the tuple\n lst.extend(tpl)\n return lst", "matching_cluster_idx": 5}, {"solution": "def add_tuple(lst, tpl):\n # Extend the list with the elements from the tuple\n lst.extend(tpl)\n return lst", "matching_cluster_idx": 5}, {"solution": "def add_tuple(lst, tpl):\n # Extend the list by adding elements from the tuple\n return lst + list(tpl)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(lst, tpl):\n # Extend the list with the elements from the tuple\n return lst + list(tpl)", "matching_cluster_idx": 2}]}, "Mbpp/753": {"dps": 97.31543624161074, "dps_norm": 75.0, "pass@1": 100.0, "profiled": [{"solution": "def min_k(tuples_list, k):\n \"\"\"\n Finds the minimum k records from a list of tuples based on the second element of each tuple.\n \n :param tuples_list: List of tuples, where each tuple contains a string and an integer.\n :param k: The number of minimum records to return.\n :return: A list of tuples containing the k minimum records.\n \"\"\"\n # Sort the list of tuples based on the second element of each tuple\n sorted_tuples = sorted(tuples_list, key=lambda x: x[1])\n # Return the first k elements from the sorted list\n return sorted_tuples[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(tuples_list, k):\n \"\"\"\n Finds the minimum k records from a list of tuples based on the second element of each tuple.\n\n Parameters:\n tuples_list (list of tuples): The list of tuples to process.\n k (int): The number of minimum records to find.\n\n Returns:\n list of tuples: A list containing the k tuples with the smallest second elements.\n \"\"\"\n # Sort the list of tuples based on the second element of each tuple\n sorted_tuples = sorted(tuples_list, key=lambda x: x[1])\n \n # Return the first k elements of the sorted list\n return sorted_tuples[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(test_list, k):\n # Sort the list based on the second element of the tuples\n sorted_list = sorted(test_list, key=lambda x: x[1])\n # Return the first k elements of the sorted list\n return sorted_list[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(tuples_list, k):\n \"\"\"\n This function takes a list of tuples and an integer k, and returns a list of the k tuples with the smallest second elements.\n \n :param tuples_list: List of tuples where each tuple is of the form (name, value)\n :param k: Integer representing the number of smallest elements to return\n :return: List of k tuples with the smallest second elements\n \"\"\"\n # Sort the list of tuples based on the second element of each tuple\n sorted_tuples = sorted(tuples_list, key=lambda x: x[1])\n \n # Return the first k elements from the sorted list\n return sorted_tuples[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(test_list, K):\n # Sort the list based on the second element of each tuple\n sorted_list = sorted(test_list, key=lambda x: x[1])\n # Extract the first K elements from the sorted list\n result = sorted_list[:K]\n return result", "matching_cluster_idx": 2}, {"solution": "def min_k(records, k):\n \"\"\"\n Finds the minimum k records from a list of tuples based on the second element of each tuple.\n \n :param records: List of tuples, where each tuple contains a name and a number.\n :param k: Number of minimum records to return.\n :return: List of tuples containing the k minimum records.\n \"\"\"\n # Sort the list of tuples based on the second element (the number)\n sorted_records = sorted(records, key=lambda x: x[1])\n \n # Return the first k elements from the sorted list\n return sorted_records[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(tuples_list, k):\n \"\"\"\n Finds the minimum k records from a list of tuples based on the second element of each tuple.\n \n :param tuples_list: List of tuples, where each tuple contains a name and a number.\n :param k: Number of minimum records to return.\n :return: List of k tuples with the smallest second elements.\n \"\"\"\n # Sort the list of tuples based on the second element of each tuple\n sorted_tuples = sorted(tuples_list, key=lambda x: x[1])\n \n # Return the first k elements from the sorted list\n return sorted_tuples[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(tuples_list, k):\n \"\"\"\n Finds the minimum k records from a list of tuples based on the second element of each tuple.\n \n :param tuples_list: List of tuples, where each tuple is of the form (name, value)\n :param k: Number of minimum records to return\n :return: List of k tuples with the smallest second elements\n \"\"\"\n # Sort the list of tuples based on the second element of each tuple\n sorted_list = sorted(tuples_list, key=lambda x: x[1])\n \n # Return the first k elements of the sorted list\n return sorted_list[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(records, k):\n \"\"\"\n Finds the minimum k records from a list of tuples based on the second element of each tuple.\n \n :param records: List of tuples, where each tuple contains a name and a numeric value.\n :param k: The number of minimum records to return.\n :return: A list of tuples containing the k minimum records.\n \"\"\"\n # Sort the list of tuples based on the second element (numeric value)\n sorted_records = sorted(records, key=lambda x: x[1])\n \n # Return the first k elements of the sorted list\n return sorted_records[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(test_list, k):\n # Sort the list based on the second element of each tuple\n sorted_list = sorted(test_list, key=lambda x: x[1])\n # Return the first k elements from the sorted list\n return sorted_list[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(test_list, K):\n # Sort the list based on the second element of the tuples\n sorted_list = sorted(test_list, key=lambda x: x[1])\n # Return the first K elements from the sorted list\n return sorted_list[:K]", "matching_cluster_idx": 2}, {"solution": "def min_k(records, k):\n \"\"\"\n Finds the minimum k records from a list of tuples based on the second element of each tuple.\n\n :param records: List of tuples where each tuple contains a name and a numeric value.\n :param k: The number of minimum records to return.\n :return: A list of tuples containing the k minimum records.\n \"\"\"\n # Sort the list of tuples based on the second element of each tuple\n sorted_records = sorted(records, key=lambda x: x[1])\n # Return the first k elements from the sorted list\n return sorted_records[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(tuples_list, k):\n # Sort the list based on the second element of each tuple\n sorted_list = sorted(tuples_list, key=lambda x: x[1])\n # Return the first k elements of the sorted list\n return sorted_list[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(records, k):\n # Sort the list of tuples based on the second element (the integer value) and slice the first k elements\n return sorted(records, key=lambda x: x[1])[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(test_list, K):\n # Sort the list based on the second element of each tuple and then slice the first K elements\n res = sorted(test_list, key=lambda x: x[1])[:K]\n return res", "matching_cluster_idx": 2}, {"solution": "def min_k(tuples_list, k):\n \"\"\"\n Finds the minimum k records from a list of tuples based on the second element of each tuple.\n \n Parameters:\n tuples_list (list of tuples): The list of tuples to process.\n k (int): The number of minimum records to return.\n \n Returns:\n list of tuples: A list containing the k tuples with the smallest second elements.\n \"\"\"\n # Sort the list of tuples based on the second element of each tuple\n sorted_list = sorted(tuples_list, key=lambda x: x[1])\n # Return the first k elements of the sorted list\n return sorted_list[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(test_list, K):\n # Sort the list based on the second element of each tuple\n sorted_list = sorted(test_list, key=lambda x: x[1])\n # Return the first K elements from the sorted list\n return sorted_list[:K]", "matching_cluster_idx": 2}, {"solution": "def min_k(lst, k):\n \"\"\"\n Finds the minimum k records from a list of tuples based on the second element of each tuple.\n \n :param lst: List of tuples where each tuple is in the form (name, value)\n :param k: Number of minimum records to return\n :return: List of k tuples with the smallest second elements\n \"\"\"\n # Sort the list of tuples based on the second element\n sorted_lst = sorted(lst, key=lambda x: x[1])\n \n # Return the first k elements of the sorted list\n return sorted_lst[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(tuples_list, k):\n # Sort the list of tuples based on the second item (numeric value)\n sorted_tuples = sorted(tuples_list, key=lambda x: x[1])\n # Return the first k elements from the sorted list\n return sorted_tuples[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(records, k):\n \"\"\"\n Finds the minimum k records from a list of tuples based on the second element of each tuple.\n \n :param records: List of tuples, where each tuple contains a name and an integer.\n :param k: Number of minimum records to return.\n :return: List of tuples representing the minimum k records.\n \"\"\"\n # Sort the list of tuples based on the second element of each tuple\n sorted_records = sorted(records, key=lambda x: x[1])\n \n # Return the first k elements from the sorted list\n return sorted_records[:k]", "matching_cluster_idx": 2}]}, "Mbpp/754": {"dps": 89.65517241379311, "dps_norm": 87.5, "pass@1": 100.0, "profiled": [{"solution": "def extract_index_list(l1, l2, l3):\n # Initialize an empty list to store common elements\n common_elements = []\n \n # Determine the length of the shortest list to avoid index out of range errors\n min_length = min(len(l1), len(l2), len(l3))\n \n # Iterate through the lists up to the length of the shortest list\n for i in range(min_length):\n # Check if the elements at the current index are the same in all three lists\n if l1[i] == l2[i] == l3[i]:\n # If they are the same, add the element to the common_elements list\n common_elements.append(l1[i])\n \n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n # Initialize an empty list to store common elements\n common_elements = []\n \n # Determine the length of the shortest list to avoid index errors\n min_length = min(len(l1), len(l2), len(l3))\n \n # Iterate through the lists up to the length of the shortest list\n for i in range(min_length):\n # Check if the elements at the current index are the same in all three lists\n if l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n \n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n # Initialize an empty list to store common elements\n common_elements = []\n \n # Determine the length of the shortest list to avoid index out of range errors\n min_length = min(len(l1), len(l2), len(l3))\n \n # Iterate through the lists up to the length of the shortest list\n for i in range(min_length):\n # Check if the elements at the current index are the same in all three lists\n if l1[i] == l2[i] == l3[i]:\n # If they are the same, add the element to the common_elements list\n common_elements.append(l1[i])\n \n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n # Initialize an empty list to store common elements\n common_elements = []\n \n # Determine the minimum length among the three lists to avoid index out of range errors\n min_length = min(len(l1), len(l2), len(l3))\n \n # Iterate through the lists up to the minimum length\n for i in range(min_length):\n # Check if the elements at the current index are the same in all three lists\n if l1[i] == l2[i] == l3[i]:\n # If they are, add the element to the common_elements list\n common_elements.append(l1[i])\n \n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n # Initialize an empty list to store the common elements\n common_elements = []\n \n # Determine the length of the shortest list to avoid index out of range errors\n min_length = min(len(l1), len(l2), len(l3))\n \n # Iterate through the lists up to the length of the shortest list\n for i in range(min_length):\n # Check if the elements at the current index are the same in all three lists\n if l1[i] == l2[i] == l3[i]:\n # If they are, add the element to the common_elements list\n common_elements.append(l1[i])\n \n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n # Initialize an empty list to store the common elements\n common_elements = []\n \n # Determine the length of the shortest list to avoid index errors\n min_length = min(len(l1), len(l2), len(l3))\n \n # Iterate through the lists up to the length of the shortest list\n for i in range(min_length):\n # Check if the elements at the current index are the same in all three lists\n if l1[i] == l2[i] == l3[i]:\n # If they are the same, add the element to the common_elements list\n common_elements.append(l1[i])\n \n # Return the list of common elements\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n # Initialize an empty list to store the common elements\n common_elements = []\n \n # Determine the length of the shortest list to avoid index errors\n min_length = min(len(l1), len(l2), len(l3))\n \n # Iterate through the lists up to the length of the shortest list\n for i in range(min_length):\n # Check if the elements at the current index are the same in all three lists\n if l1[i] == l2[i] == l3[i]:\n # If they are the same, add the element to the common_elements list\n common_elements.append(l1[i])\n \n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n # Initialize an empty list to store the common elements\n common_elements = []\n \n # Determine the length of the shortest list to avoid index errors\n min_length = min(len(l1), len(l2), len(l3))\n \n # Iterate through the lists up to the length of the shortest list\n for i in range(min_length):\n # Check if the elements at the current index are the same in all three lists\n if l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n \n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n # Initialize an empty list to store common elements\n common_elements = []\n \n # Determine the length of the shortest list to avoid index errors\n min_length = min(len(l1), len(l2), len(l3))\n \n # Iterate through the lists up to the length of the shortest list\n for i in range(min_length):\n # Check if the elements at the current index are the same in all three lists\n if l1[i] == l2[i] == l3[i]:\n # If they are, add the element to the common_elements list\n common_elements.append(l1[i])\n \n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n # Initialize an empty list to store common elements\n common_elements = []\n \n # Determine the length of the shortest list to avoid index errors\n min_length = min(len(l1), len(l2), len(l3))\n \n # Iterate through the lists up to the length of the shortest list\n for i in range(min_length):\n # Check if the elements at the current index are the same in all three lists\n if l1[i] == l2[i] == l3[i]:\n # If they are, add the element to the common_elements list\n common_elements.append(l1[i])\n \n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n # Initialize an empty list to store the common elements\n common_elements = []\n \n # Determine the length of the shortest list to avoid index errors\n min_length = min(len(l1), len(l2), len(l3))\n \n # Iterate through the lists up to the length of the shortest list\n for i in range(min_length):\n # Check if the elements at the current index are the same in all three lists\n if l1[i] == l2[i] == l3[i]:\n # If they are, add the element to the common_elements list\n common_elements.append(l1[i])\n \n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n # Initialize an empty list to store the common elements\n common_elements = []\n \n # Determine the length of the shortest list to avoid index errors\n min_length = min(len(l1), len(l2), len(l3))\n \n # Iterate through the lists up to the length of the shortest list\n for i in range(min_length):\n # Check if the elements at the current index are the same in all three lists\n if l1[i] == l2[i] == l3[i]:\n # If they are, add the element to the common_elements list\n common_elements.append(l1[i])\n \n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n # Initialize an empty list to store common elements\n common_elements = []\n \n # Determine the length of the shortest list to avoid index errors\n min_length = min(len(l1), len(l2), len(l3))\n \n # Iterate through the lists up to the length of the shortest list\n for i in range(min_length):\n # Check if the elements at the current index are the same in all three lists\n if l1[i] == l2[i] == l3[i]:\n # If they are the same, add the element to the common_elements list\n common_elements.append(l1[i])\n \n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n # Initialize an empty list to store common elements\n common_elements = []\n \n # Determine the length of the shortest list to avoid index errors\n min_length = min(len(l1), len(l2), len(l3))\n \n # Iterate through the lists up to the length of the shortest list\n for i in range(min_length):\n # Check if the elements at the current index are the same in all three lists\n if l1[i] == l2[i] == l3[i]:\n # If they are the same, add the element to the common_elements list\n common_elements.append(l1[i])\n \n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n # Initialize an empty list to store common elements\n common_elements = []\n \n # Determine the length of the shortest list to avoid index errors\n min_length = min(len(l1), len(l2), len(l3))\n \n # Iterate through the lists up to the length of the shortest list\n for i in range(min_length):\n # Check if the elements at the current index are the same in all three lists\n if l1[i] == l2[i] == l3[i]:\n # If they are the same, add the element to the common_elements list\n common_elements.append(l1[i])\n \n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n # Initialize an empty list to store the common elements\n common_elements = []\n \n # Determine the length of the shortest list to avoid index out of range errors\n min_length = min(len(l1), len(l2), len(l3))\n \n # Iterate through the lists up to the length of the shortest list\n for i in range(min_length):\n # Check if the elements at the current index are the same in all three lists\n if l1[i] == l2[i] == l3[i]:\n # If they are the same, add the element to the common_elements list\n common_elements.append(l1[i])\n \n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n # Initialize an empty list to store common elements\n common_elements = []\n \n # Determine the length of the shortest list to avoid index errors\n min_length = min(len(l1), len(l2), len(l3))\n \n # Iterate through the lists up to the length of the shortest list\n for i in range(min_length):\n # Check if the elements at the current index are the same in all three lists\n if l1[i] == l2[i] == l3[i]:\n # If they are the same, add the element to the common_elements list\n common_elements.append(l1[i])\n \n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n # Initialize an empty list to store common elements\n common_elements = []\n \n # Determine the length of the shortest list to avoid index errors\n min_length = min(len(l1), len(l2), len(l3))\n \n # Iterate through the lists up to the length of the shortest list\n for i in range(min_length):\n # Check if the elements at the current index are the same in all three lists\n if l1[i] == l2[i] == l3[i]:\n # If they are, append the element to the common_elements list\n common_elements.append(l1[i])\n \n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n # Initialize an empty list to store the common elements\n common_elements = []\n \n # Determine the length of the shortest list to avoid index out of range errors\n min_length = min(len(l1), len(l2), len(l3))\n \n # Iterate through the lists up to the length of the shortest list\n for i in range(min_length):\n # Check if the elements at the current index are the same in all three lists\n if l1[i] == l2[i] == l3[i]:\n # If they are, add the element to the common_elements list\n common_elements.append(l1[i])\n \n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n # Initialize an empty list to store common elements\n common_elements = []\n \n # Determine the length of the shortest list to avoid index out of range errors\n min_length = min(len(l1), len(l2), len(l3))\n \n # Iterate through the lists up to the length of the shortest list\n for i in range(min_length):\n # Check if the elements at the current index are the same in all three lists\n if l1[i] == l2[i] == l3[i]:\n # If they are, append the element to the common_elements list\n common_elements.append(l1[i])\n \n return common_elements", "matching_cluster_idx": 6}]}, "Mbpp/755": {"dps": 36.75516224188791, "dps_norm": 68.88888888888889, "pass@1": 15.0, "profiled": [{"solution": "def second_smallest(numbers):\n # Initialize the smallest and second smallest with infinity\n min1, min2 = float('inf'), float('inf')\n \n # Iterate through each number in the list\n for num in numbers:\n # Update min1 and min2 accordingly\n if num < min1:\n min2 = min1\n min1 = num\n elif num < min2 and num != min1:\n min2 = num\n \n # Return the second smallest number\n return min2 if min2 != float('inf') else None", "matching_cluster_idx": 4}, {"solution": "def second_smallest(numbers):\n # Initialize the smallest and second smallest with positive infinity\n smallest = second_smallest = float('inf')\n \n # Iterate through each number in the list\n for num in numbers:\n # If the current number is smaller than the smallest, update both smallest and second smallest\n if num < smallest:\n second_smallest = smallest\n smallest = num\n # If the current number is between smallest and second smallest, update second smallest\n elif smallest < num < second_smallest:\n second_smallest = num\n \n # Return the second smallest number found\n return second_smallest if second_smallest != float('inf') else None", "matching_cluster_idx": 3}, {"solution": "def second_smallest(numbers):\n # Initialize the smallest and second smallest numbers with positive infinity\n min1, min2 = float('inf'), float('inf')\n \n # Iterate through each number in the list\n for x in numbers:\n # Update min1 and min2 accordingly\n if x < min1:\n min1, min2 = x, min1\n elif min1 < x < min2:\n min2 = x\n \n # Return the second smallest number\n return min2 if min2 != float('inf') else None", "matching_cluster_idx": 3}, {"solution": "def second_smallest(numbers):\n # Initialize the smallest and second smallest with positive infinity\n first, second = float('inf'), float('inf')\n \n for num in numbers:\n # If the current number is smaller than the first smallest, update both\n if num < first:\n second, first = first, num\n # If the current number is between the first and second smallest, update the second smallest\n elif first < num < second:\n second = num\n \n # If second is still infinity, there was no second smallest number\n if second == float('inf'):\n return None\n return second", "matching_cluster_idx": 3}, {"solution": "def second_smallest(numbers):\n # Initialize the smallest and second smallest with infinity\n smallest = second_smallest = float('inf')\n \n # Iterate through the list to find the smallest and second smallest numbers\n for num in numbers:\n if num < smallest:\n second_smallest = smallest\n smallest = num\n elif smallest < num < second_smallest:\n second_smallest = num\n \n # Return the second smallest number\n return second_smallest if second_smallest != float('inf') else None", "matching_cluster_idx": 3}, {"solution": "def second_smallest(numbers):\n # Initialize the smallest and second smallest with infinity\n smallest = second_smallest = float('inf')\n \n # Iterate through the list to find the smallest and second smallest\n for num in numbers:\n if num < smallest:\n second_smallest = smallest\n smallest = num\n elif smallest < num < second_smallest:\n second_smallest = num\n \n # Return the second smallest number\n return second_smallest if second_smallest != float('inf') else None", "matching_cluster_idx": 3}, {"solution": "def second_smallest(numbers):\n # Initialize the smallest and second smallest with infinity\n first, second = float('inf'), float('inf')\n \n for num in numbers:\n # Update first and second smallest numbers if necessary\n if num < first:\n first, second = num, first\n elif first < num < second:\n second = num\n \n return second if second != float('inf') else None", "matching_cluster_idx": 3}, {"solution": "def second_smallest(numbers):\n # Initialize the smallest and second smallest with infinity\n first, second = float('inf'), float('inf')\n \n for num in numbers:\n # Update the smallest and second smallest numbers\n if num < first:\n second, first = first, num\n elif first < num < second:\n second = num\n \n return second if second != float('inf') else None", "matching_cluster_idx": 3}, {"solution": "def second_smallest(numbers):\n # Initialize the smallest and second smallest with infinity\n smallest = second = float('inf')\n \n for num in numbers:\n # Update smallest and second smallest accordingly\n if num < smallest:\n smallest, second = num, smallest\n elif smallest < num < second:\n second = num\n \n # If second smallest was never updated, return None\n if second == float('inf'):\n return None\n \n return second", "matching_cluster_idx": 3}, {"solution": "def second_smallest(numbers):\n # Initialize the smallest and second smallest numbers with positive infinity\n min1, min2 = float('inf'), float('inf')\n \n # Iterate through each number in the list\n for num in numbers:\n # Update the smallest and second smallest numbers if necessary\n if num < min1:\n min2 = min1\n min1 = num\n elif min1 < num < min2:\n min2 = num\n \n # Return the second smallest number\n return min2 if min2 != float('inf') else None", "matching_cluster_idx": 3}, {"solution": "def second_smallest(numbers):\n # Initialize the smallest and second smallest with positive infinity\n min1, min2 = float('inf'), float('inf')\n \n for num in numbers:\n # Update the smallest and second smallest if a new smaller number is found\n if num < min1:\n min1, min2 = num, min1\n elif min1 < num < min2:\n min2 = num\n \n return min2 if min2 != float('inf') else None", "matching_cluster_idx": 3}, {"solution": "def second_smallest(numbers):\n # Initialize the smallest and second smallest with infinity\n smallest = second_smallest = float('inf')\n \n for num in numbers:\n # Update smallest and second smallest if necessary\n if num < smallest:\n second_smallest = smallest\n smallest = num\n elif num < second_smallest and num != smallest:\n second_smallest = num\n \n # If second_smallest is still infinity, it means there was no distinct second smallest number\n if second_smallest == float('inf'):\n return None\n \n return second_smallest", "matching_cluster_idx": 4}, {"solution": "def second_smallest(numbers):\n # Initialize the smallest and second smallest with positive infinity\n min1, min2 = float('inf'), float('inf')\n \n for num in numbers:\n # Update the smallest and second smallest numbers\n if num < min1:\n min2 = min1\n min1 = num\n elif min1 < num < min2:\n min2 = num\n \n # Return the second smallest number\n return min2 if min2 != float('inf') else None", "matching_cluster_idx": 3}, {"solution": "def second_smallest(numbers):\n # Initialize the smallest and second smallest with positive infinity\n smallest = second_smallest_num = float('inf')\n \n for num in numbers:\n # Update the smallest and second smallest numbers if a new smaller number is found\n if num < smallest:\n second_smallest_num = smallest\n smallest = num\n elif smallest < num < second_smallest_num:\n second_smallest_num = num\n \n # If second_smallest_num is still infinity, it means there was no second smallest number\n if second_smallest_num == float('inf'):\n return None\n else:\n return second_smallest_num", "matching_cluster_idx": 3}, {"solution": "def second_smallest(numbers):\n # Initialize the smallest and second smallest with positive infinity\n smallest = second_smallest_num = float('inf')\n \n for num in numbers:\n # Update the smallest and second smallest numbers\n if num < smallest:\n second_smallest_num = smallest\n smallest = num\n elif smallest < num < second_smallest_num:\n second_smallest_num = num\n \n # Return the second smallest number if it was updated from the initial value\n return second_smallest_num if second_smallest_num != float('inf') else None", "matching_cluster_idx": 3}]}, "Mbpp/757": {"dps": null, "dps_norm": null, "pass@1": 7.0, "profiled": []}, "Mbpp/758": {"dps": 96.54440154440154, "dps_norm": 86.875, "pass@1": 100.0, "profiled": [{"solution": "from collections import Counter\ndef unique_sublists(lists):\n # Convert each sublist to a tuple and count occurrences using Counter\n counts = Counter(tuple(sublist) for sublist in lists)\n return counts", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(lists):\n # Initialize an empty dictionary to store the counts\n count_dict = {}\n \n # Iterate over each sublist in the input list\n for sublist in lists:\n # Convert the sublist to a tuple\n tuple_sublist = tuple(sublist)\n \n # If the tuple is already in the dictionary, increment its count\n if tuple_sublist in count_dict:\n count_dict[tuple_sublist] += 1\n # Otherwise, add the tuple to the dictionary with a count of 1\n else:\n count_dict[tuple_sublist] = 1\n \n return count_dict", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(lists):\n # Create a dictionary to store the count of each sublist (converted to a tuple)\n count_dict = {}\n \n # Iterate over each sublist in the input list\n for sublist in lists:\n # Convert the sublist to a tuple (since lists are not hashable and cannot be dictionary keys)\n tuple_sublist = tuple(sublist)\n \n # If the tuple is already in the dictionary, increment its count\n if tuple_sublist in count_dict:\n count_dict[tuple_sublist] += 1\n # Otherwise, add the tuple to the dictionary with a count of 1\n else:\n count_dict[tuple_sublist] = 1\n \n return count_dict", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(lists):\n # Initialize an empty dictionary to store the counts of each sublist\n count_dict = {}\n \n # Iterate through each sublist in the input list\n for sublist in lists:\n # Convert the sublist to a tuple (since lists are not hashable and cannot be dictionary keys)\n tuple_sublist = tuple(sublist)\n \n # If the tuple is already in the dictionary, increment its count\n if tuple_sublist in count_dict:\n count_dict[tuple_sublist] += 1\n # Otherwise, add the tuple to the dictionary with a count of 1\n else:\n count_dict[tuple_sublist] = 1\n \n # Return the dictionary containing the counts of each unique sublist\n return count_dict", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(lists):\n # Initialize an empty dictionary to store the counts\n counts = {}\n \n # Iterate over each sublist in the input list\n for sublist in lists:\n # Convert the sublist to a tuple (since lists can't be used as dictionary keys)\n key = tuple(sublist)\n \n # If the key is already in the dictionary, increment its count\n if key in counts:\n counts[key] += 1\n # Otherwise, add the key to the dictionary with a count of 1\n else:\n counts[key] = 1\n \n return counts", "matching_cluster_idx": 6}, {"solution": "from collections import Counter\ndef unique_sublists(list_of_lists):\n # Convert each sublist into a tuple to make it hashable\n tuple_list = [tuple(sublist) for sublist in list_of_lists]\n \n # Count occurrences of each tuple using Counter\n count_dict = Counter(tuple_list)\n \n # Return the count dictionary\n return dict(count_dict)", "matching_cluster_idx": 6}, {"solution": "from collections import Counter\ndef unique_sublists(lst):\n # Convert each sublist to a tuple to make it hashable and countable\n tuples = [tuple(sublist) for sublist in lst]\n # Use Counter to count occurrences of each tuple\n return dict(Counter(tuples))", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(lists):\n # Initialize an empty dictionary to store the counts of tuples\n count_dict = {}\n \n # Iterate over each list in the input list\n for sublist in lists:\n # Convert the sublist to a tuple\n tuple_sublist = tuple(sublist)\n # If the tuple is already in the dictionary, increment its count\n if tuple_sublist in count_dict:\n count_dict[tuple_sublist] += 1\n # If the tuple is not in the dictionary, add it with a count of 1\n else:\n count_dict[tuple_sublist] = 1\n \n return count_dict", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(lists):\n # Initialize an empty dictionary to store the count of each sublist\n count_dict = {}\n \n # Iterate over each sublist in the input list\n for sublist in lists:\n # Convert the sublist to a tuple (since lists are not hashable and cannot be dictionary keys)\n tuple_sublist = tuple(sublist)\n \n # If the tuple is already in the dictionary, increment its count\n if tuple_sublist in count_dict:\n count_dict[tuple_sublist] += 1\n # Otherwise, add the tuple to the dictionary with a count of 1\n else:\n count_dict[tuple_sublist] = 1\n \n # Return the dictionary containing the count of each unique sublist\n return count_dict", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(lists):\n # Create a dictionary to store the counts of each tuple\n count_dict = {}\n \n # Iterate over each sublist in the input list\n for sublist in lists:\n # Convert the sublist to a tuple\n tuple_sublist = tuple(sublist)\n \n # If the tuple is already in the dictionary, increment its count\n if tuple_sublist in count_dict:\n count_dict[tuple_sublist] += 1\n # Otherwise, add the tuple to the dictionary with a count of 1\n else:\n count_dict[tuple_sublist] = 1\n \n return count_dict", "matching_cluster_idx": 6}, {"solution": "from collections import Counter\ndef unique_sublists(lists):\n # Convert each sublist to a tuple to make them hashable\n # Count the occurrences of each tuple using Counter\n return dict(Counter(tuple(lst) for lst in lists))", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(lists):\n # Initialize an empty dictionary to store the counts of each sublist\n counts = {}\n \n # Iterate over each sublist in the input list\n for sublist in lists:\n # Convert the sublist to a tuple (since lists are not hashable and cannot be used as dictionary keys)\n tuple_sublist = tuple(sublist)\n \n # If the tuple is already in the dictionary, increment its count\n if tuple_sublist in counts:\n counts[tuple_sublist] += 1\n # Otherwise, add the tuple to the dictionary with a count of 1\n else:\n counts[tuple_sublist] = 1\n \n return counts", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(lst):\n # Initialize an empty dictionary to store the counts\n count_dict = {}\n \n # Iterate through each sublist in the input list\n for sublist in lst:\n # Convert the sublist to a tuple (since lists are not hashable and cannot be dictionary keys)\n key = tuple(sublist)\n \n # If the tuple is already in the dictionary, increment its count\n if key in count_dict:\n count_dict[key] += 1\n # Otherwise, add the tuple to the dictionary with a count of 1\n else:\n count_dict[key] = 1\n \n # Return the dictionary containing the counts of each unique sublist\n return count_dict", "matching_cluster_idx": 6}, {"solution": "from collections import defaultdict\ndef unique_sublists(lists):\n # Initialize a default dictionary to store the counts of each sublist\n sublist_counts = defaultdict(int)\n \n # Iterate over each sublist in the input list\n for sublist in lists:\n # Convert the sublist to a tuple and use it as a key in the dictionary\n sublist_tuple = tuple(sublist)\n # Increment the count for the tuple in the dictionary\n sublist_counts[sublist_tuple] += 1\n \n # Convert the defaultdict to a regular dictionary before returning\n return dict(sublist_counts)", "matching_cluster_idx": 5}, {"solution": "def unique_sublists(lists):\n # Initialize an empty dictionary to store the count of each sublist\n result = {}\n \n # Iterate over each sublist in the input list\n for sublist in lists:\n # Convert the sublist to a tuple (as lists are not hashable and cannot be dictionary keys)\n tuple_sublist = tuple(sublist)\n \n # If the tuple is already in the dictionary, increment its count\n if tuple_sublist in result:\n result[tuple_sublist] += 1\n # Otherwise, add the tuple to the dictionary with a count of 1\n else:\n result[tuple_sublist] = 1\n \n return result", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(lists):\n # Initialize an empty dictionary to store the counts\n sublist_count = {}\n \n # Iterate through each sublist in the input list\n for sublist in lists:\n # Convert the sublist to a tuple (since lists are not hashable and cannot be used as dictionary keys)\n tuple_sublist = tuple(sublist)\n \n # If the tuple is already in the dictionary, increment its count\n if tuple_sublist in sublist_count:\n sublist_count[tuple_sublist] += 1\n # Otherwise, add the tuple to the dictionary with a count of 1\n else:\n sublist_count[tuple_sublist] = 1\n \n return sublist_count", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(lists):\n # Initialize an empty dictionary to store the counts\n sublist_counts = {}\n \n # Iterate over each sublist in the input list\n for sublist in lists:\n # Convert the sublist to a tuple to make it hashable\n tuple_sublist = tuple(sublist)\n \n # If the tuple is already in the dictionary, increment its count\n if tuple_sublist in sublist_counts:\n sublist_counts[tuple_sublist] += 1\n # Otherwise, add the tuple to the dictionary with a count of 1\n else:\n sublist_counts[tuple_sublist] = 1\n \n return sublist_counts", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(lst):\n # Initialize an empty dictionary to store the counts\n count_dict = {}\n \n # Iterate over each sublist in the input list\n for sublist in lst:\n # Convert the sublist to a tuple so it can be used as a dictionary key\n tuple_sublist = tuple(sublist)\n \n # If the tuple is already in the dictionary, increment its count\n if tuple_sublist in count_dict:\n count_dict[tuple_sublist] += 1\n # Otherwise, add the tuple to the dictionary with a count of 1\n else:\n count_dict[tuple_sublist] = 1\n \n return count_dict", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(lists):\n # Create an empty dictionary to store the counts of each sublist\n counts = {}\n \n # Iterate over each sublist in the input list\n for sublist in lists:\n # Convert the sublist to a tuple (since lists are not hashable and cannot be dictionary keys)\n tuple_sublist = tuple(sublist)\n \n # If the tuple is already in the dictionary, increment its count\n if tuple_sublist in counts:\n counts[tuple_sublist] += 1\n # Otherwise, add the tuple to the dictionary with a count of 1\n else:\n counts[tuple_sublist] = 1\n \n # Return the dictionary with the counts\n return counts", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(lst):\n # Initialize an empty dictionary to store the counts of each sublist\n result = {}\n \n # Iterate through each sublist in the input list\n for sublist in lst:\n # Convert the sublist to a tuple (since lists can't be dictionary keys)\n tuple_sublist = tuple(sublist)\n \n # If the tuple is already in the dictionary, increment its count\n if tuple_sublist in result:\n result[tuple_sublist] += 1\n # If the tuple is not in the dictionary, add it with a count of 1\n else:\n result[tuple_sublist] = 1\n \n return result", "matching_cluster_idx": 6}]}, "Mbpp/760": {"dps": 99.27007299270073, "dps_norm": 87.5, "pass@1": 100.0, "profiled": [{"solution": "def unique_Element(lst):\n # Convert the list to a set and check if its length is 1\n return len(set(lst)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(lst):\n # Convert the list to a set and check if its length is 1\n return len(set(lst)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(lst):\n # Convert the list to a set to remove duplicate elements\n # If the length of the set is 1, then the list contains only one distinct element\n return len(set(lst)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(lst):\n # Convert the list to a set to remove duplicates\n unique_elements = set(lst)\n \n # Check if the set has only one element\n return len(unique_elements) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(numbers):\n # Convert the list to a set to remove duplicate elements\n unique_numbers = set(numbers)\n \n # Check if the length of the set is 1, indicating all elements in the list were the same\n return len(unique_numbers) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(numbers):\n # Convert the list to a set to remove duplicates\n unique_numbers = set(numbers)\n # Check if the set has only one element\n return len(unique_numbers) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(lst):\n # Convert the list to a set to remove duplicates\n # If the set has only one element, the list contains only one distinct element\n return len(set(lst)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(lst):\n # Convert the list to a set to remove duplicates\n # If the length of the set is 1, then the list contains only one distinct element\n return len(set(lst)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(lst):\n # Convert the list to a set to remove duplicate elements\n unique_set = set(lst)\n \n # Check if the set has exactly one element\n return len(unique_set) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(lst):\n # Convert the list to a set to remove duplicates\n # If the length of the set is 1, then all elements in the list are the same\n return len(set(lst)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(lst):\n # Convert the list to a set to remove duplicates\n # If the length of the set is 1, it means all elements in the list were the same\n return len(set(lst)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(numbers):\n # Convert the list to a set to remove duplicate elements\n unique_numbers = set(numbers)\n # Check if the set has only one element\n return len(unique_numbers) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(lst):\n # Convert the list to a set to remove duplicates\n unique_elements = set(lst)\n \n # Check if the set has only one element\n return len(unique_elements) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(nums):\n # Convert the list to a set to remove duplicates and check its length\n return len(set(nums)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(lst):\n # Convert the list to a set to remove duplicate elements\n # If the length of the set is 1, then all elements in the list are the same\n return len(set(lst)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(lst):\n # Convert the list to a set to remove duplicates and check its length\n return len(set(lst)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(lst):\n # Convert the list to a set to remove duplicates\n unique_elements = set(lst)\n \n # Check if the set contains exactly one element\n return len(unique_elements) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(lst):\n # Convert the list to a set to remove duplicates and check its length\n return len(set(lst)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(lst):\n # Convert the list to a set and check if its length is 1\n return len(set(lst)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(numbers):\n # Convert the list to a set to remove duplicate elements\n unique_numbers = set(numbers)\n # Check if the length of the set is 1, indicating all elements in the list are the same\n return len(unique_numbers) == 1", "matching_cluster_idx": 6}]}, "Mbpp/764": {"dps": 84.4753086419753, "dps_norm": 48.333333333333336, "pass@1": 100.0, "profiled": [{"solution": "def number_ctr(s):\n # Initialize a counter for digits\n digit_count = 0\n \n # Iterate through each character in the string\n for char in s:\n # Check if the character is a digit\n if char.isdigit():\n # Increment the digit count\n digit_count += 1\n \n # Return the final count of digits\n return digit_count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n # Initialize a counter for digits\n count = 0\n \n # Iterate through each character in the string\n for char in s:\n # Check if the character is a digit\n if char.isdigit():\n count += 1\n \n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n # Initialize a counter for digits\n count = 0\n \n # Iterate through each character in the string\n for char in s:\n # Check if the character is a digit\n if char.isdigit():\n count += 1\n \n return count", "matching_cluster_idx": 2}, {"solution": "import re\ndef number_ctr(s):\n # Use regular expression to find all digits in the string\n digits = re.findall(r'\\d', s)\n # Return the count of digits found\n return len(digits)", "matching_cluster_idx": 0}, {"solution": "def number_ctr(s):\n # Initialize a counter for digits\n digit_count = 0\n \n # Iterate through each character in the string\n for char in s:\n # Check if the character is a digit\n if char.isdigit():\n digit_count += 1\n \n return digit_count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n # Initialize a counter for digits\n digit_count = 0\n \n # Iterate through each character in the string\n for char in s:\n # Check if the character is a digit\n if char.isdigit():\n digit_count += 1\n \n return digit_count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n # Initialize a counter for digits\n digit_count = 0\n \n # Iterate through each character in the string\n for char in s:\n # Check if the character is a digit\n if char.isdigit():\n digit_count += 1\n \n return digit_count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n # Initialize a counter to count the digits in the string\n count = 0\n # Iterate over each character in the string\n for char in s:\n # Check if the character is a digit\n if char.isdigit():\n # Increment the counter if it is a digit\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(input_string):\n # Initialize a counter for digits\n digit_count = 0\n \n # Iterate through each character in the string\n for char in input_string:\n # Check if the character is a digit\n if char.isdigit():\n digit_count += 1\n \n return digit_count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n # Initialize a counter for digits\n count = 0\n \n # Iterate through each character in the string\n for char in s:\n # Check if the character is a digit\n if char.isdigit():\n count += 1\n \n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(input_string):\n # Initialize a counter for digits\n digit_count = 0\n \n # Iterate through each character in the string\n for char in input_string:\n # Check if the character is a digit\n if char.isdigit():\n digit_count += 1\n \n return digit_count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n # Initialize a counter to zero\n digit_count = 0\n \n # Iterate through each character in the string\n for char in s:\n # Check if the character is a digit\n if char.isdigit():\n # Increment the counter if the character is a digit\n digit_count += 1\n \n # Return the total count of digits\n return digit_count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n # Initialize a counter for digits\n digit_count = 0\n \n # Iterate through each character in the string\n for char in s:\n # Check if the character is a digit\n if char.isdigit():\n digit_count += 1\n \n return digit_count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(input_string):\n # Initialize a counter for digits\n digit_count = 0\n \n # Iterate through each character in the string\n for char in input_string:\n # Check if the character is a digit\n if char.isdigit():\n digit_count += 1\n \n return digit_count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n # Initialize a counter for digits\n digit_count = 0\n \n # Iterate through each character in the string\n for char in s:\n # Check if the character is a digit\n if char.isdigit():\n digit_count += 1\n \n return digit_count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n # Initialize a counter for digits\n digit_count = 0\n \n # Iterate through each character in the string\n for char in s:\n # Check if the character is a digit\n if char.isdigit():\n digit_count += 1\n \n return digit_count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n # Initialize a counter for digits\n digit_count = 0\n \n # Iterate through each character in the string\n for char in s:\n # Check if the character is a digit\n if char.isdigit():\n # Increment the digit counter\n digit_count += 1\n \n # Return the final count of digits\n return digit_count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n # Initialize a counter for digits\n digit_count = 0\n \n # Iterate through each character in the string\n for char in s:\n # Check if the character is a digit\n if char.isdigit():\n digit_count += 1\n \n return digit_count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n # Initialize a counter for digits\n digit_count = 0\n \n # Iterate through each character in the string\n for char in s:\n # Check if the character is a digit\n if char.isdigit():\n digit_count += 1\n \n return digit_count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n # Initialize a counter for digits\n digit_count = 0\n \n # Iterate through each character in the string\n for char in s:\n # Check if the character is a digit\n if char.isdigit():\n digit_count += 1\n \n return digit_count", "matching_cluster_idx": 2}]}, "Mbpp/766": {"dps": 72.66355140186916, "dps_norm": 66.66666666666667, "pass@1": 100.0, "profiled": [{"solution": "def pair_wise(lst):\n # Use list comprehension to create pairs of consecutive items\n result = [(lst[i], lst[i + 1]) for i in range(len(lst) - 1)]\n return result", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n # Create pairs of consecutive items using zip\n result = list(zip(lst, lst[1:]))\n return result", "matching_cluster_idx": 5}, {"solution": "def pair_wise(lst):\n # Create pairs of consecutive items using zip\n result = list(zip(lst, lst[1:]))\n return result", "matching_cluster_idx": 5}, {"solution": "def pair_wise(items):\n # Use list comprehension to create pairs of consecutive items\n return [(items[i], items[i + 1]) for i in range(len(items) - 1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n # Use list comprehension to create pairs of consecutive elements\n result = [(lst[i], lst[i+1]) for i in range(len(lst) - 1)]\n return result", "matching_cluster_idx": 2}, {"solution": "def pair_wise(lst):\n # Create pairs of consecutive elements using zip\n result = list(zip(lst, lst[1:]))\n return result", "matching_cluster_idx": 5}, {"solution": "def pair_wise(lst):\n # Use list comprehension to create pairs of consecutive items\n pairs = [(lst[i], lst[i+1]) for i in range(len(lst) - 1)]\n return pairs", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n # Generate a list of tuples containing consecutive pairs\n return [(lst[i], lst[i+1]) for i in range(len(lst)-1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(items):\n # Use list comprehension to create pairs of consecutive items\n return [(items[i], items[i+1]) for i in range(len(items) - 1)]", "matching_cluster_idx": 2}, {"solution": "def pair_wise(lst):\n # Create a list of tuples containing consecutive pairs from the input list\n result = [(lst[i], lst[i + 1]) for i in range(len(lst) - 1)]\n return result", "matching_cluster_idx": 2}, {"solution": "def pair_wise(lst):\n # Use list comprehension to create pairs of consecutive items\n return [(lst[i], lst[i + 1]) for i in range(len(lst) - 1)]", "matching_cluster_idx": 2}, {"solution": "def pair_wise(lst):\n # Create a list of tuples, each containing a pair of consecutive items\n result = [(lst[i], lst[i + 1]) for i in range(len(lst) - 1)]\n return result", "matching_cluster_idx": 2}, {"solution": "def pair_wise(lst):\n # Generate pairs of consecutive items using zip\n return list(zip(lst, lst[1:]))", "matching_cluster_idx": 5}, {"solution": "def pair_wise(lst):\n # Create a list of tuples containing each pair of consecutive items\n result = [(lst[i], lst[i + 1]) for i in range(len(lst) - 1)]\n return result", "matching_cluster_idx": 2}, {"solution": "def pair_wise(lst):\n # Use list comprehension to create pairs of consecutive items\n result = [(lst[i], lst[i+1]) for i in range(len(lst)-1)]\n return result", "matching_cluster_idx": 2}, {"solution": "def pair_wise(lst):\n # Create a list of tuples, each containing a pair of consecutive elements\n result = [(lst[i], lst[i + 1]) for i in range(len(lst) - 1)]\n return result", "matching_cluster_idx": 2}, {"solution": "def pair_wise(lst):\n # Use list comprehension to create pairs of consecutive items\n return [(lst[i], lst[i+1]) for i in range(len(lst)-1)]", "matching_cluster_idx": 2}, {"solution": "def pair_wise(input_list):\n # Generate pairs of consecutive items using list comprehension\n result = [(input_list[i], input_list[i+1]) for i in range(len(input_list) - 1)]\n return result", "matching_cluster_idx": 2}, {"solution": "def pair_wise(lst):\n # Create a list of tuples containing each pair of consecutive items\n return [(lst[i], lst[i + 1]) for i in range(len(lst) - 1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n # Generate pairs of consecutive items using zip\n result = list(zip(lst, lst[1:]))\n return result", "matching_cluster_idx": 5}]}, "Mbpp/775": {"dps": 92.96, "dps_norm": 70.0, "pass@1": 100.0, "profiled": [{"solution": "def odd_position(nums):\n # Iterate through the list, checking only odd indices\n for i in range(1, len(nums), 2):\n # If the number at an odd index is not odd, return False\n if nums[i] % 2 == 0:\n return False\n # If all odd indices contain odd numbers, return True\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(nums):\n # Iterate over the list, but only check elements at odd indices\n for i in range(1, len(nums), 2):\n # Check if the element at the odd index is odd\n if nums[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(nums):\n # Iterate over the list, considering only odd indices\n for i in range(1, len(nums), 2):\n # Check if the number at the odd index is not odd\n if nums[i] % 2 == 0:\n return False\n # If all numbers at odd indices are odd, return True\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(nums):\n # Iterate over the list with index and value\n for index, value in enumerate(nums):\n # Check if the index is odd\n if index % 2 != 0:\n # Check if the value at the odd index is not odd\n if value % 2 == 0:\n return False\n return True", "matching_cluster_idx": 2}, {"solution": "def odd_position(nums):\n # Iterate through the list, checking only odd indices\n for i in range(1, len(nums), 2):\n # Check if the number at the odd index is not odd\n if nums[i] % 2 == 0:\n return False\n # If all odd indices contain odd numbers, return True\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(nums):\n # Iterate through the list, checking only odd indices\n for i in range(1, len(nums), 2):\n # Check if the number at the odd index is odd\n if nums[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(nums):\n # Iterate over the list, checking only odd indices\n for i in range(1, len(nums), 2):\n # If the number at the odd index is not odd, return False\n if nums[i] % 2 == 0:\n return False\n # If all odd indices contain odd numbers, return True\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(nums):\n # Iterate through the list, checking only the odd indices\n for i in range(1, len(nums), 2):\n # If the number at the odd index is not odd, return False\n if nums[i] % 2 == 0:\n return False\n # If all numbers at odd indices are odd, return True\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(nums):\n # Iterate through the list, checking only odd indices\n for i in range(1, len(nums), 2):\n # Check if the number at the odd index is not odd\n if nums[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(nums):\n # Iterate over the list, considering only odd indices\n for i in range(1, len(nums), 2):\n # Check if the element at the odd index is not odd\n if nums[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(nums):\n # Iterate over the list, checking only the odd indices\n for i in range(1, len(nums), 2):\n # If the number at the odd index is not odd, return False\n if nums[i] % 2 == 0:\n return False\n # If all numbers at odd indices are odd, return True\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(nums):\n # Iterate over the list, checking only odd indices\n for i in range(1, len(nums), 2):\n if nums[i] % 2 == 0: # Check if the number at the odd index is even\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(nums):\n # Iterate through the list, checking only odd indices\n for i in range(1, len(nums), 2):\n # Check if the number at the odd index is odd\n if nums[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(nums):\n # Iterate over the list, checking only odd indices\n for i in range(1, len(nums), 2):\n # Check if the number at the odd index is not odd\n if nums[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(nums):\n # Iterate through the list, checking only odd indices\n for i in range(1, len(nums), 2):\n # Check if the number at the odd index is odd\n if nums[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(nums):\n # Iterate through the list, checking only odd indices\n for i in range(1, len(nums), 2):\n # Check if the number at the odd index is not odd\n if nums[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(nums):\n # Iterate through the list, checking only odd indices\n for i in range(1, len(nums), 2):\n # Check if the number at the odd index is not odd\n if nums[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(nums):\n # Iterate through the list, checking only odd indices\n for i in range(1, len(nums), 2):\n # If the number at an odd index is not odd, return False\n if nums[i] % 2 == 0:\n return False\n # If all numbers at odd indices are odd, return True\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(nums):\n # Iterate over the list, but only check elements at odd indices\n for i in range(1, len(nums), 2):\n # Check if the element at the odd index is not an odd number\n if nums[i] % 2 == 0:\n return False\n # If all elements at odd indices are odd, return True\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(nums):\n # Iterate over the list, checking only the odd indices\n for i in range(1, len(nums), 2):\n # Check if the number at the odd index is not odd\n if nums[i] % 2 == 0:\n return False\n # If all numbers at odd indices are odd, return True\n return True", "matching_cluster_idx": 4}]}, "Mbpp/777": {"dps": null, "dps_norm": null, "pass@1": 0.0, "profiled": []}, "Mbpp/781": {"dps": 88.03149606299212, "dps_norm": 43.0, "pass@1": 100.0, "profiled": [{"solution": "def count_divisors(n):\n # Initialize a counter for the divisors\n count = 0\n # Loop through numbers from 1 to n to check for divisors\n for i in range(1, n + 1):\n if n % i == 0: # If i is a divisor of n\n count += 1 # Increment the divisor count\n # Return True if the count of divisors is even, otherwise False\n return count % 2 == 0", "matching_cluster_idx": 1}, {"solution": "def count_divisors(n):\n # Initialize a counter to count the divisors\n count = 0\n # Iterate through numbers from 1 to n (inclusive)\n for i in range(1, n + 1):\n # Check if i is a divisor of n\n if n % i == 0:\n # Increment the divisor count\n count += 1\n # Return True if the count of divisors is even, otherwise False\n return count % 2 == 0", "matching_cluster_idx": 1}, {"solution": "def count_divisors(n):\n # Initialize a count variable to keep track of the number of divisors\n count = 0\n # Loop through all numbers from 1 to n (inclusive)\n for i in range(1, n + 1):\n # If i is a divisor of n, increment the count\n if n % i == 0:\n count += 1\n # Return True if the count of divisors is even, False otherwise\n return count % 2 == 0", "matching_cluster_idx": 1}, {"solution": "def count_divisors(n):\n # Initialize a counter for the divisors\n count = 0\n # Loop through possible divisors from 1 to n\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n # Check if the count of divisors is even\n return count % 2 == 0", "matching_cluster_idx": 1}, {"solution": "def count_divisors(n):\n # Initialize a count variable to keep track of divisors\n count = 0\n # Iterate through numbers from 1 to n (inclusive)\n for i in range(1, n + 1):\n # If i is a divisor of n, increment the count\n if n % i == 0:\n count += 1\n # Return True if the count of divisors is even, False otherwise\n return count % 2 == 0", "matching_cluster_idx": 1}, {"solution": "def count_divisors(n):\n # Initialize a counter for divisors\n count = 0\n # Loop through numbers from 1 to n to find divisors\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n # Check if the count of divisors is even\n return count % 2 == 0", "matching_cluster_idx": 1}, {"solution": "def count_divisors(n):\n # Initialize a counter for the divisors\n count = 0\n # Loop through numbers from 1 to n (inclusive) to count the divisors\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n # Check if the count of divisors is even\n return count % 2 == 0", "matching_cluster_idx": 1}, {"solution": "def count_divisors(n):\n # Initialize a counter for the divisors\n count = 0\n # Loop through numbers from 1 to n to find divisors\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n # Check if the count of divisors is even\n return count % 2 == 0", "matching_cluster_idx": 1}, {"solution": "def count_divisors(n):\n # Initialize a counter for the divisors\n count = 0\n # Loop through numbers from 1 to n to check for divisors\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n # Check if the count of divisors is even\n return count % 2 == 0", "matching_cluster_idx": 1}, {"solution": "def count_divisors(n):\n # Initialize a counter for the divisors\n count = 0\n # Iterate through numbers from 1 to n (inclusive) to count divisors\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n # Check if the count of divisors is even\n return count % 2 == 0", "matching_cluster_idx": 1}, {"solution": "def count_divisors(n):\n # Initialize the count of divisors\n count = 0\n # Loop through numbers from 1 to n to check if they are divisors\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n # Return True if the count of divisors is even, otherwise False\n return count % 2 == 0", "matching_cluster_idx": 1}, {"solution": "def count_divisors(n):\n # Initialize a counter for the divisors\n count = 0\n # Loop through all numbers from 1 to n to check if they are divisors\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n # Return True if the count of divisors is even, False otherwise\n return count % 2 == 0", "matching_cluster_idx": 1}, {"solution": "def count_divisors(n):\n # Initialize the count of divisors\n count = 0\n \n # Loop to find all divisors of n\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n # If divisors are equal, count only one\n if n // i == i:\n count += 1\n else:\n # Otherwise, count both divisors\n count += 2\n \n # Check if the count of divisors is even\n return count % 2 == 0", "matching_cluster_idx": 4}, {"solution": "def count_divisors(n):\n # Initialize a counter for the divisors\n count = 0\n \n # Loop through numbers from 1 to n to find divisors\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n \n # Check if the count of divisors is even\n return count % 2 == 0", "matching_cluster_idx": 1}, {"solution": "def count_divisors(n):\n # Initialize a counter to count the divisors\n count = 0\n # Loop through numbers from 1 to n to find divisors\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n # Check if the count of divisors is even\n return count % 2 == 0", "matching_cluster_idx": 1}, {"solution": "def count_divisors(n):\n # Initialize a counter for the divisors\n count = 0\n # Loop through numbers from 1 to n to check for divisors\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n # Check if the count of divisors is even\n return count % 2 == 0", "matching_cluster_idx": 1}, {"solution": "def count_divisors(n):\n # Initialize a counter for the divisors\n count = 0\n # Loop through numbers from 1 to n to check for divisors\n for i in range(1, n + 1):\n if n % i == 0: # If i is a divisor of n\n count += 1 # Increment the count\n # Check if the count of divisors is even\n return count % 2 == 0", "matching_cluster_idx": 1}, {"solution": "def count_divisors(n):\n # Initialize a counter for the divisors\n count = 0\n # Loop through numbers from 1 to n (inclusive)\n for i in range(1, n + 1):\n # If i is a divisor of n, increment the count\n if n % i == 0:\n count += 1\n # Check if the count of divisors is even\n return count % 2 == 0", "matching_cluster_idx": 1}, {"solution": "def count_divisors(n):\n # Initialize a counter for the divisors\n count = 0\n # Loop through numbers from 1 to n to find divisors\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n # Return True if the count of divisors is even, False otherwise\n return count % 2 == 0", "matching_cluster_idx": 1}, {"solution": "def count_divisors(n):\n # Initialize a counter for the divisors\n count = 0\n # Loop through numbers from 1 to n (inclusive) to find divisors\n for i in range(1, n + 1):\n if n % i == 0: # If i is a divisor of n\n count += 1 # Increment the count\n # Check if the count of divisors is even\n return count % 2 == 0", "matching_cluster_idx": 1}]}, "Mbpp/800": {"dps": 97.31343283582089, "dps_norm": 96.0, "pass@1": 84.0, "profiled": [{"solution": "def remove_all_spaces(input_string):\n # Using the replace method to remove all spaces\n return input_string.replace(' ', '')", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n # Using the replace method to remove all spaces\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n # Use the replace method to remove all spaces from the input_string\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n # Use the str.replace() method to remove all spaces from the input string\n return input_string.replace(' ', '')", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n # Use the replace method to remove all spaces from the input_string\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n # Using the replace method to remove all spaces from the string\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n # Using the replace method to remove all spaces\n return input_string.replace(' ', '')", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n # Use the str.replace() method to remove all spaces from the input string\n return input_string.replace(' ', '')", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n # Use the replace method to remove all spaces from the input_string\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n # Using the join() method and a generator expression to filter out spaces\n return ''.join(char for char in input_string if char != ' ')", "matching_cluster_idx": 0}, {"solution": "def remove_all_spaces(input_string):\n # Use the replace method to remove all spaces from the string\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n # Use the replace method to remove all spaces from the input string\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n # Use the replace method to remove all spaces from the input string\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n # Use the replace method to remove all spaces from the input string\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n # Use the replace method to remove all spaces from the input string\n return input_string.replace(' ', '')", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n # Using the replace method to remove all spaces from the input string\n return input_string.replace(' ', '')", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n # Using the replace method to remove all spaces\n return input_string.replace(' ', '')", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n # Using the replace method to remove all spaces from the string\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n # Use the replace method to remove all spaces from the input string\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n # Use the str.replace() method to remove all spaces from the input string\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}]}, "Mbpp/805": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def max_sum_list(lists):\n # Use a lambda function to find the list with the maximum sum of elements\n max_sum = max(lists, key=lambda x: sum(x))\n return max_sum", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n # Initialize a variable to keep track of the list with the maximum sum\n max_list = []\n # Initialize a variable to keep track of the maximum sum found so far\n max_sum = float('-inf')\n \n # Iterate through each list in the list of lists\n for lst in lists:\n # Calculate the sum of the current list\n current_sum = sum(lst)\n # Update the maximum sum and the corresponding list if the current sum is greater\n if current_sum > max_sum:\n max_sum = current_sum\n max_list = lst\n \n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n # Calculate the sum of each list and return the one with the highest sum\n return max(lists, key=sum)", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n # Calculate the sum of elements for each list in the list of lists\n # and return the list with the maximum sum\n return max(lists, key=sum)", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n # Calculate the sum of each list and return the one with the maximum sum\n return max(lists, key=sum)", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n # Find the list with the maximum sum of elements\n max_list = max(lists, key=sum)\n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n # Calculate the sum of each list and return the list with the highest sum\n return max(lists, key=sum)", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n # Use a lambda function to find the list with the highest sum of elements\n return max(lists, key=lambda x: sum(x))", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n # Find the list with the maximum sum of elements\n max_list = max(lists, key=sum)\n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n # Find the list with the maximum sum using the key parameter with sum function\n return max(lists, key=sum)", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n # Find the list with the maximum sum of elements\n max_sum_list = max(lists, key=sum)\n return max_sum_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n # Use the max function with key parameter to find the list with the highest sum\n return max(lists, key=sum)", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n # Find the list with the highest sum of elements\n max_sum_list = max(lists, key=sum)\n return max_sum_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n # Find the list with the maximum sum of elements\n max_sum_sublist = max(lists, key=sum)\n return max_sum_sublist", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n # Use the max function with a key to find the list with the highest sum\n return max(lists, key=sum)", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n # Find the list with the maximum sum of elements\n max_list = max(lists, key=sum)\n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n # Find the list with the maximum sum of elements\n max_list = max(lists, key=sum)\n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n # Find the list with the maximum sum of elements\n max_sum_list = max(lists, key=sum)\n return max_sum_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n # Find the list with the maximum sum of elements\n max_sum_sublist = max(lists, key=sum)\n return max_sum_sublist", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n # Calculate the sum of each list and return the list with the maximum sum\n return max(lists, key=sum)", "matching_cluster_idx": 4}]}, "Mbpp/808": {"dps": 68.8157894736842, "dps_norm": 92.5, "pass@1": 100.0, "profiled": [{"solution": "def check_K(tup, k):\n # Check if 'k' is present in the tuple 'tup'\n return k in tup", "matching_cluster_idx": 4}, {"solution": "def check_K(tup, K):\n # Check if K is in the tuple\n return K in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, K):\n # Check if K is in the tuple\n return K in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, K):\n # Check if K is in the tuple\n return K in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n # Check if 'k' is in the tuple 'tup'\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n # Check if k is present in the tuple\n return k in tup", "matching_cluster_idx": 4}, {"solution": "def check_K(tup, K):\n # Check if K is in the tuple\n return K in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, K):\n # Check if K is in the tuple tup\n return K in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(test_tup, K):\n # Check if K is in the tuple\n res = K in test_tup\n return res", "matching_cluster_idx": 4}, {"solution": "def check_K(test_tup, K):\n # Check if K is in the tuple\n res = K in test_tup\n return res", "matching_cluster_idx": 4}, {"solution": "def check_K(test_tup, K):\n # Check if K is in the tuple\n res = K in test_tup\n return res", "matching_cluster_idx": 4}, {"solution": "def check_K(tup, k):\n # Check if k is in the tuple\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n # Check if 'k' is present in the tuple 'tup'\n return k in tup", "matching_cluster_idx": 4}, {"solution": "def check_K(tup, K):\n # Check if K is in the tuple\n return K in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(test_tup, K):\n # Check if K is in the tuple\n res = K in test_tup\n return res", "matching_cluster_idx": 4}, {"solution": "def check_K(tup, K):\n # Check if K is in the tuple\n return K in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n # Check if k is present in the tuple\n return k in tup", "matching_cluster_idx": 4}, {"solution": "def check_K(tup, K):\n # Check if K is in the tuple\n return K in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n # Check if k is present in the tuple\n return k in tup", "matching_cluster_idx": 4}, {"solution": "def check_K(tup, k):\n # Check if k is present in the tuple tup\n return k in tup", "matching_cluster_idx": 5}]}}} \ No newline at end of file diff --git a/results/evalperf/Qwen--Qwen2.5-7B-Instruct_vllm_temp_1.0_evalperf_results.brief.json b/results/evalperf/Qwen--Qwen2.5-7B-Instruct_vllm_temp_1.0_evalperf_results.brief.json new file mode 100644 index 0000000..a481445 --- /dev/null +++ b/results/evalperf/Qwen--Qwen2.5-7B-Instruct_vllm_temp_1.0_evalperf_results.brief.json @@ -0,0 +1 @@ +{"date": "2024-10-19 16:31", "config": {"n_samples": 100, "temperature": 1.0, "min_correct": 10, "max_profile": 20}, "summary": {"dps": 84.68492179229716, "dps_norm": 79.33664874489173, "pass@1": 80.02542372881356}, "eval": {"HumanEval/9": {"dps": 98.81703470031546, "dps_norm": 99.44444444444444, "pass@1": 100.0, "profiled": [{"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n \"\"\"\n if not numbers:\n return []\n \n rolling_maxes = [numbers[0]] # Initialize with the first element\n current_max = numbers[0]\n \n for number in numbers[1:]:\n if number > current_max:\n current_max = number\n rolling_maxes.append(current_max)\n \n return rolling_maxes", "matching_cluster_idx": 8}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n \"\"\"\n if not numbers:\n return []\n \n rolling_max_list = [numbers[0]] # Initialize with the first element\n current_max = numbers[0]\n \n for num in numbers[1:]:\n if num > current_max:\n current_max = num\n rolling_max_list.append(current_max)\n \n return rolling_max_list", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n \n rolling_max_values = [numbers[0]] # Start with the first element as the rolling max\n current_max = numbers[0]\n \n for number in numbers[1:]:\n if number > current_max:\n current_max = number\n rolling_max_values.append(current_max)\n \n return rolling_max_values", "matching_cluster_idx": 8}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n \n rolling_maxes = [numbers[0]] # Initialize with the first element\n max_so_far = numbers[0]\n \n for number in numbers[1:]:\n if number > max_so_far:\n max_so_far = number\n rolling_maxes.append(max_so_far)\n \n return rolling_maxes", "matching_cluster_idx": 8}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n \n rolling_max_list = []\n current_max = numbers[0]\n for num in numbers:\n if num > current_max:\n current_max = num\n rolling_max_list.append(current_max)\n \n return rolling_max_list", "matching_cluster_idx": 8}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n \n rolling_max_list = []\n current_max = numbers[0]\n for number in numbers:\n if number > current_max:\n current_max = number\n rolling_max_list.append(current_max)\n \n return rolling_max_list", "matching_cluster_idx": 8}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n \n :param numbers: List of integers to process\n :return: A list of rolling maximum elements\n \"\"\"\n if not numbers:\n return []\n \n rolling_max_list = [numbers[0]] # Initialize with the first element\n current_max = numbers[0]\n \n for number in numbers[1:]:\n if number > current_max:\n current_max = number\n rolling_max_list.append(current_max)\n \n return rolling_max_list", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n \n rolling_max_list = [numbers[0]] # Initialize the list with the first element\n current_max = numbers[0] # Initialize the current max\n \n for num in numbers[1:]:\n if num > current_max:\n current_max = num\n rolling_max_list.append(current_max)\n \n return rolling_max_list", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n \n rolling_max_list = [numbers[0]] # Initialize the list with the first element\n \n for number in numbers[1:]:\n if number > rolling_max_list[-1]:\n rolling_max_list.append(number)\n else:\n rolling_max_list.append(rolling_max_list[-1])\n \n return rolling_max_list", "matching_cluster_idx": 7}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n \"\"\"\n if not numbers:\n return []\n \n rolling_maxes = [numbers[0]] # Initialize with the first element\n current_max = numbers[0]\n \n for number in numbers[1:]:\n if number > current_max:\n current_max = number\n rolling_maxes.append(current_max)\n \n return rolling_maxes", "matching_cluster_idx": 8}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n \n rolling_maxes = [numbers[0]] # Initialize the list with the first element\n current_max = numbers[0]\n \n for num in numbers[1:]:\n if num > current_max:\n current_max = num\n rolling_maxes.append(current_max)\n \n return rolling_maxes", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n \n rolling_maxes = [numbers[0]] # Initialize with the first element\n max_so_far = numbers[0]\n \n for number in numbers[1:]:\n if number > max_so_far:\n max_so_far = number\n rolling_maxes.append(max_so_far)\n \n return rolling_maxes", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n \n rolling_max_list = []\n current_max = numbers[0]\n for num in numbers:\n if num > current_max:\n current_max = num\n rolling_max_list.append(current_max)\n \n return rolling_max_list", "matching_cluster_idx": 8}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n \"\"\"\n if not numbers:\n return []\n \n rolling_maxes = [numbers[0]] # Initialize with the first element\n current_max = numbers[0]\n \n for num in numbers[1:]:\n if num > current_max:\n current_max = num\n rolling_maxes.append(current_max)\n \n return rolling_maxes", "matching_cluster_idx": 8}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n \"\"\"\n if not numbers:\n return []\n \n rolling_maxes = [numbers[0]] # Initialize the list with the first element\n current_max = numbers[0]\n \n for number in numbers[1:]:\n if number > current_max:\n current_max = number\n rolling_maxes.append(current_max)\n \n return rolling_maxes", "matching_cluster_idx": 8}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n \n rolling_maxes = [numbers[0]] # Initialize the list with the first element\n current_max = numbers[0] # Initialize the current max\n \n for num in numbers[1:]:\n if num > current_max:\n current_max = num\n rolling_maxes.append(current_max)\n \n return rolling_maxes", "matching_cluster_idx": 8}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n \n rolling_maxes = [numbers[0]] # Initialize the result list with the first element\n current_max = numbers[0]\n \n for number in numbers[1:]:\n if number > current_max:\n current_max = number\n rolling_maxes.append(current_max)\n \n return rolling_maxes", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n \n rolling_maxes = [numbers[0]] # Initialize the list with the first element\n current_max = numbers[0] # Keep track of the current maximum\n \n for num in numbers[1:]:\n if num > current_max:\n current_max = num\n rolling_maxes.append(current_max)\n \n return rolling_maxes", "matching_cluster_idx": 8}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n \n rolling_max_list = []\n current_max = numbers[0]\n \n for number in numbers:\n if number > current_max:\n current_max = number\n rolling_max_list.append(current_max)\n \n return rolling_max_list", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n \n rolling_maxes = [numbers[0]]\n current_max = numbers[0]\n \n for number in numbers[1:]:\n if number > current_max:\n current_max = number\n rolling_maxes.append(current_max)\n \n return rolling_maxes", "matching_cluster_idx": 8}]}, "HumanEval/0": {"dps": 52.325581395348834, "dps_norm": 57.142857142857146, "pass@1": 100.0, "profiled": [{"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n \"\"\"\n # Sort the list to ensure that the closest numbers will be adjacent\n numbers.sort()\n \n # Iterate through the sorted list and check the difference between consecutive elements\n for i in range(len(numbers) - 1):\n if numbers[i + 1] - numbers[i] < threshold:\n return True\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n numbers.sort()\n for i in range(1, len(numbers)):\n if numbers[i] - numbers[i - 1] < threshold:\n return True\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n numbers.sort()\n for i in range(1, len(numbers)):\n if numbers[i] - numbers[i-1] < threshold:\n return True\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n \"\"\"\n if not numbers or len(numbers) < 2:\n return False\n \n # Sort the list to make it easier to find close elements\n numbers.sort()\n \n for i in range(1, len(numbers)):\n if numbers[i] - numbers[i - 1] < threshold:\n return True\n \n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n \"\"\"\n # Sort the list to bring close numbers next to each other\n numbers.sort()\n \n # Iterate through the sorted list to find any two consecutive elements\n # that are closer than the threshold\n for i in range(1, len(numbers)):\n if numbers[i] - numbers[i - 1] < threshold:\n return True\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\"\n Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n \n :param numbers: List of float numbers\n :param threshold: A float representing the threshold value\n :return: True if there are two numbers closer than the threshold, otherwise False\n \"\"\"\n # First, sort the list to make the closer elements adjacent\n sorted_numbers = sorted(numbers)\n \n # Iterate through the sorted list to find if any two adjacent elements are within the threshold\n for i in range(len(sorted_numbers) - 1):\n if sorted_numbers[i + 1] - sorted_numbers[i] < threshold:\n return True\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n \"\"\"\n # Sort the list to bring close numbers next to each other\n numbers.sort()\n \n # Iterate through the list and check the difference between adjacent elements\n for i in range(1, len(numbers)):\n if numbers[i] - numbers[i - 1] < threshold:\n return True\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n \"\"\"\n numbers.sort() # Sort the list of numbers\n for i in range(1, len(numbers)):\n if numbers[i] - numbers[i - 1] < threshold:\n return True\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n \"\"\"\n # Sort the list first\n numbers.sort()\n \n # Check the difference between adjacent elements\n for i in range(1, len(numbers)):\n if numbers[i] - numbers[i - 1] < threshold:\n return True\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\"\n Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n \n Args:\n numbers: A list of floating point numbers.\n threshold: A positive floating point number representing the threshold.\n \n Returns:\n True if there are two numbers in the list closer to each other than the threshold, False otherwise.\n \"\"\"\n if len(numbers) < 2:\n return False\n \n # Sort the list to make the search for close elements easier\n numbers.sort()\n \n # Iterate through the sorted list and check the distance between consecutive elements\n for i in range(1, len(numbers)):\n if numbers[i] - numbers[i - 1] < threshold:\n return True\n \n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n \"\"\"\n # Sort the list first\n sorted_numbers = sorted(numbers)\n \n # Iterate through the sorted list and check the difference between consecutive elements\n for i in range(1, len(sorted_numbers)):\n if sorted_numbers[i] - sorted_numbers[i - 1] < threshold:\n return True\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n \"\"\"\n if not numbers:\n return False\n\n numbers.sort()\n\n for i in range(1, len(numbers)):\n if numbers[i] - numbers[i - 1] < threshold:\n return True\n\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n \"\"\"\n numbers.sort()\n for i in range(len(numbers) - 1):\n if numbers[i + 1] - numbers[i] < threshold:\n return True\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n numbers.sort()\n for i in range(len(numbers) - 1):\n if numbers[i + 1] - numbers[i] < threshold:\n return True\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n numbers.sort()\n for i in range(1, len(numbers)):\n if numbers[i] - numbers[i-1] < threshold:\n return True\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n if len(numbers) < 2:\n return False\n\n numbers.sort()\n\n for i in range(1, len(numbers)):\n if numbers[i] - numbers[i - 1] < threshold:\n return True\n\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n \"\"\"\n # Sort the list to bring close numbers next to each other\n numbers.sort()\n \n # Iterate through the sorted list and check the difference between consecutive elements\n for i in range(len(numbers) - 1):\n if numbers[i + 1] - numbers[i] < threshold:\n return True\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n \"\"\"\n # Sort the list to bring close numbers next to each other\n numbers.sort()\n \n # Check the difference between consecutive elements\n for i in range(1, len(numbers)):\n if numbers[i] - numbers[i - 1] < threshold:\n return True\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n \"\"\"\n # Sort the list of numbers first\n numbers.sort()\n \n # Iterate through the sorted list to find any two elements closer than the threshold\n for i in range(1, len(numbers)):\n if numbers[i] - numbers[i - 1] < threshold:\n return True\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n \"\"\"\n # Sort the list to make comparison easier\n numbers.sort()\n \n # Iterate through the list and check the difference between consecutive elements\n for i in range(1, len(numbers)):\n if numbers[i] - numbers[i - 1] < threshold:\n return True\n return False", "matching_cluster_idx": 3}]}, "HumanEval/4": {"dps": 34.129746835443036, "dps_norm": 75.83333333333334, "pass@1": 98.0, "profiled": [{"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n # Calculate the mean of the dataset\n mean_value = sum(numbers) / len(numbers)\n \n # Calculate the absolute differences from the mean\n absolute_diffs = [abs(x - mean_value) for x in numbers]\n \n # Calculate the average of these absolute differences\n mad = sum(absolute_diffs) / len(numbers)\n \n return mad", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n \"\"\"\n # Calculate the mean of the numbers\n mean_value = sum(numbers) / len(numbers)\n \n # Calculate the absolute deviations from the mean\n absolute_deviations = [abs(x - mean_value) for x in numbers]\n \n # Calculate the mean of the absolute deviations\n mad = sum(absolute_deviations) / len(numbers)\n \n return mad", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n >>> mean_absolute_deviation([2.0, 4.0, 8.0, 16.0])\n 4.5\n \"\"\"\n # Calculate the mean of the dataset\n mean_value = sum(numbers) / len(numbers)\n # Calculate the sum of the absolute differences from the mean\n absolute_diff_sum = sum(abs(x - mean_value) for x in numbers)\n # Calculate the mean absolute deviation\n mad = absolute_diff_sum / len(numbers)\n return mad", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n \"\"\"\n # Calculate the mean of the dataset\n mean_value = sum(numbers) / len(numbers)\n \n # Calculate the absolute differences from the mean\n absolute_differences = [abs(x - mean_value) for x in numbers]\n \n # Calculate the mean of the absolute differences\n mad = sum(absolute_differences) / len(numbers)\n \n return mad", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\"\n For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if not numbers:\n return 0.0\n \n mean_value = sum(numbers) / len(numbers)\n mad = sum(abs(x - mean_value) for x in numbers) / len(numbers)\n return mad", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n \"\"\"\n # Calculate the mean of the dataset\n mean_value = sum(numbers) / len(numbers)\n \n # Calculate the absolute differences from the mean\n absolute_differences = [abs(x - mean_value) for x in numbers]\n \n # Calculate the average of these absolute differences\n mad_value = sum(absolute_differences) / len(numbers)\n \n return mad_value", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n \"\"\"\n # Calculate the mean of the dataset\n mean_value = sum(numbers) / len(numbers)\n \n # Calculate the absolute differences from the mean\n absolute_diffs = [abs(x - mean_value) for x in numbers]\n \n # Calculate the average of the absolute differences\n mad = sum(absolute_diffs) / len(absolute_diffs)\n \n return mad", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\"\n For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n\n Args:\n numbers (List[float]): A list of numbers for which to calculate MAD.\n\n Returns:\n float: The calculated Mean Absolute Deviation.\n\n Examples:\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n # Calculate the mean of the dataset\n mean_value = sum(numbers) / len(numbers)\n \n # Calculate the sum of absolute differences from the mean\n sum_of_abs_differences = sum(abs(x - mean_value) for x in numbers)\n \n # Calculate the Mean Absolute Deviation\n mad = sum_of_abs_differences / len(numbers)\n \n return mad", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n \"\"\"\n # Calculate the mean of the dataset\n mean_value = sum(numbers) / len(numbers)\n \n # Calculate the absolute differences from the mean\n absolute_differences = [abs(x - mean_value) for x in numbers]\n \n # Calculate the average of these absolute differences\n mad = sum(absolute_differences) / len(numbers)\n \n return mad", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\"\n For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n \"\"\"\n # Calculate the mean of the dataset\n mean_value = sum(numbers) / len(numbers)\n \n # Calculate the absolute differences from the mean\n absolute_differences = [abs(x - mean_value) for x in numbers]\n \n # Calculate the average of the absolute differences\n mad = sum(absolute_differences) / len(numbers)\n \n return mad", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\"\n For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n # Calculate the mean of the dataset\n mean_value = sum(numbers) / len(numbers)\n \n # Calculate the absolute differences from the mean\n absolute_diffs = [abs(x - mean_value) for x in numbers]\n \n # Calculate the average of these absolute differences\n mad = sum(absolute_diffs) / len(numbers)\n \n return mad", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\"\n For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n # Calculate the mean of the dataset\n mean_value = sum(numbers) / len(numbers)\n \n # Calculate the absolute deviations from the mean\n absolute_deviations = [abs(x - mean_value) for x in numbers]\n \n # Calculate the mean of the absolute deviations\n mad = sum(absolute_deviations) / len(numbers)\n \n return mad", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n \"\"\"\n if not numbers:\n return 0.0\n \n mean_value = sum(numbers) / len(numbers)\n mad = sum(abs(x - mean_value) for x in numbers) / len(numbers)\n return mad", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n # Calculate the mean of the dataset\n mean_value = sum(numbers) / len(numbers)\n \n # Calculate the absolute differences between each element and the mean\n absolute_differences = [abs(x - mean_value) for x in numbers]\n \n # Calculate the average of these absolute differences\n mad = sum(absolute_differences) / len(numbers)\n \n return mad", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\"\n For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n \"\"\"\n if not numbers:\n return 0.0\n \n # Calculate the mean of the dataset\n mean_value = sum(numbers) / len(numbers)\n \n # Calculate the sum of absolute differences from the mean\n mad_sum = sum(abs(x - mean_value) for x in numbers)\n \n # Calculate the mean absolute deviation\n mad = mad_sum / len(numbers)\n \n return mad", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\"\n For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n # Calculate the mean of the dataset\n mean_value = sum(numbers) / len(numbers)\n \n # Calculate the absolute differences between each element and the mean\n absolute_diffs = [abs(x - mean_value) for x in numbers]\n \n # Calculate the average of these absolute differences\n mad = sum(absolute_diffs) / len(numbers)\n \n return mad", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n \"\"\"\n # Calculate the mean of the dataset\n mean_value = sum(numbers) / len(numbers)\n \n # Calculate the absolute deviations from the mean\n absolute_deviations = [abs(x - mean_value) for x in numbers]\n \n # Calculate the mean of these absolute deviations\n mad = sum(absolute_deviations) / len(numbers)\n \n return mad", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\"\n For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n # Calculate the mean of the dataset\n mean_value = sum(numbers) / len(numbers)\n \n # Calculate the absolute differences between each element and the mean\n absolute_differences = [abs(x - mean_value) for x in numbers]\n \n # Calculate the average of the absolute differences\n mad_value = sum(absolute_differences) / len(numbers)\n \n return mad_value", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n \"\"\"\n # Calculate the mean of the dataset\n mean_value = sum(numbers) / len(numbers)\n \n # Calculate the absolute differences from the mean\n absolute_differences = [abs(x - mean_value) for x in numbers]\n \n # Calculate the average of these absolute differences\n mad = sum(absolute_differences) / len(absolute_differences)\n \n return mad", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n \"\"\"\n # Calculate the mean of the dataset\n mean_value = sum(numbers) / len(numbers)\n \n # Calculate the absolute differences from the mean\n absolute_diffs = [abs(x - mean_value) for x in numbers]\n \n # Calculate the average of these absolute differences\n mad = sum(absolute_diffs) / len(absolute_diffs)\n \n return mad", "matching_cluster_idx": 3}]}, "HumanEval/16": {"dps": 45.73643410852713, "dps_norm": 88.88888888888889, "pass@1": 100.0, "profiled": [{"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\"\n Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lowercase to ignore case and then use a set to find distinct characters\n distinct_chars = set(string.lower())\n # Return the number of distinct characters\n return len(distinct_chars)", "matching_cluster_idx": 7}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\"\n Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lowercase to ignore case differences\n lowercase_string = string.lower()\n # Use a set to store distinct characters\n distinct_chars = set(lowercase_string)\n # Return the number of distinct characters\n return len(distinct_chars)", "matching_cluster_idx": 7}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\"\n Given a string, find out how many distinct characters (regardless of case) does it consist of.\n \n Args:\n string (str): The input string to analyze.\n \n Returns:\n int: The number of distinct characters in the string, case-insensitively.\n \n Examples:\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lowercase to ignore case sensitivity and use a set to store unique characters\n unique_chars = set(string.lower())\n # Return the number of unique characters\n return len(unique_chars)", "matching_cluster_idx": 7}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\"\n Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lowercase to ignore case and use a set to store unique characters\n unique_chars = set(string.lower())\n # Return the number of unique characters\n return len(unique_chars)", "matching_cluster_idx": 7}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\"\n Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lowercase to ignore case differences\n lower_string = string.lower()\n # Use a set to store unique characters\n unique_characters = set(lower_string)\n # Return the number of unique characters\n return len(unique_characters)", "matching_cluster_idx": 7}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\"\n Given a string, find out how many distinct characters (regardless of case) it consists of.\n \n :param string: Input string to check for distinct characters.\n :return: Number of distinct characters in the string, case-insensitively.\n \n Example:\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lowercase to ignore case differences\n lower_case_string = string.lower()\n # Use a set to store unique characters\n unique_chars = set(lower_case_string)\n # Return the number of unique characters\n return len(unique_chars)", "matching_cluster_idx": 7}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\"\n Given a string, find out how many distinct characters (regardless of case) it consists of.\n \n :param string: Input string to analyze\n :return: Number of distinct characters in the string, case-insensitive\n \"\"\"\n # Convert the string to lowercase to ignore case differences\n lower_string = string.lower()\n # Use a set to store unique characters\n unique_chars = set(lower_string)\n # Return the number of unique characters\n return len(unique_chars)", "matching_cluster_idx": 7}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\"\n Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lowercase to ignore case and use a set to store unique characters\n unique_chars = set(string.lower())\n # Return the number of unique characters\n return len(unique_chars)", "matching_cluster_idx": 7}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lowercase to ignore case and then convert it to a set of characters\n # The length of the set is the number of distinct characters\n return len(set(string.lower()))", "matching_cluster_idx": 7}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\"\n Given a string, find out how many distinct characters (regardless of case) does it consist of\n \n :param string: The input string to analyze\n :return: The number of distinct characters in the string, case-insensitive\n \"\"\"\n # Convert the string to lowercase to ignore case differences\n lower_string = string.lower()\n # Use a set to store unique characters\n unique_chars = set(lower_string)\n # Return the number of unique characters\n return len(unique_chars)", "matching_cluster_idx": 7}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\"\n Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lowercase to ignore case differences\n lower_string = string.lower()\n # Create a set to store distinct characters\n distinct_chars = set(lower_string)\n # Return the number of distinct characters\n return len(distinct_chars)", "matching_cluster_idx": 7}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lowercase to ignore case sensitivity\n lower_string = string.lower()\n # Use a set to store unique characters\n unique_chars = set(lower_string)\n # Return the count of unique characters\n return len(unique_chars)", "matching_cluster_idx": 7}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\"\n Given a string, find out how many distinct characters (regardless of case) does it consist of\n \n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lowercase to ignore case sensitivity and use a set to find unique characters\n unique_chars = set(string.lower())\n # Return the number of unique characters\n return len(unique_chars)", "matching_cluster_idx": 7}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lowercase to ignore case and then use a set to find distinct characters\n distinct_chars = set(string.lower())\n # The number of distinct characters is the size of the set\n return len(distinct_chars)", "matching_cluster_idx": 7}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lowercase to ignore case differences and then use a set to find unique characters\n return len(set(string.lower()))", "matching_cluster_idx": 7}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lowercase to ignore case and then convert it to a set to remove duplicates\n distinct_chars = set(string.lower())\n # Return the number of distinct characters\n return len(distinct_chars)", "matching_cluster_idx": 7}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lowercase to ignore case sensitivity and then use a set to find distinct characters\n distinct_chars = set(string.lower())\n # Return the number of distinct characters\n return len(distinct_chars)", "matching_cluster_idx": 7}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\"\n Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lowercase to ignore case differences\n lower_string = string.lower()\n # Use a set to store unique characters\n unique_chars = set(lower_string)\n # Return the number of unique characters\n return len(unique_chars)", "matching_cluster_idx": 7}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\"\n Given a string, find out how many distinct characters (regardless of case) does it consist of\n \n :param string: Input string to be analyzed\n :return: Number of distinct characters in the string, case-insensitive\n \n Example:\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lowercase to ignore case and use a set to store unique characters\n unique_chars = set(string.lower())\n # Return the number of unique characters\n return len(unique_chars)", "matching_cluster_idx": 7}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\"\n Given a string, find out how many distinct characters (regardless of case) does it consist of\n \n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lowercase to ignore case differences\n lower_string = string.lower()\n # Use a set to store unique characters\n unique_chars = set(lower_string)\n # The number of unique characters is the size of the set\n return len(unique_chars)", "matching_cluster_idx": 7}]}, "HumanEval/20": {"dps": 96.05326876513317, "dps_norm": 97.22222222222223, "pass@1": 97.0, "profiled": [{"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\"\n From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n \"\"\"\n # Sort the list to make it easier to find the closest numbers\n sorted_numbers = sorted(numbers)\n \n # Initialize the smallest difference to a large value\n smallest_diff = float('inf')\n closest_pair = (None, None)\n \n # Iterate through adjacent pairs in the sorted list\n for i in range(len(sorted_numbers) - 1):\n current_diff = sorted_numbers[i+1] - sorted_numbers[i]\n if current_diff < smallest_diff:\n smallest_diff = current_diff\n closest_pair = (sorted_numbers[i], sorted_numbers[i+1])\n \n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n # Sort the list to ensure that we can easily find the closest pair\n sorted_numbers = sorted(numbers)\n closest_pair = sorted_numbers[0], sorted_numbers[1]\n min_difference = abs(sorted_numbers[1] - sorted_numbers[0])\n \n # Iterate through the sorted list to find the pair with the minimum difference\n for i in range(1, len(sorted_numbers) - 1):\n current_difference = abs(sorted_numbers[i + 1] - sorted_numbers[i])\n if current_difference < min_difference:\n min_difference = current_difference\n closest_pair = sorted_numbers[i], sorted_numbers[i + 1]\n \n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n \"\"\"\n # Sort the list to make it easier to find the closest pair\n numbers.sort()\n \n # Initialize variables to store the closest pair and the smallest difference\n closest_pair = (numbers[0], numbers[1])\n smallest_difference = abs(numbers[1] - numbers[0])\n \n # Iterate through the sorted list to find the closest pair\n for i in range(len(numbers) - 1):\n current_difference = abs(numbers[i + 1] - numbers[i])\n if current_difference < smallest_difference:\n smallest_difference = current_difference\n closest_pair = (numbers[i], numbers[i + 1])\n \n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n # Sort the list to make finding the closest elements easier\n numbers.sort()\n \n # Initialize variables to keep track of the closest pair\n closest_diff = float('inf')\n closest_pair = (0, 0)\n \n # Iterate through the list to find the pair with the smallest difference\n for i in range(len(numbers) - 1):\n diff = numbers[i + 1] - numbers[i]\n if diff < closest_diff:\n closest_diff = diff\n closest_pair = (numbers[i], numbers[i + 1])\n \n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n \"\"\"\n # Sort the list to make finding the closest numbers easier\n sorted_numbers = sorted(numbers)\n \n # Initialize variables to store the closest pair\n closest_pair = (sorted_numbers[0], sorted_numbers[1])\n min_diff = sorted_numbers[1] - sorted_numbers[0]\n \n # Iterate through the list to find the pair with the smallest difference\n for i in range(len(sorted_numbers) - 1):\n current_diff = sorted_numbers[i + 1] - sorted_numbers[i]\n if current_diff < min_diff:\n min_diff = current_diff\n closest_pair = (sorted_numbers[i], sorted_numbers[i + 1])\n \n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\"\n From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n \n :param numbers: List of floating point numbers\n :return: A tuple containing two closest numbers in ascending order\n \"\"\"\n # Sort the list to ensure that numbers are in ascending order\n numbers.sort()\n \n # Initialize the smallest difference to a very high value\n min_diff = float('inf')\n # Initialize the closest pair\n closest_pair = (0.0, 0.0)\n \n # Iterate through the list to find the two closest numbers\n for i in range(len(numbers) - 1):\n current_diff = numbers[i+1] - numbers[i]\n if current_diff < min_diff:\n min_diff = current_diff\n closest_pair = (numbers[i], numbers[i+1])\n \n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n # Sort the list to make finding the closest elements easier\n numbers.sort()\n \n # Initialize variables to store the closest pair and the smallest difference\n closest_pair = (numbers[0], numbers[1])\n smallest_difference = abs(numbers[1] - numbers[0])\n \n # Iterate through the sorted list to find the pair with the smallest difference\n for i in range(1, len(numbers) - 1):\n current_difference = abs(numbers[i + 1] - numbers[i])\n if current_difference < smallest_difference:\n smallest_difference = current_difference\n closest_pair = (numbers[i], numbers[i + 1])\n \n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\"\n From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n \n :param numbers: List of floating point numbers.\n :return: A tuple containing the two closest numbers.\n \n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n numbers.sort() # Sort the list to bring the closest numbers next to each other\n min_diff = float('inf')\n closest_pair = None\n \n # Iterate through the sorted list to find the smallest difference\n for i in range(len(numbers) - 1):\n diff = numbers[i+1] - numbers[i]\n if diff < min_diff:\n min_diff = diff\n closest_pair = (numbers[i], numbers[i+1])\n \n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n \"\"\"\n # Check that there are at least two elements in the list\n if len(numbers) < 2:\n raise ValueError(\"The list must contain at least two elements.\")\n \n # Sort the list to ensure that the closest elements will be adjacent\n sorted_numbers = sorted(numbers)\n \n # Initialize variables to store the closest pair and their difference\n closest_pair = (sorted_numbers[0], sorted_numbers[1])\n smallest_diff = abs(sorted_numbers[1] - sorted_numbers[0])\n \n # Iterate through the sorted list and find the pair with the smallest difference\n for i in range(1, len(sorted_numbers) - 1):\n current_diff = abs(sorted_numbers[i + 1] - sorted_numbers[i])\n if current_diff < smallest_diff:\n smallest_diff = current_diff\n closest_pair = (sorted_numbers[i], sorted_numbers[i + 1])\n \n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n # Sort the list to make finding the closest elements easier\n sorted_numbers = sorted(numbers)\n # Initialize the smallest difference to a large value\n min_diff = float('inf')\n # Initialize the closest pair\n closest_pair = (0, 0)\n \n # Iterate through adjacent elements in the sorted list\n for i in range(len(sorted_numbers) - 1):\n # Calculate the difference between adjacent elements\n current_diff = sorted_numbers[i + 1] - sorted_numbers[i]\n # Update the closest pair if the current difference is smaller\n if current_diff < min_diff:\n min_diff = current_diff\n closest_pair = (sorted_numbers[i], sorted_numbers[i + 1])\n \n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n # Sort the list to ensure that we can find the closest numbers by checking adjacent elements\n sorted_numbers = sorted(numbers)\n \n # Initialize the closest pair with the first two elements\n closest_pair = (sorted_numbers[0], sorted_numbers[1])\n smallest_difference = sorted_numbers[1] - sorted_numbers[0]\n \n # Iterate through the sorted list to find the pair with the smallest difference\n for i in range(1, len(sorted_numbers) - 1):\n current_difference = sorted_numbers[i + 1] - sorted_numbers[i]\n if current_difference < smallest_difference:\n smallest_difference = current_difference\n closest_pair = (sorted_numbers[i], sorted_numbers[i + 1])\n \n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n \"\"\"\n # Sort the list to make finding the closest elements easier\n sorted_numbers = sorted(numbers)\n \n # Initialize the closest pair with the first two elements\n closest_pair = (sorted_numbers[0], sorted_numbers[1])\n min_difference = sorted_numbers[1] - sorted_numbers[0]\n \n # Iterate through the list to find the closest pair\n for i in range(1, len(sorted_numbers) - 1):\n current_difference = sorted_numbers[i + 1] - sorted_numbers[i]\n if current_difference < min_difference:\n min_difference = current_difference\n closest_pair = (sorted_numbers[i], sorted_numbers[i + 1])\n \n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n # Sort the list to make finding the closest elements easier\n sorted_numbers = sorted(numbers)\n \n # Initialize the minimum difference to a large number\n min_diff = float('inf')\n # Initialize the closest pair as (None, None)\n closest_pair = (None, None)\n \n # Iterate through the sorted list to find the closest pair\n for i in range(len(sorted_numbers) - 1):\n current_diff = sorted_numbers[i+1] - sorted_numbers[i]\n if current_diff < min_diff:\n min_diff = current_diff\n closest_pair = (sorted_numbers[i], sorted_numbers[i+1])\n \n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n \"\"\"\n # Sort the list to make it easier to find the closest elements\n sorted_numbers = sorted(numbers)\n \n # Initialize variables to store the closest pair and their minimum difference\n closest_a, closest_b = sorted_numbers[0], sorted_numbers[1]\n min_diff = sorted_numbers[1] - sorted_numbers[0]\n \n # Iterate through the list to find the pair with the smallest difference\n for i in range(len(sorted_numbers) - 1):\n current_diff = sorted_numbers[i+1] - sorted_numbers[i]\n if current_diff < min_diff:\n min_diff = current_diff\n closest_a, closest_b = sorted_numbers[i], sorted_numbers[i+1]\n \n return closest_a, closest_b", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n \"\"\"\n # Sort the list to ensure that all potential closest pairs are adjacent\n sorted_numbers = sorted(numbers)\n \n # Initialize variables to store the closest pair of numbers and their minimum difference\n closest_pair = (sorted_numbers[0], sorted_numbers[1])\n min_difference = abs(sorted_numbers[1] - sorted_numbers[0])\n \n # Iterate through the sorted list to find the pair with the minimum difference\n for i in range(1, len(sorted_numbers) - 1):\n current_difference = abs(sorted_numbers[i + 1] - sorted_numbers[i])\n if current_difference < min_difference:\n min_difference = current_difference\n closest_pair = (sorted_numbers[i], sorted_numbers[i + 1])\n \n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n # Sort the list to ensure we can find the closest pair by checking adjacent elements\n sorted_numbers = sorted(numbers)\n closest_pair = (sorted_numbers[0], sorted_numbers[1])\n smallest_difference = sorted_numbers[1] - sorted_numbers[0]\n\n # Iterate through the list to find the pair with the smallest difference\n for i in range(1, len(sorted_numbers) - 1):\n current_difference = sorted_numbers[i + 1] - sorted_numbers[i]\n if current_difference < smallest_difference:\n smallest_difference = current_difference\n closest_pair = (sorted_numbers[i], sorted_numbers[i + 1])\n\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n \"\"\"\n if len(numbers) < 2:\n raise ValueError(\"The list must contain at least two elements.\")\n \n numbers.sort()\n closest_pair = numbers[0], numbers[1]\n smallest_diff = abs(numbers[1] - numbers[0])\n \n for i in range(1, len(numbers) - 1):\n current_diff = abs(numbers[i + 1] - numbers[i])\n if current_diff < smallest_diff:\n smallest_diff = current_diff\n closest_pair = numbers[i], numbers[i + 1]\n \n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n \"\"\"\n # Check if the input list has at least two elements\n if len(numbers) < 2:\n raise ValueError(\"The list must contain at least two elements\")\n \n # Sort the list to make finding the closest elements easier\n sorted_numbers = sorted(numbers)\n \n # Initialize variables to keep track of the closest pair and their minimum difference\n min_diff = float('inf')\n closest_pair = (0, 0)\n \n # Iterate through adjacent pairs in the sorted list to find the closest pair\n for i in range(len(sorted_numbers) - 1):\n current_diff = sorted_numbers[i + 1] - sorted_numbers[i]\n if current_diff < min_diff:\n min_diff = current_diff\n closest_pair = (sorted_numbers[i], sorted_numbers[i + 1])\n \n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n \"\"\"\n # Sort the list to ensure that numbers are in ascending order\n sorted_numbers = sorted(numbers)\n \n # Initialize variables to store the closest pair and the smallest difference\n closest_pair = (sorted_numbers[0], sorted_numbers[1])\n min_difference = abs(sorted_numbers[1] - sorted_numbers[0])\n \n # Iterate through the sorted list to find the pair with the smallest difference\n for i in range(len(sorted_numbers) - 1):\n current_difference = abs(sorted_numbers[i + 1] - sorted_numbers[i])\n if current_difference < min_difference:\n min_difference = current_difference\n closest_pair = (sorted_numbers[i], sorted_numbers[i + 1])\n \n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n \"\"\"\n # Initialize the smallest difference to a large number\n smallest_diff = float('inf')\n # Initialize the closest pair to an empty tuple\n closest_pair = ()\n \n # Iterate over each pair of numbers\n for i in range(len(numbers) - 1):\n for j in range(i + 1, len(numbers)):\n # Calculate the absolute difference\n diff = abs(numbers[i] - numbers[j])\n # Update the closest pair if this pair is closer\n if diff < smallest_diff:\n smallest_diff = diff\n if numbers[i] < numbers[j]:\n closest_pair = (numbers[i], numbers[j])\n else:\n closest_pair = (numbers[j], numbers[i])\n \n return closest_pair", "matching_cluster_idx": 3}]}, "HumanEval/24": {"dps": 59.31972789115647, "dps_norm": 25.0, "pass@1": 100.0, "profiled": [{"solution": "def largest_divisor(n: int) -> int:\n \"\"\"\n For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n # Start checking from n-1 down to 1\n for i in range(n-1, 0, -1):\n if n % i == 0:\n return i\n return 1 # If no divisor is found, return 1 (n is prime or n=1)", "matching_cluster_idx": 0}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\"\n For a given number n, find the largest number that divides n evenly, smaller than n\n \n :param n: The given integer number\n :return: The largest divisor of n that is smaller than n\n \"\"\"\n # Start checking from n-1 downwards\n for i in range(n - 1, 0, -1):\n if n % i == 0:\n return i\n return 1 # If no divisor is found, return 1 (every number is divisible by 1)", "matching_cluster_idx": 1}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\"\n For a given number n, find the largest number that divides n evenly, smaller than n\n \n :param n: The number to find the largest divisor for\n :return: The largest divisor of n that is smaller than n\n \"\"\"\n for i in range(n - 1, 0, -1):\n if n % i == 0:\n return i\n return 1 # If no divisor is found, return 1 (every number is divisible by 1)", "matching_cluster_idx": 1}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\"\n For a given number n, find the largest number that divides n evenly, smaller than n.\n\n Args:\n n (int): The number to find the divisor for.\n\n Returns:\n int: The largest divisor of n smaller than n.\n\n Example:\n >>> largest_divisor(15)\n 5\n \"\"\"\n # Start checking from n-1 down to 1\n for i in range(n - 1, 0, -1):\n if n % i == 0:\n return i\n return 1 # In case no divisor is found, return 1 (n is prime)", "matching_cluster_idx": 1}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\"\n For a given number n, find the largest number that divides n evenly, smaller than n\n \n >>> largest_divisor(15)\n 5\n >>> largest_divisor(100)\n 50\n >>> largest_divisor(37)\n 1\n \"\"\"\n # Start checking from n-1 downwards\n for i in range(n-1, 1, -1):\n if n % i == 0:\n return i\n return 1 # This case will only be reached if n is 1", "matching_cluster_idx": 1}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\"\n For a given number n, find the largest number that divides n evenly, smaller than n.\n \n :param n: An integer for which the largest divisor smaller than n is to be found.\n :return: The largest divisor of n that is smaller than n.\n \n Examples:\n >>> largest_divisor(15)\n 5\n >>> largest_divisor(28)\n 14\n >>> largest_divisor(13)\n 1 # 13 is a prime number, so its largest divisor smaller than itself is 1\n \"\"\"\n # Start checking from n-1 down to 1\n for i in range(n-1, 0, -1):\n if n % i == 0:\n return i\n return 1 # If no divisor is found, return 1 (for prime numbers)", "matching_cluster_idx": 1}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n # Start checking from n-1 down to 1\n for i in range(n - 1, 0, -1):\n if n % i == 0:\n return i\n return 1 # If no divisor is found, return 1 (every number is divisible by 1)", "matching_cluster_idx": 1}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\"\n For a given number n, find the largest number that divides n evenly, smaller than n\n \n :param n: An integer number\n :return: The largest divisor of n smaller than n\n \"\"\"\n for i in range(n - 1, 1, -1):\n if n % i == 0:\n return i\n return 1 # Return 1 if n is 1 or no other divisor is found", "matching_cluster_idx": 1}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n # Start checking from n-1 down to 1\n for i in range(n-1, 0, -1):\n if n % i == 0:\n return i\n return 1 # If no divisor is found, return 1 (n is prime or 1)", "matching_cluster_idx": 1}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\"\n For a given number n, find the largest number that divides n evenly, smaller than n.\n \n :param n: An integer for which to find the largest divisor\n :return: The largest divisor of n, smaller than n\n \n Example:\n >>> largest_divisor(15)\n 5\n \"\"\"\n # Start checking from n-1 down to 1\n for i in range(n-1, 0, -1):\n if n % i == 0:\n return i\n return 1 # n is prime and its only divisors are 1 and itself", "matching_cluster_idx": 0}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n \"\"\"\n for divisor in range(n - 1, 0, -1):\n if n % divisor == 0:\n return divisor\n return 1 # If no divisor is found, return 1 (n is prime or 1)", "matching_cluster_idx": 0}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\"\n For a given number n, find the largest number that divides n evenly, smaller than n\n \n :param n: An integer to find the largest divisor for\n :return: The largest divisor of n that is smaller than n\n \n >>> largest_divisor(15)\n 5\n \"\"\"\n for i in range(n // 2, 0, -1):\n if n % i == 0:\n return i\n return 1 # In case n is 1, the largest divisor is 1 itself", "matching_cluster_idx": 4}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\"\n For a given number n, find the largest number that divides n evenly, smaller than n\n\n Args:\n n (int): The given number\n\n Returns:\n int: The largest divisor of n smaller than n\n\n Example:\n >>> largest_divisor(15)\n 5\n \"\"\"\n # Start checking from n-1 since we want the largest divisor smaller than n\n for potential_divisor in range(n-1, 1, -1):\n if n % potential_divisor == 0:\n return potential_divisor\n return 1 # If no divisor is found, return 1 (since every number is divisible by 1)", "matching_cluster_idx": 1}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n \"\"\"\n for i in range(n - 1, 0, -1):\n if n % i == 0:\n return i\n return 1 # In case no divisor is found, return 1 (which is a divisor of all numbers)", "matching_cluster_idx": 1}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\"\n For a given number n, find the largest number that divides n evenly, smaller than n\n \n >>> largest_divisor(15)\n 5\n \"\"\"\n # Start from n-1 and go down to 1 to find the largest divisor\n for i in range(n - 1, 0, -1):\n if n % i == 0:\n return i\n return 1 # In case n is 1, there is no divisor smaller than n", "matching_cluster_idx": 0}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n \"\"\"\n # Start checking from n-1 down to 1\n for i in range(n-1, 0, -1):\n if n % i == 0:\n return i\n return 1 # If no divisor found, return 1 (though this case should not happen as per the problem statement)", "matching_cluster_idx": 1}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\"\n For a given number n, find the largest number that divides n evenly, smaller than n\n \n Args:\n n (int): The given number\n \n Returns:\n int: The largest divisor of n smaller than n\n \"\"\"\n for i in range(n - 1, 0, -1):\n if n % i == 0:\n return i\n return 1 # In case there is no divisor other than 1, return 1", "matching_cluster_idx": 0}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\"\n For a given number n, find the largest number that divides n evenly, smaller than n\n \n :param n: The number to find the divisor for\n :return: The largest divisor of n smaller than n\n \"\"\"\n for i in range(n - 1, 0, -1):\n if n % i == 0:\n return i\n return 1 # If no divisor found, return 1 (n is prime)", "matching_cluster_idx": 1}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\"\n For a given number n, find the largest number that divides n evenly, smaller than n.\n \n :param n: An integer for which to find the largest divisor\n :return: The largest integer that is a divisor of n, and is smaller than n\n \n >>> largest_divisor(15)\n 5\n \"\"\"\n # Start from n-1 and go down to 1 to find the largest divisor\n for i in range(n-1, 0, -1):\n if n % i == 0:\n return i\n return 1 # If no divisor is found, return 1 (n is prime or 1)", "matching_cluster_idx": 0}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\"\n For a given number n, find the largest number that divides n evenly, smaller than n.\n\n :param n: The given number.\n :return: The largest divisor of n that is smaller than n.\n \"\"\"\n for i in range(n // 2, 0, -1):\n if n % i == 0:\n return i\n return 1 # Every number is divisible by 1", "matching_cluster_idx": 4}]}, "HumanEval/26": {"dps": 88.8, "dps_norm": 91.25, "pass@1": 57.0, "profiled": [{"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n # Create a frequency dictionary\n frequency = {}\n for num in numbers:\n if num in frequency:\n frequency[num] += 1\n else:\n frequency[num] = 1\n \n # Filter out duplicates\n result = [num for num in numbers if frequency[num] == 1]\n \n return result", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n \"\"\"\n # Track seen numbers and their counts\n seen = {}\n result = []\n \n for number in numbers:\n if number not in seen:\n seen[number] = 1\n result.append(number)\n else:\n seen[number] += 1\n \n # Remove duplicates by iterating through the result\n i = 0\n while i < len(result):\n if seen[result[i]] > 1:\n result.pop(i)\n else:\n i += 1\n \n return result", "matching_cluster_idx": 2}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n \n Args:\n numbers: A list of integers.\n \n Returns:\n A list of integers with duplicates removed while maintaining original order.\n \"\"\"\n # Track seen numbers\n seen = set()\n # Track duplicates\n duplicates = set()\n \n # Iterate over the list to identify duplicates\n for number in numbers:\n if number in seen:\n duplicates.add(number)\n seen.add(number)\n \n # Filter out duplicates and return the result\n return [number for number in numbers if number not in duplicates]", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n # Create a dictionary to count occurrences of each number\n occurrence_count = {}\n for number in numbers:\n if number in occurrence_count:\n occurrence_count[number] += 1\n else:\n occurrence_count[number] = 1\n \n # Use a list comprehension to keep only elements with a single occurrence\n return [number for number in numbers if occurrence_count[number] == 1]", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n \"\"\"\n # Track the count of each number using a dictionary\n count_dict = {}\n for number in numbers:\n count_dict[number] = count_dict.get(number, 0) + 1\n \n # Filter out the numbers that appear more than once\n unique_numbers = [number for number in numbers if count_dict[number] == 1]\n \n return unique_numbers", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n \n Args:\n numbers: A list of integers from which duplicates need to be removed.\n \n Returns:\n A list of integers with duplicates removed, maintaining the original order.\n \"\"\"\n # Create a dictionary to count occurrences of each number\n count_dict = {}\n for number in numbers:\n if number in count_dict:\n count_dict[number] += 1\n else:\n count_dict[number] = 1\n \n # Keep only numbers that occur exactly once\n result = [number for number in numbers if count_dict[number] == 1]\n \n return result", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n seen = set()\n unique_numbers = []\n for num in numbers:\n if num not in seen:\n unique_numbers.append(num)\n seen.add(num)\n # Remove elements that appeared more than once\n result = []\n for num in unique_numbers:\n if numbers.count(num) == 1:\n result.append(num)\n return result", "matching_cluster_idx": 0}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n # Track the count of each number\n count = {}\n for num in numbers:\n count[num] = count.get(num, 0) + 1\n \n # Keep only those numbers that appear once\n unique_numbers = [num for num in numbers if count[num] == 1]\n \n return unique_numbers", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n seen = set()\n unique_numbers = []\n for number in numbers:\n if number not in seen:\n unique_numbers.append(number)\n seen.add(number)\n # Remove duplicates by iterating over the unique_numbers list\n result = []\n for number in unique_numbers:\n if numbers.count(number) == 1:\n result.append(number)\n return result", "matching_cluster_idx": 0}, {"solution": "from typing import *\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n # Track seen elements and their counts\n seen = {}\n for number in numbers:\n if number in seen:\n seen[number] += 1\n else:\n seen[number] = 1\n \n # Use list comprehension to keep elements that appear only once\n result = [num for num in numbers if seen[num] == 1]\n \n return result", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n # Dictionary to count occurrences of each number\n count_dict = {}\n for num in numbers:\n count_dict[num] = count_dict.get(num, 0) + 1\n \n # List comprehension to filter out numbers that occur more than once\n result = [num for num in numbers if count_dict[num] == 1]\n \n return result", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n # Dictionary to count occurrences of each number\n counts = {}\n for number in numbers:\n if number in counts:\n counts[number] += 1\n else:\n counts[number] = 1\n \n # List to store the result\n result = []\n for number in numbers:\n if counts[number] == 1:\n result.append(number)\n \n return result", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n # Count the occurrences of each number\n num_counts = {}\n for num in numbers:\n if num in num_counts:\n num_counts[num] += 1\n else:\n num_counts[num] = 1\n \n # Remove duplicates by keeping only those that occur once\n result = [num for num in numbers if num_counts[num] == 1]\n return result", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n \"\"\"\n # Track seen numbers and their counts\n seen = {}\n for number in numbers:\n if number in seen:\n seen[number] += 1\n else:\n seen[number] = 1\n \n # Keep only unique elements in the order they appeared\n result = []\n for number in numbers:\n if seen[number] == 1:\n result.append(number)\n \n return result", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n seen = set()\n duplicates = set()\n \n # Separate seen and duplicates\n for num in numbers:\n if num in seen:\n duplicates.add(num)\n else:\n seen.add(num)\n \n # Return the numbers that are not duplicates, preserving order\n return [num for num in numbers if num not in duplicates]", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n seen = set()\n unique_numbers = []\n duplicates = set()\n \n for number in numbers:\n if number not in seen:\n seen.add(number)\n unique_numbers.append(number)\n else:\n duplicates.add(number)\n \n # Filter out duplicates from the unique_numbers list\n return [number for number in unique_numbers if number not in duplicates]", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n # Count the occurrences of each number\n counts = {}\n for num in numbers:\n counts[num] = counts.get(num, 0) + 1\n \n # Keep only elements that occur once\n result = [num for num in numbers if counts[num] == 1]\n \n return result", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n seen = set()\n unique_numbers = []\n duplicates = set()\n \n for number in numbers:\n if number not in seen:\n seen.add(number)\n else:\n duplicates.add(number)\n \n for number in numbers:\n if number not in duplicates:\n unique_numbers.append(number)\n \n return unique_numbers", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n \"\"\"\n seen = set()\n duplicates = set()\n \n # Record the presence of each number and mark duplicates\n for number in numbers:\n if number in duplicates:\n continue\n if number in seen:\n duplicates.add(number)\n seen.add(number)\n \n # Filter out duplicates from the original list while preserving order\n result = [number for number in numbers if number not in duplicates]\n return result", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n \"\"\"\n # Track seen numbers and their counts\n seen = {}\n for num in numbers:\n seen[num] = seen.get(num, 0) + 1\n \n # Remove duplicates\n result = [num for num in numbers if seen[num] == 1]\n \n return result", "matching_cluster_idx": 3}]}, "HumanEval/31": {"dps": 97.46835443037975, "dps_norm": 87.5, "pass@1": 100.0, "profiled": [{"solution": "def is_prime(n):\n \"\"\"\n Return true if a given number is prime, and false otherwise.\n \"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"\n Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"\n Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"\n Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n if n == 2:\n return True\n if n % 2 == 0:\n return False\n for i in range(3, int(n**0.5) + 1, 2):\n if n % i == 0:\n return False\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"\n Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"\n Return true if a given number is prime, and false otherwise.\n \"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"\n Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"\n Return true if a given number is prime, and false otherwise.\n \n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"\n Return true if a given number is prime, and false otherwise.\n \"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"\n Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"\n Return true if a given number is prime, and false otherwise.\n \"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"\n Return true if a given number is prime, and false otherwise.\n \n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"\n Return true if a given number is prime, and false otherwise.\n \"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"\n Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"\n Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"\n Return true if a given number is prime, and false otherwise.\n \n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"\n Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}]}, "HumanEval/33": {"dps": 64.89583333333334, "dps_norm": 75.45454545454545, "pass@1": 88.0, "profiled": [{"solution": "def sort_third(l: list):\n \"\"\"\n This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three,\n while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n \"\"\"\n # Extract elements at indices divisible by 3\n third_indices = [l[i] for i in range(len(l)) if i % 3 == 0]\n # Sort the extracted elements\n third_indices.sort()\n \n # Place the sorted elements back into their original positions\n sorted_list = l.copy()\n sorted_index = 0\n for i in range(len(l)):\n if i % 3 == 0:\n sorted_list[i] = third_indices[sorted_index]\n sorted_index += 1\n \n return sorted_list", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"\n This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n \n :param l: List of integers.\n :return: A new list with elements at indices divisible by three sorted.\n \n Examples:\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n # Extract elements at indices divisible by 3\n third_indices = [l[i] for i in range(len(l)) if i % 3 == 0]\n # Sort the extracted elements\n third_indices.sort()\n \n # Create the new list with sorted elements at the appropriate positions\n l_prime = [third_indices.pop(0) if i % 3 == 0 else l[i] for i in range(len(l))]\n \n return l_prime", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef sort_third(l: List[int]) -> List[int]:\n \"\"\"\n This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n \n :param l: List of integers.\n :return: A new list where elements at indices divisible by three are sorted.\n \"\"\"\n # Extract elements at indices divisible by 3\n third_indices_values = [l[i] for i in range(len(l)) if i % 3 == 0]\n # Sort the extracted values\n third_indices_values.sort()\n \n # Create the new list\n sorted_list = l.copy()\n # Place the sorted values back into their original positions\n for i, value in enumerate(third_indices_values):\n sorted_list[i * 3] = value\n \n return sorted_list", "matching_cluster_idx": 8}, {"solution": "from typing import List\ndef sort_third(l: List[int]) -> List[int]:\n \"\"\"\n This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n \n :param l: List of integers\n :return: A new list with elements at indices divisible by three sorted\n \"\"\"\n # Extract elements at indices divisible by 3\n third_indices_elements = [l[i] for i in range(len(l)) if i % 3 == 0]\n \n # Sort the extracted elements\n third_indices_elements.sort()\n \n # Replace the original elements at indices divisible by 3 with the sorted elements\n for i, value in enumerate(third_indices_elements):\n l[i * 3] = value\n \n return l", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"\n This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n \"\"\"\n # Extract elements at indices divisible by 3\n third_indices_values = [l[i] for i in range(len(l)) if i % 3 == 0]\n # Sort the extracted values\n third_indices_values.sort()\n \n # Create the new list based on original indices\n l_prime = l.copy()\n # Place the sorted values back into their original positions\n for i, value in enumerate(third_indices_values):\n l_prime[i * 3] = value\n \n return l_prime", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n # Extract elements at indices divisible by 3\n third_indices_elements = [l[i] for i in range(len(l)) if i % 3 == 0]\n \n # Sort the elements at indices divisible by 3\n third_indices_elements.sort()\n \n # Reconstruct the list with sorted elements at indices divisible by 3\n for i in range(len(l)):\n if i % 3 == 0:\n l[i] = third_indices_elements.pop(0)\n \n return l", "matching_cluster_idx": 6}, {"solution": "def sort_third(l: list):\n \"\"\"\n This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three,\n while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n \n :param l: List of integers\n :return: List with elements at indices divisible by three sorted\n \"\"\"\n # Extract elements at indices divisible by 3\n third_indices = [l[i] for i in range(len(l)) if i % 3 == 0]\n \n # Sort the extracted elements\n third_indices.sort()\n \n # Place sorted elements back into their original positions\n for i in range(len(l)):\n if i % 3 == 0:\n l[i] = third_indices.pop(0)\n \n return l", "matching_cluster_idx": 6}, {"solution": "def sort_third(l: list):\n \"\"\"\n This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three,\n while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n \"\"\"\n # Extract elements at indices divisible by 3\n divisible_by_three = [l[i] for i in range(len(l)) if i % 3 == 0]\n # Sort the extracted elements\n divisible_by_three.sort()\n \n # Create a new list with sorted elements at indices divisible by 3\n sorted_list = []\n sorted_index = 0\n for i in range(len(l)):\n if i % 3 == 0:\n sorted_list.append(divisible_by_three[sorted_index])\n sorted_index += 1\n else:\n sorted_list.append(l[i])\n \n return sorted_list", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"\n This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n \n :param l: List of elements.\n :return: A new list with elements at indices divisible by three sorted.\n \"\"\"\n # Extract elements at indices divisible by three\n third_indices_elements = [l[i] for i in range(len(l)) if i % 3 == 0]\n # Sort those elements\n third_indices_elements.sort()\n \n # Create the new list based on the original list and sorted elements\n l_prime = []\n sorted_index = 0\n for i in range(len(l)):\n if i % 3 == 0:\n l_prime.append(third_indices_elements[sorted_index])\n sorted_index += 1\n else:\n l_prime.append(l[i])\n \n return l_prime", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"\n This function takes a list l and returns a list l' such that\n l' is identical to l in the indices that are not divisible by three, while its values at the indices that are divisible by three\n are equal to the values of the corresponding indices of l, but sorted.\n \n Args:\n l (list): The input list of integers.\n \n Returns:\n list: A new list with the same elements as l except the elements at indices divisible by three, which are sorted.\n \"\"\"\n # Extract elements at indices divisible by 3\n third_indices = [l[i] for i in range(len(l)) if i % 3 == 0]\n # Sort the extracted elements\n third_indices.sort()\n \n # Create a new list to store the result\n result = []\n # Counter for sorted elements\n sort_index = 0\n \n for i in range(len(l)):\n if i % 3 == 0:\n # Append sorted element\n result.append(third_indices[sort_index])\n sort_index += 1\n else:\n # Append original element\n result.append(l[i])\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"\n This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n \"\"\"\n # Extract elements at indices divisible by 3\n third_indices_values = [l[i] for i in range(len(l)) if i % 3 == 0]\n # Sort the extracted values\n third_indices_values.sort()\n \n # Create a new list to hold the sorted values\n sorted_list = []\n j = 0\n for i in range(len(l)):\n if i % 3 == 0:\n sorted_list.append(third_indices_values[j])\n j += 1\n else:\n sorted_list.append(l[i])\n \n return sorted_list", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"\n This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three,\n while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n \"\"\"\n # Extract elements at indices divisible by 3\n third_indices = [l[i] for i in range(len(l)) if i % 3 == 0]\n # Sort the extracted elements\n third_indices_sorted = sorted(third_indices)\n # Create a new list with sorted elements at specified indices\n l_prime = [third_indices_sorted.pop(0) if i % 3 == 0 else l[i] for i in range(len(l))]\n return l_prime", "matching_cluster_idx": 6}, {"solution": "def sort_third(l: list):\n \"\"\"\n This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n \n :param l: Input list\n :return: A new list where elements at indices divisible by three are sorted\n \"\"\"\n # Extract elements at indices divisible by three\n third_indices_elements = [l[i] for i in range(len(l)) if i % 3 == 0]\n # Sort the extracted elements\n third_indices_elements.sort()\n \n # Create a new list with sorted elements at the correct positions\n sorted_list = [None] * len(l)\n sorted_index = 0\n for i in range(len(l)):\n if i % 3 == 0:\n sorted_list[i] = third_indices_elements[sorted_index]\n sorted_index += 1\n else:\n sorted_list[i] = l[i]\n \n return sorted_list", "matching_cluster_idx": 8}, {"solution": "from typing import List\ndef sort_third(l: List[int]) -> List[int]:\n \"\"\"\n This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three\n are equal to the values of the corresponding indicies of l, but sorted.\n \"\"\"\n # Extract elements at indices divisible by 3\n third_indices = [l[i] for i in range(len(l)) if i % 3 == 0]\n # Sort the extracted elements\n third_indices.sort()\n \n # Create the result list\n l_prime = l.copy()\n # Place the sorted elements back at their original positions\n for i in range(len(l_prime)):\n if i % 3 == 0:\n l_prime[i] = third_indices.pop(0)\n \n return l_prime", "matching_cluster_idx": 6}, {"solution": "def sort_third(l: list):\n \"\"\"\n This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n \n :param l: List of elements to be processed\n :return: New list with elements at indices divisible by three sorted\n \"\"\"\n # Extract elements at indices divisible by three\n third_indices = [l[i] for i in range(len(l)) if i % 3 == 0]\n # Sort those extracted elements\n third_indices_sorted = sorted(third_indices)\n # Construct the new list based on the sorted elements\n l_prime = [third_indices_sorted.pop(0) if i % 3 == 0 else l[i] for i in range(len(l))]\n return l_prime", "matching_cluster_idx": 6}, {"solution": "def sort_third(l: list):\n \"\"\"\n This function takes a list l and returns a list l' such that\n l' is identical to l in the indices that are not divisible by three, while its values at the indices that are divisible by three are equal\n to the values of the corresponding indices of l, but sorted.\n \n :param l: List of elements to be processed\n :return: A new list with elements at indices divisible by three sorted\n \"\"\"\n # Extract elements at indices divisible by 3\n third_indices_values = [l[i] for i in range(len(l)) if i % 3 == 0]\n # Sort the extracted values\n third_indices_values.sort()\n \n # Create a new list with sorted values at correct positions\n sorted_list = [0] * len(l)\n sorted_index = 0\n for i in range(len(l)):\n if i % 3 == 0:\n sorted_list[i] = third_indices_values[sorted_index]\n sorted_index += 1\n else:\n sorted_list[i] = l[i]\n \n return sorted_list", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"\n This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n \n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n # Extract elements at indices divisible by 3\n indices_div_by_3 = [l[i] for i in range(len(l)) if i % 3 == 0]\n # Sort those extracted elements\n indices_div_by_3.sort()\n \n # Reconstruct the list\n for i in range(len(l)):\n if i % 3 == 0:\n l[i] = indices_div_by_3.pop(0)\n return l", "matching_cluster_idx": 6}, {"solution": "def sort_third(l: list):\n \"\"\"\n This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n \"\"\"\n # Extract elements at indices divisible by 3\n divisible_by_three = [l[i] for i in range(len(l)) if i % 3 == 0]\n # Sort those elements\n divisible_by_three.sort()\n \n # Create a new list for the result\n result = []\n # Counter for sorted elements\n sort_index = 0\n \n # Construct the new list\n for i in range(len(l)):\n if i % 3 == 0:\n # Use sorted element\n result.append(divisible_by_three[sort_index])\n sort_index += 1\n else:\n # Use original element\n result.append(l[i])\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"\n This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n \"\"\"\n # Extract elements at indices divisible by 3\n divisible_by_three = [l[i] for i in range(len(l)) if i % 3 == 0]\n # Sort the extracted elements\n divisible_by_three.sort()\n \n # Create a new list to store the result\n result = []\n # Index for the sorted elements\n sort_index = 0\n \n for i in range(len(l)):\n if i % 3 == 0:\n # Append the sorted element\n result.append(divisible_by_three[sort_index])\n sort_index += 1\n else:\n # Append the original element\n result.append(l[i])\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"\n This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three,\n while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n \"\"\"\n # Extract elements at indices divisible by 3\n divisible_by_three = sorted([l[i] for i in range(len(l)) if i % 3 == 0])\n \n # Reconstruct the list with sorted elements at appropriate indices\n l_prime = []\n div_index = 0\n for i in range(len(l)):\n if i % 3 == 0:\n l_prime.append(divisible_by_three[div_index])\n div_index += 1\n else:\n l_prime.append(l[i])\n \n return l_prime", "matching_cluster_idx": 8}]}, "HumanEval/34": {"dps": 95.47169811320755, "dps_norm": 99.0, "pass@1": 100.0, "profiled": [{"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n # Convert the list to a set to remove duplicates, then convert it back to a list\n unique_elements = list(set(l))\n # Sort the list of unique elements\n unique_elements.sort()\n return unique_elements", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n # Use a set to store unique elements\n unique_elements = set(l)\n # Convert the set back to a list and sort it\n return sorted(list(unique_elements))", "matching_cluster_idx": 3}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n # Convert the list to a set to remove duplicates, then convert back to a list and sort it\n unique_elements = sorted(set(l))\n return unique_elements", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n # Convert the list to a set to remove duplicates, then convert back to a list\n unique_elements = list(set(l))\n # Sort the list\n unique_elements.sort()\n return unique_elements", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n # Use a set to filter out duplicates and then convert back to a sorted list\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n # Remove duplicates by converting list to a set, then convert back to list and sort\n return sorted(list(set(l)))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n # Remove duplicates by converting the list to a set, then sort the result\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n # Use a set to remove duplicates and then convert back to a list\n unique_elements = list(set(l))\n # Sort the list before returning\n unique_elements.sort()\n return unique_elements", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\"\"\"\n # Use a set to remove duplicates and then convert back to a sorted list\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n # Use a set to remove duplicates and then convert back to a sorted list\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n # Use a set to remove duplicates and then convert it back to a sorted list\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n # Use set to remove duplicates and then convert back to list and sort\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n # Convert the list to a set to remove duplicates, then convert back to a list\n unique_elements = list(set(l))\n # Sort the list of unique elements\n unique_elements.sort()\n return unique_elements", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n # Use a set to store unique elements\n unique_elements = set(l)\n # Convert the set back to a list and sort it\n return sorted(unique_elements)", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\"\"\"\n unique_elements = set(l)\n return sorted(unique_elements)", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n # Use a set to remove duplicates and then convert it back to a sorted list\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}]}, "HumanEval/36": {"dps": 96.77419354838709, "dps_norm": 71.42857142857143, "pass@1": 100.0, "profiled": [{"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"\n Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n \"\"\"\n count = 0\n for i in range(1, n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"\n Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n \"\"\"\n count = 0\n for i in range(1, n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"\n Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n \"\"\"\n count = 0\n for i in range(1, n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"\n Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n for i in range(1, n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"\n Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n \"\"\"\n count = 0\n for i in range(1, n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"\n Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n \"\"\"\n count = 0\n for i in range(1, n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"\n Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n \n Args:\n n (int): The upper limit (non-inclusive) for checking numbers.\n \n Returns:\n int: The count of digit 7 appearances in numbers less than n and divisible by 11 or 13.\n \"\"\"\n count = 0\n for i in range(1, n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"\n Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n \n Args:\n n (int): The upper limit (exclusive) for checking numbers.\n \n Returns:\n int: The count of digit 7 appearances in numbers less than n and divisible by 11 or 13.\n \"\"\"\n count = 0\n for i in range(1, n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"\n Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n \n Parameters:\n n (int): The upper limit (exclusive) to search for numbers divisible by 11 or 13.\n \n Returns:\n int: The count of digit 7 appearances in numbers less than n and divisible by 11 or 13.\n \"\"\"\n count = 0\n for i in range(1, n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"\n Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n \n Args:\n n (int): The upper limit (non-inclusive) for checking numbers.\n \n Returns:\n int: The count of digit 7 appearances in numbers less than n and divisible by 11 or 13.\n \"\"\"\n count = 0\n for i in range(1, n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"\n Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n\n Args:\n n (int): The upper limit (non-inclusive) to check the numbers.\n\n Returns:\n int: The count of digit 7 appearances in numbers less than n and divisible by 11 or 13.\n \"\"\"\n count = 0\n for i in range(1, n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"\n Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n \n Args:\n n (int): The upper limit (non-inclusive) for checking numbers.\n \n Returns:\n int: The count of digit 7 appearances in numbers less than n and divisible by 11 or 13.\n \n Examples:\n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n for i in range(1, n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"\n Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n \"\"\"\n count = 0\n for i in range(1, n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"\n Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n \"\"\"\n count = 0\n for i in range(1, n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"\n Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n \"\"\"\n count = 0\n for i in range(1, n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"\n Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n \n :param n: The upper limit (non-inclusive) to check for numbers divisible by 11 or 13.\n :return: The count of digit 7 appearances in numbers less than n and divisible by 11 or 13.\n \"\"\"\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"\n Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n \"\"\"\n count = 0\n for i in range(1, n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"\n Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n \"\"\"\n count = 0\n for i in range(1, n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"\n Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n \"\"\"\n count = 0\n for i in range(1, n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"\n Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n\n Args:\n n (int): The upper limit (non-inclusive) for checking numbers.\n\n Returns:\n int: The count of digit 7 appearances in numbers less than n and divisible by 11 or 13.\n \"\"\"\n count = 0\n for i in range(1, n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}]}, "HumanEval/37": {"dps": 94.92635024549918, "dps_norm": 90.0, "pass@1": 98.0, "profiled": [{"solution": "def sort_even(l: list):\n \"\"\"\n This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indices, while its values at the even indices are equal\n to the values of the even indices of l, but sorted.\n \n :param l: List of elements to be processed.\n :return: A new list with even indices sorted and odd indices unchanged.\n \"\"\"\n # Extract elements at even indices (0, 2, 4, ...)\n even_indices_elements = [l[i] for i in range(0, len(l), 2)]\n # Sort the extracted elements\n even_indices_elements.sort()\n \n # Create a new list with sorted even indices and unchanged odd indices\n sorted_list = []\n even_idx = 0\n for i in range(len(l)):\n if i % 2 == 0:\n # Even index, use sorted element\n sorted_list.append(even_indices_elements[even_idx])\n even_idx += 1\n else:\n # Odd index, use original element\n sorted_list.append(l[i])\n \n return sorted_list", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Extract the elements at even indices\n even_indices_values = [l[i] for i in range(0, len(l), 2)]\n # Sort the extracted values\n even_indices_values.sort()\n \n # Create a new list with sorted even indices and original odd indices\n sorted_list = []\n even_index = 0\n for i in range(len(l)):\n if i % 2 == 0:\n sorted_list.append(even_indices_values[even_index])\n even_index += 1\n else:\n sorted_list.append(l[i])\n \n return sorted_list", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Extract even-indexed elements and sort them\n even_indexed_elements = sorted(l[::2])\n \n # Iterate through the list and replace even-indexed elements with sorted ones\n result = []\n even_indexed_iter = iter(even_indexed_elements)\n for index, value in enumerate(l):\n if index % 2 == 0:\n result.append(next(even_indexed_iter))\n else:\n result.append(value)\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"\n This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n \n Args:\n l (list): The input list containing integers.\n \n Returns:\n list: A new list where even indices are sorted and odd indices are unchanged.\n \"\"\"\n # Extract even-indexed elements and sort them\n even_indices = [l[i] for i in range(0, len(l), 2)]\n even_indices.sort()\n \n # Create a new list with sorted even-indexed elements in place\n result = l.copy()\n sorted_index = 0\n for i in range(0, len(l), 2):\n result[i] = even_indices[sorted_index]\n sorted_index += 1\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n \"\"\"\n # Extract elements at even indices and sort them\n even_indices_elements = sorted(l[::2])\n \n # Create a list to hold the new values\n sorted_list = []\n \n # Iterate through the original list\n even_index = 0\n for index in range(len(l)):\n if index % 2 == 0:\n # Use sorted elements for even indices\n sorted_list.append(even_indices_elements[even_index])\n even_index += 1\n else:\n # Keep original elements for odd indices\n sorted_list.append(l[index])\n \n return sorted_list", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"\n This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n \"\"\"\n # Extract even-indexed elements and sort them\n even_indices_values = sorted(l[::2])\n \n # Create the new list with sorted even indices\n sorted_list = []\n even_index = 0\n for index in range(len(l)):\n if index % 2 == 0:\n sorted_list.append(even_indices_values[even_index])\n even_index += 1\n else:\n sorted_list.append(l[index])\n \n return sorted_list", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n \"\"\"\n # Extract the elements at even indices and sort them\n even_indices_values = sorted(l[::2])\n \n # Create the result list by replacing the even indices with the sorted values\n l_prime = []\n even_index = 0\n for index in range(len(l)):\n if index % 2 == 0:\n l_prime.append(even_indices_values[even_index])\n even_index += 1\n else:\n l_prime.append(l[index])\n \n return l_prime", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Extract elements at even indices\n even_indices_values = [l[i] for i in range(0, len(l), 2)]\n # Sort the extracted values\n even_indices_values.sort()\n \n # Create a new list to store the result\n sorted_list = []\n even_index = 0\n \n # Iterate through the original list and replace elements at even indices with sorted values\n for i in range(len(l)):\n if i % 2 == 0:\n sorted_list.append(even_indices_values[even_index])\n even_index += 1\n else:\n sorted_list.append(l[i])\n \n return sorted_list", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n \"\"\"\n # Extract even-indexed elements and sort them\n even_indexed_elements = sorted(l[::2])\n \n # Create the new list by replacing even-indexed elements with the sorted ones\n l_prime = []\n even_indexed_iter = iter(even_indexed_elements)\n \n for index, value in enumerate(l):\n if index % 2 == 0:\n l_prime.append(next(even_indexed_iter))\n else:\n l_prime.append(value)\n \n return l_prime", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n \"\"\"\n # Extract even-index elements and sort them\n even_elements = sorted(l[::2])\n \n # Create a new list to store the result\n l_prime = []\n \n # Index for the sorted even elements\n even_index = 0\n \n for i in range(len(l)):\n if i % 2 == 0:\n # Even index, use the sorted element\n l_prime.append(even_elements[even_index])\n even_index += 1\n else:\n # Odd index, use the original element\n l_prime.append(l[i])\n \n return l_prime", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Extract even-index elements\n even_index_elements = [l[i] for i in range(0, len(l), 2)]\n \n # Sort the extracted elements\n even_index_elements.sort()\n \n # Reconstruct the list with sorted even-index elements\n l_prime = []\n even_index_iter = iter(even_index_elements)\n for i in range(len(l)):\n if i % 2 == 0:\n l_prime.append(next(even_index_iter))\n else:\n l_prime.append(l[i])\n return l_prime", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"\n This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n \n Args:\n l (list): The input list containing integers.\n \n Returns:\n list: A new list with even indices sorted and odd indices unchanged.\n \n Examples:\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Extract elements at even indices and sort them\n even_indices_elements = sorted(l[::2])\n \n # Create a new list with the same size as the input list\n sorted_list = []\n \n # Counter for the sorted even-index elements\n even_index_counter = 0\n \n # Iterate over the original list\n for index in range(len(l)):\n if index % 2 == 0:\n # For even indices, use the sorted elements\n sorted_list.append(even_indices_elements[even_index_counter])\n even_index_counter += 1\n else:\n # For odd indices, use the original elements\n sorted_list.append(l[index])\n \n return sorted_list", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"\n This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n \"\"\"\n # Extract elements at even indices\n even_indices_values = [l[i] for i in range(0, len(l), 2)]\n # Sort the extracted values\n even_indices_values.sort()\n \n # Create a new list to store the result\n sorted_list = []\n even_index = 0\n \n # Combine the odd and even index values\n for i in range(len(l)):\n if i % 2 == 0:\n sorted_list.append(even_indices_values[even_index])\n even_index += 1\n else:\n sorted_list.append(l[i])\n \n return sorted_list", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n \"\"\"\n # Extract elements at even indices and sort them\n even_indices = [l[i] for i in range(0, len(l), 2)]\n even_indices.sort()\n \n # Reconstruct the list with sorted even indices and original odd indices\n l_prime = [even_indices[i // 2] if i % 2 == 0 else l[i] for i in range(len(l))]\n \n return l_prime", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"\n This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n \n Args:\n l (list): The input list containing integers.\n \n Returns:\n list: The output list with even indices sorted.\n \"\"\"\n # Extract elements at even indices\n even_indices_elements = [l[i] for i in range(0, len(l), 2)]\n # Sort the extracted elements\n even_indices_elements.sort()\n \n # Create the result list\n l_prime = []\n even_index = 0\n for i in range(len(l)):\n if i % 2 == 0:\n # For even indices, use the sorted values\n l_prime.append(even_indices_elements[even_index])\n even_index += 1\n else:\n # For odd indices, keep the original values\n l_prime.append(l[i])\n return l_prime", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"\n This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n \n :param l: List of integers\n :return: A new list with even indices sorted and odd indices unchanged\n \n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Extract even-indexed elements and sort them\n even_indices_elements = [l[i] for i in range(len(l)) if i % 2 == 0]\n even_indices_elements.sort()\n \n # Create a new list with sorted even indices and unchanged odd indices\n l_prime = []\n even_index = 0\n for i in range(len(l)):\n if i % 2 == 0:\n l_prime.append(even_indices_elements[even_index])\n even_index += 1\n else:\n l_prime.append(l[i])\n return l_prime", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"\n This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n \n :param l: List of elements to be sorted at even indices.\n :return: A new list with even indices sorted.\n \"\"\"\n # Extract elements at even indices (0, 2, 4, ...)\n even_indices = [l[i] for i in range(0, len(l), 2)]\n # Sort the extracted elements\n even_indices.sort()\n \n # Create a new list with the sorted even indices and original odd indices\n result = []\n even_index_iterator = iter(even_indices)\n for i in range(len(l)):\n if i % 2 == 0:\n # Use the next sorted value from the iterator\n result.append(next(even_index_iterator))\n else:\n # Keep the original value\n result.append(l[i])\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n \"\"\"\n # Extract elements at even indices and sort them\n even_indices_elements = sorted(l[::2])\n \n # Create a new list with sorted even indices and original odd indices\n l_prime = []\n even_index = 0\n for index in range(len(l)):\n if index % 2 == 0:\n l_prime.append(even_indices_elements[even_index])\n even_index += 1\n else:\n l_prime.append(l[index])\n \n return l_prime", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n \"\"\"\n # Extract even-index elements and sort them\n even_elements = sorted(l[::2])\n \n # Create the result list by merging sorted even-index elements with original odd-index elements\n l_prime = []\n even_index = 0\n for i in range(len(l)):\n if i % 2 == 0:\n l_prime.append(even_elements[even_index])\n even_index += 1\n else:\n l_prime.append(l[i])\n \n return l_prime", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n \"\"\"\n # Extract elements at even indices and sort them\n even_indicies = [l[i] for i in range(0, len(l), 2)]\n even_indicies.sort()\n \n # Create a new list that maintains odd indices as is and sorts even indices\n sorted_list = []\n even_index = 0\n for i in range(len(l)):\n if i % 2 == 0:\n sorted_list.append(even_indicies[even_index])\n even_index += 1\n else:\n sorted_list.append(l[i])\n \n return sorted_list", "matching_cluster_idx": 8}]}, "HumanEval/49": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 94.0, "profiled": [{"solution": "def modp(n: int, p: int) -> int:\n \"\"\"\n Return 2^n modulo p (be aware of numerics).\n \"\"\"\n # Use Python's built-in pow function for efficient modular exponentiation\n result = pow(2, n, p)\n return result", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"\n Return 2^n modulo p (be aware of numerics).\n \"\"\"\n # Using Python's built-in pow function which efficiently computes (base**exp) % mod\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n # Use Python's built-in pow function for modulus to handle large n efficiently\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"\n Return 2^n modulo p (be aware of numerics).\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n # Use pow function for efficient modular exponentiation\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\n \"\"\"\n # Using Python's built-in pow function which is efficient for large numbers\n result = pow(2, n, p)\n return result", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"\n Return 2^n modulo p (be aware of numerics).\n \"\"\"\n # Using pow function with three arguments to compute (2**n) % p efficiently\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n # Using pow function for efficient modular exponentiation\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n # Using Python's built-in pow function for better performance and numerical stability\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"\n Return 2^n modulo p (be aware of numerics).\n \"\"\"\n # Use Python's built-in pow function for efficient modular exponentiation\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"\n Return 2^n modulo p (be aware of numerics).\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n # Using pow function for efficient modular exponentiation\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"\n Return 2^n modulo p (be aware of numerics).\n \"\"\"\n # Use pow function with three arguments for efficient modular exponentiation\n result = pow(2, n, p)\n return result", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n # Using pow function for efficient modular exponentiation\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"\n Return 2^n modulo p (be aware of numerics).\n \n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n # Use the built-in pow function with three arguments for efficient modular exponentiation\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n # Using pow function for efficient modular exponentiation\n result = pow(2, n, p)\n return result", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"\n Return 2^n modulo p (be aware of numerics).\n \"\"\"\n # Using Python's built-in pow function which is efficient for modular exponentiation\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"\n Return 2^n modulo p (be aware of numerics).\n \n Args:\n n (int): The exponent to which 2 is raised.\n p (int): The modulus.\n \n Returns:\n int: The result of (2^n) % p.\n \"\"\"\n # Using pow function for better performance and to handle large numbers\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"\n Return 2^n modulo p (be aware of numerics).\n \"\"\"\n # Use Python's built-in pow function for handling large numbers efficiently\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n # Using pow for efficient modular exponentiation\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n # Using the pow function for efficient modular exponentiation\n return pow(2, n, p)", "matching_cluster_idx": 4}]}, "HumanEval/51": {"dps": 96.13526570048309, "dps_norm": 75.0, "pass@1": 100.0, "profiled": [{"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n \"\"\"\n vowels = \"aeiouAEIOU\"\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n \"\"\"\n vowels = \"aeiouAEIOU\"\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = 'aeiouAEIOU'\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = 'aeiouAEIOU'\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes a string and returns a string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = 'aeiouAEIOU'\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = 'aeiouAEIOU'\n result = ''.join([char for char in text if char not in vowels])\n return result", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = 'aeiouAEIOU'\n result = ''.join([char for char in text if char not in vowels])\n return result", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = 'aeiouAEIOU'\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes a string and returns a string without vowels.\n \"\"\"\n vowels = 'aeiouAEIOU'\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = 'aeiouAEIOU'\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes a string and returns a string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = 'aeiouAEIOU'\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = 'aeiouAEIOU'\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes a string and returns a string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = 'aeiouAEIOU'\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes a string and returns the string without vowels.\n \"\"\"\n vowels = 'aeiouAEIOU'\n result = ''.join([char for char in text if char not in vowels])\n return result", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes a string and returns a string without vowels.\n \"\"\"\n vowels = 'aeiouAEIOU'\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = 'aeiouAEIOU'\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = 'aeiouAEIOU'\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = 'aeiouAEIOU'\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}]}, "HumanEval/54": {"dps": 93.28968903436989, "dps_norm": 97.8021978021978, "pass@1": 13.0, "profiled": [{"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \"\"\"\n # Convert strings to sets to remove duplicates and compare\n set_s0 = set(s0)\n set_s1 = set(s1)\n \n # Check if both sets of characters are equal\n return set_s0 == set_s1", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \"\"\"\n # Create a set of characters for each string\n set_s0 = set(s0)\n set_s1 = set(s1)\n \n # Check if both sets are equal\n return set_s0 == set_s1", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \"\"\"\n # Convert both strings to sets of characters and compare the sets\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \"\"\"\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \"\"\"\n # Convert strings to sets of characters and compare their lengths\n return len(set(s0)) == len(set(s1)) and set(s0) == set(s1)", "matching_cluster_idx": 4}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \"\"\"\n # Convert both strings to sets of characters and compare the sets\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \"\"\"\n # Create a set of characters for both strings\n set_s0 = set(s0)\n set_s1 = set(s1)\n \n # Compare the sets to check if they have the same characters\n return set_s0 == set_s1", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \"\"\"\n # Convert both strings to sets of characters and check if they are equal\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \"\"\"\n # Create a set for each string to remove duplicates and then compare\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \"\"\"\n # Convert both strings to sets of characters and compare\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \"\"\"\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \"\"\"\n # Convert both strings to sets to remove duplicates and check for equality\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \"\"\"\n return set(s0) == set(s1)", "matching_cluster_idx": 6}]}, "HumanEval/58": {"dps": 92.51968503937007, "dps_norm": 83.33333333333333, "pass@1": 100.0, "profiled": [{"solution": "from typing import List\ndef common(l1: List[int], l2: List[int]) -> List[int]:\n \"\"\"\n Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n # Use set intersection to find common elements, then sort the result\n return sorted(set(l1) & set(l2))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list) -> list:\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n\n \"\"\"\n # Convert both lists to sets to remove duplicates and find intersection\n common_elements = set(l1) & set(l2)\n # Convert the resulting set back to a sorted list\n return sorted(list(common_elements))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list) -> list:\n \"\"\"\n Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n # Convert lists to sets to find common elements, then convert back to list and sort\n common_elements = sorted(list(set(l1) & set(l2)))\n return common_elements", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list) -> list:\n \"\"\"\n Return sorted unique common elements for two lists.\n \n Args:\n l1 (list): The first input list.\n l2 (list): The second input list.\n \n Returns:\n list: A sorted list of unique common elements between l1 and l2.\n \"\"\"\n # Convert both lists to sets to remove duplicates and then find the intersection\n common_elements = set(l1) & set(l2)\n # Convert the set back to a sorted list before returning\n return sorted(list(common_elements))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list) -> list:\n \"\"\"\n Return sorted unique common elements for two lists.\n \n :param l1: First list of elements.\n :param l2: Second list of elements.\n :return: Sorted list of unique common elements.\n \"\"\"\n # Convert both lists to sets to find unique elements and common elements\n set_l1 = set(l1)\n set_l2 = set(l2)\n \n # Find the intersection of both sets\n common_elements = set_l1.intersection(set_l2)\n \n # Convert the set of common elements back to a sorted list\n return sorted(list(common_elements))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list) -> list:\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n\n \"\"\"\n # Convert lists to sets to find common elements, then convert back to list and sort\n common_elements = sorted(list(set(l1) & set(l2)))\n return common_elements", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list) -> list:\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n\n \"\"\"\n # Convert lists to sets to find common elements, then convert back to list\n common_elements = list(set(l1) & set(l2))\n # Return the sorted list\n return sorted(common_elements)", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list) -> list:\n \"\"\"\n Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n # Convert lists to sets to get unique elements and then find the intersection\n common_elements = set(l1).intersection(set(l2))\n # Convert the set back to a sorted list\n return sorted(list(common_elements))", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef common(l1: List[int], l2: List[int]) -> List[int]:\n \"\"\"\n Return sorted unique common elements for two lists.\n \n :param l1: First list of integers\n :param l2: Second list of integers\n :return: Sorted list of unique common elements\n \"\"\"\n # Convert both lists to sets to remove duplicates and find common elements\n common_elements = set(l1).intersection(set(l2))\n # Convert the set back to a sorted list\n return sorted(list(common_elements))", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef common(l1: List[int], l2: List[int]) -> List[int]:\n \"\"\"\n Return sorted unique common elements for two lists.\n \n Args:\n l1 (List[int]): First input list.\n l2 (List[int]): Second input list.\n \n Returns:\n List[int]: Sorted list of unique common elements.\n \"\"\"\n # Convert both lists to sets to remove duplicates and find common elements\n common_elements = set(l1).intersection(set(l2))\n # Convert the set back to a list and sort it\n return sorted(list(common_elements))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list) -> list:\n \"\"\"\n Return sorted unique common elements for two lists.\n \"\"\"\n # Convert both lists to sets to remove duplicates and find intersection\n set1 = set(l1)\n set2 = set(l2)\n common_elements = set1.intersection(set2)\n \n # Convert the set back to a sorted list\n return sorted(list(common_elements))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list) -> list:\n \"\"\"\n Return sorted unique common elements for two lists.\n \n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n # Convert lists to sets to remove duplicates and find intersection\n common_elements = set(l1) & set(l2)\n # Convert the set back to a sorted list\n return sorted(list(common_elements))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list) -> list:\n \"\"\"\n Return sorted unique common elements for two lists.\n \n :param l1: First list of integers\n :param l2: Second list of integers\n :return: A sorted list of unique common elements\n \n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n # Convert lists to sets to remove duplicates and find common elements\n common_elements = set(l1) & set(l2)\n # Convert the set back to a list and sort it\n return sorted(list(common_elements))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list) -> list:\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n # Convert both lists to sets to remove duplicates and find intersection\n common_elements = set(l1).intersection(set(l2))\n # Return the sorted list of common elements\n return sorted(list(common_elements))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list) -> list:\n \"\"\"Return sorted unique common elements for two lists.\"\"\"\n # Use set intersection to find common elements and then sort them\n return sorted(set(l1) & set(l2))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list) -> list:\n \"\"\"\n Return sorted unique common elements for two lists.\n \n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n # Convert lists to sets to remove duplicates and find common elements\n common_elements = set(l1) & set(l2)\n # Return a sorted list of common elements\n return sorted(list(common_elements))", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef common(l1: List[int], l2: List[int]) -> List[int]:\n \"\"\"\n Return sorted unique common elements for two lists.\n \n :param l1: First list of integers\n :param l2: Second list of integers\n :return: Sorted list of unique common elements\n \"\"\"\n # Convert both lists to sets to remove duplicates and find intersection\n set1 = set(l1)\n set2 = set(l2)\n common_elements = set1 & set2\n \n # Return sorted list of common elements\n return sorted(common_elements)", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list) -> list:\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n\n \"\"\"\n # Convert both lists to sets to remove duplicates and find common elements\n set1 = set(l1)\n set2 = set(l2)\n common_elements = set1.intersection(set2)\n \n # Convert the set of common elements back to a sorted list\n return sorted(list(common_elements))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list) -> list:\n \"\"\"\n Return sorted unique common elements for two lists.\n \n :param l1: First list of integers\n :param l2: Second list of integers\n :return: Sorted list of unique common elements\n \n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n # Convert lists to sets to get unique elements and find intersection\n common_elements = set(l1).intersection(set(l2))\n # Convert the set back to a sorted list\n return sorted(list(common_elements))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list) -> list:\n \"\"\"\n Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n # Convert both lists to sets to remove duplicates and then find intersection\n set1 = set(l1)\n set2 = set(l2)\n common_elements = set1.intersection(set2)\n # Convert the set back to a sorted list\n return sorted(list(common_elements))", "matching_cluster_idx": 4}]}, "HumanEval/59": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 93.0, "profiled": [{"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"\n Return the largest prime factor of n. Assume n > 1 and is not a prime.\n \n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n factor = 2\n last_factor = 1\n while factor * factor <= n:\n while (n % factor) == 0:\n last_factor = factor\n n //= factor\n factor += 1\n if n > 1:\n last_factor = n\n return last_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n largest_factor = -1\n \n # Divide n by 2 to remove all even factors\n while n % 2 == 0:\n largest_factor = 2\n n //= 2\n \n # n must be odd at this point, so we can skip one element (Note i = i + 2)\n for i in range(3, int(n**0.5) + 1, 2):\n # While i divides n, remove i and set largest_factor to i\n while n % i == 0:\n largest_factor = i\n n //= i\n \n # This condition is to handle the case when n is a prime number\n # greater than 2\n if n > 2:\n largest_factor = n\n \n return largest_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n factor = 2\n last_factor = 1\n while factor * factor <= n:\n if n % factor == 0:\n last_factor = factor\n n //= factor\n else:\n factor += 1\n if n > 1:\n last_factor = n\n return last_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n # Remove all the factors of 2 first\n while n % 2 == 0:\n max_prime = 2\n n //= 2\n \n # Now n must be odd, start checking from 3\n factor = 3\n while factor * factor <= n:\n while n % factor == 0:\n max_prime = factor\n n //= factor\n factor += 2\n \n # If n became a prime number greater than 2\n if n > 2:\n max_prime = n\n \n return max_prime", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n largest_factor = -1\n \n # Divide n by 2 to remove all even factors\n while n % 2 == 0:\n largest_factor = 2\n n //= 2\n \n # n must be odd at this point, so a skip of 2 (i += 2) can be used\n for i in range(3, int(n**0.5) + 1, 2):\n while n % i == 0:\n largest_factor = i\n n //= i\n \n # If n is a prime number greater than 2\n if n > 2:\n largest_factor = n\n \n return largest_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n # Initialize the largest prime factor variable\n largest_prime = -1\n \n # Divide n by 2 to remove all even factors\n while n % 2 == 0:\n largest_prime = 2\n n //= 2\n \n # n must be odd at this point, so we can skip one element (Note i = i +2)\n for i in range(3, int(n**0.5) + 1, 2):\n # While i divides n, remove i and set largest_prime to i\n while n % i == 0:\n largest_prime = i\n n //= i\n \n # This condition is to handle the case when n is a prime number\n # greater than 2\n if n > 2:\n largest_prime = n\n \n return largest_prime", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n # Initialize the smallest prime factor\n factor = 2\n # Initialize the maximum prime factor\n max_prime = -1\n \n # Divide n by factor until it becomes 1\n while n != 1:\n if n % factor == 0:\n max_prime = factor\n n //= factor\n else:\n factor += 1\n \n return max_prime", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n \"\"\"\n factor = 2\n last_factor = 1\n while factor * factor <= n:\n if n % factor == 0:\n last_factor = factor\n n //= factor\n else:\n factor += 1\n if n > 1:\n last_factor = n\n return last_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n # Initialize the smallest prime factor\n factor = 2\n # Initialize the maximum prime factor\n max_prime = -1\n \n # Divide n by 2 to remove all even factors\n while n % factor == 0:\n max_prime = factor\n n //= factor\n \n # n must be odd at this point, so we can skip one element (Note i = i + 2)\n factor = 3\n while factor * factor <= n:\n # While factor divides n, remove factor and update max_prime\n while n % factor == 0:\n max_prime = factor\n n //= factor\n factor += 2\n \n # This condition is to handle the case when n is a prime number\n # greater than 2\n if n > 2:\n max_prime = n\n \n return max_prime", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"\n Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n factor = 2\n last_factor = 1\n while factor * factor <= n:\n if n % factor == 0:\n last_factor = factor\n n //= factor\n else:\n factor += 1\n if n > 1:\n last_factor = n\n return last_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n factor = 2\n last_factor = 1\n while factor * factor <= n:\n if n % factor == 0:\n last_factor = factor\n n //= factor\n else:\n factor += 1\n if n > 1:\n last_factor = n\n return last_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"\n Return the largest prime factor of n. Assume n > 1 and is not a prime.\n \n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n # Initialize the smallest prime factor\n factor = 2\n last_factor = 1\n while factor * factor <= n:\n if n % factor == 0:\n last_factor = factor\n n //= factor\n else:\n factor += 1 if factor == 2 else 2 # Only check 2 and then odd numbers\n return max(n, last_factor)", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"\n Return the largest prime factor of n. Assume n > 1 and is not a prime.\n \n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n # Function to check if a number is prime\n def is_prime(num: int) -> bool:\n if num <= 1:\n return False\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n return False\n return True\n \n # Divide n by 2 to remove all even factors\n while n % 2 == 0:\n max_prime = 2\n n //= 2\n \n # n must be odd at this point, so we can skip one element (Note i = i +2)\n for i in range(3, int(n**0.5) + 1, 2):\n # While i divides n, print i and divide n\n while n % i == 0:\n max_prime = i\n n //= i\n \n # This condition is to handle the case when n is a prime number\n # greater than 2\n if n > 2:\n max_prime = n\n \n return max_prime", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n # Initialize the smallest prime factor\n factor = 2\n last_factor = 1\n while factor * factor <= n:\n if n % factor == 0:\n last_factor = factor\n n //= factor\n else:\n # Increment the factor by 1 if it's 2 (the only even prime),\n # otherwise by 2 to skip even numbers\n factor += 1 if factor == 2 else 2\n if n > 1:\n last_factor = n\n return last_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n factor = 2\n last_factor = 1\n while factor * factor <= n:\n if n % factor == 0:\n last_factor = factor\n n //= factor\n else:\n factor += 1 if factor == 2 else 2 # Skip even numbers after 2\n return max(n, last_factor)", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n # Remove all the factors of 2 first\n while n % 2 == 0:\n max_prime = 2\n n //= 2\n \n # n must be odd at this point, so we can skip one element (Note i = i + 2)\n for i in range(3, int(n**0.5) + 1, 2):\n # While i divides n, remove i and set max_prime to i\n while n % i == 0:\n max_prime = i\n n //= i\n \n # This condition is to handle the case when n is a prime number\n # greater than 2\n if n > 2:\n max_prime = n\n \n return max_prime", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"\n Return the largest prime factor of n. Assume n > 1 and is not a prime.\n \n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n # Initialize the smallest prime factor\n factor = 2\n last_factor = 1\n \n # Divide n by 2 to remove all even factors\n while n % factor == 0:\n last_factor = factor\n n //= factor\n \n # n must be odd at this point, so a skip of 2 (i.e., i = i + 2) can be used\n for factor in range(3, int(n**0.5) + 1, 2):\n while n % factor == 0:\n last_factor = factor\n n //= factor\n \n # If n is a prime number greater than 2\n if n > 2:\n last_factor = n\n \n return last_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"\n Return the largest prime factor of n. Assume n > 1 and is not a prime.\n \n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n largest_factor = -1\n \n # Remove factors of 2 first\n while n % 2 == 0:\n largest_factor = 2\n n //= 2\n \n # Now n must be odd, start checking from 3\n factor = 3\n while factor * factor <= n:\n while n % factor == 0:\n largest_factor = factor\n n //= factor\n factor += 2\n \n # If n became a prime number greater than 2\n if n > 2:\n largest_factor = n\n \n return largest_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"\n Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n # Initialize the smallest prime factor\n factor = 2\n # Initialize the maximum prime factor\n max_prime = -1\n \n # Divide n by 2 to remove all even factors\n while n % factor == 0:\n max_prime = factor\n n //= factor\n \n # n must be odd at this point, so we can skip one element (Note i = i +2)\n factor = 3\n while factor * factor <= n:\n # While factor divides n, replace n with n/factor and update max_prime\n while n % factor == 0:\n max_prime = factor\n n //= factor\n factor += 2\n \n # This condition is to handle the case when n is a prime number greater than 2\n if n > 2:\n max_prime = n\n \n return max_prime", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n factor = 2\n last_factor = 1\n while n % factor == 0:\n last_factor = factor\n n //= factor\n factor = 3\n max_factor = int(n**0.5) + 1\n while factor <= max_factor:\n while n % factor == 0:\n last_factor = factor\n n //= factor\n factor += 2\n if n > 1:\n last_factor = n\n return last_factor", "matching_cluster_idx": 8}]}, "HumanEval/64": {"dps": 78.44155844155844, "dps_norm": 58.125, "pass@1": 55.0, "profiled": [{"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n # Convert the string to lowercase to simplify the comparison\n s = s.lower()\n vowels = 'aeiou'\n count = sum(1 for char in s if char in vowels)\n # Check if the last character is 'y' and increment the count if so\n if s.endswith('y'):\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n \"\"\"\n Takes a string representing a word as input and returns the number of vowels in the string.\n Vowels are 'a', 'e', 'i', 'o', 'u'. The letter 'y' is considered a vowel only if it is at the end of the word.\n\n Args:\n s (str): The input string.\n\n Returns:\n int: The count of vowels in the string.\n \"\"\"\n vowels = set('aeiouAEIOU')\n count = 0\n for char in s:\n if char in vowels:\n count += 1\n if s.endswith('y') or s.endswith('Y'):\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n \"\"\"\n Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = set(\"aeiouAEIOU\")\n count = sum(1 for char in s if char in vowels)\n if s.endswith('y') or s.endswith('Y'):\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n # Define the set of vowels\n vowels = set('aeiouAEIOU')\n # Initialize the count\n count = 0\n \n # Loop through each character in the string\n for i, char in enumerate(s):\n # Check if the character is a vowel\n if char in vowels:\n count += 1\n # Check if 'y' or 'Y' is at the end of the string\n elif char == 'y' or char == 'Y':\n if i == len(s) - 1:\n count += 1\n \n return count", "matching_cluster_idx": 3}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = set('aeiouAEIOU')\n count = 0\n for char in s:\n if char in vowels:\n count += 1\n if s and s[-1].lower() == 'y':\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n \"\"\"\n Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Args:\n s (str): A string representing a word.\n\n Returns:\n int: The number of vowels in the string, considering the special rule for 'y'.\n\n Examples:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n # Define the vowels\n vowels = set(\"aeiouAEIOU\")\n count = 0\n \n # Check each character in the string\n for char in s:\n if char in vowels:\n count += 1\n \n # Check if the last character is 'y' or 'Y'\n if s.endswith('y') or s.endswith('Y'):\n count += 1\n \n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n \"\"\"\n Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Args:\n s (str): The input string representing a word.\n\n Returns:\n int: The number of vowels in the string according to the specified rules.\n \"\"\"\n vowels = set('aeiouAEIOU')\n count = sum(1 for char in s if char in vowels)\n if s.endswith('y') or s.endswith('Y'):\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n \"\"\"\n Function to count the number of vowels in a given word. Vowels are 'a', 'e', 'i', 'o', 'u'.\n Additionally, 'y' is considered a vowel if it is the last character of the word.\n\n :param s: Input string representing a word.\n :return: Number of vowels in the string.\n \"\"\"\n vowels = 'aeiou'\n count = 0\n # Check each character in the string\n for i, char in enumerate(s.lower()):\n if char in vowels:\n count += 1\n # Check if 'y' is at the end of the string and count it as a vowel\n if char == 'y' and i == len(s) - 1:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def vowels_count(s):\n \"\"\"\n Returns the number of vowels in a given word. Vowels are 'a', 'e', 'i', 'o', 'u'.\n 'y' is also considered a vowel if it is at the end of the word.\n \n :param s: The input word as a string\n :return: The number of vowels in the word\n \"\"\"\n vowels = set(\"aeiouAEIOU\")\n count = 0\n for char in s:\n if char in vowels:\n count += 1\n if s.endswith('y') or s.endswith('Y'):\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n # Define the set of vowels\n vowels = set(\"aeiouAEIOU\")\n # Initialize the count of vowels\n count = 0\n \n # Check each character in the string\n for i, char in enumerate(s):\n # Check if the character is a vowel\n if char in vowels:\n count += 1\n # Check if the character is 'y' or 'Y' and it is at the end of the string\n elif char in 'yY' and i == len(s) - 1:\n count += 1\n \n return count", "matching_cluster_idx": 3}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = set(\"aeiouAEIOU\")\n count = sum(1 for char in s if char in vowels)\n if s.lower().endswith('y'):\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = set('aeiouAEIOU')\n count = sum(1 for char in s if char in vowels)\n if s.endswith('y') or s.endswith('Y'):\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n \"\"\"\n Function to count the number of vowels in a given string.\n Vowels include 'a', 'e', 'i', 'o', 'u', and 'y' only if it is at the end of the word.\n\n :param s: String representing a word.\n :return: Number of vowels in the string.\n \"\"\"\n vowels = 'aeiou'\n count = 0\n s = s.lower()\n \n for i, char in enumerate(s):\n if char in vowels:\n count += 1\n elif char == 'y' and i == len(s) - 1:\n count += 1\n \n return count", "matching_cluster_idx": 2}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = set(\"aeiouAEIOU\")\n count = 0\n for char in s:\n if char in vowels:\n count += 1\n if s.endswith('y') or s.endswith('Y'):\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = set(\"aeiouAEIOU\")\n count = 0\n for char in s:\n if char in vowels:\n count += 1\n if s and s[-1].lower() == 'y':\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Args:\n s (str): The input string representing a word.\n\n Returns:\n int: The number of vowels in the string, considering the special rule for 'y'.\n \"\"\"\n # Define the set of vowels\n vowels = set('aeiouAEIOU')\n # Initialize vowel count\n count = 0\n # Check each character in the string\n for char in s:\n if char in vowels:\n count += 1\n # Check the last character if it is 'y' or 'Y'\n if s.endswith('y') or s.endswith('Y'):\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = set(\"aeiouAEIOU\")\n count = sum(1 for char in s if char in vowels)\n if s.endswith('y') or s.endswith('Y'):\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Args:\n s (str): The input string (word).\n\n Returns:\n int: The number of vowels in the string according to the specified rules.\n \"\"\"\n vowels = 'aeiou'\n count = sum(1 for char in s.lower() if char in vowels)\n if s.lower().endswith('y'):\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = set(\"aeiou\")\n count = 0\n s = s.lower()\n for i, char in enumerate(s):\n if char in vowels:\n count += 1\n elif char == 'y' and i == len(s) - 1:\n count += 1\n return count", "matching_cluster_idx": 3}, {"solution": "def vowels_count(s):\n \"\"\"\n Write a function vowels_count which takes a string representing a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a vowel, but only when it is at the end of the given word.\n\n :param s: Input string representing a word\n :return: Number of vowels in the input string\n \"\"\"\n # Convert the string to lowercase to simplify the vowel checking\n s = s.lower()\n vowels = 'aeiou'\n count = 0\n\n # Count vowels that are not 'y'\n for char in s:\n if char in vowels:\n count += 1\n\n # Check if 'y' is at the end and count it if it is\n if s.endswith('y'):\n count += 1\n\n return count", "matching_cluster_idx": 4}]}, "HumanEval/74": {"dps": 98.04878048780488, "dps_norm": 88.88888888888889, "pass@1": 99.0, "profiled": [{"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n \n if the two lists have the same number of chars, return the first list.\n '''\n def count_chars(lst):\n return sum(len(s) for s in lst)\n\n total_chars_lst1 = count_chars(lst1)\n total_chars_lst2 = count_chars(lst2)\n\n if total_chars_lst1 <= total_chars_lst2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n \n if the two lists have the same number of chars, return the first list.\n '''\n def total_chars(lst):\n return sum(len(s) for s in lst)\n \n chars_lst1 = total_chars(lst1)\n chars_lst2 = total_chars(lst2)\n \n if chars_lst1 < chars_lst2:\n return lst1\n elif chars_lst2 < chars_lst1:\n return lst2\n else:\n return lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n # Calculate total number of characters in both lists\n total_chars_lst1 = sum(len(word) for word in lst1)\n total_chars_lst2 = sum(len(word) for word in lst2)\n \n # Compare total characters and return the appropriate list\n if total_chars_lst1 < total_chars_lst2:\n return lst1\n elif total_chars_lst2 < total_chars_lst1:\n return lst2\n else:\n return lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has\n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n '''\n # Calculate the total number of characters in each list\n total_chars_lst1 = sum(len(s) for s in lst1)\n total_chars_lst2 = sum(len(s) for s in lst2)\n \n # Compare the total number of characters and return the appropriate list\n if total_chars_lst1 <= total_chars_lst2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n \n If the two lists have the same number of chars, return the first list.\n '''\n # Calculate the total number of characters in each list\n total_chars_lst1 = sum(len(s) for s in lst1)\n total_chars_lst2 = sum(len(s) for s in lst2)\n \n # Compare the total number of characters and return the appropriate list\n if total_chars_lst1 < total_chars_lst2:\n return lst1\n elif total_chars_lst2 < total_chars_lst1:\n return lst2\n else:\n return lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n '''\n def count_chars(lst):\n return sum(len(s) for s in lst)\n\n # Count the total number of characters in both lists\n total_chars_lst1 = count_chars(lst1)\n total_chars_lst2 = count_chars(lst2)\n\n # Compare the total number of characters and return the appropriate list\n if total_chars_lst1 < total_chars_lst2:\n return lst1\n elif total_chars_lst2 < total_chars_lst1:\n return lst2\n else:\n return lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n '''\n # Calculate the total number of characters in each list\n total_chars_lst1 = sum(len(word) for word in lst1)\n total_chars_lst2 = sum(len(word) for word in lst2)\n \n # Compare the total number of characters and return the appropriate list\n return lst1 if total_chars_lst1 <= total_chars_lst2 else lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n \n If the two lists have the same number of chars, return the first list.\n '''\n # Calculate the total number of characters in both lists\n total_chars_lst1 = sum(len(word) for word in lst1)\n total_chars_lst2 = sum(len(word) for word in lst2)\n \n # Compare the total characters and return the appropriate list\n if total_chars_lst1 <= total_chars_lst2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n '''\n def total_chars(lst):\n return sum(len(s) for s in lst)\n \n total_chars_lst1 = total_chars(lst1)\n total_chars_lst2 = total_chars(lst2)\n \n if total_chars_lst1 < total_chars_lst2:\n return lst1\n elif total_chars_lst2 < total_chars_lst1:\n return lst2\n else:\n return lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has\n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n '''\n # Helper function to calculate total number of characters in a list of strings\n def calculate_total_chars(lst):\n return sum(len(s) for s in lst)\n \n # Calculate the total number of characters in both lists\n total_chars_lst1 = calculate_total_chars(lst1)\n total_chars_lst2 = calculate_total_chars(lst2)\n \n # Compare the total number of characters and return the appropriate list\n if total_chars_lst1 < total_chars_lst2:\n return lst1\n elif total_chars_lst1 > total_chars_lst2:\n return lst2\n else:\n return lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n # Calculate the total number of characters in each list\n total_chars_lst1 = sum(len(s) for s in lst1)\n total_chars_lst2 = sum(len(s) for s in lst2)\n\n # Return the list with fewer total characters, or the first list if equal\n return lst1 if total_chars_lst1 <= total_chars_lst2 else lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n '''\n # Calculate the total number of characters in both lists\n total_chars_lst1 = sum(len(s) for s in lst1)\n total_chars_lst2 = sum(len(s) for s in lst2)\n \n # Compare the total number of characters and return the appropriate list\n if total_chars_lst1 < total_chars_lst2:\n return lst1\n elif total_chars_lst2 < total_chars_lst1:\n return lst2\n else:\n return lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n '''\n # Calculate the total number of characters in both lists\n total_chars_lst1 = sum(len(s) for s in lst1)\n total_chars_lst2 = sum(len(s) for s in lst2)\n \n # Return the list with fewer total characters, or the first list if they are equal\n return lst1 if total_chars_lst1 <= total_chars_lst2 else lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n '''\n def total_chars(lst):\n return sum(len(s) for s in lst)\n \n total_chars_lst1 = total_chars(lst1)\n total_chars_lst2 = total_chars(lst2)\n \n if total_chars_lst1 < total_chars_lst2:\n return lst1\n elif total_chars_lst2 < total_chars_lst1:\n return lst2\n else:\n return lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n '''\n # Calculate the total number of characters in each list\n total_chars_lst1 = sum(len(s) for s in lst1)\n total_chars_lst2 = sum(len(s) for s in lst2)\n \n # Compare the total number of characters and return the appropriate list\n if total_chars_lst1 < total_chars_lst2:\n return lst1\n elif total_chars_lst1 > total_chars_lst2:\n return lst2\n else:\n return lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n '''\n def total_chars(lst):\n return sum(len(s) for s in lst)\n \n len1 = total_chars(lst1)\n len2 = total_chars(lst2)\n \n return lst1 if len1 <= len2 else lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n '''\n # Calculate total number of characters in each list\n total_chars_lst1 = sum(len(s) for s in lst1)\n total_chars_lst2 = sum(len(s) for s in lst2)\n \n # Return the list with fewer total characters, or the first list if equal\n return lst1 if total_chars_lst1 <= total_chars_lst2 else lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n \n if the two lists have the same number of chars, return the first list.\n '''\n # Calculate the total number of characters in both lists\n total_chars_lst1 = sum(len(s) for s in lst1)\n total_chars_lst2 = sum(len(s) for s in lst2)\n \n # Return the list with fewer total characters, or the first list if equal\n return lst1 if total_chars_lst1 <= total_chars_lst2 else lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n '''\n def total_chars(lst):\n return sum(len(s) for s in lst)\n \n count_lst1 = total_chars(lst1)\n count_lst2 = total_chars(lst2)\n \n return lst1 if count_lst1 <= count_lst2 else lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n '''\n # Calculate the total number of characters in each list\n total_chars1 = sum(len(s) for s in lst1)\n total_chars2 = sum(len(s) for s in lst2)\n\n # Compare the total number of characters and return the appropriate list\n if total_chars1 < total_chars2:\n return lst1\n elif total_chars1 > total_chars2:\n return lst2\n else:\n return lst1", "matching_cluster_idx": 7}]}, "HumanEval/85": {"dps": 92.35148514851484, "dps_norm": 60.833333333333336, "pass@1": 100.0, "profiled": [{"solution": "def add(lst):\n \"\"\"\n Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Args:\n lst (list): A non-empty list of integers.\n\n Returns:\n int: The sum of even elements at odd indices.\n\n Examples:\n >>> add([4, 2, 6, 7])\n 2\n \"\"\"\n # Initialize sum to 0\n total_sum = 0\n \n # Iterate through the list, starting from index 1 (the second element)\n for i in range(1, len(lst), 2):\n # Check if the current element is even\n if lst[i] % 2 == 0:\n total_sum += lst[i]\n \n return total_sum", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"\n Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Args:\n lst (list): A non-empty list of integers.\n\n Returns:\n int: The sum of even elements located at odd indices.\n\n Examples:\n >>> add([4, 2, 6, 7])\n 2\n >>> add([1, 3, 5, 7, 9, 11])\n 0\n >>> add([2, 4, 6, 8])\n 4\n \"\"\"\n return sum(value for index, value in enumerate(lst) if index % 2 != 0 and value % 2 == 0)", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"\n Given a non-empty list of integers lst. add the even elements that are at odd indices.\n \n Examples:\n add([4, 2, 6, 7]) ==> 2\n \"\"\"\n result = 0\n # Iterate through the list starting from index 1 (second element) with a step of 2\n for i in range(1, len(lst), 2):\n if lst[i] % 2 == 0:\n result += lst[i]\n return result", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices.\n \n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n return sum(num for idx, num in enumerate(lst) if idx % 2 != 0 and num % 2 == 0)", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"\n Given a non-empty list of integers lst. add the even elements that are at odd indices.\n \n Parameters:\n lst (list): A non-empty list of integers.\n \n Returns:\n int: The sum of even elements at odd indices.\n \"\"\"\n # Initialize the sum to 0\n result_sum = 0\n \n # Iterate through the list starting from the first odd index (1)\n for index in range(1, len(lst), 2):\n if lst[index] % 2 == 0:\n result_sum += lst[index]\n \n return result_sum", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"\n Given a non-empty list of integers lst. add the even elements that are at odd indices.\n \n Parameters:\n lst (list): A non-empty list of integers.\n \n Returns:\n int: Sum of even elements at odd indices.\n \n Examples:\n add([4, 2, 6, 7]) ==> 2\n add([1, 3, 5, 7, 9]) ==> 0\n \"\"\"\n # Initialize sum to 0\n total_sum = 0\n \n # Iterate over the list, considering only odd indices\n for index in range(1, len(lst), 2):\n if lst[index] % 2 == 0:\n total_sum += lst[index]\n \n return total_sum", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices.\"\"\"\n result = 0\n # Iterate through the list starting from index 1 (second element) with a step of 2\n for i in range(1, len(lst), 2):\n if lst[i] % 2 == 0:\n result += lst[i]\n return result", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"\n Given a non-empty list of integers lst, add the even elements that are at odd indices.\n \n Examples:\n add([4, 2, 6, 7]) ==> 2\n \"\"\"\n result = 0\n # Iterate through the list starting from index 1 (second element) with a step of 2\n for i in range(1, len(lst), 2):\n if lst[i] % 2 == 0:\n result += lst[i]\n return result", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"\n Given a non-empty list of integers lst. add the even elements that are at odd indices.\n \n Examples:\n add([4, 2, 6, 7]) ==> 2\n \"\"\"\n result = 0\n # Iterate through the list, starting from index 1 (second element) and increment by 2\n for i in range(1, len(lst), 2):\n # Check if the element at the current odd index is even\n if lst[i] % 2 == 0:\n result += lst[i]\n return result", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices.\n \n Examples:\n add([4, 2, 6, 7]) ==> 2\n \"\"\"\n result = 0\n # Iterate through the list starting from index 1 (second element) with a step of 2\n for i in range(1, len(lst), 2):\n if lst[i] % 2 == 0:\n result += lst[i]\n return result", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"\n Given a non-empty list of integers lst, add the even elements that are at odd indices.\n \n Args:\n lst (list): A non-empty list of integers.\n \n Returns:\n int: The sum of even elements at odd indices.\n \n Examples:\n >>> add([4, 2, 6, 7])\n 2\n \"\"\"\n sum_even_odd_indices = 0\n # Iterate through the list with index\n for index, value in enumerate(lst):\n # Check if the index is odd and the value is even\n if index % 2 != 0 and value % 2 == 0:\n sum_even_odd_indices += value\n return sum_even_odd_indices", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"\n Given a non-empty list of integers lst. add the even elements that are at odd indices.\n \n Args:\n lst (list): A non-empty list of integers.\n \n Returns:\n int: The sum of even elements at odd indices in the list.\n \"\"\"\n # Initialize the sum to 0\n total_sum = 0\n \n # Iterate through the list, starting from index 1 (the second element), stepping by 2\n for i in range(1, len(lst), 2):\n if lst[i] % 2 == 0:\n total_sum += lst[i]\n \n return total_sum", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"\n Given a non-empty list of integers lst. add the even elements that are at odd indices.\n \n Args:\n lst (list): A non-empty list of integers.\n\n Returns:\n int: The sum of even elements at odd indices.\n \"\"\"\n return sum(val for idx, val in enumerate(lst) if idx % 2 != 0 and val % 2 == 0)", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Args:\n lst (list): A non-empty list of integers.\n\n Returns:\n int: The sum of even elements located at odd indices in the list.\n\n Examples:\n >>> add([4, 2, 6, 7])\n 2\n \"\"\"\n # Initialize the sum to 0\n total_sum = 0\n \n # Iterate through the list, starting from index 1 (second element) and increment by 2\n for index in range(1, len(lst), 2):\n # Check if the element at the current index is even\n if lst[index] % 2 == 0:\n # Add it to the total sum\n total_sum += lst[index]\n \n return total_sum", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"\n Given a non-empty list of integers lst. add the even elements that are at odd indices.\n \n Examples:\n add([4, 2, 6, 7]) ==> 2\n \"\"\"\n result = 0\n for index, value in enumerate(lst):\n # Check if the index is odd and the value is even\n if index % 2 != 0 and value % 2 == 0:\n result += value\n return result", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices.\n \n Args:\n lst (list): A non-empty list of integers.\n \n Returns:\n int: The sum of even elements located at odd indices.\n \n Examples:\n >>> add([4, 2, 6, 7])\n 2\n >>> add([1, 3, 5, 7, 9, 11])\n 0\n >>> add([2, 4, 6, 8, 10])\n 4\n \"\"\"\n return sum(val for idx, val in enumerate(lst) if idx % 2 != 0 and val % 2 == 0)", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"\n Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2\n \"\"\"\n # Initialize the sum to 0\n total_sum = 0\n \n # Loop through the list starting from index 1 (the second element)\n for i in range(1, len(lst), 2):\n # Check if the element at the current index is even\n if lst[i] % 2 == 0:\n # Add it to the total sum\n total_sum += lst[i]\n \n return total_sum", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"\n Given a non-empty list of integers lst, add the even elements that are at odd indices.\n \n Examples:\n add([4, 2, 6, 7]) ==> 2\n \"\"\"\n result = 0\n # Iterate through the list, starting from index 1 (the second element)\n for i in range(1, len(lst), 2):\n # Check if the element at the current odd index is even\n if lst[i] % 2 == 0:\n result += lst[i]\n return result", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"\n Given a non-empty list of integers lst. add the even elements that are at odd indices.\n \n Args:\n lst (list): A non-empty list of integers.\n \n Returns:\n int: The sum of even elements at odd indices.\n \"\"\"\n # Initialize sum to 0\n sum_even_at_odd_indices = 0\n \n # Iterate over the list using enumerate to get index and value\n for index, value in enumerate(lst):\n # Check if the index is odd and the value is even\n if index % 2 != 0 and value % 2 == 0:\n sum_even_at_odd_indices += value\n \n return sum_even_at_odd_indices", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"\n Given a non-empty list of integers lst. add the even elements that are at odd indices.\n \n Args:\n lst (list): A non-empty list of integers.\n \n Returns:\n int: The sum of even elements located at odd indices in the list.\n \n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n sum_even_odd_indices = 0\n # Iterate through the list using index\n for index in range(1, len(lst), 2):\n if lst[index] % 2 == 0:\n sum_even_odd_indices += lst[index]\n return sum_even_odd_indices", "matching_cluster_idx": 3}]}, "HumanEval/86": {"dps": 81.12244897959184, "dps_norm": 89.0, "pass@1": 52.0, "profiled": [{"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n def sort_word(word):\n return ''.join(sorted(word))\n \n words = s.split(' ')\n sorted_words = [sort_word(word) for word in words]\n return ' '.join(sorted_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters are arranged in\n ascending order based on ASCII value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n # Function to sort characters in a word\n def sort_word(word):\n return ''.join(sorted(word))\n\n # Split the input string into words and sort each word\n sorted_words = [sort_word(word) for word in s.split(' ')]\n\n # Join the sorted words back into a sentence\n return ' '.join(sorted_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n # Split the string into words based on spaces\n words = s.split(' ')\n result = []\n\n for word in words:\n # Sort the characters of the word\n sorted_word = ''.join(sorted(word))\n result.append(sorted_word)\n\n # Join the sorted words back into a sentence\n return ' '.join(result)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n # Split the string into words\n words = s.split(' ')\n \n # Process each word\n shuffled_words = []\n for word in words:\n # Sort the characters in the word and join them back into a string\n sorted_word = ''.join(sorted(word))\n shuffled_words.append(sorted_word)\n \n # Join the shuffled words back into a sentence\n result = ' '.join(shuffled_words)\n return result", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n def sort_word(word):\n return ''.join(sorted(word))\n \n result = []\n word = \"\"\n for char in s:\n if char == ' ':\n if word:\n result.append(sort_word(word))\n word = \"\"\n result.append(char)\n else:\n word += char\n if word:\n result.append(sort_word(word))\n \n return ''.join(result)", "matching_cluster_idx": 1}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n \"\"\"\n def sort_word(word):\n return ''.join(sorted(word))\n \n # Split the string into words based on spaces\n words = s.split(' ')\n \n # Sort each word and reassemble the sentence\n shuffled_words = [sort_word(word) for word in words]\n \n # Join the sorted words back into a sentence\n return ' '.join(shuffled_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n def sort_chars_in_word(word):\n return ''.join(sorted(word))\n\n words = s.split(' ')\n shuffled_words = [sort_chars_in_word(word) for word in words]\n return ' '.join(shuffled_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n def sort_chars(word):\n return ''.join(sorted(word))\n \n result = []\n start = 0\n for i, char in enumerate(s):\n if char == ' ':\n result.append(sort_chars(s[start:i]))\n result.append(char)\n start = i + 1\n result.append(sort_chars(s[start:]))\n return ''.join(result)", "matching_cluster_idx": 2}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n # Function to sort characters in a word\n def sort_word(word):\n return ''.join(sorted(word))\n\n # Split the input string into words\n words = s.split(' ')\n # Apply the sort_word function to each word\n sorted_words = [sort_word(word) for word in words]\n # Join the sorted words back into a sentence\n return ' '.join(sorted_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n \"\"\"\n # Split the string into words based on spaces\n words = s.split(' ')\n \n # Process each word to sort the characters\n sorted_words = [''.join(sorted(word)) for word in words]\n \n # Join the sorted words back into a sentence\n result = ' '.join(sorted_words)\n \n return result", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n Parameters:\n s (str): The input string.\n\n Returns:\n str: The ordered version of the input string.\n\n Examples:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n # Split the input string into words\n words = s.split(' ')\n \n # Process each word, sort its characters in ascending ASCII order\n sorted_words = [''.join(sorted(word)) for word in words]\n \n # Join the processed words back into a sentence\n return ' '.join(sorted_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n def sort_word(word):\n return ''.join(sorted(word))\n\n # Split the string by spaces to handle words and keep track of spaces\n words = s.split(' ')\n sorted_words = [sort_word(word) for word in words]\n \n # Reconstruct the sentence\n result = ' '.join(sorted_words)\n return result", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n \"\"\"\n def sort_chars(word):\n return ''.join(sorted(word))\n \n result = []\n word = ''\n \n for char in s:\n if char == ' ':\n result.append(sort_chars(word))\n word = ''\n result.append(char)\n else:\n word += char\n \n # Sorting and adding the last word or remaining word\n result.append(sort_chars(word))\n \n return ''.join(result)", "matching_cluster_idx": 1}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n # Function to sort characters in a word\n def sort_word(word):\n return ''.join(sorted(word))\n \n # Split the sentence into words, process each word, and reassemble the sentence\n words = s.split(' ')\n sorted_words = [sort_word(word) for word in words]\n return ' '.join(sorted_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n # Split the input string into words based on spaces\n words = s.split(' ')\n \n # Process each word and sort its characters in ascending order\n sorted_words = [''.join(sorted(word)) for word in words]\n \n # Join the processed words back into a single string with spaces\n result = ' '.join(sorted_words)\n \n return result", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n \"\"\"\n # Split the string into words based on spaces\n words = s.split(' ')\n \n # Process each word: sort its characters in ascending ASCII order\n sorted_words = [''.join(sorted(word)) for word in words]\n \n # Join the sorted words back into a sentence\n return ' '.join(sorted_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n # Split the string into words\n words = s.split(' ')\n \n # Process each word\n shuffled_words = []\n for word in words:\n # Sort the characters in the word based on their ASCII value\n sorted_word = ''.join(sorted(word))\n # Append the sorted word to the list\n shuffled_words.append(sorted_word)\n \n # Join the processed words back into a sentence\n result = ' '.join(shuffled_words)\n return result", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n # Split the string into words\n words = s.split(' ')\n # Process each word, sort characters, and join them back into a word\n shuffled_words = [''.join(sorted(word)) for word in words]\n # Join the processed words back into a sentence\n result = ' '.join(shuffled_words)\n return result", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n \"\"\"\n def sort_word(word):\n return ''.join(sorted(word))\n \n words = s.split(' ')\n shuffled_words = [sort_word(word) for word in words]\n shuffled_sentence = ' '.join(shuffled_words)\n return shuffled_sentence", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n def sort_word(word):\n return ''.join(sorted(word))\n \n result = []\n word = []\n for char in s:\n if char == ' ':\n result.append(sort_word(word))\n word = []\n result.append(char)\n else:\n word.append(char)\n result.append(sort_word(word))\n \n return ''.join(result)", "matching_cluster_idx": 1}]}, "HumanEval/87": {"dps": 90.25936599423632, "dps_norm": 56.42857142857143, "pass@1": 82.0, "profiled": [{"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \"\"\"\n # Find all the positions of x\n positions = []\n for row_index, row in enumerate(lst):\n for col_index, value in enumerate(row):\n if value == x:\n positions.append((row_index, col_index))\n \n # Sort the positions\n positions.sort(key=lambda pos: (pos[0], -pos[1]))\n \n return positions", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n coordinates = []\n for i, row in enumerate(lst):\n for j, value in enumerate(row):\n if value == x:\n coordinates.append((i, j))\n \n # Sort by row in ascending order, and then by column in descending order within the same row\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n \n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n coordinates = []\n for i, row in enumerate(lst):\n for j, value in enumerate(row):\n if value == x:\n coordinates.append((i, j))\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n # Find all occurrences of x\n coordinates = [(i, j) for i, row in enumerate(lst) for j, val in enumerate(row) if val == x]\n \n # Sort the coordinates first by row in ascending order\n # Then, sort by column in descending order within the same row\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n \n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n # Initialize an empty list to hold the coordinates\n coordinates = []\n \n # Iterate through each row and column index\n for row_idx, row in enumerate(lst):\n for col_idx, value in enumerate(row):\n if value == x:\n coordinates.append((row_idx, col_idx))\n \n # Sort the coordinates by row in ascending order, then by column in descending order\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n \n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n # Find the coordinates of x in the list\n coordinates = []\n for row_idx, row in enumerate(lst):\n for col_idx, value in enumerate(row):\n if value == x:\n coordinates.append((row_idx, col_idx))\n \n # Sort the coordinates by row in ascending order and then by column in descending order\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n \n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n # Find all coordinates of x\n coordinates = []\n for i, row in enumerate(lst):\n for j, value in enumerate(row):\n if value == x:\n coordinates.append((i, j))\n \n # Sort by rows in ascending order, then by columns in descending order for the same row\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n \n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n result = []\n for row_index, row in enumerate(lst):\n for col_index, value in enumerate(row):\n if value == x:\n result.append((row_index, col_index))\n # Sort by row in ascending order and then by column in descending order within the same row\n result.sort(key=lambda coord: (coord[0], -coord[1]))\n return result", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n coordinates = []\n for i, row in enumerate(lst):\n for j, value in enumerate(row):\n if value == x:\n coordinates.append((i, j))\n \n # Sort by row in ascending order, and then by column in descending order within each row\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n \n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n # List to store the coordinates\n coords = []\n # Iterate through each row and column in the list\n for i, row in enumerate(lst):\n for j, val in enumerate(row):\n if val == x:\n # Append the coordinate (row, column) to the list\n coords.append((i, j))\n \n # Sort the coordinates by row in ascending order, then by column in descending order\n sorted_coords = sorted(coords, key=lambda coord: (coord[0], -coord[1]))\n \n return sorted_coords", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n # List to store the coordinates\n coordinates = []\n \n # Iterate through each row in the list\n for i, row in enumerate(lst):\n # Find all indices of x in the current row\n indices = [j for j, value in enumerate(row) if value == x]\n # Add the coordinates to the list, with column indices sorted in descending order\n coordinates.extend([(i, j) for j in sorted(indices, reverse=True)])\n \n # Sort the coordinates by row in ascending order\n coordinates.sort(key=lambda coord: coord[0])\n \n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n coordinates = []\n \n for i, row in enumerate(lst):\n for j, value in enumerate(row):\n if value == x:\n coordinates.append((i, j))\n \n # Sort coordinates initially by rows in ascending order\n # Then sort coordinates of the same row by columns in descending order\n coordinates.sort(key=lambda c: (c[0], -c[1]))\n \n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n coordinates = []\n for row_idx, row in enumerate(lst):\n for col_idx, val in enumerate(row):\n if val == x:\n coordinates.append((row_idx, col_idx))\n \n # Sort coordinates by row in ascending order and then by column in descending order for the same row\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n \n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n coordinates = []\n for i, row in enumerate(lst):\n for j, val in enumerate(row):\n if val == x:\n coordinates.append((i, j))\n # Sort by row in ascending order, and then by column in descending order\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n # Collect the coordinates\n coordinates = []\n for i, row in enumerate(lst):\n for j, value in enumerate(row):\n if value == x:\n coordinates.append((i, j))\n \n # Sort coordinates first by row in ascending order\n # and then by column in descending order within the same row\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n \n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n coordinates = []\n for i, row in enumerate(lst):\n for j, value in enumerate(row):\n if value == x:\n coordinates.append((i, j))\n # Sort by rows in ascending order and then by columns in descending order for each row\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \"\"\"\n coordinates = []\n for row_idx, row in enumerate(lst):\n for col_idx, val in enumerate(row):\n if val == x:\n coordinates.append((row_idx, col_idx))\n \n # Sort by row in ascending order, and by column in descending order within the same row\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \"\"\"\n coordinates = []\n for i, row in enumerate(lst):\n for j, val in enumerate(row):\n if val == x:\n coordinates.append((i, j))\n \n # First sort by row in ascending order\n coordinates.sort(key=lambda coord: coord[0])\n \n # Then sort by column in descending order for the same row\n for row_index in range(len(coordinates) - 1):\n for col_index in range(row_index + 1, len(coordinates)):\n if coordinates[row_index][0] == coordinates[col_index][0]:\n if coordinates[row_index][1] < coordinates[col_index][1]:\n coordinates[row_index], coordinates[col_index] = coordinates[col_index], coordinates[row_index]\n \n return coordinates", "matching_cluster_idx": 2}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \"\"\"\n coordinates = []\n for row_idx, row in enumerate(lst):\n for col_idx, value in enumerate(row):\n if value == x:\n coordinates.append((row_idx, col_idx))\n \n # Sort by row in ascending order and then by column in descending order within the same row\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n \n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \"\"\"\n # Find all the coordinates of x in the list\n coordinates = []\n for row_idx, row in enumerate(lst):\n for col_idx, val in enumerate(row):\n if val == x:\n coordinates.append((row_idx, col_idx))\n \n # Sort the coordinates by rows in ascending order\n # and then by columns in descending order within each row\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n \n return coordinates", "matching_cluster_idx": 3}]}, "HumanEval/89": {"dps": 96.70103092783506, "dps_norm": 31.42857142857143, "pass@1": 94.0, "profiled": [{"solution": "def encrypt(s):\n \"\"\"\n Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n \"\"\"\n alphabet = 'abcdefghijklmnopqrstuvwxyz'\n encrypted_string = ''\n \n for char in s:\n if char.isalpha(): # Check if character is an alphabet\n # Find the index of the character in the alphabet\n index = alphabet.index(char.lower())\n # Calculate the new index after shifting\n new_index = (index + 4) % 26 # 2 * 2 = 4\n # Append the new character to the encrypted string\n if char.islower():\n encrypted_string += alphabet[new_index]\n else:\n encrypted_string += alphabet[new_index].upper()\n else:\n # Non-alphabetic characters are appended as is\n encrypted_string += char\n \n return encrypted_string", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"\n Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n \"\"\"\n # Define the original and shifted alphabets\n alphabet = 'abcdefghijklmnopqrstuvwxyz'\n shifted_alphabet = alphabet[4:] + alphabet[:4] # Shift by 8 positions (2*2 * 2)\n \n # Create a translation table from original to shifted alphabet\n translation_table = str.maketrans(alphabet, shifted_alphabet)\n \n # Return the translated string\n return s.translate(translation_table)", "matching_cluster_idx": 5}, {"solution": "def encrypt(s):\n \"\"\"Encrypts a string by rotating the alphabet down by two multiplied by two places.\"\"\"\n result = \"\"\n for char in s:\n # Check if the character is a letter\n if char.isalpha():\n # Get the base ASCII value for 'a' or 'A' depending on the case\n base = ord('a') if char.islower() else ord('A')\n # Calculate the new character after rotation\n new_char = chr((ord(char) - base + 4) % 26 + base)\n result += new_char\n else:\n # If it's not a letter, keep the character as is\n result += char\n return result", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"\n Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n # Define the original and shifted alphabets\n original_alphabet = 'abcdefghijklmnopqrstuvwxyz'\n shifted_alphabet = original_alphabet[4:] + original_alphabet[:4]\n \n # Encrypt each character in the string\n encrypted_chars = []\n for char in s:\n if char.isalpha(): # Check if the character is a letter\n # Find the position of the character in the original alphabet and get the corresponding character from the shifted alphabet\n index = original_alphabet.find(char.lower())\n new_char = shifted_alphabet[index]\n # Preserve the original case\n if char.isupper():\n new_char = new_char.upper()\n encrypted_chars.append(new_char)\n else:\n # Non-alphabetic characters are not encrypted\n encrypted_chars.append(char)\n \n # Join the characters to form the encrypted string\n return ''.join(encrypted_chars)", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"\n Create a function encrypt that takes a string as an argument and returns a string encrypted\n with the alphabet being rotated. The alphabet should be rotated in a manner such that the letters\n shift down by two multiplied to two places.\n \n Example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n encrypted = ''\n for char in s:\n if 'a' <= char <= 'z':\n # Calculate the new character after rotating by 4 (down by two places, multiplied by 2)\n new_char = chr(((ord(char) - ord('a') + 4) % 26) + ord('a'))\n elif 'A' <= char <= 'Z':\n # Calculate the new character after rotating by 4 (down by two places, multiplied by 2)\n new_char = chr(((ord(char) - ord('A') + 4) % 26) + ord('A'))\n else:\n new_char = char\n encrypted += new_char\n return encrypted", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"\n Encrypts a string by rotating the alphabet down by two multiplied by two places.\n \n Args:\n s (str): The input string to be encrypted.\n \n Returns:\n str: The encrypted string.\n \"\"\"\n # Define the alphabet\n alphabet = \"abcdefghijklmnopqrstuvwxyz\"\n encrypted_s = \"\"\n \n # Rotate the alphabet down by two multiplied by two places (4 places)\n rotated_alphabet = alphabet[4:] + alphabet[:4]\n \n # Map each character in the input string to the corresponding character in the rotated alphabet\n for char in s:\n if char.lower() in alphabet:\n # Preserve the original case\n is_upper = char.isupper()\n encrypted_char = rotated_alphabet[alphabet.index(char.lower())]\n encrypted_s += encrypted_char.upper() if is_upper else encrypted_char\n else:\n encrypted_s += char\n \n return encrypted_s", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"\n Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n # Define the alphabet\n alphabet = 'abcdefghijklmnopqrstuvwxyz'\n encrypted_text = ''\n \n # Perform the encryption\n for char in s:\n if char.isalpha(): # Check if the character is a letter\n # Find the index of the character in the alphabet\n index = alphabet.index(char.lower())\n # Calculate the new index after shifting\n new_index = (index + (2 * 2)) % 26 # 2*2 is the shift amount\n # Append the new character to the encrypted string\n if char.isupper():\n encrypted_text += alphabet[new_index].upper()\n else:\n encrypted_text += alphabet[new_index]\n else:\n encrypted_text += char # Non-alphabetic characters are added as is\n \n return encrypted_text", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"\n Create a function encrypt that takes a string as an argument and returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters shift down by two multiplied by two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n encrypted_string = \"\"\n for char in s:\n if 'a' <= char <= 'z':\n # Shift the character down by two places and then double that shift\n shift = 2 * 2\n # Wrap around the alphabet if necessary\n new_char = chr(((ord(char) - ord('a') + shift) % 26) + ord('a'))\n elif 'A' <= char <= 'Z':\n # Shift the character down by two places and then double that shift\n shift = 2 * 2\n # Wrap around the alphabet if necessary\n new_char = chr(((ord(char) - ord('A') + shift) % 26) + ord('A'))\n else:\n # Non-alphabetic characters are not changed\n new_char = char\n encrypted_string += new_char\n return encrypted_string", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"\n Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n # Define the alphabet\n alphabet = 'abcdefghijklmnopqrstuvwxyz'\n encrypted_text = ''\n \n # Perform the rotation\n for char in s:\n if char.isalpha(): # Check if the character is a letter\n # Find the position of the character in the alphabet\n pos = alphabet.index(char.lower())\n # Calculate the new position (shift down by two multiplied to two places)\n new_pos = (pos + 4) % 26 # 2*2 = 4\n # Append the new character to the encrypted text, preserving the case\n if char.islower():\n encrypted_text += alphabet[new_pos]\n else:\n encrypted_text += alphabet[new_pos].upper()\n else:\n # Non-alphabet characters are added without changes\n encrypted_text += char\n \n return encrypted_text", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"\n Encrypts a string by shifting each letter down by two multiplied to two places\n in the alphabet. Wraps around to the beginning of the alphabet if necessary.\n \n :param s: The input string to encrypt\n :return: The encrypted string\n \"\"\"\n # Define the alphabet\n alphabet = 'abcdefghijklmnopqrstuvwxyz'\n encrypted = ''\n \n # Encrypt each character in the string\n for char in s:\n if char.isalpha(): # Check if the character is a letter\n # Find the position of the character in the alphabet\n pos = alphabet.index(char.lower())\n # Calculate the new position after shifting\n new_pos = (pos + 4) % 26 # Shift down by two multiplied by two\n # Append the new character to the encrypted string\n if char.isupper():\n encrypted += alphabet[new_pos].upper()\n else:\n encrypted += alphabet[new_pos]\n else:\n # Non-alphabetic characters are added as is\n encrypted += char\n \n return encrypted", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"\n Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n # Define the alphabet\n alphabet = 'abcdefghijklmnopqrstuvwxyz'\n encrypted = ''\n \n # Loop through each character in the input string\n for char in s:\n # Find the character in the alphabet\n if char in alphabet:\n # Calculate the new position with the rotation\n new_pos = (alphabet.index(char) + 4) % 26\n # Append the encrypted character to the result\n encrypted += alphabet[new_pos]\n else:\n # If the character is not in the alphabet, keep it as is\n encrypted += char\n \n return encrypted", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"\n Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n # Define the alphabet\n alphabet = 'abcdefghijklmnopqrstuvwxyz'\n encrypted = ''\n \n # Define the shift value\n shift_value = 4 # 2 * 2 = 4, as per the problem statement\n \n for char in s:\n if char.isalpha():\n # Find the position of the character in the alphabet\n pos = alphabet.index(char.lower())\n # Calculate the new position after rotation\n new_pos = (pos + shift_value) % 26\n # Append the new character, keeping the original case\n if char.islower():\n encrypted += alphabet[new_pos]\n else:\n encrypted += alphabet[new_pos].upper()\n else:\n # Non-alphabetic characters are added unchanged\n encrypted += char\n \n return encrypted", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"\n Encrypts a given string by rotating the alphabet down by two multiplied by two places.\n \n Args:\n s (str): The input string to be encrypted.\n \n Returns:\n str: The encrypted string.\n \"\"\"\n # Define the original and shifted alphabets\n alphabet = 'abcdefghijklmnopqrstuvwxyz'\n shifted_alphabet = alphabet[4:] + alphabet[:4] # Shift the alphabet down by 8 positions\n \n # Initialize the encrypted string\n encrypted = ''\n \n # Encrypt the string\n for char in s:\n if char.lower() in alphabet:\n # Determine the index of the character in the alphabet\n index = alphabet.index(char.lower())\n # Find the corresponding character in the shifted alphabet\n new_char = shifted_alphabet[index]\n # Preserve the original case\n if char.isupper():\n new_char = new_char.upper()\n encrypted += new_char\n else:\n # Non-alphabet characters are not encrypted\n encrypted += char\n \n return encrypted", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"\n Create a function encrypt that takes a string as an argument and returns a string\n encrypted with the alphabet being rotated. The alphabet should be rotated in a manner\n such that the letters shift down by two multiplied to two places.\n \n Args:\n s (str): The input string to be encrypted.\n\n Returns:\n str: The encrypted string.\n \"\"\"\n # Define the original and shifted alphabets\n original_alphabet = 'abcdefghijklmnopqrstuvwxyz'\n shifted_alphabet = original_alphabet[2*2:] + original_alphabet[:2*2]\n \n # Encrypt the string\n encrypted_string = ''\n for char in s:\n if char.lower() in original_alphabet:\n # Determine the case of the character\n is_upper = char.isupper()\n # Find the position and shift the character\n shifted_char = shifted_alphabet[original_alphabet.find(char.lower())]\n # Maintain the case\n if is_upper:\n shifted_char = shifted_char.upper()\n encrypted_string += shifted_char\n else:\n encrypted_string += char\n \n return encrypted_string", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"\n Create a function encrypt that takes a string as an argument and returns a string encrypted with the alphabet being rotated.\n The alphabet should be rotated in a manner such that the letters shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n # Define the original and rotated alphabet\n original_alphabet = 'abcdefghijklmnopqrstuvwxyz'\n rotated_alphabet = original_alphabet[4:] + original_alphabet[:4]\n \n # Encrypt the string\n encrypted_string = ''.join(rotated_alphabet[original_alphabet.index(char)] if char.isalpha() else char for char in s)\n \n return encrypted_string", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"\n Encrypts a string by rotating the alphabet. Each letter is shifted down by \n two multiplied to two places (i.e., 4 places). The function maintains case \n sensitivity and does not change non-alphabetic characters.\n\n :param s: The string to be encrypted.\n :return: The encrypted string.\n \"\"\"\n encrypted = \"\"\n for char in s:\n if char.isalpha():\n # Determine if the character is uppercase or lowercase for correct ASCII range\n ascii_offset = 65 if char.isupper() else 97\n # Rotate the character by 4 places\n rotated_char = chr((ord(char) - ascii_offset + 4) % 26 + ascii_offset)\n encrypted += rotated_char\n else:\n encrypted += char\n return encrypted", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"\n Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n encrypted = \"\"\n for char in s:\n if 'a' <= char <= 'z':\n # Calculate the new character with a shift of 4 (2 * 2)\n new_char = chr((ord(char) - ord('a') + 4) % 26 + ord('a'))\n elif 'A' <= char <= 'Z':\n # Calculate the new character with a shift of 4 (2 * 2)\n new_char = chr((ord(char) - ord('A') + 4) % 26 + ord('A'))\n else:\n new_char = char\n encrypted += new_char\n return encrypted", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"\n Encrypts a string by rotating its alphabet down by two multiplied by two places.\n \"\"\"\n encrypted = \"\"\n for char in s:\n if 'a' <= char <= 'z':\n # Calculate new character position and wrap around using modulo 26\n new_char = chr(((ord(char) - ord('a') + 4) % 26) + ord('a'))\n elif 'A' <= char <= 'Z':\n # Calculate new character position and wrap around using modulo 26\n new_char = chr(((ord(char) - ord('A') + 4) % 26) + ord('A'))\n else:\n new_char = char\n encrypted += new_char\n return encrypted", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"\n Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n \"\"\"\n # Define the alphabet\n alphabet = 'abcdefghijklmnopqrstuvwxyz'\n encrypted = ''\n \n # Rotate the alphabet down by two multiplied by two places (i.e., 4 places)\n rotated_alphabet = alphabet[4:] + alphabet[:4]\n \n # Encrypt each character in the input string\n for char in s:\n if char in alphabet:\n index = alphabet.index(char)\n encrypted += rotated_alphabet[index]\n else:\n encrypted += char # Non-alphabet characters remain unchanged\n \n return encrypted", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"\n Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n result = \"\"\n for char in s:\n if 'a' <= char <= 'z':\n # Calculate the new character by rotating the alphabet\n new_char = chr((ord(char) - ord('a') + 4) % 26 + ord('a'))\n result += new_char\n elif 'A' <= char <= 'Z':\n # Calculate the new character by rotating the alphabet for uppercase\n new_char = chr((ord(char) - ord('A') + 4) % 26 + ord('A'))\n result += new_char\n else:\n # Non-alphabetic characters remain unchanged\n result += char\n return result", "matching_cluster_idx": 1}]}, "HumanEval/90": {"dps": 87.54863813229572, "dps_norm": 58.333333333333336, "pass@1": 100.0, "profiled": [{"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n # Remove duplicates and sort the list\n sorted_unique_lst = sorted(set(lst))\n \n # Check if there are at least 2 unique elements\n if len(sorted_unique_lst) < 2:\n return None\n else:\n # Return the second smallest element\n return sorted_unique_lst[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n # Remove duplicates and sort the list\n unique_sorted_list = sorted(set(lst))\n \n # Check if there are at least 2 unique elements\n if len(unique_sorted_list) < 2:\n return None\n else:\n return unique_sorted_list[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \"\"\"\n if len(lst) < 2:\n return None\n \n # Remove duplicates by converting to a set, then sort the result\n unique_sorted_list = sorted(set(lst))\n \n # Check if we have at least 2 unique elements\n if len(unique_sorted_list) < 2:\n return None\n else:\n return unique_sorted_list[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n # Remove duplicates by converting to a set, then sort\n sorted_unique_lst = sorted(set(lst))\n \n # Check if there are at least 2 unique elements\n if len(sorted_unique_lst) < 2:\n return None\n \n # Return the second smallest element\n return sorted_unique_lst[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n # Remove duplicates and sort the list\n sorted_unique_lst = sorted(set(lst))\n \n # Check if there are at least 2 unique elements\n if len(sorted_unique_lst) < 2:\n return None\n else:\n return sorted_unique_lst[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n \n # Remove duplicates to avoid issues with finding the second smallest number\n unique_lst = list(set(lst))\n \n # Sort the unique list to find the second smallest element\n unique_lst.sort()\n \n # Return the second smallest element if it exists\n return unique_lst[1] if len(unique_lst) > 1 else None", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n # Remove duplicates and sort the list\n unique_sorted_list = sorted(set(lst))\n \n # Check if we have at least 2 unique elements\n if len(unique_sorted_list) < 2:\n return None\n else:\n # Return the second smallest element\n return unique_sorted_list[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n # Remove duplicates to avoid issues with the smallest element being the same\n unique_sorted_lst = sorted(set(lst))\n \n # Check if there are at least 2 unique elements\n if len(unique_sorted_lst) < 2:\n return None\n \n # Return the second smallest element\n return unique_sorted_lst[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \"\"\"\n # Remove duplicates by converting to a set\n unique_elements = set(lst)\n \n # Return None if there are less than 2 unique elements\n if len(unique_elements) < 2:\n return None\n \n # Convert back to a list and sort it\n sorted_unique_elements = sorted(unique_elements)\n \n # The 2nd smallest element is now the first element in the sorted list\n return sorted_unique_elements[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n # Remove duplicates to handle cases like [1, 1]\n unique_lst = list(set(lst))\n \n # Sort the list\n unique_lst.sort()\n \n # Check if there are at least 2 unique elements\n if len(unique_lst) < 2:\n return None\n else:\n return unique_lst[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \"\"\"\n if len(lst) < 2:\n return None\n \n # Remove duplicates and sort the list\n sorted_unique_lst = sorted(set(lst))\n \n # Check if we have at least 2 unique elements\n if len(sorted_unique_lst) < 2:\n return None\n \n # Return the second smallest element\n return sorted_unique_lst[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n # First, check if the list has at least 2 unique elements\n unique_elements = set(lst)\n if len(unique_elements) < 2:\n return None\n \n # Convert the set back to a list and sort it\n sorted_unique_elements = sorted(unique_elements)\n \n # Return the second element in the sorted list\n return sorted_unique_elements[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n # Remove duplicates and sort the list\n sorted_unique_lst = sorted(set(lst))\n \n # Check if there are at least 2 unique elements\n if len(sorted_unique_lst) < 2:\n return None\n else:\n return sorted_unique_lst[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n \n # Remove duplicates and sort the list\n sorted_unique_lst = sorted(set(lst))\n \n # Check if we have at least 2 unique elements\n if len(sorted_unique_lst) < 2:\n return None\n \n # Return the second smallest element\n return sorted_unique_lst[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n # Remove duplicates by converting to a set and then back to a sorted list\n sorted_unique_lst = sorted(set(lst))\n \n # Check if there are at least 2 unique elements\n if len(sorted_unique_lst) < 2:\n return None\n else:\n return sorted_unique_lst[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n # Remove duplicates and sort the list\n sorted_unique_lst = sorted(set(lst))\n \n # Check if there are at least 2 unique elements\n if len(sorted_unique_lst) < 2:\n return None\n else:\n return sorted_unique_lst[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n \n # Remove duplicates and sort the list\n sorted_unique_lst = sorted(set(lst))\n \n # Check if there is a second smallest element\n if len(sorted_unique_lst) < 2:\n return None\n \n return sorted_unique_lst[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n \n # Remove duplicates by converting the list to a set\n unique_lst = set(lst)\n \n # Check if there are at least 2 unique elements\n if len(unique_lst) < 2:\n return None\n \n # Convert the set back to a list and sort it\n sorted_lst = sorted(unique_lst)\n \n # Return the second element in the sorted list\n return sorted_lst[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n # Remove duplicates and sort the list\n sorted_list = sorted(set(lst))\n \n # Check if there are at least 2 unique elements\n if len(sorted_list) < 2:\n return None\n else:\n return sorted_list[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n # Remove duplicates and sort the list\n unique_sorted_lst = sorted(set(lst))\n \n # Check if there are at least 2 unique elements\n if len(unique_sorted_lst) < 2:\n return None\n \n # Return the second smallest element\n return unique_sorted_lst[1]", "matching_cluster_idx": 6}]}, "HumanEval/113": {"dps": 98.98580121703854, "dps_norm": 66.66666666666667, "pass@1": 83.0, "profiled": [{"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n \"\"\"\n def count_odds(s):\n return sum(int(digit) % 2 != 0 for digit in s)\n \n result = []\n for index, item in enumerate(lst, start=1):\n odd_count = count_odds(item)\n formatted_string = f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\"\n result.append(formatted_string)\n \n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n \"\"\"\n def count_odds(s):\n \"\"\"Helper function to count odd digits in a string.\"\"\"\n return sum(1 for char in s if int(char) % 2 != 0)\n \n result = []\n for i, s in enumerate(lst):\n odd_count = count_odds(s)\n result.append(f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\")\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n def count_odds(s):\n return sum(1 for char in s if int(char) % 2 != 0)\n\n result = []\n for index, s in enumerate(lst):\n odd_count = count_odds(s)\n result.append(f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\")\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n result = []\n for index, s in enumerate(lst):\n num_odds = sum(1 for char in s if int(char) % 2 != 0)\n odd_str = f\"the number of odd elements {num_odds}n the str{num_odds}ng {num_odds} of the {num_odds}nput.\"\n result.append(odd_str)\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n Args:\n lst (list): A list of strings, where each string consists of only digits.\n\n Returns:\n list: A list of strings with the count of odd digits and placeholders.\n\n Examples:\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n result = []\n for i, s in enumerate(lst):\n odd_count = sum(1 for c in s if int(c) % 2 != 0)\n result.append(f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\")\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n \"\"\"\n def count_odds(s):\n return sum(int(digit) % 2 != 0 for digit in s)\n \n result = []\n for i, s in enumerate(lst, 1):\n odd_count = count_odds(s)\n result.append(f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\")\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n def count_odds(s):\n return sum(int(digit) % 2 != 0 for digit in s)\n\n result = []\n for index, item in enumerate(lst, start=1):\n odd_count = count_odds(item)\n result.append(f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\")\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n result = []\n for index, s in enumerate(lst):\n # Count the number of odd digits in the current string\n odd_count = sum(1 for char in s if int(char) % 2 != 0)\n # Construct the output string\n output_str = f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\"\n result.append(output_str)\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n \"\"\"\n result = []\n for index, s in enumerate(lst):\n # Count the number of odd digits in the current string\n odd_count = sum(1 for char in s if int(char) % 2 != 0)\n # Format the output string\n output = f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\"\n result.append(output)\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n \"\"\"\n def count_odds(s):\n return sum(1 for char in s if int(char) % 2 != 0)\n \n result = []\n for i, s in enumerate(lst):\n odd_count = count_odds(s)\n result.append(f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\")\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n \"\"\"\n result = []\n for index, s in enumerate(lst):\n # Count the number of odd digits in the current string\n odd_count = sum(1 for char in s if int(char) % 2 != 0)\n # Format the result string\n formatted_result = f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\"\n result.append(formatted_result)\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n \"\"\"\n result = []\n for index, s in enumerate(lst):\n # Count the number of odd digits in the current string\n odd_count = sum(1 for char in s if int(char) % 2 != 0)\n # Format the result string with the count of odd digits\n result.append(f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\")\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n \"\"\"\n def count_odds(s):\n return sum(int(digit) % 2 for digit in s)\n \n result = []\n for index, s in enumerate(lst):\n odd_count = count_odds(s)\n odd_str = str(odd_count)\n result.append(f\"the number of odd elements {odd_str}n the str{odd_str}ng {odd_str} of the {odd_str}nput.\")\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n def count_odds(s):\n # Count the number of odd digits in the string\n return sum(1 for c in s if int(c) % 2 != 0)\n \n result = []\n for i, s in enumerate(lst):\n odd_count = count_odds(s)\n result.append(f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\")\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n \"\"\"\n def count_odds(s):\n return sum(1 for char in s if int(char) % 2 != 0)\n\n result = []\n for index, item in enumerate(lst):\n odd_count = count_odds(item)\n result.append(f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\")\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n \"\"\"\n def count_odds(s):\n \"\"\"Helper function to count the number of odd digits in a string.\"\"\"\n return sum(int(digit) % 2 != 0 for digit in s)\n\n result = []\n for index, string in enumerate(lst):\n odd_count = count_odds(string)\n result.append(f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\")\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n def count_odds(s):\n return sum(1 for char in s if int(char) % 2 != 0)\n \n result = []\n for index, s in enumerate(lst):\n num_odds = count_odds(s)\n result.append(f\"the number of odd elements {num_odds}n the str{num_odds}ng {num_odds} of the {num_odds}nput.\")\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n \"\"\"\n def count_odds(s):\n # Count the number of odd digits in the string\n return sum(1 for char in s if int(char) % 2 != 0)\n \n result = []\n for index, string in enumerate(lst, start=1):\n num_odds = count_odds(string)\n result.append(f\"the number of odd elements {num_odds}n the str{num_odds}ng {num_odds} of the {num_odds}nput.\")\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n \"\"\"\n def count_odds(s):\n \"\"\"Helper function to count odd digits in a string.\"\"\"\n return sum(1 for char in s if int(char) % 2 != 0)\n \n result = []\n for index, value in enumerate(lst):\n odd_count = count_odds(value)\n result.append(f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\")\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n \n Args:\n lst (list): A list of strings, where each string contains only digits.\n \n Returns:\n list: A list of strings with the number of odd elements replaced in the template string.\n \"\"\"\n def count_odds(s):\n return sum(1 for char in s if int(char) % 2 != 0)\n \n result = []\n for index, string in enumerate(lst):\n odd_count = count_odds(string)\n formatted_str = f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\"\n result.append(formatted_str)\n return result", "matching_cluster_idx": 3}]}, "HumanEval/119": {"dps": 81.3953488372093, "dps_norm": 96.0, "pass@1": 90.0, "profiled": [{"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n # Define a function to check if a string is balanced\n def is_balanced(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n else:\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n # Check both possible concatenations\n if is_balanced(lst[0] + lst[1]) or is_balanced(lst[1] + lst[0]):\n return 'Yes'\n else:\n return 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n '''\n def is_good(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n else:\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n \n # Check both possible concatenations\n if is_good(lst[0] + lst[1]) or is_good(lst[1] + lst[0]):\n return 'Yes'\n return 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n def is_good_string(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n else:\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n \n string1, string2 = lst[0], lst[1]\n \n # Check if concatenating in original order forms a good string\n if is_good_string(string1 + string2) or is_good_string(string2 + string1):\n return 'Yes'\n else:\n return 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n # Define a helper function to check if a string is balanced\n def is_balanced(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n else:\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n # Check both possible concatenations\n str1, str2 = lst[0], lst[1]\n if is_balanced(str1 + str2) or is_balanced(str2 + str1):\n return 'Yes'\n else:\n return 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n # Helper function to check if a string is balanced\n def is_balanced(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n else:\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n # Check both possible concatenations\n str1, str2 = lst[0], lst[1]\n if is_balanced(str1 + str2) or is_balanced(str2 + str1):\n return 'Yes'\n else:\n return 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n str1, str2 = lst\n\n # Function to check if a concatenated string is balanced\n def is_balanced(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n else:\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n # Check both possible concatenations\n if is_balanced(str1 + str2) or is_balanced(str2 + str1):\n return 'Yes'\n else:\n return 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n # Concatenate both lists in both possible orders\n concat1 = lst[0] + lst[1]\n concat2 = lst[1] + lst[0]\n\n def is_balanced(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n else:\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n # Check if either concatenation is balanced\n if is_balanced(concat1) or is_balanced(concat2):\n return 'Yes'\n else:\n return 'No'", "matching_cluster_idx": 3}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n s1, s2 = lst\n # Check if concatenating in both possible orders results in a balanced string\n if is_balanced(s1 + s2) or is_balanced(s2 + s1):\n return 'Yes'\n else:\n return 'No'\ndef is_balanced(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n else:\n balance -= 1\n # If balance is negative, parentheses are not balanced\n if balance < 0:\n return False\n # If balance is zero, parentheses are balanced\n return balance == 0", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n str1, str2 = lst\n\n # Check if the concatenated string in order 1 is good\n if is_balanced(str1 + str2):\n return 'Yes'\n # Check if the concatenated string in order 2 is good\n if is_balanced(str2 + str1):\n return 'Yes'\n \n return 'No'\ndef is_balanced(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n elif char == ')':\n balance -= 1\n # If balance is negative, parentheses are unbalanced\n if balance < 0:\n return False\n return balance == 0", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n def is_good_string(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n else:\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n # Check both possible concatenations\n str1, str2 = lst[0], lst[1]\n if is_good_string(str1 + str2) or is_good_string(str2 + str1):\n return 'Yes'\n else:\n return 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n # Check if the first string followed by the second is balanced\n first_follow_second = lst[0] + lst[1]\n balance = 0\n for char in first_follow_second:\n if char == '(':\n balance += 1\n else:\n balance -= 1\n if balance < 0:\n break\n if balance == 0:\n return 'Yes'\n \n # Check if the second string followed by the first is balanced\n second_follow_first = lst[1] + lst[0]\n balance = 0\n for char in second_follow_first:\n if char == '(':\n balance += 1\n else:\n balance -= 1\n if balance < 0:\n break\n if balance == 0:\n return 'Yes'\n \n return 'No'", "matching_cluster_idx": 3}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n # Try both possible concatenations and check if either is balanced\n for order in [lst, lst[::-1]]:\n balance = 0\n for char in order[0] + order[1]:\n if char == '(':\n balance += 1\n else:\n balance -= 1\n # If balance goes negative, it means we have more closing parentheses\n if balance < 0:\n break\n else:\n # If we didn't break, the balance is zero and it's balanced\n if balance == 0:\n return 'Yes'\n return 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n # Helper function to check if a string is balanced\n def is_balanced(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n else:\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n # Check if concatenating in the original order is balanced\n if is_balanced(lst[0] + lst[1]):\n return 'Yes'\n\n # Check if concatenating in the reverse order is balanced\n if is_balanced(lst[1] + lst[0]):\n return 'Yes'\n\n # If neither order works, return 'No'\n return 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n # First string followed by the second string\n case1 = ''.join(lst)\n # Second string followed by the first string\n case2 = ''.join(reversed(lst))\n \n def is_balanced(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n else:\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n if is_balanced(case1) or is_balanced(case2):\n return 'Yes'\n else:\n return 'No'", "matching_cluster_idx": 3}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n def is_good(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n else:\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n \n s1, s2 = lst[0], lst[1]\n # Check both possible concatenations\n if is_good(s1 + s2) or is_good(s2 + s1):\n return 'Yes'\n else:\n return 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n # Combine the strings in both possible orders and check if any is balanced\n for combo in [lst[0] + lst[1], lst[1] + lst[0]]:\n balance = 0\n for char in combo:\n if char == '(':\n balance += 1\n else:\n balance -= 1\n if balance < 0:\n break # Early exit if unbalanced\n if balance == 0:\n return 'Yes'\n return 'No'", "matching_cluster_idx": 3}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n # Function to check if a string is balanced\n def is_balanced(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n else:\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n \n # Check both possible concatenations\n if is_balanced(lst[0] + lst[1]) or is_balanced(lst[1] + lst[0]):\n return 'Yes'\n else:\n return 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n def is_good(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n else:\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n str1, str2 = lst[0], lst[1]\n # Check if concatenating in either order results in a good string\n if is_good(str1 + str2) or is_good(str2 + str1):\n return 'Yes'\n else:\n return 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n # First string followed by second\n if is_good((lst[0] + lst[1])):\n return 'Yes'\n # Second string followed by first\n elif is_good((lst[1] + lst[0])):\n return 'Yes'\n else:\n return 'No'\ndef is_good(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n else:\n balance -= 1\n if balance < 0:\n return False\n return balance == 0", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n def is_good_string(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n else:\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n str1, str2 = lst\n # Check if the concatenation of str1 and str2 in both possible orders forms a good string\n if is_good_string(str1 + str2) or is_good_string(str2 + str1):\n return 'Yes'\n else:\n return 'No'", "matching_cluster_idx": 4}]}, "HumanEval/120": {"dps": 43.29501915708812, "dps_norm": 67.46031746031746, "pass@1": 18.0, "profiled": [{"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list\n of length k with the maximum k numbers in arr.\n \"\"\"\n if k == 0 or k > len(arr):\n return sorted(arr, reverse=True)[:k]\n \n # Using Python's heapq to find the k largest elements efficiently\n import heapq\n largest_k = heapq.nlargest(k, arr)\n \n # Return the sorted list of the k largest elements\n return sorted(largest_k)", "matching_cluster_idx": 3}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list\n of length k with the maximum k numbers in arr.\n \"\"\"\n # Check if k is 0 or the array is empty, return an empty list\n if k == 0 or not arr:\n return []\n \n # Use a min heap to keep track of the k largest elements seen so far\n from heapq import heapify, heappop, heappush\n \n # Initialize a min heap with first k elements\n min_heap = arr[:k]\n heapify(min_heap)\n \n # Iterate over the rest of the elements\n for num in arr[k:]:\n # If current number is larger than the smallest in the heap, replace it\n if num > min_heap[0]:\n heappop(min_heap) # Remove the smallest\n heappush(min_heap, num) # Push the current number\n \n # The heap contains the k largest elements, but we need to sort them\n return sorted(min_heap)", "matching_cluster_idx": 5}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list\n of length k with the maximum k numbers in arr.\n \"\"\"\n # Filter out the k largest elements using heapq's nlargest function\n import heapq\n return sorted(heapq.nlargest(k, arr))", "matching_cluster_idx": 3}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list\n of length k with the maximum k numbers in arr.\n\n :param arr: List[int] -- the input array of integers\n :param k: int -- the number of maximum elements to return\n :return: List[int] -- a sorted list of the k largest integers in arr\n \"\"\"\n # Use heapq to find the k largest elements\n import heapq\n \n # Find the k largest elements\n k_largest_elements = heapq.nlargest(k, arr)\n \n # Return the result sorted\n return sorted(k_largest_elements)", "matching_cluster_idx": 3}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n \"\"\"\n # If k is 0 or the array is empty, return an empty list\n if k == 0 or len(arr) == 0:\n return []\n \n # Create a max heap using the negative values of the array\n import heapq\n max_heap = [-x for x in arr]\n heapq.heapify(max_heap)\n \n # Extract the k largest numbers\n result = []\n for _ in range(k):\n if max_heap:\n result.append(-heapq.heappop(max_heap))\n \n # Return the result sorted\n return sorted(result)", "matching_cluster_idx": 3}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n\n Example 1:\n\n Input: arr = [-3, -4, 5], k = 3\n Output: [-4, -3, 5]\n\n Example 2:\n\n Input: arr = [4, -4, 4], k = 2\n Output: [4, 4]\n\n Example 3:\n\n Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1\n Output: [2]\n \"\"\"\n # Edge case: if k is 0 or the array is empty, return an empty list\n if k == 0 or not arr:\n return []\n \n # Convert the array to a min-heap\n import heapq\n min_heap = arr[:k]\n heapq.heapify(min_heap)\n \n # Iterate over the rest of the array\n for num in arr[k:]:\n # If the current number is larger than the smallest in the heap\n if num > min_heap[0]:\n # Replace the smallest with the current number\n heapq.heapreplace(min_heap, num)\n \n # The heap contains the k largest elements; sort them before returning\n return sorted(min_heap)", "matching_cluster_idx": 5}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list\n of length k with the maximum k numbers in arr.\n \"\"\"\n # Using the nlargest function from heapq module to find the k largest elements\n import heapq\n return sorted(heapq.nlargest(k, arr))", "matching_cluster_idx": 3}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n\n Example 1:\n\n Input: arr = [-3, -4, 5], k = 3\n Output: [-4, -3, 5]\n\n Example 2:\n\n Input: arr = [4, -4, 4], k = 2\n Output: [4, 4]\n\n Example 3:\n\n Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1\n Output: [2]\n \"\"\"\n # Using nlargest from the heapq module to find the top k largest numbers\n import heapq\n return sorted(heapq.nlargest(k, arr))", "matching_cluster_idx": 3}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list\n of length k with the maximum k numbers in arr.\n \"\"\"\n # First, we use a min-heap to keep track of the top k elements efficiently.\n # However, Python's heapq module only provides a min-heap implementation, so we use negative values\n # to simulate a max-heap.\n import heapq\n max_heap = []\n \n # Push each number with a negative sign into the heap\n for num in arr:\n heapq.heappush(max_heap, -num)\n \n # Extract the top k elements from the heap and convert them back to positive\n result = [-heapq.heappop(max_heap) for _ in range(k)]\n \n # Return the sorted result\n return sorted(result)", "matching_cluster_idx": 3}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list\n of length k with the maximum k numbers in arr.\n \"\"\"\n # If k is 0 or the array is empty, return an empty list\n if k == 0 or not arr:\n return []\n \n # Use a min heap to keep track of the largest k elements\n min_heap = arr[:k]\n import heapq\n heapq.heapify(min_heap)\n \n # Iterate through the rest of the array\n for num in arr[k:]:\n # If the current number is larger than the smallest in the heap, replace it\n if num > min_heap[0]:\n heapq.heapreplace(min_heap, num)\n \n # The heap contains the k largest elements, return them sorted\n return sorted(min_heap)", "matching_cluster_idx": 5}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list\n of length k with the maximum k numbers in arr.\n \"\"\"\n # Ensure k is non-negative and within the bounds of the array length\n if k < 0 or k > len(arr):\n raise ValueError(\"k must be non-negative and less than or equal to the length of arr\")\n \n # Use a min-heap to keep track of the top k elements\n import heapq\n return sorted(heapq.nlargest(k, arr))", "matching_cluster_idx": 3}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n \"\"\"\n # Sort the array in descending order\n sorted_arr = sorted(arr, reverse=True)\n # Slice the first k elements and return them as a sorted list\n return sorted(sorted_arr[:k])", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list\n of length k with the maximum k numbers in arr.\n \"\"\"\n # Use the heapq module to find the k largest numbers efficiently\n import heapq\n\n # Find the k largest numbers in the array\n largest_k = heapq.nlargest(k, arr)\n \n # Return the result sorted in non-decreasing order\n return sorted(largest_k)", "matching_cluster_idx": 3}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list\n of length k with the maximum k numbers in arr.\n \"\"\"\n # If k is 0 or the array is empty, return an empty list\n if k == 0 or not arr:\n return []\n \n # Create a min-heap to keep track of the top k elements\n import heapq\n min_heap = []\n \n # Iterate through each number in the array\n for num in arr:\n # Push the current number into the heap\n heapq.heappush(min_heap, num)\n # If the heap size exceeds k, pop the smallest element\n if len(min_heap) > k:\n heapq.heappop(min_heap)\n \n # The heap now contains the k largest numbers, but in reverse order\n result = list(min_heap)\n \n # Return the result in sorted order\n return sorted(result)", "matching_cluster_idx": 4}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list\n of length k with the maximum k numbers in arr.\n \"\"\"\n # Use the heapq module to find the k largest elements efficiently\n import heapq\n \n # Find the k largest elements\n k_largest = heapq.nlargest(k, arr)\n \n # Return the result sorted\n return sorted(k_largest)", "matching_cluster_idx": 3}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list\n of length k with the maximum k numbers in arr.\n \"\"\"\n if k == 0:\n return []\n # Use Python's built-in nth largest numbers approach\n from heapq import nlargest\n result = nlargest(k, arr)\n return sorted(result)", "matching_cluster_idx": 3}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list\n of length k with the maximum k numbers in arr.\n \"\"\"\n # Sort the array in descending order\n sorted_arr = sorted(arr, reverse=True)\n # Slice the first k elements and return them sorted\n return sorted(sorted_arr[:k])", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list\n of length k with the maximum k numbers in arr.\n \"\"\"\n # Use nlargest from heapq to find the k largest numbers\n from heapq import nlargest\n \n # Return the k largest numbers sorted in ascending order\n return sorted(nlargest(k, arr))", "matching_cluster_idx": 3}]}, "HumanEval/121": {"dps": 85.65022421524664, "dps_norm": 64.28571428571429, "pass@1": 100.0, "profiled": [{"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n\n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==>0\n \"\"\"\n # Initialize sum to 0\n sum_of_odds = 0\n \n # Iterate through the list with index\n for i, num in enumerate(lst):\n # Check if the index is even and the number is odd\n if i % 2 == 0 and num % 2 == 1:\n sum_of_odds += num\n \n return sum_of_odds", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n\n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n # Initialize sum to 0\n odd_sum = 0\n \n # Iterate through the list, considering only even indices (0, 2, 4, ...)\n for i in range(0, len(lst), 2):\n # Check if the element at the even index is odd\n if lst[i] % 2 != 0:\n # Add it to the sum\n odd_sum += lst[i]\n \n # Return the final sum\n return odd_sum", "matching_cluster_idx": 4}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\"\"\"\n return sum(value for index, value in enumerate(lst) if index % 2 == 0 and value % 2 != 0)", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n\n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n return sum(val for idx, val in enumerate(lst) if idx % 2 == 0 and val % 2 != 0)", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n Examples:\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n return sum(val for idx, val in enumerate(lst) if idx % 2 == 0 and val % 2 == 1)", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\"\"\"\n return sum(value for index, value in enumerate(lst) if index % 2 == 0 and value % 2 != 0)", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n\n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==>0\n \"\"\"\n return sum(val for idx, val in enumerate(lst) if idx % 2 == 0 and val % 2 == 1)", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n\n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==>0\n \"\"\"\n # Use list comprehension to filter odd elements in even positions and sum them up\n return sum(lst[i] for i in range(0, len(lst), 2) if lst[i] % 2 != 0)", "matching_cluster_idx": 4}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n\n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n # Initialize sum to 0\n total_sum = 0\n \n # Iterate through the list, considering only even indices\n for i in range(0, len(lst), 2):\n # Check if the element at the even index is odd\n if lst[i] % 2 != 0:\n # Add it to the total sum\n total_sum += lst[i]\n \n return total_sum", "matching_cluster_idx": 4}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n\n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==>0\n \"\"\"\n return sum(val for idx, val in enumerate(lst) if idx % 2 == 0 and val % 2 != 0)", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n\n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n # Initialize the sum to 0\n sum_odd_in_even_positions = 0\n \n # Iterate through the list, considering only even indices (0, 2, 4, ...)\n for i in range(0, len(lst), 2):\n # Check if the element at the current even index is odd\n if lst[i] % 2 != 0:\n # Add it to the sum\n sum_odd_in_even_positions += lst[i]\n \n return sum_odd_in_even_positions", "matching_cluster_idx": 4}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n Examples:\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n return sum(lst[i] for i in range(0, len(lst), 2) if lst[i] % 2 != 0)", "matching_cluster_idx": 4}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n\n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n return sum(val for idx, val in enumerate(lst) if idx % 2 == 0 and val % 2 != 0)", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n\n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==>0\n \"\"\"\n # Initialize sum to 0\n sum_of_odds = 0\n \n # Iterate over the list with index\n for index, value in enumerate(lst):\n # Check if the index is even and the value is odd\n if index % 2 == 0 and value % 2 != 0:\n sum_of_odds += value\n \n return sum_of_odds", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n\n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==>0\n \"\"\"\n # Initialize sum to 0\n total_sum = 0\n \n # Iterate through the list, starting from index 0 (first even position)\n for i in range(0, len(lst), 2):\n # Check if the current element is odd\n if lst[i] % 2 != 0:\n # Add the odd element to the total sum\n total_sum += lst[i]\n \n return total_sum", "matching_cluster_idx": 4}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n\n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==>0\n \"\"\"\n # Initialize sum to 0\n total_sum = 0\n \n # Iterate through the list, starting from index 0 (first even position)\n for i in range(0, len(lst), 2):\n # Check if the element at the current even position is odd\n if lst[i] % 2 != 0:\n # Add it to the total sum\n total_sum += lst[i]\n \n # Return the final sum\n return total_sum", "matching_cluster_idx": 4}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==>0\n \"\"\"\n # Initialize the sum to 0\n total_sum = 0\n \n # Iterate through the list, considering only even indices (0, 2, 4, ...)\n for i in range(0, len(lst), 2):\n # Check if the element at the current even index is odd\n if lst[i] % 2 != 0:\n # Add it to the total sum\n total_sum += lst[i]\n \n # Return the total sum of odd elements in even positions\n return total_sum", "matching_cluster_idx": 4}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\"\"\"\n sum_of_odds = 0\n for i in range(0, len(lst), 2):\n if lst[i] % 2 != 0:\n sum_of_odds += lst[i]\n return sum_of_odds", "matching_cluster_idx": 4}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n Examples:\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n # Initialize sum to 0\n total_sum = 0\n \n # Iterate through the list, considering only even indices\n for i in range(0, len(lst), 2):\n # Check if the element at the even index is odd\n if lst[i] % 2 != 0:\n # Add the odd element to the total sum\n total_sum += lst[i]\n \n return total_sum", "matching_cluster_idx": 4}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n Examples:\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==>0\n \"\"\"\n # Initialize sum to 0\n sum_of_odds = 0\n \n # Iterate over the list with index\n for index, value in enumerate(lst):\n # Check if the index is even and the value is odd\n if index % 2 == 0 and value % 2 != 0:\n # Add the odd value to the sum\n sum_of_odds += value\n \n return sum_of_odds", "matching_cluster_idx": 3}]}, "HumanEval/149": {"dps": 85.82677165354332, "dps_norm": 57.142857142857146, "pass@1": 99.0, "profiled": [{"solution": "def sorted_list_sum(lst):\n \"\"\"\n Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order,\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n You may assume that all words will have the same length.\n \"\"\"\n # Filter out strings with odd lengths\n filtered_list = [word for word in lst if len(word) % 2 == 0]\n \n # Sort the filtered list first by length, then alphabetically\n sorted_list = sorted(filtered_list, key=lambda x: (len(x), x))\n \n return sorted_list", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"\n Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order.\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n \n Examples:\n assert sorted_list_sum([\"aa\", \"a\", \"aaa\"]) == [\"aa\"]\n assert sorted_list_sum([\"ab\", \"a\", \"aaa\", \"cd\"]) == [\"ab\", \"cd\"]\n \"\"\"\n # Filter out strings with odd lengths\n filtered_lst = [word for word in lst if len(word) % 2 == 0]\n # Sort the list by length, then alphabetically\n sorted_lst = sorted(filtered_lst, key=lambda x: (len(x), x))\n return sorted_lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"\n Accepts a list of strings as a parameter, deletes the strings that have odd lengths,\n and returns the resulted list with a sorted order. The list is always a list of strings and\n it may contain duplicates. The order of the list should be ascending by length of each word,\n and alphabetically if lengths are the same.\n \"\"\"\n # Filter out strings with odd lengths\n even_length_strings = [s for s in lst if len(s) % 2 == 0]\n # Sort the list first by length, then alphabetically\n sorted_list = sorted(even_length_strings, key=lambda x: (len(x), x))\n return sorted_list", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"\n Accepts a list of strings as a parameter, deletes the strings that have odd lengths,\n and returns the resulted list with a sorted order by length and alphabetically.\n \"\"\"\n # Filter out strings with odd lengths\n even_length_strings = [s for s in lst if len(s) % 2 == 0]\n \n # Sort the list by length of each word, and then alphabetically\n even_length_strings.sort(key=lambda s: (len(s), s))\n \n return even_length_strings", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"\n Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order.\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n \"\"\"\n # Filter out strings with odd lengths\n filtered_list = [word for word in lst if len(word) % 2 == 0]\n \n # Sort the list by length and then alphabetically\n sorted_list = sorted(filtered_list, key=lambda x: (len(x), x))\n \n return sorted_list", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"\n This function accepts a list of strings, removes those with odd lengths,\n and returns a sorted list of the remaining strings.\n The sorting is first by length in ascending order, then alphabetically for equal lengths.\n \"\"\"\n # Filter out strings with odd lengths\n even_length_strings = [s for s in lst if len(s) % 2 == 0]\n \n # Sort the list by length, then alphabetically\n sorted_strings = sorted(even_length_strings, key=lambda x: (len(x), x))\n \n return sorted_strings", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"\n Accepts a list of strings, deletes strings with odd lengths,\n sorts the remaining strings by length in ascending order,\n and then alphabetically if lengths are equal, and returns the sorted list.\n \"\"\"\n # Filter out strings with odd lengths\n filtered_list = [word for word in lst if len(word) % 2 == 0]\n \n # Sort the list by length, then alphabetically\n sorted_list = sorted(filtered_list, key=lambda x: (len(x), x))\n \n return sorted_list", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n # Filter out strings with odd lengths\n filtered_list = [word for word in lst if len(word) % 2 == 0]\n \n # Sort the list by length, and alphabetically for words with the same length\n sorted_list = sorted(filtered_list, key=lambda x: (len(x), x))\n \n return sorted_list", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n # Filter out strings with odd lengths\n even_length_strings = [s for s in lst if len(s) % 2 == 0]\n # Sort the list by length of each string, and then alphabetically if lengths are the same\n sorted_strings = sorted(even_length_strings, key=lambda x: (len(x), x))\n return sorted_strings", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"\n Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order,\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n You may assume that all words will have the same length.\n \"\"\"\n # Filter out strings with odd lengths\n filtered_list = [word for word in lst if len(word) % 2 == 0]\n \n # Sort the list first by length and then alphabetically\n sorted_list = sorted(filtered_list, key=lambda x: (len(x), x))\n \n return sorted_list", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n # Filter out strings with odd lengths\n filtered_list = [word for word in lst if len(word) % 2 == 0]\n \n # Sort the list by length, then alphabetically\n sorted_list = sorted(filtered_list, key=lambda x: (len(x), x))\n \n return sorted_list", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"\n Accepts a list of strings as a parameter, deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order. The order of the list should be ascending by\n the length of each word, and it should be sorted alphabetically if two words have the same length.\n \n :param lst: List of strings\n :return: Sorted list of strings with even lengths\n \n Example:\n assert sorted_list_sum([\"aa\", \"a\", \"aaa\"]) == [\"aa\"]\n assert sorted_list_sum([\"ab\", \"a\", \"aaa\", \"cd\"]) == [\"ab\", \"cd\"]\n \"\"\"\n # Filter out strings with odd lengths\n even_length_strings = [word for word in lst if len(word) % 2 == 0]\n \n # Sort the list first by length and then alphabetically if lengths are the same\n sorted_strings = sorted(even_length_strings, key=lambda x: (len(x), x))\n \n return sorted_strings", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n # Filter out strings with odd lengths\n even_length_lst = [word for word in lst if len(word) % 2 == 0]\n \n # Sort the list by length of each word, and alphabetically if lengths are the same\n sorted_lst = sorted(even_length_lst, key=lambda x: (len(x), x))\n \n return sorted_lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"\n Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order,\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n You may assume that all words will have the same length.\n \"\"\"\n # Filter out strings with odd lengths\n even_length_lst = [word for word in lst if len(word) % 2 == 0]\n \n # Sort the list first by length, then alphabetically\n sorted_lst = sorted(even_length_lst, key=lambda x: (len(x), x))\n \n return sorted_lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"\n Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order,\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n You may assume that all words will have the same length.\n \"\"\"\n # Filter out strings with odd lengths\n even_length_lst = [word for word in lst if len(word) % 2 == 0]\n \n # Sort the list first by length, then alphabetically\n sorted_lst = sorted(even_length_lst, key=lambda x: (len(x), x))\n \n return sorted_lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"\n Accepts a list of strings as a parameter, deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order, sorted by length and then alphabetically.\n \"\"\"\n # Filter out strings with odd lengths\n filtered_list = [word for word in lst if len(word) % 2 == 0]\n \n # Sort the list by length, and then alphabetically if lengths are equal\n sorted_list = sorted(filtered_list, key=lambda x: (len(x), x))\n \n return sorted_list", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"\n Accepts a list of strings, deletes strings with odd lengths,\n and returns a sorted list based on word length and lexicographical order.\n \"\"\"\n # Filter out strings with odd lengths\n even_length_strings = [s for s in lst if len(s) % 2 == 0]\n \n # Sort the list by word length, and lexicographically if lengths are the same\n sorted_strings = sorted(even_length_strings, key=lambda x: (len(x), x))\n \n return sorted_strings", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"\n Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order,\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n You may assume that all words will have the same length.\n \"\"\"\n # Filter out strings with odd lengths\n filtered_lst = [word for word in lst if len(word) % 2 == 0]\n \n # Sort the list by length, then alphabetically\n sorted_lst = sorted(filtered_lst, key=lambda x: (len(x), x))\n \n return sorted_lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"\n Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order,\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n You may assume that all words will have the same length.\n For example:\n assert list_sort([\"aa\", \"a\", \"aaa\"]) => [\"aa\"]\n assert list_sort([\"ab\", \"a\", \"aaa\", \"cd\"]) => [\"ab\", \"cd\"]\n \"\"\"\n # Filter out strings with odd lengths\n filtered_lst = [word for word in lst if len(word) % 2 == 0]\n \n # Sort the list first by length, then alphabetically\n sorted_lst = sorted(filtered_lst, key=lambda x: (len(x), x))\n \n return sorted_lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"\n Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order,\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n You may assume that all words will have the same length.\n For example:\n >>> assert list_sort([\"aa\", \"a\", \"aaa\"]) => [\"aa\"]\n >>> assert list_sort([\"ab\", \"a\", \"aaa\", \"cd\"]) => [\"ab\", \"cd\"]\n \"\"\"\n # Filter out strings with odd lengths\n even_length_strings = [s for s in lst if len(s) % 2 == 0]\n \n # Sort the list by length and alphabetically\n sorted_strings = sorted(even_length_strings, key=lambda s: (len(s), s))\n \n return sorted_strings", "matching_cluster_idx": 3}]}, "Mbpp/3": {"dps": 69.7457627118644, "dps_norm": 81.25, "pass@1": 78.0, "profiled": [{"solution": "def is_not_prime(n):\n # Determine if the number is not prime\n if n <= 1:\n return True\n if n <= 3:\n return False\n if n % 2 == 0 or n % 3 == 0:\n return True\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return True\n i += 6\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n # Check if the number is less than 2, which is not prime\n if n < 2:\n return True\n # Check divisibility from 2 to the square root of n\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return True\n return False", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(n):\n # Check if n is less than 2, which is not a prime number\n if n < 2:\n return True\n # Check divisibility from 2 to the square root of n\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return True\n return False", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(n):\n # Check if the number is less than 2, which is not prime\n if n < 2:\n return True\n # Check divisibility from 2 to the square root of n\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return True\n return False", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(n):\n \"\"\"\n Function to determine if a number is not a prime number.\n \n Args:\n n (int): The number to check.\n \n Returns:\n bool: True if the number is not prime, False otherwise.\n \"\"\"\n if n <= 1:\n return True\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return True\n return False", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(n):\n # Return False for the smallest prime number\n if n <= 1:\n return True\n # Check for factors from 2 to the square root of n\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return True\n return False", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(n):\n # Return False if n is a prime number\n if n <= 1:\n return True # 0, 1 and negative numbers are not prime\n if n <= 3:\n return False # 2 and 3 are prime numbers\n if n % 2 == 0 or n % 3 == 0:\n return True # Exclude even numbers and multiples of 3\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return True\n i += 6\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n # Check if n is less than 2, which is not prime\n if n < 2:\n return True\n # Check if n is 2 or 3, which are prime\n if n == 2 or n == 3:\n return False\n # Check if n is divisible by 2 or 3\n if n % 2 == 0 or n % 3 == 0:\n return True\n # Check for factors from 5 to sqrt(n)\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return True\n i += 6\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n # Return False for 0, 1, and negative numbers\n if n <= 1:\n return True\n # Check for non-prime by attempting division by all numbers up to n-1\n for i in range(2, n):\n if n % i == 0:\n return True\n # If no factors found, it's a prime number\n return False", "matching_cluster_idx": 1}, {"solution": "def is_not_prime(n):\n # Check if a number is not prime\n if n <= 1:\n return True\n if n <= 3:\n return False\n if n % 2 == 0 or n % 3 == 0:\n return True\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return True\n i += 6\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n # Check if a number is not prime\n if n <= 1:\n return True # 0 and 1 are not prime numbers\n if n == 2:\n return False # 2 is a prime number\n if n % 2 == 0:\n return True # Other even numbers are not prime\n for i in range(3, int(n**0.5) + 1, 2):\n if n % i == 0:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n # Return False for numbers less than 2\n if n < 2:\n return True\n # Check for divisibility by any number from 2 to n-1\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return True\n return False", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(n):\n # Check if a number is not prime\n if n <= 1:\n return True # 0 and 1 are not prime numbers\n elif n <= 3:\n return False # 2 and 3 are prime numbers\n elif n % 2 == 0 or n % 3 == 0:\n return True # multiples of 2 and 3 are not prime\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return True # if n is divisible by any number other than 1 and itself, it's not prime\n i += 6\n return False # if no divisors were found, the number is prime", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n # Return True if the number is not prime, False otherwise\n if n <= 1:\n return True\n if n <= 3:\n return False\n if n % 2 == 0 or n % 3 == 0:\n return True\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return True\n i += 6\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n # A number is not prime if it is less than 2\n if n < 2:\n return True\n # Check for divisibility from 2 to the square root of n\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return True\n return False", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(n):\n # Check if the number is less than 2, which is not prime\n if n < 2:\n return True\n # Check divisibility from 2 to the square root of n\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return True\n return False", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(n):\n # Check if the number is less than 2, which is not prime\n if n < 2:\n return True\n # Check for divisibility from 2 to the square root of n\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return True\n return False", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(n):\n # Check if a number is not prime\n if n <= 1:\n return True\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return True\n return False", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(n):\n # Check if the number is less than 2, which is not prime\n if n < 2:\n return True\n # Check for divisibility by numbers up to the square root of n\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return True\n return False", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(n):\n # Check if n is a prime number or not\n if n <= 1:\n return True # 0 and 1 are not prime numbers\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return True # If divisible by any number other than 1 and itself, it's not prime\n return False", "matching_cluster_idx": 5}]}, "Mbpp/4": {"dps": 95.22184300341297, "dps_norm": 83.33333333333333, "pass@1": 95.0, "profiled": [{"solution": "import heapq\ndef heap_queue_largest(numbers, n):\n # Use nlargest from heapq to find the n largest elements in the list\n # Since heapq.nlargest returns the largest elements in ascending order, we reverse them to descending order\n return sorted(heapq.nlargest(n, numbers), reverse=True)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(numbers, n):\n # Use nlargest from heapq to find the n largest elements\n largest_nums = heapq.nlargest(n, numbers)\n # Return the result in descending order\n return sorted(largest_nums, reverse=True)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(numbers, n):\n # Use nlargest from heapq to get the n largest numbers\n largest_numbers = heapq.nlargest(n, numbers)\n # Return the result in descending order\n return largest_numbers", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n # Use heapq.nlargest to find the n largest numbers in the list\n largest_nums = heapq.nlargest(n, nums)\n # Return the largest numbers in descending order\n return sorted(largest_nums, reverse=True)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n # Use nlargest from heapq to find the n largest elements from the list\n result = heapq.nlargest(n, nums)\n # Return the result sorted in descending order\n return sorted(result, reverse=True)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(numbers, n):\n # Use nlargest from heapq to find the n largest elements in numbers\n # Since heapq.nlargest returns the elements in descending order, we don't need to sort further\n return heapq.nlargest(n, numbers)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n # Use nlargest from heapq to get the n largest elements from the list\n largest_nums = heapq.nlargest(n, nums)\n # Return the result in descending order\n return largest_nums", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(numbers, n):\n # Use nlargest from heapq to find the n largest elements\n largest_numbers = heapq.nlargest(n, numbers)\n # Return the result in descending order\n return sorted(largest_numbers, reverse=True)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(numbers, n):\n # Use nlargest from heapq to find the n largest numbers in the list\n return heapq.nlargest(n, numbers)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(numbers, n):\n # Use nlargest from heapq to find the n largest numbers in the list\n # Since heapq.nlargest returns the result in descending order, it directly meets our requirement\n return heapq.nlargest(n, numbers)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(numbers, n):\n # Use nlargest from heapq to find the n largest elements\n largest_elements = heapq.nlargest(n, numbers)\n # Sort the result in descending order\n largest_elements.sort(reverse=True)\n return largest_elements", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(numbers, n):\n # Use nlargest from heapq to find the n largest numbers in the list\n return heapq.nlargest(n, numbers)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(numbers, n):\n # Use nlargest from heapq to find the n largest numbers in the list\n largest_numbers = heapq.nlargest(n, numbers)\n # Return the result sorted in descending order\n return sorted(largest_numbers, reverse=True)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(numbers, n):\n # Use nlargest from heapq to find the n largest numbers and then reverse them to descending order\n return sorted(heapq.nlargest(n, numbers), reverse=True)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(numbers, n):\n # Use nlargest from heapq to find the n largest elements in the list\n return heapq.nlargest(n, numbers)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(numbers, n):\n # Use nlargest from heapq to find the n largest numbers\n largest_numbers = heapq.nlargest(n, numbers)\n # Sort the result in descending order\n largest_numbers.sort(reverse=True)\n return largest_numbers", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n # Use nlargest from heapq to find the n largest numbers in the list\n largest_nums = heapq.nlargest(n, nums)\n # Return the result sorted in descending order\n return sorted(largest_nums, reverse=True)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(numbers, n):\n # Use nlargest from heapq to find the n largest elements in the list\n largest_nums = heapq.nlargest(n, numbers)\n # Return the result in descending order\n return sorted(largest_nums, reverse=True)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(numbers, n):\n # Use nlargest from heapq to find the n largest numbers\n return heapq.nlargest(n, numbers)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n # Use heapq.nlargest to find the n largest elements in the list\n largest_nums = heapq.nlargest(n, nums)\n # Return the results in descending order\n return sorted(largest_nums, reverse=True)", "matching_cluster_idx": 9}]}, "Mbpp/9": {"dps": 90.3061224489796, "dps_norm": 59.5, "pass@1": 66.0, "profiled": [{"solution": "def find_Rotations(s):\n # Check if the string is empty or None\n if not s:\n return 0\n \n # Concatenate the string with itself to handle rotation\n concatenated = s + s\n \n # Iterate through possible rotations\n for i in range(1, len(s)):\n # If a rotation of the string is found in the concatenated string\n if concatenated[i:i+len(s)] == s:\n return i\n \n # If no rotation is found other than the original string (which is not allowed by the problem)\n return len(s)", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(s):\n # Check if the string is empty\n if not s:\n return 0\n \n # Concatenate the string with itself to cover all possible rotations\n double_s = s + s\n \n # Find the shortest substring of double_s that starts with the original string\n for i in range(1, len(s)):\n if double_s[i:i+len(s)] == s:\n return i\n \n # If no rotation is found, return the length of the string (special case)\n return len(s)", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(s):\n # Check if the string is empty or None\n if not s:\n return 0\n \n # Concatenate the string with itself to cover all possible rotations\n temp = s + s\n \n # Iterate to find the minimum number of rotations\n for i in range(1, len(s)):\n # Extract a substring of length equal to the original string from the temp\n if temp[i:i+len(s)] == s:\n return i\n \n # If no rotation matches, return the length of the string (all rotations are the same)\n return len(s)", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(s):\n # If the string is empty, return 0 as no rotations are needed\n if not s:\n return 0\n \n # Concatenate the string with itself to handle rotations\n double_s = s + s\n \n # Check all possible rotations by slicing the doubled string\n for i in range(1, len(s)):\n # Potential rotation substring\n rotated_substring = double_s[i:i+len(s)]\n # If the rotated substring matches the original string, return the rotation count\n if rotated_substring == s:\n return i\n \n # If no valid rotation is found, return the length of the string (though it should not happen in valid cases)\n return len(s)", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(s):\n # Check if the string is empty or does not contain repeating characters\n if len(s) == 0 or len(set(s)) == 1:\n return 1\n \n # Iterate through possible rotations\n for i in range(1, len(s)):\n # Generate rotated string\n rotated_string = s[i:] + s[:i]\n # Check if the current rotation matches the original string\n if rotated_string == s:\n return i\n \n # If no rotation matches, return the length of the string (all rotations considered)\n return len(s)", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(s):\n # Check if the string is empty or all characters are the same\n if len(s) == 0 or len(set(s)) == 1:\n return 1\n \n # Concatenate the string with itself to handle rotations\n double_s = s + s\n # Find the index where the original string starts in the doubled string\n index = double_s.find(s)\n \n # The minimum rotations needed is the length of the string minus the index found,\n # but we need to subtract 1 because we are looking for rotations greater than 0\n rotations = len(s) - index if index != -1 else 1\n \n return rotations", "matching_cluster_idx": 7}, {"solution": "def find_Rotations(s):\n # Check if the string is empty\n if not s:\n return 0\n \n # Concatenate the string with itself to handle rotations\n concatenated_string = s + s\n \n # Find the minimum number of rotations\n for i in range(1, len(s)):\n if concatenated_string[i:i+len(s)] == s:\n return i\n \n # If no rotation matches, return the length of the string (should not happen for valid inputs)\n return len(s)", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(s):\n # Check if the string is empty or does not contain any character\n if not s:\n return 0\n \n # Concatenate the string with itself to handle rotation logic\n temp = s + s\n \n # Iterate through the possible rotations\n for i in range(1, len(s)):\n # If the rotated substring matches the original string, return the rotation count\n if temp[i:i+len(s)] == s:\n return i\n \n # If no rotation matches, return the length of the string (full rotation)\n return len(s)", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(s):\n # Check if the string is empty\n if not s:\n return 0\n \n # Concatenate the string with itself to handle rotations\n double_s = s + s\n \n # Iterate through possible rotations\n for i in range(1, len(s)):\n # Extract a substring of the same length as the original string\n rotated_string = double_s[i:i+len(s)]\n # Check if the rotated substring is equal to the original string\n if rotated_string == s:\n return i\n \n # If no rotation matches the original string, return the length of the string\n return len(s)", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(s):\n # Check if the string is empty or has only one character\n if len(s) <= 1:\n return 0\n \n # Concatenate the string with itself to easily find rotations\n concatenated_string = s + s\n \n # Check each possible rotation\n for i in range(1, len(s)):\n # Extract the substring\n rotated_string = concatenated_string[i:i+len(s)]\n # If the rotated substring is equal to the original string, return the rotation count\n if rotated_string == s:\n return i\n \n # If no rotation matches, return the length of the string (full rotation)\n return len(s)", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(s):\n # Check if the string is empty or None\n if not s:\n return 0\n \n # Concatenate the string with itself to cover all possible rotations\n double_s = s + s\n \n # Iterate through possible rotations\n for i in range(1, len(s)):\n # Extract a substring from the double string that represents a rotation\n rotated_string = double_s[i:i+len(s)]\n # Check if the rotated substring is the same as the original string\n if rotated_string == s:\n return i\n \n # If no rotation matches the original string, return the length of the string\n return len(s)", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(s):\n \"\"\"\n Function to find the minimum number of rotations (greater than 0) required to get the same string.\n \n :param s: The input string\n :return: The minimum number of rotations required\n \"\"\"\n if not s:\n return 0\n \n # Concatenate the string with itself to handle rotations\n doubled_string = s + s\n \n # Iterate through possible rotations\n for i in range(1, len(s)):\n # Extract a substring of the same length as the original string\n rotated_substring = doubled_string[i:i+len(s)]\n # Check if the substring matches the original string\n if rotated_substring == s:\n return i\n \n # If no valid rotation is found, return the length of the string\n return len(s)", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(s):\n # Check if the string is empty or all characters are the same\n if len(s) == 0 or len(set(s)) == 1:\n return 1\n \n # Concatenate the string with itself to simplify finding rotations\n doubled_string = s + s\n \n # Check each possible rotation\n for i in range(1, len(s)):\n # If the substring of doubled_string starting from i and of length len(s) matches s, return i\n if doubled_string[i:i+len(s)] == s:\n return i\n \n # If no rotation matches, return the length of the string (cycling back to the original string)\n return len(s)", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(s):\n # Check if the string is empty or has only one character\n if len(s) <= 1:\n return 1\n \n # Concatenate the string with itself to handle rotations\n concatenated = s + s\n \n # Iterate over possible rotation counts from 1 to len(s) - 1\n for i in range(1, len(s)):\n # Check if the rotated substring matches the original string\n if concatenated[i:i+len(s)] == s:\n return i\n \n # If no rotation matches, return the length of the string (all characters are the same)\n return len(s)", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(s):\n # Check if the string is empty or all characters are the same\n if not s or len(set(s)) == 1:\n return 1\n \n # Iterate through possible rotations\n for i in range(1, len(s)):\n # Generate the rotated string\n rotated_str = s[i:] + s[:i]\n # Check if the rotated string is the same as the original\n if rotated_str == s:\n return i\n \n # If no rotation is found, return the length of the string (should not happen with valid input)\n return len(s)", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(s):\n # Check if the string is empty or all characters are the same\n if len(s) == 0 or len(set(s)) == 1:\n return 1 if len(s) > 0 else 0\n \n # Iterate through possible rotations\n for i in range(1, len(s)):\n if s == s[i:] + s[:i]:\n return i\n return len(s)", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(s):\n # Check if the string is empty or has only one character\n if len(s) <= 1:\n return 0\n \n # Concatenate the string with itself\n temp = s + s\n \n # Find the length of the string\n n = len(s)\n \n # Iterate to find the minimum number of rotations\n for i in range(1, n):\n # Generate the rotated substring\n rotated_substring = temp[i:i+n]\n if s == rotated_substring:\n return i\n \n # If no rotation matches, return the length of the string\n return n", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(s):\n \"\"\"\n Find the minimum number of rotations required to get the same string.\n\n Args:\n s (str): The input string.\n\n Returns:\n int: The minimum number of rotations needed.\n\n Examples:\n >>> find_Rotations(\"aaaa\")\n 1\n \"\"\"\n if not s:\n return 0\n \n # Concatenate the string with itself to handle rotation\n doubled_s = s + s\n \n # Calculate the length of the string\n length = len(s)\n \n # Check each possible rotation\n for i in range(1, length):\n # Extract the rotated string\n rotated_s = doubled_s[i:i+length]\n # Check if the rotated string matches the original string\n if s == rotated_s:\n return i\n \n # If no rotation matches, return the length of the string\n return length", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(s):\n # Check if the string is empty\n if not s:\n return 0\n \n # Concatenate the string with itself to handle rotations\n temp = s + s\n \n # Iterate to find the minimum number of rotations\n for i in range(1, len(s)):\n if temp[i:i+len(s)] == s:\n return i\n \n # If no rotation matches, return the length of the string\n return len(s)", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(s):\n # Check if the string is empty or has only one character\n if len(s) <= 1:\n return 0\n \n # Concatenate the string with itself to cover all possible rotations\n doubled_s = s + s\n \n # Iterate through possible rotation lengths\n for i in range(1, len(s)):\n # Extract a substring of length equal to the original string\n rotated_substring = doubled_s[i:i+len(s)]\n # If the rotated substring is equal to the original string, return the rotation count\n if rotated_substring == s:\n return i\n \n # If no rotation results in the original string, return the original string length\n return len(s)", "matching_cluster_idx": 5}]}, "Mbpp/11": {"dps": 62.72401433691756, "dps_norm": 94.44444444444444, "pass@1": 53.0, "profiled": [{"solution": "def remove_Occ(s, ch):\n # Find the index of the first occurrence of the character\n first_occurrence = s.find(ch)\n \n # If the character is found in the string, remove it from the start\n if first_occurrence != -1:\n s = s[:first_occurrence] + s[first_occurrence + 1:]\n \n # Find the index of the last occurrence of the character\n last_occurrence = s.rfind(ch)\n \n # If the character is found in the string, remove it from the end\n if last_occurrence != -1:\n s = s[:last_occurrence] + s[last_occurrence + 1:]\n \n return s", "matching_cluster_idx": 7}, {"solution": "def remove_Occ(input_str, char):\n # Find the first occurrence of the character and remove it\n first_index = input_str.find(char)\n if first_index != -1:\n input_str = input_str[:first_index] + input_str[first_index + 1:]\n \n # Find the last occurrence of the character and remove it\n last_index = input_str.rfind(char)\n if last_index != -1:\n input_str = input_str[:last_index] + input_str[last_index + 1:]\n \n return input_str", "matching_cluster_idx": 7}, {"solution": "def remove_Occ(s, ch):\n # Find the first occurrence of the character and remove it\n if ch in s:\n s = s.replace(ch, \"\", 1)\n \n # Find the last occurrence of the character and remove it\n last_index = s.rfind(ch)\n if last_index != -1:\n s = s[:last_index] + s[last_index + 1:]\n \n return s", "matching_cluster_idx": 7}, {"solution": "def remove_Occ(s, ch):\n # Find the first occurrence and remove it\n first_occurrence = s.find(ch)\n if first_occurrence != -1:\n s = s[:first_occurrence] + s[first_occurrence + 1:]\n \n # Find the last occurrence and remove it\n last_occurrence = s.rfind(ch)\n if last_occurrence != -1:\n s = s[:last_occurrence] + s[last_occurrence + 1:]\n \n return s", "matching_cluster_idx": 7}, {"solution": "def remove_Occ(s, ch):\n # Find the first occurrence of the character and remove it\n first_occurrence = s.find(ch)\n if first_occurrence == -1:\n return s # Character not found in the string, return the original string\n \n # Find the last occurrence of the character and remove it\n last_occurrence = s.rfind(ch)\n if last_occurrence == -1:\n return s # Character not found in the string, return the original string\n \n # Construct the new string by concatenating parts before the first occurrence,\n # between the first and last occurrence, and after the last occurrence\n new_string = s[:first_occurrence] + s[first_occurrence + 1:last_occurrence] + s[last_occurrence + 1:]\n \n return new_string", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(s, ch):\n # Find index of the first occurrence of ch\n first_occurrence = s.find(ch)\n \n # Find index of the last occurrence of ch\n last_occurrence = s.rfind(ch)\n \n # If the character is not found at all, return the string as is\n if first_occurrence == -1 or last_occurrence == -1:\n return s\n \n # Construct the result string by removing the first and last occurrences\n if first_occurrence == last_occurrence:\n # Only one occurrence of ch, remove it\n return s[:first_occurrence] + s[first_occurrence+1:]\n else:\n # More than one occurrence, remove the first and the last\n return s[:first_occurrence] + s[first_occurrence+1:last_occurrence] + s[last_occurrence+1:]", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(s, char):\n # Find the first occurrence of the character and remove it\n first_index = s.find(char)\n if first_index != -1:\n s = s[:first_index] + s[first_index + 1:]\n \n # Find the last occurrence of the character and remove it\n last_index = s.rfind(char)\n if last_index != -1:\n s = s[:last_index] + s[last_index + 1:]\n \n return s", "matching_cluster_idx": 7}, {"solution": "def remove_Occ(s, char):\n # Find the first occurrence and remove it\n first_index = s.find(char)\n if first_index == -1:\n return s # Return original string if char is not found\n\n # Find the last occurrence and remove it\n last_index = s.rfind(char)\n new_string = s[:first_index] + s[first_index+1:last_index] + s[last_index+1:]\n\n return new_string", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(input_str, char):\n # Find the first occurrence of the character\n first_occurrence = input_str.find(char)\n \n # Find the last occurrence of the character\n last_occurrence = input_str.rfind(char)\n \n # Remove the character from both occurrences\n if first_occurrence != -1 and last_occurrence != -1:\n return input_str[:first_occurrence] + input_str[first_occurrence+1:last_occurrence] + input_str[last_occurrence+1:]\n else:\n # If the character is not found in the string, return the original string\n return input_str", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(s, ch):\n # Find the first occurrence of the character\n first_occ = s.find(ch)\n if first_occ == -1:\n # If the character is not found, return the original string\n return s\n \n # Find the last occurrence of the character\n last_occ = s.rfind(ch)\n \n # Remove the first occurrence\n modified_str = s[:first_occ] + s[first_occ+1:last_occ] + s[last_occ+1:]\n \n return modified_str", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(input_str, char):\n # Find the first occurrence of the character\n first_occurrence = input_str.find(char)\n \n # Find the last occurrence of the character\n last_occurrence = input_str.rfind(char)\n \n # If the character is not found, return the original string\n if first_occurrence == -1 or last_occurrence == -1:\n return input_str\n \n # Construct the new string without the first and last occurrences of the character\n if first_occurrence == last_occurrence:\n # If they are the same, remove only one instance\n return input_str[:first_occurrence] + input_str[first_occurrence + 1:]\n else:\n # If they are different, remove both instances\n return input_str[:first_occurrence] + input_str[first_occurrence + 1:last_occurrence] + input_str[last_occurrence + 1:]", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(s, char):\n # Find the index of the first occurrence of the character\n first_index = s.find(char)\n # Find the index of the last occurrence of the character\n last_index = s.rfind(char)\n \n # If the character is not found at all, return the original string\n if first_index == -1 or last_index == -1:\n return s\n \n # Remove the first and last occurrence of the character\n modified_string = s[:first_index] + s[first_index+1:last_index] + s[last_index+1:]\n \n return modified_string", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(input_str, char):\n # Find the first occurrence of the character\n first_occurrence = input_str.find(char)\n \n # Find the last occurrence of the character\n last_occurrence = input_str.rfind(char)\n \n # Remove the first occurrence\n if first_occurrence == -1:\n # Character not found in the string, return original string\n return input_str\n \n # Remove the last occurrence\n if last_occurrence == -1:\n # Character not found in the string, return original string after first removal\n return input_str[:first_occurrence] + input_str[first_occurrence + 1:]\n \n # Combine the string segments around the occurrences\n return input_str[:first_occurrence] + input_str[first_occurrence + 1:last_occurrence] + input_str[last_occurrence + 1:]", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(s, char):\n # Find the first occurrence of the character and remove it\n first_index = s.find(char)\n if first_index == -1:\n return s # Return the original string if the character is not found\n \n # Find the last occurrence of the character and remove it\n last_index = s.rfind(char)\n if last_index == -1:\n return s # Return the substring from the first occurrence to the end\n \n # Remove the first and last occurrence of the character\n return s[:first_index] + s[first_index+1:last_index] + s[last_index+1:]", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(s, char):\n # Find the first occurrence of the character and remove it\n first_occurrence = s.find(char)\n if first_occurrence != -1:\n s = s[:first_occurrence] + s[first_occurrence + 1:]\n \n # Find the last occurrence of the character and remove it\n last_occurrence = s.rfind(char)\n if last_occurrence != -1:\n s = s[:last_occurrence] + s[last_occurrence + 1:]\n \n return s", "matching_cluster_idx": 7}, {"solution": "def remove_Occ(s, ch):\n # Find the first occurrence of the character and remove it\n first_occurrence = s.find(ch)\n if first_occurrence != -1:\n s = s[:first_occurrence] + s[first_occurrence + 1:]\n \n # Find the last occurrence of the character and remove it\n last_occurrence = s.rfind(ch)\n if last_occurrence != -1:\n s = s[:last_occurrence] + s[last_occurrence + 1:]\n \n return s", "matching_cluster_idx": 7}, {"solution": "def remove_Occ(s, ch):\n # Find the first occurrence and remove it\n first_occurrence = s.find(ch)\n if first_occurrence != -1:\n s = s[:first_occurrence] + s[first_occurrence + 1:]\n \n # Find the last occurrence and remove it\n last_occurrence = s.rfind(ch)\n if last_occurrence != -1:\n s = s[:last_occurrence] + s[last_occurrence + 1:]\n \n return s", "matching_cluster_idx": 7}, {"solution": "def remove_Occ(input_str, ch):\n # Find the first occurrence of the character from the beginning\n first_occurrence = input_str.find(ch)\n \n # Find the last occurrence of the character from the end\n last_occurrence = input_str.rfind(ch)\n \n # If the character is not in the string, return the original string\n if first_occurrence == -1 or last_occurrence == -1:\n return input_str\n \n # Create a new string without the first and last occurrences\n if first_occurrence != last_occurrence:\n new_str = input_str[:first_occurrence] + input_str[first_occurrence + 1:last_occurrence] + input_str[last_occurrence + 1:]\n else:\n new_str = input_str[:first_occurrence] + input_str[first_occurrence + 1:]\n \n return new_str", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(s, char):\n # Find the first occurrence and remove it\n first_occurrence = s.find(char)\n if first_occurrence != -1:\n s = s[:first_occurrence] + s[first_occurrence + 1:]\n \n # Find the last occurrence and remove it\n last_occurrence = s.rfind(char)\n if last_occurrence != -1:\n s = s[:last_occurrence] + s[last_occurrence + 1:]\n \n return s", "matching_cluster_idx": 7}, {"solution": "def remove_Occ(input_string, char):\n # Find the first occurrence of the character and remove it\n first_occurrence = input_string.find(char)\n if first_occurrence != -1:\n input_string = input_string[:first_occurrence] + input_string[first_occurrence + 1:]\n \n # Find the last occurrence of the character and remove it if it exists after the first removal\n last_occurrence = input_string.rfind(char)\n if last_occurrence != -1:\n input_string = input_string[:last_occurrence] + input_string[last_occurrence + 1:]\n \n return input_string", "matching_cluster_idx": 7}]}, "Mbpp/12": {"dps": 95.71428571428571, "dps_norm": 99.6875, "pass@1": 99.0, "profiled": [{"solution": "def sort_matrix(matrix):\n # Zip the matrix and its sum of rows to align each row with its sum\n sorted_rows = sorted(enumerate(matrix), key=lambda x: sum(x[1]))\n \n # Unzip the rows back from the sorted list of tuples\n sorted_matrix = [list(row[1]) for row in sorted_rows]\n \n return sorted_matrix", "matching_cluster_idx": 14}, {"solution": "def sort_matrix(matrix):\n # Use list comprehension to pair each row with its sum, sort by the sum, and then extract the rows\n sorted_matrix = [row for _, row in sorted(zip([sum(row) for row in matrix], matrix))]\n return sorted_matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Pair each row with its sum and store in a list\n summed_rows = [(sum(row), row) for row in matrix]\n # Sort the list based on the sum of the rows\n sorted_summed_rows = sorted(summed_rows)\n # Extract the sorted rows from the list\n sorted_matrix = [row for _, row in sorted_summed_rows]\n return sorted_matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Sort the matrix based on the sum of each row\n sorted_matrix = sorted(matrix, key=sum)\n return sorted_matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Sort the matrix based on the sum of the elements in each row\n sorted_matrix = sorted(matrix, key=sum)\n return sorted_matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Pair each row with its sum and sort by the sum\n sorted_matrix = sorted(matrix, key=sum)\n return sorted_matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Calculate the sum of each row and store it along with the row index\n row_sums = [(sum(row), i) for i, row in enumerate(matrix)]\n \n # Sort the rows based on the sum of their elements\n row_sums.sort()\n \n # Extract the sorted rows from the sorted list\n sorted_rows = [matrix[i] for _, i in row_sums]\n \n return sorted_rows", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Sort the matrix based on the sum of each row\n sorted_matrix = sorted(matrix, key=sum)\n return sorted_matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Pair each row with its sum and sort based on the sum\n sorted_matrix = sorted(matrix, key=sum)\n return sorted_matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Use the sorted function with a custom key that sums up the elements of each row\n sorted_matrix = sorted(matrix, key=sum)\n return sorted_matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Pair each row with its row sum, sort by the sum, and then extract the rows\n sorted_matrix = sorted(matrix, key=sum)\n return sorted_matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Sort the matrix based on the sum of the rows\n sorted_matrix = sorted(matrix, key=sum)\n return sorted_matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Pair each row with its sum and sort by the sum\n sorted_matrix = sorted(matrix, key=sum)\n return sorted_matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Sort the matrix based on the sum of each row in ascending order\n sorted_matrix = sorted(matrix, key=sum)\n return sorted_matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Pair each row with its sum and sort based on the sum\n sorted_matrix = sorted(matrix, key=sum)\n return sorted_matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Sort the matrix based on the sum of elements in each row\n sorted_matrix = sorted(matrix, key=sum)\n return sorted_matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Combine each row with its sum and sort based on the sum\n sorted_matrix = sorted(enumerate(matrix), key=lambda x: sum(x[1]))\n # Extract the sorted rows from the sorted list of tuples\n sorted_matrix = [row for index, row in sorted_matrix]\n return sorted_matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Sort the matrix based on the sum of each row\n sorted_matrix = sorted(matrix, key=sum)\n return sorted_matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Sort the matrix based on the sum of the elements in each row\n sorted_matrix = sorted(matrix, key=sum)\n return sorted_matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Pair each row with its sum and sort by the sum\n sorted_matrix = sorted(matrix, key=sum)\n return sorted_matrix", "matching_cluster_idx": 15}]}, "Mbpp/16": {"dps": null, "dps_norm": null, "pass@1": 0.0, "profiled": []}, "Mbpp/19": {"dps": 94.6969696969697, "dps_norm": 97.0, "pass@1": 100.0, "profiled": [{"solution": "def test_duplicate(nums):\n # Create an empty set to store unique numbers\n seen = set()\n \n # Iterate through each number in the list\n for num in nums:\n # If the number is already in the set, we found a duplicate\n if num in seen:\n return True\n # Otherwise, add the number to the set\n seen.add(num)\n \n # If we reach here, there are no duplicates\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(arr):\n # Using a set to track seen numbers\n seen = set()\n \n for num in arr:\n # If the number is already in the set, we have a duplicate\n if num in seen:\n return True\n seen.add(num)\n \n # No duplicates found\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(arr):\n # Convert the list to a set and compare its length to the original list\n return len(arr) != len(set(arr))", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(arr):\n # Use a set to track seen numbers\n seen = set()\n for num in arr:\n if num in seen:\n return True\n seen.add(num)\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(nums):\n # Create an empty set to keep track of seen numbers\n seen = set()\n \n # Iterate through each number in the array\n for num in nums:\n # If the number is already in the set, we found a duplicate\n if num in seen:\n return True\n # Add the number to the set\n seen.add(num)\n \n # If we finish the loop without finding any duplicates, return False\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(arr):\n # Create a set to keep track of seen numbers\n seen = set()\n \n # Iterate through the array\n for num in arr:\n # Check if the number is already in the set\n if num in seen:\n return True\n seen.add(num)\n \n # If no duplicates are found, return False\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(arr):\n # Create a set to store unique elements\n seen = set()\n \n # Iterate through the array\n for num in arr:\n # If the number is already in the set, return True (duplicate found)\n if num in seen:\n return True\n # Otherwise, add the number to the set\n seen.add(num)\n \n # If no duplicates are found, return False\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(nums):\n # Use a set to keep track of seen numbers\n seen = set()\n \n for num in nums:\n # If the number is already in the set, we have a duplicate\n if num in seen:\n return True\n seen.add(num)\n \n # If we reach here, no duplicates were found\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(arr):\n # Create a set to store unique elements\n seen = set()\n \n # Iterate through the array\n for num in arr:\n # If the number is already in the set, we found a duplicate\n if num in seen:\n return True\n # Otherwise, add the number to the set\n seen.add(num)\n \n # If no duplicates found, return False\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(arr):\n # Create a set to store the elements of the array\n seen = set()\n \n # Iterate through each element in the array\n for num in arr:\n # If the element is already in the set, we found a duplicate\n if num in seen:\n return True\n seen.add(num)\n \n # If no duplicates were found, return False\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(nums):\n # Convert the list to a set and check if the lengths are different\n return len(nums) != len(set(nums))", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(arr):\n # Using a set to track seen numbers\n seen = set()\n \n for num in arr:\n # If the number is already in the set, we found a duplicate\n if num in seen:\n return True\n seen.add(num)\n \n # No duplicates found\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(arr):\n # Use a set to keep track of seen numbers\n seen = set()\n for num in arr:\n if num in seen:\n return True\n seen.add(num)\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(arr):\n # Create a set to store unique elements\n unique_elements = set()\n \n # Iterate through each element in the array\n for num in arr:\n # If the element is already in the set, a duplicate is found\n if num in unique_elements:\n return True\n # Add the element to the set\n unique_elements.add(num)\n \n # If no duplicates are found, return False\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(arr):\n # Use a set to track seen elements\n seen = set()\n \n # Iterate through the array\n for num in arr:\n # If the number is already in the set, we found a duplicate\n if num in seen:\n return True\n # Otherwise, add the number to the set\n seen.add(num)\n \n # If no duplicates were found, return False\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(arr):\n # Convert the list to a set to remove duplicates\n # If the length of the set is less than the original array, it means there were duplicates\n return len(arr) != len(set(arr))", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(arr):\n # Use a set to keep track of seen numbers\n seen = set()\n \n for num in arr:\n # If the number is already in the set, we found a duplicate\n if num in seen:\n return True\n # Add the number to the set\n seen.add(num)\n \n # If no duplicates were found, return False\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(arr):\n # Use a set to track seen numbers\n seen = set()\n for num in arr:\n if num in seen:\n return True\n seen.add(num)\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(arr):\n # Use a set to track seen numbers\n seen = set()\n for num in arr:\n if num in seen:\n return True\n seen.add(num)\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(arr):\n # Create a set to store unique elements\n seen = set()\n \n # Iterate through each element in the array\n for num in arr:\n # If the element is already in the set, a duplicate exists\n if num in seen:\n return True\n # Add the element to the set\n seen.add(num)\n \n # If no duplicates are found, return False\n return False", "matching_cluster_idx": 14}]}, "Mbpp/62": {"dps": 97.0, "dps_norm": 98.0, "pass@1": 100.0, "profiled": [{"solution": "def smallest_num(numbers):\n # Return the smallest number in the list using the min function\n return min(numbers)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(lst):\n # Return the minimum element in the list\n return min(lst)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(lst):\n # Use the min function to find the smallest number in the list\n return min(lst)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(lst):\n # Check if the list is empty\n if not lst:\n return None\n \n # Initialize the smallest number with the first element of the list\n smallest = lst[0]\n \n # Iterate through the list to find the smallest number\n for num in lst:\n if num < smallest:\n smallest = num\n \n return smallest", "matching_cluster_idx": 3}, {"solution": "def smallest_num(lst):\n # Return the minimum element in the list\n return min(lst)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(lst):\n # Return the minimum value from the list\n return min(lst)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(lst):\n # Return the smallest element in the list using the min function\n return min(lst)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(lst):\n # Return the smallest number in the list using the min function\n return min(lst)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(lst):\n # Check if the list is not empty\n if not lst:\n return None\n \n # Initialize the smallest number to the first element of the list\n smallest = lst[0]\n \n # Iterate through each number in the list\n for num in lst:\n # Update smallest if a smaller number is found\n if num < smallest:\n smallest = num\n \n return smallest", "matching_cluster_idx": 3}, {"solution": "def smallest_num(numbers):\n # Return the minimum value from the list using the min function\n return min(numbers)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(lst):\n # Return the minimum value from the list\n return min(lst)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(lst):\n # Return the minimum value from the list\n return min(lst)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(lst):\n # Return the minimum value from the list\n return min(lst)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(numbers):\n # Return the smallest number in the list\n return min(numbers)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(nums):\n # Return the smallest number in the list\n return min(nums)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(nums):\n # Return the smallest number in the list using the min function\n return min(nums)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(numbers):\n # Find and return the smallest number in the list\n return min(numbers)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(numbers):\n # Return the smallest number in the list\n return min(numbers)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(lst):\n # Use the min function to find the smallest number in the list\n return min(lst)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(lst):\n # Return the minimum value from the list\n return min(lst)", "matching_cluster_idx": 4}]}, "Mbpp/75": {"dps": 93.21428571428572, "dps_norm": 68.33333333333334, "pass@1": 100.0, "profiled": [{"solution": "def find_tuples(tuples_list, k):\n # Use list comprehension to filter tuples with all elements divisible by k\n result = [t for t in tuples_list if all(x % k == 0 for x in t)]\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(lst, k):\n # Use list comprehension to filter tuples with all elements divisible by k\n result = [t for t in lst if all(x % k == 0 for x in t)]\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(lst, k):\n # Use list comprehension to filter tuples where all elements are divisible by k\n result = [tup for tup in lst if all(ele % k == 0 for ele in tup)]\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n # Use list comprehension to find tuples where all elements are divisible by k\n result = [t for t in tuples_list if all(x % k == 0 for x in t)]\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(lst, k):\n # Filter the list to only include tuples where all elements are divisible by k\n result = [tup for tup in lst if all(x % k == 0 for x in tup)]\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(lst, k):\n # Use a list comprehension to filter tuples where all elements are divisible by k\n result = [t for t in lst if all(x % k == 0 for x in t)]\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n # Use a list comprehension to filter tuples where all elements are divisible by k\n result = [t for t in tuples_list if all(x % k == 0 for x in t)]\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n # Use list comprehension to filter tuples where all elements are divisible by k\n result = [t for t in tuples_list if all(x % k == 0 for x in t)]\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(lst, k):\n # Use list comprehension to filter tuples where all elements are divisible by k\n result = [t for t in lst if all(x % k == 0 for x in t)]\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n # Initialize an empty list to store the result\n result = []\n \n # Iterate through each tuple in the list\n for tup in tuples_list:\n # Check if all elements in the tuple are divisible by k\n if all(x % k == 0 for x in tup):\n # If true, add the tuple to the result list\n result.append(tup)\n \n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(lst, k):\n # List comprehension to filter tuples where all elements are divisible by k\n result = [tup for tup in lst if all(x % k == 0 for x in tup)]\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n # Initialize an empty list to store the result\n result = []\n \n # Iterate through each tuple in the list\n for tup in tuples_list:\n # Check if all elements in the tuple are divisible by k\n if all(x % k == 0 for x in tup):\n # If true, add the tuple to the result list\n result.append(tup)\n \n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(lst, k):\n # Initialize an empty list to store the resulting tuples\n result = []\n \n # Iterate through each tuple in the list\n for tup in lst:\n # Assume the tuple is valid until proven otherwise\n is_valid = True\n # Check each element in the tuple\n for elem in tup:\n # If any element is not divisible by k, mark it as invalid\n if elem % k != 0:\n is_valid = False\n break\n \n # If the tuple is valid (all elements divisible by k), add it to the result list\n if is_valid:\n result.append(tup)\n \n return result", "matching_cluster_idx": 8}, {"solution": "def find_tuples(lst, k):\n # Use a list comprehension to filter tuples where all elements are divisible by k\n result = [t for t in lst if all(x % k == 0 for x in t)]\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n # Use a list comprehension to filter the tuples\n result = [tup for tup in tuples_list if all(item % k == 0 for item in tup)]\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(lst, k):\n # Use list comprehension to filter tuples where all elements are divisible by k\n result = [tpl for tpl in lst if all(x % k == 0 for x in tpl)]\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(lst, k):\n # Use list comprehension to filter tuples where all elements are divisible by k\n result = [t for t in lst if all(x % k == 0 for x in t)]\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n # Use a list comprehension to filter tuples where all elements are divisible by k\n result = [t for t in tuples_list if all(x % k == 0 for x in t)]\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(lst, k):\n # Use list comprehension to filter tuples where all elements are divisible by k\n result = [tup for tup in lst if all(ele % k == 0 for ele in tup)]\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n # Use list comprehension to find tuples where all elements are divisible by k\n result = [t for t in tuples_list if all(x % k == 0 for x in t)]\n return result", "matching_cluster_idx": 5}]}, "Mbpp/88": {"dps": 74.80392156862744, "dps_norm": 70.0, "pass@1": 100.0, "profiled": [{"solution": "def freq_count(lst):\n # Import the Counter class from collections module\n from collections import Counter\n \n # Use Counter to get the frequency of elements in the list\n freq_dict = Counter(lst)\n \n # Return the dictionary\n return freq_dict", "matching_cluster_idx": 6}, {"solution": "def freq_count(lst):\n # Initialize an empty dictionary to store the frequency of elements\n frequency_dict = {}\n \n # Iterate over each element in the list\n for element in lst:\n # If the element is already in the dictionary, increment its count\n if element in frequency_dict:\n frequency_dict[element] += 1\n # Otherwise, add the element to the dictionary with a count of 1\n else:\n frequency_dict[element] = 1\n \n return frequency_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n # Create an empty dictionary to store the frequency of each element\n freq_dict = {}\n \n # Iterate over each element in the list\n for element in lst:\n # If the element is already in the dictionary, increment its count\n if element in freq_dict:\n freq_dict[element] += 1\n # If the element is not in the dictionary, add it with count 1\n else:\n freq_dict[element] = 1\n \n # Return the frequency dictionary\n return freq_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n # Initialize an empty dictionary to store the frequency of each element\n frequency_dict = {}\n \n # Iterate through each element in the list\n for item in lst:\n # If the item is already in the dictionary, increment its count\n if item in frequency_dict:\n frequency_dict[item] += 1\n else:\n # Otherwise, add the item to the dictionary with a count of 1\n frequency_dict[item] = 1\n \n return frequency_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n # Using dictionary comprehension to count the frequency of each element in the list\n return {key: lst.count(key) for key in lst}", "matching_cluster_idx": 0}, {"solution": "def freq_count(lst):\n # Use a dictionary to count the frequency of each element in the list\n frequency_dict = {}\n for item in lst:\n if item in frequency_dict:\n frequency_dict[item] += 1\n else:\n frequency_dict[item] = 1\n return frequency_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n # Create a dictionary to hold the frequency of each element\n frequency_dict = {}\n \n # Iterate over each element in the list\n for element in lst:\n # If the element is already in the dictionary, increment its count\n if element in frequency_dict:\n frequency_dict[element] += 1\n # Otherwise, add the element to the dictionary with a count of 1\n else:\n frequency_dict[element] = 1\n \n return frequency_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n # Initialize an empty dictionary to store the frequency of each element\n freq_dict = {}\n \n # Iterate over each element in the list\n for element in lst:\n # If the element is already in the dictionary, increment its count\n if element in freq_dict:\n freq_dict[element] += 1\n else:\n # Otherwise, add the element to the dictionary with a count of 1\n freq_dict[element] = 1\n \n return freq_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(arr):\n # Create a dictionary to store the frequency of each element\n frequency_dict = {}\n \n # Iterate over each element in the array\n for element in arr:\n # If the element is already in the dictionary, increment its count\n if element in frequency_dict:\n frequency_dict[element] += 1\n else:\n # Otherwise, add the element to the dictionary with a count of 1\n frequency_dict[element] = 1\n \n return frequency_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n # Using a dictionary comprehension to count frequencies of elements\n return {i: lst.count(i) for i in lst}", "matching_cluster_idx": 0}, {"solution": "def freq_count(lst):\n # Initialize an empty dictionary to store the frequency of elements\n frequency_dict = {}\n \n # Iterate over each element in the list\n for element in lst:\n # If the element is already in the dictionary, increment its count\n if element in frequency_dict:\n frequency_dict[element] += 1\n else:\n # Otherwise, add the element to the dictionary with a count of 1\n frequency_dict[element] = 1\n \n return frequency_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n # Initialize an empty dictionary to store frequencies\n frequency_dict = {}\n \n # Iterate through each item in the list\n for item in lst:\n # If the item is already in the dictionary, increment its count\n if item in frequency_dict:\n frequency_dict[item] += 1\n # If the item is not in the dictionary, add it with count 1\n else:\n frequency_dict[item] = 1\n \n return frequency_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n # Using a dictionary to count the frequency of each element in the list\n frequency_dict = {}\n for item in lst:\n if item in frequency_dict:\n frequency_dict[item] += 1\n else:\n frequency_dict[item] = 1\n return frequency_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n # Initialize an empty dictionary to store the frequency of elements\n freq_dict = {}\n \n # Iterate over each element in the list\n for element in lst:\n # If the element is already in the dictionary, increment its count\n if element in freq_dict:\n freq_dict[element] += 1\n # If the element is not in the dictionary, add it with count 1\n else:\n freq_dict[element] = 1\n \n return freq_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(arr):\n # Create a dictionary to store the frequency of each element\n freq_dict = {}\n \n # Iterate through the list and count the frequency of each element\n for element in arr:\n if element in freq_dict:\n freq_dict[element] += 1\n else:\n freq_dict[element] = 1\n \n return freq_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n # Create an empty dictionary to store the frequency of each element\n freq = {}\n \n # Iterate over each element in the list\n for item in lst:\n # If the element is already in the dictionary, increment its count\n if item in freq:\n freq[item] += 1\n # Otherwise, add the element to the dictionary with a count of 1\n else:\n freq[item] = 1\n \n # Return the dictionary containing elements and their frequencies\n return freq", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n # Using dictionary comprehension to count frequencies\n freq = {i: lst.count(i) for i in lst}\n return freq", "matching_cluster_idx": 0}, {"solution": "def freq_count(lst):\n # Using dictionary comprehension to count frequencies\n return {key: lst.count(key) for key in set(lst)}", "matching_cluster_idx": 2}, {"solution": "def freq_count(lst):\n # Use a dictionary comprehension to count the frequency of each element in the list\n return {element: lst.count(element) for element in lst}", "matching_cluster_idx": 0}, {"solution": "def freq_count(lst):\n # Initialize an empty dictionary to store the frequency of each element\n frequency_dict = {}\n \n # Iterate over each element in the list\n for element in lst:\n # If the element is already in the dictionary, increment its count\n if element in frequency_dict:\n frequency_dict[element] += 1\n else:\n # Otherwise, add the element to the dictionary with a count of 1\n frequency_dict[element] = 1\n \n return frequency_dict", "matching_cluster_idx": 5}]}, "Mbpp/90": {"dps": 95.90243902439025, "dps_norm": 97.14285714285714, "pass@1": 100.0, "profiled": [{"solution": "def len_log(words):\n # Find the longest word by using max function with key parameter set to len\n longest_word = max(words, key=len)\n # Return the length of the longest word\n return len(longest_word)", "matching_cluster_idx": 6}, {"solution": "def len_log(words):\n # Find the longest word by using the max function with key as len\n longest_word = max(words, key=len)\n return len(longest_word)", "matching_cluster_idx": 6}, {"solution": "def len_log(words):\n # Use max function with key parameter set to len to find the longest word\n longest_word = max(words, key=len)\n return len(longest_word)", "matching_cluster_idx": 6}, {"solution": "def len_log(words):\n # Find the longest word using max with key=len\n longest_word = max(words, key=len)\n # Return the length of the longest word\n return len(longest_word)", "matching_cluster_idx": 6}, {"solution": "def len_log(words):\n # Find the longest word using max with key=len, and return its length\n longest_word_length = len(max(words, key=len))\n return longest_word_length", "matching_cluster_idx": 6}, {"solution": "def len_log(words):\n # Find the longest word using max function and length as the key\n longest_word = max(words, key=len)\n # Return the length of the longest word\n return len(longest_word)", "matching_cluster_idx": 6}, {"solution": "def len_log(words):\n # Find the longest word using max with key=len\n longest_word = max(words, key=len)\n # Return the length of the longest word\n return len(longest_word)", "matching_cluster_idx": 6}, {"solution": "def len_log(words):\n # Initialize the maximum length to 0\n max_length = 0\n \n # Iterate through each word in the list\n for word in words:\n # Update max_length if the current word is longer\n if len(word) > max_length:\n max_length = len(word)\n \n # Return the length of the longest word\n return max_length", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n # Find the longest word using max with key=len\n longest_word = max(words, key=len)\n return len(longest_word)", "matching_cluster_idx": 6}, {"solution": "def len_log(words):\n # Find the longest word by sorting the list based on word length in descending order\n longest_word = max(words, key=len)\n return len(longest_word)", "matching_cluster_idx": 6}, {"solution": "def len_log(words):\n # Find the longest word in the list using max with key=len\n longest_word = max(words, key=len)\n # Return the length of the longest word\n return len(longest_word)", "matching_cluster_idx": 6}, {"solution": "def len_log(words):\n # Find the longest word by comparing lengths and return its length\n longest_word_length = max(len(word) for word in words)\n return longest_word_length", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n # Find the longest word using max with key=len\n longest_word = max(words, key=len)\n # Return the length of the longest word\n return len(longest_word)", "matching_cluster_idx": 6}, {"solution": "def len_log(words):\n # Use the max function with key parameter set to len to find the longest word\n longest_word = max(words, key=len)\n return len(longest_word)", "matching_cluster_idx": 6}, {"solution": "def len_log(words):\n # Find the longest word by comparing the lengths of all words\n longest_word = max(words, key=len)\n # Return the length of the longest word\n return len(longest_word)", "matching_cluster_idx": 6}, {"solution": "def len_log(words):\n # Find the longest word in the list and return its length\n longest_word = max(words, key=len)\n return len(longest_word)", "matching_cluster_idx": 6}, {"solution": "def len_log(words):\n # Initialize the length of the longest word\n max_length = 0\n \n # Iterate through each word in the list\n for word in words:\n # Update max_length if the current word is longer\n if len(word) > max_length:\n max_length = len(word)\n \n # Return the length of the longest word found\n return max_length", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n # Find the longest word by using max function with key parameter set to len\n longest_word = max(words, key=len)\n # Return the length of the longest word\n return len(longest_word)", "matching_cluster_idx": 6}, {"solution": "def len_log(words):\n # Find the longest word using max function with key set to len\n longest_word = max(words, key=len)\n # Return the length of the longest word\n return len(longest_word)", "matching_cluster_idx": 6}, {"solution": "def len_log(words):\n # Find the maximum length of the words in the list\n max_length = max(len(word) for word in words)\n return max_length", "matching_cluster_idx": 5}]}, "Mbpp/94": {"dps": 78.04878048780488, "dps_norm": 60.0, "pass@1": 100.0, "profiled": [{"solution": "def index_minimum(lst):\n # Find the tuple with the smallest second value and return its first value\n return min(lst, key=lambda x: x[1])[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(pairs):\n # Find the tuple with the smallest second value and return its first value\n return min(pairs, key=lambda x: x[1])[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(lst):\n # Find the tuple with the smallest second value\n min_tuple = min(lst, key=lambda x: x[1])\n # Return the first value of that tuple\n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(lst):\n # Find the tuple with the smallest second value\n min_tuple = min(lst, key=lambda x: x[1])\n # Return the first value of the tuple\n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(lst):\n # Check if the list is not empty to avoid index error\n if lst:\n # Find the tuple with the smallest second value\n min_tuple = min(lst, key=lambda x: x[1])\n # Return the first value of that tuple\n return min_tuple[0]\n else:\n return None # Return None or raise an error if the list is empty", "matching_cluster_idx": 2}, {"solution": "def index_minimum(lst):\n # Find the tuple with the smallest second value and return its first value\n return min(lst, key=lambda x: x[1])[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(lst):\n # Find the tuple with the smallest second value and return its first value\n return min(lst, key=lambda x: x[1])[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(lst):\n # Use the min function to find the tuple with the smallest second value\n # The key argument is set to index the tuple at the second position (index 1)\n smallest_tuple = min(lst, key=lambda x: x[1])\n # Return the first value of the tuple with the smallest second value\n return smallest_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(lst):\n # Find the tuple with the smallest second value\n min_tuple = min(lst, key=lambda x: x[1])\n # Return the first value of that tuple\n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(lst):\n # Find the tuple with the smallest second value\n min_tuple = min(lst, key=lambda x: x[1])\n # Return the first value of that tuple\n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(lst):\n # Find the tuple with the smallest second value\n min_tuple = min(lst, key=lambda x: x[1])\n # Return the first value of that tuple\n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(lst):\n # Find the tuple with the smallest second value and return its first value\n return min(lst, key=lambda x: x[1])[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(lst):\n # Find the tuple with the smallest second value\n min_tuple = min(lst, key=lambda x: x[1])\n # Return the first value of that tuple\n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(lst):\n # Find the tuple with the smallest second value\n min_tuple = min(lst, key=lambda x: x[1])\n # Return the first value of that tuple\n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(lst):\n # Find the tuple with the smallest second value and return its first value\n return min(lst, key=lambda x: x[1])[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(pairs):\n # Find the tuple with the smallest second value\n min_tuple = min(pairs, key=lambda x: x[1])\n # Return the first value of the tuple\n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(lst):\n # Check if the list is empty\n if not lst:\n return None\n \n # Find the tuple with the smallest second value\n min_tuple = min(lst, key=lambda x: x[1])\n \n # Return the first value of the tuple\n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(pairs):\n # Find the tuple with the smallest second value\n min_tuple = min(pairs, key=lambda x: x[1])\n # Return the first value of that tuple\n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(pairs):\n # Find the tuple with the smallest second value\n min_tuple = min(pairs, key=lambda x: x[1])\n # Return the first value of the tuple\n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(lst):\n # Find the tuple with the smallest second value\n min_tuple = min(lst, key=lambda x: x[1])\n # Return the first value of that tuple\n return min_tuple[0]", "matching_cluster_idx": 2}]}, "Mbpp/96": {"dps": 80.0, "dps_norm": 48.57142857142857, "pass@1": 94.0, "profiled": [{"solution": "def divisor(n):\n # Initialize divisor count\n count = 0\n # Iterate from 1 to n to count all divisors\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n # Initialize the count of divisors\n count = 0\n \n # Iterate from 1 to the given number n\n for i in range(1, n + 1):\n # If i is a divisor of n, increment the count\n if n % i == 0:\n count += 1\n \n # Return the total count of divisors\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n # Initialize count of divisors\n count = 0\n \n # Iterate from 1 to n (inclusive)\n for i in range(1, n + 1):\n # If i is a divisor of n, increment the count\n if n % i == 0:\n count += 1\n \n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n # Initialize count of divisors\n count = 0\n # Iterate through all numbers from 1 to n to check for divisors\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n # Initialize count of divisors\n count = 0\n \n # Iterate from 1 to n to check for divisors\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n \n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n # Initialize counter for divisors\n count = 0\n # Iterate from 1 to n (inclusive)\n for i in range(1, n + 1):\n # If i is a divisor of n, increment count\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n # Initialize divisor count\n count = 0\n # Loop through all possible divisors from 1 to n\n for i in range(1, n + 1):\n if n % i == 0: # Check if i is a divisor of n\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n # Initialize the count of divisors\n count = 0\n # Iterate from 1 to the square root of n\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n # If divisors are equal, count only once\n if n // i == i:\n count += 1\n else:\n # Otherwise, count both divisors\n count += 2\n return count", "matching_cluster_idx": 6}, {"solution": "def divisor(n):\n # Initialize a count variable to store the number of divisors\n count = 0\n # Loop through possible divisors from 1 to n\n for i in range(1, n + 1):\n # If i is a divisor of n, increment the count\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n # Initialize the divisor count\n count = 0\n # Loop through all possible divisors up to the number itself\n for i in range(1, n + 1):\n # If i is a divisor of n, increment the count\n if n % i == 0:\n count += 1\n # Return the total count of divisors\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n # Initialize divisor count\n count = 0\n \n # Loop through all possible divisors\n for i in range(1, n + 1):\n # If i is a divisor of n\n if n % i == 0:\n # Increment the count\n count += 1\n \n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n # Initialize count of divisors\n count = 0\n # Loop through possible divisors from 1 to n\n for i in range(1, n + 1):\n # If i is a divisor of n, increment count\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n # Initialize the count of divisors\n count = 0\n # Iterate from 1 to the square root of n\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0: # Check if i is a divisor\n count += 1 # Increment the count\n if i != n // i: # Check if n//i is different to avoid counting the square root twice\n count += 1 # Increment the count again if n//i is different\n return count", "matching_cluster_idx": 6}, {"solution": "def divisor(n):\n # Initialize count of divisors\n count = 0\n \n # Loop through all numbers from 1 to n (inclusive)\n for i in range(1, n + 1):\n # If i is a divisor of n, increment the count\n if n % i == 0:\n count += 1\n \n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n # Initialize a count variable to keep track of divisors\n count = 0\n # Iterate through all numbers from 1 to n (inclusive)\n for i in range(1, n + 1):\n # If i is a divisor of n, increment the count\n if n % i == 0:\n count += 1\n # Return the total count of divisors\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n # Initialize count to 0\n count = 0\n \n # Loop from 1 to n (inclusive)\n for i in range(1, n + 1):\n # If n is divisible by i, increment count\n if n % i == 0:\n count += 1\n \n # Return the total count of divisors\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n # Initialize count of divisors\n count = 0\n \n # Loop through all numbers from 1 to n\n for i in range(1, n + 1):\n # If i is a divisor of n, increment count\n if n % i == 0:\n count += 1\n \n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n # Initialize the count of divisors\n count = 0\n # Iterate from 1 to the given number n\n for i in range(1, n + 1):\n # If i is a divisor of n, increment the count\n if n % i == 0:\n count += 1\n # Return the total count of divisors\n return count", "matching_cluster_idx": 2}]}, "Mbpp/97": {"dps": 95.16239316239316, "dps_norm": 85.0, "pass@1": 91.0, "profiled": [{"solution": "def frequency_lists(lst_of_lsts):\n # Use a dictionary to count the frequency of each element\n frequency_dict = {}\n for sublist in lst_of_lsts:\n for elem in sublist:\n if elem in frequency_dict:\n frequency_dict[elem] += 1\n else:\n frequency_dict[elem] = 1\n return frequency_dict", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lists):\n # Initialize an empty dictionary to store the frequency of each element\n frequency = {}\n \n # Iterate through each sublist in the input list\n for sublist in lists:\n # Iterate through each element in the sublist\n for element in sublist:\n # If the element is already in the dictionary, increment its count\n if element in frequency:\n frequency[element] += 1\n else:\n # Otherwise, add the element to the dictionary with count 1\n frequency[element] = 1\n \n return frequency", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lists):\n # Flatten the list of lists and count frequencies\n flat_list = [item for sublist in lists for item in sublist]\n frequency_dict = {item: flat_list.count(item) for item in set(flat_list)}\n \n return frequency_dict", "matching_cluster_idx": 2}, {"solution": "def frequency_lists(lists):\n # Initialize an empty dictionary to store the frequencies\n frequency = {}\n \n # Iterate through each sublist in the input list of lists\n for sublist in lists:\n # Iterate through each element in the sublist\n for element in sublist:\n # If the element is already in the dictionary, increment its count\n if element in frequency:\n frequency[element] += 1\n # If the element is not in the dictionary, add it with a count of 1\n else:\n frequency[element] = 1\n \n # Return the resulting dictionary\n return frequency", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lists):\n # Create an empty dictionary to store the frequency of each element\n frequency_dict = {}\n \n # Iterate through each sublist in the input lists\n for sublist in lists:\n # Iterate through each element in the sublist\n for element in sublist:\n # If the element is already in the dictionary, increment its count\n if element in frequency_dict:\n frequency_dict[element] += 1\n # If the element is not in the dictionary, add it with count 1\n else:\n frequency_dict[element] = 1\n \n return frequency_dict", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lists):\n # Flatten the list of lists and count the frequency of each element\n frequency_dict = {}\n for sublist in lists:\n for element in sublist:\n if element in frequency_dict:\n frequency_dict[element] += 1\n else:\n frequency_dict[element] = 1\n return frequency_dict", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lists):\n # Create an empty dictionary to store the frequency of each element\n freq_dict = {}\n \n # Iterate over each sublist in the list of lists\n for sublist in lists:\n # Extend the frequency dictionary with the current sublist\n for item in sublist:\n if item in freq_dict:\n freq_dict[item] += 1\n else:\n freq_dict[item] = 1\n \n return freq_dict", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(list_of_lists):\n # Initialize an empty dictionary to store the frequency of each element\n frequency_dict = {}\n \n # Iterate through each list in the list of lists\n for sublist in list_of_lists:\n # Extend the frequency dictionary with the current sublist\n for element in sublist:\n if element in frequency_dict:\n frequency_dict[element] += 1\n else:\n frequency_dict[element] = 1\n \n return frequency_dict", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(nested_list):\n # Create an empty dictionary to store the frequency of each element\n frequency_dict = {}\n \n # Iterate through each sublist in the nested list\n for sublist in nested_list:\n # Iterate through each element in the sublist\n for element in sublist:\n # If the element is already in the dictionary, increment its count\n if element in frequency_dict:\n frequency_dict[element] += 1\n # Otherwise, add the element to the dictionary with a count of 1\n else:\n frequency_dict[element] = 1\n \n return frequency_dict", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lists):\n # Flatten the list of lists into a single list\n flat_list = [item for sublist in lists for item in sublist]\n \n # Create a dictionary to store the frequency of each element\n frequency_dict = {}\n \n # Iterate through the flat list and count the frequency of each element\n for item in flat_list:\n if item in frequency_dict:\n frequency_dict[item] += 1\n else:\n frequency_dict[item] = 1\n \n return frequency_dict", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lists):\n # Flatten the list of lists and count the frequency of each element\n frequency_dict = {}\n for sublist in lists:\n for item in sublist:\n if item in frequency_dict:\n frequency_dict[item] += 1\n else:\n frequency_dict[item] = 1\n return frequency_dict", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lists):\n # Initialize an empty dictionary to store the frequency of each element\n freq_dict = {}\n \n # Iterate through each sublist in the input list\n for sublist in lists:\n # Update the frequency of each element in the current sublist\n for element in sublist:\n if element in freq_dict:\n freq_dict[element] += 1\n else:\n freq_dict[element] = 1\n \n return freq_dict", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lists):\n # Flatten the list of lists\n flat_list = [item for sublist in lists for item in sublist]\n \n # Create a dictionary to hold the frequency of each element\n frequency = {}\n \n # Iterate over the flattened list and count the frequency of each element\n for item in flat_list:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n \n return frequency", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lists):\n from collections import defaultdict\n \n # Initialize a defaultdict to count frequencies\n frequency_dict = defaultdict(int)\n \n # Iterate over each sublist and then over each element in the sublist\n for sublist in lists:\n for element in sublist:\n frequency_dict[element] += 1\n \n # Convert defaultdict to a regular dict before returning\n return dict(frequency_dict)", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lst_of_lsts):\n # Create an empty dictionary to store the frequency of each element\n frequency_dict = {}\n \n # Iterate through each sublist and then each element in the sublist\n for sublist in lst_of_lsts:\n for element in sublist:\n # If the element is already in the dictionary, increment its count\n if element in frequency_dict:\n frequency_dict[element] += 1\n # If the element is not in the dictionary, add it with count 1\n else:\n frequency_dict[element] = 1\n \n return frequency_dict", "matching_cluster_idx": 6}, {"solution": "from collections import Counter\ndef frequency_lists(lst_of_lsts):\n # Flatten the list of lists\n flat_list = [item for sublist in lst_of_lsts for item in sublist]\n # Count the frequency of each element\n frequency = Counter(flat_list)\n # Return the frequency as a dictionary\n return dict(frequency)", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lst):\n # Flatten the list of lists\n flat_list = [item for sublist in lst for item in sublist]\n \n # Create a dictionary to hold the frequency of each element\n frequency = {}\n \n # Count the frequency of each element in the flattened list\n for item in flat_list:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n \n return frequency", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lists):\n # Initialize an empty dictionary to store the frequency of elements\n freq_dict = {}\n \n # Iterate through each sublist in the list of lists\n for sublist in lists:\n # Update the frequency of each element in the sublist\n for element in sublist:\n if element in freq_dict:\n freq_dict[element] += 1\n else:\n freq_dict[element] = 1\n \n return freq_dict", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lists):\n # Flatten the list of lists and count frequencies\n from collections import Counter\n \n flat_list = [item for sublist in lists for item in sublist]\n frequency_dict = dict(Counter(flat_list))\n \n return frequency_dict", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lists):\n # Initialize an empty dictionary to store the frequency of elements\n frequency_dict = {}\n \n # Iterate through each sublist in the given list of lists\n for sublist in lists:\n # Update the frequency dictionary with each element in the sublist\n for element in sublist:\n if element in frequency_dict:\n frequency_dict[element] += 1\n else:\n frequency_dict[element] = 1\n \n return frequency_dict", "matching_cluster_idx": 6}]}, "Mbpp/106": {"dps": 48.47402597402598, "dps_norm": 84.16666666666666, "pass@1": 92.0, "profiled": [{"solution": "def add_lists(lst, tup):\n # Concatenate the list to the tuple\n result = tup + tuple(lst)\n return result", "matching_cluster_idx": 4}, {"solution": "def add_lists(lst, tup):\n # Concatenate the tuple and the list and return the result\n return tup + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, t):\n # Concatenate the list to the tuple and return the result\n return t + tuple(lst)", "matching_cluster_idx": 4}, {"solution": "def add_lists(list1, tuple1):\n # Concatenate the tuple and the list\n result = tuple1 + tuple(list1)\n return result", "matching_cluster_idx": 4}, {"solution": "def add_lists(lst, tup):\n # Extend the tuple with the list\n result = tup + tuple(lst)\n return result", "matching_cluster_idx": 4}, {"solution": "def add_lists(list1, tuple1):\n # Convert the tuple to a list, extend it with the second list, and convert it back to a tuple\n result_tuple = tuple(list(tuple1) + list1)\n return result_tuple", "matching_cluster_idx": 2}, {"solution": "def add_lists(list_to_add, tuple_to_append):\n # Convert the tuple to a list to allow modification\n modified_list = list(tuple_to_append)\n # Extend the modified list with the given list\n modified_list.extend(list_to_add)\n # Convert the list back to a tuple and return\n return tuple(modified_list)", "matching_cluster_idx": 4}, {"solution": "def add_lists(lst, tup):\n # Concatenate the tuple and the list and return the result\n return tup + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tpl):\n # Concatenate the list to the tuple and return the result\n return tpl + tuple(lst)", "matching_cluster_idx": 4}, {"solution": "def add_lists(lst, tup):\n # Concatenate the tuple and the list and return the result as a new tuple\n return tup + tuple(lst)", "matching_cluster_idx": 4}, {"solution": "def add_lists(lst, tup):\n # Use the + operator to concatenate the tuple and the list\n return tup + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tup):\n # Combine the tuple and the list into a new tuple\n new_tuple = tup + tuple(lst)\n return new_tuple", "matching_cluster_idx": 4}, {"solution": "def add_lists(lst, tup):\n # Combine the tuple and the list into a new tuple\n result = tup + tuple(lst)\n return result", "matching_cluster_idx": 4}, {"solution": "def add_lists(lst, tpl):\n # Use the + operator to concatenate the list and the tuple\n result = tpl + tuple(lst)\n return result", "matching_cluster_idx": 4}, {"solution": "def add_lists(lst, tup):\n # Concatenate the list to the tuple and return the result\n return tup + tuple(lst)", "matching_cluster_idx": 4}, {"solution": "def add_lists(lst, tup):\n # Concatenate the list to the tuple and return the result\n return tup + tuple(lst)", "matching_cluster_idx": 4}, {"solution": "def add_lists(lst, tup):\n # Concatenate the tuple and the list and return the result as a new tuple\n return tup + tuple(lst)", "matching_cluster_idx": 4}, {"solution": "def add_lists(lst, tup):\n # Convert the tuple to a list, extend it with the new list, and then convert it back to a tuple\n return tuple(list(tup) + lst)", "matching_cluster_idx": 3}, {"solution": "def add_lists(list1, tuple1):\n # Convert the tuple to a list to allow modification\n modified_list = list(tuple1)\n # Extend the modified list with elements from the given list\n modified_list.extend(list1)\n # Convert the list back to a tuple and return\n return tuple(modified_list)", "matching_cluster_idx": 4}, {"solution": "def add_lists(lst, tup):\n # Concatenate the list to the tuple and return the new tuple\n return tup + tuple(lst)", "matching_cluster_idx": 5}]}, "Mbpp/108": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 99.0, "profiled": [{"solution": "def merge_sorted_list(list1, list2, list3):\n # Combine all three lists into one\n merged_list = list1 + list2 + list3\n # Sort the merged list\n merged_list.sort()\n return merged_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Combine all three lists\n combined_list = list1 + list2 + list3\n \n # Sort the combined list\n combined_list.sort()\n \n return combined_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Merge all three lists into one\n merged_list = list1 + list2 + list3\n \n # Sort the merged list\n merged_list.sort()\n \n return merged_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Combine the three lists into one\n combined_list = list1 + list2 + list3\n \n # Sort the combined list\n combined_list.sort()\n \n return combined_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Merge the three lists\n merged_list = list1 + list2 + list3\n # Sort the merged list\n merged_list.sort()\n return merged_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Combine all three lists\n combined_list = list1 + list2 + list3\n \n # Sort the combined list\n combined_list.sort()\n \n return combined_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Merge all three lists into one\n merged_list = list1 + list2 + list3\n # Sort the merged list\n merged_list.sort()\n return merged_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Combine all three lists\n combined_list = list1 + list2 + list3\n # Sort the combined list\n combined_list.sort()\n return combined_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Merge all three lists\n merged_list = list1 + list2 + list3\n # Sort the merged list\n merged_list.sort()\n return merged_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Combine all three lists\n combined_list = list1 + list2 + list3\n # Sort the combined list\n combined_list.sort()\n return combined_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Combine all three lists into one\n combined_list = list1 + list2 + list3\n \n # Sort the combined list\n combined_list.sort()\n \n return combined_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Combine the three lists into one\n combined_list = list1 + list2 + list3\n # Sort the combined list\n combined_list.sort()\n return combined_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Merge all three lists into one\n merged_list = list1 + list2 + list3\n \n # Sort the merged list\n merged_list.sort()\n \n return merged_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Merge all three lists into one\n merged_list = list1 + list2 + list3\n # Sort the merged list\n merged_list.sort()\n return merged_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Combine all three lists into one\n combined_list = list1 + list2 + list3\n # Sort the combined list\n combined_list.sort()\n return combined_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Combine all three lists\n combined_list = list1 + list2 + list3\n \n # Sort the combined list\n combined_list.sort()\n \n return combined_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Combine all three lists into one\n merged_list = list1 + list2 + list3\n # Sort the combined list in ascending order\n merged_list.sort()\n return merged_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Combine all three lists into one\n combined_list = list1 + list2 + list3\n # Sort the combined list\n combined_list.sort()\n return combined_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Merge all lists into one\n merged_list = list1 + list2 + list3\n # Sort the merged list\n merged_list.sort()\n return merged_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(lst1, lst2, lst3):\n # Merge all lists into one\n merged_list = lst1 + lst2 + lst3\n # Sort the merged list\n merged_list.sort()\n return merged_list", "matching_cluster_idx": 10}]}, "Mbpp/111": {"dps": 77.06153846153846, "dps_norm": 81.25, "pass@1": 76.0, "profiled": [{"solution": "def common_in_nested_lists(nested_lists):\n # Flatten the nested lists into a single list\n flat_list = [item for sublist in nested_lists for item in sublist]\n # Find the common elements in the flat list\n common_elements = set(flat_list)\n for sublist in nested_lists:\n common_elements.intersection_update(sublist)\n return common_elements", "matching_cluster_idx": 3}, {"solution": "def common_in_nested_lists(nested_lists):\n # Flatten the nested list into a single list of elements\n flat_list = [item for sublist in nested_lists for item in sublist]\n # Use set operations to find common elements\n common_elements = set(flat_list)\n for sublist in nested_lists:\n common_elements.intersection_update(sublist)\n return common_elements", "matching_cluster_idx": 3}, {"solution": "def common_in_nested_lists(nested_lists):\n # Import the set intersection function\n from functools import reduce\n \n # Use set intersection to find common elements\n common_elements = reduce(set.intersection, map(set, nested_lists))\n \n return common_elements", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n # Extract the first list's elements to start with\n common_elements = set(nested_lists[0])\n \n # Iterate through each list starting from the second one\n for lst in nested_lists[1:]:\n # Intersect the current set of common elements with the current list\n common_elements.intersection_update(lst)\n \n # Return the set of common elements\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n # Initialize the set with the first list's elements\n common_elements = set(nested_lists[0])\n \n # Iterate through the rest of the lists starting from the second one\n for lst in nested_lists[1:]:\n # Update the set of common elements with the intersection of the current set and the list\n common_elements.intersection_update(lst)\n \n return common_elements", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n # Initialize the set with the first sublist's elements\n common_elements = set(nested_lists[0])\n \n # Iterate through each sublist starting from the second one\n for sublist in nested_lists[1:]:\n # Retain only the elements that are also in the current sublist\n common_elements.intersection_update(sublist)\n \n return common_elements", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n # Initialize the common elements set with the first list\n common_elements = set(nested_lists[0])\n \n # Iterate through each sublist starting from the second one\n for sublist in nested_lists[1:]:\n # Update the set to only include elements present in the current sublist\n common_elements.intersection_update(sublist)\n \n # Return the final set of common elements\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n if not nested_lists:\n return set()\n \n # Convert all inner lists to sets for easier intersection operation\n set_of_lists = [set(inner_list) for inner_list in nested_lists]\n \n # Use set.intersection to find common elements\n common_elements = set.intersection(*set_of_lists)\n \n return common_elements", "matching_cluster_idx": 4}, {"solution": "def common_in_nested_lists(nested_lists):\n # Extract the first list from the nested lists\n common_elements = set(nested_lists[0])\n \n # Iterate over the remaining lists starting from the second one\n for lst in nested_lists[1:]:\n # Update the common elements set to keep only the common elements\n common_elements.intersection_update(lst)\n \n return common_elements", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n # Use set intersection to find common elements in all sublists\n common_elements = set.intersection(*map(set, nested_lists))\n return common_elements", "matching_cluster_idx": 5}, {"solution": "def common_in_nested_lists(nested_lists):\n # Initialize the set of common elements with the first list's elements\n common_elements = set(nested_lists[0])\n \n # Iterate through the remaining nested lists\n for sublist in nested_lists[1:]:\n # Update the set of common elements by intersecting with the current sublist\n common_elements.intersection_update(sublist)\n \n return common_elements", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n # Use set intersection to find common elements\n if not nested_lists:\n return set()\n common_elements = set(nested_lists[0])\n for lst in nested_lists[1:]:\n common_elements.intersection_update(lst)\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n if not nested_lists:\n return set()\n \n # Convert each sublist to a set and store in a list\n set_lists = [set(sublist) for sublist in nested_lists]\n \n # Initialize the result with the first set\n common_elements = set_lists[0]\n \n # Iterate over the other sets and retain only the common elements\n for s in set_lists[1:]:\n common_elements.intersection_update(s)\n \n return common_elements", "matching_cluster_idx": 5}, {"solution": "def common_in_nested_lists(nested_lists):\n # Initialize the set of common elements with the first list\n common_elements = set(nested_lists[0])\n \n # Iterate through each list starting from the second one\n for lst in nested_lists[1:]:\n # Update the set of common elements to only keep common items\n common_elements.intersection_update(lst)\n \n # Return the set of common elements found\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n # Initialize the set with all elements from the first list\n common_elements = set(nested_lists[0])\n \n # Iterate through each list starting from the second one\n for lst in nested_lists[1:]:\n # Update the set to retain only the elements that are in both sets\n common_elements.intersection_update(lst)\n \n return common_elements", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n # Extract the first list from the nested lists to start comparison\n common_elements = set(nested_lists[0])\n \n # Iterate over each subsequent list in the nested lists\n for lst in nested_lists[1:]:\n # Update the set of common elements by intersecting with the current list\n common_elements.intersection_update(lst)\n \n return common_elements", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n # Find the first list to start comparison\n if not nested_lists:\n return set()\n \n # Initialize the set with elements of the first list\n common_elements = set(nested_lists[0])\n \n # Iterate through each list starting from the second one\n for sublist in nested_lists[1:]:\n # Update the set of common elements with the intersection of the current set and the sublist\n common_elements.intersection_update(sublist)\n \n return common_elements", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n # Extract the first list and convert it to a set\n common_elements = set(nested_lists[0])\n \n # Iterate through the rest of the lists\n for lst in nested_lists[1:]:\n # Update the set of common elements\n common_elements.intersection_update(lst)\n \n return common_elements", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n # Initialize the set with the first list's elements\n common_elements = set(nested_lists[0])\n \n # Iterate through each sublist starting from the second one\n for sublist in nested_lists[1:]:\n # Intersect the current set of common elements with the next sublist\n common_elements.intersection_update(sublist)\n \n # Return the set of common elements\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n if not nested_lists:\n return set()\n \n # Use set intersection to find common elements\n common_elements = set(nested_lists[0])\n for lst in nested_lists[1:]:\n common_elements &= set(lst)\n \n return common_elements", "matching_cluster_idx": 6}]}, "Mbpp/123": {"dps": 99.62686567164178, "dps_norm": 85.71428571428571, "pass@1": 12.0, "profiled": [{"solution": "def sum_of_divisors(n):\n \"\"\"Return the sum of proper divisors of n.\"\"\"\n sum_div = 1 # Start with 1 because it's a proper divisor for all n > 1\n sqrt_n = int(n**0.5)\n for i in range(2, sqrt_n + 1):\n if n % i == 0:\n sum_div += i\n if i != n // i:\n sum_div += n // i\n return sum_div\ndef is_amicable(x):\n \"\"\"Check if a number is amicable and return its pair if it is.\"\"\"\n y = sum_of_divisors(x)\n if y > x and sum_of_divisors(y) == x:\n return y\n return None\ndef amicable_numbers_sum(max_num):\n amicable_set = set()\n for num in range(2, max_num):\n pair = is_amicable(num)\n if pair and pair < max_num and pair not in amicable_set:\n amicable_set.add(num)\n amicable_set.add(pair)\n return sum(amicable_set)", "matching_cluster_idx": 11}, {"solution": "def divisors_sum(n):\n \"\"\"Return the sum of proper divisors of n.\"\"\"\n divisors = [1] # 1 is a proper divisor of any n > 1\n for i in range(2, int(n ** 0.5) + 1):\n if n % i == 0:\n divisors.append(i)\n if i != n // i:\n divisors.append(n // i)\n return sum(divisors)\ndef amicable_numbers_sum(limit):\n \"\"\"\n Return the sum of all amicable numbers less than the specified limit.\n \n An amicable pair (a, b) consists of two integers for which the sum of proper divisors\n (excluding the number itself) of one is equal to the other number, and vice versa.\n \"\"\"\n sum_of_divisors = [0] * (limit + 1)\n for i in range(2, limit):\n sum_of_divisors[i] = divisors_sum(i)\n \n amicable_sum = 0\n for i in range(2, limit):\n j = sum_of_divisors[i]\n if j <= limit and i != j and sum_of_divisors[j] == i:\n amicable_sum += i\n \n return amicable_sum", "matching_cluster_idx": 11}, {"solution": "def sum_of_divisors(n):\n \"\"\"Return the sum of proper divisors of n.\"\"\"\n divisors_sum = 1 # Start with 1 since it's a proper divisor for any n > 1\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n divisors_sum += i\n if i != n // i: # Add the quotient only if it's different from i\n divisors_sum += n // i\n return divisors_sum\ndef is_amicable(a):\n \"\"\"Check if a number is amicable.\"\"\"\n b = sum_of_divisors(a)\n return b != a and sum_of_divisors(b) == a\ndef amicable_numbers_sum(n):\n \"\"\"Return the sum of all amicable numbers less than or equal to n.\"\"\"\n total_sum = 0\n for num in range(2, n + 1):\n if is_amicable(num):\n total_sum += num\n return total_sum", "matching_cluster_idx": 11}, {"solution": "def sum_of_divisors(n):\n # Calculate the sum of divisors of a number excluding the number itself\n div_sum = 1 # Start with 1 since it's a divisor of all numbers\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n div_sum += i\n if i != n // i:\n div_sum += n // i\n return div_sum\ndef amicable_numbers_sum(n):\n # Initialize the total sum of amicable numbers\n total_sum = 0\n \n # Iterate through all numbers from 2 to n-1\n for i in range(2, n):\n j = sum_of_divisors(i)\n \n # Check if i and j are amicable\n if j != i and sum_of_divisors(j) == i:\n total_sum += i\n \n return total_sum", "matching_cluster_idx": 11}, {"solution": "def sum_of_divisors(n):\n \"\"\"Return the sum of proper divisors of n.\"\"\"\n divisors_sum = 1 # 1 is a proper divisor of all natural numbers\n sqrt_n = int(n ** 0.5)\n for i in range(2, sqrt_n + 1):\n if n % i == 0:\n divisors_sum += i\n if i != n // i: # Add the quotient only if it's different from i\n divisors_sum += n // i\n return divisors_sum\ndef is_amicable(a, amicable_dict):\n \"\"\"Check if a number is amicable and return the corresponding amicable number.\"\"\"\n b = sum_of_divisors(a)\n if a == sum_of_divisors(b) and a != b:\n amicable_dict[a] = b\n return b\n return None\ndef amicable_numbers_sum(max_num):\n \"\"\"\n Return the sum of all amicable numbers less than max_num.\n \"\"\"\n amicable_dict = {}\n for num in range(2, max_num):\n is_amicable(num, amicable_dict)\n return sum(amicable_dict.values())", "matching_cluster_idx": 11}, {"solution": "def amicable_numbers_sum(n):\n # Helper function to calculate the sum of proper divisors of x\n def sum_of_divisors(x):\n divisors_sum = 1 # Start from 1 since it's a proper divisor for all x > 1\n for i in range(2, int(x ** 0.5) + 1):\n if x % i == 0:\n divisors_sum += i\n if i != x // i:\n divisors_sum += x // i\n return divisors_sum\n \n amicable_sum = 0\n \n for num in range(2, n + 1):\n # Calculate sum of proper divisors\n div_sum = sum_of_divisors(num)\n # Check if num and div_sum are amicable\n if num != div_sum and sum_of_divisors(div_sum) == num:\n amicable_sum += num\n \n return amicable_sum", "matching_cluster_idx": 11}, {"solution": "def d(n):\n \"\"\"Calculate the sum of proper divisors of n.\"\"\"\n divisors_sum = 1 # Start with 1 because it's a proper divisor of all n > 1\n for i in range(2, int(n ** 0.5) + 1):\n if n % i == 0:\n divisors_sum += i\n if i != n // i:\n divisors_sum += n // i\n return divisors_sum\ndef is_amicable(a):\n \"\"\"Check if a number is part of an amicable pair.\"\"\"\n b = d(a)\n return a != b and d(b) == a\ndef amicable_numbers_sum(n):\n \"\"\"\n Sum all amicable numbers from 1 to n.\n\n :param n: The upper limit.\n :return: Sum of all amicable numbers up to n.\n \"\"\"\n return sum(x for x in range(2, n) if is_amicable(x))", "matching_cluster_idx": 11}, {"solution": "def divisors_sum(n):\n # Calculate the sum of proper divisors of n\n sum_divisors = 1 # Start with 1 because it's a proper divisor for all n > 1\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n sum_divisors += i\n if i != n // i:\n sum_divisors += n // i\n return sum_divisors\ndef amicable_numbers_sum(n):\n # List to store amicable numbers\n amicable_list = []\n \n for num in range(2, n + 1):\n pair = divisors_sum(num)\n # Check if the pair is amicable and not the same as num\n if pair != num and divisors_sum(pair) == num:\n amicable_list.append(num)\n amicable_list.append(pair)\n \n # Remove duplicates and sum all unique amicable numbers\n unique_amicable_numbers = list(set(amicable_list))\n return sum(unique_amicable_numbers)", "matching_cluster_idx": 11}, {"solution": "def sum_of_divisors(n):\n \"\"\"Return the sum of proper divisors of n.\"\"\"\n divisors_sum = 1 # Start with 1 since it's a divisor for all n > 1\n sqrt_n = int(n**0.5)\n for i in range(2, sqrt_n + 1):\n if n % i == 0:\n divisors_sum += i\n if i != n // i:\n divisors_sum += n // i\n return divisors_sum\ndef amicable_numbers_sum(n):\n \"\"\"\n Return the sum of all amicable numbers less than or equal to n.\n \n An amicable pair (a, b) are two different numbers where the sum of the proper\n divisors of one number equals the other number, and vice versa.\n \"\"\"\n def is_amicable(a):\n b = sum_of_divisors(a)\n return a != b and sum_of_divisors(b) == a\n \n amicable_sum = 0\n for num in range(2, n + 1):\n if is_amicable(num):\n amicable_sum += num\n return amicable_sum", "matching_cluster_idx": 11}, {"solution": "def amicable_numbers_sum(n):\n # Function to calculate the sum of proper divisors of x\n def sum_of_proper_divisors(x):\n divisors_sum = 1 # 1 is a proper divisor of all natural numbers\n sqrt_x = int(x ** 0.5)\n for i in range(2, sqrt_x + 1):\n if x % i == 0:\n divisors_sum += i\n if i != x // i:\n divisors_sum += x // i\n return divisors_sum\n \n # List to keep track of amicable numbers\n amicable_sum = 0\n \n # Calculate sum of amicable numbers\n for num in range(2, n + 1):\n # Calculate the sum of proper divisors of num\n div_sum = sum_of_proper_divisors(num)\n # Check if the pair (num, div_sum) are amicable\n if num != div_sum and sum_of_proper_divisors(div_sum) == num:\n amicable_sum += num\n \n return amicable_sum", "matching_cluster_idx": 11}, {"solution": "def sum_divisors(n):\n \"\"\"Return the sum of all proper divisors of n.\"\"\"\n sum = 1 # Start with 1 because it's a divisor for any n > 1\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n sum += i\n if i != n // i: # Add the quotient only if it's different from i\n sum += n // i\n return sum\ndef amicable_numbers_sum(n):\n \"\"\"\n Return the sum of all amicable numbers less than or equal to n.\n \n Amicable numbers are two different numbers so related that the sum of the proper divisors \n of each is equal to the other number.\n \"\"\"\n amicable_sum = 0\n for num in range(2, n + 1):\n # Calculate the sum of divisors for num\n sum1 = sum_divisors(num)\n sum2 = sum_divisors(sum1)\n \n # Check if num and sum1 are amicable and sum1 is within range\n if num == sum2 and num != sum1:\n amicable_sum += num\n return amicable_sum", "matching_cluster_idx": 11}, {"solution": "def sum_divisors(n):\n \"\"\"Return the sum of proper divisors of n.\"\"\"\n sum_div = 1 # Start with 1 because it's a proper divisor of every number\n sqrt_n = int(n**0.5)\n for i in range(2, sqrt_n + 1):\n if n % i == 0:\n sum_div += i\n if i != n // i: # Avoid adding the square root twice for perfect squares\n sum_div += n // i\n return sum_div\ndef amicable_numbers_sum(limit):\n \"\"\"\n Return the sum of all amicable numbers from 1 to the specified limit.\n \n An amicable pair (a, b) are two numbers for which the sum of proper divisors\n (excluding the number itself) of one is equal to the other number, and vice versa.\n \"\"\"\n amicable_sum = 0\n for num in range(2, limit):\n if num == sum_divisors(sum_divisors(num)) and sum_divisors(num) != num:\n amicable_sum += num\n return amicable_sum", "matching_cluster_idx": 11}]}, "Mbpp/128": {"dps": 99.5475113122172, "dps_norm": 80.0, "pass@1": 61.0, "profiled": [{"solution": "def long_words(n, sentence):\n # Split the sentence into words\n words = sentence.split()\n # Filter words that are longer than n characters\n long_words_list = [word for word in words if len(word) > n]\n return long_words_list", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n # Split the sentence into words\n words = sentence.split()\n \n # Filter words that are longer than n characters\n long_words_list = [word for word in words if len(word) > n]\n \n return long_words_list", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n # Split the sentence into words\n words = sentence.split()\n \n # Filter words that are longer than n characters\n long_words_list = [word for word in words if len(word) > n]\n \n return long_words_list", "matching_cluster_idx": 3}, {"solution": "def long_words(n, words):\n # Filter words that are longer than n characters\n long_words_list = [word for word in words.split() if len(word) > n]\n return long_words_list", "matching_cluster_idx": 3}, {"solution": "def long_words(n, words_string):\n # Split the input string into words\n words = words_string.split()\n \n # Filter words that are longer than n characters\n long_words = [word for word in words if len(word) > n]\n \n return long_words", "matching_cluster_idx": 3}, {"solution": "def long_words(n, words_string):\n # Split the input string into words\n words = words_string.split()\n # Filter words that are longer than n characters\n long_words_list = [word for word in words if len(word) > n]\n return long_words_list", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n # Split the sentence into words\n words = sentence.split()\n # Filter words that are longer than n characters\n long_words = [word for word in words if len(word) > n]\n return long_words", "matching_cluster_idx": 3}, {"solution": "def long_words(n, words_string):\n # Split the input string into a list of words\n words_list = words_string.split()\n \n # Filter out the words that are longer than n characters\n long_words_list = [word for word in words_list if len(word) > n]\n \n # Return the list of long words\n return long_words_list", "matching_cluster_idx": 3}, {"solution": "def long_words(n, words):\n # Use list comprehension to filter words longer than n characters\n long_words_list = [word for word in words.split() if len(word) > n]\n return long_words_list", "matching_cluster_idx": 3}, {"solution": "def long_words(n, words):\n # Use a list comprehension to filter words longer than n characters\n long_words_list = [word for word in words.split() if len(word) > n]\n return long_words_list", "matching_cluster_idx": 3}, {"solution": "def long_words(n, words):\n # Use a list comprehension to filter words longer than n characters\n long_words_list = [word for word in words.split() if len(word) > n]\n return long_words_list", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n # Split the sentence into words\n words = sentence.split()\n # Filter words that are longer than n characters\n long_words_list = [word for word in words if len(word) > n]\n return long_words_list", "matching_cluster_idx": 3}, {"solution": "def long_words(n, words_string):\n # Split the input string into a list of words\n words_list = words_string.split()\n \n # Use a list comprehension to filter words longer than n characters\n long_words_list = [word for word in words_list if len(word) > n]\n \n return long_words_list", "matching_cluster_idx": 3}, {"solution": "def long_words(n, words_string):\n # Split the words_string into a list of words\n words_list = words_string.split()\n # Filter out the words that are longer than n characters\n long_words_list = [word for word in words_list if len(word) > n]\n return long_words_list", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n # Split the sentence into words\n words = sentence.split()\n \n # Filter words that are longer than n characters\n long_words_list = [word for word in words if len(word) > n]\n \n return long_words_list", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n # Split the sentence into words\n words = sentence.split()\n \n # Filter words that are longer than n characters\n long_words = [word for word in words if len(word) > n]\n \n return long_words", "matching_cluster_idx": 3}, {"solution": "def long_words(n, words_string):\n # Split the input string into a list of words\n words_list = words_string.split()\n \n # Use a list comprehension to filter words longer than n characters\n long_words_list = [word for word in words_list if len(word) > n]\n \n return long_words_list", "matching_cluster_idx": 3}, {"solution": "def long_words(n, words_string):\n # Split the input string into words\n words_list = words_string.split()\n # Filter words that are longer than n characters\n long_words_list = [word for word in words_list if len(word) > n]\n return long_words_list", "matching_cluster_idx": 3}, {"solution": "def long_words(n, words):\n # Use list comprehension to filter words longer than n characters\n return [word for word in words.split() if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, words_string):\n # Split the input string into a list of words\n words_list = words_string.split()\n # Use list comprehension to filter words longer than n characters\n long_words_list = [word for word in words_list if len(word) > n]\n return long_words_list", "matching_cluster_idx": 3}]}, "Mbpp/129": {"dps": 72.07908163265306, "dps_norm": 96.33333333333333, "pass@1": 50.0, "profiled": [{"solution": "def is_magic_square(matrix):\n n = len(matrix)\n # Calculate the sum of the first row to use as a reference\n magic_sum = sum(matrix[0])\n \n # Check row sums\n for row in matrix:\n if sum(row) != magic_sum:\n return False\n \n # Check column sums\n for col in range(n):\n if sum(matrix[row][col] for row in range(n)) != magic_sum:\n return False\n \n # Check diagonal sums\n if sum(matrix[i][i] for i in range(n)) != magic_sum:\n return False\n if sum(matrix[i][n-1-i] for i in range(n)) != magic_sum:\n return False\n \n return True\ndef magic_square_test(matrix):\n return is_magic_square(matrix)", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(square):\n # Check if the input is a square matrix\n n = len(square)\n if any(len(row) != n for row in square):\n return False\n \n # Calculate the sum of the first row to use as a reference\n magic_sum = sum(square[0])\n \n # Check row sums\n for row in square:\n if sum(row) != magic_sum:\n return False\n \n # Check column sums\n for col in range(n):\n if sum(square[row][col] for row in range(n)) != magic_sum:\n return False\n \n # Check diagonal sums\n if sum(square[i][i] for i in range(n)) != magic_sum:\n return False\n if sum(square[i][n-1-i] for i in range(n)) != magic_sum:\n return False\n \n return True", "matching_cluster_idx": 13}, {"solution": "def magic_square_test(square):\n n = len(square)\n if n == 0 or any(len(row) != n for row in square):\n return False # Not a square matrix or empty\n\n # Calculate the sum of the first row to use as a reference\n magic_sum = sum(square[0])\n\n # Check sums of rows\n for row in square:\n if sum(row) != magic_sum:\n return False\n\n # Check sums of columns\n for col in range(n):\n if sum(square[row][col] for row in range(n)) != magic_sum:\n return False\n\n # Check sum of the main diagonal\n if sum(square[i][i] for i in range(n)) != magic_sum:\n return False\n\n # Check sum of the secondary diagonal\n if sum(square[i][n - 1 - i] for i in range(n)) != magic_sum:\n return False\n\n return True", "matching_cluster_idx": 13}, {"solution": "def magic_square_test(matrix):\n # Check if the matrix is a magic square\n n = len(matrix)\n if any(len(row) != n for row in matrix):\n return False # Matrix is not square\n \n # Calculate the sum of the first row to use as a reference\n magic_sum = sum(matrix[0])\n \n # Check the sum of each row\n for row in matrix:\n if sum(row) != magic_sum:\n return False\n \n # Check the sum of each column\n for col in range(n):\n if sum(matrix[row][col] for row in range(n)) != magic_sum:\n return False\n \n # Check the sum of the main diagonal\n if sum(matrix[i][i] for i in range(n)) != magic_sum:\n return False\n \n # Check the sum of the secondary diagonal\n if sum(matrix[i][n - 1 - i] for i in range(n)) != magic_sum:\n return False\n \n return True", "matching_cluster_idx": 13}, {"solution": "def magic_square_test(square):\n n = len(square)\n \n # Calculate the sum of the first row to use as a reference\n magic_sum = sum(square[0])\n \n # Check the sums of all rows\n for row in square:\n if sum(row) != magic_sum:\n return False\n \n # Check the sums of all columns\n for col in range(n):\n if sum(square[row][col] for row in range(n)) != magic_sum:\n return False\n \n # Check the sum of the main diagonal\n if sum(square[i][i] for i in range(n)) != magic_sum:\n return False\n \n # Check the sum of the secondary diagonal\n if sum(square[i][n - 1 - i] for i in range(n)) != magic_sum:\n return False\n \n return True", "matching_cluster_idx": 14}, {"solution": "def is_magic_square(square):\n n = len(square)\n if n == 0:\n return False\n magic_sum = sum(square[0]) # Calculate the sum of the first row\n \n # Check rows and columns\n for i in range(n):\n if sum(square[i]) != magic_sum or sum(row[i] for row in square) != magic_sum:\n return False\n \n # Check diagonals\n if sum(square[i][i] for i in range(n)) != magic_sum or sum(square[i][n-1-i] for i in range(n)) != magic_sum:\n return False\n \n return True\ndef magic_square_test(test_square):\n return is_magic_square(test_square)", "matching_cluster_idx": 13}, {"solution": "def magic_square_test(matrix):\n n = len(matrix)\n # Check if the sum of the first row is the magic constant\n magic_constant = sum(matrix[0])\n \n # Check the sum of each row\n for row in matrix:\n if sum(row) != magic_constant:\n return False\n \n # Check the sum of each column\n for col in range(n):\n if sum(matrix[row][col] for row in range(n)) != magic_constant:\n return False\n \n # Check the sum of the main diagonal\n if sum(matrix[i][i] for i in range(n)) != magic_constant:\n return False\n \n # Check the sum of the secondary diagonal\n if sum(matrix[i][n - 1 - i] for i in range(n)) != magic_constant:\n return False\n \n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n # Calculate the sum of the first row to establish the target sum\n target_sum = sum(matrix[0])\n \n # Check row sums\n for row in matrix:\n if sum(row) != target_sum:\n return False\n \n # Check column sums\n for col in range(len(matrix)):\n if sum(matrix[row][col] for row in range(len(matrix))) != target_sum:\n return False\n \n # Check diagonal sums\n if sum(matrix[i][i] for i in range(len(matrix))) != target_sum:\n return False\n if sum(matrix[i][len(matrix) - 1 - i] for i in range(len(matrix))) != target_sum:\n return False\n \n return True", "matching_cluster_idx": 14}, {"solution": "def is_magic_square(matrix):\n n = len(matrix)\n # Check if all rows have the same length\n for row in matrix:\n if len(row) != n:\n return False\n \n # Calculate the sum of the first row to compare with other rows, columns, and diagonals\n magic_sum = sum(matrix[0])\n \n # Check the sum of each row\n for row in matrix:\n if sum(row) != magic_sum:\n return False\n \n # Check the sum of each column\n for col in range(n):\n if sum(matrix[row][col] for row in range(n)) != magic_sum:\n return False\n \n # Check the sum of the main diagonal\n if sum(matrix[i][i] for i in range(n)) != magic_sum:\n return False\n \n # Check the sum of the secondary diagonal\n if sum(matrix[i][n-1-i] for i in range(n)) != magic_sum:\n return False\n \n return True\ndef magic_square_test(matrix):\n return is_magic_square(matrix)", "matching_cluster_idx": 13}, {"solution": "def magic_square_test(matrix):\n # Calculate the sum of the first row to establish what the magic constant should be\n magic_constant = sum(matrix[0])\n \n # Check rows and columns\n for i in range(len(matrix)):\n if sum(matrix[i]) != magic_constant or sum(matrix[j][i] for j in range(len(matrix))) != magic_constant:\n return False\n \n # Check diagonals\n if sum(matrix[i][i] for i in range(len(matrix))) != magic_constant or sum(matrix[i][len(matrix) - i - 1] for i in range(len(matrix))) != magic_constant:\n return False\n \n # If all checks pass\n return True", "matching_cluster_idx": 13}, {"solution": "def magic_square_test(matrix):\n # Calculate the sum of the first row to use as a reference\n magic_sum = sum(matrix[0])\n \n # Check the sum of all rows\n for row in matrix:\n if sum(row) != magic_sum:\n return False\n \n # Check the sum of all columns\n for col in range(len(matrix[0])):\n if sum(matrix[row][col] for row in range(len(matrix))) != magic_sum:\n return False\n \n # Check the sum of the main diagonal\n if sum(matrix[i][i] for i in range(len(matrix))) != magic_sum:\n return False\n \n # Check the sum of the secondary diagonal\n if sum(matrix[i][len(matrix) - 1 - i] for i in range(len(matrix))) != magic_sum:\n return False\n \n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(square):\n n = len(square)\n # Calculate the sum of the first row to set as target\n magic_sum = sum(square[0])\n \n # Check the sum of each row\n for row in square:\n if sum(row) != magic_sum:\n return False\n \n # Check the sum of each column\n for col in range(n):\n if sum(square[row][col] for row in range(n)) != magic_sum:\n return False\n \n # Check the sum of the main diagonal\n if sum(square[i][i] for i in range(n)) != magic_sum:\n return False\n \n # Check the sum of the secondary diagonal\n if sum(square[i][n - 1 - i] for i in range(n)) != magic_sum:\n return False\n \n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n # Check if the matrix is square\n n = len(matrix)\n if any(len(row) != n for row in matrix):\n return False\n \n # Calculate the magic sum using the first row\n magic_sum = sum(matrix[0])\n \n # Check rows and columns\n for i in range(n):\n if sum(matrix[i]) != magic_sum or sum(matrix[j][i] for j in range(n)) != magic_sum:\n return False\n \n # Check diagonals\n if sum(matrix[i][i] for i in range(n)) != magic_sum or sum(matrix[i][n-1-i] for i in range(n)) != magic_sum:\n return False\n \n return True", "matching_cluster_idx": 13}, {"solution": "def magic_square_test(square):\n n = len(square)\n # Calculate the sum of the first row to set as target\n target_sum = sum(square[0])\n \n # Check the sum of all rows\n for row in square:\n if sum(row) != target_sum:\n return False\n \n # Check the sum of all columns\n for col in range(n):\n if sum(square[row][col] for row in range(n)) != target_sum:\n return False\n \n # Check the sum of the main diagonal\n if sum(square[i][i] for i in range(n)) != target_sum:\n return False\n \n # Check the sum of the secondary diagonal\n if sum(square[i][n - 1 - i] for i in range(n)) != target_sum:\n return False\n \n # All checks passed\n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(square):\n # Helper function to calculate the sum of each row\n def sum_row(matrix, row_index):\n return sum(matrix[row_index])\n \n # Helper function to calculate the sum of each column\n def sum_col(matrix, col_index):\n return sum(matrix[row][col_index] for row in range(len(matrix)))\n \n # Helper function to calculate the sum of the main diagonal\n def sum_main_diagonal(matrix):\n return sum(matrix[i][i] for i in range(len(matrix)))\n \n # Helper function to calculate the sum of the secondary diagonal\n def sum_secondary_diagonal(matrix):\n return sum(matrix[i][len(matrix) - 1 - i] for i in range(len(matrix)))\n \n # Calculate the sum of the first row to use as a reference\n reference_sum = sum_row(square, 0)\n \n # Check the sum of each row\n for row in square:\n if sum_row(square, square.index(row)) != reference_sum:\n return False\n \n # Check the sum of each column\n for col in range(len(square)):\n if sum_col(square, col) != reference_sum:\n return False\n \n # Check the sum of the main diagonal\n if sum_main_diagonal(square) != reference_sum:\n return False\n \n # Check the sum of the secondary diagonal\n if sum_secondary_diagonal(square) != reference_sum:\n return False\n \n # If all sums match, it is a magic square\n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(square):\n n = len(square)\n if n == 0 or any(len(row) != n for row in square):\n return False # Not a square matrix\n \n # Calculate the sum of the first row to use as a reference\n magic_sum = sum(square[0])\n \n # Check row sums\n for row in square:\n if sum(row) != magic_sum:\n return False\n \n # Check column sums\n for col in range(n):\n if sum(square[row][col] for row in range(n)) != magic_sum:\n return False\n \n # Check diagonal sums\n if sum(square[i][i] for i in range(n)) != magic_sum:\n return False\n if sum(square[i][n-1-i] for i in range(n)) != magic_sum:\n return False\n \n return True", "matching_cluster_idx": 13}, {"solution": "def is_magic_square(matrix):\n n = len(matrix)\n if any(len(row) != n for row in matrix):\n return False # Ensure all rows are of the same length\n \n # Calculate the sum of the first row to use as a reference\n magic_sum = sum(matrix[0])\n \n # Check row sums\n if any(sum(row) != magic_sum for row in matrix):\n return False\n \n # Check column sums\n if any(sum(matrix[row][col] for row in range(n)) != magic_sum for col in range(n)):\n return False\n \n # Check diagonal sums\n if sum(matrix[i][i] for i in range(n)) != magic_sum or \\\n sum(matrix[i][n-1-i] for i in range(n)) != magic_sum:\n return False\n \n return True\ndef magic_square_test(matrix):\n return is_magic_square(matrix)", "matching_cluster_idx": 13}, {"solution": "def calculate_sum(matrix, n):\n # Calculate the sum of the first row to use as a reference\n magic_sum = sum(matrix[0])\n \n # Check the sum of each row\n for row in matrix:\n if sum(row) != magic_sum:\n return False\n \n # Check the sum of each column\n for col in range(n):\n if sum(matrix[row][col] for row in range(n)) != magic_sum:\n return False\n \n # Check the sum of the main diagonal\n if sum(matrix[i][i] for i in range(n)) != magic_sum:\n return False\n \n # Check the sum of the secondary diagonal\n if sum(matrix[i][n - 1 - i] for i in range(n)) != magic_sum:\n return False\n \n return True\ndef magic_square_test(matrix):\n n = len(matrix)\n if n == 0 or any(len(row) != n for row in matrix):\n return False # Matrix must be square and non-empty\n \n return calculate_sum(matrix, n)", "matching_cluster_idx": 13}, {"solution": "def magic_square_test(square):\n n = len(square)\n # Calculate the magic sum using the first row\n magic_sum = sum(square[0])\n \n # Check if all rows have the same sum\n for row in square:\n if sum(row) != magic_sum:\n return False\n \n # Check if all columns have the same sum\n for col in range(n):\n if sum(square[row][col] for row in range(n)) != magic_sum:\n return False\n \n # Check if the main diagonal has the magic sum\n if sum(square[i][i] for i in range(n)) != magic_sum:\n return False\n \n # Check if the secondary diagonal has the magic sum\n if sum(square[i][n - 1 - i] for i in range(n)) != magic_sum:\n return False\n \n return True", "matching_cluster_idx": 14}, {"solution": "def is_magic_square(matrix):\n n = len(matrix)\n if any(len(row) != n for row in matrix):\n return False # Not a square matrix\n \n # Calculate the sum of the first row to use as a reference\n magic_sum = sum(matrix[0])\n \n # Check the sums of all rows\n if any(sum(row) != magic_sum for row in matrix):\n return False\n \n # Check the sums of all columns\n if any(sum(matrix[row_idx][col_idx] for row_idx in range(n)) != magic_sum for col_idx in range(n)):\n return False\n \n # Check the sum of the main diagonal\n if sum(matrix[i][i] for i in range(n)) != magic_sum:\n return False\n \n # Check the sum of the secondary diagonal\n if sum(matrix[i][n - 1 - i] for i in range(n)) != magic_sum:\n return False\n \n return True\ndef magic_square_test(matrix):\n return is_magic_square(matrix)", "matching_cluster_idx": 13}]}, "Mbpp/130": {"dps": 94.2152466367713, "dps_norm": 80.0, "pass@1": 100.0, "profiled": [{"solution": "from collections import Counter\ndef max_occurrences(lst):\n # Count the frequency of each element in the list\n frequency_counter = Counter(lst)\n \n # Find the element with the maximum frequency\n max_occurrence = frequency_counter.most_common(1)[0][0]\n \n return max_occurrence", "matching_cluster_idx": 4}, {"solution": "from collections import Counter\ndef max_occurrences(lst):\n # Count the frequency of each item in the list\n frequency_counter = Counter(lst)\n \n # Find the item with the maximum frequency\n max_item = max(frequency_counter, key=frequency_counter.get)\n \n return max_item", "matching_cluster_idx": 4}, {"solution": "from collections import Counter\ndef max_occurrences(lst):\n # Count the frequency of each element in the list\n freq_counter = Counter(lst)\n \n # Find the item with the maximum frequency\n max_freq_item = max(freq_counter, key=freq_counter.get)\n \n return max_freq_item", "matching_cluster_idx": 4}, {"solution": "from collections import Counter\ndef max_occurrences(lst):\n # Count the frequency of each item in the list\n freq_counter = Counter(lst)\n # Find the item with the maximum frequency\n max_freq_item = freq_counter.most_common(1)[0][0]\n return max_freq_item", "matching_cluster_idx": 4}, {"solution": "from collections import Counter\ndef max_occurrences(lst):\n # Count the frequency of each item in the list\n freq_counter = Counter(lst)\n \n # Find the item with the maximum frequency\n max_freq_item = max(freq_counter, key=freq_counter.get)\n \n return max_freq_item", "matching_cluster_idx": 4}, {"solution": "from collections import Counter\ndef max_occurrences(lst):\n # Count the frequency of each element in the list\n freq_map = Counter(lst)\n # Find the item with the maximum frequency\n max_freq_item = max(freq_map.items(), key=lambda x: x[1])[0]\n return max_freq_item", "matching_cluster_idx": 3}, {"solution": "from collections import Counter\ndef max_occurrences(lst):\n # Count the frequency of each item in the list\n freq_counter = Counter(lst)\n \n # Find the item with the maximum frequency\n max_freq_item = freq_counter.most_common(1)[0][0]\n \n return max_freq_item", "matching_cluster_idx": 4}, {"solution": "def max_occurrences(lst):\n # Importing collections for using Counter\n from collections import Counter\n \n # Using Counter to get frequency of each item in the list\n freq_counter = Counter(lst)\n \n # Finding the item with the maximum frequency\n max_freq_item = freq_counter.most_common(1)[0][0]\n \n return max_freq_item", "matching_cluster_idx": 3}, {"solution": "from collections import Counter\ndef max_occurrences(lst):\n # Count the frequency of each item in the list\n freq_counter = Counter(lst)\n \n # Find the item with the maximum frequency\n max_item = max(freq_counter.items(), key=lambda x: x[1])[0]\n \n return max_item", "matching_cluster_idx": 3}, {"solution": "from collections import Counter\ndef max_occurrences(lst):\n # Count the frequency of each element in the list\n freq_counter = Counter(lst)\n \n # Find the item with the maximum frequency\n max_freq_item = max(freq_counter, key=freq_counter.get)\n \n return max_freq_item", "matching_cluster_idx": 4}, {"solution": "from collections import Counter\ndef max_occurrences(lst):\n # Count the frequency of each item in the list\n freq_counter = Counter(lst)\n # Find the item with the maximum frequency\n max_item = freq_counter.most_common(1)[0][0]\n return max_item", "matching_cluster_idx": 4}, {"solution": "from collections import Counter\ndef max_occurrences(lst):\n # Count the frequency of each item in the list\n freq_counter = Counter(lst)\n # Find the item with the maximum frequency\n max_item = max(freq_counter, key=freq_counter.get)\n return max_item", "matching_cluster_idx": 4}, {"solution": "from collections import Counter\ndef max_occurrences(lst):\n # Count the frequency of each item in the list\n frequency = Counter(lst)\n # Find the item with the maximum frequency\n max_occurrence = frequency.most_common(1)[0]\n # Return the item (the most_common method returns a list of tuples, so we take the first element)\n return max_occurrence[0]", "matching_cluster_idx": 4}, {"solution": "from collections import Counter\ndef max_occurrences(lst):\n # Count the frequency of each item in the list\n freq_counter = Counter(lst)\n # Find the item with the maximum frequency\n max_freq_item = max(freq_counter, key=freq_counter.get)\n # Return the item with the maximum frequency\n return max_freq_item", "matching_cluster_idx": 4}, {"solution": "from collections import Counter\ndef max_occurrences(lst):\n # Count the frequency of each element in the list\n frequency_counter = Counter(lst)\n \n # Find the item with the maximum frequency\n max_freq_item = frequency_counter.most_common(1)[0][0]\n \n return max_freq_item", "matching_cluster_idx": 4}, {"solution": "from collections import Counter\ndef max_occurrences(lst):\n # Count the frequency of each item in the list\n freq_counter = Counter(lst)\n # Find the item with the maximum frequency\n max_freq_item = max(freq_counter, key=freq_counter.get)\n return max_freq_item", "matching_cluster_idx": 4}, {"solution": "from collections import Counter\ndef max_occurrences(lst):\n # Count the occurrences of each item in the list\n counts = Counter(lst)\n \n # Find the item with the maximum frequency\n max_item = max(counts, key=counts.get)\n \n return max_item", "matching_cluster_idx": 4}, {"solution": "from collections import Counter\ndef max_occurrences(lst):\n # Count the frequency of each item in the list\n frequency_counter = Counter(lst)\n \n # Find the item with the maximum frequency\n max_frequency_item = frequency_counter.most_common(1)\n \n # Return the item (most_common returns a list of tuples, so we take the first element)\n return max_frequency_item[0][0]", "matching_cluster_idx": 4}, {"solution": "from collections import defaultdict\ndef max_occurrences(lst):\n # Create a dictionary to count occurrences of each item\n frequency_dict = defaultdict(int)\n for item in lst:\n frequency_dict[item] += 1\n \n # Find the item with maximum frequency\n max_occurrence = max(frequency_dict.items(), key=lambda x: x[1])\n \n # Return the item with the highest frequency\n return max_occurrence[0]", "matching_cluster_idx": 3}, {"solution": "from collections import Counter\ndef max_occurrences(lst):\n # Count the frequency of each item in the list\n frequency_counter = Counter(lst)\n \n # Find the item with the maximum frequency\n max_freq_item = frequency_counter.most_common(1)[0][0]\n \n return max_freq_item", "matching_cluster_idx": 4}]}, "Mbpp/137": {"dps": null, "dps_norm": null, "pass@1": 2.0, "profiled": []}, "Mbpp/140": {"dps": 89.37888198757764, "dps_norm": 85.0, "pass@1": 100.0, "profiled": [{"solution": "def extract_singly(list_of_lists):\n # Use a set comprehension to flatten and eliminate duplicates\n return {item for sublist in list_of_lists for item in sublist}", "matching_cluster_idx": 5}, {"solution": "def extract_singly(nested_list):\n # Use a set to store unique elements\n unique_elements = set()\n \n # Iterate through each sublist in the nested list\n for sublist in nested_list:\n # Add elements of the sublist to the set\n unique_elements.update(sublist)\n \n return unique_elements", "matching_cluster_idx": 7}, {"solution": "def extract_singly(nested_lists):\n # Use a set to store the unique numbers\n unique_numbers = set()\n \n # Iterate through each sublist in the nested list\n for sublist in nested_lists:\n # Update the set with the elements from the current sublist\n unique_numbers.update(sublist)\n \n return unique_numbers", "matching_cluster_idx": 7}, {"solution": "def extract_singly(list_of_lists):\n # Use set comprehension to flatten the list of lists and create a set of unique numbers\n return {number for sublist in list_of_lists for number in sublist}", "matching_cluster_idx": 5}, {"solution": "def extract_singly(lists):\n # Flatten the list of lists into a single list\n flat_list = [item for sublist in lists for item in sublist]\n # Convert the list to a set to get unique elements\n unique_set = set(flat_list)\n return unique_set", "matching_cluster_idx": 5}, {"solution": "def extract_singly(list_of_lists):\n # Use a set to collect unique elements from the list of lists\n result_set = set()\n \n # Iterate through each sublist in the main list\n for sublist in list_of_lists:\n # Add each element in the sublist to the result set\n result_set.update(sublist)\n \n return result_set", "matching_cluster_idx": 7}, {"solution": "def extract_singly(list_of_lists):\n # Use a set to store unique elements from the nested lists\n unique_elements = set()\n for sublist in list_of_lists:\n unique_elements.update(sublist)\n return unique_elements", "matching_cluster_idx": 7}, {"solution": "def extract_singly(lists):\n # Use set comprehension to flatten the list of lists into a single set\n return {item for sublist in lists for item in sublist}", "matching_cluster_idx": 5}, {"solution": "def extract_singly(list_of_lists):\n # Use a set to store the flattened list of numbers without duplicates\n flattened_set = set()\n \n # Iterate through each list in the list of lists\n for sublist in list_of_lists:\n # Update the set with the numbers from the current sublist\n flattened_set.update(sublist)\n \n return flattened_set", "matching_cluster_idx": 7}, {"solution": "def extract_singly(list_of_lists):\n # Use set comprehension to flatten and remove duplicates\n return {element for sublist in list_of_lists for element in sublist}", "matching_cluster_idx": 5}, {"solution": "def extract_singly(list_of_lists):\n # Use set to automatically remove duplicates and flatten the list\n return set(number for sublist in list_of_lists for number in sublist)", "matching_cluster_idx": 5}, {"solution": "def extract_singly(lists):\n # Use a set comprehension to flatten and eliminate duplicates\n return {num for sublist in lists for num in sublist}", "matching_cluster_idx": 5}, {"solution": "def extract_singly(nested_lists):\n # Use set comprehension to flatten and remove duplicates\n return {element for sublist in nested_lists for element in sublist}", "matching_cluster_idx": 5}, {"solution": "def extract_singly(nested_lists):\n # Use a set to store unique elements from all sublists\n flattened_set = set()\n \n # Iterate through each sublist in the nested list\n for sublist in nested_lists:\n # Update the set with elements from the current sublist\n flattened_set.update(sublist)\n \n return flattened_set", "matching_cluster_idx": 7}, {"solution": "def extract_singly(list_of_lists):\n # Use set comprehension to flatten and remove duplicates from the list of lists\n return {element for sublist in list_of_lists for element in sublist}", "matching_cluster_idx": 5}, {"solution": "def extract_singly(nested_list):\n # Use a set to store unique numbers\n unique_numbers = set()\n \n # Iterate through each sublist in the nested list\n for sublist in nested_list:\n # Add each element in the sublist to the set\n unique_numbers.update(sublist)\n \n # Return the set of unique numbers\n return unique_numbers", "matching_cluster_idx": 7}, {"solution": "def extract_singly(nested_lists):\n # Use set comprehension to flatten and convert all elements to a single set\n flattened_set = {element for sublist in nested_lists for element in sublist}\n return flattened_set", "matching_cluster_idx": 5}, {"solution": "def extract_singly(lists):\n # Use set comprehension to flatten the list of lists into a single set of numbers\n return {element for sublist in lists for element in sublist}", "matching_cluster_idx": 5}, {"solution": "def extract_singly(list_of_lists):\n # Use a set to store unique numbers from the list of lists\n unique_numbers = set()\n for sublist in list_of_lists:\n unique_numbers.update(sublist)\n return unique_numbers", "matching_cluster_idx": 7}, {"solution": "def extract_singly(list_of_lists):\n # Use a set comprehension to flatten and remove duplicates from the list of lists\n return {element for sublist in list_of_lists for element in sublist}", "matching_cluster_idx": 5}]}, "Mbpp/141": {"dps": 82.38095238095238, "dps_norm": 45.625, "pass@1": 90.0, "profiled": [{"solution": "def pancake_sort(arr):\n # Length of the array\n n = len(arr)\n \n # Traverse through all array elements\n for i in range(n, 1, -1):\n # Find index of the maximum element in arr[0:i]\n max_pos = arr.index(max(arr[:i]), 0, i)\n \n # Move the maximum element to end of the current array segment\n if max_pos != i - 1:\n # Reverse the array from start to max_pos\n arr[:max_pos+1] = arr[:max_pos+1][::-1]\n # Reverse the array from start to i-1\n arr[:i] = arr[:i][::-1]\n \n return arr", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(arr):\n # Perform the pancake sort\n def flip(sub_arr, k):\n return sub_arr[:k][::-1] + sub_arr[k:]\n \n def find_max_index(sub_arr):\n return max(range(len(sub_arr)), key=sub_arr.__getitem__)\n \n n = len(arr)\n for i in range(n, 1, -1):\n # Find the index of the maximum element in arr[0:i]\n max_index = find_max_index(arr[:i])\n \n # Flip it to the front if it's not already at the front\n if max_index != i - 1:\n # Flip the max to the beginning\n arr = flip(arr, max_index + 1)\n # Flip it to its position\n arr = flip(arr, i)\n \n return arr", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(arr):\n # Get the length of the array\n n = len(arr)\n \n # Traverse through all array elements\n for i in range(n, 0, -1):\n # Find the index of the maximum element in arr[0:i]\n max_index = arr.index(max(arr[:i]))\n \n # Swap the found maximum element with the current element at index i-1\n if max_index != i-1:\n # First flip to move the maximum number to the beginning\n arr[:max_index+1] = reversed(arr[:max_index+1])\n # Second flip to move the maximum number to its correct position\n arr[:i] = reversed(arr[:i])\n \n return arr", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(arr):\n def flip(sub_arr, k):\n # Flip the first k elements of sub_arr\n sub_arr[:k] = sub_arr[:k][::-1]\n \n n = len(arr)\n for i in range(n, 1, -1):\n # Find the index of the maximum element in arr[0:i]\n max_index = arr.index(max(arr[0:i]))\n \n # Bring the maximum element to the front if it's not already there\n if max_index != 0:\n flip(arr, max_index + 1)\n \n # Now bring this max element to its correct position\n flip(arr, i)\n \n return arr", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(arr):\n n = len(arr)\n # Traverse through all array elements\n for i in range(n-1, 0, -1):\n # Find the maximum element in the unsorted array\n max_idx = arr.index(max(arr[0:i+1]))\n # Swap the found maximum element with the first element\n arr[0:max_idx+1] = reversed(arr[0:max_idx+1])\n arr[0:i+1] = reversed(arr[0:i+1])\n return arr", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(arr):\n # Get the length of the array\n n = len(arr)\n \n def flip(sub_arr, k):\n # Perform the flip operation on the first k elements of sub_arr\n return sub_arr[:k][::-1] + sub_arr[k:]\n \n def find_max_index(sub_arr):\n # Find the index of the maximum element in sub_arr\n return max(range(len(sub_arr)), key=sub_arr.__getitem__)\n \n for i in range(n, 1, -1):\n max_index = find_max_index(arr[:i])\n if max_index + 1 != i:\n # Flip the max index to the current position\n arr = flip(arr, max_index + 1)\n # Flip the current position to its final position\n arr = flip(arr, i)\n \n return arr", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(arr):\n def flip(sub_arr, k):\n sub_arr[:k] = sub_arr[:k][::-1]\n \n n = len(arr)\n for curr_size in range(n, 1, -1):\n # Find the index of the maximum element in arr[0..curr_size-1]\n max_idx = arr.index(max(arr[:curr_size]))\n \n # Move the maximum element to end of the current array\n if max_idx != curr_size - 1:\n # Flip the array from start to max element\n flip(arr, max_idx + 1)\n # Flip the array from start to current end\n flip(arr, curr_size)\n \n return arr", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(arr):\n def flip(sub_arr, k):\n \"\"\"Helper function to flip the first k elements of sub_arr in-place.\"\"\"\n for i in range(k // 2):\n sub_arr[i], sub_arr[k - i - 1] = sub_arr[k - i - 1], sub_arr[i]\n \n n = len(arr)\n for curr_size in range(n, 1, -1):\n # Find the index of the maximum element in arr[0..curr_size-1]\n max_idx = arr.index(max(arr[:curr_size]))\n \n # Move the maximum element to the end of the current sub-array\n if max_idx != curr_size - 1:\n # Flip the array from 0 to max_idx\n flip(arr, max_idx + 1)\n # Flip the array from 0 to curr_size (move max to end of current sub-array)\n flip(arr, curr_size)\n \n return arr", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(arr):\n # Function to reverse the first k elements of the array\n def flip(sub_arr, k):\n start = 0\n while start < k:\n temp = sub_arr[start]\n sub_arr[start] = sub_arr[k]\n sub_arr[k] = temp\n start += 1\n k -= 1\n\n # Main function to perform pancake sort\n def sort_pancakes(arr):\n cur = len(arr)\n while cur > 1:\n # Find the index of the maximum element in arr[0..cur-1]\n max_pos = arr.index(max(arr[0:cur]))\n # Move the maximum element to end of current array if it's not already at the position\n if max_pos != cur - 1:\n # Flip the array from 0 to max_pos, so that the maximum element goes to the front\n flip(arr, max_pos)\n # Flip the array from 0 to cur-1, so that the maximum element goes to its final position\n flip(arr, cur - 1)\n # Reduce the current size by one\n cur -= 1\n return arr\n\n return sort_pancakes(arr)", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(arr):\n # Get the length of the array\n n = len(arr)\n \n # Traverse through all array elements\n for i in range(n, 1, -1):\n # Find index of the maximum element in arr[0..i-1]\n max_index = arr.index(max(arr[:i]), 0, i)\n \n # Swap the found maximum element with the current element at position i-1\n arr[:max_index+1] = reversed(arr[:max_index+1])\n arr[:i] = reversed(arr[:i])\n \n return arr", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(arr):\n # Perform pancake sort\n def flip(sub_arr, k):\n sub_arr[:k] = sub_arr[:k][::-1]\n \n n = len(arr)\n for i in range(n, 1, -1):\n # Find the index of the maximum element in arr[0:i]\n max_index = arr.index(max(arr[:i]))\n # Bring the maximum element to the beginning\n if max_index != 0:\n flip(arr, max_index + 1)\n # Bring the maximum element to its correct position\n flip(arr, i)\n return arr", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(arr):\n n = len(arr)\n for i in range(n - 1, 0, -1):\n # Find index of the maximum element in arr[0:i+1]\n max_index = i\n for j in range(i):\n if arr[j] > arr[max_index]:\n max_index = j\n # Swap the maximum element with the last element of the unsorted portion\n if max_index != i:\n arr[:max_index + 1] = reversed(arr[:max_index + 1])\n arr[:i + 1] = reversed(arr[:i + 1])\n return arr", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(arr):\n def flip(sub_arr, k):\n \"\"\"Helper function to flip the first k elements of the sub_arr.\"\"\"\n sub_arr[:k] = sub_arr[:k][::-1]\n \n def find_max_index(sub_arr, n):\n \"\"\"Helper function to find the index of the maximum element in the first n elements.\"\"\"\n max_val = sub_arr[0]\n max_index = 0\n for i in range(1, n):\n if sub_arr[i] > max_val:\n max_val = sub_arr[i]\n max_index = i\n return max_index\n \n n = len(arr)\n for curr_size in range(n, 1, -1):\n # Find the index of the maximum element in arr[0..curr_size-1]\n max_index = find_max_index(arr, curr_size)\n \n # Move the maximum element to the end of the current subarray\n if max_index != curr_size - 1:\n # First flip the maximum element at max_index to the start\n flip(arr, max_index + 1)\n # Then flip it to its correct position in the current subarray\n flip(arr, curr_size)\n \n return arr", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(arr):\n # Iterate through the list\n for cur_size in range(len(arr), 1, -1):\n # Find the maximum element in the unsorted part\n max_ind = arr.index(max(arr[0:cur_size]))\n \n # Move the maximum element to the current size position\n if max_ind + 1 != cur_size:\n # First flip to move the maximum to the front\n arr[:max_ind + 1] = reversed(arr[:max_ind + 1])\n # Second flip to move it to its final position\n arr[:cur_size] = reversed(arr[:cur_size])\n \n return arr", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(arr):\n def flip(sub_arr, k):\n \"\"\"Helper function to flip the first k elements of the list.\"\"\"\n sub_arr[:k] = sub_arr[:k][::-1]\n \n n = len(arr)\n for curr_size in range(n, 1, -1):\n # Find the index of the maximum element in arr[0..curr_size-1]\n max_idx = arr.index(max(arr[0:curr_size]))\n \n # Move the maximum element to the end of the current subarray\n if max_idx != curr_size - 1:\n # Flip the array from the start to the position of the max element\n flip(arr, max_idx + 1)\n # Flip the array from the start to the current subarray end\n flip(arr, curr_size)\n \n return arr", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(arr):\n def flip(sublist, k):\n # Perform the flip operation on the sublist\n return sublist[:k][::-1] + sublist[k:]\n \n def find_max_index(sublist):\n # Find the index of the maximum element in the sublist\n return sublist.index(max(sublist))\n \n n = len(arr)\n for i in range(n, 1, -1):\n max_index = find_max_index(arr[:i])\n if max_index + 1 != i:\n # Flip the max element to the front if it's not already in place\n arr = flip(arr, max_index + 1)\n # Flip it into its final position\n arr = flip(arr, i)\n \n return arr", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(arr):\n # Function to reverse the first k elements of the input array\n def flip(sub_arr, k):\n sub_arr[:k] = sub_arr[:k][::-1]\n \n n = len(arr)\n for i in range(n, 0, -1):\n # Find the index of the maximum element in arr[0:i]\n max_idx = arr.index(max(arr[:i]))\n \n # Bring the maximum element to the front if it's not already there\n if max_idx != 0:\n flip(arr, max_idx + 1)\n \n # Now bring this max element to its correct position\n flip(arr, i)\n \n return arr", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(arr):\n # Function to reverse the order of the first k elements in the list\n def flip(sub_arr, k):\n sub_arr[:k] = reversed(sub_arr[:k])\n \n n = len(arr)\n for curr_size in range(n, 1, -1):\n # Find the index of the maximum element in arr[0..curr_size-1]\n max_idx = arr.index(max(arr[0:curr_size]))\n \n # Move the maximum element to the end of the current subarray\n if max_idx != curr_size - 1:\n # Flip the list to move the maximum element to the front\n flip(arr, max_idx + 1)\n # Flip the list to move the maximum element to its final position\n flip(arr, curr_size)\n \n return arr", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(arr):\n def flip(sub_arr, k):\n sub_arr[:k] = sub_arr[:k][::-1]\n \n def find_max_index(sub_arr, n):\n max_index = 0\n for i in range(1, n):\n if sub_arr[i] > sub_arr[max_index]:\n max_index = i\n return max_index\n \n sorted_arr = arr.copy()\n for i in range(len(sorted_arr), 1, -1):\n max_index = find_max_index(sorted_arr, i)\n if max_index != i - 1:\n # Bring the maximum element to the front\n flip(sorted_arr, max_index + 1)\n # Bring the maximum element to its correct position\n flip(sorted_arr, i)\n return sorted_arr", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(arr):\n # Iterate through the list from the largest element to the smallest\n for curr_size in range(len(arr), 1, -1):\n # Find the index of the maximum element in arr[0..curr_size-1]\n max_idx = arr.index(max(arr[0:curr_size]))\n \n # Move the maximum element to the end of the current subarray\n arr[:max_idx+1] = reversed(arr[:max_idx+1])\n arr[:curr_size] = reversed(arr[:curr_size])\n \n return arr", "matching_cluster_idx": 3}]}, "Mbpp/166": {"dps": 94.39999999999999, "dps_norm": 50.0, "pass@1": 98.0, "profiled": [{"solution": "def find_even_pair(arr):\n even_count = 0\n for i in range(len(arr)):\n for j in range(i + 1, len(arr)):\n if (arr[i] ^ arr[j]) % 2 == 0:\n even_count += 1\n return even_count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(lst):\n even_count = 0\n for i in range(len(lst)):\n for j in range(i + 1, len(lst)):\n if (lst[i] ^ lst[j]) % 2 == 0:\n even_count += 1\n return even_count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(lst):\n even_count = 0\n for i in range(len(lst)):\n for j in range(i + 1, len(lst)):\n if (lst[i] ^ lst[j]) % 2 == 0:\n even_count += 1\n return even_count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(arr):\n even_count = 0\n for i in range(len(arr)):\n for j in range(i + 1, len(arr)):\n if (arr[i] ^ arr[j]) % 2 == 0:\n even_count += 1\n return even_count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(lst):\n count = 0\n # Iterate through the list to find pairs\n for i in range(len(lst)):\n for j in range(i + 1, len(lst)):\n # Check if the XOR of the pair is even\n if (lst[i] ^ lst[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(arr):\n count = 0\n n = len(arr)\n for i in range(n):\n for j in range(i + 1, n):\n if (arr[i] ^ arr[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(arr):\n # Initialize the count of even pairs\n even_pairs_count = 0\n \n # Iterate through the array\n for i in range(len(arr)):\n for j in range(i + 1, len(arr)):\n # Check if the XOR of the pair is even\n if (arr[i] ^ arr[j]) % 2 == 0:\n even_pairs_count += 1\n \n return even_pairs_count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(arr):\n count = 0\n for i in range(len(arr)):\n for j in range(i + 1, len(arr)):\n if (arr[i] ^ arr[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(lst):\n # Initialize count of pairs\n even_pairs_count = 0\n \n # Iterate through all pairs in the list\n for i in range(len(lst)):\n for j in range(i + 1, len(lst)):\n # Check if XOR of the pair is even\n if (lst[i] ^ lst[j]) % 2 == 0:\n even_pairs_count += 1\n \n return even_pairs_count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(arr):\n even_count = 0\n for i in range(len(arr)):\n for j in range(i + 1, len(arr)):\n if (arr[i] ^ arr[j]) % 2 == 0:\n even_count += 1\n return even_count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(lst):\n # Count pairs that xor to an even number\n even_count = 0\n for i in range(len(lst)):\n for j in range(i + 1, len(lst)):\n if (lst[i] ^ lst[j]) % 2 == 0:\n even_count += 1\n return even_count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(nums):\n # Initialize the count of pairs that xor to an even number\n even_pairs_count = 0\n \n # Iterate through all pairs in the list\n for i in range(len(nums)):\n for j in range(i + 1, len(nums)):\n # XOR the numbers and check if the result is even\n if (nums[i] ^ nums[j]) % 2 == 0:\n even_pairs_count += 1\n \n return even_pairs_count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(lst):\n count = 0\n # Loop through the list and check each pair of integers\n for i in range(len(lst)):\n for j in range(i + 1, len(lst)):\n # Check if the XOR of the pair is even\n if (lst[i] ^ lst[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(arr):\n count = 0\n for i in range(len(arr)):\n for j in range(i + 1, len(arr)):\n if (arr[i] ^ arr[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(nums):\n even_count = 0\n for i in range(len(nums)):\n for j in range(i + 1, len(nums)):\n if (nums[i] ^ nums[j]) % 2 == 0:\n even_count += 1\n return even_count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(arr):\n count = 0\n for i in range(len(arr)):\n for j in range(i + 1, len(arr)):\n if (arr[i] ^ arr[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(nums):\n even_count = 0\n for i in range(len(nums)):\n for j in range(i + 1, len(nums)):\n if (nums[i] ^ nums[j]) % 2 == 0:\n even_count += 1\n return even_count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(arr):\n # Initialize the count of even pairs\n even_pairs_count = 0\n \n # Iterate through the array to find pairs\n for i in range(len(arr)):\n for j in range(i + 1, len(arr)):\n # XOR the pair and check if the result is even (i.e., result % 2 == 0)\n if (arr[i] ^ arr[j]) % 2 == 0:\n even_pairs_count += 1\n \n return even_pairs_count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(lst):\n count = 0\n for i in range(len(lst)):\n for j in range(i + 1, len(lst)):\n if (lst[i] ^ lst[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(arr):\n # Initialize the count of even pairs\n even_count = 0\n \n # Iterate through all pairs in the array\n for i in range(len(arr)):\n for j in range(i + 1, len(arr)):\n # XOR the pair and check if the result is even\n if (arr[i] ^ arr[j]) % 2 == 0:\n even_count += 1\n \n return even_count", "matching_cluster_idx": 1}]}, "Mbpp/170": {"dps": 96.81159420289855, "dps_norm": 99.375, "pass@1": 81.0, "profiled": [{"solution": "def sum_range_list(numbers, start_index, end_index):\n # Check if the indices are within the bounds of the list\n if 0 <= start_index <= end_index < len(numbers):\n # Use slice to get the sublist and sum it\n return sum(numbers[start_index:end_index+1])\n else:\n # Return 0 if indices are out of bounds\n return 0", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(nums, start_index, end_index):\n # Ensure the start_index is not less than 0 and end_index is not greater than the length of nums\n start_index = max(0, start_index)\n end_index = min(len(nums), end_index)\n \n # Calculate the sum of the specified range\n return sum(nums[start_index:end_index + 1])", "matching_cluster_idx": 6}, {"solution": "def sum_range_list(numbers, start_index, end_index):\n # Ensure start_index and end_index are within the bounds of the list\n if start_index < 0 or end_index >= len(numbers) or start_index > end_index:\n return 0\n \n # Calculate the sum of the specified range\n return sum(numbers[start_index:end_index + 1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(numbers, start_index, end_index):\n # Ensure the start and end indices are within the list bounds\n start_index = max(0, start_index)\n end_index = min(len(numbers) - 1, end_index)\n \n # Calculate the sum of the specified range\n return sum(numbers[start_index:end_index + 1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(numbers, start_index, end_index):\n # Ensure the start_index is not negative and end_index is within the list length\n start_index = max(start_index, 0)\n end_index = min(end_index, len(numbers))\n \n # Calculate the sum of elements from start_index to end_index (inclusive)\n return sum(numbers[start_index:end_index + 1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(numbers, start_index, end_index):\n # Ensure the start index is not less than 0 and the end index is within the list bounds\n start_index = max(0, start_index)\n end_index = min(len(numbers) - 1, end_index)\n \n # Calculate the sum of the specified range\n sum_range = sum(numbers[start_index:end_index + 1])\n return sum_range", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(nums, start, end):\n # Calculate the sum of the specified slice of the list\n return sum(nums[start:end+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(nums, start_index, end_index):\n # Check if start_index and end_index are within the bounds of the list\n if 0 <= start_index < len(nums) and 0 <= end_index < len(nums):\n # Calculate the sum of the specified range in the list\n return sum(nums[start_index:end_index + 1])\n else:\n # Return 0 if indices are out of bounds\n return 0", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(lst, start_index, end_index):\n # Ensure start_index is not less than 0 and end_index does not exceed the list length\n start_index = max(0, start_index)\n end_index = min(len(lst), end_index)\n \n # Calculate the sum of elements within the specified range\n return sum(lst[start_index:end_index+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(numbers, start_index, end_index):\n # Ensure the start index is not less than 0 and the end index is within the list bounds\n start_index = max(0, start_index)\n end_index = min(len(numbers) - 1, end_index)\n \n # Calculate the sum of the sublist from start_index to end_index\n return sum(numbers[start_index:end_index + 1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(numbers, start_index, end_index):\n # Ensure the start and end indices are within the bounds of the list\n if start_index < 0 or end_index >= len(numbers) or start_index > end_index:\n return 0\n \n # Calculate the sum of the specified range\n total_sum = sum(numbers[start_index:end_index+1])\n return total_sum", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(nums, start, end):\n # Calculate the sum of elements from index start to end (inclusive)\n return sum(nums[start:end+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(lst, start, end):\n # Ensure the start and end are within the bounds of the list\n start = max(0, start)\n end = min(len(lst), end + 1)\n \n # Calculate the sum of the specified range\n return sum(lst[start:end])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(nums, start, end):\n # Ensure start and end are within the range of the list\n if start < 0 or end >= len(nums):\n return None\n \n # Calculate the sum of the specified range\n return sum(nums[start:end+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(lst, start_index, end_index):\n # Calculate the sum of elements from start_index to end_index\n return sum(lst[start_index:end_index+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(nums, start, end):\n # Ensure the start and end indices are within the bounds of the list\n start = max(0, start)\n end = min(len(nums) - 1, end)\n \n # Calculate the sum of elements from the start index to the end index\n return sum(nums[start:end+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(numbers, start_index, end_index):\n # Ensure the indices are within the bounds of the list\n if not (0 <= start_index < len(numbers)) or not (0 <= end_index < len(numbers)):\n return None # Return None if indices are out of bounds\n \n # Calculate the sum of the specified range\n return sum(numbers[start_index:end_index + 1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(numbers, start_index, end_index):\n # Ensure the start and end indices are within the bounds of the list\n start_index = max(0, start_index)\n end_index = min(len(numbers) - 1, end_index)\n \n # Calculate the sum of the specified range\n sum_range = sum(numbers[start_index:end_index + 1])\n \n return sum_range", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(nums, start_index, end_index):\n # Ensure the start_index and end_index are within the bounds of the list\n if start_index < 0 or end_index >= len(nums):\n return \"Invalid range\"\n \n # Calculate the sum of the sublist from start_index to end_index\n result = sum(nums[start_index:end_index + 1])\n return result", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(lst, start, end):\n # Ensure the start and end indices are within the range of the list\n if start < 0 or end >= len(lst) or start > end:\n return 0\n \n # Calculate the sum of the specified range\n return sum(lst[start:end+1])", "matching_cluster_idx": 7}]}, "Mbpp/226": {"dps": 73.06201550387597, "dps_norm": 23.571428571428573, "pass@1": 100.0, "profiled": [{"solution": "def odd_values_string(input_string):\n # Initialize an empty result string\n result_string = ''\n \n # Iterate over the string, stepping by 2 to skip odd indices\n for i in range(0, len(input_string), 2):\n # Append character at even index to the result string\n result_string += input_string[i]\n \n return result_string", "matching_cluster_idx": 1}, {"solution": "def odd_values_string(input_string):\n # Initialize an empty result string\n result = ''\n \n # Loop through the string, stepping by 2 to skip every other character starting from index 0\n for i in range(0, len(input_string), 2):\n result += input_string[i]\n \n return result", "matching_cluster_idx": 2}, {"solution": "def odd_values_string(input_string):\n # Initialize an empty string to store the result\n result = ''\n \n # Iterate over the string, stepping by 2 to skip odd indices\n for i in range(0, len(input_string), 2):\n result += input_string[i]\n \n return result", "matching_cluster_idx": 2}, {"solution": "def odd_values_string(input_string):\n # Initialize an empty string to store the result\n result_string = ''\n \n # Iterate over the string using index\n for index in range(len(input_string)):\n # Check if the index is even\n if index % 2 == 0:\n # Append the character at the current index to the result string\n result_string += input_string[index]\n \n return result_string", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(input_string):\n # Initialize an empty string to store the result\n result_string = ''\n \n # Iterate over the string, stepping by 2 to skip every other character (odd index)\n for i in range(0, len(input_string), 2):\n # Append character at even index to the result string\n result_string += input_string[i]\n \n return result_string", "matching_cluster_idx": 2}, {"solution": "def odd_values_string(input_string):\n # Initialize an empty string to store the result\n result_string = ''\n \n # Iterate over the string using index\n for index in range(len(input_string)):\n # Check if the index is even\n if index % 2 == 0:\n # Append the character at the current index to the result string\n result_string += input_string[index]\n \n return result_string", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(input_string):\n # Initialize an empty string to store the characters with even indices\n result_string = ''\n \n # Iterate through the string, considering only characters at even indices\n for index in range(0, len(input_string), 2):\n result_string += input_string[index]\n \n return result_string", "matching_cluster_idx": 1}, {"solution": "def odd_values_string(input_string):\n # Initialize an empty result string\n result = ''\n # Loop through the string, considering only even indices\n for i in range(0, len(input_string)):\n # Check if the index is even (character at odd position)\n if i % 2 == 0:\n # Append the character at the current even index to the result\n result += input_string[i]\n return result", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(input_string):\n # Initialize an empty string to store the result\n result_string = ''\n \n # Iterate over the string, stepping by 2 to skip odd indices\n for i in range(0, len(input_string), 2):\n result_string += input_string[i]\n \n return result_string", "matching_cluster_idx": 1}, {"solution": "def odd_values_string(input_string):\n # Initialize an empty string to store the result\n result_string = ''\n \n # Iterate over the string using index\n for index in range(len(input_string)):\n # Check if the index is even\n if index % 2 == 0:\n # Append the character at the even index to the result string\n result_string += input_string[index]\n \n return result_string", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(input_string):\n # Initialize an empty result string\n result_string = ''\n # Iterate over the string, considering only characters at even indices (0, 2, 4, ...)\n for i in range(0, len(input_string), 2):\n result_string += input_string[i]\n return result_string", "matching_cluster_idx": 2}, {"solution": "def odd_values_string(input_string):\n # Initialize an empty result string\n result = ''\n \n # Loop through the string, considering only even indices\n for i in range(0, len(input_string)):\n if i % 2 == 0:\n result += input_string[i]\n \n return result", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(input_string):\n # Initialize an empty string for the result\n result = ''\n \n # Iterate over the string using index\n for index in range(len(input_string)):\n # Check if the index is even (not odd)\n if index % 2 == 0:\n # Append the character at the current index to the result string\n result += input_string[index]\n \n return result", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(input_string):\n # Initialize an empty result string\n result = ''\n # Iterate over the string using index\n for index in range(len(input_string)):\n # Check if the index is even\n if index % 2 == 0:\n # Append the character to the result string\n result += input_string[index]\n return result", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(input_string):\n # Initialize an empty string to hold the result\n result_string = ''\n # Loop through the string, iterating over even indices (0, 2, 4, ...)\n for i in range(0, len(input_string), 2):\n # Concatenate the character at the even index to the result_string\n result_string += input_string[i]\n return result_string", "matching_cluster_idx": 2}, {"solution": "def odd_values_string(input_string):\n # Initialize an empty string to store the result\n result_string = ''\n # Iterate through the string, considering only characters with even indices\n for index in range(len(input_string)):\n # Check if the index is even (0-based)\n if index % 2 == 0:\n result_string += input_string[index]\n return result_string", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(input_string):\n # Initialize an empty string to store the result\n result_string = ''\n \n # Iterate over the string using index\n for index in range(len(input_string)):\n # Check if the index is even (0-based)\n if index % 2 == 0:\n # Append the character at the current index to the result string\n result_string += input_string[index]\n \n return result_string", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(input_string):\n # Initialize an empty string to store the result\n result_string = ''\n # Iterate over the string using index\n for index in range(len(input_string)):\n # Check if the index is even\n if index % 2 == 0:\n # Append the character to the result string\n result_string += input_string[index]\n return result_string", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(input_string):\n # Initialize an empty result string\n result_string = ''\n # Iterate over the string using index\n for index in range(len(input_string)):\n # Check if the index is even\n if index % 2 == 0:\n # Append character at even index to the result string\n result_string += input_string[index]\n return result_string", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(input_string):\n # Initialize an empty result string\n result = ''\n # Iterate over the string, considering only characters with even indices\n for i in range(len(input_string)):\n if i % 2 == 0:\n result += input_string[i]\n return result", "matching_cluster_idx": 0}]}, "Mbpp/230": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def replace_blank(input_string, replace_char):\n # Replace blank spaces in the string with the specified character\n modified_string = input_string.replace(\" \", replace_char)\n return modified_string", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string, replacement_char):\n # Replace blank spaces in the string with the specified character\n result_string = input_string.replace(\" \", replacement_char)\n return result_string", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string, replacement_char):\n # Replace all blank spaces in the input_string with replacement_char\n return input_string.replace(\" \", replacement_char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string, replacement_char):\n # Replace all blank spaces in the input string with the replacement character\n result_string = input_string.replace(\" \", replacement_char)\n return result_string", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string, replacement_char):\n # Replace all blank spaces in the input_string with the replacement_char\n return input_string.replace(\" \", replacement_char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string, replacement_char):\n # Replace blank spaces in the string with the specified character\n result_string = input_string.replace(\" \", replacement_char)\n return result_string", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string, replacement_char):\n # Replace all blank spaces in the input_string with replacement_char\n result_string = input_string.replace(' ', replacement_char)\n return result_string", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string, replacement_char):\n # Replace all blank spaces in the input_string with the replacement_char\n result_string = input_string.replace(' ', replacement_char)\n return result_string", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string, replacement_char):\n # Replace all blank spaces in the string with the given character\n result_string = input_string.replace(\" \", replacement_char)\n return result_string", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string, replace_char):\n # Replace all blank spaces in the input string with the specified character\n result = input_string.replace(\" \", replace_char)\n return result", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string, replacement_char):\n # Replace all blank spaces in the input_string with replacement_char\n return input_string.replace(\" \", replacement_char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string, replacement_char):\n # Replace all blank spaces in the input_string with the replacement_char\n result_string = input_string.replace(\" \", replacement_char)\n return result_string", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string, replacement_char):\n # Replace all blank spaces in the input_string with replacement_char\n result_string = input_string.replace(' ', replacement_char)\n return result_string", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string, replace_char):\n # Replace all blank spaces in the input_string with the replace_char\n modified_string = input_string.replace(\" \", replace_char)\n return modified_string", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string, replacement_char):\n # Replace all blank spaces in the string with the given character\n result_string = input_string.replace(' ', replacement_char)\n return result_string", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string, replacement_char):\n # Replace all blank spaces in the input_string with replacement_char\n result_string = input_string.replace(\" \", replacement_char)\n return result_string", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string, replacement_char):\n # Replace all blank spaces in the string with the specified character\n modified_string = input_string.replace(\" \", replacement_char)\n return modified_string", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string, replacement_char):\n # Replace blank spaces in the input_string with the replacement_char\n return input_string.replace(\" \", replacement_char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string, replacement_char):\n # Replace all blank spaces in the input string with the replacement character\n result_string = input_string.replace(\" \", replacement_char)\n return result_string", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string, replacement_char):\n # Replace all blank spaces in the input string with the replacement character\n modified_string = input_string.replace(\" \", replacement_char)\n return modified_string", "matching_cluster_idx": 7}]}, "Mbpp/239": {"dps": 75.86206896551724, "dps_norm": 78.0, "pass@1": 44.0, "profiled": [{"solution": "def get_total_number_of_sequences(m, n):\n # If n is 1, then there is only one sequence possible (1 to m)\n if n == 1:\n return m\n \n # Initialize a DP table\n dp = [[0] * (n + 1) for _ in range(m + 1)]\n \n # Fill the DP table\n for i in range(1, m + 1):\n dp[i][1] = 1\n \n for length in range(2, n + 1):\n for i in range(1, m + 1):\n for prev in range(1, int(i / 2) + 1):\n dp[i][length] += dp[prev][length - 1]\n \n # Sum up all possibilities for the sequences of length n\n result = sum(dp[i][n] for i in range(1, m + 1))\n return result", "matching_cluster_idx": 6}, {"solution": "def get_total_number_of_sequences(m, n):\n # This is a dynamic programming approach\n # dp[i][j] will be the number of sequences of length i ending with number j\n dp = [[0 for _ in range(m + 1)] for _ in range(n + 1)]\n \n # Base case: There's one way to have a sequence of length 1 for any value (1 to m)\n for j in range(1, m + 1):\n dp[1][j] = 1\n \n # Fill the dp table\n for i in range(2, n + 1):\n for j in range(1, m + 1):\n # Sum the values where j >= 2 * dp[i-1][k]\n for k in range(1, (j // 2) + 1):\n dp[i][j] += dp[i - 1][k]\n \n # Sum all the ways to form a sequence of length n\n result = sum(dp[n])\n return result", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n # Base case: If n is 1, the sequence can only be any single number from 1 to m\n if n == 1:\n return m\n \n # Base case: If m is less than 2, no valid sequence can be formed\n if m < 2:\n return 0\n \n # Initialize a 2D array to store the number of sequences\n dp = [[0] * (n + 1) for _ in range(m + 1)]\n \n # Fill the dp table\n for i in range(1, m + 1):\n dp[i][1] = 1 # Base case: There is one sequence for each single number\n \n for length in range(2, n + 1):\n for max_val in range(1, m + 1):\n for prev_val in range(1, max_val // 2 + 1):\n dp[max_val][length] += dp[prev_val][length - 1]\n \n # Sum up all possible sequences of length n for all possible maximum values\n return sum(dp[i][n] for i in range(1, m + 1))", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n # Initialize a 2D list where dp[i][j] represents the number of sequences of length i\n # ending with j. \n dp = [[0] * (m + 1) for _ in range(n + 1)]\n \n # There is one way to have a sequence of length 1 ending in any number from 1 to m\n for j in range(1, m + 1):\n dp[1][j] = 1\n \n # Fill the dp table\n for i in range(2, n + 1): # i represents sequence length\n for j in range(1, m + 1): # j represents the ending number\n for k in range(1, (j // 2) + 1): # k represents the previous number\n dp[i][j] += dp[i - 1][k]\n \n # The answer is the sum of the last row of the dp table\n return sum(dp[n])", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n # Initialize a 2D array where dp[i][j] represents the number of sequences\n # of length j that can end with i\n dp = [[0 for _ in range(n + 1)] for _ in range(m + 1)]\n \n # There is exactly one sequence of length 1 for each i (the sequence is [i])\n for i in range(1, m + 1):\n dp[i][1] = 1\n \n # Fill the dp table\n for j in range(2, n + 1): # Length of sequence\n for i in range(1, m + 1): # Ending value of the sequence\n for k in range(1, i // 2 + 1): # Previous value in the sequence\n dp[i][j] += dp[k][j - 1]\n \n # Sum up all possibilities for sequences of length n\n return sum(dp[i][n] for i in range(1, m + 1))", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n # Initialize a DP table where dp[i][j] represents the number of sequences of length i ending with j\n dp = [[0 for _ in range(m + 1)] for _ in range(n + 1)]\n \n # For sequences of length 1, there is only one sequence ending with each number from 1 to m\n for j in range(1, m + 1):\n dp[1][j] = 1\n \n # Fill the DP table\n for i in range(2, n + 1): # Length of the sequence\n for j in range(1, m + 1): # Ending number of the sequence\n for k in range(1, j // 2 + 1): # Previous number which is <= j/2\n dp[i][j] += dp[i - 1][k]\n \n # Sum up all possibilities for sequences of length n\n return sum(dp[n][j] for j in range(1, m + 1))", "matching_cluster_idx": 6}, {"solution": "def get_total_number_of_sequences(m, n):\n # Initialize a 2D array to store intermediate results\n dp = [[0] * (n + 1) for _ in range(m + 1)]\n \n # There is one way to form a sequence of length 1 (the number itself)\n for i in range(1, m + 1):\n dp[i][1] = 1\n \n # Fill the dp table\n for i in range(1, m + 1):\n for j in range(2, n + 1):\n for k in range(1, i // 2 + 1):\n dp[i][j] += dp[k][j - 1]\n \n # Return the number of sequences of length n ending with any number <= m\n return sum(dp[i][n] for i in range(1, m + 1))", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n # If n is 1, the only sequence is the number itself\n if n == 1:\n return m\n \n # Initialize a 2D list to store the number of sequences\n dp = [[0 for _ in range(n+1)] for _ in range(m+1)]\n \n # Base case: sequences of length 1\n for i in range(1, m+1):\n dp[i][1] = 1\n \n # Fill the dp table\n for length in range(2, n+1):\n for max_val in range(1, m+1):\n for prev_val in range(1, (max_val // 2) + 1):\n dp[max_val][length] += dp[prev_val][length-1]\n \n # Sum up all possible sequences of length n ending at any value up to m\n return sum(dp[i][n] for i in range(1, m+1))", "matching_cluster_idx": 6}, {"solution": "def get_total_number_of_sequences(m, n):\n # If n is 1, there's only one sequence possible for each m\n if n == 1:\n return m\n \n # Initialize a 2D list to store the number of sequences\n dp = [[0] * (m + 1) for _ in range(n + 1)]\n \n # Base case: for length 1, there are m possible sequences\n for i in range(1, m + 1):\n dp[1][i] = 1\n \n # Fill the dp table\n for i in range(2, n + 1):\n for j in range(1, m + 1):\n for k in range(1, j // 2 + 1):\n dp[i][j] += dp[i - 1][k]\n \n # The answer will be the sum of sequences of length n for all possible starting points\n return sum(dp[n])", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n # We use dynamic programming to solve this problem.\n # dp[i][j] represents the number of sequences of length i with the last element being j.\n dp = [[0] * (m + 1) for _ in range(n + 1)]\n \n # There is one way to have a sequence of length 1, which is the number itself.\n for j in range(1, m + 1):\n dp[1][j] = 1\n \n # Fill the dp table\n for i in range(2, n + 1):\n for j in range(1, m + 1):\n for k in range(1, j // 2 + 1):\n dp[i][j] += dp[i - 1][k]\n \n # Sum up the sequences of length n for all possible last elements\n result = sum(dp[n])\n return result", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n # If n is 1, there's only one sequence possible for any m\n if n == 1:\n return m\n \n # Initialize a 2D array to store the number of sequences\n # dp[i][j] will store the number of sequences of length i ending with number j\n dp = [[0 for _ in range(m + 1)] for _ in range(n + 1)]\n \n # Base case: There's one way to form a sequence of length 1 for each number\n for i in range(1, m + 1):\n dp[1][i] = 1\n \n # Fill the dp table\n for i in range(2, n + 1):\n for j in range(1, m + 1):\n for k in range(1, j // 2 + 1):\n dp[i][j] += dp[i - 1][k]\n \n # Sum up all possible sequences of length n\n result = sum(dp[n])\n return result", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n # Initialize a 2D list to store the number of sequences\n dp = [[0] * (n + 1) for _ in range(m + 1)]\n \n # There's 1 way to form a sequence of length 1 for any element\n for i in range(1, m + 1):\n dp[i][1] = 1\n \n # Fill the dp table\n for length in range(2, n + 1):\n for max_val in range(1, m + 1):\n for previous_val in range(1, (max_val // 2) + 1):\n dp[max_val][length] += dp[previous_val][length - 1]\n \n # The answer is the sum of sequences that can end with any value from 1 to m\n return sum(dp[i][n] for i in range(1, m + 1))", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n # Create a 2D list to store the results of subproblems\n dp = [[0] * (n + 1) for _ in range(m + 1)]\n \n # Base case: There's 1 way to form a sequence of length 1 for any number\n for i in range(1, m + 1):\n dp[i][1] = 1\n \n # Fill the dp table\n for length in range(2, n + 1):\n for max_val in range(1, m + 1):\n for prev_val in range(1, (max_val // 2) + 1):\n dp[max_val][length] += dp[prev_val][length - 1]\n \n # Sum up all the ways to form a sequence of length n\n return sum(dp[i][n] for i in range(1, m + 1))", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n # If n is 1, any value from 1 to m can be a sequence\n if n == 1:\n return m\n \n # Use dynamic programming to store intermediate results\n dp = [[0] * (n + 1) for _ in range(m + 1)]\n \n # Initialize the base case where the sequence length is 1\n for i in range(1, m + 1):\n dp[i][1] = 1\n \n # Fill the dp table\n for length in range(2, n + 1):\n for max_val in range(1, m + 1):\n for prev_val in range(1, (max_val // 2) + 1):\n dp[max_val][length] += dp[prev_val][length - 1]\n \n # Sum up all possible sequences of length n\n return sum(dp[i][n] for i in range(1, m + 1))", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n # Create a 2D array to store the number of sequences\n dp = [[0] * (n + 1) for _ in range(m + 1)]\n \n # Base case: There is one way to form a sequence of length 1\n for i in range(1, m + 1):\n dp[i][1] = 1\n \n # Fill the dp table\n for i in range(1, m + 1):\n for j in range(2, n + 1):\n for k in range(1, i // 2 + 1):\n dp[i][j] += dp[k][j - 1]\n \n # Sum up the number of sequences ending with each number\n result = sum(dp[i][n] for i in range(1, m + 1))\n return result", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n # If n is 1, there is only one possible sequence for any m\n if n == 1:\n return m\n \n # Initialize a 2D list to store the number of sequences\n dp = [[0] * (m + 1) for _ in range(n + 1)]\n \n # Base case: for length 1 sequence, the number of valid sequences ending with i is 1\n for i in range(1, m + 1):\n dp[1][i] = 1\n \n # Fill the dp table\n for i in range(2, n + 1):\n for j in range(1, m + 1):\n for k in range(1, j // 2 + 1):\n dp[i][j] += dp[i - 1][k]\n \n # The answer is the sum of all possible sequences of length n\n return sum(dp[n][1:])", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n # Initialize a 2D list to store intermediate results\n dp = [[0] * (n + 1) for _ in range(m + 1)]\n \n # Base case: There's one sequence of length 1 for each possible starting number\n for i in range(1, m + 1):\n dp[i][1] = 1\n \n # Fill the dp table\n for i in range(1, m + 1):\n for j in range(2, n + 1):\n for k in range(1, i // 2 + 1):\n dp[i][j] += dp[k][j - 1]\n \n # Sum up all possible sequences of length n\n total_sequences = sum(dp[i][n] for i in range(1, m + 1))\n return total_sequences", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n # If n is 1, there is only one possible sequence: a single number\n if n == 1:\n return m\n \n # Initialize a 2D list to store the number of sequences ending with a specific value\n dp = [[0] * (m + 1) for _ in range(n + 1)]\n \n # Base case: with one element, any number from 1 to m is valid\n for i in range(1, m + 1):\n dp[1][i] = 1\n \n # Fill the dp table\n for i in range(2, n + 1):\n for j in range(1, m + 1):\n for k in range(1, j // 2 + 1):\n dp[i][j] += dp[i - 1][k]\n \n # Sum up all valid sequences of length n that end with any number from 1 to m\n result = sum(dp[n][1:])\n return result", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n # Initialize a 2D array to store the number of ways to form a sequence of length i with the last element j\n dp = [[0 for _ in range(m + 1)] for _ in range(n + 1)]\n \n # Base case: there's 1 way to form a sequence of length 1 with any element from 1 to m\n for j in range(1, m + 1):\n dp[1][j] = 1\n \n # Fill the dp table\n for i in range(2, n + 1):\n for j in range(1, m + 1):\n for k in range(1, (j // 2) + 1):\n dp[i][j] += dp[i - 1][k]\n \n # Sum up all the ways to form a sequence of length n ending with any valid element\n return sum(dp[n][1:])", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n # If n is 1, any single number from 1 to m can be the sequence\n if n == 1:\n return m\n \n # Initialize a DP table where dp[i][j] represents the number of sequences\n # of length j that end with number i\n dp = [[0 for _ in range(n + 1)] for _ in range(m + 1)]\n \n # Base case: there's only one way to form a sequence of length 1\n for i in range(1, m + 1):\n dp[i][1] = 1\n \n # Fill the DP table\n for seq_length in range(2, n + 1):\n for max_num in range(1, m + 1):\n for prev_max in range(1, (max_num // 2) + 1):\n dp[max_num][seq_length] += dp[prev_max][seq_length - 1]\n \n # Sum up all possible sequences of length n\n total_sequences = sum(dp[i][n] for i in range(1, m + 1))\n return total_sequences", "matching_cluster_idx": 6}]}, "Mbpp/240": {"dps": 80.48780487804879, "dps_norm": 88.88888888888889, "pass@1": 62.0, "profiled": [{"solution": "def replace_list(lst1, lst2):\n # Replace the last element of lst1 with all elements of lst2\n lst1[-1:] = lst2\n return lst1", "matching_cluster_idx": 7}, {"solution": "def replace_list(lst1, lst2):\n # Replace the last element of lst1 with all elements of lst2\n lst1[-1:] = lst2\n return lst1", "matching_cluster_idx": 7}, {"solution": "def replace_list(lst1, lst2):\n # Replace the last element of the first list with all elements of the second list\n lst1[-1:] = lst2\n return lst1", "matching_cluster_idx": 7}, {"solution": "def replace_list(list1, list2):\n # Replace the last element of the first list with the elements of the second list\n list1[-1:] = list2\n return list1", "matching_cluster_idx": 7}, {"solution": "def replace_list(list1, list2):\n # Replace the last element of list1 with all elements of list2\n list1[-1:] = list2\n return list1", "matching_cluster_idx": 7}, {"solution": "def replace_list(lst1, lst2):\n # Replace the last element of lst1 with all elements of lst2\n lst1[-1:] = lst2\n return lst1", "matching_cluster_idx": 7}, {"solution": "def replace_list(lst1, lst2):\n # Replace the last element of the first list with the elements of the second list\n lst1[-1:] = lst2\n return lst1", "matching_cluster_idx": 7}, {"solution": "def replace_list(lst1, lst2):\n # Replace the last element of lst1 with all elements of lst2 starting from index 0\n lst1[-1:] = lst2\n return lst1", "matching_cluster_idx": 7}, {"solution": "def replace_list(lst1, lst2):\n # Replace the last element of lst1 with all elements of lst2\n lst1[-1:] = lst2\n return lst1", "matching_cluster_idx": 7}, {"solution": "def replace_list(lst1, lst2):\n # Replace the last element of lst1 with the elements of lst2\n lst1[-1:] = lst2\n return lst1", "matching_cluster_idx": 7}, {"solution": "def replace_list(list1, list2):\n # Replace the last element of list1 with the elements of list2\n list1[-1:] = list2\n return list1", "matching_cluster_idx": 7}, {"solution": "def replace_list(lst1, lst2):\n # Replace the last element of lst1 with the elements of lst2\n lst1[-1:] = lst2\n return lst1", "matching_cluster_idx": 7}, {"solution": "def replace_list(list1, list2):\n # Replace the last element of list1 with elements from list2\n list1[-1:] = list2\n return list1", "matching_cluster_idx": 7}, {"solution": "def replace_list(list1, list2):\n # Replace the last element of the first list with elements of the second list\n list1[-1:] = list2\n return list1", "matching_cluster_idx": 7}, {"solution": "def replace_list(list1, list2):\n # Replace the last element of list1 with all elements of list2\n list1[-1:] = list2\n return list1", "matching_cluster_idx": 7}, {"solution": "def replace_list(lst1, lst2):\n # Replace the last element of lst1 with all elements of lst2\n lst1[-1:] = lst2\n return lst1", "matching_cluster_idx": 7}, {"solution": "def replace_list(lst1, lst2):\n # Replace the last element of the first list with all elements of the second list\n lst1[-1:] = lst2\n return lst1", "matching_cluster_idx": 7}, {"solution": "def replace_list(lst1, lst2):\n # Replace the last element of lst1 with the elements of lst2\n lst1[-1:] = lst2\n return lst1", "matching_cluster_idx": 7}, {"solution": "def replace_list(lst1, lst2):\n # Replace the last element of lst1 with the elements of lst2\n lst1[-1:] = lst2\n return lst1", "matching_cluster_idx": 7}, {"solution": "def replace_list(list1, list2):\n # Replace the last element of the first list with the elements of the second list\n list1[-1:] = list2\n return list1", "matching_cluster_idx": 7}]}, "Mbpp/251": {"dps": 87.95977011494254, "dps_norm": 76.66666666666666, "pass@1": 35.0, "profiled": [{"solution": "def insert_element(lst, element):\n # Create a new list by iterating through the original list and inserting the element before each item\n result = []\n for item in lst:\n result.append(element)\n result.append(item)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n # Insert the element before each element in the list\n result = []\n for item in lst:\n result.append(element)\n result.append(item)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n # Initialize an empty list to store the result\n result = []\n \n # Iterate over each item in the input list\n for item in lst:\n # Append the element to the result list\n result.append(element)\n # Append the current item from the input list to the result list\n result.append(item)\n \n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n # Initialize an empty list to store the result\n result = []\n \n # Iterate through each item in the input list\n for item in lst:\n # Append the element to the result list\n result.append(element)\n # Append the current item from the input list to the result list\n result.append(item)\n \n # Return the resulting list\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n # Initialize an empty list to store the result\n result = []\n # Iterate through each item in the input list\n for item in lst:\n # Append the specified element to the result list\n result.append(element)\n # Append the current item from the input list to the result list\n result.append(item)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n # Initialize an empty list to store the result\n result = []\n \n # Iterate through each item in the original list\n for item in lst:\n # Append the specified element to the result list\n result.append(element)\n # Append the current item from the original list to the result list\n result.append(item)\n \n # Return the resulting list\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n # Initialize an empty list to store the result\n result = []\n # Iterate through each element in the input list\n for item in lst:\n # Append the specified element to the result list\n result.append(element)\n # Append the current element from the input list to the result list\n result.append(item)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n # Initialize an empty list to store the result\n result = []\n # Iterate over each item in the original list\n for item in lst:\n # Insert the element before the current item and extend the result list\n result.extend([element, item])\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n # Insert 'element' before each element in the list\n result = []\n for item in lst:\n result.append(element)\n result.append(item)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n # Create a new list to store the result\n result = []\n # Iterate through each element in the input list\n for item in lst:\n # Insert the given element before the current item\n result.append(element)\n result.append(item)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n # Create a new list to store the result\n result = []\n \n # Iterate through each item in the input list\n for item in lst:\n # Insert the specified element and then append the current item\n result.extend([element, item])\n \n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n # Create a new list that will store the modified elements\n result = []\n \n # Iterate over each item in the original list\n for item in lst:\n # Insert the element before each item and append the current item to the result list\n result.append(element)\n result.append(item)\n \n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n # Insert the element before each element in the list\n result = []\n for item in lst:\n result.append(element)\n result.append(item)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n # Create a new list that will store the result\n result = []\n \n # Iterate through each item in the input list\n for item in lst:\n # Insert the element before the current item\n result.append(element)\n result.append(item)\n \n # Return the resulting list\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n # Insert 'element' before each element in the list and return the new list\n result = []\n for item in lst:\n result.append(element)\n result.append(item)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n # Initialize an empty list to store the result\n result = []\n # Iterate through each item in the input list\n for item in lst:\n # Append the specified element to the result list\n result.append(element)\n # Append the current item from the input list to the result list\n result.append(item)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n # Insert `element` before each element in `lst`\n result = []\n for item in lst:\n result.append(element)\n result.append(item)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n # Initialize an empty list to store the result\n result = []\n \n # Iterate through each item in the input list\n for item in lst:\n # Insert the element before the current item and add both to the result list\n result.append(element)\n result.append(item)\n \n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n # Use list comprehension to insert 'element' before each element in the list\n result = [element] + [item for item in lst] + [element]\n # Adjust the list to include 'element' before each item\n return [item for pair in zip([element] * (len(lst) + 1), lst) for item in pair]", "matching_cluster_idx": 4}, {"solution": "def insert_element(lst, element):\n # Initialize an empty list to store the result\n result = []\n \n # Iterate over each item in the input list\n for item in lst:\n # Insert the element before the current item and extend the result list\n result.extend([element, item])\n \n return result", "matching_cluster_idx": 6}]}, "Mbpp/256": {"dps": 64.29223744292237, "dps_norm": 60.0, "pass@1": 100.0, "profiled": [{"solution": "import math\ndef is_prime(num):\n \"\"\"Check if a number is prime.\"\"\"\n if num <= 1:\n return False\n if num <= 3:\n return True\n if num % 2 == 0 or num % 3 == 0:\n return False\n i = 5\n while i * i <= num:\n if num % i == 0 or num % (i + 2) == 0:\n return False\n i += 6\n return True\ndef count_Primes_nums(n):\n \"\"\"\n Takes in a non-negative number and returns the number of prime numbers less than the given non-negative number.\n \"\"\"\n count = 0\n for i in range(2, n):\n if is_prime(i):\n count += 1\n return count", "matching_cluster_idx": 10}, {"solution": "def is_prime(n):\n \"\"\"Check if a number is prime.\"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True\ndef count_Primes_nums(n):\n \"\"\"\n Takes in a non-negative number and returns the number of prime numbers less than the given non-negative number.\n \n :param n: Non-negative integer\n :return: Number of prime numbers less than n\n \"\"\"\n count = 0\n for i in range(2, n):\n if is_prime(i):\n count += 1\n return count", "matching_cluster_idx": 10}, {"solution": "def is_prime(n):\n \"\"\"Check if a number is prime.\"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True\ndef count_Primes_nums(num):\n \"\"\"\n Takes in a non-negative number and returns the number of prime numbers less than the given non-negative number.\n \"\"\"\n count = 0\n for i in range(2, num):\n if is_prime(i):\n count += 1\n return count", "matching_cluster_idx": 10}, {"solution": "def is_prime(num):\n \"\"\"Check if a number is prime.\"\"\"\n if num <= 1:\n return False\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n return False\n return True\ndef count_Primes_nums(n):\n \"\"\"\n Takes in a non-negative number and returns the number of prime numbers less than the given non-negative number.\n \n :param n: Non-negative integer\n :return: Count of prime numbers less than n\n \n >>> count_Primes_nums(5)\n 2\n \"\"\"\n count = 0\n for i in range(2, n):\n if is_prime(i):\n count += 1\n return count", "matching_cluster_idx": 8}, {"solution": "def is_prime(n):\n \"\"\"Check if a number is prime.\"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True\ndef count_Primes_nums(num):\n \"\"\"\n Returns the number of prime numbers less than the given non-negative number.\n\n :param num: Non-negative integer\n :return: Number of prime numbers less than num\n \"\"\"\n count = 0\n for i in range(2, num):\n if is_prime(i):\n count += 1\n return count", "matching_cluster_idx": 10}, {"solution": "def is_prime(n):\n \"\"\"Check if a number is prime.\"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True\ndef count_Primes_nums(num):\n \"\"\"\n Return the number of prime numbers less than the given non-negative number.\n \n :param num: Non-negative integer\n :return: Count of prime numbers less than num\n \"\"\"\n count = 0\n for i in range(2, num):\n if is_prime(i):\n count += 1\n return count", "matching_cluster_idx": 10}, {"solution": "def count_Primes_nums(n):\n # Helper function to check if a number is prime\n def is_prime(num):\n if num <= 1:\n return False\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n return False\n return True\n \n # Count the number of prime numbers less than n\n count = 0\n for num in range(2, n):\n if is_prime(num):\n count += 1\n return count", "matching_cluster_idx": 8}, {"solution": "def count_Primes_nums(n):\n # Helper function to check if a number is prime\n def is_prime(num):\n if num <= 1:\n return False\n if num <= 3:\n return True\n if num % 2 == 0 or num % 3 == 0:\n return False\n i = 5\n while i * i <= num:\n if num % i == 0 or num % (i + 2) == 0:\n return False\n i += 6\n return True\n \n # Count and return the number of primes less than n\n return sum(is_prime(i) for i in range(2, n))", "matching_cluster_idx": 10}, {"solution": "def count_Primes_nums(n):\n # Helper function to check if a number is prime\n def is_prime(num):\n if num <= 1:\n return False\n if num <= 3:\n return True\n if num % 2 == 0 or num % 3 == 0:\n return False\n i = 5\n while i * i <= num:\n if num % i == 0 or num % (i + 2) == 0:\n return False\n i += 6\n return True\n \n # Count the number of primes less than n\n count = 0\n for i in range(2, n):\n if is_prime(i):\n count += 1\n return count", "matching_cluster_idx": 10}, {"solution": "def is_prime(num):\n \"\"\"Check if a number is prime.\"\"\"\n if num <= 1:\n return False\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n return False\n return True\ndef count_Primes_nums(n):\n \"\"\"\n Takes in a non-negative number and returns the number of prime numbers less than the given non-negative number.\n \n :param n: Non-negative integer\n :return: Count of prime numbers less than n\n \"\"\"\n count = 0\n for num in range(2, n):\n if is_prime(num):\n count += 1\n return count", "matching_cluster_idx": 8}, {"solution": "import math\ndef is_prime(num):\n if num <= 1:\n return False\n if num <= 3:\n return True\n if num % 2 == 0 or num % 3 == 0:\n return False\n i = 5\n while i * i <= num:\n if num % i == 0 or num % (i + 2) == 0:\n return False\n i += 6\n return True\ndef count_Primes_nums(n):\n # Count the number of primes less than n\n count = 0\n for i in range(2, n):\n if is_prime(i):\n count += 1\n return count", "matching_cluster_idx": 10}, {"solution": "def is_prime(n):\n \"\"\"Check if a number is prime.\"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True\ndef count_Primes_nums(num):\n \"\"\"\n Takes in a non-negative number and returns the number of prime numbers less than the given non-negative number.\n \n :param num: Non-negative integer\n :return: Count of prime numbers less than num\n \"\"\"\n if num <= 2:\n return 0\n count = 0\n for i in range(2, num):\n if is_prime(i):\n count += 1\n return count", "matching_cluster_idx": 10}, {"solution": "def count_Primes_nums(n):\n \"\"\"\n This function takes in a non-negative number n and returns the number of prime numbers less than n.\n \"\"\"\n def is_prime(num):\n if num <= 1:\n return False\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n return False\n return True\n \n count = 0\n for i in range(2, n):\n if is_prime(i):\n count += 1\n return count", "matching_cluster_idx": 8}, {"solution": "def count_Primes_nums(n):\n # Helper function to check if a number is prime\n def is_prime(num):\n if num <= 1:\n return False\n if num <= 3:\n return True\n if num % 2 == 0 or num % 3 == 0:\n return False\n i = 5\n while i * i <= num:\n if num % i == 0 or num % (i + 2) == 0:\n return False\n i += 6\n return True\n \n # Count the number of primes less than n\n count = 0\n for i in range(2, n):\n if is_prime(i):\n count += 1\n \n return count", "matching_cluster_idx": 10}, {"solution": "def count_Primes_nums(n):\n # Helper function to check if a number is prime\n def is_prime(num):\n if num <= 1:\n return False\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n return False\n return True\n \n # Count and return the number of prime numbers less than n\n return sum(is_prime(i) for i in range(2, n))", "matching_cluster_idx": 8}, {"solution": "def is_prime(n):\n \"\"\"Check if a number is prime.\"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True\ndef count_Primes_nums(n):\n \"\"\"\n Returns the number of prime numbers less than the given non-negative number.\n\n :param n: Non-negative number\n :return: Number of prime numbers less than n\n\n >>> count_Primes_nums(5)\n 2\n \"\"\"\n count = 0\n for i in range(2, n):\n if is_prime(i):\n count += 1\n return count", "matching_cluster_idx": 10}, {"solution": "def count_Primes_nums(n):\n # Helper function to check if a number is prime\n def is_prime(num):\n if num <= 1:\n return False\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n return False\n return True\n \n # Count and return the number of primes less than n\n return sum(is_prime(i) for i in range(2, n))", "matching_cluster_idx": 8}, {"solution": "def count_Primes_nums(n):\n # A function to check if a number is prime\n def is_prime(num):\n if num <= 1:\n return False\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n return False\n return True\n \n # Count the number of primes less than n\n prime_count = 0\n for i in range(2, n):\n if is_prime(i):\n prime_count += 1\n \n return prime_count", "matching_cluster_idx": 8}, {"solution": "def count_Primes_nums(n):\n # Helper function to check if a number is prime\n def is_prime(num):\n if num <= 1:\n return False\n if num <= 3:\n return True\n if num % 2 == 0 or num % 3 == 0:\n return False\n i = 5\n while i * i <= num:\n if num % i == 0 or num % (i + 2) == 0:\n return False\n i += 6\n return True\n \n # Count prime numbers less than n\n prime_count = 0\n for i in range(2, n):\n if is_prime(i):\n prime_count += 1\n \n return prime_count", "matching_cluster_idx": 10}, {"solution": "def count_Primes_nums(n):\n def is_prime(num):\n if num <= 1:\n return False\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n return False\n return True\n \n prime_count = 0\n for i in range(2, n):\n if is_prime(i):\n prime_count += 1\n \n return prime_count", "matching_cluster_idx": 8}]}, "Mbpp/265": {"dps": 70.93023255813954, "dps_norm": 83.33333333333333, "pass@1": 13.0, "profiled": [{"solution": "def list_split(lst, n):\n # Use list comprehension to group elements based on their index modulo n\n return [lst[i::n] for i in range(n)]", "matching_cluster_idx": 4}, {"solution": "def list_split(input_list, n):\n # Split the list into sublists every nth element\n return [input_list[i::n] for i in range(n)]", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n # Split the list every nth element\n return [lst[i::n] for i in range(n)]", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n # Use list comprehension to split the list every nth element\n return [lst[i::n] for i in range(n)]", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n # Split the list into sublists every nth element\n return [lst[i::n] for i in range(n)]", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n # Use list comprehension to split the list every nth element\n return [lst[i::n] for i in range(n)]", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n # Use list comprehension to split the list every nth element\n return [lst[i::n] for i in range(n)]", "matching_cluster_idx": 4}, {"solution": "def list_split(input_list, n):\n # Use list comprehension to split the list every nth element\n return [input_list[i::n] for i in range(n)]", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n # Create a list of lists split every nth element\n return [lst[i::n] for i in range(n)]", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n # Split the list for every nth element\n return [lst[i::n] for i in range(n)]", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n # Split the list into sublists at every nth element\n return [lst[i::n] for i in range(n)]", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n # Use list comprehension to split the list every nth element\n return [lst[i::n] for i in range(n)]", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n # Create a list of lists, splitting the original list every nth element\n return [lst[i::n] for i in range(n)]", "matching_cluster_idx": 4}]}, "Mbpp/281": {"dps": 94.0, "dps_norm": 81.81818181818181, "pass@1": 100.0, "profiled": [{"solution": "def all_unique(lst):\n \"\"\"\n Check if the elements of a given list are unique.\n \n Args:\n lst (list): The list to check for uniqueness.\n \n Returns:\n bool: True if all elements are unique, False otherwise.\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n # Convert the list to a set and check if its length is the same as the input list\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n Check if the elements of a given list are unique.\n\n Args:\n lst (list): The list to check.\n\n Returns:\n bool: True if all elements are unique, False otherwise.\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n # Create a set from the list. If the lengths of the set and the list are different,\n # it means there were duplicates in the list.\n return len(set(lst)) == len(lst)", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n # Using set to store unique elements, and comparing lengths\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n # Convert the list to a set and compare its length to the original list\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(numbers):\n # Create a set from the list to remove duplicates\n unique_numbers = set(numbers)\n # Compare the length of the set with the list\n return len(unique_numbers) == len(numbers)", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n Check if the elements of a given list are unique.\n\n Args:\n lst (list): The list to check.\n\n Returns:\n bool: True if all elements are unique, False otherwise.\n\n Test cases:\n >>> all_unique([1, 2, 3])\n True\n >>> all_unique([1, 2, 2])\n False\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(nums):\n # Create a set from the list to remove duplicates\n unique_set = set(nums)\n # Compare the length of the set with the list\n return len(unique_set) == len(nums)", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n # Create a set from the list, which will remove duplicates\n # Compare the length of the set with the list\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(elements):\n \"\"\"\n Check if all elements in the list are unique.\n\n Args:\n elements (list): The list of elements to check.\n\n Returns:\n bool: True if all elements are unique, False otherwise.\n \"\"\"\n return len(elements) == len(set(elements))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n # Create a set from the list to remove duplicates\n unique_elements = set(lst)\n # Compare lengths of the original list and the set\n return len(lst) == len(unique_elements)", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n Check if the elements of a given list are unique or not.\n\n Args:\n lst (list): The list to check for uniqueness.\n\n Returns:\n bool: True if all elements are unique, False otherwise.\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n Check if the elements of a given list are unique or not.\n\n Args:\n lst (list): The list to check for uniqueness.\n\n Returns:\n bool: True if all elements are unique, False otherwise.\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n Check if the elements of a given list are unique or not.\n \n Args:\n lst (list): The list to check for uniqueness.\n \n Returns:\n bool: True if all elements are unique, False otherwise.\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n # Convert the list to a set and compare its length to the original list's length\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n # Check if the length of the list is equal to the length of the set of the list\n # If they are equal, it means all elements in the list are unique\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n Check if the elements of a given list are unique or not.\n\n Args:\n lst (list): The list to check for uniqueness.\n\n Returns:\n bool: True if all elements are unique, False otherwise.\n\n Examples:\n >>> all_unique([1, 2, 3])\n True\n >>> all_unique([1, 2, 2])\n False\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n # Create a set from the list. If the lengths differ, duplicates were removed.\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}]}, "Mbpp/296": {"dps": 96.41025641025641, "dps_norm": 98.33333333333333, "pass@1": 64.0, "profiled": [{"solution": "def get_Inv_Count(arr):\n def merge_sort_count(arr):\n if len(arr) <= 1:\n return arr, 0\n else:\n mid = len(arr) // 2\n left, left_count = merge_sort_count(arr[:mid])\n right, right_count = merge_sort_count(arr[mid:])\n merged, split_count = merge_count(left, right)\n return merged, left_count + right_count + split_count\n\n def merge_count(left, right):\n count = 0\n result = []\n i = j = 0\n while i < len(left) and j < len(right):\n if left[i] <= right[j]:\n result.append(left[i])\n i += 1\n else:\n result.append(right[j])\n j += 1\n count += len(left) - i # Count inversions\n result += left[i:]\n result += right[j:]\n return result, count\n\n _, total_inversions = merge_sort_count(arr)\n return total_inversions", "matching_cluster_idx": 5}, {"solution": "def get_Inv_Count(arr):\n def merge_sort_and_count(arr):\n if len(arr) <= 1:\n return arr, 0\n \n mid = len(arr) // 2\n left, x = merge_sort_and_count(arr[:mid])\n right, y = merge_sort_and_count(arr[mid:])\n merged, z = merge_and_count(left, right)\n return merged, x + y + z\n \n def merge_and_count(left, right):\n merged = []\n i = j = inv_count = 0\n \n while i < len(left) and j < len(right):\n if left[i] <= right[j]:\n merged.append(left[i])\n i += 1\n else:\n merged.append(right[j])\n j += 1\n inv_count += len(left) - i\n \n merged.extend(left[i:])\n merged.extend(right[j:])\n \n return merged, inv_count\n \n _, inversion_count = merge_sort_and_count(arr)\n return inversion_count", "matching_cluster_idx": 5}, {"solution": "def get_Inv_Count(arr):\n def merge_sort_and_count(arr):\n if len(arr) <= 1:\n return arr, 0\n mid = len(arr) // 2\n left, x = merge_sort_and_count(arr[:mid])\n right, y = merge_sort_and_count(arr[mid:])\n merged, z = merge_and_count_split_inv(left, right)\n return merged, x + y + z\n\n def merge_and_count_split_inv(left, right):\n merged = []\n i = j = inv_count = 0\n while i < len(left) and j < len(right):\n if left[i] <= right[j]:\n merged.append(left[i])\n i += 1\n else:\n merged.append(right[j])\n j += 1\n inv_count += len(left) - i # Count inversions\n merged += left[i:]\n merged += right[j:]\n return merged, inv_count\n\n _, inv_count = merge_sort_and_count(arr)\n return inv_count", "matching_cluster_idx": 5}, {"solution": "def get_Inv_Count(arr):\n # Base case: if the array has 1 or 0 elements, there are no inversions\n if len(arr) <= 1:\n return 0\n \n # Split the array into two halves\n mid = len(arr) // 2\n left = arr[:mid]\n right = arr[mid:]\n \n # Recursively count inversions in both halves\n left_inv = get_Inv_Count(left)\n right_inv = get_Inv_Count(right)\n \n # Count split inversions\n split_inv = 0\n i, j, k = 0, 0, 0\n left_len = len(left)\n right_len = len(right)\n \n while i < left_len and j < right_len:\n if left[i] <= right[j]:\n arr[k] = left[i]\n i += 1\n else:\n arr[k] = right[j]\n j += 1\n split_inv += left_len - i # Count all remaining elements in left as inversions\n k += 1\n \n # Copy remaining elements of left, if any\n while i < left_len:\n arr[k] = left[i]\n i += 1\n k += 1\n \n # Copy remaining elements of right, if any\n while j < right_len:\n arr[k] = right[j]\n j += 1\n k += 1\n \n # Return total inversions\n return left_inv + right_inv + split_inv", "matching_cluster_idx": 5}, {"solution": "def merge_sort_and_count(arr):\n if len(arr) <= 1:\n return arr, 0\n \n mid = len(arr) // 2\n left, x = merge_sort_and_count(arr[:mid])\n right, y = merge_sort_and_count(arr[mid:])\n result, z = merge_and_count_split_inversions(left, right)\n return result, x + y + z\ndef merge_and_count_split_inversions(left, right):\n result = []\n i = j = inv_count = 0\n \n while i < len(left) and j < len(right):\n if left[i] <= right[j]:\n result.append(left[i])\n i += 1\n else:\n result.append(right[j])\n j += 1\n inv_count += len(left) - i # All remaining elements in left are inversions\n \n result += left[i:]\n result += right[j:]\n \n return result, inv_count\ndef get_Inv_Count(arr):\n _, total_inversions = merge_sort_and_count(arr)\n return total_inversions", "matching_cluster_idx": 5}, {"solution": "def merge_sort(arr, temp_arr, left, right):\n inv_count = 0\n if left < right:\n mid = (left + right) // 2\n inv_count += merge_sort(arr, temp_arr, left, mid)\n inv_count += merge_sort(arr, temp_arr, mid + 1, right)\n inv_count += merge_and_count_inv(arr, temp_arr, left, mid, right)\n return inv_count\ndef merge_and_count_inv(arr, temp_arr, left, mid, right):\n i = left # Starting index for left subarray\n j = mid + 1 # Starting index for right subarray\n k = left # Starting index to be sorted\n inv_count = 0\n \n while i <= mid and j <= right:\n if arr[i] <= arr[j]:\n temp_arr[k] = arr[i]\n i += 1\n else:\n temp_arr[k] = arr[j]\n inv_count += (mid - i + 1) # Count inversions\n j += 1\n k += 1\n\n # Copy the remaining elements of left subarray (if any) to temp\n while i <= mid:\n temp_arr[k] = arr[i]\n i += 1\n k += 1\n\n # Copy the remaining elements of right subarray (if any) to temp\n while j <= right:\n temp_arr[k] = arr[j]\n j += 1\n k += 1\n\n # Copy the sorted subarray into Original array\n for i in range(left, right + 1):\n arr[i] = temp_arr[i]\n \n return inv_count\ndef get_Inv_Count(arr):\n n = len(arr)\n temp_arr = [0] * n\n return merge_sort(arr, temp_arr, 0, n - 1)", "matching_cluster_idx": 5}, {"solution": "def get_Inv_Count(arr):\n # Base case: if the array has 1 or no elements, it has 0 inversions\n if len(arr) <= 1:\n return 0\n \n # Split the array into two halves\n mid = len(arr) // 2\n left_half = arr[:mid]\n right_half = arr[mid:]\n \n # Recursively count inversions in both halves\n left_inv_count = get_Inv_Count(left_half)\n right_inv_count = get_Inv_Count(right_half)\n \n # Count split inversions between the left and right halves\n split_inv_count = 0\n i = j = k = 0\n while i < len(left_half) and j < len(right_half):\n if left_half[i] <= right_half[j]:\n arr[k] = left_half[i]\n i += 1\n else:\n arr[k] = right_half[j]\n j += 1\n split_inv_count += len(left_half) - i\n k += 1\n \n # Copy the remaining elements of left_half, if any, to arr\n while i < len(left_half):\n arr[k] = left_half[i]\n i += 1\n k += 1\n \n # Copy the remaining elements of right_half, if any, to arr\n while j < len(right_half):\n arr[k] = right_half[j]\n j += 1\n k += 1\n \n # Return the total number of inversions\n return left_inv_count + right_inv_count + split_inv_count", "matching_cluster_idx": 5}, {"solution": "def get_Inv_Count(arr):\n def merge_sort_and_count(arr):\n if len(arr) <= 1:\n return arr, 0\n \n mid = len(arr) // 2\n left, left_count = merge_sort_and_count(arr[:mid])\n right, right_count = merge_sort_and_count(arr[mid:])\n \n merged, split_count = merge_and_count(left, right)\n return merged, left_count + right_count + split_count\n \n def merge_and_count(left, right):\n merged = []\n count = 0\n i = j = 0\n \n while i < len(left) and j < len(right):\n if left[i] <= right[j]:\n merged.append(left[i])\n i += 1\n else:\n merged.append(right[j])\n j += 1\n count += len(left) - i # Count inversions\n \n merged.extend(left[i:])\n merged.extend(right[j:])\n \n return merged, count\n \n _, inv_count = merge_sort_and_count(arr)\n return inv_count", "matching_cluster_idx": 5}, {"solution": "def get_Inv_Count(arr):\n def merge_sort_and_count(arr):\n if len(arr) <= 1:\n return arr, 0\n \n mid = len(arr) // 2\n left, x = merge_sort_and_count(arr[:mid])\n right, y = merge_sort_and_count(arr[mid:])\n merged, z = merge_and_count(left, right)\n return merged, x + y + z\n \n def merge_and_count(left, right):\n merged = []\n i = j = inv_count = 0\n \n while i < len(left) and j < len(right):\n if left[i] <= right[j]:\n merged.append(left[i])\n i += 1\n else:\n merged.append(right[j])\n inv_count += len(left) - i # Count inversions\n j += 1\n \n merged += left[i:]\n merged += right[j:]\n \n return merged, inv_count\n \n _, total_inversions = merge_sort_and_count(arr)\n return total_inversions", "matching_cluster_idx": 5}, {"solution": "def get_Inv_Count(arr):\n # Base case: if the array is of length 0 or 1, it has no inversions\n if len(arr) <= 1:\n return 0\n \n # Split the array into two halves\n mid = len(arr) // 2\n left = arr[:mid]\n right = arr[mid:]\n \n # Recursively count inversions in both halves\n left_inv = get_Inv_Count(left)\n right_inv = get_Inv_Count(right)\n \n # Count cross inversions\n i, j, k, inv_count = 0, 0, 0, 0\n while i < len(left) and j < len(right):\n if left[i] <= right[j]:\n arr[k] = left[i]\n i += 1\n else:\n arr[k] = right[j]\n j += 1\n inv_count += len(left) - i # All remaining elements in left are inversions\n k += 1\n \n # Copy the remaining elements (if any)\n while i < len(left):\n arr[k] = left[i]\n i += 1\n k += 1\n while j < len(right):\n arr[k] = right[j]\n j += 1\n k += 1\n \n return inv_count + left_inv + right_inv", "matching_cluster_idx": 5}, {"solution": "def get_Inv_Count(arr):\n # Initialize inversion count\n inv_count = 0\n \n # Iterate through the array\n for i in range(len(arr)):\n for j in range(i + 1, len(arr)):\n # If an inversion is found, increment the count\n if arr[i] > arr[j]:\n inv_count += 1\n \n return inv_count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n # Base case: if the array is empty or has only one element, there are no inversions\n if len(arr) <= 1:\n return 0\n \n # Split the array into two halves\n mid = len(arr) // 2\n left_half = arr[:mid]\n right_half = arr[mid:]\n \n # Recursively count inversions in both halves\n left_inv = get_Inv_Count(left_half)\n right_inv = get_Inv_Count(right_half)\n \n # Merge the arrays and count split inversions\n i, j = 0, 0\n merged = []\n inv_count = left_inv + right_inv\n \n while i < len(left_half) and j < len(right_half):\n if left_half[i] <= right_half[j]:\n merged.append(left_half[i])\n i += 1\n else:\n merged.append(right_half[j])\n inv_count += len(left_half) - i # Count the inversions\n j += 1\n \n # Append the remaining elements\n merged += left_half[i:]\n merged += right_half[j:]\n \n # Update the original array\n arr[:] = merged\n \n return inv_count", "matching_cluster_idx": 5}, {"solution": "def get_Inv_Count(arr):\n # Base case: if the array has 1 or no elements, it has no inversions\n if len(arr) <= 1:\n return 0\n \n # Divide the array into two halves\n mid = len(arr) // 2\n left_half = arr[:mid]\n right_half = arr[mid:]\n \n # Recursively count inversions in both halves\n left_inversions = get_Inv_Count(left_half)\n right_inversions = get_Inv_Count(right_half)\n \n # Merge the two halves and count split inversions\n merged_array = []\n i = j = inv_count = 0\n \n # Count split inversions\n while i < len(left_half) and j < len(right_half):\n if left_half[i] <= right_half[j]:\n merged_array.append(left_half[i])\n i += 1\n else:\n merged_array.append(right_half[j])\n j += 1\n # The number of split inversions is the number of elements left in the left half\n inv_count += (mid - i)\n \n # Add the remaining elements of left_half, if any\n while i < len(left_half):\n merged_array.append(left_half[i])\n i += 1\n \n # Add the remaining elements of right_half, if any\n while j < len(right_half):\n merged_array.append(right_half[j])\n j += 1\n \n # Copy the merged array back to arr\n arr[:] = merged_array\n \n # Total inversions is sum of inversions in left, right, and split inversions\n return left_inversions + right_inversions + inv_count", "matching_cluster_idx": 5}, {"solution": "def get_Inv_Count(arr):\n def merge_sort_and_count(arr):\n if len(arr) <= 1:\n return arr, 0\n mid = len(arr) // 2\n left, left_count = merge_sort_and_count(arr[:mid])\n right, right_count = merge_sort_and_count(arr[mid:])\n merged, merge_count = merge_and_count(left, right)\n return merged, left_count + right_count + merge_count\n \n def merge_and_count(left, right):\n merged = []\n i, j, inv_count = 0, 0, 0\n while i < len(left) and j < len(right):\n if left[i] <= right[j]:\n merged.append(left[i])\n i += 1\n else:\n merged.append(right[j])\n inv_count += len(left) - i\n j += 1\n merged += left[i:]\n merged += right[j:]\n return merged, inv_count\n \n _, inv_count = merge_sort_and_count(arr)\n return inv_count", "matching_cluster_idx": 5}, {"solution": "def merge_sort(arr):\n if len(arr) <= 1:\n return arr, 0\n \n mid = len(arr) // 2\n left, left_inv = merge_sort(arr[:mid])\n right, right_inv = merge_sort(arr[mid:])\n \n merged, split_inv = merge(left, right)\n \n return merged, (left_inv + right_inv + split_inv)\ndef merge(left, right):\n merged = []\n inversions = 0\n i, j = 0, 0\n \n while i < len(left) and j < len(right):\n if left[i] <= right[j]:\n merged.append(left[i])\n i += 1\n else:\n merged.append(right[j])\n j += 1\n inversions += len(left) - i # Count inversions\n \n merged += left[i:]\n merged += right[j:]\n \n return merged, inversions\ndef get_Inv_Count(arr):\n return merge_sort(arr)[1]", "matching_cluster_idx": 5}, {"solution": "def get_Inv_Count(arr):\n # Base case: if the array has 1 or no elements, it has no inversions\n if len(arr) <= 1:\n return 0\n \n # Split the array into two halves\n mid = len(arr) // 2\n left_half = arr[:mid]\n right_half = arr[mid:]\n \n # Recursively count inversions in both halves\n left_inv = get_Inv_Count(left_half)\n right_inv = get_Inv_Count(right_half)\n \n # Count inversions that cross the midpoint\n cross_inv = 0\n i = j = k = 0\n left_index = 0\n right_index = 0\n \n while left_index < len(left_half) and right_index < len(right_half):\n if left_half[left_index] <= right_half[right_index]:\n arr[k] = left_half[left_index]\n left_index += 1\n else:\n arr[k] = right_half[right_index]\n right_index += 1\n cross_inv += len(left_half) - left_index\n k += 1\n \n # Copy any remaining elements from the left half\n while left_index < len(left_half):\n arr[k] = left_half[left_index]\n left_index += 1\n k += 1\n \n # Copy any remaining elements from the right half\n while right_index < len(right_half):\n arr[k] = right_half[right_index]\n right_index += 1\n k += 1\n \n return left_inv + right_inv + cross_inv", "matching_cluster_idx": 5}, {"solution": "def merge_sort(arr):\n if len(arr) <= 1:\n return arr, 0\n \n mid = len(arr) // 2\n left, x = merge_sort(arr[:mid])\n right, y = merge_sort(arr[mid:])\n result, z = merge(left, right)\n return result, x + y + z\ndef merge(left, right):\n result = []\n i = j = inv_count = 0\n \n while i < len(left) and j < len(right):\n if left[i] <= right[j]:\n result.append(left[i])\n i += 1\n else:\n result.append(right[j])\n j += 1\n inv_count += len(left) - i # Count inversions\n \n result += left[i:]\n result += right[j:]\n \n return result, inv_count\ndef get_Inv_Count(arr):\n _, inv_count = merge_sort(arr)\n return inv_count", "matching_cluster_idx": 5}, {"solution": "def get_Inv_Count(arr):\n def merge_sort(arr):\n if len(arr) <= 1:\n return arr, 0\n else:\n mid = len(arr) // 2\n left, x = merge_sort(arr[:mid])\n right, y = merge_sort(arr[mid:])\n merged, z = merge(left, right)\n return merged, x + y + z\n\n def merge(left, right):\n merged = []\n i = j = inv_count = 0\n while i < len(left) and j < len(right):\n if left[i] <= right[j]:\n merged.append(left[i])\n i += 1\n else:\n merged.append(right[j])\n j += 1\n inv_count += len(left) - i # All remaining elements in left are inversions\n merged += left[i:]\n merged += right[j:]\n return merged, inv_count\n\n _, inv_count = merge_sort(arr)\n return inv_count", "matching_cluster_idx": 5}, {"solution": "def get_Inv_Count(arr):\n def merge_count_split_inv(left, right):\n i, j = 0, 0\n count = 0\n merged = []\n while i < len(left) and j < len(right):\n if left[i] <= right[j]:\n merged.append(left[i])\n i += 1\n else:\n merged.append(right[j])\n j += 1\n count += len(left) - i # Count inversions\n merged += left[i:]\n merged += right[j:]\n return merged, count\n \n def merge_sort_count_inv(arr):\n if len(arr) <= 1:\n return arr, 0\n mid = len(arr) // 2\n left, left_inv = merge_sort_count_inv(arr[:mid])\n right, right_inv = merge_sort_count_inv(arr[mid:])\n merged, split_inv = merge_count_split_inv(left, right)\n return merged, left_inv + right_inv + split_inv\n \n _, inv_count = merge_sort_count_inv(arr)\n return inv_count", "matching_cluster_idx": 5}, {"solution": "def get_Inv_Count(arr):\n # Base case: if the array has 1 or no elements, it has 0 inversions\n if len(arr) <= 1:\n return 0\n \n # Split the array into two halves\n mid = len(arr) // 2\n left_half = arr[:mid]\n right_half = arr[mid:]\n \n # Recursively count inversions in both halves\n left_inversions = get_Inv_Count(left_half)\n right_inversions = get_Inv_Count(right_half)\n \n # Count split inversions\n split_inversions = 0\n i, j = 0, 0\n left_index, right_index = 0, 0\n while left_index < len(left_half) and right_index < len(right_half):\n if left_half[left_index] <= right_half[right_index]:\n arr[i] = left_half[left_index]\n left_index += 1\n else:\n arr[i] = right_half[right_index]\n right_index += 1\n split_inversions += len(left_half) - left_index\n i += 1\n \n # Copy any remaining elements of left_half, if there are any\n while left_index < len(left_half):\n arr[i] = left_half[left_index]\n left_index += 1\n i += 1\n \n # Copy any remaining elements of right_half, if there are any\n while right_index < len(right_half):\n arr[i] = right_half[right_index]\n right_index += 1\n i += 1\n \n # Return the total number of inversions\n return left_inversions + right_inversions + split_inversions", "matching_cluster_idx": 5}]}, "Mbpp/308": {"dps": 91.17241379310346, "dps_norm": 66.66666666666667, "pass@1": 98.0, "profiled": [{"solution": "def large_product(lst1, lst2, n):\n # Create a list to store the products\n products = []\n # Calculate the product of each pair of elements from the two lists\n for num1 in lst1:\n for num2 in lst2:\n products.append(num1 * num2)\n \n # Sort the products in descending order\n products.sort(reverse=True)\n \n # Return the first n largest products\n return products[:n]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, k):\n # Create a list of tuples where each tuple is a product of elements from list1 and list2\n product_list = [(x * y) for x in list1 for y in list2]\n \n # Sort the list of products in descending order\n product_list.sort(reverse=True)\n \n # Return the first k elements from the sorted list\n return product_list[:k]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n # Generate all possible products from the two lists\n products = sorted([x * y for x in list1 for y in list2], reverse=True)[:n]\n return products", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, num):\n # Generate all possible products by combining one element from list1 and one from list2\n products = [x * y for x in list1 for y in list2]\n \n # Sort the list of products in descending order\n products.sort(reverse=True)\n \n # Return the first 'num' elements from the sorted list\n return products[:num]", "matching_cluster_idx": 3}, {"solution": "def large_product(lst1, lst2, k):\n # Multiply each element in lst1 with each element in lst2 and store the results in a list\n products = [x * y for x in lst1 for y in lst2]\n \n # Sort the list of products in descending order\n products.sort(reverse=True)\n \n # Return the first k elements from the sorted list\n return products[:k]", "matching_cluster_idx": 3}, {"solution": "def large_product(arr1, arr2, n):\n # Use a list to store the products\n products = []\n \n # Generate all possible products from the two arrays\n for num1 in arr1:\n for num2 in arr2:\n products.append(num1 * num2)\n \n # Sort the products in descending order\n products.sort(reverse=True)\n \n # Return the first n elements from the sorted list\n return products[:n]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n # Create a list of tuples with the product of each pair of elements from the two lists\n products = [(x * y, x, y) for x in list1 for y in list2]\n \n # Sort the products in descending order\n sorted_products = sorted(products, reverse=True)\n \n # Extract the largest n products\n largest_n_products = [product for product, _, _ in sorted_products[:n]]\n \n return largest_n_products", "matching_cluster_idx": 2}, {"solution": "def large_product(list1, list2, n):\n # Generate all possible products\n products = [x * y for x in list1 for y in list2]\n \n # Sort the products in descending order\n products.sort(reverse=True)\n \n # Return the first n largest products\n return products[:n]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n # Generate all possible products of elements from list1 and list2\n products = [x * y for x in list1 for y in list2]\n \n # Sort the list of products in descending order\n products.sort(reverse=True)\n \n # Return the first n elements from the sorted list\n return products[:n]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, num):\n # Generate all possible products from the two lists\n products = sorted([x * y for x in list1 for y in list2], reverse=True)[:num]\n return products", "matching_cluster_idx": 3}, {"solution": "def large_product(lst1, lst2, n):\n # Create a list to store the products\n products = []\n \n # Calculate the product of each possible pair and store it in the list\n for num1 in lst1:\n for num2 in lst2:\n products.append(num1 * num2)\n \n # Sort the products in descending order\n products.sort(reverse=True)\n \n # Return the first n products from the sorted list\n return products[:n]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n # Calculate all possible products from the two lists\n products = sorted([x * y for x in list1 for y in list2], reverse=True)\n \n # Return the first n products from the sorted list\n return products[:n]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n # Create a list of tuples containing the product of each pair of elements from the two lists\n products = [x * y for x in list1 for y in list2]\n \n # Sort the list of products in descending order\n products_sorted = sorted(products, reverse=True)\n \n # Return the first n elements from the sorted list\n return products_sorted[:n]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n # Create a list to store the products\n products = []\n \n # Calculate all possible products of elements from both lists\n for num1 in list1:\n for num2 in list2:\n products.append(num1 * num2)\n \n # Sort the list of products in descending order\n products.sort(reverse=True)\n \n # Return the first n products from the sorted list\n return products[:n]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n # Import the necessary module for heap operations\n from heapq import nlargest\n \n # Calculate all possible products of the elements from both lists\n products = [x * y for x in list1 for y in list2]\n \n # Find the n largest products using nlargest from the heapq module\n largest_n_products = nlargest(n, products)\n \n return largest_n_products", "matching_cluster_idx": 4}, {"solution": "def large_product(lst1, lst2, num):\n # Import the necessary function to get the largest elements\n from heapq import nlargest\n \n # Calculate all possible products\n products = [x * y for x in lst1 for y in lst2]\n \n # Use nlargest to find the 'num' largest products\n largest_products = nlargest(num, products)\n \n return largest_products", "matching_cluster_idx": 4}, {"solution": "def large_product(list1, list2, num):\n # Generate all possible products from the two lists\n products = sorted([x * y for x in list1 for y in list2], reverse=True)[:num]\n return products", "matching_cluster_idx": 3}, {"solution": "def large_product(lst1, lst2, n):\n # Generate all possible products between elements of lst1 and lst2\n all_products = [x * y for x in lst1 for y in lst2]\n \n # Sort the list of products in descending order\n all_products.sort(reverse=True)\n \n # Return the first n largest products\n return all_products[:n]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, num):\n # Generate all possible products by multiplying elements from both lists\n products = [x * y for x in list1 for y in list2]\n \n # Sort the products in descending order\n sorted_products = sorted(products, reverse=True)\n \n # Return the first 'num' largest products\n return sorted_products[:num]", "matching_cluster_idx": 3}, {"solution": "def large_product(lst1, lst2, n):\n # Create a list of tuples with the product and the corresponding indices\n products = [(a * b, i, j) for i, a in enumerate(lst1) for j, b in enumerate(lst2)]\n \n # Sort the list of products in descending order\n products.sort(reverse=True)\n \n # Extract the values of the top n products\n top_products = [products[i][0] for i in range(n)]\n \n return top_products", "matching_cluster_idx": 2}]}, "Mbpp/392": {"dps": 90.21126760563381, "dps_norm": 89.61538461538461, "pass@1": 66.0, "profiled": [{"solution": "def get_max_sum(n):\n # Create a dictionary to store the results of subproblems\n memo = {0: 0, 1: 1}\n \n def f(n):\n # Check if the result is already computed\n if n not in memo:\n # Compute the value and store it in the dictionary\n memo[n] = max(f(n // 2) + f(n // 3) + f(n // 4) + f(n // 5), n)\n return memo[n]\n \n return f(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n # Base case: if n is 0 or 1, return n\n if n == 0 or n == 1:\n return n\n \n # Memoization dictionary to store the results of subproblems\n memo = {0: 0, 1: 1}\n \n def f(m):\n # If the result is already computed, return it\n if m in memo:\n return memo[m]\n else:\n # Calculate the maximum sum using the given formula\n max_sum = max(f(m // 2) + f(m // 3) + f(m // 4) + f(m // 5), m)\n # Store the result in the dictionary\n memo[m] = max_sum\n return max_sum\n \n # Return the result for n\n return f(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n # Create a dictionary to store the results of subproblems\n memo = {0: 0, 1: 1, 2: 2, 3: 3, 4: 4, 5: 5}\n \n def f(n):\n # Return the result if it's already computed\n if n in memo:\n return memo[n]\n else:\n # Compute the result and store it in the dictionary\n memo[n] = max(f(n // 2) + f(n // 3) + f(n // 4) + f(n // 5), n)\n return memo[n]\n \n return f(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n # Create a cache to store previously computed results\n cache = {}\n\n def f(num):\n if num in cache:\n return cache[num]\n # Base case\n if num == 0:\n return 0\n # Calculate the maximum sum using the given equation\n max_sum = num\n max_sum = max(max_sum, f(num // 2) + f(num // 3) + f(num // 4) + f(num // 5))\n # Store the result in cache\n cache[num] = max_sum\n return max_sum\n\n return f(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n # Base case: if n is 0 or 1, return n\n if n <= 1:\n return n\n \n # Memoization to store computed values\n memo = [0] * (n + 1)\n \n def f(n):\n if n <= 1:\n return n\n # Return the stored value if already computed\n if memo[n] != 0:\n return memo[n]\n \n # Compute the maximum sum using the given equation\n memo[n] = max(f(n // 2) + f(n // 3) + f(n // 4) + f(n // 5), n)\n return memo[n]\n \n # Start the computation from the given number\n return f(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n # Create a dictionary to store already computed values\n memo = {}\n \n def f(n):\n # Check if the value is already computed\n if n in memo:\n return memo[n]\n # Base case\n if n == 0:\n return 0\n # Compute the value using the given equation\n max_sum = max(f(n // 2) + f(n // 3) + f(n // 4) + f(n // 5), n)\n # Store the computed value in the dictionary\n memo[n] = max_sum\n return max_sum\n \n # Start the recursion with the given number\n return f(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n # Base case: if n is 0 or 1, return n\n if n == 0 or n == 1:\n return n\n \n # Initialize the maximum sum to be the number itself\n max_sum = n\n \n # Recursively calculate the maximum sum for the given equation\n max_sum = max(max_sum, (get_max_sum(n // 2) + get_max_sum(n // 3) + get_max_sum(n // 4) + get_max_sum(n // 5)))\n \n return max_sum", "matching_cluster_idx": 3}, {"solution": "def get_max_sum(n):\n # Base case: if n is 0 or 1, return n\n if n == 0 or n == 1:\n return n\n \n # Dictionary to store previously computed results\n memo = {0: 0, 1: 1}\n \n def helper(x):\n # If the result is already computed, return it\n if x in memo:\n return memo[x]\n \n # Compute the result using the given equation\n result = max(x, helper(x // 2) + helper(x // 3) + helper(x // 4) + helper(x // 5))\n \n # Store the result in the dictionary\n memo[x] = result\n return result\n \n # Start the recursion with the initial value\n return helper(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n # Base case: if n is 0 or 1, the maximum sum is n\n if n <= 1:\n return n\n \n # Memoization dictionary to store previously computed values\n memo = {0: 0, 1: 1}\n \n def f(num):\n if num not in memo:\n memo[num] = max(f(num // 2) + f(num // 3) + f(num // 4) + f(num // 5), num)\n return memo[num]\n \n return f(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n # Base case: if n is 1 or less, return n\n if n <= 1:\n return n\n # Dictionary to store computed values for memoization\n memo = {0: 0, 1: 1}\n \n def f(x):\n if x not in memo:\n # Recursive call with memoization\n memo[x] = max(x, f(x // 2) + f(x // 3) + f(x // 4) + f(x // 5))\n return memo[x]\n \n return f(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n # Create a dictionary to store the results of subproblems\n memo = {0: 0, 1: 1, 2: 2, 3: 3, 4: 4, 5: 5}\n \n def f(n):\n # If the value is already computed, return it\n if n in memo:\n return memo[n]\n # Otherwise, compute the value and store it in memo\n memo[n] = max(f(n // 2) + f(n // 3) + f(n // 4) + f(n // 5), n)\n return memo[n]\n \n return f(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n # Create a dictionary to store computed results for memoization\n memo = {0: 0, 1: 1, 2: 2, 3: 3, 4: 4, 5: 5}\n \n def f(n):\n # If the result is already computed, return it\n if n in memo:\n return memo[n]\n else:\n # Compute the result and store it in the dictionary\n memo[n] = max(f(n // 2) + f(n // 3) + f(n // 4) + f(n // 5), n)\n return memo[n]\n \n return f(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n, memo={0: 0, 1: 1}):\n if n in memo:\n return memo[n]\n # Calculate the maximum sum using the given equation\n max_sum = max((get_max_sum(n // 2, memo) + get_max_sum(n // 3, memo) + \n get_max_sum(n // 4, memo) + get_max_sum(n // 5, memo)), n)\n # Store the result in memoization dictionary\n memo[n] = max_sum\n return max_sum", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n # Create a dictionary to store computed results for memoization\n memo = {0: 0, 1: 1, 2: 2, 3: 3, 4: 4, 5: 5}\n \n def f(num):\n # If the value is already computed, return it\n if num in memo:\n return memo[num]\n # Compute the value and store it in the memoization table\n memo[num] = max(num, f(num // 2) + f(num // 3) + f(num // 4) + f(num // 5))\n return memo[num]\n \n return f(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n # Cache to store previously computed results\n cache = {0: 0, 1: 1, 2: 2, 3: 3, 4: 4, 5: 5}\n \n def f(num):\n # If the result is already computed, return it\n if num in cache:\n return cache[num]\n \n # Calculate the maximum sum using the given equation\n max_sum = max(f(num // 2) + f(num // 3) + f(num // 4) + f(num // 5), num)\n \n # Store the computed result in the cache\n cache[num] = max_sum\n return max_sum\n \n # Start the recursive computation from the given number\n return f(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n # Create a cache to store already computed results\n memo = {}\n \n def f(n):\n # If the result is already computed, return it\n if n in memo:\n return memo[n]\n # Base case: if n is 0 or less, return 0\n if n <= 0:\n return 0\n # Recursive case: compute the maximum sum\n max_sum = n\n max_sum = max(max_sum, f(n // 2) + f(n // 3) + f(n // 4) + f(n // 5))\n # Store the result in the cache\n memo[n] = max_sum\n return max_sum\n \n # Call the recursive function and return the result\n return f(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n # Base case: if n is less than 1, return 0\n if n < 1:\n return 0\n # Base case: if n is 0 or 1, return n\n if n == 0 or n == 1:\n return n\n \n # Initialize the maximum sum with the current n\n max_sum = n\n \n # Calculate the sum using the given equation and recursively find the max for subproblems\n max_sum = max(max_sum, (get_max_sum(n // 2) + get_max_sum(n // 3) + get_max_sum(n // 4) + get_max_sum(n // 5)))\n \n return max_sum", "matching_cluster_idx": 3}, {"solution": "def get_max_sum(n):\n # Base case: if n is less than or equal to 0, return 0\n if n <= 0:\n return 0\n # Base case: if n is 1, return 1\n if n == 1:\n return 1\n \n # Calculate the maximum sum using the given equation\n max_sum = max(get_max_sum(n // 2) + get_max_sum(n // 3) + get_max_sum(n // 4) + get_max_sum(n // 5), n)\n \n return max_sum", "matching_cluster_idx": 3}, {"solution": "def get_max_sum(n):\n # Base case: if n is 0 or less, return 0\n if n <= 0:\n return 0\n \n # Use memoization to store previously computed values\n memo = {}\n \n def f(num):\n if num in memo:\n return memo[num]\n # Base case for recursion\n if num == 0:\n return 0\n # Calculate the value based on the given equation\n result = max(f(num // 2) + f(num // 3) + f(num // 4) + f(num // 5), num)\n # Store the result in memo dictionary\n memo[num] = result\n return result\n \n # Start the recursion with the given number n\n return f(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n # Base case: if n is 0 or less, return 0\n if n <= 0:\n return 0\n \n # Dictionary to store previously computed values for memoization\n memo = {0: 0, 1: 1}\n \n def helper(x):\n # If the value is already computed, return it\n if x in memo:\n return memo[x]\n # Otherwise, compute and memoize the value\n memo[x] = max(x, helper(x // 2) + helper(x // 3) + helper(x // 4) + helper(x // 5))\n return memo[x]\n \n # Call the helper function with the input number and return the result\n return helper(n)", "matching_cluster_idx": 12}]}, "Mbpp/395": {"dps": 93.85057471264368, "dps_norm": 74.375, "pass@1": 100.0, "profiled": [{"solution": "def first_non_repeating_character(input_string):\n # Create a dictionary to store the frequency of each character\n char_frequency = {}\n \n # First pass to count the frequency of each character\n for char in input_string:\n if char in char_frequency:\n char_frequency[char] += 1\n else:\n char_frequency[char] = 1\n \n # Second pass to find the first non-repeated character\n for char in input_string:\n if char_frequency[char] == 1:\n return char\n \n # If no non-repeated character is found, return None\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n # Dictionary to store the frequency of each character\n char_frequency = {}\n \n # Calculate the frequency of each character in the string\n for char in s:\n if char in char_frequency:\n char_frequency[char] += 1\n else:\n char_frequency[char] = 1\n \n # Find the first non-repeating character\n for char in s:\n if char_frequency[char] == 1:\n return char\n \n # If no non-repeating character is found, return None\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(input_string):\n # Dictionary to keep track of character counts and their first occurrence index\n char_map = {}\n \n # Iterate over the string to fill the char_map with counts and indices\n for index, char in enumerate(input_string):\n if char in char_map:\n char_map[char] = (char_map[char][0] + 1, -1) # Increment count\n else:\n char_map[char] = (1, index) # First occurrence\n \n # Find the first non-repeated character\n for _, (count, index) in char_map.items():\n if count == 1 and index != -1:\n return input_string[index]\n \n # If no non-repeated character is found, return None\n return None", "matching_cluster_idx": 4}, {"solution": "def first_non_repeating_character(input_string):\n # Create a dictionary to store the count of each character\n char_count = {}\n \n # Iterate over the string to populate the character count dictionary\n for char in input_string:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n \n # Iterate over the string again to find the first non-repeated character\n for char in input_string:\n if char_count[char] == 1:\n return char\n \n # If no non-repeated character is found, return None\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(input_string):\n # Dictionary to store count of each character\n char_count = {}\n \n # Count occurrence of each character in the string\n for char in input_string:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n \n # Find the first non-repeated character\n for char in input_string:\n if char_count[char] == 1:\n return char\n \n # If no non-repeated character is found, return None\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(input_string):\n # Create a dictionary to store the frequency of each character\n char_frequency = {}\n \n # Count the frequency of each character in the string\n for char in input_string:\n if char in char_frequency:\n char_frequency[char] += 1\n else:\n char_frequency[char] = 1\n \n # Find the first character with a frequency of 1\n for char in input_string:\n if char_frequency[char] == 1:\n return char\n \n # If no non-repeating character is found, return None\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n # Count the occurrence of each character in the string\n char_count = {}\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n \n # Find the first character with a count of 1\n for char in s:\n if char_count[char] == 1:\n return char\n \n # If no non-repeating character is found, return None\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(input_string):\n # Dictionary to store count of each character\n char_count = {}\n \n # Count the occurrence of each character in the string\n for char in input_string:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n \n # Finding the first non-repeating character\n for char in input_string:\n if char_count[char] == 1:\n return char\n \n # If no non-repeating character is found\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n char_count = {}\n \n # Count the occurrence of each character\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n \n # Find the first non-repeated character\n for char in s:\n if char_count[char] == 1:\n return char\n \n # If no non-repeated character is found, return None\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(input_string):\n # Dictionary to hold character counts\n char_count = {}\n \n # Count the occurrences of each character\n for char in input_string:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n \n # Find the first character with a count of 1\n for char in input_string:\n if char_count[char] == 1:\n return char\n \n # If no non-repeated character is found, return None\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(input_string):\n # Dictionary to keep track of character counts\n char_count = {}\n \n # First pass to count the occurrences of each character\n for char in input_string:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n \n # Second pass to find the first non-repeating character\n for char in input_string:\n if char_count[char] == 1:\n return char\n \n # If no non-repeating character is found, return None\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(input_string):\n # Create a dictionary to store the count of each character\n char_count = {}\n \n # Count the occurrences of each character in the string\n for char in input_string:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n \n # Find the first character with a count of 1\n for char in input_string:\n if char_count[char] == 1:\n return char\n \n # If no non-repeated character is found, return None\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(input_string):\n # Create a dictionary to store character counts\n char_count = {}\n \n # Count the occurrences of each character in the string\n for char in input_string:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n \n # Find the first character with a count of 1\n for char in input_string:\n if char_count[char] == 1:\n return char\n \n # If no non-repeated character is found, return None\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(input_string):\n # Dictionary to store the count of each character\n char_count = {}\n \n # First pass to count the occurrences of each character\n for char in input_string:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n \n # Second pass to find the first non-repeated character\n for char in input_string:\n if char_count[char] == 1:\n return char\n \n # If no non-repeated character is found, return None\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(input_string):\n # Dictionary to hold character counts\n char_count = {}\n \n # First pass to count the occurrences of each character\n for char in input_string:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n \n # Second pass to find the first non-repeating character\n for char in input_string:\n if char_count[char] == 1:\n return char\n \n # If no non-repeating character is found, return None\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(input_string):\n # Create a dictionary to store the count of each character\n char_count = {}\n \n # Iterate over the string to count the occurrences of each character\n for char in input_string:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n \n # Iterate over the string again to find the first non-repeated character\n for char in input_string:\n if char_count[char] == 1:\n return char\n \n # If no non-repeated character is found, return None\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(input_string):\n # Import the collections module for Counter\n from collections import Counter\n \n # Count the occurrences of each character in the string\n char_count = Counter(input_string)\n \n # Iterate over the string to find the first character with a count of 1\n for char in input_string:\n if char_count[char] == 1:\n return char\n \n # If no non-repeated character is found, return None\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(input_string):\n # Create a dictionary to store the count of each character\n char_count = {}\n \n # Count the occurrences of each character in the string\n for char in input_string:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n \n # Find the first character that appears only once\n for char in input_string:\n if char_count[char] == 1:\n return char\n \n # If no non-repeated character is found, return None\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(input_string):\n # Dictionary to keep track of character counts and their first occurrence\n char_count = {}\n char_order = []\n \n # Iterate over the string to populate char_count and char_order\n for char in input_string:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n char_order.append(char)\n \n # Find the first character that has a count of 1\n for char in char_order:\n if char_count[char] == 1:\n return char\n \n # If no non-repeating character is found, return None\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n # Create a dictionary to store character counts\n char_count = {}\n \n # Iterate through the string and count occurrences of each character\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n \n # Find the first non-repeated character\n for char in s:\n if char_count[char] == 1:\n return char\n \n # If no non-repeated character is found, return None\n return None", "matching_cluster_idx": 5}]}, "Mbpp/405": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def check_tuplex(test_tup, element):\n # Check if the element exists in the tuple\n return element in test_tup", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, element):\n # Check if the element exists in the tuple\n if element in tuplex:\n return True\n else:\n return False", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(test_tup, ele):\n # Check if the element exists in the tuple using the 'in' keyword\n if ele in test_tup:\n return True\n else:\n return False", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, element):\n # Check if the element exists in the tuple\n return element in tuplex", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(test_tup, elem):\n # Check if the element exists in the tuple\n if elem in test_tup:\n return True\n else:\n return False", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, element):\n # Check if the element exists in the tuple\n return element in tuplex", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, element):\n # Check if the element exists in the tuple\n return element in tuplex", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(test_tup, element):\n # Check if the element exists in the tuple\n return element in test_tup", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(test_tup, element):\n # Check if the element exists in the tuple\n if element in test_tup:\n return True\n else:\n return False", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, element):\n # Check if the element is in the tuple\n if element in tuplex:\n return True\n else:\n return False", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, element):\n # Check if the element exists in the tuple\n return element in tuplex", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(test_tup, element):\n # Check if the element exists in the tuple\n return element in test_tup", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(test_tup, element):\n # Check if the element exists in the tuple\n return element in test_tup", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(test_tup, element):\n # Check if the element exists in the tuple\n return element in test_tup", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(test_tup, element):\n # Check if the element exists in the tuple\n if element in test_tup:\n return True\n else:\n return False", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(test_tup, elem):\n # Check if the element exists in the tuple using 'in' keyword\n return elem in test_tup", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(test_tup, ele):\n # Check if the element exists in the tuple\n if ele in test_tup:\n return True\n else:\n return False", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(test_tup, element):\n # Check if the element exists in the tuple\n return element in test_tup", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, element):\n # Check if the element exists in the tuple\n return element in tuplex", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, element):\n # Check if the element exists in the tuple\n if element in tuplex:\n return True\n else:\n return False", "matching_cluster_idx": 3}]}, "Mbpp/414": {"dps": 91.5527950310559, "dps_norm": 93.88888888888889, "pass@1": 100.0, "profiled": [{"solution": "def overlapping(seq1, seq2):\n # Check if there is any common element between seq1 and seq2\n return not set(seq1).isdisjoint(seq2)", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n # Check if any element of seq2 exists in seq1\n return any(value in seq1 for value in seq2)", "matching_cluster_idx": 8}, {"solution": "def overlapping(seq1, seq2):\n # Check if there is any common value between seq1 and seq2\n return any(value in seq2 for value in seq1)", "matching_cluster_idx": 7}, {"solution": "def overlapping(sequence1, sequence2):\n # Check if any element of sequence1 is in sequence2\n return any(item in sequence2 for item in sequence1)", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n # Check if any element of seq1 is in seq2\n return any(item in seq2 for item in seq1)", "matching_cluster_idx": 7}, {"solution": "def overlapping(sequence1, sequence2):\n # Check if any element of sequence2 exists in sequence1\n return any(item in sequence1 for item in sequence2)", "matching_cluster_idx": 8}, {"solution": "def overlapping(sequence1, sequence2):\n # Check if any element in sequence2 is in sequence1\n return any(item in sequence1 for item in sequence2)", "matching_cluster_idx": 8}, {"solution": "def overlapping(seq1, seq2):\n # Check if any value in seq2 exists in seq1\n return any(val in seq1 for val in seq2)", "matching_cluster_idx": 8}, {"solution": "def overlapping(sequence1, sequence2):\n # Check if there is any common element between the two sequences\n return bool(set(sequence1) & set(sequence2))", "matching_cluster_idx": 5}, {"solution": "def overlapping(seq1, seq2):\n # Check if any element in seq1 is in seq2\n for element in seq1:\n if element in seq2:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n # Check if any element of seq2 is in seq1\n return any(val in seq1 for val in seq2)", "matching_cluster_idx": 8}, {"solution": "def overlapping(sequence1, sequence2):\n # Check if any element in sequence2 is in sequence1\n for element in sequence2:\n if element in sequence1:\n return True\n return False", "matching_cluster_idx": 8}, {"solution": "def overlapping(sequence1, sequence2):\n # Check if any value in sequence2 exists in sequence1\n for value in sequence2:\n if value in sequence1:\n return True\n return False", "matching_cluster_idx": 8}, {"solution": "def overlapping(seq1, seq2):\n # Check if any element in seq2 exists in seq1\n return any(item in seq1 for item in seq2)", "matching_cluster_idx": 8}, {"solution": "def overlapping(sequence1, sequence2):\n # Check if any value in sequence2 exists in sequence1\n return bool(set(sequence1) & set(sequence2))", "matching_cluster_idx": 5}, {"solution": "def overlapping(sequence1, sequence2):\n # Check if any element in sequence2 is in sequence1\n for element in sequence2:\n if element in sequence1:\n return True\n return False", "matching_cluster_idx": 8}, {"solution": "def overlapping(seq1, seq2):\n # Check if any element in seq2 exists in seq1\n for element in seq2:\n if element in seq1:\n return True\n return False", "matching_cluster_idx": 8}, {"solution": "def overlapping(sequence1, sequence2):\n # Check if any value in sequence2 exists in sequence1\n for value in sequence2:\n if value in sequence1:\n return True\n return False", "matching_cluster_idx": 8}, {"solution": "def overlapping(seq1, seq2):\n # Check if any element in seq2 exists in seq1\n return any(item in seq1 for item in seq2)", "matching_cluster_idx": 8}, {"solution": "def overlapping(sequence1, sequence2):\n # Check if any element in sequence2 exists in sequence1\n for element in sequence2:\n if element in sequence1:\n return True\n return False", "matching_cluster_idx": 8}]}, "Mbpp/421": {"dps": 59.17695473251029, "dps_norm": 84.28571428571428, "pass@1": 80.0, "profiled": [{"solution": "def concatenate_tuple(input_tuple, delimiter=\"-\"):\n # Join all elements of the tuple using the delimiter\n result = delimiter.join(str(item) for item in input_tuple)\n return result", "matching_cluster_idx": 4}, {"solution": "def concatenate_tuple(tup, delimiter='-'):\n # Join tuple elements with the specified delimiter\n result = delimiter.join(map(str, tup))\n return result", "matching_cluster_idx": 6}, {"solution": "def concatenate_tuple(tup, delimiter='-'):\n \"\"\"\n Concatenate each element of tuple by the delimiter.\n \n Args:\n tup (tuple): The input tuple containing elements to be concatenated.\n delimiter (str): The string to use for delimiting elements.\n \n Returns:\n str: The concatenated string with elements from the tuple separated by the delimiter.\n \"\"\"\n return delimiter.join(map(str, tup))", "matching_cluster_idx": 5}, {"solution": "def concatenate_tuple(tup, delimiter=\"-\"):\n # Use the join method to concatenate tuple elements with the delimiter\n return delimiter.join(str(item) for item in tup)", "matching_cluster_idx": 4}, {"solution": "def concatenate_tuple(tup, delimiter=\"-\"):\n # Convert each element in the tuple to string and join them with the delimiter\n result = delimiter.join(map(str, tup))\n return result", "matching_cluster_idx": 6}, {"solution": "def concatenate_tuple(tup, delimiter='-'):\n \"\"\"\n Concatenate each element of tuple by the delimiter.\n \n Args:\n tup (tuple): Input tuple.\n delimiter (str): Delimiter to join tuple elements. Default is '-'.\n \n Returns:\n str: Concatenated string of tuple elements.\n \"\"\"\n return delimiter.join(map(str, tup))", "matching_cluster_idx": 5}, {"solution": "def concatenate_tuple(tup, delimiter='-'):\n # Join all elements in the tuple using the specified delimiter\n result = delimiter.join(str(item) for item in tup)\n return result", "matching_cluster_idx": 4}, {"solution": "def concatenate_tuple(tpl, delimiter=\"-\"):\n \"\"\"\n Concatenate each element of tuple by the delimiter.\n\n Args:\n tpl (tuple): A tuple of elements to be concatenated.\n delimiter (str): The delimiter to use for concatenation. Defaults to '-'.\n\n Returns:\n str: A string with each element of the tuple concatenated by the delimiter.\n\n Example:\n >>> concatenate_tuple((\"ID\", \"is\", 4, \"UTS\"))\n 'ID-is-4-UTS'\n \"\"\"\n # Convert all elements to string and join them with the delimiter\n result = delimiter.join(map(str, tpl))\n return result", "matching_cluster_idx": 6}, {"solution": "def concatenate_tuple(tup, delimiter=\"-\"):\n \"\"\"\n Concatenate each element of the tuple using the specified delimiter.\n\n Args:\n tup (tuple): The tuple to be concatenated.\n delimiter (str): The string to insert between tuple elements. Default is \"-\".\n\n Returns:\n str: The concatenated string.\n \"\"\"\n return delimiter.join(map(str, tup))", "matching_cluster_idx": 5}, {"solution": "def concatenate_tuple(tup, delimiter=\"-\"):\n # Join the elements of the tuple using the specified delimiter\n result = delimiter.join(map(str, tup))\n return result", "matching_cluster_idx": 5}, {"solution": "def concatenate_tuple(tup, delimiter=\"-\"):\n \"\"\"\n Concatenate each element of tuple by the delimiter.\n \n Args:\n tup (tuple): The input tuple containing elements to be concatenated.\n delimiter (str): The delimiter used to concatenate tuple elements.\n \n Returns:\n str: A string with tuple elements concatenated by the delimiter.\n \"\"\"\n return delimiter.join(str(item) for item in tup)", "matching_cluster_idx": 4}, {"solution": "def concatenate_tuple(tup, delimiter=\"-\"):\n \"\"\"\n Concatenates each element of a tuple by the specified delimiter.\n\n Args:\n tup: A tuple containing elements to be concatenated.\n delimiter: A string used to separate the elements in the resulting string.\n\n Returns:\n A string with each element of the tuple concatenated by the delimiter.\n\n Example:\n >>> concatenate_tuple((\"ID\", \"is\", 4, \"UTS\"))\n 'ID-is-4-UTS'\n \"\"\"\n return delimiter.join(map(str, tup))", "matching_cluster_idx": 6}, {"solution": "def concatenate_tuple(tup, delimiter=\"-\"):\n \"\"\"\n Concatenate each element of tuple by the delimiter.\n\n Args:\n tup (tuple): The input tuple.\n delimiter (str): The delimiter to use between tuple elements.\n\n Returns:\n str: The concatenated string of tuple elements.\n \"\"\"\n return delimiter.join(str(item) for item in tup)", "matching_cluster_idx": 4}, {"solution": "def concatenate_tuple(tup, delimiter='-'):\n # Join each element of the tuple with the specified delimiter\n result = delimiter.join(map(str, tup))\n return result", "matching_cluster_idx": 5}, {"solution": "def concatenate_tuple(tup, delimiter='-'):\n # Convert each element in the tuple to string and join them with the delimiter\n return delimiter.join(map(str, tup))", "matching_cluster_idx": 5}, {"solution": "def concatenate_tuple(tpl):\n # Convert each element in the tuple to string and join them with the delimiter '-'\n result = \"-\".join(str(item) for item in tpl)\n return result", "matching_cluster_idx": 4}, {"solution": "def concatenate_tuple(input_tuple):\n # Convert each element to string and join them with the delimiter '-'\n result = '-'.join(str(item) for item in input_tuple)\n return result", "matching_cluster_idx": 4}, {"solution": "def concatenate_tuple(tup, delimiter=\"-\"):\n # Join each element of the tuple with the specified delimiter\n result = delimiter.join(str(item) for item in tup)\n return result", "matching_cluster_idx": 4}, {"solution": "def concatenate_tuple(tup, delimiter='-'):\n # Join the elements of the tuple using the specified delimiter\n return delimiter.join(map(str, tup))", "matching_cluster_idx": 6}, {"solution": "def concatenate_tuple(tup, delimiter=\"-\"):\n # Join tuple elements with the specified delimiter\n result = delimiter.join(map(str, tup))\n return result", "matching_cluster_idx": 6}]}, "Mbpp/424": {"dps": 83.06859205776173, "dps_norm": 93.0, "pass@1": 77.0, "profiled": [{"solution": "def extract_rear(input_tuple):\n # Use a list comprehension to extract the last character of each string in the tuple\n return [s[-1] for s in input_tuple]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(input_tuple):\n # Use a list comprehension to extract the last character of each string in the tuple\n return [s[-1] for s in input_tuple]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(strings_tuple):\n # Extract the last character of each string in the tuple\n rear_elements = tuple(s[-1] for s in strings_tuple)\n # Convert the tuple to a list and return\n return list(rear_elements)", "matching_cluster_idx": 3}, {"solution": "def extract_rear(input_tuple):\n # Extract the last character of each string in the tuple\n rear_elements = tuple(s[-1] for s in input_tuple)\n # Convert the tuple to a list and return it\n return list(rear_elements)", "matching_cluster_idx": 3}, {"solution": "def extract_rear(strings):\n # Extract the last character of each string in the tuple\n rear_elements = tuple(s[-1] for s in strings)\n # Convert the tuple to a list and return it\n return list(rear_elements)", "matching_cluster_idx": 3}, {"solution": "def extract_rear(tup):\n # Use list comprehension to iterate through each string in the tuple and\n # extract the last character (rear index element) of each string\n return [s[-1] for s in tup]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(strings_tuple):\n # Use list comprehension to extract the last character of each string in the tuple\n return [s[-1] for s in strings_tuple]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(tup):\n # Extract the last character of each string in the tuple\n rear_elements = tuple(s[-1] for s in tup)\n # Convert the tuple to a list before returning\n return list(rear_elements)", "matching_cluster_idx": 3}, {"solution": "def extract_rear(tup):\n # Extract the last character of each string in the tuple\n result = [s[-1] for s in tup]\n return result", "matching_cluster_idx": 4}, {"solution": "def extract_rear(input_tuple):\n # Use list comprehension to extract the last character of each string in the tuple\n return [s[-1] for s in input_tuple]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(tup):\n # Use a list comprehension to extract the last character of each string in the tuple\n return [s[-1] for s in tup]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(input_tuple):\n # Use a list comprehension to extract the last character of each string\n return [s[-1] for s in input_tuple]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(tup):\n # Use a list comprehension to extract the last character of each string in the tuple\n return [s[-1] for s in tup]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(tup):\n # Use list comprehension to iterate through each string in the tuple and extract the last character\n return [s[-1] for s in tup]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(input_tuple):\n # Extract the last character of each string in the tuple\n result = [s[-1] for s in input_tuple]\n return result", "matching_cluster_idx": 4}, {"solution": "def extract_rear(input_tuple):\n # Extract the rear index element (i.e., the last character) of each string in the tuple\n rear_elements = tuple(s[-1] for s in input_tuple)\n \n # Convert the tuple of elements back to a list before returning\n return list(rear_elements)", "matching_cluster_idx": 3}, {"solution": "def extract_rear(input_tuple):\n # Extract the last character of each string in the tuple\n rear_elements = tuple(s[-1] for s in input_tuple)\n # Convert the tuple of characters back to a list\n return list(rear_elements)", "matching_cluster_idx": 3}, {"solution": "def extract_rear(strings_tuple):\n # Use a list comprehension to get the last character of each string\n return [s[-1] for s in strings_tuple]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(input_tuple):\n # Use a list comprehension to extract the last character of each string in the tuple\n rear_elements = [s[-1] for s in input_tuple]\n return rear_elements", "matching_cluster_idx": 4}, {"solution": "def extract_rear(strings):\n # Extract the rear index (last character) of each string in the tuple\n rear_elements = tuple(s[-1] for s in strings)\n # Convert the tuple to a list and return it\n return list(rear_elements)", "matching_cluster_idx": 3}]}, "Mbpp/425": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def count_element_in_list(lst, element):\n count = 0\n for sublist in lst:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, element):\n count = 0\n # Iterate through each sublist in the list\n for sublist in lst:\n # Check if the element is in the current sublist\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, element):\n count = 0\n for sublist in lst:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, element):\n count = 0\n # Iterate through each sublist in the list\n for sublist in lst:\n # Check if the element is in the current sublist\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, element):\n # Initialize counter\n count = 0\n \n # Iterate through each sublist in the list\n for sublist in lst:\n # Check if the element is in the current sublist\n if element in sublist:\n # Increment the counter if the element is found\n count += 1\n \n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, element):\n count = 0\n for sublist in lst:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, element):\n # Initialize a counter to keep track of the occurrences\n count = 0\n \n # Iterate through each sublist in the main list\n for sublist in lst:\n # If the element is in the current sublist, increment the counter\n if element in sublist:\n count += 1\n \n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, element):\n count = 0\n for sublist in lst:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, element):\n count = 0\n for sublist in lst:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, element):\n count = 0\n for sublist in lst:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, element):\n count = 0\n # Iterate through each sublist in the main list\n for sublist in lst:\n # Check if the element is in the current sublist\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, element):\n count = 0\n for sublist in lst:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, element):\n count = 0\n for sublist in lst:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, element):\n count = 0\n # Iterate through each sublist in the list\n for sublist in lst:\n # Check if the element is in the current sublist\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, element):\n count = 0\n for sublist in lst:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, element):\n count = 0\n # Iterate through each sublist in the list\n for sublist in lst:\n # Check if the element is in the current sublist\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, element):\n count = 0\n for sublist in lst:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, element):\n # Initialize a counter to keep track of occurrences\n count = 0\n \n # Iterate through each sublist in the main list\n for sublist in lst:\n # Check if the element is in the current sublist\n if element in sublist:\n # Increment the counter if the element is found\n count += 1\n \n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, element):\n count = 0\n for sublist in lst:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, element):\n count = 0\n # Iterate through each sublist in the list\n for sublist in lst:\n # Check if the element is in the current sublist\n if element in sublist:\n # Increment count if the element is found\n count += 1\n return count", "matching_cluster_idx": 4}]}, "Mbpp/428": {"dps": 84.29752066115702, "dps_norm": 55.55555555555556, "pass@1": 100.0, "profiled": [{"solution": "def shell_sort(arr):\n # Start with a big gap, then reduce the gap\n n = len(arr)\n gap = n // 2\n \n # Gap 'gap' must be greater than 0\n while gap > 0:\n # Do a gapped insertion sort for this gap size.\n # The first gap elements arr[0..gap-1] are already in gapped order\n # keep adding one more element until the entire array is gap sorted\n for i in range(gap, n):\n temp = arr[i]\n # shift earlier gap-sorted elements up until the correct location for arr[i] is found\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n # put temp (the original arr[i]) in its correct location\n arr[j] = temp\n # reduce the gap for the next element\n gap //= 2\n \n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n # Start with a big gap, then reduce the gap\n n = len(arr)\n gap = n // 2 # Initial gap size\n \n # Do a gapped insertion sort for this gap size.\n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n # Shift earlier gap-sorted elements up until the correct location for arr[i] is found\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n # Put temp (the original arr[i]) in its correct location\n arr[j] = temp\n # Reduce the gap for the next element\n gap //= 2\n \n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n # Start with a big gap, then reduce the gap\n n = len(arr)\n gap = n // 2\n \n # Do a gapped insertion sort for this gap size.\n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n # Shift earlier gap-sorted elements up until the correct location for arr[i] is found\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n # Put temp (the original arr[i]) in its correct location\n arr[j] = temp\n # Reduce the gap for the next element\n gap //= 2\n \n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2\n \n # Start with a big gap, then reduce the gap\n while gap > 0:\n # Do a gapped insertion sort for this gap size.\n # The first gap elements arr[0..gap-1] are already in gapped order\n # keep adding one more element until the entire array is gap sorted\n for i in range(gap, n):\n temp = arr[i]\n # shift earlier gap-sorted elements up until the correct location for arr[i] is found\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n # put temp (the original arr[i]) in its correct location\n arr[j] = temp\n gap //= 2\n \n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n # Start with a large gap, then reduce the gap\n n = len(arr)\n gap = n // 2\n \n # Gap 'gap' must be greater than 0\n while gap > 0:\n # Do a gapped insertion sort for this gap size.\n for i in range(gap, n):\n temp = arr[i]\n j = i\n # Shift earlier gap-sorted elements up until the correct location for arr[i] is found\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n # Put temp (the original arr[i]) in its correct location\n arr[j] = temp\n # Reduce the gap for the next element\n gap //= 2\n \n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2\n \n # Start with a big gap, then reduce the gap\n while gap > 0:\n # Do a gapped insertion sort for this gap size.\n # The first gap elements arr[0..gap-1] are already in gapped order\n # keep adding one more element until the entire array is gap sorted\n for i in range(gap, n):\n temp = arr[i]\n # shift earlier gap-sorted elements up until the correct location\n # for arr[i] is found\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n # put temp (the original arr[i]) in its correct location\n arr[j] = temp\n gap //= 2\n \n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2 # Initialize the gap size to half of the array length\n \n # Start with a big gap, then reduce the gap\n while gap > 0:\n # Do a gapped insertion sort for this gap size.\n # The first gap elements arr[0..gap-1] are already in gapped order\n # keep adding one more element until the entire array is gap sorted\n for i in range(gap, n):\n temp = arr[i]\n j = i\n # Shift earlier gap-sorted elements up until the correct location for arr[i] is found\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n # Put temp (the original arr[i]) in its correct location\n arr[j] = temp\n gap //= 2 # Reduce the gap for the next element\n \n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n n = len(arr)\n # Start with a big gap, then reduce the gap\n gap = n // 2\n \n # Gap 'gap' must be greater than 0\n while gap > 0:\n # Do a gapped insertion sort for this gap size.\n for i in range(gap, n):\n # add arr[i] to the elements that have been gap sorted\n temp = arr[i]\n j = i\n # shift earlier gap-sorted elements up until the correct location for arr[i] is found\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n # put temp (the original arr[i]) in its correct location\n arr[j] = temp\n # Reduce the gap for the next element\n gap //= 2\n \n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n # Start with a big gap, then reduce the gap\n n = len(arr)\n gap = n // 2 # Initialize the gap size to half of the array length\n \n # Gap 'gap' must be greater than 0\n while gap > 0:\n # Do a gapped insertion sort for this gap size.\n for i in range(gap, n):\n # add arr[i] to the elements that have been gap sorted\n temp = arr[i]\n j = i\n # shift earlier gap-sorted elements up until the correct location for arr[i] is found\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n # put temp (the original arr[i]) in its correct location\n arr[j] = temp\n # Reduce the gap for the next element\n gap //= 2\n \n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n # Start with a big gap, then reduce the gap\n n = len(arr)\n gap = n // 2\n \n # Gap 'gap' must be greater than 0\n while gap > 0:\n # Do a gapped insertion sort for this gap size.\n # The first gap elements arr[0..gap-1] are already in gapped order\n # keep adding one more element until the entire array is gap sorted\n for i in range(gap, n):\n temp = arr[i]\n # Shift earlier gap-sorted elements up until the correct location for arr[i] is found\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n # Put temp (the original arr[i]) in its correct location\n arr[j] = temp\n gap //= 2\n \n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2 # Initialize the gap.\n \n # Start with a big gap, then reduce the gap until it is 1\n while gap > 0:\n # Do a gapped insertion sort for this gap size.\n # The first gap elements arr[0..gap-1] are already in gapped order\n # keep adding one more element until the entire array is gap sorted\n for i in range(gap, n):\n temp = arr[i]\n # shift earlier gap-sorted elements up until the correct location for arr[i] is found\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n # put temp (the original arr[i]) in its correct location\n arr[j] = temp\n gap //= 2 # Reduce the gap for the next element\n\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2 # Initialize the gap size to half of the list length\n \n # Start with a big gap, then reduce the gap\n while gap > 0:\n # Do a gapped insertion sort for this gap size.\n # The first gap elements arr[0..gap-1] are already in gapped order\n # keep adding one more element until the entire array is gap sorted\n for i in range(gap, n):\n temp = arr[i]\n # shift earlier gap-sorted elements up until the correct location for arr[i] is found\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n # put temp (the original arr[i]) in its correct location\n arr[j] = temp\n gap //= 2 # Reduce the gap for the next element\n\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2 # Initial gap size\n \n # Start with a big gap, then reduce the gap\n while gap > 0:\n # Do a gapped insertion sort for this gap size.\n # The first gap elements arr[0..gap-1] are already in gapped order\n # keep adding one more element until the entire array is gap sorted\n for i in range(gap, n):\n temp = arr[i]\n # shift earlier gap-sorted elements up until the correct location\n # for arr[i] is found\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n # put temp (the original arr[i]) in its correct location\n arr[j] = temp\n gap //= 2 # Reduce the gap for the next element\n \n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n n = len(arr)\n # Start with a large gap, then reduce the gap\n gap = n // 2\n \n # Perform a gapped insertion sort for this gap size.\n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n # Shift earlier gap-sorted elements up until the correct location for arr[i] is found\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n # Put temp (the original arr[i]) in its correct location\n arr[j] = temp\n # Reduce the gap for the next element\n gap //= 2\n \n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2 # Initialize the gap size to half of the array length\n \n # Start with a big gap, then reduce the gap\n while gap > 0:\n # Do a gapped insertion sort for this gap size.\n # The first gap elements arr[0..gap-1] are already in gapped order\n # keep adding one more element until the entire array is gap sorted\n for i in range(gap, n):\n temp = arr[i]\n j = i\n # Shift earlier gap-sorted elements up until the correct location\n # for arr[i] is found\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n # Put temp (the original arr[i]) in its correct location\n arr[j] = temp\n gap //= 2 # Reduce the gap for the next element\n \n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2 # Initialize the gap size\n \n # Start with a big gap, then reduce the gap\n while gap > 0:\n # Do a gapped insertion sort for this gap size.\n # The first gap elements arr[0..gap-1] are already in gapped order\n # keep adding one more element until the entire array is gap sorted\n for i in range(gap, n):\n temp = arr[i]\n j = i\n # Shift earlier gap-sorted elements up until the correct location for arr[i] is found\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n # Put temp (the original arr[i]) in its correct location\n arr[j] = temp\n gap //= 2 # Reduce the gap for the next element\n \n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2 # Initialize the gap\n \n # Start with a big gap, then reduce the gap\n while gap > 0:\n # Do a gapped insertion sort for this gap size.\n # The first gap elements arr[0..gap-1] are already in gapped order\n # keep adding one more element until the entire array is gap sorted\n for i in range(gap, n):\n temp = arr[i]\n # Shift earlier gap-sorted elements up until the correct location\n # for arr[i] is found\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n # Put temp (the original arr[i]) in its correct location\n arr[j] = temp\n gap //= 2 # Reduce the gap for the next element\n\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2 # Initialize the gap size to half of the array length\n \n # Start with a big gap, then reduce the gap\n while gap > 0:\n # Do a gapped insertion sort for this gap size.\n # The first gap elements arr[0..gap-1] are already in gapped order\n # keep adding one more element until the entire array is gap sorted\n for i in range(gap, n):\n temp = arr[i]\n # Shift earlier gap-sorted elements up until the correct location\n # for arr[i] is found\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n # Put temp (the original arr[i]) in its correct location\n arr[j] = temp\n gap //= 2 # Reduce the gap for the next element\n \n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n n = len(arr)\n # Start with a large gap, then reduce the gap\n gap = n // 2\n \n # Gap 'gap' must be greater than 0\n while gap > 0:\n # Do a gapped insertion sort for this gap size.\n # The first gap elements arr[0..gap-1] are already in gapped order\n # keep adding one more element until the entire array is gap sorted\n for i in range(gap, n):\n temp = arr[i]\n # shift earlier gap-sorted elements up until the correct location for arr[i] is found\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n # put temp (the original arr[i]) in its correct location\n arr[j] = temp\n # Reduce the gap for the next element\n gap //= 2\n \n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2 # Initial gap size\n \n # Start with a big gap, then reduce the gap\n while gap > 0:\n # Do a gapped insertion sort for this gap size.\n for i in range(gap, n):\n temp = arr[i]\n j = i\n # Shift earlier gap-sorted elements up until the correct location for arr[i] is found\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n # Put temp (the original arr[i]) in its correct location\n arr[j] = temp\n gap //= 2 # Reduce the gap for the next element\n \n return arr", "matching_cluster_idx": 4}]}, "Mbpp/433": {"dps": 84.09574468085107, "dps_norm": 89.0, "pass@1": 84.0, "profiled": [{"solution": "def check_greater(arr, num):\n \"\"\"\n Check if the given number is greater than all elements in the array.\n \n :param arr: List of integers\n :param num: Integer to compare with elements of the array\n :return: Boolean indicating if num is greater than all elements in arr\n \"\"\"\n # Iterate through the array to check if num is greater than all elements\n for element in arr:\n if element >= num:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def check_greater(arr, number):\n \"\"\"\n Check if the given number is greater than all elements in the array.\n \n Args:\n arr : list of int\n The array of integers to compare against.\n number : int\n The number to check if it's greater than all elements in the array.\n \n Returns:\n bool\n True if the number is greater than all elements in the array, False otherwise.\n \"\"\"\n for element in arr:\n if number <= element:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def check_greater(array, number):\n # Check if the number is greater than all elements in the array\n for element in array:\n if number <= element:\n return False\n return True", "matching_cluster_idx": 3}, {"solution": "def check_greater(arr, num):\n # Check if the given number is greater than all elements in the array\n for element in arr:\n if num <= element:\n return False\n return True", "matching_cluster_idx": 3}, {"solution": "def check_greater(arr, num):\n # Check if the number is greater than all elements in the array\n for element in arr:\n if num <= element:\n return False\n return True", "matching_cluster_idx": 3}, {"solution": "def check_greater(arr, num):\n # Check if the given number is greater than all elements in the array\n for element in arr:\n if num <= element:\n return False\n return True", "matching_cluster_idx": 3}, {"solution": "def check_greater(arr, num):\n # Check if any element in the array is greater than or equal to the num\n for element in arr:\n if element >= num:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def check_greater(array, number):\n # Check if any element in the array is greater than or equal to the number\n for element in array:\n if element >= number:\n return False\n # If the loop completes without returning False, the number is greater than all elements\n return True", "matching_cluster_idx": 4}, {"solution": "def check_greater(arr, num):\n \"\"\"\n Checks if the given number is greater than all the elements in the array.\n \n Args:\n arr : List[int] - The list of integers to compare against.\n num : int - The number to check if it is greater than all elements in the list.\n \n Returns:\n bool - True if the number is greater than all elements in the array, False otherwise.\n \"\"\"\n # Check if any element in the array is greater than or equal to the number\n return all(element < num for element in arr)", "matching_cluster_idx": 2}, {"solution": "def check_greater(array, number):\n # Check if the number is greater than all elements in the array\n for element in array:\n if element >= number:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def check_greater(arr, num):\n # Iterate through each element in the array\n for element in arr:\n # Check if any element in the array is greater than or equal to the number\n if element >= num:\n return False\n # If the loop completes without returning False, the number is greater than all elements\n return True", "matching_cluster_idx": 4}, {"solution": "def check_greater(arr, num):\n # Check if the given number is greater than all elements in the array\n for element in arr:\n if element >= num:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def check_greater(arr, num):\n # Check if any element in the array is greater than or equal to the num\n for element in arr:\n if element >= num:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def check_greater(arr, num):\n # Check if the given number is greater than all elements in the array\n for element in arr:\n if num <= element:\n return False\n return True", "matching_cluster_idx": 3}, {"solution": "def check_greater(arr, num):\n # Check if any element in the array is greater than or equal to the num\n for element in arr:\n if element >= num:\n return False\n # If the loop completes without returning False, num is greater than all elements\n return True", "matching_cluster_idx": 4}, {"solution": "def check_greater(arr, num):\n # Check if any element in the array is greater than or equal to num\n for element in arr:\n if element >= num:\n return False\n # If no element is greater than or equal to num, return True\n return True", "matching_cluster_idx": 4}, {"solution": "def check_greater(array, number):\n \"\"\"\n Check if the entered number is greater than all elements of the given array.\n \n Args:\n array (list): A list of integers.\n number (int): An integer to compare against all elements in the array.\n \n Returns:\n bool: True if the number is greater than all elements in the array, False otherwise.\n \"\"\"\n # Iterate through each element in the array\n for element in array:\n # If any element is greater than or equal to the number, return False\n if element >= number:\n return False\n # If all elements are less than the number, return True\n return True", "matching_cluster_idx": 4}, {"solution": "def check_greater(arr, number):\n # Check if the number is greater than every element in the array\n return all(number > x for x in arr)", "matching_cluster_idx": 2}, {"solution": "def check_greater(arr, num):\n # Check if the given number is greater than all elements in the array\n for element in arr:\n if num <= element:\n return False\n return True", "matching_cluster_idx": 3}, {"solution": "def check_greater(arr, num):\n # Check if the given number is greater than all elements in the array\n for element in arr:\n if num <= element:\n return False\n return True", "matching_cluster_idx": 3}]}, "Mbpp/437": {"dps": 80.88235294117648, "dps_norm": 50.0, "pass@1": 69.0, "profiled": [{"solution": "def remove_odd(input_string):\n # Create an empty string to store the result\n result_string = ''\n # Iterate over the string, taking every second character (skipping odd indices)\n for i in range(1, len(input_string) + 1):\n if i % 2 == 0:\n result_string += input_string[i-1]\n return result_string", "matching_cluster_idx": 0}, {"solution": "def remove_odd(s):\n # Initialize an empty string to hold the result\n result = ''\n # Iterate over the string, taking every second character (starting from index 1)\n for i in range(1, len(s), 2):\n result += s[i]\n return result", "matching_cluster_idx": 1}, {"solution": "def remove_odd(input_string):\n # Construct a new string with only the characters at even indices\n result_string = input_string[1::2]\n return result_string", "matching_cluster_idx": 3}, {"solution": "def remove_odd(s):\n # Initialize an empty string to hold the result\n result = \"\"\n \n # Iterate over the characters in the string, starting from index 1\n # with a step of 2 to get the odd-indexed characters\n for i in range(1, len(s), 2):\n result += s[i]\n \n return result", "matching_cluster_idx": 1}, {"solution": "def remove_odd(s):\n # Use a generator expression to filter out characters at odd indices\n return ''.join(s[i] for i in range(1, len(s), 2))", "matching_cluster_idx": 2}, {"solution": "def remove_odd(s):\n # Construct a new string by iterating over the even-indexed characters\n result = s[1::2]\n return result", "matching_cluster_idx": 3}, {"solution": "def remove_odd(s):\n # Initialize an empty string to store even-indexed characters\n result = ''\n \n # Iterate over the string, starting from index 1 and stepping by 2\n for i in range(1, len(s) + 1):\n if i % 2 == 0:\n result += s[i - 1]\n \n return result", "matching_cluster_idx": 0}, {"solution": "def remove_odd(s):\n # Initialize an empty string to store the result\n result = ''\n \n # Iterate over the characters in the string, taking every second character starting from index 1\n for i in range(1, len(s), 2):\n result += s[i]\n \n return result", "matching_cluster_idx": 1}, {"solution": "def remove_odd(s):\n # Initialize an empty string to store the result\n result = \"\"\n \n # Iterate over the string, considering every second character (starting from the second character)\n for i in range(1, len(s), 2):\n result += s[i]\n \n return result", "matching_cluster_idx": 1}, {"solution": "def remove_odd(text):\n # Use a list comprehension to iterate over every second character (even indices)\n result = ''.join([text[i] for i in range(len(text)) if i % 2 == 1])\n return result", "matching_cluster_idx": 1}, {"solution": "def remove_odd(s):\n # Using list comprehension to filter out every other character starting from index 1\n result = ''.join([s[i] for i in range(1, len(s), 2)])\n return result", "matching_cluster_idx": 2}, {"solution": "def remove_odd(s):\n # Using list comprehension to filter out characters at odd indices\n return ''.join(s[i] for i in range(len(s)) if i % 2 == 1)", "matching_cluster_idx": 0}, {"solution": "def remove_odd(s):\n # Initialize an empty string to store even-indexed characters\n result = ''\n # Loop through the string, considering characters at even indices (0, 2, 4, ...)\n for i in range(1, len(s) + 1):\n if i % 2 == 0:\n result += s[i - 1]\n return result", "matching_cluster_idx": 0}, {"solution": "def remove_odd(s):\n # Initialize an empty string to store the result\n result = \"\"\n # Iterate over the string, taking every second character starting from index 1\n for i in range(1, len(s), 2):\n result += s[i]\n return result", "matching_cluster_idx": 1}, {"solution": "def remove_odd(s):\n # Use string slicing to get characters at even indices\n return s[1::2]", "matching_cluster_idx": 4}, {"solution": "def remove_odd(s):\n # Use string slicing to get characters at even indices\n return s[1::2]", "matching_cluster_idx": 4}, {"solution": "def remove_odd(s):\n # Use list comprehension to filter out characters at odd indices\n result = s[1::2]\n return result", "matching_cluster_idx": 3}, {"solution": "def remove_odd(s):\n # Initialize an empty string to hold even-positioned characters\n result = \"\"\n # Loop through the string, considering only characters at even positions (0-indexed)\n for i in range(1, len(s) + 1):\n if i % 2 == 0:\n result += s[i-1]\n return result", "matching_cluster_idx": 0}, {"solution": "def remove_odd(s):\n # Construct the resulting string by including only characters at even indices\n result = s[1::2]\n return result", "matching_cluster_idx": 3}, {"solution": "def remove_odd(s):\n # Create an empty string to store even-indexed characters\n result = ''\n \n # Iterate over the string, considering only characters at even indices (0, 2, 4, ...)\n for i in range(1, len(s) + 1):\n if i % 2 == 0:\n result += s[i - 1]\n \n return result", "matching_cluster_idx": 0}]}, "Mbpp/440": {"dps": null, "dps_norm": null, "pass@1": 2.0, "profiled": []}, "Mbpp/446": {"dps": 97.4384236453202, "dps_norm": 74.0, "pass@1": 79.0, "profiled": [{"solution": "def count_Occurrence(test_tuple, test_list):\n # Initialize a dictionary to count occurrences of elements from test_list in test_tuple\n count_dict = {}\n \n # Count the occurrences of each element in the tuple\n for element in test_tuple:\n if element in count_dict:\n count_dict[element] += 1\n else:\n count_dict[element] = 1\n \n # Sum the counts of the elements that are in the test_list\n result = sum(count_dict.get(element, 0) for element in test_list)\n \n return result", "matching_cluster_idx": 4}, {"solution": "def count_Occurrence(tup, lst):\n # Initialize a dictionary to hold the counts\n count_dict = {}\n \n # Count occurrences of each element in the tuple\n for element in tup:\n if element in count_dict:\n count_dict[element] += 1\n else:\n count_dict[element] = 1\n \n # Sum the counts of the elements that are in the list\n result = sum(count_dict[element] for element in lst if element in count_dict)\n \n return result", "matching_cluster_idx": 4}, {"solution": "def count_Occurrence(tup, lst):\n # Count the occurrences of all elements in the tuple\n count_dict = {}\n for item in tup:\n if item in count_dict:\n count_dict[item] += 1\n else:\n count_dict[item] = 1\n \n # Sum the occurrences of the specified elements in the list\n result = sum(count_dict[item] for item in lst if item in count_dict)\n return result", "matching_cluster_idx": 4}, {"solution": "def count_Occurrence(test_tuple, test_list):\n # Count the occurrences of each element in the tuple for all elements in the list\n count_dict = {}\n for elem in test_tuple:\n if elem in count_dict:\n count_dict[elem] += 1\n else:\n count_dict[elem] = 1\n \n # Calculate the total count of elements present in both the tuple and the list\n result = sum(count_dict.get(elem, 0) for elem in test_list)\n \n return result", "matching_cluster_idx": 4}, {"solution": "def count_Occurrence(tup, lst):\n count = 0\n for item in lst:\n if item in tup:\n count += tup.count(item)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tup, lst):\n # Count the occurrences of each element in the tuple for all elements in the list\n count_dict = {}\n for item in tup:\n if item in count_dict:\n count_dict[item] += 1\n else:\n count_dict[item] = 1\n \n # Sum the counts of elements that are in both the tuple and the list\n result = sum(count_dict.get(item, 0) for item in lst)\n return result", "matching_cluster_idx": 4}, {"solution": "def count_Occurrence(tup, lst):\n count = 0\n for item in lst:\n if item in tup:\n count += tup.count(item)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tup, lst):\n # Count the occurrences of each element in the tuple\n from collections import Counter\n counter = Counter(tup)\n \n # Sum the counts of the elements that are also in the list\n result = sum(counter[element] for element in lst if element in counter)\n \n return result", "matching_cluster_idx": 4}, {"solution": "def count_Occurrence(test_tup, test_list):\n # Count occurrences of each element in the tuple that is also in the list\n count = sum(test_tup.count(elem) for elem in test_list)\n \n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(test_tuple, test_list):\n # Initialize a counter to zero\n count = 0\n \n # Iterate through each element in the test_list\n for ele in test_list:\n # Count the number of occurrences of the element in the test_tuple\n count += test_tuple.count(ele)\n \n # Return the total count of occurrences\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tup, lst):\n count = 0\n for element in lst:\n if element in tup:\n count += tup.count(element)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tup, lst):\n # Count the occurrences of all elements in the list within the tuple\n return sum(tup.count(item) for item in lst)", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tup, lst):\n # Initialize a counter to zero\n count = 0\n \n # Iterate over each element in the list\n for item in lst:\n # Count the occurrences of the item in the tuple\n count += tup.count(item)\n \n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tup, lst):\n count = 0\n # Iterate through each item in the list\n for item in lst:\n # Check if the item is in the tuple\n if item in tup:\n count += tup.count(item)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tup, lst):\n # Initialize a dictionary to count occurrences\n count_dict = {}\n # Count occurrences of each element in the tuple\n for item in tup:\n if item in count_dict:\n count_dict[item] += 1\n else:\n count_dict[item] = 1\n \n # Initialize the result count\n result_count = 0\n # Sum up the counts of the elements that are in the list\n for item in lst:\n result_count += count_dict.get(item, 0)\n \n return result_count", "matching_cluster_idx": 4}, {"solution": "def count_Occurrence(tup, lst):\n # Initialize a counter for the total occurrences\n total_occurrences = 0\n \n # Iterate over each element in the list\n for element in lst:\n # Count the occurrences of the current element in the tuple\n occurrences = tup.count(element)\n # Add the occurrences to the total counter\n total_occurrences += occurrences\n \n return total_occurrences", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(test_tup, test_list):\n # Count the occurrence of each element in the tuple that is also in the list\n count = sum(test_tup.count(char) for char in test_list)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tup, lst):\n count = 0\n for item in lst:\n if item in tup:\n count += tup.count(item)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(test_tup, test_list):\n # Count occurrences of each element in the tuple for the elements present in the list\n result = sum(test_tup.count(ele) for ele in test_list)\n return result", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tup, lst):\n # Initialize a counter for the occurrences\n occurrence_count = 0\n \n # Iterate through each element in the list\n for element in lst:\n # If the element is in the tuple, increment the counter\n if element in tup:\n occurrence_count += tup.count(element)\n \n return occurrence_count", "matching_cluster_idx": 2}]}, "Mbpp/451": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 81.0, "profiled": [{"solution": "def remove_whitespaces(input_string):\n # Use the replace method to remove all whitespaces\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string):\n # Use the built-in replace method to replace all whitespaces with an empty string\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string):\n # Use str.replace method to replace all whitespace characters with an empty string\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string):\n # Use str.replace method to replace all sequences of whitespace with no whitespace\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string):\n # Use the replace method to remove all whitespaces\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string):\n # Use str.replace to replace all occurrences of whitespace characters with an empty string\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string):\n # Remove all whitespaces from the input string\n return input_string.replace(' ', '')", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string):\n # Use the replace method to remove all whitespaces\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string):\n # Use the replace method to remove all whitespaces\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string):\n # Use the replace method to replace all whitespaces with an empty string\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string):\n # Remove all whitespaces from the input string\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string):\n # Using the replace method to remove all whitespaces from the string\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string):\n # Remove all whitespaces from the input string\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string):\n # Use the replace method to remove all whitespaces\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string):\n # Use the replace method to remove all whitespaces\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string):\n # Remove all whitespaces from the input string\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string):\n # Use the replace method to remove all whitespaces\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string):\n # Use the replace method to remove all whitespaces\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string):\n # Remove all whitespaces from the input string\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string):\n # Use the replace method to remove all whitespaces\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}]}, "Mbpp/456": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def reverse_string_list(string_list):\n # Use list comprehension to reverse each string in the list\n return [s[::-1] for s in string_list]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n # Use list comprehension to reverse each string in the list\n reversed_list = [s[::-1] for s in string_list]\n return reversed_list", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(input_list):\n # Reverse each string in the list and return the new list\n return [s[::-1] for s in input_list]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n # Use list comprehension to reverse each string in the list\n reversed_list = [s[::-1] for s in string_list]\n return reversed_list", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n # Reverse each string in the list and return the new list\n return [s[::-1] for s in string_list]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n # Use a list comprehension to reverse each string in the list\n reversed_list = [s[::-1] for s in string_list]\n return reversed_list", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n # Use list comprehension to reverse each string in the list\n return [s[::-1] for s in string_list]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(input_list):\n # Reverse each string in the list and return the new list\n return [s[::-1] for s in input_list]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n # Reverse each string in the list and return the new list\n return [s[::-1] for s in string_list]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n # Reverse each string in the list using a list comprehension\n reversed_list = [s[::-1] for s in string_list]\n return reversed_list", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(input_list):\n # Use list comprehension to reverse each string in the list\n return [s[::-1] for s in input_list]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n # Use a list comprehension to reverse each string in the list\n return [s[::-1] for s in string_list]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n # Reverse each string in the list using a list comprehension\n reversed_list = [s[::-1] for s in string_list]\n return reversed_list", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n # Reverse each string in the list and return the new list\n return [s[::-1] for s in string_list]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n # Use a list comprehension to reverse each string in the list\n return [s[::-1] for s in string_list]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n # Use list comprehension to reverse each string in the list\n reversed_list = [s[::-1] for s in string_list]\n return reversed_list", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n # Use list comprehension to reverse each string in the list\n return [s[::-1] for s in string_list]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n # Use a list comprehension to reverse each string in the list\n reversed_list = [s[::-1] for s in string_list]\n return reversed_list", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n # Reverse each string in the list using a list comprehension\n reversed_list = [s[::-1] for s in string_list]\n return reversed_list", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(input_list):\n # Reverse each string in the input list\n reversed_list = [s[::-1] for s in input_list]\n return reversed_list", "matching_cluster_idx": 4}]}, "Mbpp/460": {"dps": 97.40384615384616, "dps_norm": 99.0, "pass@1": 100.0, "profiled": [{"solution": "def Extract(lst):\n # Extract the first element of each sublist and return as a list\n return [item[0] for item in lst]", "matching_cluster_idx": 4}, {"solution": "def Extract(lst):\n # Use a list comprehension to extract the first element of each sublist\n return [item[0] for item in lst]", "matching_cluster_idx": 4}, {"solution": "def Extract(lst):\n # Use list comprehension to extract the first element from each sublist\n return [item[0] for item in lst]", "matching_cluster_idx": 4}, {"solution": "def Extract(lst):\n # Extract the first element of each sublist\n return [item[0] for item in lst]", "matching_cluster_idx": 4}, {"solution": "def Extract(lst):\n # Use list comprehension to extract the first element from each sublist\n return [item[0] for item in lst if item]", "matching_cluster_idx": 3}, {"solution": "def Extract(lst):\n # Use list comprehension to extract the first element of each sublist\n return [item[0] for item in lst]", "matching_cluster_idx": 4}, {"solution": "def Extract(lst):\n # Use list comprehension to extract the first element from each sublist\n return [item[0] for item in lst]", "matching_cluster_idx": 4}, {"solution": "def Extract(lst):\n # Use list comprehension to extract the first element from each sublist\n return [item[0] for item in lst]", "matching_cluster_idx": 4}, {"solution": "def Extract(lst):\n # Use a list comprehension to extract the first element from each sublist\n return [item[0] for item in lst]", "matching_cluster_idx": 4}, {"solution": "def Extract(lst):\n # Extracts the first element from each sublist in the given list\n return [item[0] for item in lst]", "matching_cluster_idx": 4}, {"solution": "def Extract(lst):\n # Extracts the first element from each sublist in the given list of lists\n return [item[0] for item in lst]", "matching_cluster_idx": 4}, {"solution": "def Extract(lst):\n # Use list comprehension to extract the first element from each sublist\n return [item[0] for item in lst]", "matching_cluster_idx": 4}, {"solution": "def Extract(lst):\n # Use list comprehension to extract the first element of each sublist\n return [item[0] for item in lst]", "matching_cluster_idx": 4}, {"solution": "def Extract(lst):\n # Extracts the first element from each sublist and returns them in a list\n return [item[0] for item in lst]", "matching_cluster_idx": 4}, {"solution": "def Extract(lst):\n # Extract the first element from each sublist and return as a list\n return [item[0] for item in lst]", "matching_cluster_idx": 4}, {"solution": "def Extract(lst):\n # Use list comprehension to get the first element of each sublist\n return [item[0] for item in lst]", "matching_cluster_idx": 4}, {"solution": "def Extract(lst):\n # Use list comprehension to extract the first element from each sublist\n return [item[0] for item in lst]", "matching_cluster_idx": 4}, {"solution": "def Extract(lst):\n # Use list comprehension to extract the first element from each sublist\n return [item[0] for item in lst]", "matching_cluster_idx": 4}, {"solution": "def Extract(lst):\n # Extract the first element from each sublist\n return [item[0] for item in lst]", "matching_cluster_idx": 4}, {"solution": "def Extract(lst):\n # Use list comprehension to extract the first element from each sublist\n return [item[0] for item in lst]", "matching_cluster_idx": 4}]}, "Mbpp/474": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def replace_char(s, old_char, new_char):\n # Replace all occurrences of old_char with new_char in the string s\n return s.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, old_char, new_char):\n # Replace all occurrences of old_char with new_char in the string s\n result = s.replace(old_char, new_char)\n return result", "matching_cluster_idx": 6}, {"solution": "def replace_char(input_str, old_char, new_char):\n # Replace occurrences of old_char with new_char in input_str\n modified_str = input_str.replace(old_char, new_char)\n return modified_str", "matching_cluster_idx": 6}, {"solution": "def replace_char(input_str, old_char, new_char):\n # Replace occurrences of old_char with new_char in input_str\n result_str = input_str.replace(old_char, new_char)\n return result_str", "matching_cluster_idx": 6}, {"solution": "def replace_char(input_string, target_char, replacement_char):\n # Replace all occurrences of target_char with replacement_char\n modified_string = input_string.replace(target_char, replacement_char)\n return modified_string", "matching_cluster_idx": 6}, {"solution": "def replace_char(input_str, old_char, new_char):\n # Replace occurrences of old_char with new_char in input_str\n modified_str = input_str.replace(old_char, new_char)\n return modified_str", "matching_cluster_idx": 6}, {"solution": "def replace_char(string, old_char, new_char):\n # Replace occurrences of old_char with new_char in the string\n modified_string = string.replace(old_char, new_char)\n return modified_string", "matching_cluster_idx": 6}, {"solution": "def replace_char(input_string, old_char, new_char):\n # Replace occurrences of old_char with new_char in input_string\n result_string = input_string.replace(old_char, new_char)\n return result_string", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, old_char, new_char):\n # Replace all occurrences of old_char with new_char in string s\n return s.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(input_string, old_char, new_char):\n # Replace occurrences of old_char with new_char in the input_string\n return input_string.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(input_string, target_char, replacement_char):\n # Replace occurrences of target_char with replacement_char\n modified_string = input_string.replace(target_char, replacement_char)\n return modified_string", "matching_cluster_idx": 6}, {"solution": "def replace_char(input_str, old_char, new_char):\n # Replace occurrences of old_char with new_char in the input string\n return input_str.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(input_string, old_char, new_char):\n # Replace occurrences of old_char with new_char in the input_string\n return input_string.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(input_str, old_char, new_char):\n # Replace all occurrences of old_char with new_char in input_str\n return input_str.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(input_string, old_char, new_char):\n # Replace all occurrences of old_char with new_char\n modified_string = input_string.replace(old_char, new_char)\n return modified_string", "matching_cluster_idx": 6}, {"solution": "def replace_char(input_str, old_char, new_char):\n # Replace occurrences of old_char with new_char in input_str\n modified_str = input_str.replace(old_char, new_char)\n return modified_str", "matching_cluster_idx": 6}, {"solution": "def replace_char(input_string, old_char, new_char):\n # Replace occurrences of old_char with new_char in input_string\n modified_string = input_string.replace(old_char, new_char)\n return modified_string", "matching_cluster_idx": 6}, {"solution": "def replace_char(input_str, old_char, new_char):\n # Replace occurrences of old_char with new_char in the input_str\n modified_str = input_str.replace(old_char, new_char)\n return modified_str", "matching_cluster_idx": 6}, {"solution": "def replace_char(input_str, old_char, new_char):\n # Replace occurrences of old_char with new_char in input_str\n modified_str = input_str.replace(old_char, new_char)\n return modified_str", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, old_char, new_char):\n # Replace occurrences of old_char with new_char in string s\n return s.replace(old_char, new_char)", "matching_cluster_idx": 6}]}, "Mbpp/476": {"dps": 96.84563758389261, "dps_norm": 98.33333333333333, "pass@1": 100.0, "profiled": [{"solution": "def big_sum(arr):\n # Find the smallest and largest values in the array\n smallest = min(arr)\n largest = max(arr)\n \n # Calculate the sum of the smallest and largest values\n result = smallest + largest\n \n return result", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n # Find the maximum and minimum values in the array\n max_val = max(arr)\n min_val = min(arr)\n \n # Calculate the sum of the maximum and minimum values\n result = max_val + min_val\n \n return result", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n # Check if the array is empty\n if not arr:\n return None # Return None or any other appropriate value if the array is empty\n \n # Find the maximum and minimum values in the array\n max_val = max(arr)\n min_val = min(arr)\n \n # Calculate the sum of the maximum and minimum values\n result = max_val + min_val\n \n return result", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n # Find the smallest and largest elements in the array\n smallest = min(arr)\n largest = max(arr)\n \n # Calculate the sum of the smallest and largest values\n result = smallest + largest\n \n return result", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n # Find the maximum and minimum values in the array\n max_val = max(arr)\n min_val = min(arr)\n \n # Calculate the sum of the maximum and minimum values\n result = max_val + min_val\n \n return result", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n # Find the maximum and minimum values in the array\n max_val = max(arr)\n min_val = min(arr)\n \n # Calculate the sum of the maximum and minimum values\n result = max_val + min_val\n \n return result", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n # Find the maximum and minimum values in the array\n max_val = max(arr)\n min_val = min(arr)\n \n # Calculate the sum of the maximum and minimum values\n result = max_val + min_val\n \n return result", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n # Find the maximum and minimum values in the array\n max_val = max(arr)\n min_val = min(arr)\n \n # Calculate the sum of the maximum and minimum values\n result = max_val + min_val\n \n return result", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n # Find the maximum and minimum values in the array\n max_value = max(arr)\n min_value = min(arr)\n \n # Calculate the sum of the maximum and minimum values\n result = max_value + min_value\n \n return result", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n # Calculate the sum of the largest and smallest values in the array\n return max(arr) + min(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n # Check if the array is empty\n if not arr:\n return 0\n \n # Find the smallest and largest values in the array\n smallest = min(arr)\n largest = max(arr)\n \n # Calculate the sum of the smallest and largest values\n result = smallest + largest\n \n return result", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n # Find the largest and smallest values in the array\n max_value = max(arr)\n min_value = min(arr)\n \n # Return their sum\n return max_value + min_value", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n # Check if the array is empty\n if not arr:\n return None\n \n # Find the maximum and minimum values in the array\n max_val = max(arr)\n min_val = min(arr)\n \n # Return the sum of the maximum and minimum values\n return max_val + min_val", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n # Calculate the maximum and minimum values in the array\n max_val = max(arr)\n min_val = min(arr)\n \n # Return the sum of the maximum and minimum values\n return max_val + min_val", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n # Check if the array is empty\n if not arr:\n return 0\n # Find the smallest and largest values in the array\n smallest = min(arr)\n largest = max(arr)\n # Return their sum\n return smallest + largest", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n # Find the largest and smallest values in the array\n max_val = max(arr)\n min_val = min(arr)\n \n # Calculate the sum of the largest and smallest values\n result = max_val + min_val\n \n # Return the result\n return result", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n # Check if the input array is empty\n if not arr:\n return 0\n \n # Initialize max_val and min_val with the first element of the array\n max_val = min_val = arr[0]\n \n # Iterate through the array to find the max and min values\n for num in arr:\n if num > max_val:\n max_val = num\n elif num < min_val:\n min_val = num\n \n # Return the sum of the max and min values\n return max_val + min_val", "matching_cluster_idx": 3}, {"solution": "def big_sum(arr):\n # Check if the array is empty\n if not arr:\n return None # Return None for an empty array\n \n # Find the maximum and minimum values in the array\n max_value = max(arr)\n min_value = min(arr)\n \n # Calculate the sum of the largest and smallest values\n result = max_value + min_value\n \n return result", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n # Check if the array is empty\n if not arr:\n return 0\n # Find the largest and smallest values in the array\n max_val = max(arr)\n min_val = min(arr)\n # Return their sum\n return max_val + min_val", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n # Find the maximum and minimum values in the array\n max_val = max(arr)\n min_val = min(arr)\n \n # Return the sum of the maximum and minimum values\n return max_val + min_val", "matching_cluster_idx": 5}]}, "Mbpp/477": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def is_lower(input_string):\n # Convert the input string to lower case using the lower() method\n return input_string.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(input_string):\n \"\"\"\n Converts the given string to lower case.\n \n :param input_string: The string to convert to lower case\n :return: The lower case version of the input string\n \"\"\"\n return input_string.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(input_string):\n # Convert the input string to lower case using the lower() method\n return input_string.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(input_string):\n # Using the lower() method to convert the string to lower case\n return input_string.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n # Convert the given string to lower case\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(input_string):\n # Convert the input string to lower case using the lower() method\n return input_string.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(input_string):\n # Using the lower() method to convert the input string to lower case\n return input_string.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(input_string):\n # Convert the given string to lower case using the lower() method\n return input_string.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(input_string):\n \"\"\"\n Convert the given string to lower case.\n\n Args:\n input_string (str): The string to be converted.\n\n Returns:\n str: The converted lower case string.\n \"\"\"\n return input_string.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n # Convert the given string to lower case\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n \"\"\"\n Converts the given string to lower case.\n\n Args:\n s (str): The string to be converted.\n\n Returns:\n str: The lower case version of the input string.\n \"\"\"\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n # Convert the given string to lower case\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(input_string):\n # Convert the given string to lower case using str.lower() method\n return input_string.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(input_string):\n \"\"\"\n Converts the given string to lower case.\n\n Args:\n input_string (str): The string to be converted.\n\n Returns:\n str: The converted lower case string.\n \"\"\"\n return input_string.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n \"\"\"\n Convert the given string to lower case.\n\n :param s: String to be converted to lower case\n :return: Lower case version of the input string\n \"\"\"\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n \"\"\"\n Converts the given string to lower case.\n\n Args:\n s (str): The string to be converted to lower case.\n\n Returns:\n str: The lower case version of the input string.\n \"\"\"\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n # Convert the given string to lower case using the lower() method\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n # Use the lower() method to convert the string to lower case\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(input_string):\n # Convert the input string to lower case\n return input_string.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n # Convert the given string to lower case\n return s.lower()", "matching_cluster_idx": 4}]}, "Mbpp/563": {"dps": 85.24590163934427, "dps_norm": 81.81818181818181, "pass@1": 87.0, "profiled": [{"solution": "import re\ndef extract_values(input_string):\n # Use regular expression to find all text enclosed in double quotes\n return re.findall(r'\"(.*?)\"', input_string)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(input_string):\n # Use regular expression to find all text enclosed in double quotes\n matches = re.findall(r'\"(.*?)\"', input_string)\n return matches", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(input_string):\n # Use regular expression to find all text enclosed in double quotes\n matches = re.findall(r'\"(.*?)\"', input_string)\n return matches", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(input_string):\n # Use regular expression to find all substrings enclosed in double quotes\n matches = re.findall(r'\"(.*?)\"', input_string)\n return matches", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(input_string):\n # Use regular expression to find all text enclosed in double quotes\n matches = re.findall(r'\"(.*?)\"', input_string)\n # Return the list of matches\n return matches", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(input_string):\n # Use regular expression to find all text within double quotes\n matches = re.findall(r'\"(.*?)\"', input_string)\n return matches", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(input_string):\n # Use regular expression to find all text enclosed in double quotes\n matches = re.findall(r'\"(.*?)\"', input_string)\n return matches", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(input_string):\n # Use regular expression to find all text enclosed in double quotes\n matches = re.findall(r'\"(.*?)\"', input_string)\n return matches", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(input_string):\n # Use regular expression to find all values between double quotes\n matches = re.findall(r'\"(.*?)\"', input_string)\n return matches", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(input_string):\n # Use regular expression to find all text enclosed in double quotes\n matches = re.findall(r'\"(.*?)\"', input_string)\n return matches", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(input_string):\n # Use regular expression to find all text enclosed in double quotes\n matches = re.findall(r'\"(.*?)\"', input_string)\n return matches", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(input_string):\n # Use regular expression to find all text within double quotes\n matches = re.findall(r'\"(.*?)\"', input_string)\n return matches", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(input_string):\n # Use regular expression to find all text within double quotation marks\n matches = re.findall(r'\"(.*?)\"', input_string)\n return matches", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(input_string):\n # Use regular expression to find all substrings enclosed in double quotes\n matches = re.findall(r'\"(.*?)\"', input_string)\n return matches", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(input_string):\n # Use regular expression to find all text within double quotes\n matches = re.findall(r'\"(.*?)\"', input_string)\n return matches", "matching_cluster_idx": 8}, {"solution": "def extract_values(input_string):\n # Import the re module for regular expression operations\n import re\n \n # Use regular expression to find all text enclosed in double quotes\n values = re.findall(r'\"(.*?)\"', input_string)\n \n # Return the list of extracted values\n return values", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(input_string):\n # Use regular expression to find all values between quotation marks\n matches = re.findall(r'\"(.*?)\"', input_string)\n return matches", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(input_string):\n # Use regular expression to find all text within double quotes\n matches = re.findall(r'\"(.*?)\"', input_string)\n return matches", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(input_string):\n # Use regular expression to find all values enclosed in double quotes\n matches = re.findall(r'\"(.*?)\"', input_string)\n return matches", "matching_cluster_idx": 8}, {"solution": "def extract_values(input_string):\n # Importing the necessary module\n import re\n \n # Using regular expression to find all substrings enclosed in double quotes\n matches = re.findall(r'\"(.*?)\"', input_string)\n \n # Returning the list of found substrings\n return matches", "matching_cluster_idx": 8}]}, "Mbpp/572": {"dps": 95.06172839506173, "dps_norm": 85.71428571428571, "pass@1": 11.0, "profiled": [{"solution": "def two_unique_nums(nums_list):\n # Use a set to track unique numbers\n unique_nums = set()\n duplicates = set()\n \n # Iterate through the list to find duplicates\n for num in nums_list:\n if num in unique_nums:\n duplicates.add(num)\n else:\n unique_nums.add(num)\n \n # Filter out the duplicates and return the result\n return [num for num in nums_list if num not in duplicates]", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(nums):\n # Count the occurrences of each number\n num_counts = {}\n for num in nums:\n if num in num_counts:\n num_counts[num] += 1\n else:\n num_counts[num] = 1\n \n # Filter numbers that occur exactly once\n result = [num for num, count in num_counts.items() if count == 1]\n \n return result", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(nums):\n # Using a set to store unique numbers\n unique_nums = set()\n # Using another set to store numbers that have been seen as duplicates\n duplicates = set()\n \n # Iterate through each number in the input list\n for num in nums:\n # If the number is a duplicate, add it to the duplicates set\n if num in unique_nums:\n duplicates.add(num)\n # If the number is not a duplicate, add it to the unique_nums set\n else:\n unique_nums.add(num)\n \n # The result is all unique numbers minus the duplicates\n result = [num for num in nums if num not in duplicates]\n \n return result", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(numbers):\n # Count the occurrences of each number\n num_counts = {}\n for num in numbers:\n if num in num_counts:\n num_counts[num] += 1\n else:\n num_counts[num] = 1\n \n # Collect numbers that occur exactly once\n unique_nums = [num for num, count in num_counts.items() if count == 1]\n \n return unique_nums", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(numbers):\n # Count the occurrences of each number\n num_counts = {}\n for num in numbers:\n if num in num_counts:\n num_counts[num] += 1\n else:\n num_counts[num] = 1\n \n # Filter numbers that occur exactly once\n unique_nums = [num for num, count in num_counts.items() if count == 1]\n \n return unique_nums", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(nums):\n # Count the occurrences of each number\n num_counts = {}\n for num in nums:\n if num in num_counts:\n num_counts[num] += 1\n else:\n num_counts[num] = 1\n \n # Filter numbers that occur exactly once\n unique_nums = [num for num, count in num_counts.items() if count == 1]\n \n return unique_nums", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(nums):\n # Count the occurrences of each number\n num_counts = {}\n for num in nums:\n if num in num_counts:\n num_counts[num] += 1\n else:\n num_counts[num] = 1\n \n # Collect numbers that occur exactly once\n unique_nums = [num for num, count in num_counts.items() if count == 1]\n \n return unique_nums", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(nums):\n # Create a set to store unique numbers\n unique_set = set()\n # Create a set to store numbers that have been marked for removal\n to_remove = set()\n \n for num in nums:\n if num in unique_set:\n to_remove.add(num)\n elif num not in to_remove:\n unique_set.add(num)\n \n # Filter out the numbers that need to be removed\n result = [num for num in nums if num not in to_remove]\n return result", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(nums):\n # Count the occurrences of each number\n num_counts = {}\n for num in nums:\n if num in num_counts:\n num_counts[num] += 1\n else:\n num_counts[num] = 1\n \n # Filter numbers that appear exactly once\n unique_nums = [num for num, count in num_counts.items() if count == 1]\n \n return unique_nums", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(nums):\n # Count the occurrences of each number\n num_counts = {}\n for num in nums:\n if num in num_counts:\n num_counts[num] += 1\n else:\n num_counts[num] = 1\n \n # Extract the numbers that occur exactly once\n unique_nums = [num for num, count in num_counts.items() if count == 1]\n \n return unique_nums", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(nums):\n # Count the frequency of each number using a dictionary\n num_count = {}\n for num in nums:\n if num in num_count:\n num_count[num] += 1\n else:\n num_count[num] = 1\n \n # Collect numbers that appear exactly once\n unique_nums = [num for num, count in num_count.items() if count == 1]\n \n return unique_nums", "matching_cluster_idx": 5}]}, "Mbpp/578": {"dps": 89.14285714285714, "dps_norm": 70.9090909090909, "pass@1": 100.0, "profiled": [{"solution": "def interleave_lists(list1, list2, list3):\n # Combine elements from each list in order and create a flat list\n result = [item for triple in zip(list1, list2, list3) for item in triple]\n return result", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(list1, list2, list3):\n # Using list comprehension to interleave the lists and flatten the result\n interleaved_list = [item for triplet in zip(list1, list2, list3) for item in triplet]\n return interleaved_list", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(list1, list2, list3):\n # Interleave elements from three lists of the same length into one flat list\n return [item for triplet in zip(list1, list2, list3) for item in triplet]", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(list1, list2, list3):\n # Combine the lists into a single list by interleaving elements from each list\n result = [item for triplet in zip(list1, list2, list3) for item in triplet]\n return result", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(list1, list2, list3):\n # Use a list comprehension to interleave the three lists\n interleaved_list = [item for triplet in zip(list1, list2, list3) for item in triplet]\n return interleaved_list", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(list1, list2, list3):\n # Interleave the elements of the three lists into a single flat list\n interleaved_list = []\n for i in range(len(list1)):\n interleaved_list.append(list1[i])\n interleaved_list.append(list2[i])\n interleaved_list.append(list3[i])\n return interleaved_list", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n # Use zip to combine the lists and then flatten the tuples\n interleaved = [item for sublist in zip(list1, list2, list3) for item in sublist]\n return interleaved", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(list1, list2, list3):\n # Use zip to pair up elements from the three lists and then flatten the tuples\n interleaved = [item for sublist in zip(list1, list2, list3) for item in sublist]\n return interleaved", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(list1, list2, list3):\n # Use list comprehension to interleave the three lists and then flatten them\n interleaved_list = [item for triplet in zip(list1, list2, list3) for item in triplet]\n return interleaved_list", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(list1, list2, list3):\n # Initialize an empty list to store the interleaved result\n interleaved_list = []\n \n # Get the length of any input list to ensure all lists are of the same length\n length = len(list1)\n \n # Interleave the elements from each list\n for i in range(length):\n interleaved_list.append(list1[i])\n interleaved_list.append(list2[i])\n interleaved_list.append(list3[i])\n \n return interleaved_list", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n # Use a list comprehension to iterate over the indices of the lists\n # and gather elements from each list in order\n result = [element for triplet in zip(list1, list2, list3) for element in triplet]\n return result", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(list1, list2, list3):\n # Initialize an empty list to store the interleaved result\n interleaved_list = []\n \n # Get the length of any of the lists (they are of the same length)\n length = len(list1)\n \n # Interleave the lists by iterating through their indices\n for i in range(length):\n interleaved_list.append(list1[i])\n interleaved_list.append(list2[i])\n interleaved_list.append(list3[i])\n \n return interleaved_list", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n # Use list comprehension to interleave the elements of the three lists\n interleaved_list = [item for triplet in zip(list1, list2, list3) for item in triplet]\n return interleaved_list", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(list1, list2, list3):\n # Initialize an empty list to store the result\n result = []\n # Use zip to iterate over the lists in parallel\n for item1, item2, item3 in zip(list1, list2, list3):\n # Extend the result list with each of the items in sequence\n result.extend([item1, item2, item3])\n return result", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(list1, list2, list3):\n # Initialize an empty list to store the result\n interleaved_list = []\n \n # Get the length of the lists\n length = len(list1)\n \n # Interleave the three lists by iterating through each index\n for i in range(length):\n interleaved_list.append(list1[i])\n interleaved_list.append(list2[i])\n interleaved_list.append(list3[i])\n \n return interleaved_list", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n # Use a list comprehension to interleave the elements from the three lists\n interleaved_list = [item for triple in zip(list1, list2, list3) for item in triple]\n return interleaved_list", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(list1, list2, list3):\n # Interleave the three lists into a single flat list\n result = [val for triplet in zip(list1, list2, list3) for val in triplet]\n return result", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(list1, list2, list3):\n # Use list comprehension to interleave and flatten the lists\n interleaved_list = [item for triplet in zip(list1, list2, list3) for item in triplet]\n return interleaved_list", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(list1, list2, list3):\n # Use a list comprehension to interleave the three lists\n interleaved_list = [item for triple in zip(list1, list2, list3) for item in triple]\n return interleaved_list", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(list1, list2, list3):\n # Use zip to pair up elements from the three lists and then flatten the result\n interleaved = [item for triplet in zip(list1, list2, list3) for item in triplet]\n return interleaved", "matching_cluster_idx": 7}]}, "Mbpp/586": {"dps": 98.83040935672514, "dps_norm": 87.5, "pass@1": 39.0, "profiled": [{"solution": "def split_Arr(arr, n):\n # Split the array into two parts at the nth element and rearrange\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n # Split the array at the nth element and rotate it\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n # Split the list into two parts at the nth element\n first_part = arr[n:]\n second_part = arr[:n]\n \n # Add the first part to the end of the second part\n result = first_part + second_part\n \n return result", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n # Split the array at the nth element\n first_part = arr[n:] # Elements from n to the end\n second_part = arr[:n] # Elements from the start to n-1\n \n # Concatenate the first part with the second part\n result = first_part + second_part\n \n return result", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n # Split the array at the nth element and rotate it\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n # Split the list at the nth element\n split_part = arr[n:] + arr[:n]\n return split_part", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n # Split the array into two parts and rearrange\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n # Split the list at the nth element\n first_part = arr[n:] # Elements from nth element to the end\n second_part = arr[:n] # Elements from the start to (n-1)th element\n \n # Add the first part to the end of the second part\n result = first_part + second_part\n \n return result", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n # Split the array at the nth element and rotate it\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n # Split the array at the nth element\n split_part = arr[:n]\n remaining_part = arr[n:]\n \n # Add the first part to the end of the remaining part\n result = remaining_part + split_part\n \n return result", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n # Split the array into two parts\n first_part = arr[n:] # Elements from nth element to the end\n second_part = arr[:n] # Elements from start to (n-1)th element\n \n # Concatenate the first part with the second part\n result = first_part + second_part\n \n return result", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n # Split the list at the nth element and move the first part to the end\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n # Split the list at the nth element and add the first part to the end\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n # Split the list at the nth element\n # Concatenate the second part with the first part\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n # Split the array at the nth element and rotate it so the first part is moved to the end\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n # Split the list into two parts\n first_part = arr[n:]\n second_part = arr[:n]\n \n # Add the first part to the end of the second part\n result = first_part + second_part\n return result", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n # Split the array into two parts and add the first part to the end\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n # Split the list at the nth element and rotate it so the first part is moved to the end\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n # Split the list at the nth element\n part1 = arr[n:] \n part2 = arr[:n]\n \n # Add the first part to the end of the second part\n result = part1 + part2\n \n return result", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n # Split the array at the nth element and move the first part to the end\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}]}, "Mbpp/587": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def list_tuple(input_list):\n # Convert the list to a tuple\n result = tuple(input_list)\n return result", "matching_cluster_idx": 3}, {"solution": "def list_tuple(input_list):\n # Convert the list to a tuple\n result_tuple = tuple(input_list)\n return result_tuple", "matching_cluster_idx": 3}, {"solution": "def list_tuple(input_list):\n # Convert the input list to a tuple\n result = tuple(input_list)\n return result", "matching_cluster_idx": 3}, {"solution": "def list_tuple(input_list):\n # Convert the list to a tuple\n result_tuple = tuple(input_list)\n return result_tuple", "matching_cluster_idx": 3}, {"solution": "def list_tuple(input_list):\n # Convert the list to a tuple\n result_tuple = tuple(input_list)\n return result_tuple", "matching_cluster_idx": 3}, {"solution": "def list_tuple(input_list):\n # Convert the list to a tuple and return it\n return tuple(input_list)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(input_list):\n # Convert the input list to a tuple\n result_tuple = tuple(input_list)\n return result_tuple", "matching_cluster_idx": 3}, {"solution": "def list_tuple(input_list):\n # Convert the list to a tuple\n result_tuple = tuple(input_list)\n return result_tuple", "matching_cluster_idx": 3}, {"solution": "def list_tuple(input_list):\n # Convert the list to a tuple\n result_tuple = tuple(input_list)\n return result_tuple", "matching_cluster_idx": 3}, {"solution": "def list_tuple(input_list):\n # Convert the list to a tuple\n result_tuple = tuple(input_list)\n return result_tuple", "matching_cluster_idx": 3}, {"solution": "def list_tuple(input_list):\n # Convert the list to a tuple\n result_tuple = tuple(input_list)\n return result_tuple", "matching_cluster_idx": 3}, {"solution": "def list_tuple(input_list):\n # Convert the list to a tuple\n result_tuple = tuple(input_list)\n return result_tuple", "matching_cluster_idx": 3}, {"solution": "def list_tuple(input_list):\n # Convert the list to a tuple\n result_tuple = tuple(input_list)\n return result_tuple", "matching_cluster_idx": 3}, {"solution": "def list_tuple(input_list):\n # Convert the list to a tuple and return\n return tuple(input_list)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(input_list):\n # Convert the list to a tuple and return it\n return tuple(input_list)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(input_list):\n # Convert the list to a tuple\n result = tuple(input_list)\n return result", "matching_cluster_idx": 3}, {"solution": "def list_tuple(input_list):\n # Convert the list to a tuple\n result = tuple(input_list)\n return result", "matching_cluster_idx": 3}, {"solution": "def list_tuple(input_list):\n # Convert the list to a tuple\n result_tuple = tuple(input_list)\n return result_tuple", "matching_cluster_idx": 3}, {"solution": "def list_tuple(input_list):\n # Convert the input list to a tuple and return it\n return tuple(input_list)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(input_list):\n # Convert the list to a tuple\n result_tuple = tuple(input_list)\n return result_tuple", "matching_cluster_idx": 3}]}, "Mbpp/588": {"dps": 97.13302752293578, "dps_norm": 99.16666666666667, "pass@1": 100.0, "profiled": [{"solution": "def big_diff(lst):\n if not lst: # Check if the list is empty\n return 0\n \n # Find the maximum and minimum values in the list\n max_value = max(lst)\n min_value = min(lst)\n \n # Calculate the difference between the max and min values\n result = max_value - min_value\n \n return result", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n # Check if the list is empty\n if not nums:\n return 0\n \n # Find the maximum and minimum values in the list\n max_val = max(nums)\n min_val = min(nums)\n \n # Calculate the difference between max and min values\n diff = max_val - min_val\n \n return diff", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n # Check if the list is empty\n if not nums:\n return 0\n \n # Find the maximum and minimum values in the list\n max_val = max(nums)\n min_val = min(nums)\n \n # Calculate and return the difference\n return max_val - min_val", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n if not nums:\n return 0\n \n # Find the maximum and minimum values in the list\n max_val = max(nums)\n min_val = min(nums)\n \n # Calculate the difference between the max and min values\n difference = max_val - min_val\n \n return difference", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n # Find the maximum and minimum values in the list\n if not nums:\n return 0\n max_val = max(nums)\n min_val = min(nums)\n \n # Calculate the difference between the max and min values\n return max_val - min_val", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n if not nums:\n return 0\n \n # Find the maximum and minimum values in the list\n max_value = max(nums)\n min_value = min(nums)\n \n # Calculate the difference between the maximum and minimum values\n difference = max_value - min_value\n \n return difference", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n if not nums: # Check if the list is empty\n return 0\n \n # Find the maximum and minimum values in the list\n max_val = max(nums)\n min_val = min(nums)\n \n # Return the difference between the maximum and minimum values\n return max_val - min_val", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n # Check if the list is empty\n if not nums:\n return 0\n \n # Find the maximum and minimum values in the list\n maximum = max(nums)\n minimum = min(nums)\n \n # Calculate the difference\n difference = maximum - minimum\n \n return difference", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n # Find the maximum and minimum values in the list\n if not nums:\n return 0 # Return 0 if the list is empty\n max_val = max(nums)\n min_val = min(nums)\n \n # Calculate the difference between the max and min values\n return max_val - min_val", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n if not nums:\n return 0\n \n # Find the maximum and minimum values in the list\n max_val = max(nums)\n min_val = min(nums)\n \n # Calculate and return the difference\n return max_val - min_val", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n # Check if the list is empty or has only one element, return 0 or the only element respectively\n if len(nums) == 0:\n return 0\n elif len(nums) == 1:\n return nums[0]\n \n # Find the maximum and minimum values in the list\n max_val = max(nums)\n min_val = min(nums)\n \n # Return the difference between the maximum and minimum values\n return max_val - min_val", "matching_cluster_idx": 4}, {"solution": "def big_diff(nums):\n # Find the maximum and minimum values in the list\n max_val = max(nums)\n min_val = min(nums)\n \n # Calculate and return the difference\n return max_val - min_val", "matching_cluster_idx": 5}, {"solution": "def big_diff(lst):\n # Find the maximum and minimum values in the list\n max_val = max(lst)\n min_val = min(lst)\n \n # Calculate the difference\n diff = max_val - min_val\n \n return diff", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n # Find the difference between the largest and smallest values in the list\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n # Check if the list is empty or contains only one element\n if len(nums) < 2:\n return 0\n \n # Find the largest and smallest values in the list\n max_val = max(nums)\n min_val = min(nums)\n \n # Calculate and return the difference\n return max_val - min_val", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n if not nums:\n return 0\n # Find the maximum and minimum values in the list\n max_value = max(nums)\n min_value = min(nums)\n \n # Calculate the difference\n difference = max_value - min_value\n \n return difference", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n # Find the maximum and minimum values in the list\n max_val = max(nums)\n min_val = min(nums)\n \n # Calculate the difference\n difference = max_val - min_val\n \n return difference", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n # Find the maximum and minimum values in the list\n max_value = max(nums)\n min_value = min(nums)\n \n # Calculate the difference\n diff = max_value - min_value\n \n return diff", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n # Check if the list is empty\n if not nums:\n return 0\n \n # Find the maximum and minimum values in the list\n max_val = max(nums)\n min_val = min(nums)\n \n # Calculate the difference\n result = max_val - min_val\n \n return result", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n # Check if the list is empty\n if not nums:\n return None\n \n # Find the maximum and minimum values in the list\n max_val = max(nums)\n min_val = min(nums)\n \n # Calculate and return the difference\n return max_val - min_val", "matching_cluster_idx": 5}]}, "Mbpp/592": {"dps": 78.66666666666667, "dps_norm": 57.5, "pass@1": 58.0, "profiled": [{"solution": "from math import comb\ndef sum_Of_product(n):\n # Calculate the sum of the product of consecutive binomial coefficients\n sum_product = sum(comb(n, i) * comb(n, i + 1) for i in range(n))\n return sum_product", "matching_cluster_idx": 4}, {"solution": "from math import comb\ndef sum_Of_product(n):\n # Calculate the sum of the product of consecutive binomial coefficients\n sum_product = 0\n for i in range(n):\n sum_product += comb(n, i) * comb(n, i + 1)\n return sum_product", "matching_cluster_idx": 5}, {"solution": "from math import comb\ndef sum_Of_product(n):\n # Initialize the sum to 0\n total_sum = 0\n \n # Iterate through all pairs of consecutive binomial coefficients\n for i in range(n):\n # Add the product of the binomial coefficients to the total sum\n total_sum += comb(n, i) * comb(n, i + 1)\n \n return total_sum", "matching_cluster_idx": 5}, {"solution": "from math import comb\ndef sum_Of_product(n):\n # Initialize the sum to 0\n total_sum = 0\n \n # Calculate the sum of the product of consecutive binomial coefficients\n for i in range(n):\n total_sum += comb(n, i) * comb(n, i + 1)\n \n return total_sum", "matching_cluster_idx": 5}, {"solution": "from math import comb\ndef sum_Of_product(n):\n \"\"\"\n Function to find the sum of the product of consecutive binomial co-efficients.\n \n Parameters:\n n (int): The number of terms in the sequence of binomial coefficients.\n \n Returns:\n int: The sum of the product of consecutive binomial coefficients.\n \"\"\"\n total_sum = 0\n for i in range(n):\n total_sum += comb(n, i) * comb(n, i + 1)\n return total_sum", "matching_cluster_idx": 5}, {"solution": "from math import comb\ndef sum_Of_product(n):\n # Initialize sum to 0\n total_sum = 0\n \n # Loop through each number from 0 to n-1\n for i in range(n):\n # Calculate the product of consecutive binomial coefficients\n product = comb(n, i) * comb(n, i + 1)\n # Add the product to the total sum\n total_sum += product\n \n return total_sum", "matching_cluster_idx": 5}, {"solution": "from math import comb\ndef sum_Of_product(n):\n # Calculate the sum of the product of consecutive binomial coefficients\n total_sum = sum(comb(n, i) * comb(n, i + 1) for i in range(n))\n return total_sum", "matching_cluster_idx": 4}, {"solution": "from math import comb\ndef sum_Of_product(n):\n # Calculate the sum of the product of consecutive binomial coefficients\n result = 0\n for i in range(n):\n result += comb(n, i) * comb(n, i + 1)\n return result", "matching_cluster_idx": 4}, {"solution": "from math import comb\ndef sum_Of_product(n):\n # Calculate the sum of the product of consecutive binomial coefficients\n sum_product = sum(comb(n, i) * comb(n, i + 1) for i in range(n))\n return sum_product", "matching_cluster_idx": 4}, {"solution": "from math import comb\ndef sum_Of_product(n):\n \"\"\"\n Calculate the sum of the product of consecutive binomial coefficients.\n \n Args:\n n (int): The number of terms in the sequence.\n \n Returns:\n int: The sum of the product of consecutive binomial coefficients.\n \"\"\"\n result = 0\n for i in range(1, n + 1):\n result += comb(n, i) * comb(n, i - 1)\n return result", "matching_cluster_idx": 5}, {"solution": "import math\ndef sum_Of_product(n):\n # Initialize the sum to 0\n sum_product = 0\n \n # Loop through the range from 0 to n-1\n for i in range(n):\n # Calculate the product of consecutive binomial coefficients\n product = math.comb(n, i) * math.comb(n, i + 1)\n # Add the product to the sum\n sum_product += product\n \n return sum_product", "matching_cluster_idx": 5}, {"solution": "from math import comb\ndef sum_Of_product(n):\n # Initialize the sum to 0\n result = 0\n \n # Calculate the sum of the product of consecutive binomial coefficients\n for i in range(n):\n result += comb(n, i) * comb(n, i + 1)\n \n return result", "matching_cluster_idx": 5}, {"solution": "from math import comb\ndef sum_Of_product(n):\n # Initialize the sum to 0\n sum_product = 0\n \n # Calculate the sum of the product of consecutive binomial coefficients\n for i in range(n):\n sum_product += comb(n, i) * comb(n, i + 1)\n \n return sum_product", "matching_cluster_idx": 5}, {"solution": "import math\ndef sum_Of_product(n):\n # Calculate the sum of the product of consecutive binomial coefficients\n sum_product = 0\n for i in range(n):\n sum_product += math.comb(n, i) * math.comb(n, i + 1)\n return sum_product", "matching_cluster_idx": 5}, {"solution": "from math import comb\ndef sum_Of_product(n):\n # Calculate the sum of the product of consecutive binomial coefficients\n result = sum(comb(n, i) * comb(n, i + 1) for i in range(n))\n return result", "matching_cluster_idx": 4}, {"solution": "import math\ndef sum_Of_product(n):\n # Initialize the sum to 0\n total_sum = 0\n \n # Iterate through the range from 0 to n-1\n for i in range(n):\n # Calculate the product of consecutive binomial coefficients\n # C(n, i) * C(n, i+1)\n product = math.comb(n, i) * math.comb(n, i + 1)\n # Add the product to the total sum\n total_sum += product\n \n return total_sum", "matching_cluster_idx": 5}, {"solution": "import math\ndef sum_Of_product(n):\n # Calculate the sum of the product of consecutive binomial coefficients\n total_sum = 0\n for i in range(n):\n total_sum += math.comb(n, i) * math.comb(n, i + 1)\n return total_sum", "matching_cluster_idx": 5}, {"solution": "from math import comb\ndef sum_Of_product(n):\n # Initialize the sum to 0\n sum_result = 0\n \n # Iterate over the range from 0 to n-1\n for i in range(n):\n # Calculate the product of consecutive binomial coefficients and add to sum_result\n sum_result += comb(n, i) * comb(n, i + 1)\n \n return sum_result", "matching_cluster_idx": 5}, {"solution": "import math\ndef choose(n, k):\n return math.comb(n, k)\ndef sum_Of_product(n):\n sum_product = 0\n for i in range(n):\n sum_product += choose(n, i) * choose(n, i + 1)\n return sum_product", "matching_cluster_idx": 5}, {"solution": "from math import comb\ndef sum_Of_product(n):\n \"\"\"\n Calculate the sum of the product of consecutive binomial coefficients.\n\n Parameters:\n n (int): The number of terms in the series.\n\n Returns:\n int: The sum of the product of consecutive binomial coefficients.\n\n Examples:\n >>> sum_Of_product(3)\n 15\n \"\"\"\n result = 0\n for i in range(1, n + 1):\n result += comb(n, i) * comb(n, i - 1)\n return result", "matching_cluster_idx": 5}]}, "Mbpp/597": {"dps": null, "dps_norm": null, "pass@1": 0.0, "profiled": []}, "Mbpp/604": {"dps": 90.45454545454545, "dps_norm": 98.0, "pass@1": 54.0, "profiled": [{"solution": "def reverse_words(sentence):\n # Split the sentence into words based on spaces\n words = sentence.split()\n # Reverse the list of words\n reversed_words = words[::-1]\n # Join the reversed list of words back into a string with spaces\n reversed_sentence = ' '.join(reversed_words)\n return reversed_sentence", "matching_cluster_idx": 4}, {"solution": "def reverse_words(sentence):\n # Split the sentence into words, reverse the list of words, and join them back with a space\n return ' '.join(sentence.split()[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(sentence):\n # Split the sentence into words\n words = sentence.split()\n # Reverse the list of words\n reversed_words = words[::-1]\n # Join the reversed list of words back into a sentence\n reversed_sentence = ' '.join(reversed_words)\n return reversed_sentence", "matching_cluster_idx": 4}, {"solution": "def reverse_words(sentence):\n # Split the sentence into words\n words = sentence.split()\n # Reverse the list of words\n reversed_words = words[::-1]\n # Join the reversed list of words back into a sentence\n reversed_sentence = ' '.join(reversed_words)\n return reversed_sentence", "matching_cluster_idx": 4}, {"solution": "def reverse_words(sentence):\n # Split the sentence into words\n words = sentence.split()\n # Reverse the list of words and join them back with a space\n reversed_sentence = ' '.join(reversed(words))\n return reversed_sentence", "matching_cluster_idx": 3}, {"solution": "def reverse_words(sentence):\n # Split the sentence into words, reverse the list of words, and join them back with spaces\n reversed_sentence = ' '.join(reversed(sentence.split()))\n return reversed_sentence", "matching_cluster_idx": 3}, {"solution": "def reverse_words(sentence):\n # Split the sentence into words based on spaces\n words = sentence.split()\n # Reverse the list of words\n reversed_words = words[::-1]\n # Join the reversed list of words back into a string\n reversed_sentence = ' '.join(reversed_words)\n return reversed_sentence", "matching_cluster_idx": 4}, {"solution": "def reverse_words(sentence):\n # Split the sentence into words based on spaces\n words = sentence.split()\n # Reverse the list of words\n reversed_words = words[::-1]\n # Join the reversed list of words back into a string\n reversed_sentence = ' '.join(reversed_words)\n return reversed_sentence", "matching_cluster_idx": 4}, {"solution": "def reverse_words(sentence):\n # Split the sentence into words based on spaces\n words = sentence.split()\n # Reverse the list of words\n reversed_words = words[::-1]\n # Join the reversed list of words back into a string with spaces\n reversed_sentence = ' '.join(reversed_words)\n return reversed_sentence", "matching_cluster_idx": 4}, {"solution": "def reverse_words(sentence):\n # Split the sentence into words\n words = sentence.split()\n # Reverse the list of words\n reversed_words = words[::-1]\n # Join the reversed list of words with spaces\n reversed_sentence = ' '.join(reversed_words)\n return reversed_sentence", "matching_cluster_idx": 4}, {"solution": "def reverse_words(sentence):\n # Split the sentence into words\n words = sentence.split()\n # Reverse the list of words\n reversed_words = words[::-1]\n # Join the reversed list of words back into a sentence\n reversed_sentence = ' '.join(reversed_words)\n return reversed_sentence", "matching_cluster_idx": 4}, {"solution": "def reverse_words(sentence):\n # Split the sentence into words\n words = sentence.split()\n # Reverse the list of words\n reversed_words = words[::-1]\n # Join the reversed list of words back into a string with spaces\n reversed_sentence = ' '.join(reversed_words)\n return reversed_sentence", "matching_cluster_idx": 4}, {"solution": "def reverse_words(sentence):\n # Split the sentence into words\n words = sentence.split()\n # Reverse the list of words\n reversed_words = words[::-1]\n # Join the reversed list back into a sentence\n reversed_sentence = ' '.join(reversed_words)\n return reversed_sentence", "matching_cluster_idx": 4}, {"solution": "def reverse_words(sentence):\n # Split the sentence into words based on spaces\n words = sentence.split()\n # Reverse the list of words\n reversed_words = words[::-1]\n # Join the reversed list of words back into a string with spaces\n reversed_sentence = ' '.join(reversed_words)\n return reversed_sentence", "matching_cluster_idx": 4}, {"solution": "def reverse_words(sentence):\n # Split the sentence into words based on spaces\n words = sentence.split()\n # Reverse the list of words\n reversed_words = words[::-1]\n # Join the reversed list of words back into a string with spaces\n reversed_sentence = ' '.join(reversed_words)\n return reversed_sentence", "matching_cluster_idx": 4}, {"solution": "def reverse_words(sentence):\n # Split the sentence into words based on spaces\n words = sentence.split()\n \n # Reverse the list of words\n reversed_words = words[::-1]\n \n # Join the reversed list of words back into a string with spaces\n reversed_sentence = ' '.join(reversed_words)\n \n return reversed_sentence", "matching_cluster_idx": 4}, {"solution": "def reverse_words(sentence):\n # Split the sentence into words, reverse the list of words, and join them back with a space\n return ' '.join(sentence.split()[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(sentence):\n # Split the sentence into words, reverse the list of words, and join them back with a space\n return ' '.join(sentence.split()[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(sentence):\n # Split the sentence into words\n words = sentence.split()\n # Reverse the list of words\n reversed_words = words[::-1]\n # Join the reversed list of words back into a sentence\n reversed_sentence = ' '.join(reversed_words)\n return reversed_sentence", "matching_cluster_idx": 4}, {"solution": "def reverse_words(sentence):\n # Split the sentence into words\n words = sentence.split()\n # Reverse the list of words\n reversed_words = words[::-1]\n # Join the reversed list of words back into a string\n reversed_sentence = ' '.join(reversed_words)\n return reversed_sentence", "matching_cluster_idx": 4}]}, "Mbpp/610": {"dps": 53.57142857142858, "dps_norm": 59.183673469387756, "pass@1": 14.0, "profiled": [{"solution": "def remove_kth_element(lst, k):\n # Check if k is within valid range\n if 1 <= k <= len(lst):\n # Use list slicing to remove the k'th element\n return lst[:k-1] + lst[k:]\n else:\n # Return the original list if k is out of valid range\n return lst", "matching_cluster_idx": 2}, {"solution": "def remove_kth_element(lst, k):\n # Check if k is within the bounds of the list\n if 1 <= k <= len(lst):\n # Use list slicing to create a new list without the k'th element\n return lst[:k-1] + lst[k:]\n else:\n # If k is out of bounds, return the original list\n return lst", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(lst, k):\n \"\"\"\n Removes the k'th element from a given list.\n \n Args:\n lst (list): The input list from which the k'th element is to be removed.\n k (int): The 1-based index of the element to remove.\n \n Returns:\n list: A new list with the k'th element removed.\n \"\"\"\n if k <= 0:\n return lst # If k is not a valid index, return the original list\n return [item for index, item in enumerate(lst) if index != k-1]", "matching_cluster_idx": 1}, {"solution": "def remove_kth_element(lst, k):\n \"\"\"\n Takes a list and returns a list with the same elements, but the k'th element removed.\n \n :param lst: List of elements\n :param k: The 1-based index of the element to remove\n :return: List with the k'th element removed\n \n Example:\n remove_kth_element([1,1,2,3,4,4,5,1],3) should return [1, 1, 3, 4, 4, 5, 1]\n \"\"\"\n # Check if k is a valid index\n if 1 <= k <= len(lst):\n # Remove the k'th element (1-based index)\n del lst[k-1]\n return lst", "matching_cluster_idx": 6}, {"solution": "def remove_kth_element(lst, k):\n # Check if k is within the valid range\n if 1 <= k <= len(lst):\n # Create a new list without the k'th element\n new_lst = lst[:k-1] + lst[k:]\n return new_lst\n else:\n # If k is out of range, return the original list\n return lst", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(lst, k):\n \"\"\"\n Removes the k'th element from the provided list and returns a new list with the element removed.\n \n Args:\n lst (list): The input list.\n k (int): The 1-based index of the element to remove.\n \n Returns:\n list: A new list with the k'th element removed.\n \"\"\"\n if k < 1 or k > len(lst):\n raise ValueError(\"k must be between 1 and the length of the list\")\n \n # Return a new list without the k'th element\n return lst[:k-1] + lst[k:]", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(lst, k):\n # Check if k is within valid range\n if 1 <= k <= len(lst):\n # Remove the k'th element (1-indexed)\n del lst[k-1]\n return lst", "matching_cluster_idx": 6}, {"solution": "def remove_kth_element(lst, k):\n \"\"\"\n Removes the k'th element from a list and returns the new list.\n \n Parameters:\n lst (list): The input list.\n k (int): The 1-based index of the element to remove.\n \n Returns:\n list: A new list with the k'th element removed.\n \"\"\"\n # Check if k is within the valid range\n if 1 <= k <= len(lst):\n # Remove the k'th element\n return lst[:k-1] + lst[k:]\n else:\n # If k is out of bounds, return the original list\n return lst", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(lst, k):\n # Ensure k is within the bounds of the list\n if 1 <= k <= len(lst):\n # Create a new list excluding the k'th element\n return [lst[i] for i in range(len(lst)) if i != k-1]\n else:\n # Return the original list if k is out of bounds\n return lst", "matching_cluster_idx": 0}, {"solution": "def remove_kth_element(lst, k):\n \"\"\"\n Removes the k'th element from the given list and returns a new list.\n \n :param lst: List of elements from which to remove the k'th element.\n :param k: The 1-based index of the element to remove.\n :return: A new list with the k'th element removed.\n \"\"\"\n # Ensure the index is within the bounds of the list\n if 0 < k <= len(lst):\n return lst[:k-1] + lst[k:]\n else:\n # If k is out of bounds, return the original list\n return lst", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(lst, k):\n \"\"\"\n Removes the k'th element from the provided list and returns the modified list.\n \n :param lst: List of elements from which the k'th element will be removed.\n :param k: The index (1-based) of the element to remove.\n :return: A new list with the k'th element removed.\n \"\"\"\n # Adjust k to be 0-based index\n k -= 1\n if 0 <= k < len(lst):\n return lst[:k] + lst[k+1:]\n else:\n # k is out of bounds, return the original list\n return lst", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(lst, k):\n \"\"\"\n Removes the k'th element from the given list and returns the modified list.\n \n :param lst: List from which the k'th element will be removed.\n :param k: The 1-based index of the element to remove.\n :return: A new list with the k'th element removed.\n \"\"\"\n if 1 <= k <= len(lst):\n return lst[:k-1] + lst[k:]\n else:\n # If k is out of bounds, return the original list\n return lst", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(lst, k):\n # Check if k is within the bounds of the list\n if 1 <= k <= len(lst):\n # Use list slicing to remove the k'th element\n return lst[:k-1] + lst[k:]\n else:\n # If k is out of bounds, return the original list\n return lst", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(lst, k):\n # Create a copy of the list to avoid modifying the original list\n new_lst = lst.copy()\n # Check if k is within the bounds of the list\n if 1 <= k <= len(lst):\n # Remove the k'th element (index k-1)\n new_lst.pop(k-1)\n return new_lst", "matching_cluster_idx": 5}]}, "Mbpp/611": {"dps": 86.1042944785276, "dps_norm": 96.66666666666667, "pass@1": 35.0, "profiled": [{"solution": "def max_of_nth(matrix, n):\n # Extract the nth column from the matrix\n nth_column = [row[n] for row in matrix]\n \n # Return the maximum value of the nth column\n return max(nth_column)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n # Find the length of the matrix to handle cases where the n'th column might not exist\n max_length = max(len(row) for row in matrix)\n \n # If n is out of the range of the column indices, return None or handle it as needed\n if n >= max_length:\n return None\n \n # Find the maximum value in the n'th column\n max_value = max(row[n] for row in matrix if n < len(row))\n \n return max_value", "matching_cluster_idx": 3}, {"solution": "def max_of_nth(matrix, n):\n # Check if the n'th column exists\n if n >= len(matrix[0]):\n return None\n \n # Extract the n'th column from the matrix\n nth_column = [row[n] for row in matrix]\n \n # Return the maximum value of the n'th column\n return max(nth_column)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n # Initialize the maximum value to a very small number\n max_value = float('-inf')\n \n # Iterate through each row in the matrix\n for row in matrix:\n # Check if the current row has at least n+1 elements\n if len(row) > n:\n # Update max_value if the current element in the n'th column is greater\n max_value = max(max_value, row[n])\n \n return max_value", "matching_cluster_idx": 4}, {"solution": "def max_of_nth(matrix, n):\n # Use max function with a generator expression to find the maximum value in the specified column\n return max(row[n] for row in matrix)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n # Find the maximum value in the specified column\n max_value = max(row[n] for row in matrix if n < len(row))\n return max_value", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n # Find the length of the matrix (number of rows)\n row_length = len(matrix)\n \n # Initialize max_value with the smallest possible integer\n max_value = float('-inf')\n \n # Iterate through each row in the matrix\n for row in matrix:\n # Check if the column index is within the valid range\n if n < len(row):\n # Update max_value if the current column value is greater\n max_value = max(max_value, row[n])\n \n return max_value", "matching_cluster_idx": 4}, {"solution": "def max_of_nth(matrix, n):\n # Check if the n'th column exists in the matrix\n if not matrix or n >= len(matrix[0]):\n return None\n \n # Find the maximum value in the n'th column\n max_value = max(row[n] for row in matrix)\n \n return max_value", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n # Check if n is within the bounds of the matrix columns\n if not matrix or n >= len(matrix[0]):\n return None\n \n # Use list comprehension to get all elements in the n'th column and find the max\n max_value = max(matrix[row][n] for row in range(len(matrix)))\n return max_value", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n # Initialize max value to a very small number to ensure any column value will be larger\n max_value = float('-inf')\n \n # Iterate through each row in the matrix\n for row in matrix:\n # Check if the current column value is greater than the max_value\n if row[n] > max_value:\n max_value = row[n]\n \n return max_value", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n # Extract the nth column from the matrix\n column = [row[n] for row in matrix]\n \n # Return the maximum value of the extracted column\n return max(column)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n # Use list comprehension to extract the nth column and then find the max value\n return max([row[n] for row in matrix])", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n # Check if the matrix is empty or column index is out of range\n if not matrix or n >= len(matrix[0]):\n return None\n \n # Initialize the maximum value with the first element of the nth column\n max_val = matrix[0][n]\n \n # Iterate through the matrix to find the max value in the nth column\n for row in matrix:\n if row[n] > max_val:\n max_val = row[n]\n \n return max_val", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n # Use list comprehension to extract the nth column from the matrix\n # and return the max value of that column\n return max([row[n] for row in matrix])", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n # Use a generator expression to find the maximum value in the specified column\n return max(row[n] for row in matrix)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n # Check if the n'th column exists in the matrix\n if n >= len(matrix[0]):\n raise ValueError(\"Column index out of range\")\n \n # Extract the n'th column and find the maximum value\n max_value = max(row[n] for row in matrix)\n return max_value", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n # Ensure the matrix is not empty\n if not matrix:\n return None\n \n # Find the maximum value in the specified column\n max_value = max(row[n] for row in matrix)\n return max_value", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n # Check if the n'th column exists\n if n >= len(matrix[0]):\n raise IndexError(\"Column index is out of range.\")\n \n # Extract the n'th column and find the maximum value\n max_value = max(row[n] for row in matrix)\n return max_value", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n # Extract the nth column from the matrix\n nth_column = [row[n] for row in matrix]\n # Return the maximum value from the nth column\n return max(nth_column)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n # Use max function with a generator expression to find the max value in the n'th column\n return max(row[n] for row in matrix) if n < len(matrix[0]) and matrix else None", "matching_cluster_idx": 5}]}, "Mbpp/631": {"dps": null, "dps_norm": null, "pass@1": 0.0, "profiled": []}, "Mbpp/632": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 99.0, "profiled": [{"solution": "def move_zero(arr):\n # Initialize pointers for finding non-zero elements\n non_zero_index = 0\n \n # Iterate over the array\n for i in range(len(arr)):\n # Move non-zero elements to the front\n if arr[i] != 0:\n arr[non_zero_index] = arr[i]\n non_zero_index += 1\n \n # Fill the remaining positions with zeroes\n while non_zero_index < len(arr):\n arr[non_zero_index] = 0\n non_zero_index += 1\n \n return arr", "matching_cluster_idx": 6}, {"solution": "def move_zero(lst):\n # Create a list comprehension to filter out non-zero elements\n non_zeros = [num for num in lst if num != 0]\n # Create a list of zeros the same length as the number of elements in the original list\n zeros = [0] * (len(lst) - len(non_zeros))\n # Combine the non-zero elements with the zeros\n result = non_zeros + zeros\n return result", "matching_cluster_idx": 6}, {"solution": "def move_zero(lst):\n # Initialize an empty list to hold non-zero elements\n non_zero = [element for element in lst if element != 0]\n \n # Append zeroes to the end of the non_zero list\n non_zero.extend([0] * lst.count(0))\n \n return non_zero", "matching_cluster_idx": 6}, {"solution": "def move_zero(arr):\n # Filter out non-zero elements and extend the result with zeros\n return [x for x in arr if x != 0] + [0] * arr.count(0)", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n # Remove all zeroes from the list and store the remaining elements\n nums_without_zeroes = [num for num in nums if num != 0]\n \n # Extend the list with the appropriate number of zeroes\n nums[:] = (nums_without_zeroes + [0] * (len(nums) - len(nums_without_zeroes)))\n \n return nums", "matching_cluster_idx": 6}, {"solution": "def move_zero(arr):\n # Filter out non-zero elements and extend the result with zeros\n return [num for num in arr if num != 0] + [0] * arr.count(0)", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n # Create a new list to hold the result\n result = []\n # Count of zeroes to be added at the end\n zero_count = 0\n \n # Iterate through the input list\n for num in nums:\n if num == 0:\n zero_count += 1\n else:\n result.append(num)\n \n # Add all the zeroes to the end of the result list\n result.extend([0] * zero_count)\n \n return result", "matching_cluster_idx": 6}, {"solution": "def move_zero(lst):\n non_zero = [num for num in lst if num != 0]\n zeros = [0] * (len(lst) - len(non_zero))\n return non_zero + zeros", "matching_cluster_idx": 6}, {"solution": "def move_zero(arr):\n # Create a list to store non-zero elements\n non_zero = [x for x in arr if x != 0]\n # Append zeroes to the end of the non_zero list\n non_zero.extend([0] * (len(arr) - len(non_zero)))\n return non_zero", "matching_cluster_idx": 6}, {"solution": "def move_zero(arr):\n non_zero = [num for num in arr if num != 0]\n zeros = [0] * (len(arr) - len(non_zero))\n return non_zero + zeros", "matching_cluster_idx": 6}, {"solution": "def move_zero(lst):\n # Filter out non-zero elements and extend the new list with zeros\n non_zero_elements = [element for element in lst if element != 0]\n zero_elements = [0] * (len(lst) - len(non_zero_elements))\n return non_zero_elements + zero_elements", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n # Create a list to hold the non-zero elements\n non_zero = [num for num in nums if num != 0]\n \n # Append zeros to the end of the list\n non_zero.extend([0] * nums.count(0))\n \n return non_zero", "matching_cluster_idx": 6}, {"solution": "def move_zero(arr):\n # Remove all zeroes from the list and keep the order of other elements\n non_zero_elements = [x for x in arr if x != 0]\n # Append zeroes at the end of the list\n non_zero_elements.extend([0] * (len(arr) - len(non_zero_elements)))\n return non_zero_elements", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n # Initialize an index for the position to place the next non-zero element\n next_non_zero_pos = 0\n \n # Iterate through the list\n for num in nums:\n if num != 0:\n # Place the non-zero element at the next position\n nums[next_non_zero_pos] = num\n next_non_zero_pos += 1\n \n # Fill the remaining positions with zeroes\n for i in range(next_non_zero_pos, len(nums)):\n nums[i] = 0\n \n return nums", "matching_cluster_idx": 6}, {"solution": "def move_zero(arr):\n # Create two lists, one for non-zero elements, and one for zeros\n non_zero = [x for x in arr if x != 0]\n zeros = [x for x in arr if x == 0]\n \n # Combine the non-zero elements with the zeros\n result = non_zero + zeros\n return result", "matching_cluster_idx": 6}, {"solution": "def move_zero(arr):\n # Move all zeros in the list to the end while maintaining the order of non-zero elements\n non_zero = [i for i in arr if i != 0]\n zeros = [0] * (len(arr) - len(non_zero))\n return non_zero + zeros", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n # Create an empty list to store non-zero elements\n non_zero = [num for num in nums if num != 0]\n \n # Append zeros to the end of the non_zero list\n non_zero.extend([0] * nums.count(0))\n \n return non_zero", "matching_cluster_idx": 6}, {"solution": "def move_zero(arr):\n # Create a list comprehension to separate non-zero elements\n non_zero_elements = [element for element in arr if element != 0]\n # Extend the non-zero elements list with the appropriate number of zeroes\n non_zero_elements.extend([0] * (len(arr) - len(non_zero_elements)))\n return non_zero_elements", "matching_cluster_idx": 6}, {"solution": "def move_zero(arr):\n # Create a pointer to keep track of the position to place the next non-zero element\n non_zero_index = 0\n \n # Iterate through the list\n for i in range(len(arr)):\n if arr[i] != 0:\n # Place the non-zero element at the current non_zero_index\n arr[non_zero_index] = arr[i]\n non_zero_index += 1\n \n # Fill the remaining positions with zeroes\n while non_zero_index < len(arr):\n arr[non_zero_index] = 0\n non_zero_index += 1\n \n return arr", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n non_zero = [num for num in nums if num != 0]\n zeros = [0] * (len(nums) - len(non_zero))\n return non_zero + zeros", "matching_cluster_idx": 6}]}, "Mbpp/633": {"dps": 97.03252032520325, "dps_norm": 69.16666666666666, "pass@1": 70.0, "profiled": [{"solution": "def pair_xor_Sum(arr, n):\n # Initialize the sum to 0\n xor_sum = 0\n \n # Iterate through all elements in the array\n for i in range(n):\n for j in range(i+1, n):\n # Compute XOR for each pair (arr[i], arr[j]) and add to the sum\n xor_sum += arr[i] ^ arr[j]\n \n return xor_sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(arr, n):\n # Initialize the result\n result = 0\n \n # Iterate through each number in the array\n for i in range(32): # Consider 32 bits since integers are considered\n count = 0\n # Count numbers with i-th bit set\n for j in range(n):\n if (arr[j] & (1 << i)):\n count += 1\n # Total numbers with i-th bit unset\n total = n - count\n # XOR contributes to result when both bits in pair are different\n result += (count * total * (1 << i))\n \n return result", "matching_cluster_idx": 4}, {"solution": "def pair_xor_Sum(arr, n):\n # Calculate the sum of xor of all pairs\n result = 0\n for i in range(32):\n count = 0\n # Check each bit in the integers\n for j in range(n):\n # Count integers where the current bit is set\n if (arr[j] & (1 << i)):\n count += 1\n # Calculate the contribution of the current bit to the result\n result += (count * (n - count) * (1 << i))\n return result", "matching_cluster_idx": 4}, {"solution": "def pair_xor_Sum(arr, n):\n # Initialize result\n result = 0\n \n # Iterate through each element in the array\n for i in range(32):\n count = 0\n # For each bit position, count how many numbers have the i-th bit set\n for j in range(n):\n if (arr[j] & (1 << i)):\n count += 1\n # Calculate the contribution of the i-th bit to the result\n result += (count * (n - count) * (1 << i))\n \n return result", "matching_cluster_idx": 4}, {"solution": "def pair_xor_Sum(arr, n):\n # Calculate the sum of XOR of all pairs\n result = 0\n # Iterate through each bit position (0 to 30 assuming 32-bit integers)\n for i in range(31):\n count = 0\n # Count how many numbers have the i-th bit set\n for j in range(n):\n if (arr[j] & (1 << i)):\n count += 1\n # Calculate the contribution of the i-th bit to the result\n result += (count * (n - count) * (1 << i))\n return result", "matching_cluster_idx": 4}, {"solution": "def pair_xor_Sum(arr, n):\n # Initialize result\n xorSum = 0\n \n # Iterate over each pair and calculate XOR\n for i in range(n):\n for j in range(i + 1, n):\n xorSum += arr[i] ^ arr[j]\n \n return xorSum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(arr, n):\n # Initialize sum to 0\n xorSum = 0\n \n # Calculate the XOR for each bit position (0 to 31 for 32-bit integers)\n for i in range(32):\n # Calculate the count of numbers with i-th bit set\n count = 0\n for j in range(n):\n if (arr[j] & (1 << i)):\n count += 1\n \n # Calculate the contribution of the i-th bit to the total XOR sum\n xorSum += (count * (n - count) * (1 << i))\n \n return xorSum", "matching_cluster_idx": 4}, {"solution": "def pair_xor_Sum(arr, n):\n # Calculate the sum of XOR of all pairs in the list\n result = 0\n for i in range(32): # Considering integer limit from 0 to 10^9, which fits in 32 bits\n count = 0\n for j in range(n):\n if (arr[j] & (1 << i)):\n count += 1\n result += (count * (n - count) * (1 << i))\n return result", "matching_cluster_idx": 4}, {"solution": "def pair_xor_Sum(arr, n):\n # Calculate the sum of xor for all pairs\n result = 0\n for i in range(32):\n count = 0\n for j in range(n):\n # Count numbers with i-th bit set\n if arr[j] & (1 << i):\n count += 1\n # Total pairs with different i-th bit\n result += (count * (n - count) * (1 << i))\n return result", "matching_cluster_idx": 4}, {"solution": "def pair_xor_Sum(arr, n):\n # Initialize sum to 0\n xorSum = 0\n \n # Iterate through each element in the array\n for i in range(n):\n # XOR each element with every other element and add to sum\n for j in range(i + 1, n):\n xorSum += arr[i] ^ arr[j]\n \n return xorSum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(arr, n):\n # Initialize the result\n result = 0\n \n # Iterate through the array\n for i in range(32):\n count = 0\n # Count numbers with i-th bit set\n for j in range(n):\n if (arr[j] & (1 << i)):\n count += 1\n # XOR contribution of the i-th bit to the result\n result += (count * (n - count) * (1 << i))\n \n return result", "matching_cluster_idx": 4}, {"solution": "def pair_xor_Sum(arr, n):\n # Calculate the sum of XOR of all pairs\n result = 0\n for i in range(32): # Considering the maximum value of the 32-bit integer\n count = 0\n for j in range(n):\n if (arr[j] & (1 << i)) != 0:\n count += 1\n result += (count * (n - count) * (1 << i))\n return result", "matching_cluster_idx": 3}, {"solution": "def pair_xor_Sum(arr, n):\n # Calculate the sum of individual XORs\n result = 0\n for i in range(32):\n count = 0\n # Check each bit position\n for j in range(n):\n if (arr[j] >> i) & 1:\n count += 1\n # Calculate the contribution of the current bit position\n result += (count * (n - count) * (1 << i))\n return result", "matching_cluster_idx": 4}, {"solution": "def pair_xor_Sum(arr, n):\n # Initialize sum of xor\n xor_sum = 0\n \n # Iterate through each pair\n for i in range(n):\n for j in range(i+1, n):\n # Calculate XOR for the pair and add to the sum\n xor_sum += arr[i] ^ arr[j]\n \n return xor_sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(arr, n):\n # Calculate the sum of XOR for all pairs in the array\n total_xor_sum = 0\n for i in range(n):\n for j in range(i + 1, n):\n total_xor_sum += arr[i] ^ arr[j]\n return total_xor_sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(arr, n):\n # Calculate the sum of xor of all pairs\n result = 0\n for i in range(32): # Considering 32-bit integers\n count = 0\n for j in range(n):\n # Count numbers with i-th bit set\n if (arr[j] & (1 << i)):\n count += 1\n # Number of pairs where i-th bit of the first number is set and of the second number is not set\n result += (count * (n - count) * (1 << i))\n return result", "matching_cluster_idx": 4}, {"solution": "def pair_xor_Sum(arr, n):\n # Initialize result\n result = 0\n \n # Iterate through all possible pairs\n for i in range(n):\n for j in range(i+1, n):\n # Add XOR of current pair to result\n result += arr[i] ^ arr[j]\n \n return result", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(arr, n):\n # Calculate the sum of xor of all pairs using the formula\n result = 0\n for bit_position in range(32):\n count_set_bits = 0\n for i in range(n):\n if arr[i] & (1 << bit_position):\n count_set_bits += 1\n # Number of pairs with different bits at the current position\n pairs_with_different_bits = count_set_bits * (n - count_set_bits)\n # Add the contribution of the current bit position to the result\n result += (pairs_with_different_bits * (1 << bit_position))\n return result", "matching_cluster_idx": 4}, {"solution": "def pair_xor_Sum(arr, n):\n # Initialize the sum of XORS\n xorSum = 0\n \n # Iterate over all possible pairs and calculate the XOR\n for i in range(n):\n for j in range(i+1, n):\n xorSum += arr[i] ^ arr[j]\n \n return xorSum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(arr, n):\n # Initialize the result to store the sum of XOR\n result = 0\n \n # Iterate through the array to calculate the sum of XOR for all pairs\n for i in range(n):\n for j in range(i + 1, n):\n result += arr[i] ^ arr[j]\n \n return result", "matching_cluster_idx": 2}]}, "Mbpp/644": {"dps": 66.17021276595743, "dps_norm": 75.0, "pass@1": 97.0, "profiled": [{"solution": "def reverse_Array_Upto_K(arr, k):\n # Slice the array up to the position k and reverse it\n reversed_part = arr[:k][::-1]\n \n # Concatenate the reversed part with the remaining part of the array\n result = reversed_part + arr[k:]\n \n return result", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n # Check if k is valid\n if not 0 < k <= len(arr):\n raise ValueError(\"k must be within the length of the array and greater than 0\")\n \n # Reverse the array up to the position k\n left, right = 0, k - 1\n while left < right:\n arr[left], arr[right] = arr[right], arr[left]\n left, right = left + 1, right - 1\n \n return arr", "matching_cluster_idx": 6}, {"solution": "def reverse_Array_Upto_K(arr, k):\n # Reverse the array up to the position k-1\n left = 0\n right = k - 1\n while left < right:\n arr[left], arr[right] = arr[right], arr[left]\n left += 1\n right -= 1\n return arr", "matching_cluster_idx": 6}, {"solution": "def reverse_Array_Upto_K(arr, k):\n # Extract the portion of the array up to index k and reverse it\n reversed_portion = arr[:k][::-1]\n # Combine the reversed portion with the rest of the array\n result = reversed_portion + arr[k:]\n return result", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n # Extract the portion of the array up to position k (non-inclusive)\n portion = arr[:k]\n # Reverse the portion\n portion.reverse()\n # Replace the original portion with the reversed portion\n arr[:k] = portion\n return arr", "matching_cluster_idx": 13}, {"solution": "def reverse_Array_Upto_K(arr, k):\n # Reverse the array up to the position k\n return arr[:k][::-1] + arr[k:]", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n # Reverse the elements up to the given position k\n left = 0\n right = k - 1\n while left < right:\n arr[left], arr[right] = arr[right], arr[left]\n left += 1\n right -= 1\n return arr", "matching_cluster_idx": 7}, {"solution": "def reverse_Array_Upto_K(arr, k):\n # Extract the subarray from start to position k and reverse it\n subarray = arr[:k]\n subarray.reverse()\n \n # Combine the reversed subarray with the rest of the array\n return subarray + arr[k:]", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n # Create a copy of the array to avoid modifying the original array\n arr = arr.copy()\n # Reverse the array up to position k (non-inclusive)\n arr[:k] = reversed(arr[:k])\n return arr", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n # Check if k is within the array bounds\n if k < 1 or k > len(arr):\n raise ValueError(\"k must be within the bounds of the array\")\n \n # Reverse the elements up to position k\n left = 0\n right = k - 1\n while left < right:\n arr[left], arr[right] = arr[right], arr[left]\n left += 1\n right -= 1\n \n return arr", "matching_cluster_idx": 6}, {"solution": "def reverse_Array_Upto_K(arr, k):\n # Extract the portion of the array up to k and reverse it\n portion = arr[:k]\n portion.reverse()\n # Combine the reversed portion with the rest of the array\n return portion + arr[k:]", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n # Ensure k does not exceed the length of the array\n k = min(k, len(arr))\n \n # Reverse the elements from the start up to the k-1 position\n arr[:k] = arr[:k][::-1]\n \n return arr", "matching_cluster_idx": 12}, {"solution": "def reverse_Array_Upto_K(arr, k):\n # Reverse the array up to the position k\n arr[:k] = reversed(arr[:k])\n return arr", "matching_cluster_idx": 12}, {"solution": "def reverse_Array_Upto_K(arr, k):\n # Ensure k is within the bounds of the array length\n k = min(k, len(arr))\n \n # Reverse the array up to index k\n arr[:k] = arr[:k][::-1]\n \n return arr", "matching_cluster_idx": 12}, {"solution": "def reverse_Array_Upto_K(arr, k):\n # Reverse the array up to the position k-1\n arr[:k] = arr[:k][::-1]\n return arr", "matching_cluster_idx": 13}, {"solution": "def reverse_Array_Upto_K(arr, k):\n # Reverse the array up to the position k\n left = 0\n right = k - 1\n while left < right:\n arr[left], arr[right] = arr[right], arr[left]\n left += 1\n right -= 1\n return arr", "matching_cluster_idx": 7}, {"solution": "def reverse_Array_Upto_K(arr, k):\n # Reverse the array up to the given position k\n arr[:k] = arr[:k][::-1]\n return arr", "matching_cluster_idx": 13}, {"solution": "def reverse_Array_Upto_K(arr, k):\n # Reverse the sublist from the start up to but not including position k\n arr[:k] = arr[:k][::-1]\n return arr", "matching_cluster_idx": 13}, {"solution": "def reverse_Array_Upto_K(arr, k):\n # Reverse the portion of the array up to index k\n arr[:k] = reversed(arr[:k])\n return arr", "matching_cluster_idx": 12}, {"solution": "def reverse_Array_Upto_K(arr, k):\n # Extract the subarray up to the given position k and reverse it\n subarray = arr[:k]\n reversed_subarray = subarray[::-1]\n \n # Replace the original subarray with the reversed subarray\n arr[:k] = reversed_subarray\n \n return arr", "matching_cluster_idx": 13}]}, "Mbpp/720": {"dps": 96.92307692307692, "dps_norm": 99.0, "pass@1": 97.0, "profiled": [{"solution": "def add_dict_to_tuple(tup, dictionary):\n # Append the dictionary to the tuple\n updated_tuple = tup + (dictionary,)\n return updated_tuple", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(tup, dictionary):\n # Concatenate the tuple with the dictionary\n result = tup + (dictionary,)\n return result", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(tup, dictionary):\n # Add the dictionary to the tuple\n new_tuple = tup + (dictionary,)\n return new_tuple", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(tup, dictionary):\n # Append the dictionary to the tuple\n updated_tuple = tup + (dictionary,)\n return updated_tuple", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(tup, dictionary):\n # Concatenate the tuple and the dictionary enclosed in another tuple\n new_tuple = tup + (dictionary,)\n return new_tuple", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(tup, dict_to_add):\n # Concatenate the tuple with the dictionary converted to a tuple\n return tup + (dict_to_add,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(t, d):\n # Append the dictionary to the tuple and return the new tuple\n new_tuple = t + (d,)\n return new_tuple", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(tup, dictionary):\n # Append the dictionary to the tuple\n new_tuple = tup + (dictionary,)\n return new_tuple", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(tup, dictionary):\n # Append the dictionary to the tuple\n updated_tuple = tup + (dictionary,)\n return updated_tuple", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(input_tuple, input_dict):\n # Add the dictionary to the end of the tuple\n result_tuple = input_tuple + (input_dict,)\n return result_tuple", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(tup, dictionary):\n # Create a new tuple by concatenating the original tuple with the dictionary\n new_tuple = tup + (dictionary,)\n return new_tuple", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(tup, dict_to_add):\n # Return a new tuple that is the original tuple plus the added dictionary\n return tup + (dict_to_add,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(tup, dictionary):\n # Add the dictionary to the tuple\n updated_tuple = tup + (dictionary,)\n return updated_tuple", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(tup, dictionary):\n # Append the dictionary to the tuple\n result = tup + (dictionary,)\n return result", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(tup, dic):\n # Add the dictionary to the end of the tuple\n result = tup + (dic,)\n return result", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(tup, dictionary):\n # Concatenate the tuple and the dictionary as a tuple of tuples\n return tup + (dictionary,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(tup, dictionary):\n # Concatenate the tuple and the dictionary inside a tuple\n return tup + (dictionary,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(input_tuple, input_dict):\n # Append the dictionary to the tuple by converting the dictionary to a tuple of tuples and then to a tuple\n result = input_tuple + (input_dict,)\n return result", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(input_tuple, input_dict):\n # Concatenate the tuple with the dictionary wrapped in a tuple\n result = input_tuple + (input_dict,)\n return result", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(tup, dictionary):\n # Convert the tuple to a list to allow modification\n modified_list = list(tup)\n # Append the dictionary to the list\n modified_list.append(dictionary)\n # Convert the list back to a tuple\n result_tuple = tuple(modified_list)\n return result_tuple", "matching_cluster_idx": 3}]}, "Mbpp/725": {"dps": 69.2896174863388, "dps_norm": 73.125, "pass@1": 97.0, "profiled": [{"solution": "import re\ndef extract_quotation(input_string):\n # Use regular expression to find all text enclosed in double quotes\n matches = re.findall(r'\"(.*?)\"', input_string)\n return matches", "matching_cluster_idx": 4}, {"solution": "import re\ndef extract_quotation(input_string):\n # Use regular expression to find all text within double quotes\n matches = re.findall(r'\"(.*?)\"', input_string)\n return matches", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(s):\n # Use regular expression to find all text enclosed in double quotes\n matches = re.findall(r'\"(.*?)\"', s)\n return matches", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(s):\n # Use regular expression to find all text enclosed in double quotes\n matches = re.findall(r'\"([^\"]*)\"', s)\n return matches", "matching_cluster_idx": 6}, {"solution": "import re\ndef extract_quotation(input_string):\n # Use regular expression to find all text enclosed in double quotes\n return re.findall(r'\"(.*?)\"', input_string)", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(input_string):\n # Use regular expression to find all text enclosed in double quotes\n matches = re.findall(r'\"(.*?)\"', input_string)\n return matches", "matching_cluster_idx": 4}, {"solution": "import re\ndef extract_quotation(text):\n # Use regular expression to find all text enclosed in double quotes\n return re.findall(r'\"(.*?)\"', text)", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(s):\n # Use regular expression to find all text enclosed in double quotes\n matches = re.findall(r'\"(.*?)\"', s)\n return matches", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(input_string):\n # Use regular expression to find all text within quotes\n matches = re.findall(r'\"(.*?)\"', input_string)\n return matches", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(input_string):\n # Use regular expression to find all text within double quotes\n matches = re.findall(r'\"(.*?)\"', input_string)\n return matches", "matching_cluster_idx": 5}, {"solution": "def extract_quotation(s):\n # Import the re module for regular expression operations\n import re\n \n # Use re.findall to extract all substrings enclosed in double quotes\n return re.findall(r'\"(.*?)\"', s)", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(input_string):\n # Use regular expression to find all text enclosed in double quotes\n matches = re.findall(r'\"(.*?)\"', input_string)\n return matches", "matching_cluster_idx": 4}, {"solution": "import re\ndef extract_quotation(input_string):\n # Use regular expression to find all text within double quotes\n matches = re.findall(r'\"(.*?)\"', input_string)\n return matches", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(input_string):\n # Use regular expression to find all text enclosed in double quotes\n matches = re.findall(r'\"(.*?)\"', input_string)\n return matches", "matching_cluster_idx": 4}, {"solution": "import re\ndef extract_quotation(input_string):\n # Use regular expression to find all substrings enclosed in double quotes\n matches = re.findall(r'\"(.*?)\"', input_string)\n return matches", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(input_string):\n # Use regular expression to find all substrings enclosed in double quotes\n matches = re.findall(r'\"(.*?)\"', input_string)\n return matches", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(s):\n # Use regular expression to find all text enclosed in double quotes\n matches = re.findall(r'\"(.*?)\"', s)\n return matches", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(input_string):\n # Use regular expression to find all text enclosed in double quotes\n return re.findall(r'\"(.*?)\"', input_string)", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(input_string):\n # Use regular expression to find all text enclosed in double quotes\n return re.findall(r'\"(.*?)\"', input_string)", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(s):\n # Use regular expression to find all text enclosed in double quotes\n return re.findall(r'\"(.*?)\"', s)", "matching_cluster_idx": 5}]}, "Mbpp/732": {"dps": 69.94186046511628, "dps_norm": 82.0, "pass@1": 100.0, "profiled": [{"solution": "def replace_specialchar(input_string):\n # Define the characters to be replaced and the replacement character\n chars_to_replace = [' ', ',', '.']\n replacement_char = ':'\n \n # Replace each occurrence of the specified characters with the replacement character\n for char in chars_to_replace:\n input_string = input_string.replace(char, replacement_char)\n \n return input_string", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(input_string):\n # Define the characters to replace and the replacement character\n chars_to_replace = ' ,.'\n replacement_char = ':'\n \n # Replace each occurrence of the characters in chars_to_replace with replacement_char\n result_string = ''.join([replacement_char if char in chars_to_replace else char for char in input_string])\n \n return result_string", "matching_cluster_idx": 5}, {"solution": "def replace_specialchar(input_string):\n # Replace spaces, commas, and dots with colon\n result = input_string.replace(' ', ':').replace(',', ':').replace('.', ':')\n return result", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(input_string):\n # Replace spaces, commas, or dots with a colon\n result = input_string.replace(' ', ':').replace(',', ':').replace('.', ':')\n return result", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(input_string):\n # Replace spaces, commas, or dots with a colon\n result = input_string.replace(' ', ':').replace(',', ':').replace('.', ':')\n return result", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(input_string):\n # Replace spaces, commas, and dots with colon\n result_string = input_string.replace(' ', ':').replace(',', ':').replace('.', ':')\n return result_string", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(input_string):\n # Define the characters to be replaced and the replacement character\n chars_to_replace = [' ', ',', '.']\n replacement_char = ':'\n \n # Replace all occurrences of the characters with the replacement character\n result = input_string\n for char in chars_to_replace:\n result = result.replace(char, replacement_char)\n \n return result", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(input_string):\n # Replace spaces, commas, and dots with colon\n result = input_string.replace(' ', ':').replace(',', ':').replace('.', ':')\n return result", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(input_string):\n # Define the characters to replace and the replacement character\n special_chars = ' ,.'\n replacement_char = ':'\n \n # Replace each special character in the string with the replacement character\n result_string = ''\n for char in input_string:\n if char in special_chars:\n result_string += replacement_char\n else:\n result_string += char\n \n return result_string", "matching_cluster_idx": 3}, {"solution": "def replace_specialchar(input_string):\n # Define the characters to replace and the replacement character\n special_chars = ' ,.'\n replacement = ':'\n \n # Replace each special character with the replacement character\n result = ''\n for char in input_string:\n if char in special_chars:\n result += replacement\n else:\n result += char\n \n return result", "matching_cluster_idx": 3}, {"solution": "def replace_specialchar(input_string):\n # Define the characters to be replaced and the replacement character\n special_chars = \" ,.\"\n replacement_char = \":\"\n \n # Replace each occurrence of the special characters with the replacement character\n result_string = \"\"\n for char in input_string:\n if char in special_chars:\n result_string += replacement_char\n else:\n result_string += char\n \n return result_string", "matching_cluster_idx": 3}, {"solution": "def replace_specialchar(input_string):\n # Define the characters to replace and the replacement character\n special_chars = ' ,.'\n replacement = ':'\n \n # Replace each special character in the string with the replacement character\n result_string = ''.join(char if char not in special_chars else replacement for char in input_string)\n \n return result_string", "matching_cluster_idx": 5}, {"solution": "def replace_specialchar(input_string):\n # Replace spaces, commas, or dots with a colon\n result = input_string.replace(' ', ':').replace(',', ':').replace('.', ':')\n return result", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(input_string):\n # Define the characters to replace and the replacement character\n special_chars = ' ,.'\n replace_with = ':'\n \n # Replace each special character with the replacement character\n for char in special_chars:\n input_string = input_string.replace(char, replace_with)\n \n return input_string", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(input_string):\n # Replace spaces, commas, or dots with a colon\n result = input_string.replace(' ', ':').replace(',', ':').replace('.', ':')\n return result", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(input_string):\n # Replace spaces, commas, or dots with a colon\n result = input_string.replace(' ', ':').replace(',', ':').replace('.', ':')\n return result", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(input_string):\n # Define the characters to replace and the replacement character\n special_chars = ' ,.'\n replacement = ':'\n \n # Replace each occurrence of special characters with the replacement character\n result_string = ''.join([char if char not in special_chars else replacement for char in input_string])\n \n return result_string", "matching_cluster_idx": 5}, {"solution": "def replace_specialchar(input_string):\n # Define the characters to replace and the replacement character\n special_chars = ' ,.'\n replacement_char = ':'\n \n # Replace each special character with the replacement character\n result = \"\"\n for char in input_string:\n if char in special_chars:\n result += replacement_char\n else:\n result += char\n \n return result", "matching_cluster_idx": 3}, {"solution": "def replace_specialchar(input_string):\n # Replace spaces, commas, or dots with a colon\n result = input_string.replace(' ', ':').replace(',', ':').replace('.', ':')\n return result", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(input_string):\n # Replace spaces, commas, and dots with colons\n result = input_string.replace(' ', ':').replace(',', ':').replace('.', ':')\n return result", "matching_cluster_idx": 9}]}, "Mbpp/740": {"dps": 77.58181818181818, "dps_norm": 66.11111111111111, "pass@1": 100.0, "profiled": [{"solution": "def tuple_to_dict(tup):\n # Create an empty dictionary\n result_dict = {}\n \n # Iterate through the tuple in steps of 2 to create key-value pairs\n for i in range(0, len(tup) - 1, 2):\n # Add key-value pairs to the dictionary\n result_dict[tup[i]] = tup[i + 1]\n \n return result_dict", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(tup):\n # Create a dictionary from the tuple by pairing adjacent elements\n result_dict = {}\n for i in range(0, len(tup), 2):\n if i + 1 < len(tup):\n result_dict[tup[i]] = tup[i + 1]\n return result_dict", "matching_cluster_idx": 3}, {"solution": "def tuple_to_dict(input_tuple):\n # Create a dictionary by zipping two adjacent elements of the input tuple\n result_dict = dict(zip(input_tuple[::2], input_tuple[1::2]))\n return result_dict", "matching_cluster_idx": 8}, {"solution": "def tuple_to_dict(test_tuple):\n # Create a dictionary from the tuple by pairing adjacent elements\n result_dict = {test_tuple[i]: test_tuple[i + 1] for i in range(0, len(test_tuple) - 1, 2)}\n return result_dict", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(t):\n # Ensure the tuple has an even number of elements for proper key-value pairing\n if len(t) % 2 != 0:\n raise ValueError(\"Tuple must contain an even number of elements for key-value pairing.\")\n \n # Create a dictionary using adjacent elements as key-value pairs\n result_dict = {t[i]: t[i + 1] for i in range(0, len(t), 2)}\n return result_dict", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(tpl):\n # Create an empty dictionary\n result_dict = {}\n \n # Iterate over the tuple in steps of 2 to get adjacent elements\n for i in range(0, len(tpl) - 1, 2):\n key = tpl[i]\n value = tpl[i + 1]\n result_dict[key] = value\n \n return result_dict", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(tup):\n # Check if the tuple has an even number of elements\n if len(tup) % 2 != 0:\n raise ValueError(\"Tuple must contain an even number of elements\")\n \n # Create a dictionary by pairing adjacent elements in the tuple\n result_dict = dict()\n for i in range(0, len(tup), 2):\n result_dict[tup[i]] = tup[i + 1]\n \n return result_dict", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(tup):\n # Create an empty dictionary to store the result\n result_dict = {}\n # Loop through the tuple in steps of 2 to get key-value pairs\n for i in range(0, len(tup) - 1, 2):\n # Add the key-value pair to the dictionary\n result_dict[tup[i]] = tup[i + 1]\n return result_dict", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(tup):\n # Create a dictionary using adjacent elements of the tuple\n result_dict = {tup[i]: tup[i + 1] for i in range(0, len(tup), 2)}\n return result_dict", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(test_tup):\n res = dict()\n # Loop through the tuple in steps of 2 to create key-value pairs\n for key_val in range(0, len(test_tup) - 1, 2):\n key = test_tup[key_val]\n value = test_tup[key_val + 1]\n res[key] = value\n return res", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(test_tuple):\n # Create a dictionary from the tuple by using adjacent elements as key-value pairs\n result_dict = {test_tuple[i]: test_tuple[i + 1] for i in range(0, len(test_tuple), 2)}\n return result_dict", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(tup):\n # Check if the tuple has an even number of elements\n if len(tup) % 2 != 0:\n raise ValueError(\"Tuple must contain an even number of elements\")\n \n # Create a dictionary from adjacent tuple elements\n result_dict = {tup[i]: tup[i + 1] for i in range(0, len(tup), 2)}\n return result_dict", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(test_tup):\n res = dict()\n # Loop through the tuple two elements at a time\n for i in range(0, len(test_tup) - 1, 2):\n key = test_tup[i]\n value = test_tup[i + 1]\n res[key] = value\n return res", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(test_tup):\n # Create an empty dictionary\n res = {}\n \n # Iterate over the tuple in steps of 2 to get adjacent elements\n for i in range(0, len(test_tup) - 1, 2):\n # Use the first element of the pair as key and second as value\n res[test_tup[i]] = test_tup[i + 1]\n \n return res", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(tup):\n # Create an empty dictionary\n result_dict = {}\n # Ensure the tuple has even number of elements to form key-value pairs\n if len(tup) % 2 != 0:\n raise ValueError(\"Tuple must contain an even number of elements to form key-value pairs.\")\n \n # Iterate through the tuple in steps of 2 to get key-value pairs\n for i in range(0, len(tup), 2):\n key = tup[i]\n value = tup[i + 1]\n result_dict[key] = value\n \n return result_dict", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(test_tuple):\n # Create an empty dictionary\n result_dict = {}\n \n # Iterate through the tuple in steps of 2 to get key-value pairs\n for i in range(0, len(test_tuple) - 1, 2):\n key = test_tuple[i]\n value = test_tuple[i + 1]\n result_dict[key] = value\n \n return result_dict", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(t):\n # Create an empty dictionary\n result_dict = {}\n # Loop through the tuple in steps of 2 to get key-value pairs\n for i in range(0, len(t) - 1, 2):\n key = t[i]\n value = t[i + 1]\n # Add key-value pair to the dictionary\n result_dict[key] = value\n return result_dict", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(t):\n # Create a dictionary from the tuple by pairing adjacent elements\n result_dict = {}\n # Loop through the tuple in steps of 2 to get adjacent pairs\n for i in range(0, len(t), 2):\n key = t[i]\n value = t[i + 1] if i + 1 < len(t) else None\n result_dict[key] = value\n return result_dict", "matching_cluster_idx": 3}, {"solution": "def tuple_to_dict(test_tuples):\n # Create a dictionary by pairing adjacent elements in the tuple\n result_dict = {test_tuples[i]: test_tuples[i + 1] for i in range(0, len(test_tuples) - 1, 2)}\n return result_dict", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(input_tuple):\n # Check if the tuple length is even, as we need pairs of elements\n if len(input_tuple) % 2 != 0:\n raise ValueError(\"Tuple must contain an even number of elements for key-value pairs\")\n \n # Create an empty dictionary\n result_dict = {}\n \n # Iterate through the tuple two elements at a time\n for i in range(0, len(input_tuple), 2):\n key = input_tuple[i]\n value = input_tuple[i + 1]\n result_dict[key] = value\n \n return result_dict", "matching_cluster_idx": 5}]}, "Mbpp/744": {"dps": 18.698630136986303, "dps_norm": 43.333333333333336, "pass@1": 98.0, "profiled": [{"solution": "def check_none(input_tuple):\n # Check if any element in the tuple is None\n return any(item is None for item in input_tuple)", "matching_cluster_idx": 2}, {"solution": "def check_none(test_tuple):\n # Check if any element in the tuple is None\n res = any(item is None for item in test_tuple)\n return res", "matching_cluster_idx": 1}, {"solution": "def check_none(test_tuple):\n # Check if any element in the tuple is None\n for elem in test_tuple:\n if elem is None:\n return True\n return False", "matching_cluster_idx": 4}, {"solution": "def check_none(test_tuple):\n # Check if any element in the tuple is None\n return any(item is None for item in test_tuple)", "matching_cluster_idx": 1}, {"solution": "def check_none(input_tuple):\n # Check if any element in the tuple is None\n return any(item is None for item in input_tuple)", "matching_cluster_idx": 2}, {"solution": "def check_none(input_tuple):\n # Check if any element in the tuple is None\n return any(item is None for item in input_tuple)", "matching_cluster_idx": 2}, {"solution": "def check_none(test_tuple):\n # Check if any element in the tuple is None\n res = any(element is None for element in test_tuple)\n return res", "matching_cluster_idx": 1}, {"solution": "def check_none(input_tuple):\n # Check if any element in the tuple is None\n return any(item is None for item in input_tuple)", "matching_cluster_idx": 2}, {"solution": "def check_none(test_tuple):\n # Check if any element in the tuple is None\n return any(item is None for item in test_tuple)", "matching_cluster_idx": 1}, {"solution": "def check_none(test_tuple):\n # Check if any element in the tuple is None\n res = any(item is None for item in test_tuple)\n return res", "matching_cluster_idx": 1}, {"solution": "def check_none(test_tuple):\n # Check if any element in the tuple is None\n return any(item is None for item in test_tuple)", "matching_cluster_idx": 1}, {"solution": "def check_none(test_tuple):\n # Check if any element in the tuple is None\n return any(item is None for item in test_tuple)", "matching_cluster_idx": 1}, {"solution": "def check_none(test_tuple):\n # Check if any element in the tuple is None\n res = any(element is None for element in test_tuple)\n return res", "matching_cluster_idx": 1}, {"solution": "def check_none(test_tuple):\n # Check if any element in the tuple is None\n res = any(elem is None for elem in test_tuple)\n return res", "matching_cluster_idx": 1}, {"solution": "def check_none(test_tuple):\n # Check if any element in the tuple is None\n return any(item is None for item in test_tuple)", "matching_cluster_idx": 1}, {"solution": "def check_none(test_tuple):\n # Check if any element in the tuple is None\n return any(item is None for item in test_tuple)", "matching_cluster_idx": 1}, {"solution": "def check_none(test_tuple):\n # Check if any element in the tuple is None\n for element in test_tuple:\n if element is None:\n return True\n return False", "matching_cluster_idx": 4}, {"solution": "def check_none(input_tuple):\n # Check if any element in the tuple is None\n return any(item is None for item in input_tuple)", "matching_cluster_idx": 2}, {"solution": "def check_none(input_tuple):\n # Check if any element in the tuple is None\n return any(item is None for item in input_tuple)", "matching_cluster_idx": 2}, {"solution": "def check_none(test_tuple):\n # Check if any element in the tuple is None\n return any(item is None for item in test_tuple)", "matching_cluster_idx": 1}]}, "Mbpp/750": {"dps": 91.39455782312925, "dps_norm": 91.66666666666667, "pass@1": 100.0, "profiled": [{"solution": "def add_tuple(lst, tuple_to_add):\n # Extend the list with the elements of the tuple\n lst.extend(tuple_to_add)\n return lst", "matching_cluster_idx": 5}, {"solution": "def add_tuple(lst, tpl):\n # Extend the list with elements from the tuple\n lst.extend(tpl)\n return lst", "matching_cluster_idx": 5}, {"solution": "def add_tuple(lst, tup):\n # Add the elements of the tuple to the end of the list\n lst.extend(tup)\n return lst", "matching_cluster_idx": 5}, {"solution": "def add_tuple(lst, tup):\n # Extend the list by appending elements from the tuple\n lst.extend(tup)\n return lst", "matching_cluster_idx": 5}, {"solution": "def add_tuple(lst, tup):\n # Extend the list with the elements of the tuple\n lst.extend(tup)\n return lst", "matching_cluster_idx": 5}, {"solution": "def add_tuple(lst, tup):\n # Extend the list with elements from the tuple\n lst.extend(tup)\n return lst", "matching_cluster_idx": 5}, {"solution": "def add_tuple(lst, tup):\n # Add the tuple elements to the list\n lst.extend(tup)\n return lst", "matching_cluster_idx": 5}, {"solution": "def add_tuple(lst, t):\n # Extend the list by unpacking the tuple\n lst.extend(t)\n return lst", "matching_cluster_idx": 5}, {"solution": "def add_tuple(lst, tup):\n # Add the elements of the tuple to the list\n lst += tup\n return lst", "matching_cluster_idx": 5}, {"solution": "def add_tuple(lst, tpl):\n # Extend the list with the elements of the tuple\n lst.extend(tpl)\n # Return the updated list\n return lst", "matching_cluster_idx": 5}, {"solution": "def add_tuple(lst, tpl):\n # Extend the list by unpacking the tuple\n lst.extend(tpl)\n return lst", "matching_cluster_idx": 5}, {"solution": "def add_tuple(lst, tup):\n # Adding the elements of the tuple to the end of the list\n return lst + list(tup)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(lst, tup):\n # Extend the list with elements from the tuple\n lst.extend(tup)\n return lst", "matching_cluster_idx": 5}, {"solution": "def add_tuple(lst, tpl):\n # Add the elements of the tuple to the end of the list\n return lst + list(tpl)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(lst, tpl):\n # Extend the list with the elements of the tuple\n lst.extend(tpl)\n return lst", "matching_cluster_idx": 5}, {"solution": "def add_tuple(lst, tup):\n # Add elements from the tuple to the list\n lst += tup\n return lst", "matching_cluster_idx": 5}, {"solution": "def add_tuple(lst, tup):\n # Extend the list with the elements of the tuple\n lst.extend(tup)\n return lst", "matching_cluster_idx": 5}, {"solution": "def add_tuple(lst, tup):\n # Extend the list by unpacking the tuple\n lst.extend(tup)\n return lst", "matching_cluster_idx": 5}, {"solution": "def add_tuple(lst, tpl):\n # Add the elements of the tuple to the list\n lst += list(tpl)\n return lst", "matching_cluster_idx": 4}, {"solution": "def add_tuple(lst, tup):\n # Add the elements of the tuple to the list\n return lst + list(tup)", "matching_cluster_idx": 2}]}, "Mbpp/753": {"dps": 97.31543624161074, "dps_norm": 75.0, "pass@1": 100.0, "profiled": [{"solution": "def min_k(records, k):\n \"\"\"\n Find the minimum k records from the given list of tuples based on the second element of each tuple.\n \n Args:\n records: A list of tuples, where each tuple contains at least two elements.\n k: The number of minimum records to find.\n \n Returns:\n A list of tuples containing the k records with the smallest second elements.\n \"\"\"\n # Sort the list of tuples based on the second element of each tuple\n sorted_records = sorted(records, key=lambda x: x[1])\n # Return the first k elements from the sorted list\n return sorted_records[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(records, k):\n \"\"\"\n Given a list of tuples representing records, and an integer k, this function returns the k records with the smallest second elements.\n \n :param records: List of tuples, where each tuple contains a name and a number\n :param k: Number of records to return\n :return: A list of k tuples with the smallest second elements\n \"\"\"\n # Sort the records based on the second element of each tuple\n sorted_records = sorted(records, key=lambda x: x[1])\n # Return the first k elements from the sorted list\n return sorted_records[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(records, k):\n \"\"\"\n Find the minimum k records from a list of tuples based on the second element of each tuple.\n \n :param records: List of tuples, where each tuple contains at least two elements.\n :param k: Number of minimum records to find.\n :return: A list of tuples containing the k records with the smallest second elements.\n \"\"\"\n # Sort the list of tuples based on the second element of each tuple\n sorted_records = sorted(records, key=lambda x: x[1])\n # Return the first k elements from the sorted list\n return sorted_records[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(records, k):\n # Use the sorted function to sort the records based on the second element of each tuple\n sorted_records = sorted(records, key=lambda x: x[1])\n # Slice the first k elements from the sorted list\n return sorted_records[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(records, k):\n # Use the sorted function to sort the records based on the second item in each tuple\n # Then slice the first k elements from the sorted list\n return sorted(records, key=lambda x: x[1])[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(records, k):\n # Sort the list of tuples based on the second element of each tuple\n sorted_records = sorted(records, key=lambda x: x[1])\n # Return the first k elements from the sorted list\n return sorted_records[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(records, k):\n # Sort the list of tuples based on the second element (score)\n sorted_records = sorted(records, key=lambda x: x[1])\n # Return the first k elements from the sorted list\n return sorted_records[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(records, k):\n # Sort the list of tuples based on the second item (score) in ascending order\n sorted_records = sorted(records, key=lambda x: x[1])\n # Return the first k elements from the sorted list\n return sorted_records[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(records, k):\n # Sort the list of tuples based on the second element (score)\n sorted_records = sorted(records, key=lambda x: x[1])\n # Return the first k elements from the sorted list\n return sorted_records[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(records, k):\n # Sort the list of tuples based on the second element (score)\n sorted_records = sorted(records, key=lambda x: x[1])\n # Return the first k elements from the sorted list\n return sorted_records[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(tuple_list, k):\n # Sort the list of tuples based on the second item (score) in ascending order\n sorted_list = sorted(tuple_list, key=lambda x: x[1])\n # Return the first k elements from the sorted list\n return sorted_list[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(records, k):\n # Sort the records based on the second element (score) in each tuple\n sorted_records = sorted(records, key=lambda x: x[1])\n # Return the first k elements from the sorted list\n return sorted_records[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(lst, k):\n # Use sorted function to sort the list of tuples based on the second item (score) in ascending order\n sorted_lst = sorted(lst, key=lambda x: x[1])\n # Return the first k elements from the sorted list\n return sorted_lst[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(tuple_list, k):\n # Sort the list of tuples based on the second item in each tuple\n sorted_list = sorted(tuple_list, key=lambda x: x[1])\n # Return the first k elements from the sorted list\n return sorted_list[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(lst, k):\n # Use the sorted function to sort the list of tuples based on the second element\n # Then, slice the first k elements from the sorted list\n return sorted(lst, key=lambda x: x[1])[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(tuple_list, k):\n # Sort the tuple list based on the second element of each tuple\n sorted_list = sorted(tuple_list, key=lambda x: x[1])\n # Return the first k elements from the sorted list\n return sorted_list[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(data, k):\n \"\"\"\n Finds the minimum k records from a list of tuples based on the second element of each tuple.\n \n :param data: List of tuples where each tuple contains at least two elements.\n :param k: Number of minimum records to find.\n :return: A list of k tuples with the smallest second elements.\n \"\"\"\n # Sort the list of tuples based on the second element of each tuple\n sorted_data = sorted(data, key=lambda x: x[1])\n # Return the first k elements from the sorted list\n return sorted_data[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(tuple_list, k):\n # Sort the list of tuples based on the second item in each tuple\n sorted_list = sorted(tuple_list, key=lambda x: x[1])\n # Return the first k elements from the sorted list\n return sorted_list[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(records, k):\n # Sort the list of tuples based on the second element (score) in ascending order\n sorted_records = sorted(records, key=lambda x: x[1])\n # Return the first k records from the sorted list\n return sorted_records[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(records, k):\n # Sort the list of tuples based on the second item in each tuple\n sorted_records = sorted(records, key=lambda x: x[1])\n # Return the first k elements from the sorted list\n return sorted_records[:k]", "matching_cluster_idx": 2}]}, "Mbpp/754": {"dps": 89.65517241379311, "dps_norm": 87.5, "pass@1": 91.0, "profiled": [{"solution": "def extract_index_list(l1, l2, l3):\n # Initialize an empty list to store common elements\n common_elements = []\n \n # Determine the length of the shortest list\n min_length = min(len(l1), len(l2), len(l3))\n \n # Iterate over the range of the shortest list length\n for i in range(min_length):\n # Check if the current elements in all three lists are the same\n if l1[i] == l2[i] == l3[i]:\n # If so, add the element to the common_elements list\n common_elements.append(l1[i])\n \n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n # Initialize an empty list to store the common elements\n common_elements = []\n \n # Get the length of the shortest list\n min_len = min(len(l1), len(l2), len(l3))\n \n # Iterate through the lists up to the length of the shortest list\n for i in range(min_len):\n # Check if the current elements in all three lists are the same\n if l1[i] == l2[i] == l3[i]:\n # If they are the same, add the element to the common_elements list\n common_elements.append(l1[i])\n \n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n # Initialize an empty list to store the common elements\n common_elements = []\n \n # Get the length of the shortest list\n min_length = min(len(l1), len(l2), len(l3))\n \n # Iterate up to the length of the shortest list\n for i in range(min_length):\n # Check if elements at index i are the same in all three lists\n if l1[i] == l2[i] == l3[i]:\n # If so, append the element to the common_elements list\n common_elements.append(l1[i])\n \n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n # Initialize an empty list to store the common elements\n common_elements = []\n \n # Determine the length of the shortest list\n min_length = min(len(l1), len(l2), len(l3))\n \n # Iterate through the indices from 0 to min_length-1\n for i in range(min_length):\n # Check if the elements at the current index are the same in all three lists\n if l1[i] == l2[i] == l3[i]:\n # If so, append the element to the common_elements list\n common_elements.append(l1[i])\n \n # Return the list of common elements\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n # Initialize an empty list to store the common elements\n common_elements = []\n \n # Get the length of the shortest list to avoid index out of range errors\n min_length = min(len(l1), len(l2), len(l3))\n \n # Iterate through the lists up to the length of the shortest list\n for i in range(min_length):\n # Check if the elements at the current index are the same in all three lists\n if l1[i] == l2[i] == l3[i]:\n # If so, add the element to the common_elements list\n common_elements.append(l1[i])\n \n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n # Use a list comprehension to filter elements that are present in all three lists at the same index\n result = [l1[i] for i in range(min(len(l1), len(l2), len(l3))) if l1[i] == l2[i] == l3[i]]\n return result", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n # Initialize an empty list to store the common elements\n common_elements = []\n \n # Find the minimum length among the three lists to avoid index out of range errors\n min_len = min(len(l1), len(l2), len(l3))\n \n # Iterate through the lists up to the minimum length\n for i in range(min_len):\n # Check if the elements at the current index are the same in all three lists\n if l1[i] == l2[i] == l3[i]:\n # If so, add the element to the common_elements list\n common_elements.append(l1[i])\n \n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n # Initialize an empty list to store the common elements\n common_elements = []\n # Determine the length of the shortest list to avoid index out of range errors\n min_length = min(len(l1), len(l2), len(l3))\n \n # Iterate through the lists up to the length of the shortest list\n for i in range(min_length):\n # Check if the current elements in all three lists are the same\n if l1[i] == l2[i] == l3[i]:\n # If they are the same, append the element to the common_elements list\n common_elements.append(l1[i])\n \n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n # Initialize an empty list to store the common elements\n common_elements = []\n \n # Get the length of the shortest list\n min_length = min(len(l1), len(l2), len(l3))\n \n # Iterate over the indices of the shortest list\n for i in range(min_length):\n # Check if the elements at index i are the same in all three lists\n if l1[i] == l2[i] == l3[i]:\n # If so, add the element to the common_elements list\n common_elements.append(l1[i])\n \n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n # Initialize an empty list to store the common elements\n common_elements = []\n \n # Determine the length of the shortest list\n min_length = min(len(l1), len(l2), len(l3))\n \n # Iterate through the indices from 0 to the minimum length - 1\n for i in range(min_length):\n # Check if the elements at the current index are the same in all three lists\n if l1[i] == l2[i] == l3[i]:\n # If they are, append the element to the common_elements list\n common_elements.append(l1[i])\n \n # Return the list of common elements\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n # Initialize an empty list to store the result\n result = []\n \n # Iterate through the indices of the lists\n for i in range(min(len(l1), len(l2), len(l3))):\n # Check if the elements at the current index are the same in all three lists\n if l1[i] == l2[i] == l3[i]:\n # If so, add the element to the result list\n result.append(l1[i])\n \n # Return the result list\n return result", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n # Initialize an empty list to store the common elements\n common_elements = []\n \n # Find the minimum length of the three lists to avoid index out of range errors\n min_length = min(len(l1), len(l2), len(l3))\n \n # Iterate over the lists up to the minimum length\n for i in range(min_length):\n # Check if the current elements in all three lists are the same\n if l1[i] == l2[i] == l3[i]:\n # If so, add the element to the common_elements list\n common_elements.append(l1[i])\n \n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n # Use list comprehension to iterate and filter common elements\n return [l1[i] for i in range(min(len(l1), len(l2), len(l3))) if l1[i] == l2[i] == l3[i]]", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n # Initialize an empty list to store the common elements\n common_elements = []\n \n # Get the length of the shortest list\n min_length = min(len(l1), len(l2), len(l3))\n \n # Iterate through the lists up to the length of the shortest list\n for i in range(min_length):\n # Check if the current elements at index i are the same in all three lists\n if l1[i] == l2[i] == l3[i]:\n # If they are, add it to the common_elements list\n common_elements.append(l1[i])\n \n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n # Initialize an empty list to store common elements\n common_elements = []\n \n # Get the length of the shortest list to avoid index out of range errors\n min_length = min(len(l1), len(l2), len(l3))\n \n # Iterate over the range of the shortest list\n for i in range(min_length):\n # Check if elements at index i in all three lists are the same\n if l1[i] == l2[i] == l3[i]:\n # If so, append the element to the common_elements list\n common_elements.append(l1[i])\n \n # Return the list of common elements\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n # Initialize an empty list to store common elements\n common_elements = []\n \n # Determine the length of the shortest list\n min_length = min(len(l1), len(l2), len(l3))\n \n # Iterate through the lists up to the length of the shortest list\n for i in range(min_length):\n # Check if the current elements in all three lists are the same\n if l1[i] == l2[i] == l3[i]:\n # If they are, add it to the common_elements list\n common_elements.append(l1[i])\n \n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n \"\"\"\n Returns a list of elements that are common in the same index positions in all three input lists.\n \n :param l1: First list of elements\n :param l2: Second list of elements\n :param l3: Third list of elements\n :return: List of common elements at the same index in all three lists\n \"\"\"\n result = []\n # Ensure all lists have the same length, if not, use the length of the shortest list\n length = min(len(l1), len(l2), len(l3))\n \n for i in range(length):\n if l1[i] == l2[i] == l3[i]:\n result.append(l1[i])\n \n return result", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n # Use list comprehension to iterate through the lists and filter common elements by index\n return [l1[i] for i in range(min(len(l1), len(l2), len(l3))) if l1[i] == l2[i] == l3[i]]", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n # Initialize an empty list to store the common elements\n common_elements = []\n \n # Get the length of the shortest list\n min_length = min(len(l1), len(l2), len(l3))\n \n # Iterate through the lists up to the length of the shortest list\n for i in range(min_length):\n # Check if the elements at the current index are the same in all three lists\n if l1[i] == l2[i] == l3[i]:\n # If they are, add the element to the common_elements list\n common_elements.append(l1[i])\n \n # Return the list of common elements\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n # Initialize an empty list to store the common elements\n common_elements = []\n \n # Get the length of the shortest list\n min_length = min(len(l1), len(l2), len(l3))\n \n # Iterate through the lists and compare elements at the same index\n for i in range(min_length):\n if l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n \n return common_elements", "matching_cluster_idx": 6}]}, "Mbpp/755": {"dps": 49.38053097345133, "dps_norm": 76.66666666666667, "pass@1": 59.0, "profiled": [{"solution": "def second_smallest(nums):\n # Initialize the smallest and second smallest with infinity\n smallest = second_smallest = float('inf')\n \n for num in nums:\n # Update smallest and second smallest accordingly\n if num < smallest:\n second_smallest = smallest\n smallest = num\n elif num < second_smallest and num != smallest:\n second_smallest = num\n \n # If second smallest is still infinity, it means all elements are the same\n return second_smallest if second_smallest != float('inf') else None", "matching_cluster_idx": 4}, {"solution": "def second_smallest(numbers):\n if len(numbers) < 2:\n return None # Not enough elements for a second smallest\n \n # Initialize first and second smallest\n first, second = float('inf'), float('inf')\n \n for n in numbers:\n if n < first:\n second = first\n first = n\n elif n < second and n != first:\n second = n\n \n if second == float('inf'):\n return None # No second smallest found\n else:\n return second", "matching_cluster_idx": 4}, {"solution": "def second_smallest(nums):\n # Initialize the smallest and second smallest with infinity\n first = second = float('inf')\n \n for n in nums:\n # Update first and second smallest numbers if necessary\n if n < first:\n first, second = n, first\n elif first < n < second:\n second = n\n \n return second if second != float('inf') else None", "matching_cluster_idx": 3}, {"solution": "def second_smallest(numbers):\n if len(numbers) < 2:\n return None # Not enough elements for a second smallest number\n \n # Initialize the smallest and second smallest with infinity\n smallest = second_smallest = float('inf')\n \n for number in numbers:\n if number < smallest:\n # Update second smallest before smallest\n second_smallest = smallest\n smallest = number\n elif smallest < number < second_smallest:\n # Update second smallest if number is between smallest and current second smallest\n second_smallest = number\n \n if second_smallest == float('inf'):\n return None # There is no second smallest element\n else:\n return second_smallest", "matching_cluster_idx": 3}, {"solution": "def second_smallest(numbers):\n if len(numbers) < 2:\n return None # Not enough elements to find the second smallest\n \n # Initialize the smallest and second smallest with infinity\n smallest = second_smallest = float('inf')\n \n for num in numbers:\n if num < smallest:\n # Update second smallest before smallest, as smallest is found\n second_smallest = smallest\n smallest = num\n elif num < second_smallest and num != smallest:\n # Update second smallest if num is smaller\n second_smallest = num\n \n if second_smallest == float('inf'):\n return None # No second smallest found\n else:\n return second_smallest", "matching_cluster_idx": 4}, {"solution": "def second_smallest(nums):\n # Initialize two variables to positive infinity\n smallest = second_smallest_num = float('inf')\n \n for num in nums:\n if num < smallest:\n # Update second smallest number and smallest number\n second_smallest_num, smallest = smallest, num\n elif smallest < num < second_smallest_num:\n # Update second smallest number if current number is between smallest and second smallest\n second_smallest_num = num\n \n return second_smallest_num if second_smallest_num != float('inf') else None", "matching_cluster_idx": 3}, {"solution": "def second_smallest(nums):\n # Remove duplicates to avoid issues with identical elements\n unique_nums = list(set(nums))\n \n # Sort the list to bring the smallest and second smallest numbers to the front\n unique_nums.sort()\n \n # Check if there are at least two unique numbers\n if len(unique_nums) < 2:\n return None # Return None if there's no second smallest number\n \n # Return the second smallest number\n return unique_nums[1]", "matching_cluster_idx": 5}, {"solution": "def second_smallest(numbers):\n # Initialize the smallest and second smallest with positive infinity\n first = second = float('inf')\n \n for number in numbers:\n # Update first and second smallest if needed\n if number < first:\n first, second = number, first\n elif first < number < second:\n second = number\n \n return second if second != float('inf') else None", "matching_cluster_idx": 3}, {"solution": "def second_smallest(nums):\n # Handle edge cases with not enough unique elements\n if len(nums) < 2:\n return None\n \n # Initialize the smallest and second smallest with infinity\n smallest = second_smallest = float('inf')\n \n for num in nums:\n # Update smallest and second smallest accordingly\n if num < smallest:\n second_smallest, smallest = smallest, num\n elif smallest < num < second_smallest:\n second_smallest = num\n \n # Check if we found a second smallest element\n if second_smallest == float('inf'):\n return None\n else:\n return second_smallest", "matching_cluster_idx": 3}, {"solution": "def second_smallest(numbers):\n # Initialize the smallest and second smallest with infinity\n first = second = float('inf')\n \n for number in numbers:\n if number < first:\n # Update first and second\n first, second = number, first\n elif first < number < second:\n # Update second only\n second = number\n \n # If second is still infinity, it means all elements are the same\n if second == float('inf'):\n return None\n else:\n return second", "matching_cluster_idx": 3}, {"solution": "def second_smallest(numbers):\n # Remove duplicates by converting to a set, then sort the list\n unique_numbers = sorted(set(numbers))\n # Check if we have at least 2 unique numbers\n if len(unique_numbers) < 2:\n return None # Not enough unique numbers for a second smallest\n else:\n return unique_numbers[1] # Second smallest number is at index 1", "matching_cluster_idx": 5}, {"solution": "def second_smallest(nums):\n if len(nums) < 2:\n return None # Not enough elements to find the second smallest\n \n # Initialize the smallest and second smallest with infinity\n smallest = second_smallest = float('inf')\n \n for num in nums:\n if num < smallest:\n # Update second smallest before updating smallest\n second_smallest = smallest\n smallest = num\n elif num < second_smallest and num != smallest:\n # Update second smallest if num is smaller than current second smallest\n second_smallest = num\n \n if second_smallest == float('inf'):\n return None # There is no second smallest element\n else:\n return second_smallest", "matching_cluster_idx": 4}, {"solution": "def second_smallest(numbers):\n # Initialize the smallest and second smallest with positive infinity\n first, second = float('inf'), float('inf')\n \n # Iterate through each number in the list\n for number in numbers:\n # Update first and second smallest accordingly\n if number < first:\n second = first\n first = number\n elif number < second and number != first:\n second = number\n \n # Check if second still holds infinity, meaning all elements were the same\n if second == float('inf'):\n return None\n else:\n return second", "matching_cluster_idx": 4}, {"solution": "def second_smallest(numbers):\n # Remove duplicates and sort the list\n unique_numbers = sorted(set(numbers))\n \n # Check if we have at least 2 unique numbers\n if len(unique_numbers) < 2:\n return None # Not enough unique elements to find second smallest\n \n # Return the second smallest element\n return unique_numbers[1]", "matching_cluster_idx": 5}, {"solution": "def second_smallest(numbers):\n if len(numbers) < 2:\n return None # Not enough elements for a second smallest\n \n # Initialize the smallest and second smallest with infinity\n smallest = second_smallest = float('inf')\n \n for number in numbers:\n if number < smallest:\n second_smallest, smallest = smallest, number # Update smallest and second smallest\n elif smallest < number < second_smallest:\n second_smallest = number # Update second smallest if number is between smallest and current second smallest\n \n if second_smallest == float('inf'):\n return None # No second smallest element found\n else:\n return second_smallest", "matching_cluster_idx": 3}, {"solution": "def second_smallest(numbers):\n # Initialize the smallest and second smallest with infinity\n first = second = float('inf')\n \n for number in numbers:\n # Update first and second smallest numbers if needed\n if number < first:\n first, second = number, first\n elif first < number < second:\n second = number\n \n # Check if second smallest was updated\n if second == float('inf'):\n return None # Not enough distinct numbers\n else:\n return second", "matching_cluster_idx": 3}, {"solution": "def second_smallest(numbers):\n if len(numbers) < 2:\n return None # Not enough elements for a second smallest\n \n # Initialize the smallest and second smallest with infinity\n smallest = second_smallest = float('inf')\n \n for number in numbers:\n if number < smallest:\n # Update second smallest before smallest, as smallest gets the new smallest value\n second_smallest = smallest\n smallest = number\n elif smallest < number < second_smallest:\n # Found a new second smallest\n second_smallest = number\n \n if second_smallest == float('inf'):\n return None # No second smallest element found\n \n return second_smallest", "matching_cluster_idx": 3}, {"solution": "def second_smallest(nums):\n # Initialize the smallest and second smallest with infinity\n first = second = float('inf')\n \n for n in nums:\n if n < first:\n # Update first and second\n first, second = n, first\n elif first < n < second:\n # Update second only if n is between first and second\n second = n\n \n # If second is still infinity, it means all elements are the same\n if second == float('inf'):\n return None # or raise an exception, depending on the desired behavior\n \n return second", "matching_cluster_idx": 3}, {"solution": "def second_smallest(nums):\n # Initialize the smallest and second smallest with infinity\n first = second = float('inf')\n \n # Iterate through each number in the list\n for num in nums:\n # Update first and second smallest numbers\n if num < first:\n first, second = num, first\n elif num < second and num != first:\n second = num\n \n # Return the second smallest number found\n return second if second != float('inf') else None", "matching_cluster_idx": 4}, {"solution": "def second_smallest(nums):\n # Initialize the smallest and second smallest with infinity\n first = second = float('inf')\n \n for num in nums:\n # Update first and second smallest if needed\n if num < first:\n first, second = num, first\n elif first < num < second:\n second = num\n \n return second if second != float('inf') else None", "matching_cluster_idx": 3}]}, "Mbpp/757": {"dps": 76.79906542056075, "dps_norm": 23.46153846153846, "pass@1": 45.0, "profiled": [{"solution": "def count_reverse_pairs(str_list):\n # Initialize the count of reverse pairs\n reverse_pairs_count = 0\n \n # Iterate through the list to find reverse pairs\n for i in range(len(str_list)):\n for j in range(i + 1, len(str_list)):\n # Check if the reverse of one string is the other string\n if str_list[j] == str_list[i][::-1]:\n reverse_pairs_count += 1\n \n return reverse_pairs_count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(string_list):\n count = 0\n # Iterate through each string in the list\n for i, string in enumerate(string_list):\n # Check each subsequent string to find a reverse pair\n for j in range(i + 1, len(string_list)):\n if string_list[j] == string[::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(string_list):\n \"\"\"\n Counts the number of pairs of reverse strings in the given string list.\n\n Args:\n string_list (list): A list of strings.\n\n Returns:\n int: The number of pairs of reverse strings.\n \"\"\"\n count = 0\n for i, s1 in enumerate(string_list):\n for s2 in string_list[i+1:]:\n if s1 == s2[::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(string_list):\n # Initialize the count of reverse pairs\n reverse_pair_count = 0\n \n # Iterate through each string in the list\n for i, string in enumerate(string_list):\n # Iterate through the remaining strings\n for j in range(i + 1, len(string_list)):\n # Check if the current string is the reverse of the next string\n if string == string_list[j][::-1]:\n # Increment the count if they are reverse pairs\n reverse_pair_count += 1\n \n return reverse_pair_count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(str_list):\n # Initialize the count of reverse pairs\n reverse_pairs_count = 0\n \n # Iterate through each string in the list\n for i, string in enumerate(str_list):\n # Check against the remaining strings in the list\n for j in range(i + 1, len(str_list)):\n # Check if the current string is the reverse of the other string\n if string == str_list[j][::-1]:\n # Increment the count if a reverse pair is found\n reverse_pairs_count += 1\n \n return reverse_pairs_count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(string_list):\n # Count how many reverse pairs are in the list\n count = 0\n for i in range(len(string_list)):\n for j in range(i + 1, len(string_list)):\n if string_list[i] == string_list[j][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(lst):\n count = 0\n # Iterate through the list of strings\n for i in range(len(lst)):\n for j in range(i + 1, len(lst)):\n # Check if the reverse of lst[i] equals lst[j]\n if lst[j] == lst[i][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(str_list):\n \"\"\"\n Counts the pairs of reverse strings in the given string list.\n \n :param str_list: List of strings to be checked for reverse pairs\n :return: Number of reverse string pairs found\n \"\"\"\n count = 0\n for i, word1 in enumerate(str_list):\n for j, word2 in enumerate(str_list):\n if i != j and word1[::-1] == word2:\n count += 1\n return count // 2 # Each pair is counted twice, so divide by 2", "matching_cluster_idx": 0}, {"solution": "def count_reverse_pairs(string_list):\n \"\"\"\n Counts the pairs of reverse strings in the given string list.\n \n :param string_list: List of strings to be checked for reverse pairs.\n :return: Number of reverse pairs found in the list.\n \"\"\"\n reverse_pairs_count = 0\n for i, word1 in enumerate(string_list):\n for j, word2 in enumerate(string_list):\n if i != j and word1 == word2[::-1]:\n reverse_pairs_count += 1\n return reverse_pairs_count // 2", "matching_cluster_idx": 0}, {"solution": "def count_reverse_pairs(strings):\n count = 0\n # Iterate through each string in the list\n for i, string in enumerate(strings):\n # Check the rest of the list for a reverse pair\n for j in range(i + 1, len(strings)):\n if string == strings[j][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(lst):\n count = 0\n for i in range(len(lst)):\n for j in range(i + 1, len(lst)):\n if lst[i] == lst[j][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(lst):\n # Count the number of reverse string pairs in the list\n count = 0\n for i in range(len(lst)):\n for j in range(i + 1, len(lst)):\n if lst[i] == lst[j][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(string_list):\n # Initialize the count of reverse pairs\n reverse_pair_count = 0\n \n # Iterate over each string in the list\n for i, string in enumerate(string_list):\n # Check against the rest of the strings in the list\n for other_string in string_list[i+1:]:\n # Check if the current string is a reverse of the other string\n if string[::-1] == other_string:\n reverse_pair_count += 1\n \n return reverse_pair_count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(lst):\n # Initialize the count of reverse pairs\n count = 0\n \n # Iterate through each string in the list\n for i in range(len(lst)):\n # Iterate through the remaining strings in the list\n for j in range(i + 1, len(lst)):\n # Check if the reverse of the first string is the second string\n if lst[i] == lst[j][::-1]:\n count += 1\n \n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(str_list):\n # Count how many reverse pairs exist in the string list\n count = 0\n for i, word1 in enumerate(str_list):\n for word2 in str_list[i+1:]:\n if word1[::-1] == word2:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(string_list):\n count = 0\n # Iterate through each string in the list\n for i, s1 in enumerate(string_list):\n # Reverse the string\n reversed_s1 = s1[::-1]\n # Check the rest of the list for the reverse string\n for s2 in string_list[i+1:]:\n if s2 == reversed_s1:\n count += 1\n return count", "matching_cluster_idx": 7}, {"solution": "def count_reverse_pairs(string_list):\n count = 0\n # Iterate through the list and its reversed version\n for i in range(len(string_list)):\n for j in range(i + 1, len(string_list)):\n if string_list[i] == string_list[j][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(string_list):\n # Count how many reverse pairs are in the list\n count = 0\n for i, word in enumerate(string_list):\n for j in range(i + 1, len(string_list)):\n if word == string_list[j][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(string_list):\n # Count how many pairs of reverse strings are present in the list\n count = 0\n for i in range(len(string_list)):\n for j in range(i + 1, len(string_list)):\n if string_list[i] == string_list[j][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(string_list):\n count = 0\n # Iterate through each string in the list\n for i in range(len(string_list)):\n for j in range(i + 1, len(string_list)):\n # Check if the reverse of one string matches the other string\n if string_list[i] == string_list[j][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}]}, "Mbpp/758": {"dps": 90.47297297297297, "dps_norm": 85.0, "pass@1": 98.0, "profiled": [{"solution": "def unique_sublists(lst):\n # Convert each sublist to a tuple and count occurrences\n from collections import Counter\n \n # Flatten the list of lists into a list of tuples\n tuples_list = [tuple(sublist) for sublist in lst]\n \n # Use Counter to count occurrences of each tuple\n count_dict = Counter(tuples_list)\n \n # Return the dictionary with tuples as keys and their counts as values\n return dict(count_dict)", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(lst):\n # Dictionary to keep count of each unique tuple\n count_dict = {}\n for sublist in lst:\n # Convert the sublist to a tuple and increment its count in the dictionary\n tuple_sublist = tuple(sublist)\n if tuple_sublist in count_dict:\n count_dict[tuple_sublist] += 1\n else:\n count_dict[tuple_sublist] = 1\n return count_dict", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(lst):\n # Initialize a dictionary to store the frequency of each tuple\n frequency_dict = {}\n \n # Iterate over each sublist in the input list\n for sublist in lst:\n # Convert the sublist to a tuple and update its count in the dictionary\n tuple_sublist = tuple(sublist)\n if tuple_sublist in frequency_dict:\n frequency_dict[tuple_sublist] += 1\n else:\n frequency_dict[tuple_sublist] = 1\n \n return frequency_dict", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(lst):\n # Dictionary to keep track of count of each tuple representation of list\n count_dict = {}\n \n # Iterate through each sublist in the input list\n for sublist in lst:\n # Convert the sublist to a tuple and use it as a key in the dictionary\n # Increment the count for this key\n tuple_sublist = tuple(sublist)\n count_dict[tuple_sublist] = count_dict.get(tuple_sublist, 0) + 1\n \n # Convert the dictionary to the desired format and return\n return count_dict", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(lst):\n # Dictionary to store the count of each tuple representation of a list\n count_dict = {}\n # Iterate through each list in the input list\n for sublist in lst:\n # Convert the list to a tuple and update its count in the dictionary\n tuple_sublist = tuple(sublist)\n if tuple_sublist in count_dict:\n count_dict[tuple_sublist] += 1\n else:\n count_dict[tuple_sublist] = 1\n return count_dict", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(lst):\n # Dictionary to store the tuples of lists as keys and their counts as values\n count_dict = {}\n \n # Iterate through each sublist in the input list\n for sublist in lst:\n # Convert the sublist to a tuple and use it as a key in the dictionary\n tuple_key = tuple(sublist)\n # If the tuple key is not in the dictionary, add it with a count of 1\n if tuple_key not in count_dict:\n count_dict[tuple_key] = 1\n else:\n # If the tuple key already exists, increment its count\n count_dict[tuple_key] += 1\n \n return count_dict", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(lst):\n # Dictionary to hold the count of each tuple representation of the lists\n count_dict = {}\n # Iterate over each sublist in the input list\n for sublist in lst:\n # Convert the sublist to a tuple and use it as a key in the dictionary\n tuple_sublist = tuple(sublist)\n # If the tuple is not in the dictionary, add it with a count of 1\n # Otherwise, increment the existing count\n count_dict[tuple_sublist] = count_dict.get(tuple_sublist, 0) + 1\n return count_dict", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(lst):\n # Initialize a dictionary to keep count of unique sublists\n count_dict = {}\n \n # Iterate through each sublist in the list\n for sublist in lst:\n # Convert the sublist to a tuple and use it as a key in the dictionary\n tuple_sublist = tuple(sublist)\n # If the tuple is not yet a key in the dictionary, add it with a count of 1\n # Otherwise, increment the count\n if tuple_sublist in count_dict:\n count_dict[tuple_sublist] += 1\n else:\n count_dict[tuple_sublist] = 1\n \n return count_dict", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(lst):\n # Dictionary to store the count of each tuple representation of a sublist\n count_dict = {}\n \n # Iterate through each sublist in the provided list\n for sublist in lst:\n # Convert the current sublist to a tuple (to make it hashable) and increment its count\n tuple_sublist = tuple(sublist)\n count_dict[tuple_sublist] = count_dict.get(tuple_sublist, 0) + 1\n \n # Return the final dictionary with counts\n return count_dict", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(lst):\n # Create a dictionary to store the frequency of each tuple\n frequency = {}\n \n # Iterate over each sublist in the input list\n for sublist in lst:\n # Convert the sublist to a tuple and update its count in the dictionary\n tuple_sublist = tuple(sublist)\n if tuple_sublist in frequency:\n frequency[tuple_sublist] += 1\n else:\n frequency[tuple_sublist] = 1\n \n return frequency", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(lst):\n # Dictionary to store the count of each tuple representation of a sublist\n count_dict = {}\n \n # Iterate over each sublist in the input list\n for sublist in lst:\n # Convert the sublist to a tuple to use as a dictionary key\n tuple_version = tuple(sublist)\n # Increment the count for this tuple in the dictionary\n if tuple_version in count_dict:\n count_dict[tuple_version] += 1\n else:\n count_dict[tuple_version] = 1\n \n return count_dict", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(lst):\n # Create a dictionary to store the count of each tuple representation of the sublists\n count_dict = {}\n \n # Iterate through each sublist in the input list\n for sublist in lst:\n # Convert the sublist to a tuple and use it as a key in the dictionary\n # Increment the count for this key\n count_dict[tuple(sublist)] = count_dict.get(tuple(sublist), 0) + 1\n \n # Return the dictionary containing unique sublists as tuples and their counts\n return count_dict", "matching_cluster_idx": 5}, {"solution": "def unique_sublists(lst):\n # Convert each sublist to a tuple and count occurrences\n count_dict = {}\n for sublist in lst:\n # Convert list to tuple and count occurrences\n tuple_sublist = tuple(sublist)\n if tuple_sublist in count_dict:\n count_dict[tuple_sublist] += 1\n else:\n count_dict[tuple_sublist] = 1\n return count_dict", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(lst):\n # Dictionary to store the count of each unique tuple\n count_dict = {}\n \n # Iterate through each sublist in the input list\n for sublist in lst:\n # Convert the sublist to a tuple and use it as a key in the dictionary\n tuple_sublist = tuple(sublist)\n # Increment the count for this tuple in the dictionary\n if tuple_sublist in count_dict:\n count_dict[tuple_sublist] += 1\n else:\n count_dict[tuple_sublist] = 1\n \n # Return the dictionary containing unique tuples and their counts\n return count_dict", "matching_cluster_idx": 6}, {"solution": "from collections import Counter\ndef unique_sublists(lst):\n # Convert each sublist to a tuple and count occurrences\n counter = Counter(map(tuple, lst))\n # Convert the counter to a dictionary with the required format\n result = {sublist: count for sublist, count in counter.items()}\n return result", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(lst):\n # Dictionary to store the count of each tuple\n count_dict = {}\n \n # Iterate through each sublist in the list\n for sublist in lst:\n # Convert the sublist to a tuple and use it as a key in the dictionary\n # Increment the count for this tuple\n count_dict[tuple(sublist)] = count_dict.get(tuple(sublist), 0) + 1\n \n return count_dict", "matching_cluster_idx": 5}, {"solution": "def unique_sublists(lst):\n # Convert the list of lists into a list of tuples\n tuple_list = [tuple(sublist) for sublist in lst]\n # Create a dictionary to count occurrences of each tuple\n count_dict = {}\n for item in tuple_list:\n if item in count_dict:\n count_dict[item] += 1\n else:\n count_dict[item] = 1\n return count_dict", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(lst):\n # Use a dictionary to count occurrences of each tuple\n count_dict = {}\n \n # Iterate through each sublist in the input list\n for sublist in lst:\n # Convert the sublist to a tuple and use it as a key in the dictionary\n # Increment the count for this tuple in the dictionary\n count_dict.setdefault(tuple(sublist), 0)\n count_dict[tuple(sublist)] += 1\n \n # Return the dictionary with tuple keys and counts as values\n return count_dict", "matching_cluster_idx": 4}, {"solution": "def unique_sublists(lst):\n # Dictionary to hold the count of each tuple representation of a list\n count_dict = {}\n \n # Iterate through each list in the input list\n for sublist in lst:\n # Convert the list to a tuple (hashable type) to use as a dictionary key\n tuple_sublist = tuple(sublist)\n # If the tuple is not a key in the dictionary, add it with a count of 1\n # If it is a key, increment the count\n count_dict[tuple_sublist] = count_dict.get(tuple_sublist, 0) + 1\n \n # Return the dictionary with tuple representations of lists as keys and their counts as values\n return count_dict", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(lst):\n # Convert the list of lists to a list of tuples\n tuples_list = [tuple(sublist) for sublist in lst]\n # Use a dictionary to count occurrences of each tuple\n count_dict = {}\n for tup in tuples_list:\n if tup in count_dict:\n count_dict[tup] += 1\n else:\n count_dict[tup] = 1\n return count_dict", "matching_cluster_idx": 6}]}, "Mbpp/760": {"dps": 99.27007299270073, "dps_norm": 87.5, "pass@1": 100.0, "profiled": [{"solution": "def unique_Element(lst):\n # Use set to find unique elements in the list\n unique_elements = set(lst)\n # If there's only one unique element, return True, otherwise return False\n return len(unique_elements) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(lst):\n # Convert the list to a set to remove duplicates, and check the length\n return len(set(lst)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(lst):\n # Convert the list to a set and check if its length is 1\n return len(set(lst)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(lst):\n # Use set to find distinct elements and check its length\n return len(set(lst)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(lst):\n # Check if all elements in the list are the same by comparing the set of the list to {None}\n # If the set has only one element or is empty (all elements are the same), return True\n # Otherwise, return False\n return len(set(lst)) <= 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(nums):\n # Return True if all elements in the list are the same, False otherwise\n return len(set(nums)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(nums):\n # Check if the list is empty\n if not nums:\n return True # An empty list is considered to have only one distinct element by default\n \n # Use a set to find unique elements in the list\n unique_elements = set(nums)\n \n # If there is only one unique element, return True\n return len(unique_elements) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(lst):\n # Check if the set of the list has a length of 1, which means all elements are the same\n return len(set(lst)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(lst):\n # Convert the list to a set to remove duplicates\n unique_set = set(lst)\n \n # Check if the set size is 1, which means all elements in the list are the same\n if len(unique_set) == 1:\n return True\n else:\n return False", "matching_cluster_idx": 6}, {"solution": "def unique_Element(lst):\n # Use set to find unique elements in the list\n unique_elements = set(lst)\n # Check if there is only one unique element\n return len(unique_elements) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(arr):\n # Check if the set of the list has only one unique element\n return len(set(arr)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(nums):\n # Convert the list to a set to remove duplicates and check its length\n return len(set(nums)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(lst):\n # Check if the list is empty or all elements are the same\n return len(set(lst)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(lst):\n # Use a set to store unique elements\n unique_elements = set(lst)\n \n # If the set length is 1, all elements are the same\n if len(unique_elements) == 1:\n return True\n else:\n return False", "matching_cluster_idx": 6}, {"solution": "def unique_Element(lst):\n # Check if all elements in the list are the same by comparing the first element with the rest\n return len(set(lst)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(arr):\n # Return True if all elements in the list are the same, otherwise False\n return len(set(arr)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(arr):\n # Convert the list to a set to remove duplicates, then compare its length to the original list\n return len(set(arr)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(test_list):\n # Check if all elements in the list are the same\n return len(set(test_list)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(lst):\n # Use set to find distinct elements in the list\n distinct_elements = set(lst)\n # Check if there is exactly one distinct element\n return len(distinct_elements) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(arr):\n # Check if all elements in the list are the same by comparing the set of the list to {None}\n # If the list is empty, len(set(arr)) will be 0, so we return False\n return len(set(arr)) == 1", "matching_cluster_idx": 6}]}, "Mbpp/764": {"dps": 9.444444444444445, "dps_norm": 20.0, "pass@1": 100.0, "profiled": [{"solution": "import re\ndef number_ctr(input_string):\n # Use regular expression to find all digits in the input string\n digits = re.findall(r'\\d', input_string)\n # Return the count of digits found\n return len(digits)", "matching_cluster_idx": 0}, {"solution": "import re\ndef number_ctr(input_string):\n # Use regular expression to find all digits in the string\n digits = re.findall(r'\\d', input_string)\n # Return the count of digits\n return len(digits)", "matching_cluster_idx": 0}, {"solution": "import re\ndef number_ctr(input_string):\n # Use regular expression to find all digits in the string\n digits = re.findall(r'\\d', input_string)\n \n # Return the count of digits found\n return len(digits)", "matching_cluster_idx": 0}, {"solution": "import re\ndef number_ctr(input_string):\n # Use regular expression to find all digits in the string\n digits = re.findall(r'\\d', input_string)\n \n # Return the count of digits found\n return len(digits)", "matching_cluster_idx": 0}, {"solution": "import re\ndef number_ctr(input_string):\n # Use regular expression to find all digits in the string\n digits = re.findall(r'\\d', input_string)\n # Return the count of digits found\n return len(digits)", "matching_cluster_idx": 0}, {"solution": "import re\ndef number_ctr(input_string):\n # Use regular expression to find all digits in the string\n digits = re.findall(r'\\d', input_string)\n \n # Return the count of digits found\n return len(digits)", "matching_cluster_idx": 0}, {"solution": "def number_ctr(input_string):\n # Initialize digit count\n digit_count = 0\n \n # Iterate through each character in the string\n for char in input_string:\n # Check if the character is a digit\n if char.isdigit():\n digit_count += 1\n \n return digit_count", "matching_cluster_idx": 2}, {"solution": "import re\ndef number_ctr(input_string):\n # Use regular expression to find all digits in the string\n digits = re.findall(r'\\d', input_string)\n \n # Return the count of digits found\n return len(digits)", "matching_cluster_idx": 0}, {"solution": "import re\ndef number_ctr(input_string):\n # Use regular expression to find all digits in the string\n digits = re.findall(r'\\d', input_string)\n \n # Return the count of digits found\n return len(digits)", "matching_cluster_idx": 0}, {"solution": "import re\ndef number_ctr(input_string):\n # Use regular expression to find all digits in the string\n digits = re.findall(r'\\d', input_string)\n # Return the count of digits found\n return len(digits)", "matching_cluster_idx": 0}, {"solution": "import re\ndef number_ctr(input_string):\n # Use regular expression to find all digits in the string\n digits = re.findall(r'\\d', input_string)\n # Return the count of digits found\n return len(digits)", "matching_cluster_idx": 0}, {"solution": "import re\ndef number_ctr(input_string):\n # Use regular expression to find all digits in the string\n digits = re.findall(r'\\d', input_string)\n # Return the count of digits\n return len(digits)", "matching_cluster_idx": 0}, {"solution": "import re\ndef number_ctr(input_string):\n # Use regular expression to find all digits in the string\n digits = re.findall(r'\\d', input_string)\n # Return the count of digits found\n return len(digits)", "matching_cluster_idx": 0}, {"solution": "import re\ndef number_ctr(input_string):\n # Use regular expression to find all digits in the string\n digits = re.findall(r'\\d', input_string)\n # Return the count of digits found\n return len(digits)", "matching_cluster_idx": 0}, {"solution": "import re\ndef number_ctr(input_string):\n # Use regular expression to find all digits in the input string\n digits = re.findall(r'\\d', input_string)\n # Return the count of digits found\n return len(digits)", "matching_cluster_idx": 0}, {"solution": "def number_ctr(input_string):\n # Initialize digit count\n digit_count = 0\n \n # Iterate through each character in the input string\n for char in input_string:\n # Check if the character is a digit\n if char.isdigit():\n digit_count += 1\n \n return digit_count", "matching_cluster_idx": 2}, {"solution": "import re\ndef number_ctr(input_string):\n # Use regular expression to find all digits in the string\n numbers = re.findall(r'\\d', input_string)\n # Return the count of digits\n return len(numbers)", "matching_cluster_idx": 0}, {"solution": "import re\ndef number_ctr(input_string):\n # Use regex to find all digits in the string\n digits = re.findall(r'\\d', input_string)\n # Return the count of digits\n return len(digits)", "matching_cluster_idx": 0}, {"solution": "import re\ndef number_ctr(input_string):\n # Use regular expression to find all digits in the input string\n digits = re.findall(r'\\d', input_string)\n \n # Return the count of digits found\n return len(digits)", "matching_cluster_idx": 0}, {"solution": "import re\ndef number_ctr(input_string):\n # Use regular expression to find all digits in the input string\n digits = re.findall(r'\\d', input_string)\n # Return the count of digits found\n return len(digits)", "matching_cluster_idx": 0}]}, "Mbpp/766": {"dps": 70.60747663551402, "dps_norm": 65.83333333333333, "pass@1": 100.0, "profiled": [{"solution": "def pair_wise(lst):\n # Use zip to pair consecutive elements\n return list(zip(lst[:-1], lst[1:]))", "matching_cluster_idx": 4}, {"solution": "def pair_wise(lst):\n # Use zip to create pairs of consecutive items from the list\n return list(zip(lst, lst[1:]))", "matching_cluster_idx": 5}, {"solution": "def pair_wise(lst):\n # Create a list of consecutive pairs using zip and a sliced list\n return list(zip(lst, lst[1:]))", "matching_cluster_idx": 5}, {"solution": "def pair_wise(lst):\n # Create pairs of consecutive items from the list\n return list(zip(lst, lst[1:]))", "matching_cluster_idx": 5}, {"solution": "def pair_wise(lst):\n # Create a list of consecutive pairs\n return [(lst[i], lst[i + 1]) for i in range(len(lst) - 1)]", "matching_cluster_idx": 2}, {"solution": "def pair_wise(lst):\n # Create pairs of consecutive items\n return [(lst[i], lst[i + 1]) for i in range(len(lst) - 1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n # Use zip to pair consecutive elements from the list\n return list(zip(lst, lst[1:]))", "matching_cluster_idx": 5}, {"solution": "def pair_wise(lst):\n # Initialize an empty list to store the pairs\n pairs = []\n \n # Iterate through the list, stopping one element before the end\n for i in range(len(lst) - 1):\n # Append the pair of consecutive items to the list\n pairs.append((lst[i], lst[i + 1]))\n \n return pairs", "matching_cluster_idx": 2}, {"solution": "def pair_wise(lst):\n # Create pairs of consecutive items in the list\n return [(lst[i], lst[i + 1]) for i in range(len(lst) - 1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n # Initialize an empty list to store the pairs\n result = []\n # Iterate through the list, stopping before the last element\n for i in range(len(lst) - 1):\n # Add a tuple of the current and next element to the result list\n result.append((lst[i], lst[i + 1]))\n return result", "matching_cluster_idx": 2}, {"solution": "def pair_wise(lst):\n # Pair each element with its consecutive element\n return [(lst[i], lst[i + 1]) for i in range(len(lst) - 1)]", "matching_cluster_idx": 2}, {"solution": "def pair_wise(input_list):\n # Initialize an empty list to store the pairs\n pairs = []\n # Loop through the list elements, stopping one before the last\n for i in range(len(input_list) - 1):\n # Add a tuple of consecutive elements to the pairs list\n pairs.append((input_list[i], input_list[i + 1]))\n return pairs", "matching_cluster_idx": 2}, {"solution": "def pair_wise(lst):\n # Create pairs of consecutive items from the list\n return [(lst[i], lst[i + 1]) for i in range(len(lst) - 1)]", "matching_cluster_idx": 2}, {"solution": "def pair_wise(lst):\n # Create a list of pairs of consecutive items\n return [(lst[i], lst[i + 1]) for i in range(len(lst) - 1)]", "matching_cluster_idx": 2}, {"solution": "def pair_wise(input_list):\n # Initialize an empty list to store the pairs\n result_pairs = []\n \n # Iterate through the list, stopping one element before the end\n for i in range(len(input_list) - 1):\n # Create a tuple of consecutive items and add it to the result list\n result_pairs.append((input_list[i], input_list[i + 1]))\n \n return result_pairs", "matching_cluster_idx": 2}, {"solution": "def pair_wise(input_list):\n # Create a list to store the pairs\n pairs = []\n \n # Iterate through the list, stopping one item before the end\n for i in range(len(input_list) - 1):\n # Append the tuple of consecutive items to the pairs list\n pairs.append((input_list[i], input_list[i + 1]))\n \n return pairs", "matching_cluster_idx": 2}, {"solution": "def pair_wise(lst):\n # Create pairs of consecutive items in the list\n return [(lst[i], lst[i + 1]) for i in range(len(lst) - 1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n # Generate pairs of consecutive items in the list\n return [(lst[i], lst[i + 1]) for i in range(len(lst) - 1)]", "matching_cluster_idx": 2}, {"solution": "def pair_wise(lst):\n # Pair each element with the next one in the list\n return [(lst[i], lst[i + 1]) for i in range(len(lst) - 1)]", "matching_cluster_idx": 2}, {"solution": "def pair_wise(lst):\n # Use zip to create pairs of consecutive items\n return list(zip(lst, lst[1:]))", "matching_cluster_idx": 4}]}, "Mbpp/775": {"dps": 94.39999999999999, "dps_norm": 71.42857142857143, "pass@1": 97.0, "profiled": [{"solution": "def odd_position(lst):\n # Check if all elements at odd indices are odd\n for i in range(1, len(lst), 2):\n if lst[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(arr):\n # Iterate through the list checking elements at odd indices\n for i in range(1, len(arr), 2):\n # Check if the element at the odd index is not odd\n if arr[i] % 2 == 0:\n return False\n # If all checks pass, return True\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n # Check if every odd index contains an odd number\n for i in range(1, len(lst), 2):\n if lst[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(arr):\n # Iterate through the list, considering only odd indices\n for i in range(1, len(arr), 2):\n # Check if the number at the current odd index is not odd\n if arr[i] % 2 == 0:\n return False\n # If all numbers at odd indices are odd, return True\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n # Iterate through the list, checking elements at odd indices\n for i in range(1, len(lst), 2):\n # Check if the element at the current odd index is even\n if lst[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n # Iterate through the list starting from index 1 (second element)\n for i in range(1, len(lst), 2):\n # Check if the number at the odd index is not an odd number\n if lst[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n # Iterate through the list checking elements at odd indices\n for i in range(1, len(lst), 2):\n # Check if the element at the odd index is not an odd number\n if lst[i] % 2 == 0:\n return False\n # If all elements at odd indices are odd numbers\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n # Iterate through the list, checking elements at odd indices\n for i in range(1, len(lst), 2):\n # Check if the element at the odd index is not an odd number\n if lst[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n # Check each element at odd index\n for i in range(1, len(lst), 2):\n # If the element at an odd index is not odd, return False\n if lst[i] % 2 == 0:\n return False\n # If all elements at odd indices are odd, return True\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n # Check if the length of the list is odd or even\n # Iterate through the list, starting from index 1 (second element) to the end\n # with a step of 2 (to check only odd indices)\n for i in range(1, len(lst), 2):\n # Check if the value at the current odd index is even\n if lst[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n # Iterate through the list, checking only odd indices\n for i in range(1, len(lst), 2):\n # Check if the number at the odd index is not odd\n if lst[i] % 2 == 0:\n return False\n # If all numbers at odd indices are odd, return True\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n # Iterate through the list, starting from index 1 and stepping by 2\n for i in range(1, len(lst), 2):\n # Check if the value at the current odd index is not an odd number\n if lst[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n # Iterate through the list, starting from index 1 and stepping by 2\n for i in range(1, len(lst), 2):\n # Check if the number at the current odd index is not odd\n if lst[i] % 2 == 0:\n return False\n # If all numbers at odd indices are odd, return True\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n # Iterate over the list, checking elements at odd indices\n for i in range(1, len(lst), 2):\n # Check if the element at the current odd index is not an odd number\n if lst[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n # Iterate through the list checking elements at odd indices\n for i in range(1, len(lst), 2):\n # Check if the element at the odd index is not an odd number\n if lst[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n # Iterate through the list, checking elements at odd indices\n for i in range(1, len(lst), 2):\n # Check if the element at the odd index is not an odd number\n if lst[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n # Iterate over the list, considering only odd indices (1, 3, 5, ...)\n for i in range(1, len(lst), 2):\n # Check if the number at the odd index is not odd\n if lst[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n # Iterate through the list, checking elements at odd indices\n for i in range(1, len(lst), 2):\n # Check if the element at the current odd index is not odd\n if lst[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n # Iterate through the list, checking elements at odd indices\n for i in range(1, len(lst), 2):\n # Check if the element at the current odd index is even\n if lst[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n # Iterate through the list, checking elements at odd indices\n for i in range(1, len(lst), 2):\n # Check if the element at the current odd index is not odd\n if lst[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}]}, "Mbpp/777": {"dps": null, "dps_norm": null, "pass@1": 0.0, "profiled": []}, "Mbpp/781": {"dps": 90.15748031496062, "dps_norm": 72.0, "pass@1": 100.0, "profiled": [{"solution": "def count_divisors(n):\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count % 2 == 0", "matching_cluster_idx": 1}, {"solution": "def count_divisors(n):\n # Initialize divisor count\n count = 0\n # Loop to check for divisors\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n # If divisors are equal, count only once\n if n // i == i:\n count += 1\n else:\n # Otherwise, count both divisors\n count += 2\n return count % 2 == 0", "matching_cluster_idx": 4}, {"solution": "def count_divisors(n):\n # Initialize count of divisors\n count = 0\n \n # Loop to find divisors\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n # If divisors are equal, count only once\n if n // i == i:\n count += 1\n else:\n # Count both divisors\n count += 2\n \n # Check if the count of divisors is even\n return count % 2 == 0", "matching_cluster_idx": 4}, {"solution": "def count_divisors(number):\n # Initialize a counter to count the number of divisors\n count = 0\n \n # Iterate from 1 to the number itself\n for i in range(1, number + 1):\n # If i is a divisor of the number, increment the count\n if number % i == 0:\n count += 1\n \n # Check if the count of divisors is even\n if count % 2 == 0:\n return True\n else:\n return False", "matching_cluster_idx": 1}, {"solution": "def count_divisors(n):\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n # If divisors are equal, count only once\n if n // i == i:\n count += 1\n else:\n count += 2\n return count % 2 == 0", "matching_cluster_idx": 4}, {"solution": "def count_divisors(n):\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n # If divisors are equal, count only once\n if n // i == i:\n count += 1\n else:\n count += 2\n return count % 2 == 0", "matching_cluster_idx": 4}, {"solution": "def count_divisors(number):\n # Initialize divisor count\n count = 0\n \n # Iterate from 1 to the given number\n for i in range(1, number + 1):\n # If i is a divisor of the number\n if number % i == 0:\n count += 1\n \n # Check if the count of divisors is even\n return count % 2 == 0", "matching_cluster_idx": 0}, {"solution": "def count_divisors(n):\n # Initialize count of divisors\n count = 0\n \n # Loop through all possible divisors from 1 to n\n for i in range(1, n + 1):\n # If i is a divisor of n, increment count\n if n % i == 0:\n count += 1\n \n # Check if the count of divisors is even\n return count % 2 == 0", "matching_cluster_idx": 1}, {"solution": "def count_divisors(n):\n # Initialize count of divisors\n count = 0\n \n # Iterate from 1 to the square root of n\n for i in range(1, int(n**0.5) + 1):\n # If i is a divisor of n\n if n % i == 0:\n # If both divisors are the same, count only once\n if i == n // i:\n count += 1\n else:\n count += 2\n \n # Check if the total number of divisors is even\n return count % 2 == 0", "matching_cluster_idx": 4}, {"solution": "def count_divisors(n):\n # Initialize count of divisors\n count = 0\n \n # Loop to find divisors\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n # If divisors are equal, count only one\n if n // i == i:\n count += 1\n else:\n # Otherwise count both\n count += 2\n \n # Check if the count of divisors is even\n return count % 2 == 0", "matching_cluster_idx": 4}, {"solution": "def count_divisors(n):\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n # If divisors are equal, count only once\n if n // i == i:\n count += 1\n else:\n count += 2\n return count % 2 == 0", "matching_cluster_idx": 4}, {"solution": "def count_divisors(n):\n count = 0\n # Iterate from 1 to the number itself\n for i in range(1, n + 1):\n # Check if i is a divisor of n\n if n % i == 0:\n count += 1\n # Check if the count of divisors is even\n return count % 2 == 0", "matching_cluster_idx": 1}, {"solution": "def count_divisors(number):\n # Initialize divisor count\n count = 0\n \n # Iterate through all numbers from 1 to the given number\n for i in range(1, number + 1):\n # If 'i' is a divisor of 'number'\n if number % i == 0:\n # Increment the count\n count += 1\n \n # Check if the count of divisors is even\n return count % 2 == 0", "matching_cluster_idx": 1}, {"solution": "def count_divisors(n):\n # Initialize count of divisors\n count = 0\n \n # Loop through all possible divisors\n for i in range(1, int(n**0.5) + 1):\n # If 'i' is a divisor of 'n'\n if n % i == 0:\n # If divisors are equal, count only once\n if n // i == i:\n count += 1\n else:\n # Otherwise, count both divisors\n count += 2\n \n # Check if the count of divisors is even\n return count % 2 == 0", "matching_cluster_idx": 4}, {"solution": "def count_divisors(n):\n count = 0\n # Iterate over all numbers from 1 to n\n for i in range(1, n + 1):\n # Check if i is a divisor of n\n if n % i == 0:\n count += 1\n # Check if the count of divisors is even\n return count % 2 == 0", "matching_cluster_idx": 1}, {"solution": "def count_divisors(n):\n # Initialize count of divisors\n count = 0\n \n # Loop to find all divisors\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n # Increment count if i is a divisor\n count += 1\n \n # Check if n/i is a different divisor and increment count accordingly\n if i != n // i:\n count += 1\n \n # Return whether the count is even\n return count % 2 == 0", "matching_cluster_idx": 4}, {"solution": "def count_divisors(n):\n # Initialize count of divisors\n count = 0\n \n # Loop through all numbers from 1 to n\n for i in range(1, n + 1):\n # Check if i is a divisor of n\n if n % i == 0:\n count += 1\n \n # Check if count of divisors is even\n if count % 2 == 0:\n return True\n else:\n return False", "matching_cluster_idx": 1}, {"solution": "def count_divisors(n):\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n # If divisors are equal, count only once\n if n // i == i:\n count += 1\n else:\n count += 2\n return count % 2 == 0", "matching_cluster_idx": 4}, {"solution": "def count_divisors(num):\n count = 0\n for i in range(1, int(num**0.5) + 1):\n if num % i == 0:\n # If divisors are equal, count only once\n if num // i == i:\n count += 1\n else:\n count += 2\n return count % 2 == 0", "matching_cluster_idx": 4}, {"solution": "def count_divisors(n):\n # Initialize count of divisors\n count = 0\n \n # Loop through all numbers from 1 to n\n for i in range(1, n + 1):\n # If i is a divisor of n\n if n % i == 0:\n count += 1\n \n # Check if count is even\n return count % 2 == 0", "matching_cluster_idx": 1}]}, "Mbpp/800": {"dps": 91.34328358208955, "dps_norm": 96.0, "pass@1": 97.0, "profiled": [{"solution": "def remove_all_spaces(input_string):\n # Remove all whitespaces from the input string\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n # Use the replace method to remove all spaces from the input string\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n # Use the replace method to remove all whitespaces\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n # Use str.replace to remove all spaces from the input string\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n # Remove all whitespaces from the input string\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n # Using the replace method to remove all spaces from the input string\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n # Use str.replace method to replace all occurrences of whitespace with nothing\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 3}, {"solution": "def remove_all_spaces(input_string):\n # Use the replace method to remove all spaces\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 3}, {"solution": "def remove_all_spaces(input_string):\n # Use the str.replace method to replace all spaces with an empty string\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 3}, {"solution": "def remove_all_spaces(input_string):\n # Remove all whitespaces from the input string\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n # Use str.replace method to replace all spaces with an empty string\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 3}, {"solution": "def remove_all_spaces(input_string):\n # Using the replace method to remove all spaces from the input string\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n # Remove all whitespaces from the input string\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n # Use the str.replace method to replace all occurrences of spaces with nothing\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n # Remove all whitespaces from the input string\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n # Use str.replace to replace all occurrences of whitespace with nothing\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n # Using str.replace to remove all whitespaces\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n # Use str.replace method to remove all whitespaces\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n # Using the replace method to remove all whitespaces\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n # Remove all whitespace characters from the input string\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}]}, "Mbpp/805": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 99.0, "profiled": [{"solution": "def max_sum_list(lists):\n # Use max function with key parameter to find the list with the highest sum\n return max(lists, key=sum)", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n # Use max function with key parameter to find the list with the maximum sum\n return max(lists, key=sum)", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(list_of_lists):\n # Initialize the maximum sum to a very small number and the result list to None\n max_sum = float('-inf')\n max_list = None\n \n # Iterate through each list in the list of lists\n for lst in list_of_lists:\n # Calculate the sum of the current list\n current_sum = sum(lst)\n \n # Update max_sum and max_list if the current list has a greater sum\n if current_sum > max_sum:\n max_sum = current_sum\n max_list = lst\n \n # Return the list with the highest sum\n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(list_of_lists):\n # Find the list with the maximum sum of elements\n max_list = max(list_of_lists, key=sum)\n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(list_of_lists):\n # Initialize a variable to keep track of the maximum sum found\n max_sum = float('-inf')\n # Initialize the variable to store the list with the maximum sum\n max_list = []\n \n # Iterate through each list in the list of lists\n for lst in list_of_lists:\n # Calculate the sum of the current list\n current_sum = sum(lst)\n # Update max_sum and max_list if the current list's sum is greater\n if current_sum > max_sum:\n max_sum = current_sum\n max_list = lst\n \n # Return the list with the highest sum\n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(list_of_lists):\n # Use max with key parameter to find the list with the highest sum of elements\n max_list = max(list_of_lists, key=sum)\n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n # Initialize a variable to store the list with the highest sum\n max_list = None\n # Initialize a variable to store the highest sum encountered\n max_sum = float('-inf')\n \n # Iterate through each list in the input list of lists\n for lst in lists:\n # Calculate the sum of the current list\n current_sum = sum(lst)\n # Update max_list and max_sum if the current list's sum is greater\n if current_sum > max_sum:\n max_sum = current_sum\n max_list = lst\n \n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n # Find the list with the maximum sum of elements\n max_list = max(lists, key=sum)\n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(list_of_lists):\n # Use max function with key parameter to find the list with the highest sum\n return max(list_of_lists, key=sum)", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(list_of_lists):\n \"\"\"\n Returns the list in a list of lists whose sum of elements is the highest.\n \n :param list_of_lists: List of lists containing integers\n :return: The list with the highest sum of elements\n \"\"\"\n if not list_of_lists:\n return []\n \n max_sum_list = max(list_of_lists, key=sum)\n return max_sum_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n # Check if the list is empty\n if not lists:\n return []\n \n # Initialize the max sum and the list with the max sum\n max_sum = float('-inf')\n max_list = []\n \n # Iterate through each list in the list of lists\n for lst in lists:\n # Calculate the sum of the current list\n current_sum = sum(lst)\n # Update max_sum and max_list if current_sum is greater\n if current_sum > max_sum:\n max_sum = current_sum\n max_list = lst\n \n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(list_of_lists):\n # Check if the list of lists is empty\n if not list_of_lists:\n return []\n \n # Initialize the max_sum to a very small number and max_list to None\n max_sum = float('-inf')\n max_list = None\n \n # Iterate through each list in the list of lists\n for lst in list_of_lists:\n # Calculate the sum of the current list\n current_sum = sum(lst)\n \n # Update max_sum and max_list if the current sum is greater than max_sum\n if current_sum > max_sum:\n max_sum = current_sum\n max_list = lst\n \n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(list_of_lists):\n # Initialize a variable to store the maximum sum encountered and the list with that sum\n max_sum = float('-inf')\n max_list = []\n \n # Iterate through each list in the list of lists\n for sublist in list_of_lists:\n # Calculate the sum of the current sublist\n current_sum = sum(sublist)\n \n # Update max_sum and max_list if current_sum is greater than max_sum\n if current_sum > max_sum:\n max_sum = current_sum\n max_list = sublist\n \n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n # Find the list with the maximum sum of its elements\n max_list = max(lists, key=sum)\n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n # Find the list with the maximum sum of elements\n max_list = max(lists, key=sum)\n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(list_of_lists):\n # Initialize the maximum sum and the list with the maximum sum\n max_sum = float('-inf')\n max_list = []\n \n # Iterate through each list in the list of lists\n for current_list in list_of_lists:\n # Calculate the sum of the current list\n current_sum = sum(current_list)\n \n # Update max_sum and max_list if current_sum is greater than max_sum\n if current_sum > max_sum:\n max_sum = current_sum\n max_list = current_list\n \n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n # Calculate the sum of each list and find the one with the maximum sum\n max_list = max(lists, key=sum)\n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(list_of_lists):\n \"\"\"\n Returns the list from a list of lists whose sum of elements is the highest.\n \n :param list_of_lists: List of lists containing numerical values\n :return: The list with the highest sum of elements\n \n Example:\n assert max_sum_list([[1,2,3], [4,5,6], [10,11,12], [7,8,9]]) == [10, 11, 12]\n \"\"\"\n # Find the list with the maximum sum of elements\n max_list = max(list_of_lists, key=sum)\n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(list_of_lists):\n # Initialize the maximum sum to a very small number\n max_sum = float('-inf')\n # Initialize the list with the highest sum to an empty list\n max_list = []\n \n # Iterate through each list in the list of lists\n for sublist in list_of_lists:\n # Calculate the sum of the current sublist\n current_sum = sum(sublist)\n # Update max_sum and max_list if the current_sum is greater than max_sum\n if current_sum > max_sum:\n max_sum = current_sum\n max_list = sublist\n \n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(list_of_lists):\n # Check if the input list is empty\n if not list_of_lists:\n return []\n \n # Initialize the max sum and the list with the max sum\n max_sum = float('-inf')\n max_list = []\n \n # Iterate through each list in the list of lists\n for current_list in list_of_lists:\n # Calculate the sum of the current list\n current_sum = sum(current_list)\n \n # Update max_sum and max_list if current_sum is greater than max_sum\n if current_sum > max_sum:\n max_sum = current_sum\n max_list = current_list\n \n return max_list", "matching_cluster_idx": 4}]}, "Mbpp/808": {"dps": 68.8157894736842, "dps_norm": 92.5, "pass@1": 100.0, "profiled": [{"solution": "def check_K(test_tup, K):\n # Check if K is in the tuple and return the result\n return K in test_tup", "matching_cluster_idx": 4}, {"solution": "def check_K(tup, k):\n # Check if k is in the tuple\n return k in tup", "matching_cluster_idx": 4}, {"solution": "def check_K(tup, k):\n \"\"\"\n Check if the given tuple contains the integer k.\n \n Args:\n tup : tuple of integers\n k : integer to search for in the tuple\n \n Returns:\n bool: True if k is in the tuple, False otherwise\n \"\"\"\n return k in tup", "matching_cluster_idx": 4}, {"solution": "def check_K(test_tup, K):\n # Check if K is in the tuple and return the result\n return K in test_tup", "matching_cluster_idx": 4}, {"solution": "def check_K(tup, k):\n # Check if k is in the tuple\n if k in tup:\n return True\n else:\n return False", "matching_cluster_idx": 4}, {"solution": "def check_K(tup, k):\n \"\"\"\n Check if the given tuple contains the specified value k.\n\n Args:\n tup (tuple): The tuple to be checked.\n k (int): The value to search for in the tuple.\n\n Returns:\n bool: True if k is found in the tuple, False otherwise.\n \"\"\"\n return k in tup", "matching_cluster_idx": 4}, {"solution": "def check_K(tuples, k):\n \"\"\"\n Check if the given tuples contain the k or not.\n\n :param tuples: Tuple containing elements\n :param k: Element to check for in the tuple\n :return: True if k is in the tuple, False otherwise\n \"\"\"\n return k in tuples", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n \"\"\"\n Check if the given tuple contains the specified element k.\n\n Args:\n tup (tuple): The input tuple to be checked.\n k (int/float): The element to be searched within the tuple.\n\n Returns:\n bool: True if k is found in the tuple, False otherwise.\n \"\"\"\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(tuples, k):\n # Check if the given tuple contains the integer k\n return k in tuples", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n \"\"\"\n Check if the given tuple contains the k or not.\n \n :param tup: Tuple to check\n :param k: Value to search for in the tuple\n :return: True if k is in the tuple, False otherwise\n \"\"\"\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n \"\"\"\n Check if the given tuple contains the k or not.\n\n :param tup: Tuple to search\n :param k: Value to search for in the tuple\n :return: True if k is found in tup, False otherwise\n \"\"\"\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n \"\"\"\n Check if the given tuple contains the k or not.\n\n Parameters:\n tup (tuple): The tuple to check.\n k (int): The value to search for in the tuple.\n\n Returns:\n bool: True if k is in the tuple, False otherwise.\n \"\"\"\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n \"\"\"\n Check if the given tuple contains the number k.\n \n :param tup: Tuple of integers\n :param k: Integer to check in the tuple\n :return: True if k is in tup, False otherwise\n \"\"\"\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n # Check if k is in the tuple\n return k in tup", "matching_cluster_idx": 4}, {"solution": "def check_K(tup, k):\n # Check if k is in the tuple\n return k in tup", "matching_cluster_idx": 4}, {"solution": "def check_K(tup, k):\n \"\"\"\n Check if the given tuple contains the specified element k.\n\n Args:\n tup (tuple): The input tuple.\n k (int or any type): The element to check for in the tuple.\n\n Returns:\n bool: True if k is in tup, False otherwise.\n \"\"\"\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(test_tup, K):\n \"\"\"\n Check if the given tuple contains the given number K or not.\n\n :param test_tup: Tuple to check for the presence of K.\n :param K: Number to check for in the tuple.\n :return: True if K is found in the tuple, False otherwise.\n \"\"\"\n # Check if K is in the tuple\n return K in test_tup", "matching_cluster_idx": 5}, {"solution": "def check_K(tuples, k):\n # Check if k is in the given tuple\n return k in tuples", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n # Check if k is in the tuple\n if k in tup:\n return True\n else:\n return False", "matching_cluster_idx": 4}, {"solution": "def check_K(tuples, k):\n \"\"\"\n Check if the given tuples contain the k or not.\n\n Args:\n tuples (tuple): A tuple of elements.\n k: The element to search for in the tuple.\n\n Returns:\n bool: True if k is in the tuple, False otherwise.\n \"\"\"\n return k in tuples", "matching_cluster_idx": 5}]}}} \ No newline at end of file diff --git a/results/evalperf/Qwen--Qwen2.5-Coder-7B-Instruct_vllm_temp_1.0_evalperf_results.brief.json b/results/evalperf/Qwen--Qwen2.5-Coder-7B-Instruct_vllm_temp_1.0_evalperf_results.brief.json new file mode 100644 index 0000000..4cb4cf9 --- /dev/null +++ b/results/evalperf/Qwen--Qwen2.5-Coder-7B-Instruct_vllm_temp_1.0_evalperf_results.brief.json @@ -0,0 +1 @@ +{"date": "2024-10-19 16:30", "config": {"n_samples": 100, "temperature": 1.0, "min_correct": 10, "max_profile": 20}, "summary": {"dps": 79.81023172966313, "dps_norm": 76.74937875060594, "pass@1": 76.42372881355932}, "eval": {"HumanEval/9": {"dps": 79.70031545741325, "dps_norm": 75.55555555555556, "pass@1": 100.0, "profiled": [{"solution": "from typing import *\nfrom collections import *\nfrom typing import List, Tuple\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n \n max_list = []\n current_max = numbers[0]\n for number in numbers:\n current_max = max(current_max, number)\n max_list.append(current_max)\n \n return max_list", "matching_cluster_idx": 4}, {"solution": "from typing import *\nfrom collections import *\nfrom typing import List, Tuple\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n\n result = []\n current_max = numbers[0]\n for number in numbers:\n current_max = max(current_max, number)\n result.append(current_max)\n return result", "matching_cluster_idx": 4}, {"solution": "from typing import *\nfrom collections import *\nfrom typing import List, Tuple\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n \n result = []\n current_max = numbers[0]\n for number in numbers:\n if number > current_max:\n current_max = number\n result.append(current_max)\n \n return result", "matching_cluster_idx": 8}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n \n result = []\n current_max = float('-inf')\n \n for number in numbers:\n current_max = max(current_max, number)\n result.append(current_max)\n \n return result", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n\n result = [numbers[0]]\n current_max = numbers[0]\n\n for number in numbers[1:]:\n if number > current_max:\n current_max = number\n result.append(current_max)\n\n return result", "matching_cluster_idx": 8}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n if not numbers:\n return []\n\n rolling_max_list = [numbers[0]]\n for number in numbers[1:]:\n rolling_max_list.append(max(rolling_max_list[-1], number))\n\n return rolling_max_list", "matching_cluster_idx": 4}, {"solution": "from typing import *\nfrom collections import *\nfrom typing import List, Tuple\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n \n max_list = []\n current_max = numbers[0]\n for number in numbers:\n if number > current_max:\n current_max = number\n max_list.append(current_max)\n \n return max_list", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n\n max_list = []\n current_max = numbers[0]\n for number in numbers:\n if number > current_max:\n current_max = number\n max_list.append(current_max)\n\n return max_list", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n\n max_so_far = numbers[0]\n rolling_max_list = [max_so_far]\n\n for num in numbers[1:]:\n max_so_far = max(max_so_far, num)\n rolling_max_list.append(max_so_far)\n\n return rolling_max_list", "matching_cluster_idx": 4}, {"solution": "from typing import *\nfrom collections import *\nfrom typing import List, Tuple\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n \n max_list = []\n current_max = numbers[0]\n for number in numbers:\n if number > current_max:\n current_max = number\n max_list.append(current_max)\n \n return max_list", "matching_cluster_idx": 8}, {"solution": "from typing import *\nfrom collections import *\nfrom typing import List, Tuple\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers: # Check if the list is empty\n return []\n \n result = []\n current_max = numbers[0]\n \n for number in numbers:\n current_max = max(current_max, number) # Update current_max if the number is greater\n result.append(current_max) # Append the current_max to the result list\n \n return result", "matching_cluster_idx": 4}, {"solution": "from typing import List, Tuple\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n\n result = []\n current_max = numbers[0]\n for number in numbers:\n current_max = max(current_max, number)\n result.append(current_max)\n\n return result", "matching_cluster_idx": 4}, {"solution": "from typing import List, Tuple\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n\n max_so_far = numbers[0]\n result = [max_so_far]\n\n for number in numbers[1:]:\n if number > max_so_far:\n max_so_far = number\n result.append(max_so_far)\n\n return result", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n\n # Initialize the list to store the rolling maxima\n rolling_max_list = []\n # Initialize the current max to the first element\n current_max = numbers[0]\n # Iterate over the list of numbers\n for number in numbers:\n # Update the current max if the current number is greater\n if number > current_max:\n current_max = number\n # Append the current max to the rolling maxima list\n rolling_max_list.append(current_max)\n\n return rolling_max_list", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n\n result = [numbers[0]]\n for num in numbers[1:]:\n result.append(max(result[-1], num))\n\n return result", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n\n result = []\n current_max = float('-inf')\n for num in numbers:\n current_max = max(current_max, num)\n result.append(current_max)\n\n return result", "matching_cluster_idx": 4}, {"solution": "from typing import List, Tuple\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n max_list = []\n current_max = float('-inf')\n for number in numbers:\n if number > current_max:\n current_max = number\n max_list.append(current_max)\n return max_list", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n\n result = []\n current_max = numbers[0]\n for num in numbers:\n current_max = max(current_max, num)\n result.append(current_max)\n\n return result", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n if not numbers:\n return []\n\n max_list = [numbers[0]]\n for number in numbers[1:]:\n max_list.append(max(max_list[-1], number))\n return max_list", "matching_cluster_idx": 4}, {"solution": "from typing import List, Tuple\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n\n max_until_now = numbers[0]\n result = [max_until_now]\n\n for number in numbers[1:]:\n if number > max_until_now:\n max_until_now = number\n result.append(max_until_now)\n\n return result", "matching_cluster_idx": 8}]}, "HumanEval/0": {"dps": 58.02325581395348, "dps_norm": 65.71428571428572, "pass@1": 100.0, "profiled": [{"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n \"\"\"\n # Iterate through each pair of numbers in the list\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n # Check if the absolute difference between the numbers is less than the threshold\n if abs(numbers[i] - numbers[j]) < threshold:\n return True\n return False", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n # Sort the list to make it easier to find close elements\n sorted_numbers = sorted(numbers)\n # Iterate through the sorted list and check adjacent elements\n for i in range(len(sorted_numbers) - 1):\n if abs(sorted_numbers[i] - sorted_numbers[i + 1]) < threshold:\n return True\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n numbers.sort()\n for i in range(len(numbers) - 1):\n if numbers[i + 1] - numbers[i] < threshold:\n return True\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n # Sort the list to make it easier to find close elements\n numbers.sort()\n \n # Iterate through the sorted list and check the difference between consecutive elements\n for i in range(len(numbers) - 1):\n if abs(numbers[i] - numbers[i + 1]) < threshold:\n return True\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\"\n Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n \n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n # Sort the list to make comparison easier\n sorted_numbers = sorted(numbers)\n # Iterate through the sorted list and check the difference between consecutive elements\n for i in range(len(sorted_numbers) - 1):\n if abs(sorted_numbers[i] - sorted_numbers[i + 1]) < threshold:\n return True\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\"\n Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n \"\"\"\n # Sort the list to make it easier to find close elements\n sorted_numbers = sorted(numbers)\n # Iterate through the sorted list and check the difference between consecutive elements\n for i in range(len(sorted_numbers) - 1):\n if abs(sorted_numbers[i] - sorted_numbers[i + 1]) < threshold:\n return True\n return False", "matching_cluster_idx": 2}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n # Sort the list to make comparison easier\n sorted_numbers = sorted(numbers)\n # Iterate through the sorted list and check the difference between consecutive elements\n for i in range(len(sorted_numbers) - 1):\n if abs(sorted_numbers[i] - sorted_numbers[i + 1]) < threshold:\n return True\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n # Sort the list to make comparison easier\n numbers.sort()\n \n # Iterate through the sorted list and check the difference between consecutive elements\n for i in range(len(numbers) - 1):\n if abs(numbers[i] - numbers[i + 1]) < threshold:\n return True\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import *\nfrom collections import *\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n numbers.sort()\n for i in range(len(numbers) - 1):\n if numbers[i + 1] - numbers[i] < threshold:\n return True\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\"\n Check if in the given list of numbers, any two numbers are closer to each other than the given threshold.\n \n :param numbers: List of floating-point numbers.\n :param threshold: A floating-point number representing the threshold.\n :return: True if any two numbers are closer than the threshold, False otherwise.\n \n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n # Sort the list to make the comparison easier\n sorted_numbers = sorted(numbers)\n \n # Iterate through the sorted list and check the difference between consecutive elements\n for i in range(len(sorted_numbers) - 1):\n if abs(sorted_numbers[i] - sorted_numbers[i + 1]) < threshold:\n return True\n return False", "matching_cluster_idx": 2}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\"\n Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n numbers.sort() # Sort the list to make comparison easier\n for i in range(len(numbers) - 1):\n if abs(numbers[i] - numbers[i + 1]) < threshold:\n return True\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n # Iterate through each pair of numbers in the list\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n # Check if the absolute difference between the numbers is less than the threshold\n if abs(numbers[i] - numbers[j]) < threshold:\n return True\n return False", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\"\n Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n # Iterate over each pair of numbers in the list\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n # Check if the absolute difference between any two numbers is less than the threshold\n if abs(numbers[i] - numbers[j]) < threshold:\n return True\n # Return False if no such pair is found\n return False", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n # Sort the list to make comparison easier\n sorted_numbers = sorted(numbers)\n # Iterate through the sorted list and check adjacent elements\n for i in range(len(sorted_numbers) - 1):\n # If the difference between two adjacent elements is less than the threshold, return True\n if sorted_numbers[i + 1] - sorted_numbers[i] < threshold:\n return True\n # If no such pair is found, return False\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n if abs(numbers[i] - numbers[j]) < threshold:\n return True\n return False", "matching_cluster_idx": 6}, {"solution": "from typing import List\nfrom itertools import combinations\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n \"\"\"\n for num1, num2 in combinations(numbers, 2):\n if abs(num1 - num2) < threshold:\n return True\n return False", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n numbers.sort() # Sorting the list to reduce the number of comparisons\n for i in range(len(numbers) - 1):\n if abs(numbers[i] - numbers[i + 1]) < threshold:\n return True\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n numbers.sort() # Sort the list to make comparison easier\n for i in range(len(numbers) - 1):\n if abs(numbers[i] - numbers[i + 1]) < threshold:\n return True\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n # Sort the list to make comparison easier\n numbers.sort()\n # Iterate through the list and compare adjacent elements\n for i in range(len(numbers) - 1):\n if abs(numbers[i] - numbers[i + 1]) < threshold:\n return True\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n \"\"\"\n # Sort the list to make the comparison easier\n numbers.sort()\n \n # Iterate through the sorted list and check the difference between consecutive elements\n for i in range(len(numbers) - 1):\n if abs(numbers[i] - numbers[i + 1]) < threshold:\n return True\n return False", "matching_cluster_idx": 3}]}, "HumanEval/4": {"dps": 65.99683544303798, "dps_norm": 70.83333333333333, "pass@1": 97.0, "profiled": [{"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if not numbers:\n return 0.0\n\n mean = sum(numbers) / len(numbers)\n total_deviation = sum(abs(x - mean) for x in numbers)\n return total_deviation / len(numbers)", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if not numbers:\n raise ValueError(\"The list of numbers cannot be empty\")\n\n mean = sum(numbers) / len(numbers)\n total_deviation = sum(abs(x - mean) for x in numbers)\n mad = total_deviation / len(numbers)\n return mad", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\"\n Calculate Mean Absolute Deviation of a list of numbers around the mean.\n \n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if not numbers:\n return 0.0\n\n mean = sum(numbers) / len(numbers)\n mads = [abs(x - mean) for x in numbers]\n mad = sum(mads) / len(mads)\n return mad", "matching_cluster_idx": 5}, {"solution": "from typing import List\nimport statistics\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n mean = statistics.mean(numbers)\n return statistics.mean([abs(x - mean) for x in numbers])", "matching_cluster_idx": 0}, {"solution": "from typing import List\nfrom statistics import mean\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n data_mean = mean(numbers)\n return mean([abs(x - data_mean) for x in numbers])", "matching_cluster_idx": 0}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if not numbers:\n return 0.0\n \n mean = sum(numbers) / len(numbers)\n mad = sum(abs(x - mean) for x in numbers) / len(numbers)\n \n return mad", "matching_cluster_idx": 5}, {"solution": "from typing import *\nfrom collections import *\nfrom typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n mean = sum(numbers) / len(numbers)\n absolute_deviations = [abs(x - mean) for x in numbers]\n mad = sum(absolute_deviations) / len(absolute_deviations)\n return mad", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n mean = sum(numbers) / len(numbers)\n total_deviation = sum(abs(x - mean) for x in numbers)\n return total_deviation / len(numbers)", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if not numbers:\n return 0.0\n\n mean = sum(numbers) / len(numbers)\n total_deviation = sum(abs(x - mean) for x in numbers)\n mad = total_deviation / len(numbers)\n return mad", "matching_cluster_idx": 5}, {"solution": "from typing import List\nimport statistics\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n mean_value = statistics.mean(numbers)\n mad = sum(abs(x - mean_value) for x in numbers) / len(numbers)\n return mad", "matching_cluster_idx": 0}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if not numbers:\n return 0.0 # Return 0.0 if the list is empty to avoid division by zero\n \n mean = sum(numbers) / len(numbers)\n mad = sum(abs(x - mean) for x in numbers) / len(numbers)\n return mad", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n mean = sum(numbers) / len(numbers)\n total_deviation = sum(abs(x - mean) for x in numbers)\n mad = total_deviation / len(numbers)\n return mad", "matching_cluster_idx": 5}, {"solution": "from typing import List\nimport statistics\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n mean = statistics.mean(numbers)\n return sum(abs(x - mean) for x in numbers) / len(numbers)", "matching_cluster_idx": 0}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if not numbers:\n return 0.0\n \n mean = sum(numbers) / len(numbers)\n total_deviation = sum(abs(x - mean) for x in numbers)\n mad = total_deviation / len(numbers)\n \n return mad", "matching_cluster_idx": 5}, {"solution": "from typing import List\nimport statistics\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\"\n For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if not numbers:\n return 0.0\n\n mean_value = statistics.mean(numbers)\n mad = sum(abs(x - mean_value) for x in numbers) / len(numbers)\n return mad", "matching_cluster_idx": 0}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if not numbers:\n return 0.0 # Return 0 if the list is empty\n\n mean = sum(numbers) / len(numbers)\n return sum(abs(x - mean) for x in numbers) / len(numbers)", "matching_cluster_idx": 5}, {"solution": "from typing import List\nimport statistics\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n mean = statistics.mean(numbers)\n return sum(abs(x - mean) for x in numbers) / len(numbers)", "matching_cluster_idx": 0}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n mean = sum(numbers) / len(numbers)\n return sum(abs(x - mean) for x in numbers) / len(numbers)", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n # Calculate the mean of the dataset\n mean = sum(numbers) / len(numbers)\n \n # Calculate the absolute deviations from the mean\n absolute_deviations = [abs(x - mean) for x in numbers]\n \n # Calculate the mean of these absolute deviations (MAD)\n mad = sum(absolute_deviations) / len(absolute_deviations)\n \n return mad", "matching_cluster_idx": 5}, {"solution": "from typing import List\nfrom statistics import mean\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\"\n Calculate the Mean Absolute Deviation of a given list of numbers.\n\n :param numbers: List of input numbers.\n :return: Mean Absolute Deviation of the input numbers.\n \"\"\"\n if not numbers:\n return 0.0\n\n mean_value = mean(numbers)\n abs_deviation_sum = sum(abs(x - mean_value) for x in numbers)\n mad = abs_deviation_sum / len(numbers)\n return mad", "matching_cluster_idx": 0}]}, "HumanEval/16": {"dps": 42.7906976744186, "dps_norm": 83.33333333333333, "pass@1": 100.0, "profiled": [{"solution": "def count_distinct_characters(s: str) -> int:\n # Convert the string to lowercase to ignore case differences\n s = s.lower()\n # Use a set to store unique characters\n distinct_chars = set(s)\n # Return the number of distinct characters\n return len(distinct_chars)", "matching_cluster_idx": 7}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n return len(set(string.lower()))", "matching_cluster_idx": 7}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lowercase to ensure case-insensitivity\n lowercase_string = string.lower()\n # Use a set to store distinct characters\n distinct_characters = set(lowercase_string)\n # Return the number of distinct characters\n return len(distinct_characters)", "matching_cluster_idx": 7}, {"solution": "def count_distinct_characters(string: str) -> int:\n # Convert the string to lowercase to ignore case differences\n string = string.lower()\n # Use a set to store distinct characters\n distinct_chars = set()\n # Iterate over each character in the string\n for char in string:\n # Add the character to the set (duplicates are ignored)\n distinct_chars.add(char)\n # Return the number of distinct characters\n return len(distinct_chars)", "matching_cluster_idx": 2}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lowercase to ignore case differences\n lowercase_string = string.lower()\n # Use a set to store distinct characters\n distinct_characters = set(lowercase_string)\n # Return the number of distinct characters\n return len(distinct_characters)", "matching_cluster_idx": 7}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lowercase to ignore case and use a set to find distinct characters\n return len(set(string.lower()))", "matching_cluster_idx": 7}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n return len(set(string.lower()))", "matching_cluster_idx": 7}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n return len(set(string.lower()))", "matching_cluster_idx": 7}, {"solution": "def count_distinct_characters(s: str) -> int:\n \"\"\"Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n return len(set(s.lower()))", "matching_cluster_idx": 7}, {"solution": "def count_distinct_characters(string: str) -> int:\n # Convert the string to lowercase to ignore case differences and create a set of characters\n unique_chars = set(string.lower())\n # Return the number of unique characters\n return len(unique_chars)", "matching_cluster_idx": 7}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n return len(set(string.lower()))", "matching_cluster_idx": 7}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lowercase to ignore case differences\n # Then use a set to store unique characters\n unique_chars = set(string.lower())\n # Return the number of unique characters\n return len(unique_chars)", "matching_cluster_idx": 7}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\"\n Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lowercase to ignore case and use a set to store distinct characters\n distinct_chars = set(string.lower())\n # Return the number of distinct characters\n return len(distinct_chars)", "matching_cluster_idx": 7}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lowercase to ignore case differences\n # Use a set to store distinct characters\n distinct_chars = set(string.lower())\n # Return the number of distinct characters\n return len(distinct_chars)", "matching_cluster_idx": 7}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lowercase to ensure case-insensitivity\n string = string.lower()\n # Use a set to store distinct characters\n distinct_chars = set(string)\n # Return the number of distinct characters\n return len(distinct_chars)", "matching_cluster_idx": 7}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\"\n Given a string, find out how many distinct characters (regardless of case) does it consist of.\n \n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lowercase to ignore case differences\n lower_string = string.lower()\n # Use a set to store distinct characters\n distinct_chars = set(lower_string)\n # Return the number of distinct characters\n return len(distinct_chars)", "matching_cluster_idx": 7}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lowercase to ignore case differences\n string = string.lower()\n # Use a set to store distinct characters\n distinct_chars = set()\n for char in string:\n distinct_chars.add(char)\n return len(distinct_chars)", "matching_cluster_idx": 2}, {"solution": "def count_distinct_characters(string: str) -> int:\n # Convert the string to lowercase to ignore case and use a set to find distinct characters\n return len(set(string.lower()))", "matching_cluster_idx": 7}, {"solution": "def count_distinct_characters(s: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lowercase to ignore case and then find distinct characters\n distinct_chars = set(s.lower())\n return len(distinct_chars)", "matching_cluster_idx": 7}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n return len(set(string.lower()))", "matching_cluster_idx": 7}]}, "HumanEval/20": {"dps": 84.21307506053269, "dps_norm": 88.88888888888889, "pass@1": 97.0, "profiled": [{"solution": "from typing import List, Tuple\nimport math\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n # Initialize the minimum distance and closest pair with very large distance and dummy values\n min_distance = math.inf\n closest_pair = (None, None)\n \n # Sort the list to ensure that potential closest elements are adjacent\n numbers_sorted = sorted(numbers)\n \n # Iterate through the sorted list to find the closest pair\n for i in range(len(numbers_sorted) - 1):\n current_distance = numbers_sorted[i + 1] - numbers_sorted[i]\n if current_distance < min_distance:\n min_distance = current_distance\n closest_pair = (numbers_sorted[i], numbers_sorted[i + 1])\n \n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\nfrom math import inf\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n min_diff = inf\n closest_pair = (0, 0)\n\n # Sort the list to make finding the closest pair more efficient\n sorted_numbers = sorted(numbers)\n\n for i in range(len(sorted_numbers) - 1):\n diff = sorted_numbers[i + 1] - sorted_numbers[i]\n if diff < min_diff:\n min_diff = diff\n closest_pair = (sorted_numbers[i], sorted_numbers[i + 1])\n\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n # First, sort the list to make finding the closest pair easier\n sorted_numbers = sorted(numbers)\n # Initialize variables to store the closest pair and the smallest difference found\n closest_pair = (sorted_numbers[0], sorted_numbers[1])\n smallest_diff = abs(sorted_numbers[1] - sorted_numbers[0])\n\n # Iterate through the sorted list to find the closest pair\n for i in range(1, len(sorted_numbers) - 1):\n current_diff = abs(sorted_numbers[i + 1] - sorted_numbers[i])\n if current_diff < smallest_diff:\n smallest_diff = current_diff\n closest_pair = (sorted_numbers[i], sorted_numbers[i + 1])\n\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\"\n Find and return the two closest numbers in the provided list.\n\n Args:\n numbers: A list of floating-point numbers with at least two elements.\n\n Returns:\n A tuple containing the two closest numbers, ordered from smallest to largest.\n\n Examples:\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n # Initialize variables to store the closest pair and the smallest difference\n closest_pair = (numbers[0], numbers[1])\n smallest_diff = abs(numbers[1] - numbers[0])\n\n # Iterate through the list to find the closest pair\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n current_diff = abs(numbers[j] - numbers[i])\n if current_diff < smallest_diff:\n smallest_diff = current_diff\n closest_pair = (min(numbers[i], numbers[j]), max(numbers[i], numbers[j]))\n\n return closest_pair", "matching_cluster_idx": 3}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n # Sort the list to make it easier to find the closest elements\n sorted_numbers = sorted(numbers)\n \n # Initialize variables to store the closest pair and the smallest difference found\n closest_pair = (sorted_numbers[0], sorted_numbers[1])\n smallest_difference = abs(sorted_numbers[1] - sorted_numbers[0])\n \n # Iterate through the sorted list to find the pair with the smallest difference\n for i in range(1, len(sorted_numbers) - 1):\n current_difference = abs(sorted_numbers[i+1] - sorted_numbers[i])\n if current_difference < smallest_difference:\n smallest_difference = current_difference\n closest_pair = (sorted_numbers[i], sorted_numbers[i+1])\n \n # Return the closest pair as a tuple (smaller number, larger number)\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\"\n From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n \"\"\"\n if len(numbers) < 2:\n raise ValueError(\"List must contain at least two elements.\")\n \n # Sort the list to make it easier to find the closest elements\n sorted_numbers = sorted(numbers)\n \n # Initialize variables to store the closest pair and the smallest difference found\n closest_pair = (sorted_numbers[0], sorted_numbers[1])\n smallest_diff = abs(sorted_numbers[1] - sorted_numbers[0])\n \n # Iterate through the sorted list to find the closest pair\n for i in range(1, len(sorted_numbers) - 1):\n diff = abs(sorted_numbers[i + 1] - sorted_numbers[i])\n if diff < smallest_diff:\n smallest_diff = diff\n closest_pair = (sorted_numbers[i], sorted_numbers[i + 1])\n \n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n # Sort the list to make it easier to find the closest pair\n sorted_numbers = sorted(numbers)\n # Initialize variables to store the closest pair and the smallest difference found\n closest_pair = (sorted_numbers[0], sorted_numbers[1])\n smallest_difference = abs(sorted_numbers[1] - sorted_numbers[0])\n \n # Iterate through the sorted list to find the pair with the smallest difference\n for i in range(1, len(sorted_numbers) - 1):\n current_difference = abs(sorted_numbers[i+1] - sorted_numbers[i])\n if current_difference < smallest_difference:\n smallest_difference = current_difference\n closest_pair = (sorted_numbers[i], sorted_numbers[i+1])\n \n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n numbers.sort() # Sort the numbers to make comparison easier\n closest_pair = (numbers[0], numbers[1])\n min_diff = abs(numbers[1] - numbers[0])\n\n for i in range(1, len(numbers) - 1):\n current_diff = abs(numbers[i + 1] - numbers[i])\n if current_diff < min_diff:\n min_diff = current_diff\n closest_pair = (numbers[i], numbers[i + 1])\n\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n if len(numbers) < 2:\n raise ValueError(\"List must contain at least two elements\")\n\n # Sort the list to make finding the closest elements easier\n numbers.sort()\n\n # Initialize variables to store the closest elements and the smallest difference found\n closest_pair = (numbers[0], numbers[1])\n smallest_difference = abs(numbers[1] - numbers[0])\n\n # Iterate through the sorted list to find the pair with the smallest difference\n for i in range(1, len(numbers) - 1):\n current_difference = abs(numbers[i + 1] - numbers[i])\n if current_difference < smallest_difference:\n closest_pair = (numbers[i], numbers[i + 1])\n smallest_difference = current_difference\n\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n closest_pair = (numbers[0], numbers[1])\n smallest_diff = abs(numbers[1] - numbers[0])\n\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n current_diff = abs(numbers[j] - numbers[i])\n if current_diff < smallest_diff:\n smallest_diff = current_diff\n closest_pair = (min(numbers[i], numbers[j]), max(numbers[i], numbers[j]))\n\n return closest_pair", "matching_cluster_idx": 3}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n # Initialize with the first two elements\n closest_pair = (numbers[0], numbers[1])\n min_diff = abs(numbers[1] - numbers[0])\n \n # Iterate through each pair of elements to find the closest one\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n diff = abs(numbers[j] - numbers[i])\n if diff < min_diff:\n min_diff = diff\n closest_pair = (min(numbers[i], numbers[j]), max(numbers[i], numbers[j]))\n \n return closest_pair", "matching_cluster_idx": 3}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\"\n From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n # Sort the list to simplify the process of finding the closest elements\n sorted_numbers = sorted(numbers)\n closest_distance = float('inf')\n closest_pair = (0, 0)\n\n # Iterate through the sorted list to find the pair with the smallest difference\n for i in range(len(sorted_numbers) - 1):\n diff = sorted_numbers[i+1] - sorted_numbers[i]\n if diff < closest_distance:\n closest_distance = diff\n closest_pair = (sorted_numbers[i], sorted_numbers[i+1])\n\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\"From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n\n :param numbers: List of numbers with at least two elements\n :return: A tuple of two closest numbers, in ascending order\n\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n if len(numbers) < 2:\n raise ValueError(\"List must contain at least two numbers\")\n\n numbers.sort()\n closest_pair = (numbers[0], numbers[1])\n smallest_diff = abs(numbers[1] - numbers[0])\n\n for i in range(1, len(numbers) - 1):\n diff = abs(numbers[i + 1] - numbers[i])\n if diff < smallest_diff:\n smallest_diff = diff\n closest_pair = (numbers[i], numbers[i + 1])\n\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\"\n From a supplied list of numbers (of length at least two) select and return two that are the closest to each other\n and return them in order (smaller number, larger number).\n \"\"\"\n # Initialize variables to store the closest pair and the smallest difference found\n closest_pair = (numbers[0], numbers[1])\n smallest_diff = abs(numbers[1] - numbers[0])\n \n # Sort the numbers to make finding the closest pair easier\n sorted_numbers = sorted(numbers)\n \n # Iterate through the sorted list to find the closest pair\n for i in range(len(sorted_numbers) - 1):\n diff = abs(sorted_numbers[i] - sorted_numbers[i + 1])\n if diff < smallest_diff:\n smallest_diff = diff\n closest_pair = (sorted_numbers[i], sorted_numbers[i + 1])\n \n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n # Initialize variables to store the closest pair and the smallest difference found\n closest_pair = ()\n smallest_diff = float('inf')\n \n # Sort the list to make it easier to find the closest elements\n sorted_numbers = sorted(numbers)\n \n # Iterate through the sorted list to find the pair with the smallest difference\n for i in range(len(sorted_numbers) - 1):\n diff = sorted_numbers[i+1] - sorted_numbers[i]\n if diff < smallest_diff:\n smallest_diff = diff\n closest_pair = (sorted_numbers[i], sorted_numbers[i+1])\n \n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import *\nfrom collections import *\nfrom typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n if len(numbers) < 2:\n raise ValueError(\"List must contain at least two numbers\")\n\n numbers.sort()\n closest_pair = (numbers[0], numbers[1])\n min_distance = abs(numbers[1] - numbers[0])\n\n for i in range(1, len(numbers) - 1):\n current_distance = abs(numbers[i + 1] - numbers[i])\n if current_distance < min_distance:\n min_distance = current_distance\n closest_pair = (numbers[i], numbers[i + 1])\n\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n numbers.sort()\n closest_pair = (numbers[0], numbers[1])\n min_diff = abs(numbers[1] - numbers[0])\n \n for i in range(1, len(numbers) - 1):\n diff = abs(numbers[i + 1] - numbers[i])\n if diff < min_diff:\n min_diff = diff\n closest_pair = (numbers[i], numbers[i + 1])\n \n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\"\n Find and return two numbers from the supplied list that are closest to each other, in ascending order.\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n if len(numbers) < 2:\n raise ValueError(\"Input list must contain at least two elements\")\n\n # Sort the list to make it easier to find the closest elements\n numbers.sort()\n\n # Initialize variables to store the closest pair and the smallest difference found\n closest_pair = (numbers[0], numbers[1])\n smallest_diff = abs(numbers[1] - numbers[0])\n\n # Iterate through the sorted list to find the closest pair\n for i in range(1, len(numbers) - 1):\n current_diff = abs(numbers[i + 1] - numbers[i])\n if current_diff < smallest_diff:\n smallest_diff = current_diff\n closest_pair = (numbers[i], numbers[i + 1])\n\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n # Sort the list to make it easier to find the closest elements\n sorted_numbers = sorted(numbers)\n # Initialize variables to store the closest pair and the smallest difference found\n closest_pair = (sorted_numbers[0], sorted_numbers[1])\n smallest_diff = abs(sorted_numbers[1] - sorted_numbers[0])\n \n # Iterate through the sorted list to find the closest pair\n for i in range(1, len(sorted_numbers) - 1):\n diff = abs(sorted_numbers[i + 1] - sorted_numbers[i])\n if diff < smallest_diff:\n smallest_diff = diff\n closest_pair = (sorted_numbers[i], sorted_numbers[i + 1])\n \n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n closest_pair = (numbers[0], numbers[1])\n min_diff = abs(numbers[0] - numbers[1])\n\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n current_diff = abs(numbers[i] - numbers[j])\n if current_diff < min_diff:\n min_diff = current_diff\n closest_pair = (min(numbers[i], numbers[j]), max(numbers[i], numbers[j]))\n\n return closest_pair", "matching_cluster_idx": 3}]}, "HumanEval/24": {"dps": 72.04081632653062, "dps_norm": 31.25, "pass@1": 100.0, "profiled": [{"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n if n <= 1:\n return None # No divisors other than 1 for numbers <= 1\n for i in range(n // 2, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 4}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n for divisor in range(n - 1, 0, -1):\n if n % divisor == 0:\n return divisor\n return None # In case n is 1, which has no divisors smaller than itself", "matching_cluster_idx": 0}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n for i in range(n - 1, 0, -1):\n if n % i == 0:\n return i\n return 1", "matching_cluster_idx": 1}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n # Start checking from n-1 down to 1\n for i in range(n-1, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 1}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n if n <= 1:\n return None # No divisors for numbers less than or equal to 1\n for i in range(n - 1, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 0}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n for i in range(n // 2, 0, -1):\n if n % i == 0:\n return i\n return 1", "matching_cluster_idx": 4}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n for i in range(n-1, 0, -1):\n if n % i == 0:\n return i\n return 1", "matching_cluster_idx": 1}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n # Start from the largest possible divisor, which is n // 2\n for divisor in range(n // 2, 0, -1):\n # Check if n is divisible by the current divisor\n if n % divisor == 0:\n return divisor\n # If no divisor is found, return 1 (every number is divisible by 1)\n return 1", "matching_cluster_idx": 4}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n\n >>> largest_divisor(15)\n 5\n \"\"\"\n for i in range(n - 1, 0, -1):\n if n % i == 0:\n return i\n return 1", "matching_cluster_idx": 1}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n \n >>> largest_divisor(15)\n 5\n \"\"\"\n for i in range(n-1, 0, -1):\n if n % i == 0:\n return i\n return 1", "matching_cluster_idx": 1}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n for i in range(n-1, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 1}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n for i in range(n-1, 0, -1):\n if n % i == 0:\n return i\n return 1 # If no divisor found other than 1, return 1", "matching_cluster_idx": 1}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n for i in range(n - 1, 0, -1):\n if n % i == 0:\n return i\n return None", "matching_cluster_idx": 1}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n # Start checking from n-1 down to 1\n for i in range(n-1, 0, -1):\n # Check if i is a divisor of n\n if n % i == 0:\n return i # Return the first divisor found, which is the largest\n return 1 # If no divisor found other than 1, return 1", "matching_cluster_idx": 1}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n for i in range(n-1, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 1}, {"solution": "from typing import *\ndef largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n for divisor in range(n - 1, 0, -1):\n if n % divisor == 0:\n return divisor", "matching_cluster_idx": 1}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n for i in range(n // 2, 0, -1):\n if n % i == 0:\n return i\n return 1 # If no divisor found, return 1 (for prime numbers)", "matching_cluster_idx": 4}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n for i in range(n - 1, 0, -1):\n if n % i == 0:\n return i\n return 1 # If no divisor found other than 1, return 1", "matching_cluster_idx": 1}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n\n >>> largest_divisor(15)\n 5\n \"\"\"\n # Start checking from n-1 down to 1 to find the largest divisor\n for i in range(n - 1, 0, -1):\n if n % i == 0:\n return i\n return 1 # If no divisor is found, return 1 (every number is divisible by 1)", "matching_cluster_idx": 1}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n # Start checking from n-1 down to 1 to find the largest divisor\n for i in range(n-1, 0, -1):\n if n % i == 0:\n return i\n return 1 # Every number is divisible by 1", "matching_cluster_idx": 1}]}, "HumanEval/26": {"dps": 96.4, "dps_norm": 98.75, "pass@1": 25.0, "profiled": [{"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n # Create a dictionary to count occurrences of each number\n count_dict = {}\n for num in numbers:\n if num in count_dict:\n count_dict[num] += 1\n else:\n count_dict[num] = 1\n \n # Filter numbers that occur more than once\n result = [num for num in numbers if count_dict[num] == 1]\n \n return result", "matching_cluster_idx": 3}, {"solution": "from typing import *\nfrom collections import *\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n # Dictionary to track the count of each number\n count = defaultdict(int)\n # List to store numbers that occur only once\n unique_numbers = []\n\n # Count occurrences of each number\n for number in numbers:\n count[number] += 1\n\n # Append numbers that occur only once to the result list\n for number in numbers:\n if count[number] == 1:\n unique_numbers.append(number)\n\n return unique_numbers", "matching_cluster_idx": 2}, {"solution": "from typing import *\nfrom collections import *\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n seen = set()\n duplicates = set()\n result = []\n\n for number in numbers:\n if number in seen:\n duplicates.add(number)\n else:\n seen.add(number)\n \n for number in numbers:\n if number not in duplicates:\n result.append(number)\n \n return result", "matching_cluster_idx": 3}, {"solution": "from typing import *\nfrom collections import *\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n counts = Counter(numbers)\n return [num for num in numbers if counts[num] == 1]", "matching_cluster_idx": 3}, {"solution": "from typing import *\nfrom collections import *\nfrom typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n # Use a dictionary to count occurrences of each number\n count = defaultdict(int)\n for num in numbers:\n count[num] += 1\n \n # Filter out numbers that occur more than once and return the result\n return [num for num in numbers if count[num] == 1]", "matching_cluster_idx": 3}, {"solution": "from typing import *\nfrom collections import *\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n # Create a counter for all numbers in the list\n number_counts = Counter(numbers)\n \n # Filter out numbers that appear more than once and return the result\n return [num for num in numbers if number_counts[num] == 1]", "matching_cluster_idx": 3}, {"solution": "from typing import *\nfrom collections import *\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n # Create a counter to keep track of the occurrence of each number\n number_counter = Counter(numbers)\n \n # Filter out numbers that occur more than once\n result = [num for num in numbers if number_counter[num] == 1]\n \n return result", "matching_cluster_idx": 3}, {"solution": "from typing import *\nfrom collections import *\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n # Create a counter for the elements in the list\n element_count = Counter(numbers)\n # Filter out elements that appear more than once and keep the order\n unique_numbers = [num for num in numbers if element_count[num] == 1]\n return unique_numbers", "matching_cluster_idx": 3}, {"solution": "from typing import *\nfrom collections import *\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n # Create a dictionary to count occurrences of each number\n counts = defaultdict(int)\n for number in numbers:\n counts[number] += 1\n\n # Filter out numbers that occur more than once and maintain the order\n result = [number for number in numbers if counts[number] == 1]\n\n return result", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n # Create a dictionary to keep track of the occurrences of each number\n occurrences = {}\n \n # Iterate over the list and count occurrences\n for number in numbers:\n if number in occurrences:\n occurrences[number] += 1\n else:\n occurrences[number] = 1\n \n # Use list comprehension to filter out numbers that occur more than once\n result = [number for number in numbers if occurrences[number] == 1]\n \n return result", "matching_cluster_idx": 3}, {"solution": "from typing import *\nfrom collections import *\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n # Create a dictionary to count occurrences of each number\n count = Counter(numbers)\n \n # Filter out numbers that occur more than once\n return [num for num in numbers if count[num] == 1]", "matching_cluster_idx": 3}, {"solution": "from typing import *\nfrom collections import *\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n # Create a dictionary to count occurrences of each number\n count = Counter(numbers)\n # Filter numbers that occur only once and maintain order\n return [num for num in numbers if count[num] == 1]", "matching_cluster_idx": 3}, {"solution": "from typing import *\nfrom collections import *\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n # Create a counter to count occurrences of each number\n counts = Counter(numbers)\n # Filter numbers that occur only once and preserve the order\n return [num for num in numbers if counts[num] == 1]", "matching_cluster_idx": 3}, {"solution": "from typing import List\nfrom collections import Counter\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n # Count occurrences of each number\n counts = Counter(numbers)\n # Filter numbers that appear only once and preserve the order\n unique_numbers = [num for num in numbers if counts[num] == 1]\n return unique_numbers", "matching_cluster_idx": 3}, {"solution": "from typing import *\nfrom collections import *\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n seen = set()\n duplicates = set()\n result = []\n\n for number in numbers:\n if number in seen:\n duplicates.add(number)\n else:\n seen.add(number)\n \n for number in numbers:\n if number not in duplicates:\n result.append(number)\n \n return result", "matching_cluster_idx": 3}, {"solution": "from typing import *\nfrom collections import *\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n # Use a dictionary to count occurrences of each number\n counts = defaultdict(int)\n for number in numbers:\n counts[number] += 1\n \n # Keep only numbers that occur exactly once\n return [number for number in numbers if counts[number] == 1]", "matching_cluster_idx": 3}, {"solution": "from typing import List\nfrom collections import Counter\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n # Count the occurrences of each number\n counts = Counter(numbers)\n # Filter numbers that occur more than once and maintain the original order\n return [num for num in numbers if counts[num] == 1]", "matching_cluster_idx": 3}, {"solution": "from typing import *\nfrom collections import *\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n seen = set()\n duplicates = set()\n result = []\n\n for number in numbers:\n if number in seen:\n duplicates.add(number)\n else:\n seen.add(number)\n\n for number in numbers:\n if number not in duplicates:\n result.append(number)\n\n return result", "matching_cluster_idx": 3}, {"solution": "from typing import *\nfrom collections import *\nfrom typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n # Track the count of each number\n count = Counter(numbers)\n # Filter numbers that occur only once and maintain their order\n return [num for num in numbers if count[num] == 1]", "matching_cluster_idx": 3}, {"solution": "from typing import List\nfrom collections import Counter\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n # Count occurrences of each number\n num_counts = Counter(numbers)\n # Filter numbers that appear only once and preserve the original order\n return [num for num in numbers if num_counts[num] == 1]", "matching_cluster_idx": 3}]}, "HumanEval/31": {"dps": 88.10126582278481, "dps_norm": 85.0, "pass@1": 100.0, "profiled": [{"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n # Check if the number is less than 2\n if n <= 1:\n return False\n # Check for factors from 2 to the square root of n\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True", "matching_cluster_idx": 5}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n # Handle numbers less than 2 and even numbers directly\n if n <= 1 or (n % 2 == 0 and n > 2): \n return False\n # Check for factors from 3 to the square root of n\n for i in range(3, int(n**0.5) + 1, 2):\n if n % i == 0:\n return False\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True", "matching_cluster_idx": 5}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "import math\ndef is_prime(n):\n \"\"\"\n Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False # 0 and 1 are not prime numbers\n if n <= 3:\n return True # 2 and 3 are prime numbers\n \n # Check if n is divisible by 2 or 3\n if n % 2 == 0 or n % 3 == 0:\n return False\n \n # Check for factors from 5 to the square root of n\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n \n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True", "matching_cluster_idx": 5}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True", "matching_cluster_idx": 5}]}, "HumanEval/33": {"dps": 92.60416666666667, "dps_norm": 80.9090909090909, "pass@1": 88.0, "profiled": [{"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indices that are not divisible by three, while its values at the indices that are divisible by three are equal\n to the values of the corresponding indices of l, but sorted.\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n # Extract elements at indices divisible by three\n third_elements = [l[i] for i in range(len(l)) if i % 3 == 0]\n \n # Sort the extracted elements\n third_elements.sort()\n \n # Create a new list to store the result\n result = l[:]\n \n # Replace the elements in the result list at indices divisible by three with the sorted elements\n sorted_index = 0\n for i in range(len(l)):\n if i % 3 == 0:\n result[i] = third_elements[sorted_index]\n sorted_index += 1\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(lst: list):\n \"\"\"\n This function takes a list and returns a new list where elements at indices divisible by three are sorted,\n while other elements remain unchanged.\n \n :param lst: List of integers\n :return: Modified list with sorted elements at indices divisible by three\n \"\"\"\n # Extract elements at indices divisible by three\n divisible_by_three = [lst[i] for i in range(len(lst)) if i % 3 == 0]\n # Sort the extracted elements\n divisible_by_three.sort()\n \n # Create a new list to store the result\n result = lst[:]\n \n # Replace elements at indices divisible by three with sorted values\n for i in range(len(divisible_by_three)):\n result[i * 3] = divisible_by_three[i]\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indices that are not divisible by three, while its values at the indices that are divisible by three are equal\n to the values of the corresponding indices of l, but sorted.\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n # Extract elements at indices divisible by three\n third_elements = [l[i] for i in range(len(l)) if i % 3 == 0]\n \n # Sort the extracted elements\n sorted_third_elements = sorted(third_elements)\n \n # Create a new list to store the result\n result = l[:]\n \n # Replace elements in the result list at indices divisible by three with sorted elements\n for i, value in enumerate(sorted_third_elements):\n result[i * 3] = value\n \n return result", "matching_cluster_idx": 8}, {"solution": "from typing import List\nimport doctest\ndef sort_third(l: List[int]) -> List[int]:\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indices that are not divisible by three, while its values at the indices that are divisible by three are equal\n to the values of the corresponding indices of l, but sorted.\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n # Extract elements at indices divisible by three\n divisible_by_three = [l[i] for i in range(len(l)) if i % 3 == 0]\n # Sort these elements\n sorted_third = sorted(divisible_by_three)\n # Create a new list to store the result\n result = l[:]\n # Replace elements at indices divisible by three with sorted elements\n for i, value in enumerate(sorted_third):\n result[i * 3] = value\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(lst):\n \"\"\"\n This function takes a list and returns a new list where elements at indices divisible by three are sorted.\n Other elements remain unchanged.\n \n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n # Extract elements at indices divisible by three\n elements_to_sort = [lst[i] for i in range(len(lst)) if i % 3 == 0]\n # Sort the extracted elements\n sorted_elements = sorted(elements_to_sort)\n # Create a new list with sorted elements placed back at the correct positions\n result_list = lst[:]\n for i, value in enumerate(sorted_elements):\n result_list[i * 3] = value\n return result_list", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n # Create a copy of the list to modify\n sorted_list = l[:]\n # Extract elements at indices divisible by three\n elements_to_sort = [sorted_list[i] for i in range(0, len(sorted_list), 3)]\n # Sort these elements\n elements_to_sort.sort()\n # Replace the original elements with the sorted ones\n for i, value in enumerate(elements_to_sort):\n sorted_list[i * 3] = value\n return sorted_list", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n # Extract elements at indices divisible by three\n elements_to_sort = [l[i] for i in range(len(l)) if i % 3 == 0]\n # Sort these elements\n elements_to_sort.sort()\n # Create a new list where sorted elements replace original elements at divisible by three indices\n result = l[:]\n for i, value in enumerate(elements_to_sort):\n result[i * 3] = value\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n # Extract elements at indices divisible by three\n third_elements = [l[i] for i in range(0, len(l), 3)]\n # Sort the extracted elements\n third_elements.sort()\n \n # Create a copy of the original list to modify\n l_copy = l[:]\n # Replace elements at indices divisible by three with sorted ones\n for i, val in enumerate(third_elements):\n l_copy[i * 3] = val\n \n return l_copy", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"\n This function takes a list l and returns a list l' such that\n l' is identical to l in the indices that are not divisible by three, while its values at the indices that are divisible by three are equal\n to the values of the corresponding indices of l, but sorted.\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n # Extract elements at indices divisible by three\n to_sort = [l[i] for i in range(len(l)) if i % 3 == 0]\n # Sort these elements\n to_sort.sort()\n # Create a new list to store the result\n l_prime = l[:]\n # Replace elements at indices divisible by three with the sorted values\n for i, value in enumerate(to_sort):\n l_prime[i * 3] = value\n return l_prime", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list) -> list:\n # Extract elements at indices divisible by three\n divisible_by_three = [l[i] for i in range(len(l)) if i % 3 == 0]\n # Sort the extracted elements\n divisible_by_three.sort()\n # Replace the original elements with sorted ones at the same indices\n result = l[:]\n for i, value in enumerate(divisible_by_three):\n result[i * 3] = value\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n l_prime = l[:]\n l_div_by_three = [l[i] for i in range(len(l)) if i % 3 == 0]\n l_div_by_three.sort()\n for i, val in enumerate(l_div_by_three):\n l_prime[i * 3] = val\n return l_prime", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n # Extract elements at indices divisible by three\n elements_to_sort = [l[i] for i in range(len(l)) if i % 3 == 0]\n # Sort these elements\n sorted_elements = sorted(elements_to_sort)\n \n # Create a copy of the original list to modify\n result = l[:]\n # Replace elements at indices divisible by three with sorted elements\n for i, value in enumerate(sorted_elements):\n result[i * 3] = value\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indices that are not divisible by three, while its values at the indices that are divisible by three are equal\n to the values of the corresponding indices of l, but sorted.\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n # Extract elements at indices divisible by three\n indices_div_by_three = [i for i, x in enumerate(l) if i % 3 == 0]\n values_div_by_three = [l[i] for i in indices_div_by_three]\n \n # Sort the extracted values\n sorted_values = sorted(values_div_by_three)\n \n # Create a new list to store the result\n result = l[:]\n \n # Replace elements at indices divisible by three with sorted values\n for i, value in zip(indices_div_by_three, sorted_values):\n result[i] = value\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indices that are not divisible by three, while its values at the indices that are divisible by three are equal\n to the values of the corresponding indices of l, but sorted.\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n # Extract elements at indices divisible by three\n divisible_by_three = [l[i] for i in range(len(l)) if i % 3 == 0]\n # Sort these elements\n divisible_by_three.sort()\n \n # Create a new list to store the result\n result = l[:]\n # Replace elements at indices divisible by three with sorted values\n for i, value in enumerate(divisible_by_three):\n result[i * 3] = value\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n sorted_thirds = sorted(l[i] for i in range(len(l)) if i % 3 == 0)\n result = []\n sorted_index = 0\n for i in range(len(l)):\n if i % 3 == 0:\n result.append(sorted_thirds[sorted_index])\n sorted_index += 1\n else:\n result.append(l[i])\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n # Extract elements at indices divisible by three\n third_elements = [l[i] for i in range(len(l)) if i % 3 == 0]\n # Sort these elements\n third_elements.sort()\n \n # Create a new list to store the result\n result = []\n # Iterator for sorted elements\n third_iter = iter(third_elements)\n \n for i in range(len(l)):\n if i % 3 == 0:\n # Append from sorted elements\n result.append(next(third_iter))\n else:\n # Append the original element\n result.append(l[i])\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list) -> list:\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n\n Args:\n l (list): The input list of integers.\n\n Returns:\n list: A new list where elements at indices divisible by three are sorted, while other elements remain unchanged.\n\n Examples:\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n # Extract elements at indices divisible by three\n to_sort = [l[i] for i in range(len(l)) if i % 3 == 0]\n # Sort the extracted elements\n to_sort.sort()\n # Create a new list with sorted elements at the correct positions\n result = [to_sort.pop(0) if i % 3 == 0 else l[i] for i in range(len(l))]\n return result", "matching_cluster_idx": 6}, {"solution": "def sort_third(l: list) -> list:\n \"\"\"\n Sorts elements at indexes that are divisible by three in the given list.\n Args:\n l: A list of integers.\n \n Returns:\n A list of integers with elements at indexes divisible by three sorted.\n \n Examples:\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n # Extract elements at indices divisible by three\n divisible_by_three = [l[i] for i in range(len(l)) if i % 3 == 0]\n # Sort these specific elements\n divisible_by_three_sorted = sorted(divisible_by_three)\n \n # Create a new list where sorted elements are placed back at their original positions\n result = l[:]\n sorted_index = 0\n for i in range(len(result)):\n if i % 3 == 0:\n result[i] = divisible_by_three_sorted[sorted_index]\n sorted_index += 1\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(lst):\n \"\"\"\n This function takes a list lst and returns a list lst' such that\n lst' is identical to lst in the indices that are not divisible by three, while its values at the indices that are divisible by three\n are equal to the values of the corresponding indices of lst, but sorted.\n \n Args:\n lst (list): The input list to be modified.\n \n Returns:\n list: The modified list with elements at indices divisible by three sorted.\n \n Examples:\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n \n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n # Extract elements at indices divisible by three\n elements_to_sort = [lst[i] for i in range(len(lst)) if i % 3 == 0]\n \n # Sort these elements\n elements_to_sort.sort()\n \n # Create a copy of the original list to modify\n sorted_list = lst[:]\n \n # Replace elements at indices divisible by three with sorted elements\n for i, value in enumerate(elements_to_sort):\n sorted_list[i * 3] = value\n \n return sorted_list", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n sorted_indices = [i for i in range(len(l)) if i % 3 == 0]\n values_at_sorted_indices = [l[i] for i in sorted_indices]\n sorted_values = sorted(values_at_sorted_indices)\n \n result = l[:]\n for i, value in zip(sorted_indices, sorted_values):\n result[i] = value\n \n return result", "matching_cluster_idx": 8}]}, "HumanEval/34": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n # Convert the list to a set to remove duplicates, then convert back to a list\n unique_elements = list(set(l))\n # Sort the list before returning\n unique_elements.sort()\n return unique_elements", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n unique_elements = list(set(l)) # Convert list to set to remove duplicates\n unique_elements.sort() # Sort the list\n return unique_elements", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n # Convert the list to a set to remove duplicates, then convert back to a list and sort it\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list) -> list:\n \"\"\"\n Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"\n Return sorted unique elements in a list.\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n # Convert the list to a set to remove duplicates, then convert it back to a list\n unique_elements = list(set(l))\n # Sort the list before returning\n unique_elements.sort()\n return unique_elements", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n # Convert list to a set to remove duplicates, then convert back to a sorted list\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n # Convert the list to a set to remove duplicates\n unique_elements = set(l)\n # Convert the set back to a list and sort it\n sorted_unique_list = sorted(unique_elements)\n return sorted_unique_list", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n # Convert the list to a set to remove duplicates, then sort the set and return\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n # Convert the list to a set to remove duplicates, then sort the result\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n\n Args:\n l (list): A list of elements.\n\n Returns:\n list: A sorted list of unique elements from the input list.\n\n Examples:\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n # Convert the list to a set to remove duplicates, then convert back to a list\n unique_elements = list(set(l))\n # Sort the list and return\n return sorted(unique_elements)", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n # Convert the list to a set to remove duplicates, then back to a sorted list\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n unique_elements = list(set(l))\n unique_elements.sort()\n return unique_elements", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n unique_elements = list(set(l))\n unique_elements.sort()\n return unique_elements", "matching_cluster_idx": 4}]}, "HumanEval/36": {"dps": 96.77419354838709, "dps_norm": 71.42857142857143, "pass@1": 87.0, "profiled": [{"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"\n Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"\n Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n count = 0\n for i in range(1, n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int):\n # Initialize a counter to keep track of the occurrences of the digit '7'\n count = 0\n \n # Iterate through numbers from 1 to n-1 (exclusive)\n for i in range(1, n):\n # Check if the current number is divisible by 11 or 13\n if i % 11 == 0 or i % 13 == 0:\n # Convert the number to a string to count occurrences of '7'\n count += str(i).count('7')\n \n # Return the total count of '7's found\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"\n Count how many times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n \n Parameters:\n n (int): The upper limit (exclusive) to search for numbers divisible by 11 or 13.\n \n Returns:\n int: The total count of digit 7 appearances.\n \"\"\"\n count = 0\n # Iterate through all numbers less than n\n for i in range(1, n):\n # Check if the number is divisible by 11 or 13\n if i % 11 == 0 or i % 13 == 0:\n # Convert the number to string and count the '7's\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n # Initialize a counter for the occurrences of the digit 7\n count_of_sevens = 0\n \n # Iterate through all numbers less than n\n for i in range(1, n):\n # Check if the number is divisible by 11 or 13\n if i % 11 == 0 or i % 13 == 0:\n # Convert the number to a string and count the occurrences of '7'\n count_of_sevens += str(i).count('7')\n \n # Return the total count of the digit 7\n return count_of_sevens", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n for i in range(1, n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n\n Args:\n n (int): The upper limit (exclusive) to search for numbers divisible by 11 or 13 containing the digit 7.\n\n Returns:\n int: The count of times the digit 7 appears in numbers less than n divisible by 11 or 13.\n\n Examples:\n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n for i in range(1, n):\n if (i % 11 == 0 or i % 13 == 0) and '7' in str(i):\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n\n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"\n Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n \n :param n: An integer representing the upper limit (exclusive) for checking numbers.\n :return: The count of digit 7 appearances in numbers less than n divisible by 11 or 13.\n \n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int):\n count = 0\n for i in range(1, n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int):\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n for i in range(1, n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n count = 0\n for i in range(1, n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}]}, "HumanEval/37": {"dps": 95.43371522094927, "dps_norm": 91.0, "pass@1": 100.0, "profiled": [{"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Extract even-indexed elements and sort them\n even_elements = sorted(l[::2])\n # Create a new list to store the result\n result = l[:]\n # Replace even-indexed elements in the result list with sorted elements\n result[::2] = even_elements\n return result", "matching_cluster_idx": 9}, {"solution": "def sort_even(l: list):\n \"\"\"\n This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indices, while its values at the even indices are equal\n to the values of the even indices of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Extract elements at even indices\n even_elements = [l[i] for i in range(len(l)) if i % 2 == 0]\n # Sort the extracted elements\n even_elements.sort()\n # Create a new list to store the result\n result = l[:]\n # Replace elements at even indices with sorted elements\n for i, value in enumerate(even_elements):\n result[2 * i] = value\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Extract elements at even indices\n even_elements = [l[i] for i in range(0, len(l), 2)]\n # Sort the extracted elements\n even_elements.sort()\n # Create a new list to store the result\n l_prime = l[:]\n # Replace elements at even indices in the new list with sorted elements\n for i, value in enumerate(even_elements):\n l_prime[2*i] = value\n return l_prime", "matching_cluster_idx": 8}, {"solution": "from typing import List\ndef sort_even(l: List[int]) -> List[int]:\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Extract even-indexed elements and sort them\n even_elements = sorted(l[::2])\n \n # Create a copy of the original list to modify\n result = l[:]\n \n # Replace even-indexed elements in the result list with sorted values\n for i, value in enumerate(even_elements):\n result[2 * i] = value\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n # Extract the elements at even indices\n even_elements = [l[i] for i in range(len(l)) if i % 2 == 0]\n # Sort the extracted elements\n even_elements.sort()\n # Create a new list to store the result\n result = []\n even_index = 0\n # Iterate over the original list\n for i in range(len(l)):\n # If the index is even, insert the sorted element\n if i % 2 == 0:\n result.append(even_elements[even_index])\n even_index += 1\n else:\n # If the index is odd, keep the original element\n result.append(l[i])\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n even_indices_values = sorted(l[i] for i in range(0, len(l), 2))\n l_prime = l[:]\n even_index = 0\n for i in range(0, len(l), 2):\n l_prime[i] = even_indices_values[even_index]\n even_index += 1\n return l_prime", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Extract elements at even indices\n even_elements = [l[i] for i in range(0, len(l), 2)]\n # Sort the extracted elements\n even_elements.sort()\n # Create a new list to store the result\n result = []\n even_index = 0\n # Iterate over the original list\n for i in range(len(l)):\n if i % 2 == 0:\n # Replace element at even index with sorted element\n result.append(even_elements[even_index])\n even_index += 1\n else:\n # Keep element at odd index unchanged\n result.append(l[i])\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n # Extract elements at even indices and sort them\n even_elements = sorted(l[::2])\n # Iterate over the list and replace elements at even indices with sorted ones\n for i, value in enumerate(even_elements):\n l[i * 2] = value\n return l", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"\n This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Extract elements at even indices\n even_elements = l[::2]\n # Sort the extracted elements\n even_elements.sort()\n \n # Create a new list to store the result\n result = l[:]\n # Replace elements at even indices with sorted elements\n result[::2] = even_elements\n \n return result", "matching_cluster_idx": 9}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Extract the elements at even indices\n even_elements = [l[i] for i in range(0, len(l), 2)]\n \n # Sort the extracted elements\n even_elements_sorted = sorted(even_elements)\n \n # Create a new list to store the result\n result = l[:]\n \n # Replace the elements at even indices with the sorted ones\n j = 0\n for i in range(0, len(result), 2):\n result[i] = even_elements_sorted[j]\n j += 1\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n \"\"\"\n # Extract even-indexed elements and sort them\n even_elements = sorted([l[i] for i in range(len(l)) if i % 2 == 0])\n \n # Reconstruct the list with sorted even-indexed elements and original odd-indexed elements\n result = [even_elements[i // 2] if i % 2 == 0 else l[i] for i in range(len(l))]\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list) -> list:\n # Extract elements at even indices\n even_elements = [l[i] for i in range(0, len(l), 2)]\n # Sort the extracted elements\n even_elements.sort()\n # Create a new list to store the result\n result = l[:]\n # Replace elements at even indices with sorted elements\n for i, value in enumerate(even_elements):\n result[2 * i] = value\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indices, while its values at the even indices are equal\n to the values of the even indices of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Extract elements at even indices\n even_indices_elements = [l[i] for i in range(len(l)) if i % 2 == 0]\n # Sort the extracted elements\n even_indices_elements.sort()\n \n # Create a new list with the sorted even indices elements\n l_prime = l.copy()\n even_index = 0\n for i in range(len(l_prime)):\n if i % 2 == 0:\n l_prime[i] = even_indices_elements[even_index]\n even_index += 1\n \n return l_prime", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Extract elements at even indices\n even_elements = [l[i] for i in range(0, len(l), 2)]\n \n # Sort the extracted elements\n even_elements_sorted = sorted(even_elements)\n \n # Create a copy of the original list to modify\n result = l[:]\n \n # Replace elements at even indices with sorted values\n result[::2] = even_elements_sorted\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Extract elements at even indices\n even_elements = [l[i] for i in range(len(l)) if i % 2 == 0]\n # Sort the extracted elements\n even_elements.sort()\n \n # Create a new list to store the result\n l_prime = l.copy()\n # Replace elements at even indices with sorted elements\n even_index = 0\n for i in range(len(l_prime)):\n if i % 2 == 0:\n l_prime[i] = even_elements[even_index]\n even_index += 1\n \n return l_prime", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list) -> list:\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Extract elements at even indices and sort them\n even_elements = sorted(l[i] for i in range(0, len(l), 2))\n \n # Create a new list to store the result\n result = []\n \n # Iterate over the original list and construct the result list\n even_index = 0\n for i in range(len(l)):\n if i % 2 == 0:\n # Append sorted even elements\n result.append(even_elements[even_index])\n even_index += 1\n else:\n # Append elements from the original list at odd indices\n result.append(l[i])\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list) -> list:\n # Extract elements at even indices\n even_indices_elements = [l[i] for i in range(len(l)) if i % 2 == 0]\n # Sort the extracted elements\n even_indices_elements.sort()\n \n # Create a new list to store the result\n l_prime = l[:]\n # Replace elements at even indices with sorted elements\n for i, value in enumerate(even_indices_elements):\n l_prime[i * 2] = value\n \n return l_prime", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n # Extract the values at even indices\n even_values = [l[i] for i in range(len(l)) if i % 2 == 0]\n # Sort these values\n even_values.sort()\n \n # Create a new list to hold the result\n l_prime = l[:]\n # Replace the values at even indices in the result list with the sorted values\n for i, value in enumerate(even_values):\n l_prime[i * 2] = value\n \n return l_prime", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list) -> list:\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n even_indices_values = sorted(l[i] for i in range(0, len(l), 2))\n sorted_list = l[:]\n for i, value in enumerate(even_indices_values):\n sorted_list[2 * i] = value\n return sorted_list", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indices, while its values at the even indices are equal\n to the values of the even indices of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n even_indices_values = sorted(l[::2])\n l_prime = l[:]\n even_index = 0\n for i in range(0, len(l), 2):\n l_prime[i] = even_indices_values[even_index]\n even_index += 1\n return l_prime", "matching_cluster_idx": 8}]}, "HumanEval/49": {"dps": 93.88235294117646, "dps_norm": 98.0, "pass@1": 77.0, "profiled": [{"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n # Calculate 2^n using the built-in pow function which is optimized for this purpose\n power_result = pow(2, n, p)\n \n # Return the result modulo p\n return power_result % p", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"\n Return 2^n modulo p (be aware of numerics).\n\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n # Calculate 2^n\n power_result = 2 ** n\n \n # Calculate 2^n modulo p\n mod_result = power_result % p\n \n return mod_result", "matching_cluster_idx": 3}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\n \"\"\"\n # Calculate 2^n and then take modulo p\n result = pow(2, n, p)\n return result", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n # Using Python's built-in pow function for modular exponentiation\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\n \"\"\"\n # Using Python's built-in pow function with three arguments for efficient calculation\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"\n Return 2^n modulo p (be aware of numerics).\n \n Args:\n n (int): The exponent to raise 2 by.\n p (int): The modulo value.\n \n Returns:\n int: The result of (2^n) % p.\n \n Examples:\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n result = pow(2, n, p) # Utilizing Python's built-in pow function for efficient calculation\n return result", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\n \n Args:\n n (int): The exponent to raise 2 to.\n p (int): The modulus.\n\n Returns:\n int: The result of (2^n) % p.\n\n Examples:\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n # Calculate 2^n using the pow function with three arguments for efficiency\n # This also handles large exponents more gracefully by using modulo during exponentiation\n result = pow(2, n, p)\n return result", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n # Calculate 2^n and then take modulo p\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n # Calculate 2^n % p using the built-in pow function which is efficient\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n # Calculate 2^n modulo p using Python's built-in pow function with three arguments for efficiency\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\n \"\"\"\n # Calculate 2^n\n result = 2 ** n\n # Compute result modulo p\n return result % p", "matching_cluster_idx": 3}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\n \n Args:\n n (int): The exponent to raise 2 by.\n p (int): The modulus.\n \n Returns:\n int: The result of 2^n mod p.\n \n Examples:\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n # Calculate 2^n modulo p using Python's built-in pow function with three arguments\n result = pow(2, n, p)\n return result", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"\n Return 2^n modulo p (be aware of numerics).\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n # Use Python's built-in pow function to compute (2^n) % p efficiently\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"\n Return 2^n modulo p (be aware of numerics).\n\n The function uses Python's built-in pow function with three arguments\n for efficient computation of power modulo, which is more efficient\n and numerically stable than manually calculating 2^n and then taking the modulo.\n\n Args:\n n (int): The exponent to which 2 is raised.\n p (int): The modulus.\n\n Returns:\n int: The result of (2^n) % p.\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}]}, "HumanEval/51": {"dps": 91.42512077294685, "dps_norm": 72.5, "pass@1": 100.0, "profiled": [{"solution": "import re\ndef remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n # Define a regular expression pattern to match vowels both lowercase and uppercase\n vowel_pattern = re.compile('[aeiouAEIOU]')\n \n # Use the sub() method to replace all occurrences of the pattern with an empty string\n return vowel_pattern.sub('', text)", "matching_cluster_idx": 1}, {"solution": "def remove_vowels(text):\n # Define a string containing all vowels (both lowercase and uppercase)\n vowels = 'aeiouAEIOU'\n # Use a list comprehension to filter out vowels from the text\n # and join the list back into a string\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n vowels = 'aeiouAEIOU'\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n \"\"\"\n # Define a string containing all vowels in both lowercase and uppercase\n vowels = \"aeiouAEIOU\"\n # Use a list comprehension to filter out the vowels and join the result to form a new string\n result = ''.join([char for char in text if char not in vowels])\n return result", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n # Define a string of vowels including both uppercase and lowercase\n vowels = 'aeiouAEIOU'\n # Use a generator expression to filter out vowels and join the result back into a string\n return ''.join(char for char in text if char not in vowels)", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes a string and returns the string without vowels.\n \"\"\"\n vowels = \"aeiouAEIOU\"\n return \"\".join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes a string and returns a string without vowels.\n \"\"\"\n vowels = 'aeiouAEIOU'\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes a string and returns a string without vowels.\n \"\"\"\n # Define a string of vowels\n vowels = \"aeiouAEIOU\"\n # Use list comprehension to filter out vowels and join the result to form the new string\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n # Define a set of vowels for quick lookup\n vowels = set('aeiouAEIOU')\n # Use a list comprehension to filter out vowels and join the result into a string\n return ''.join(char for char in text if char not in vowels)", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n \"\"\"\n vowels = \"aeiouAEIOU\"\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n vowels = 'aeiouAEIOU'\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes a string and returns the string without vowels.\n \"\"\"\n # Define a string containing all vowels in both lowercase and uppercase\n vowels = 'aeiouAEIOU'\n # Use a generator expression to filter out vowels and join the result to form the new string\n return ''.join(char for char in text if char not in vowels)", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n # Define a string containing all vowel characters in both lower and upper case\n vowels = \"aeiouAEIOU\"\n # Use a list comprehension to filter out vowels and join the result back into a string\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n \"\"\"\n # Define a string of vowels including both lowercase and uppercase\n vowels = 'aeiouAEIOU'\n # Use a list comprehension to filter out vowels and join the result back into a string\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n \"\"\"\n vowels = \"aeiouAEIOU\"\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n # Define a set of vowels for quick lookup\n vowels = set('aeiouAEIOU')\n \n # Use a list comprehension to filter out vowels and join the result to form the new string\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n \"\"\"\n vowels = \"aeiouAEIOU\"\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n vowels = \"aeiouAEIOU\"\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = 'aeiouAEIOU'\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n vowels = \"aeiouAEIOU\"\n result = ''.join([char for char in text if char not in vowels])\n return result", "matching_cluster_idx": 5}]}, "HumanEval/54": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 87.0, "profiled": [{"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \n Args:\n s0 (str): The first string to compare.\n s1 (str): The second string to compare.\n \n Returns:\n bool: True if both strings have the same characters, False otherwise.\n \"\"\"\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "from typing import *\nfrom collections import *\ndef same_chars(s0: str, s1: str) -> bool:\n # Create sets from the characters of both strings\n set_s0 = set(s0)\n set_s1 = set(s1)\n \n # Check if the sets are equal\n return set_s0 == set_s1", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \"\"\"\n # Remove duplicates by converting the strings to sets\n set_s0 = set(s0)\n set_s1 = set(s1)\n \n # Compare the sets to check if they have the same elements\n return set_s0 == set_s1", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \"\"\"\n # Convert both strings to sets of characters to remove duplicates\n # and compare them for equality\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \n :param s0: First word to compare.\n :param s1: Second word to compare.\n :return: True if both words have the same characters, False otherwise.\n \"\"\"\n # Using set to compare unique characters in both strings\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n\n Args:\n s0 (str): The first word to compare.\n s1 (str): The second word to compare.\n\n Returns:\n bool: True if both words have the same characters, False otherwise.\n \"\"\"\n # Use set to compare unique characters in both strings\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \n Args:\n s0 (str): The first string to compare.\n s1 (str): The second string to compare.\n \n Returns:\n bool: True if both strings contain the same characters, False otherwise.\n \"\"\"\n # Create sets from both strings to remove duplicate characters and compare\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \"\"\"\n # Convert both strings to sets of characters and compare\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \"\"\"\n # Use set to remove duplicate characters and compare the length of the resulting sets\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str):\n \"\"\"\n Check if two words have the same characters.\n \"\"\"\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \n :param s0: First string to compare\n :param s1: Second string to compare\n :return: True if both strings have the same characters, False otherwise\n \"\"\"\n # Convert both strings to sets and compare\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \"\"\"\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \n Args:\n s0 (str): The first word to compare.\n s1 (str): The second word to compare.\n\n Returns:\n bool: True if both words have the same characters, False otherwise.\n \"\"\"\n # Convert both strings to sets to remove duplicates and compare\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str):\n \"\"\"\n Check if two words have the same characters.\n \"\"\"\n # Convert both strings to sets of characters and compare\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n\n Args:\n s0 (str): The first word.\n s1 (str): The second word.\n\n Returns:\n bool: True if both words have the same characters, False otherwise.\n \"\"\"\n # Use set to remove duplicates and compare\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \"\"\"\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')\n True\n >>> same_chars('abcd', 'dddddddabc')\n True\n >>> same_chars('dddddddabc', 'abcd')\n True\n >>> same_chars('eabcd', 'dddddddabc')\n False\n >>> same_chars('abcd', 'dddddddabce')\n False\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')\n False\n \"\"\"\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \"\"\"\n # Use set to remove duplicates and compare the sorted lists of characters from both strings\n return sorted(set(s0)) == sorted(set(s1))", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \"\"\"\n # Convert both strings to sets to remove duplicates and compare\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \"\"\"\n return set(s0) == set(s1)", "matching_cluster_idx": 6}]}, "HumanEval/58": {"dps": 89.11417322834646, "dps_norm": 82.5, "pass@1": 100.0, "profiled": [{"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n # Use set intersection to find common elements and convert the result to a sorted list\n return sorted(list(set(l1) & set(l2)))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"\n Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n # Convert both lists to sets to remove duplicates and then find common elements\n common_elements = set(l1) & set(l2)\n # Convert the set of common elements back to a sorted list\n return sorted(list(common_elements))", "matching_cluster_idx": 4}, {"solution": "from typing import *\nfrom collections import *\ndef common(l1: list, l2: list) -> list:\n \"\"\"Return sorted unique common elements for two lists.\n \n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n # Find the intersection of the two sets created from the lists\n common_elements = set(l1).intersection(set(l2))\n # Convert the set to a sorted list and return\n return sorted(list(common_elements))", "matching_cluster_idx": 4}, {"solution": "from typing import *\nfrom collections import *\ndef common(l1: list, l2: list):\n \"\"\"\n Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n # Convert both lists to sets to remove duplicates and find the intersection\n common_elements = set(l1) & set(l2)\n # Convert the set back to a sorted list\n return sorted(list(common_elements))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list) -> list:\n \"\"\"Return sorted unique common elements for two lists.\n\n Parameters:\n l1 (list): The first input list.\n l2 (list): The second input list.\n\n Returns:\n list: A sorted list of unique common elements.\n\n Examples:\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n\n \"\"\"\n # Convert lists to sets to find the unique common elements\n common_set = set(l1).intersection(l2)\n # Return the sorted list of the common elements\n return sorted(common_set)", "matching_cluster_idx": 5}, {"solution": "from typing import List\nfrom itertools import chain\ndef common(l1: List[int], l2: List[int]) -> List[int]:\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n common_elements = set(chain(l1, l2)) # Combine both lists into one set\n common_elements &= set(l1) & set(l2) # Find the intersection of both sets\n return sorted(list(common_elements)) # Return sorted list of common elements", "matching_cluster_idx": 2}, {"solution": "def common(l1: list, l2: list):\n \"\"\"\n Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n\n \"\"\"\n # Use set intersection to find common elements and then sort the result\n result = sorted(set(l1) & set(l2))\n return result", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n # Convert both lists to sets to find the intersection\n common_elements = set(l1) & set(l2)\n \n # Convert the set back to a sorted list\n return sorted(list(common_elements))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n # Convert both lists to sets to remove duplicates and allow for efficient intersection\n set1 = set(l1)\n set2 = set(l2)\n \n # Find the intersection of the two sets\n common_elements = set1.intersection(set2)\n \n # Convert the set to a sorted list\n sorted_common_elements = sorted(common_elements)\n \n return sorted_common_elements", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"\n Return sorted unique common elements for two lists.\n\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n\n \"\"\"\n # Convert both lists to sets to remove duplicates and then find the intersection\n common_elements = set(l1) & set(l2)\n # Return the sorted list of common elements\n return sorted(list(common_elements))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n # Use set intersection to find common elements and then sort them\n result = sorted(list(set(l1) & set(l2)))\n return result", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n # Use set intersection to find common elements\n common_elements = set(l1) & set(l2)\n # Return sorted list of unique common elements\n return sorted(common_elements)", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"\n Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n\n \"\"\"\n # Convert both lists to sets to find the common elements and remove duplicates\n common_elements = set(l1) & set(l2)\n # Sort the common elements and return as a list\n return sorted(list(common_elements))", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef common(l1: List[int], l2: List[int]) -> List[int]:\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n # Convert lists to sets to find common elements and remove duplicates\n common_elements = set(l1) & set(l2)\n # Return sorted list of common elements\n return sorted(list(common_elements))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n # Convert both lists to sets to remove duplicates and then find the intersection\n common_elements = set(l1) & set(l2)\n # Return the sorted list of common elements\n return sorted(list(common_elements))", "matching_cluster_idx": 4}, {"solution": "from typing import *\nfrom collections import *\ndef common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n # Convert both lists to sets to remove duplicates and find common elements\n common_elements = set(l1).intersection(set(l2))\n # Return the sorted list of common elements\n return sorted(common_elements)", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n # Use set intersection to find common elements and then sort them\n common_elements = sorted(set(l1) & set(l2))\n return common_elements", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n\n \"\"\"\n # Convert both lists to sets to remove duplicates and find common elements\n common_elements = set(l1) & set(l2)\n # Sort the common elements and return as a list\n return sorted(list(common_elements))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n\n \"\"\"\n # Convert both lists to sets to remove duplicates and then find the intersection\n common_elements = set(l1) & set(l2)\n # Convert the set back to a list and sort it\n return sorted(list(common_elements))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list) -> list:\n \"\"\"\n Return sorted unique common elements for two lists.\n\n Args:\n l1 (list): The first list of integers.\n l2 (list): The second list of integers.\n\n Returns:\n list: A sorted list of unique elements that are common to both input lists.\n\n Examples:\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n # Convert lists to sets to find unique elements and common elements\n set1 = set(l1)\n set2 = set(l2)\n common_set = set1.intersection(set2)\n # Convert the set to a sorted list before returning\n return sorted(common_set)", "matching_cluster_idx": 4}]}, "HumanEval/59": {"dps": 95.57291666666667, "dps_norm": 96.66666666666667, "pass@1": 95.0, "profiled": [{"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n factor = 2\n while factor * factor <= n:\n if n % factor:\n factor += 1\n else:\n n //= factor\n return n", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n # Start with the smallest prime number\n factor = 2\n last_factor = 1\n \n # Divide n by 2 until it's odd\n while n % factor == 0:\n last_factor = factor\n n //= factor\n \n # Check for odd factors from 3 onwards\n factor = 3\n max_factor = int(n**0.5) + 1\n while factor <= max_factor:\n while n % factor == 0:\n last_factor = factor\n n //= factor\n max_factor = int(n**0.5) + 1\n factor += 2\n \n # If n is a prime number greater than 2\n if n > 2:\n last_factor = n\n \n return last_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"\n Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n\n # Initialize the largest prime factor\n largest_prime = -1\n\n # Divide n by 2 to remove all even factors\n while n % 2 == 0:\n largest_prime = 2\n n //= 2\n\n # n must be odd at this point, so we can skip even numbers in our loop\n for i in range(3, int(n**0.5) + 1, 2):\n # While i divides n, remove i and set largest_prime to i\n while n % i == 0:\n largest_prime = i\n n //= i\n\n # If n is a prime number greater than 2\n if n > 2:\n largest_prime = n\n\n return largest_prime", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n factor = 2\n while factor * factor <= n:\n if n % factor:\n factor += 1\n else:\n n //= factor\n return n", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n factor = 2\n last_factor = 1\n while factor * factor <= n:\n if n % factor:\n factor += 1\n else:\n n //= factor\n last_factor = factor\n if n > 1:\n last_factor = n\n return last_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n largest_prime = -1\n while n % 2 == 0:\n largest_prime = 2\n n //= 2\n\n factor = 3\n while factor * factor <= n:\n while n % factor == 0:\n largest_prime = factor\n n //= factor\n factor += 2\n\n if n > 2:\n largest_prime = n\n\n return largest_prime", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n factor = 2\n while factor * factor <= n:\n if n % factor:\n factor += 1\n else:\n n //= factor\n return n", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n\n factor = 2\n last_factor = 1\n while factor * factor <= n:\n if n % factor:\n factor += 1\n else:\n n //= factor\n last_factor = factor\n if n > 1:\n last_factor = n\n return last_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n # Start with the smallest prime number\n factor = 2\n last_factor = 1\n while n > 1:\n while n % factor == 0:\n last_factor = factor\n n //= factor\n factor += 1\n return last_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n # Start with the smallest prime number\n factor = 2\n while factor * factor <= n:\n if n % factor:\n factor += 1\n else:\n n //= factor\n return n", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n # Initialize the largest factor\n largest_factor = None\n \n # Divide n by 2 until it becomes odd\n while n % 2 == 0:\n largest_factor = 2\n n //= 2\n \n # Check for odd factors\n factor = 3\n while factor * factor <= n:\n while n % factor == 0:\n largest_factor = factor\n n //= factor\n factor += 2\n \n # If n becomes a prime number greater than 2\n if n > 2:\n largest_factor = n\n \n return largest_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n # Initialize the largest prime factor\n largest_prime = -1\n \n # Divide n by 2 to remove all even factors\n while n % 2 == 0:\n largest_prime = 2\n n //= 2\n \n # n must be odd at this point, so a skip of 2 (i += 2) can be used\n for i in range(3, int(n**0.5) + 1, 2):\n # While i divides n, remove i and set largest_prime to i\n while n % i == 0:\n largest_prime = i\n n //= i\n \n # If n is a prime number greater than 2\n if n > 2:\n largest_prime = n\n \n return largest_prime", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n\n Examples:\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n factor = 2\n last_factor = 1\n while factor * factor <= n:\n if n % factor:\n factor += 1\n else:\n last_factor = factor\n n //= factor\n if n > 1:\n last_factor = n\n return last_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n i = 2\n while i * i <= n:\n if n % i:\n i += 1\n else:\n n //= i\n return n", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n\n # Function to check if a number is prime\n def is_prime(num):\n if num <= 1:\n return False\n if num <= 3:\n return True\n if num % 2 == 0 or num % 3 == 0:\n return False\n i = 5\n while i * i <= num:\n if num % i == 0 or num % (i + 2) == 0:\n return False\n i += 6\n return True\n\n # Finding the largest prime factor\n largest_factor = 1\n for i in range(2, n + 1):\n if n % i == 0 and is_prime(i):\n largest_factor = max(largest_factor, i)\n return largest_factor", "matching_cluster_idx": 2}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n def prime_factors(n):\n i = 2\n factors = []\n while i * i <= n:\n if n % i:\n i += 1\n else:\n n //= i\n factors.append(i)\n if n > 1:\n factors.append(n)\n return factors\n \n return max(prime_factors(n))", "matching_cluster_idx": 8}, {"solution": "import math\ndef largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n largest_factor = None\n # Divide n by 2 to remove all even factors\n while n % 2 == 0:\n largest_factor = 2\n n = n // 2\n \n # n must be odd at this point, so we can skip one element (Note i = i + 2)\n for i in range(3, int(math.sqrt(n)) + 1, 2):\n while n % i == 0:\n largest_factor = i\n n = n // i\n \n # If n is a prime number greater than 2\n if n > 2:\n largest_factor = n\n \n return largest_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n # Initialize the largest prime factor\n largest_prime = -1\n\n # Divide n by 2 to remove all even factors\n while n % 2 == 0:\n largest_prime = 2\n n //= 2\n\n # n must be odd at this point, so a skip of 2 (i += 2) can be used\n factor = 3\n while factor * factor <= n:\n # While factor divides n, remove it and set largest_prime to factor\n while n % factor == 0:\n largest_prime = factor\n n //= factor\n factor += 2\n\n # If n is a prime number greater than 2\n if n > 2:\n largest_prime = n\n\n return largest_prime", "matching_cluster_idx": 8}, {"solution": "import math\ndef largest_prime_factor(n: int) -> int:\n \"\"\"\n Return the largest prime factor of n. Assume n > 1 and is not a prime.\n \n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n # Start with the smallest prime factor\n factor = 2\n last_factor = 1\n \n # Divide n by the smallest factor as long as possible\n while n % factor == 0:\n last_factor = factor\n n //= factor\n \n # Now n must be odd, start checking from 3 and step by 2\n for factor in range(3, int(math.sqrt(n)) + 1, 2):\n while n % factor == 0:\n last_factor = factor\n n //= factor\n \n # If n is now reduced to a prime number greater than 2\n if n > 2:\n last_factor = n\n \n return last_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n # Initialize the largest prime factor to the lowest possible value\n largest_prime = -1\n \n # Divide n by 2 to remove all even factors\n while n % 2 == 0:\n largest_prime = 2\n n //= 2\n \n # n must be odd at this point, so we can skip one element (Note i = i +2)\n for i in range(3, int(n**0.5) + 1, 2):\n # While i divides n, remove i and set largest_prime to i\n while n % i == 0:\n largest_prime = i\n n //= i\n \n # If n is a prime number greater than 2\n if n > 2:\n largest_prime = n\n \n return largest_prime", "matching_cluster_idx": 8}]}, "HumanEval/64": {"dps": 83.96103896103897, "dps_norm": 60.0, "pass@1": 78.0, "profiled": [{"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n # Convert the string to lowercase to handle case insensitivity\n s = s.lower()\n # Define the set of vowels\n vowels = set('aeiou')\n # Initialize the vowel count\n count = 0\n \n # Iterate over each character in the string\n for char in s:\n # Check if the character is a vowel\n if char in vowels:\n count += 1\n \n # Check if the last character is 'y'\n if s.endswith('y'):\n count += 1\n \n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = 'aeiou'\n count = sum(1 for char in s if char.lower() in vowels)\n if s.endswith('y') or s.endswith('Y'):\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n # Define the set of vowels\n vowels = set(\"aeiouAEIOU\")\n \n # Initialize the count of vowels\n count = 0\n \n # Iterate over each character in the string\n for char in s:\n # Check if the character is a vowel\n if char in vowels:\n count += 1\n \n # Check if the last character is 'y' or 'Y' and add to count if true\n if s.endswith('y') or s.endswith('Y'):\n count += 1\n \n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = \"aeiouAEIOU\"\n count = sum(1 for char in s if char in vowels)\n if s.endswith('y') or s.endswith('Y'):\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n # Define the set of vowels\n vowels = set(\"aeiouAEIOU\")\n # Initialize a counter for vowels\n count = 0\n # Iterate through each character in the string\n for char in s:\n # Check if the character is a vowel\n if char in vowels:\n count += 1\n # Check if the last character is 'y' or 'Y' and add to count if true\n if s.endswith('y') or s.endswith('Y'):\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n # Define the set of vowels\n vowels = {'a', 'e', 'i', 'o', 'u', 'A', 'E', 'I', 'O', 'U'}\n \n # Initialize the vowel count\n count = 0\n \n # Iterate through each character in the string\n for char in s:\n # Check if the character is a vowel\n if char in vowels:\n count += 1\n \n # Check if the last character is 'y' or 'Y' and consider it as a vowel\n if s.endswith('y') or s.endswith('Y'):\n count += 1\n \n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n # Convert the string to lowercase to make the function case-insensitive\n s = s.lower()\n # Define the set of vowels\n vowels = set('aeiou')\n # Initialize the count of vowels\n count = 0\n # Iterate over each character in the string\n for char in s:\n # Check if the character is a vowel\n if char in vowels:\n count += 1\n # Check if the last character is 'y'\n if s.endswith('y'):\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n # Convert the string to lowercase to simplify matching\n s = s.lower()\n # Define the set of vowels\n vowels = set('aeiou')\n # Initialize the count of vowels\n count = 0\n\n # Iterate through each character in the string\n for char in s:\n # Check if the character is a vowel\n if char in vowels:\n count += 1\n\n # Check if the last character is 'y'\n if s.endswith('y'):\n count += 1\n\n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n \"\"\"\n This function takes a string s and returns the count of vowels in it.\n Vowels are 'a', 'e', 'i', 'o', 'u', and 'y' if it is the last character.\n \"\"\"\n # Define the set of vowels\n vowels = {'a', 'e', 'i', 'o', 'u'}\n \n # Convert string to lowercase for uniformity\n s = s.lower()\n \n # Initialize count of vowels\n count = 0\n \n # Iterate through each character in the string\n for i, char in enumerate(s):\n if char in vowels:\n count += 1\n # Check for 'y' at the end of the word\n elif char == 'y' and i == len(s) - 1:\n count += 1\n \n return count", "matching_cluster_idx": 3}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n # Define the vowels including 'y' as a special case\n vowels = \"aeiouAEIOU\"\n # Initialize a counter for vowels\n count = 0\n\n # Check each character in the string\n for char in s:\n if char in vowels:\n count += 1\n # Check if 'y' is at the end and is not preceded by another vowel\n if s.endswith('y') or s.endswith('Y'):\n count += 1\n\n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n # Define the set of vowels including 'y' as a vowel only when it is at the end\n vowels = set('aeiouAEIOU')\n count = 0\n \n # Iterate over each character in the string\n for char in s:\n # Check if the character is a vowel\n if char in vowels:\n count += 1\n \n # Check if the last character is 'y' and consider it as a vowel\n if s.endswith('y') or s.endswith('Y'):\n count += 1\n \n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n # Define the set of vowels\n vowels = set('aeiouAEIOU')\n count = 0\n \n # Count each vowel in the string\n for char in s:\n if char in vowels:\n count += 1\n \n # Check if the last character is 'y' or 'Y'\n if s.endswith('y') or s.endswith('Y'):\n count += 1\n \n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n # Define the set of vowels, including 'y' at the end\n vowels = {'a', 'e', 'i', 'o', 'u'}\n # Convert the input string to lowercase to handle case insensitivity\n s = s.lower()\n # Initialize the count of vowels\n count = 0\n # Iterate over each character in the string\n for char in s:\n # Check if the character is a vowel\n if char in vowels:\n count += 1\n # Check if the last character is 'y'\n if s.endswith('y'):\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n \"\"\"\n Function to count the number of vowels in a given word.\n Vowels are 'a', 'e', 'i', 'o', 'u', and 'y' if it is at the end of the word.\n \"\"\"\n # Define the set of vowels\n vowels = set(\"aeiouAEIOU\")\n # Initialize a counter for vowels\n count = 0\n \n # Iterate over each character in the string\n for i, char in enumerate(s):\n # Check if the character is a vowel\n if char in vowels:\n count += 1\n # Check if 'y' is at the end and treat it as a vowel\n elif char == 'y' or char == 'Y':\n if i == len(s) - 1:\n count += 1\n \n # Return the total count of vowels\n return count", "matching_cluster_idx": 3}, {"solution": "def vowels_count(s):\n \"\"\"\n Counts the number of vowels in a given word.\n Vowels are 'a', 'e', 'i', 'o', 'u'.\n 'y' is considered a vowel only if it is the last character of the word.\n \"\"\"\n # Define a set of vowels for easy checking\n vowels = {'a', 'e', 'i', 'o', 'u'}\n \n # Convert the input string to lowercase to handle mixed cases\n s = s.lower()\n \n # Initialize a counter for vowels\n count = 0\n \n # Iterate through each character in the string\n for char in s:\n # If the character is a vowel, increment the count\n if char in vowels:\n count += 1\n \n # Check if the last character is 'y', and if so, increment the count\n if s.endswith('y'):\n count += 1\n \n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = \"aeiouAEIOU\"\n count = sum(1 for char in s if char in vowels)\n if s.endswith('y') or s.endswith('Y'):\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n # Define the set of vowels\n vowels = set('aeiouAEIOU')\n \n # Initialize the count of vowels\n count = 0\n \n # Iterate over each character in the string\n for char in s:\n # Check if the character is a vowel\n if char in vowels:\n count += 1\n \n # Check if the last character is 'y' or 'Y' and count it as a vowel\n if s.endswith('y') or s.endswith('Y'):\n count += 1\n \n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n # Define the set of vowels\n vowels = {'a', 'e', 'i', 'o', 'u', 'A', 'E', 'I', 'O', 'U'}\n \n # Initialize the count of vowels\n count = 0\n \n # Iterate over each character in the string\n for char in s:\n # Check if the character is a vowel\n if char in vowels:\n count += 1\n \n # Check if the last character is 'y' or 'Y', it should be considered a vowel if it's at the end\n if s.endswith('y') or s.endswith('Y'):\n count += 1\n \n # Return the total count of vowels\n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n # Define the set of vowels\n vowels = set(\"aeiouAEIOU\")\n # Initialize the count of vowels\n count = 0\n # Iterate over each character in the string\n for char in s:\n # If the character is a vowel, increment the count\n if char in vowels:\n count += 1\n # Check if the last character is 'y' or 'Y' and it's not the only character\n if s.endswith('y') or s.endswith('Y'):\n count += 1\n # Return the total count of vowels\n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n \"\"\"Count the number of vowels in a given word, considering 'y' as a vowel only if it is at the end of the word.\"\"\"\n vowels = set('aeiouAEIOU')\n count = sum(1 for char in s if char in vowels)\n if s.endswith('y') or s.endswith('Y'):\n count += 1\n return count", "matching_cluster_idx": 4}]}, "HumanEval/74": {"dps": 93.46341463414635, "dps_norm": 87.77777777777777, "pass@1": 91.0, "profiled": [{"solution": "def total_match(lst1, lst2):\n # Calculate the total number of characters in all strings of the first list\n total_chars_lst1 = sum(len(s) for s in lst1)\n # Calculate the total number of characters in all strings of the second list\n total_chars_lst2 = sum(len(s) for s in lst2)\n \n # Compare the total characters and return the list with fewer characters\n # If both lists have the same number of characters, return the first list\n return lst1 if total_chars_lst1 <= total_chars_lst2 else lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n def count_chars(lst):\n return sum(len(s) for s in lst)\n\n count1 = count_chars(lst1)\n count2 = count_chars(lst2)\n\n if count1 <= count2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n \"\"\"\n This function takes two lists of strings and returns the list with the lesser total number of characters.\n If both lists have the same total number of characters, it returns the first list.\n \n Parameters:\n lst1 (List[str]): The first list of strings.\n lst2 (List[str]): The second list of strings.\n \n Returns:\n List[str]: The list with the lesser total number of characters or the first list if they are equal.\n \"\"\"\n # Calculate the total number of characters in each list\n total_chars_lst1 = sum(len(s) for s in lst1)\n total_chars_lst2 = sum(len(s) for s in lst2)\n \n # Compare the total number of characters and return the appropriate list\n if total_chars_lst1 <= total_chars_lst2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n # Calculate the total number of characters in each list\n total_chars_lst1 = sum(len(s) for s in lst1)\n total_chars_lst2 = sum(len(s) for s in lst2)\n \n # Compare the totals and return the appropriate list\n if total_chars_lst1 < total_chars_lst2:\n return lst1\n elif total_chars_lst1 > total_chars_lst2:\n return lst2\n else:\n return lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n # Calculate the total number of characters in all strings of lst1 and lst2\n total_chars_lst1 = sum(len(s) for s in lst1)\n total_chars_lst2 = sum(len(s) for s in lst2)\n\n # Compare the total characters and return the list with fewer characters\n # If both have the same number of characters, return the first list\n if total_chars_lst1 <= total_chars_lst2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n # Calculate the total number of characters in each list\n total_chars_lst1 = sum(len(s) for s in lst1)\n total_chars_lst2 = sum(len(s) for s in lst2)\n \n # Compare the total characters and return the appropriate list\n if total_chars_lst1 < total_chars_lst2:\n return lst1\n elif total_chars_lst2 < total_chars_lst1:\n return lst2\n else:\n return lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n # Calculate the total number of characters in all strings of lst1\n total_chars_lst1 = sum(len(s) for s in lst1)\n # Calculate the total number of characters in all strings of lst2\n total_chars_lst2 = sum(len(s) for s in lst2)\n \n # Compare the total characters and return the appropriate list\n if total_chars_lst1 < total_chars_lst2:\n return lst1\n elif total_chars_lst2 < total_chars_lst1:\n return lst2\n else:\n return lst1", "matching_cluster_idx": 7}, {"solution": "from typing import *\nfrom collections import *\ndef total_match(lst1, lst2):\n # Calculate the total number of characters in all strings of each list\n total_chars_lst1 = sum(len(s) for s in lst1)\n total_chars_lst2 = sum(len(s) for s in lst2)\n \n # Compare the total number of characters and return the list with fewer characters\n if total_chars_lst1 <= total_chars_lst2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n def total_chars(lst):\n return sum(len(s) for s in lst)\n\n if total_chars(lst1) < total_chars(lst2):\n return lst1\n elif total_chars(lst1) > total_chars(lst2):\n return lst2\n else:\n return lst1", "matching_cluster_idx": 5}, {"solution": "def total_match(lst1, lst2):\n # Calculate total number of characters in each list\n total_chars_lst1 = sum(len(s) for s in lst1)\n total_chars_lst2 = sum(len(s) for s in lst2)\n \n # Compare total characters and return the list with fewer or equal characters\n if total_chars_lst1 <= total_chars_lst2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n \"\"\"\n Returns the list with a total number of characters in all strings less than the other list.\n Returns the first list if the total number of characters is the same in both lists.\n\n Parameters:\n lst1 (list of str): The first list of strings.\n lst2 (list of str): The second list of strings.\n\n Returns:\n list of str: The list with fewer total characters or the first list if they are equal.\n \"\"\"\n total_chars_lst1 = sum(len(s) for s in lst1)\n total_chars_lst2 = sum(len(s) for s in lst2)\n \n if total_chars_lst1 <= total_chars_lst2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n # Calculate the total number of characters in each list\n total_chars_lst1 = sum(len(s) for s in lst1)\n total_chars_lst2 = sum(len(s) for s in lst2)\n \n # Compare and return the list with fewer characters, or the first one if they are equal\n if total_chars_lst1 <= total_chars_lst2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n # Calculate the total number of characters in each list\n total_chars_lst1 = sum(len(s) for s in lst1)\n total_chars_lst2 = sum(len(s) for s in lst2)\n \n # Compare and return the appropriate list\n if total_chars_lst1 <= total_chars_lst2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n # Calculate the total number of characters in all strings of each list\n total_chars_lst1 = sum(len(s) for s in lst1)\n total_chars_lst2 = sum(len(s) for s in lst2)\n \n # Compare the total characters and return the list with fewer characters\n if total_chars_lst1 < total_chars_lst2:\n return lst1\n elif total_chars_lst2 < total_chars_lst1:\n return lst2\n else:\n # Return the first list if both have the same number of characters\n return lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n # Calculate total number of characters in all strings of lst1\n total_chars_lst1 = sum(len(s) for s in lst1)\n \n # Calculate total number of characters in all strings of lst2\n total_chars_lst2 = sum(len(s) for s in lst2)\n \n # Compare the total characters and return the list with fewer characters\n if total_chars_lst1 < total_chars_lst2:\n return lst1\n elif total_chars_lst1 > total_chars_lst2:\n return lst2\n else:\n return lst1 # Return the first list if they have the same total number of characters", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n # Calculate total number of characters in each list\n total_chars_lst1 = sum(len(s) for s in lst1)\n total_chars_lst2 = sum(len(s) for s in lst2)\n \n # Compare the total number of characters and return the appropriate list\n if total_chars_lst1 < total_chars_lst2:\n return lst1\n elif total_chars_lst1 > total_chars_lst2:\n return lst2\n else:\n return lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n # Calculate the total number of characters in all strings of lst1 and lst2\n total_chars_lst1 = sum(len(word) for word in lst1)\n total_chars_lst2 = sum(len(word) for word in lst2)\n \n # Compare the total characters and return the list with fewer characters\n # If both lists have the same number of characters, return the first list\n if total_chars_lst1 <= total_chars_lst2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n # Calculate total number of characters in each list\n total_chars_lst1 = sum(len(s) for s in lst1)\n total_chars_lst2 = sum(len(s) for s in lst2)\n \n # Compare and return the appropriate list\n if total_chars_lst1 <= total_chars_lst2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n # Calculate the total number of characters in all strings of each list\n total_chars_lst1 = sum(len(s) for s in lst1)\n total_chars_lst2 = sum(len(s) for s in lst2)\n \n # Compare the total characters and return the list with fewer characters or the first list if equal\n if total_chars_lst1 <= total_chars_lst2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n # Calculate the total number of characters in all strings of each list\n total_chars_lst1 = sum(len(s) for s in lst1)\n total_chars_lst2 = sum(len(s) for s in lst2)\n\n # Compare the total number of characters and return the appropriate list\n if total_chars_lst1 < total_chars_lst2:\n return lst1\n elif total_chars_lst2 < total_chars_lst1:\n return lst2\n else:\n return lst1", "matching_cluster_idx": 7}]}, "HumanEval/85": {"dps": 85.0, "dps_norm": 51.666666666666664, "pass@1": 100.0, "profiled": [{"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices.\n\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n # Initialize the sum to zero\n total = 0\n \n # Iterate over the list, considering only odd indices\n for i in range(1, len(lst), 2):\n # Check if the element at the current odd index is even\n if lst[i] % 2 == 0:\n # Add it to the total sum\n total += lst[i]\n \n # Return the final sum\n return total", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n return sum(x for i, x in enumerate(lst) if i % 2 == 1 and x % 2 == 0)", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices.\n\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n return sum(x for i, x in enumerate(lst) if i % 2 != 0 and x % 2 == 0)", "matching_cluster_idx": 2}, {"solution": "from typing import *\nfrom collections import *\ndef add(lst):\n \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices..\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n return sum(x for i, x in enumerate(lst) if i % 2 == 1 and x % 2 == 0)", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"\n Given a non-empty list of integers lst. add the even elements that are at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2\n \"\"\"\n return sum(x for i, x in enumerate(lst) if i % 2 == 1 and x % 2 == 0)", "matching_cluster_idx": 2}, {"solution": "from typing import *\nfrom collections import *\ndef add(lst):\n \"\"\"\n Given a non-empty list of integers lst. add the even elements that are at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2\n \"\"\"\n return sum(val for idx, val in enumerate(lst) if idx % 2 == 1 and val % 2 == 0)", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"\n Given a non-empty list of integers lst. add the even elements that are at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2\n \"\"\"\n return sum(val for idx, val in enumerate(lst) if idx % 2 != 0 and val % 2 == 0)", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"\n Given a non-empty list of integers lst. add the even elements that are at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2\n \"\"\"\n # Initialize the sum to 0\n total_sum = 0\n \n # Iterate over the list with index\n for index, value in enumerate(lst):\n # Check if the index is odd and the value is even\n if index % 2 != 0 and value % 2 == 0:\n total_sum += value\n \n return total_sum", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices..\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n return sum(x for i, x in enumerate(lst) if i % 2 == 1 and x % 2 == 0)", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"\n Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n # Initialize the sum of even elements at odd indices\n sum_even = 0\n \n # Iterate over the list using enumerate to get both index and value\n for index, value in enumerate(lst):\n # Check if the index is odd and the value is even\n if index % 2 != 0 and value % 2 == 0:\n # Add the value to the sum\n sum_even += value\n \n # Return the total sum of even elements at odd indices\n return sum_even", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices..\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n return sum(val for idx, val in enumerate(lst) if idx % 2 != 0 and val % 2 == 0)", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"\n Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2\n \"\"\"\n return sum(x for i, x in enumerate(lst) if i % 2 != 0 and x % 2 == 0)", "matching_cluster_idx": 2}, {"solution": "from typing import *\ndef add(lst):\n \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices.\n\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n return sum(x for i, x in enumerate(lst) if i % 2 == 1 and x % 2 == 0)", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices..\n\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n return sum(val for idx, val in enumerate(lst) if idx % 2 != 0 and val % 2 == 0)", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices..\n\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n # Initialize sum to store the result\n result = 0\n \n # Iterate over the list using enumerate to get both index and value\n for i, value in enumerate(lst):\n # Check if the index is odd and the value is even\n if i % 2 == 1 and value % 2 == 0:\n # Add the value to the result\n result += value\n \n # Return the final result\n return result", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n # Initialize the sum of even elements at odd indices\n total_sum = 0\n \n # Iterate through the list with both index and value\n for index, value in enumerate(lst):\n # Check if the index is odd and the value is even\n if index % 2 == 1 and value % 2 == 0:\n total_sum += value\n \n # Return the computed sum\n return total_sum", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2\n \"\"\"\n return sum(element for index, element in enumerate(lst) if index % 2 != 0 and element % 2 == 0)", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n # Initialize the sum to 0\n result = 0\n \n # Iterate through the list with index\n for i in range(1, len(lst), 2): # Start from index 1 and step by 2 to get odd indices\n if lst[i] % 2 == 0: # Check if the element is even\n result += lst[i] # Add the even element at odd index to the result\n \n return result", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices..\n\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n return sum(x for i, x in enumerate(lst) if i % 2 == 1 and x % 2 == 0)", "matching_cluster_idx": 2}, {"solution": "from typing import *\nfrom collections import *\ndef add(lst):\n \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices..\n\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n # Initialize the sum to 0\n total = 0\n \n # Iterate over the list with index\n for index, value in enumerate(lst):\n # Check if the index is odd and the value is even\n if index % 2 != 0 and value % 2 == 0:\n total += value\n \n return total", "matching_cluster_idx": 2}]}, "HumanEval/86": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 67.0, "profiled": [{"solution": "def anti_shuffle(s):\n words = s.split(' ')\n result = []\n\n for word in words:\n sorted_word = ''.join(sorted(word))\n result.append(sorted_word)\n\n return ' '.join(result)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n # Split the input string into words and iterate over them\n return ' '.join([''.join(sorted(word)) for word in s.split(' ')])", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n words = s.split(' ')\n ordered_words = [''.join(sorted(word)) for word in words]\n return ' '.join(ordered_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n # Split the sentence into words\n words = s.split(' ')\n # Process each word\n ordered_words = [''.join(sorted(word)) for word in words]\n # Join the processed words back into a sentence\n return ' '.join(ordered_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n result = []\n for word in s.split(' '):\n sorted_word = ''.join(sorted(word))\n result.append(sorted_word)\n return ' '.join(result)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n # Split the input string into words\n words = s.split(' ')\n # Process each word\n ordered_words = [''.join(sorted(word)) for word in words]\n # Join the processed words back into a single string\n return ' '.join(ordered_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n # Split the input string into words\n words = s.split(' ')\n \n # Process each word\n ordered_words = []\n for word in words:\n # Sort characters of the word in ascending order\n sorted_word = ''.join(sorted(word))\n # Append the sorted word to the list\n ordered_words.append(sorted_word)\n \n # Join the sorted words back into a string with spaces\n ordered_string = ' '.join(ordered_words)\n return ordered_string", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n words = s.split(' ')\n ordered_words = [''.join(sorted(word)) for word in words]\n return ' '.join(ordered_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n def sort_word(word):\n return ''.join(sorted(word))\n\n words = s.split(' ')\n ordered_words = [sort_word(word) for word in words]\n return ' '.join(ordered_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n # Split the string into words and iterate over them\n words = s.split(' ')\n ordered_words = []\n for word in words:\n # Sort the characters of the word in ascending order and join them back into a word\n ordered_word = ''.join(sorted(word))\n ordered_words.append(ordered_word)\n \n # Join the ordered words back into a sentence with spaces and return\n return ' '.join(ordered_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n # Split the input string into words and spaces\n words_and_spaces = s.split(' ')\n # Initialize an empty list to store the ordered words\n ordered_words = []\n # Iterate over each element in the split list\n for element in words_and_spaces:\n # Check if the element is a space or a word\n if element == '':\n # If it's a space, simply append it to the ordered list\n ordered_words.append(element)\n else:\n # If it's a word, sort its characters in ascending ASCII order\n ordered_word = ''.join(sorted(element))\n # Append the sorted word to the ordered list\n ordered_words.append(ordered_word)\n # Join the ordered list into a single string and return it\n return ' '.join(ordered_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n words = s.split(' ')\n ordered_words = [''.join(sorted(word)) for word in words]\n return ' '.join(ordered_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n # Split the sentence into words\n words = s.split(' ')\n # Process each word\n ordered_words = [''.join(sorted(word)) for word in words]\n # Join the processed words back into a sentence\n return ' '.join(ordered_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n # Split the sentence into words\n words = s.split(' ')\n # Process each word\n ordered_words = [''.join(sorted(word)) for word in words]\n # Join the ordered words back into a sentence\n return ' '.join(ordered_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n # Split the input string into words\n words = s.split(' ')\n # Process each word\n ordered_words = []\n for word in words:\n # Sort characters of the word in ascending order\n ordered_word = ''.join(sorted(word))\n ordered_words.append(ordered_word)\n # Join the processed words back into a string with spaces\n return ' '.join(ordered_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n # Split the input string into words\n words = s.split(' ')\n ordered_words = []\n \n # Process each word\n for word in words:\n # Sort the characters in the word\n sorted_word = ''.join(sorted(word))\n ordered_words.append(sorted_word)\n \n # Join the ordered words back into a string\n return ' '.join(ordered_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n words = s.split(' ')\n ordered_words = []\n\n for word in words:\n ordered_word = ''.join(sorted(word))\n ordered_words.append(ordered_word)\n\n return ' '.join(ordered_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n words = s.split(\" \")\n ordered_words = []\n \n for word in words:\n ordered_word = \"\".join(sorted(word))\n ordered_words.append(ordered_word)\n \n return \" \".join(ordered_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n words = s.split(' ')\n ordered_words = []\n for word in words:\n ordered_word = ''.join(sorted(word))\n ordered_words.append(ordered_word)\n return ' '.join(ordered_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n words = s.split(' ')\n ordered_words = [''.join(sorted(word)) for word in words]\n return ' '.join(ordered_words)", "matching_cluster_idx": 4}]}, "HumanEval/87": {"dps": 83.15561959654178, "dps_norm": 56.42857142857143, "pass@1": 97.0, "profiled": [{"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n result = []\n for i, row in enumerate(lst):\n for j, value in enumerate(row):\n if value == x:\n result.append((i, j))\n # Sort by rows in ascending order, and by columns in descending order within each row\n result.sort(key=lambda x: (x[0], -x[1]))\n return result", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n result = []\n for i, row in enumerate(lst):\n for j, value in enumerate(row):\n if value == x:\n result.append((i, j))\n # Sort by row in ascending order and then by column in descending order within the same row\n result.sort(key=lambda x: (x[0], -x[1]))\n return result", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n result = []\n for i, row in enumerate(lst):\n for j, val in enumerate(row):\n if val == x:\n result.append((i, j))\n # Sort by rows in ascending order and by columns in descending order\n result.sort(key=lambda x: (x[0], -x[1]))\n return result", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n Given a 2D list 'lst' and an integer 'x', find all occurrences of 'x'\n in the list and return a list of tuples (row, col) sorted by row in ascending\n order and by column in descending order within the same row.\n \"\"\"\n coordinates = []\n for row_idx, row in enumerate(lst):\n for col_idx, value in enumerate(row):\n if value == x:\n coordinates.append((row_idx, col_idx))\n # Sort by row in ascending order and then by column in descending order within the same row\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n coordinates = []\n # Iterate over rows and columns to find coordinates of x\n for i, row in enumerate(lst):\n for j, value in enumerate(row):\n if value == x:\n coordinates.append((i, j))\n \n # Sort by rows in ascending order and then by columns in descending order within each row\n sorted_coordinates = sorted(coordinates, key=lambda coord: (coord[0], -coord[1]))\n return sorted_coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n Given a 2-dimensional list 'lst' and an integer 'x', this function finds all occurrences of 'x'\n in 'lst', returns a list of tuples representing their coordinates in the format (row, column),\n sorted initially by rows in ascending order and then by columns in descending order within the same row.\n \"\"\"\n result = []\n # Enumerate through each row and column, starting from 0\n for row_idx, row in enumerate(lst):\n for col_idx, item in enumerate(reversed(row)):\n if item == x:\n # Adjust column index for the reversed row\n adjusted_col_idx = len(row) - 1 - col_idx\n result.append((row_idx, adjusted_col_idx))\n \n # Sort the result by row in ascending order and then by column in descending order within the same row\n result.sort(key=lambda x: (x[0], -x[1]))\n return result", "matching_cluster_idx": 3}, {"solution": "from typing import List, Tuple\ndef get_row(lst: List[List[int]], x: int) -> List[Tuple[int, int]]:\n \"\"\"\n This function takes a 2D list and an integer x as input. It returns a list of tuples\n representing the coordinates (row, column) of all occurrences of x in the 2D list.\n The list of tuples is sorted by row in ascending order and by column in descending order within each row.\n \"\"\"\n result = []\n for row_index, row in enumerate(lst):\n for col_index, value in enumerate(row[::-1]): # Reversing the row to sort by columns in descending order\n if value == x:\n # Adjusting column index to reflect correct position before reversing\n correct_col_index = len(row) - 1 - col_index\n result.append((row_index, correct_col_index))\n \n result.sort(key=lambda item: (item[0], -item[1])) # Sorting by row (ascending) and column (descending)\n return result", "matching_cluster_idx": 2}, {"solution": "def get_row(lst, x):\n \"\"\"\n Finds the coordinates of integer x in a 2D list (matrix),\n where each row may have a different number of columns.\n \n Parameters:\n lst (list of list of int): The input 2D list.\n x (int): The integer to find in the list.\n \n Returns:\n list of tuple: A list of tuples, where each tuple represents\n the (row, column) coordinates of x, sorted as specified.\n \"\"\"\n result = []\n for i, row in enumerate(lst):\n for j, value in enumerate(row):\n if value == x:\n result.append((i, j))\n \n # Sort by row in ascending order, then by column in descending order\n result.sort(key=lambda x: (x[0], -x[1]))\n \n return result", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n # List to store the result\n result = []\n # Iterate over rows in the nested list\n for row_idx, row in enumerate(lst):\n # Iterate over columns in the row\n for col_idx, value in enumerate(reversed(row)):\n # Check if the value is equal to x\n if value == x:\n # Append the tuple (row, column) to the result list\n # Adjust the column index because of the reversal\n result.append((row_idx, len(row) - 1 - col_idx))\n # Sort the result list by row in ascending order and then by column in descending order\n result.sort(key=lambda item: (item[0], -item[1]))\n return result", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n # Initialize an empty list to store the coordinates\n coordinates = []\n \n # Iterate through the list to find the integer x\n for row_index, row in enumerate(lst):\n for col_index, value in enumerate(row):\n if value == x:\n # Append the coordinate to the list\n coordinates.append((row_index, col_index))\n \n # Sort the coordinates by rows in ascending order\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n \n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n This function takes a 2D list 'lst' and an integer 'x'. It returns a list of tuples\n representing the coordinates of all occurrences of 'x' in 'lst'. The coordinates are\n sorted first by row in ascending order, and then by column in descending order within each row.\n \"\"\"\n result = []\n # Iterate over each row\n for row_idx, row in enumerate(lst):\n # Iterate over each column in the current row\n for col_idx, value in enumerate(row):\n # Check if the current value matches 'x'\n if value == x:\n # If it matches, add the coordinate to the result list\n result.append((row_idx, col_idx))\n # Sort the result list by row (ascending) and then by column (descending)\n result.sort(key=lambda x: (x[0], -x[1]))\n return result", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n result = []\n for i, row in enumerate(lst):\n if x in row:\n for j in range(len(row) - 1, -1, -1):\n if row[j] == x:\n result.append((i, j))\n return sorted(result, key=lambda item: (item[0], -item[1]))", "matching_cluster_idx": 5}, {"solution": "from typing import List, Tuple\ndef get_row(lst: List[List[int]], x: int) -> List[Tuple[int, int]]:\n coordinates = []\n\n # Iterate over each row\n for row_idx, row in enumerate(lst):\n # Reverse the row for descending column order when appended\n for col_idx, value in enumerate(row[::-1]):\n if value == x:\n # Reverse the column index to match original order in the reversed row\n original_col_idx = len(row) - col_idx - 1\n coordinates.append((row_idx, original_col_idx))\n\n # Sort by row in ascending order and then by column in descending order within the row\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n\n return coordinates", "matching_cluster_idx": 2}, {"solution": "def get_row(lst, x):\n \"\"\"\n Finds the coordinates of a given value in a 2D list and returns them sorted by row and column.\n \"\"\"\n # List to store the coordinates of the value x\n coordinates = []\n \n # Iterate over the list with index to get row number\n for row_index, row in enumerate(lst):\n # Reverse the row to facilitate sorting by column in descending order later\n row = row[::-1]\n # Enumerate the row to get column index\n for col_index, value in enumerate(row):\n # Check if the current value is equal to x\n if value == x:\n # Calculate the actual column index in the original list\n actual_col_index = len(row) - 1 - col_index\n # Append the coordinate (row_index, actual_col_index) to the list\n coordinates.append((row_index, actual_col_index))\n \n # Sort coordinates first by row in ascending order and then by column in descending order\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n \n # Return the sorted list of coordinates\n return coordinates", "matching_cluster_idx": 2}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n coordinates = []\n for i, row in enumerate(lst):\n for j, value in enumerate(row):\n if value == x:\n coordinates.append((i, j))\n # Sort by rows in ascending order and then by columns in descending order within the same row\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n result = []\n for i, row in enumerate(lst):\n for j, value in enumerate(reversed(row)):\n if value == x:\n result.append((i, len(row) - 1 - j))\n \n # Sort by rows in ascending order and then by columns in descending order within each row\n result.sort(key=lambda x: (x[0], -x[1]))\n return result", "matching_cluster_idx": 3}, {"solution": "from typing import *\nfrom collections import *\ndef get_row(lst, x):\n \"\"\"\n Find the coordinates of x in the given 2D list.\n \"\"\"\n result = []\n # Iterate through the list\n for i, row in enumerate(lst):\n # Find the indices of x in the current row\n for j in range(len(row) - 1, -1, -1):\n if row[j] == x:\n result.append((i, j))\n return result", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n result = []\n for i, row in enumerate(lst):\n for j, value in enumerate(reversed(row)):\n if value == x:\n result.append((i, len(row) - 1 - j))\n result.sort(key=lambda x: (x[0], -x[1]))\n return result", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n result = []\n # Iterate over the list with row index\n for row_index, row in enumerate(lst):\n # Iterate over the row with column index\n for col_index, value in enumerate(reversed(row)):\n # Check if the value matches x\n if value == x:\n # Calculate the actual column index from the reversed position\n actual_col_index = len(row) - 1 - col_index\n # Append the tuple of (row, column) to the result\n result.append((row_index, actual_col_index))\n # Sort the result first by row (ascending) and then by column (descending)\n result.sort(key=lambda item: (item[0], -item[1]))\n return result", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n Function to find coordinates of integer x in a 2D list.\n Each row in the list may have a different number of columns.\n \n Args:\n lst (list of lists of int): The 2D list to search through.\n x (int): The integer to search for.\n \n Returns:\n list of tuples: List of coordinates (row, column) for each occurrence of x.\n Sorted by rows in ascending order and columns in descending order within each row.\n \"\"\"\n # Initialize an empty list to store the coordinates\n coordinates = []\n \n # Iterate over the list to find occurrences of x\n for row_index, row in enumerate(lst):\n for col_index, value in enumerate(row):\n if value == x:\n # Append the coordinates to the list\n coordinates.append((row_index, col_index))\n \n # Sort coordinates by rows ascending and by columns descending within each row\n sorted_coordinates = sorted(coordinates, key=lambda x: (x[0], -x[1]))\n \n # Return the sorted list of coordinates\n return sorted_coordinates", "matching_cluster_idx": 3}]}, "HumanEval/89": {"dps": 96.71391752577321, "dps_norm": 32.142857142857146, "pass@1": 97.0, "profiled": [{"solution": "def encrypt(s):\n \"\"\"\n Encrypts a given string by rotating the alphabet by two multiplied to two places down the alphabet.\n \n Args:\n s (str): The string to encrypt.\n \n Returns:\n str: The encrypted string.\n \"\"\"\n result = \"\"\n for char in s:\n if char.isalpha(): # Check if the character is an alphabet\n shift = (2 * 2) % 26 # Calculate the shift amount\n if char.islower():\n # Rotate lowercase letters\n result += chr((ord(char) - ord('a') + shift) % 26 + ord('a'))\n else:\n # Rotate uppercase letters\n result += chr((ord(char) - ord('A') + shift) % 26 + ord('A'))\n else:\n # Non-alphabet characters are added unchanged\n result += char\n return result", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n result = []\n for char in s:\n if char.isalpha():\n # Calculate the shift amount (2 * 2 = 4)\n shift = 4\n # Determine the ASCII offset (lowercase or uppercase)\n ascii_offset = ord('a') if char.islower() else ord('A')\n # Calculate the new character code with wrap-around\n new_char_code = (ord(char) - ascii_offset + shift) % 26 + ascii_offset\n # Convert the new character code back to a character\n new_char = chr(new_char_code)\n result.append(new_char)\n else:\n # Non-alphabetic characters are not encrypted\n result.append(char)\n return ''.join(result)", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"\n Encrypts a string by rotating the alphabet by four places.\n \n Args:\n s (str): The input string to be encrypted.\n \n Returns:\n str: The encrypted string with the alphabet rotated by four places.\n \n Examples:\n >>> encrypt('hi')\n 'lm'\n >>> encrypt('asdfghjkl')\n 'ewhjklnop'\n >>> encrypt('gf')\n 'kj'\n >>> encrypt('et')\n 'ix'\n \"\"\"\n result = []\n for char in s:\n if char.isalpha():\n shift = 4\n if char.islower():\n base = ord('a')\n else:\n base = ord('A')\n encrypted_char = chr((ord(char) - base + shift) % 26 + base)\n result.append(encrypted_char)\n else:\n result.append(char)\n return ''.join(result)", "matching_cluster_idx": 1}, {"solution": "import string\ndef encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n # Define the alphabet and create a mapping for encrypted letters\n alphabet = string.ascii_lowercase\n encrypted_alphabet = alphabet[4:] + alphabet[:4] # Shift by 4 places\n\n # Create a dictionary for quick lookup of encrypted letters\n encryption_dict = {original: encrypted for original, encrypted in zip(alphabet, encrypted_alphabet)}\n\n # Encrypt the input string using the lookup dictionary\n encrypted_string = ''.join([encryption_dict[char] if char in alphabet else char for char in s])\n\n return encrypted_string", "matching_cluster_idx": 2}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n # Define the alphabet\n alphabet = \"abcdefghijklmnopqrstuvwxyz\"\n encrypted_string = \"\"\n\n # Loop through each character in the input string\n for char in s:\n if char in alphabet:\n # Find the index of the character in the alphabet\n index = alphabet.index(char)\n # Calculate the new index with the rotation\n new_index = (index + (2 * 2)) % len(alphabet)\n # Append the rotated character to the result string\n encrypted_string += alphabet[new_index]\n else:\n # If the character is not in the alphabet, append it unchanged\n encrypted_string += char\n\n return encrypted_string", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"\n Encrypts a given string by rotating the alphabet. \n Each letter in the string is replaced by the letter that is two multiplied by two places down the alphabet.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n result = \"\"\n for char in s:\n if char.isalpha():\n shift = 2 * 2\n if char.islower():\n start = ord('a')\n else:\n start = ord('A')\n encrypted_char = chr((ord(char) - start + shift) % 26 + start)\n result += encrypted_char\n else:\n result += char\n return result", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n # Define the alphabet\n alphabet = 'abcdefghijklmnopqrstuvwxyz'\n # Initialize the encrypted string\n encrypted_string = ''\n # Iterate through each character in the input string\n for char in s:\n # Check if the character is in the alphabet\n if char in alphabet:\n # Find the new position of the character\n new_position = (alphabet.index(char) + (2 * 2)) % 26\n # Append the new character to the encrypted string\n encrypted_string += alphabet[new_position]\n else:\n # If the character is not in the alphabet, leave it as it is\n encrypted_string += char\n # Return the encrypted string\n return encrypted_string", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"\n Encrypt a string by rotating the alphabet by four places.\n \n Args:\n s (str): The string to be encrypted.\n \n Returns:\n str: The encrypted string.\n \"\"\"\n result = \"\"\n for char in s:\n if char.isalpha(): # Check if the character is a letter\n shift = 4\n if char.islower():\n base = ord('a')\n else:\n base = ord('A')\n encrypted_char = chr((ord(char) - base + shift) % 26 + base)\n result += encrypted_char\n else:\n result += char # Non-alphabet characters are not encrypted\n return result", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"\n Encrypts a string by rotating the alphabet down by two multiplied to two places.\n \"\"\"\n result = \"\"\n for char in s:\n if char.isalpha():\n shift = 2 * 2\n if char.islower():\n result += chr((ord(char) - ord('a') + shift) % 26 + ord('a'))\n else:\n result += chr((ord(char) - ord('A') + shift) % 26 + ord('A'))\n else:\n result += char\n return result", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n alphabet = \"abcdefghijklmnopqrstuvwxyz\"\n encrypted_string = \"\"\n for char in s:\n if char.isalpha():\n shift = (2 * 2) % 26 # Shift by 4 places\n index = alphabet.index(char.lower())\n shifted_index = (index + shift) % 26\n if char.isupper():\n encrypted_string += alphabet[shifted_index].upper()\n else:\n encrypted_string += alphabet[shifted_index]\n else:\n encrypted_string += char # Non-alphabetic characters remain unchanged\n return encrypted_string", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n encrypted_string = ''\n for char in s:\n if char.isalpha():\n ascii_offset = 97 if char.islower() else 65\n encrypted_char = chr((ord(char) - ascii_offset + 4) % 26 + ascii_offset)\n encrypted_string += encrypted_char\n else:\n encrypted_string += char\n return encrypted_string", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n # Define the alphabet\n alphabet = 'abcdefghijklmnopqrstuvwxyz'\n # Initialize the encrypted string\n encrypted = ''\n # Iterate through each character in the input string\n for char in s:\n # Check if the character is in the alphabet\n if char in alphabet:\n # Find the index of the character in the alphabet\n index = alphabet.index(char)\n # Calculate the new index with the specified shift\n new_index = (index + 2 * 2) % 26\n # Append the encrypted character to the encrypted string\n encrypted += alphabet[new_index]\n else:\n # If the character is not in the alphabet, append it unchanged\n encrypted += char\n # Return the encrypted string\n return encrypted", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"\n Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n # Define the alphabet\n alphabet = 'abcdefghijklmnopqrstuvwxyz'\n encrypted = ''\n \n # Function to rotate a character\n def rotate_char(c):\n if c in alphabet:\n return alphabet[(alphabet.index(c) + (2 * 2)) % 26]\n else:\n return c\n \n # Encrypt each character in the input string\n for char in s:\n encrypted += rotate_char(char)\n \n return encrypted", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n result = \"\" # Initialize an empty string to store the result\n for char in s: # Iterate through each character in the input string\n if char.isalpha(): # Check if the character is a letter\n shift = 2 * 2 # Define the shift amount\n # Shift character forward and wrap around the alphabet using modulo\n if char.islower():\n result += chr((ord(char) - ord('a') + shift) % 26 + ord('a'))\n else:\n result += chr((ord(char) - ord('A') + shift) % 26 + ord('A'))\n else:\n result += char # If not a letter, add the character as is\n return result", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n result = \"\"\n for char in s:\n if char.isalpha():\n # Calculate the shift amount\n shift = (2 * 2) % 26\n if char.islower():\n # Encrypt lowercase letters\n result += chr((ord(char) - ord('a') + shift) % 26 + ord('a'))\n else:\n # Encrypt uppercase letters\n result += chr((ord(char) - ord('A') + shift) % 26 + ord('A'))\n else:\n # If not a letter, add the character as it is\n result += char\n return result", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n result = []\n for char in s:\n if char.isalpha():\n shift = 2 * 2\n if char.islower():\n start = ord('a')\n else:\n start = ord('A')\n encrypted_char = chr((ord(char) - start + shift) % 26 + start)\n result.append(encrypted_char)\n else:\n result.append(char)\n return ''.join(result)", "matching_cluster_idx": 1}, {"solution": "import string\ndef encrypt(s):\n # Define the alphabet and the alphabet rotated by 2*2=4 places\n alphabet = string.ascii_lowercase\n shifted_alphabet = alphabet[4:] + alphabet[:4]\n \n # Create a translation table for encryption\n table = str.maketrans(alphabet, shifted_alphabet)\n \n # Return the encrypted string\n return s.translate(table)", "matching_cluster_idx": 5}, {"solution": "def encrypt(s):\n encrypted = \"\"\n for char in s:\n if char.isalpha():\n shift = 2 * 2\n if char.islower():\n encrypted += chr((ord(char) - ord('a') + shift) % 26 + ord('a'))\n else:\n encrypted += chr((ord(char) - ord('A') + shift) % 26 + ord('A'))\n else:\n encrypted += char\n return encrypted", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n encrypted_text = \"\"\n for char in s:\n if char.isalpha():\n shift = 2 * 2\n ascii_offset = 65 if char.isupper() else 97\n # Calculate the new character, wrapping around the alphabet if necessary\n new_char = chr((ord(char) - ascii_offset + shift) % 26 + ascii_offset)\n encrypted_text += new_char\n else:\n encrypted_text += char\n return encrypted_text", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n result = \"\"\n for char in s:\n if char.isalpha():\n shift = (2 * 2) % 26 # Rotating the alphabet by 4 places\n if char.islower():\n result += chr((ord(char) - ord('a') + shift) % 26 + ord('a'))\n else:\n result += chr((ord(char) - ord('A') + shift) % 26 + ord('A'))\n else:\n result += char\n return result", "matching_cluster_idx": 1}]}, "HumanEval/90": {"dps": 83.96887159533074, "dps_norm": 57.5, "pass@1": 96.0, "profiled": [{"solution": "from typing import List, Optional\ndef next_smallest(lst: List[int]) -> Optional[int]:\n \"\"\"\n Returns the 2nd smallest element in the list.\n If there is no such element, returns None.\n \"\"\"\n if len(lst) < 2:\n return None\n\n # Initialize the smallest and second smallest with infinity\n smallest = float('inf')\n second_smallest = float('inf')\n\n for num in lst:\n if num < smallest:\n # Update the second smallest before updating the smallest\n second_smallest = smallest\n smallest = num\n elif num < second_smallest and num != smallest:\n second_smallest = num\n\n return second_smallest if second_smallest != float('inf') else None", "matching_cluster_idx": 5}, {"solution": "from typing import List, Optional\ndef next_smallest(lst: List[int]) -> Optional[int]:\n \"\"\"\n Find the second smallest element in a list of integers.\n Returns None if there is no such element.\n \"\"\"\n unique_elements = list(set(lst)) # Remove duplicates\n if len(unique_elements) < 2:\n return None\n unique_elements.sort() # Sort elements\n return unique_elements[1] # Return the second smallest element", "matching_cluster_idx": 6}, {"solution": "from typing import *\nfrom collections import *\ndef next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n # Remove duplicates and sort the list\n unique_sorted_lst = sorted(set(lst))\n \n # Check if there are at least 2 unique elements\n if len(unique_sorted_lst) < 2:\n return None\n \n # Return the 2nd smallest element\n return unique_sorted_lst[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n Returns the 2nd smallest element in the list or None if it doesn't exist.\n \"\"\"\n # Remove duplicates by converting to set, then back to list\n unique_lst = list(set(lst))\n # Sort the list\n unique_lst.sort()\n # Check if there is at least two unique elements\n if len(unique_lst) < 2:\n return None\n else:\n return unique_lst[1] # Return the second smallest element", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \"\"\"\n if len(lst) < 2:\n return None\n \n unique_lst = list(set(lst))\n if len(unique_lst) < 2:\n return None\n \n unique_lst.sort()\n return unique_lst[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n # Remove duplicates to handle cases like [1, 1]\n unique_lst = list(set(lst))\n \n # Check if there are at least two unique elements\n if len(unique_lst) < 2:\n return None\n \n # Sort the list to find the 2nd smallest element\n unique_lst.sort()\n \n # Return the 2nd element in the sorted list\n return unique_lst[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n \n # Convert the list to a set to remove duplicates and then back to a sorted list\n sorted_unique_lst = sorted(set(lst))\n \n # Return the 2nd smallest element if it exists, otherwise return None\n return sorted_unique_lst[1] if len(sorted_unique_lst) > 1 else None", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n if len(lst) < 2:\n return None\n \n unique_elements = list(set(lst))\n if len(unique_elements) < 2:\n return None\n \n unique_elements.sort()\n return unique_elements[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n # Remove duplicates by converting the list to a set, then back to a sorted list\n unique_sorted_list = sorted(set(lst))\n # Check if there are at least two unique elements\n if len(unique_sorted_list) < 2:\n return None\n # Return the second smallest element\n return unique_sorted_list[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n # Check if the list has less than 2 unique elements\n if len(set(lst)) < 2:\n return None\n # Remove duplicates and sort the list\n sorted_unique_lst = sorted(set(lst))\n # Return the second smallest element\n return sorted_unique_lst[1]", "matching_cluster_idx": 5}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n # Remove duplicates and sort the list\n unique_sorted_lst = sorted(set(lst))\n \n # Check if there are at least 2 unique elements\n if len(unique_sorted_lst) < 2:\n return None\n \n # Return the 2nd smallest element\n return unique_sorted_lst[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n \n unique_sorted = sorted(set(lst))\n \n if len(unique_sorted) < 2:\n return None\n \n return unique_sorted[1]", "matching_cluster_idx": 6}, {"solution": "from typing import *\nfrom collections import *\ndef next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \"\"\"\n unique_sorted_lst = sorted(set(lst))\n if len(unique_sorted_lst) < 2:\n return None\n return unique_sorted_lst[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n Returns the 2nd smallest element of the list.\n Returns None if there is no such element.\n \"\"\"\n if len(lst) < 2:\n return None\n \n # Remove duplicates and sort the list\n unique_sorted_lst = sorted(set(lst))\n \n # Check if there are at least 2 unique elements\n if len(unique_sorted_lst) < 2:\n return None\n \n # Return the 2nd smallest element\n return unique_sorted_lst[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n Returns the 2nd smallest element in the list, or None if it doesn't exist.\n \"\"\"\n if len(lst) < 2:\n return None\n\n # Remove duplicates to ensure we are looking for the actual 2nd smallest distinct number\n unique_elements = list(set(lst))\n if len(unique_elements) < 2:\n return None\n\n # Sort the unique elements to find the 2nd smallest\n unique_elements.sort()\n\n # Return the 2nd smallest element\n return unique_elements[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n Returns the 2nd smallest element in the list, or None if it doesn't exist.\n \"\"\"\n if len(lst) < 2:\n return None\n \n # Convert list to a set to remove duplicates and then back to a sorted list\n sorted_unique = sorted(set(lst))\n \n # Check if there are at least two unique elements\n if len(sorted_unique) < 2:\n return None\n \n # Return the second smallest element\n return sorted_unique[1]", "matching_cluster_idx": 6}, {"solution": "from typing import List, Optional\ndef next_smallest(lst: List[int]) -> Optional[int]:\n \"\"\"\n Return the 2nd smallest element in the list if it exists, otherwise return None.\n \"\"\"\n unique_elements = sorted(set(lst))\n return unique_elements[1] if len(unique_elements) > 1 else None", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n This function finds the 2nd smallest element in a list of integers.\n If the list is empty or all elements are the same, it returns None.\n \n :param lst: List of integers\n :return: The 2nd smallest element or None\n \"\"\"\n unique_elements = list(set(lst)) # Remove duplicates\n if len(unique_elements) < 2:\n return None # Not enough unique elements for a 2nd smallest\n unique_elements.sort() # Sort the unique elements\n return unique_elements[1] # Return the 2nd smallest element", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \"\"\"\n if len(lst) < 2:\n return None\n \n # Convert list to a set to remove duplicates and then back to a sorted list\n sorted_unique_lst = sorted(set(lst))\n \n # Check if there are at least 2 unique elements\n if len(sorted_unique_lst) < 2:\n return None\n \n # Return the second smallest element\n return sorted_unique_lst[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n # Remove duplicates and sort the list\n unique_sorted_list = sorted(set(lst))\n \n # Check if there is at least two unique elements\n if len(unique_sorted_list) < 2:\n return None\n \n # Return the second smallest element\n return unique_sorted_list[1]", "matching_cluster_idx": 6}]}, "HumanEval/113": {"dps": 94.32048681541582, "dps_norm": 64.16666666666667, "pass@1": 91.0, "profiled": [{"solution": "def odd_count(lst):\n \"\"\"\n Given a list of strings, where each string consists of only digits,\n return a list where each element is a sentence that describes the number\n of odd digits in each string of the input list.\n \n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n output = []\n for number_str in lst:\n odd_count = sum(1 for char in number_str if int(char) % 2 == 1)\n output.append(f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\")\n return output", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n result = []\n for num_str in lst:\n odd_count = sum(1 for char in num_str if int(char) % 2 != 0)\n result.append(f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\")\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"\n Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n result = []\n for num_str in lst:\n # Count the number of odd digits in the string\n odd_count = sum(1 for char in num_str if int(char) % 2 != 0)\n # Replace all occurrences of 'i' with the count of odd digits and add to the result list\n result.append(f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\")\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n # Define a function to count odd digits in a string\n def count_odd_digits(s):\n return sum(1 for char in s if int(char) % 2 != 0)\n\n # Apply the count_odd_digits function to each string in the list\n result = []\n for i, string in enumerate(lst, start=1):\n odd_count = count_odd_digits(string)\n # Replace all occurrences of 'i' with the count of odd digits\n output = f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\"\n result.append(output)\n\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"\n Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n Parameters:\n lst (list): A list of strings, each containing only digits.\n\n Returns:\n list: A list of strings with the specified transformation.\n \"\"\"\n result = []\n for s in lst:\n odd_count = sum(1 for char in s if int(char) % 2 != 0)\n transformed_string = f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\"\n result.append(transformed_string)\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"\n Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n \n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n result = []\n for item in lst:\n odd_count = sum(1 for char in item if int(char) % 2 != 0)\n result.append(f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\")\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n result = []\n for i, num_str in enumerate(lst, start=1):\n odd_count = sum(1 for digit in num_str if int(digit) % 2 != 0)\n result.append(f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\")\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n # Define a helper function to count odd digits in a string\n def count_odd(s):\n return sum(1 for char in s if int(char) % 2 == 1)\n \n # Apply the helper function to each string in the input list\n result = []\n for s in lst:\n odd_count = count_odd(s)\n # Replace all 'i's in the template string with the odd count\n result.append(f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\")\n \n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n result = []\n for s in lst:\n odd_count = sum(1 for char in s if int(char) % 2 != 0)\n result.append(f'the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.')\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n result = []\n for i, number_string in enumerate(lst, start=1):\n odd_count = sum(1 for char in number_string if int(char) % 2 != 0)\n result.append(f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\")\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"\n Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n \"\"\"\n result = []\n for s in lst:\n count_odd = sum(1 for char in s if int(char) % 2 != 0)\n result.append(f\"the number of odd elements {count_odd}n the str{count_odd}ng {count_odd} of the {count_odd}nput.\")\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n # Function to count odd digits in a string\n def count_odd_in_string(s):\n count = sum(1 for char in s if int(char) % 2 != 0)\n return count\n\n # Generate the output list\n result = []\n for s in lst:\n count = count_odd_in_string(s)\n result.append(f\"the number of odd elements {count}n the str{count}ng {count} of the {count}nput.\")\n \n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"\n Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n result = []\n for string in lst:\n odd_count = sum(1 for char in string if int(char) % 2 != 0)\n modified_string = string.replace(str(odd_count), str(odd_count) + 'n')\n modified_string = modified_string.replace(str(odd_count), str(odd_count) + 'ng ' + str(odd_count))\n modified_string = modified_string.replace(str(odd_count), str(odd_count) + ' of ')\n modified_string = modified_string.replace(str(odd_count), str(odd_count) + 'nput.')\n result.append(f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\")\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n # Helper function to count odd digits in a string\n def count_odd_digits(s):\n return sum(1 for char in s if int(char) % 2 == 1)\n\n # Generate the output list with the required format\n result = [\n f\"the number of odd elements {count_odd_digits(s)}n the str{count_odd_digits(s)}ng {count_odd_digits(s)} of the {count_odd_digits(s)}nput.\"\n for s in lst\n ]\n return result", "matching_cluster_idx": 0}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n result = []\n for s in lst:\n odd_count = sum(1 for char in s if int(char) % 2 == 1)\n result.append(f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\")\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n result = []\n for s in lst:\n odd_count = sum(1 for char in s if int(char) % 2 != 0)\n modified_string = s.replace(str(odd_count), 'n')\n result.append(f'the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.')\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n output = []\n for item in lst:\n odd_count = sum(1 for digit in item if int(digit) % 2 != 0)\n output.append(f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\")\n return output", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n # Function to count odd digits in a string\n def count_odd_in_string(s):\n return sum(1 for char in s if int(char) % 2 != 0)\n \n # Generate the output list\n result = []\n for index, string in enumerate(lst):\n odd_count = count_odd_in_string(string)\n result.append(f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\")\n \n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n output = []\n for num_str in lst:\n odd_count = sum(1 for digit in num_str if int(digit) % 2 != 0)\n output.append(f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\")\n return output", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"\n Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n \"\"\"\n result = []\n for string in lst:\n odd_count = sum(1 for char in string if int(char) % 2 == 1)\n result.append(f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\")\n return result", "matching_cluster_idx": 3}]}, "HumanEval/119": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 99.0, "profiled": [{"solution": "def match_parens(lst):\n '''\n Check if it's possible to concatenate two strings of parentheses in some order to form a balanced string.\n A string is balanced if all parentheses are properly closed and opened.\n\n :param lst: List containing two strings of parentheses\n :return: 'Yes' if a balanced string can be formed, 'No' otherwise\n '''\n\n def is_balanced(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n else:\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n # Try both possible concatenations\n concat1 = lst[0] + lst[1]\n concat2 = lst[1] + lst[0]\n\n if is_balanced(concat1) or is_balanced(concat2):\n return 'Yes'\n else:\n return 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n\n def is_balanced(s):\n count = 0\n for char in s:\n if char == '(':\n count += 1\n else:\n count -= 1\n if count < 0:\n return False\n return count == 0\n\n # Try concatenating in both possible orders\n if is_balanced(lst[0] + lst[1]) or is_balanced(lst[1] + lst[0]):\n return 'Yes'\n return 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n # Concatenate in both possible orders\n combined1 = lst[0] + lst[1]\n combined2 = lst[1] + lst[0]\n \n # Check if either combined string is good\n if is_good(combined1) or is_good(combined2):\n return 'Yes'\n else:\n return 'No'\ndef is_good(s):\n # Initialize counter for open parentheses\n open_count = 0\n for char in s:\n if char == '(':\n open_count += 1\n elif char == ')':\n open_count -= 1\n # If open count goes negative, parentheses are not balanced\n if open_count < 0:\n return False\n # If open count is zero, parentheses are balanced\n return open_count == 0", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n '''\n Check if it is possible to concatenate two strings in some order to form a balanced string of parentheses.\n \n :param lst: List of two strings, each containing only '(' or ')'.\n :return: 'Yes' if a balanced string can be formed, 'No' otherwise.\n '''\n # Function to check if a string of parentheses is balanced\n def is_balanced(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n else:\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n # Try both concatenations\n concat1 = lst[0] + lst[1]\n concat2 = lst[1] + lst[0]\n\n # Check if either concatenation results in a balanced string\n if is_balanced(concat1) or is_balanced(concat2):\n return 'Yes'\n else:\n return 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n\n def is_balanced(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n else:\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n str1, str2 = lst\n # Check if concatenating in both possible orders results in a balanced string\n return 'Yes' if is_balanced(str1 + str2) or is_balanced(str2 + str1) else 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n def is_balanced(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n else:\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n first_combination = lst[0] + lst[1]\n second_combination = lst[1] + lst[0]\n if is_balanced(first_combination) or is_balanced(second_combination):\n return 'Yes'\n else:\n return 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n \"\"\"\n Checks if concatenating two strings in any order can result in a balanced parentheses string.\n \n Args:\n lst (list): A list containing two strings made up of '(' and ')' characters.\n \n Returns:\n str: 'Yes' if a balanced string can be formed, 'No' otherwise.\n \"\"\"\n def is_balanced(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n else:\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n str1, str2 = lst\n if is_balanced(str1 + str2) or is_balanced(str2 + str1):\n return 'Yes'\n return 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n def is_balanced(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n else:\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n # Check both possible concatenations\n combined1 = lst[0] + lst[1]\n combined2 = lst[1] + lst[0]\n \n # Check if either combination is balanced\n if is_balanced(combined1) or is_balanced(combined2):\n return 'Yes'\n else:\n return 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n def is_balanced(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n elif char == ')':\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n # Check both possible concatenations\n if is_balanced(lst[0] + lst[1]) or is_balanced(lst[1] + lst[0]):\n return 'Yes'\n else:\n return 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n\n def is_balanced(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n else:\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n # Concatenate in both possible orders\n first_order = lst[0] + lst[1]\n second_order = lst[1] + lst[0]\n \n # Check if either concatenated string is balanced\n if is_balanced(first_order) or is_balanced(second_order):\n return 'Yes'\n else:\n return 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n\n # Helper function to check if a string has balanced parentheses\n def is_balanced(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n else:\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n # Try concatenating in both possible orders\n first_order = lst[0] + lst[1]\n second_order = lst[1] + lst[0]\n\n # Check if either order results in a balanced string\n if is_balanced(first_order) or is_balanced(second_order):\n return 'Yes'\n else:\n return 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n def is_balanced(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n else:\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n first_order = lst[0] + lst[1]\n second_order = lst[1] + lst[0]\n if is_balanced(first_order) or is_balanced(second_order):\n return 'Yes'\n else:\n return 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n \"\"\"\n Checks if it is possible to concatenate two strings in some order to form a balanced parentheses string.\n \n Args:\n lst (list of str): A list containing two strings composed only of '(' and ')'.\n \n Returns:\n str: 'Yes' if a balanced string can be formed, 'No' otherwise.\n \"\"\"\n # Function to check if a string has balanced parentheses\n def is_balanced(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n elif char == ')':\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n # Check both possible concatenations\n concat1 = lst[0] + lst[1]\n concat2 = lst[1] + lst[0]\n\n # Return 'Yes' if either concatenation is balanced, otherwise 'No'\n return 'Yes' if is_balanced(concat1) or is_balanced(concat2) else 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n \"\"\"\n Check if concatenating two strings in some order results in a balanced parentheses string.\n\n Args:\n lst: A list of two strings, each containing only '(' or ')'.\n\n Returns:\n 'Yes' if a balanced string can be formed, 'No' otherwise.\n \"\"\"\n # Try both possible concatenations\n for order in [lst, lst[::-1]]:\n balance = 0\n for char in order[0] + order[1]:\n if char == '(':\n balance += 1\n else:\n balance -= 1\n # If balance goes negative, parentheses are not balanced\n if balance < 0:\n break\n # If balance is zero after processing both strings, they are balanced\n if balance == 0:\n return 'Yes'\n return 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n \"\"\"\n Check if two strings consisting only of '(' or ')' can be concatenated in\n some order to form a balanced parentheses string.\n \n :param lst: List of two strings\n :return: 'Yes' if a balanced string can be formed, 'No' otherwise\n \"\"\"\n def is_balanced(s):\n \"\"\"Check if the given string is balanced.\"\"\"\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n else:\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n # Check both possible concatenations\n if is_balanced(lst[0] + lst[1]) or is_balanced(lst[1] + lst[0]):\n return 'Yes'\n return 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n # Helper function to check if a string has balanced parentheses\n def is_balanced(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n else:\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n # Check both possible concatenations\n concatenation1 = lst[0] + lst[1]\n concatenation2 = lst[1] + lst[0]\n\n # Return 'Yes' if either concatenation results in a balanced string\n if is_balanced(concatenation1) or is_balanced(concatenation2):\n return 'Yes'\n else:\n return 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n def is_balanced(s):\n # Check if the parentheses in the string are balanced\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n else:\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n # Try concatenating in both possible orders\n if is_balanced(lst[0] + lst[1]) or is_balanced(lst[1] + lst[0]):\n return 'Yes'\n else:\n return 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n '''\n Check if it is possible to concatenate two strings from the list in some order\n to form a balanced parentheses string.\n\n :param lst: List of two strings containing only '(' and ')'.\n :return: 'Yes' if a balanced string can be formed, 'No' otherwise.\n '''\n\n def is_balanced(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n else:\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n combined1 = lst[0] + lst[1]\n combined2 = lst[1] + lst[0]\n return 'Yes' if is_balanced(combined1) or is_balanced(combined2) else 'No'", "matching_cluster_idx": 4}, {"solution": "from typing import *\nfrom collections import *\ndef match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n\n def is_balanced(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n else:\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n str1 = lst[0]\n str2 = lst[1]\n\n # Check both concatenations\n concat1 = str1 + str2\n concat2 = str2 + str1\n\n if is_balanced(concat1) or is_balanced(concat2):\n return 'Yes'\n else:\n return 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n '''\n Checks if it is possible to concatenate two strings in some order\n to form a balanced parentheses string.\n '''\n # Importing the deque class from collections module for efficient list operations\n from collections import deque\n \n # Function to check if a string has balanced parentheses\n def is_balanced(s):\n stack = deque()\n for char in s:\n if char == '(':\n stack.append(char)\n elif char == ')':\n if not stack:\n return False\n stack.pop()\n return len(stack) == 0\n \n # Concatenate the strings in both possible orders and check for balance\n if is_balanced(lst[0] + lst[1]) or is_balanced(lst[1] + lst[0]):\n return 'Yes'\n else:\n return 'No'", "matching_cluster_idx": 4}]}, "HumanEval/120": {"dps": 96.63793103448276, "dps_norm": 97.85714285714286, "pass@1": 39.0, "profiled": [{"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n\n Example 1:\n\n Input: arr = [-3, -4, 5], k = 3\n Output: [-4, -3, 5]\n\n Example 2:\n\n Input: arr = [4, -4, 4], k = 2\n Output: [4, 4]\n\n Example 3:\n\n Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1\n Output: [2]\n\n Note:\n 1. The length of the array will be in the range of [1, 1000].\n 2. The elements in the array will be in the range of [-1000, 1000].\n 3. 0 <= k <= len(arr)\n \"\"\"\n\n if k == 0:\n return []\n\n # Sort the array in descending order and take the first k elements\n sorted_arr = sorted(arr, reverse=True)[:k]\n\n # Return the sorted list of the k largest elements\n return sorted(sorted_arr)", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n\n This implementation uses Python's built-in functions to sort the array and then slice \n the top k elements.\n\n Parameters:\n arr (List[int]): The list of integers.\n k (int): The number of top elements to return.\n\n Returns:\n List[int]: A sorted list of the maximum k elements in arr.\n \"\"\"\n # Edge case: if k is 0, return an empty list\n if k == 0:\n return []\n \n # Sort the array in ascending order\n arr.sort()\n \n # Return the last k elements from the sorted array, which are the largest k elements\n return arr[-k:]", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n \"\"\"\n # Sort the array in descending order to get the maximum elements at the beginning\n arr.sort(reverse=True)\n # Return the first k elements and then sort them in ascending order to meet the requirement\n return sorted(arr[:k])", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n \"\"\"\n # If k is 0, return an empty list\n if k == 0:\n return []\n # Sort the array in descending order and take the first k elements\n max_elements = sorted(arr, reverse=True)[:k]\n # Return the first k elements sorted in ascending order\n return sorted(max_elements)", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n \n Args:\n arr (List[int]): The array of integers.\n k (int): The number of maximum elements to return.\n \n Returns:\n List[int]: A sorted list of length k with the maximum k numbers in arr.\n \"\"\"\n # Check if k is 0 or arr is empty, return an empty list\n if k == 0 or not arr:\n return []\n \n # Sort the array in descending order to get the maximum elements at the start\n arr.sort(reverse=True)\n \n # Return the first k elements and sort them to meet the problem's requirement\n return sorted(arr[:k])", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n \"\"\"\n # Sort the array in descending order\n arr.sort(reverse=True)\n # Return the first k elements of the sorted array, sorted again in ascending order\n return sorted(arr[:k])", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n\n Example 1:\n\n Input: arr = [-3, -4, 5], k = 3\n Output: [-4, -3, 5]\n\n Example 2:\n\n Input: arr = [4, -4, 4], k = 2\n Output: [4, 4]\n\n Example 3:\n\n Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1\n Output: [2]\n\n Note:\n 1. The length of the array will be in the range of [1, 1000].\n 2. The elements in the array will be in the range of [-1000, 1000].\n 3. 0 <= k <= len(arr)\n \"\"\"\n # Sort the array in descending order and take the first k elements\n max_elements = sorted(arr, reverse=True)[:k]\n # Return the sorted list of the maximum k elements\n return sorted(max_elements)", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n \n The function uses Python's built-in sorting method to sort the array in \n descending order and then returns the first k elements, which are the largest \n ones. Finally, it sorts these k elements in ascending order before returning \n them as the output.\n \n Note:\n 1. The length of the array will be in the range of [1, 1000].\n 2. The elements in the array will be in the range of [-1000, 1000].\n 3. 0 <= k <= len(arr)\n \"\"\"\n # Sort the array in descending order\n sorted_arr = sorted(arr, reverse=True)\n # Select the first k elements\n top_k = sorted_arr[:k]\n # Sort the selected elements in ascending order before returning\n return sorted(top_k)", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n \"\"\"\n # Sort the array in descending order to get the largest elements at the beginning\n sorted_arr = sorted(arr, reverse=True)\n # Slice the first k elements and then sort the result in ascending order\n result = sorted(sorted_arr[:k])\n return result", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n\n :param arr: List[int] - The array of integers.\n :param k: int - The number of maximum elements to return.\n :return: List[int] - A sorted list of the maximum k numbers.\n \"\"\"\n # Sort the array in descending order and select the first k elements\n max_k_elements = sorted(arr, reverse=True)[:k]\n # Return these elements sorted in ascending order\n return sorted(max_k_elements)", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n \"\"\"\n # Check if k is 0, return an empty list\n if k == 0:\n return []\n \n # Sort the array in descending order\n arr.sort(reverse=True)\n \n # Slice the first k elements and sort them in ascending order before returning\n return sorted(arr[:k])", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n\n Example 1:\n\n Input: arr = [-3, -4, 5], k = 3\n Output: [-4, -3, 5]\n\n Example 2:\n\n Input: arr = [4, -4, 4], k = 2\n Output: [4, 4]\n\n Example 3:\n\n Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1\n Output: [2]\n\n Note:\n 1. The length of the array will be in the range of [1, 1000].\n 2. The elements in the array will be in the range of [-1000, 1000].\n 3. 0 <= k <= len(arr)\n \"\"\"\n # Sort the array in descending order and take the first k elements\n top_k = sorted(arr, reverse=True)[:k]\n # Return the sorted list of the top k elements\n return sorted(top_k)", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n\n Example 1:\n\n Input: arr = [-3, -4, 5], k = 3\n Output: [-4, -3, 5]\n\n Example 2:\n\n Input: arr = [4, -4, 4], k = 2\n Output: [4, 4]\n\n Example 3:\n\n Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1\n Output: [2]\n\n Note:\n 1. The length of the array will be in the range of [1, 1000].\n 2. The elements in the array will be in the range of [-1000, 1000].\n 3. 0 <= k <= len(arr)\n \"\"\"\n # Sort the array in descending order\n arr.sort(reverse=True)\n # Return the first k elements and sort them in ascending order before returning\n return sorted(arr[:k])", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n \"\"\"\n if k == 0:\n return []\n # Sort the array in descending order and take the first k elements\n max_elements = sorted(arr, reverse=True)[:k]\n # Return the sorted list of the first k maximum elements\n return sorted(max_elements)", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n \n This function first sorts the array in descending order, then takes the first k\n elements and returns them sorted in ascending order as the result.\n \n :param arr: List[int] - A list of integers\n :param k: int - The number of maximum elements to return\n :return: List[int] - A sorted list containing the maximum k elements from the input array\n \"\"\"\n # Check if k is 0, return an empty list\n if k == 0:\n return []\n \n # Sort the array in descending order\n arr.sort(reverse=True)\n \n # Take the first k elements\n top_k = arr[:k]\n \n # Return the k elements sorted in ascending order\n return sorted(top_k)", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n \"\"\"\n # Sort the array in descending order and then take the first k elements\n max_elements = sorted(arr, reverse=True)[:k]\n # Return the result sorted in ascending order\n return sorted(max_elements)", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Return a sorted list of length k with the maximum k numbers in arr.\n\n Args:\n arr (list of int): The list of integers.\n k (int): The number of maximum elements to return.\n\n Returns:\n list of int: The sorted list of k maximum elements.\n \"\"\"\n # Sort the array in descending order and slice the first k elements\n result = sorted(arr, reverse=True)[:k]\n # Return the sorted result\n return sorted(result)", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n\n Example 1:\n\n Input: arr = [-3, -4, 5], k = 3\n Output: [-4, -3, 5]\n\n Example 2:\n\n Input: arr = [4, -4, 4], k = 2\n Output: [4, 4]\n\n Example 3:\n\n Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1\n Output: [2]\n\n Note:\n 1. The length of the array will be in the range of [1, 1000].\n 2. The elements in the array will be in the range of [-1000, 1000].\n 3. 0 <= k <= len(arr)\n \"\"\"\n if k == 0:\n return []\n\n # Use a min-heap to keep track of the k largest elements\n from heapq import nlargest\n largest_k = nlargest(k, arr)\n \n # Sort the list of largest k elements\n largest_k.sort()\n \n return largest_k", "matching_cluster_idx": 3}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n\n Example 1:\n\n Input: arr = [-3, -4, 5], k = 3\n Output: [-4, -3, 5]\n\n Example 2:\n\n Input: arr = [4, -4, 4], k = 2\n Output: [4, 4]\n\n Example 3:\n\n Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1\n Output: [2]\n\n Note:\n 1. The length of the array will be in the range of [1, 1000].\n 2. The elements in the array will be in the range of [-1000, 1000].\n 3. 0 <= k <= len(arr)\n \"\"\"\n # Sort the array in descending order\n arr.sort(reverse=True)\n \n # Return the first k elements and sort them in ascending order before returning\n return sorted(arr[:k])", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n \"\"\"\n # Sort the array in descending order and slice the first k elements\n top_k = sorted(arr, reverse=True)[:k]\n # Return the sorted list of the top k elements\n return sorted(top_k)", "matching_cluster_idx": 6}]}, "HumanEval/121": {"dps": 84.88789237668162, "dps_norm": 63.57142857142858, "pass@1": 74.0, "profiled": [{"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n\n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n # Initialize sum to 0\n sum_odd = 0\n \n # Iterate over the list with index\n for i in range(len(lst)):\n # Check if the position is even and the element is odd\n if i % 2 == 0 and lst[i] % 2 != 0:\n sum_odd += lst[i]\n \n return sum_odd", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n \"\"\"\n Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n\n Examples:\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n return sum(val for i, val in enumerate(lst) if i % 2 == 0 and val % 2 != 0)", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n \"\"\"\n Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==>0\n \"\"\"\n # Initialize the sum to 0\n sum_odd_even_positions = 0\n \n # Iterate over the list with index\n for i in range(len(lst)):\n # Check if the position is even and the element is odd\n if i % 2 == 0 and lst[i] % 2 != 0:\n sum_odd_even_positions += lst[i]\n \n # Return the sum\n return sum_odd_even_positions", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n \"\"\"\n Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n\n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==>0\n \"\"\"\n total = 0\n # Iterate over the list, considering only the even positions (0-indexed, so step by 2)\n for i in range(0, len(lst), 2):\n # Check if the element at the current even position is odd\n if lst[i] % 2 != 0:\n # Add it to the total sum\n total += lst[i]\n return total", "matching_cluster_idx": 4}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n\n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==>0\n \"\"\"\n return sum(val for idx, val in enumerate(lst) if idx % 2 == 0 and val % 2 == 1)", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n # Initialize the sum to 0\n total = 0\n # Iterate over the list with index\n for i in range(0, len(lst), 2): # Start from 0 to consider even positions\n if lst[i] % 2 != 0: # Check if the number is odd\n total += lst[i] # Add to the total if it's odd\n return total", "matching_cluster_idx": 4}, {"solution": "def solution(lst):\n # Initialize the sum to zero\n sum_odd_even_positions = 0\n \n # Iterate through the list, considering only even positions (0-based index)\n for i in range(0, len(lst), 2):\n # Check if the element at the even position is odd\n if lst[i] % 2 != 0:\n # Add it to the sum\n sum_odd_even_positions += lst[i]\n \n # Return the final sum\n return sum_odd_even_positions", "matching_cluster_idx": 4}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n Examples:\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n # Initialize the sum to 0\n total_sum = 0\n \n # Iterate over the list with index\n for index, value in enumerate(lst):\n # Check if the index is even and the value is odd\n if index % 2 == 0 and value % 2 != 0:\n # Add the value to the total sum\n total_sum += value\n \n # Return the total sum of odd elements at even positions\n return total_sum", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n # Initialize the sum to 0\n total_sum = 0\n \n # Iterate over the list, considering only even positions (0-indexed)\n for i in range(0, len(lst), 2):\n # Check if the element at the even position is odd\n if lst[i] % 2 != 0:\n # Add it to the total sum\n total_sum += lst[i]\n \n # Return the computed sum\n return total_sum", "matching_cluster_idx": 4}, {"solution": "def solution(lst):\n \"\"\"\n Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==>0\n \"\"\"\n # Initialize the sum to 0\n sum_odd = 0\n \n # Iterate over the list, considering only even positions (0-indexed)\n for i in range(0, len(lst), 2):\n # Check if the element at the even position is odd\n if lst[i] % 2 != 0:\n # Add the odd element to the sum\n sum_odd += lst[i]\n \n # Return the total sum of odd elements at even positions\n return sum_odd", "matching_cluster_idx": 4}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==>0\n \"\"\"\n total = 0\n # Iterate over the list, considering only even positions (0-indexed)\n for index in range(0, len(lst), 2):\n # Check if the element at the current even position is odd\n if lst[index] % 2 != 0:\n # Add it to the total sum\n total += lst[index]\n return total", "matching_cluster_idx": 4}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n\n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==>0\n \"\"\"\n return sum(lst[i] for i in range(0, len(lst), 2) if lst[i] % 2 != 0)", "matching_cluster_idx": 4}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n\n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==>0\n \"\"\"\n return sum(val for idx, val in enumerate(lst) if idx % 2 == 0 and val % 2 == 1)", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n\n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n return sum(x for i, x in enumerate(lst) if i % 2 == 0 and x % 2 != 0)", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n\n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n return sum(x for i, x in enumerate(lst) if i % 2 == 0 and x % 2 == 1)", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n \"\"\"\n Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==>0\n \"\"\"\n # Initialize the sum to zero\n sum_odd = 0\n \n # Iterate over the list using enumerate to get both index and value\n for index, value in enumerate(lst):\n # Check if the position is even and the number is odd\n if index % 2 == 0 and value % 2 != 0:\n # Add the odd number to the sum\n sum_odd += value\n \n # Return the final sum of odd numbers in even positions\n return sum_odd", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n\n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==>0\n \"\"\"\n sum_odd = 0\n for i in range(0, len(lst), 2): # Iterate through even indices\n if lst[i] % 2 != 0: # Check if the element is odd\n sum_odd += lst[i]\n return sum_odd", "matching_cluster_idx": 4}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==>0\n \"\"\"\n # Initialize the sum to zero\n total_sum = 0\n \n # Iterate over the list with index\n for index, value in enumerate(lst):\n # Check if the index is even and the value is odd\n if index % 2 == 0 and value % 2 != 0:\n # Add the value to the total sum\n total_sum += value\n \n # Return the total sum of odd elements in even positions\n return total_sum", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==>0\n \"\"\"\n # Initialize sum to 0\n total_sum = 0\n \n # Iterate over the list, considering only even positions (indices)\n for i in range(0, len(lst), 2):\n if lst[i] % 2 != 0: # Check if the element is odd\n total_sum += lst[i] # Add to total sum\n \n return total_sum", "matching_cluster_idx": 4}, {"solution": "def solution(lst):\n # Initialize the sum of odd elements in even positions to 0\n odd_sum = 0\n # Iterate over the list, considering the index\n for i in range(len(lst)):\n # Check if the index is even and the element is odd\n if i % 2 == 0 and lst[i] % 2 != 0:\n # Add the odd element to the sum\n odd_sum += lst[i]\n # Return the calculated sum\n return odd_sum", "matching_cluster_idx": 3}]}, "HumanEval/149": {"dps": 85.82677165354332, "dps_norm": 57.142857142857146, "pass@1": 100.0, "profiled": [{"solution": "def sorted_list_sum(lst):\n # Filter out strings with odd lengths\n filtered_list = [word for word in lst if len(word) % 2 == 0]\n \n # Sort the list by the length of the words, and then alphabetically\n sorted_list = sorted(filtered_list, key=lambda x: (len(x), x))\n \n return sorted_list", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order.\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n You may assume that all words will have the same length.\n For example:\n assert list_sort([\"aa\", \"a\", \"aaa\"]) => [\"aa\"]\n assert list_sort([\"ab\", \"a\", \"aaa\", \"cd\"]) => [\"ab\", \"cd\"]\n \"\"\"\n # Filter out strings with odd lengths\n filtered_list = [word for word in lst if len(word) % 2 == 0]\n \n # Sort the list by length, and then alphabetically for words of the same length\n sorted_list = sorted(filtered_list, key=lambda x: (len(x), x))\n \n return sorted_list", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"Sorts a list of strings in ascending order by length.\n If two strings have the same length, sorts them alphabetically.\n Removes strings with odd lengths before sorting.\"\"\"\n # Filter out strings with odd lengths\n even_length_lst = [word for word in lst if len(word) % 2 == 0]\n \n # Sort the list first by length, then alphabetically\n sorted_lst = sorted(even_length_lst, key=lambda x: (len(x), x))\n \n return sorted_lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n # Filter out strings with odd lengths\n filtered_lst = [word for word in lst if len(word) % 2 == 0]\n \n # Sort the list by the length of the strings, and then alphabetically\n sorted_lst = sorted(filtered_lst, key=lambda x: (len(x), x))\n \n return sorted_lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"\n This function removes strings with odd lengths from a list and returns a sorted list.\n The list is sorted by word length in ascending order. If two words have the same length,\n they are sorted alphabetically.\n \n :param lst: List of strings\n :return: Sorted list of strings with even lengths\n \"\"\"\n # Filter out strings with odd lengths\n even_length_lst = [word for word in lst if len(word) % 2 == 0]\n \n # Sort the list by word length, and then alphabetically\n even_length_lst.sort(key=lambda x: (len(x), x))\n \n return even_length_lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n # Filter out strings with odd lengths\n filtered_lst = [word for word in lst if len(word) % 2 == 0]\n \n # Sort the list by length, and then alphabetically for words of the same length\n sorted_lst = sorted(filtered_lst, key=lambda x: (len(x), x))\n \n return sorted_lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n # Filter out strings with odd lengths\n even_length_words = [word for word in lst if len(word) % 2 == 0]\n \n # Sort the list by length, and then alphabetically for words of the same length\n sorted_words = sorted(even_length_words, key=lambda x: (len(x), x))\n \n return sorted_words", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n # Filter out strings with odd lengths\n filtered_lst = [word for word in lst if len(word) % 2 == 0]\n \n # Sort the list first by length and then alphabetically\n sorted_lst = sorted(filtered_lst, key=lambda x: (len(x), x))\n \n return sorted_lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n # Filter out strings with odd lengths\n filtered_list = [word for word in lst if len(word) % 2 == 0]\n \n # Sort the list by length, and then alphabetically for words of the same length\n sorted_list = sorted(filtered_list, key=lambda x: (len(x), x))\n \n return sorted_list", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n # Filter out strings with odd lengths\n even_length_lst = [word for word in lst if len(word) % 2 == 0]\n \n # Sort the list first by length of words, then alphabetically\n sorted_lst = sorted(even_length_lst, key=lambda x: (len(x), x))\n \n return sorted_lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n # Filter out strings with odd lengths\n even_length_lst = [word for word in lst if len(word) % 2 == 0]\n \n # Sort the list by length of words, then alphabetically for words of the same length\n even_length_lst.sort(key=lambda x: (len(x), x))\n \n return even_length_lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n # Filter out words with odd lengths\n filtered_list = [word for word in lst if len(word) % 2 == 0]\n \n # Sort the list by length of words, and then alphabetically if lengths are equal\n sorted_list = sorted(filtered_list, key=lambda x: (len(x), x))\n \n return sorted_list", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order.\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n You may assume that all words will have the same length.\n For example:\n assert list_sort([\"aa\", \"a\", \"aaa\"]) => [\"aa\"]\n assert list_sort([\"ab\", \"a\", \"aaa\", \"cd\"]) => [\"ab\", \"cd\"]\n \"\"\"\n # Filter out strings with odd lengths\n filtered_list = [word for word in lst if len(word) % 2 == 0]\n \n # Sort the list by length, then alphabetically\n sorted_list = sorted(filtered_list, key=lambda x: (len(x), x))\n \n return sorted_list", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef sorted_list_sum(lst: List[str]) -> List[str]:\n \"\"\"Sort a list of strings based on their lengths, and remove strings with odd lengths.\n\n Args:\n lst (List[str]): A list of strings.\n\n Returns:\n List[str]: A sorted list of strings with even lengths.\n \"\"\"\n # Filter out strings with odd lengths\n even_length_words = [word for word in lst if len(word) % 2 == 0]\n \n # Sort the list by word length, and then alphabetically\n even_length_words.sort(key=lambda x: (len(x), x))\n \n return even_length_words", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n # Filter out strings with odd lengths\n filtered_lst = [word for word in lst if len(word) % 2 == 0]\n \n # Sort the list by the length of each word, and alphabetically for words of the same length\n sorted_lst = sorted(filtered_lst, key=lambda x: (len(x), x))\n \n return sorted_lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order,\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n You may assume that all words will have the same length.\n For example:\n assert list_sort([\"aa\", \"a\", \"aaa\"]) => [\"aa\"]\n assert list_sort([\"ab\", \"a\", \"aaa\", \"cd\"]) => [\"ab\", \"cd\"]\n \"\"\"\n # Filter out strings with odd lengths\n even_length_lst = [word for word in lst if len(word) % 2 == 0]\n \n # Sort the list by length, then alphabetically\n sorted_lst = sorted(even_length_lst, key=lambda x: (len(x), x))\n \n return sorted_lst", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef sorted_list_sum(lst: List[str]) -> List[str]:\n # Filter out strings with odd lengths\n filtered_list = [word for word in lst if len(word) % 2 == 0]\n \n # Sort the list first by length, then alphabetically\n sorted_list = sorted(filtered_list, key=lambda x: (len(x), x))\n \n return sorted_list", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"Sorts a list of strings after removing those with odd lengths and returns the list sorted by word length and alphabetically.\"\"\"\n # Filter out strings with odd lengths\n even_length_words = [word for word in lst if len(word) % 2 == 0]\n \n # Sort the list by word length, and alphabetically if lengths are equal\n even_length_words.sort(key=lambda word: (len(word), word))\n \n return even_length_words", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order.\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n You may assume that all words will have the same length.\n For example:\n assert list_sort([\"aa\", \"a\", \"aaa\"]) => [\"aa\"]\n assert list_sort([\"ab\", \"a\", \"aaa\", \"cd\"]) => [\"ab\", \"cd\"]\n \"\"\"\n # Filter out strings with odd lengths\n filtered_list = [word for word in lst if len(word) % 2 == 0]\n \n # Sort the list by length and then alphabetically\n sorted_list = sorted(filtered_list, key=lambda x: (len(x), x))\n \n return sorted_list", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"\n Write a function that accepts a list of strings as a parameter, deletes\n the strings that have odd lengths from it, and returns the resulted list\n with a sorted order. The list is always a list of strings and never an\n array of numbers, and it may contain duplicates. The order of the list\n should be ascending by length of each word, and you should return the list\n sorted by that rule. If two words have the same length, sort the list\n alphabetically. The function should return a list of strings in sorted order.\n You may assume that all words will have the same length.\n \n For example:\n assert sorted_list_sum([\"aa\", \"a\", \"aaa\"]) == [\"aa\"]\n assert sorted_list_sum([\"ab\", \"a\", \"aaa\", \"cd\"]) == [\"ab\", \"cd\"]\n \"\"\"\n # Filter out words with odd lengths\n filtered_lst = [word for word in lst if len(word) % 2 == 0]\n \n # Sort the list by length, then alphabetically\n sorted_lst = sorted(filtered_lst, key=lambda x: (len(x), x))\n \n return sorted_lst", "matching_cluster_idx": 3}]}, "Mbpp/3": {"dps": 57.58474576271186, "dps_norm": 74.375, "pass@1": 85.0, "profiled": [{"solution": "def is_not_prime(n):\n # Check if the number is less than or equal to 1, which are not prime\n if n <= 1:\n return True\n \n # Check divisibility from 2 up to the square root of n\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return True\n \n # If no divisors found, the number is prime\n return False", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(num):\n # If the number is less than 2, it is not prime\n if num < 2:\n return True\n # If the number is 2, it is prime\n if num == 2:\n return False\n # If the number is divisible by any number up to its square root, it is not prime\n if num % 2 == 0:\n return True\n # Check for factors from 3 to the square root of num\n for i in range(3, int(num**0.5) + 1, 2):\n if num % i == 0:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(num):\n # Check if the number is less than or equal to 1\n if num <= 1:\n return True\n # Check for factors from 2 to the square root of num\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n return True\n return False", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(num):\n # Check if the number is less than 2, which is not considered a prime number\n if num < 2:\n return True\n # Check if the number is divisible by any number from 2 to its square root\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n return True\n # If no divisors were found, the number is prime\n return False", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(n):\n # Check if the number is less than or equal to 1, which is not prime\n if n <= 1:\n return True\n # Check divisibility from 2 to the square root of n\n for i in range(2, int(n**0.5) + 1):\n # If n is divisible by any number in the range, it is not prime\n if n % i == 0:\n return True\n # If no divisors found, n is prime\n return False", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(num):\n # Check if the number is less than 2\n if num < 2:\n return True\n # Check for factors from 2 to the square root of num\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n return True\n return False", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(n):\n # A number is non-prime if it is divisible by any number other than 1 and itself\n if (n == 0 or n == 1):\n return True\n for x in range(2, n):\n if n % x == 0:\n return True\n return False", "matching_cluster_idx": 0}, {"solution": "import math\ndef is_not_prime(x):\n # If the number is less than or equal to 1, it is not prime\n if x <= 1:\n return True\n # Check divisibility from 2 up to the square root of x\n for i in range(2, int(math.sqrt(x)) + 1):\n # If divisible by any number, it is not prime\n if x % i == 0:\n return True\n # If not divisible by any number, it is prime\n return False", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(n):\n # Check if n is less than 2, which is not a prime number\n if n < 2:\n return True\n # Check for factors from 2 to the square root of n\n for i in range(2, int(n**0.5) + 1):\n # If n is divisible by any number within this range, it is not prime\n if n % i == 0:\n return True\n # If no factors are found, n is prime\n return False", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(num):\n # Check if the number is less than 2\n if num < 2:\n return True\n # Check if the number is divisible by any number from 2 to the square root of the number\n for i in range(2, int(num ** 0.5) + 1):\n if num % i == 0:\n return True\n # If the number is not divisible by any number, it is prime\n return False", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(n):\n # Check if n is less than or equal to 1, which are not prime numbers\n if n <= 1:\n return True\n # Check for factors from 2 to the square root of n\n for i in range(2, int(n**0.5) + 1):\n # If a factor is found, n is not a prime number\n if n % i == 0:\n return True\n # If no factors are found, n is a prime number\n return False", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(n):\n # A number less than 2 is not prime\n if n < 2:\n return True\n # Check divisibility from 2 up to the square root of n\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return True\n return False", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(n):\n # Check if the number is less than 2, which are not prime\n if n <= 1:\n return True\n # Check for factors from 2 to the square root of n\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return True\n # If no factors are found, the number is prime\n return False", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(x):\n # Check if the number is less than 2\n if x < 2:\n return True\n # Check for factors from 2 to the square root of x\n for n in range(2, int(x**0.5) + 1):\n if x % n == 0:\n return True\n return False", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(n):\n # Check if the number is less than 2\n if n < 2:\n return True\n # Check if the number is divisible by any number from 2 to the square root of n\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return True\n # If no divisors are found, the number is prime\n return False", "matching_cluster_idx": 5}, {"solution": "import math\ndef is_not_prime(x):\n # If x is less than 2, it is not a prime number\n if x < 2:\n return True\n # Check divisibility from 2 up to the square root of x\n for i in range(2, int(math.sqrt(x)) + 1):\n if x % i == 0:\n return True\n return False", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(n):\n # Check for non-prime by attempting division from 2 to the square root of n\n if n < 2:\n return True\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return True\n return False", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(num):\n # Check if the number is less than 2, which is not a prime number\n if num < 2:\n return True\n # Check for factors from 2 to the square root of num\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n return True\n return False", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(x):\n # Check if the number is less than 2, as 0 and 1 are not prime numbers\n if x <= 1:\n return True\n # Check divisibility from 2 up to the square root of x\n for n in range(2, int(x**0.5) + 1):\n if x % n == 0:\n # If divisible, return True indicating x is not prime\n return True\n # If not divisible by any number other than 1 and itself, return False\n return False", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(n):\n # Check for non-prime numbers by testing divisibility\n if n <= 1:\n return True # 1 and negative numbers are not prime\n if n <= 3:\n return False # 2 and 3 are prime\n if n % 2 == 0 or n % 3 == 0:\n return True # multiples of 2 and 3 are not prime\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return True # check for divisibility by numbers of the form 6k \u00b1 1\n i += 6\n return False # no divisors found, number is prime", "matching_cluster_idx": 7}]}, "Mbpp/4": {"dps": 95.46075085324232, "dps_norm": 84.16666666666666, "pass@1": 87.0, "profiled": [{"solution": "def heap_queue_largest(nums, n):\n # Import the heapq module to work with heap queues\n import heapq\n \n # Find the n largest numbers in the list using heapq's nlargest function\n largest_nums = heapq.nlargest(n, nums)\n \n # Return the largest numbers in descending order\n return largest_nums", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n # Use heapq's nlargest method to find the n largest numbers\n largest_nums = heapq.nlargest(n, nums)\n # Return the result sorted in descending order\n return sorted(largest_nums, reverse=True)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n # Using nlargest from heapq to find the n largest elements and sorting them in descending order\n largest_nums = heapq.nlargest(n, nums)\n largest_nums.sort(reverse=True)\n return largest_nums", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(list1, n):\n # Using heapq.nlargest to find the n largest numbers in the list and sorting them in descending order\n largest_nums = heapq.nlargest(n, list1)\n # Returning the sorted list\n return sorted(largest_nums, reverse=True)", "matching_cluster_idx": 9}, {"solution": "import heapq as hq\ndef heap_queue_largest(nums, n):\n # Use nlargest from heapq to find the n largest elements\n largest_nums = hq.nlargest(n, nums)\n # Return the largest elements sorted in descending order\n return sorted(largest_nums, reverse=True)", "matching_cluster_idx": 9}, {"solution": "import heapq as hq\ndef heap_queue_largest(nums, n):\n # Using nlargest method from heapq to get the n largest elements\n largest_nums = hq.nlargest(n, nums)\n return largest_nums # Returning the n largest numbers in descending order", "matching_cluster_idx": 9}, {"solution": "import heapq as hq\ndef heap_queue_largest(nums, n):\n # Use heapq.nlargest to find the n largest numbers and return them in descending order\n return hq.nlargest(n, nums)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n # Use the heapq.nlargest function to find the n largest elements\n largest_nums = heapq.nlargest(n, nums)\n # Return the list of largest elements sorted in descending order\n return largest_nums", "matching_cluster_idx": 9}, {"solution": "import heapq as hq\ndef heap_queue_largest(nums, n):\n # Use the nlargest function from the heapq module to find the n largest elements\n largest_nums = hq.nlargest(n, nums)\n return largest_nums", "matching_cluster_idx": 9}, {"solution": "import heapq as hq\ndef heap_queue_largest(nums, n):\n # Use heapq's nlargest function to find the n largest elements in the list\n return hq.nlargest(n, nums)", "matching_cluster_idx": 9}, {"solution": "import heapq as hq\ndef heap_queue_largest(nums, n):\n # Find the n largest numbers using heapq's nlargest function\n largest_nums = hq.nlargest(n, nums)\n # Return the list of n largest numbers in descending order\n return largest_nums", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n # Use heapq.nlargest to find the n largest elements\n largest_nums = heapq.nlargest(n, nums)\n # Return the elements in descending order\n return largest_nums", "matching_cluster_idx": 9}, {"solution": "from heapq import nlargest\ndef heap_queue_largest(nums, n):\n # Use the nlargest function from the heapq module to find the n largest elements\n # and then sort them in descending order\n return sorted(nlargest(n, nums), reverse=True)", "matching_cluster_idx": 9}, {"solution": "import heapq as hq\ndef heap_queue_largest(nums, n):\n # Use heapq to find the n largest elements and convert them to a sorted list in descending order\n return sorted(hq.nlargest(n, nums), reverse=True)", "matching_cluster_idx": 9}, {"solution": "def heap_queue_largest(numbers_list, n):\n # Sort the list in descending order and return the first n elements\n return sorted(numbers_list, reverse=True)[:n]", "matching_cluster_idx": 11}, {"solution": "from heapq import nlargest\ndef heap_queue_largest(nums, n):\n # Use the nlargest function from the heapq module to find the n largest numbers\n return nlargest(n, nums)", "matching_cluster_idx": 9}, {"solution": "import heapq as hq\ndef heap_queue_largest(nums, n):\n # Using heapq.nlargest to find the n largest numbers in the list\n # and returning them in descending order\n return hq.nlargest(n, nums)", "matching_cluster_idx": 9}, {"solution": "import heapq as hq\ndef heap_queue_largest(nums, n):\n # Use nlargest from heapq to find the n largest elements\n largest_nums = hq.nlargest(n, nums)\n # Return the elements sorted in descending order\n return sorted(largest_nums, reverse=True)", "matching_cluster_idx": 9}, {"solution": "import heapq as hq\ndef heap_queue_largest(nums, n):\n # Use heapq.nlargest function to get the n largest elements\n # and return them in descending order\n largest_nums = hq.nlargest(n, nums)\n return largest_nums", "matching_cluster_idx": 9}, {"solution": "import heapq as hq\ndef heap_queue_largest(nums, n):\n # Use heapq.nlargest to get the n largest numbers from the list\n # The result is already in descending order\n largest_nums = hq.nlargest(n, nums)\n return largest_nums", "matching_cluster_idx": 9}]}, "Mbpp/9": {"dps": 62.074829931972786, "dps_norm": 52.5, "pass@1": 26.0, "profiled": [{"solution": "def find_Rotations(s):\n # Concatenate the string with itself to handle rotations\n temp = s + s\n \n # Initialize the minimum rotations to the length of the string\n minimum_rotations = len(s)\n \n # Iterate through the possible rotations\n for i in range(1, len(s)):\n # Compare the current rotation with the original string\n if (temp[i:len(s)+i] == s):\n # Update the minimum rotations if a smaller rotation is found\n minimum_rotations = min(minimum_rotations, i)\n \n # Return the minimum number of rotations greater than 0\n return minimum_rotations", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(str1):\n # Iterate through the length of the string to check for rotations\n for i in range(1, len(str1)):\n # Rotate the string by slicing and compare with the original\n if str1[i:] + str1[:i] == str1:\n return i\n # If no rotation matches the original, return the length of the string\n return len(str1)", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(s):\n n = len(s) # Get the length of the string\n if n == 0: # If the string is empty, return 0 rotations needed\n return 0\n temp = s * 2 # Double the string to simulate rotations\n for i in range(1, n): # Loop from 1 to n-1 to check each rotation\n if temp[i:i + n] == s: # If the substring from i to i+n matches the original string\n return i # Return the number of rotations needed\n return n # If no match found, return the length of the string", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(str):\n n = len(str)\n for i in range(1, n):\n # Check if the string starts with the same characters as its rotated version\n if str.startswith(str[i:] + str[:i]):\n return i\n return n", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(str1):\n # Calculate the length of the input string\n size = len(str1)\n # Iterate over possible rotation points\n for i in range(1, size):\n # Check if the string from index i to the end concatenated with the substring from the start to index i\n # is equal to the original string\n if (str1[i:] + str1[0:i]) == str1:\n return i\n # If no rotation matches the original string, return the size of the string (no full rotation needed)\n return size", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(str1):\n # Check if the input string is empty\n if str1 == '':\n return 0\n \n # Initialize rotation count to 1\n count = 1\n \n # Check for the same string after rotations\n for i in range(1, len(str1)):\n new_str = str1[i:] + str1[:i]\n if new_str == str1:\n return count\n count += 1\n \n # Return the minimum number of rotations\n return count", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(s):\n # Concatenate the string to itself to handle rotations\n temp = s + s\n n = len(s)\n \n # Iterate through the string to check for rotations\n for i in range(1, n):\n # If the substring matches the original string, return i\n if temp[i:n+i] == s:\n return i\n # If no match is found, return the length of the string\n return n", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(s):\n # Get the length of the string\n n = len(s)\n \n # Check if all characters in the string are the same\n if len(set(s)) == 1:\n # If so, return 1 as no rotation will change the string\n return 1\n \n # Iterate through possible rotations\n for i in range(1, n):\n # Check if the current rotation matches the original string\n if s[i:] + s[:i] == s:\n # If a match is found, return the number of rotations\n return i\n \n # If no match is found, return n (the total number of rotations)\n return n", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(string):\n # Check if the string is empty\n if string == \"\":\n return -1\n \n # Get the length of the string\n length = len(string)\n \n # Concatenate the string to itself to check for rotations\n concatenated_string = string + string\n \n # Iterate through the original string\n for i in range(1, length):\n # Check if the substring from index i to i+length matches the original string\n if (concatenated_string[i:i+length] == string):\n return i\n \n # If no match is found, return the length of the string\n return length", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(str):\n # Length of the string\n len_str = len(str)\n for i in range(1, len_str):\n # Rotate the string by i and check if it matches the original string\n if (str[i:] + str[:i]) == str:\n # If a match is found, return the number of rotations (i)\n return i\n # If no match is found, return the length of the string (original string is the same)\n return len_str", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(str1):\n # Get the length of the string\n n = len(str1)\n # Reverse the string and concatenate it with itself\n concatenated = str1 + str1\n # Check for each rotation\n for i in range(1, n):\n temp = concatenated[i:i+n]\n # Check if the current rotation is equal to the original string\n if (temp == str1):\n return i\n # If no rotation matches, return n\n return n", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(s):\n # Find the minimum length of rotations\n return len(set(s[i:] + s[:i] for i in range(len(s))))", "matching_cluster_idx": 3}, {"solution": "def find_Rotations(str):\n # Calculate the length of the input string\n n = len(str)\n \n # If the string is empty, return 0 rotations\n if n == 0:\n return 0\n \n # If the string has only one character, return 0 rotations\n if n == 1:\n return 0\n \n # Iterate through the string to find the minimum rotations required\n for i in range(1, n):\n if (str[i:] + str[:i]) == str:\n return i\n \n # If no rotation matches, return n (the length of the string)\n return n", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(str1):\n # Calculate the length of the string\n len1 = len(str1)\n \n # Find the smallest index where the string has a rotation that matches the original\n for i in range(1, len1):\n if str1[i:] + str1[:i] == str1:\n return i\n \n # If no such rotation is found, return the length of the string (no rotation needed)\n return len1", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(str1): \n # Calculate the length of the string\n length = len(str1) \n # Iterate through the range of the string length\n for i in range(1, length): \n # Check if the substring from index i to end and from start to index i are equal\n if (str1[i:]+str1[0:i] == str1): \n # Return the number of rotations required\n return i \n # If no rotation results in the same string, return the length of the string\n return length", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(str1):\n # Concatenate the string with itself to cover all possible rotations\n concat_str = str1 + str1\n # Calculate the length of the original string\n len_str = len(str1)\n # Iterate through each possible rotation\n for i in range(1, len_str):\n temp_str = concat_str[i:i+len_str]\n # Check if the rotated string is equal to the original string\n if temp_str == str1:\n return i # Return the number of rotations needed\n return len_str # Return the length of the string if no exact match is found", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(str): \n # Get the length of the string\n n = len(str) \n for i in range(1, n): \n # Rotate the string by one position\n str1 = str[i:] + str[0:i] \n # Compare the rotated string with the original string\n if str1 == str: \n # If they are the same, return the number of rotations needed\n return i \n # If no rotation results in the original string, return the length of the string\n return n", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(s):\n # Iterate through all possible rotations\n for i in range(1, len(s)):\n # Check if the current rotation matches the original string\n if s[i:] + s[:i] == s:\n return i\n # If no match is found, return the length of the string (0-based index)\n return len(s)", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(s):\n # Loop through each character in the string\n for i in range(1, len(s)):\n # Rotate the string by slicing and concatenating\n s1 = s[i:] + s[:i]\n # Check if the rotated string matches the original string\n if s1 == s:\n return i # Return the number of rotations\n return len(s) # Return the length if no match found", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(str): \n # Initialize the length of the string\n n = len(str) \n # Iterate through the string\n for i in range(1, n): \n # Check if rotating the string gives the same string\n if (str[i:] + str[0:i]) == str: \n return i \n # If no rotation gives the same string, return the length\n return n", "matching_cluster_idx": 4}]}, "Mbpp/11": {"dps": 25.017921146953405, "dps_norm": 68.33333333333333, "pass@1": 60.0, "profiled": [{"solution": "def remove_Occ(string, character):\n # Find the index of the first occurrence of the character\n index_first_occ = string.find(character)\n \n # Remove the first occurrence if found\n if index_first_occ != -1:\n string = string[:index_first_occ] + string[index_first_occ + 1:]\n \n # Reverse the string to find and remove the last occurrence (which is now the first in the reversed string)\n string_reversed = string[::-1]\n index_last_occ = string_reversed.find(character)\n \n # Remove the last occurrence if found\n if index_last_occ != -1:\n string = string[:len(string) - index_last_occ - 1] + string[len(string) - index_last_occ:]\n \n return string", "matching_cluster_idx": 4}, {"solution": "def remove_Occ(text, ch):\n # Find the index of the first occurrence of the character\n first_occurrence = text.find(ch)\n \n # If the character is not found, return the original text\n if first_occurrence == -1:\n return text\n \n # Find the index of the last occurrence of the character\n last_occurrence = text.rfind(ch)\n \n # If the first and last occurrences are the same, remove that occurrence\n if first_occurrence == last_occurrence:\n return text[:first_occurrence] + text[first_occurrence + 1:]\n \n # Remove both the first and last occurrences of the character\n return text[:first_occurrence] + text[first_occurrence + 1:last_occurrence] + text[last_occurrence + 1:]", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(input, C):\n # Initialize variables to track the first and last occurrence indices\n first, last = -1, -1\n \n # Loop through the string to find the first and last occurrences of the character\n for i in range(len(input)):\n if input[i] == C:\n if first == -1:\n first = i\n last = i\n \n # If the character is not found in the string, return the original string\n if first == -1:\n return input\n \n # Return the string with the first and last occurrences of the character removed\n return input[:first] + input[first+1:last] + input[last+1:]", "matching_cluster_idx": 0}, {"solution": "def remove_Occ(my_str, S):\n # Find the first occurrence of the character and remove it\n first_occ = my_str.find(S)\n if first_occ != -1:\n my_str = my_str[:first_occ] + my_str[first_occ + 1:]\n \n # Find the last occurrence of the character and remove it\n last_occ = my_str.rfind(S)\n if last_occ != -1:\n my_str = my_str[:last_occ] + my_str[last_occ + 1:]\n \n return my_str", "matching_cluster_idx": 7}, {"solution": "def remove_Occ(string, character):\n # Find the index of the first occurrence of the character\n l = string.find(character)\n \n # Remove the first occurrence\n if l != -1:\n string = string[:l] + string[l+1:]\n \n # Find the index of the last occurrence of the character\n l = string.rfind(character)\n \n # Remove the last occurrence if it exists\n if l != -1:\n string = string[:l] + string[l+1:]\n \n return string", "matching_cluster_idx": 7}, {"solution": "def remove_Occ(string, char):\n # Find the first occurrence of the character\n first_index = string.find(char)\n \n # Find the last occurrence of the character\n last_index = string.rfind(char)\n \n # Return the string with the first and last occurrence removed\n if first_index != -1:\n return string[:first_index] + string[first_index + 1:last_index] + string[last_index + 1:]\n return string", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(string, s):\n # Initialize counters for the first and last occurrence\n first = -1\n last = -1\n i = 0\n \n # Find the first occurrence of the character\n while i < len(string):\n if string[i] == s:\n first = i\n break\n i += 1\n \n i = 0\n \n # Find the last occurrence of the character\n while i < len(string):\n if string[i] == s:\n last = i\n i += 1\n \n # If the character was found, remove it from the first and last occurrence\n if first != -1:\n string = string[:first] + string[first + 1:]\n if last != first:\n string = string[:last - 1] + string[last:]\n \n return string", "matching_cluster_idx": -1}, {"solution": "def remove_Occ(s, ch):\n # Check if the character exists in the string and remove the first occurrence\n if ch in s:\n s = s.replace(ch, \"\", 1)\n \n # Check if the character still exists in the string and remove the last occurrence\n if ch in s:\n s = s[::-1].replace(ch, \"\", 1)[::-1]\n \n return s", "matching_cluster_idx": 4}, {"solution": "def remove_Occ(string, char):\n # Remove the first occurrence of the character\n string = string.replace(char, \"\", 1)\n # Remove the last occurrence of the character\n string = string[::-1].replace(char, \"\", 1)[::-1]\n return string", "matching_cluster_idx": 4}, {"solution": "def remove_Occ(str1, char):\n # Find the first occurrence of the character and remove it\n first_occurrence = str1.find(char)\n if first_occurrence != -1:\n str1 = str1[:first_occurrence] + str1[first_occurrence + 1:]\n \n # Find the last occurrence of the character and remove it\n last_occurrence = str1.rfind(char)\n if last_occurrence != -1:\n str1 = str1[:last_occurrence] + str1[last_occurrence + 1:]\n \n return str1", "matching_cluster_idx": 7}, {"solution": "def remove_Occ(arr, ch):\n # Loop through the string to remove the first occurrence\n for i in range(len(arr)):\n if arr[i] == ch:\n arr = arr[:i] + arr[i + 1:]\n break\n \n # Loop through the string in reverse to remove the last occurrence\n for i in range(len(arr) - 1, -1, -1):\n if arr[i] == ch:\n arr = arr[:i] + arr[i + 1:]\n break\n \n return arr", "matching_cluster_idx": 7}, {"solution": "def remove_Occ(s, ch):\n # Find the first occurrence of the character and remove it\n s = s.replace(ch, '', 1)\n # Find the last occurrence of the character and remove it\n s = s[::-1].replace(ch, '', 1)[::-1]\n return s", "matching_cluster_idx": 4}, {"solution": "def remove_Occ(string, char):\n # Count the number of occurrences of the character\n num_occ = string.count(char)\n \n # If the character is not found, return the original string\n if num_occ == 0:\n return string\n \n # Remove the first occurrence of the character\n for i in range(len(string)):\n if string[i] == char:\n string = string[:i] + string[i+1:]\n break\n \n # Remove the last occurrence of the character\n for i in range(len(string) - 1, -1, -1):\n if string[i] == char:\n string = string[:i] + string[i+1:]\n break\n \n return string", "matching_cluster_idx": 5}, {"solution": "def remove_Occ(S, C):\n # Find the first occurrence of the character C in the string S\n f_idx = S.find(C)\n # If the character is found, remove the first occurrence by slicing\n if f_idx != -1:\n S = S[:f_idx] + S[f_idx + 1:]\n \n # Find the last occurrence of the character C in the string S\n l_idx = S.rfind(C)\n # If the character is found, remove the last occurrence by slicing\n if l_idx != -1:\n S = S[:l_idx] + S[l_idx + 1:]\n \n # Return the modified string without the first and last occurrence of the character\n return S", "matching_cluster_idx": 7}, {"solution": "def remove_Occ(string, character):\n # Find the index of the first occurrence of the character\n first_occurrence = string.find(character)\n \n # If the character is found, remove the first occurrence\n if first_occurrence != -1:\n string = string[:first_occurrence] + string[first_occurrence + 1:]\n \n # Find the index of the last occurrence of the character\n last_occurrence = string.rfind(character)\n \n # If the character is found, remove the last occurrence\n if last_occurrence != -1:\n string = string[:last_occurrence] + string[last_occurrence + 1:]\n \n return string", "matching_cluster_idx": 7}, {"solution": "def remove_Occ(string, char):\n # Get the first index of the character\n first = string.find(char)\n if first != -1:\n string = string[:first] + string[first + 1:]\n \n # Get the last index of the character\n last = string.rfind(char)\n if last != -1:\n string = string[:last] + string[last + 1:]\n \n return string", "matching_cluster_idx": 7}, {"solution": "def remove_Occ(s, c):\n # Find the index of the first occurrence of the character\n f = s.find(c)\n # If the character is not found, return the original string\n if f == -1:\n return s\n # Remove the first occurrence by slicing the string\n s = s[:f] + s[f+1:]\n # Find the index of the last occurrence of the character\n l = s.rfind(c)\n # If the character is not found, return the string without the first occurrence\n if l == -1:\n return s\n # Remove the last occurrence by slicing the string\n return s[:l] + s[l+1:]", "matching_cluster_idx": 7}, {"solution": "def remove_Occ(text, C):\n # Check if the character is present in the string\n if C in text:\n # Remove the first occurrence of the character\n text = text.replace(C, \"\", 1)\n # Remove the last occurrence of the character\n text = text[::-1].replace(C, \"\", 1)[::-1]\n # Return the modified string\n return text", "matching_cluster_idx": 4}, {"solution": "def remove_Occ(string, character):\n # Iterate over the string to remove the first occurrence\n for i in range(len(string)):\n if string[i] == character:\n string = string[:i] + string[i + 1:]\n break\n # Iterate from the end to remove the last occurrence\n for i in range(len(string) - 1, -1, -1):\n if string[i] == character:\n string = string[:i] + string[i + 1:]\n break\n return string", "matching_cluster_idx": 7}, {"solution": "def remove_Occ(s, character):\n # Convert the string into a list of characters\n new_str = list(s)\n \n # Initialize flags for finding the first and last occurrences\n first_occurrence = -1\n last_occurrence = -1\n \n # Iterate over the list to find the first and last occurrences of the character\n for i in range(len(new_str)):\n if new_str[i] == character:\n if first_occurrence == -1:\n first_occurrence = i\n last_occurrence = i\n \n # If the character is not found, return the original string\n if first_occurrence == -1:\n return s\n \n # Remove the first and last occurrence of the character\n new_str.pop(first_occurrence)\n if first_occurrence != last_occurrence:\n new_str.pop(last_occurrence - 1)\n \n # Convert the list back to a string and return it\n return ''.join(new_str)", "matching_cluster_idx": 0}]}, "Mbpp/12": {"dps": 95.08086253369272, "dps_norm": 95.9375, "pass@1": 97.0, "profiled": [{"solution": "def sort_matrix(matrix):\n # Sort the matrix rows based on their sum in ascending order\n matrix.sort(key=sum)\n return matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(arr):\n # Sort the matrix by the sum of rows in ascending order\n return sorted(arr, key=sum)", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(mat):\n # Sort the matrix based on the sum of rows using the sorted function with a custom key\n return sorted(mat, key=sum)", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Sort the matrix rows based on the sum of elements in each row\n return sorted(matrix, key=lambda x: sum(x))", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Sort the matrix in place based on the sum of the rows\n matrix.sort(key=lambda row: sum(row))\n return matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(mat):\n # Sort the matrix rows based on the sum of their elements in ascending order\n mat.sort(key=sum)\n return mat", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(mat):\n # Sort the matrix based on the sum of rows using a lambda function as the key\n # lambda x: sum(x) sorts the rows by their sum in ascending order\n mat.sort(key=lambda x: sum(x))\n return mat", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(mat):\n # Sort the matrix rows based on the sum of their elements\n sorted_mat = sorted(mat, key=sum)\n return sorted_mat", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Sort the matrix based on the sum of rows\n return sorted(matrix, key=sum)", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(mat):\n # Sort the matrix based on the sum of its rows using a lambda function\n return sorted(mat, key=lambda x: sum(x))", "matching_cluster_idx": 15}, {"solution": "from copy import deepcopy\ndef sort_matrix(matrix):\n # Creating a deep copy of the matrix to avoid modifying the original matrix\n sorted_matrix = deepcopy(matrix)\n \n # Sorting the matrix based on the sum of each row in ascending order\n sorted_matrix.sort(key=sum)\n \n return sorted_matrix", "matching_cluster_idx": 2}, {"solution": "def sort_matrix(mat):\n # Sort the matrix based on the sum of its rows in ascending order\n return sorted(mat, key=lambda x: sum(x))", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(mat):\n # Sort the matrix based on the sum of rows using a lambda function as the key\n # The sorted function returns the matrix sorted in ascending order of row sums\n return sorted(mat, key=lambda row: sum(row))", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Sort the matrix based on the sum of each row\n matrix.sort(key=sum)\n return matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(m):\n # Sort the matrix based on the sum of the rows\n return sorted(m, key=sum)", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(mat):\n # Sort the matrix based on the sum of its rows\n mat.sort(key=sum)\n return mat", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Sort the matrix rows based on the sum of elements in each row\n sorted_matrix = sorted(matrix, key=lambda x: sum(x))\n return sorted_matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(A):\n # Sort the matrix rows based on their sum\n return sorted(A, key=sum)", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(mat):\n # Sort the matrix based on the sum of its rows using the sorted function\n sorted_mat = sorted(mat, key=sum)\n return sorted_mat", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(mat):\n # Sort the matrix based on the sum of each row\n result = sorted(mat, key=lambda x: sum(x))\n return result", "matching_cluster_idx": 15}]}, "Mbpp/16": {"dps": null, "dps_norm": null, "pass@1": 4.0, "profiled": []}, "Mbpp/19": {"dps": 75.60606060606061, "dps_norm": 86.33333333333333, "pass@1": 100.0, "profiled": [{"solution": "def test_duplicate(nums):\n # Create an empty set to store unique elements\n num_set = set()\n \n # Iterate through each element in the array\n for num in nums:\n # Check if the element is already in the set\n if num in num_set:\n # If found, return True indicating a duplicate exists\n return True\n # Add the element to the set if not already present\n num_set.add(num)\n \n # If no duplicates are found, return False\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(lst):\n # Create a set to store unique elements\n unique = set()\n \n # Iterate through each number in the list\n for n in lst:\n # Check if the number is already in the set\n if n in unique:\n return True # Duplicate found\n # Add the number to the set\n unique.add(n)\n return False # No duplicates found", "matching_cluster_idx": 14}, {"solution": "from copy import deepcopy\ndef test_duplicate(nums):\n # Check if the list is empty or has only one element\n if len(nums) <= 1:\n return False\n \n # Create a copy of the list to work with\n numsCopy = deepcopy(nums)\n \n # Sort the copied list\n numsCopy.sort()\n \n # Iterate through the sorted list to find duplicates\n for i in range(len(numsCopy) - 1):\n if numsCopy[i] == numsCopy[i + 1]:\n return True\n \n # Return False if no duplicates are found\n return False", "matching_cluster_idx": 1}, {"solution": "def test_duplicate(nums):\n # Initialize an empty list to keep track of seen elements\n seen = []\n \n # Iterate through each element in the input list\n for i in nums:\n # Check if the current element is already in the seen list\n if i in seen:\n return True\n # If not, add the current element to the seen list\n seen.append(i)\n \n # If no duplicates are found, return False\n return False", "matching_cluster_idx": 12}, {"solution": "def test_duplicate(array_nums):\n # Check if the array has any duplicate elements\n return len(array_nums) != len(set(array_nums))", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(nums):\n # Convert the list to a set to remove duplicates and compare lengths\n return len(nums) != len(set(nums))", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(array_nums):\n # Create a set to store unique elements\n unique_nums = set()\n \n # Iterate through each number in the input array\n for x in array_nums:\n # If the number is already in the set, it's a duplicate\n if x in unique_nums:\n return True\n # Otherwise, add the number to the set\n unique_nums.add(x)\n \n # If no duplicates are found, return False\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(lst):\n # Create a set from the list to remove duplicates and compare its length to the original list\n return len(lst) > len(set(lst))", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(array_nums):\n # Convert the list to a set to remove duplicates and compare lengths\n unique_nums = set(array_nums)\n return len(array_nums) != len(unique_nums)", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(nums):\n # Convert the array to a set to remove duplicates and compare its length to the original array\n return len(nums) != len(set(nums))", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(arr):\n # Use a set to track unique elements\n my_set = set()\n # Iterate through each element in the array\n for i in arr:\n # Check if the element is already in the set\n if i in my_set:\n return True # Duplicate found\n else:\n my_set.add(i) # Add element to the set\n return False # No duplicates found", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(arr):\n # Create a set to store unique elements\n seen = set()\n \n # Iterate through each element in the array\n for i in arr:\n # Check if the element is already in the set\n if i in seen:\n return True # Duplicate found\n seen.add(i) # Add the element to the set\n return False # No duplicates found", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(nums):\n # Create a set to store unique elements\n u = set()\n # Iterate through each number in the array\n for n in nums:\n # Check if the number is already in the set\n if n in u:\n # If found, return True indicating a duplicate exists\n return True\n else:\n # If not found, add the number to the set\n u.add(n)\n # If the loop completes, return False indicating no duplicates\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(nums):\n # Create a set to store unique elements encountered in the array\n set_nums = set()\n \n # Iterate through each number in the input list\n for num in nums:\n # Check if the number is already in the set\n if num in set_nums:\n # If found, return True indicating a duplicate exists\n return True\n else:\n # If not found, add the number to the set\n set_nums.add(num)\n \n # If no duplicates are found, return False\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(array_nums):\n # Create a dictionary to track the occurrences of each number\n num_dictionary = {}\n \n # Iterate through the array to populate the dictionary\n for num in array_nums:\n if num not in num_dictionary:\n num_dictionary[num] = 1\n else:\n # If the number is already in the dictionary, return True\n return True\n \n # If no duplicates are found, return False\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(test_list):\n # Initialize an empty set to keep track of seen elements\n seen = set()\n \n # Iterate through each element in the test list\n for ele in test_list:\n # Check if the element is already in the seen set\n if ele in seen:\n # If found, return True indicating a duplicate\n return True\n # If not found, add the element to the seen set\n seen.add(ele)\n \n # If no duplicates are found, return False\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(array_nums):\n # Convert the array to a set to remove duplicates and compare lengths\n return len(array_nums) > len(set(array_nums))", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(arr):\n # Create an empty set to store unique elements\n unique_elements = set()\n \n # Iterate through each element in the array\n for i in range(len(arr)):\n # Check if the element is already in the set\n if arr[i] in unique_elements:\n # If found, return True indicating a duplicate\n return True\n # Add the element to the set\n unique_elements.add(arr[i])\n \n # If no duplicates found, return False\n return False", "matching_cluster_idx": 13}, {"solution": "def test_duplicate(arr):\n # Convert the array to a set to remove duplicates\n array = list(set(arr))\n \n # Compare the length of the set with the original array\n if len(array) != len(arr):\n return True # Duplicates exist\n else:\n return False # No duplicates", "matching_cluster_idx": 10}, {"solution": "def test_duplicate(nums):\n # Convert the list to a set to remove duplicates and compare lengths\n return len(set(nums)) != len(nums)", "matching_cluster_idx": 11}]}, "Mbpp/62": {"dps": 79.46153846153847, "dps_norm": 86.0, "pass@1": 100.0, "profiled": [{"solution": "def smallest_num(list_num):\n # Using the min function to find the smallest number in the list\n minimum = min(list_num)\n return minimum", "matching_cluster_idx": 4}, {"solution": "def smallest_num(numbers):\n # Initialize the smallest number to a very large positive value\n smallest = float('inf')\n # Iterate through each number in the list\n for num in numbers:\n # Update the smallest number if a smaller number is found\n if num < smallest:\n smallest = num\n # Return the smallest number found\n return smallest", "matching_cluster_idx": 3}, {"solution": "def smallest_num(list1):\n # Find and return the smallest number in the list using min() function\n return min(list1)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(numbers):\n # Use the built-in min function to find and return the smallest number in the list\n return min(numbers)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(list1):\n # Initialize the smallest number with the first element of the list\n smallest_num = list1[0]\n \n # Iterate through each number in the list\n for i in list1:\n # Update the smallest number if the current number is smaller\n if i < smallest_num:\n smallest_num = i\n \n # Return the smallest number found\n return smallest_num", "matching_cluster_idx": 3}, {"solution": "def smallest_num(list1):\n # Return the minimum value from the list using the built-in min() function\n return min(list1)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(nums):\n # Return the smallest number in the list using the built-in min function\n return min(nums)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(numbers):\n # Initialize the smallest number as the first element of the list\n smallest = numbers[0]\n # Iterate over each number in the list\n for num in numbers:\n # Update the smallest number if the current number is smaller\n if num < smallest:\n smallest = num\n # Return the smallest number found\n return smallest", "matching_cluster_idx": 3}, {"solution": "def smallest_num(nums):\n # Initialize the smallest number with the first element of the list\n smallest_num = nums[0]\n \n # Iterate through each number in the list\n for x in nums:\n # Update the smallest number if the current number is smaller\n if x < smallest_num:\n smallest_num = x\n \n # Return the smallest number found\n return smallest_num", "matching_cluster_idx": 3}, {"solution": "def smallest_num(list1):\n # Initialize the smallest number to the first element in the list\n smallest = list1[0]\n \n # Iterate over each number in the list\n for x in list1:\n # Update the smallest number if the current number is smaller\n if x < smallest:\n smallest = x\n \n # Return the smallest number found\n return smallest", "matching_cluster_idx": 3}, {"solution": "def smallest_num(list1):\n # Find and return the minimum number in the list\n small = min(list1)\n return small", "matching_cluster_idx": 4}, {"solution": "def smallest_num(list1):\n # Check if the list is empty\n if not list1:\n return None # Return None for empty list\n \n # Initialize the smallest number with the first element of the list\n min = list1[0]\n \n # Iterate through the list starting from the second element\n for x in list1:\n # Update the smallest number if a smaller element is found\n if x < min:\n min = x\n \n # Return the smallest number found\n return min", "matching_cluster_idx": 3}, {"solution": "def smallest_num(list1):\n # Initialize the smallest number with the first element of the list\n smallest = list1[0]\n # Iterate through the list\n for x in list1:\n # Update the smallest number if a smaller number is found\n if x < smallest:\n smallest = x\n return smallest", "matching_cluster_idx": 3}, {"solution": "def smallest_num(list1):\n # Find the smallest number in the list using the min() function\n min_num = min(list1)\n return min_num", "matching_cluster_idx": 4}, {"solution": "def smallest_num(numbers):\n # Use the built-in min() function to find the smallest number in the list\n return min(numbers)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(list1):\n # Use the min() function to find and return the smallest number in the list\n return min(list1)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(numbers):\n # Use the min() function to find the smallest number in the list\n return min(numbers)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(list1):\n # Initialize the minimum number with the first element of the list\n min1 = list1[0]\n # Iterate through the list starting from the second element\n for x in list1:\n # Update the minimum number if a smaller element is found\n if x < min1:\n min1 = x\n # Return the smallest number found\n return min1", "matching_cluster_idx": 3}, {"solution": "def smallest_num(list1):\n # Initialize the smallest number with the first element of the list\n small_num = list1[0]\n \n # Iterate through each number in the list\n for i in range(len(list1)):\n # Update the smallest number if the current number is smaller\n if list1[i] < small_num:\n small_num = list1[i]\n \n # Return the smallest number found\n return small_num", "matching_cluster_idx": 1}, {"solution": "def smallest_num(numbers):\n # Initialize the smallest number with the first element of the list\n min_num = numbers[0]\n \n # Iterate through the list starting from the second element\n for i in range(1, len(numbers)):\n # Update the smallest number if a smaller number is found\n if numbers[i] < min_num:\n min_num = numbers[i]\n \n # Return the smallest number found\n return min_num", "matching_cluster_idx": 1}]}, "Mbpp/75": {"dps": 92.85714285714286, "dps_norm": 66.66666666666667, "pass@1": 100.0, "profiled": [{"solution": "def find_tuples(test_list, K):\n # Use a list comprehension to filter tuples\n res = [tuple_val for tuple_val in test_list if all(ele % K == 0 for ele in tuple_val)]\n return res", "matching_cluster_idx": 5}, {"solution": "def find_tuples(test_list, K):\n # Use list comprehension to filter tuples\n # Check if all elements in the tuple are divisible by K using all() and modulo operation\n res = [sub for sub in test_list if all(ele % K == 0 for ele in sub)]\n return res", "matching_cluster_idx": 5}, {"solution": "def find_tuples(test_list, K):\n # Filter tuples to include only those where all elements are divisible by K\n res = [tuple for tuple in test_list if all(i % K == 0 for i in tuple)]\n return res", "matching_cluster_idx": 5}, {"solution": "def find_tuples(test_list, K):\n # Use list comprehension to filter tuples\n res = [ele for ele in test_list if all(x % K == 0 for x in ele)]\n return res", "matching_cluster_idx": 5}, {"solution": "def find_tuples(test_list, K):\n # Use list comprehension to filter tuples\n res = [ele for ele in test_list if all(ele % K == 0 for ele in ele)]\n return res", "matching_cluster_idx": 5}, {"solution": "def find_tuples(test_list, K):\n # Use list comprehension to filter tuples\n res = [tu for tu in test_list if all(ele % K == 0 for ele in tu)]\n return res", "matching_cluster_idx": 5}, {"solution": "def find_tuples(lst, K):\n # Filter the list of tuples and retain only those where all elements are divisible by K\n result = [tuple_ for tuple_ in lst if all(num % K == 0 for num in tuple_)]\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(test_list, K):\n # Initialize an empty list to store tuples with all elements divisible by K\n res = []\n \n # Iterate through each tuple in the test list\n for sub in test_list:\n # Check if all elements in the tuple are divisible by K\n if all(ele % K == 0 for ele in sub):\n # If condition is satisfied, add the tuple to the result list\n res.append(sub)\n \n # Return the list of tuples with all elements divisible by K\n return res", "matching_cluster_idx": 5}, {"solution": "def find_tuples(test_list, K):\n # Initialize an empty list to store tuples with all elements divisible by K\n res = []\n \n # Iterate over each tuple in the test list\n for ele in test_list:\n # Check if all elements in the tuple are divisible by K\n if all(i % K == 0 for i in ele):\n # If yes, add the tuple to the result list\n res.append(ele)\n \n # Return the list of tuples\n return res", "matching_cluster_idx": 5}, {"solution": "def find_tuples(test_list, K):\n # Filter tuples in the list where all elements are divisible by K\n res = [ele for ele in test_list if all(x % K == 0 for x in ele)]\n return res", "matching_cluster_idx": 5}, {"solution": "def find_tuples(test_list, K):\n # Filter tuples where all elements are divisible by K using a list comprehension\n res = [tup for tup in test_list if all(ele % K == 0 for ele in tup)]\n return res", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tup1, K):\n # Use a list comprehension to filter tuples\n res = [tup for tup in tup1 if all(ele % K == 0 for ele in tup)]\n return res", "matching_cluster_idx": 5}, {"solution": "def find_tuples(lst, divisor):\n # Filter tuples to find those where all elements are divisible by the divisor\n result = [t for t in lst if all(x % divisor == 0 for x in t)]\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(test_list, K):\n # Use list comprehension to filter tuples\n # Check if all elements in the tuple are divisible by K\n res = [tup for tup in test_list if all(ele % K == 0 for ele in tup)]\n return res", "matching_cluster_idx": 5}, {"solution": "def find_tuples(nums, k):\n # Use list comprehension to filter tuples\n # Check if all elements in the tuple are divisible by k\n result = [t for t in nums if all(x % k == 0 for x in t)]\n return result", "matching_cluster_idx": 5}, {"solution": "from itertools import product\ndef find_tuples(test_list, K):\n # Filter tuples where all elements are divisible by K\n res = [tuple for tuple in test_list if all(ele % K == 0 for ele in tuple)]\n return res", "matching_cluster_idx": 5}, {"solution": "def find_tuples(test_list, N):\n # Use list comprehension to filter tuples where all elements are divisible by N\n res = [tuple_val for tuple_val in test_list if all(ele % N == 0 for ele in tuple_val)]\n return res", "matching_cluster_idx": 5}, {"solution": "def find_tuples(test_list, divisor):\n # Use list comprehension to filter tuples\n # Each tuple must have all elements divisible by the divisor\n res = [tuple for tuple in test_list if all(element % divisor == 0 for element in tuple)]\n return res", "matching_cluster_idx": 5}, {"solution": "def find_tuples(test_list, K):\n # Filter tuples where all elements are divisible by K using list comprehension\n res = [el for el in test_list if all(ele % K == 0 for ele in el)]\n return res", "matching_cluster_idx": 5}, {"solution": "def find_tuples(test_list, K):\n # Filter tuples where all elements are divisible by K\n res = [sub for sub in test_list if all(ele % K == 0 for ele in sub)]\n return res", "matching_cluster_idx": 5}]}, "Mbpp/88": {"dps": 78.11274509803921, "dps_norm": 77.85714285714285, "pass@1": 99.0, "profiled": [{"solution": "def freq_count(test_list):\n # Initialize an empty dictionary to store element frequencies\n freq_dict = {}\n \n # Iterate over each element in the list\n for ele in test_list:\n # If the element is already in the dictionary, increment its count\n if ele in freq_dict:\n freq_dict[ele] += 1\n # If the element is not in the dictionary, add it with a count of 1\n else:\n freq_dict[ele] = 1\n \n # Return the dictionary containing element frequencies\n return freq_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(numbers):\n # Initialize an empty dictionary to store element frequencies\n freq_dictionary = {}\n \n # Iterate through each number in the list\n for number in numbers:\n # Check if the number is already in the dictionary\n if number in freq_dictionary:\n # If yes, increment its count\n freq_dictionary[number] += 1\n else:\n # If no, add the number to the dictionary with count 1\n freq_dictionary[number] = 1\n \n # Return the dictionary containing frequencies of all elements\n return freq_dictionary", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n # Create a dictionary to store the frequency of each element\n freq_dict = {}\n \n # Iterate through each element in the list\n for item in lst:\n # If the element is already in the dictionary, increment its count\n if item in freq_dict:\n freq_dict[item] += 1\n # If the element is not in the dictionary, add it with a count of 1\n else:\n freq_dict[item] = 1\n \n # Return the dictionary containing element frequencies\n return freq_dict", "matching_cluster_idx": 5}, {"solution": "from collections import defaultdict\ndef freq_count(test_list):\n # Initialize a default dictionary to store frequencies\n res = defaultdict(int)\n \n # Iterate over each element in the list\n for ele in test_list:\n # Increment the count of the element in the dictionary\n res[ele] += 1\n \n return dict(res)", "matching_cluster_idx": 3}, {"solution": "def freq_count(arr):\n # Initialize an empty dictionary to store the frequency of elements\n frequency = {}\n \n # Iterate over each element in the array\n for element in arr:\n # If the element is already in the dictionary, increment its count\n if element in frequency:\n frequency[element] += 1\n # If the element is not in the dictionary, add it with a count of 1\n else:\n frequency[element] = 1\n \n # Return the dictionary containing the frequency of all elements\n return frequency", "matching_cluster_idx": 5}, {"solution": "def freq_count(test_list):\n # Use a dictionary comprehension to count the frequency of each element\n res = {key: test_list.count(key) for key in set(test_list)}\n return res", "matching_cluster_idx": 2}, {"solution": "def freq_count(arr):\n # Initialize an empty dictionary to store frequencies\n frequency = {}\n \n # Iterate over each element in the array\n for num in arr:\n # If the element is already in the dictionary, increment its count\n if num in frequency:\n frequency[num] += 1\n # If the element is not in the dictionary, add it with a count of 1\n else:\n frequency[num] = 1\n \n # Return the dictionary containing elements and their frequencies\n return frequency", "matching_cluster_idx": 5}, {"solution": "def freq_count(items):\n # Use a dictionary comprehension to count occurrences of each item\n return {i: items.count(i) for i in items}", "matching_cluster_idx": 0}, {"solution": "def freq_count(arr):\n # Initialize an empty dictionary to store the frequency of elements\n freq_dict = {}\n # Iterate over each element in the list\n for element in arr:\n # If the element is already in the dictionary, increment its count\n if element in freq_dict:\n freq_dict[element] += 1\n # If the element is not in the dictionary, add it with a count of 1\n else:\n freq_dict[element] = 1\n # Return the dictionary containing the frequency of each element\n return freq_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(test_list):\n # Initialize an empty dictionary to store the frequency of elements\n res = {}\n \n # Iterate over each element in the list\n for ele in test_list:\n # If the element is already in the dictionary, increment its count\n if ele in res:\n res[ele] += 1\n # If the element is not in the dictionary, add it with a count of 1\n else:\n res[ele] = 1\n \n # Return the dictionary containing element frequencies\n return res", "matching_cluster_idx": 5}, {"solution": "def freq_count(A):\n # Create a dictionary to store the frequency of each element\n freqDict = {}\n # Iterate over each element in the list\n for i in A:\n # Increment the count of the element in the dictionary\n freqDict[i] = freqDict.get(i, 0) + 1\n # Return the frequency dictionary\n return freqDict", "matching_cluster_idx": 4}, {"solution": "def freq_count(my_list):\n # Initialize an empty dictionary to store the frequency of elements\n my_dict = {}\n \n # Iterate through each element in the list\n for i in my_list:\n # Check if the element is already a key in the dictionary\n if i in my_dict:\n # Increment the frequency of the element\n my_dict[i] += 1\n else:\n # Add the element to the dictionary with a frequency of 1\n my_dict[i] = 1\n \n # Return the dictionary containing the frequency of all elements\n return my_dict", "matching_cluster_idx": 5}, {"solution": "from collections import Counter\ndef freq_count(my_list):\n # Using Counter to count the frequency of each element in the list\n return dict(Counter(my_list))", "matching_cluster_idx": 6}, {"solution": "def freq_count(test_list):\n # Initialize an empty dictionary to store the frequency of elements\n freq_dict = {}\n \n # Iterate over each element in the list\n for ele in test_list:\n # If the element is already in the dictionary, increment its count\n if ele in freq_dict:\n freq_dict[ele] += 1\n # If the element is not in the dictionary, add it with a count of 1\n else:\n freq_dict[ele] = 1\n \n # Return the dictionary containing the frequency of elements\n return freq_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n # Initialize an empty dictionary to store the frequency of each element\n freq = {}\n \n # Iterate through each element in the list\n for i in lst:\n # If the element is already in the dictionary, increment its count\n if i in freq:\n freq[i] += 1\n # If the element is not in the dictionary, add it with a count of 1\n else:\n freq[i] = 1\n \n # Return the dictionary containing the frequency of each element\n return freq", "matching_cluster_idx": 5}, {"solution": "def freq_count(test_list):\n # Initialize an empty dictionary to store the frequency of each element\n res = dict()\n \n # Iterate through each element in the input list\n for ele in test_list:\n # If the element is already in the dictionary, increment its count\n if ele in res:\n res[ele] += 1\n # If the element is not in the dictionary, add it with a count of 1\n else:\n res[ele] = 1\n \n # Return the dictionary containing the frequency of each element\n return res", "matching_cluster_idx": 5}, {"solution": "def freq_count(input_list):\n # Dictionary to store the frequency of each element\n res = {}\n \n # Iterate through each element in the input list\n for ele in input_list:\n # Increment the count of the element in the dictionary\n res[ele] = res.get(ele, 0) + 1\n \n # Return the dictionary containing frequencies of all elements\n return res", "matching_cluster_idx": 4}, {"solution": "def freq_count(input_list):\n # Initialize an empty dictionary to store element frequencies\n freqs = {}\n \n # Iterate over each element in the input list\n for element in input_list:\n # If the element is already in the dictionary, increment its count\n if element in freqs:\n freqs[element] += 1\n # If the element is not in the dictionary, add it with a count of 1\n else:\n freqs[element] = 1\n \n # Return the dictionary containing frequencies of all elements\n return freqs", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n # Create a dictionary to store the frequency of each element\n freq_dict = {}\n \n # Iterate through each element in the list\n for element in lst:\n # If the element is already in the dictionary, increment its count\n if element in freq_dict:\n freq_dict[element] += 1\n # Otherwise, add the element to the dictionary with a count of 1\n else:\n freq_dict[element] = 1\n \n # Return the dictionary containing the frequencies\n return freq_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(nums):\n # Create an empty dictionary to store the frequency of each element\n frequency = {}\n \n # Iterate over each element in the list\n for num in nums:\n # If the element is already in the dictionary, increment its count\n if num in frequency:\n frequency[num] += 1\n # If the element is not in the dictionary, add it with a count of 1\n else:\n frequency[num] = 1\n \n # Return the dictionary containing the frequency of each element\n return frequency", "matching_cluster_idx": 5}]}, "Mbpp/90": {"dps": 74.3658536585366, "dps_norm": 85.0, "pass@1": 95.0, "profiled": [{"solution": "def len_log(str_list):\n # Use the max function with key=str len to find the longest word\n max_len = max(str_list, key=len)\n # Return the length of the longest word\n return len(max_len)", "matching_cluster_idx": 6}, {"solution": "def len_log(words):\n # Use the max function with a key argument to find the longest word's length\n return len(max(words, key=len))", "matching_cluster_idx": 6}, {"solution": "def len_log(str1):\n # Calculate the maximum length of words in the list using a generator expression\n longest_word_length = max(len(word) for word in str1)\n return longest_word_length", "matching_cluster_idx": 5}, {"solution": "from operator import itemgetter\ndef len_log(words):\n # Use a generator expression to get the lengths of the words\n word_lengths = ((len(word), word) for word in words)\n # Sort the items by length and take the length of the longest word\n max_length = max(word_lengths, key=itemgetter(0))[0]\n return max_length", "matching_cluster_idx": 3}, {"solution": "def len_log(list):\n # Check if the list is empty\n if len(list) == 0:\n return 0\n \n # Initialize the maximum length with the length of the first word\n max_length = len(list[0])\n \n # Iterate over each word in the list\n for i in range(1, len(list)):\n # Update max_length if the current word's length is greater\n if len(list[i]) > max_length:\n max_length = len(list[i])\n \n # Return the maximum length found\n return max_length", "matching_cluster_idx": 4}, {"solution": "def len_log(words):\n # Find the length of the longest word in the list\n max_length = max(len(word) for word in words)\n return max_length", "matching_cluster_idx": 5}, {"solution": "def len_log(strings):\n # Initialize the longest string length variable with a value less than the length of the shortest possible string\n longest = -1\n # Iterate through each string in the list\n for s in strings:\n # Update the longest string length if the current string is longer\n if len(s) > longest:\n longest = len(s)\n # Return the length of the longest string found\n return longest", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n # Find the length of the longest word using the max function with a key function that returns the length of each word\n return len(max(words, key=len))", "matching_cluster_idx": 6}, {"solution": "def len_log(texts):\n # Find the maximum length of words in the list 'texts'\n return max(len(x) for x in texts)", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n # Find the maximum length of words in the list\n max_length = max(len(word) for word in words)\n return max_length", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n # Find the length of the longest word in the list using a generator expression\n max_length = max(len(word) for word in words)\n return max_length", "matching_cluster_idx": 5}, {"solution": "def len_log(str):\n # Initialize the length of the longest word\n max_length = 0\n \n # Iterate through each word in the list\n for word in str:\n # Update the max_length if the current word's length is greater\n max_length = max(max_length, len(word))\n \n # Return the length of the longest word\n return max_length", "matching_cluster_idx": 2}, {"solution": "def len_log(words):\n # Find the maximum length of words in the list using the map function\n longest = max(map(len, words))\n return longest", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n # Use the max function with the key parameter set to len to find the longest word\n # Then, use the len function to return the length of the longest word\n return len(max(words, key=len))", "matching_cluster_idx": 6}, {"solution": "def len_log(words):\n # Initialize a variable to store the maximum word length found\n max_length = 0\n \n # Iterate through each word in the list\n for word in words:\n # Update max_length if the current word's length is greater\n if len(word) > max_length:\n max_length = len(word)\n \n # Return the maximum word length found\n return max_length", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n # Initialize max_length to the length of the first word\n max_length = len(words[0])\n # Iterate through each word in the list\n for word in words:\n # Update max_length if the current word is longer\n if len(word) > max_length:\n max_length = len(word)\n # Return the maximum length found\n return max_length", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n # Use a list comprehension to get the lengths of all words\n word_len = [len(word) for word in words]\n # Return the maximum length found\n return max(word_len)", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n # Use the max function with a key to find the length of the longest word\n return len(max(words, key=len))", "matching_cluster_idx": 6}, {"solution": "def len_log(words):\n # Use the map function to apply the len function to each word in the list\n # Then, find the maximum length using the max function\n return max(map(len, words))", "matching_cluster_idx": 5}, {"solution": "def len_log(string):\n # Use the max function to find the maximum length of words in the list\n # The key parameter specifies that the length of each word should be used for comparison\n return max(len(word) for word in string)", "matching_cluster_idx": 5}]}, "Mbpp/94": {"dps": 82.85060975609755, "dps_norm": 69.0, "pass@1": 94.0, "profiled": [{"solution": "def index_minimum(lst):\n # Find the minimum value among the second elements of the tuples\n min_val = min(lst, key=lambda x: x[1])[1]\n # Iterate through the list to find the first tuple with the minimum second value\n for i in lst:\n if i[1] == min_val:\n # Return the first element of the found tuple\n return i[0]", "matching_cluster_idx": 2}, {"solution": "from operator import itemgetter\ndef index_minimum(test_list):\n # Use the min function with key parameter set to itemgetter(1) to find the tuple with the smallest second value\n # Return the first value of that tuple\n res = min(test_list, key=itemgetter(1))[0]\n return res", "matching_cluster_idx": 4}, {"solution": "def index_minimum(test_list):\n # Use min function with key parameter to find the tuple with the smallest second value\n # and extract the first value of that tuple\n res = min(test_list, key=lambda x: x[1])[0]\n return res", "matching_cluster_idx": 2}, {"solution": "def index_minimum(test_list):\n # Using min function with key to find the tuple with the minimum second value\n res = min(test_list, key=lambda x: x[1])[0]\n return res", "matching_cluster_idx": 2}, {"solution": "def index_minimum(test_list):\n # Find the index of the tuple with the minimum second value\n res = min(test_list, key=lambda x: x[1])[0]\n return res", "matching_cluster_idx": 2}, {"solution": "def index_minimum(test_list):\n # Use the min function with a key to find the tuple with the minimum second element\n # Then return the first element of that tuple\n res = min(test_list, key=lambda x: x[1])[0]\n return res", "matching_cluster_idx": 2}, {"solution": "def index_minimum(test_list):\n # Using min function with key parameter to find the tuple with the smallest second element\n res = min(test_list, key=lambda x: x[1])[0]\n return res", "matching_cluster_idx": 2}, {"solution": "def index_minimum(list1):\n # Initialize a variable with infinity as a default value for comparison\n min_value = float('inf')\n # Variable to store the result\n small = 0\n # Iterate through the list of tuples\n for i, v in enumerate(list1):\n # Check if the second element of the tuple is less than the current minimum value\n if min_value > v[1]:\n min_value = v[1]\n small = v[0]\n return small", "matching_cluster_idx": 2}, {"solution": "def index_minimum(test_list):\n # The function uses the built-in min function along with a lambda function to\n # find the tuple with the smallest second element. The lambda function takes\n # a tuple and returns its second element for comparison. The min function returns\n # the tuple with the minimum value according to the second element.\n res = min(test_list, key=lambda x: x[1])\n # The first element of the tuple with the smallest second value is returned.\n return res[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(test_list):\n # Initialize the minimum value to a very high number and the corresponding index to -1\n min_val, min_ind = float('inf'), -1\n \n # Iterate over the list of tuples\n for ele in test_list:\n # Check if the current tuple's second value is smaller than the current minimum\n if ele[1] < min_val:\n min_val = ele[1] # Update the minimum value\n min_ind = ele[0] # Update the corresponding first value\n \n # Return the first value of the tuple with the smallest second value\n return min_ind", "matching_cluster_idx": 4}, {"solution": "from operator import itemgetter\ndef index_minimum(test_list):\n # Use the itemgetter function to sort the list of tuples based on the second item of each tuple\n # Then, extract the first element of the tuple with the smallest second item\n res = min(test_list, key=itemgetter(1))[0]\n return res", "matching_cluster_idx": 4}, {"solution": "def index_minimum(test_list):\n # Find the index of the minimum value in the second element of each tuple\n res = min(test_list, key=lambda x: x[1])[0]\n return res", "matching_cluster_idx": 2}, {"solution": "def index_minimum(test_list):\n # Using the min function with a key to find the tuple with the minimum second element\n # The index method then retrieves the first element of that tuple\n res = min(test_list, key=lambda x: x[1])[0]\n return res", "matching_cluster_idx": 2}, {"solution": "def index_minimum(test_list):\n # Find the index of the tuple with the minimum second element\n res = min(test_list, key=lambda x: x[1])[0]\n return res", "matching_cluster_idx": 2}, {"solution": "def index_minimum(test_list):\n # Find the tuple with the minimum second element\n res = min(test_list, key=lambda x: x[1])[0]\n return res", "matching_cluster_idx": 2}, {"solution": "from operator import itemgetter\ndef index_minimum(lst):\n # Using the min function with key=itemgetter(1) to find the tuple with the smallest second value\n # Then, accessing the first value of that tuple\n return min(lst, key=itemgetter(1))[0]", "matching_cluster_idx": 4}, {"solution": "def index_minimum(test_list):\n # Use the min function with a key to find the tuple with the smallest second value\n res = min(test_list, key=lambda ele: ele[1])\n # Return the first value of the found tuple\n return res[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(lst):\n # Use the key parameter of the min function to sort by the second item in each tuple\n return min(lst, key=lambda x: x[1])[0]", "matching_cluster_idx": 2}, {"solution": "from operator import itemgetter\ndef index_minimum(test_list):\n # Initialize min element and min value as None\n min_element = None\n min_value = None\n \n # Iterate through each element in the test list\n for ele in test_list:\n # Check if this is the first element or if the current element's second value is smaller\n if min_element is None or ele[1] < min_value:\n # Update the min element and min value\n min_element = ele\n min_value = ele[1]\n \n # Return the first value of the tuple with the smallest second value\n return min_element[0]", "matching_cluster_idx": 3}, {"solution": "def index_minimum(lst):\n # Use the min function with a key to find the tuple with the smallest second value\n # and then extract the first value of that tuple\n return min(lst, key=lambda x: x[1])[0]", "matching_cluster_idx": 2}]}, "Mbpp/96": {"dps": 81.1111111111111, "dps_norm": 51.42857142857142, "pass@1": 94.0, "profiled": [{"solution": "def divisor(n):\n # Initialize a counter for divisors\n count = 0\n \n # Iterate through potential divisors from 1 to n\n for i in range(1, n + 1):\n # Check if i is a divisor of n\n if n % i == 0:\n # If it is, increment the counter\n count += 1\n \n # Return the total count of divisors\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n # Initialize a counter for divisors\n res = 0\n \n # Iterate through numbers from 1 to n to check for divisors\n for i in range(1, n + 1):\n # If i divides n without a remainder, it is a divisor\n if n % i == 0:\n res += 1\n \n # Return the total count of divisors\n return res", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n \"\"\"\n Write a python function to find the number of divisors of a given integer.\n \n Args:\n n (int): The number to find the divisors of.\n \n Returns:\n int: The number of divisors of the given integer.\n \"\"\"\n # Initialize a counter for divisors\n count = 0\n \n # Iterate through possible divisors up to the square root of n\n for i in range(1, int(n ** 0.5) + 1):\n # If i is a divisor, increment the count\n if n % i == 0:\n count += 1\n \n # If i is not the square root of n, increment the count for the quotient\n if i != n // i:\n count += 1\n \n return count", "matching_cluster_idx": 6}, {"solution": "def divisor(n):\n # Initialize a counter for divisors\n count = 0\n # Loop through possible divisors\n for i in range(1, n + 1):\n # Check if i is a divisor of n\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n # Initialize a counter for divisors\n cnt = 0\n \n # Iterate through all possible divisors from 1 to n\n for i in range(1, n + 1):\n # Check if i is a divisor of n\n if (n % i == 0):\n # If it is, increment the divisor counter\n cnt += 1\n \n # Return the total count of divisors\n return cnt", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n \"\"\"\n Write a python function to find the number of divisors of a given integer.\n \n Args:\n n (int): The integer to find the divisors for.\n \n Returns:\n int: The number of divisors of the given integer.\n \n Examples:\n >>> divisor(15)\n 4\n \"\"\"\n count = 0 # Initialize the count of divisors\n for i in range(1, n + 1): # Iterate through numbers from 1 to n\n if n % i == 0: # Check if i is a divisor of n\n count += 1 # Increment the count if i is a divisor\n return count # Return the total count of divisors", "matching_cluster_idx": 2}, {"solution": "def divisor(num):\n # Initialize a counter for divisors\n total = 0\n \n # Iterate through all numbers from 1 to the square root of 'num'\n for i in range(1, int(num**0.5) + 1):\n # If 'i' is a divisor of 'num', increment the counter\n if num % i == 0:\n total += 1\n # If 'i' is not the square root of 'num', count the pair divisor\n if i != num // i:\n total += 1\n \n # Return the total number of divisors\n return total", "matching_cluster_idx": 6}, {"solution": "def divisor(n):\n # Initialize a counter for divisors\n divisor_count = 0\n \n # Iterate through all numbers from 1 to n\n for i in range(1, n + 1):\n # Check if i is a divisor of n\n if n % i == 0:\n # Increment the divisor count if i is a divisor\n divisor_count += 1\n \n # Return the total count of divisors\n return divisor_count", "matching_cluster_idx": 2}, {"solution": "def divisor(N):\n # Initialize a counter for divisors\n cnt = 0\n # Iterate over possible divisors up to the square root of N\n for i in range(1, int(N ** 0.5) + 1):\n # Check if i is a divisor of N\n if N % i == 0:\n # If i divides N, increment the count\n cnt += 1\n # If i and N/i are distinct, increment the count again\n if i != N // i:\n cnt += 1\n # Return the total number of divisors\n return cnt", "matching_cluster_idx": 6}, {"solution": "def divisor(n):\n # Initialize a counter to 0\n c = 0\n # Loop through numbers from 1 to n (inclusive)\n for i in range(1, n + 1):\n # Check if i is a divisor of n\n if n % i == 0:\n # Increment the counter if i is a divisor\n c += 1\n # Return the total count of divisors\n return c", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n # Initialize a counter for divisors\n num = 0\n \n # Iterate through possible divisors from 1 to n\n for i in range(1, n + 1):\n # Check if i is a divisor of n\n if n % i == 0:\n # If divisible, increment the divisor counter\n num += 1\n \n # Return the total number of divisors found\n return num", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n # Initialize a counter to keep track of divisors\n count = 0\n \n # Loop through numbers from 1 to n (inclusive)\n for i in range(1, n + 1):\n # Check if 'i' is a divisor of 'n'\n if n % i == 0:\n count += 1\n \n # Return the total count of divisors\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n # Initialize counter for divisors\n cnt = 0\n # Loop through numbers from 1 to n\n for i in range(1, n + 1):\n # If i divides n without a remainder, increment the counter\n if n % i == 0:\n cnt += 1\n # Return the total count of divisors\n return cnt", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n # Initialize counter for divisors\n count = 0\n \n # Iterate through possible divisors from 1 to n\n for i in range(1, n + 1):\n # Check if i is a divisor of n\n if n % i == 0:\n # If it is, increment the counter\n count += 1\n \n # Return the total count of divisors\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n # Initialize a counter for divisors\n count = 0\n # Iterate through possible divisors\n for i in range(1, n + 1):\n if n % i == 0: # Check if i is a divisor of n\n count += 1 # Increment the counter if i is a divisor\n return count # Return the total count of divisors", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n # Initialize a counter for the number of divisors\n count = 0\n \n # Iterate through all possible divisors\n for i in range(1, n + 1):\n # If 'i' is a divisor of 'n', increment the counter\n if n % i == 0:\n count += 1\n \n # Return the total count of divisors\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n # Initialize a counter for divisors\n c = 0\n # Iterate through numbers from 1 to n (inclusive)\n for i in range(1, n + 1):\n # Check if i is a divisor of n\n if n % i == 0:\n # If so, increment the counter\n c += 1\n # Return the total count of divisors\n return c", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n # Initialize a counter for divisors\n count = 0\n \n # Iterate through all numbers from 1 to n to check for divisors\n for i in range(1, n + 1):\n # If i is a divisor of n, increment the counter\n if n % i == 0:\n count += 1\n \n # Return the total count of divisors\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n # Initialize a counter to keep track of the number of divisors\n count = 0\n \n # Loop through all numbers from 1 to n (inclusive)\n for i in range(1, n + 1):\n # Check if i is a divisor of n\n if n % i == 0:\n # If it is, increment the counter\n count += 1\n \n # Return the total count of divisors\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n # Initialize a counter for divisors\n count = 0\n \n # Iterate through possible divisors from 1 to n\n for i in range(1, n + 1):\n # If i is a divisor of n, increment the count\n if n % i == 0:\n count += 1\n \n # Return the total count of divisors\n return count", "matching_cluster_idx": 2}]}, "Mbpp/97": {"dps": 95.19658119658119, "dps_norm": 86.25, "pass@1": 96.0, "profiled": [{"solution": "from collections import defaultdict\ndef frequency_lists(arr):\n # Initialize a defaultdict to store frequencies\n count_map = defaultdict(int)\n \n # Iterate over each list in the input list\n for arr1 in arr:\n # Iterate over each element in the sublist\n for n in arr1:\n # Increment the frequency of the element\n count_map[n] += 1\n \n # Convert the defaultdict to a dictionary before returning\n return dict(count_map)", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lst):\n frequency = {}\n # Iterate over each sublist in the list of lists\n for sublist in lst:\n # Iterate over each element in the sublist\n for element in sublist:\n # Check if the element is already in the dictionary\n if element in frequency:\n # Increment the count of the element in the dictionary\n frequency[element] += 1\n else:\n # Add the element to the dictionary with a count of 1\n frequency[element] = 1\n return frequency", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(test_list):\n # Initialize an empty dictionary to store frequencies\n res = {}\n \n # Iterate over each sublist in the list of lists\n for sub in test_list:\n # Iterate over each element in the sublist\n for ele in sub:\n # If the element is already in the dictionary, increment its count\n if ele in res:\n res[ele] += 1\n # If the element is not in the dictionary, add it with a count of 1\n else:\n res[ele] = 1\n \n # Return the dictionary containing frequencies of each element\n return res", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lst):\n # Flatten the list of lists into a single list\n lst = [item for sublist in lst for item in sublist]\n \n # Initialize an empty dictionary to store the frequency of each element\n f_dict = {}\n \n # Iterate through each element in the flattened list\n for ele in lst:\n # If the element is already in the dictionary, increment its count\n if ele in f_dict:\n f_dict[ele] += 1\n # If the element is not in the dictionary, add it with a count of 1\n else:\n f_dict[ele] = 1\n \n # Return the dictionary containing the frequency of each element\n return f_dict", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(list1):\n # Flatten the list of lists into a single list\n list1 = [item for sublist in list1 for item in sublist]\n \n # Create a dictionary to store the frequency of each element\n dict1 = {}\n \n # Iterate over each element in the flattened list\n for item in list1:\n # If the item is already in the dictionary, increment its count\n if item in dict1:\n dict1[item] += 1\n # If the item is not in the dictionary, add it with a count of 1\n else:\n dict1[item] = 1\n \n # Return the dictionary containing the frequency of each element\n return dict1", "matching_cluster_idx": 6}, {"solution": "from collections import Counter\ndef frequency_lists(list_of_lists):\n # Flatten the list of lists using a list comprehension\n flattened_list = [item for sublist in list_of_lists for item in sublist]\n \n # Use Counter to count the frequency of each element in the flattened list\n result = dict(Counter(flattened_list))\n \n return result", "matching_cluster_idx": 6}, {"solution": "from collections import Counter\ndef frequency_lists(test_list):\n # Flatten the list of lists using sum function\n flat_list = sum(test_list, [])\n \n # Count the frequency of each element using Counter from collections\n res = dict(Counter(flat_list))\n \n return res", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lists):\n frequency = {} # Initialize an empty dictionary to store frequencies\n for sublist in lists:\n for element in sublist:\n if element in frequency:\n frequency[element] += 1 # Increment the frequency of the element\n else:\n frequency[element] = 1 # Initialize the frequency of the element\n return frequency", "matching_cluster_idx": 6}, {"solution": "from collections import Counter\nfrom itertools import chain\ndef frequency_lists(test_list):\n # Flatten the list of lists using itertools.chain\n # Count the frequency of each element using collections.Counter\n res = dict(Counter(chain.from_iterable(test_list)))\n return res", "matching_cluster_idx": 7}, {"solution": "def frequency_lists(flist):\n # Initialize an empty dictionary to store the frequency of elements\n d = {}\n # Iterate over each sublist in the list of lists\n for sublist in flist:\n # Iterate over each element in the sublist\n for element in sublist:\n # If the element is already in the dictionary, increment its count\n if element in d:\n d[element] += 1\n # If the element is not in the dictionary, add it with a count of 1\n else:\n d[element] = 1\n # Return the dictionary containing the frequency of each element\n return d", "matching_cluster_idx": 6}, {"solution": "from collections import Counter\ndef frequency_lists(arr):\n # Flatten the list of lists into a single list\n flat_list = [item for sublist in arr for item in sublist]\n \n # Use Counter to count the frequency of each element in the flattened list\n frequency_dict = dict(Counter(flat_list))\n \n return frequency_dict", "matching_cluster_idx": 6}, {"solution": "from collections import defaultdict\ndef frequency_lists(list1):\n # Create a defaultdict to store the frequency of each element\n res = defaultdict(int)\n \n # Iterate through each sublist in the list\n for sub in list1:\n # Iterate through each element in the sublist\n for ele in sub:\n # Increment the count of the element in the dictionary\n res[ele] += 1\n \n # Convert the defaultdict to a regular dictionary and return\n return dict(res)", "matching_cluster_idx": 6}, {"solution": "from collections import Counter\nfrom itertools import chain\ndef frequency_lists(list_of_lists):\n # Flatten the list of lists into a single list using chain.from_iterable\n # Then, use Counter to count the frequency of each element in the flattened list\n return dict(Counter(chain.from_iterable(list_of_lists)))", "matching_cluster_idx": 7}, {"solution": "def frequency_lists(list_of_lists):\n frequency_dict = {}\n for sublist in list_of_lists:\n for element in sublist:\n if element in frequency_dict:\n frequency_dict[element] += 1\n else:\n frequency_dict[element] = 1\n return frequency_dict", "matching_cluster_idx": 6}, {"solution": "from collections import Counter\ndef frequency_lists(matrix):\n # Flatten the list of lists into a single list\n flat_list = [item for sublist in matrix for item in sublist]\n \n # Count the frequency of each element using Counter and convert to dictionary\n result = dict(Counter(flat_list))\n \n return result", "matching_cluster_idx": 6}, {"solution": "from collections import defaultdict\ndef frequency_lists(arr):\n # Initialize a defaultdict to count frequencies\n freq = defaultdict(int)\n \n # Iterate through each sublist in the list of lists\n for sublist in arr:\n # Iterate through each element in the sublist\n for element in sublist:\n # Increment the frequency count for the element\n freq[element] += 1\n \n # Return the frequency dictionary\n return dict(freq)", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(nums):\n # Flatten the list of lists into a single list\n list_nums = [num for sublist in nums for num in sublist]\n # Count the frequency of each element in the flattened list\n frequency = {num: list_nums.count(num) for num in set(list_nums)}\n return frequency", "matching_cluster_idx": 2}, {"solution": "def frequency_lists(lst):\n # Initialize an empty dictionary to store the frequency of each element\n dict1 = {}\n \n # Flatten the list of lists and count the frequency of each element\n for i in lst:\n for j in i:\n if j in dict1:\n dict1[j] += 1\n else:\n dict1[j] = 1\n \n # Return the dictionary with the frequency of each element\n return dict1", "matching_cluster_idx": 6}, {"solution": "from collections import Counter\nfrom typing import List, Dict\ndef frequency_lists(list1: List[List[int]]) -> Dict[int, int]:\n # Flatten the list of lists into a single list\n flat_list = [item for sublist in list1 for item in sublist]\n # Use Counter to count the frequency of each element\n return dict(Counter(flat_list))", "matching_cluster_idx": 6}, {"solution": "from collections import Counter\ndef frequency_lists(test_list):\n # Flatten the list of lists using list comprehension\n flat_list = [i for sublist in test_list for i in sublist]\n # Use Counter to count the frequency of each element in the flattened list\n res = dict(Counter(flat_list))\n return res", "matching_cluster_idx": 6}]}, "Mbpp/106": {"dps": 21.2012987012987, "dps_norm": 71.66666666666667, "pass@1": 85.0, "profiled": [{"solution": "def add_lists(list1, tup1):\n # Convert the tuple to a list, append the second list, and convert back to a tuple\n result = tuple(list(tup1) + list1)\n return result", "matching_cluster_idx": 3}, {"solution": "def add_lists(test_list, test_tup):\n # Convert the tuple to a list, append the new list, and then convert back to a tuple\n res = tuple(list(test_tup) + test_list)\n return res", "matching_cluster_idx": 3}, {"solution": "def add_lists(lst, tup):\n # Convert the tuple to a list, append the given list to it, and convert it back to a tuple\n tup = list(tup)\n tup.extend(lst)\n return tuple(tup)", "matching_cluster_idx": 4}, {"solution": "def add_lists(test_list, test_tup):\n # Append each element of the list to the tuple\n res = tuple(list(test_tup) + test_list)\n return res", "matching_cluster_idx": 3}, {"solution": "def add_lists(lists, tuples):\n # Convert the tuple to a list, append the given list, and then convert it back to a tuple\n result = tuple(list(tuples) + lists)\n return result", "matching_cluster_idx": 3}, {"solution": "def add_lists(test_list, test_tup):\n # Append each element of the list to the tuple\n res = test_tup + tuple(test_list)\n return res", "matching_cluster_idx": 5}, {"solution": "def add_lists(list1, tuple1):\n # Convert the tuple to a list\n converted_tuple = list(tuple1)\n # Extend the converted list with the given list\n converted_tuple.extend(list1)\n # Convert the list back to a tuple and return\n return tuple(converted_tuple)", "matching_cluster_idx": 4}, {"solution": "def add_lists(list1, tuple1):\n # Convert the tuple to a list, append the given list, and then convert back to a tuple\n return tuple(list(tuple1) + list1)", "matching_cluster_idx": 3}, {"solution": "def add_lists(listt, tuplee):\n # Convert the tuple to a list, concatenate the given list, and then convert back to a tuple\n return tuple(list(tuplee) + listt)", "matching_cluster_idx": 3}, {"solution": "def add_lists(list1, tup1):\n # Convert the tuple to a list, append the second list, and then convert back to a tuple\n return tuple(list(tup1) + list1)", "matching_cluster_idx": 3}, {"solution": "def add_lists(list1, tuple1):\n # Convert the tuple to a list, append the second list, and convert it back to a tuple\n return tuple(list(tuple1) + list1)", "matching_cluster_idx": 3}, {"solution": "def add_lists(test_list, test_tup):\n # Convert the tuple to a list, append the original list to it, and then convert it back to a tuple\n res = tuple(list(test_tup) + test_list)\n return res", "matching_cluster_idx": 3}, {"solution": "def add_lists(lst, tup):\n # Convert the tuple to a list and concatenate it with the given list\n # Then convert the resulting list back to a tuple and return it\n return tuple(list(tup) + lst)", "matching_cluster_idx": 3}, {"solution": "def add_lists(list1, tup):\n # Convert the tuple to a list\n temp = list(tup)\n \n # Extend the list with the original list elements\n temp.extend(list1)\n \n # Convert the list back to a tuple\n res = tuple(temp)\n \n return res", "matching_cluster_idx": 4}, {"solution": "def add_lists(mylist, mytuple):\n # Convert the tuple to a list\n mylist = list(mytuple) + mylist\n # Convert the list back to a tuple\n mylist = tuple(mylist)\n return mylist", "matching_cluster_idx": 3}, {"solution": "def add_lists(list1, tuple1):\n # Convert the tuple to a list, append the given list to it, and then convert it back to a tuple\n tuple1 = list(tuple1)\n tuple1.extend(list1)\n return tuple(tuple1)", "matching_cluster_idx": 4}, {"solution": "def add_lists(lst, tup):\n # Convert the tuple to a list, append the given list, and then convert back to a tuple\n return tuple(list(tup) + lst)", "matching_cluster_idx": 3}, {"solution": "def add_lists(list1, tup1):\n # Convert the tuple to a list and concatenate with the given list\n result = list(tup1) + list1\n # Return the concatenated list as a tuple\n return tuple(result)", "matching_cluster_idx": 3}, {"solution": "def add_lists(lists, tuples):\n # Convert the tuples into a list, append the given list to it, and then convert it back to a tuple\n new_tup = tuple(list(tuples) + lists)\n return new_tup", "matching_cluster_idx": 3}, {"solution": "def add_lists(lst, tp):\n # Convert the tuple to a list, append the given list, and then convert back to a tuple\n result = tuple(list(tp) + lst)\n return result", "matching_cluster_idx": 3}]}, "Mbpp/108": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 85.0, "profiled": [{"solution": "def merge_sorted_list(nums1, nums2, nums3):\n # Combine the three lists into one\n nums = nums1 + nums2 + nums3\n \n # Sort the combined list\n nums.sort()\n \n # Return the sorted list\n return nums", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(nums1, nums2, nums3):\n # Merge the three lists into one\n merged = nums1 + nums2 + nums3\n # Sort the merged list\n merged.sort()\n return merged", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(nums1, nums2, nums3):\n # Merge the three lists into a single list\n nums = nums1 + nums2 + nums3\n \n # Sort the merged list\n nums.sort()\n return nums", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(nums1, nums2, nums3):\n # Combine all three lists into one\n nums4 = nums1 + nums2 + nums3\n # Sort the combined list\n nums4.sort()\n return nums4", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(nums1, nums2, nums3):\n # Concatenate all three lists\n nums1.extend(nums2)\n nums1.extend(nums3)\n # Sort the combined list\n nums1.sort()\n return nums1", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Merge the three lists into one\n merged_list = list1 + list2 + list3\n \n # Sort the merged list\n merged_list.sort()\n \n # Return the sorted list\n return merged_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(arr1, arr2, arr3):\n # Concatenate the three lists into one\n merged_list = arr1 + arr2 + arr3\n # Sort the merged list\n merged_list.sort()\n # Return the sorted merged list\n return merged_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Concatenate the three lists\n merged_list = list1 + list2 + list3\n \n # Sort the merged list\n sorted_list = sorted(merged_list)\n \n return sorted_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(nums1, nums2, nums3):\n # Concatenate the three lists into one\n list1 = nums1 + nums2 + nums3\n # Sort the concatenated list\n list1.sort()\n return list1", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(arr1, arr2, arr3):\n # Merging the three lists\n merged_list = arr1 + arr2 + arr3\n # Sorting the merged list\n sorted_list = sorted(merged_list)\n return sorted_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(lst1, lst2, lst3):\n # Merge the three lists into one\n merged = lst1 + lst2 + lst3\n # Sort the merged list\n merged.sort()\n # Return the sorted merged list\n return merged", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(nums1, nums2, nums3):\n # Concatenate the three input lists\n merged_list = nums1 + nums2 + nums3\n # Sort the merged list\n merged_list.sort()\n # Return the sorted list\n return merged_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Combine all three lists into one\n combined_list = list1 + list2 + list3\n \n # Sort the combined list\n combined_list.sort()\n \n # Return the sorted list\n return combined_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(lst1, lst2, lst3):\n # Merge the three lists\n merged_list = lst1 + lst2 + lst3\n # Sort the merged list\n merged_list.sort()\n # Return the sorted merged list\n return merged_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Merge the three lists\n merged_list = list1 + list2 + list3\n # Sort the merged list\n merged_list.sort()\n return merged_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(arr1, arr2, arr3):\n # Merge the three lists\n merged_list = arr1 + arr2 + arr3\n \n # Sort the merged list\n merged_list.sort()\n \n return merged_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(nums1, nums2, nums3):\n # Concatenate the three lists\n nums = nums1 + nums2 + nums3\n # Sort the combined list\n nums.sort()\n return nums", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Combine all three lists into one list\n combined_list = list1 + list2 + list3\n \n # Sort the combined list\n sorted_list = sorted(combined_list)\n \n return sorted_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Concatenate the three lists\n merged = list1 + list2 + list3\n \n # Sort the merged list\n sorted_list = sorted(merged)\n \n return sorted_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(lst1, lst2, lst3):\n # Concatenate the three lists\n result = lst1 + lst2 + lst3\n \n # Sort the concatenated list\n result.sort()\n \n # Return the sorted list\n return result", "matching_cluster_idx": 10}]}, "Mbpp/111": {"dps": 33.753846153846155, "dps_norm": 71.25, "pass@1": 85.0, "profiled": [{"solution": "def common_in_nested_lists(nested_lists):\n # Use set intersection to find common elements\n common_elements = set.intersection(*map(set, nested_lists))\n return common_elements", "matching_cluster_idx": 5}, {"solution": "def common_in_nested_lists(nested_lists):\n # Initialize a set with the first list's elements\n common = set(nested_lists[0])\n \n # Iterate over the rest of the lists\n for sublist in nested_lists[1:]:\n # Update the set to keep only elements present in both the current set and the current sublist\n common &= set(sublist)\n \n # Return the final set of common elements\n return common", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_list):\n # Find the common elements in the nested lists using set intersection\n result = set.intersection(*map(set, nested_list))\n return result", "matching_cluster_idx": 4}, {"solution": "def common_in_nested_lists(nested_list):\n # Use set intersection to find common elements in all nested lists\n common = set(nested_list[0]).intersection(*nested_list)\n return common", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(lists):\n # Use set intersection to find common elements\n common_elements = set.intersection(*[set(l) for l in lists])\n # Return the common elements as a set\n return common_elements", "matching_cluster_idx": 4}, {"solution": "def common_in_nested_lists(nested_lists):\n # Use a set intersection to find common elements\n common_elements = set.intersection(*map(set, nested_lists))\n return common_elements", "matching_cluster_idx": 4}, {"solution": "def common_in_nested_lists(nested_list):\n # Convert each sublist to a set and find the intersection\n common_elements = set.intersection(*map(set, nested_list))\n return common_elements", "matching_cluster_idx": 4}, {"solution": "def common_in_nested_lists(input_list):\n # Use set intersection to find common elements across all sublists\n result = set.intersection(*[set(sublist) for sublist in input_list])\n return result", "matching_cluster_idx": 4}, {"solution": "def common_in_nested_lists(lists):\n # Initialize the common elements list with the first list in the nested lists\n common_list = lists[0]\n \n # Iterate over the remaining lists in the nested lists\n for i in range(1, len(lists)):\n # Update the common_list with the intersection of itself and the current list\n common_list = [value for value in common_list if value in lists[i]]\n \n # Return the common elements as a set\n return set(common_list)", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_list):\n # Initialize the result list with the first sublist\n result = nested_list[0]\n \n # Iterate over each sublist starting from the second one\n for sublist in nested_list[1:]:\n # Update the result list to keep only the common elements\n result = list(set(result).intersection(sublist))\n \n # Return the result list as a set for an unordered collection of unique elements\n return set(result)", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n # Use the set intersection method to find common elements\n return set.intersection(*map(set, nested_lists))", "matching_cluster_idx": 4}, {"solution": "def common_in_nested_lists(nested_lists):\n # Convert each sublist to a set and find the intersection\n result = set.intersection(*map(set, nested_lists))\n return result", "matching_cluster_idx": 4}, {"solution": "def common_in_nested_lists(nested_lists):\n # Get the set of elements from each sublist and find the intersection\n result_set = set.intersection(*[set(i) for i in nested_lists])\n return result_set", "matching_cluster_idx": 4}, {"solution": "def common_in_nested_lists(list_of_lists):\n # Initialize a set with the elements of the first nested list\n common_elements = set(list_of_lists[0])\n \n # Iterate over the rest of the nested lists\n for sublist in list_of_lists[1:]:\n # Update the set of common elements to intersection of current and next sublist\n common_elements &= set(sublist)\n \n return common_elements", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n # Initialize the first list as the intersection set\n common_elements = set(nested_lists[0])\n \n # Iterate over the remaining lists\n for i in range(1, len(nested_lists)):\n # Find the intersection with the current list\n common_elements = common_elements.intersection(set(nested_lists[i]))\n \n # Return the set of common elements\n return common_elements", "matching_cluster_idx": 5}, {"solution": "def common_in_nested_lists(a):\n # Initialize the result set with elements from the first sublist\n result = set(a[0])\n \n # Iterate over the remaining sublists\n for b in a[1:]:\n # Update the result set to keep only the common elements\n result = result.intersection(b)\n \n # Return the result set as a sorted list\n return sorted(list(result))", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n # Use set intersection to find common elements in the nested lists\n return set.intersection(*map(set, nested_lists))", "matching_cluster_idx": 4}, {"solution": "def common_in_nested_lists(list1):\n # Find common elements in the nested lists\n result = list(set.intersection(*map(set, list1)))\n return result", "matching_cluster_idx": 4}, {"solution": "from typing import List, Any\ndef common_in_nested_lists(lists: List[List[Any]]) -> List[Any]:\n # Find the intersection of all sets in the list of lists\n common_elements = list(set.intersection(*map(set, lists)))\n return common_elements", "matching_cluster_idx": 4}, {"solution": "def common_in_nested_lists(input_list):\n # Use set intersection to find common elements in nested lists\n return set.intersection(*map(set, input_list))", "matching_cluster_idx": 4}]}, "Mbpp/123": {"dps": 99.62686567164178, "dps_norm": 85.71428571428571, "pass@1": 27.0, "profiled": [{"solution": "def amicable_numbers_sum(n):\n # Function to find the sum of proper divisors of a number\n def div_sum(x):\n total = 1 # Start with 1 since it's a proper divisor for all x > 1\n i = 2\n while i * i <= x:\n if x % i:\n i += 1\n else:\n if i * (x // i) == x: # Check to avoid adding the square root twice for perfect squares\n total += i + x // i\n else:\n total += i + x // i\n i += 1\n return total\n \n # Main logic to find amicable numbers and their sum\n amicable_sum = 0\n for i in range(2, n):\n sum1 = div_sum(i)\n sum2 = div_sum(sum1)\n if i == sum2 and i != sum1:\n amicable_sum += i\n return amicable_sum", "matching_cluster_idx": 11}, {"solution": "def amicable_numbers_sum(upper):\n # Function to calculate the sum of proper divisors of a number\n def sum_of_proper_divisors(n):\n total = 1 # 1 is a proper divisor of all numbers\n for i in range(2, int(n ** 0.5) + 1):\n if n % i == 0:\n total += i\n if i != n // i: # Add the quotient only if it's different from i\n total += n // i\n return total\n \n amicable_sum = 0\n # Iterate through numbers from 2 to the specified upper limit\n for i in range(2, upper):\n partner = sum_of_proper_divisors(i)\n # Check if the number is amicable\n if i == sum_of_proper_divisors(partner) and i != partner:\n amicable_sum += i + partner\n return amicable_sum // 2 # Each pair is counted twice, so divide by 2", "matching_cluster_idx": 11}, {"solution": "def amicable_numbers_sum(upper_limit):\n # Function to calculate the sum of proper divisors of a number\n def sum_of_divisors(n):\n divisors_sum = 1\n i = 2\n while i * i <= n:\n if n % i:\n i += 1\n else:\n if i * (n // i) == n:\n divisors_sum = divisors_sum + i + n//i\n else:\n divisors_sum = divisors_sum + i + n//i\n i += 1\n return divisors_sum\n \n # Initialize the sum of amicable numbers\n amicable_sum = 0\n \n # Iterate through all numbers from 1 to upper_limit\n for i in range(2, upper_limit + 1):\n sum1 = sum_of_divisors(i)\n sum2 = sum_of_divisors(sum1)\n \n # Check if the pair is amicable and not repeated\n if (i == sum2 and sum1 != sum2):\n amicable_sum += i\n \n return amicable_sum", "matching_cluster_idx": 11}, {"solution": "def amicable_numbers_sum(upper_limit):\n # Helper function to find the sum of proper divisors of n\n def sum_of_divisors(n):\n total = 1\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n total += i\n if i != n // i:\n total += n // i\n return total\n\n # List to store amicable numbers\n amicable_nums = []\n \n # Iterate through numbers to find amicable pairs\n for a in range(2, upper_limit):\n b = sum_of_divisors(a)\n if a != b and sum_of_divisors(b) == a:\n amicable_nums.append(a)\n amicable_nums.append(b)\n \n # Calculate the sum of all unique amicable numbers\n return sum(set(amicable_nums))", "matching_cluster_idx": 11}, {"solution": "def amicable_numbers_sum(upper_limit):\n # Helper function to calculate the sum of proper divisors of a number\n def sum_of_divisors(num):\n total = 1 # Start with 1 as it is a proper divisor of all numbers\n sqrt_num = int(num ** 0.5) + 1 # Only need to check up to the square root\n for i in range(2, sqrt_num):\n if num % i == 0:\n total += i\n if i != num // i: # Add the corresponding divisor pair\n total += num // i\n return total\n\n # Find and sum all amicable numbers from 1 to upper_limit\n amicable_sum = 0\n for num in range(2, upper_limit):\n amicable_pair = sum_of_divisors(num)\n if sum_of_divisors(amicable_pair) == num and num < amicable_pair:\n amicable_sum += num\n amicable_sum += amicable_pair\n return amicable_sum", "matching_cluster_idx": 11}, {"solution": "def amicable_numbers_sum(n):\n # Function to calculate the sum of proper divisors of a number\n def sum_of_divisors(x):\n total = 1 # 1 is a proper divisor of any number\n i = 2\n while i * i <= x:\n if x % i:\n i += 1\n else:\n if i * (x // i) == x:\n total = total + i + x // i\n else:\n total = total + i + x // i\n i += 1\n return total\n\n sum_amicable = 0\n # Iterate through all numbers from 2 to n\n for i in range(2, n + 1):\n j = sum_of_divisors(i)\n # Check if the sum of divisors of i equals j and j equals i\n if i == sum_of_divisors(j) and i != j:\n sum_amicable += i + j\n # Return the sum of all amicable numbers up to n\n return sum_amicable // 2", "matching_cluster_idx": 11}, {"solution": "def amicable_numbers_sum(upper_limit):\n # Helper function to calculate the sum of proper divisors of n\n def sum_of_divisors(n):\n total = 1 # Start with 1 because it is a proper divisor for all n > 1\n for i in range(2, int(n**0.5) + 1): # Only go up to the square root of n\n if n % i == 0:\n total += i\n if i != n // i: # Avoid adding the square root twice for perfect squares\n total += n // i\n return total\n \n total_sum = 0 # Initialize the total sum of amicable numbers\n for a in range(2, upper_limit): # Start from 2 because 1 is not considered amicable\n b = sum_of_divisors(a)\n if a != b and a == sum_of_divisors(b):\n total_sum += a # Only add a if it is part of an amicable pair and not already added\n return total_sum", "matching_cluster_idx": 11}, {"solution": "def amicable_numbers_sum(limit):\n # Function to calculate sum of proper divisors of n\n def sum_of_divisors(n):\n # Start with 1 as it's a proper divisor for all numbers\n total_sum = 1\n # Loop from 2 to square root of n to find other divisors\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n total_sum += i\n # Add the divisor pair if it's different from i\n if i != n // i:\n total_sum += n // i\n return total_sum\n \n # Dictionary to store amicable pairs\n amicable_pairs = {}\n for number in range(2, limit + 1):\n # Check if number is not already in dictionary to avoid reprocessing\n if number not in amicable_pairs:\n # Calculate sum of divisors for the current number\n div_sum = sum_of_divisors(number)\n # Check if the calculated sum has a corresponding sum that is a divisor of the number\n if sum_of_divisors(div_sum) == number and number != div_sum:\n # Add both numbers as amicable pairs\n amicable_pairs[number] = div_sum\n amicable_pairs[div_sum] = number\n \n # Sum all unique amicable numbers\n return sum(amicable_pairs.keys())", "matching_cluster_idx": 11}, {"solution": "def amicable_numbers_sum(N):\n # Helper function to calculate the sum of divisors excluding the number itself\n def sum_of_divisors(n):\n result = 1 # 1 is a divisor for all numbers\n sqrt_n = int(n ** 0.5)\n for i in range(2, sqrt_n + 1):\n if n % i == 0:\n result += i\n if i != n // i:\n result += n // i\n return result\n\n # Set to store amicable numbers\n amicable_set = set()\n for num in range(2, N + 1):\n # Calculate the sum of divisors for the current number\n div_sum = sum_of_divisors(num)\n # Check if the sum of divisors is within the range and forms an amicable pair\n if num != div_sum and num == sum_of_divisors(div_sum):\n amicable_set.add(num)\n amicable_set.add(div_sum)\n\n # Return the sum of all amicable numbers\n return sum(amicable_set)", "matching_cluster_idx": 11}, {"solution": "def amicable_numbers_sum(upper_limit):\n # Helper function to calculate the sum of proper divisors of a number\n def sum_of_divisors(n):\n sum = 1 # Start with 1 because it's a proper divisor for all n > 1\n i = 2\n # Only need to check up to the square root of n\n while i * i <= n:\n if n % i:\n i += 1\n else:\n if i * (n // i) == n: # Check to avoid adding the square root twice for perfect squares\n sum = sum + i + n // i\n else:\n sum = sum + i + n // i\n i += 1\n return sum\n \n amicable_sum = 0\n # Iterate through numbers from 1 to upper_limit\n for n in range(1, upper_limit):\n sum1 = sum_of_divisors(n)\n # Check if the sum of divisors of sum1 is n and n is not equal to sum1\n if (sum_of_divisors(sum1) == n and n != sum1):\n amicable_sum += n\n \n return amicable_sum", "matching_cluster_idx": 11}, {"solution": "def amicable_numbers_sum(upper_limit):\n # Helper function to calculate the sum of proper divisors of a number\n def divisors_sum(num):\n total = 1 # 1 is a proper divisor of any number\n for divisor in range(2, int(num ** 0.5) + 1):\n if num % divisor == 0:\n total += divisor\n if divisor != num // divisor: # Check to avoid adding the square root twice\n total += num // divisor\n return total\n \n total_sum = 0 # Initialize the sum of amicable numbers\n \n # Iterate through all numbers up to the upper limit\n for number in range(2, upper_limit + 1):\n # Calculate the sum of divisors of the current number\n div_sum = divisors_sum(number)\n # Check if the number is amicable\n if div_sum != number and divisors_sum(div_sum) == number:\n total_sum += number\n \n return total_sum", "matching_cluster_idx": 11}, {"solution": "def amicable_numbers_sum(n):\n # Helper function to calculate the sum of proper divisors of n\n def sum_of_divisors(x):\n divisors_sum = 1 # Start with 1 since it's a proper divisor of all numbers\n i = 2\n while i * i <= x:\n if x % i:\n i += 1\n else:\n if i * (x // i) == x:\n divisors_sum = divisors_sum + i + x // i\n else:\n divisors_sum = divisors_sum + i + x // i\n i += 1\n return divisors_sum\n \n # Iterate through all numbers from 1 to n-1\n return sum(x for x in range(1, n) if sum_of_divisors(x) != x and sum_of_divisors(sum_of_divisors(x)) == x)", "matching_cluster_idx": 11}, {"solution": "def sum_proper_divisors(n):\n # Initialize sum of divisors with 1, as it's a proper divisor of every number\n sum = 1\n i = 2\n while i * i <= n:\n if n % i:\n i += 1\n else:\n # If divisors are equal, add only one\n if i * (n // i) == n:\n sum = sum + i + n // i\n else:\n # Add both divisors\n sum = sum + i + n // i\n i += 1\n return sum\ndef amicable_numbers_sum(upper_limit):\n # Initialize total sum of amicable numbers\n sum_amicable = 0\n # Iterate through numbers up to the upper limit\n for num in range(2, upper_limit + 1):\n # Check if the number is amicable\n if sum_proper_divisors(num) != num and sum_proper_divisors(sum_proper_divisors(num)) == num:\n sum_amicable += num\n return sum_amicable", "matching_cluster_idx": 11}, {"solution": "def amicable_numbers_sum(n):\n # Helper function to calculate the sum of divisors of a number\n def sum_divisors(n):\n # Initialize sum with 1 because 1 is a divisor for all n > 1\n sum = 1\n # Iterate from 2 to the square root of n\n i = 2\n while i * i <= n:\n # If i divides n, add both divisors\n if n % i == 0:\n if i * i != n:\n sum = sum + i + n // i\n else:\n sum = sum + i\n i = i + 1\n return sum\n\n # Initialize sum of amicable numbers\n amicable_sum = 0\n # Iterate through numbers from 1 to n-1\n for i in range(1, n):\n # Check if the number is amicable\n if sum_divisors(i) != i and sum_divisors(sum_divisors(i)) == i:\n amicable_sum += i\n return amicable_sum", "matching_cluster_idx": 11}, {"solution": "def amicable_numbers_sum(upper_limit):\n # Helper function to calculate the sum of proper divisors of a number\n def sum_of_divisors(n):\n total = 1 # 1 is a proper divisor of any number\n for i in range(2, int(n ** 0.5) + 1):\n if n % i == 0:\n total += i\n if i != n // i: # Add the complement divisor if it's different\n total += n // i\n return total\n\n # List to store amicable numbers within the range\n amicable_numbers = []\n \n # Iterate through the range to find amicable numbers\n for i in range(2, upper_limit + 1):\n if i not in amicable_numbers:\n partner = sum_of_divisors(i)\n if partner != i and sum_of_divisors(partner) == i:\n amicable_numbers.append(i)\n amicable_numbers.append(partner)\n \n # Sum all amicable numbers found\n return sum(amicable_numbers)", "matching_cluster_idx": 11}, {"solution": "def amicable_numbers_sum(n):\n # Function to calculate the sum of divisors of a number\n def sum_of_divisors(x):\n sum = 1\n i = 2\n while i * i <= x:\n if x % i:\n i += 1\n else:\n if i * (x // i) == x:\n sum = sum + i + x // i\n else:\n sum = sum + i + x // i\n i += 1\n return sum\n \n # Calculate the sum of all amicable numbers up to n\n amicable_sum = 0\n for num in range(1, n + 1):\n # Get the sum of divisors of num\n div_sum = sum_of_divisors(num)\n # Check if the sum of divisors is amicable\n if div_sum != num and sum_of_divisors(div_sum) == num:\n amicable_sum += num\n \n return amicable_sum", "matching_cluster_idx": 11}, {"solution": "def amicable_numbers_sum(limit):\n # Function to find the sum of divisors of a number excluding the number itself\n def sum_of_divisors(n):\n sum = 1\n i = 2\n while i * i <= n:\n if n % i:\n i += 1\n else:\n if i * (n // i) == n:\n sum = sum + i + n // i\n else:\n sum = sum + i + n // i\n i += 1\n return sum\n \n # List to store amicable numbers\n amicable = []\n \n # Loop through all numbers from 1 to the limit\n for a in range(1, limit + 1):\n # Find the sum of divisors of a\n sum_a = sum_of_divisors(a)\n \n # Check if the sum of divisors of sum_a is a and not equal to a\n if sum_of_divisors(sum_a) == a and a != sum_a:\n # Ensure a is not already in the amicable list\n if a not in amicable:\n amicable.append(a)\n # Ensure sum_a is not already in the amicable list\n if sum_a not in amicable:\n amicable.append(sum_a)\n \n # Sum all unique amicable numbers and return the result\n return sum(amicable)", "matching_cluster_idx": 11}, {"solution": "def amicable_numbers_sum(n):\n # Function to find the sum of proper divisors of a number\n def sum_divisors(num):\n total = 1 # 1 is always a divisor\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n total += i\n if i != num // i: # Add the pair divisor if it's different from i\n total += num // i\n return total\n \n # Initialize sum of amicable numbers\n amicable_sum = 0\n \n # Loop through all numbers from 1 to n\n for i in range(2, n + 1):\n # Find the sum of divisors of i\n sum_i = sum_divisors(i)\n \n # Check if the sum of divisors of sum_i is i and not equal to i itself\n if sum_i != i and sum_divisors(sum_i) == i:\n amicable_sum += i\n \n return amicable_sum", "matching_cluster_idx": 11}, {"solution": "def amicable_numbers_sum(upper_limit):\n # Helper function to calculate the sum of divisors of a number\n def sum_of_divisors(num):\n # Initialize the sum with 1 because it is a proper divisor\n total = 1\n # Check for divisors from 2 to the square root of the number\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n total += i\n # If the divisor is not the square root of the number, add both divisors\n if i != num // i:\n total += num // i\n return total\n \n # Initialize the sum of amicable numbers\n total_amicable = 0\n # Iterate through all numbers from 2 to the upper limit\n for num in range(2, upper_limit + 1):\n # Calculate the sum of divisors of the current number\n a = sum_of_divisors(num)\n # Check if the sum of divisors of the sum equals the original number and they are not the same\n if sum_of_divisors(a) == num and a != num:\n total_amicable += num\n \n # Return the total sum of amicable numbers\n return total_amicable", "matching_cluster_idx": 11}, {"solution": "def amicable_numbers_sum(upper_limit):\n # Helper function to calculate the sum of divisors of n\n def getDivisorSum(n):\n total = 1 # 1 is always a divisor\n i = 2\n while i * i <= n:\n if n % i:\n i += 1\n else:\n if i * (n // i) == n:\n total += i + n // i\n else:\n total += i\n total += n // i\n i += 1\n return total\n\n total_sum = 0\n # Iterate through numbers to find amicable pairs\n for num in range(1, upper_limit):\n sum1 = getDivisorSum(num)\n sum2 = getDivisorSum(sum1)\n if num == sum2 and num != sum1:\n total_sum += num\n return total_sum", "matching_cluster_idx": 11}]}, "Mbpp/128": {"dps": 85.36199095022624, "dps_norm": 77.0, "pass@1": 98.0, "profiled": [{"solution": "def long_words(n, string):\n # Split the input string into a list of words\n words_list = string.split(\" \")\n # Use list comprehension to filter words longer than n characters\n result = [word for word in words_list if len(word) > n]\n return result", "matching_cluster_idx": 3}, {"solution": "def long_words(n, str1):\n # Split the input string into a list of words\n words = str1.split(\" \")\n # Filter words that are longer than n characters and return them\n return [word for word in words if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, str):\n # Split the input string into a list of words\n words = str.split(\" \")\n # Use list comprehension to filter words longer than 'n' characters\n longer_words = [word for word in words if len(word) > n]\n # Return the list of filtered words\n return longer_words", "matching_cluster_idx": 3}, {"solution": "def long_words(n, str1):\n # Split the input string into a list of words\n words = str1.split(\" \")\n # Use list comprehension to filter out words longer than n characters\n long_word_list = [word for word in words if len(word) > n]\n # Return the list of long words\n return long_word_list", "matching_cluster_idx": 3}, {"solution": "def long_words(n, str):\n # Split the string into individual words\n words = str.split(\" \")\n # Initialize an empty list to store words longer than n characters\n result = []\n # Iterate over each word in the list\n for word in words:\n # If the length of the word is greater than n, add it to the result list\n if len(word) > n:\n result.append(word)\n # Return the list of words longer than n characters\n return result", "matching_cluster_idx": 3}, {"solution": "def long_words(n, str1):\n # Split the input string into a list of words\n words = str1.split(\" \")\n # Filter words longer than n characters and return the list\n longer_words = list(filter(lambda x: len(x) > n, words))\n return longer_words", "matching_cluster_idx": 2}, {"solution": "def long_words(n, string):\n # Split the string into a list of words\n words = string.split(\" \")\n # Filter and return words that are longer than n characters\n return [word for word in words if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, str1):\n # Split the input string into a list of words\n words = str1.split(\" \")\n # Use list comprehension to filter words longer than n characters\n long_words_list = [word for word in words if len(word) > n]\n return long_words_list", "matching_cluster_idx": 3}, {"solution": "def long_words(n, str):\n # Split the input string into a list of words\n str = str.split(\" \")\n # Filter words that are longer than 'n' characters using list comprehension\n result = [word for word in str if len(word) > n]\n # Return the filtered list of words\n return result", "matching_cluster_idx": 3}, {"solution": "def long_words(n, x):\n # Initialize an empty list to store words longer than n characters\n result = []\n # Iterate over each word in the given list\n for word in x.split():\n # Check if the length of the word is greater than n\n if len(word) > n:\n # If so, add the word to the result list\n result.append(word)\n # Return the list of words longer than n characters\n return result", "matching_cluster_idx": 3}, {"solution": "def long_words(n, str):\n # Split the input string into a list of words\n words = str.split(\" \")\n \n # Filter and return words that are longer than n characters\n return list(filter(lambda x: len(x) > n, words))", "matching_cluster_idx": 2}, {"solution": "def long_words(n, str1):\n # Split the input string into a list of words\n words = str1.split(\" \")\n \n # Use list comprehension to filter out words longer than n characters\n return [word for word in words if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, x):\n # Use list comprehension to filter words longer than n characters\n result = [i for i in x.split(\" \") if len(i) > n]\n return result", "matching_cluster_idx": 3}, {"solution": "def long_words(n, str1):\n # Split the input string into a list of words\n words = str1.split(\" \")\n # Use list comprehension to filter words longer than n characters\n long_words_list = [word for word in words if len(word) > n]\n # Return the list of long words\n return long_words_list", "matching_cluster_idx": 3}, {"solution": "def long_words(n, string):\n # Split the string into words using space as a delimiter\n words = string.split(\" \")\n # Filter words to include only those longer than n characters\n longer_words = list(filter(lambda x: len(x) > n, words))\n return longer_words", "matching_cluster_idx": 2}, {"solution": "def long_words(n, str1):\n # Split the input string into a list of words\n words = str1.split(\" \")\n # Use list comprehension to filter words longer than 'n' characters\n long_words_list = [word for word in words if len(word) > n]\n # Return the list of filtered words\n return long_words_list", "matching_cluster_idx": 3}, {"solution": "def long_words(n, str):\n # Split the input string into a list of words\n words = str.split(\" \")\n # Use list comprehension to filter and select words longer than n characters\n return [word for word in words if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, str):\n # Split the input string into a list of words\n str = str.split(\" \")\n # Use list comprehension to filter words longer than n characters\n longword = [word for word in str if len(word) > n]\n return longword", "matching_cluster_idx": 3}, {"solution": "def long_words(n, str1):\n # Split the input string into a list of words\n words_list = str1.split(\" \")\n \n # Filter the list to include only words longer than n characters\n resultant_list = [word for word in words_list if len(word) > n]\n \n return resultant_list", "matching_cluster_idx": 3}, {"solution": "def long_words(n, str1):\n # Use list comprehension to filter words longer than 'n' characters\n result = [word for word in str1.split() if len(word) > n]\n return result", "matching_cluster_idx": 3}]}, "Mbpp/129": {"dps": 92.38520408163265, "dps_norm": 99.0, "pass@1": 36.0, "profiled": [{"solution": "def magic_square_test(M):\n def magic_square(M):\n n = len(M)\n s = sum(M[0]) # Sum of the first row as reference\n\n # Check sums of rows\n for i in range(1, n):\n if sum(M[i]) != s:\n return False\n\n # Check sums of columns\n for j in range(n):\n if sum(M[i][j] for i in range(n)) != s:\n return False\n\n # Check sum of main diagonal\n if sum(M[i][i] for i in range(n)) != s:\n return False\n\n # Check sum of secondary diagonal\n if sum(M[i][n - i - 1] for i in range(n)) != s:\n return False\n\n return True\n\n return magic_square(M)", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(array):\n # Calculate the size of the matrix\n size = len(array)\n \n # Calculate the magic sum using the first element\n magic_sum = sum(array[0])\n \n # Function to check the sum of elements in a row\n def row_sum(array, i):\n return sum(array[i])\n \n # Function to check the sum of elements in a column\n def column_sum(array, i):\n return sum(array[j][i] for j in range(size))\n \n # Function to check the sum of elements in the main diagonal\n def main_diagonal_sum(array):\n return sum(array[i][i] for i in range(size))\n \n # Function to check the sum of elements in the secondary diagonal\n def secondary_diagonal_sum(array):\n return sum(array[i][size - i - 1] for i in range(size))\n \n # Check the sums of all rows, columns, and diagonals\n for i in range(size):\n if row_sum(array, i) != magic_sum:\n return False\n if column_sum(array, i) != magic_sum:\n return False\n \n if main_diagonal_sum(array) != magic_sum:\n return False\n if secondary_diagonal_sum(array) != magic_sum:\n return False\n \n return True", "matching_cluster_idx": 13}, {"solution": "def magic_square_test(mat):\n # Check if the given matrix is a magic square\n n = len(mat)\n m = len(mat[0])\n \n # Check if the matrix is square\n if n != m:\n return False\n \n # Calculate the sum of the elements in the first row\n s = sum(mat[0])\n \n # Check the sums of the elements in the other rows\n for i in range(1, n):\n if sum(mat[i]) != s:\n return False\n \n # Check the sums of the elements in the columns\n for i in range(n):\n if sum(mat[j][i] for j in range(n)) != s:\n return False\n \n # Check the sums of the elements in the diagonals\n if sum(mat[i][i] for i in range(n)) != s:\n return False\n if sum(mat[i][n-i-1] for i in range(n)) != s:\n return False\n \n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(test_matrix): \n size = len(test_matrix) # Get the size of the matrix\n sum_magic = sum(test_matrix[0]) # Calculate the sum of the first row as the reference\n\n # Check if the sum of each row is the same\n for i in range(1, size): \n if sum(test_matrix[i]) != sum_magic: \n return False \n\n # Check if the sum of each column is the same\n for i in range(size): \n sum_col = 0\n for j in range(size): \n sum_col += test_matrix[j][i] \n if sum_col != sum_magic: \n return False \n\n # Check if the sum of the main diagonal is the same\n sum_diag1 = 0\n for i in range(size): \n sum_diag1 += test_matrix[i][i] \n\n # Check if the sum of the secondary diagonal is the same\n sum_diag2 = 0\n for i in range(size): \n sum_diag2 += test_matrix[i][size - i - 1] \n\n # Check if the sum of the main diagonal and the secondary diagonal are equal to the reference sum\n if sum_diag1 != sum_magic or sum_diag2 != sum_magic: \n return False \n\n # If all checks pass, return True\n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(n):\n # Check if each row has the same sum\n for x in range(len(n)):\n if sum(n[x]) != sum(n[0]):\n return False\n \n # Check if each column has the same sum\n for x in range(len(n)):\n sum1 = 0\n for y in range(len(n)):\n sum1 += n[y][x]\n if sum1 != sum(n[0]):\n return False\n \n # Check if the sum of the diagonals are the same\n sum1 = 0\n sum2 = 0\n for x in range(len(n)):\n sum1 += n[x][x]\n sum2 += n[x][len(n) - x - 1]\n \n if sum1 != sum(n[0]) or sum2 != sum(n[0]):\n return False\n \n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(magic_square):\n # Sum of the elements in the first row to be used as a reference\n n = len(magic_square)\n magic_sum = 0\n for num in magic_square[0]:\n magic_sum += num\n \n # Check sums of all rows\n for i in range(1, n):\n row_sum = 0\n for num in magic_square[i]:\n row_sum += num\n if row_sum != magic_sum:\n return False\n \n # Check sums of all columns\n for i in range(n):\n col_sum = 0\n for j in range(n):\n col_sum += magic_square[j][i]\n if col_sum != magic_sum:\n return False\n \n # Check sums of the two diagonals\n d1_sum = sum(magic_square[i][i] for i in range(n))\n if d1_sum != magic_sum:\n return False\n \n d2_sum = sum(magic_square[i][n-i-1] for i in range(n))\n if d2_sum != magic_sum:\n return False\n \n # If all checks pass, it is a magic square\n return True", "matching_cluster_idx": 13}, {"solution": "def magic_square_test(matrix):\n magic_sum = sum(matrix[0]) # Calculate the sum of the first row as the magic sum\n n = len(matrix) # Get the size of the matrix\n \n # Check the sum of all rows\n for row in range(1, n):\n if sum(matrix[row]) != magic_sum:\n return False\n \n # Check the sum of all columns\n for col in range(n):\n if sum(matrix[row][col] for row in range(n)) != magic_sum:\n return False\n \n # Check the sum of the main diagonal\n if sum(matrix[i][i] for i in range(n)) != magic_sum:\n return False\n \n # Check the sum of the secondary diagonal\n if sum(matrix[i][n - 1 - i] for i in range(n)) != magic_sum:\n return False\n \n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(arr):\n n = len(arr)\n s = sum(arr[0])\n \n # Check sums of each row\n for i in range(1, n):\n if sum(arr[i]) != s:\n return False\n \n # Check sums of each column\n for i in range(n):\n if sum(arr[j][i] for j in range(n)) != s:\n return False\n \n # Check sum of main diagonal\n if sum(arr[i][i] for i in range(n)) != s:\n return False\n \n # Check sum of secondary diagonal\n if sum(arr[i][n-i-1] for i in range(n)) != s:\n return False\n \n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(grid):\n # Function to check if a matrix is a magic square\n n = len(grid) # Number of rows/columns in the matrix\n \n # Calculate the sum of the first row to use as a reference\n magic_sum = sum(grid[0])\n \n # Check sums of all rows\n for row in grid:\n if sum(row) != magic_sum:\n return False\n \n # Check sums of all columns\n for col in range(n):\n if sum(grid[row][col] for row in range(n)) != magic_sum:\n return False\n \n # Check sum of the main diagonal\n if sum(grid[i][i] for i in range(n)) != magic_sum:\n return False\n \n # Check sum of the secondary diagonal\n if sum(grid[i][n - 1 - i] for i in range(n)) != magic_sum:\n return False\n \n # If all checks pass, it is a magic square\n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(grid):\n # Calculate the length of the grid\n n = len(grid)\n \n # Calculate the magic constant by summing the first row\n magic_constant = sum(grid[0])\n \n # Check the sum of each row\n for row in grid:\n if sum(row) != magic_constant:\n return False\n \n # Check the sum of each column\n for col in range(n):\n if sum(grid[row][col] for row in range(n)) != magic_constant:\n return False\n \n # Check the sum of the main diagonal\n if sum(grid[i][i] for i in range(n)) != magic_constant:\n return False\n \n # Check the sum of the secondary diagonal\n if sum(grid[i][n-1-i] for i in range(n)) != magic_constant:\n return False\n \n # If all checks pass, it is a magic square\n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(m):\n # Get the size of the matrix\n n = len(m)\n # Calculate the magic sum using the first row\n sum_of_magic = sum(m[0])\n \n # Check each row for the magic sum\n for i in range(1, n):\n if sum(m[i]) != sum_of_magic:\n return False\n \n # Check each column for the magic sum\n for i in range(n):\n if sum(m[j][i] for j in range(n)) != sum_of_magic:\n return False\n \n # Check the main diagonal\n if sum(m[i][i] for i in range(n)) != sum_of_magic:\n return False\n \n # Check the secondary diagonal\n if sum(m[i][n - i - 1] for i in range(n)) != sum_of_magic:\n return False\n \n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(test_matrix):\n # Check if the matrix is square\n if len(test_matrix) != len(test_matrix[0]):\n return False\n \n size = len(test_matrix)\n magic_constant = 0\n \n # Calculate the magic constant using the first row\n for num in test_matrix[0]:\n magic_constant += num\n \n # Check the sum of each row\n for row in test_matrix:\n if sum(row) != magic_constant:\n return False\n \n # Check the sum of each column\n for col in range(size):\n if sum(test_matrix[row][col] for row in range(size)) != magic_constant:\n return False\n \n # Check the sum of the main diagonal\n if sum(test_matrix[i][i] for i in range(size)) != magic_constant:\n return False\n \n # Check the sum of the secondary diagonal\n if sum(test_matrix[i][size - i - 1] for i in range(size)) != magic_constant:\n return False\n \n # If all checks pass, it is a magic square\n return True", "matching_cluster_idx": 13}, {"solution": "def magic_square_test(grid):\n magic = 0\n n = len(grid)\n \n # Sum the first row to set as the magic sum\n magic = sum(grid[0])\n \n # Check if sum of each row is the same\n for i in range(1, n):\n if sum(grid[i]) != magic:\n return False\n \n # Check if sum of each column is the same\n for i in range(n):\n if sum(grid[j][i] for j in range(n)) != magic:\n return False\n \n # Check if sum of diagonal (top-left to bottom-right) is the same\n if sum(grid[i][i] for i in range(n)) != magic:\n return False\n \n # Check if sum of anti-diagonal (top-right to bottom-left) is the same\n if sum(grid[i][n-1-i] for i in range(n)) != magic:\n return False\n \n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n # Calculate the size of the matrix\n size = len(matrix)\n \n # Calculate the sum of the first row to use as a reference\n total_sum = sum(matrix[0])\n \n # Check sums of the other rows\n for row in matrix[1:]:\n if sum(row) != total_sum:\n return False\n \n # Check sums of the columns\n for col in range(size):\n if sum(matrix[row][col] for row in range(size)) != total_sum:\n return False\n \n # Check sums of the diagonals\n if sum(matrix[i][i] for i in range(size)) != total_sum:\n return False\n if sum(matrix[i][size - 1 - i] for i in range(size)) != total_sum:\n return False\n \n # If all checks pass, it's a magic square\n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(magic_square):\n n = len(magic_square)\n \n # Calculate the sum of the first row to use as a reference\n magic_sum = sum(magic_square[0])\n \n # Check sums of rows\n for row in magic_square:\n if sum(row) != magic_sum:\n return False\n \n # Check sums of columns\n for col in range(n):\n if sum(magic_square[row][col] for row in range(n)) != magic_sum:\n return False\n \n # Check sum of the main diagonal\n if sum(magic_square[i][i] for i in range(n)) != magic_sum:\n return False\n \n # Check sum of the secondary diagonal\n if sum(magic_square[i][n-1-i] for i in range(n)) != magic_sum:\n return False\n \n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n # Initialize the magic constant with the sum of the first row\n magic_constant = sum(matrix[0])\n n = len(matrix)\n \n # Calculate the sum of each row\n for row in matrix:\n if sum(row) != magic_constant:\n return False\n \n # Calculate the sum of each column\n for col in range(n):\n if sum(matrix[row][col] for row in range(n)) != magic_constant:\n return False\n \n # Calculate the sum of the main diagonal\n if sum(matrix[i][i] for i in range(n)) != magic_constant:\n return False\n \n # Calculate the sum of the secondary diagonal\n if sum(matrix[i][n-i-1] for i in range(n)) != magic_constant:\n return False\n \n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(arr):\n n = len(arr)\n # Calculate the sum of the first row for the magic constant\n magic_constant = sum(arr[0])\n \n # Check sums of all rows\n for i in range(1, n):\n if sum(arr[i]) != magic_constant:\n return False\n \n # Check sums of all columns\n for i in range(n):\n if sum(arr[j][i] for j in range(n)) != magic_constant:\n return False\n \n # Check sum of main diagonal\n if sum(arr[i][i] for i in range(n)) != magic_constant:\n return False\n \n # Check sum of secondary diagonal\n if sum(arr[i][n - 1 - i] for i in range(n)) != magic_constant:\n return False\n \n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(magic_square):\n # Calculate the size of the matrix\n n = len(magic_square)\n \n # Calculate the magic number by summing the first row and dividing by n\n magic_number = sum(magic_square[0])\n \n # Check sums of all rows\n for row in magic_square:\n if sum(row) != magic_number:\n return False\n \n # Check sums of all columns\n for col in range(n):\n if sum(magic_square[row][col] for row in range(n)) != magic_number:\n return False\n \n # Check sum of the main diagonal\n if sum(magic_square[i][i] for i in range(n)) != magic_number:\n return False\n \n # Check sum of the secondary diagonal\n if sum(magic_square[i][n-i-1] for i in range(n)) != magic_number:\n return False\n \n # If all checks pass, the matrix is a magic square\n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix): \n # Determine the size of the square matrix\n n = len(matrix) \n \n # Calculate the sum of the first row for comparison\n total_sum = sum(matrix[0]) \n \n # Check sums of all rows\n for row in range(1, n): \n if sum(matrix[row]) != total_sum: \n return False\n \n # Check sums of all columns\n for col in range(n): \n if sum(matrix[row][col] for row in range(n)) != total_sum: \n return False\n \n # Check sum of the main diagonal\n if sum(matrix[i][i] for i in range(n)) != total_sum: \n return False\n \n # Check sum of the secondary diagonal\n if sum(matrix[i][n - i - 1] for i in range(n)) != total_sum: \n return False\n \n # If all checks pass, it's a magic square\n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(arr):\n # Calculate the size of the matrix\n N = len(arr)\n \n # Calculate the sum of the first row for reference\n magic_sum = sum(arr[0])\n \n # Calculate sums of each row\n for row in arr:\n if sum(row) != magic_sum:\n return False\n \n # Calculate sums of each column\n for col in range(N):\n if sum(arr[row][col] for row in range(N)) != magic_sum:\n return False\n \n # Calculate sum of the main diagonal\n if sum(arr[i][i] for i in range(N)) != magic_sum:\n return False\n \n # Calculate sum of the secondary diagonal\n if sum(arr[i][N - 1 - i] for i in range(N)) != magic_sum:\n return False\n \n # If all checks pass, it is a magic square\n return True", "matching_cluster_idx": 14}]}, "Mbpp/130": {"dps": 72.71300448430493, "dps_norm": 66.66666666666667, "pass@1": 74.0, "profiled": [{"solution": "def max_occurrences(arr):\n # Create a dictionary to store the frequency of each item\n freq = {}\n \n # Iterate over the array to count the frequency of each item\n for item in arr:\n if item in freq:\n freq[item] += 1\n else:\n freq[item] = 1\n \n # Initialize variables to keep track of the item with the maximum frequency\n max_item = 0\n max_val = 0\n \n # Iterate over the dictionary to find the item with the maximum frequency\n for item, value in freq.items():\n if value > max_val:\n max_val = value\n max_item = item\n \n # Return the item with the maximum frequency\n return max_item", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(arr):\n # Initialize a dictionary to store the frequency of each item\n d = {}\n # Iterate over each item in the list\n for i in arr:\n # Increment the count of the item in the dictionary\n d[i] = d.get(i, 0) + 1\n \n # Find the maximum value in the dictionary\n max_value = max(d.values())\n \n # Iterate over the dictionary to find the item(s) with the maximum frequency\n for (k, v) in d.items():\n if v == max_value:\n # Return the item with the maximum frequency\n return k", "matching_cluster_idx": 3}, {"solution": "from collections import defaultdict\ndef max_occurrences(nums):\n # Create a dictionary to store the frequency of each item\n freq = defaultdict(int)\n \n # Iterate through the list and count the frequency of each item\n for i in nums:\n freq[i] += 1\n \n # Initialize variables to store the item with maximum frequency and its count\n max_count = 0\n max_item = None\n \n # Iterate through the dictionary to find the item with the highest frequency\n for item, count in freq.items():\n if count > max_count:\n max_count = count\n max_item = item\n \n # Return the item with the maximum frequency\n return max_item", "matching_cluster_idx": 3}, {"solution": "from collections import Counter\ndef max_occurrences(nums):\n # Use Counter to count occurrences of each item\n count_dict = Counter(nums)\n # Find the item with the maximum occurrence\n res = max(count_dict, key=count_dict.get)\n return res", "matching_cluster_idx": 4}, {"solution": "def max_occurrences(list1):\n # Using the max function with key parameter to find the element with the maximum frequency\n return max(list1, key=list1.count)", "matching_cluster_idx": 1}, {"solution": "from collections import Counter\ndef max_occurrences(nums):\n # Count occurrences of each element in the list\n frequency = Counter(nums)\n # Find the element with the maximum frequency\n max_item = max(frequency, key=frequency.get)\n return max_item", "matching_cluster_idx": 4}, {"solution": "from collections import defaultdict\ndef max_occurrences(nums):\n # Dictionary to store frequency of each element\n my_dict = defaultdict(int)\n \n # Count frequency of each element\n for num in nums:\n my_dict[num] += 1\n \n # Return the element with the maximum frequency\n return max(my_dict, key=my_dict.get)", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(nums):\n # Use a dictionary to store the frequency of each number\n frequency = {}\n \n # Iterate over each number in the list\n for num in nums:\n # If the number is already in the dictionary, increment its count\n if num in frequency:\n frequency[num] += 1\n # If the number is not in the dictionary, add it with a count of 1\n else:\n frequency[num] = 1\n \n # Return the key (number) with the maximum value (frequency)\n return max(frequency, key=frequency.get)", "matching_cluster_idx": 3}, {"solution": "from collections import Counter\ndef max_occurrences(nums):\n # Use Counter to count occurrences of each number in the list\n frequency = Counter(nums)\n # Return the number with the maximum occurrence\n return max(frequency, key=frequency.get)", "matching_cluster_idx": 4}, {"solution": "from collections import Counter\ndef max_occurrences(nums):\n # Create a counter object to count occurrences of each item\n count = Counter(nums)\n # Find the item with the maximum frequency\n max_item = max(count, key=count.get)\n return max_item", "matching_cluster_idx": 4}, {"solution": "def max_occurrences(arr):\n # Initialize a dictionary to store the frequency of each element\n count = {}\n for i in arr:\n count[i] = count.get(i, 0) + 1\n \n # Initialize variables to keep track of the item with maximum frequency and its count\n max_count = 0\n max_item = arr[0]\n \n # Iterate through the dictionary to find the item with the maximum frequency\n for i in count:\n if count[i] > max_count:\n max_count = count[i]\n max_item = i\n \n # Return the item with maximum frequency\n return max_item", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(input_list):\n # Initialize a dictionary to keep track of item frequencies\n dict = {}\n \n # Iterate over each item in the input list\n for item in input_list:\n # If the item is already in the dictionary, increment its count\n if item in dict:\n dict[item] += 1\n # If the item is not in the dictionary, add it with a count of 1\n else:\n dict[item] = 1\n \n # Find the maximum frequency among all items\n max_value = max(dict.values())\n \n # Initialize a variable to store the item with the maximum frequency\n max_item = -1\n \n # Iterate over the dictionary items to find the item with the maximum frequency\n for (key, value) in dict.items():\n if max_value == value:\n # Return the item with the maximum frequency\n return key", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(nums):\n # Create a dictionary to store the frequency of each number\n freq = dict()\n # Find the maximum frequency\n max_freq = 0\n # Iterate over each number in the list\n for num in nums:\n # Increment the frequency of the current number\n freq[num] = freq.get(num, 0) + 1\n # Update the maximum frequency if necessary\n if freq[num] > max_freq:\n max_freq = freq[num]\n \n # Iterate over the list again to find the number with the maximum frequency\n for num in nums:\n if freq[num] == max_freq:\n return num", "matching_cluster_idx": 3}, {"solution": "from collections import defaultdict\ndef max_occurrences(arr):\n # Create a dictionary to store the frequency of each item\n frequency = defaultdict(int)\n \n # Iterate over each item in the array\n for item in arr:\n # Increment the count for the current item\n frequency[item] += 1\n \n # Find the item with the maximum frequency\n max_item = max(frequency, key=frequency.get)\n \n return max_item", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(nums):\n # Use dictionary to store the frequency of each element\n mp = {}\n \n # Traverse through the list and count the frequency of each element\n for x in nums:\n if x in mp:\n mp[x] += 1\n else:\n mp[x] = 1\n \n # Initialize a variable to store the maximum frequency found\n max_freq = -1\n # Initialize a variable to store the item with maximum frequency\n x = 0\n \n # Iterate through the dictionary to find the item with the maximum frequency\n for key, value in mp.items():\n if value > max_freq:\n max_freq = value\n x = key\n \n # Return the item with the maximum frequency\n return x", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(arr):\n # Dictionary to store the frequency of each element\n freq = {}\n for i in arr:\n if i in freq:\n # Increment the count if the element is already in the dictionary\n freq[i] += 1\n else:\n # Initialize the count to 1 if the element is not in the dictionary\n freq[i] = 1\n \n # Return the key with the maximum value from the dictionary\n return max(freq, key=freq.get)", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(nums):\n count_dict = {}\n \n # Count the frequency of each item\n for num in nums:\n if num in count_dict:\n count_dict[num] += 1\n else:\n count_dict[num] = 1\n \n max_occurrence = max(count_dict.values())\n max_key = None\n \n # Find the item with the maximum frequency\n for key, value in count_dict.items():\n if value == max_occurrence:\n max_key = key\n break\n \n return max_key", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(nums):\n # Create a dictionary to store the frequency of each element\n freq_dict = {}\n \n # Iterate through each number in the list\n for num in nums:\n # If the number is already in the dictionary, increment its count\n if num in freq_dict:\n freq_dict[num] += 1\n # Otherwise, add the number to the dictionary with a count of 1\n else:\n freq_dict[num] = 1\n \n # Find the item with the maximum frequency\n max_item = max(freq_dict, key=freq_dict.get)\n \n return max_item", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(test_list):\n # Initialize result and frequency counter\n res = 0\n freq = -float('inf')\n \n # Iterate through the list\n for ele in test_list:\n # Count occurrences of each element\n temp = test_list.count(ele)\n \n # Update result and frequency if current element's frequency is higher\n if temp > freq:\n res = ele\n freq = temp\n \n return res", "matching_cluster_idx": 1}, {"solution": "def max_occurrences(arr):\n # Dictionary to store the frequency of each element\n dict = {}\n \n # Count the frequency of each element\n for i in arr:\n if i not in dict:\n dict[i] = 0\n dict[i] += 1\n \n # Initialize variables to store the maximum frequency and its corresponding element\n max_key = arr[0]\n max_val = dict[arr[0]]\n \n # Find the element with the maximum frequency\n for (key, value) in dict.items():\n if value > max_val:\n max_val = value\n max_key = key\n \n return max_key", "matching_cluster_idx": 3}]}, "Mbpp/137": {"dps": null, "dps_norm": null, "pass@1": 1.0, "profiled": []}, "Mbpp/140": {"dps": 74.48757763975155, "dps_norm": 74.375, "pass@1": 98.0, "profiled": [{"solution": "def extract_singly(data):\n # Initialize an empty set to store unique numbers\n res = set()\n # Iterate through each sublist in the list of lists\n for i in range(len(data)):\n # Update the set with elements from the current sublist\n res.update(data[i])\n # Return the set containing unique numbers\n return res", "matching_cluster_idx": 6}, {"solution": "from itertools import chain\ndef extract_singly(list_of_lists):\n # Flatten the list of lists and convert it into a set to remove duplicates\n return set(chain.from_iterable(list_of_lists))", "matching_cluster_idx": 6}, {"solution": "def extract_singly(lst):\n # Use list comprehension to iterate through each sublist\n # Use set to remove duplicates and flatten the list of lists into a single set\n result = set(i for j in lst for i in j)\n return result", "matching_cluster_idx": 5}, {"solution": "def extract_singly(test_list):\n # Flatten the list of lists using a list comprehension\n res = [ele for sublist in test_list for ele in sublist]\n return res", "matching_cluster_idx": 5}, {"solution": "def extract_singly(lst):\n # Use a generator expression to iterate through each tuple in the list\n # and then through each element in the tuple to flatten the list of lists\n # Finally, convert the flattened elements into a set to remove duplicates\n return set(i for j in lst for i in j)", "matching_cluster_idx": 5}, {"solution": "def extract_singly(list_of_list):\n # Initialize an empty list to store the flattened elements\n num_list = []\n \n # Iterate through each sublist in the list of lists\n for i in range(len(list_of_list)):\n # Extend the num_list with the elements of the current sublist\n num_list.extend(list_of_list[i])\n \n # Convert the list to a set to remove duplicates and return it\n return set(num_list)", "matching_cluster_idx": 6}, {"solution": "def extract_singly(lst):\n # Convert each tuple in the list to a set to remove duplicates within each tuple,\n # then use the union of sets to combine all elements into a single set without duplicates.\n return set([y for x in lst for y in x])", "matching_cluster_idx": 5}, {"solution": "def extract_singly(nested_list):\n # Flatten the list of lists and convert to a set to remove duplicates\n return set(number for sublist in nested_list for number in sublist)", "matching_cluster_idx": 5}, {"solution": "def extract_singly(lst):\n # Use a set comprehension to flatten the list of lists into a single set of numbers\n return {val for tup in lst for val in tup}", "matching_cluster_idx": 5}, {"solution": "def extract_singly(nested_list):\n # Initialize an empty set to store unique elements\n single_set = set()\n \n # Iterate through each sublist in the nested list\n for sub_list in nested_list:\n # Add each element of the sublist to the set\n for element in sub_list:\n single_set.add(element)\n \n # Return the set of unique elements\n return single_set", "matching_cluster_idx": 3}, {"solution": "def extract_singly(test_list):\n # Initialize an empty list to store unique elements\n res = []\n \n # Iterate through each sublist in the input list of lists\n for sub in test_list:\n # Use a set comprehension to collect unique elements\n res.extend({ele for ele in sub})\n \n # Return the list containing unique elements as a set\n return set(res)", "matching_cluster_idx": 4}, {"solution": "def extract_singly(given_list):\n # Flatten the list of lists into a single list\n flat_list = [element for sublist in given_list for element in sublist]\n # Convert the flat list into a set to remove duplicates\n result_set = set(flat_list)\n return result_set", "matching_cluster_idx": 5}, {"solution": "def extract_singly(test_list):\n # Flatten the list of lists and convert it to a set\n res = set(item for sublist in test_list for item in sublist)\n return res", "matching_cluster_idx": 5}, {"solution": "def extract_singly(test_list):\n # Use set comprehension to flatten the list of lists into a single set\n res = {ele for sub_list in test_list for ele in sub_list}\n return res", "matching_cluster_idx": 5}, {"solution": "def extract_singly(A):\n # Initialize an empty set to store unique numbers\n res = set()\n \n # Iterate through each sublist in the list of lists\n for i in range(len(A)):\n for j in range(len(A[i])):\n # Add each number to the set\n res.add(A[i][j])\n \n # Return the set containing unique numbers\n return res", "matching_cluster_idx": 3}, {"solution": "def extract_singly(lst):\n # Flatten the list of lists using a generator expression\n flattened = (x for y in lst for x in y)\n # Convert the flattened sequence to a set to remove duplicates\n output = set(flattened)\n return output", "matching_cluster_idx": 5}, {"solution": "def extract_singly(test_list):\n # Flatten the list of lists and convert to a set to remove duplicates\n res = set(num for sub in test_list for num in sub)\n return res", "matching_cluster_idx": 5}, {"solution": "def extract_singly(test_list):\n # Flatten the list of lists and convert it into a set of numbers\n res = {ele for sub in test_list for ele in sub}\n return res", "matching_cluster_idx": 5}, {"solution": "def extract_singly(list_of_lists):\n # Flatten the list of lists and convert it to a set\n return set(val for sublist in list_of_lists for val in sublist)", "matching_cluster_idx": 5}, {"solution": "def extract_singly(lis):\n # Initialize an empty list to store the flattened elements\n singly = []\n # Iterate through each sublist in the list of lists\n for sub_lis in lis:\n # Extend the singly list with each element from the sublist\n singly.extend(sub_lis)\n # Convert the list to a set to remove duplicates and return it\n return set(singly)", "matching_cluster_idx": 6}]}, "Mbpp/141": {"dps": 84.31885574742718, "dps_norm": 46.15384615384615, "pass@1": 13.0, "profiled": [{"solution": "def pancake_sort(A):\n # Get the number of elements in the list\n cur_size = len(A)\n \n # Traverse through the list from the end to the beginning\n while cur_size > 1:\n # Find the index of the maximum element in the unsorted portion of the list\n mi = A.index(max(A[0:cur_size]))\n \n # If the maximum element is not already in the correct position\n if mi != cur_size - 1:\n # Flip the list up to the position of the maximum element\n A[0:mi+1] = reversed(A[0:mi+1])\n # Flip the entire unsorted portion of the list\n A[0:cur_size] = reversed(A[0:cur_size])\n \n # Reduce the size of the unsorted portion\n cur_size -= 1\n \n # Return the sorted list\n return A", "matching_cluster_idx": 3}, {"solution": "def flip(lst, k):\n # Flip the elements up to index k\n temp = lst[:k]\n temp.reverse()\n lst[:k] = temp\n return lst\ndef pancake_sort(lst):\n # Start with the unsorted portion of the list\n for curr_size in range(len(lst), 1, -1):\n # Find the index of the maximum element in the unsorted part\n max_index = lst.index(max(lst[:curr_size]))\n # Flip the list up to the found index\n lst = flip(lst, max_index + 1)\n # Flip the list to move the maximum element to its correct position\n lst = flip(lst, curr_size)\n return lst", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(arr):\n # Loop through the array from the end to the beginning\n for i in range(len(arr) - 1, 0, -1):\n # Find the index of the maximum element in the unsorted portion\n max_index = arr.index(max(arr[:i + 1]))\n \n # If the maximum element is not already in its correct position\n if max_index != i:\n # Flip the array up to the index of the maximum element\n arr[:max_index + 1] = reversed(arr[:max_index + 1])\n # Flip the array up to the current position\n arr[:i + 1] = reversed(arr[:i + 1])\n return arr", "matching_cluster_idx": 3}, {"solution": "def flip(arr, k):\n # Reverse the elements from 0 to k\n return arr[:k+1][::-1] + arr[k+1:]\ndef pancake_sort(arr):\n # Get the length of the list\n n = len(arr)\n while n > 1:\n # Find the index of the maximum element in the unsorted part of the list\n max_index = arr.index(max(arr[:n]))\n # If the maximum element is not already in its correct position\n if max_index != n - 1:\n # Flip the list up to the position of the maximum element\n arr = flip(arr, max_index)\n # Flip the entire unsorted part of the list\n arr = flip(arr, n - 1)\n # Decrement the size of the unsorted part\n n -= 1\n return arr", "matching_cluster_idx": 3}, {"solution": "def flip(arr, k): \n # Reverse the sub-list from 0 to k\n sub_list = arr[:k+1]\n sub_list.reverse()\n arr[:k+1] = sub_list\n return arr\ndef pancake_sort(arr): \n # Function to perform pancake sort\n n = len(arr)\n while n > 1: \n # Find the index of the maximum element in arr\n mi = arr.index(max(arr[0:n])) \n \n # Move the maximum number to end of array \n # if it is not already at the end \n if mi != n-1: \n # First move maximum number to beginning \n arr = flip(arr, mi) \n \n # Now move the maximum number to end by reversing current array \n arr = flip(arr, n-1) \n n -= 1\n return arr", "matching_cluster_idx": 3}, {"solution": "def flip(arr, i):\n # Reverse the elements from the start of the array up to and including index i\n start = 0\n while start < i:\n arr[start], arr[i] = arr[i], arr[start]\n start += 1\n i -= 1\n return arr\ndef pancake_sort(arr):\n # Start from the end of the array and work towards the beginning\n arr_len = len(arr)\n while arr_len > 1:\n # Find the index of the maximum element in arr\n max_index = arr.index(max(arr[:arr_len]))\n # Flip the maximum element to the beginning\n arr = flip(arr, max_index)\n # Flip the maximum element to its correct position at the end of the array\n arr = flip(arr, arr_len - 1)\n # Move to the next unsorted element\n arr_len -= 1\n return arr", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(arr):\n # Initialize the size of the array to be sorted\n n = len(arr)\n \n # Traverse through all array elements\n for i in range(n, 1, -1):\n # Find the index of the maximum element in arr[0..i-1]\n max_index = arr.index(max(arr[:i]))\n \n # Move the maximum element to end of current array if it's not already at the end\n if max_index != i - 1:\n # First move the maximum number to the beginning\n arr[:max_index + 1] = reversed(arr[:max_index + 1])\n # Now move the maximum number to its correct position\n arr[:i] = reversed(arr[:i])\n \n return arr", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(arr):\n # Function to reverse the elements from the start to the given index\n def flip(sub_arr, k):\n sub_arr[:k+1] = sub_arr[:k+1][::-1]\n \n # Start sorting from the last element\n n = len(arr)\n while n > 1:\n # Find the index of the maximum element in arr[0..n-1]\n mi = arr.index(max(arr[0:n]))\n \n # Move the maximum element to the end of current array\n if mi != n-1:\n # First move the maximum number to the beginning\n flip(arr, mi)\n # Now move the maximum number to the end by reversing current array\n flip(arr, n-1)\n n -= 1\n return arr", "matching_cluster_idx": 3}, {"solution": "def flip(arr, i):\n # Reverse the elements from the start to the i-th element\n temp = arr[:i + 1]\n temp.reverse()\n arr[:i + 1] = temp\n return arr\ndef pancake_sort(arr):\n # Start from the complete array and reduce size by one in each iteration\n curr_size = len(arr)\n while curr_size > 1:\n # Find the index of the maximum element in arr[0..curr_size-1]\n mi = arr.index(max(arr[:curr_size]))\n \n # Move the maximum number to end of current array if it's not already at the end\n if mi != curr_size - 1:\n # First move maximum number to beginning\n arr = flip(arr, mi)\n \n # Now move the maximum number to end by reversing current array\n arr = flip(arr, curr_size - 1)\n curr_size -= 1\n return arr", "matching_cluster_idx": 3}, {"solution": "def flip(sub_li, k):\n # Function to reverse elements from 0 to k\n start = 0\n end = k\n while start < end:\n sub_li[start], sub_li[end] = sub_li[end], sub_li[start]\n start += 1\n end -= 1\n return sub_li\ndef pancake_sort(arr):\n # Initialize the array size\n arr_len = len(arr)\n # One by one reduce size of array\n while arr_len > 1:\n # Find the index of maximum element in arr[0..arr_len-1]\n mi = arr.index(max(arr[0:arr_len]))\n # Move the maximum number to end of current array if it's not already at the end\n if mi != arr_len-1:\n # First move maximum number to beginning\n arr = flip(arr, mi)\n # Now move the maximum number to end by reversing current array\n arr = flip(arr, arr_len-1)\n arr_len -= 1\n return arr", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(arr):\n # Function to flip the array from 0 to i\n def flip(sub_arr, i):\n start = 0\n end = i\n while start < end:\n # Swap the elements at start and end indices\n sub_arr[start], sub_arr[end] = sub_arr[end], sub_arr[start]\n start += 1\n end -= 1\n \n # Loop through the array to sort it\n for i in range(len(arr), 1, -1):\n # Find the index of the maximum element in arr[0..i-1]\n max_index = arr.index(max(arr[:i]))\n \n # Move the maximum element to the beginning\n flip(arr, max_index)\n \n # Move the maximum element to its correct position\n flip(arr, i - 1)\n \n return arr", "matching_cluster_idx": 2}, {"solution": "def flip(lst, i):\n # Reverse elements from the start of the list up to the i-th element\n return lst[:i+1][::-1] + lst[i+1:]\ndef find_max_index(lst, n):\n # Find the index of the maximum element in the first n elements\n max_index = 0\n for i in range(1, n):\n if lst[i] > lst[max_index]:\n max_index = i\n return max_index\ndef pancake_sort(arr):\n # Sort the array using the pancake sort algorithm\n curr_size = len(arr)\n while curr_size > 1:\n # Find the index of the maximum element in the current unsorted part of the array\n mi = find_max_index(arr, curr_size)\n # If the maximum element is not already at the end, move it to the end\n if mi != curr_size - 1:\n arr = flip(arr, mi)\n arr = flip(arr, curr_size - 1)\n curr_size -= 1\n return arr", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(A):\n # Iterate through the list from the end to the beginning\n for i in range(len(A) - 1, 0, -1):\n # Find the index of the maximum element in the unsorted portion of the list\n max_index = A.index(max(A[0:i + 1]))\n \n # If the maximum element is not already at the end, flip it to the front\n if max_index != i:\n # Flip the list up to the maximum element\n A[:max_index + 1] = A[:max_index + 1][::-1]\n # Flip the list up to the end of the unsorted portion\n A[:i + 1] = A[:i + 1][::-1]\n return A", "matching_cluster_idx": 3}]}, "Mbpp/166": {"dps": 94.75999999999999, "dps_norm": 53.75, "pass@1": 84.0, "profiled": [{"solution": "def find_even_pair(a):\n # Initialize count of pairs\n count = 0\n \n # Iterate through each pair\n for i in range(len(a)):\n for j in range(i + 1, len(a)):\n # Check if XOR of the pair is even\n if (a[i] ^ a[j]) % 2 == 0:\n # Increment count if condition is met\n count += 1\n \n # Return the total count of such pairs\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(arr):\n ans = 0\n # Iterate through all possible pairs\n for i in range(len(arr)):\n for j in range(i + 1, len(arr)):\n # Check if the XOR of the pair is even\n if (arr[i] ^ arr[j]) % 2 == 0:\n ans += 1\n return ans", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(arr):\n # Initialize the count of pairs\n count = 0\n # Iterate over each pair combination\n for i in range(len(arr)):\n for j in range(i + 1, len(arr)):\n # Check if the XOR of the pair is even\n if (arr[i] ^ arr[j]) % 2 == 0:\n # Increment the count if true\n count += 1\n # Return the total count of pairs with an even XOR\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(nums):\n # Initialize count of pairs\n count = 0\n # Iterate over each pair of numbers in the list\n for i in range(len(nums)):\n for j in range(i + 1, len(nums)):\n # Check if the XOR of the pair is even\n if (nums[i] ^ nums[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(nums):\n # Initialize count of pairs with even xor result\n cnt = 0\n # Calculate the number of even and odd numbers in the list\n even = sum(n & 1 == 0 for n in nums)\n odd = len(nums) - even\n # The number of pairs with even xor is the sum of products of even and odd counts\n cnt = even * (even - 1) // 2 + odd * (odd - 1) // 2\n return cnt", "matching_cluster_idx": 2}, {"solution": "def find_even_pair(arr):\n # Initialize the count of even XOR pairs to 0\n count = 0\n \n # Iterate over all pairs of integers in the list\n for i in range(len(arr)):\n for j in range(i + 1, len(arr)):\n # Calculate the XOR of the pair and check if it's even\n if (arr[i] ^ arr[j]) % 2 == 0:\n # If even, increment the count\n count += 1\n \n # Return the total count of even XOR pairs\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(arr):\n # Initialize a counter for pairs with an even XOR\n count = 0\n # Iterate through each element in the array\n for i in range(len(arr)):\n # Compare the current element with all other elements\n for j in range(i + 1, len(arr)):\n # XOR the two elements and check if the result is even\n if (arr[i] ^ arr[j]) % 2 == 0:\n # Increment the counter if the result is even\n count += 1\n # Return the total count of such pairs\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(array):\n count = 0\n n = len(array)\n \n # Iterate over each element in the array\n for i in range(n):\n # Compare the current element with the rest of the elements\n for j in range(i + 1, n):\n # Check if the XOR of the current pair is even\n if (array[i] ^ array[j]) % 2 == 0:\n count += 1\n \n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(arr):\n # Initialize the counter for pairs whose XOR is even\n even_count = 0\n \n # Iterate through the array\n for i in range(len(arr)):\n # Compare each element with every other element in the array\n for j in range(i + 1, len(arr)):\n # Check if the XOR of the current pair is even\n if (arr[i] ^ arr[j]) % 2 == 0:\n # Increment the counter if the condition is met\n even_count += 1\n \n # Return the total count of pairs\n return even_count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(arr):\n # Initialize a counter to keep track of the number of valid pairs\n count = 0\n \n # Iterate through each pair of elements in the array\n for i in range(len(arr)):\n for j in range(i + 1, len(arr)):\n # Check if the XOR of the current pair is even\n if (arr[i] ^ arr[j]) % 2 == 0:\n # Increment the counter if the condition is met\n count += 1\n \n # Return the total count of pairs whose XOR is even\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(arr):\n # Initialize a counter for the number of pairs with an even XOR\n cnt = 0\n \n # Iterate over the array with two nested loops to check all pairs\n for i in range(len(arr)):\n for j in range(i + 1, len(arr)):\n # Check if the XOR of the current pair is even\n if (arr[i] ^ arr[j]) % 2 == 0:\n cnt += 1\n \n # Return the total count of pairs with an even XOR\n return cnt", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(arr):\n # Initialize count of even xor pairs\n ans = 0\n \n # Iterate through the list\n for i in range(len(arr)):\n # Iterate through the list from the next element\n for j in range(i + 1, len(arr)):\n # Calculate xor of the current pair\n xor = arr[i] ^ arr[j]\n # Check if the xor is even\n if xor % 2 == 0:\n # Increment the count if even\n ans += 1\n \n # Return the total count of even xor pairs\n return ans", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(arr):\n count = 0 # Initialize count of pairs whose XOR is even\n \n # Iterate over each pair of elements in the array\n for i in range(len(arr)):\n for j in range(i + 1, len(arr)):\n # Check if the XOR of the pair is even\n if (arr[i] ^ arr[j]) % 2 == 0:\n count += 1 # Increment count if the XOR is even\n \n return count # Return the total count of even XOR pairs", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(lst):\n # Initialize count of even XOR pairs to 0\n count = 0\n # Use nested loops to compare each pair in the list\n for i in range(len(lst)):\n for j in range(i+1, len(lst)):\n # Check if XOR of the current pair is even\n if ((lst[i] ^ lst[j]) & 1) == 0:\n # Increment count if XOR is even\n count += 1\n # Return the total count of even XOR pairs\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(arr):\n # Initialize counter for pairs with even XOR\n count = 0\n \n # Iterate over each element in the array\n for i in range(len(arr)):\n # Compare the current element with the rest of the array\n for j in range(i + 1, len(arr)):\n # Calculate the XOR of the current pair\n xor = arr[i] ^ arr[j]\n # Check if the XOR is even\n if xor % 2 == 0:\n # Increment the counter if even XOR\n count += 1\n \n # Return the total count of pairs with even XOR\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(arr):\n # Initialize the count of pairs whose XOR is even\n count = 0\n \n # Iterate through each element in the array\n for i in range(len(arr)):\n # Compare the current element with all other elements\n for j in range(i + 1, len(arr)):\n # XOR the current pair of elements\n if (arr[i] ^ arr[j]) % 2 == 0:\n # If the XOR is even, increment the count\n count += 1\n \n # Return the total count of pairs with an even XOR\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(nums):\n # Count the number of pairs with an even xor result\n return sum((nums[i] ^ nums[j]) % 2 == 0 for i in range(len(nums)) for j in range(i + 1, len(nums)))", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(arr):\n # Initialize count of pairs\n cnt = 0\n \n # Iterate through each element in the array\n for i in range(len(arr)):\n for j in range(i + 1, len(arr)):\n # Check if the XOR of the current pair is even\n if (arr[i] ^ arr[j]) % 2 == 0:\n cnt += 1\n \n # Return the total count of pairs with an even XOR\n return cnt", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(arr):\n # Count the number of even and odd elements in the array\n odd = 0\n even = 0\n for num in arr:\n if num % 2 == 0:\n even += 1\n else:\n odd += 1\n \n # The number of pairs that have an even XOR is the sum of:\n # - The number of ways to choose 2 even numbers\n # - The number of ways to choose 2 odd numbers\n return even * (even - 1) // 2 + odd * (odd - 1) // 2", "matching_cluster_idx": 3}, {"solution": "def find_even_pair(arr):\n # Initialize count to zero\n count = 0\n \n # Iterate through each element in the array\n for i in range(len(arr)):\n # Compare the current element with the rest of the array\n for j in range(i + 1, len(arr)):\n # Calculate the XOR of the pair\n xor_result = arr[i] ^ arr[j]\n \n # Check if the XOR result is even\n if xor_result % 2 == 0:\n # Increment the count if the XOR is even\n count += 1\n \n # Return the total count of pairs with even XOR\n return count", "matching_cluster_idx": 1}]}, "Mbpp/170": {"dps": 62.572463768115945, "dps_norm": 80.0, "pass@1": 97.0, "profiled": [{"solution": "def sum_range_list(lst, l, r):\n # Calculate the sum of elements in the list within the specified range [l, r]\n return sum(lst[l:r + 1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(lst, start_index, end_index):\n # Calculate the sum of elements from start_index to end_index (inclusive)\n # It is assumed that the input indices are valid and within the list bounds\n total_sum = sum(lst[start_index:end_index + 1])\n return total_sum", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(numbers, left, right):\n # Initialize the sum to zero\n total = 0\n # Iterate over the sublist from index 'left' to 'right' (inclusive)\n for i in range(left, right + 1):\n total += numbers[i] # Add the current element to the total sum\n return total # Return the computed sum", "matching_cluster_idx": 4}, {"solution": "def sum_range_list(lst, left, right):\n # Initialize the sum to 0\n sum1 = 0\n # Iterate over the sublist from index left to right (inclusive)\n for i in range(left, right + 1):\n sum1 += lst[i]\n # Return the computed sum\n return sum1", "matching_cluster_idx": 4}, {"solution": "def sum_range_list(lst, start, end):\n # Calculate the sum of elements from index 'start' to 'end' (inclusive)\n return sum(lst[i] for i in range(start, end + 1))", "matching_cluster_idx": 4}, {"solution": "def sum_range_list(numbers, start, end):\n # Use list slicing to extract the sublist and the sum function to calculate its sum\n total = sum(numbers[start:end+1])\n return total", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(input_list, range_start, range_end):\n # Initialize sum to 0\n total_sum = 0\n # Iterate through the specified range of indices\n for i in range(range_start, range_end + 1):\n # Add the element at the current index to the total sum\n total_sum += input_list[i]\n # Return the total sum of the elements within the specified range\n return total_sum", "matching_cluster_idx": 4}, {"solution": "def sum_range_list(numbers, start, end):\n # Initialize the sum to zero\n res = 0\n # Iterate over the range from start to end (inclusive)\n for i in range(start, end + 1):\n # Add the current number in the list to the result\n res += numbers[i]\n # Return the final sum\n return res", "matching_cluster_idx": 4}, {"solution": "def sum_range_list(nums, a, b):\n # Calculate the sum of elements in the list from index a to index b (inclusive)\n return sum(nums[a:b+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(arr, l, r):\n # Initialize a variable to store the sum of the elements within the specified range\n sum = 0\n \n # Iterate over the specified range in the list\n for i in range(l, r + 1):\n # Add the element at the current index to the sum\n sum += arr[i]\n \n # Return the calculated sum\n return sum", "matching_cluster_idx": 4}, {"solution": "def sum_range_list(list, start, end):\n # Calculate the sum of elements from start index to end index (inclusive)\n return sum(list[start:end + 1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(nums, L, R):\n # Initialize the sum variable to store the sum of the elements within the specified range\n s = 0\n # Iterate over the range from L to R (inclusive) and add each element to the sum\n for i in range(L, R + 1):\n s += nums[i]\n # Return the calculated sum\n return s", "matching_cluster_idx": 4}, {"solution": "def sum_range_list(num_list, m, n):\n # Calculate the sum of elements in the range [m, n] inclusive\n total = sum(num_list[m:n+1])\n return total", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(lst, left, right):\n # Use list slicing to extract the sublist from index 'left' to 'right' (inclusive)\n sublist = lst[left:right + 1]\n \n # Initialize a variable to store the sum of the sublist\n summation = 0\n \n # Iterate over each number in the sublist\n for num in sublist:\n # Add the current number to the summation\n summation += num\n \n # Return the total sum of the sublist\n return summation", "matching_cluster_idx": 5}, {"solution": "def sum_range_list(l, i, j):\n # Calculate the sum of elements in the list l from index i to index j (inclusive)\n result = sum(l[i:j + 1])\n return result", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(nums, low, high):\n # Initialize a variable to store the sum of the elements in the specified range\n total_sum = 0\n # Iterate over the range from low to high (inclusive)\n for i in range(low, high + 1):\n # Add the current element to the total sum\n total_sum += nums[i]\n # Return the total sum of the elements in the specified range\n return total_sum", "matching_cluster_idx": 4}, {"solution": "def sum_range_list(nums, start, end):\n # Iterate through the list from the start index to the end index (inclusive)\n # Sum the elements that fall within the specified range\n return sum(nums[i] for i in range(start, end + 1))", "matching_cluster_idx": 4}, {"solution": "def sum_range_list(nums, l, r):\n # Calculate the sum of numbers in the list from index l to r (inclusive)\n return sum(nums[l:r+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(nums, L, R):\n # Initialize sum to zero\n sum = 0\n # Iterate over the range from L to R (inclusive)\n for i in range(L, R + 1):\n # Add the current element to the sum\n sum += nums[i]\n # Return the calculated sum\n return sum", "matching_cluster_idx": 4}, {"solution": "def sum_range_list(arr, left, right):\n # Calculate the sum of elements in the list from index 'left' to 'right' (inclusive)\n sum_val = sum(arr[left:right + 1])\n return sum_val", "matching_cluster_idx": 7}]}, "Mbpp/226": {"dps": 74.57364341085271, "dps_norm": 31.42857142857143, "pass@1": 99.0, "profiled": [{"solution": "def odd_values_string(str):\n # Initialize an empty string to store characters at even indices\n result = ''\n \n # Iterate over the string using enumerate to get both index and character\n for index, value in enumerate(str):\n # Check if the index is even (0-based index)\n if index % 2 == 0:\n # Append the character at the even index to the result string\n result += value\n \n # Return the final result string\n return result", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(str1):\n # Initialize an empty string to store the result\n result = \"\"\n # Iterate over the string using enumerate to get both index and character\n for i, c in enumerate(str1):\n # Check if the index is even (odd index values)\n if i % 2 == 0:\n # Append the character at the even index to the result string\n result = result + c\n # Return the result string\n return result", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(str1):\n # Create a new string with characters from even index values\n result_str = ''\n for index in range(len(str1)):\n if index % 2 == 0:\n result_str += str1[index]\n return result_str", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(str):\n # Join characters at even indices (0-based indexing)\n return \"\".join([str[i] for i in range(len(str)) if i % 2 == 0])", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(str1):\n # Initialize an empty string to store the result\n result = ''\n # Iterate over the string using enumerate to get both index and character\n for index, char in enumerate(str1):\n # Check if the index is even (since index starts from 0, even indices correspond to odd positions)\n if index % 2 == 0:\n # Append the character at the even index to the result string\n result += char\n # Return the resulting string\n return result", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(str):\n # Initialize an empty string to store the result\n result = \"\"\n # Iterate over the string using index and character\n for i in range(len(str)):\n # Check if the index is even\n if i % 2 == 0:\n # Append the character at the even index to the result string\n result += str[i]\n # Return the result string\n return result", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(str):\n # Join characters with even indices (0, 2, 4, ...) using a list comprehension\n return \"\".join([str[i] for i in range(len(str)) if i % 2 == 0])", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(str1):\n # Initialize an empty string to store the result\n result = \"\"\n # Iterate over the string using enumerate to get both index and character\n for index, character in enumerate(str1):\n # Check if the index is even\n if index % 2 == 0:\n # Append the character at the even index to the result string\n result += character\n # Return the resulting string\n return result", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(str):\n # Use string slicing to get characters at even indices (0, 2, 4, ...)\n result = str[::2]\n return result", "matching_cluster_idx": 6}, {"solution": "def odd_values_string(str1):\n # Initialize an empty string to store the result\n result = ''\n # Iterate over the string with index\n for index in range(len(str1)):\n # Check if the index is even\n if index % 2 == 0:\n # Append the character at the current index to the result string\n result += str1[index]\n # Return the resulting string\n return result", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(str1):\n # Use list comprehension to select characters at even indices\n result = str1[::2]\n return result", "matching_cluster_idx": 6}, {"solution": "def odd_values_string(str1):\n # Initialize an empty string to store characters with even indices\n result = \"\"\n # Iterate over the string using enumerate to get both index and character\n for index, char in enumerate(str1):\n # Check if the index is even\n if index % 2 == 0:\n # Append the character at even index to the result string\n result += char\n return result", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(str1):\n # Initialize an empty string to store the result\n result = ''\n # Iterate through the string using index\n for i in range(len(str1)):\n # Check if the index is even\n if i % 2 == 0:\n # Append the character at the even index to the result string\n result += str1[i]\n return result", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(str):\n # Using list comprehension to filter characters at even indices (0-based)\n return \"\".join([str[i] for i in range(len(str)) if i % 2 == 0])", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(input_str):\n # Use string slicing to select characters at even indices\n return input_str[::2]", "matching_cluster_idx": 6}, {"solution": "def odd_values_string(input):\n # Using slicing to select characters with even indices\n return input[0::2]", "matching_cluster_idx": 6}, {"solution": "def odd_values_string(str1):\n # Initialize an empty string to store the result\n result = ''\n # Iterate over the string using enumerate to get both index and character\n for index, character in enumerate(str1):\n # Check if the index is even\n if index % 2 == 0:\n # Append the character to the result string\n result += character\n # Return the resulting string\n return result", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(str):\n # Initialize an empty string to store the result\n result = \"\"\n \n # Iterate over the string using enumerate to get both index and character\n for index, char in enumerate(str):\n # Check if the index is even (thereby the character is at an odd position in human-readable counting)\n if index % 2 == 0:\n result += char\n \n # Return the result string\n return result", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(str):\n # Initialize an empty string to store the result\n result = ''\n \n # Iterate over the string using enumerate to get both index and character\n for i, v in enumerate(str):\n # Check if the index is even (i.e., odd character position)\n if i % 2 == 0:\n # Append the character to the result string\n result += v\n \n # Return the result string\n return result", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(input_string):\n # Initialize an empty string to store the result\n result_string = \"\"\n # Iterate over the string using enumerate to get both index and character\n for i, char in enumerate(input_string):\n # Check if the index is even\n if i % 2 == 0:\n # Append the character to the result string\n result_string += char\n # Return the resulting string\n return result_string", "matching_cluster_idx": 0}]}, "Mbpp/230": {"dps": 95.95238095238095, "dps_norm": 98.125, "pass@1": 99.0, "profiled": [{"solution": "def replace_blank(input_string, input_char):\n # Replace all blank spaces in the string with the specified character\n result = input_string.replace(\" \", input_char)\n return result", "matching_cluster_idx": 7}, {"solution": "def replace_blank(s, c):\n # Replace all blank spaces in the string 's' with the character 'c'\n s = s.replace(' ', c)\n return s", "matching_cluster_idx": 7}, {"solution": "def replace_blank(string, ch):\n # Replace each blank space in the string with the given character\n return string.replace(\" \", ch)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(s, c):\n # Replace blank spaces in the string 's' with the character 'c'\n s = s.replace(' ', c)\n return s", "matching_cluster_idx": 7}, {"solution": "def replace_blank(my_string, ch):\n # Replace all blank spaces (' ') in the string with the specified character\n my_string = my_string.replace(\" \", ch)\n # Return the modified string\n return my_string", "matching_cluster_idx": 7}, {"solution": "def replace_blank(str, c):\n # Replace all blank spaces in the string with the given character\n return str.replace(\" \", c)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(st, ch):\n # Replace all blank spaces in the string 'st' with the character 'ch'\n res = st.replace(' ', ch)\n return res", "matching_cluster_idx": 7}, {"solution": "def replace_blank(s, c):\n # Replace each blank space in the string with the specified character\n return s.replace(' ', c)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(st, c):\n # Replace each blank space (' ') in the string with the specified character (c)\n result = st.replace(' ', c)\n return result", "matching_cluster_idx": 7}, {"solution": "def replace_blank(s, c):\n # Replace all blank spaces in the string 's' with the character 'c'\n s = s.replace(' ', c)\n return s", "matching_cluster_idx": 7}, {"solution": "def replace_blank(s, c):\n # Replace all blank spaces in the string with the specified character\n return s.replace(' ', c)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(string, char):\n # Initialize an empty string to store the result\n result_string = ''\n \n # Iterate through each character in the input string\n for char_in_string in string:\n # Check if the current character is a blank space\n if char_in_string == ' ':\n # If it is, append the specified character to the result string\n result_string += char\n else:\n # If it is not, append the current character to the result string\n result_string += char_in_string\n \n # Return the modified string\n return result_string", "matching_cluster_idx": 4}, {"solution": "def replace_blank(str1, char1):\n # Replace all occurrences of blank spaces in the string with the specified character\n result = str1.replace(\" \", char1)\n return result", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string, replacement_char):\n # Replace all occurrences of blank spaces with the specified character\n modified_string = input_string.replace(' ', replacement_char)\n return modified_string", "matching_cluster_idx": 7}, {"solution": "def replace_blank(s, char):\n # Use the replace() method to replace blank spaces with the specified character\n return s.replace(\" \", char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(text, character):\n # Replace all blank spaces in the string with the specified character\n text = text.replace(\" \", character)\n return text", "matching_cluster_idx": 7}, {"solution": "def replace_blank(text, s):\n # Replace all blank spaces in the input string with the specified character\n return text.replace(\" \", s)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(str1, ch):\n # Use the replace() method to replace all blank spaces with the specified character\n result = str1.replace(\" \", ch)\n # Return the modified string\n return result", "matching_cluster_idx": 7}, {"solution": "def replace_blank(text, char):\n # Replace all blank spaces in the input string with the specified character\n return text.replace(' ', char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(str, c):\n # Use the string's replace method to substitute ' ' (blank spaces) with the specified character 'c'\n return str.replace(' ', c)", "matching_cluster_idx": 7}]}, "Mbpp/239": {"dps": 83.62068965517241, "dps_norm": 82.5, "pass@1": 32.0, "profiled": [{"solution": "def get_total_number_of_sequences(m, n):\n # Initialize a 2D list to store the number of sequences of length i with the last element j\n dp = [[0 for i in range(m + 1)] for j in range(n + 1)]\n \n # Base case: There's one way to form a sequence of length 1 with any element 1 to m\n for i in range(1, m + 1):\n dp[1][i] = 1\n \n # Fill the dp table\n for i in range(2, n + 1):\n for j in range(1, m + 1):\n # Sum the number of ways to form a sequence of length i-1 with elements up to j/2\n dp[i][j] = sum(dp[i - 1][k] for k in range(1, j // 2 + 1))\n \n # Return the total number of sequences of length n with elements up to m\n return sum(dp[n][i] for i in range(1, m + 1))", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n # Initialize the solution matrix with zeros\n sol = [[0 for i in range(n + 1)] for i in range(m + 1)]\n \n # Iterate through each possible end value of the sequence\n for i in range(1, m + 1):\n # Calculate the number of sequences of length 1\n sol[i][1] = i\n \n # Iterate through each possible sequence length\n for i in range(1, m + 1):\n # Iterate through each possible end value of the sequence\n for j in range(2, n + 1):\n # Calculate the number of sequences of length j ending with i\n sol[i][j] = sol[i - 1][j] + sol[i // 2][j - 1]\n \n # Return the number of sequences of length n ending with m\n return sol[m][n]", "matching_cluster_idx": 8}, {"solution": "def get_total_number_of_sequences(max_value, sequence_length):\n # Initialize a 2D list to store the number of sequences\n dp = [[0 for _ in range(sequence_length + 1)] for _ in range(max_value + 1)]\n \n # Fill the DP table\n for i in range(1, max_value + 1):\n for j in range(1, sequence_length + 1):\n if j == 1:\n # Base case: there's only one way to form a sequence of length 1 with any value\n dp[i][j] = i\n else:\n # Calculate the number of sequences ending with the current value i\n dp[i][j] = dp[i - 1][j] + dp[i // 2][j - 1]\n \n # Return the total number of sequences of the given length\n return dp[max_value][sequence_length]", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n # Initialize a 2D list to store intermediate results\n dp = [[0 for _ in range(n + 1)] for _ in range(m + 1)]\n \n # Iterate over all possible values of m and n\n for i in range(1, m + 1):\n for j in range(1, n + 1):\n # Base case: If the sequence length is 1, there is only one possibility\n if j == 1:\n dp[i][j] = i\n else:\n # Calculate the number of sequences by summing up\n dp[i][j] = dp[i - 1][j] + dp[i // 2][j - 1]\n \n # Return the total number of sequences of length n for values up to m\n return dp[m][n]", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n # Create a 2D array to store intermediate results\n # dp[i][j] will store the number of valid sequences of length j using integers up to i\n dp = [[0 for i in range(n + 1)] for j in range(m + 1)]\n \n # Fill the table\n for i in range(m + 1):\n for j in range(n + 1):\n # If there is only one element in the sequence, all integers up to m are valid\n if j == 1:\n dp[i][j] = i\n # If the sequence length is more than one, calculate the number of valid sequences\n else:\n dp[i][j] = dp[i - 1][j] + dp[i // 2][j - 1]\n \n # Return the total number of valid sequences of length n using integers up to m\n return dp[m][n]", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n): \n # Initialize a 2D list to store the count of sequences\n count = [[0 for x in range(n + 1)] for x in range(m + 1)] \n \n # Loop through each possible sequence length\n for length in range(1, n + 1): \n # Loop through each possible maximum value in the sequence\n for maximum in range(1, m + 1): \n if length == 1: \n # For length 1, the count is equal to the maximum value\n count[maximum][length] = maximum \n else: \n # For length greater than 1, calculate the count based on previous values\n count[maximum][length] = count[maximum - 1][length] + count[maximum // 2][length - 1] \n \n # Return the total number of sequences of length n and maximum value m\n return count[m][n]", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n # Initialize a 2D list with zeros\n dp = [[0] * (n + 1) for _ in range(m + 1)]\n \n # Base case: there's one way to form a sequence of length 1\n for i in range(1, m + 1):\n dp[i][1] = i\n \n # Fill the dp table\n for i in range(2, m + 1):\n for j in range(2, n + 1):\n dp[i][j] = dp[i - 1][j] + dp[i // 2][j - 1]\n \n # Return the total number of sequences of length n with maximum value m\n return dp[m][n]", "matching_cluster_idx": 8}, {"solution": "def get_total_number_of_sequences(m, n):\n # Initialize a 2D list with zeros\n dp = [[0 for x in range(n + 1)] for x in range(m + 1)]\n \n # Iterate over each value from 0 to m\n for i in range(1, m + 1):\n # Iterate over each sequence length from 1 to n\n for j in range(1, n + 1):\n # If it's the first element, there's only one way to choose it\n if j == 1:\n dp[i][j] = i\n else:\n # Calculate the number of sequences ending with the current value i\n dp[i][j] = dp[i - 1][j] + dp[i // 2][j - 1]\n \n # Return the number of sequences of length n with values up to m\n return dp[m][n]", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n # Initialize a 2D list to store the number of sequences\n dp = [[0 for _ in range(n + 1)] for _ in range(m + 1)]\n \n # Iterate over possible maximum elements in the sequence\n for i in range(1, m + 1):\n # Iterate over possible sequence lengths\n for j in range(1, n + 1):\n # Initialize the first element of the sequence\n if j == 1:\n dp[i][j] = i\n else:\n # Sum up the number of sequences for smaller maximum elements and lengths\n dp[i][j] = dp[i - 1][j] + dp[i // 2][j - 1]\n \n # Return the number of possible sequences of length n with maximum element m\n return dp[m][n]", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(max_value, sequence_length):\n # Initialize a 2D list to store results of subproblems\n dp = [[0 for i in range(sequence_length + 1)] for i in range(max_value + 1)]\n \n # Iterate over all possible maximum values of sequence elements\n for i in range(1, max_value + 1):\n # Iterate over all possible lengths of sequences\n for j in range(1, sequence_length + 1):\n # If sequence length is 1, any value up to max_value is valid\n if j == 1:\n dp[i][j] = i\n else:\n # Calculate the number of valid sequences\n dp[i][j] = dp[i - 1][j] + dp[i // 2][j - 1]\n \n # The result is the number of sequences of length n with elements up to m\n return dp[max_value][sequence_length]", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n # Initialize a table to store the number of sequences\n dp = [[0] * (n + 1) for _ in range(m + 1)]\n \n # Fill the table\n for i in range(1, m + 1):\n dp[i][1] = i # There are i sequences of length 1 with values from 1 to i\n \n for i in range(2, m + 1):\n for j in range(2, n + 1):\n dp[i][j] = dp[i - 1][j] + dp[i // 2][j - 1]\n \n return dp[m][n]", "matching_cluster_idx": 8}, {"solution": "def get_total_number_of_sequences(m, n):\n # Initialize a 2D DP array with (m+1) rows and (n+1) columns\n dp = [[0 for _ in range(n + 1)] for _ in range(m + 1)]\n\n # Loop through each possible element value from 1 to m\n for i in range(1, m + 1):\n # Loop through each sequence length from 1 to n\n for j in range(1, n + 1):\n # Set the first element of the DP array\n if j == 1:\n dp[i][j] = i\n else:\n # Calculate the number of valid sequences\n dp[i][j] = dp[i - 1][j] + dp[i // 2][j - 1]\n\n # Return the total number of valid sequences of length n\n return dp[m][n]", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n # Create a 2D array to store the number of sequences\n dp = [[0 for i in range(n + 1)] for j in range(m + 1)]\n \n # Iterate over the possible values of elements in the sequence\n for i in range(1, m + 1):\n # Iterate over the possible lengths of the sequence\n for j in range(1, n + 1):\n # If there is only one element in the sequence\n if j == 1:\n dp[i][j] = i\n else:\n # If the length of the sequence is more than one\n dp[i][j] = dp[i - 1][j] + dp[i // 2][j - 1]\n \n # Return the total number of sequences\n return dp[m][n]", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n): \n # Initialize a 2D list with zeros to store the number of sequences\n dp = [[0 for i in range(n + 1)] for j in range(m + 1)] \n \n # Iterate through the 2D list and fill it with the number of sequences\n for i in range(1, m + 1): \n for j in range(1, n + 1): \n if j == 1: \n # Base case: There is one sequence of length 1 for each number\n dp[i][j] = i \n else: \n # Calculate the number of sequences by summing up the sequences of smaller lengths\n dp[i][j] = dp[i - 1][j] + dp[i // 2][j - 1] \n \n # Return the total number of sequences of length n\n return dp[m][n]", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n # Initialize a 2D list with zeros\n dp = [[0 for x in range(n + 1)] for x in range(m + 1)]\n \n # Base case: There is one way to form a sequence of length 1 with any number up to m\n for i in range(1, m + 1):\n dp[i][1] = i\n \n # Fill the dp table\n for i in range(1, m + 1):\n for j in range(2, n + 1):\n # Calculate the number of sequences ending with i of length j\n dp[i][j] = dp[i - 1][j] + dp[i // 2][j - 1]\n \n # The answer is the total number of sequences of length n that can end with any number up to m\n return dp[m][n]", "matching_cluster_idx": 8}, {"solution": "def get_total_number_of_sequences(m, n):\n # Initialize a 2D list with (m+1) rows and (n+1) columns with 0s\n dp = [[0 for i in range(n + 1)] for j in range(m + 1)]\n \n # Loop through all possible values of i and j\n for i in range(1, m + 1):\n for j in range(1, n + 1):\n # If the sequence length is 1, the number of sequences is i\n if j == 1:\n dp[i][j] = i\n else:\n # Calculate the number of sequences by adding the number of sequences\n # with the previous element being less than or equal to i\n dp[i][j] = dp[i - 1][j] + dp[i // 2][j - 1]\n \n # Return the total number of sequences of length n with elements between 1 and m\n return dp[m][n]", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n # Create a 2D list to store the number of sequences\n dp = [[0 for x in range(n + 1)] for x in range(m + 1)]\n \n # Initialize the first row of the dp table\n for i in range(1, m + 1):\n dp[i][1] = i\n \n # Fill the dp table using a nested loop\n for i in range(2, m + 1):\n for j in range(2, n + 1):\n dp[i][j] = dp[i - 1][j] + dp[i // 2][j - 1]\n \n # Return the number of sequences of length n where elements are between 1 and m\n return dp[m][n]", "matching_cluster_idx": 8}, {"solution": "def get_total_number_of_sequences(m, n): \n # Initialize a 2D list with (m+1) rows and (n+1) columns\n dp = [[0 for x in range(n + 1)] for x in range(m + 1)] \n \n # Loop through each element in the 2D list\n for i in range(1, m + 1): \n for j in range(1, n + 1): \n if j == 1: \n # Base case: only one way to form a sequence of length 1 with any m\n dp[i][j] = i \n else: \n # Calculate the number of sequences ending with i\n dp[i][j] = dp[i - 1][j] + dp[i // 2][j - 1] \n \n # Return the total number of sequences of length n with elements up to m\n return dp[m][n]", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n # Initialize a 2D list to store the number of sequences\n dp = [[0 for x in range(n + 1)] for x in range(m + 1)]\n \n # Iterate over possible values of m and n\n for i in range(1, m + 1):\n for j in range(1, n + 1):\n # If j is 1, all values of i are valid sequences\n if j == 1:\n dp[i][j] = i\n else:\n # Calculate the number of sequences using dynamic programming\n dp[i][j] = dp[i - 1][j] + dp[i // 2][j - 1]\n \n # Return the number of possible sequences of length n\n return dp[m][n]", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n # Initialize a 2D list to store the results of subproblems\n T = [[0 for j in range(n + 1)] for i in range(m + 1)]\n \n # Iterate over each element value i\n for i in range(1, m + 1):\n # Iterate over each sequence length j\n for j in range(1, n + 1):\n # If the sequence length is 1, all values are valid\n if j == 1:\n T[i][j] = i\n else:\n # Calculate the number of sequences ending with value i\n T[i][j] = T[i - 1][j] + T[i // 2][j - 1]\n \n # Return the total number of sequences of length n with elements between 1 and m\n return T[m][n]", "matching_cluster_idx": 7}]}, "Mbpp/240": {"dps": 77.50000000000001, "dps_norm": 87.22222222222221, "pass@1": 92.0, "profiled": [{"solution": "def replace_list(list1, list2):\n # Replace the last element of list1 with the elements of list2\n list1[-1:] = list2\n return list1", "matching_cluster_idx": 7}, {"solution": "def replace_list(nums1, nums2):\n # Replace the last element of nums1 with the elements of nums2\n nums1[-1:] = nums2\n return nums1", "matching_cluster_idx": 7}, {"solution": "def replace_list(nums, nums1):\n # Replace the last element of the first list with the elements of the second list\n nums[-1:] = nums1\n # Return the modified first list\n return nums", "matching_cluster_idx": 7}, {"solution": "def replace_list(input_list1, input_list2):\n # Assign the elements of the second list to replace the last element of the first list\n input_list1[-1:] = input_list2\n return input_list1", "matching_cluster_idx": 7}, {"solution": "from typing import List\ndef replace_list(nums1: List[int], nums2: List[int]) -> List[int]:\n # Replace the last element of nums1 with the elements of nums2\n nums1[-1:] = nums2\n return nums1", "matching_cluster_idx": 7}, {"solution": "def replace_list(arr1, arr2):\n # Replace the last element of the first list with the elements of the second list\n arr1[-1:] = arr2\n return arr1", "matching_cluster_idx": 7}, {"solution": "def replace_list(input1, input2):\n # Replace the last element of input1 with all elements of input2\n input1[-1:] = input2\n return input1", "matching_cluster_idx": 7}, {"solution": "def replace_list(list1, list2):\n # Replace the last element of list1 with all elements from list2\n list1[-1:] = list2\n return list1", "matching_cluster_idx": 7}, {"solution": "def replace_list(list1, list2):\n # Replace the last element of list1 with all elements of list2\n list1[-1:] = list2\n # Return the modified list1\n return list1", "matching_cluster_idx": 7}, {"solution": "def replace_list(list1, list2):\n # Replace the last element of list1 with all elements of list2\n list1[-1:] = list2\n return list1", "matching_cluster_idx": 7}, {"solution": "def replace_list(input_list, add_list):\n # Replace the last element of the input_list with elements from add_list\n input_list[-1:] = add_list\n return input_list", "matching_cluster_idx": 7}, {"solution": "def replace_list(num_list, sub_list):\n # Replace the last element of num_list with the elements of sub_list\n num_list[-1:] = sub_list\n return num_list", "matching_cluster_idx": 7}, {"solution": "def replace_list(A, B):\n # Replacing the last element of list A with all elements of list B\n A[-1:] = B\n # Returning the modified list A\n return A", "matching_cluster_idx": 7}, {"solution": "def replace_list(arr, arr1):\n # Replace the last element of arr with the elements of arr1\n arr[-1:] = arr1\n return arr", "matching_cluster_idx": 7}, {"solution": "def replace_list(A, B):\n # Replace the last element of list A with all elements of list B\n A[:-1] = A[:-1]\n A[-1:] = B\n return A", "matching_cluster_idx": 4}, {"solution": "def replace_list(numbers, new_elements):\n # Replace the last element of the first list with elements of the second list\n numbers[-1:] = new_elements\n return numbers", "matching_cluster_idx": 7}, {"solution": "def replace_list(test_list1, test_list2):\n # Replace the last element of the first list with the elements of the second list\n test_list1[-1:] = test_list2\n return test_list1", "matching_cluster_idx": 7}, {"solution": "def replace_list(list1, list2):\n # Replace the last element of list1 with all elements from list2\n list1[-1:] = list2\n # Return the modified list1\n return list1", "matching_cluster_idx": 7}, {"solution": "def replace_list(nums1, nums2):\n # Replace the last element of the first list with the second list\n nums1[-1:] = nums2\n return nums1", "matching_cluster_idx": 7}, {"solution": "def replace_list(list1, list2):\n # Replace the last element of list1 with the elements of list2\n list1[-1:] = list2\n # Return the modified list1\n return list1", "matching_cluster_idx": 7}]}, "Mbpp/251": {"dps": 59.252873563218394, "dps_norm": 69.44444444444444, "pass@1": 89.0, "profiled": [{"solution": "def insert_element(test_list, K):\n # Using list comprehension to insert K before each element in the list\n res = [y for x in test_list for y in (K, x)]\n return res", "matching_cluster_idx": 5}, {"solution": "def insert_element(lst, element):\n # Initialize an empty list to store the result\n res = []\n # Iterate through each item in the input list\n for x in lst:\n # Append the element first\n res.append(element)\n # Then append the current item\n res.append(x)\n # Return the resulting list\n return res", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, elem):\n # Create an empty list to store the result\n res = []\n # Iterate through each element in the input list\n for val in lst:\n # Append the current element and the insert element to the result list\n res.extend([elem, val])\n # Return the modified list\n return res", "matching_cluster_idx": 6}, {"solution": "def insert_element(list1, element):\n # Use list comprehension to iterate through list1 and insert 'element' before each item\n result = [value for item in list1 for value in (element, item)]\n return result", "matching_cluster_idx": 5}, {"solution": "def insert_element(lst, element):\n # Initialize an empty list to store the result\n res = []\n \n # Iterate over each element in the input list\n for val in lst:\n # Append the specified element followed by the current list element to the result list\n res.extend([element, val])\n \n # Return the modified list\n return res", "matching_cluster_idx": 6}, {"solution": "def insert_element(lists, element):\n # Initialize an empty list to store the result\n list2 = []\n # Iterate through each element in the input list\n for i in range(len(lists)):\n # Insert the specified element before the current element in the input list\n list2.extend([element, lists[i]])\n # Return the resulting list\n return list2", "matching_cluster_idx": 4}, {"solution": "def insert_element(lst, element):\n # Using list comprehension to insert the element before each element in the list\n res = [value for item in lst for value in (element, item)]\n return res", "matching_cluster_idx": 5}, {"solution": "def insert_element(test_list, K):\n # Create a list comprehension to insert K before each element in test_list\n res_list = [val for ele in test_list for val in (K, ele)]\n return res_list", "matching_cluster_idx": 5}, {"solution": "def insert_element(lst, element):\n # Iterate over the list in reverse order\n for i in range(len(lst) - 1, -1, -1):\n # Insert the element before the current index\n lst.insert(i, element)\n # Return the modified list\n return lst", "matching_cluster_idx": 0}, {"solution": "def insert_element(test_list, K):\n # Initialize an empty list to store the result\n res = []\n # Iterate over each element in the test_list\n for ele in test_list:\n # Append K and then the current element to the result list\n res.extend([K, ele])\n return res", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n # Initialize an empty list to store the result\n result = []\n # Iterate through each item in the input list\n for item in lst:\n # Append the element before the current item\n result.extend([element, item])\n # Return the resulting list\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n # Initialize an empty list to store the result\n result = []\n # Iterate over each element in the input list\n for item in lst:\n # Append the element before each item in the input list\n result.append(element)\n result.append(item)\n # Return the resulting list\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(test_list, K):\n # Extend the list by inserting the element K before each existing element\n test_list = [item for element in test_list for item in (K, element)]\n return test_list", "matching_cluster_idx": 5}, {"solution": "import copy\ndef insert_element(L, num):\n # Initialize the result list\n result = []\n # Iterate through each element in the input list\n for ele in L:\n # Append the element before the current item\n result.extend([num, ele])\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(test_list, K):\n # Initialize an empty list to store the result\n res = []\n # Iterate through each element in the test list\n for ele in test_list:\n # Insert K before the current element and append it to the result list\n res.extend([K, ele])\n return res", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, x):\n # Initialize an empty list to store the result\n res = []\n # Iterate through each element in the input list\n for ele in lst:\n # Append 'x' and then the current element to the result list\n res.extend([x, ele])\n # Return the resulting list\n return res", "matching_cluster_idx": 6}, {"solution": "def insert_element(test_list, K):\n # Using list comprehension to insert K before each element in the test_list\n res = [value for item in test_list for value in (K, item)]\n return res", "matching_cluster_idx": 5}, {"solution": "def insert_element(list, element):\n # Create a new list with the element inserted before each element in the original list\n res = [item for ele in list for item in (element, ele)]\n return res", "matching_cluster_idx": 5}, {"solution": "def insert_element(lst, element):\n # Initialize an empty list to store the result\n result = []\n # Iterate through each item in the input list\n for item in lst:\n # Append the given element and then the item to the result list\n result.extend([element, item])\n # Return the modified result list\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(items, item):\n # Initialize an empty list to store the result\n result = []\n \n # Iterate through each element in the input list\n for e in items:\n # Append the specified item and the current element to the result list\n result += [item, e]\n \n # Return the modified list\n return result", "matching_cluster_idx": 6}]}, "Mbpp/256": {"dps": 70.82191780821918, "dps_norm": 67.05882352941177, "pass@1": 85.0, "profiled": [{"solution": "def count_Primes_nums(n):\n # Initialize a list to keep track of prime numbers\n primes = []\n \n # Iterate through numbers from 2 to n-1\n for i in range(2, n):\n # Assume the number is prime until proven otherwise\n prime_flag = True\n \n # Check if the number is divisible by any number up to its square root\n for j in range(2, int(i**0.5) + 1):\n if i % j == 0:\n # If divisible, it's not a prime number\n prime_flag = False\n break\n \n # If still considered prime, add it to the list\n if prime_flag:\n primes.append(i)\n \n # Return the total count of prime numbers found\n return len(primes)", "matching_cluster_idx": 8}, {"solution": "def count_Primes_nums(n):\n # Helper function to check if a number is prime\n def is_prime(num):\n if num < 2:\n return False\n for i in range(2, int(num ** 0.5) + 1):\n if num % i == 0:\n return False\n return True\n \n # Counting prime numbers less than n\n count = 0\n for number in range(2, n):\n if is_prime(number):\n count += 1\n return count", "matching_cluster_idx": 8}, {"solution": "def count_Primes_nums(n):\n # Create a list of boolean values to represent whether each number is prime\n isprime = [True] * n\n # Initialize the count of prime numbers\n prime_count = 0\n \n # Skip the first two indices (0 and 1) which are not prime\n for i in range(2, n):\n # If the number is still marked as prime\n if isprime[i]:\n # Increment the count\n prime_count += 1\n # Mark all multiples of i as not prime\n for j in range(i * 2, n, i):\n isprime[j] = False\n \n # Return the count of prime numbers\n return prime_count", "matching_cluster_idx": 12}, {"solution": "def count_Primes_nums(n):\n # Check if the input number is less than 3, in which case there are no prime numbers less than it\n if n < 3:\n return 0\n \n # Create a list of boolean values to represent whether each number is prime\n is_prime = [True] * n\n is_prime[0] = is_prime[1] = False # 0 and 1 are not prime numbers\n \n # Iterate over the numbers starting from 2 to n-1\n for i in range(2, int(n**0.5) + 1):\n # If the number is prime, mark all multiples of it as not prime\n if is_prime[i]:\n for j in range(i*i, n, i):\n is_prime[j] = False\n \n # Count and return the number of prime numbers\n return sum(is_prime)", "matching_cluster_idx": 14}, {"solution": "def count_Primes_nums(n):\n # Check if the input number is less than 2\n if n <= 2:\n return 0\n \n # Initialize a list to keep track of prime status for each number up to n\n primes = [True] * n\n primes[0] = primes[1] = False\n \n # Implement the Sieve of Eratosthenes algorithm\n for i in range(2, int(n**0.5) + 1):\n if primes[i]:\n primes[i*i::i] = [False] * (((n - 1) // i) - (i - 1))\n \n # Count the number of True values in the primes list\n count = sum(primes)\n \n # Return the count of prime numbers less than n\n return count", "matching_cluster_idx": 16}, {"solution": "def count_Primes_nums(n):\n count = 0\n for num in range(2, n):\n for i in range(2, num):\n if (num % i) == 0:\n break\n else:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Primes_nums(num):\n # Check if the input number is less than 2\n if num < 2:\n return 0\n \n # List to keep track of prime numbers\n primes = []\n for i in range(2, num):\n # Assume the number is prime\n is_prime = True\n for j in range(2, int(i ** 0.5) + 1):\n # If divisible by any number, it's not prime\n if i % j == 0:\n is_prime = False\n break\n \n # If prime, add to the list\n if is_prime:\n primes.append(i)\n \n # Return the count of prime numbers\n return len(primes)", "matching_cluster_idx": 8}, {"solution": "def is_prime(x):\n if x < 2:\n return False\n if x <= 3:\n return True\n if x % 2 == 0 or x % 3 == 0:\n return False\n for i in range(5, int(x**0.5) + 1, 6):\n if x % i == 0 or x % (i + 2) == 0:\n return False\n return True\ndef count_Primes_nums(n):\n count = 0\n for i in range(2, n):\n if is_prime(i):\n count += 1\n return count", "matching_cluster_idx": 10}, {"solution": "def count_Primes_nums(num):\n # Helper function to check if a number is prime\n def helper(n):\n # Special case for 0 and 1, which are not prime numbers\n if n < 2:\n return False\n # Check for divisibility up to the square root of n\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True\n \n # Count prime numbers less than num\n return sum(helper(n) for n in range(num))", "matching_cluster_idx": 8}, {"solution": "import math\ndef count_Primes_nums(n): \n # Initialize a list to keep track of prime status\n primes = [1] * n \n result = 0\n \n # Check for corner cases where n is less than 2\n if n < 2:\n return result\n \n # Set the status of 0 and 1 to 0 (not prime)\n primes[0] = 0\n primes[1] = 0\n \n # Iterate over numbers from 2 to the square root of n\n for i in range(2, int(math.sqrt(n)) + 1): \n # If the number is marked as prime\n if primes[i] == 1: \n # Mark all multiples of i as not prime\n for j in range(i * i, n, i): \n primes[j] = 0\n \n # Count and return the number of primes found\n for i in range(2, n): \n if primes[i] == 1: \n result += 1\n \n return result", "matching_cluster_idx": 13}, {"solution": "import math\ndef count_Primes_nums(N):\n # Edge case: 0 and 1 are not prime numbers\n if N <= 2:\n return 0\n \n # Initialize a list to keep track of prime numbers\n is_prime = [True] * N\n is_prime[0] = is_prime[1] = False # 0 and 1 are not prime\n \n # Implement the Sieve of Eratosthenes algorithm\n for i in range(2, int(math.sqrt(N)) + 1):\n if is_prime[i]:\n for j in range(i * i, N, i):\n is_prime[j] = False\n \n # Count and return the number of prime numbers\n return sum(is_prime)", "matching_cluster_idx": 14}, {"solution": "def count_Primes_nums(n):\n # Create a boolean array \"prime[0..n-1]\" and initialize\n # all entries it as true. A value in prime[i] will\n # finally be false if i is Not a prime, else true.\n prime = [True for i in range(n)]\n p = 2\n while (p * p <= n):\n # If prime[p] is not changed, then it is a prime\n if (prime[p] == True):\n # Updating all multiples of p to not prime\n for i in range(p * p, n, p):\n prime[i] = False\n p += 1\n\n # Counting the number of prime numbers less than n\n count = 0\n for p in range(2, n):\n if prime[p]:\n count += 1\n\n return count", "matching_cluster_idx": 13}, {"solution": "def count_Primes_nums(num):\n # Check if the number is less than 2\n if num < 2:\n return 0\n \n # Initialize a list to track prime status of numbers\n primes = [True] * num\n \n # The first prime number is 2\n primes[0] = primes[1] = False\n \n # Use the Sieve of Eratosthenes algorithm to mark non-prime numbers\n for i in range(2, int(num ** 0.5) + 1):\n if primes[i]:\n for j in range(i * i, num, i):\n primes[j] = False\n \n # Count the number of prime numbers\n count = sum(primes)\n \n return count", "matching_cluster_idx": 14}, {"solution": "def count_Primes_nums(n):\n # If n is less than 3, there are no prime numbers less than n\n if n < 3:\n return 0\n # Initialize a list to keep track of prime numbers\n primes = [True] * n\n p = 2\n # Use the Sieve of Eratosthenes algorithm to find all prime numbers less than n\n while p * p < n:\n if primes[p]:\n for i in range(p * p, n, p):\n primes[i] = False\n p += 1\n # Count the number of prime numbers found\n return sum(primes) - 2 # Subtract 2 because primes[0] and primes[1] are not considered prime", "matching_cluster_idx": 14}, {"solution": "def count_Primes_nums(n):\n # Check if the number is less than 2, in which case there are no prime numbers\n if (n <= 2):\n return 0\n\n # Initialize an array to store the prime status of numbers\n prime = [0] * n\n count = 0\n\n # Marking all numbers as prime initially\n for i in range(2, n):\n prime[i] = 1\n\n # Sieve of Eratosthenes algorithm to mark non-prime numbers\n for i in range(2, int(n ** 0.5) + 1):\n if (prime[i] == 1):\n for j in range(i * i, n, i):\n prime[j] = 0\n\n # Counting the number of prime numbers\n for i in range(2, n):\n if prime[i] == 1:\n count += 1\n\n return count", "matching_cluster_idx": 12}, {"solution": "def count_Primes_nums(n):\n # Check for edge case\n if n <= 2:\n return 0\n \n # Initialize a list to mark non-prime numbers\n prime_nums = [True] * n\n prime_nums[0], prime_nums[1] = False, False\n \n # Use the Sieve of Eratosthenes algorithm to find all primes\n for i in range(2, int(n**0.5) + 1):\n if prime_nums[i]:\n for j in range(i*i, n, i):\n prime_nums[j] = False\n \n # Count and return the number of primes\n return sum(prime_nums)", "matching_cluster_idx": 14}, {"solution": "def is_prime(num):\n # Check if a number is prime\n if num < 2:\n return False\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n return False\n return True\ndef count_Primes_nums(n):\n # Count the number of prime numbers less than n\n count = 0\n for i in range(2, n):\n if is_prime(i):\n count += 1\n return count", "matching_cluster_idx": 8}, {"solution": "def count_Primes_nums(num):\n count = 0\n \n # Helper function to check if a number is prime\n def prime(n):\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True\n \n # Iterate through numbers from 2 to num-1\n for i in range(2, num):\n if prime(i):\n count += 1\n \n return count", "matching_cluster_idx": 8}, {"solution": "def is_prime(n):\n # Check if a number is a prime\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True\ndef count_Primes_nums(num):\n # Count the number of prime numbers less than the given number\n count = 0\n for i in range(2, num):\n if is_prime(i):\n count += 1\n return count", "matching_cluster_idx": 10}, {"solution": "def count_Primes_nums(n):\n # List to hold prime numbers\n prime_nums = []\n \n # Iterate through numbers to find primes\n for num in range(2, n):\n is_prime = True\n # Check divisibility for each number\n for i in range(2, num):\n if num % i == 0:\n is_prime = False\n break\n # If the number is prime, add to the list\n if is_prime:\n prime_nums.append(num)\n \n # Return the count of prime numbers\n return len(prime_nums)", "matching_cluster_idx": 2}]}, "Mbpp/265": {"dps": 98.54651162790698, "dps_norm": 99.16666666666667, "pass@1": 36.0, "profiled": [{"solution": "def list_split(L, n):\n # Split the list into sublists of length n\n return [L[i::n] for i in range(n)]", "matching_cluster_idx": 5}, {"solution": "def list_split(lst, n):\n # Split the list into chunks of size n and return a list of these chunks\n return [lst[i::n] for i in range(n)]", "matching_cluster_idx": 5}, {"solution": "def list_split(lst, n):\n # Use list comprehension to split the list into sublists of length n\n result = [lst[i::n] for i in range(n)]\n return result", "matching_cluster_idx": 5}, {"solution": "def list_split(lst, n):\n # Split the list into sublists where each sublist contains every nth element\n return [lst[i::n] for i in range(n)]", "matching_cluster_idx": 5}, {"solution": "def list_split(lst, n):\n # Using list comprehension to slice the list from index 0 to len(lst) with step n\n return [lst[i::n] for i in range(n)]", "matching_cluster_idx": 5}, {"solution": "def list_split(test_list, N):\n res = [test_list[i::N] for i in range(N)]\n return res", "matching_cluster_idx": 4}, {"solution": "def list_split(data, n):\n # Split the list into parts where each part contains elements spaced by 'n'\n return [data[i::n] for i in range(n)]", "matching_cluster_idx": 5}, {"solution": "def list_split(lst, n):\n # Split the list into sublists where each sublist contains elements at every nth index\n return [lst[i::n] for i in range(n)]", "matching_cluster_idx": 5}, {"solution": "def list_split(data_list, n):\n # Using list slicing to create chunks of size n\n return [data_list[i::n] for i in range(n)]", "matching_cluster_idx": 5}, {"solution": "def list_split(lst, n):\n # Split the list into sublists where each sublist contains every nth element\n result = [lst[i::n] for i in range(n)]\n return result", "matching_cluster_idx": 5}, {"solution": "def list_split(inlist, n):\n # Split the list by taking every nth element\n return [inlist[i::n] for i in range(n)]", "matching_cluster_idx": 5}, {"solution": "def list_split(list1, n):\n # Use list comprehension to split the list into sublists of size 'n'\n result = [list1[i::n] for i in range(n)]\n return result", "matching_cluster_idx": 5}, {"solution": "def list_split(input_list, n):\n # Use list comprehension to create new lists split by every nth element\n return [input_list[i::n] for i in range(n)]", "matching_cluster_idx": 5}, {"solution": "def list_split(lst, n):\n # Using list comprehension and range to split the list every nth element\n return [lst[i::n] for i in range(n)]", "matching_cluster_idx": 5}, {"solution": "def list_split(test_list, N):\n # Split the list into sublists of length N\n res = [test_list[i::N] for i in range(N)]\n return res", "matching_cluster_idx": 5}, {"solution": "def list_split(lst, n):\n # Split the list into sublists of length n\n return [lst[i::n] for i in range(n)]", "matching_cluster_idx": 5}, {"solution": "def list_split(input_list, nth):\n # Create sublists for every nth element using list comprehension\n result = [input_list[i::nth] for i in range(nth)]\n return result", "matching_cluster_idx": 5}, {"solution": "def list_split(test_list, N):\n # Slice the list from the start to the end with a step of N\n res = [test_list[i::N] for i in range(N)]\n return res", "matching_cluster_idx": 5}, {"solution": "def list_split(lst, n):\n # Create a list of lists by iterating through 'lst' and taking every 'n'th element\n res = [lst[i::n] for i in range(n)]\n return res", "matching_cluster_idx": 5}, {"solution": "def list_split(lst, n):\n # Use list comprehension to split the list into sublists\n return [lst[i::n] for i in range(n)]", "matching_cluster_idx": 5}]}, "Mbpp/281": {"dps": 91.6, "dps_norm": 86.36363636363636, "pass@1": 100.0, "profiled": [{"solution": "def all_unique(data):\n # Check if all elements in the list are unique by comparing the length of the list\n # with the length of the set created from the list. A set automatically removes duplicates.\n return len(data) == len(set(data))", "matching_cluster_idx": 8}, {"solution": "def all_unique(data):\n # Create an empty dictionary to store occurrences of each element\n occurrences = {}\n \n # Iterate through each element in the data list\n for value in data:\n # Check if the value is already in the dictionary\n if value in occurrences:\n # If it is, return False indicating not all elements are unique\n return False\n # If not, add the value to the dictionary\n else:\n occurrences[value] = 1\n \n # If the loop completes without finding duplicates, return True\n return True", "matching_cluster_idx": 10}, {"solution": "def all_unique(data):\n # Create a set to store unique elements\n seen = set()\n # Iterate over each element in the list\n for x in data:\n # If the element is already in the set, it's not unique\n if x in seen:\n return False\n # Add the element to the set\n seen.add(x)\n # If no duplicates were found, return True\n return True", "matching_cluster_idx": 10}, {"solution": "def all_unique(data):\n # Convert the list to a set to remove duplicates and compare its length to the original list\n return len(data) == len(set(data))", "matching_cluster_idx": 8}, {"solution": "def all_unique(my_list):\n # Convert the list to a set to remove duplicates\n # If the length of the set is less than the original list, duplicates exist\n if len(set(my_list)) < len(my_list):\n return False\n return True", "matching_cluster_idx": 8}, {"solution": "def all_unique(data):\n # Convert the list to a set to remove duplicates and compare its length to the original list\n return len(set(data)) == len(data)", "matching_cluster_idx": 8}, {"solution": "def all_unique(data):\n # Initialize an empty list to keep track of seen items\n seen = []\n \n # Iterate through each item in the input list\n for x in data:\n # Check if the item is already in the seen list\n if x in seen:\n return False # Return False if duplicate found\n else:\n seen.append(x) # Add item to the seen list if not duplicate\n \n return True # Return True if no duplicates found", "matching_cluster_idx": 7}, {"solution": "def all_unique(data):\n # Using a set to track unique elements\n unique = set()\n \n # Iterate over each element in the input list\n for item in data:\n # If the item is already in the set, return False indicating non-uniqueness\n if item in unique:\n return False\n # Otherwise, add the item to the set\n unique.add(item)\n \n # If the loop completes, all items were unique, return True\n return True", "matching_cluster_idx": 9}, {"solution": "def all_unique(data):\n # Create an empty set to store unique elements\n seen = set()\n # Iterate over each element in the list\n for x in data:\n # Check if the element is already in the set\n if x in seen:\n return False\n # Add the element to the set\n seen.add(x)\n return True", "matching_cluster_idx": 10}, {"solution": "def all_unique(data):\n # Convert the list to a set to remove duplicates\n # If the lengths of the list and the set are equal, all elements are unique\n return len(data) == len(set(data))", "matching_cluster_idx": 8}, {"solution": "def all_unique(data):\n # Convert the list to a set and compare its length to the original list's length\n return len(data) == len(set(data))", "matching_cluster_idx": 8}, {"solution": "def all_unique(data):\n # Convert the list to a set to remove duplicates\n # Compare the length of the set with the length of the list\n return len(set(data)) == len(data)", "matching_cluster_idx": 8}, {"solution": "def all_unique(data):\n # Convert the list to a set to remove duplicate elements\n # If the lengths are equal, all elements were unique\n return len(data) == len(set(data))", "matching_cluster_idx": 8}, {"solution": "def all_unique(data):\n # Convert the list to a set and compare its length to the original list\n return len(data) == len(set(data))", "matching_cluster_idx": 8}, {"solution": "def all_unique(data):\n # Convert the list to a set to remove duplicates and compare lengths\n return len(data) == len(set(data))", "matching_cluster_idx": 8}, {"solution": "def all_unique(data):\n # Use a set to track seen elements\n seen = set()\n # Iterate over each element in the list\n for x in data:\n # If the element is already in the set, return False\n if x in seen:\n return False\n # Add the element to the set\n seen.add(x)\n # If no duplicates were found, return True\n return True", "matching_cluster_idx": 10}, {"solution": "def all_unique(data):\n # Create an empty set to store elements\n seen = set()\n # Iterate over each element in the list\n for x in data:\n # Check if the element is already in the set\n if x in seen:\n return False\n # Add the element to the set\n seen.add(x)\n # If the loop completes without finding duplicates, return True\n return True", "matching_cluster_idx": 10}, {"solution": "def all_unique(data):\n # Convert the list to a set to remove duplicates\n # If the length of the set is the same as the list, all elements are unique\n return len(set(data)) == len(data)", "matching_cluster_idx": 8}, {"solution": "def all_unique(data):\n # Convert the list to a set and compare its length to the original list\n return len(set(data)) == len(data)", "matching_cluster_idx": 8}, {"solution": "def all_unique(data):\n # Convert the list to a set to remove duplicates and compare its length to the original list\n return len(data) == len(set(data))", "matching_cluster_idx": 8}]}, "Mbpp/296": {"dps": 60.51282051282051, "dps_norm": 81.66666666666667, "pass@1": 86.0, "profiled": [{"solution": "def get_Inv_Count(arr):\n # Initialize count to 0\n count = 0\n \n # Iterate through the array with two nested loops\n for i in range(len(arr)):\n for j in range(i+1, len(arr)):\n # Check if the pair (arr[i], arr[j]) is an inversion\n if arr[i] > arr[j]:\n count += 1\n \n # Return the total count of inversions\n return count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(A):\n # Initialize inversion count to zero\n inv_count = 0\n n = len(A)\n \n # Traverse through all elements of the array\n for i in range(n):\n for j in range(i + 1, n):\n # Increment inversion count if an inversion is found\n if A[i] > A[j]:\n inv_count += 1\n return inv_count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n n = len(arr)\n inv_count = 0\n \n # Iterate through the array\n for i in range(n):\n for j in range(i + 1, n):\n # If an inversion is found, increment the count\n if arr[i] > arr[j]:\n inv_count += 1\n \n return inv_count", "matching_cluster_idx": 3}, {"solution": "def merge_and_count(arr, temp_arr, left, mid, right):\n \"\"\"\n This function merges two subarrays and counts inversions\n \"\"\"\n i = left # Starting index for left subarray\n j = mid + 1 # Starting index for right subarray\n k = left # Starting index to be sorted\n inv_count = 0\n \n # Conditions are checked to ensure that i doesn't exceed mid and j doesn't exceed right\n while i <= mid and j <= right:\n if arr[i] <= arr[j]:\n # There will be mid - i inversions, because all the remaining elements in the left subarray (arr[i], arr[i+1], ..., arr[mid]) are greater than arr[j]\n temp_arr[k] = arr[i]\n i += 1\n else:\n temp_arr[k] = arr[j]\n inv_count += mid - i + 1\n j += 1\n k += 1\n\n # Copy the remaining elements of left subarray, if any\n while i <= mid:\n temp_arr[k] = arr[i]\n i += 1\n k += 1\n\n # Copy the remaining elements of right subarray, if any\n while j <= right:\n temp_arr[k] = arr[j]\n j += 1\n k += 1\n\n # Copy the sorted subarray into Original array\n for i in range(left, right + 1):\n arr[i] = temp_arr[i]\n\n return inv_count\ndef get_Inv_Count(arr):\n \"\"\"\n This function returns the number of inversions in array arr[]\n \"\"\"\n n = len(arr)\n temp_arr = [0]*n\n return merge_sort_and_count(arr, temp_arr, 0, n - 1)\ndef merge_sort_and_count(arr, temp_arr, left, right):\n \"\"\"\n An auxiliary recursive function that sorts the input array and returns the number of inversions in the array\n \"\"\"\n inv_count = 0\n if left < right:\n mid = (left + right)//2\n \n inv_count += merge_sort_and_count(arr, temp_arr, left, mid)\n inv_count += merge_sort_and_count(arr, temp_arr, mid + 1, right)\n \n inv_count += merge_and_count(arr, temp_arr, left, mid, right)\n \n return inv_count", "matching_cluster_idx": 5}, {"solution": "def get_Inv_Count(arr):\n # Helper function to merge two halves and count inversions\n def merge_and_count(arr, l, m, r):\n n1 = m - l + 1\n n2 = r - m\n \n # Create temp arrays\n L = [0] * n1\n R = [0] * n2\n \n # Copy data to temp arrays L[] and R[]\n for i in range(0, n1):\n L[i] = arr[l + i]\n for j in range(0, n2):\n R[j] = arr[m + 1 + j]\n \n i = 0 # Initial index of first subarray\n j = 0 # Initial index of second subarray\n k = l # Initial index to merge back\n inv_count = 0\n \n # Merge the temp arrays back into arr[l..r]\n while i < n1 and j < n2:\n if L[i] <= R[j]:\n arr[k] = L[i]\n i += 1\n else:\n # There are n1 - i inversions, because all the remaining elements in L[]\n # are greater than R[j]\n arr[k] = R[j]\n j += 1\n inv_count += n1 - i\n k += 1\n \n # Copy the remaining elements of L[], if there are any\n while i < n1:\n arr[k] = L[i]\n i += 1\n k += 1\n \n # Copy the remaining elements of R[], if there are any\n while j < n2:\n arr[k] = R[j]\n j += 1\n k += 1\n \n return inv_count\n \n # Helper function to divide the array into halves and count inversions\n def merge_sort_and_count(arr, l, r):\n inv_count = 0\n if l < r:\n m = (l + r) // 2\n \n inv_count += merge_sort_and_count(arr, l, m)\n inv_count += merge_sort_and_count(arr, m + 1, r)\n \n inv_count += merge_and_count(arr, l, m, r)\n \n return inv_count\n \n # Check if the array is not empty\n if not arr:\n return 0\n \n # Call the merge sort and count function\n return merge_sort_and_count(arr, 0, len(arr) - 1)", "matching_cluster_idx": 5}, {"solution": "def get_Inv_Count(arr):\n # Initialize count of inversions to 0\n inv_count = 0\n # Iterate through each element in the array\n for i in range(len(arr)):\n # Compare the current element with all elements that follow it\n for j in range(i + 1, len(arr)):\n # If the current element is greater than the next element, it's an inversion\n if arr[i] > arr[j]:\n inv_count += 1\n # Return the total count of inversions\n return inv_count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n # Initialize count to zero\n count = 0\n \n # Iterate through the array\n for i in range(len(arr)):\n for j in range(i + 1, len(arr)):\n # If an inversion is found, increment count\n if arr[i] > arr[j]:\n count += 1\n \n return count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n # Base case: if the array has 1 or 0 elements, no inversions exist\n if len(arr) < 2:\n return 0\n \n mid = len(arr) // 2 # Find the middle index to divide the array\n left = arr[:mid] # Split the array into left and right halves\n right = arr[mid:]\n \n # Recursively count inversions in the left and right halves\n left_count = get_Inv_Count(left)\n right_count = get_Inv_Count(right)\n \n merge_count = 0 # Initialize inversion count for the merge process\n i = j = k = 0 # Initialize pointers for the merge process\n \n # Merge the two halves and count inversions\n while i < len(left) and j < len(right):\n if left[i] <= right[j]:\n arr[k] = left[i]\n i += 1\n else:\n arr[k] = right[j]\n merge_count += len(left) - i # Count inversions when left[i] > right[j]\n j += 1\n k += 1\n \n # Copy any remaining elements from the left half\n while i < len(left):\n arr[k] = left[i]\n i += 1\n k += 1\n \n # Copy any remaining elements from the right half\n while j < len(right):\n arr[k] = right[j]\n j += 1\n k += 1\n \n # Return the total inversion count\n return left_count + right_count + merge_count", "matching_cluster_idx": 5}, {"solution": "def get_Inv_Count(arr):\n # Initialize a counter for inversions\n inv_count = 0\n # Iterate through each element in the array\n for i in range(len(arr)):\n for j in range(i + 1, len(arr)):\n # If an inversion is found, increment the counter\n if arr[i] > arr[j]:\n inv_count += 1\n # Return the total number of inversions\n return inv_count", "matching_cluster_idx": 3}, {"solution": "def merge_sort_and_count(arr, temp_arr, left, right):\n inv_count = 0\n if left < right:\n mid = (left + right) // 2\n \n inv_count += merge_sort_and_count(arr, temp_arr, left, mid)\n inv_count += merge_sort_and_count(arr, temp_arr, mid + 1, right)\n \n inv_count += merge_and_count(arr, temp_arr, left, mid, right)\n return inv_count\ndef merge_and_count(arr, temp_arr, left, mid, right):\n i = left \n j = mid + 1 \n k = left \n inv_count = 0\n \n while i <= mid and j <= right:\n if arr[i] <= arr[j]:\n temp_arr[k] = arr[i]\n i += 1\n else:\n temp_arr[k] = arr[j]\n inv_count += (mid-i + 1)\n j += 1\n k += 1\n\n while i <= mid:\n temp_arr[k] = arr[i]\n i += 1\n k += 1\n\n while j <= right:\n temp_arr[k] = arr[j]\n j += 1\n k += 1\n\n for i in range(left, right + 1):\n arr[i] = temp_arr[i]\n \n return inv_count\ndef get_Inv_Count(arr):\n n = len(arr)\n temp_arr = [0]*n\n return merge_sort_and_count(arr, temp_arr, 0, n-1)", "matching_cluster_idx": 5}, {"solution": "def get_Inv_Count(arr):\n n = len(arr)\n ans = 0\n \n # Iterate through the array\n for i in range(0, n):\n for j in range(i+1, n):\n # If the current pair (i, j) is an inversion, increment the count\n if arr[i] > arr[j]:\n ans += 1\n \n return ans", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(A):\n # Initialize a variable to count inversions\n inv_count = 0\n # Loop through each element in the array except the last one\n for i in range(len(A)-1):\n # For each element, compare it with all elements ahead of it\n for j in range(i+1, len(A)):\n # If an inversion is found, increment the count\n if A[i] > A[j]:\n inv_count += 1\n # Return the total count of inversions found\n return inv_count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n # Function to count inversions using merge sort\n def merge_and_count(arr, temp_arr, left, mid, right):\n i = left # Starting index for left subarray\n j = mid + 1 # Starting index for right subarray\n k = left # Starting index to be sorted\n inv_count = 0\n\n # Conditions are checked to ensure that i doesn't exceed mid and j doesn't exceed right\n while i <= mid and j <= right:\n if arr[i] <= arr[j]:\n temp_arr[k] = arr[i]\n i += 1\n else:\n # There are mid - i inversions, because all the remaining elements in the left subarray (arr[i], arr[i+1], ..., arr[mid]) are greater than arr[j]\n temp_arr[k] = arr[j]\n inv_count += (mid-i + 1)\n j += 1\n k += 1\n\n # Copy the remaining elements of left subarray, if any\n while i <= mid:\n temp_arr[k] = arr[i]\n i += 1\n k += 1\n\n # Copy the remaining elements of right subarray, if any\n while j <= right:\n temp_arr[k] = arr[j]\n j += 1\n k += 1\n\n # Copy the sorted subarray into Original array\n for i in range(left, right + 1):\n arr[i] = temp_arr[i]\n\n return inv_count\n\n def merge_sort_and_count(arr, temp_arr, left, right):\n inv_count = 0\n if left < right:\n mid = (left + right) // 2\n\n inv_count += merge_sort_and_count(arr, temp_arr, left, mid)\n inv_count += merge_sort_and_count(arr, temp_arr, mid + 1, right)\n\n inv_count += merge_and_count(arr, temp_arr, left, mid, right)\n\n return inv_count\n\n # Create a temporary array and assign it to arr[] so that the original array is not modified\n temp_arr = [0]*len(arr)\n return merge_sort_and_count(arr, temp_arr, 0, len(arr)-1)", "matching_cluster_idx": 5}, {"solution": "def get_Inv_Count(arr):\n # Initialize the inversion count to zero\n inv_count = 0\n \n # Iterate through each element in the array\n for i in range(len(arr)):\n for j in range(i + 1, len(arr)):\n # If an inversion is found, increment the count\n if arr[i] > arr[j]:\n inv_count += 1\n \n return inv_count", "matching_cluster_idx": 3}, {"solution": "def merge_and_count(arr, temp_arr, left, mid, right):\n \"\"\"\n A utility function that merges two sorted halves and counts inversions in them.\n \"\"\"\n i = left # Starting index for left subarray\n j = mid + 1 # Starting index for right subarray\n k = left # Starting index to be sorted\n inv_count = 0\n \n # Conditions are checked to ensure that i doesn't exceed mid and j doesn't exceed right\n while i <= mid and j <= right:\n if arr[i] <= arr[j]:\n temp_arr[k] = arr[i]\n i += 1\n else:\n # There are mid - i inversions, because all the remaining elements in the left subarray\n # (arr[i], arr[i+1], ..., arr[mid]) are greater than arr[j]\n temp_arr[k] = arr[j]\n inv_count += (mid-i + 1)\n j += 1\n k += 1\n\n # Copy the remaining elements of left subarray, if any\n while i <= mid:\n temp_arr[k] = arr[i]\n i += 1\n k += 1\n\n # Copy the remaining elements of right subarray, if any\n while j <= right:\n temp_arr[k] = arr[j]\n j += 1\n k += 1\n\n # Copy the sorted subarray into Original array\n for i in range(left, right + 1):\n arr[i] = temp_arr[i]\n \n return inv_count\ndef merge_sort_and_count(arr, temp_arr, left, right):\n \"\"\"\n A utility function that sorts the array and counts inversions in the array.\n \"\"\"\n inv_count = 0\n if left < right:\n mid = (left + right)//2\n \n inv_count += merge_sort_and_count(arr, temp_arr, left, mid)\n inv_count += merge_sort_and_count(arr, temp_arr, mid + 1, right)\n \n inv_count += merge_and_count(arr, temp_arr, left, mid, right)\n \n return inv_count\ndef get_Inv_Count(arr):\n \"\"\"\n Function to count the number of inversions in an array.\n \"\"\"\n n = len(arr)\n temp_arr = [0]*n\n return merge_sort_and_count(arr, temp_arr, 0, n-1)", "matching_cluster_idx": 5}, {"solution": "def get_Inv_Count(A):\n n = len(A)\n inv_count = 0\n for i in range(n):\n for j in range(i + 1, n):\n if A[i] > A[j]:\n inv_count += 1\n return inv_count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n # Helper function to merge and count inversions\n def merge_sort_and_count(arr, temp_arr, left, right):\n inv_count = 0\n if left < right:\n mid = (left + right) // 2\n inv_count += merge_sort_and_count(arr, temp_arr, left, mid)\n inv_count += merge_sort_and_count(arr, temp_arr, mid + 1, right)\n inv_count += merge_and_count(arr, temp_arr, left, mid, right)\n return inv_count\n \n # Helper function to merge and count inversions during merge\n def merge_and_count(arr, temp_arr, left, mid, right):\n i = left # Starting index for left subarray\n j = mid + 1 # Starting index for right subarray\n k = left # Starting index to be sorted\n inv_count = 0\n \n # Conditions are checked to ensure that i doesn't exceed mid and j doesn't exceed right\n while i <= mid and j <= right:\n if arr[i] <= arr[j]:\n temp_arr[k] = arr[i]\n i += 1\n else:\n # There are mid - i inversions, because all the remaining elements in the left subarray\n # (arr[i], arr[i+1], ..., arr[mid]) are greater than arr[j]\n temp_arr[k] = arr[j]\n inv_count += (mid - i + 1)\n j += 1\n k += 1\n \n # Copy the remaining elements of left subarray, if any\n while i <= mid:\n temp_arr[k] = arr[i]\n i += 1\n k += 1\n \n # Copy the remaining elements of right subarray, if any\n while j <= right:\n temp_arr[k] = arr[j]\n j += 1\n k += 1\n \n # Copy the sorted subarray into Original array\n for i in range(left, right + 1):\n arr[i] = temp_arr[i]\n \n return inv_count\n \n # Temporary array to store elements of original array\n temp_arr = [0] * len(arr)\n return merge_sort_and_count(arr, temp_arr, 0, len(arr) - 1)", "matching_cluster_idx": 5}, {"solution": "def get_Inv_Count(arr):\n # Function to merge two halves and count inversions\n def merge_and_count(arr, temp_arr, left, mid, right):\n i = left # Starting index for left subarray\n j = mid + 1 # Starting index for right subarray\n k = left # Starting index to be sorted\n inv_count = 0\n\n # Conditions are checked to ensure that i doesn't exceed mid and j doesn't exceed right\n while i <= mid and j <= right:\n if arr[i] <= arr[j]:\n temp_arr[k] = arr[i]\n i += 1\n else:\n # There are mid - i inversions, because all the remaining elements in the left subarray (arr[i], arr[i+1], ..., arr[mid]) are greater than arr[j]\n temp_arr[k] = arr[j]\n inv_count += (mid-i + 1)\n j += 1\n k += 1\n\n # Copy the remaining elements of left subarray, if any\n while i <= mid:\n temp_arr[k] = arr[i]\n i += 1\n k += 1\n\n # Copy the remaining elements of right subarray, if any\n while j <= right:\n temp_arr[k] = arr[j]\n j += 1\n k += 1\n\n # Copy the sorted subarray into Original array\n for i in range(left, right + 1):\n arr[i] = temp_arr[i]\n\n return inv_count\n\n # Function to divide the array elements into 2 halves and call _merge Sort and _merge function\n def merge_sort_and_count(arr, temp_arr, left, right):\n inv_count = 0\n if left < right:\n mid = (left + right) // 2\n\n inv_count += merge_sort_and_count(arr, temp_arr, left, mid)\n inv_count += merge_sort_and_count(arr, temp_arr, mid + 1, right)\n inv_count += merge_and_count(arr, temp_arr, left, mid, right)\n\n return inv_count\n\n # Initialize the temporary array\n temp_arr = [0]*len(arr)\n return merge_sort_and_count(arr, temp_arr, 0, len(arr) - 1)", "matching_cluster_idx": 5}, {"solution": "def get_Inv_Count(arr):\n # Helper function to merge two halves and count inversions\n def mergeSortAndCount(arr, temp_arr, left, right):\n inv_count = 0\n if left < right:\n mid = (left + right) // 2\n inv_count += mergeSortAndCount(arr, temp_arr, left, mid)\n inv_count += mergeSortAndCount(arr, temp_arr, mid + 1, right)\n inv_count += mergeAndCount(arr, temp_arr, left, mid, right)\n return inv_count\n\n # Helper function to merge two subarrays and count inversions\n def mergeAndCount(arr, temp_arr, left, mid, right):\n i = left # Starting index for left subarray\n j = mid + 1 # Starting index for right subarray\n k = left # Starting index to be sorted\n inv_count = 0\n\n # Conditions are checked to ensure that i doesn't exceed mid and j doesn't exceed right\n while i <= mid and j <= right:\n if arr[i] <= arr[j]:\n temp_arr[k] = arr[i]\n i += 1\n else:\n # There are mid - i inversions, because all the remaining elements in the left subarray\n # (arr[i], arr[i+1], ..., arr[mid]) are greater than arr[j]\n temp_arr[k] = arr[j]\n inv_count += (mid-i + 1)\n j += 1\n k += 1\n\n # Copy the remaining elements of left subarray, if any\n while i <= mid:\n temp_arr[k] = arr[i]\n i += 1\n k += 1\n\n # Copy the remaining elements of right subarray, if any\n while j <= right:\n temp_arr[k] = arr[j]\n j += 1\n k += 1\n\n # Copy the sorted subarray into Original array\n for i in range(left, right + 1):\n arr[i] = temp_arr[i]\n\n return inv_count\n\n # Initialize temporary array for merge sort\n temp_arr = [0] * len(arr)\n return mergeSortAndCount(arr, temp_arr, 0, len(arr) - 1)", "matching_cluster_idx": 5}, {"solution": "def get_Inv_Count(arr):\n # Initialize inversion count to 0\n inversion_count = 0\n \n # Iterate through the array\n for i in range(len(arr)):\n for j in range(i + 1, len(arr)):\n # If an inversion is found, increment the count\n if arr[i] > arr[j]:\n inversion_count += 1\n \n # Return the total number of inversions\n return inversion_count", "matching_cluster_idx": 3}]}, "Mbpp/308": {"dps": 74.62068965517241, "dps_norm": 62.5, "pass@1": 55.0, "profiled": [{"solution": "def large_product(nums1, nums2, k):\n # Combine both lists and sort them in descending order of their product\n combined = sorted([(a * b, a, b) for a in nums1 for b in nums2], reverse=True)\n # Extract the first k products and return them\n result = [product for product, _, _ in combined[:k]]\n return result", "matching_cluster_idx": 2}, {"solution": "def large_product(list1, list2, N):\n # Generate all possible products by multiplying one element from each list\n total = [list1[i] * list2[j] for i in range(len(list1)) for j in range(len(list2))]\n # Sort the list of products in descending order and select the first N elements\n ans = sorted(total, reverse=True)[:N]\n return ans", "matching_cluster_idx": 2}, {"solution": "import itertools\ndef large_product(A, B, K):\n # Generate all possible pairs of elements from the two lists\n result = itertools.product(A, B)\n # Calculate the product for each pair\n result = [x * y for x, y in result]\n # Sort the products in descending order\n result.sort(reverse=True)\n # Return the top K largest products\n return result[:K]", "matching_cluster_idx": 3}, {"solution": "from heapq import nlargest\ndef large_product(list1, list2, num):\n # Create a list of all possible products between elements of the two lists\n products = [x * y for x in list1 for y in list2]\n # Use nlargest from heapq to find the 'num' largest products\n return nlargest(num, products)", "matching_cluster_idx": 4}, {"solution": "from heapq import nlargest\nfrom itertools import product\ndef large_product(list1, list2, N):\n # Generate all possible products from the two lists\n products = list(product(list1, list2))\n # Use heapq to find the N largest products\n large_pro = nlargest(N, products, key=lambda x: x[0] * x[1])\n # Extract the product values from the tuples\n result = [product[0] * product[1] for product in large_pro]\n return result", "matching_cluster_idx": 2}, {"solution": "def large_product(nums1, nums2, k):\n # Initialize an empty list to store the products\n result = []\n # Iterate over each number in nums1\n for x in nums1:\n # Iterate over each number in nums2\n for y in nums2:\n # Append the product to the result list\n result.append(x * y)\n # Sort the result list in descending order\n result.sort(reverse=True)\n # Return the first k elements from the sorted result list\n return result[:k]", "matching_cluster_idx": 3}, {"solution": "def large_product(nums1, nums2, k):\n # Generate all possible products by selecting one factor from each list\n result = [a * b for a in nums1 for b in nums2]\n # Sort the products in descending order and return the first k products\n return sorted(result, reverse=True)[:k]", "matching_cluster_idx": 3}, {"solution": "def large_product(nums1, nums2, K):\n # Create a list of all possible products between elements of nums1 and nums2\n product_list = sorted([x * y for x in nums1 for y in nums2], reverse=True)\n # Return the first K elements from the sorted list of products\n return product_list[:K]", "matching_cluster_idx": 3}, {"solution": "def large_product(arr1, arr2, k):\n # Generate all possible products of elements from the two lists\n list2 = [arr1[i] * arr2[j] for i in range(len(arr1)) for j in range(len(arr2))]\n \n # Sort the list of products in descending order\n list2.sort(reverse=True)\n \n # Return the first 'k' products from the sorted list\n return list2[:k]", "matching_cluster_idx": 2}, {"solution": "from itertools import product\ndef large_product(nums1, nums2, k):\n # Compute all possible products of one element from each list\n lst = [i * j for i, j in product(nums1, nums2)]\n # Sort the products in descending order and take the top 'k' products\n lst.sort(reverse=True)\n return lst[:k]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, k):\n # Generate all possible products by iterating over both lists\n products = [list1[i] * list2[j] for i in range(len(list1)) for j in range(len(list2))]\n # Sort the products list in descending order\n products.sort(reverse=True)\n # Return the first 'k' products from the sorted list\n return products[:k]", "matching_cluster_idx": 2}, {"solution": "def large_product(a, b, k):\n # Calculate all possible products from pairs of numbers from the two lists\n c = sorted([i * j for i in a for j in b], reverse=True)\n # Return the first k elements from the sorted list of products\n return c[:k]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, k):\n # Sort both input lists in descending order\n sorted_list1 = sorted(list1, reverse=True)\n sorted_list2 = sorted(list2, reverse=True)\n \n # Calculate all possible products and store them in a list\n products = [i * j for i in sorted_list1 for j in sorted_list2]\n \n # Return the first k elements from the sorted list of products\n return sorted(products, reverse=True)[:k]", "matching_cluster_idx": 3}, {"solution": "import heapq\ndef large_product(list1, list2, count):\n # Calculate all possible products between elements of the two lists\n # Use heapq.nlargest to find the 'count' largest products\n return heapq.nlargest(count, [x * y for x in list1 for y in list2])", "matching_cluster_idx": 4}, {"solution": "def large_product(nums1, nums2, k):\n # Use list comprehension to create a list of all possible products\n products = [nums1[i] * nums2[j] for i in range(len(nums1)) for j in range(len(nums2))]\n \n # Sort the list of products in ascending order and take the last k elements\n sorted_products = sorted(products, reverse=True)\n \n # Return the last k elements from the sorted list\n return sorted_products[:k]", "matching_cluster_idx": 2}, {"solution": "def large_product(list1, list2, k):\n # Calculate all possible products from pairs of elements from list1 and list2\n result = [x * y for x in list1 for y in list2]\n \n # Sort the result list in descending order to get the largest products first\n result.sort(reverse=True)\n \n # Return the first 'k' products from the sorted list\n return result[:k]", "matching_cluster_idx": 3}, {"solution": "def large_product(l1, l2, n):\n # Combine each element of the first list with each element of the second list\n res = [i * j for i in l1 for j in l2]\n # Sort the resulting list in descending order and select the top 'n' elements\n return sorted(res, reverse=True)[:n]", "matching_cluster_idx": 3}, {"solution": "import heapq\ndef large_product(A, B, k):\n # Use heapq to find the k largest products\n result = heapq.nlargest(k, (a * b for a in A for b in B))\n return result", "matching_cluster_idx": 3}, {"solution": "def large_product(nums1, nums2, k):\n # Calculate all possible products of one element from each list\n products = sorted([nums1[i] * nums2[j] for i in range(len(nums1)) for j in range(len(nums2))], reverse=True)\n \n # Return the first 'k' largest products\n return products[:k]", "matching_cluster_idx": 2}, {"solution": "def large_product(list1, list2, no_of_products):\n # Generate all possible products by multiplying each element from list1 with each element from list2\n products = [a * b for a in list1 for b in list2]\n # Sort the list of products in descending order and select the specified number of largest products\n largest_products = sorted(products, reverse=True)[:no_of_products]\n return largest_products", "matching_cluster_idx": 3}]}, "Mbpp/392": {"dps": 94.01408450704226, "dps_norm": 97.6923076923077, "pass@1": 48.0, "profiled": [{"solution": "def get_max_sum(n):\n # Dictionary to store computed results for memoization\n dict_values = {0: 0, 1: 1}\n \n def compute_value(x):\n # If the result is already computed, return it\n if x in dict_values:\n return dict_values[x]\n \n # Calculate the maximum sum recursively\n max_sum = max(compute_value(x // 2) + compute_value(x // 3) + compute_value(x // 4) + compute_value(x // 5), x)\n \n # Store the computed result in the dictionary\n dict_values[x] = max_sum\n \n return max_sum\n \n # Start computation with the input number\n return compute_value(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n # Dictionary to store already computed results\n table = [0] * (n + 1)\n \n def maximum_sum(number):\n nonlocal table # Use nonlocal keyword to modify the outer function's variable\n \n # Base case: if the number is less than 2, return the number itself\n if number < 2:\n return number\n \n # Check if the result is already computed and stored in the table\n if table[number] != 0:\n return table[number]\n \n # Recursive calculation using the given formula\n result = max(maximum_sum(number // 2) + maximum_sum(number // 3) + maximum_sum(number // 4) + maximum_sum(number // 5), number)\n \n # Store the result in the table for future reference\n table[number] = result\n \n return result\n \n # Call the recursive function with the input number\n return maximum_sum(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n # Create an array to store previously computed values\n dp = [-1] * (n + 1)\n \n # Function to recursively calculate the maximum sum\n def find_max(n):\n # Base case: if the value is already computed, return it\n if dp[n] != -1:\n return dp[n]\n \n # Base case: if n is less than or equal to 0, return 0\n if n <= 0:\n return 0\n \n # Calculate the maximum sum using the given equation\n dp[n] = max(n, find_max(n // 2) + find_max(n // 3) + find_max(n // 4) + find_max(n // 5))\n return dp[n]\n \n # Call the recursive function to get the maximum sum for n\n return find_max(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n # Initialize a list to store the maximum sums for numbers up to n\n dp = [0] * (n + 1)\n \n # Iterate through each number from 1 to n to fill the dp array\n for i in range(1, n + 1):\n # Calculate the maximum sum using the given formula\n dp[i] = max(dp[i // 2] + dp[i // 3] + dp[i // 4] + dp[i // 5], i)\n \n # Return the maximum sum for the given number n\n return dp[n]", "matching_cluster_idx": 10}, {"solution": "import sys\ndef get_max_sum(n):\n \"\"\"\n This function calculates the maximum sum possible for a given number using the equation f(n) = max(f(n/2) + f(n/3) + f(n/4) + f(n/5), n).\n \n Parameters:\n n (int): The number for which to calculate the maximum sum.\n \n Returns:\n int: The maximum sum possible.\n \"\"\"\n # Dictionary to store computed results for memoization\n dp = {0: 0, 1: 1}\n \n def helper(x):\n \"\"\"\n Helper function to calculate the sum using memoization.\n \n Parameters:\n x (int): The number to calculate the sum for.\n \n Returns:\n int: The calculated sum.\n \"\"\"\n if x not in dp:\n # Recursively calculate the sum using memoized results\n dp[x] = max(helper(x // 2) + helper(x // 3) + helper(x // 4) + helper(x // 5), x)\n return dp[x]\n \n return helper(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n, memo={}):\n # Base case: if n is 0 or 1, return n\n if n <= 1:\n return n\n \n # Check if the result is already computed and stored in the memo dictionary\n if n not in memo:\n # Recursive case: compute the maximum sum using the given equation\n memo[n] = max(get_max_sum(n // 2, memo) + get_max_sum(n // 3, memo) + get_max_sum(n // 4, memo) + get_max_sum(n // 5, memo), n)\n \n # Return the computed result\n return memo[n]", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n # Initialize a list to store maximum sums\n lookup = [0 for i in range(n + 1)]\n \n def max_sum(num):\n # Base case: if num is less than or equal to 0, return 0\n if num <= 0:\n return 0\n # If the result is already computed, return it\n if lookup[num] != 0:\n return lookup[num]\n \n # Compute the maximum sum using the given equation\n lookup[num] = max(max_sum(num // 2) + max_sum(num // 3) + max_sum(num // 4) + max_sum(num // 5), num)\n return lookup[num]\n \n # Call the helper function with the given number\n return max_sum(n)", "matching_cluster_idx": 10}, {"solution": "def get_max_sum(n):\n # Initialize a dictionary to store previously computed results\n dp = {}\n dp[0] = 0 # Base case: f(0) = 0\n dp[1] = 1 # Base case: f(1) = 1\n \n # Define a recursive function to compute f(n)\n def get_sum(n):\n # If n is already computed, return the result\n if n in dp:\n return dp[n]\n # Otherwise, compute it recursively\n else:\n dp[n] = max(n, get_sum(n // 2) + get_sum(n // 3) + get_sum(n // 4) + get_sum(n // 5))\n return dp[n]\n \n # Compute the result for the given n\n result = get_sum(n)\n \n return result", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n # Initialize a list to store results of subproblems\n dp = [-1] * (n + 1)\n \n def calculate_sum(n):\n # If the result for this n is already calculated, return it\n if dp[n] != -1:\n return dp[n]\n \n # Calculate the maximum sum using the given equation\n if n == 0:\n dp[n] = 0\n elif n == 1:\n dp[n] = 1\n else:\n dp[n] = max(calculate_sum(n // 2) + calculate_sum(n // 3) + calculate_sum(n // 4) + calculate_sum(n // 5), n)\n \n return dp[n]\n \n # Call the helper function with the given number n\n return calculate_sum(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n # Dictionary to store the maximum sums\n max_sum_dict = {0: 0, 1: 1}\n\n # Function to get the maximum sum using memoization\n def memoized_max_sum(n):\n if n not in max_sum_dict:\n # Calculate the maximum sum for n using the given equation\n max_sum = max(n, memoized_max_sum(n // 2) + memoized_max_sum(n // 3) + memoized_max_sum(n // 4) + memoized_max_sum(n // 5))\n max_sum_dict[n] = max_sum\n return max_sum_dict[n]\n\n # Call the memoized function to get the maximum sum for n\n return memoized_max_sum(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n # Initialize a dictionary to store the maximum sum for each number\n dp = [0 for i in range(n + 1)]\n \n # Define a recursive function to compute the maximum sum\n def helper(x):\n # If the value is already computed, return it\n if x <= 1:\n return x\n # If the value is not computed, compute it using the given equation\n if dp[x] == 0:\n dp[x] = max(helper(x // 2) + helper(x // 3) + helper(x // 4) + helper(x // 5), x)\n return dp[x]\n \n # Call the helper function to compute the maximum sum for 'n'\n return helper(n)", "matching_cluster_idx": 10}, {"solution": "def get_max_sum(n):\n # Initialize a dictionary to store computed results\n dp = {0: 0, 1: 1}\n \n # Helper function to calculate the maximum sum using memoization\n def max_sum(n):\n # Base case: if n is already computed, return the stored result\n if n in dp:\n return dp[n]\n \n # Recursive case: compute the result using the given formula\n dp[n] = max(n, max_sum(n // 2) + max_sum(n // 3) + max_sum(n // 4) + max_sum(n // 5))\n return dp[n]\n \n # Call the helper function with the given number\n return max_sum(n)", "matching_cluster_idx": 12}, {"solution": "import math\ndef get_max_sum(n):\n # Dictionary to store the computed values of f(n)\n dp = dict()\n\n # Recursive function to calculate the maximum sum\n def helper(n):\n # Base case: if n is 0, return 0\n if n == 0:\n return 0\n # Base case: if n is 1, return 1\n if n == 1:\n return 1\n # Check if the value has already been computed\n if n in dp:\n return dp[n]\n # Recursively calculate the sum of f(n/2), f(n/3), f(n/4), and f(n/5)\n # and compare it with n to decide the maximum sum\n dp[n] = max(helper(int(n / 2)) + helper(int(n / 3)) + helper(int(n / 4)) + helper(int(n / 5)), n)\n return dp[n]\n\n # Start the recursion with the given number n\n return helper(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n # Initialize a dictionary to store computed results\n dp = dict()\n\n def compute(n):\n # Check if the result is already computed\n if n in dp:\n return dp[n]\n # Base case: if n is less than 2, return n\n elif n < 2:\n return n\n else:\n # Compute the maximum sum using the given formula\n dp[n] = max(compute(n // 2) + compute(n // 3) + compute(n // 4) + compute(n // 5), n)\n return dp[n]\n\n # Call the recursive function with the initial input\n return compute(n)", "matching_cluster_idx": 12}, {"solution": "memory = {}\ndef get_max_sum(n):\n # Check if the result for n is already computed and stored\n if n in memory:\n return memory[n]\n # Base case: if n is less than or equal to 1, return n\n if n <= 1:\n result = n\n else:\n # Recursive case: calculate the maximum sum using the given formula\n result = max(get_max_sum(n//2) + get_max_sum(n//3) + get_max_sum(n//4) + get_max_sum(n//5), n)\n # Store the result in the dictionary for future reference\n memory[n] = result\n return result", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n # Initialize a dictionary to store computed values\n f = {0: 0, 1: 1}\n \n # Helper function to compute the maximum sum\n def fmax(n):\n # Check if the value is already computed\n if n in f:\n return f[n]\n \n # Recursively compute the maximum sum using the given formula\n f[n] = max(fmax(n // 2) + fmax(n // 3) + fmax(n // 4) + fmax(n // 5), n)\n \n return f[n]\n \n # Return the result of the helper function for the given input n\n return fmax(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n # Dictionary to store the maximum sum values\n dp = {}\n \n # Helper function to calculate the maximum sum recursively\n def max_sum_helper(num):\n # Base case: if num is less than or equal to 0, return 0\n if num <= 0:\n return 0\n # If the value is already computed, return it from the dictionary\n if num in dp:\n return dp[num]\n \n # Recursively calculate the maximum sum using the given equation\n dp[num] = max(max_sum_helper(num // 2) + max_sum_helper(num // 3) + max_sum_helper(num // 4) + max_sum_helper(num // 5), num)\n return dp[num]\n \n # Calculate the maximum sum for the given number n\n return max_sum_helper(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n # Create a dictionary to store computed results for dynamic programming\n dp = {}\n \n # Helper function to compute the maximum sum\n def f(n):\n # If the result is already computed, return it\n if n in dp:\n return dp[n]\n # Base case: if n is less than or equal to 0, the sum is n\n elif n <= 0:\n return n\n else:\n # Compute the sum using the recursive formula and store it in the dictionary\n dp[n] = max(f(n // 2) + f(n // 3) + f(n // 4) + f(n // 5), n)\n return dp[n]\n \n # Call the helper function with the input n\n return f(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n # Dictionary to store previously computed results\n memo = {}\n \n def helper(n):\n # Check if the result is already computed\n if n in memo:\n return memo[n]\n \n # Base case\n if n <= 1:\n return n\n \n # Compute the sum using the given formula\n result = max(helper(n // 2) + helper(n // 3) + helper(n // 4) + helper(n // 5), n)\n \n # Store the computed result in the dictionary\n memo[n] = result\n \n return result\n \n # Call the helper function with the input n\n return helper(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n # Dictionary to store already computed sums\n dp = {}\n \n def find_maximum(n):\n # Check if the result is already computed\n if n in dp:\n return dp[n]\n \n # Base cases\n if n <= 1:\n return n\n \n # Recursively calculate the sum\n result = max((find_maximum(n // 2) + find_maximum(n // 3) + find_maximum(n // 4) + find_maximum(n // 5)), n)\n # Store the result in the dictionary\n dp[n] = result\n return result\n \n # Call the recursive function with the given number\n return find_maximum(n)", "matching_cluster_idx": 12}]}, "Mbpp/395": {"dps": 89.48275862068965, "dps_norm": 71.875, "pass@1": 98.0, "profiled": [{"solution": "def first_non_repeating_character(s):\n # Create a dictionary to store the frequency of each character\n frequency = {}\n \n # Iterate over the string and populate the frequency dictionary\n for char in s:\n if char in frequency:\n frequency[char] += 1\n else:\n frequency[char] = 1\n \n # Iterate over the string again and return the first character with a frequency of 1\n for char in s:\n if frequency[char] == 1:\n return char\n \n # If no non-repeating character is found, return None\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n # Dictionary to count occurrences of each character\n char_count = {}\n \n # Count the occurrence of each character\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n \n # Find the first character with a count of 1\n for char in s:\n if char_count[char] == 1:\n return char\n \n # Return None if no non-repeated character is found\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n # Initialize a list to store character counts\n char_count = [0] * 256\n \n # Iterate over the string to count each character's occurrences\n for i in range(len(s)):\n char_count[ord(s[i])] += 1\n \n # Iterate over the string again to find the first character with a count of 1\n for i in range(len(s)):\n if char_count[ord(s[i])] == 1:\n return s[i]\n \n # Return None if no non-repeated character is found\n return None", "matching_cluster_idx": 4}, {"solution": "def first_non_repeating_character(s):\n # Initialize a dictionary to store the count of each character\n char_count = {}\n \n # Count the occurrences of each character in the string\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n \n # Iterate through the string again to find the first non-repeated character\n for char in s:\n if char_count[char] == 1:\n return char\n \n # If no non-repeated character is found, return None\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(str1):\n # Create a dictionary to store the frequency of each character\n dict = {}\n \n # Iterate over each character in the string\n for char in str1:\n # If the character is already in the dictionary, increment its count\n if char in dict:\n dict[char] += 1\n # Otherwise, add the character to the dictionary with a count of 1\n else:\n dict[char] = 1\n \n # Iterate over each character in the string again\n for char in str1:\n # If the character's count in the dictionary is 1, it's the first non-repeated character\n if dict[char] == 1:\n return char\n \n # If no non-repeated character is found, return None\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n # Create a dictionary to store the frequency of each character\n freq = {}\n \n # Iterate over each character in the string\n for char in s:\n # If the character is already in the dictionary, increment its count\n if char in freq:\n freq[char] += 1\n # If the character is not in the dictionary, add it with a count of 1\n else:\n freq[char] = 1\n \n # Iterate over each character in the string again\n for char in s:\n # Check if the frequency of the current character is 1\n if freq[char] == 1:\n # If it is, return that character\n return char\n \n # If no non-repeating character is found, return None\n return None", "matching_cluster_idx": 5}, {"solution": "from collections import OrderedDict\ndef first_non_repeating_character(s):\n # Create an ordered dictionary to store character counts\n count = OrderedDict()\n \n # Count occurrences of each character in the string\n for ch in s:\n if ch in count:\n count[ch] += 1\n else:\n count[ch] = 1\n \n # Return the first character with a count of 1\n for ch, freq in count.items():\n if freq == 1:\n return ch\n \n # If no non-repeated character is found, return None\n return None", "matching_cluster_idx": 5}, {"solution": "from collections import defaultdict\ndef first_non_repeating_character(s):\n # Create a dictionary to store the frequency of each character in the string\n char_frequency = defaultdict(int)\n \n # Iterate over the string and count the frequency of each character\n for char in s:\n char_frequency[char] += 1\n \n # Iterate over the string again and return the first character with a frequency of 1\n for char in s:\n if char_frequency[char] == 1:\n return char\n \n # If no non-repeating character is found, return None\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n # Dictionary to count occurrences of each character\n count = {}\n \n # Count each character in the string\n for char in s:\n if char in count:\n count[char] += 1\n else:\n count[char] = 1\n \n # Find the first character with a count of 1\n for char in s:\n if count[char] == 1:\n return char\n \n # Return None if no non-repeating character is found\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n # Dictionary to store character counts\n dic = {}\n \n # First pass to populate the dictionary with counts of each character\n for x in s:\n dic[x] = dic.get(x, 0) + 1\n \n # Second pass to find the first character with a count of 1\n for x in s:\n if dic[x] == 1:\n return x\n \n # Return None if no non-repeated character is found\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n # Initialize an empty dictionary to store character counts\n counts = {}\n \n # Loop through the string to count occurrences of each character\n for c in s:\n if c in counts:\n counts[c] += 1\n else:\n counts[c] = 1\n \n # Iterate through the string again to find the first character with a count of 1\n for c in s:\n if counts[c] == 1:\n return c\n \n # If no non-repeated character is found, return None\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n # Create a dictionary to store the frequency of each character\n d = {}\n \n # Iterate over the characters in the string\n for char in s:\n if char in d:\n # If character is already in dictionary, increment its count\n d[char] += 1\n else:\n # If character is not in dictionary, add it with count 1\n d[char] = 1\n \n # Iterate over the characters in the string again\n for char in s:\n # Check if the count of the character is 1\n if d[char] == 1:\n # If count is 1, return the character\n return char\n \n # If no non-repeating character is found, return None\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n # Iterate through the string\n for i in range(len(s)):\n # Check if the current character is the only one in the string\n if s.count(s[i]) == 1:\n return s[i]\n # Return None if no non-repeating character is found\n return None", "matching_cluster_idx": 1}, {"solution": "from collections import OrderedDict\ndef first_non_repeating_character(s):\n # Create an ordered dictionary to maintain the order of characters and their counts\n counts = OrderedDict()\n \n # Count occurrences of each character in the string\n for char in s:\n counts[char] = counts.get(char, 0) + 1\n \n # Find the first character with a count of 1\n for char in counts:\n if counts[char] == 1:\n return char\n \n # Return None if no non-repeating character is found\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(input_str):\n # Create a dictionary to store character frequencies\n char_freq = {}\n \n # Iterate over each character in the input string\n for char in input_str:\n if char in char_freq:\n # Increment the frequency of the character if it's already in the dictionary\n char_freq[char] += 1\n else:\n # Initialize the frequency of the character to 1 if it's not in the dictionary\n char_freq[char] = 1\n \n # Iterate over the string again to find the first character with a frequency of 1\n for char in input_str:\n if char_freq[char] == 1:\n # Return the first non-repeating character\n return char\n \n # Return None if no non-repeating character is found\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(str1):\n # Create a dictionary to store the count of each character\n char_count = {}\n \n # Count the occurrences of each character\n for char in str1:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n \n # Iterate through the string and return the first character with a count of 1\n for char in str1:\n if char_count[char] == 1:\n return char\n \n # Return None if no non-repeating character is found\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n # Create a dictionary to store the frequency of each character\n count = {}\n for char in s:\n if char in count:\n count[char] += 1\n else:\n count[char] = 1\n \n # Iterate over the string and return the first character with a count of 1\n for char in s:\n if count[char] == 1:\n return char\n \n # If no non-repeated character is found, return None\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n # Initialize a dictionary to store the frequency of each character\n frequency = {}\n \n # Iterate over each character in the string\n for char in s:\n # If the character is already in the dictionary, increment its count\n if char in frequency:\n frequency[char] += 1\n # Otherwise, add the character to the dictionary with a count of 1\n else:\n frequency[char] = 1\n \n # Iterate over each character in the string again\n for char in s:\n # If the count of the character in the dictionary is 1, return it\n if frequency[char] == 1:\n return char\n \n # If no non-repeating character is found, return None\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n # Dictionary to store character counts\n character_count = {}\n \n # First loop to count occurrences of each character\n for char in s:\n if char in character_count:\n character_count[char] += 1\n else:\n character_count[char] = 1\n \n # Second loop to find the first non-repeating character\n for char in s:\n if character_count[char] == 1:\n return char\n \n # If no non-repeating character is found, return None\n return None", "matching_cluster_idx": 5}, {"solution": "from collections import Counter\ndef first_non_repeating_character(s):\n # Count the frequency of each character in the string\n frequency = Counter(s)\n \n # Iterate through the string and return the first character with a frequency of 1\n for char in s:\n if frequency[char] == 1:\n return char\n \n # If no non-repeated character is found, return None\n return None", "matching_cluster_idx": 5}]}, "Mbpp/405": {"dps": 95.96153846153847, "dps_norm": 96.25, "pass@1": 98.0, "profiled": [{"solution": "def check_tuplex(tuplex, element):\n # Check if the element exists in the tuple\n return element in tuplex", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, element):\n # Check if the element is in the tuple using the 'in' keyword\n return element in tuplex", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, element):\n # Check if the element exists in the tuple\n if element in tuplex:\n return True\n else:\n return False", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuple, element):\n # Use the 'in' keyword to check if the element exists in the tuple\n return element in tuple", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(test_tup, K):\n # Check if the element K exists in the tuple test_tup using the 'in' keyword\n res = (K in test_tup)\n return res", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, element):\n # Check if the element is in the tuple and return the result\n return element in tuplex", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(test_tup, K):\n # Check if the element is in the tuple and return the result\n res = K in test_tup\n return res", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(test_tup, K):\n # Use the 'in' keyword to check if the element is in the tuple and return the result\n res = K in test_tup\n return res", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, element):\n # Check if the element exists in the tuple\n if element in tuplex:\n return True\n else:\n return False", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuple, element):\n # Check if the element exists in the tuple and return the result\n return element in tuple", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, element):\n # Check if the element exists in the tuple\n result = element in tuplex\n return result", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, element):\n # Check if the element exists in the tuple\n if element in tuplex:\n return True\n else:\n return False", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, element):\n # Check if the element is in the tuple using the 'in' keyword\n if element in tuplex:\n return True\n else:\n return False", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, element):\n # Iterate through each item in the tuple\n for item in tuplex:\n # Check if the current item matches the element\n if (item == element):\n # If a match is found, return True\n return True\n # If no match is found after checking all items, return False\n return False", "matching_cluster_idx": 0}, {"solution": "def check_tuplex(tuplex, element):\n # Return True if the element is in the tuple, otherwise False\n return element in tuplex", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, element):\n # Check if the element exists in the tuple and return True if found\n return element in tuplex", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, element):\n # Check if the element is in the tuple and return the result\n return element in tuplex", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, element):\n # Use the 'in' operator to check if the element is in the tuple\n return element in tuplex", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, element):\n # Check if the element exists in the tuple\n if element in tuplex:\n return True\n else:\n return False", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, element):\n # Check if the element exists in the tuple\n if element in tuplex:\n return True\n else:\n return False", "matching_cluster_idx": 3}]}, "Mbpp/414": {"dps": 63.41614906832298, "dps_norm": 77.22222222222223, "pass@1": 99.0, "profiled": [{"solution": "def overlapping(seq1, seq2):\n # Iterate over each item in the first sequence\n for value in seq1:\n # Check if the item is in the second sequence\n if value in seq2:\n # If found, return True indicating an overlap\n return True\n # If no overlap found, return False\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(list1, list2):\n # Check if there is any common element between list1 and list2\n return bool(set(list1) & set(list2))", "matching_cluster_idx": 5}, {"solution": "def overlapping(seq1, seq2):\n # Use set intersection to find common elements between the two sequences\n if len(set(seq1) & set(seq2)):\n return True # Return True if there are any overlapping values\n else:\n return False # Return False if there are no overlapping values", "matching_cluster_idx": 5}, {"solution": "def overlapping(test_list1, test_list2):\n # Check if there is any element in test_list1 that is also in test_list2\n res = any(x in test_list2 for x in test_list1)\n return res", "matching_cluster_idx": 7}, {"solution": "def overlapping(list1, list2):\n # Use set intersection to find common elements\n common_elements = set(list1) & set(list2)\n # Return True if there are common elements, False otherwise\n return bool(common_elements)", "matching_cluster_idx": 5}, {"solution": "def overlapping(list1, list2):\n # Initialize a variable to track if there is an overlapping element\n flag = 0\n # Iterate over each element in the first list\n for i in list1:\n # Check if the current element is in the second list\n if i in list2:\n # If found, set the flag to 1 (True) and break the loop\n flag = 1\n break\n # Return True if an overlap is found, otherwise False\n if flag == 1:\n return True\n else:\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(list1, list2):\n # Check if there is any overlap between list1 and list2\n return bool(set(list1) & set(list2))", "matching_cluster_idx": 5}, {"solution": "def overlapping(test_list1, test_list2):\n # Check if any element in test_list1 is also in test_list2\n res = any(i in test_list2 for i in test_list1)\n return res", "matching_cluster_idx": 7}, {"solution": "def overlapping(list1, list2):\n # Use set to find intersection of two lists\n if set(list1) & set(list2):\n return True\n return False", "matching_cluster_idx": 5}, {"solution": "def overlapping(test_list1, test_list2):\n # Use set intersection to check for common elements\n res = bool(set(test_list1) & set(test_list2))\n return res", "matching_cluster_idx": 5}, {"solution": "def overlapping(test_list1, test_list2):\n # Check if any element from test_list2 exists in test_list1\n res = any(item in test_list1 for item in test_list2)\n return res", "matching_cluster_idx": 8}, {"solution": "def overlapping(list1, list2):\n # Create a set from the first list for O(1) average-case complexity for lookups\n list1_set = set(list1)\n # Check each element in the second list against the set\n return any(element in list1_set for element in list2)", "matching_cluster_idx": 6}, {"solution": "def overlapping(seq1, seq2):\n # Loop through each element in the first sequence\n for x in seq1:\n # Check if the current element is in the second sequence\n if x in seq2:\n return True\n # If no common elements are found, return False\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(list1, list2):\n # Initialize a variable to indicate if there's any overlap\n flag = 0\n \n # Iterate through each element in the first list\n for i in list1:\n # Check if the current element is in the second list\n if i in list2:\n # If found, set the flag to 1 (True) and break the loop\n flag = 1\n break\n \n # Return the result: True if flag is 1, otherwise False\n return bool(flag)", "matching_cluster_idx": 7}, {"solution": "def overlapping(test_list1, test_list2):\n # Check if any element from test_list1 exists in test_list2\n res = any([ele in test_list2 for ele in test_list1])\n return res", "matching_cluster_idx": 2}, {"solution": "def overlapping(test_list1, test_list2):\n # Check if any value in test_list1 exists in test_list2 using set intersection\n res = bool(set(test_list1) & set(test_list2))\n return res", "matching_cluster_idx": 5}, {"solution": "def overlapping(list1, list2):\n # Using set intersection to check if any value exists in both lists\n if set(list1) & set(list2):\n return True\n return False", "matching_cluster_idx": 5}, {"solution": "def overlapping(list1, list2):\n # Iterate through each element in the first list\n for element in list1:\n # Check if the element is present in the second list\n if element in list2:\n return True # Return True if the element is found\n return False # Return False if no common element is found", "matching_cluster_idx": 7}, {"solution": "def overlapping(test_list1, test_list2):\n # Initialize result as False\n res = False\n # Iterate through each element in the first list\n for ele in test_list1:\n # Check if the element is in the second list\n if ele in test_list2:\n # If found, set result to True and break the loop\n res = True\n break\n # Return the result\n return res", "matching_cluster_idx": 7}, {"solution": "def overlapping(list1, list2):\n # Iterate over each element in the first list\n for i in list1:\n # Check if the element is present in the second list\n if i in list2:\n return True\n # Return False if no common element is found\n return False", "matching_cluster_idx": 7}]}, "Mbpp/421": {"dps": 39.876543209876544, "dps_norm": 75.71428571428571, "pass@1": 93.0, "profiled": [{"solution": "def concatenate_tuple(test_tup):\n # Convert each element in the tuple to a string and join them with a hyphen as the delimiter\n res = '-'.join(str(ele) for ele in test_tup)\n return str(res)", "matching_cluster_idx": 4}, {"solution": "def concatenate_tuple(test_tup):\n # Concatenate each element of the tuple into a single string with a dash delimiter\n res = '-'.join(str(ele) for ele in test_tup)\n return res", "matching_cluster_idx": 4}, {"solution": "def concatenate_tuple(test_tup):\n # Join each element of the tuple into a string with '-' as the delimiter\n res = '-'.join(str(ele) for ele in test_tup)\n return str(res)", "matching_cluster_idx": 4}, {"solution": "def concatenate_tuple(test_tup):\n # Convert each element of the tuple to string and join them with '-'\n res = '-'.join(str(ele) for ele in test_tup)\n return res", "matching_cluster_idx": 4}, {"solution": "def concatenate_tuple(test_tup):\n # Convert each element in the tuple to string and join with '-'\n res = '-'.join(map(str, test_tup))\n return str(res)", "matching_cluster_idx": 5}, {"solution": "def concatenate_tuple(test_tup):\n # Initialize an empty string to store the result\n res = \"\"\n # Iterate through each element in the tuple\n for ele in test_tup:\n # Convert the element to string and concatenate it with the result\n # Add a hyphen as a delimiter\n res += str(ele) + '-'\n # Return the result string, removing the trailing hyphen\n return res[:-1]", "matching_cluster_idx": 3}, {"solution": "def concatenate_tuple(test_tup):\n # Initialize an empty string as the result\n res = ''\n # Iterate over each element in the tuple\n for ele in test_tup:\n # Convert the element to string and concatenate it to res with a hyphen\n res += str(ele) + '-'\n # Return the result string, removing the trailing hyphen\n return res[:-1]", "matching_cluster_idx": 3}, {"solution": "def concatenate_tuple(test_tup):\n # Using join() to concatenate tuple elements with '-'\n res = '-'.join(str(ele) for ele in test_tup)\n return res", "matching_cluster_idx": 4}, {"solution": "def concatenate_tuple(tup):\n # Convert each element of the tuple to string and concatenate with '-'\n result = '-'.join(str(element) for element in tup)\n return result", "matching_cluster_idx": 4}, {"solution": "def concatenate_tuple(test_tup):\n # Convert each element in the tuple to a string\n res = '-'.join(str(ele) for ele in test_tup)\n return res", "matching_cluster_idx": 4}, {"solution": "def concatenate_tuple(Tup):\n # Initialize an empty string to store the result\n res = ''\n # Iterate through each element in the tuple\n for ele in Tup:\n # Convert each element to string and concatenate with a hyphen\n res += str(ele) + '-'\n # Return the result string, slicing to remove the trailing hyphen\n return res[:-1]", "matching_cluster_idx": 3}, {"solution": "def concatenate_tuple(test_tup):\n # Using the join() method to concatenate tuple elements with '-' as a delimiter\n res = '-'.join([str(ele) for ele in test_tup])\n return str(res)", "matching_cluster_idx": 5}, {"solution": "def concatenate_tuple(tup):\n # Convert each element of the tuple to string and join them with '-'\n return '-'.join(str(element) for element in tup)", "matching_cluster_idx": 4}, {"solution": "def concatenate_tuple(items):\n # Convert each element of the tuple to a string and join them with a hyphen as the delimiter\n return '-'.join(map(str, items))", "matching_cluster_idx": 6}, {"solution": "def concatenate_tuple(test_tup):\n # Convert each element to string and join them with the delimiter '-'\n res = '-'.join([str(ele) for ele in test_tup])\n return str(res)", "matching_cluster_idx": 5}, {"solution": "def concatenate_tuple(test_tup):\n # Use the join() method with '-' as the delimiter to concatenate elements of the tuple\n res = '-'.join([str(ele) for ele in test_tup])\n return str(res)", "matching_cluster_idx": 5}, {"solution": "def concatenate_tuple(test_tup):\n # Check if the tuple contains any non-string elements\n res = '-'.join(map(str, test_tup))\n return res", "matching_cluster_idx": 6}, {"solution": "def concatenate_tuple(test_tup):\n # Initialize a result variable as an empty string\n res = \"\"\n # Iterate through each element in the tuple\n for ele in test_tup:\n # Convert the element to string and concatenate with the result\n res += str(ele) + \"-\"\n # Return the result string, removing the trailing delimiter\n return res[:-1]", "matching_cluster_idx": 3}, {"solution": "def concatenate_tuple(input_tuple):\n # Joining tuple elements into a string with '-' as the delimiter\n result = '-'.join(str(element) for element in input_tuple)\n return result", "matching_cluster_idx": 4}, {"solution": "def concatenate_tuple(items):\n # Convert each element in the tuple to string and join them with '-'\n return '-'.join(map(str, items))", "matching_cluster_idx": 6}]}, "Mbpp/424": {"dps": 92.74368231046931, "dps_norm": 97.0, "pass@1": 100.0, "profiled": [{"solution": "def extract_rear(test_tup):\n # Using list comprehension and indexing to extract the last character of each string in the tuple\n res = [sub[-1] for sub in test_tup]\n return res", "matching_cluster_idx": 4}, {"solution": "def extract_rear(input_tuple):\n # Use list comprehension to extract the last character of each string in the tuple\n result = [element[-1] for element in input_tuple]\n return result", "matching_cluster_idx": 4}, {"solution": "def extract_rear(test_tup):\n # Using list comprehension to iterate over each string in the tuple and extract the last character\n res = [sub[-1] for sub in test_tup]\n return res", "matching_cluster_idx": 4}, {"solution": "def extract_rear(test_tup):\n # Extracting the last element from each string in the tuple\n res = [sub[-1] for sub in test_tup]\n return res", "matching_cluster_idx": 4}, {"solution": "def extract_rear(test_tup):\n # Using list comprehension to iterate through each string in the tuple\n # and extracting the last character of each string\n res = [sub[-1] for sub in test_tup]\n return res", "matching_cluster_idx": 4}, {"solution": "def extract_rear(test_tup):\n # Using list comprehension to extract the last character of each string in the tuple\n res = [sub[-1] for sub in test_tup]\n return res", "matching_cluster_idx": 4}, {"solution": "def extract_rear(test_tup):\n # Extract the last element of each string in the tuple\n res = [sub[-1] for sub in test_tup]\n return res", "matching_cluster_idx": 3}, {"solution": "def extract_rear(test_tup):\n # Extract the last character of each string in the tuple using list comprehension\n res = [sub[-1] for sub in test_tup]\n return res", "matching_cluster_idx": 4}, {"solution": "def extract_rear(test_tup):\n # Extracting the last element from each string in the tuple using list comprehension\n res = [sub[-1] for sub in test_tup]\n return res", "matching_cluster_idx": 4}, {"solution": "def extract_rear(test_tup):\n # Extract the last element of each string in the tuple using list comprehension\n res = [sub[-1] for sub in test_tup]\n return res", "matching_cluster_idx": 4}, {"solution": "def extract_rear(test_tup):\n # Using list comprehension to extract the last character of each string\n res = [sub[-1] for sub in test_tup]\n return res", "matching_cluster_idx": 4}, {"solution": "def extract_rear(test_tup):\n # Initialize an empty list to store the last elements\n res = []\n # Iterate through each string in the tuple\n for ele in test_tup:\n # Append the last character of each string to the result list\n res.append(ele[-1])\n return res", "matching_cluster_idx": 3}, {"solution": "def extract_rear(test_tup):\n # Use list comprehension to iterate through each string in the tuple\n # The [-1] index selects the last character of each string\n res = [sub[-1] for sub in test_tup]\n return res", "matching_cluster_idx": 4}, {"solution": "def extract_rear(test_tup):\n # Initialize an empty list to store the last characters\n res = []\n # Iterate through each element in the tuple\n for ele in test_tup:\n # Append the last character of the string to the result list\n res.append(ele[-1])\n # Return the list containing the last characters\n return res", "matching_cluster_idx": 3}, {"solution": "def extract_rear(test_tup):\n # Use list comprehension to iterate over each string in the tuple and get the last character\n res = [sub[-1] for sub in test_tup]\n return res", "matching_cluster_idx": 4}, {"solution": "def extract_rear(test_tup):\n # Extract the last character from each string in the tuple using list comprehension\n res = [sub[-1] for sub in test_tup]\n return res", "matching_cluster_idx": 4}, {"solution": "def extract_rear(test_tup):\n # Use list comprehension to iterate over each string in the tuple\n # and extract the last character using slicing (-1)\n res = [el[-1] for el in test_tup]\n return res", "matching_cluster_idx": 4}, {"solution": "def extract_rear(test_tup):\n # Using list comprehension to iterate through each string in the tuple\n # and extracting the last character (reversed index -1) of each string.\n res = [sub[-1] for sub in test_tup]\n return res", "matching_cluster_idx": 4}, {"solution": "def extract_rear(words):\n # Use a list comprehension to iterate through each word in the tuple\n return [word[-1] for word in words]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(words_tuple):\n # Using list comprehension to iterate over each word in the tuple\n # The [-1] index is used to access the last character of each word\n rear_elements = [word[-1] for word in words_tuple]\n # Returning the list of last characters\n return rear_elements", "matching_cluster_idx": 4}]}, "Mbpp/425": {"dps": 95.7396449704142, "dps_norm": 99.0, "pass@1": 100.0, "profiled": [{"solution": "def count_element_in_list(my_list, element):\n # Initialize a counter to keep track of sublists containing the element\n counter = 0\n \n # Iterate over each sublist in the main list\n for sublist in my_list:\n # Check if the element is in the current sublist\n if element in sublist:\n # If found, increment the counter\n counter += 1\n \n # Return the total count of sublists containing the element\n return counter", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(list1, element):\n # Using the sum function and a list comprehension to count occurrences\n count = sum(1 for sublist in list1 if element in sublist)\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(nums, x):\n # Use the sum function with a generator expression to count occurrences of x in sublists\n count = sum(1 for sublist in nums if x in sublist)\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(list1, x):\n # Initialize a counter to keep track of the number of sublists containing the element x\n count = 0\n # Iterate through each sublist in the main list\n for sublist in list1:\n # Check if the element x is in the current sublist\n if x in sublist:\n # If found, increment the counter\n count += 1\n # Return the total count of sublists containing the element x\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(list1, element):\n count = 0 # Initialize count of sublists containing the element\n # Iterate through each sublist in the main list\n for sublist in list1:\n # Check if the element is in the current sublist\n if element in sublist:\n count += 1 # Increment count if the element is found\n return count # Return the total count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, element):\n # Count elements in the list of lists\n return sum(x.count(element) for x in lst)", "matching_cluster_idx": 3}, {"solution": "def count_element_in_list(test_list, K):\n # Use the sum function to count how many sublists contain the element K\n res = sum(1 for sub in test_list if K in sub)\n return res", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(list1, element):\n # Use the sum function with a generator expression to count sublists containing the element\n return sum(1 for sub_list in list1 if element in sub_list)", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef count_element_in_list(lst: List[List[int]], element: int) -> int:\n # Initialize a counter to keep track of sublists containing the element\n count = 0\n # Iterate through each sublist in the list\n for sublist in lst:\n # Check if the element is in the current sublist\n if element in sublist:\n # Increment the counter if the element is found\n count += 1\n # Return the total count of sublists containing the element\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, n):\n # Initialize a counter to keep track of sublists containing the element\n count = 0\n \n # Iterate through each sublist in the list\n for sublist in lst:\n # Check if the element 'n' is in the current sublist\n if n in sublist:\n # If the element is found, increment the counter\n count += 1\n \n # Return the total count of sublists containing the element\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(test_list, K):\n # Initialize a counter to keep track of sublists containing the element K\n res = 0\n # Iterate over each sublist in the main list\n for sublist in test_list:\n # Check if the element K is in the current sublist\n if K in sublist:\n # Increment the counter if K is found\n res += 1\n # Return the total count of sublists containing the element K\n return res", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lis, x):\n # Initialize a count variable to zero\n count = 0\n \n # Iterate through each sublist in the list\n for sublist in lis:\n # Check if the element x is in the current sublist\n if x in sublist:\n # Increment the count if x is found\n count += 1\n \n # Return the total count of sublists containing the element x\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(list1, element):\n # Using list comprehension to count sublists containing the specific element\n count = sum(1 for sublist in list1 if element in sublist)\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(input_list, element):\n # Use a generator expression to count sublists that contain the specified element\n return sum(1 for sub_list in input_list if element in sub_list)", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, x):\n # Count the number of sublists that contain the element x\n return sum(x in sublist for sublist in lst)", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(input_list, element):\n count = 0\n # Loop through each sublist in the main list\n for sublist in input_list:\n # Check if the element is in the current sublist\n if element in sublist:\n count += 1\n # Return the total count of sublists containing the element\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, x):\n # Use the sum function to count how many sublists contain the element x\n return sum(1 for s in lst if x in s)", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, x):\n # Initialize count to zero\n count = 0\n # Iterate over each sublist in the list\n for sublist in lst:\n # If x is found in the sublist, increment the count\n if x in sublist:\n count += 1\n # Return the total count of sublists containing x\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(input_list, element):\n # Initialize a counter to keep track of sublists containing the element\n counter = 0\n \n # Iterate through each sublist in the input list\n for sublist in input_list:\n # Check if the element is present in the current sublist\n if element in sublist:\n # If the element is found, increment the counter\n counter += 1\n \n # Return the total count of sublists containing the element\n return counter", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(list_of_lists, element):\n # Initialize a counter to keep track of occurrences\n counter = 0\n \n # Iterate through each sublist in the list of lists\n for sublist in list_of_lists:\n # Check if the element is in the current sublist\n if element in sublist:\n # Increment the counter if the element is found\n counter += 1\n \n # Return the total count of sublists containing the element\n return counter", "matching_cluster_idx": 4}]}, "Mbpp/428": {"dps": 84.29752066115702, "dps_norm": 55.55555555555556, "pass@1": 90.0, "profiled": [{"solution": "def shell_sort(arr):\n n = len(arr)\n \n # Start with a big gap, then reduce the gap\n gap = n // 2\n \n # Do a gapped insertion sort for this gap size.\n # The first gap elements arr[0..gap-1] are already in gapped order\n # keep adding one more element until the entire array is gap sorted\n while gap > 0:\n # Do a gapped insertion sort for this gap size.\n # The first gap elements arr[0..gap-1] are already in gapped order\n # keep adding one more element until the entire array is gap sorted\n for i in range(gap, n):\n temp = arr[i]\n \n # shift earlier gap-sorted elements up until the correct location for arr[i] is found\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n \n # put temp (the original arr[i]) in its correct location\n arr[j] = temp\n gap //= 2\n \n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n # Get the length of the array\n n = len(arr)\n \n # Start with a large gap, then reduce the gap\n gap = n // 2\n \n # Perform a gapped insertion sort for this gap size.\n # The first gap elements a[0..gap-1] are already in gapped order\n # keep adding one more element until the entire array is gap sorted\n while gap > 0:\n # Do a gapped insertion sort for this gap size.\n # The first gap elements arr[0..gap-1] are already in gapped order\n # keep adding one more element until the entire array is gap sorted\n for i in range(gap, n):\n # add a[i] to the elements that have been gap sorted\n # save a[i] in temp and make a hole at position i\n temp = arr[i]\n # shift earlier gap-sorted elements up until the correct location for arr[i] is found\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n # put temp (the original a[i]) in its correct location\n arr[j] = temp\n # Reduce the gap for the next element\n gap //= 2\n\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n # Get the length of the array\n n = len(arr)\n # Start with a big gap, then reduce the gap\n gap = n // 2\n \n # Continue until the gap is 0\n while gap > 0:\n # Do a gapped insertion sort for this gap size.\n # The first gap elements arr[0..gap-1] are already in gapped order\n # keep adding one more element until the entire array is gap sorted\n for i in range(gap, n):\n # add arr[i] to the elements that have been gap sorted\n # save arr[i] in temp and make a hole at position i\n temp = arr[i]\n j = i\n # shift earlier gap-sorted elements up until the correct location for arr[i] is found\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n # put temp (the original arr[i]) in its correct location\n arr[j] = temp\n # Reduce the gap for the next element\n gap //= 2\n \n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2\n \n # Continue until the gap is 0\n while gap > 0:\n # Perform a gapped insertion sort\n for i in range(gap, n):\n temp = arr[i]\n j = i\n # Shift earlier gap-sorted elements up until the correct location for arr[i] is found\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n # Put temp (the original arr[i]) in its correct location\n arr[j] = temp\n gap //= 2 # Reduce the gap for the next element\n \n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2\n\n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n\n # Shift earlier gap-sorted elements up until the correct location for arr[i] is found\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n\n # Put temp (the original arr[i]) in its correct location\n arr[j] = temp\n gap //= 2\n\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2 # Start with a large gap, then reduce the gap\n \n # Continue while the gap is greater than 0\n while gap > 0:\n # Perform a gapped insertion sort for this gap size.\n for i in range(gap, n):\n temp = arr[i]\n j = i\n \n # Shift earlier gap-sorted elements up until the correct location for arr[i] is found\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n \n # Put temp (the original arr[i]) in its correct location\n arr[j] = temp\n gap //= 2 # Reduce the gap for the next iteration\n \n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n # Initialize the gap size\n gap = len(arr) // 2\n \n # Continue until the gap is 0\n while gap > 0:\n # Perform a gapped insertion sort for this gap size\n for i in range(gap, len(arr)):\n temp = arr[i]\n j = i\n # Shift earlier gap-sorted elements up until the correct location for arr[i] is found\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n # Put temp (the original arr[i]) in its correct location\n arr[j] = temp\n # Reduce the gap for the next element\n gap //= 2\n \n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n # Get the number of elements in the array\n n = len(arr)\n # Start with a big gap, then reduce the gap\n gap = n // 2\n \n # Keep reducing the gap until it becomes 0\n while gap > 0:\n # Do a gapped insertion sort for this gap size\n for i in range(gap, n):\n # add a[i] to the elements that have been gap sorted\n temp = arr[i]\n j = i\n \n # shift earlier gap-sorted elements up until the correct location for arr[i] is found\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n \n # put temp (the original arr[i]) in its correct location\n arr[j] = temp\n \n # Reduce the gap for the next element\n gap //= 2\n \n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n # Start with a big gap, then reduce the gap\n n = len(arr)\n gap = n // 2\n\n # Do a gapped insertion sort for this gap size.\n # The first gap elements arr[0..gap-1] are already in gapped order\n # keep adding one more element until the entire array is gap sorted\n while gap > 0:\n # Do a gapped insertion sort for this gap size.\n # The first gap elements arr[0..gap-1] are already in gapped order\n # keep adding one more element until the entire array is gap sorted\n for i in range(gap, n):\n # add a[i] to the elements that have been gap sorted\n # save a[i] in temp and make a hole at position i\n temp = arr[i]\n j = i\n\n # shift earlier gap-sorted elements up until the correct location for arr[i] is found\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n\n # put temp (the original a[i]) in its correct location\n arr[j] = temp\n gap //= 2\n\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n n = len(arr)\n # Start with a big gap, then reduce the gap\n gap = n // 2\n \n while gap > 0:\n # Do a gapped insertion sort for this gap size.\n # The first gap elements arr[0..gap-1] are already in gapped order\n # keep adding one more element until the entire array is gap sorted\n for i in range(gap, n):\n temp = arr[i]\n # add arr[i] to the elements that have been gap sorted\n # save arr[i] in temp and make a hole at position i\n j = i\n # shift earlier gap-sorted elements up until the correct location for arr[i] is found\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n # put temp (the original arr[i]) in its correct location\n arr[j] = temp\n # reduce the gap for the next element\n gap //= 2\n \n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n # Start with a big gap, then reduce the gap\n gap = len(arr) // 2\n \n # Do a gapped insertion sort for this gap size.\n # The first gap elements arr[0..gap-1] are already in gapped order\n # keep adding one more element until the entire array is gap sorted\n while gap > 0:\n for i in range(gap, len(arr)):\n # add arr[i] to the elements that have been gap sorted\n # save arr[i] in temp and make a hole at position i\n temp = arr[i]\n # shift earlier gap-sorted elements up until the correct location for arr[i] is found\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n # put temp (the original arr[i]) in its correct location\n arr[j] = temp\n gap //= 2 # Reduce the gap for the next element\n \n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n # Start with a big gap, then reduce the gap\n gap = len(arr) // 2\n \n # Keep reducing the gap until it becomes 0\n while gap > 0:\n # Do a gapped insertion sort for this gap size\n for i in range(gap, len(arr)):\n temp = arr[i]\n j = i\n \n # Shift earlier gap-sorted elements up until the correct location for arr[i] is found\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n \n # Put temp (the original arr[i]) in its correct location\n arr[j] = temp\n \n # Reduce the gap for the next element\n gap //= 2\n \n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2\n \n # Continue with the gap until it becomes 0\n while gap > 0:\n # Perform a gapped insertion sort\n for i in range(gap, n):\n temp = arr[i]\n j = i\n # Shift earlier gap-sorted elements up until the correct location for arr[i] is found\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n # Put temp (the original arr[i]) in its correct location\n arr[j] = temp\n gap //= 2 # Reduce the gap for the next element\n \n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n # Get the length of the array\n n = len(arr)\n gap = n // 2\n \n # Continue until the gap is 0\n while gap > 0:\n # Perform insertion sort for this gap size\n for i in range(gap, n):\n temp = arr[i]\n j = i\n \n # Shift earlier gap-sorted elements up until the correct location for arr[i] is found\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n \n # Put temp (the original arr[i]) in its correct location\n arr[j] = temp\n \n # Reduce the gap for the next element\n gap //= 2\n \n # Return the sorted array\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n # Start with a big gap, then reduce the gap\n n = len(arr)\n gap = n // 2\n \n # Do a gapped insertion sort for this gap size.\n # The first gap elements arr[0..gap-1] are already in gapped order\n # keep adding one more element until the entire array is gap sorted\n while gap > 0:\n for i in range(gap, n):\n # add arr[i] to the elements that have been gap sorted\n # save arr[i] in temp and make a hole at position i\n temp = arr[i]\n # shift earlier gap-sorted elements up until the correct location for arr[i] is found\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n \n # put temp (the original arr[i]) in its correct location\n arr[j] = temp\n \n # reduce the gap for the next element\n gap //= 2\n \n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n # Start with a big gap, then reduce the gap\n n = len(arr)\n gap = n // 2\n \n # Keep reducing the gap until it becomes 0\n while gap > 0:\n # Do a gapped insertion sort for this gap size.\n # The first gap elements arr[0..gap-1] are already in gapped order\n # keep adding one more element until the entire array is gap sorted\n for i in range(gap, n):\n temp = arr[i]\n j = i\n # shift earlier gap-sorted elements up until the correct location for arr[i] is found\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n # put temp (the original arr[i]) in its correct location\n arr[j] = temp\n gap //= 2\n \n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n # Calculate the initial gap size\n gap = len(arr) // 2\n \n # Continue until the gap is 0\n while gap > 0:\n # Perform a gapped insertion sort for this gap size\n for i in range(gap, len(arr)):\n temp = arr[i]\n j = i\n \n # Shift earlier gap-sorted elements up until the correct location for arr[i] is found\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n \n # Put temp (the original arr[i]) in its correct location\n arr[j] = temp\n \n # Reduce the gap for the next round\n gap //= 2\n \n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n # Start with a big gap, then reduce the gap\n n = len(arr)\n gap = n // 2\n\n # Do a gapped insertion sort for this gap size.\n # The first gap elements arr[0..gap-1] are already in gapped order\n # keep adding one more element until the entire array is gap sorted\n while gap > 0:\n # Do a gapped insertion sort for this gap size.\n # The first gap elements arr[0..gap-1] are already in gapped order\n # keep adding one more element until the entire array is gap sorted\n for i in range(gap, n):\n # add arr[i] to the elements that have been gap sorted\n # save arr[i] in temp and make a hole at position i\n temp = arr[i]\n\n # shift earlier gap-sorted elements up until the correct location for arr[i] is found\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n\n # put temp (the original arr[i]) in its correct location\n arr[j] = temp\n gap //= 2\n\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2\n \n # Start with a big gap, then reduce the gap\n while gap > 0:\n # Do a gapped insertion sort for this gap size.\n # The first gap elements arr[0..gap-1] are already in gapped order\n # keep adding one more element until the entire array is gap sorted\n for i in range(gap, n):\n temp = arr[i]\n j = i\n \n # shift earlier gap-sorted elements up until the correct location for arr[i] is found\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n \n # put temp (the original arr[i]) in its correct location\n arr[j] = temp\n gap //= 2 # Reduce the gap for the next element\n \n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2\n\n # Continue until the gap is 0\n while gap > 0:\n # Perform a gapped insertion sort\n for i in range(gap, n):\n temp = arr[i]\n j = i\n # Shift earlier gap-sorted elements up until the correct location for arr[i] is found\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n # Put temp (the original arr[i]) in its correct location\n arr[j] = temp\n gap //= 2 # Reduce the gap for the next element\n\n return arr", "matching_cluster_idx": 4}]}, "Mbpp/433": {"dps": 68.33060556464811, "dps_norm": 73.84615384615384, "pass@1": 13.0, "profiled": [{"solution": "def check_greater(arr, x):\n # Iterate through each element in the array\n for i in arr:\n # If the element is greater than or equal to x, return False\n if i >= x:\n return False\n # If no element is greater than or equal to x, return True\n return True", "matching_cluster_idx": 4}, {"solution": "def check_greater(arr, x):\n # Use a generator expression to check if x is greater than all elements in arr\n return all(x > element for element in arr)", "matching_cluster_idx": 2}, {"solution": "def check_greater(arr, N):\n # Iterate through each element in the array\n for i in arr:\n # Check if the current element is greater than or equal to N\n if i >= N:\n return False\n # If no element is greater than or equal to N, return True\n return True", "matching_cluster_idx": 4}, {"solution": "def check_greater(nums, k):\n # Check if all elements in the array are less than the given number k\n result = all([k > num for num in nums])\n return result", "matching_cluster_idx": 3}, {"solution": "def check_greater(arr, num):\n # Return True if the maximum element in the array is less than num, else False\n return all(x < num for x in arr)", "matching_cluster_idx": 2}, {"solution": "def check_greater(array, target):\n # Iterate through each element in the array\n for i in range(len(array)):\n # Check if the target is less than or equal to the current element\n if target <= array[i]:\n # Return False if the target is not greater than the current element\n return False\n # Return True if the target is greater than all elements in the array\n return True", "matching_cluster_idx": 1}, {"solution": "def check_greater(arr, x):\n # Loop through each element in the array\n for i in range(len(arr)):\n # Check if the element is greater than or equal to x\n if arr[i] >= x:\n # Return False if any element is greater than or equal to x\n return False\n # Return True if no element is greater than or equal to x\n return True", "matching_cluster_idx": 1}, {"solution": "def check_greater(test_list, K):\n # Loop through each element in the list\n for ele in test_list:\n # Check if the current element is greater than or equal to K\n if ele >= K:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def check_greater(arr, num):\n # Iterate through each element in the array\n for x in arr:\n # If the current element is greater than or equal to the number, return False\n if x >= num:\n return False\n # If no element is greater than the number, return True\n return True", "matching_cluster_idx": 4}, {"solution": "def check_greater(arr, n):\n # Check if the number n is greater than all elements in the array arr\n return all(x < n for x in arr)", "matching_cluster_idx": 2}, {"solution": "def check_greater(arr, n):\n # Iterate through the array\n for i in arr:\n # Check if the number n is less than or equal to any element in the array\n if n <= i:\n return False\n # If the number n is greater than all elements in the array, return True\n return True", "matching_cluster_idx": 4}, {"solution": "def check_greater(array, number):\n # Check if all elements in the array are less than the number\n result = all(number > n for n in array)\n return result", "matching_cluster_idx": 2}, {"solution": "def check_greater(arr, key):\n # Check if the key is greater than all elements in the array\n if all(key > ele for ele in arr):\n return True\n # If the key is not greater than all elements, return False\n else:\n return False", "matching_cluster_idx": 2}]}, "Mbpp/437": {"dps": 69.26470588235294, "dps_norm": 24.0, "pass@1": 38.0, "profiled": [{"solution": "def remove_odd(s):\n # Initialize an empty string to store the result\n res = ''\n \n # Iterate over each character in the string, starting from index 1\n for i in range(1, len(s) + 1):\n # If the index is even (considering 1-based indexing), append the character to the result\n if i % 2 == 0:\n res += s[i-1]\n \n # Return the result string\n return res", "matching_cluster_idx": 0}, {"solution": "def remove_odd(s):\n # Initialize an empty list to store even-indexed characters\n res = []\n \n # Iterate over the string, considering the index\n for i in range(len(s)):\n # Check if the index is even (i.e., character is at an even position)\n if i % 2 == 1:\n # Append the character at the even index to the result list\n res.append(s[i])\n \n # Join the list of characters into a string and return it\n return ''.join(res)", "matching_cluster_idx": 0}, {"solution": "def remove_odd(s):\n # Use list comprehension to select characters at even indices (0, 2, 4, ...)\n return ''.join([s[i] for i in range(len(s)) if i % 2 == 1])", "matching_cluster_idx": 1}, {"solution": "def remove_odd(str):\n # Filter out characters at even indices (odd positions) using list comprehension\n return ''.join(str[i] for i in range(len(str)) if i % 2 != 0)", "matching_cluster_idx": 0}, {"solution": "def remove_odd(S):\n # Initialize an empty string to store the result\n result = \"\"\n \n # Iterate over the string using its index\n for i in range(len(S)):\n # Check if the index is even (odd characters in 1-based indexing)\n if i % 2 != 0:\n # Append the character at the even index to the result string\n result += S[i]\n \n # Return the result string which contains only the even-indexed characters\n return result", "matching_cluster_idx": 0}, {"solution": "def remove_odd(test_str):\n # Use list comprehension to filter out odd positioned characters (1-based index)\n # and join the characters to form the new string\n res = ''.join([test_str[i] for i in range(len(test_str)) if (i + 1) % 2 == 0])\n return res", "matching_cluster_idx": 0}, {"solution": "def remove_odd(s):\n # Use list comprehension to filter out characters at odd indices\n return \"\".join([ch for idx, ch in enumerate(s) if idx % 2 != 0])", "matching_cluster_idx": 0}, {"solution": "def remove_odd(s):\n # Use a list comprehension to filter out characters at even indices\n # Starting from index 1 to remove characters at odd positions (1-based indexing)\n return ''.join([s[i] for i in range(len(s)) if i % 2 != 0])", "matching_cluster_idx": 0}, {"solution": "def remove_odd(str1):\n # Initialize an empty string to store even-indexed characters\n result = \"\"\n # Loop through the string, starting from index 1 to remove odd characters\n for i in range(1, len(str1) + 1):\n if i % 2 == 0:\n result += str1[i - 1]\n return result", "matching_cluster_idx": 0}, {"solution": "def remove_odd(input_string):\n # Initialize an empty string to store the result\n result = \"\"\n \n # Iterate through the string using enumerate to get both index and character\n for i, char in enumerate(input_string):\n # Check if the index is even (since Python uses 0-based indexing, even index means odd position)\n if i % 2 == 1:\n # Append the character at the even index to the result string\n result += char\n \n # Return the result string with odd characters removed\n return result", "matching_cluster_idx": 0}, {"solution": "def remove_odd(s):\n # Filter out odd-indexed characters and join the result\n return ''.join(c for i, c in enumerate(s) if i % 2 == 1)", "matching_cluster_idx": 0}, {"solution": "def remove_odd(test_str):\n # Using a list comprehension to filter out odd-indexed characters (even positions)\n res = ''.join([char for idx, char in enumerate(test_str) if idx % 2 == 1])\n return res", "matching_cluster_idx": 0}, {"solution": "def remove_odd(s):\n \"\"\"\n Remove odd characters from a string, considering index-based parity (1-indexed).\n \n Args:\n s (str): The input string from which odd characters will be removed.\n \n Returns:\n str: A new string containing only the characters at even indices of the original string.\n \"\"\"\n # Initialize an empty string to store the result\n result = \"\"\n \n # Iterate over the string using an index\n for i in range(len(s)):\n # Check if the character is at an even index (considering 0-indexing)\n if (i + 1) % 2 == 0:\n # Append the character to the result string\n result += s[i]\n \n # Return the result string\n return result", "matching_cluster_idx": -1}, {"solution": "def remove_odd(input_string):\n # Initialize an empty string to store the result\n result = ''\n \n # Iterate over the input string using an index\n for i in range(len(input_string)):\n # Check if the current index is even\n if i % 2 == 1:\n # Append the character at the current index to the result string\n result += input_string[i]\n \n # Return the result string\n return result", "matching_cluster_idx": 0}, {"solution": "def remove_odd(s):\n # Initialize an empty string to store the result\n res = \"\"\n \n # Iterate over the string using enumerate to get both index and character\n for i, j in enumerate(s):\n # Check if the index is even (i.e., the character is at an odd position)\n if i % 2 != 0:\n # Append the character to the result string\n res += j\n \n # Return the result string with characters at odd positions removed\n return res", "matching_cluster_idx": 0}, {"solution": "def remove_odd(s):\n # Initialize an empty string to store the result\n result = \"\"\n # Iterate over the string with index\n for i in range(len(s)):\n # Check if the index is even (since indices are 0-based, even indices represent odd characters in the problem statement)\n if i % 2 == 1:\n # Append the character at the even index to the result string\n result += s[i]\n # Return the result string\n return result", "matching_cluster_idx": 0}, {"solution": "def remove_odd(my_string):\n # Use list comprehension to filter out odd indexed characters\n result = [my_string[i] for i in range(len(my_string)) if i % 2 == 1]\n # Join the list back into a string\n return ''.join(result)", "matching_cluster_idx": 1}, {"solution": "def remove_odd(S):\n # Initialize an empty string to store the result\n output = ''\n # Iterate over the string using enumerate to get both index and character\n for i, s in enumerate(S):\n # Check if the index is even (odd character positions in human terms)\n if i % 2 != 0:\n # Append the character at even index to the result string\n output += s\n return output", "matching_cluster_idx": 0}, {"solution": "def remove_odd(input_string):\n # Initialize an empty list to store even-indexed characters\n output_list = []\n \n # Iterate over the string, starting from index 1 to ignore the first character\n for index in range(1, len(input_string), 2):\n # Append the character at the current index to the output list\n output_list.append(input_string[index])\n \n # Join the list into a string and return it\n return ''.join(output_list)", "matching_cluster_idx": 2}, {"solution": "def remove_odd(s):\n # Use list comprehension to filter out characters at odd indices\n return \"\".join([s[i] for i in range(len(s)) if i % 2 == 1])", "matching_cluster_idx": 1}]}, "Mbpp/440": {"dps": 88.63636363636364, "dps_norm": 91.25, "pass@1": 57.0, "profiled": [{"solution": "import re\ndef find_adverb_position(text):\n # Use regex to find the first occurrence of an adverb and its position\n match = re.search(r\"\\w+ly\", text)\n if match:\n # Return the start position, end position, and the matched adverb\n return (match.start(), match.end(), match.group(0))\n else:\n # Return None if no adverb is found\n return None", "matching_cluster_idx": 3}, {"solution": "import re\ndef find_adverb_position(sentence):\n # Use regular expression to find all occurrences of words ending with 'ly'\n adverbs = re.findall(r\"\\w+ly\", sentence)\n # Iterate over the adverbs found\n for adverb in adverbs:\n # Find the starting and ending positions of the adverb in the sentence\n start_pos = sentence.find(adverb)\n end_pos = start_pos + len(adverb)\n # Return the positions and the adverb itself\n return (start_pos, end_pos, adverb)", "matching_cluster_idx": 1}, {"solution": "def find_adverb_position(text):\n # Using regular expression to find all occurrences of adverbs\n import re\n adverbs = re.findall(r\"\\w+ly\", text)\n \n # Check if there are adverbs in the text\n if not adverbs:\n return None\n else:\n # Iterate through each adverb found\n for adverb in adverbs:\n # Find the starting position of the adverb in the text\n start = text.find(adverb)\n # Find the ending position of the adverb in the text\n end = start + len(adverb)\n # Return the starting, ending positions, and the adverb itself\n return (start, end, adverb)", "matching_cluster_idx": 1}, {"solution": "import re\ndef find_adverb_position(string):\n # Use regular expression to find the first occurrence of an adverb and its position\n for m in re.finditer(r\"\\w+ly\", string):\n # Return the start and end positions, along with the adverb itself\n return (m.start(), m.end(), m.group(0))", "matching_cluster_idx": 3}, {"solution": "import re\ndef find_adverb_position(string):\n # Use regular expression to find adverbs ending in 'ly'\n for match in re.finditer(r\"\\w+ly\", string):\n # Return the start and end positions along with the matched adverb\n return (match.start(), match.end(), match.group(0))", "matching_cluster_idx": 3}, {"solution": "def find_adverb_position(text):\n # Find the position of the first adverb using regular expression\n import re\n pos = re.search(r\"\\w+ly\", text)\n \n # If an adverb is found, return its start, end positions, and the adverb itself\n if pos:\n return (pos.start(), pos.end(), pos.group(0))\n else:\n # Return None if no adverb is found\n return None", "matching_cluster_idx": 3}, {"solution": "def find_adverb_position(text):\n # Import the regex module to work with regular expressions\n import re\n \n # Use regex to search for words ending with 'ly', which are adverbs\n for match in re.finditer(r\"\\w+ly\", text):\n # Return the start and end positions, along with the matched adverb\n return (match.start(), match.end(), match.group(0))", "matching_cluster_idx": 3}, {"solution": "import re\ndef find_adverb_position(text):\n # Use regular expression to find all occurrences of adverbs and their starting and ending positions\n results = re.finditer(r\"\\w+ly\", text)\n # Check if any adverb is found\n if results is not None:\n # Iterate over all matches found\n for result in results:\n # Return the start position, end position, and the adverb itself\n return result.start(), result.end(), result.group(0)\n # Return None if no adverb is found\n return None", "matching_cluster_idx": 3}, {"solution": "import re\ndef find_adverb_position(sentence):\n # Define a regex pattern to match adverbs\n pattern = r\"\\w+ly\"\n # Search for the pattern in the sentence\n match = re.search(pattern, sentence)\n \n if match:\n # If a match is found, return the start position, end position, and the adverb itself\n return (match.start(), match.end(), match.group(0))\n else:\n # If no match is found, return None\n return None", "matching_cluster_idx": 3}, {"solution": "import re\ndef find_adverb_position(string):\n # Regular expression pattern to match words ending in 'ly'\n pattern = r\"([a-z]+ly)\"\n # Search for the first occurrence of the pattern\n for m in re.finditer(pattern, string):\n # Return the start and end positions of the match, along with the matched word\n return (m.start(), m.end(), m.group(0))", "matching_cluster_idx": 3}, {"solution": "import re\ndef find_adverb_position(sentence):\n # Define a regular expression pattern to match words ending in 'ly'\n pattern = r\"\\w+ly\"\n \n # Use re.search to find the first occurrence that matches the pattern\n match = re.search(pattern, sentence)\n \n if match:\n # If a match is found, return the starting position, ending position, and the adverb itself\n return (match.start(), match.end(), match.group(0))", "matching_cluster_idx": 3}, {"solution": "import re\ndef find_adverb_position(s):\n # Use regular expression to find all occurrences of words ending with 'ly'\n for match in re.finditer(r\"\\w+ly\", s):\n # Return the start and end positions, and the matched adverb\n return (match.start(), match.end(), match.group(0))", "matching_cluster_idx": 3}, {"solution": "import re\ndef find_adverb_position(string):\n # Use regular expression to find adverbs and their positions\n for match in re.finditer(r\"\\w+ly\", string):\n # Return the start and end positions, along with the adverb\n return (match.start(), match.end(), match.group(0))", "matching_cluster_idx": 3}, {"solution": "import re\ndef find_adverb_position(sentence):\n # Define a regular expression pattern to find adverbs\n pattern = r\"\\w+ly\"\n # Find all matches of the pattern in the sentence\n adverbs = re.findall(pattern, sentence)\n \n # If there are no adverbs, return None\n if not adverbs:\n return None\n \n # Define another regular expression pattern to find the exact position of the first adverb\n loc_pattern = re.compile(r\"\\w+ly\")\n # Search for the first occurrence of the adverb pattern\n location = loc_pattern.search(sentence)\n \n # Return a tuple with the start and end positions, and the found adverb\n return (location.start(), location.end(), location.group(0))", "matching_cluster_idx": 0}, {"solution": "import re\ndef find_adverb_position(sentence):\n # Regular expression to find adverbs and their start position\n for match in re.finditer(r\"\\w+ly\", sentence):\n # Return the start and end positions along with the adverb found\n return match.start(), match.end(), match.group(0)", "matching_cluster_idx": 3}, {"solution": "def find_adverb_position(text):\n # Use regular expression to find words ending with 'ly'\n import re\n match = re.search(r\"\\w+ly\", text)\n if match:\n # If a match is found, return start and end positions along with the adverb\n return (match.start(), match.end(), match.group(0))", "matching_cluster_idx": 3}, {"solution": "import re\ndef find_adverb_position(sentence):\n # Using regular expression to find the first adverb and its position\n match = re.search(r\"\\w+ly\", sentence)\n if match:\n # Returning the start, end position and the adverb itself\n return (match.start(), match.end(), match.group(0))\n else:\n # Returning None if no adverb is found\n return None", "matching_cluster_idx": 3}, {"solution": "import re\ndef find_adverb_position(string):\n # Using regular expression to find the first adverb and its position\n adverb = re.search(r\"\\w+ly\", string)\n \n if adverb:\n # Extracting the starting index and the adverb itself\n s = adverb.start()\n e = adverb.end()\n return (s, e, adverb.group(0))\n else:\n return None", "matching_cluster_idx": 3}, {"solution": "import re\ndef find_adverb_position(text):\n # Use regular expression to find adverbs and their start and end positions\n for position in re.finditer(r\"\\w+ly\", text):\n # Return the start and end position, along with the matched adverb\n return (position.start(), position.end(), position.group(0))", "matching_cluster_idx": 3}, {"solution": "import re\ndef find_adverb_position(text):\n # Use regular expression to find all occurrences of adverbs ending in 'ly'\n match = re.search(r\"\\w+ly\", text)\n \n # If a match is found, return the start and end positions along with the adverb\n if match:\n return (match.start(), match.end(), match.group(0))", "matching_cluster_idx": 3}]}, "Mbpp/446": {"dps": 92.66009852216749, "dps_norm": 69.0, "pass@1": 22.0, "profiled": [{"solution": "from collections import Counter\ndef count_Occurrence(test_tup, K):\n # Count occurrences of each element in the tuple\n count = Counter(test_tup)\n \n # Initialize result to 0\n res = 0\n \n # Iterate through each element in the provided list K\n for ele in K:\n # Add the count of each element in K to the result\n res += count[ele]\n \n return res", "matching_cluster_idx": 4}, {"solution": "def count_Occurrence(test_tup, K):\n # Initialize a counter variable to store the total count\n res = 0\n \n # Iterate over each element in the list\n for ele in K:\n # Count the occurrences of the element in the tuple and add to the result\n res += test_tup.count(ele)\n \n # Return the total count of occurrences\n return res", "matching_cluster_idx": 2}, {"solution": "from typing import List, Tuple\ndef count_Occurrence(test_tup: Tuple[str], K: List[str]) -> int:\n # Use list comprehension and the count method to sum occurrences\n res = sum(test_tup.count(ele) for ele in K)\n return res", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(test_tup, K):\n # Convert the tuple into a list to enable counting\n res = [i.count(j) for i, j in zip([test_tup] * len(K), K)]\n \n # Sum up the counts and return the result\n return sum(res)", "matching_cluster_idx": 2}, {"solution": "from collections import defaultdict\ndef count_Occurrence(test_tup, K):\n # Initialize a defaultdict to count occurrences of each element in the list\n res = defaultdict(int)\n \n # Count occurrences of each element in the tuple\n for ele in test_tup:\n res[ele] += 1\n \n # Sum the occurrences of elements present in the list K\n res = sum(res[ele] for ele in K if ele in res)\n \n return res", "matching_cluster_idx": 4}, {"solution": "def count_Occurrence(test_tup, K):\n # Count occurrences of elements in the tuple that are present in the list\n res = sum(test_tup.count(ele) for ele in K)\n return res", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(test_tup, K):\n # Count occurrences using sum and generator expression\n res = sum(test_tup.count(ele) for ele in K)\n return res", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tuple, list):\n # Initialize a counter to zero\n counter = 0\n \n # Loop through each element in the list\n for ele in list:\n # If the element is in the tuple, increment the counter by the count of that element in the tuple\n counter += tuple.count(ele)\n \n # Return the total count\n return counter", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(test_tup, K):\n # Initialize result to 0\n res = 0\n # Iterate through each element in the list K\n for ele in K:\n # Count occurrences of each element in the tuple test_tup\n res += test_tup.count(ele)\n return res", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tuple1, list1):\n count = 0 # Initialize a counter to keep track of occurrences\n for x in tuple1: # Iterate through each element in the tuple\n for y in list1: # Iterate through each element in the list\n if x == y: # Check if the current element in the tuple matches the current element in the list\n count += 1 # Increment the counter if there is a match\n return count # Return the total count of occurrences", "matching_cluster_idx": 1}, {"solution": "def count_Occurrence(test_tup, K):\n # Count each element in the tuple\n res = sum(test_tup.count(ele) for ele in K)\n return res", "matching_cluster_idx": 2}, {"solution": "from collections import Counter\ndef count_Occurrence(given_tuple, list_values):\n # Count the occurrences of each element in the tuple using Counter\n frequency = Counter(given_tuple)\n \n # Initialize a variable to accumulate the total occurrences\n result = 0\n \n # Iterate through each value in the list and add its frequency to the result\n for value in list_values:\n result += frequency[value]\n \n # Return the total count of occurrences\n return result", "matching_cluster_idx": 4}, {"solution": "def count_Occurrence(test_tup, K):\n # Use a dictionary comprehension to count occurrences of each element in the tuple\n res = sum(test_tup.count(ele) for ele in K)\n return res", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(test_tup, K):\n # Using sum() to count occurrences of elements in list K within tuple test_tup\n res = sum(test_tup.count(ele) for ele in K)\n return res", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(test_tup, K):\n # Count occurrences of each element in the tuple\n res = sum(test_tup.count(ele) for ele in K)\n return res", "matching_cluster_idx": 2}, {"solution": "from collections import Counter\ndef count_Occurrence(test_tup, K):\n # Using Counter to count occurrences of each element in the tuple\n res = sum([test_tup.count(ele) for ele in K])\n return res", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(test_tup, K):\n # Initialize counter for occurrences\n res = 0\n # Iterate through each element in the list\n for ele in K:\n # Count occurrences of each element in the tuple\n res += test_tup.count(ele)\n return res", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(test_tup, K):\n # Count the total occurrence of elements from K in test_tup\n res = sum(test_tup.count(ele) for ele in K)\n return res", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(test_tup, K):\n # Initialize result dictionary\n res = dict()\n \n # Iterate over the tuple and count occurrences of each element\n for ele in test_tup:\n if ele in res:\n res[ele] += 1\n else:\n res[ele] = 1\n \n # Count the occurrences of the specified elements in K\n count = 0\n for ele in K:\n if ele in res:\n count += res[ele]\n \n return count", "matching_cluster_idx": 4}, {"solution": "from collections import Counter\ndef count_Occurrence(given_tuple, elements):\n # Initialize a counter with the given_tuple\n counter = Counter(given_tuple)\n \n # Initialize count to 0\n count = 0\n \n # Iterate through each element in the elements list\n for ele in elements:\n # If the element is in the counter, add its count to the total count\n if ele in counter:\n count += counter[ele]\n \n # Return the total count of specified elements\n return count", "matching_cluster_idx": 4}]}, "Mbpp/451": {"dps": 74.91525423728814, "dps_norm": 85.0, "pass@1": 60.0, "profiled": [{"solution": "def remove_whitespaces(s):\n # Use the join method to concatenate characters, excluding whitespaces\n return ''.join(char for char in s if char != ' ')", "matching_cluster_idx": 2}, {"solution": "def remove_whitespaces(s):\n # Replace all whitespace characters in the string with an empty string\n return s.replace(' ', '')", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(str1):\n # Remove all whitespaces from the given string using str.replace()\n str2 = str1.replace(' ', '')\n return str2", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input):\n # Initialize an empty string to store the result\n res = \"\"\n # Iterate through each character in the input string\n for i in input:\n # Check if the character is not a whitespace\n if i != \" \":\n # Append the character to the result string\n res += i\n # Return the result string with all whitespaces removed\n return res", "matching_cluster_idx": 2}, {"solution": "def remove_whitespaces(s):\n # Replace all white spaces with an empty string\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(s):\n # Replace all whitespace characters in the string with an empty string\n s = s.replace(\" \", \"\")\n return s", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(string):\n # Replace all whitespace characters in the string with an empty string\n return string.replace(' ', '')", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_str):\n # Remove all whitespaces from the input string\n input_str = input_str.replace(\" \", \"\")\n return input_str", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(string):\n # Initialize an empty string to store the result\n res = \"\"\n # Iterate through each character in the input string\n for ch in string:\n # Check if the character is not a whitespace\n if ch != ' ':\n # Append the character to the result string\n res += ch\n # Return the result string without whitespaces\n return res", "matching_cluster_idx": 2}, {"solution": "def remove_whitespaces(text):\n # Initialize an empty string to store the result\n res = ''\n # Iterate through each character in the input string\n for i in range(len(text)):\n # Check if the current character is not a whitespace\n if text[i] != ' ':\n # Append non-whitespace characters to the result string\n res += text[i]\n # Return the resulting string without any whitespaces\n return res", "matching_cluster_idx": 1}, {"solution": "def remove_whitespaces(test_str):\n # Replace all whitespace characters (spaces, tabs, newlines) with an empty string\n res = test_str.replace(\" \", \"\")\n return res", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_str):\n # Using the translate method with str.maketrans to remove all whitespaces\n return input_str.translate(str.maketrans('', '', ' '))", "matching_cluster_idx": 3}, {"solution": "def remove_whitespaces(str):\n # Use the translate method with str.maketrans to remove all whitespaces\n result = str.translate(str.maketrans('', '', ' ')) \n return result", "matching_cluster_idx": 3}, {"solution": "def remove_whitespaces(str1):\n # Use the join method to concatenate characters that are not whitespace\n return \"\".join(char for char in str1 if char != \" \")", "matching_cluster_idx": 2}, {"solution": "def remove_whitespaces(test_str):\n # Using the replace method to remove all whitespaces from the string\n res = test_str.replace(\" \", \"\")\n return res", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(s):\n # Use the replace method to remove all whitespace characters from the string\n s = s.replace(' ', '')\n return s", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(string):\n # The replace method is used to substitute all occurrences of whitespace\n # with an empty string, effectively removing them\n return string.replace(' ', '')", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(str1):\n # Use the replace method to remove all whitespaces from the string\n result = str1.replace(\" \", \"\")\n return result", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string):\n # Join all characters in the string except for whitespace\n return ''.join([char for char in input_string if char != ' '])", "matching_cluster_idx": 2}, {"solution": "def remove_whitespaces(test_str):\n # Remove all whitespaces from the input string using string's replace method\n res = test_str.replace(\" \", \"\")\n return res", "matching_cluster_idx": 4}]}, "Mbpp/456": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def reverse_string_list(test_list):\n # Using list comprehension to reverse each string in the list\n res = [word[::-1] for word in test_list]\n return res", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(test_list):\n # Using list comprehension to reverse each string in the list\n res = [i[::-1] for i in test_list]\n return res", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(str_list):\n # Using list comprehension to reverse each string in the list\n reversed_list = [s[::-1] for s in str_list]\n return reversed_list", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(test_list):\n # Using list comprehension to reverse each string using slicing\n res = [ele[::-1] for ele in test_list]\n return res", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(color_list):\n # Using list comprehension to reverse each string in the list\n return [i[::-1] for i in color_list]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(colors):\n # Using list comprehension and slicing to reverse each string in the list\n result = [i[::-1] for i in colors]\n return result", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(color_list):\n # Reverse each string in the list using list comprehension\n reversed_list = [i[::-1] for i in color_list]\n return reversed_list", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(lst):\n # Using list comprehension to reverse each string in the list\n return [i[::-1] for i in lst]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n # Using list comprehension to reverse each string in the list\n reverse_list = [s[::-1] for s in string_list]\n return reverse_list", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string):\n # Use list comprehension to reverse each string in the list\n reversed_strings = [i[::-1] for i in string]\n return reversed_strings", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n # Use list comprehension to reverse each string in the list\n result = [string[::-1] for string in string_list]\n return result", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(colors):\n # Reverse each string in the list using list comprehension\n result = [i[::-1] for i in colors]\n return result", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n # Use list comprehension to reverse each string in the list\n return [s[::-1] for s in string_list]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n # Reverse each string in the list using list comprehension\n result = [word[::-1] for word in string_list]\n return result", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(colors):\n # Reverse each string in the list using list comprehension\n return [x[::-1] for x in colors]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(stringList):\n # Reverse each string in the list using a list comprehension\n reversed_list = [item[::-1] for item in stringList]\n return reversed_list", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(str_list):\n # Reverse each string in the list using list comprehension and slicing\n reversed_list = [i[::-1] for i in str_list]\n return reversed_list", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n # Initialize an empty list to store reversed strings\n reversed_list = []\n \n # Iterate through each string in the input list\n for s in string_list:\n # Reverse the string and append to the reversed_list\n reversed_list.append(s[::-1])\n \n # Return the list of reversed strings\n return reversed_list", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(colors):\n # Using list comprehension to reverse each string in the list\n return [i[::-1] for i in colors]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n # Reverse each string in the list using list comprehension and slicing\n reversed_strings = [s[::-1] for s in string_list]\n return reversed_strings", "matching_cluster_idx": 4}]}, "Mbpp/460": {"dps": 66.25, "dps_norm": 87.0, "pass@1": 100.0, "profiled": [{"solution": "def Extract(lst):\n # Use a list comprehension to iterate through each sublist\n # and extract the first element using the index [0]\n return [element[0] for element in lst]", "matching_cluster_idx": 4}, {"solution": "def Extract(lst):\n # Use list comprehension to iterate over each sublist and extract the first element\n return [sublist[0] for sublist in lst]", "matching_cluster_idx": 4}, {"solution": "def Extract(lst):\n # Use a list comprehension to iterate through each sublist\n # and extract the first element using index 0\n return [ele[0] for ele in lst]", "matching_cluster_idx": 4}, {"solution": "def Extract(test_list):\n # Use list comprehension to iterate over each sublist in the main list\n # and extract the first element of each sublist\n res = [sublist[0] for sublist in test_list]\n return res", "matching_cluster_idx": 4}, {"solution": "def Extract(test_list):\n # Using list comprehension to iterate through each sublist and extract the first element\n res = [sublist[0] for sublist in test_list]\n return res", "matching_cluster_idx": 3}, {"solution": "def Extract(test_list):\n # Using list comprehension to iterate through each sublist and get the first element\n res = [sublist[0] for sublist in test_list]\n return res", "matching_cluster_idx": 3}, {"solution": "def Extract(list):\n # Use a list comprehension to iterate over each sublist and extract the first element\n result = [sublist[0] for sublist in list]\n return result", "matching_cluster_idx": 3}, {"solution": "def Extract(lst):\n # Use list comprehension to iterate through each sublist and extract the first element\n res = [sublist[0] for sublist in lst]\n # Return the list of first elements\n return res", "matching_cluster_idx": 3}, {"solution": "def Extract(lst):\n # Use list comprehension to extract the first element from each sublist\n return [sublist[0] for sublist in lst]", "matching_cluster_idx": 4}, {"solution": "def Extract(test_list):\n # Using list comprehension to extract the first element from each sublist\n res = [sublist[0] for sublist in test_list]\n return res", "matching_cluster_idx": 3}, {"solution": "def Extract(lists):\n # Using list comprehension to extract the first element from each sublist\n res = [sublist[0] for sublist in lists]\n return res", "matching_cluster_idx": 4}, {"solution": "def Extract(lst):\n # Using list comprehension to extract the first element from each sublist\n return [sublist[0] for sublist in lst]", "matching_cluster_idx": 4}, {"solution": "def Extract(test_list):\n # Using list comprehension to iterate through each sublist\n # and extracting the first element using indexing\n res = [sublist[0] for sublist in test_list]\n return res", "matching_cluster_idx": 3}, {"solution": "def Extract(lst):\n # Using list comprehension to iterate through each sublist and extract the first element\n first_elements = [sublist[0] for sublist in lst]\n return first_elements", "matching_cluster_idx": 3}, {"solution": "def Extract(lst):\n # Using list comprehension to iterate through each sublist and extract the first element\n res = [i[0] for i in lst]\n return res", "matching_cluster_idx": 3}, {"solution": "def Extract(lst):\n # Use list comprehension to iterate through each sublist\n # and extract the first element\n res = [sublist[0] for sublist in lst]\n return res", "matching_cluster_idx": 3}, {"solution": "def Extract(lst):\n # Extract the first element of each sublist using list comprehension\n res = [x[0] for x in lst]\n return res", "matching_cluster_idx": 3}, {"solution": "def Extract(lst):\n # Use list comprehension to iterate through each sublist in the input list\n # and extract the first element (index 0) of each sublist\n result = [sublist[0] for sublist in lst]\n return result", "matching_cluster_idx": 3}, {"solution": "def Extract(lst):\n # Use list comprehension to iterate over each sublist and extract the first element\n result = [sublist[0] for sublist in lst]\n return result", "matching_cluster_idx": 3}, {"solution": "def Extract(test_list):\n # Use list comprehension to extract the first element from each sublist\n res = [sub[0] for sub in test_list]\n return res", "matching_cluster_idx": 3}]}, "Mbpp/474": {"dps": 68.5609756097561, "dps_norm": 70.71428571428571, "pass@1": 98.0, "profiled": [{"solution": "def replace_char(string, char1, char2):\n # Replace all occurrences of char1 with char2 in the string\n new_string = string.replace(char1, char2)\n return new_string", "matching_cluster_idx": 6}, {"solution": "def replace_char(string, old_char, new_char):\n # Replace occurrences of old_char with new_char in the string\n string = string.replace(old_char, new_char)\n return string", "matching_cluster_idx": 6}, {"solution": "def replace_char(str, old, new):\n # Iterate over the indices of the string\n for i in range(len(str)):\n # Check if the current character matches the old character\n if str[i] == old:\n # Replace the old character with the new character\n str = str[:i] + new + str[i+1:]\n # Return the modified string\n return str", "matching_cluster_idx": -1}, {"solution": "def replace_char(str, old, new):\n # Replace occurrences of 'old' character with 'new' character in the string\n str = str.replace(old, new)\n return str", "matching_cluster_idx": 6}, {"solution": "def replace_char(str1, char1, char2):\n # Replace occurrences of char1 with char2 in the string str1\n result = str1.replace(char1, char2)\n return result", "matching_cluster_idx": 6}, {"solution": "def replace_char(string, old_char, new_char):\n # Replace occurrences of old_char with new_char in the string\n return string.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(string, old_char, new_char):\n # Replace all occurrences of old_char with new_char in the string\n new_string = string.replace(old_char, new_char)\n return new_string", "matching_cluster_idx": 6}, {"solution": "def replace_char(st, p, r):\n # Initialize an empty string to store the result\n str1 = \"\"\n # Iterate through each character in the string\n for i in range(len(st)):\n # Check if the current character matches the one to be replaced\n if st[i] == p:\n # Append the replacement character to the result string\n str1 += r\n else:\n # Append the current character to the result string\n str1 += st[i]\n # Return the modified string\n return str1", "matching_cluster_idx": 0}, {"solution": "def replace_char(str1, char1, char2):\n # Replace occurrences of char1 with char2 in str1\n res = str1.replace(char1, char2)\n return res", "matching_cluster_idx": 6}, {"solution": "def replace_char(str, old_char, new_char):\n # Replace all occurrences of old_char with new_char in the string\n for i in range(len(str)):\n if str[i] == old_char:\n str = str[:i] + new_char + str[i+1:]\n return str", "matching_cluster_idx": -1}, {"solution": "def replace_char(string, old_char, new_char):\n # Replace old_char with new_char in the given string\n string = string.replace(old_char, new_char)\n return string", "matching_cluster_idx": 6}, {"solution": "def replace_char(string, old_char, new_char):\n # Check if the old character is present in the string\n if old_char not in string:\n return string\n \n # Initialize an empty string for the result\n res = ''\n \n # Iterate through each character in the string\n for char in string:\n # Replace the old character with the new character\n res += char if char != old_char else new_char\n \n return res", "matching_cluster_idx": 2}, {"solution": "def replace_char(s, old, new):\n # Initialize an empty string to store the result\n final = \"\"\n \n # Iterate through each character in the string\n for i in s:\n # If the character matches the old character, replace it with the new character\n if i == old:\n final = final + new\n else:\n # Otherwise, keep the character as is\n final = final + i\n \n # Return the modified string\n return final", "matching_cluster_idx": 2}, {"solution": "def replace_char(str, a, b):\n # Replace all occurrences of 'a' with 'b' in the string\n str = str.replace(a, b)\n # Return the modified string\n return str", "matching_cluster_idx": 6}, {"solution": "def replace_char(str, oldchar, newchar):\n # Replace occurrences of oldchar with newchar in the string\n for i in range(len(str)):\n if str[i] == oldchar:\n str = str[:i] + newchar + str[i+1:]\n return str", "matching_cluster_idx": -1}, {"solution": "def replace_char(str1, old_char, new_char):\n # Replace occurrences of old_char with new_char in str1\n str2 = str1.replace(old_char, new_char)\n return str2", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, old_char, new_char):\n # Create a new string where all occurrences of old_char are replaced with new_char\n return s.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, c1, c2):\n # Replace each occurrence of c1 with c2 in the string s\n s = s.replace(c1, c2)\n return s", "matching_cluster_idx": 6}, {"solution": "def replace_char(str, old, new):\n # Count the number of occurrences of the old character\n count = 0\n for i in range(len(str)):\n # Check if the current character is the old character\n if str[i] == old:\n count += 1\n\n # If the old character does not exist in the string, return the original string\n if count == 0:\n return str\n\n # Convert the string to a character array for easy manipulation\n str = list(str)\n\n # Replace all occurrences of the old character with the new character\n for i in range(len(str)):\n if str[i] == old:\n str[i] = new\n\n # Convert the character array back to a string\n return ''.join(str)", "matching_cluster_idx": 0}, {"solution": "def replace_char(str1, old_char, new_char):\n # Replace occurrences of old_char with new_char in str1\n str1 = str1.replace(old_char, new_char)\n return str1", "matching_cluster_idx": 6}]}, "Mbpp/476": {"dps": 91.89597315436242, "dps_norm": 95.0, "pass@1": 100.0, "profiled": [{"solution": "def big_sum(nums):\n # Calculate the sum of the maximum and minimum values in the array\n return max(nums) + min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_sum(input_list):\n # Initialize max with the first element of the list\n maximum = input_list[0]\n # Initialize min with the first element of the list\n minimum = input_list[0]\n \n # Iterate through the list starting from the second element\n for i in input_list[1:]:\n # Update maximum if the current element is greater\n if i > maximum:\n maximum = i\n # Update minimum if the current element is smaller\n elif i < minimum:\n minimum = i\n \n # Return the sum of the maximum and minimum values\n return maximum + minimum", "matching_cluster_idx": 3}, {"solution": "def big_sum(nums):\n # Sort the array to access the smallest and largest values easily\n nums.sort()\n # Return the sum of the smallest and largest values\n return nums[0] + nums[-1]", "matching_cluster_idx": 1}, {"solution": "def big_sum(nums):\n # Calculate the sum of the largest and smallest values in the array\n return max(nums) + min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_sum(lst):\n # Calculate the sum of the largest and smallest numbers in the list\n result = max(lst) + min(lst)\n return result", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n # Find the smallest value in the array\n min_value = min(arr)\n # Find the largest value in the array\n max_value = max(arr)\n # Calculate the sum of the smallest and largest values\n total_sum = min_value + max_value\n return total_sum", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n # Calculate the sum of the largest and smallest values in the array\n return max(arr) + min(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(nums):\n # Calculate the sum of the largest and smallest numbers in the array\n return max(nums) + min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_sum(nums):\n # Calculate the sum of the largest and smallest numbers in the list\n return max(nums) + min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n # Calculate the sum of the maximum and minimum values in the array\n return max(arr) + min(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n # Calculate the sum of the maximum and minimum values in the array\n return max(arr) + min(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(nums):\n # Calculate the sum of the maximum and minimum values in the list\n return max(nums) + min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_sum(nums):\n # Find the sum of the largest and smallest elements in the list\n return (max(nums) + min(nums))", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n # Check if the array has two or more elements\n if len(arr) >= 2:\n # Calculate the sum of the largest and smallest elements\n return (max(arr) + min(arr))\n else:\n # If the array has fewer than two elements, return None\n return None", "matching_cluster_idx": 5}, {"solution": "def big_sum(nums):\n # Calculate the sum of the maximum and minimum values in the list\n result = max(nums) + min(nums)\n return result", "matching_cluster_idx": 5}, {"solution": "def big_sum(nums):\n # Calculate the sum of the maximum and minimum values in the list\n return max(nums) + min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n # Find the maximum and minimum values in the array\n max_value = max(arr)\n min_value = min(arr)\n \n # Return the sum of the maximum and minimum values\n return max_value + min_value", "matching_cluster_idx": 5}, {"solution": "def big_sum(nums):\n # Find the minimum and maximum elements in the array\n return max(nums) + min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_sum(numbers):\n # Find the smallest and largest numbers in the array\n smallest_number = min(numbers)\n largest_number = max(numbers)\n # Return the sum of the smallest and largest number\n return smallest_number + largest_number", "matching_cluster_idx": 5}, {"solution": "def big_sum(nums):\n # Calculate the sum of the maximum and minimum values in the array\n return max(nums) + min(nums)", "matching_cluster_idx": 5}]}, "Mbpp/477": {"dps": 92.23880597014926, "dps_norm": 98.0, "pass@1": 64.0, "profiled": [{"solution": "def is_lower(text):\n # Check if all characters in the text are lowercase\n if text == text.lower():\n return text\n else:\n # Convert the text to lowercase if not already\n return text.lower()", "matching_cluster_idx": 3}, {"solution": "def is_lower(string):\n # Convert the string to lowercase using the lower() method\n return string.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n # Using the built-in lower() method of string to convert it to lower case\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(word):\n # Use the lower() method to convert all characters in the string to lowercase\n return word.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(str):\n # Convert the string to lower case using the built-in lower() method\n return str.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(a):\n # Check if all characters in the string are in lowercase\n if a.islower():\n return a\n # If not, convert the string to lowercase and return\n else:\n return a.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n # Convert the given string to lower case\n s = s.lower()\n return s", "matching_cluster_idx": 4}, {"solution": "def is_lower(string):\n # Use the lower() method to convert the string to lower case\n return string.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n # Convert the string to lower case\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(str1):\n # Check if all characters in the string are lower case\n if str1.islower():\n return str1\n else:\n # Convert the string to lower case if not already\n return str1.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(text):\n # Check if all characters in the text are lowercase\n if text.islower():\n return text\n else:\n # Return the text converted to lowercase\n return text.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(a):\n # Use the built-in lower() method to convert the string to lowercase\n return a.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(str):\n # Convert the given string to lower case\n str = str.lower()\n return str", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n # Use the built-in lower() method to convert the string to lowercase\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(st):\n # Initialize a flag to track if the string is all lowercase\n flag = 0\n # Iterate through each character in the string\n for i in range(len(st)):\n # Check if the current character is uppercase\n if st[i] >= 'A' and st[i] <= 'Z':\n # Set the flag to 1 if an uppercase character is found\n flag = 1\n break\n # If no uppercase characters are found, return the original string\n if flag == 0:\n return st\n else:\n # Convert the string to lowercase if an uppercase character is found\n return st.lower()", "matching_cluster_idx": 3}, {"solution": "def is_lower(str):\n # Use the str.lower() method to convert the string to lowercase\n return str.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(str):\n # Use the lower() method to convert the string to lowercase\n return str.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(a):\n # Use the lower() method to convert the string to lower case\n return a.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(str):\n # Use the lower() method to convert the string to lower case\n return str.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(string):\n # Convert the given string to lower case and return\n return string.lower()", "matching_cluster_idx": 4}]}, "Mbpp/563": {"dps": 81.12021857923497, "dps_norm": 78.63636363636363, "pass@1": 36.0, "profiled": [{"solution": "import re\ndef extract_values(str1):\n # Use regular expression to find all values enclosed in quotation marks\n return re.findall(r'\"(.*?)\"', str1)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(text):\n # Use regular expression to find all values within double quotes\n results = re.findall(r'\\\"(.*?)\\\"', text)\n return results", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(s):\n # Use regular expression to find all occurrences of text within quotation marks\n result = re.findall(r'\"(.*?)\"', s)\n return result", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(s):\n # Use regular expression to find all sequences of characters within quotation marks\n return re.findall(r'\\\"(.*?)\\\"', s)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(string):\n # Using regex to find all occurrences of text enclosed in double quotes\n values = re.findall(r'\"([^\"]*)\"', string)\n return values", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(string):\n # Use regular expression to find all substrings between quotation marks\n return re.findall(r'\"(.*?)\"', string)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(string):\n # Use regular expression to find values between quotation marks\n values = re.findall(r'\"(.*?)\"', string)\n return values", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(text):\n # Use regular expression to find all values enclosed in quotation marks\n return re.findall(r'\"(.*?)\"', text)", "matching_cluster_idx": 8}, {"solution": "def extract_values(text):\n result = []\n start_index = 0\n \n # Iterate over the string to find values between quotation marks\n while start_index < len(text):\n if text[start_index] == '\"':\n start_index += 1 # Skip the opening quotation mark\n end_index = text.find('\"', start_index)\n if end_index != -1:\n # Extract the value between quotation marks\n value = text[start_index:end_index]\n result.append(value)\n start_index = end_index + 1 # Move to the next character after closing quotation mark\n else:\n break # No closing quotation mark found, stop the loop\n else:\n start_index += 1 # Move to the next character if not a quotation mark\n \n return result", "matching_cluster_idx": 1}, {"solution": "import re\ndef extract_values(text):\n # Use regular expression to find all words surrounded by double quotes\n words = re.findall(r'\\\"(.*?)\\\"', text)\n return words", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(s):\n # Use regular expression to find all substrings enclosed in double quotes\n result = re.findall(r'\"(.*?)\"', s)\n return result", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(s):\n \"\"\"\n This function extracts values enclosed in quotation marks from a given string.\n \n Args:\n s (str): The input string from which values enclosed in quotation marks are to be extracted.\n \n Returns:\n list: A list of strings that were enclosed in quotation marks in the input string.\n \"\"\"\n # Using regular expression to find all substrings enclosed in quotation marks\n return re.findall(r'\\\"(.*?)\\\"', s)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(data):\n # Use regular expression to find all occurrences of text enclosed in double quotes\n result = re.findall(r'\"(.*?)\"', data)\n return result", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(items):\n # Use regular expression to find all sequences that are enclosed in double quotes\n values = re.findall(r'\"(.*?)\"', items)\n return values", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(text):\n # Using regular expression to find values between quotation marks\n match = re.findall(r'\"(.*?)\"', text)\n return match", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(text):\n # Use regular expression to find values enclosed in double quotes\n results = re.findall(r'\"(.*?)\"', text)\n return results", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(my_string):\n # Using regular expression to find all occurrences of values enclosed in double quotes\n return re.findall(r'\"(.*?)\"', my_string)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(text):\n # Use regular expression to find all values within double quotation marks\n return re.findall(r'\\\"(.*?)\\\"', text)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(s):\n # Using regular expression to find all substrings enclosed in quotation marks\n matches = re.findall(r'\\\"(.*?)\\\"', s)\n # Returning the list of matched values\n return matches", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(sentence):\n # Use regular expression to find all occurrences of text within double quotation marks\n result = re.findall(r'\\\"(.*?)\\\"', sentence)\n return result", "matching_cluster_idx": 8}]}, "Mbpp/572": {"dps": null, "dps_norm": null, "pass@1": 3.0, "profiled": []}, "Mbpp/578": {"dps": 77.71428571428571, "dps_norm": 68.63636363636364, "pass@1": 97.0, "profiled": [{"solution": "def interleave_lists(list1, list2, list3):\n # Combine all three lists into one\n list_all = list1 + list2 + list3\n # Create an empty list to store the result\n lst = []\n # Loop through each index in the combined list\n for i in range(len(list_all) // 3):\n # Append elements from each list at the current index to the result list\n lst.append(list1[i])\n lst.append(list2[i])\n lst.append(list3[i])\n return lst", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(lst1, lst2, lst3):\n # Create a flat list by interleaving elements from the three input lists\n flat_list = [item for sublist in zip(lst1, lst2, lst3) for item in sublist]\n return flat_list", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(list1, list2, list3):\n # Initialize an empty list to store the interleaved result\n result = []\n # Iterate over the range of the length of the lists (assuming they are of the same length)\n for i in range(len(list1)):\n # Append elements from list1, list2, and list3 in order to the result list\n result.append(list1[i])\n result.append(list2[i])\n result.append(list3[i])\n # Return the interleaved list\n return result", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(arr1, arr2, arr3):\n n = len(arr1) # Determine the length of the input lists\n inter_list = [] # Initialize an empty list to store the interleaved elements\n # Iterate through the length of the lists\n for i in range(n):\n inter_list.append(arr1[i]) # Append element from the first list\n inter_list.append(arr2[i]) # Append element from the second list\n inter_list.append(arr3[i]) # Append element from the third list\n return inter_list # Return the interleaved list", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(nums1, nums2, nums3):\n # Initialize an empty list to store the result\n res = []\n \n # Iterate over the length of the lists using the range of the first list's length\n for i in range(len(nums1)):\n # Append elements from each list to the result list one by one\n res.append(nums1[i])\n res.append(nums2[i])\n res.append(nums3[i])\n \n # Return the interleaved list\n return res", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n result = [] # Initialize an empty list to store the interleaved result\n for i in range(len(list1)):\n # Append elements from each list in the current iteration to the result list\n result.append(list1[i])\n result.append(list2[i])\n result.append(list3[i])\n return result # Return the interleaved list", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n # Create a new list to store the interleaved elements\n interleaved_list = []\n \n # Iterate through the lists using zip to combine them\n for a, b, c in zip(list1, list2, list3):\n # Append each element from the three lists to the interleaved list\n interleaved_list.append(a)\n interleaved_list.append(b)\n interleaved_list.append(c)\n \n # Return the interleaved list\n return interleaved_list", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n # Use zip to iterate over all three lists simultaneously\n # Extend each element from the lists into a single flat list\n result = [i for lists in zip(list1, list2, list3) for i in lists]\n return result", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(list1, list2, list3):\n # Interleave elements from three lists using list comprehension\n result = [item for triplet in zip(list1, list2, list3) for item in triplet]\n return result", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(list1, list2, list3):\n # Create an empty list to store the interleaved result\n result = []\n # Iterate over the indices of the lists\n for i in range(len(list1)):\n # Append elements from each list at the current index to the result list\n result.extend([list1[i], list2[i], list3[i]])\n return result", "matching_cluster_idx": 6}, {"solution": "import itertools\ndef interleave_lists(list1, list2, list3):\n # Using itertools.chain.from_iterable to interleave the lists\n # Then converting the iterator to a list before returning\n return list(itertools.chain.from_iterable(zip(list1, list2, list3)))", "matching_cluster_idx": 8}, {"solution": "def interleave_lists(a, b, c):\n # Initialize an empty list to store the interleaved result\n result = []\n \n # Determine the length of the lists (assuming all lists are of the same length)\n length = len(a)\n \n # Iterate through the indices of the lists\n for i in range(length):\n # Append the i-th element from each list to the result list\n result.append(a[i])\n result.append(b[i])\n result.append(c[i])\n \n # Return the interleaved list\n return result", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n # Check if all lists have the same length\n if len(list1) == len(list2) == len(list3):\n # Use zip to combine lists elementwise and flatten the result using sum with a list comprehension\n return [item for sublist in zip(list1, list2, list3) for item in sublist]\n else:\n # If lists are not of the same length, raise a ValueError\n raise ValueError(\"All lists must have the same length\")", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(list1, list2, list3):\n # Combine the three lists using list comprehension\n result = [item for sublist in zip(list1, list2, list3) for item in sublist]\n return result", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(nums1, nums2, nums3):\n # Initialize an empty list to store the interleaved elements\n result = []\n \n # Determine the length of the lists\n n = len(nums1)\n \n # Iterate over the indices of the lists\n for i in range(n):\n # Append elements from each list to the result list\n result.append(nums1[i])\n result.append(nums2[i])\n result.append(nums3[i])\n \n # Return the interleaved list\n return result", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n # Initialize an empty list to store the interleaved results\n inter_list = []\n \n # Iterate over the range of the length of any of the lists (assuming they are the same length)\n for i in range(len(list1)):\n # Append the i-th element from each list to the inter_list\n inter_list.extend([list1[i], list2[i], list3[i]])\n \n # Return the interleaved list\n return inter_list", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(A, B, C):\n # Using list comprehension to interleave elements from A, B, and C\n res = [ele for tup in zip(A, B, C) for ele in tup]\n return res", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(a, b, c):\n # Use list comprehension to interleave elements from the three lists\n return [j for i in zip(a, b, c) for j in i]", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(A, B, C):\n # Interleave elements from three lists A, B, and C\n interleaved_list = [item for sublist in zip(A, B, C) for item in sublist]\n return interleaved_list", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(A, B, C):\n # Using list comprehension to interleave elements from all three lists\n res = [j for i in zip(A, B, C) for j in i]\n return res", "matching_cluster_idx": 7}]}, "Mbpp/586": {"dps": 98.83040935672514, "dps_norm": 87.5, "pass@1": 92.0, "profiled": [{"solution": "def split_Arr(arr, n):\n # Split the array at the nth element and concatenate the second part with the first part\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(Arr, N):\n # Create a new list that starts from index N to the end of the original list\n A1 = Arr[N:]\n # Concatenate the new list with the part from the start of the original list to index N\n A2 = A1 + Arr[0:N]\n # Return the concatenated list\n return A2", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n): \n # Split the list at the nth element and store the second part\n sec_part = arr[n:] \n # Get the first part of the list up to the nth element\n first_part = arr[:n] \n # Concatenate the second part with the first part\n return sec_part + first_part", "matching_cluster_idx": 6}, {"solution": "def split_Arr(lst, N):\n # Split the list into two parts\n first_part = lst[:N]\n second_part = lst[N:]\n \n # Combine the second part with the first part\n result = second_part + first_part\n \n # Return the concatenated list\n return result", "matching_cluster_idx": 6}, {"solution": "def split_Arr(A, N):\n # Use slicing to split the array at index N and swap the parts\n A = A[N:] + A[:N]\n return A", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, N):\n # Split the list at the Nth element and rearrange\n return arr[N:] + arr[:N]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(input_list, N):\n # Slice the list from the Nth element to the end\n left_part = input_list[N:]\n # Slice the list from the beginning to the Nth element\n right_part = input_list[:N]\n # Concatenate the left part with the right part\n output_list = left_part + right_part\n return output_list", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, N):\n # Split the array at the Nth element\n split_arr = arr[N:] + arr[:N]\n return split_arr", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n # Slicing the array to get the part after the nth element and the part before the nth element\n # Then concatenating these two parts in reversed order\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, N):\n # Split the list into two parts at the Nth element\n res = arr[N:] + arr[:N]\n return res", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, N):\n # Split the array at index N and concatenate the two parts\n return arr[N:] + arr[:N]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, N):\n # Split the array at the N-th element and concatenate the two parts\n result = arr[N:] + arr[:N]\n return result", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n # Split the array into two parts\n part1 = arr[:n]\n part2 = arr[n:]\n # Concatenate the second part with the first part\n return part2 + part1", "matching_cluster_idx": 6}, {"solution": "def split_Arr(A, N):\n # Split the list at the nth element\n B = A[N:] + A[:N]\n return B", "matching_cluster_idx": 6}, {"solution": "def split_Arr(test_list, N):\n # Splitting the list at the Nth element\n res = test_list[N:] + test_list[:N]\n return res", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, N):\n # Splitting the array at index N\n part = arr[:N]\n # Adding the first part to the end of the array\n arr = arr[N:] + part\n return arr", "matching_cluster_idx": 6}, {"solution": "def split_Arr(array, N):\n # Slice the array from the Nth element to the end\n A = array[N:]\n # Slice the array from the start to the Nth element\n B = array[:N]\n # Concatenate the slices and return the result\n result = A + B\n return result", "matching_cluster_idx": 6}, {"solution": "def split_Arr(Arr, N):\n # Split the array at the Nth element\n return Arr[N:] + Arr[:N]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, N):\n # Split the array into two parts at the Nth element\n a1 = arr[N:] # Elements from N to the end of the array\n a2 = arr[:N] # Elements from the start of the array to N\n # Concatenate the second part with the first part\n a3 = a1 + a2\n return a3", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, N):\n # Split the array at the Nth element and concatenate the parts\n return arr[N:] + arr[:N]", "matching_cluster_idx": 6}]}, "Mbpp/587": {"dps": 73.64864864864865, "dps_norm": 92.5, "pass@1": 100.0, "profiled": [{"solution": "def list_tuple(test_list):\n # Convert the list to a tuple and return it\n res = tuple(test_list)\n return res", "matching_cluster_idx": 3}, {"solution": "def list_tuple(test_list):\n # Use the tuple() constructor to convert the list to a tuple\n res = tuple(test_list)\n # Return the resulting tuple\n return res", "matching_cluster_idx": 3}, {"solution": "def list_tuple(test_list):\n # Convert the list to a tuple using the tuple() function\n res = tuple(test_list)\n return res", "matching_cluster_idx": 3}, {"solution": "def list_tuple(list1):\n # Convert the list to a tuple\n tuple1 = tuple(list1)\n return tuple1", "matching_cluster_idx": 2}, {"solution": "def list_tuple(test_list):\n # Converting the list to a tuple using the tuple() function\n res = tuple(test_list)\n return res", "matching_cluster_idx": 3}, {"solution": "def list_tuple(items):\n # Use the tuple() function to convert the list to a tuple\n t = tuple(items)\n # Return the resulting tuple\n return t", "matching_cluster_idx": 3}, {"solution": "def list_tuple(test_list):\n # Convert the list to a tuple and return it\n res = tuple(test_list)\n return res", "matching_cluster_idx": 2}, {"solution": "def list_tuple(test_list):\n # Converting the list to a tuple using the tuple() function\n res = tuple(test_list)\n return res", "matching_cluster_idx": 3}, {"solution": "def list_tuple(l1):\n # Convert the list to a tuple and return it\n t1 = tuple(l1)\n return t1", "matching_cluster_idx": 3}, {"solution": "def list_tuple(test_list):\n # Convert the list to a tuple and return the result\n res = tuple(test_list)\n return res", "matching_cluster_idx": 3}, {"solution": "def list_tuple(input_list):\n # Convert the input list to a tuple and return\n return tuple(input_list)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(test_list):\n # Convert list to tuple using tuple() function\n res = tuple(test_list)\n return res", "matching_cluster_idx": 2}, {"solution": "from typing import List, Tuple\ndef list_tuple(x: List[int]) -> Tuple[int]:\n # Convert the list 'x' into a tuple and return it\n return tuple(x)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(test_list):\n # Convert the list to a tuple using the tuple() function\n res = tuple(test_list)\n return res", "matching_cluster_idx": 3}, {"solution": "def list_tuple(test_list):\n # Convert the list to a tuple\n res = tuple(test_list)\n # Return the resulting tuple\n return res", "matching_cluster_idx": 3}, {"solution": "def list_tuple(test_list):\n # Convert the list to a tuple using tuple() and return the result\n res = tuple(test_list)\n return res", "matching_cluster_idx": 3}, {"solution": "def list_tuple(items):\n # Convert the list to a tuple and return the result\n return tuple(items)", "matching_cluster_idx": 2}, {"solution": "def list_tuple(test_list):\n # Convert the list to a tuple using the tuple() function\n res = tuple(test_list)\n return res", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lis):\n # Convert the list to a tuple and return it\n return tuple(lis)", "matching_cluster_idx": 2}, {"solution": "def list_tuple(items):\n # Convert the list to a tuple and return it\n return tuple(items)", "matching_cluster_idx": 2}]}, "Mbpp/588": {"dps": 92.33944954128441, "dps_norm": 96.66666666666667, "pass@1": 100.0, "profiled": [{"solution": "def big_diff(nums):\n # Calculate the difference between the maximum and minimum values in the list\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n # Calculate the difference between the maximum and minimum values in the list\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n # Calculate the difference between the maximum and minimum values in the list\n result = max(nums) - min(nums)\n return result", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n # Calculate the difference between the maximum and minimum values in the list\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n # Calculate the difference between the maximum and minimum values in the list\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n # Calculate the difference between the maximum and minimum values in the list\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n # Calculate the maximum and minimum values in the list\n max_val = max(nums)\n min_val = min(nums)\n # Return the difference between the maximum and minimum values\n return max_val - min_val", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n # Calculate the difference between the maximum and minimum values in the list\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n # Calculate the difference between the maximum and minimum values in the list\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n # Calculate the difference between the maximum and minimum values in the list\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n # Calculate the difference between the maximum and minimum values in the list\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n # Calculate the difference between the maximum and minimum values in the list\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n # Calculate the difference between the maximum and minimum values in the list\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n # Initialize the minimum value to the first element of the list\n min = nums[0]\n \n # Initialize the maximum value to the first element of the list\n max = nums[0]\n \n # Iterate through the list starting from the second element\n for x in nums[1:]:\n # Update the minimum value if the current element is smaller\n min = min if min < x else x\n \n # Update the maximum value if the current element is larger\n max = max if max > x else x\n \n # Return the difference between the maximum and minimum values\n return max - min", "matching_cluster_idx": 3}, {"solution": "def big_diff(nums):\n # Find the minimum value in the list\n min_val = min(nums)\n # Find the maximum value in the list\n max_val = max(nums)\n # Return the difference between the maximum and minimum values\n return max_val - min_val", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n # Check if the list is empty\n if len(nums) == 0:\n return 0\n \n # Initialize the minimum and maximum elements with the first element of the list\n min_element = nums[0]\n max_element = nums[0]\n \n # Iterate through the list starting from the second element\n for i in range(1, len(nums)):\n # Update the minimum and maximum elements\n if nums[i] < min_element:\n min_element = nums[i]\n if nums[i] > max_element:\n max_element = nums[i]\n \n # Return the difference between the maximum and minimum elements\n return max_element - min_element", "matching_cluster_idx": 3}, {"solution": "def big_diff(nums):\n # Calculate the difference between the maximum and minimum values in the list\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n # Calculate the difference between the maximum and minimum values in the list\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n # Find the maximum and minimum values in the list\n max_val = max(nums)\n min_val = min(nums)\n \n # Calculate the difference between the maximum and minimum values\n return max_val - min_val", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n # Find the difference between the largest and smallest numbers in the list\n return max(nums) - min(nums)", "matching_cluster_idx": 5}]}, "Mbpp/592": {"dps": 51.73333333333334, "dps_norm": 48.0, "pass@1": 10.0, "profiled": [{"solution": "def factorial(n):\n # Base case: factorial of 0 or 1\n if n == 0 or n == 1:\n return 1\n result = 1\n # Iterative calculation of factorial\n for i in range(2, n + 1):\n result *= i\n return result\ndef binomialCoeff(n, k):\n # Calculate binomial coefficient using factorial\n return factorial(n) // (factorial(k) * factorial(n - k))\ndef sum_Of_product(n):\n sum1 = 0\n # Calculate the sum of the product of consecutive binomial coefficients\n for i in range(1, n + 1):\n sum1 = sum1 + (binomialCoeff(n, i) * binomialCoeff(n, i - 1))\n return sum1", "matching_cluster_idx": 0}, {"solution": "from math import comb\ndef sum_Of_product(n):\n total_sum = 0\n # Iterate through the range from 0 to n\n for i in range(n + 1):\n # Calculate the product of consecutive binomial coefficients\n product = comb(n, i) * comb(n, i + 1)\n # Add the product to the total sum\n total_sum += product\n return total_sum", "matching_cluster_idx": 5}, {"solution": "def sum_Of_product(n):\n # Initialize the result to 0\n result = 0\n \n # Loop through the range from 0 to n-1\n for k in range(n):\n # Calculate the product of two binomial coefficients and add it to the result\n result += binomial_coefficient(n, k) * binomial_coefficient(n, k + 1)\n \n return result\ndef binomial_coefficient(n, k):\n # Calculate binomial coefficient using a nested loop\n res = 1\n \n # If k is greater than n-k, then it is more efficient to calculate C(n, n-k)\n if (k > n - k):\n k = n - k\n \n # Calculate the value of binomial coefficient C(n, k)\n for i in range(k):\n res *= (n - i)\n res //= (i + 1)\n \n return res", "matching_cluster_idx": 4}, {"solution": "def binomial_coefficient(n, k):\n res = 1 # Initialize result\n # Update result using an efficient formula\n if k > n - k:\n k = n - k\n for i in range(k):\n res *= (n - i)\n res //= (i + 1)\n return res\ndef sum_Of_product(n):\n if n < 1:\n return 0\n sum = 0\n # Loop through all possible pairs of consecutive binomial coefficients\n for i in range(1, n + 1):\n sum += (binomial_coefficient(n, i) * binomial_coefficient(n, i - 1))\n return sum", "matching_cluster_idx": 4}, {"solution": "from math import factorial\ndef sum_Of_product(N):\n # Initialize the result variable to store the sum of products\n result = 0\n \n # Iterate through each number from 0 to N-1\n for i in range(0, N):\n # Calculate the product of consecutive binomial coefficients using the factorial function\n binom_prod = (factorial(N) // (factorial(i) * factorial(N - i))) * (factorial(N) // (factorial(i + 1) * factorial(N - i - 1)))\n \n # Add the product to the result\n result += binom_prod\n \n # Return the computed result\n return result", "matching_cluster_idx": 2}, {"solution": "from math import comb\ndef sum_Of_product(N):\n # Initialize the sum to 0\n sum = 0\n \n # Iterate through the range from 0 to N-1\n for i in range(N):\n # Calculate the product of binomial coefficients for the current and next term\n sum += comb(N, i) * comb(N, i + 1)\n \n # Return the final sum of products\n return sum", "matching_cluster_idx": 5}, {"solution": "def sum_Of_product(N):\n # Initialize the result variable to store the sum of products\n result = 0\n \n # Calculate the sum of the product of consecutive binomial coefficients\n for r in range(1, N + 1):\n result += (binomial_coefficient(N, r) * binomial_coefficient(N, r - 1))\n \n return result\ndef binomial_coefficient(n, k):\n # Helper function to calculate the binomial coefficient C(n, k)\n result = 1\n \n # If k is greater than n-k, use symmetry property C(n, k) = C(n, n-k)\n if k > n - k:\n k = n - k\n \n # Calculate the binomial coefficient using the formula C(n, k) = n! / (k! * (n-k)!)\n for i in range(k):\n result *= (n - i)\n result //= (i + 1)\n \n return result", "matching_cluster_idx": 4}, {"solution": "def nCr(n, r):\n # Initialize result\n res = 1\n\n # Since C(n, r) = C(n, n-r)\n if r > n - r:\n r = n - r\n\n # Calculate value of [n*(n-1)*---*(n-r+1)] / [r*(r-1)*---*1]\n for i in range(r):\n res *= (n - i)\n res //= (i + 1)\n\n return res\ndef sum_Of_product(n):\n # Calculate the sum of product of consecutive binomial coefficients\n res = 0\n for r in range(1, n + 1):\n res += (nCr(n, r) * nCr(n, r - 1))\n return res", "matching_cluster_idx": 4}, {"solution": "from math import comb\ndef sum_Of_product(n):\n # Initialize the sum of products\n sum = 0\n \n # Iterate over the range from 0 to n (inclusive)\n for i in range(0, n + 1):\n # Calculate the product of consecutive binomial coefficients\n # and add it to the sum\n sum += comb(n, i) * comb(n, i + 1)\n \n # Return the final sum of products\n return sum", "matching_cluster_idx": 5}, {"solution": "from math import comb\ndef sum_Of_product(n):\n total_sum = 0 # Initialize the sum to zero\n \n # Iterate over each possible value of k from 1 to n\n for k in range(1, n + 1):\n # Calculate the product of the binomial coefficients for two consecutive k values\n # and add it to the total sum\n total_sum += comb(n, k - 1) * comb(n, k)\n \n return total_sum", "matching_cluster_idx": 5}]}, "Mbpp/597": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 13.0, "profiled": [{"solution": "def find_kth(arr1, arr2, k):\n # Concatenate both arrays\n combined = arr1 + arr2\n \n # Sort the concatenated array\n combined.sort()\n \n # Return the kth element (index k-1 because list indices are 0-based)\n return combined[k-1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(arr1, arr2, k):\n # Combine both arrays\n result = arr1 + arr2\n # Sort the combined array\n result.sort()\n # Return the kth element from the sorted array\n return result[k - 1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(nums1, nums2, k):\n # Merge nums1 and nums2 into a sorted list\n merged = sorted(nums1 + nums2)\n # Return the k-th element in the merged list (adjusted for 0-based indexing)\n return merged[k - 1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(A, B, k):\n # Merge the two sorted arrays into one sorted array\n merged = sorted(A + B)\n \n # Return the kth element from the merged sorted array\n return merged[k - 1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(arr1, arr2, k):\n # Concatenate the two sorted arrays\n combined = sorted(arr1 + arr2)\n # Return the k-1 element (since list indices start at 0)\n return combined[k - 1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(arr1, arr2, k):\n # Concatenate both arrays and sort them\n result = sorted(arr1 + arr2)\n # Return the k-1 index element (since indexing starts from 0)\n return result[k - 1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(arr1, arr2, k):\n # Join the two arrays\n arr = arr1 + arr2\n \n # Sort the combined array\n arr.sort()\n \n # Return the kth element (adjust index by subtracting 1)\n return arr[k-1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(arr1, arr2, k):\n # Concatenate the two arrays\n merged = arr1 + arr2\n \n # Sort the merged array\n merged.sort()\n \n # Return the kth element (0-based index)\n return merged[k - 1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(nums1, nums2, k):\n # Combine both lists\n nums3 = nums1 + nums2\n # Sort the combined list\n nums3.sort()\n # Return the kth element (1-based index, hence nums3[k-1])\n return nums3[k - 1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(arr1, arr2, k):\n # Merge both arrays\n merged_array = arr1 + arr2\n # Sort the merged array\n merged_array.sort()\n # Return the kth element (adjust for 0-based indexing)\n return merged_array[k - 1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(nums1, nums2, k):\n # Merge the two sorted arrays and create a new list\n result = sorted(nums1 + nums2)\n # Return the kth element from the merged list\n return result[k - 1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(arr1, arr2, k):\n # Combine both arrays and sort them\n combined_sorted = sorted(arr1 + arr2)\n \n # Return the k-th element (1-based index), subtract 1 for 0-based index\n return combined_sorted[k - 1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(arr1, arr2, k):\n # Merge the two sorted arrays\n merged_arr = sorted(arr1 + arr2)\n \n # Return the kth element, adjusting for zero-based indexing\n return merged_arr[k - 1]", "matching_cluster_idx": 3}]}, "Mbpp/604": {"dps": 85.68181818181819, "dps_norm": 97.0, "pass@1": 25.0, "profiled": [{"solution": "def reverse_words(s):\n # Split the string into words, reverse the list of words, and join them back into a string\n return ' '.join(s.split()[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n # Split the string into words, reverse the list of words, and join them back into a string\n return ' '.join(s.split()[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n # Split the string into a list of words, reverse the list, and join it back into a string\n return ' '.join(reversed(s.split()))", "matching_cluster_idx": 3}, {"solution": "def reverse_words(s):\n # Split the string into words, reverse the list of words, and join them back into a string\n return \" \".join(s.split()[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n # Split the string into words using split(), reverse the list using reverse(), and then join them back with join()\n return ' '.join(reversed(s.split()))", "matching_cluster_idx": 3}, {"solution": "def reverse_words(s):\n # Split the string into words, reverse the list of words, and join them back into a string\n return ' '.join(s.split()[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n # Split the string into words, reverse the list of words, and join them back with spaces\n return ' '.join(s.split()[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n # Split the string into words, reverse the list of words, and join them back into a string\n return \" \".join(s.split()[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n # Split the string into words\n words = s.split()\n \n # Reverse the list of words\n words = words[::-1]\n \n # Join the reversed words back into a string\n return ' '.join(words)", "matching_cluster_idx": 4}, {"solution": "def reverse_words(input_string):\n # Split the input string into words\n words = input_string.split()\n # Reverse the list of words and join them back into a string\n reversed_string = ' '.join(reversed(words))\n return reversed_string", "matching_cluster_idx": 3}, {"solution": "def reverse_words(s):\n # Split the string into words\n words = s.split()\n # Reverse the list of words\n words.reverse()\n # Join the reversed list of words back into a string\n reversed_string = ' '.join(words)\n # Return the resulting string\n return reversed_string", "matching_cluster_idx": 4}, {"solution": "import sys\ndef reverse_words(s):\n # Splitting the string into words and reversing the order\n words = s.split()\n reversed_words = words[::-1]\n # Joining the reversed words back into a single string with spaces\n reversed_string = ' '.join(reversed_words)\n return reversed_string", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n # Split the string into a list of words\n words = s.split()\n # Reverse the list of words\n reversed_words = words[::-1]\n # Join the reversed list of words back into a string\n return ' '.join(reversed_words)", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n # Split the string into words, reverse the list of words, and join them back into a string\n return ' '.join(s.split()[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n # Split the string into words\n words = s.split()\n \n # Reverse the list of words\n words.reverse()\n \n # Join the reversed words back into a string\n reversed_string = ' '.join(words)\n \n return reversed_string", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n # Split the string into words, reverse the list of words, and join them back into a string\n return ' '.join(s.split()[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n # Split the string into words and reverse the order\n return ' '.join(s.split()[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n # Split the input string into words, reverse the list of words, and then join them back into a string\n return ' '.join(s.split()[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n # Split the string into words\n words = s.split()\n # Reverse the list of words\n words = words[::-1]\n # Join the reversed list of words back into a string\n return ' '.join(words)", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n # Split the input string into words\n words = s.split()\n \n # Reverse the list of words\n words = words[::-1]\n \n # Join the reversed words to form the output string\n s = ' '.join(words)\n \n return s", "matching_cluster_idx": 4}]}, "Mbpp/610": {"dps": 66.85736079328757, "dps_norm": 73.6842105263158, "pass@1": 19.0, "profiled": [{"solution": "def remove_kth_element(mylist, K):\n # Calculate the index to remove\n mylist.pop(K - 1)\n return mylist", "matching_cluster_idx": 6}, {"solution": "def remove_kth_element(lst, k):\n # Initialize an empty list to store the result\n temp_list = []\n # Iterate through the original list\n for i in range(len(lst)):\n # Check if the current index is not equal to the k-1 index\n if i != k-1:\n # Append the current element to the result list\n temp_list.append(lst[i])\n # Return the result list without the k'th element\n return temp_list", "matching_cluster_idx": 0}, {"solution": "def remove_kth_element(lst, k):\n # Check if k is within the valid range\n if k <= 0 or k > len(lst):\n raise ValueError(\"k must be in the range 1 to the length of the list\")\n \n # Create a new list excluding the k'th element\n new_list = lst[:k-1] + lst[k:]\n return new_list", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(mylist, k):\n # Remove the k-th element from the list\n # k is 0-based index, so k-1 is used\n del mylist[k-1]\n return mylist", "matching_cluster_idx": 6}, {"solution": "def remove_kth_element(nums, k):\n # Remove the k'th element from the list (index k-1)\n del nums[k - 1]\n # Return the modified list\n return nums", "matching_cluster_idx": 6}, {"solution": "def remove_kth_element(list1, k):\n # Initialize a temporary list to store elements except the k-th one\n temp = []\n for i in range(len(list1)):\n # Check if the current index is not equal to k-1 (since list index is 0-based)\n if i != (k - 1):\n temp.append(list1[i])\n return temp", "matching_cluster_idx": 0}, {"solution": "def remove_kth_element(numbers, k):\n # Create a new list that is a copy of the original list\n new_list = numbers[:]\n \n # Remove the k'th element from the new list (Python uses 0-based indexing)\n del new_list[k - 1]\n \n # Return the modified list\n return new_list", "matching_cluster_idx": 5}, {"solution": "def remove_kth_element(l1, K):\n # Remove the K'th element from the list (1-based index)\n l1.pop(K - 1)\n # Return the modified list\n return l1", "matching_cluster_idx": 6}, {"solution": "def remove_kth_element(test_list, K):\n # Iterate over the list and use list comprehension to exclude the k'th element\n res = [ele for ind, ele in enumerate(test_list) if ind != K - 1]\n return res", "matching_cluster_idx": 1}, {"solution": "def remove_kth_element(input_list, k):\n # Create a copy of the input list to avoid modifying the original list\n result = input_list[:]\n \n # Convert the k index to be zero-based since list indices in Python start at 0\n k -= 1\n \n # Check if the k index is within the bounds of the list\n if k >= 0 and k < len(result):\n # Remove the k'th element from the list\n del result[k]\n \n return result", "matching_cluster_idx": 4}, {"solution": "def remove_kth_element(nums, k):\n # Create a copy of the list using slicing\n result = nums[:]\n # Remove the k'th element by deleting it at index k-1 (since Python indices start at 0)\n del result[k - 1]\n return result", "matching_cluster_idx": 5}, {"solution": "def remove_kth_element(nums, k):\n # Remove the element at the k-1 index\n nums.pop(k - 1)\n return nums", "matching_cluster_idx": 6}, {"solution": "def remove_kth_element(lst, k):\n # Remove the element at index k-1 from the list\n del lst[k-1]\n # Return the modified list\n return lst", "matching_cluster_idx": 6}, {"solution": "def remove_kth_element(nums, k):\n # Remove the k'th element from the list\n del nums[k-1]\n return nums", "matching_cluster_idx": 6}, {"solution": "def remove_kth_element(nums, k):\n # Calculate the index of the element to remove\n index_to_remove = k - 1 # Adjusting index to zero-based\n \n # Remove the k'th element\n nums.pop(index_to_remove)\n \n # Return the modified list\n return nums", "matching_cluster_idx": 6}, {"solution": "def remove_kth_element(test_list, K):\n # Check if the value of K is greater than the length of the list\n if K > len(test_list) or K < 1:\n return test_list\n \n # Initialize an empty list to store the modified elements\n res = []\n \n # Iterate over the list and append elements to the result list\n for idx in range(len(test_list)):\n if idx != K - 1: # Skip the K'th element\n res.append(test_list[idx])\n \n return res", "matching_cluster_idx": 0}, {"solution": "def remove_kth_element(lis, k):\n # Remove the element at the index k-1 (since index is 0-based)\n del lis[k-1]\n return lis", "matching_cluster_idx": 6}, {"solution": "def remove_kth_element(nums, k):\n # Remove the element at the (k-1)th index from the list\n nums.pop(k - 1)\n return nums", "matching_cluster_idx": 6}, {"solution": "def remove_kth_element(test_list, K):\n # Use list comprehension to iterate through the list and include only elements not at the K-1 index\n res = [ele for idx, ele in enumerate(test_list) if idx != K - 1]\n return res", "matching_cluster_idx": 1}]}, "Mbpp/611": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 98.0, "profiled": [{"solution": "def max_of_nth(matrix, n):\n # Use a generator expression to iterate through each row of the matrix\n # and extract the nth element from each row, then find the maximum of those elements.\n return max(row[n] for row in matrix)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(lst, n):\n # Extract the nth column from each sublist and find the maximum value\n max_val = max(sublist[n] for sublist in lst)\n return max_val", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(list1, n):\n # Extracts the nth column from the list of lists and returns the maximum value\n return max(i[n] for i in list1)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n # Use a generator expression to iterate over the nth column and find the maximum value\n return max(row[n] for row in matrix)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(lst, N):\n # Use a generator expression to extract the N-th element from each sublist in the matrix\n # and find the maximum value using the max() function\n return max(row[N] for row in lst)", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef max_of_nth(matrix: List[List[int]], n: int) -> int:\n # Use a generator expression to iterate through the nth column and find the maximum value\n return max(x[n] for x in matrix)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n # Extract the nth column from the matrix using list comprehension\n return max([row[n] for row in matrix])", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(lst, n):\n # Extract the nth column from the list of lists\n nth_column = [x[n] for x in lst]\n # Return the maximum value from the nth column\n return max(nth_column)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n # Initialize a list to store the nth elements of each row\n nth_elements = []\n \n # Iterate through each row in the matrix\n for row in matrix:\n # Check if the row has enough elements to access the nth column\n if len(row) > n:\n # Append the nth element of the row to the list\n nth_elements.append(row[n])\n \n # Return the maximum value found in the list of nth elements\n return max(nth_elements)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(lst, n):\n # Use a generator expression to extract the nth element from each sublist and find the maximum\n return max(item[n] for item in lst)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n # Check if the matrix is empty or if n is out of the valid column range\n if not matrix or n >= len(matrix[0]):\n return None\n # Find the maximum element in the nth column using a generator expression\n return max(row[n] for row in matrix)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n # Use the map function to extract the nth element from each row in the matrix\n # Use max function to find the maximum value among the nth elements\n return max(map(lambda x: x[n], matrix))", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(arr, n):\n # Extract the n-th column from the matrix\n nth_column = [row[n] for row in arr]\n # Return the maximum value from the n-th column\n return max(nth_column)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n # Initialize the maximum value to the first element of the nth column\n max_value = matrix[0][n]\n \n # Iterate through each row of the matrix\n for i in range(len(matrix)):\n # Update the maximum value if the current element is greater\n if matrix[i][n] > max_value:\n max_value = matrix[i][n]\n \n # Return the maximum value found in the nth column\n return max_value", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n # Use list comprehension to extract the nth element from each row and then find the maximum\n return max(row[n] for row in matrix)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(input_list, N):\n # Extract the N'th element from each sublist using list comprehension\n return max([sub_list[N] for sub_list in input_list])", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n # Use a generator expression to extract the nth element from each sublist and find the maximum\n return max(sublist[n] for sublist in matrix if n < len(sublist))", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(lst, n):\n # Initialize the maximum value to negative infinity\n max_val = float('-inf')\n \n # Iterate through each row in the list\n for x in lst:\n # Check if the current column has a value greater than the max_val\n if len(x) > n and x[n] > max_val:\n # Update the maximum value\n max_val = x[n]\n \n # Return the maximum value found\n return max_val", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n # Extract the nth column from each row and find the maximum value\n return max(row[n] for row in matrix if len(row) > n)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n # Extract the nth column from the matrix\n nth_column = [row[n] for row in matrix]\n \n # Return the maximum value from the nth column\n return max(nth_column)", "matching_cluster_idx": 5}]}, "Mbpp/631": {"dps": 93.33333333333331, "dps_norm": 96.25, "pass@1": 52.0, "profiled": [{"solution": "def replace_spaces(input_str):\n # Check if the input string contains any spaces\n if ' ' in input_str:\n # Replace spaces with underscores if they exist\n return input_str.replace(' ', '_')\n else:\n # Replace underscores with spaces if no spaces exist\n return input_str.replace('_', ' ')", "matching_cluster_idx": 7}, {"solution": "def replace_spaces(test_str):\n # Check if the string contains underscores\n if '_' in test_str:\n # Replace underscores with spaces\n res = test_str.replace('_', ' ')\n else:\n # Replace spaces with underscores\n res = test_str.replace(' ', '_')\n return res", "matching_cluster_idx": 6}, {"solution": "def replace_spaces(s):\n # Check if the string contains spaces, if so, replace them with underscores\n if ' ' in s:\n return s.replace(' ', '_')\n # If no spaces are found, replace underscores with spaces\n else:\n return s.replace('_', ' ')", "matching_cluster_idx": 7}, {"solution": "def replace_spaces(text):\n # Check if the string contains spaces\n if ' ' in text:\n # Replace spaces with underscores\n return text.replace(' ', '_')\n # If no spaces, replace underscores with spaces\n else:\n return text.replace('_', ' ')", "matching_cluster_idx": 7}, {"solution": "def replace_spaces(input_string):\n # Replace all whitespaces with underscores\n str1 = input_string.replace(' ', '_')\n # Replace all underscores with whitespaces\n str2 = input_string.replace('_', ' ')\n \n # Check which transformation was applied and return the result accordingly\n if input_string == str1:\n return str2\n else:\n return str1", "matching_cluster_idx": 6}, {"solution": "def replace_spaces(str1):\n # Check if the input string contains spaces\n if ' ' in str1:\n # Replace spaces with underscores\n str1 = str1.replace(' ', '_')\n else:\n # Replace underscores with spaces\n str1 = str1.replace('_', ' ')\n return str1", "matching_cluster_idx": 7}, {"solution": "def replace_spaces(test_str):\n # Check if the string contains any spaces\n if \" \" in test_str:\n # Replace spaces with underscores if present\n res = test_str.replace(\" \", \"_\")\n else:\n # Replace underscores with spaces if no spaces are present\n res = test_str.replace(\"_\", \" \")\n return res", "matching_cluster_idx": 7}, {"solution": "def replace_spaces(str1):\n # Split the string into a list of words\n a = list(str1.split(\" \"))\n # Join the words with underscores\n b = \"_\".join(a)\n # Split the string by underscores into a list\n c = list(str1.split(\"_\"))\n # Join the words with spaces\n d = \" \".join(c)\n \n # Check which operation was performed and return the appropriate result\n if str1 == b:\n return d\n else:\n return b", "matching_cluster_idx": 3}, {"solution": "def replace_spaces(s):\n # Check if the string contains spaces\n if ' ' in s:\n # Replace all spaces with underscores\n s = s.replace(' ', '_')\n else:\n # Replace all underscores with spaces\n s = s.replace('_', ' ')\n return s", "matching_cluster_idx": 7}, {"solution": "def replace_spaces(input_string):\n # Check if the input string contains spaces\n if ' ' in input_string:\n # Replace spaces with underscores\n output_string = input_string.replace(' ', '_')\n else:\n # Replace underscores with spaces\n output_string = input_string.replace('_', ' ')\n return output_string", "matching_cluster_idx": 7}, {"solution": "def replace_spaces(input_string):\n # Check if the input string contains spaces\n if ' ' in input_string:\n # Replace spaces with underscores\n return input_string.replace(' ', '_')\n # If no spaces, replace underscores with spaces\n return input_string.replace('_', ' ')", "matching_cluster_idx": 7}, {"solution": "def replace_spaces(input_string):\n # Check if the input string contains spaces\n if ' ' in input_string:\n # Replace spaces with underscores\n return input_string.replace(' ', '_')\n else:\n # Replace underscores with spaces\n return input_string.replace('_', ' ')", "matching_cluster_idx": 7}, {"solution": "def replace_spaces(string):\n # Check if the string contains spaces, if so, replace spaces with underscores\n if \" \" in string:\n return string.replace(\" \", \"_\")\n else:\n # If no spaces, replace underscores with spaces\n return string.replace(\"_\", \" \")", "matching_cluster_idx": 7}, {"solution": "def replace_spaces(str1):\n # Check if the string contains any space\n if \" \" in str1:\n # Replace spaces with underscores\n return str1.replace(\" \", \"_\")\n else:\n # Replace underscores with spaces\n return str1.replace(\"_\", \" \")", "matching_cluster_idx": 7}, {"solution": "def replace_spaces(input_str):\n # Check if there are any spaces in the input string\n if ' ' in input_str:\n # Replace spaces with underscores if spaces are found\n return input_str.replace(' ', '_')\n else:\n # Replace underscores with spaces if no spaces are found\n return input_str.replace('_', ' ')", "matching_cluster_idx": 7}, {"solution": "def replace_spaces(input_string):\n # Check if the string contains spaces and replace them with underscores\n if ' ' in input_string:\n return input_string.replace(' ', '_')\n # If no spaces, replace underscores with spaces\n else:\n return input_string.replace('_', ' ')", "matching_cluster_idx": 7}, {"solution": "def replace_spaces(str1):\n # Check if there are any whitespaces in the string\n if str1.find(' ') >= 0:\n # Replace whitespaces with underscores\n return str1.replace(' ', '_')\n else:\n # Replace underscores with whitespaces\n return str1.replace('_', ' ')", "matching_cluster_idx": 7}, {"solution": "def replace_spaces(input_string):\n # Check if the input string contains any spaces\n if ' ' in input_string:\n # Replace all spaces with underscores\n return input_string.replace(' ', '_')\n else:\n # Replace all underscores with spaces\n return input_string.replace('_', ' ')", "matching_cluster_idx": 7}, {"solution": "def replace_spaces(str1):\n # Use the replace method to substitute spaces with underscores\n if ' ' in str1:\n # Replace spaces with underscores if they exist\n return str1.replace(' ', '_')\n # Replace underscores with spaces if spaces do not exist\n else:\n return str1.replace('_', ' ')", "matching_cluster_idx": 7}, {"solution": "def replace_spaces(str1):\n # Replace spaces with underscores and vice versa\n if ' ' in str1:\n result_str = str1.replace(' ', '_')\n else:\n result_str = str1.replace('_', ' ')\n return result_str", "matching_cluster_idx": 7}]}, "Mbpp/632": {"dps": 95.1219512195122, "dps_norm": 97.14285714285714, "pass@1": 96.0, "profiled": [{"solution": "def move_zero(nums):\n i = 0 # Initialize pointer to track the position to place the next non-zero element\n for j in range(len(nums)):\n if nums[j] != 0:\n nums[i], nums[j] = nums[j], nums[i] # Swap non-zero element with the element at position i\n i += 1 # Move the pointer to the next position\n return nums", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n # Move all zeroes to the end of the list\n non_zero_pos = 0 # Position to place the next non-zero element\n \n # Iterate through the list and place non-zero elements at non_zero_pos\n for i in range(len(nums)):\n if nums[i] != 0:\n nums[non_zero_pos] = nums[i]\n non_zero_pos += 1\n \n # Fill the remaining positions with zeroes\n for i in range(non_zero_pos, len(nums)):\n nums[i] = 0\n \n return nums", "matching_cluster_idx": 6}, {"solution": "def move_zero(arr):\n # Filter out non-zero elements and count zeros\n non_zeros = [x for x in arr if x != 0]\n num_zeros = len(arr) - len(non_zeros)\n \n # Create the new list with non-zeros followed by zeros\n result = non_zeros + [0] * num_zeros\n \n return result", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n # Use list comprehension to filter out non-zero elements\n non_zero = [i for i in nums if i != 0]\n \n # Calculate the number of zeroes to append\n num_zeros = len(nums) - len(non_zero)\n \n # Extend the non-zero list with zeroes\n return non_zero + [0] * num_zeros", "matching_cluster_idx": 6}, {"solution": "def move_zero(lst):\n # Remove all zeroes and count them\n non_zeroes = [x for x in lst if x != 0]\n num_zeroes = len(lst) - len(non_zeroes)\n \n # Create a new list with non-zeroes and append the correct number of zeroes\n result = non_zeroes + [0] * num_zeroes\n \n return result", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n # Initialize the position to place the next non-zero element\n place_at = 0\n \n # Iterate through each number in the list\n for num in nums:\n # If the current number is not zero, place it at the current position and increment the position\n if num != 0:\n nums[place_at] = num\n place_at += 1\n \n # Fill the remaining positions with zeros\n for i in range(place_at, len(nums)):\n nums[i] = 0\n \n return nums", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n # Initialize a pointer to keep track of the position to place the next non-zero element\n position = 0\n \n # Iterate through each number in the list\n for num in nums:\n # If the current number is not zero, place it at the 'position' index and increment the position\n if num != 0:\n nums[position] = num\n position += 1\n \n # Fill the remaining positions in the list with zero\n while position < len(nums):\n nums[position] = 0\n position += 1\n \n # Return the modified list\n return nums", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n # Initialize a pointer for the position to place non-zero elements\n j = 0\n \n # Move all non-zero elements to the beginning of the list\n for i in range(len(nums)):\n if nums[i] != 0:\n nums[i], nums[j] = nums[j], nums[i] # Swap non-zero element to the front\n j += 1\n \n # Fill the rest of the list with zeros\n for i in range(j, len(nums)):\n nums[i] = 0\n \n return nums", "matching_cluster_idx": 6}, {"solution": "def move_zero(arr):\n # Count the number of zeroes in the array\n count_zero = arr.count(0)\n # Create a new list without zeroes and return it\n return [i for i in arr if i != 0] + [0] * count_zero", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n # Count the number of zeroes in the list\n count = nums.count(0)\n # Filter out zeroes and create a new list without zeroes\n new_list = [num for num in nums if num != 0]\n # Extend the new list with zeroes\n new_list.extend([0] * count)\n return new_list", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n # Count the number of zeroes in the list\n count = nums.count(0)\n \n # Remove all zeroes from the list\n nums = [x for x in nums if x != 0]\n \n # Append the counted zeroes to the end of the list\n return nums + [0] * count", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n # Count the number of zeroes in the list\n num_zeroes = nums.count(0)\n # Remove all zeroes from the list\n nums = [num for num in nums if num != 0]\n # Append the counted zeroes to the end of the list\n nums += [0] * num_zeroes\n return nums", "matching_cluster_idx": 6}, {"solution": "def move_zero(lst):\n # Count the number of zeroes in the list\n count = lst.count(0)\n # Remove all zeroes from the list\n while 0 in lst:\n lst.remove(0)\n # Append the same number of zeroes to the end of the list\n while count:\n lst.append(0)\n count -= 1\n return lst", "matching_cluster_idx": 2}, {"solution": "def move_zero(nums):\n non_zero_index = 0 # Initialize an index to place the next non-zero element\n \n # Move all non-zero elements to the beginning of the list\n for i in range(len(nums)):\n if nums[i] != 0:\n nums[non_zero_index] = nums[i]\n non_zero_index += 1\n \n # Fill the remaining positions in the list with zeros\n for i in range(non_zero_index, len(nums)):\n nums[i] = 0\n \n return nums", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n # Count the number of zeroes in the list\n zeroes = nums.count(0)\n # Remove all zeroes from the list\n nums = [num for num in nums if num != 0]\n # Extend the list with the count of zeroes\n nums.extend([0] * zeroes)\n return nums", "matching_cluster_idx": 6}, {"solution": "def move_zero(arr):\n n = len(arr) # Get the length of the list\n \n count = 0 # Initialize a count to track the number of non-zero elements\n \n # Traverse the array from the start\n for i in range(n):\n # If the current element is non-zero, move it to the position of count\n if arr[i] != 0:\n arr[count] = arr[i]\n count += 1\n \n # Fill the remaining positions with zeroes\n while count < n:\n arr[count] = 0\n count += 1\n \n return arr # Return the modified array with all zeroes at the end", "matching_cluster_idx": 6}, {"solution": "def move_zero(lst):\n # Calculate the number of zeroes in the list\n zeroes = lst.count(0)\n # Remove all zeroes from the list\n lst = [i for i in lst if i != 0]\n # Append the count of zeroes to the end of the list\n lst += [0] * zeroes\n return lst", "matching_cluster_idx": 6}, {"solution": "def move_zero(arr):\n # Count the number of zeroes in the array\n cnt = arr.count(0)\n \n # Filter out zeroes and extend the list with the same number of zeroes\n arr = [i for i in arr if i != 0] + [0] * cnt\n \n return arr", "matching_cluster_idx": 6}, {"solution": "def move_zero(lst):\n # Count the number of zeroes in the list\n zero_count = lst.count(0)\n # Remove all zeroes from the list\n lst = [x for x in lst if x != 0]\n # Append the number of zeroes to the end of the list\n return lst + [0] * zero_count", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n # Count the number of zeroes in the list\n count_zeroes = nums.count(0)\n # Filter out zeroes and collect the rest of the numbers\n result = [num for num in nums if num != 0]\n # Extend the result list with zeroes\n result.extend([0] * count_zeroes)\n return result", "matching_cluster_idx": 6}]}, "Mbpp/633": {"dps": 95.8130081300813, "dps_norm": 60.83333333333333, "pass@1": 52.0, "profiled": [{"solution": "def pair_xor_Sum(arr, n):\n # Initialize the result to 0\n xor_sum = 0\n \n # Iterate over each bit position from 0 to 31 (since we are dealing with 32-bit integers)\n for i in range(32):\n # Initialize counters for the number of times bit i is set to 0 and 1\n count0 = 0\n count1 = 0\n \n # Count the number of 1s and 0s at the i-th bit position in the list\n for j in range(n):\n if arr[j] & (1 << i):\n count1 += 1\n else:\n count0 += 1\n \n # Calculate the contribution of the i-th bit to the overall XOR sum\n xor_sum += (count0 * count1 * (1 << i))\n \n # Return the total XOR sum\n return xor_sum", "matching_cluster_idx": 3}, {"solution": "def pair_xor_Sum(arr, n):\n # Initialize the sum of XOR to 0\n sum_xor = 0\n \n # Iterate over all pairs (i, j)\n for i in range(n):\n for j in range(i + 1, n):\n # Calculate the XOR for the current pair and add it to the sum\n sum_xor += (arr[i] ^ arr[j])\n \n # Return the total sum of XOR for all pairs\n return sum_xor", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(arr, n):\n # Initialize the answer\n ans = 0\n \n # Iterate over all bits of an integer\n for i in range(32):\n # Count the number of elements which have ith bit set\n cnt = 0\n for j in range(n):\n if arr[j] & (1 << i):\n cnt += 1\n \n # If ith bit is set in any number, then contribute\n # (cnt * (n - cnt) * pow(2, i)) to the answer\n if cnt > 0:\n ans += cnt * (n - cnt) * (1 << i)\n \n # Return the final sum\n return ans", "matching_cluster_idx": 4}, {"solution": "def pair_xor_Sum(arr, n):\n # Initialize result\n res = 0\n \n # Traverse all bits\n for i in range(0, 32):\n # Find count of set bits at i'th position in all numbers\n count = 0\n for j in range(0, n):\n if (arr[j] & (1 << i)):\n count += 1\n \n # Add \"count * (n - count) * (1 << i)\" to result\n res += count * (n - count) * (1 << i)\n \n return res", "matching_cluster_idx": 4}, {"solution": "def pair_xor_Sum(arr, n):\n # Initialize the result variable\n res = 0\n \n # Iterate through all pairs\n for i in range(0, n):\n for j in range(i + 1, n):\n # Calculate the xor and add it to the result\n res += (arr[i] ^ arr[j])\n \n return res", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(arr, n):\n # Initialize the sum variable to store the sum of XOR values\n sum = 0\n \n # Iterate through each element of the array\n for i in range(n):\n # Iterate through each element of the array after the current element\n for j in range(i + 1, n):\n # Calculate the XOR of the current pair and add it to the sum\n sum += (arr[i] ^ arr[j])\n \n # Return the total sum of XOR values of all pairs\n return sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(nums, n):\n # Calculate the total sum of XORs of all pairs\n xorSum = sum(nums[i] ^ nums[j] for i in range(n) for j in range(i + 1, n))\n return xorSum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(nums, size): \n xor_sum = 0 # Initialize the sum of XOR values\n\n # Iterate through the list\n for i in range(size): \n # For each element, check all other elements\n for j in range(i + 1, size): \n # Compute the XOR of the current pair and add to the sum\n xor_sum = xor_sum + (nums[i] ^ nums[j]) \n \n return xor_sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(arr, n):\n # Initialize the answer with 0\n answer = 0\n \n # Iterate over each bit position (31 to 0 for 32-bit integers)\n for i in range(32):\n # Count the number of elements with the i-th bit set\n c1 = 0\n for j in range(n):\n if arr[j] & (1 << i):\n c1 += 1\n \n # Calculate the number of pairs with the i-th bit set in XOR\n c2 = c1 * (n - c1)\n \n # Add to the answer considering the contribution of the i-th bit\n answer += (c2 << i)\n \n return answer", "matching_cluster_idx": 4}, {"solution": "def pair_xor_Sum(A, N):\n # Iterate over all possible pairs using two nested loops\n sum = 0\n for i in range(N):\n for j in range(i + 1, N):\n # Calculate the XOR of the current pair and add it to the sum\n sum += A[i] ^ A[j]\n # Return the total sum of XOR of all pairs\n return sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(arr, N):\n # Calculate the sum of XOR of all pairs\n return sum((arr[i] ^ arr[j]) for i in range(N) for j in range(i + 1, N))", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(arr, n):\n # Initialize the result\n result = 0\n \n # Iterate through the array from the first to the second last element\n for i in range(n - 1):\n # Iterate through the array from the element next to i to the last element\n for j in range(i + 1, n):\n # XOR the elements at i and j and add the result to the total result\n result += arr[i] ^ arr[j]\n \n # Return the total XOR sum of all pairs\n return result", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(arr, n):\n xor_Sum = 0 # Initialize the variable to store the sum of XORs\n \n # Iterate over all pairs using nested loops\n for i in range(n):\n for j in range(i + 1, n):\n xor_Sum += (arr[i] ^ arr[j]) # XOR the current pair and add to the sum\n \n return xor_Sum # Return the computed sum of XORs", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(arr, n): \n # Calculate the sum of xor of all pairs \n res = 0\n for i in range(n): \n # For each bit position \n for j in range(i, n): \n # Calculate the xor of the current pair and add it to the result \n res += arr[i] ^ arr[j] \n return res", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(arr, N):\n # Initialize the sum of XOR values\n res = 0\n \n # Iterate over each bit position (0 to 31)\n for i in range(32):\n # Count the number of elements with the i-th bit set\n cnt = 0\n for j in range(N):\n if arr[j] & (1 << i):\n cnt += 1\n \n # Calculate the number of pairs with the i-th bit set\n res += (1 << i) * cnt * (N - cnt)\n \n # Return the final result\n return res", "matching_cluster_idx": 4}, {"solution": "def pair_xor_Sum(arr, n):\n # Initialize total_sum to 0\n total_sum = 0\n \n # Iterate over each bit position from 0 to 31 (for 32-bit numbers)\n for i in range(32):\n # Initialize count of 1s to 0\n set_bit = 0\n \n # Iterate over each element in the array\n for j in range(n):\n # Count how many numbers have the i-th bit set\n if arr[j] & (1 << i):\n set_bit += 1\n \n # Calculate the contribution of this bit to the total sum\n total_sum += set_bit * (n - set_bit) * (1 << i)\n \n return total_sum", "matching_cluster_idx": 4}, {"solution": "def pair_xor_Sum(arr, N):\n ans = 0\n # Iterate over each bit position from 0 to 31 (32 bits)\n for i in range(32):\n # Count the number of elements with the i-th bit set\n count = 0\n for j in range(N):\n if (arr[j] & (1 << i)):\n count += 1\n # Calculate the contribution of the i-th bit to the final answer\n ans += (1 << i) * count * (N - count)\n return ans", "matching_cluster_idx": 4}, {"solution": "def pair_xor_Sum(arr, n):\n # Initialize the sum of XOR results\n result = 0\n \n # Iterate over all possible pairs (i, j)\n for i in range(n):\n for j in range(i + 1, n):\n # XOR the current pair and add to the result\n result += arr[i] ^ arr[j]\n \n return result", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(arr, n):\n # Initialize the sum to 0\n s = 0\n \n # Iterate over each element in the array\n for i in range(n):\n # Iterate over the elements that come after the current element\n for j in range(i + 1, n):\n # Add the xor of the current pair to the sum\n s += arr[i] ^ arr[j]\n \n # Return the total sum of xor for all pairs\n return s", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(arr, N):\n # Initialize sum of xor of all pairs to 0\n S = 0\n \n # Iterate over the array to find xor of all pairs\n for i in range(N):\n for j in range(i + 1, N):\n # Calculate xor of the pair and add to the sum\n S += (arr[i] ^ arr[j])\n \n # Return the total sum of xor of all pairs\n return S", "matching_cluster_idx": 2}]}, "Mbpp/644": {"dps": 48.324468085106375, "dps_norm": 65.66666666666667, "pass@1": 75.0, "profiled": [{"solution": "def reverse_Array_Upto_K(arr, K):\n # Reverse the elements from the start up to K\n arr[:K] = arr[:K][::-1]\n return arr", "matching_cluster_idx": 13}, {"solution": "def reverse_Array_Upto_K(array, K):\n # Reverse elements from index 0 to K-1\n array[:K] = reversed(array[:K])\n return array", "matching_cluster_idx": 12}, {"solution": "def reverse_Array_Upto_K(arr, k):\n # Reverse the elements from index 0 to k-1 using slicing\n arr[:k] = arr[:k][::-1]\n return arr", "matching_cluster_idx": 13}, {"solution": "def reverse_Array_Upto_K(arr, k):\n # Loop through the array from the start to the index k (exclusive)\n for i in range(k // 2):\n # Swap the elements at the current index i and k-i-1\n arr[i], arr[k - i - 1] = arr[k - i - 1], arr[i]\n return arr", "matching_cluster_idx": 6}, {"solution": "def reverse_Array_Upto_K(array, K):\n # Reverse the elements from the start to the Kth position (exclusive)\n array[:K] = array[:K][::-1]\n return array", "matching_cluster_idx": 13}, {"solution": "def reverse_Array_Upto_K(A, K):\n # Reverse the elements from the start to the K-th index\n A[0:K] = A[K-1::-1]\n return A", "matching_cluster_idx": 14}, {"solution": "def reverse_Array_Upto_K(arr, k):\n # Create a copy of the array to avoid modifying the original array\n new_arr = arr.copy()\n \n # Reverse the elements from index 0 to k-1\n for i in range(k // 2):\n new_arr[i], new_arr[k - 1 - i] = new_arr[k - 1 - i], new_arr[i]\n \n return new_arr", "matching_cluster_idx": 5}, {"solution": "def reverse_Array_Upto_K(arr, k):\n # Reverse elements from 0 to k-1\n arr[:k] = reversed(arr[:k])\n return arr", "matching_cluster_idx": 12}, {"solution": "def reverse_Array_Upto_K(A, K):\n # Reverse elements from the start up to index K (inclusive)\n for i in range(0, K // 2):\n A[i], A[K - i - 1] = A[K - i - 1], A[i]\n # Return the modified array\n return A", "matching_cluster_idx": 6}, {"solution": "def reverse_Array_Upto_K(arr, K):\n # Iterate through the array up to the K-th element\n for i in range(0, K//2):\n # Swap the elements at the current position and the corresponding position from the end\n arr[i], arr[K-i-1] = arr[K-i-1], arr[i]\n return arr", "matching_cluster_idx": 6}, {"solution": "def reverse_Array_Upto_K(arr, k):\n # Loop through the array from the start to the k-th position\n for i in range(int(k / 2)):\n # Swap elements at positions i and k-i-1\n arr[i], arr[k - i - 1] = arr[k - i - 1], arr[i]\n # Return the modified array\n return arr", "matching_cluster_idx": 6}, {"solution": "def reverse_Array_Upto_K(A, K):\n # Initialize start and end pointers\n start = 0\n end = K - 1\n \n # Loop to reverse elements from start to end\n while start < end:\n # Swap elements at start and end\n A[start], A[end] = A[end], A[start]\n # Move the start pointer to the right\n start += 1\n # Move the end pointer to the left\n end -= 1\n \n # Return the modified array\n return A", "matching_cluster_idx": 7}, {"solution": "def reverse_Array_Upto_K(arr, k):\n # Slice the array up to position k and reverse it\n # Concatenate it with the rest of the array unchanged\n return arr[:k][::-1] + arr[k:]", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, K):\n # Loop through the first K elements of the array\n for i in range(K // 2):\n # Swap the elements at indices i and K-i-1\n arr[i], arr[K-i-1] = arr[K-i-1], arr[i]\n return arr", "matching_cluster_idx": 6}, {"solution": "def reverse_Array_Upto_K(arr, K):\n # Reverse the elements from index 0 to K-1\n i = 0\n while i < K // 2:\n temp = arr[i]\n arr[i] = arr[K - i - 1]\n arr[K - i - 1] = temp\n i += 1\n return arr", "matching_cluster_idx": 4}, {"solution": "def reverse_Array_Upto_K(A, K):\n # Reverse the elements of the array from the start up to and including the Kth position\n for i in range(0, K // 2):\n A[i], A[K - i - 1] = A[K - i - 1], A[i]\n # Return the modified array\n return A", "matching_cluster_idx": 6}, {"solution": "def reverse_Array_Upto_K(arr, k):\n # Create a copy of the array up to the k-th element (index k-1)\n lst = arr[:k]\n \n # Reverse the copied array\n lst = lst[::-1]\n \n # Extend the reversed array with the remaining elements of the original array\n lst.extend(arr[k:])\n \n # Return the modified array\n return lst", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, K):\n # Reverse the subarray from index 0 to K-1\n arr[:K] = reversed(arr[:K])\n return arr", "matching_cluster_idx": 12}, {"solution": "def reverse_Array_Upto_K(arr, K):\n # Reverse the elements from the start up to the Kth index\n return arr[:K][::-1] + arr[K:]", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(A, K):\n # Loop through the array from the start to the K-th element\n for i in range(int(K / 2)):\n # Swap elements symmetrically from the start and end of the array\n A[i], A[K - i - 1] = A[K - i - 1], A[i]\n # Return the modified array with the first K elements reversed\n return A", "matching_cluster_idx": 6}]}, "Mbpp/720": {"dps": 48.24175824175824, "dps_norm": 72.0, "pass@1": 99.0, "profiled": [{"solution": "def add_dict_to_tuple(test_tup, K):\n # Extend the tuple by converting it to a list, appending the dictionary, and then converting back to a tuple\n res = tuple(list(test_tup) + [K])\n return res", "matching_cluster_idx": 2}, {"solution": "def add_dict_to_tuple(test_tup, dict_to_add):\n # Convert the tuple to a list, append the dictionary, and convert back to a tuple\n res = tuple(list(test_tup) + [dict_to_add])\n return res", "matching_cluster_idx": 1}, {"solution": "def add_dict_to_tuple(test_tup, add_dict):\n # Append the dictionary to the tuple using tuple concatenation\n res = test_tup + (add_dict,)\n return res", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(test_tup, dict_val):\n \"\"\"\n This function takes a tuple and a dictionary as input and returns a new tuple\n with the dictionary added as its last element.\n \"\"\"\n # Append the dictionary to the tuple\n res = test_tup + (dict_val,)\n \n return res", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(test_tup, dict_add):\n \"\"\"\n Add a dictionary to the tuple and return the updated tuple.\n\n Args:\n test_tup (tuple): The original tuple to which the dictionary will be added.\n dict_add (dict): The dictionary to add to the tuple.\n\n Returns:\n tuple: The updated tuple with the dictionary added as its last element.\n \"\"\"\n # Convert the tuple to a list, append the dictionary, then convert back to a tuple\n res = tuple(list(test_tup) + [dict_add])\n return res", "matching_cluster_idx": 1}, {"solution": "def add_dict_to_tuple(tup, dictionary):\n # Convert the tuple to a list\n temp_list = list(tup)\n # Append the dictionary to the list\n temp_list.append(dictionary)\n # Convert the list back to a tuple\n return tuple(temp_list)", "matching_cluster_idx": 3}, {"solution": "def add_dict_to_tuple(test_tup, dictx):\n # Using the '+=' operator to concatenate a tuple containing the dictionary\n test_tup += (dictx,)\n return test_tup", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(test_tup, res_dict):\n # Concatenate the tuple with the dictionary inside another tuple\n res = test_tup + (res_dict,)\n return (res)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(test_tup, dict_test):\n # Convert the tuple to a list to allow modification\n res = list(test_tup)\n # Append the dictionary to the list\n res.append(dict_test)\n # Convert the list back to a tuple\n res = tuple(res)\n return res", "matching_cluster_idx": 3}, {"solution": "def add_dict_to_tuple(test_tup, K):\n # Append the dictionary to the tuple\n res = test_tup + (K,)\n return res", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(test_tup, dic):\n # Convert the tuple to a list, append the dictionary to the list, and convert back to a tuple\n res = tuple(list(test_tup) + [dic])\n return res", "matching_cluster_idx": 1}, {"solution": "def add_dict_to_tuple(test_tup, res_dict):\n # Convert the tuple to a list to allow modification\n temp_list = list(test_tup)\n \n # Append the dictionary to the list\n temp_list.append(res_dict)\n \n # Convert the list back to a tuple\n res = tuple(temp_list)\n \n return res", "matching_cluster_idx": 3}, {"solution": "def add_dict_to_tuple(test_tup, K):\n \"\"\"\n This function takes a tuple and a dictionary as arguments and returns a new tuple with the dictionary added as its last element.\n \n :param test_tup: Tuple to which the dictionary will be added.\n :param K: Dictionary to be added to the tuple.\n :return: A new tuple with the dictionary added.\n \"\"\"\n # Convert the tuple to a list, append the dictionary, and convert back to a tuple\n res = tuple(list(test_tup) + [K])\n return res", "matching_cluster_idx": 1}, {"solution": "def add_dict_to_tuple(test_tup, test_dict):\n \"\"\"\n This function takes a tuple and a dictionary as arguments and returns a new tuple\n with the dictionary appended as its last element.\n \n :param test_tup: Tuple to which the dictionary will be appended\n :param test_dict: Dictionary to be appended to the tuple\n :return: New tuple with the dictionary appended\n \"\"\"\n # Append the dictionary to the tuple\n res = test_tup + (test_dict,)\n return res", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(test_tup, res_dict):\n # Convert the tuple to a list, append the dictionary, and convert back to a tuple\n res = tuple(list(test_tup) + [res_dict])\n return res", "matching_cluster_idx": 1}, {"solution": "def add_dict_to_tuple(test_tup, dic):\n # Convert the tuple to a list, append the dictionary, and convert back to a tuple\n res = tuple(list(test_tup) + [dic])\n return res", "matching_cluster_idx": 1}, {"solution": "def add_dict_to_tuple(test_tup, res_dict):\n # Add the dictionary to the tuple using the + operator\n res = test_tup + (res_dict,)\n return res", "matching_cluster_idx": 4}, {"solution": "from copy import deepcopy\ndef add_dict_to_tuple(test_tup, K):\n # Creating a deep copy of the tuple to avoid modifying the original tuple\n res = deepcopy(test_tup)\n # Appending the dictionary to the copied tuple\n res += (K,)\n return res", "matching_cluster_idx": 0}, {"solution": "def add_dict_to_tuple(test_tup, dict_to_add):\n \"\"\"\n This function takes a tuple and a dictionary as arguments.\n It converts the tuple into a list, appends the dictionary to the list,\n and then converts the list back into a tuple.\n \n Args:\n test_tup (tuple): The original tuple to which the dictionary will be added.\n dict_to_add (dict): The dictionary to add to the tuple.\n \n Returns:\n tuple: A new tuple containing the original elements and the added dictionary.\n \"\"\"\n # Convert the tuple to a list\n res = list(test_tup)\n \n # Append the dictionary to the list\n res.append(dict_to_add)\n \n # Convert the list back to a tuple\n return tuple(res)", "matching_cluster_idx": 3}, {"solution": "def add_dict_to_tuple(test_tup, dict_to_add):\n # Append the dictionary to the tuple and convert it back to a tuple\n res = tuple(test_tup + (dict_to_add,))\n return res", "matching_cluster_idx": 4}]}, "Mbpp/725": {"dps": 65.40983606557377, "dps_norm": 69.375, "pass@1": 35.0, "profiled": [{"solution": "import re\ndef extract_quotation(word):\n # Use regular expression to find all occurrences of text between quotation marks\n return re.findall(r'\"(.*?)\"', word)", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(s):\n # Use a regular expression to find all occurrences of text between quotation marks\n res = re.findall(r'\"(.*?)\"', s)\n return res", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(text):\n # Find all occurrences of text enclosed in double quotes\n data = re.findall(r'\"(.*?)\"', text)\n return data", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(text):\n # Use regular expression to find all values between quotation marks\n result = re.findall(r'\\\"(.*?)\\\"', text)\n return result", "matching_cluster_idx": 4}, {"solution": "def extract_quotation(text):\n # Initialize an empty list to store the extracted values\n words = []\n \n # Convert the text to a list of characters for easier manipulation\n l = list(text)\n \n # Variables to track the positions of the quotation marks\n open_index = 0\n close_index = 0\n \n # Iterate through the list of characters\n for i in range(len(l)):\n if l[i] == '\"':\n # Toggle the state between open and close quotation mark\n if close_index == 0:\n open_index = i\n close_index = 1\n else:\n close_index = 0\n # Extract the substring between the quotation marks\n words.append(text[open_index + 1 : i])\n open_index = 0\n \n # Return the list of extracted words\n return words", "matching_cluster_idx": 2}, {"solution": "import re\ndef extract_quotation(input_str):\n # Use regular expression to find all values enclosed in double quotes\n result = re.findall(r'\"(.*?)\"', input_str)\n return result", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(input_str):\n # Use regular expression to find all occurrences of text within double quotation marks\n matched_items = re.findall(r'\"(.*?)\"', input_str)\n return matched_items", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(mstr):\n # Use regular expression to find all words enclosed in quotation marks\n return re.findall(r'\"(.*?)\"', mstr)", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(text):\n # Use regular expression to find all text between quotation marks\n return re.findall(r'\"(.*?)\"', text)", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(str1):\n # Using regular expression to find all text enclosed in quotation marks\n result = re.findall(r'\"(.*?)\"', str1)\n return result", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(s):\n # Use regular expression to find all substrings within quotation marks\n return re.findall(r'\"(.*?)\"', s)", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(input_string):\n # Use regular expression to find text within quotation marks\n pattern = '[\"](.*?)[\"]'\n # Find all matches in the input string\n match = re.findall(pattern, input_string)\n \n return match", "matching_cluster_idx": 4}, {"solution": "import re\ndef extract_quotation(strings):\n # Use regular expression to find all sequences of characters\n # enclosed in double quotes and return them as a list\n return re.findall(r'\"(.*?)\"', strings)", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(string):\n # Using regular expression to find all text within quotation marks\n result = re.findall(r'\"(.*?)\"', string)\n return result", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(data):\n # Use regular expression to find all substrings between double quotation marks\n res = re.findall(r'\"(.*?)\"', data)\n return res", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(text):\n # Use regular expression to find all occurrences of text within quotation marks\n return re.findall(r'\"(.*?)\"', text)", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(str1):\n # Use a regular expression to find text within quotation marks\n result = re.findall(r'\"(.*?)\"', str1)\n return result", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(s):\n # Use regex to find all sequences of characters between quotation marks\n result = re.findall(r'\"(.*?)\"', s)\n # Return the list of extracted values\n return result", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(text):\n # Use regular expression to find all words within double quotes\n words_within_quotes = re.findall(r'\\\"(.*?)\\\"', text)\n return words_within_quotes", "matching_cluster_idx": 4}, {"solution": "def extract_quotation(s):\n # Initialize an empty list to store the extracted values\n arr = []\n # Initialize indices to track the current position in the string\n i, j = 0, 0\n \n # Loop through the string to find pairs of quotation marks\n while i < len(s) and j < len(s):\n # Find the next opening quotation mark\n i = s.find('\"', j)\n # If no opening quotation mark is found, break the loop\n if i == -1:\n break\n # Find the following closing quotation mark\n j = s.find('\"', i + 1)\n # If no closing quotation mark is found, break the loop\n if j == -1:\n break\n \n # Extract the value between the quotation marks and add it to the list\n arr.append(s[i + 1 : j])\n # Move the index j forward to continue searching for more pairs\n j += 1\n \n # Return the list of extracted values\n return arr", "matching_cluster_idx": 2}]}, "Mbpp/732": {"dps": 70.03875968992249, "dps_norm": 83.5, "pass@1": 87.0, "profiled": [{"solution": "def replace_specialchar(s):\n # Using the replace method to substitute spaces, commas, and dots with a colon\n s = s.replace(' ', ':').replace(',', ':').replace('.', ':')\n return s", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(test_str):\n # Replace spaces, commas, or dots with a colon\n res = test_str.replace(\" \", \":\").replace(\",\", \":\").replace(\".\", \":\")\n return res", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(test_str):\n # Replace spaces, commas, and dots with a colon\n res = test_str.replace(' ', ':').replace(',', ':').replace('.', ':')\n return res", "matching_cluster_idx": 9}, {"solution": "import re\ndef replace_specialchar(S):\n # Use regular expression to replace spaces, commas, or dots with a colon\n return re.sub(\"[ ,.]\", \":\", S)", "matching_cluster_idx": 4}, {"solution": "def replace_specialchar(input_string):\n # Replace spaces, commas, and dots with a colon using string replacement\n replaced_string = input_string.replace(' ', ':').replace(',', ':').replace('.', ':')\n # Return the modified string\n return replaced_string", "matching_cluster_idx": 9}, {"solution": "import re\ndef replace_specialchar(text):\n # Using regular expression to replace spaces, commas, or dots with a colon\n return re.sub(\"[ ,.]\", \":\", text)", "matching_cluster_idx": 4}, {"solution": "def replace_specialchar(S):\n # Replace all spaces, commas, and dots with a colon using the translate method\n res = S.translate(S.maketrans(' ,.', ':::'))\n return res", "matching_cluster_idx": 8}, {"solution": "def replace_specialchar(s):\n # Replace spaces, commas, or dots with a colon\n return s.replace(' ', ':').replace(',', ':').replace('.', ':')", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(s):\n # Replace all occurrences of spaces, commas, or dots with a colon\n s = s.replace(' ', ':').replace(',', ':').replace('.', ':')\n return s", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(string):\n # Replace all spaces, commas, and dots with a colon\n new_string = string.replace(\" \", \":\").replace(\",\", \":\").replace(\".\", \":\")\n return new_string", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(s):\n # Using the translate method with a translation table\n # That maps space, comma, and dot to a colon\n return s.translate(str.maketrans(\" ,.\", \"|||\")).replace(\"|\", \":\")", "matching_cluster_idx": 7}, {"solution": "def replace_specialchar(street):\n # Replace spaces, commas, and dots with a colon\n return street.replace(' ', ':').replace(',', ':').replace('.', ':')", "matching_cluster_idx": 9}, {"solution": "import re\ndef replace_specialchar(text):\n # Use regular expression to replace spaces, commas, or dots with a colon\n return re.sub(r\"[ ,.]\", \":\", text)", "matching_cluster_idx": 4}, {"solution": "def replace_specialchar(S):\n # Replace all spaces, commas, or dots with a colon\n S = S.replace(\" \", \":\")\n S = S.replace(\",\", \":\")\n S = S.replace(\".\", \":\")\n return S", "matching_cluster_idx": 9}, {"solution": "import re\ndef replace_specialchar(text):\n # Using re.sub() to replace spaces, commas, or dots with a colon\n return re.sub('[ ,.]', ':', text)", "matching_cluster_idx": 4}, {"solution": "def replace_specialchar(st):\n # Replace spaces, commas, and dots with colons\n return st.replace(' ', ':').replace(',', ':').replace('.', ':')", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(str1):\n # Replace spaces, commas, and dots with a colon\n result = str1.replace(' ', ':').replace(',', ':').replace('.', ':')\n return result", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(s):\n # Replace spaces with colons\n s = s.replace(' ', ':')\n # Replace commas with colons\n s = s.replace(',', ':')\n # Replace dots with colons\n s = s.replace('.', ':')\n # Return the modified string\n return s", "matching_cluster_idx": 9}, {"solution": "import re\ndef replace_specialchar(test_str):\n # Use regular expression to replace spaces, commas, or dots with a colon\n result = re.sub(\"[ ,.]\", \":\", test_str)\n return result", "matching_cluster_idx": 4}, {"solution": "import re\ndef replace_specialchar(string):\n # Replace spaces, commas, and dots with a colon\n return re.sub(\"[ ,.]\", \":\", string)", "matching_cluster_idx": 4}]}, "Mbpp/740": {"dps": 74.52727272727273, "dps_norm": 66.66666666666667, "pass@1": 100.0, "profiled": [{"solution": "from typing import Tuple, Dict\ndef tuple_to_dict(test_tup: Tuple[int, ...]) -> Dict[int, int]:\n \"\"\"\n Convert a tuple of adjacent elements into a dictionary.\n\n Parameters:\n test_tup (Tuple[int, ...]): A tuple containing elements to be converted into a dictionary.\n\n Returns:\n Dict[int, int]: A dictionary with key-value pairs derived from the tuple.\n \"\"\"\n # Using dictionary comprehension to create the dictionary\n res = {test_tup[idx]: test_tup[idx + 1] for idx in range(0, len(test_tup), 2)}\n return res", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(test_tup):\n # Initialize an empty dictionary to store the result\n res = {}\n # Iterate over the tuple with a step of 2 to create key-value pairs\n for i in range(0, len(test_tup), 2):\n res[test_tup[i]] = test_tup[i + 1]\n return res", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(test_tup):\n # Initialize an empty dictionary to store the key-value pairs\n res = {}\n \n # Iterate over the tuple elements using a step of 2 to get pairs\n for ele in range(0, len(test_tup), 2):\n # Assign the current element as key and the next element as value\n res[test_tup[ele]] = test_tup[ele + 1]\n \n return res", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(test_tup):\n # Initialize an empty dictionary\n res = dict()\n # Iterate over the tuple in steps of 2 to create key-value pairs\n for ele in range(0, len(test_tup), 2):\n # Assign each pair to the dictionary\n res[test_tup[ele]] = test_tup[ele + 1]\n return res", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(test_tup):\n \"\"\"\n Convert a tuple to a dictionary using adjacent elements.\n \n Parameters:\n test_tup (tuple): A tuple with even number of elements.\n \n Returns:\n dict: A dictionary with elements from the tuple as key-value pairs.\n \"\"\"\n # Using dictionary comprehension to create key-value pairs\n res = {test_tup[idx]: test_tup[idx + 1] for idx in range(0, len(test_tup), 2)}\n return res", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(test_tup):\n # Create a dictionary using dict comprehension\n # Zip function pairs up elements from two tuples, effectively\n # treating the tuple as key-value pairs.\n res = {test_tup[idx]: test_tup[idx + 1] for idx in range(0, len(test_tup) - 1, 2)}\n return res", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(test_tup):\n # Initialize an empty dictionary to store the result\n res = {}\n # Iterate over the tuple using a loop\n for idx in range(0, len(test_tup) - 1, 2):\n # Use the current element as the key and the next element as the value\n res[test_tup[idx]] = test_tup[idx + 1]\n # Return the resulting dictionary\n return res", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(test_tup):\n # Create a dictionary using dictionary comprehension and zip function\n res = {test_tup[i]: test_tup[i + 1] for i in range(0, len(test_tup) - 1, 2)}\n return res", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(test_tup):\n # Convert tuple to dictionary using dictionary comprehension\n res = dict(test_tup[idx : idx + 2] for idx in range(0, len(test_tup), 2))\n return res", "matching_cluster_idx": 4}, {"solution": "def tuple_to_dict(test_tup):\n # Initialize an empty dictionary\n res_dict = {}\n # Iterate through the tuple in steps of 2 to pair elements\n for ele in range(0, len(test_tup), 2):\n # Assign each pair of adjacent elements to the dictionary\n res_dict[test_tup[ele]] = test_tup[ele + 1]\n return res_dict", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(test_tup):\n # Initialize an empty dictionary\n res = dict()\n # Iterate over the tuple in steps of 2\n for ele in range(0, len(test_tup), 2):\n # Assign adjacent elements as key-value pairs\n res[test_tup[ele]] = test_tup[ele + 1]\n return res", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(test_tup):\n # Convert the tuple into a dictionary using a dictionary comprehension\n # The comprehension iterates over pairs of elements, taking the first as the key and the second as the value\n res = dict(test_tup[idx:idx + 2] for idx in range(0, len(test_tup), 2))\n return res", "matching_cluster_idx": 4}, {"solution": "def tuple_to_dict(test_tup):\n # Using dictionary comprehension to create a dictionary from the tuple\n res = {test_tup[idx]: test_tup[idx + 1] for idx in range(0, len(test_tup) - 1, 2)}\n return res", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(test_tup):\n # Using dictionary comprehension to convert tuple pairs into key-value dictionary\n res = {test_tup[idx]: test_tup[idx + 1] for idx in range(0, len(test_tup), 2)}\n return res", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(test_tup):\n # Using dictionary comprehension to pair adjacent elements\n res = {test_tup[idx]: test_tup[idx + 1] for idx in range(0, len(test_tup) - 1, 2)}\n return res", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(test_tup):\n # Use the zip function to pair each element with its successor\n # Slice the tuple to stop one element short to avoid pairing with an empty tuple\n res = dict(zip(test_tup[0::2], test_tup[1::2]))\n return res", "matching_cluster_idx": 8}, {"solution": "def tuple_to_dict(test_tup):\n # Using dictionary comprehension to pair adjacent elements\n res = {test_tup[idx]: test_tup[idx + 1] for idx in range(0, len(test_tup) - 1, 2)}\n return res", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(test_tup):\n # Use zip function to pair adjacent elements and convert to dictionary\n res = dict(test_tup[idx:idx + 2] for idx in range(0, len(test_tup), 2))\n return res", "matching_cluster_idx": 4}, {"solution": "def tuple_to_dict(test_tup):\n # Initialize an empty dictionary to store the key-value pairs\n res = dict()\n \n # Iterate over the tuple in steps of 2 to form key-value pairs\n for ele in range(0, len(test_tup), 2):\n # Assign the current element as key and the next element as value\n res[test_tup[ele]] = test_tup[ele + 1]\n \n # Return the resulting dictionary\n return res", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(test_tup):\n # Using dictionary comprehension to convert tuple to dictionary\n # Adjacent elements are converted into key-value pairs\n res = {test_tup[idx]: test_tup[idx + 1] for idx in range(0, len(test_tup) - 1, 2)}\n return res", "matching_cluster_idx": 5}]}, "Mbpp/744": {"dps": 28.32191780821918, "dps_norm": 50.833333333333336, "pass@1": 90.0, "profiled": [{"solution": "def check_none(test_tup):\n # Initialize result as False\n res = False\n # Iterate through each element in the tuple\n for ele in test_tup:\n # Check if the current element is None\n if ele is None:\n # Set result to True if any element is None\n res = True\n return res", "matching_cluster_idx": 1}, {"solution": "def check_none(test_tup):\n # Check if 'None' is present in the tuple\n res = any(ele is None for ele in test_tup)\n return res", "matching_cluster_idx": 1}, {"solution": "def check_none(test_tuple):\n # Check if any element in the tuple is None\n res = any(val is None for val in test_tuple)\n return res", "matching_cluster_idx": 1}, {"solution": "def check_none(test_tup):\n # Check if 'None' is present in the tuple\n res = any(ele is None for ele in test_tup)\n return res", "matching_cluster_idx": 1}, {"solution": "def check_none(tup):\n # Use the 'any()' function to check if any element in the tuple is 'None'\n if any(ele is None for ele in tup):\n return True # Return True if a None value is found\n return False # Return False if no None value is found", "matching_cluster_idx": 1}, {"solution": "def check_none(test_tup):\n # Initialize a variable to keep track of whether a None value is found\n flag = 0\n \n # Loop through each element in the tuple\n for ele in test_tup:\n # Check if the current element is None\n if ele is None:\n # If None is found, set the flag to 1 and break the loop\n flag = 1\n break\n \n # Return whether a None value was found\n return bool(flag)", "matching_cluster_idx": 4}, {"solution": "def check_none(test_tup):\n # Check if 'None' is present in the tuple\n res = any(var is None for var in test_tup)\n return res", "matching_cluster_idx": 1}, {"solution": "def check_none(tup):\n # Use the any() function to check if any element in the tuple is None\n return any(i is None for i in tup)", "matching_cluster_idx": 1}, {"solution": "def check_none(tup):\n # Check if the tuple contains any None values\n return None in tup", "matching_cluster_idx": 5}, {"solution": "def check_none(test_tup):\n # Using any() function to check if there is any None value in the tuple\n res = any(ele is None for ele in test_tup)\n return res", "matching_cluster_idx": 1}, {"solution": "def check_none(tup):\n # Check if the tuple contains the value None\n if None in tup:\n return True\n return False", "matching_cluster_idx": 4}, {"solution": "def check_none(test_tup):\n # Check if None is present in the tuple and return the result\n return any(ele is None for ele in test_tup)", "matching_cluster_idx": 1}, {"solution": "def check_none(test_tup):\n # Check if there is any 'None' value in the tuple\n res = any(i is None for i in test_tup)\n return res", "matching_cluster_idx": 1}, {"solution": "def check_none(input_tuple):\n # Check if 'None' is present in the input tuple using 'in' keyword\n return None in input_tuple", "matching_cluster_idx": 5}, {"solution": "def check_none(test_tup):\n # Check if the 'None' value exists in the tuple\n res = any(val is None for val in test_tup)\n return res", "matching_cluster_idx": 1}, {"solution": "def check_none(test_tup):\n # Check if any element in the tuple is None\n res = any(ele is None for ele in test_tup)\n return res", "matching_cluster_idx": 1}, {"solution": "def check_none(test_tuple):\n # Use a generator expression to check if 'None' is in the tuple\n res = any(item is None for item in test_tuple)\n return res", "matching_cluster_idx": 1}, {"solution": "def check_none(input_tuple):\n # Iterate through each element in the tuple\n for element in input_tuple:\n # Check if the current element is None\n if element is None:\n # If a None value is found, return True\n return True\n # If no None values are found, return False\n return False", "matching_cluster_idx": 4}, {"solution": "def check_none(test_tuple):\n # Check if 'None' is present in the tuple\n res = None in test_tuple\n return res", "matching_cluster_idx": 5}, {"solution": "def check_none(test_tup):\n # Check if None is in the tuple using any()\n res = any(val is None for val in test_tup)\n return res", "matching_cluster_idx": 1}]}, "Mbpp/750": {"dps": 86.05442176870748, "dps_norm": 85.83333333333333, "pass@1": 96.0, "profiled": [{"solution": "def add_tuple(list1, tuple1):\n # Concatenate the list and the tuple, then return the result as a list\n return list1 + list(tuple1)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(list1, tup1):\n # Append the tuple to the list\n list1 += tup1\n return list1", "matching_cluster_idx": 5}, {"solution": "def add_tuple(test_list, test_tup):\n # Extend the list with elements from the tuple\n test_list.extend(test_tup)\n # Return the modified list\n return test_list", "matching_cluster_idx": 5}, {"solution": "def add_tuple(test_list, K):\n # Extend the test list by appending each element of the tuple K\n for ele in K:\n test_list.append(ele)\n return test_list", "matching_cluster_idx": 0}, {"solution": "def add_tuple(given_list, given_tuple):\n # Extend the list by adding each element of the tuple\n given_list.extend(given_tuple)\n # Return the updated list\n return given_list", "matching_cluster_idx": 5}, {"solution": "def add_tuple(lst, tup):\n # Extend the list by appending elements from the tuple\n lst.extend(tup)\n # Return the modified list\n return lst", "matching_cluster_idx": 5}, {"solution": "def add_tuple(nums_list, nums_tuple):\n # Extend the list with elements of the tuple\n nums_list.extend(nums_tuple)\n return nums_list", "matching_cluster_idx": 5}, {"solution": "def add_tuple(lst, tup):\n # Use list.extend() to add all elements of the tuple to the list\n lst.extend(tup)\n # Return the updated list\n return lst", "matching_cluster_idx": 5}, {"solution": "def add_tuple(test_list, test_tup):\n # Use the extend method to add elements of the tuple to the list\n test_list.extend(test_tup)\n return test_list", "matching_cluster_idx": 5}, {"solution": "def add_tuple(test_list, K):\n # Extend the list by unpacking the tuple\n test_list.extend(K)\n # Return the modified list\n return test_list", "matching_cluster_idx": 5}, {"solution": "def add_tuple(test_list, test_tup):\n # Extend the list with elements from the tuple\n res = test_list.extend(test_tup)\n return test_list", "matching_cluster_idx": 5}, {"solution": "def add_tuple(int_list, int_tuple):\n # Extend the list by iterating over each element in the tuple and appending it\n int_list.extend(int_tuple)\n return int_list", "matching_cluster_idx": 5}, {"solution": "def add_tuple(test_list, test_tup):\n # Extend the list by appending each element of the tuple\n test_list.extend(test_tup)\n return test_list", "matching_cluster_idx": 5}, {"solution": "def add_tuple(nums_list, tuple_nums):\n # Extend the list by appending each element from the tuple\n nums_list.extend(tuple_nums)\n # Return the updated list\n return nums_list", "matching_cluster_idx": 5}, {"solution": "def add_tuple(test_list, tup):\n # Extend the list by adding the elements of the tuple\n test_list.extend(tup)\n # Return the updated list\n return test_list", "matching_cluster_idx": 5}, {"solution": "def add_tuple(given_list, given_tuple):\n # Extend the list by appending each element of the tuple\n given_list.extend(given_tuple)\n # Return the updated list\n return given_list", "matching_cluster_idx": 5}, {"solution": "def add_tuple(list_input, tuple_input):\n # Extend the list by appending each element of the tuple\n list_input.extend(tuple_input)\n # Return the updated list\n return list_input", "matching_cluster_idx": 5}, {"solution": "def add_tuple(test_list, test_tup):\n # Extend the list by appending each element of the tuple\n [test_list.append(ele) for ele in test_tup]\n return test_list", "matching_cluster_idx": -1}, {"solution": "def add_tuple(test_list, test_tup):\n # Concatenate the list and tuple into a new list\n res = test_list + list(test_tup)\n return res", "matching_cluster_idx": 2}, {"solution": "def add_tuple(given_list, given_tuple):\n # Extend the given list by appending the given tuple\n given_list.extend(given_tuple)\n return given_list", "matching_cluster_idx": 5}]}, "Mbpp/753": {"dps": 82.91946308724832, "dps_norm": 71.25, "pass@1": 86.0, "profiled": [{"solution": "def min_k(test_list, N):\n # Sorting the list of tuples based on the second element in ascending order\n res = sorted(test_list, key = lambda x: x[1])[:N]\n return res", "matching_cluster_idx": 2}, {"solution": "def min_k(test_list, K):\n # Sort the list of tuples based on the second element of each tuple and select the first K elements\n res = sorted(test_list, key=lambda x: x[1])[:K]\n return res", "matching_cluster_idx": 2}, {"solution": "def min_k(list1, k):\n # Use the sorted function to sort the list based on the second element of each tuple\n # Then, return the first k elements from the sorted list\n return sorted(list1, key=lambda x: x[1])[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(test_list, N):\n # Sort the list of tuples based on the second element in ascending order and select the first N elements\n res = sorted(test_list, key=lambda x: x[1])[:N]\n return res", "matching_cluster_idx": 1}, {"solution": "def min_k(test_list, K):\n # Sorting the list of tuples based on the second element (scores) in ascending order\n res = sorted(test_list, key=lambda x: x[1])\n # Slicing the first K elements from the sorted list\n res = res[:K]\n return res", "matching_cluster_idx": 2}, {"solution": "def min_k(test_list, K):\n # Use the sorted function to sort the list of tuples based on the second element\n # The [0:K] slice is then used to get the first K tuples from the sorted list\n result = sorted(test_list, key=lambda x: x[1])[0:K]\n return result", "matching_cluster_idx": 2}, {"solution": "def min_k(test_list, K):\n # Sort the list of tuples based on the second element in each tuple\n res = sorted(test_list, key=lambda x: x[1])\n \n # Return the first K elements from the sorted list\n return res[:K]", "matching_cluster_idx": 2}, {"solution": "def min_k(test_list, K):\n # Sort the list of tuples based on the second element of each tuple in ascending order\n res = sorted(test_list, key=lambda ele: ele[1])[:K]\n return res", "matching_cluster_idx": 2}, {"solution": "def min_k(test_list, N):\n # Sort the list of tuples based on the second item in each tuple\n res = sorted(test_list, key=lambda x: x[1])[:N]\n # Return the first N elements from the sorted list\n return res", "matching_cluster_idx": 2}, {"solution": "def min_k(test_list, K):\n # Sort the list of tuples based on the second element in ascending order\n res = sorted(test_list, key=lambda x: x[1])\n # Select the first K elements from the sorted list\n res = res[:K]\n return res", "matching_cluster_idx": 1}, {"solution": "def min_k(test_list, N):\n # Use the sorted function to sort the list of tuples based on the second element (i.e., the score)\n # Then, use slicing to select the first N tuples from the sorted list\n res = sorted(test_list, key=lambda x: x[1])[:N]\n return res", "matching_cluster_idx": 2}, {"solution": "def min_k(test_list, K):\n # Sort the list of tuples based on the second element of each tuple\n res = sorted(test_list, key = lambda ele: ele[1])\n # Slice the first K elements from the sorted list\n res = res[:K]\n return res", "matching_cluster_idx": 2}, {"solution": "def min_k(test_list, K):\n # Using list comprehension to filter and sort the first K elements\n res = sorted(test_list, key=lambda x: x[1])[:K]\n return res", "matching_cluster_idx": 2}, {"solution": "def min_k(tuple_list, K):\n # Use the sorted function with a lambda function to sort by the second element in each tuple\n sorted_list = sorted(tuple_list, key=lambda x: x[1])\n # Return the first K elements from the sorted list\n return sorted_list[:K]", "matching_cluster_idx": 2}, {"solution": "def min_k(test_list, K):\n # Sort the list of tuples based on the second element of each tuple\n res = sorted(test_list, key=lambda x: x[1])\n # Slice the list to get the first K elements, which will be the smallest\n res = res[:K]\n return res", "matching_cluster_idx": 2}, {"solution": "def min_k(test_list, K):\n # Sorting the list of tuples based on the second element in ascending order\n res = sorted(test_list, key=lambda x: x[1])[:K]\n return res", "matching_cluster_idx": 2}, {"solution": "def min_k(tuple_list, k):\n # Sort the tuple list based on the second element of each tuple (i.e., the score)\n sorted_list = sorted(tuple_list, key=lambda x: x[1])\n # Return the first k elements from the sorted list\n return sorted_list[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(test_list, K):\n # Use the sorted function to sort the list based on the second item (price) in ascending order\n # Then slice the first K items from the sorted list to get the minimum K records\n res = sorted(test_list, key=lambda x: x[1])[:K]\n return res", "matching_cluster_idx": 1}, {"solution": "def min_k(test_list, K):\n # Sort the list of tuples based on the second item in each tuple\n res = sorted(test_list, key=lambda ele: ele[1])\n \n # Slice the first K elements to get the minimum K records\n res = res[:K]\n \n return res", "matching_cluster_idx": 2}, {"solution": "def min_k(test_list, K):\n # Use the sorted function to sort the list of tuples based on the second element of each tuple in ascending order\n # Take the first K elements from the sorted list to get the minimum K records\n res = sorted(test_list, key=lambda x: x[1])[:K]\n return res", "matching_cluster_idx": 2}]}, "Mbpp/754": {"dps": 94.3103448275862, "dps_norm": 93.125, "pass@1": 34.0, "profiled": [{"solution": "def extract_index_list(l1, l2, l3):\n # Initialize an empty list to store common elements\n common_index = []\n \n # Iterate through the indices of the lists up to the minimum length\n for i in range(min(len(l1), len(l2), len(l3))):\n # Check if the elements at the current index in all three lists are the same\n if l1[i] == l2[i] == l3[i]:\n # If they are, add the element to the common elements list\n common_index.append(l1[i])\n \n # Return the list of common elements\n return common_index", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n # Use list comprehension to filter elements that are common at the same index in all three lists\n res = [x for x, y, z in zip(l1, l2, l3) if x == y == z]\n return res", "matching_cluster_idx": 7}, {"solution": "def extract_index_list(lst1, lst2, lst3):\n # Use list comprehension to find elements that are the same at each index\n common_elements = [lst1[i] for i in range(min(len(lst1), len(lst2), len(lst3))) if lst1[i] == lst2[i] == lst3[i]]\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(list1, list2, list3):\n # Initialize an empty list to store common elements\n common = []\n # Iterate through the lists up to the length of the shortest list\n for i in range(min(len(list1), len(list2), len(list3))):\n # Check if the elements at the current index are the same\n if list1[i] == list2[i] == list3[i]:\n # If they are the same, add the element to the common list\n common.append(list1[i])\n # Return the list of common elements\n return common", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(A, B, C):\n # Iterate through the elements of the lists using zip\n # Append the element to the result if it is the same in all three lists\n result = [a for a, b, c in zip(A, B, C) if a == b == c]\n return result", "matching_cluster_idx": 7}, {"solution": "def extract_index_list(a, b, c):\n # Use a list comprehension to find elements that are common at the same index in all three lists\n common_elements = [x for x, y, z in zip(a, b, c) if x == y == z]\n return common_elements", "matching_cluster_idx": 7}, {"solution": "def extract_index_list(lst1, lst2, lst3):\n # Use the zip function to iterate over the three lists in parallel\n # Use list comprehension to check if all elements at the current index are the same\n return [tup[0] for tup in zip(lst1, lst2, lst3) if tup[0] == tup[1] == tup[2]]", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n # Using list comprehension to find common elements at the same index\n # for all three lists\n res = [i for i, j, k in zip(l1, l2, l3) if i == j == k]\n return res", "matching_cluster_idx": 7}, {"solution": "def extract_index_list(nums1, nums2, nums3):\n # Iterate through the indices of the lists\n return [nums1[i] for i in range(min(len(nums1), len(nums2), len(nums3))) if nums1[i] == nums2[i] == nums3[i]]", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n # Use list comprehension to filter and return elements that are equal at the same index in all three lists\n return [x for x, y, z in zip(l1, l2, l3) if x == y == z]", "matching_cluster_idx": 7}, {"solution": "def extract_index_list(list1, list2, list3):\n # Use zip to iterate over the three lists simultaneously\n # Use the expression (x == y == z) to check if the elements at the same index are the same\n # Filter the results to only include True values (i.e., elements that are common in all three lists)\n result = [x for x, y, z in zip(list1, list2, list3) if (x == y == z)]\n return result", "matching_cluster_idx": 7}, {"solution": "def extract_index_list(lst1, lst2, lst3):\n # Use list comprehension to find elements at the same index in all three lists\n res = [lst1[i] for i in range(min(len(lst1), len(lst2), len(lst3))) \n if lst1[i] == lst2[i] == lst3[i]]\n return res", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(arr1, arr2, arr3):\n # Initialize an empty list to store the result\n res = []\n # Get the length of the shortest array\n length = min(len(arr1), len(arr2), len(arr3))\n # Iterate through the arrays up to the length of the shortest array\n for i in range(length):\n # Check if the elements at the current index are the same in all three arrays\n if arr1[i] == arr2[i] == arr3[i]:\n # If they are the same, add the element to the result list\n res.append(arr1[i])\n # Return the list of common elements\n return res", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n # Use zip to iterate over all three lists simultaneously and compare elements at each index\n # Filter elements that are equal in all three lists using a lambda function\n return [x for x, y, z in zip(l1, l2, l3) if x == y == z]", "matching_cluster_idx": 7}, {"solution": "def extract_index_list(l1, l2, l3):\n # Use list comprehension to filter elements\n # Check if elements at the same index are equal in all three lists\n result = [l1[i] for i in range(min(len(l1), len(l2), len(l3))) if l1[i] == l2[i] == l3[i]]\n return result", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n # Use zip to iterate through all three lists in parallel\n # Use list comprehension to filter elements that are equal across all lists\n result = [i for i, j, k in zip(l1, l2, l3) if i == j == k]\n return result", "matching_cluster_idx": 7}, {"solution": "from typing import List\ndef extract_index_list(list1: List[int], list2: List[int], list3: List[int]) -> List[int]:\n # Find the common elements at the same index in all three lists\n common_elements = [list1[i] for i in range(min(len(list1), len(list2), len(list3))) if list1[i] == list2[i] == list3[i]]\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(list1, list2, list3):\n # Initialize an empty list to store common elements\n common_elements = []\n \n # Iterate through the lists up to the length of the shortest list\n for i in range(min(len(list1), len(list2), len(list3))):\n # Check if the elements at the current index are the same in all three lists\n if list1[i] == list2[i] == list3[i]:\n # If they are the same, append the element to the common_elements list\n common_elements.append(list1[i])\n \n # Return the list of common elements\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n # Use a generator expression to iterate over the zipped lists\n # Filter elements that appear in all three lists at the same index\n result = [x for x, y, z in zip(l1, l2, l3) if x == y == z]\n return result", "matching_cluster_idx": 7}, {"solution": "def extract_index_list(list1, list2, list3):\n # Initialize an empty list to store common elements\n common_elements = []\n \n # Calculate the minimum length among the three lists\n length = min(len(list1), len(list2), len(list3))\n \n # Iterate through the lists up to the minimum length\n for i in range(length):\n # Check if the elements at the current index are the same in all three lists\n if list1[i] == list2[i] == list3[i]:\n # If they are, append the element to the common_elements list\n common_elements.append(list1[i])\n \n # Return the list of common elements\n return common_elements", "matching_cluster_idx": 6}]}, "Mbpp/755": {"dps": 59.65642894325872, "dps_norm": 76.47058823529412, "pass@1": 17.0, "profiled": [{"solution": "def second_smallest(numbers):\n # Remove duplicates by converting the list to a set and back to a list\n unique_numbers = list(set(numbers))\n \n # If there are less than 2 unique numbers, return None as we can't find the second smallest\n if len(unique_numbers) < 2:\n return None\n \n # Sort the list of unique numbers\n unique_numbers.sort()\n \n # Return the second smallest number\n return unique_numbers[1]", "matching_cluster_idx": 5}, {"solution": "def second_smallest(numbers):\n # Remove duplicates by converting the list to a set and then back to a list\n unique_numbers = list(set(numbers))\n \n # Sort the unique numbers\n unique_numbers.sort()\n \n # Check if there are at least two unique numbers\n if len(unique_numbers) >= 2:\n return unique_numbers[1] # Return the second smallest\n else:\n return None # Return None if there's no second smallest number", "matching_cluster_idx": 5}, {"solution": "def second_smallest(numbers):\n # Initialize first and second smallest to a large number\n first = second = float('inf')\n \n # Iterate through each number in the list\n for x in numbers:\n # Update the smallest number if the current number is smaller\n if x < first:\n second = first # Move the current smallest to second\n first = x # Update first with the new smallest number\n # Update the second smallest if the current number is between first and second\n elif first < x < second:\n second = x\n \n # If second still equals infinity, it means there's no second smallest number\n return second if second != float('inf') else None", "matching_cluster_idx": 3}, {"solution": "def second_smallest(arr):\n # Convert the list to a set to remove duplicates\n arr = set(arr)\n # Convert the set back to a list and sort it\n arr = list(arr)\n arr.sort()\n # Return the second element if the list has at least two elements, otherwise return None\n return arr[1] if len(arr) > 1 else None", "matching_cluster_idx": 5}, {"solution": "def second_smallest(numbers):\n # Sort the list in ascending order\n numbers.sort()\n # Initialize the second smallest number to None\n second_smallest = None\n # Iterate through the sorted list\n for num in numbers:\n # Check if the number is greater than the smallest number and not equal to it\n if num > min(numbers) and (second_smallest is None or num < second_smallest):\n # Update the second smallest number\n second_smallest = num\n return second_smallest", "matching_cluster_idx": -1}, {"solution": "def second_smallest(numbers):\n # Check if the list has fewer than 2 elements\n if len(numbers) < 2:\n return None\n \n # Initialize the first and second smallest to None\n first, second = None, None\n \n # Iterate through each number in the list\n for num in numbers:\n # Update the first smallest if found smaller than current first\n if first is None or num < first:\n first, second = num, first\n # Update the second smallest if num is greater than first but smaller than second\n elif (second is None or num < second) and num != first:\n second = num\n \n return second", "matching_cluster_idx": 3}, {"solution": "def second_smallest(numbers):\n # Convert the list to a set to remove duplicates and then back to a list\n unique_numbers = list(set(numbers))\n \n # If there are less than 2 unique numbers, return None as there's no second smallest\n if len(unique_numbers) < 2:\n return None\n \n # Sort the unique numbers list\n unique_numbers.sort()\n \n # Return the second smallest number\n return unique_numbers[1]", "matching_cluster_idx": 5}, {"solution": "def second_smallest(numbers):\n # Check if the list has less than 2 unique elements\n if len(set(numbers)) < 2:\n return None # Return None if not enough unique elements\n # Remove duplicates and sort the list\n unique_numbers = sorted(set(numbers))\n # Return the second element, which is the second smallest\n return unique_numbers[1]", "matching_cluster_idx": 4}, {"solution": "def second_smallest(numbers):\n # Check if the list contains at least two distinct elements\n if len(numbers) < 2:\n return None\n \n # Initialize the smallest and second smallest to None\n smallest = second_smallest = float('inf')\n \n # Iterate through each number in the list\n for num in numbers:\n # Update the smallest and second smallest values\n if num < smallest:\n second_smallest = smallest\n smallest = num\n elif smallest < num < second_smallest:\n second_smallest = num\n \n # Check if a valid second smallest was found\n if second_smallest == float('inf'):\n return None\n else:\n return second_smallest", "matching_cluster_idx": 3}, {"solution": "def second_smallest(numbers):\n # Initialize minimum and second_minimum with None\n minimum, second_minimum = None, None\n \n # Iterate through each number in the list\n for num in numbers:\n # Update minimum and second_minimum accordingly\n if minimum is None or num < minimum:\n second_minimum = minimum\n minimum = num\n elif (second_minimum is None or num < second_minimum) and num != minimum:\n second_minimum = num\n \n # Return the second smallest number if found, else return None\n return second_minimum", "matching_cluster_idx": 3}, {"solution": "def second_smallest(numbers):\n # Convert the list to a set to remove duplicates\n unique_numbers = set(numbers)\n # Sort the set to find the second smallest number\n sorted_numbers = sorted(unique_numbers)\n # Return the second smallest number if it exists, otherwise return None\n return sorted_numbers[1] if len(sorted_numbers) > 1 else None", "matching_cluster_idx": 5}, {"solution": "def second_smallest(numbers):\n # Initialize the minimum and second minimum to None\n min1 = min2 = None\n \n # Iterate through each number in the list\n for x in numbers:\n # Check if the number is None or less than the current min1\n if min1 is None or x < min1:\n # Update min2 to the current min1 and update min1 to the current number\n min2 = min1\n min1 = x\n # Check if the number is not equal to min1 and is smaller than the current min2\n elif (min2 is None or x < min2) and x != min1:\n # Update min2 to the current number\n min2 = x\n \n # Return the second smallest number\n return min2", "matching_cluster_idx": 3}, {"solution": "def second_smallest(numbers):\n # Use set to remove duplicates and then convert back to list\n numbers = list(set(numbers))\n # Check if there are at least two unique numbers\n if len(numbers) < 2:\n return None\n # Initialize first and second smallest to positive infinity\n first, second = float('inf'), float('inf')\n # Iterate through the list to find the smallest and second smallest numbers\n for x in numbers:\n if x <= first:\n first, second = x, first\n elif x < second:\n second = x\n return second", "matching_cluster_idx": 3}, {"solution": "def second_smallest(numbers):\n # Initialize the smallest and second smallest elements to None\n smallest = second_smallest = None\n \n # Iterate through each number in the list\n for num in numbers:\n # If the current number is None, or the smallest is None, update the smallest\n if smallest is None or num < smallest:\n second_smallest = smallest\n smallest = num\n # If the current number is not equal to the smallest and is either None or greater than the second smallest, update the second smallest\n elif num != smallest and (second_smallest is None or num < second_smallest):\n second_smallest = num\n \n # Return the second smallest number found\n return second_smallest", "matching_cluster_idx": 2}, {"solution": "def second_smallest(list1):\n # Remove duplicates by converting the list to a set\n list1 = list(set(list1))\n \n # Sort the list in ascending order\n list1.sort()\n \n # Return the second smallest element if it exists, otherwise return None\n if len(list1) < 2:\n return None\n else:\n return list1[1]", "matching_cluster_idx": 5}, {"solution": "def second_smallest(numbers):\n # Initialize both first and second smallest to None\n first, second = None, None\n \n # Iterate through each number in the list\n for num in numbers:\n # If the number is smaller than 'first' (or if 'first' is None), update 'first' and 'second'\n if first is None or num < first:\n first, second = num, first\n # If the number is between 'first' and 'second' (or if 'second' is None), update 'second'\n elif (second is None or num < second) and num != first:\n second = num\n \n # Return the second smallest number found\n return second", "matching_cluster_idx": 3}, {"solution": "def second_smallest(numbers):\n # Remove duplicate numbers by converting the list to a set\n unique_numbers = set(numbers)\n \n # If there are fewer than 2 unique numbers, return None (not enough elements)\n if len(unique_numbers) < 2:\n return None\n \n # Convert the set back to a list and sort it\n sorted_numbers = list(unique_numbers)\n sorted_numbers.sort()\n \n # Return the second element from the sorted list\n return sorted_numbers[1]", "matching_cluster_idx": 5}]}, "Mbpp/757": {"dps": 80.04672897196262, "dps_norm": 29.23076923076923, "pass@1": 36.0, "profiled": [{"solution": "def count_reverse_pairs(mylist):\n # Initialize a counter for reverse pairs\n count = 0\n \n # Iterate over each pair of elements in the list\n for i in range(len(mylist)):\n for j in range(i + 1, len(mylist)):\n # Check if one string is the reverse of the other\n if mylist[i] == mylist[j][::-1]:\n count += 1\n \n # Return the total count of reverse pairs found\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(string_list):\n # Use dictionary to store the frequency of reversed strings\n reversed_freq = {}\n count = 0\n \n for s in string_list:\n # Reverse the current string\n reversed_str = s[::-1]\n \n # If the reversed string is already in the dictionary, increment the count\n if reversed_str in reversed_freq:\n count += reversed_freq[reversed_str]\n \n # Increment the frequency of the current string in the dictionary\n if s in reversed_freq:\n reversed_freq[s] += 1\n else:\n reversed_freq[s] = 1\n \n return count", "matching_cluster_idx": 12}, {"solution": "def count_reverse_pairs(arr):\n count = 0 # Initialize count of reverse pairs\n for i in range(len(arr)): # Iterate through the list\n for j in range(i + 1, len(arr)): # Compare with subsequent elements\n # Check if the current element is the reverse of the subsequent element\n if arr[i][::-1] == arr[j]:\n count += 1 # Increment count if a reverse pair is found\n return count # Return the total count of reverse pairs", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(arr):\n # Initialize a counter for reverse pairs\n count = 0\n \n # Iterate through each element in the array\n for i in range(len(arr)):\n # Iterate through each element after the current one\n for j in range(i + 1, len(arr)):\n # Check if the current element is the reverse of any following element\n if arr[i][::-1] == arr[j]:\n # If so, increment the counter\n count += 1\n \n # Return the total count of reverse pairs found\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(words):\n # Initialize count to 0\n count = 0\n \n # Iterate through each word in the list\n for i in range(len(words)):\n # Iterate through each word in the list after the current word\n for j in range(i + 1, len(words)):\n # Check if the current word is the reverse of the next word\n if words[i] == words[j][::-1]:\n count += 1 # Increment count if reverse pair is found\n \n return count # Return the total count of reverse pairs", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(str_list):\n # Initialize a counter for reverse pairs\n count = 0\n \n # Iterate through each string in the list\n for i in range(len(str_list)):\n # Iterate through the remaining strings in the list\n for j in range(i + 1, len(str_list)):\n # Check if one string is the reverse of the other\n if str_list[i] == str_list[j][::-1]:\n # If so, increment the counter\n count += 1\n \n # Return the total count of reverse pairs found\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(a):\n # Count the number of reverse pairs in the list\n return sum(a[i] == ''.join(reversed(a[j])) for i in range(len(a)) for j in range(i + 1, len(a)))", "matching_cluster_idx": -1}, {"solution": "def count_reverse_pairs(list):\n # Initialize the count of reverse pairs\n res = 0\n \n # Iterate through the list to compare each string with the rest\n for i in range(len(list)):\n for j in range(i + 1, len(list)):\n # Check if the current string is the reverse of another string in the list\n if list[i] == list[j][::-1]:\n # Increment the count if a pair is found\n res += 1\n \n # Return the total count of reverse pairs\n return res", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(str_list):\n # Initialize count to 0\n count = 0\n \n # Iterate over each string in the list\n for i in range(len(str_list)):\n # Compare the current string with all subsequent strings in the list\n for j in range(i + 1, len(str_list)):\n # Check if the reverse of the current string matches any subsequent string\n if str_list[i] == str_list[j][::-1]:\n # If a match is found, increment the count\n count += 1\n \n # Return the total count of reverse pairs found\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(word_list):\n # Initialize a counter to keep track of reverse pairs\n count = 0\n \n # Loop through each word in the list\n for i in range(len(word_list)):\n # Loop through each word again starting from the next word\n for j in range(i + 1, len(word_list)):\n # Check if the current word is the reverse of the other word\n if word_list[i] == word_list[j][::-1]:\n # If they are, increment the counter\n count += 1\n \n # Return the total count of reverse pairs\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(a):\n # Initialize a counter for reverse pairs\n count = 0\n \n # Iterate over each string in the list\n for i in range(len(a)):\n # Iterate over each string after the current one\n for j in range(i + 1, len(a)):\n # Check if the string at index i is the reverse of the string at index j\n if a[i] == a[j][::-1]:\n # If so, increment the counter\n count += 1\n \n # Return the total count of reverse pairs\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(input_list):\n count = 0\n # Iterate through the list\n for i in range(0, len(input_list)):\n # Compare each element with the rest of the elements in the list\n for j in range(i + 1, len(input_list)):\n # Check if the current element is the reverse of the element at index j\n if input_list[i] == input_list[j][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(string_list):\n # Count the number of pairs of strings that are reverses of each other\n return sum(1 for i in range(len(string_list)) for j in range(i + 1, len(string_list)) if string_list[i][::-1] == string_list[j])", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(string_list):\n # Initialize a count for reverse pairs\n count = 0\n # Iterate through each string in the list\n for i in range(len(string_list)):\n # Iterate through each string after the current one\n for j in range(i + 1, len(string_list)):\n # Check if the current string is the reverse of another string in the list\n if string_list[i] == string_list[j][::-1]:\n # If true, increment the count\n count += 1\n # Return the total count of reverse pairs\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(str_list):\n # Count the number of pairs where one string is the reverse of another\n return sum([1 for i in range(len(str_list)) for j in range(i + 1, len(str_list)) if str_list[i] == str_list[j][::-1]])", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(test_list):\n # Initialize counter for reverse pairs\n res = 0\n # Iterate through each pair of strings in the list\n for i in range(len(test_list)):\n for j in range(i + 1, len(test_list)):\n # Check if one string is the reverse of the other\n if test_list[i] == test_list[j][::-1]:\n res += 1\n return res", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(word_list):\n reverse_count = 0\n for i in range(len(word_list)):\n for j in range(i + 1, len(word_list)):\n # Check if one word is the reverse of another\n if word_list[i] == word_list[j][::-1]:\n reverse_count += 1\n return reverse_count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(string_list):\n # Initialize a counter to keep track of the number of reverse pairs\n cnt = 0\n \n # Iterate through the string list\n for i in range(len(string_list)):\n # For each string, check all other strings in the list\n for j in range(i + 1, len(string_list)):\n # Check if the current string is the reverse of another string\n if string_list[i] == string_list[j][::-1]:\n # If it is, increment the counter\n cnt += 1\n \n # Return the total count of reverse pairs\n return cnt", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(strlist):\n # Create a dictionary to store the reverse strings and their counts\n strdict = {}\n count = 0\n \n # Iterate through the list of strings\n for i in range(len(strlist)):\n # Get the reverse of the current string\n strv = strlist[i][::-1]\n \n # Check if the reversed string exists in the dictionary\n if strv in strdict:\n # Increment the count for this reversed string\n count += strdict[strv]\n \n # Add the current string to the dictionary with its count\n strdict[strlist[i]] = strdict.get(strlist[i], 0) + 1\n \n # Return the total count of reverse string pairs\n return count", "matching_cluster_idx": 11}, {"solution": "def count_reverse_pairs(string_list):\n # Initialize a counter for reverse pairs\n count = 0\n \n # Iterate over each word in the list\n for i in range(len(string_list)):\n # Iterate over each word that comes after the current word\n for j in range(i + 1, len(string_list)):\n # Check if the current word is the reverse of the next word\n if string_list[i] == string_list[j][::-1]:\n # Increment the counter if a reverse pair is found\n count += 1\n \n # Return the total count of reverse pairs\n return count", "matching_cluster_idx": 2}]}, "Mbpp/758": {"dps": 59.54633204633204, "dps_norm": 71.875, "pass@1": 97.0, "profiled": [{"solution": "def unique_sublists(lst):\n # Using dict comprehension to count occurrences of each sublist\n return {tuple(x): lst.count(x) for x in lst}", "matching_cluster_idx": 3}, {"solution": "def unique_sublists(input_list):\n # Initialize an empty dictionary to store the counts of each tuple\n occurrences = {}\n # Iterate through each sublist in the input list\n for sublist in input_list:\n # Convert the sublist to a tuple, as tuples are hashable and can be dictionary keys\n current_tuple = tuple(sublist)\n # If the tuple is not already in the dictionary, add it with a count of 1\n if current_tuple not in occurrences:\n occurrences[current_tuple] = 1\n # If the tuple is already in the dictionary, increment its count by 1\n else:\n occurrences[current_tuple] += 1\n # Return the dictionary containing tuples and their counts\n return occurrences", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(input_list):\n # Create a dictionary to store the tuples and their frequency\n list_dict = {}\n \n # Iterate through each sublist in the input list\n for sublist in input_list:\n # Convert the sublist to a tuple so it can be a dictionary key\n tuple_sublist = tuple(sublist)\n \n # If the tuple is already in the dictionary, increment its count\n if tuple_sublist in list_dict:\n list_dict[tuple_sublist] += 1\n # If the tuple is not in the dictionary, add it with a count of 1\n else:\n list_dict[tuple_sublist] = 1\n \n # Return the dictionary containing the tuples and their frequencies\n return list_dict", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(input_list):\n # Initialize a dictionary to store count of each tuple form of sublist\n count_dict = {}\n \n # Iterate over each sublist in the input list\n for sublist in input_list:\n # Convert the sublist to a tuple and count its occurrences\n # Use .get() method to avoid KeyError and set default count to 0\n count_dict[tuple(sublist)] = count_dict.get(tuple(sublist), 0) + 1\n \n # Return the dictionary containing tuples and their counts\n return count_dict", "matching_cluster_idx": 5}, {"solution": "def unique_sublists(lst):\n # Convert each sublist in the list to a tuple and store in a dictionary with count\n res = {tuple(sub): lst.count(sub) for sub in lst}\n return res", "matching_cluster_idx": 3}, {"solution": "def unique_sublists(lst):\n # Create a dictionary to store the frequency of each tuple\n res = {}\n \n # Iterate over each sublist in the list\n for sub in lst:\n # Convert the sublist to a tuple and count its occurrences\n res[tuple(sub)] = res.get(tuple(sub), 0) + 1\n \n # Return the dictionary containing tuples and their frequencies\n return res", "matching_cluster_idx": 5}, {"solution": "def unique_sublists(given_list):\n # Create an empty dictionary to store the result\n result = {}\n # Iterate over the given list\n for sublist in given_list:\n # Convert each sublist to a tuple and count its occurrences\n # Using the tuple as a key in the dictionary\n result.setdefault(tuple(sublist), 0)\n result[tuple(sublist)] += 1\n return result", "matching_cluster_idx": 4}, {"solution": "from collections import defaultdict\ndef unique_sublists(lst):\n # Dictionary to store the frequency of each tuple\n freq = defaultdict(int)\n \n # Convert each sublist to a tuple and count its occurrences\n for sublist in lst:\n # Convert sublist to a tuple and increment its count in the dictionary\n freq[tuple(sublist)] += 1\n \n # Convert defaultdict back to a regular dictionary\n return dict(freq)", "matching_cluster_idx": 5}, {"solution": "def unique_sublists(input_list):\n # Create an empty dictionary to store the result\n result = {}\n # Iterate over each sublist in the input list\n for sublist in input_list:\n # Convert the sublist to a tuple since lists are not hashable\n tuple_version = tuple(sublist)\n # If the tuple is already in the dictionary, increment its count\n if tuple_version in result:\n result[tuple_version] += 1\n # If the tuple is not in the dictionary, add it with a count of 1\n else:\n result[tuple_version] = 1\n # Return the dictionary with sublists as tuples and their counts\n return result", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(input_list):\n # Convert each sublist in the list to a tuple and count their occurrences\n sublists_count = {tuple(sublist): input_list.count(sublist) for sublist in input_list}\n return sublists_count", "matching_cluster_idx": 3}, {"solution": "def unique_sublists(sublist):\n # Use a dictionary to store the count of each tuple version of a sublist\n sublist_count = {}\n # Iterate over each sublist in the provided list\n for sublist in sublist:\n # Convert the sublist to a tuple to make it hashable and add to the dictionary\n # Increment the count for this tuple, starting at 0 if it's not already in the dictionary\n sublist_count[tuple(sublist)] = sublist_count.get(tuple(sublist), 0) + 1\n return sublist_count", "matching_cluster_idx": 5}, {"solution": "def unique_sublists(input_list):\n # Create a dictionary to store the count of each unique sublist\n count_dict = {}\n # Iterate over each sublist in the input list\n for sublist in input_list:\n # Convert the sublist to a tuple (since lists are not hashable and cannot be used as dictionary keys)\n tuple_form = tuple(sublist)\n # If the tuple is not already a key in the dictionary, add it with a count of 0\n count_dict[tuple_form] = count_dict.get(tuple_form, 0) + 1\n # Return the dictionary containing the counts of each unique sublist\n return count_dict", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(list1):\n # Create an empty dictionary to store tuples as keys and their counts as values\n res = {}\n # Iterate through each sublist in the input list\n for ele in list1:\n # Convert the sublist to a tuple and assign it a count of 1 if it's not already in the dictionary,\n # otherwise increment the existing count\n res[tuple(ele)] = res.get(tuple(ele), 0) + 1\n # Return the resulting dictionary\n return res", "matching_cluster_idx": 5}, {"solution": "def unique_sublists(list1):\n result = {}\n # Iterate through each sublist in the input list\n for sublist in list1:\n # Convert sublist to a tuple and check its occurrence\n if tuple(sublist) in result:\n result[tuple(sublist)] += 1\n else:\n result[tuple(sublist)] = 1\n return result", "matching_cluster_idx": 5}, {"solution": "def unique_sublists(list1):\n # Create a dictionary to store the count of each unique sublist\n result = dict()\n \n # Iterate through each sublist in the input list\n for sublist in list1:\n # Convert the sublist to a tuple to make it hashable and thus usable as a dictionary key\n t = tuple(sublist)\n \n # If the tuple is already in the dictionary, increment its count\n if t in result:\n result[t] += 1\n else:\n # Otherwise, add the tuple to the dictionary with a count of 1\n result[t] = 1\n \n # Return the dictionary containing the count of each unique sublist\n return result", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(lst):\n # Use a dictionary to count occurrences of list tuples\n result = {}\n for sublist in lst:\n # Convert list to tuple to make it hashable\n tuple_sublist = tuple(sublist)\n # Count the occurrences\n result[tuple_sublist] = result.get(tuple_sublist, 0) + 1\n return result", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(list1):\n # Initialize an empty dictionary to store the result\n dict1 = {}\n # Iterate through each list in the input list\n for sublist in list1:\n # Convert the sublist to a tuple and store it in the dictionary\n # Increment the count of this tuple in the dictionary\n dict1[tuple(sublist)] = dict1.get(tuple(sublist), 0) + 1\n # Return the dictionary containing tuples and their counts\n return dict1", "matching_cluster_idx": 5}, {"solution": "def unique_sublists(lst):\n # Convert each list in the input list to a tuple and count occurrences\n return {tuple(i): lst.count(i) for i in lst}", "matching_cluster_idx": 3}, {"solution": "def unique_sublists(lists):\n # Convert each sublist in the list to a tuple\n tuples = [tuple(i) for i in lists]\n # Create a dictionary to store tuples and their counts\n return dict((x, tuples.count(x)) for x in set(tuples))", "matching_cluster_idx": 2}, {"solution": "def unique_sublists(sub_li):\n # Initialize an empty dictionary to store the results\n result = {}\n \n # Iterate through each sublist in the list of lists\n for sub in sub_li:\n # Convert the sublist to a tuple since lists are not hashable\n temp = tuple(sub)\n \n # Check if the tuple is already in the dictionary\n if temp in result:\n # If it is, increment its count\n result[temp] += 1\n else:\n # If it's not, add it with a count of 1\n result[temp] = 1\n \n # Return the dictionary with tuples as keys and their counts as values\n return result", "matching_cluster_idx": 6}]}, "Mbpp/760": {"dps": 85.47445255474453, "dps_norm": 80.625, "pass@1": 92.0, "profiled": [{"solution": "def unique_Element(lst):\n # Check if the length of the set of the list is equal to 1\n return len(set(lst)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(input_list):\n # Check if all elements in the list are the same\n return all(input_list[i] == input_list[0] for i in range(len(input_list)))", "matching_cluster_idx": 2}, {"solution": "def unique_Element(nums):\n # Use a set to find unique elements\n s = set(nums)\n # Check if the size of the set is 1 (all elements are the same)\n return len(s) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(list1):\n # Convert the list to a set and check if the length is 1\n return len(set(list1)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(nums):\n # Check if the set of the list contains only one unique element\n return len(set(nums)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(nums):\n # Check if the list contains only one distinct element\n return len(set(nums)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(list1):\n # Check if all elements in the list are the same by comparing the first element with the rest\n return all(list1[i] == list1[0] for i in range(len(list1)))", "matching_cluster_idx": 2}, {"solution": "def unique_Element(test_list):\n # Use set() to remove duplicates and check if the length of the set is 1\n res = len(set(test_list)) == 1\n return res", "matching_cluster_idx": 6}, {"solution": "def unique_Element(nums):\n # Check if the length of the set created from the list is 1\n return len(set(nums)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(lst):\n # Use a set to find unique elements and check if there is only one unique element\n return len(set(lst)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(nums):\n # Check if the length of the set of numbers is equal to 1\n return len(set(nums)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(nums):\n # Check if the length of the set created from the list is equal to 1\n # A set in Python does not allow duplicate elements\n return len(set(nums)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(nums):\n # Check if the set of numbers has only one unique element\n return len(set(nums)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(input_list):\n # Use a set to find unique elements\n unique_elements = set(input_list)\n # Return True if the number of unique elements is 1, False otherwise\n return len(unique_elements) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(nums):\n # Check if all elements in the list are equal\n return all(nums[0] == num for num in nums)", "matching_cluster_idx": 3}, {"solution": "def unique_Element(nums):\n # Check if the number of unique elements in the list is equal to 1\n return len(set(nums)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(nums):\n # Check if the set of numbers has a length of 1, meaning all elements are the same\n return len(set(nums)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(nums):\n # Check if the number of unique elements in the list is exactly 1\n if len(set(nums)) == 1:\n return True\n return False", "matching_cluster_idx": 6}, {"solution": "def unique_Element(nums):\n # Convert the list to a set to remove duplicates and check if its length is 1\n return len(set(nums)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(test_list):\n # Check if all elements in the list are the same by comparing the set of the list with a set containing the first element\n res = len(set(test_list)) == 1\n return res", "matching_cluster_idx": 6}]}, "Mbpp/764": {"dps": 88.88888888888889, "dps_norm": 50.0, "pass@1": 99.0, "profiled": [{"solution": "def number_ctr(str):\n num = 0 # Initialize a counter for digits\n for i in str: # Loop through each character in the string\n if i.isdigit(): # Check if the character is a digit\n num += 1 # Increment the digit counter\n return num # Return the total count of digits", "matching_cluster_idx": 2}, {"solution": "def number_ctr(string):\n # Initialize a counter for digits\n c = 0\n # Iterate over each character in the string\n for char in string:\n # Check if the character is a digit\n if char.isdigit():\n c += 1\n # Return the count of digits\n return c", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n # Initialize a counter for digits\n ctr = 0\n # Iterate through each character in the string\n for char in s:\n # Check if the character is a digit\n if char.isdigit():\n # Increment the counter if it's a digit\n ctr += 1\n # Return the total count of digits\n return ctr", "matching_cluster_idx": 2}, {"solution": "def number_ctr(str1):\n # Initialize a counter to zero\n ctr = 0\n # Iterate over each character in the string\n for char in str1:\n # Check if the character is a digit\n if char.isdigit():\n # Increment the counter if it's a digit\n ctr += 1\n # Return the total count of digits\n return ctr", "matching_cluster_idx": 2}, {"solution": "def number_ctr(S):\n # Initialize a counter for digits\n dig_ctr = 0\n # Iterate through each character in the string\n for ele in S:\n # Check if the character is a digit\n if ele.isdigit():\n # Increment the digit counter\n dig_ctr += 1\n # Return the total count of digits\n return dig_ctr", "matching_cluster_idx": 2}, {"solution": "def number_ctr(str):\n # Initialize a counter to zero\n num = 0\n # Iterate through each character in the string\n for char in str:\n # Check if the character is a digit\n if char.isdigit():\n # Increment the counter if the character is a digit\n num += 1\n # Return the total count of digits\n return num", "matching_cluster_idx": 2}, {"solution": "def number_ctr(str1):\n # Use the sum function with a generator expression to count digits\n return sum(char.isdigit() for char in str1)", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n # Initialize a counter for digits\n count = 0\n \n # Iterate through each character in the string\n for i in range(len(s)):\n # Check if the character is a digit\n if s[i].isdigit():\n # Increment the counter if it is a digit\n count += 1\n \n # Return the total count of digits\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(st): \n count = 0 # Initialize counter to 0\n for i in st: \n if i.isdigit(): # Check if the character is a digit\n count += 1 # Increment counter if it is a digit\n return count # Return the total count of digits", "matching_cluster_idx": 2}, {"solution": "def number_ctr(str):\n # Use a generator expression to count digits in the string\n return sum(c.isdigit() for c in str)", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n # Initialize a counter for digits\n cnt = 0\n # Iterate through each character in the string\n for i in s:\n # Check if the character is a digit using isdigit() method\n if i.isdigit():\n # Increment the counter if the character is a digit\n cnt += 1\n # Return the total count of digits\n return cnt", "matching_cluster_idx": 2}, {"solution": "def number_ctr(n):\n # Initialize a counter for digits\n number_ctr = 0\n # Iterate through each character in the string\n for i in range(len(n)):\n # Check if the character is a digit using isdigit() method\n if n[i].isdigit():\n number_ctr += 1\n # Return the count of digits\n return number_ctr", "matching_cluster_idx": 2}, {"solution": "def number_ctr(str1):\n # Initialize a counter for digits\n number_ctr = 0\n # Iterate through each character in the string\n for char in str1:\n # Check if the character is a digit\n if char.isdigit():\n # Increment the counter if it is a digit\n number_ctr += 1\n # Return the total count of digits\n return number_ctr", "matching_cluster_idx": 2}, {"solution": "def number_ctr(string):\n # Initialize a counter to count the number of digits\n counter = 0\n # Iterate through each character in the string\n for i in string:\n # Check if the character is a digit\n if i.isdigit():\n # Increment the counter if it is a digit\n counter += 1\n # Return the total count of digits\n return counter", "matching_cluster_idx": 2}, {"solution": "def number_ctr(str1):\n # Initialize a counter for digits\n total = 0\n # Iterate through each character in the string\n for char in str1:\n # Check if the character is a digit\n if char.isdigit():\n total += 1\n # Return the total count of digits\n return total", "matching_cluster_idx": 2}, {"solution": "def number_ctr(str):\n # Initialize a counter to zero\n n_ctr = 0\n \n # Iterate through each character in the string\n for char in str:\n # Check if the character is a digit\n if char.isdigit():\n # Increment the counter if it is a digit\n n_ctr += 1\n \n # Return the total count of digits\n return n_ctr", "matching_cluster_idx": 2}, {"solution": "def number_ctr(str1):\n # Initialize a counter for digits\n num_ctr = 0\n # Iterate through each character in the string\n for i in str1:\n # Check if the character is a digit\n if i.isdigit():\n num_ctr += 1\n # Return the total count of digits\n return num_ctr", "matching_cluster_idx": 2}, {"solution": "def number_ctr(str1):\n # Count the number of digits in the string using a generator expression\n return sum(c.isdigit() for c in str1)", "matching_cluster_idx": 2}, {"solution": "def number_ctr(text):\n # Initialize a counter for digits\n count = 0\n \n # Iterate through each character in the text\n for i in text:\n # Check if the character is a digit\n if i.isdigit():\n # Increment the counter if it is a digit\n count += 1\n \n # Return the total count of digits\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(str):\n # Initialize counter to 0\n ctr = 0\n # Iterate through each character in the string\n for char in str:\n # Check if the character is a digit\n if char.isdigit():\n # Increment the counter if the character is a digit\n ctr += 1\n # Return the total count of digits\n return ctr", "matching_cluster_idx": 2}]}, "Mbpp/766": {"dps": 84.4392523364486, "dps_norm": 80.0, "pass@1": 95.0, "profiled": [{"solution": "def pair_wise(input_list):\n # Use list comprehension to generate pairs of consecutive items\n result = [(input_list[i], input_list[i + 1]) for i in range(len(input_list) - 1)]\n return result", "matching_cluster_idx": 3}, {"solution": "def pair_wise(test_list):\n # Use list comprehension with zip to create pairs of consecutive items\n res = list(zip(test_list, test_list[1:]))\n return res", "matching_cluster_idx": 5}, {"solution": "def pair_wise(lst):\n # Use list comprehension to create pairs of consecutive items\n # Starting from the first element and stepping by 1\n return [(lst[i], lst[i + 1]) for i in range(len(lst) - 1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(nums):\n # Initialize an empty list to store the pairs of consecutive items\n result = []\n # Iterate through the list, stopping one element before the end\n for i in range(len(nums) - 1):\n # Append the current item and the next item as a tuple\n result.append((nums[i], nums[i + 1]))\n # Return the list of tuples\n return result", "matching_cluster_idx": 2}, {"solution": "def pair_wise(l):\n # Use list comprehension to iterate through pairs of consecutive elements\n result = [(l[i], l[i + 1]) for i in range(len(l) - 1)]\n return result", "matching_cluster_idx": 3}, {"solution": "def pair_wise(test_list):\n # Create a list of pairs using list comprehension\n res = [(x, y) for x, y in zip(test_list, test_list[1:])]\n return res", "matching_cluster_idx": 4}, {"solution": "def pair_wise(test_list):\n # Using list comprehension to create pairs of consecutive elements\n res = [(test_list[idx], test_list[idx + 1]) for idx in range(len(test_list) - 1)]\n return res", "matching_cluster_idx": 3}, {"solution": "from itertools import islice, tee\ndef pair_wise(nums):\n # Create two iterators from the input list\n a, b = tee(nums)\n # Advance the second iterator by one element\n next(b, None)\n # Use zip to pair elements from the two iterators\n return list(zip(a, b))", "matching_cluster_idx": 5}, {"solution": "from itertools import pairwise\ndef pair_wise(nums):\n # Use pairwise from itertools to generate all consecutive pairs\n return list(pairwise(nums))", "matching_cluster_idx": 5}, {"solution": "def pair_wise(lst):\n # Use list comprehension to iterate over pairs of consecutive elements in the list\n return [(lst[i], lst[i + 1]) for i in range(len(lst) - 1)]", "matching_cluster_idx": 3}, {"solution": "from itertools import islice, tee\ndef pair_wise(iterable):\n \"\"\"\n Return a list of all pairs of consecutive items in a given list.\n \n Args:\n iterable (list): The input list of items.\n \n Returns:\n list: A list of tuples, each containing a pair of consecutive items.\n \"\"\"\n # Create two iterators, one to take each element from the iterable and one that starts one item ahead\n a, b = tee(iterable, 2)\n # Skip the first item in the second iterator using islice\n next(b, None)\n # Use zip to pair items from both iterators and return as a list\n return list(zip(a, b))", "matching_cluster_idx": 5}, {"solution": "from itertools import islice, tee\ndef pair_wise(lst):\n # Check if the input list is empty\n if not lst:\n return []\n \n # Create two iterators, one advanced by one element\n iter1, iter2 = tee(iter(lst))\n next(iter2, None)\n \n # Create a list of tuples containing consecutive elements\n pairs = list(zip(iter1, iter2))\n return pairs", "matching_cluster_idx": 5}, {"solution": "def pair_wise(items):\n # Use zip to pair each element with its next one, then convert to list\n return list(zip(items[:-1], items[1:]))", "matching_cluster_idx": 5}, {"solution": "def pair_wise(nums):\n # Use zip to create pairs of consecutive items in the list\n res = list(zip(nums, nums[1:]))\n return res", "matching_cluster_idx": 5}, {"solution": "def pair_wise(array):\n # Initialize an empty list to store the pairs\n res = []\n # Iterate through the array using the enumerate function to get indices and values\n for i in range(len(array)):\n # Check if the current index is not the last index\n if i != len(array) - 1:\n # Append a tuple of the current element and the next element to the result list\n res.append((array[i], array[i + 1]))\n # Return the list of pairs\n return res", "matching_cluster_idx": 1}, {"solution": "def pair_wise(test_list):\n # Use list comprehension with zip to generate pairs of consecutive elements\n res = [(test_list[idx], test_list[idx + 1]) for idx in range(len(test_list) - 1)]\n return res", "matching_cluster_idx": 3}, {"solution": "def pair_wise(nums):\n # Use zip to create pairs of consecutive items\n return list(zip(nums[:-1], nums[1:]))", "matching_cluster_idx": 5}, {"solution": "def pair_wise(lst):\n # Use list comprehension to iterate through the list with a step of 1\n return [(lst[i], lst[i + 1]) for i in range(len(lst) - 1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(test_list):\n # Using zip to create pairs of consecutive elements\n res = list(zip(test_list, test_list[1:]))\n return res", "matching_cluster_idx": 5}, {"solution": "def pair_wise(lst):\n # Use list comprehension and zip to create pairs of consecutive elements\n return [(lst[i], lst[i + 1]) for i in range(len(lst) - 1)]", "matching_cluster_idx": 3}]}, "Mbpp/775": {"dps": 85.75999999999999, "dps_norm": 62.85714285714286, "pass@1": 86.0, "profiled": [{"solution": "def odd_position(nums):\n # Loop through the list, considering only odd indices\n for i in range(1, len(nums), 2):\n # Check if the number at the current odd index is odd\n if nums[i] % 2 == 0:\n # If an even number is found at an odd index, return False\n return False\n # If all numbers at odd indices are odd, return True\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(nums):\n # Iterate through the list, focusing on odd indices\n for i in range(1, len(nums), 2):\n # Check if the number at the odd index is not odd\n if nums[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(nums):\n # Iterate through the list, considering only odd indices\n for x in range(1, len(nums), 2):\n # Check if the element at the odd index is not odd\n if nums[x] % 2 == 0:\n # Return False if any odd index does not contain an odd number\n return False\n # Return True if all odd indices contain odd numbers\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(nums):\n # Iterate over the list, checking elements at odd indices\n for i in range(1, len(nums), 2):\n # If an odd index has an even number, return False\n if nums[i] % 2 == 0:\n return False\n # If all checks pass, return True\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(nums):\n # Iterate through the list using enumerate to get both index and value\n for i, x in enumerate(nums):\n # Check if the index is odd and the number at the index is not odd\n if i % 2 != 0 and x % 2 == 0:\n return False\n # Return True if all conditions are satisfied\n return True", "matching_cluster_idx": 2}, {"solution": "def odd_position(nums):\n # Iterate over the list, checking elements at odd indices\n for i in range(1, len(nums), 2):\n # Check if the element at the odd index is not odd\n if nums[i] % 2 == 0:\n return False\n # Return True if all elements at odd indices are odd\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(nums):\n # Iterate through the list, checking only odd indices (1, 3, 5, ...)\n for i in range(1, len(nums), 2):\n # If the value at an odd index is not odd, return False\n if nums[i] % 2 == 0:\n return False\n # If all odd-index values are odd, return True\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n # Iterate over the list using index and value\n for index, value in enumerate(lst):\n # Check if the index is odd and the value is not odd\n if index % 2 == 1 and value % 2 == 0:\n # Return False if the condition is met\n return False\n # Return True if no such condition is met in the list\n return True", "matching_cluster_idx": 2}, {"solution": "def odd_position(nums):\n # Iterate over the list with index\n for i in range(len(nums)):\n # Check if the index is odd and the number at that index is even\n if i % 2 != 0 and nums[i] % 2 == 0:\n return False\n # If all checks pass, return True\n return True", "matching_cluster_idx": 2}, {"solution": "def odd_position(nums):\n # Iterate over the list, checking elements at odd indices\n for i in range(1, len(nums), 2):\n # Check if the element at the odd index is not odd\n if nums[i] % 2 == 0:\n return False\n # If all elements at odd indices are odd, return True\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(nums):\n # Iterate through the list, skipping the first element and checking every second element\n for i in range(1, len(nums), 2):\n # Check if the current element at an odd index is not an odd number\n if nums[i] % 2 == 0:\n # Return False if the condition is not met\n return False\n # Return True if all conditions are met\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(nums):\n # Iterate through the list, checking each odd index\n for i in range(1, len(nums), 2):\n # Check if the number at the current index is not odd\n if nums[i] % 2 == 0:\n return False\n # If all odd indices have odd numbers, return True\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(nums):\n # Iterate over the list, checking only odd indices\n for i in range(1, len(nums), 2):\n # Check if the number at the current odd index is not odd\n if nums[i] % 2 == 0:\n return False\n # If the loop completes without returning False, all odd indices contain odd numbers\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(nums):\n # Iterate through the list using enumerate to get both index and value\n for i, x in enumerate(nums):\n # Check if the index is odd and the number at that index is even\n if i % 2 != 0 and x % 2 == 0:\n return False # Return False if an odd index contains an even number\n return True # Return True if all odd indices contain odd numbers", "matching_cluster_idx": 2}, {"solution": "def odd_position(nums):\n # Check if every odd index contains an odd number\n return all(x % 2 for x in nums[1::2])", "matching_cluster_idx": 4}, {"solution": "def odd_position(nums):\n # Iterate over the list, checking elements at odd indices\n for i in range(1, len(nums), 2):\n # Check if the element at an odd index is not odd\n if nums[i] % 2 == 0:\n return False\n # Return True if all odd-index elements are odd\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(nums):\n # Iterate over the list using enumerate to get both index and value\n for i, x in enumerate(nums):\n # Check if the index is odd and the number is not odd\n if i % 2 != 0 and x % 2 == 0:\n return False\n return True", "matching_cluster_idx": 2}, {"solution": "def odd_position(lst):\n # Iterate over each element in the list except the first one\n return all(x % 2 != 0 for x in lst[1::2])", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n # Loop through the list using range and step to check only odd indices\n for i in range(1, len(lst), 2):\n # If the number at the odd index is not odd, return False\n if lst[i] % 2 == 0:\n return False\n # If all odd indices contain odd numbers, return True\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(nums):\n # Check each element at an odd index to see if it's an odd number\n return all(x % 2 for i, x in enumerate(nums) if i % 2)", "matching_cluster_idx": 2}]}, "Mbpp/777": {"dps": null, "dps_norm": null, "pass@1": 8.0, "profiled": []}, "Mbpp/781": {"dps": 71.61417322834646, "dps_norm": 62.0, "pass@1": 88.0, "profiled": [{"solution": "import math\ndef count_divisors(n):\n # Initialize count of divisors\n c = 0\n # Iterate over possible divisors\n for i in range(1, int(math.sqrt(n)) + 1):\n # If i divides n, increment count\n if n % i == 0:\n c += 1\n # If i is not the square root of n, increment count for the complement divisor\n if i != n // i:\n c += 1\n # Check if count of divisors is even\n return c % 2 == 0", "matching_cluster_idx": 4}, {"solution": "def count_divisors(n):\n # Initialize a counter to keep track of divisors\n i = 1\n count = 0\n # Iterate from 1 to n to find divisors\n while i <= n:\n if n % i == 0:\n # If i is a divisor, increment the count\n count += 1\n i += 1\n # Return True if the count of divisors is even, False otherwise\n if count % 2 == 0:\n return True\n else:\n return False", "matching_cluster_idx": -1}, {"solution": "def count_divisors(n):\n # Initialize count of divisors\n count = 0\n \n # Iterate through possible divisors\n for i in range(1, int(n**0.5) + 1):\n # If 'i' is a divisor of 'n'\n if n % i == 0:\n # If both divisors are the same, increment count by 1\n if i == n // i:\n count += 1\n else:\n # If different, increment count by 2\n count += 2\n \n # Check if the count of divisors is even\n return count % 2 == 0", "matching_cluster_idx": 4}, {"solution": "def count_divisors(n):\n # Initialize divisor count to 0\n cnt = 0\n \n # Iterate from 1 to n (inclusive) to find divisors\n for i in range(1, n + 1):\n if n % i == 0:\n cnt += 1\n \n # Return True if the count of divisors is even, False otherwise\n return (cnt % 2 == 0)", "matching_cluster_idx": 1}, {"solution": "def count_divisors(n):\n # Initialize a counter for the number of divisors\n divisor_count = 0\n \n # Iterate through numbers from 1 to n to check for divisors\n for i in range(1, n + 1):\n # If i divides n evenly, it is a divisor\n if n % i == 0:\n divisor_count += 1\n \n # Check if the number of divisors is even\n if divisor_count % 2 == 0:\n return True\n else:\n return False", "matching_cluster_idx": 1}, {"solution": "def count_divisors(n):\n # Initialize counter for divisors\n count = 0\n \n # Iterate through possible divisors up to the square root of n\n for i in range(1, int(n**0.5) + 1):\n # Check if i is a divisor of n\n if n % i == 0:\n # If i is a divisor, increment count\n count += 1\n # Check if the corresponding divisor (n // i) is different\n if n // i != i:\n # If it's different, increment count again\n count += 1\n \n # Check if the total count of divisors is even\n return count % 2 == 0", "matching_cluster_idx": 4}, {"solution": "def count_divisors(n):\n count = 0\n # Loop through possible divisors up to the square root of n\n i = 1\n while i * i <= n:\n # Check if i is a divisor of n\n if n % i == 0:\n # If divisors are the same, increment count by 1\n if i == n // i:\n count += 1\n # If divisors are different, increment count by 2\n else:\n count += 2\n i += 1\n # Return True if count is even, False otherwise\n return count % 2 == 0", "matching_cluster_idx": 3}, {"solution": "from math import sqrt\ndef count_divisors(n):\n # Initialize a counter for divisors\n count = 0\n # Iterate from 1 to the square root of n\n for i in range(1, int(sqrt(n)) + 1):\n # Check if i is a divisor of n\n if n % i == 0:\n # If i is a divisor, increment count\n count += 1\n # If i and n//i are different, increment count again\n if i != n // i:\n count += 1\n # Return True if the count of divisors is even, False otherwise\n return count % 2 == 0", "matching_cluster_idx": 4}, {"solution": "def count_divisors(n):\n # Initialize a counter for divisors\n divisor_count = 0\n \n # Iterate through numbers from 1 to n to find divisors\n for i in range(1, n + 1):\n if n % i == 0:\n divisor_count += 1\n \n # Check if the number of divisors is even\n if divisor_count % 2 == 0:\n return True\n else:\n return False", "matching_cluster_idx": 0}, {"solution": "def count_divisors(n):\n # Initialize the count of divisors\n divisor_count = 0\n \n # Loop through potential divisors up to the square root of n\n i = 1\n while i * i <= n:\n # If i is a divisor of n\n if n % i == 0:\n # If both divisors are the same, count only once\n if i == n // i:\n divisor_count += 1\n else:\n # Count both divisors\n divisor_count += 2\n i += 1\n \n # Return True if the count of divisors is even, otherwise False\n return divisor_count % 2 == 0", "matching_cluster_idx": 3}, {"solution": "import math\ndef count_divisors(num):\n # Initialize count of divisors\n cnt = 0\n # Iterate over possible divisors\n for i in range(1, int(math.sqrt(num)) + 1):\n # If 'i' is a divisor of 'num'\n if (num % i == 0):\n # If 'i' and 'num/i' are the same, increment cnt by 1\n if (i == num // i):\n cnt += 1\n else:\n # Increment cnt by 2 for both divisors\n cnt += 2\n # Check if the count of divisors is even\n if (cnt % 2 == 0):\n return True\n else:\n return False", "matching_cluster_idx": 4}, {"solution": "def count_divisors(n):\n # Initialize a counter for divisors\n c = 0\n \n # Iterate over all numbers from 1 to n (inclusive)\n for i in range(1, n + 1):\n # If i is a divisor of n, increment the counter\n if n % i == 0:\n c += 1\n \n # Check if the count of divisors is even\n return c % 2 == 0", "matching_cluster_idx": 0}, {"solution": "def count_divisors(n):\n # Initialize a counter for divisors\n count = 0\n # Iterate over possible divisors up to the square root of n\n for i in range(1, int(n**0.5) + 1):\n # If i is a divisor of n\n if n % i == 0:\n # If both divisors are the same, increment count by 1\n if n // i == i:\n count += 1\n # If divisors are different, increment count by 2\n else:\n count += 2\n # Check if the count of divisors is even\n if count % 2 == 0:\n return True\n else:\n return False", "matching_cluster_idx": 4}, {"solution": "def count_divisors(n): \n # Initialize divisor count to 0\n divisor_count = 0\n # Loop through possible divisors\n for i in range(1, n + 1): \n # If i is a divisor of n, increment divisor count\n if n % i == 0: \n divisor_count += 1\n # Check if the divisor count is even\n return divisor_count % 2 == 0", "matching_cluster_idx": 0}, {"solution": "def count_divisors(n): \n # Initialize the counter\n c = 0\n # Loop to iterate through possible divisors\n for i in range(1, n + 1): \n # Check if i is a divisor of n\n if n % i == 0: \n # Increment counter if i is a divisor\n c += 1\n # Return True if the count of divisors is even, otherwise False\n return c % 2 == 0", "matching_cluster_idx": 0}, {"solution": "def count_divisors(n):\n # Initialize a counter for divisors\n count = 0\n \n # Iterate through all numbers from 1 to n\n for i in range(1, n + 1):\n # Check if i is a divisor of n\n if n % i == 0:\n count += 1\n \n # Check if the count of divisors is even\n if count % 2 == 0:\n return True\n else:\n return False", "matching_cluster_idx": 1}, {"solution": "def count_divisors(n):\n # Initialize a counter for divisors\n count = 0\n \n # Loop through numbers from 1 to the square root of n\n for i in range(1, int(n**0.5) + 1):\n # Check if i is a divisor of n\n if n % i == 0:\n # If divisors are equal, increment count by 1\n if i == n // i:\n count += 1\n else:\n # Increment count by 2 if divisors are not equal\n count += 2\n \n # Check if the count of divisors is even\n if count % 2 == 0:\n return True\n else:\n return False", "matching_cluster_idx": 4}, {"solution": "def count_divisors(n):\n # Initialize a counter for divisors\n divisors_count = 0\n \n # Loop through all numbers from 1 to n (inclusive)\n for i in range(1, n + 1):\n # If i divides n without a remainder, it is a divisor\n if (n % i == 0):\n divisors_count += 1\n \n # Return True if the count of divisors is even, False otherwise\n return divisors_count % 2 == 0", "matching_cluster_idx": 1}, {"solution": "def count_divisors(n): \n # Initialize divisor count to 0\n count = 0\n \n # Iterate through possible divisors\n for i in range(1, int(n ** 0.5) + 1): \n if (n % i == 0): \n # If divisors are equal, count only once\n if (n / i == i): \n count += 1\n # If divisors are different, count both\n else: \n count += 2\n \n # Check if the number of divisors is even\n if count % 2 == 0: \n return 1\n else: \n return 0", "matching_cluster_idx": 4}, {"solution": "def count_divisors(n):\n # Initialize count of divisors\n c = 0\n # Iterate from 1 to the number\n for i in range(1, n + 1):\n # If i is a divisor of n, increment the count\n if (n % i == 0):\n c += 1\n # Return True if the count of divisors is even, otherwise False\n return bool(c % 2 == 0)", "matching_cluster_idx": 1}]}, "Mbpp/800": {"dps": 76.86567164179104, "dps_norm": 70.0, "pass@1": 76.0, "profiled": [{"solution": "def remove_all_spaces(s):\n # Using the join method to concatenate characters excluding spaces\n return ''.join([char for char in s if char != ' '])", "matching_cluster_idx": 0}, {"solution": "def remove_all_spaces(text):\n # Use the replace method to substitute all whitespace characters with an empty string\n result = text.replace(\" \", \"\")\n return result", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input):\n # Initialize an empty string to store the result\n result = ''\n # Iterate through each character in the input string\n for i in input:\n # Check if the character is not a whitespace\n if i != ' ':\n # Append non-whitespace characters to the result string\n result += i\n # Return the result string without any whitespaces\n return result", "matching_cluster_idx": 0}, {"solution": "def remove_all_spaces(input_string):\n # Use the replace method to remove all spaces from the input string\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(s):\n # The translate method removes all characters in the string that are present in the translation table.\n # str.maketrans creates a translation table that can be used with str.translate to replace specified characters.\n # Here, it is used to remove all whitespace characters.\n return s.translate(str.maketrans('', '', ' '))", "matching_cluster_idx": 3}, {"solution": "def remove_all_spaces(text):\n # Initialize an empty string to store the result\n result = \"\"\n \n # Iterate through each character in the input string\n for char in text:\n # Check if the character is not a whitespace\n if char != \" \":\n # Append the non-whitespace character to the result string\n result += char\n \n # Return the result string without any whitespaces\n return result", "matching_cluster_idx": 0}, {"solution": "def remove_all_spaces(str1):\n # Use the replace method to remove all spaces from the string\n return str1.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n # Remove all whitespaces from the input string using string's replace method\n # The replace method takes two arguments: the substring to be replaced and the substring to replace with\n # By passing an empty string as the second argument, all occurrences of the first argument are replaced\n input_string = input_string.replace(\" \", \"\")\n return input_string", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(str1):\n # Using the replace method to remove all spaces from the string\n return str1.replace(' ', '')", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(str1):\n # The replace() method is used to replace all occurrences of a specified substring with another substring.\n # In this case, it removes all spaces (' ') from the input string.\n return str1.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(str):\n # Initialize an empty string to store the result\n result = \"\"\n # Iterate through each character in the input string\n for i in str:\n # Check if the character is not a space\n if i != ' ':\n # If not a space, add it to the result string\n result += i\n # Return the result string with all spaces removed\n return result", "matching_cluster_idx": 0}, {"solution": "def remove_all_spaces(text):\n # Use the replace method to remove all whitespace characters from the string\n return text.replace(' ', '')", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(text):\n # Use the translate method with str.maketrans to remove all spaces\n return text.translate(str.maketrans('', '', ' '))", "matching_cluster_idx": 3}, {"solution": "def remove_all_spaces(input_str):\n # Using the join method to concatenate characters that are not spaces\n return ''.join([char for char in input_str if char != ' '])", "matching_cluster_idx": 0}, {"solution": "def remove_all_spaces(string):\n # Remove all whitespaces from the string using replace method\n string = string.replace(\" \", \"\")\n return string", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(s):\n # Initialize an empty string to store the result\n s1 = ''\n # Iterate through each character in the input string\n for char in s:\n # If the character is not a whitespace, add it to the result string\n if char != ' ':\n s1 = s1 + char\n # Return the result string without any whitespaces\n return s1", "matching_cluster_idx": 0}, {"solution": "def remove_all_spaces(input_string):\n # Use the replace method to substitute spaces with no space character\n result = input_string.replace(' ', '')\n return result", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n # Using the replace method to substitute all whitespace characters with an empty string\n result_string = input_string.replace(' ', '')\n return result_string", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(s):\n # Initialize an empty string to store the result\n s1 = \"\"\n # Iterate through each character in the input string\n for i in s:\n # If the character is not a space, add it to the result string\n if i != \" \":\n s1 += i\n # Return the result string without any spaces\n return s1", "matching_cluster_idx": 0}, {"solution": "def remove_all_spaces(input_string):\n # Replace all whitespace characters with no space and return the result\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}]}, "Mbpp/805": {"dps": 71.5807560137457, "dps_norm": 85.0, "pass@1": 81.0, "profiled": [{"solution": "def max_sum_list(list):\n # Initialize an empty list to store the list with the maximum sum\n max_sum_list = []\n # Initialize the maximum sum to a very small value\n max_sum = float('-inf')\n\n # Iterate through each list in the list of lists\n for lst in list:\n # Calculate the sum of the current list\n sum = 0\n for i in lst:\n sum += i\n\n # Check if the current sum is greater than the maximum sum found so far\n if max_sum < sum:\n # If yes, update the maximum sum and the list with the maximum sum\n max_sum = sum\n max_sum_list = lst\n\n # Return the list with the maximum sum\n return max_sum_list", "matching_cluster_idx": 1}, {"solution": "def max_sum_list(input_list):\n # Check if the input list is empty\n if not input_list:\n return None\n \n # Sort the list of lists based on the sum of elements in descending order\n input_list.sort(key=lambda x: sum(x), reverse=True)\n \n # Return the first list from the sorted list (the one with the highest sum)\n return input_list[0]", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(list1):\n # Initialize the list with the first sublist and set max_sum to its sum\n max_sum = sum(list1[0])\n res = list1[0]\n \n # Iterate over the list of lists\n for i in list1[1:]:\n # Calculate the sum of the current sublist\n cur_sum = sum(i)\n \n # Check if the current sum is greater than the max_sum found so far\n if cur_sum > max_sum:\n max_sum = cur_sum\n res = i\n \n # Return the sublist with the highest sum\n return res", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lst):\n # Calculate the sum of elements in each sublist and find the index of the sublist with the maximum sum\n return lst[[sum(i) for i in lst].index(max([sum(i) for i in lst]))]", "matching_cluster_idx": 2}, {"solution": "def max_sum_list(lists):\n # Find the maximum sum among all sublists\n max_sum = max([sum(sublist) for sublist in lists])\n # Return the sublist with the maximum sum\n return [sublist for sublist in lists if sum(sublist) == max_sum][0]", "matching_cluster_idx": 2}, {"solution": "from typing import List\ndef max_sum_list(lists: List[List[int]]) -> List[int]:\n # Find the list with the maximum sum of elements\n max_list = max(lists, key=lambda x: sum(x))\n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n # Find the list with the maximum sum of elements\n max_list = max(lists, key=sum)\n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n # Find the list with the maximum sum using a generator expression\n return max(lists, key=sum)", "matching_cluster_idx": 4}, {"solution": "from copy import deepcopy\ndef max_sum_list(test_list):\n # Using list comprehension to create a deep copy of the input list\n res = deepcopy(test_list)\n \n # Sorting the copied list based on the sum of elements in each sublist in descending order\n res.sort(key=sum, reverse=True)\n \n # Returning the first sublist from the sorted list, which has the highest sum\n return res[0]", "matching_cluster_idx": 0}, {"solution": "def max_sum_list(lists):\n # Initialize a list to keep track of lists with positive sums\n positive_sum_lists = [lst for lst in lists if sum(lst) > 0]\n \n # If no positive sum lists are found, return the original list\n if not positive_sum_lists:\n return lists[0]\n \n # Return the list with the highest sum of elements\n return max(positive_sum_lists, key=sum)", "matching_cluster_idx": 2}, {"solution": "def max_sum_list(lists):\n # Use the max function with key parameter to find the list with the maximum sum of elements\n max_sum_list = max(lists, key=sum)\n return max_sum_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(list_of_lists):\n # Initialize max_sum to a very small number to ensure any sum of the lists will be higher\n max_sum = float('-inf')\n # Initialize max_index to -1 to mark that no list has been checked yet\n max_index = -1\n \n # Iterate over the list of lists\n for index, lst in enumerate(list_of_lists):\n # Calculate the sum of the current list\n current_sum = sum(lst)\n # Check if the current sum is greater than the max_sum found so far\n if current_sum > max_sum:\n # Update max_sum and max_index\n max_sum = current_sum\n max_index = index\n \n # Return the list with the highest sum of elements\n return list_of_lists[max_index]", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lst):\n # Initialize a variable to keep track of the maximum sum\n max_sum = -float('inf')\n # Initialize a variable to store the list with the maximum sum\n result = []\n \n # Iterate through each list in the list of lists\n for sublist in lst:\n # Calculate the sum of the current sublist\n current_sum = sum(sublist)\n # Update the maximum sum and result if the current sum is higher\n if current_sum > max_sum:\n max_sum = current_sum\n result = sublist\n \n # Return the list with the highest sum\n return result", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n # Calculate the sum of each sublist and find the maximum sum\n max_sum = max(sum(lst) for lst in lists)\n # Return the sublist that has the maximum sum\n return [lst for lst in lists if sum(lst) == max_sum][0]", "matching_cluster_idx": 2}, {"solution": "def max_sum_list(list1):\n # Find the list with the maximum sum of elements\n max_element = max(list1, key=sum)\n return max_element", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lst):\n # Find the list with the maximum sum of elements using max function and key parameter\n return max(lst, key=sum)", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lst):\n # Find the list with the maximum sum of elements using the max function and a lambda function as the key\n res = max(lst, key=lambda i: sum(i))\n return res", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n # Find the list with the maximum sum of elements\n return max(lists, key=sum)", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(test_list):\n # Use a generator expression to calculate the sum of each sublist\n # Find the sublist with the maximum sum and return it\n res = max(test_list, key=sum)\n return res", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lst):\n # Find the maximum sum among the sublists using the max function with a key that calculates the sum of each sublist\n return max(lst, key=sum)", "matching_cluster_idx": 4}]}, "Mbpp/808": {"dps": 22.894736842105264, "dps_norm": 66.66666666666667, "pass@1": 95.0, "profiled": [{"solution": "def check_K(test_tup, K):\n # Use the any() function to check if K is present in the tuple\n res = any(K == ele for ele in test_tup)\n return res", "matching_cluster_idx": 1}, {"solution": "def check_K(test_tup, K):\n # Check if the integer K is present in the tuple test_tup\n res = K in test_tup\n return res", "matching_cluster_idx": 4}, {"solution": "def check_K(test_tuple, K):\n # Check if the element K is in the tuple test_tuple using the 'in' keyword\n res = K in test_tuple\n return res", "matching_cluster_idx": 4}, {"solution": "def check_K(test_tup, K):\n # Check if the element K is in the tuple test_tup\n res = K in test_tup\n return res", "matching_cluster_idx": 4}, {"solution": "def check_K(test_tup, K):\n # Check if K is in the tuple\n res = K in test_tup\n return res", "matching_cluster_idx": 4}, {"solution": "def check_K(test_tup, K):\n # Initialize a flag to False\n res = False\n \n # Iterate through each element in the tuple\n for ele in test_tup:\n # Check if the current element is equal to K\n if ele == K:\n # If found, set the flag to True and break the loop\n res = True\n break\n \n # Return the result\n return res", "matching_cluster_idx": 2}, {"solution": "def check_K(test_tup, K):\n # Check if the element K is present in the tuple test_tup\n res = K in test_tup\n return res", "matching_cluster_idx": 4}, {"solution": "def check_K(test_tup, K):\n # Check if K is in the tuple\n res = K in test_tup\n return res", "matching_cluster_idx": 4}, {"solution": "def check_K(test_tup, K):\n # Use the 'in' keyword to check if 'K' is present in 'test_tup'\n res = K in test_tup\n return res", "matching_cluster_idx": 4}, {"solution": "def check_K(test_tup, K):\n # Initialize a flag to False, assuming k is not in the tuple\n res = False\n # Loop through each element in the tuple\n for ele in test_tup:\n # Check if the current element is equal to k\n if ele == K:\n # Set the flag to True and break out of the loop\n res = True\n break\n # Return the result indicating whether k was found in the tuple\n return (res)", "matching_cluster_idx": 3}, {"solution": "def check_K(test_tup, K):\n # Initialize a counter to zero\n count = 0\n # Iterate through each element in the tuple\n for ele in test_tup:\n # Increment the counter if the element is equal to K\n if ele == K:\n count += 1\n # Return True if any element was equal to K, otherwise False\n return (count >= 1)", "matching_cluster_idx": -1}, {"solution": "def check_K(test_tup, K):\n # Use the any() function to check if K is in the tuple\n res = any(elem == K for elem in test_tup)\n return res", "matching_cluster_idx": 1}, {"solution": "def check_K(test_tup, K):\n # Use the any() function to check if K is in the tuple\n res = any(item == K for item in test_tup)\n return res", "matching_cluster_idx": 1}, {"solution": "def check_K(test_tup, K):\n # Initialize a result variable to False\n res = False\n \n # Iterate through each element in the tuple\n for ele in test_tup:\n # Check if the current element is equal to K\n if ele == K:\n res = True\n break # Exit the loop if K is found\n \n return res", "matching_cluster_idx": 3}, {"solution": "def check_K(test_tup, K):\n # Check if the element K is present in the tuple test_tup\n res = K in test_tup\n return res", "matching_cluster_idx": 4}, {"solution": "def check_K(test_tup, K):\n # Initialize a result variable to False\n res = False\n # Iterate through each element in the tuple\n for ele in test_tup:\n # Check if the current element equals the target value K\n if ele == K:\n res = True\n break # Exit the loop if K is found\n return res", "matching_cluster_idx": 3}, {"solution": "def check_K(test_tup, K):\n # Check if the tuple contains the element K\n res = K in test_tup\n return res", "matching_cluster_idx": 4}, {"solution": "def check_K(test_tup, K):\n # Iterate through each element in the tuple\n for ele in test_tup:\n # Check if the current element is equal to k\n if ele == K:\n # Return True if k is found in the tuple\n return True\n # Return False if k is not found in the tuple\n return False", "matching_cluster_idx": 3}, {"solution": "def check_K(test_tup, K):\n # Use the any() function to check if K is in the tuple\n res = K in test_tup\n return res", "matching_cluster_idx": 4}, {"solution": "def check_K(test_tup, K):\n # Check if K is in the tuple\n res = K in test_tup\n return res", "matching_cluster_idx": 4}]}}} \ No newline at end of file diff --git a/results/evalperf/deepseek-ai--DeepSeek-Coder-V2-Lite-Instruct_vllm_temp_1.0_evalperf_results.brief.json b/results/evalperf/deepseek-ai--DeepSeek-Coder-V2-Lite-Instruct_vllm_temp_1.0_evalperf_results.brief.json new file mode 100644 index 0000000..45e8ace --- /dev/null +++ b/results/evalperf/deepseek-ai--DeepSeek-Coder-V2-Lite-Instruct_vllm_temp_1.0_evalperf_results.brief.json @@ -0,0 +1 @@ +{"date": "2024-10-19 16:31", "config": {"n_samples": 100, "temperature": 1.0, "min_correct": 10, "max_profile": 20}, "summary": {"dps": 82.81873138697289, "dps_norm": 78.09379634032757, "pass@1": 79.04237288135593}, "eval": {"HumanEval/9": {"dps": 72.3186119873817, "dps_norm": 66.66666666666667, "pass@1": 100.0, "profiled": [{"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n \n max_so_far = numbers[0]\n rolling_max_list = [max_so_far]\n \n for num in numbers[1:]:\n max_so_far = max(max_so_far, num)\n rolling_max_list.append(max_so_far)\n \n return rolling_max_list", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n\n max_so_far = numbers[0]\n rolling_max_list = [max_so_far]\n\n for num in numbers[1:]:\n max_so_far = max(max_so_far, num)\n rolling_max_list.append(max_so_far)\n\n return rolling_max_list", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n\n max_so_far = numbers[0]\n rolling_max_list = [max_so_far]\n\n for num in numbers[1:]:\n max_so_far = max(max_so_far, num)\n rolling_max_list.append(max_so_far)\n\n return rolling_max_list", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n \n max_so_far = numbers[0]\n rolling_max_list = [max_so_far]\n \n for num in numbers[1:]:\n max_so_far = max(max_so_far, num)\n rolling_max_list.append(max_so_far)\n \n return rolling_max_list", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n \n rolling_max_list = [numbers[0]]\n current_max = numbers[0]\n \n for num in numbers[1:]:\n current_max = max(current_max, num)\n rolling_max_list.append(current_max)\n \n return rolling_max_list", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n \n max_so_far = numbers[0]\n rolling_max_list = [max_so_far]\n \n for num in numbers[1:]:\n max_so_far = max(max_so_far, num)\n rolling_max_list.append(max_so_far)\n \n return rolling_max_list", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n \n max_so_far = numbers[0]\n rolling_max_list = [max_so_far]\n \n for num in numbers[1:]:\n if num > max_so_far:\n max_so_far = num\n rolling_max_list.append(max_so_far)\n \n return rolling_max_list", "matching_cluster_idx": 8}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n\n rolling_max_list = [numbers[0]]\n current_max = numbers[0]\n\n for num in numbers[1:]:\n current_max = max(current_max, num)\n rolling_max_list.append(current_max)\n\n return rolling_max_list", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n \n rolling_max_list = [numbers[0]]\n current_max = numbers[0]\n \n for num in numbers[1:]:\n current_max = max(current_max, num)\n rolling_max_list.append(current_max)\n \n return rolling_max_list", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n\n rolling_max_list = [numbers[0]]\n for num in numbers[1:]:\n current_max = max(rolling_max_list[-1], num)\n rolling_max_list.append(current_max)\n \n return rolling_max_list", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n \n max_so_far = numbers[0]\n rolling_max_list = [max_so_far]\n \n for num in numbers[1:]:\n if num > max_so_far:\n max_so_far = num\n rolling_max_list.append(max_so_far)\n \n return rolling_max_list", "matching_cluster_idx": 8}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n \n rolling_max_list = [numbers[0]]\n current_max = numbers[0]\n \n for num in numbers[1:]:\n current_max = max(current_max, num)\n rolling_max_list.append(current_max)\n \n return rolling_max_list", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n \n max_so_far = numbers[0]\n rolling_max_list = [max_so_far]\n \n for num in numbers[1:]:\n if num > max_so_far:\n max_so_far = num\n rolling_max_list.append(max_so_far)\n \n return rolling_max_list", "matching_cluster_idx": 8}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n \n max_so_far = numbers[0]\n rolling_max_list = [max_so_far]\n \n for num in numbers[1:]:\n max_so_far = max(max_so_far, num)\n rolling_max_list.append(max_so_far)\n \n return rolling_max_list", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n \n max_so_far = numbers[0]\n result = [max_so_far]\n \n for num in numbers[1:]:\n max_so_far = max(max_so_far, num)\n result.append(max_so_far)\n \n return result", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n \n max_so_far = numbers[0]\n rolling_max_list = [max_so_far]\n \n for num in numbers[1:]:\n if num > max_so_far:\n max_so_far = num\n rolling_max_list.append(max_so_far)\n \n return rolling_max_list", "matching_cluster_idx": 8}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n \n max_so_far = numbers[0]\n result = [max_so_far]\n \n for num in numbers[1:]:\n max_so_far = max(max_so_far, num)\n result.append(max_so_far)\n \n return result", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n \n max_so_far = numbers[0]\n rolling_max_list = [max_so_far]\n \n for num in numbers[1:]:\n max_so_far = max(max_so_far, num)\n rolling_max_list.append(max_so_far)\n \n return rolling_max_list", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n \n max_so_far = numbers[0]\n result = [max_so_far]\n \n for num in numbers[1:]:\n if num > max_so_far:\n max_so_far = num\n result.append(max_so_far)\n \n return result", "matching_cluster_idx": 8}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n \n max_so_far = numbers[0]\n rolling_max_list = [max_so_far]\n \n for num in numbers[1:]:\n max_so_far = max(max_so_far, num)\n rolling_max_list.append(max_so_far)\n \n return rolling_max_list", "matching_cluster_idx": 4}]}, "HumanEval/0": {"dps": 59.853121175030594, "dps_norm": 63.90977443609023, "pass@1": 19.0, "profiled": [{"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n numbers.sort() # Sort the list first to make it easier to find close elements\n for i in range(len(numbers) - 1):\n if numbers[i + 1] - numbers[i] < threshold:\n return True\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n numbers.sort()\n for i in range(len(numbers) - 1):\n if numbers[i + 1] - numbers[i] < threshold:\n return True\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n numbers.sort()\n for i in range(len(numbers) - 1):\n if numbers[i + 1] - numbers[i] < threshold:\n return True\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n numbers.sort()\n for i in range(len(numbers) - 1):\n if numbers[i + 1] - numbers[i] < threshold:\n return True\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n if abs(numbers[i] - numbers[j]) < threshold:\n return True\n return False", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n numbers.sort()\n for i in range(len(numbers) - 1):\n if numbers[i+1] - numbers[i] < threshold:\n return True\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n numbers.sort()\n for i in range(len(numbers) - 1):\n if numbers[i + 1] - numbers[i] < threshold:\n return True\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n if abs(numbers[i] - numbers[j]) < threshold:\n return True\n return False", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n numbers.sort() # Sort the list to make it easier to find close elements\n for i in range(len(numbers) - 1):\n if numbers[i + 1] - numbers[i] < threshold:\n return True\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n numbers.sort()\n for i in range(len(numbers) - 1):\n if numbers[i + 1] - numbers[i] < threshold:\n return True\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n numbers.sort()\n for i in range(len(numbers) - 1):\n if numbers[i + 1] - numbers[i] < threshold:\n return True\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n numbers.sort()\n for i in range(len(numbers) - 1):\n if numbers[i + 1] - numbers[i] < threshold:\n return True\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n numbers.sort()\n for i in range(len(numbers) - 1):\n if numbers[i+1] - numbers[i] < threshold:\n return True\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n numbers.sort()\n for i in range(len(numbers) - 1):\n if numbers[i + 1] - numbers[i] < threshold:\n return True\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n if abs(numbers[i] - numbers[j]) < threshold:\n return True\n return False", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n numbers.sort()\n for i in range(len(numbers) - 1):\n if numbers[i + 1] - numbers[i] < threshold:\n return True\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n numbers.sort()\n for i in range(len(numbers) - 1):\n if numbers[i + 1] - numbers[i] < threshold:\n return True\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n numbers.sort()\n for i in range(len(numbers) - 1):\n if numbers[i + 1] - numbers[i] < threshold:\n return True\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n numbers.sort()\n for i in range(len(numbers) - 1):\n if numbers[i + 1] - numbers[i] < threshold:\n return True\n return False", "matching_cluster_idx": 3}]}, "HumanEval/4": {"dps": 74.01898734177215, "dps_norm": 83.33333333333333, "pass@1": 100.0, "profiled": [{"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if not numbers: # Check if the list is empty\n return 0\n mean = sum(numbers) / len(numbers) # Calculate the mean\n deviations = [abs(x - mean) for x in numbers] # Calculate absolute deviations\n mad = sum(deviations) / len(numbers) # Calculate the mean of the deviations\n return mad", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if not numbers:\n return 0\n mean = sum(numbers) / len(numbers)\n deviations = [abs(x - mean) for x in numbers]\n mad = sum(deviations) / len(numbers)\n return mad", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if not numbers:\n return 0\n mean = sum(numbers) / len(numbers)\n deviations = [abs(x - mean) for x in numbers]\n mad = sum(deviations) / len(numbers)\n return mad", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\"\n For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if not numbers: # Check if the list is empty\n return 0\n mean = sum(numbers) / len(numbers)\n deviations = [abs(x - mean) for x in numbers]\n mad = sum(deviations) / len(deviations)\n return mad", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if not numbers:\n raise ValueError(\"The input list must contain at least one number.\")\n \n mean = sum(numbers) / len(numbers)\n absolute_deviations = [abs(number - mean) for number in numbers]\n mad = sum(absolute_deviations) / len(numbers)\n \n return mad", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if not numbers: # Check if the list is empty\n return 0.0\n \n mean = sum(numbers) / len(numbers)\n deviations = [abs(x - mean) for x in numbers]\n mad = sum(deviations) / len(numbers)\n \n return mad", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if not numbers:\n return 0.0 # If the list is empty, return 0 to avoid division by zero\n\n mean = sum(numbers) / len(numbers)\n absolute_deviations = [abs(x - mean) for x in numbers]\n mad = sum(absolute_deviations) / len(numbers)\n return mad", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if not numbers: # Check if the list is empty\n return 0\n mean = sum(numbers) / len(numbers)\n deviations = [abs(num - mean) for num in numbers]\n mad = sum(deviations) / len(numbers)\n return mad", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if not numbers:\n return 0.0\n \n mean = sum(numbers) / len(numbers)\n absolute_deviations = [abs(num - mean) for num in numbers]\n mad = sum(absolute_deviations) / len(numbers)\n \n return mad", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" \n For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if not numbers: # Check if the list is empty\n return 0\n \n mean = sum(numbers) / len(numbers) # Calculate the mean\n deviations = [abs(x - mean) for x in numbers] # Calculate absolute deviations\n mad = sum(deviations) / len(numbers) # Calculate the mean of absolute deviations\n return mad", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if not numbers:\n return 0\n mean = sum(numbers) / len(numbers)\n deviations = [abs(x - mean) for x in numbers]\n mad = sum(deviations) / len(numbers)\n return mad", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if not numbers:\n return 0.0\n mean = sum(numbers) / len(numbers)\n mad = sum(abs(x - mean) for x in numbers) / len(numbers)\n return mad", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if not numbers: # Check if the list is empty\n return 0\n mean = sum(numbers) / len(numbers)\n deviations = [abs(num - mean) for num in numbers]\n mad = sum(deviations) / len(numbers)\n return mad", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if not numbers: # Check if the list is empty\n return 0\n mean = sum(numbers) / len(numbers)\n deviations = [abs(x - mean) for x in numbers]\n mad = sum(deviations) / len(numbers)\n return mad", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if not numbers: # Check if the list is empty\n return 0\n \n mean = sum(numbers) / len(numbers) # Calculate the mean of the numbers\n absolute_differences = [abs(x - mean) for x in numbers] # Calculate absolute differences\n mad = sum(absolute_differences) / len(numbers) # Calculate the mean of the absolute differences\n return mad", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if not numbers:\n return 0.0\n \n mean = sum(numbers) / len(numbers)\n deviations = [abs(x - mean) for x in numbers]\n mad = sum(deviations) / len(numbers)\n return mad", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if not numbers:\n return 0\n mean = sum(numbers) / len(numbers)\n deviations = [abs(x - mean) for x in numbers]\n mad = sum(deviations) / len(numbers)\n return mad", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if not numbers: # Check if the list is empty\n return 0.0\n mean = sum(numbers) / len(numbers)\n absolute_deviations = [abs(x - mean) for x in numbers]\n mad = sum(absolute_deviations) / len(numbers)\n return mad", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\"\n For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n \"\"\"\n if not numbers: # Check if the list is empty\n return 0\n \n mean = sum(numbers) / len(numbers) # Calculate the mean of the numbers\n absolute_deviations = [abs(x - mean) for x in numbers] # Calculate absolute deviations from the mean\n mad = sum(absolute_deviations) / len(numbers) # Calculate the mean of the absolute deviations\n \n return mad", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if not numbers:\n return 0.0\n\n mean_value = sum(numbers) / len(numbers)\n deviations = [abs(number - mean_value) for number in numbers]\n mad = sum(deviations) / len(numbers)\n return mad", "matching_cluster_idx": 4}]}, "HumanEval/16": {"dps": 32.55813953488372, "dps_norm": 43.888888888888886, "pass@1": 100.0, "profiled": [{"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lowercase to make the comparison case-insensitive\n string = string.lower()\n # Use a set to store distinct characters\n distinct_chars = set()\n # Iterate through each character in the string\n for char in string:\n # Add the character to the set of distinct characters\n distinct_chars.add(char)\n # Return the number of distinct characters\n return len(distinct_chars)", "matching_cluster_idx": 3}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lowercase to ignore case\n string = string.lower()\n # Use a set to store distinct characters\n distinct_chars = set()\n # Iterate through each character in the string\n for char in string:\n # Add the character to the set of distinct characters\n distinct_chars.add(char)\n # Return the number of distinct characters\n return len(distinct_chars)", "matching_cluster_idx": 3}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lowercase to make the comparison case-insensitive\n string = string.lower()\n # Use a set to store distinct characters\n distinct_chars = set()\n for char in string:\n distinct_chars.add(char)\n return len(distinct_chars)", "matching_cluster_idx": 3}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n distinct_characters = set()\n for char in string:\n distinct_characters.add(char.lower())\n return len(distinct_characters)", "matching_cluster_idx": 2}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n distinct_chars = set()\n for char in string:\n distinct_chars.add(char.lower())\n return len(distinct_chars)", "matching_cluster_idx": 2}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n distinct_chars = set()\n for char in string:\n distinct_chars.add(char.lower())\n return len(distinct_chars)", "matching_cluster_idx": 2}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n return len(set(string.lower()))", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lowercase to make the comparison case-insensitive\n string = string.lower()\n # Use a set to store distinct characters\n distinct_chars = set()\n for char in string:\n distinct_chars.add(char)\n # Return the number of distinct characters\n return len(distinct_chars)", "matching_cluster_idx": 3}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n distinct_chars = set()\n for char in string:\n distinct_chars.add(char.lower())\n return len(distinct_chars)", "matching_cluster_idx": 2}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lowercase to make the comparison case-insensitive\n string = string.lower()\n # Use a set to store distinct characters\n distinct_chars = set()\n # Iterate over each character in the string\n for char in string:\n # Add the character to the set of distinct characters\n distinct_chars.add(char)\n # Return the number of distinct characters\n return len(distinct_chars)", "matching_cluster_idx": 3}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lowercase to make the comparison case-insensitive\n string = string.lower()\n # Use a set to store distinct characters\n distinct_chars = set()\n # Iterate over each character in the string and add it to the set\n for char in string:\n distinct_chars.add(char)\n # Return the number of distinct characters\n return len(distinct_chars)", "matching_cluster_idx": 3}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lowercase to make the comparison case-insensitive\n lower_string = string.lower()\n # Use a set to store distinct characters\n distinct_chars = set()\n for char in lower_string:\n distinct_chars.add(char)\n # Return the number of distinct characters\n return len(distinct_chars)", "matching_cluster_idx": 3}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lowercase to make the comparison case-insensitive\n string = string.lower()\n # Use a set to store distinct characters\n distinct_chars = set()\n for char in string:\n distinct_chars.add(char)\n return len(distinct_chars)", "matching_cluster_idx": 3}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lowercase to make the comparison case-insensitive\n string = string.lower()\n # Use a set to store distinct characters\n distinct_chars = set()\n # Iterate over each character in the string\n for char in string:\n # Add the character to the set\n distinct_chars.add(char)\n # Return the number of distinct characters\n return len(distinct_chars)", "matching_cluster_idx": 3}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lowercase to ensure case-insensitive comparison\n lower_string = string.lower()\n # Use a set to store distinct characters\n distinct_chars = set()\n for char in lower_string:\n distinct_chars.add(char)\n # Return the number of distinct characters\n return len(distinct_chars)", "matching_cluster_idx": 3}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n distinct_chars = set()\n for char in string:\n distinct_chars.add(char.lower())\n return len(distinct_chars)", "matching_cluster_idx": 2}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n distinct_chars = set()\n for char in string:\n distinct_chars.add(char.lower())\n return len(distinct_chars)", "matching_cluster_idx": 2}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lowercase to make the comparison case-insensitive\n string_lower = string.lower()\n # Use a set to store distinct characters\n distinct_chars = set()\n for char in string_lower:\n distinct_chars.add(char)\n # Return the number of distinct characters\n return len(distinct_chars)", "matching_cluster_idx": 3}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lowercase to make the comparison case-insensitive\n string = string.lower()\n # Use a set to store distinct characters\n distinct_chars = set()\n # Iterate through each character in the string and add it to the set\n for char in string:\n distinct_chars.add(char)\n # Return the number of distinct characters\n return len(distinct_chars)", "matching_cluster_idx": 3}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lowercase to make the comparison case-insensitive\n string = string.lower()\n # Use a set to store distinct characters\n distinct_chars = set()\n # Iterate through each character in the string\n for char in string:\n # Add the character to the set of distinct characters\n distinct_chars.add(char)\n # Return the number of distinct characters\n return len(distinct_chars)", "matching_cluster_idx": 3}]}, "HumanEval/20": {"dps": 84.21307506053269, "dps_norm": 88.88888888888889, "pass@1": 100.0, "profiled": [{"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n if len(numbers) < 2:\n raise ValueError(\"The list must contain at least two elements.\")\n \n # Sort the list to make it easier to find the closest elements\n numbers.sort()\n \n # Initialize variables to store the closest pair and the smallest difference\n closest_pair = (numbers[0], numbers[1])\n smallest_diff = abs(numbers[1] - numbers[0])\n \n # Iterate through the list to find the closest pair\n for i in range(len(numbers) - 1):\n current_diff = abs(numbers[i + 1] - numbers[i])\n if current_diff < smallest_diff:\n smallest_diff = current_diff\n closest_pair = (numbers[i], numbers[i + 1])\n \n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n min_diff = float('inf')\n closest_pair = (0.0, 0.0)\n\n numbers.sort()\n\n for i in range(len(numbers) - 1):\n diff = numbers[i + 1] - numbers[i]\n if diff < min_diff:\n min_diff = diff\n closest_pair = (numbers[i], numbers[i + 1])\n\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n # Sort the list to ensure that the closest elements are adjacent\n numbers.sort()\n \n # Initialize variables to store the closest pair and the smallest difference\n closest_pair = (numbers[0], numbers[1])\n smallest_diff = numbers[1] - numbers[0]\n \n # Iterate through the sorted list to find the closest pair\n for i in range(1, len(numbers) - 1):\n diff = numbers[i + 1] - numbers[i]\n if diff < smallest_diff:\n smallest_diff = diff\n closest_pair = (numbers[i], numbers[i + 1])\n \n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n if len(numbers) < 2:\n raise ValueError(\"The list must contain at least two elements.\")\n \n # Sort the numbers first\n numbers.sort()\n \n # Initialize the minimum difference to a large number\n min_diff = float('inf')\n closest_pair = (0.0, 0.0)\n \n # Iterate through the sorted list and find the pair with the smallest difference\n for i in range(len(numbers) - 1):\n diff = numbers[i + 1] - numbers[i]\n if diff < min_diff:\n min_diff = diff\n closest_pair = (numbers[i], numbers[i + 1])\n \n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n # Sort the list of numbers\n sorted_numbers = sorted(numbers)\n \n # Initialize variables to store the closest pair and the smallest difference\n closest_pair = (sorted_numbers[0], sorted_numbers[1])\n smallest_diff = abs(sorted_numbers[1] - sorted_numbers[0])\n \n # Iterate through the sorted list to find the closest pair\n for i in range(1, len(sorted_numbers) - 1):\n current_diff = abs(sorted_numbers[i + 1] - sorted_numbers[i])\n if current_diff < smallest_diff:\n smallest_diff = current_diff\n closest_pair = (sorted_numbers[i], sorted_numbers[i + 1])\n \n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n if len(numbers) < 2:\n raise ValueError(\"The list must contain at least two elements.\")\n \n # Sort the list\n numbers.sort()\n \n # Initialize the minimum difference to a large value\n min_diff = float('inf')\n closest_pair = (0.0, 0.0)\n \n # Iterate through the sorted list and find the pair with the minimum difference\n for i in range(len(numbers) - 1):\n diff = numbers[i + 1] - numbers[i]\n if diff < min_diff:\n min_diff = diff\n closest_pair = (numbers[i], numbers[i + 1])\n \n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n if len(numbers) < 2:\n raise ValueError(\"The list must contain at least two elements.\")\n \n # Sort the list to find the closest elements easily\n sorted_numbers = sorted(numbers)\n \n # Initialize variables to store the closest pair\n closest_pair = (sorted_numbers[0], sorted_numbers[1])\n min_diff = abs(sorted_numbers[0] - sorted_numbers[1])\n \n # Iterate through the sorted list to find the closest pair\n for i in range(1, len(sorted_numbers) - 1):\n diff = abs(sorted_numbers[i] - sorted_numbers[i + 1])\n if diff < min_diff:\n min_diff = diff\n closest_pair = (sorted_numbers[i], sorted_numbers[i + 1])\n \n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n if len(numbers) < 2:\n raise ValueError(\"The list must contain at least two elements.\")\n \n # Sort the list to easily find the closest elements\n sorted_numbers = sorted(numbers)\n \n # Initialize variables to store the minimum difference and the pair of numbers\n min_diff = float('inf')\n closest_pair = (0.0, 0.0)\n \n # Iterate through the sorted list to find the closest pair\n for i in range(len(sorted_numbers) - 1):\n diff = sorted_numbers[i + 1] - sorted_numbers[i]\n if diff < min_diff:\n min_diff = diff\n closest_pair = (sorted_numbers[i], sorted_numbers[i + 1])\n \n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n if len(numbers) < 2:\n raise ValueError(\"The input list must contain at least two numbers.\")\n \n closest_pair = (numbers[0], numbers[1])\n min_diff = abs(numbers[0] - numbers[1])\n \n for i in range(len(numbers)):\n for j in range(i+1, len(numbers)):\n diff = abs(numbers[i] - numbers[j])\n if diff < min_diff:\n min_diff = diff\n closest_pair = (min(numbers[i], numbers[j]), max(numbers[i], numbers[j]))\n \n return closest_pair", "matching_cluster_idx": 3}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n if len(numbers) < 2:\n raise ValueError(\"The list must contain at least two elements.\")\n \n # Sort the list to find the closest elements efficiently\n numbers.sort()\n \n # Initialize the smallest difference to a large value\n smallest_diff = float('inf')\n closest_pair = (0.0, 0.0)\n \n # Iterate through the sorted list to find the closest pair\n for i in range(len(numbers) - 1):\n current_diff = numbers[i + 1] - numbers[i]\n if current_diff < smallest_diff:\n smallest_diff = current_diff\n closest_pair = (numbers[i], numbers[i + 1])\n \n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n if len(numbers) < 2:\n raise ValueError(\"The input list must contain at least two elements.\")\n \n closest_pair = (numbers[0], numbers[1])\n min_diff = abs(numbers[0] - numbers[1])\n \n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n diff = abs(numbers[i] - numbers[j])\n if diff < min_diff:\n min_diff = diff\n closest_pair = (min(numbers[i], numbers[j]), max(numbers[i], numbers[j]))\n \n return closest_pair", "matching_cluster_idx": 3}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n if len(numbers) < 2:\n raise ValueError(\"The list must contain at least two elements.\")\n\n numbers.sort()\n min_diff = float('inf')\n closest_pair = (0.0, 0.0)\n\n for i in range(len(numbers) - 1):\n current_diff = numbers[i + 1] - numbers[i]\n if current_diff < min_diff:\n min_diff = current_diff\n closest_pair = (numbers[i], numbers[i + 1])\n\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n if len(numbers) < 2:\n raise ValueError(\"The list must contain at least two elements.\")\n \n # Sort the list to ensure the closest elements are adjacent\n numbers.sort()\n \n # Initialize variables to store the minimum difference and the pair of numbers\n min_diff = float('inf')\n closest_pair = (0.0, 0.0)\n \n # Iterate through the sorted list to find the closest pair\n for i in range(len(numbers) - 1):\n diff = numbers[i + 1] - numbers[i]\n if diff < min_diff:\n min_diff = diff\n closest_pair = (numbers[i], numbers[i + 1])\n \n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n if len(numbers) < 2:\n raise ValueError(\"List must contain at least two elements.\")\n \n # Sort the list to make it easier to find the closest pair\n numbers.sort()\n \n # Initialize the minimum difference to a large value\n min_diff = float('inf')\n closest_pair = (0.0, 0.0)\n \n # Iterate through the sorted list and find the pair with the smallest difference\n for i in range(len(numbers) - 1):\n diff = numbers[i + 1] - numbers[i]\n if diff < min_diff:\n min_diff = diff\n closest_pair = (numbers[i], numbers[i + 1])\n \n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n if len(numbers) < 2:\n raise ValueError(\"List must contain at least two elements.\")\n \n closest_pair = (numbers[0], numbers[1])\n min_diff = abs(numbers[0] - numbers[1])\n \n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n diff = abs(numbers[i] - numbers[j])\n if diff < min_diff:\n min_diff = diff\n closest_pair = (min(numbers[i], numbers[j]), max(numbers[i], numbers[j]))\n \n return closest_pair", "matching_cluster_idx": 3}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n if len(numbers) < 2:\n raise ValueError(\"The list must contain at least two elements.\")\n \n # Sort the list to find the closest elements\n numbers.sort()\n \n # Initialize variables to store the minimum difference and the pair of numbers\n min_diff = float('inf')\n closest_pair = (0.0, 0.0)\n \n # Iterate through the sorted list to find the closest pair\n for i in range(len(numbers) - 1):\n diff = numbers[i + 1] - numbers[i]\n if diff < min_diff:\n min_diff = diff\n closest_pair = (numbers[i], numbers[i + 1])\n \n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n if len(numbers) < 2:\n raise ValueError(\"The list must contain at least two elements.\")\n \n closest_pair = (numbers[0], numbers[1])\n min_diff = abs(numbers[0] - numbers[1])\n \n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n diff = abs(numbers[i] - numbers[j])\n if diff < min_diff:\n min_diff = diff\n closest_pair = (min(numbers[i], numbers[j]), max(numbers[i], numbers[j]))\n \n return closest_pair", "matching_cluster_idx": 3}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n if len(numbers) < 2:\n raise ValueError(\"The list must contain at least two elements.\")\n \n # Sort the numbers\n numbers.sort()\n \n # Initialize the minimum difference to a large value\n min_diff = float('inf')\n closest_pair = (0.0, 0.0)\n \n # Iterate through the sorted list to find the closest pair\n for i in range(len(numbers) - 1):\n diff = numbers[i + 1] - numbers[i]\n if diff < min_diff:\n min_diff = diff\n closest_pair = (numbers[i], numbers[i + 1])\n \n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n if len(numbers) < 2:\n raise ValueError(\"The list must contain at least two elements.\")\n \n # Sort the numbers to make it easier to find the closest elements\n sorted_numbers = sorted(numbers)\n \n # Initialize variables to store the minimum difference and the pair of numbers\n min_diff = float('inf')\n closest_pair = (0.0, 0.0)\n \n # Iterate through the sorted list to find the closest pair\n for i in range(len(sorted_numbers) - 1):\n diff = sorted_numbers[i + 1] - sorted_numbers[i]\n if diff < min_diff:\n min_diff = diff\n closest_pair = (sorted_numbers[i], sorted_numbers[i + 1])\n \n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n if len(numbers) < 2:\n raise ValueError(\"List must contain at least two elements.\")\n\n # Sort the list to make it easier to find the closest elements\n sorted_numbers = sorted(numbers)\n\n # Initialize variables to store the smallest difference and the pair of numbers\n smallest_diff = float('inf')\n closest_pair = (0.0, 0.0)\n\n # Iterate through the sorted list to find the closest pair\n for i in range(len(sorted_numbers) - 1):\n diff = sorted_numbers[i + 1] - sorted_numbers[i]\n if diff < smallest_diff:\n smallest_diff = diff\n closest_pair = (sorted_numbers[i], sorted_numbers[i + 1])\n\n return closest_pair", "matching_cluster_idx": 8}]}, "HumanEval/24": {"dps": 91.56462585034015, "dps_norm": 58.75, "pass@1": 100.0, "profiled": [{"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n for i in range(n//2, 0, -1):\n if n % i == 0:\n return i\n return 1 # In case n is 1, as 1 has no divisors smaller than itself", "matching_cluster_idx": 4}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n if n < 2:\n raise ValueError(\"n must be greater than 1\")\n \n for i in range(n // 2, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 4}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n if n <= 1:\n raise ValueError(\"n must be greater than 1\")\n for i in range(n // 2, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 4}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n for i in range(n//2, 0, -1):\n if n % i == 0:\n return i\n return 1 # In case the number is 1 or if the loop never finds a divisor (though 1 is not smaller than n)", "matching_cluster_idx": 3}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n for i in range(n//2, 0, -1):\n if n % i == 0:\n return i\n return 1 # In case the number is 1 or there's an error, though the problem assumes n > 1", "matching_cluster_idx": 4}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n for i in range(n // 2, 0, -1):\n if n % i == 0:\n return i\n return 1 # In case n is 1, which doesn't have any smaller divisors than itself", "matching_cluster_idx": 4}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n \"\"\"\n for i in range(n//2, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 4}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n for i in range(n // 2, 0, -1):\n if n % i == 0:\n return i\n return 1 # This line is technically unreachable because every number has 1 as a divisor", "matching_cluster_idx": 4}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n for i in range(n//2, 0, -1):\n if n % i == 0:\n return i\n return 1 # Return 1 for the case where n is 1 or if no divisors are found", "matching_cluster_idx": 3}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n for i in range(n//2, 0, -1):\n if n % i == 0:\n return i\n return 1 # Fallback, should not reach here for n > 1", "matching_cluster_idx": 4}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n for i in range(n // 2, 0, -1):\n if n % i == 0:\n return i\n return 1 # If n is 1, the largest divisor is 1", "matching_cluster_idx": 3}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n if n < 2:\n raise ValueError(\"n must be greater than 1\")\n for i in range(n // 2, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 3}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n for i in range(n // 2, 0, -1):\n if n % i == 0:\n return i\n return 1 # In case the number is 1, which has no divisors less than itself", "matching_cluster_idx": 4}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n for i in range(n//2, 0, -1):\n if n % i == 0:\n return i\n return 1 # In case n is 1, as 1 has no divisors other than 1 itself", "matching_cluster_idx": 4}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n for i in range(n//2, 0, -1):\n if n % i == 0:\n return i\n return 1 # Return 1 for the smallest divisor if no other divisor is found", "matching_cluster_idx": 4}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n for i in range(n // 2, 0, -1):\n if n % i == 0:\n return i\n return 1 # In case the number is 1 or if the loop never returns, return 1 as a fallback", "matching_cluster_idx": 4}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n for i in range(n // 2, 0, -1):\n if n % i == 0:\n return i\n return 1 # n is a prime number", "matching_cluster_idx": 4}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n for i in range(n//2, 0, -1):\n if n % i == 0:\n return i\n return 1 # In case the number is 1, as it has no divisors smaller than itself", "matching_cluster_idx": 3}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n for i in range(n//2, 0, -1):\n if n % i == 0:\n return i\n return 1 # In case n is 1, there are no divisors smaller than n", "matching_cluster_idx": 4}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n for i in range(n // 2, 0, -1):\n if n % i == 0:\n return i\n return 1 # Fallback, though not necessary if n > 1", "matching_cluster_idx": 3}]}, "HumanEval/26": {"dps": 96.4, "dps_norm": 98.75, "pass@1": 52.0, "profiled": [{"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n counts = {}\n for num in numbers:\n counts[num] = counts.get(num, 0) + 1\n \n result = []\n for num in numbers:\n if counts[num] == 1:\n result.append(num)\n \n return result", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n counts = {}\n for num in numbers:\n counts[num] = counts.get(num, 0) + 1\n \n result = []\n for num in numbers:\n if counts[num] == 1:\n result.append(num)\n \n return result", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n seen = set()\n duplicates = set()\n result = []\n \n for number in numbers:\n if number in seen:\n if number not in duplicates:\n duplicates.add(number)\n result.remove(number) # Remove the last occurrence\n else:\n seen.add(number)\n result.append(number)\n \n return result", "matching_cluster_idx": 2}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n counts = {}\n for number in numbers:\n counts[number] = counts.get(number, 0) + 1\n \n result = []\n for number in numbers:\n if counts[number] == 1:\n result.append(number)\n \n return result", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n seen = set()\n duplicates = set()\n result = []\n \n for number in numbers:\n if number in seen:\n duplicates.add(number)\n else:\n seen.add(number)\n \n for number in numbers:\n if number not in duplicates:\n result.append(number)\n \n return result", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n seen = set()\n duplicates = set()\n result = []\n \n for number in numbers:\n if number in seen:\n duplicates.add(number)\n else:\n seen.add(number)\n \n for number in numbers:\n if number not in duplicates:\n result.append(number)\n \n return result", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n counts = {}\n for number in numbers:\n counts[number] = counts.get(number, 0) + 1\n \n result = []\n for number in numbers:\n if counts[number] == 1:\n result.append(number)\n \n return result", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n seen = set()\n duplicates = set()\n result = []\n \n for number in numbers:\n if number in seen:\n duplicates.add(number)\n else:\n seen.add(number)\n \n for number in numbers:\n if number not in duplicates:\n result.append(number)\n \n return result", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n counts = {}\n for num in numbers:\n counts[num] = counts.get(num, 0) + 1\n \n return [num for num in numbers if counts[num] == 1]", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n counts = {}\n for num in numbers:\n counts[num] = counts.get(num, 0) + 1\n \n return [num for num in numbers if counts[num] == 1]", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n counts = {}\n for num in numbers:\n counts[num] = counts.get(num, 0) + 1\n \n result = []\n for num in numbers:\n if counts[num] == 1:\n result.append(num)\n \n return result", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n counts = {}\n for num in numbers:\n counts[num] = counts.get(num, 0) + 1\n \n result = []\n for num in numbers:\n if counts[num] == 1:\n result.append(num)\n \n return result", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n counts = {}\n for num in numbers:\n counts[num] = counts.get(num, 0) + 1\n \n result = []\n for num in numbers:\n if counts[num] == 1:\n result.append(num)\n \n return result", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n seen = set()\n duplicates = set()\n result = []\n \n for number in numbers:\n if number in seen:\n duplicates.add(number)\n else:\n seen.add(number)\n \n for number in numbers:\n if number not in duplicates:\n result.append(number)\n \n return result", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n counts = {}\n for number in numbers:\n counts[number] = counts.get(number, 0) + 1\n \n result = []\n for number in numbers:\n if counts[number] == 1:\n result.append(number)\n \n return result", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n counts = {}\n for num in numbers:\n counts[num] = counts.get(num, 0) + 1\n \n result = []\n for num in numbers:\n if counts[num] == 1:\n result.append(num)\n \n return result", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n counts = {}\n for number in numbers:\n counts[number] = counts.get(number, 0) + 1\n \n result = []\n for number in numbers:\n if counts[number] == 1:\n result.append(number)\n \n return result", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n counts = {}\n for number in numbers:\n counts[number] = counts.get(number, 0) + 1\n \n return [number for number in numbers if counts[number] == 1]", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n counts = {}\n for num in numbers:\n counts[num] = counts.get(num, 0) + 1\n \n result = []\n for num in numbers:\n if counts[num] == 1:\n result.append(num)\n \n return result", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n seen = set()\n duplicates = set()\n result = []\n for number in numbers:\n if number in seen:\n duplicates.add(number)\n else:\n seen.add(number)\n for number in numbers:\n if number not in duplicates:\n result.append(number)\n return result", "matching_cluster_idx": 3}]}, "HumanEval/31": {"dps": 88.10126582278481, "dps_norm": 85.0, "pass@1": 100.0, "profiled": [{"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 5}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 5}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 5}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 5}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}]}, "HumanEval/33": {"dps": 97.22222222222223, "dps_norm": 81.81818181818181, "pass@1": 92.0, "profiled": [{"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n # Extract elements at indices divisible by 3\n divisible_by_three = [l[i] for i in range(len(l)) if i % 3 == 0]\n # Sort these elements\n divisible_by_three.sort()\n # Create a new list to store the result\n result = l[:]\n # Replace elements at indices divisible by 3 with sorted elements\n for i, value in zip(range(0, len(l), 3), divisible_by_three):\n result[i] = value\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indices that are not divisible by three, while its values at the indices that are divisible by three are equal\n to the values of the corresponding indices of l, but sorted.\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n # Extract the values at indices divisible by 3\n divisible_by_three = [l[i] for i in range(len(l)) if i % 3 == 0]\n # Sort these values\n divisible_by_three.sort()\n # Create a new list to store the result\n result = l[:]\n # Replace the values at indices divisible by 3 with the sorted values\n for i, value in zip(range(0, len(l), 3), divisible_by_three):\n result[i] = value\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n # Extract the elements at indices divisible by 3\n divisible_by_three = [l[i] for i in range(len(l)) if i % 3 == 0]\n # Sort these elements\n divisible_by_three.sort()\n # Create a new list to store the result\n result = l[:]\n # Replace the elements at indices divisible by 3 with the sorted elements\n for i, value in zip(range(0, len(l), 3), divisible_by_three):\n result[i] = value\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indices that are not divisible by three, while its values at the indices that are divisible by three are equal\n to the values of the corresponding indices of l, but sorted.\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n # Extract the elements at indices divisible by 3\n third_elements = [l[i] for i in range(len(l)) if i % 3 == 0]\n # Sort the extracted elements\n third_elements.sort()\n # Create a new list with sorted elements at indices divisible by 3\n result = l[:]\n for i, value in zip(range(0, len(l), 3), third_elements):\n result[i] = value\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indices that are not divisible by three, while its values at the indices that are divisible by three are equal\n to the values of the corresponding indices of l, but sorted.\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n # Extract the elements at indices divisible by 3\n divisible_by_three = [l[i] for i in range(len(l)) if i % 3 == 0]\n # Sort the extracted elements\n divisible_by_three.sort()\n # Create a new list to store the result\n result = l[:]\n # Replace the elements at indices divisible by 3 with the sorted elements\n for i, value in zip(range(0, len(l), 3), divisible_by_three):\n result[i] = value\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n # Extract elements at indices divisible by 3\n divisible_by_three = [l[i] for i in range(len(l)) if i % 3 == 0]\n # Sort the extracted elements\n divisible_by_three.sort()\n # Create a new list to hold the result\n result = l[:]\n # Replace elements at indices divisible by 3 with sorted elements\n for i, value in zip(range(0, len(l), 3), divisible_by_three):\n result[i] = value\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n # Extract the elements at indices divisible by 3\n divisible_by_three = [l[i] for i in range(len(l)) if i % 3 == 0]\n \n # Sort the extracted elements\n divisible_by_three.sort()\n \n # Create a new list to store the result\n result = l[:]\n \n # Replace the elements at indices divisible by 3 with the sorted elements\n for i, value in zip(range(0, len(l), 3), divisible_by_three):\n result[i] = value\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n # Extract values at indices divisible by 3\n values_at_thirds = [l[i] for i in range(len(l)) if i % 3 == 0]\n \n # Sort these values\n values_at_thirds.sort()\n \n # Create a new list to hold the result\n result = l[:]\n \n # Replace values at indices divisible by 3 with sorted values\n for i, value in zip(range(0, len(l), 3), values_at_thirds):\n result[i] = value\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indices that are not divisible by three, while its values at the indices that are divisible by three are equal\n to the values of the corresponding indices of l, but sorted.\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n # Extract the elements at indices divisible by 3\n third_elements = [l[i] for i in range(len(l)) if i % 3 == 0]\n # Sort the extracted elements\n third_elements.sort()\n # Create a new list to hold the result\n result = l[:]\n # Replace the elements at indices divisible by 3 with the sorted elements\n for i, value in zip(range(0, len(l), 3), third_elements):\n result[i] = value\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n # Extract values at indices divisible by 3\n divisible_by_three = [l[i] for i in range(len(l)) if i % 3 == 0]\n # Sort the extracted values\n divisible_by_three.sort()\n # Create a new list to store the result\n result = l[:]\n # Replace values at indices divisible by 3 with sorted values\n for i, value in zip(range(0, len(l), 3), divisible_by_three):\n result[i] = value\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indices that are not divisible by three, while its values at the indices that are divisible by three are equal\n to the values of the corresponding indices of l, but sorted.\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n # Extract elements at indices divisible by 3\n divisible_by_three = [l[i] for i in range(len(l)) if i % 3 == 0]\n # Sort the extracted elements\n divisible_by_three.sort()\n # Create a new list to store the result\n result = l[:]\n # Replace elements at indices divisible by 3 with sorted elements\n for i, value in zip(range(0, len(l), 3), divisible_by_three):\n result[i] = value\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n # Extract elements at indices divisible by 3\n divisible_by_three = [l[i] for i in range(len(l)) if i % 3 == 0]\n # Sort these elements\n divisible_by_three.sort()\n # Create a new list to hold the result\n result = l[:]\n # Replace elements at indices divisible by 3 with sorted elements\n for i, val in zip(range(0, len(l), 3), divisible_by_three):\n result[i] = val\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n # Extract elements at indices divisible by 3\n divisible_by_three = [l[i] for i in range(len(l)) if i % 3 == 0]\n # Sort the extracted elements\n divisible_by_three.sort()\n # Create a new list to hold the result\n result = l[:]\n # Replace elements at indices divisible by 3 with sorted elements\n for i, value in zip(range(0, len(l), 3), divisible_by_three):\n result[i] = value\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indices that are not divisible by three, while its values at the indices that are divisible by three are equal\n to the values of the corresponding indices of l, but sorted.\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n # Extract the elements at indices divisible by 3\n third_elements = [l[i] for i in range(len(l)) if i % 3 == 0]\n \n # Sort the extracted elements\n third_elements.sort()\n \n # Create a new list to hold the result\n result = l[:]\n \n # Replace the elements at indices divisible by 3 with the sorted elements\n for i, value in zip(range(0, len(l), 3), third_elements):\n result[i] = value\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indices that are not divisible by three, while its values at the indices that are divisible by three are equal\n to the values of the corresponding indices of l, but sorted.\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n # Extract elements at indices divisible by 3\n divisible_by_three = [l[i] for i in range(len(l)) if i % 3 == 0]\n # Sort these elements\n divisible_by_three.sort()\n # Create a new list to hold the result\n result = l[:]\n # Replace elements at indices divisible by 3 with sorted elements\n for i, value in zip(range(0, len(l), 3), divisible_by_three):\n result[i] = value\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indices that are not divisible by three, while its values at the indices that are divisible by three are equal\n to the values of the corresponding indices of l, but sorted.\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n # Extract elements at indices divisible by 3\n divisible_by_three = [l[i] for i in range(len(l)) if i % 3 == 0]\n \n # Sort the extracted elements\n divisible_by_three.sort()\n \n # Create a new list to hold the result\n result = l[:]\n \n # Replace elements at indices divisible by 3 with sorted elements\n for i, value in zip(range(0, len(l), 3), divisible_by_three):\n result[i] = value\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indices that are not divisible by three, while its values at the indices that are divisible by three are equal\n to the values of the corresponding indices of l, but sorted.\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n # Extract the elements at indices divisible by 3\n divisible_by_three = [l[i] for i in range(len(l)) if i % 3 == 0]\n # Sort the extracted elements\n divisible_by_three.sort()\n # Create a new list to hold the result\n result = l[:]\n # Replace the elements at indices divisible by 3 with sorted elements\n for i, value in zip(range(0, len(l), 3), divisible_by_three):\n result[i] = value\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indices that are not divisible by three, while its values at the indices that are divisible by three are equal\n to the values of the corresponding indices of l, but sorted.\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n # Extract the elements at indices divisible by 3\n divisible_by_3 = [l[i] for i in range(len(l)) if i % 3 == 0]\n # Sort the extracted elements\n divisible_by_3.sort()\n # Create a new list to hold the result\n result = l[:]\n # Replace the elements at indices divisible by 3 with the sorted elements\n for i, value in zip(range(0, len(l), 3), divisible_by_3):\n result[i] = value\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indices that are not divisible by three, while its values at the indices that are divisible by three are equal\n to the values of the corresponding indices of l, but sorted.\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n # Extract the elements at indices divisible by 3\n divisible_by_three = [l[i] for i in range(len(l)) if i % 3 == 0]\n # Sort the extracted elements\n divisible_by_three.sort()\n # Create a new list to store the result\n result = l[:]\n # Replace the elements at indices divisible by 3 with the sorted elements\n for i, value in zip(range(0, len(l), 3), divisible_by_three):\n result[i] = value\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n # Extract the elements at indices divisible by 3\n divisible_by_three = [l[i] for i in range(len(l)) if i % 3 == 0]\n \n # Sort the extracted elements\n divisible_by_three.sort()\n \n # Create a new list to hold the result\n result = l[:]\n \n # Replace the elements at indices divisible by 3 with the sorted elements\n for i, value in zip(range(0, len(l), 3), divisible_by_three):\n result[i] = value\n \n return result", "matching_cluster_idx": 8}]}, "HumanEval/34": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list) -> list:\n \"\"\"Return sorted unique elements in a list\"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list) -> list:\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list) -> list:\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list) -> list:\n \"\"\"Return sorted unique elements in a list\"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list) -> list:\n \"\"\"Return sorted unique elements in a list\"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}]}, "HumanEval/36": {"dps": null, "dps_norm": null, "pass@1": 2.0, "profiled": []}, "HumanEval/37": {"dps": 94.92635024549918, "dps_norm": 90.0, "pass@1": 100.0, "profiled": [{"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Extract even-indexed elements\n evens = [l[i] for i in range(len(l)) if i % 2 == 0]\n # Sort the extracted elements\n evens.sort()\n # Create a new list with sorted even-indexed elements\n sorted_list = l[:]\n even_index = 0\n for i in range(0, len(l), 2):\n sorted_list[i] = evens[even_index]\n even_index += 1\n return sorted_list", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Extract even-indexed elements\n even_elements = [l[i] for i in range(0, len(l), 2)]\n # Sort the even-indexed elements\n even_elements_sorted = sorted(even_elements)\n # Create a new list to hold the result\n result = l[:]\n # Replace even-indexed elements in the result with sorted elements\n for i, value in zip(range(0, len(l), 2), even_elements_sorted):\n result[i] = value\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indices, while its values at the even indices are equal\n to the values of the even indices of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Extract the even-indexed elements\n even_elements = [l[i] for i in range(len(l)) if i % 2 == 0]\n # Sort the extracted elements\n even_elements.sort()\n \n # Create a new list to hold the result\n sorted_list = l[:]\n # Replace the even-indexed elements with sorted ones\n for i, value in enumerate(even_elements):\n sorted_list[i * 2] = value\n \n return sorted_list", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indices, while its values at the even indices are equal\n to the values of the even indices of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Extract the elements at even indices\n even_elements = [l[i] for i in range(len(l)) if i % 2 == 0]\n # Sort the extracted elements\n even_elements.sort()\n # Create a new list to hold the result\n result = l[:]\n # Replace the elements at even indices with the sorted elements\n for i, value in zip(range(0, len(l), 2), even_elements):\n result[i] = value\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Extract even indexed elements\n evens = [l[i] for i in range(len(l)) if i % 2 == 0]\n # Sort the extracted elements\n evens.sort()\n # Create a new list with sorted even indexed elements\n sorted_list = l[:]\n even_index = 0\n for i in range(0, len(l), 2):\n sorted_list[i] = evens[even_index]\n even_index += 1\n return sorted_list", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Extract even-indexed elements\n even_elements = [l[i] for i in range(len(l)) if i % 2 == 0]\n # Sort even-indexed elements\n even_elements.sort()\n # Create a new list with sorted even-indexed elements and original odd-indexed elements\n sorted_list = l[:]\n for i, value in zip(range(0, len(l), 2), even_elements):\n sorted_list[i] = value\n return sorted_list", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n evens = sorted([l[i] for i in range(len(l)) if i % 2 == 0])\n result = l[:]\n even_index = 0\n for i in range(0, len(l), 2):\n result[i] = evens[even_index]\n even_index += 1\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Extract even-indexed elements\n even_elements = [l[i] for i in range(len(l)) if i % 2 == 0]\n \n # Sort the even-indexed elements\n even_elements.sort()\n \n # Create a new list with sorted even-indexed elements and original odd-indexed elements\n sorted_list = l[:]\n even_index = 0\n for i in range(len(l)):\n if i % 2 == 0:\n sorted_list[i] = even_elements[even_index]\n even_index += 1\n \n return sorted_list", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Extract even-indexed values\n even_values = [l[i] for i in range(len(l)) if i % 2 == 0]\n # Sort the even-indexed values\n even_values.sort()\n # Create a new list to store the result\n result = l[:]\n # Replace even-indexed values in the result with sorted values\n for i, value in zip(range(0, len(l), 2), even_values):\n result[i] = value\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Extract even-indexed elements and sort them\n even_elements = sorted([l[i] for i in range(0, len(l), 2)])\n \n # Create a new list to store the result\n result = l[:]\n \n # Replace even-indexed elements in the result with sorted elements\n for i, value in zip(range(0, len(l), 2), even_elements):\n result[i] = value\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Extract even-indexed values and sort them\n even_values = sorted([l[i] for i in range(0, len(l), 2)])\n \n # Create a new list to hold the result\n result = l[:]\n \n # Replace even-indexed values in the result with the sorted values\n for i, value in zip(range(0, len(l), 2), even_values):\n result[i] = value\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Extract the elements at even indices\n even_indices_values = [l[i] for i in range(len(l)) if i % 2 == 0]\n # Sort the extracted values\n even_indices_values.sort()\n # Create a new list to store the result\n sorted_list = l[:]\n # Replace the elements at even indices with the sorted values\n for i, value in enumerate(even_indices_values):\n sorted_list[i * 2] = value\n return sorted_list", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Extract the even indexed values and sort them\n even_values = sorted([l[i] for i in range(0, len(l), 2)])\n \n # Create a new list to store the result\n result = l[:]\n \n # Replace the even indexed values in the result with the sorted values\n for i, value in zip(range(0, len(l), 2), even_values):\n result[i] = value\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Extract the even-indexed elements\n even_elements = [l[i] for i in range(len(l)) if i % 2 == 0]\n # Sort the extracted elements\n even_elements_sorted = sorted(even_elements)\n \n # Create a new list to hold the result\n result = l[:]\n \n # Replace the even-indexed elements in the result with the sorted ones\n for i, value in zip(range(0, len(l), 2), even_elements_sorted):\n result[i] = value\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Extract even-indexed elements\n even_elements = [l[i] for i in range(len(l)) if i % 2 == 0]\n # Sort the extracted elements\n even_elements_sorted = sorted(even_elements)\n # Create a new list to hold the result\n result = l[:]\n # Replace even-indexed elements in the result with sorted ones\n for i, value in enumerate(even_elements_sorted):\n result[i * 2] = value\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Extract even-indexed elements and sort them\n even_elements = sorted([l[i] for i in range(0, len(l), 2)])\n \n # Create a new list to hold the result\n result = l[:]\n \n # Replace even-indexed elements in the result with the sorted ones\n even_index = 0\n for i in range(0, len(l), 2):\n result[i] = even_elements[even_index]\n even_index += 1\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indices, while its values at the even indices are equal\n to the values of the even indices of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Extract even-indexed elements\n even_elements = [l[i] for i in range(len(l)) if i % 2 == 0]\n # Sort the extracted elements\n even_elements_sorted = sorted(even_elements)\n # Create a new list to store the result\n result = l[:]\n # Replace even-indexed elements with sorted ones\n for i, value in enumerate(even_elements_sorted):\n result[i * 2] = value\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Extract even-indexed values and sort them\n evens = sorted([l[i] for i in range(0, len(l), 2)])\n \n # Create a new list with sorted even-indexed values\n result = l[:]\n even_index = 0\n for i in range(0, len(l), 2):\n result[i] = evens[even_index]\n even_index += 1\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n evens = sorted([l[i] for i in range(len(l)) if i % 2 == 0])\n result = l[:]\n even_index = 0\n for i in range(0, len(l), 2):\n result[i] = evens[even_index]\n even_index += 1\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Extract even-indexed values and sort them\n evens = sorted([l[i] for i in range(len(l)) if i % 2 == 0])\n \n # Create a new list to store the result\n result = l[:]\n \n # Replace even-indexed values with sorted ones\n even_index = 0\n for i in range(len(l)):\n if i % 2 == 0:\n result[i] = evens[even_index]\n even_index += 1\n \n return result", "matching_cluster_idx": 8}]}, "HumanEval/49": {"dps": 78.3529411764706, "dps_norm": 92.0, "pass@1": 100.0, "profiled": [{"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int):\n \"\"\"Return 2^n modulo p (be aware of numerics).\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n # Calculate 2^n\n power_of_two = 2 ** n\n # Return the result modulo p\n return power_of_two % p", "matching_cluster_idx": 3}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int):\n \"\"\"Return 2^n modulo p (be aware of numerics).\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\"\"\"\n # Calculate 2^n\n power_of_two = 2**n\n # Return the result modulo p\n return power_of_two % p", "matching_cluster_idx": 3}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n # Calculate 2^n modulo p\n result = pow(2, n, p)\n return result", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\"\"\"\n # Calculate 2^n\n power_of_two = 2**n\n # Return the modulo of the result\n return power_of_two % p", "matching_cluster_idx": 3}, {"solution": "def modp(n: int, p: int):\n \"\"\"Return 2^n modulo p (be aware of numerics).\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int):\n \"\"\"Return 2^n modulo p (be aware of numerics).\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\"\"\"\n # Calculate 2^n\n power_of_two = 2 ** n\n # Return the result modulo p\n return power_of_two % p", "matching_cluster_idx": 2}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\"\"\"\n # Calculate 2^n\n power_of_two = 2**n\n # Return the result modulo p\n return power_of_two % p", "matching_cluster_idx": 3}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\"\"\"\n # Calculate 2^n\n power_of_two = 2 ** n\n # Return the result modulo p\n return power_of_two % p", "matching_cluster_idx": 2}]}, "HumanEval/51": {"dps": 96.13526570048309, "dps_norm": 75.0, "pass@1": 100.0, "profiled": [{"solution": "def remove_vowels(text):\n vowels = \"aeiouAEIOU\"\n return \"\".join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n vowels = \"aeiouAEIOU\"\n return \"\".join(char for char in text if char not in vowels)", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = 'aeiouAEIOU'\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n return ''.join(char for char in text if char not in vowels)", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n return ''.join(char for char in text if char not in vowels)", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n return ''.join(char for char in text if char not in vowels)", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n vowels = \"aeiouAEIOU\"\n return ''.join(char for char in text if char not in vowels)", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n vowels = \"aeiouAEIOU\"\n return ''.join(char for char in text if char not in vowels)", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = 'aeiouAEIOU'\n return ''.join(char for char in text if char not in vowels)", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n return ''.join(char for char in text if char not in vowels)", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n vowels = \"aeiouAEIOU\"\n return ''.join(char for char in text if char not in vowels)", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n vowels = \"aeiouAEIOU\"\n return \"\".join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n return ''.join(char for char in text if char not in vowels)", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n vowels = \"aeiouAEIOU\"\n return ''.join(char for char in text if char not in vowels)", "matching_cluster_idx": 5}]}, "HumanEval/54": {"dps": null, "dps_norm": null, "pass@1": 0.0, "profiled": []}, "HumanEval/58": {"dps": 92.51968503937007, "dps_norm": 83.33333333333333, "pass@1": 100.0, "profiled": [{"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n # Convert both lists to sets to find the intersection\n set1 = set(l1)\n set2 = set(l2)\n # Find the intersection of both sets\n intersection = set1.intersection(set2)\n # Convert the intersection back to a sorted list\n result = sorted(list(intersection))\n return result", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n # Convert lists to sets to find common elements\n set1 = set(l1)\n set2 = set(l2)\n \n # Find intersection and convert back to list\n common_elements = list(set1 & set2)\n \n # Sort the list and return\n return sorted(common_elements)", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n # Convert both lists to sets to find the intersection\n set1 = set(l1)\n set2 = set(l2)\n intersection = set1.intersection(set2)\n \n # Convert the intersection back to a sorted list\n sorted_common = sorted(list(intersection))\n return sorted_common", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n # Convert both lists to sets to find the intersection\n set1 = set(l1)\n set2 = set(l2)\n common_elements = set1.intersection(set2)\n \n # Convert the set of common elements back to a sorted list\n sorted_common_elements = sorted(common_elements)\n \n return sorted_common_elements", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n # Convert both lists to sets to find the intersection\n set1 = set(l1)\n set2 = set(l2)\n \n # Find the intersection and sort it\n common_elements = sorted(list(set1 & set2))\n \n return common_elements", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n # Convert lists to sets to find common elements\n set1 = set(l1)\n set2 = set(l2)\n \n # Find intersection and convert back to list to remove duplicates\n common_elements = list(set1.intersection(set2))\n \n # Sort the list of common elements\n common_elements.sort()\n \n return common_elements", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n # Convert both lists to sets to find the intersection\n set1 = set(l1)\n set2 = set(l2)\n # Find the intersection and convert it back to a list\n common_elements = list(set1.intersection(set2))\n # Sort the list and return it\n return sorted(common_elements)", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n # Convert both lists to sets to remove duplicates and allow for O(1) lookups\n set1 = set(l1)\n set2 = set(l2)\n \n # Find the intersection of both sets\n common_elements = set1.intersection(set2)\n \n # Convert the set of common elements back to a sorted list\n return sorted(list(common_elements))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n # Convert both lists to sets to remove duplicates and enable set operations\n set1 = set(l1)\n set2 = set(l2)\n \n # Find the intersection of the two sets\n common_elements = set1.intersection(set2)\n \n # Convert the result back to a sorted list\n return sorted(list(common_elements))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n # Convert both lists to sets to find the intersection\n set1 = set(l1)\n set2 = set(l2)\n \n # Find the intersection of both sets\n common_elements = set1.intersection(set2)\n \n # Convert the result back to a sorted list to ensure sorted output\n return sorted(common_elements)", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n # Convert lists to sets to find common elements\n set1 = set(l1)\n set2 = set(l2)\n common_elements = set1.intersection(set2)\n \n # Convert the set of common elements back to a sorted list\n return sorted(common_elements)", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n # Convert both lists to sets to find the intersection\n set1 = set(l1)\n set2 = set(l2)\n common_elements = set1.intersection(set2)\n \n # Convert the set of common elements back to a sorted list\n sorted_common_elements = sorted(common_elements)\n \n return sorted_common_elements", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n # Convert lists to sets to find common elements\n set1 = set(l1)\n set2 = set(l2)\n common_elements = set1.intersection(set2)\n # Convert the result back to a sorted list\n return sorted(list(common_elements))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n # Convert lists to sets to find common elements\n set1 = set(l1)\n set2 = set(l2)\n common_elements = set1.intersection(set2)\n \n # Convert the set of common elements back to a sorted list\n return sorted(list(common_elements))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n # Convert lists to sets to find common elements\n set1 = set(l1)\n set2 = set(l2)\n \n # Find intersection and convert it to a sorted list\n common_elements = sorted(list(set1.intersection(set2)))\n \n return common_elements", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n # Convert both lists to sets to find common elements\n set1 = set(l1)\n set2 = set(l2)\n \n # Find intersection and convert it back to a sorted list\n common_elements = sorted(list(set1 & set2))\n return common_elements", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n # Convert both lists to sets to remove duplicates and enable set operations\n set1 = set(l1)\n set2 = set(l2)\n \n # Find the intersection of the two sets\n intersection = set1.intersection(set2)\n \n # Convert the intersection back to a sorted list\n result = sorted(list(intersection))\n \n return result", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n # Convert both lists to sets to find common elements and remove duplicates\n set1 = set(l1)\n set2 = set(l2)\n common_elements = set1.intersection(set2)\n # Convert the set back to a sorted list\n return sorted(list(common_elements))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n # Convert lists to sets to find common elements and remove duplicates\n set1 = set(l1)\n set2 = set(l2)\n common_elements = set1.intersection(set2)\n \n # Convert the set of common elements back to a sorted list\n return sorted(common_elements)", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n # Convert both lists to sets to find the intersection\n set1 = set(l1)\n set2 = set(l2)\n \n # Find the intersection of the two sets\n intersection = set1.intersection(set2)\n \n # Convert the intersection back to a sorted list to ensure sorted output\n return sorted(list(intersection))", "matching_cluster_idx": 4}]}, "HumanEval/59": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n i = 2\n largest_factor = i\n while i * i <= n:\n if n % i:\n i += 1\n else:\n n //= i\n largest_factor = i\n if n > largest_factor:\n return n\n return largest_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n i = 2\n largest_factor = i\n while i * i <= n:\n if n % i:\n i += 1\n else:\n n //= i\n largest_factor = i\n if n > largest_factor:\n largest_factor = n\n return largest_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n i = 2\n largest_factor = i\n while i * i <= n:\n if n % i:\n i += 1\n else:\n n //= i\n largest_factor = i\n if n > largest_factor:\n return n\n return largest_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n i = 2\n largest_factor = i\n while i * i <= n:\n if n % i:\n i += 1\n else:\n n //= i\n largest_factor = i\n if n > largest_factor:\n largest_factor = n\n return largest_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n i = 2\n largest_factor = i\n while i * i <= n:\n if n % i:\n i += 1\n else:\n n //= i\n largest_factor = i\n return n if n > 1 else largest_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n # Initialize the largest prime factor\n largest_factor = None\n \n # Divide n by 2 until it's odd\n while n % 2 == 0:\n largest_factor = 2\n n //= 2\n \n # Check for odd factors from 3 onwards\n factor = 3\n while factor * factor <= n:\n while n % factor == 0:\n largest_factor = factor\n n //= factor\n factor += 2\n \n # If n is a prime number greater than 2\n if n > 2:\n largest_factor = n\n \n return largest_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n i = 2\n largest_factor = i\n while i * i <= n:\n if n % i:\n i += 1\n else:\n n //= i\n largest_factor = i\n return n if n > largest_factor else largest_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n i = 2\n largest_prime = i\n while i * i <= n:\n while n % i == 0:\n largest_prime = i\n n //= i\n i += 1\n if n > 1:\n largest_prime = n\n return largest_prime", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n i = 2\n largest_prime = i\n while i * i <= n:\n while n % i == 0:\n largest_prime = i\n n //= i\n i += 1\n if n > 1:\n largest_prime = n\n return largest_prime", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n i = 2\n largest_prime = i\n while i * i <= n:\n while n % i == 0:\n largest_prime = i\n n //= i\n i += 1\n if n > 1:\n largest_prime = n\n return largest_prime", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n i = 2\n largest_factor = i\n while i * i <= n:\n if n % i:\n i += 1\n else:\n n //= i\n largest_factor = i\n if n > largest_factor:\n largest_factor = n\n return largest_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n i = 2\n largest_factor = i\n while i * i <= n:\n if n % i:\n i += 1\n else:\n n //= i\n largest_factor = i\n if n > largest_factor:\n largest_factor = n\n return largest_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n i = 2\n largest_factor = i\n while i * i <= n:\n if n % i:\n i += 1\n else:\n n //= i\n largest_factor = i\n if n > largest_factor:\n largest_factor = n\n return largest_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n i = 2\n largest_factor = i\n while i * i <= n:\n if n % i:\n i += 1\n else:\n n //= i\n largest_factor = i\n if n > largest_factor:\n largest_factor = n\n return largest_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n i = 2\n largest_factor = i\n while i * i <= n:\n if n % i:\n i += 1\n else:\n n //= i\n largest_factor = i\n if n > 1:\n largest_factor = n\n return largest_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n i = 2\n largest_prime = i\n while i * i <= n:\n if n % i:\n i += 1\n else:\n n //= i\n largest_prime = i\n if n > 1:\n largest_prime = n\n return largest_prime", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n i = 2\n largest_factor = i\n while i * i <= n:\n if n % i:\n i += 1\n else:\n n //= i\n largest_factor = i\n if n > largest_factor:\n return n\n return largest_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n i = 2\n largest_prime = i\n while i * i <= n:\n if n % i:\n i += 1\n else:\n n //= i\n largest_prime = i\n if n > largest_prime:\n largest_prime = n\n return largest_prime", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n # Initialize the largest prime factor\n largest_factor = None\n \n # Divide n by 2 to remove all factors of 2\n while n % 2 == 0:\n largest_factor = 2\n n //= 2\n \n # Check for odd factors from 3 onwards\n factor = 3\n while factor * factor <= n:\n while n % factor == 0:\n largest_factor = factor\n n //= factor\n factor += 2\n \n # If n is still greater than 2, then it must be prime\n if n > 2:\n largest_factor = n\n \n return largest_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n i = 2\n largest_factor = i\n while i * i <= n:\n if n % i:\n i += 1\n else:\n n //= i\n largest_factor = i\n if n > largest_factor:\n largest_factor = n\n return largest_factor", "matching_cluster_idx": 8}]}, "HumanEval/64": {"dps": 37.14285714285714, "dps_norm": 45.0, "pass@1": 96.0, "profiled": [{"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = \"aeiou\"\n count = 0\n s = s.lower() # Convert to lowercase to make the function case-insensitive\n for i in range(len(s)):\n if s[i] in vowels:\n count += 1\n elif s[i] == 'y' and i == len(s) - 1: # Check if 'y' is at the end of the word\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = \"aeiou\"\n count = 0\n s = s.lower()\n for i in range(len(s)):\n if s[i] in vowels:\n count += 1\n elif s[i] == 'y' and i == len(s) - 1:\n count += 1\n return count", "matching_cluster_idx": 3}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = \"aeiou\"\n count = 0\n s = s.lower() # Convert to lowercase to make the function case-insensitive\n for i in range(len(s)):\n if s[i] in vowels:\n count += 1\n elif s[i] == 'y' and i == len(s) - 1: # Check if 'y' is at the end of the word\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = \"aeiou\"\n count = 0\n s = s.lower() # Convert to lowercase to make the function case-insensitive\n for i in range(len(s)):\n if s[i] in vowels:\n count += 1\n elif s[i] == 'y' and i == len(s) - 1: # Check if 'y' is at the end of the word\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = \"aeiou\"\n count = 0\n s = s.lower()\n for i in range(len(s)):\n if s[i] in vowels:\n count += 1\n elif s[i] == 'y' and i == len(s) - 1:\n count += 1\n return count", "matching_cluster_idx": 3}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = \"aeiou\"\n count = 0\n s = s.lower()\n for i in range(len(s)):\n if s[i] in vowels:\n count += 1\n elif s[i] == 'y' and i == len(s) - 1:\n count += 1\n return count", "matching_cluster_idx": 3}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = \"aeiou\"\n count = 0\n s = s.lower()\n for i in range(len(s)):\n if s[i] in vowels:\n count += 1\n elif s[i] == 'y' and i == len(s) - 1:\n count += 1\n return count", "matching_cluster_idx": 3}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = 'aeiou'\n count = 0\n s = s.lower() # Convert the string to lowercase to make the function case-insensitive\n for i, char in enumerate(s):\n if char in vowels:\n count += 1\n elif char == 'y' and i == len(s) - 1: # Check if 'y' is at the end of the word\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = 'aeiou'\n count = 0\n s = s.lower() # Convert the string to lowercase to make the function case-insensitive\n for i, char in enumerate(s):\n if char in vowels:\n count += 1\n elif char == 'y' and i == len(s) - 1:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = 'aeiou'\n count = 0\n s = s.lower()\n for i in range(len(s)):\n if s[i] in vowels:\n count += 1\n elif s[i] == 'y' and i == len(s) - 1:\n count += 1\n return count", "matching_cluster_idx": 3}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = \"aeiou\"\n count = 0\n s = s.lower()\n for i, char in enumerate(s):\n if char in vowels:\n count += 1\n elif char == 'y' and i == len(s) - 1:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = \"aeiou\"\n count = 0\n s = s.lower() # Convert the string to lowercase to make the function case-insensitive\n for i in range(len(s)):\n if s[i] in vowels:\n count += 1\n elif s[i] == 'y' and i == len(s) - 1: # Check if 'y' is at the end of the word\n count += 1\n return count", "matching_cluster_idx": 3}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = \"aeiou\"\n count = 0\n s = s.lower()\n for i in range(len(s)):\n if s[i] in vowels:\n count += 1\n elif s[i] == 'y' and i == len(s) - 1:\n count += 1\n return count", "matching_cluster_idx": 3}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = \"aeiou\"\n count = 0\n s = s.lower() # Convert the string to lowercase to make the function case-insensitive\n for i, char in enumerate(s):\n if char in vowels:\n count += 1\n elif char == 'y' and i == len(s) - 1: # Check if 'y' is at the end of the word\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = \"aeiou\"\n count = 0\n s = s.lower()\n for i in range(len(s)):\n if s[i] in vowels:\n count += 1\n elif s[i] == 'y' and i == len(s) - 1:\n count += 1\n return count", "matching_cluster_idx": 3}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = \"aeiou\"\n count = 0\n s = s.lower() # Convert the string to lowercase to make the function case-insensitive\n for i in range(len(s)):\n if s[i] in vowels:\n count += 1\n elif s[i] == 'y' and i == len(s) - 1: # Check if 'y' is at the end of the word\n count += 1\n return count", "matching_cluster_idx": 3}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = \"aeiou\"\n count = 0\n s = s.lower() # Normalize the string to lowercase\n for i in range(len(s)):\n if s[i] in vowels:\n count += 1\n elif s[i] == 'y' and i == len(s) - 1: # Check if 'y' is at the end\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = \"aeiou\"\n count = 0\n s = s.lower()\n for i in range(len(s)):\n if s[i] in vowels:\n count += 1\n elif s[i] == 'y' and i == len(s) - 1:\n count += 1\n return count", "matching_cluster_idx": 3}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = \"aeiou\"\n count = 0\n s = s.lower()\n for i in range(len(s)):\n if s[i] in vowels:\n count += 1\n elif s[i] == 'y' and i == len(s) - 1:\n count += 1\n return count", "matching_cluster_idx": 3}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = \"aeiou\"\n count = 0\n s = s.lower()\n for i in range(len(s)):\n if s[i] in vowels:\n count += 1\n elif s[i] == 'y' and i == len(s) - 1:\n count += 1\n return count", "matching_cluster_idx": 3}]}, "HumanEval/74": {"dps": 98.04878048780488, "dps_norm": 88.88888888888889, "pass@1": 70.0, "profiled": [{"solution": "def total_match(lst1, lst2):\n def char_count(lst):\n return sum(len(s) for s in lst)\n \n count1 = char_count(lst1)\n count2 = char_count(lst2)\n \n if count1 < count2:\n return lst1\n elif count2 < count1:\n return lst2\n else:\n return lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n def char_count(lst):\n return sum(len(s) for s in lst)\n\n count1 = char_count(lst1)\n count2 = char_count(lst2)\n\n if count1 < count2:\n return lst1\n elif count2 < count1:\n return lst2\n else:\n return lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n def char_count(lst):\n return sum(len(s) for s in lst)\n \n count1 = char_count(lst1)\n count2 = char_count(lst2)\n \n if count1 < count2:\n return lst1\n elif count2 < count1:\n return lst2\n else:\n return lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n def char_count(lst):\n return sum(len(s) for s in lst)\n \n count1 = char_count(lst1)\n count2 = char_count(lst2)\n \n if count1 < count2:\n return lst1\n elif count2 < count1:\n return lst2\n else:\n return lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n def char_count(lst):\n return sum(len(s) for s in lst)\n \n count1 = char_count(lst1)\n count2 = char_count(lst2)\n \n if count1 < count2:\n return lst1\n elif count2 < count1:\n return lst2\n else:\n return lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n def char_count(lst):\n return sum(len(s) for s in lst)\n \n count1 = char_count(lst1)\n count2 = char_count(lst2)\n \n if count1 < count2:\n return lst1\n elif count2 < count1:\n return lst2\n else:\n return lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n def char_count(lst):\n return sum(len(s) for s in lst)\n \n count1 = char_count(lst1)\n count2 = char_count(lst2)\n \n if count1 < count2:\n return lst1\n elif count2 < count1:\n return lst2\n else:\n return lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n def count_chars(lst):\n return sum(len(s) for s in lst)\n \n count1 = count_chars(lst1)\n count2 = count_chars(lst2)\n \n if count1 < count2:\n return lst1\n elif count2 < count1:\n return lst2\n else:\n return lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n def char_count(lst):\n return sum(len(s) for s in lst)\n \n count1 = char_count(lst1)\n count2 = char_count(lst2)\n \n if count1 < count2:\n return lst1\n elif count2 < count1:\n return lst2\n else:\n return lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n def char_count(lst):\n return sum(len(s) for s in lst)\n \n count1 = char_count(lst1)\n count2 = char_count(lst2)\n \n if count1 < count2:\n return lst1\n elif count2 < count1:\n return lst2\n else:\n return lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n def total_chars(lst):\n return sum(len(s) for s in lst)\n \n chars_lst1 = total_chars(lst1)\n chars_lst2 = total_chars(lst2)\n \n if chars_lst1 < chars_lst2:\n return lst1\n elif chars_lst2 < chars_lst1:\n return lst2\n else:\n return lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n def char_count(lst):\n return sum(len(s) for s in lst)\n \n count1 = char_count(lst1)\n count2 = char_count(lst2)\n \n if count1 < count2:\n return lst1\n elif count2 < count1:\n return lst2\n else:\n return lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n # Helper function to calculate the total number of characters in a list of strings\n def total_chars(lst):\n return sum(len(s) for s in lst)\n \n # Calculate the total number of characters for both lists\n total_chars_lst1 = total_chars(lst1)\n total_chars_lst2 = total_chars(lst2)\n \n # Compare the total number of characters and return the appropriate list\n if total_chars_lst1 < total_chars_lst2:\n return lst1\n elif total_chars_lst2 < total_chars_lst1:\n return lst2\n else:\n return lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n def char_count(lst):\n return sum(len(s) for s in lst)\n\n count1 = char_count(lst1)\n count2 = char_count(lst2)\n\n if count1 < count2:\n return lst1\n elif count2 < count1:\n return lst2\n else:\n return lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n def char_count(lst):\n return sum(len(s) for s in lst)\n \n count1 = char_count(lst1)\n count2 = char_count(lst2)\n \n if count1 < count2:\n return lst1\n elif count2 < count1:\n return lst2\n else:\n return lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n def char_count(lst):\n return sum(len(s) for s in lst)\n \n count1 = char_count(lst1)\n count2 = char_count(lst2)\n \n if count1 < count2:\n return lst1\n elif count2 < count1:\n return lst2\n else:\n return lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n def count_chars(lst):\n return sum(len(s) for s in lst)\n\n count1 = count_chars(lst1)\n count2 = count_chars(lst2)\n\n if count1 < count2:\n return lst1\n elif count2 < count1:\n return lst2\n else:\n return lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n def count_chars(lst):\n return sum(len(s) for s in lst)\n\n count1 = count_chars(lst1)\n count2 = count_chars(lst2)\n\n if count1 < count2:\n return lst1\n elif count2 < count1:\n return lst2\n else:\n return lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n def char_count(lst):\n return sum(len(s) for s in lst)\n\n count1 = char_count(lst1)\n count2 = char_count(lst2)\n\n if count1 < count2:\n return lst1\n elif count2 < count1:\n return lst2\n else:\n return lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n def count_chars(lst):\n return sum(len(s) for s in lst)\n\n count1 = count_chars(lst1)\n count2 = count_chars(lst2)\n\n if count1 < count2:\n return lst1\n elif count2 < count1:\n return lst2\n else:\n return lst1", "matching_cluster_idx": 7}]}, "HumanEval/85": {"dps": 91.68316831683168, "dps_norm": 60.0, "pass@1": 100.0, "profiled": [{"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices..\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n total = 0\n for i in range(1, len(lst), 2): # Iterate over odd indices\n if lst[i] % 2 == 0: # Check if the element is even\n total += lst[i]\n return total", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst, add the even elements that are at odd indices.\"\"\"\n return sum(x for i, x in enumerate(lst) if i % 2 != 0 and x % 2 == 0)", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst, add the even elements that are at odd indices.\"\"\"\n return sum(value for index, value in enumerate(lst) if index % 2 == 1 and value % 2 == 0)", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. Add the even elements that are at odd indices.\"\"\"\n return sum(value for index, value in enumerate(lst) if index % 2 != 0 and value % 2 == 0)", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst, add the even elements that are at odd indices.\"\"\"\n return sum(x for i, x in enumerate(lst) if i % 2 != 0 and x % 2 == 0)", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices.\"\"\"\n return sum(num for idx, num in enumerate(lst) if idx % 2 != 0 and num % 2 == 0)", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst, add the even elements that are at odd indices.\"\"\"\n total = 0\n for i in range(1, len(lst), 2): # Iterate over odd indices\n if lst[i] % 2 == 0: # Check if the element is even\n total += lst[i]\n return total", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst, add the even elements that are at odd indices.\"\"\"\n total = 0\n for i in range(1, len(lst), 2): # Start from index 1 and step by 2 to hit odd indices\n if lst[i] % 2 == 0: # Check if the element at the odd index is even\n total += lst[i]\n return total", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices..\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n total = 0\n for i in range(1, len(lst), 2): # Start from index 1 (odd index) and step by 2\n if lst[i] % 2 == 0: # Check if the element at the odd index is even\n total += lst[i]\n return total", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices.\"\"\"\n total = 0\n for i in range(1, len(lst), 2): # Start from index 1 and step by 2 to get odd indices\n if lst[i] % 2 == 0: # Check if the element at the odd index is even\n total += lst[i]\n return total", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices.\"\"\"\n total = 0\n for i in range(1, len(lst), 2): # Start from index 1 and step by 2 to get odd indices\n if lst[i] % 2 == 0: # Check if the element at the odd index is even\n total += lst[i]\n return total", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices..\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n total = 0\n for i in range(1, len(lst), 2): # Start from index 1 and step by 2 to hit odd indices\n if lst[i] % 2 == 0: # Check if the element is even\n total += lst[i]\n return total", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices..\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n result = 0\n for i in range(1, len(lst), 2): # Start from index 1 (odd indices)\n if lst[i] % 2 == 0: # Check if the element is even\n result += lst[i]\n return result", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices.\"\"\"\n return sum(num for idx, num in enumerate(lst) if idx % 2 == 1 and num % 2 == 0)", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices..\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n total = 0\n for i in range(1, len(lst), 2): # Iterate over odd indices\n if lst[i] % 2 == 0: # Check if the element is even\n total += lst[i]\n return total", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst, add the even elements that are at odd indices.\"\"\"\n total = 0\n for i in range(1, len(lst), 2): # Start from index 1 and step by 2 to get odd indices\n if lst[i] % 2 == 0: # Check if the element at the odd index is even\n total += lst[i]\n return total", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst, add the even elements that are at odd indices.\"\"\"\n return sum(num for idx, num in enumerate(lst) if idx % 2 != 0 and num % 2 == 0)", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices.\"\"\"\n total = 0\n for i in range(1, len(lst), 2): # Start from index 1 and step by 2 to get odd indices\n if lst[i] % 2 == 0: # Check if the element at the odd index is even\n total += lst[i]\n return total", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices..\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n total = 0\n for i in range(1, len(lst), 2): # Start from index 1 and step by 2 to get odd indices\n if lst[i] % 2 == 0: # Check if the element at the odd index is even\n total += lst[i]\n return total", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. Add the even elements that are at odd indices.\"\"\"\n total = 0\n for i in range(1, len(lst), 2): # Start from index 1 and step by 2 to get odd indices\n if lst[i] % 2 == 0: # Check if the element at the odd index is even\n total += lst[i]\n return total", "matching_cluster_idx": 3}]}, "HumanEval/86": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n words = s.split(' ')\n ordered_words = []\n for word in words:\n ordered_word = ''.join(sorted(word))\n ordered_words.append(ordered_word)\n return ' '.join(ordered_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n words = s.split(' ')\n ordered_words = []\n for word in words:\n ordered_word = ''.join(sorted(word))\n ordered_words.append(ordered_word)\n return ' '.join(ordered_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n def sort_word(word):\n return ''.join(sorted(word))\n\n words = s.split(' ')\n sorted_words = [sort_word(word) for word in words]\n return ' '.join(sorted_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n words = s.split(' ') # Split the string into words\n ordered_words = []\n\n for word in words:\n # Sort the characters in the word and join them back into a string\n ordered_word = ''.join(sorted(word))\n ordered_words.append(ordered_word)\n\n # Join the ordered words back into a single string with spaces\n return ' '.join(ordered_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n words = s.split(' ')\n ordered_words = []\n for word in words:\n ordered_word = ''.join(sorted(word))\n ordered_words.append(ordered_word)\n return ' '.join(ordered_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n words = s.split(' ')\n ordered_words = []\n for word in words:\n ordered_word = ''.join(sorted(word))\n ordered_words.append(ordered_word)\n return ' '.join(ordered_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n words = s.split(' ')\n ordered_words = []\n \n for word in words:\n ordered_word = ''.join(sorted(word))\n ordered_words.append(ordered_word)\n \n return ' '.join(ordered_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n words = s.split(' ')\n ordered_words = []\n for word in words:\n ordered_word = ''.join(sorted(word))\n ordered_words.append(ordered_word)\n return ' '.join(ordered_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n words = s.split(' ')\n ordered_words = []\n\n for word in words:\n ordered_word = ''.join(sorted(word))\n ordered_words.append(ordered_word)\n\n return ' '.join(ordered_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n # Split the string into words\n words = s.split(' ')\n \n # Sort each word and join them back into a string\n sorted_words = [''.join(sorted(word)) for word in words]\n \n # Join the sorted words back into a string, maintaining spaces\n return ' '.join(sorted_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n words = s.split(' ')\n ordered_words = []\n for word in words:\n ordered_word = ''.join(sorted(word))\n ordered_words.append(ordered_word)\n return ' '.join(ordered_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n # Split the string into words\n words = s.split(' ')\n \n # Sort each word and join them back together\n sorted_words = [''.join(sorted(word)) for word in words]\n \n # Join the sorted words back into a single string, maintaining spaces\n result = ' '.join(sorted_words)\n \n return result", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n words = s.split(' ')\n ordered_words = []\n \n for word in words:\n ordered_word = ''.join(sorted(word))\n ordered_words.append(ordered_word)\n \n return ' '.join(ordered_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n words = s.split(' ')\n ordered_words = []\n\n for word in words:\n ordered_word = ''.join(sorted(word))\n ordered_words.append(ordered_word)\n\n return ' '.join(ordered_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n # Split the string into words while preserving spaces\n words = s.split(' ')\n \n # Sort each word based on ASCII values\n sorted_words = []\n for word in words:\n sorted_word = ''.join(sorted(word))\n sorted_words.append(sorted_word)\n \n # Join the sorted words back into a string with spaces\n return ' '.join(sorted_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n words = s.split(' ')\n ordered_words = []\n for word in words:\n ordered_word = ''.join(sorted(word))\n ordered_words.append(ordered_word)\n return ' '.join(ordered_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n words = s.split(' ')\n ordered_words = []\n\n for word in words:\n ordered_word = ''.join(sorted(word))\n ordered_words.append(ordered_word)\n\n return ' '.join(ordered_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n words = s.split(' ')\n ordered_words = []\n for word in words:\n ordered_word = ''.join(sorted(word))\n ordered_words.append(ordered_word)\n return ' '.join(ordered_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n words = s.split(' ')\n ordered_words = []\n for word in words:\n ordered_word = ''.join(sorted(word))\n ordered_words.append(ordered_word)\n return ' '.join(ordered_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n words = s.split(' ')\n ordered_words = []\n for word in words:\n ordered_word = ''.join(sorted(word))\n ordered_words.append(ordered_word)\n return ' '.join(ordered_words)", "matching_cluster_idx": 4}]}, "HumanEval/87": {"dps": 93.94812680115274, "dps_norm": 57.142857142857146, "pass@1": 100.0, "profiled": [{"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n coordinates = []\n for i, row in enumerate(lst):\n for j, value in enumerate(row):\n if value == x:\n coordinates.append((i, j))\n \n # Sort by rows first, then by columns in descending order\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n coordinates = []\n for i, row in enumerate(lst):\n for j, value in enumerate(row):\n if value == x:\n coordinates.append((i, j))\n \n # Sort coordinates by rows in ascending order and columns in descending order\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n coordinates = []\n for i, row in enumerate(lst):\n for j, value in enumerate(row):\n if value == x:\n coordinates.append((i, j))\n \n # Sort by rows in ascending order, then by columns in descending order\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n coordinates = []\n for row_index, row in enumerate(lst):\n for column_index, value in enumerate(row):\n if value == x:\n coordinates.append((row_index, column_index))\n \n # Sort by row index first, then by column index in descending order\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n \n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n coordinates = []\n for i, row in enumerate(lst):\n for j, value in enumerate(row):\n if value == x:\n coordinates.append((i, j))\n \n # Sort by rows first, then by columns in descending order within each row\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n \n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n coordinates = []\n for row_index, row in enumerate(lst):\n for column_index, value in enumerate(row):\n if value == x:\n coordinates.append((row_index, column_index))\n \n # Sort by rows first in ascending order, then by columns in descending order\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n coordinates = []\n for row_idx, row in enumerate(lst):\n for col_idx, value in enumerate(row):\n if value == x:\n coordinates.append((row_idx, col_idx))\n \n # Sort by row index ascending, then by column index descending\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n \n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n coordinates = []\n for row_index, row in enumerate(lst):\n for col_index, value in enumerate(row):\n if value == x:\n coordinates.append((row_index, col_index))\n \n # Sort by rows first, then by columns in descending order within each row\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n coordinates = []\n for row_index, row in enumerate(lst):\n for col_index, value in enumerate(row):\n if value == x:\n coordinates.append((row_index, col_index))\n \n # Sort by row index, then by column index in descending order\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n \n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n coordinates = []\n for row_idx, row in enumerate(lst):\n for col_idx, value in enumerate(row):\n if value == x:\n coordinates.append((row_idx, col_idx))\n \n # Sort by row index, then by column index in descending order\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n coordinates = []\n for i, row in enumerate(lst):\n for j, value in enumerate(row):\n if value == x:\n coordinates.append((i, j))\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n coordinates = []\n for row_index, row in enumerate(lst):\n for col_index, value in enumerate(row):\n if value == x:\n coordinates.append((row_index, col_index))\n \n # Sort by rows in ascending order, then by columns in descending order\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n coordinates = []\n for row_index, row in enumerate(lst):\n for col_index, value in enumerate(row):\n if value == x:\n coordinates.append((row_index, col_index))\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n coordinates = []\n for i, row in enumerate(lst):\n for j, value in enumerate(row):\n if value == x:\n coordinates.append((i, j))\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n coordinates = []\n for row_index, row in enumerate(lst):\n for column_index, value in enumerate(row):\n if value == x:\n coordinates.append((row_index, column_index))\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n coordinates = []\n for row_index, row in enumerate(lst):\n for col_index, value in enumerate(row):\n if value == x:\n coordinates.append((row_index, col_index))\n \n # Sort by row index ascending, then by column index descending\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n coordinates = []\n for row_idx, row in enumerate(lst):\n for col_idx, value in enumerate(row):\n if value == x:\n coordinates.append((row_idx, col_idx))\n \n # Sort by rows in ascending order, then by columns in descending order\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n coordinates = []\n for row_index, row in enumerate(lst):\n for column_index, value in enumerate(row):\n if value == x:\n coordinates.append((row_index, column_index))\n \n # Sort by rows first (ascending) and then by columns (descending)\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n \n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n coordinates = []\n for row_index, row in enumerate(lst):\n for col_index, value in enumerate(row):\n if value == x:\n coordinates.append((row_index, col_index))\n \n # Sort by row index ascending, then by column index descending\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n coordinates = []\n for row_idx, row in enumerate(lst):\n for col_idx, value in enumerate(row):\n if value == x:\n coordinates.append((row_idx, col_idx))\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n return coordinates", "matching_cluster_idx": 3}]}, "HumanEval/89": {"dps": 96.64948453608248, "dps_norm": 28.571428571428573, "pass@1": 100.0, "profiled": [{"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n def rotate_char(c):\n if 'a' <= c <= 'z':\n return chr((ord(c) - ord('a') + 2 * 2) % 26 + ord('a'))\n elif 'A' <= c <= 'Z':\n return chr((ord(c) - ord('A') + 2 * 2) % 26 + ord('A'))\n else:\n return c\n\n return ''.join(rotate_char(c) for c in s)", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n def rotate_char(c, rotation):\n if 'a' <= c <= 'z':\n return chr(((ord(c) - ord('a') + rotation) % 26) + ord('a'))\n elif 'A' <= c <= 'Z':\n return chr(((ord(c) - ord('A') + rotation) % 26) + ord('A'))\n else:\n return c\n\n result = \"\"\n for char in s:\n result += rotate_char(char, 4) # 2 * 2 = 4\n return result", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n def rotate_char(c):\n if 'a' <= c <= 'z':\n return chr((ord(c) - ord('a') + 2 * 2) % 26 + ord('a'))\n elif 'A' <= c <= 'Z':\n return chr((ord(c) - ord('A') + 2 * 2) % 26 + ord('A'))\n else:\n return c\n\n return ''.join(rotate_char(c) for c in s)", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n def rotate_char(c):\n if 'a' <= c <= 'z':\n return chr((ord(c) - ord('a') + 2 * 2) % 26 + ord('a'))\n elif 'A' <= c <= 'Z':\n return chr((ord(c) - ord('A') + 2 * 2) % 26 + ord('A'))\n else:\n return c\n\n return ''.join(rotate_char(c) for c in s)", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n def rotate_char(c):\n if 'a' <= c <= 'z':\n return chr((ord(c) - ord('a') + 2 * 2) % 26 + ord('a'))\n elif 'A' <= c <= 'Z':\n return chr((ord(c) - ord('A') + 2 * 2) % 26 + ord('A'))\n else:\n return c\n\n encrypted_string = ''.join(rotate_char(c) for c in s)\n return encrypted_string", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n result = []\n for char in s:\n if char.isalpha():\n shift = 2 * 2 # Shift each letter by 4 places\n if char.islower():\n # Rotate the lowercase alphabet\n encrypted_char = chr((ord(char) - ord('a') + shift) % 26 + ord('a'))\n else:\n # Rotate the uppercase alphabet\n encrypted_char = chr((ord(char) - ord('A') + shift) % 26 + ord('A'))\n result.append(encrypted_char)\n else:\n result.append(char)\n return ''.join(result)", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n def rotate_char(c):\n if 'a' <= c <= 'z':\n return chr((ord(c) - ord('a') + 2 * 2) % 26 + ord('a'))\n elif 'A' <= c <= 'Z':\n return chr((ord(c) - ord('A') + 2 * 2) % 26 + ord('A'))\n else:\n return c\n\n return ''.join(rotate_char(c) for c in s)", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n result = []\n for char in s:\n if char.isalpha():\n if char.islower():\n offset = ord('a')\n shifted = (ord(char) - offset + 2 * 2) % 26\n result.append(chr(offset + shifted))\n else:\n offset = ord('A')\n shifted = (ord(char) - offset + 2 * 2) % 26\n result.append(chr(offset + shifted))\n else:\n result.append(char)\n return ''.join(result)", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n def rotate_char(c):\n if 'a' <= c <= 'z':\n return chr((ord(c) - ord('a') + 2 * 2) % 26 + ord('a'))\n elif 'A' <= c <= 'Z':\n return chr((ord(c) - ord('A') + 2 * 2) % 26 + ord('A'))\n else:\n return c\n\n return ''.join(rotate_char(c) for c in s)", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n def rotate_char(c, n):\n if 'a' <= c <= 'z':\n return chr((ord(c) - ord('a') + n) % 26 + ord('a'))\n elif 'A' <= c <= 'Z':\n return chr((ord(c) - ord('A') + n) % 26 + ord('A'))\n else:\n return c\n \n encrypted_text = \"\"\n for char in s:\n encrypted_text += rotate_char(char, 4) # 2 * 2 = 4\n return encrypted_text", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n def rotate_char(c):\n if c.isalpha():\n offset = 65 if c.isupper() else 97\n return chr((ord(c) - offset + 2 * 2) % 26 + offset)\n return c\n\n return ''.join(rotate_char(c) for c in s)", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n def rotate_char(c):\n if 'a' <= c <= 'z':\n return chr(((ord(c) - ord('a') + 2 * 2) % 26) + ord('a'))\n elif 'A' <= c <= 'Z':\n return chr(((ord(c) - ord('A') + 2 * 2) % 26) + ord('A'))\n else:\n return c\n\n return ''.join(rotate_char(c) for c in s)", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n def shift_char(c):\n if 'a' <= c <= 'z':\n return chr((ord(c) - ord('a') + 2 * 2) % 26 + ord('a'))\n elif 'A' <= c <= 'Z':\n return chr((ord(c) - ord('A') + 2 * 2) % 26 + ord('A'))\n else:\n return c\n\n return ''.join(shift_char(c) for c in s)", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n def rotate_char(c):\n if 'a' <= c <= 'z':\n return chr((ord(c) - ord('a') + 2 * 2) % 26 + ord('a'))\n elif 'A' <= c <= 'Z':\n return chr((ord(c) - ord('A') + 2 * 2) % 26 + ord('A'))\n else:\n return c\n\n encrypted_string = ''.join(rotate_char(c) for c in s)\n return encrypted_string", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n def rotate_char(c):\n if 'a' <= c <= 'z':\n return chr((ord(c) - ord('a') + 2 * 2) % 26 + ord('a'))\n elif 'A' <= c <= 'Z':\n return chr((ord(c) - ord('A') + 2 * 2) % 26 + ord('A'))\n else:\n return c\n \n return ''.join(rotate_char(c) for c in s)", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n def rotate_char(c):\n if 'a' <= c <= 'z':\n return chr((ord(c) - ord('a') + 2 * 2) % 26 + ord('a'))\n elif 'A' <= c <= 'Z':\n return chr((ord(c) - ord('A') + 2 * 2) % 26 + ord('A'))\n else:\n return c\n \n return ''.join(rotate_char(c) for c in s)", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n def rotate_char(c):\n if 'a' <= c <= 'z':\n return chr((ord(c) - ord('a') + 2 * 2) % 26 + ord('a'))\n elif 'A' <= c <= 'Z':\n return chr((ord(c) - ord('A') + 2 * 2) % 26 + ord('A'))\n else:\n return c\n\n return ''.join(rotate_char(c) for c in s)", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n def rotate_char(c, n):\n if 'a' <= c <= 'z':\n return chr((ord(c) - ord('a') + n) % 26 + ord('a'))\n elif 'A' <= c <= 'Z':\n return chr((ord(c) - ord('A') + n) % 26 + ord('A'))\n else:\n return c\n\n encrypted_text = ''\n for char in s:\n encrypted_text += rotate_char(char, 2 * 2) # Rotate by 4 positions\n return encrypted_text", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n def rotate_char(c, n):\n if 'a' <= c <= 'z':\n return chr((ord(c) - ord('a') + n) % 26 + ord('a'))\n elif 'A' <= c <= 'Z':\n return chr((ord(c) - ord('A') + n) % 26 + ord('A'))\n else:\n return c\n\n encrypted_string = \"\"\n for char in s:\n encrypted_string += rotate_char(char, 2 * 2) # Rotate by 4 positions\n return encrypted_string", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n def rotate_char(c, n):\n if c.isalpha():\n ascii_offset = ord('a') if c.islower() else ord('A')\n return chr((ord(c) - ascii_offset + n) % 26 + ascii_offset)\n return c\n\n rotation = 2 * 2 # Rotate by 2*2 = 4 places\n encrypted_string = ''.join(rotate_char(c, rotation) for c in s)\n return encrypted_string", "matching_cluster_idx": 1}]}, "HumanEval/90": {"dps": 85.75875486381324, "dps_norm": 57.91666666666667, "pass@1": 100.0, "profiled": [{"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n unique_sorted = sorted(set(lst))\n if len(unique_sorted) < 2:\n return None\n return unique_sorted[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n unique_sorted = sorted(set(lst))\n if len(unique_sorted) < 2:\n return None\n return unique_sorted[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n sorted_unique_list = sorted(set(lst))\n if len(sorted_unique_list) < 2:\n return None\n return sorted_unique_list[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n sorted_lst = sorted(set(lst))\n if len(sorted_lst) < 2:\n return None\n return sorted_lst[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n unique_sorted_lst = sorted(set(lst))\n if len(unique_sorted_lst) < 2:\n return None\n return unique_sorted_lst[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n sorted_lst = sorted(set(lst))\n if len(sorted_lst) < 2:\n return None\n return sorted_lst[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n sorted_lst = sorted(set(lst))\n if len(sorted_lst) < 2:\n return None\n return sorted_lst[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n sorted_lst = sorted(set(lst))\n if len(sorted_lst) < 2:\n return None\n return sorted_lst[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n unique_sorted_lst = sorted(set(lst))\n if len(unique_sorted_lst) < 2:\n return None\n return unique_sorted_lst[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n unique_sorted = sorted(set(lst))\n if len(unique_sorted) < 2:\n return None\n return unique_sorted[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n unique_sorted = sorted(set(lst))\n if len(unique_sorted) < 2:\n return None\n return unique_sorted[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n \n # Remove duplicates and sort the list\n unique_sorted_lst = sorted(set(lst))\n \n # Check if there is a second smallest element\n if len(unique_sorted_lst) < 2:\n return None\n \n return unique_sorted_lst[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n unique_sorted_list = sorted(set(lst))\n if len(unique_sorted_list) < 2:\n return None\n return unique_sorted_list[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n unique_sorted_lst = sorted(set(lst))\n if len(unique_sorted_lst) < 2:\n return None\n return unique_sorted_lst[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n sorted_lst = sorted(set(lst))\n if len(sorted_lst) < 2:\n return None\n return sorted_lst[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n \n # Remove duplicates and sort the list\n unique_sorted_lst = sorted(set(lst))\n \n # Return the 2nd smallest element if it exists\n return unique_sorted_lst[1] if len(unique_sorted_lst) > 1 else None", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n \n first_min = float('inf')\n second_min = float('inf')\n \n for num in lst:\n if num < first_min:\n second_min = first_min\n first_min = num\n elif first_min < num < second_min:\n second_min = num\n \n return second_min if second_min != float('inf') else None", "matching_cluster_idx": 5}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n unique_sorted = sorted(set(lst))\n if len(unique_sorted) < 2:\n return None\n return unique_sorted[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n unique_sorted = sorted(set(lst))\n if len(unique_sorted) < 2:\n return None\n return unique_sorted[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n sorted_unique_lst = sorted(set(lst))\n return sorted_unique_lst[1] if len(sorted_unique_lst) > 1 else None", "matching_cluster_idx": 6}]}, "HumanEval/113": {"dps": 98.98580121703854, "dps_norm": 66.66666666666667, "pass@1": 96.0, "profiled": [{"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n result = []\n for s in lst:\n odd_count = sum(1 for char in s if int(char) % 2 != 0)\n output = f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\"\n result.append(output)\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n result = []\n for s in lst:\n odd_digits = sum(1 for char in s if int(char) % 2 != 0)\n result.append(f\"the number of odd elements {odd_digits}n the str{odd_digits}ng {odd_digits} of the {odd_digits}nput.\")\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n result = []\n for s in lst:\n odd_digits = sum(1 for digit in s if int(digit) % 2 != 0)\n output = \"the number of odd elements {}n the str{}ng {} of the {}nput.\".format(odd_digits, odd_digits, odd_digits, odd_digits)\n result.append(output)\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n result = []\n for s in lst:\n odd_digits = sum(1 for c in s if int(c) % 2 != 0)\n result.append(f\"the number of odd elements {odd_digits}n the str{odd_digits}ng {odd_digits} of the {odd_digits}nput.\")\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n result = []\n for s in lst:\n odd_digits = sum(1 for char in s if int(char) % 2 != 0)\n result.append(f\"the number of odd elements {odd_digits}n the str{odd_digits}ng {odd_digits} of the {odd_digits}nput.\")\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n def count_odds(s):\n return sum(1 for char in s if int(char) % 2 != 0)\n\n result = []\n for i, s in enumerate(lst):\n odd_count = count_odds(s)\n # Replace all occurrences of 'i' with the count of odd digits in the string\n output_str = f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\"\n result.append(output_str)\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n results = []\n for s in lst:\n odd_digits = sum(1 for c in s if int(c) % 2 != 0)\n result_str = f\"the number of odd elements {odd_digits}n the str{odd_digits}ng {odd_digits} of the {odd_digits}nput.\"\n results.append(result_str)\n return results", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n def count_odds(s):\n return sum(1 for char in s if int(char) % 2 != 0)\n\n result = []\n for i, s in enumerate(lst):\n odd_count = count_odds(s)\n # Create the output string with the count of odd digits\n output_str = f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\"\n result.append(output_str)\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n def count_odds_in_string(s):\n return sum(1 for char in s if int(char) % 2 != 0)\n\n result = []\n for i, string in enumerate(lst):\n odd_count_in_string = count_odds_in_string(string)\n result.append(f\"the number of odd elements {odd_count_in_string}n the str{odd_count_in_string}ng {odd_count_in_string} of the {odd_count_in_string}nput.\")\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n def count_odds_in_string(s):\n return sum(1 for char in s if int(char) % 2 != 0)\n\n result = []\n for i, s in enumerate(lst):\n odd_count = count_odds_in_string(s)\n # Replace the number in the template string with the count of odd digits\n result_string = f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\"\n result.append(result_string)\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n def count_odds(s):\n return sum(1 for char in s if int(char) % 2 != 0)\n \n result = []\n for i, s in enumerate(lst):\n odd_count = count_odds(s)\n # Replace all occurrences of 'i' with the count of odd digits in the string\n replaced = s.replace('i', str(odd_count))\n result.append(f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\")\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n def count_odds(s):\n return sum(1 for char in s if int(char) % 2 != 0)\n\n result = []\n for i, s in enumerate(lst):\n odd_count = count_odds(s)\n # Replace 'n' with 'odd' and 'd' with 'digits' to match the expected output format\n output_string = f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\"\n result.append(output_string)\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n result = []\n for s in lst:\n odd_digits = sum(1 for char in s if int(char) % 2 != 0)\n # Replace all occurrences of 'i' with the number of odd digits\n output_str = \"the number of odd elements {0}n the str{0}ng {0} of the {0}nput.\".format(odd_digits)\n result.append(output_str)\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n result = []\n for s in lst:\n odd_digits = sum(1 for char in s if int(char) % 2 != 0)\n output_str = f\"the number of odd elements {odd_digits}n the str{odd_digits}ng {odd_digits} of the {odd_digits}nput.\"\n result.append(output_str)\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n def count_odds_in_string(s):\n return sum(1 for char in s if int(char) % 2 != 0)\n\n result = []\n for i, s in enumerate(lst):\n odd_count = count_odds_in_string(s)\n replaced_string = f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\"\n result.append(replaced_string)\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n result = []\n for s in lst:\n odd_digits = sum(1 for c in s if int(c) % 2 != 0)\n result.append(f\"the number of odd elements {odd_digits}n the str{odd_digits}ng {odd_digits} of the {odd_digits}nput.\")\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n def count_odds(s):\n return sum(1 for char in s if int(char) % 2 != 0)\n\n result = []\n for idx, s in enumerate(lst):\n odd_count = count_odds(s)\n # Replace the number with the count of odd digits in the string\n new_string = f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\"\n result.append(new_string)\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n result = []\n for s in lst:\n odd_count = sum(1 for c in s if int(c) % 2 != 0)\n result.append(f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\")\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n def count_odds_in_string(s):\n return sum(1 for char in s if int(char) % 2 != 0)\n\n result = []\n for i, s in enumerate(lst):\n odd_count = count_odds_in_string(s)\n # Create the replacement string with the count of odd digits\n replacement = f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\"\n result.append(replacement)\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n def count_odds_in_string(s):\n return sum(1 for char in s if int(char) % 2 != 0)\n\n result = []\n for i, s in enumerate(lst):\n odd_count = count_odds_in_string(s)\n # Replace all occurrences of 'i' with the count of odd digits in the string\n output_string = f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\"\n result.append(output_string)\n return result", "matching_cluster_idx": 3}]}, "HumanEval/119": {"dps": 62.7906976744186, "dps_norm": 92.0, "pass@1": 96.0, "profiled": [{"solution": "def match_parens(lst):\n def is_balanced(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n else:\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n s1, s2 = lst\n return 'Yes' if is_balanced(s1 + s2) or is_balanced(s2 + s1) else 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n s1, s2 = lst\n\n # Check all possible concatenations\n if is_balanced(s1 + s2) or is_balanced(s2 + s1):\n return 'Yes'\n else:\n return 'No'\ndef is_balanced(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n elif char == ')':\n balance -= 1\n if balance < 0:\n return False\n return balance == 0", "matching_cluster_idx": 3}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n # Concatenate the two strings in both possible orders\n s1, s2 = lst\n combined1 = s1 + s2\n combined2 = s2 + s1\n\n # Check if either combined string is balanced\n def is_balanced(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n else:\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n return 'Yes' if is_balanced(combined1) or is_balanced(combined2) else 'No'", "matching_cluster_idx": 3}, {"solution": "def match_parens(lst):\n def is_good(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n else:\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n s1, s2 = lst\n # Check both possible concatenations\n if is_good(s1 + s2) or is_good(s2 + s1):\n return 'Yes'\n else:\n return 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n def is_good(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n else:\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n s1, s2 = lst\n # Check all possible concatenations\n if is_good(s1 + s2) or is_good(s2 + s1):\n return 'Yes'\n else:\n return 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n s1, s2 = lst\n\n # Check if concatenating both strings in any order can result in a balanced string\n for order in [s1 + s2, s2 + s1]:\n balance = 0\n is_good = True\n for char in order:\n if char == '(':\n balance += 1\n elif char == ')':\n balance -= 1\n if balance < 0:\n is_good = False\n break\n if is_good and balance == 0:\n return 'Yes'\n return 'No'", "matching_cluster_idx": 3}, {"solution": "def match_parens(lst):\n def is_good(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n else:\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n s1, s2 = lst\n # Check all possible concatenations\n return 'Yes' if is_good(s1 + s2) or is_good(s2 + s1) else 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n def is_balanced(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n else:\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n s1, s2 = lst\n return 'Yes' if is_balanced(s1 + s2) or is_balanced(s2 + s1) else 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n s1, s2 = lst\n\n def is_good(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n else:\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n return 'Yes' if is_good(s1 + s2) or is_good(s2 + s1) else 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n def is_good(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n else:\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n s1, s2 = lst\n # Check all combinations\n if is_good(s1 + s2) or is_good(s2 + s1):\n return 'Yes'\n else:\n return 'No'", "matching_cluster_idx": 3}, {"solution": "def match_parens(lst):\n def is_balanced(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n elif char == ')':\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n s1, s2 = lst\n return 'Yes' if is_balanced(s1 + s2) or is_balanced(s2 + s1) else 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n def is_balanced(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n else:\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n s1, s2 = lst\n # Check all possible concatenations\n if is_balanced(s1 + s2) or is_balanced(s2 + s1):\n return 'Yes'\n else:\n return 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n # Helper function to check if a single string is balanced\n def is_balanced(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n else:\n balance -= 1\n if balance < 0:\n return False # More closing than opening\n return balance == 0\n\n # Concatenate the two strings in both possible orders and check if either is balanced\n s1, s2 = lst\n if is_balanced(s1 + s2) or is_balanced(s2 + s1):\n return 'Yes'\n else:\n return 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n def is_balanced(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n else:\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n s1, s2 = lst\n return 'Yes' if is_balanced(s1 + s2) or is_balanced(s2 + s1) else 'No'", "matching_cluster_idx": 3}, {"solution": "def match_parens(lst):\n def is_good(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n else:\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n s1, s2 = lst\n # Check both possible concatenations\n if is_good(s1 + s2) or is_good(s2 + s1):\n return 'Yes'\n else:\n return 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n def is_good(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n else:\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n s1, s2 = lst\n # Try concatenating in both orders\n if is_good(s1 + s2) or is_good(s2 + s1):\n return 'Yes'\n else:\n return 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n def is_balanced(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n else:\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n s1, s2 = lst\n # Check both possible concatenations\n if is_balanced(s1 + s2) or is_balanced(s2 + s1):\n return 'Yes'\n else:\n return 'No'", "matching_cluster_idx": 3}, {"solution": "def match_parens(lst):\n def is_good(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n else:\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n s1, s2 = lst\n return 'Yes' if is_good(s1 + s2) or is_good(s2 + s1) else 'No'", "matching_cluster_idx": 3}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n # Helper function to check if a single string is balanced\n def is_balanced(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n else:\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n # Try concatenating the strings in both possible orders\n s1, s2 = lst\n return 'Yes' if is_balanced(s1 + s2) or is_balanced(s2 + s1) else 'No'", "matching_cluster_idx": 3}, {"solution": "def match_parens(lst):\n def is_balanced(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n elif char == ')':\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n s1, s2 = lst\n # Check both possible concatenations\n if is_balanced(s1 + s2) or is_balanced(s2 + s1):\n return 'Yes'\n else:\n return 'No'", "matching_cluster_idx": 4}]}, "HumanEval/120": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 22.0, "profiled": [{"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n \"\"\"\n # Sort the array in descending order\n sorted_arr = sorted(arr, reverse=True)\n # Return the first k elements from the sorted array\n return sorted(sorted_arr[:k])", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n\n Example 1:\n\n Input: arr = [-3, -4, 5], k = 3\n Output: [-4, -3, 5]\n\n Example 2:\n\n Input: arr = [4, -4, 4], k = 2\n Output: [4, 4]\n\n Example 3:\n\n Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1\n Output: [2]\n\n Note:\n 1. The length of the array will be in the range of [1, 1000].\n 2. The elements in the array will be in the range of [-1000, 1000].\n 3. 0 <= k <= len(arr)\n \"\"\"\n if k == 0:\n return []\n arr.sort(reverse=True)\n return sorted(arr[:k])", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n\n Example 1:\n\n Input: arr = [-3, -4, 5], k = 3\n Output: [-4, -3, 5]\n\n Example 2:\n\n Input: arr = [4, -4, 4], k = 2\n Output: [4, 4]\n\n Example 3:\n\n Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1\n Output: [2]\n\n Note:\n 1. The length of the array will be in the range of [1, 1000].\n 2. The elements in the array will be in the range of [-1000, 1000].\n 3. 0 <= k <= len(arr)\n \"\"\"\n # Sort the array in descending order\n sorted_arr = sorted(arr, reverse=True)\n # Get the first k elements from the sorted array\n max_k_elements = sorted_arr[:k]\n # Sort the result in ascending order before returning\n return sorted(max_k_elements)", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n\n Example 1:\n\n Input: arr = [-3, -4, 5], k = 3\n Output: [-4, -3, 5]\n\n Example 2:\n\n Input: arr = [4, -4, 4], k = 2\n Output: [4, 4]\n\n Example 3:\n\n Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1\n Output: [2]\n\n Note:\n 1. The length of the array will be in the range of [1, 1000].\n 2. The elements in the array will be in the range of [-1000, 1000].\n 3. 0 <= k <= len(arr)\n \"\"\"\n # Sort the array in descending order\n sorted_arr = sorted(arr, reverse=True)\n # Get the top k elements\n top_k = sorted_arr[:k]\n # Return the sorted list\n return sorted(top_k)", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n\n Example 1:\n\n Input: arr = [-3, -4, 5], k = 3\n Output: [-4, -3, 5]\n\n Example 2:\n\n Input: arr = [4, -4, 4], k = 2\n Output: [4, 4]\n\n Example 3:\n\n Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1\n Output: [2]\n\n Note:\n 1. The length of the array will be in the range of [1, 1000].\n 2. The elements in the array will be in the range of [-1000, 1000].\n 3. 0 <= k <= len(arr)\n \"\"\"\n if k == 0:\n return []\n arr_sorted = sorted(arr, reverse=True)\n return sorted(arr_sorted[:k])", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n\n Example 1:\n\n Input: arr = [-3, -4, 5], k = 3\n Output: [-4, -3, 5]\n\n Example 2:\n\n Input: arr = [4, -4, 4], k = 2\n Output: [4, 4]\n\n Example 3:\n\n Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1\n Output: [2]\n\n Note:\n 1. The length of the array will be in the range of [1, 1000].\n 2. The elements in the array will be in the range of [-1000, 1000].\n 3. 0 <= k <= len(arr)\n \"\"\"\n if k == 0:\n return []\n arr_sorted = sorted(arr, reverse=True)\n return sorted(arr_sorted[:k])", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n\n Example 1:\n\n Input: arr = [-3, -4, 5], k = 3\n Output: [-4, -3, 5]\n\n Example 2:\n\n Input: arr = [4, -4, 4], k = 2\n Output: [4, 4]\n\n Example 3:\n\n Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1\n Output: [2]\n\n Note:\n 1. The length of the array will be in the range of [1, 1000].\n 2. The elements in the array will be in the range of [-1000, 1000].\n 3. 0 <= k <= len(arr)\n \"\"\"\n if k == 0:\n return []\n arr_sorted = sorted(arr, reverse=True)\n return sorted(arr_sorted[:k])", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n\n Example 1:\n\n Input: arr = [-3, -4, 5], k = 3\n Output: [-4, -3, 5]\n\n Example 2:\n\n Input: arr = [4, -4, 4], k = 2\n Output: [4, 4]\n\n Example 3:\n\n Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1\n Output: [2]\n\n Note:\n 1. The length of the array will be in the range of [1, 1000].\n 2. The elements in the array will be in the range of [-1000, 1000].\n 3. 0 <= k <= len(arr)\n \"\"\"\n if k == 0:\n return []\n arr.sort(reverse=True)\n return sorted(arr[:k])", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n \"\"\"\n # Sort the array in descending order\n sorted_arr = sorted(arr, reverse=True)\n # Return the first k elements from the sorted array\n return sorted(sorted_arr[:k])", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n \"\"\"\n # Sort the array in descending order\n sorted_arr = sorted(arr, reverse=True)\n # Get the first k elements from the sorted array\n max_k_elements = sorted_arr[:k]\n # Sort the result to ensure the output is in ascending order\n return sorted(max_k_elements)", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n\n Example 1:\n\n Input: arr = [-3, -4, 5], k = 3\n Output: [-4, -3, 5]\n\n Example 2:\n\n Input: arr = [4, -4, 4], k = 2\n Output: [4, 4]\n\n Example 3:\n\n Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1\n Output: [2]\n\n Note:\n 1. The length of the array will be in the range of [1, 1000].\n 2. The elements in the array will be in the range of [-1000, 1000].\n 3. 0 <= k <= len(arr)\n \"\"\"\n if k == 0:\n return []\n arr.sort()\n return arr[-k:]", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n\n Example 1:\n\n Input: arr = [-3, -4, 5], k = 3\n Output: [-4, -3, 5]\n\n Example 2:\n\n Input: arr = [4, -4, 4], k = 2\n Output: [4, 4]\n\n Example 3:\n\n Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1\n Output: [2]\n\n Note:\n 1. The length of the array will be in the range of [1, 1000].\n 2. The elements in the array will be in the range of [-1000, 1000].\n 3. 0 <= k <= len(arr)\n \"\"\"\n arr.sort(reverse=True) # Sort the array in descending order\n return sorted(arr[:k]) # Return the first k elements sorted in ascending order", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n \"\"\"\n if k == 0:\n return []\n arr_sorted = sorted(arr, reverse=True)\n return sorted(arr_sorted[:k])", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n\n Example 1:\n\n Input: arr = [-3, -4, 5], k = 3\n Output: [-4, -3, 5]\n\n Example 2:\n\n Input: arr = [4, -4, 4], k = 2\n Output: [4, 4]\n\n Example 3:\n\n Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1\n Output: [2]\n\n Note:\n 1. The length of the array will be in the range of [1, 1000].\n 2. The elements in the array will be in the range of [-1000, 1000].\n 3. 0 <= k <= len(arr)\n \"\"\"\n # Sort the array in descending order\n arr_sorted = sorted(arr, reverse=True)\n # Get the first k elements from the sorted array\n max_k_elements = arr_sorted[:k]\n # Return the sorted list of maximum k elements\n return sorted(max_k_elements)", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n \"\"\"\n if k == 0:\n return []\n arr.sort(reverse=True)\n return sorted(arr[:k])", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n\n Example 1:\n\n Input: arr = [-3, -4, 5], k = 3\n Output: [-4, -3, 5]\n\n Example 2:\n\n Input: arr = [4, -4, 4], k = 2\n Output: [4, 4]\n\n Example 3:\n\n Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1\n Output: [2]\n\n Note:\n 1. The length of the array will be in the range of [1, 1000].\n 2. The elements in the array will be in the range of [-1000, 1000].\n 3. 0 <= k <= len(arr)\n \"\"\"\n # Sort the array in descending order\n sorted_arr = sorted(arr, reverse=True)\n # Get the first k elements from the sorted array\n max_k_elements = sorted_arr[:k]\n # Return the sorted list of maximum k numbers\n return sorted(max_k_elements)", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n\n Example 1:\n\n Input: arr = [-3, -4, 5], k = 3\n Output: [-4, -3, 5]\n\n Example 2:\n\n Input: arr = [4, -4, 4], k = 2\n Output: [4, 4]\n\n Example 3:\n\n Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1\n Output: [2]\n\n Note:\n 1. The length of the array will be in the range of [1, 1000].\n 2. The elements in the array will be in the range of [-1000, 1000].\n 3. 0 <= k <= len(arr)\n \"\"\"\n # Sort the array in descending order\n sorted_arr = sorted(arr, reverse=True)\n # Get the first k elements from the sorted array\n max_k_elements = sorted_arr[:k]\n # Sort the result in ascending order before returning\n return sorted(max_k_elements)", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n \"\"\"\n # Sort the array in descending order\n sorted_arr = sorted(arr, reverse=True)\n # Return the first k elements of the sorted array\n return sorted(sorted_arr[:k])", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n \"\"\"\n # Sort the array in descending order\n sorted_arr = sorted(arr, reverse=True)\n # Get the top k elements\n top_k = sorted_arr[:k]\n # Return the sorted list of maximum k numbers\n return sorted(top_k)", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n\n Example 1:\n\n Input: arr = [-3, -4, 5], k = 3\n Output: [-4, -3, 5]\n\n Example 2:\n\n Input: arr = [4, -4, 4], k = 2\n Output: [4, 4]\n\n Example 3:\n\n Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1\n Output: [2]\n\n Note:\n 1. The length of the array will be in the range of [1, 1000].\n 2. The elements in the array will be in the range of [-1000, 1000].\n 3. 0 <= k <= len(arr)\n \"\"\"\n arr.sort(reverse=True) # Sort the array in descending order\n return sorted(arr[:k]) # Return the first k elements sorted in ascending order", "matching_cluster_idx": 6}]}, "HumanEval/121": {"dps": 92.51121076233184, "dps_norm": 70.71428571428572, "pass@1": 100.0, "profiled": [{"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n Examples:\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n total_sum = 0\n for i in range(0, len(lst), 2): # Iterate over even indices\n if lst[i] % 2 != 0: # Check if the number is odd\n total_sum += lst[i]\n return total_sum", "matching_cluster_idx": 4}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n total_sum = 0\n for i in range(0, len(lst), 2): # Iterate over even positions\n if lst[i] % 2 != 0: # Check if the element is odd\n total_sum += lst[i]\n return total_sum", "matching_cluster_idx": 4}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n\n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==>0\n \"\"\"\n total_sum = 0\n for i in range(0, len(lst), 2): # Iterate over even positions\n if lst[i] % 2 != 0: # Check if the element is odd\n total_sum += lst[i]\n return total_sum", "matching_cluster_idx": 4}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n Examples:\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n total_sum = 0\n for i in range(0, len(lst), 2): # Iterate over even indices\n if lst[i] % 2 != 0: # Check if the element is odd\n total_sum += lst[i]\n return total_sum", "matching_cluster_idx": 4}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n\n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==>0\n \"\"\"\n return sum(lst[i] for i in range(0, len(lst), 2) if lst[i] % 2 != 0)", "matching_cluster_idx": 4}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n\n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n total = 0\n for i in range(0, len(lst), 2): # Iterate over even indices\n if lst[i] % 2 != 0: # Check if the element is odd\n total += lst[i]\n return total", "matching_cluster_idx": 4}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n\n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==>0\n \"\"\"\n total_sum = 0\n for i in range(0, len(lst), 2): # Iterate over even positions\n if lst[i] % 2 != 0: # Check if the element is odd\n total_sum += lst[i]\n return total_sum", "matching_cluster_idx": 4}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n\n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==>0\n \"\"\"\n total_sum = 0\n for i in range(0, len(lst), 2): # Iterate over even indices\n if lst[i] % 2 != 0: # Check if the element is odd\n total_sum += lst[i]\n return total_sum", "matching_cluster_idx": 4}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n\n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==>0\n \"\"\"\n total_sum = 0\n for i in range(0, len(lst), 2): # Iterate over even positions\n if lst[i] % 2 != 0: # Check if the element is odd\n total_sum += lst[i]\n return total_sum", "matching_cluster_idx": 4}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n Examples:\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n total_sum = 0\n for i in range(0, len(lst), 2): # Iterate over even positions\n if lst[i] % 2 != 0: # Check if the element is odd\n total_sum += lst[i]\n return total_sum", "matching_cluster_idx": 4}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n\n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n total_sum = 0\n for i in range(0, len(lst), 2): # Iterate over even positions\n if lst[i] % 2 != 0: # Check if the element is odd\n total_sum += lst[i]\n return total_sum", "matching_cluster_idx": 4}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n\n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==>0\n \"\"\"\n sum_odd = 0\n for i in range(0, len(lst), 2): # Iterate over even indices\n if lst[i] % 2 != 0: # Check if the element is odd\n sum_odd += lst[i]\n return sum_odd", "matching_cluster_idx": 4}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n\n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==>0\n \"\"\"\n sum_odd_in_even_positions = 0\n for i in range(0, len(lst), 2): # Iterate over even positions\n if lst[i] % 2 != 0: # Check if the element is odd\n sum_odd_in_even_positions += lst[i]\n return sum_odd_in_even_positions", "matching_cluster_idx": 4}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n Examples:\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n sum_of_odds = 0\n for i in range(0, len(lst), 2): # Iterate over even positions\n if lst[i] % 2 != 0: # Check if the element is odd\n sum_of_odds += lst[i]\n return sum_of_odds", "matching_cluster_idx": 4}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n Examples:\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n total_sum = 0\n for i in range(0, len(lst), 2): # Iterate over even positions\n if lst[i] % 2 != 0: # Check if the element is odd\n total_sum += lst[i]\n return total_sum", "matching_cluster_idx": 4}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n\n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==>0\n \"\"\"\n total_sum = 0\n for i in range(0, len(lst), 2): # Iterate over even positions\n if lst[i] % 2 != 0: # Check if the element is odd\n total_sum += lst[i]\n return total_sum", "matching_cluster_idx": 4}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n Examples:\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n total_sum = 0\n for i in range(0, len(lst), 2): # Iterate over even positions\n if lst[i] % 2 != 0: # Check if the element is odd\n total_sum += lst[i]\n return total_sum", "matching_cluster_idx": 4}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n Examples:\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n sum_odd_in_even_positions = 0\n for i in range(0, len(lst), 2): # Iterate over even indices\n if lst[i] % 2 != 0: # Check if the element is odd\n sum_odd_in_even_positions += lst[i]\n return sum_odd_in_even_positions", "matching_cluster_idx": 4}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n Examples:\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n total_sum = 0\n for i in range(0, len(lst), 2): # Iterate over even positions\n if lst[i] % 2 != 0: # Check if the element is odd\n total_sum += lst[i]\n return total_sum", "matching_cluster_idx": 4}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n return sum(num for idx, num in enumerate(lst) if idx % 2 == 0 and num % 2 != 0)", "matching_cluster_idx": 3}]}, "HumanEval/149": {"dps": 85.82677165354332, "dps_norm": 57.142857142857146, "pass@1": 100.0, "profiled": [{"solution": "def sorted_list_sum(lst):\n \"\"\"Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order,\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n For example:\n assert list_sort([\"aa\", \"a\", \"aaa\"]) => [\"aa\"]\n assert list_sort([\"ab\", \"a\", \"aaa\", \"cd\"]) => [\"ab\", \"cd\"]\n \"\"\"\n # Filter out strings with odd lengths\n filtered_lst = [s for s in lst if len(s) % 2 == 0]\n \n # Sort the filtered list by length and then alphabetically\n sorted_lst = sorted(filtered_lst, key=lambda x: (len(x), x))\n \n return sorted_lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n # Filter out strings with odd lengths\n filtered_lst = [s for s in lst if len(s) % 2 == 0]\n \n # Sort the list by length and then alphabetically\n sorted_lst = sorted(filtered_lst, key=lambda x: (len(x), x))\n \n return sorted_lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order,\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n You may assume that all words will have the same length.\n For example:\n assert list_sort([\"aa\", \"a\", \"aaa\"]) => [\"aa\"]\n assert list_sort([\"ab\", \"a\", \"aaa\", \"cd\"]) => [\"ab\", \"cd\"]\n \"\"\"\n # Filter out strings with odd lengths\n filtered_lst = [s for s in lst if len(s) % 2 == 0]\n \n # Sort the list by length and then alphabetically\n sorted_lst = sorted(filtered_lst, key=lambda x: (len(x), x))\n \n return sorted_lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order,\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n You may assume that all words will have the same length.\n For example:\n assert list_sort([\"aa\", \"a\", \"aaa\"]) => [\"aa\"]\n assert list_sort([\"ab\", \"a\", \"aaa\", \"cd\"]) => [\"ab\", \"cd\"]\n \"\"\"\n # Filter out strings with odd lengths\n filtered_lst = [s for s in lst if len(s) % 2 == 0]\n \n # Sort the list by length and then alphabetically\n sorted_lst = sorted(filtered_lst, key=lambda x: (len(x), x))\n \n return sorted_lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order,\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n You may assume that all words will have the same length.\n For example:\n assert list_sort([\"aa\", \"a\", \"aaa\"]) => [\"aa\"]\n assert list_sort([\"ab\", \"a\", \"aaa\", \"cd\"]) => [\"ab\", \"cd\"]\n \"\"\"\n # Filter out strings with odd lengths\n filtered_lst = [s for s in lst if len(s) % 2 == 0]\n \n # Sort the list by length and then alphabetically\n sorted_lst = sorted(filtered_lst, key=lambda x: (len(x), x))\n \n return sorted_lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"\n Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order,\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n For example:\n assert sorted_list_sum([\"aa\", \"a\", \"aaa\"]) => [\"aa\"]\n assert sorted_list_sum([\"ab\", \"a\", \"aaa\", \"cd\"]) => [\"ab\", \"cd\"]\n \"\"\"\n # Filter out strings with odd lengths\n filtered_lst = [s for s in lst if len(s) % 2 == 0]\n \n # Sort the list by length and then alphabetically\n sorted_lst = sorted(filtered_lst, key=lambda x: (len(x), x))\n \n return sorted_lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order,\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n You may assume that all words will have the same length.\n For example:\n assert list_sort([\"aa\", \"a\", \"aaa\"]) => [\"aa\"]\n assert list_sort([\"ab\", \"a\", \"aaa\", \"cd\"]) => [\"ab\", \"cd\"]\n \"\"\"\n # Filter out strings with odd lengths\n filtered_lst = [s for s in lst if len(s) % 2 == 0]\n \n # Sort the list by length first, then alphabetically\n sorted_lst = sorted(filtered_lst, key=lambda x: (len(x), x))\n \n return sorted_lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order,\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n You may assume that all words will have the same length.\n For example:\n assert list_sort([\"aa\", \"a\", \"aaa\"]) => [\"aa\"]\n assert list_sort([\"ab\", \"a\", \"aaa\", \"cd\"]) => [\"ab\", \"cd\"]\n \"\"\"\n # Filter out strings with odd lengths\n filtered_lst = [s for s in lst if len(s) % 2 == 0]\n \n # Sort the list by length, then alphabetically\n sorted_lst = sorted(filtered_lst, key=lambda x: (len(x), x))\n \n return sorted_lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order,\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n You may assume that all words will have the same length.\n For example:\n assert list_sort([\"aa\", \"a\", \"aaa\"]) => [\"aa\"]\n assert list_sort([\"ab\", \"a\", \"aaa\", \"cd\"]) => [\"ab\", \"cd\"]\n \"\"\"\n # Filter out strings with odd lengths\n filtered_lst = [s for s in lst if len(s) % 2 == 0]\n \n # Sort the list by length and then alphabetically\n sorted_lst = sorted(filtered_lst, key=lambda x: (len(x), x))\n \n return sorted_lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order,\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n You may assume that all words will have the same length.\n For example:\n assert list_sort([\"aa\", \"a\", \"aaa\"]) => [\"aa\"]\n assert list_sort([\"ab\", \"a\", \"aaa\", \"cd\"]) => [\"ab\", \"cd\"]\n \"\"\"\n # Filter out strings with odd lengths\n filtered_lst = [s for s in lst if len(s) % 2 == 0]\n \n # Sort the list by length and then alphabetically\n sorted_lst = sorted(filtered_lst, key=lambda x: (len(x), x))\n \n return sorted_lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order,\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n You may assume that all words will have the same length.\n For example:\n assert list_sort([\"aa\", \"a\", \"aaa\"]) => [\"aa\"]\n assert list_sort([\"ab\", \"a\", \"aaa\", \"cd\"]) => [\"ab\", \"cd\"]\n \"\"\"\n # Filter out strings with odd lengths\n filtered_list = [s for s in lst if len(s) % 2 == 0]\n \n # Sort the list by length and then alphabetically\n sorted_list = sorted(filtered_list, key=lambda x: (len(x), x))\n \n return sorted_list", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"\n Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order,\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n You may assume that all words will have the same length.\n For example:\n assert list_sort([\"aa\", \"a\", \"aaa\"]) => [\"aa\"]\n assert list_sort([\"ab\", \"a\", \"aaa\", \"cd\"]) => [\"ab\", \"cd\"]\n \"\"\"\n # Filter out strings with odd lengths\n filtered_lst = [s for s in lst if len(s) % 2 == 0]\n \n # Sort the list by length and then alphabetically\n sorted_lst = sorted(filtered_lst, key=lambda x: (len(x), x))\n \n return sorted_lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"\n Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order,\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n You may assume that all words will have the same length.\n For example:\n assert list_sort([\"aa\", \"a\", \"aaa\"]) => [\"aa\"]\n assert list_sort([\"ab\", \"a\", \"aaa\", \"cd\"]) => [\"ab\", \"cd\"]\n \"\"\"\n # Filter out strings with odd lengths\n filtered_lst = [s for s in lst if len(s) % 2 == 0]\n \n # Sort the list by length, then alphabetically\n sorted_lst = sorted(filtered_lst, key=lambda x: (len(x), x))\n \n return sorted_lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order,\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n You may assume that all words will have the same length.\n For example:\n assert list_sort([\"aa\", \"a\", \"aaa\"]) => [\"aa\"]\n assert list_sort([\"ab\", \"a\", \"aaa\", \"cd\"]) => [\"ab\", \"cd\"]\n \"\"\"\n # Filter out strings with odd lengths\n filtered_lst = [s for s in lst if len(s) % 2 == 0]\n \n # Sort the list by length and then alphabetically\n sorted_lst = sorted(filtered_lst, key=lambda x: (len(x), x))\n \n return sorted_lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order,\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n You may assume that all words will have the same length.\n For example:\n assert list_sort([\"aa\", \"a\", \"aaa\"]) => [\"aa\"]\n assert list_sort([\"ab\", \"a\", \"aaa\", \"cd\"]) => [\"ab\", \"cd\"]\n \"\"\"\n # Filter out strings with odd lengths\n filtered_lst = [s for s in lst if len(s) % 2 == 0]\n \n # Sort the list by length and then alphabetically\n sorted_lst = sorted(filtered_lst, key=lambda x: (len(x), x))\n \n return sorted_lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order,\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n For example:\n assert list_sort([\"aa\", \"a\", \"aaa\"]) => [\"aa\"]\n assert list_sort([\"ab\", \"a\", \"aaa\", \"cd\"]) => [\"ab\", \"cd\"]\n \"\"\"\n # Filter out strings with odd lengths\n filtered_lst = [s for s in lst if len(s) % 2 == 0]\n \n # Sort the list by length and then alphabetically\n sorted_lst = sorted(filtered_lst, key=lambda x: (len(x), x))\n \n return sorted_lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"\n Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order,\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n You may assume that all words will have the same length.\n For example:\n assert list_sort([\"aa\", \"a\", \"aaa\"]) => [\"aa\"]\n assert list_sort([\"ab\", \"a\", \"aaa\", \"cd\"]) => [\"ab\", \"cd\"]\n \"\"\"\n # Filter out strings with odd lengths\n filtered_lst = [s for s in lst if len(s) % 2 == 0]\n \n # Sort the list by length and then alphabetically\n sorted_lst = sorted(filtered_lst, key=lambda x: (len(x), x))\n \n return sorted_lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order,\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n You may assume that all words will have the same length.\n For example:\n assert list_sort([\"aa\", \"a\", \"aaa\"]) => [\"aa\"]\n assert list_sort([\"ab\", \"a\", \"aaa\", \"cd\"]) => [\"ab\", \"cd\"]\n \"\"\"\n # Filter out strings with odd lengths\n filtered_lst = [s for s in lst if len(s) % 2 == 0]\n \n # Sort the list by length and then alphabetically\n sorted_lst = sorted(filtered_lst, key=lambda x: (len(x), x))\n \n return sorted_lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"\n Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order,\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n You may assume that all words will have the same length.\n For example:\n assert list_sort([\"aa\", \"a\", \"aaa\"]) => [\"aa\"]\n assert list_sort([\"ab\", \"a\", \"aaa\", \"cd\"]) => [\"ab\", \"cd\"]\n \"\"\"\n # Filter out strings with odd lengths\n filtered_lst = [s for s in lst if len(s) % 2 == 0]\n \n # Sort the list by length and then alphabetically\n sorted_lst = sorted(filtered_lst, key=lambda x: (len(x), x))\n \n return sorted_lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n # Filter out strings with odd lengths\n filtered_lst = [s for s in lst if len(s) % 2 == 0]\n \n # Sort the list by length and then alphabetically\n sorted_lst = sorted(filtered_lst, key=lambda x: (len(x), x))\n \n return sorted_lst", "matching_cluster_idx": 3}]}, "Mbpp/3": {"dps": 97.79661016949153, "dps_norm": 98.75, "pass@1": 71.0, "profiled": [{"solution": "def is_not_prime(n):\n \"\"\"\n Determines if a number is not prime.\n A non-prime number has more than two distinct positive divisors: 1 and itself.\n \"\"\"\n if n <= 1:\n return True\n if n <= 3:\n return False\n if n % 2 == 0 or n % 3 == 0:\n return True\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return True\n i += 6\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n if n <= 1:\n return True\n if n <= 3:\n return False\n if n % 2 == 0 or n % 3 == 0:\n return True\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return True\n i += 6\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n \"\"\"\n Check if a number is not prime.\n\n Args:\n n (int): The number to check.\n\n Returns:\n bool: True if the number is not prime, False otherwise.\n \"\"\"\n if n <= 1:\n return True # 0 and 1 are not prime numbers\n if n <= 3:\n return False # 2 and 3 are prime numbers\n if n % 2 == 0 or n % 3 == 0:\n return True # Multiples of 2 and 3 are not prime\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return True\n i += 6\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n \"\"\"\n This function returns True if the number is not prime, otherwise False.\n \"\"\"\n if n <= 1:\n return True # 0 and 1 are not prime numbers\n if n <= 3:\n return False # 2 and 3 are prime numbers\n if n % 2 == 0 or n % 3 == 0:\n return True # Numbers divisible by 2 or 3 are not prime\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return True # Numbers divisible by i or i+2 are not prime\n i += 6\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n \"\"\"\n Check if a number is not prime.\n \n Parameters:\n n (int): The number to check.\n \n Returns:\n bool: True if the number is not prime, False otherwise.\n \"\"\"\n if n <= 1:\n return True # 0 and 1 are not prime numbers\n if n <= 3:\n return False # 2 and 3 are prime numbers\n \n # This is checked so that we can skip middle five numbers in below loop\n if n % 2 == 0 or n % 3 == 0:\n return True\n \n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return True\n i += 6\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n \"\"\"\n Check if a number is not prime.\n\n Args:\n n (int): The number to check.\n\n Returns:\n bool: True if the number is not prime, False otherwise.\n \"\"\"\n if n <= 1:\n return True # 0 and 1 are not prime numbers\n if n <= 3:\n return False # 2 and 3 are prime numbers\n\n # This is checked so that we can skip middle five numbers in below loop\n if n % 2 == 0 or n % 3 == 0:\n return True\n\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return True\n i += 6\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n \"\"\"\n Check if a number is not prime.\n \"\"\"\n if n <= 1:\n return True\n if n <= 3:\n return False\n if n % 2 == 0 or n % 3 == 0:\n return True\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return True\n i += 6\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n \"\"\"\n Checks if a number is not prime.\n \n Args:\n n (int): The number to check.\n \n Returns:\n bool: True if the number is not prime, False otherwise.\n \"\"\"\n if n <= 1:\n return True\n if n <= 3:\n return False\n if n % 2 == 0 or n % 3 == 0:\n return True\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return True\n i += 6\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n \"\"\"\n Returns True if the number is not prime, otherwise False.\n \"\"\"\n if n <= 1:\n return True\n if n == 2:\n return False\n if n % 2 == 0:\n return True\n for i in range(3, int(n**0.5) + 1, 2):\n if n % i == 0:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n \"\"\"\n Check if a number is not prime.\n \n Args:\n n (int): The number to check.\n \n Returns:\n bool: True if the number is not prime, False otherwise.\n \"\"\"\n if n <= 1:\n return True\n if n <= 3:\n return False\n if n % 2 == 0 or n % 3 == 0:\n return True\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return True\n i += 6\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n \"\"\"\n Check if a number is not prime.\n \n Args:\n n (int): The number to check.\n \n Returns:\n bool: True if the number is not prime, False otherwise.\n \"\"\"\n if n <= 1:\n return True\n if n <= 3:\n return False\n if n % 2 == 0 or n % 3 == 0:\n return True\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return True\n i += 6\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n \"\"\"\n Check if a number is not prime.\n \n Args:\n n (int): The number to check.\n \n Returns:\n bool: True if the number is not prime, False otherwise.\n \"\"\"\n if n <= 1:\n return True\n if n <= 3:\n return False\n if n % 2 == 0 or n % 3 == 0:\n return True\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return True\n i += 6\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n \"\"\"\n Determine if a number is not prime.\n\n A non-prime number has more than two distinct positive divisors: 1 and itself.\n \"\"\"\n if n <= 1:\n return True # 0 and 1 are not prime numbers\n if n <= 3:\n return False # 2 and 3 are prime numbers\n\n # This is to skip middle five check in below loop\n if n % 2 == 0 or n % 3 == 0:\n return True\n\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return True\n i += 6\n\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n if n <= 1:\n return True\n if n <= 3:\n return False\n if n % 2 == 0 or n % 3 == 0:\n return True\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return True\n i += 6\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n \"\"\"\n Check if a number is not prime.\n \n Parameters:\n n (int): The number to check\n \n Returns:\n bool: True if n is not prime, False otherwise\n \"\"\"\n if n <= 1:\n return True\n if n <= 3:\n return False\n if n % 2 == 0 or n % 3 == 0:\n return True\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return True\n i += 6\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n \"\"\"\n Checks if a number is not prime.\n \n A prime number is a natural number greater than 1 that has no positive divisors other than 1 and itself.\n \n :param n: int - The number to check\n :return: bool - True if n is not prime, False otherwise\n \"\"\"\n if n <= 1:\n return True # 0 and 1 are not prime numbers\n if n <= 3:\n return False # 2 and 3 are prime numbers\n \n # This is to skip middle five numbers in below loop\n if n % 2 == 0 or n % 3 == 0:\n return True\n \n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return True\n i += 6\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n \"\"\"\n Check if a number is not prime.\n\n Args:\n n (int): The number to check for primality.\n\n Returns:\n bool: True if the number is not prime, False otherwise.\n \"\"\"\n # Handle edge cases: numbers less than 2 are not prime\n if n < 2:\n return True\n # Only need to check up to the square root of n for factors\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return True\n return False", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(n):\n \"\"\"\n Check if a number is not prime.\n \n A non-prime number is defined as a number that has divisors other than 1 and itself.\n The function returns True if the number is not prime, and False otherwise.\n \"\"\"\n if n <= 1:\n return True # 0 and 1 are not prime numbers\n if n <= 3:\n return False # 2 and 3 are prime numbers\n \n # This is to skip middle five numbers in below loop\n if n % 2 == 0 or n % 3 == 0:\n return True\n \n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return True\n i += 6\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n \"\"\"\n Checks if a number is not prime.\n \n Args:\n n (int): The number to check.\n \n Returns:\n bool: True if the number is not prime, False otherwise.\n \"\"\"\n if n <= 1:\n return True\n if n <= 3:\n return False\n if n % 2 == 0 or n % 3 == 0:\n return True\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return True\n i += 6\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n \"\"\"\n This function checks if a number is not prime.\n A non-prime number has more than two distinct positive divisors: 1 and itself.\n \"\"\"\n if n <= 1:\n return True # 0 and 1 are not prime numbers\n if n <= 3:\n return False # 2 and 3 are prime numbers\n \n # This is to skip middle five numbers in below loop\n if n % 2 == 0 or n % 3 == 0:\n return True\n \n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return True\n i += 6\n return False", "matching_cluster_idx": 7}]}, "Mbpp/4": {"dps": 95.22184300341297, "dps_norm": 83.33333333333333, "pass@1": 56.0, "profiled": [{"solution": "def heap_queue_largest(numbers, n):\n if n <= 0:\n return []\n from heapq import nlargest\n largest_numbers = nlargest(n, numbers)\n return sorted(largest_numbers, reverse=True)", "matching_cluster_idx": 9}, {"solution": "def heap_queue_largest(numbers, n):\n if n <= 0:\n return []\n from heapq import nlargest\n largest_numbers = nlargest(n, numbers)\n return largest_numbers", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(numbers, n):\n if n > len(numbers):\n raise ValueError(\"n should be less than or equal to the length of the list\")\n \n # Use heapq.nlargest to find the n largest elements\n largest_n_elements = heapq.nlargest(n, numbers)\n \n # Return the result in descending order\n return sorted(largest_n_elements, reverse=True)", "matching_cluster_idx": 9}, {"solution": "def heap_queue_largest(numbers, n):\n \"\"\"\n Function to find the n largest integers from a given list of numbers, returned in descending order.\n \"\"\"\n import heapq\n if n > len(numbers):\n raise ValueError(\"n should be less than or equal to the length of the list.\")\n largest_n = heapq.nlargest(n, numbers)\n return sorted(largest_n, reverse=True)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(numbers, n):\n if n > len(numbers):\n raise ValueError(\"n should be less than or equal to the length of the list\")\n \n # Use heapq.nlargest to find the n largest elements\n largest_numbers = heapq.nlargest(n, numbers)\n \n # Sort the result in descending order\n largest_numbers.sort(reverse=True)\n \n return largest_numbers", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(numbers, n):\n if n > len(numbers):\n return []\n largest_numbers = heapq.nlargest(n, numbers)\n return largest_numbers", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(numbers, n):\n if n > len(numbers):\n raise ValueError(\"n cannot be greater than the length of the list\")\n \n # Use heapq.nlargest to get the n largest elements\n largest_n = heapq.nlargest(n, numbers)\n \n # Since heapq.nlargest returns a list, we don't need to reverse it\n # to get descending order as it is already in descending order\n return largest_n", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(numbers, n):\n # Use heapq.nlargest to find the n largest elements\n largest_numbers = heapq.nlargest(n, numbers)\n # Return the result in descending order\n return sorted(largest_numbers, reverse=True)", "matching_cluster_idx": 9}, {"solution": "def heap_queue_largest(numbers, n):\n if n == 0:\n return []\n from heapq import nlargest\n largest_numbers = nlargest(n, numbers)\n return sorted(largest_numbers, reverse=True)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(numbers, n):\n # Use heapq.nlargest to find the n largest elements\n largest_n = heapq.nlargest(n, numbers)\n # Return the result in descending order\n return largest_n", "matching_cluster_idx": 9}, {"solution": "def heap_queue_largest(numbers, n):\n if n > len(numbers):\n raise ValueError(\"n should be less than or equal to the length of the list\")\n \n # Use a min-heap to keep track of the n largest numbers\n import heapq\n heap = []\n \n for number in numbers:\n if len(heap) < n:\n heapq.heappush(heap, number)\n else:\n if number > heap[0]:\n heapq.heappop(heap)\n heapq.heappush(heap, number)\n \n # The heap contains the n largest numbers, but they are in ascending order\n # We can reverse it to get the numbers in descending order\n return sorted(heap, reverse=True)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(numbers, n):\n if n <= 0:\n return []\n if n > len(numbers):\n return sorted(numbers, reverse=True)\n \n # Use heapq.nlargest to find the n largest elements\n largest_n = heapq.nlargest(n, numbers)\n # Return the result in descending order\n return sorted(largest_n, reverse=True)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(numbers, n):\n if n <= 0:\n return []\n if n > len(numbers):\n return sorted(numbers, reverse=True)\n \n # Use heapq.nlargest to get the n largest elements\n largest_n = heapq.nlargest(n, numbers)\n return sorted(largest_n, reverse=True)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(numbers, n):\n if n > len(numbers):\n raise ValueError(\"n cannot be greater than the length of the list\")\n largest_n = heapq.nlargest(n, numbers)\n return largest_n", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(numbers, n):\n if n > len(numbers):\n raise ValueError(\"n cannot be greater than the length of the list\")\n largest = heapq.nlargest(n, numbers)\n return largest", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(numbers, n):\n if n <= 0:\n return []\n # Use heapq.nlargest to get the n largest elements\n largest_n = heapq.nlargest(n, numbers)\n return largest_n", "matching_cluster_idx": 9}, {"solution": "def heap_queue_largest(numbers, n):\n if n > len(numbers):\n raise ValueError(\"n cannot be greater than the length of the list.\")\n \n from heapq import nlargest\n \n largest_numbers = nlargest(n, numbers)\n return sorted(largest_numbers, reverse=True)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(numbers, n):\n if n <= 0:\n return []\n # Use heapq.nlargest to get the n largest elements from the list\n largest_numbers = heapq.nlargest(n, numbers)\n # Sort the result in descending order\n largest_numbers.sort(reverse=True)\n return largest_numbers", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(numbers, n):\n if n > len(numbers):\n raise ValueError(\"n cannot be greater than the length of the list.\")\n \n # Use heapq.nlargest to get the n largest elements\n largest_n = heapq.nlargest(n, numbers)\n \n # Return the result in descending order\n return sorted(largest_n, reverse=True)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(numbers, n):\n if n > len(numbers):\n raise ValueError(\"n cannot be greater than the length of the list\")\n \n # Use heapq.nlargest to get the n largest elements\n largest_n = heapq.nlargest(n, numbers)\n \n # Since heapq.nlargest returns a list, we don't need to sort it again\n return largest_n", "matching_cluster_idx": 9}]}, "Mbpp/9": {"dps": 66.83673469387755, "dps_norm": 54.5, "pass@1": 75.0, "profiled": [{"solution": "def find_Rotations(s):\n n = len(s)\n original_string = s\n s = s + s # Concatenate the string with itself to facilitate checking all rotations\n for i in range(1, n):\n if s[i:i+n] == original_string:\n return i\n return n # If no rotation matches, the string is already a single rotation", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(s):\n # The length of the string\n n = len(s)\n # Iterate through all possible rotations\n for i in range(1, n):\n # Check if the current rotation is the same as the original string\n if s == s[i:] + s[:i]:\n return i\n # If no rotation matches, the string does not rotate to itself\n return n", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(s):\n original = s\n s = s + s # Concatenate string with itself\n n = len(original)\n for i in range(1, n):\n # Check if the substring starting at index i is equal to the original string\n if s[i:i+n] == original:\n return i\n return n", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(s):\n original_string = s\n s = s + s # Concatenate the string with itself\n n = len(original_string)\n \n # Check for each rotation\n for i in range(1, n):\n # Extract string of length equal to the original string from the doubled string\n rotated_string = s[i:i+n]\n # If the rotated string matches the original string, return the rotation count\n if rotated_string == original_string:\n return i\n return n # If no rotation matches, return the length of the string", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(s):\n # The function checks all rotations from 1 to len(s) - 1 and returns the smallest number of rotations\n # that results in the original string.\n for i in range(1, len(s)):\n if s == s[i:] + s[:i]:\n return i\n return len(s)", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(s):\n \"\"\"\n Function to find the minimum number of rotations (greater than 0) required to get the same string.\n \"\"\"\n for i in range(1, len(s)):\n if s == s[i:] + s[:i]:\n return i\n return len(s)", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(s):\n # The string itself is always a rotation of itself\n n = len(s)\n # Try every rotation starting from 1 to n-1\n for i in range(1, n):\n # Check if the current rotation is the same as the original string\n if s[:i] == s[n-i:] and s[i:] == s[:n-i]:\n return i\n # If no rotation matches, return the length of the string (this case is not expected in the problem statement)\n return n", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(s):\n # The minimum number of rotations to get the same string is the length of the string\n # divided by the smallest number that divides the length of the string without a remainder\n # where the rotated string equals the original string.\n n = len(s)\n for i in range(1, n):\n if n % i == 0:\n rotated = s[i:] + s[:i]\n if rotated == s:\n return i\n return n", "matching_cluster_idx": 7}, {"solution": "def find_Rotations(s):\n n = len(s)\n for i in range(1, n):\n if s == s[i:] + s[:i]:\n return i\n return n", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(s):\n # The length of the string\n n = len(s)\n # Iterate over all possible rotations\n for i in range(1, n):\n # Check if the current rotation is the same as the original string\n if s == s[i:] + s[:i]:\n # Return the number of rotations\n return i\n # If no rotation is found, return the length of the string (which means no rotation)\n return n", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(s):\n # Check all rotations\n for i in range(1, len(s)):\n if s == s[i:] + s[:i]:\n return i\n return len(s)", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(s):\n n = len(s)\n original_string = s\n s = s + s\n for i in range(1, n):\n rotated_string = s[i:i + n]\n if rotated_string == original_string:\n return i\n return n", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(s):\n # The string will have the same substring if it is a rotation of itself\n # We check for each possible rotation if it's equal to the original string\n for i in range(1, len(s)):\n if s == s[i:] + s[:i]:\n return i\n return len(s)", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(s):\n n = len(s)\n for i in range(1, n):\n if s == s[i:] + s[:i]:\n return i\n return n", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(s):\n original_string = s\n s = s + s # Concatenate the string with itself\n n = len(original_string)\n for i in range(1, n):\n substring = s[i:i+n]\n if substring == original_string:\n return i\n return n # In case no rotation matches, return the length of the string", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(s):\n original = s\n s = s + s # Concatenate the string to itself\n n = len(original)\n for i in range(1, n):\n if s[i:i+n] == original:\n return i\n return n", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(s):\n # The string itself is always a rotation of itself\n rotations = 1\n # Start checking for rotations\n while rotations < len(s):\n # Check if the rotated string is the same as the original\n if s == s[rotations:] + s[:rotations]:\n return rotations\n rotations += 1\n # If no rotation matches, return the length of the string (not greater than 0)\n return len(s)", "matching_cluster_idx": 3}, {"solution": "def find_Rotations(s):\n n = len(s)\n for i in range(1, n):\n if s == s[i:] + s[:i]:\n return i\n return n", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(s):\n n = len(s)\n for i in range(1, n):\n if s == s[i:] + s[:i]:\n return i\n return n", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(s):\n original_str = s\n s = s + s # Concatenate the string with itself\n n = len(original_str)\n \n for i in range(1, n):\n rotated_str = s[i:i+n]\n if rotated_str == original_str:\n return i\n return n", "matching_cluster_idx": 5}]}, "Mbpp/11": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 53.0, "profiled": [{"solution": "def remove_Occ(s, c):\n if len(s) == 0 or c not in s:\n return s\n \n first_index = s.find(c)\n last_index = s.rfind(c)\n \n if first_index == -1 or last_index == -1:\n return s\n \n return s[:first_index] + s[first_index+1:last_index] + s[last_index+1:]", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(s, char):\n if char not in s:\n return s\n first_index = s.find(char)\n last_index = s.rfind(char)\n if first_index == last_index:\n return s[:first_index] + s[first_index + 1:]\n else:\n return s[:first_index] + s[first_index + 1:last_index] + s[last_index + 1:]", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(string, char):\n if char not in string:\n return string\n first_index = string.find(char)\n last_index = string.rfind(char)\n return string[:first_index] + string[first_index+1:last_index] + string[last_index+1:]", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(s, char):\n if char not in s:\n return s\n first_index = s.find(char)\n last_index = s.rfind(char)\n return s[:first_index] + s[first_index+1:last_index] + s[last_index+1:]", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(s, c):\n if len(s) == 0 or c not in s:\n return s\n \n first_index = s.find(c)\n last_index = s.rfind(c)\n \n if first_index == -1 or last_index == -1:\n return s\n \n return s[:first_index] + s[first_index + 1:last_index] + s[last_index + 1:]", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(string, char):\n if len(string) == 0 or char not in string:\n return string\n first_index = string.find(char)\n last_index = string.rfind(char)\n if first_index == last_index:\n return string.replace(char, '')\n else:\n return string[:first_index] + string[first_index+1:last_index] + string[last_index+1:]", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(string, char):\n if len(string) == 0 or char not in string:\n return string\n \n first_occurrence = string.find(char)\n last_occurrence = string.rfind(char)\n \n if first_occurrence == -1 or last_occurrence == -1:\n return string\n \n return string[:first_occurrence] + string[first_occurrence + 1:last_occurrence] + string[last_occurrence + 1:]", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(string, char):\n if char not in string:\n return string\n first_index = string.find(char)\n last_index = string.rfind(char)\n return string[:first_index] + string[first_index + 1:last_index] + string[last_index + 1:]", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(s, char):\n if char not in s:\n return s\n \n first_index = s.find(char)\n last_index = s.rfind(char)\n \n if first_index == last_index:\n return s[:first_index] + s[first_index+1:]\n \n return s[:first_index] + s[first_index+1:last_index] + s[last_index+1:]", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(s, c):\n if not s or c not in s:\n return s\n first_index = s.find(c)\n last_index = s.rfind(c)\n return s[:first_index] + s[first_index+1:last_index] + s[last_index+1:]", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(s, ch):\n if ch in s:\n first_index = s.find(ch)\n last_index = s.rfind(ch)\n return s[:first_index] + s[first_index + 1:last_index] + s[last_index + 1:]\n else:\n return s", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(s, char):\n if len(s) < 2:\n return s.replace(char, '')\n \n first_index = s.find(char)\n last_index = s.rfind(char)\n \n if first_index == -1:\n return s\n \n return s[:first_index] + s[first_index + 1:last_index] + s[last_index + 1:]", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(string, char):\n if char not in string:\n return string\n \n first_index = string.find(char)\n last_index = string.rfind(char)\n \n if first_index == last_index:\n # If the character is only present once, remove it.\n return string[:first_index] + string[first_index+1:]\n else:\n # Remove the first and last occurrence of the character.\n return string[:first_index] + string[first_index+1:last_index] + string[last_index+1:]", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(s, char):\n if char not in s:\n return s\n first_index = s.find(char)\n last_index = s.rfind(char)\n return s[:first_index] + s[first_index+1:last_index] + s[last_index+1:]", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(s, char):\n if char not in s:\n return s\n first_index = s.find(char)\n last_index = s.rfind(char)\n return s[:first_index] + s[first_index+1:last_index] + s[last_index+1:]", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(s, char):\n if char not in s:\n return s\n first_index = s.find(char)\n last_index = s.rfind(char)\n return s[:first_index] + s[first_index+1:last_index] + s[last_index+1:]", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(s, ch):\n if ch not in s:\n return s\n first_index = s.find(ch)\n last_index = s.rfind(ch)\n return s[:first_index] + s[first_index+1:last_index] + s[last_index+1:]", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(s, c):\n if c not in s:\n return s\n first_index = s.find(c)\n last_index = s.rfind(c)\n return s[:first_index] + s[first_index + 1:last_index] + s[last_index + 1:]", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(string, char):\n if not string or not char:\n return string\n \n first_occurrence = string.find(char)\n last_occurrence = string.rfind(char)\n \n if first_occurrence == -1:\n return string\n \n if first_occurrence == last_occurrence:\n return string[:first_occurrence] + string[first_occurrence + 1:]\n \n return string[:first_occurrence] + string[first_occurrence + 1:last_occurrence] + string[last_occurrence + 1:]", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(s, c):\n if c in s:\n first_index = s.find(c)\n last_index = s.rfind(c)\n return s[:first_index] + s[first_index+1:last_index] + s[last_index+1:]\n else:\n return s", "matching_cluster_idx": 8}]}, "Mbpp/12": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def sort_matrix(matrix):\n # Sort the matrix based on the sum of each row\n sorted_matrix = sorted(matrix, key=sum)\n return sorted_matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Sort the matrix rows based on the sum of the rows\n return sorted(matrix, key=sum)", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Sort the matrix based on the sum of each row\n sorted_matrix = sorted(matrix, key=lambda row: sum(row))\n return sorted_matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Sort the matrix based on the sum of the rows\n return sorted(matrix, key=sum)", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Sort the matrix based on the sum of each row\n sorted_matrix = sorted(matrix, key=lambda row: sum(row))\n return sorted_matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Sort the matrix based on the sum of the rows\n sorted_matrix = sorted(matrix, key=lambda row: sum(row))\n return sorted_matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Sort the matrix based on the sum of each row\n matrix.sort(key=lambda row: sum(row))\n return matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Sort the matrix based on the sum of the rows\n return sorted(matrix, key=lambda row: sum(row))", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Sort the matrix based on the sum of the rows\n return sorted(matrix, key=sum)", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Sort the matrix based on the sum of the rows\n matrix.sort(key=sum)\n return matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Sort the matrix based on the sum of each row\n sorted_matrix = sorted(matrix, key=lambda row: sum(row))\n return sorted_matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Sort the matrix based on the sum of the rows\n return sorted(matrix, key=lambda row: sum(row))", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Sort the matrix based on the sum of each row\n sorted_matrix = sorted(matrix, key=sum)\n return sorted_matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Sort the matrix based on the sum of the rows\n return sorted(matrix, key=sum)", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Sort the matrix based on the sum of each row\n return sorted(matrix, key=sum)", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Sort the matrix rows based on the sum of the rows\n sorted_matrix = sorted(matrix, key=sum)\n return sorted_matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Sort the matrix based on the sum of each row\n return sorted(matrix, key=lambda row: sum(row))", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Sort the matrix rows based on the sum of each row\n sorted_matrix = sorted(matrix, key=sum)\n return sorted_matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Sort the matrix based on the sum of each row\n sorted_matrix = sorted(matrix, key=lambda row: sum(row))\n return sorted_matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Sort the matrix based on the sum of the rows\n return sorted(matrix, key=lambda row: sum(row))", "matching_cluster_idx": 15}]}, "Mbpp/16": {"dps": null, "dps_norm": null, "pass@1": 8.0, "profiled": []}, "Mbpp/19": {"dps": 92.92929292929293, "dps_norm": 96.0, "pass@1": 99.0, "profiled": [{"solution": "def test_duplicate(nums):\n seen = set()\n for num in nums:\n if num in seen:\n return True\n seen.add(num)\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(nums):\n \"\"\"\n Function to check if an array contains any duplicates.\n \"\"\"\n return len(nums) != len(set(nums))", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(numbers):\n seen = set()\n for number in numbers:\n if number in seen:\n return True\n seen.add(number)\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(nums):\n return len(nums) != len(set(nums))", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(nums):\n \"\"\"\n Function to check if there are any duplicates in the list.\n Returns True if there are duplicates, False otherwise.\n \"\"\"\n return len(nums) != len(set(nums))", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(nums):\n \"\"\"\n Function to find whether a given array of integers contains any duplicate element.\n \"\"\"\n seen = set()\n for num in nums:\n if num in seen:\n return True\n seen.add(num)\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(nums):\n return len(nums) != len(set(nums))", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(numbers):\n seen = set()\n for number in numbers:\n if number in seen:\n return True\n seen.add(number)\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(nums):\n \"\"\"\n Function to find whether a given array of integers contains any duplicate element.\n \"\"\"\n seen = set()\n for num in nums:\n if num in seen:\n return True\n seen.add(num)\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(nums):\n seen = set()\n for num in nums:\n if num in seen:\n return True\n seen.add(num)\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(numbers):\n seen = set()\n for number in numbers:\n if number in seen:\n return True\n seen.add(number)\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(nums):\n seen = set()\n for num in nums:\n if num in seen:\n return True\n seen.add(num)\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(nums):\n seen = set()\n for num in nums:\n if num in seen:\n return True\n seen.add(num)\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(numbers):\n seen = set()\n for number in numbers:\n if number in seen:\n return True\n seen.add(number)\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(nums):\n seen = set()\n for num in nums:\n if num in seen:\n return True\n seen.add(num)\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(numbers):\n seen = set()\n for number in numbers:\n if number in seen:\n return True\n seen.add(number)\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(numbers):\n seen = set()\n for number in numbers:\n if number in seen:\n return True\n seen.add(number)\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(arr):\n seen = set()\n for num in arr:\n if num in seen:\n return True\n seen.add(num)\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(nums):\n seen = set()\n for num in nums:\n if num in seen:\n return True\n seen.add(num)\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(nums):\n seen = set()\n for num in nums:\n if num in seen:\n return True\n seen.add(num)\n return False", "matching_cluster_idx": 14}]}, "Mbpp/62": {"dps": 98.5, "dps_norm": 99.0, "pass@1": 100.0, "profiled": [{"solution": "def smallest_num(numbers):\n return min(numbers)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(numbers):\n return min(numbers)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(numbers):\n return min(numbers)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(numbers):\n if not numbers: # Check if the list is empty\n raise ValueError(\"The list is empty\")\n return min(numbers)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(numbers):\n return min(numbers)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(numbers):\n if not numbers:\n raise ValueError(\"The list is empty\")\n smallest = numbers[0]\n for num in numbers:\n if num < smallest:\n smallest = num\n return smallest", "matching_cluster_idx": 3}, {"solution": "def smallest_num(numbers):\n return min(numbers)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(numbers):\n return min(numbers)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(numbers):\n return min(numbers)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(numbers):\n return min(numbers)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(numbers):\n \"\"\"\n This function finds and returns the smallest number in a list.\n \"\"\"\n return min(numbers)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(numbers):\n return min(numbers)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(numbers):\n \"\"\"\n Returns the smallest number in a list.\n \"\"\"\n return min(numbers)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(numbers):\n if not numbers: # Check if the list is empty\n raise ValueError(\"The list is empty\")\n return min(numbers)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(numbers):\n return min(numbers)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(numbers):\n \"\"\"\n This function returns the smallest number in a list.\n \"\"\"\n if not numbers:\n raise ValueError(\"The list is empty\")\n return min(numbers)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(numbers):\n if not numbers:\n raise ValueError(\"The list is empty\")\n return min(numbers)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(numbers):\n return min(numbers)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(numbers):\n return min(numbers)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(numbers):\n return min(numbers)", "matching_cluster_idx": 4}]}, "Mbpp/75": {"dps": 92.85714285714286, "dps_norm": 66.66666666666667, "pass@1": 100.0, "profiled": [{"solution": "def find_tuples(tuples_list, k):\n result = []\n for tup in tuples_list:\n if all(x % k == 0 for x in tup):\n result.append(tup)\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n result = []\n for t in tuples_list:\n if all(x % k == 0 for x in t):\n result.append(t)\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n \"\"\"\n This function takes a list of tuples and an integer k, and returns a list of tuples\n where all elements are divisible by k.\n \"\"\"\n result = []\n for t in tuples_list:\n if all(x % k == 0 for x in t):\n result.append(t)\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n result = []\n for t in tuples_list:\n if all(x % k == 0 for x in t):\n result.append(t)\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n result = []\n for t in tuples_list:\n if all(x % k == 0 for x in t):\n result.append(t)\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n result = []\n for t in tuples_list:\n if all(x % k == 0 for x in t):\n result.append(t)\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n def is_divisible_by_k(tup):\n return all(x % k == 0 for x in tup)\n \n return [tup for tup in tuples_list if is_divisible_by_k(tup)]", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n result = []\n for t in tuples_list:\n if all(x % k == 0 for x in t):\n result.append(t)\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n def divisible_by_k(tup):\n return all(x % k == 0 for x in tup)\n\n return [tup for tup in tuples_list if divisible_by_k(tup)]", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n result = []\n for t in tuples_list:\n if all(x % k == 0 for x in t):\n result.append(t)\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n result = []\n for tup in tuples_list:\n if all(x % k == 0 for x in tup):\n result.append(tup)\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n \"\"\"\n Find tuples which have all elements divisible by k from the given list of tuples.\n \n :param tuples_list: List of tuples containing integers\n :param k: Integer divisor\n :return: List of tuples where all elements are divisible by k\n \"\"\"\n result = []\n for tup in tuples_list:\n if all(elem % k == 0 for elem in tup):\n result.append(tup)\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n \"\"\"\n Finds tuples where all elements are divisible by k.\n \n :param tuples_list: List of tuples\n :param k: Integer divisor\n :return: List of tuples where all elements are divisible by k\n \"\"\"\n result = []\n for t in tuples_list:\n if all(x % k == 0 for x in t):\n result.append(t)\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n result = []\n for tup in tuples_list:\n if all(element % k == 0 for element in tup):\n result.append(tup)\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n result = []\n for tup in tuples_list:\n if all(elem % k == 0 for elem in tup):\n result.append(tup)\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n result = []\n for t in tuples_list:\n if all(x % k == 0 for x in t):\n result.append(t)\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n result = []\n for t in tuples_list:\n if all(x % k == 0 for x in t):\n result.append(t)\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n result = []\n for t in tuples_list:\n if all(x % k == 0 for x in t):\n result.append(t)\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n result = []\n for t in tuples_list:\n if all(x % k == 0 for x in t):\n result.append(t)\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n result = []\n for t in tuples_list:\n if all(x % k == 0 for x in t):\n result.append(t)\n return result", "matching_cluster_idx": 5}]}, "Mbpp/88": {"dps": 96.56862745098039, "dps_norm": 85.71428571428571, "pass@1": 100.0, "profiled": [{"solution": "def freq_count(lst):\n frequency_dict = {}\n for element in lst:\n if element in frequency_dict:\n frequency_dict[element] += 1\n else:\n frequency_dict[element] = 1\n return frequency_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n frequency = {}\n for item in lst:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n return frequency", "matching_cluster_idx": 5}, {"solution": "def freq_count(numbers):\n frequency_dict = {}\n for number in numbers:\n if number in frequency_dict:\n frequency_dict[number] += 1\n else:\n frequency_dict[number] = 1\n return frequency_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(numbers):\n frequency_dict = {}\n for number in numbers:\n if number in frequency_dict:\n frequency_dict[number] += 1\n else:\n frequency_dict[number] = 1\n return frequency_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(numbers):\n frequency = {}\n for number in numbers:\n if number in frequency:\n frequency[number] += 1\n else:\n frequency[number] = 1\n return frequency", "matching_cluster_idx": 5}, {"solution": "def freq_count(numbers):\n frequency_dict = {}\n for num in numbers:\n if num in frequency_dict:\n frequency_dict[num] += 1\n else:\n frequency_dict[num] = 1\n return frequency_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(numbers):\n frequency_dict = {}\n for number in numbers:\n if number in frequency_dict:\n frequency_dict[number] += 1\n else:\n frequency_dict[number] = 1\n return frequency_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n freq_dict = {}\n for item in lst:\n if item in freq_dict:\n freq_dict[item] += 1\n else:\n freq_dict[item] = 1\n return freq_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n frequency_dict = {}\n for item in lst:\n if item in frequency_dict:\n frequency_dict[item] += 1\n else:\n frequency_dict[item] = 1\n return frequency_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(numbers):\n frequency = {}\n for number in numbers:\n if number in frequency:\n frequency[number] += 1\n else:\n frequency[number] = 1\n return frequency", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n frequency = {}\n for item in lst:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n return frequency", "matching_cluster_idx": 5}, {"solution": "def freq_count(numbers):\n frequency_dict = {}\n for number in numbers:\n if number in frequency_dict:\n frequency_dict[number] += 1\n else:\n frequency_dict[number] = 1\n return frequency_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(numbers):\n frequency_dict = {}\n for number in numbers:\n if number in frequency_dict:\n frequency_dict[number] += 1\n else:\n frequency_dict[number] = 1\n return frequency_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n frequency_dict = {}\n for item in lst:\n if item in frequency_dict:\n frequency_dict[item] += 1\n else:\n frequency_dict[item] = 1\n return frequency_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(numbers):\n frequency_dict = {}\n for number in numbers:\n if number in frequency_dict:\n frequency_dict[number] += 1\n else:\n frequency_dict[number] = 1\n return frequency_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(numbers):\n frequency_dict = {}\n for number in numbers:\n if number in frequency_dict:\n frequency_dict[number] += 1\n else:\n frequency_dict[number] = 1\n return frequency_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n freq_dict = {}\n for item in lst:\n if item in freq_dict:\n freq_dict[item] += 1\n else:\n freq_dict[item] = 1\n return freq_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n frequency_dict = {}\n for element in lst:\n if element in frequency_dict:\n frequency_dict[element] += 1\n else:\n frequency_dict[element] = 1\n return frequency_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n frequency_dict = {}\n for item in lst:\n if item in frequency_dict:\n frequency_dict[item] += 1\n else:\n frequency_dict[item] = 1\n return frequency_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n frequency_dict = {}\n for item in lst:\n if item in frequency_dict:\n frequency_dict[item] += 1\n else:\n frequency_dict[item] = 1\n return frequency_dict", "matching_cluster_idx": 5}]}, "Mbpp/90": {"dps": 77.75609756097562, "dps_norm": 85.71428571428571, "pass@1": 100.0, "profiled": [{"solution": "def len_log(words):\n if not words: # Check if the list is empty\n return 0\n longest_word = max(words, key=len) # Find the longest word using the `max` function with `key=len`\n return len(longest_word) # Return the length of the longest word", "matching_cluster_idx": 6}, {"solution": "def len_log(words):\n max_length = 0\n for word in words:\n if len(word) > max_length:\n max_length = len(word)\n return max_length", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n max_length = 0\n for word in words:\n if len(word) > max_length:\n max_length = len(word)\n return max_length", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n max_length = 0\n for word in words:\n if len(word) > max_length:\n max_length = len(word)\n return max_length", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n longest_word_length = 0\n for word in words:\n if len(word) > longest_word_length:\n longest_word_length = len(word)\n return longest_word_length", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n longest = \"\"\n for word in words:\n if len(word) > len(longest):\n longest = word\n return len(longest)", "matching_cluster_idx": 4}, {"solution": "def len_log(words):\n max_length = 0\n for word in words:\n if len(word) > max_length:\n max_length = len(word)\n return max_length", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n if not words:\n return 0\n longest_word_length = len(words[0])\n for word in words:\n if len(word) > longest_word_length:\n longest_word_length = len(word)\n return longest_word_length", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n if not words:\n return 0\n longest_length = max(len(word) for word in words)\n return longest_length", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n max_length = 0\n for word in words:\n if len(word) > max_length:\n max_length = len(word)\n return max_length", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n longest = 0\n for word in words:\n if len(word) > longest:\n longest = len(word)\n return longest", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n max_length = 0\n for word in words:\n if len(word) > max_length:\n max_length = len(word)\n return max_length", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n if not words:\n return 0\n return max(len(word) for word in words)", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n max_length = 0\n for word in words:\n if len(word) > max_length:\n max_length = len(word)\n return max_length", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n # Initialize the maximum length of a word\n max_length = 0\n \n # Iterate through each word in the list\n for word in words:\n # Update the maximum length if the current word's length is greater\n if len(word) > max_length:\n max_length = len(word)\n \n return max_length", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n max_length = 0\n for word in words:\n if len(word) > max_length:\n max_length = len(word)\n return max_length", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n max_length = 0\n for word in words:\n if len(word) > max_length:\n max_length = len(word)\n return max_length", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n if not words:\n return 0\n max_length = len(words[0])\n for word in words:\n if len(word) > max_length:\n max_length = len(word)\n return max_length", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n max_length = 0\n for word in words:\n if len(word) > max_length:\n max_length = len(word)\n return max_length", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n max_length = 0\n for word in words:\n if len(word) > max_length:\n max_length = len(word)\n return max_length", "matching_cluster_idx": 5}]}, "Mbpp/94": {"dps": 80.2439024390244, "dps_norm": 64.0, "pass@1": 68.0, "profiled": [{"solution": "def index_minimum(tuples_list):\n # Initialize variables to store the smallest tuple and its index\n smallest_tuple = None\n smallest_value = float('inf')\n \n # Iterate over the list of tuples\n for item in tuples_list:\n # Check if the current tuple's second value is smaller than the smallest found so far\n if item[1] < smallest_value:\n smallest_value = item[1]\n smallest_tuple = item\n \n # Return the first value of the tuple with the smallest second value\n return smallest_tuple[0]", "matching_cluster_idx": 4}, {"solution": "def index_minimum(tuples_list):\n # Use the min function with a key to find the tuple with the smallest second value\n # Then return the first value of that tuple\n return min(tuples_list, key=lambda x: x[1])[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(tuples_list):\n # Find the tuple with the smallest second value\n min_tuple = min(tuples_list, key=lambda x: x[1])\n # Return the first value of the tuple with the smallest second value\n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(lst):\n # Find the tuple with the smallest second value\n min_tuple = min(lst, key=lambda x: x[1])\n # Return the first value of that tuple\n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(lst):\n # Find the tuple with the smallest second value\n min_tuple = min(lst, key=lambda x: x[1])\n # Return the first value of the tuple with the smallest second value\n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(tuples_list):\n # Find the tuple with the smallest second value\n min_tuple = min(tuples_list, key=lambda x: x[1])\n # Return the first value of the tuple with the smallest second value\n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(tuples_list):\n # Use the min function with a key to find the tuple with the smallest second value\n return min(tuples_list, key=lambda x: x[1])[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(tuples_list):\n # Use the min function with a key to find the tuple with the smallest second value\n # Then return the first value of that tuple\n return min(tuples_list, key=lambda x: x[1])[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(tuples_list):\n # Find the tuple with the smallest second value\n min_tuple = min(tuples_list, key=lambda x: x[1])\n # Return the first value of the tuple with the smallest second value\n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(tuples_list):\n # Find the tuple with the smallest second value\n min_tuple = min(tuples_list, key=lambda x: x[1])\n # Return the first value of the tuple with the smallest second value\n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(tuples_list):\n # Find the tuple with the smallest second value\n min_tuple = min(tuples_list, key=lambda x: x[1])\n # Return the first value of the tuple with the smallest second value\n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(tuples_list):\n # Find the tuple with the smallest second value\n min_tuple = min(tuples_list, key=lambda x: x[1])\n # Return the first value of the tuple with the smallest second value\n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(tuples_list):\n # Find the tuple with the smallest second value\n min_tuple = min(tuples_list, key=lambda x: x[1])\n # Return the first value of the tuple with the smallest second value\n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(tuples_list):\n # Find the tuple with the smallest second value\n min_tuple = min(tuples_list, key=lambda x: x[1])\n # Return the first value of that tuple\n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(tuples_list):\n return min(tuples_list, key=lambda x: x[1])[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(tuples_list):\n # Find the tuple with the smallest second value\n min_tuple = min(tuples_list, key=lambda x: x[1])\n # Return the first value of the tuple with the smallest second value\n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(tuples_list):\n # Find the tuple with the smallest second value\n min_tuple = min(tuples_list, key=lambda x: x[1])\n # Return the first value of that tuple\n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(tuples_list):\n # Find the tuple with the smallest second value\n min_tuple = min(tuples_list, key=lambda x: x[1])\n # Return the first value of that tuple\n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(tuples_list):\n # Initialize the minimum value to a large number\n min_value = float('inf')\n # Initialize the result to an empty string\n result = \"\"\n \n # Iterate through each tuple in the list\n for item in tuples_list:\n # Check if the current tuple's second value is less than the current min_value\n if item[1] < min_value:\n # Update the min_value and result with the current tuple's second value and first value\n min_value = item[1]\n result = item[0]\n \n # Return the first value of the tuple with the smallest second value\n return result", "matching_cluster_idx": 4}, {"solution": "def index_minimum(tuples_list):\n # Find the tuple with the smallest second value\n min_tuple = min(tuples_list, key=lambda x: x[1])\n # Return the first value of the tuple with the smallest second value\n return min_tuple[0]", "matching_cluster_idx": 2}]}, "Mbpp/96": {"dps": 97.49999999999999, "dps_norm": 97.85714285714286, "pass@1": 94.0, "profiled": [{"solution": "def divisor(n):\n if n <= 0:\n return 0\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n count += 1\n if i != n // i:\n count += 1\n return count", "matching_cluster_idx": 6}, {"solution": "def divisor(n):\n \"\"\"\n This function calculates the number of divisors of a given integer n.\n \"\"\"\n if n <= 0:\n raise ValueError(\"Input must be a positive integer.\")\n \n divisors_count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n divisors_count += 1\n if i != n // i:\n divisors_count += 1\n \n return divisors_count", "matching_cluster_idx": 5}, {"solution": "def divisor(n):\n \"\"\"\n Function to find the number of divisors of a given integer.\n \"\"\"\n if n <= 0:\n return 0 # There are no divisors for non-positive integers\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n count += 1\n if i != n // i:\n count += 1\n return count", "matching_cluster_idx": 6}, {"solution": "def divisor(n):\n \"\"\"\n Function to find the number of divisors of a given integer.\n \"\"\"\n if n <= 0:\n raise ValueError(\"Input must be a positive integer\")\n \n divisors_count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n divisors_count += 1\n if i != n // i:\n divisors_count += 1\n return divisors_count", "matching_cluster_idx": 5}, {"solution": "def divisor(n):\n \"\"\"\n This function returns the number of divisors of a given integer.\n \"\"\"\n if n < 1:\n return 0\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n count += 1\n if i != n // i:\n count += 1\n return count", "matching_cluster_idx": 6}, {"solution": "def divisor(n):\n \"\"\"\n This function calculates the number of divisors of a given integer n.\n \"\"\"\n if n <= 0:\n return 0\n \n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n count += 1\n if i != n // i:\n count += 1\n return count", "matching_cluster_idx": 6}, {"solution": "def divisor(n):\n \"\"\"\n Calculate the number of divisors of a given integer n.\n \"\"\"\n if n <= 0:\n raise ValueError(\"Input must be a positive integer.\")\n \n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n count += 1\n if i != n // i:\n count += 1\n return count", "matching_cluster_idx": 6}, {"solution": "def divisor(n):\n if n < 1:\n return 0\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n count += 1\n if i != n // i:\n count += 1\n return count", "matching_cluster_idx": 6}, {"solution": "def divisor(n):\n \"\"\"\n Function to find the number of divisors of a given integer.\n \"\"\"\n if n <= 0:\n raise ValueError(\"Input must be a positive integer.\")\n \n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n count += 1\n if i != n // i:\n count += 1\n return count", "matching_cluster_idx": 6}, {"solution": "def divisor(n):\n \"\"\"\n This function returns the number of divisors of a given integer n.\n \"\"\"\n if n <= 0:\n return 0 # No divisors for non-positive numbers\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n count += 1\n if i != n // i:\n count += 1\n return count", "matching_cluster_idx": 6}, {"solution": "def divisor(n):\n if n < 1:\n return 0 # No divisors for negative numbers or zero\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n count += 1\n if i != n // i:\n count += 1\n return count", "matching_cluster_idx": 6}, {"solution": "def divisor(n):\n if n < 1:\n return 0\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n count += 1\n if i != n // i:\n count += 1\n return count", "matching_cluster_idx": 6}, {"solution": "def divisor(n):\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n count += 1\n if i != n // i:\n count += 1\n return count", "matching_cluster_idx": 6}, {"solution": "def divisor(n):\n \"\"\"\n This function finds the number of divisors of a given integer.\n \"\"\"\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n count += 1\n if i != n // i:\n count += 1\n return count", "matching_cluster_idx": 6}, {"solution": "def divisor(n):\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n count += 1\n if i != n // i:\n count += 1\n return count", "matching_cluster_idx": 6}, {"solution": "def divisor(n):\n \"\"\"\n Function to find the number of divisors of a given integer.\n \"\"\"\n if n <= 0:\n raise ValueError(\"Input must be a positive integer.\")\n \n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n count += 1\n if i != n // i:\n count += 1\n return count", "matching_cluster_idx": 6}, {"solution": "def divisor(n):\n if n <= 0:\n raise ValueError(\"Input must be a positive integer.\")\n divisors_count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n divisors_count += 1\n if i != n // i:\n divisors_count += 1\n return divisors_count", "matching_cluster_idx": 6}, {"solution": "def divisor(n):\n \"\"\"\n This function calculates the number of divisors of a given integer n.\n \"\"\"\n if n <= 0:\n raise ValueError(\"Input must be a positive integer.\")\n \n divisors_count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n divisors_count += 1\n if i != n // i:\n divisors_count += 1\n return divisors_count", "matching_cluster_idx": 6}, {"solution": "def divisor(n):\n if n <= 0:\n return 0 # There are no divisors for non-positive integers\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n count += 1\n if i != n // i:\n count += 1\n return count", "matching_cluster_idx": 5}, {"solution": "def divisor(n):\n \"\"\"\n Function to find the number of divisors of a given integer.\n \"\"\"\n if n <= 0:\n raise ValueError(\"Input must be a positive integer.\")\n divisors_count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n divisors_count += 1\n if i != n // i:\n divisors_count += 1\n return divisors_count", "matching_cluster_idx": 6}]}, "Mbpp/97": {"dps": 99.67521367521368, "dps_norm": 88.125, "pass@1": 100.0, "profiled": [{"solution": "def frequency_lists(list_of_lists):\n frequency_dict = {}\n for sublist in list_of_lists:\n for element in sublist:\n if element in frequency_dict:\n frequency_dict[element] += 1\n else:\n frequency_dict[element] = 1\n return frequency_dict", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(list_of_lists):\n frequency_dict = {}\n for sublist in list_of_lists:\n for element in sublist:\n if element in frequency_dict:\n frequency_dict[element] += 1\n else:\n frequency_dict[element] = 1\n return frequency_dict", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lists):\n flat_list = [item for sublist in lists for item in sublist]\n frequency = {}\n for item in flat_list:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n return frequency", "matching_cluster_idx": 6}, {"solution": "from collections import Counter\nfrom itertools import chain\ndef frequency_lists(lst_of_lsts):\n flattened_list = list(chain.from_iterable(lst_of_lsts))\n frequency_dict = dict(Counter(flattened_list))\n return frequency_dict", "matching_cluster_idx": 7}, {"solution": "from collections import Counter\ndef frequency_lists(list_of_lists):\n # Flatten the list of lists\n flattened_list = [item for sublist in list_of_lists for item in sublist]\n # Count the frequency of each element\n frequency_dict = dict(Counter(flattened_list))\n return frequency_dict", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(list_of_lists):\n frequency_dict = {}\n for sublist in list_of_lists:\n for element in sublist:\n if element in frequency_dict:\n frequency_dict[element] += 1\n else:\n frequency_dict[element] = 1\n return frequency_dict", "matching_cluster_idx": 6}, {"solution": "from collections import Counter\ndef frequency_lists(lists):\n # Flatten the list of lists\n flattened_list = [item for sublist in lists for item in sublist]\n # Count the frequency of each element\n frequency_dict = dict(Counter(flattened_list))\n return frequency_dict", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(list_of_lists):\n frequency_dict = {}\n for sublist in list_of_lists:\n for element in sublist:\n if element in frequency_dict:\n frequency_dict[element] += 1\n else:\n frequency_dict[element] = 1\n return frequency_dict", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(list_of_lists):\n flat_list = [item for sublist in list_of_lists for item in sublist]\n frequency_dict = {}\n for item in flat_list:\n if item in frequency_dict:\n frequency_dict[item] += 1\n else:\n frequency_dict[item] = 1\n return frequency_dict", "matching_cluster_idx": 6}, {"solution": "from collections import Counter\ndef frequency_lists(list_of_lists):\n # Flatten the list of lists\n flattened_list = [item for sublist in list_of_lists for item in sublist]\n # Count the frequency of each element\n frequency_dict = Counter(flattened_list)\n return dict(frequency_dict)", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(list_of_lists):\n frequency_dict = {}\n for sublist in list_of_lists:\n for element in sublist:\n if element in frequency_dict:\n frequency_dict[element] += 1\n else:\n frequency_dict[element] = 1\n return frequency_dict", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lists):\n from collections import Counter\n # Flatten the list of lists\n flat_list = [item for sublist in lists for item in sublist]\n # Count the frequency of each element\n frequency_dict = dict(Counter(flat_list))\n return frequency_dict", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(list_of_lists):\n flattened_list = [item for sublist in list_of_lists for item in sublist]\n frequency = {}\n for item in flattened_list:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n return frequency", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lists):\n frequency_dict = {}\n for sublist in lists:\n for element in sublist:\n if element in frequency_dict:\n frequency_dict[element] += 1\n else:\n frequency_dict[element] = 1\n return frequency_dict", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lists):\n flat_list = [item for sublist in lists for item in sublist]\n frequency_dict = {}\n for item in flat_list:\n if item in frequency_dict:\n frequency_dict[item] += 1\n else:\n frequency_dict[item] = 1\n return frequency_dict", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(list_of_lists):\n flat_list = [item for sublist in list_of_lists for item in sublist]\n frequency_dict = {}\n for item in flat_list:\n if item in frequency_dict:\n frequency_dict[item] += 1\n else:\n frequency_dict[item] = 1\n return frequency_dict", "matching_cluster_idx": 6}, {"solution": "from collections import defaultdict\nfrom itertools import chain\ndef frequency_lists(list_of_lists):\n frequency_dict = defaultdict(int)\n for element in chain.from_iterable(list_of_lists):\n frequency_dict[element] += 1\n return dict(frequency_dict)", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(list_of_lists):\n frequency_dict = {}\n flattened_list = [item for sublist in list_of_lists for item in sublist]\n for item in flattened_list:\n if item in frequency_dict:\n frequency_dict[item] += 1\n else:\n frequency_dict[item] = 1\n return frequency_dict", "matching_cluster_idx": 6}, {"solution": "from collections import Counter\ndef frequency_lists(list_of_lists):\n flattened_list = [item for sublist in list_of_lists for item in sublist]\n frequency_dict = dict(Counter(flattened_list))\n return frequency_dict", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(list_of_lists):\n from collections import defaultdict\n \n frequency_dict = defaultdict(int)\n \n # Flatten the list of lists\n flattened_list = [item for sublist in list_of_lists for item in sublist]\n \n # Count the frequency of each element\n for item in flattened_list:\n frequency_dict[item] += 1\n \n return dict(frequency_dict)", "matching_cluster_idx": 6}]}, "Mbpp/106": {"dps": 75.84415584415585, "dps_norm": 93.33333333333333, "pass@1": 100.0, "profiled": [{"solution": "def add_lists(lst, tup):\n return tup + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tup):\n return tup + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tup):\n return tup + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tpl):\n return tpl + tuple(lst)", "matching_cluster_idx": 4}, {"solution": "def add_lists(lst, tpl):\n return tpl + tuple(lst)", "matching_cluster_idx": 4}, {"solution": "def add_lists(lst, tup):\n return tup + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tp):\n return tp + tuple(lst)", "matching_cluster_idx": 4}, {"solution": "def add_lists(lst, tup):\n return tup + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tpl):\n \"\"\"\n Appends the given list to the given tuple.\n \n Parameters:\n lst (list): The list to append.\n tpl (tuple): The tuple to which the list will be appended.\n \n Returns:\n tuple: A new tuple containing the elements of the original tuple followed by the elements of the list.\n \"\"\"\n return tpl + tuple(lst)", "matching_cluster_idx": 4}, {"solution": "def add_lists(lst, tup):\n return tup + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tpl):\n return tpl + tuple(lst)", "matching_cluster_idx": 4}, {"solution": "def add_lists(lst, tup):\n return tup + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tp):\n return tp + tuple(lst)", "matching_cluster_idx": 4}, {"solution": "def add_lists(lst, tpl):\n \"\"\"\n Appends the given list to the given tuple.\n \"\"\"\n return tpl + tuple(lst)", "matching_cluster_idx": 4}, {"solution": "def add_lists(lst, tup):\n return tup + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tpl):\n return tpl + tuple(lst)", "matching_cluster_idx": 4}, {"solution": "def add_lists(lst, tup):\n return tup + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tup):\n return tup + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tup):\n return tup + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tup):\n return tup + tuple(lst)", "matching_cluster_idx": 5}]}, "Mbpp/108": {"dps": 96.02409638554217, "dps_norm": 99.54545454545455, "pass@1": 50.0, "profiled": [{"solution": "def merge_sorted_list(list1, list2, list3):\n # Merge the three lists\n merged_list = list1 + list2 + list3\n # Sort the merged list\n merged_list.sort()\n return merged_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Merge the lists\n merged_list = sorted(list1 + list2 + list3)\n return merged_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Merge the three lists\n merged_list = list1 + list2 + list3\n # Sort the merged list\n merged_list.sort()\n return merged_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Merge all lists into one\n merged_list = list1 + list2 + list3\n # Sort the merged list\n merged_list.sort()\n return merged_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(*lists):\n merged_list = []\n for lst in lists:\n merged_list.extend(lst)\n merged_list.sort()\n return merged_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Merge the three lists\n merged_list = list1 + list2 + list3\n # Sort the merged list\n merged_list.sort()\n return merged_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Merge the three lists\n merged_list = list1 + list2 + list3\n # Sort the merged list\n merged_list.sort()\n return merged_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(*lists):\n # Flatten the list of lists and sort the combined list\n combined_list = []\n for lst in lists:\n combined_list.extend(lst)\n return sorted(combined_list)", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Merge the lists into one\n merged_list = list1 + list2 + list3\n # Sort the merged list\n merged_list.sort()\n return merged_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(*lists):\n # Flatten the lists into one single list\n merged_list = []\n for lst in lists:\n merged_list.extend(lst)\n \n # Sort the merged list\n merged_list.sort()\n return merged_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Merge the lists\n merged_list = list1 + list2 + list3\n # Sort the merged list\n merged_list.sort()\n return merged_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(*lists):\n # Flatten the list of lists and convert to a single list\n flat_list = [item for sublist in lists for item in sublist]\n # Sort the flattened list\n flat_list.sort()\n return flat_list", "matching_cluster_idx": 9}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Merge the lists\n merged_list = sorted(list1 + list2 + list3)\n return merged_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Merge the lists\n merged_list = list1 + list2 + list3\n # Sort the merged list\n merged_list.sort()\n return merged_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Merge all three lists into one\n merged_list = list1 + list2 + list3\n # Sort the merged list\n merged_list.sort()\n return merged_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(*lists):\n # Flatten the list of lists and convert it to a single list\n merged_list = []\n for lst in lists:\n merged_list.extend(lst)\n \n # Sort the merged list\n merged_list.sort()\n return merged_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Merge the lists\n merged_list = sorted(list1 + list2 + list3)\n return merged_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Merge the lists\n merged_list = list1 + list2 + list3\n # Sort the merged list\n merged_list.sort()\n return merged_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Merge the three lists\n merged_list = list1 + list2 + list3\n # Sort the merged list\n merged_list.sort()\n return merged_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(*lists):\n merged_list = []\n for lst in lists:\n merged_list.extend(lst)\n merged_list.sort()\n return merged_list", "matching_cluster_idx": 10}]}, "Mbpp/111": {"dps": 77.95384615384616, "dps_norm": 81.875, "pass@1": 62.0, "profiled": [{"solution": "def common_in_nested_lists(lists):\n if not lists:\n return []\n common_elements = set(lists[0])\n for lst in lists[1:]:\n common_elements.intersection_update(lst)\n return list(common_elements)", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(lists):\n # Convert the first list to a set for efficient comparison\n common_set = set(lists[0])\n \n # Iterate over the rest of the lists and update the common_set\n for lst in lists[1:]:\n common_set.intersection_update(lst)\n \n # Return the common elements as a sorted list (though sets are unordered, this is for consistency with the assertion)\n return sorted(common_set)", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(lists):\n # Convert the first list to a set for efficient comparison\n common_set = set(lists[0])\n \n # Iterate over the rest of the lists and update the common_set\n for lst in lists[1:]:\n common_set.intersection_update(lst)\n \n return common_set", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(lists):\n if not lists:\n return set()\n \n # Convert the first list to a set for efficient comparison\n common_set = set(lists[0])\n \n # Iterate over the remaining lists and update the common set\n for lst in lists[1:]:\n common_set.intersection_update(lst)\n \n return common_set", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(lists):\n # Flatten the nested lists into a single list\n flattened_list = [item for sublist in lists for item in sublist]\n \n # Create a set of the first list for comparison\n common_elements = set(lists[0])\n \n # Iterate over the remaining lists and update the common elements\n for lst in lists[1:]:\n common_elements.intersection_update(lst)\n \n return common_elements", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef common_in_nested_lists(lists: List[List[int]]) -> List[int]:\n # Convert the first list to a set for efficient comparison\n common_set = set(lists[0])\n \n # Iterate over the remaining lists\n for lst in lists[1:]:\n # Update the common_set with the intersection of the current set and the next list\n common_set.intersection_update(lst)\n \n # Convert the result back to a list before returning\n return list(common_set)", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n if not nested_lists:\n return set()\n \n # Convert the first list to a set for comparison\n common_set = set(nested_lists[0])\n \n # Iterate over the rest of the lists and update the common_set with intersection\n for lst in nested_lists[1:]:\n common_set.intersection_update(lst)\n \n return common_set", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(lists):\n # Convert all lists to sets to remove duplicates and allow for set operations\n sets = [set(lst) for lst in lists]\n \n # Use intersection to find common elements across all sets\n common_elements = set.intersection(*sets)\n \n return common_elements", "matching_cluster_idx": 5}, {"solution": "def common_in_nested_lists(lists):\n # Convert the first list to a set for initial comparison\n common_set = set(lists[0])\n \n # Iterate over the rest of the lists and update the common_set\n for lst in lists[1:]:\n common_set.intersection_update(lst)\n \n return common_set", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(lists):\n # Convert the first list to a set for fast lookup\n common_set = set(lists[0])\n \n # Iterate over the remaining lists and update the common_set with intersection\n for lst in lists[1:]:\n common_set.intersection_update(lst)\n \n return common_set", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(lists):\n # Convert the first list to a set for initial comparison\n common_set = set(lists[0])\n \n # Iterate over the rest of the lists\n for lst in lists[1:]:\n # Update the common_set to include only elements that are also in the current list\n common_set.intersection_update(lst)\n \n return common_set", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef common_in_nested_lists(nested_lists: List[List[int]]) -> List[int]:\n if not nested_lists:\n return []\n \n # Initialize the common set with the first list\n common_set = set(nested_lists[0])\n \n # Iterate over the remaining lists\n for lst in nested_lists[1:]:\n # Update the common set with the intersection of the current common set and the current list\n common_set.intersection_update(lst)\n \n # Return the sorted list of common elements\n return sorted(list(common_set))", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(lists):\n if not lists:\n return set()\n \n # Convert the first list to a set for efficient comparison\n common_set = set(lists[0])\n \n # Iterate over the remaining lists and update the common_set\n for lst in lists[1:]:\n common_set.intersection_update(lst)\n \n return common_set", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(lists):\n # Convert all lists to sets to remove duplicates within each list and enable set operations\n sets = [set(lst) for lst in lists]\n \n # Find the intersection of all sets to get the common elements\n common_elements = set.intersection(*sets)\n \n return common_elements", "matching_cluster_idx": 5}, {"solution": "def common_in_nested_lists(nested_lists):\n if not nested_lists:\n return set()\n\n # Convert the first list into a set for efficient comparison\n common_set = set(nested_lists[0])\n\n # Iterate through the rest of the lists and update the common_set\n for lst in nested_lists[1:]:\n common_set.intersection_update(lst)\n\n return common_set", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef common_in_nested_lists(lists: List[List[int]]) -> List[int]:\n # Convert the first list to a set for efficient comparison\n common_set = set(lists[0])\n \n # Iterate over the remaining lists and update the common_set with their elements\n for lst in lists[1:]:\n common_set.intersection_update(lst)\n \n # Convert the result back to a list and sort it (optional, as per the assert statement)\n return sorted(list(common_set))", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(lists):\n if not lists:\n return set()\n \n # Initialize the common set with the first list\n common = set(lists[0])\n \n # Iterate over the rest of the lists and update the common set\n for lst in lists[1:]:\n common &= set(lst)\n \n return common", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(lists):\n # Convert all lists to sets for efficient comparison\n sets = [set(lst) for lst in lists]\n \n # Find the intersection of all sets\n common_elements = set.intersection(*sets)\n \n return common_elements", "matching_cluster_idx": 5}, {"solution": "def common_in_nested_lists(lists):\n # Convert the first list to a set for efficient comparison\n common_set = set(lists[0])\n \n # Iterate over the rest of the lists\n for lst in lists[1:]:\n # Update the common_set with the intersection of current common_set and current list\n common_set.intersection_update(lst)\n \n return common_set", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n # Flatten the nested lists into a single list\n flat_list = [item for sublist in nested_lists for item in sublist]\n \n # Find the common elements using set intersection\n common_elements = set(flat_list)\n for lst in nested_lists:\n common_elements &= set(lst)\n \n return common_elements", "matching_cluster_idx": 3}]}, "Mbpp/123": {"dps": 99.62686567164178, "dps_norm": 85.71428571428571, "pass@1": 100.0, "profiled": [{"solution": "def sum_of_divisors(n):\n \"\"\"Calculate the sum of proper divisors of n.\"\"\"\n sum_divisors = 1\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n sum_divisors += i\n if i != n // i:\n sum_divisors += n // i\n return sum_divisors\ndef amicable_numbers_sum(limit):\n \"\"\"Sum all amicable numbers from 1 to the specified limit.\"\"\"\n sum_amicable = 0\n for a in range(2, limit + 1):\n b = sum_of_divisors(a)\n if b > a and sum_of_divisors(b) == a:\n sum_amicable += a + b\n return sum_amicable", "matching_cluster_idx": 11}, {"solution": "def sum_of_divisors(n):\n \"\"\"Calculate the sum of all proper divisors of n.\"\"\"\n sum_div = 1\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n sum_div += i\n if i != n // i:\n sum_div += n // i\n return sum_div\ndef amicable_numbers_sum(num):\n \"\"\"Sum all amicable numbers from 1 to num.\"\"\"\n sum_amicable = 0\n for a in range(2, num + 1):\n b = sum_of_divisors(a)\n if a != b and sum_of_divisors(b) == a:\n sum_amicable += a\n return sum_amicable", "matching_cluster_idx": 11}, {"solution": "def sum_of_divisors(n):\n \"\"\"Calculate the sum of all proper divisors of n.\"\"\"\n divisors_sum = 1\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n divisors_sum += i\n if i != n // i:\n divisors_sum += n // i\n return divisors_sum\ndef amicable_numbers_sum(limit):\n \"\"\"Sum all amicable numbers from 1 to the specified limit.\"\"\"\n amicable_sum = 0\n for a in range(2, limit + 1):\n b = sum_of_divisors(a)\n if b > a and sum_of_divisors(b) == a:\n amicable_sum += a + b\n return amicable_sum", "matching_cluster_idx": 11}, {"solution": "def sum_of_divisors(n):\n \"\"\"Calculate the sum of proper divisors of n.\"\"\"\n sum_divisors = 1\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n sum_divisors += i\n if i != n // i:\n sum_divisors += n // i\n return sum_divisors\ndef amicable_numbers_sum(number):\n \"\"\"Sum all amicable numbers from 1 to a specified number.\"\"\"\n sum_amicable = 0\n for a in range(2, number + 1):\n b = sum_of_divisors(a)\n if b > a and sum_of_divisors(b) == a:\n sum_amicable += a + b\n return sum_amicable", "matching_cluster_idx": 11}, {"solution": "def sum_of_divisors(n):\n \"\"\"Helper function to calculate the sum of divisors of n.\"\"\"\n sum_divisors = 1\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n sum_divisors += i\n if i != n // i:\n sum_divisors += n // i\n return sum_divisors\ndef amicable_numbers_sum(limit):\n \"\"\"Function to sum all amicable numbers from 1 to a specified number.\"\"\"\n amicable_sum = 0\n for a in range(2, limit + 1):\n b = sum_of_divisors(a)\n if a != b and sum_of_divisors(b) == a:\n amicable_sum += a\n return amicable_sum", "matching_cluster_idx": 11}, {"solution": "def sum_of_divisors(n):\n \"\"\"Return the sum of all divisors of n.\"\"\"\n divisors_sum = 1\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n divisors_sum += i\n if i != n // i:\n divisors_sum += n // i\n return divisors_sum\ndef amicable_numbers_sum(limit):\n \"\"\"Return the sum of all amicable numbers up to the specified limit.\"\"\"\n amicable_sum = 0\n for a in range(2, limit + 1):\n b = sum_of_divisors(a)\n if a != b and sum_of_divisors(b) == a:\n amicable_sum += a\n return amicable_sum", "matching_cluster_idx": 11}, {"solution": "def sum_of_divisors(n):\n \"\"\"Calculate the sum of proper divisors of n.\"\"\"\n sum_divisors = 1\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n sum_divisors += i\n if i != n // i:\n sum_divisors += n // i\n return sum_divisors\ndef amicable_numbers_sum(limit):\n \"\"\"Sum all amicable numbers from 1 to the specified number.\"\"\"\n sum_amicable = 0\n for a in range(1, limit + 1):\n b = sum_of_divisors(a)\n if a != b and sum_of_divisors(b) == a:\n sum_amicable += a\n return sum_amicable", "matching_cluster_idx": 11}, {"solution": "def sum_of_divisors(n):\n \"\"\"Calculate the sum of proper divisors of n.\"\"\"\n sum_div = 1\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n sum_div += i\n if i != n // i:\n sum_div += n // i\n return sum_div\ndef amicable_numbers_sum(limit):\n \"\"\"Sum all amicable numbers from 1 to the specified limit.\"\"\"\n sum_amicable = 0\n for a in range(1, limit + 1):\n b = sum_of_divisors(a)\n if a != b and sum_of_divisors(b) == a:\n sum_amicable += a\n return sum_amicable", "matching_cluster_idx": 11}, {"solution": "def sum_of_divisors(n):\n \"\"\"Calculate the sum of all proper divisors of n.\"\"\"\n sum_divisors = 1\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n sum_divisors += i\n if i != n // i:\n sum_divisors += n // i\n return sum_divisors\ndef amicable_numbers_sum(limit):\n \"\"\"Sum all amicable numbers from 1 to the specified limit.\"\"\"\n sum_amicable = 0\n for a in range(2, limit + 1):\n b = sum_of_divisors(a)\n if a != b and sum_of_divisors(b) == a:\n sum_amicable += a\n return sum_amicable", "matching_cluster_idx": 11}, {"solution": "def sum_of_divisors(n):\n \"\"\"Calculate the sum of proper divisors of n.\"\"\"\n divisors_sum = 1\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n divisors_sum += i\n if i != n // i:\n divisors_sum += n // i\n return divisors_sum\ndef amicable_numbers_sum(limit):\n \"\"\"Sum all amicable numbers from 1 to the specified limit.\"\"\"\n amicable_sum = 0\n for a in range(2, limit + 1):\n b = sum_of_divisors(a)\n if b > a and sum_of_divisors(b) == a:\n amicable_sum += a + b\n return amicable_sum", "matching_cluster_idx": 11}, {"solution": "def sum_of_divisors(n):\n sum_div = 1\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n sum_div += i\n if i != n // i:\n sum_div += n // i\n return sum_div\ndef amicable_numbers_sum(limit):\n sum_amicable = 0\n for a in range(2, limit + 1):\n b = sum_of_divisors(a)\n if a != b and sum_of_divisors(b) == a:\n sum_amicable += a\n return sum_amicable", "matching_cluster_idx": 11}, {"solution": "def sum_of_divisors(n):\n \"\"\"Calculate the sum of proper divisors of n.\"\"\"\n sum_div = 1\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n sum_div += i\n if i != n // i:\n sum_div += n // i\n return sum_div\ndef amicable_numbers_sum(limit):\n \"\"\"Sum all amicable numbers from 1 to a specified number.\"\"\"\n sum_amicable = 0\n for a in range(2, limit + 1):\n b = sum_of_divisors(a)\n if a != b and sum_of_divisors(b) == a:\n sum_amicable += a\n return sum_amicable", "matching_cluster_idx": 11}, {"solution": "def sum_of_divisors(n):\n \"\"\"Compute the sum of proper divisors of n.\"\"\"\n sum_divisors = 1\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n sum_divisors += i\n if i != n // i:\n sum_divisors += n // i\n return sum_divisors\ndef amicable_numbers_sum(limit):\n \"\"\"Sum all amicable numbers from 1 to a specified number.\"\"\"\n sum_amicable = 0\n for a in range(2, limit + 1):\n b = sum_of_divisors(a)\n if b > a and sum_of_divisors(b) == a:\n sum_amicable += a + b\n return sum_amicable", "matching_cluster_idx": 11}, {"solution": "def sum_of_divisors(n):\n \"\"\"Calculate the sum of proper divisors of n.\"\"\"\n sum_divisors = 1\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n sum_divisors += i\n if i != n // i:\n sum_divisors += n // i\n return sum_divisors\ndef amicable_numbers_sum(limit):\n \"\"\"Sum all amicable numbers from 1 to the specified limit.\"\"\"\n amicable_sum = 0\n for a in range(2, limit + 1):\n b = sum_of_divisors(a)\n if a != b and sum_of_divisors(b) == a:\n amicable_sum += a\n return amicable_sum", "matching_cluster_idx": 11}, {"solution": "def sum_of_divisors(n):\n \"\"\"Calculate the sum of proper divisors of n.\"\"\"\n sum_div = 1\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n sum_div += i\n if i != n // i:\n sum_div += n // i\n return sum_div\ndef amicable_numbers_sum(limit):\n \"\"\"Sum all amicable numbers from 1 to the specified limit.\"\"\"\n sum_amicable = 0\n for a in range(2, limit + 1):\n b = sum_of_divisors(a)\n if b > a and sum_of_divisors(b) == a:\n sum_amicable += a + b\n return sum_amicable", "matching_cluster_idx": 11}, {"solution": "def sum_of_divisors(n):\n \"\"\"Return the sum of proper divisors of n.\"\"\"\n sum_div = 1\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n sum_div += i\n if i != n // i:\n sum_div += n // i\n return sum_div\ndef amicable_numbers_sum(limit):\n \"\"\"Return the sum of all amicable numbers from 1 to limit.\"\"\"\n sum_amicable = 0\n for a in range(2, limit + 1):\n b = sum_of_divisors(a)\n if a != b and sum_of_divisors(b) == a:\n sum_amicable += a\n return sum_amicable", "matching_cluster_idx": 11}, {"solution": "def sum_of_divisors(n):\n \"\"\"Calculate the sum of proper divisors of n.\"\"\"\n sum_divisors = 1\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n sum_divisors += i\n if i != n // i:\n sum_divisors += n // i\n return sum_divisors\ndef amicable_numbers_sum(limit):\n \"\"\"Sum all amicable numbers from 1 to a specified number.\"\"\"\n sum_amicable = 0\n for a in range(2, limit + 1):\n b = sum_of_divisors(a)\n if a != b and sum_of_divisors(b) == a:\n sum_amicable += a\n return sum_amicable", "matching_cluster_idx": 11}, {"solution": "def sum_of_divisors(n):\n \"\"\"Helper function to calculate the sum of divisors of n.\"\"\"\n sum_divisors = 1\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n sum_divisors += i\n if i != n // i:\n sum_divisors += n // i\n return sum_divisors\ndef amicable_numbers_sum(limit):\n \"\"\"Function to calculate the sum of all amicable numbers from 1 to a specified number.\"\"\"\n sum_amicable = 0\n for a in range(2, limit + 1):\n b = sum_of_divisors(a)\n if a != b and sum_of_divisors(b) == a:\n sum_amicable += a\n return sum_amicable", "matching_cluster_idx": 11}, {"solution": "def sum_of_divisors(n):\n \"\"\"Calculate the sum of proper divisors of n.\"\"\"\n sum_divisors = 1\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n sum_divisors += i\n if i != n // i:\n sum_divisors += n // i\n return sum_divisors\ndef amicable_numbers_sum(limit):\n \"\"\"Sum all amicable numbers from 1 to a specified number.\"\"\"\n sum_amicable = 0\n for a in range(2, limit + 1):\n b = sum_of_divisors(a)\n if a != b and sum_of_divisors(b) == a:\n sum_amicable += a\n return sum_amicable", "matching_cluster_idx": 11}, {"solution": "def sum_of_divisors(n):\n \"\"\"Calculate the sum of proper divisors of n.\"\"\"\n sum_divisors = 1\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n sum_divisors += i\n if i != n // i:\n sum_divisors += n // i\n return sum_divisors\ndef amicable_numbers_sum(limit):\n \"\"\"Sum all amicable numbers from 1 to the specified number.\"\"\"\n amicable_sum = 0\n for a in range(2, limit + 1):\n b = sum_of_divisors(a)\n if b > a and sum_of_divisors(b) == a:\n amicable_sum += a + b\n return amicable_sum", "matching_cluster_idx": 11}]}, "Mbpp/128": {"dps": 99.5475113122172, "dps_norm": 80.0, "pass@1": 100.0, "profiled": [{"solution": "def long_words(n, text):\n \"\"\"\n Returns a list of words from the given text that are longer than n characters.\n \n Args:\n n (int): The minimum length of words to be considered.\n text (str): The input text from which to extract words.\n \n Returns:\n List[str]: A list of words longer than n characters.\n \"\"\"\n words = text.split()\n return [word for word in words if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, text):\n words = text.split()\n return [word for word in words if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, text):\n words = text.split()\n result = [word for word in words if len(word) > n]\n return result", "matching_cluster_idx": 3}, {"solution": "def long_words(n, text):\n words = text.split()\n return [word for word in words if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, text):\n words = text.split()\n result = [word for word in words if len(word) > n]\n return result", "matching_cluster_idx": 3}, {"solution": "def long_words(n, text):\n words = text.split()\n return [word for word in words if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, text):\n words = text.split()\n return [word for word in words if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, text):\n words = text.split()\n return [word for word in words if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, text):\n words = text.split()\n return [word for word in words if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, text):\n words = text.split()\n return [word for word in words if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, text):\n words = text.split()\n return [word for word in words if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, text):\n words = text.split()\n return [word for word in words if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, text):\n words = text.split()\n return [word for word in words if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, text):\n words = text.split()\n return [word for word in words if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, text):\n words = text.split()\n return [word for word in words if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, text):\n words = text.split()\n return [word for word in words if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, text):\n words = text.split()\n return [word for word in words if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, text):\n words = text.split()\n return [word for word in words if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, text):\n words = text.split()\n return [word for word in words if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, text):\n words = text.split()\n return [word for word in words if len(word) > n]", "matching_cluster_idx": 3}]}, "Mbpp/129": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 57.0, "profiled": [{"solution": "def magic_square_test(my_square):\n n = len(my_square)\n # Calculate the sum of the first row to use as a reference\n magic_sum = sum(my_square[0])\n\n # Check the sum of each row\n for row in my_square:\n if sum(row) != magic_sum:\n return False\n\n # Check the sum of each column\n for col in range(n):\n if sum(my_square[row][col] for row in range(n)) != magic_sum:\n return False\n\n # Check the sum of the primary diagonal\n if sum(my_square[i][i] for i in range(n)) != magic_sum:\n return False\n\n # Check the sum of the secondary diagonal\n if sum(my_square[i][n - i - 1] for i in range(n)) != magic_sum:\n return False\n\n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(my_matrix):\n # Calculate the size of the matrix\n n = len(my_matrix)\n \n # Calculate the sum of the first row\n magic_sum = sum(my_matrix[0])\n \n # Check the sum of each row\n for row in my_matrix:\n if sum(row) != magic_sum:\n return False\n \n # Check the sum of each column\n for col in range(n):\n if sum(my_matrix[row][col] for row in range(n)) != magic_sum:\n return False\n \n # Check the sum of the main diagonal\n if sum(my_matrix[i][i] for i in range(n)) != magic_sum:\n return False\n \n # Check the sum of the secondary diagonal\n if sum(my_matrix[i][n-i-1] for i in range(n)) != magic_sum:\n return False\n \n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(my_matrix):\n size = len(my_matrix)\n magic_sum = sum(my_matrix[0])\n\n # Check sums of rows\n for row in my_matrix:\n if sum(row) != magic_sum:\n return False\n\n # Check sums of columns\n for col in range(size):\n if sum(my_matrix[row][col] for row in range(size)) != magic_sum:\n return False\n\n # Check sum of primary diagonal\n if sum(my_matrix[i][i] for i in range(size)) != magic_sum:\n return False\n\n # Check sum of secondary diagonal\n if sum(my_matrix[i][size - i - 1] for i in range(size)) != magic_sum:\n return False\n\n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(my_matrix):\n n = len(my_matrix)\n # Calculate the sum of the first row\n magic_sum = sum(my_matrix[0])\n \n # Check the sum of each row\n for row in my_matrix:\n if sum(row) != magic_sum:\n return False\n \n # Check the sum of each column\n for col in range(n):\n if sum(my_matrix[row][col] for row in range(n)) != magic_sum:\n return False\n \n # Check the sum of the primary diagonal\n if sum(my_matrix[i][i] for i in range(n)) != magic_sum:\n return False\n \n # Check the sum of the secondary diagonal\n if sum(my_matrix[i][n - i - 1] for i in range(n)) != magic_sum:\n return False\n \n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(my_square):\n n = len(my_square)\n # Calculate the sum of the first row\n magic_sum = sum(my_square[0])\n \n # Check the sum of each row\n for row in my_square:\n if sum(row) != magic_sum:\n return False\n \n # Check the sum of each column\n for col in range(n):\n if sum(my_square[row][col] for row in range(n)) != magic_sum:\n return False\n \n # Check the sum of the main diagonal\n if sum(my_square[i][i] for i in range(n)) != magic_sum:\n return False\n \n # Check the sum of the secondary diagonal\n if sum(my_square[i][n - 1 - i] for i in range(n)) != magic_sum:\n return False\n \n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(my_list):\n size = len(my_list)\n # Calculate the sum of the first row\n magic_sum = sum(my_list[0])\n\n # Check the sum of each row\n for row in my_list:\n if sum(row) != magic_sum:\n return False\n\n # Check the sum of each column\n for col in range(size):\n if sum(my_list[row][col] for row in range(size)) != magic_sum:\n return False\n\n # Check the sum of the primary diagonal\n if sum(my_list[i][i] for i in range(size)) != magic_sum:\n return False\n\n # Check the sum of the secondary diagonal\n if sum(my_list[i][size - i - 1] for i in range(size)) != magic_sum:\n return False\n\n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(my_square):\n n = len(my_square)\n # Calculate the sum of the first row to use as a reference\n magic_constant = sum(my_square[0])\n \n # Check the sum of each row\n for row in my_square:\n if sum(row) != magic_constant:\n return False\n \n # Check the sum of each column\n for col in range(n):\n if sum(my_square[row][col] for row in range(n)) != magic_constant:\n return False\n \n # Check the sum of the main diagonal\n if sum(my_square[i][i] for i in range(n)) != magic_constant:\n return False\n \n # Check the sum of the secondary diagonal\n if sum(my_square[i][n-i-1] for i in range(n)) != magic_constant:\n return False\n \n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(my_matrix):\n n = len(my_matrix)\n # Calculate the sum of the first row\n magic_sum = sum(my_matrix[0])\n \n # Check the sum of each row\n for row in my_matrix:\n if sum(row) != magic_sum:\n return False\n \n # Check the sum of each column\n for col in range(n):\n if sum(my_matrix[row][col] for row in range(n)) != magic_sum:\n return False\n \n # Check the sum of the primary diagonal\n if sum(my_matrix[i][i] for i in range(n)) != magic_sum:\n return False\n \n # Check the sum of the secondary diagonal\n if sum(my_matrix[i][n-i-1] for i in range(n)) != magic_sum:\n return False\n \n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(my_matrix):\n n = len(my_matrix)\n magic_sum = sum(my_matrix[0])\n\n # Check sums of rows\n for row in my_matrix:\n if sum(row) != magic_sum:\n return False\n\n # Check sums of columns\n for col in range(n):\n if sum(my_matrix[row][col] for row in range(n)) != magic_sum:\n return False\n\n # Check sum of main diagonal\n if sum(my_matrix[i][i] for i in range(n)) != magic_sum:\n return False\n\n # Check sum of secondary diagonal\n if sum(my_matrix[i][n - i - 1] for i in range(n)) != magic_sum:\n return False\n\n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(my_matrix):\n n = len(my_matrix)\n magic_sum = sum(my_matrix[0])\n \n # Check the sum of each row\n for row in my_matrix:\n if sum(row) != magic_sum:\n return False\n \n # Check the sum of each column\n for col in range(n):\n if sum(my_matrix[row][col] for row in range(n)) != magic_sum:\n return False\n \n # Check the sum of the primary diagonal\n if sum(my_matrix[i][i] for i in range(n)) != magic_sum:\n return False\n \n # Check the sum of the secondary diagonal\n if sum(my_matrix[i][n-1-i] for i in range(n)) != magic_sum:\n return False\n \n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(my_square):\n n = len(my_square)\n magic_sum = sum(my_square[0])\n \n # Check the sum of each row\n for row in my_square:\n if sum(row) != magic_sum:\n return False\n \n # Check the sum of each column\n for col in range(n):\n if sum(my_square[row][col] for row in range(n)) != magic_sum:\n return False\n \n # Check the sum of the main diagonal\n if sum(my_square[i][i] for i in range(n)) != magic_sum:\n return False\n \n # Check the sum of the secondary diagonal\n if sum(my_square[i][n - 1 - i] for i in range(n)) != magic_sum:\n return False\n \n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(my_matrix):\n n = len(my_matrix)\n # Calculate the sum of the first row\n magic_sum = sum(my_matrix[0])\n \n # Check the sum of each row\n for row in my_matrix:\n if sum(row) != magic_sum:\n return False\n \n # Check the sum of each column\n for col in range(n):\n if sum(my_matrix[row][col] for row in range(n)) != magic_sum:\n return False\n \n # Check the sum of the main diagonal\n if sum(my_matrix[i][i] for i in range(n)) != magic_sum:\n return False\n \n # Check the sum of the secondary diagonal\n if sum(my_matrix[i][n-i-1] for i in range(n)) != magic_sum:\n return False\n \n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(my_square):\n n = len(my_square)\n \n # Calculate the sum of the first row to use as a reference\n magic_sum = sum(my_square[0])\n \n # Check the sum of each row\n for row in my_square:\n if sum(row) != magic_sum:\n return False\n \n # Check the sum of each column\n for col in range(n):\n if sum(my_square[row][col] for row in range(n)) != magic_sum:\n return False\n \n # Check the sum of the primary diagonal\n if sum(my_square[i][i] for i in range(n)) != magic_sum:\n return False\n \n # Check the sum of the secondary diagonal\n if sum(my_square[i][n - i - 1] for i in range(n)) != magic_sum:\n return False\n \n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(my_matrix):\n n = len(my_matrix)\n \n # Calculate the sum of the first row\n sum_base = sum(my_matrix[0])\n \n # Check the sum of each row\n for i in range(1, n):\n if sum(my_matrix[i]) != sum_base:\n return False\n \n # Check the sum of each column\n for i in range(n):\n if sum(my_matrix[j][i] for j in range(n)) != sum_base:\n return False\n \n # Check the sum of the primary diagonal\n if sum(my_matrix[i][i] for i in range(n)) != sum_base:\n return False\n \n # Check the sum of the secondary diagonal\n if sum(my_matrix[i][n-i-1] for i in range(n)) != sum_base:\n return False\n \n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(my_matrix):\n n = len(my_matrix)\n # Calculate the sum of the first row\n magic_sum = sum(my_matrix[0])\n \n # Check the sum of each row\n for row in my_matrix:\n if sum(row) != magic_sum:\n return False\n \n # Check the sum of each column\n for col in range(n):\n if sum(my_matrix[row][col] for row in range(n)) != magic_sum:\n return False\n \n # Check the sum of the primary diagonal\n if sum(my_matrix[i][i] for i in range(n)) != magic_sum:\n return False\n \n # Check the sum of the secondary diagonal\n if sum(my_matrix[i][n-i-1] for i in range(n)) != magic_sum:\n return False\n \n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(my_matrix):\n size = len(my_matrix)\n # Calculate the sum of the first row to use as a comparison\n magic_sum = sum(my_matrix[0])\n\n # Check the sum of each row\n for row in my_matrix:\n if sum(row) != magic_sum:\n return False\n\n # Check the sum of each column\n for col in range(size):\n if sum(my_matrix[row][col] for row in range(size)) != magic_sum:\n return False\n\n # Check the sum of the primary diagonal\n if sum(my_matrix[i][i] for i in range(size)) != magic_sum:\n return False\n\n # Check the sum of the secondary diagonal\n if sum(my_matrix[i][size - i - 1] for i in range(size)) != magic_sum:\n return False\n\n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(my_matrix):\n n = len(my_matrix)\n magic_constant = sum(my_matrix[0])\n\n # Check sum of each row\n for row in my_matrix:\n if sum(row) != magic_constant:\n return False\n\n # Check sum of each column\n for col in range(n):\n if sum(my_matrix[row][col] for row in range(n)) != magic_constant:\n return False\n\n # Check sum of the primary diagonal\n if sum(my_matrix[i][i] for i in range(n)) != magic_constant:\n return False\n\n # Check sum of the secondary diagonal\n if sum(my_matrix[i][n - i - 1] for i in range(n)) != magic_constant:\n return False\n\n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(my_square):\n n = len(my_square)\n magic_sum = sum(my_square[0])\n \n # Check the sum of each row\n for row in my_square:\n if sum(row) != magic_sum:\n return False\n \n # Check the sum of each column\n for col in range(n):\n if sum(my_square[row][col] for row in range(n)) != magic_sum:\n return False\n \n # Check the sum of the primary diagonal\n if sum(my_square[i][i] for i in range(n)) != magic_sum:\n return False\n \n # Check the sum of the secondary diagonal\n if sum(my_square[i][n - i - 1] for i in range(n)) != magic_sum:\n return False\n \n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(my_square):\n n = len(my_square)\n # Calculate the sum of the first row\n magic_sum = sum(my_square[0])\n\n # Check the sum of each row\n for row in my_square:\n if sum(row) != magic_sum:\n return False\n\n # Check the sum of each column\n for col in range(n):\n if sum(my_square[row][col] for row in range(n)) != magic_sum:\n return False\n\n # Check the sum of the primary diagonal\n if sum(my_square[i][i] for i in range(n)) != magic_sum:\n return False\n\n # Check the sum of the secondary diagonal\n if sum(my_square[i][n - i - 1] for i in range(n)) != magic_sum:\n return False\n\n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(my_square):\n n = len(my_square)\n \n # Calculate the sum of the first row to use as a reference\n magic_sum = sum(my_square[0])\n \n # Check the sum of each row\n for row in my_square:\n if sum(row) != magic_sum:\n return False\n \n # Check the sum of each column\n for col in range(n):\n if sum(my_square[row][col] for row in range(n)) != magic_sum:\n return False\n \n # Check the sum of the main diagonal\n if sum(my_square[i][i] for i in range(n)) != magic_sum:\n return False\n \n # Check the sum of the secondary diagonal\n if sum(my_square[i][n-1-i] for i in range(n)) != magic_sum:\n return False\n \n return True", "matching_cluster_idx": 14}]}, "Mbpp/130": {"dps": 78.41928251121077, "dps_norm": 70.83333333333334, "pass@1": 75.0, "profiled": [{"solution": "def max_occurrences(numbers):\n frequency = {}\n for number in numbers:\n if number in frequency:\n frequency[number] += 1\n else:\n frequency[number] = 1\n max_occur = max(frequency.values())\n for number, count in frequency.items():\n if count == max_occur:\n return number", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(lst):\n frequency = {}\n for item in lst:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n max_item = max(frequency, key=frequency.get)\n return max_item", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(lst):\n frequency = {}\n for item in lst:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n max_item = None\n max_count = 0\n for item, count in frequency.items():\n if count > max_count:\n max_count = count\n max_item = item\n return max_item", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(lst):\n if not lst:\n return None # Handle the case of an empty list\n frequency_dict = {}\n for item in lst:\n if item in frequency_dict:\n frequency_dict[item] += 1\n else:\n frequency_dict[item] = 1\n max_item = max(frequency_dict, key=frequency_dict.get)\n return max_item", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(numbers):\n frequency_dict = {}\n for number in numbers:\n if number in frequency_dict:\n frequency_dict[number] += 1\n else:\n frequency_dict[number] = 1\n max_frequency = max(frequency_dict.values())\n for number, freq in frequency_dict.items():\n if freq == max_frequency:\n return number", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(numbers):\n if not numbers:\n return None\n \n frequency = {}\n for number in numbers:\n frequency[number] = frequency.get(number, 0) + 1\n \n max_occurrence = max(frequency.values())\n for number, count in frequency.items():\n if count == max_occurrence:\n return number", "matching_cluster_idx": 3}, {"solution": "from collections import Counter\ndef max_occurrences(lst):\n if not lst:\n return None\n frequency_counter = Counter(lst)\n max_freq = max(frequency_counter.values())\n for item, freq in frequency_counter.items():\n if freq == max_freq:\n return item", "matching_cluster_idx": 5}, {"solution": "def max_occurrences(numbers):\n frequency = {}\n for num in numbers:\n if num in frequency:\n frequency[num] += 1\n else:\n frequency[num] = 1\n max_item = max(frequency, key=frequency.get)\n return max_item", "matching_cluster_idx": 3}, {"solution": "from collections import Counter\ndef max_occurrences(lst):\n \"\"\"\n Function to find the item with maximum frequency in a given list.\n \"\"\"\n if not lst:\n return None\n freq_count = Counter(lst)\n max_item = max(freq_count, key=freq_count.get)\n return max_item", "matching_cluster_idx": 4}, {"solution": "def max_occurrences(lst):\n frequency = {}\n for item in lst:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n max_item = max(frequency, key=frequency.get)\n return max_item", "matching_cluster_idx": 3}, {"solution": "from collections import Counter\ndef max_occurrences(numbers):\n \"\"\"\n Function to find the item with maximum frequency in a given list.\n \"\"\"\n if not numbers:\n return None # Return None for an empty list\n \n # Use Counter to count the frequency of each element\n frequency = Counter(numbers)\n \n # Find the element with the maximum frequency\n max_item, max_freq = max(frequency.items(), key=lambda x: x[1])\n \n return max_item", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(numbers):\n frequency = {}\n for number in numbers:\n if number in frequency:\n frequency[number] += 1\n else:\n frequency[number] = 1\n max_item = max(frequency, key=frequency.get)\n return max_item", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(lst):\n frequency = {}\n for item in lst:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n max_item = max(frequency, key=frequency.get)\n return max_item", "matching_cluster_idx": 3}, {"solution": "from collections import Counter\ndef max_occurrences(lst):\n if not lst:\n return None\n frequency_counter = Counter(lst)\n max_freq = max(frequency_counter.values())\n for item, freq in frequency_counter.items():\n if freq == max_freq:\n return item", "matching_cluster_idx": 5}, {"solution": "def max_occurrences(lst):\n frequency_dict = {}\n for item in lst:\n if item in frequency_dict:\n frequency_dict[item] += 1\n else:\n frequency_dict[item] = 1\n max_item = None\n max_count = 0\n for item, count in frequency_dict.items():\n if count > max_count:\n max_count = count\n max_item = item\n return max_item", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(lst):\n frequency = {}\n for item in lst:\n frequency[item] = frequency.get(item, 0) + 1\n max_item = max(frequency, key=frequency.get)\n return max_item", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(numbers):\n frequency = {}\n for number in numbers:\n if number in frequency:\n frequency[number] += 1\n else:\n frequency[number] = 1\n max_item = max(frequency, key=frequency.get)\n return max_item", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(numbers):\n frequency = {}\n for number in numbers:\n if number in frequency:\n frequency[number] += 1\n else:\n frequency[number] = 1\n max_item = None\n max_count = 0\n for number, count in frequency.items():\n if count > max_count:\n max_count = count\n max_item = number\n return max_item", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(lst):\n frequency = {}\n for item in lst:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n max_item = max(frequency, key=frequency.get)\n return max_item", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(numbers):\n frequency = {}\n for num in numbers:\n if num in frequency:\n frequency[num] += 1\n else:\n frequency[num] = 1\n max_item = max(frequency, key=frequency.get)\n return max_item", "matching_cluster_idx": 3}]}, "Mbpp/137": {"dps": null, "dps_norm": null, "pass@1": 7.0, "profiled": []}, "Mbpp/140": {"dps": 63.69565217391305, "dps_norm": 74.375, "pass@1": 100.0, "profiled": [{"solution": "def extract_singly(list_of_lists):\n \"\"\"\n Flattens a list of lists into a single set of numbers.\n \"\"\"\n flat_set = set()\n for sublist in list_of_lists:\n flat_set.update(sublist)\n return flat_set", "matching_cluster_idx": 6}, {"solution": "def extract_singly(list_of_lists):\n flat_set = set()\n for sublist in list_of_lists:\n flat_set.update(sublist)\n return flat_set", "matching_cluster_idx": 6}, {"solution": "def extract_singly(list_of_lists):\n flat_set = set()\n for sublist in list_of_lists:\n flat_set.update(sublist)\n return flat_set", "matching_cluster_idx": 6}, {"solution": "def extract_singly(list_of_lists):\n flat_set = set()\n for sublist in list_of_lists:\n flat_set.update(sublist)\n return flat_set", "matching_cluster_idx": 6}, {"solution": "def extract_singly(list_of_lists):\n flat_set = set()\n for sublist in list_of_lists:\n for item in sublist:\n flat_set.add(item)\n return flat_set", "matching_cluster_idx": 4}, {"solution": "def extract_singly(list_of_lists):\n \"\"\"\n Flattens a list of lists into a set of unique numbers.\n \"\"\"\n flat_set = set()\n for sublist in list_of_lists:\n for item in sublist:\n flat_set.add(item)\n return flat_set", "matching_cluster_idx": 4}, {"solution": "def extract_singly(list_of_lists):\n flattened_set = set()\n for sublist in list_of_lists:\n for item in sublist:\n flattened_set.add(item)\n return flattened_set", "matching_cluster_idx": 4}, {"solution": "def extract_singly(list_of_lists):\n flat_set = set()\n for lst in list_of_lists:\n flat_set.update(lst)\n return flat_set", "matching_cluster_idx": 7}, {"solution": "def extract_singly(list_of_lists):\n flat_set = set()\n for sublist in list_of_lists:\n for item in sublist:\n flat_set.add(item)\n return flat_set", "matching_cluster_idx": 4}, {"solution": "def extract_singly(list_of_lists):\n flat_set = set()\n for sublist in list_of_lists:\n flat_set.update(sublist)\n return flat_set", "matching_cluster_idx": 6}, {"solution": "def extract_singly(list_of_lists):\n flat_set = set()\n for sublist in list_of_lists:\n for item in sublist:\n flat_set.add(item)\n return flat_set", "matching_cluster_idx": 4}, {"solution": "def extract_singly(list_of_lists):\n flat_set = set()\n for lst in list_of_lists:\n for item in lst:\n flat_set.add(item)\n return flat_set", "matching_cluster_idx": 4}, {"solution": "def extract_singly(list_of_lists):\n result = set()\n for sublist in list_of_lists:\n for item in sublist:\n result.add(item)\n return result", "matching_cluster_idx": 4}, {"solution": "def extract_singly(list_of_lists):\n flattened_set = set()\n for sublist in list_of_lists:\n flattened_set.update(sublist)\n return flattened_set", "matching_cluster_idx": 6}, {"solution": "def extract_singly(list_of_lists):\n \"\"\"\n Flattens a list of lists into a single set of numbers.\n \n Args:\n list_of_lists (list of tuple): A list containing tuples of numbers.\n \n Returns:\n set: A set containing all unique numbers from the input list of lists.\n \"\"\"\n result_set = set()\n for sublist in list_of_lists:\n for item in sublist:\n result_set.add(item)\n return result_set", "matching_cluster_idx": 4}, {"solution": "def extract_singly(list_of_lists):\n flat_set = set()\n for sublist in list_of_lists:\n flat_set.update(sublist)\n return flat_set", "matching_cluster_idx": 6}, {"solution": "def extract_singly(list_of_lists):\n flat_set = set()\n for sublist in list_of_lists:\n for item in sublist:\n flat_set.add(item)\n return flat_set", "matching_cluster_idx": 4}, {"solution": "def extract_singly(list_of_lists):\n flat_set = set()\n for sublist in list_of_lists:\n for item in sublist:\n flat_set.add(item)\n return flat_set", "matching_cluster_idx": 4}, {"solution": "def extract_singly(list_of_lists):\n flat_set = set()\n for sublist in list_of_lists:\n flat_set.update(sublist)\n return flat_set", "matching_cluster_idx": 6}, {"solution": "def extract_singly(list_of_lists):\n flat_set = set()\n for sublist in list_of_lists:\n for item in sublist:\n flat_set.add(item)\n return flat_set", "matching_cluster_idx": 4}]}, "Mbpp/141": {"dps": 70.9297052154195, "dps_norm": 42.5, "pass@1": 94.0, "profiled": [{"solution": "def pancake_sort(arr):\n def flip(sub_arr, k):\n i = 0\n while i < k:\n sub_arr[i], sub_arr[k] = sub_arr[k], sub_arr[i]\n i += 1\n k -= 1\n\n n = len(arr)\n while n > 1:\n # Find the index of the maximum element in the unsorted part of the array\n mi = arr.index(max(arr[:n]))\n \n # Flip the sub-array to bring the maximum element to the first position\n flip(arr, mi)\n \n # Flip the sub-array to bring the maximum element to the correct position\n flip(arr, n - 1)\n \n n -= 1\n \n return arr", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(arr):\n def flip(sub_array, k):\n i, j = 0, k\n while i < j:\n sub_array[i], sub_array[j] = sub_array[j], sub_array[i]\n i += 1\n j -= 1\n\n n = len(arr)\n while n > 1:\n # Find the index of the maximum element in the unsorted part of the array\n mi = arr.index(max(arr[0:n]))\n # Flip the subarray from 0 to mi to bring the maximum element to the front\n flip(arr, mi)\n # Flip the subarray from 0 to n-1 to move the maximum element to its correct position\n flip(arr, n - 1)\n n -= 1\n return arr", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(arr):\n def flip(sub_arr, k):\n i, j = 0, k\n while i < j:\n sub_arr[i], sub_arr[j] = sub_arr[j], sub_arr[i]\n i += 1\n j -= 1\n\n n = len(arr)\n while n > 1:\n # Find the index of the maximum element in the unsorted portion of the array\n mi = arr.index(max(arr[0:n]))\n # Flip the maximum element to the beginning of the array\n flip(arr, mi)\n # Flip the maximum element to the end of the unsorted portion of the array\n flip(arr, n - 1)\n n -= 1\n return arr", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(arr):\n \"\"\"\n Sorts a list using pancake sort algorithm.\n \"\"\"\n for size in range(len(arr), 1, -1):\n # Find the index of the maximum element in the unsorted part of the array\n max_index = arr.index(max(arr[:size]))\n \n # Move the maximum element to the end of the unsorted part of the array\n arr = arr[:max_index+1][::-1] + arr[max_index+1:]\n \n # Move the maximum element to the end of the entire array\n arr = arr[:size][::-1] + arr[size:]\n \n return arr", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(arr):\n # Helper function to flip the first k elements of the array\n def flip(sub_array, k):\n i = 0\n while i < k / 2:\n sub_array[i], sub_array[k - i - 1] = sub_array[k - i - 1], sub_array[i]\n i += 1\n return sub_array\n \n n = len(arr)\n while n > 1:\n # Find the index of the maximum element in the array\n mi = arr.index(max(arr[0:n]))\n \n # Flip the maximum element to the beginning of the array\n arr = flip(arr, mi + 1)\n \n # Flip the maximum element to its correct position\n arr = flip(arr, n)\n \n n -= 1\n \n return arr", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(lst):\n def flip(sub_list, k):\n i = 0\n while i < k:\n sub_list[i], sub_list[k] = sub_list[k], sub_list[i]\n i += 1\n k -= 1\n return sub_list\n\n n = len(lst)\n while n > 1:\n max_idx = lst.index(max(lst[0:n]))\n if max_idx != n - 1:\n if max_idx != 0:\n lst = flip(lst, max_idx)\n lst = flip(lst, n - 1)\n n -= 1\n return lst", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(arr):\n def flip(sub_arr, k):\n i = 0\n while i < k:\n sub_arr[i], sub_arr[k] = sub_arr[k], sub_arr[i]\n i += 1\n k -= 1\n\n n = len(arr)\n while n > 1:\n # Find the index of the maximum element in the unsorted part of the array\n mi = arr.index(max(arr[0:n]))\n if mi != n - 1:\n # Flip the maximum element to the top (beginning) if it's not already there\n if mi != 0:\n flip(arr, mi)\n # Flip the maximum element to the bottom (end) of the unsorted part\n flip(arr, n - 1)\n n -= 1\n return arr", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(lst):\n \"\"\"\n Sorts a list using pancake sort algorithm.\n :param lst: List of elements to be sorted.\n :return: Sorted list.\n \"\"\"\n def flip(sub_list, k):\n \"\"\"\n Reverses the order of the first k elements of the list.\n :param sub_list: List to be flipped.\n :param k: Number of elements to flip.\n :return: Flipped list.\n \"\"\"\n return sub_list[:k][::-1] + sub_list[k:]\n\n n = len(lst)\n while n > 1:\n # Find the index of the maximum element in the unsorted part of the list\n max_idx = lst.index(max(lst[:n]))\n\n # Move the maximum element to the beginning of the list if it's not already\n if max_idx != n - 1:\n if max_idx != 0:\n lst = flip(lst, max_idx + 1)\n lst = flip(lst, n)\n\n n -= 1\n return lst", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(arr):\n def flip(sub_arr, k):\n i = 0\n while i < k:\n sub_arr[i], sub_arr[k] = sub_arr[k], sub_arr[i]\n i += 1\n k -= 1\n\n n = len(arr)\n while n > 1:\n # Find the index of the maximum element in the unsorted part of the array\n mi = arr.index(max(arr[:n]))\n # Move the maximum element to the end of the unsorted part\n if mi != n - 1:\n # Flip the sub-array from the start to the position of the maximum element\n flip(arr, mi)\n # Flip the sub-array from the start to the end of the unsorted part\n flip(arr, n - 1)\n n -= 1\n return arr", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(lst):\n for size in range(len(lst), 1, -1):\n # Find the index of the maximum element in the unsorted part of the list\n max_index = lst.index(max(lst[:size]))\n \n # Move the maximum element to the end of the unsorted part\n lst = lst[max_index::-1] + lst[max_index+1:]\n \n # Move the maximum element to the end of the entire list\n lst = lst[size-1::-1] + lst[size:]\n \n return lst", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(arr):\n def flip(sub_arr, k):\n i = 0\n while i < k:\n sub_arr[i], sub_arr[k] = sub_arr[k], sub_arr[i]\n i += 1\n k -= 1\n\n n = len(arr)\n while n > 1:\n # Find the index of the maximum element in the unsorted part of the array\n mi = arr.index(max(arr[:n]))\n\n # Flip the maximum element to the front (or the end, depending on its current position)\n flip(arr, mi)\n\n # Flip the maximum element to its final position\n flip(arr, n - 1)\n\n n -= 1\n\n return arr", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(lst):\n def flip(sub_list, k):\n i = 0\n while i < k:\n sub_list[i], sub_list[k] = sub_list[k], sub_list[i]\n i += 1\n k -= 1\n return sub_list\n\n n = len(lst)\n while n > 1:\n # Find the index of the maximum element in the unsorted part of the list\n mi = lst.index(max(lst[0:n]))\n # Flip the list up to the maximum element to bring it to the front\n lst = flip(lst, mi)\n # Flip the list up to the end of the unsorted part to bubble it to the end\n lst = flip(lst, n - 1)\n n -= 1\n return lst", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(lst):\n for size in range(len(lst), 1, -1):\n # Find the index of the maximum element in the unsorted part of the list\n max_index = lst.index(max(lst[:size]))\n # If the maximum element is already in its correct position, continue\n if max_index == size - 1:\n continue\n # Reverse the list up to the maximum element to bring it to the start\n lst = lst[max_index::-1] + lst[max_index+1:]\n # Reverse the entire unsorted part to move the maximum element to its correct position\n lst = lst[size-1::-1] + lst[size:]\n return lst", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(lst):\n def flip(sub_list, k):\n i = 0\n while i < k:\n sub_list[i], sub_list[k] = sub_list[k], sub_list[i]\n i += 1\n k -= 1\n return sub_list\n\n n = len(lst)\n while n > 1:\n max_index = lst.index(max(lst[0:n]))\n lst = flip(lst, max_index)\n lst = flip(lst, n - 1)\n n -= 1\n return lst", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(lst):\n def flip(sub_list, k):\n return sub_list[:k][::-1] + sub_list[k:]\n\n arr = lst[:]\n n = len(arr)\n while n > 1:\n max_idx = arr.index(max(arr[:n]))\n if max_idx != n - 1:\n if max_idx != 0:\n arr = flip(arr, max_idx + 1)\n arr = flip(arr, n)\n n -= 1\n return arr", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(arr):\n \"\"\"\n Sort a list using pancake sort.\n \n :param arr: List[int] - The list to be sorted.\n :return: List[int] - The sorted list.\n \"\"\"\n n = len(arr)\n while n > 1:\n # Find the index of the maximum element in the unsorted part of the array\n mi = arr.index(max(arr[0:n]))\n \n # Flip the list up to and including the maximum element to bring it to the front\n arr = arr[mi::-1] + arr[mi+1:]\n \n # Flip the entire unsorted part of the list to bring the maximum element to its final position\n arr = arr[n-1::-1] + arr[n:]\n \n # Reduce the range of the unsorted part of the list\n n -= 1\n \n return arr", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(arr):\n def flip(sub_arr, k):\n i = 0\n while i < k:\n sub_arr[i], sub_arr[k] = sub_arr[k], sub_arr[i]\n i += 1\n k -= 1\n\n n = len(arr)\n while n > 1:\n # Find the index of the maximum element in the unsorted part of the array\n mi = arr.index(max(arr[:n]))\n\n # Flip the maximum element to the beginning of the array\n flip(arr, mi)\n\n # Flip the maximum element to the end of the unsorted part of the array\n flip(arr, n - 1)\n\n n -= 1\n\n return arr", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(lst):\n def flip(sub_list, k):\n return sub_list[:k][::-1] + sub_list[k:]\n\n arr = lst.copy()\n n = len(arr)\n while n > 1:\n # Find the index of the maximum element in the unsorted part of the list\n mi = arr.index(max(arr[:n]))\n \n # Flip the maximum element to the beginning of the list\n arr = flip(arr, mi + 1)\n \n # Flip the maximum element to its final position\n arr = flip(arr, n)\n \n n -= 1\n \n return arr", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(arr):\n def flip(sub_arr, k):\n i = 0\n while i < k:\n sub_arr[i], sub_arr[k] = sub_arr[k], sub_arr[i]\n i += 1\n k -= 1\n\n n = len(arr)\n while n > 1:\n # Find the index of the maximum element in the unsorted part of the array\n mi = arr.index(max(arr[:n]))\n \n # Flip the maximum element to the beginning of the array\n flip(arr, mi)\n \n # Flip the maximum element to the end of the unsorted part of the array\n flip(arr, n - 1)\n \n n -= 1\n \n return arr", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(arr):\n \"\"\"\n Sorts a list using the pancake sort algorithm.\n \"\"\"\n def flip(sub_list, k):\n \"\"\"\n Helper function to flip the first k elements of the sublist.\n \"\"\"\n return sub_list[:k][::-1] + sub_list[k:]\n\n n = len(arr)\n while n > 1:\n # Find the index of the maximum element in the unsorted part of the array\n mi = arr.index(max(arr[:n]))\n\n # Move the maximum element to the beginning of the array\n arr = flip(arr, mi + 1)\n\n # Move the maximum element to the end of the unsorted part of the array\n arr = flip(arr, n)\n\n # Reduce the size of the unsorted part of the array\n n -= 1\n\n return arr", "matching_cluster_idx": 3}]}, "Mbpp/166": {"dps": 94.39999999999999, "dps_norm": 50.0, "pass@1": 100.0, "profiled": [{"solution": "def find_even_pair(numbers):\n count = 0\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n if (numbers[i] ^ numbers[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(numbers):\n count = 0\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n if (numbers[i] ^ numbers[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(lst):\n count = 0\n for i in range(len(lst)):\n for j in range(i+1, len(lst)):\n if (lst[i] ^ lst[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(nums):\n count = 0\n for i in range(len(nums)):\n for j in range(i + 1, len(nums)):\n if (nums[i] ^ nums[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(nums):\n count = 0\n for i in range(len(nums)):\n for j in range(i+1, len(nums)):\n if (nums[i] ^ nums[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(nums):\n count = 0\n for i in range(len(nums)):\n for j in range(i + 1, len(nums)):\n if (nums[i] ^ nums[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(lst):\n count = 0\n for i in range(len(lst)):\n for j in range(i + 1, len(lst)):\n if (lst[i] ^ lst[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(numbers):\n count = 0\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n if (numbers[i] ^ numbers[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(numbers):\n count = 0\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n if (numbers[i] ^ numbers[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(numbers):\n count = 0\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n if (numbers[i] ^ numbers[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(nums):\n count = 0\n for i in range(len(nums)):\n for j in range(i + 1, len(nums)):\n if (nums[i] ^ nums[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(nums):\n count = 0\n for i in range(len(nums)):\n for j in range(i + 1, len(nums)):\n if (nums[i] ^ nums[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(numbers):\n count = 0\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n if (numbers[i] ^ numbers[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(numbers):\n count = 0\n for i in range(len(numbers)):\n for j in range(i+1, len(numbers)):\n if (numbers[i] ^ numbers[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(numbers):\n count = 0\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n if (numbers[i] ^ numbers[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(numbers):\n count = 0\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n if (numbers[i] ^ numbers[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(nums):\n count = 0\n for i in range(len(nums)):\n for j in range(i + 1, len(nums)):\n if (nums[i] ^ nums[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(nums):\n count = 0\n for i in range(len(nums)):\n for j in range(i + 1, len(nums)):\n if (nums[i] ^ nums[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(lst):\n count = 0\n for i in range(len(lst)):\n for j in range(i + 1, len(lst)):\n if (lst[i] ^ lst[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(lst):\n count = 0\n for i in range(len(lst)):\n for j in range(i + 1, len(lst)):\n if (lst[i] ^ lst[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}]}, "Mbpp/170": {"dps": 93.6231884057971, "dps_norm": 98.75, "pass@1": 66.0, "profiled": [{"solution": "def sum_range_list(numbers, start, end):\n return sum(numbers[start:end+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(lst, start, end):\n \"\"\"\n Function to find the sum of numbers in a list within a range specified by two indices.\n \"\"\"\n return sum(lst[start:end+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(numbers, start, end):\n # Ensure the start and end indices are within the bounds of the list\n start = max(0, start)\n end = min(len(numbers) - 1, end)\n \n # Sum the numbers in the specified range\n return sum(numbers[start:end+1])", "matching_cluster_idx": 6}, {"solution": "def sum_range_list(numbers, start, end):\n \"\"\"\n Calculate the sum of numbers in a list within a range specified by two indices.\n \n Args:\n numbers (list): A list of integers.\n start (int): The start index of the range.\n end (int): The end index of the range.\n \n Returns:\n int: The sum of numbers within the specified range.\n \"\"\"\n return sum(numbers[start:end+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(lst, start, end):\n \"\"\"\n Function to find the sum of numbers in a list within a range specified by two indices.\n \"\"\"\n return sum(lst[start:end+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(lst, start, end):\n \"\"\"\n Function to find the sum of numbers in a list within a range specified by two indices.\n \n Args:\n lst (list): The list of numbers.\n start (int): The start index of the range.\n end (int): The end index of the range.\n \n Returns:\n int: The sum of numbers in the specified range.\n \"\"\"\n return sum(lst[start:end+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(numbers, start, end):\n \"\"\"\n Returns the sum of numbers in the list within the specified range [start, end].\n \"\"\"\n return sum(numbers[start:end+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(numbers, start, end):\n \"\"\"\n This function calculates the sum of numbers in a list within a range specified by two indices.\n \n Args:\n numbers (list): A list of integers.\n start (int): The starting index (inclusive).\n end (int): The ending index (inclusive).\n \n Returns:\n int: The sum of numbers in the specified range.\n \"\"\"\n return sum(numbers[start:end+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(numbers, start, end):\n \"\"\"\n Function to find the sum of numbers in a list within a range specified by two indices.\n \"\"\"\n return sum(numbers[start:end+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(numbers, start, end):\n \"\"\"\n Sum the numbers in the list that fall within the specified range.\n\n Parameters:\n numbers (list): A list of integers.\n start (int): The start index (inclusive).\n end (int): The end index (inclusive).\n\n Returns:\n int: The sum of numbers within the specified range.\n \"\"\"\n return sum(numbers[start:end+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(nums, start, end):\n # Ensure the start and end indices are within the bounds of the list\n if start < 0 or end >= len(nums) or start > end:\n return 0\n # Sum the numbers within the specified range\n return sum(nums[start:end+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(nums, start, end):\n \"\"\"\n This function calculates the sum of numbers in the list nums between the indices start and end (inclusive).\n \n Parameters:\n nums (list): The list of numbers.\n start (int): The starting index (inclusive).\n end (int): The ending index (inclusive).\n \n Returns:\n int: The sum of numbers in the specified range.\n \"\"\"\n return sum(nums[start:end+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(numbers, start, end):\n \"\"\"\n Return the sum of numbers in the list within the specified range [start, end].\n \"\"\"\n return sum(numbers[start:end+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(lst, start, end):\n \"\"\"\n Find the sum of numbers in a list within a range specified by two indices.\n \"\"\"\n return sum(lst[start:end+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(lst, start, end):\n \"\"\"\n Function to find the sum of numbers in a list within a range specified by two indices.\n \"\"\"\n return sum(lst[start:end+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(nums, start, end):\n \"\"\"\n Calculate the sum of numbers in the list `nums` within the specified range [start, end].\n \n Args:\n nums (list): A list of numbers.\n start (int): The starting index of the range (inclusive).\n end (int): The ending index of the range (inclusive).\n \n Returns:\n int: The sum of numbers within the specified range.\n \"\"\"\n return sum(nums[start:end+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(numbers, start, end):\n \"\"\"\n This function calculates the sum of numbers in a list within a range specified by two indices.\n \n Parameters:\n numbers (list): A list of integers.\n start (int): The starting index (inclusive).\n end (int): The ending index (inclusive).\n \n Returns:\n int: The sum of numbers within the specified range.\n \"\"\"\n return sum(numbers[start:end+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(lst, start, end):\n # Ensure the start and end are within the bounds of the list\n start = max(start, 0)\n end = min(end, len(lst) - 1)\n \n # Sum the numbers in the specified range\n return sum(lst[start:end+1])", "matching_cluster_idx": 6}, {"solution": "def sum_range_list(nums, start, end):\n \"\"\"\n Find the sum of numbers in a list within a range specified by two indices.\n \"\"\"\n return sum(nums[start:end+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(lst, start, end):\n \"\"\"\n This function takes a list of numbers and two indices, and returns the sum of numbers within the range [start, end].\n \"\"\"\n return sum(lst[start:end+1])", "matching_cluster_idx": 7}]}, "Mbpp/226": {"dps": 72.984496124031, "dps_norm": 27.142857142857142, "pass@1": 97.0, "profiled": [{"solution": "def odd_values_string(s):\n return s[::2]", "matching_cluster_idx": 6}, {"solution": "def odd_values_string(s):\n return ''.join(s[i] for i in range(len(s)) if i % 2 == 0)", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(s):\n result = \"\"\n for i in range(len(s)):\n if i % 2 == 0:\n result += s[i]\n return result", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(s):\n result = \"\"\n for i in range(len(s)):\n if i % 2 == 0:\n result += s[i]\n return result", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(s):\n result = \"\"\n for i in range(len(s)):\n if i % 2 == 0:\n result += s[i]\n return result", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(s):\n return ''.join(s[i] for i in range(len(s)) if i % 2 == 0)", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(s):\n return ''.join(s[i] for i in range(len(s)) if i % 2 == 0)", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(s):\n result = \"\"\n for i in range(len(s)):\n if i % 2 == 0:\n result += s[i]\n return result", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(s):\n result = \"\"\n for i in range(len(s)):\n if i % 2 == 0:\n result += s[i]\n return result", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(s):\n result = \"\"\n for i in range(len(s)):\n if i % 2 == 0:\n result += s[i]\n return result", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(s):\n return ''.join(s[i] for i in range(len(s)) if i % 2 == 0)", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(s):\n result = ''\n for i in range(len(s)):\n if i % 2 == 0:\n result += s[i]\n return result", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(s):\n return ''.join(s[i] for i in range(len(s)) if i % 2 == 0)", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(s):\n return s[::2]", "matching_cluster_idx": 6}, {"solution": "def odd_values_string(s):\n return ''.join(s[i] for i in range(len(s)) if i % 2 == 0)", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(s):\n result = \"\"\n for i in range(len(s)):\n if i % 2 == 0:\n result += s[i]\n return result", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(s):\n result = \"\"\n for i in range(len(s)):\n if i % 2 == 0:\n result += s[i]\n return result", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(s):\n return s[::2] # Using slicing to select every second character", "matching_cluster_idx": 6}, {"solution": "def odd_values_string(s):\n result = \"\"\n for i in range(len(s)):\n if i % 2 == 0:\n result += s[i]\n return result", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(s):\n result = \"\"\n for i in range(len(s)):\n if i % 2 == 0:\n result += s[i]\n return result", "matching_cluster_idx": 0}]}, "Mbpp/230": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def replace_blank(s, char):\n return s.replace(\" \", char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string, char):\n return input_string.replace(\" \", char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(text, char):\n return text.replace(\" \", char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(text, char):\n return text.replace(' ', char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(text, char):\n return text.replace(\" \", char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(string, char):\n return string.replace(' ', char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(string, char):\n return string.replace(\" \", char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(text, char):\n \"\"\"\n This function replaces all blank spaces in a given string with a specified character.\n \n Parameters:\n text (str): The input string where spaces need to be replaced.\n char (str): The character to replace the spaces with.\n \n Returns:\n str: The string with spaces replaced by the specified character.\n \"\"\"\n return text.replace(' ', char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(string, char):\n return string.replace(\" \", char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(string, char):\n return string.replace(' ', char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(s: str, char: str) -> str:\n \"\"\"\n Replace all blank spaces in the given string with the specified character.\n \n Parameters:\n s (str): The input string.\n char (str): The character to replace spaces with.\n \n Returns:\n str: The string with spaces replaced by the specified character.\n \"\"\"\n return s.replace(' ', char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string, replacement_char):\n return input_string.replace(' ', replacement_char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string, replacement_char):\n return input_string.replace(' ', replacement_char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(string, char):\n return string.replace(\" \", char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(string, char):\n return string.replace(\" \", char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(string, character):\n return string.replace(' ', character)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(string, character):\n return string.replace(\" \", character)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(string, char):\n \"\"\"\n Replace blank spaces in a string with a specified character.\n \n Args:\n string (str): The input string.\n char (str): The character to replace spaces with.\n \n Returns:\n str: The string with spaces replaced by the specified character.\n \"\"\"\n return string.replace(' ', char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(s, char):\n return s.replace(' ', char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(string, char):\n return string.replace(' ', char)", "matching_cluster_idx": 7}]}, "Mbpp/239": {"dps": 75.17241379310344, "dps_norm": 77.0, "pass@1": 36.0, "profiled": [{"solution": "def get_total_number_of_sequences(m, n):\n # Initialize a memoization table\n memo = {}\n\n def count_sequences(current, length):\n # If the sequence length is n, we have found a valid sequence\n if length == n:\n return 1\n # If we exceed the length, return 0 as it's not a valid sequence\n if length > n:\n return 0\n # Use memoization to store already computed sequences\n if (current, length) in memo:\n return memo[(current, length)]\n\n total = 0\n # Generate the next possible element\n for next_element in range(current * 2, m + 1):\n total += count_sequences(next_element, length + 1)\n # Store the result in memoization table\n memo[(current, length)] = total\n return total\n\n # Start the sequence with each possible starting element\n return sum(count_sequences(i, 1) for i in range(1, m + 1))", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n # Create a memoization table where dp[i][j] represents the number of ways to\n # form a sequence of length i where the last element is j.\n dp = [[0] * (m + 1) for _ in range(n + 1)]\n \n # Base case: There is 1 way to form a sequence of length 1 with any element.\n for j in range(1, m + 1):\n dp[1][j] = 1\n \n # Fill the dp table\n for i in range(2, n + 1): # For each sequence length from 2 to n\n for j in range(1, m + 1): # For each possible last element value from 1 to m\n for k in range(1, j // 2 + 1): # Sum over all valid previous elements\n dp[i][j] += dp[i - 1][k]\n \n # The answer is the sum of all possible sequences of length n\n return sum(dp[n])", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n # Initialize a memoization table where dp[i][j] represents the number of sequences of length j ending with the number i\n dp = [[0] * (n + 1) for _ in range(m + 1)]\n \n # There is one way to have a sequence of length 1: the number itself (base case)\n for i in range(1, m + 1):\n dp[i][1] = 1\n \n # Fill the dp table\n for j in range(2, n + 1):\n for i in range(1, m + 1):\n for k in range(1, i // 2 + 1): # k is the previous number in the sequence\n dp[i][j] += dp[k][j - 1]\n \n # Sum up all sequences of length n\n total = 0\n for i in range(1, m + 1):\n total += dp[i][n]\n \n return total", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n # Initialize a 2D DP array where dp[i][j] represents the number of ways to have a sequence of length j ending with the number i\n dp = [[0] * (n + 1) for _ in range(m + 1)]\n\n # There is 1 way to have a sequence of length 1 with any number i (just the number i itself)\n for i in range(1, m + 1):\n dp[i][1] = 1\n\n # Fill the DP table\n for j in range(2, n + 1): # Sequence length\n for i in range(1, m + 1): # Ending number\n for k in range(2 * i, m + 1): # Previous number must be at least twice the current number\n dp[i][j] += dp[k][j - 1]\n\n # Sum up all the sequences of length n\n total_sequences = 0\n for i in range(1, m + 1):\n total_sequences += dp[i][n]\n\n return total_sequences", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n # Initialize a memoization table where dp[i][j] represents the number of sequences of length j ending with the number i\n dp = [[0] * (n + 1) for _ in range(m + 1)]\n \n # Base case: there's 1 way to have a sequence of length 1 (only the number itself)\n for i in range(1, m + 1):\n dp[i][1] = 1\n \n # Fill the dp table\n for j in range(2, n + 1): # For each sequence length from 2 to n\n for i in range(1, m + 1): # For each possible end number\n for k in range(1, i // 2 + 1): # For each possible previous number\n dp[i][j] += dp[k][j - 1]\n \n # Sum up all the sequences of length n\n total_sequences = sum(dp[i][n] for i in range(1, m + 1))\n return total_sequences", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n def count_sequences(start, length):\n if length == 0:\n return 1\n count = 0\n for next_element in range(start * 2, m + 1):\n count += count_sequences(next_element, length - 1)\n return count\n\n total_count = 0\n for start in range(1, m + 1):\n total_count += count_sequences(start, n - 1)\n return total_count", "matching_cluster_idx": 5}, {"solution": "def get_total_number_of_sequences(m, n):\n # Initialize a memoization table where dp[i][j] represents the number of ways to form a sequence of length j ending with the number i\n dp = [[0] * (n + 1) for _ in range(m + 1)]\n \n # There is one way to form a sequence of length 1, which is the number itself\n for i in range(1, m + 1):\n dp[i][1] = 1\n \n # Fill the dp table\n for j in range(2, n + 1):\n for i in range(1, m + 1):\n for k in range(2 * i, m + 1):\n dp[i][j] += dp[k][j - 1]\n \n # Sum up all possible sequences of length n\n total_sequences = 0\n for i in range(1, m + 1):\n total_sequences += dp[i][n]\n \n return total_sequences", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n # Initialize a cache for memoization\n cache = {}\n\n def count_sequences(prev, length):\n # If the sequence length is n, return 1 (a valid sequence is found)\n if length == n:\n return 1\n # If the current state is cached, return the cached result\n if (prev, length) in cache:\n return cache[(prev, length)]\n\n # Initialize the count of sequences\n count = 0\n # Iterate over the possible next numbers\n for next_num in range(prev * 2, m + 1):\n # Recursively count sequences starting with the next number\n count += count_sequences(next_num, length + 1)\n # Cache the result and return it\n cache[(prev, length)] = count\n return count\n\n # Start the sequence with a number between 1 and m\n total_count = 0\n for start in range(1, m + 1):\n total_count += count_sequences(start, 1)\n\n return total_count", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n # Initialize a memoization table with -1 to indicate uncomputed values\n memo = [[-1 for _ in range(n + 1)] for _ in range(m + 1)]\n\n def count_sequences(prev, length):\n # If we have reached the desired length, return 1 for a valid sequence\n if length == n:\n return 1\n # If the result is already computed, return it\n if memo[prev][length] != -1:\n return memo[prev][length]\n # Initialize the count for the current length and previous value\n count = 0\n # Iterate over possible next values based on the problem constraints\n for next_val in range(prev * 2, m + 1):\n # Recursively count sequences with the next value\n count += count_sequences(next_val, length + 1)\n # Memoize the computed result\n memo[prev][length] = count\n return count\n\n # Start the recursion with each possible starting value\n total_count = 0\n for start in range(1, m + 1):\n total_count += count_sequences(start, 1)\n return total_count", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n # Memoization dictionary to store the results of subproblems\n memo = {}\n\n def count_sequences(start, length):\n # If we have reached the desired length, return 1 (one valid sequence)\n if length == 0:\n return 1\n # If the result for this state is already computed, return it\n if (start, length) in memo:\n return memo[(start, length)]\n\n # Initialize the count for this state\n count = 0\n # Iterate over possible next numbers\n for next_num in range(start * 2, m + 1):\n count += count_sequences(next_num, length - 1)\n # Store the result in memo before returning\n memo[(start, length)] = count\n return count\n\n # Start the recursion with each number from 1 to m as a possible starting point\n total_count = 0\n for start in range(1, m + 1):\n total_count += count_sequences(start, n - 1)\n\n return total_count", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n # Initialize a memoization table where dp[i][j] represents the number of ways to form a sequence of length j ending with i\n dp = [[0] * (n + 1) for _ in range(m + 1)]\n \n # There is one way to form a sequence of length 1 with any number, which is the number itself\n for i in range(1, m + 1):\n dp[i][1] = 1\n \n # Fill the dp table\n for j in range(2, n + 1):\n for i in range(1, m + 1):\n for k in range(1, i // 2 + 1):\n dp[i][j] += dp[k][j - 1]\n \n # Sum up all the ways to form sequences of length n\n total_ways = 0\n for i in range(1, m + 1):\n total_ways += dp[i][n]\n \n return total_ways", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n # Memoization dictionary to store computed values\n memo = {}\n\n def count_sequences(start, length):\n if length == 0:\n return 1\n if (start, length) in memo:\n return memo[(start, length)]\n\n total = 0\n for next_element in range(start * 2, m + 1):\n total += count_sequences(next_element, length - 1)\n memo[(start, length)] = total\n return total\n\n total_sequences = 0\n for first_element in range(1, m + 1):\n total_sequences += count_sequences(first_element, n - 1)\n\n return total_sequences", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n \"\"\"\n This function calculates the number of possible sequences of length n, where each element is a positive integer\n and is greater than or equal to twice the previous element but less than or equal to m.\n \n Args:\n m (int): The upper bound for the elements in the sequence.\n n (int): The length of the sequence.\n \n Returns:\n int: The total number of sequences that satisfy the given conditions.\n \"\"\"\n \n # Initialize a cache to store the results of subproblems\n cache = {}\n \n def dp(prev, length):\n \"\"\"\n A helper function that uses dynamic programming to find the number of sequences.\n \n Args:\n prev (int): The previous element in the sequence.\n length (int): The current length of the sequence.\n \n Returns:\n int: The number of sequences that can be formed.\n \"\"\"\n if (prev, length) in cache:\n return cache[(prev, length)]\n \n if length == n:\n return 1\n \n count = 0\n for next_val in range(prev * 2, m + 1):\n count += dp(next_val, length + 1)\n \n cache[(prev, length)] = count\n return count\n \n total_count = 0\n for start in range(1, m + 1):\n total_count += dp(start, 1)\n \n return total_count", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n def count_sequences(current, length):\n if length == 1:\n return 1\n count = 0\n for next_value in range(current * 2, m + 1):\n count += count_sequences(next_value, length - 1)\n return count\n \n total_count = 0\n for start in range(1, m + 1):\n total_count += count_sequences(start, n)\n return total_count", "matching_cluster_idx": 5}, {"solution": "def get_total_number_of_sequences(m, n):\n # Initialize a cache for memoization\n cache = {}\n\n def count_sequences(prev, length):\n # Base case: if the sequence length is n, we found a valid sequence\n if length == n:\n return 1\n # If the result is already in the cache, return it\n if (prev, length) in cache:\n return cache[(prev, length)]\n \n # Initialize the count of sequences\n count = 0\n # Iterate over possible next elements\n for next_element in range(prev * 2, m + 1):\n # Recursively count sequences from the next element\n count += count_sequences(next_element, length + 1)\n \n # Cache the result and return\n cache[(prev, length)] = count\n return count\n\n # Start the sequence with the smallest possible element\n total_sequences = 0\n for start in range(1, m + 1):\n total_sequences += count_sequences(start, 1)\n \n return total_sequences", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n def count_sequences(prev, length):\n if length == n:\n return 1\n count = 0\n for next_val in range(prev * 2, m + 1):\n count += count_sequences(next_val, length + 1)\n return count\n\n total_count = 0\n for start in range(1, m + 1):\n total_count += count_sequences(start, 1)\n return total_count", "matching_cluster_idx": 5}, {"solution": "def get_total_number_of_sequences(m, n):\n # Initialize a memoization table where dp[i][j] represents the number of ways\n # to have a sequence of length j ending with the number i\n dp = [[0] * (n + 1) for _ in range(m + 1)]\n \n # Base case: There is 1 way to have a sequence of length 1 with any number i\n for i in range(1, m + 1):\n dp[i][1] = 1\n \n # Fill the dp table\n for j in range(2, n + 1):\n for i in range(1, m + 1):\n for k in range(2 * i, m + 1):\n dp[i][j] += dp[k][j - 1]\n \n # Sum all possible sequences of length n\n total = 0\n for i in range(1, m + 1):\n total += dp[i][n]\n \n return total", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n # Initialize a memoization table\n memo = {}\n\n def count_sequences(prev, length):\n # If we have reached the desired length, return 1 as a valid sequence\n if length == n:\n return 1\n # Use memoization to store results of subproblems\n if (prev, length) in memo:\n return memo[(prev, length)]\n \n count = 0\n # Generate the next element in the sequence\n for next_el in range(prev * 2, m + 1):\n count += count_sequences(next_el, length + 1)\n \n # Store the result in memoization table\n memo[(prev, length)] = count\n return count\n\n # Start the sequence with each number from 1 to m\n total_count = 0\n for start in range(1, m + 1):\n total_count += count_sequences(start, 1)\n\n return total_count", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n # Initialize a list to store the number of ways to reach each length of sequence\n dp = [[0] * (m + 1) for _ in range(n + 1)]\n \n # There is one way to reach a sequence of length 0, which is to have no elements\n for j in range(m + 1):\n dp[0][j] = 1\n \n # Fill the dp table\n for i in range(1, n + 1): # For each length of sequence\n for j in range(1, m + 1): # For each possible last element\n # Sum the ways to reach this length with each valid previous element\n for k in range(2 * j, m + 1):\n dp[i][j] += dp[i - 1][k]\n \n # The result is the sum of the ways to reach the desired length with each valid last element\n return sum(dp[n - 1])", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n # Initialize a DP table where dp[i][j] represents the number of ways to have a sequence of length j ending with the number i\n dp = [[0] * (n + 1) for _ in range(m + 1)]\n \n # Base case: There is 1 way to have a sequence of length 1 with any number i, which is the number itself\n for i in range(1, m + 1):\n dp[i][1] = 1\n \n # Fill the DP table\n for j in range(2, n + 1):\n for i in range(1, m + 1):\n for k in range(1, i // 2 + 1):\n dp[i][j] += dp[k][j - 1]\n \n # Sum all possible sequences of length n\n total_sequences = 0\n for i in range(1, m + 1):\n total_sequences += dp[i][n]\n \n return total_sequences", "matching_cluster_idx": 7}]}, "Mbpp/240": {"dps": 80.48780487804879, "dps_norm": 88.88888888888889, "pass@1": 39.0, "profiled": [{"solution": "def replace_list(list1, list2):\n \"\"\"\n Replaces the last element of the first list with the elements of the second list.\n \"\"\"\n if list1: # Check if list1 is not empty\n list1[-1:] = list2 # Replace the last element of list1 with elements of list2\n else:\n list1.extend(list2) # If list1 is empty, extend it with list2\n return list1", "matching_cluster_idx": 7}, {"solution": "def replace_list(list1, list2):\n # Check if list1 has at least one element to ensure we can replace the last element\n if list1:\n # Replace the last element of list1 with all elements of list2\n list1[-1:] = list2\n else:\n # If list1 is empty, just append list2 to it\n list1.extend(list2)\n return list1", "matching_cluster_idx": 7}, {"solution": "def replace_list(list1, list2):\n # Check if list1 is empty to avoid index out of range error\n if not list1:\n return list2\n # Replace the last element of list1 with the elements of list2\n list1[-1:] = list2\n return list1", "matching_cluster_idx": 7}, {"solution": "def replace_list(list1, list2):\n # Check if list1 is empty, if so, replace its first element with list2\n if not list1:\n list1.extend(list2)\n else:\n # Replace the last element of list1 with the first element of list2\n list1[-1:] = list2\n return list1", "matching_cluster_idx": 7}, {"solution": "def replace_list(list1, list2):\n \"\"\"\n This function replaces the last element of the first list with the elements of the second list.\n \"\"\"\n if list1:\n list1[-1:] = list2\n else:\n list1.extend(list2)\n return list1", "matching_cluster_idx": 7}, {"solution": "def replace_list(list1, list2):\n # Replace the last element of list1 with the elements of list2\n list1[-1:] = list2\n return list1", "matching_cluster_idx": 7}, {"solution": "def replace_list(list1, list2):\n if list1:\n list1[-1:] = list2\n else:\n list1.extend(list2)\n return list1", "matching_cluster_idx": 7}, {"solution": "def replace_list(list1, list2):\n if list1: # Check if list1 is not empty\n list1[-1:] = list2 # Replace the last element of list1 with the elements of list2\n else:\n list1.extend(list2) # If list1 is empty, extend it with list2\n return list1", "matching_cluster_idx": 7}, {"solution": "def replace_list(list1, list2):\n if list1: # Check if list1 is not empty\n list1[-1:] = list2 # Replace the last element of list1 with elements of list2\n else:\n list1.extend(list2) # If list1 is empty, extend it with list2\n return list1", "matching_cluster_idx": 7}, {"solution": "def replace_list(list1, list2):\n # Replace the last element of list1 with all elements of list2\n if list1: # Check if list1 is not empty\n list1[-1:] = list2\n else:\n list1.extend(list2) # If list1 is empty, extend it with list2\n return list1", "matching_cluster_idx": 7}, {"solution": "def replace_list(list1, list2):\n # Replace the last element of list1 with the elements of list2\n list1[-1:] = list2\n return list1", "matching_cluster_idx": 7}, {"solution": "def replace_list(list1, list2):\n # Check if the first list is not empty\n if list1:\n # Replace the last element of the first list with the elements of the second list\n list1[-1:] = list2\n else:\n # If the first list is empty, extend it with the second list\n list1.extend(list2)\n return list1", "matching_cluster_idx": 7}, {"solution": "def replace_list(list1, list2):\n \"\"\"\n Replaces the last element of the first list with the elements of the second list.\n \"\"\"\n if list1:\n list1[-1:] = list2\n else:\n return list2 # If list1 is empty, return list2 as the new list\n return list1", "matching_cluster_idx": 7}, {"solution": "def replace_list(list1, list2):\n if list1:\n list1[-1:] = list2\n else:\n list1.extend(list2)\n return list1", "matching_cluster_idx": 7}, {"solution": "def replace_list(list1, list2):\n if list1: # Check if list1 is not empty\n list1[-1:] = list2 # Replace the last element of list1 with the elements of list2\n else:\n list1.extend(list2) # If list1 is empty, extend it with list2\n return list1", "matching_cluster_idx": 7}, {"solution": "def replace_list(list1, list2):\n # Check if list1 has at least one element to ensure we can replace the last element\n if list1:\n # Replace the last element of list1 with the elements of list2\n list1[-1:] = list2\n else:\n # If list1 is empty, just extend list2 to list1\n list1.extend(list2)\n return list1", "matching_cluster_idx": 7}, {"solution": "def replace_list(list1, list2):\n \"\"\"\n Replaces the last element of the first list with the elements of the second list.\n \"\"\"\n if list1: # Check if list1 is not empty\n list1[-1:] = list2 # Replace the last element of list1 with all elements of list2\n else:\n list1.extend(list2) # If list1 is empty, extend it with list2\n return list1", "matching_cluster_idx": 7}, {"solution": "def replace_list(list1, list2):\n if list1: # Check if list1 is not empty\n list1[-1:] = list2 # Replace the last element of list1 with all elements of list2\n else:\n list1.extend(list2) # If list1 is empty, extend it with list2\n return list1", "matching_cluster_idx": 7}, {"solution": "def replace_list(list1, list2):\n # Replace the last element of list1 with elements of list2\n if list1: # Check if list1 is not empty\n list1[-1:] = list2\n else: # If list1 is empty, extend it with list2\n list1.extend(list2)\n return list1", "matching_cluster_idx": 7}, {"solution": "def replace_list(list1, list2):\n if list1: # Check if list1 is not empty\n list1[-1:] = list2 # Replace the last element of list1 with elements of list2\n else:\n list1.extend(list2) # If list1 is empty, extend it with list2\n return list1", "matching_cluster_idx": 7}]}, "Mbpp/251": {"dps": 91.95402298850576, "dps_norm": 77.77777777777777, "pass@1": 100.0, "profiled": [{"solution": "def insert_element(lst, elem):\n result = []\n for item in lst:\n result.append(elem)\n result.append(item)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, elem):\n result = []\n for item in lst:\n result.append(elem)\n result.append(item)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n result = []\n for item in lst:\n result.append(element)\n result.append(item)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n result = []\n for item in lst:\n result.append(element)\n result.append(item)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n result = []\n for item in lst:\n result.append(element)\n result.append(item)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, elem):\n result = []\n for item in lst:\n result.append(elem)\n result.append(item)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, elem):\n result = []\n for item in lst:\n result.append(elem)\n result.append(item)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n result = []\n for item in lst:\n result.append(element)\n result.append(item)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n result = []\n for item in lst:\n result.append(element)\n result.append(item)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n result = []\n for item in lst:\n result.append(element)\n result.append(item)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n result = []\n for item in lst:\n result.append(element)\n result.append(item)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n result = []\n for item in lst:\n result.append(element)\n result.append(item)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n result = []\n for item in lst:\n result.append(element)\n result.append(item)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n result = []\n for item in lst:\n result.append(element)\n result.append(item)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n result = []\n for item in lst:\n result.append(element)\n result.append(item)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n result = []\n for item in lst:\n result.append(element)\n result.append(item)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n result = []\n for item in lst:\n result.append(element)\n result.append(item)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n result = []\n for item in lst:\n result.append(element)\n result.append(item)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n result = []\n for item in lst:\n result.append(element)\n result.append(item)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, elem):\n result = []\n for item in lst:\n result.append(elem)\n result.append(item)\n return result", "matching_cluster_idx": 6}]}, "Mbpp/256": {"dps": 72.23744292237443, "dps_norm": 67.05882352941177, "pass@1": 100.0, "profiled": [{"solution": "def is_prime(n):\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True\ndef count_Primes_nums(n):\n count = 0\n for i in range(2, n):\n if is_prime(i):\n count += 1\n return count", "matching_cluster_idx": 10}, {"solution": "def is_prime(n):\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True\ndef count_Primes_nums(n):\n count = 0\n for i in range(2, n):\n if is_prime(i):\n count += 1\n return count", "matching_cluster_idx": 10}, {"solution": "def is_prime(n):\n \"\"\"Check if a number is a prime number.\"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True\ndef count_Primes_nums(num):\n \"\"\"Count the number of prime numbers less than the given non-negative number.\"\"\"\n count = 0\n for i in range(2, num):\n if is_prime(i):\n count += 1\n return count", "matching_cluster_idx": 10}, {"solution": "def is_prime(n):\n \"\"\"Check if a number is prime.\"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True\ndef count_Primes_nums(n):\n \"\"\"Count the number of prime numbers less than n.\"\"\"\n if n <= 2:\n return 0\n count = 0\n for i in range(2, n):\n if is_prime(i):\n count += 1\n return count", "matching_cluster_idx": 10}, {"solution": "def is_prime(n):\n \"\"\"Check if a number is a prime.\"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True\ndef count_Primes_nums(n):\n \"\"\"Return the number of prime numbers less than n.\"\"\"\n count = 0\n for i in range(2, n):\n if is_prime(i):\n count += 1\n return count", "matching_cluster_idx": 10}, {"solution": "def count_Primes_nums(n: int) -> int:\n if n <= 2:\n return 0\n \n sieve = [True] * n\n sieve[0] = sieve[1] = False\n \n for i in range(2, int(n**0.5) + 1):\n if sieve[i]:\n for j in range(i*i, n, i):\n sieve[j] = False\n \n return sum(sieve)", "matching_cluster_idx": 14}, {"solution": "def is_prime(n):\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True\ndef count_Primes_nums(num):\n count = 0\n for i in range(2, num):\n if is_prime(i):\n count += 1\n return count", "matching_cluster_idx": 10}, {"solution": "def is_prime(n):\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True\ndef count_Primes_nums(n):\n count = 0\n for i in range(2, n):\n if is_prime(i):\n count += 1\n return count", "matching_cluster_idx": 10}, {"solution": "def is_prime(num):\n \"\"\"Helper function to check if a number is prime.\"\"\"\n if num <= 1:\n return False\n if num <= 3:\n return True\n if num % 2 == 0 or num % 3 == 0:\n return False\n i = 5\n while i * i <= num:\n if num % i == 0 or num % (i + 2) == 0:\n return False\n i += 6\n return True\ndef count_Primes_nums(n):\n \"\"\"Function to count prime numbers less than a given non-negative number n.\"\"\"\n if n <= 2:\n return 0\n count = 0\n for i in range(2, n):\n if is_prime(i):\n count += 1\n return count", "matching_cluster_idx": 10}, {"solution": "def is_prime(n):\n \"\"\"Check if a number is prime.\"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True\ndef count_Primes_nums(n):\n \"\"\"Count the number of prime numbers less than a non-negative number.\"\"\"\n count = 0\n for i in range(2, n):\n if is_prime(i):\n count += 1\n return count", "matching_cluster_idx": 10}, {"solution": "def is_prime(n):\n \"\"\"Check if a number is prime.\"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True\ndef count_Primes_nums(n):\n \"\"\"Return the number of prime numbers less than n.\"\"\"\n count = 0\n for i in range(2, n):\n if is_prime(i):\n count += 1\n return count", "matching_cluster_idx": 10}, {"solution": "def is_prime(n):\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True\ndef count_Primes_nums(num):\n count = 0\n for i in range(2, num):\n if is_prime(i):\n count += 1\n return count", "matching_cluster_idx": 10}, {"solution": "def is_prime(num):\n if num <= 1:\n return False\n if num <= 3:\n return True\n if num % 2 == 0 or num % 3 == 0:\n return False\n i = 5\n while i * i <= num:\n if num % i == 0 or num % (i + 2) == 0:\n return False\n i += 6\n return True\ndef count_Primes_nums(n):\n count = 0\n for i in range(2, n):\n if is_prime(i):\n count += 1\n return count", "matching_cluster_idx": 10}, {"solution": "def is_prime(n):\n \"\"\"Check if a number is prime.\"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True\ndef count_Primes_nums(num):\n \"\"\"Count the number of prime numbers less than a given non-negative number.\"\"\"\n count = 0\n for i in range(2, num):\n if is_prime(i):\n count += 1\n return count", "matching_cluster_idx": 10}, {"solution": "def count_Primes_nums(n):\n if n <= 2:\n return 0\n is_prime = [True] * n\n is_prime[0] = is_prime[1] = False\n for i in range(2, int(n**0.5) + 1):\n if is_prime[i]:\n for j in range(i*i, n, i):\n is_prime[j] = False\n return sum(is_prime)", "matching_cluster_idx": 14}, {"solution": "def is_prime(n):\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True\ndef count_Primes_nums(n):\n count = 0\n for i in range(2, n):\n if is_prime(i):\n count += 1\n return count", "matching_cluster_idx": 10}, {"solution": "def is_prime(num):\n \"\"\"Check if a number is a prime number.\"\"\"\n if num <= 1:\n return False\n if num <= 3:\n return True\n if num % 2 == 0 or num % 3 == 0:\n return False\n i = 5\n while i * i <= num:\n if num % i == 0 or num % (i + 2) == 0:\n return False\n i += 6\n return True\ndef count_Primes_nums(n):\n \"\"\"Return the number of prime numbers less than n.\"\"\"\n count = 0\n for i in range(2, n):\n if is_prime(i):\n count += 1\n return count", "matching_cluster_idx": 10}, {"solution": "def is_prime(n):\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True\ndef count_Primes_nums(n):\n count = 0\n for i in range(2, n):\n if is_prime(i):\n count += 1\n return count", "matching_cluster_idx": 10}, {"solution": "def is_prime(n):\n \"\"\"Check if a number is prime.\"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True\ndef count_Primes_nums(n):\n \"\"\"Count the number of prime numbers less than n.\"\"\"\n count = 0\n for i in range(2, n):\n if is_prime(i):\n count += 1\n return count", "matching_cluster_idx": 10}, {"solution": "def is_prime(n):\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True\ndef count_Primes_nums(num):\n count = 0\n for i in range(2, num):\n if is_prime(i):\n count += 1\n return count", "matching_cluster_idx": 10}]}, "Mbpp/265": {"dps": 52.73255813953489, "dps_norm": 69.16666666666667, "pass@1": 94.0, "profiled": [{"solution": "def list_split(lst, n):\n # Initialize an empty list to hold the resulting sublists\n result = []\n \n # Iterate over the range of indices, stepping by n each time\n for i in range(n):\n # For each starting index, create a sublist of every nth element\n sublist = [lst[j] for j in range(i, len(lst), n)]\n # Append the sublist to the result list\n result.append(sublist)\n \n return result", "matching_cluster_idx": 1}, {"solution": "def list_split(lst, n):\n return [lst[i::n] for i in range(n)]", "matching_cluster_idx": 5}, {"solution": "def list_split(lst, n):\n \"\"\"\n Splits a list into sublists with every nth element.\n \n Args:\n lst (list): The list to be split.\n n (int): The interval at which to split the list.\n \n Returns:\n list: A list of lists, where each sublist contains every nth element from the original list.\n \"\"\"\n return [lst[i::n] for i in range(n)]", "matching_cluster_idx": 5}, {"solution": "def list_split(lst, n):\n \"\"\"\n Splits a list into sublists for every nth element.\n \n Parameters:\n lst (list): The input list to be split.\n n (int): The interval at which to split the list.\n \n Returns:\n list of lists: A list containing sublists of every nth element.\n \"\"\"\n return [lst[i::n] for i in range(n)]", "matching_cluster_idx": 5}, {"solution": "def list_split(lst, n):\n # Initialize an empty list to hold the resulting lists\n result = []\n \n # Iterate over the list, stepping by n each time\n for i in range(n):\n # For each starting point, create a sublist by stepping by n\n sublist = [lst[j] for j in range(i, len(lst), n)]\n # Append the sublist to the result\n result.append(sublist)\n \n return result", "matching_cluster_idx": 1}, {"solution": "def list_split(lst, n):\n # Create a list to hold the resulting sublists\n result = []\n \n # Iterate over the indices of the list, stepping by n\n for i in range(n):\n # Create a sublist starting from index i and stepping by n each time\n sublist = [lst[j] for j in range(i, len(lst), n)]\n # Append the sublist to the result list\n result.append(sublist)\n \n return result", "matching_cluster_idx": 1}, {"solution": "def list_split(lst, n):\n # Initialize an empty list to store the resulting sublists\n result = []\n \n # Iterate over the list in steps of n\n for i in range(n):\n # Create a sublist starting from index i and incrementing by n each time\n sublist = [lst[j] for j in range(i, len(lst), n)]\n # Append the sublist to the result\n result.append(sublist)\n \n return result", "matching_cluster_idx": 1}, {"solution": "def list_split(lst, n):\n \"\"\"\n Splits a list into sublists, taking every nth element.\n \n Args:\n lst (list): The list to be split.\n n (int): The interval at which to split the list.\n \n Returns:\n List[List[Any]]: A list of lists, where each sublist contains every nth element from the original list.\n \"\"\"\n return [lst[i::n] for i in range(n)]", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n # Create a list to hold the result\n result = []\n # Iterate over the list in steps of n\n for i in range(n):\n # Create a sublist starting from index i and step by n\n sublist = [lst[j] for j in range(i, len(lst), n)]\n result.append(sublist)\n return result", "matching_cluster_idx": 1}, {"solution": "def list_split(lst, n):\n \"\"\"\n Splits a list into sublists, taking every nth element from the original list.\n \n Parameters:\n lst (list): The list to be split.\n n (int): The interval at which to take elements.\n \n Returns:\n List[List]: A list of sublists, where each sublist contains every nth element from the original list.\n \"\"\"\n return [lst[i::n] for i in range(n)]", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n \"\"\"\n Splits a list for every nth element and returns a list of the resulting lists.\n \n Args:\n lst (list): The list to be split.\n n (int): The interval at which to split the list.\n \n Returns:\n list: A list of lists, each containing every nth element from the original list.\n \"\"\"\n return [lst[i::n] for i in range(n)]", "matching_cluster_idx": 4}, {"solution": "def list_split(input_list, n):\n # Initialize an empty list to store the resulting lists\n result = []\n \n # Iterate over the indices of the input list, stepping by n\n for i in range(n):\n # For each starting index, create a sublist from the input list\n sublist = [input_list[j] for j in range(i, len(input_list), n)]\n # Append the sublist to the result list\n result.append(sublist)\n \n return result", "matching_cluster_idx": 1}, {"solution": "def list_split(lst, n):\n # Create an empty list to hold the resulting sublists\n result = []\n \n # Iterate over the list, step by n elements\n for i in range(n):\n # Create a sublist for every nth element\n sublist = [lst[j] for j in range(i, len(lst), n)]\n # Append the sublist to the result list\n result.append(sublist)\n \n return result", "matching_cluster_idx": 1}, {"solution": "def list_split(lst, n):\n \"\"\"\n Splits a list into sublists, grouping every nth element.\n \n Args:\n lst (list): The list to be split.\n n (int): The interval at which to split the list.\n \n Returns:\n list: A list of sublists, each containing every nth element from the original list.\n \"\"\"\n return [lst[i::n] for i in range(n)]", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n \"\"\"\n Splits a list into sublists of length n.\n \n Args:\n lst (list): The list to be split.\n n (int): The number of elements per sublist.\n \n Returns:\n List[List]: A list of sublists.\n \"\"\"\n return [lst[i::n] for i in range(n)]", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n \"\"\"\n Splits a list for every nth element, returning a list of the resulting lists.\n \"\"\"\n return [lst[i::n] for i in range(n)]", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n \"\"\"\n Splits a list into sublists based on every nth element.\n \n Args:\n lst (list): The list to be split.\n n (int): The interval at which to split the list.\n \n Returns:\n List[List[Any]]: A list of lists containing the elements split according to the nth interval.\n \"\"\"\n return [lst[i::n] for i in range(n)]", "matching_cluster_idx": 5}, {"solution": "def list_split(lst, n):\n \"\"\"\n Splits a list into sublists, each containing every nth element from the original list.\n \n Parameters:\n lst (list): The list to be split.\n n (int): The interval at which to split the list.\n \n Returns:\n list of lists: A list containing sublists of nth elements from the original list.\n \"\"\"\n return [lst[i::n] for i in range(n)]", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n \"\"\"\n Splits a list for every nth element, returning a list of the resulting lists.\n \"\"\"\n return [lst[i::n] for i in range(n)]", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n \"\"\"\n Splits a list into sublists, taking every nth element.\n \n Args:\n lst (list): The list to be split.\n n (int): The interval at which to split the list.\n \n Returns:\n list of lists: A list of lists containing elements from the original list, taken every nth element.\n \"\"\"\n if n <= 0:\n raise ValueError(\"n must be a positive integer\")\n \n return [lst[i::n] for i in range(n)]", "matching_cluster_idx": 4}]}, "Mbpp/281": {"dps": 94.4, "dps_norm": 85.45454545454545, "pass@1": 100.0, "profiled": [{"solution": "def all_unique(lst):\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n seen = set()\n for item in lst:\n if item in seen:\n return False\n seen.add(item)\n return True", "matching_cluster_idx": 9}, {"solution": "def all_unique(lst):\n seen = set()\n return not any(item in seen or seen.add(item) for item in lst)", "matching_cluster_idx": 9}, {"solution": "def all_unique(lst):\n \"\"\"\n Check if all elements in the list are unique.\n \n Args:\n lst (list): A list of elements to check.\n \n Returns:\n bool: True if all elements are unique, False otherwise.\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n seen = set()\n for item in lst:\n if item in seen:\n return False\n seen.add(item)\n return True", "matching_cluster_idx": 9}, {"solution": "def all_unique(lst):\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n seen = set()\n return not any(item in seen or seen.add(item) for item in lst)", "matching_cluster_idx": 9}, {"solution": "def all_unique(lst):\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n seen = set()\n for item in lst:\n if item in seen:\n return False\n seen.add(item)\n return True", "matching_cluster_idx": 9}, {"solution": "def all_unique(lst):\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n Check if all elements in the list are unique.\n \n Args:\n lst (list): The list of elements to check.\n \n Returns:\n bool: True if all elements are unique, False otherwise.\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n seen = set()\n for item in lst:\n if item in seen:\n return False\n seen.add(item)\n return True", "matching_cluster_idx": 9}, {"solution": "def all_unique(lst):\n seen = set()\n for item in lst:\n if item in seen:\n return False\n seen.add(item)\n return True", "matching_cluster_idx": 9}, {"solution": "def all_unique(lst):\n seen = set()\n for item in lst:\n if item in seen:\n return False\n seen.add(item)\n return True", "matching_cluster_idx": 9}, {"solution": "def all_unique(lst):\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}]}, "Mbpp/296": {"dps": 30.51282051282051, "dps_norm": 67.5, "pass@1": 100.0, "profiled": [{"solution": "def get_Inv_Count(arr):\n \"\"\"\n This function calculates the number of inversions in an array using a brute force method.\n An inversion in an array a[] is a pair (a[i], a[j]) such that i < j and a[i] > a[j].\n \"\"\"\n inv_count = 0\n for i in range(len(arr)):\n for j in range(i + 1, len(arr)):\n if arr[i] > arr[j]:\n inv_count += 1\n return inv_count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n # Initialize the inversion count\n inv_count = 0\n # Iterate through the array\n for i in range(len(arr)):\n for j in range(i + 1, len(arr)):\n # Check if the element at the later index is smaller than the element at the current index\n if arr[i] > arr[j]:\n inv_count += 1\n return inv_count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n inv_count = 0\n n = len(arr)\n for i in range(n):\n for j in range(i + 1, n):\n if arr[i] > arr[j]:\n inv_count += 1\n return inv_count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n n = len(arr)\n inv_count = 0\n for i in range(n):\n for j in range(i + 1, n):\n if arr[i] > arr[j]:\n inv_count += 1\n return inv_count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n \"\"\"\n This function counts the number of inversions in an array.\n An inversion is a pair (i, j) where i < j and arr[i] > arr[j].\n \"\"\"\n inv_count = 0\n for i in range(len(arr)):\n for j in range(i + 1, len(arr)):\n if arr[i] > arr[j]:\n inv_count += 1\n return inv_count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n inv_count = 0\n for i in range(len(arr)):\n for j in range(i + 1, len(arr)):\n if arr[i] > arr[j]:\n inv_count += 1\n return inv_count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n inv_count = 0\n for i in range(len(arr)):\n for j in range(i + 1, len(arr)):\n if arr[i] > arr[j]:\n inv_count += 1\n return inv_count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n def merge_sort_and_count(arr, temp_arr, left, right):\n inv_count = 0\n if left < right:\n mid = (left + right) // 2\n inv_count += merge_sort_and_count(arr, temp_arr, left, mid)\n inv_count += merge_sort_and_count(arr, temp_arr, mid + 1, right)\n inv_count += merge_and_count(arr, temp_arr, left, mid, right)\n return inv_count\n\n def merge_and_count(arr, temp_arr, left, mid, right):\n i = left # Starting index for left subarray\n j = mid + 1 # Starting index for right subarray\n k = left # Starting index to be sorted in temp_arr\n inv_count = 0\n\n # Conditions are checked to ensure that i doesn't exceed mid and j doesn't exceed right\n while i <= mid and j <= right:\n if arr[i] <= arr[j]:\n temp_arr[k] = arr[i]\n i += 1\n else:\n # There are mid - i inversions, because all elements left to i in the left subarray are greater than arr[j]\n temp_arr[k] = arr[j]\n inv_count += (mid - i + 1)\n j += 1\n k += 1\n\n # Copy the remaining elements of left subarray, if any\n while i <= mid:\n temp_arr[k] = arr[i]\n i += 1\n k += 1\n\n # Copy the remaining elements of right subarray, if any\n while j <= right:\n temp_arr[k] = arr[j]\n j += 1\n k += 1\n\n # Copy the sorted subarray into Original array\n for loop_var in range(left, right + 1):\n arr[loop_var] = temp_arr[loop_var]\n\n return inv_count\n\n n = len(arr)\n temp_arr = [0] * n\n return merge_sort_and_count(arr, temp_arr, 0, n - 1)", "matching_cluster_idx": 5}, {"solution": "def get_Inv_Count(arr):\n inv_count = 0\n for i in range(len(arr)):\n for j in range(i + 1, len(arr)):\n if arr[i] > arr[j]:\n inv_count += 1\n return inv_count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n \"\"\"\n Function to count inversions in an array.\n \"\"\"\n n = len(arr)\n inv_count = 0\n for i in range(n):\n for j in range(i + 1, n):\n if arr[i] > arr[j]:\n inv_count += 1\n return inv_count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n inv_count = 0\n for i in range(len(arr)):\n for j in range(i + 1, len(arr)):\n if arr[i] > arr[j]:\n inv_count += 1\n return inv_count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n inv_count = 0\n n = len(arr)\n for i in range(n):\n for j in range(i + 1, n):\n if arr[i] > arr[j]:\n inv_count += 1\n return inv_count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n n = len(arr)\n inv_count = 0\n for i in range(n):\n for j in range(i + 1, n):\n if arr[i] > arr[j]:\n inv_count += 1\n return inv_count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n inv_count = 0\n n = len(arr)\n for i in range(n):\n for j in range(i + 1, n):\n if arr[i] > arr[j]:\n inv_count += 1\n return inv_count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n \"\"\"\n This function counts the number of inversions in the array.\n An inversion is a pair (i, j) where arr[i] > arr[j] and i < j.\n \"\"\"\n n = len(arr)\n inv_count = 0\n for i in range(n):\n for j in range(i + 1, n):\n if arr[i] > arr[j]:\n inv_count += 1\n return inv_count", "matching_cluster_idx": 2}, {"solution": "def get_Inv_Count(arr):\n inv_count = 0\n for i in range(len(arr)):\n for j in range(i + 1, len(arr)):\n if arr[i] > arr[j]:\n inv_count += 1\n return inv_count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n inv_count = 0\n for i in range(len(arr)):\n for j in range(i + 1, len(arr)):\n if arr[i] > arr[j]:\n inv_count += 1\n return inv_count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n # Initialize the inversion count\n inv_count = 0\n \n # Loop through the array to compare elements\n for i in range(len(arr)):\n for j in range(i + 1, len(arr)):\n if arr[i] > arr[j]:\n inv_count += 1\n \n return inv_count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n n = len(arr)\n inv_count = 0\n for i in range(n):\n for j in range(i + 1, n):\n if arr[i] > arr[j]:\n inv_count += 1\n return inv_count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n inv_count = 0\n for i in range(len(arr)):\n for j in range(i + 1, len(arr)):\n if arr[i] > arr[j]:\n inv_count += 1\n return inv_count", "matching_cluster_idx": 3}]}, "Mbpp/308": {"dps": 87.65517241379311, "dps_norm": 64.16666666666667, "pass@1": 94.0, "profiled": [{"solution": "def large_product(list1, list2, num):\n # Create a list of products by multiplying each element of list1 with each element of list2\n products = [a * b for a in list1 for b in list2]\n \n # Sort the products in descending order\n products.sort(reverse=True)\n \n # Return the top 'num' largest products\n return products[:num]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n # Create a list of products by multiplying elements from both lists\n products = [a * b for a in list1 for b in list2]\n \n # Sort the products in descending order\n products.sort(reverse=True)\n \n # Return the top n largest products\n return products[:n]", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef large_product(list1: List[int], list2: List[int], n: int) -> List[int]:\n # Create a list of products\n products = [x * y for x in list1 for y in list2]\n # Sort the products in descending order\n products.sort(reverse=True)\n # Return the top n products\n return products[:n]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n # Combine products of each element in list1 with each element in list2\n products = [a * b for a in list1 for b in list2]\n # Sort the products in descending order\n sorted_products = sorted(products, reverse=True)\n # Return the top n largest products\n return sorted_products[:n]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n # Calculate all possible products\n products = [a * b for a in list1 for b in list2]\n \n # Sort the products in descending order\n sorted_products = sorted(products, reverse=True)\n \n # Return the top n products\n return sorted_products[:n]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n # Create a list of all possible products\n products = [x * y for x in list1 for y in list2]\n # Sort the products in descending order\n products.sort(reverse=True)\n # Return the top n products\n return products[:n]", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef large_product(list1: List[int], list2: List[int], n: int) -> List[int]:\n # Calculate the products of each element from list1 with each element from list2\n products = [a * b for a in list1 for b in list2]\n # Sort the products in descending order\n products.sort(reverse=True)\n # Return the top n products\n return products[:n]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n # Create a list of products by multiplying each element of list1 with each element of list2\n products = [a * b for a in list1 for b in list2]\n # Sort the products in descending order\n products.sort(reverse=True)\n # Return the top n largest products\n return products[:n]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n # Create a list of products by multiplying each element of list1 with each element of list2\n products = [x * y for x in list1 for y in list2]\n \n # Sort the products in descending order\n products.sort(reverse=True)\n \n # Return the top n largest products\n return products[:n]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, num):\n # Calculate the products of each element in list1 with each element in list2\n products = [a * b for a in list1 for b in list2]\n # Sort the products in descending order\n products.sort(reverse=True)\n # Return the specified number of largest products\n return products[:num]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n # Pair elements from both lists and calculate their products\n products = [(a * b, a, b) for a in list1 for b in list2]\n # Sort the products in descending order\n sorted_products = sorted(products, key=lambda x: x[0], reverse=True)\n # Extract the top n largest products\n top_n_products = [product[0] for product in sorted_products[:n]]\n return top_n_products", "matching_cluster_idx": 2}, {"solution": "def large_product(list1, list2, n):\n # Create a list of tuples (product, index from list1, index from list2)\n products = [(a * b, i, j) for i, a in enumerate(list1) for j, b in enumerate(list2)]\n \n # Sort the products by their values in descending order\n products.sort(key=lambda x: -x[0])\n \n # Extract the top n products\n top_products = [product[0] for product in products[:n]]\n \n return top_products", "matching_cluster_idx": 2}, {"solution": "def large_product(list1, list2, n):\n # Calculate the products of each element in list1 with each element in list2\n products = [a * b for a in list1 for b in list2]\n # Sort the products in descending order\n sorted_products = sorted(products, reverse=True)\n # Return the top n largest products\n return sorted_products[:n]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, num_products):\n # Calculate all possible products\n products = [a * b for a in list1 for b in list2]\n # Sort the products in descending order\n sorted_products = sorted(products, reverse=True)\n # Return the specified number of largest products\n return sorted_products[:num_products]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n # Create a list of products by multiplying elements from both lists\n products = [a * b for a in list1 for b in list2]\n # Sort the products in descending order\n products.sort(reverse=True)\n # Return the top 'n' largest products\n return [products[i] for i in range(n)]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n # Calculate all products of elements from list1 and list2\n products = [a * b for a in list1 for b in list2]\n \n # Sort the products in descending order\n products.sort(reverse=True)\n \n # Return the top n largest products\n return products[:n]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n # Calculate all possible products\n products = [x * y for x in list1 for y in list2]\n \n # Sort the products in descending order\n products.sort(reverse=True)\n \n # Return the top n largest products\n return products[:n]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n # Create a list of tuples combining elements from both lists along with their product\n combined = [(a * b, a, b) for a in list1 for b in list2]\n \n # Sort the combined list by the product in descending order\n combined.sort(key=lambda x: x[0], reverse=True)\n \n # Extract the top 'n' products\n top_n_products = [combined[i][0] for i in range(n)]\n \n return top_n_products", "matching_cluster_idx": 2}, {"solution": "def large_product(list1, list2, n):\n # Generate all possible products from multiplying one element from list1 with one from list2\n products = [a * b for a in list1 for b in list2]\n \n # Sort the products in descending order\n products.sort(reverse=True)\n \n # Return the top n largest products\n return products[:n]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n # Create a list of products by multiplying each element of list1 with each element of list2\n products = [a * b for a in list1 for b in list2]\n # Sort the products in descending order\n products.sort(reverse=True)\n # Return the top n largest products\n return products[:n]", "matching_cluster_idx": 3}]}, "Mbpp/392": {"dps": 62.67605633802817, "dps_norm": 66.15384615384616, "pass@1": 66.0, "profiled": [{"solution": "def get_max_sum(n):\n # Base case: if n is less than 2, the maximum sum is n itself\n if n < 2:\n return n\n \n # Initialize a list to store the maximum sum for each number up to n\n max_sum = [0] * (n + 1)\n max_sum[0] = 0\n max_sum[1] = 1\n \n # Compute the maximum sum for each number from 2 to n\n for i in range(2, n + 1):\n max_sum[i] = max(max_sum[i // 2] + max_sum[i // 3] + max_sum[i // 4] + max_sum[i // 5], i)\n \n return max_sum[n]", "matching_cluster_idx": 10}, {"solution": "def get_max_sum(n):\n # Create a memoization table to store previously computed values\n memo = {0: 0, 1: 1}\n\n # Define a recursive function to find the maximum sum\n def max_sum(x):\n # Check if the value is already computed\n if x in memo:\n return memo[x]\n\n # Compute the value using the given equation\n result = max(max_sum(x // 2) + max_sum(x // 3) + max_sum(x // 4) + max_sum(x // 5), x)\n\n # Store the computed value in the memoization table\n memo[x] = result\n\n return result\n\n # Call the recursive function for the given input\n return max_sum(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n # Base case: if n is less than 2, the maximum sum is n itself\n if n < 2:\n return n\n \n # Initialize the maximum sum for the current number\n max_sum = n\n \n # Calculate the maximum sum by recursively evaluating f(n/2), f(n/3), f(n/4), and f(n/5)\n if n // 2 > 0:\n max_sum = max(max_sum, get_max_sum(n // 2) + get_max_sum(n // 3) + get_max_sum(n // 4) + get_max_sum(n // 5))\n \n return max_sum", "matching_cluster_idx": 3}, {"solution": "def get_max_sum(n):\n # Base case: if n is less than or equal to 1, return n\n if n <= 1:\n return n\n \n # Calculate the maximum sum using the given equation\n max_sum = max(get_max_sum(n // 2) + get_max_sum(n // 3) + get_max_sum(n // 4) + get_max_sum(n // 5), n)\n \n return max_sum", "matching_cluster_idx": 3}, {"solution": "def get_max_sum(n):\n # Create a memoization table to store previously computed values\n memo = {0: 0, 1: 1}\n \n # Define a helper function for memoization\n def dp(x):\n if x in memo:\n return memo[x]\n memo[x] = max(dp(x // 2) + dp(x // 3) + dp(x // 4) + dp(x // 5), x)\n return memo[x]\n \n # Call the helper function for the given n\n return dp(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n if n == 0:\n return 0\n if n in memo:\n return memo[n]\n result = max(get_max_sum(n // 2) + get_max_sum(n // 3) + get_max_sum(n // 4) + get_max_sum(n // 5), n)\n memo[n] = result\n return result\nmemo = {}", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n # Base case: if n is less than 2, the maximum sum is n itself\n if n < 2:\n return n\n \n # Initialize a list to store the maximum sum for each number up to n\n max_sum = [0] * (n + 1)\n max_sum[1] = 1 # Base case: max_sum(1) = 1\n \n # Compute the maximum sum for each number from 2 to n\n for i in range(2, n + 1):\n max_sum[i] = max(max_sum[i // 2] + max_sum[i // 3] + max_sum[i // 4] + max_sum[i // 5], i)\n \n return max_sum[n]", "matching_cluster_idx": 10}, {"solution": "def get_max_sum(n):\n # Base case: if n is less than 2, return n\n if n < 2:\n return n\n \n # Initialize a list to store the computed max sums for each number up to n\n max_sums = [0] * (n + 1)\n \n # Set the base case for max_sums[0] and max_sums[1]\n max_sums[0] = 0\n max_sums[1] = 1\n \n # Compute the max sum for each number from 2 to n\n for i in range(2, n + 1):\n max_sums[i] = max(max_sums[i // 2] + max_sums[i // 3] + max_sums[i // 4] + max_sums[i // 5], i)\n \n # Return the max sum for the given n\n return max_sums[n]", "matching_cluster_idx": 10}, {"solution": "def get_max_sum(n):\n # Create a memoization table to store already computed values\n memo = {0: 0, 1: 1}\n\n # Define a recursive function to compute the maximum sum\n def max_sum(x):\n if x in memo:\n return memo[x]\n result = max(max_sum(x // 2) + max_sum(x // 3) + max_sum(x // 4) + max_sum(x // 5), x)\n memo[x] = result\n return result\n\n # Compute the maximum sum for the given n\n return max_sum(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n # Base case: if n is less than 2, the maximum sum is n itself\n if n < 2:\n return n\n \n # Initialize a list to store the maximum sums for each number up to n\n max_sums = [0] * (n + 1)\n \n # Set the base case for the maximum sum of 0 and 1\n max_sums[0], max_sums[1] = 0, 1\n \n # Compute the maximum sum for each number from 2 to n\n for i in range(2, n + 1):\n max_sums[i] = max(max_sums[i // 2] + max_sums[i // 3] + max_sums[i // 4] + max_sums[i // 5], i)\n \n # Return the maximum sum for the given number n\n return max_sums[n]", "matching_cluster_idx": 10}, {"solution": "def get_max_sum(n):\n # Create a memoization table to store previously computed results\n memo = {0: 0, 1: 1}\n\n # Define a helper function for recursion with memoization\n def helper(x):\n if x in memo:\n return memo[x]\n result = max(helper(x // 2) + helper(x // 3) + helper(x // 4) + helper(x // 5), x)\n memo[x] = result\n return result\n\n # Compute the maximum sum for the given n\n return helper(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n # Base case: if n is less than or equal to 1, return n\n if n <= 1:\n return n\n\n # Calculate the maximum sum using the given equation\n max_sum = max(get_max_sum(n // 2) + get_max_sum(n // 3) + get_max_sum(n // 4) + get_max_sum(n // 5), n)\n return max_sum", "matching_cluster_idx": 3}, {"solution": "def get_max_sum(n):\n # Create a memoization table to store already computed values\n memo = {0: 0, 1: 1}\n \n # Define a helper function for recursive computation with memoization\n def helper(x):\n if x in memo:\n return memo[x]\n # Compute the maximum sum using the given equation\n memo[x] = max(helper(x // 2) + helper(x // 3) + helper(x // 4) + helper(x // 5), x)\n return memo[x]\n \n # Compute the maximum sum for the given n\n return helper(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n # Base case: if n is less than or equal to 1, return n\n if n <= 1:\n return n\n \n # Calculate the maximum sum for the current value of n\n max_sum = max(get_max_sum(n // 2) + get_max_sum(n // 3) + get_max_sum(n // 4) + get_max_sum(n // 5), n)\n return max_sum", "matching_cluster_idx": 3}, {"solution": "def get_max_sum(n):\n # Base case: if n is less than or equal to 1, return n\n if n <= 1:\n return n\n \n # Calculate the maximum sum using the given equation\n max_sum = max(get_max_sum(n // 2) + get_max_sum(n // 3) + get_max_sum(n // 4) + get_max_sum(n // 5), n)\n \n return max_sum", "matching_cluster_idx": 3}, {"solution": "def get_max_sum(n):\n # Base case: if n is less than or equal to 1, return n\n if n <= 1:\n return n\n \n # Calculate the maximum sum using the given equation\n max_sum = max(get_max_sum(n // 2) + get_max_sum(n // 3) + get_max_sum(n // 4) + get_max_sum(n // 5), n)\n return max_sum", "matching_cluster_idx": 3}, {"solution": "def get_max_sum(n):\n # Base case: if n is less than 2, return n (since f(n) = max(f(n/2) + f(n/3) + f(n/4) + f(n/5), n) for n >= 2)\n if n < 2:\n return n\n \n # Initialize the maximum sum to n\n max_sum = n\n \n # Calculate the sum of f(n/2), f(n/3), f(n/4), and f(n/5) and compare with n\n if n // 2 > 0:\n max_sum = max(max_sum, get_max_sum(n // 2) + get_max_sum(n // 3) + get_max_sum(n // 4) + get_max_sum(n // 5))\n \n return max_sum", "matching_cluster_idx": 3}, {"solution": "def get_max_sum(n):\n # Base cases\n if n == 0:\n return 0\n if n <= 2:\n return n\n \n # Recursive case\n return max(get_max_sum(n // 2) + get_max_sum(n // 3) + get_max_sum(n // 4) + get_max_sum(n // 5), n)", "matching_cluster_idx": 4}, {"solution": "def get_max_sum(n):\n # Create a memoization table to store already computed values\n memo = {0: 0, 1: 1}\n \n # Define a recursive function with memoization\n def compute_max_sum(x):\n if x in memo:\n return memo[x]\n # Compute the maximum sum for the current value using the given equation\n max_sum = max(compute_max_sum(x // 2) + compute_max_sum(x // 3) + compute_max_sum(x // 4) + compute_max_sum(x // 5), x)\n memo[x] = max_sum\n return max_sum\n \n # Compute and return the maximum sum for the given number n\n return compute_max_sum(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n # Base case: if n is less than 2, the max sum is n itself.\n if n < 2:\n return n\n \n # Calculate the maximum sum for the given value of n.\n max_sum = max(get_max_sum(n // 2) + get_max_sum(n // 3) + get_max_sum(n // 4) + get_max_sum(n // 5), n)\n return max_sum", "matching_cluster_idx": 3}]}, "Mbpp/395": {"dps": 98.08429118773947, "dps_norm": 75.0, "pass@1": 100.0, "profiled": [{"solution": "def first_non_repeating_character(s):\n # Create a dictionary to count occurrences of each character\n char_count = {}\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n \n # Find the first character with a count of 1\n for char in s:\n if char_count[char] == 1:\n return char\n \n # If no non-repeated character is found, return None\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n \"\"\"\n Function to find the first non-repeated character in a given string.\n \"\"\"\n # Create a dictionary to store the frequency of each character\n frequency = {}\n \n # Populate the frequency dictionary\n for char in s:\n if char in frequency:\n frequency[char] += 1\n else:\n frequency[char] = 1\n \n # Find the first character with a frequency of 1\n for char in s:\n if frequency[char] == 1:\n return char\n \n # If no non-repeated character is found, return None\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n char_order = []\n ctr = {}\n \n # Count the occurrences of each character\n for c in s:\n if c in ctr:\n ctr[c] += 1\n else:\n ctr[c] = 1\n char_order.append(c)\n \n # Find the first non-repeated character\n for c in char_order:\n if ctr[c] == 1:\n return c\n \n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n # Create a dictionary to keep track of character counts\n char_count = {}\n \n # Count the occurrences of each character in the string\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n \n # Find the first character with a count of 1\n for char in s:\n if char_count[char] == 1:\n return char\n \n # If no non-repeating character is found, return None\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n # Create a dictionary to store the count of each character\n char_count = {}\n \n # Populate the dictionary with the count of each character\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n \n # Find the first character with a count of 1\n for char in s:\n if char_count[char] == 1:\n return char\n \n # If no non-repeating character is found, return None\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n char_order = []\n counts = {}\n for c in s:\n if c in counts:\n counts[c] += 1\n else:\n counts[c] = 1\n char_order.append(c)\n \n for c in char_order:\n if counts[c] == 1:\n return c\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n char_order = []\n ctr = {}\n \n # Count the frequency of each character\n for c in s:\n if c in ctr:\n ctr[c] += 1\n else:\n ctr[c] = 1\n char_order.append(c)\n \n # Find the first character that has a frequency of 1\n for c in char_order:\n if ctr[c] == 1:\n return c\n \n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n char_order = []\n counts = {}\n for c in s:\n if c in counts:\n counts[c] += 1\n else:\n counts[c] = 1\n char_order.append(c)\n \n for c in char_order:\n if counts[c] == 1:\n return c\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n char_order = []\n ctr = {}\n \n # Build the count and order dictionaries\n for c in s:\n if c in ctr:\n ctr[c] += 1\n else:\n ctr[c] = 1\n char_order.append(c)\n \n # Find the first non-repeating character\n for c in char_order:\n if ctr[c] == 1:\n return c\n \n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n char_order = []\n ctr = {}\n \n # Counting occurrences of each character\n for c in s:\n if c in ctr:\n ctr[c] += 1\n else:\n ctr[c] = 1\n char_order.append(c)\n \n # Finding the first character that occurs only once\n for c in char_order:\n if ctr[c] == 1:\n return c\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n char_order = []\n counts = {}\n for c in s:\n if c in counts:\n counts[c] += 1\n else:\n counts[c] = 1\n char_order.append(c)\n for c in char_order:\n if counts[c] == 1:\n return c\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(string):\n # Create a dictionary to count the frequency of each character\n char_count = {}\n \n # Count the frequency of each character in the string\n for char in string:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n \n # Find the first character that has a frequency of 1\n for char in string:\n if char_count[char] == 1:\n return char\n \n # If no non-repeated character is found, return None\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n \"\"\"\n This function finds the first non-repeated character in a given string.\n If all characters are repeated or the string is empty, it returns None.\n \"\"\"\n char_order = []\n ctr = {}\n \n # Count the occurrences of each character\n for c in s:\n if c in ctr:\n ctr[c] += 1\n else:\n ctr[c] = 1\n char_order.append(c)\n \n # Find the first character with a count of 1\n for c in char_order:\n if ctr[c] == 1:\n return c\n \n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n # Create a dictionary to count the frequency of each character\n char_count = {}\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n \n # Find the first character with a count of 1\n for char in s:\n if char_count[char] == 1:\n return char\n \n # If no non-repeating character is found, return None\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n # Create a dictionary to count the occurrences of each character\n char_count = {}\n \n # Count the occurrences of each character in the string\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n \n # Find the first character that has a count of 1\n for char in s:\n if char_count[char] == 1:\n return char\n \n # If no non-repeating character is found, return None\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n # Create a dictionary to keep track of character counts\n char_count = {}\n \n # Count the occurrences of each character in the string\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n \n # Find the first character that occurs only once\n for char in s:\n if char_count[char] == 1:\n return char\n \n # If no non-repeating character is found, return None\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n char_order = []\n ctr = {}\n for c in s:\n if c in ctr:\n ctr[c] += 1\n else:\n ctr[c] = 1\n char_order.append(c)\n for c in char_order:\n if ctr[c] == 1:\n return c\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n # Create a dictionary to keep track of character counts\n char_count = {}\n \n # Populate the dictionary with character counts\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n \n # Find the first character with a count of 1\n for char in s:\n if char_count[char] == 1:\n return char\n \n # If no non-repeating character is found, return None\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n char_order = []\n ctr = {}\n for c in s:\n if c in ctr:\n ctr[c] += 1\n else:\n ctr[c] = 1\n char_order.append(c)\n for c in char_order:\n if ctr[c] == 1:\n return c\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n # Create a dictionary to keep track of character counts\n char_count = {}\n \n # Count the occurrences of each character in the string\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n \n # Find the first character that has a count of 1\n for char in s:\n if char_count[char] == 1:\n return char\n \n # If no non-repeating character is found, return None\n return None", "matching_cluster_idx": 5}]}, "Mbpp/405": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def check_tuplex(tuplex, element):\n \"\"\"\n This function checks whether an element exists within a tuple.\n \n Args:\n tuplex (tuple): The tuple in which to check for the element.\n element: The element to check for within the tuple.\n \n Returns:\n bool: True if the element is found in the tuple, False otherwise.\n \"\"\"\n return element in tuplex", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, element):\n return element in tuplex", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(test_tup, element_to_check):\n \"\"\"\n Check if the element exists within the tuple.\n \n Args:\n test_tup (tuple): The tuple to search within.\n element_to_check (any): The element to check for in the tuple.\n \n Returns:\n bool: True if the element is found, False otherwise.\n \"\"\"\n return element_to_check in test_tup", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, element):\n \"\"\"\n Check whether an element exists within a tuple.\n \"\"\"\n return element in tuplex", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, element):\n \"\"\"\n This function checks whether an element exists within a tuple.\n \n Args:\n tuplex (tuple): The tuple to check for the element.\n element: The element to look for within the tuple.\n \n Returns:\n bool: True if the element exists in the tuple, False otherwise.\n \"\"\"\n return element in tuplex", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, element):\n \"\"\"\n Check whether an element exists within a tuple.\n \"\"\"\n return element in tuplex", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, element):\n \"\"\"\n Check if an element exists within a tuple.\n \n Args:\n tuplex (tuple): The tuple to search within.\n element: The element to search for.\n \n Returns:\n bool: True if the element exists in the tuple, False otherwise.\n \"\"\"\n return element in tuplex", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(test_tup, element_to_check):\n result = element_to_check in test_tup\n return result", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, element):\n return element in tuplex", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, element):\n return element in tuplex", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, element):\n return element in tuplex", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, element):\n return element in tuplex", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, element):\n \"\"\"\n This function checks whether an element exists within a tuple.\n \"\"\"\n return element in tuplex", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, element):\n return element in tuplex", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, element):\n \"\"\"\n Check if the element exists within the tuple.\n \n Args:\n tuplex (tuple): The tuple to check within.\n element: The element to look for in the tuple.\n \n Returns:\n bool: True if the element exists in the tuple, False otherwise.\n \"\"\"\n return element in tuplex", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, element):\n \"\"\"\n This function checks whether an element exists within a tuple.\n \"\"\"\n return element in tuplex", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, element):\n \"\"\"\n Check whether an element exists within a tuple.\n \"\"\"\n return element in tuplex", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, element):\n return element in tuplex", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, element):\n \"\"\"\n This function checks whether an element exists within a tuple.\n \"\"\"\n return element in tuplex", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, element):\n return element in tuplex", "matching_cluster_idx": 3}]}, "Mbpp/414": {"dps": 88.60248447204968, "dps_norm": 87.77777777777777, "pass@1": 100.0, "profiled": [{"solution": "def overlapping(seq1, seq2):\n for item in seq1:\n if item in seq2:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n for item in seq1:\n if item in seq2:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Check if there is any value in seq1 that also exists in seq2.\n \"\"\"\n for item in seq1:\n if item in seq2:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n for item in seq1:\n if item in seq2:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n for item in seq1:\n if item in seq2:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Check if there is any value in the first sequence that also exists in the second sequence.\n \"\"\"\n for item in seq1:\n if item in seq2:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Check whether any value in the first sequence exists in the second sequence.\n \n Args:\n seq1 (list): The first sequence of values.\n seq2 (list): The second sequence of values.\n \n Returns:\n bool: True if there is at least one overlapping value, False otherwise.\n \"\"\"\n return bool(set(seq1) & set(seq2))", "matching_cluster_idx": 5}, {"solution": "def overlapping(seq1, seq2):\n for item in seq1:\n if item in seq2:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n for item in seq1:\n if item in seq2:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(list1, list2):\n for item in list1:\n if item in list2:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n for item in seq1:\n if item in seq2:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n for item in seq1:\n if item in seq2:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n for item in seq1:\n if item in seq2:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n for item in seq1:\n if item in seq2:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n for item in seq1:\n if item in seq2:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(list1, list2):\n for item in list1:\n if item in list2:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Check whether any value in the first sequence exists in the second sequence.\n \"\"\"\n return any(item in seq2 for item in seq1)", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n for item in seq1:\n if item in seq2:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n for item in seq1:\n if item in seq2:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Check if any value in the first sequence exists in the second sequence.\n \"\"\"\n for item in seq1:\n if item in seq2:\n return True\n return False", "matching_cluster_idx": 7}]}, "Mbpp/421": {"dps": 24.48559670781893, "dps_norm": 73.57142857142857, "pass@1": 92.0, "profiled": [{"solution": "def concatenate_tuple(input_tuple):\n # Convert the tuple to a list to use the join method\n str_list = [str(item) for item in input_tuple]\n # Concatenate elements with the delimiter '-'\n result = '-'.join(str_list)\n return result", "matching_cluster_idx": 5}, {"solution": "def concatenate_tuple(test_tuple):\n return '-'.join(str(x) for x in test_tuple)", "matching_cluster_idx": 4}, {"solution": "def concatenate_tuple(test_tuple):\n # Convert each element to string and join them with the delimiter '-'\n return '-'.join(str(element) for element in test_tuple)", "matching_cluster_idx": 4}, {"solution": "def concatenate_tuple(tup):\n \"\"\"\n Concatenates each element of the tuple into a single string with a '-' delimiter.\n \n Args:\n tup (tuple): A tuple of elements to be concatenated.\n \n Returns:\n str: A single string with elements concatenated by '-'.\n \"\"\"\n return '-'.join(str(item) for item in tup)", "matching_cluster_idx": 4}, {"solution": "def concatenate_tuple(input_tuple):\n delimiter = \"-\"\n return delimiter.join(str(item) for item in input_tuple)", "matching_cluster_idx": 4}, {"solution": "def concatenate_tuple(input_tuple):\n # Convert the tuple to a list to make it mutable\n temp_list = list(input_tuple)\n # Join the elements of the list with the delimiter\n result = \"-\".join(str(item) for item in temp_list)\n return result", "matching_cluster_idx": 4}, {"solution": "def concatenate_tuple(input_tuple):\n \"\"\"\n Concatenate each element of the tuple by the delimiter.\n \n Parameters:\n input_tuple (tuple): A tuple containing elements to be concatenated.\n \n Returns:\n str: A string with elements concatenated by the delimiter '-'.\n \"\"\"\n # Convert the tuple to a list for easier manipulation\n elements = list(input_tuple)\n \n # Join the elements with the delimiter\n result = '-'.join(str(element) for element in elements)\n \n return result", "matching_cluster_idx": 4}, {"solution": "def concatenate_tuple(test_tuple):\n # Convert the tuple elements to a list to join them with a delimiter\n list_elements = list(test_tuple)\n # Join the elements with the specified delimiter\n result = '-'.join(map(str, list_elements))\n return result", "matching_cluster_idx": 5}, {"solution": "def concatenate_tuple(tup):\n return '-'.join(str(x) for x in tup)", "matching_cluster_idx": 4}, {"solution": "def concatenate_tuple(tup):\n return '-'.join(str(item) for item in tup)", "matching_cluster_idx": 4}, {"solution": "def concatenate_tuple(tup):\n return '-'.join(str(x) for x in tup)", "matching_cluster_idx": 4}, {"solution": "def concatenate_tuple(tup):\n # Convert the tuple to a string using the delimiter\n return '-'.join(str(item) for item in tup)", "matching_cluster_idx": 4}, {"solution": "def concatenate_tuple(test_tuple):\n # Convert each element to string and join them with the delimiter\n result = '-'.join(str(element) for element in test_tuple)\n return result", "matching_cluster_idx": 4}, {"solution": "def concatenate_tuple(test_tuple):\n # Concatenate each element of the tuple with the delimiter '-'\n return '-'.join(str(element) for element in test_tuple)", "matching_cluster_idx": 4}, {"solution": "def concatenate_tuple(tup):\n return '-'.join(str(element) for element in tup)", "matching_cluster_idx": 4}, {"solution": "def concatenate_tuple(test_tuple):\n # Convert the tuple to a list to use join\n test_list = list(test_tuple)\n # Join the elements with the delimiter '-'\n result = '-'.join(map(str, test_list))\n return result", "matching_cluster_idx": 5}, {"solution": "def concatenate_tuple(tup):\n return '-'.join(str(element) for element in tup)", "matching_cluster_idx": 4}, {"solution": "def concatenate_tuple(test_tup):\n # Join each element of the tuple with the delimiter '-'\n result = '-'.join(str(x) for x in test_tup)\n return result", "matching_cluster_idx": 4}, {"solution": "def concatenate_tuple(tup):\n return '-'.join(str(x) for x in tup)", "matching_cluster_idx": 4}, {"solution": "def concatenate_tuple(test_tuple):\n # Join each element of the tuple with the delimiter '-'\n result = '-'.join(str(item) for item in test_tuple)\n return result", "matching_cluster_idx": 4}]}, "Mbpp/424": {"dps": 90.32490974729242, "dps_norm": 96.0, "pass@1": 98.0, "profiled": [{"solution": "def extract_rear(strings):\n return [string[-1] for string in strings]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(strings_tuple):\n return [s[-1] for s in strings_tuple]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(strings):\n return [string[-1] for string in strings]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(test_tuple):\n result = [item[-1] for item in test_tuple]\n return result", "matching_cluster_idx": 3}, {"solution": "def extract_rear(strings_tuple):\n return [string[-1] for string in strings_tuple]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(strings):\n return [string[-1] for string in strings]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(strings_tuple):\n return [string[-1] for string in strings_tuple]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(test_tuple):\n result = [item[-1] for item in test_tuple]\n return result", "matching_cluster_idx": 3}, {"solution": "def extract_rear(test_tuple):\n # Extract the last character of each string in the tuple\n result = [item[-1] for item in test_tuple]\n return result\ntest_tuple = ('Mers', 'for', 'Vers')", "matching_cluster_idx": 4}, {"solution": "def extract_rear(strings):\n return [string[-1] for string in strings]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(strings):\n return [string[-1] for string in strings]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(strings_tuple):\n return [string[-1] for string in strings_tuple]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(strings):\n return [string[-1] for string in strings]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(strings):\n return [string[-1] for string in strings]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(strings):\n return [s[-1] for s in strings]", "matching_cluster_idx": 3}, {"solution": "def extract_rear(strings):\n return [string[-1] for string in strings]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(strings):\n return [string[-1] for string in strings]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(strings):\n return [string[-1] for string in strings]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(strings):\n return [s[-1] for s in strings]", "matching_cluster_idx": 3}, {"solution": "def extract_rear(input_tuple):\n return [word[-1] for word in input_tuple]", "matching_cluster_idx": 4}]}, "Mbpp/425": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def count_element_in_list(lst, element):\n count = 0\n for sublist in lst:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(list1, element):\n count = 0\n for sublist in list1:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, element):\n count = 0\n for sublist in lst:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, element):\n count = 0\n for sublist in lst:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, element):\n count = 0\n for sublist in lst:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(list1, element):\n count = 0\n for sublist in list1:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, element):\n count = 0\n for sublist in lst:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, element):\n count = 0\n for sublist in lst:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, element):\n count = 0\n for sublist in lst:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, element):\n count = 0\n for sublist in lst:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(list1, element):\n count = 0\n for sublist in list1:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, element):\n count = 0\n for sublist in lst:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, element):\n count = 0\n for sublist in lst:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, element):\n count = 0\n for sublist in lst:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, element):\n count = 0\n for sublist in lst:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, element):\n count = 0\n for sublist in lst:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, element):\n count = 0\n for sublist in lst:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, element):\n count = 0\n for sublist in lst:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(list1, element):\n count = 0\n for sublist in list1:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, element):\n count = 0\n for sublist in lst:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}]}, "Mbpp/428": {"dps": 84.29752066115702, "dps_norm": 55.55555555555556, "pass@1": 100.0, "profiled": [{"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2\n\n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2\n\n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n # Start with a big gap, then reduce the gap\n n = len(arr)\n gap = n // 2\n\n # Do a gapped insertion sort for this gap size.\n # The first gap elements arr[0..gap-1] are already in gapped order\n # keep adding one more element until the entire array is gap sorted\n while gap > 0:\n for i in range(gap, n):\n # add arr[i] to the elements that have been gap sorted\n # save arr[i] in temp and make a hole at position i\n temp = arr[i]\n j = i\n # shift earlier gap-sorted elements up until the correct location for arr[i] is found\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n # put temp (the original arr[i]) in its correct location\n arr[j] = temp\n gap //= 2\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n # Start with a big gap, then reduce the gap\n n = len(arr)\n gap = n // 2\n\n # Do a gapped insertion sort for this gap size.\n # The first gap elements arr[0..gap-1] are already in gapped order\n # keep adding one more element until the entire array is gap sorted\n while gap > 0:\n for i in range(gap, n):\n # add arr[i] to the elements that have been gap sorted\n # save arr[i] in temp and make a hole at position i\n temp = arr[i]\n\n # shift earlier gap-sorted elements up until the correct location for arr[i] is found\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n\n # put temp (the original arr[i]) in its correct location\n arr[j] = temp\n gap //= 2\n\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n # Start with a big gap, then reduce the gap\n n = len(arr)\n gap = n // 2\n\n # Do a gapped insertion sort for this gap size.\n # The first gap elements arr[0..gap-1] are already in gapped order\n # keep adding one more element until the entire array is gap sorted\n while gap > 0:\n for i in range(gap, n):\n # add arr[i] to the elements that have been gap sorted\n # save arr[i] in temp and make a hole at position i\n temp = arr[i]\n\n # shift earlier gap-sorted elements up until the correct location for arr[i] is found\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n\n # put temp (the original arr[i]) in its correct location\n arr[j] = temp\n gap //= 2\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n # Start with a big gap, then reduce the gap\n n = len(arr)\n gap = n // 2\n\n # Do a gapped insertion sort for this gap size.\n # The first gap elements arr[0..gap-1] are already in gapped order\n # keep adding one more element until the entire array is gap sorted\n while gap > 0:\n for i in range(gap, n):\n # add arr[i] to the elements that have been gap sorted\n # save arr[i] in temp and make a hole at position i\n temp = arr[i]\n j = i\n # shift earlier gap-sorted elements up until the correct location for arr[i] is found\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n # put temp (the original arr[i]) in its correct location\n arr[j] = temp\n gap //= 2\n\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2\n\n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n # Start with a big gap, then reduce the gap\n n = len(arr)\n gap = n // 2\n\n # Do a gapped insertion sort for this gap size.\n # The first gap elements arr[0..gap-1] are already in gapped order\n # keep adding one more element until the entire array is gap sorted\n while gap > 0:\n for i in range(gap, n):\n # add arr[i] to the elements that have been gap sorted\n # save arr[i] in temp and make a hole at position i\n temp = arr[i]\n # shift earlier gap-sorted elements up until the correct location for arr[i] is found\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n # put temp (the original arr[i]) in its correct location\n arr[j] = temp\n gap //= 2\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2\n\n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n # Start with a big gap, then reduce the gap\n n = len(arr)\n gap = n // 2\n\n # Do a gapped insertion sort for this gap size.\n # The first gap elements arr[0..gap-1] are already in gapped order\n # keep adding one more element until the entire array is gap sorted\n while gap > 0:\n for i in range(gap, n):\n # add arr[i] to the elements that have been gap sorted\n # save arr[i] in temp and make a hole at position i\n temp = arr[i]\n # shift earlier gap-sorted elements up until the correct location for arr[i] is found\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n # put temp (the original arr[i]) in its correct location\n arr[j] = temp\n gap //= 2\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n n = len(arr)\n # Start with a big gap, then reduce the gap\n gap = n // 2\n\n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2\n\n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n # Start with a big gap, then reduce the gap\n n = len(arr)\n gap = n // 2\n\n # Do a gapped insertion sort for this gap size.\n # The first gap elements arr[0..gap-1] are already in gapped order\n # keep adding one more element until the entire array is gap sorted\n while gap > 0:\n for i in range(gap, n):\n # add arr[i] to the elements that have been gap sorted\n # save arr[i] in temp and make a hole at position i\n temp = arr[i]\n\n # shift earlier gap-sorted elements up until the correct location for arr[i] is found\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n\n # put temp (the original arr[i]) in its correct location\n arr[j] = temp\n gap //= 2\n\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2\n\n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2\n\n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n # Start with a big gap, then reduce the gap\n n = len(arr)\n gap = n // 2\n\n # Do a gapped insertion sort for this gap size.\n # The first gap elements arr[0..gap-1] are already in gapped order\n # keep adding one more element until the entire array is gap sorted\n while gap > 0:\n for i in range(gap, n):\n # add arr[i] to the elements that have been gap sorted\n # save arr[i] in temp and make a hole at position i\n temp = arr[i]\n # shift earlier gap-sorted elements up until the correct location for arr[i] is found\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n # put temp (the original arr[i]) in its correct location\n arr[j] = temp\n gap //= 2\n\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2\n\n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n # Start with a big gap, then reduce the gap\n n = len(arr)\n gap = n // 2\n\n # Do a gapped insertion sort for this gap size.\n # The first gap elements arr[0..gap-1] are already in gapped order\n # keep adding one more element until the entire array is gap sorted\n while gap > 0:\n for i in range(gap, n):\n # add arr[i] to the elements that have been gap sorted\n # save arr[i] in temp and make a hole at position i\n temp = arr[i]\n # shift earlier gap-sorted elements up until the correct location for arr[i] is found\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n # put temp (the original arr[i]) in its correct location\n arr[j] = temp\n gap //= 2\n\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n # Start with a big gap, then reduce the gap\n n = len(arr)\n gap = n // 2\n\n # Do a gapped insertion sort for this gap size.\n # The first gap elements arr[0..gap-1] are already in gapped order\n # keep adding one more element until the entire array is gap sorted\n while gap > 0:\n for i in range(gap, n):\n # add arr[i] to the elements that have been gap sorted\n # save arr[i] in temp and make a hole at position i\n temp = arr[i]\n # shift earlier gap-sorted elements up until the correct location for arr[i] is found\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n # put temp (the original arr[i]) in its correct location\n arr[j] = temp\n gap //= 2\n\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n # Start with a big gap, then reduce the gap\n n = len(arr)\n gap = n // 2\n\n # Do a gapped insertion sort for this gap size.\n # The first gap elements arr[0..gap-1] are already in gapped order\n # keep adding one more element until the entire array is gap sorted\n while gap > 0:\n for i in range(gap, n):\n # add arr[i] to the elements that have been gap sorted\n # save arr[i] in temp and make a hole at position i\n temp = arr[i]\n # shift earlier gap-sorted elements up until the correct location for arr[i] is found\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n # put temp (the original arr[i]) in its correct location\n arr[j] = temp\n gap //= 2\n return arr", "matching_cluster_idx": 4}]}, "Mbpp/433": {"dps": 72.87234042553192, "dps_norm": 70.0, "pass@1": 37.0, "profiled": [{"solution": "def check_greater(numbers, target):\n return all(target > num for num in numbers)", "matching_cluster_idx": 2}, {"solution": "def check_greater(arr, num):\n \"\"\"\n Check whether the entered number is greater than the elements of the given array.\n \"\"\"\n return all(num > element for element in arr)", "matching_cluster_idx": 2}, {"solution": "def check_greater(arr, num):\n \"\"\"\n Check whether the entered number is greater than the elements of the given array.\n \n Args:\n arr (list): The list of numbers.\n num (int): The number to check against the elements of the list.\n \n Returns:\n bool: True if the number is greater than all elements in the array, False otherwise.\n \"\"\"\n return all(num > element for element in arr)", "matching_cluster_idx": 2}, {"solution": "def check_greater(arr, num):\n \"\"\"\n Function to check whether the entered number is greater than the elements of the given array.\n \"\"\"\n return all(num > element for element in arr)", "matching_cluster_idx": 2}, {"solution": "def check_greater(numbers, value):\n return all(value > num for num in numbers)", "matching_cluster_idx": 2}, {"solution": "def check_greater(arr, num):\n return all(num > element for element in arr)", "matching_cluster_idx": 2}, {"solution": "def check_greater(arr, num):\n for element in arr:\n if num <= element:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def check_greater(arr, num):\n for element in arr:\n if num <= element:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def check_greater(arr, num):\n for element in arr:\n if num <= element:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def check_greater(numbers, target):\n return all(target > num for num in numbers)", "matching_cluster_idx": 2}, {"solution": "def check_greater(arr, num):\n \"\"\"\n Check whether the entered number is greater than the elements of the given array.\n \"\"\"\n return all(num > elem for elem in arr)", "matching_cluster_idx": 2}, {"solution": "def check_greater(arr, num):\n for element in arr:\n if num <= element:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def check_greater(arr, num):\n \"\"\"\n Check if the number is greater than all elements in the array.\n \n Parameters:\n arr (list): A list of integers.\n num (int): The integer to compare with the elements of the array.\n \n Returns:\n bool: True if the number is greater than all elements in the array, False otherwise.\n \"\"\"\n return all(num > x for x in arr)", "matching_cluster_idx": 2}, {"solution": "def check_greater(arr, num):\n return all(num > element for element in arr)", "matching_cluster_idx": 2}, {"solution": "def check_greater(arr, num):\n return all(num > element for element in arr)", "matching_cluster_idx": 2}, {"solution": "def check_greater(arr, num):\n \"\"\"\n Check whether the entered number is greater than the elements of the given array.\n \"\"\"\n return all(num > element for element in arr)", "matching_cluster_idx": 2}, {"solution": "def check_greater(arr, num):\n \"\"\"\n Check whether the entered number is greater than the elements of the given array.\n \n Args:\n arr (list): A list of numbers.\n num (int): The number to check against the elements of the array.\n \n Returns:\n bool: True if the number is greater than all elements in the array, False otherwise.\n \"\"\"\n return all(num > element for element in arr)", "matching_cluster_idx": 2}, {"solution": "def check_greater(arr, num):\n for element in arr:\n if num <= element:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def check_greater(arr, num):\n \"\"\"\n Check whether the entered number is greater than the elements of the given array.\n \"\"\"\n return all(num > element for element in arr)", "matching_cluster_idx": 2}, {"solution": "def check_greater(arr, num):\n \"\"\"\n This function checks whether the entered number is greater than the elements of the given array.\n \"\"\"\n return all(num > element for element in arr)", "matching_cluster_idx": 2}]}, "Mbpp/437": {"dps": null, "dps_norm": null, "pass@1": 0.0, "profiled": []}, "Mbpp/440": {"dps": null, "dps_norm": null, "pass@1": 0.0, "profiled": []}, "Mbpp/446": {"dps": 96.05911330049261, "dps_norm": 60.0, "pass@1": 60.0, "profiled": [{"solution": "def count_Occurrence(test_tup, lst):\n res = sum(test_tup.count(ele) for ele in lst)\n return res", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(test_tup, list1):\n res = sum(test_tup.count(ele) for ele in list1)\n return res", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tup, lst):\n count = 0\n for item in lst:\n count += tup.count(item)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(test_tup, list1):\n res = sum(test_tup.count(ele) for ele in list1)\n return res", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(test_tup, list1):\n # Initialize the count to 0\n count = 0\n # Iterate over each element in the list1\n for ele in list1:\n # Count the occurrences of the element in the test_tup\n count += test_tup.count(ele)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(test_tup, test_list):\n res = sum(test_tup.count(ele) for ele in test_list)\n return res", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tup, lst):\n count = 0\n for item in lst:\n count += tup.count(item)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(test_tup, list1):\n res = sum(test_tup.count(ele) for ele in list1)\n return res", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(test_tup, test_list):\n res = sum(test_tup.count(ele) for ele in test_list)\n return res", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(test_tup, list1):\n res = sum(test_tup.count(ele) for ele in list1)\n return res", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(test_tup, test_list):\n res = sum(test_tup.count(ele) for ele in test_list)\n return res", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(input_tuple, list_elements):\n count = 0\n for element in list_elements:\n count += input_tuple.count(element)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(test_tup, list1):\n # Initialize a count variable\n count = 0\n # Iterate over each element in the list1\n for ele in list1:\n # Count the occurrences of the element in the test_tup\n count += test_tup.count(ele)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(test_tup, list1):\n res = sum(test_tup.count(ele) for ele in list1)\n return res", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(test_tup, list1):\n res = sum(test_tup.count(ele) for ele in list1)\n return res", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(test_tuple, test_list):\n # Initialize a result counter\n res = 0\n # Iterate through each element in the test_list\n for ele in test_list:\n # Count the occurrences of the current element in the test_tuple and add to res\n res += test_tuple.count(ele)\n return res", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(test_tup, test_list):\n result = sum(test_tup.count(ele) for ele in test_list)\n return result", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(input_tuple, elements_list):\n # Initialize a count variable to keep track of the total occurrences\n total_occurrences = 0\n \n # Iterate over each element in the elements_list\n for element in elements_list:\n # Count the occurrences of the current element in the input_tuple and add it to the total_occurrences\n total_occurrences += input_tuple.count(element)\n \n # Return the total number of occurrences\n return total_occurrences", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(test_tup, list1):\n res = sum(test_tup.count(ele) for ele in list1)\n return res", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(test_tup, list1):\n res = sum(test_tup.count(ele) for ele in list1)\n return res", "matching_cluster_idx": 2}]}, "Mbpp/451": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 99.0, "profiled": [{"solution": "def remove_whitespaces(s: str) -> str:\n \"\"\"\n Remove all whitespaces from the given string.\n \"\"\"\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string):\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(s):\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(s):\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(text):\n return text.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string):\n \"\"\"\n Removes all whitespaces from the given string.\n \"\"\"\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(s: str) -> str:\n \"\"\"\n Remove all whitespaces from the given string.\n \"\"\"\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(s: str) -> str:\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(s):\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string):\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(s: str) -> str:\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(s):\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(s):\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string):\n \"\"\"\n Remove all whitespaces from the given string.\n \n Args:\n input_string (str): The input string from which whitespaces need to be removed.\n \n Returns:\n str: The input string with all whitespaces removed.\n \"\"\"\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string):\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(s):\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(s: str) -> str:\n \"\"\"\n Removes all whitespaces from the given string.\n \n Args:\n s (str): The input string.\n \n Returns:\n str: The string with all whitespaces removed.\n \"\"\"\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(s):\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(s):\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string):\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}]}, "Mbpp/456": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def reverse_string_list(strings):\n # Use a list comprehension to reverse each string in the list\n return [s[::-1] for s in strings]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(strings):\n reversed_list = []\n for string in strings:\n reversed_list.append(string[::-1])\n return reversed_list", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n \"\"\"\n Reverses each string in the given list of string values.\n \n Args:\n string_list (list of str): The list of strings to be reversed.\n \n Returns:\n list of str: A new list with each string reversed.\n \"\"\"\n reversed_list = []\n for string in string_list:\n reversed_list.append(string[::-1])\n return reversed_list", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(strings):\n \"\"\"\n Reverses each string in the given list of strings.\n\n Args:\n strings (list of str): List of strings to be reversed.\n\n Returns:\n list of str: List of reversed strings.\n \"\"\"\n return [s[::-1] for s in strings]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(strings):\n # Use a list comprehension to reverse each string in the list\n return [s[::-1] for s in strings]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(strings):\n return [s[::-1] for s in strings]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(strings):\n return [s[::-1] for s in strings]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(strings):\n \"\"\"\n Reverses each string in a given list of string values.\n \n Args:\n strings (list of str): A list of strings to be reversed.\n \n Returns:\n list of str: A list of reversed strings.\n \"\"\"\n reversed_list = []\n for string in strings:\n reversed_list.append(string[::-1])\n return reversed_list", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(strings):\n return [s[::-1] for s in strings]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(strings):\n return [s[::-1] for s in strings]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n reversed_list = []\n for string in string_list:\n reversed_list.append(string[::-1])\n return reversed_list", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(strings):\n \"\"\"\n Reverses each string in the given list of string values.\n \n Args:\n strings (list of str): A list containing strings to be reversed.\n \n Returns:\n list of str: A new list with each string reversed.\n \"\"\"\n return [s[::-1] for s in strings]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(strings):\n return [s[::-1] for s in strings]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(strings):\n reversed_strings = [s[::-1] for s in strings]\n return reversed_strings", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(strings):\n return [s[::-1] for s in strings]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(strings):\n return [s[::-1] for s in strings]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n \"\"\"\n Reverses each string in the given list of string values.\n \n Args:\n string_list (list): A list of strings.\n \n Returns:\n list: A list of strings, each string in the original list reversed.\n \"\"\"\n return [s[::-1] for s in string_list]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(strings):\n reversed_strings = []\n for string in strings:\n reversed_strings.append(string[::-1])\n return reversed_strings", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(strings):\n reversed_strings = []\n for string in strings:\n reversed_strings.append(string[::-1])\n return reversed_strings", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(strings):\n reversed_strings = []\n for string in strings:\n reversed_strings.append(string[::-1])\n return reversed_strings", "matching_cluster_idx": 4}]}, "Mbpp/460": {"dps": 45.96153846153846, "dps_norm": 79.0, "pass@1": 100.0, "profiled": [{"solution": "def Extract(lst):\n return [item[0] for item in lst]", "matching_cluster_idx": 3}, {"solution": "def Extract(lst):\n return [item[0] for item in lst]", "matching_cluster_idx": 3}, {"solution": "def Extract(lst):\n return [item[0] for item in lst]", "matching_cluster_idx": 3}, {"solution": "def Extract(lst):\n return [item[0] for item in lst]", "matching_cluster_idx": 3}, {"solution": "def Extract(lst):\n return [item[0] for item in lst]", "matching_cluster_idx": 3}, {"solution": "def Extract(lst):\n return [item[0] for item in lst]", "matching_cluster_idx": 3}, {"solution": "def Extract(lst):\n return [item[0] if len(item) > 0 else None for item in lst]", "matching_cluster_idx": 2}, {"solution": "def Extract(lists):\n return [sublist[0] for sublist in lists]", "matching_cluster_idx": 3}, {"solution": "def Extract(lst):\n return [item[0] if item else None for item in lst]", "matching_cluster_idx": 3}, {"solution": "def Extract(list1):\n return [sublist[0] for sublist in list1]", "matching_cluster_idx": 3}, {"solution": "def Extract(lists):\n return [sublist[0] for sublist in lists]", "matching_cluster_idx": 3}, {"solution": "def Extract(lst):\n return [item[0] for item in lst]", "matching_cluster_idx": 3}, {"solution": "def Extract(lst):\n return [item[0] for item in lst]", "matching_cluster_idx": 3}, {"solution": "def Extract(lst):\n return [item[0] for item in lst]", "matching_cluster_idx": 3}, {"solution": "def Extract(lst):\n return [item[0] for item in lst]", "matching_cluster_idx": 3}, {"solution": "def Extract(lst):\n return [item[0] for item in lst]", "matching_cluster_idx": 3}, {"solution": "def Extract(lst):\n return [item[0] for item in lst]", "matching_cluster_idx": 3}, {"solution": "def Extract(list1):\n return [sublist[0] for sublist in list1]", "matching_cluster_idx": 3}, {"solution": "def Extract(lists):\n return [sublist[0] for sublist in lists]", "matching_cluster_idx": 3}, {"solution": "def Extract(lst):\n return [item[0] for item in lst]", "matching_cluster_idx": 3}]}, "Mbpp/474": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def replace_char(input_string, old_char, new_char):\n \"\"\"\n Replaces all occurrences of a character in a string with another character.\n \n Args:\n input_string (str): The original string.\n old_char (str): The character to be replaced.\n new_char (str): The character to replace with.\n \n Returns:\n str: The string with the specified character replaced.\n \"\"\"\n return input_string.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, old_char, new_char):\n \"\"\"\n Replace all occurrences of a character in a string with another character.\n \n Parameters:\n s (str): The input string.\n old_char (str): The character to be replaced.\n new_char (str): The character to replace with.\n \n Returns:\n str: The new string with replaced characters.\n \"\"\"\n return s.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, old, new):\n return s.replace(old, new)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, old_char, new_char):\n return s.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, old_char, new_char):\n \"\"\"\n Replace all occurrences of a character in a string with another character.\n \n Parameters:\n s (str): The original string.\n old_char (str): The character to be replaced.\n new_char (str): The character to replace with.\n \n Returns:\n str: The modified string.\n \"\"\"\n return s.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(string, old_char, new_char):\n \"\"\"\n Replaces all occurrences of a specified character with another character in a given string.\n \n Parameters:\n string (str): The input string.\n old_char (str): The character to be replaced.\n new_char (str): The character to replace with.\n \n Returns:\n str: A new string with all occurrences of old_char replaced by new_char.\n \"\"\"\n return string.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(string, old_char, new_char):\n \"\"\"\n Replaces all occurrences of a character in a string with another character.\n \n Args:\n string (str): The input string.\n old_char (str): The character to be replaced.\n new_char (str): The character to replace with.\n \n Returns:\n str: The new string with replaced characters.\n \"\"\"\n return string.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, old_char, new_char):\n return s.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, old, new):\n return s.replace(old, new)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, old_char, new_char):\n \"\"\"\n Replace all occurrences of a character in a string with another character.\n \n Args:\n s (str): The input string.\n old_char (str): The character to be replaced.\n new_char (str): The character to replace with.\n \n Returns:\n str: A new string with all occurrences of old_char replaced with new_char.\n \"\"\"\n return s.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, old, new):\n return s.replace(old, new)", "matching_cluster_idx": 6}, {"solution": "def replace_char(input_string, char_to_replace, new_char):\n \"\"\"\n Replace all occurrences of a character in a string with another character.\n\n Args:\n input_string (str): The original string.\n char_to_replace (str): The character to be replaced.\n new_char (str): The new character to replace with.\n\n Returns:\n str: The string with all occurrences of char_to_replace replaced with new_char.\n \"\"\"\n return input_string.replace(char_to_replace, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, old, new):\n return s.replace(old, new)", "matching_cluster_idx": 6}, {"solution": "def replace_char(string, old_char, new_char):\n # Use the str.replace() method to replace all occurrences of old_char with new_char\n return string.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, old_char, new_char):\n \"\"\"\n Replace all occurrences of a character in a string with another character.\n \n Args:\n s (str): The input string.\n old_char (str): The character to be replaced.\n new_char (str): The character to replace with.\n \n Returns:\n str: A new string with the specified character replacements.\n \"\"\"\n return s.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, old, new):\n return s.replace(old, new)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, old_char, new_char):\n \"\"\"\n Replaces all occurrences of a specific character with another character in a string.\n \n Args:\n s (str): The input string.\n old_char (str): The character to be replaced.\n new_char (str): The character to replace with.\n \n Returns:\n str: A new string with all occurrences of old_char replaced with new_char.\n \"\"\"\n return s.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, old, new):\n return s.replace(old, new)", "matching_cluster_idx": 6}, {"solution": "def replace_char(string, old_char, new_char):\n \"\"\"\n Replace all occurrences of a character in a string with another character.\n \n Args:\n string (str): The input string.\n old_char (str): The character to be replaced.\n new_char (str): The character to replace with.\n \n Returns:\n str: The new string with the replacements made.\n \"\"\"\n return string.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, old_char, new_char):\n \"\"\"\n Replace all occurrences of a character in a string with another character.\n \n Args:\n s (str): The input string.\n old_char (str): The character to be replaced.\n new_char (str): The character to replace with.\n \n Returns:\n str: The resulting string after replacement.\n \"\"\"\n return s.replace(old_char, new_char)", "matching_cluster_idx": 6}]}, "Mbpp/476": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def big_sum(arr):\n if not arr: # Check if the array is empty\n return None\n return max(arr) + min(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(numbers):\n return max(numbers) + min(numbers)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n if not arr: # Check if the array is empty\n return 0\n return max(arr) + min(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(numbers):\n return max(numbers) + min(numbers)", "matching_cluster_idx": 5}, {"solution": "def big_sum(numbers):\n if not numbers:\n raise ValueError(\"The input list must contain at least one element.\")\n return max(numbers) + min(numbers)", "matching_cluster_idx": 5}, {"solution": "def big_sum(numbers):\n if not numbers: # Check if the list is empty\n return 0\n return max(numbers) + min(numbers)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n return max(arr) + min(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n if not arr: # Check if the array is empty\n return 0\n return max(arr) + min(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n if not arr:\n raise ValueError(\"Array must not be empty\")\n return max(arr) + min(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n if not arr: # Check if the array is empty\n return 0\n return max(arr) + min(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(numbers):\n return max(numbers) + min(numbers)", "matching_cluster_idx": 5}, {"solution": "def big_sum(numbers):\n if not numbers:\n raise ValueError(\"The input array must not be empty\")\n return max(numbers) + min(numbers)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n return max(arr) + min(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(numbers):\n if not numbers: # Check if the array is empty\n return 0\n return max(numbers) + min(numbers)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n if not arr: # Check if the array is empty\n return 0\n return max(arr) + min(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n if not arr: # Check if the array is empty\n return 0\n return max(arr) + min(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(numbers):\n if not numbers: # Check if the list is empty\n return 0\n return max(numbers) + min(numbers)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n \"\"\"\n Function to find the sum of the largest and smallest value in a given array.\n \"\"\"\n if not arr: # Check if the array is empty\n return 0\n return max(arr) + min(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n return max(arr) + min(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(numbers):\n if not numbers:\n raise ValueError(\"The array cannot be empty\")\n return max(numbers) + min(numbers)", "matching_cluster_idx": 5}]}, "Mbpp/477": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 56.0, "profiled": [{"solution": "def is_lower(string):\n return string.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(input_string):\n \"\"\"\n Converts the given string to lower case.\n \"\"\"\n return input_string.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n \"\"\"\n Converts the given string to lower case.\n \"\"\"\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(string):\n return string.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(input_string):\n return input_string.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(text):\n \"\"\"\n Convert the given string to lower case.\n \"\"\"\n return text.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(text):\n return text.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(string):\n return string.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(string):\n return string.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n \"\"\"\n Convert the given string to lower case.\n \"\"\"\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(string):\n return string.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(input_string):\n return input_string.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(string):\n return string.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(string):\n return string.lower()", "matching_cluster_idx": 4}]}, "Mbpp/563": {"dps": 85.24590163934427, "dps_norm": 81.81818181818181, "pass@1": 90.0, "profiled": [{"solution": "import re\ndef extract_values(s):\n # Use regex to find all substrings that are enclosed in double quotes\n return [match.strip('\"') for match in re.findall(r'\"(.*?)\"', s)]", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(string):\n # Use regular expression to find all substrings within quotation marks\n pattern = r'\"(.*?)\"'\n matches = re.findall(pattern, string)\n return matches", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(s):\n # Use regular expression to find all substrings that are enclosed in double quotes\n values = re.findall(r'\"(.*?)\"', s)\n return values", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(text):\n # Use regular expression to find all substrings enclosed in quotation marks\n pattern = r'\"(.*?)\"'\n matches = re.findall(pattern, text)\n return matches", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(text):\n # Use regular expression to find all substrings within quotation marks\n return [match.strip('\"') for match in re.findall(r'\"(.*?)\"', text)]", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(text):\n # Use regular expression to find all substrings within quotation marks\n matches = re.findall(r'\"(.*?)\"', text)\n return matches", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(input_string):\n # Use regular expression to find all substrings within double quotes\n matches = re.findall(r'\"(.*?)\"', input_string)\n return matches", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(input_string):\n # Use regular expression to find all substrings between double quotes\n return [match.group(1) for match in re.finditer(r'\"(.*?)\"', input_string)]", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(input_string):\n # Use regular expression to find all substrings within quotation marks\n pattern = r'\"(.*?)\"'\n matches = re.findall(pattern, input_string)\n return matches", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(input_string):\n # Use regular expression to find all substrings in quotation marks\n values = re.findall(r'\"(.*?)\"', input_string)\n return values", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(input_string):\n # Use regular expression to find all values enclosed in quotation marks\n pattern = r'\"(.*?)\"'\n matches = re.findall(pattern, input_string)\n return matches", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(s: str) -> list:\n # Use regular expression to find all substrings within quotation marks\n matches = re.findall(r'\"(.*?)\"', s)\n return matches", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(input_string):\n # Use regular expression to find all substrings within quotation marks\n return [match.strip('\"') for match in re.findall(r'\"(.*?)\"', input_string)]", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(text):\n # Use regex to find all substrings that are enclosed in double quotes\n matches = re.findall(r'\"(.*?)\"', text)\n return matches", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(input_string):\n # Use regular expression to find all substrings within quotation marks\n matches = re.findall(r'\"(.*?)\"', input_string)\n return matches", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(text):\n # Use regular expression to find all substrings between double quotes\n matches = re.findall(r'\"(.*?)\"', text)\n return matches", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(input_string):\n # Use regular expression to find all substrings between double quotes\n matches = re.findall(r'\"(.*?)\"', input_string)\n return matches", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(text):\n # Use regex to find all substrings between double quotes\n matches = re.findall(r'\"(.*?)\"', text)\n return matches", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(s: str) -> list:\n # Use regex to find all substrings enclosed in quotation marks\n return re.findall(r'\"(.*?)\"', s)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(text):\n # Use regular expression to find all substrings within double quotes\n pattern = r'\"(.*?)\"'\n matches = re.findall(pattern, text)\n return matches", "matching_cluster_idx": 8}]}, "Mbpp/572": {"dps": 34.567901234567906, "dps_norm": 28.571428571428573, "pass@1": 97.0, "profiled": [{"solution": "def two_unique_nums(numbers):\n unique_numbers = []\n for number in numbers:\n if numbers.count(number) == 1:\n unique_numbers.append(number)\n return unique_numbers", "matching_cluster_idx": 1}, {"solution": "def two_unique_nums(numbers):\n unique_numbers = []\n for number in numbers:\n if numbers.count(number) == 1 and number not in unique_numbers:\n unique_numbers.append(number)\n return unique_numbers", "matching_cluster_idx": 1}, {"solution": "def two_unique_nums(numbers):\n unique_numbers = []\n for number in numbers:\n if numbers.count(number) == 1:\n unique_numbers.append(number)\n return unique_numbers", "matching_cluster_idx": 1}, {"solution": "def two_unique_nums(numbers):\n unique_numbers = []\n for number in numbers:\n if numbers.count(number) == 1:\n unique_numbers.append(number)\n return unique_numbers", "matching_cluster_idx": 1}, {"solution": "def two_unique_nums(nums):\n unique_nums = []\n for num in nums:\n if nums.count(num) == 1 and num not in unique_nums:\n unique_nums.append(num)\n return unique_nums", "matching_cluster_idx": 1}, {"solution": "def two_unique_nums(numbers):\n unique_numbers = []\n for number in numbers:\n if numbers.count(number) == 1 and number not in unique_numbers:\n unique_numbers.append(number)\n return unique_numbers", "matching_cluster_idx": 1}, {"solution": "def two_unique_nums(numbers):\n unique_numbers = []\n for number in numbers:\n if numbers.count(number) == 1 and number not in unique_numbers:\n unique_numbers.append(number)\n return unique_numbers", "matching_cluster_idx": 1}, {"solution": "def two_unique_nums(nums):\n unique_nums = []\n for num in nums:\n if nums.count(num) == 1:\n unique_nums.append(num)\n return unique_nums", "matching_cluster_idx": 1}, {"solution": "def two_unique_nums(numbers):\n unique_numbers = []\n for number in numbers:\n if numbers.count(number) == 1 and number not in unique_numbers:\n unique_numbers.append(number)\n return unique_numbers", "matching_cluster_idx": 1}, {"solution": "def two_unique_nums(numbers):\n unique_numbers = []\n for number in numbers:\n if numbers.count(number) == 1 and number not in unique_numbers:\n unique_numbers.append(number)\n return unique_numbers", "matching_cluster_idx": 1}, {"solution": "def two_unique_nums(numbers):\n unique_numbers = []\n for num in numbers:\n if numbers.count(num) == 1 and num not in unique_numbers:\n unique_numbers.append(num)\n return unique_numbers", "matching_cluster_idx": 1}, {"solution": "def two_unique_nums(numbers):\n unique_numbers = []\n for number in numbers:\n if numbers.count(number) == 1 and number not in unique_numbers:\n unique_numbers.append(number)\n return unique_numbers", "matching_cluster_idx": 1}, {"solution": "def two_unique_nums(numbers):\n unique_numbers = []\n for num in numbers:\n if numbers.count(num) == 1:\n unique_numbers.append(num)\n return unique_numbers", "matching_cluster_idx": 1}, {"solution": "def two_unique_nums(numbers):\n unique_numbers = []\n for number in numbers:\n if numbers.count(number) == 1:\n unique_numbers.append(number)\n return unique_numbers", "matching_cluster_idx": 1}, {"solution": "def two_unique_nums(numbers):\n unique_numbers = []\n for number in numbers:\n if numbers.count(number) == 1:\n unique_numbers.append(number)\n return unique_numbers", "matching_cluster_idx": 1}, {"solution": "def two_unique_nums(numbers):\n unique_numbers = []\n for number in numbers:\n if numbers.count(number) == 1:\n unique_numbers.append(number)\n return unique_numbers", "matching_cluster_idx": 1}, {"solution": "def two_unique_nums(nums):\n unique_nums = []\n for num in nums:\n if nums.count(num) == 1 and num not in unique_nums:\n unique_nums.append(num)\n return unique_nums", "matching_cluster_idx": 1}, {"solution": "def two_unique_nums(numbers):\n unique_numbers = []\n for number in numbers:\n if numbers.count(number) == 1:\n unique_numbers.append(number)\n return unique_numbers", "matching_cluster_idx": 1}, {"solution": "def two_unique_nums(numbers):\n unique_numbers = []\n for number in numbers:\n if numbers.count(number) == 1 and number not in unique_numbers:\n unique_numbers.append(number)\n return unique_numbers", "matching_cluster_idx": 1}, {"solution": "def two_unique_nums(numbers):\n unique_numbers = []\n for number in numbers:\n if numbers.count(number) == 1:\n unique_numbers.append(number)\n return unique_numbers", "matching_cluster_idx": 1}]}, "Mbpp/578": {"dps": 60.33333333333333, "dps_norm": 64.0909090909091, "pass@1": 100.0, "profiled": [{"solution": "def interleave_lists(list1, list2, list3):\n # Initialize an empty list to store the result\n result = []\n \n # Get the length of the lists\n n = len(list1)\n \n # Loop through the indices of the lists\n for i in range(n):\n # Append the elements from each list at the current index\n result.append(list1[i])\n result.append(list2[i])\n result.append(list3[i])\n \n return result", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n result = []\n for i in range(len(list1)):\n result.append(list1[i])\n result.append(list2[i])\n result.append(list3[i])\n return result", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n result = []\n for i in range(len(list1)):\n result.append(list1[i])\n result.append(list2[i])\n result.append(list3[i])\n return result", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n result = []\n for i in range(len(list1)):\n result.append(list1[i])\n result.append(list2[i])\n result.append(list3[i])\n return result", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n result = []\n for i in range(len(list1)):\n result.append(list1[i])\n result.append(list2[i])\n result.append(list3[i])\n return result", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n result = []\n for i in range(len(list1)):\n result.append(list1[i])\n result.append(list2[i])\n result.append(list3[i])\n return result", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n # Initialize an empty list to store the result\n result = []\n \n # Get the length of the lists (since they are of the same length)\n length = len(list1)\n \n # Loop through the lists using their indices\n for i in range(length):\n # Append the elements from each list at the current index\n result.append(list1[i])\n result.append(list2[i])\n result.append(list3[i])\n \n return result", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n result = []\n for i in range(len(list1)):\n result.append(list1[i])\n result.append(list2[i])\n result.append(list3[i])\n return result", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"\n Interleave three lists of the same length into a single flat list.\n \n Args:\n list1 (list): The first list.\n list2 (list): The second list.\n list3 (list): The third list.\n \n Returns:\n list: A single flat list containing interleaved elements from the input lists.\n \"\"\"\n result = []\n for i in range(len(list1)):\n result.append(list1[i])\n result.append(list2[i])\n result.append(list3[i])\n return result", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n result = []\n for i in range(len(list1)):\n result.append(list1[i])\n result.append(list2[i])\n result.append(list3[i])\n return result", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n # Initialize an empty list to store the result\n result = []\n \n # Iterate over the range of the length of one of the lists\n for i in range(len(list1)):\n # Append the elements from each list at the current index\n result.append(list1[i])\n result.append(list2[i])\n result.append(list3[i])\n \n return result", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n # Initialize an empty list to hold the result\n result = []\n \n # Iterate over the range of the length of one of the lists\n for i in range(len(list1)):\n # Append the elements from each list at index i\n result.append(list1[i])\n result.append(list2[i])\n result.append(list3[i])\n \n return result", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n result = []\n for i in range(len(list1)):\n result.append(list1[i])\n result.append(list2[i])\n result.append(list3[i])\n return result", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n result = []\n for i in range(len(list1)):\n result.append(list1[i])\n result.append(list2[i])\n result.append(list3[i])\n return result", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n # Initialize an empty list to hold the result\n result = []\n \n # Use the range of the lists to iterate through them\n for i in range(len(list1)):\n # Append elements from each list in order\n result.append(list1[i])\n result.append(list2[i])\n result.append(list3[i])\n \n return result", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n result = []\n for i in range(len(list1)):\n result.append(list1[i])\n result.append(list2[i])\n result.append(list3[i])\n return result", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n # Initialize an empty list to store the result\n result = []\n # Iterate through the length of the lists\n for i in range(len(list1)):\n # Append elements from each list at the current index\n result.append(list1[i])\n result.append(list2[i])\n result.append(list3[i])\n return result", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n # Initialize an empty list to store the result\n result = []\n # Use the zip function to pair elements from each list\n for (a, b, c) in zip(list1, list2, list3):\n # Append the elements from each list in order\n result.extend([a, b, c])\n return result", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(list1, list2, list3):\n result = []\n for i in range(len(list1)):\n result.append(list1[i])\n result.append(list2[i])\n result.append(list3[i])\n return result", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n result = []\n for i in range(len(list1)):\n result.append(list1[i])\n result.append(list2[i])\n result.append(list3[i])\n return result", "matching_cluster_idx": 6}]}, "Mbpp/586": {"dps": 98.83040935672514, "dps_norm": 87.5, "pass@1": 31.0, "profiled": [{"solution": "def split_Arr(arr, n):\n if n >= len(arr):\n return arr # If n is greater than or equal to the length of the array, return the array as is.\n first_part = arr[:n]\n second_part = arr[n:]\n return second_part + first_part", "matching_cluster_idx": 6}, {"solution": "def split_Arr(lst, n):\n # Split the list at the nth element\n first_part = lst[:n]\n second_part = lst[n:]\n # Add the first part to the end\n return second_part + first_part", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n if n < 0 or n > len(arr):\n raise ValueError(\"n is out of the range of the array\")\n \n first_part = arr[:n]\n second_part = arr[n:]\n return second_part + first_part", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n if n >= len(arr):\n return arr # If n is greater than or equal to the length of the array, return the array as is.\n first_part = arr[:n]\n second_part = arr[n:]\n return second_part + first_part", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n if n >= len(arr):\n return arr\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n if n < 0 or n > len(arr):\n raise ValueError(\"n is out of the range of the array\")\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(lst, n):\n return lst[n:] + lst[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n if n > len(arr):\n raise ValueError(\"n is greater than the length of the array\")\n \n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n if n < 0 or n > len(arr):\n raise ValueError(\"n is out of the range of the array\")\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n if n >= len(arr):\n return arr # If n is greater than or equal to the length of the array, return the array as is\n return arr[n:] + arr[:n] # Split the array and reassemble", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n if n < 0 or n > len(arr):\n raise ValueError(\"n is out of the range of the array length\")\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(lst, n):\n # Split the list at the nth element\n first_part = lst[:n]\n second_part = lst[n:]\n # Add the first part to the end\n return second_part + first_part", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n if n > len(arr):\n raise ValueError(\"n is greater than the length of the array\")\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n if n < 0 or n > len(arr):\n raise ValueError(\"n is out of the range of the array\")\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n if n >= len(arr):\n return arr\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n if n >= len(arr):\n return arr\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n if n < 0 or n > len(arr):\n raise ValueError(\"n must be within the bounds of the array\")\n \n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n if n >= len(arr):\n return arr\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n if n > len(arr):\n raise ValueError(\"n is greater than the length of the array\")\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n if n >= len(arr):\n return arr # If n is greater than or equal to the length of the array, return the array as is.\n first_part = arr[:n]\n second_part = arr[n:]\n return second_part + first_part", "matching_cluster_idx": 6}]}, "Mbpp/587": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def list_tuple(lst):\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n \"\"\"\n Converts a list to a tuple.\n \n Args:\n lst (list): A list of elements.\n \n Returns:\n tuple: A tuple with the same elements as the input list.\n \"\"\"\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n \"\"\"\n Converts a list to a tuple.\n \n Args:\n lst (list): The list to be converted.\n \n Returns:\n tuple: The converted tuple.\n \"\"\"\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(input_list):\n return tuple(input_list)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(input_list):\n return tuple(input_list)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(input_list):\n return tuple(input_list)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(input_list):\n return tuple(input_list)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n return tuple(lst)", "matching_cluster_idx": 3}]}, "Mbpp/588": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def big_diff(nums):\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n \"\"\"\n Given a list of numbers, return the difference between the largest and smallest number.\n \"\"\"\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n \"\"\"\n Returns the difference between the largest and smallest values in a given list.\n \"\"\"\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n \"\"\"\n Write a python function to find the difference between the largest and smallest value in a given list.\n assert big_diff([1,2,3,4]) == 3\n \"\"\"\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n \"\"\"\n Function to find the difference between the largest and smallest value in a given list.\n \"\"\"\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n return max(nums) - min(nums)", "matching_cluster_idx": 5}]}, "Mbpp/592": {"dps": 40.53333333333334, "dps_norm": 51.0, "pass@1": 42.0, "profiled": [{"solution": "def binomial_coefficient(n, k):\n \"\"\"Calculate the binomial coefficient 'n choose k'.\"\"\"\n if k < 0 or k > n:\n return 0\n if k == 0 or k == n:\n return 1\n k = min(k, n - k) # Take advantage of symmetry\n c = 1\n for i in range(k):\n c = c * (n - i) // (i + 1)\n return c\ndef sum_Of_product(n):\n \"\"\"Sum of the product of consecutive binomial coefficients.\"\"\"\n total_sum = 0\n for k in range(n + 1):\n total_sum += binomial_coefficient(n, k) * binomial_coefficient(n, k + 1)\n return total_sum", "matching_cluster_idx": 4}, {"solution": "def binomial_coefficient(n, k):\n \"\"\"Calculate the binomial coefficient 'n choose k'.\"\"\"\n if k < 0 or k > n:\n return 0\n if k == 0 or k == n:\n return 1\n k = min(k, n - k) # Take advantage of symmetry\n c = 1\n for i in range(k):\n c = c * (n - i) // (i + 1)\n return c\ndef sum_Of_product(n):\n \"\"\"Sum of the product of consecutive binomial coefficients.\"\"\"\n result = 0\n for k in range(n + 1):\n result += binomial_coefficient(n, k) * binomial_coefficient(n, k + 1)\n return result", "matching_cluster_idx": 4}, {"solution": "def binomial_coefficient(n, k):\n if k < 0 or k > n:\n return 0\n if k == 0 or k == n:\n return 1\n k = min(k, n - k) # Take advantage of symmetry\n c = 1\n for i in range(k):\n c = c * (n - i) // (i + 1)\n return c\ndef sum_Of_product(n):\n result = 0\n for k in range(n + 1):\n result += binomial_coefficient(n, k) * binomial_coefficient(n, k + 1)\n return result", "matching_cluster_idx": 4}, {"solution": "def binomial_coefficient(n, k):\n \"\"\"Calculate the binomial coefficient 'n choose k'.\"\"\"\n if k < 0 or k > n:\n return 0\n if k == 0 or k == n:\n return 1\n k = min(k, n - k) # Take advantage of symmetry\n c = 1\n for i in range(k):\n c = c * (n - i) // (i + 1)\n return c\ndef sum_Of_product(n):\n \"\"\"Find the sum of the product of consecutive binomial coefficients up to n.\"\"\"\n sum_product = 0\n for k in range(n + 1):\n sum_product += binomial_coefficient(n, k) * binomial_coefficient(n, k + 1)\n return sum_product", "matching_cluster_idx": 4}, {"solution": "def binomial_coefficient(n, k):\n \"\"\"Calculate the binomial coefficient 'n choose k'.\"\"\"\n if k < 0 or k > n:\n return 0\n if k == 0 or k == n:\n return 1\n k = min(k, n - k) # Take advantage of symmetry\n c = 1\n for i in range(k):\n c = c * (n - i) // (i + 1)\n return c\ndef sum_Of_product(n):\n \"\"\"Calculate the sum of the product of consecutive binomial coefficients.\"\"\"\n result = 0\n for k in range(n + 1):\n result += binomial_coefficient(n, k) * binomial_coefficient(n, k + 1)\n return result", "matching_cluster_idx": 4}, {"solution": "def binomial_coefficient(n, k):\n \"\"\"Calculate the binomial coefficient 'n choose k'.\"\"\"\n if k > n:\n return 0\n if k == 0 or k == n:\n return 1\n k = min(k, n - k) # Take advantage of symmetry\n c = 1\n for i in range(k):\n c = c * (n - i) // (i + 1)\n return c\ndef sum_Of_product(n):\n \"\"\"Sum of the product of consecutive binomial coefficients.\"\"\"\n result = 0\n for k in range(n + 1):\n result += binomial_coefficient(n, k) * binomial_coefficient(n, k + 1)\n return result", "matching_cluster_idx": 4}, {"solution": "def binomial_coefficient(n, k):\n \"\"\"Calculate the binomial coefficient 'n choose k'.\"\"\"\n if k < 0 or k > n:\n return 0\n if k == 0 or k == n:\n return 1\n k = min(k, n - k) # Take advantage of symmetry\n c = 1\n for i in range(k):\n c = c * (n - i) // (i + 1)\n return c\ndef sum_Of_product(n):\n \"\"\"Find the sum of the product of consecutive binomial coefficients.\"\"\"\n result = 0\n for k in range(n + 1):\n result += binomial_coefficient(n, k) * binomial_coefficient(n, k + 1)\n return result", "matching_cluster_idx": 4}, {"solution": "def binomial_coefficient(n, k):\n \"\"\"Calculate the binomial coefficient 'n choose k'.\"\"\"\n if k < 0 or k > n:\n return 0\n if k == 0 or k == n:\n return 1\n k = min(k, n - k) # Take advantage of symmetry\n c = 1\n for i in range(k):\n c = c * (n - i) // (i + 1)\n return c\ndef sum_Of_product(n):\n \"\"\"Calculate the sum of the product of consecutive binomial coefficients up to n.\"\"\"\n sum_product = 0\n for k in range(n + 1):\n sum_product += binomial_coefficient(n, k) * binomial_coefficient(n, k + 1)\n return sum_product", "matching_cluster_idx": 4}, {"solution": "def binomial_coefficient(n, k):\n \"\"\"Calculate the binomial coefficient 'n choose k'.\"\"\"\n if k < 0 or k > n:\n return 0\n if k == 0 or k == n:\n return 1\n k = min(k, n - k) # Take advantage of symmetry\n c = 1\n for i in range(k):\n c = c * (n - i) // (i + 1)\n return c\ndef sum_Of_product(n):\n \"\"\"Calculate the sum of the product of consecutive binomial coefficients up to n.\"\"\"\n result = 0\n for k in range(n + 1):\n result += binomial_coefficient(n, k) * binomial_coefficient(n, k + 1)\n return result", "matching_cluster_idx": 4}, {"solution": "def binomial_coefficient(n, k):\n \"\"\"Calculate the binomial coefficient 'n choose k'.\"\"\"\n if k < 0 or k > n:\n return 0\n if k == 0 or k == n:\n return 1\n k = min(k, n - k) # Take advantage of symmetry\n c = 1\n for i in range(k):\n c = c * (n - i) // (i + 1)\n return c\ndef sum_Of_product(n):\n \"\"\"Sum of the product of consecutive binomial coefficients.\"\"\"\n result = 0\n for i in range(n + 1):\n result += binomial_coefficient(n, i) * binomial_coefficient(n, i + 1)\n return result", "matching_cluster_idx": 4}, {"solution": "def binomial_coefficient(n, k):\n if k < 0 or k > n:\n return 0\n if k == 0 or k == n:\n return 1\n k = min(k, n - k) # Take advantage of symmetry\n c = 1\n for i in range(k):\n c = c * (n - i) // (i + 1)\n return c\ndef sum_Of_product(n):\n sum_product = 0\n for k in range(n + 1):\n sum_product += binomial_coefficient(n, k) * binomial_coefficient(n, k + 1)\n return sum_product", "matching_cluster_idx": 4}, {"solution": "def binomial_coefficient(n, k):\n if k < 0 or k > n:\n return 0\n if k == 0 or k == n:\n return 1\n k = min(k, n - k) # Take advantage of symmetry\n c = 1\n for i in range(k):\n c = c * (n - i) // (i + 1)\n return c\ndef sum_Of_product(n):\n total_sum = 0\n for k in range(n + 1):\n total_sum += binomial_coefficient(n, k) * binomial_coefficient(n, k + 1)\n return total_sum", "matching_cluster_idx": 4}, {"solution": "def binomial_coefficient(n, k):\n if k < 0 or k > n:\n return 0\n if k == 0 or k == n:\n return 1\n result = 1\n for i in range(1, min(k, n - k) + 1):\n result = result * (n - i + 1) // i\n return result\ndef sum_Of_product(n):\n sum_product = 0\n for k in range(n + 1):\n sum_product += binomial_coefficient(n, k) * binomial_coefficient(n, k + 1)\n return sum_product", "matching_cluster_idx": 4}, {"solution": "def binomial_coefficient(n, k):\n \"\"\"Calculate the binomial coefficient 'n choose k'.\"\"\"\n if k > n:\n return 0\n if k == 0 or k == n:\n return 1\n k = min(k, n - k) # Take advantage of symmetry\n c = 1\n for i in range(k):\n c = c * (n - i) // (i + 1)\n return c\ndef sum_Of_product(n):\n \"\"\"Calculate the sum of the product of consecutive binomial coefficients.\"\"\"\n result = 0\n for k in range(n + 1):\n result += binomial_coefficient(n, k) * binomial_coefficient(n, k + 1)\n return result", "matching_cluster_idx": 4}, {"solution": "def binomial_coefficient(n, k):\n if k < 0 or k > n:\n return 0\n if k == 0 or k == n:\n return 1\n k = min(k, n - k) # Take advantage of symmetry\n c = 1\n for i in range(k):\n c = c * (n - i) // (i + 1)\n return c\ndef sum_Of_product(n):\n result = 0\n for k in range(n + 1):\n result += binomial_coefficient(n, k) * binomial_coefficient(n, k + 1)\n return result", "matching_cluster_idx": 4}, {"solution": "def binomial_coefficient(n, k):\n \"\"\"Calculate the binomial coefficient 'n choose k'.\"\"\"\n if k < 0 or k > n:\n return 0\n if k == 0 or k == n:\n return 1\n k = min(k, n - k) # Take advantage of symmetry\n c = 1\n for i in range(k):\n c = c * (n - i) // (i + 1)\n return c\ndef sum_Of_product(n):\n \"\"\"Calculate the sum of the product of consecutive binomial coefficients.\"\"\"\n sum_ = 0\n for k in range(n + 1):\n sum_ += binomial_coefficient(n, k) * binomial_coefficient(n, k + 1)\n return sum_", "matching_cluster_idx": 4}, {"solution": "def binomial_coefficient(n, k):\n \"\"\"Calculate the binomial coefficient 'n choose k'.\"\"\"\n if k > n:\n return 0\n if k == 0 or k == n:\n return 1\n k = min(k, n - k) # Take advantage of symmetry\n c = 1\n for i in range(k):\n c = c * (n - i) // (i + 1)\n return c\ndef sum_Of_product(n):\n \"\"\"Sum of the product of consecutive binomial coefficients.\"\"\"\n sum_ = 0\n for k in range(n + 1):\n sum_ += binomial_coefficient(n, k) * binomial_coefficient(n, k + 1)\n return sum_", "matching_cluster_idx": 4}, {"solution": "def binomial_coefficient(n, k):\n \"\"\"Calculate the binomial coefficient 'n choose k'.\"\"\"\n if k < 0 or k > n:\n return 0\n if k == 0 or k == n:\n return 1\n k = min(k, n - k) # Take advantage of symmetry\n c = 1\n for i in range(k):\n c = c * (n - i) // (i + 1)\n return c\ndef sum_Of_product(n):\n \"\"\"Find the sum of the product of consecutive binomial coefficients up to n.\"\"\"\n sum_ = 0\n for k in range(n + 1):\n sum_ += binomial_coefficient(n, k) * binomial_coefficient(n, k + 1)\n return sum_", "matching_cluster_idx": 4}, {"solution": "from math import comb\ndef sum_Of_product(n):\n result = 0\n for k in range(n + 1):\n result += comb(n, k) * comb(n, k+1)\n return result", "matching_cluster_idx": 5}, {"solution": "from math import comb\ndef sum_Of_product(n):\n total_sum = 0\n for k in range(n + 1):\n total_sum += comb(n, k) * comb(n, k + 1)\n return total_sum", "matching_cluster_idx": 5}]}, "Mbpp/597": {"dps": null, "dps_norm": null, "pass@1": 0.0, "profiled": []}, "Mbpp/604": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def reverse_words(s):\n words = s.split()\n return ' '.join(words[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n words = s.split()\n reversed_words = words[::-1]\n return ' '.join(reversed_words)", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s: str) -> str:\n words = s.split() # Split the string into a list of words\n reversed_words = words[::-1] # Reverse the list of words\n return ' '.join(reversed_words) # Join the reversed list back into a string", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n words = s.split()\n return ' '.join(words[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n words = s.split()\n reversed_words = words[::-1]\n return ' '.join(reversed_words)", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s: str) -> str:\n words = s.split() # Split the string into words\n reversed_words = words[::-1] # Reverse the list of words\n return ' '.join(reversed_words) # Join the reversed list back into a string", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n words = s.split()\n reversed_words = words[::-1]\n return ' '.join(reversed_words)", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n words = s.split()\n return ' '.join(words[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s: str) -> str:\n words = s.split()\n return ' '.join(words[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n words = s.split()\n return ' '.join(words[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s: str) -> str:\n words = s.split()\n return ' '.join(words[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n words = s.split() # Split the string into words\n reversed_words = words[::-1] # Reverse the list of words\n return ' '.join(reversed_words) # Join the reversed list back into a string", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n words = s.split() # Split the string into a list of words\n reversed_words = words[::-1] # Reverse the list of words\n return ' '.join(reversed_words) # Join the reversed list back into a string", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s: str) -> str:\n \"\"\"\n Reverses the order of words in the given string.\n \n Args:\n s (str): The input string.\n \n Returns:\n str: The string with the words reversed.\n \"\"\"\n words = s.split() # Split the string into words\n reversed_words = words[::-1] # Reverse the list of words\n return ' '.join(reversed_words) # Join the reversed list back into a string", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n words = s.split() # Split the string into a list of words\n reversed_words = words[::-1] # Reverse the list of words\n return ' '.join(reversed_words) # Join the reversed list back into a string", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n words = s.split() # Split the string into words\n reversed_words = words[::-1] # Reverse the list of words\n return ' '.join(reversed_words) # Join the reversed list back into a string", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n words = s.split()\n return ' '.join(words[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n words = s.split() # Split the string into words\n reversed_words = words[::-1] # Reverse the list of words\n return ' '.join(reversed_words) # Join the reversed list back into a string", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n words = s.split()\n return ' '.join(words[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n words = s.split()\n reversed_words = words[::-1]\n return ' '.join(reversed_words)", "matching_cluster_idx": 4}]}, "Mbpp/610": {"dps": 58.69565217391305, "dps_norm": 57.142857142857146, "pass@1": 100.0, "profiled": [{"solution": "def remove_kth_element(lst, k):\n if k <= 0 or k > len(lst):\n return lst\n return lst[:k-1] + lst[k:]", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(lst, k):\n if k < 1 or k > len(lst):\n raise ValueError(\"k is out of the range of the list\")\n return lst[:k-1] + lst[k:]", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(lst, k):\n if k < 1 or k > len(lst):\n return lst\n return lst[:k-1] + lst[k:]", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(lst, k):\n if k < 1 or k > len(lst):\n return lst # Return the original list if k is out of bounds\n return lst[:k-1] + lst[k:]", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(lst, k):\n if k <= 0 or k > len(lst):\n return lst\n return lst[:k-1] + lst[k:]", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(lst, k):\n if k > 0 and k <= len(lst):\n return lst[:k-1] + lst[k:]\n return lst", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(lst, k):\n # Ensure k is within the bounds of the list\n if k <= 0 or k > len(lst):\n return lst\n # Use list slicing to return a new list with the k'th element removed\n return lst[:k-1] + lst[k:]", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(lst, k):\n # Check if k is within the bounds of the list\n if k > 0 and k <= len(lst):\n # Use slicing to create a new list excluding the k'th element\n return lst[:k-1] + lst[k:]\n else:\n # If k is out of bounds, return the list as is\n return lst", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(lst, k):\n if k <= 0 or k > len(lst):\n return lst\n return lst[:k-1] + lst[k:]", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(lst, k):\n if k > 0 and k <= len(lst):\n return lst[:k-1] + lst[k:]\n else:\n raise ValueError(\"Index k is out of range\")", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(lst, k):\n if k > 0 and k <= len(lst):\n return lst[:k-1] + lst[k:]\n else:\n return lst", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(lst, k):\n if k <= 0 or k > len(lst):\n raise ValueError(\"k is out of range\")\n return lst[:k-1] + lst[k:]", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(lst, k):\n # Check if k is within the bounds of the list\n if k > 0 and k <= len(lst):\n # Use list slicing to return a new list with the k'th element removed\n return lst[:k-1] + lst[k:]\n else:\n # If k is out of bounds, return the original list\n return lst", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(lst, k):\n \"\"\"\n Removes the k'th element from the list.\n \n Args:\n lst (list): The list from which the k'th element is to be removed.\n k (int): The index of the element to be removed, starting from 1.\n \n Returns:\n list: A new list with the k'th element removed.\n \"\"\"\n if k < 1 or k > len(lst):\n raise IndexError(\"Index out of range\")\n return lst[:k-1] + lst[k:]", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(lst, k):\n if k < 1 or k > len(lst):\n return lst # Return the original list if k is out of range\n return lst[:k-1] + lst[k:]", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(lst, k):\n if k < 1 or k > len(lst):\n return lst\n return lst[:k-1] + lst[k:]", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(lst, k):\n if k < 1 or k > len(lst):\n return lst # Return the original list if k is out of range\n return lst[:k-1] + lst[k:] # Slice the list to exclude the k'th element", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(lst, k):\n if k <= 0 or k > len(lst):\n return lst\n return lst[:k-1] + lst[k:]", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(lst, k):\n if k < 1 or k > len(lst):\n return lst\n return lst[:k-1] + lst[k:]", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(lst, k):\n \"\"\"\n Remove the k'th element from the list.\n \"\"\"\n if k < 1 or k > len(lst):\n return lst # Return the original list if k is out of bounds\n return lst[:k-1] + lst[k:]", "matching_cluster_idx": 3}]}, "Mbpp/611": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 47.0, "profiled": [{"solution": "def max_of_nth(matrix, n):\n if n >= len(matrix[0]):\n raise ValueError(\"The n'th column does not exist in the matrix.\")\n max_value = matrix[0][n]\n for row in matrix:\n if row[n] > max_value:\n max_value = row[n]\n return max_value", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n if n >= len(matrix[0]):\n raise ValueError(\"Column index out of range\")\n return max(row[n] for row in matrix)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n # Check if the matrix is empty or n is out of range\n if not matrix or n >= len(matrix[0]):\n return None\n \n # Extract the n'th column from the matrix\n column = [row[n] for row in matrix]\n \n # Return the maximum value in the n'th column\n return max(column)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n if n >= len(matrix[0]):\n raise ValueError(\"Column index out of range\")\n return max(row[n] for row in matrix)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n if n >= len(matrix[0]):\n raise ValueError(\"Column index is out of range\")\n return max(row[n] for row in matrix)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n if n >= len(matrix[0]):\n raise IndexError(\"Column index out of range\")\n return max(row[n] for row in matrix)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n if n >= len(matrix[0]):\n raise ValueError(\"Column index is out of range\")\n return max(row[n] for row in matrix)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n if n >= len(matrix[0]):\n raise IndexError(\"Column index out of range\")\n return max(row[n] for row in matrix)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n if n >= len(matrix[0]):\n raise ValueError(\"Column index is out of bounds\")\n \n max_value = matrix[0][n]\n for row in matrix:\n if row[n] > max_value:\n max_value = row[n]\n return max_value", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n if n >= len(matrix[0]):\n raise ValueError(\"Column index is out of range\")\n \n max_value = matrix[0][n]\n for row in matrix:\n if row[n] > max_value:\n max_value = row[n]\n return max_value", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n if n >= len(matrix[0]):\n raise IndexError(\"Column index out of range\")\n return max(row[n] for row in matrix)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n if n >= len(matrix[0]):\n raise IndexError(\"Column index out of range\")\n return max(row[n] for row in matrix)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n if n >= len(matrix[0]):\n raise ValueError(\"Column index out of range\")\n return max(row[n] for row in matrix)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n if n >= len(matrix[0]):\n raise IndexError(\"Column index out of range\")\n \n max_value = matrix[0][n]\n for row in matrix:\n if row[n] > max_value:\n max_value = row[n]\n return max_value", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n # Ensure n is within the bounds of the matrix columns\n if n >= len(matrix[0]):\n raise ValueError(\"Column index is out of bounds\")\n \n # Extract the n'th column from the matrix\n nth_column = [row[n] for row in matrix]\n \n # Return the maximum value in the n'th column\n return max(nth_column)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n if n >= len(matrix[0]):\n raise ValueError(\"Column index is out of range.\")\n \n max_value = float('-inf')\n for row in matrix:\n if row[n] > max_value:\n max_value = row[n]\n return max_value", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n if n >= len(matrix[0]):\n raise ValueError(\"Column index is out of range\")\n return max(row[n] for row in matrix)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n if not matrix or n >= len(matrix[0]):\n return None\n return max(row[n] for row in matrix)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n if n >= len(matrix[0]):\n raise ValueError(\"Column index is out of range.\")\n \n max_value = matrix[0][n]\n for row in matrix:\n if row[n] > max_value:\n max_value = row[n]\n return max_value", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n if not matrix or not matrix[0]:\n raise ValueError(\"Matrix must be non-empty and have at least one row with elements\")\n if n >= len(matrix[0]):\n raise IndexError(\"Column index is out of range\")\n \n max_value = matrix[0][n]\n for row in matrix:\n if row[n] > max_value:\n max_value = row[n]\n return max_value", "matching_cluster_idx": 5}]}, "Mbpp/631": {"dps": 99.99999999999999, "dps_norm": 100.0, "pass@1": 11.0, "profiled": [{"solution": "def replace_spaces(s):\n return s.replace(' ', '_') if ' ' in s else s.replace('_', ' ')", "matching_cluster_idx": 7}, {"solution": "def replace_spaces(s):\n return s.replace(' ', '_') if ' ' in s else s.replace('_', ' ')", "matching_cluster_idx": 7}, {"solution": "def replace_spaces(s: str) -> str:\n return s.replace(' ', '_') if ' ' in s else s.replace('_', ' ')", "matching_cluster_idx": 7}, {"solution": "def replace_spaces(s):\n return s.replace(' ', '_') if ' ' in s else s.replace('_', ' ')", "matching_cluster_idx": 7}, {"solution": "def replace_spaces(s):\n return s.replace(' ', '_') if ' ' in s else s.replace('_', ' ')", "matching_cluster_idx": 7}, {"solution": "def replace_spaces(s):\n return s.replace(' ', '_') if ' ' in s else s.replace('_', ' ')", "matching_cluster_idx": 7}, {"solution": "def replace_spaces(s):\n return s.replace(' ', '_') if ' ' in s else s.replace('_', ' ')", "matching_cluster_idx": 7}, {"solution": "def replace_spaces(s):\n return s.replace(\" \", \"_\") if \" \" in s else s.replace(\"_\", \" \")", "matching_cluster_idx": 7}, {"solution": "def replace_spaces(s):\n return s.replace(' ', '_') if ' ' in s else s.replace('_', ' ')", "matching_cluster_idx": 7}, {"solution": "def replace_spaces(s):\n return s.replace(' ', '_') if ' ' in s else s.replace('_', ' ')", "matching_cluster_idx": 7}, {"solution": "def replace_spaces(s):\n return s.replace(' ', '_') if ' ' in s else s.replace('_', ' ')", "matching_cluster_idx": 7}]}, "Mbpp/632": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def move_zero(nums):\n # Initialize a list to store non-zero elements\n non_zero = [num for num in nums if num != 0]\n # Initialize a list to store zero elements\n zero = [num for num in nums if num == 0]\n # Concatenate non-zero elements with zero elements\n return non_zero + zero", "matching_cluster_idx": 6}, {"solution": "def move_zero(num_list):\n # Initialize two lists: one for non-zero elements and one for zeros\n non_zero = [x for x in num_list if x != 0]\n zero = [x for x in num_list if x == 0]\n # Concatenate the non-zero list and the zero list\n return non_zero + zero", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n # Create a list to store non-zero elements\n non_zeros = [num for num in nums if num != 0]\n # Create a list to store zero elements\n zeros = [num for num in nums if num == 0]\n # Combine the non-zero and zero elements\n return non_zeros + zeros", "matching_cluster_idx": 6}, {"solution": "def move_zero(num_list):\n # Create a list to store non-zero elements\n non_zero = [num for num in num_list if num != 0]\n # Count the number of zeros in the original list\n zero_count = num_list.count(0)\n # Append the zeros to the end of the non-zero list\n result = non_zero + [0] * zero_count\n return result", "matching_cluster_idx": 6}, {"solution": "def move_zero(num_list):\n # Create two lists: one for non-zero elements and one for zeros\n non_zero = [x for x in num_list if x != 0]\n zero = [x for x in num_list if x == 0]\n \n # Concatenate the non-zero list and the zero list\n return non_zero + zero", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n # Filter out all non-zero elements\n non_zero_elements = [num for num in nums if num != 0]\n # Count the number of zeros in the original list\n zero_count = nums.count(0)\n # Append the zeros to the end of the non-zero elements list\n return non_zero_elements + [0] * zero_count", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n # Create a list to store non-zero elements\n non_zero = [num for num in nums if num != 0]\n # Create a list to store zero elements\n zero = [num for num in nums if num == 0]\n # Combine non-zero elements with zero elements\n return non_zero + zero", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n # Create a list to store non-zero elements\n non_zero = [x for x in nums if x != 0]\n # Create a list to store the zero elements\n zero = [x for x in nums if x == 0]\n # Combine the non-zero and zero lists\n return non_zero + zero", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n # Create a list to store non-zero elements\n non_zeros = [x for x in nums if x != 0]\n # Create a list to store the count of zeros\n zeros = [0] * (len(nums) - len(non_zeros))\n # Combine non-zero elements with zeros\n return non_zeros + zeros", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n # Create a list to hold non-zero elements\n non_zero_elements = [num for num in nums if num != 0]\n # Calculate the number of zeros to append\n zero_count = len(nums) - len(non_zero_elements)\n # Append the zeros to the end of the non-zero elements list\n result = non_zero_elements + [0] * zero_count\n return result", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n \"\"\"\n Function to move all zeroes to the end of the given list.\n \"\"\"\n # Initialize a pointer to track the position where the next non-zero element should be placed\n insert_position = 0\n \n # Iterate through the list\n for num in nums:\n if num != 0:\n nums[insert_position] = num\n insert_position += 1\n \n # Fill the remaining positions with zeroes\n for i in range(insert_position, len(nums)):\n nums[i] = 0\n \n return nums", "matching_cluster_idx": 6}, {"solution": "def move_zero(num_list):\n # Create a list to store non-zero elements\n non_zero = [num for num in num_list if num != 0]\n # Create a list to store zero elements\n zero = [num for num in num_list if num == 0]\n # Concatenate non-zero elements with zero elements\n return non_zero + zero", "matching_cluster_idx": 6}, {"solution": "def move_zero(num_list):\n # Create a list to hold non-zero elements\n non_zero = [num for num in num_list if num != 0]\n # Create a list to hold zero elements\n zero = [num for num in num_list if num == 0]\n # Combine non-zero elements with zero elements\n return non_zero + zero", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n # Filter out all non-zero elements\n non_zeroes = [x for x in nums if x != 0]\n # Count the number of zeroes\n zero_count = nums.count(0)\n # Combine non-zero elements with the same number of zeroes at the end\n return non_zeroes + [0] * zero_count", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n # Create a list to hold non-zero elements\n non_zeroes = [num for num in nums if num != 0]\n # Create a list to hold zeroes\n zeroes = [0] * (len(nums) - len(non_zeroes))\n # Combine non-zeroes and zeroes\n return non_zeroes + zeroes", "matching_cluster_idx": 6}, {"solution": "def move_zero(num_list):\n # Create a list to hold non-zero elements\n non_zero = [num for num in num_list if num != 0]\n # Count the number of zeros in the original list\n zero_count = num_list.count(0)\n # Append the zeros to the end of the non-zero list\n result = non_zero + [0] * zero_count\n return result", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n # Create a list to store non-zero elements\n non_zero = [x for x in nums if x != 0]\n # Create a list to store zero elements\n zero = [x for x in nums if x == 0]\n # Concatenate non-zero elements with zero elements\n return non_zero + zero", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n # Create a list to hold non-zero elements\n non_zero = [num for num in nums if num != 0]\n # Create a list to hold zero elements\n zero = [0] * (len(nums) - len(non_zero))\n # Concatenate the non-zero elements with the zero elements\n return non_zero + zero", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n # Create a list to hold non-zero elements\n non_zeros = [x for x in nums if x != 0]\n # Count the number of zeros in the original list\n zero_count = nums.count(0)\n # Append the zeros to the end of the non-zero elements\n result = non_zeros + [0] * zero_count\n return result", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n \"\"\"\n Moves all zeroes to the end of the given list.\n \"\"\"\n non_zero_elements = [num for num in nums if num != 0]\n zero_elements = [num for num in nums if num == 0]\n return non_zero_elements + zero_elements", "matching_cluster_idx": 6}]}, "Mbpp/633": {"dps": 94.3089430894309, "dps_norm": 50.0, "pass@1": 63.0, "profiled": [{"solution": "def pair_xor_Sum(arr, n):\n total_sum = 0\n for i in range(n):\n for j in range(i + 1, n):\n total_sum += arr[i] ^ arr[j]\n return total_sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(arr, n):\n total_sum = 0\n for i in range(n):\n for j in range(i + 1, n):\n total_sum += arr[i] ^ arr[j]\n return total_sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(arr, n):\n total_sum = 0\n for i in range(n):\n for j in range(i + 1, n):\n total_sum += arr[i] ^ arr[j]\n return total_sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(nums, n):\n total_sum = 0\n for i in range(n):\n for j in range(i + 1, n):\n total_sum += nums[i] ^ nums[j]\n return total_sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(nums, n):\n total_sum = 0\n for i in range(n):\n for j in range(i + 1, n):\n total_sum += nums[i] ^ nums[j]\n return total_sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(numbers, n):\n total_sum = 0\n for i in range(n):\n for j in range(i + 1, n):\n total_sum += numbers[i] ^ numbers[j]\n return total_sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(arr, n):\n total_sum = 0\n for i in range(n):\n for j in range(i + 1, n):\n total_sum += arr[i] ^ arr[j]\n return total_sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(nums, n):\n total_sum = 0\n for i in range(n):\n for j in range(i + 1, n):\n total_sum += nums[i] ^ nums[j]\n return total_sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(arr, n):\n total_xor_sum = 0\n for i in range(n):\n for j in range(i + 1, n):\n total_xor_sum += arr[i] ^ arr[j]\n return total_xor_sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(nums, n):\n total_sum = 0\n for i in range(n):\n for j in range(i + 1, n):\n total_sum += nums[i] ^ nums[j]\n return total_sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(arr, n):\n total_xor_sum = 0\n for i in range(n):\n for j in range(i + 1, n):\n total_xor_sum += arr[i] ^ arr[j]\n return total_xor_sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(nums, n):\n total_xor_sum = 0\n for i in range(n):\n for j in range(i + 1, n):\n total_xor_sum += nums[i] ^ nums[j]\n return total_xor_sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(nums, n):\n total_sum = 0\n for i in range(n):\n for j in range(i + 1, n):\n total_sum += nums[i] ^ nums[j]\n return total_sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(nums, n):\n total_xor_sum = 0\n for i in range(n):\n for j in range(i + 1, n):\n total_xor_sum += nums[i] ^ nums[j]\n return total_xor_sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(nums, n):\n total_sum = 0\n for i in range(n):\n for j in range(i + 1, n):\n total_sum += nums[i] ^ nums[j]\n return total_sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(nums, n):\n total_xor_sum = 0\n for i in range(n):\n for j in range(i + 1, n):\n total_xor_sum += nums[i] ^ nums[j]\n return total_xor_sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(arr, n):\n total_sum = 0\n for i in range(n):\n for j in range(i + 1, n):\n total_sum += arr[i] ^ arr[j]\n return total_sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(nums, n):\n total_xor_sum = 0\n for i in range(n):\n for j in range(i + 1, n):\n total_xor_sum += nums[i] ^ nums[j]\n return total_xor_sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(nums, n):\n total_sum = 0\n for i in range(n):\n for j in range(i + 1, n):\n total_sum += nums[i] ^ nums[j]\n return total_sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(nums, n):\n total_xor_sum = 0\n for i in range(n):\n for j in range(i + 1, n):\n total_xor_sum += nums[i] ^ nums[j]\n return total_xor_sum", "matching_cluster_idx": 2}]}, "Mbpp/644": {"dps": 71.80851063829786, "dps_norm": 73.33333333333333, "pass@1": 99.0, "profiled": [{"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n Reverses the array upto a given position k.\n \n Args:\n arr (list): The list to be reversed.\n k (int): The position upto which the array should be reversed.\n \n Returns:\n list: The array after reversing the first k elements.\n \"\"\"\n return arr[:k][::-1] + arr[k:]", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n # Reverse the array up to the given position k\n return arr[:k][::-1] + arr[k:]", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n # Check if k is 0 or negative, return the array as is\n if k <= 0:\n return arr\n # Reverse the array from start to k (exclusive)\n return arr[:k][::-1] + arr[k:]", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n Function to reverse an array upto a given position k.\n \"\"\"\n return arr[:k][::-1] + arr[k:]", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n Reverses the array up to a given position k.\n \n Args:\n arr (list): The list of elements to reverse.\n k (int): The position up to which the array should be reversed.\n \n Returns:\n list: The modified array after reversing up to position k.\n \"\"\"\n # Ensure k is within the bounds of the array\n if k < 0 or k > len(arr):\n raise ValueError(\"k is out of bounds for the array\")\n \n # Reverse the array up to k\n return arr[:k][::-1] + arr[k:]", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n # Check if k is within the bounds of the array\n if k < 0 or k > len(arr):\n raise ValueError(\"Position k is out of bounds\")\n \n # Reverse the array from the start up to the kth position\n return arr[:k][::-1] + arr[k:]", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n Reverses the array up to a given position k.\n \n Args:\n arr (list): The list to be reversed.\n k (int): The position up to which the array should be reversed.\n \n Returns:\n list: The array after reversing up to position k.\n \"\"\"\n return arr[:k][::-1] + arr[k:]", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n Reverses the array up to a given position k.\n :param arr: List[int] - The array to be reversed\n :param k: int - The position up to which the array should be reversed\n :return: List[int] - The array after reversing up to position k\n \"\"\"\n return arr[:k][::-1] + arr[k:]", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n Reverses the array up to the given position k.\n \n Args:\n arr (list): The input list to reverse.\n k (int): The position up to which the array should be reversed.\n \n Returns:\n list: The array reversed up to the position k.\n \"\"\"\n # Reverse the array from the start up to the k-th position\n return arr[:k][::-1] + arr[k:]", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n This function reverses an array up to a given position k.\n Args:\n arr (list): The input list to be reversed.\n k (int): The position upto which the array should be reversed.\n Returns:\n list: The array after reversing the elements up to position k.\n \"\"\"\n # Reverse the array up to the k-th element (0-indexed)\n return arr[:k][::-1] + arr[k:]", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n # Reverse the array from the start up to the k-th position\n return arr[:k][::-1] + arr[k:]", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n Reverses the array up to the given position k.\n \n Args:\n arr (list): The list of elements to be reversed.\n k (int): The position up to which the array should be reversed.\n \n Returns:\n list: The array reversed up to the k-th position.\n \"\"\"\n return arr[:k][::-1] + arr[k:]", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n Reverses the array up to a given position k.\n \n Parameters:\n arr (list): The list of elements.\n k (int): The position up to which the array should be reversed.\n \n Returns:\n list: The array with the elements up to position k reversed.\n \"\"\"\n return arr[:k][::-1] + arr[k:]", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n Reverses the array up to a given position k.\n \n Args:\n arr (list): The list of elements.\n k (int): The position upto which the array should be reversed.\n \n Returns:\n list: The array reversed up to position k.\n \"\"\"\n return arr[:k][::-1] + arr[k:]", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n Reverses the array up to a given position k.\n \n Args:\n arr (list): The list of elements to reverse.\n k (int): The position upto which the array should be reversed.\n \n Returns:\n list: The array after reversing elements up to position k.\n \"\"\"\n return arr[:k][::-1] + arr[k:]", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n # Ensure k is within the bounds of the array\n if k < 0 or k > len(arr):\n raise ValueError(\"Position k is out of bounds\")\n \n # Reverse the array from the start to k (exclusive)\n return arr[:k][::-1] + arr[k:]", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n Reverses the array up to the given position k.\n \n Args:\n arr (list): The list of elements to reverse.\n k (int): The position upto which the array needs to be reversed.\n \n Returns:\n list: The array after reversing up to position k.\n \"\"\"\n # Ensure k is within the bounds of the array\n if k < 0 or k > len(arr):\n raise ValueError(\"Position k is out of bounds for the array.\")\n \n # Reverse the array up to k (inclusive)\n return arr[:k][::-1] + arr[k:]", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n # Check if k is within the bounds of the array\n if k < 0 or k > len(arr):\n return arr # Return the original array if k is out of bounds\n \n # Reverse the array from start to k (inclusive)\n return arr[:k][::-1] + arr[k:]", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n # Reverse the array from the start up to the k-th position\n return arr[:k][::-1] + arr[k:]", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n Reverse the array up to a given position k.\n Args:\n arr (list): The list to be reversed.\n k (int): The position upto which the array should be reversed.\n Returns:\n list: The array reversed up to position k.\n \"\"\"\n # Reverse the array up to position k using slicing\n return arr[:k][::-1] + arr[k:]", "matching_cluster_idx": 10}]}, "Mbpp/720": {"dps": 40.21978021978022, "dps_norm": 75.0, "pass@1": 26.0, "profiled": [{"solution": "def add_dict_to_tuple(input_tuple, input_dict):\n # Convert the tuple to a list so it can be modified\n temp_list = list(input_tuple)\n # Append the dictionary to the end of the list\n temp_list.append(input_dict)\n # Convert the list back to a tuple\n output_tuple = tuple(temp_list)\n return output_tuple", "matching_cluster_idx": 3}, {"solution": "def add_dict_to_tuple(input_tuple, input_dict):\n # Combine the tuple and dictionary into a new list\n combined_list = list(input_tuple) + [input_dict]\n # Convert the list back to a tuple\n combined_tuple = tuple(combined_list)\n return combined_tuple", "matching_cluster_idx": 1}, {"solution": "def add_dict_to_tuple(tup, dictionary):\n # Convert the tuple to a list to allow modification\n temp_list = list(tup)\n # Add the dictionary to the end of the list\n temp_list.append(dictionary)\n # Convert the list back to a tuple\n result_tuple = tuple(temp_list)\n return result_tuple", "matching_cluster_idx": 3}, {"solution": "def add_dict_to_tuple(input_tuple, input_dict):\n \"\"\"\n Add a dictionary to the end of a tuple.\n\n Parameters:\n input_tuple (tuple): The original tuple to which the dictionary will be added.\n input_dict (dict): The dictionary to be added to the tuple.\n\n Returns:\n tuple: A new tuple that includes the original tuple elements followed by the dictionary.\n \"\"\"\n return input_tuple + (input_dict,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(input_tuple, input_dict):\n \"\"\"\n Add a dictionary to the end of a tuple and return the new tuple.\n \n Args:\n input_tuple (tuple): The original tuple.\n input_dict (dict): The dictionary to be added to the tuple.\n \n Returns:\n tuple: A new tuple with the dictionary added at the end.\n \"\"\"\n # Combine the tuple and the dictionary into a list\n combined_list = list(input_tuple) + [input_dict]\n # Convert the list back to a tuple\n result_tuple = tuple(combined_list)\n return result_tuple", "matching_cluster_idx": 1}, {"solution": "def add_dict_to_tuple(tup, dictionary):\n # Combine the tuple and the dictionary into a new list\n combined_list = list(tup) + [dictionary]\n # Convert the list back to a tuple\n combined_tuple = tuple(combined_list)\n return combined_tuple", "matching_cluster_idx": 1}, {"solution": "def add_dict_to_tuple(input_tuple, input_dict):\n # Convert the tuple to a list to allow modification\n temp_list = list(input_tuple)\n # Append the dictionary to the list\n temp_list.append(input_dict)\n # Convert the list back to a tuple\n output_tuple = tuple(temp_list)\n return output_tuple", "matching_cluster_idx": 3}, {"solution": "def add_dict_to_tuple(input_tuple, input_dict):\n # Combine the tuple and the dictionary into a new tuple that includes the dictionary as the last element\n combined_tuple = input_tuple + (input_dict,)\n return combined_tuple", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(test_tuple, test_dict):\n # Convert the tuple to a list to allow modification\n temp_list = list(test_tuple)\n # Add the dictionary to the end of the list\n temp_list.append(test_dict)\n # Convert the list back to a tuple\n result_tuple = tuple(temp_list)\n return result_tuple", "matching_cluster_idx": 3}, {"solution": "def add_dict_to_tuple(tup, dictionary):\n # Convert the tuple to a list to allow modification\n tup_list = list(tup)\n # Update the list with the dictionary items\n tup_list.append(dictionary)\n # Convert the list back to a tuple\n return tuple(tup_list)", "matching_cluster_idx": 3}, {"solution": "def add_dict_to_tuple(test_tuple, test_dict):\n # Concatenate the tuple and the dictionary into a single iterable\n combined = (*test_tuple, test_dict)\n return combined", "matching_cluster_idx": 3}, {"solution": "def add_dict_to_tuple(input_tuple, input_dict):\n # Convert the tuple to a list to allow modification (since tuples are immutable)\n temp_list = list(input_tuple)\n # Add the dictionary to the end of the list\n temp_list.append(input_dict)\n # Convert the list back to a tuple\n output_tuple = tuple(temp_list)\n return output_tuple", "matching_cluster_idx": 3}, {"solution": "def add_dict_to_tuple(tup, dictionary):\n # Convert the tuple to a list to allow modification\n temp_list = list(tup)\n # Add the dictionary to the end of the list\n temp_list.append(dictionary)\n # Convert the list back to a tuple\n result_tuple = tuple(temp_list)\n return result_tuple", "matching_cluster_idx": 3}, {"solution": "def add_dict_to_tuple(tup, dictionary):\n \"\"\"\n Add a dictionary to the end of a tuple and return the new tuple.\n \n Args:\n tup (tuple): The original tuple to which the dictionary will be appended.\n dictionary (dict): The dictionary to be appended to the tuple.\n \n Returns:\n tuple: A new tuple with the original tuple followed by the dictionary.\n \"\"\"\n return tup + (dictionary,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(tup, dictionary):\n # Convert the tuple to a list to allow modification\n temp_list = list(tup)\n # Add the dictionary to the end of the list\n temp_list.append(dictionary)\n # Convert the list back to a tuple\n result_tuple = tuple(temp_list)\n return result_tuple", "matching_cluster_idx": 3}, {"solution": "def add_dict_to_tuple(input_tuple, input_dict):\n # Combine the tuple and the dictionary into a new list\n combined_list = list(input_tuple) + [input_dict]\n # Convert the list back to a tuple\n result_tuple = tuple(combined_list)\n return result_tuple", "matching_cluster_idx": 1}, {"solution": "def add_dict_to_tuple(input_tuple, input_dict):\n # Convert the tuple to a list to allow modification\n tuple_list = list(input_tuple)\n # Add the dictionary to the end of the list\n tuple_list.append(input_dict)\n # Convert the list back to a tuple\n result_tuple = tuple(tuple_list)\n return result_tuple", "matching_cluster_idx": 3}, {"solution": "def add_dict_to_tuple(tup, dictionary):\n # Convert the tuple to a list to allow modification\n temp = list(tup)\n # Add the dictionary to the end of the list\n temp.append(dictionary)\n # Convert the list back to a tuple\n return tuple(temp)", "matching_cluster_idx": 3}, {"solution": "def add_dict_to_tuple(tuple_input, dict_input):\n # Convert the tuple to a list so we can append\n tuple_list = list(tuple_input)\n # Append the dictionary to the list\n tuple_list.append(dict_input)\n # Convert the list back to a tuple and return\n return tuple(tuple_list)", "matching_cluster_idx": 3}, {"solution": "def add_dict_to_tuple(test_tuple, dict_to_add):\n # Convert the tuple to a list to allow modification\n temp_list = list(test_tuple)\n # Add the dictionary to the end of the list\n temp_list.append(dict_to_add)\n # Convert the list back to a tuple\n result_tuple = tuple(temp_list)\n return result_tuple", "matching_cluster_idx": 3}]}, "Mbpp/725": {"dps": 67.97814207650272, "dps_norm": 72.5, "pass@1": 87.0, "profiled": [{"solution": "import re\ndef extract_quotation(input_string):\n # Use regular expression to find all substrings enclosed in double quotes\n matches = re.findall(r'\"(.*?)\"', input_string)\n return matches", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(text):\n \"\"\"\n Extract values between quotation marks \" \" of the given string.\n \"\"\"\n # Use regex to find all substrings within quotation marks\n matches = re.findall(r'\"(.*?)\"', text)\n return matches", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(input_string):\n # Use regular expression to find all substrings enclosed in quotation marks\n matches = re.findall(r'\"(.*?)\"', input_string)\n return matches", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(text):\n # Use regular expression to find all substrings within quotation marks\n return [match.group(1) for match in re.finditer(r'\"(.*?)\"', text)]", "matching_cluster_idx": 4}, {"solution": "import re\ndef extract_quotation(text):\n # Use regular expression to find all substrings within quotation marks\n matches = re.findall(r'\"(.*?)\"', text)\n return matches", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(text):\n # Use regular expression to find all substrings in quotation marks\n matches = re.findall(r'\"(.*?)\"', text)\n return matches", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(text):\n # Use regular expression to find all substrings enclosed in double quotes\n matches = re.findall(r'\"(.*?)\"', text)\n return matches", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(input_string):\n # Use regex to find all substrings enclosed in quotation marks\n pattern = r'\"(.*?)\"'\n matches = re.findall(pattern, input_string)\n return matches", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(text):\n # Use regular expression to find all substrings enclosed in quotation marks\n matches = re.findall(r'\"(.*?)\"', text)\n return matches", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(text):\n # Use regular expression to find all substrings between double quotes\n pattern = r'\"(.*?)\"'\n matches = re.findall(pattern, text)\n return matches", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(input_string):\n # Use regex to find all substrings enclosed in quotation marks\n return re.findall(r'\"(.*?)\"', input_string)", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(input_string):\n # Use regex to find all substrings enclosed in quotation marks\n matches = re.findall(r'\"(.*?)\"', input_string)\n return matches", "matching_cluster_idx": 4}, {"solution": "import re\ndef extract_quotation(text):\n # Use regular expression to find all substrings enclosed in double quotes\n matches = re.findall(r'\"(.*?)\"', text)\n return matches", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(text):\n # Use regex to find all substrings enclosed in quotation marks\n pattern = r'\"(.*?)\"'\n matches = re.findall(pattern, text)\n return matches", "matching_cluster_idx": 4}, {"solution": "import re\ndef extract_quotation(text):\n # Use regular expression to find all substrings between double quotes\n matches = re.findall(r'\"(.*?)\"', text)\n return matches", "matching_cluster_idx": 4}, {"solution": "import re\ndef extract_quotation(text):\n # Use regular expression to find all substrings enclosed in quotation marks\n matches = re.findall(r'\"(.*?)\"', text)\n return matches", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(input_string):\n # Use regular expression to find all substrings enclosed in double quotes\n matches = re.findall(r'\"(.*?)\"', input_string)\n return matches", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(input_string):\n # Use regular expression to find all substrings enclosed in quotation marks\n matches = re.findall(r'\"(.*?)\"', input_string)\n return matches", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(input_string):\n # Use regular expression to find all substrings within double quotes\n matches = re.findall(r'\"(.*?)\"', input_string)\n return matches", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(input_string):\n # Use regular expression to find all matches between quotation marks\n matches = re.findall(r'\"(.*?)\"', input_string)\n return matches", "matching_cluster_idx": 5}]}, "Mbpp/732": {"dps": 95.29069767441861, "dps_norm": 97.0, "pass@1": 100.0, "profiled": [{"solution": "def replace_specialchar(text):\n # Replace spaces, commas, and dots with a colon\n return text.replace(' ', ':').replace(',', ':').replace('.', ':')", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(text):\n replacements = {' ': ':', ',': ':', '.': ':'}\n for old, new in replacements.items():\n text = text.replace(old, new)\n return text", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(text):\n # Replace spaces, commas, and dots with a colon\n return text.replace(' ', ':').replace(',', ':').replace('.', ':')", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(text):\n # Replace spaces, commas, and dots with a colon\n return text.replace(' ', ':').replace(',', ':').replace('.', ':')", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(text):\n replacements = {' ': ':', ',': ':', '.': ':'}\n for old, new in replacements.items():\n text = text.replace(old, new)\n return text", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(text):\n replacements = {' ': ':', ',': ':', '.': ':'}\n for char, replacement in replacements.items():\n text = text.replace(char, replacement)\n return text", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(text):\n replacements = {' ': ':', ',': ':', '.': ':'}\n for old, new in replacements.items():\n text = text.replace(old, new)\n return text", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(text):\n \"\"\"\n Replace all occurrences of spaces, commas, or dots with a colon.\n \"\"\"\n return text.replace(' ', ':').replace(',', ':').replace('.', ':')", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(text):\n replacements = {' ': ':', ',': ':', '.': ':'}\n for old, new in replacements.items():\n text = text.replace(old, new)\n return text", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(text):\n replacements = {' ': ':', ',': ':', '.': ':'}\n for old, new in replacements.items():\n text = text.replace(old, new)\n return text", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(text):\n replacements = {' ': ':', ',': ':', '.': ':'}\n for old, new in replacements.items():\n text = text.replace(old, new)\n return text", "matching_cluster_idx": 9}, {"solution": "import re\ndef replace_specialchar(text):\n \"\"\"\n Replace all occurrences of spaces, commas, or dots with a colon.\n \"\"\"\n return re.sub(\"[ ,.]\", \":\", text)", "matching_cluster_idx": 3}, {"solution": "def replace_specialchar(text):\n # Replace spaces, commas, and dots with a colon\n return text.replace(' ', ':').replace(',', ':').replace('.', ':')", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(input_string):\n # Replace all spaces, commas, and dots with a colon\n return input_string.replace(' ', ':').replace(',', ':').replace('.', ':')", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(text):\n replacements = {' ': ':', ',': ':', '.': ':'}\n for char, replacement in replacements.items():\n text = text.replace(char, replacement)\n return text", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(text):\n replacements = {' ': ':', ',': ':', '.': ':'}\n for old, new in replacements.items():\n text = text.replace(old, new)\n return text", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(text):\n replacements = {\n ' ': ':',\n ',': ':',\n '.': ':'\n }\n for old, new in replacements.items():\n text = text.replace(old, new)\n return text", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(text):\n replacements = {\n ' ': ':',\n ',': ':',\n '.': ':'\n }\n for old, new in replacements.items():\n text = text.replace(old, new)\n return text", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(text):\n # Replace spaces, commas, and dots with a colon\n replaced_text = text.replace(' ', ':').replace(',', ':').replace('.', ':')\n return replaced_text", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(text):\n # Replace spaces, commas, and dots with a colon\n return text.replace(' ', ':').replace(',', ':').replace('.', ':')", "matching_cluster_idx": 9}]}, "Mbpp/740": {"dps": 50.981818181818184, "dps_norm": 61.111111111111114, "pass@1": 99.0, "profiled": [{"solution": "def tuple_to_dict(test_tup):\n res = {}\n for i in range(0, len(test_tup) - 1, 2):\n res[test_tup[i]] = test_tup[i + 1]\n return res", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(input_tuple):\n if len(input_tuple) % 2 != 0:\n raise ValueError(\"Input tuple must have an even number of elements\")\n \n result = {}\n for i in range(0, len(input_tuple), 2):\n key = input_tuple[i]\n value = input_tuple[i + 1]\n result[key] = value\n \n return result", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(input_tuple):\n if len(input_tuple) % 2 != 0:\n raise ValueError(\"Input tuple must have an even number of elements\")\n \n result_dict = {}\n for i in range(0, len(input_tuple), 2):\n key, value = input_tuple[i], input_tuple[i + 1]\n result_dict[key] = value\n return result_dict", "matching_cluster_idx": 4}, {"solution": "def tuple_to_dict(input_tuple):\n if len(input_tuple) % 2 != 0:\n raise ValueError(\"Input tuple must have an even number of elements\")\n \n result_dict = {}\n for i in range(0, len(input_tuple), 2):\n key, value = input_tuple[i], input_tuple[i+1]\n result_dict[key] = value\n return result_dict", "matching_cluster_idx": 4}, {"solution": "def tuple_to_dict(t):\n if len(t) % 2 != 0:\n raise ValueError(\"The tuple length must be even.\")\n \n result = {}\n for i in range(0, len(t), 2):\n key, value = t[i], t[i+1]\n result[key] = value\n return result", "matching_cluster_idx": 4}, {"solution": "def tuple_to_dict(t):\n if len(t) % 2 != 0:\n raise ValueError(\"Tuple must have an even number of elements\")\n \n result = {}\n for i in range(0, len(t), 2):\n result[t[i]] = t[i+1]\n return result", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(test_tuple):\n result_dict = {}\n for i in range(0, len(test_tuple), 2):\n if i + 1 < len(test_tuple):\n result_dict[test_tuple[i]] = test_tuple[i + 1]\n return result_dict", "matching_cluster_idx": 3}, {"solution": "def tuple_to_dict(tup):\n # Initialize an empty dictionary\n result_dict = {}\n \n # Iterate over the tuple in steps of 2\n for i in range(0, len(tup), 2):\n # Check if there are at least two more elements to pair\n if i + 1 < len(tup):\n result_dict[tup[i]] = tup[i + 1]\n else:\n # If only one element is left, it won't have a pair\n result_dict[tup[i]] = None\n \n return result_dict", "matching_cluster_idx": 3}, {"solution": "def tuple_to_dict(test_tup):\n res = dict(zip(test_tup[::2], test_tup[1::2]))\n return res", "matching_cluster_idx": 8}, {"solution": "def tuple_to_dict(test_tup):\n # Check if the tuple has an even number of elements\n if len(test_tup) % 2 != 0:\n raise ValueError(\"The tuple must have an even number of elements\")\n\n # Create a dictionary using adjacent elements\n res = {}\n for i in range(0, len(test_tup), 2):\n res[test_tup[i]] = test_tup[i + 1]\n\n return res", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(tup):\n if len(tup) % 2 != 0:\n raise ValueError(\"The tuple length must be even.\")\n \n result_dict = {}\n for i in range(0, len(tup), 2):\n key = tup[i]\n value = tup[i + 1]\n result_dict[key] = value\n return result_dict", "matching_cluster_idx": 4}, {"solution": "def tuple_to_dict(t):\n if len(t) % 2 != 0:\n raise ValueError(\"The tuple must have an even number of elements\")\n \n result = {}\n for i in range(0, len(t), 2):\n key, value = t[i], t[i+1]\n result[key] = value\n return result", "matching_cluster_idx": 4}, {"solution": "def tuple_to_dict(t):\n if len(t) % 2 != 0:\n raise ValueError(\"Input tuple must have an even number of elements\")\n \n result = {}\n for i in range(0, len(t), 2):\n key = t[i]\n value = t[i + 1]\n result[key] = value\n return result", "matching_cluster_idx": 4}, {"solution": "def tuple_to_dict(input_tuple):\n # Initialize an empty dictionary\n result_dict = {}\n \n # Iterate over the tuple, taking two elements at a time\n for i in range(0, len(input_tuple), 2):\n # Check if there are at least two more elements left\n if i + 1 < len(input_tuple):\n # Assign the pair of elements to the dictionary\n result_dict[input_tuple[i]] = input_tuple[i + 1]\n \n return result_dict", "matching_cluster_idx": 3}, {"solution": "def tuple_to_dict(tup):\n if len(tup) % 2 != 0:\n raise ValueError(\"Tuple must contain an even number of elements\")\n \n result = {}\n for i in range(0, len(tup), 2):\n result[tup[i]] = tup[i + 1]\n \n return result", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(input_tuple):\n if len(input_tuple) % 2 != 0:\n raise ValueError(\"Input tuple must have an even number of elements\")\n \n result_dict = {}\n for i in range(0, len(input_tuple), 2):\n key = input_tuple[i]\n value = input_tuple[i + 1]\n result_dict[key] = value\n return result_dict", "matching_cluster_idx": 4}, {"solution": "def tuple_to_dict(input_tuple):\n if len(input_tuple) % 2 != 0:\n raise ValueError(\"Input tuple must have an even number of elements\")\n \n result_dict = {}\n for i in range(0, len(input_tuple), 2):\n key = input_tuple[i]\n value = input_tuple[i + 1]\n result_dict[key] = value\n \n return result_dict", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(tup):\n if len(tup) % 2 != 0:\n raise ValueError(\"The tuple must have an even number of elements\")\n \n result = {}\n for i in range(0, len(tup), 2):\n result[tup[i]] = tup[i+1]\n return result", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(tup):\n if len(tup) % 2 != 0:\n raise ValueError(\"Tuple must have an even number of elements\")\n \n result = {}\n for i in range(0, len(tup), 2):\n result[tup[i]] = tup[i+1]\n return result", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(input_tuple):\n # Check if the tuple has an even number of elements\n if len(input_tuple) % 2 != 0:\n raise ValueError(\"Input tuple must have an even number of elements\")\n \n # Create a dictionary from the tuple elements\n result_dict = {}\n for i in range(0, len(input_tuple), 2):\n key = input_tuple[i]\n value = input_tuple[i + 1]\n result_dict[key] = value\n return result_dict", "matching_cluster_idx": 5}]}, "Mbpp/744": {"dps": 17.123287671232877, "dps_norm": 41.66666666666667, "pass@1": 100.0, "profiled": [{"solution": "def check_none(test_tuple):\n return any(element is None for element in test_tuple)", "matching_cluster_idx": 2}, {"solution": "def check_none(test_tuple):\n return any(item is None for item in test_tuple)", "matching_cluster_idx": 1}, {"solution": "def check_none(test_tuple):\n return any(x is None for x in test_tuple)", "matching_cluster_idx": 2}, {"solution": "def check_none(test_tuple):\n # Check if None is in the tuple\n return any(item is None for item in test_tuple)", "matching_cluster_idx": 2}, {"solution": "def check_none(test_tuple):\n return any(item is None for item in test_tuple)", "matching_cluster_idx": 1}, {"solution": "def check_none(test_tuple):\n return any(item is None for item in test_tuple)", "matching_cluster_idx": 1}, {"solution": "def check_none(test_tuple):\n return any(x is None for x in test_tuple)", "matching_cluster_idx": 2}, {"solution": "def check_none(test_tuple):\n return any(item is None for item in test_tuple)", "matching_cluster_idx": 1}, {"solution": "def check_none(test_tuple):\n return any(x is None for x in test_tuple)", "matching_cluster_idx": 2}, {"solution": "def check_none(test_tuple):\n # Check if any element in the tuple is None\n return any(element is None for element in test_tuple)", "matching_cluster_idx": 1}, {"solution": "def check_none(test_tuple):\n return any(x is None for x in test_tuple)", "matching_cluster_idx": 2}, {"solution": "def check_none(test_tup):\n return any(item is None for item in test_tup)", "matching_cluster_idx": 2}, {"solution": "def check_none(test_tuple):\n return any(item is None for item in test_tuple)", "matching_cluster_idx": 1}, {"solution": "def check_none(test_tuple):\n return any(element is None for element in test_tuple)", "matching_cluster_idx": 2}, {"solution": "def check_none(input_tuple):\n return any(element is None for element in input_tuple)", "matching_cluster_idx": 1}, {"solution": "def check_none(test_tuple):\n return any(item is None for item in test_tuple)", "matching_cluster_idx": 1}, {"solution": "def check_none(test_tup):\n return any(item is None for item in test_tup)", "matching_cluster_idx": 2}, {"solution": "def check_none(test_tuple):\n return any(item is None for item in test_tuple)", "matching_cluster_idx": 1}, {"solution": "def check_none(test_tuple):\n return any(element is None for element in test_tuple)", "matching_cluster_idx": 2}, {"solution": "def check_none(test_tuple):\n return any(item is None for item in test_tuple)", "matching_cluster_idx": 1}]}, "Mbpp/750": {"dps": 88.70748299319727, "dps_norm": 90.0, "pass@1": 96.0, "profiled": [{"solution": "def add_tuple(lst, tup):\n \"\"\"\n Adds elements of the given tuple to the end of the given list.\n\n Args:\n lst (list): The list to which the tuple elements will be added.\n tup (tuple): The tuple containing elements to be added to the list.\n\n Returns:\n list: The list after adding the elements of the tuple.\n \"\"\"\n lst.extend(tup)\n return lst", "matching_cluster_idx": 5}, {"solution": "def add_tuple(lst, tup):\n \"\"\"\n Adds elements from the given tuple to the end of the given list.\n \n Args:\n lst (list): The list to which elements will be added.\n tup (tuple): The tuple containing elements to be added to the list.\n \n Returns:\n list: The list after adding elements from the tuple.\n \"\"\"\n lst.extend(tup)\n return lst", "matching_cluster_idx": 5}, {"solution": "def add_tuple(lst, tup):\n # Extend the list with the elements of the tuple\n lst.extend(tup)\n return lst", "matching_cluster_idx": 5}, {"solution": "def add_tuple(lst, tup):\n \"\"\"\n Adds the elements of the given tuple to the end of the given list.\n \n Args:\n lst (list): The list to which the tuple elements will be added.\n tup (tuple): The tuple whose elements will be added to the list.\n \n Returns:\n list: The list after adding the tuple elements.\n \"\"\"\n lst.extend(tup)\n return lst", "matching_cluster_idx": 5}, {"solution": "def add_tuple(lst, tup):\n # Extend the list by adding the elements from the tuple\n lst.extend(tup)\n return lst", "matching_cluster_idx": 5}, {"solution": "def add_tuple(list1, tuple1):\n # Convert tuple1 to a list and extend list1 with it\n list1.extend(list(tuple1))\n return list1", "matching_cluster_idx": 3}, {"solution": "def add_tuple(list_1, tuple_1):\n # Append the elements of the tuple to the end of the list\n list_1.extend(tuple_1)\n return list_1", "matching_cluster_idx": 5}, {"solution": "def add_tuple(list1, tuple1):\n # Combine the list and the tuple\n combined = list1 + list(tuple1)\n return combined", "matching_cluster_idx": 2}, {"solution": "def add_tuple(lst, tup):\n # Extend the list with the elements of the tuple\n lst.extend(tup)\n return lst", "matching_cluster_idx": 5}, {"solution": "def add_tuple(list_arg, tuple_arg):\n # Extend the list with the elements of the tuple\n list_arg.extend(tuple_arg)\n return list_arg", "matching_cluster_idx": 5}, {"solution": "def add_tuple(lst, tup):\n # Convert the tuple to a list and extend the original list\n lst.extend(list(tup))\n return lst", "matching_cluster_idx": 3}, {"solution": "def add_tuple(lst, tup):\n return lst + list(tup)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(list1, tuple1):\n # Extend the list by adding the elements from the tuple\n list1.extend(tuple1)\n return list1", "matching_cluster_idx": 5}, {"solution": "def add_tuple(lst, tup):\n # Extend the list by the elements of the tuple\n lst.extend(tup)\n return lst", "matching_cluster_idx": 5}, {"solution": "def add_tuple(lst, tup):\n # Extend the list with the elements of the tuple\n lst.extend(tup)\n return lst", "matching_cluster_idx": 5}, {"solution": "def add_tuple(list1, tuple1):\n # Extend the list with the elements of the tuple\n list1.extend(tuple1)\n return list1", "matching_cluster_idx": 5}, {"solution": "def add_tuple(list1, tuple1):\n # Extend the list with the elements of the tuple\n list1.extend(tuple1)\n return list1", "matching_cluster_idx": 5}, {"solution": "def add_tuple(test_list, test_tup):\n # Convert the tuple to a list and extend the original list\n test_list.extend(list(test_tup))\n return test_list", "matching_cluster_idx": 3}, {"solution": "def add_tuple(list_arg, tuple_arg):\n # Extend the list by appending elements from the tuple\n list_arg.extend(tuple_arg)\n return list_arg", "matching_cluster_idx": 5}, {"solution": "def add_tuple(lst, tup):\n # Extend the list by adding the elements of the tuple at the end\n lst.extend(tup)\n return lst", "matching_cluster_idx": 5}]}, "Mbpp/753": {"dps": 87.71812080536913, "dps_norm": 72.5, "pass@1": 98.0, "profiled": [{"solution": "def min_k(tuples_list, k):\n \"\"\"\n Function to find minimum k records from tuple list.\n \"\"\"\n # Sort the list based on the second element of each tuple\n sorted_list = sorted(tuples_list, key=lambda x: x[1])\n # Return the first k elements from the sorted list\n return sorted_list[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(test_tuples, K):\n # Sort the list of tuples based on the second element (the number)\n sorted_tuples = sorted(test_tuples, key=lambda x: x[1])\n # Return the first K elements from the sorted list\n return sorted_tuples[:K]", "matching_cluster_idx": 2}, {"solution": "def min_k(records, k):\n \"\"\"\n Find the minimum k records from a list of tuples.\n \n Args:\n records (list of tuples): List of tuples where each tuple contains a name and a score.\n k (int): Number of minimum records to find.\n \n Returns:\n list of tuples: List of k minimum records sorted by score.\n \"\"\"\n # Sort the records based on the score\n sorted_records = sorted(records, key=lambda x: x[1])\n # Return the first k records from the sorted list\n return sorted_records[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(tuple_list, k):\n # Sort the list based on the second element of each tuple (the score)\n sorted_list = sorted(tuple_list, key=lambda x: x[1])\n # Return the first k elements from the sorted list\n return sorted_list[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(test_list, K):\n # Sort the list by the second element of each tuple (the score)\n sorted_list = sorted(test_list, key=lambda x: x[1])\n # Return the first K elements from the sorted list\n return sorted_list[:K]", "matching_cluster_idx": 2}, {"solution": "def min_k(test_list, K):\n # Sort the list by the second element (score) in descending order\n sorted_list = sorted(test_list, key=lambda x: x[1])\n # Return the first K elements from the sorted list\n return sorted_list[:K]", "matching_cluster_idx": 2}, {"solution": "def min_k(test_tuples, K):\n # Sort the tuples by the second element (the number) in ascending order\n sorted_tuples = sorted(test_tuples, key=lambda x: x[1])\n # Return the first K elements from the sorted list\n return sorted_tuples[:K]", "matching_cluster_idx": 2}, {"solution": "def min_k(tuples_list, k):\n # Sort the list based on the second element of each tuple (the score)\n sorted_list = sorted(tuples_list, key=lambda x: x[1])\n # Return the first k elements from the sorted list\n return sorted_list[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(test_tuples, K):\n # Sort the tuples based on the second element (score)\n sorted_tuples = sorted(test_tuples, key=lambda x: x[1])\n # Return the first K tuples from the sorted list\n return sorted_tuples[:K]", "matching_cluster_idx": 2}, {"solution": "def min_k(tuples_list, k):\n # Sort the list of tuples based on the second element (score)\n sorted_list = sorted(tuples_list, key=lambda x: x[1])\n # Return the first k elements from the sorted list\n return sorted_list[:k]", "matching_cluster_idx": 1}, {"solution": "def min_k(tuple_list, k):\n # Sort the tuple list based on the second element of each tuple (the score)\n sorted_list = sorted(tuple_list, key=lambda x: x[1])\n # Return the first k elements from the sorted list\n return sorted_list[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(test_tup, K):\n # Sort the tuple list based on the second element of each tuple\n sorted_tup = sorted(test_tup, key=lambda x: x[1])\n # Return the first K elements from the sorted list\n return sorted_tup[:K]", "matching_cluster_idx": 2}, {"solution": "def min_k(tuples_list, k):\n # Sort the list based on the second element of each tuple (the score)\n sorted_list = sorted(tuples_list, key=lambda x: x[1])\n # Return the first k elements from the sorted list\n return sorted_list[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(tuples_list, k):\n # Sort the list based on the second element of each tuple\n sorted_tuples = sorted(tuples_list, key=lambda x: x[1])\n # Return the first k elements from the sorted list\n return sorted_tuples[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(test_tup, K):\n # Sort the list based on the second element of each tuple (the score)\n sorted_tup = sorted(test_tup, key=lambda x: x[1])\n # Return the first K elements from the sorted list\n return sorted_tup[:K]", "matching_cluster_idx": 2}, {"solution": "def min_k(records, k):\n # Sort the records based on the second element (the number)\n sorted_records = sorted(records, key=lambda x: x[1])\n # Return the first k elements from the sorted list\n return sorted_records[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(test_list, K):\n # Sort the list based on the second element of each tuple (the score)\n sorted_list = sorted(test_list, key=lambda x: x[1])\n # Return the first K elements from the sorted list\n return sorted_list[:K]", "matching_cluster_idx": 1}, {"solution": "def min_k(tuple_list, k):\n # Sort the list based on the second element of each tuple (the score)\n sorted_list = sorted(tuple_list, key=lambda x: x[1])\n # Return the first k elements from the sorted list\n return sorted_list[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(test_tup, K):\n # Sort the list of tuples by the second element (score)\n sorted_tuples = sorted(test_tup, key=lambda x: x[1])\n # Return the first K elements from the sorted list\n return sorted_tuples[:K]", "matching_cluster_idx": 2}, {"solution": "def min_k(test_list, K):\n # Sort the list based on the second element of each tuple\n sorted_list = sorted(test_list, key=lambda x: x[1])\n # Return the first K elements from the sorted list\n return sorted_list[:K]", "matching_cluster_idx": 2}]}, "Mbpp/754": {"dps": 73.27586206896552, "dps_norm": 81.25, "pass@1": 64.0, "profiled": [{"solution": "def extract_index_list(l1, l2, l3):\n # Find the common elements by checking the index positions\n common_elements = []\n for i in range(min(len(l1), len(l2), len(l3))):\n if l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n # Find the common elements by checking each element at the same index in all three lists\n common_elements = []\n for i in range(min(len(l1), len(l2), len(l3))):\n if l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n # Find common elements that appear at the same index in all three lists\n common_elements = []\n for i in range(min(len(l1), len(l2), len(l3))):\n if l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n # Find the common elements that appear at the same indices in all three lists\n common_elements = []\n for i in range(min(len(l1), len(l2), len(l3))):\n if l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n # Find the common elements based on their indices in all three lists\n common_elements = []\n for i in range(min(len(l1), len(l2), len(l3))):\n if l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n # Find the common elements by checking indices\n common_elements = []\n for i in range(min(len(l1), len(l2), len(l3))):\n if l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n common_elements = []\n for index, (elem1, elem2, elem3) in enumerate(zip(l1, l2, l3)):\n if elem1 == elem2 == elem3:\n common_elements.append(elem1)\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n # Find the common elements by checking each index in all three lists\n common_elements = []\n for i in range(min(len(l1), len(l2), len(l3))):\n if l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n common_elements = []\n for i in range(len(l1)):\n if i < len(l2) and i < len(l3) and l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n return common_elements", "matching_cluster_idx": 4}, {"solution": "def extract_index_list(l1, l2, l3):\n # Find the common elements by comparing the lists element-wise\n common_elements = []\n for i in range(min(len(l1), len(l2), len(l3))):\n if l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n # Find the minimum length among the three lists to avoid index errors\n min_length = min(len(l1), len(l2), len(l3))\n \n # Initialize an empty list to store common elements\n common_elements = []\n \n # Iterate through the lists up to the length of the shortest list\n for i in range(min_length):\n # Check if the element at the current index is the same in all three lists\n if l1[i] == l2[i] == l3[i]:\n # If so, append it to the common_elements list\n common_elements.append(l1[i])\n \n # Return the list of common elements\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n common_elements = []\n for i in range(len(l1)):\n if i < len(l2) and i < len(l3) and l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n return common_elements", "matching_cluster_idx": 4}, {"solution": "def extract_index_list(l1, l2, l3):\n common_elements = []\n for i in range(min(len(l1), len(l2), len(l3))):\n if l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n # Find the common elements by comparing the indices of elements in all three lists\n common_elements = []\n for i in range(len(l1)):\n if i < len(l2) and i < len(l3) and l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n return common_elements", "matching_cluster_idx": 4}, {"solution": "def extract_index_list(l1, l2, l3):\n # Initialize an empty list to store common elements\n common_elements = []\n \n # Iterate through the lists using zip to get elements at the same index\n for item1, item2, item3 in zip(l1, l2, l3):\n # Check if the element is the same in all three lists\n if item1 == item2 == item3:\n common_elements.append(item1)\n \n return common_elements", "matching_cluster_idx": 7}, {"solution": "def extract_index_list(l1, l2, l3):\n # Find the minimum length among the three lists to avoid index out of range\n min_length = min(len(l1), len(l2), len(l3))\n \n # Initialize an empty list to store the common elements\n common_elements = []\n \n # Iterate through the lists up to the minimum length\n for i in range(min_length):\n # Check if the element at the current index is the same in all three lists\n if l1[i] == l2[i] == l3[i]:\n # If it is, append it to the common_elements list\n common_elements.append(l1[i])\n \n # Return the list of common elements\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n common_elements = []\n for i in range(len(l1)):\n if i < len(l2) and i < len(l3) and l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n return common_elements", "matching_cluster_idx": 4}, {"solution": "def extract_index_list(l1, l2, l3):\n # Find the common elements by checking each element at the same index in all three lists\n common_elements = []\n for i in range(len(l1)):\n if i < len(l2) and i < len(l3): # Ensure the index exists in all lists\n if l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n return common_elements", "matching_cluster_idx": 4}, {"solution": "def extract_index_list(l1, l2, l3):\n common_elements = []\n for index, (item1, item2, item3) in enumerate(zip(l1, l2, l3)):\n if item1 == item2 == item3:\n common_elements.append(item1)\n return common_elements", "matching_cluster_idx": 5}, {"solution": "def extract_index_list(l1, l2, l3):\n # Find the common elements that appear at the same indices\n common_elements = []\n for i in range(min(len(l1), len(l2), len(l3))):\n if l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n return common_elements", "matching_cluster_idx": 6}]}, "Mbpp/755": {"dps": null, "dps_norm": null, "pass@1": 0.0, "profiled": []}, "Mbpp/757": {"dps": 82.71028037383178, "dps_norm": 23.076923076923077, "pass@1": 20.0, "profiled": [{"solution": "def count_reverse_pairs(string_list):\n count = 0\n for i in range(len(string_list)):\n for j in range(i + 1, len(string_list)):\n if string_list[i] == string_list[j][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(strings):\n count = 0\n for i in range(len(strings)):\n for j in range(i + 1, len(strings)):\n if strings[i] == strings[j][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(strings):\n count = 0\n for i in range(len(strings)):\n for j in range(i + 1, len(strings)):\n if strings[i] == strings[j][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(strings):\n count = 0\n for i in range(len(strings)):\n for j in range(i + 1, len(strings)):\n if strings[i] == strings[j][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(strings):\n count = 0\n for i in range(len(strings)):\n for j in range(i + 1, len(strings)):\n if strings[i] == strings[j][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(str_list):\n count = 0\n for i in range(len(str_list)):\n for j in range(i + 1, len(str_list)):\n if str_list[i] == str_list[j][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(str_list):\n count = 0\n for i in range(len(str_list)):\n for j in range(i + 1, len(str_list)):\n if str_list[i] == str_list[j][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(string_list):\n count = 0\n for i in range(len(string_list)):\n for j in range(i + 1, len(string_list)):\n if string_list[i] == string_list[j][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(strings):\n count = 0\n for i in range(len(strings)):\n for j in range(i + 1, len(strings)):\n if strings[i] == strings[j][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(strings):\n count = 0\n for i in range(len(strings)):\n for j in range(i + 1, len(strings)):\n if strings[i] == strings[j][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(str_list):\n count = 0\n for i in range(len(str_list)):\n for j in range(i+1, len(str_list)):\n if str_list[i] == str_list[j][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(str_list):\n count = 0\n for i in range(len(str_list)):\n for j in range(i + 1, len(str_list)):\n if str_list[i] == str_list[j][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(strings):\n count = 0\n for i in range(len(strings)):\n for j in range(i + 1, len(strings)):\n if strings[i] == strings[j][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(strings):\n count = 0\n for i in range(len(strings)):\n for j in range(i + 1, len(strings)):\n if strings[i] == strings[j][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(strings):\n count = 0\n for i in range(len(strings)):\n for j in range(i + 1, len(strings)):\n if strings[i] == strings[j][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(str_list):\n count = 0\n for i in range(len(str_list)):\n for j in range(i + 1, len(str_list)):\n if str_list[i] == str_list[j][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(str_list):\n count = 0\n for i in range(len(str_list)):\n for j in range(i + 1, len(str_list)):\n if str_list[i] == str_list[j][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(str_list):\n count = 0\n for i in range(len(str_list)):\n for j in range(i + 1, len(str_list)):\n if str_list[i] == str_list[j][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(str_list):\n count = 0\n for i in range(len(str_list)):\n for j in range(i + 1, len(str_list)):\n if str_list[i] == str_list[j][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(string_list):\n count = 0\n for i in range(len(string_list)):\n for j in range(i + 1, len(string_list)):\n if string_list[i] == string_list[j][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}]}, "Mbpp/758": {"dps": 91.38996138996139, "dps_norm": 85.0, "pass@1": 100.0, "profiled": [{"solution": "def unique_sublists(lst):\n sublist_count = {}\n for sublist in lst:\n # Convert the sublist to a tuple to use as a dictionary key\n sublist_tuple = tuple(sublist)\n # Increment the count for this sublist in the dictionary\n sublist_count[sublist_tuple] = sublist_count.get(sublist_tuple, 0) + 1\n return sublist_count", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(lst):\n sublist_count = {}\n for sublist in lst:\n # Convert the sublist to a tuple to use it as a dictionary key\n sublist_tuple = tuple(sublist)\n # Count the occurrences of each sublist\n if sublist_tuple in sublist_count:\n sublist_count[sublist_tuple] += 1\n else:\n sublist_count[sublist_tuple] = 1\n return sublist_count", "matching_cluster_idx": 6}, {"solution": "from collections import defaultdict\ndef unique_sublists(lst):\n sublist_count = defaultdict(int)\n for sublist in lst:\n # Convert each sublist to a tuple to use it as a dictionary key\n sublist_tuple = tuple(sublist)\n sublist_count[sublist_tuple] += 1\n return dict(sublist_count)", "matching_cluster_idx": 5}, {"solution": "def unique_sublists(lst):\n sublist_count = {}\n for sublist in lst:\n # Convert the sublist to a tuple since tuples are hashable and can be keys in a dictionary\n sublist_tuple = tuple(sublist)\n if sublist_tuple in sublist_count:\n sublist_count[sublist_tuple] += 1\n else:\n sublist_count[sublist_tuple] = 1\n return sublist_count", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(lst):\n # Initialize an empty dictionary to store the counts\n counts = {}\n \n # Iterate through each sublist in the main list\n for sublist in lst:\n # Convert the sublist to a tuple (since tuples are hashable and can be dictionary keys)\n sublist_tuple = tuple(sublist)\n \n # Check if the tuple is already in the dictionary\n if sublist_tuple in counts:\n # If yes, increment its count\n counts[sublist_tuple] += 1\n else:\n # If not, add it to the dictionary with a count of 1\n counts[sublist_tuple] = 1\n \n # Return the dictionary with tuples as keys and counts as values\n return counts", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(lst):\n sublist_count = {}\n for sublist in lst:\n # Convert the sublist to a tuple to make it hashable and usable as a dictionary key\n sublist_tuple = tuple(sublist)\n if sublist_tuple in sublist_count:\n sublist_count[sublist_tuple] += 1\n else:\n sublist_count[sublist_tuple] = 1\n return sublist_count", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(lst):\n sublist_count = {}\n for sublist in lst:\n # Convert the sublist to a tuple as dictionary keys must be hashable\n sublist_tuple = tuple(sublist)\n # Count the occurrences of each tuple\n if sublist_tuple in sublist_count:\n sublist_count[sublist_tuple] += 1\n else:\n sublist_count[sublist_tuple] = 1\n return sublist_count", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(lst):\n sublist_count = {}\n for sublist in lst:\n # Convert the sublist to a tuple since tuples are hashable and can be used as dictionary keys\n sublist_tuple = tuple(sublist)\n # Increment the count for this sublist tuple in the dictionary\n if sublist_tuple in sublist_count:\n sublist_count[sublist_tuple] += 1\n else:\n sublist_count[sublist_tuple] = 1\n return sublist_count", "matching_cluster_idx": 6}, {"solution": "from collections import Counter\ndef unique_sublists(lst):\n # Convert each sublist to a tuple\n tuple_list = [tuple(sublist) for sublist in lst]\n # Count the occurrences of each tuple\n counts = Counter(tuple_list)\n # Return the counts as a dictionary\n return dict(counts)", "matching_cluster_idx": 6}, {"solution": "from collections import defaultdict\ndef unique_sublists(lst):\n sublist_count = defaultdict(int)\n for sublist in lst:\n # Convert the sublist to a tuple since tuples are hashable and can be used as dictionary keys\n sublist_tuple = tuple(sublist)\n sublist_count[sublist_tuple] += 1\n \n # Convert the defaultdict to a regular dictionary for the final output\n return dict(sublist_count)", "matching_cluster_idx": 5}, {"solution": "from collections import defaultdict\ndef unique_sublists(lst):\n sublist_count = defaultdict(int)\n for sublist in lst:\n # Convert each sublist to a tuple to use it as a dictionary key\n tuple_sublist = tuple(sublist)\n sublist_count[tuple_sublist] += 1\n return dict(sublist_count)", "matching_cluster_idx": 5}, {"solution": "def unique_sublists(lst):\n # Initialize an empty dictionary to store the counts\n counts = {}\n \n # Iterate through each sublist in the input list\n for sublist in lst:\n # Convert the sublist to a tuple (since tuples are hashable and can be keys in a dictionary)\n sublist_tuple = tuple(sublist)\n \n # Increment the count for this tuple in the dictionary\n counts[sublist_tuple] = counts.get(sublist_tuple, 0) + 1\n \n # Return the dictionary with counts\n return counts", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(lst):\n count_dict = {}\n for sublist in lst:\n # Convert sublist to a tuple since tuples are hashable and can be used as dictionary keys\n sublist_tuple = tuple(sublist)\n if sublist_tuple in count_dict:\n count_dict[sublist_tuple] += 1\n else:\n count_dict[sublist_tuple] = 1\n return count_dict", "matching_cluster_idx": 6}, {"solution": "from collections import defaultdict\ndef unique_sublists(lst):\n count_dict = defaultdict(int)\n for sublist in lst:\n # Convert each sublist to a tuple (since tuples are hashable and can be used as dictionary keys)\n sublist_tuple = tuple(sublist)\n count_dict[sublist_tuple] += 1\n return dict(count_dict)", "matching_cluster_idx": 5}, {"solution": "def unique_sublists(lst):\n count_dict = {}\n for sublist in lst:\n # Convert each sublist to a tuple (immutable and hashable)\n sublist_tuple = tuple(sublist)\n # Count the occurrences of each tuple\n if sublist_tuple in count_dict:\n count_dict[sublist_tuple] += 1\n else:\n count_dict[sublist_tuple] = 1\n return count_dict", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(lst):\n count_dict = {}\n for sublist in lst:\n sublist_tuple = tuple(sublist)\n if sublist_tuple in count_dict:\n count_dict[sublist_tuple] += 1\n else:\n count_dict[sublist_tuple] = 1\n return count_dict", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(lst):\n sublist_count = {}\n for sublist in lst:\n # Convert the sublist to a tuple since tuples are hashable and can be used as dictionary keys\n sublist_tuple = tuple(sublist)\n if sublist_tuple in sublist_count:\n sublist_count[sublist_tuple] += 1\n else:\n sublist_count[sublist_tuple] = 1\n return sublist_count", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(lst):\n sublist_count = {}\n for sublist in lst:\n # Convert each sublist to a tuple to use as a dictionary key\n sublist_tuple = tuple(sublist)\n # Count the occurrences of each unique sublist\n if sublist_tuple in sublist_count:\n sublist_count[sublist_tuple] += 1\n else:\n sublist_count[sublist_tuple] = 1\n return sublist_count", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(lst):\n sublist_count = {}\n for sublist in lst:\n sublist_tuple = tuple(sublist)\n if sublist_tuple in sublist_count:\n sublist_count[sublist_tuple] += 1\n else:\n sublist_count[sublist_tuple] = 1\n return sublist_count", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(lst):\n sublist_count = {}\n for sublist in lst:\n # Convert each sublist to a tuple (since tuples are hashable and can be dictionary keys)\n sublist_tuple = tuple(sublist)\n # Count the occurrences of each unique sublist\n if sublist_tuple in sublist_count:\n sublist_count[sublist_tuple] += 1\n else:\n sublist_count[sublist_tuple] = 1\n return sublist_count", "matching_cluster_idx": 6}]}, "Mbpp/760": {"dps": 43.175182481751825, "dps_norm": 73.75, "pass@1": 100.0, "profiled": [{"solution": "def unique_Element(lst):\n return all(element == lst[0] for element in lst)", "matching_cluster_idx": 3}, {"solution": "def unique_Element(numbers):\n if not numbers: # If the list is empty, return False as there's no distinct element\n return False\n first_element = numbers[0] # Take the first element as a reference\n for number in numbers[1:]: # Iterate over the rest of the elements\n if number != first_element: # If any element is different from the first one\n return False # The list does not contain only one distinct element\n return True # If the loop completes without returning False, all elements are the same", "matching_cluster_idx": 5}, {"solution": "def unique_Element(numbers):\n if not numbers: # Check if the list is empty\n return False # An empty list does not contain a single distinct element\n first_element = numbers[0]\n for number in numbers:\n if number != first_element:\n return False # Found a different element, so return False\n return True # All elements are the same", "matching_cluster_idx": 5}, {"solution": "def unique_Element(numbers):\n # Check if the list is empty or has only one element\n if not numbers or len(set(numbers)) == 1:\n return True\n return False", "matching_cluster_idx": 6}, {"solution": "def unique_Element(nums):\n # Use a set to find the unique elements in the list\n unique_set = set(nums)\n # Check if the length of the set is 1, which means all elements are the same\n return len(unique_set) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(numbers):\n if not numbers: # Check if the list is empty\n return False\n first_element = numbers[0]\n for number in numbers:\n if number != first_element:\n return False\n return True", "matching_cluster_idx": 5}, {"solution": "def unique_Element(numbers):\n if not numbers: # Check if the list is empty\n return False\n first_element = numbers[0]\n for number in numbers:\n if number != first_element:\n return False\n return True", "matching_cluster_idx": 5}, {"solution": "def unique_Element(lst):\n return all(element == lst[0] for element in lst)", "matching_cluster_idx": 3}, {"solution": "def unique_Element(numbers):\n if not numbers: # If the list is empty, we cannot have a unique element\n return False\n first_element = numbers[0]\n for number in numbers:\n if number != first_element:\n return False\n return True", "matching_cluster_idx": 5}, {"solution": "def unique_Element(numbers):\n return all(num == numbers[0] for num in numbers)", "matching_cluster_idx": 3}, {"solution": "def unique_Element(numbers):\n if not numbers: # Check if the list is empty\n return False # An empty list does not contain a single distinct element\n first_element = numbers[0]\n for num in numbers:\n if num != first_element:\n return False # Found a different element, so return False\n return True # All elements are the same", "matching_cluster_idx": 5}, {"solution": "def unique_Element(numbers):\n if not numbers: # Check if the list is empty\n return False # An empty list does not contain a single distinct element\n first_element = numbers[0]\n for number in numbers:\n if number != first_element:\n return False\n return True", "matching_cluster_idx": 5}, {"solution": "def unique_Element(numbers):\n if not numbers: # Check if the list is empty\n return False\n first_element = numbers[0]\n for num in numbers:\n if num != first_element:\n return False\n return True", "matching_cluster_idx": 5}, {"solution": "def unique_Element(lst):\n \"\"\"\n Check whether a list of numbers contains only one distinct element or not.\n \n Args:\n lst (list): A list of numbers.\n \n Returns:\n bool: True if the list contains only one distinct element, False otherwise.\n \"\"\"\n return len(set(lst)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(numbers):\n if not numbers: # Check if the list is empty\n return False\n first_element = numbers[0]\n for num in numbers:\n if num != first_element:\n return False\n return True", "matching_cluster_idx": 5}, {"solution": "def unique_Element(numbers):\n if not numbers: # Check if the list is empty\n return False # An empty list does not contain a single distinct element\n first_element = numbers[0]\n for number in numbers:\n if number != first_element:\n return False # Found a different element, so return False\n return True # All elements are the same", "matching_cluster_idx": 5}, {"solution": "def unique_Element(nums):\n if not nums: # Check if the list is empty\n return False\n first_element = nums[0]\n for num in nums:\n if num != first_element:\n return False\n return True", "matching_cluster_idx": 5}, {"solution": "def unique_Element(numbers):\n if not numbers: # Check if the list is empty\n return False # Assuming empty list does not contain one distinct element\n first_element = numbers[0]\n for num in numbers:\n if num != first_element:\n return False\n return True", "matching_cluster_idx": 5}, {"solution": "def unique_Element(numbers):\n if not numbers: # If the list is empty, we cannot have a unique element\n return False\n first_element = numbers[0]\n for number in numbers:\n if number != first_element:\n return False\n return True", "matching_cluster_idx": 5}, {"solution": "def unique_Element(numbers):\n # Check if the list is empty\n if not numbers:\n return False\n # Use a set to find unique elements\n unique_set = set(numbers)\n # Return True if there's only one unique element\n return len(unique_set) == 1", "matching_cluster_idx": 6}]}, "Mbpp/764": {"dps": 88.88888888888889, "dps_norm": 50.0, "pass@1": 100.0, "profiled": [{"solution": "def number_ctr(input_string):\n count = 0\n for char in input_string:\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(input_string):\n \"\"\"\n Counts the number of digits in the given string.\n \n Args:\n input_string (str): The string to be evaluated.\n \n Returns:\n int: The count of digits in the input string.\n \"\"\"\n count = 0\n for char in input_string:\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n count = 0\n for char in s:\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s: str) -> int:\n \"\"\"\n Function to count number of digits in a given string.\n \"\"\"\n return sum(c.isdigit() for c in s)", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n count = 0\n for char in s:\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n count = 0\n for char in s:\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n count = 0\n for char in s:\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n count = 0\n for char in s:\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s: str) -> int:\n return sum(c.isdigit() for c in s)", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s: str) -> int:\n count = 0\n for char in s:\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n count = 0\n for char in s:\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n count = 0\n for char in s:\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(input_string):\n count = 0\n for char in input_string:\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n count = 0\n for char in s:\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n count = 0\n for char in s:\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(input_string):\n count = 0\n for char in input_string:\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n \"\"\"\n Count the number of digits in the given string.\n \"\"\"\n return sum(c.isdigit() for c in s)", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n count = 0\n for char in s:\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(input_string):\n count = 0\n for char in input_string:\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s: str) -> int:\n \"\"\"\n This function counts the number of digits in a given string.\n \"\"\"\n return sum(c.isdigit() for c in s)", "matching_cluster_idx": 2}]}, "Mbpp/766": {"dps": 63.27102803738318, "dps_norm": 60.0, "pass@1": 100.0, "profiled": [{"solution": "def pair_wise(lst):\n return [(lst[i], lst[i+1]) for i in range(len(lst)-1)]", "matching_cluster_idx": 2}, {"solution": "def pair_wise(lst):\n return [(lst[i], lst[i+1]) for i in range(len(lst)-1)]", "matching_cluster_idx": 2}, {"solution": "def pair_wise(lst):\n return [(lst[i], lst[i+1]) for i in range(len(lst)-1)]", "matching_cluster_idx": 2}, {"solution": "def pair_wise(lst):\n return [(lst[i], lst[i+1]) for i in range(len(lst)-1)]", "matching_cluster_idx": 2}, {"solution": "def pair_wise(lst):\n return [(lst[i], lst[i+1]) for i in range(len(lst) - 1)]", "matching_cluster_idx": 2}, {"solution": "def pair_wise(lst):\n return list(zip(lst[:-1], lst[1:]))", "matching_cluster_idx": 4}, {"solution": "def pair_wise(lst):\n return [(lst[i], lst[i+1]) for i in range(len(lst)-1)]", "matching_cluster_idx": 2}, {"solution": "def pair_wise(lst):\n return [(lst[i], lst[i+1]) for i in range(len(lst)-1)]", "matching_cluster_idx": 2}, {"solution": "def pair_wise(lst):\n return [(lst[i], lst[i+1]) for i in range(len(lst)-1)]", "matching_cluster_idx": 2}, {"solution": "def pair_wise(lst):\n return list(zip(lst[:-1], lst[1:]))", "matching_cluster_idx": 4}, {"solution": "def pair_wise(lst):\n return [(lst[i], lst[i+1]) for i in range(len(lst) - 1)]", "matching_cluster_idx": 2}, {"solution": "def pair_wise(lst):\n return list(zip(lst[:-1], lst[1:]))", "matching_cluster_idx": 4}, {"solution": "def pair_wise(lst):\n return [(lst[i], lst[i+1]) for i in range(len(lst)-1)]", "matching_cluster_idx": 2}, {"solution": "def pair_wise(lst):\n return [(lst[i], lst[i+1]) for i in range(len(lst)-1)]", "matching_cluster_idx": 2}, {"solution": "def pair_wise(lst):\n \"\"\"\n Returns a list of all pairs of consecutive items in a given list.\n \n Args:\n lst (list): The input list of items.\n \n Returns:\n list: A list of tuples, where each tuple contains a pair of consecutive items from the input list.\n \"\"\"\n return [(lst[i], lst[i+1]) for i in range(len(lst)-1)]", "matching_cluster_idx": 2}, {"solution": "def pair_wise(lst):\n return list(zip(lst[:-1], lst[1:]))", "matching_cluster_idx": 4}, {"solution": "def pair_wise(lst):\n return list(zip(lst[:-1], lst[1:]))", "matching_cluster_idx": 4}, {"solution": "def pair_wise(lst):\n return [(lst[i], lst[i+1]) for i in range(len(lst)-1)]", "matching_cluster_idx": 2}, {"solution": "def pair_wise(lst):\n return [(lst[i], lst[i+1]) for i in range(len(lst)-1)]", "matching_cluster_idx": 2}, {"solution": "def pair_wise(lst):\n return list(zip(lst[:-1], lst[1:]))", "matching_cluster_idx": 4}]}, "Mbpp/775": {"dps": 94.39999999999999, "dps_norm": 71.42857142857143, "pass@1": 100.0, "profiled": [{"solution": "def odd_position(numbers):\n for i in range(1, len(numbers), 2): # Start from index 1 and step by 2\n if numbers[i] % 2 == 0: # Check if the number at odd index is even\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n for i in range(1, len(lst), 2): # Start from index 1 and step by 2 to check odd indices\n if lst[i] % 2 == 0: # Check if the number at the odd index is even\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n for i in range(1, len(lst), 2): # Start from index 1 and step by 2 to check odd indices\n if lst[i] % 2 == 0: # Check if the number at the odd index is even\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n for i in range(1, len(lst), 2): # Start from index 1 and step by 2\n if lst[i] % 2 == 0: # Check if the number at the odd position is even\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n for i in range(1, len(lst), 2): # Iterate over odd indices\n if lst[i] % 2 == 0: # Check if the number at the odd index is even\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n for i in range(1, len(lst), 2):\n if lst[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n for i in range(1, len(lst), 2): # Iterate over odd indices starting from 1\n if lst[i] % 2 == 0: # Check if the number at the odd position is even\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n for i in range(1, len(lst), 2): # Start from index 1 and step by 2 to get odd indices\n if lst[i] % 2 == 0: # Check if the number at the odd index is even\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n for i in range(1, len(lst), 2): # Start from index 1 and step by 2 to check odd indices\n if lst[i] % 2 == 0: # Check if the number at the odd index is even\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n for i in range(1, len(lst), 2): # Iterate over odd positions\n if lst[i] % 2 == 0: # Check if the number at the odd position is even\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(numbers):\n for i in range(1, len(numbers), 2): # Iterate over odd indices\n if numbers[i] % 2 == 0: # Check if the number at the odd index is even\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n for i in range(1, len(lst), 2): # Start from index 1 and step by 2\n if lst[i] % 2 == 0: # Check if the number at the odd index is even\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(numbers):\n for i in range(1, len(numbers), 2): # Start from index 1 and step by 2\n if numbers[i] % 2 == 0: # Check if the number at odd index is even\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(numbers):\n for i in range(1, len(numbers), 2):\n if numbers[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n for i in range(1, len(lst), 2): # Iterate over odd indices starting from 1\n if lst[i] % 2 == 0: # Check if the number at the odd index is even\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(numbers):\n for i in range(1, len(numbers), 2):\n if numbers[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(numbers):\n for i in range(1, len(numbers), 2): # Start at index 1 and step by 2\n if numbers[i] % 2 == 0: # Check if the number at the odd position is even\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n for i in range(1, len(lst), 2): # Start at index 1 and step by 2 to check only odd indices\n if lst[i] % 2 == 0: # Check if the number at the odd index is even\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n for i in range(1, len(lst), 2): # Start from index 1 and step by 2 to check odd indices\n if lst[i] % 2 == 0: # Check if the number at the odd index is even\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n for i in range(1, len(lst), 2): # Iterate over odd indices starting from 1\n if lst[i] % 2 == 0: # Check if the number at the odd index is even\n return False\n return True", "matching_cluster_idx": 4}]}, "Mbpp/777": {"dps": 28.80690737833595, "dps_norm": 45.2991452991453, "pass@1": 13.0, "profiled": [{"solution": "def find_sum(numbers):\n unique_numbers = set(numbers)\n sum_unique = sum(unique_numbers)\n return sum_unique", "matching_cluster_idx": 8}, {"solution": "def find_sum(lst):\n unique_elements = []\n for element in lst:\n if element not in unique_elements:\n unique_elements.append(element)\n return sum(unique_elements)", "matching_cluster_idx": 1}, {"solution": "def find_sum(numbers):\n unique_numbers = []\n for num in numbers:\n if num not in unique_numbers:\n unique_numbers.append(num)\n return sum(unique_numbers)", "matching_cluster_idx": 2}, {"solution": "def find_sum(numbers):\n unique_numbers = []\n for number in numbers:\n if number not in unique_numbers:\n unique_numbers.append(number)\n return sum(unique_numbers)", "matching_cluster_idx": 1}, {"solution": "def find_sum(lst):\n element_sum = 0\n seen = set()\n for element in lst:\n if element not in seen:\n element_sum += element\n seen.add(element)\n return element_sum", "matching_cluster_idx": 4}, {"solution": "def find_sum(lst):\n unique_elements = []\n for element in lst:\n if element not in unique_elements:\n unique_elements.append(element)\n return sum(unique_elements)", "matching_cluster_idx": 1}, {"solution": "def find_sum(lst):\n element_sum = 0\n seen = set()\n for element in lst:\n if element not in seen:\n element_sum += element\n seen.add(element)\n return element_sum", "matching_cluster_idx": 4}, {"solution": "def find_sum(numbers):\n unique_numbers = []\n for number in numbers:\n if number not in unique_numbers:\n unique_numbers.append(number)\n return sum(unique_numbers)", "matching_cluster_idx": 1}, {"solution": "def find_sum(lst):\n sum_of_elements = 0\n seen = set()\n for element in lst:\n if element not in seen:\n sum_of_elements += element\n seen.add(element)\n return sum_of_elements", "matching_cluster_idx": 4}, {"solution": "def find_sum(numbers):\n unique_numbers = []\n for number in numbers:\n if number not in unique_numbers:\n unique_numbers.append(number)\n return sum(unique_numbers)", "matching_cluster_idx": 1}, {"solution": "def find_sum(lst):\n element_sum = 0\n seen = set()\n \n for element in lst:\n if element not in seen:\n element_sum += element\n seen.add(element)\n \n return element_sum", "matching_cluster_idx": 4}, {"solution": "def find_sum(lst):\n unique_elements = []\n for element in lst:\n if element not in unique_elements:\n unique_elements.append(element)\n return sum(unique_elements)", "matching_cluster_idx": 1}, {"solution": "def find_sum(numbers):\n unique_numbers = set(numbers) # Remove duplicates by converting to a set\n return sum(unique_numbers) # Sum the unique elements", "matching_cluster_idx": 8}]}, "Mbpp/781": {"dps": null, "dps_norm": null, "pass@1": 0.0, "profiled": []}, "Mbpp/800": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def remove_all_spaces(input_string):\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n # Use the replace method to replace all spaces with an empty string\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(s):\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(s):\n \"\"\"\n Remove all whitespaces from a string.\n \"\"\"\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(s):\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(s):\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(s: str) -> str:\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n # Use the str.replace method to replace all spaces with an empty string\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(s):\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(s):\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(s):\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(s):\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}]}, "Mbpp/805": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def max_sum_list(lists):\n if not lists:\n return []\n \n max_sum = float('-inf')\n max_list = []\n \n for lst in lists:\n current_sum = sum(lst)\n if current_sum > max_sum:\n max_sum = current_sum\n max_list = lst\n \n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n if not lists:\n return []\n max_sum = float('-inf')\n max_list = []\n for lst in lists:\n current_sum = sum(lst)\n if current_sum > max_sum:\n max_sum = current_sum\n max_list = lst\n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n # Initialize the maximum sum to a very small number\n max_sum = float('-inf')\n # Initialize the result list to an empty list\n result = []\n \n # Iterate through each list in the list of lists\n for lst in lists:\n # Calculate the sum of the current list\n current_sum = sum(lst)\n # If the current sum is greater than the max_sum, update max_sum and result\n if current_sum > max_sum:\n max_sum = current_sum\n result = lst\n \n return result", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(list_of_lists):\n # Initialize the maximum sum to a very small number\n max_sum = float('-inf')\n # Initialize the result list to an empty list\n result_list = []\n \n # Iterate over each list in the list of lists\n for lst in list_of_lists:\n # Calculate the sum of the current list\n current_sum = sum(lst)\n # If the current sum is greater than the max_sum, update max_sum and result_list\n if current_sum > max_sum:\n max_sum = current_sum\n result_list = lst\n \n return result_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(list_of_lists):\n # Find the list with the maximum sum of elements\n max_sum_list = max(list_of_lists, key=sum)\n return max_sum_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n # Initialize the maximum sum and the corresponding list\n max_sum = float('-inf')\n max_list = []\n \n # Iterate through each list in the list of lists\n for lst in lists:\n # Calculate the sum of the current list\n current_sum = sum(lst)\n # Update max_sum and max_list if the current sum is greater than the max_sum\n if current_sum > max_sum:\n max_sum = current_sum\n max_list = lst\n \n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n if not lists:\n return []\n return max(lists, key=sum)", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(list_of_lists):\n # Initialize the maximum sum to a very small number\n max_sum = float('-inf')\n # Initialize the result list to an empty list\n result_list = []\n \n # Iterate through each list in the list of lists\n for lst in list_of_lists:\n # Calculate the sum of the current list\n current_sum = sum(lst)\n # If the current sum is greater than the maximum sum found so far\n if current_sum > max_sum:\n # Update the maximum sum and the result list\n max_sum = current_sum\n result_list = lst\n \n return result_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(list_of_lists):\n if not list_of_lists:\n return []\n max_sum = sum(list_of_lists[0])\n max_list = list_of_lists[0]\n for lst in list_of_lists:\n current_sum = sum(lst)\n if current_sum > max_sum:\n max_sum = current_sum\n max_list = lst\n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(list_of_lists):\n max_sum = float('-inf')\n max_list = []\n for lst in list_of_lists:\n current_sum = sum(lst)\n if current_sum > max_sum:\n max_sum = current_sum\n max_list = lst\n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(list_of_lists):\n # Find the list with the maximum sum of elements\n return max(list_of_lists, key=sum)", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n # Initialize the variable to store the list with the highest sum\n max_sum_list = []\n max_sum = float('-inf')\n \n # Iterate through each list in the list of lists\n for lst in lists:\n # Calculate the sum of the current list\n current_sum = sum(lst)\n # Update the max_sum and max_sum_list if the current sum is greater than the max_sum\n if current_sum > max_sum:\n max_sum = current_sum\n max_sum_list = lst\n \n return max_sum_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(list_of_lists):\n # Initialize the variable to store the list with the highest sum\n max_sum_list = []\n # Initialize the variable to store the maximum sum found so far\n max_sum = float('-inf')\n \n # Iterate through each list in the list of lists\n for lst in list_of_lists:\n # Calculate the sum of the current list\n current_sum = sum(lst)\n # Update the maximum sum and the list associated with this sum if the current sum is greater\n if current_sum > max_sum:\n max_sum = current_sum\n max_sum_list = lst\n \n return max_sum_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n if not lists:\n return []\n return max(lists, key=sum)", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n if not lists:\n return []\n return max(lists, key=sum)", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(list_of_lists):\n if not list_of_lists:\n return []\n max_sum = float('-inf')\n max_list = []\n for lst in list_of_lists:\n current_sum = sum(lst)\n if current_sum > max_sum:\n max_sum = current_sum\n max_list = lst\n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(list_of_lists):\n max_sum = float('-inf')\n max_list = []\n for lst in list_of_lists:\n current_sum = sum(lst)\n if current_sum > max_sum:\n max_sum = current_sum\n max_list = lst\n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n return max(lists, key=sum)", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(list_of_lists):\n # Initialize the maximum sum to a very small number\n max_sum = float('-inf')\n # Initialize the result list to an empty list\n result_list = []\n \n # Iterate over each sublist in the list of lists\n for sublist in list_of_lists:\n # Calculate the sum of the current sublist\n current_sum = sum(sublist)\n # If the current sum is greater than the max_sum, update max_sum and result_list\n if current_sum > max_sum:\n max_sum = current_sum\n result_list = sublist\n \n return result_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n # Initialize the maximum sum to negative infinity and the result list to None\n max_sum = float('-inf')\n max_list = None\n \n # Iterate through each list in the list of lists\n for lst in lists:\n # Calculate the sum of the current list\n current_sum = sum(lst)\n # If the current sum is greater than the max_sum, update max_sum and max_list\n if current_sum > max_sum:\n max_sum = current_sum\n max_list = lst\n \n # Return the list with the highest sum of elements\n return max_list", "matching_cluster_idx": 4}]}, "Mbpp/808": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 96.0, "profiled": [{"solution": "def check_K(tup, k):\n \"\"\"\n This function checks if the given tuple contains the value k or not.\n \n Parameters:\n tup (tuple): The tuple to be checked.\n k (int): The value to check for in the tuple.\n \n Returns:\n bool: True if k is in the tuple, False otherwise.\n \"\"\"\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(test_tup, K):\n return K in test_tup", "matching_cluster_idx": 5}, {"solution": "def check_K(test_tup, K):\n return K in test_tup", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n \"\"\"\n Check if the given tuple contains the element k.\n \n Args:\n tup (tuple): The tuple to be checked.\n k (int): The element to search for.\n \n Returns:\n bool: True if k is found in the tuple, False otherwise.\n \"\"\"\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(test_tup, K):\n return K in test_tup", "matching_cluster_idx": 5}, {"solution": "def check_K(test_tup, K):\n return K in test_tup", "matching_cluster_idx": 5}, {"solution": "def check_K(test_tup, K):\n return K in test_tup", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(test_tup, K):\n \"\"\"\n Function to check if K is present in the given tuple.\n \n Args:\n test_tup (tuple): The tuple to search within.\n K (int): The integer to look for in the tuple.\n \n Returns:\n bool: True if K is found in the tuple, False otherwise.\n \"\"\"\n return K in test_tup", "matching_cluster_idx": 5}, {"solution": "def check_K(input_tuple, k):\n return k in input_tuple", "matching_cluster_idx": 5}, {"solution": "def check_K(test_tup, K):\n return K in test_tup", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(test_tup, K):\n return K in test_tup", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n \"\"\"\n Check if the tuple contains the element k.\n \"\"\"\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(test_tup, K):\n return K in test_tup", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(test_tup, K):\n return K in test_tup", "matching_cluster_idx": 5}, {"solution": "def check_K(test_tup, K):\n return K in test_tup", "matching_cluster_idx": 5}, {"solution": "def check_K(test_tuple, K):\n return K in test_tuple", "matching_cluster_idx": 5}]}}} \ No newline at end of file diff --git a/results/evalperf/deepseek-ai--deepseek-coder-33b-instruct_vllm_temp_1.0_evalperf_results.brief.json b/results/evalperf/deepseek-ai--deepseek-coder-33b-instruct_vllm_temp_1.0_evalperf_results.brief.json new file mode 100644 index 0000000..5e5de05 --- /dev/null +++ b/results/evalperf/deepseek-ai--deepseek-coder-33b-instruct_vllm_temp_1.0_evalperf_results.brief.json @@ -0,0 +1 @@ +{"date": "2024-10-19 16:31", "config": {"n_samples": 100, "temperature": 1.0, "min_correct": 10, "max_profile": 20}, "summary": {"dps": 82.65680460618937, "dps_norm": 77.67106700323255, "pass@1": 77.50847457627118}, "eval": {"HumanEval/9": {"dps": 80.50473186119874, "dps_norm": 80.0, "pass@1": 92.0, "profiled": [{"solution": "from typing import List, Tuple\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" \n From a given list of integers, generate a list of rolling maximum \n element found until given moment in the sequence.\n\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n \n roll_max = [numbers[0]]\n for num in numbers[1:]:\n if num > roll_max[-1]:\n roll_max.append(num)\n else:\n roll_max.append(roll_max[-1])\n return roll_max", "matching_cluster_idx": 7}, {"solution": "from typing import List, Tuple\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\"\n From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n\n Parameters:\n numbers (List[int]): a list of integers\n\n Returns:\n List[int]: list of rolling maximum values\n \"\"\"\n result = []\n max_so_far = float('-inf')\n for num in numbers:\n if num > max_so_far:\n max_so_far = num\n result.append(max_so_far)\n return result", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" \n From a given list of integers, generate a list of rolling maximum element found until given moment \n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n\n result = []\n max_so_far = numbers[0]\n\n for num in numbers:\n if num > max_so_far:\n max_so_far = num\n result.append(max_so_far)\n\n return result", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\"\n From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n\n max_numbers = [numbers[0]]\n for num in numbers[1:]:\n max_numbers.append(max(max_numbers[-1], num))\n\n return max_numbers", "matching_cluster_idx": 4}, {"solution": "from typing import List, Tuple\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" \n From a given list of integers, generate a list of rolling maximum \n element found until given moment in the sequence. \n \"\"\"\n if not numbers:\n return []\n\n max_num = numbers[0]\n result = [max_num]\n\n for num in numbers[1:]:\n if num > max_num:\n max_num = num\n result.append(max_num)\n\n return result", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n result = []\n max_val = float('-inf')\n\n for num in numbers:\n if num > max_val:\n max_val = num\n result.append(max_val)\n\n return result", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\"\n From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n \"\"\"\n if len(numbers) == 0:\n return []\n\n max_numbers = [numbers[0]]\n for number in numbers[1:]:\n if number > max_numbers[-1]:\n max_numbers.append(number)\n else:\n max_numbers.append(max_numbers[-1])\n\n return max_numbers", "matching_cluster_idx": 7}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n if not numbers:\n return []\n\n max_so_far = numbers[0]\n result = [max_so_far]\n\n for num in numbers[1:]:\n max_so_far = max(max_so_far, num)\n result.append(max_so_far)\n\n return result", "matching_cluster_idx": 4}, {"solution": "from typing import List, Tuple\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n\n rolling_max_values = [numbers[0]]\n for num in numbers[1:]:\n rolling_max_values.append(max(rolling_max_values[-1], num))\n\n return rolling_max_values", "matching_cluster_idx": 4}, {"solution": "from typing import List, Tuple\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n rolling_max_list = []\n max_number = float('-inf')\n for num in numbers:\n if num > max_number:\n max_number = num\n rolling_max_list.append(max_number)\n return rolling_max_list", "matching_cluster_idx": 8}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if len(numbers) == 0: \n return [] \n\n max_list = [numbers[0]]\n for i in range(1, len(numbers)):\n max_list.append(max(max_list[i-1], numbers[i]))\n\n return max_list", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n max_nums = []\n current_max = None\n\n for num in numbers:\n if current_max is None or num > current_max:\n current_max = num\n max_nums.append(current_max)\n\n return max_nums", "matching_cluster_idx": 7}, {"solution": "from typing import List, Tuple\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n \"\"\"\n if len(numbers) == 0:\n return []\n\n rolling_max_list = [numbers[0]]\n for num in numbers[1:]:\n rolling_max_list.append(max(rolling_max_list[-1], num))\n return rolling_max_list", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n \"\"\"\n if not numbers:\n return []\n \n max_numbers = [numbers[0]]\n for num in numbers[1:]:\n if num > max_numbers[-1]:\n max_numbers.append(num)\n else:\n max_numbers.append(max_numbers[-1])\n return max_numbers", "matching_cluster_idx": 7}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\"\n This function generates a list of rolling maximum element found until given moment in the sequence.\n \"\"\"\n # Check if input is a list\n if not isinstance(numbers, list):\n raise TypeError(\"Input should be a list of integers\")\n # Check if list is empty\n if len(numbers) == 0:\n return []\n \n result = []\n max_so_far = numbers[0]\n \n for num in numbers:\n if num > max_so_far:\n max_so_far = num\n result.append(max_so_far)\n \n return result", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n current_max = float('-inf')\n rolling_max_list = []\n for number in numbers:\n current_max = max(current_max, number)\n rolling_max_list.append(current_max)\n return rolling_max_list", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\"\n From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n\n maximum = numbers[0]\n result = []\n\n for num in numbers:\n if num > maximum:\n maximum = num\n result.append(maximum)\n\n return result\ntest_data = [1, 2, 3, 2, 3, 4, 2]\nresult = rolling_max(test_data)", "matching_cluster_idx": 8}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n\n maximum = numbers[0]\n result = []\n for num in numbers:\n if num > maximum:\n maximum = num\n result.append(maximum)\n return result", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n\n if not numbers: # return empty list if input is empty\n return []\n \n # initialize the result with first element in the input\n rolling_max_list = [numbers[0]]\n \n for num in numbers[1:]:\n # append max between current num and previously calculated max\n rolling_max_list.append(max(num, rolling_max_list[-1]))\n \n return rolling_max_list", "matching_cluster_idx": 4}, {"solution": "from typing import List, Tuple\ndef rolling_max(numbers: List[int]) -> List[int]:\n if not numbers:\n return []\n\n max_num = numbers[0]\n result = []\n\n for num in numbers:\n max_num = max(max_num, num)\n result.append(max_num)\n\n return result", "matching_cluster_idx": 4}]}, "HumanEval/0": {"dps": 72.09302325581395, "dps_norm": 75.71428571428572, "pass@1": 71.0, "profiled": [{"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n n = len(numbers)\n for i in range(n):\n for j in range(i + 1, n):\n if abs(numbers[i] - numbers[j]) < threshold:\n return True\n return False", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n \"\"\"\n n = len(numbers)\n for i in range(n):\n for j in range(i+1, n):\n if abs(numbers[i] - numbers[j]) < threshold:\n return True\n return False", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n \"\"\"\n if len(numbers) < 2:\n return False\n\n numbers.sort()\n\n for i in range(len(numbers) - 1):\n if numbers[i + 1] - numbers[i] < threshold:\n return True\n\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n if not numbers or len(numbers) < 2:\n return False\n\n numbers.sort()\n\n for i in range(1, len(numbers)):\n if numbers[i] - numbers[i-1] < threshold:\n return True\n\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n \"\"\"\n numbers.sort() # Sort the list in ascending order.\n for i in range(len(numbers) - 1):\n if numbers[i + 1] - numbers[i] < threshold:\n return True # If the difference is less than threshold, return True.\n return False # If no two close elements found, return False.", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" \n Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n if not isinstance(numbers, list) or not isinstance(threshold, (int, float)):\n raise ValueError('Invalid input type')\n\n if len(numbers) < 2:\n return False\n\n numbers.sort()\n\n for i in range(1, len(numbers)):\n if numbers[i] - numbers[i - 1] < threshold:\n return True\n\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n \"\"\"\n # sort the list\n numbers.sort()\n \n # iterate over the list\n for i in range(1, len(numbers)):\n # check if the difference between two consecutive numbers is less than threshold\n if abs(numbers[i] - numbers[i-1]) < threshold:\n return True\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n numbers.sort() # Sort the list in ascending order\n for i in range(len(numbers) - 1):\n if numbers[i + 1] - numbers[i] < threshold:\n return True\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n num_len = len(numbers)\n for i in range(num_len):\n for j in range(i + 1, num_len):\n if abs(numbers[i] - numbers[j]) < threshold:\n return True\n return False", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n n = len(numbers)\n for i in range(n):\n for j in range(i + 1, n):\n if abs(numbers[i] - numbers[j]) < threshold:\n return True\n return False", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n # Sort the numbers\n numbers.sort()\n\n # Iterate over each pair of adjacent numbers\n for i in range(len(numbers) - 1):\n # If the difference between the numbers is less than the threshold,\n # return True\n if abs(numbers[i] - numbers[i+1]) < threshold:\n return True\n\n # If no such pair of numbers was found, return False\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n if abs(numbers[i] - numbers[j]) < threshold:\n return True\n return False", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n for i in range(len(numbers)):\n for j in range(i+1, len(numbers)):\n if abs(numbers[i] - numbers[j]) < threshold:\n return True\n return False", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n numbers.sort()\n for i in range(len(numbers) - 1):\n if abs(numbers[i] - numbers[i+1]) < threshold:\n return True\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n # Sort the numbers\n numbers.sort()\n\n # Iterate over the sorted numbers\n for i in range(len(numbers)-1):\n # If the difference between two adjacent numbers is less than the threshold,\n # then return True as they are close to each other\n if numbers[i+1] - numbers[i] < threshold:\n return True\n\n # If no such pair is found, return False\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n # Iterate over the numbers with their indices\n for i, num1 in enumerate(numbers):\n # Iterate over the numbers after the current number\n for num2 in numbers[i+1:]:\n # Check if the difference between the numbers is less than the threshold\n if abs(num1 - num2) < threshold:\n # If it is, return True\n return True\n # If no close elements are found, return False\n return False", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n for i in range(len(numbers)):\n for j in range(i+1, len(numbers)):\n if abs(numbers[i] - numbers[j]) < threshold:\n return True\n return False", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\"\n Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n \"\"\"\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n if abs(numbers[i] - numbers[j]) < threshold:\n return True\n return False", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n numbers.sort() # Sort the list of numbers\n for i in range(len(numbers) - 1):\n if numbers[i + 1] - numbers[i] < threshold:\n return True\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" \n Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n \n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n # Sort the numbers in ascending order\n numbers.sort()\n # Loop over the numbers and check if any two adjacent numbers differ by less than the threshold\n for i in range(len(numbers) - 1):\n if numbers[i + 1] - numbers[i] < threshold:\n return True\n return False", "matching_cluster_idx": 3}]}, "HumanEval/4": {"dps": 74.27215189873418, "dps_norm": 86.66666666666667, "pass@1": 99.0, "profiled": [{"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\"\n For a given list of input numbers, calculate Mean Absolute Deviation around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n # Calculate the mean\n mean = sum(numbers) / len(numbers)\n \n # Calculate the absolute deviation from the mean for each number in the list\n deviations = [abs(number - mean) for number in numbers]\n \n # Calculate the Mean Absolute Deviation (MAD)\n mad = sum(deviations) / len(deviations)\n \n return mad", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n # Calculate the mean of the input list\n mean = sum(numbers) / len(numbers)\n\n # Calculate absolute differences between each element and the mean\n abs_diff = [abs(num - mean) for num in numbers]\n\n # Calculate mean of these absolute differences\n mad = sum(abs_diff) / len(abs_diff)\n\n return mad", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\"\n For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n\n # calculate mean\n mean = sum(numbers) / len(numbers)\n\n # calculate absolute deviation for each element\n abs_deviations = [abs(x - mean) for x in numbers]\n\n # calculate mean of absolute deviations\n mad = sum(abs_deviations) / len(abs_deviations)\n\n return mad", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n mean = sum(numbers) / len(numbers)\n mad = sum(abs(x - mean) for x in numbers) / len(numbers)\n return mad", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n mean = sum(numbers) / len(numbers)\n absolute_differences = [abs(number - mean) for number in numbers]\n mad = sum(absolute_differences) / len(numbers)\n return mad", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" \n For a given list of input numbers, calculate Mean Absolute Deviation around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n\n # calculate the mean of the numbers\n mean = sum(numbers) / len(numbers)\n\n # calculate the absolute deviation from the mean for each number\n deviations = [abs(x - mean) for x in numbers]\n\n # calculate and return the mean of these deviations\n return sum(deviations) / len(deviations)", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\"\n For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n # Calculate the mean of the list\n mean = sum(numbers) / len(numbers)\n\n # Calculate the absolute deviation from the mean for each element\n abs_deviations = [abs(x - mean) for x in numbers]\n\n # Return the mean of the absolute deviations\n return sum(abs_deviations) / len(abs_deviations)", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\"\n For a given list of input numbers, calculate Mean Absolute Deviation around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n mean = sum(numbers) / len(numbers)\n return sum(abs(x - mean) for x in numbers) / len(numbers)", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n mean = sum(numbers) / len(numbers)\n mad = sum(abs(x - mean) for x in numbers) / len(numbers)\n return mad", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if not numbers:\n raise ValueError(\"List of numbers cannot be empty\")\n\n mean = sum(numbers) / len(numbers)\n mad = sum(abs(x - mean) for x in numbers) / len(numbers)\n\n return mad", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\"\n For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n # Calculate the mean\n mean = sum(numbers) / len(numbers)\n \n # Calculate absolute differences\n absolute_differences = [abs(x - mean) for x in numbers]\n \n # Calculate and return Mean Absolute Deviation\n return sum(absolute_differences) / len(absolute_differences)\nnumbers = [1.0, 2.0, 3.0, 4.0]", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\"\n For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n n = len(numbers)\n mean = sum(numbers) / n\n return sum(abs(x - mean) for x in numbers) / n", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n mean = sum(numbers) / len(numbers)\n absolute_deviations = [abs(num - mean) for num in numbers]\n return sum(absolute_deviations) / len(numbers)", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n # Calculate the mean of the numbers\n mean = sum(numbers) / len(numbers)\n\n # Calculate the absolute differences\n absolute_diffs = [abs(x - mean) for x in numbers]\n\n # Calculate the Mean Absolute Deviation\n mad = sum(absolute_diffs) / len(numbers)\n\n return mad", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n def calculate_mean(numbers):\n return sum(numbers) / len(numbers)\n\n def calculate_abs_deviation(numbers, mean):\n return [abs(number - mean) for number in numbers]\n\n # Calculate the mean of the numbers\n mean = calculate_mean(numbers)\n\n # Calculate the absolute deviation from the mean\n abs_deviations = calculate_abs_deviation(numbers, mean)\n\n # Calculate the mean absolute deviation\n mad = sum(abs_deviations) / len(abs_deviations)\n\n return mad", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\"\n For a given list of input numbers, calculate Mean Absolute Deviation around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n mean = sum(numbers) / len(numbers)\n absolute_diffs = [abs(x - mean) for x in numbers]\n mad = sum(absolute_diffs) / len(numbers)\n return mad", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\"\n For a given list of input numbers, calculate Mean Absolute Deviation around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n # First, we compute the mean of the numbers\n mean = sum(numbers) / len(numbers)\n \n # Then, we calculate the absolute differences from the mean for each number\n abs_diffs = [abs(num - mean) for num in numbers]\n \n # Finally, the Mean Absolute Deviation is the average of these differences\n mad = sum(abs_diffs) / len(abs_diffs)\n \n return mad", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n mean = sum(numbers) / len(numbers)\n mad = sum(abs(number - mean) for number in numbers) / len(numbers)\n return mad", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n mean = sum(numbers) / len(numbers)\n return sum(abs(x - mean) for x in numbers) / len(numbers)", "matching_cluster_idx": 5}, {"solution": "from typing import List\nimport random\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n # Calculate the mean of the input list\n mean = sum(numbers) / len(numbers)\n # Calculate the absolute difference from the mean for each number\n absolute_differences = [abs(number - mean) for number in numbers]\n # Calculate the Mean Absolute Deviation\n mad = sum(absolute_differences) / len(numbers)\n return mad\nnumbers = [1.0, 2.0, 3.0, 4.0]", "matching_cluster_idx": 4}]}, "HumanEval/16": {"dps": 42.7906976744186, "dps_norm": 83.33333333333333, "pass@1": 100.0, "profiled": [{"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n return len(set(string.lower()))", "matching_cluster_idx": 7}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert string to lowercase to make sure that 'a' and 'A' are treated as the same character\n string_lower = string.lower()\n # Create a set to remove duplicates, then return the size of the set\n return len(set(string_lower))", "matching_cluster_idx": 7}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of \"\"\"\n return len(set(string.lower()))", "matching_cluster_idx": 7}, {"solution": "import doctest\ndef count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n return len(set(string.lower()))", "matching_cluster_idx": 7}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of \"\"\"\n\n # converting the string to lowercase to make the function case-insensitive\n string = string.lower()\n\n # using a set to automatically eliminate duplicate characters\n distinct_characters = set(string)\n\n # returning the length of the set\n return len(distinct_characters)", "matching_cluster_idx": 7}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of \"\"\"\n return len(set(string.lower()))", "matching_cluster_idx": 7}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\"\n Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # We convert the string to lowercase to make the function case-insensitive\n string = string.lower()\n \n # We use a set to store the characters. Since sets only allow unique values, this automatically gives us the unique characters\n unique_characters = set(string)\n \n # We return the length of the set, which is the number of unique characters\n return len(unique_characters)", "matching_cluster_idx": 7}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n return len(set(string.lower()))", "matching_cluster_idx": 7}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lowercase to ignore case sensitivity\n string_lower = string.lower()\n \n # Initialize an empty set\n distinct_chars = set()\n\n # Iterate over the string, adding each character to the set\n for char in string_lower:\n distinct_chars.add(char)\n\n # Return the length of the set\n return len(distinct_chars)", "matching_cluster_idx": 2}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\"\n Given a string, find out how many distinct characters (regardless of case) does it consist of\n \"\"\"\n return len(set(string.lower()))", "matching_cluster_idx": 7}, {"solution": "def count_distinct_characters(string: str) -> int:\n return len(set(string.lower()))", "matching_cluster_idx": 7}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of \"\"\"\n return len(set(string.lower()))", "matching_cluster_idx": 7}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lowercase to ensure case insensitive comparison\n string = string.lower()\n # Initialize an empty set to store unique characters\n unique_characters = set()\n # Iterate over each character in the string\n for char in string:\n # Add the character to the set\n unique_characters.add(char)\n # The length of the set is the number of unique characters\n return len(unique_characters)", "matching_cluster_idx": 2}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n return len(set(string.lower()))", "matching_cluster_idx": 7}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n return len(set(string.lower()))", "matching_cluster_idx": 7}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" \n Given a string, find out how many distinct characters (regardless of case) does it consist of \n \"\"\"\n return len(set(string.lower()))", "matching_cluster_idx": 7}, {"solution": "def count_distinct_characters(string: str) -> int:\n return len(set(string.lower()))", "matching_cluster_idx": 7}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\"\n Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n return len(set(string.lower()))", "matching_cluster_idx": 7}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n return len(set(string.lower()))", "matching_cluster_idx": 7}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n lower_string = string.lower()\n return len(set(lower_string))", "matching_cluster_idx": 7}]}, "HumanEval/20": {"dps": 96.30750605326877, "dps_norm": 99.44444444444444, "pass@1": 99.0, "profiled": [{"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n numbers.sort()\n min_diff = float('inf')\n res = ()\n for i in range(1, len(numbers)):\n diff = numbers[i] - numbers[i-1]\n if diff < min_diff:\n min_diff = diff\n res = (numbers[i-1], numbers[i])\n return res", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n \"\"\"\n # Sort the list of numbers\n numbers.sort()\n\n # Initialize the minimum difference and closest pair\n min_diff = float('inf')\n closest_pair = (None, None)\n\n # Compare each pair of consecutive numbers\n for i in range(1, len(numbers)):\n diff = numbers[i] - numbers[i - 1]\n if diff < min_diff:\n min_diff = diff\n closest_pair = (numbers[i - 1], numbers[i])\n\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n \"\"\"\n\n # Sort the numbers list\n numbers.sort()\n\n # Initialize closest pair with the first two numbers\n closest_pair = (numbers[0], numbers[1])\n min_distance = abs(numbers[1] - numbers[0])\n\n # Go through the list and check if a pair is closer than the current closest pair\n for i in range(1, len(numbers) - 1):\n distance = abs(numbers[i+1] - numbers[i])\n if distance < min_distance:\n min_distance = distance\n closest_pair = (numbers[i], numbers[i+1])\n\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n numbers.sort()\n min_diff = float('inf')\n closest_nums = (None, None)\n\n for i in range(1, len(numbers)):\n diff = numbers[i] - numbers[i - 1]\n if diff < min_diff:\n min_diff = diff\n closest_nums = (numbers[i - 1], numbers[i])\n\n return closest_nums", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n # sort the numbers\n numbers.sort()\n\n # initialize the smallest difference\n smallest_diff = float('inf')\n\n # initialize the result tuple\n result = (0.0, 0.0)\n\n # iterate through the list of numbers\n for i in range(1, len(numbers)):\n # calculate the difference between current number and the previous one\n diff = numbers[i] - numbers[i - 1]\n\n # if the difference is smaller than the smallest difference seen so far,\n # update the smallest difference and the result tuple\n if diff < smallest_diff:\n smallest_diff = diff\n result = (numbers[i - 1], numbers[i])\n\n # return the result tuple\n return result", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n numbers.sort()\n min_difference = float('inf')\n result = (None, None)\n for i in range(1, len(numbers)):\n diff = numbers[i] - numbers[i-1]\n if diff < min_difference:\n min_difference = diff\n result = (numbers[i-1], numbers[i])\n return result", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n numbers.sort()\n closest = (numbers[0], numbers[1])\n min_diff = abs(numbers[0] - numbers[1])\n\n for i in range(1, len(numbers) - 1):\n diff = abs(numbers[i] - numbers[i+1])\n if diff < min_diff:\n min_diff = diff\n closest = (numbers[i], numbers[i+1])\n\n return closest", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n numbers.sort()\n min_diff = float('inf')\n closest_pair = None\n for i in range(1, len(numbers)):\n diff = numbers[i] - numbers[i-1]\n if diff < min_diff:\n min_diff = diff\n closest_pair = (numbers[i-1], numbers[i])\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\"\n From a supplied list of numbers (of length at least two), select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n \"\"\"\n numbers.sort()\n min_diff = float('inf')\n result = (None, None)\n for i in range(1, len(numbers)):\n diff = numbers[i] - numbers[i - 1]\n if diff < min_diff:\n min_diff = diff\n result = (numbers[i - 1], numbers[i])\n return result", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n numbers.sort() # Sort the numbers\n min_diff = float('inf')\n result = (None, None)\n\n for i in range(1, len(numbers)):\n diff = numbers[i] - numbers[i - 1]\n if diff < min_diff:\n min_diff = diff\n result = (numbers[i - 1], numbers[i])\n\n return result", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n numbers.sort()\n diff = float('inf')\n result = (0, 0)\n for i in range(1, len(numbers)):\n if numbers[i] - numbers[i-1] < diff:\n diff = numbers[i] - numbers[i-1]\n result = (numbers[i-1], numbers[i])\n return result", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n numbers.sort()\n min_diff = float('inf')\n res = (0, 0)\n for i in range(1, len(numbers)):\n diff = numbers[i] - numbers[i-1]\n if diff < min_diff:\n min_diff = diff\n res = (numbers[i-1], numbers[i])\n return res", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n numbers.sort()\n closest_tuple = min(((numbers[i], numbers[i+1]) for i in range(len(numbers)-1)), key=lambda pair: pair[1] - pair[0])\n return closest_tuple", "matching_cluster_idx": 7}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n # Sort the list in ascending order\n numbers.sort()\n \n # Initialize the minimum difference and the closest pair\n min_diff = float('inf')\n closest_pair = (None, None)\n \n # Iterate over the sorted list to find the closest pair\n for i in range(1, len(numbers)):\n diff = numbers[i] - numbers[i-1]\n if diff < min_diff:\n min_diff = diff\n closest_pair = (numbers[i-1], numbers[i])\n \n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n if len(numbers) < 2:\n raise ValueError('Input list must have at least two numbers')\n \n numbers.sort()\n closest_diff = float('inf')\n closest_nums = None\n for i in range(1, len(numbers)):\n diff = numbers[i] - numbers[i - 1]\n if diff < closest_diff:\n closest_diff = diff\n closest_nums = (numbers[i - 1], numbers[i])\n return closest_nums", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n numbers.sort()\n min_diff = float('inf')\n result = (None, None)\n for i in range(1, len(numbers)):\n diff = numbers[i] - numbers[i-1]\n if diff < min_diff:\n min_diff = diff\n result = (numbers[i-1], numbers[i])\n return result", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\"\n Finds the closest elements in a list of floats\n\n Args:\n numbers: List of floats\n\n Returns:\n The two closest floats in the list\n \"\"\"\n assert len(numbers) >= 2, \"numbers list must have at least 2 elements\"\n\n numbers.sort()\n closest_diff = float('inf')\n closest_elements = (None, None)\n\n for i in range(len(numbers) - 1):\n diff = numbers[i+1] - numbers[i]\n if diff < closest_diff:\n closest_diff = diff\n closest_elements = (numbers[i], numbers[i+1])\n\n return closest_elements", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n \"\"\"\n numbers.sort()\n min_diff, result = numbers[1] - numbers[0], (numbers[0], numbers[1])\n for i in range(1, len(numbers) - 1):\n diff = numbers[i+1] - numbers[i]\n if diff < min_diff:\n min_diff, result = diff, (numbers[i], numbers[i+1])\n return result", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n numbers.sort()\n min_diff = float('inf')\n result = None\n for i in range(1, len(numbers)):\n diff = numbers[i] - numbers[i-1]\n if diff < min_diff:\n min_diff = diff\n result = (numbers[i-1], numbers[i])\n return result", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n if len(numbers) < 2:\n raise ValueError(\"The input list must contain at least two numbers.\")\n\n sorted_numbers = sorted(numbers)\n closest_pair = (sorted_numbers[0], sorted_numbers[1])\n min_difference = abs(sorted_numbers[0] - sorted_numbers[1])\n\n for i in range(1, len(sorted_numbers) - 1):\n current_difference = abs(sorted_numbers[i] - sorted_numbers[i+1])\n if current_difference < min_difference:\n closest_pair = (sorted_numbers[i], sorted_numbers[i+1])\n min_difference = current_difference\n\n return closest_pair", "matching_cluster_idx": 8}]}, "HumanEval/24": {"dps": 65.71428571428572, "dps_norm": 25.0, "pass@1": 98.0, "profiled": [{"solution": "def largest_divisor(n: int) -> int:\n \"\"\" \n For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n # Check if input is valid\n if n <= 0 or not isinstance(n, int):\n raise ValueError(\"Input must be a positive integer\")\n \n # The largest divisor of n that is less than n is always n/2 when n is even\n # If n is odd, then the largest divisor is n-1\n for i in range(n-1, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 0}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n \"\"\"\n\n # Start from the number less than n\n for i in range(n-1, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 1}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n.\n Args:\n n (int): The number to find the largest divisor of.\n Returns:\n int: The largest divisor of n.\n \"\"\"\n # Start from n-1 and decrement until a divisor is found.\n for i in range(n-1, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 1}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\"For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n for i in range(n-1, 0, -1):\n if n % i == 0:\n return i\n return None", "matching_cluster_idx": 1}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n \"\"\"\n for i in range(n-1, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 1}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" \n For a given number n, find the largest number that divides n evenly, smaller than n\n \"\"\"\n for i in range(n-1, 0, -1):\n if n % i == 0:\n return i\n return None\nn = 15", "matching_cluster_idx": 1}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\"\n For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n # Initialize the largest divisor to 1 (as it is the smallest possible divisor)\n largest_divisor = 1\n \n # Iterate through each number from 2 to n\n for i in range(2, n):\n # If i divides n evenly, it's a divisor\n if n % i == 0:\n largest_divisor = i\n \n return largest_divisor", "matching_cluster_idx": 1}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\"\n For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n\n # Start checking from n-1 down to 1\n for i in range(n - 1, 0, -1):\n if n % i == 0:\n # If i divides n evenly, it is the largest number that divides n evenly, smaller than n\n return i", "matching_cluster_idx": 1}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n \"\"\"\n for i in range(n-1, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 1}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\"\n For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n for i in range(n-1, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 1}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\"\n For a given number n, find the largest number that divides n evenly, smaller than n\n \"\"\"\n for i in range(n-1, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 1}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" \n For a given number n, find the largest number that divides n evenly, smaller than n.\n\n :param n: An integer\n :return: The largest divisor of n less than n.\n \"\"\"\n # Initialize the largest divisor to None\n largest_divisor = None\n\n # Loop from n-1 to 1 to find the largest divisor\n for i in range(n-1, 0, -1):\n if n % i == 0: # If i is a divisor of n\n largest_divisor = i # Update the largest divisor\n break # Exit the loop since we found the largest divisor\n\n # Return the largest divisor\n return largest_divisor", "matching_cluster_idx": 1}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n # Edge case for n = 0 or 1\n if n <= 1:\n return None\n\n # Iterate from 2 to n/2 and find the largest divisor\n for i in range(n//2, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 4}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n for i in range(n-1, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 1}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n \"\"\"\n for i in range(n-1, 0, -1): # we iterate backwards from n-1 to 1\n if n % i == 0: # if n is evenly divisible by i, i is the largest divisor\n return i # return i\n return None # in case no divisor is found, return None", "matching_cluster_idx": 1}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" \n For a given number n, find the largest number that divides n evenly, and is less than n.\n >>> largest_divisor(15)\n 5\n \"\"\"\n for i in range(n-1, 0, -1):\n if n % i == 0:\n return i\n return None", "matching_cluster_idx": 1}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n \"\"\"\n for i in range(n-1, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 1}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n if n < 2:\n raise ValueError(\"Input should be an integer greater than 1\")\n for i in range(n - 1, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 0}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n \"\"\"\n for i in range(n-1, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 1}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n if n < 2:\n raise ValueError('Input should be an integer greater than 1')\n\n for i in range(n-1, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 0}]}, "HumanEval/26": {"dps": 73.6, "dps_norm": 76.25, "pass@1": 44.0, "profiled": [{"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n \"\"\"\n result = []\n count_dict = {}\n for num in numbers:\n if num not in count_dict:\n count_dict[num] = 1\n result.append(num)\n else:\n count_dict[num] += 1\n return [x for x in result if count_dict[x] == 1]", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n result = []\n for number in numbers:\n if numbers.count(number) == 1:\n result.append(number)\n return result", "matching_cluster_idx": 0}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 2, 4]\n \"\"\"\n unique_nums = []\n counts = {}\n \n for num in numbers:\n if num not in counts:\n unique_nums.append(num)\n counts[num] = 1\n else:\n counts[num] += 1\n \n return [num for num in unique_nums if counts[num] == 1]", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n \"\"\"\n result = []\n counts = {}\n for num in numbers:\n if num not in counts:\n counts[num] = 1\n result.append(num)\n else:\n counts[num] += 1\n \n return [num for num in result if counts[num] == 1]", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n return [n for i, n in enumerate(numbers) if numbers.count(n) == 1]", "matching_cluster_idx": 0}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n result = []\n counter = {}\n\n for num in numbers:\n if num not in counter:\n counter[num] = 1\n result.append(num)\n else:\n counter[num] += 1\n\n return [num for num in result if counter[num] == 1]", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 2, 4]\n \"\"\"\n num_dict = {}\n result = []\n for num in numbers:\n if num not in num_dict:\n result.append(num)\n num_dict[num] = 1\n else:\n num_dict[num] += 1\n\n return [num for num in result if num_dict[num] == 1]", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\"\n From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n \"\"\"\n output_list = []\n counter_dict = {}\n\n for num in numbers:\n if num not in counter_dict:\n counter_dict[num] = 1\n output_list.append(num)\n else:\n counter_dict[num] += 1\n\n output_list = [num for num in output_list if counter_dict[num] == 1]\n \n return output_list", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n result = []\n for num in numbers:\n if numbers.count(num) == 1:\n result.append(num)\n return result", "matching_cluster_idx": 0}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" \n From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n result = []\n for num in numbers:\n if numbers.count(num) == 1:\n result.append(num)\n return result", "matching_cluster_idx": 0}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" \n From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n \"\"\"\n counts = {}\n for num in numbers:\n if num in counts:\n counts[num] += 1\n else:\n counts[num] = 1\n\n return [num for num in numbers if counts[num] == 1]", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n num_counts = {}\n unique_numbers = []\n\n for num in numbers:\n if num not in num_counts:\n num_counts[num] = 1\n unique_numbers.append(num)\n else:\n num_counts[num] += 1\n\n return [num for num in unique_numbers if num_counts[num] == 1]", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" \n From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n \n seen = set()\n result = []\n\n for num in numbers:\n if num not in seen:\n seen.add(num)\n result.append(num)\n else:\n if num in result:\n result.remove(num)\n\n return result", "matching_cluster_idx": 2}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\"\n From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n \"\"\"\n result = []\n counts = {}\n \n for num in numbers:\n if num not in counts:\n counts[num] = 1\n result.append(num)\n else:\n counts[num] += 1\n \n return [num for num in result if counts[num] == 1]", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" \n From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n \"\"\"\n result = []\n counts = {}\n\n # Count the occurrence of each number\n for number in numbers:\n if number in counts:\n counts[number] += 1\n else:\n counts[number] = 1\n\n # Add the number to the result list if it's not a duplicate\n for number in numbers:\n if counts[number] == 1:\n result.append(number)\n\n return result", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n result = []\n for num in numbers:\n if numbers.count(num) == 1:\n result.append(num)\n return result", "matching_cluster_idx": 0}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\"\n From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n \"\"\"\n num_counter = {}\n for num in numbers:\n if num in num_counter:\n num_counter[num] += 1\n else:\n num_counter[num] = 1\n return [num for num in numbers if num_counter[num] == 1]", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n result = []\n for num in numbers:\n if numbers.count(num) == 1:\n result.append(num)\n return result", "matching_cluster_idx": 0}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n \"\"\"\n number_dict = {}\n result = []\n\n for number in numbers:\n if number in number_dict:\n number_dict[number] += 1\n else:\n number_dict[number] = 1\n\n for number in numbers:\n if number_dict[number] == 1:\n result.append(number)\n \n return result", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\"\n From a list of integers, remove all elements that occur more than once. \n Keep order of elements left the same as in the input.\n \"\"\"\n # Use a dictionary to store the count of each number in the list.\n counts = {}\n for num in numbers:\n if num in counts:\n counts[num] += 1\n else:\n counts[num] = 1\n\n # Iterate through the list and only add the number to the result if its count is 1.\n result = []\n for num in numbers:\n if counts[num] == 1:\n result.append(num)\n\n return result", "matching_cluster_idx": 3}]}, "HumanEval/31": {"dps": 76.39240506329114, "dps_norm": 81.875, "pass@1": 95.0, "profiled": [{"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n # 0 and 1 are not prime numbers\n if n < 2:\n return False\n # 2 is the only even prime number\n if n == 2: \n return True\n # all other even numbers are not primes\n if not n & 1: \n return False\n # range starts with 3 and only needs to go up the square root of n\n # for all odd numbers\n for x in range(3, int(n**0.5)+1, 2):\n if n % x == 0:\n return False\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n \"\"\"\n if n < 2:\n return False\n for i in range(2, int(n ** 0.5) + 1):\n if n % i == 0:\n return False\n return True", "matching_cluster_idx": 5}, {"solution": "def is_prime(n):\n \"\"\"\n Return true if a given number is prime, and false otherwise.\n \n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n False\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n < 2:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True", "matching_cluster_idx": 5}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n False\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n if n == 2:\n return True\n if n % 2 == 0:\n return False\n i = 3\n while i * i <= n:\n if n % i == 0:\n return False\n i += 2\n return True", "matching_cluster_idx": 5}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\"\"\"\n if n < 2:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True", "matching_cluster_idx": 5}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n False\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n elif n <= 3:\n return True\n elif n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"\n Return true if a given number is prime, and false otherwise.\n \"\"\"\n if n < 2:\n return False\n for i in range(2, int(n ** 0.5) + 1):\n if n % i == 0:\n return False\n return True", "matching_cluster_idx": 5}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n < 2:\n return False\n for i in range(2, int(n ** 0.5) + 1):\n if n % i == 0:\n return False\n return True", "matching_cluster_idx": 5}, {"solution": "def is_prime(n):\n \"\"\"\n Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n False\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n < 2:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True", "matching_cluster_idx": 5}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n False\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n elif n <= 3:\n return True\n elif n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\"\"\"\n if n <= 1:\n return False\n elif n <= 3:\n return True\n elif n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n False\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n < 2: \n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True", "matching_cluster_idx": 5}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n \"\"\"\n if n < 2:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True", "matching_cluster_idx": 5}, {"solution": "def is_prime(n):\n \"\"\"\n Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n False\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n elif n <= 3:\n return True\n elif n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n False\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i = i + 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n False\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n elif n <= 3:\n return True\n elif n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n False\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n # 0 and 1 are not prime numbers\n if n < 2:\n return False\n # 2 is the only even prime number\n if n == 2: \n return True\n # all other even numbers are not primes\n if n % 2 == 0: \n return False\n # range starts with 3 and only needs to go up the square root of n\n # for all odd numbers\n for x in range(3, int(n**0.5)+1, 2):\n if n % x == 0:\n return False\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"\n Return true if a given number is prime, and false otherwise.\n \n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n False\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n elif n <= 3:\n return True\n elif n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while (i * i <= n):\n if (n % i == 0 or n % (i + 2) == 0):\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n False\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\"\"\"\n if n <= 1:\n return False\n elif n <= 3:\n return True\n elif n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}]}, "HumanEval/33": {"dps": 46.423611111111114, "dps_norm": 71.81818181818181, "pass@1": 80.0, "profiled": [{"solution": "def sort_third(l):\n \"\"\"\n This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are \n equal to the values of the corresponding indicies of l, but sorted.\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n l_third = sorted(l[i] for i in range(len(l)) if i % 3 == 0)\n l_prime = []\n for i in range(len(l)):\n if i % 3 == 0:\n l_prime.append(l_third.pop(0))\n else:\n l_prime.append(l[i])\n return l_prime", "matching_cluster_idx": 6}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n \"\"\"\n # Separate the elements divisible by 3 and the rest\n divisible_by_three = sorted([i for index, i in enumerate(l) if index % 3 == 0])\n not_divisible_by_three = [i for index, i in enumerate(l) if index % 3 != 0]\n \n # Replace the elements at indicies divisible by 3\n for i in range(len(l)):\n if i % 3 == 0:\n l[i] = divisible_by_three.pop(0)\n\n return l", "matching_cluster_idx": 6}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\"\"\"\n # Create a list of indices divisible by 3 and sort them\n indices = [i for i in range(len(l)) if i % 3 == 0]\n sorted_values = sorted([l[i] for i in indices])\n\n # Create a copy of l with values at divisible indices replaced with sorted values\n l_prime = l[:]\n for i, sorted_value in zip(indices, sorted_values):\n l_prime[i] = sorted_value\n\n return l_prime", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n \"\"\"\n divisible_by_3 = [l[i] for i in range(len(l)) if i % 3 == 0]\n divisible_by_3.sort()\n j = 0\n res = [None] * len(l)\n for i in range(len(l)):\n if i % 3 == 0:\n res[i] = divisible_by_3[j]\n j += 1\n else:\n res[i] = l[i]\n return res", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n # Store the elements at indices divisible by 3\n elems = sorted([x for i, x in enumerate(l) if i % 3 == 0])\n \n # Create a new list while keeping the elements at indices not divisible by 3\n new_list = [elems.pop(0) if i % 3 == 0 else x for i, x in enumerate(l)]\n\n return new_list", "matching_cluster_idx": 6}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indices that are not divisible by three, while its values at the indices that are divisible by three are equal\n to the values of the corresponding indices of l, but sorted.\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n divisible_by_three = [l[i] for i in range(len(l)) if i % 3 == 0]\n divisible_by_three.sort()\n\n new_l = l.copy()\n for i in range(len(l)):\n if i % 3 == 0:\n new_l[i] = divisible_by_three.pop(0)\n return new_l", "matching_cluster_idx": 6}, {"solution": "def sort_third(l: list):\n divisible_by_three = sorted([elem for i, elem in enumerate(l) if i % 3 == 0])\n result = l.copy()\n index = 0\n for i, elem in enumerate(result):\n if i % 3 == 0:\n result[i] = divisible_by_three[index]\n index += 1\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\"\"\"\n # create a list of elements with indices divisible by 3\n sorted_thirds = sorted(l[i] for i in range(len(l)) if i % 3 == 0)\n # create a list of elements with indices not divisible by 3\n others = [l[i] for i in range(len(l)) if i % 3 != 0]\n\n # initialize an output list with size equal to the input list\n res = [0]*len(l)\n j = 0\n # for every third element replace its value in the output list with a sorted value\n for i in range(len(res)):\n if i % 3 == 0:\n res[i] = sorted_thirds[j]\n j += 1\n else:\n res[i] = others.pop(0)\n return res", "matching_cluster_idx": 6}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\"\"\"\n\n divisible_by_three = sorted([l[i] for i in range(len(l)) if i % 3 == 0])\n sorted_l = l.copy()\n for i in range(len(l)):\n if i % 3 == 0:\n sorted_l[i] = divisible_by_three.pop(0)\n return sorted_l", "matching_cluster_idx": 6}, {"solution": "def sort_third(l: list):\n \"\"\"\n This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n \"\"\"\n third_indices = [i for i in range(len(l)) if i % 3 == 0]\n third_elements = [l[i] for i in third_indices]\n third_elements.sort()\n res = list(l)\n for i, v in zip(third_indices, third_elements):\n res[i] = v\n return res", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n divisible_by_3_indices = [i for i in range(len(l)) if i % 3 == 0]\n divisible_by_3_values = sorted([l[i] for i in divisible_by_3_indices])\n result = l.copy()\n for i, j in zip(divisible_by_3_indices, divisible_by_3_values):\n result[i] = j\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n \"\"\"\n\n # Creating a list to hold third elements\n third_elements = [l[i] for i in range(0, len(l), 3)]\n\n # Sorting the list of third elements\n third_elements.sort()\n\n # Fill the third_elements in sorted order in the original list\n for i in range(0, len(l), 3):\n l[i] = third_elements.pop(0)\n\n return l", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n third_values = [l[i] for i in range(len(l)) if i % 3 == 0]\n third_values.sort()\n result = l.copy()\n for i in range(len(l)):\n if i % 3 == 0:\n result[i] = third_values.pop(0)\n return result", "matching_cluster_idx": 6}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n \"\"\"\n # Get values from input list where index is divisible by three\n thirds = sorted([v for i, v in enumerate(l) if i % 3 == 0])\n\n # Get values from input list where index is not divisible by three\n rest = [v for i, v in enumerate(l) if i % 3 != 0]\n\n # Create new list by placing sorted third values back at their original indexes\n # And placing rest values in the remaining indexes\n res = []\n for i in range(len(l)):\n if i % 3 == 0 and thirds:\n res.append(thirds.pop(0))\n else:\n res.append(rest.pop(0))\n\n return res", "matching_cluster_idx": 6}, {"solution": "def sort_third(l: list):\n # Extract elements at indices that are divisible by three\n indices = [i for i in range(len(l)) if i % 3 == 0]\n elems = [l[i] for i in indices]\n\n # Sort these elements\n elems.sort()\n\n # Replace elements at those indices with the sorted elements\n for i, index in enumerate(indices):\n l[index] = elems[i]\n\n return l", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n # Separate items at indices that are divisible by three\n divisible_by_three = [l[i] for i in range(len(l)) if i % 3 == 0]\n # Sort the separated items\n divisible_by_three.sort()\n # Replace items at indices that are divisible by three\n for i in range(len(l)):\n if i % 3 == 0:\n l[i] = divisible_by_three.pop(0)\n return l", "matching_cluster_idx": 6}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indices that are not divisible by three, while its values at the indices that are divisible by three are \n equal to the values of the corresponding indices of l, but sorted.\n \"\"\"\n # Collect all values that are at indices that are divisible by 3\n div_by_3_vals = sorted([l[i] for i in range(len(l)) if i % 3 == 0])\n\n # Replace the values at indices that are divisible by 3\n j = 0\n for i in range(len(l)):\n if i % 3 == 0:\n l[i] = div_by_3_vals[j]\n j += 1\n\n return l", "matching_cluster_idx": 8}, {"solution": "def sort_third(l):\n elements_at_indices_div_by_three = sorted([l[i] for i in range(len(l)) if i % 3 == 0])\n return [elements_at_indices_div_by_three.pop(0) if i % 3 == 0 else l[i] for i in range(len(l))]", "matching_cluster_idx": 6}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\"\"\"\n # Get list of numbers that are divisible by three\n divisible_by_three = sorted([l[i] for i in range(len(l)) if i % 3 == 0])\n\n # Copy the original list\n new_list = l.copy()\n \n # Replace numbers at positions that are divisible by three with sorted numbers\n for i in range(len(l)):\n if i % 3 == 0:\n new_list[i] = divisible_by_three.pop(0)\n\n return new_list", "matching_cluster_idx": 6}, {"solution": "def sort_third(l):\n div_three_indices = [i for i in range(len(l)) if i % 3 == 0]\n div_three_values = sorted([l[i] for i in div_three_indices])\n \n l_prime = l.copy()\n for index, value in zip(div_three_indices, div_three_values):\n l_prime[index] = value\n \n return l_prime", "matching_cluster_idx": 8}]}, "HumanEval/34": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def unique(l):\n \"\"\"Return sorted unique elements in a list\"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n # Convert the list to a set to get unique elements,\n # then convert the set back to a list,\n # and finally sort the list\n return sorted(list(set(l)))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n\n Args:\n l (list): The list to find unique elements from.\n\n Returns:\n list: A sorted list of unique elements.\n\n Example:\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(list(set(l)))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(list(set(l)))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(list(set(l)))", "matching_cluster_idx": 4}]}, "HumanEval/36": {"dps": 96.77419354838709, "dps_norm": 71.42857142857143, "pass@1": 86.0, "profiled": [{"solution": "def fizz_buzz(n: int):\n count = 0\n for i in range(1, n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int):\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\"\"\"\n count = 0\n for i in range(1, n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"\n Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n \"\"\"\n counter = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n counter += str(i).count('7')\n return counter", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int):\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int):\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\"\"\"\n # Initialize a counter\n counter = 0\n \n # Iterate through integers less than n\n for i in range(n):\n # If i is divisible by 11 or 13\n if i % 11 == 0 or i % 13 == 0:\n # Convert i to a string and count the number of times '7' appears\n counter += str(i).count('7')\n \n return counter", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int):\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n for i in range(11, n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int):\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n\n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int):\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\"\"\"\n count = 0\n for i in range(1, n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int):\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\"\"\"\n \n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n count = 0\n for i in range(11, n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int):\n def count_sevens(num: int):\n return str(num).count('7')\n\n total_sevens = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n total_sevens += count_sevens(i)\n\n return total_sevens", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int):\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\"\"\"\n\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int):\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int):\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\"\"\"\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int):\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}]}, "HumanEval/37": {"dps": 95.18003273322422, "dps_norm": 90.5, "pass@1": 87.0, "profiled": [{"solution": "def sort_even(l):\n # Store even-indexed elements of list in a sorted list\n sorted_even = sorted([l[i] for i in range(0, len(l), 2)])\n \n # Replace even-indexed elements of list with sorted elements\n for i in range(0, len(l), 2):\n l[i] = sorted_even.pop(0)\n \n # Return updated list\n return l", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Extract the even-indexed elements and sort them\n even_elements = sorted(l[i] for i in range(0, len(l), 2))\n \n # Insert the sorted elements back into the original list\n for i, element in zip(range(0, len(l), 2), even_elements):\n l[i] = element\n \n return l", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n \"\"\"\n # Extract even indexed elements and sort them\n even_sorted = sorted(l[::2])\n \n # Construct result list\n result = [None] * len(l)\n result[::2] = even_sorted\n result[1::2] = l[1::2]\n \n return result", "matching_cluster_idx": 9}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n sorted_even_idx_values = sorted(l[i] for i in range(0, len(l), 2))\n for i in range(0, len(l), 2):\n l[i] = sorted_even_idx_values.pop(0)\n return l", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n even_indices = sorted([l[i] for i in range(0, len(l), 2)])\n for i in range(0, len(l), 2):\n l[i] = even_indices[i//2]\n return l", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n even_values = sorted(l[::2])\n for i in range(0, len(l), 2):\n l[i] = even_values.pop(0)\n return l", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n \"\"\"\n even_index_values = sorted(l[i] for i in range(0, len(l), 2))\n result = [None] * len(l)\n result[::2] = even_index_values\n result[1::2] = l[1::2]\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n even_indices = sorted([l[i] for i in range(0, len(l), 2)])\n for i in range(0, len(l), 2):\n l[i] = even_indices.pop(0)\n return l", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"\n This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n even_elements = sorted([l[i] for i in range(0, len(l), 2)])\n for i in range(0, len(l), 2):\n l[i] = even_elements.pop(0)\n return l", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list) -> list:\n \"\"\"\n This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n \"\"\"\n even_index_values = sorted([value for i, value in enumerate(l) if i % 2 == 0])\n new_list = [None]*len(l)\n\n for i, value in enumerate(l):\n if i % 2 == 0:\n new_list[i] = even_index_values.pop(0)\n else:\n new_list[i] = value\n return new_list", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n\n # Extract even-indexed elements and sort them\n sorted_even_indexed_elements = sorted([l[i] for i in range(0, len(l), 2)])\n\n # Replace even-indexed elements in the original list\n for i in range(0, len(l), 2):\n l[i] = sorted_even_indexed_elements.pop(0)\n\n return l", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n sorted_even = sorted([val for idx, val in enumerate(l) if idx % 2 == 0])\n result = [val if idx % 2 != 0 else sorted_even.pop(0) for idx, val in enumerate(l)]\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n \"\"\"\n evens = sorted(l[::2])\n for i in range(0, len(l), 2):\n l[i] = evens.pop(0)\n return l", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"\n This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n \"\"\"\n # Get the even indices\n even_indices = [i for i in range(len(l)) if i % 2 == 0]\n even_values = [l[i] for i in even_indices]\n even_values.sort()\n \n # Replace the even indices in l with the sorted values\n for i, value in zip(even_indices, even_values):\n l[i] = value\n\n return l", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n even_list = sorted([l[i] for i in range(0, len(l), 2)])\n for i in range(0, len(l), 2):\n l[i] = even_list[i//2]\n return l", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n # extract elements at even indices into a new list\n even_index_list = [l[i] for i in range(0, len(l), 2)]\n\n # sort the new list in ascending order\n even_index_list.sort()\n\n # replace the elements at even indices with sorted elements\n for i in range(0, len(l), 2):\n l[i] = even_index_list.pop(0)\n\n return l", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n even_elements = sorted(l[i] for i in range(0, len(l), 2))\n result = l.copy()\n for i in range(0, len(l), 2):\n result[i] = even_elements[i // 2]\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"\n This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Create a copy of the list\n result = l.copy()\n # Extract the even-indexed elements of l and sort them\n sorted_even_indices = sorted(l[i] for i in range(0, len(l), 2))\n\n # Assign the sorted elements back to the even-indexed positions in the result\n for i in range(0, len(l), 2):\n result[i] = sorted_even_indices[i // 2]\n\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n even_numbers = [l[i] for i in range(0, len(l), 2)]\n even_numbers.sort()\n for i in range(0, len(l), 2):\n l[i] = even_numbers.pop(0)\n return l", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Extract the even index elements\n even_indices = [l[i] for i in range(0, len(l), 2)]\n \n # Sort the even indices elements\n even_indices.sort()\n \n # Create a new list by replacing even indices with sorted elements and leaving odd indices as they are\n new_list = [even_indices.pop(0) if i%2 == 0 else l[i] for i in range(len(l))]\n \n return new_list", "matching_cluster_idx": 8}]}, "HumanEval/49": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 90.0, "profiled": [{"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int):\n \"\"\"Return 2^n modulo p (be aware of numerics).\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int):\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"\n Return 2^n modulo p (be aware of numerics).\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n # calculate 2^n using the built-in function pow\n result = pow(2, n, p)\n return result", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"\n Return 2^n modulo p (be aware of numerics).\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n # calculate the result of 2**n modulo p\n result = pow(2, n, p)\n\n return result", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n return pow(2, n, p)", "matching_cluster_idx": 4}]}, "HumanEval/51": {"dps": 96.13526570048309, "dps_norm": 75.0, "pass@1": 100.0, "profiled": [{"solution": "def remove_vowels(text):\n vowels = 'aeiouAEIOU'\n new_text = ''\n\n for char in text:\n if char not in vowels:\n new_text += char\n \n return new_text", "matching_cluster_idx": 5}, {"solution": "import doctest\ndef remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n \"\"\"\n vowels = 'aeiouAEIOU'\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n \"\"\"\n vowels = \"aeiouAEIOU\"\n return \"\".join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n \"\"\"\n vowels = 'aeiouAEIOU'\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n \"\"\"\n vowels = 'aeiouAEIOU'\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n vowels = 'aeiouAEIOU'\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n \"\"\"\n vowels = 'aeiouAEIOU'\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n \"\"\"\n vowels = 'aeiouAEIOU'\n return ''.join([ch for ch in text if ch not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n \"\"\"\n vowels = 'aeiouAEIOU'\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n vowels = 'aeiouAEIOU'\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n \"\"\"\n vowels = 'aeiouAEIOU'\n no_vowel_text = ''.join([char for char in text if char not in vowels])\n return no_vowel_text", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n \"\"\"\n vowels = 'aeiouAEIOU'\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n \"\"\"\n vowels = 'aeiouAEIOU'\n return ''.join([ch for ch in text if ch not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n \"\"\"\n vowels = 'aeiouAEIOU'\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\\\nghijklm\")\n 'bcdf\\\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = 'aeiouAEIOU'\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = ['a', 'e', 'i', 'o', 'u', 'A', 'E', 'I', 'O', 'U']\n return ''.join([i for i in text if i not in vowels])", "matching_cluster_idx": 5}, {"solution": "import doctest\ndef remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = ['a', 'e', 'i', 'o', 'u', 'A', 'E', 'I', 'O', 'U']\n result = ''\n for char in text:\n if char not in vowels:\n result += char\n return result", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n vowels = 'aeiouAEIOU'\n return ''.join(char for char in text if char not in vowels)", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n \"\"\"\n vowels = \"aeiouAEIOU\"\n return \"\".join(c for c in text if c not in vowels)", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n vowels = 'aeiouAEIOU'\n return ''.join(char for char in text if char not in vowels)", "matching_cluster_idx": 5}]}, "HumanEval/54": {"dps": null, "dps_norm": null, "pass@1": 2.0, "profiled": []}, "HumanEval/58": {"dps": 88.66141732283464, "dps_norm": 80.0, "pass@1": 99.0, "profiled": [{"solution": "def common(l1: list, l2: list) -> list:\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n\n \"\"\"\n result = sorted(set(l1) & set(l2))\n return result", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\"\"\"\n\n # Combine the two lists and filter out the unique values\n common_list = list(set(l1) & set(l2))\n \n # Sort the common elements in ascending order\n sorted_list = sorted(common_list)\n \n return sorted_list", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n\n \"\"\"\n return sorted(list(set(l1) & set(l2)))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n \n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n\n \"\"\"\n # Converts lists to sets to make it easier to find common elements\n set1 = set(l1)\n set2 = set(l2)\n \n # Uses set intersection to find common elements\n common_elements = set1 & set2\n\n # Converts set back to list and sorts it\n common_elements = list(common_elements)\n common_elements.sort()\n \n return common_elements", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list) -> list:\n \"\"\"Return sorted unique common elements for two lists.\"\"\"\n return sorted(list(set(l1) & set(l2)))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\"\"\"\n return sorted(list(set(l1) & set(l2)))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\"\"\"\n return sorted(list(set(l1) & set(l2)))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n\n \"\"\"\n common_set = list(set(l1) & set(l2))\n common_set.sort()\n return common_set", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\"\"\"\n return sorted(list(set(l1) & set(l2)))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\"\"\"\n return sorted(list(set(l1) & set(l2)))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n\n # Find intersection of both lists\n common_elements = list(set(l1) & set(l2))\n\n # Sort the list in ascending order\n common_elements.sort()\n\n return common_elements", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n # Converting lists to sets to get unique elements and then convert back to list\n l1 = list(set(l1))\n l2 = list(set(l2))\n common_list = []\n\n # Iterate over elements in both lists and add common elements to common_list\n for i in l1:\n if i in l2:\n common_list.append(i)\n\n # Sort and return common_list\n return sorted(common_list)", "matching_cluster_idx": 0}, {"solution": "def common(l1: list, l2: list) -> list:\n \"\"\"Return sorted unique common elements for two lists.\"\"\"\n return sorted(list(set(l1) & set(l2)))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list) -> list:\n \"\"\"Return sorted unique common elements for two lists.\"\"\"\n return sorted(list(set(l1) & set(l2)))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n\n \"\"\"\n # Convert the lists to sets to find the intersection.\n # Convert the result back to a list for further operations.\n common_elements = list(set(l1) & set(l2))\n # Sort the common elements.\n common_elements.sort()\n return common_elements", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n\n \"\"\"\n # Use list comprehension and set intersection\n common_list = sorted(list(set(l1) & set(l2)))\n return common_list", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n\n \"\"\"\n # Convert lists to sets to get unique elements\n set1 = set(l1)\n set2 = set(l2)\n\n # Find the common elements by intersecting the two sets\n common_set = set1.intersection(set2)\n\n # Convert the common set to a list, sort it and return\n common_list = list(common_set)\n common_list.sort()\n return common_list", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\"\"\"\n return sorted(list(set(l1) & set(l2)))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n # Convert lists to sets to remove duplicates\n set1 = set(l1)\n set2 = set(l2)\n\n # Find the common elements\n common_elements = set1 & set2\n\n # Return the sorted common elements\n return sorted(common_elements)", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list) -> list:\n \"\"\"Return sorted unique common elements for two lists.\"\"\"\n common_elements = list(set(l1) & set(l2))\n common_elements.sort()\n return common_elements", "matching_cluster_idx": 4}]}, "HumanEval/59": {"dps": 91.14583333333333, "dps_norm": 93.33333333333333, "pass@1": 95.0, "profiled": [{"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\"\"\"\n i = 2\n while i * i <= n:\n if n % i:\n i += 1\n else:\n n //= i\n return n", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n def is_prime(num: int) -> bool:\n if num < 2:\n return False\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n return False\n return True\n\n largest_factor = None\n for i in range(2, n):\n if n % i == 0 and is_prime(i):\n largest_factor = i\n\n return largest_factor", "matching_cluster_idx": 2}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\"\"\"\n i = 2\n while i * i <= n:\n if n % i:\n i += 1\n else:\n n //= i\n return n", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\"\"\"\n # Initializing the maximum prime number to 1\n max_prime = -1\n\n # Print the number of 2s that divide n\n while n % 2 == 0:\n max_prime = 2\n n >>= 1 # equivalent to n /= 2\n\n # n is odd now, so a skip of 2 can be used\n for i in range(3, int(n ** 0.5) + 1, 2):\n while n % i == 0:\n max_prime = i\n n //= i\n\n # If n is a prime number and n > 2, n will not get reduced to 1 in loop,\n # so return n\n if n > 2:\n max_prime = n\n\n return max_prime", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\"\"\"\n i = 2\n while i * i <= n:\n if n % i:\n i += 1\n else:\n n //= i\n return n", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\"\"\"\n def is_prime(m: int):\n \"\"\"Check if m is a prime number.\"\"\"\n if m <= 1:\n return False\n if m <= 3:\n return True\n if m % 2 == 0 or m % 3 == 0:\n return False\n i = 5\n while i * i <= m:\n if m % i == 0 or m % (i + 2) == 0:\n return False\n i += 6\n return True\n\n largest_factor = -1\n if n % 2 == 0:\n largest_factor = 2\n while n % 2 == 0:\n n /= 2\n if n % 3 == 0:\n largest_factor = 3\n while n % 3 == 0:\n n /= 3\n i = 5\n while i * i <= n:\n if n % i == 0:\n largest_factor = i\n while n % i == 0:\n n /= i\n if n % (i + 2) == 0:\n largest_factor = i + 2\n while n % (i + 2) == 0:\n n /= (i + 2)\n i += 6\n if n > 1:\n return int(n)\n else:\n return largest_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n i = 2\n while i * i <= n:\n if n % i:\n i += 1\n else:\n n //= i\n return n", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n i = 2\n while i * i <= n:\n if n % i:\n i += 1\n else:\n n //= i\n return n", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\"\"\"\n\n i = 2\n factors = []\n\n while i * i <= n:\n if n % i:\n i += 1\n else:\n n //= i\n factors.append(i)\n\n if n > 1:\n factors.append(n)\n\n return max(factors)", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n i = 2\n while i * i <= n:\n if n % i:\n i += 1\n else:\n n //= i\n return n", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\"\"\"\n i = 2\n while i * i <= n:\n if n % i:\n i += 1\n else:\n n //= i\n return n", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\"\"\"\n def is_prime(num: int) -> bool:\n \"\"\"Helper function to check if a number is prime.\"\"\"\n if num < 2:\n return False\n for i in range(2, int(num**0.5)+1):\n if num % i == 0:\n return False\n return True\n\n largest_factor = None\n for i in range(2, n):\n if n % i == 0 and is_prime(i):\n largest_factor = i\n return largest_factor", "matching_cluster_idx": 2}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n i = 2\n factors = []\n while i * i <= n:\n if n % i:\n i += 1\n else:\n n //= i\n factors.append(i)\n if n > 1:\n factors.append(n)\n return max(factors)", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\"\"\"\n assert n > 1, \"n must be greater than 1\"\n i = 2\n while i * i <= n:\n if n % i:\n i += 1\n else:\n n //= i\n return n", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\"\"\"\n # check for factor 2\n while n % 2 == 0:\n n /= 2\n if n == 1:\n return 2\n\n # check for odd factor\n i = 3\n while i * i <= n:\n while n % i == 0:\n max_prime = i\n n /= i\n i += 2\n\n # if n is a prime number and n > 2\n if n > 2:\n max_prime = n\n\n return max_prime", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\"\"\"\n i = 2\n while i * i <= n:\n if n % i:\n i += 1\n else:\n n //= i\n return n", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"\n Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n i = 2\n while i * i <= n:\n if n % i:\n i += 1\n else:\n n //= i\n return n", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n i = 2\n while i * i <= n:\n if n % i:\n i += 1\n else:\n n //= i\n return n", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n i = 2\n while i * i <= n:\n if n % i:\n i += 1\n else:\n n //= i\n return n", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\"\"\"\n i = 2\n while i * i <= n:\n if n % i:\n i += 1\n else:\n n //= i\n return n", "matching_cluster_idx": 8}]}, "HumanEval/64": {"dps": 66.77489177489177, "dps_norm": 51.041666666666664, "pass@1": 12.0, "profiled": [{"solution": "def vowels_count(s):\n \"\"\"\n Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = 'aeiou'\n s = s.lower()\n count = sum(1 for c in s if c in vowels)\n # if 'y' is at the end, increment count\n if s and s[-1] == 'y':\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n\n vowels = 'aeiou'\n s = s.lower()\n count = sum(1 for char in s if char in vowels)\n\n # Additional condition if y is at end of string\n if s.endswith('y'):\n count += 1\n \n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n vowels = \"aeiou\"\n count = 0\n for char in s.lower():\n if char in vowels:\n count += 1\n if s.lower().endswith('y'):\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n s = s.lower()\n vowel_set = set('aeiou')\n count = sum(1 for char in s if char in vowel_set)\n if s.endswith('y'):\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n \"\"\"\n Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n # Define vowels\n vowels = set(\"aeiou\")\n\n # Initialize counter\n count = 0\n\n # Iterate over the string\n for i in range(len(s)):\n if s[i].lower() in vowels or (s[i].lower() == 'y' and i == len(s) - 1):\n count += 1\n\n return count", "matching_cluster_idx": 1}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n s = s.lower()\n vowels = 'aeiou'\n count = sum(1 for c in s if c in vowels)\n \n # handle 'y' as a vowel when it's at the end\n if s.endswith('y'):\n count += 1\n \n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n vowels = \"aeiou\"\n count = 0\n for letter in s.lower():\n if letter in vowels:\n count += 1\n if s.endswith(\"y\") or s.endswith(\"Y\"):\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n count = 0\n vowels = \"aeiou\"\n\n # Check vowels at beginning and end of string\n for i in range(len(s)):\n if s[i].lower() in vowels or (s[i].lower() == 'y' and i == len(s)-1):\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n count = sum(1 for c in s.lower() if c in 'aeiou')\n if s.lower().endswith('y'):\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n count = 0\n for i in range(len(s)):\n if s[i].lower() in 'aeiou':\n count += 1\n elif i == len(s) - 1 and s[i].lower() == 'y':\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def vowels_count(s):\n vowels = ['a', 'e', 'i', 'o', 'u']\n count = 0\n s = s.lower()\n for i in range(len(s)):\n if s[i] in vowels:\n count += 1\n if s[i] == 'y' and i == len(s) - 1:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def vowels_count(s):\n vowels = \"aeiou\"\n count = 0\n for char in s:\n if char.lower() in vowels:\n count += 1\n # if 'y' is at the end, count it as a vowel\n if s.lower().endswith('y'):\n count += 1\n return count", "matching_cluster_idx": 2}]}, "HumanEval/74": {"dps": 93.46341463414635, "dps_norm": 87.77777777777777, "pass@1": 86.0, "profiled": [{"solution": "def total_match(lst1, lst2):\n sum1 = sum(len(x) for x in lst1)\n sum2 = sum(len(x) for x in lst2)\n \n if sum1 <= sum2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n \"\"\"\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n \"\"\"\n len1 = sum(len(x) for x in lst1)\n len2 = sum(len(x) for x in lst2)\n\n return lst1 if len1 < len2 else lst2 if len1 != len2 else lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n\n len1 = sum(len(s) for s in lst1)\n len2 = sum(len(s) for s in lst2)\n\n if len1 < len2:\n return lst1\n elif len2 < len1:\n return lst2\n else:\n return lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n This function accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n '''\n len1 = sum(len(x) for x in lst1)\n len2 = sum(len(x) for x in lst2)\n if len1 <= len2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n \"\"\"\n This function accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n \"\"\"\n # calculating total number of chars in each list\n total_chars1 = sum(len(x) for x in lst1)\n total_chars2 = sum(len(x) for x in lst2)\n\n # comparing and returning the correct list\n if total_chars1 < total_chars2:\n return lst1\n elif total_chars1 > total_chars2:\n return lst2\n else:\n return lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n def count_chars(lst):\n return sum(len(s) for s in lst)\n\n if count_chars(lst1) <= count_chars(lst2):\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n if sum(len(x) for x in lst1) <= sum(len(x) for x in lst2):\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n total_chars_lst1 = sum(len(s) for s in lst1)\n total_chars_lst2 = sum(len(s) for s in lst2)\n\n if total_chars_lst1 <= total_chars_lst2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n # Getting the total number of characters for both lists\n total_chars1 = sum(len(word) for word in lst1)\n total_chars2 = sum(len(word) for word in lst2)\n\n # Comparing the total number of characters in the two lists and returning the list\n # with fewer total characters. If they are the same, return the first list.\n if total_chars1 <= total_chars2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n lst1_total = sum(len(i) for i in lst1)\n lst2_total = sum(len(i) for i in lst2)\n if lst1_total == lst2_total:\n return lst1\n else:\n return lst1 if lst1_total < lst2_total else lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n len_lst1 = sum(len(s) for s in lst1)\n len_lst2 = sum(len(s) for s in lst2)\n\n if len_lst1 < len_lst2:\n return lst1\n elif len_lst2 < len_lst1:\n return lst2\n else:\n return lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n sum_lst1 = sum(len(word) for word in lst1)\n sum_lst2 = sum(len(word) for word in lst2)\n if sum_lst1 <= sum_lst2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n A function that accepts two lists of strings and returns the list that has total \n number of chars in the all strings of the list less than the other list.\n\n If the two lists have the same number of chars, return the first list.\n '''\n len1 = sum(len(s) for s in lst1)\n len2 = sum(len(s) for s in lst2)\n\n if len1 <= len2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n total_chars1 = sum([len(s) for s in lst1])\n total_chars2 = sum([len(s) for s in lst2])\n \n if total_chars1 <= total_chars2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n sum1 = sum(len(x) for x in lst1)\n sum2 = sum(len(x) for x in lst2)\n\n if sum1 <= sum2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n len_lst1 = sum([len(s) for s in lst1])\n len_lst2 = sum([len(s) for s in lst2])\n\n if len_lst1 <= len_lst2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n total1 = sum(len(x) for x in lst1)\n total2 = sum(len(x) for x in lst2)\n return lst1 if total1 < total2 else lst2 if total1 != total2 else lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n lst1_total_chars = sum(len(x) for x in lst1)\n lst2_total_chars = sum(len(x) for x in lst2)\n\n if lst1_total_chars <= lst2_total_chars:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n def total_chars(lst):\n return sum(len(s) for s in lst)\n\n if total_chars(lst1) < total_chars(lst2):\n return lst1\n elif total_chars(lst1) > total_chars(lst2):\n return lst2\n else:\n return lst1", "matching_cluster_idx": 5}, {"solution": "def total_match(lst1, lst2):\n sum1 = sum(len(s) for s in lst1)\n sum2 = sum(len(s) for s in lst2)\n return lst1 if sum1 <= sum2 else lst2", "matching_cluster_idx": 7}]}, "HumanEval/85": {"dps": 83.66336633663366, "dps_norm": 50.0, "pass@1": 98.0, "profiled": [{"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst, add the even elements that are at odd indices.\n \"\"\"\n return sum(value for index, value in enumerate(lst) if index % 2 != 0 and value % 2 == 0)", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices.\n\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n return sum(value for index, value in enumerate(lst) if index % 2 != 0 and value % 2 == 0)", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices..\n\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n\n return sum(value for index, value in enumerate(lst) if index % 2 != 0 and value % 2 == 0)", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices..\"\"\"\n return sum([value for index, value in enumerate(lst) if index % 2 != 0 and value % 2 == 0])", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n return sum(value for index, value in enumerate(lst) if index % 2 != 0 and value % 2 == 0)", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices.\"\"\"\n\n return sum(value for index, value in enumerate(lst) if index % 2 == 1 and value % 2 == 0)", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n return sum(value for index, value in enumerate(lst) if index % 2 != 0 and value % 2 == 0)", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst, add the even elements that are at odd indices.\n \n Examples:\n add([4, 2, 6, 7]) returns 2 \n \"\"\"\n # Initialize a sum to 0\n sum = 0\n \n # For each index in the list\n for i in range(len(lst)):\n # If the index is odd and the element at that index is even\n if i % 2 == 1 and lst[i] % 2 == 0:\n # Add the element to the sum\n sum += lst[i]\n \n # Return the sum\n return sum", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices.\"\"\"\n\n return sum([n for i, n in enumerate(lst) if i % 2 == 1 and n % 2 == 0])", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"\n Given a non-empty list of integers lst. add the even elements that are at odd indices..\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n result = 0\n for i in range(len(lst)):\n # check if index is odd\n if i % 2 != 0:\n # check if element is even\n if lst[i] % 2 == 0:\n result += lst[i]\n return result", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"\n Given a non-empty list of integers lst. add the even elements that are at odd indices.\n\n Parameters:\n lst (list): a non-empty list of integers.\n\n Returns:\n (int): the sum of the even elements at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) returns: 2\n add([3, 1, 2, 4, 6, 7, 8]) returns: 10\n \"\"\"\n return sum(el for idx, el in enumerate(lst) if idx % 2 != 0 and el % 2 == 0)", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"\n Given a non-empty list of integers lst. add the even elements that are at odd indices.\n \n :param lst: non-empty list of integers \n :return: the sum of even elements at odd indices\n\n Examples:\n add([4, 2, 6, 7]) => 2\n \"\"\"\n \n return sum(num for idx, num in enumerate(lst) if idx % 2 != 0 and num % 2 == 0)", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices.\"\"\"\n return sum(value for index, value in enumerate(lst) if index % 2 == 1 and value % 2 == 0)", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n sum_val = 0\n for i in range(len(lst)):\n if i % 2 != 0 and lst[i] % 2 == 0:\n sum_val += lst[i]\n return sum_val", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices.\n\n Args:\n lst: A list of integers.\n\n Returns:\n Sum of even numbers at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) \n >>> 2\n \"\"\"\n return sum(val for idx, val in enumerate(lst) if idx % 2 != 0 and val % 2 == 0)", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices.\n\n Examples:\n >>> add([4, 2, 6, 7]) \n 2\n \"\"\"\n\n return sum(x for i, x in enumerate(lst) if i % 2 != 0 and x % 2 == 0)", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices.\"\"\"\n return sum(value for index, value in enumerate(lst) if index % 2 != 0 and value % 2 == 0)", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"\n Given a non-empty list of integers lst. add the even elements that are at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n return sum([val for i, val in enumerate(lst) if i % 2 != 0 and val % 2 == 0])", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices.\"\"\"\n return sum(value for index, value in enumerate(lst) if index % 2 == 1 and value % 2 == 0)", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst, add the even elements that are at odd indices.\"\"\"\n return sum(value for index, value in enumerate(lst) if index % 2 != 0 and value % 2 == 0)", "matching_cluster_idx": 2}]}, "HumanEval/86": {"dps": 95.61224489795919, "dps_norm": 98.0, "pass@1": 51.0, "profiled": [{"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n words = s.split(\" \")\n ordered_words = [''.join(sorted(word)) for word in words]\n return ' '.join(ordered_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n words = s.split(' ')\n anti_shuffled = [''.join(sorted(word)) for word in words]\n return ' '.join(anti_shuffled)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n \"\"\"\n words = s.split(' ')\n ordered_words = [\"\".join(sorted(word)) for word in words]\n return ' '.join(ordered_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n \n # Split the string into words\n words = s.split(' ')\n \n # Sort characters in each word\n for i in range(len(words)):\n words[i] = ''.join(sorted(words[i]))\n \n # Join sorted words back into a string\n return ' '.join(words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n def sort_chars(word):\n return ''.join(sorted(word))\n \n words = s.split(' ')\n sorted_words = [sort_chars(word) for word in words]\n return ' '.join(sorted_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n words = s.split(' ')\n ordered_words = [''.join(sorted(word)) for word in words]\n return ' '.join(ordered_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n return ' '.join(''.join(sorted(word, key=lambda x: ord(x))) for word in s.split(' '))", "matching_cluster_idx": 2}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n words = s.split(' ')\n ordered_words = [''.join(sorted(word)) for word in words]\n return ' '.join(ordered_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n \n # Split the string into a list of words\n words = s.split(' ')\n \n # For each word in the list, sort the characters by ascii value and join them\n # back together\n sorted_words = [''.join(sorted(word)) for word in words]\n \n # Join the sorted words back into a string and return\n return ' '.join(sorted_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n def sort_chars(word):\n \"\"\"Returns the word sorted by ASCII value.\"\"\"\n return ''.join(sorted(word, key=ord))\n\n # Split string into words\n words = s.split(' ')\n\n # Sort each word\n sorted_words = [sort_chars(word) for word in words]\n\n # Join words back into a string\n sorted_s = ' '.join(sorted_words)\n\n return sorted_s", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n return ' '.join(''.join(sorted(word)) for word in s.split(' '))", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n words = s.split(\" \")\n for i, word in enumerate(words):\n words[i] = \"\".join(sorted(word))\n return \" \".join(words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n def sort_word(word):\n return ''.join(sorted(word))\n\n words = s.split(' ')\n sorted_words = [sort_word(word) for word in words]\n\n return ' '.join(sorted_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n\n words = s.split(' ')\n ordered_words = [' '.join([''.join(sorted(word)) for word in words])]\n return ' '.join(ordered_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n words = s.split(\" \")\n new_words = []\n\n for word in words:\n chars = list(word)\n chars.sort()\n new_word = \"\".join(chars)\n new_words.append(new_word)\n \n return \" \".join(new_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n\n :param s: str\n :return: str\n \"\"\"\n\n words = s.split(' ')\n sorted_words = [''.join(sorted(word)) for word in words]\n return ' '.join(sorted_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n This function takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n \"\"\"\n\n # Split the sentence into words by space\n words = s.split(' ')\n ordered_words = []\n \n for word in words:\n # Sort characters of the word in ascending order and join them back into a string\n ordered_word = ''.join(sorted(word))\n ordered_words.append(ordered_word)\n \n # Join the words back into a sentence and return\n return ' '.join(ordered_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n\n def order_word(word):\n return ''.join(sorted(word))\n\n words = s.split(' ')\n ordered_words = [order_word(word) for word in words]\n return ' '.join(ordered_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Function that takes a string and returns an ordered version of it.\n \"\"\"\n # split the string into words\n words = s.split(\" \")\n\n # for each word, sort characters and join them back into a string\n ordered_words = [''.join(sorted(word)) for word in words]\n\n # join words back into a string and return it\n return ' '.join(ordered_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Function to return an ordered version of a string.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n\n :param s: string\n :return: string\n \"\"\"\n return \" \".join(\"\".join(sorted(word)) for word in s.split(\" \"))", "matching_cluster_idx": 4}]}, "HumanEval/87": {"dps": 53.371757925072046, "dps_norm": 49.285714285714285, "pass@1": 60.0, "profiled": [{"solution": "def get_row(lst, x):\n coordinates = []\n for i, row in enumerate(lst):\n for j, col in enumerate(row[::-1]):\n if col == x:\n coordinates.append((i, len(row) - j - 1))\n coordinates.sort(key=lambda k: (k[0], -k[1]))\n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n result = []\n for i, row in enumerate(lst):\n indices = [j for j, num in enumerate(row) if num == x]\n for index in sorted(indices, reverse=True):\n result.append((i, index))\n return result", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n coordinates = []\n for i in range(len(lst)):\n for j in range(len(lst[i])):\n if lst[i][j] == x:\n coordinates.append((i, j))\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n return coordinates", "matching_cluster_idx": 2}, {"solution": "def get_row(lst, x):\n coordinates = []\n for i in range(len(lst)):\n for j in range(len(lst[i])):\n if lst[i][j] == x:\n coordinates.append((i, j))\n coordinates.sort(key=lambda c: (c[0], -c[1]))\n return coordinates", "matching_cluster_idx": 2}, {"solution": "def get_row(lst, x):\n coordinates = []\n for i, row in enumerate(lst):\n for j, value in enumerate(row):\n if value == x:\n coordinates.append((i, j))\n #Sort by rows in ascending order and then columns in descending order\n coordinates.sort(key=lambda c: (c[0], -c[1]))\n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n Find integers x in the list and return list of tuples,\n [(x1, y1), (x2, y2) ...] such that each tuple is\n a coordinate - (row, columns), starting with 0. Sort\n coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \"\"\"\n # Initialize an empty list to store coordinates\n coords = []\n\n # Loop through the rows and columns of the 2D list\n for i, row in enumerate(lst):\n # Get indices of x in the current row, starting from 0\n indices = [i for i, v in enumerate(row) if v == x]\n\n # If x is in the current row, add the coordinates to the list\n if indices:\n coords.extend([(i, j) for j in indices])\n\n # Sort coordinates initially by rows in ascending order,\n # then by columns in descending order\n coords.sort(key=lambda x: (x[0], -x[1]))\n\n return coords", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n coordinates = []\n for i in range(len(lst)):\n for j in range(len(lst[i])):\n if lst[i][j] == x:\n coordinates.append((i, j))\n return sorted(coordinates, key=lambda coord: (coord[0], -coord[1]))", "matching_cluster_idx": 2}, {"solution": "def get_row(lst, x):\n coords = []\n for i in range(len(lst)):\n for j in range(len(lst[i])):\n if lst[i][j] == x:\n coords.append((i, j))\n coords.sort(key=lambda coord: (coord[0], -coord[1]))\n return coords", "matching_cluster_idx": 2}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n coordinates = []\n for i in range(len(lst)):\n for j in range(len(lst[i])):\n if lst[i][j] == x:\n coordinates.append((i, j))\n \n # Sorting by rows in ascending order and columns in descending order\n coordinates.sort(key=lambda x: (x[0], -x[1]))\n return coordinates", "matching_cluster_idx": 2}, {"solution": "def get_row(lst, x):\n coordinates = []\n for i in range(len(lst)):\n for j in range(len(lst[i])):\n if lst[i][j] == x:\n coordinates.append((i,j))\n return sorted(coordinates, key=lambda x: (x[0], -x[1]))", "matching_cluster_idx": 2}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n\n coordinates = []\n for row_index, row in enumerate(lst):\n for column_index in sorted([i for i, val in enumerate(row) if val == x], reverse=True):\n coordinates.append((row_index, column_index))\n\n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n coords = []\n\n for row_index, row in enumerate(lst):\n for column_index in reversed(range(len(row))):\n if row[column_index] == x:\n coords.append((row_index, column_index))\n\n return coords", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n Function to find a given number in a 2D list and return its indices\n \"\"\"\n result = []\n for i in range(len(lst)):\n for j in range(len(lst[i])):\n if lst[i][j] == x:\n result.append((i, j))\n\n # Sorting initially by rows in ascending order and then by columns in descending order\n result.sort(key=lambda x: (x[0], -x[1]))\n return result", "matching_cluster_idx": 2}, {"solution": "def get_row(lst, x):\n result = []\n for i in range(len(lst)):\n row = lst[i]\n for j in range(len(row)):\n if row[j] == x:\n result.append((i, j))\n result.sort(key=lambda x: (x[0], -x[1]))\n return result", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n result = []\n for i in range(len(lst)):\n for j in range(len(lst[i])):\n if lst[i][j] == x:\n result.append((i, j))\n result.sort(key=lambda x: (x[0], -x[1]))\n return result", "matching_cluster_idx": 2}, {"solution": "def get_row(lst, x):\n \"\"\"\n Function to find integer x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Args:\n lst: a 2 dimensional data, as a nested lists\n x: an integer\n \n Returns:\n A list of tuples with row and column coordinates of x sorted\n \n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n coordinates = []\n for i in range(len(lst)):\n for j in range(len(lst[i]) - 1, -1, -1):\n if lst[i][j] == x:\n coordinates.append((i, j))\n return coordinates", "matching_cluster_idx": 2}, {"solution": "def get_row(lst, x):\n coordinates = []\n for i in range(len(lst)):\n for j in range(len(lst[i])):\n if lst[i][j] == x:\n coordinates.append((i, j))\n coordinates.sort(key=lambda x: (x[0], -x[1]))\n return coordinates", "matching_cluster_idx": 2}, {"solution": "def get_row(lst, x):\n coords = []\n for i in range(len(lst)):\n for j in range(len(lst[i])):\n if lst[i][j] == x:\n coords.append((i, j))\n coords.sort(key=lambda x: (x[0], -x[1]))\n return coords", "matching_cluster_idx": 2}, {"solution": "def get_row(lst, x):\n \"\"\"\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \"\"\"\n\n coordinates = []\n \n for i in range(len(lst)):\n row = lst[i]\n for j in range(len(row)):\n if row[j] == x:\n coordinates.append((i, j))\n \n coordinates.sort(key=lambda x: (x[0], -x[1]))\n \n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n coordinates = []\n for i in range(len(lst)):\n row = lst[i]\n indices = [(i, j) for j in range(len(row)) if row[j] == x]\n indices.sort(key=lambda x: x[1], reverse=True)\n coordinates.extend(indices)\n return coordinates", "matching_cluster_idx": 3}]}, "HumanEval/89": {"dps": 96.70103092783506, "dps_norm": 31.42857142857143, "pass@1": 69.0, "profiled": [{"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n # Create a string of the alphabet\n alpha = 'abcdefghijklmnopqrstuvwxyz'\n\n # Create a variable to hold the output string\n output_str = ''\n\n # Iterate through each character in the input string\n for char in s:\n # If the character is in the alphabet, get the index and shift it down by 2*2\n if char.lower() in alpha:\n output_str += alpha[(alpha.index(char.lower()) + 2*2) % len(alpha)]\n else:\n output_str += char\n\n # Return the output string\n return output_str", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"\n Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n shift = 2 * 2\n result = \"\"\n\n for char in s:\n if char.isalpha():\n ascii_offset = 65 if char.isupper() else 97\n encrypted_char = chr((((ord(char) - ascii_offset) + shift) % 26) + ascii_offset)\n result += encrypted_char\n else:\n result += char\n\n return result", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"\n Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n \"\"\"\n\n encrypted_text = \"\"\n for character in s:\n ascii_val = ord(character)\n if 65 <= ascii_val <= 90: # For upper case characters\n new_val = ((ascii_val - 65 + 2*2) % 26) + 65\n elif 97 <= ascii_val <= 122: # For lower case characters\n new_val = ((ascii_val - 97 + 2*2) % 26) + 97\n else: # For any other characters that are not letters\n new_val = ascii_val\n encrypted_text += chr(new_val)\n\n return encrypted_text", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n alphabet = 'abcdefghijklmnopqrstuvwxyz'\n encrypted = ''\n for char in s:\n if char in alphabet:\n encrypted += alphabet[(alphabet.index(char) + 4) % len(alphabet)]\n else:\n encrypted += char\n return encrypted", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"\n Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n \"\"\"\n encrypted_s = ''\n for char in s:\n if char.isalpha():\n shift = 4\n if char.isupper():\n encrypted_s += chr((ord(char) - ord('A') + shift) % 26 + ord('A'))\n else:\n encrypted_s += chr((ord(char) - ord('a') + shift) % 26 + ord('a'))\n else:\n encrypted_s += char\n return encrypted_s", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n \"\"\"\n result = \"\"\n for char in s:\n if char.isalpha():\n shift = 2*2\n if char.isupper():\n result += chr((ord(char) - ord('A') + shift) % 26 + ord('A'))\n else:\n result += chr((ord(char) - ord('a') + shift) % 26 + ord('a'))\n else:\n result += char\n return result", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n alphabet = 'abcdefghijklmnopqrstuvwxyz'\n encrypted = ''\n for char in s:\n if char in alphabet:\n index = (alphabet.index(char) + 4) % 26\n encrypted += alphabet[index]\n else:\n encrypted += char\n return encrypted", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and \n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n \n def rotate_char(c):\n \"\"\"Rotate char c by two places.\n If c is not a lowercase letter, return c as it is.\"\"\"\n if 'a' <= c <= 'z':\n return chr(((ord(c) - ord('a') + 4) % 26) + ord('a'))\n else:\n return c\n\n return ''.join(rotate_char(c) for c in s)", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n \"\"\"\n alphabet = \"abcdefghijklmnopqrstuvwxyz\"\n encrypted_text = \"\"\n for char in s:\n if char in alphabet:\n index = (alphabet.index(char) + 2*2) % 26 # use modulus to make sure index stays within bounds\n encrypted_text += alphabet[index]\n else:\n encrypted_text += char\n return encrypted_text", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n result = ''\n for char in s:\n ascii_val = ord(char)\n if 97 <= ascii_val <= 122: # Lowercase a-z\n result += chr((ascii_val - ord('a') + 2*2) % 26 + ord('a'))\n elif 65 <= ascii_val <= 90: # Uppercase A-Z\n result += chr((ascii_val - ord('A') + 2*2) % 26 + ord('A'))\n else:\n result += char\n return result", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n encrypted_string = \"\"\n for char in s:\n if char.isalpha():\n ascii_offset = 65 if char.isupper() else 97\n encrypted_string += chr(((ord(char) - ascii_offset + 2*2) % 26) + ascii_offset)\n else:\n encrypted_string += char\n return encrypted_string", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"\n Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n # Define the alphabet\n alphabet = 'abcdefghijklmnopqrstuvwxyz'\n \n # Define the key for encryption\n key = alphabet[2 * 2:] + alphabet[:2 * 2]\n \n # Create a translation table\n table = str.maketrans(alphabet + alphabet.upper(), key + key.upper())\n \n # Return the encrypted string\n return s.translate(table)", "matching_cluster_idx": 5}, {"solution": "def encrypt(s):\n \"\"\"\n Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n result = \"\"\n for c in s:\n if 'a' <= c <= 'z':\n result += chr(((ord(c) - ord('a') + 4) % 26) + ord('a'))\n elif 'A' <= c <= 'Z':\n result += chr(((ord(c) - ord('A') + 4) % 26) + ord('A'))\n else:\n result += c\n return result", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n result = \"\"\n for letter in s:\n if letter.isalpha():\n ascii_value = ord(letter)\n # Shift down by two multiplied to two places\n new_ascii_value = ascii_value + (2 * 2)\n if letter.isupper():\n if new_ascii_value > ord('Z'):\n new_ascii_value -= 26\n result += chr(new_ascii_value)\n else:\n if new_ascii_value > ord('z'):\n new_ascii_value -= 26\n result += chr(new_ascii_value)\n else:\n result += letter\n return result", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n result = \"\"\n for char in s:\n if char.isalpha():\n ascii_value = ord(char.lower())\n if ascii_value + (2*2) > 122:\n result += chr((ascii_value + (2*2)) % 123 + 97)\n else:\n result += chr(ascii_value + (2*2))\n else:\n result += char\n return result", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n result = \"\"\n for char in s:\n ascii_code = ord(char)\n if 97 <= ascii_code <= 122: # check if the character is lowercase\n result += chr(((ascii_code - 97 + 2*2) % 26) + 97)\n elif 65 <= ascii_code <= 90: # check if the character is uppercase\n result += chr(((ascii_code - 65 + 2*2) % 26) + 65)\n else: # non-alphabetic character\n result += char\n return result", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n \n result = \"\"\n for char in s:\n # If character is a letter, shift it down by 2*2 places in the alphabet\n if char.isalpha():\n char_code = ord(char.lower())\n new_char_code = (char_code - 97 + 4) % 26 + 97\n new_char = chr(new_char_code).upper() if char.isupper() else chr(new_char_code)\n else:\n new_char = char\n result += new_char\n return result", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n alphabet = 'abcdefghijklmnopqrstuvwxyz'\n encrypted_s = ''\n for char in s:\n if char in alphabet:\n new_char = alphabet[(alphabet.index(char) + 2*2) % len(alphabet)]\n encrypted_s += new_char\n else:\n encrypted_s += char\n return encrypted_s", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n result = \"\"\n for char in s:\n if char.isalpha():\n ascii_offset = 97 if char.islower() else 65\n result += chr((ord(char) - ascii_offset + 2*2) % 26 + ascii_offset)\n else:\n result += char\n return result", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n result = \"\"\n for char in s:\n if char.isalpha():\n shift = 2 * 2\n if char.isupper():\n result += chr((ord(char) - ord('A') + shift) % 26 + ord('A'))\n else:\n result += chr((ord(char) - ord('a') + shift) % 26 + ord('a'))\n else:\n result += char\n return result", "matching_cluster_idx": 1}]}, "HumanEval/90": {"dps": 83.21011673151752, "dps_norm": 63.333333333333336, "pass@1": 80.0, "profiled": [{"solution": "def next_smallest(lst):\n if len(lst) < 2:\n return None\n else:\n lst = list(set(lst)) # removing duplicates\n lst.sort()\n if len(lst) < 2:\n return None\n else:\n return lst[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n Return the 2nd smallest element of the list.\n Return None if there is no such element.\n\n >>> next_smallest([1, 2, 3, 4, 5])\n 2\n >>> next_smallest([5, 1, 4, 3, 2])\n 2\n >>> next_smallest([])\n >>> next_smallest([1, 1])\n \"\"\"\n\n # convert the list to a set to remove duplicates\n unique_lst = list(set(lst))\n \n # check if list has less than 2 unique elements\n if len(unique_lst) < 2:\n return None\n \n # sort the list and return the 2nd element\n unique_lst.sort()\n return unique_lst[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n\n if len(lst) < 2:\n return None\n\n smallest = min(lst)\n next_smallest = None\n for i in lst:\n if i != smallest and (next_smallest is None or i < next_smallest):\n next_smallest = i\n\n return next_smallest", "matching_cluster_idx": 2}, {"solution": "def next_smallest(lst):\n if len(lst) < 2: # if there is only 0 or 1 item in list, 2nd smallest element does not exist\n return None\n else:\n lst = sorted(lst) # sort the list in ascending order\n smallest = lst[0] # find the smallest element\n next_smallest = None\n for num in lst[1:]: # iterate through the rest of the list\n if num > smallest: # if an element is larger than the smallest one\n next_smallest = num # it's the next smallest number\n break # exit the loop, because we need only the 2nd smallest element\n return next_smallest", "matching_cluster_idx": 9}, {"solution": "def next_smallest(lst):\n \"\"\"\n Function returns the 2nd smallest element of the list.\n Returns None if there is no such element.\n \"\"\"\n if len(lst) < 2: \n return None\n else:\n lst = list(set(lst))\n lst.sort()\n if len(lst) < 2: \n return None\n else:\n return lst[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n Function that returns the 2nd smallest element of a list\n \"\"\"\n # Remove duplicates from the list\n unique_lst = list(set(lst))\n \n # Sort the list in ascending order\n unique_lst.sort()\n \n # Return None if there is no 2nd smallest element\n if len(unique_lst) < 2:\n return None\n \n return unique_lst[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n if len(lst) < 2:\n return None\n else:\n lst = sorted(lst)\n smallest = lst[0]\n for num in lst:\n if num != smallest:\n return num\n return None", "matching_cluster_idx": 10}, {"solution": "def next_smallest(lst):\n \"\"\"\n Function to return the 2nd smallest element of the list.\n \"\"\"\n # Remove duplicates\n lst = list(set(lst))\n # Check if there are at least 2 unique elements\n if len(lst) < 2:\n return None\n else:\n lst.sort() # sort the list\n return lst[1] # return the 2nd smallest", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n # Remove duplicates\n unique_lst = list(set(lst))\n # Sort in ascending order\n sorted_lst = sorted(unique_lst)\n if len(sorted_lst) > 1:\n return sorted_lst[1]\n return None", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n # Create a set from the list to remove duplicates\n distinct_elements = set(lst)\n \n # If the list has less than 2 distinct elements, there's no 2nd smallest element\n if len(distinct_elements) < 2:\n return None\n \n # Sort the set in ascending order and return the second element\n sorted_elements = sorted(distinct_elements)\n return sorted_elements[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n if len(lst) < 2:\n return None\n else:\n lst.sort()\n smallest = lst[0]\n for item in lst:\n if item > smallest:\n return item\n return None", "matching_cluster_idx": 11}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n\n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) <= 1:\n return None\n else:\n unique_numbers = list(set(lst))\n unique_numbers.sort()\n if len(unique_numbers) > 1:\n return unique_numbers[1]\n else:\n return None", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n Returns the 2nd smallest element of the list.\n \"\"\"\n unique_elements = sorted(set(lst))\n return unique_elements[1] if len(unique_elements) >= 2 else None", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n # convert list to set to remove duplicates\n unique_lst = set(lst)\n # if there are 1 or 0 elements in unique list then there is no 2nd smallest\n if len(unique_lst) <= 1:\n return None\n else:\n # convert back to list and sort\n sorted_lst = sorted(list(unique_lst))\n # return 2nd element in sorted list\n return sorted_lst[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n Function to find the 2nd smallest element in a list\n\n Returns:\n The 2nd smallest element in the list or None if not available\n \"\"\"\n \n # Convert list to set to remove duplicates, then convert back to list\n lst = list(set(lst))\n\n # Sort the list\n lst.sort()\n\n # If there are at least 2 elements in the list return the second smallest\n if len(lst) > 1:\n return lst[1]\n else:\n return None", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n # checking if the list contains at least 2 distinct elements\n if len(set(lst)) < 2:\n return None\n else:\n return sorted(set(lst))[1]", "matching_cluster_idx": 5}, {"solution": "def next_smallest(lst):\n \"\"\"\n Returns the 2nd smallest element of the list.\n If there is no such element, returns None.\n \"\"\"\n distinct_lst = list(set(lst))\n if len(distinct_lst) < 2:\n return None\n else:\n distinct_lst.sort()\n return distinct_lst[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n Returns the 2nd smallest element of the list.\n \"\"\"\n # Remove duplicates by converting the list to a set\n lst = list(set(lst))\n\n # If there are less than 2 unique elements, return None\n if len(lst) < 2:\n return None\n \n # Sort the list and return the 2nd element (which is the 2nd smallest)\n lst.sort()\n return lst[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n\n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n unique_sorted_lst = sorted(set(lst))\n return unique_sorted_lst[1] if len(unique_sorted_lst) > 1 else None", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n lst.sort()\n smallest = lst[0]\n for num in lst:\n if num > smallest:\n return num\n return None", "matching_cluster_idx": 11}]}, "HumanEval/113": {"dps": 94.32048681541582, "dps_norm": 64.16666666666667, "pass@1": 84.0, "profiled": [{"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\"\"\"\n return [f\"the number of odd elements {str(len([ch for ch in item if int(ch) % 2 != 0]))}n the str{len([ch for ch in item if int(ch) % 2 != 0])}ng {len([ch for ch in item if int(ch) % 2 != 0])} of the {len([ch for ch in item if int(ch) % 2 != 0])}nput.\" for item in lst]", "matching_cluster_idx": 0}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n res = []\n for idx, string in enumerate(lst, 1):\n odd_count = sum(1 for digit in string if int(digit) % 2 != 0)\n replaced_string = \"the number of odd elements {}n the str{}ng {} of the {}nput.\".format(odd_count, odd_count, odd_count, odd_count)\n res.append(replaced_string)\n return res", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n output = []\n for i, string in enumerate(lst):\n count = sum(1 for digit in string if int(digit) % 2 != 0)\n output.append(f\"the number of odd elements {count}n the str{count}ng {count} of the {count}nput.\")\n return output", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n result = []\n for i in range(len(lst)):\n string = lst[i]\n count = sum(1 for digit in string if int(digit) % 2 != 0)\n result.append(\"the number of odd elements {}n the str{}ng {} of the {}nput.\".format(count, count, count, count))\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n result = []\n for i, string in enumerate(lst):\n num_odds = sum(int(char) % 2 for char in string)\n result.append(\"the number of odd elements {}n the str{}ng {} of the {}nput.\".format(num_odds, num_odds, num_odds, num_odds))\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n\n result = []\n for i in range(len(lst)):\n odd_digits_count = sum(1 for c in lst[i] if int(c) % 2 != 0)\n result.append(\n f\"the number of odd elements {odd_digits_count}n the str{odd_digits_count}ng {odd_digits_count} of the {odd_digits_count}nput.\")\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n def count_odd_digits(s):\n return sum(1 for c in s if int(c) % 2 == 1)\n\n def generate_string(count, string):\n return f\"the number of odd elements {count}n the str{count}ng {count} of the {count}nput.\"\n\n return [generate_string(count_odd_digits(s), s) for s in lst]", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n result = []\n\n for i in range(len(lst)):\n count = sum(int(d) % 2 for d in lst[i])\n temp_string = f\"the number of odd elements {count}n the str{count}ng {count} of the {count}nput.\"\n result.append(temp_string)\n \n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n output = []\n for i, string in enumerate(lst):\n count = sum(int(digit) % 2 for digit in string)\n output.append(f\"the number of odd elements {count}n the str{count}ng {count} of the {count}nput.\")\n return output", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n output = []\n for i, string in enumerate(lst):\n count_odd = sum(int(ch) % 2 for ch in string)\n output.append(f\"the number of odd elements {count_odd}n the str{count_odd}ng {count_odd} of the {count_odd}nput.\")\n return output", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n result = []\n for i in lst:\n num_of_odds = sum(1 for digit in i if int(digit) % 2 != 0)\n result.append(\n f\"the number of odd elements {num_of_odds}n the str{num_of_odds}ng {num_of_odds} of the {num_of_odds}nput.\")\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n result = []\n for i, s in enumerate(lst):\n odd_digits_in_s = sum(int(c) % 2 for c in s)\n temp = \"the number of odd elements {}n the str{}ng {} of the {}nput.\".format(\n odd_digits_in_s,\n odd_digits_in_s,\n odd_digits_in_s,\n odd_digits_in_s\n )\n result.append(temp)\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n \"\"\"\n result = []\n for i in range(len(lst)):\n odd_numbers = sum(1 for n in lst[i] if int(n) % 2 != 0)\n result.append(f\"the number of odd elements {odd_numbers}n the str{odd_numbers}ng {odd_numbers} of the {odd_numbers}nput.\")\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n output = []\n for i in range(len(lst)):\n str_ = lst[i]\n count = sum(1 for char in str_ if int(char) % 2 != 0)\n output.append(f\"the number of odd elements {count}n the str{count}ng {count} of the {count}nput.\")\n return output", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\"\"\"\n output = []\n for i, string in enumerate(lst):\n count_odd = sum([int(d) % 2 for d in string])\n # Modify the template string\n temp_string = \"the number of odd elements 4n the str4ng 4 of the 4nput.\"\n temp_string = temp_string.replace(\"4\", str(count_odd))\n output.append(temp_string)\n return output", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n output_list = []\n for i, string in enumerate(lst):\n count_odd = sum(1 for digit in string if int(digit) % 2 != 0)\n output_string = f\"the number of odd elements {count_odd}n the str{count_odd}ng {count_odd} of the {count_odd}nput.\"\n output_list.append(output_string)\n return output_list", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n result = []\n for i, s in enumerate(lst):\n count = sum(int(c) % 2 for c in s)\n result.append(f\"the number of odd elements {count}n the str{count}ng {count} of the {count}nput.\")\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n result = []\n for idx, string in enumerate(lst):\n num_odd = sum(1 for digit in string if int(digit) % 2 != 0)\n new_string = \"the number of odd elements {}n the str{}ng {} of the {}nput.\".format(\n num_odd, num_odd, num_odd, num_odd)\n result.append(new_string)\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n result = []\n for i, string in enumerate(lst):\n count = sum(1 for digit in string if int(digit) % 2 != 0)\n temp = \"the number of odd elements {}n the str{}ng {} of the {}nput.\".format(count, count, count, count)\n result.append(temp)\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n result = []\n for i, s in enumerate(lst):\n count = sum(int(c) % 2 for c in s)\n s = s.replace('1', 'n') # replace '1' with 'n'\n s = s.replace('3', 'r') # replace '3' with 'r'\n s = s.replace('4', 'n') # replace '4' with 'n'\n result.append(f\"the number of odd elements {count}n the str{count}ng {count} of the {count}nput.\")\n return result", "matching_cluster_idx": 3}]}, "HumanEval/119": {"dps": 85.81395348837209, "dps_norm": 95.0, "pass@1": 39.0, "profiled": [{"solution": "def match_parens(lst):\n '''\n Given a list of two strings, both strings consist of open parentheses '(' or close parentheses ')',\n the function checks if it is possible to concatenate the two strings in some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S are balanced.\n Returns 'Yes' if there's a way to make a good string, and 'No' otherwise.\n '''\n def is_balanced(s):\n '''\n Helper function to check if a string s is balanced\n '''\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n elif char == ')':\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n s1, s2 = lst\n\n # Try all possible combinations of concatenations and see if any result in a good string\n if is_balanced(s1 + s2):\n return 'Yes'\n elif is_balanced(s2 + s1):\n return 'Yes'\n return 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n def is_good(s):\n count = 0\n for i in s:\n if i == '(':\n count += 1\n else:\n count -= 1\n if count < 0:\n return False\n return count == 0\n\n a, b = lst\n return 'Yes' if is_good(a+b) or is_good(b+a) else 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n # Function to check if the parentheses in the given string is balanced\n def check_balance(s):\n stack = []\n for i in s:\n if i == \"(\":\n stack.append(i)\n elif i == \")\":\n if not stack:\n return False\n stack.pop()\n return len(stack) == 0\n\n # Check for all combinations and return 'Yes' if any of them is good\n for i in range(2):\n if check_balance(lst[0] + lst[1]):\n return \"Yes\"\n lst[0], lst[1] = lst[1], lst[0]\n\n return \"No\"", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n def check(s):\n cnt = 0\n for i in s:\n if i == '(':\n cnt += 1\n else:\n if cnt == 0:\n return False\n cnt -= 1\n return cnt == 0\n\n return 'Yes' if check(lst[0] + lst[1]) or check(lst[1] + lst[0]) else 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n def check_good(s):\n # Function to check if a string is good\n cnt = 0\n for ch in s:\n if ch == '(':\n cnt += 1\n else:\n if cnt == 0:\n return False\n cnt -= 1\n return cnt == 0\n\n # Try all possible concatenations\n if check_good(lst[0] + lst[1]) or check_good(lst[1] + lst[0]):\n return 'Yes'\n else:\n return 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n '''\n Check if it's possible to concatenate the two strings in some order,\n so that the resulting string is good. A string is considered to be good\n if and only if all parentheses in it are balanced.\n\n Parameters:\n lst (list): A list of two strings. Both strings consist of open parentheses '('\n or close parentheses ')'.\n\n Returns:\n str: 'Yes' if there's a way to make a good string, 'No' otherwise.\n '''\n def is_balanced(s):\n '''\n Check if a string is balanced.\n\n Parameters:\n s (str): The input string.\n\n Returns:\n bool: True if the string is balanced, False otherwise.\n '''\n balance = 0\n for c in s:\n if c == '(':\n balance += 1\n else:\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n for i in range(2):\n if is_balanced(lst[0] + lst[1]):\n return 'Yes'\n lst = [lst[1], lst[0]]\n\n return 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n def is_good(s):\n cnt = 0\n for ch in s:\n if ch == '(':\n cnt += 1\n elif ch == ')':\n cnt -= 1\n if cnt < 0:\n return False\n return cnt == 0\n\n return 'Yes' if is_good(lst[0] + lst[1]) or is_good(lst[1] + lst[0]) else 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n def is_good(s):\n cnt = 0\n for c in s:\n if c == '(':\n cnt += 1\n else:\n cnt -= 1\n if cnt < 0:\n return False\n return cnt == 0\n\n return 'Yes' if is_good(lst[0] + lst[1]) or is_good(lst[1] + lst[0]) else 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n def check_balance(s):\n balance = 0\n for c in s:\n if c == '(':\n balance += 1\n elif c == ')':\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n def dfs(idx, s1, s2):\n if idx == len(lst):\n return check_balance(s1 + s2)\n return (dfs(idx + 1, s1 + lst[idx], s2) or \n dfs(idx + 1, s1, s2 + lst[idx]))\n\n return 'Yes' if dfs(0, \"\", \"\") else 'No'", "matching_cluster_idx": 2}, {"solution": "def match_parens(lst):\n # Define a helper function to check if a string is balanced\n def is_balanced(s):\n stack = []\n for ch in s:\n if ch == '(':\n stack.append(ch)\n elif not stack:\n return False\n else:\n stack.pop()\n return not stack\n\n # Use recursion to generate all permutations of the two strings\n def permute(data, i, length):\n # Base case\n if i==length:\n # Check if the concatenated string is balanced\n if is_balanced(data[0] + data[1]):\n return True\n else:\n # Generate permutations\n for j in range(i,length):\n # Swap the i-th and j-th element\n data[j], data[i] = data[i], data[j]\n # Recurse to generate the remaining permutations\n if permute(data, i+1, length):\n return True\n # Swap the i-th and j-th element back (to backtrack)\n data[j], data[i] = data[i], data[j] \n return False\n\n return 'Yes' if permute(lst, 0, len(lst)) else 'No'", "matching_cluster_idx": 3}, {"solution": "def match_parens(lst):\n def is_balanced(s):\n balance = 0\n for c in s:\n if c == '(':\n balance += 1\n elif c == ')':\n balance -= 1\n if balance < 0: # early stopping if there's a closing parenthesis before an opening one\n return False\n return balance == 0\n\n a, b = lst\n return 'Yes' if is_balanced(a + b) or is_balanced(b + a) else 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n if len(lst) != 2:\n return 'Invalid input. Please provide exactly two strings.'\n\n def check_string(string):\n balance = 0\n for character in string:\n if character == '(':\n balance += 1\n elif character == ')':\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n str1, str2 = lst\n return 'Yes' if check_string(str1 + str2) or check_string(str2 + str1) else 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n def check(s):\n balance = 0\n for ch in s:\n if ch == '(':\n balance += 1\n else:\n if balance == 0:\n return False\n balance -= 1\n return balance == 0\n\n a, b = lst\n if check(a + b) or check(b + a):\n return 'Yes'\n else:\n return 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n def check_balance(s):\n balance = 0\n for p in s:\n if p == '(':\n balance += 1\n else:\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n def concat_and_check(s1, s2):\n return check_balance(s1+s2) or check_balance(s2+s1)\n\n return 'Yes' if concat_and_check(lst[0], lst[1]) else 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n def check_balance(s):\n balance = 0\n for c in s:\n if c == '(':\n balance += 1\n elif c == ')':\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n for i in range(2):\n if check_balance(lst[0] + lst[1]):\n return 'Yes'\n lst = [lst[1], lst[0]]\n\n return 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n def is_good(s):\n balance = 0\n for c in s:\n if c == '(':\n balance += 1\n else:\n if balance == 0:\n return False\n balance -= 1\n return balance == 0\n\n s1, s2 = lst\n return 'Yes' if is_good(s1 + s2) or is_good(s2 + s1) else 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n '''\n Checks if it is possible to concatenate the two strings in some order, \n that the resulting string will be good. A string S is considered to be good \n if and only if all parentheses in S are balanced. For example: the string \n '(())()' is good, while the string '())' is not. Returns 'Yes' if there's \n a way to make a good string, and 'No' otherwise.\n \n Parameters:\n lst (list of str): A list of two strings.\n\n Returns:\n str: 'Yes' if a good string can be formed. 'No' otherwise.\n '''\n\n s1, s2 = lst\n def valid(s):\n bal = 0\n for c in s:\n if c == '(':\n bal += 1\n else:\n bal -= 1\n if bal < 0:\n return False\n return bal == 0\n \n return 'Yes' if (valid(s1 + s2) or valid(s2 + s1)) else 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n\n # Join the two strings in a specific order and check if the resulting string is good.\n def is_good(s):\n '''Check if a string s is good.'''\n balance = 0\n for c in s:\n if c == '(':\n balance += 1\n else:\n if balance == 0:\n return False\n balance -= 1\n return balance == 0\n\n # Try all possible concatenation orders.\n if is_good(lst[0] + lst[1]) or is_good(lst[1] + lst[0]):\n return 'Yes'\n else:\n return 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n def is_good(s):\n balance = 0\n for p in s:\n if p == '(':\n balance += 1\n elif p == ')':\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n return 'Yes' if is_good(lst[0] + lst[1]) or is_good(lst[1] + lst[0]) else 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n def balanced(s):\n count = 0\n for c in s:\n if c == '(':\n count += 1\n elif c == ')':\n count -= 1\n if count < 0:\n return False\n return count == 0\n\n return 'Yes' if any(balanced(lst[0] + lst[1]) or balanced(lst[1] + lst[0]) for _ in lst) else 'No'", "matching_cluster_idx": 2}]}, "HumanEval/120": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 40.0, "profiled": [{"solution": "def maximum(arr, k):\n arr.sort(reverse=True)\n return sorted(arr[:k])", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n\n Example 1:\n\n Input: arr = [-3, -4, 5], k = 3\n Output: [-4, -3, 5]\n\n Example 2:\n\n Input: arr = [4, -4, 4], k = 2\n Output: [4, 4]\n\n Example 3:\n\n Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1\n Output: [2]\n\n Note:\n 1. The length of the array will be in the range of [1, 1000].\n 2. The elements in the array will be in the range of [-1000, 1000].\n 3. 0 <= k <= len(arr)\n \"\"\"\n arr.sort(reverse=True)\n return sorted(arr[:k])", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n\n Example 1:\n\n Input: arr = [-3, -4, 5], k = 3\n Output: [-4, -3, 5]\n\n Example 2:\n\n Input: arr = [4, -4, 4], k = 2\n Output: [4, 4]\n\n Example 3:\n\n Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1\n Output: [2]\n\n Note:\n 1. The length of the array will be in the range of [1, 1000].\n 2. The elements in the array will be in the range of [-1000, 1000].\n 3. 0 <= k <= len(arr)\n \"\"\"\n arr.sort(reverse=True)\n return sorted(arr[:k])", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n\n Example 1:\n\n Input: arr = [-3, -4, 5], k = 3\n Output: [-4, -3, 5]\n\n Example 2:\n\n Input: arr = [4, -4, 4], k = 2\n Output: [4, 4]\n\n Example 3:\n\n Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1\n Output: [2]\n\n Note:\n 1. The length of the array will be in the range of [1, 1000].\n 2. The elements in the array will be in the range of [-1000, 1000].\n 3. 0 <= k <= len(arr)\n \"\"\"\n \n # Sort the array in descending order\n arr.sort(reverse=True)\n\n # Get the first k elements\n max_k = arr[:k]\n\n # Sort the result in ascending order\n max_k.sort()\n\n return max_k", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n \"\"\"\n # Sort the array in descending order\n arr.sort(reverse=True)\n\n # Return the first k elements\n return sorted(arr[:k])", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n arr.sort(reverse=True)\n return sorted(arr[:k])", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n arr.sort(reverse=True)\n return sorted(arr[:k])", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n\n Example 1:\n\n Input: arr = [-3, -4, 5], k = 3\n Output: [-4, -3, 5]\n\n Example 2:\n\n Input: arr = [4, -4, 4], k = 2\n Output: [4, 4]\n\n Example 3:\n\n Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1\n Output: [2]\n\n Note:\n 1. The length of the array will be in the range of [1, 1000].\n 2. The elements in the array will be in the range of [-1000, 1000].\n 3. 0 <= k <= len(arr)\n \"\"\"\n\n arr.sort(reverse=True)\n return sorted(arr[:k])", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n \"\"\"\n # sort the array in descending order\n arr.sort(reverse=True)\n # return the first k elements\n return sorted(arr[:k])", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n arr.sort(reverse=True)\n return sorted(arr[:k])", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n\n Example 1:\n\n Input: arr = [-3, -4, 5], k = 3\n Output: [-4, -3, 5]\n\n Example 2:\n\n Input: arr = [4, -4, 4], k = 2\n Output: [4, 4]\n\n Example 3:\n\n Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1\n Output: [2]\n\n Note:\n 1. The length of the array will be in the range of [1, 1000].\n 2. The elements in the array will be in the range of [-1000, 1000].\n 3. 0 <= k <= len(arr)\n \"\"\"\n # Sort the array in decreasing order\n arr.sort(reverse=True)\n\n # Return a sorted list with maximum k numbers\n return sorted(arr[:k])", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n \"\"\"\n arr.sort(reverse=True)\n return sorted(arr[:k])", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n\n Example 1:\n\n Input: arr = [-3, -4, 5], k = 3\n Output: [-4, -3, 5]\n\n Example 2:\n\n Input: arr = [4, -4, 4], k = 2\n Output: [4, 4]\n\n Example 3:\n\n Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1\n Output: [2]\n\n Note:\n 1. The length of the array will be in the range of [1, 1000].\n 2. The elements in the array will be in the range of [-1000, 1000].\n 3. 0 <= k <= len(arr)\n \"\"\"\n arr.sort(reverse=True)\n return sorted(arr[:k])", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n\n Example 1:\n\n Input: arr = [-3, -4, 5], k = 3\n Output: [-4, -3, 5]\n\n Example 2:\n\n Input: arr = [4, -4, 4], k = 2\n Output: [4, 4]\n\n Example 3:\n\n Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1\n Output: [2]\n\n Note:\n 1. The length of the array will be in the range of [1, 1000].\n 2. The elements in the array will be in the range of [-1000, 1000].\n 3. 0 <= k <= len(arr)\n \"\"\"\n arr.sort(reverse=True)\n return sorted(arr[:k])", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n \"\"\"\n arr.sort(reverse=True)\n return sorted(arr[:k])", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n\n Example 1:\n\n Input: arr = [-3, -4, 5], k = 3\n Output: [-4, -3, 5]\n\n Example 2:\n\n Input: arr = [4, -4, 4], k = 2\n Output: [4, 4]\n\n Example 3:\n\n Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1\n Output: [2]\n\n Note:\n 1. The length of the array will be in the range of [1, 1000].\n 2. The elements in the array will be in the range of [-1000, 1000].\n 3. 0 <= k <= len(arr)\n \"\"\"\n\n arr.sort(reverse=True)\n return sorted(arr[:k])", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n \"\"\"\n # Sort the array in descending order\n arr.sort(reverse=True)\n\n # Return the first k elements\n return sorted(arr[:k])", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n\n Example 1:\n\n Input: arr = [-3, -4, 5], k = 3\n Output: [-4, -3, 5]\n\n Example 2:\n\n Input: arr = [4, -4, 4], k = 2\n Output: [4, 4]\n\n Example 3:\n\n Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1\n Output: [2]\n\n Note:\n 1. The length of the array will be in the range of [1, 1000].\n 2. The elements in the array will be in the range of [-1000, 1000].\n 3. 0 <= k <= len(arr)\n \"\"\"\n arr.sort(reverse=True)\n return sorted(arr[:k])", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n\n Example 1:\n\n Input: arr = [-3, -4, 5], k = 3\n Output: [-4, -3, 5]\n\n Example 2:\n\n Input: arr = [4, -4, 4], k = 2\n Output: [4, 4]\n\n Example 3:\n\n Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1\n Output: [2]\n\n Note:\n 1. The length of the array will be in the range of [1, 1000].\n 2. The elements in the array will be in the range of [-1000, 1000].\n 3. 0 <= k <= len(arr)\n \"\"\"\n arr.sort(reverse=True)\n return sorted(arr[:k])", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n \"\"\"\n arr.sort(reverse=True) # Sort the array in descending order\n return sorted(arr[:k]) # Return the first k elements of the sorted array", "matching_cluster_idx": 6}]}, "HumanEval/121": {"dps": 78.02690582959642, "dps_norm": 57.142857142857146, "pass@1": 100.0, "profiled": [{"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\"\"\"\n return sum(n for i, n in enumerate(lst) if i % 2 == 0 and n % 2 == 1)", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements \n that are in even positions.\n\n Examples:\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==>0\n \"\"\"\n return sum(val for i, val in enumerate(lst) if i % 2 == 0 and val % 2 != 0)", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n\n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==>0\n \"\"\"\n\n return sum(value for index, value in enumerate(lst) if index % 2 == 0 and value % 2 == 1)", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n return sum(value for index, value in enumerate(lst) if index % 2 == 0 and value % 2 == 1)", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n\n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==>0\n \"\"\"\n \n return sum(val for i, val in enumerate(lst) if i % 2 == 0 and val % 2 == 1)", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n\n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==>0\n \"\"\"\n\n return sum(val for i, val in enumerate(lst) if i % 2 == 0 and val % 2 == 1)", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \"\"\"\n return sum(el for i, el in enumerate(lst) if i % 2 == 0 and el % 2 == 1)", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n \"\"\"\n Given a non-empty list of integers, return the sum of all of the odd elements \n that are in even positions.\n\n Examples:\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==>0\n \"\"\"\n return sum(value for index, value in enumerate(lst) if index % 2 == 0 and value % 2 == 1)", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n return sum(value for index, value in enumerate(lst) if index % 2 == 0 and value % 2 == 1)", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n return sum(value for index, value in enumerate(lst) if index % 2 == 0 and value % 2 != 0)", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \"\"\"\n result = 0\n for index, value in enumerate(lst):\n if index % 2 == 0 and value % 2 != 0:\n result += value\n return result", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n return sum([num for index, num in enumerate(lst) if index % 2 == 0 and num % 2 != 0])", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \"\"\"\n return sum([num for idx, num in enumerate(lst) if idx % 2 == 0 and num % 2 != 0])", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n return sum(val for i, val in enumerate(lst) if i % 2 == 0 and val % 2 == 1)", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==>0\n \"\"\"\n return sum(val for idx, val in enumerate(lst) if idx % 2 == 0 and val % 2 != 0)", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\"\"\"\n return sum(x for i, x in enumerate(lst) if i % 2 == 0 and x % 2 != 0)", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n return sum([num for index, num in enumerate(lst) if index % 2 == 0 and num % 2 != 0])", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n return sum(value for index, value in enumerate(lst) if index % 2 == 0 and value % 2 != 0)", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n return sum(val for i, val in enumerate(lst) if i % 2 == 0 and val % 2 != 0)", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n\n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==>0\n \"\"\"\n return sum(val for i, val in enumerate(lst) if i % 2 == 0 and val % 2 == 1)", "matching_cluster_idx": 3}]}, "HumanEval/149": {"dps": 86.53543307086615, "dps_norm": 59.28571428571429, "pass@1": 100.0, "profiled": [{"solution": "def sorted_list_sum(lst):\n \"\"\"Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order,\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n You may assume that all words will have the same length.\n For example:\n assert list_sort([\"aa\", \"a\", \"aaa\"]) => [\"aa\"]\n assert list_sort([\"ab\", \"a\", \"aaa\", \"cd\"]) => [\"ab\", \"cd\"]\n \"\"\"\n # Filtering the list to only keep the strings with even length\n lst = [x for x in lst if len(x) % 2 == 0]\n\n # Sorting the list by length and alphabetically\n lst.sort(key=lambda x: (len(x), x))\n\n return lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n # Filter the list to only include words with even length\n lst = [word for word in lst if len(word) % 2 == 0]\n \n # Sort the list by length and then lexicographically\n lst.sort(key=lambda x: (len(x), x))\n\n return lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n # Use list comprehension to filter out words of odd length\n lst = [word for word in lst if len(word) % 2 == 0]\n\n # Sort the list by length and then alphabetically\n lst.sort(key = lambda x:(len(x), x))\n\n return lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n even_length_lst = [string for string in lst if len(string) % 2 == 0]\n sorted_lst = sorted(even_length_lst, key=lambda x: (len(x), x))\n return sorted_lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"\n Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order.\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word,\n and you should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n You may assume that all words will have the same length.\n For example:\n assert list_sort([\"aa\", \"a\", \"aaa\"]) => [\"aa\"]\n assert list_sort([\"ab\", \"a\", \"aaa\", \"cd\"]) => [\"ab\", \"cd\"]\n \"\"\"\n # Filter the list to only include strings of even length\n filtered_list = [s for s in lst if len(s) % 2 == 0]\n \n # Sort the list by length of the strings and then by the strings themselves\n sorted_list = sorted(filtered_list, key=lambda x: (len(x), x))\n \n return sorted_list", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"Return a sorted list of strings of even length.\"\"\"\n # Filter out strings with odd lengths\n lst = [s for s in lst if len(s) % 2 == 0]\n \n # Sort by length and then alphabetically\n lst.sort(key=lambda s: (len(s), s))\n \n return lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n # Filter the list to exclude strings with odd lengths\n lst = [x for x in lst if len(x) % 2 == 0]\n \n # Sort the list first by length and then alphabetically\n lst.sort(key=lambda x: (len(x), x))\n \n return lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"\n Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order,\n \"\"\"\n\n # remove strings of odd lengths\n lst = [word for word in lst if len(word) % 2 == 0]\n\n # sort the list by length, then lexicographically\n lst.sort(key=lambda x: (len(x), x))\n\n return lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n # Filter out the strings with odd lengths\n lst = [s for s in lst if len(s) % 2 == 0]\n\n # Sort the list by length and then alphabetically\n lst.sort(key=lambda s: (len(s), s))\n\n return lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"\n This function takes a list of strings as input and:\n 1. Filters out the strings with odd lengths.\n 2. Sorts the list by length of words, and alphabetically for words of same length.\n 3. Returns the resulting sorted list.\n \"\"\"\n # Filter out strings with odd lengths\n lst = [word for word in lst if len(word) % 2 == 0]\n\n # Sort the list by length of words and alphabetically\n lst.sort(key=lambda x: (len(x), x))\n\n return lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"\n Function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order.\n \"\"\"\n \n # filter out strings with odd length\n lst = [s for s in lst if len(s) % 2 == 0]\n\n # sort by length then alphabetically\n lst.sort(key=lambda s: (len(s), s))\n\n return lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order.\n \"\"\"\n # Filter out strings with odd lengths\n lst = [i for i in lst if len(i) % 2 == 0]\n # Sort the list by length and then alphabetically\n lst.sort(key=lambda x: (len(x), x))\n return lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order,\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n You may assume that all words will have the same length.\n For example:\n assert list_sum([\"aa\", \"a\", \"aaa\"]) => [\"aa\"]\n assert list_sum([\"ab\", \"a\", \"aaa\", \"cd\"]) => [\"ab\", \"cd\"]\n \"\"\"\n # Filter list by length\n filtered_lst = [s for s in lst if len(s) % 2 == 0]\n\n # Sort filtered list by length and then alphabetically\n sorted_lst = sorted(filtered_lst, key=lambda x: (len(x), x))\n\n return sorted_lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order,\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n You may assume that all words will have the same length.\n For example:\n assert list_sort([\"aa\", \"a\", \"aaa\"]) => [\"aa\"]\n assert list_sort([\"ab\", \"a\", \"aaa\", \"cd\"]) => [\"ab\", \"cd\"]\n \"\"\"\n \n even_length_list = [s for s in lst if len(s) % 2 == 0]\n even_length_list.sort()\n even_length_list.sort(key=len)\n return even_length_list", "matching_cluster_idx": 6}, {"solution": "def sorted_list_sum(lst):\n \"\"\"\n Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order,\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n You may assume that all words will have the same length.\n For example:\n assert list_sort([\"aa\", \"a\", \"aaa\"]) => [\"aa\"]\n assert list_sort([\"ab\", \"a\", \"aaa\", \"cd\"]) => [\"ab\", \"cd\"]\n \"\"\"\n # Remove strings with odd length\n lst = [s for s in lst if len(s) % 2 == 0]\n\n # Sort the list by length of each word, then alphabetically\n lst.sort(key=lambda s: (len(s), s))\n\n return lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order,\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n You may assume that all words will have the same length.\n For example:\n assert list_sort([\"aa\", \"a\", \"aaa\"]) => [\"aa\"]\n assert list_sort([\"ab\", \"a\", \"aaa\", \"cd\"]) => [\"ab\", \"cd\"]\n \"\"\"\n # filter out words of odd lengths\n lst = [word for word in lst if len(word) % 2 == 0]\n # sort words by length and then alphabetically\n lst.sort(key=lambda x: (len(x), x))\n return lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"\n Deletes the strings that have odd lengths from list,\n returns the resulted list with a sorted order.\n\n Order of the list is ascending by length of each word, and alphabetically.\n\n Args:\n lst (list): a list of strings\n\n Returns:\n list: a list of strings sorted as described above\n \"\"\"\n result = [word for word in lst if len(word) % 2 == 0]\n return sorted(result, key=lambda word: (len(word), word))", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"\n Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order.\n \"\"\"\n # Delete the strings that have odd lengths from the list\n lst = [s for s in lst if len(s) % 2 == 0]\n\n # Sort the list by length of each word and then by alphabetically\n lst = sorted(lst, key=lambda s: (len(s), s))\n\n return lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n # Filter list to contain only words of even length\n lst = [word for word in lst if len(word) % 2 == 0]\n # Sort the list first by length and then alphabetically\n lst.sort(key=lambda word: (len(word), word))\n return lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n # Filter out the strings with odd lengths\n lst = [word for word in lst if len(word) % 2 == 0]\n\n # Sort by length and then alphabetically\n lst.sort(key=lambda x: (len(x), x))\n\n return lst", "matching_cluster_idx": 3}]}, "Mbpp/3": {"dps": 80.76271186440678, "dps_norm": 87.5, "pass@1": 88.0, "profiled": [{"solution": "def is_not_prime(n):\n if n <= 1:\n return True\n elif n <= 3:\n return False\n elif n % 2 == 0 or n % 3 == 0:\n return True\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return True\n i += 6\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n \"\"\"\n Function to check if a given number is not prime\n \"\"\"\n # if number is less than 2, it's not prime\n if n < 2:\n return True\n # check divisibility starting from 2 up to n\n for i in range(2, n):\n if n % i == 0: # number is divisible - not prime\n return True\n # if no divisible number found - it's a prime number\n return False", "matching_cluster_idx": 1}, {"solution": "def is_not_prime(n):\n if n <= 1:\n return True\n if n <= 3:\n return False\n if n % 2 == 0 or n % 3 == 0:\n return True\n i = 5\n while(i * i <= n):\n if n % i == 0 or n % (i + 2) == 0:\n return True\n i += 6\n return False", "matching_cluster_idx": 7}, {"solution": "def is_prime(n):\n \"\"\"\n Helper function to check if a number is prime\n \"\"\"\n if n < 2:\n return False\n for i in range(2, int(n ** 0.5) + 1):\n if n % i == 0:\n return False\n return True\ndef is_not_prime(n):\n \"\"\"\n Main function to check if a number is not prime\n \"\"\"\n return not is_prime(n)", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(n):\n if n < 2:\n return True\n for i in range(2, int(n ** 0.5) + 1):\n if n % i == 0:\n return True\n return False", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(n):\n \"\"\"\n Check if a number is not prime.\n \"\"\"\n if n <= 1:\n return True\n elif n <= 3:\n return False\n elif n % 2 == 0 or n % 3 == 0:\n return True\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return True\n i += 6\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n \"\"\"\n This function checks if a number is not a prime number.\n \"\"\"\n # 0 and 1 are not prime numbers\n if n < 2:\n return True\n # 2 is the only even prime number\n if n == 2: \n return False\n # all other even numbers are not primes\n if n % 2 == 0: \n return True\n # range starts with 3 and only needs to go up the square root of n\n # for all odd numbers\n for x in range(3, int(n**0.5) + 1, 2):\n if n % x == 0:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n \"\"\"\n Function to identify non-prime numbers.\n \"\"\"\n if n <= 1:\n return True\n elif n <= 3:\n return False\n elif n % 2 == 0 or n % 3 == 0:\n return True\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return True\n i += 6\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n \"\"\"\n Check if a number is not prime.\n \"\"\"\n # 0 and 1 are not prime\n if n < 2:\n return True\n \n # 2 is prime\n if n == 2:\n return False\n\n # check factors\n for i in range(2, int(n ** 0.5) + 1):\n if n % i == 0:\n return True\n\n return False", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(n):\n if n <= 1:\n return True\n elif n <= 3:\n return False\n elif n % 2 == 0 or n % 3 == 0:\n return True\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return True\n i += 6\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(num):\n if num <= 1:\n return True\n elif num <= 3:\n return False\n elif num % 2 == 0 or num % 3 == 0:\n return True\n i = 5\n while i * i <= num:\n if num % i == 0 or num % (i + 2) == 0:\n return True\n i += 6\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n if n <= 1:\n return True\n elif n <= 3:\n return False\n elif n % 2 == 0 or n % 3 == 0:\n return True\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return True\n i = i + 6\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n if n <= 1:\n return True\n for i in range(2, int(n ** 0.5) + 1):\n if n % i == 0:\n return True\n return False", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(n):\n if n <= 1 or (n % 2 == 0 and n > 2): \n return True\n for i in range(3, int(n**0.5) + 1, 2):\n if n % i == 0:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n \"\"\"\n Function to check if a number is not prime.\n\n Parameters:\n n (int): Number to be checked\n\n Returns:\n bool: Whether the number is not prime\n \"\"\"\n if n < 2: # Numbers less than 2 are not prime\n return True\n for i in range(2, int(n**0.5) + 1): # Checking for factors up to sqrt(n)\n if n % i == 0: # If n is divisible by any i, it is not prime\n return True\n return False # If no factors found, n is prime", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(n):\n if n <= 1:\n return True\n if n <= 3:\n return False\n if n % 2 == 0 or n % 3 == 0:\n return True\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return True\n i += 6\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n if n <= 1 or (n % 2 == 0 and n > 2): \n return True\n for i in range(3, int(n**0.5) + 1, 2):\n if n % i == 0:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n if n < 2:\n return True\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return True\n return False", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(n):\n \"\"\"\n Function to check if a number is not prime\n \"\"\"\n if n <= 1:\n return True\n elif n <= 3:\n return False\n elif n % 2 == 0 or n % 3 == 0:\n return True\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return True\n i += 6\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n if n < 2:\n return True\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return True\n return False", "matching_cluster_idx": 5}]}, "Mbpp/4": {"dps": 91.51877133105802, "dps_norm": 82.91666666666666, "pass@1": 92.0, "profiled": [{"solution": "import heapq\ndef heap_queue_largest(numbers, n):\n return heapq.nlargest(n, numbers)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n return heapq.nlargest(n, nums)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n \"\"\"\n Function to find the n largest integers from a given list of numbers.\n \"\"\"\n # Using a heap data structure to find the n largest numbers\n return heapq.nlargest(n, nums)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n # Use heapq to find the n largest elements\n return heapq.nlargest(n, nums)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n # use heapq's nlargest function\n # it returns a list with n largest elements of the nums list\n # in descending order\n return heapq.nlargest(n, nums)\nnums = [25, 35, 22, 85, 14, 65, 75, 22, 58]\nn = 3", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n \"\"\"Returns the n largest integers from a given list, in descending order.\"\"\"\n return heapq.nlargest(n, nums)", "matching_cluster_idx": 9}, {"solution": "def heap_queue_largest(numbers, n):\n import heapq\n # Use heapq.nlargest to find the n largest numbers\n # Negate the numbers to turn the problem into finding the n smallest numbers, and then negate them back to get the answer in descending order\n return [-x for x in heapq.nsmallest(n, [-num for num in numbers])]", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(lst, n):\n #Use heapq library to find the n largest integers\n return heapq.nlargest(n, lst)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n return heapq.nlargest(n, nums)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(numbers, n):\n return heapq.nlargest(n, numbers)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n # Convert the list to a heap\n heap = [-num for num in nums]\n heapq.heapify(heap)\n \n # Find the n largest numbers\n largest = [heapq.heappop(heap) for _ in range(n)]\n \n # Convert the results back to original values and return\n return [-num for num in largest]", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(numbers, n):\n if n > len(numbers):\n return None\n return sorted(heapq.nlargest(n, numbers), reverse=True)", "matching_cluster_idx": 9}, {"solution": "def heap_queue_largest(nums, n):\n \"\"\"Find the n largest integers from a given list of numbers, returned in descending order.\"\"\"\n import heapq\n\n if len(nums) < n:\n return \"Error: n is larger than the list length\"\n \n return heapq.nlargest(n, nums)", "matching_cluster_idx": 9}, {"solution": "def heap_queue_largest(lst, n):\n import heapq\n heap = []\n for num in lst:\n heapq.heappush(heap, num)\n if len(heap) > n:\n heapq.heappop(heap)\n return sorted(heap, reverse=True)", "matching_cluster_idx": 8}, {"solution": "def heap_queue_largest(nums, n):\n \"\"\"\n Function to find the n largest integers from a given list of numbers, \n returned in descending order.\n \"\"\"\n # Checking if the list has enough elements to return n numbers\n if len(nums) < n:\n return \"Error: List has less than n elements\"\n\n # Using list comprehension to handle possible invalid inputs\n try:\n nums = [int(i) for i in nums]\n except ValueError:\n return \"Error: List contains non-integer elements\"\n\n # Sorting the list in descending order and returning the first n numbers\n nums.sort(reverse=True)\n return nums[:n]", "matching_cluster_idx": 9}, {"solution": "def heap_queue_largest(nums, n):\n import heapq\n return heapq.nlargest(n, nums)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n return heapq.nlargest(n, nums)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n # Use heapq.nlargest to find the n largest numbers from the list\n # Include negative sign to turn the min-heap into a max-heap\n # Since Python doesn't support max-heap, we are assuming we will consider max as min\n return heapq.nlargest(n, nums)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(lst, n):\n if not lst or n > len(lst) or n < 1:\n return None\n \n return heapq.nlargest(n, lst)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n \"\"\"\n Function to find the n largest integers from a given list of numbers, returned in descending order.\n \"\"\"\n if n <= 0 or not nums:\n return []\n\n return heapq.nlargest(n, nums)", "matching_cluster_idx": 9}]}, "Mbpp/9": {"dps": 92.58503401360544, "dps_norm": 59.0, "pass@1": 72.0, "profiled": [{"solution": "def find_Rotations(s):\n # Concatenate the string with itself\n concatenated = s + s\n\n # Search for the first occurrence of the original string in the concatenated string\n for i in range(1, len(s) + 1):\n if concatenated[i : i + len(s)] == s:\n return i\n\n # If no rotation equals the original string, return len(s)\n return len(s)", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(string):\n double_string = string + string\n length = len(string)\n for i in range(1, length + 1):\n rotation = double_string[i : i+length]\n if rotation == string:\n return i\n return length", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(input_string):\n # create a string that is double the original string\n double_string = input_string + input_string\n \n # find the minimum number of rotations\n for i in range(1, len(input_string) + 1):\n if double_string[i : i + len(input_string)] == input_string:\n return i\n # return 0 if no rotations are possible\n return 0", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(input_str):\n temp = input_str + input_str\n str_len = len(input_str)\n\n for i in range(1, str_len + 1):\n sub_str = temp[i : str_len + i]\n if (input_str == sub_str):\n return i\n\n return str_len", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(str):\n temp = str + str\n n = len(str)\n for i in range(1, n + 1):\n substring = temp[i: i+n]\n if substring == str:\n return i\n return n", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(s):\n temp = s + s\n n = len(s)\n\n for i in range(1, n+1):\n substring = temp[i: n+i]\n if (s == substring):\n return i\n\n return n", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(s):\n n = len(s)\n check_string = s + s\n for i in range(1, n + 1):\n sub_string = check_string[i:n + i]\n if sub_string == s:\n return i\n return n", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(input_string):\n # Concatenate 'input_string' with itself\n tmp = input_string + input_string\n length = len(input_string)\n\n for i in range(1, length + 1):\n # Substring of length 'length' from index 'i' in 'tmp'\n substring = tmp[i : i + length]\n\n # If the substring is equal to the input_string, then return the rotation count\n if substring == input_string:\n return i\n\n # If no rotation gives the input_string\n return -1", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(s):\n temp = s + s\n n = len(s)\n for i in range(1, n + 1):\n substring = temp[i: n + i]\n if s == substring:\n return i\n return n", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(string):\n if len(string) == 0:\n return 0\n temp = string + string\n length = len(string)\n for i in range(1, len(temp)-length+1):\n rotation = temp[i : i+length]\n if rotation == string:\n return i\n return len(string)", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(s):\n temp = s + s\n n = len(s)\n\n for i in range(1, n+1):\n substring = temp[i:n+i]\n if (s == substring):\n return i\n return n", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(string):\n temp = string + string\n n = len(string)\n \n for i in range(1, n + 1):\n s = temp[i: n + i]\n if s == string:\n return i\n return n", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(s):\n # This is the basic string that we will be trying to rotate\n basic = s\n\n # For counting how many rotations we have made\n count = 0\n\n # We will keep repeating this process until we match the original string\n while True:\n # The first character of the string is removed and placed at the end\n s = s[1:] + s[0]\n\n # Increment the count\n count += 1\n\n # Check if the new string is same as the original\n if s == basic:\n # If yes, return the count of rotations\n return count", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(s: str) -> int:\n n = len(s)\n s2 = s + s\n for i in range(1, n+1):\n if s2[i:i+n] == s:\n return i\n return n", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(s):\n temp = s + s\n n = len(s)\n\n for i in range(1, n + 1):\n substring = temp[i: n + i]\n if substring == s:\n return i\n\n return n", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(s):\n \"\"\"\n Function to find the minimum number of rotations to get back the same string.\n If there is no rotation possible, return -1\n \"\"\"\n double = s + s\n n = len(s)\n\n for i in range(1, n + 1):\n substring = double[i : n + i]\n if (s == substring):\n return i\n\n return -1", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(string):\n # 2-pointer approach\n i = 1\n while i < len(string):\n if string == string[i:] + string[:i]:\n return i\n i += 1\n return len(string)", "matching_cluster_idx": 3}, {"solution": "def find_Rotations(input_string):\n temp = input_string + input_string\n n = len(input_string)\n\n for i in range(1, n + 1):\n substring = temp[i : n + i]\n if (input_string == substring):\n return i\n\n return n", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(s):\n ss = s + s\n n = len(s)\n\n for i in range(1, n+1):\n if ss[i : i+n] == s:\n return i", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(strng):\n # Copy the original string \n temp = strng + strng\n n = len(strng)\n\n for i in range(1, n + 1):\n # Get substring from index i and size n\n substring = temp[i: n + i]\n # If the constructed string is equal to the original string,\n # break the loop\n if (strng == substring):\n break\n\n # Return the number of rotations\n return i", "matching_cluster_idx": 5}]}, "Mbpp/11": {"dps": 85.08960573476702, "dps_norm": 97.77777777777777, "pass@1": 31.0, "profiled": [{"solution": "def remove_Occ(s, char):\n # Check if the character is present in the string\n if char in s:\n # Get the first and last occurrence of the character\n first_occ = s.index(char)\n last_occ = s.rindex(char)\n # Remove first and last occurrences of the character\n s = s[:first_occ] + s[first_occ+1:last_occ] + s[last_occ+1:]\n return s", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(s, c):\n first_occurrence = s.find(c)\n last_occurrence = s.rfind(c)\n\n # If character doesn't exist in string\n if first_occurrence == -1:\n return s\n\n # If the first and last occurrence are same, we return string removing all occurrences of character\n if first_occurrence == last_occurrence:\n return s.replace(c, \"\")\n\n # Remove first and last occurrence of the character\n return s[:first_occurrence] + s[first_occurrence+1:last_occurrence] + s[last_occurrence+1:]", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(string, char):\n first_occurrence = string.find(char)\n last_occurrence = string.rfind(char)\n \n if first_occurrence != -1 and last_occurrence != -1:\n if first_occurrence == last_occurrence:\n return string[:first_occurrence] + string[first_occurrence + 1:]\n else:\n return string[:first_occurrence] + string[first_occurrence + 1:last_occurrence] + string[last_occurrence + 1:]\n else:\n return string", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(s, c):\n first_occurrence = s.find(c)\n last_occurrence = s.rfind(c)\n if first_occurrence != -1 and last_occurrence != -1:\n s = s[:first_occurrence] + s[first_occurrence+1:last_occurrence] + s[last_occurrence+1:]\n return s", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(s, c):\n first_occ = s.find(c)\n if first_occ == -1:\n return s\n last_occ = s.rfind(c)\n if first_occ == last_occ:\n return s[:first_occ] + s[first_occ+1:]\n return s[:first_occ] + s[first_occ+1:last_occ] + s[last_occ+1:]", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(s, ch):\n first = s.find(ch)\n if first == -1:\n return s\n last = s.rfind(ch)\n if first == last:\n return s[:first] + s[first+1:]\n else:\n return s[:first] + s[first+1:last] + s[last+1:]", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(s,c):\n first_occurrence = s.find(c)\n if first_occurrence == -1:\n return s\n last_occurrence = s.rfind(c)\n if first_occurrence == last_occurrence:\n return s[:first_occurrence] + s[first_occurrence+1:]\n else:\n return s[:first_occurrence] + s[first_occurrence+1:last_occurrence] + s[last_occurrence+1:]", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(input_string, char):\n first_occurrence = input_string.find(char)\n if first_occurrence != -1:\n input_string = input_string[:first_occurrence] + input_string[(first_occurrence+1):]\n last_occurrence = input_string.rfind(char)\n if last_occurrence != -1:\n input_string = input_string[:last_occurrence] + input_string[(last_occurrence+1):]\n return input_string", "matching_cluster_idx": 7}, {"solution": "def remove_Occ(s, c):\n first_occurrence = s.find(c)\n if first_occurrence == -1:\n return s\n last_occurrence = s.rfind(c)\n s = s[:first_occurrence] + s[first_occurrence+1:last_occurrence] + s[last_occurrence+1:]\n return s", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(s, c):\n # check if the character is not in string\n if c not in s:\n return s\n else:\n # find the first and last occurrence of character\n first_occur = s.index(c)\n last_occur = s.rindex(c)\n\n # remove first and last occurrence of character\n s_modified = s[:first_occur] + s[first_occur+1:last_occur] + s[last_occur+1:]\n\n return s_modified", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(s, c):\n first_index = s.find(c)\n last_index = s.rfind(c)\n if first_index != -1 and last_index != -1:\n s = s[:first_index] + s[first_index+1:last_index] + s[last_index+1:]\n return s", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(s, c):\n first = s.find(c)\n last = s.rfind(c)\n if first != -1 and last != -1:\n s = s[:first] + s[first+1:last] + s[last+1:]\n return s", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(s, ch):\n first_occ = s.find(ch)\n last_occ = s.rfind(ch)\n \n if first_occ == -1:\n return s\n \n if first_occ == last_occ:\n return s[:first_occ] + s[first_occ+1:]\n else:\n return s[:first_occ] + s[first_occ+1:last_occ] + s[last_occ+1:]", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(word, char):\n # Empty string case\n if not word:\n return word\n\n first_occ = word.find(char)\n if first_occ == -1:\n return word\n\n last_occ = word.rfind(char)\n\n # If only one occurrence, remove it\n if first_occ == last_occ:\n return word[:first_occ] + word[first_occ + 1:]\n\n # If two occurrences\n word_no_first = word[:first_occ] + word[first_occ + 1:]\n word_no_both = word_no_first[:last_occ - 1] + word_no_first[last_occ:]\n return word_no_both", "matching_cluster_idx": 7}, {"solution": "def remove_Occ(input_str, char):\n first_index = input_str.find(char)\n last_index = input_str.rfind(char)\n if first_index == -1 or last_index == -1:\n return input_str # Return string as is if char not found\n else:\n new_str = input_str[:first_index] + input_str[first_index+1:last_index] + input_str[last_index+1:]\n return new_str", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(s, ch):\n first_occ = s.find(ch)\n if first_occ != -1:\n s = s[:first_occ] + s[first_occ+1:]\n last_occ = s.rfind(ch)\n if last_occ != -1:\n s = s[:last_occ] + s[last_occ+1:]\n return s", "matching_cluster_idx": 7}, {"solution": "def remove_Occ(s: str, c: str) -> str:\n first_occ = s.find(c)\n last_occ = s.rfind(c)\n if first_occ == -1: # Character not in string\n return s\n elif first_occ == last_occ: # Only one occurrence of character in string\n return s.replace(c, '', 1)\n else: # More than one occurrence of character in string\n return s[:first_occ] + s[first_occ:last_occ].replace(c, '', 1) + s[last_occ+1:]", "matching_cluster_idx": 7}, {"solution": "def remove_Occ(s, char):\n first_occurrence = s.find(char)\n last_occurrence = s.rfind(char)\n \n if first_occurrence == -1:\n return s\n \n if first_occurrence == last_occurrence:\n return s[:first_occurrence] + s[first_occurrence+1:]\n \n return s[:first_occurrence] + s[first_occurrence+1:last_occurrence] + s[last_occurrence+1:]", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(string: str, char: str) -> str:\n first = string.find(char)\n last = string.rfind(char)\n if first != -1 and last != -1:\n if first == last:\n return string[:first] + string[first+1:]\n else:\n part1 = string[:first]\n part2 = string[first+1:last]\n part3 = string[last+1:]\n return part1 + part2 + part3\n else:\n return string", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(input_str, ch):\n first_ch_pos = input_str.find(ch)\n if first_ch_pos == -1:\n return input_str\n last_ch_pos = input_str.rfind(ch)\n if last_ch_pos == first_ch_pos:\n return input_str[:first_ch_pos] + input_str[first_ch_pos+1:]\n else:\n return input_str[:first_ch_pos] + input_str[first_ch_pos+1:last_ch_pos] + input_str[last_ch_pos+1:]", "matching_cluster_idx": 8}]}, "Mbpp/12": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 98.0, "profiled": [{"solution": "def sort_matrix(matrix):\n \"\"\"\n Function to sort a given matrix in ascending order according to the sum of its rows.\n \"\"\"\n # Calculate the sum of each row\n row_sums = [sum(row) for row in matrix]\n # Zip the row sums and the matrix together, sort by the row sums,\n # and then discard the row sums\n sorted_matrix = [row for _, row in sorted(zip(row_sums, matrix))]\n return sorted_matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Sort the matrix based on the sum of its rows\n matrix.sort(key=sum)\n return matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"Sorts a matrix in ascending order according to the sum of its rows.\"\"\"\n return sorted(matrix, key=sum)", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n return sorted(matrix, key=sum)", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"\n Sort a matrix in ascending order according to the sum of its rows.\n \n Parameters:\n matrix (list of lists): The matrix to be sorted.\n \n Returns:\n list of lists: The sorted matrix.\n \"\"\"\n return sorted(matrix, key=sum)", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n return sorted(matrix, key=sum)", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Calculate the sum of each row and store it in a tuple with the row\n sum_matrix = [(sum(row), row) for row in matrix]\n \n # Sort the list of tuples based on the sum of rows\n sum_matrix.sort()\n \n # Extract the sorted rows from the sorted tuples\n sorted_matrix = [row for _, row in sum_matrix]\n \n return sorted_matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n return sorted(matrix, key=sum)", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Sorting the matrix according to the sum of its rows\n matrix.sort(key=sum)\n return matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Function to compute sum of each row\n def sum_row(row):\n return sum(row)\n\n # Sorting matrix based on sum of rows in ascending order\n sorted_matrix = sorted(matrix, key=sum_row)\n \n return sorted_matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n return sorted(matrix, key=sum)", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"\n Sort a given matrix in ascending order according to the sum of its rows.\n \"\"\"\n matrix.sort(key=sum)\n return matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n matrix.sort(key=sum)\n return matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n return sorted(matrix, key=sum)", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n return sorted(matrix, key=sum)", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"\n Function to sort a given matrix in ascending order according to the sum of its rows.\n \"\"\"\n # Calculate the sum of each row\n row_sums = [sum(row) for row in matrix]\n \n # Create a list of tuples where the first element is the sum and the second is the original row\n row_sums_matrix = list(zip(row_sums, matrix))\n \n # Sort the list of tuples based on the sum\n sorted_row_sums_matrix = sorted(row_sums_matrix)\n \n # Extract the sorted matrix\n sorted_matrix = [row for _, row in sorted_row_sums_matrix]\n \n return sorted_matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n return sorted(matrix, key=sum)", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"Sort the matrix by the sum of its rows.\"\"\"\n return sorted(matrix, key=sum)", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n return sorted(matrix, key=sum)", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n return sorted(matrix, key=sum)\nmatrix = [[1, 2, 3], [2, 4, 5], [1, 1, 1]]", "matching_cluster_idx": 15}]}, "Mbpp/16": {"dps": 89.0548780487805, "dps_norm": 92.5, "pass@1": 48.0, "profiled": [{"solution": "import re\ndef text_lowercase_underscore(s):\n pattern = r\"^[a-z]+(_[a-z]+)*$\"\n match = re.fullmatch(pattern, s)\n return match is not None", "matching_cluster_idx": 7}, {"solution": "def text_lowercase_underscore(input_string):\n # Split the input string by underscore\n sequences = input_string.split(\"_\")\n # Check each sequence\n for sequence in sequences:\n # If the sequence contains characters other than lowercase letters, return False\n if not sequence.islower():\n return False\n # If all sequences pass the check, return True\n return True", "matching_cluster_idx": 5}, {"solution": "import re\ndef text_lowercase_underscore(input_string):\n pattern = r'^[a-z]+(_[a-z]+)*$'\n return bool(re.match(pattern, input_string))", "matching_cluster_idx": 7}, {"solution": "import re\ndef text_lowercase_underscore(s):\n \"\"\"\n Returns true if the input string contains sequences of lowercase letters joined with an underscore and false otherwise.\n \"\"\"\n pattern = '^[a-z]+(_[a-z]+)*$'\n return bool(re.fullmatch(pattern, s))", "matching_cluster_idx": 7}, {"solution": "import re\ndef text_lowercase_underscore(input_string):\n \"\"\"\n A function to check if the input string contains sequences of lowercase letters joined with an underscore.\n\n :param input_string: string - input string to be checked\n :return: bool - True if the input string contains sequences of lowercase letters joined with an underscore, False otherwise\n \"\"\"\n return bool(re.match('^[a-z]+(?:_[a-z]+)*$', input_string))", "matching_cluster_idx": 7}, {"solution": "import re\ndef text_lowercase_underscore(text):\n \"\"\"\n Function to check if the input string contains sequences of lowercase letters joined with an underscore\n\n Parameters:\n text (str): The string to be checked\n\n Returns:\n bool: True if the input string contains sequences of lowercase letters joined with an underscore, False otherwise\n \"\"\"\n return bool(re.search(r\"^[a-z]+(?:_[a-z]+)*$\", text))", "matching_cluster_idx": 3}, {"solution": "import re\ndef text_lowercase_underscore(input_string):\n \"\"\"\n This function checks if the input_string contains sequences of lowercase letters joined with an underscore.\n \n :param input_string: The string to check.\n :type input_string: str\n :return: True if the string contains sequences of lowercase letters joined with an underscore; False otherwise.\n :rtype: bool\n \"\"\"\n return bool(re.match('^[a-z]+(?:_[a-z]+)*$', input_string))", "matching_cluster_idx": 7}, {"solution": "import re\ndef text_lowercase_underscore(s):\n pattern = r\"^[a-z]+(_[a-z]+)*$\"\n return bool(re.match(pattern, s))", "matching_cluster_idx": 7}, {"solution": "def text_lowercase_underscore(s):\n parts = s.split('_')\n for part in parts:\n if not part.islower():\n return False\n return True", "matching_cluster_idx": 5}, {"solution": "import re\ndef text_lowercase_underscore(s):\n return bool(re.fullmatch(r'[a-z]+(?:_[a-z]+)*', s))", "matching_cluster_idx": 7}, {"solution": "import re\ndef text_lowercase_underscore(s):\n return bool(re.fullmatch(r'[a-z]+(?:_[a-z]+)*', s))", "matching_cluster_idx": 7}, {"solution": "import re\ndef text_lowercase_underscore(text):\n # Use regular expression to check if the string contains lowercase letters joined with an underscore\n pattern = r'^[a-z]+(_[a-z]+)*$'\n if re.match(pattern, text):\n return True\n else:\n return False", "matching_cluster_idx": 7}, {"solution": "def text_lowercase_underscore(s: str) -> bool:\n words = s.split('_')\n for word in words:\n if not word.islower() or not word.isalpha():\n return False\n return True", "matching_cluster_idx": 5}, {"solution": "import re\ndef text_lowercase_underscore(s):\n \"\"\"\n Function to check if the input string contains sequences of lowercase letters joined with an underscore\n \"\"\"\n pattern = '[a-z]+(_[a-z]+)*'\n return re.fullmatch(pattern, s) is not None", "matching_cluster_idx": 7}, {"solution": "import re\ndef text_lowercase_underscore(s):\n # Searches for sequences of lowercase letters joined with an underscore\n pattern = re.compile(r'^[a-z]+(_[a-z]+)*$')\n\n # Returns True if the pattern is found, False otherwise\n return bool(pattern.match(s))", "matching_cluster_idx": 7}, {"solution": "def text_lowercase_underscore(input_str):\n sequence = input_str.split('_')\n for seq in sequence:\n if not seq.islower() or not seq.isalpha():\n return False\n return True", "matching_cluster_idx": 5}, {"solution": "import re\ndef text_lowercase_underscore(input_str):\n \"\"\"\n Returns true if the input string contains sequences of lowercase letters joined with an underscore and false otherwise.\n \"\"\"\n pattern = r'^[a-z]+(_[a-z]+)*$'\n return bool(re.fullmatch(pattern, input_str))", "matching_cluster_idx": 7}, {"solution": "import re\ndef text_lowercase_underscore(s):\n \"\"\"\n Check if the input string contains sequences of lowercase letters joined with an underscore.\n \"\"\"\n pattern = '[a-z]+(_[a-z]+)*'\n return re.fullmatch(pattern, s) is not None", "matching_cluster_idx": 7}, {"solution": "import re\ndef text_lowercase_underscore(input_string):\n pattern = r\"^[a-z]+(_[a-z]+)*$\"\n return bool(re.match(pattern, input_string))", "matching_cluster_idx": 7}, {"solution": "import re\ndef text_lowercase_underscore(text):\n pattern = re.compile(r'[a-z]+(_[a-z]+)*')\n return pattern.fullmatch(text) is not None", "matching_cluster_idx": 7}]}, "Mbpp/19": {"dps": 62.601010101010104, "dps_norm": 80.33333333333333, "pass@1": 88.0, "profiled": [{"solution": "def test_duplicate(array):\n \"\"\"\n Function to find whether a given array of integers contains any duplicate element.\n \"\"\"\n # Check if array is None or empty\n if array is None or len(array) == 0:\n return False\n\n # Initialize empty set for tracking duplicates\n num_set = set()\n\n # Iterate through array elements\n for num in array:\n # If element is already in set, return True\n if num in num_set:\n return True\n # Otherwise, add element to set\n num_set.add(num)\n\n # If no duplicates were found, return False\n return False", "matching_cluster_idx": 13}, {"solution": "def has_duplicate(arr):\n return len(arr) != len(set(arr))\ndef test_duplicate(arr):\n return has_duplicate(arr)", "matching_cluster_idx": 10}, {"solution": "def test_duplicate(arr):\n \"\"\"\n This function checks if the array contains any duplicate elements.\n \"\"\"\n return len(arr) != len(set(arr))", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(nums):\n if len(nums) == len(set(nums)):\n return False\n else:\n return True", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(arr):\n \"\"\"\n This function checks whether a given array of integers contains any duplicate element.\n \"\"\"\n # use set to check for duplicates\n if len(arr) == len(set(arr)):\n return False\n else:\n return True", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(nums):\n \"\"\"\n Function to check if there are any duplicate elements in an integer array\n \"\"\"\n # convert the list to a set and compare the lengths.\n # set removes duplicates, so if lengths are different, there must have been duplicates.\n return len(nums) != len(set(nums))", "matching_cluster_idx": 11}, {"solution": "def has_duplicate(nums):\n return len(nums) != len(set(nums))\ndef test_duplicate(nums):\n return has_duplicate(nums)", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(nums):\n return len(nums) != len(set(nums))", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(arr):\n \"\"\"\n Function to find whether a given array of integers contains any duplicate element.\n :param arr: List[int]\n :return: bool\n \"\"\"\n return len(arr) != len(set(arr))", "matching_cluster_idx": 11}, {"solution": "def contains_duplicate(nums):\n \"\"\"\n :type nums: List[int]\n :rtype: bool\n \"\"\"\n return len(nums) != len(set(nums))\ndef test_duplicate(nums):\n \"\"\"\n :type nums: List[int]\n :rtype: bool\n \"\"\"\n return contains_duplicate(nums)", "matching_cluster_idx": 11}, {"solution": "def has_duplicates(lst):\n \"\"\"\n Function to find whether a given array of integers contains any duplicate element.\n \"\"\"\n return len(lst) != len(set(lst))\ndef test_duplicate(lst):\n \"\"\"\n Function to test the has_duplicates function.\n \"\"\"\n return has_duplicates(lst)", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(array):\n \"\"\"\n Checks whether the given array contains any duplicate element.\n \"\"\"\n # Create a set from the input array\n # Set only contains unique elements, so duplicates will be removed\n set_array = set(array)\n\n # If the length of the set is not equal to the length of the array,\n # then there were duplicates in the array\n if len(set_array) != len(array):\n return True\n else:\n return False", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(nums):\n \"\"\"\n A function to check whether a given array of integers contains any duplicate element.\n \"\"\"\n if len(nums) == len(set(nums)):\n return False\n else:\n return True", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(arr):\n \"\"\"\n Function to find whether a given array of integers contains any duplicate element.\n \"\"\"\n return len(arr) != len(set(arr))", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(arr):\n \"\"\"\n A function to find whether a given array of integers contains any duplicate element.\n \"\"\"\n # using set for duplicate checking. If size of set is less than array size means there are duplicates.\n return len(arr) != len(set(arr))", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(arr):\n \"\"\"\n Function to find whether a given array of integers contains any duplicate element.\n \"\"\"\n return len(arr) != len(set(arr))", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(nums):\n \"\"\"Function to find whether a given array of integers contains any duplicate element\"\"\"\n return len(nums) != len(set(nums))", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(numbers):\n return len(numbers) != len(set(numbers))", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(nums):\n \"\"\"\n Test whether a given array of integers contains any duplicate element.\n \n Parameters:\n nums (List[int]): A list of integers.\n \n Returns:\n bool: True if there is any duplicate element, False otherwise.\n \"\"\"\n return len(nums) != len(set(nums))", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(input_array):\n \"\"\"Function to check if given array contains any duplicate element\"\"\"\n if len(input_array) == len(set(input_array)):\n return False\n else:\n return True", "matching_cluster_idx": 11}]}, "Mbpp/62": {"dps": 92.5, "dps_norm": 95.0, "pass@1": 100.0, "profiled": [{"solution": "def smallest_num(numbers):\n \"\"\"\n Find smallest number in a list.\n :type numbers: List[int]\n :rtype: int\n \"\"\"\n return min(numbers)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(numbers):\n return min(numbers)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(numbers):\n \"\"\"\n This function returns the smallest number in a list.\n \"\"\"\n # The built-in Python function min() returns the smallest item in a iterable.\n return min(numbers)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(num_list):\n return min(num_list)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(numbers):\n return min(numbers)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(num_list):\n \"\"\"\n A function to find the smallest number in a list.\n \"\"\"\n return min(num_list)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(lst):\n \"\"\"\n Finds the smallest number in a list.\n\n :param lst: a list of integers\n :returns: the smallest number in the list\n \"\"\"\n # Setting initial smallest number as first number in the list\n smallest = lst[0]\n \n # Iterating through each number in the list\n for num in lst:\n # If current number is smaller than smallest\n if num < smallest:\n # Set current number as smallest\n smallest = num\n return smallest", "matching_cluster_idx": 3}, {"solution": "def smallest_num(numbers):\n return min(numbers)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(numbers):\n return min(numbers)\nnumbers = [10, 20, 1, 45, 99]", "matching_cluster_idx": 4}, {"solution": "def smallest_num(numbers):\n \"\"\"\n Finds the smallest number in a list.\n \"\"\"\n return min(numbers)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(numbers):\n return min(numbers)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(lst):\n \"\"\"Function to find smallest number in a list\"\"\"\n # Check if the list is not empty\n if len(lst) == 0:\n return None\n else:\n smallest = lst[0] # Initialize smallest with the first element\n for num in lst:\n if num < smallest:\n smallest = num\n return smallest", "matching_cluster_idx": 3}, {"solution": "def smallest_num(numbers):\n \"\"\"\n Return the smallest number in a list\n :param numbers: list of numbers\n :return: smallest number\n \"\"\"\n return min(numbers)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(lst):\n \"\"\"Return the smallest number in the given list.\"\"\"\n smallest = lst[0]\n for num in lst:\n if num < smallest:\n smallest = num\n return smallest", "matching_cluster_idx": 3}, {"solution": "def smallest_num(numbers):\n return min(numbers)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(nums):\n \"\"\"Find smallest number in a list.\"\"\"\n smallest = nums[0]\n for num in nums:\n if num < smallest:\n smallest = num\n return smallest", "matching_cluster_idx": 3}, {"solution": "def smallest_num(nums):\n \"\"\"Returns the smallest number in a list.\"\"\"\n return min(nums)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(lst):\n \"\"\"Returns the smallest number in a list.\"\"\"\n return min(lst)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(lst):\n \"\"\"\n This function finds the smallest number in a list.\n \"\"\"\n # Initialize the smallest number as the first number in the list\n smallest = lst[0]\n\n # Iterate over the list\n for num in lst:\n # If a number is smaller than the current smallest number, update the smallest number\n if num < smallest:\n smallest = num\n\n # Return the smallest number\n return smallest", "matching_cluster_idx": 3}, {"solution": "def smallest_num(num_list):\n \"\"\"Find smallest number in a list.\"\"\"\n return min(num_list)", "matching_cluster_idx": 4}]}, "Mbpp/75": {"dps": 88.53571428571429, "dps_norm": 65.55555555555556, "pass@1": 100.0, "profiled": [{"solution": "def find_tuples(list_of_tuples, k):\n \"\"\"\n Function to find tuples which have all elements divisible by k from the given list of tuples.\n \"\"\"\n return [t for t in list_of_tuples if all(i % k == 0 for i in t)]", "matching_cluster_idx": 5}, {"solution": "def find_tuples(input_tuples, k):\n \"\"\"\n This function finds tuples that have all elements divisible by k from a list of tuples.\n \"\"\"\n result = []\n for tpl in input_tuples:\n if all(map(lambda x: x % k == 0, tpl)):\n result.append(tpl)\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n \"\"\"\n Find tuples which have all elements divisible by k.\n \n Args:\n tuples_list: list of tuples.\n k: integer value.\n \n Returns:\n List of tuples which have all elements divisible by k.\n \"\"\"\n # Filter the list using the condition that all elements of the tuple are divisible by k\n result = [t for t in tuples_list if all(e % k == 0 for e in t)]\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples, k):\n \"\"\"\n Finds tuples where all elements are divisible by k.\n\n :param tuples: A list of tuples of integers.\n :param k: An integer.\n :return: A list of tuples where all elements are divisible by k.\n \"\"\"\n # List to store the tuples where all elements are divisible by k\n divisible_tuples = []\n\n # Check each tuple in the list\n for t in tuples:\n # If all elements of the tuple are divisible by k, add the tuple to the list\n if all(el % k == 0 for el in t):\n divisible_tuples.append(t)\n\n # Return the list of tuples\n return divisible_tuples", "matching_cluster_idx": 5}, {"solution": "def find_tuples(list_of_tuples, k):\n # list of result tuples\n res = []\n # iterate through list of tuples\n for tup in list_of_tuples:\n # check if all elements are divisible by k\n if all([el % k == 0 for el in tup]):\n res.append(tup)\n return res", "matching_cluster_idx": 2}, {"solution": "def find_tuples(lst, k):\n result = []\n for t in lst:\n if all(map(lambda x: x % k == 0, t)):\n result.append(t)\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n return [t for t in tuples_list if all(i % k == 0 for i in t)]", "matching_cluster_idx": 5}, {"solution": "def find_tuples(input_list, k):\n return [t for t in input_list if all(i % k == 0 for i in t)]", "matching_cluster_idx": 5}, {"solution": "def find_tuples(list_of_tuples, k):\n # Create an empty list to store the result\n result = []\n \n # Iterate over all tuples in the list\n for tpl in list_of_tuples:\n # Check if all elements in the tuple are divisible by k\n if all(x % k == 0 for x in tpl):\n # If so, append it to the result list\n result.append(tpl)\n \n # Return the final result\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(lst, k):\n \"\"\"Find tuples in the list which all elements are divisible by k.\"\"\"\n result = []\n for t in lst:\n if all(x % k == 0 for x in t):\n result.append(t)\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(lst, k):\n return [t for t in lst if all(i % k == 0 for i in t)]", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n return [t for t in tuples_list if all(i % k == 0 for i in t)]\ntuples_list = [(6, 24, 12), (7, 9, 6), (12, 18, 21)]\nk = 6", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuple_list, k):\n return [t for t in tuple_list if all(i % k == 0 for i in t)]", "matching_cluster_idx": 5}, {"solution": "def find_tuples(list_of_tuples, k):\n result = []\n for tup in list_of_tuples:\n if all(e % k == 0 for e in tup):\n result.append(tup)\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n return [t for t in tuples_list if all(el % k == 0 for el in t)]", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n result = []\n for tup in tuples_list:\n if all(el % k == 0 for el in tup):\n result.append(tup)\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples, k):\n def divisible(n):\n return all(n % k == 0 for n in n)\n return [n for n in tuples if divisible(n)]", "matching_cluster_idx": 5}, {"solution": "def find_tuples(list_of_tuples, k):\n \"\"\"\n A function to find tuples which have all elements divisible by k from the given list of tuples.\n\n :param list_of_tuples: List of tuples\n :param k: Integer\n :return: List of tuples where all elements are divisible by k\n \"\"\"\n result = []\n for t in list_of_tuples:\n if all(e % k == 0 for e in t):\n result.append(t)\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(lst, k):\n def is_divisible(n):\n return n % k == 0\n return [t for t in lst if all(map(is_divisible, t))]", "matching_cluster_idx": 6}, {"solution": "def find_tuples(lst, k):\n \"\"\"Return a list of tuples in 'lst' where all elements are divisible by 'k'.\"\"\"\n return [t for t in lst if all(x % k == 0 for x in t)]", "matching_cluster_idx": 5}]}, "Mbpp/88": {"dps": 96.56862745098039, "dps_norm": 85.71428571428571, "pass@1": 100.0, "profiled": [{"solution": "def freq_count(elements):\n freq_dict = {}\n for element in elements:\n if element in freq_dict:\n freq_dict[element] += 1\n else:\n freq_dict[element] = 1\n return freq_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n # Create a dictionary to store the frequency of each element\n freq_dict = {}\n\n # Iterate over the list\n for item in lst:\n # If the element is already in the dictionary, increment its count\n if item in freq_dict:\n freq_dict[item] += 1\n # If the element is not in the dictionary, add it with a count of 1\n else:\n freq_dict[item] = 1\n \n # Return the frequency dictionary\n return freq_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n frequency_dict = {}\n for item in lst:\n if item in frequency_dict:\n frequency_dict[item] += 1\n else:\n frequency_dict[item] = 1\n return frequency_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(arr):\n freq_dict = {}\n for item in arr:\n if (item in freq_dict):\n freq_dict[item] += 1\n else:\n freq_dict[item] = 1\n return freq_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(input_list):\n freq_dict = {}\n for item in input_list:\n if item in freq_dict:\n freq_dict[item] += 1\n else:\n freq_dict[item] = 1\n return freq_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n dict_count = {}\n for num in lst:\n if num in dict_count:\n dict_count[num] += 1\n else:\n dict_count[num] = 1\n return dict_count", "matching_cluster_idx": 5}, {"solution": "def freq_count(input_list):\n \"\"\"\n This function takes a list as input and returns a dictionary with the frequency count of each element in the list.\n \"\"\"\n # Create an empty dictionary\n freq_dict = {}\n\n # Iterate over the list\n for i in input_list:\n # If the element is already in the dictionary, increment its count by 1\n if i in freq_dict:\n freq_dict[i] += 1\n # If the element is not in the dictionary, add it with a count of 1\n else:\n freq_dict[i] = 1\n\n # Return the dictionary\n return freq_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(num_list):\n freq_dict = {}\n for i in num_list:\n if i in freq_dict:\n freq_dict[i] += 1\n else:\n freq_dict[i] = 1\n return freq_dict\nnum_list = [10,10,10,10,20,20,20,20,40,40,50,50,30]", "matching_cluster_idx": 5}, {"solution": "def freq_count(arr):\n freq_dict = {}\n for i in arr:\n if i in freq_dict:\n freq_dict[i] += 1\n else:\n freq_dict[i] = 1\n return freq_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n freq = {}\n for item in lst:\n if item in freq:\n freq[item] += 1\n else:\n freq[item] = 1\n return freq", "matching_cluster_idx": 5}, {"solution": "def freq_count(input_list):\n \"\"\"\n Write a function to get the frequency of all the elements in a list, returned as a dictionary.\n \"\"\"\n frequency_dict = {}\n for element in input_list:\n if element in frequency_dict:\n frequency_dict[element] += 1\n else:\n frequency_dict[element] = 1\n return frequency_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n freq_dict = {}\n for item in lst:\n if item in freq_dict:\n freq_dict[item] += 1\n else:\n freq_dict[item] = 1\n return freq_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(input_list):\n frequency = {}\n for item in input_list:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n return frequency", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n \"\"\"\n Function to get the frequency of all the elements in a list,\n returned as a dictionary.\n \"\"\"\n freq = {}\n for item in lst:\n if item in freq:\n freq[item] += 1\n else:\n freq[item] = 1\n return freq", "matching_cluster_idx": 5}, {"solution": "def freq_count(input_list):\n count_dict = {}\n for i in input_list:\n if i in count_dict:\n count_dict[i] += 1\n else:\n count_dict[i] = 1\n return count_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n freq_dict = {}\n for i in lst:\n if i in freq_dict:\n freq_dict[i] += 1\n else:\n freq_dict[i] = 1\n return freq_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(arr):\n freq_dict = {}\n for item in arr:\n if item in freq_dict:\n freq_dict[item] += 1\n else:\n freq_dict[item] = 1\n return freq_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(num_list):\n count_dict = {}\n for i in num_list:\n if i in count_dict:\n count_dict[i] += 1\n else:\n count_dict[i] = 1\n return count_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n freq_dict = {}\n for item in lst:\n if (item in freq_dict):\n freq_dict[item] += 1\n else:\n freq_dict[item] = 1\n return freq_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n freq_dict = {}\n for item in lst:\n if item in freq_dict:\n freq_dict[item] += 1\n else:\n freq_dict[item] = 1\n return freq_dict", "matching_cluster_idx": 5}]}, "Mbpp/90": {"dps": 76.65853658536585, "dps_norm": 84.28571428571428, "pass@1": 100.0, "profiled": [{"solution": "def len_log(lst):\n return max(len(word) for word in lst)", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n return max(len(word) for word in words)", "matching_cluster_idx": 5}, {"solution": "def len_log(input_list):\n max_len = 0\n for i in input_list:\n if len(i) > max_len:\n max_len = len(i)\n return max_len", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n \"\"\"\n Function to find the length of the longest word in a list.\n :param words: List of strings.\n :return: Length of the longest word in the list.\n \"\"\"\n return max(len(word) for word in words)", "matching_cluster_idx": 5}, {"solution": "def len_log(word_list):\n \"\"\"\n Function to find the length of the longest word in a list of words.\n \"\"\"\n # Initialize the maximum length variable to 0\n max_len = 0\n # Loop through each word in the list\n for word in word_list:\n # Check the length of the current word and update max_len if necessary\n if len(word) > max_len:\n max_len = len(word)\n # Return the maximum length\n return max_len", "matching_cluster_idx": 5}, {"solution": "def len_log(lst):\n \"\"\"\n Finds the length of the longest word\n \"\"\"\n return max(len(word) for word in lst)", "matching_cluster_idx": 5}, {"solution": "def len_log(word_list):\n return max([len(word) for word in word_list])", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n # Assert that the input is a list\n assert isinstance(words, list), 'Input should be a list of words'\n # Map the length function over the list and find the max\n lengths = list(map(len, words))\n return max(lengths)", "matching_cluster_idx": 5}, {"solution": "def len_log(word_list):\n return max(len(word) for word in word_list)", "matching_cluster_idx": 5}, {"solution": "def len_log(word_list):\n return max(len(word) for word in word_list)", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n return max(len(word) for word in words)", "matching_cluster_idx": 5}, {"solution": "def len_log(lst):\n return max(len(word) for word in lst)", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n max_length = 0\n for word in words:\n max_length = max(max_length, len(word))\n return max_length", "matching_cluster_idx": 2}, {"solution": "def len_log(words):\n \"\"\"\n Function to find the length of the longest word\n \"\"\"\n return max(len(word) for word in words)", "matching_cluster_idx": 5}, {"solution": "def len_log(word_list):\n max_len = 0\n for word in word_list:\n if len(word) > max_len:\n max_len = len(word)\n return max_len", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n \"\"\"\n Find the length of the longest word.\n \"\"\"\n return max(len(word) for word in words)", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n \"\"\"\n Find the length of the longest word.\n \"\"\"\n return max(len(word) for word in words)", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n \"\"\"\n Function to find the length of the longest word.\n \"\"\"\n return len(max(words, key=len))", "matching_cluster_idx": 6}, {"solution": "def len_log(words):\n \"\"\"\n This function returns the length of the longest word from a list of words.\n \"\"\"\n return max(len(word) for word in words)", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n \"\"\"\n A function to find the length of the longest word\n \"\"\"\n return max(len(word) for word in words)", "matching_cluster_idx": 5}]}, "Mbpp/94": {"dps": 78.8719512195122, "dps_norm": 62.0, "pass@1": 96.0, "profiled": [{"solution": "def index_minimum(lst):\n return min(lst, key = lambda x: x[1])[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(lst):\n return min(lst, key=lambda x: x[1])[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(lst):\n # returning the first value of the tuple with the smallest second value\n return min(lst, key=lambda x: x[1])[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(list_tuples):\n return min(list_tuples, key=lambda x:x[1])[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(lst):\n \"\"\"\n Function to return the first value of the tuple with the smallest second value.\n \"\"\"\n # Check if list is empty\n if not lst:\n return None\n\n # Initialize minimum value with first element of list\n min_value = lst[0][1]\n min_index = 0\n\n # Iterate over list to find the minimum\n for i in range(1, len(lst)):\n if lst[i][1] < min_value:\n min_value = lst[i][1]\n min_index = i\n\n # Return the first value of tuple with smallest second value\n return lst[min_index][0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(lst):\n \"\"\"\n Given a list of tuples, returns the first value of the tuple with the smallest second value.\n \"\"\"\n return min(lst, key = lambda x: x[1])[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(list_of_tuples):\n # Return the first element of the tuple with the smallest second value.\n return min(list_of_tuples, key = lambda x: x[1])[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(lst):\n min_tuple = min(lst, key=lambda x: x[1])\n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(input_list):\n \"\"\"\n Function to find the first value of the tuple with the smallest second value.\n \"\"\"\n # Check if list is not empty\n if len(input_list) == 0:\n return None\n\n min_value = input_list[0][1]\n min_index = 0\n\n # Iterate over list and find the smallest second value\n for i in range(1, len(input_list)):\n if input_list[i][1] < min_value:\n min_value = input_list[i][1]\n min_index = i\n\n # Return the first value of the tuple with the smallest second value\n return input_list[min_index][0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(list_of_tuples):\n \"\"\"\n Given a list of tuples, this function returns the first value of the tuple with the smallest second value.\n \"\"\"\n\n # Check if the list is not empty\n if not list_of_tuples:\n raise ValueError(\"The list is empty\")\n\n # Initialize with the first tuple\n min_tuple = list_of_tuples[0]\n\n # Go through each tuple in the list\n for tup in list_of_tuples:\n # If the second value of this tuple is smaller than the second value of min_tuple\n if tup[1] < min_tuple[1]:\n # Update min_tuple\n min_tuple = tup\n\n # Return the first value of the tuple with the smallest second value\n return min_tuple[0]", "matching_cluster_idx": 3}, {"solution": "def index_minimum(lst):\n return min(lst, key=lambda x: x[1])[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(tuples_list):\n return min(tuples_list, key=lambda x: x[1])[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(lst):\n # Check if the list is empty\n if not lst:\n return None\n\n # Initialize the minimum value and the index\n min_value = lst[0][1]\n min_index = 0\n\n # Loop through the list to find the minimum value\n for i in range(1, len(lst)):\n if lst[i][1] < min_value:\n min_value = lst[i][1]\n min_index = i\n\n # Return the first value of the tuple with the smallest second value\n return lst[min_index][0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(lst):\n # Sort the list of tuples based on second item in each tuple\n lst.sort(key = lambda x: x[1])\n # Return the first value (index 0) of the first tuple in the list\n return lst[0][0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(input_list):\n # Edge case\n if len(input_list) == 0:\n return None\n\n # Assume the first tuple has the smallest second value.\n smallest_tuple = input_list[0]\n \n # Compare all tuples to find the tuple with the smallest second value.\n for t in input_list:\n if t[1] < smallest_tuple[1]:\n smallest_tuple = t\n\n # Return the first element (name) of the smallest tuple.\n return smallest_tuple[0]\ninput_list = [('Rash', 143), ('Manjeet', 200), ('Varsha', 100)]", "matching_cluster_idx": 3}, {"solution": "def index_minimum(tuples_list):\n # Find the smallest second value and return the first value corresponding to that smallest second value\n min_tuple = min(tuples_list, key=lambda x: x[1])\n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(list_of_tuples):\n return min(list_of_tuples, key = lambda x: x[1])[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(lst):\n return min(lst, key=lambda x: x[1])[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(lst):\n return min(lst, key = lambda x: x[1])[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(lst):\n \"\"\"Returns the first value of the tuple with the smallest second value.\"\"\"\n # Assume the first tuple has the smallest second value\n min_val = lst[0][1]\n min_index = 0\n\n # Traverse the list and check for smallest second value\n for i in range(1, len(lst)):\n if lst[i][1] < min_val:\n min_val = lst[i][1]\n min_index = i\n\n return lst[min_index][0]", "matching_cluster_idx": 2}]}, "Mbpp/96": {"dps": 76.18055555555554, "dps_norm": 47.14285714285714, "pass@1": 80.0, "profiled": [{"solution": "def divisor(n):\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n \"\"\"\n Function to find the number of divisors of a given integer.\n \"\"\"\n count = 0\n for i in range(1, n+1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n i = 1\n count = 0\n while i <= n:\n if n % i == 0:\n count += 1\n i += 1\n return count", "matching_cluster_idx": 0}, {"solution": "def divisor(num):\n count = 0\n for i in range(1, num + 1):\n if num % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n \"\"\"\n This function takes an integer n and returns the number of divisors of n.\n \"\"\"\n count = 0\n for i in range(1, n+1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n count = 0\n for i in range(1, n+1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n \"\"\"\n This function takes an integer n and returns the number of divisors of n.\n \"\"\"\n # Initialize count of divisors to 0\n count = 0\n\n # Loop through all numbers up to n and increment count if i divides n\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n count = 0\n for i in range(1, int(n ** 0.5) + 1):\n if n % i == 0:\n if n / i == i:\n count += 1\n else:\n count += 2\n return count", "matching_cluster_idx": 6}, {"solution": "def divisor(n):\n \"\"\"\n Function to find the number of divisors of a given integer\n\n :param n: an integer\n :return: the number of divisors of the integer\n \"\"\"\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n \"\"\"Find the number of divisors of a given integer.\n \n Args:\n n (int): The number whose divisors we want to find.\n\n Returns:\n int: The number of divisors.\n \"\"\"\n assert n > 0, \"n should be greater than 0\"\n count = 0\n for i in range(1, n+1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n divisors = 0\n for i in range(1, int(n**0.5)+1):\n if n % i == 0:\n if n / i == i:\n divisors += 1\n else:\n divisors += 2\n return divisors", "matching_cluster_idx": 6}, {"solution": "def divisor(n):\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n \"\"\"\n This function takes an integer as input and returns the number of divisors of the integer.\n \"\"\"\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}]}, "Mbpp/97": {"dps": 76.73504273504274, "dps_norm": 74.375, "pass@1": 99.0, "profiled": [{"solution": "from typing import List, Dict\ndef flatten_list(lst: List[List[int]]) -> List[int]:\n \"\"\"Flattens a list of lists into a single list.\"\"\"\n return [item for sublist in lst for item in sublist]\ndef frequency_elements(lst: List[int]) -> Dict[int, int]:\n \"\"\"Counts the frequency of each element in a list.\"\"\"\n freq_dict = {}\n for item in lst:\n if item in freq_dict:\n freq_dict[item] += 1\n else:\n freq_dict[item] = 1\n return freq_dict\ndef frequency_lists(lst: List[List[int]]) -> Dict[int, int]:\n \"\"\"Counts the frequency of each element in a flattened list of lists.\"\"\"\n flattened_list = flatten_list(lst)\n return frequency_elements(flattened_list)", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lst):\n freq = {}\n for sublist in lst:\n for item in sublist:\n if item not in freq:\n freq[item] = 1\n else:\n freq[item] += 1\n return freq", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(nested_list):\n flattened_list = [element for sublist in nested_list for element in sublist]\n frequency_dict = {}\n for element in flattened_list:\n if element in frequency_dict:\n frequency_dict[element] += 1\n else:\n frequency_dict[element] = 1\n return frequency_dict", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(input_list):\n flattened_list = [item for sublist in input_list for item in sublist]\n freq_dict = {}\n for item in flattened_list:\n if item in freq_dict:\n freq_dict[item] += 1\n else:\n freq_dict[item] = 1\n return freq_dict", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lst):\n freq_dict = {}\n for sublist in lst:\n for item in sublist:\n if item in freq_dict:\n freq_dict[item] += 1\n else:\n freq_dict[item] = 1\n return freq_dict", "matching_cluster_idx": 6}, {"solution": "from collections import Counter\nfrom typing import List\ndef flatten(input_list: List[List[int]]) -> List[int]:\n \"\"\"\n Function to flatten a list of lists\n \"\"\"\n return [item for sublist in input_list for item in sublist]\ndef frequency_lists(input_list: List[List[int]]) -> dict:\n \"\"\"\n Function to find frequency of each element in a flattened list of lists\n \"\"\"\n flattened = flatten(input_list)\n return dict(Counter(flattened))", "matching_cluster_idx": 6}, {"solution": "def flatten_lists(lst):\n return [item for sublist in lst for item in sublist]\ndef frequency_lists(lst):\n flattened = flatten_lists(lst)\n return {i: flattened.count(i) for i in set(flattened)}", "matching_cluster_idx": 2}, {"solution": "def flatten_list(lst):\n result = []\n for sublist in lst:\n for item in sublist:\n result.append(item)\n return result\ndef frequency_lists(lst):\n flat_list = flatten_list(lst)\n frequency_dict = {}\n for item in flat_list:\n if item in frequency_dict:\n frequency_dict[item] += 1\n else:\n frequency_dict[item] = 1\n return frequency_dict", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(nested_list):\n frequency_dict = {}\n for sublist in nested_list:\n for item in sublist:\n if item not in frequency_dict:\n frequency_dict[item] = 1\n else:\n frequency_dict[item] += 1\n return frequency_dict", "matching_cluster_idx": 6}, {"solution": "from typing import List, Dict, Union\ndef frequency_lists(list_of_lists: List[List[Union[int, float, str]]]) -> Dict[Union[int, float, str], int]:\n # Flatten the list of lists\n flattened_list = [item for sublist in list_of_lists for item in sublist]\n # Find the frequency of each element\n frequency_dict = {i: flattened_list.count(i) for i in flattened_list}\n return frequency_dict", "matching_cluster_idx": 1}, {"solution": "from collections import Counter\nfrom typing import List, Dict, Union\ndef frequency_lists(lsts: List[List[Union[int, float, str]]]) -> Dict[Union[int, float, str], int]:\n flattened = [item for sublist in lsts for item in sublist]\n return dict(Counter(flattened))", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(list_of_lists):\n \"\"\"\n Function to find frequency of each element in a flattened list of lists.\n \"\"\"\n flattened = [item for sublist in list_of_lists for item in sublist]\n frequencies = {i: flattened.count(i) for i in flattened}\n return frequencies", "matching_cluster_idx": 1}, {"solution": "from typing import List, Union\ndef flatten_list(nested_list):\n \"\"\"Flatten a nested list\"\"\"\n flat_list = []\n for item in nested_list:\n if isinstance(item, list):\n flat_list.extend(flatten_list(item))\n else:\n flat_list.append(item)\n return flat_list\ndef frequency_lists(nested_list: List[List[Union[int, float, str]]]):\n \"\"\"Find frequency of each element in a nested list\"\"\"\n flat_list = flatten_list(nested_list)\n frequency_dict = {}\n for item in flat_list:\n if item in frequency_dict:\n frequency_dict[item] += 1\n else:\n frequency_dict[item] = 1\n return frequency_dict", "matching_cluster_idx": 4}, {"solution": "from typing import List, Dict\nfrom collections import defaultdict\ndef frequency_lists(lists: List[List[int]]) -> Dict[int, int]:\n flattened_list = [num for sublist in lists for num in sublist]\n frequency_dict = defaultdict(int)\n for num in flattened_list:\n frequency_dict[num] += 1\n return frequency_dict", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lst):\n frequency = {}\n flatten_list = [elem for sublist in lst for elem in sublist]\n for i in flatten_list:\n if i in frequency:\n frequency[i] += 1\n else:\n frequency[i] = 1\n return frequency", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lst):\n flat_list = [item for sublist in lst for item in sublist]\n frequency_dict = {}\n for i in flat_list:\n if i in frequency_dict:\n frequency_dict[i] += 1\n else:\n frequency_dict[i] = 1\n return frequency_dict", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lst):\n # Flatten the list\n flat_list = [item for sublist in lst for item in sublist]\n \n # Compute frequencies\n freq = {}\n for i in flat_list:\n if i in freq:\n freq[i] += 1\n else:\n freq[i] = 1\n return freq", "matching_cluster_idx": 6}, {"solution": "def flatten_list(lst):\n flat_list = [item for sublist in lst for item in sublist]\n return flat_list\ndef frequency_lists(lst):\n flat_list = flatten_list(lst)\n freq_dict = {i: flat_list.count(i) for i in flat_list}\n return freq_dict", "matching_cluster_idx": 1}, {"solution": "def frequency_lists(nested_list):\n \"\"\"\n Calculates the frequency of each element in a flattened list of lists.\n Args:\n nested_list: A list of lists\n\n Returns:\n A dictionary containing each element of the flattened list as keys and their frequency as values.\n \"\"\"\n flattened_list = [item for sublist in nested_list for item in sublist]\n frequency_dict = {}\n for item in flattened_list:\n if item in frequency_dict:\n frequency_dict[item] += 1\n else:\n frequency_dict[item] = 1\n return frequency_dict", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lst):\n flat_list = [item for sublist in lst for item in sublist]\n frequency_dict = {}\n for i in flat_list:\n if i in frequency_dict:\n frequency_dict[i] += 1\n else:\n frequency_dict[i] = 1\n return frequency_dict", "matching_cluster_idx": 6}]}, "Mbpp/106": {"dps": 34.61038961038961, "dps_norm": 79.16666666666666, "pass@1": 91.0, "profiled": [{"solution": "def add_lists(input_list, input_tuple):\n \"\"\"\n Function to append the given list to the given tuple.\n \"\"\"\n # Convert the tuple to list, extend it with the input list and convert back to tuple\n extended_tuple = tuple(list(input_tuple) + input_list)\n\n return extended_tuple", "matching_cluster_idx": 2}, {"solution": "def add_lists(lst, tpl):\n \"\"\"\n Append a list to a tuple.\n\n Args:\n lst (list): A list of elements.\n tpl (tuple): A tuple of elements.\n\n Returns:\n tuple: A new tuple that combines the list and the tuple.\n \"\"\"\n return tpl + tuple(lst)", "matching_cluster_idx": 4}, {"solution": "def add_lists(list_to_add, tuple_to_append):\n \"\"\"\n This function appends the given list to the given tuple\n \"\"\"\n return tuple_to_append + tuple(list_to_add)", "matching_cluster_idx": 4}, {"solution": "def add_lists(list_, tuple_):\n return tuple_ + tuple(list_)", "matching_cluster_idx": 4}, {"solution": "def add_lists(lst, tpl):\n return tpl + tuple(lst)", "matching_cluster_idx": 4}, {"solution": "def add_lists(list_val, tuple_val):\n \"\"\"\n Append the given list to the given tuple.\n \"\"\"\n return tuple_val + tuple(list_val)", "matching_cluster_idx": 4}, {"solution": "def add_lists(list_to_add, tuple_to_add_to):\n # Type checking\n if not isinstance(list_to_add, list) or not isinstance(tuple_to_add_to, tuple):\n raise TypeError(\"Expected a list and a tuple\")\n \n # Concatenate the list to the tuple using tuple unpacking and return the result\n return tuple_to_add_to + tuple(list_to_add)", "matching_cluster_idx": 4}, {"solution": "def add_lists(list_, tuple_):\n \"\"\"\n Append the given list to the given tuple.\n \"\"\"\n result_list = list(tuple_) + list_\n result_tuple = tuple(result_list)\n return result_tuple", "matching_cluster_idx": 2}, {"solution": "def add_lists(list_to_add, tuple_to_append):\n \"\"\"\n This function appends a given list to a given tuple.\n \"\"\"\n return tuple_to_append + tuple(list_to_add)", "matching_cluster_idx": 4}, {"solution": "def add_lists(list_to_append, original_tuple):\n return original_tuple + tuple(list_to_append)", "matching_cluster_idx": 4}, {"solution": "def add_lists(lst, tpl):\n return tpl + tuple(lst)", "matching_cluster_idx": 4}, {"solution": "def add_lists(lst, tup):\n \"\"\"\n Appends the given list to the given tuple.\n \"\"\"\n return tup + tuple(lst)", "matching_cluster_idx": 4}, {"solution": "def add_lists(list_to_append, initial_tuple):\n \"\"\"\n Append the given list to the given tuple.\n \"\"\"\n return initial_tuple + tuple(list_to_append)", "matching_cluster_idx": 4}, {"solution": "def add_lists(my_list, my_tuple):\n \"\"\"\n Appends the given list to the given tuple\n \"\"\"\n return my_tuple + tuple(my_list)", "matching_cluster_idx": 4}, {"solution": "def add_lists(input_list, input_tuple):\n \"\"\"\n Function to append the given list to the given tuple.\n \"\"\"\n return input_tuple + tuple(input_list)", "matching_cluster_idx": 4}, {"solution": "def add_lists(lst, tup):\n # Convert the tuple to a list and add the elements of the list to it\n return tuple(list(tup) + lst)", "matching_cluster_idx": 3}, {"solution": "def add_lists(lst, tup):\n \"\"\"Add list elements to the end of a tuple\"\"\"\n return tup + tuple(lst)", "matching_cluster_idx": 4}, {"solution": "def add_lists(list_, tup):\n return tup + tuple(list_)", "matching_cluster_idx": 4}, {"solution": "def add_lists(list_, tuple_):\n # Convert tuple to list, because tuples are immutable in Python\n tuple_list = list(tuple_)\n \n # Append the given list to the converted tuple list\n tuple_list.extend(list_)\n \n # Convert the result list back to a tuple and return it\n return tuple(tuple_list)", "matching_cluster_idx": 4}, {"solution": "def add_lists(lst, tup):\n return tup + tuple(lst)", "matching_cluster_idx": 4}]}, "Mbpp/108": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def merge_sorted_list(list1, list2, list3):\n merged_list = list1 + list2 + list3\n merged_list.sort()\n return merged_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n \"\"\"\n Function to merge three lists into a single sorted list.\n \"\"\"\n # Combine all the lists into one\n combined_list = list1 + list2 + list3\n\n # Sort the combined list in increasing order\n sorted_list = sorted(combined_list)\n\n return sorted_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n return sorted(list1 + list2 + list3)\nlist1 = [25, 24, 15, 4, 5, 29, 110]\nlist2 = [19, 20, 11, 56, 25, 233, 154]\nlist3 = [24, 26, 54, 48]", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n merged = list1 + list2 + list3\n merged.sort()\n return merged", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n result = list1 + list2 + list3\n result.sort()\n return result\nlist1 = [25, 24, 15, 4, 5, 29, 110]\nlist2 = [19, 20, 11, 56, 25, 233, 154]\nlist3 = [24, 26, 54, 48]", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(l1, l2, l3):\n merged_list = l1 + l2 + l3\n merged_list.sort()\n return merged_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Merge the three lists\n merged_list = list1 + list2 + list3\n # Sort the merged list\n merged_list.sort()\n return merged_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n \"\"\" Merges three sorted lists into a single sorted list. \"\"\"\n return sorted(list1 + list2 + list3)", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n merged_list = list1 + list2 + list3\n merged_list.sort()\n return merged_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Combine all lists into one\n combined = list1 + list2 + list3\n # Sort the combined list\n combined.sort()\n return combined", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n combined_list = list1 + list2 + list3\n return sorted(combined_list)", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(lst1, lst2, lst3):\n \"\"\"Merge three sorted lists into a single sorted list.\"\"\"\n result = lst1 + lst2 + lst3 # Combine lists\n result.sort() # Sort the combined list\n return result", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(lst1, lst2, lst3):\n merged_lst = lst1 + lst2 + lst3\n merged_lst.sort()\n return merged_lst\nlst1 = [25, 24, 15, 4, 5, 29, 110]\nlst2 = [19, 20, 11, 56, 25, 233, 154]\nlst3 = [24, 26, 54, 48]", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n \"\"\"\n Merges and sorts three lists into a single list.\n \"\"\"\n merged_list = list1 + list2 + list3\n merged_list.sort()\n return merged_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n return sorted(list1 + list2 + list3)", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n combined = list1 + list2 + list3\n combined.sort()\n return combined", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n return sorted(list1 + list2 + list3)", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(lst1, lst2, lst3):\n result = lst1 + lst2 + lst3\n result.sort()\n return result", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(l1, l2, l3):\n merged = l1 + l2 + l3\n merged.sort()\n return merged", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(l1, l2, l3):\n \"\"\"\n Merges three lists and sorts the merged list in ascending order\n \"\"\"\n # Merge the three lists\n merged_list = l1 + l2 + l3\n \n # Sort the merged list\n merged_list.sort()\n \n return merged_list", "matching_cluster_idx": 10}]}, "Mbpp/111": {"dps": 79.76923076923077, "dps_norm": 84.375, "pass@1": 90.0, "profiled": [{"solution": "def common_in_nested_lists(nested_lists):\n sets = [set(lst) for lst in nested_lists]\n common_elements = set.intersection(*sets)\n return list(common_elements)", "matching_cluster_idx": 5}, {"solution": "def common_in_nested_lists(nested_lists):\n common_elements = set(nested_lists[0])\n for sublist in nested_lists[1:]:\n common_elements = common_elements.intersection(sublist)\n return list(common_elements)", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n result = set(nested_lists[0])\n for sublist in nested_lists[1:]:\n result.intersection_update(sublist)\n return list(result)", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n result_set = set(nested_lists[0])\n for sublist in nested_lists[1:]:\n result_set &= set(sublist)\n return list(result_set)", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n # Converts nested lists to a set for each list and performs intersection of all sets\n common_elements = set(nested_lists[0]).intersection(*[set(lst) for lst in nested_lists[1:]])\n return list(common_elements)", "matching_cluster_idx": 5}, {"solution": "def common_in_nested_lists(nested_lists):\n \"\"\"\n Finds the common elements in given nested lists.\n \"\"\"\n common_elements = set(nested_lists[0])\n for l in nested_lists[1:]:\n common_elements = common_elements.intersection(l)\n return list(common_elements)\ntest_list = [[12, 18, 23, 25, 45], [7, 12, 18, 24, 28], [1, 5, 8, 12, 15, 16, 18]]\ncommon_elements = common_in_nested_lists(test_list)", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n \"\"\"\n Function to find the common elements in given nested lists.\n \"\"\"\n # convert each list to a set\n sets = [set(lst) for lst in nested_lists]\n \n # intersect all sets\n common = sets[0]\n for s in sets[1:]:\n common = common & s\n\n return list(common)", "matching_cluster_idx": 5}, {"solution": "def common_in_nested_lists(nested_list):\n common_set = set(nested_list[0])\n for sub_list in nested_list[1:]:\n common_set &= set(sub_list)\n return list(common_set)", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_list):\n \"\"\"\n This function takes a nested list as an input and returns a set of common elements.\n \"\"\"\n # The set.intersection() method is used to get common elements in the list\n common_set = set(nested_list[0])\n\n # Iterate over all nested lists in the given list\n for l in nested_list[1:]:\n # Calculate the intersection of the current common set and the current list\n common_set = common_set.intersection(set(l))\n \n return common_set", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n \"\"\"\n function to find the common elements in given nested lists.\n \"\"\"\n result = None\n\n for lst in nested_lists:\n if result is None:\n result = set(lst)\n else:\n result = result & set(lst) # intersection of two sets\n\n if not result: # if intersection is empty\n break\n\n return result", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n common_set = set(nested_lists[0])\n\n for sublist in nested_lists[1:]:\n common_set &= set(sublist)\n\n return list(common_set)", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n if not nested_lists:\n return []\n\n common_elements = set(nested_lists[0])\n for sublist in nested_lists[1:]:\n common_elements.intersection_update(sublist)\n\n return list(common_elements)", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(lst):\n result_set = set(lst[0])\n for sub_lst in lst[1:]:\n result_set = result_set.intersection(sub_lst)\n return list(result_set)", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n # Get the first list as the common elements to start with\n common_elements = set(nested_lists[0])\n\n # For every other list, find the intersection with the current common elements\n for lst in nested_lists[1:]:\n common_elements &= set(lst)\n\n return list(common_elements)", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n # Get first list of the nested lists\n common_set = set(nested_lists[0])\n\n # Iterate over the remaining lists\n for lst in nested_lists[1:]:\n # Keep only the common elements between current list and current common_set\n common_set.intersection_update(lst)\n\n return list(common_set)", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n common_elements = set(nested_lists[0])\n for sub_list in nested_lists[1:]:\n common_elements.intersection_update(sub_list)\n return list(common_elements)", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n if not isinstance(nested_lists, list) or not all(isinstance(i, list) for i in nested_lists):\n raise ValueError(\"Input should be a list of lists.\")\n\n common = set(nested_lists[0])\n for lst in nested_lists[1:]:\n common &= set(lst)\n return list(common)", "matching_cluster_idx": 5}, {"solution": "def common_in_nested_lists(nested_lists):\n # Start with the first list in the nested_lists\n common_elements = set(nested_lists[0])\n\n # Iterate over the remaining lists in the nested_lists\n for lst in nested_lists[1:]:\n # Use the intersection method to get the common elements with the current list\n common_elements = common_elements.intersection(lst)\n\n # Return the set of common elements\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n \"\"\"\n Function to find common elements in given nested lists.\n \"\"\"\n # Convert nested list to a set of sets\n sets = [set(lst) for lst in nested_lists]\n\n # Find intersection of all sets using built-in Python function\n common_elements = set.intersection(*sets)\n\n return common_elements", "matching_cluster_idx": 5}, {"solution": "def common_in_nested_lists(nested_lists):\n common_elements = set(nested_lists[0])\n \n for lst in nested_lists[1:]:\n common_elements = common_elements & set(lst)\n\n return list(common_elements)", "matching_cluster_idx": 6}]}, "Mbpp/123": {"dps": 99.63619402985074, "dps_norm": 86.07142857142857, "pass@1": 67.0, "profiled": [{"solution": "def sum_of_divisors(n):\n sum = 1\n for i in range(2, int(n ** 0.5) + 1):\n if n % i == 0:\n if i == (n / i):\n sum = sum + i\n else:\n sum = sum + (i + n / i)\n return sum\ndef amicable_numbers_sum(max_range):\n sum = 0\n for num in range(max_range+1):\n div_sum = sum_of_divisors(num)\n if (num != div_sum and sum_of_divisors(div_sum) == num):\n sum += num\n return sum", "matching_cluster_idx": 11}, {"solution": "def divisor_sum(n):\n sum = 1\n i = 2\n while i * i <= n :\n if n % i == 0 :\n sum = sum + i + n/i\n i += 1\n return sum\ndef amicable_numbers_sum(limit):\n sum = 0\n for num in range(2, limit + 1):\n temp = divisor_sum(num)\n if (temp > num and divisor_sum(temp) == num):\n sum += (num + temp)\n return sum", "matching_cluster_idx": 11}, {"solution": "def amicable_numbers_sum(limit):\n def divisors(n):\n divs = [1]\n for i in range(2, int(n**0.5)+1):\n if n%i:\n continue\n if i*i != n:\n divs.extend([i,n//i])\n else:\n divs.append(i)\n return divs\n \n sum_amicable = 0\n for a in range(2, limit + 1):\n b = sum(divisors(a))\n if b > a and sum(divisors(b)) == a:\n sum_amicable += a + b\n return sum_amicable", "matching_cluster_idx": 11}, {"solution": "def sum_proper_divisors(n):\n result = 1\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n result += i\n if n // i != i:\n result += n // i\n return result\ndef amicable_numbers_sum(n):\n result = 0\n for a in range(2, n+1):\n b = sum_proper_divisors(a)\n if b > a and sum_proper_divisors(b) == a:\n result += a + b\n return result", "matching_cluster_idx": 11}, {"solution": "def amicable_numbers_sum(limit):\n sum_divisors = [0] * (limit + 1)\n for i in range(1, limit + 1):\n for j in range(i * 2, limit + 1, i):\n sum_divisors[j] += i\n sum_amicable = 0\n for i in range(1, limit + 1):\n j = sum_divisors[i]\n if j <= limit and j > i and sum_divisors[j] == i:\n sum_amicable += i + j\n return sum_amicable", "matching_cluster_idx": 12}, {"solution": "def sum_of_divisors(n):\n total = 1\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n total += i\n if n // i != i:\n total += n // i\n return total\ndef amicable_numbers_sum(limit):\n amicable_numbers = []\n for a in range(limit + 1):\n b = sum_of_divisors(a)\n if a != b and sum_of_divisors(b) == a:\n amicable_numbers.append(a)\n return sum(amicable_numbers)", "matching_cluster_idx": 11}, {"solution": "def amicable_numbers_sum(n):\n def sum_divisors(n):\n result = 1\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n result += i\n if n//i != i:\n result += n//i\n return result\n\n total = 0\n for a in range(2, n+1):\n b = sum_divisors(a)\n if a != b and a == sum_divisors(b):\n total += a\n return total", "matching_cluster_idx": 11}, {"solution": "def amicable_numbers_sum(n):\n def sum_proper_divisors(num):\n divisors_sum = 1\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n if i == (num / i):\n divisors_sum += i\n else:\n divisors_sum += (i + num / i)\n return divisors_sum\n\n def is_amicable(num):\n sum_1 = sum_proper_divisors(num)\n sum_2 = sum_proper_divisors(sum_1)\n if sum_2 == num and sum_1 != sum_2:\n return True\n else:\n return False\n\n amicable_sum = 0\n for i in range(1, n + 1):\n if is_amicable(i):\n amicable_sum += i\n\n return amicable_sum", "matching_cluster_idx": 11}, {"solution": "def sum_of_divisors(n):\n # function to get sum of divisors\n sum = 1\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n if n // i == i:\n sum += i\n else:\n sum += i\n sum += n // i\n return sum\ndef amicable_numbers_sum(n):\n # function to sum all amicable numbers\n sum = 0\n for i in range(2, n + 1):\n divisor_sum = sum_of_divisors(i)\n if (i != divisor_sum and i == sum_of_divisors(divisor_sum)):\n sum += i\n return sum", "matching_cluster_idx": 11}, {"solution": "def find_divisors(n):\n divisors = [1]\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n divisors.extend([i, n // i])\n return list(set(divisors))\ndef amicable_numbers_sum(num):\n result = 0\n for i in range(2, num + 1):\n divisors_sum = sum(find_divisors(i))\n if i != divisors_sum and i == sum(find_divisors(divisors_sum)):\n result += i\n return result", "matching_cluster_idx": 11}, {"solution": "def sum_of_divisors(n):\n result = 1\n for i in range(2, int(n**0.5)+1):\n if n % i == 0:\n if n // i == i:\n result += i\n else:\n result += i + n // i\n return result\ndef is_amicable(a, b):\n return (sum_of_divisors(a) == b and sum_of_divisors(b) == a)\ndef amicable_numbers_sum(n):\n amicable_numbers = []\n for a in range(1, n+1):\n if a not in amicable_numbers:\n b = sum_of_divisors(a)\n if a != b and is_amicable(a, b):\n amicable_numbers.extend([a, b])\n return sum(amicable_numbers)", "matching_cluster_idx": 11}, {"solution": "def proper_divisors(n):\n \"\"\" Return a list with all proper divisors of n. \"\"\"\n divisors = [1]\n for i in range(2, int(n ** 0.5) + 1):\n if n % i:\n continue\n if i*i != n:\n divisors.extend([i, n // i])\n else:\n divisors.append(i)\n return divisors\ndef amicable_numbers_sum(limit):\n \"\"\" Sum all amicable numbers from 1 to the specified limit. \"\"\"\n sum_amicable = 0\n for a in range(4, limit):\n b = sum(proper_divisors(a))\n if a != b and sum(proper_divisors(a)) == b and sum(proper_divisors(b)) == a:\n sum_amicable += a\n return sum_amicable", "matching_cluster_idx": 11}, {"solution": "def sum_of_divisors(n):\n sum = 1\n i = 2\n while i * i <= n:\n if n % i == 0:\n sum = sum + i\n other_divisor = n // i\n if other_divisor != i:\n sum = sum + other_divisor\n i += 1\n return sum\ndef amicable_numbers_sum(num):\n sum = 0\n for i in range(2, num+1):\n div_sum = sum_of_divisors(i)\n if sum_of_divisors(div_sum) == i and i != div_sum:\n sum += i\n return sum", "matching_cluster_idx": 11}, {"solution": "def amicable_numbers_sum(limit):\n def sum_divisors(n):\n sum = 1\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n if i == (n / i):\n sum += i\n else:\n sum += (i + n//i)\n return sum\n\n result = 0\n for i in range(2, limit+1):\n sum_i = sum_divisors(i)\n if sum_divisors(sum_i) == i and sum_i != i and sum_i <= limit:\n result += i\n return result", "matching_cluster_idx": 11}, {"solution": "def divisors(n):\n divs = [1]\n for i in range(2, int(n**0.5)+1):\n if n%i == 0:\n if n/i == i:\n divs.append(i)\n else:\n divs.extend([i, n//i])\n return divs\ndef amicable_numbers_sum(n):\n def amicable(a):\n b = sum(divisors(a))\n return b != a and sum(divisors(b)) == a\n return sum(a for a in range(1, n+1) if amicable(a))", "matching_cluster_idx": 11}, {"solution": "def amicable_numbers_sum(n):\n def sum_divisors(num):\n result = 1\n i = 2\n while i <= num**0.5:\n if (num % i == 0):\n if (i == (num / i)):\n result = result + i\n else:\n result = result + (i + num//i)\n i += 1\n return result\n\n amicable_sum = 0\n for i in range(1, n+1):\n sum_i = sum_divisors(i)\n if sum_i > i and sum_divisors(sum_i) == i:\n amicable_sum += i + sum_i\n return amicable_sum", "matching_cluster_idx": 11}, {"solution": "def amicable_numbers_sum(n):\n def sum_proper_divisors(num):\n result = 1\n i = 2\n while i * i <= num:\n if (num % i == 0):\n if (i == (num / i)):\n result = result + i\n else:\n result = result + (i + num//i)\n i += 1\n return result\n\n amicable_sum = 0\n for num in range(2, n + 1):\n sum_of_divisors = sum_proper_divisors(num)\n if sum_of_divisors > num and sum_proper_divisors(sum_of_divisors) == num:\n amicable_sum += num + sum_of_divisors\n return amicable_sum", "matching_cluster_idx": 11}, {"solution": "def amicable_numbers_sum(limit):\n def sum_divisors(n) :\n result = 1\n i = 2\n while i <= n**0.5 :\n if (n % i == 0) :\n if (i == (n/i)) :\n result = result + i\n else :\n result = result + (i + n//i)\n i = i + 1\n return result\n \n total = 0\n for i in range(1, limit+1):\n divisor_sum = sum_divisors(i)\n if sum_divisors(divisor_sum) == i and divisor_sum != i:\n total += i\n \n return total", "matching_cluster_idx": 11}, {"solution": "def sum_proper_divisors(n):\n divisors = [1]\n for i in range(2, int(n**0.5)+1):\n if n % i == 0:\n if n//i == i:\n divisors.append(i)\n else:\n divisors.extend([i, n//i])\n return sum(divisors)\ndef amicable_numbers_sum(n):\n amicable_numbers = []\n for a in range(1, n+1):\n b = sum_proper_divisors(a)\n if a != b and sum_proper_divisors(b) == a:\n if a not in amicable_numbers and b not in amicable_numbers:\n amicable_numbers.append(a)\n if b <= n:\n amicable_numbers.append(b)\n return sum(amicable_numbers)", "matching_cluster_idx": 11}, {"solution": "def proper_divisors(n):\n \"\"\"\n Helper function to find proper divisors of a number\n \"\"\"\n result = [1]\n for i in range(2, int(n ** 0.5) + 1):\n if n % i == 0:\n result.extend([i, n//i])\n return list(set(result))\ndef amicable_numbers_sum(num):\n \"\"\"\n Function to sum all amicable numbers from 1 to a specified number.\n \"\"\"\n result = 0\n for i in range(1, num+1):\n s1 = sum(proper_divisors(i))\n if i != s1 and sum(proper_divisors(s1)) == i:\n result += i\n return result", "matching_cluster_idx": 11}]}, "Mbpp/128": {"dps": 99.5475113122172, "dps_norm": 80.0, "pass@1": 100.0, "profiled": [{"solution": "def long_words(n, sentence):\n # Splitting the sentence into words\n words = sentence.split()\n\n # Filtering out words that are longer than n characters\n long_words = [word for word in words if len(word) > n]\n\n return long_words", "matching_cluster_idx": 3}, {"solution": "def long_words(n, string):\n words = string.split(\" \")\n return [word for word in words if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n return [word for word in sentence.split() if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n words = sentence.split()\n result = [word for word in words if len(word) > n]\n return result", "matching_cluster_idx": 3}, {"solution": "def long_words(n, string):\n words = string.split(' ')\n return [word for word in words if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, string):\n \"\"\"\n Function to find words that are longer than n characters from a given list of words.\n \"\"\"\n words = string.split()\n long_words = [word for word in words if len(word) > n]\n return long_words", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n return [word for word in sentence.split() if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n return [word for word in sentence.split() if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n return [word for word in sentence.split() if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n return [word for word in sentence.split() if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, s):\n return [word for word in s.split() if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, string):\n words = string.split(' ')\n long_words = [word for word in words if len(word) > n]\n return long_words", "matching_cluster_idx": 3}, {"solution": "def long_words(n, str):\n return [word for word in str.split() if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, s):\n \"\"\"\n Find words that are longer than n characters from a given string.\n \"\"\"\n return [word for word in s.split() if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n \"\"\"\n Function to find words that are longer than n characters from a given sentence.\n \"\"\"\n words = sentence.split(' ')\n long_words = [word for word in words if len(word) > n]\n return long_words", "matching_cluster_idx": 3}, {"solution": "def long_words(n, s):\n return [word for word in s.split() if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n words = sentence.split()\n result = [word for word in words if len(word) > n]\n return result", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n words = sentence.split()\n return [word for word in words if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n # Splitting the sentence into words\n words = sentence.split()\n\n # Initializing an empty list for long words\n long_words_list = []\n\n # Iterate over each word in the list\n for word in words:\n # If the word is longer than 'n' characters, add it to the 'long_words_list'\n if len(word) > n:\n long_words_list.append(word)\n\n # Return the list of long words\n return long_words_list", "matching_cluster_idx": 3}, {"solution": "def long_words(n, text):\n return [word for word in text.split() if len(word) > n]", "matching_cluster_idx": 3}]}, "Mbpp/129": {"dps": 83.3545918367347, "dps_norm": 95.66666666666667, "pass@1": 57.0, "profiled": [{"solution": "def magic_square_test(matrix):\n # Calculate the sum of the first row\n magic_const = sum(matrix[0])\n\n # Check if each row adds up to the same value\n for row in matrix:\n if sum(row) != magic_const:\n return False\n\n # Check if each column adds up to the same value\n for i in range(len(matrix)):\n if sum(row[i] for row in matrix) != magic_const:\n return False\n\n # Check if both diagonals add up to the same value\n if sum(matrix[i][i] for i in range(len(matrix))) != magic_const:\n return False\n if sum(matrix[i][len(matrix)-i-1] for i in range(len(matrix))) != magic_const:\n return False\n\n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n # Check if the matrix is a square matrix\n if len(matrix) == 0 or len(matrix) != len(matrix[0]):\n return False\n # Calculate the sum of the first row\n row_sum = sum(matrix[0])\n # Check if all rows have the same sum\n for row in matrix:\n if sum(row) != row_sum:\n return False\n # Check if all columns have the same sum\n for i in range(len(matrix)):\n if sum(row[i] for row in matrix) != row_sum:\n return False\n # Check if the sum of the main diagonal is the same as the row sum\n if sum(matrix[i][i] for i in range(len(matrix))) != row_sum:\n return False\n # Check if the sum of the other diagonal is the same as the row sum\n if sum(matrix[i][len(matrix)-1-i] for i in range(len(matrix))) != row_sum:\n return False\n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n # calculate the sum of the first row as the magic number\n magic_num = sum(matrix[0])\n\n # check row sums\n for row in matrix:\n if sum(row) != magic_num:\n return False\n\n # check column sums\n for col in range(len(matrix[0])):\n if sum(row[col] for row in matrix) != magic_num:\n return False\n\n # check diagonal sums\n if sum(matrix[i][i] for i in range(len(matrix))) != magic_num:\n return False\n if sum(matrix[i][len(matrix)-i-1] for i in range(len(matrix))) != magic_num:\n return False\n\n # if all checks pass, it's a magic square\n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n # Check if the matrix is square\n if len(matrix) != len(matrix[0]):\n return False\n \n # Calculate the magic constant\n magic_constant = sum(matrix[0])\n\n # Check the sum of each row\n for row in matrix:\n if sum(row) != magic_constant:\n return False\n\n # Check the sum of each column\n for i in range(len(matrix)):\n if sum([row[i] for row in matrix]) != magic_constant:\n return False\n\n # Check the sum of the diagonals\n if sum([matrix[i][i] for i in range(len(matrix))]) != magic_constant or sum([matrix[i][len(matrix) - i - 1] for i in range(len(matrix))]) != magic_constant:\n return False\n\n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n # calculate sum of the first row\n sum_ref = sum(matrix[0])\n\n # check the sum of each row\n for row in matrix:\n if sum(row) != sum_ref:\n return False\n\n # check the sum of each column\n for col in range(len(matrix[0])):\n if sum(row[col] for row in matrix) != sum_ref:\n return False\n\n # check the sum of diagonal elements\n if sum(matrix[i][i] for i in range(len(matrix))) != sum_ref:\n return False\n # check the sum of anti-diagonal elements\n if sum(matrix[i][len(matrix)-i-1] for i in range(len(matrix))) != sum_ref:\n return False\n\n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n # Step 1: Determine the magic constant (the sum of each row, column, or diagonal)\n magic_const = sum(matrix[0])\n\n # Step 2: Check if all rows and columns have the same sum\n for i in range(len(matrix)):\n if sum(matrix[i]) != magic_const:\n return False\n if sum([row[i] for row in matrix]) != magic_const:\n return False\n\n # Step 3: Check the diagonals\n if sum([matrix[i][i] for i in range(len(matrix))]) != magic_const:\n return False\n if sum([matrix[i][len(matrix)-i-1] for i in range(len(matrix))]) != magic_const:\n return False\n\n # If we've made it this far, it's a magic square\n return True", "matching_cluster_idx": 13}, {"solution": "def magic_square_test(matrix):\n # get the sum of the first row\n sum_target = sum(matrix[0])\n\n # check rows\n for row in matrix:\n if sum(row) != sum_target:\n return False\n\n # check columns\n for col in range(len(matrix[0])):\n if sum(row[col] for row in matrix) != sum_target:\n return False\n\n # check diagonals\n if sum(matrix[i][i] for i in range(len(matrix))) != sum_target:\n return False\n if sum(matrix[i][len(matrix)-i-1] for i in range(len(matrix))) != sum_target:\n return False\n\n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n n = len(matrix)\n sum_list = []\n\n # check if it's a square\n if any(len(row) != n for row in matrix):\n return False\n\n # calculate sum of rows, columns and diagonals\n sum_list.extend([sum(row) for row in matrix])\n sum_list.extend([sum(col) for col in zip(*matrix)])\n sum_list.append(sum(matrix[i][i] for i in range(n)))\n sum_list.append(sum(matrix[i][n - i - 1] for i in range(n)))\n\n # check if all sums are equal\n return len(set(sum_list)) == 1", "matching_cluster_idx": 8}, {"solution": "def magic_square_test(matrix):\n # Calculate sum of first row for comparison\n sum_num = sum(matrix[0])\n\n # Check each row sum\n for row in matrix:\n if sum(row) != sum_num:\n return False\n\n # Check each column sum\n for col in range(len(matrix[0])):\n if sum(row[col] for row in matrix) != sum_num:\n return False\n\n # Check diagonals\n if sum(matrix[i][i] for i in range(len(matrix))) != sum_num or \\\n sum(matrix[i][len(matrix)-i-1] for i in range(len(matrix))) != sum_num:\n return False\n\n # If all checks pass, return True\n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n \"\"\"Function to check if a given matrix is a magic square or not.\"\"\"\n # Check if the matrix is empty\n if len(matrix) == 0:\n return True\n \n # Calculate the sum of the first row\n magic_sum = sum(matrix[0])\n \n # Check rows\n for row in matrix:\n if sum(row) != magic_sum:\n return False\n \n # Check columns\n for col in range(len(matrix[0])):\n if sum(row[col] for row in matrix) != magic_sum:\n return False\n \n # Check diagonals\n if sum(matrix[i][i] for i in range(len(matrix))) != magic_sum:\n return False\n if sum(matrix[i][len(matrix)-i-1] for i in range(len(matrix))) != magic_sum:\n return False\n \n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n order = len(matrix)\n diag_sum1 = 0\n diag_sum2 = 0\n for i in range(order):\n if len(matrix[i]) != order:\n return False\n diag_sum1 += matrix[i][i]\n diag_sum2 += matrix[i][order-i-1]\n if sum(matrix[i]) != sum(row[i] for row in matrix):\n return False\n if diag_sum1 != diag_sum2:\n return False\n return True", "matching_cluster_idx": 13}, {"solution": "def magic_square_test(matrix):\n # calculate the magic constant (e.g. 1+2+3+4 = 10)\n magic_const = sum(matrix[0])\n # the transpose of matrix\n transpose = list(map(list, zip(*matrix)))\n\n # check if all rows and columns sum up to the magic constant\n for row in matrix:\n if sum(row) != magic_const:\n return False\n for col in transpose:\n if sum(col) != magic_const:\n return False\n\n # check if the sum of diagonal elements equals to the magic constant\n diag_sum1 = sum(matrix[i][i] for i in range(len(matrix)))\n diag_sum2 = sum(matrix[i][len(matrix)-i-1] for i in range(len(matrix)))\n if diag_sum1 != magic_const or diag_sum2 != magic_const:\n return False\n\n return True", "matching_cluster_idx": 10}, {"solution": "def magic_square_test(matrix):\n # calculate sum of the first row\n magic_const = sum(matrix[0])\n\n # calculate sum of each row, if any is not equal to magic_const, return False\n for row in matrix:\n if sum(row) != magic_const:\n return False\n\n # calculate sum of each column, if any is not equal to magic_const, return False\n for col in range(len(matrix[0])):\n if sum(row[col] for row in matrix) != magic_const:\n return False\n\n # calculate sum of leading diagonal, if not equal to magic_const, return False\n if sum(matrix[i][i] for i in range(len(matrix))) != magic_const:\n return False\n\n # calculate sum of counter diagonal, if not equal to magic_const, return False\n if sum(matrix[i][len(matrix)-i-1] for i in range(len(matrix))) != magic_const:\n return False\n\n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n \"\"\"\n This function checks if a given square matrix is a magic square.\n A magic square is a square grid filled with distinct positive integers\n such that each cell contains a different integer and the sum of the integers\n in each row, each column, and both diagonals is the same.\n \"\"\"\n # Calculate the target sum\n target_sum = sum(matrix[0])\n\n # Check row sums\n for row in matrix:\n if sum(row) != target_sum:\n return False\n\n # Check column sums\n for column in range(len(matrix)):\n if sum(matrix[row][column] for row in range(len(matrix))) != target_sum:\n return False\n\n # Check diagonal sums\n if sum(matrix[i][i] for i in range(len(matrix))) != target_sum:\n return False\n if sum(matrix[i][len(matrix)-i-1] for i in range(len(matrix))) != target_sum:\n return False\n\n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n # First, we need to calculate the sum of the first row as the reference sum\n first_row_sum = sum(matrix[0])\n \n # Verify the sum of each row, column, and diagonals\n for row in matrix:\n if sum(row) != first_row_sum:\n return False\n \n for col in range(len(matrix)):\n if sum(matrix[i][col] for i in range(len(matrix))) != first_row_sum:\n return False\n \n if sum(matrix[i][i] for i in range(len(matrix))) != first_row_sum:\n return False\n \n if sum(matrix[i][len(matrix)-i-1] for i in range(len(matrix))) != first_row_sum:\n return False\n \n # If we passed all tests, it's a magic square\n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n # Check if the matrix is square.\n if len(matrix) != len(matrix[0]):\n return False\n\n # Calculate the sum of the first row.\n magic_constant = sum(matrix[0])\n\n # Check the sum of each row.\n for row in matrix:\n if sum(row) != magic_constant:\n return False\n\n # Check the sum of each column.\n for i in range(len(matrix)):\n if sum(row[i] for row in matrix) != magic_constant:\n return False\n\n # Check the sum of main diagonal.\n if sum(matrix[i][i] for i in range(len(matrix))) != magic_constant:\n return False\n\n # Check the sum of antidiagonal.\n if sum(matrix[i][len(matrix)-i-1] for i in range(len(matrix))) != magic_constant:\n return False\n\n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n # Check if it's a square matrix\n if len(matrix) == 0 or len(matrix) != len(matrix[0]):\n return False\n\n # Sum of first row\n magic_constant = sum(matrix[0])\n\n # Check rows\n for row in matrix:\n if sum(row) != magic_constant:\n return False\n\n # Check columns\n for col in range(len(matrix[0])):\n if sum(row[col] for row in matrix) != magic_constant:\n return False\n\n # Check diagonals\n if sum(matrix[i][i] for i in range(len(matrix))) != magic_constant or \\\n sum(matrix[i][len(matrix)-i-1] for i in range(len(matrix))) != magic_constant:\n return False\n\n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n size = len(matrix)\n\n # Calculate the magic constant (sum of first row)\n magic_constant = sum(matrix[0])\n\n # Check each row\n for row in matrix:\n if sum(row) != magic_constant:\n return False\n\n # Check each column\n for i in range(size):\n column_sum = sum(row[i] for row in matrix)\n if column_sum != magic_constant:\n return False\n\n # Check diagonals\n diagonal1 = sum(matrix[i][i] for i in range(size))\n diagonal2 = sum(matrix[i][size - i - 1] for i in range(size))\n\n if diagonal1 != magic_constant or diagonal2 != magic_constant:\n return False\n\n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n # first check that the matrix is square\n size = len(matrix)\n for row in matrix:\n if len(row) != size:\n return False\n\n # calculate the sum of the first row\n magic_sum = sum(matrix[0])\n\n # check rows and columns\n for i in range(size):\n if sum(matrix[i]) != magic_sum or sum([row[i] for row in matrix]) != magic_sum:\n return False\n\n # check diagonals\n if sum([matrix[i][i] for i in range(size)]) != magic_sum or sum([matrix[i][size-i-1] for i in range(size)]) != magic_sum:\n return False\n\n return True", "matching_cluster_idx": 13}, {"solution": "def magic_square_test(matrix):\n n = len(matrix)\n\n # Calculate the magic constant (sum of first row)\n magic_constant = sum(matrix[0])\n\n # Check if all rows have the same sum\n for row in matrix:\n if sum(row) != magic_constant:\n return False\n\n # Check if all columns have the same sum\n for col in range(n):\n if sum(row[col] for row in matrix) != magic_constant:\n return False\n\n # Check if the sum of the main diagonal is the same\n if sum(matrix[i][i] for i in range(n)) != magic_constant:\n return False\n\n # Check if the sum of the antidiagonal is the same\n if sum(matrix[i][n - i - 1] for i in range(n)) != magic_constant:\n return False\n\n return True", "matching_cluster_idx": 14}]}, "Mbpp/130": {"dps": 74.91031390134529, "dps_norm": 67.5, "pass@1": 41.0, "profiled": [{"solution": "def max_occurrences(lst):\n counts = {i: lst.count(i) for i in lst}\n max_count = max(counts.values())\n return next(key for key, value in counts.items() if value == max_count)", "matching_cluster_idx": 1}, {"solution": "def max_occurrences(lst):\n count = {} # Dictionary to store counts of elements\n for item in lst:\n if item in count:\n count[item] += 1\n else:\n count[item] = 1\n # Find item with max frequency\n max_item = max(count, key=count.get)\n return max_item", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(input_list):\n # Create a dictionary to store the count of each element in the list\n count_dict = {}\n for item in input_list:\n if item in count_dict:\n count_dict[item] += 1\n else:\n count_dict[item] = 1\n\n # Find the item with the maximum count\n max_count_item = None\n max_count = 0\n for item, count in count_dict.items():\n if count > max_count:\n max_count = count\n max_count_item = item\n\n return max_count_item", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(lst):\n from collections import Counter\n freq_dict = dict(Counter(lst))\n max_freq = max(freq_dict.values())\n for key, value in freq_dict.items():\n if value == max_freq:\n return key", "matching_cluster_idx": 4}, {"solution": "from collections import Counter\ndef max_occurrences(lst):\n counter = Counter(lst)\n return max(counter, key=counter.get)", "matching_cluster_idx": 4}, {"solution": "def max_occurrences(input_list):\n # Count frequencies using a dictionary\n freq_dict = {}\n for item in input_list:\n if item in freq_dict:\n freq_dict[item] += 1\n else:\n freq_dict[item] = 1\n \n # Find item with max frequency\n max_freq = 0\n max_item = None\n for item, freq in freq_dict.items():\n if freq > max_freq:\n max_freq = freq\n max_item = item\n\n return max_item", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(lst):\n counts = {}\n for num in lst:\n if num in counts:\n counts[num] += 1\n else:\n counts[num] = 1\n return max(counts, key=counts.get)", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(lst):\n from collections import Counter\n\n # Create a dictionary with counts of each element\n count_dict = Counter(lst)\n\n # Get the maximum count\n max_count = max(count_dict.values())\n\n # Get the items which have the maximum count\n max_count_items = [item for item, count in count_dict.items() if count == max_count]\n\n # Return the first maximum occurring item (since the list is not sorted, we can return any of them)\n return max_count_items[0]", "matching_cluster_idx": 4}, {"solution": "from collections import Counter\ndef max_occurrences(lst):\n count = Counter(lst)\n return max(count.items(), key=lambda x: x[1])[0]", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(lst):\n # Get the frequency of each item using a dictionary\n freq_dict = {}\n for item in lst:\n if item in freq_dict:\n freq_dict[item] += 1\n else:\n freq_dict[item] = 1\n\n # Find the item with maximum frequency\n max_item = max(freq_dict, key=freq_dict.get)\n\n return max_item", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(lst):\n frequency_dict = {}\n for item in lst:\n if item in frequency_dict:\n frequency_dict[item] += 1\n else:\n frequency_dict[item] = 1\n max_frequency = max(list(frequency_dict.values()))\n items_with_max_frequency = [key for key, value in frequency_dict.items() if value == max_frequency]\n return items_with_max_frequency[0]", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(arr):\n \"\"\"\n Finds the item with maximum frequency in the given list.\n \"\"\"\n num_dict = {}\n for i in arr:\n if i in num_dict:\n num_dict[i] += 1\n else:\n num_dict[i] = 1\n\n max_freq = max(num_dict.values())\n\n for num, freq in num_dict.items():\n if freq == max_freq:\n return num", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(lst):\n counts = {}\n for item in lst:\n if item in counts:\n counts[item] += 1\n else:\n counts[item] = 1\n max_item = max(counts, key=counts.get)\n return max_item", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(input_list):\n \"\"\"Function to find the item with maximum frequency in a given list.\"\"\"\n count_dict = {}\n for item in input_list:\n if item in count_dict:\n count_dict[item] += 1\n else:\n count_dict[item] = 1\n max_key = max(count_dict, key=count_dict.get)\n return max_key", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(lst):\n # create a dictionary to store each item and its frequency\n freq_dict = {}\n for item in lst:\n if item in freq_dict:\n freq_dict[item] += 1\n else:\n freq_dict[item] = 1\n\n # find the item with maximum frequency\n max_freq = 0\n max_item = None\n for item, freq in freq_dict.items():\n if freq > max_freq:\n max_freq = freq\n max_item = item\n\n return max_item", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(lst):\n count_dict = {}\n for i in lst:\n if i in count_dict:\n count_dict[i] += 1\n else:\n count_dict[i] = 1\n max_item = max(count_dict, key=count_dict.get)\n return max_item", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(lst):\n if not lst: \n return None\n frequency_dict = {}\n for num in lst:\n if num in frequency_dict:\n frequency_dict[num] += 1\n else:\n frequency_dict[num] = 1\n\n max_freq_item = max(frequency_dict, key=frequency_dict.get)\n return max_freq_item", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(input_list):\n \"\"\"\n Function to find the item with maximum frequency in a given list.\n \"\"\"\n # Create a dictionary to store item frequencies\n item_freq = {}\n\n # Iterate over the list\n for item in input_list:\n if item in item_freq:\n item_freq[item] += 1\n else:\n item_freq[item] = 1\n\n # Find item(s) with maximum frequency\n max_freq = max(item_freq.values())\n max_freq_items = [item for item, freq in item_freq.items() if freq == max_freq]\n\n # If there is only one item with maximum frequency, return it\n if len(max_freq_items) == 1:\n return max_freq_items[0]\n else:\n # If there are multiple items with the same maximum frequency, return the first one\n return max_freq_items[0]", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(lst):\n \"\"\"Find the item with maximum frequency in a given list.\"\"\"\n # create an empty dictionary\n freq_dict = {}\n\n # iterate through the list\n for item in lst:\n # if item is already in the dictionary, increment its count\n if item in freq_dict:\n freq_dict[item] += 1\n # if item is not in the dictionary, add it with a count of 1\n else:\n freq_dict[item] = 1\n\n # find the item with the maximum frequency\n max_freq_item = max(freq_dict, key=freq_dict.get)\n\n return max_freq_item", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(num_list):\n num_dict = {}\n for num in num_list:\n if num in num_dict:\n num_dict[num] += 1\n else:\n num_dict[num] = 1\n\n max_freq = 0\n max_num = None\n\n for num, freq in num_dict.items():\n if freq > max_freq:\n max_freq = freq\n max_num = num\n\n return max_num", "matching_cluster_idx": 3}]}, "Mbpp/137": {"dps": 53.1409168081494, "dps_norm": 67.76315789473684, "pass@1": 19.0, "profiled": [{"solution": "import math\ndef zero_count(arr):\n \"\"\"\n Function to find the ratio of zeroes to non-zeroes in an array of integers.\n \"\"\"\n zero_count = arr.count(0)\n non_zero_count = len(arr) - zero_count\n return zero_count / non_zero_count if non_zero_count != 0 else math.inf\narr = [0, 1, 2, -1, -5, 6, 0, -3, -2, 3, 4, 6, 8]", "matching_cluster_idx": 7}, {"solution": "import math\ndef zero_count(array):\n total = len(array)\n zeroes = array.count(0)\n non_zeroes = total - zeroes\n ratio = zeroes/non_zeroes if non_zeroes != 0 else float('inf')\n return ratio", "matching_cluster_idx": 6}, {"solution": "import math\ndef zero_count(arr):\n \"\"\"\n Returns the ratio of zeroes to non-zeroes in an array of integers.\n \"\"\"\n zeroes = arr.count(0)\n non_zeroes = len(arr) - zeroes\n \n if non_zeroes == 0:\n return float('inf') # assuming ratio of zeroes to non-zeroes is infinite\n return zeroes / non_zeroes\narr = [0, 1, 2, -1, -5, 6, 0, -3, -2, 3, 4, 6, 8]", "matching_cluster_idx": 7}, {"solution": "import math\ndef zero_count(array):\n \"\"\"Function to find the ratio of zeroes to non-zeroes in an array of integers\"\"\"\n\n # Count zeroes and non-zeroes\n zeroes = array.count(0)\n non_zeroes = len(array) - zeroes\n\n # Handle case when non-zeroes are 0\n if non_zeroes == 0:\n return float('inf')\n\n # Calculate ratio\n ratio = zeroes / non_zeroes\n\n return ratio", "matching_cluster_idx": 6}, {"solution": "import math\ndef zero_count(array):\n zero_count = sum(1 for i in array if i == 0)\n non_zero_count = len(array) - zero_count\n return zero_count / non_zero_count if non_zero_count != 0 else float('inf')", "matching_cluster_idx": 5}, {"solution": "import math\ndef zero_count(array):\n zero_count = 0\n non_zero_count = 0\n for i in array:\n if i == 0:\n zero_count += 1\n else:\n non_zero_count += 1\n return zero_count / non_zero_count if non_zero_count != 0 else float('inf')", "matching_cluster_idx": 3}, {"solution": "from typing import List\nimport math\ndef zero_count(nums: List[int]) -> float:\n zero_count = len([num for num in nums if num == 0])\n non_zero_count = len([num for num in nums if num != 0])\n return zero_count / non_zero_count if non_zero_count != 0 else math.inf", "matching_cluster_idx": 2}, {"solution": "import math\ndef zero_count(arr):\n zero_count = sum(1 for i in arr if i==0)\n non_zero_count = len(arr) - zero_count\n return zero_count / non_zero_count if non_zero_count != 0 else float('inf')", "matching_cluster_idx": 5}, {"solution": "import math\nfrom typing import List\ndef zero_count(arr: List[int]) -> float:\n zeroes = len([num for num in arr if num == 0])\n non_zeroes = len([num for num in arr if num != 0])\n return zeroes / non_zeroes if non_zeroes != 0 else float('inf')", "matching_cluster_idx": 2}, {"solution": "import math\ndef zero_count(arr):\n total = len(arr)\n zeroes = arr.count(0)\n non_zeroes = total - zeroes\n return zeroes / non_zeroes if non_zeroes != 0 else float('inf')", "matching_cluster_idx": 6}, {"solution": "import math\ndef zero_count(lst):\n \"\"\"\n Function that returns the ratio of zeroes to non-zeroes in a list of integers.\n \"\"\"\n if len(lst) == 0:\n return 0.0\n else:\n zero_count = lst.count(0)\n nonzero_count = len(lst) - zero_count\n return zero_count / nonzero_count if nonzero_count != 0 else math.inf", "matching_cluster_idx": 6}, {"solution": "import math\ndef zero_count(arr):\n zeroes = sum(1 for num in arr if num == 0)\n non_zeroes = sum(1 for num in arr if num != 0)\n ratio = zeroes / non_zeroes if non_zeroes != 0 else float('inf')\n return ratio", "matching_cluster_idx": 1}, {"solution": "import math\ndef zero_count(arr):\n zeroes = len([num for num in arr if num == 0])\n non_zeroes = len(arr) - zeroes\n return zeroes / non_zeroes if non_zeroes != 0 else float('inf')", "matching_cluster_idx": 6}, {"solution": "import math\ndef zero_count(arr):\n zeroes = arr.count(0)\n non_zeroes = len(arr) - zeroes\n return zeroes / non_zeroes if non_zeroes != 0 else float('inf')", "matching_cluster_idx": 6}, {"solution": "import math\ndef zero_count(arr):\n zeroes = arr.count(0)\n non_zeroes = len(arr) - zeroes\n return zeroes / non_zeroes if non_zeroes != 0 else float('inf')", "matching_cluster_idx": 6}, {"solution": "import math\ndef zero_count(arr):\n zero_count = sum(1 for i in arr if i == 0)\n non_zero_count = len(arr) - zero_count\n return zero_count / non_zero_count if non_zero_count != 0 else float('inf')", "matching_cluster_idx": 5}, {"solution": "import math\ndef zero_count(arr):\n if not arr:\n return 0.0\n zero_count = sum(1 for num in arr if num == 0)\n nonzero_count = sum(1 for num in arr if num != 0)\n return zero_count / nonzero_count if nonzero_count != 0 else math.inf", "matching_cluster_idx": 1}, {"solution": "import math\ndef zero_count(arr):\n \"\"\"\n Function to find the ratio of zeroes to non-zeroes in an array of integers.\n\n :param arr: list of integers\n :return: ratio of zeroes to non-zeroes\n \"\"\"\n # Check that arr is a list\n if not isinstance(arr, list):\n raise TypeError(\"arr must be a list\")\n\n # Check that all elements in arr are integers\n if not all(isinstance(i, int) for i in arr):\n raise ValueError(\"All elements in arr must be integers\")\n\n # Count zeroes and non-zeroes\n zeroes = arr.count(0)\n non_zeroes = len(arr) - zeroes\n\n # Handle division by zero\n if non_zeroes == 0:\n return float('inf')\n\n return zeroes / non_zeroes\narr = [0, 1, 2, -1, -5, 6, 0, -3, -2, 3, 4, 6, 8]", "matching_cluster_idx": 2}, {"solution": "import math\ndef zero_count(arr):\n zeroes = len(list(filter(lambda x: x == 0, arr)))\n non_zeroes = len(arr) - zeroes\n return zeroes / non_zeroes if non_zeroes != 0 else math.inf", "matching_cluster_idx": 2}]}, "Mbpp/140": {"dps": 45.559006211180126, "dps_norm": 64.375, "pass@1": 83.0, "profiled": [{"solution": "def extract_singly(list_of_lists):\n flat_list = [item for sublist in list_of_lists for item in sublist]\n return set(flat_list)", "matching_cluster_idx": 5}, {"solution": "def extract_singly(list_of_lists):\n return set(num for sublist in list_of_lists for num in sublist)", "matching_cluster_idx": 5}, {"solution": "def extract_singly(nested_list):\n \"\"\"\n Function to flatten the list of lists into a single set of numbers.\n \"\"\"\n # Initializing empty set\n extracted_set = set()\n \n # Iterate over each list in the nested list\n for sub_list in nested_list:\n # Iterate over each element in the sub_list\n for element in sub_list:\n # Add the element to the set\n extracted_set.add(element)\n \n return extracted_set", "matching_cluster_idx": 3}, {"solution": "def extract_singly(list_of_lists):\n \"\"\"\n Takes a list of lists as input and returns a set of unique values from that list.\n \"\"\"\n flattened_list = []\n\n for sublist in list_of_lists:\n for item in sublist:\n flattened_list.append(item)\n\n # Converts the list to a set to remove duplicate values\n flattened_set = set(flattened_list)\n return flattened_set", "matching_cluster_idx": 4}, {"solution": "def extract_singly(lst):\n result = []\n for sublist in lst:\n for item in sublist:\n result.append(item)\n return set(result)", "matching_cluster_idx": 4}, {"solution": "def extract_singly(list_of_tuples):\n \"\"\"Flatten the list of lists into a single set of numbers.\n \n Parameters:\n list_of_tuples (list): A list of tuples.\n\n Returns:\n set: A set of numbers.\n\n Example:\n >>> extract_singly([(3, 4, 5), (4, 5, 7), (1, 4)])\n {1, 3, 4, 5, 7}\n \"\"\"\n result = set()\n for tup in list_of_tuples:\n for num in tup:\n result.add(num)\n return result", "matching_cluster_idx": 3}, {"solution": "def extract_singly(nested_lists):\n \"\"\"Function to flatten the list of lists into a single set of numbers.\"\"\"\n flat_list = []\n for sublist in nested_lists:\n for item in sublist:\n flat_list.append(item)\n return set(flat_list)", "matching_cluster_idx": 4}, {"solution": "def extract_singly(list_of_tuples):\n \"\"\"Extracts and flattens list of tuples into a single list of numbers.\"\"\"\n return [num for tup in list_of_tuples for num in tup]", "matching_cluster_idx": 5}, {"solution": "def extract_singly(nested_list):\n # Create an empty set to hold flattened elements\n flattened_set = set()\n\n # Iterate over each sub-list in the nested list\n for sub_list in nested_list:\n # Iterate over each item in the sub-list\n for item in sub_list:\n # Add the item to the set\n flattened_set.add(item)\n\n # Return the set of flattened elements\n return flattened_set", "matching_cluster_idx": 4}, {"solution": "def extract_singly(list_of_lists):\n return set([item for sublist in list_of_lists for item in sublist])", "matching_cluster_idx": 5}, {"solution": "def extract_singly(lst):\n return set(num for sublist in lst for num in sublist)", "matching_cluster_idx": 5}, {"solution": "def extract_singly(list_of_tuples):\n result = set() # Create an empty set\n for tuple_item in list_of_tuples: # Go through each tuple in the list\n for num in tuple_item: # Go through each number in the tuple\n result.add(num) # Add the number to the set\n return result", "matching_cluster_idx": 3}, {"solution": "def extract_singly(list_of_lists):\n return set([item for sublist in list_of_lists for item in sublist])", "matching_cluster_idx": 5}, {"solution": "def extract_singly(list_of_lists):\n # Initialize an empty set\n singly_set = set()\n\n # Iterate through each list in the input\n for one_list in list_of_lists:\n # Add each item in the list to the set\n for item in one_list:\n singly_set.add(item)\n \n # Return the populated set\n return singly_set", "matching_cluster_idx": 3}, {"solution": "def extract_singly(lists):\n \"\"\"\n This function takes a list of tuples or lists and returns a single set of unique numbers.\n \"\"\"\n result = set()\n for l in lists:\n for item in l:\n result.add(item)\n return result", "matching_cluster_idx": 3}, {"solution": "def extract_singly(list_of_tuples):\n result = set()\n for t in list_of_tuples:\n for num in t:\n result.add(num)\n return result", "matching_cluster_idx": 4}, {"solution": "def extract_singly(input_list):\n output_set = set()\n for sublist in input_list:\n for item in sublist:\n output_set.add(item)\n return output_set", "matching_cluster_idx": 4}, {"solution": "def extract_singly(input_list):\n # initialize an empty set\n result_set = set()\n \n # iterate over the list of tuples\n for tup in input_list:\n # add each element of the tuple to the set\n result_set.update(tup)\n \n return result_set", "matching_cluster_idx": 6}, {"solution": "def extract_singly(list_of_tuples):\n result = set()\n for t in list_of_tuples:\n for x in t:\n result.add(x)\n return result", "matching_cluster_idx": 4}, {"solution": "def extract_singly(list_of_lists):\n result = set() # Define an empty set\n for sub_list in list_of_lists: # Iterate over each sublist in the main list\n for element in sub_list: # Iterate over each element in the sublist\n result.add(element) # Add each element to the result set\n return result", "matching_cluster_idx": 4}]}, "Mbpp/141": {"dps": 82.38095238095238, "dps_norm": 45.625, "pass@1": 85.0, "profiled": [{"solution": "def pancake_sort(arr):\n for size in reversed(range(len(arr))):\n max_index = arr.index(max(arr[:size+1]))\n if max_index != size:\n arr = arr[max_index::-1] + arr[max_index+1:]\n arr = arr[size::-1] + arr[size+1:]\n return arr", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(lst):\n \"\"\"\n Function to sort a list of elements.\n \"\"\"\n for size in reversed(range(len(lst))):\n max_ind = max(range(size + 1), key=lst.__getitem__)\n if max_ind != size:\n # Perform pancake flip\n lst[0:max_ind+1] = reversed(lst[0:max_ind+1])\n lst[0:size+1] = reversed(lst[0:size+1])\n return lst", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(lst):\n for size in reversed(range(len(lst))):\n max_ind = max(range(size+1), key=lst.__getitem__)\n if max_ind != size:\n lst[0:max_ind+1] = reversed(lst[0:max_ind+1])\n lst[0:size+1] = reversed(lst[0:size+1])\n return lst", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(lst):\n def flip(arr, i):\n start = 0\n while start < i:\n arr[start], arr[i] = arr[i], arr[start]\n start += 1\n i -= 1\n\n n = len(lst)\n for curr_size in reversed(range(2, n+1)):\n max_index = lst.index(max(lst[:curr_size]))\n if max_index != curr_size - 1:\n flip(lst, max_index)\n flip(lst, curr_size - 1)\n\n return lst", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(list):\n \"\"\"\n This function sorts the list by repeatedly finding the maximum number in the unsorted part of the list\n and moving it to the end. This process is done for the entire list, hence the name 'pancake sort'.\n \"\"\"\n # Get the length of the list\n length = len(list)\n\n # Loop through the list from the last to the first\n for curr_size in reversed(range(length)):\n # Get the index of maximum number in the list[0...curr_size]\n max_idx = list.index(max(list[:curr_size+1]))\n\n # If the maximum number is not at the end of the list\n if max_idx != curr_size:\n # If the maximum number is at the beginning, move it to the end\n if max_idx != 0:\n list[:max_idx+1] = reversed(list[:max_idx+1])\n \n # Reverse the list from 0 to curr_size\n list[:curr_size+1] = reversed(list[:curr_size+1])\n \n # Return the sorted list\n return list", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(lst):\n \"\"\"\n Function to sort a list of elements using pancake sort\n \"\"\"\n for size in reversed(range(len(lst))):\n max_ind = max(range(size + 1), key = lst.__getitem__)\n if max_ind != size:\n lst[0:max_ind+1] = reversed(lst[0:max_ind+1])\n lst[0:size+1] = reversed(lst[0:size+1])\n return lst", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(lst):\n # Base case\n if len(lst) <= 1:\n return lst\n # Recursive case\n else:\n max_index = lst.index(max(lst))\n if max_index != len(lst) - 1: \n # flip the list so the max number is on the bottom\n lst = lst[max_index::-1] + lst[max_index+1:]\n # flip the list so the max number is on the top\n lst = lst[::-1]\n # recursively sort the rest of the list\n return pancake_sort(lst[:-1]) + list(lst[-1:])", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(lst):\n \"\"\"\n Pancake sort function.\n This function is a variant of bubble sort that uses the concept of 'pancakes' from the cooking analogy.\n It is an efficient sorting algorithm, not requiring any nested loops, and is not adaptive (making it faster on sorted data).\n \"\"\"\n def flip(arr, i):\n \"\"\"Flip arr[0..i]\"\"\"\n start = 0\n while start < i:\n arr[start], arr[i] = arr[i], arr[start]\n start += 1\n i -= 1\n\n n = len(lst)\n\n # Start from the complete array and one by one\n # reduce current size by one\n for curr_size in reversed(range(n)):\n # Find index of the maximum element\n # in lst[0..curr_size]\n max_idx = lst.index(max(lst[:curr_size + 1]))\n\n # Move the maximum element to end of\n # current array if it's not already at\n # the end\n if max_idx != curr_size:\n # To move at the end, first\n # move maximum number to beginning\n flip(lst, max_idx)\n\n # Now move the maximum number\n # to end by reversing current array\n flip(lst, curr_size)\n\n return lst", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(num_list):\n # Length of list\n n = len(num_list)\n\n # Traverse through all list elements\n for cur_size in reversed(range(2, n+1)):\n max_index = num_list.index(max(num_list[0:cur_size]))\n if max_index != cur_size-1:\n # To move at the end, first move maximum number to beginning\n num_list[0:max_index+1] = reversed(num_list[0:max_index+1])\n\n # Now move the maximum number to end by reversing current array\n num_list[0:cur_size] = reversed(num_list[0:cur_size])\n\n return num_list", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(lst):\n if len(lst) <= 1:\n return lst\n for size in reversed(range(len(lst))):\n max_ind = max(range(size + 1), key=lst.__getitem__)\n if max_ind != size:\n lst = lst[:max_ind+1][::-1] + lst[max_ind+1:]\n lst = lst[:size+1][::-1] + lst[size+1:]\n return lst", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(lst):\n for size in reversed(range(len(lst))):\n max_ind = max(range(size+1), key=lst.__getitem__)\n if max_ind != size:\n lst[0:max_ind+1] = reversed(lst[0:max_ind+1])\n lst[0:size+1] = reversed(lst[0:size+1])\n return lst", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(lst):\n \"\"\"\n This function implements the Pancake Sort algorithm.\n This is a much-hyped sorting algorithm in competitive programming circles.\n \"\"\"\n def flip(arr, i):\n \"\"\"\n Reverse array elements from 0 to i\n \"\"\"\n start = 0\n while start < i:\n temp = arr[start]\n arr[start] = arr[i]\n arr[i] = temp\n start += 1\n i -= 1\n\n n = len(lst)\n # Start from the complete array and reduce current size by one\n for curr_size in range(n-1, 0, -1):\n # Find index of the maximum element in lst[0..curr_size]\n max_index = 0\n for i in range(1, curr_size + 1):\n if lst[i] > lst[max_index]:\n max_index = i\n\n # If not already sorted, flip max element to beginning\n if max_index != curr_size:\n flip(lst, max_index)\n flip(lst, curr_size)\n return lst", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(arr):\n def flip(arr, i):\n start = 0\n while start < i:\n temp = arr[start]\n arr[start] = arr[i]\n arr[i] = temp\n start += 1\n i -= 1\n\n n = len(arr)\n for curr_size in reversed(range(n)):\n max_ind = arr.index(max(arr[:curr_size + 1]))\n if max_ind != curr_size:\n flip(arr, max_ind)\n flip(arr, curr_size)\n return arr", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(arr):\n n = len(arr)\n # Loop through each element of the array\n for curr_size in reversed(range(n)):\n max_index = 0\n # Find index of the max element in remaining unsorted array\n for i in range(1, curr_size + 1):\n if arr[i] > arr[max_index]:\n max_index = i\n # Move max element to end of unsorted array\n if max_index != curr_size:\n arr = reverse_arr(arr, max_index)\n arr = reverse_arr(arr, curr_size)\n return arr\ndef reverse_arr(arr, i):\n # Helper function to reverse array from 0 to i\n start = 0\n while start < i:\n arr[start], arr[i] = arr[i], arr[start]\n start += 1\n i -= 1\n return arr", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(nums):\n for i in range(len(nums)-1, 0, -1):\n max_index = nums.index(max(nums[:i+1]))\n if max_index != i:\n if max_index != 0:\n nums[:max_index+1] = reversed(nums[:max_index+1])\n nums[:i+1] = reversed(nums[:i+1])\n return nums", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(lst):\n for size in reversed(range(len(lst))):\n max_ind = max(range(size + 1), key = lst.__getitem__)\n if max_ind != size:\n # This indexed max needs moving\n if max_ind != 0:\n # Flip the max item to the left\n lst[:max_ind+1] = reversed(lst[:max_ind+1])\n # Then flip it to the right\n lst[:size+1] = reversed(lst[:size+1])\n return lst", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(arr):\n n = len(arr)\n for size in reversed(range(n)):\n max_index = 0\n for i in range(1, size + 1):\n if arr[i] > arr[max_index]:\n max_index = i\n if max_index != size:\n arr[0:max_index+1] = reversed(arr[0:max_index+1])\n arr[0:size+1] = reversed(arr[0:size+1])\n return arr", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(lst):\n def flip(arr, i):\n start = 0\n while start < i:\n temp = arr[start]\n arr[start] = arr[i]\n arr[i] = temp\n start += 1\n i -= 1\n\n n = len(lst)\n for curr_size in reversed(range(n)):\n max_index = max(range(curr_size + 1), key=lst.__getitem__)\n if max_index != curr_size:\n flip(lst, max_index)\n flip(lst, curr_size)\n return lst", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(arr):\n for size in reversed(range(len(arr))):\n max_ind = max(range(size+1), key=arr.__getitem__)\n if max_ind != size:\n arr[0:max_ind+1] = reversed(arr[0:max_ind+1])\n arr[0:size+1] = reversed(arr[0:size+1])\n return arr", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(lst):\n for size in reversed(range(len(lst))):\n max_ind = max(range(size+1), key=lst.__getitem__)\n if max_ind != size:\n lst[0:max_ind+1] = reversed(lst[0:max_ind+1])\n lst[0:size+1] = reversed(lst[0:size+1])\n return lst", "matching_cluster_idx": 3}]}, "Mbpp/166": {"dps": 97.71999999999998, "dps_norm": 81.25, "pass@1": 42.0, "profiled": [{"solution": "def find_even_pair(numbers):\n even_count = len([num for num in numbers if num % 2 == 0])\n odd_count = len(numbers) - even_count\n return even_count * (even_count - 1) // 2 + odd_count * (odd_count - 1) // 2", "matching_cluster_idx": 3}, {"solution": "def find_even_pair(lst):\n even = 0\n odd = 0\n for num in lst:\n if num & 1:\n odd += 1\n else:\n even += 1\n\n return even * (even - 1) // 2 + odd * (odd - 1) // 2", "matching_cluster_idx": 2}, {"solution": "def find_even_pair(lst):\n even = sum(1 for num in lst if num % 2 == 0)\n odd = len(lst) - even\n return even * (even - 1) // 2 + odd * (odd - 1) // 2", "matching_cluster_idx": 3}, {"solution": "def find_even_pair(nums):\n even = sum(num % 2 == 0 for num in nums)\n odd = len(nums) - even\n return even * (even - 1) // 2 + odd * (odd - 1) // 2", "matching_cluster_idx": 3}, {"solution": "def find_even_pair(nums):\n even_count = len([i for i in nums if i % 2 == 0])\n odd_count = len(nums) - even_count\n\n # For any two numbers x and y, x XOR y is even if and only if x and y have the same parity (both even or both odd). \n # This means the number of pairs x XOR y to be even is the sum of the counts of the even numbers and the counts of the odd numbers.\n return even_count * (even_count - 1) // 2 + odd_count * (odd_count - 1) // 2", "matching_cluster_idx": 3}, {"solution": "def find_even_pair(lst):\n even_count = len([i for i in lst if i % 2 == 0])\n odd_count = len(lst) - even_count\n return even_count * (even_count - 1) // 2 + odd_count * (odd_count - 1) // 2", "matching_cluster_idx": 3}, {"solution": "def find_even_pair(lst):\n even = sum(1 for i in lst if i % 2 == 0)\n odd = len(lst) - even\n return even * (even - 1) // 2 + odd * (odd - 1) // 2", "matching_cluster_idx": 3}, {"solution": "def find_even_pair(lst):\n count = 0\n n = len(lst)\n for i in range(0, n):\n for j in range(i + 1, n):\n if (lst[i] ^ lst[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(nums):\n \"\"\"\n Counts the number of pairs in nums that xor to an even number\n \"\"\"\n even_count = len(list(filter(lambda x: x % 2 == 0, nums)))\n odd_count = len(nums) - even_count\n\n return even_count * (even_count - 1) // 2 + odd_count * (odd_count - 1) // 2", "matching_cluster_idx": 2}, {"solution": "def find_even_pair(lst):\n even = sum(1 for num in lst if num % 2 == 0)\n odd = len(lst) - even\n return even * (even - 1) // 2 + odd * (odd - 1) // 2", "matching_cluster_idx": 3}, {"solution": "def find_even_pair(lst):\n even_count = 0\n odd_count = 0\n\n for num in lst:\n if num % 2 == 0:\n even_count += 1\n else:\n odd_count += 1\n\n return even_count * (even_count - 1) // 2 + odd_count * (odd_count - 1) // 2", "matching_cluster_idx": 2}, {"solution": "def find_even_pair(lst):\n count = 0\n for i in range(len(lst)):\n for j in range(i+1, len(lst)):\n if (lst[i] ^ lst[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(arr):\n even = sum(1 for num in arr if num % 2 == 0)\n odd = len(arr) - even\n return even * (even - 1) // 2 + odd * (odd - 1) // 2", "matching_cluster_idx": 3}, {"solution": "def find_even_pair(nums):\n even_count = sum(x % 2 == 0 for x in nums)\n return even_count * (even_count - 1) // 2 + (len(nums) - even_count) * (len(nums) - even_count - 1) // 2", "matching_cluster_idx": 3}, {"solution": "def find_even_pair(lst):\n even_count = sum(1 for num in lst if num % 2 == 0)\n odd_count = len(lst) - even_count\n return even_count * (even_count - 1) // 2 + odd_count * (odd_count - 1) // 2", "matching_cluster_idx": 3}, {"solution": "def find_even_pair(num_list):\n count = 0\n for i in range(len(num_list)):\n for j in range(i+1, len(num_list)):\n if (num_list[i] ^ num_list[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(lst):\n count = 0\n for i in range(len(lst)):\n for j in range(i + 1, len(lst)):\n # XOR operation\n xor_result = lst[i] ^ lst[j]\n # Check if the XOR result is even\n if xor_result % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(lst):\n count = 0\n for i in range(len(lst)):\n for j in range(i+1, len(lst)):\n if (lst[i] ^ lst[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(arr):\n count = 0\n for i in range(len(arr)):\n for j in range(i + 1, len(arr)):\n xor = arr[i] ^ arr[j]\n if xor % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(num_list):\n even_count = sum(1 for num in num_list if num % 2 == 0)\n odd_count = len(num_list) - even_count\n return even_count * (even_count - 1) // 2 + odd_count * (odd_count - 1) // 2", "matching_cluster_idx": 3}]}, "Mbpp/170": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 78.0, "profiled": [{"solution": "def sum_range_list(lst, start_idx, end_idx):\n return sum(lst[start_idx:end_idx+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(num_list, start_idx, end_idx):\n \"\"\"\n Function to find the sum of numbers in a list within a range specified by two indices.\n \"\"\"\n\n return sum(num_list[start_idx:end_idx+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(lst, start, end):\n return sum(lst[start:end+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(lst, start, end):\n return sum(lst[start:end+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(lst, start, end):\n \"\"\"\n Find the sum of numbers in a list within a range specified by two indices.\n\n :param lst: list of numbers\n :param start: start index\n :param end: end index\n :return: sum of numbers within the range\n \"\"\"\n return sum(lst[start:end+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(lst, start, end):\n \"\"\"\n Given a list of integers and two indices, this function returns the sum\n of all the numbers within the range specified by the two indices.\n \"\"\"\n return sum(lst[start:end+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(list_of_nums, start_index, end_index):\n return sum(list_of_nums[start_index:end_index+1])\nlist_of_nums = [2,1,5,6,8,3,4,9,10,11,8,12]\nstart_index = 8\nend_index = 10", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(lst, start, end):\n return sum(lst[start:end+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(nums, index1, index2):\n return sum(nums[index1:index2+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(lst, start_index, end_index):\n return sum(lst[start_index:end_index+1])\nlst = [2,1,5,6,8,3,4,9,10,11,8,12]\nstart_index = 8\nend_index = 10", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(num_list, start, end):\n return sum(num_list[start:end+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(nums, start, end):\n return sum(nums[start:end+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(num_list, start, end):\n return sum(num_list[start:end+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(num_list, start_index, end_index):\n \"\"\"\n Function to find the sum of numbers in a list within a range specified by two indices.\n :param num_list: list of numbers\n :param start_index: start index\n :param end_index: end index\n :return: sum of numbers in num_list from start_index to end_index\n \"\"\"\n return sum(num_list[start_index:end_index+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(nums, start, end):\n \"\"\"\n This function takes a list of numbers and two indices and returns the sum of the numbers between these two indices.\n \"\"\"\n return sum(nums[start:end+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(lst, start, end):\n return sum(lst[start:end+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(num_list, start_index, end_index):\n return sum(num_list[start_index:end_index + 1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(nums, start, end):\n return sum(nums[start:end+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(lst, start, end):\n return sum(lst[start:end+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(num_list, start, end):\n \"\"\"\n Returns the sum of numbers within a list given start and end indices.\n \"\"\"\n return sum(num_list[start:end+1])", "matching_cluster_idx": 7}]}, "Mbpp/226": {"dps": 70.15503875968992, "dps_norm": 17.857142857142858, "pass@1": 98.0, "profiled": [{"solution": "def odd_values_string(input_str):\n \"\"\"\n Function to remove the characters which have odd index values of a given string.\n \"\"\"\n return ''.join(char for index, char in enumerate(input_str) if index % 2 == 0)", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(str):\n result = \"\"\n for i in range(len(str)):\n if i % 2 == 0:\n result += str[i]\n return result", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(input_string):\n result = \"\"\n for i in range(len(input_string)):\n if i % 2 == 0:\n result += input_string[i]\n return result", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(input_str):\n return ''.join([input_str[i] for i in range(len(input_str)) if i % 2 == 0])", "matching_cluster_idx": 1}, {"solution": "def odd_values_string(input_string):\n \"\"\"\n This function returns a new string containing the characters of the input string \n which are at an even index position (considering 0 as the first index).\n \"\"\"\n return ''.join([char for index, char in enumerate(input_string) if index % 2 == 0])", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(input_string):\n result = \"\"\n for i in range(len(input_string)):\n if i % 2 == 0:\n result += input_string[i]\n return result", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(s):\n return ''.join(s[i] for i in range(len(s)) if i % 2 == 0)", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(input_string):\n \"\"\"\n Removes characters from a given string with odd index values.\n :param input_string: The string from which to remove characters.\n :return: The resulting string.\n \"\"\"\n return ''.join([input_string[i] for i in range(len(input_string)) if i % 2 == 0])", "matching_cluster_idx": 1}, {"solution": "def odd_values_string(input_string):\n return ''.join([input_string[i] for i in range(len(input_string)) if i % 2 == 0])", "matching_cluster_idx": 1}, {"solution": "def odd_values_string(input_string):\n result = \"\"\n for i in range(len(input_string)):\n if i % 2 == 0:\n result += input_string[i]\n return result", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(input_str):\n \"\"\"\n Write a python function to remove the characters which have odd index values of a given string.\n \"\"\"\n return ''.join(input_str[i] for i in range(len(input_str)) if i % 2 == 0)", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(input_string):\n return \"\".join([char for index, char in enumerate(input_string) if index % 2 == 0])", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(input_string):\n return ''.join([v for i, v in enumerate(input_string) if i % 2 == 0])", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(input_string):\n \"\"\"\n Remove characters with odd index values from a given string.\n\n Parameters:\n input_string (str): input string\n\n Returns:\n str: string after removing characters with odd index values\n \"\"\"\n # Return a string of characters with even index values\n return ''.join([input_string[i] for i in range(len(input_string)) if i % 2 == 0])", "matching_cluster_idx": 1}, {"solution": "def odd_values_string(input_string):\n return \"\".join([char for index, char in enumerate(input_string) if index % 2 == 0])", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(input_string):\n # Using list comprehension to get characters with even indices (0-indexed)\n return ''.join([input_string[i] for i in range(len(input_string)) if i % 2 == 0])", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(input_string):\n result = \"\"\n for i in range(len(input_string)):\n if i % 2 == 0:\n result += input_string[i]\n return result", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(str):\n result = \"\"\n for i in range(len(str)):\n if i % 2 == 0:\n result += str[i]\n return result", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(input_str):\n return ''.join([input_str[i] for i in range(len(input_str)) if i % 2 == 0])", "matching_cluster_idx": 1}, {"solution": "def odd_values_string(input_string):\n result_string = ''\n for i in range(len(input_string)):\n if i % 2 == 0:\n result_string += input_string[i]\n return result_string", "matching_cluster_idx": 0}]}, "Mbpp/230": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def replace_blank(string, char):\n return string.replace(' ', char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(s: str, c: str) -> str:\n return s.replace(' ', c)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string, replacement_char):\n return input_string.replace(' ', replacement_char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(s, c):\n return s.replace(' ', c)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(s, char):\n return s.replace(\" \", char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(string, char):\n \"\"\"\n Replaces blank spaces in the string with the provided character.\n \"\"\"\n # Replace blank spaces in the string with the character\n new_string = string.replace(' ', char)\n\n # Return the result\n return new_string", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string, replacement_character):\n # Replace each space with the replacement character\n return input_string.replace(' ', replacement_character)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(str_input, char_input):\n return str_input.replace(' ', char_input)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(s, char):\n return s.replace(' ', char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_str, char):\n \"\"\"\n This function replaces blank spaces in the string with the specified character.\n\n Parameters:\n input_str (str): The input string.\n char (str): The character to replace blank spaces.\n\n Returns:\n str: The modified string.\n \"\"\"\n return input_str.replace(\" \", char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string, char):\n \"\"\"\n This function replaces all blank spaces in a string with a character.\n \"\"\"\n return input_string.replace(' ', char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(s, char):\n \"\"\"Replace spaces in string s with character char and return the result.\"\"\"\n return s.replace(' ', char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string, character):\n return input_string.replace(\" \", character)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(s: str, char: str) -> str:\n return s.replace(\" \", char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string, character):\n return input_string.replace(' ', character)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(s, c):\n return s.replace(' ', c)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(string, char):\n return string.replace(' ', char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(string, char):\n return string.replace(\" \", char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_str: str, char: str) -> str:\n \"\"\"\n This function replaces blank spaces in the input string with the provided character and returns the string.\n :param input_str: The input string to be processed.\n :param char: The character to replace blank spaces with.\n :return: The processed string.\n \"\"\"\n return input_str.replace(\" \", char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_str, replacement_char):\n \"\"\"\n Function that takes in a string and character, \n replaces blank spaces in the string with the character, and returns the string.\n\n :param input_str: The input string\n :param replacement_char: Character to replace blank spaces with\n :return: The modified string\n \"\"\"\n return input_str.replace(' ', replacement_char)", "matching_cluster_idx": 7}]}, "Mbpp/239": {"dps": null, "dps_norm": null, "pass@1": 7.0, "profiled": []}, "Mbpp/240": {"dps": 73.47560975609757, "dps_norm": 83.33333333333333, "pass@1": 61.0, "profiled": [{"solution": "def replace_list(list1, list2):\n list1[-1:] = list2\n return list1", "matching_cluster_idx": 7}, {"solution": "def replace_list(first_list, second_list):\n first_list.pop() # Remove the last element of the first list\n for i in second_list:\n first_list.append(i) # Add the elements of the second list to the first list\n return first_list", "matching_cluster_idx": 3}, {"solution": "def replace_list(list1, list2):\n list1[-1:] = list2\n return list1", "matching_cluster_idx": 7}, {"solution": "def replace_list(list1, list2):\n \"\"\"\n Replaces the last element of the first list with the elements of the second list.\n\n Args:\n list1 (list): The list where the last element is to be replaced.\n list2 (list): The list containing elements to replace the last element of the first list.\n\n Returns:\n list: A new list where the last element of the first list is replaced by the elements of the second list.\n \"\"\"\n list1[-1:] = list2\n return list1", "matching_cluster_idx": 7}, {"solution": "def replace_list(list1, list2):\n list1[-1:] = list2\n return list1", "matching_cluster_idx": 7}, {"solution": "def replace_list(list1, list2):\n list1[-1:] = list2\n return list1", "matching_cluster_idx": 7}, {"solution": "def replace_list(list1, list2):\n # Pop last element from list1\n list1.pop()\n # Append list2 to list1\n list1.extend(list2)\n return list1", "matching_cluster_idx": 8}, {"solution": "def replace_list(first_list, second_list):\n \"\"\"\n Function to replace the last element of the first list with the elements of the second list\n \"\"\"\n\n # Replace the last element of first_list with elements of second_list\n first_list[-1:] = second_list\n\n # Return the modified list\n return first_list", "matching_cluster_idx": 7}, {"solution": "def replace_list(list1, list2):\n # Remove the last element of the first list\n list1 = list1[:-1]\n # Append elements of the second list to the end of the first list\n list1.extend(list2)\n return list1", "matching_cluster_idx": 6}, {"solution": "def replace_list(list1, list2):\n \"\"\"\n Replace last element of first list with second list.\n\n Parameters:\n list1 (list): Original list.\n list2 (list): List to replace last element.\n\n Returns:\n list: Modified list.\n \"\"\"\n # Get all elements of list1 except the last one\n first_part = list1[:-1]\n # Add elements of list2 at the end\n first_part.extend(list2)\n return first_part", "matching_cluster_idx": 6}, {"solution": "def replace_list(list1, list2):\n list1 = list1[:-1] + list2\n return list1", "matching_cluster_idx": 5}, {"solution": "def replace_list(list1, list2):\n list1[-1:] = list2\n return list1", "matching_cluster_idx": 7}, {"solution": "def replace_list(list1, list2):\n list1[-1:] = list2\n return list1", "matching_cluster_idx": 7}, {"solution": "def replace_list(list1, list2):\n # Pop the last element of the first list\n list1.pop()\n # Add the elements of the second list\n list1.extend(list2)\n return list1", "matching_cluster_idx": 8}, {"solution": "def replace_list(list1, list2):\n # Remove the last element of list1 and add list2's elements to the end of list1\n list1 = list1[:-1] + list2\n return list1", "matching_cluster_idx": 5}, {"solution": "def replace_list(list1, list2):\n list1 = list1[:-1] + list2\n return list1", "matching_cluster_idx": 5}, {"solution": "def replace_list(list1, list2):\n list1[-1:] = list2\n return list1", "matching_cluster_idx": 7}, {"solution": "def replace_list(list1, list2):\n list1[-1:] = list2\n return list1", "matching_cluster_idx": 7}, {"solution": "def replace_list(first_list, second_list):\n first_list[-1:] = second_list\n return first_list", "matching_cluster_idx": 7}, {"solution": "def replace_list(list1, list2):\n # if list1 is not empty, replace its last element with elements of list2\n if list1:\n list1[-1:] = list2\n return list1", "matching_cluster_idx": 7}]}, "Mbpp/251": {"dps": 87.95977011494254, "dps_norm": 76.66666666666666, "pass@1": 95.0, "profiled": [{"solution": "def insert_element(input_list, element):\n result = []\n for i in input_list:\n result.append(element)\n result.append(i)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(input_list, element):\n result = []\n for i in input_list:\n result.append(element)\n result.append(i)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(input_list, element):\n result = []\n for i in input_list:\n result.append(element)\n result.append(i)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, elem):\n \"\"\"Inserts the element before each element in the list and returns the resulting list.\"\"\"\n\n # List comprehension solution\n return [elem for pair in [[elem, item] for item in lst] for elem in pair]", "matching_cluster_idx": 4}, {"solution": "def insert_element(lst, element):\n result = []\n for item in lst:\n result.append(element)\n result.append(item)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(input_list, element):\n result = []\n for i in input_list:\n result.append(element)\n result.append(i)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(input_list, element):\n \"\"\"\n Insert an element before each element in the list\n \"\"\"\n result = []\n for i in input_list:\n result.extend([element, i])\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, elem):\n result = []\n for i in lst:\n result.append(elem)\n result.append(i)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(my_list, element):\n \"\"\"\n This function takes in a list and an element and inserts the element before \n each element in the list, and returns the resulting list.\n \"\"\"\n output = []\n for item in my_list:\n output.extend([element, item])\n return output", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n \"\"\"\n Insert an element before each element in the list and return the resulting list.\n \"\"\"\n result = []\n for item in lst:\n result.extend([element, item])\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n new_list = []\n for item in lst:\n new_list.append(element)\n new_list.append(item)\n return new_list", "matching_cluster_idx": 6}, {"solution": "def insert_element(input_list, element):\n result = []\n for i in input_list:\n result.append(element)\n result.append(i)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n result = []\n for i in lst:\n result.append(element)\n result.append(i)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, elm):\n result = []\n for i in lst:\n result.extend([elm, i])\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n result = []\n for i in lst:\n result.append(element)\n result.append(i)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n result = []\n for i in lst:\n result.append(element)\n result.append(i)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, elem):\n \"\"\"\n Inserts an element before each element in the list and returns the resulting list.\n\n Args:\n lst (List): The list to insert elements into.\n elem (Any): The element to insert.\n\n Returns:\n List: The list with elements inserted.\n \"\"\"\n # initialize an empty list\n result = []\n\n # loop through the input list\n for i in lst:\n # insert the element before each element\n result.extend([elem, i])\n\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, elm):\n result = []\n for item in lst:\n result.append(elm)\n result.append(item)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, elem):\n result = []\n for i in lst:\n result.append(elem)\n result.append(i)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n new_list = []\n for item in lst:\n new_list.append(element)\n new_list.append(item)\n return new_list", "matching_cluster_idx": 6}]}, "Mbpp/256": {"dps": 68.83561643835617, "dps_norm": 63.529411764705884, "pass@1": 89.0, "profiled": [{"solution": "def count_Primes_nums(n):\n if n<2:\n return 0\n primes = [True] * n\n primes[0] = primes[1] = False\n for current in range(2, int(n**0.5)+1):\n if primes[current] == True:\n for multiple in range(current*current, n, current):\n primes[multiple] = False\n return sum(primes)", "matching_cluster_idx": 14}, {"solution": "def is_prime(n):\n \"\"\"\n A helper function that checks if a number is prime\n \"\"\"\n if n == 0 or n == 1:\n return False\n for x in range(2, int(n**0.5) + 1):\n if n % x == 0:\n return False\n return True\ndef count_Primes_nums(n):\n \"\"\"\n Main function that counts the number of prime numbers less than n\n \"\"\"\n count = 0\n for i in range(n):\n if is_prime(i):\n count += 1\n return count", "matching_cluster_idx": 8}, {"solution": "def count_Primes_nums(n):\n # zero and one are not prime numbers\n if n < 2:\n return 0\n primes = [True] * n\n primes[0] = primes[1] = False\n for current in range(2, int(n**0.5) + 1):\n if primes[current]:\n primes[current*current: n: current] = [False] * len(primes[current*current: n: current])\n return sum(primes)", "matching_cluster_idx": 15}, {"solution": "def count_Primes_nums(n):\n def is_prime(num):\n \"\"\"\n Helper function to check if a number is a prime number or not.\n \"\"\"\n if num < 2:\n return False\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n return False\n return True\n\n count = 0\n for i in range(2, n): # range starts from 2, not 1, because 1 is not a prime number\n if is_prime(i):\n count += 1\n return count", "matching_cluster_idx": 8}, {"solution": "def count_Primes_nums(n):\n def is_prime(num):\n if num < 2:\n return False\n for i in range(2, int(num ** 0.5) + 1):\n if num % i == 0:\n return False\n return True\n\n count = 0\n for i in range(2, n):\n if is_prime(i):\n count += 1\n\n return count", "matching_cluster_idx": 8}, {"solution": "def count_Primes_nums(n):\n if n < 2:\n return 0\n \n primes = [True] * n\n primes[0] = primes[1] = False\n\n for current in range(2, int(n ** 0.5) + 1):\n if primes[current] == True:\n for multiple in range(current*current, n, current):\n primes[multiple] = False\n\n return sum(primes)", "matching_cluster_idx": 14}, {"solution": "def count_Primes_nums(n):\n def is_prime(num):\n if num < 2:\n return False\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n return False\n return True\n\n count = 0\n for i in range(2, n):\n if is_prime(i):\n count += 1\n return count", "matching_cluster_idx": 8}, {"solution": "def count_Primes_nums(n: int) -> int:\n \"\"\"\n A python function that takes in a non-negative number and returns the number of prime numbers less than the given non-negative number.\n \"\"\"\n def is_prime(num: int) -> bool:\n if num < 2:\n return False\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n return False\n return True\n\n count = 0\n for i in range(2, n):\n if is_prime(i):\n count += 1\n return count", "matching_cluster_idx": 8}, {"solution": "def count_Primes_nums(n):\n if n < 2:\n return 0\n primes = [True] * (n)\n primes[0] = primes[1] = False\n for current in range(2, int(n ** 0.5) + 1):\n if primes[current]:\n for multiple in range(current * current, n, current):\n primes[multiple] = False\n return sum(primes)", "matching_cluster_idx": 14}, {"solution": "def count_Primes_nums(n):\n def is_prime(num):\n if num <= 1:\n return False\n elif num <= 3:\n return True\n elif num % 2 == 0 or num % 3 == 0:\n return False\n i = 5\n while i * i <= num:\n if num % i == 0 or num % (i + 2) == 0:\n return False\n i = i + 6\n return True\n\n count = 0\n for i in range(n):\n if is_prime(i):\n count += 1\n return count", "matching_cluster_idx": 10}, {"solution": "def count_Primes_nums(num):\n def is_prime(n):\n if n < 2:\n return False\n for i in range(2, int(n**0.5)+1):\n if n % i == 0:\n return False\n return True\n \n count = 0\n for i in range(2, num):\n if is_prime(i):\n count += 1\n return count", "matching_cluster_idx": 8}, {"solution": "def count_Primes_nums(n):\n def is_prime(num):\n if num < 2: return False\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n return False\n return True\n\n count = 0\n for i in range(n):\n if is_prime(i):\n count += 1\n return count", "matching_cluster_idx": 8}, {"solution": "def count_Primes_nums(n):\n if n < 2:\n return 0\n primes = [True]*n\n primes[0] = primes[1] = False\n for current in range(2, int(n ** 0.5) + 1):\n if primes[current]:\n primes[current*current: n: current] = [False] * len(primes[current*current: n: current])\n return sum(primes)", "matching_cluster_idx": 15}, {"solution": "def count_Primes_nums(num):\n # Function to check if a number is prime or not\n def is_prime(n):\n if n < 2:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True\n\n # Counting the prime numbers\n count = 0\n for i in range(num):\n if is_prime(i):\n count += 1\n\n return count", "matching_cluster_idx": 8}, {"solution": "def count_Primes_nums(n):\n def is_prime(n):\n \"\"\"\n Function to check if a number is prime.\n \"\"\"\n if n == 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True\n \n # if n is less than 2, there are no primes less than it\n if n < 2:\n return 0\n\n # else, count the primes less than n\n count = 0\n for i in range(2, n):\n if is_prime(i):\n count += 1\n return count", "matching_cluster_idx": 8}, {"solution": "def is_prime(num):\n if num < 2:\n return False\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n return False\n return True\ndef count_Primes_nums(num):\n return len([i for i in range(num) if is_prime(i)])", "matching_cluster_idx": 8}, {"solution": "def count_Primes_nums(n):\n if n < 2:\n return 0\n primes = [True]*n\n primes[0] = primes[1] = False\n for current in range(2, int(n**0.5) + 1):\n if primes[current] == True:\n for multiple in range(current*current, n, current):\n primes[multiple] = False\n return sum(primes)", "matching_cluster_idx": 14}, {"solution": "def count_Primes_nums(n):\n \"\"\"\n Returns the number of prime numbers less than the given non-negative number.\n\n Parameters:\n n (int): The number upto which primes should be counted.\n\n Returns:\n int: The count of prime numbers less than n.\n \"\"\"\n\n def is_prime(num):\n \"\"\"\n Helper function to check if a number is prime.\n\n Parameters:\n num (int): The number to be checked.\n\n Returns:\n bool: True if the number is prime, False otherwise.\n \"\"\"\n if num < 2:\n return False\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n return False\n return True\n\n count = 0\n for i in range(2, n):\n if is_prime(i):\n count += 1\n return count", "matching_cluster_idx": 8}, {"solution": "def is_prime(n):\n if n == 2 or n == 3: return True\n if n < 2 or n%2 == 0: return False\n if n < 9: return True\n if n%3 == 0: return False\n r = int(n**0.5)\n f = 5\n while f <= r:\n if n%f == 0: return False\n if n%(f+2) == 0: return False\n f +=6\n return True\ndef count_Primes_nums(num):\n count = 0\n for n in range(num):\n if is_prime(n):\n count += 1\n return count", "matching_cluster_idx": 10}, {"solution": "def count_Primes_nums(n):\n # Function to check if a number is prime\n def is_prime(num):\n if num < 2:\n return False\n for i in range(2, num):\n if num % i == 0:\n return False\n return True\n\n # Initialize a counter\n counter = 0\n\n # Iterate from 2 to n (exclusive)\n for i in range(2, n):\n # If the number is prime, increment the counter\n if is_prime(i):\n counter += 1\n\n # Return the final count of prime numbers\n return counter", "matching_cluster_idx": 2}]}, "Mbpp/265": {"dps": 78.37209302325581, "dps_norm": 88.33333333333333, "pass@1": 97.0, "profiled": [{"solution": "def list_split(input_list, n):\n return [input_list[i::n] for i in range(n)]", "matching_cluster_idx": 5}, {"solution": "def list_split(lst, n):\n output = [[] for _ in range(n)]\n for i, el in enumerate(lst):\n output[i%n].append(el)\n return output", "matching_cluster_idx": 4}, {"solution": "def list_split(input_list, n):\n return [input_list[i::n] for i in range(n)]", "matching_cluster_idx": 5}, {"solution": "def list_split(lst, n):\n \"\"\"\n This function splits a list for every nth element\n \"\"\"\n return [lst[i::n] for i in range(n)]", "matching_cluster_idx": 5}, {"solution": "def list_split(lst, n):\n result = [[] for _ in range(n)]\n for i, x in enumerate(lst):\n result[i%n].append(x)\n return result", "matching_cluster_idx": 4}, {"solution": "def list_split(list_input, n):\n # Creates an empty list of lists\n output_list = [[] for _ in range(n)]\n\n # Fill each sublist with every nth element\n for i in range(len(list_input)):\n output_list[i % n].append(list_input[i])\n\n return output_list", "matching_cluster_idx": 4}, {"solution": "def list_split(input_list, n):\n result_list = []\n for i in range(n):\n temp_list = []\n for j in range(i, len(input_list), n):\n temp_list.append(input_list[j])\n result_list.append(temp_list)\n return result_list", "matching_cluster_idx": 3}, {"solution": "def list_split(lst, n):\n return [lst[i::n] for i in range(n)]", "matching_cluster_idx": 5}, {"solution": "def list_split(lst, n):\n return [lst[i::n] for i in range(n)]", "matching_cluster_idx": 5}, {"solution": "def list_split(lst, n):\n result = [[] for _ in range(n)]\n for i in range(len(lst)):\n result[i%n].append(lst[i])\n return result\nlst = ['a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j', 'k', 'l', 'm', 'n']\nn = 3", "matching_cluster_idx": 4}, {"solution": "def list_split(input_list, n):\n result = []\n for i in range(n):\n temp = []\n for j in range(i, len(input_list), n):\n temp.append(input_list[j])\n result.append(temp)\n return result", "matching_cluster_idx": 3}, {"solution": "def list_split(lst, n):\n result = [[] for _ in range(n)]\n for i, el in enumerate(lst):\n result[i%n].append(el)\n return result", "matching_cluster_idx": 4}, {"solution": "def list_split(input_list, n):\n return [input_list[i::n] for i in range(n)]\ninput_list = ['a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j', 'k', 'l', 'm', 'n']\nn = 3", "matching_cluster_idx": 5}, {"solution": "def list_split(input_list, n):\n split_list = []\n for i in range(n):\n split_list.append([input_list[j] for j in range(i, len(input_list), n)])\n return split_list", "matching_cluster_idx": 2}, {"solution": "def list_split(input_list, n):\n return [input_list[i::n] for i in range(n)]", "matching_cluster_idx": 5}, {"solution": "def list_split(lst, n):\n return [lst[i::n] for i in range(n)]", "matching_cluster_idx": 5}, {"solution": "def list_split(input_list, n):\n result_lists = [[] for _ in range(n)]\n for index, item in enumerate(input_list):\n result_lists[index % n].append(item)\n return result_lists", "matching_cluster_idx": 4}, {"solution": "def list_split(input_list, n):\n return [input_list[i::n] for i in range(n)]", "matching_cluster_idx": 5}, {"solution": "def list_split(input_list, n):\n return [input_list[i::n] for i in range(n)]", "matching_cluster_idx": 5}, {"solution": "def list_split(input_list, n):\n result = [[] for _ in range(n)]\n for i, element in enumerate(input_list):\n result[i%n].append(element)\n return result", "matching_cluster_idx": 4}]}, "Mbpp/281": {"dps": 94.0, "dps_norm": 81.81818181818181, "pass@1": 100.0, "profiled": [{"solution": "def all_unique(lst):\n \"\"\"\n Function to check if all elements in a list are unique.\n \"\"\"\n # By converting the list to a set, we remove any duplicate values\n # and then we check if the length of the set equals the length of the list\n # to determine if all elements were unique.\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\" \n Checks if all elements of the given list are unique.\n \n Parameters:\n lst (list): input list\n \n Returns:\n bool: True if all elements are unique, False otherwise.\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\" Check if the elements of a given list are unique \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"Check if the elements in list are unique or not\"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n if len(lst) == len(set(lst)):\n return True\n else:\n return False", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n Check if all elements in the list are unique.\n \n Parameters:\n lst (list): The list to check.\n \n Returns:\n bool: True if all elements in the list are unique, False otherwise.\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n Checks if all elements in the list are unique or not.\n\n :param lst: list of elements\n :return: True if all elements in the list are unique, False otherwise.\n \"\"\"\n if len(lst) == len(set(lst)):\n return True\n else:\n return False", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(input_list):\n \"\"\"This function checks if the elements of the given list are unique or not\"\"\"\n if len(input_list) == len(set(input_list)):\n return True\n else:\n return False", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n Check if elements in a list are unique.\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n Function to check if the elements of a given list are unique or not.\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\" \n This function checks if the elements of a given list are unique. \n \n Args:\n lst (list): The list to check\n \n Returns:\n bool: Returns True if all elements are unique, False otherwise\n \"\"\"\n\n # Convert the list to a set\n # Sets in Python are inherently unique, meaning they cannot contain any duplicate elements\n # Hence, if the length of the set is not equal to the length of the original list, there must be duplicates in the original list\n if len(lst) == len(set(lst)):\n return True\n else:\n return False", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"Check if the elements of a list are unique or not.\"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(input_list):\n \"\"\"Checks if all elements in a list are unique.\"\"\"\n if len(input_list) == len(set(input_list)):\n return True\n else:\n return False", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n Function to check if the elements of a list are unique or not.\n \"\"\"\n if len(lst) == len(set(lst)):\n return True\n else:\n return False", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n if len(lst) == len(set(lst)):\n return True\n else:\n return False", "matching_cluster_idx": 8}, {"solution": "def all_unique(input_list):\n \"\"\"\n Function to check if all elements in a list are unique.\n\n Parameters:\n input_list (list): Input list to check for uniqueness.\n\n Returns:\n bool: True if all elements are unique, False otherwise.\n \"\"\"\n # Checking if length of set of list elements is same as list\n if len(input_list) == len(set(input_list)):\n return True\n else:\n return False", "matching_cluster_idx": 8}]}, "Mbpp/296": {"dps": 46.15384615384615, "dps_norm": 75.0, "pass@1": 98.0, "profiled": [{"solution": "def get_Inv_Count(arr):\n inv_count = 0\n for i in range(len(arr)):\n for j in range(i + 1, len(arr)):\n if (arr[i] > arr[j]):\n inv_count += 1\n \n return inv_count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n n = len(arr)\n inversion_count = 0\n for i in range(n):\n for j in range(i + 1, n):\n if (arr[i] > arr[j]):\n inversion_count += 1\n\n return inversion_count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n inv_count = 0\n for i in range(len(arr)):\n for j in range(i + 1, len(arr)):\n if (arr[i] > arr[j]):\n inv_count += 1\n\n return inv_count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n inversionCount = 0\n n = len(arr)\n\n # Traverse through all array elements\n for i in range(n):\n for j in range(i + 1, n):\n if (arr[i] > arr[j]):\n inversionCount += 1\n\n return inversionCount", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n n = len(arr)\n temp_arr = [0]*n\n return _merge_sort(arr, temp_arr, 0, n-1)\ndef _merge_sort(arr, temp_arr, left, right):\n inv_count = 0\n\n if left < right:\n mid = (left + right)//2\n inv_count = _merge_sort(arr, temp_arr, left, mid)\n inv_count += _merge_sort(arr, temp_arr, mid + 1, right)\n inv_count += merge(arr, temp_arr, left, mid, right)\n return inv_count\ndef merge(arr, temp_arr, left, mid, right):\n i = left \n j = mid + 1\n k = left \n inv_count = 0\n\n while i <= mid and j <= right:\n if arr[i] <= arr[j]:\n temp_arr[k] = arr[i]\n k += 1\n i += 1\n else:\n temp_arr[k] = arr[j]\n inv_count += (mid-i + 1)\n k += 1\n j += 1\n\n while i <= mid:\n temp_arr[k] = arr[i]\n k += 1\n i += 1\n\n while j <= right:\n temp_arr[k] = arr[j]\n k += 1\n j += 1\n\n for loop_var in range(left, right + 1):\n arr[loop_var] = temp_arr[loop_var]\n \n return inv_count", "matching_cluster_idx": 5}, {"solution": "def get_Inv_Count(arr):\n inv_count = 0\n for i in range(len(arr)):\n for j in range(i + 1, len(arr)):\n if (arr[i] > arr[j]):\n inv_count += 1\n\n return inv_count", "matching_cluster_idx": 3}, {"solution": "def mergeSort(arr, n):\n temp_arr = [0]*n\n return _mergeSort(arr, temp_arr, 0, n-1)\ndef _mergeSort(arr, temp_arr, left, right):\n inv_count = 0\n\n if left < right:\n mid = (left + right)//2\n inv_count = _mergeSort(arr, temp_arr,left, mid)\n inv_count += _mergeSort(arr, temp_arr, mid + 1, right)\n inv_count += merge(arr, temp_arr, left, mid, right)\n return inv_count\ndef merge(arr, temp_arr, left, mid, right):\n i = left \n j = mid + 1 \n k = left \n inv_count = 0\n\n while i <= mid and j <= right:\n if arr[i] <= arr[j]:\n temp_arr[k] = arr[i]\n k += 1\n i += 1\n else:\n temp_arr[k] = arr[j]\n inv_count += (mid-i + 1)\n k += 1\n j += 1\n\n while i <= mid:\n temp_arr[k] = arr[i]\n k += 1\n i += 1\n\n while j <= right:\n temp_arr[k] = arr[j]\n k += 1\n j += 1\n\n for loop_var in range(left, right + 1):\n arr[loop_var] = temp_arr[loop_var]\n \n return inv_count\ndef get_Inv_Count(arr):\n n = len(arr)\n return mergeSort(arr,n)", "matching_cluster_idx": 5}, {"solution": "def get_Inv_Count(arr):\n inv_count = 0\n for i in range(len(arr)):\n for j in range(i+1, len(arr)):\n if (arr[i] > arr[j]):\n inv_count += 1\n return inv_count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(array):\n def mergeSort(arr, n):\n temp_arr = [0]*n\n return _mergeSort(arr, temp_arr, 0, n-1)\n\n def _mergeSort(arr, temp_arr, left, right):\n inv_count = 0\n if left < right:\n mid = (left + right)//2\n inv_count += _mergeSort(arr, temp_arr, left, mid)\n inv_count += _mergeSort(arr, temp_arr, mid + 1, right)\n inv_count += merge(arr, temp_arr, left, mid, right)\n return inv_count\n\n def merge(arr, temp_arr, left, mid, right):\n i = left \n j = mid + 1 \n k = left \n inv_count = 0\n while i <= mid and j <= right:\n if arr[i] <= arr[j]:\n temp_arr[k] = arr[i]\n k += 1\n i += 1\n else:\n temp_arr[k] = arr[j]\n inv_count += (mid-i + 1)\n k += 1\n j += 1\n while i <= mid:\n temp_arr[k] = arr[i]\n k += 1\n i += 1\n while j <= right:\n temp_arr[k] = arr[j]\n k += 1\n j += 1\n for loop_var in range(left, right + 1):\n arr[loop_var] = temp_arr[loop_var]\n return inv_count\n n = len(array)\n return mergeSort(array,n)", "matching_cluster_idx": 5}, {"solution": "def get_Inv_Count(arr):\n inv_count = 0\n for i in range(len(arr)):\n for j in range(i + 1, len(arr)):\n if (arr[i] > arr[j]):\n inv_count += 1\n return inv_count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n n = len(arr)\n inv_count = 0\n for i in range(n):\n for j in range(i + 1, n):\n if (arr[i] > arr[j]):\n inv_count += 1\n\n return inv_count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n inversion_count = 0\n n = len(arr)\n for i in range(n): \n for j in range(i + 1, n): \n if (arr[i] > arr[j]): \n inversion_count += 1\n return inversion_count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n def _mergeSort(arr):\n inv_count = 0\n if len(arr) > 1:\n mid = len(arr) // 2\n left = arr[:mid]\n right = arr[mid:]\n\n inv_count += _mergeSort(left)\n inv_count += _mergeSort(right)\n\n i = j = k = 0\n while i < len(left) and j < len(right):\n if left[i] <= right[j]:\n arr[k] = left[i]\n i += 1\n else:\n arr[k] = right[j]\n inv_count += len(left) - i\n j += 1\n k += 1\n\n while i < len(left):\n arr[k] = left[i]\n i += 1\n k += 1\n\n while j < len(right):\n arr[k] = right[j]\n j += 1\n k += 1\n return inv_count\n\n return _mergeSort(arr)", "matching_cluster_idx": 5}, {"solution": "def get_Inv_Count(arr):\n n = len(arr)\n inv_count = 0\n for i in range(n):\n for j in range(i + 1, n):\n if (arr[i] > arr[j]):\n inv_count += 1\n return inv_count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n inv_count = 0\n for i in range(len(arr)):\n for j in range(i + 1, len(arr)):\n if (arr[i] > arr[j]):\n inv_count += 1\n return inv_count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n count = 0\n n = len(arr)\n \n for i in range(n):\n for j in range(i + 1, n):\n if (arr[i] > arr[j]):\n count += 1\n \n return count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n n = len(arr)\n temp_arr = [0]*n\n return _mergeSort(arr, temp_arr, 0, n-1)\ndef _mergeSort(arr, temp_arr, left, right):\n inv_count = 0\n\n if left < right:\n\n # Divide the array into two parts\n mid = (left + right)//2\n\n # Inversion count will be the sum of inversions in left part,\n # right part and number of inversions in merging\n inv_count = _mergeSort(arr, temp_arr, left, mid)\n inv_count += _mergeSort(arr, temp_arr, mid + 1, right)\n inv_count += merge(arr, temp_arr, left, mid, right)\n return inv_count\ndef merge(arr, temp_arr, left, mid, right):\n i = left # Starting index of left subarray\n j = mid + 1 # Starting index of right subarray\n k = left # Starting index of to be sorted subarray\n inv_count = 0\n\n # Conditions are checked to make sure that i and j do not exceed their subarray limits.\n while i <= mid and j <= right:\n\n # There is no inversion if arr[i] <= arr[j]\n if arr[i] <= arr[j]:\n temp_arr[k] = arr[i]\n k += 1\n i += 1\n else:\n # Inversion found\n temp_arr[k] = arr[j]\n inv_count += (mid-i + 1)\n k += 1\n j += 1\n\n # Copy the remaining elements of left subarray into temporary array\n while i <= mid:\n temp_arr[k] = arr[i]\n k += 1\n i += 1\n\n # Copy the remaining elements of right subarray into temporary array\n while j <= right:\n temp_arr[k] = arr[j]\n k += 1\n j += 1\n\n # Copy the sorted subarray into original array\n for loop_var in range(left, right + 1):\n arr[loop_var] = temp_arr[loop_var]\n\n return inv_count", "matching_cluster_idx": 5}, {"solution": "def get_Inv_Count(arr):\n \"\"\"\n This function takes an array as input and returns the number of inversions present in it.\n Inversion Count for an array indicates \u2013 how far (or close) the array is from being sorted. If array is already sorted then inversion count is 0. If array is sorted in reverse order that inversion count is the maximum. \n Formally speaking, two elements a[i] and a[j] form an inversion if a[i] > a[j] and i < j \n \"\"\"\n inv_count = 0\n for i in range(len(arr)):\n for j in range(i + 1, len(arr)):\n if (arr[i] > arr[j]):\n inv_count += 1\n return inv_count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n inv_count = 0\n for i in range(len(arr)):\n for j in range(i + 1, len(arr)):\n if (arr[i] > arr[j]):\n inv_count += 1\n \n return inv_count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n count = 0\n n = len(arr)\n\n for i in range(n):\n for j in range(i + 1, n):\n if arr[i] > arr[j]:\n count += 1\n\n return count", "matching_cluster_idx": 3}]}, "Mbpp/308": {"dps": 97.58620689655173, "dps_norm": 66.66666666666667, "pass@1": 46.0, "profiled": [{"solution": "def large_product(list1, list2, k):\n # Create a list of all possible products\n products = sorted([i*j for i in list1 for j in list2], reverse=True)\n \n # Return the first k elements\n return products[:k]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n # generate all products from list1 and list2\n products = [a * b for a in list1 for b in list2]\n\n # sort the products in descending order\n products.sort(reverse=True)\n\n # return the first n elements from the sorted products list\n return products[:n]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n return sorted([i * j for i in list1 for j in list2], reverse=True)[:n]", "matching_cluster_idx": 3}, {"solution": "from typing import List, Union\ndef large_product(a: List[Union[int, float]], b: List[Union[int, float]], n: int) -> List[Union[int, float]]:\n \"\"\"\n Finds the 'n' largest products from two given lists.\n\n Parameters:\n a (List[Union[int, float]]): First list of numbers.\n b (List[Union[int, float]]): Second list of numbers.\n n (int): Number of largest products to be found.\n\n Returns:\n List[Union[int, float]]: List of 'n' largest products.\n\n \"\"\"\n\n # Get all product combinations\n products = sorted([i*j for i in a for j in b], reverse=True)\n\n # Return the 'n' largest products\n return products[:n]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, num):\n if not (isinstance(list1, list) and isinstance(list2, list) and isinstance(num, int)):\n raise TypeError(\"Input must be a list and a number.\")\n\n products = [i*j for i in list1 for j in list2]\n products.sort(reverse=True)\n return products[:num]", "matching_cluster_idx": 3}, {"solution": "import heapq\ndef large_product(list1, list2, n):\n # Calculate all possible products\n products = [i*j for i in list1 for j in list2]\n\n # Find the n largest products\n n_largest = heapq.nlargest(n, products)\n\n return n_largest", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, num):\n \"\"\"\n This function will return the `num` largest products from two lists.\n \"\"\"\n products = [a * b for a in list1 for b in list2]\n products.sort(reverse=True)\n return products[:num]", "matching_cluster_idx": 3}, {"solution": "def large_product(lst1, lst2, n):\n \"\"\"\n Function to find the specified number of largest products\n \"\"\"\n products = [i*j for i in lst1 for j in lst2]\n products.sort(reverse=True)\n return products[:n]\nlst1 = [1, 2, 3, 4, 5, 6]\nlst2 = [3, 6, 8, 9, 10, 6]\nn = 3", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n # Prevent trying to compute more products than possible.\n if n > len(list1)*len(list2):\n raise ValueError(\"Can't compute more products than there are elements in the lists\")\n\n # Generate a list of all possible products.\n products = [x*y for x in list1 for y in list2]\n\n # Sort the products in descending order and return the top n.\n return sorted(products, reverse=True)[:n]", "matching_cluster_idx": 3}, {"solution": "def large_product(numbers1, numbers2, count):\n products = sorted([num1 * num2 for num1 in numbers1 for num2 in numbers2], reverse=True)\n return products[:count]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, num):\n products = []\n for i in list1:\n for j in list2:\n products.append(i * j)\n products.sort(reverse=True)\n return products[:num]", "matching_cluster_idx": 3}, {"solution": "def large_product(l1, l2, k):\n products = []\n for i in l1:\n for j in l2:\n products.append(i*j)\n products.sort(reverse=True)\n return products[:k]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n # Generate all possible pairs of products\n products = [i*j for i in list1 for j in list2]\n # Sort in descending order\n products.sort(reverse=True)\n # Return the first n elements\n return products[:n]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n # Calculate the product of all factors in lists\n product_list = [i*j for i in list1 for j in list2]\n # Sort the list in descending order\n product_list.sort(reverse=True)\n # Return the first n elements\n return product_list[:n]", "matching_cluster_idx": 3}, {"solution": "def large_product(lst1, lst2, k):\n products = [i*j for i in lst1 for j in lst2]\n products.sort(reverse=True)\n return products[:k]\nlst1 = [1, 2, 3, 4, 5, 6]\nlst2 = [3, 6, 8, 9, 10, 6]\nk = 3", "matching_cluster_idx": 3}, {"solution": "import heapq\ndef large_product(list1, list2, k):\n \"\"\"\n Find the specified number of largest products from two given lists\n by selecting one factor from each list.\n \"\"\"\n # create a max-heap\n heap = []\n for a in list1:\n for b in list2:\n # heap stores negative values to simulate max-heap\n heapq.heappush(heap, -a * b)\n # return the largest k values\n return sorted([-heapq.heappop(heap) for _ in range(k)], reverse=True)", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, num):\n # Calculate the product for all combinations\n products = [a*b for a in list1 for b in list2]\n\n # Sort products in descending order\n products.sort(reverse=True)\n\n # Return the 'num' largest products\n return products[:num]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, k):\n # Create two lists to hold product combinations.\n products = [i*j for i in list1 for j in list2]\n \n # Sort the products in descending order.\n products.sort(reverse=True)\n \n # Return the first k elements from the sorted list.\n return products[:k]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n # Generate all possible products\n products = [x*y for x in list1 for y in list2]\n # Sort the list in descending order\n products.sort(reverse=True)\n # Return the first n elements\n return products[:n]", "matching_cluster_idx": 3}, {"solution": "def large_product(lst1, lst2, n):\n products = []\n for i in lst1:\n for j in lst2:\n products.append(i * j)\n products.sort(reverse=True)\n return products[:n]", "matching_cluster_idx": 3}]}, "Mbpp/392": {"dps": 34.671361502347416, "dps_norm": 45.76923076923077, "pass@1": 50.0, "profiled": [{"solution": "def get_max_sum(n):\n if n < 0:\n return 0\n\n if n == 0 or n == 1:\n return n\n\n # Create a list to store the results of sub-problems\n dp = [0]*(n+1)\n\n # Base case\n dp[0] = 0\n dp[1] = 1\n\n # Bottom-up DP: Fill up dp[] array in bottom up manner\n for i in range(2, n+1):\n dp[i] = max((dp[int(i/2)] + dp[int(i/3)] + dp[int(i/4)] + dp[int(i/5)]), i)\n\n return dp[n]", "matching_cluster_idx": 9}, {"solution": "def get_max_sum(n):\n # Base case\n if n == 0:\n return 0\n\n # Initialize list for memoization\n dp = [0] * (n + 1)\n\n # Fill the dp list\n for i in range(1, n + 1):\n # Include the current index or its divisions\n dp[i] = max(i, dp[i // 2] + dp[i // 3] + dp[i // 4] + dp[i // 5])\n\n return dp[n]", "matching_cluster_idx": 10}, {"solution": "def get_max_sum(n):\n # Using a lookup table for memoization\n sum_array = [0, 1]\n\n # Iterating over the range and filling up the lookup table\n for i in range(2, n+1):\n sum_array.append(max(sum_array[int(i/2)] + sum_array[int(i/3)] + sum_array[int(i/4)] + sum_array[int(i/5)], i))\n\n # Returning the maximum sum possible\n return sum_array[n]", "matching_cluster_idx": 9}, {"solution": "def get_max_sum(n):\n if n == 0:\n return 0\n else:\n return max((get_max_sum(n//2) + get_max_sum(n//3) + get_max_sum(n//4) + get_max_sum(n//5)), n)", "matching_cluster_idx": 2}, {"solution": "def get_max_sum(n):\n if n == 0:\n return 0\n else:\n return max(get_max_sum(n//2) + get_max_sum(n//3) + get_max_sum(n//4) + get_max_sum(n//5), n)", "matching_cluster_idx": 2}, {"solution": "def get_max_sum(n):\n if n == 0: \n return 0\n else:\n # Recursive case\n return max(get_max_sum(n//2) + get_max_sum(n//3) + get_max_sum(n//4) + get_max_sum(n//5), n)", "matching_cluster_idx": 2}, {"solution": "def get_max_sum(n):\n if n == 0:\n return 0\n else:\n return max((get_max_sum(n//2) + get_max_sum(n//3) + get_max_sum(n//4) + get_max_sum(n//5)), n)", "matching_cluster_idx": 2}, {"solution": "def get_max_sum(n):\n if n == 0:\n return 0\n else:\n return max((get_max_sum(n//2) + get_max_sum(n//3) + get_max_sum(n//4) + get_max_sum(n//5)), n)", "matching_cluster_idx": 2}, {"solution": "def get_max_sum(n):\n if n == 0:\n return 0\n else:\n return max((get_max_sum(n//2) + get_max_sum(n//3) + get_max_sum(n//4) + get_max_sum(n//5)), n)", "matching_cluster_idx": 2}, {"solution": "def get_max_sum(n):\n # a memoization dictionary to save computed subproblem results\n memo = {0: 0, 1: 1}\n # recursive function that computes the maximum sum\n def max_sum(n):\n # if n is not in memo, compute it and store it in memo\n if n not in memo:\n memo[n] = max(max_sum(n//2) + max_sum(n//3) + max_sum(n//4) + max_sum(n//5), n)\n # return the computed value from memo\n return memo[n]\n # return the maximum sum for n\n return max_sum(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n if n == 0:\n return 0\n else:\n return max(get_max_sum(n//2) + get_max_sum(n//3) + get_max_sum(n//4) + get_max_sum(n//5), n)", "matching_cluster_idx": 2}, {"solution": "def get_max_sum(n):\n ## A cache to store precomputed values for efficiency\n cache = {0:0, 1:1}\n\n def f(n):\n if n in cache:\n return cache[n]\n else:\n cache[n] = max(f(n//2) + f(n//3) + f(n//4) + f(n//5), n)\n return cache[n]\n \n return f(n)", "matching_cluster_idx": 12}, {"solution": "def max_sum(n):\n if n == 0: \n return 0\n else:\n return max(n, max_sum(n//2) + max_sum(n//3) + max_sum(n//4) + max_sum(n//5))\ndef get_max_sum(n):\n return max_sum(n)", "matching_cluster_idx": 2}, {"solution": "def get_max_sum(n):\n if n < 1:\n return 0\n else:\n return max((get_max_sum(n // 2) + get_max_sum(n // 3) + get_max_sum(n // 4) + get_max_sum(n // 5)), n)", "matching_cluster_idx": 2}, {"solution": "def get_max_sum(n, memo={}):\n \"\"\"\n Function to find the maximum sum possible by using the given equation \n f(n) = max( (f(n/2) + f(n/3) + f(n/4) + f(n/5)), n)\n \"\"\"\n if n == 0:\n return 0\n if n in memo: \n return memo[n]\n else:\n memo[n] = max((get_max_sum(n//2, memo) + get_max_sum(n//3, memo) + \n get_max_sum(n//4, memo) + get_max_sum(n//5, memo)), n)\n return memo[n]", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n\n if n < 2:\n return n\n \n # Create a list to store the maximum sum for each number\n dp = [0] * (n + 1)\n dp[1] = 1\n \n # Fill in the list bottom-up\n for i in range(2, n + 1):\n dp[i] = max((dp[int(i/2)] + dp[int(i/3)] + dp[int(i/4)] + dp[int(i/5)]), i)\n \n return dp[n]", "matching_cluster_idx": 9}, {"solution": "def get_max_sum(n):\n if n == 0:\n return 0\n else:\n return max(get_max_sum(n//2) + get_max_sum(n//3) + get_max_sum(n//4) + get_max_sum(n//5), n)", "matching_cluster_idx": 2}, {"solution": "def get_max_sum(n):\n if n == 0: \n return 0\n else:\n return max((get_max_sum(n//2) + get_max_sum(n//3) + get_max_sum(n//4) + get_max_sum(n//5)), n)", "matching_cluster_idx": 2}, {"solution": "def get_max_sum(n):\n if n == 0: \n return 0\n else:\n return max(get_max_sum(n//2) + get_max_sum(n//3) + get_max_sum(n//4) + get_max_sum(n//5), n)", "matching_cluster_idx": 2}, {"solution": "def get_max_sum(n):\n if n == 0:\n return 0\n else:\n return max(get_max_sum(n//2) + get_max_sum(n//3) + get_max_sum(n//4) + get_max_sum(n//5), n)", "matching_cluster_idx": 2}]}, "Mbpp/395": {"dps": 89.6168582375479, "dps_norm": 73.75, "pass@1": 100.0, "profiled": [{"solution": "def first_non_repeating_character(string):\n char_order = []\n ctr = {}\n for c in string:\n if c in ctr:\n ctr[c] += 1\n else:\n ctr[c] = 1 \n char_order.append(c)\n for c in char_order:\n if ctr[c] == 1:\n return c\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(string):\n char_count = {}\n for char in string:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n\n for char in string:\n if char_count[char] == 1:\n return char\n\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(input_string):\n char_counts = {}\n\n # Count the number of occurrences of each character\n for char in input_string:\n if char in char_counts:\n char_counts[char] += 1\n else:\n char_counts[char] = 1\n\n # Find the first character that has a count of 1\n for char in input_string:\n if char_counts[char] == 1:\n return char\n\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(input_string):\n char_count = {}\n for char in input_string:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n\n for char in input_string:\n if char_count[char] == 1:\n return char\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n char_order = []\n ctr = {}\n for c in s:\n if c in ctr:\n ctr[c] += 1\n else:\n ctr[c] = 1\n char_order.append(c)\n for c in char_order:\n if ctr[c] == 1:\n return c\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n char_count = {}\n for char in s:\n if char not in char_count:\n char_count[char] = 1\n else:\n char_count[char] += 1\n\n for char in s:\n if char_count[char] == 1:\n return char\n return None", "matching_cluster_idx": 4}, {"solution": "def first_non_repeating_character(input_string):\n char_count = {}\n for char in input_string:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n for char in input_string:\n if char_count[char] == 1:\n return char\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(string):\n char_count = {}\n for char in string:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n \n for char in string:\n if char_count[char] == 1:\n return char\n\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n char_count = {}\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n for char in s:\n if char_count[char] == 1:\n return char\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(string):\n \"\"\"Function to find the first non-repeated character in a given string.\"\"\"\n char_count = {}\n\n for char in string:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n\n for char in string:\n if char_count[char] == 1:\n return char\n\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n frequency = {}\n for char in s:\n if char in frequency:\n frequency[char] += 1\n else:\n frequency[char] = 1\n \n for char in s:\n if frequency[char] == 1:\n return char\n \n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n char_count = {}\n for char in s:\n char_count[char] = char_count.get(char, 0) + 1\n for char in s:\n if char_count[char] == 1:\n return char\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(string):\n char_order = []\n counts = {}\n for c in string:\n if c in counts:\n counts[c] += 1\n else:\n counts[c] = 1\n char_order.append(c)\n for c in char_order:\n if counts[c] == 1:\n return c\n return None", "matching_cluster_idx": 4}, {"solution": "def first_non_repeating_character(string):\n char_count = {}\n \n for char in string:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n\n for char in string:\n if char_count[char] == 1:\n return char\n\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(input_string):\n char_count = {}\n for character in input_string:\n if character in char_count:\n char_count[character] += 1\n else:\n char_count[character] = 1\n\n for character in input_string:\n if char_count[character] == 1:\n return character\n\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n char_count = {}\n for c in s:\n if c in char_count:\n char_count[c] += 1\n else:\n char_count[c] = 1\n for c in s:\n if char_count[c] == 1:\n return c\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n char_count = {}\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n\n for char in s:\n if char_count[char] == 1:\n return char\n\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(string):\n \"\"\"\n Function to find the first non-repeated character in a given string.\n \"\"\"\n char_order = []\n ctr = {}\n for char in string:\n if char in ctr:\n ctr[char] += 1\n else:\n ctr[char] = 1\n char_order.append(char)\n for char in char_order:\n if ctr[char] == 1:\n return char\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n char_count = {}\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n\n for char in s:\n if char_count[char] == 1:\n return char\n\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(input_string):\n # initialize dictionary to store character count\n count = {}\n # iterate over the input string\n for char in input_string:\n # if the character is not in the count dictionary, add it with count 1\n # otherwise, increment the count by 1\n count[char] = count.get(char, 0) + 1\n # iterate over the input string\n for char in input_string:\n # if the count of the character is 1, it is the first non-repeating character\n if count[char] == 1:\n return char\n # if no character is found, return None\n return None", "matching_cluster_idx": 5}]}, "Mbpp/405": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def check_tuplex(tuplex, element):\n \"\"\"\n Function to check whether an element exists within a tuple.\n \"\"\"\n return element in tuplex", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, item):\n \"\"\"\n Check if an element exists within a tuple.\n \"\"\"\n return item in tuplex", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tup, element):\n \"\"\"\n Check if element exists within tuple.\n \"\"\"\n return element in tup", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tup, element):\n \"\"\"\n This function checks if an element exists within a tuple.\n \"\"\"\n if element in tup:\n return True\n else:\n return False", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, char):\n \"\"\"\n Check if an element exists within a tuple\n :param tuplex: The tuple to be checked\n :param char: The element to look for in the tuple\n :return: True if element exists, False otherwise\n \"\"\"\n if char in tuplex:\n return True\n else:\n return False", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, element):\n \"\"\"\n Check if an element exists within a tuple\n \"\"\"\n return element in tuplex", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, element):\n if element in tuplex:\n return True\n else:\n return False", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, element):\n \"\"\"Check if an element exists within a tuple.\"\"\"\n return element in tuplex", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(input_tuple, target):\n \"\"\"\n This function checks whether an element exists within a tuple.\n\n :param input_tuple: The tuple where you're checking if element exists.\n :param target: The element you're checking for in the tuple.\n :return: Returns True if element exists, False otherwise.\n \"\"\"\n return target in input_tuple", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tup, ele):\n \"\"\"\n Function to check whether an element exists within a tuple.\n \"\"\"\n return ele in tup", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(my_tuple, element):\n return element in my_tuple", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tup, element):\n \"\"\"\n Write a function to check whether an element exists within a tuple.\n \"\"\"\n return element in tup", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, element):\n \"\"\"\n Check whether a certain element exists within a tuple\n\n Parameters:\n tuplex: Tuple to be checked\n element: Element to be looked for in the tuple\n\n Returns:\n bool: True if the element exists in the tuple, False otherwise\n\n Example:\n >>> assert check_tuplex((\"w\", 3, \"r\", \"e\", \"s\", \"o\", \"u\", \"r\", \"c\", \"e\"),'r')==True\n \"\"\"\n return element in tuplex", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, element):\n \"\"\"\n Function to check whether an element exists within a tuple.\n\n Parameters:\n tuplex (tuple): The tuple to be checked.\n element (any): The element to be searched.\n\n Returns:\n bool: True if the element exists in the tuple, False otherwise.\n \"\"\"\n return element in tuplex", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(t, element):\n \"\"\"Check whether an element exists within a tuple\"\"\"\n return element in t", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, element):\n return element in tuplex", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(t, element):\n \"\"\"\n A function to check whether an element exists within a tuple.\n :param t: tuple\n :param element: the element to be checked for existence in the tuple\n :return: True if the element exists in the tuple, False otherwise\n \"\"\"\n return element in t", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(t, element):\n return element in t", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tup, element):\n \"\"\"\n Function to check whether an element exists within a tuple\n \"\"\"\n return element in tup", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, element):\n \"\"\"\n Function to check whether an element exists within a tuple\n \"\"\"\n return element in tuplex", "matching_cluster_idx": 3}]}, "Mbpp/414": {"dps": 89.00621118012423, "dps_norm": 88.33333333333333, "pass@1": 100.0, "profiled": [{"solution": "def overlapping(sequence1, sequence2):\n \"\"\"\n Check whether any value in sequence1 exists in sequence2 or not.\n \"\"\"\n for val in sequence1:\n if val in sequence2:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n for i in seq1:\n if i in seq2:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Function to check whether any value in a sequence exists in a sequence or not.\n \"\"\"\n for value in seq1:\n if value in seq2:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Check if any value from seq1 exists in seq2.\n \"\"\"\n for el in seq1:\n if el in seq2:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n for i in seq1:\n if i in seq2:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Function to check if any value in seq1 exists in seq2.\n Returns True if any value exists, otherwise False.\n \"\"\"\n # Convert the sequences to sets to speed up the lookup process\n set1 = set(seq1)\n set2 = set(seq2)\n\n # Check each value in set1, if any is found in set2 return True\n for val in set1:\n if val in set2:\n return True\n\n # If no overlapping values are found return False\n return False", "matching_cluster_idx": 6}, {"solution": "def overlapping(seq1, seq2):\n for i in seq1:\n if i in seq2:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n for i in seq1:\n if i in seq2:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(list1, list2):\n for i in list1:\n if i in list2:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n return any(item in seq2 for item in seq1)", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Check if any value in seq1 exists in seq2.\n :param seq1: first sequence\n :param seq2: second sequence\n :return: True if any value in seq1 is in seq2, False otherwise\n \"\"\"\n # Use any() function to check if any element in seq1 is in seq2\n return any(item in seq2 for item in seq1)", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n A function to check whether any value in a sequence exists in another sequence\n :param seq1: First sequence\n :param seq2: Second sequence\n :return: True if any value in seq1 exists in seq2, otherwise False\n \"\"\"\n # convert seq2 to a set for faster lookup\n seq2_set = set(seq2)\n # check if any value in seq1 exists in seq2\n for val in seq1:\n if val in seq2_set:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n for value in seq1:\n if value in seq2:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n This function checks if any value in seq1 exists in seq2 or not\n \"\"\"\n return any(i in seq2 for i in seq1)", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n for i in seq1:\n if i in seq2:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n This function checks whether any value in seq1 exists in seq2\n :param seq1: First sequence to check\n :param seq2: Second sequence to check\n :return: Boolean indicating whether any value in seq1 is also in seq2\n \"\"\"\n return any(item in seq2 for item in seq1)", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n for value in seq1:\n if value in seq2:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(list1, list2):\n for i in list1:\n if i in list2:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Check if any value in seq1 exists in seq2\n\n Args:\n seq1 (list or set): a sequence of values\n seq2 (list or set): a sequence of values\n\n Returns:\n bool: True if any value in seq1 exists in seq2, False otherwise\n \"\"\"\n return any(i in seq2 for i in seq1)", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Function to check whether any value in a sequence exists in another sequence.\n \"\"\"\n for i in seq1:\n if i in seq2:\n return True\n return False", "matching_cluster_idx": 7}]}, "Mbpp/421": {"dps": 54.83539094650206, "dps_norm": 82.14285714285714, "pass@1": 100.0, "profiled": [{"solution": "def concatenate_tuple(tup, delimiter = \"-\"):\n # Mapping function to convert each element to string\n str_tup = map(str, tup)\n # Joining strings in the tuple by the delimiter\n return delimiter.join(str_tup)", "matching_cluster_idx": 6}, {"solution": "def concatenate_tuple(t, delimiter='-'):\n # Check if input is a tuple\n if not isinstance(t, tuple):\n raise ValueError(\"Input should be a tuple.\")\n # Check if delimiter is a string\n if not isinstance(delimiter, str):\n raise ValueError(\"Delimiter should be a string.\")\n # Convert each element of tuple into string, if it is not already a string\n str_elements = [str(i) for i in t]\n # Concatenate the elements with the delimiter\n result = delimiter.join(str_elements)\n return result", "matching_cluster_idx": 4}, {"solution": "def concatenate_tuple(t, delimiter='-'):\n return delimiter.join(str(i) for i in t)", "matching_cluster_idx": 4}, {"solution": "def concatenate_tuple(input_tuple, delimiter='-'):\n \"\"\"\n This function takes a tuple and a delimiter (default is '-') and \n concatenates each element of the tuple with the delimiter.\n \"\"\"\n # Converting each element to string \n input_tuple = map(str, input_tuple)\n # Joining the elements of the tuple with the delimiter\n result = delimiter.join(input_tuple)\n return result", "matching_cluster_idx": 5}, {"solution": "def concatenate_tuple(input_tuple, delimiter='-'):\n \"\"\"\n This function concatenates each element of input_tuple by the delimiter.\n \"\"\"\n result = ''\n for i in input_tuple:\n result += str(i) + delimiter\n return result[:-len(delimiter)]", "matching_cluster_idx": 3}, {"solution": "def concatenate_tuple(tuple_val, delimiter='-'):\n return delimiter.join(map(str,tuple_val))", "matching_cluster_idx": 5}, {"solution": "def concatenate_tuple(tup):\n return '-'.join(str(i) for i in tup)", "matching_cluster_idx": 4}, {"solution": "def concatenate_tuple(t, delimiter='-'):\n return delimiter.join(str(i) for i in t)", "matching_cluster_idx": 4}, {"solution": "def concatenate_tuple(tup, delimiter='-'):\n return delimiter.join(map(str, tup))", "matching_cluster_idx": 5}, {"solution": "def concatenate_tuple(tup):\n return '-'.join(str(i) for i in tup)", "matching_cluster_idx": 4}, {"solution": "def concatenate_tuple(tup, delimiter='-'):\n return delimiter.join(str(i) for i in tup)", "matching_cluster_idx": 4}, {"solution": "def concatenate_tuple(input_tuple):\n delimiter = '-'\n return delimiter.join(map(str, input_tuple))", "matching_cluster_idx": 5}, {"solution": "def concatenate_tuple(input_tuple, delimiter='-'):\n \"\"\"\n This function takes in a tuple and a delimiter, and returns a string which \n is the concatenation of all elements of the tuple, separated by the delimiter.\n \"\"\"\n # Use the built-in `map()` function to convert all elements to strings\n # Use the built-in `join()` function to concatenate all strings\n result = delimiter.join(map(str, input_tuple))\n\n return result", "matching_cluster_idx": 6}, {"solution": "def concatenate_tuple(tpl, delimiter='-'):\n return delimiter.join(str(ele) for ele in tpl)", "matching_cluster_idx": 4}, {"solution": "def concatenate_tuple(input_tuple, delimiter='-'):\n # Convert each element of tuple to string, to handle both string and number types\n string_elements = map(str, input_tuple)\n # Concatenate string elements of tuple with the delimiter\n concatenated_string = delimiter.join(string_elements)\n return concatenated_string", "matching_cluster_idx": 6}, {"solution": "def concatenate_tuple(tuple_, delimiter='-'):\n \"\"\"\n This function concatenates each element of a tuple by the delimiter.\n \"\"\"\n # convert each element of the tuple to a string using map()\n # join the strings with the delimiter using the join() method\n return delimiter.join(map(str, tuple_))", "matching_cluster_idx": 6}, {"solution": "def concatenate_tuple(tup):\n return \"-\".join(map(str, tup))", "matching_cluster_idx": 5}, {"solution": "def concatenate_tuple(input_tuple, delimiter='-'):\n return delimiter.join(str(i) for i in input_tuple)", "matching_cluster_idx": 4}, {"solution": "def concatenate_tuple(input_tuple):\n # Converting all elements in tuple to string\n str_tuple = map(str, input_tuple)\n\n # Concatenating elements in the tuple with '-' delimiter\n result = \"-\".join(str_tuple)\n\n return result", "matching_cluster_idx": 6}, {"solution": "def concatenate_tuple(t, delimiter='-'):\n \"\"\"\n This function concatenates each element of tuple by the delimiter.\n \"\"\"\n # Converting tuple to list to allow modifications\n t = list(t)\n # Converting each element in the list to string and joining with the delimiter\n t = delimiter.join(map(str, t))\n return t", "matching_cluster_idx": 5}]}, "Mbpp/424": {"dps": 80.95667870036101, "dps_norm": 92.0, "pass@1": 100.0, "profiled": [{"solution": "def extract_rear(input_tuple):\n \"\"\"\n This function extracts the last character of each string in a given tuple and returns a list of these characters.\n \"\"\"\n return [word[-1] for word in input_tuple]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(input_tuple):\n return [x[-1] for x in input_tuple]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(input_tuple):\n \"\"\"\n Extract the rear index element of each string in the given tuple.\n \"\"\"\n return [string[-1] for string in input_tuple]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(strings_tuple):\n return [s[-1] for s in strings_tuple]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(input_tuple):\n result = []\n for string in input_tuple:\n result.append(string[-1])\n return result", "matching_cluster_idx": 3}, {"solution": "def extract_rear(input_tuple):\n # Initialize an empty list to store the extracted elements\n result = []\n\n # Iterate over each string in the given tuple\n for string in input_tuple:\n # Extract the rear index element and add it to the result\n result.append(string[-1])\n\n return result", "matching_cluster_idx": 3}, {"solution": "def extract_rear(input_tuple):\n return [string[-1] for string in input_tuple]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(tuple_str):\n \"\"\"\n Function to extract only the rear index element of each string in the given tuple.\n \"\"\"\n return [s[-1] for s in tuple_str]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(tup):\n return [word[-1] for word in tup]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(strings_tuple):\n return [string[-1] for string in strings_tuple]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(strings):\n return [string[-1] for string in strings]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(input_tuple):\n # Initialize an empty list\n result = []\n\n # Iterate over each string in the given tuple\n for string in input_tuple:\n # Extract the last character and add it to the result list\n result.append(string[-1])\n\n # Return the final list\n return result", "matching_cluster_idx": 3}, {"solution": "def extract_rear(strings):\n \"\"\"\n Function to extract the rear index element of each string in the given tuple\n \"\"\"\n return [string[-1] for string in strings]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(input_tuple):\n return [i[-1] for i in input_tuple]", "matching_cluster_idx": 3}, {"solution": "def extract_rear(tup):\n return [word[-1] for word in tup]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(input_tuple):\n \"\"\"\n Function to extract only the rear index element of each string in the given tuple.\n \"\"\"\n return [s[-1] for s in input_tuple]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(input_tuple):\n # Initializing an empty list to store the rear index element of each string\n rear_elements = []\n\n # Iterating over the input tuple\n for item in input_tuple:\n # If item is a string, add its last character to the rear_elements list\n if isinstance(item, str):\n rear_elements.append(item[-1])\n\n # Return the rear elements list\n return rear_elements", "matching_cluster_idx": 2}, {"solution": "def extract_rear(tup):\n \"\"\"\n Function to extract only the rear index element of each string in the given tuple.\n :param tup: The input tuple of strings.\n :return: A list with rear index elements of each string.\n \"\"\"\n return [s[-1] for s in tup]", "matching_cluster_idx": 3}, {"solution": "def extract_rear(tpl):\n return [item[-1] for item in tpl]", "matching_cluster_idx": 3}, {"solution": "def extract_rear(strings_tuple):\n return [string[-1] for string in strings_tuple]", "matching_cluster_idx": 4}]}, "Mbpp/425": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def count_element_in_list(lst, elm):\n count = 0\n for sublist in lst:\n if elm in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(list_of_lists, element):\n count = 0\n for sublist in list_of_lists:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, element):\n return sum(element in sublist for sublist in lst)", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, element):\n count = 0\n for sublist in lst:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, elem):\n count = 0\n for sublist in lst:\n if elem in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, elem):\n \"\"\"\n Counts the number of sublists in a list that contain a particular element.\n \n Args:\n lst: The main list to be checked.\n elem: The element to be looked for.\n \n Returns:\n An integer which is the number of sublists in 'lst' that contain 'elem'.\n \"\"\"\n \n count = 0\n for sublist in lst:\n if elem in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(input_list, element):\n count = 0\n for sublist in input_list:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, elem):\n count = 0\n for sublist in lst:\n if elem in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, ele):\n # Variable to store the count\n count = 0\n\n # Iterate over each sublist\n for sublist in lst:\n # If the element is in the sublist, increment the count\n if ele in sublist:\n count += 1\n\n # Return the final count\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(main_list, target_element):\n count = 0\n for sublist in main_list:\n if target_element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, elm):\n count = 0\n for sublist in lst:\n if elm in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, element):\n return sum([element in sublist for sublist in lst])", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, element):\n return sum(1 for sublist in lst if element in sublist)", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(list_of_lists, target):\n count = 0\n for sublist in list_of_lists:\n if target in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(input_list, target):\n count = 0\n for sublist in input_list:\n if target in sublist:\n count += 1\n return count\ninput_list = [[1, 3], [5, 7], [1, 11], [1, 15, 7]]\ntarget = 1", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, ele):\n \"\"\"Counts the number of sublists that contain a specific element.\n \n Arguments:\n lst -- A list of lists to be searched.\n ele -- The element to be searched for in the list.\n\n Returns:\n count -- The number of sublists containing the specific element.\n\n Tests:\n >>> count_element_in_list([[1, 3], [5, 7], [1, 11], [1, 15, 7]],1)\n 3\n \"\"\"\n count = 0\n for sublist in lst:\n if ele in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, element):\n count = 0\n for sublist in lst:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(input_list, element):\n count = 0\n for sublist in input_list:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lists, element):\n count = 0\n for sublist in lists:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lists, element):\n count = 0\n for sublist in lists:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}]}, "Mbpp/428": {"dps": 84.29752066115702, "dps_norm": 55.55555555555556, "pass@1": 99.0, "profiled": [{"solution": "def shell_sort(arr):\n gap = len(arr) // 2\n\n while gap > 0:\n for i in range(gap, len(arr)):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(lst):\n gap = len(lst) // 2\n while gap > 0:\n for i in range(gap, len(lst)):\n temp = lst[i]\n j = i\n while j >= gap and lst[j - gap] > temp:\n lst[j] = lst[j - gap]\n j -= gap\n lst[j] = temp\n gap //= 2\n return lst", "matching_cluster_idx": 4}, {"solution": "def shell_sort(array):\n n = len(array)\n gap = n//2\n\n while gap > 0:\n for i in range(gap,n):\n temp = array[i]\n j = i\n while j >= gap and array[j-gap] >temp:\n array[j] = array[j-gap]\n j -= gap\n array[j] = temp\n gap //= 2\n\n return array", "matching_cluster_idx": 4}, {"solution": "def shell_sort(input_list):\n gap = len(input_list) // 2\n while gap > 0:\n for i in range(gap, len(input_list)):\n temp = input_list[i]\n j = i\n while j >= gap and input_list[j - gap] > temp:\n input_list[j] = input_list[j - gap]\n j = j-gap\n input_list[j] = temp\n gap = gap // 2\n return input_list", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n # Start with a big gap, then reduce the gap\n n = len(arr)\n gap = n // 2\n\n # Do a gapped insertion sort for this gap size.\n # The first gap elements a[0..gap-1] are already in gapped order\n # keep adding one more element until the entire array is gap sorted\n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n while j >= gap and arr[j-gap] > temp:\n arr[j] = arr[j-gap]\n j -= gap\n arr[j] = temp\n\n # Reduce the gap for the next iteration\n gap //= 2\n\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(array):\n # Start with a big gap, then reduce the gap\n n = len(array)\n gap = n // 2\n\n # Do a gapped insertion sort for this gap size.\n while gap > 0:\n for i in range(gap, n):\n temp = array[i]\n\n j = i\n while j >= gap and array[j - gap] > temp:\n array[j] = array[j - gap]\n j -= gap\n\n array[j] = temp\n\n gap //= 2\n\n return array", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n gap = len(arr) // 2\n while gap > 0:\n for i in range(gap, len(arr)):\n temp = arr[i]\n j = i\n while j >= gap and arr[j-gap] > temp:\n arr[j] = arr[j-gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n gap = len(arr) // 2\n while gap > 0:\n for i in range(gap, len(arr)):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n\n arr[j] = temp\n gap //= 2\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2\n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n while j >= gap and arr[j-gap] > temp:\n arr[j] = arr[j-gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n//2\n\n while gap > 0:\n for i in range(gap,n):\n temp = arr[i]\n j = i\n while j >= gap and arr[j-gap] >temp:\n arr[j] = arr[j-gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(input_array):\n gap = len(input_array) // 2\n while gap > 0:\n for i in range(gap, len(input_array)):\n temp = input_array[i]\n j = i\n while j >= gap and input_array[j - gap] > temp:\n input_array[j] = input_array[j - gap]\n j = j-gap\n input_array[j] = temp\n gap = gap // 2\n return input_array", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n gap = len(arr) // 2\n while gap > 0:\n for i in range(gap, len(arr)):\n temp = arr[i]\n j = i\n while j >= gap and arr[j-gap] > temp:\n arr[j] = arr[j-gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n gap = len(arr) // 2\n while gap > 0:\n for i in range(gap, len(arr)):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2\n\n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n\n while j >= gap and arr[j-gap] > temp:\n arr[j] = arr[j-gap]\n j -= gap\n\n arr[j] = temp\n gap //= 2\n \n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n gap = len(arr) // 2\n while gap > 0:\n for i in range(gap, len(arr)):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n \"\"\"\n This function sorts an array using shell sort.\n \"\"\"\n n = len(arr)\n gap = n//2\n\n # start with a big gap, then reduce the gap\n while gap > 0:\n\n # for every gap, do a gapped insertion sort\n for i in range(gap,n):\n\n temp = arr[i]\n\n j = i\n while j >= gap and arr[j-gap] > temp:\n arr[j] = arr[j-gap]\n j -= gap\n\n arr[j] = temp\n gap //= 2\n\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n gap = len(arr) // 2\n # start with a big gap, then reduce the gap\n while gap > 0:\n\n # do a gapped insertion sort for this gap size.\n # the first gap elements a[0..gap-1] are already in gapped order\n # keep adding one more element until the entire array is gap sorted\n for i in range(gap, len(arr)):\n\n # add a[i] to the elements that have been gap sorted\n # save a[i] in temp and make a hole at position i\n temp = arr[i]\n\n # shift earlier gap-sorted elements up until the correct location for a[i] is found\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n\n # put temp (the original a[i]) in its correct location\n arr[j] = temp\n gap //= 2\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(array):\n gap = len(array) // 2\n while gap > 0:\n for i in range(gap, len(array)):\n temp = array[i]\n j = i\n while j >= gap and array[j - gap] > temp:\n array[j] = array[j - gap]\n j -= gap\n array[j] = temp\n gap //= 2\n return array", "matching_cluster_idx": 4}, {"solution": "def shell_sort(array):\n n = len(array)\n gap = n//2\n\n while gap > 0:\n for i in range(gap,n):\n temp = array[i]\n j = i\n while j >= gap and array[j-gap] >temp:\n array[j] = array[j-gap]\n j = j-gap\n array[j] = temp\n gap = gap//2\n return array", "matching_cluster_idx": 4}, {"solution": "def shell_sort(array):\n n = len(array)\n gap = n//2\n\n while gap > 0:\n for i in range(gap, n):\n temp = array[i]\n j = i\n while j >= gap and array[j-gap] > temp:\n array[j] = array[j-gap]\n j -= gap\n array[j] = temp\n gap //= 2\n return array", "matching_cluster_idx": 4}]}, "Mbpp/433": {"dps": 71.06382978723404, "dps_norm": 68.0, "pass@1": 58.0, "profiled": [{"solution": "def check_greater(arr, num):\n \"\"\"\n Function to check whether the entered number is greater than the elements of the given array.\n \"\"\"\n return all(i < num for i in arr)", "matching_cluster_idx": 2}, {"solution": "def check_greater(array, num):\n \"\"\"\n Check if the number is greater than all elements in the array.\n\n :param array: List of integers\n :param num: Integer\n :return: Boolean\n \"\"\"\n return all(num > i for i in array)", "matching_cluster_idx": 2}, {"solution": "def check_greater(input_list, value):\n \"\"\"\n Function to check whether the entered number is greater than all elements of the given list.\n \"\"\"\n for item in input_list:\n if item >= value:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def check_greater(num_list, num):\n \"\"\"\n Check whether num is greater than every element in num_list.\n \"\"\"\n return all(num > x for x in num_list)", "matching_cluster_idx": 2}, {"solution": "def check_greater(arr, num):\n \"\"\"\n Function to check if a number is greater than elements of an array\n \"\"\"\n return all(num > x for x in arr)", "matching_cluster_idx": 2}, {"solution": "def check_greater(numbers, num):\n \"\"\"Check if num is greater than all elements in numbers.\"\"\"\n return all(num > number for number in numbers)", "matching_cluster_idx": 2}, {"solution": "def check_greater(lst, num):\n return all(x < num for x in lst)", "matching_cluster_idx": 2}, {"solution": "def check_greater(arr, n):\n \"\"\"\n Function to check if entered number is greater than the elements in given array.\n \"\"\"\n for i in arr:\n if i >= n:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def check_greater(array, number):\n \"\"\"\n Function to check whether the entered number is greater than the elements of the given array.\n \"\"\"\n for element in array:\n if number <= element:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def check_greater(array, number):\n \"\"\"\n Check if the entered number is greater than the elements of the given array.\n\n Parameters:\n array (list): List of integers.\n number (int): The number to be checked.\n\n Returns:\n bool: True if the number is greater than all elements in the array, False otherwise.\n\n Example:\n >>> check_greater([1, 2, 3, 4, 5], 4)\n False\n \"\"\"\n return all(number > element for element in array)", "matching_cluster_idx": 2}, {"solution": "def check_greater(arr, num):\n return all(i < num for i in arr)", "matching_cluster_idx": 2}, {"solution": "def check_greater(array, num):\n \"\"\"Checks if the entered number is greater than any element in the given array.\"\"\"\n return all(num > i for i in array)", "matching_cluster_idx": 2}, {"solution": "def check_greater(arr, num):\n return all(num > x for x in arr)", "matching_cluster_idx": 2}, {"solution": "def check_greater(input_array, number):\n \"\"\"\n Checks if the entered number is greater than the elements of the given array.\n \"\"\"\n return all(number > element for element in input_array)", "matching_cluster_idx": 2}, {"solution": "def check_greater(array, number):\n \"\"\"\n Check if a number is greater than all the elements in an array.\n \"\"\"\n return all(number > elem for elem in array)", "matching_cluster_idx": 2}, {"solution": "def check_greater(arr, num):\n \"\"\"\n Check if num is greater than all elements in arr.\n \"\"\"\n return all(num > x for x in arr)", "matching_cluster_idx": 2}, {"solution": "def check_greater(array, num):\n \"\"\"\n This function checks whether the entered number is greater than the elements of the given array.\n \"\"\"\n return all(num > x for x in array)", "matching_cluster_idx": 2}, {"solution": "def check_greater(array, num):\n \"\"\"\n Check whether num is greater than elements of the array.\n \n Parameters:\n array (list): Array of integers.\n num (int): Number to be checked.\n \n Returns:\n bool: True if num is greater than all elements in array, False otherwise.\n \"\"\"\n\n for elem in array:\n if num <= elem:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def check_greater(arr, num):\n return all(num > i for i in arr)", "matching_cluster_idx": 2}, {"solution": "def check_greater(arr, n):\n \"\"\"\n This function checks whether the entered number is greater than the elements of the given array.\n \"\"\"\n return all(n > x for x in arr)", "matching_cluster_idx": 2}]}, "Mbpp/437": {"dps": 86.1029411764706, "dps_norm": 63.0, "pass@1": 50.0, "profiled": [{"solution": "def remove_odd(input_string):\n return ''.join([input_string[i] for i in range(len(input_string)) if i % 2 != 0])", "matching_cluster_idx": 0}, {"solution": "def remove_odd(s):\n return \"\".join([s[i] for i in range(1, len(s), 2)])", "matching_cluster_idx": 2}, {"solution": "def remove_odd(input_string):\n result = \"\"\n for i in range(len(input_string)):\n if i % 2 == 1:\n result += input_string[i]\n return result", "matching_cluster_idx": 0}, {"solution": "def remove_odd(s):\n return ''.join([s[i] for i in range(len(s)) if i % 2 != 0])", "matching_cluster_idx": 0}, {"solution": "def remove_odd(input_string):\n return \"\".join(char for index, char in enumerate(input_string) if index % 2 != 0)", "matching_cluster_idx": 0}, {"solution": "def remove_odd(s):\n return s[1::2]", "matching_cluster_idx": 4}, {"solution": "def remove_odd(input_string):\n return ''.join([input_string[i] for i in range(len(input_string)) if i % 2 == 1])", "matching_cluster_idx": 1}, {"solution": "def remove_odd(input_string):\n return input_string[1::2]", "matching_cluster_idx": 4}, {"solution": "def remove_odd(string):\n return ''.join(string[i] for i in range(len(string)) if i % 2 != 0)", "matching_cluster_idx": 0}, {"solution": "def remove_odd(input_string):\n return ''.join([input_string[i] for i in range(1, len(input_string), 2)])", "matching_cluster_idx": 2}, {"solution": "def remove_odd(input_string):\n return ''.join([input_string[i] for i in range(len(input_string)) if i % 2 == 1])", "matching_cluster_idx": 1}, {"solution": "def remove_odd(input_str):\n return input_str[1::2]", "matching_cluster_idx": 3}, {"solution": "def remove_odd(s):\n \"\"\"\n Write a function to remove odd characters in a string.\n \"\"\"\n return s[1::2]", "matching_cluster_idx": 4}, {"solution": "def remove_odd(s):\n return s[1::2]", "matching_cluster_idx": 4}, {"solution": "def remove_odd(word):\n return word[1::2]", "matching_cluster_idx": 4}, {"solution": "def remove_odd(string):\n return \"\".join(string[i] for i in range(len(string)) if i%2 == 1)", "matching_cluster_idx": 0}, {"solution": "def remove_odd(s):\n return s[1::2]", "matching_cluster_idx": 4}, {"solution": "def remove_odd(s):\n return ''.join([s[i] for i in range(1, len(s), 2)])", "matching_cluster_idx": 2}, {"solution": "def remove_odd(input_str):\n return input_str[1::2]\ninput_str = \"I love programming\"", "matching_cluster_idx": 4}, {"solution": "def remove_odd(s):\n return s[1::2]", "matching_cluster_idx": 4}]}, "Mbpp/440": {"dps": null, "dps_norm": null, "pass@1": 3.0, "profiled": []}, "Mbpp/446": {"dps": 96.45320197044335, "dps_norm": 64.0, "pass@1": 37.0, "profiled": [{"solution": "def count_Occurrence(input_tuple, input_list):\n \"\"\"\n Returns the count of elements in list that appear in tuple\n\n Parameters:\n input_tuple (tuple): Tuple of elements\n input_list (list): List of elements to count\n\n Returns:\n int: Count of elements in list that appear in tuple\n \"\"\"\n # Initial count is 0\n count = 0\n\n # Iterate over each element in list\n for element in input_list:\n # Add the count of each element in tuple to the count\n count += input_tuple.count(element)\n \n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(input_tuple, element_list):\n return sum([input_tuple.count(el) for el in element_list])", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tuple_, list_):\n return sum([tuple_.count(x) for x in list_])\ntuple_ = ('a', 'a', 'c', 'b', 'd')\nlist_ = ['a', 'b']", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tup, lst):\n return sum([tup.count(item) for item in lst])", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tup, lst):\n \"\"\"\n A function to count the occurrence of all elements of list in a tuple.\n \"\"\"\n return sum([tup.count(x) for x in lst])", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tup, lst):\n \"\"\"\n Count the occurrence of all elements of list in a tuple.\n\n Parameters:\n tup (tuple): A tuple with elements to be checked.\n lst (list): A list of elements to check for in the tuple.\n\n Returns:\n int: The total count of occurrences of all elements in the list.\n\n >>> count_Occurrence(('a', 'a', 'c', 'b', 'd'),['a', 'b'])\n 3\n \"\"\"\n # Initialize the count to zero\n count = 0\n \n # Loop through each element in the list\n for elem in lst:\n # Count the occurrences in the tuple\n count += tup.count(elem)\n\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(input_tuple, input_list):\n return sum([input_tuple.count(i) for i in input_list])", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tup, lst):\n \"\"\"\n This function counts the occurrences of elements from a list within a tuple.\n \"\"\"\n count = 0\n for ele in lst:\n count += tup.count(ele)\n return count\ntup = ('a', 'a', 'c', 'b', 'd')\nlst = ['a', 'b']", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tup, lst):\n return sum([tup.count(x) for x in lst])", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(input_tuple, element_list):\n return sum([input_tuple.count(x) for x in element_list])", "matching_cluster_idx": 2}, {"solution": "from collections import Counter\ndef count_Occurrence(tup, elements):\n count_tuple = Counter(tup)\n count_elements = sum(count_tuple[elem] for elem in elements)\n return count_elements", "matching_cluster_idx": 4}, {"solution": "def count_Occurrence(t, lst):\n # count occurrences of elements in list\n return sum([t.count(i) for i in lst])", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(t, l):\n count = 0\n for i in l:\n count += t.count(i)\n return count", "matching_cluster_idx": 2}, {"solution": "from collections import Counter\ndef count_Occurrence(input_tuple, check_list):\n # convert input_tuple into a counter object\n input_counter = Counter(input_tuple)\n\n # return the sum of counts for each element in check_list\n return sum(input_counter[item] for item in check_list)", "matching_cluster_idx": 4}, {"solution": "def count_Occurrence(tup, lst):\n # Convert tuple to list\n tup_list = list(tup)\n\n # Initialize a counter\n count = 0\n\n # Loop over the elements in the list\n for element in lst:\n # Count the occurrence of each element in the list\n count += tup_list.count(element)\n\n # Return the final count\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tpl, lst):\n return sum([tpl.count(i) for i in lst])", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(t, l):\n return sum([t.count(i) for i in l])", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(t,l):\n \"\"\"Counts the occurrences of elements of l in t.\"\"\"\n count = 0\n for item in l:\n count += t.count(item)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tuple_input, list_input):\n \"\"\"\n Returns the count of all elements of list_input in tuple_input.\n\n :param tuple_input: The tuple where elements are to be counted.\n :param list_input: The list containing the elements to be counted.\n :returns: The total count of elements in list_input present in tuple_input.\n \"\"\"\n \n return sum([tuple_input.count(i) for i in list_input])", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(t,l):\n \"\"\"\n This function counts the occurrence of all elements of list in a tuple.\n\n Parameters:\n t (tuple): Input tuple to be analyzed.\n l (list): List of elements to be counted.\n\n Returns:\n int: The count of occurrences of the elements of list in the tuple.\n\n Example:\n >>> count_Occurrence(('a', 'a', 'c', 'b', 'd'),['a', 'b'])\n 3\n \"\"\"\n return sum([t.count(i) for i in l])", "matching_cluster_idx": 2}]}, "Mbpp/451": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 95.0, "profiled": [{"solution": "def remove_whitespaces(input_string):\n \"\"\"\n This function takes a string and removes all the whitespace characters from it.\n\n :param input_string: The string from which whitespaces are to be removed\n :type input_string: str\n :return: The input string without any whitespace characters\n :rtype: str\n \"\"\"\n return input_string.replace(' ', '')", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(s):\n return s.replace(' ', '')", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(string):\n return string.replace(' ', '')", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(string):\n return string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(s):\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string: str) -> str:\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string):\n return input_string.replace(\" \", \"\")\ninput_string = \" Google Flutter \"", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string):\n return input_string.replace(' ', '')", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(string):\n return string.replace(' ', '')", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(s):\n \"\"\"\n Removes all whitespaces from the given string.\n \n Parameters:\n s (str): The string from which whitespaces will be removed\n \n Returns:\n str: The string without whitespaces\n \"\"\"\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(s):\n \"\"\"\n Removes all whitespaces from the given string.\n \"\"\"\n return s.replace(' ', '')", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_str):\n return input_str.replace(' ', '')", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string):\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string):\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(s):\n return s.replace(' ', '')", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string):\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(s: str) -> str:\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string):\n \"\"\"\n Function to remove all whitespaces from the given string.\n \"\"\"\n return input_string.replace(' ', '')", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(s):\n return s.replace(' ', '')", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(s):\n \"\"\"\n Function to remove all whitespaces from the given string\n \"\"\"\n return s.replace(' ', '')", "matching_cluster_idx": 4}]}, "Mbpp/456": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def reverse_string_list(str_list):\n return [s[::-1] for s in str_list]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(input_list):\n reversed_list = []\n for string in input_list:\n reversed_list.append(string[::-1])\n return reversed_list", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(input_list):\n return [i[::-1] for i in input_list]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(lst):\n \"\"\"\n This function accepts a list of strings as input and returns a new list \n where each string is reversed.\n \"\"\"\n return [i[::-1] for i in lst]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(lst):\n return [s[::-1] for s in lst]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(input_list):\n return [s[::-1] for s in input_list]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n \"\"\"\n This function takes a list of strings as input and returns a new list where every string has been reversed.\n \"\"\"\n return [s[::-1] for s in string_list]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(lst):\n return [s[::-1] for s in lst]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(strings):\n return [s[::-1] for s in strings]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(list_of_strings):\n return [s[::-1] for s in list_of_strings]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(input_list):\n # Use list comprehension to reverse each string in the list\n reversed_list = [s[::-1] for s in input_list]\n return reversed_list", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(strings):\n \"\"\"\n Reverses the order of characters in each string in the given list.\n \"\"\"\n # List comprehension to create new reversed list\n reversed_list = [s[::-1] for s in strings]\n return reversed_list", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(lst):\n return [s[::-1] for s in lst]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(str_list):\n reversed_list = [s[::-1] for s in str_list]\n return reversed_list", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(input_list):\n return [item[::-1] for item in input_list]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(s_list):\n return [s[::-1] for s in s_list]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(input_list):\n return [i[::-1] for i in input_list]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(input_list):\n return [s[::-1] for s in input_list]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(input_list):\n reversed_list = [x[::-1] for x in input_list]\n return reversed_list", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(input_list):\n return [i[::-1] for i in input_list]", "matching_cluster_idx": 4}]}, "Mbpp/460": {"dps": 89.61538461538461, "dps_norm": 96.0, "pass@1": 75.0, "profiled": [{"solution": "def Extract(lst):\n return [item[0] for item in lst]", "matching_cluster_idx": 3}, {"solution": "def Extract(lists):\n return [sublist[0] for sublist in lists]", "matching_cluster_idx": 4}, {"solution": "def Extract(sublist):\n # list comprehension to get the first element of each sublist\n return [i[0] for i in sublist]", "matching_cluster_idx": 4}, {"solution": "def Extract(main_list):\n return [sub_list[0] for sub_list in main_list]", "matching_cluster_idx": 4}, {"solution": "def Extract(lst):\n return [sublist[0] for sublist in lst]", "matching_cluster_idx": 4}, {"solution": "def Extract(lst):\n return [sublist[0] for sublist in lst]", "matching_cluster_idx": 4}, {"solution": "def Extract(lst):\n \"\"\"\n Extracts the first element of each sublist in the provided list of lists.\n :param lst: A list of lists.\n :return: A list of the first elements of each sublist.\n \"\"\"\n return [sublist[0] for sublist in lst]", "matching_cluster_idx": 4}, {"solution": "def Extract(input_list):\n return [sublist[0] for sublist in input_list]", "matching_cluster_idx": 4}, {"solution": "def Extract(lst):\n return [item[0] for item in lst]", "matching_cluster_idx": 3}, {"solution": "def Extract(sublists):\n # Use a list comprehension to get the first element of each sublist.\n return [sublist[0] for sublist in sublists]", "matching_cluster_idx": 4}, {"solution": "def Extract(nested_list):\n return [sublist[0] for sublist in nested_list]", "matching_cluster_idx": 4}, {"solution": "def Extract(sublists):\n return [sublist[0] for sublist in sublists]", "matching_cluster_idx": 3}, {"solution": "def Extract(lst):\n return [sub_lst[0] for sub_lst in lst]", "matching_cluster_idx": 4}, {"solution": "def Extract(list_of_sublists):\n \"\"\"\n Function to get the first element of each sublist.\n \"\"\"\n return [sublist[0] for sublist in list_of_sublists]", "matching_cluster_idx": 4}, {"solution": "def Extract(lst):\n \"\"\"This function takes a list of lists as input and returns a list\n consisting of the first element of each sublist.\n \"\"\"\n return [sublist[0] for sublist in lst]", "matching_cluster_idx": 4}, {"solution": "def Extract(lst):\n return [item[0] for item in lst]", "matching_cluster_idx": 3}, {"solution": "def Extract(lst):\n \"\"\"Returns the first element of each sublist.\"\"\"\n return [sublist[0] for sublist in lst]", "matching_cluster_idx": 4}, {"solution": "def Extract(lst):\n return [sublist[0] for sublist in lst]", "matching_cluster_idx": 4}, {"solution": "def Extract(input_list):\n \"\"\"\n Function that gets the first element of each sublist\n \"\"\"\n return [sublist[0] for sublist in input_list]", "matching_cluster_idx": 4}, {"solution": "def Extract(lst):\n return [sub_lst[0] for sub_lst in lst]", "matching_cluster_idx": 4}]}, "Mbpp/474": {"dps": 93.46341463414635, "dps_norm": 94.28571428571429, "pass@1": 100.0, "profiled": [{"solution": "def replace_char(string, char_to_replace, char_to_insert):\n return string.replace(char_to_replace, char_to_insert)", "matching_cluster_idx": 6}, {"solution": "def replace_char(input_string, old_char, new_char):\n \"\"\"\n This function replaces the occurrences of old_char with new_char in the input_string.\n \"\"\"\n return input_string.replace(old_char, new_char)\ninput_string = \"polygon\"\nold_char = 'y'\nnew_char = 'l'", "matching_cluster_idx": 6}, {"solution": "def replace_char(string, old, new):\n \"\"\"\n Replaces all occurrences of old character with new character in a string.\n\n Parameters:\n string (str): The string to be modified.\n old (str): The character to be replaced.\n new (str): The character to replace the old character with.\n\n Returns:\n str: The modified string.\n \"\"\"\n return string.replace(old, new)", "matching_cluster_idx": 6}, {"solution": "def replace_char(string, old_char, new_char):\n return string.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, old, new):\n # use built-in replace function\n return s.replace(old, new)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, old, new):\n \"\"\"\n This function replaces a character in a string with another character.\n Args:\n s (str): The input string.\n old (str): The character to replace.\n new (str): The new character.\n Returns:\n str: The resulting string with replaced characters.\n \"\"\"\n\n # replace characters in the string\n s = s.replace(old, new)\n\n return s", "matching_cluster_idx": 6}, {"solution": "def replace_char(string, old_char, new_char):\n \"\"\"\n Function to replace characters in a string.\n\n Parameters:\n string (str): The input string.\n old_char (str): The character to be replaced.\n new_char (str): The character that will replace old_char.\n\n Returns:\n str: The string with the replaced characters.\n \"\"\"\n return string.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, target, replacement):\n return s.replace(target, replacement)", "matching_cluster_idx": 6}, {"solution": "def replace_char(string, old, new):\n \"\"\"\n Replace old character by new character in a given string.\n \"\"\"\n new_string = ''\n\n for character in string:\n if character == old:\n new_string += new\n else:\n new_string += character\n\n return new_string", "matching_cluster_idx": 2}, {"solution": "def replace_char(input_string, old_char, new_char):\n return input_string.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(input_str, target_char, replacement_char):\n \"\"\"\n This function replaces a target character in the input string with a replacement character.\n :param input_str: input string to process.\n :param target_char: character to replace.\n :param replacement_char: character to replace with.\n :return: processed string.\n \"\"\"\n return input_str.replace(target_char, replacement_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(str, old_char, new_char):\n \"\"\"Replace all occurrences of old_char with new_char in str\"\"\"\n return str.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(str, char_to_replace, char_to_add):\n \"\"\"\n Replaces all occurrences of char_to_replace in str with char_to_add\n \"\"\"\n result = \"\"\n for char in str:\n if char == char_to_replace:\n result += char_to_add\n else:\n result += char\n return result", "matching_cluster_idx": 2}, {"solution": "def replace_char(string, char_to_replace, new_char):\n return string.replace(char_to_replace, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(string, target, replacement):\n return string.replace(target, replacement)", "matching_cluster_idx": 6}, {"solution": "def replace_char(str, old, new):\n return str.replace(old, new)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, old, new):\n \"\"\"\n Replaces all occurrences of character 'old' in a string 's' with 'new'.\n\n Args:\n s (str): The input string.\n old (str): The character to be replaced.\n new (str): The character to replace with.\n\n Returns:\n str: The string with all occurrences of 'old' replaced by 'new'.\n \"\"\"\n # Uses the replace() method to replace all occurrences of 'old' with 'new'\n return s.replace(old, new)", "matching_cluster_idx": 6}, {"solution": "def replace_char(input_string:str, old_char:str, new_char:str) -> str:\n return input_string.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(string: str, char_to_replace: str, new_char: str) -> str:\n \"\"\"\n Function to replace characters in a string.\n \"\"\"\n return string.replace(char_to_replace, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, old, new):\n \"\"\"\n Replaces all occurrences of old character with new character in a string.\n Args:\n s (str): The input string.\n old (str): The character to be replaced.\n new (str): The character to replace with.\n Returns:\n str: The new string with replaced characters.\n \"\"\"\n return s.replace(old, new)", "matching_cluster_idx": 6}]}, "Mbpp/476": {"dps": 93.05369127516778, "dps_norm": 95.83333333333333, "pass@1": 100.0, "profiled": [{"solution": "def big_sum(array):\n \"\"\"\n This function finds the sum of the largest and smallest value in a given array.\n \"\"\"\n if len(array) == 0:\n return 0\n \n return min(array) + max(array)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n # Check if array is not empty\n if len(arr) > 0:\n return max(arr) + min(arr)\n else:\n raise ValueError('Array is empty')", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n return max(arr) + min(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n if len(arr) == 0:\n return 0\n else:\n return max(arr) + min(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(lst):\n return min(lst) + max(lst)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n if len(arr) == 0:\n return None\n return max(arr) + min(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n if len(arr) == 0:\n return 0\n return max(arr) + min(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n \"\"\"\n Finds the sum of the largest and smallest value in a given array.\n \"\"\"\n # If the array is empty, return 0\n if not arr:\n return 0\n \n # Initialize the largest and smallest values\n largest = smallest = arr[0]\n \n # Traverse the array to find the largest and smallest values\n for num in arr:\n if num > largest:\n largest = num\n elif num < smallest:\n smallest = num\n \n # Return the sum of the largest and smallest values\n return largest + smallest", "matching_cluster_idx": 3}, {"solution": "def big_sum(arr):\n if arr:\n return min(arr) + max(arr)\n else:\n raise ValueError(\"The array is empty.\")", "matching_cluster_idx": 5}, {"solution": "def big_sum(array):\n if len(array) == 0:\n return 0\n return min(array) + max(array)", "matching_cluster_idx": 5}, {"solution": "def big_sum(lst):\n if not lst:\n return 0\n return min(lst) + max(lst)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n if len(arr) == 0:\n return None\n return max(arr) + min(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n return max(arr) + min(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(lst):\n if not lst:\n raise ValueError(\"List is empty\")\n return max(lst) + min(lst)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n return max(arr) + min(arr)", "matching_cluster_idx": 5}, {"solution": "import random\ndef big_sum(nums):\n return max(nums) + min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_sum(numbers):\n \"\"\"Return the sum of the largest and smallest value in the array.\"\"\"\n # check if the list is not empty\n if not numbers:\n return None\n # return the sum of the largest and smallest elements\n return max(numbers) + min(numbers)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n # Check if the array is not empty\n if len(arr) > 0:\n return max(arr) + min(arr)\n else:\n return None", "matching_cluster_idx": 5}, {"solution": "def big_sum(array):\n if len(array) == 0:\n return 0\n\n smallest = array[0]\n largest = array[0]\n\n for i in range(1, len(array)):\n if array[i] < smallest:\n smallest = array[i]\n elif array[i] > largest:\n largest = array[i]\n\n return smallest + largest", "matching_cluster_idx": 2}, {"solution": "def big_sum(array):\n if array:\n return max(array) + min(array)\n else:\n return \"Array is empty\"", "matching_cluster_idx": 5}]}, "Mbpp/477": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 59.0, "profiled": [{"solution": "def is_lower(s):\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(input_string):\n \"\"\"Convert string to lowercase.\"\"\"\n return input_string.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(string):\n return string.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(string):\n return string.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(string):\n \"\"\"\n This function converts a given string to lower case\n \"\"\"\n return string.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s: str) -> str:\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s: str) -> str:\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(string):\n return string.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(input_str):\n \"\"\"\n Function to convert the given string to lower case.\n\n Args:\n input_str: the input string to be converted to lowercase\n\n Returns:\n the lowercased string\n \"\"\"\n return input_str.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(input_string):\n return input_string.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(input_str):\n return input_str.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n \"\"\"\n Convert the given string to lower case.\n :param s: String to be converted\n :type s: str\n :return: The string converted to lower case\n :rtype: str\n \"\"\"\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s: str) -> str:\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s: str) -> str:\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s: str) -> str:\n \"\"\"\n Convert the given string to lower case.\n\n :param s: The string to be converted.\n :return: The lower case string.\n \"\"\"\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n return s.lower()", "matching_cluster_idx": 4}]}, "Mbpp/563": {"dps": 72.40437158469946, "dps_norm": 75.45454545454545, "pass@1": 68.0, "profiled": [{"solution": "def extract_values(s):\n values = []\n inside_quote = False\n temp_val = ''\n for char in s:\n if char == '\"':\n if inside_quote:\n values.append(temp_val)\n temp_val = ''\n inside_quote = not inside_quote\n elif inside_quote:\n temp_val += char\n return values", "matching_cluster_idx": 6}, {"solution": "import re\ndef extract_values(s):\n pattern = re.compile(r'\"(.*?)\"')\n return pattern.findall(s)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(s):\n \"\"\"\n Extracts values between quotation marks from a string\n \"\"\"\n return re.findall(r'\"([^\"]*)\"', s)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(string):\n pattern = r'\"(.*?)\"'\n return re.findall(pattern, string)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(s):\n # Use regex to find matches between quotation marks\n matches = re.findall(r'\"([^\"]*)\"', s)\n return matches", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(s):\n return re.findall(r'\"(.*?)\"', s)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(s):\n \"\"\"\n This function extracts values between quotation marks from a string.\n \"\"\"\n return re.findall(r'\"(.*?)\"', s)\ns = '\"Python\", \"PHP\", \"Java\"'", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(text):\n \"\"\"\n Function to extract values between quotation marks from a string.\n \"\"\"\n return re.findall(r'\"([^\"]*)\"', text)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(input_string):\n pattern = re.compile(r'\"(.*?)\"')\n matches = pattern.findall(input_string)\n return matches", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(string):\n return re.findall(r'\"([^\"]*)\"', string)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(s):\n return re.findall(r'\"([^\"]*)\"', s)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(input_string):\n values = re.findall(r'\"([^\"]*)\"', input_string)\n return values", "matching_cluster_idx": 8}, {"solution": "def extract_values(input_string):\n values = []\n start = end = 0\n for i, char in enumerate(input_string):\n if char == '\"' and start == 0:\n start = i + 1\n elif char == '\"' and start != 0:\n end = i\n values.append(input_string[start:end])\n start = end = 0\n return values", "matching_cluster_idx": 3}, {"solution": "import re\ndef extract_values(string):\n pattern = r'\"(.*?)\"'\n values = re.findall(pattern, string)\n return values", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(s):\n \"\"\"\n Function to extract values between quotation marks from a string\n \"\"\"\n # Regular expression pattern to match values between quotation marks\n pattern = r'\"([^\"]*)\"'\n\n # Find all matches\n matches = re.findall(pattern, s)\n\n # Return the matches\n return matches", "matching_cluster_idx": 8}, {"solution": "def extract_values(string):\n \"\"\"\n A function to extract values between quotation marks from a string.\n \"\"\"\n result = []\n word = ''\n in_quotes = False\n\n for char in string:\n if char == '\"':\n if in_quotes:\n result.append(word)\n word = ''\n in_quotes = not in_quotes\n elif in_quotes:\n word += char\n\n return result", "matching_cluster_idx": 6}, {"solution": "import re\ndef extract_values(input_str):\n \"\"\"\n This function extracts values between quotation marks from a string.\n \"\"\"\n pattern = re.compile(r'\"(.*?)\"')\n return pattern.findall(input_str)", "matching_cluster_idx": 8}, {"solution": "def extract_values(string):\n values = []\n start = end = 0\n in_quote = False\n for i, char in enumerate(string):\n if char == '\"' and not in_quote:\n in_quote = True\n start = i + 1\n elif char == '\"' and in_quote:\n in_quote = False\n end = i\n values.append(string[start:end])\n return values", "matching_cluster_idx": 3}, {"solution": "import re\ndef extract_values(s):\n return re.findall(r'\"(.*?)\"', s)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(text):\n return re.findall(r'\"(.*?)\"', text)", "matching_cluster_idx": 8}]}, "Mbpp/572": {"dps": 89.25925925925927, "dps_norm": 80.71428571428571, "pass@1": 73.0, "profiled": [{"solution": "def two_unique_nums(nums):\n counts = {}\n for num in nums:\n if num not in counts:\n counts[num] = 1\n else:\n counts[num] += 1\n\n unique_nums = [num for num, count in counts.items() if count == 1]\n return unique_nums", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(lst):\n return [num for num in lst if lst.count(num) == 1]", "matching_cluster_idx": 1}, {"solution": "def two_unique_nums(numbers):\n count_dict = {}\n for num in numbers:\n if num in count_dict:\n count_dict[num] += 1\n else:\n count_dict[num] = 1\n return [key for key, value in count_dict.items() if value == 1]", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(lst):\n count_dict = {}\n for num in lst:\n if num in count_dict:\n count_dict[num] += 1\n else:\n count_dict[num] = 1\n\n unique_nums = [num for num, count in count_dict.items() if count == 1]\n \n return unique_nums", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(numbers):\n counts = {}\n for num in numbers:\n if num in counts:\n counts[num] += 1\n else:\n counts[num] = 1\n return [num for num, count in counts.items() if count == 1]", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(nums):\n counts = {}\n result = []\n\n for num in nums:\n if num in counts:\n counts[num] += 1\n else:\n counts[num] = 1\n\n for num in counts:\n if counts[num] == 1:\n result.append(num)\n\n return result", "matching_cluster_idx": 5}, {"solution": "def remove_duplicate_numbers(nums):\n counts = {}\n for num in nums:\n if num in counts:\n counts[num] += 1\n else:\n counts[num] = 1\n return [num for num in counts if counts[num] == 1]\ndef two_unique_nums(nums):\n return remove_duplicate_numbers(nums)", "matching_cluster_idx": 5}, {"solution": "def remove_duplicates(input_list):\n # An empty dictionary to store the count of each number in the list\n count_dict = {}\n\n # For each number in the list\n for num in input_list:\n # If the number is not in the dictionary, add it\n if num not in count_dict:\n count_dict[num] = 1\n # If the number is already in the dictionary, increment its count\n else:\n count_dict[num] += 1\n\n # Filter out the numbers that have a count of more than 1\n result = [num for num in count_dict if count_dict[num] == 1]\n\n # Return the result\n return result\ndef two_unique_nums(input_list):\n return remove_duplicates(input_list)", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(nums):\n \"\"\"\n Function to remove duplicate numbers from a given list\n \"\"\"\n # Create an empty dictionary\n num_dict = {}\n # Iterate over the list\n for num in nums:\n # If number is in the dictionary, increment its count\n if num in num_dict:\n num_dict[num] += 1\n # Otherwise, add it to the dictionary\n else:\n num_dict[num] = 1\n # Initialize an empty list to store unique numbers\n unique_nums = []\n # Iterate over the dictionary\n for num, count in num_dict.items():\n # If count is 1, number is unique so add it to the list\n if count == 1:\n unique_nums.append(num)\n return unique_nums", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(num_list):\n counts = {}\n for num in num_list:\n if num in counts:\n counts[num] += 1\n else:\n counts[num] = 1\n\n unique_nums = [key for key, value in counts.items() if value == 1]\n\n return unique_nums", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(nums):\n # dict to store frequency of numbers\n num_freq = {}\n\n # Count frequency of each number\n for num in nums:\n if num in num_freq:\n num_freq[num] += 1\n else:\n num_freq[num] = 1\n\n # Create a list of numbers that appear once in the original list\n result = [num for num, freq in num_freq.items() if freq == 1]\n\n return result", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(nums):\n num_count = {}\n for num in nums:\n if num in num_count:\n num_count[num] += 1\n else:\n num_count[num] = 1\n return [key for key, value in num_count.items() if value == 1]", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(lst):\n num_counts = {}\n for num in lst:\n if num in num_counts:\n num_counts[num] += 1\n else:\n num_counts[num] = 1\n unique_nums = []\n for num, count in num_counts.items():\n if count == 1:\n unique_nums.append(num)\n return unique_nums", "matching_cluster_idx": 5}, {"solution": "def remove_duplicates(num_list):\n \"\"\"\n Function to remove duplicate numbers from a given list\n :param num_list: list of numbers\n :return: list of unique numbers\n \"\"\"\n counts = {}\n result = []\n\n for num in num_list:\n if num in counts:\n counts[num] += 1\n else:\n counts[num] = 1\n\n for num, count in counts.items():\n if count == 1:\n result.append(num)\n\n return result\ndef two_unique_nums(num_list):\n \"\"\"\n Function to remove duplicate numbers from a given list of numbers\n :param num_list: list of numbers\n :return: list of unique numbers\n \"\"\"\n return remove_duplicates(num_list)", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(nums):\n count_dict = {}\n result = []\n for num in nums:\n count_dict[num] = count_dict.get(num, 0) + 1\n for num in count_dict:\n if count_dict[num] == 1:\n result.append(num)\n return result", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(nums):\n counts = {}\n for num in nums:\n counts[num] = counts.get(num, 0) + 1\n return [key for key, value in counts.items() if value == 1]", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(nums):\n num_count = {}\n for num in nums:\n num_count[num] = num_count.get(num, 0) + 1\n return [num for num, count in num_count.items() if count == 1]", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(num_list):\n \"\"\"Function to remove duplicate numbers from a given list of numbers.\"\"\"\n return [num for num in num_list if num_list.count(num) == 1]", "matching_cluster_idx": 1}, {"solution": "def two_unique_nums(numbers):\n num_counts = {}\n\n # Count occurrence of each number\n for num in numbers:\n if num in num_counts:\n num_counts[num] += 1\n else:\n num_counts[num] = 1\n\n # Return numbers with count 1\n return [num for num, count in num_counts.items() if count == 1]", "matching_cluster_idx": 5}, {"solution": "from collections import Counter\ndef two_unique_nums(nums):\n \"\"\"\n Remove duplicates from the list.\n Return a list of numbers that appear only once.\n \"\"\"\n count = Counter(nums)\n return [num for num, freq in count.items() if freq == 1]", "matching_cluster_idx": 6}]}, "Mbpp/578": {"dps": 66.09523809523809, "dps_norm": 65.45454545454545, "pass@1": 100.0, "profiled": [{"solution": "def interleave_lists(list1, list2, list3):\n interleaved = []\n for i in range(len(list1)):\n interleaved.extend([list1[i], list2[i], list3[i]])\n return interleaved\nlist1 = [1,2,3,4,5,6,7]\nlist2 = [10,20,30,40,50,60,70]\nlist3 = [100,200,300,400,500,600,700]", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n interleaved_list = []\n for i in range(len(list1)):\n interleaved_list.append(list1[i])\n interleaved_list.append(list2[i])\n interleaved_list.append(list3[i])\n return interleaved_list", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n if len(list1) != len(list2) or len(list1) != len(list3):\n return \"Input lists are not of the same length.\"\n\n result = []\n for i in range(len(list1)):\n result.append(list1[i])\n result.append(list2[i])\n result.append(list3[i])\n\n return result\nlist1 = [1,2,3,4,5,6,7]\nlist2 = [10,20,30,40,50,60,70]\nlist3 = [100,200,300,400,500,600,700]", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(lst1, lst2, lst3):\n interleaved_list = []\n for i in range(len(lst1)):\n interleaved_list.append(lst1[i])\n interleaved_list.append(lst2[i])\n interleaved_list.append(lst3[i])\n return interleaved_list", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n result = []\n for item1, item2, item3 in zip(list1, list2, list3):\n result.append(item1)\n result.append(item2)\n result.append(item3)\n return result", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n # Make sure all lists have the same length\n assert len(list1) == len(list2) == len(list3), \"All lists must have the same length\"\n \n # Interleave the lists\n interleaved_list = []\n for i in range(len(list1)):\n interleaved_list.append(list1[i])\n interleaved_list.append(list2[i])\n interleaved_list.append(list3[i])\n \n return interleaved_list\nlist1 = [1,2,3,4,5,6,7]\nlist2 = [10,20,30,40,50,60,70]\nlist3 = [100,200,300,400,500,600,700]", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"\n Function to interleave 3 lists of the same length into a single flat list.\n \"\"\"\n # Check if all lists are of the same length\n assert len(list1) == len(list2) == len(list3), \"All lists must be of same length\"\n \n # Interleave the lists\n interleaved_list = [val for sublist in zip(list1, list2, list3) for val in sublist]\n \n return interleaved_list", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(l1, l2, l3):\n if len(l1) != len(l2) or len(l1) != len(l3) or len(l2) != len(l3):\n raise ValueError(\"All lists must be of the same length\")\n res = []\n for a, b, c in zip(l1, l2, l3):\n res.append(a)\n res.append(b)\n res.append(c)\n return res", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(l1, l2, l3):\n result = []\n for i in range(len(l1)):\n result.extend([l1[i], l2[i], l3[i]])\n return result", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n return [item for sublist in zip(list1, list2, list3) for item in sublist]", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(l1, l2, l3):\n if len(l1) != len(l2) or len(l1) != len(l3):\n raise ValueError(\"All input lists must be of the same length.\")\n result = []\n for i in range(len(l1)):\n result.append(l1[i])\n result.append(l2[i])\n result.append(l3[i])\n return result", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n interleaved_list = []\n\n for a, b, c in zip(list1, list2, list3):\n interleaved_list.extend([a, b, c])\n\n return interleaved_list\nlist1 = [1,2,3,4,5,6,7]\nlist2 = [10,20,30,40,50,60,70]\nlist3 = [100,200,300,400,500,600,700]", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(l1, l2, l3):\n interleaved_list = []\n for i in range(len(l1)):\n interleaved_list.append(l1[i])\n interleaved_list.append(l2[i])\n interleaved_list.append(l3[i])\n return interleaved_list", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n # Input lists must be of equal length\n assert len(list1) == len(list2) == len(list3)\n\n # Combine the three lists into one list of tuples\n combined = zip(list1, list2, list3)\n\n # Flatten the list of tuples using list comprehension\n flattened = [num for sublist in combined for num in sublist]\n\n return flattened\nlist1 = [1,2,3,4,5,6,7]\nlist2 = [10,20,30,40,50,60,70]\nlist3 = [100,200,300,400,500,600,700]", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"\n Function to interleave 3 lists of the same length into a single flat list\n \"\"\"\n # Make sure all the lists are of the same length\n assert len(list1) == len(list2) == len(list3), \"All lists should be of the same length\"\n\n # Interleave the lists\n interleaved_list = []\n for i in range(len(list1)):\n interleaved_list.append(list1[i])\n interleaved_list.append(list2[i])\n interleaved_list.append(list3[i])\n \n return interleaved_list", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n result = []\n for i in range(len(list1)):\n result.append(list1[i])\n result.append(list2[i])\n result.append(list3[i])\n return result", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n interleaved_list = []\n for i in range(len(list1)):\n interleaved_list.append(list1[i])\n interleaved_list.append(list2[i])\n interleaved_list.append(list3[i])\n return interleaved_list", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n # Check that all lists are of the same length\n assert len(list1) == len(list2) == len(list3), \"Input lists are of different lengths\"\n\n result = []\n for i in range(len(list1)):\n result.extend([list1[i], list2[i], list3[i]])\n\n return result\nlist1 = [1,2,3,4,5,6,7]\nlist2 = [10,20,30,40,50,60,70]\nlist3 = [100,200,300,400,500,600,700]", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n result = []\n for i in range(len(list1)):\n result.extend([list1[i], list2[i], list3[i]])\n return result", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n result = []\n for i in range(len(list1)):\n result.append(list1[i])\n result.append(list2[i])\n result.append(list3[i])\n return result\nlist1 = [1,2,3,4,5,6,7]\nlist2 = [10,20,30,40,50,60,70]\nlist3 = [100,200,300,400,500,600,700]\nresult = interleave_lists(list1, list2, list3)", "matching_cluster_idx": 6}]}, "Mbpp/586": {"dps": 98.83040935672514, "dps_norm": 87.5, "pass@1": 81.0, "profiled": [{"solution": "def split_Arr(arr, n):\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(lst, n):\n return lst[n:] + lst[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"\n This function splits the array at the nth element and moves the first part to the end.\n\n :param arr: The list to split and rearrange\n :param n: The index at which to split the list\n :return: The rearranged list\n \"\"\"\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n if n < len(arr):\n return arr[n:] + arr[:n]\n else:\n return arr", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n # check the length of the array\n if n > len(arr):\n print(\"The provided index is bigger than the length of the list\")\n return None\n # split the list at the nth position and add the first part to the end\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(input_list, n):\n if n > len(input_list):\n return \"Error: n is larger than the length of the list\"\n return input_list[n:] + input_list[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n # split the list at the nth element\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(lst, n):\n return lst[n:] + lst[:n]", "matching_cluster_idx": 6}]}, "Mbpp/587": {"dps": 51.689189189189186, "dps_norm": 86.25, "pass@1": 100.0, "profiled": [{"solution": "def list_tuple(lst):\n return tuple(lst)", "matching_cluster_idx": 2}, {"solution": "def list_tuple(lst):\n return tuple(lst)", "matching_cluster_idx": 2}, {"solution": "def list_tuple(lst):\n return tuple(lst)", "matching_cluster_idx": 2}, {"solution": "def list_tuple(lst):\n \"\"\"\n Converts a list to a tuple.\n \"\"\"\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n \"\"\"\n Function that converts a list to a tuple\n \"\"\"\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(input_list):\n \"\"\"\n This function converts a given list to a tuple.\n\n Parameters:\n input_list (list): The list to be converted.\n\n Returns:\n tuple: The resulting tuple.\n \"\"\"\n\n return tuple(input_list)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n return tuple(lst)", "matching_cluster_idx": 2}, {"solution": "def list_tuple(lst):\n \"\"\"\n Convert a list to a tuple.\n\n Parameters:\n lst (list): The list to be converted to a tuple.\n\n Returns:\n tuple: A tuple resulting from the conversion of the list.\n \"\"\"\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(input_list):\n return tuple(input_list)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n \"\"\"\n This function converts a list to a tuple.\n \n :param lst: list\n :returns: tuple\n \"\"\"\n return tuple(lst)", "matching_cluster_idx": 2}, {"solution": "def list_tuple(lst):\n return tuple(lst)", "matching_cluster_idx": 2}, {"solution": "def list_tuple(input_list):\n \"\"\"\n Convert a list to a tuple\n \"\"\"\n return tuple(input_list)", "matching_cluster_idx": 2}, {"solution": "def list_tuple(lst):\n \"\"\"Convert a list to a tuple\"\"\"\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n \"\"\"Converts a list to a tuple.\n\n >>> assert list_tuple([5, 10, 7, 4, 15, 3]) == (5, 10, 7, 4, 15, 3)\n \"\"\"\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n \"\"\"\n Convert a list to a tuple.\n\n >>> list_tuple([5, 10, 7, 4, 15, 3])\n (5, 10, 7, 4, 15, 3)\n \"\"\"\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n return tuple(lst)", "matching_cluster_idx": 2}, {"solution": "def list_tuple(lst):\n return tuple(lst)", "matching_cluster_idx": 2}, {"solution": "def list_tuple(list):\n # Convert the list to a tuple\n return tuple(list)", "matching_cluster_idx": 2}, {"solution": "def list_tuple(lst):\n return tuple(lst)", "matching_cluster_idx": 2}, {"solution": "def list_tuple(lst):\n \"\"\"\n Convert a list to a tuple.\n :param lst: list to be converted\n :return: tuple of the list elements\n \"\"\"\n return tuple(lst)", "matching_cluster_idx": 3}]}, "Mbpp/588": {"dps": 89.35779816513761, "dps_norm": 95.0, "pass@1": 100.0, "profiled": [{"solution": "def big_diff(lst):\n \"\"\"\n Find the difference between largest and smallest value in a given list.\n \"\"\"\n return max(lst) - min(lst)", "matching_cluster_idx": 5}, {"solution": "def big_diff(input_list):\n \"\"\"\n Function to find the difference between largest and smallest value in a given list.\n \"\"\"\n try:\n # validate that all elements in the list are numbers\n for item in input_list:\n if not isinstance(item, (int, float)):\n raise TypeError\n\n # find the min and max values in the list and return their difference\n return max(input_list) - min(input_list)\n\n except TypeError:\n print(\"Error: All elements in the input list should be numbers\")\n return None", "matching_cluster_idx": 1}, {"solution": "def big_diff(numbers):\n if len(numbers) <= 0:\n return None\n else:\n return max(numbers) - min(numbers)", "matching_cluster_idx": 5}, {"solution": "def big_diff(lst):\n # Return the difference between max and min element in the list\n return max(lst) - min(lst)", "matching_cluster_idx": 5}, {"solution": "def big_diff(input_list):\n return max(input_list) - min(input_list)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n \"\"\"\n Function to find the difference between the largest and smallest value in a given list.\n \"\"\"\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(lst):\n return max(lst) - min(lst)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n if len(nums) == 0:\n return None\n max_value = nums[0]\n min_value = nums[0]\n for num in nums:\n if num > max_value:\n max_value = num\n if num < min_value:\n min_value = num\n return max_value - min_value", "matching_cluster_idx": 4}, {"solution": "def big_diff(nums):\n \"\"\"Function to find the difference between largest and smallest value in a given list.\"\"\"\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(lst):\n \"\"\"\n Find the difference between the largest and smallest value in a given list.\n \"\"\"\n if len(lst) == 0:\n return 0\n else:\n return max(lst) - min(lst)", "matching_cluster_idx": 5}, {"solution": "def big_diff(num_list):\n \"\"\"\n This function finds the difference between the largest and smallest value in a given list.\n \"\"\"\n return max(num_list) - min(num_list)", "matching_cluster_idx": 5}, {"solution": "def big_diff(lst):\n if not lst: # check if list is empty\n return 0\n return max(lst) - min(lst)", "matching_cluster_idx": 5}, {"solution": "def big_diff(lst):\n \"\"\"\n This function returns the difference between the largest and smallest values in a list.\n \"\"\"\n # Find the smallest and largest numbers in the list\n min_val = min(lst)\n max_val = max(lst)\n # Return the difference\n return max_val - min_val", "matching_cluster_idx": 5}, {"solution": "def big_diff(input_list):\n \"\"\"\n This function calculates the difference between the largest and smallest\n number in a given list. If the list is empty, it returns 0.\n \"\"\"\n if len(input_list) == 0:\n return 0\n return max(input_list) - min(input_list)", "matching_cluster_idx": 5}, {"solution": "def big_diff(lst):\n if not lst: # If the list is empty, returns 0\n return 0\n \n min_val = lst[0] # Initialize min_val with the first value of the list\n max_val = lst[0] # Initialize max_val with the first value of the list\n \n for num in lst:\n if num < min_val:\n min_val = num # Update min_val if a smaller number is found\n elif num > max_val:\n max_val = num # Update max_val if a larger number is found\n \n return max_val - min_val # Return the difference between max and min values", "matching_cluster_idx": 4}, {"solution": "def big_diff(num_list):\n return max(num_list) - min(num_list)", "matching_cluster_idx": 5}, {"solution": "def big_diff(lst):\n \"\"\"\n Function to find the difference between the largest and smallest values in a list.\n \"\"\"\n if len(lst) == 0:\n return 0\n return max(lst) - min(lst)", "matching_cluster_idx": 5}, {"solution": "def big_diff(input_list):\n if not input_list:\n return None\n else:\n return max(input_list) - min(input_list)", "matching_cluster_idx": 5}, {"solution": "def big_diff(lst):\n \"\"\"\n Find the difference between the largest and smallest value in a list\n :param lst: list of numbers\n :return: difference between the largest and smallest value\n \"\"\"\n if len(lst) == 0:\n raise ValueError(\"The list cannot be empty\")\n\n return max(lst) - min(lst)", "matching_cluster_idx": 5}]}, "Mbpp/592": {"dps": 80.2962962962963, "dps_norm": 57.77777777777778, "pass@1": 18.0, "profiled": [{"solution": "import math\ndef sum_Of_product(n):\n result = 0\n for i in range(n):\n result += math.comb(n, i) * math.comb(n, i+1)\n return result", "matching_cluster_idx": 5}, {"solution": "from math import comb\ndef sum_Of_product(n):\n return sum(comb(n, i) * comb(n, i+1) for i in range(n))", "matching_cluster_idx": 5}, {"solution": "def binomial_coefficient(n, k):\n result = 1\n if k > n - k: \n k = n - k\n for i in range(k):\n result *= (n - i)\n result //= (i + 1)\n return result\ndef sum_Of_product(n):\n result = 0\n for k in range(n):\n result += binomial_coefficient(n, k) * binomial_coefficient(n, k + 1)\n return result", "matching_cluster_idx": 4}, {"solution": "import math\ndef sum_Of_product(n):\n sum = 0\n for i in range(n):\n sum += math.comb(n, i) * math.comb(n, i+1)\n return sum", "matching_cluster_idx": 5}, {"solution": "from math import comb\ndef sum_Of_product(n):\n total = 0\n for i in range(n):\n total += comb(n, i) * comb(n, i+1)\n return total", "matching_cluster_idx": 5}, {"solution": "from math import comb\ndef sum_Of_product(n):\n result = 0\n for i in range(n):\n result += comb(n, i) * comb(n, i+1)\n return result", "matching_cluster_idx": 5}, {"solution": "from math import comb\ndef sum_Of_product(n):\n return sum(comb(n,i)*comb(n,i+1) for i in range(n))", "matching_cluster_idx": 5}, {"solution": "import math\ndef sum_Of_product(n):\n sum_product = 0\n for i in range(n+1):\n product = math.comb(n, i) * math.comb(n, i+1)\n sum_product += product\n return sum_product", "matching_cluster_idx": 5}, {"solution": "from math import comb\ndef sum_Of_product(n):\n return sum(comb(n, i) * comb(n, i+1) for i in range(n))", "matching_cluster_idx": 5}, {"solution": "def binomial_coefficient(n, k):\n res = 1\n if (k > n - k):\n k = n - k\n for i in range(0 , k):\n res = res * (n - i)\n res = res // (i + 1)\n return res\ndef sum_Of_product(n):\n result = 0\n for i in range(n):\n result += binomial_coefficient(n, i) * binomial_coefficient(n, i + 1)\n return result", "matching_cluster_idx": 4}, {"solution": "import math\ndef sum_Of_product(n):\n sum = 0\n for i in range(n):\n sum += math.comb(n, i) * math.comb(n, i+1)\n return sum", "matching_cluster_idx": 5}, {"solution": "from math import comb\ndef sum_Of_product(n):\n \"\"\"\n This function returns the sum of the product of consecutive binomial co-efficients for the given number.\n \"\"\"\n sum_of_product = 0\n for i in range(n):\n sum_of_product += comb(n, i) * comb(n, i+1)\n return sum_of_product", "matching_cluster_idx": 5}, {"solution": "from math import comb\ndef sum_Of_product(n):\n result = 0\n for i in range(n):\n result += comb(n, i) * comb(n, i+1)\n return result", "matching_cluster_idx": 5}, {"solution": "import math\ndef sum_Of_product(n):\n result = 0\n for i in range(n):\n result += math.comb(n, i) * math.comb(n, i + 1)\n return result", "matching_cluster_idx": 5}, {"solution": "def sum_Of_product(n):\n result = 0\n for i in range(n):\n result += binomial(n, i) * binomial(n, i+1)\n return result\ndef binomial(n, k):\n if k > n:\n return 0\n if k > n // 2:\n k = n - k\n b = 1\n for x, y in enumerate(range(n, n-k, -1)):\n b = (b * y) // (x + 1)\n return b", "matching_cluster_idx": 4}, {"solution": "import math\ndef sum_Of_product(n):\n sum = 0\n for i in range(n):\n sum += math.comb(n, i) * math.comb(n, i+1)\n return sum", "matching_cluster_idx": 5}, {"solution": "from math import comb\ndef sum_Of_product(n):\n \"\"\"Calculate the sum of the product of consecutive binomial co-efficients\"\"\"\n return sum(comb(n, i)*comb(n, i-1) for i in range(1, n+1))", "matching_cluster_idx": 5}, {"solution": "def sum_Of_product(n):\n result = 0\n for i in range(n):\n result += binomial(n, i) * binomial(n, i+1)\n return result\ndef binomial(n, k):\n if k > n:\n return 0\n if k > n // 2:\n k = n - k\n b = 1\n for x, y in enumerate(range(n, n - k, -1)):\n b = (b * y) // (x + 1)\n return b", "matching_cluster_idx": 4}]}, "Mbpp/597": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 44.0, "profiled": [{"solution": "def find_kth(array1, array2, k):\n array = sorted(array1 + array2)\n if k <= len(array):\n return array[k-1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(array1, array2, k):\n # merge two sorted arrays into one sorted array\n array = sorted(array1 + array2)\n\n # check if k is within the array bounds\n if k > len(array):\n return \"Index out of bounds\"\n\n return array[k - 1] # return kth element from merged and sorted array", "matching_cluster_idx": 3}, {"solution": "def find_kth(arr1, arr2, k):\n merged_arr = sorted(arr1 + arr2)\n \n return merged_arr[k-1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(arr1, arr2, k):\n arr = sorted(arr1 + arr2)\n return arr[k - 1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(arr1, arr2, k):\n # Concatenate the two arrays\n arr = arr1 + arr2\n\n # Sort the concatenated array\n arr.sort()\n\n # Subtract 1 from k because array index starts at 0\n return arr[k - 1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(arr1, arr2, k):\n merged = sorted(arr1 + arr2)\n if k <= len(merged):\n return merged[k-1]\n else:\n return \"k is out of range\"", "matching_cluster_idx": 3}, {"solution": "def find_kth(arr1, arr2, k):\n merged = sorted(arr1 + arr2)\n return merged[k-1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(arr1, arr2, k):\n # The two arrays are assumed to be sorted, so we can simply concatenate and\n # sort them. However, a more efficient solution would use a merge-like approach\n # to find the k-th element in a single pass.\n result = sorted(arr1 + arr2)\n # If the k-th element exists, return it, otherwise return None.\n return result[k-1] if k <= len(result) else None", "matching_cluster_idx": 3}, {"solution": "def find_kth(arr1, arr2, k):\n # Merge the arrays\n merged_arr = arr1 + arr2\n # Sort the merged array\n merged_arr.sort()\n # Return the kth element\n return merged_arr[k-1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(array1, array2, k):\n merged_array = sorted(array1 + array2)\n return merged_array[k - 1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(array1, array2, k):\n merged_array = array1 + array2\n merged_array.sort()\n return merged_array[k - 1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(arr1, arr2, k):\n # Concatenate two arrays and sort them\n sorted_array = sorted(arr1 + arr2)\n \n # Check if kth element exist\n if k <= len(sorted_array):\n return sorted_array[k - 1]\n else:\n return None", "matching_cluster_idx": 3}, {"solution": "def find_kth(arr1, arr2, k):\n \"\"\" Find kth element from the given two sorted arrays. \"\"\"\n merged = sorted(arr1 + arr2)\n return merged[k-1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(arr1, arr2, k):\n # concatenate the two sorted arrays\n arr = sorted(arr1 + arr2)\n # return the kth element, considering the 1-based indexing\n return arr[k-1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(arr1, arr2, k):\n \"\"\"Function to find kth element from the given two sorted arrays.\"\"\"\n merged = sorted(arr1 + arr2)\n return merged[k-1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(arr1, arr2, k):\n merged = sorted(arr1 + arr2)\n return merged[k-1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(arr1, arr2, k):\n merged = sorted(arr1 + arr2)\n if k > len(merged):\n return \"Index out of bounds!\"\n else:\n return merged[k - 1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(arr1, arr2, k):\n # Merge two arrays into one\n sorted_arr = sorted(arr1 + arr2)\n\n # Return kth element\n return sorted_arr[k - 1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(array1, array2, k):\n \"\"\"\n Function to find kth element from the given two sorted arrays.\n \"\"\"\n merged = sorted(array1 + array2)\n if k <= len(merged):\n return merged[k-1]\n else:\n return None", "matching_cluster_idx": 3}, {"solution": "def find_kth(arr1, arr2, k):\n merged = sorted(arr1 + arr2)\n return merged[k - 1]", "matching_cluster_idx": 3}]}, "Mbpp/604": {"dps": 90.45454545454545, "dps_norm": 98.0, "pass@1": 53.0, "profiled": [{"solution": "def reverse_words(s):\n return ' '.join(s.split()[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n words = s.split()\n words.reverse()\n return ' '.join(words)", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n words = s.split()\n reversed_words = ' '.join(reversed(words))\n return reversed_words", "matching_cluster_idx": 4}, {"solution": "def reverse_words(input_str):\n words = input_str.split()\n reversed_str = \" \".join(reversed(words))\n return reversed_str", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n return \" \".join(s.split()[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n return \" \".join(s.split()[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(sentence):\n # Split the string into a list of words\n words = sentence.split()\n\n # Reverse the list of words\n words_reversed = words[::-1]\n\n # Join the reversed words back into a string with spaces\n sentence_reversed = \" \".join(words_reversed)\n\n return sentence_reversed", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n return ' '.join(s.split()[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n words = s.split()\n reversed_words = ' '.join(reversed(words))\n return reversed_words", "matching_cluster_idx": 4}, {"solution": "def reverse_words(input_string):\n words = input_string.split()\n reversed_words = ' '.join(reversed(words))\n return reversed_words", "matching_cluster_idx": 3}, {"solution": "def reverse_words(s):\n return ' '.join(s.split()[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s: str) -> str:\n return \" \".join(s.split()[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n return ' '.join(s.split()[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n \"\"\"\n Function to reverse words separated by spaces in a given string.\n \"\"\"\n return \" \".join(s.split()[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(string):\n words = string.split()\n reversed_string = ' '.join(reversed(words))\n return reversed_string", "matching_cluster_idx": 3}, {"solution": "def reverse_words(s):\n # split the string into a list of words\n words = s.split()\n # reverse the list of words\n words = words[::-1]\n # join the words back into a string with spaces\n reversed_s = \" \".join(words)\n return reversed_s", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n return ' '.join(s.split()[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n \"\"\"\n Write a function to reverse words seperated by spaces in a given string.\n \"\"\"\n return ' '.join(s.split()[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(input_string):\n words = input_string.split()\n words = words[::-1]\n reversed_string = ' '.join(words)\n return reversed_string", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n words = s.split() # Split string into list of words\n words = words[::-1] # Reverse the list of words\n return ' '.join(words) # Join words back into a single string with spaces in between", "matching_cluster_idx": 4}]}, "Mbpp/610": {"dps": 77.17391304347827, "dps_norm": 78.57142857142857, "pass@1": 38.0, "profiled": [{"solution": "def remove_kth_element(lst, k):\n if k > len(lst) or k < 1:\n raise ValueError(\"k should be between 1 and the size of the list\")\n return lst[:k-1] + lst[k:]", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(input_list, k):\n if k < 1 or k > len(input_list):\n raise ValueError(\"k is out of bounds\")\n input_list.pop(k-1)\n return input_list", "matching_cluster_idx": 6}, {"solution": "def remove_kth_element(input_list, k):\n # Check if the k is valid index for the list\n if k > len(input_list) or k < 1:\n return input_list\n \n # Create a new list where the k'th element is removed\n result_list = input_list[:k-1] + input_list[k:]\n return result_list", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(lst, k):\n \"\"\"Remove k'th element from the list and return new list.\"\"\"\n if k < 1 or k > len(lst):\n raise ValueError(\"k is out of range\")\n return lst[:k-1] + lst[k:]", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(input_list, k):\n if k < 1 or k > len(input_list):\n return input_list\n\n return input_list[:k-1] + input_list[k:]", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(input_list, k):\n if k < 1 or k > len(input_list):\n raise IndexError('k should be between 1 and length of input list.')\n return input_list[:k-1] + input_list[k:]", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(input_list, k):\n if k < 1 or k > len(input_list):\n raise ValueError('Index k is out of range of the input list')\n \n input_list.pop(k - 1)\n return input_list", "matching_cluster_idx": 5}, {"solution": "def remove_kth_element(input_list, k):\n if k <= len(input_list):\n input_list.pop(k-1)\n return input_list", "matching_cluster_idx": 6}, {"solution": "def remove_kth_element(lst, k):\n \"\"\"\n This function removes k'th element from the list and returns the list.\n \"\"\"\n # list comprehension approach to avoid mutating list during iteration\n return [lst[i] for i in range(len(lst)) if i != k-1]", "matching_cluster_idx": 1}, {"solution": "def remove_kth_element(input_list, k):\n if k > len(input_list) or k < 1: # k should be a valid index\n return \"Invalid index\"\n else:\n return input_list[:k-1] + input_list[k:]", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(lst, k):\n if k > len(lst):\n return lst\n else:\n lst.pop(k-1) # pop is 0-indexed\n return lst", "matching_cluster_idx": 6}, {"solution": "def remove_kth_element(lst, k):\n \"\"\"\n Remove the k'th element from the given list.\n\n Parameters:\n lst (list): The list from which to remove an element\n k (int): The index of the element to remove (1-based index)\n\n Returns:\n list: A new list with the k'th element removed\n \"\"\"\n # Check if the index is in range (1-based)\n if k < 1 or k > len(lst):\n raise IndexError(\"The provided index is out of range\")\n\n return lst[:k-1] + lst[k:]", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(input_list, k):\n if k < 1 or k > len(input_list):\n return input_list\n del input_list[k-1]\n return input_list", "matching_cluster_idx": 6}, {"solution": "def remove_kth_element(input_list, k):\n del input_list[k-1]\n return input_list", "matching_cluster_idx": 6}, {"solution": "def remove_kth_element(input_list, k):\n if k < 1 or k > len(input_list):\n return input_list\n del input_list[k-1]\n return input_list", "matching_cluster_idx": 6}, {"solution": "def remove_kth_element(my_list, k):\n if k <= len(my_list) and k > 0:\n del my_list[k - 1]\n return my_list", "matching_cluster_idx": 6}, {"solution": "def remove_kth_element(input_list, k):\n if k < 1 or k > len(input_list):\n raise IndexError(\"Index out of range\")\n \n del input_list[k-1]\n return input_list\ninput_list = [1,1,2,3,4,4,5,1]\nk = 3", "matching_cluster_idx": 6}, {"solution": "def remove_kth_element(input_list, k):\n # Checking if the provided list is not empty and if k is a valid index of the list\n if input_list and 0 < k <= len(input_list):\n # Removing the k'th element\n del input_list[k-1]\n return input_list\n else:\n return \"Invalid input\"", "matching_cluster_idx": 6}, {"solution": "def remove_kth_element(input_list, k):\n if k > len(input_list) or k < 1:\n raise ValueError(\"k should be between 1 and length of the list.\")\n del input_list[k-1]\n return input_list", "matching_cluster_idx": 6}, {"solution": "def remove_kth_element(input_list, k):\n if k > len(input_list) or k <= 0:\n raise ValueError(\"The value of k is out of range. It should be in range of 1 to len(list)\")\n\n return input_list[:k-1] + input_list[k:]", "matching_cluster_idx": 3}]}, "Mbpp/611": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 32.0, "profiled": [{"solution": "def max_of_nth(matrix, n):\n \"\"\"\n Function to find the max of the n'th column in a matrix\n :param matrix: A matrix represented as a list of lists\n :param n: The column number\n :return: The max of the n'th column\n \"\"\"\n return max(row[n] for row in matrix)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n \"\"\"Return max of the n'th column\"\"\"\n return max(row[n] for row in matrix)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n return max(row[n] for row in matrix)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n \"\"\"\n This function returns the max of the n'th column in the matrix.\n \"\"\"\n return max(column[n] for column in matrix)\nmatrix = [[5, 6, 7], [1, 3, 5], [8, 9, 19]]\nn = 2", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n \"\"\"Returns the max of the n'th column of a matrix represented as a list of lists.\"\"\"\n column = [row[n] for row in matrix]\n return max(column)\nmatrix = [[5, 6, 7], [1, 3, 5], [8, 9, 19]]\nn = 2", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n \"\"\"\n A function that given a matrix represented as a list of lists returns \n the max of the n'th column.\n \"\"\"\n column = [row[n] for row in matrix]\n return max(column)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n \"\"\"\n Function which given a matrix represented as a list of lists returns the max of the n'th column.\n \"\"\"\n return max(column[n] for column in matrix)\nmatrix = [[5, 6, 7], [1, 3, 5], [8, 9, 19]]\nn = 2", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n \"\"\"\n Returns the max of the n'th column from the given matrix.\n \"\"\"\n return max(row[n] for row in matrix)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n \"\"\"\n Given a matrix represented as a list of lists and returns the max of the n'th column.\n \"\"\"\n # Check if the matrix is not empty and the requested column exists.\n if len(matrix) == 0 or len(matrix[0]) <= n:\n raise ValueError(\"Matrix does not have that many columns.\")\n \n # Get the n'th column values and return its maximum.\n return max(row[n] for row in matrix)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n \"\"\"\n This function takes a matrix represented as a list of lists and an integer n and returns the max value\n of the n'th column.\n \"\"\"\n return max(row[n] for row in matrix)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n \"\"\"\n Returns the max of the n'th column in the given matrix.\n\n Parameters:\n matrix (list): A 2D list representing the matrix.\n n (int): The column number for which the max is to be found. The count starts from 0.\n\n Returns:\n int: The maximum value in the n'th column of the matrix.\n\n Examples:\n >>> max_of_nth([[5, 6, 7], [1, 3, 5], [8, 9, 19]], 2)\n 19\n \"\"\"\n nth_col = [row[n] for row in matrix]\n return max(nth_col)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n # get nth column\n nth_column = [row[n] for row in matrix]\n\n # return max of nth column\n return max(nth_column)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n column = [row[n] for row in matrix]\n return max(column)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n return max(row[n] for row in matrix)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n \"\"\"\n Function to get the max of the n'th column of a given matrix.\n\n :param matrix: list of lists representing the matrix.\n :param n: column index (0-based).\n :return: max of the n'th column.\n \"\"\"\n column = [row[n] for row in matrix]\n return max(column)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n return max(row[n] for row in matrix)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n column = [row[n] for row in matrix]\n return max(column)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n return max(row[n] for row in matrix)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n return max(row[n] for row in matrix)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n \"\"\"Return max of nth column in the matrix.\"\"\"\n return max(row[n] for row in matrix)\nmatrix = [[5, 6, 7], [1, 3, 5], [8, 9, 19]]", "matching_cluster_idx": 5}]}, "Mbpp/631": {"dps": 76.87499999999999, "dps_norm": 75.625, "pass@1": 70.0, "profiled": [{"solution": "def replace_spaces(s):\n new_s = \"\"\n for i in s:\n if i == \" \":\n new_s += \"_\"\n elif i == \"_\":\n new_s += \" \"\n else:\n new_s += i\n return new_s", "matching_cluster_idx": 2}, {"solution": "def replace_spaces(input_string):\n \"\"\"\n Function to replace whitespaces with an underscore and vice versa in a given string.\n \"\"\"\n return input_string.replace(' ', '_') if ' ' in input_string else input_string.replace('_', ' ')", "matching_cluster_idx": 7}, {"solution": "def replace_spaces(s):\n \"\"\"\n Replace whitespaces with an underscore and vice versa in a given string.\n \"\"\"\n return s.replace(' ', '_') if ' ' in s else s.replace('_', ' ')", "matching_cluster_idx": 7}, {"solution": "def replace_spaces(s):\n \"\"\"\n Replace whitespaces with underscore and vice versa in a given string.\n \"\"\"\n return s.replace(' ', '_') if ' ' in s else s.replace('_', ' ')", "matching_cluster_idx": 7}, {"solution": "def replace_spaces(input_string):\n result_string = \"\"\n for char in input_string:\n if char == \" \":\n result_string += \"_\"\n elif char == \"_\":\n result_string += \" \"\n else:\n result_string += char\n return result_string", "matching_cluster_idx": 2}, {"solution": "def replace_spaces(s):\n \"\"\"\n Replaces whitespaces with underscore and vice versa in a given string.\n \"\"\"\n return s.replace(' ', '_') if ' ' in s else s.replace('_', ' ')", "matching_cluster_idx": 7}, {"solution": "def replace_spaces(input_str):\n \"\"\"Replaces whitespaces with an underscore and vice versa in a given string.\"\"\"\n return input_str.translate(str.maketrans(\" _\", \"_ \"))", "matching_cluster_idx": 6}, {"solution": "def replace_spaces(s):\n return s.replace(' ', '_') if ' ' in s else s.replace('_', ' ')", "matching_cluster_idx": 7}, {"solution": "def replace_spaces(input_string):\n return input_string.replace(' ', '_') if ' ' in input_string else input_string.replace('_', ' ')", "matching_cluster_idx": 7}, {"solution": "def replace_spaces(s: str) -> str:\n result = []\n for char in s:\n if char == ' ':\n result.append('_')\n elif char == '_':\n result.append(' ')\n else:\n result.append(char)\n return ''.join(result)", "matching_cluster_idx": 3}, {"solution": "def replace_spaces(s):\n return s.replace(\" \", \"_\") if \" \" in s else s.replace(\"_\", \" \")", "matching_cluster_idx": 7}, {"solution": "def replace_spaces(s):\n result = ''\n for char in s:\n if char == ' ':\n result += '_'\n elif char == '_':\n result += ' '\n else:\n result += char\n return result", "matching_cluster_idx": 2}, {"solution": "def replace_spaces(s):\n \"\"\"\n Replaces whitespaces with an underscore and vice versa in a given string.\n \"\"\"\n return s.replace(\" \", \"_\") if \" \" in s else s.replace(\"_\", \" \")", "matching_cluster_idx": 7}, {"solution": "def replace_spaces(s: str) -> str:\n # Creating an empty string to hold our result\n res = ''\n # Iterating over the characters in the string\n for char in s:\n # If the character is a whitespace, replace with an underscore\n if char == ' ':\n res += '_'\n # If the character is an underscore, replace with a whitespace\n elif char == '_':\n res += ' '\n # If the character is not a whitespace or underscore, just add it to the result\n else:\n res += char\n return res", "matching_cluster_idx": 2}, {"solution": "def replace_spaces(s):\n \"\"\"Replaces spaces with underscores or underscores with spaces in a string.\"\"\"\n result = []\n for ch in s:\n if ch == ' ':\n result.append('_')\n elif ch == '_':\n result.append(' ')\n else:\n result.append(ch)\n return ''.join(result)\ns = 'Jumanji The Jungle'", "matching_cluster_idx": 3}, {"solution": "def replace_spaces(s):\n return s.replace(' ', '_') if ' ' in s else s.replace('_', ' ')", "matching_cluster_idx": 7}, {"solution": "def replace_spaces(input_string):\n \"\"\"\n Function to replace whitespaces with underscores and vice versa in a string.\n \"\"\"\n # Replace spaces with underscores and vice versa\n output_string = ''\n for char in input_string:\n if char == ' ':\n output_string += '_'\n elif char == '_':\n output_string += ' '\n else:\n output_string += char\n \n return output_string", "matching_cluster_idx": 2}, {"solution": "def replace_spaces(string: str):\n return string.replace(' ', '_') if ' ' in string else string.replace('_', ' ')", "matching_cluster_idx": 7}, {"solution": "def replace_spaces(input_str):\n new_str = \"\"\n for char in input_str:\n if char == \" \":\n new_str += \"_\"\n elif char == \"_\":\n new_str += \" \"\n else:\n new_str += char\n return new_str", "matching_cluster_idx": 2}, {"solution": "def replace_spaces(s):\n \"\"\"\n Replace whitespaces with an underscore and vice versa in a given string.\n \n Parameters:\n s (str): Input string.\n \n Returns:\n str: Modified string.\n \"\"\"\n if ' ' in s:\n return s.replace(' ', '_')\n else:\n return s.replace('_', ' ')", "matching_cluster_idx": 7}]}, "Mbpp/632": {"dps": 75.60975609756098, "dps_norm": 85.71428571428571, "pass@1": 84.0, "profiled": [{"solution": "def move_zero(num_list):\n return sorted(num_list, key = lambda x: x==0)", "matching_cluster_idx": 6}, {"solution": "def move_zero(num_list):\n zeros = num_list.count(0)\n num_list = [num for num in num_list if num != 0]\n num_list += [0] * zeros\n return num_list", "matching_cluster_idx": 6}, {"solution": "def move_zero(arr):\n for i in arr:\n if i == 0:\n arr.remove(i)\n arr.append(i)\n return arr", "matching_cluster_idx": 2}, {"solution": "def move_zero(arr):\n n = arr.count(0)\n arr = [i for i in arr if i != 0]\n arr.extend([0]*n)\n return arr", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n \"\"\"\n Move all zeroes to the end of the given list.\n \"\"\"\n for i in nums:\n if i == 0:\n nums.remove(i)\n nums.append(i)\n return nums", "matching_cluster_idx": 2}, {"solution": "def move_zero(lst):\n \"\"\"Function to move all zeroes to the end of the given list.\"\"\"\n new_lst = [num for num in lst if num != 0]\n zero_count = lst.count(0)\n new_lst.extend([0]*zero_count)\n return new_lst", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n \"\"\"\n Move all zeroes in the list to the end.\n \"\"\"\n non_zeroes = [num for num in nums if num != 0]\n zeroes = [num for num in nums if num == 0]\n return non_zeroes + zeroes", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n \"\"\"\n Function to move all zeroes to the end of the given list\n :param nums: input list\n :return: list after moving zeroes to end\n \"\"\"\n for i in nums:\n if i == 0:\n nums.remove(i)\n nums.append(i)\n return nums", "matching_cluster_idx": 2}, {"solution": "def move_zero(nums):\n count = nums.count(0) # count the zeroes\n nums = [num for num in nums if num != 0] # create a new list without zeroes\n nums += [0]*count # append the zeroes to the end of the list\n return nums", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n for i in nums:\n if i == 0:\n nums.remove(0)\n nums.append(0)\n return nums", "matching_cluster_idx": 2}, {"solution": "def move_zero(nums):\n zero_count = nums.count(0)\n nums = list(filter(lambda a: a != 0, nums))\n nums.extend([0]*zero_count)\n return nums", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n for i in nums:\n if i == 0:\n nums.remove(i)\n nums.append(i)\n return nums", "matching_cluster_idx": 2}, {"solution": "def move_zero(nums):\n count = nums.count(0)\n nums = [num for num in nums if num != 0]\n nums.extend([0]*count)\n return nums", "matching_cluster_idx": 6}, {"solution": "def move_zero(input_list):\n non_zero = [i for i in input_list if i != 0]\n zero_count = input_list.count(0)\n return non_zero + [0]*zero_count", "matching_cluster_idx": 6}, {"solution": "def move_zero(arr):\n # create two empty lists to hold non-zero and zero elements respectively\n non_zero = []\n zero = []\n # loop through the input list\n for num in arr:\n # if the number is not zero, append it to the non_zero list, else append it to zero list\n if num != 0:\n non_zero.append(num)\n else:\n zero.append(num)\n # concatenate the non_zero and zero lists and return the result\n return non_zero + zero", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n count_zero = 0\n for i in range(len(nums)):\n if nums[i] != 0:\n nums[i], nums[count_zero] = nums[count_zero], nums[i]\n count_zero += 1\n return nums", "matching_cluster_idx": 6}, {"solution": "def move_zero(lst):\n non_zero_lst = [x for x in lst if x != 0]\n zero_lst = [x for x in lst if x == 0]\n return non_zero_lst + zero_lst", "matching_cluster_idx": 6}, {"solution": "def move_zero(arr):\n n = len(arr)\n count = 0\n\n for i in range(n):\n if arr[i] != 0:\n\n # here count is incremented\n arr[count] = arr[i]\n count+=1\n\n while count < n:\n arr[count] = 0\n count += 1\n \n return arr\narr = [1,0,2,0,3,4]", "matching_cluster_idx": 6}, {"solution": "def move_zero(lst):\n zero_count = lst.count(0)\n lst = [i for i in lst if i != 0]\n lst.extend([0]*zero_count)\n return lst", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n return [num for num in nums if num] + [0]*nums.count(0)", "matching_cluster_idx": 6}]}, "Mbpp/633": {"dps": 94.3089430894309, "dps_norm": 50.0, "pass@1": 29.0, "profiled": [{"solution": "def pair_xor_Sum(lst, n):\n res = 0\n for i in range(0, n):\n for j in range(i + 1, n):\n res += lst[i] ^ lst[j]\n return res", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(num_list, n):\n \"\"\"\n Function to find the sum of xor of all pairs of numbers in the given list.\n \"\"\"\n xor_sum = 0\n for i in range(n):\n for j in range(i+1, n):\n xor_sum += num_list[i] ^ num_list[j]\n return xor_sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(arr, n):\n sum_val = 0\n for i in range(0, n):\n for j in range(i + 1, n):\n sum_val += arr[i] ^ arr[j]\n return sum_val", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(num_list, n):\n xor_sum = 0\n for i in range(0, n):\n for j in range(i + 1, n):\n xor_sum += num_list[i] ^ num_list[j]\n return xor_sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(lst, n):\n xor_sum = 0\n for i in range(0, n):\n for j in range(i + 1, n):\n xor_sum += lst[i] ^ lst[j]\n return xor_sum\nlst = [5, 9, 7, 6]\nn = len(lst)", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(nums, length):\n result = 0\n for i in range(0, length):\n for j in range(i + 1, length):\n result += nums[i] ^ nums[j]\n return result", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(arr,n):\n sum = 0\n for i in range(0,n):\n for j in range(i+1,n):\n sum += arr[i] ^ arr[j]\n return sum\narr = [5,9,7,6]\nn = 4", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(lst, length):\n xor_sum = 0\n for i in range(0,length):\n for j in range(i+1, length):\n xor_sum += (lst[i] ^ lst[j])\n\n return xor_sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(nums, n):\n xor_sum = 0\n for i in range(n):\n for j in range(i + 1, n):\n xor_sum += nums[i] ^ nums[j]\n return xor_sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(numbers, n):\n \"\"\"\n Function to find the sum of xor of all pairs of numbers in the given list.\n \"\"\"\n sum_xor = 0\n\n for i in range(0, n):\n for j in range(i+1, n):\n sum_xor += numbers[i] ^ numbers[j]\n\n return sum_xor", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(lst, n):\n xor_sum = 0\n for i in range(0, n):\n for j in range(i + 1, n):\n xor_sum += lst[i] ^ lst[j]\n return xor_sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(nums, n):\n result = 0\n for i in range(0, n):\n for j in range(i + 1, n):\n result += nums[i] ^ nums[j]\n\n return result\nnums = [5,9,7,6]\nn = 4", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(arr, n):\n total = 0\n for i in range(0, n):\n for j in range(i + 1, n):\n total += arr[i] ^ arr[j]\n return total", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(lst, n):\n sum = 0\n for i in range(0, n):\n for j in range(i + 1, n):\n sum += lst[i] ^ lst[j]\n return sum\nlst = [5,9,7,6]\nn = 4", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(lst, n):\n \"\"\"\n This function takes in a list of numbers and their count as input, \n returns the sum of xor of all pairs of numbers in the given list\n \"\"\"\n\n xor_sum = 0\n for i in range(0, n):\n for j in range(i + 1, n):\n xor_sum += lst[i] ^ lst[j]\n\n return xor_sum\nlst = [5, 9, 7, 6]\nn = len(lst)", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(numbers, n):\n sum_xor = 0\n for i in range(0, n):\n for j in range(i + 1, n):\n sum_xor += numbers[i] ^ numbers[j]\n return sum_xor", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(nums, n):\n sum_xor = 0\n for i in range(0, n):\n for j in range(i + 1, n):\n sum_xor += nums[i] ^ nums[j]\n return sum_xor\nnums = [5,9,7,6]\nn = len(nums)", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(arr, n):\n total = 0\n for i in range(0, n):\n for j in range(i + 1, n):\n total += arr[i] ^ arr[j]\n return total", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(lst, n):\n sum = 0\n for i in range(0, n):\n for j in range(i + 1, n):\n sum += lst[i] ^ lst[j]\n\n return sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(lst, n):\n xor_sum = 0\n for i in range(0, n):\n for j in range(i + 1, n):\n xor_sum += lst[i] ^ lst[j]\n return xor_sum", "matching_cluster_idx": 2}]}, "Mbpp/644": {"dps": 82.57978723404254, "dps_norm": 84.66666666666666, "pass@1": 99.0, "profiled": [{"solution": "def reverse_Array_Upto_K(arr, k):\n # Check if the position is valid\n if k > len(arr) or k < 0:\n raise ValueError(\"Invalid position\")\n \n # Reverse the array upto the given position\n return arr[:k][::-1] + arr[k:]", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(array, k):\n # Split array into 2 parts at position k\n first_part = array[:k]\n second_part = array[k:]\n \n # Reverse the first part\n first_part = first_part[::-1]\n \n # Join both parts\n reversed_array = first_part + second_part\n \n return reversed_array", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n Function to reverse an array upto a given position.\n \"\"\"\n # Check the validity of the inputs\n if not isinstance(arr, list) or not isinstance(k, int) or k < 0 or k > len(arr):\n raise ValueError(\"Invalid inputs. Please provide a valid list and an integer k.\")\n\n # Reverse the array upto k\n arr[:k] = arr[k-1::-1]\n\n return arr", "matching_cluster_idx": 14}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n A python function to reverse an array upto a given position.\n \"\"\"\n arr[:k] = arr[:k][::-1]\n return arr", "matching_cluster_idx": 13}, {"solution": "def reverse_Array_Upto_K(arr, k):\n # Reverse the list upto k elements\n arr[:k] = arr[:k][::-1]\n return arr", "matching_cluster_idx": 13}, {"solution": "def reverse_Array_Upto_K(arr, k):\n # Check if the position is within the valid range of the array\n if k > len(arr) or k < 0:\n return \"Invalid position, please enter a valid position\"\n\n # Reverse the elements upto the given position\n arr[:k] = arr[k-1::-1]\n \n return arr", "matching_cluster_idx": 14}, {"solution": "def reverse_Array_Upto_K(arr, k):\n return arr[:k][::-1] + arr[k:]", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n Function to reverse an array upto a given position.\n \"\"\"\n # slicing the array upto position k and reverse it, and concat it with the rest of the array\n arr[:k] = arr[:k][::-1]\n return arr", "matching_cluster_idx": 13}, {"solution": "def reverse_Array_Upto_K(arr, k):\n # Reverse first k elements of array\n arr[:k] = arr[k-1::-1]\n return arr", "matching_cluster_idx": 14}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n This function reverses an array upto a given position.\n \"\"\"\n # Make sure that the given position is valid\n assert k > 0 and k <= len(arr), 'Position should be within array length'\n\n # Reverse the array upto the given position\n arr[:k] = arr[:k][::-1]\n\n return arr", "matching_cluster_idx": 13}, {"solution": "def reverse_Array_Upto_K(arr, k):\n return arr[:k][::-1] + arr[k:]", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n arr[:k] = arr[k-1::-1]\n return arr", "matching_cluster_idx": 14}, {"solution": "def reverse_Array_Upto_K(array, k):\n return array[:k][::-1] + array[k:]", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n This function reverses the first k elements in the given array and returns the modified array.\n \"\"\"\n # Check if k is less than or equal to the size of the array\n if k <= len(arr):\n # Reverse first k elements in-place\n for i in range(k//2):\n arr[i], arr[k-i-1] = arr[k-i-1], arr[i]\n return arr\narr = [1, 2, 3, 4, 5, 6]\nk = 4", "matching_cluster_idx": 6}, {"solution": "def reverse_Array_Upto_K(arr, k):\n return arr[:k][::-1] + arr[k:]", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n arr[:k] = reversed(arr[:k])\n return arr", "matching_cluster_idx": 12}, {"solution": "def reverse_Array_Upto_K(arr, k):\n return arr[:k][::-1] + arr[k:]", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n return arr[:k][::-1] + arr[k:]", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n arr[:k] = arr[k-1::-1]\n return arr", "matching_cluster_idx": 14}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n Function to reverse an array upto a given position.\n \"\"\"\n # array slicing method\n arr[:k] = arr[k-1::-1]\n return arr", "matching_cluster_idx": 14}]}, "Mbpp/720": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 98.0, "profiled": [{"solution": "def add_dict_to_tuple(tup, dictionary):\n \"\"\"\n This function takes a tuple and a dictionary as input and returns a new tuple that concatenates the tuple and the dictionary.\n \"\"\"\n return tup + (dictionary,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(tup, dic):\n \"\"\"\n This function adds a dictionary to the end of a tuple.\n \"\"\"\n tup += (dic,)\n return tup", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(input_tuple, input_dict):\n return input_tuple + (input_dict,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(input_tuple, dict_to_add):\n return input_tuple + (dict_to_add,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(tup, dict):\n \"\"\"\n Adds a dictionary to a tuple.\n\n :param tup: original tuple\n :param dict: dictionary to add\n :return: resulting tuple\n \"\"\"\n return tup + (dict,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(tup, d):\n \"\"\"\n This function takes a tuple and a dictionary as arguments and returns a new tuple\n with the elements from the dictionary appended to the original tuple.\n \"\"\"\n return tup + (d,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(tpl, dict):\n \"\"\"\n Function to add a dictionary to a tuple\n \"\"\"\n return tpl + (dict, )", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(tup, dict):\n return tup + (dict,)\ntup = (4, 5, 6)\ndict = {\"MSAM\" : 1, \"is\" : 2, \"best\" : 3}", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(tup, dict):\n return tup + (dict,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(tup, dict):\n \"\"\"\n Adds dictionary to tuple and returns a new tuple.\n \"\"\"\n return tup + (dict, )", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(tup, dic):\n \"\"\"\n This function adds a dictionary to a tuple and returns the resulting tuple.\n \"\"\"\n # Add dictionary to the tuple\n tup += (dic, )\n return tup", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(original_tuple, dictionary):\n return original_tuple + (dictionary,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(t, d):\n return t + (d,)\nt = (4, 5, 6)\nd = {\"MSAM\" : 1, \"is\" : 2, \"best\" : 3}", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(tup, dic):\n \"\"\"\n Function to add a dictionary to the tuple. The output is a tuple.\n \"\"\"\n return tup + (dic,)\ntup = (4, 5, 6)\ndic = {\"MSAM\" : 1, \"is\" : 2, \"best\" : 3}", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(t, d):\n return t + (d,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(t, d):\n \"\"\"\n This function adds a dictionary to a tuple.\n \"\"\"\n return t + (d, )", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(original_tuple, dict_to_add):\n \"\"\"\n A function to add a dictionary to the tuple. The output should be a tuple.\n \"\"\"\n return original_tuple + (dict_to_add,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(input_tuple, input_dict):\n \"\"\"\n Add a dictionary to a tuple\n \"\"\"\n return input_tuple + (input_dict, )", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(initial_tuple, dict_to_add):\n \"\"\"\n Function to add a dictionary to a tuple.\n :param initial_tuple: The initial tuple.\n :param dict_to_add: The dictionary to add.\n :return: A new tuple that contains the dictionary.\n \"\"\"\n return initial_tuple + (dict_to_add,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(input_tuple, input_dict):\n \"\"\"\n Function to add a dictionary to the tuple\n \"\"\"\n return input_tuple + (input_dict,)", "matching_cluster_idx": 4}]}, "Mbpp/725": {"dps": 94.20765027322403, "dps_norm": 85.0, "pass@1": 92.0, "profiled": [{"solution": "import re\ndef extract_quotation(string):\n return re.findall('\"([^\"]*)\"', string)", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(string):\n pattern = r'\"([^\"]*)\"'\n return re.findall(pattern, string)", "matching_cluster_idx": 6}, {"solution": "import re\ndef extract_quotation(s):\n pattern = '\\\"(.*?)\\\"'\n return re.findall(pattern, s)", "matching_cluster_idx": 4}, {"solution": "import re\ndef extract_quotation(text):\n pattern = r'\"([^\"]*)\"'\n return re.findall(pattern, text)", "matching_cluster_idx": 6}, {"solution": "import re\ndef extract_quotation(s):\n return re.findall(r'\"([^\"]*)\"', s)", "matching_cluster_idx": 6}, {"solution": "import re\ndef extract_quotation(input_str):\n return re.findall(r'\"([^\"]*)\"', input_str)", "matching_cluster_idx": 6}, {"solution": "import re\ndef extract_quotation(text):\n return re.findall(r'\"([^\"]*)\"', text)", "matching_cluster_idx": 6}, {"solution": "import re\ndef extract_quotation(string):\n \"\"\"\n A function to extract values between quotation marks \" \" of the given string.\n \"\"\"\n # Use regex to find all substrings enclosed by quotes\n matches = re.findall(r'\"([^\"]*)\"', string)\n return matches", "matching_cluster_idx": 6}, {"solution": "import re\ndef extract_quotation(s):\n return re.findall(r'\"([^\"]*)\"', s)", "matching_cluster_idx": 6}, {"solution": "import re\ndef extract_quotation(input_string):\n return re.findall(r'\"([^\"]*)\"', input_string)", "matching_cluster_idx": 6}, {"solution": "import re\ndef extract_quotation(s):\n return re.findall(r'\"([^\"]*)\"', s)", "matching_cluster_idx": 6}, {"solution": "import re\ndef extract_quotation(string):\n return re.findall('\"([^\"]*)\"', string)", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(s):\n return re.findall(r'\"([^\"]*)\"', s)", "matching_cluster_idx": 6}, {"solution": "import re\ndef extract_quotation(s):\n \"\"\"\n Function to extract values between quotation marks \" \" of the given string.\n \"\"\"\n return re.findall(r'\"([^\"]*)\"', s)", "matching_cluster_idx": 6}, {"solution": "import re\ndef extract_quotation(s):\n \"\"\"\n This function returns a list of values between quotation marks of a given string\n\n Parameters:\n s (str): The input string\n\n Returns:\n list: a list of strings extracted from between quotation marks\n \"\"\"\n # Using regular expression to find the strings enclosed in quotation marks\n matches = re.findall(r'\"([^\"]*)\"', s)\n \n # Return the list of matches\n return matches", "matching_cluster_idx": 6}, {"solution": "import re\ndef extract_quotation(s):\n return re.findall('\"([^\"]*)\"', s)", "matching_cluster_idx": 6}, {"solution": "import re\ndef extract_quotation(input_string):\n pattern = r'\"([^\"]*)\"'\n return re.findall(pattern, input_string)", "matching_cluster_idx": 6}, {"solution": "import re\ndef extract_quotation(input_string):\n return re.findall(r'\"([^\"]*)\"', input_string)", "matching_cluster_idx": 6}, {"solution": "import re\ndef extract_quotation(input_string):\n return re.findall(r'\"([^\"]*)\"', input_string)", "matching_cluster_idx": 6}, {"solution": "import re\ndef extract_quotation(s):\n return re.findall(r'\"([^\"]*)\"', s)", "matching_cluster_idx": 6}]}, "Mbpp/732": {"dps": 68.17829457364341, "dps_norm": 80.5, "pass@1": 100.0, "profiled": [{"solution": "def replace_specialchar(s):\n for char in [',', '.', ' ']:\n s = s.replace(char, ':')\n return s", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(s):\n \"\"\"\n Write a function to replace all occurrences of spaces, commas, or dots with a colon.\n \"\"\"\n to_replace = [\" \", \",\", \".\"]\n for char in to_replace:\n s = s.replace(char, ':')\n return s", "matching_cluster_idx": 9}, {"solution": "import re\ndef replace_specialchar(input_string):\n # Using regular expressions to replace all occurrences of spaces, commas, or dots\n result = re.sub(r'[ ,.]', ':', input_string)\n return result", "matching_cluster_idx": 3}, {"solution": "import re\ndef replace_specialchar(s):\n \"\"\"\n Replaces all occurrences of spaces, commas, or dots with a colon.\n \"\"\"\n return re.sub(r'[ ,.]', ':', s)", "matching_cluster_idx": 3}, {"solution": "def replace_specialchar(s):\n for char in [' ', ',', '.']:\n s = s.replace(char, ':')\n return s", "matching_cluster_idx": 9}, {"solution": "import re\ndef replace_specialchar(text):\n # Replace all spaces, commas and dots with a colon\n return re.sub(r'[ ,.]', ':', text)", "matching_cluster_idx": 3}, {"solution": "import re\ndef replace_specialchar(input_string):\n \"\"\"\n Function to replace all occurrences of spaces, commas, or dots with a colon.\n \"\"\"\n pattern = r\"[\\s.,]\"\n replacement = \":\"\n return re.sub(pattern, replacement, input_string)", "matching_cluster_idx": 2}, {"solution": "def replace_specialchar(s):\n chars_to_replace = [' ', ',', '.']\n for char in chars_to_replace:\n s = s.replace(char, ':')\n return s", "matching_cluster_idx": 9}, {"solution": "import re\ndef replace_specialchar(input_str):\n # replace all spaces, commas and dots using regex\n output_str = re.sub(r'[\\s,.]', ':', input_str)\n return output_str", "matching_cluster_idx": 2}, {"solution": "def replace_specialchar(s):\n for ch in [',', '.', ' ']:\n if ch in s:\n s = s.replace(ch, ':')\n return s", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(s):\n return s.replace(' ', ':').replace(',', ':').replace('.', ':')", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(s):\n special_chars = [' ', ',', '.']\n for char in special_chars:\n s = s.replace(char, ':')\n return s", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(s):\n \"\"\"\n Replace all occurrences of spaces, commas, or dots with a colon.\n \"\"\"\n # Use the Python string translate method\n return s.translate(str.maketrans(\" ,.\", \":::\"))", "matching_cluster_idx": 8}, {"solution": "def replace_specialchar(string: str) -> str:\n return string.replace(' ', ':').replace(',', ':').replace('.', ':')", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(s):\n return s.replace(' ', ':').replace(',', ':').replace('.', ':')", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(s):\n for char in [',', '.', ' ']:\n s = s.replace(char, ':')\n return s", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(string):\n for ch in [',', '.', ' ']:\n if ch in string:\n string = string.replace(ch, ':')\n return string", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(s):\n return s.replace(' ', ':').replace(',', ':').replace('.', ':')", "matching_cluster_idx": 9}, {"solution": "import re\ndef replace_specialchar(string):\n # Use the re.sub function from regular expressions module to replace all occurrences of the given special characters with a colon\n result = re.sub('[ ,.]', ':', string)\n return result", "matching_cluster_idx": 3}, {"solution": "def replace_specialchar(input_string):\n # Define the characters to be replaced\n special_characters = [\" \", \",\", \".\"]\n # Iterate over the list of special characters and replace them with a colon\n for char in special_characters:\n input_string = input_string.replace(char, \":\")\n return input_string", "matching_cluster_idx": 9}]}, "Mbpp/740": {"dps": 83.63636363636364, "dps_norm": 66.66666666666667, "pass@1": 100.0, "profiled": [{"solution": "def tuple_to_dict(input_tuple):\n \"\"\"\n Convert the given tuple to a key-value dictionary using adjacent elements.\n\n Parameters:\n input_tuple (tuple): A tuple of integers.\n\n Returns:\n dict: A dictionary where every two adjacent elements in the tuple\n form a key-value pair in the dictionary.\n \"\"\"\n output_dict = {}\n\n for i in range(0, len(input_tuple) - 1, 2):\n output_dict[input_tuple[i]] = input_tuple[i + 1]\n\n return output_dict", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(input_tuple):\n \"\"\"\n Function to convert a given tuple to a dictionary using adjacent elements\n \"\"\"\n\n # Asserting that the tuple contains even number of elements\n assert len(input_tuple) % 2 == 0, \"Input tuple should contain even number of elements\"\n\n # Initializing an empty dictionary\n output_dict = {}\n\n # Iterating over the input tuple, 2 elements at a time\n for i in range(0, len(input_tuple), 2):\n # Adding the pair of adjacent elements as a key-value pair to the dictionary\n output_dict[input_tuple[i]] = input_tuple[i + 1]\n\n # Returning the output dictionary\n return output_dict", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(tpl):\n return {tpl[i]: tpl[i + 1] for i in range(0, len(tpl), 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(tup):\n \"\"\"\n This function converts a tuple into a dictionary. The even elements of the tuple are used as keys\n and the next odd elements are used as corresponding values.\n \"\"\"\n # Create an empty dictionary\n dictionary = {}\n \n # Go through the tuple by iterating over each 2 elements (since we are using adjacent pairs)\n for i in range(0, len(tup), 2):\n # Add the key-value pair to the dictionary\n dictionary[tup[i]] = tup[i+1]\n \n # Return the created dictionary\n return dictionary", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(tup):\n return {tup[i]: tup[i + 1] for i in range(0, len(tup), 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(input_tuple):\n return {input_tuple[i]: input_tuple[i+1] for i in range(0, len(input_tuple), 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(t):\n return {t[i]: t[i + 1] for i in range(0, len(t), 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(input_tuple):\n return {input_tuple[i]: input_tuple[i+1] for i in range(0, len(input_tuple), 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(input_tuple):\n return {input_tuple[i]: input_tuple[i+1] for i in range(0, len(input_tuple), 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(t):\n if len(t) % 2 != 0:\n raise ValueError(\"Length of input tuple must be even.\")\n \n return {t[i]: t[i + 1] for i in range(0, len(t), 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(input_tuple):\n if len(input_tuple) % 2 != 0:\n raise ValueError(\"The input tuple must have an even number of elements.\")\n\n result = {}\n for i in range(0, len(input_tuple), 2):\n result[input_tuple[i]] = input_tuple[i+1]\n\n return result", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(tup):\n \"\"\"\n Convert the given tuple to a key-value dictionary using adjacent elements.\n\n Parameters:\n tup (tuple): Input tuple\n\n Returns:\n dict: Resulting dictionary\n\n >>> tuple_to_dict((1, 5, 7, 10, 13, 5))\n {1: 5, 7: 10, 13: 5}\n \"\"\"\n return {tup[i]: tup[i+1] for i in range(0, len(tup), 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(input_tuple):\n return {input_tuple[i]: input_tuple[i+1] for i in range(0, len(input_tuple), 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(t):\n return {t[i]: t[i + 1] for i in range(0, len(t), 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(t):\n return {t[i]: t[i+1] for i in range(0, len(t), 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(input_tuple):\n # create a new dictionary using dict comprehension\n new_dict = {input_tuple[i]: input_tuple[i+1] for i in range(0, len(input_tuple), 2)}\n return new_dict", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(t):\n return {t[i]: t[i + 1] for i in range(0, len(t), 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(input_tuple):\n if len(input_tuple) % 2 != 0:\n raise ValueError(\"The input tuple must have an even length.\")\n\n result = {}\n for i in range(0, len(input_tuple), 2):\n result[input_tuple[i]] = input_tuple[i+1]\n \n return result", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(t):\n return {t[i]: t[i+1] for i in range(0, len(t), 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(tup):\n \"\"\"\n Converts a tuple to a key-value dictionary using adjacent elements. \n \"\"\"\n return {tup[i]: tup[i + 1] for i in range(0, len(tup), 2)}", "matching_cluster_idx": 5}]}, "Mbpp/744": {"dps": 61.33561643835616, "dps_norm": 73.33333333333333, "pass@1": 100.0, "profiled": [{"solution": "def check_none(input_tuple):\n \"\"\"Check if the given tuple has any None value\"\"\"\n return any(item is None for item in input_tuple)", "matching_cluster_idx": 1}, {"solution": "def check_none(input_tuple):\n \"\"\"\n Returns True if any None value is found in the input tuple, else False.\n \"\"\"\n return any(item is None for item in input_tuple)", "matching_cluster_idx": 2}, {"solution": "def check_none(input_tuple):\n \"\"\"\n Checks if the given tuple has any None value or not.\n \"\"\"\n return None in input_tuple", "matching_cluster_idx": 5}, {"solution": "def check_none(input_tuple):\n return None in input_tuple", "matching_cluster_idx": 5}, {"solution": "def check_none(input_tuple):\n \"\"\"Function to check if the given tuple has any None value\"\"\"\n return any(value is None for value in input_tuple)", "matching_cluster_idx": 1}, {"solution": "def check_none(input_tuple):\n if None in input_tuple:\n return True\n else:\n return False", "matching_cluster_idx": 5}, {"solution": "def check_none(t):\n # Go through each element in the tuple\n for x in t:\n # If None found, return True\n if x is None:\n return True\n # If None not found, return False\n return False", "matching_cluster_idx": 4}, {"solution": "def check_none(tpl):\n \"\"\"\n Checks if the given tuple has any None value or not.\n \"\"\"\n return None in tpl", "matching_cluster_idx": 5}, {"solution": "def check_none(t):\n \"\"\"\n Function to check if the given tuple has any none value or not.\n \"\"\"\n # Using 'None' keyword in tuple because 'None' is also a keyword in python.\n return any(x is None for x in t)", "matching_cluster_idx": 1}, {"solution": "def check_none(tpl):\n \"\"\"\n This function checks if the given tuple has any none value or not.\n \"\"\"\n return any(item is None for item in tpl)", "matching_cluster_idx": 1}, {"solution": "def check_none(tup):\n \"\"\"\n Function to check if the given tuple has any None value or not\n \"\"\"\n return any(x is None for x in tup)", "matching_cluster_idx": 1}, {"solution": "def check_none(tup):\n \"\"\"\n Check if a tuple has any None value\n \"\"\"\n if None in tup:\n return True\n return False", "matching_cluster_idx": 5}, {"solution": "def check_none(input_tuple):\n \"\"\"\n Function to check if the given tuple has any none value or not.\n \"\"\"\n return None in input_tuple", "matching_cluster_idx": 5}, {"solution": "def check_none(tup):\n return any(x is None for x in tup)", "matching_cluster_idx": 1}, {"solution": "def check_none(input_tuple):\n \"\"\"\n Function to check if the given tuple has any none value or not\n \"\"\"\n return any(item is None for item in input_tuple)", "matching_cluster_idx": 1}, {"solution": "def check_none(input_tuple):\n return None in input_tuple", "matching_cluster_idx": 5}, {"solution": "def check_none(my_tuple):\n return None in my_tuple", "matching_cluster_idx": 5}, {"solution": "def check_none(t):\n \"\"\"\n Function to check if the given tuple has any None value or not.\n \"\"\"\n return None in t", "matching_cluster_idx": 5}, {"solution": "def check_none(num_tuple):\n \"\"\"\n Check if the given tuple has any none value or not.\n \n Arguments:\n num_tuple -- The tuple to check.\n \n Returns:\n True if the tuple contains at least one None value, False otherwise.\n \"\"\"\n return None in num_tuple", "matching_cluster_idx": 5}, {"solution": "def check_none(tup):\n \"\"\"Check if the given tuple has any None value.\"\"\"\n return None in tup", "matching_cluster_idx": 5}]}, "Mbpp/750": {"dps": 53.53741496598639, "dps_norm": 51.666666666666664, "pass@1": 99.0, "profiled": [{"solution": "def add_tuple(input_list, input_tuple):\n \"\"\"\n This function adds a given tuple to the end of a given list.\n\n Parameters:\n input_list (list): The list to add a tuple to.\n input_tuple (tuple): The tuple to add to the list.\n \n Returns:\n list: The updated list.\n \"\"\"\n\n return input_list + list(input_tuple)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(lst, tup):\n lst.extend(tup)\n return lst", "matching_cluster_idx": 5}, {"solution": "def add_tuple(list_input, tuple_input):\n return list_input + list(tuple_input)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(given_list, given_tuple):\n return given_list + list(given_tuple)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(input_list, input_tuple):\n \"\"\"\n Function to add a tuple to a list\n \"\"\"\n if not isinstance(input_list, list) or not isinstance(input_tuple, tuple):\n raise TypeError(\"Invalid input type. The first argument should be a list, and the second argument should be a tuple.\")\n return input_list + list(input_tuple)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(numbers_list, numbers_tuple):\n \"\"\"\n A function to add a tuple to a list\n \"\"\"\n if not isinstance(numbers_list, list):\n raise TypeError(\"Expected a list as argument, got {} instead.\".format(type(numbers_list)))\n if not isinstance(numbers_tuple, tuple):\n raise TypeError(\"Expected a tuple as argument, got {} instead.\".format(type(numbers_tuple)))\n return numbers_list + list(numbers_tuple)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(initial_list, tuple_to_add):\n \"\"\"\n A function to add the given tuple to the given list.\n >>> add_tuple([5, 6, 7], (9, 10))\n [5, 6, 7, 9, 10]\n \"\"\"\n # For every item in the tuple, append to the list.\n for item in tuple_to_add:\n initial_list.append(item)\n return initial_list", "matching_cluster_idx": 0}, {"solution": "def add_tuple(lst, tpl):\n return lst + list(tpl)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(lst, tup):\n \"\"\"\n A function that concatenates a given tuple to a list.\n \n Parameters:\n lst (list): The list to which the tuple will be concatenated.\n tup (tuple): The tuple to be concatenated to the list.\n \n Returns:\n list: The concatenated list with tuple's elements.\n \"\"\"\n return lst + list(tup)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(lst, tup):\n \"\"\"\n Adds the given tuple to the given list.\n \"\"\"\n return lst + list(tup)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(lst, tpl):\n \"\"\"Add the given tuple to the given list.\"\"\"\n return lst + list(tpl)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(lst, tpl):\n return lst + list(tpl)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(lst, tup):\n return lst + list(tup)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(lst, tup):\n \"\"\"\n Add the given tuple to the given list.\n \n Args:\n lst (list): The list to append the tuple to.\n tup (tuple): The tuple to append to the list.\n \n Returns:\n list: The resulting list after appending the tuple to the given list.\n \"\"\"\n return lst + list(tup)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(list, tuple):\n \"\"\"\n This function adds the given tuple to the given list.\n \"\"\"\n # Using the extend() function to add each element of the tuple to the list.\n list.extend(tuple)\n # Return the modified list\n return list", "matching_cluster_idx": 5}, {"solution": "def add_tuple(lst, tup):\n return lst + list(tup)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(lst, tpl):\n \"\"\"\n Function to add a tuple to a list.\n \"\"\"\n return lst + list(tpl)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(list_, tuple_):\n \"\"\"This function takes a list and a tuple as input, appends elements from the tuple to the list, and returns the combined list.\"\"\"\n\n # Check if the input is a list and a tuple\n if not isinstance(list_, list) or not isinstance(tuple_, tuple):\n raise ValueError('Input must be a list and a tuple')\n\n # Add elements from the tuple to the list\n for element in tuple_:\n list_.append(element)\n\n return list_", "matching_cluster_idx": 0}, {"solution": "def add_tuple(lst, tpl):\n return lst + list(tpl)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(lst, tpl):\n return lst + list(tpl)", "matching_cluster_idx": 2}]}, "Mbpp/753": {"dps": 97.31543624161074, "dps_norm": 75.0, "pass@1": 100.0, "profiled": [{"solution": "def min_k(tuple_list, k):\n tuple_list.sort(key = lambda x: x[1])\n return tuple_list[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(tuples, k):\n # Sort the list of tuples by second item in each tuple\n sorted_tuples = sorted(tuples, key=lambda x: x[1])\n # Return the first k tuples\n return sorted_tuples[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(records, k):\n records.sort(key = lambda x: x[1])\n return records[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(tuples, k):\n \"\"\"\n Function to find minimum k records from tuple list.\n \"\"\"\n # Sort the list of tuples by second item in each tuple (in ascending order)\n tuples.sort(key = lambda x: x[1])\n # Return the first k tuples\n return tuples[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(data, k):\n data.sort(key=lambda x: x[1])\n return data[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(tuples, k):\n tuples.sort(key = lambda x: x[1])\n return tuples[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(lst, k):\n \"\"\"\n Find the k minimum records from a list of tuples\n \"\"\"\n # sort the list by second element in tuple\n lst.sort(key=lambda x: x[1])\n \n # return the first k elements from sorted list\n return lst[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(input_list, k):\n # Sort the list based on second item of tuple\n sorted_list = sorted(input_list, key=lambda x: x[1])\n # Return the first k elements\n return sorted_list[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(input_list, k):\n input_list.sort(key = lambda x: x[1])\n return input_list[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(tuples_list, k):\n tuples_list.sort(key=lambda x: x[1]) # Sort the list of tuples by the second element of each tuple\n return tuples_list[:k] # Return the first k elements", "matching_cluster_idx": 2}, {"solution": "def min_k(lst, k):\n lst.sort(key = lambda x: x[1])\n return lst[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(tuples_list, k):\n \"\"\"\n Function to find minimum k records from tuple list.\n \"\"\"\n tuples_list.sort(key=lambda x: x[1])\n return tuples_list[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(records, k):\n \"\"\"\n Function to find minimum k records from tuple list\n \"\"\"\n # Sort the list by second item in tuple (number) in ascending order\n records.sort(key=lambda x: x[1])\n\n # Return the first k records\n return records[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(records, k):\n records.sort(key=lambda x: x[1])\n return records[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(input_list, k):\n # Sorting the list based on second item of tuple\n input_list.sort(key = lambda x: x[1])\n \n # Returning first k records\n return input_list[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(tuple_list, k):\n \"\"\"\n Given a list of tuples, this function returns the minimum k records from the list.\n\n Parameters:\n tuple_list (list): A list of tuples where each tuple contains a name and a number.\n k (int): The number of minimum records to return.\n\n Returns:\n list: A list of minimum k records from the tuple_list.\n \"\"\"\n # Sort the list in ascending order according to the second element in each tuple\n tuple_list.sort(key = lambda x: x[1])\n\n # Return the first k records from the sorted list\n return tuple_list[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(data, k):\n return sorted(data, key=lambda x: x[1])[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(tuples, k):\n # Sort the tuple list based on the second element of each tuple (values)\n tuples.sort(key=lambda x: x[1])\n\n # return the first k elements from the sorted list\n return tuples[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(tuple_list, k):\n tuple_list.sort(key=lambda x: x[1])\n return tuple_list[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(lst, k):\n lst.sort(key=lambda x: x[1])\n return lst[:k]", "matching_cluster_idx": 2}]}, "Mbpp/754": {"dps": 78.27586206896552, "dps_norm": 82.5, "pass@1": 62.0, "profiled": [{"solution": "def extract_index_list(l1, l2, l3):\n common = []\n for i in range(min(len(l1), len(l2), len(l3))):\n if l1[i] == l2[i] == l3[i]:\n common.append(l1[i])\n return common\nl1 = [1, 1, 3, 4, 5, 6, 7]\nl2 = [0, 1, 2, 3, 4, 5, 7]\nl3 = [0, 1, 2, 3, 4, 5, 7]", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n common_elements = []\n for i in range(min(len(l1), len(l2), len(l3))):\n if l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n return common_elements\nl1 = [1, 1, 3, 4, 5, 6, 7]\nl2 = [0, 1, 2, 3, 4, 5, 7]\nl3 = [0, 1, 2, 3, 4, 5, 7]", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n common = []\n for i in range(min(len(l1), len(l2), len(l3))):\n if l1[i] == l2[i] == l3[i]:\n common.append(l1[i])\n return common", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n common_elements = []\n min_length = min(len(l1), len(l2), len(l3))\n for i in range(min_length):\n if l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n common_elements = []\n for i in range(min(len(l1), len(l2), len(l3))):\n if l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n common_elements = []\n for i in range(min(len(l1), len(l2), len(l3))):\n if l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n return common_elements\nl1 = [1, 1, 3, 4, 5, 6, 7]\nl2 = [0, 1, 2, 3, 4, 5, 7]\nl3 = [0, 1, 2, 3, 4, 5, 7]", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n \"\"\"Find common elements from three lists.\n \n Parameters:\n l1 (list): The first list.\n l2 (list): The second list.\n l3 (list): The third list.\n \n Returns:\n list: A list of common elements.\n \"\"\"\n assert isinstance(l1, list), \"l1 must be a list\"\n assert isinstance(l2, list), \"l2 must be a list\"\n assert isinstance(l3, list), \"l3 must be a list\"\n \n common_list = []\n \n # Iterating over each list simultaneously and checking if the elements are same\n for i, j, k in zip(l1, l2, l3):\n if i == j == k:\n common_list.append(i)\n \n return common_list", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n common_elements = []\n for i in range(len(l1)):\n if i < len(l2) and i < len(l3) and l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n return common_elements", "matching_cluster_idx": 4}, {"solution": "def extract_index_list(l1, l2, l3):\n result = []\n for i in range(min(len(l1), len(l2), len(l3))):\n if l1[i] == l2[i] == l3[i]:\n result.append(l1[i])\n return result", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n common_elements = []\n min_length = min(len(l1), len(l2), len(l3))\n for i in range(min_length):\n if l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n common = []\n for i in range(min(len(l1), len(l2), len(l3))):\n if l1[i] == l2[i] == l3[i]:\n common.append(l1[i])\n return common\nl1 = [1, 1, 3, 4, 5, 6, 7]\nl2 = [0, 1, 2, 3, 4, 5, 7]\nl3 = [0, 1, 2, 3, 4, 5, 7]", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n common_elements = []\n for i in range(min(len(l1), len(l2), len(l3))):\n if l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n return common_elements\nl1 = [1, 1, 3, 4, 5, 6, 7]\nl2 = [0, 1, 2, 3, 4, 5, 7]\nl3 = [0, 1, 2, 3, 4, 5, 7]", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n common_elements = []\n for i in range(len(l1)):\n if i < len(l2) and i < len(l3) and l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n return common_elements\nl1 = [1, 1, 3, 4, 5, 6, 7]\nl2 = [0, 1, 2, 3, 4, 5, 7]\nl3 = [0, 1, 2, 3, 4, 5, 7]", "matching_cluster_idx": 4}, {"solution": "def extract_index_list(l1, l2, l3):\n common = []\n for i in range(min(len(l1), len(l2), len(l3))):\n if l1[i] == l2[i] == l3[i]:\n common.append(l1[i])\n return common\nl1 = [1, 1, 3, 4, 5, 6, 7]\nl2 = [0, 1, 2, 3, 4, 5, 7]\nl3 = [0, 1, 2, 3, 4, 5, 7]", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n common_elements = [value for index, value in enumerate(l1) if index < len(l2) and index < len(l3) and value == l2[index] == l3[index]]\n return common_elements", "matching_cluster_idx": 4}, {"solution": "def extract_index_list(l1, l2, l3):\n common_elements = []\n for i in range(min(len(l1), len(l2), len(l3))):\n if l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n return common_elements\nl1 = [1, 1, 3, 4, 5, 6, 7]\nl2 = [0, 1, 2, 3, 4, 5, 7]\nl3 = [0, 1, 2, 3, 4, 5, 7]", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n common_elements = []\n length = min(len(l1), len(l2), len(l3))\n for i in range(length):\n if l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n common_elements = []\n for i in range(min(len(l1), len(l2), len(l3))):\n if l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n return common_elements\nl1 = [1, 1, 3, 4, 5, 6, 7]\nl2 = [0, 1, 2, 3, 4, 5, 7]\nl3 = [0, 1, 2, 3, 4, 5, 7]", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n result = []\n for i in range(min(len(l1), len(l2), len(l3))):\n if l1[i] == l2[i] == l3[i]:\n result.append(l1[i])\n return result", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n common_elements = []\n for i in range(len(l1)):\n if i < len(l2) and i < len(l3) and l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n return common_elements", "matching_cluster_idx": 4}]}, "Mbpp/755": {"dps": 63.49557522123894, "dps_norm": 80.0, "pass@1": 29.0, "profiled": [{"solution": "def second_smallest(lst):\n # Remove duplicate values from the list\n unique_lst = list(set(lst))\n \n # If the list only has one unique value or none\n if len(unique_lst) < 2:\n return None\n \n # Sort the list in ascending order and return the second element\n unique_lst.sort()\n return unique_lst[1]", "matching_cluster_idx": 5}, {"solution": "def second_smallest(nums):\n \"\"\"\n Function to find the second smallest number in a list.\n \"\"\"\n nums.sort()\n for i in range(1, len(nums)):\n if nums[i] > nums[0]:\n return nums[i]\n return None", "matching_cluster_idx": 2}, {"solution": "def second_smallest(nums):\n \"\"\"\n Find the second smallest number in a list.\n \"\"\"\n # Remove duplicates by converting list to set\n nums = list(set(nums))\n\n # If list contains only one or zero element\n if len(nums) < 2:\n return None\n else:\n # sort the list and return the second element\n nums.sort()\n return nums[1]", "matching_cluster_idx": 5}, {"solution": "def second_smallest(numbers):\n # Remove duplicates from the list\n numbers = list(set(numbers))\n\n # Check if there are less than 2 unique numbers\n if len(numbers) < 2:\n return None\n\n # Initialize the smallest and second smallest numbers\n smallest = min(numbers[0], numbers[1])\n second_smallest = max(numbers[0], numbers[1])\n\n # Iterate over the remaining numbers in the list\n for num in numbers[2:]:\n # If the current number is smaller than the smallest number\n if num < smallest:\n # Update the smallest and second smallest numbers\n second_smallest = smallest\n smallest = num\n # If the current number is between the smallest and second smallest numbers\n elif num < second_smallest:\n # Update the second smallest number\n second_smallest = num\n\n return second_smallest\nnumbers = [1, 2, -8, -2, 0, -2]", "matching_cluster_idx": 3}, {"solution": "def second_smallest(num_list):\n # Making sure that the list has at least two elements\n if len(num_list) < 2:\n return None\n \n # Initializing the smallest and second smallest as maximum number\n smallest = float('inf')\n second_smallest = float('inf')\n \n # Go through the list once\n for num in num_list:\n # If current number is less than the smallest number\n if num < smallest:\n # Update the smallest and second smallest\n second_smallest = smallest\n smallest = num\n # If current number is between smallest and second smallest\n elif num < second_smallest and num > smallest:\n # Update the second smallest number\n second_smallest = num\n \n # Return the second smallest if found, else return None\n if second_smallest < float('inf'):\n return second_smallest\n else:\n return None", "matching_cluster_idx": 4}, {"solution": "def second_smallest(nums):\n \"\"\"\n Function to find the second smallest number in a list.\n \"\"\"\n if len(nums) < 2:\n return None\n nums = sorted(set(nums))\n if len(nums) < 2:\n return None\n else:\n return nums[1]", "matching_cluster_idx": 5}, {"solution": "def second_smallest(nums):\n \"\"\"\n Function to find the second smallest number in a list.\n If the list has less than 2 elements, it will return None.\n \"\"\"\n if len(nums) < 2:\n return None\n\n # Initialize the first and second smallest numbers\n first, second = float('inf'), float('inf')\n\n # Iterate over the list\n for num in nums:\n # Check if this number is smaller than the smallest number so far\n if num < first:\n second = first\n first = num\n # Check if this number is the second smallest and not equal to the smallest\n elif first < num < second:\n second = num\n\n # If the second smallest number is still equal to infinity after the iteration, it means\n # there is no second smallest number\n if second == float('inf'):\n return None\n\n return second", "matching_cluster_idx": 3}, {"solution": "def second_smallest(numbers):\n # Remove duplicate elements from list\n numbers = list(set(numbers))\n \n # Check if there are at least 2 distinct numbers\n if len(numbers)<2:\n return None\n \n # Find the two smallest numbers\n smallest = min(numbers)\n numbers.remove(smallest)\n second_smallest_num = min(numbers)\n \n return second_smallest_num", "matching_cluster_idx": 4}, {"solution": "def second_smallest(nums):\n \"\"\"\n Finds the second smallest number in a list of numbers\n\n Parameters:\n nums (list): List of numbers\n\n Returns:\n Second smallest number in the list. If the list is less than 2 elements or\n does not contain a second smallest number, it returns None\n \"\"\"\n\n # if the list is less than 2 elements\n if len(nums) < 2:\n return None\n \n # initialize the first and second variables\n first, second = float('inf'), float('inf')\n\n # iterate over the list\n for num in nums:\n # ignore if the number is non-numeric\n if not isinstance(num, (int, float)):\n continue\n # update the first and second smallest if the current number is smaller\n if num < first:\n first, second = num, first\n elif first < num < second:\n second = num\n\n # if after iterating we couldn't find a second smallest\n if second == float('inf'):\n return None\n \n # return the second smallest\n return second", "matching_cluster_idx": 0}, {"solution": "def second_smallest(lst):\n \"\"\"\n This function returns the second smallest number in a list.\n \"\"\"\n # Remove duplicate values in list\n lst = list(dict.fromkeys(lst))\n \n # If there are fewer than 2 distinct numbers in the list\n if len(lst) < 2:\n return None\n \n # Sort the list in ascending order\n lst.sort()\n \n # Return the second number in the list\n return lst[1]", "matching_cluster_idx": 2}, {"solution": "def second_smallest(numbers):\n \"\"\"\n This function takes a list of numbers and returns the second smallest number in the list.\n If the list has less than two distinct numbers, it returns None.\n \"\"\"\n # Remove duplicates by converting list to set\n numbers_set = set(numbers)\n\n # Convert back to list and sort in ascending order\n sorted_numbers = sorted(list(numbers_set))\n\n # Return second number if it exists, else return None\n if len(sorted_numbers) >= 2:\n return sorted_numbers[1]\n else:\n return None", "matching_cluster_idx": 5}, {"solution": "def second_smallest(num_list):\n \"\"\"\n This function returns the second smallest number in a list.\n \"\"\"\n\n # Remove duplicates from the list\n num_list = list(set(num_list))\n \n # If there are less than 2 unique numbers, we return None\n if len(num_list) < 2:\n return None\n\n # Sort the list in ascending order\n num_list.sort()\n \n # Return the second number in the sorted list\n return num_list[1]", "matching_cluster_idx": 5}, {"solution": "def second_smallest(numbers):\n \"\"\"\n Function to find the second smallest number in a list.\n \"\"\"\n if len(numbers) < 2:\n return None\n\n first_smallest = second_smallest = float('inf')\n for number in numbers:\n if number < first_smallest:\n first_smallest, second_smallest = number, first_smallest\n elif first_smallest < number < second_smallest:\n second_smallest = number\n return None if second_smallest == float('inf') else second_smallest", "matching_cluster_idx": 3}, {"solution": "def second_smallest(lst):\n \"\"\"\n Function to find the second smallest number in a list.\n \"\"\"\n # remove duplicates and sort the list\n lst = sorted(set(lst))\n # return the second smallest number\n return lst[1] if len(lst) > 1 else None", "matching_cluster_idx": 5}, {"solution": "def second_smallest(nums):\n # Remove duplicates from list\n nums = list(set(nums))\n # Sort the list\n nums.sort()\n # If the list has less than 2 elements, there is no second smallest element\n if len(nums) < 2:\n return None\n else:\n # Return the second element of sorted list\n return nums[1]", "matching_cluster_idx": 5}, {"solution": "def second_smallest(nums):\n # Remove duplicates by using set and then convert back to list\n nums = list(set(nums))\n # Sort the list\n nums.sort()\n # If list has at least two elements, return the second one\n if len(nums) > 1:\n return nums[1]\n else:\n return None", "matching_cluster_idx": 5}, {"solution": "def second_smallest(lst):\n # Remove duplicates from the list.\n unique_numbers = list(set(lst))\n\n # Initialize the smallest and second smallest as positive infinity.\n smallest, second_smallest = float('inf'), float('inf')\n \n # If the list has less than 2 distinct numbers, return None.\n if len(unique_numbers) < 2:\n return None\n\n # Find the smallest and second smallest numbers in the list.\n for number in unique_numbers:\n if number < smallest:\n smallest = number\n unique_numbers.remove(smallest)\n for number in unique_numbers:\n if number < second_smallest:\n second_smallest = number\n\n return second_smallest", "matching_cluster_idx": 3}, {"solution": "def second_smallest(nums):\n nums = set(nums)\n if len(nums) < 2:\n return None\n nums.remove(min(nums))\n return min(nums)", "matching_cluster_idx": 4}, {"solution": "def second_smallest(nums):\n \"\"\"Function to find the second smallest number in a list.\"\"\"\n\n # Remove duplicates.\n nums = list(set(nums))\n\n # Check if the list contains at least two unique numbers.\n if len(nums) < 2:\n return None\n\n # Sort the list in ascending order and return the second element.\n nums.sort()\n\n return nums[1]", "matching_cluster_idx": 5}, {"solution": "def second_smallest(nums):\n smallest = None\n second_smallest = None\n \n for num in nums:\n if smallest is None:\n smallest = num\n elif num < smallest:\n second_smallest = smallest\n smallest = num\n elif (second_smallest is None or second_smallest > num) and num != smallest:\n second_smallest = num\n \n return second_smallest", "matching_cluster_idx": 3}]}, "Mbpp/757": {"dps": 82.71028037383178, "dps_norm": 23.076923076923077, "pass@1": 15.0, "profiled": [{"solution": "def count_reverse_pairs(words):\n count = 0\n for i in range(len(words)):\n for j in range(i+1, len(words)):\n if words[i] == words[j][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(lst):\n pairs = []\n for i in range(len(lst)):\n for j in range(i+1, len(lst)):\n if lst[i] == lst[j][::-1]:\n pairs.append((lst[i], lst[j]))\n return len(pairs)", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(words):\n count = 0\n for i in range(len(words)):\n for j in range(i+1, len(words)):\n if words[i][::-1] == words[j]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(lst):\n count = 0\n for i in range(len(lst)):\n for j in range(i+1, len(lst)):\n if lst[i][::-1] == lst[j]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(arr):\n def is_reverse(s1, s2):\n return s1 == s2[::-1]\n\n count = 0\n for i in range(len(arr)):\n for j in range(i+1, len(arr)):\n if is_reverse(arr[i], arr[j]):\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(lst):\n count = 0\n for i in range(len(lst)):\n for j in range(i+1, len(lst)):\n if lst[i] == lst[j][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(str_list):\n count = 0\n for i in range(len(str_list)):\n for j in range(i+1, len(str_list)):\n if str_list[i] == str_list[j][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(strings):\n count = 0\n for i in range(len(strings)):\n for j in range(i + 1, len(strings)):\n if strings[i] == strings[j][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(words):\n count = 0\n for i in range(len(words)):\n for j in range(i+1, len(words)):\n if words[i] == words[j][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(strings):\n count = 0\n for i in range(len(strings)):\n for j in range(i + 1, len(strings)):\n if strings[i] == strings[j][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(list_of_strings):\n count = 0\n for i in range(len(list_of_strings)):\n for j in range(i + 1, len(list_of_strings)):\n if list_of_strings[i] == list_of_strings[j][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(word_list):\n \"\"\"\n Function to count the pairs of reverse strings in the given string list.\n \"\"\"\n count = 0\n for i in range(len(word_list)):\n for j in range(i+1, len(word_list)):\n # check if a word is the reverse of the other\n if word_list[i] == word_list[j][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(input_list):\n counter = 0\n for i in range(len(input_list)):\n for j in range(i+1, len(input_list)):\n if input_list[i][::-1] == input_list[j]:\n counter += 1\n return counter", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(lst):\n reverse_pairs_count = 0\n for i in range(len(lst)):\n for j in range(i+1, len(lst)):\n if lst[i] == lst[j][::-1]:\n reverse_pairs_count += 1\n return reverse_pairs_count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(lst):\n count = 0\n for i in range(len(lst)):\n for j in range(i+1, len(lst)):\n if lst[i][::-1] == lst[j]:\n count += 1\n return count", "matching_cluster_idx": 2}]}, "Mbpp/758": {"dps": 87.8185328185328, "dps_norm": 83.125, "pass@1": 96.0, "profiled": [{"solution": "def unique_sublists(lst):\n res = {}\n for i in lst:\n i = tuple(i)\n if i in res:\n res[i] += 1\n else:\n res[i] = 1\n return res", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(lst):\n result = {}\n for sublist in lst:\n # convert each sublist to a tuple\n sublist_tuple = tuple(sublist)\n if sublist_tuple in result:\n result[sublist_tuple] += 1\n else:\n result[sublist_tuple] = 1\n return result", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(lst):\n result_dict = {}\n for sublist in lst:\n tup = tuple(sublist)\n if tup in result_dict:\n result_dict[tup] += 1\n else:\n result_dict[tup] = 1\n return result_dict", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(lst):\n from collections import defaultdict\n dict_count = defaultdict(int)\n for sublist in lst:\n dict_count[tuple(sublist)] += 1\n return dict_count", "matching_cluster_idx": 5}, {"solution": "def unique_sublists(lst):\n result = {}\n for sublist in lst:\n sublist_as_tuple = tuple(sublist)\n if sublist_as_tuple in result:\n result[sublist_as_tuple] += 1\n else:\n result[sublist_as_tuple] = 1\n return result", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(sublists):\n sublists_dict = {}\n for sublist in sublists:\n sublist_tuple = tuple(sublist)\n if sublist_tuple in sublists_dict:\n sublists_dict[sublist_tuple] += 1\n else:\n sublists_dict[sublist_tuple] = 1\n return sublists_dict", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(lst):\n result = {}\n for sub_lst in lst:\n sub_tup = tuple(sub_lst)\n if sub_tup in result:\n result[sub_tup] += 1\n else:\n result[sub_tup] = 1\n return result", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(lst):\n freq_dict = {}\n for sub_list in lst:\n sub_tuple = tuple(sub_list)\n if sub_tuple in freq_dict:\n freq_dict[sub_tuple] += 1\n else:\n freq_dict[sub_tuple] = 1\n return freq_dict", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(lst):\n count_dict = {}\n for sublist in lst:\n tuple_sublist = tuple(sublist)\n if tuple_sublist in count_dict:\n count_dict[tuple_sublist] += 1\n else:\n count_dict[tuple_sublist] = 1\n return count_dict", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(lst):\n dic = {}\n for sublist in lst:\n t = tuple(sublist)\n if t in dic:\n dic[t] += 1\n else:\n dic[t] = 1\n return dic", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(lst):\n result = {}\n for sublist in lst:\n sublist_tuple = tuple(sublist)\n if sublist_tuple in result:\n result[sublist_tuple] += 1\n else:\n result[sublist_tuple] = 1\n return result", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(lst):\n # Convert each sublist to a tuple\n lst = [tuple(i) for i in lst]\n \n # Create a dictionary with tuples as keys and their counts as values\n unique_dict = {}\n for i in lst:\n if i in unique_dict:\n unique_dict[i] += 1\n else:\n unique_dict[i] = 1\n \n return unique_dict", "matching_cluster_idx": 6}, {"solution": "from collections import Counter\ndef unique_sublists(lst):\n tupled_lst = [tuple(sublist) for sublist in lst]\n return dict(Counter(tupled_lst))", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(lst):\n return {tuple(sublist): lst.count(sublist) for sublist in lst}", "matching_cluster_idx": 3}, {"solution": "def unique_sublists(lists):\n # Convert each list to a tuple, and count its occurrences in the original list\n return {tuple(lst): lists.count(lst) for lst in [list(x) for x in set(tuple(x) for x in lists)]}", "matching_cluster_idx": 3}, {"solution": "def unique_sublists(lst):\n count_dict = {}\n for sublst in lst:\n sublst = tuple(sublst)\n if sublst in count_dict:\n count_dict[sublst] += 1\n else:\n count_dict[sublst] = 1\n return count_dict", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(list_of_lists):\n from collections import Counter\n tuple_list = [tuple(sublist) for sublist in list_of_lists]\n count_dict = dict(Counter(tuple_list))\n return count_dict", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(input_list):\n output_dict = {}\n for sublist in input_list:\n sublist_tuple = tuple(sublist)\n if sublist_tuple not in output_dict:\n output_dict[sublist_tuple] = 1\n else:\n output_dict[sublist_tuple] += 1\n return output_dict", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(lst):\n dict_out = {}\n for sublist in lst:\n tup = tuple(sublist)\n if tup in dict_out:\n dict_out[tup] += 1\n else:\n dict_out[tup] = 1\n return dict_out\nlst = [[1, 3], [5, 7], [1, 3], [13, 15, 17], [5, 7], [9, 11]]", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(lst):\n dic = {}\n for sublist in lst:\n tup = tuple(sublist)\n if tup in dic:\n dic[tup] += 1\n else:\n dic[tup] = 1\n return dic", "matching_cluster_idx": 6}]}, "Mbpp/760": {"dps": 99.27007299270073, "dps_norm": 87.5, "pass@1": 70.0, "profiled": [{"solution": "def unique_Element(num_list):\n \"\"\"\n Function to check whether a list of numbers contains only one distinct element or not\n \"\"\"\n return len(set(num_list)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(num_list):\n \"\"\"\n Function to check whether a list contains only one distinct element or not.\n \"\"\"\n # Create a set from the list\n set_list = set(num_list)\n \n # If the length of the set is 1, return True (the list contains only unique elements)\n if len(set_list) == 1:\n return True\n else:\n return False", "matching_cluster_idx": 6}, {"solution": "def unique_Element(input_list):\n return len(set(input_list)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(numbers):\n return len(set(numbers)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(lst):\n return len(set(lst)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(lst):\n return len(set(lst)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(lst):\n return len(set(lst)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(nums):\n return len(set(nums)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(num_list):\n return len(set(num_list)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(num_list):\n \"\"\"\n A function to check if a list contains only one distinct element or not\n :param num_list: list\n :return: bool\n \"\"\"\n return len(set(num_list)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(num_list):\n # Check if all elements in the list are the same\n return len(set(num_list)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(lst):\n return len(set(lst)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(lst):\n return len(set(lst)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(lst):\n return len(set(lst)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(lst):\n return len(set(lst)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(lst):\n return len(set(lst)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(lst):\n return len(set(lst)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(lst):\n # Check if all elements in the list are the same\n return len(set(lst)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(lst):\n return len(set(lst)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(lst):\n \"\"\"\n Function to check if a list of numbers contains only one distinct element\n \"\"\"\n return len(set(lst)) == 1", "matching_cluster_idx": 6}]}, "Mbpp/764": {"dps": 88.88888888888889, "dps_norm": 50.0, "pass@1": 100.0, "profiled": [{"solution": "def number_ctr(string):\n return sum(c.isdigit() for c in string)", "matching_cluster_idx": 2}, {"solution": "def number_ctr(input_str):\n \"\"\"\n A python function to count number of digits in a given string.\n \"\"\"\n return sum(c.isdigit() for c in input_str)", "matching_cluster_idx": 2}, {"solution": "def number_ctr(text):\n count = 0\n for char in text:\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(input_str):\n return sum(c.isdigit() for c in input_str)", "matching_cluster_idx": 2}, {"solution": "def number_ctr(string):\n count = 0\n for char in string:\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(string):\n \"\"\"\n A function to count the number of digits in a string.\n \n Parameters:\n string (str): The string in which to count the digits.\n \n Returns:\n int: The number of digits in the string.\n \"\"\"\n return sum(c.isdigit() for c in string)", "matching_cluster_idx": 2}, {"solution": "def number_ctr(string):\n # Initialize count to 0\n count = 0\n\n # Iterate over each character in the string\n for char in string:\n # Check if character is a digit\n if char.isdigit():\n # Increase count by 1\n count += 1\n\n # Return count\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n return sum(c.isdigit() for c in s)", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n return sum(c.isdigit() for c in s)", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n return sum(c.isdigit() for c in s)", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n return sum(c.isdigit() for c in s)", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n return sum(c.isdigit() for c in s)", "matching_cluster_idx": 2}, {"solution": "def number_ctr(string):\n \"\"\"Count number of digits in a given string.\"\"\"\n return sum(character.isdigit() for character in string)", "matching_cluster_idx": 2}, {"solution": "def number_ctr(string):\n return sum(character.isdigit() for character in string)", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n return sum(c.isdigit() for c in s)", "matching_cluster_idx": 2}, {"solution": "def number_ctr(input_string):\n return sum(c.isdigit() for c in input_string)", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n return sum(c.isdigit() for c in s)", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n \"\"\"\n Function to count number of digits in a given string.\n \"\"\"\n # Initialize counter\n digit_ctr = 0\n\n # Iterate over each character in the string\n for char in s:\n\n # If the character is a digit, increment counter\n if char.isdigit():\n digit_ctr += 1\n\n return digit_ctr", "matching_cluster_idx": 2}, {"solution": "def number_ctr(string: str) -> int:\n return sum(character.isdigit() for character in string)", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n return sum(c.isdigit() for c in s)", "matching_cluster_idx": 2}]}, "Mbpp/766": {"dps": 58.925233644859816, "dps_norm": 52.5, "pass@1": 100.0, "profiled": [{"solution": "def pair_wise(lst):\n return [(lst[i], lst[i+1]) for i in range(len(lst)-1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n return [(lst[i], lst[i + 1]) for i in range(len(lst) - 1)]", "matching_cluster_idx": 2}, {"solution": "def pair_wise(input_list):\n \"\"\"\n Function to return a list of all pairs of consecutive items in a given list.\n \"\"\"\n result = [(input_list[n], input_list[n + 1]) for n in range(len(input_list) - 1)]\n return result", "matching_cluster_idx": 2}, {"solution": "def pair_wise(nums):\n \"\"\"Returns a list of all pairs of consecutive items in a given list.\"\"\"\n return [(nums[i], nums[i+1]) for i in range(len(nums)-1)]", "matching_cluster_idx": 2}, {"solution": "def pair_wise(lst):\n return [(lst[i], lst[i+1]) for i in range(len(lst)-1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(items):\n return [(items[i], items[i+1]) for i in range(len(items)-1)]", "matching_cluster_idx": 2}, {"solution": "def pair_wise(lst):\n \"\"\"Return a list of all pairs of consecutive items in a given list.\"\"\"\n return [(lst[i], lst[i+1]) for i in range(len(lst)-1)]", "matching_cluster_idx": 2}, {"solution": "def pair_wise(lst):\n return [(lst[i], lst[i+1]) for i in range(len(lst)-1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n return [(lst[i], lst[i + 1]) for i in range(len(lst) - 1)]", "matching_cluster_idx": 2}, {"solution": "def pair_wise(input_list):\n return [(input_list[i], input_list[i+1]) for i in range(len(input_list)-1)]", "matching_cluster_idx": 2}, {"solution": "def pair_wise(lst):\n return [(lst[i], lst[i + 1]) for i in range(len(lst) - 1)]", "matching_cluster_idx": 2}, {"solution": "def pair_wise(lst):\n return [(lst[i], lst[i+1]) for i in range(len(lst) - 1)]", "matching_cluster_idx": 2}, {"solution": "def pair_wise(arr):\n \"\"\"\n Returns a list of all pairs of consecutive items in a given list.\n \"\"\"\n return [(arr[i], arr[i+1]) for i in range(len(arr)-1)]", "matching_cluster_idx": 2}, {"solution": "def pair_wise(lst):\n return [(lst[i], lst[i + 1]) for i in range(len(lst) - 1)]", "matching_cluster_idx": 2}, {"solution": "def pair_wise(lst):\n return [(lst[i], lst[i+1]) for i in range(len(lst) - 1)]", "matching_cluster_idx": 2}, {"solution": "def pair_wise(lst):\n return [(lst[i], lst[i + 1]) for i in range(len(lst) - 1)]", "matching_cluster_idx": 2}, {"solution": "def pair_wise(input_list):\n return [(input_list[i], input_list[i+1]) for i in range(len(input_list)-1)]", "matching_cluster_idx": 2}, {"solution": "def pair_wise(list_):\n return [(list_[i], list_[i + 1]) for i in range(len(list_) - 1)]", "matching_cluster_idx": 2}, {"solution": "def pair_wise(lst):\n return [(lst[i], lst[i + 1]) for i in range(len(lst) - 1)]", "matching_cluster_idx": 2}, {"solution": "def pair_wise(arr):\n \"\"\"\n This function returns a list of all pairs of consecutive items in a given list.\n \"\"\"\n result = []\n for i in range(len(arr) - 1):\n result.append((arr[i], arr[i + 1]))\n return result", "matching_cluster_idx": 2}]}, "Mbpp/775": {"dps": 69.91999999999999, "dps_norm": 47.14285714285714, "pass@1": 89.0, "profiled": [{"solution": "def odd_position(lst):\n return all(i % 2 == 1 for i in lst[1::2])", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n \"\"\"\n Check if every odd index contains odd numbers in the given list.\n \"\"\"\n return all(n % 2 != 0 for i, n in enumerate(lst) if i % 2 != 0)", "matching_cluster_idx": 2}, {"solution": "def odd_position(num_list):\n for i in range(len(num_list)):\n if i % 2 != 0 and num_list[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 2}, {"solution": "def odd_position(lst):\n \"\"\"\n Function to check whether every odd index contains odd numbers of a given list.\n \"\"\"\n for i in range(len(lst)):\n if i % 2 != 0 and lst[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 2}, {"solution": "def odd_position(lst):\n return all(v % 2 != 0 for i, v in enumerate(lst) if i % 2 != 0)", "matching_cluster_idx": 2}, {"solution": "def odd_position(lst):\n for i in range(len(lst)):\n if i % 2 == 1 and lst[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 2}, {"solution": "def odd_position(lst):\n for i in range(len(lst)):\n if i % 2 != 0 and lst[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 2}, {"solution": "def odd_position(lst):\n for i in range(len(lst)):\n if i % 2 != 0 and lst[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 2}, {"solution": "def odd_position(lst):\n return all(value % 2 != 0 for index, value in enumerate(lst) if index % 2 != 0)", "matching_cluster_idx": 2}, {"solution": "def odd_position(lst):\n for i in range(1, len(lst), 2):\n if lst[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n \"\"\"\n This function checks whether every odd index contains odd numbers of a given list.\n \"\"\"\n for i in range(len(lst)):\n # Check if index is odd and element on that index is not odd\n if i % 2 != 0 and lst[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 2}, {"solution": "def odd_position(lst):\n \"\"\"\n Check if every odd index contains odd numbers from a given list.\n\n Parameters:\n lst (list): input list of integers.\n\n Returns:\n bool: True if every odd index contains an odd number, False otherwise.\n \"\"\"\n for i in range(len(lst)):\n if i % 2 != 0 and lst[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 2}, {"solution": "def odd_position(input_list):\n # Initialize odd_count to 0\n odd_count = 0\n\n # Iterate over odd indices\n for i in range(1, len(input_list), 2):\n # If number at odd index is odd, increment odd_count\n if input_list[i] % 2 != 0:\n odd_count += 1\n\n # If odd_count equals half of length of list (rounded down), return True, else False\n return odd_count == len(input_list) // 2", "matching_cluster_idx": 2}, {"solution": "def odd_position(lst):\n # Check every odd indexed element in the list for oddness.\n for i in range(len(lst)):\n if i % 2 != 0 and lst[i] % 2 == 0:\n return False\n\n return True", "matching_cluster_idx": 2}, {"solution": "def odd_position(input_list):\n \"\"\"\n Check if every odd index contains odd numbers.\n \"\"\"\n return all(num % 2 != 0 for i, num in enumerate(input_list) if i % 2 != 0)", "matching_cluster_idx": 2}, {"solution": "def odd_position(arr):\n # filter odd indices and store in a new list\n odd_indices = [arr[i] for i in range(len(arr)) if i % 2 != 0]\n\n # check whether every element of the new list is odd\n for i in odd_indices:\n if i % 2 == 0:\n return False\n return True", "matching_cluster_idx": 2}, {"solution": "def odd_position(input_list):\n for i in range(len(input_list)):\n if i % 2 != 0 and input_list[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 2}, {"solution": "def odd_position(input_list):\n # Start checking from index 1 with step 2\n for i in range(1, len(input_list), 2):\n if input_list[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n for i in range(len(lst)):\n # Skip even indices\n if i % 2 == 0:\n continue\n # Check if number on odd index is odd\n if lst[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 2}, {"solution": "def odd_position(lst):\n return all(v % 2 != 0 for i, v in enumerate(lst) if i % 2 != 0)", "matching_cluster_idx": 2}]}, "Mbpp/777": {"dps": null, "dps_norm": null, "pass@1": 8.0, "profiled": []}, "Mbpp/781": {"dps": 67.4015748031496, "dps_norm": 66.0, "pass@1": 91.0, "profiled": [{"solution": "def count_divisors(n):\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n if n / i == i:\n count += 1\n else:\n count += 2\n return count % 2 == 0", "matching_cluster_idx": 4}, {"solution": "def count_divisors(num):\n \"\"\"Return whether the count of divisors is even.\"\"\"\n count = 0\n for i in range(1, num + 1):\n if num % i == 0:\n count += 1\n return count % 2 == 0", "matching_cluster_idx": 1}, {"solution": "def count_divisors(n):\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n if n / i == i:\n count += 1\n else:\n count += 2\n return count % 2 == 0", "matching_cluster_idx": 4}, {"solution": "def count_divisors(num):\n \"\"\"\n Function that counts the number of divisors of an integer and checks whether the count is even\n \"\"\"\n divisors_count = 0\n for i in range(1, int(num**0.5) + 1):\n if num % i == 0:\n divisors_count += 1\n if num / i != i:\n divisors_count += 1\n return divisors_count % 2 == 0", "matching_cluster_idx": 4}, {"solution": "import math\ndef count_divisors(n):\n count = 0\n for i in range(1, int(math.sqrt(n)) + 1):\n if n % i == 0:\n if n / i == i:\n count += 1\n else:\n count += 2\n return count % 2 == 0", "matching_cluster_idx": 3}, {"solution": "def count_divisors(n):\n count = 0\n for i in range(1, int(n**0.5)+1):\n if n % i == 0:\n if n / i == i:\n count += 1\n else:\n count += 2\n return count % 2 == 0", "matching_cluster_idx": 3}, {"solution": "def count_divisors(n):\n \"\"\"\n This function takes an integer n and returns True if the count of its divisors is even, False otherwise.\n \"\"\"\n count = 0\n for i in range(1, int(n**0.5)+1):\n if n % i == 0:\n if n / i == i:\n count += 1\n else:\n count += 2\n return count % 2 == 0", "matching_cluster_idx": 4}, {"solution": "def count_divisors(n):\n count = 0\n for i in range(1, n+1):\n if n % i == 0:\n count += 1\n return count % 2 == 0", "matching_cluster_idx": 0}, {"solution": "def count_divisors(n):\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n if n / i == i:\n count += 1\n else:\n count += 2\n return count % 2 == 0", "matching_cluster_idx": 4}, {"solution": "def count_divisors(n):\n count = 0\n for i in range(1, int(n**0.5) + 1): # Loop up to the square root of n\n if n % i == 0: # If i is a divisor of n\n if n / i == i: # If divisors are equal\n count += 1\n else: # If divisors are different\n count += 2\n return count % 2 == 0 # Return True if count of divisors is even, False otherwise", "matching_cluster_idx": 4}, {"solution": "def count_divisors(n):\n count = 0\n i = 1\n while i * i <= n:\n if n % i == 0:\n if n / i == i:\n count += 1\n else:\n count += 2\n i += 1\n return count % 2 == 0", "matching_cluster_idx": 2}, {"solution": "def count_divisors(n):\n count = 0\n i = 1\n while i <= n :\n if (n % i == 0) :\n count += 1\n i += 1\n return count % 2 == 0", "matching_cluster_idx": 0}, {"solution": "def count_divisors(n):\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n if n / i == i:\n count += 1\n else:\n count += 2\n return count % 2 == 0", "matching_cluster_idx": 4}, {"solution": "def count_divisors(n):\n \"\"\"\n Return True if the count of divisors is even, False otherwise.\n \"\"\"\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n if n / i == i:\n count += 1\n else:\n count += 2\n return count % 2 == 0", "matching_cluster_idx": 3}, {"solution": "def count_divisors(num):\n count = 0\n for i in range(1, num + 1):\n if num % i == 0:\n count += 1\n return count % 2 == 0", "matching_cluster_idx": 0}, {"solution": "def count_divisors(n):\n \"\"\"\n Function to check whether the count of divisors is even.\n \"\"\"\n count = 0\n for i in range(1, int(n**0.5)+1):\n if n % i == 0:\n if n / i == i:\n count += 1\n else:\n count += 2\n return count % 2 == 0", "matching_cluster_idx": 3}, {"solution": "def count_divisors(n):\n count = 0\n i = 1\n while i <= n:\n if n % i == 0:\n count += 1\n i += 1\n return count % 2 == 0", "matching_cluster_idx": 0}, {"solution": "def count_divisors(n):\n \"\"\"\n This function counts the number of divisors of a number.\n \"\"\"\n count = 0\n for i in range(1, n+1):\n if n % i == 0:\n count += 1\n return count % 2 == 0", "matching_cluster_idx": 0}, {"solution": "def count_divisors(n):\n \"\"\"\n Counts the number of divisors for a number n.\n :param n: the number to check for number of divisors\n :returns: True if the count of divisors is even, else False\n \"\"\"\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n if n / i == i:\n count += 1\n else:\n count += 2\n return count % 2 == 0", "matching_cluster_idx": 3}, {"solution": "def count_divisors(num):\n \"\"\"\n This function counts the number of divisors of an integer\n and checks if the count is even or not.\n\n Arguments:\n num -- integer number to check its divisors\n\n Returns:\n True -- if the count of divisors is even\n False -- otherwise\n \"\"\"\n count = 0\n for i in range(1, num + 1):\n if num % i == 0:\n count += 1\n return count % 2 == 0", "matching_cluster_idx": 0}]}, "Mbpp/800": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def remove_all_spaces(string):\n \"\"\"Remove all whitespaces from a string.\"\"\"\n return string.replace(' ', '')", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(s):\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n \"\"\"\n Remove all whitespaces from a string.\n \"\"\"\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(s):\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(s):\n return s.replace(' ', '')", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n \"\"\"\n Function to remove all whitespaces from a string.\n \"\"\"\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(s):\n return s.replace(' ', '')", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(s):\n \"\"\"\n Remove all whitespaces from a string.\n \"\"\"\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_str):\n return input_str.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_str):\n return input_str.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n \"\"\"\n This function removes all white spaces from a string\n \"\"\"\n return input_string.replace(' ', '')", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(s):\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(s):\n return s.replace(' ', '')", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(s: str) -> str:\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n \"\"\"\n Function to remove all whitespaces from a string.\n \"\"\"\n return input_string.replace(' ', '')", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(string):\n return string.replace(' ', '')", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(s):\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}]}, "Mbpp/805": {"dps": 95.03436426116839, "dps_norm": 96.0, "pass@1": 92.0, "profiled": [{"solution": "def max_sum_list(list_of_lists):\n return max(list_of_lists, key=sum)", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lst):\n max_sum = -float('inf')\n max_list = []\n for sublist in lst:\n if sum(sublist) > max_sum:\n max_sum = sum(sublist)\n max_list = sublist\n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n \"\"\"\n Function that returns the list in a list of lists whose sum of elements is the highest.\n \"\"\"\n max_sum = sum(lists[0])\n max_list = lists[0]\n for l in lists:\n if sum(l) > max_sum:\n max_sum = sum(l)\n max_list = l\n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lst):\n \"\"\"\n Returns the list in a list of lists whose sum of elements is the highest.\n \"\"\"\n return max(lst, key=sum)", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(list_of_lists):\n return max(list_of_lists, key=sum)", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(list_of_lists):\n max_sum_index = max(range(len(list_of_lists)), key=lambda index: sum(list_of_lists[index]))\n return list_of_lists[max_sum_index]", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lst):\n \"\"\"\n Function to return the list in a list of lists whose sum of elements is the highest.\n \"\"\"\n return max(lst, key=sum)", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(list_of_lists):\n \"\"\"\n Function to find the list in a list of lists whose sum of elements is the highest.\n \"\"\"\n return max(list_of_lists, key=sum)", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lst_of_lst):\n return max(lst_of_lst, key=sum)", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(list_of_lists):\n return max(list_of_lists, key=sum)", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(list_of_lists):\n return max(list_of_lists, key=sum)", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(list_of_lists):\n \"\"\"Function to return the list with the highest sum of elements\"\"\"\n return max(list_of_lists, key=sum)", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lst):\n \"\"\"\n Returns the list in a list of lists whose sum of elements is the highest.\n \"\"\"\n max_sum = sum(lst[0])\n max_list = lst[0]\n\n for sublist in lst[1:]:\n if sum(sublist) > max_sum:\n max_sum = sum(sublist)\n max_list = sublist\n\n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lst):\n return max(lst, key=sum)", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(list_of_lists):\n return max(list_of_lists, key=sum)", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(list_of_lists):\n return max(list_of_lists, key=sum)", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lst):\n # Return None if list is empty\n if not lst: return None\n # The first sublist is assumed to have the highest sum initially\n max_sum_sublist = lst[0]\n max_sum = sum(max_sum_sublist)\n # Iterate through the rest of the list\n for sublist in lst[1:]:\n if sum(sublist) > max_sum:\n max_sum = sum(sublist)\n max_sum_sublist = sublist\n return max_sum_sublist", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n \"\"\"\n This function returns the list in a list of lists whose sum of elements is the highest.\n \"\"\"\n return max(lists, key=sum)", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lst):\n return max(lst, key=sum)", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(list_of_lists):\n if not all(isinstance(i, list) for i in list_of_lists):\n raise ValueError(\"Input should be a list of lists\")\n \n if not all(all(isinstance(j, (int, float)) for j in i) for i in list_of_lists):\n raise ValueError(\"Sub-lists should contain only integers or floats\")\n\n return max(list_of_lists, key=sum)", "matching_cluster_idx": 0}]}, "Mbpp/808": {"dps": 96.53508771929825, "dps_norm": 99.16666666666667, "pass@1": 98.0, "profiled": [{"solution": "def check_K(t, k):\n \"\"\"\n Function to check if the given tuple contains the k or not.\n \"\"\"\n return k in t\nt = (10, 4, 5, 6, 8)\nk = 6", "matching_cluster_idx": 5}, {"solution": "def check_K(numbers, k):\n \"\"\"\n Function to check if the given tuple contains the number 'k'\n \"\"\"\n # Check if tuple 'numbers' contains number 'k'\n if k in numbers:\n return True\n else:\n return False", "matching_cluster_idx": 4}, {"solution": "def check_K(t, k):\n \"\"\"\n Checks if given tuple contains the value k or not.\n \"\"\"\n return k in t", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n \"\"\"\n Function to check if the given tuple contains k or not.\n :param tup: The input tuple\n :param k: The key to be searched for\n :return: True if k is in the tuple, otherwise False\n \"\"\"\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(tpl, k):\n \"\"\"\n This function checks if the given tuple contains the element k or not.\n \"\"\"\n return k in tpl", "matching_cluster_idx": 5}, {"solution": "def check_K(tpl, k):\n \"\"\"\n Function to check if the given tuples contain the k or not.\n\n Parameters:\n tpl (tuple): Tuple to check for the element 'k'.\n k (int): The element to be checked in the tuple 'tpl'.\n\n Returns:\n bool: True if the 'k' is found in the tuple 'tpl', otherwise False.\n\n \"\"\"\n return k in tpl", "matching_cluster_idx": 5}, {"solution": "def check_K(t, k):\n return k in t", "matching_cluster_idx": 5}, {"solution": "def check_K(input_tuple, k):\n \"\"\"\n The function checks whether the given element k exists in the given tuple or not.\n \n Parameters:\n input_tuple (tuple): Input tuple to be searched.\n k: element to be searched in the tuple.\n\n Returns:\n bool: Return True if element k is found in the tuple, else False.\n \"\"\"\n return k in input_tuple", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n \"\"\"\n Function to check if the given tuples contain the k or not.\n \"\"\"\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n \"\"\"\n Check if a tuple contains a given number.\n\n :param tup: The tuple to check.\n :param k: The number to look for.\n :return: True if the tuple contains k, False otherwise.\n \"\"\"\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(tuple_input, k):\n \"\"\"\n Checks if the given tuples contain the k or not.\n \"\"\"\n return k in tuple_input", "matching_cluster_idx": 5}, {"solution": "def check_K(t, k):\n return k in t", "matching_cluster_idx": 5}, {"solution": "def check_K(t, k):\n \"\"\"\n This function checks whether a given tuple contains a specific number.\n\n Args:\n t (tuple): A tuple of numbers.\n k (int): The number to check for.\n\n Returns:\n bool: True if the number k is in the tuple t, False otherwise.\n \"\"\"\n return k in t", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n \"\"\"\n Function to check if the given tuple contains the k or not\n \"\"\"\n # Return True if k is in the tuple, else return False\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n \"\"\"\n This function checks whether the given k is present in the tuple or not.\n \"\"\"\n # The built-in Python function to check if an element is in the tuple\n if k in tup:\n return True\n else:\n return False", "matching_cluster_idx": 5}, {"solution": "def check_K(tuple, k):\n \"\"\"\n This function checks if the given tuple contains the given value k.\n \"\"\"\n return k in tuple", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n \"\"\"\n This function checks if the given tuple contains the number k or not.\n \"\"\"\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(tpl, k):\n return k in tpl", "matching_cluster_idx": 5}]}}} \ No newline at end of file diff --git a/results/evalperf/deepseek-ai--deepseek-coder-6.7b-instruct_vllm_temp_1.0_evalperf_results.brief.json b/results/evalperf/deepseek-ai--deepseek-coder-6.7b-instruct_vllm_temp_1.0_evalperf_results.brief.json new file mode 100644 index 0000000..71cc71d --- /dev/null +++ b/results/evalperf/deepseek-ai--deepseek-coder-6.7b-instruct_vllm_temp_1.0_evalperf_results.brief.json @@ -0,0 +1 @@ +{"date": "2024-10-19 16:28", "config": {"n_samples": 100, "temperature": 1.0, "min_correct": 10, "max_profile": 20}, "summary": {"dps": 83.55516548026816, "dps_norm": 78.20569308671841, "pass@1": 73.57627118644068}, "eval": {"HumanEval/9": {"dps": 72.98107255520505, "dps_norm": 68.33333333333333, "pass@1": 78.0, "profiled": [{"solution": "from typing import List, Tuple\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n \"\"\"\n if not numbers:\n return []\n\n max_numbers = [numbers[0]]\n for i in range(1, len(numbers)):\n max_numbers.append(max(max_numbers[-1], numbers[i]))\n \n return max_numbers", "matching_cluster_idx": 4}, {"solution": "from typing import List, Tuple\ndef rolling_max(numbers: List[int]) -> List[int]:\n if len(numbers) == 0:\n return []\n \n max_numbers = [numbers[0]]\n for i in range(1, len(numbers)):\n max_numbers.append(max(numbers[i], max_numbers[i-1]))\n\n return max_numbers", "matching_cluster_idx": 4}, {"solution": "from typing import List, Tuple\ndef rolling_max(numbers: List[int]) -> List[int]:\n if not numbers:\n return []\n \n max_numbers = [numbers[0]] \n for i in range(1, len(numbers)):\n max_numbers.append(max(max_numbers[-1], numbers[i]))\n return max_numbers", "matching_cluster_idx": 4}, {"solution": "from typing import List, Tuple\ndef rolling_max(numbers: List[int]) -> List[int]:\n if not numbers:\n return []\n result = [numbers[0]]\n for i in range(1, len(numbers)):\n result.append(max(result[-1], numbers[i]))\n return result", "matching_cluster_idx": 4}, {"solution": "from typing import List, Tuple\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n\n rolling_max_list = [numbers[0]]\n for num in numbers[1:]:\n rolling_max_list.append(max(rolling_max_list[-1], num))\n\n return rolling_max_list", "matching_cluster_idx": 4}, {"solution": "from typing import List, Tuple\ndef rolling_max(numbers: List[int]) -> List[int]:\n if not numbers:\n return []\n\n max_values = [numbers[0]]\n current_max = numbers[0]\n\n for num in numbers[1:]:\n current_max = max(current_max, num)\n max_values.append(current_max)\n\n return max_values", "matching_cluster_idx": 4}, {"solution": "from typing import List, Tuple\ndef rolling_max(numbers: List[int]) -> List[int]:\n if not numbers:\n return []\n rolling_max_list = [numbers[0]]\n for i in range(1, len(numbers)):\n rolling_max_list.append(max(rolling_max_list[-1], numbers[i]))\n return rolling_max_list", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n if not numbers:\n return []\n\n max_so_far = numbers[0]\n result = [max_so_far]\n\n for num in numbers[1:]:\n if num > max_so_far:\n max_so_far = num\n result.append(max_so_far)\n\n return result", "matching_cluster_idx": 8}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n # Initialize an empty list to store the rolling maximums\n rolling_maxes = []\n \n # Initialize the maximum to None\n max_number = None\n\n # Loop over the numbers in the input list\n for number in numbers:\n # If the maximum is None (or if the current number is greater than the maximum),\n # update the maximum\n if max_number is None or number > max_number:\n max_number = number\n \n # Append the current maximum to the list of rolling maximums\n rolling_maxes.append(max_number)\n \n return rolling_maxes", "matching_cluster_idx": 7}, {"solution": "from typing import List, Tuple\ndef rolling_max(numbers: List[int]) -> List[int]:\n if not numbers:\n return []\n \n res = [numbers[0]]\n max_val = numbers[0]\n \n for num in numbers[1:]:\n if num > max_val:\n max_val = num\n res.append(max_val)\n \n return res", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef rolling_max(numbers: List[int]) -> List[int]:\n if not numbers:\n return []\n max_list = [numbers[0]]\n for i in range(1, len(numbers)):\n max_list.append(max(max_list[-1], numbers[i]))\n return max_list", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n if not numbers:\n return []\n \n rolling_max_values = [numbers[0]]\n for i in range(1, len(numbers)):\n rolling_max_values.append(max(numbers[i], rolling_max_values[-1]))\n return rolling_max_values", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\"\n From a given list of integers, generate a list of rolling maximum \n element found until given moment in the sequence.\n \"\"\"\n if not numbers: \n return []\n \n result = [numbers[0]]\n for num in numbers[1:]:\n result.append(max(result[-1], num))\n\n return result", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n if not numbers:\n return []\n max_list = [numbers[0]]\n for i in range(1, len(numbers)):\n max_list.append(max(max_list[i-1], numbers[i]))\n return max_list", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n max_nums = []\n max_num = float('-inf')\n\n for num in numbers:\n max_num = max(max_num, num)\n max_nums.append(max_num)\n\n return max_nums", "matching_cluster_idx": 4}, {"solution": "from typing import List, Tuple\ndef rolling_max(numbers: List[int]) -> List[int]:\n if not numbers:\n return []\n\n max_num = numbers[0]\n result = [max_num]\n\n for num in numbers[1:]:\n if num > max_num:\n max_num = num\n result.append(max_num)\n\n return result", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n\n max_nums = [numbers[0]]\n for num in numbers[1:]:\n max_nums.append(max(num, max_nums[-1]))\n\n return max_nums", "matching_cluster_idx": 4}, {"solution": "from typing import List, Tuple\ndef rolling_max(numbers: List[int]) -> List[int]:\n max_numbers = []\n current_max = numbers[0] if numbers else None\n for num in numbers:\n if num > current_max:\n current_max = num\n max_numbers.append(current_max)\n return max_numbers", "matching_cluster_idx": 8}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n if not numbers:\n return []\n res = [numbers[0]]\n for num in numbers[1:]:\n res.append(max(res[-1], num))\n return res", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n \"\"\"\n if not numbers:\n return []\n\n rolling_max_list = [numbers[0]]\n current_max = numbers[0]\n for num in numbers[1:]:\n if num > current_max:\n current_max = num\n rolling_max_list.append(current_max)\n return rolling_max_list", "matching_cluster_idx": 8}]}, "HumanEval/0": {"dps": 62.67441860465116, "dps_norm": 68.57142857142857, "pass@1": 96.0, "profiled": [{"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" \n Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n for i in range(len(numbers)):\n for j in range(i+1, len(numbers)):\n if abs(numbers[i] - numbers[j]) < threshold:\n return True\n return False", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n for i in range(len(numbers)):\n for j in range(i+1, len(numbers)):\n if abs(numbers[i] - numbers[j]) < threshold:\n return True\n return False", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n \"\"\"\n numbers.sort() # Sorting the list of numbers\n for i in range(1, len(numbers)): # Iterating over the list from 2nd position to the end\n if abs(numbers[i] - numbers[i - 1]) < threshold: # If the difference between current number and previous number is smaller than threshold, return True\n return True\n return False # If no such pair found, return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\nimport math\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n for i in range(len(numbers)):\n for j in range(i+1, len(numbers)):\n if math.fabs(numbers[i] - numbers[j]) < threshold:\n return True\n return False", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n for i in range(len(numbers)):\n for j in range(i+1, len(numbers)):\n if abs(numbers[i] - numbers[j]) < threshold:\n return True\n return False", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n \"\"\"\n numbers.sort()\n for i in range(len(numbers)-1):\n if abs(numbers[i] - numbers[i+1]) < threshold:\n return True\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n numbers.sort()\n\n for i in range(1, len(numbers)):\n if abs(numbers[i] - numbers[i - 1]) < threshold:\n return True\n\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n \"\"\"\n sorted_nums = sorted(numbers)\n for i in range(len(sorted_nums) - 1):\n if abs(sorted_nums[i] - sorted_nums[i + 1]) < threshold:\n return True\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n numbers = sorted(numbers)\n for i in range(1, len(numbers)):\n if abs(numbers[i] - numbers[i-1]) < threshold:\n return True\n return False", "matching_cluster_idx": 2}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n numbers.sort()\n for i in range(1, len(numbers)):\n if numbers[i] - numbers[i-1] < threshold:\n return True\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" \n Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n \"\"\"\n numbers.sort()\n for i in range(1, len(numbers)):\n if numbers[i] - numbers[i-1] < threshold:\n return True\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\"\n Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n numbers = sorted(numbers)\n for i in range(len(numbers) - 1):\n if numbers[i+1] - numbers[i] < threshold:\n return True\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n \"\"\"\n # Sort the list\n numbers.sort()\n # Loop through the list comparing each element to its next one\n for i in range(len(numbers) - 1):\n if abs(numbers[i] - numbers[i + 1]) < threshold:\n # If the difference is smaller than the threshold, return True\n return True\n # If no close elements are found, return False\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n \"\"\"\n numbers.sort()\n for i in range(1, len(numbers)):\n if numbers[i] - numbers[i - 1] < threshold:\n return True\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" \n Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n for i in range(len(numbers) - 1):\n for j in range(i+1, len(numbers)):\n if abs(numbers[i] - numbers[j]) < threshold:\n return True\n return False", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\"\n Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n \"\"\"\n for i in range(len(numbers) - 1):\n for j in range(i + 1, len(numbers)):\n if abs(numbers[i] - numbers[j]) < threshold:\n return True\n return False", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\"\n Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n sorted_numbers = sorted(numbers)\n for i in range(1, len(sorted_numbers)):\n if abs(sorted_numbers[i] - sorted_numbers[i - 1]) < threshold:\n return True\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\"\n Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n numbers.sort()\n for i in range(1, len(numbers)):\n if numbers[i] - numbers[i - 1] < threshold:\n return True\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n numbers.sort()\n for i in range(1, len(numbers)):\n if numbers[i] - numbers[i - 1] < threshold:\n return True\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n \"\"\"\n numbers.sort()\n for i in range(1, len(numbers)):\n if numbers[i] - numbers[i - 1] < threshold:\n return True\n return False", "matching_cluster_idx": 3}]}, "HumanEval/4": {"dps": 77.23101265822785, "dps_norm": 82.5, "pass@1": 97.0, "profiled": [{"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\"\n For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n mean = sum(numbers) / len(numbers)\n deviations = [abs(x - mean) for x in numbers]\n mad = sum(deviations) / len(deviations)\n return mad", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\"\n For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n \"\"\"\n mean = sum(numbers) / len(numbers)\n abs_diff = [abs(x - mean) for x in numbers]\n mad = sum(abs_diff) / len(abs_diff)\n return mad", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n mean = sum(numbers) / len(numbers)\n differences = [abs(number - mean) for number in numbers]\n mad = sum(differences) / len(differences)\n return mad", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n mean = sum(numbers) / len(numbers)\n mad = sum(abs(num - mean) for num in numbers) / len(numbers)\n return mad", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n mean = sum(numbers) / len(numbers)\n abs_diffs = [abs(x - mean) for x in numbers]\n mad = sum(abs_diffs) / len(abs_diffs)\n return mad", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\"\n For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n\n MAD = average | x - x_mean |\n\n Examples:\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n >>> mean_absolute_deviation([5.0, 10.0, 10.0, 10.0, 15.0])\n 3.0\n >>> mean_absolute_deviation([-1.0, -1.0, -1.0, 1.0, 1.0])\n 0.6666666666666666\n \"\"\"\n mean = sum(numbers) / len(numbers)\n return sum(abs(x - mean) for x in numbers) / len(numbers)", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n mean = sum(numbers) / len(numbers)\n abs_diffs = [abs(num - mean) for num in numbers]\n mad = sum(abs_diffs) / len(abs_diffs)\n return mad", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n \"\"\"\n mean = sum(numbers) / len(numbers)\n abs_diffs = [abs(num - mean) for num in numbers]\n mad = sum(abs_diffs) / len(abs_diffs)\n return mad", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n \"\"\"\n mean = sum(numbers) / len(numbers)\n return sum(abs(num - mean) for num in numbers) / len(numbers)", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n mean = sum(numbers) / len(numbers)\n deviations = [abs(x - mean) for x in numbers]\n mad = sum(deviations) / len(deviations)\n return mad", "matching_cluster_idx": 4}, {"solution": "from typing import List\nimport statistics\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n mean = statistics.mean(numbers)\n mad = sum(abs(x - mean) for x in numbers) / len(numbers)\n return mad", "matching_cluster_idx": 0}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n mean = sum(numbers) / len(numbers)\n abs_diffs = [abs(x - mean) for x in numbers]\n mad = sum(abs_diffs) / len(abs_diffs)\n return mad", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n mean = sum(numbers) / len(numbers)\n abs_diffs = [abs(x - mean) for x in numbers]\n mad = sum(abs_diffs) / len(abs_diffs)\n return mad", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n \"\"\"\n if len(numbers) == 0:\n raise ValueError(\"Input list should not be empty.\")\n mean = sum(numbers) / len(numbers)\n deviations = [abs(n - mean) for n in numbers]\n mad = sum(deviations) / len(deviations)\n return mad", "matching_cluster_idx": 4}, {"solution": "from typing import List\nimport statistics\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n mean_val = statistics.mean(numbers)\n mad_val = sum(abs(num - mean_val) for num in numbers) / len(numbers)\n return mad_val", "matching_cluster_idx": 0}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n \"\"\"\n mean = sum(numbers) / len(numbers)\n return sum(abs(num - mean) for num in numbers) / len(numbers)", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n\n mean = sum(numbers) / len(numbers)\n return sum(abs(n - mean) for n in numbers) / len(numbers)\nnumbers = [1.0, 2.0, 3.0, 4.0]", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" \n For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n mean = sum(numbers) / len(numbers)\n mad = sum(abs(n - mean) for n in numbers) / len(numbers)\n return mad", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\"\n For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n \"\"\"\n mean = sum(numbers) / len(numbers)\n return sum(abs(x - mean) for x in numbers) / len(numbers)", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n mean = sum(numbers) / len(numbers)\n absolute_deviation = [abs(number - mean) for number in numbers]\n mad = sum(absolute_deviation) / len(absolute_deviation)\n\n return mad", "matching_cluster_idx": 4}]}, "HumanEval/16": {"dps": 92.55813953488372, "dps_norm": 93.88888888888889, "pass@1": 72.0, "profiled": [{"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\"\n Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n return len(set(string.lower()))", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n \"\"\"\n distinct_chars = set(string.lower())\n return len(distinct_chars)", "matching_cluster_idx": 8}, {"solution": "import doctest\ndef count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n return len(set(string.lower()))", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n return len(set(string.lower()))", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of \"\"\"\n return len(set(string.lower()))", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Converting the input string to lowercase and converting it to a set to remove duplicates.\n # Then, returning the length of the set.\n return len(set(string.lower()))", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n \"\"\"\n distinct_characters = set(string.lower())\n return len(distinct_characters)", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\"\n Given a string, find out how many distinct characters (regardless of case) does it consist of.\n \"\"\"\n distinct_characters = set()\n for char in string:\n distinct_characters.add(char.lower())\n\n return len(distinct_characters)", "matching_cluster_idx": 2}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n return len(set(string.lower()))", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n return len(set(string.lower()))", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n return len(set(string.lower()))", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n # convert the string to lower case to ignore case sensitivity\n string = string.lower()\n # use a set to get distinct characters in the string\n distinct_characters = set(string)\n # return the length of the set (the number of distinct characters)\n return len(distinct_characters)", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n return len(set(string.lower()))", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n distinct_characters = set()\n for char in string.lower():\n distinct_characters.add(char)\n return len(distinct_characters)", "matching_cluster_idx": 3}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of \"\"\"\n # convert all letters to lower case to handle case-insensitive distinct characters\n lower_string = string.lower()\n # convert the string to a set, which removes duplicate letters\n distinct_letters = set(lower_string)\n # count the number of letters in the set, these are the distinct characters\n num_distinct_characters = len(distinct_letters)\n return num_distinct_characters", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n \"\"\"\n return len(set(string.lower()))", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n distinct_chars = set(string.lower())\n return len(distinct_chars)", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lower case and then convert it to a set to get distinct characters.\n # Finally, get the length of the set to get the number of distinct characters.\n return len(set(string.lower()))", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of \"\"\"\n return len(set(string.lower()))", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n return len(set(string.lower()))", "matching_cluster_idx": 8}]}, "HumanEval/20": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\"\n From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n \"\"\"\n numbers = sorted(numbers)\n min_diff = float('inf')\n result = (0, 0)\n for i in range(1, len(numbers)):\n diff = numbers[i] - numbers[i - 1]\n if diff < min_diff:\n min_diff = diff\n result = (numbers[i - 1], numbers[i])\n return result", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n if len(numbers) < 2:\n raise ValueError(\"Input list must have at least two elements\")\n\n min_diff = float('inf')\n result = (0, 0)\n \n sorted_numbers = sorted(numbers)\n for i in range(len(sorted_numbers) - 1):\n diff = sorted_numbers[i + 1] - sorted_numbers[i]\n if diff < min_diff:\n min_diff = diff\n result = (sorted_numbers[i], sorted_numbers[i + 1])\n \n return result", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n numbers.sort()\n min_diff = float('inf')\n result = ()\n for i in range(1, len(numbers)):\n diff = numbers[i] - numbers[i - 1]\n if diff < min_diff:\n min_diff = diff\n result = (numbers[i - 1], numbers[i])\n return result", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n numbers.sort()\n min_diff = float('inf')\n result = (None, None)\n for i in range(len(numbers)-1):\n diff = numbers[i+1] - numbers[i]\n if diff < min_diff:\n min_diff = diff\n result = (numbers[i], numbers[i+1])\n return result", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n numbers.sort()\n min_difference = float('inf')\n result = ()\n for i in range(1, len(numbers)):\n difference = numbers[i] - numbers[i - 1]\n if difference < min_difference:\n min_difference = difference\n result = (numbers[i - 1], numbers[i])\n return result", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n if len(numbers) < 2:\n raise ValueError(\"List of numbers must contain at least two elements\")\n \n numbers.sort()\n min_diff = float('inf')\n result = ()\n \n for i in range(1, len(numbers)):\n diff = numbers[i] - numbers[i-1]\n if diff < min_diff:\n min_diff = diff\n result = (numbers[i-1], numbers[i])\n \n return result", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\"\n From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n \"\"\"\n numbers.sort()\n smallest_difference = float('inf')\n result = (None, None)\n for i in range(len(numbers) - 1):\n difference = numbers[i+1] - numbers[i]\n if difference < smallest_difference:\n smallest_difference = difference\n result = (numbers[i], numbers[i+1])\n return result", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" \n From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n \n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n assert len(numbers) >= 2, \"List must contain at least two numbers\"\n \n numbers.sort()\n smallest_diff = float('inf')\n result = ()\n\n for i in range(1, len(numbers)):\n diff = numbers[i] - numbers[i - 1]\n if diff < smallest_diff:\n smallest_diff = diff\n result = (numbers[i - 1], numbers[i])\n \n return result", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n \"\"\"\n if len(numbers) < 2:\n raise ValueError(\"Input list must contain at least two elements\")\n\n numbers.sort()\n min_diff = numbers[1] - numbers[0]\n result = (numbers[0], numbers[1])\n\n for i in range(len(numbers) - 1):\n diff = numbers[i+1] - numbers[i]\n if diff < min_diff:\n min_diff = diff\n result = (numbers[i], numbers[i+1])\n\n return result", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\"\n From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n \"\"\"\n numbers.sort()\n min_diff = float('inf')\n result = ()\n for i in range(1, len(numbers)):\n diff = numbers[i] - numbers[i - 1]\n if diff < min_diff:\n min_diff = diff\n result = (numbers[i - 1], numbers[i])\n return result", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n \"\"\"\n numbers.sort()\n min_diff = float('inf')\n closest_pair = (0, 0)\n for i in range(1, len(numbers)):\n diff = numbers[i] - numbers[i-1]\n if diff < min_diff:\n min_diff = diff\n closest_pair = (numbers[i-1], numbers[i])\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\"\n From a supplied list of numbers (of length at least two) select and return two that are the closest to each other\n and return them in order (smaller number, larger number).\n \"\"\"\n if len(numbers) < 2:\n raise ValueError('Input list must have at least two elements')\n \n numbers.sort()\n min_diff = numbers[1] - numbers[0]\n result = (numbers[0], numbers[1])\n \n for i in range(2, len(numbers)):\n diff = numbers[i] - numbers[i-1]\n if diff < min_diff:\n min_diff = diff\n result = (numbers[i-1], numbers[i])\n \n return result", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n \"\"\"\n numbers.sort() # sort the list in ascending order\n min_diff = float('inf') # initialize minimum difference as infinity\n result = (0.0, 0.0) # initialize result as two zeros\n for i in range(1, len(numbers)):\n # calculate the difference between the current pair and the previous minimum difference\n diff = numbers[i] - numbers[i - 1]\n if diff < min_diff:\n # if the difference is smaller, update the minimum difference and the result\n min_diff = diff\n result = (numbers[i - 1], numbers[i])\n return result", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n assert len(numbers) >= 2, \"Input list must have at least two numbers\"\n\n numbers.sort()\n\n min_diff = float('inf')\n closest_pair = (0.0, 0.0)\n\n for i in range(len(numbers) - 1):\n diff = numbers[i+1] - numbers[i]\n if diff < min_diff:\n min_diff = diff\n closest_pair = (numbers[i], numbers[i+1])\n\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n \"\"\"\n # Sort the list in ascending order\n numbers.sort()\n\n # Initialize variables to keep track of the smallest difference and the closest pair\n smallest_difference = float('inf')\n closest_pair = (None, None)\n\n # Loop over the list to find the closest pair\n for i in range(1, len(numbers)):\n difference = numbers[i] - numbers[i - 1]\n if difference < smallest_difference:\n smallest_difference = difference\n closest_pair = (numbers[i - 1], numbers[i])\n\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n numbers.sort()\n min_diff = float('inf')\n result = (0, 0)\n for i in range(1, len(numbers)):\n diff = numbers[i] - numbers[i-1]\n if diff < min_diff:\n min_diff = diff\n result = (numbers[i-1], numbers[i])\n return result", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n \"\"\"\n sorted_numbers = sorted(numbers)\n min_diff = float('inf')\n result = (0, 0)\n for i in range(1, len(sorted_numbers)):\n diff = sorted_numbers[i] - sorted_numbers[i - 1]\n if diff < min_diff:\n min_diff = diff\n result = (sorted_numbers[i - 1], sorted_numbers[i])\n return result", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n numbers.sort()\n min_diff = float('inf')\n result = (None, None)\n for i in range(1, len(numbers)):\n diff = numbers[i] - numbers[i - 1]\n if diff < min_diff:\n min_diff = diff\n result = (numbers[i - 1], numbers[i])\n return result", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n numbers.sort()\n min_diff = float('inf')\n result = ()\n for i in range(1, len(numbers)):\n diff = numbers[i] - numbers[i - 1]\n if diff < min_diff:\n min_diff = diff\n result = (numbers[i - 1], numbers[i])\n return result", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n \"\"\"\n if len(numbers) < 2:\n raise ValueError(\"Input list must have at least two numbers.\")\n \n numbers.sort()\n min_diff = float('inf')\n closest_pair = (0.0, 0.0)\n for i in range(1, len(numbers)):\n diff = numbers[i] - numbers[i-1]\n if diff < min_diff:\n min_diff = diff\n closest_pair = (numbers[i-1], numbers[i])\n return closest_pair", "matching_cluster_idx": 8}]}, "HumanEval/24": {"dps": 54.25170068027211, "dps_norm": 20.625, "pass@1": 100.0, "profiled": [{"solution": "def largest_divisor(n: int) -> int:\n \"\"\" \n For a given number n, find the largest number that divides n evenly, smaller than n.\n >>> largest_divisor(15)\n 5\n \"\"\"\n for i in range(n-1, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 1}, {"solution": "def largest_divisor(n: int) -> int:\n for i in range(n-1, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 1}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n for i in range(n-1, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 1}, {"solution": "def largest_divisor(n: int) -> int:\n i = n - 1\n while i > 0:\n if n % i == 0:\n return i\n i -= 1", "matching_cluster_idx": 0}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" \n For a given number n, find the largest number that divides n evenly, \n smaller than n\n\n >>> largest_divisor(15)\n 5\n \"\"\"\n # Initialize the divisor to the largest possible\n largest_divisor = n - 1\n\n # Starting from the largest possible divisor, decrement until a divisor is found\n while n % largest_divisor != 0:\n largest_divisor -= 1\n\n return largest_divisor", "matching_cluster_idx": 0}, {"solution": "import doctest\ndef largest_divisor(n: int) -> int:\n \"\"\"\n For a given number n, find the largest number that divides n evenly, smaller than n\n\n >>> largest_divisor(15)\n 5\n \"\"\"\n if n < 2:\n return None\n for i in range(n-1, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 0}, {"solution": "def largest_divisor(n: int) -> int:\n for i in range(n-1, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 1}, {"solution": "def largest_divisor(n: int) -> int:\n i = n - 1\n while i > 0:\n if n % i == 0:\n return i\n i -= 1\n return None", "matching_cluster_idx": 0}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" \n For a given number n, find the largest number that divides n evenly, smaller than n\n \"\"\"\n if n <= 1:\n return None\n for i in range(n - 1, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 1}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n i = n - 1\n while i > 0:\n if n % i == 0:\n return i\n i -= 1", "matching_cluster_idx": 0}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n for i in range(n - 1, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 1}, {"solution": "def largest_divisor(n: int) -> int:\n if n <= 1:\n raise ValueError(\"Number must be greater than 1\")\n for i in range(n-1, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 1}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n for i in range(n-1, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 1}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n for i in range(n-1, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 1}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n # If the number is less than or equal to 1, it does not have a proper divisor\n if n <= 1:\n return None\n \n # Start from the number itself and decrease until you find a divisor\n for i in range(n - 1, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 0}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n \"\"\"\n for i in range(n-1, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 1}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" \n For a given number n, find the largest number that divides n evenly, smaller than n.\n >>> largest_divisor(15)\n 5\n \"\"\"\n if n < 2:\n return None\n for i in range(n - 1, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 1}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\"\n For a given number n, find the largest number that divides n evenly, smaller than n\n \n >>> largest_divisor(15)\n 5\n >>> largest_divisor(30)\n 15\n \"\"\"\n for i in range(n - 1, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 0}, {"solution": "def largest_divisor(n: int) -> int:\n for i in range(n-1, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 1}, {"solution": "def largest_divisor(n: int) -> int:\n for i in range(n-1, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 1}]}, "HumanEval/26": {"dps": 89.0, "dps_norm": 93.75, "pass@1": 21.0, "profiled": [{"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n count_dict = {}\n for num in numbers:\n if num in count_dict:\n count_dict[num] += 1\n else:\n count_dict[num] = 1\n \n non_duplicates = [key for key, value in count_dict.items() if value == 1]\n return non_duplicates", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n counts = dict()\n result = []\n for num in numbers:\n if num in counts:\n counts[num] += 1\n else:\n counts[num] = 1\n\n for num in numbers:\n if counts[num] == 1:\n result.append(num)\n return result", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n count_dict = {}\n for num in numbers:\n if num in count_dict:\n count_dict[num] += 1\n else:\n count_dict[num] = 1\n unique_nums = [num for num, count in count_dict.items() if count == 1]\n return unique_nums", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n counts = dict()\n result = []\n for num in numbers:\n if num in counts:\n counts[num] += 1\n else:\n counts[num] = 1\n \n for num in numbers:\n if counts[num] == 1:\n result.append(num)\n counts[num] -= 1\n \n return result", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n count = {}\n result = []\n\n for num in numbers:\n if num in count:\n count[num] += 1\n else:\n count[num] = 1\n\n for num in numbers:\n if count[num] == 1:\n result.append(num)\n return result", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n count_dict = {}\n result = []\n for num in numbers:\n if num in count_dict:\n count_dict[num] += 1\n else:\n count_dict[num] = 1\n for num in numbers:\n if count_dict[num] == 1:\n result.append(num)\n count_dict[num] -= 1\n return result", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n counts = {}\n for num in numbers:\n if num not in counts:\n counts[num] = 1\n else:\n counts[num] += 1\n\n return [num for num in counts if counts[num] == 1]", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n no_duplicates = []\n counts = {}\n for num in numbers:\n if num in counts:\n counts[num] += 1\n else:\n counts[num] = 1\n for num in numbers:\n if counts[num] == 1:\n no_duplicates.append(num)\n return no_duplicates", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n count_dict = {}\n for num in numbers:\n count_dict[num] = count_dict.get(num, 0) + 1\n return [num for num in numbers if count_dict[num] == 1]", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n unique_numbers = []\n count_dict = {}\n \n for num in numbers:\n if num in count_dict:\n count_dict[num] += 1\n else:\n count_dict[num] = 1\n \n for num in numbers:\n if count_dict[num] == 1:\n unique_numbers.append(num)\n \n return unique_numbers", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n result = []\n for number in numbers:\n if numbers.count(number) == 1:\n result.append(number)\n return result", "matching_cluster_idx": 0}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n counts = {}\n for num in numbers:\n counts[num] = counts.get(num, 0) + 1\n return [num for num in numbers if counts[num] == 1]", "matching_cluster_idx": 3}, {"solution": "from typing import List\nfrom collections import Counter\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n \"\"\"\n counts = Counter(numbers)\n return [num for num in numbers if counts[num] == 1]", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n count_dict = {}\n output = []\n for num in numbers:\n if num in count_dict:\n count_dict[num] += 1\n else:\n count_dict[num] = 1\n for num in numbers:\n if count_dict[num] == 1:\n output.append(num)\n count_dict[num] -= 1\n return output", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n count_map = {}\n result = []\n for num in numbers:\n if num in count_map:\n count_map[num] += 1\n else:\n count_map[num] = 1\n\n for num in numbers:\n if count_map[num] == 1:\n result.append(num)\n count_map[num] -= 1\n\n return result", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n count_map = {}\n res = []\n for num in numbers:\n if num in count_map:\n count_map[num] += 1\n else:\n count_map[num] = 1\n for num in numbers:\n if count_map[num] == 1:\n res.append(num)\n count_map[num] -= 1\n return res", "matching_cluster_idx": 3}, {"solution": "from typing import List\nfrom collections import defaultdict\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n number_counts = defaultdict(int)\n output_numbers = []\n\n for number in numbers:\n number_counts[number] += 1\n\n for number in numbers:\n if number_counts[number] == 1:\n output_numbers.append(number)\n\n return output_numbers", "matching_cluster_idx": 2}, {"solution": "from typing import List\nfrom collections import Counter\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n count_map = Counter(numbers)\n non_duplicate_nums = [num for num, count in count_map.items() if count == 1]\n return non_duplicate_nums", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n count_dict = {}\n for num in numbers:\n if num in count_dict:\n count_dict[num] += 1\n else:\n count_dict[num] = 1\n\n result = [num for num in count_dict if count_dict[num] == 1]\n return result", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\"\n From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n \"\"\"\n result = []\n counts = {}\n\n for num in numbers:\n if num not in counts:\n counts[num] = 0\n counts[num] += 1\n\n for num in numbers:\n if counts[num] == 1:\n result.append(num)\n\n return result", "matching_cluster_idx": 2}]}, "HumanEval/31": {"dps": 64.68354430379748, "dps_norm": 78.75, "pass@1": 94.0, "profiled": [{"solution": "def is_prime(n):\n if n < 2:\n return False\n for i in range(2, int(n ** 0.5) + 1):\n if n % i == 0:\n return False\n return True", "matching_cluster_idx": 5}, {"solution": "def is_prime(n):\n if n <= 1:\n return False\n elif n <= 3:\n return True\n elif n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n if n <= 1:\n return False\n elif n <= 3:\n return True\n elif n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i = i + 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"\n Return True if a given number is prime, and False otherwise.\n \"\"\"\n if n <= 1:\n return False\n elif n <= 3:\n return True\n elif n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n if n < 2:\n return False\n if n == 2 or n == 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n w = 2\n while i * i <= n:\n if n % i == 0:\n return False\n i += w\n w = 6 - w\n return True", "matching_cluster_idx": 5}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\"\"\"\n if n <= 1:\n return False\n elif n <= 3:\n return True\n elif n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n if n < 2:\n return False\n for i in range(2, int(n ** 0.5) + 1):\n if n % i == 0:\n return False\n return True", "matching_cluster_idx": 5}, {"solution": "def is_prime(n):\n if n < 2:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True", "matching_cluster_idx": 5}, {"solution": "import doctest\ndef is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n False\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n < 2:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True", "matching_cluster_idx": 5}, {"solution": "def is_prime(n):\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 5}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\"\"\"\n if n < 2:\n return False\n for i in range(2, int(n ** 0.5) + 1):\n if n % i == 0:\n return False\n return True", "matching_cluster_idx": 5}, {"solution": "def is_prime(n):\n if n < 2:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True", "matching_cluster_idx": 5}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n if n < 2:\n return False\n for i in range(2, int(n**0.5)+1):\n if n % i == 0:\n return False\n return True", "matching_cluster_idx": 5}, {"solution": "def is_prime(n):\n if n < 2:\n return False\n if n == 2:\n return True\n if n % 2 == 0:\n return False\n for i in range(3, int(n**0.5) + 1, 2):\n if n % i == 0:\n return False\n return True", "matching_cluster_idx": 5}, {"solution": "def is_prime(n):\n if n < 2: # 0 and 1 are not prime numbers\n return False\n if n == 2: # 2 is a prime number\n return True\n if n % 2 == 0: # all other even numbers are not prime\n return False\n for current in range(3, int(n ** 0.5) + 1, 2):\n if n % current == 0: \n return False\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"\n Return true if a given number is prime, and false otherwise.\n \"\"\"\n # 0 and 1 are not prime numbers\n if n < 2:\n return False\n\n # 2 is the only even prime number\n if n == 2: \n return True\n \n # all other even numbers are not primes\n if n % 2 == 0: \n return False\n\n # range starts with 3 and only needs to go up \n # the square root of n for all odd numbers\n for x in range(3, int(n**0.5) + 1, 2):\n if n % x == 0:\n return False\n return True", "matching_cluster_idx": 5}, {"solution": "import doctest\ndef is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n False\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n < 2:\n return False\n if n == 2:\n return True\n if n % 2 == 0:\n return False\n i = 3\n while i * i <= n:\n if n % i == 0:\n return False\n i += 2\n return True", "matching_cluster_idx": 5}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\"\"\"\n if n < 2:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True", "matching_cluster_idx": 5}, {"solution": "def is_prime(n):\n \"\"\"\n Return true if a given number is prime, and false otherwise.\n \"\"\"\n if n < 2:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True", "matching_cluster_idx": 5}]}, "HumanEval/33": {"dps": 69.5138888888889, "dps_norm": 76.36363636363636, "pass@1": 41.0, "profiled": [{"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n \n Example:\n \n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n # Create list of elements with indices divisible by three\n l_div_by_three = [l[i] for i in range(len(l)) if i % 3 == 0]\n \n # Sort list with elements at indices divisible by three\n l_div_by_three.sort()\n\n # Create new list based on original one with sorted values at indices divisible by three\n l_prime = [l_div_by_three[i // 3] if i % 3 == 0 else l[i] for i in range(len(l))]\n\n return l_prime", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n # Save values at the positions divisible by 3\n divisible_by_three_values = [l[i] for i in range(len(l)) if i % 3 == 0]\n \n # Sort these values\n divisible_by_three_values.sort()\n \n # Create an output list with same length as the input\n l_prime = [None]*len(l)\n \n # Put the sorted values in the places divisible by 3 in the output list\n for i in range(len(l)):\n if i % 3 == 0:\n l_prime[i] = divisible_by_three_values.pop(0)\n else:\n l_prime[i] = l[i]\n \n return l_prime", "matching_cluster_idx": 6}, {"solution": "def sort_third(l: list):\n sorted_third = sorted([l[i] for i in range(len(l)) if i % 3 == 0])\n l_prime = [sorted_third[i//3] if i % 3 == 0 else l[i] for i in range(len(l))]\n return l_prime", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n values_at_indexes_divisible_by_three = sorted(l[i] for i in range(len(l)) if i % 3 == 0)\n result = l[:]\n result[::3] = values_at_indexes_divisible_by_three\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n sortable = sorted([l[i] for i in range(len(l)) if i % 3 == 0])\n l_prime = [sortable.pop(0) if i % 3 == 0 else l[i] for i in range(len(l))]\n return l_prime", "matching_cluster_idx": 6}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n \n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n divisible_by_three = [l[i] for i in range(len(l)) if i % 3 == 0]\n divisible_by_three.sort()\n for i in range(len(l)):\n if i % 3 == 0:\n l[i] = divisible_by_three.pop(0)\n return l", "matching_cluster_idx": 6}, {"solution": "def sort_third(l: list):\n # get items at indices divisible by 3\n div_by_3 = [l[i] for i in range(len(l)) if i % 3 == 0]\n # sort the selected items\n div_by_3.sort()\n\n # replace items at indices divisible by 3 with sorted items\n for i in range(len(l)):\n if i % 3 == 0:\n l[i] = div_by_3[i // 3]\n\n return l", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n sorted_l = sorted(l[i] for i in range(len(l)) if i % 3 == 0)\n new_l = [0]*len(l)\n\n sorted_index = 0\n for i in range(len(l)):\n if i % 3 == 0:\n new_l[i] = sorted_l[sorted_index]\n sorted_index += 1\n else:\n new_l[i] = l[i]\n \n return new_l", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n \"\"\"\n divisible_by_three = [(i, v) for i, v in enumerate(l) if i % 3 == 0]\n sorted_values = sorted([v for i, v in divisible_by_three])\n l_prime = l.copy()\n for (i, v), sorted_value in zip(divisible_by_three, sorted_values):\n l_prime[i] = sorted_value\n return l_prime", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n # Extract the values that are at the indices divisible by three\n values_at_indices_div_by_3 = [l[i] for i in range(len(l)) if i % 3 == 0]\n \n # Sort these values\n sorted_values = sorted(values_at_indices_div_by_3)\n \n # Initialize the list l'\n l_prime = l.copy()\n \n # Overwrite the values at the indices divisible by three with the sorted values\n for i in range(len(l_prime)):\n if i % 3 == 0:\n l_prime[i] = sorted_values[i // 3]\n \n return l_prime", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n values = []\n for i in range(len(l)):\n if i % 3 == 0:\n values.append(l[i])\n values.sort()\n j = 0\n for i in range(len(l)):\n if i % 3 == 0:\n l[i] = values[j]\n j += 1\n return l", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n sorted_every_third = sorted([l[i] for i in range(len(l)) if i % 3 == 0])\n result = [None]*len(l)\n for i in range(len(l)):\n if i % 3 == 0:\n result[i] = sorted_every_third[i//3]\n else:\n result[i] = l[i]\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n \"\"\"\n sorted_values = sorted([l[i] for i in range(len(l)) if i % 3 == 0])\n result = []\n for i in range(len(l)):\n if i % 3 == 0:\n result.append(sorted_values.pop(0))\n else:\n result.append(l[i])\n return result", "matching_cluster_idx": 6}, {"solution": "def sort_third(l: list):\n three_index_values = sorted([l[i] for i in range(len(l)) if i % 3 == 0])\n three_index_count = 0\n for i in range(len(l)):\n if i % 3 == 0:\n l[i] = three_index_values[three_index_count]\n three_index_count += 1\n return l", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n sorted_list = sorted([x for i, x in enumerate(l) if i % 3 == 0])\n new_list = [sorted_list.pop(0) if i % 3 == 0 else x for i, x in enumerate(l)]\n return new_list", "matching_cluster_idx": 6}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n \"\"\"\n divisible_by_three = [l[i] for i in range(len(l)) if i % 3 == 0]\n divisible_by_three.sort()\n \n result = l.copy()\n for i in range(len(result)):\n if i % 3 == 0:\n result[i] = divisible_by_three[i // 3]\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n # Create a sorted list of elements at indices divisible by 3.\n divisible_by_three = sorted(l[i] for i in range(len(l)) if i % 3 == 0)\n\n l_prime = l.copy() # Initialize the return list as a copy of l.\n\n for i in range(len(l)):\n if i % 3 == 0:\n # Insert the next element from divisible_by_three into l_prime.\n l_prime[i] = divisible_by_three.pop(0)\n\n return l_prime", "matching_cluster_idx": 6}, {"solution": "def sort_third(l):\n sorted_list = sorted(l[i] for i in range(len(l)) if i % 3 == 0)\n result = [None]*len(l)\n counter = 0\n for i in range(len(l)):\n if i % 3 == 0:\n result[i] = sorted_list[counter]\n counter += 1\n else:\n result[i] = l[i]\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list) -> list:\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n \"\"\"\n sorted_indices = sorted([i for i, e in enumerate(l) if i % 3 == 0])\n sorted_values = sorted([e for i, e in enumerate(l) if i % 3 == 0])\n l_prime = l[:]\n for i, j in enumerate(sorted_indices):\n l_prime[j] = sorted_values[i]\n return l_prime", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n # separate values at the indicies that are divisible by three\n div_by_three = [l[i] for i in range(len(l)) if i % 3 == 0]\n # sort the list of values\n div_by_three.sort()\n # create a copy of the original list\n l_prime = l[:]\n # replace elements in the copied list that are divisible by three with sorted values\n for i in range(len(l_prime)):\n if i % 3 == 0:\n l_prime[i] = div_by_three[i // 3]\n return l_prime", "matching_cluster_idx": 8}]}, "HumanEval/34": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(list(set(l)))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(list(set(l)))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n \"\"\"\n return sorted(list(set(l)))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(list(set(l)))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(list(set(l)))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(list(set(l)))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(list(set(l)))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n return sorted(list(set(l)))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n \"\"\"\n return sorted(list(set(l)))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}]}, "HumanEval/36": {"dps": 96.77419354838709, "dps_norm": 71.42857142857143, "pass@1": 97.0, "profiled": [{"solution": "def fizz_buzz(n: int) -> int:\n count = 0\n for i in range(1, n):\n if (i % 11 == 0 or i % 13 == 0):\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "import doctest\ndef fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n count = 0\n for i in range(1, n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int):\n \"\"\"\n Return the number of times the digit 7 appears in integers less than n \n which are divisible by 11 or 13.\n \n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n for i in range(1, n):\n if (i % 11 == 0 or i % 13 == 0):\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\"\"\"\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\"\"\"\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n count = 0\n for i in range(1, n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "import doctest\ndef fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n \n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n for i in range(1, n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n count = 0\n for i in range(1, n):\n if (i % 11 == 0 or i % 13 == 0):\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"\n Returns the number of times the digit 7 appears in integers \n less than n which are divisible by 11 or 13.\n\n Args:\n n (int): Upper limit for the search.\n\n Returns:\n int: The number of times the digit 7 appears.\n\n Doctests:\n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n for i in range(1, n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n count = 0\n for i in range(1, n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int):\n count = 0\n for i in range(1, n):\n if (i % 11 == 0 or i % 13 == 0):\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\"\"\"\n count = 0\n for i in range(1, n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\"\"\"\n count = 0\n for i in range(1, n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}]}, "HumanEval/37": {"dps": 94.92635024549918, "dps_norm": 90.0, "pass@1": 97.0, "profiled": [{"solution": "def sort_even(l: list):\n evens = sorted([v for i, v in enumerate(l) if i % 2 == 0])\n j = 0\n res = []\n for i in range(len(l)):\n if i % 2 == 0:\n res.append(evens[j])\n j += 1\n else:\n res.append(l[i])\n return res", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n even_indices_values = sorted([v for i, v in enumerate(l) if i % 2 == 0])\n result = [even_indices_values.pop(0) if i % 2 == 0 else v for i, v in enumerate(l)]\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n # get the elements at even positions in l\n even_positions = [l[i] for i in range(0, len(l), 2)]\n # sort the list of even positions\n even_positions.sort()\n # create a new list\n new_list = []\n # iterate through the elements of l\n for i in range(len(l)):\n # if the current index is even, append the next element from sorted list of even positions\n if i % 2 == 0:\n new_list.append(even_positions.pop(0))\n # else, append the current element of l\n else:\n new_list.append(l[i])\n return new_list", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list) -> list:\n # extract values at even indices\n evens = [l[i] for i in range(0, len(l), 2)]\n # sort these values\n evens.sort()\n\n # create a copy of l\n l_prime = l.copy()\n\n # replace values at even indices of l_prime with sorted values\n for i in range(0, len(l_prime), 2):\n l_prime[i] = evens[i // 2]\n\n return l_prime", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n even_indices = [i for i in range(0, len(l), 2)] # Indices of even positions\n even_values = sorted([l[i] for i in even_indices]) # Sorted values at even positions\n new_l = l.copy() # Create a copy of original list\n for i, value in zip(even_indices, even_values):\n new_l[i] = value\n return new_l", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n # separate the even and odd indices\n even_indices = [i for i in range(len(l)) if i % 2 == 0]\n odd_indices = [i for i in range(len(l)) if i % 2 != 0]\n\n even_values = [l[i] for i in even_indices]\n even_values.sort()\n\n # construct the result\n res = [None] * len(l)\n for i in even_indices:\n res[i] = even_values.pop(0)\n for i in odd_indices:\n res[i] = l[i]\n\n return res", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n \"\"\"\n even_values = sorted([l[i] for i in range(0, len(l), 2)])\n j = 0\n for i in range(0, len(l), 2):\n l[i] = even_values[j]\n j += 1\n return l", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n # Store all values at even indices in the original list\n even_values = [l[i] for i in range(0, len(l), 2)]\n \n # Sort those even values\n even_values.sort()\n \n # Create a new list with the same length as original\n result = [0] * len(l)\n \n # Fill the odd indices with the elements of the original list\n for i in range(1, len(l), 2):\n result[i] = l[i]\n \n # Fill the even indices with the sorted even values\n for i in range(0, len(l), 2):\n result[i] = even_values[i // 2]\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n # separate even and odd indicies\n evens = [v for i, v in enumerate(l) if i % 2 == 0]\n odds = [v for i, v in enumerate(l) if i % 2 != 0]\n\n # sort the even indicies\n evens.sort()\n\n # merge the sorted even and unaltered odd indicies\n l_prime = [None] * len(l)\n l_prime[::2] = evens\n l_prime[1::2] = odds\n\n return l_prime", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Extract the even-indexed elements and sort them\n even_indices_sorted = sorted(l[i] for i in range(0, len(l), 2))\n l_prime = l[:]\n \n # Replace the even-indexed elements with the sorted values\n for i, value in zip(range(0, len(l), 2), even_indices_sorted):\n l_prime[i] = value\n \n return l_prime", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n # list to store even indexed values\n even_values = [l[i] for i in range(len(l)) if i % 2 == 0]\n # sort the even_values list\n even_values.sort()\n\n # create a new list with the same length as l\n l_prime = [0] * len(l)\n\n for i in range(len(l)):\n if i % 2 == 0:\n # place the smallest value from even_values at even indexed positions\n l_prime[i] = even_values[i // 2]\n else:\n # place the original value at odd indexed positions\n l_prime[i] = l[i]\n\n return l_prime", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n even_indices_values = sorted(l[i] for i in range(0, len(l), 2))\n l_prime = [even_indices_values.pop(0) if i % 2 == 0 else v for i, v in enumerate(l)]\n return l_prime", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Fetch the elements at even indicies\n even_elements = [l[i] for i in range(0, len(l), 2)]\n # Sort the even elements\n even_elements.sort()\n\n # Combine sorted even elements and odd elements\n sorted_l = [even_elements.pop(0) if i % 2 == 0 else l[i] for i in range(len(l))]\n \n return sorted_l", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list) -> list:\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n even_indicies = [x for x in range(0, len(l), 2)]\n sorted_even = sorted(l[i] for i in even_indicies)\n result = l[:]\n for index, val in zip(even_indicies, sorted_even):\n result[index] = val\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n # Extracting the values at even indicies and sorting them\n sorted_even_values = sorted(l[i] for i in range(0, len(l), 2))\n result = l[:]\n # Replacing the values at even indicies with the sorted values\n for i in range(0, len(l), 2):\n result[i] = sorted_even_values.pop(0)\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n even_elements = sorted([l[i] for i in range(0, len(l), 2)])\n sorted_l = l[::2]\n sorted_l = [even_elements.pop(0) if i % 2 == 0 else l[i] for i in range(len(l))]\n return sorted_l", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n # Seperate even indexed and odd indexed elements.\n even_elements = [l[i] for i in range(0, len(l), 2)]\n odd_elements = [l[i] for i in range(1, len(l), 2)]\n\n # Sort the even indexed elements.\n even_elements.sort()\n\n # Reconstruct the list with even indexed elements in sorted order.\n result = [None] * len(l)\n result[::2] = even_elements\n result[1::2] = odd_elements\n\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list) -> list:\n # Split the list into even-indexed and odd-indexed elements.\n even_indices = [element for index, element in enumerate(l) if index % 2 == 0]\n odd_indices = [element for index, element in enumerate(l) if index % 2 == 1]\n\n # Sort the even-indexed elements.\n even_indices.sort()\n\n # Create a new list with the sorted even-indexed elements and original odd-indexed elements.\n l_prime = [None]*len(l)\n l_prime[::2] = even_indices\n l_prime[1::2] = odd_indices\n\n return l_prime", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are \n equal to the values of the even indicies of l, but sorted.\n \"\"\"\n even_indicies = [x for x in range(0, len(l), 2)] # Extracting even indicies\n even_values = sorted([l[i] for i in even_indicies]) # Sorting the even values\n l_prime = l.copy() # Copying the original list\n for i, v in zip(even_indicies, even_values):\n l_prime[i] = v # Replacing the sorted even values at the corresponding even indicies\n return l_prime", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n even_elements = sorted([l[i] for i in range(0, len(l), 2)])\n l_prime = [even_elements.pop(0) if i % 2 == 0 else l[i] for i in range(len(l))]\n return l_prime", "matching_cluster_idx": 8}]}, "HumanEval/49": {"dps": 70.82352941176471, "dps_norm": 90.0, "pass@1": 80.0, "profiled": [{"solution": "def modp(n: int, p: int) -> int:\n # return 2^n modulo p (be aware of numerics)\n return (2**n) % p", "matching_cluster_idx": 3}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n # Return 2^n modulo p using exponentiation by squaring\n if p == 1: \n return 0 \n elif n == 0: \n return 1\n else:\n partial_result = modp(n//2, p)\n if n % 2 == 0:\n return (partial_result ** 2) % p\n else:\n return (2 * (partial_result ** 2) % p) % p", "matching_cluster_idx": 3}, {"solution": "def modp(n: int, p: int) -> int:\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int):\n \"\"\"Return 2^n modulo p (be aware of numerics).\"\"\"\n return (2**n) % p", "matching_cluster_idx": 3}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int):\n if p == 1:\n return 0\n else:\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n # The property of exponentiation is used to calculate the remainder.\n # (a * b) % p = ((a % p) * (b % p)) % p\n # So, we can compute large powers modulo p in logarithmic time.\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\"\"\"\n return (2 ** n) % p", "matching_cluster_idx": 3}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\"\"\"\n return (2**n) % p", "matching_cluster_idx": 3}, {"solution": "def modp(n: int, p: int):\n \"\"\"Return 2^n modulo p (be aware of numerics).\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n if p == 1:\n return 0\n else:\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int):\n \"\"\"Return 2^n modulo p (be aware of numerics).\n \"\"\"\n return (2 ** n) % p", "matching_cluster_idx": 3}, {"solution": "def modp(n: int, p: int):\n return (2 ** n) % p", "matching_cluster_idx": 3}, {"solution": "import doctest\ndef modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n # Calculate 2^n without modulo\n power_without_modulo = 2**n\n\n # Return the modulo of power_without_modulo by p\n return power_without_modulo % p", "matching_cluster_idx": 2}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n # Python handles overflow automatically when calculating powers of large numbers\n result = pow(2, n, p)\n return result", "matching_cluster_idx": 4}, {"solution": "import doctest\ndef modp(n: int, p: int):\n \"\"\"\n Return 2^n modulo p (be aware of numerics).\n\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n if n == 0:\n return 1 % p\n elif n == 1:\n return 2 % p\n else:\n half_pow = modp(n // 2, p)\n if n % 2 == 0:\n return (half_pow * half_pow) % p\n else:\n return (half_pow * half_pow * 2) % p", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int):\n \"\"\"Return 2^n modulo p (be aware of numerics).\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n return (2**n) % p", "matching_cluster_idx": 3}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int):\n \"\"\"Return 2^n modulo p (be aware of numerics).\n \"\"\"\n # handle the special case where p is 1\n if p == 1:\n return 0\n else:\n return pow(2, n, p)", "matching_cluster_idx": 4}]}, "HumanEval/51": {"dps": 92.41545893719807, "dps_norm": 73.125, "pass@1": 100.0, "profiled": [{"solution": "def remove_vowels(text):\n vowels = 'aeiouAEIOU'\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n vowels = \"aeiouAEIOU\"\n return \"\".join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n vowels = 'aeiouAEIOU'\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n vowels = 'aeiouAEIOU'\n return ''.join([c for c in text if c not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n vowels = ['a', 'e', 'i', 'o', 'u', 'A', 'E', 'I', 'O', 'U']\n text_without_vowels = ''.join([char for char in text if char not in vowels])\n return text_without_vowels", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n vowels = {'a', 'e', 'i', 'o', 'u', 'A', 'E', 'I', 'O', 'U'}\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n vowels = 'aeiouAEIOU'\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = 'aeiouAEIOU'\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n vowels = {'a', 'e', 'i', 'o', 'u', 'A', 'E', 'I', 'O', 'U'}\n return \"\".join(char for char in text if char not in vowels)", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n vowels = 'aeiouAEIOU'\n return ''.join(c for c in text if c not in vowels)", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n vowels = 'aeiouAEIOU'\n result = [char for char in text if char not in vowels]\n return ''.join(result)", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n vowels = 'aeiouAEIOU'\n result = ''\n for char in text:\n if char not in vowels:\n result += char\n return result", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n vowels = 'aeiouAEIOU'\n return ''.join([letter for letter in text if letter not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n \"\"\"\n return ''.join(c for c in text if c.lower() not in 'aeiou')", "matching_cluster_idx": 2}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = 'aeiouAEIOU'\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "import doctest\ndef remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = 'aeiouAEIOU'\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n vowels = ['a', 'e', 'i', 'o', 'u', 'A', 'E', 'I', 'O', 'U']\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n \"\"\"\n vowels = {'a', 'e', 'i', 'o', 'u', 'A', 'E', 'I', 'O', 'U'}\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n \"\"\"\n vowels = 'aeiouAEIOU'\n return ''.join([c for c in text if c not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n vowels = 'aeiouAEIOU'\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}]}, "HumanEval/54": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 20.0, "profiled": [{"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')\n True\n >>> same_chars('abcd', 'dddddddabc')\n True\n >>> same_chars('dddddddabc', 'abcd')\n True\n >>> same_chars('eabcd', 'dddddddabc')\n False\n >>> same_chars('abcd', 'dddddddabce')\n False\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')\n False\n \"\"\"\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \"\"\"\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')\n True\n >>> same_chars('abcd', 'dddddddabc')\n True\n >>> same_chars('dddddddabc', 'abcd')\n True\n >>> same_chars('eabcd', 'dddddddabc')\n False\n >>> same_chars('abcd', 'dddddddabce')\n False\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')\n False\n \"\"\"\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \"\"\"\n # Convert the strings to character sets (remove duplicates and maintain order)\n set0 = sorted(set(s0))\n set1 = sorted(set(s1))\n\n # Return if the character sets are equal\n return set0 == set1", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')\n True\n >>> same_chars('abcd', 'dddddddabc')\n True\n >>> same_chars('dddddddabc', 'abcd')\n True\n >>> same_chars('eabcd', 'dddddddabc')\n False\n >>> same_chars('abcd', 'dddddddabce')\n False\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')\n False\n \"\"\"\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \"\"\"\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \"\"\"\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \"\"\"\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \"\"\"\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n # Convert to sets and compare\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \"\"\"\n # Convert the two strings to sets of characters\n s0_set = set(s0)\n s1_set = set(s1)\n\n # Return True if the two sets are equal, False otherwise\n return s0_set == s1_set", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \"\"\"\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \"\"\"\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n return set(s0) == set(s1)", "matching_cluster_idx": 6}]}, "HumanEval/58": {"dps": 77.08661417322834, "dps_norm": 70.0, "pass@1": 100.0, "profiled": [{"solution": "def common(l1: list, l2: list):\n \"\"\"\n Return sorted unique common elements for two lists.\n \"\"\"\n return sorted(list(set(l1) & set(l2)))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list) -> list:\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n\n \"\"\"\n return sorted(set(l1) & set(l2))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n return sorted(list(set(l1)&set(l2)))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n # Convert the lists to sets and use intersection to find common elements.\n # Then, sort the resulting list and return it.\n return sorted(list(set(l1) & set(l2)))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list) -> list:\n \"\"\"Return sorted unique common elements for two lists.\n \"\"\"\n # Use set to remove duplicates and find intersection\n common_set = set(l1) & set(l2)\n\n # Convert back to list and sort\n return sorted(list(common_set))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n\n \"\"\"\n # Convert lists to sets to perform set operations\n s1 = set(l1)\n s2 = set(l2)\n\n # Find intersection of sets which gives common elements\n common_set = s1.intersection(s2)\n\n # Return sorted list of common elements\n return sorted(list(common_set))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list) -> list:\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n return sorted(set([x for x in l1 if x in l2]))", "matching_cluster_idx": 0}, {"solution": "def common(l1: list, l2: list) -> list:\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n\n \"\"\"\n # Convert both lists to sets\n set1 = set(l1)\n set2 = set(l2)\n\n # Find common elements and sort them\n common_elements = sorted(list(set1 & set2))\n\n return common_elements", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list) -> list:\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n return sorted(set([x for x in l1 if x in l2]))", "matching_cluster_idx": 0}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n # Set intersection to find common elements and then sort and return them\n return sorted(set(l1) & set(l2))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n return sorted(list(set(l1) & set(l2)))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n return sorted(list(set(l1)&set(l2)))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n \"\"\"\n return sorted(list(set(l1) & set(l2)))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n return sorted(set(x for x in l1 if x in l2))", "matching_cluster_idx": 0}, {"solution": "def common(l1: list, l2: list) -> list:\n return sorted(set(l1) & set(l2))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list) -> list:\n \"\"\"Return sorted unique common elements for two lists.\n\n Parameters:\n l1 (list): First list of elements.\n l2 (list): Second list of elements.\n\n Returns:\n list: Sorted unique common elements.\n\n Examples:\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n\n \"\"\"\n # Convert the lists to sets\n s1 = set(l1)\n s2 = set(l2)\n\n # Return the sorted list of unique common elements\n return sorted(s1 & s2)", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list) -> list:\n \"\"\"Return sorted unique common elements for two lists.\n \"\"\"\n return sorted(set([item for item in l1 if item in l2]))", "matching_cluster_idx": 0}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n \"\"\"\n return sorted(list(set(l1) & set(l2)))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list) -> list:\n \"\"\"Return sorted unique common elements for two lists.\n\n Args:\n l1: The first list of integers.\n l2: The second list of integers.\n\n Returns:\n A list of unique common elements sorted in ascending order.\n\n Examples:\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n return sorted(set(l1) & set(l2))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n return sorted(list(set(l1) & set(l2)))", "matching_cluster_idx": 4}]}, "HumanEval/59": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 91.0, "profiled": [{"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n \"\"\"\n i = 2\n while i * i <= n:\n if n % i:\n i += 1\n else:\n n //= i\n return n", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n i = 2\n factors = []\n while i * i <= n:\n if n % i:\n i += 1\n else:\n n //= i\n factors.append(i)\n if n > 1:\n factors.append(n)\n return max(factors)", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n \"\"\"\n i = 2\n while i * i <= n:\n if n % i:\n i += 1\n else:\n n //= i\n return n", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"\n Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n i = 2\n while i * i <= n:\n if n % i:\n i += 1\n else:\n n //= i\n return n", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n i = 2\n while i * i <= n:\n if n % i:\n i += 1\n else:\n n //= i\n return n", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n i = 2\n while i * i <= n:\n if n % i:\n i += 1\n else:\n n //= i\n return n", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n \"\"\"\n i = 2\n while i * i <= n:\n if n % i:\n i += 1\n else:\n n //= i\n return n", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\"\"\"\n i = 2\n while i * i <= n:\n if n % i:\n i += 1\n else:\n n //= i\n return n", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n i = 2\n factors = []\n while i * i <= n:\n if n % i:\n i += 1\n else:\n n //= i\n factors.append(i)\n if n > 1:\n factors.append(n)\n return max(factors)", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"\n Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n i = 2\n factors = []\n while i * i <= n:\n if n % i:\n i += 1\n else:\n n //= i\n factors.append(i)\n if n > 1:\n factors.append(n)\n return max(factors)", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n\n def is_prime(num: int):\n \"\"\"Helper function to check if num is a prime number.\"\"\"\n if num < 2:\n return False\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n return False\n return True\n\n largest_prime = None\n for i in range(2, n + 1):\n if n % i == 0 and is_prime(i):\n largest_prime = i\n while n % i == 0:\n n //= i\n if n == 1:\n break\n return largest_prime", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n \"\"\"\n i = 2\n while i * i <= n:\n if n % i:\n i += 1\n else:\n n //= i\n return n", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n \"\"\"\n i = 2\n while i * i <= n:\n if n % i:\n i += 1\n else:\n n //= i\n return n", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n i = 2\n while i * i <= n:\n if n % i:\n i += 1\n else:\n n //= i\n return n", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n def is_prime(num: int):\n if num == 1:\n return False\n elif num == 2:\n return True\n else:\n for i in range(2, num):\n if num % i == 0:\n return False\n return True\n\n i = 2\n while i * i <= n:\n if n % i:\n i += 1\n else:\n n //= i\n return n if is_prime(n) else i", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n \"\"\"\n i = 2\n while i * i <= n:\n if n % i:\n i += 1\n else:\n n //= i\n return n", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n i = 2\n while i * i <= n:\n if n % i:\n i += 1\n else:\n n //= i\n return n", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n \"\"\"\n i = 2\n while i * i <= n:\n if n % i:\n i += 1\n else:\n n //= i\n return n", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"\n Return the largest prime factor of n. \n Assume n > 1 and is not a prime.\n\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n i = 2\n while i * i <= n:\n if n % i:\n i += 1\n else:\n n //= i\n return n", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\"\"\"\n\n def is_prime(x):\n \"\"\"Check if a number is prime.\"\"\"\n if x < 2:\n return False\n for i in range(2, int(x**0.5) + 1):\n if x % i == 0:\n return False\n return True\n\n largest_prime_factor = 1\n # Check dividing by 2\n while n % 2 == 0:\n largest_prime_factor = 2\n n = n / 2\n\n # Check the odd numbers\n for i in range(3, int(n**0.5) + 1, 2):\n while n % i == 0:\n largest_prime_factor = i\n n = n / i\n\n # Check if n itself is a prime\n if n > 2 and is_prime(n):\n largest_prime_factor = n\n\n return largest_prime_factor", "matching_cluster_idx": 8}]}, "HumanEval/64": {"dps": 58.76623376623377, "dps_norm": 45.0, "pass@1": 26.0, "profiled": [{"solution": "def vowels_count(s):\n count = 0\n vowels = ['a', 'e', 'i', 'o', 'u']\n\n for i in range(len(s)):\n if s[i].lower() in vowels:\n count += 1\n # Check for 'y' at the end of the string\n if s[i].lower() == 'y' and i == len(s) - 1:\n count += 1\n\n return count", "matching_cluster_idx": 0}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n count = 0\n for i in range(len(s)):\n if s[i].lower() in 'aeiou':\n count += 1\n elif i == len(s)-1 and s[i].lower() == 'y':\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = \"aeiouAEIOU\"\n count = 0\n for letter in s:\n if letter in vowels:\n count += 1\n if s.endswith('y') or s.endswith('Y'):\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n vowels = \"aeiou\"\n count = 0\n for i in range(len(s)):\n if s[i].lower() in vowels:\n count += 1\n if i == len(s) - 1 and s[i].lower() == \"y\":\n count += 1\n return count", "matching_cluster_idx": 0}, {"solution": "def vowels_count(s):\n count = 0\n vowels = ['a', 'e', 'i', 'o', 'u', 'A', 'E', 'I', 'O', 'U']\n last_char = s[-1] if s else ''\n\n for letter in s:\n if letter in vowels:\n count += 1\n if last_char == 'y' or last_char == 'Y':\n count += 1\n\n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n vowels = 'aeiou'\n count = sum(1 for char in s.lower() if char in vowels)\n if s.lower().endswith('y'):\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n vowels = 'aeiou'\n count = 0\n for i in range(len(s)):\n if s[i].lower() in vowels:\n count += 1\n if i == len(s) - 1 and s[i].lower() == 'y':\n count += 1\n return count", "matching_cluster_idx": 0}, {"solution": "def vowels_count(s):\n vowels = \"aeiou\"\n s = s.lower()\n count = sum(1 for char in s if char in vowels)\n if s.endswith('y'):\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n vowels = 'aeiou'\n s = s.lower()\n count = sum(1 for char in s if char in vowels)\n if s.endswith('y'):\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n count = 0\n s = s.lower()\n for char in s:\n if char in 'aeiou':\n count += 1\n if s.endswith('y'):\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n count = 0\n vowels = \"aeiou\"\n s = s.lower()\n for i in range(len(s)):\n if s[i] in vowels:\n count += 1\n if i == len(s)-1 and s[i] == 'y':\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def vowels_count(s):\n # List of vowels\n vowels = ['a', 'e', 'i', 'o', 'u']\n \n # Variable to store count of vowels\n count = 0\n\n # Convert input string to lower case for case insensitive comparison\n s = s.lower()\n\n # Iterate over the string to count vowels\n for char in s:\n if char in vowels:\n count += 1\n \n # If the string ends with 'y', increment count by 1\n if s.endswith('y'):\n count += 1\n\n # Return count of vowels\n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n vowels = 'aeiou'\n count = 0\n last_character = s[-1].lower() if s else ''\n for char in s.lower():\n if char in vowels:\n count += 1\n if last_character == 'y':\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n vowels = \"aeiou\"\n s = s.lower()\n count = 0\n for i in range(len(s)):\n if s[i] in vowels:\n count += 1\n if i == len(s) - 1 and s[i] == 'y':\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = 'aeiou'\n s = s.lower()\n count = sum(1 for char in s if char in vowels)\n if s.endswith('y'):\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n vowels = 'aeiou'\n s = s.lower()\n count = 0\n for char in s:\n if char in vowels:\n count += 1\n if s.endswith('y'):\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = 'aeiou'\n s = s.lower()\n count = sum(1 for char in s if char in vowels)\n if s.endswith('y'):\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n vowels = ['a', 'e', 'i', 'o', 'u']\n count = 0\n s = s.lower()\n for i in range(len(s)):\n if s[i] in vowels:\n count += 1\n if s[i] == 'y' and i == len(s) - 1:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def vowels_count(s):\n s = s.lower()\n vowels = ['a', 'e', 'i', 'o', 'u']\n count = 0\n for i in range(len(s)):\n if s[i] in vowels:\n count += 1\n if s[i] == 'y' and i == len(s)-1:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def vowels_count(s):\n vowels = \"aeiou\"\n count = 0\n for i in range(len(s)):\n if s[i].lower() in vowels:\n count += 1\n if s[i].lower() == 'y' and i == len(s)-1:\n count += 1\n return count", "matching_cluster_idx": 0}]}, "HumanEval/74": {"dps": 98.04878048780488, "dps_norm": 88.88888888888889, "pass@1": 85.0, "profiled": [{"solution": "def total_match(lst1, lst2):\n sum1 = sum(len(i) for i in lst1)\n sum2 = sum(len(i) for i in lst2)\n if sum1 < sum2:\n return lst1\n elif sum2 < sum1:\n return lst2\n else:\n return lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n len_lst1 = sum(len(word) for word in lst1)\n len_lst2 = sum(len(word) for word in lst2)\n if len_lst1 < len_lst2:\n return lst1\n elif len_lst2 < len_lst1:\n return lst2\n else:\n return lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n sum1 = sum(len(i) for i in lst1)\n sum2 = sum(len(i) for i in lst2)\n if sum1 < sum2:\n return lst1\n elif sum2 < sum1:\n return lst2\n else:\n return lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n len_lst1 = sum([len(i) for i in lst1])\n len_lst2 = sum([len(i) for i in lst2])\n if len_lst1 < len_lst2:\n return lst1\n elif len_lst2 < len_lst1:\n return lst2\n else:\n return lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n len1 = sum(len(s) for s in lst1)\n len2 = sum(len(s) for s in lst2)\n if len1 < len2:\n return lst1\n elif len2 < len1:\n return lst2\n else:\n return lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n len1 = sum(len(s) for s in lst1)\n len2 = sum(len(s) for s in lst2)\n if len1 < len2:\n return lst1\n elif len2 < len1:\n return lst2\n else:\n return lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n sum1 = sum(len(word) for word in lst1)\n sum2 = sum(len(word) for word in lst2)\n if sum1 < sum2:\n return lst1\n elif sum2 < sum1:\n return lst2\n else:\n return lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n sum1 = sum(len(s) for s in lst1)\n sum2 = sum(len(s) for s in lst2)\n if sum1 <= sum2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n sum_lst1 = sum([len(word) for word in lst1])\n sum_lst2 = sum([len(word) for word in lst2])\n\n if sum_lst1 < sum_lst2:\n return lst1\n elif sum_lst2 < sum_lst1:\n return lst2\n else:\n return lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n total_chars_lst1 = sum(len(word) for word in lst1)\n total_chars_lst2 = sum(len(word) for word in lst2)\n if total_chars_lst1 <= total_chars_lst2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n chars_in_lst1 = sum(len(word) for word in lst1)\n chars_in_lst2 = sum(len(word) for word in lst2)\n \n if chars_in_lst1 < chars_in_lst2:\n return lst1\n elif chars_in_lst1 > chars_in_lst2:\n return lst2\n else:\n return lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n sum1 = sum(len(word) for word in lst1)\n sum2 = sum(len(word) for word in lst2)\n \n if sum1 <= sum2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n sum1 = sum(len(word) for word in lst1)\n sum2 = sum(len(word) for word in lst2)\n\n if sum1 < sum2:\n return lst1\n elif sum1 > sum2:\n return lst2\n else:\n return lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n sum1 = sum(len(word) for word in lst1)\n sum2 = sum(len(word) for word in lst2)\n if sum1 < sum2:\n return lst1\n elif sum2 < sum1:\n return lst2\n else:\n return lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n total_chars1 = sum(len(s) for s in lst1)\n total_chars2 = sum(len(s) for s in lst2)\n if total_chars1 <= total_chars2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n len_lst1 = sum(len(word) for word in lst1)\n len_lst2 = sum(len(word) for word in lst2)\n if len_lst1 < len_lst2:\n return lst1\n elif len_lst2 < len_lst1:\n return lst2\n else:\n return lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n return lst1 if sum(len(word) for word in lst1) <= sum(len(word) for word in lst2) else lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n len1 = sum(len(word) for word in lst1)\n len2 = sum(len(word) for word in lst2)\n if len1 < len2:\n return lst1\n elif len1 > len2:\n return lst2\n else:\n return lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n total_chars1 = sum([len(word) for word in lst1])\n total_chars2 = sum([len(word) for word in lst2])\n \n if total_chars1 < total_chars2:\n return lst1\n elif total_chars2 < total_chars1:\n return lst2\n else:\n return lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n sum1 = sum(len(word) for word in lst1)\n sum2 = sum(len(word) for word in lst2)\n \n return lst1 if sum1 <= sum2 else lst2", "matching_cluster_idx": 7}]}, "HumanEval/85": {"dps": 89.15841584158416, "dps_norm": 58.333333333333336, "pass@1": 86.0, "profiled": [{"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n return sum(val for idx, val in enumerate(lst) if idx % 2 != 0 and val % 2 == 0)", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n return sum(lst[i] for i in range(1, len(lst), 2) if lst[i] % 2 == 0)", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst, add the even elements that are at odd indices.\"\"\"\n return sum(lst[i] for i in range(1, len(lst), 2) if lst[i] % 2 == 0)", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n return sum(value for index, value in enumerate(lst) if index % 2 != 0 and value % 2 == 0)", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"\n Given a non-empty list of integers lst. \n Add the even elements that are at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n # initialize sum to 0\n s = 0\n # loop over the lst\n for i in range(len(lst)):\n # check if the index is odd and element at that index is even\n if i % 2 != 0 and lst[i] % 2 == 0:\n # add the element to the sum\n s += lst[i]\n # return the sum\n return s", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst, return the sum of even elements that are at odd indices\"\"\"\n\n # Slice out every other element starting from index 1 (adjusting for zero-based indexing)\n odd_indices = lst[1::2]\n\n # Filter out odd numbers\n even_numbers = [num for num in odd_indices if num % 2 == 0]\n\n # Return the sum of the remaining even numbers\n return sum(even_numbers)", "matching_cluster_idx": 5}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst, add the even elements that are at odd indices.\n \"\"\"\n return sum(el for idx, el in enumerate(lst) if idx % 2 != 0 and el % 2 == 0)", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n return sum(num for index, num in enumerate(lst) if index % 2 == 1 and num % 2 == 0)", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices..\n\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n return sum(lst[i] for i in range(1, len(lst), 2) if lst[i] % 2 == 0)", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"\n Given a non-empty list of integers lst, add the even elements that are at odd indices.\n \"\"\"\n return sum(lst[i] for i in range(1, len(lst), 2) if lst[i] % 2 == 0)", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices..\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n # initial sum is 0\n total = 0\n\n # loop through the list and add the element if it is at an odd index and even\n for i in range(len(lst)):\n if i % 2 != 0 and lst[i] % 2 == 0:\n total += lst[i]\n\n return total", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst, add the even elements that are at odd indices.\"\"\"\n \n # Initialize sum to 0\n sum_even_odd_indices = 0\n \n # Iterate over lst from 0 to len(lst)\n for i in range(len(lst)):\n # Check if the index is odd and the number at that index is even\n if i % 2 != 0 and lst[i] % 2 == 0:\n # Add the number to the sum\n sum_even_odd_indices += lst[i]\n \n return sum_even_odd_indices", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n return sum(val for idx, val in enumerate(lst) if idx % 2 != 0 and val % 2 == 0)", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst, add the even elements that are at odd indices.\n \n Examples:\n add([4, 2, 6, 7]) ==> 2\n \"\"\"\n return sum(lst[i] for i in range(1, len(lst), 2) if lst[i] % 2 == 0)", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst, \n add the even elements that are at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2\n \"\"\"\n\n # initialize sum\n even_sum = 0\n \n # iterate over the list with odd indices\n for i in range(1, len(lst), 2):\n # check if the number is even\n if lst[i] % 2 == 0:\n # add to sum\n even_sum += lst[i]\n \n return even_sum", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices..\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n return sum(v for i, v in enumerate(lst) if i % 2 == 1 and v % 2 == 0)", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices..\"\"\"\n\n # Use list slicing to get odd index elements and filter out odd ones\n odd_indices_even_nums = [num for index, num in enumerate(lst) if index % 2 != 0 and num % 2 == 0]\n \n # Return the sum of the odd index even numbers\n return sum(odd_indices_even_nums)", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"\n Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n # filter for elements at odd indices and even values \n odd_even_pairs = [n for i, n in enumerate(lst) if i % 2 != 0 and n % 2 == 0]\n # return the sum of the filtered list\n return sum(odd_even_pairs)", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices.\"\"\"\n return sum(lst[i] for i in range(1, len(lst), 2) if lst[i] % 2 == 0)", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices..\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n return sum(val for idx, val in enumerate(lst) if idx % 2 != 0 and val % 2 == 0)", "matching_cluster_idx": 2}]}, "HumanEval/86": {"dps": 91.22448979591837, "dps_norm": 96.0, "pass@1": 77.0, "profiled": [{"solution": "def anti_shuffle(s):\n words = s.split(' ')\n return ' '.join([''.join(sorted(word)) for word in words])", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n words = s.split(' ')\n ordered_words = [''.join(sorted(word)) for word in words]\n return ' '.join(ordered_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n\n # split the string into words, then sort characters in each word\n return ' '.join([''.join(sorted(word)) if word != ' ' else ' ' for word in s.split(' ')])", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n words = s.split(' ')\n ordered_words = [''.join(sorted(word)) for word in words]\n ordered_str = ' '.join(ordered_words)\n return ordered_str", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n words = s.split(' ')\n result = []\n\n for word in words:\n chars = list(word)\n chars.sort(key=lambda x: ord(x))\n result.append(''.join(chars))\n\n return ' '.join(result)", "matching_cluster_idx": 2}, {"solution": "def anti_shuffle(s):\n words = s.split(' ')\n ordered_words = [' '.join([''.join(sorted(w)) for w in words])]\n return ordered_words[0]", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n # Split the string into words\n words = s.split(' ')\n # For each word, sort its characters based on their ASCII values\n words = [''.join(sorted(word)) for word in words]\n # Join the sorted words back together\n return ' '.join(words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n words = s.split(' ')\n ordered_words = [''.join(sorted(word)) for word in words]\n return ' '.join(ordered_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n words = s.split(' ')\n result = []\n for word in words:\n chars = list(word)\n chars.sort(key=lambda x: ord(x))\n result.append(''.join(chars))\n return ' '.join(result)", "matching_cluster_idx": 2}, {"solution": "def anti_shuffle(s):\n words = s.split(\" \")\n shuffled_words = [''.join(sorted(word)) for word in words]\n return ' '.join(shuffled_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n words = s.split(' ')\n ordered_words = [''.join(sorted(word)) for word in words]\n return ' '.join(ordered_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n words = s.split(' ')\n ordered_words = [''.join(sorted(word)) for word in words]\n return ' '.join(ordered_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n # Split the sentence into words and blank spaces.\n words = s.split(' ')\n result = []\n\n # For each word, sort its characters based on ASCII values.\n for word in words:\n new_word = ''.join(sorted(word))\n # Append the new sorted word to the result list.\n result.append(new_word)\n\n # Join the sorted words with blank spaces and return the result.\n return ' '.join(result)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n words = s.split(\" \")\n for i in range(len(words)):\n words[i] = \"\".join(sorted(words[i]))\n return \" \".join(words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n words = s.split(' ')\n ordered_words = [''.join(sorted(word)) for word in words]\n return ' '.join(ordered_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n return \" \".join(\n \"\".join(sorted(word)) if word != \" \" else \" \"\n for word in s.split(\" \")\n )", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n words = s.split(' ')\n for i, word in enumerate(words):\n new_word = ''.join(sorted(word))\n words[i] = new_word\n return ' '.join(words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n words = s.split(' ')\n new_words = []\n for word in words:\n new_word = \"\".join(sorted(word))\n new_words.append(new_word)\n new_s = \" \".join(new_words)\n return new_s", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n words = s.split(' ')\n for i in range(len(words)):\n words[i] = ''.join(sorted(words[i]))\n return ' '.join(words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n words = s.split(' ')\n ordered_words = [''.join(sorted(word)) for word in words]\n return ' '.join(ordered_words)", "matching_cluster_idx": 4}]}, "HumanEval/87": {"dps": 64.43804034582132, "dps_norm": 51.42857142857143, "pass@1": 85.0, "profiled": [{"solution": "def get_row(lst, x):\n # Initialize an empty list to store the coordinates\n coords = []\n \n # Iterate over the rows in the list\n for i in range(len(lst)):\n # Iterate over the columns in the current row\n for j in range(len(lst[i])):\n # If the current element is equal to x, add its coordinates to coords\n if lst[i][j] == x:\n coords.append((i, j))\n \n # Sort the coordinates first by row number, then by column number in descending order\n coords.sort(key=lambda coord: (coord[0], -coord[1]))\n \n return coords", "matching_cluster_idx": 2}, {"solution": "def get_row(lst, x):\n coord = []\n for i, row in enumerate(lst):\n for j, col in enumerate(row):\n if col == x:\n coord.append((i, j))\n return sorted(coord, key=lambda y: (y[0], -y[1]))", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n coords = []\n for i, row in enumerate(lst):\n for j, col in enumerate(row):\n if col == x:\n coords.append((i, j))\n return sorted(coords, key=lambda tup: (tup[0], -tup[1]))", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n result = [(i, j) for i, row in enumerate(lst) for j, val in enumerate(row) if val == x]\n result.sort(key=lambda y: (y[0], -y[1]))\n return result", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n coordinates = []\n for i, row in enumerate(lst):\n for j, item in enumerate(row):\n if item == x:\n coordinates.append((i, j))\n\n coordinates.sort(key=lambda y: (y[0], -y[1]))\n\n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n coordinates = []\n for i in range(len(lst)):\n for j in range(len(lst[i])):\n if lst[i][j] == x:\n coordinates.append((i, j))\n coordinates.sort(key=lambda y: (y[0], -y[1]))\n return coordinates", "matching_cluster_idx": 2}, {"solution": "def get_row(lst, x):\n coords = []\n for i, row in enumerate(lst):\n for j, elem in enumerate(row):\n if elem == x:\n coords.append((i, j))\n coords.sort(key=lambda y: (y[0], -y[1]))\n return coords", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n # Initialize an empty list for the coordinates\n coordinates = []\n # Loop through the rows\n for i in range(len(lst)):\n # Loop through the elements in the row\n for j in range(len(lst[i])):\n # If the element is equal to x, append its coordinates to the list\n if lst[i][j] == x:\n coordinates.append((i, j))\n # Sort the coordinates first by rows in ascending order, then by columns in descending order\n coordinates.sort(key = lambda y: (y[0], -y[1]))\n return coordinates", "matching_cluster_idx": 2}, {"solution": "def get_row(lst, x):\n # Initialize empty list to store tuples\n tuples = []\n \n # Loop through each row\n for i in range(len(lst)):\n # Loop through each element in the row\n for j in range(len(lst[i])):\n # If element matches x, append tuple (i, j)\n if lst[i][j] == x:\n tuples.append((i, j))\n \n # Sort tuples first by row and then by column\n tuples.sort(key=lambda y: (y[0], -y[1]))\n \n # Return the list of tuples\n return tuples", "matching_cluster_idx": 2}, {"solution": "def get_row(lst, x):\n if not lst: return []\n coords = []\n for i in range(len(lst)):\n for j in range(len(lst[i])):\n if lst[i][j] == x:\n coords.append((i, j))\n coords.sort(key = lambda y: (y[0], -y[1]))\n return coords", "matching_cluster_idx": 2}, {"solution": "def get_row(lst, x):\n coordinates = []\n for i, row in enumerate(lst):\n for j, item in enumerate(row):\n if item == x:\n coordinates.append((i, j))\n\n # Sort by row then by column in descending order\n coordinates.sort(key=lambda y: (y[0], -y[1]))\n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n if not lst:\n return []\n\n coordinates = []\n for i in range(len(lst)):\n for j in range(len(lst[i])):\n if lst[i][j] == x:\n coordinates.append((i, j))\n\n # Sort coordinates first by rows in ascending order,\n # then by columns in descending order\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n\n return coordinates", "matching_cluster_idx": 2}, {"solution": "def get_row(lst, x):\n coordinates = []\n for i, row in enumerate(lst):\n for j, element in enumerate(row):\n if element == x:\n coordinates.append((i, j))\n\n coordinates.sort(key=lambda y: (y[0], -y[1]))\n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n coordinates = []\n for i in range(len(lst)):\n for j in range(len(lst[i])):\n if lst[i][j] == x:\n coordinates.append((i, j))\n coordinates.sort(key = lambda y: (y[0], -y[1]))\n return coordinates", "matching_cluster_idx": 2}, {"solution": "def get_row(lst, x):\n coordinates = []\n for i, row in enumerate(lst):\n for j, num in enumerate(row):\n if num == x:\n coordinates.append((i, j))\n # sort the coordinates first by row and then by column\n coordinates.sort(key=lambda tup: (tup[0], -tup[1]))\n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n coords = []\n for i, row in enumerate(lst):\n for j, elem in enumerate(row):\n if elem == x:\n coords.append((i, j))\n coords.sort(key = lambda y: (y[0], -y[1]))\n return coords", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n coords = []\n for i, row in enumerate(lst):\n for j, val in enumerate(row):\n if val == x:\n coords.append((i, j))\n return sorted(coords, key=lambda y: (y[0], -y[1]))", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n result = []\n for row in range(len(lst)):\n for col in range(len(lst[row])):\n if lst[row][col] == x:\n result.append((row, col))\n result.sort(key=lambda y: (y[0], -y[1]))\n return result", "matching_cluster_idx": 2}, {"solution": "def get_row(lst, x):\n result = [(i, j) for i, row in enumerate(lst) for j, col in enumerate(row) if col == x]\n result.sort(key=lambda y: (y[0], -y[1]))\n return result", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \"\"\"\n result = []\n for i, row in enumerate(lst):\n for j, elem in enumerate(row):\n if elem == x:\n result.append((i, j))\n result.sort(key=lambda tup: (tup[0], -tup[1]))\n return result", "matching_cluster_idx": 3}]}, "HumanEval/89": {"dps": 96.64948453608248, "dps_norm": 28.571428571428573, "pass@1": 68.0, "profiled": [{"solution": "def encrypt(s):\n encrypted_string = \"\"\n for char in s:\n if char.isalpha():\n shift = 2 * 2\n char = char.lower()\n encrypted_char = chr(((ord(char) - 97 + shift) % 26) + 97)\n encrypted_string += encrypted_char.upper() if char.isupper() else encrypted_char\n else:\n encrypted_string += char\n return encrypted_string", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n result = \"\"\n for char in s:\n if char.isalpha():\n shift = 2 * 2\n char_code = ord(char.lower())\n if char.isupper():\n result += chr((char_code - 65 + shift) % 26 + 65)\n else:\n result += chr((char_code - 97 + shift) % 26 + 97)\n else:\n result += char\n return result", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n encrypted_s = \"\"\n for char in s:\n if char.isalpha():\n ascii_offset = 65 if char.isupper() else 97\n encrypted_s += chr((ord(char) - ascii_offset + 2 * 2) % 26 + ascii_offset)\n else:\n encrypted_s += char\n return encrypted_s", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n result = \"\"\n for char in s:\n # handle only alphabets, keep others intact\n if char.isalpha():\n ascii_offset = 65 if char.isupper() else 97\n result += chr((ord(char) - ascii_offset + 2 * 2) % 26 + ascii_offset)\n else:\n result += char\n return result", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n result = \"\"\n for c in s:\n if 'a' <= c <= 'z':\n result += chr((ord(c) - ord('a') + 2*2) % 26 + ord('a'))\n elif 'A' <= c <= 'Z':\n result += chr((ord(c) - ord('A') + 2*2) % 26 + ord('A'))\n else:\n result += c\n return result", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n result = \"\"\n for char in s:\n if char.isalpha():\n ascii_offset = 65 if char.isupper() else 97\n result += chr((ord(char) - ascii_offset + 2*2) % 26 + ascii_offset)\n else:\n result += char\n return result", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n encrypted_s = \"\"\n for c in s:\n if c.isalpha():\n ascii_offset = 65 if c.isupper() else 97\n encrypted_s += chr((ord(c) - ascii_offset + 2 * 2) % 26 + ascii_offset)\n else:\n encrypted_s += c\n return encrypted_s", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n encrypted_text = \"\"\n for char in s:\n if char.isalpha():\n ascii_offset = 65 if char.isupper() else 97\n encrypted_text += chr((ord(char) - ascii_offset + 2*2) % 26 + ascii_offset)\n else:\n encrypted_text += char\n return encrypted_text", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n result = ''\n for char in s:\n if char.isalpha():\n char_code = ord(char.lower())\n char_code = (char_code - ord('a') + 2*2) % 26 + ord('a')\n result += chr(char_code) if char.islower() else chr(char_code).upper()\n else:\n result += char\n return result", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n result = ''\n for char in s:\n if char.isalpha():\n ascii_offset = 65 if char.isupper() else 97\n result += chr((ord(char) - ascii_offset + 4) % 26 + ascii_offset)\n else:\n result += char\n return result", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n result = \"\"\n for char in s:\n if char.isalpha():\n char = char.lower()\n if ord(char) + 4 > ord('z'):\n result += chr(ord('a') + (ord(char) + 4 - ord('z')) - 1)\n else:\n result += chr(ord(char) + 4)\n else:\n result += char\n return result", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n result = ''\n for char in s:\n # handle lowercase characters\n if char.islower():\n result += chr(((ord(char) - ord('a') + 2*2) % 26) + ord('a'))\n # handle uppercase characters\n elif char.isupper():\n result += chr(((ord(char) - ord('A') + 2*2) % 26) + ord('A'))\n # keep non-alphabet characters as is\n else:\n result += char\n return result", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n encrypted_string = \"\"\n\n for char in s:\n if char.isalpha():\n ascii_val = ord(char.lower())\n new_char = chr(((ascii_val - 97 + 2*2) % 26) + 97)\n encrypted_string += new_char.upper() if char.isupper() else new_char\n else:\n encrypted_string += char\n\n return encrypted_string", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n result = \"\"\n for char in s:\n if char.isalpha():\n shift = 2 * 2\n char = char.lower()\n if ord(char) + shift > ord('z'):\n result += chr(ord('a') + (shift - (ord('z') - ord(char) + 1)))\n else:\n result += chr(ord(char) + shift)\n else:\n result += char\n return result", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n encrypted_string = \"\"\n for char in s:\n if not char.isalpha():\n encrypted_string += char\n continue\n ascii_offset = 65 if char.isupper() else 97\n encrypted_string += chr((ord(char) - ascii_offset + 4) % 26 + ascii_offset)\n return encrypted_string", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n encrypted_s = \"\"\n for char in s:\n if char.isalpha():\n ascii_offset = 65 if char.isupper() else 97\n encrypted_s += chr((ord(char) - ascii_offset + 2*2) % 26 + ascii_offset)\n else:\n encrypted_s += char\n return encrypted_s", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n result = \"\"\n for char in s:\n if 'a' <= char <= 'z':\n result += chr(((ord(char) - ord('a') + 2*2) % 26) + ord('a'))\n elif 'A' <= char <= 'Z':\n result += chr(((ord(char) - ord('A') + 2*2) % 26) + ord('A'))\n else:\n result += char\n return result", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n encrypted = \"\"\n for char in s:\n # Check if character is an uppercase letter\n if 'A' <= char <= 'Z':\n encrypted += chr(((ord(char) - 65 + 2*2) % 26) + 65)\n # Check if character is a lowercase letter\n elif 'a' <= char <= 'z':\n encrypted += chr(((ord(char) - 97 + 2*2) % 26) + 97)\n # If not a letter, add to the encrypted string without change\n else:\n encrypted += char\n return encrypted", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n encrypted_text = \"\"\n for character in s:\n if character.isalpha():\n ascii_offset = 65 if character.isupper() else 97\n encrypted_character = chr((((ord(character) - ascii_offset) + 2*2) % 26) + ascii_offset)\n encrypted_text += encrypted_character\n else:\n encrypted_text += character\n return encrypted_text", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n encrypted = \"\"\n for character in s:\n if character.isalpha():\n ascii_offset = ord('a') if character.islower() else ord('A')\n encrypted += chr((ord(character) - ascii_offset + 2*2) % 26 + ascii_offset)\n else:\n encrypted += character\n return encrypted", "matching_cluster_idx": 1}]}, "HumanEval/90": {"dps": 72.06225680933852, "dps_norm": 56.66666666666667, "pass@1": 63.0, "profiled": [{"solution": "def next_smallest(lst):\n if len(lst) < 2:\n return None\n smallest = second_smallest = float('inf')\n for num in lst:\n if num < smallest:\n second_smallest = smallest\n smallest = num\n elif num < second_smallest and num != smallest:\n second_smallest = num\n return None if second_smallest == float('inf') else second_smallest", "matching_cluster_idx": 5}, {"solution": "def next_smallest(lst):\n if len(lst) < 2:\n return None\n smallest = float('inf')\n second_smallest = float('inf')\n for num in lst:\n if num < smallest:\n second_smallest = smallest\n smallest = num\n elif smallest < num < second_smallest:\n second_smallest = num\n return second_smallest if second_smallest != float('inf') else None", "matching_cluster_idx": 5}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n \n # sorting the list\n lst.sort()\n \n # finding the second smallest element\n for i in range(1, len(lst)):\n if lst[i] != lst[0]:\n return lst[i]\n \n return None", "matching_cluster_idx": 11}, {"solution": "def next_smallest(lst):\n if not lst or len(lst) < 2:\n return None\n first_min = second_min = float('inf')\n for num in lst:\n if num < first_min:\n first_min, second_min = num, first_min\n elif first_min < num < second_min:\n second_min = num\n return None if second_min == float('inf') else second_min", "matching_cluster_idx": 5}, {"solution": "def next_smallest(lst):\n if len(lst) < 2:\n return None\n smallest = second_smallest = float('inf')\n for num in lst:\n if num < smallest:\n second_smallest = smallest\n smallest = num\n elif smallest < num < second_smallest:\n second_smallest = num\n return None if second_smallest == float('inf') else second_smallest", "matching_cluster_idx": 5}, {"solution": "def next_smallest(lst):\n if len(lst) < 2:\n return None\n first_min = second_min = float('inf')\n for i in lst:\n if i < first_min:\n first_min, second_min = i, first_min\n elif first_min < i < second_min:\n second_min = i\n return second_min if second_min < float('inf') else None", "matching_cluster_idx": 5}, {"solution": "def next_smallest(lst):\n # Filter out duplicates, sort the list, and check for empty list\n lst = sorted(list(set(lst)))\n if len(lst) < 2:\n return None\n else:\n return lst[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n if len(lst) < 2:\n return None\n lst = list(set(lst))\n lst.sort()\n if len(lst) < 2:\n return None\n return lst[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n lst = list(set(lst)) # Remove duplicates\n lst.sort() # Sort the list in ascending order\n\n # Check if the list has at least 2 elements\n if len(lst) < 2:\n return None\n else:\n return lst[1] # Return the second smallest element", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n if len(lst) < 2:\n return None\n smallest = float('inf')\n second_smallest = float('inf')\n for num in lst:\n if num < smallest:\n second_smallest = smallest\n smallest = num\n elif smallest < num < second_smallest:\n second_smallest = num\n return second_smallest if second_smallest != float('inf') else None", "matching_cluster_idx": 5}, {"solution": "def next_smallest(lst):\n if len(lst) < 2:\n return None\n lst_set = set(lst)\n lst_set.remove(min(lst_set))\n if len(lst_set) < 1:\n return None\n return min(lst_set)", "matching_cluster_idx": 5}, {"solution": "def next_smallest(lst):\n if len(lst) < 2:\n return None\n lst = list(set(lst))\n lst.sort()\n if len(lst) < 2:\n return None\n return lst[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n if len(lst) < 2:\n return None\n smallest = float('inf')\n second_smallest = float('inf')\n for num in lst:\n if num < smallest:\n second_smallest = smallest\n smallest = num\n elif smallest < num < second_smallest:\n second_smallest = num\n return second_smallest if second_smallest != float('inf') else None", "matching_cluster_idx": 5}, {"solution": "def next_smallest(lst):\n # Check if the list is empty\n if len(lst) < 2:\n return None\n\n min_val = float('inf')\n second_min = float('inf')\n \n # Go through each element in the list\n for ele in lst:\n # If the current element is smaller than the current minimum, update minimum\n if ele < min_val:\n second_min = min_val\n min_val = ele\n # If the current element is in between the current minimum and second minimum, update second minimum\n elif min_val < ele < second_min:\n second_min = ele\n\n # If there was no second minimum found (in case all elements in the list were equal), return None\n if second_min == float('inf'):\n return None\n \n return second_min", "matching_cluster_idx": 5}, {"solution": "def next_smallest(lst):\n if len(lst) < 2:\n return None\n lst = list(set(lst))\n lst.sort()\n if len(lst) < 2:\n return None\n return lst[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n # Handle empty list\n if not lst:\n return None\n \n # Remove duplicate values\n lst = list(set(lst))\n \n # Sort the list\n lst.sort()\n \n # If there are at least 2 elements, return the 2nd smallest one. Else, return None.\n return lst[1] if len(lst) > 1 else None", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n # Remove duplicate items in the list\n lst = list(set(lst))\n\n # Check if there are at least 2 unique elements in the list\n if len(lst) < 2:\n return None\n\n # Sort the list in ascending order\n lst.sort()\n\n # Return the 2nd smallest item\n return lst[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \"\"\"\n # First, we will sort the list\n lst = sorted(list(set(lst)))\n\n # Next, we'll check if there is at least one element in the list.\n if len(lst) < 2:\n return None\n else:\n return lst[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n if len(lst) < 2:\n return None\n lst = list(set(lst))\n lst.sort()\n return lst[1] if len(lst) > 1 else None", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n if len(lst) < 2:\n return None\n lst = list(set(lst)) # Remove duplicates\n lst.sort()\n if len(lst) < 2:\n return None\n return lst[1]", "matching_cluster_idx": 6}]}, "HumanEval/113": {"dps": 80.32454361054766, "dps_norm": 56.66666666666667, "pass@1": 61.0, "profiled": [{"solution": "def odd_count(lst):\n result = []\n for idx, val in enumerate(lst):\n count = sum(1 for char in val if int(char) % 2 != 0)\n sentence = \"the number of odd elements {}n the str{}ng {} of the {}nput.\".format(count, count, count, count)\n result.append(sentence)\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n results = []\n for index, num_str in enumerate(lst):\n count = sum(1 for ch in num_str if int(ch) % 2 != 0)\n result = f\"the number of odd elements {count}n the str{count}ng {count} of the {count}nput.\"\n results.append(result)\n return results", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n result = []\n for i, s in enumerate(lst):\n odd_num = sum(int(c) % 2 for c in s)\n str_odd_num = str(odd_num)\n output = f\"the number of odd elements {str_odd_num}n the str{str_odd_num}ng {str_odd_num} of the {str_odd_num}nput.\"\n result.append(output)\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n # Initialize an empty list to store the results\n results = []\n\n # Loop through the input list\n for i, s in enumerate(lst):\n # Initialize a count of odd numbers to 0\n odd_count = 0\n\n # Loop through each character in the string\n for ch in s:\n # If the character is odd (1, 3, 5, etc.), increment the count\n if int(ch) % 2 != 0:\n odd_count += 1\n\n # Generate the required string and append it to the results list\n result_string = f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\"\n results.append(result_string)\n\n # Return the list of results\n return results", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n def count_odd_digits(string):\n return sum(1 for char in string if int(char) % 2 != 0)\n \n return [\"the number of odd elements {}n the str{}ng {} of the {}nput.\".format(count_odd_digits(s), count_odd_digits(s), count_odd_digits(s), count_odd_digits(s)) for s in lst]", "matching_cluster_idx": 0}, {"solution": "def odd_count(lst):\n \"\"\"\n Given a list of strings, where each string consists of only digits, \n return a list. Each element i of the output should be \n \"the number of odd elements in the string i of the input.\" \n where all the i's should be replaced by the number of odd digits in the i'th string of the input.\n \"\"\"\n def count_odds(num_str):\n \"\"\"Count the number of odd digits in a string of digits\"\"\"\n return sum(int(d) % 2 != 0 for d in num_str)\n\n return [f\"the number of odd elements {count_odds(s)}n the str{count_odds(s)}ng {count_odds(s)} of the {count_odds(s)}nput.\" for s in lst]", "matching_cluster_idx": 0}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n\n # Initialize an empty list to store the result\n result = []\n \n # Loop through each string in the input list\n for i, string in enumerate(lst):\n # Count the number of odd digits in the string\n odd_count = sum(1 for char in string if int(char) % 2 != 0)\n\n # Construct the result string and append it to the result list\n result_str = f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\"\n result.append(result_str)\n\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n result = []\n for i, s in enumerate(lst):\n count = sum(int(c) % 2 for c in s)\n element = f\"the number of odd elements {count}n the str{count}ng {count} of the {count}nput.\"\n result.append(element)\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n result = []\n for i, s in enumerate(lst):\n count = sum(1 for c in s if int(c) % 2 != 0)\n result.append(f\"the number of odd elements {count}n the str{count}ng {count} of the {count}nput.\")\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n odd_elements_count = lambda string: sum(1 for char in string if int(char) % 2 != 0)\n result = [\"the number of odd elements {}n the str{}ng {} of the {}nput.\".format(\n odd_elements_count(string),\n odd_elements_count(string),\n odd_elements_count(string),\n odd_elements_count(string)\n ) for string in lst]\n return result", "matching_cluster_idx": 0}, {"solution": "def odd_count(lst):\n result = []\n for i, s in enumerate(lst):\n count = sum(1 for c in s if int(c) % 2 != 0)\n result.append(f\"the number of odd elements {count}n the str{count}ng {count} of the {count}nput.\")\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n result = []\n for i, s in enumerate(lst):\n count = sum([1 for c in s if int(c) % 2 != 0])\n result.append(f\"the number of odd elements {count}n the str{count}ng {count} of the {count}nput.\")\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n result = []\n for i, s in enumerate(lst):\n odd_count = sum(int(c) % 2 for c in s)\n new_string = \"the number of odd elements {}n the str{}ng {} of the {}nput.\".format(odd_count, odd_count, odd_count, odd_count)\n result.append(new_string)\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n # list to store the counts\n counts = []\n\n for i, string in enumerate(lst, start=1):\n # count the odd numbers in the string\n odd_count = sum(int(c) % 2 != 0 for c in string)\n\n # generate the required string and append to counts\n counts.append(\"the number of odd elements {}n the str{}ng {} of the {}nput.\".format(odd_count, odd_count, odd_count, odd_count))\n\n return counts", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"\n Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n result = []\n for idx, string in enumerate(lst):\n odd_digits_count = sum((int(x) % 2 != 0) for x in string)\n element = \"the number of odd elements {}n the str{}ng {} of the {}nput.\".format(\n odd_digits_count,\n odd_digits_count,\n odd_digits_count,\n odd_digits_count\n )\n result.append(element)\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n result = []\n for i, s in enumerate(lst, start=1):\n count = sum(1 for c in s if int(c) % 2 != 0)\n result.append(f\"the number of odd elements {count}n the str{count}ng {count} of the {count}nput.\")\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n result = []\n for index, element in enumerate(lst):\n odd_digits = sum(int(char) % 2 for char in element)\n sentence = f\"the number of odd elements {odd_digits}n the str{odd_digits}ng {odd_digits} of the {odd_digits}nput.\"\n result.append(sentence)\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n def count_odd_digits(s):\n return sum(1 for ch in s if int(ch) % 2 != 0)\n\n result = []\n for i, s in enumerate(lst):\n odd_count = count_odd_digits(s)\n s = s.replace(s, str(odd_count))\n template = \"the number of odd elements {0}n the str{0}ng {0} of the {0}nput.\"\n result.append(template.format(s))\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n def count_odd(num):\n return sum(int(digit) % 2 for digit in num)\n\n return [f\"the number of odd elements {count_odd(s)}n the str{count_odd(s)}ng {count_odd(s)} of the {count_odd(s)}nput.\" for s in lst]", "matching_cluster_idx": 0}, {"solution": "def odd_count(lst):\n output = []\n for i, string in enumerate(lst):\n count = sum(int(char) % 2 for char in string)\n string = \"the number of odd elements {}n the str{}ng {} of the {}nput.\".format(count, count, count, count)\n output.append(string)\n return output", "matching_cluster_idx": 3}]}, "HumanEval/119": {"dps": null, "dps_norm": null, "pass@1": 0.0, "profiled": []}, "HumanEval/120": {"dps": null, "dps_norm": null, "pass@1": 8.0, "profiled": []}, "HumanEval/121": {"dps": 83.2286995515695, "dps_norm": 62.85714285714286, "pass@1": 97.0, "profiled": [{"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n\n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==>0\n \"\"\"\n return sum(x for x in lst[::2] if x % 2 != 0)", "matching_cluster_idx": 5}, {"solution": "def solution(lst):\n return sum(val for idx, val in enumerate(lst) if idx % 2 == 0 and val % 2 != 0)", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n sum = 0\n for i in range(len(lst)):\n if i % 2 == 0 and lst[i] % 2 == 1:\n sum += lst[i]\n return sum", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n return sum(num for idx, num in enumerate(lst) if idx % 2 == 0 and num % 2 != 0)", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n # filter for odd numbers at even positions\n odd_even_numbers = [num for i, num in enumerate(lst) if i % 2 == 0 and num % 2 == 1]\n # calculate sum of filtered odd numbers\n return sum(odd_even_numbers)", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n\n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==>0\n \"\"\"\n # Initialize a variable to store the sum\n sum = 0\n\n # Iterate through the list\n for i in range(0, len(lst), 2):\n # If the element is odd, add it to the sum\n if lst[i] % 2 != 0:\n sum += lst[i]\n\n # Return the sum\n return sum", "matching_cluster_idx": 4}, {"solution": "def solution(lst):\n return sum(val for idx, val in enumerate(lst) if idx % 2 == 0 and val % 2 != 0)", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\"\"\"\n return sum(lst[i] for i in range(0, len(lst), 2) if lst[i] % 2 != 0)", "matching_cluster_idx": 4}, {"solution": "def solution(lst):\n return sum([n for i, n in enumerate(lst) if i % 2 == 0 and n % 2 == 1])", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n \"\"\"\n Given a non-empty list of integers, \n return the sum of all of the odd elements that are in even positions.\n \"\"\"\n return sum(el for idx, el in enumerate(lst) if idx % 2 == 0 and el % 2 != 0)", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n\n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==>0\n \"\"\"\n return sum(el for idx, el in enumerate(lst) if idx % 2 == 0 and el % 2 != 0)", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n \"\"\"\n Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \"\"\"\n return sum([v for i, v in enumerate(lst) if i % 2 == 0 and v % 2 != 0])", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n return sum(el for i, el in enumerate(lst) if i % 2 == 0 and el % 2 != 0)", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==>0\n \"\"\"\n return sum(value for index, value in enumerate(lst) if index % 2 == 0 and value % 2 != 0)", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n\n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==>0\n \"\"\"\n return sum(val for idx, val in enumerate(lst) if idx % 2 == 0 and val % 2 != 0)", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\"\"\"\n return sum(value for index, value in enumerate(lst) if index % 2 == 0 and value % 2 != 0)", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n return sum(elm for i, elm in enumerate(lst) if i % 2 == 0 and elm % 2 != 0)", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n\n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==>0\n \"\"\"\n\n return sum(lst[i] for i in range(0, len(lst), 2) if lst[i] % 2 != 0)", "matching_cluster_idx": 4}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\"\"\"\n return sum(x for x in lst[::2] if x % 2 != 0)", "matching_cluster_idx": 5}, {"solution": "def solution(lst):\n sum = 0\n for i in range(0, len(lst), 2):\n if lst[i] % 2 != 0:\n sum += lst[i]\n return sum", "matching_cluster_idx": 4}]}, "HumanEval/149": {"dps": 96.45669291338584, "dps_norm": 89.28571428571429, "pass@1": 90.0, "profiled": [{"solution": "def sorted_list_sum(lst):\n # Delete strings with odd lengths\n filtered_lst = [x for x in lst if len(x) % 2 == 0]\n \n # Sort the list by length of each word, and then alphabetically\n sorted_lst = sorted(sorted(filtered_lst), key=len)\n \n return sorted_lst", "matching_cluster_idx": 6}, {"solution": "def sorted_list_sum(lst):\n # Delete the strings of odd lengths\n lst = [i for i in lst if len(i) % 2 == 0]\n # Return the list sorted by length and alphabetically\n return sorted(lst, key=lambda x: (len(x), x))", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n # Filtering the list for even length strings\n even_lst = [i for i in lst if len(i) % 2 == 0]\n # Sorting the filtered list first by length and then alphabetically\n even_lst.sort()\n even_lst.sort(key=len)\n return even_lst", "matching_cluster_idx": 6}, {"solution": "def sorted_list_sum(lst):\n # Filter list for strings with even length\n lst = [x for x in lst if len(x) % 2 == 0]\n # Sort the list by length and then alphabetically\n lst.sort()\n lst.sort(key=len)\n return lst", "matching_cluster_idx": 6}, {"solution": "def sorted_list_sum(lst):\n even_length_lst = [word for word in lst if len(word) % 2 == 0]\n even_length_lst.sort()\n return sorted(even_length_lst, key=len)", "matching_cluster_idx": 6}, {"solution": "def sorted_list_sum(lst):\n # deleting strings with odd lengths\n filtered_list = [string for string in lst if len(string) % 2 == 0]\n # sorting the list by length of each word, and then alphabetically\n sorted_list = sorted(sorted(filtered_list), key=len)\n return sorted_list", "matching_cluster_idx": 6}, {"solution": "def sorted_list_sum(lst):\n # Deletes the strings that have odd lengths from list.\n lst = [i for i in lst if len(i) % 2 == 0]\n\n # Sorts the list by length of each word and alphabetically.\n lst = sorted(lst, key=lambda x: (len(x), x))\n\n return lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n # Filter out strings of odd length\n filtered_list = [word for word in lst if len(word) % 2 == 0]\n \n # Sort the list by length first and then alphabetically\n sorted_list = sorted(sorted(filtered_list), key=len)\n \n return sorted_list", "matching_cluster_idx": 6}, {"solution": "def sorted_list_sum(lst):\n # delete the strings that have odd lengths\n lst = [word for word in lst if len(word) % 2 == 0]\n # sort the list by length and alphabetically\n lst.sort()\n lst.sort(key=len)\n return lst", "matching_cluster_idx": 6}, {"solution": "def sorted_list_sum(lst):\n # Filter out strings with odd lengths\n lst = [s for s in lst if len(s) % 2 == 0]\n # Sort list by length of each word, then alphabetically\n lst.sort(key=lambda s: (len(s), s))\n return lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n # Remove strings with odd lengths\n lst = [i for i in lst if len(i) % 2 == 0]\n # Sort by length and then by alphabetical order\n lst.sort()\n lst.sort(key=len)\n return lst", "matching_cluster_idx": 6}, {"solution": "def sorted_list_sum(lst):\n # Remove strings of odd length\n lst = [x for x in lst if len(x) % 2 == 0]\n # Sort the list first by length, then by alphabetical order\n lst.sort()\n lst.sort(key=len)\n return lst", "matching_cluster_idx": 6}, {"solution": "def sorted_list_sum(lst):\n # Filter out words with odd lengths\n filtered = [word for word in lst if len(word) % 2 == 0]\n # Sort by length and then alphabetically\n return sorted(sorted(filtered), key=len)", "matching_cluster_idx": 6}, {"solution": "def sorted_list_sum(lst):\n even_length_words = [word for word in lst if len(word) % 2 == 0]\n sorted_words = sorted(even_length_words, key=lambda word: (len(word), word))\n return sorted_words", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n # Remove the strings with odd lengths\n lst = [x for x in lst if len(x) % 2 == 0]\n\n # Sort the list by length and then alphabetically\n lst.sort()\n lst.sort(key=len)\n\n return lst", "matching_cluster_idx": 6}, {"solution": "def sorted_list_sum(lst):\n # Filter the list to remove strings of odd length\n filtered_lst = [word for word in lst if len(word) % 2 == 0]\n\n # Sort the list by length of each word, and then by alphabetical order\n sorted_lst = sorted(sorted(filtered_lst), key=len)\n\n return sorted_lst", "matching_cluster_idx": 6}, {"solution": "def sorted_list_sum(lst):\n # delete the strings that have odd lengths\n lst = [x for x in lst if len(x) % 2 == 0]\n\n # sort the list first by length and then alphabetically\n lst.sort()\n lst.sort(key=len)\n\n return lst", "matching_cluster_idx": 6}, {"solution": "def sorted_list_sum(lst):\n # Delete the strings that have odd lengths from the list\n lst = [i for i in lst if len(i) % 2 == 0]\n # Sort the list first by length of each word and then by alphabetical order\n lst.sort()\n lst.sort(key=len)\n return lst", "matching_cluster_idx": 6}, {"solution": "def sorted_list_sum(lst):\n even_length_lst = [word for word in lst if len(word) % 2 == 0]\n even_length_lst.sort(key=lambda x: (len(x), x))\n return even_length_lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n # Remove the strings that have odd lengths\n lst = [word for word in lst if len(word) % 2 == 0]\n\n # If two words have the same length, sort the list alphabetically\n lst.sort()\n\n # Sort the list by length of each word\n lst.sort(key=len)\n\n return lst", "matching_cluster_idx": 6}]}, "Mbpp/3": {"dps": 70.29661016949153, "dps_norm": 76.875, "pass@1": 91.0, "profiled": [{"solution": "def is_not_prime(n):\n if n <= 1:\n return True\n elif n <= 3:\n return False\n elif n % 2 == 0 or n % 3 == 0:\n return True\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return True\n i += 6\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n if n <= 1:\n return True\n elif n <= 3:\n return False\n elif n % 2 == 0 or n % 3 == 0:\n return True\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return True\n i += 6\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n if n <= 1:\n return True\n if n == 2:\n return False\n if n % 2 == 0:\n return True\n p = 3\n while p * p <= n:\n if n % p == 0:\n return True\n p += 2\n return False", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(num):\n if num <= 1:\n return True\n for i in range(2, num):\n if num % i == 0:\n return True\n return False", "matching_cluster_idx": 1}, {"solution": "def is_not_prime(n):\n if n <= 1:\n return True\n elif n <= 3:\n return False\n elif n % 2 == 0 or n % 3 == 0:\n return True\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return True\n i += 6\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n if n <= 1:\n return True\n if n <= 3:\n return False\n if n % 2 == 0 or n % 3 == 0:\n return True\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return True\n i += 6\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n if n <= 1:\n return True\n if n <= 3:\n return False\n if n % 2 == 0 or n % 3 == 0:\n return True\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return True\n i += 6\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(num):\n if num <= 1:\n return True\n if num == 2:\n return False\n if num % 2 == 0:\n return True\n for i in range(3, int(num**0.5) + 1, 2):\n if num % i == 0:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n if n <= 1:\n return True\n elif n <= 3:\n return False\n elif n % 2 == 0 or n % 3 == 0:\n return True\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return True\n i += 6\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n if n <= 1:\n return True\n if n == 2:\n return False\n if n % 2 == 0:\n return True\n max_divisor = int(n ** 0.5)\n for d in range(3, 1 + max_divisor, 2):\n if n % d == 0:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n if n <= 1:\n return True\n elif n == 2:\n return False\n else:\n for i in range(2, n):\n if n % i == 0:\n return True\n return False", "matching_cluster_idx": 0}, {"solution": "def is_not_prime(n):\n if n <= 1:\n return True\n elif n == 2:\n return False\n else:\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return True\n return False", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(n):\n if n < 2:\n return True\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return True\n return False", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(n):\n if n < 2:\n return True\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return True\n return False", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(n):\n if n < 2:\n return True\n if n == 2:\n return False\n if n % 2 == 0:\n return True\n max_divisor = int(n**0.5) + 1\n for d in range(3, max_divisor, 2):\n if n % d == 0:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n if n <= 1:\n return True\n elif n <= 3:\n return False\n elif n % 2 == 0 or n % 3 == 0:\n return True\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return True\n i += 6\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n if n <= 1:\n return True\n if n == 2:\n return False\n if n % 2 == 0:\n return True\n max_div = int(n**0.5) + 1\n for i in range(3, max_div, 2):\n if n % i == 0:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n if n <= 1:\n return True\n for i in range(2, n):\n if (n % i) == 0:\n return True\n return False", "matching_cluster_idx": 0}, {"solution": "def is_not_prime(n):\n if n < 2:\n return True\n if n == 2:\n return False\n if n % 2 == 0:\n return True\n i = 3\n while i * i <= n:\n if n % i == 0:\n return True\n i += 2\n return False", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(num):\n \"\"\"\n A function that returns True if the number is not prime and False otherwise.\n\n Args:\n num (int): the number to be evaluated\n\n Returns:\n bool: True if the number is not prime, False otherwise\n \"\"\"\n\n # Non-prime numbers are numbers less than 2\n if num < 2:\n return True\n\n # Prime numbers are only divisible by 1 and themselves, so loop through 2 to num\n for i in range(2, num):\n # If num is divisible by any number in the range, it's not prime\n if num % i == 0:\n return True\n\n # If num has no divisors other than 1 and itself, it is prime\n return False", "matching_cluster_idx": 0}]}, "Mbpp/4": {"dps": 88.05460750853243, "dps_norm": 83.33333333333333, "pass@1": 90.0, "profiled": [{"solution": "import heapq\ndef heap_queue_largest(nums, n):\n return heapq.nlargest(n, nums)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(numbers, n):\n return heapq.nlargest(n, numbers)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n return heapq.nlargest(n, nums)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n # Using heapify to convert list into heap\n heapq.heapify(nums)\n # Using nlargest to get 'n' largest numbers\n largest_nums = heapq.nlargest(n, nums)\n # Returning the 'n' largest numbers in descending order\n return sorted(largest_nums, reverse=True)", "matching_cluster_idx": 8}, {"solution": "import heapq\ndef heap_queue_largest(numbers, n):\n return heapq.nlargest(n, numbers)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n return heapq.nlargest(n, nums)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(numbers, n):\n return heapq.nlargest(n, numbers)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(numbers, n):\n # heapq module provides an implementation of the heap queue algorithm, \n # also known as the priority queue algorithm. \n # We use negative of number to convert max heap to min heap as Python heapq provides min heap by default.\n max_heap = [-x for x in numbers]\n heapq.heapify(max_heap)\n \n # Extract n largest integers\n largest_numbers = [-heapq.heappop(max_heap) for _ in range(n)]\n return largest_numbers\nnumbers = [25, 35, 22, 85, 14, 65, 75, 22, 58]\nn = 3", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(numbers_list, n):\n return heapq.nlargest(n, numbers_list)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(numbers, n):\n # use heapq.nlargest to get the n largest numbers and then reverse the list to get in descending order\n return sorted(heapq.nlargest(n, numbers), reverse=True)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n return heapq.nlargest(n, nums)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n return heapq.nlargest(n, nums)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n return heapq.nlargest(n, nums)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(numbers, n):\n # Use nlargest from heapq module to find n largest integers\n return heapq.nlargest(n, numbers)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(numbers, n):\n if n > len(numbers):\n raise ValueError('n is larger than the length of numbers')\n \n # Use heapq to turn list into a heap, in ascending order\n # The minus sign is used to make a max-heap as min-heap is default in python\n largest_numbers = heapq.nlargest(n, numbers)\n \n # The returned values are sorted in descending order, as requested\n return sorted(largest_numbers, reverse=True)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n # Use heapq.nlargest() to get the 'n' largest numbers in the list\n largest_nums = heapq.nlargest(n, nums)\n # Return the numbers in descending order\n return sorted(largest_nums, reverse=True)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(numbers, n):\n # Converting to a heap\n heapq.heapify(numbers)\n # Extracting largest n elements in descending order\n largest_numbers = heapq.nlargest(n, numbers)\n largest_numbers.sort(reverse=True)\n return largest_numbers", "matching_cluster_idx": 8}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n # Use heapq library's nlargest function\n largest_nums = heapq.nlargest(n, nums)\n # Sort the list in descending order\n largest_nums.sort(reverse=True)\n return largest_nums", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(numbers, n):\n # Use the heapq module to create a heap, this will convert the iterable into a heap data structure.\n # The smallest element is at the front.\n heap = heapq.nlargest(n, numbers)\n # Use the heapify function to convert an iterable into a heap.\n # This is efficient because it places the smallest item at the root of the heap.\n heapq.heapify(heap)\n # Return the heap in descending order\n return sorted(heap, reverse=True)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(num_list, n):\n # Use heapq to turn list into a max heap\n heapq._heapify_max(num_list)\n\n # Pop off and append largest n elements into a new list\n result = [heapq._heappop_max(num_list) for _ in range(n)]\n\n return result", "matching_cluster_idx": 11}]}, "Mbpp/9": {"dps": 64.421768707483, "dps_norm": 53.0, "pass@1": 25.0, "profiled": [{"solution": "def find_Rotations(s: str) -> int:\n n = len(s)\n temp = s + s\n\n for i in range(1, n):\n if temp[i:i+n] == s:\n return i\n\n return n", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(s: str) -> int:\n n = len(s)\n for i in range(1, n):\n if s[i:] + s[:i] == s:\n return i\n return n", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(s):\n for i in range(1, len(s)):\n if s[i:] + s[:i] == s:\n return i\n return len(s)", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(string: str) -> int:\n \"\"\"\n This function finds the minimum number of rotations required to get the same string.\n \"\"\"\n\n # Check if string is not empty\n if string and len(string) > 1:\n # Concatenating the string\n string = string + string\n # Finding the length of the concatenated string\n length = len(string)\n\n # Finding the next character of the prefix\n failure = [0] * length\n j = 1\n i = 0\n while j < length:\n if string[i] == string[j]:\n failure[j] = i + 1\n i += 1\n j += 1\n elif i > 0:\n i = failure[i - 1]\n else:\n j += 1\n\n # Find minimum rotation\n min_rotation = len(string) - failure[-1]\n\n # If length is multiple of min_rotation, then return 1\n if len(string) % min_rotation == 0:\n return min_rotation\n\n return 0 # If string is empty or has only one character", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(s: str) -> int:\n for i in range(1, len(s)):\n if s == s[i:] + s[:i]:\n return i\n return len(s)", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(s: str) -> int:\n n = len(s)\n for i in range(1, n):\n if s[i:] + s[:i] == s:\n return i\n return n", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(s: str) -> int:\n n = len(s)\n for i in range(1, n):\n if s[i:] + s[:i] == s:\n return i\n return n", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(str1):\n # compute temporary string\n temp = str1 + str1\n\n # find length of original string\n n = len(str1)\n \n # find minimum rotation by comparing\n # string with temp string\n for i in range(1, n+1):\n if (temp[i:i+n] == str1):\n return i\n return n", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(s: str) -> int:\n n = len(s)\n temp = s + s\n # For concatenation, we need to make sure that\n # there is no rotation of the string which gives us\n # the original string as a substring.\n # This means, we are looking for the smallest non-1\n # factor of length of the string.\n for i in range(1, n):\n if temp[i:i+n] == s:\n return i\n return n # In case of no rotation", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(string):\n length = len(string)\n if length <= 1:\n return 0\n for rotation in range(1, length):\n if string[rotation:] + string[:rotation] == string:\n return rotation\n return length", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(s):\n n = len(s)\n temp = s + s\n for i in range(1, n):\n if temp[i:i+n] == s:\n return i\n return n", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(string):\n n = len(string)\n for i in range(1, n):\n if string[i:] + string[:i] == string:\n return i\n return n", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(str):\n # Get the length of the string\n n = len(str)\n \n # Create a concatenated string\n temp = str + str\n \n # Set initial minimum rotation as maximum possible value\n min_rotation = float('inf')\n \n # Find the rotation\n for i in range(1, n+1):\n # For each i, compare the substring with the original string\n # If they are the same, get the rotation number\n if str == temp[i:i+n]:\n min_rotation = min(min_rotation, i)\n \n # Return the minimum rotation\n return min_rotation", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(s):\n \"\"\"\n This function finds the minimum number of rotations (greater than 0) required to get the same string.\n \"\"\"\n rotation = 1\n while rotation <= len(s):\n if s[rotation:] + s[:rotation] == s:\n return rotation\n rotation += 1\n return len(s)", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(string: str) -> int:\n if string == \"\":\n return 0\n else:\n # Check how many rotations are needed to get the same string\n for i in range(1, len(string)):\n if string[i:] + string[:i] == string:\n return i\n # If no rotation was needed, return the length of the string\n return len(string)", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(s: str) -> int:\n \"\"\"\n A function that finds the minimum number of rotations to get the same string.\n\n Parameters:\n s (str): The input string.\n\n Returns:\n int: The minimum number of rotations.\n \"\"\"\n n = len(s)\n for i in range(1, n):\n if s[i:] + s[:i] == s:\n return i\n return n", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(input_string):\n length = len(input_string)\n for i in range(1, length):\n if input_string[i:] + input_string[:i] == input_string:\n return i\n return length", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(input_string: str) -> int:\n # check if input string is empty or contains only one character\n if len(input_string) <= 1:\n return 0\n\n # rotate the string and compare it with the original string\n for i in range(1, len(input_string)):\n # if string is same after rotation, return the number of rotations\n if input_string == input_string[i:] + input_string[:i]:\n return i\n\n # if no rotation gives the same string, return the length of the string\n return len(input_string)", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(str_input):\n str_size = len(str_input)\n for i in range(1, str_size):\n # splitting the original string into two parts at ith position\n split_str = str_input[i:str_size] + str_input[0:i]\n # checking if it's rotation of original string\n if split_str == str_input:\n return i # Return the rotation count\n return str_size # If no rotation found return string size", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(s: str) -> int:\n \"\"\"\n Function to find the minimum number of rotations\n required to get the same string\n \"\"\"\n rotation_count = 0\n original = s\n\n while True:\n s = s[1:] + s[0] # rotate string\n rotation_count += 1 # increment rotation counter\n\n if s == original: # if string is same as original, return rotation count\n return rotation_count", "matching_cluster_idx": 5}]}, "Mbpp/11": {"dps": 74.05017921146954, "dps_norm": 87.77777777777777, "pass@1": 58.0, "profiled": [{"solution": "def remove_Occ(s, ch):\n first_idx = s.find(ch) # find the first occurrence of ch\n if first_idx != -1: # if ch is present in s\n last_idx = s.rfind(ch) # find the last occurrence of ch\n # remove the first and last occurrence of ch from s\n s = s[:first_idx] + s[first_idx+1:last_idx] + s[last_idx+1:]\n return s", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(input_string, character):\n first_Occ = input_string.find(character)\n if first_Occ != -1:\n input_string = input_string[:first_Occ] + input_string[first_Occ+1:]\n last_Occ = input_string.rfind(character)\n if last_Occ != -1:\n input_string = input_string[:last_Occ] + input_string[last_Occ+1:]\n return input_string", "matching_cluster_idx": 7}, {"solution": "def remove_Occ(s, ch):\n s = list(s)\n for i in range(len(s)):\n if s[i] == ch:\n s[i] = ''\n break\n for i in range(len(s) - 1, -1, -1):\n if s[i] == ch:\n s[i] = ''\n break\n return ''.join(s)", "matching_cluster_idx": 2}, {"solution": "def remove_Occ(str1, char1):\n # Initialize first and last indexes with -1\n first_index = last_index = -1\n \n # Find first and last occurrences of the given character\n for i in range(len(str1)):\n if str1[i] == char1:\n if first_index == -1: # For first occurrence\n first_index = i\n last_index = i # For last occurrence\n \n # If character is not found in string\n if first_index == -1:\n return str1\n\n # Remove first and last occurrences of the character from string\n str1 = str1[:first_index] + str1[first_index+1:last_index] + str1[last_index+1:]\n\n return str1", "matching_cluster_idx": 0}, {"solution": "def remove_Occ(s, c):\n # finding the first and the last occurrence of a given character in the string\n first_occurrence = s.find(c)\n last_occurrence = s.rfind(c)\n\n # checking if the character exists in the string\n if first_occurrence != -1 and last_occurrence != -1:\n # removing first and last occurrence of a character from the string\n s = s[:first_occurrence] + s[first_occurrence+1:last_occurrence] + s[last_occurrence+1:]\n return s", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(s, c):\n first_index = s.find(c)\n if first_index != -1:\n last_index = s.rfind(c)\n return s[:first_index] + s[first_index+1:last_index] + s[last_index+1:]\n else:\n return s", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(str, ch):\n first_occurance = str.find(ch)\n if first_occurance == -1:\n return str\n last_occurance = str.rfind(ch)\n if first_occurance == last_occurance:\n return str[:first_occurance] + str[first_occurance+1:]\n else:\n return str[:first_occurance] + str[first_occurance+1:last_occurance] + str[last_occurance+1:]", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(str, char):\n first_Occ = str.find(char)\n if first_Occ == -1:\n return str\n last_Occ = str.rfind(char)\n return str[:first_Occ] + str[first_Occ+1:last_Occ] + str[last_Occ+1:]", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(string, char):\n first_index = string.find(char)\n if first_index != -1: # character is found\n last_index = string.rfind(char)\n string = string[:first_index] + string[first_index+1:last_index] + string[last_index+1:]\n return string", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(s, ch):\n first_occur = s.find(ch)\n last_occur = s.rfind(ch)\n \n if first_occur == -1:\n return s\n \n return s[:first_occur] + s[first_occur+1:last_occur] + s[last_occur+1:]", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(s, c):\n \"\"\"\n Removes the first and last occurrence of a given character from a string.\n\n Parameters:\n s (str): The string from which to remove the first and last occurrence of a character.\n c (char): The character to remove from the string.\n\n Returns:\n str: The modified string with the first and last occurrence of the character removed.\n \"\"\"\n # Finding the first and last occurrence of the character in the string\n first_occurrence = s.find(c)\n last_occurrence = s.rfind(c)\n\n # If the character is not in the string, return the original string\n if first_occurrence == -1:\n return s\n\n # Removing the first and last occurrence of the character from the string\n s = s[:first_occurrence] + s[first_occurrence+1:last_occurrence] + s[last_occurrence+1:]\n\n return s", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(string, char):\n first_index = string.find(char)\n if first_index != -1:\n string = string[:first_index] + string[first_index+1:]\n last_index = string.rfind(char)\n if last_index != -1:\n string = string[:last_index] + string[last_index+1:]\n return string", "matching_cluster_idx": 7}, {"solution": "def remove_Occ(str, char):\n first_Occ = str.find(char)\n if first_Occ == -1:\n return str\n last_Occ = str.rfind(char)\n return str[:first_Occ] + str[first_Occ+1:last_Occ] + str[last_Occ+1:]", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(s, ch):\n first_Occ = s.find(ch)\n if first_Occ == -1:\n return s\n last_Occ = s.rfind(ch)\n return s[:first_Occ] + s[first_Occ+1:last_Occ] + s[last_Occ+1:]", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(input_string, char_to_remove):\n first_idx = input_string.find(char_to_remove)\n last_idx = input_string.rfind(char_to_remove)\n\n if first_idx != -1 and last_idx != -1 and first_idx != last_idx:\n return input_string[:first_idx] + input_string[first_idx+1:last_idx] + input_string[last_idx+1:]\n elif first_idx != -1:\n return input_string[:first_idx] + input_string[first_idx+1:]\n elif last_idx != -1:\n return input_string[:last_idx] + input_string[last_idx+1:]\n else:\n return input_string", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(string, char):\n first_index = string.find(char) # find the first occurrence\n if first_index != -1: # if character is found\n string = string[:first_index] + string[first_index+1:] # remove first occurrence\n last_index = string.rfind(char) # find the last occurrence\n if last_index != -1: # if character is found\n string = string[:last_index] + string[last_index+1:] # remove last occurrence\n return string", "matching_cluster_idx": 7}, {"solution": "def remove_Occ(s, c):\n first_index = s.find(c)\n last_index = s.rfind(c)\n if first_index != -1 and last_index != -1 and first_index != last_index:\n return s[:first_index] + s[first_index+1:last_index] + s[last_index+1:]\n elif first_index != -1:\n return s[:first_index] + s[first_index+1:]\n elif last_index != -1:\n return s[:last_index] + s[last_index+1:]\n else:\n return s", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(s, char):\n # Finding first and last occurrence of the character in the string\n first_occurrence = s.find(char)\n last_occurrence = s.rfind(char)\n \n # If character is not found in the string, returning original string\n if first_occurrence == -1:\n return s\n\n # If first and last occurrences are the same, removing only one occurrence \n if first_occurrence == last_occurrence:\n return s[:first_occurrence] + s[first_occurrence+1:]\n \n # If first and last occurrences are different, removing both occurrences\n return s[:first_occurrence] + s[first_occurrence+1:last_occurrence] + s[last_occurrence+1:]", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(s, ch):\n # Checking if the character is present in the string\n if ch in s:\n # Removing first and last occurrence of the character\n s = s.replace(ch, '', 1) # Replace first occurrence\n s = s[::-1] # Reverse the string\n s = s.replace(ch, '', 1) # Remove the last occurrence of the character\n s = s[::-1] # Reverse back to original order\n return s", "matching_cluster_idx": 3}, {"solution": "def remove_Occ(string, char):\n # getting first and last occurrence of character\n first_occur = string.find(char)\n last_occur = string.rfind(char)\n\n # checking if character is present in string\n if first_occur == -1 or last_occur == -1:\n return string # return string if character is not present\n\n # removing first and last occurrence of character\n string = string[:first_occur] + string[first_occur+1:last_occur] + string[last_occur+1:]\n\n return string", "matching_cluster_idx": 8}]}, "Mbpp/12": {"dps": 95.71428571428571, "dps_norm": 99.6875, "pass@1": 97.0, "profiled": [{"solution": "def sort_matrix(matrix):\n sum_row = [sum(row) for row in matrix]\n zipped = list(zip(matrix, sum_row))\n zipped.sort(key=lambda x: x[1])\n return [row[0] for row in zipped]", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n return sorted(matrix, key=sum)", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(mat):\n mat.sort(key=sum)\n return mat", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(mat):\n return sorted(mat, key=sum)", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n sum_rows = [sum(row) for row in matrix]\n sorted_matrix = [x for _,x in sorted(zip(sum_rows, matrix))]\n return sorted_matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Calculate the sum of each row and store it in a tuple (sum, row)\n sums = [(sum(row), row) for row in matrix]\n \n # Sort the list of tuples by the first element of each tuple (i.e., the sum)\n sums.sort()\n \n # Extract the rows in the correct order\n sorted_matrix = [row for _, row in sums]\n \n return sorted_matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n return sorted(matrix, key=sum)", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Calculate sums of rows and sort by them\n sorted_indices = sorted(range(len(matrix)), key=lambda i: sum(matrix[i]))\n sorted_matrix = [matrix[i] for i in sorted_indices]\n return sorted_matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n return sorted(matrix, key=sum)", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"\n Sorts a given matrix in ascending order according to the sum of its rows.\n \"\"\"\n return sorted(matrix, key=sum)", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Create a list to hold the sum of each row and the corresponding index\n sum_list = [(sum(row), i) for i, row in enumerate(matrix)]\n # Sort the list of sums\n sum_list.sort()\n # Create a new sorted matrix by using the indices of the original matrix\n sorted_matrix = [matrix[i] for _, i in sum_list]\n return sorted_matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n return sorted(matrix, key=sum)", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"\n This function takes a matrix and returns a new matrix sorted in ascending order of the sums of its rows.\n \"\"\"\n # Calculate the sum for each row\n sums_list = [sum(row) for row in matrix]\n # Zip together the row sums with the original rows\n zipped_matrix = list(zip(sums_list, matrix))\n # Sort the zipped list and get back the rows\n sorted_matrix = [row for _, row in sorted(zipped_matrix)]\n return sorted_matrix", "matching_cluster_idx": 14}, {"solution": "def sort_matrix(matrix):\n return sorted(matrix, key=sum)", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(mat):\n return sorted(mat, key=sum)", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n return sorted(matrix, key=sum)\nmatrix = [[1, 2, 3], [2, 4, 5], [1, 1, 1]]", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"Sorts the matrix rows based on the sum of their values.\"\"\"\n return sorted(matrix, key=sum)", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n return sorted(matrix, key=sum)", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n return sorted(matrix, key=sum)", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n return sorted(matrix, key=sum)", "matching_cluster_idx": 15}]}, "Mbpp/16": {"dps": 57.4390243902439, "dps_norm": 75.0, "pass@1": 40.0, "profiled": [{"solution": "import re\ndef text_lowercase_underscore(input_string):\n pattern = r'^[a-z]+(_[a-z]+)*$'\n if re.match(pattern, input_string):\n return True\n else:\n return False", "matching_cluster_idx": 7}, {"solution": "def text_lowercase_underscore(s: str) -> bool:\n split_strings = s.split(\"_\")\n for string in split_strings:\n if not string.islower():\n return False\n return True", "matching_cluster_idx": 5}, {"solution": "import re\ndef text_lowercase_underscore(s):\n pattern = '^[a-z]+(_[a-z]+)*$'\n if re.fullmatch(pattern, s):\n return True\n else:\n return False", "matching_cluster_idx": 7}, {"solution": "def text_lowercase_underscore(text):\n # Split the text into words\n words = text.split(\"_\")\n # For each word check if it is all in lower case and consists of letters only.\n # If all words pass this condition, return True, otherwise False\n return all(word.islower() and word.isalpha() for word in words)", "matching_cluster_idx": 4}, {"solution": "def text_lowercase_underscore(s):\n words = s.split(\"_\")\n for word in words:\n if not word.islower():\n return False\n return True", "matching_cluster_idx": 5}, {"solution": "import re\ndef text_lowercase_underscore(text):\n pattern = \"^[a-z]+(_[a-z]+)*$\"\n if re.search(pattern, text):\n return True\n else:\n return False", "matching_cluster_idx": 3}, {"solution": "def text_lowercase_underscore(input_string):\n split_string = input_string.split('_')\n for sequence in split_string:\n if not sequence.islower():\n return False\n return True", "matching_cluster_idx": 5}, {"solution": "def text_lowercase_underscore(text):\n # Split the text into words\n words = text.split(\"_\")\n # Check each word if it only contains lowercase letters\n for word in words:\n if not word.islower():\n return False\n return True", "matching_cluster_idx": 5}, {"solution": "def text_lowercase_underscore(s):\n # Split the string into a list of words\n words = s.split(\"_\")\n \n # Check each word in the list\n for word in words:\n # If any word is not entirely in lowercase, return False\n if not word.islower():\n return False\n \n # If no non-lowercase word is found, return True\n return True", "matching_cluster_idx": 5}, {"solution": "def text_lowercase_underscore(s):\n for word in s.split(\"_\"):\n if not word.islower():\n return False\n return True", "matching_cluster_idx": 5}, {"solution": "import re\ndef text_lowercase_underscore(input_str):\n # regex check for sequences of lowercase letters joined with an underscore\n pattern = \"^[a-z]+(_[a-z]+)*$\"\n if re.match(pattern, input_str):\n return True\n else:\n return False", "matching_cluster_idx": 7}, {"solution": "def text_lowercase_underscore(s):\n \"\"\"\n This function checks if the input string contains sequences of lowercase letters\n joined with an underscore.\n \"\"\"\n split_text = s.split(\"_\")\n for text in split_text:\n if not text.islower() or not text.isalpha():\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "import re\ndef text_lowercase_underscore(s):\n pattern = \"^[a-z]+(_[a-z]+)*$\"\n if(re.search(pattern, s)):\n return True\n else:\n return False", "matching_cluster_idx": 3}, {"solution": "def text_lowercase_underscore(s):\n parts = s.split('_')\n return all(part.islower() and part.isalpha() for part in parts)", "matching_cluster_idx": 4}, {"solution": "import re\ndef text_lowercase_underscore(text):\n pattern = r'^[a-z]+(_[a-z]+)*$'\n return bool(re.match(pattern, text))", "matching_cluster_idx": 7}, {"solution": "def text_lowercase_underscore(txt):\n words = txt.split('_')\n for word in words:\n if not word.islower() or not word.isalpha():\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def text_lowercase_underscore(text):\n # Split the text into segments using '_' as the separator\n segments = text.split(\"_\")\n\n # For each segment, check if it consists only of lowercase letters\n for segment in segments:\n if not segment.islower():\n return False\n\n return True", "matching_cluster_idx": 5}, {"solution": "def text_lowercase_underscore(s):\n # split string into words\n words = s.split(\"_\")\n\n # check if all words are in lowercase\n return all(word.islower() for word in words)", "matching_cluster_idx": 5}, {"solution": "def text_lowercase_underscore(s):\n split_string = s.split(\"_\")\n for sub_str in split_string:\n if not sub_str.islower():\n return False\n return True", "matching_cluster_idx": 5}, {"solution": "def text_lowercase_underscore(input_string):\n split_string = input_string.split(\"_\")\n for word in split_string:\n if not word.islower():\n return False\n return True", "matching_cluster_idx": 5}]}, "Mbpp/19": {"dps": 66.41414141414141, "dps_norm": 81.0, "pass@1": 100.0, "profiled": [{"solution": "def test_duplicate(arr):\n return len(arr) != len(set(arr))", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(input_list):\n \"\"\"\n This function takes a list of integers and checks if there are any duplicates.\n It returns True if there are duplicates and False if there are no duplicates.\n \"\"\"\n if len(input_list) == len(set(input_list)):\n return False\n else:\n return True", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(arr):\n return len(arr) != len(set(arr))", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(array):\n if len(array) == len(set(array)):\n return False\n else:\n return True", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(arr):\n \"\"\"This function checks for duplicate elements in the given list\"\"\"\n if len(arr) == len(set(arr)):\n return False\n else:\n return True", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(array):\n if len(array) == len(set(array)):\n return False\n else:\n return True", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(arr):\n # Using a set to store the elements of the list.\n # Set does not allow duplicate elements,\n # so if the length of the set and the list is not the same, \n # it means that there are duplicate elements in the list.\n if len(arr) == len(set(arr)):\n return False\n else:\n return True", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(numbers):\n if len(numbers) == len(set(numbers)):\n return False\n else:\n return True", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(nums):\n if len(nums) == len(set(nums)):\n return False\n else:\n return True", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(lst):\n return len(lst) != len(set(lst))", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(lst):\n return len(lst) != len(set(lst))", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(array):\n seen = set()\n for num in array:\n if num in seen:\n return True\n seen.add(num)\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(nums):\n if len(nums) == len(set(nums)):\n return False\n else:\n return True", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(arr):\n return len(arr) != len(set(arr))", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(lst):\n return len(lst) != len(set(lst))", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(lst):\n return len(lst) != len(set(lst))", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(arr):\n if len(arr) == len(set(arr)):\n return False\n else:\n return True", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(arr):\n \"\"\"\n This function checks if a given list of integers contains any duplicate element.\n If there is a duplicate, it returns True; otherwise, it returns False.\n\n :param arr: a list of integers\n :return: a boolean indicating whether there are duplicate elements\n \"\"\"\n if len(arr) == len(set(arr)):\n return False\n else:\n return True", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(array):\n \"\"\"\n This function checks if there are any duplicate elements in the given list.\n\n Parameters:\n array (list): A list of integers\n\n Returns:\n bool: True if there are duplicate elements, False otherwise\n \"\"\"\n return len(array) != len(set(array))", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(array):\n \"\"\"\n Function to check if any element is repeated in a given array of integers.\n\n :param array: List of integers.\n :return: True if any element is repeated, False otherwise.\n \"\"\"\n return len(array) != len(set(array))", "matching_cluster_idx": 11}]}, "Mbpp/62": {"dps": 97.0, "dps_norm": 98.0, "pass@1": 100.0, "profiled": [{"solution": "def smallest_num(num_list):\n return min(num_list)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(num_list):\n \"\"\"\n This function takes a list of numbers as an argument, finds and returns the smallest number in the list.\n \"\"\"\n return min(num_list)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(lst):\n return min(lst)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(num_list):\n \"\"\"\n Function to find smallest number in a list.\n \"\"\"\n return min(num_list)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(lst):\n return min(lst)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(num_list):\n return min(num_list)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(num_list):\n \"\"\"\n This function takes a list of numbers as input and returns the smallest number in the list.\n \"\"\"\n\n # Checking if the list is empty. If so, returning None.\n if not num_list:\n return None\n\n # Initializing the smallest number as the first number in the list.\n smallest = num_list[0]\n\n # Going through the rest of the list.\n for num in num_list:\n\n # If the current number is smaller than the current smallest, \n # update the smallest number.\n if num < smallest:\n smallest = num\n \n # Return the smallest number.\n return smallest", "matching_cluster_idx": 3}, {"solution": "def smallest_num(lst):\n return min(lst)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(lst):\n return min(lst)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(lst):\n \"\"\"\n This function finds the smallest number in a list.\n Args:\n lst: list of integers\n \n Returns:\n smallest_num: smallest integer in the list\n \"\"\"\n smallest_num = min(lst)\n return smallest_num", "matching_cluster_idx": 4}, {"solution": "def smallest_num(lst):\n \"\"\"\n This function takes a list of integers as input and returns the smallest number in the list.\n \"\"\"\n # Initialize min_num as the first element in the list\n min_num = lst[0]\n \n # Iterate through each element in the list\n for num in lst:\n # If the current element is smaller than min_num, update min_num\n if num < min_num:\n min_num = num\n \n # Return the smallest number\n return min_num", "matching_cluster_idx": 3}, {"solution": "def smallest_num(lst):\n return min(lst)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(num_list):\n return min(num_list)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(lst):\n return min(lst)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(num_list):\n return min(num_list)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(lst):\n \"\"\"\n This function takes a list of numbers as input and returns the smallest number in the list.\n \"\"\"\n return min(lst)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(numbers):\n return min(numbers)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(lst):\n \"\"\"\n This function takes a list of numbers as input and returns the smallest number.\n \"\"\"\n return min(lst)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(num_list):\n return min(num_list)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(lst):\n return min(lst)", "matching_cluster_idx": 4}]}, "Mbpp/75": {"dps": 93.21428571428572, "dps_norm": 68.33333333333334, "pass@1": 100.0, "profiled": [{"solution": "def find_tuples(tuples_list, k):\n result = []\n for t in tuples_list:\n if all(i % k == 0 for i in t):\n result.append(t)\n return result\ntuples_list = [(6, 24, 12), (7, 9, 6), (12, 18, 21)]\nk = 6", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n result = []\n for t in tuples_list:\n if all(x % k == 0 for x in t):\n result.append(t)\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n result = []\n for t in tuples_list:\n if all(i % k == 0 for i in t):\n result.append(t)\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(lst, k):\n result = []\n for t in lst:\n if all(i % k == 0 for i in t):\n result.append(t)\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n result = []\n for tpl in tuples_list:\n if all(i % k == 0 for i in tpl):\n result.append(tpl)\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n result = []\n for tup in tuples_list:\n if all(el % k == 0 for el in tup):\n result.append(tup)\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(list_of_tuples, k):\n return [t for t in list_of_tuples if all(i % k == 0 for i in t)]", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n result = [t for t in tuples_list if all(e % k == 0 for e in t)]\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(lst, k):\n def all_divisible(tpl, k):\n return all(i % k == 0 for i in tpl)\n\n return [tpl for tpl in lst if all_divisible(tpl, k)]", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n # Filter the list using a custom function to check if all elements of a tuple are divisible by k\n result = [t for t in tuples_list if all(x % k == 0 for x in t)]\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n result = [t for t in tuples_list if all(x % k == 0 for x in t)]\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(lst, k):\n # Initialize an empty list to store the results\n result = []\n \n # Iterate over the input list of tuples\n for t in lst:\n # Iterate over the elements in each tuple\n for elem in t:\n # If the element is not divisible by k, break the loop and move on to the next tuple\n if elem % k != 0:\n break\n # If we've gotten this far without breaking, that means all elements in the tuple are divisible by k\n else:\n # Add the tuple to the results list\n result.append(t)\n \n # Return the list of results\n return result", "matching_cluster_idx": 8}, {"solution": "def find_tuples(tuples_list, k):\n \"\"\"\n This function finds tuples which have all elements divisible by k from the given list of tuples.\n \"\"\"\n result = []\n for tup in tuples_list:\n if all(i % k == 0 for i in tup):\n result.append(tup)\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tup_list, k):\n return [tup for tup in tup_list if all(el % k == 0 for el in tup)]", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n result = [t for t in tuples_list if all(x % k == 0 for x in t)]\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n result = []\n for tpl in tuples_list:\n if all(el % k == 0 for el in tpl):\n result.append(tpl)\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n result = [t for t in tuples_list if all(e % k == 0 for e in t)]\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n result = [t for t in tuples_list if all(i % k == 0 for i in t)]\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples, k):\n result = [t for t in tuples if all(x % k == 0 for x in t)]\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples, k):\n result = [t for t in tuples if all(x % k == 0 for x in t)]\n return result", "matching_cluster_idx": 5}]}, "Mbpp/88": {"dps": 96.56862745098039, "dps_norm": 85.71428571428571, "pass@1": 100.0, "profiled": [{"solution": "def freq_count(lst):\n freqs = {}\n for item in lst:\n if (item in freqs):\n freqs[item] += 1\n else:\n freqs[item] = 1\n return freqs", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n frequency = {}\n for item in lst:\n if (item in frequency):\n frequency[item] += 1\n else:\n frequency[item] = 1\n return frequency", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n frequency = {}\n for item in lst:\n if (item in frequency):\n frequency[item] += 1\n else:\n frequency[item] = 1\n return frequency", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n freq_dict = {}\n for i in lst:\n if i in freq_dict:\n freq_dict[i] += 1\n else:\n freq_dict[i] = 1\n return freq_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n # create an empty dictionary\n count_dict = {}\n \n # iterate over each element in the list\n for elem in lst:\n if elem in count_dict:\n # if the element is already in the dictionary, increase its count\n count_dict[elem] += 1\n else:\n # if the element is not in the dictionary, add it with a count of 1\n count_dict[elem] = 1\n \n # return the resulting dictionary\n return count_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n count_dict = {}\n for i in lst:\n if i in count_dict:\n count_dict[i] += 1\n else:\n count_dict[i] = 1\n return count_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(input_list):\n freq_dict = {}\n for item in input_list:\n if item in freq_dict:\n freq_dict[item] += 1\n else:\n freq_dict[item] = 1\n return freq_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n freq_dict = {}\n for i in lst:\n if i in freq_dict:\n freq_dict[i] += 1\n else:\n freq_dict[i] = 1\n return freq_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n \"\"\"\n Function to get the frequency of all the elements in a list\n \"\"\"\n # Create an empty dictionary\n freq_dict = {}\n # Loop through the list\n for i in lst:\n # If the element is in the dictionary, increment the count\n if i in freq_dict:\n freq_dict[i] += 1\n # If the element is not in the dictionary, add it with count 1\n else:\n freq_dict[i] = 1\n return freq_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n freq_dict = {}\n for item in lst:\n if item in freq_dict:\n freq_dict[item] += 1\n else:\n freq_dict[item] = 1\n return freq_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n freqs = {}\n for item in lst:\n if item in freqs:\n freqs[item] += 1\n else:\n freqs[item] = 1\n return freqs", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n freq_dict = {}\n for item in lst:\n if item in freq_dict:\n freq_dict[item] += 1\n else:\n freq_dict[item] = 1\n return freq_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n frequency = {}\n for i in lst:\n if i in frequency:\n frequency[i] += 1\n else:\n frequency[i] = 1\n return frequency", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n freq_dict = {}\n for i in lst:\n if i in freq_dict:\n freq_dict[i] += 1\n else:\n freq_dict[i] = 1\n return freq_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n freqs = {}\n for el in lst:\n if el in freqs:\n freqs[el] += 1\n else:\n freqs[el] = 1\n return freqs", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n freqs = {}\n for el in lst:\n if el in freqs:\n freqs[el] += 1\n else:\n freqs[el] = 1\n return freqs", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n freqs = {}\n for num in lst:\n if num in freqs:\n freqs[num] += 1\n else:\n freqs[num] = 1\n return freqs", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n freqs = {}\n for item in lst:\n if item in freqs:\n freqs[item] += 1\n else:\n freqs[item] = 1\n return freqs", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n freqs = {}\n for i in lst:\n if i in freqs:\n freqs[i] += 1\n else:\n freqs[i] = 1\n return freqs", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n freqs = {}\n for elem in lst:\n if elem in freqs:\n freqs[elem] += 1\n else:\n freqs[elem] = 1\n return freqs", "matching_cluster_idx": 5}]}, "Mbpp/90": {"dps": 79.51219512195122, "dps_norm": 85.71428571428571, "pass@1": 26.0, "profiled": [{"solution": "def len_log(words):\n return max(len(word) for word in words)", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n #initialize maximum length to 0\n max_len = 0\n\n #iterate through each word in the list\n for word in words:\n #if the length of the current word is greater than max_len, update max_len\n if len(word) > max_len:\n max_len = len(word)\n\n return max_len", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n return max(len(word) for word in words)", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n \"\"\"\n This function takes a list of words and returns the length of the longest word.\n \"\"\"\n return max(len(word) for word in words)", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n \"\"\"\n This function takes a list of words and returns the length of the longest word.\n \"\"\"\n # Initialize max_length to 0\n max_length = 0\n\n # For each word in the list\n for word in words:\n # If the length of the current word is greater than max_length\n if len(word) > max_length:\n # Update max_length to the length of the current word\n max_length = len(word)\n\n # Return the maximum length\n return max_length", "matching_cluster_idx": 5}, {"solution": "def len_log(lst):\n return max(len(word) for word in lst)", "matching_cluster_idx": 5}, {"solution": "def len_log(words_list):\n # Initialize maximum length to 0\n max_length = 0\n # Loop through each word in the list\n for word in words_list:\n # If the length of the current word is greater than max_length, update max_length\n if len(word) > max_length:\n max_length = len(word)\n # Return the longest word length\n return max_length", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n return max(len(word) for word in words)", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n return max(len(word) for word in words)", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n return max(len(word) for word in words)", "matching_cluster_idx": 5}, {"solution": "def len_log(word_list):\n return max(len(word) for word in word_list)", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n return max(len(word) for word in words)", "matching_cluster_idx": 5}, {"solution": "def len_log(word_list):\n return max(len(word) for word in word_list)", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n return max(len(word) for word in words)", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n return max(len(word) for word in words)", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n return max(len(word) for word in words)", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n return max(len(word) for word in words)", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n return max(len(word) for word in words)", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n return max(len(word) for word in words)", "matching_cluster_idx": 5}, {"solution": "def len_log(words_list):\n return max(len(word) for word in words_list)", "matching_cluster_idx": 5}]}, "Mbpp/94": {"dps": 78.04878048780488, "dps_norm": 60.0, "pass@1": 91.0, "profiled": [{"solution": "def index_minimum(list_of_tuples):\n return min(list_of_tuples, key=lambda x: x[1])[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(lst):\n \"\"\"Given a list of tuples, returns the first value of the tuple with the smallest second value\"\"\"\n return min(lst, key=lambda x: x[1])[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(lst):\n return min(lst, key=lambda x: x[1])[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(tuples):\n \"\"\"Return the first value of the tuple with the smallest second value\"\"\"\n return min(tuples, key=lambda x: x[1])[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(list_of_tuples):\n # Initialize the minimum index and value to the first item in the list\n min_index, min_value = 0, list_of_tuples[0][1]\n\n # Iterate over the rest of the list\n for i in range(1, len(list_of_tuples)):\n # If the item has a smaller second value than the current minimum, update the minimum\n if list_of_tuples[i][1] < min_value:\n min_index, min_value = i, list_of_tuples[i][1]\n\n # Return the first value of the tuple with the smallest second value\n return list_of_tuples[min_index][0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(lst):\n return min(lst, key=lambda x: x[1])[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(tuples_list):\n return min(tuples_list, key=lambda x: x[1])[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(lst):\n # The 'min' function finds the minimum of a list.\n # 'key' is used to specify a function of one argument that is used to extract a comparison key from each element.\n # In this case, it's set to get the second element of each tuple.\n min_value_tuple = min(lst, key = lambda x:x[1])\n # Return only the first element of the found tuple (index 0).\n return min_value_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(lst):\n return min(lst, key=lambda x: x[1])[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(lst):\n return min(lst, key=lambda x: x[1])[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(lst):\n \"\"\"\n Finds the tuple with the smallest second value and returns the first value of that tuple.\n :param lst: a list of tuples\n :return: the first value of the tuple with the smallest second value\n \"\"\"\n # Start by assuming the first tuple's second value is the smallest\n smallest_second_value = lst[0][1]\n smallest_second_index = 0\n\n # Go through each tuple in the list\n for i in range(len(lst)):\n # If the current tuple's second value is smaller than the smallest_second_value, update the smallest_second_value and smallest_second_index\n if lst[i][1] < smallest_second_value:\n smallest_second_value = lst[i][1]\n smallest_second_index = i\n\n # Return the first value of the tuple with the smallest second value\n return lst[smallest_second_index][0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(lst):\n if lst:\n return min(lst, key=lambda x: x[1])[0]\n else:\n return None", "matching_cluster_idx": 2}, {"solution": "def index_minimum(lst):\n return min(lst, key=lambda x: x[1])[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(lst):\n return min(lst, key=lambda x: x[1])[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(list_tuple):\n return min(list_tuple, key=lambda x: x[1])[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(tuples):\n return min(tuples, key=lambda x: x[1])[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(lst):\n # Sort the list of tuples by the second element.\n lst.sort(key=lambda x: x[1])\n # Return the first (index 0) element of the sorted list.\n return lst[0][0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(lst):\n \"\"\"\n Given a list of tuples, the function returns the first value of the tuple with the smallest second value.\n\n :param lst: List of tuples\n :type lst: List[Tuple[Any, int]]\n :return: First value of the tuple with the smallest second value\n :rtype: Any\n \"\"\"\n # Sort the list based on the second element of each tuple\n lst.sort(key=lambda x: x[1])\n\n # Return the first value of the first tuple in the sorted list\n return lst[0][0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(lst):\n return min(lst, key=lambda x: x[1])[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(tuples_list):\n min_tuple = min(tuples_list, key=lambda x: x[1])\n return min_tuple[0]", "matching_cluster_idx": 2}]}, "Mbpp/96": {"dps": 77.77777777777777, "dps_norm": 42.857142857142854, "pass@1": 95.0, "profiled": [{"solution": "def divisor(n):\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(num):\n count = 0\n for i in range(1, num+1):\n if num % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n # Initialize count to 0\n count = 0\n for i in range(1, n + 1):\n # Check if i is a divisor\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n: int) -> int:\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n count = 0\n for i in range(1, n+1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n count = 0\n for i in range(1, n+1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n count = 0\n for i in range(1, n+1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n count = 0\n for i in range(1, n+1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(num):\n count = 0\n for i in range(1, num + 1):\n if num % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n: int) -> int:\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n count = 0\n for i in range(1, n+1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}]}, "Mbpp/97": {"dps": 95.00854700854701, "dps_norm": 84.375, "pass@1": 90.0, "profiled": [{"solution": "def frequency_lists(lst):\n flat_list = [item for sublist in lst for item in sublist]\n frequency = {}\n for item in flat_list:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n return frequency", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lst):\n # Flatten the list of lists\n flat_list = [item for sublist in lst for item in sublist]\n\n # Create a dictionary to store frequencies\n freq_dict = {}\n\n # Iterate through the flattened list\n for item in flat_list:\n # If the item is in the dictionary, increase its count\n if item in freq_dict:\n freq_dict[item] += 1\n # If the item is not in the dictionary, add it with a count of 1\n else:\n freq_dict[item] = 1\n\n return freq_dict", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lst):\n freqs = {}\n for sublist in lst:\n for elem in sublist:\n if elem in freqs:\n freqs[elem] += 1\n else:\n freqs[elem] = 1\n return freqs", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lst):\n \"\"\"\n This function finds the frequency of each element in a flattened list of lists\n \"\"\"\n frequency = {}\n for sublist in lst:\n for element in sublist:\n if element in frequency:\n frequency[element] += 1\n else:\n frequency[element] = 1\n return frequency", "matching_cluster_idx": 6}, {"solution": "from collections import defaultdict\ndef flatten(lst):\n return [item for sublist in lst for item in sublist]\ndef frequency_lists(lst_of_lst):\n flat_list = flatten(lst_of_lst)\n freq_dict = defaultdict(int)\n for item in flat_list:\n freq_dict[item] += 1\n return dict(freq_dict)", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lists):\n freqs = {}\n for sublist in lists:\n for element in sublist:\n if element in freqs:\n freqs[element] += 1\n else:\n freqs[element] = 1\n return freqs", "matching_cluster_idx": 6}, {"solution": "from collections import defaultdict\ndef frequency_lists(lst):\n freq_dict = defaultdict(int)\n for sublist in lst:\n for item in sublist:\n freq_dict[item] += 1\n return dict(freq_dict)", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lists):\n freq_dict = {}\n for sublist in lists:\n for item in sublist:\n if item in freq_dict:\n freq_dict[item] += 1\n else:\n freq_dict[item] = 1\n return freq_dict", "matching_cluster_idx": 6}, {"solution": "def flatten(lst):\n return [item for sublist in lst for item in sublist]\ndef frequency_lists(lst):\n flat_list = flatten(lst)\n frequency_dict = {}\n for item in flat_list:\n if item in frequency_dict:\n frequency_dict[item] += 1\n else:\n frequency_dict[item] = 1\n return frequency_dict", "matching_cluster_idx": 6}, {"solution": "from collections import Counter\ndef flatten(lst):\n return [item for sublist in lst for item in sublist]\ndef frequency_lists(lst):\n flattened_list = flatten(lst)\n return dict(Counter(flattened_list))", "matching_cluster_idx": 6}, {"solution": "def flatten(input_list):\n output_list = []\n for i in input_list:\n output_list.extend(i)\n return output_list\ndef frequency(input_list):\n frequency_dict = {}\n for i in input_list:\n if i in frequency_dict:\n frequency_dict[i] += 1\n else:\n frequency_dict[i] = 1\n return frequency_dict\ndef frequency_lists(input_lists):\n return frequency(flatten(input_lists))", "matching_cluster_idx": 6}, {"solution": "from collections import Counter\ndef flatten(input_list):\n flattened = [item for sublist in input_list for item in sublist]\n return flattened\ndef frequency_lists(input_list):\n flattened = flatten(input_list)\n frequency = dict(Counter(flattened))\n return frequency", "matching_cluster_idx": 6}, {"solution": "from collections import Counter\ndef flatten(lst):\n return [item for sublist in lst for item in sublist]\ndef frequency_lists(lst):\n flat_list = flatten(lst)\n return dict(Counter(flat_list))", "matching_cluster_idx": 6}, {"solution": "def flatten(lst):\n return [item for sublist in lst for item in sublist]\ndef frequency_lists(lst):\n flat_list = flatten(lst)\n frequency_dict = {}\n for item in flat_list:\n if item in frequency_dict:\n frequency_dict[item] += 1\n else:\n frequency_dict[item] = 1\n return frequency_dict", "matching_cluster_idx": 6}, {"solution": "def flatten_list(lst):\n return [item for sublist in lst for item in sublist]\ndef frequency_lists(lst):\n flat_list = flatten_list(lst)\n frequency_dict = {}\n for item in flat_list:\n if item in frequency_dict:\n frequency_dict[item] += 1\n else:\n frequency_dict[item] = 1\n return frequency_dict", "matching_cluster_idx": 6}, {"solution": "from collections import Counter\ndef flatten(lst):\n return [item for sublist in lst for item in sublist]\ndef frequency_lists(lsts):\n flat_list = flatten(lsts)\n return dict(Counter(flat_list))", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lst):\n freq = {}\n for sublist in lst:\n for item in sublist:\n if item in freq:\n freq[item] += 1\n else:\n freq[item] = 1\n return freq", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lst):\n # Flatten the list of lists\n flat_list = [item for sublist in lst for item in sublist]\n\n # Create an empty dictionary to store frequency counts\n frequency_count = {}\n\n # For each item in the flattened list, increase the count in the dictionary\n for item in flat_list:\n if item in frequency_count:\n frequency_count[item] += 1\n else:\n frequency_count[item] = 1\n\n return frequency_count", "matching_cluster_idx": 6}, {"solution": "def flatten(nested_list):\n # helper function to flatten list\n result = []\n for sublist in nested_list:\n for item in sublist:\n result.append(item)\n return result\ndef frequency_lists(nested_list):\n # function to count frequency of each item in the flattened list\n flat_list = flatten(nested_list)\n frequency = {}\n for item in flat_list:\n if (item in frequency):\n frequency[item] += 1\n else:\n frequency[item] = 1\n return frequency", "matching_cluster_idx": 6}, {"solution": "def flatten(lst):\n \"\"\"Flattens a list of lists\"\"\"\n return [item for sublist in lst for item in sublist]\ndef frequency_lists(lst):\n \"\"\"Returns a dictionary with the frequency of each element in the flattened list of lists\"\"\"\n flat_list = flatten(lst)\n return {i: flat_list.count(i) for i in flat_list}", "matching_cluster_idx": 1}]}, "Mbpp/106": {"dps": 66.78571428571429, "dps_norm": 90.83333333333333, "pass@1": 99.0, "profiled": [{"solution": "def add_lists(lst, tpl):\n return tpl + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tpl):\n # concatenate the tuple and the list using + operator\n return tpl + tuple(lst)", "matching_cluster_idx": 4}, {"solution": "def add_lists(lst, tpl):\n return tpl + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tup):\n return tup + tuple(lst)", "matching_cluster_idx": 4}, {"solution": "def add_lists(lst, tpl):\n # combine the tuple and list\n combined = tpl + tuple(lst)\n return combined", "matching_cluster_idx": 4}, {"solution": "def add_lists(lst, tup):\n return tup + tuple(lst)", "matching_cluster_idx": 4}, {"solution": "def add_lists(lst, tpl):\n # Convert the tuple to list\n tpl_list = list(tpl)\n \n # Add the given list to the list of the tuple\n tpl_list.extend(lst)\n \n # Convert the list back to tuple\n tpl = tuple(tpl_list)\n \n return tpl", "matching_cluster_idx": 4}, {"solution": "def add_lists(lst, tpl):\n return tpl + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tpl):\n return tpl + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tup):\n # Convert tuple to list\n tup_list = list(tup)\n # Append the list to the tuple list\n tup_list.extend(lst)\n # Convert list back to tuple\n new_tup = tuple(tup_list)\n return new_tup", "matching_cluster_idx": 4}, {"solution": "def add_lists(lst, tpl):\n \"\"\"Append the given list to the given tuples\"\"\"\n return tpl + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tpl):\n return tpl + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tup):\n return tup + tuple(lst)", "matching_cluster_idx": 4}, {"solution": "def add_lists(lst, tpl):\n \"\"\"\n This function appends a given list to the given tuple and returns the result.\n \n Parameters:\n lst (List): The list to be appended.\n tpl (Tuple): The tuple to which the list will be appended.\n \n Returns:\n Tuple: A tuple consisting of the elements of the initial tuple followed by the elements of the list.\n \"\"\"\n # Convert the tuple to list\n tpl_list = list(tpl)\n # Append the list to the list\n tpl_list.extend(lst)\n # Convert the list back to tuple\n result_tpl = tuple(tpl_list)\n # Return the resulting tuple\n return result_tpl", "matching_cluster_idx": 4}, {"solution": "def add_lists(lst, tup):\n \"\"\"\n This function appends a given list to a given tuple and returns the combined object.\n \n Parameters:\n lst (list): The list to be added.\n tup (tuple): The tuple to which the list is appended.\n \n Returns:\n tuple: The tuple resulting from appending the list to the tuple.\n \"\"\"\n return tup + tuple(lst)", "matching_cluster_idx": 4}, {"solution": "def add_lists(lst, tpl):\n return tpl + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tpl):\n # Using the + operator to concatenate tuples and lists\n return tpl + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tup):\n return tup + tuple(lst)", "matching_cluster_idx": 4}, {"solution": "def add_lists(lst, tpl):\n return tpl + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tup):\n return tup + tuple(lst)", "matching_cluster_idx": 4}]}, "Mbpp/108": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 99.0, "profiled": [{"solution": "def merge_sorted_list(list1, list2, list3):\n merged_list = list1 + list2 + list3\n return sorted(merged_list)", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(lst1, lst2, lst3):\n merged_list = lst1 + lst2 + lst3\n merged_list.sort()\n return merged_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n \"\"\" Merge three sorted lists into a single sorted list.\n\n Args:\n list1 (list): first sorted list\n list2 (list): second sorted list\n list3 (list): third sorted list\n\n Returns:\n list: A sorted list containing elements from all three input lists.\n \"\"\"\n\n # Merge the lists\n merged_list = list1 + list2 + list3\n\n # Sort the merged list\n merged_list.sort()\n\n return merged_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # concatenate the lists\n merged_list = list1 + list2 + list3\n # sort the merged list\n merged_list.sort()\n # return the sorted list\n return merged_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Merging the three lists into one\n merged_list = list1 + list2 + list3\n\n # Sorting the combined list\n sorted_list = sorted(merged_list)\n\n return sorted_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Concatenate the lists\n merged_list = list1 + list2 + list3\n # Sort the merged list\n merged_list.sort()\n return merged_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(l1, l2, l3):\n merged_list = l1 + l2 + l3\n merged_list.sort()\n return merged_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(a, b, c):\n # merge all three lists into one\n merged_list = a + b + c\n # sort the merged list\n merged_list.sort()\n return merged_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n merged_list = list1 + list2 + list3\n merged_list.sort()\n return merged_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(l1, l2, l3):\n # Merge the three lists\n merged_list = l1 + l2 + l3\n # Sort the merged list\n merged_list.sort()\n return merged_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n merged_list = list1 + list2 + list3\n merged_list.sort()\n return merged_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(l1, l2, l3):\n merged_list = l1 + l2 + l3\n merged_list.sort()\n return merged_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n return sorted(list1 + list2 + list3)", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(l1, l2, l3):\n merged_list = l1 + l2 + l3\n merged_list.sort()\n return merged_list\nlst1 = [25, 24, 15, 4, 5, 29, 110]\nlst2 = [19, 20, 11, 56, 25, 233, 154]\nlst3 = [24, 26, 54, 48]\nmerged_list = merge_sorted_list(lst1, lst2, lst3)", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Merge all lists\n merged_list = list1 + list2 + list3\n # Sort the merged list\n sorted_list = sorted(merged_list)\n return sorted_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(lst1, lst2, lst3):\n merged = lst1 + lst2 + lst3\n return sorted(merged)", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Merge the lists\n merged_list = list1 + list2 + list3\n # Sort the merged list\n merged_list.sort()\n return merged_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n merged_list = list1 + list2 + list3\n merged_list.sort()\n return merged_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n merged_list = list1 + list2 + list3\n return sorted(merged_list)\nlist1 = [25, 24, 15, 4, 5, 29, 110]\nlist2 = [19, 20, 11, 56, 25, 233, 154]\nlist3 = [24, 26, 54, 48]", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n result = list1 + list2 + list3\n result.sort()\n return result", "matching_cluster_idx": 10}]}, "Mbpp/111": {"dps": 52.12307692307692, "dps_norm": 75.625, "pass@1": 94.0, "profiled": [{"solution": "def common_in_nested_lists(nested_lists):\n return list(set.intersection(*map(set, nested_lists)))", "matching_cluster_idx": 4}, {"solution": "def common_in_nested_lists(nested_list):\n return list(set.intersection(*map(set, nested_list)))", "matching_cluster_idx": 4}, {"solution": "def common_in_nested_lists(nested_lists):\n return list(set.intersection(*map(set, nested_lists)))", "matching_cluster_idx": 4}, {"solution": "def common_in_nested_lists(nested_lists):\n # Get the first list in the nested lists as a starting point\n common_elements = set(nested_lists[0])\n # Loop over remaining lists\n for cur_list in nested_lists[1:]:\n # Intersection of elements in current list with the common elements\n common_elements = common_elements.intersection(set(cur_list))\n # Convert to list and return\n return list(common_elements)\nnested_lists = [[12, 18, 23, 25, 45], [7, 12, 18, 24, 28], [1, 5, 8, 12, 15, 16, 18]]", "matching_cluster_idx": 5}, {"solution": "def common_in_nested_lists(nested_list):\n if not nested_list:\n return []\n\n common_elements = set(nested_list[0])\n for cur_list in nested_list[1:]:\n common_elements = common_elements & set(cur_list)\n return list(common_elements)", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n common_elements = set(nested_lists[0])\n for lst in nested_lists[1:]:\n common_elements = common_elements & set(lst)\n return list(common_elements)", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_list):\n return list(set.intersection(*map(set, nested_list)))", "matching_cluster_idx": 4}, {"solution": "def common_in_nested_lists(nested_lists):\n result = set(nested_lists[0]) # start with first list\n for lst in nested_lists[1:]: # iterate over the remaining lists\n result = result & set(lst) # find common elements with current result and current list\n return list(result) # return list of common elements", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n \"\"\"\n This function finds the common elements in given nested lists\n and returns them as a list.\n \"\"\"\n result = set(nested_lists[0])\n for sub_list in nested_lists[1:]:\n result = result.intersection(set(sub_list))\n return list(result)", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n return list(set.intersection(*map(set, nested_lists)))", "matching_cluster_idx": 4}, {"solution": "def common_in_nested_lists(nested_lists):\n # convert the first list to a set\n common_elements = set(nested_lists[0])\n\n # iterate over the rest of the lists\n for current_list in nested_lists[1:]:\n # keep only elements that are common in the current list and the common_elements set\n common_elements = common_elements.intersection(current_list)\n\n return list(common_elements)", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n return list(set.intersection(*map(set, nested_lists)))", "matching_cluster_idx": 4}, {"solution": "def common_in_nested_lists(nested_list):\n \"\"\"\n This function takes a nested list of numbers and returns common elements.\n \"\"\"\n result = set(nested_list[0]) # Initial result is the set of first list\n for each_list in nested_list[1:]: # Loop over the rest of the lists\n result = result & set(each_list) # Take intersection of the current result and current list\n return list(result) # Return the result as a list", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_list):\n # convert nested list into set of list\n set_lists = map(set, nested_list)\n # use python built-in set.intersection method\n common = set.intersection(*set_lists)\n return list(common)", "matching_cluster_idx": 4}, {"solution": "def common_in_nested_lists(lst):\n if len(lst)==0:\n return []\n common_set = set(lst[0])\n for l in lst[1:]:\n common_set = common_set & set(l)\n return list(common_set)", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n # To solve the problem, use the built-in Python function set() \n # and & operator to find intersection of all elements in each nested list.\n common_elements = set(nested_lists[0])\n for lst in nested_lists[1:]:\n common_elements = common_elements & set(lst)\n return list(common_elements)", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n # Find common elements in the first list\n common = set(nested_lists[0])\n # For each subsequent list, find common elements\n for lst in nested_lists[1:]:\n common &= set(lst) # Intersection of current common elements and new list\n return list(common)", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_list):\n return list(set.intersection(*map(set, nested_list)))", "matching_cluster_idx": 4}, {"solution": "def common_in_nested_lists(lists):\n common = set(lists[0])\n for lst in lists[1:]:\n common = common & set(lst)\n return list(common)", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_list):\n return list(set.intersection(*map(set, nested_list)))", "matching_cluster_idx": 4}]}, "Mbpp/123": {"dps": 99.62686567164178, "dps_norm": 85.71428571428571, "pass@1": 49.0, "profiled": [{"solution": "def sum_of_divisors(n):\n sum = 1\n i = 2\n while i * i <= n:\n if n % i:\n i += 1\n else:\n if i * (n // i) == n:\n sum = sum + i + n//i\n else:\n sum += i\n i += 1\n return sum\ndef amicable_numbers_sum(limit):\n amicable_sum = 0\n for i in range(1, limit+1):\n j = sum_of_divisors(i)\n if i != j and sum_of_divisors(j) == i:\n amicable_sum += i\n return amicable_sum", "matching_cluster_idx": 11}, {"solution": "def sum_of_divisors(n):\n sum = 1\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n sum += i\n if n / i != i:\n sum += n // i\n return sum\ndef amicable_numbers_sum(n):\n sum = 0\n for i in range(1, n):\n if sum_of_divisors(sum_of_divisors(i)) == i and sum_of_divisors(i) != i:\n sum += i\n return sum", "matching_cluster_idx": 11}, {"solution": "def sum_of_divisors(n): \n sum = 1\n i = 2\n while i * i <= n: \n if n % i: \n i += 1\n else: \n if i * (n // i) == n: \n sum = sum + i + n//i \n else: \n sum = sum + i \n i += 1\n return sum\ndef amicable_numbers_sum(limit):\n amicable_numbers_sum = 0\n for i in range(1, limit+1):\n sum_of_divisors_i = sum_of_divisors(i)\n if i != sum_of_divisors_i and sum_of_divisors(sum_of_divisors_i) == i:\n amicable_numbers_sum += i\n return amicable_numbers_sum", "matching_cluster_idx": 11}, {"solution": "def amicable_numbers_sum(n):\n def sum_divisors(num):\n sum = 1\n i = 2\n while i * i <= num:\n if num % i:\n i += 1\n else:\n if i * (num // i) == num:\n sum = sum + i + num//i\n else:\n sum = sum + i\n i += 1\n return sum\n\n amicable_sum = 0\n for i in range(1, n+1):\n sum_1 = sum_divisors(i)\n sum_2 = sum_divisors(sum_1)\n if sum_2==i and sum_1!=sum_2:\n amicable_sum += i\n return amicable_sum", "matching_cluster_idx": 11}, {"solution": "def divisors_sum(n):\n '''Calculates the sum of divisors excluding the number itself.'''\n divisors = [1]\n for i in range(2, int(n ** 0.5) + 1):\n if n % i == 0:\n if n / i == i:\n divisors.append(i)\n else:\n divisors.extend([i, n // i])\n return sum(divisors)\ndef amicable_numbers_sum(limit):\n '''Calculates the sum of all amicable numbers up to a specified limit.'''\n amicable_numbers = set()\n for i in range(2, limit + 1):\n if i in amicable_numbers:\n continue\n sum_divisors = divisors_sum(i)\n if (sum_divisors != i) and (divisors_sum(sum_divisors) == i):\n amicable_numbers.update([i, sum_divisors])\n return sum(amicable_numbers)", "matching_cluster_idx": 11}, {"solution": "def d(n):\n \"\"\"\n Function to find the sum of proper divisors of a number\n \"\"\"\n sum = 1\n i = 2\n while i * i <= n:\n if n % i:\n i += 1\n else:\n if i * (n // i) == n:\n sum = sum + i + n//i\n else:\n sum += i\n i += 1\n return sum\ndef amicable_numbers_sum(limit):\n \"\"\"\n Function to find sum of amicable numbers in a given limit\n \"\"\"\n amicable_sum = 0\n numbers = [0] * (limit+1)\n\n for i in range(1, limit+1):\n numbers[i] = d(i)\n\n for i in range(1, limit+1):\n if (numbers[i] != i and numbers[i] <= limit and numbers[numbers[i]] == i):\n amicable_sum += i\n return amicable_sum", "matching_cluster_idx": 11}, {"solution": "def sum_of_proper_divisors(n):\n sum = 1\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n if i == n/i:\n sum += i\n else:\n sum += i + n/i\n return sum\ndef amicable_numbers_sum(n):\n sum = 0\n for i in range(1, n+1):\n sum_of_i = sum_of_proper_divisors(i)\n if i != sum_of_i and i == sum_of_proper_divisors(sum_of_i):\n sum += i\n return sum", "matching_cluster_idx": 11}, {"solution": "def amicable_numbers_sum(limit):\n def d(n):\n s = 1\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n s += i\n if i * i != n:\n s += n // i\n return s\n\n amicable_numbers = set()\n for i in range(1, limit + 1):\n j = d(i)\n if j > i and d(j) == i:\n amicable_numbers.add(i)\n amicable_numbers.add(j)\n return sum(amicable_numbers)", "matching_cluster_idx": 11}, {"solution": "def sum_of_divisors(n):\n sum = 1\n for i in range(2, int(n**0.5) + 1):\n if n % i:\n continue\n if i * i != n:\n sum = sum + i + n // i\n else:\n sum = sum + i\n return sum\ndef amicable_numbers_sum(limit):\n sum = 0\n for i in range(1, limit):\n num1 = sum_of_divisors(i)\n num2 = sum_of_divisors(num1)\n if num2 == i and num1 != num2:\n sum += i\n return sum", "matching_cluster_idx": 11}, {"solution": "def amicable_numbers_sum(n):\n # Initialize the sum\n sum = 0\n\n for num in range(1, n+1):\n div_sum = sum_of_factors(num)\n\n # Check if num is not equal to the sum of factors and if the sum of factors\n # is less than or equal to n\n if (num != div_sum and div_sum <= n):\n second_div_sum = sum_of_factors(div_sum)\n\n # Check if num is equal to sum of factors of sum of factors\n if (num == second_div_sum):\n # Add num to the sum\n sum += num\n return sum\ndef sum_of_factors(n):\n sum = 1\n i = 2\n while i <= n // i:\n if n % i == 0:\n if i == (n // i):\n sum = sum + i\n else:\n sum = sum + (i + n // i)\n i += 1\n return sum", "matching_cluster_idx": 11}, {"solution": "def amicable_numbers_sum(limit):\n def sum_divisors(n):\n sum = 1\n i = 2\n while i * i <= n:\n if n % i:\n i += 1\n else:\n if i * (n // i) == n:\n sum = sum + i + n//i\n else:\n sum = sum + i\n i += 1\n return sum\n amicable_numbers = set()\n for i in range(1, limit+1):\n s = sum_divisors(i)\n if s > i and s <= limit and sum_divisors(s) == i:\n amicable_numbers.add(i)\n amicable_numbers.add(s)\n return sum(amicable_numbers)", "matching_cluster_idx": 11}, {"solution": "def sum_divisors(n):\n sum = 1\n i = 2\n while i * i <= n:\n if n % i:\n i += 1\n else:\n if i * (n // i) == n:\n sum = sum + i + n//i\n else:\n sum += i\n i += 1\n return sum\ndef amicable_numbers_sum(limit):\n amicable_numbers = set()\n for i in range(2, limit+1):\n sum_i = sum_divisors(i)\n sum_sum_i = sum_divisors(sum_i)\n if i != sum_i and sum_i <= limit and i == sum_sum_i:\n amicable_numbers.add(i)\n return sum(amicable_numbers)", "matching_cluster_idx": 11}, {"solution": "def sum_divisors(n):\n sum = 1\n d = 2\n while d * d <= n:\n if n % d:\n d += 1\n else:\n if d * (n // d) == n:\n sum = sum + d + n//d\n else:\n sum = sum + d\n d += 1\n return sum\ndef amicable_numbers_sum(limit):\n sum = 0\n for i in range(1, limit+1):\n j = sum_divisors(i)\n if i != j and sum_divisors(j) == i:\n sum += i\n return sum", "matching_cluster_idx": 11}, {"solution": "def d(n):\n \"\"\"\n Function to find sum of proper divisors of n.\n \"\"\"\n sum = 1\n i = 2\n while i * i <= n:\n if n % i:\n i += 1\n else:\n if i * (n // i) == n:\n sum = sum + i + n//i\n else:\n sum = sum + i\n i += 1\n return sum\ndef amicable_numbers_sum(n):\n \"\"\"\n Function to find sum of all amicable numbers from 1 to n.\n \"\"\"\n sum = 0\n for i in range(2,n+1):\n if d(d(i))==i and d(i)!=i:\n sum += i\n return sum", "matching_cluster_idx": 11}, {"solution": "def d(n):\n \"\"\"\n Find the sum of proper divisors of the given number.\n \"\"\"\n sum = 1\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n if i*i != n:\n sum = sum + i + n // i\n else:\n sum = sum + i\n return sum\ndef amicable_numbers_sum(limit):\n \"\"\"\n Find the sum of all amicable numbers from 1 to the specified limit.\n \"\"\"\n sum = 0\n for i in range(1, limit):\n if i == d(d(i)) and i != d(i):\n sum += i\n return sum", "matching_cluster_idx": 11}, {"solution": "def d(n):\n sum = 1\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n sum += i\n if i * i != n:\n sum += n // i\n return sum\ndef amicable_numbers_sum(limit):\n sum = 0\n for i in range(1, limit+1):\n num1 = d(i)\n num2 = d(num1)\n if num2 == i and num1 != num2:\n sum += i\n return sum", "matching_cluster_idx": 11}, {"solution": "def sum_divisors(n):\n \"\"\"\n Helper function to compute the sum of divisors of a number excluding itself\n \"\"\"\n divisors = [1]\n for i in range(2, int(n ** 0.5) + 1):\n if n % i == 0:\n if n / i == i:\n divisors.append(i)\n else:\n divisors.extend([i, n // i])\n return sum(divisors)\ndef amicable_numbers_sum(limit):\n \"\"\"\n Function to sum all amicable numbers up to the limit\n \"\"\"\n amicable_numbers = set()\n for i in range(2, limit + 1):\n j = sum_divisors(i)\n if j != i and j <= limit and sum_divisors(j) == i:\n amicable_numbers.add(i)\n amicable_numbers.add(j)\n return sum(amicable_numbers)", "matching_cluster_idx": 11}, {"solution": "def divisor_sum(n):\n divisor_list = [1]\n for i in range(2, int(n**0.5) + 1):\n if n % i:\n continue\n if i == n // i:\n divisor_list.append(i)\n else:\n divisor_list.extend([i, n // i])\n return sum(divisor_list)\ndef amicable_numbers_sum(limit):\n amicable_numbers = set()\n for i in range(1, limit + 1):\n if i in amicable_numbers:\n continue\n sum_div = divisor_sum(i)\n if sum_div > i and divisor_sum(sum_div) == i:\n amicable_numbers.update([i, sum_div])\n return sum(amicable_numbers)", "matching_cluster_idx": 11}, {"solution": "def amicable_numbers_sum(limit):\n def d(n):\n result = 1\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n result += i\n if i * i != n: # if i is a square root, then don't count it twice\n result += n // i\n return result\n\n amicable_numbers = set()\n for a in range(1, limit + 1):\n b = d(a)\n if a != b and d(b) == a:\n amicable_numbers.add(a)\n amicable_numbers.add(b)\n return sum(amicable_numbers)", "matching_cluster_idx": 11}, {"solution": "def d(n):\n \"\"\"\n helper function to calculate sum of factors excluding the number itself\n \"\"\"\n sum = 1\n for i in range(2, int(n ** 0.5) + 1):\n if n % i:\n continue\n if i * i != n:\n sum = sum + i + n // i\n else:\n sum = sum + i\n return sum\ndef amicable_numbers_sum(limit):\n \"\"\"\n function to find and sum up all amicable numbers up to a specified limit\n \"\"\"\n result = 0\n for i in range(1, limit):\n if i == d(d(i)) and i != d(i):\n result += i\n return result", "matching_cluster_idx": 11}]}, "Mbpp/128": {"dps": 99.5475113122172, "dps_norm": 80.0, "pass@1": 100.0, "profiled": [{"solution": "def long_words(n, sentence):\n return [word for word in sentence.split(\" \") if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n # Split the sentence into words\n words = sentence.split(' ')\n \n # Filter out words that are longer than n characters\n long_words = [word for word in words if len(word) > n]\n \n return long_words", "matching_cluster_idx": 3}, {"solution": "def long_words(n, words):\n word_list = words.split()\n return [word for word in word_list if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n word_list = sentence.split()\n long_words = [word for word in word_list if len(word) > n]\n return long_words", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n words = sentence.split(' ')\n result = [word for word in words if len(word) > n]\n return result", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n words = sentence.split(\" \")\n long_words = [word for word in words if len(word) > n]\n return long_words", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n word_list = sentence.split()\n long_words = [word for word in word_list if len(word) > n]\n return long_words", "matching_cluster_idx": 3}, {"solution": "def long_words(n, string_list):\n words = string_list.split(' ')\n long_words_list = [word for word in words if len(word) > n]\n return long_words_list", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n words = sentence.split()\n return [word for word in words if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, words):\n word_list = words.split(\" \")\n long_words = [word for word in word_list if len(word) > n]\n return long_words", "matching_cluster_idx": 3}, {"solution": "def long_words(n, words_str):\n # Split words_str into a list of words\n words = words_str.split(' ')\n \n # Use list comprehension to get the words longer than n characters\n long_words_list = [word for word in words if len(word) > n]\n \n return long_words_list", "matching_cluster_idx": 3}, {"solution": "def long_words(n, string):\n words = string.split()\n long_words = [word for word in words if len(word) > n]\n return long_words", "matching_cluster_idx": 3}, {"solution": "def long_words(n, string):\n words = string.split(\" \")\n return [word for word in words if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, words):\n word_list = words.split()\n return [word for word in word_list if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n word_list = sentence.split(' ')\n long_words = [word for word in word_list if len(word) > n]\n return long_words", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n word_list = sentence.split()\n return [word for word in word_list if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n word_list = sentence.split(' ')\n long_words = [word for word in word_list if len(word) > n]\n return long_words", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n words = sentence.split(' ')\n long_words = [word for word in words if len(word) > n]\n return long_words", "matching_cluster_idx": 3}, {"solution": "def long_words(n, text):\n words = text.split(' ')\n long_words = [word for word in words if len(word) > n]\n return long_words", "matching_cluster_idx": 3}, {"solution": "def long_words(n, string):\n words = string.split()\n return [word for word in words if len(word) > n]", "matching_cluster_idx": 3}]}, "Mbpp/129": {"dps": 74.31122448979592, "dps_norm": 91.33333333333333, "pass@1": 56.0, "profiled": [{"solution": "def magic_square_test(matrix):\n # Get the dimension of the square\n dimension = len(matrix)\n\n # The sum of the first row is the constant sum\n magic_constant = sum(matrix[0])\n\n # Check row sums\n for row in matrix:\n if sum(row) != magic_constant:\n return False\n\n # Check column sums\n for i in range(dimension):\n if sum(row[i] for row in matrix) != magic_constant:\n return False\n\n # Check diagonal sums\n if sum(matrix[i][i] for i in range(dimension)) != magic_constant:\n return False\n if sum(matrix[i][dimension - i - 1] for i in range(dimension)) != magic_constant:\n return False\n\n # If we made it this far, the matrix is a magic square\n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n # Find number of rows (n) and columns (m)\n n = len(matrix)\n m = len(matrix[0])\n\n # Calculate the sum of elements in the first row\n magic_constant = sum(matrix[0])\n\n # Check rows\n for row in matrix:\n if sum(row) != magic_constant:\n return False\n\n # Check columns\n for j in range(m):\n if sum(matrix[i][j] for i in range(n)) != magic_constant:\n return False\n\n # Check diagonals\n if sum(matrix[i][i] for i in range(n)) != magic_constant:\n return False\n if sum(matrix[i][n - i - 1] for i in range(n)) != magic_constant:\n return False\n\n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(square):\n # Assuming a square matrix of order n x n\n n = len(square)\n\n # Calculating the sum of the first row\n magic_constant = sum(square[0])\n\n # Checking each row for magic constant sum\n for row in square:\n if sum(row) != magic_constant:\n return False\n\n # Checking each column for magic constant sum\n for i in range(n):\n if sum(row[i] for row in square) != magic_constant:\n return False\n\n # Checking the diagonal sum from top left to bottom right\n if sum(square[i][i] for i in range(n)) != magic_constant:\n return False\n\n # Checking the diagonal sum from top right to bottom left\n if sum(square[i][n - i - 1] for i in range(n)) != magic_constant:\n return False\n\n # If all conditions are met, the matrix is a magic square\n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n # Get the length (row and column size) of the matrix\n n = len(matrix)\n\n # Initialize the sum of first row\n sum_row = sum(matrix[0])\n\n # Check sum of each row\n for row in matrix:\n if sum(row) != sum_row:\n return False\n \n # Check sum of each column\n for j in range(n):\n if sum(matrix[i][j] for i in range(n)) != sum_row:\n return False\n\n # Check sum of two diagonals\n if sum(matrix[i][i] for i in range(n)) != sum_row:\n return False\n if sum(matrix[i][n-i-1] for i in range(n)) != sum_row:\n return False\n\n # If all checks pass\n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n # Get the size of the matrix\n size = len(matrix)\n \n # Calculate the sum of the first row to use as the target\n target = sum(matrix[0])\n \n # Check rows\n for row in matrix:\n if sum(row) != target:\n return False\n \n # Check columns\n for i in range(size):\n if sum(row[i] for row in matrix) != target:\n return False\n \n # Check diagonal\n if sum(matrix[i][i] for i in range(size)) != target:\n return False\n \n # Check anti-diagonal\n if sum(matrix[i][size-i-1] for i in range(size)) != target:\n return False\n \n # If all checks passed, it's a magic square\n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n # check if it's a square matrix\n if len(matrix) != len(matrix[0]):\n return False\n\n # calculate the sum of the first row\n magic_constant = sum(matrix[0])\n\n # check rows\n for row in matrix:\n if sum(row) != magic_constant:\n return False\n\n # check columns\n for col in range(len(matrix[0])):\n if sum(matrix[i][col] for i in range(len(matrix))) != magic_constant:\n return False\n\n # check diagonals\n if sum(matrix[i][i] for i in range(len(matrix))) != magic_constant:\n return False\n if sum(matrix[i][len(matrix)-i-1] for i in range(len(matrix))) != magic_constant:\n return False\n\n # if all tests pass, it's a magic square\n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(square):\n # Check if the matrix is a square\n if len(square) != len(square[0]):\n return False\n\n # Calculate the sum of the first row\n magic_constant = sum(square[0])\n\n # Check horizontal rows\n for row in square:\n if sum(row) != magic_constant:\n return False\n\n # Check vertical columns\n for i in range(len(square)):\n if sum(row[i] for row in square) != magic_constant:\n return False\n\n # Check diagonals\n if sum(square[i][i] for i in range(len(square))) != magic_constant:\n return False\n if sum(square[i][len(square)-i-1] for i in range(len(square))) != magic_constant:\n return False\n\n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n # Transpose the matrix to check the rows and columns\n transposed = zip(*matrix)\n\n # Calculate the sum of elements in the first row\n first_row_sum = sum(matrix[0])\n\n # Check if sum of each row is equal\n for row in matrix:\n if sum(row) != first_row_sum:\n return False\n\n # Check if sum of each column is equal\n for column in transposed:\n if sum(column) != first_row_sum:\n return False\n\n # Check the sum of the two diagonals\n diagonal_sum_1 = sum(matrix[i][i] for i in range(len(matrix)))\n if diagonal_sum_1 != first_row_sum:\n return False\n\n diagonal_sum_2 = sum(matrix[i][-i - 1] for i in range(len(matrix)))\n if diagonal_sum_2 != first_row_sum:\n return False\n\n # If all the checks passed, the matrix is a magic square\n return True", "matching_cluster_idx": 11}, {"solution": "def magic_square_test(square):\n # Get the size of the matrix (assumed to be a square matrix)\n size = len(square)\n \n # Calculate the sum of the first row\n magic_constant = sum(square[0])\n \n # Check rows\n for row in square:\n if sum(row) != magic_constant:\n return False\n \n # Check columns\n for col in range(size):\n if sum(square[i][col] for i in range(size)) != magic_constant:\n return False\n \n # Check diagonals\n if sum(square[i][i] for i in range(size)) != magic_constant:\n return False\n if sum(square[i][size - i - 1] for i in range(size)) != magic_constant:\n return False\n \n # If none of the tests failed, the matrix is a magic square\n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n # Get the size of the matrix\n n = len(matrix)\n # Get the sum of the first row\n magic_constant = sum(matrix[0])\n\n # Check rows and columns\n for i in range(n):\n if sum(matrix[i]) != magic_constant or sum([row[i] for row in matrix]) != magic_constant:\n return False\n\n # Check diagonals\n if sum(matrix[i][i] for i in range(n)) != magic_constant or sum(matrix[i][n - i - 1] for i in range(n)) != magic_constant:\n return False\n\n # If none of the above tests fail, then the matrix is a magic square\n return True", "matching_cluster_idx": 13}, {"solution": "def magic_square_test(matrix):\n # The matrix must be a square matrix\n if len(matrix) == 0 or len(matrix) != len(matrix[0]):\n return False\n\n # The sum of elements in each row, column and two diagonals must be same\n total_sum = sum(matrix[0])\n col_sums = [sum(col) for col in zip(*matrix)]\n diag_sums = [sum(matrix[i][i] for i in range(len(matrix))), sum(matrix[i][len(matrix)-i-1] for i in range(len(matrix)))]\n\n if any(row_sum != total_sum for row_sum in map(sum, matrix)) or \\\n any(col_sum != total_sum for col_sum in col_sums) or \\\n not all(diag_sum == total_sum for diag_sum in diag_sums):\n return False\n\n return True", "matching_cluster_idx": 9}, {"solution": "def magic_square_test(matrix):\n # check if the matrix is a square\n if len(matrix) != len(matrix[0]):\n return False\n\n # calculate the sum of the first row\n magic_constant = sum(matrix[0])\n\n # check rows\n for row in matrix:\n if sum(row) != magic_constant:\n return False\n\n # check columns\n for i in range(len(matrix)):\n if sum(row[i] for row in matrix) != magic_constant:\n return False\n\n # check diagonals\n if sum(matrix[i][i] for i in range(len(matrix))) != magic_constant:\n return False\n if sum(matrix[i][len(matrix)-i-1] for i in range(len(matrix))) != magic_constant:\n return False\n\n # if all checks pass, the matrix is a magic square\n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(mat):\n # Find the size of the matrix\n size = len(mat)\n\n # Calculate the sum of the first row\n magic_constant = sum(mat[0])\n\n # Check the sum of each row\n for row in mat:\n if sum(row) != magic_constant:\n return False\n\n # Check the sum of each column\n for col_idx in range(size):\n if sum(mat[row_idx][col_idx] for row_idx in range(size)) != magic_constant:\n return False\n\n # Check the sum of the diagonal\n if sum(mat[row_idx][row_idx] for row_idx in range(size)) != magic_constant:\n return False\n\n # Check the sum of the other diagonal\n if sum(mat[row_idx][size - row_idx - 1] for row_idx in range(size)) != magic_constant:\n return False\n\n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n # Check if the matrix is a square\n if len(matrix) != len(matrix[0]):\n return False\n\n # Calculate the sum of a row, column or diagonal\n target_sum = sum(matrix[0])\n\n # Check the sum of each row\n for row in matrix:\n if sum(row) != target_sum:\n return False\n\n # Check the sum of each column\n for col in range(len(matrix[0])):\n if sum(matrix[i][col] for i in range(len(matrix))) != target_sum:\n return False\n\n # Check the sum of the two diagonals\n if sum(matrix[i][i] for i in range(len(matrix))) != target_sum:\n return False\n if sum(matrix[i][len(matrix)-i-1] for i in range(len(matrix))) != target_sum:\n return False\n\n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n # Calculate the magic constant\n magic_constant = sum(row[0] for row in matrix)\n \n # Check rows\n for row in matrix:\n if sum(row) != magic_constant:\n return False\n \n # Check columns\n for col in range(len(matrix[0])):\n if sum(matrix[row][col] for row in range(len(matrix))) != magic_constant:\n return False\n \n # Check diagonal\n if sum(matrix[i][i] for i in range(len(matrix))) != magic_constant:\n return False\n \n # Check anti-diagonal\n if sum(matrix[i][len(matrix)-1-i] for i in range(len(matrix))) != magic_constant:\n return False\n \n # If passed all tests, it's a magic square\n return True", "matching_cluster_idx": 13}, {"solution": "def magic_square_test(matrix):\n # Check if the input is a list\n if type(matrix) is not list:\n return False\n # Check if the input is a square matrix\n if not all(len(row) == len(matrix) for row in matrix):\n return False\n # Calculate the sum of the first row\n magic_sum = sum(matrix[0])\n # Check if the rows have the same sum\n if any(sum(row) != magic_sum for row in matrix):\n return False\n # Check if the columns have the same sum\n if any(sum(matrix[j][i] for j in range(len(matrix))) != magic_sum for i in range(len(matrix))):\n return False\n # Check if the diagonals have the same sum\n if sum(matrix[i][i] for i in range(len(matrix))) != magic_sum or sum(matrix[i][len(matrix)-i-1] for i in range(len(matrix))) != magic_sum:\n return False\n return True", "matching_cluster_idx": 13}, {"solution": "def magic_square_test(matrix):\n # Check if matrix is square\n if len(matrix) != len(matrix[0]):\n return False\n row_sums = [sum(row) for row in matrix]\n col_sums = [sum(column) for column in zip(*matrix)]\n diagonal_sum1 = sum(matrix[i][i] for i in range(len(matrix)))\n diagonal_sum2 = sum(matrix[i][-i - 1] for i in range(len(matrix)))\n return all(sum_val == row_sums[0] for sum_val in row_sums + col_sums + [diagonal_sum1, diagonal_sum2])", "matching_cluster_idx": 8}, {"solution": "def magic_square_test(square):\n # check if square is a list of lists\n if not all(isinstance(row, list) for row in square):\n return False\n # check if all rows are of same length\n if not all(len(row) == len(square) for row in square):\n return False\n # check if all elements are integers\n if not all(isinstance(element, int) for row in square for element in row):\n return False\n \n # calculate sum of elements in the first row\n reference_sum = sum(square[0])\n \n # check rows, columns and diagonals\n for i in range(len(square)):\n if sum(square[i]) != reference_sum or sum(square[j][i] for j in range(len(square))) != reference_sum or sum(square[j][j] for j in range(len(square))) != reference_sum or sum(square[j][len(square)-j-1] for j in range(len(square))) != reference_sum:\n return False\n return True", "matching_cluster_idx": 5}, {"solution": "def magic_square_test(matrix):\n # Get the length of the square matrix\n n = len(matrix)\n\n # Store the sum of the first row as the expected sum\n expected_sum = sum(matrix[0])\n\n # Check the rows\n for row in matrix:\n if sum(row) != expected_sum:\n return False\n\n # Check the columns\n for i in range(n):\n if sum(matrix[j][i] for j in range(n)) != expected_sum:\n return False\n\n # Check the diagonals\n if sum(matrix[i][i] for i in range(n)) != expected_sum:\n return False\n if sum(matrix[i][n - i - 1] for i in range(n)) != expected_sum:\n return False\n\n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(square):\n # Check if the square is a square\n if len(square) != len(square[0]):\n return False\n\n # Calculate the sum of the first row\n magic_constant = sum(square[0])\n\n # Check the rows\n for row in square:\n if sum(row) != magic_constant:\n return False\n\n # Check the columns\n for i in range(len(square)):\n if sum(row[i] for row in square) != magic_constant:\n return False\n\n # Check the diagonals\n if sum(square[i][i] for i in range(len(square))) != magic_constant:\n return False\n if sum(square[i][len(square)-i-1] for i in range(len(square))) != magic_constant:\n return False\n\n return True", "matching_cluster_idx": 14}]}, "Mbpp/130": {"dps": 72.95964125560539, "dps_norm": 67.5, "pass@1": 78.0, "profiled": [{"solution": "def max_occurrences(lst):\n max_freq = 0\n max_item = None\n for item in lst:\n freq = lst.count(item)\n if freq > max_freq:\n max_freq = freq\n max_item = item\n return max_item", "matching_cluster_idx": 1}, {"solution": "from collections import Counter\ndef max_occurrences(lst):\n # Use Counter to get the counts of each item in the list\n count_dict = Counter(lst)\n \n # Use the most_common() method to get the item with maximum count\n max_item = count_dict.most_common(1)\n\n # Return the item, and its count\n if max_item:\n return max_item[0][0]\n\n # If the list is empty, return None\n return None", "matching_cluster_idx": 4}, {"solution": "def max_occurrences(lst):\n freq_dict = {}\n for item in lst:\n if item in freq_dict:\n freq_dict[item] += 1\n else:\n freq_dict[item] = 1\n return max(freq_dict, key=freq_dict.get)", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(lst):\n from collections import Counter\n count = Counter(lst)\n max_count = max(list(count.values()))\n for item, freq in count.items():\n if freq == max_count:\n return item", "matching_cluster_idx": 4}, {"solution": "def max_occurrences(lst):\n count_dict = {}\n for num in lst:\n if num in count_dict:\n count_dict[num] += 1\n else:\n count_dict[num] = 1\n max_val = max(count_dict.values())\n for key, value in count_dict.items():\n if value == max_val:\n return key\n return None", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(lst):\n \"\"\"\n Returns the item with maximum frequency in a list.\n \n Parameters:\n lst (list): a list of elements\n\n Returns:\n item: the item with maximum frequency\n\n \"\"\"\n # Initialize a dictionary to store the frequency of each item\n frequency_dict = {}\n\n # Count the frequency of each item\n for item in lst:\n if item in frequency_dict:\n frequency_dict[item] += 1\n else:\n frequency_dict[item] = 1\n\n # Find the item with maximum frequency\n max_freq_item = max(frequency_dict, key=frequency_dict.get)\n\n return max_freq_item", "matching_cluster_idx": 3}, {"solution": "from collections import Counter\ndef max_occurrences(lst):\n cnt = Counter(lst)\n return cnt.most_common(1)[0][0]", "matching_cluster_idx": 4}, {"solution": "def max_occurrences(lst):\n # Creating a dictionary to keep count of each item in the list\n count_dict = {i: lst.count(i) for i in lst}\n\n # Finding the item with maximum frequency\n max_item = max(count_dict, key=count_dict.get)\n\n # Returning the item with maximum frequency\n return max_item", "matching_cluster_idx": 1}, {"solution": "from collections import Counter\ndef max_occurrences(lst):\n count = Counter(lst)\n return count.most_common(1)[0][0]", "matching_cluster_idx": 4}, {"solution": "from collections import Counter\ndef max_occurrences(lst):\n counter = Counter(lst)\n max_count = max(list(counter.values()))\n for item, count in counter.items():\n if count == max_count:\n return item", "matching_cluster_idx": 4}, {"solution": "def max_occurrences(lst):\n # Create a dictionary to store the occurrences of each item\n freq_dict = {}\n for item in lst:\n if item in freq_dict:\n freq_dict[item] += 1\n else:\n freq_dict[item] = 1\n\n # Find the item with maximum frequency\n max_freq = max(freq_dict.values())\n max_freq_item = [item for item, freq in freq_dict.items() if freq == max_freq]\n\n # Return the item with maximum frequency\n # In case of a tie, return the first item with maximum frequency\n return max_freq_item[0]", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(nums):\n count_dict = {}\n for num in nums:\n if num in count_dict:\n count_dict[num] += 1\n else:\n count_dict[num] = 1\n max_freq = max(count_dict.values())\n for key, value in count_dict.items():\n if value == max_freq:\n return key", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(lst):\n count_dict = {}\n for item in lst:\n if item in count_dict:\n count_dict[item] += 1\n else:\n count_dict[item] = 1\n return max(count_dict, key=count_dict.get)", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(lst):\n counts = {}\n for num in lst:\n if num in counts:\n counts[num] += 1\n else:\n counts[num] = 1\n max_freq_num = max(counts, key=counts.get)\n return max_freq_num", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(lst):\n # Create an empty dictionary\n count_dict = {}\n \n # Traverse through the list and fill dictionary\n for i in lst:\n if i in count_dict:\n count_dict[i] += 1\n else:\n count_dict[i] = 1\n \n # Find maximum occurrence\n max_freq = max(count_dict.values())\n \n # Find corresponding item with maximum occurrence\n max_item = [item for item, frequency in count_dict.items() if frequency == max_freq]\n \n # Return first item in case of multiple items with the same highest frequency\n return max_item[0]", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(lst):\n # Use a dictionary to store the counts of each item\n counts = {}\n for item in lst:\n if item in counts:\n counts[item] += 1\n else:\n counts[item] = 1\n # Find the item with the maximum count\n max_item = max(counts, key=counts.get)\n return max_item", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(input_list):\n frequency_dict = {}\n for item in input_list:\n if item in frequency_dict:\n frequency_dict[item] += 1\n else:\n frequency_dict[item] = 1\n max_frequency = max(frequency_dict.values())\n for item, frequency in frequency_dict.items():\n if frequency == max_frequency:\n return item", "matching_cluster_idx": 3}, {"solution": "from collections import Counter\ndef max_occurrences(lst):\n counts = Counter(lst)\n max_val = max(counts.values())\n max_keys = [k for k, v in counts.items() if v == max_val]\n return max_keys[0] if max_keys else None", "matching_cluster_idx": 4}, {"solution": "from collections import Counter\ndef max_occurrences(lst):\n # Count the frequency of each item\n freq_dict = dict(Counter(lst))\n # Find the item with maximum frequency\n max_freq = max(freq_dict.values())\n for item, freq in freq_dict.items():\n if freq == max_freq:\n return item", "matching_cluster_idx": 4}, {"solution": "def max_occurrences(lst):\n # Use a dictionary to count the occurrence of each item in the list\n count_dict = {i: lst.count(i) for i in lst}\n # Return the item with maximum count\n return max(count_dict, key=count_dict.get)", "matching_cluster_idx": 1}]}, "Mbpp/137": {"dps": null, "dps_norm": null, "pass@1": 3.0, "profiled": []}, "Mbpp/140": {"dps": 55.40372670807454, "dps_norm": 68.125, "pass@1": 95.0, "profiled": [{"solution": "def extract_singly(lst):\n \"\"\"\n A function that flatten a list of lists into a single set of numbers.\n \"\"\"\n flatten_lst = []\n for sub_lst in lst:\n for num in sub_lst:\n flatten_lst.append(num)\n return flatten_lst", "matching_cluster_idx": 4}, {"solution": "def extract_singly(lst):\n # initialize an empty set\n result = set()\n # iterate over each sublist\n for sublist in lst:\n # iterate over each number in the sublist and add it to the set\n for number in sublist:\n result.add(number)\n # return the resulting set\n return result", "matching_cluster_idx": 4}, {"solution": "def extract_singly(nested_list):\n # Create an empty list\n result = []\n # Iterate through each tuple in the nested list\n for tup in nested_list:\n # Add each element of the tuple to the result list\n result += tup\n # Return the result list as a set\n return set(result)", "matching_cluster_idx": 6}, {"solution": "def extract_singly(lst):\n result = []\n for sublist in lst:\n for item in sublist:\n result.append(item)\n return result", "matching_cluster_idx": 4}, {"solution": "def extract_singly(lst):\n output = []\n for sublist in lst:\n for item in sublist:\n output.append(item)\n return output", "matching_cluster_idx": 4}, {"solution": "def extract_singly(lst):\n \"\"\"\n This function takes a list of tuples and flatten it into a single set of numbers.\n \"\"\"\n flat_list = [item for sublist in lst for item in sublist]\n return set(flat_list)", "matching_cluster_idx": 5}, {"solution": "def extract_singly(num_list):\n output_set = set()\n for num_tuple in num_list:\n output_set = output_set | set(num_tuple)\n return output_set", "matching_cluster_idx": 5}, {"solution": "def extract_singly(lst):\n result = []\n for sublist in lst:\n for item in sublist:\n result.append(item)\n return result", "matching_cluster_idx": 4}, {"solution": "def extract_singly(lst):\n flat_list = [item for sublist in lst for item in sublist]\n return set(flat_list)", "matching_cluster_idx": 5}, {"solution": "def extract_singly(nested_list):\n single_list = [num for sublist in nested_list for num in sublist]\n return set(single_list)", "matching_cluster_idx": 5}, {"solution": "def extract_singly(list_of_tuples):\n result = []\n for tup in list_of_tuples:\n for element in tup:\n result.append(element)\n return result", "matching_cluster_idx": 4}, {"solution": "def extract_singly(nested_list):\n result = []\n for inner_list in nested_list:\n for item in inner_list:\n result.append(item)\n return result", "matching_cluster_idx": 4}, {"solution": "def extract_singly(llist):\n single_list = []\n for l in llist:\n single_list.extend(l)\n return set(single_list)", "matching_cluster_idx": 6}, {"solution": "def extract_singly(lst):\n result = []\n for sublist in lst:\n for item in sublist:\n result.append(item)\n return result", "matching_cluster_idx": 4}, {"solution": "def extract_singly(lst):\n result = []\n for sublist in lst:\n for item in sublist:\n result.append(item)\n return result", "matching_cluster_idx": 4}, {"solution": "def extract_singly(list_of_tuples):\n # Initializing an empty list to store the results\n flat_list = []\n\n # Looping through each tuple in the input list\n for tup in list_of_tuples:\n # Looping through each element in the current tuple and appending it to the flat_list\n for item in tup:\n flat_list.append(item)\n\n # Returning the flat_list as a set to remove duplicates and preserve order\n return set(flat_list)", "matching_cluster_idx": 4}, {"solution": "def extract_singly(list_of_lists):\n result = []\n for inner_list in list_of_lists:\n for item in inner_list:\n result.append(item)\n return result", "matching_cluster_idx": 4}, {"solution": "def extract_singly(lst):\n \"\"\"\n A function that takes a list of lists and returns a single set of numbers.\n \"\"\"\n flattened_set = set()\n for sub_list in lst:\n for item in sub_list:\n flattened_set.add(item)\n return flattened_set", "matching_cluster_idx": 3}, {"solution": "def extract_singly(lst):\n return [item for sublist in lst for item in sublist]", "matching_cluster_idx": 5}, {"solution": "def extract_singly(lst):\n \"\"\"Flatten list of lists to single set of numbers.\n\n Args:\n lst (List[Tuple]): list of tuples to flatten\n\n Returns:\n Set: single set of numbers\n\n Examples:\n >>> extract_singly([(3, 4, 5), (4, 5, 7), (1, 4)])\n {1, 3, 4, 5, 7}\n \"\"\"\n return {n for sub_lst in lst for n in sub_lst}", "matching_cluster_idx": 5}]}, "Mbpp/141": {"dps": 82.38095238095238, "dps_norm": 45.625, "pass@1": 43.0, "profiled": [{"solution": "def pancake_sort(unsorted):\n \"\"\"\n Using pancake sorting algorithm to sort a list\n \"\"\"\n # Iterating over each index in the list\n for i in range(len(unsorted), 0, -1):\n # Finding the max number in unsorted list\n max_idx = unsorted.index(max(unsorted[:i]))\n # Flipping the max number to the beginning if it isn't there\n if max_idx != i - 1:\n # Flipping the max to its original position\n unsorted = unsorted[:max_idx+1][::-1] + unsorted[max_idx+1:]\n # Flipping the whole list to get the maximum number to its sorted position\n unsorted = unsorted[:i][::-1] + unsorted[i:]\n return unsorted", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(lst):\n for i in range(len(lst)):\n max_idx = 0\n for j in range(len(lst) - i):\n if lst[j] > lst[max_idx]:\n max_idx = j\n lst[max_idx], lst[-i-1] = lst[-i-1], lst[max_idx]\n return lst", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(list_to_sort):\n \"\"\"\n Implementation of pancake sort.\n \"\"\"\n for cur_size in reversed(range(2, len(list_to_sort)+1)):\n # Find the index of maximum element\n max_idx = list_to_sort[:cur_size].index(max(list_to_sort[:cur_size]))\n if max_idx != cur_size - 1:\n # if the maximum element is not at the last position\n if max_idx != 0:\n # Flip the maximum element to the start\n list_to_sort[:max_idx+1] = reversed(list_to_sort[:max_idx+1])\n # Flip the maximum to the end, so that it is in its final sorted place\n list_to_sort[:cur_size] = reversed(list_to_sort[:cur_size])\n return list_to_sort", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(lst):\n for i in range(len(lst), 0, -1):\n max_index = lst.index(max(lst[:i]))\n if max_index != i - 1:\n lst = lst[max_index::-1] + lst[max_index+1:]\n lst = lst[i-1::-1] + lst[i:]\n return lst", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(unsorted_list):\n # Find the maximum element in the list and flip it to the front.\n # Then flip the maximum element to the end.\n # Do this process for all elements in the list.\n for i in range(len(unsorted_list), 0, -1):\n max_index = unsorted_list.index(max(unsorted_list[:i]))\n if max_index != i-1:\n unsorted_list = unsorted_list[:max_index+1][::-1] + unsorted_list[max_index+1:]\n unsorted_list = unsorted_list[i-1::-1] + unsorted_list[i:]\n return unsorted_list", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(unsorted):\n for size in reversed(range(len(unsorted))):\n for i in range(size):\n if unsorted[i] > unsorted[i + 1]:\n unsorted[i], unsorted[i + 1] = unsorted[i + 1], unsorted[i]\n return unsorted", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(arr):\n # Number of elements in arr\n n = len(arr)\n\n # Start from the last element and one by one fix arr\n for i in range(n-1, 0, -1):\n # Find index of the maximum element such that element at max_index is greater than i\n max_index = i\n for j in range(i-1, -1, -1):\n if arr[j] > arr[max_index]:\n max_index = j\n\n # Swap max_index found with i\n if max_index != i:\n arr[i], arr[max_index] = arr[max_index], arr[i]\n\n return arr", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(input_list):\n for cur_size in reversed(range(len(input_list))):\n # Flip elements to put max value at end of current size\n max_idx = max(range(cur_size + 1), key=input_list.__getitem__)\n if max_idx != cur_size:\n input_list[max_idx], input_list[cur_size] = input_list[cur_size], input_list[max_idx]\n return input_list", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(input_list):\n for cur_size in range(len(input_list), 1, -1):\n # Find the maximum item in the unsorted part of the list\n max_index = input_list.index(max(input_list[:cur_size]))\n if max_index != cur_size - 1:\n # If the maximum item is not already in the last position, \n # flip it to the last position and flip the whole unsorted list\n if max_index != 0:\n input_list[:max_index + 1] = input_list[:max_index + 1][::-1]\n input_list[:cur_size] = input_list[:cur_size][::-1]\n return input_list", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(lst):\n for i in range(len(lst)-1, 0, -1):\n max_idx = max_element(lst, i)\n lst = flip(lst, max_idx)\n lst = flip(lst, i)\n return lst\ndef max_element(lst, end):\n max_idx = 0\n for i in range(0, end+1):\n if lst[i] > lst[max_idx]:\n max_idx = i\n return max_idx\ndef flip(lst, k):\n start = 0\n while start < k:\n lst[start], lst[k] = lst[k], lst[start]\n start += 1\n k -= 1\n return lst", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(lst):\n # Function to implement flip operation\n def flip(arr, k):\n start = 0\n while start < k:\n arr[start], arr[k] = arr[k], arr[start]\n start += 1\n k -= 1\n\n # Function to find maximum element in unsorted array\n def max_index(arr, n):\n max_idx = 0\n for i in range(1, n):\n if arr[i] > arr[max_idx]:\n max_idx = i\n return max_idx\n\n # Function to perform pancake sort\n def pancake_sort(arr):\n n = len(arr)\n for i in range(n, 0, -1):\n # Find index of maximum element in unsorted array\n max_idx = max_index(arr, i)\n # Flip the maximum element to the beginning\n flip(arr, max_idx)\n # Flip the maximum element to its correct position\n flip(arr, i - 1)\n return arr\n\n return pancake_sort(lst)", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(lst):\n for i in range(len(lst), 0, -1):\n # Index of the maximum element in the unsorted part of the list\n max_idx = lst.index(max(lst[:i]))\n if max_idx != i - 1:\n # Flip the maximum element to the leftmost position\n lst = lst[:max_idx+1][::-1] + lst[max_idx+1:]\n # Flip the maximum element to its correct position\n lst = lst[:i][::-1] + lst[i:]\n return lst", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(lst):\n def flip(lst, k):\n \"\"\"Flip the first k elements in the list\"\"\"\n lst[:k] = lst[:k][::-1]\n return lst\n\n n = len(lst)\n for i in range(n, 0, -1):\n # find the maximum element index\n max_idx = lst.index(max(lst[:i]))\n # if it's not at the first position, flip it to the first position\n if max_idx != 0:\n lst = flip(lst, max_idx + 1)\n # then, flip it to its correct position\n lst = flip(lst, i)\n return lst", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(lst):\n n = len(lst)\n \n for i in range(n):\n # Find the index of the maximum element from 0 to n-i\n max_index = max_element(lst, 0, n - i)\n \n # Move the maximum element to the end\n lst = flip(lst, max_index)\n \n # Move the maximum element to its correct position\n lst = flip(lst, n - i - 1)\n \n return lst\ndef max_element(lst, start, end):\n max_index = start\n for i in range(start, end):\n if lst[i] > lst[max_index]:\n max_index = i\n return max_index\ndef flip(lst, end):\n start = 0\n while start < end:\n lst[start], lst[end] = lst[end], lst[start]\n start += 1\n end -= 1\n return lst", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(list_to_sort):\n \"\"\"\n Pancake sorting algorithm for sorting a list.\n Flips items at the max index repeatedly to get the max value to the front.\n \"\"\"\n for unsorted_portion in range(len(list_to_sort), 0, -1):\n max_index = list_to_sort[:unsorted_portion].index(max(list_to_sort[:unsorted_portion]))\n\n # If the maximum value is not at the front, flip it to the front\n if max_index != (unsorted_portion - 1):\n # Flip to move max value to the front\n list_to_sort = list_to_sort[:max_index+1][::-1] + list_to_sort[max_index+1:]\n # Flip to move the max value to the end of the sorted section\n list_to_sort = list_to_sort[:unsorted_portion][::-1] + list_to_sort[unsorted_portion:]\n\n return list_to_sort", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(lst):\n for i in range(len(lst), 1, -1):\n max_idx = lst.index(max(lst[0:i]))\n if max_idx != i - 1:\n if max_idx != 0:\n lst[:max_idx+1] = lst[0:max_idx+1][::-1]\n lst[0:i] = lst[0:i][::-1]\n return lst", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(unsorted):\n for i in range(len(unsorted), 0, -1):\n # Find the index of the maximum element from the unsorted part of the list\n max_idx = unsorted.index(max(unsorted[:i]))\n # Flip the maximum element to the start of the unsorted part of the list\n unsorted[:max_idx + 1] = reversed(unsorted[:max_idx + 1])\n # Flip the maximum element to its correct position\n unsorted[:i] = reversed(unsorted[:i])\n return unsorted", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(lst):\n \"\"\"\n A function to sort a list of elements using the pancake sort method.\n \"\"\"\n\n # Get the length of the list.\n n = len(lst)\n\n # Start from the last element and iterate through the list backwards.\n for cur_size in range(n, 0, -1):\n\n # Find the index of the maximum element in the unsorted part of the list.\n max_idx = lst.index(max(lst[:cur_size]))\n\n # If the maximum element is not at the correct position, flip elements to move it to the correct position.\n if max_idx != cur_size - 1:\n lst = lst[:max_idx+1][::-1] + lst[max_idx+1:]\n lst = lst[:cur_size][::-1] + lst[cur_size:]\n\n return lst", "matching_cluster_idx": 3}, {"solution": "def flip(arr, k):\n \"\"\"Flip the first k elements in the list.\"\"\"\n i = 0\n while i < k / 2:\n arr[i], arr[k-i-1] = arr[k-i-1], arr[i]\n i += 1\n return arr\ndef find_max_index(arr, end):\n \"\"\"Find index of the maximum number in the list.\"\"\"\n max_index = 0\n for i in range(0, end):\n if arr[i] > arr[max_index]:\n max_index = i\n return max_index\ndef pancake_sort(arr):\n \"\"\"Sort the list using pancake sort algorithm.\"\"\"\n cur_size = len(arr)\n while cur_size > 0:\n max_index = find_max_index(arr, cur_size)\n if max_index != cur_size-1:\n # flip the max number to the beginning\n arr = flip(arr, max_index+1)\n # flip the max number to the end\n arr = flip(arr, cur_size)\n cur_size -= 1\n return arr", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(list_to_sort):\n for i in range(len(list_to_sort), 0, -1):\n max_index = list_to_sort.index(max(list_to_sort[:i]))\n if max_index != i - 1:\n if max_index != 0:\n list_to_sort[:max_index + 1] = reversed(list_to_sort[:max_index + 1])\n list_to_sort[:i] = reversed(list_to_sort[:i])\n return list_to_sort", "matching_cluster_idx": 3}]}, "Mbpp/166": {"dps": 94.39999999999999, "dps_norm": 50.0, "pass@1": 32.0, "profiled": [{"solution": "def find_even_pair(lst):\n count = 0\n for i in range(len(lst)):\n for j in range(i + 1, len(lst)):\n if (lst[i] ^ lst[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(lst):\n count = 0\n for i in range(len(lst)):\n for j in range(i+1, len(lst)):\n if (lst[i] ^ lst[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(lst):\n even_count = 0\n for i in range(len(lst)):\n for j in range(i + 1, len(lst)):\n if (lst[i] ^ lst[j]) % 2 == 0:\n even_count += 1\n return even_count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(lst):\n count = 0\n for i in range(len(lst)):\n for j in range(i+1, len(lst)):\n if (lst[i] ^ lst[j]) % 2 == 0: # The ^ operator is the xor operator\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(lst):\n # Initialize count to 0\n count = 0\n for i in range(len(lst)):\n for j in range(i + 1, len(lst)):\n # Check XOR of the integers is even\n if (lst[i] ^ lst[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(lst):\n count = 0\n for i in range(len(lst)):\n for j in range(i+1, len(lst)):\n if (lst[i] ^ lst[j]) % 2 == 0: # if xor is even\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(lst):\n count = 0\n for i in range(len(lst)):\n for j in range(i + 1, len(lst)):\n if (lst[i] ^ lst[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(lst):\n count = 0\n for i in range(len(lst)):\n for j in range(i + 1, len(lst)):\n if (lst[i] ^ lst[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(lst):\n count = 0\n for i in range(len(lst)):\n for j in range(i + 1, len(lst)):\n if (lst[i] ^ lst[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(lst):\n \"\"\"This function finds the count of pairs of integers in a list that xor to an even number.\"\"\"\n even_count = 0\n for i in range(len(lst)):\n for j in range(i+1, len(lst)):\n # perform xor operation and check if result is even\n if (lst[i] ^ lst[j]) % 2 == 0:\n even_count += 1\n return even_count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(nums):\n count = 0\n for i in range(len(nums)):\n for j in range(i + 1, len(nums)):\n if (nums[i] ^ nums[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(lst):\n count = 0\n for i in range(len(lst)):\n for j in range(i + 1, len(lst)):\n if (lst[i] ^ lst[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(lst):\n count = 0\n for i in range(len(lst)):\n for j in range(i+1, len(lst)):\n if (lst[i] ^ lst[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(lst):\n count = 0\n for i in range(len(lst)):\n for j in range(i + 1, len(lst)):\n if (lst[i] ^ lst[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(lst):\n count = 0\n for i in range(len(lst)):\n for j in range(i + 1, len(lst)):\n if (lst[i] ^ lst[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(lst):\n even_count = 0\n for i in range(len(lst)):\n for j in range(i+1, len(lst)):\n if (lst[i] ^ lst[j]) % 2 == 0:\n even_count += 1\n return even_count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(lst):\n count = 0\n for i in range(len(lst)):\n for j in range(i+1, len(lst)):\n if (lst[i] ^ lst[j]) % 2 == 0: # The XOR operation is performed with ^, and the modulus operation checks if the result is even\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(lst):\n count = 0\n for i in range(len(lst)):\n for j in range(i + 1, len(lst)):\n if (lst[i] ^ lst[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(lst):\n count = 0\n for i in range(len(lst)):\n for j in range(i + 1, len(lst)):\n if (lst[i] ^ lst[j]) % 2 == 0: # xor operation\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(arr):\n even_count = 0\n for i in range(len(arr)):\n for j in range(i+1, len(arr)):\n if (arr[i] ^ arr[j]) % 2 == 0:\n even_count += 1\n return even_count", "matching_cluster_idx": 1}]}, "Mbpp/170": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 93.0, "profiled": [{"solution": "def sum_range_list(lst, start, end):\n return sum(lst[start:end+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(lst, start, end):\n return sum(lst[start:end+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(lst, start, end):\n return sum(lst[start:end+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(lst, start, end):\n return sum(lst[start:end+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(lst, start, end):\n if start < 0 or end > len(lst):\n raise ValueError('The start or end index is out of the list range')\n return sum(lst[start:end+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(lst, start, end):\n return sum(lst[start:end+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(lst, start, end):\n return sum(lst[start:end+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(lst, start_index, end_index):\n return sum(lst[start_index:end_index+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(lst, start, end):\n if not 0 <= start < len(lst) or not 0 <= end < len(lst):\n return \"Invalid indices\"\n return sum(lst[start:end+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(numbers, start, end):\n return sum(numbers[start:end+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(lst, start, end):\n return sum(lst[start:end+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(lst, start, end):\n return sum(lst[start:end+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(lst, start_index, end_index):\n return sum(lst[start_index:end_index + 1])\nlst = [2,1,5,6,8,3,4,9,10,11,8,12]", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(lst, start, end):\n return sum(lst[start:end+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(nums, start, end):\n return sum(nums[start:end+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(num_list, start_index, end_index):\n return sum(num_list[start_index:end_index+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(numbers, start, end):\n return sum(numbers[start:end+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(lst, start, end):\n return sum(lst[start:end+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(lst, start, end):\n return sum(lst[start:end+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(lst, start, end):\n return sum(lst[start:end+1])", "matching_cluster_idx": 7}]}, "Mbpp/226": {"dps": 79.96124031007751, "dps_norm": 56.42857142857142, "pass@1": 88.0, "profiled": [{"solution": "def odd_values_string(s):\n \"\"\"Remove characters with odd index values from a given string.\"\"\"\n return ''.join([s[i] for i in range(len(s)) if i % 2 == 0])", "matching_cluster_idx": 1}, {"solution": "def odd_values_string(input_string):\n output_string = \"\"\n for i in range(len(input_string)):\n if i % 2 == 0:\n output_string += input_string[i]\n return output_string", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(input_string):\n output_string = ''\n for i in range(0, len(input_string), 2):\n output_string += input_string[i]\n return output_string", "matching_cluster_idx": 2}, {"solution": "def odd_values_string(input_str):\n # initialize an empty string to hold the characters with even index\n even_chars = \"\"\n\n # iterate over each character in the input_str\n for i in range(len(input_str)):\n # if the index of the character is even\n if i % 2 == 0:\n # add it to the string of even characters\n even_chars += input_str[i]\n\n return even_chars", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(s):\n return s[::2]", "matching_cluster_idx": 5}, {"solution": "def odd_values_string(input_string):\n return input_string[::2]", "matching_cluster_idx": 5}, {"solution": "def odd_values_string(s):\n return s[::2]", "matching_cluster_idx": 5}, {"solution": "def odd_values_string(input_string):\n # Starts with an empty string for the output\n output_string = \"\"\n # Iterates over the string\n for i in range(len(input_string)):\n # Only adds the character to the output_string if its index is even\n if i % 2 == 0:\n output_string += input_string[i]\n return output_string", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(s):\n # use list comprehension to form a new string with characters at even indices\n return ''.join([s[i] for i in range(len(s)) if i % 2 == 0])", "matching_cluster_idx": 1}, {"solution": "def odd_values_string(input_string):\n result = \"\"\n for i in range(len(input_string)):\n if i % 2 == 0: # If the index is even\n result += input_string[i]\n return result", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(s):\n \"\"\"\n Removes characters with odd index values from a given string.\n\n Parameters:\n s (str): input string\n\n Returns:\n str: string with characters with odd index values removed\n\n \"\"\"\n # Using list comprehension to get even index characters\n return ''.join([s[i] for i in range(len(s)) if i % 2 == 0])", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(s):\n return s[::2]", "matching_cluster_idx": 5}, {"solution": "def odd_values_string(s):\n return s[::2]", "matching_cluster_idx": 5}, {"solution": "def odd_values_string(s):\n return s[::2]", "matching_cluster_idx": 5}, {"solution": "def odd_values_string(input_string):\n \"\"\"\n This function removes characters at odd index from the given string and returns the new string.\n \"\"\"\n new_string = input_string[::2]\n return new_string", "matching_cluster_idx": 5}, {"solution": "def odd_values_string(s):\n \"\"\"\n This function removes characters with odd indices from a given string.\n \"\"\"\n # Initialize an empty string to store the result\n result = ''\n\n # Iterate over each index in the string\n for i in range(len(s)):\n # If the index is even (0-based), append the character to the result\n if i % 2 == 0:\n result += s[i]\n\n return result", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(input_string):\n # Start from the index 0, and take every second character in the string\n return input_string[::2]", "matching_cluster_idx": 5}, {"solution": "def odd_values_string(input_string):\n return input_string[::2]", "matching_cluster_idx": 5}, {"solution": "def odd_values_string(s):\n \"\"\"\n Function to remove characters with odd index values from a given string.\n \"\"\"\n return s[::2]", "matching_cluster_idx": 5}, {"solution": "def odd_values_string(input_string):\n return input_string[::2]", "matching_cluster_idx": 5}]}, "Mbpp/230": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def replace_blank(s, char):\n return s.replace(' ', char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(s, char):\n return s.replace(' ', char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(string, char):\n return string.replace(' ', char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string, replace_char):\n return input_string.replace(\" \", replace_char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(string, char):\n return string.replace(\" \", char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(s, c):\n return s.replace(\" \", c)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(s, c):\n return s.replace(' ', c)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(text, char):\n return text.replace(' ', char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string, char):\n return input_string.replace(' ', char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(s, c):\n return s.replace(\" \", c)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(s, ch):\n return s.replace(\" \", ch)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(s, char):\n return s.replace(' ', char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_str, char):\n return input_str.replace(\" \", char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(str, char):\n return str.replace(\" \", char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(string, char):\n return string.replace(' ', char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(s, c):\n return s.replace(' ', c)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(string, character):\n return string.replace(' ', character)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(string, char):\n return string.replace(' ', char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(s, c):\n return s.replace(' ', c)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(s, char):\n # Replace blank spaces in the string with the character\n s = s.replace(' ', char)\n return s", "matching_cluster_idx": 7}]}, "Mbpp/239": {"dps": null, "dps_norm": null, "pass@1": 4.0, "profiled": []}, "Mbpp/240": {"dps": 78.29268292682927, "dps_norm": 87.22222222222221, "pass@1": 92.0, "profiled": [{"solution": "def replace_list(list1, list2):\n list1[-1:] = list2\n return list1", "matching_cluster_idx": 7}, {"solution": "def replace_list(list1, list2):\n # replace the last element of list1 with list2\n list1[-1:] = list2\n return list1", "matching_cluster_idx": 7}, {"solution": "def replace_list(list1, list2):\n # remove the last element in the first list\n list1 = list1[:-1]\n # append the second list to the first\n list1.extend(list2)\n return list1", "matching_cluster_idx": 6}, {"solution": "def replace_list(list1, list2):\n # Replace the last element of the first list with elements of the second list\n list1[-1:] = list2\n return list1", "matching_cluster_idx": 7}, {"solution": "def replace_list(list1, list2):\n list1[-1:] = list2\n return list1", "matching_cluster_idx": 7}, {"solution": "def replace_list(list1, list2):\n \"\"\"\n Replaces the last element of the first list with the elements of the second list.\n\n Parameters:\n list1 (list): The first list.\n list2 (list): The list to replace the last element of list1 with.\n\n Returns:\n list: The modified list1 where the last element is replaced with list2.\n \"\"\"\n return list1[:-1] + list2", "matching_cluster_idx": 5}, {"solution": "def replace_list(l1, l2):\n l1[-1:] = l2\n return l1", "matching_cluster_idx": 7}, {"solution": "def replace_list(list1, list2):\n # Replaces the last element of list1 with the elements of list2\n list1[-1:] = list2\n return list1", "matching_cluster_idx": 7}, {"solution": "def replace_list(lst1, lst2):\n lst1[-1:] = lst2\n return lst1", "matching_cluster_idx": 7}, {"solution": "def replace_list(list1, list2):\n list1[-1:] = list2\n return list1", "matching_cluster_idx": 7}, {"solution": "def replace_list(lst1, lst2):\n \"\"\"\n This function takes in two lists and replaces the last element of the first list with the elements of the second list.\n \"\"\"\n # Replace the last element of lst1 with lst2\n lst1[-1:] = lst2\n return lst1", "matching_cluster_idx": 7}, {"solution": "def replace_list(list1, list2):\n list1[-1:] = list2\n return list1", "matching_cluster_idx": 7}, {"solution": "def replace_list(list1, list2):\n \"\"\"\n Replace the last element of the first list with elements of the second list.\n \"\"\"\n # Replace last element of the first list with elements of second list\n list1[-1:] = list2\n return list1", "matching_cluster_idx": 7}, {"solution": "def replace_list(list1, list2):\n list1[-1:] = list2\n return list1", "matching_cluster_idx": 7}, {"solution": "def replace_list(list1, list2):\n list1[-1:] = list2\n return list1", "matching_cluster_idx": 7}, {"solution": "def replace_list(list1, list2):\n # Replace the last element of the first list with the second list\n list1[-1:] = list2\n return list1", "matching_cluster_idx": 7}, {"solution": "def replace_list(list1, list2):\n list1[-1:] = list2\n return list1", "matching_cluster_idx": 7}, {"solution": "def replace_list(list1, list2):\n list1[-1:] = list2\n return list1", "matching_cluster_idx": 7}, {"solution": "def replace_list(list1, list2):\n list1[-1:] = list2\n return list1", "matching_cluster_idx": 7}, {"solution": "def replace_list(list1, list2):\n list1[-1:] = list2\n return list1", "matching_cluster_idx": 7}]}, "Mbpp/251": {"dps": 88.70689655172414, "dps_norm": 77.77777777777777, "pass@1": 72.0, "profiled": [{"solution": "def insert_element(list_, element):\n result = []\n for item in list_:\n result.extend([element, item])\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n result = []\n for i in lst:\n result.append(element)\n result.append(i)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, el):\n result = []\n for item in lst:\n result += [el, item]\n return result", "matching_cluster_idx": 7}, {"solution": "def insert_element(lst, element):\n result = []\n for i in lst:\n result.extend([element, i])\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, elm):\n result = []\n for item in lst:\n result.extend([elm, item])\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, elm):\n result = []\n for i in lst:\n result += [elm, i]\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, elm):\n new_list = []\n for item in lst:\n new_list.append(elm)\n new_list.append(item)\n return new_list", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, elem):\n result = []\n for item in lst:\n result.extend([elem, item])\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n new_lst = []\n for item in lst:\n new_lst.extend([element, item])\n return new_lst", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, el):\n result = []\n for item in lst:\n result += [el, item]\n return result", "matching_cluster_idx": 7}, {"solution": "def insert_element(lst, elem):\n # The list comprehension goes through the list lst, inserts elem before each element and returns the result\n return [item for sublist in [[elem, item] for item in lst] for item in sublist]", "matching_cluster_idx": 4}, {"solution": "def insert_element(lst, element):\n result = []\n for i in lst:\n result.extend([element, i])\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(list, element):\n result = []\n for item in list:\n result.append(element)\n result.append(item)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n result = []\n for item in lst:\n result.extend([element, item])\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, elem):\n result = []\n for item in lst:\n result.extend([elem, item])\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, elem):\n result = []\n for i in lst:\n result += [elem, i]\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, elem):\n result = []\n for i in lst:\n result.extend([elem, i])\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, el):\n result = []\n for item in lst:\n result.extend([el, item])\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, el):\n result = []\n for i in lst:\n result.extend([el, i])\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n result = []\n for i in lst:\n result.extend([element, i])\n return result", "matching_cluster_idx": 6}]}, "Mbpp/256": {"dps": 62.294520547945204, "dps_norm": 58.8235294117647, "pass@1": 84.0, "profiled": [{"solution": "def count_Primes_nums(n):\n if n<2:\n return 0\n primes = [True] * n\n p = 2\n while p * p <= n:\n if primes[p]:\n for i in range(p * p, n, p):\n primes[i] = False\n p += 1\n return sum(primes) - 2 # subtract 2 because 0 and 1 are not considered prime numbers", "matching_cluster_idx": 14}, {"solution": "def count_Primes_nums(n):\n # function to check if a number is prime\n def is_prime(num):\n if num < 2:\n return False\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n return False\n return True\n\n count = 0\n for i in range(n):\n if is_prime(i):\n count += 1\n return count", "matching_cluster_idx": 8}, {"solution": "def count_Primes_nums(num):\n if num < 2:\n return 0\n\n primes = [True] * num\n primes[0] = primes[1] = False\n for i, is_prime in enumerate(primes):\n if is_prime:\n for n in range(i*i, num, i):\n primes[n] = False\n\n return sum(primes)", "matching_cluster_idx": 13}, {"solution": "def count_Primes_nums(n):\n # Initialize an empty list to store prime numbers\n primes = []\n # Loop through numbers from 2 up to n\n for i in range(2, n):\n # Check if the current number is prime\n if all(i % p > 0 for p in primes):\n primes.append(i)\n # Return the length of the prime numbers\n return len(primes)", "matching_cluster_idx": 3}, {"solution": "def count_Primes_nums(num):\n prime_numbers = []\n for potential_prime in range(2, num):\n is_prime = True\n for divisor in range(2, potential_prime):\n if potential_prime % divisor == 0:\n is_prime = False\n if is_prime:\n prime_numbers.append(potential_prime)\n return len(prime_numbers)", "matching_cluster_idx": -1}, {"solution": "def count_Primes_nums(n):\n if n <= 2:\n return 0\n primes = [True] * n\n p = 2\n while p * p <= n:\n if primes[p] is True:\n for i in range(p * p, n, p):\n primes[i] = False\n p += 1\n primes[0] = False\n primes[1] = False\n return sum(primes)", "matching_cluster_idx": 14}, {"solution": "def is_prime(num):\n \"\"\"\n Check if a number is prime.\n \"\"\"\n if num < 2:\n return False\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n return False\n return True\ndef count_Primes_nums(num):\n \"\"\"\n Count the number of prime numbers less than a given non-negative number.\n \"\"\"\n count = 0\n for i in range(num):\n if is_prime(i):\n count += 1\n return count", "matching_cluster_idx": 8}, {"solution": "def count_Primes_nums(n):\n if n < 2:\n return 0\n else:\n primes = [True for _ in range(n)]\n p = 2\n while p * p <= n:\n if primes[p]:\n for i in range(p * p, n, p):\n primes[i] = False\n p += 1\n return sum(primes) - 2 # subtract 2 to exclude 0 and 1", "matching_cluster_idx": 13}, {"solution": "def count_Primes_nums(n):\n if n < 2: # no prime numbers less than 2\n return 0\n\n sieve = [1] * n\n sieve[0] = 0 # 0 and 1 are not prime numbers\n sieve[1] = 0 # 1 is not a prime number\n\n # Sieve of Eratosthenes algorithm\n for i in range(2, int(n**0.5) + 1):\n if sieve[i]:\n for j in range(i*i, n, i):\n sieve[j] = 0\n\n return sum(sieve)", "matching_cluster_idx": 14}, {"solution": "def is_prime(num):\n if num < 2:\n return False\n for i in range(2, num):\n if num % i == 0:\n return False\n return True\ndef count_Primes_nums(num):\n count = 0\n for i in range(num):\n if is_prime(i):\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Primes_nums(n):\n def is_prime(num):\n if num < 2:\n return False\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n return False\n return True\n \n return sum(is_prime(i) for i in range(n))", "matching_cluster_idx": 8}, {"solution": "def count_Primes_nums(n):\n # Initialize count of prime numbers\n count = 0\n for num in range(2, n):\n # Check if the number is prime by iterating through all possible factors\n for i in range(2, num):\n if (num % i) == 0: # If the number is divisible by any other number, it's not prime\n break\n else: # If the number is not divisible by any other number, it's prime\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def is_prime(n):\n if n <= 1:\n return False\n elif n <= 3:\n return True\n elif n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True\ndef count_Primes_nums(n):\n count = 0\n for i in range(2, n):\n if is_prime(i):\n count += 1\n return count", "matching_cluster_idx": 10}, {"solution": "def count_Primes_nums(n):\n # Initialize prime count\n prime_count = 0\n for num in range(2, n):\n # All prime numbers are greater than 1\n if num > 1:\n for i in range(2, num):\n # Check for factors\n if (num % i) == 0:\n # If factor is found, break\n break\n else:\n # This number is prime\n prime_count += 1\n return prime_count", "matching_cluster_idx": 2}, {"solution": "def count_Primes_nums(n):\n def is_prime(num):\n if num < 2:\n return False\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n return False\n return True\n\n count = 0\n for i in range(2, n):\n if is_prime(i):\n count += 1\n\n return count", "matching_cluster_idx": 8}, {"solution": "def count_Primes_nums(n):\n if n < 2:\n return 0\n primes = [1] * n\n primes[0] = primes[1] = 0\n for ind, val in enumerate(primes):\n if val == 1:\n primes[ind*2::ind] = [0] * (((n - 1)//ind) - 1)\n return sum(primes)", "matching_cluster_idx": 14}, {"solution": "def count_Primes_nums(n):\n primes = [True for _ in range(n+1)]\n p = 2\n while p ** 2 <= n:\n if primes[p] == True:\n for i in range(p ** 2, n+1, p):\n primes[i] = False\n p += 1\n count = 0\n for i in range(2, n):\n if primes[i]:\n count += 1\n return count", "matching_cluster_idx": 12}, {"solution": "def count_Primes_nums(n):\n \"\"\"\n This function calculates the number of primes less than a given non-negative number.\n \"\"\"\n if n < 2:\n return 0\n primes = [True for _ in range(n)]\n p = 2\n while p*p <= n:\n if primes[p] is True:\n for i in range(p*p, n, p):\n primes[i] = False\n p += 1\n return sum(primes) - 2 # Subtract 2 to exclude 0 and 1", "matching_cluster_idx": 13}, {"solution": "def count_Primes_nums(n):\n if n < 2:\n return 0\n\n primes = [True for _ in range(n)]\n p = 2\n while p * p <= n:\n if primes[p]:\n for i in range(p * p, n, p):\n primes[i] = False\n p += 1\n \n return sum(primes) - 2 # subtracting 2 because the numbers 0 and 1 are not prime", "matching_cluster_idx": 13}, {"solution": "def is_prime(n):\n if n < 2:\n return False\n if n == 2:\n return True\n if n % 2 == 0:\n return False\n for i in range(3, int(n**0.5) + 1, 2):\n if n % i == 0:\n return False\n return True\ndef count_Primes_nums(n):\n count = 0\n for i in range(n):\n if is_prime(i):\n count += 1\n return count", "matching_cluster_idx": 10}]}, "Mbpp/265": {"dps": 70.93023255813954, "dps_norm": 83.33333333333333, "pass@1": 10.0, "profiled": [{"solution": "def list_split(input_list, n):\n return [input_list[i::n] for i in range(n)]", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n return [lst[i::n] for i in range(n)]", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n return [lst[i::n] for i in range(n)]", "matching_cluster_idx": 4}, {"solution": "def list_split(input_list, n):\n return [input_list[i::n] for i in range(n)]", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n return [lst[i::n] for i in range(n)]", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n return [lst[i::n] for i in range(n)]", "matching_cluster_idx": 4}, {"solution": "def list_split(input_list, n):\n return [input_list[i::n] for i in range(n)]", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n return [lst[i::n] for i in range(n)]", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n return [lst[i::n] for i in range(n)]", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n return [lst[i::n] for i in range(n)]", "matching_cluster_idx": 4}]}, "Mbpp/281": {"dps": 94.0, "dps_norm": 81.81818181818181, "pass@1": 100.0, "profiled": [{"solution": "def all_unique(lst):\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n This function checks if all elements in a given list are unique.\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n if len(lst) == len(set(lst)):\n return True\n else:\n return False", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n Check if all elements in a given list are unique.\n \"\"\"\n # Using a set to remove duplicates and then comparing the length of the set and the original list\n # If the lengths are the same, all elements are unique\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n if len(lst) == len(set(lst)):\n return True\n else:\n return False", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"Check if all elements in the list are unique.\"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n Function to check if all elements in a list are unique.\n :param lst: list of elements\n :return: True if all elements are unique, False otherwise\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n if len(lst) == len(set(lst)):\n return True\n else:\n return False", "matching_cluster_idx": 8}]}, "Mbpp/296": {"dps": 28.205128205128204, "dps_norm": 66.66666666666667, "pass@1": 100.0, "profiled": [{"solution": "def get_Inv_Count(arr):\n inv_count = 0\n for i in range(len(arr)):\n for j in range(i + 1, len(arr)):\n if arr[i] > arr[j]:\n inv_count += 1\n return inv_count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n inv_count = 0\n for i in range(len(arr)):\n for j in range(i + 1, len(arr)):\n if arr[i] > arr[j]:\n inv_count += 1\n return inv_count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n inv_count = 0\n for i in range(len(arr)):\n for j in range(i + 1, len(arr)):\n if arr[i] > arr[j]:\n inv_count += 1\n return inv_count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n inv_count = 0\n for i in range(len(arr)):\n for j in range(i + 1, len(arr)):\n if arr[i] > arr[j]:\n inv_count += 1\n return inv_count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n inv_count = 0\n for i in range(len(arr)):\n for j in range(i + 1, len(arr)):\n if arr[i] > arr[j]:\n inv_count += 1\n return inv_count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n inv_count = 0\n for i in range(len(arr)):\n for j in range(i + 1, len(arr)):\n if arr[i] > arr[j]:\n inv_count += 1\n return inv_count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n inv_count = 0\n for i in range(len(arr)):\n for j in range(i + 1, len(arr)):\n if arr[i] > arr[j]:\n inv_count += 1\n return inv_count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n inv_count = 0\n for i in range(len(arr)):\n for j in range(i + 1, len(arr)):\n if arr[i] > arr[j]:\n inv_count += 1\n return inv_count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n inv_count = 0\n for i in range(len(arr)):\n for j in range(i + 1, len(arr)):\n if arr[i] > arr[j]:\n inv_count += 1\n return inv_count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n inversion_count = 0\n for i in range(len(arr)):\n for j in range(i + 1, len(arr)):\n if arr[i] > arr[j]:\n inversion_count += 1\n return inversion_count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n inv_count = 0\n for i in range(len(arr)):\n for j in range(i + 1, len(arr)):\n if arr[i] > arr[j]:\n inv_count += 1\n return inv_count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n inv_count = 0\n for i in range(len(arr)):\n for j in range(i + 1, len(arr)):\n if arr[i] > arr[j]:\n inv_count += 1\n return inv_count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(array):\n inv_count = 0\n for i in range(len(array)):\n for j in range(i + 1, len(array)):\n if array[i] > array[j]:\n inv_count += 1\n return inv_count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n inv_count = 0\n for i in range(len(arr)):\n for j in range(i + 1, len(arr)):\n if arr[i] > arr[j]:\n inv_count += 1\n return inv_count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n inv_count = 0\n for i in range(len(arr)):\n for j in range(i+1, len(arr)):\n if arr[i] > arr[j]:\n inv_count += 1\n return inv_count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n inv_count = 0\n for i in range(len(arr)):\n for j in range(i + 1, len(arr)):\n if arr[i] > arr[j]:\n inv_count += 1\n return inv_count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n inv_count = 0\n for i in range(len(arr)):\n for j in range(i + 1, len(arr)):\n if arr[i] > arr[j]:\n inv_count += 1\n return inv_count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n inversions = 0\n for i in range(len(arr)):\n for j in range(i + 1, len(arr)):\n if arr[i] > arr[j]:\n inversions += 1\n return inversions", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n inv_count = 0\n for i in range(len(arr)):\n for j in range(i + 1, len(arr)):\n if arr[i] > arr[j]:\n inv_count += 1\n return inv_count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n inversions = 0\n for i in range(len(arr)):\n for j in range(i + 1, len(arr)):\n if arr[i] > arr[j]:\n inversions += 1\n return inversions", "matching_cluster_idx": 3}]}, "Mbpp/308": {"dps": 97.58620689655173, "dps_norm": 66.66666666666667, "pass@1": 93.0, "profiled": [{"solution": "def large_product(list1, list2, n):\n products = [i * j for i in list1 for j in list2]\n products.sort(reverse=True)\n return products[:n]", "matching_cluster_idx": 3}, {"solution": "def large_product(lst1, lst2, n):\n # We multiply two elements from the lists and store the result in a new list\n products = [a * b for a in lst1 for b in lst2]\n \n # We then sort the list in descending order\n products.sort(reverse=True)\n\n # We then return a slice of the list that includes only the first n elements\n return products[:n]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, num):\n products = []\n for i in list1:\n for j in list2:\n products.append(i*j)\n products.sort(reverse=True)\n return products[:num]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n product_list = [i * j for i in list1 for j in list2]\n product_list.sort(reverse=True)\n return product_list[:n]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, num):\n products = [a * b for a in list1 for b in list2]\n products.sort(reverse=True)\n return products[:num]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, num):\n products = []\n for i in list1:\n for j in list2:\n products.append(i * j)\n products.sort(reverse=True)\n return products[:num]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n products = []\n for i in list1:\n for j in list2:\n products.append(i*j)\n products.sort(reverse=True)\n return products[:n]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n product_list = [(x*y) for x in list1 for y in list2]\n product_list.sort(reverse=True)\n return product_list[:n]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, num):\n # creating a new list to store the products\n products = []\n \n # iterating over each element of list1 and list2\n for i in list1:\n for j in list2:\n # multiplying each element and appending to the products list\n products.append(i*j)\n \n # sorting the products in descending order\n products.sort(reverse=True)\n \n # returning the first 'num' elements from the sorted list\n return products[:num]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n products = []\n for i in list1:\n for j in list2:\n products.append(i*j)\n products.sort(reverse=True)\n return products[:n]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n products = [a*b for a in list1 for b in list2]\n products.sort(reverse=True)\n return products[:n]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, k):\n # Create a list to store the products\n products = []\n \n # Iterate through each item in list1\n for i in list1:\n # Iterate through each item in list2\n for j in list2:\n # Append the product of i and j to the products list\n products.append(i*j)\n \n # Sort the products list in descending order\n products.sort(reverse=True)\n \n # Return the first k items from the products list\n return products[:k]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n # Generate all products\n products = [(x*y) for x in list1 for y in list2]\n # Sort the products in descending order\n products.sort(reverse=True)\n # Return the first n products\n return products[:n]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n products = [a * b for a in list1 for b in list2]\n products.sort(reverse=True)\n return products[:n]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n product_list = [i*j for i in list1 for j in list2]\n product_list.sort(reverse=True)\n return product_list[:n]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, num):\n product_list = [(x*y) for x in list1 for y in list2]\n product_list.sort(reverse=True)\n return product_list[:num]", "matching_cluster_idx": 3}, {"solution": "def large_product(lst1, lst2, k):\n combined = [(i*j) for i in lst1 for j in lst2]\n combined.sort(reverse=True)\n return combined[:k]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n products = []\n for i in list1:\n for j in list2:\n products.append(i*j)\n products.sort(reverse=True)\n return products[:n]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, num):\n # Multiply each element in list1 with each element in list2\n product_list = [i * j for i in list1 for j in list2]\n \n # Sort the product_list in descending order\n product_list.sort(reverse=True)\n\n # Return the specified number of largest products\n return product_list[:num]", "matching_cluster_idx": 3}, {"solution": "def large_product(lst1, lst2, n):\n combined_lst = [(x * y) for x in lst1 for y in lst2]\n combined_lst.sort(reverse=True)\n return combined_lst[:n]", "matching_cluster_idx": 3}]}, "Mbpp/392": {"dps": 74.71830985915493, "dps_norm": 80.38461538461539, "pass@1": 32.0, "profiled": [{"solution": "def get_max_sum(n):\n if n <= 1:\n return n\n\n # Memoization to store the maximum sum that can be obtained using n\n max_sum_table = [0]*(n+1)\n max_sum_table[0] = 0\n max_sum_table[1] = 1\n\n for i in range(2, n+1):\n max_sum_table[i] = max(max_sum_table[i//2] + max_sum_table[i//3] + max_sum_table[i//4] + max_sum_table[i//5], i)\n\n return max_sum_table[n]", "matching_cluster_idx": 10}, {"solution": "def get_max_sum(n):\n # initializing cache with a base case of 0\n cache = [0] * (n + 1)\n\n # iterate from 1 to n\n for i in range(1, n + 1):\n # applying equation\n cache[i] = max(cache[i//2] + cache[i//3] + cache[i//4] + cache[i//5], i)\n\n # return computed result\n return cache[n]", "matching_cluster_idx": 10}, {"solution": "def get_max_sum(n):\n if n<=5:\n return n\n else:\n f_n_2 = get_max_sum(n//2)\n f_n_3 = get_max_sum(n//3)\n f_n_4 = get_max_sum(n//4)\n f_n_5 = get_max_sum(n//5)\n return max(f_n_2 + f_n_3 + f_n_4 + f_n_5, n)", "matching_cluster_idx": 7}, {"solution": "def get_max_sum(n, memo={}):\n \"\"\"\n This function calculates the maximum sum given by the equation \n f(n) = max( (f(n/2) + f(n/3) + f(n/4) + f(n/5)), n).\n It uses a dictionary 'memo' to store previously computed results, \n thereby optimizing the function and reducing its time complexity.\n \"\"\"\n if n in memo:\n return memo[n]\n\n if n<1:\n return 0\n\n memo[n] = max(get_max_sum(n//2, memo) + get_max_sum(n//3, memo) + get_max_sum(n//4, memo) + get_max_sum(n//5, memo), n)\n\n return memo[n]", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n if n <= 1:\n return n\n return max(n, get_max_sum(n//2) + get_max_sum(n//3) + get_max_sum(n//4) + get_max_sum(n//5))", "matching_cluster_idx": 3}, {"solution": "def get_max_sum(n):\n cache = {0: 0} # Initialize cache dictionary\n def f(n):\n # Check if the value is already calculated before\n if n not in cache:\n # Calculate and store the value in the cache\n cache[n] = max(f(n//2) + f(n//3) + f(n//4) + f(n//5), n)\n return cache[n]\n return f(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n # Memoization dictionary to store the results of already computed values\n memo = {0:0, 1:1}\n\n def recursive(n):\n # Check if result is already computed\n if n not in memo:\n # Compute the result\n memo[n] = max(recursive(n//2) + recursive(n//3) + recursive(n//4) + recursive(n//5), n)\n return memo[n]\n\n return recursive(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n # Create a memoization dictionary to store intermediate results\n memo = {0:0}\n def helper(n):\n # If the result is already calculated, return it\n if n in memo:\n return memo[n]\n # Otherwise, calculate and store the result and return it\n else:\n result = max(helper(n//2) + helper(n//3) + helper(n//4) + helper(n//5), n)\n memo[n] = result\n return result\n return helper(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n memo = {0:0} # store the calculated maximum sum\n def f(n):\n if n not in memo: \n memo[n] = max((f(n//2) + f(n//3) + f(n//4) + f(n//5)), n)\n return memo[n]\n\n return f(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n if n == 0:\n return 0\n return max((get_max_sum(n//2) + get_max_sum(n//3) + get_max_sum(n//4) + get_max_sum(n//5)), n)", "matching_cluster_idx": 2}, {"solution": "def get_max_sum(n, memo={}):\n if n in memo:\n return memo[n]\n if n <= 1:\n return n\n memo[n] = max((get_max_sum(n//2, memo) + get_max_sum(n//3, memo) + get_max_sum(n//4, memo) + get_max_sum(n//5, memo)), n)\n return memo[n]", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n if n < 2:\n return n\n\n dp = [0]*(n+1)\n dp[0] = 0\n dp[1] = 1\n\n for i in range(2, n+1):\n dp[i] = max(dp[i//2] + dp[i//3] + dp[i//4] + dp[i//5], i)\n \n return dp[n]", "matching_cluster_idx": 10}, {"solution": "def get_max_sum(n, computed = {0:0}):\n if n not in computed:\n computed[n] = max([get_max_sum(n//2) + get_max_sum(n//3) + get_max_sum(n//4) + get_max_sum(n//5)] + [n])\n return computed[n]", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n # Creating a memo dict to cache previously computed sums\n memo = {0:0}\n\n def max_sum(n):\n # If n is in the cache, return the cached sum\n if n in memo:\n return memo[n]\n\n # Compute the sum using the formula and update the cache\n memo[n] = max((max_sum(n//2) + max_sum(n//3) + max_sum(n//4) + max_sum(n//5)), n)\n return memo[n]\n \n return max_sum(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n if n <= 1:\n return n\n else:\n return max(get_max_sum(n//2) + get_max_sum(n//3) + get_max_sum(n//4) + get_max_sum(n//5), n)", "matching_cluster_idx": 3}, {"solution": "def get_max_sum(n):\n if n <= 1:\n return n\n\n sums = [0] * (n+1)\n sums[0] = 0\n sums[1] = 1\n\n for i in range(2, n+1):\n sums[i] = max((sums[int(i/2)] + sums[int(i/3)] + sums[int(i/4)] + sums[int(i/5)]), i)\n \n return sums[n]", "matching_cluster_idx": 9}, {"solution": "def get_max_sum(n):\n memo = dict()\n def max_sum(n):\n if n == 0:\n return 0\n if n in memo:\n return memo[n]\n result = max(max_sum(n//2) + max_sum(n//3) + max_sum(n//4) + max_sum(n//5), n)\n memo[n] = result\n return result\n return max_sum(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n if n <= 1:\n return n\n\n # memoization dictionary\n dp = {0:0, 1:1}\n \n def helper(n):\n if n not in dp:\n dp[n] = max(helper(n//2) + helper(n//3) + helper(n//4) + helper(n//5), n)\n return dp[n]\n\n return helper(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n if n <= 1:\n return n\n else:\n return max(n, get_max_sum(n//2) + get_max_sum(n//3) + get_max_sum(n//4) + get_max_sum(n//5))", "matching_cluster_idx": 3}, {"solution": "def get_max_sum(n):\n # Create a dictionary to store previously computed values\n computed_values = {0:0, 1:1}\n def max_sum(n):\n # If value is already computed, return it\n if n in computed_values:\n return computed_values[n]\n # If not, compute and store value then return it\n computed_values[n] = max(max_sum(n//2) + max_sum(n//3) + max_sum(n//4) + max_sum(n//5), n)\n return computed_values[n]\n return max_sum(n)", "matching_cluster_idx": 12}]}, "Mbpp/395": {"dps": 84.9808429118774, "dps_norm": 67.5, "pass@1": 100.0, "profiled": [{"solution": "def first_non_repeating_character(string):\n char_count = {}\n for char in string:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n for char in string:\n if char_count[char] == 1:\n return char\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(string):\n count = {}\n for char in string:\n count[char] = count.get(char, 0) + 1\n for char in string:\n if count[char] == 1:\n return char\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n for i in s:\n if s.count(i) == 1:\n return i\n return None", "matching_cluster_idx": 1}, {"solution": "def first_non_repeating_character(string):\n char_count = {}\n for char in string:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n for char in string:\n if char_count[char] == 1:\n return char\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(string):\n # Count the occurrences of each character\n char_count = {}\n for char in string:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n\n # Iterate through the string to find the first non-repeating character\n for char in string:\n if char_count[char] == 1:\n return char\n\n # If no non-repeating character is found, return None\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(string):\n for index, character in enumerate(string):\n if string.count(character) == 1:\n return character\n return None", "matching_cluster_idx": 1}, {"solution": "def first_non_repeating_character(s):\n count = {}\n for char in s:\n if char in count:\n count[char] += 1\n else:\n count[char] = 1\n for char in s:\n if count[char] == 1:\n return char\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(string):\n char_count = {}\n for char in string:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n for char in string:\n if char_count[char] == 1:\n return char\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(string):\n char_count = {}\n for char in string:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n for char in string:\n if char_count[char] == 1:\n return char\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(string):\n for char in string:\n if string.count(char) == 1:\n return char\n return None", "matching_cluster_idx": 1}, {"solution": "def first_non_repeating_character(string):\n char_count = {}\n for char in string:\n char_count[char] = char_count.get(char, 0) + 1\n for char in string:\n if char_count[char] == 1:\n return char\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(string):\n char_count = {}\n for char in string:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n for char in string:\n if char_count[char] == 1:\n return char\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s: str) -> str:\n char_counts = {}\n for char in s:\n if char in char_counts:\n char_counts[char] += 1\n else:\n char_counts[char] = 1\n for char in s:\n if char_counts[char] == 1:\n return char\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n counts = {}\n for c in s:\n if c in counts:\n counts[c] += 1\n else:\n counts[c] = 1\n for c in s:\n if counts[c] == 1:\n return c\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(string):\n \"\"\"\n Function to find the first non-repeated character in a given string.\n \"\"\"\n # Initialize a dictionary to store character counts\n char_counts = {}\n\n # Count the occurrences of each character in the string\n for char in string:\n if char in char_counts:\n char_counts[char] += 1\n else:\n char_counts[char] = 1\n\n # Iterate through the string to find the first non-repeated character\n for char in string:\n if char_counts[char] == 1:\n return char\n\n # Return None if all characters are repeated\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(string):\n char_count = {}\n for char in string:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n for char in string:\n if char_count[char] == 1:\n return char\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(string):\n character_count = {}\n\n # count the occurrence of each character in the string\n for char in string:\n if char in character_count:\n character_count[char] += 1\n else:\n character_count[char] = 1\n\n # find the first character with count of 1\n for char in string:\n if character_count[char] == 1:\n return char\n\n # return None if no such character found\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(string):\n # Use a dictionary to store character counts\n char_counts = {}\n\n # Traverse the string to count characters\n for char in string:\n char_counts[char] = char_counts.get(char, 0) + 1\n\n # Traverse the string again to find the first non-repeated character\n for char in string:\n if char_counts[char] == 1:\n return char\n\n # If all characters are repeated, return None\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n counts = {}\n for c in s:\n if c in counts:\n counts[c] += 1\n else:\n counts[c] = 1\n for c in s:\n if counts[c] == 1:\n return c\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n count = {}\n for ch in s:\n count[ch] = count.get(ch, 0) + 1\n for ch in s:\n if count[ch] == 1:\n return ch\n return None", "matching_cluster_idx": 5}]}, "Mbpp/405": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def check_tuplex(tuplex, element):\n return element in tuplex", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, element):\n if element in tuplex:\n return True\n else:\n return False", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, element):\n return element in tuplex", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, element):\n return element in tuplex", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, elem):\n if elem in tuplex:\n return True\n else:\n return False", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, element):\n return element in tuplex", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, element):\n \"\"\"\n This function checks if an element exists within a tuple.\n \"\"\"\n return element in tuplex", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, element):\n return element in tuplex", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, elem):\n return elem in tuplex", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, elem):\n return elem in tuplex", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, element):\n return element in tuplex", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, ele):\n if ele in tuplex:\n return True\n else:\n return False", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, element):\n return element in tuplex", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, element):\n \"\"\"\n Function to check whether an element exists within a tuple\n \"\"\"\n return element in tuplex", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, elem):\n return elem in tuplex", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, element):\n if element in tuplex:\n return True\n return False", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, element):\n return element in tuplex", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, element):\n return element in tuplex", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, elem):\n return elem in tuplex", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, element):\n # Check if element exists in the tuple\n if element in tuplex:\n return True\n else:\n return False", "matching_cluster_idx": 3}]}, "Mbpp/414": {"dps": 85.71428571428571, "dps_norm": 87.22222222222221, "pass@1": 83.0, "profiled": [{"solution": "def overlapping(seq1, seq2):\n for i in seq1:\n if i in seq2:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(sequence1, sequence2):\n \"\"\"\n This function checks whether any value in the first sequence exists in the second sequence.\n\n Parameters:\n sequence1 (list): A list of integers.\n sequence2 (list): A list of integers.\n\n Returns:\n bool: True if any value in the first sequence exists in the second sequence; False otherwise.\n\n Examples:\n >>> overlapping([1,2,3,4,5],[6,7,8,9])\n False\n \"\"\"\n for value in sequence1:\n if value in sequence2:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n return any(item in seq1 for item in seq2)", "matching_cluster_idx": 8}, {"solution": "def overlapping(seq1, seq2):\n # Check if any element of seq1 is in seq2\n if any(elem in seq2 for elem in seq1):\n return True\n # Check if any element of seq2 is in seq1\n elif any(elem in seq1 for elem in seq2):\n return True\n else:\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n for item in seq1:\n if item in seq2:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(sequence1, sequence2):\n for item in sequence1:\n if item in sequence2:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(sequence1, sequence2):\n for i in sequence1:\n if i in sequence2:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(sequence1, sequence2):\n return bool(set(sequence1) & set(sequence2))", "matching_cluster_idx": 5}, {"solution": "def overlapping(seq1, seq2):\n for element in seq1:\n if element in seq2:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n return any(item in seq1 for item in seq2)", "matching_cluster_idx": 8}, {"solution": "def overlapping(seq1, seq2):\n for i in seq1:\n if i in seq2:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Check whether any value in a sequence exists in another sequence.\n \"\"\"\n return any(value in seq2 for value in seq1)", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n This function checks whether any value in the first sequence exists in the second sequence.\n\n Parameters:\n seq1 (list): The first sequence\n seq2 (list): The second sequence\n\n Returns:\n bool: True if any value in seq1 is in seq2; False otherwise\n \"\"\"\n for item in seq1:\n if item in seq2:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n # iterate over each value in seq1\n for value in seq1:\n # check if value exists in seq2\n if value in seq2:\n # if exists, return True\n return True\n # if no match found after iterating over seq1, return False\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n for value in seq1:\n if value in seq2:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n # check if there is any common element in both sequences\n for i in seq1:\n if i in seq2:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(sequence1, sequence2):\n for i in sequence1:\n if i in sequence2:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n # Check each item in seq1 against every item in seq2\n for item1 in seq1:\n for item2 in seq2:\n if item1 == item2:\n return True\n return False", "matching_cluster_idx": 4}, {"solution": "def overlapping(seq1, seq2):\n for item in seq1:\n if item in seq2:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n for i in seq1:\n if i in seq2:\n return True\n return False", "matching_cluster_idx": 7}]}, "Mbpp/421": {"dps": 78.80658436213992, "dps_norm": 92.85714285714286, "pass@1": 100.0, "profiled": [{"solution": "def concatenate_tuple(tup, delimiter='-'):\n \"\"\"\n This function concatenates each element of the tuple into a string,\n separating the elements by a specified delimiter.\n \"\"\"\n return delimiter.join(map(str, tup))", "matching_cluster_idx": 6}, {"solution": "def concatenate_tuple(tup):\n return \"-\".join(str(element) for element in tup)", "matching_cluster_idx": 4}, {"solution": "def concatenate_tuple(t, delimiter='-'):\n return delimiter.join(map(str, t))", "matching_cluster_idx": 6}, {"solution": "def concatenate_tuple(tup, delimiter='-'):\n return delimiter.join(map(str, tup))", "matching_cluster_idx": 6}, {"solution": "def concatenate_tuple(tup):\n return '-'.join(str(i) for i in tup)", "matching_cluster_idx": 4}, {"solution": "def concatenate_tuple(t, delimiter=\"-\"):\n \"\"\"\n Concatenate each element of tuple by the delimiter.\n \"\"\"\n return delimiter.join(map(str, t))", "matching_cluster_idx": 6}, {"solution": "def concatenate_tuple(input_tuple):\n return \"-\".join(map(str, input_tuple))", "matching_cluster_idx": 6}, {"solution": "def concatenate_tuple(t, delimiter='-'):\n return delimiter.join(map(str, t))", "matching_cluster_idx": 6}, {"solution": "def concatenate_tuple(tup, delimiter='-'):\n return delimiter.join(map(str, tup))", "matching_cluster_idx": 6}, {"solution": "def concatenate_tuple(input_tuple, delimiter='-'):\n \"\"\"\n Function to concatenate each element of tuple by the delimiter.\n\n Parameters:\n input_tuple (tuple): Tuple containing elements to be concatenated\n delimiter (str, optional): Delimiter to use in concatenation. Defaults to '-'.\n\n Returns:\n str: Concatenated string\n \"\"\"\n return delimiter.join(map(str, input_tuple))", "matching_cluster_idx": 6}, {"solution": "def concatenate_tuple(t):\n return '-'.join(str(i) for i in t)", "matching_cluster_idx": 4}, {"solution": "def concatenate_tuple(tup):\n return '-'.join(map(str, tup))", "matching_cluster_idx": 6}, {"solution": "def concatenate_tuple(tup):\n return \"-\".join(str(i) for i in tup)", "matching_cluster_idx": 4}, {"solution": "def concatenate_tuple(tup, delimiter='-'):\n return delimiter.join(map(str, tup))", "matching_cluster_idx": 6}, {"solution": "def concatenate_tuple(tup, delimiter='-'):\n return delimiter.join(map(str, tup))", "matching_cluster_idx": 6}, {"solution": "def concatenate_tuple(tup, delimiter='-'):\n return delimiter.join(map(str, tup))", "matching_cluster_idx": 6}, {"solution": "def concatenate_tuple(tuple, delimiter=\"-\"):\n return delimiter.join(map(str, tuple))", "matching_cluster_idx": 6}, {"solution": "def concatenate_tuple(t, delimiter='-'):\n return delimiter.join(map(str, t))", "matching_cluster_idx": 6}, {"solution": "def concatenate_tuple(tuple_in):\n # Concatenate using the \"-\" as delimiter\n return '-'.join(str(i) for i in tuple_in)", "matching_cluster_idx": 4}, {"solution": "def concatenate_tuple(tup, delimiter='-'):\n return delimiter.join(map(str, tup))", "matching_cluster_idx": 6}]}, "Mbpp/424": {"dps": 78.53790613718412, "dps_norm": 91.0, "pass@1": 100.0, "profiled": [{"solution": "def extract_rear(tup):\n return [s[-1] for s in tup]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(tup):\n return [s[-1] for s in tup]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(t):\n return [i[-1] for i in t]", "matching_cluster_idx": 3}, {"solution": "def extract_rear(input_tuple):\n return [word[-1] for word in input_tuple]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(tup):\n return [s[-1] for s in tup]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(input_tuple):\n result = []\n for word in input_tuple:\n result.append(word[-1])\n return result", "matching_cluster_idx": 3}, {"solution": "def extract_rear(tup):\n return [s[-1] for s in tup]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(tup):\n return [s[-1] for s in tup]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(t):\n #initialize an empty list to store the result\n result = []\n #iterate over the tuple\n for word in t:\n #append the last character of each word to the result list\n result.append(word[-1])\n #return the result\n return result", "matching_cluster_idx": 3}, {"solution": "def extract_rear(tup):\n # initialize an empty list\n result = []\n # for each string in the tuple\n for string in tup:\n # if the string has more than one character (to avoid IndexErrors)\n if len(string) > 1:\n # append the last character to the result\n result.append(string[-1])\n # if the string has only one character, append it to the result\n else:\n result.append(string)\n # return the final result\n return result", "matching_cluster_idx": 2}, {"solution": "def extract_rear(tup):\n return [s[-1] for s in tup]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(tup):\n \"\"\"Extract the last index element of each string in a tuple.\"\"\"\n return [s[-1] for s in tup]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(t):\n return [i[-1] for i in t]", "matching_cluster_idx": 3}, {"solution": "def extract_rear(input_tuple):\n result = []\n for string in input_tuple:\n result.append(string[-1])\n return result", "matching_cluster_idx": 3}, {"solution": "def extract_rear(t):\n return [s[-1] for s in t]", "matching_cluster_idx": 3}, {"solution": "def extract_rear(tup):\n return [s[-1] for s in tup]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(t):\n return [i[-1] for i in t]", "matching_cluster_idx": 3}, {"solution": "def extract_rear(tup):\n return [s[-1] for s in tup]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(input_tuple):\n return [word[-1] for word in input_tuple]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(tup):\n return [s[-1] for s in tup]", "matching_cluster_idx": 4}]}, "Mbpp/425": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def count_element_in_list(lst, element):\n # Initialize count\n count = 0\n # Iterate over sublists\n for sublist in lst:\n # If element in sublist, increment count\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(main_list, element):\n return sum(1 for sublist in main_list if element in sublist)", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, element):\n \"\"\"\n This function counts the number of sublists that contain the specified element.\n \"\"\"\n count = 0\n for sublist in lst:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, elem):\n count = 0\n for sublist in lst:\n if elem in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, elem):\n return sum(1 for sublist in lst if elem in sublist)", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, element):\n count = 0\n for sublist in lst:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, elem):\n count = 0\n for sub_list in lst:\n if elem in sub_list:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, element):\n count = 0\n for sublist in lst:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(input_list, element):\n count = 0\n for sublist in input_list:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(main_list, element):\n # Initialize a count variable to 0\n count = 0\n \n # Loop through each sublist in the main list\n for sublist in main_list:\n # If the element is in the sublist, increment the count\n if element in sublist:\n count += 1\n \n # Return the count\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(main_list, element):\n count = 0\n for sub_list in main_list:\n if element in sub_list:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, el):\n return sum(1 for sublist in lst if el in sublist)", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, elm):\n \"\"\"\n Function to count the number of sublists containing a particular element\n\n Parameters:\n lst (list): list of lists\n elm (any type): element to be counted\n\n Returns:\n int: number of occurrences of `elm` in `lst`\n \"\"\"\n\n return sum(elm in sublist for sublist in lst)", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(sublist_list, element):\n count = 0\n for sublist in sublist_list:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, el):\n count = 0\n for sublist in lst:\n if el in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, element):\n return sum(1 for sublist in lst if element in sublist)", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(input_list, element):\n count = 0\n for sublist in input_list:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, element):\n count = 0\n for sublist in lst:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, elm):\n count = 0\n for sub_lst in lst:\n if elm in sub_lst:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, el):\n count = 0\n for sublist in lst:\n if el in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}]}, "Mbpp/428": {"dps": 84.29752066115702, "dps_norm": 55.55555555555556, "pass@1": 95.0, "profiled": [{"solution": "def shell_sort(arr):\n # Start with a big gap, then reduce the gap\n n = len(arr)\n gap = n//2\n\n # Repeat the sorting process until gap becomes 1\n while gap > 0:\n\n # Do a gapped insertion sort for this gap size.\n # The first gap elements a[0..gap-1] are already in gapped order keep adding one more element\n # until the entire array is gap sorted\n for i in range(gap,n):\n\n # add a[i] to the elements that have been gap sorted save a[i] in temp and make a hole at position i\n temp = arr[i]\n\n # shift earlier gap-sorted elements up until the correct location for 'temp' is found\n j = i\n while j >= gap and arr[j-gap] >temp:\n arr[j] = arr[j-gap]\n j -= gap\n\n # put temp (the original a[i]) in its correct location\n arr[j] = temp\n gap //= 2\n\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2\n\n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n\n arr[j] = temp\n gap //= 2\n\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(array):\n # Start with a big gap, then reduce the gap\n n = len(array)\n gap = n//2\n\n # Do a gapped insertion sort for this gap size.The first gap elements \n # a[0..gap-1] are already in gapped order keep adding one more element \n # until the entire array is gap sorted\n while gap > 0:\n for i in range(gap,n):\n # add a[i] to the elements that have been gap sorted \n # save a[i] in temp and make a hole at position i\n temp = array[i]\n j = i\n # shift earlier gap-sorted elements up until the correct location for temp is found\n while j >= gap and array[j-gap] > temp:\n array[j] = array[j-gap]\n j -= gap\n # put temp (the original a[i]) in its correct location\n array[j] = temp\n gap //= 2\n return array", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2\n\n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(array):\n gap = len(array) // 2\n while gap > 0:\n for i in range(gap, len(array)):\n temp = array[i]\n j = i\n while j >= gap and array[j - gap] > temp:\n array[j] = array[j - gap]\n j -= gap\n array[j] = temp\n gap //= 2\n return array", "matching_cluster_idx": 4}, {"solution": "def shell_sort(array):\n length = len(array)\n gap = length // 2\n while gap > 0:\n for i in range(gap, length):\n temp = array[i]\n j = i\n while j >= gap and array[j - gap] > temp:\n array[j] = array[j - gap]\n j = j-gap\n array[j] = temp\n gap = gap // 2\n return array", "matching_cluster_idx": 4}, {"solution": "def shell_sort(array):\n gap = len(array) // 2\n while gap > 0:\n for i in range(gap, len(array)):\n temp = array[i]\n j = i\n while j >= gap and array[j - gap] > temp:\n array[j] = array[j - gap]\n j -= gap\n array[j] = temp\n gap //= 2\n return array", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n gap = len(arr) // 2\n while gap > 0:\n for i in range(gap, len(arr)):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(array):\n n = len(array)\n gap = n // 2\n\n while gap > 0:\n for i in range(gap, n):\n temp = array[i]\n j = i\n while j >= gap and array[j - gap] > temp:\n array[j] = array[j - gap]\n j -= gap\n array[j] = temp\n gap //= 2\n\n return array", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n//2\n while gap > 0:\n for i in range(gap,n):\n temp = arr[i]\n j = i\n while j >= gap and arr[j-gap] >temp:\n arr[j] = arr[j-gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n//2\n\n while gap > 0:\n for i in range(gap,n):\n temp = arr[i]\n j = i\n while j >= gap and arr[j-gap] > temp:\n arr[j] = arr[j-gap]\n j -= gap\n\n arr[j] = temp\n gap //= 2\n\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n # Start with a big gap, then reduce the gap\n n = len(arr)\n gap = n // 2\n\n # Do a gapped insertion sort for this gap size.\n while gap > 0:\n\n for i in range(gap, n):\n\n # add a[i] to the elements that have been gap sorted\n temp = arr[i]\n\n # shift earlier gap-sorted elements up until the correct location for 'temp' is found\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n\n # put temp (the original arr[i]) in its correct location\n arr[j] = temp\n gap //= 2\n\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(array):\n n = len(array)\n gap = n // 2\n while gap > 0:\n for i in range(gap, n):\n temp = array[i]\n j = i\n while j >= gap and array[j - gap] > temp:\n array[j] = array[j - gap]\n j -= gap\n array[j] = temp\n gap //= 2\n return array", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2\n\n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2\n \n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n \n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n \n arr[j] = temp\n gap //= 2\n \n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(array):\n # Start with a big gap, then reduce the gap\n n = len(array)\n gap = n//2\n\n # Shell Sort\n while gap > 0:\n for i in range(gap,n):\n temp = array[i]\n j = i\n while j >= gap and array[j-gap] > temp:\n array[j] = array[j-gap]\n j -= gap\n array[j] = temp\n gap //= 2\n\n return array", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2\n\n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n\n arr[j] = temp\n\n gap //= 2\n\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(array):\n length = len(array)\n gap = length // 2\n\n while gap > 0:\n for i in range(gap, length):\n temp = array[i]\n j = i\n\n # Compare elements and swap\n while j >= gap and array[j - gap] > temp:\n array[j] = array[j - gap]\n j -= gap\n\n array[j] = temp\n gap //= 2\n\n return array", "matching_cluster_idx": 4}, {"solution": "def shell_sort(array):\n # Start with a big gap, then reduce the gap\n n = len(array)\n gap = n//2\n\n # Loop over the array while the gap is greater than zero\n while gap > 0:\n # Do a gapped 'insertion sort' for this gap size\n # The first gap elements a[0..gap-1] are already in gapped order\n # keep adding one more element until the entire array is gap sorted\n for i in range(gap,n):\n # add a[i] to the elements that have been gap sorted \n temp = array[i]\n j = i\n # shift earlier gap-sorted elements up until the correct \n # location for 'a[i]' is found\n while j >= gap and array[j-gap] > temp:\n array[j] = array[j-gap]\n j -= gap\n # put temp (the original a[i]) in its correct location\n array[j] = temp\n gap //= 2\n return array", "matching_cluster_idx": 4}, {"solution": "def shell_sort(array):\n gap = len(array) // 2\n while gap > 0:\n for i in range(gap, len(array)):\n temp = array[i]\n j = i\n while j >= gap and array[j - gap] > temp:\n array[j] = array[j - gap]\n j -= gap\n array[j] = temp\n gap //= 2\n return array", "matching_cluster_idx": 4}]}, "Mbpp/433": {"dps": null, "dps_norm": null, "pass@1": 7.0, "profiled": []}, "Mbpp/437": {"dps": null, "dps_norm": null, "pass@1": 8.0, "profiled": []}, "Mbpp/440": {"dps": null, "dps_norm": null, "pass@1": 0.0, "profiled": []}, "Mbpp/446": {"dps": 96.05911330049261, "dps_norm": 60.0, "pass@1": 71.0, "profiled": [{"solution": "def count_Occurrence(tup, lst):\n count = 0\n for i in lst:\n count += tup.count(i)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tup, lst):\n count = 0\n for element in lst:\n count += tup.count(element)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tup, lst):\n count = 0\n for item in lst:\n count += tup.count(item)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tuple_input, list_input):\n count = 0\n for i in list_input:\n count += tuple_input.count(i)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tuple_input, list_input):\n # Initialize count to 0\n count = 0\n # For each element in the list\n for i in list_input:\n # Count the number of times the element is in the tuple\n count += tuple_input.count(i)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tuple_input, list_input):\n occurrence_count = 0\n for element in list_input:\n occurrence_count += tuple_input.count(element)\n return occurrence_count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(input_tuple, input_list):\n count = 0\n for elem in input_list:\n count += input_tuple.count(elem)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tup, lst):\n count = 0\n for element in lst:\n count += tup.count(element)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tup, lst):\n count = 0\n for element in lst:\n count += tup.count(element)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tup, lst):\n count = 0\n for element in lst:\n count += tup.count(element)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tup, lst):\n return sum(tup.count(item) for item in lst)", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tuple1, list1):\n count = 0\n for element in list1:\n count += tuple1.count(element)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tuple_var, list_var):\n \"\"\"\n This function counts the occurrence of elements of list in a tuple\n \"\"\"\n count = 0\n for elem in list_var:\n count += tuple_var.count(elem)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tpl, lst):\n return sum(tpl.count(element) for element in lst)", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tpl, lst):\n count = 0\n for i in lst:\n count += tpl.count(i)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(input_tuple, input_list):\n count = 0\n for element in input_list:\n count += input_tuple.count(element)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tuple_input, list_input):\n count = 0\n for item in list_input:\n count += tuple_input.count(item)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(my_tuple, my_list):\n count = 0\n for elem in my_list:\n count += my_tuple.count(elem)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tup, lst):\n count = 0\n for item in lst:\n count += tup.count(item)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tuple_input, list_input):\n # Initialize counter\n counter = 0\n # Iterate over list elements\n for elem in list_input:\n # Count the occurrence of the element in the tuple\n counter += tuple_input.count(elem)\n return counter", "matching_cluster_idx": 2}]}, "Mbpp/451": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 97.0, "profiled": [{"solution": "def remove_whitespaces(input_string):\n return input_string.replace(' ', '')", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string):\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(str1):\n return str1.replace(' ', '')", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string):\n # Replace all whitespaces with empty string\n return input_string.replace(' ', '')", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_str):\n return input_str.replace(' ', '')", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string):\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(s):\n return s.replace(' ', '')", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string):\n return input_string.replace(' ', '')", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string):\n return input_string.replace(' ', '')", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string):\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_str):\n return input_str.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string):\n \"\"\"\n This function removes all whitespaces from the input string.\n :param input_string: The string from which the whitespaces should be removed.\n :return: The string without whitespaces.\n \"\"\"\n return input_string.replace(' ', '')", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string):\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_str):\n return input_str.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string):\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string):\n # Replace all whitespaces with empty string\n no_whitespace_string = input_string.replace(' ', '')\n return no_whitespace_string", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string):\n # Remove all whitespaces from the string.\n # We use the replace() function, which is used to replace a specified phrase with another.\n # In this case, we replace all whitespace characters with no character.\n return input_string.replace(' ', '')", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string):\n return input_string.replace(' ', '')", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string):\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(s):\n return s.replace(' ', '')", "matching_cluster_idx": 4}]}, "Mbpp/456": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def reverse_string_list(lst):\n return [s[::-1] for s in lst]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n \"\"\"\n Returns a new list where each string in the given list is reversed.\n \n >>> reverse_string_list(['Red', 'Green', 'Blue', 'White', 'Black'])\n ['deR', 'neerG', 'eulB', 'etihW', 'kcalB']\n \"\"\"\n return [s[::-1] for s in string_list]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(lst):\n return [s[::-1] for s in lst]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(input_list):\n return [s[::-1] for s in input_list]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(lst):\n return [s[::-1] for s in lst]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(input_list):\n reversed_list = [s[::-1] for s in input_list]\n return reversed_list", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(str_list):\n return [s[::-1] for s in str_list]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n \"\"\"\n This function takes a list of strings and returns a new list where each string has been reversed.\n \"\"\"\n reversed_list = [s[::-1] for s in string_list]\n return reversed_list", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(lst):\n return [s[::-1] for s in lst]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(lst):\n return [s[::-1] for s in lst]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(lst):\n \"\"\"\n Returns a new list where every string in the given list is reversed.\n \"\"\"\n return [s[::-1] for s in lst]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(strings):\n return [s[::-1] for s in strings]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(lst):\n \"\"\"\n This function takes a list of strings as input and returns a new list with all the strings reversed.\n \"\"\"\n return [s[::-1] for s in lst]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(input_list):\n \"\"\"\n This function reverses each string in a given list.\n :param input_list: a list of strings\n :return: a list of reversed strings\n \"\"\"\n return [s[::-1] for s in input_list]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(str_list):\n reversed_list = [s[::-1] for s in str_list]\n return reversed_list", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(strings):\n return [s[::-1] for s in strings]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(lst):\n return [s[::-1] for s in lst]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n return [s[::-1] for s in string_list]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(lst):\n return [s[::-1] for s in lst]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(str_list):\n return [s[::-1] for s in str_list]", "matching_cluster_idx": 4}]}, "Mbpp/460": {"dps": 58.46153846153846, "dps_norm": 84.0, "pass@1": 81.0, "profiled": [{"solution": "def Extract(lst):\n return [sublist[0] for sublist in lst]", "matching_cluster_idx": 3}, {"solution": "def Extract(sublists):\n return [sublist[0] for sublist in sublists]", "matching_cluster_idx": 3}, {"solution": "def Extract(lst):\n result = [sub[0] for sub in lst]\n return result", "matching_cluster_idx": 4}, {"solution": "def Extract(input_list):\n return [sublist[0] for sublist in input_list]", "matching_cluster_idx": 4}, {"solution": "def Extract(input_list):\n return [sublist[0] for sublist in input_list]", "matching_cluster_idx": 4}, {"solution": "def Extract(lst):\n return [item[0] for item in lst]", "matching_cluster_idx": 4}, {"solution": "def Extract(lst):\n return [sublist[0] for sublist in lst]", "matching_cluster_idx": 3}, {"solution": "def Extract(sublists):\n return [sublist[0] for sublist in sublists]", "matching_cluster_idx": 3}, {"solution": "def Extract(sublists):\n return [sublist[0] for sublist in sublists]", "matching_cluster_idx": 3}, {"solution": "def Extract(sublists):\n return [sublist[0] for sublist in sublists]", "matching_cluster_idx": 3}, {"solution": "def Extract(lst):\n return [sublist[0] for sublist in lst]", "matching_cluster_idx": 3}, {"solution": "def Extract(lst):\n return [sublist[0] for sublist in lst]", "matching_cluster_idx": 3}, {"solution": "def Extract(list_of_lists):\n return [sublist[0] for sublist in list_of_lists]", "matching_cluster_idx": 3}, {"solution": "def Extract(lst):\n return [sublist[0] for sublist in lst]", "matching_cluster_idx": 3}, {"solution": "def Extract(lst):\n return [sublist[0] for sublist in lst]", "matching_cluster_idx": 3}, {"solution": "def Extract(lst):\n return [sublist[0] for sublist in lst]", "matching_cluster_idx": 3}, {"solution": "def Extract(lst):\n return [sublist[0] for sublist in lst]", "matching_cluster_idx": 3}, {"solution": "def Extract(lst):\n return [sublist[0] for sublist in lst]", "matching_cluster_idx": 3}, {"solution": "def Extract(lst):\n return [sublist[0] for sublist in lst]", "matching_cluster_idx": 3}, {"solution": "def Extract(lst):\n return [sublist[0] for sublist in lst]", "matching_cluster_idx": 3}]}, "Mbpp/474": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def replace_char(s, old, new):\n \"\"\"\n This function replaces all occurrences of a character in a string with another character.\n\n Args:\n s (str): The input string.\n old (str): The character to be replaced.\n new (str): The character to replace with.\n\n Returns:\n str: The modified string after replacing all occurrences of old character with new character.\n \"\"\"\n return s.replace(old, new)", "matching_cluster_idx": 6}, {"solution": "def replace_char(input_str, old_char, new_char):\n # Replaces all occurrences of 'old_char' with 'new_char' in 'input_str'\n return input_str.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s: str, old_char: str, new_char: str) -> str:\n return s.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(str_input, char_to_replace, new_char):\n return str_input.replace(char_to_replace, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(input_string, old_char, new_char):\n \"\"\"\n This function takes a string, a character to be replaced, and a replacement character, and replaces the old character with the new character in the input string.\n \"\"\"\n return input_string.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, old_char, new_char):\n return s.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(input_string, target_char, replacement_char):\n return input_string.replace(target_char, replacement_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(text, old_char, new_char):\n return text.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(input_str, old_char, new_char):\n return input_str.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, old_char, new_char):\n return s.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(input_string, old_char, new_char):\n return input_string.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(string, to_replace, replace_with):\n \"\"\"\n Replace all occurrences of a character in a string with another character.\n \"\"\"\n return string.replace(to_replace, replace_with)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, target, replacement):\n return s.replace(target, replacement)", "matching_cluster_idx": 6}, {"solution": "def replace_char(input_string, char_to_replace, replacement_char):\n return input_string.replace(char_to_replace, replacement_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, old, new):\n \"\"\"\n Function to replace characters in a string.\n \"\"\"\n return s.replace(old, new)", "matching_cluster_idx": 6}, {"solution": "def replace_char(input_str, old_char, new_char):\n return input_str.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, target, replacement):\n return s.replace(target, replacement)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, old_char, new_char):\n return s.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, c1, c2):\n return s.replace(c1, c2)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, o, n):\n return s.replace(o, n)", "matching_cluster_idx": 6}]}, "Mbpp/476": {"dps": 86.94630872483222, "dps_norm": 91.66666666666667, "pass@1": 98.0, "profiled": [{"solution": "def big_sum(arr):\n \"\"\"\n This function takes an array of integers as an argument,\n finds the largest and smallest values in the array,\n and returns the sum of these two values.\n \"\"\"\n if len(arr)==0: # if the list is empty\n return 0\n else:\n return max(arr) + min(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n # checking if arr is empty\n if not arr:\n return None\n\n # checking if arr has only 1 element\n if len(arr) == 1:\n return arr[0]\n\n return max(arr) + min(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n \"\"\"\n This function accepts a list of integers, finds the largest and the smallest values in the list, \n and returns the sum of these two values.\n \"\"\"\n return max(arr) + min(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n if not arr:\n return 0\n return max(arr) + min(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n \"\"\"\n This function finds the sum of the largest and smallest value in a given array.\n \"\"\"\n # Check if array is not empty\n if arr:\n return max(arr) + min(arr)\n else:\n return None", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n if arr:\n return max(arr) + min(arr)\n else:\n return 0", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n if not arr:\n return 0\n return max(arr) + min(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n return max(arr) + min(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n # find minimum and maximum values in the array\n min_val = min(arr)\n max_val = max(arr)\n # return the sum of these values\n return min_val + max_val", "matching_cluster_idx": 5}, {"solution": "def big_sum(array):\n return max(array) + min(array)", "matching_cluster_idx": 5}, {"solution": "def big_sum(array):\n \"\"\"\n The function takes an array as input and returns the sum of the largest and smallest value in the array.\n \"\"\"\n # Sort the array in ascending order\n array.sort()\n # The sum of the smallest and largest values is calculated and returned\n return array[0] + array[-1]", "matching_cluster_idx": 1}, {"solution": "def big_sum(arr):\n return max(arr) + min(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(array):\n \"\"\"\n This function takes in an array of integers and returns the sum of the largest and smallest integer.\n \"\"\"\n # Sort the array in ascending order\n array.sort()\n\n # Calculate the sum of the largest and smallest values\n big_sum_result = array[-1] + array[0]\n \n return big_sum_result", "matching_cluster_idx": 1}, {"solution": "def big_sum(arr):\n return max(arr) + min(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n \"\"\"Return the sum of the largest and smallest values in an array.\"\"\"\n return max(arr) + min(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n # check if the array is not empty\n if arr:\n return max(arr) + min(arr)\n else:\n return 0", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n \"\"\"\n This function takes an array of numbers as input, finds the largest and smallest numbers in the array\n and returns their sum.\n\n Parameters:\n arr (List[int]): A list of integers.\n\n Returns:\n int: The sum of the largest and smallest numbers in the array.\n \"\"\"\n\n # If the list is empty, return 0\n if len(arr) == 0:\n return 0\n\n # Initialize the largest and smallest numbers as the first number in the list\n smallest = largest = arr[0]\n\n # Iterate over the list\n for num in arr:\n\n # If the current number is smaller than the smallest, update the smallest\n if num < smallest:\n smallest = num\n\n # If the current number is larger than the largest, update the largest\n if num > largest:\n largest = num\n\n # Return the sum of the smallest and largest numbers\n return smallest + largest", "matching_cluster_idx": 3}, {"solution": "def big_sum(lst):\n \"\"\"Return the sum of the largest and smallest value in a given list.\"\"\"\n if len(lst)>0:\n return max(lst) + min(lst)\n else:\n return \"List is empty\"", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n if len(arr) == 0:\n return 0\n max_val = max(arr)\n min_val = min(arr)\n return max_val + min_val", "matching_cluster_idx": 5}, {"solution": "def big_sum(nums):\n # We assume that the list is not empty\n # Otherwise, we should add a check for empty lists\n return max(nums) + min(nums)", "matching_cluster_idx": 5}]}, "Mbpp/477": {"dps": null, "dps_norm": null, "pass@1": 8.0, "profiled": []}, "Mbpp/563": {"dps": 85.24590163934427, "dps_norm": 81.81818181818181, "pass@1": 99.0, "profiled": [{"solution": "import re\ndef extract_values(s):\n return re.findall(r'\"([^\"]*)\"', s)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(string):\n return re.findall(r'\"(.*?)\"', string)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(str):\n # Find all substrings in string that are enclosed in quotes\n quotes = re.findall(r'\"([^\"]*)\"', str)\n return quotes", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(s):\n return re.findall(r'\"([^\"]*)\"', s)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(s):\n return re.findall(r'\"([^\"]*)\"', s)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(s):\n return re.findall(r'\"([^\"]*)\"', s)", "matching_cluster_idx": 8}, {"solution": "def extract_values(s):\n import re\n return re.findall(r'\"([^\"]*)\"', s)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(s):\n return re.findall(r'\"([^\"]*)\"', s)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(s):\n return re.findall(r'\"([^\"]*)\"', s)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(s):\n return re.findall(r'\"([^\"]*)\"', s)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(string):\n return re.findall(r'\"([^\"]*)\"', string)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(string):\n return re.findall(r'\"([^\"]*)\"', string)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(s):\n return re.findall(r'\"([^\"]*)\"', s)", "matching_cluster_idx": 8}, {"solution": "def extract_values(string):\n import re\n return re.findall(r'\"([^\"]*)\"', string)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(s):\n return re.findall(r'\"([^\"]*)\"', s)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(s):\n return re.findall(r'\"([^\"]*)\"', s)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(s):\n return re.findall(r'\"([^\"]*)\"', s)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(input_string):\n \"\"\"\n Extracts values between quotation marks in a string\n \"\"\"\n return re.findall(r'\"([^\"]*)\"', input_string)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(s):\n return re.findall(r'\"([^\"]*)\"', s)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(s):\n return re.findall(r'\"([^\"]*)\"', s)", "matching_cluster_idx": 8}]}, "Mbpp/572": {"dps": 56.84624017957352, "dps_norm": 54.54545454545455, "pass@1": 11.0, "profiled": [{"solution": "def two_unique_nums(num_list):\n result = []\n for num in num_list:\n if num_list.count(num) == 1:\n result.append(num)\n return result", "matching_cluster_idx": 1}, {"solution": "def two_unique_nums(lst):\n return [item for item in lst if lst.count(item) == 1]", "matching_cluster_idx": 1}, {"solution": "def two_unique_nums(lst):\n # Count the occurrences of each element in the list\n num_dict = {num: lst.count(num) for num in lst}\n # Only keep elements which appear exactly once (i.e., they are unique)\n unique_nums = [num for num, count in num_dict.items() if count == 1]\n return unique_nums", "matching_cluster_idx": 1}, {"solution": "def two_unique_nums(nums):\n unique_nums = set(nums)\n return [num for num in nums if nums.count(num) == 1]", "matching_cluster_idx": 1}, {"solution": "def two_unique_nums(nums):\n # create a dictionary\n num_dict = {}\n # iterate through each number\n for num in nums:\n # if the number is already in the dictionary, increment its count\n # otherwise, set its count to 1\n num_dict[num] = num_dict.get(num, 0) + 1\n \n # create a list of numbers that appear exactly once\n unique_nums = [num for num, count in num_dict.items() if count == 1]\n \n return unique_nums", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(num_list):\n unique_nums = []\n for num in num_list:\n if num_list.count(num) == 1:\n unique_nums.append(num)\n return unique_nums", "matching_cluster_idx": 1}, {"solution": "def two_unique_nums(num_list):\n \"\"\"\n This function receives a list of numbers and removes duplicate numbers.\n \"\"\"\n\n # Make an empty dictionary to store numbers\n num_dict = {}\n\n # Go through each number in the list\n for num in num_list:\n\n # If the number is already in the dictionary, increment its count\n if num in num_dict:\n num_dict[num] += 1\n\n # If the number is not in the dictionary, add it with a count of 1\n else:\n num_dict[num] = 1\n\n # Make a new list to store unique numbers\n unique_num_list = []\n\n # Go through each item in the dictionary\n for item in num_dict.items():\n\n # If the count of the number is 1, add the number to the list\n if item[1] == 1:\n unique_num_list.append(item[0])\n\n return unique_num_list", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(nums):\n counts = {}\n for num in nums:\n counts[num] = counts.get(num, 0) + 1\n return [num for num, count in counts.items() if count == 1]", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(num_list):\n # Create a dictionary to store unique numbers\n unique_dict = {}\n\n # Iterate over the list\n for num in num_list:\n # If the number is already in the dictionary, add it to a list\n if num in unique_dict:\n unique_dict[num].append(num)\n # If not, add it to the dictionary\n else:\n unique_dict[num] = [num]\n\n # Collect the keys with only one occurrence\n non_duplicates = [key for key, value in unique_dict.items() if len(value) == 1]\n\n return non_duplicates", "matching_cluster_idx": 4}, {"solution": "def two_unique_nums(lst):\n num_counts = {}\n\n for num in lst:\n if num in num_counts:\n num_counts[num] += 1\n else:\n num_counts[num] = 1\n\n unique_nums = []\n for num, count in num_counts.items():\n if count == 1:\n unique_nums.append(num)\n\n return unique_nums", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(nums):\n unique = []\n duplicates = []\n for num in nums:\n if num not in unique:\n unique.append(num)\n elif num not in duplicates:\n duplicates.append(num)\n return [num for num in nums if num not in duplicates]", "matching_cluster_idx": 2}]}, "Mbpp/578": {"dps": 80.76190476190476, "dps_norm": 69.0909090909091, "pass@1": 99.0, "profiled": [{"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"\n This function takes three lists of equal length and returns a new list which is the interleaving of the three input lists.\n \"\"\"\n # Ensure all lists have same length\n assert len(list1) == len(list2) == len(list3)\n\n # Interleave lists\n interleaved_list = [val for pair in zip(list1, list2, list3) for val in pair]\n\n return interleaved_list", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(list1, list2, list3):\n interleaved_list = [val for pair in zip(list1, list2, list3) for val in pair]\n return interleaved_list", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(a, b, c):\n return [val for pair in zip(a, b, c) for val in pair]", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(lst1, lst2, lst3):\n result = []\n for i in range(len(lst1)):\n result.extend([lst1[i], lst2[i], lst3[i]])\n return result", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(lst1, lst2, lst3):\n return [val for pair in zip(lst1, lst2, lst3) for val in pair]", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(list1, list2, list3):\n # initialize an empty list to store the result\n result = []\n \n # iterate over the indices of the lists\n for i in range(len(list1)):\n # append each element of the three lists to the result list\n result.extend([list1[i], list2[i], list3[i]])\n \n return result", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(l1, l2, l3):\n interleaved = []\n for i in range(len(l1)):\n interleaved.append(l1[i])\n interleaved.append(l2[i])\n interleaved.append(l3[i])\n return interleaved", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(a, b, c):\n return [val for pair in zip(a, b, c) for val in pair]", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(list1, list2, list3):\n return [j for i in zip(list1, list2, list3) for j in i]", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(lst1, lst2, lst3):\n interleaved = [None]*(len(lst1)*3)\n for i in range(len(lst1)):\n interleaved[i*3] = lst1[i]\n interleaved[i*3+1] = lst2[i]\n interleaved[i*3+2] = lst3[i]\n return interleaved", "matching_cluster_idx": 5}, {"solution": "def interleave_lists(list1, list2, list3):\n interleaved = []\n for i in range(len(list1)):\n interleaved.append(list1[i])\n interleaved.append(list2[i])\n interleaved.append(list3[i])\n return interleaved", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n interleaved_list = []\n for i in range(len(list1)):\n interleaved_list.append(list1[i])\n interleaved_list.append(list2[i])\n interleaved_list.append(list3[i])\n return interleaved_list", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(l1, l2, l3):\n return [val for pair in zip(l1, l2, l3) for val in pair]", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(list1, list2, list3):\n return [val for pair in zip(list1, list2, list3) for val in pair]", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(list1, list2, list3):\n return [val for pair in zip(list1, list2, list3) for val in pair]", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(l1, l2, l3):\n return [val for pair in zip(l1, l2, l3) for val in pair]", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(list1, list2, list3):\n interleaved = []\n for i in range(len(list1)):\n interleaved.extend([list1[i], list2[i], list3[i]])\n return interleaved", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n return [val for pair in zip(list1, list2, list3) for val in pair]", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(list1, list2, list3):\n return [val for pair in zip(list1, list2, list3) for val in pair]", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(list1, list2, list3):\n return [val for pair in zip(list1, list2, list3) for val in pair]", "matching_cluster_idx": 7}]}, "Mbpp/586": {"dps": 98.83040935672514, "dps_norm": 87.5, "pass@1": 96.0, "profiled": [{"solution": "def split_Arr(arr, n):\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(lst, n):\n return lst[n:] + lst[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n # split the array at the nth element and add the first part to the end\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(lst, n):\n return lst[n:] + lst[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(input_list, n):\n return input_list[n:] + input_list[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(lst, n):\n # Split the list at the nth element\n first_half = lst[:n]\n second_half = lst[n:]\n\n # Add the first part to the end\n return second_half + first_half", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(input_list, n):\n # Split the list at the nth element and add the first part to the end\n return input_list[n:] + input_list[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(input_array, n):\n # Splitting the list at nth element and adding first part to the end\n split_list = input_array[n:] + input_array[:n]\n return split_list", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n if n < len(arr):\n arr = arr[n:] + arr[:n]\n return arr", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n # Split the list at the nth element\n # Then combine the two parts and add the first part to the end\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(lst, n):\n \"\"\"\n This function splits a given list at the nth element and adds the first part to the end.\n \n Args:\n lst (list): The list to be split and rearranged.\n n (int): The index at which the list should be split.\n\n Returns:\n list: The rearranged list.\n \"\"\"\n return lst[n:] + lst[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(input_list, n):\n return input_list[n:] + input_list[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n # Split the list at nth position and add the first part to the end\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n # split the array at the nth element and add the first part to the end\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(input_list, n):\n if len(input_list) > n:\n return input_list[n:] + input_list[:n]\n return input_list", "matching_cluster_idx": 6}, {"solution": "def split_Arr(lst, n):\n \"\"\"\n Splits a list at the nth element and moves the first part to the end.\n\n Parameters:\n lst (list): The list to be split.\n n (int): The index at which to split the list.\n\n Returns:\n list: The split list with the first part moved to the end.\n \"\"\"\n return lst[n:] + lst[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(input_list, n):\n # Split the list at the nth element and add the first part to the end\n return input_list[n:] + input_list[:n]", "matching_cluster_idx": 6}]}, "Mbpp/587": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def list_tuple(input_list):\n return tuple(input_list)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n \"\"\"\n This function converts a list into a tuple.\n \"\"\"\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n \"\"\"\n This function converts a list to a tuple\n\n Arguments:\n lst -- the list to be converted\n\n Returns:\n a tuple which is the conversion result\n \"\"\"\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(input_list):\n return tuple(input_list)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n return tuple(lst)", "matching_cluster_idx": 3}]}, "Mbpp/588": {"dps": 97.13302752293578, "dps_norm": 99.16666666666667, "pass@1": 100.0, "profiled": [{"solution": "def big_diff(lst):\n if lst: # checking if the list is not empty\n return max(lst) - min(lst)\n return 0", "matching_cluster_idx": 5}, {"solution": "def big_diff(lst):\n if lst: # checking if list is not empty\n return max(lst) - min(lst)\n else:\n return \"List is empty\"", "matching_cluster_idx": 5}, {"solution": "def big_diff(lst):\n return max(lst) - min(lst)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(lst):\n return max(lst) - min(lst)", "matching_cluster_idx": 5}, {"solution": "def big_diff(lst):\n return max(lst) - min(lst)", "matching_cluster_idx": 5}, {"solution": "def big_diff(lst):\n \"\"\"\n This function calculates the difference between the largest and smallest values in a given list.\n \n :param lst: A list of integers.\n :return: An integer representing the difference between the largest and smallest values.\n \"\"\"\n if not lst:\n return 0\n return max(lst) - min(lst)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(lst):\n return max(lst) - min(lst)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n if nums:\n return max(nums) - min(nums)\n else:\n return 0", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n if len(nums) < 2:\n return 0\n else:\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(lst):\n if not lst:\n return 0\n max_val = max(lst)\n min_val = min(lst)\n return max_val - min_val", "matching_cluster_idx": 5}, {"solution": "def big_diff(lst):\n # Check if the list is empty\n if len(lst) == 0:\n return 0\n \n min_val = lst[0]\n max_val = lst[0]\n\n for num in lst:\n # Update min_val if we find a smaller number\n if num < min_val:\n min_val = num\n # Update max_val if we find a larger number\n if num > max_val:\n max_val = num\n\n # Return the difference between max_val and min_val\n return max_val - min_val", "matching_cluster_idx": 4}, {"solution": "def big_diff(nums):\n if len(nums) < 2:\n return 0\n else:\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(lst):\n return max(lst) - min(lst)", "matching_cluster_idx": 5}, {"solution": "def big_diff(lst):\n if lst: # ensure that the list is not empty\n return max(lst) - min(lst)\n else:\n return \"List is empty\"", "matching_cluster_idx": 5}, {"solution": "def big_diff(lst):\n if lst:\n return max(lst) - min(lst)\n else:\n return 0", "matching_cluster_idx": 5}, {"solution": "def big_diff(lst):\n return max(lst) - min(lst)", "matching_cluster_idx": 5}, {"solution": "def big_diff(lst):\n if lst: # ensure list is not empty\n return max(lst) - min(lst)\n return 0 # or raise an exception if you want to indicate an error", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n return max(nums) - min(nums)", "matching_cluster_idx": 5}]}, "Mbpp/592": {"dps": null, "dps_norm": null, "pass@1": 8.0, "profiled": []}, "Mbpp/597": {"dps": 95.07462686567165, "dps_norm": 96.25, "pass@1": 82.0, "profiled": [{"solution": "def find_kth(arr1, arr2, k):\n return sorted(arr1 + arr2)[k - 1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(arr1, arr2, k):\n \"\"\"\n Merge the given two sorted arrays and return kth element.\n \"\"\"\n # Merge two sorted arrays\n arr = sorted(arr1 + arr2)\n # Return kth element\n return arr[k-1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(arr1, arr2, k):\n \"\"\"\n Function to find kth element from the given two sorted arrays.\n \"\"\"\n # Combine the two sorted arrays into one\n combined = sorted(arr1 + arr2)\n\n # Return the kth element\n return combined[k - 1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(arr1, arr2, k):\n merged = sorted(arr1 + arr2)\n return merged[k-1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(nums1, nums2, k):\n \"\"\"\n This function merges the two sorted lists, sorts the merged list and returns the kth element.\n \"\"\"\n # Merge the two lists\n merged = nums1 + nums2\n # Sort the merged list\n merged.sort()\n # Return the kth element\n return merged[k-1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(arr1, arr2, k):\n combined = sorted(arr1 + arr2)\n return combined[k - 1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(nums1, nums2, k):\n \"\"\"\n :type nums1: List[int]\n :type nums2: List[int]\n :type k: int\n :rtype: int\n \"\"\"\n return sorted(nums1 + nums2)[k - 1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(nums1, nums2, k):\n \"\"\"\n Given two sorted arrays, find the kth element\n \"\"\"\n # Merge the two sorted arrays\n merged = sorted(nums1 + nums2)\n \n # Return the kth element from the merged array\n return merged[k - 1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(nums1, nums2, k):\n \"\"\"\n This function is used to find the kth element from two sorted arrays.\n \n :param nums1: a list of sorted integers\n :param nums2: a list of sorted integers\n :param k: the kth element to find\n :return: kth element from merged list of nums1 and nums2\n \"\"\"\n \n # merge both arrays\n merged = sorted(nums1 + nums2)\n\n # check if k is out of range\n if k > len(merged):\n return \"k is out of range!\"\n else:\n return merged[k - 1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(arr1, arr2, k):\n # Merging two lists and sorting\n merged = sorted(arr1 + arr2)\n \n # Return kth element\n return merged[k - 1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(arr1, arr2, k):\n merged = sorted(arr1 + arr2)\n return merged[k - 1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(arr1, arr2, k):\n \"\"\"\n Find the kth element from the given two sorted arrays.\n \"\"\"\n # merge the two arrays\n merged = sorted(arr1 + arr2)\n\n # check if k is out of range\n if k > len(merged) or k < 1:\n return None\n\n # return kth element\n return merged[k - 1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(nums1, nums2, k):\n nums1.sort()\n nums2.sort()\n i = j = 0\n curr = prev = None\n while i + j < k:\n if i == len(nums1):\n curr = nums2[j]\n j += 1\n elif j == len(nums2):\n curr = nums1[i]\n i += 1\n elif nums1[i] < nums2[j]:\n curr = nums1[i]\n i += 1\n else:\n curr = nums2[j]\n j += 1\n prev = curr\n return prev", "matching_cluster_idx": 0}, {"solution": "def find_kth(nums1, nums2, k):\n merged = sorted(nums1 + nums2)\n return merged[k - 1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(nums1, nums2, k):\n # Concatenate the two lists\n merged = sorted(nums1 + nums2)\n\n # Return kth element from the merged list\n return merged[k - 1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(nums1, nums2, k):\n merged = sorted(nums1 + nums2)\n return merged[k - 1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(arr1, arr2, k):\n # Merge the two arrays into one sorted array.\n merged = sorted(arr1 + arr2)\n # Check if k is out of range\n if k > len(merged) or k <= 0:\n return 'k is out of range.'\n else:\n # Return the kth element\n return merged[k - 1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(nums1, nums2, k):\n \"\"\"\n Function to find the kth element from the given two sorted arrays.\n :param nums1: First sorted array\n :param nums2: Second sorted array\n :param k: Kth element to be found\n :return: Kth element from the merged sorted array\n \"\"\"\n assert k > 0, \"K should be greater than 0\"\n nums1.extend(nums2)\n nums1.sort()\n return nums1[k-1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(nums1, nums2, k):\n \"\"\"\n Given two sorted arrays, find the kth element.\n \"\"\"\n # Merge the arrays\n merged = sorted(nums1 + nums2)\n # Return the kth element\n return merged[k - 1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(arr1, arr2, k):\n merged_arr = sorted(arr1 + arr2)\n return merged_arr[k-1]", "matching_cluster_idx": 3}]}, "Mbpp/604": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 54.0, "profiled": [{"solution": "def reverse_words(s):\n return \" \".join(s.split()[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s: str) -> str:\n return ' '.join(reversed(s.split()))", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n return \" \".join(s.split()[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n return ' '.join(s.split()[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n return \" \".join(s.split()[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n words = s.split()\n words.reverse()\n return ' '.join(words)", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n return ' '.join(s.split()[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s: str) -> str:\n return \" \".join(s.split()[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n return ' '.join(s.split()[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(string):\n words = string.split()[::-1] \n return ' '.join(words)", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s: str) -> str:\n return ' '.join(s.split()[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n return \" \".join(s.split()[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(input_str):\n return \" \".join(input_str.split()[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n \"\"\"\n This function reverses the words in a given string separated by spaces.\n \"\"\"\n return \" \".join(s.split()[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n # split the string into words\n words = s.split()\n # reverse the order of the words\n words = words[::-1]\n # join the words back into a string with a space separator\n s = ' '.join(words)\n return s", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s: str) -> str:\n return ' '.join(s.split()[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n return \" \".join(s.split()[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n return \" \".join(s.split()[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(input_string):\n words = input_string.split()\n reversed_words = \" \".join(reversed(words))\n return reversed_words", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n # split the string by spaces and then reverse the list of words\n words = s.split()[::-1]\n # join the words back into a string\n reversed_s = ' '.join(words)\n return reversed_s", "matching_cluster_idx": 4}]}, "Mbpp/610": {"dps": 67.75362318840581, "dps_norm": 79.46428571428571, "pass@1": 16.0, "profiled": [{"solution": "def remove_kth_element(lst, k):\n # Ensure the index is within the bounds of the list\n if k-1 < len(lst):\n # Remove the k'th element\n del lst[k-1]\n return lst", "matching_cluster_idx": 6}, {"solution": "def remove_kth_element(lst, k):\n if k < 1 or k > len(lst):\n return lst\n else:\n return lst[:k-1] + lst[k:]", "matching_cluster_idx": 2}, {"solution": "def remove_kth_element(lst, k):\n \"\"\"\n This function takes in a list and an integer k, and returns a list with the k'th element removed.\n \"\"\"\n del lst[k-1]\n return lst", "matching_cluster_idx": 6}, {"solution": "def remove_kth_element(lst, k):\n if k < 1 or k > len(lst):\n return lst\n return lst[:k-1] + lst[k:]", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(lst, k):\n del lst[k-1]\n return lst", "matching_cluster_idx": 6}, {"solution": "def remove_kth_element(lst, k):\n del lst[k-1]\n return lst", "matching_cluster_idx": 6}, {"solution": "def remove_kth_element(lst, k):\n # Indexing in Python starts from 0, so we need to subtract 1 from k\n if k-1 in range(len(lst)):\n return lst[:k-1] + lst[k:]\n else:\n return lst", "matching_cluster_idx": 2}, {"solution": "def remove_kth_element(lst, k):\n # The list is 0-indexed, so we subtract 1 from k\n del lst[k-1]\n return lst", "matching_cluster_idx": 6}, {"solution": "def remove_kth_element(lst, k):\n # Remove the k'th element from the list\n del lst[k-1]\n # Return the modified list\n return lst", "matching_cluster_idx": 6}, {"solution": "def remove_kth_element(lst, k):\n if k > 0 and k <= len(lst):\n return lst[:k-1] + lst[k:]\n else:\n return lst", "matching_cluster_idx": 2}, {"solution": "def remove_kth_element(input_list, k):\n \"\"\"\n This function takes a list and a number, 'k', and returns a new list with the k'th element removed.\n \"\"\"\n if k < 1 or k > len(input_list):\n return input_list\n else:\n return input_list[:k - 1] + input_list[k:]", "matching_cluster_idx": 2}, {"solution": "def remove_kth_element(lst, k):\n del lst[k-1]\n return lst", "matching_cluster_idx": 6}, {"solution": "def remove_kth_element(lst, k):\n # validate that k is within the list's range\n if k-1 < len(lst):\n # remove the k'th element using the list slicing\n new_lst = lst[:k-1] + lst[k:]\n return new_lst\n else:\n return \"Invalid k, it is out of the list's range.\"", "matching_cluster_idx": 2}, {"solution": "def remove_kth_element(input_list, k):\n del input_list[k-1]\n return input_list", "matching_cluster_idx": 6}, {"solution": "def remove_kth_element(input_list, k):\n \"\"\"\n This function takes a list and an integer as arguments and returns a list with the same elements, \n but the k'th element removed.\n \"\"\"\n del input_list[k-1]\n return input_list", "matching_cluster_idx": 6}, {"solution": "def remove_kth_element(lst, k):\n del lst[k-1] # Python lists index from 0, so we remove the (k-1)th element\n return lst", "matching_cluster_idx": 6}]}, "Mbpp/611": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def max_of_nth(matrix, n):\n \"\"\"\n Given a matrix represented as a list of lists \n return the max of the n'th column.\n \"\"\"\n return max(row[n] for row in matrix)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n # get the n'th column from the matrix\n column = [row[n] for row in matrix]\n # return the maximum value in the n'th column\n return max(column)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n return max(row[n] for row in matrix)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n return max(row[n] for row in matrix)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n return max(row[n] for row in matrix)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n return max(row[n] for row in matrix)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n return max(row[n] for row in matrix)\nmatrix = [[5, 6, 7], [1, 3, 5], [8, 9, 19]]\nn = 2", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n # Using list comprehension to get nth element of every row and find the max\n return max(row[n] for row in matrix)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n return max(row[n] for row in matrix)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n return max(row[n] for row in matrix)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n # Using list comprehension to extract the n'th element from each list in the matrix\n column = [row[n] for row in matrix]\n # Returning the max value from the column list\n return max(column)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n return max(row[n] for row in matrix)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n return max(row[n] for row in matrix)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n return max(row[n] for row in matrix)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n \"\"\"\n Function to find the maximum value in the n-th column of the matrix.\n :param matrix: 2D list (matrix) to process.\n :param n: Column number to look at.\n :return: Maximum value in the n-th column.\n \"\"\"\n return max(row[n] for row in matrix)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n return max(row[n] for row in matrix)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n return max(row[n] for row in matrix)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n return max(row[n] for row in matrix)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n \"\"\"\n This function takes in a matrix represented as a list of lists and an integer n.\n It returns the maximum value of the n-th column in the matrix.\n \"\"\"\n return max(row[n] for row in matrix)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n \"\"\"\n This function returns the max of the n'th column in a matrix.\n\n Parameters:\n matrix (List[List[int]]): The input matrix.\n n (int): The n'th column to find the max of.\n\n Returns:\n int: The maximum element in the n'th column of the matrix.\n\n \"\"\"\n return max(row[n] for row in matrix)", "matching_cluster_idx": 5}]}, "Mbpp/631": {"dps": 56.24999999999999, "dps_norm": 57.142857142857146, "pass@1": 14.0, "profiled": [{"solution": "def replace_spaces(s):\n result = \"\"\n for c in s:\n if c == \" \":\n result += \"_\"\n elif c == \"_\":\n result += \" \"\n else:\n result += c\n return result", "matching_cluster_idx": 2}, {"solution": "def replace_spaces(string):\n new_string = ''\n for character in string:\n if character == ' ':\n new_string += '_'\n elif character == '_':\n new_string += ' '\n else:\n new_string += character\n return new_string", "matching_cluster_idx": 2}, {"solution": "def replace_spaces(s):\n result = ''\n for char in s:\n if char == ' ':\n result += '_'\n elif char == '_':\n result += ' '\n else:\n result += char\n return result", "matching_cluster_idx": 2}, {"solution": "def replace_spaces(string):\n new_string = \"\"\n for char in string:\n if char == ' ':\n new_string += '_'\n elif char == '_':\n new_string += ' '\n else:\n new_string += char\n return new_string", "matching_cluster_idx": 1}, {"solution": "def replace_spaces(string):\n result = \"\"\n for char in string:\n if char == \" \":\n result += \"_\"\n elif char == \"_\":\n result += \" \"\n else:\n result += char\n return result", "matching_cluster_idx": 1}, {"solution": "def replace_spaces(text):\n result = ''\n for char in text:\n if char == ' ':\n result += '_'\n elif char == '_':\n result += ' '\n else:\n result += char\n return result", "matching_cluster_idx": 1}, {"solution": "def replace_spaces(s):\n \"\"\"\n This function receives a string and replaces all whitespaces with underscores and vice versa.\n \"\"\"\n return s.replace(' ', '_') if ' ' in s else s.replace('_', ' ')", "matching_cluster_idx": 7}, {"solution": "def replace_spaces(input_string):\n if ' ' in input_string:\n return input_string.replace(' ', '_')\n else:\n return input_string.replace('_', ' ')", "matching_cluster_idx": 7}, {"solution": "def replace_spaces(input_str):\n if \" \" in input_str:\n return input_str.replace(\" \", \"_\")\n else:\n return input_str.replace(\"_\", \" \")", "matching_cluster_idx": 7}, {"solution": "def replace_spaces(s):\n \"\"\"\n This function takes a string s and replaces all spaces with underscore(_) and vice versa.\n\n Input:\n s(str): Input string\n\n Output:\n str: Output string after replacement\n \"\"\"\n return s.replace(' ', '_') if ' ' in s else s.replace('_', ' ')", "matching_cluster_idx": 7}, {"solution": "def replace_spaces(s):\n \"\"\"\n This function takes a string as input and returns the same string but with all spaces replaced with underscores\n and all underscores replaced with spaces.\n \"\"\"\n result = \"\"\n for char in s:\n if char == \" \":\n result += \"_\"\n elif char == \"_\":\n result += \" \"\n else:\n result += char\n return result", "matching_cluster_idx": 2}, {"solution": "def replace_spaces(s):\n \"\"\"\n This function takes a string s and replaces whitespaces with underscores \n and vice versa in the string.\n \"\"\"\n new_string = ''\n for ch in s:\n if ch == ' ':\n new_string += '_'\n elif ch == '_':\n new_string += ' '\n else:\n new_string += ch\n return new_string", "matching_cluster_idx": 2}, {"solution": "def replace_spaces(s):\n result = ''\n for character in s:\n if character == ' ':\n result += '_'\n elif character == '_':\n result += ' '\n else:\n result += character\n return result", "matching_cluster_idx": 2}, {"solution": "def replace_spaces(s):\n # Replace underscores with whitespaces and vice versa\n return s.replace(' ', '_') if '_' not in s else s.replace('_', ' ')", "matching_cluster_idx": 7}]}, "Mbpp/632": {"dps": 80.48780487804878, "dps_norm": 88.57142857142857, "pass@1": 98.0, "profiled": [{"solution": "def move_zero(lst):\n # Initializing a new empty list to hold all the non-zero elements.\n new_lst = [i for i in lst if i!=0]\n \n # Fetching the length of the original list and new list.\n orig_len = len(lst)\n new_len = len(new_lst)\n \n # Extending the new list with zeroes until its length matches the original length.\n new_lst.extend([0]*(orig_len-new_len))\n \n # Returning the new list.\n return new_lst", "matching_cluster_idx": 6}, {"solution": "def move_zero(lst):\n for i in lst:\n if i == 0:\n lst.remove(i)\n lst.append(i)\n return lst", "matching_cluster_idx": 2}, {"solution": "def move_zero(lst):\n return [i for i in lst if i!=0] + [i for i in lst if i == 0]", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n # Use list comprehension to separate non-zero numbers and count the zeros\n no_zeros = [num for num in nums if num != 0]\n count_zeros = len(nums) - len(no_zeros)\n \n # Append zeros to the end of the non-zero numbers list\n no_zeros.extend([0]*count_zeros)\n return no_zeros", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n count = nums.count(0)\n nums[:] = [num for num in nums if num!=0]\n nums.extend([0]*count)\n return nums", "matching_cluster_idx": 6}, {"solution": "def move_zero(lst):\n zero_count = lst.count(0)\n new_list = [i for i in lst if i!=0]\n new_list.extend([0]*zero_count)\n return new_list", "matching_cluster_idx": 6}, {"solution": "def move_zero(lst):\n \"\"\"\n Moves all zeroes to the end of the given list.\n\n Parameters:\n lst (list): The list to move zeroes to the end.\n\n Returns:\n list: The list with all zeroes moved to the end.\n\n Example:\n >>> move_zero([1,0,2,0,3,4])\n [1,2,3,4,0,0]\n \"\"\"\n\n # count the number of zeros in the list\n num_zeros = lst.count(0)\n\n # remove all zeroes from the list\n lst = [num for num in lst if num != 0]\n\n # extend the list with the number of zeros at the end\n lst.extend([0]*num_zeros)\n\n return lst", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n for i in nums:\n if i == 0:\n nums.remove(i)\n nums.append(i)\n return nums", "matching_cluster_idx": 2}, {"solution": "def move_zero(num_list):\n for i in num_list:\n if i == 0:\n num_list.remove(i)\n num_list.append(i)\n return num_list", "matching_cluster_idx": 2}, {"solution": "def move_zero(lst):\n # count the number of zeroes in the list\n count = lst.count(0)\n \n # remove all the zeroes from the list\n lst = [i for i in lst if i!=0]\n \n # extend the list with the count of zeroes\n lst.extend([0]*count)\n \n return lst", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n # Count the number of zeroes\n count = nums.count(0)\n # Remove zeroes from the list\n nums = [num for num in nums if num != 0]\n # Extend the list with number of zeroes at the end\n nums.extend([0]*count)\n return nums", "matching_cluster_idx": 6}, {"solution": "def move_zero(lst):\n for i in lst:\n if i == 0:\n lst.remove(i)\n lst.append(i)\n return lst", "matching_cluster_idx": 2}, {"solution": "def move_zero(lst):\n count = lst.count(0)\n lst = [i for i in lst if i!=0]\n lst.extend([0]*count)\n return lst", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n \"\"\"\n This function takes in a list of numbers and moves all zeros to the end of the list.\n \"\"\"\n # count the number of zeros in the list\n zero = nums.count(0)\n \n # remove all zeros from the list\n nums = [i for i in nums if i != 0]\n \n # extend the list with the number of zeros found at the end\n nums.extend([0]*zero)\n \n return nums", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n # Count the number of zeros in the list\n num_zeros = nums.count(0)\n \n # Create a list with the non-zero elements\n non_zeros = [num for num in nums if num != 0]\n \n # Extend the non_zeros list with the number of zeros\n non_zeros.extend([0]*num_zeros)\n \n return non_zeros", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n \"\"\"Move all zeroes to the end of a list\"\"\"\n return [num for num in nums if num!=0] + [0]*(nums.count(0))", "matching_cluster_idx": 6}, {"solution": "def move_zero(lst):\n \"\"\"\n This function moves all zeroes to the end of the given list.\n \"\"\"\n # Initializing empty lists for non-zero and zero values\n non_zeros = []\n zeros = []\n\n # Iterate over the elements in the list\n for item in lst:\n # If the element is zero, append it to the zeros list\n if item == 0:\n zeros.append(item)\n # If the element is not zero, append it to the non_zeros list\n else:\n non_zeros.append(item)\n\n # Concatenate the non_zeros list with the zeros list and return the result\n return non_zeros + zeros", "matching_cluster_idx": 6}, {"solution": "def move_zero(lst):\n # Count the number of zeroes\n zero_count = lst.count(0)\n # Remove all zeroes\n lst = [num for num in lst if num!=0]\n # Append zero_count number of zeroes at the end of the list\n lst += [0] * zero_count\n return lst", "matching_cluster_idx": 6}, {"solution": "def move_zero(lst):\n \"\"\"\n Moves all zeros in the given list to the end.\n \"\"\"\n # Count zeros in the list\n num_zeros = lst.count(0)\n\n # Remove all zeros from the list\n lst = [num for num in lst if num != 0]\n\n # Append the number of zeros to the end of the list\n lst.extend([0]*num_zeros)\n\n return lst", "matching_cluster_idx": 6}, {"solution": "def move_zero(lst):\n # List comprehension that filters out 0s and concatenates them at the end\n return [i for i in lst if i!=0] + [i for i in lst if i==0]", "matching_cluster_idx": 6}]}, "Mbpp/633": {"dps": 94.3089430894309, "dps_norm": 50.0, "pass@1": 19.0, "profiled": [{"solution": "def pair_xor_Sum(nums, n):\n sum = 0\n for i in range(n):\n for j in range(i + 1, n):\n sum += nums[i] ^ nums[j]\n return sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(lst, n):\n \"\"\"\n This function calculates the sum of XOR of all pairs of numbers in the given list.\n \"\"\"\n # Initialize the sum to 0\n xor_sum = 0\n\n # Iterate over the list to find all pairs\n for i in range(n):\n for j in range(i+1, n):\n # Calculate the XOR of the pair and add it to the sum\n xor_sum += lst[i] ^ lst[j]\n\n return xor_sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(arr, n):\n # Initialize result\n res = 0\n\n for i in range(0, n):\n for j in range(i + 1, n):\n # Do XOR and add to result\n res = res + (arr[i] ^ arr[j])\n\n return res", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(nums, n):\n xor_sum = 0\n for i in range(n):\n for j in range(i+1, n):\n xor_sum += nums[i] ^ nums[j]\n return xor_sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(lst, n):\n sum = 0\n for i in range(n):\n for j in range(i+1, n):\n sum += lst[i] ^ lst[j]\n return sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(lst, n):\n \"\"\"\n This function finds the sum of xor of all pairs of numbers in the given list.\n \"\"\"\n sum = 0\n for i in range(n):\n for j in range(i+1, n):\n sum += lst[i] ^ lst[j]\n return sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(lst, n):\n sum = 0\n for i in range(n):\n for j in range(i + 1, n):\n sum += lst[i] ^ lst[j]\n return sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(lst, n):\n # initialize sum with 0\n total = 0\n\n # create a for loop to iterate through lst\n for i in range(n):\n # create another loop to iterate through lst from i+1 to n\n for j in range(i + 1, n):\n # perform xor operation and add it to total\n total += lst[i] ^ lst[j]\n \n # return the total sum\n return total", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(lst, n):\n sum = 0\n for i in range(n):\n for j in range(i + 1, n):\n sum += lst[i] ^ lst[j]\n return sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(lst, n):\n if len(lst) < n:\n return \"List is shorter than n\"\n else:\n xor_sum = 0\n for i in range(n):\n for j in range(i+1, n):\n xor_sum += lst[i] ^ lst[j]\n return xor_sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(lst, n):\n xor_sum = 0\n for i in range(n):\n for j in range(i+1, n):\n xor_sum += lst[i] ^ lst[j]\n return xor_sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(lst, length):\n sum = 0\n for i in range(length):\n for j in range(i + 1, length):\n sum += lst[i] ^ lst[j]\n return sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(lst, n):\n \"\"\"\n This function finds the sum of xor of all pairs of numbers in the given list.\n \"\"\"\n xor_sum = 0\n for i in range(n):\n for j in range(i + 1, n):\n xor_sum += lst[i] ^ lst[j]\n return xor_sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(lst, n):\n sum = 0\n for i in range(n):\n for j in range(i+1, n):\n sum += lst[i] ^ lst[j]\n return sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(lst, n):\n \"\"\"\n Function to find the sum of xor of all pairs of numbers in the given list.\n \"\"\"\n xor_sum = 0\n for i in range(n):\n for j in range(i + 1, n):\n xor_sum += lst[i] ^ lst[j]\n return xor_sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(lst,n):\n xor_sum = 0\n for i in range(n):\n for j in range(i + 1, n):\n xor_sum += lst[i] ^ lst[j]\n return xor_sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(nums, n):\n sum_xor = 0\n for i in range(0,n):\n for j in range(i+1,n):\n sum_xor += nums[i] ^ nums[j]\n return sum_xor", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(lst, n):\n pair_xor_sum = 0\n for i in range(n):\n for j in range(i + 1, n):\n pair_xor_sum += lst[i] ^ lst[j]\n return pair_xor_sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(lst, n):\n xor_sum = 0\n for i in range(n):\n for j in range(i+1, n):\n xor_sum += lst[i] ^ lst[j]\n return xor_sum\nlst = [5,9,7,6]\nn = len(lst)", "matching_cluster_idx": 2}]}, "Mbpp/644": {"dps": 78.77659574468083, "dps_norm": 82.33333333333333, "pass@1": 89.0, "profiled": [{"solution": "def reverse_Array_Upto_K(array, k):\n # This will reverse array from 0 to k position.\n return array[:k][::-1] + array[k:]", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n # Reverse the first k elements\n arr[:k] = arr[:k][::-1]\n return arr", "matching_cluster_idx": 13}, {"solution": "def reverse_Array_Upto_K(arr, k):\n arr[:k] = arr[:k][::-1]\n return arr", "matching_cluster_idx": 13}, {"solution": "def reverse_Array_Upto_K(arr, K):\n arr[:K] = arr[:K][::-1]\n return arr", "matching_cluster_idx": 13}, {"solution": "def reverse_Array_Upto_K(arr, K):\n if K > len(arr):\n return \"Invalid K\"\n \n for i in range(int(K/2)):\n arr[i], arr[K-i-1] = arr[K-i-1], arr[i]\n\n return arr", "matching_cluster_idx": 6}, {"solution": "def reverse_Array_Upto_K(arr, K):\n \"\"\"\n This function accepts an array and a number K as input, and reverses the array up to the Kth position.\n \"\"\"\n return arr[:K][::-1] + arr[K:]", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n arr[:k] = arr[:k][::-1]\n return arr", "matching_cluster_idx": 13}, {"solution": "def reverse_Array_Upto_K(arr, K):\n arr[:K] = arr[:K][::-1]\n return arr", "matching_cluster_idx": 13}, {"solution": "def reverse_Array_Upto_K(arr, k):\n # Reverse the array upto the given position using slicing\n arr[:k] = arr[:k][::-1]\n return arr", "matching_cluster_idx": 13}, {"solution": "def reverse_Array_Upto_K(arr, k):\n # [::-1] is a python slicing technique that is used for reversing a list\n arr[:k] = arr[:k][::-1]\n return arr", "matching_cluster_idx": 13}, {"solution": "def reverse_Array_Upto_K(arr, k):\n if k > len(arr): \n return arr \n return arr[:k][::-1] + arr[k:]", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, K):\n arr[:K] = arr[:K][::-1]\n return arr", "matching_cluster_idx": 13}, {"solution": "def reverse_Array_Upto_K(arr, k):\n # If k is greater than array size, return original array\n if k > len(arr):\n return arr\n \n # Reverse the first k elements\n for i in range(int(k/2)):\n arr[i], arr[k-i-1] = arr[k-i-1], arr[i]\n \n return arr", "matching_cluster_idx": 6}, {"solution": "def reverse_Array_Upto_K(arr, k):\n for i in range(k//2):\n arr[i], arr[k-i-1] = arr[k-i-1], arr[i]\n return arr", "matching_cluster_idx": 6}, {"solution": "def reverse_Array_Upto_K(arr, k):\n arr[:k] = arr[:k][::-1]\n return arr", "matching_cluster_idx": 13}, {"solution": "def reverse_Array_Upto_K(arr, k):\n # Using slicing to reverse up to k elements\n arr[:k] = arr[:k][::-1]\n return arr", "matching_cluster_idx": 13}, {"solution": "def reverse_Array_Upto_K(arr, k):\n # Check if k is larger than the length of the array\n # If it is, we will return the same array to avoid an error\n k = min(k, len(arr))\n \n # Reverse the array up to the 'k'th index\n arr[:k] = arr[:k][::-1]\n \n # Return the resulting array\n return arr", "matching_cluster_idx": 13}, {"solution": "def reverse_Array_Upto_K(arr, K):\n arr[:K] = arr[:K][::-1]\n return arr", "matching_cluster_idx": 13}, {"solution": "def reverse_Array_Upto_K(arr, k):\n arr[:k] = arr[:k][::-1]\n return arr", "matching_cluster_idx": 13}, {"solution": "def reverse_Array_Upto_K(arr, k):\n # arr[k:] returns the elements from kth to the end of the array\n # [::-1] is used to reverse the selected elements\n return arr[:k][::-1] + arr[k:]", "matching_cluster_idx": 10}]}, "Mbpp/720": {"dps": 90.76923076923077, "dps_norm": 97.0, "pass@1": 99.0, "profiled": [{"solution": "def add_dict_to_tuple(my_tuple, my_dict):\n return my_tuple + (my_dict,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(tuple_input, dict_input):\n \"\"\" \n The function to add a dictionary to the tuple. \n\n Parameters:\n tuple_input (tuple): The tuple input.\n dict_input (dict): The dictionary input.\n \n Returns:\n tuple: The combined tuple.\n \"\"\"\n return tuple_input + (dict_input,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(t, d):\n return t + (d,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(tpl, dct):\n return tpl + (dct, )", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(tup, dic):\n return tup + (dic, )", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(tup, d):\n return tup + (d,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(input_tuple, input_dict):\n \"\"\"\n Adds a dictionary to a tuple and returns the resultant tuple.\n \"\"\"\n return input_tuple + (input_dict,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(tup, dict_to_add):\n \"\"\"Adds a dictionary to a tuple and returns the result as a tuple.\"\"\"\n result = list(tup)\n result.append(dict_to_add)\n return tuple(result)", "matching_cluster_idx": 3}, {"solution": "def add_dict_to_tuple(tup, dic):\n return tup + (dic,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(t, d):\n return t + (d,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(tup, dic):\n tup += (dic, )\n return tup", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(input_tuple, input_dict):\n return input_tuple + (input_dict,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(tup, dic):\n return tup + (dic,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(tup, dic):\n return tup + (dic,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(tup, dic):\n return tup + (dic,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(tuple_, dict_):\n \"\"\" Add a dictionary to a tuple\"\"\"\n list_ = list(tuple_)\n list_.append(dict_)\n return tuple(list_)", "matching_cluster_idx": 3}, {"solution": "def add_dict_to_tuple(input_tuple, input_dict):\n \"\"\"Add a dictionary to the tuple and return as tuple.\"\"\"\n # convert input tuple and dictionary to a list and append one after the other\n output_list = list(input_tuple)\n output_list.append(input_dict)\n # convert list back to tuple\n output_tuple = tuple(output_list)\n return output_tuple", "matching_cluster_idx": 3}, {"solution": "def add_dict_to_tuple(input_tuple, input_dict):\n return input_tuple + (input_dict,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(tup, d):\n return tup + (d,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(tup, dic):\n return tup + (dic, )", "matching_cluster_idx": 4}]}, "Mbpp/725": {"dps": 74.53551912568305, "dps_norm": 75.625, "pass@1": 100.0, "profiled": [{"solution": "import re\ndef extract_quotation(s):\n return re.findall(r'\"([^\"]*)\"', s)", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(s):\n return re.findall(r'\"([^\"]*)\"', s)", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(string):\n return re.findall(r'\"([^\"]*)\"', string)", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(text):\n return re.findall(r'\"([^\"]*)\"', text)", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(text):\n # regular expression to find values between quotation marks\n pattern = r'\"([^\"]*)\"'\n matches = re.findall(pattern, text)\n return matches", "matching_cluster_idx": 6}, {"solution": "import re\ndef extract_quotation(s):\n # Using RegEx to match strings between quotation marks\n return re.findall(r'\"(.*?)\"', s)", "matching_cluster_idx": 4}, {"solution": "import re\ndef extract_quotation(text):\n return re.findall(r'\"([^\"]*)\"', text)", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(s):\n return re.findall(r'\"([^\"]*)\"', s)", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(s):\n return re.findall(r'\"([^\"]*)\"', s)", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(text):\n return re.findall(r'\"([^\"]*)\"', text)", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(s: str) -> list:\n matches = re.findall(r'\"([^\"]*)\"', s)\n return matches", "matching_cluster_idx": 6}, {"solution": "import re\ndef extract_quotation(s):\n return re.findall(r'\"([^\"]*)\"', s)", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(string):\n return re.findall(r'\"([^\"]*)\"', string)", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(s):\n return re.findall(r'\"([^\"]*)\"', s)", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(s):\n return re.findall(r'\"([^\"]*)\"', s)", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(s):\n return re.findall(r'\"([^\"]*)\"', s)", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(s):\n return re.findall(r'\"([^\"]*)\"', s)", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(text):\n return re.findall(r'\"([^\"]*)\"', text)", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(s):\n return re.findall(r'\"([^\"]*)\"', s)", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(s):\n return re.findall(r'\"([^\"]*)\"', s)", "matching_cluster_idx": 5}]}, "Mbpp/732": {"dps": 95.15503875968992, "dps_norm": 95.5, "pass@1": 100.0, "profiled": [{"solution": "def replace_specialchar(sentence):\n special_chars = [' ', ',', '.']\n for char in special_chars:\n sentence = sentence.replace(char, ':')\n return sentence", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(s):\n s = s.replace(' ', ':')\n s = s.replace(',', ':')\n s = s.replace('.', ':')\n return s", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(text):\n return text.replace(' ', ':').replace(',', ':').replace('.', ':')", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(s):\n for char in s:\n if char in \" ,.\":\n s = s.replace(char, \":\")\n return s", "matching_cluster_idx": 0}, {"solution": "def replace_specialchar(string):\n return string.replace(' ', ':').replace(',', ':').replace('.', ':')", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(text):\n special_chars = [' ', ',', '.']\n for special_char in special_chars:\n text = text.replace(special_char, ':')\n return text", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(input_str):\n return input_str.replace(\" \", \":\").replace(\",\", \":\").replace(\".\", \":\")", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(s):\n replace_chars = ['.', ',', ' ']\n for char in replace_chars:\n s = s.replace(char, ':')\n return s", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(text):\n for ch in [' ', ',', '.']:\n text = text.replace(ch, ':')\n return text", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(text):\n return text.replace(' ', ':').replace(',', ':').replace('.', ':')", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(text):\n special_chars = [\" \", \",\", \".\"]\n for char in special_chars:\n text = text.replace(char, \":\")\n return text", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(str):\n for c in [' ', ',', '.']:\n if c in str:\n str = str.replace(c, ':')\n return str", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(sentence):\n sentence = sentence.replace(' ', ':')\n sentence = sentence.replace(',', ':')\n sentence = sentence.replace('.', ':')\n return sentence", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(string):\n special_characters = [' ', ',', '.']\n for char in special_characters:\n string = string.replace(char, ':')\n return string", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(text):\n chars = [\" \", \",\", \".\"]\n for char in chars:\n text = text.replace(char, \":\")\n return text", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(s):\n special_chars = [',', '.', ' ']\n for special_char in special_chars:\n s = s.replace(special_char, ':')\n return s", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(s):\n chars_to_replace = ['.', ',', ' ']\n for c in chars_to_replace:\n if c in s:\n s = s.replace(c, ':')\n return s", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(s):\n # replace all occurrences of spaces, commas, or dots with a colon\n s = s.replace(' ', ':')\n s = s.replace(',', ':')\n s = s.replace('.', ':')\n return s", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(s):\n special_chars = [' ', ',', '.']\n for special_char in special_chars:\n s = s.replace(special_char, ':')\n return s", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(sentence):\n \"\"\"\n Function to replace all occurrences of spaces, commas, or dots with a colon.\n \"\"\"\n # Replacing spaces, commas and dots with colon\n sentence = sentence.replace(\" \", \":\").replace(\",\", \":\").replace(\".\", \":\")\n return sentence", "matching_cluster_idx": 9}]}, "Mbpp/740": {"dps": 83.63636363636364, "dps_norm": 66.66666666666667, "pass@1": 100.0, "profiled": [{"solution": "def tuple_to_dict(input_tuple):\n if len(input_tuple) == 0:\n return {}\n else:\n return {input_tuple[i]: input_tuple[i+1] for i in range(0, len(input_tuple)-1, 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(t):\n return {t[i]: t[i + 1] for i in range(0, len(t), 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(tup):\n return {tup[n]: tup[n + 1] for n in range(0, len(tup), 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(tup):\n return {tup[n]: tup[n + 1] for n in range(0, len(tup), 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(t):\n return {t[i]: t[i + 1] for i in range(0, len(t), 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(tup):\n return {tup[i]: tup[i + 1] for i in range(0, len(tup), 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(t):\n return {t[i]: t[i+1] for i in range(0, len(t), 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(tup):\n return {tup[i]: tup[i + 1] for i in range(0, len(tup), 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(t):\n return {t[i]: t[i + 1] for i in range(0, len(t), 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(t):\n return {t[i]: t[i + 1] for i in range(0, len(t), 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(tup):\n return {tup[i]: tup[i + 1] for i in range(0, len(tup), 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(tup):\n return {tup[i]: tup[i + 1] for i in range(0, len(tup) - 1, 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(tup):\n return {tup[i]: tup[i + 1] for i in range(0, len(tup), 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(t):\n return {t[i]: t[i + 1] for i in range(0, len(t), 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(t):\n return {t[i]: t[i + 1] for i in range(0, len(t), 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(tup):\n return {tup[i]: tup[i+1] for i in range(0, len(tup), 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(tup):\n return {tup[i]: tup[i + 1] for i in range(0, len(tup), 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(tup):\n return {tup[i]: tup[i + 1] for i in range(0, len(tup), 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(tup):\n return {tup[i]: tup[i + 1] for i in range(0, len(tup) - 1, 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(tup):\n return {tup[i]: tup[i + 1] for i in range(0, len(tup), 2)}", "matching_cluster_idx": 5}]}, "Mbpp/744": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def check_none(tup):\n return None in tup", "matching_cluster_idx": 5}, {"solution": "def check_none(input_tuple):\n if None in input_tuple:\n return True\n else:\n return False", "matching_cluster_idx": 5}, {"solution": "def check_none(input_tuple):\n return None in input_tuple", "matching_cluster_idx": 5}, {"solution": "def check_none(tup):\n \"\"\"\n This function checks if the given tuple has any none value or not.\n If it does, it returns True, otherwise it returns False.\n \"\"\"\n return None in tup", "matching_cluster_idx": 5}, {"solution": "def check_none(tup):\n return None in tup", "matching_cluster_idx": 5}, {"solution": "def check_none(input_tuple):\n if None in input_tuple:\n return True\n else:\n return False", "matching_cluster_idx": 5}, {"solution": "def check_none(tup):\n if None in tup:\n return True\n else:\n return False", "matching_cluster_idx": 5}, {"solution": "def check_none(tup):\n return None in tup", "matching_cluster_idx": 5}, {"solution": "def check_none(input_tuple):\n return None in input_tuple", "matching_cluster_idx": 5}, {"solution": "def check_none(tuple):\n if None in tuple:\n return True\n else:\n return False", "matching_cluster_idx": 5}, {"solution": "def check_none(t):\n return None in t", "matching_cluster_idx": 5}, {"solution": "def check_none(tup):\n return None in tup", "matching_cluster_idx": 5}, {"solution": "def check_none(tup):\n return None in tup", "matching_cluster_idx": 5}, {"solution": "def check_none(input_tuple):\n return None in input_tuple", "matching_cluster_idx": 5}, {"solution": "def check_none(input_tuple):\n \"\"\"\n This function checks if the given tuple has any None value or not.\n \"\"\"\n return None in input_tuple", "matching_cluster_idx": 5}, {"solution": "def check_none(in_tuple):\n \"\"\"\n Check if tuple contains any None values.\n\n Parameters:\n in_tuple (tuple): tuple to check for None\n\n Returns:\n bool: True if None in tuple, False otherwise.\n \"\"\"\n return None in in_tuple", "matching_cluster_idx": 5}, {"solution": "def check_none(tup):\n return None in tup", "matching_cluster_idx": 5}, {"solution": "def check_none(input_tuple):\n if None in input_tuple:\n return True\n else:\n return False", "matching_cluster_idx": 5}, {"solution": "def check_none(input_tuple):\n if None in input_tuple:\n return True\n else:\n return False", "matching_cluster_idx": 5}, {"solution": "def check_none(tup):\n if None in tup:\n return True\n else:\n return False", "matching_cluster_idx": 5}]}, "Mbpp/750": {"dps": 83.70748299319727, "dps_norm": 85.0, "pass@1": 100.0, "profiled": [{"solution": "def add_tuple(lst, tup):\n return lst + list(tup)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(lst, tpl):\n \"\"\"\n This function adds a given tuple to a given list.\n \"\"\"\n # append the tuple to the list\n lst.extend(tpl)\n # return the updated list\n return lst", "matching_cluster_idx": 5}, {"solution": "def add_tuple(lst, tup):\n \"\"\"\n This function adds a tuple to a list.\n \"\"\"\n # Add tuple to list using extend method\n lst.extend(tup)\n return lst", "matching_cluster_idx": 5}, {"solution": "def add_tuple(lst, tup):\n lst.extend(tup)\n return lst", "matching_cluster_idx": 5}, {"solution": "def add_tuple(lst, tup):\n lst.extend(tup)\n return lst", "matching_cluster_idx": 5}, {"solution": "def add_tuple(lst, tpl):\n return lst + list(tpl)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(lst, tup):\n \"\"\"\n Adds the tuple to the list.\n\n Parameters:\n lst (list): The list to which the tuple should be added.\n tup (tuple): The tuple to be added.\n\n Returns:\n list: The updated list.\n \"\"\"\n lst.extend(tup)\n return lst", "matching_cluster_idx": 5}, {"solution": "def add_tuple(lst, tup):\n \"\"\"\n Adds a tuple to a list.\n\n Args:\n lst (List): The list to add the tuple to.\n tup (Tuple): The tuple to add to the list.\n\n Returns:\n List: The resulting list after adding the tuple.\n \"\"\"\n return lst + list(tup)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(lst, tup):\n \"\"\"Add a tuple to a list.\"\"\"\n lst.extend(tup)\n return lst", "matching_cluster_idx": 5}, {"solution": "def add_tuple(lst, tpl):\n \"\"\"\n Adds the given tuple to the given list.\n :param lst: The list to add to.\n :param tpl: The tuple to add.\n :return: The new list with the tuple added.\n \"\"\"\n return lst + list(tpl)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(lst, tup):\n \"\"\"\n This function appends a tuple to the end of a list.\n \"\"\"\n lst.extend(tup)\n return lst", "matching_cluster_idx": 4}, {"solution": "def add_tuple(lst, tup):\n \"\"\"\n This function takes a list and a tuple and adds the tuple to the end of the list.\n \"\"\"\n lst.extend(tup)\n return lst", "matching_cluster_idx": 5}, {"solution": "def add_tuple(input_list, input_tuple):\n # Adding the tuple elements to the list\n input_list.extend(input_tuple)\n return input_list", "matching_cluster_idx": 5}, {"solution": "def add_tuple(lst, tpl):\n \"\"\"\n Function to add the given tuple to the given list.\n :param lst: list of integers\n :param tpl: tuple of integers\n :return: list with added tuple\n \"\"\"\n lst.extend(tpl)\n return lst", "matching_cluster_idx": 5}, {"solution": "def add_tuple(input_list, input_tuple):\n \"\"\"\n Function to add a tuple to the given list.\n\n Parameters:\n input_list (list): A list of integers.\n input_tuple (tuple): A tuple of integers.\n\n Returns:\n list: The original list with the tuple elements added.\n \"\"\"\n # Adding tuple elements to the list\n input_list.extend(input_tuple)\n return input_list", "matching_cluster_idx": 5}, {"solution": "def add_tuple(lst, tup):\n # Extend list by tuple\n lst.extend(tup)\n return lst", "matching_cluster_idx": 5}, {"solution": "def add_tuple(lst, tup):\n # extend the list by the tuple\n lst.extend(tup)\n return lst", "matching_cluster_idx": 4}, {"solution": "def add_tuple(lst, tpl):\n \"\"\"\n Function to add the given tuple to the given list.\n \"\"\"\n return lst + list(tpl)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(my_list, my_tuple):\n \"\"\"\n Adds the given tuple to the given list.\n \"\"\"\n my_list.extend(my_tuple)\n return my_list", "matching_cluster_idx": 4}, {"solution": "def add_tuple(lst, tup):\n lst.extend(tup)\n return lst", "matching_cluster_idx": 5}]}, "Mbpp/753": {"dps": 97.31543624161074, "dps_norm": 75.0, "pass@1": 96.0, "profiled": [{"solution": "def min_k(records, k):\n return sorted(records, key=lambda x: x[1])[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(records, k):\n return sorted(records, key=lambda x: x[1])[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(lst, k):\n return sorted(lst, key=lambda x: x[1])[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(records, k):\n return sorted(records, key=lambda x: x[1])[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(records, k):\n # Sort the records in ascending order\n records.sort(key = lambda x: x[1])\n # Return the first k records\n return records[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(data, k):\n \"\"\"Return minimum k records from tuple list.\"\"\"\n return sorted(data, key=lambda x: x[1])[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(records, k):\n \"\"\"\n Given a list of tuples, each containing a string and an integer,\n and an integer k, return the k tuples with the smallest integers.\n \"\"\"\n # sort the list of tuples based on the integer values\n sorted_records = sorted(records, key=lambda x: x[1])\n\n # return the first k elements\n return sorted_records[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(lst, k):\n return sorted(lst, key = lambda x: x[1])[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(tuples_list, k):\n #Sorting the list on the basis of second value in tuple\n sorted_list = sorted(tuples_list, key=lambda x:x[1])\n #Returning first k elements\n return sorted_list[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(tuples, k):\n # Sorting the tuples by the second element of the tuple\n sorted_tuples = sorted(tuples, key=lambda x: x[1])\n\n # Returning first k elements\n return sorted_tuples[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(tuple_list, k):\n \"\"\"\n Given a list of tuples, return the k tuples with the smallest second element.\n \"\"\"\n sorted_tuples = sorted(tuple_list, key=lambda x: x[1])\n return sorted_tuples[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(records, k):\n # Using the sorted() function and lambda to sort the records in ascending order by the second element of the tuples\n # We also limit the output to the first k records\n return sorted(records, key=lambda record: record[1])[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(lst, k):\n # Sort the list based on second element of tuple\n lst.sort(key = lambda x: x[1])\n # Return the first k elements of the list\n return lst[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(lst, k):\n # Sort list by second item in tuple\n lst.sort(key=lambda x: x[1])\n\n # Return first k records\n return lst[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(records, k):\n # Sort records by value in ascending order\n sorted_records = sorted(records, key=lambda x: x[1])\n\n # Return first k records\n return sorted_records[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(lst, k):\n \"\"\"\n Find minimum k records from tuple list.\n\n Args:\n lst: List of tuples where each tuple has two items: a string and an integer\n k: Number of minimum records to retrieve\n\n Returns:\n Minimum k records from the list as a list of tuples\n \"\"\"\n lst.sort(key = lambda x: x[1]) # sort the list based on the second element of each tuple\n return lst[:k] # return the first k elements of the list", "matching_cluster_idx": 2}, {"solution": "def min_k(lst, k):\n # Sort the list by the second element in tuple\n lst.sort(key = lambda x: x[1])\n return lst[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(tuples, k):\n return sorted(tuples, key=lambda x: x[1])[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(records, k):\n return sorted(records, key=lambda x: x[1])[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(lst, k):\n return sorted(lst, key=lambda x: x[1])[:k]", "matching_cluster_idx": 2}]}, "Mbpp/754": {"dps": 89.65517241379311, "dps_norm": 87.5, "pass@1": 13.0, "profiled": [{"solution": "def extract_index_list(l1, l2, l3):\n common_elements = []\n min_length = min(len(l1), len(l2), len(l3))\n \n for i in range(min_length):\n if l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n \n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n common_elements = []\n for i in range(min(len(l1), len(l2), len(l3))):\n if l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n common_elements = []\n min_len = min(len(l1), len(l2), len(l3))\n for i in range(min_len):\n if l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n common_elements = [l1[i] for i in range(min(len(l1), len(l2), len(l3))) if l1[i] == l2[i] == l3[i]]\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n common_elements = []\n for i in range(min(len(l1), len(l2), len(l3))):\n if l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n common_elements = []\n for i in range(min(len(l1), len(l2), len(l3))):\n if l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n common_elements = []\n min_length = min(len(l1), len(l2), len(l3))\n \n for i in range(min_length):\n if l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n \n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n common_elements = []\n for i in range(min(len(l1), len(l2), len(l3))):\n if l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n common_elements = []\n for i in range(min(len(l1), len(l2), len(l3))):\n if l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n common_elements = []\n min_len = min(len(l1), len(l2), len(l3))\n\n for i in range(min_len):\n if l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n common_elements = []\n for i in range(min(len(l1), len(l2), len(l3))):\n if l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n common_elements = []\n for i in range(min(len(l1), len(l2), len(l3))):\n if l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n common_elements = []\n for i in range(min(len(l1), len(l2), len(l3))):\n if l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n return common_elements", "matching_cluster_idx": 6}]}, "Mbpp/755": {"dps": null, "dps_norm": null, "pass@1": 4.0, "profiled": []}, "Mbpp/757": {"dps": 85.30373831775701, "dps_norm": 34.61538461538461, "pass@1": 43.0, "profiled": [{"solution": "def count_reverse_pairs(lst):\n n = len(lst)\n count = 0\n for i in range(n):\n for j in range(i+1, n):\n if lst[i] == lst[j][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(strs):\n count = 0\n str_dict = {}\n for s in strs:\n rev_s = s[::-1]\n if rev_s in str_dict:\n count += str_dict[rev_s]\n str_dict[s] = str_dict.get(s, 0) + 1\n else:\n str_dict[s] = str_dict.get(s, 0) + 1\n return count", "matching_cluster_idx": 12}, {"solution": "def count_reverse_pairs(lst):\n count = 0\n for i in range(len(lst)):\n for j in range(i + 1, len(lst)):\n if lst[i] == lst[j][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(lst):\n count = 0\n for i in range(len(lst)):\n for j in range(i+1, len(lst)):\n if lst[i] == lst[j][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(input_list):\n \"\"\"\n Function to count the pairs of reverse strings in a given string list.\n \"\"\"\n count = 0\n for i in range(len(input_list)):\n for j in range(i+1, len(input_list)):\n if input_list[i] == input_list[j][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(str_list):\n count = 0\n str_dict = {}\n for string in str_list:\n reversed_string = string[::-1]\n if reversed_string in str_dict:\n count += str_dict[reversed_string]\n str_dict[string] = str_dict.get(string, 0) + 1\n else:\n str_dict[string] = str_dict.get(string, 0) + 1\n return count", "matching_cluster_idx": 12}, {"solution": "def count_reverse_pairs(strings_list):\n count = 0\n for i in range(len(strings_list)):\n for j in range(i+1, len(strings_list)):\n if strings_list[i] == strings_list[j][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(lst):\n count = 0\n for i in range(len(lst)):\n for j in range(i+1, len(lst)):\n if lst[i] == lst[j][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(lst):\n count = 0\n for i in range(len(lst)):\n for j in range(i + 1, len(lst)):\n if lst[i] == lst[j][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(strings):\n count = 0\n for i in range(len(strings)):\n for j in range(i + 1, len(strings)):\n if strings[i] == strings[j][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(lst):\n reverse_pairs = 0\n for i in range(len(lst)):\n for j in range(i+1, len(lst)):\n if lst[i] == lst[j][::-1]:\n reverse_pairs += 1\n return reverse_pairs", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(lst):\n pairs = 0\n for i in range(len(lst)):\n for j in range(i+1, len(lst)):\n if lst[i] == lst[j][::-1]:\n pairs += 1\n return pairs", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(lst):\n n = len(lst)\n count = 0\n for i in range(n):\n for j in range(i+1, n):\n if lst[i] == lst[j][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(lst):\n count = 0\n for i in range(len(lst)):\n for j in range(i + 1, len(lst)):\n if lst[i] == lst[j][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(str_list):\n count = 0\n for i in range(len(str_list)):\n for j in range(i+1, len(str_list)):\n if str_list[i] == str_list[j][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(strs):\n count = 0\n str_map = {}\n\n for s in strs:\n rev_s = s[::-1]\n \n if rev_s in str_map:\n count += str_map[rev_s]\n str_map[s] = str_map.get(s, 0) + 1\n else:\n str_map[s] = str_map.get(s, 0) + 1\n \n return count", "matching_cluster_idx": 12}, {"solution": "def count_reverse_pairs(str_list):\n count = 0\n for i in range(len(str_list)):\n for j in range(i + 1, len(str_list)):\n if str_list[i] == str_list[j][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(lst):\n count = 0\n for i in range(len(lst)):\n for j in range(i+1, len(lst)):\n if lst[i] == lst[j][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(lst):\n count = 0\n for i in range(len(lst)):\n for j in range(i+1, len(lst)):\n if lst[i] == lst[j][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(lst):\n count = 0\n for i in range(len(lst)):\n for j in range(i+1, len(lst)):\n if lst[i] == lst[j][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}]}, "Mbpp/758": {"dps": 79.36293436293435, "dps_norm": 80.625, "pass@1": 43.0, "profiled": [{"solution": "def unique_sublists(lst):\n sublists_dict = {}\n for sublist in lst:\n tuple_sublist = tuple(sublist)\n if tuple_sublist in sublists_dict:\n sublists_dict[tuple_sublist] += 1\n else:\n sublists_dict[tuple_sublist] = 1\n return sublists_dict", "matching_cluster_idx": 6}, {"solution": "from collections import Counter\ndef unique_sublists(lst):\n # Convert each sublist to a tuple and use collections.Counter\n # to count occurrences\n counts = Counter(tuple(sub) for sub in lst)\n return dict(counts)", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(lst):\n sublist_dict = {}\n for sublist in lst:\n tuple_sublist = tuple(sublist)\n if tuple_sublist in sublist_dict:\n sublist_dict[tuple_sublist] += 1\n else:\n sublist_dict[tuple_sublist] = 1\n return sublist_dict", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(lst):\n unique_dict = {}\n for sub_list in lst:\n tup = tuple(sub_list)\n if tup in unique_dict:\n unique_dict[tup] += 1\n else:\n unique_dict[tup] = 1\n return unique_dict", "matching_cluster_idx": 6}, {"solution": "from collections import Counter\ndef unique_sublists(input_list):\n # Convert each sublist to tuple and use Counter to count the frequency\n return dict(Counter(tuple(sub) for sub in input_list))", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(lst):\n count_dict = {}\n for sub_list in lst:\n tuple_item = tuple(sub_list)\n if tuple_item in count_dict:\n count_dict[tuple_item] += 1\n else:\n count_dict[tuple_item] = 1\n return count_dict", "matching_cluster_idx": 5}, {"solution": "def unique_sublists(lst):\n dct = {}\n for sublist in lst:\n tuple_sublist = tuple(sublist)\n if tuple_sublist in dct:\n dct[tuple_sublist] += 1\n else:\n dct[tuple_sublist] = 1\n return dct", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(lst):\n d = {}\n for sub_list in lst:\n tup = tuple(sub_list)\n if tup in d:\n d[tup] += 1\n else:\n d[tup] = 1\n return d", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(lst):\n dict_count = {}\n for sub_list in lst:\n tuple_sub_list = tuple(sub_list)\n if tuple_sub_list in dict_count:\n dict_count[tuple_sub_list] += 1\n else:\n dict_count[tuple_sub_list] = 1\n return dict_count", "matching_cluster_idx": 6}, {"solution": "from collections import Counter\ndef unique_sublists(lst):\n # convert each list in lst to tuple\n tuples = [tuple(sublist) for sublist in lst]\n # count the number of occurrences of each tuple in tuples\n counts = Counter(tuples)\n return counts", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(lst):\n result = {}\n for sublist in lst:\n tuple_sublist = tuple(sublist)\n if tuple_sublist in result:\n result[tuple_sublist] += 1\n else:\n result[tuple_sublist] = 1\n return result", "matching_cluster_idx": 5}, {"solution": "def unique_sublists(lst):\n result = {}\n for sublist in lst:\n tuple_sublist = tuple(sublist)\n if tuple_sublist in result:\n result[tuple_sublist] += 1\n else:\n result[tuple_sublist] = 1\n return result", "matching_cluster_idx": 5}, {"solution": "def unique_sublists(lst):\n count_dict = {}\n for sublist in lst:\n tuple_sublist = tuple(sublist)\n if tuple_sublist in count_dict:\n count_dict[tuple_sublist] += 1\n else:\n count_dict[tuple_sublist] = 1\n return count_dict", "matching_cluster_idx": 5}, {"solution": "def unique_sublists(lst):\n count_dict = {}\n for sublist in lst:\n tuple_sublist = tuple(sublist)\n if tuple_sublist in count_dict:\n count_dict[tuple_sublist] += 1\n else:\n count_dict[tuple_sublist] = 1\n return count_dict", "matching_cluster_idx": 5}, {"solution": "def unique_sublists(input_list):\n # Create an empty dictionary to store the tuples and their counts\n result = {}\n\n # Iterate over the input list\n for sublist in input_list:\n # Convert the sublist to a tuple\n sublist_tuple = tuple(sublist)\n\n # If the tuple is not in the result dictionary, add it with count 1\n if sublist_tuple not in result:\n result[sublist_tuple] = 1\n # If the tuple is already in the result dictionary, increment the count\n else:\n result[sublist_tuple] += 1\n\n # Return the result dictionary\n return result", "matching_cluster_idx": 5}, {"solution": "def unique_sublists(lst):\n d = {}\n for sublist in lst:\n tuple_sublist = tuple(sublist)\n if tuple_sublist in d:\n d[tuple_sublist] += 1\n else:\n d[tuple_sublist] = 1\n return d", "matching_cluster_idx": 5}, {"solution": "def unique_sublists(lst):\n count_dict = {}\n for sublist in lst:\n tuple_sublist = tuple(sublist)\n if tuple_sublist in count_dict:\n count_dict[tuple_sublist] += 1\n else:\n count_dict[tuple_sublist] = 1\n return count_dict", "matching_cluster_idx": 5}, {"solution": "def unique_sublists(lst):\n # Create an empty dictionary\n result = {}\n\n # Loop over each list in the input list\n for sublist in lst:\n # Convert the list to a tuple\n sublist_tuple = tuple(sublist)\n\n # If the tuple is in the dictionary, increment the count\n if sublist_tuple in result:\n result[sublist_tuple] += 1\n # If the tuple is not in the dictionary, add it with a count of 1\n else:\n result[sublist_tuple] = 1\n\n # Return the dictionary\n return result", "matching_cluster_idx": 5}, {"solution": "def unique_sublists(lst):\n count_dict = {}\n for sublist in lst:\n tuple_sublist = tuple(sublist)\n if tuple_sublist in count_dict:\n count_dict[tuple_sublist] += 1\n else:\n count_dict[tuple_sublist] = 1\n return count_dict", "matching_cluster_idx": 5}, {"solution": "def unique_sublists(lst):\n result = {}\n for sublist in lst:\n sublist_tuple = tuple(sublist)\n if sublist_tuple in result:\n result[sublist_tuple] += 1\n else:\n result[sublist_tuple] = 1\n return result", "matching_cluster_idx": 5}]}, "Mbpp/760": {"dps": 91.75182481751825, "dps_norm": 85.625, "pass@1": 75.0, "profiled": [{"solution": "def unique_Element(num_list):\n return len(set(num_list)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(lst):\n if len(set(lst)) == 1: # A set is a data structure that removes duplicates\n return True\n else:\n return False", "matching_cluster_idx": 6}, {"solution": "def unique_Element(lst):\n \"\"\"\n This function checks if all elements of a list are identical.\n Parameters: \n lst (list): List to be evaluated.\n \n Returns:\n bool: True if all elements are identical, False otherwise.\n \"\"\"\n \n # Return True if the list is empty\n if not lst:\n return True\n \n # Compare each element of the list with the first element\n for i in lst:\n if i != lst[0]:\n return False\n \n # If the execution reaches this point, all elements are identical\n return True", "matching_cluster_idx": 4}, {"solution": "def unique_Element(lst):\n return len(set(lst)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(list):\n return len(set(list)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(nums):\n return len(set(nums)) <= 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(lst):\n return len(set(lst)) <= 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(lst):\n return lst.count(lst[0]) == len(lst)", "matching_cluster_idx": 6}, {"solution": "def unique_Element(lst):\n \"\"\"\n This function checks if a list contains only one distinct element.\n \"\"\"\n # Check if list is empty\n if len(lst) == 0:\n return True\n else:\n first_element = lst[0]\n # Compare each element to the first\n for element in lst:\n if element != first_element:\n return False\n return True", "matching_cluster_idx": 5}, {"solution": "def unique_Element(lst):\n return len(set(lst)) <= 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(lst):\n return len(set(lst)) <= 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(num_list):\n return len(set(num_list)) <= 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(lst):\n return len(set(lst)) <= 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(lst):\n # Check if the list has at least two elements\n if len(set(lst)) == 1:\n return True\n else:\n return False", "matching_cluster_idx": 6}, {"solution": "def unique_Element(lst):\n # If list is empty or contains only one element\n if len(lst) < 2:\n return True\n else:\n return len(set(lst)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(lst):\n return len(set(lst)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(lst):\n return lst.count(lst[0]) == len(lst)", "matching_cluster_idx": 6}, {"solution": "def unique_Element(lst):\n \"\"\"\n This function checks whether a list of numbers contains only one distinct element or not.\n \"\"\"\n return len(set(lst)) <= 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(lst):\n return len(set(lst)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(lst):\n # Check if the list has more than one distinct element\n if len(set(lst)) > 1:\n return False\n else:\n return True", "matching_cluster_idx": 6}]}, "Mbpp/764": {"dps": 88.88888888888889, "dps_norm": 50.0, "pass@1": 100.0, "profiled": [{"solution": "def number_ctr(string):\n return sum(c.isdigit() for c in string)", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n return sum(c.isdigit() for c in s)", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n count = 0\n for char in s:\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n return sum(c.isdigit() for c in s)", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n return sum(c.isdigit() for c in s)", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n return sum(c.isdigit() for c in s)", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n return sum(c.isdigit() for c in s)", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n # Initialize count to 0\n count = 0\n for char in s:\n # Check if each character is a digit\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n return sum(c.isdigit() for c in s)", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n return sum(c.isdigit() for c in s)", "matching_cluster_idx": 2}, {"solution": "def number_ctr(input_string):\n count = 0\n for char in input_string:\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(string):\n return sum(c.isdigit() for c in string)", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n # initialize a counter variable to zero\n counter = 0\n # iterate over each character in the string\n for char in s:\n # if the character is a digit, increment the counter\n if char.isdigit():\n counter += 1\n # return the counter value\n return counter", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n return sum(c.isdigit() for c in s)", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n \"\"\"\n Function to count the number of digits in a given string.\n \"\"\"\n return sum(c.isdigit() for c in s)", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n return sum(c.isdigit() for c in s)", "matching_cluster_idx": 2}, {"solution": "def number_ctr(input_str):\n return sum(c.isdigit() for c in input_str)", "matching_cluster_idx": 2}, {"solution": "def number_ctr(input_string):\n return sum(c.isdigit() for c in input_string)", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n return sum(c.isdigit() for c in s)", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n return sum(c.isdigit() for c in s)", "matching_cluster_idx": 2}]}, "Mbpp/766": {"dps": 80.37383177570094, "dps_norm": 66.66666666666667, "pass@1": 100.0, "profiled": [{"solution": "def pair_wise(lst):\n return [(lst[i], lst[i+1]) for i in range(len(lst)-1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(input_list):\n return [(input_list[i], input_list[i + 1]) for i in range(len(input_list) - 1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n return [(lst[i], lst[i+1]) for i in range(len(lst)-1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n return [(lst[i], lst[i+1]) for i in range(len(lst)-1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n return [(lst[i], lst[i + 1]) for i in range(len(lst) - 1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n return [(lst[i], lst[i+1]) for i in range(len(lst)-1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n return [(lst[i], lst[i+1]) for i in range(len(lst)-1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n return [(lst[i], lst[i+1]) for i in range(len(lst)-1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n return [(lst[i], lst[i + 1]) for i in range(len(lst) - 1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n return [(lst[i], lst[i + 1]) for i in range(len(lst) - 1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n return [(lst[i], lst[i+1]) for i in range(len(lst)-1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n return [(lst[i], lst[i + 1]) for i in range(len(lst) - 1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n return [(lst[i], lst[i+1]) for i in range(len(lst)-1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n return [(lst[i], lst[i + 1]) for i in range(len(lst) - 1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n return [(lst[i], lst[i+1]) for i in range(len(lst)-1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n return [(lst[i], lst[i+1]) for i in range(len(lst)-1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n return [(lst[i], lst[i + 1]) for i in range(len(lst) - 1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n return [(lst[i], lst[i + 1]) for i in range(len(lst) - 1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n return [(lst[i], lst[i + 1]) for i in range(len(lst) - 1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(input_list):\n return [(input_list[i], input_list[i+1]) for i in range(len(input_list)-1)]", "matching_cluster_idx": 3}]}, "Mbpp/775": {"dps": 81.44, "dps_norm": 58.57142857142857, "pass@1": 76.0, "profiled": [{"solution": "def odd_position(lst):\n for i in range(1, len(lst), 2):\n if lst[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n return all(el % 2 != 0 for el in lst[1::2])", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n for i in range(len(lst)):\n if i % 2 != 0 and lst[i] % 2 == 0: # Check if the index is odd and the value at that index is even.\n return False\n return True", "matching_cluster_idx": 2}, {"solution": "def odd_position(lst):\n for i in range(len(lst)):\n if i % 2 != 0 and lst[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 2}, {"solution": "def odd_position(lst):\n \"\"\"\n This function checks whether every odd index contains odd numbers.\n \"\"\"\n return all(el % 2 != 0 for el in lst[1::2])", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n for i in range(len(lst)):\n if i % 2 != 0 and lst[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 2}, {"solution": "def odd_position(lst):\n for i in range(len(lst)):\n if i % 2 != 0 and lst[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 2}, {"solution": "def odd_position(lst):\n return all(e % 2 == 1 for i, e in enumerate(lst) if i % 2 == 1)", "matching_cluster_idx": 2}, {"solution": "def odd_position(lst):\n for i in range(1, len(lst), 2):\n if lst[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n # iterating through the list with odd indices\n for i in range(len(lst)):\n if i % 2 != 0 and lst[i] % 2 == 0:\n # if any odd index contains even number, returning False\n return False\n # if none of the odd indexes contain even number, returning True\n return True", "matching_cluster_idx": 2}, {"solution": "def odd_position(lst):\n return all(el % 2 != 0 for el in lst[1::2])", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n \"\"\" Check if every odd index contains odd numbers \"\"\"\n for i in range(1, len(lst), 2): # iterate over odd indexes\n if lst[i] % 2 == 0: # if the number in the odd index is even\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n return all(e % 2 != 0 for i, e in enumerate(lst) if i % 2 != 0)", "matching_cluster_idx": 2}, {"solution": "def odd_position(lst):\n for i in range(1, len(lst), 2):\n if lst[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(nums):\n # Loop over the list at every odd index (using step of 2)\n for i in range(1, len(nums), 2):\n # If the number is even, return False\n if nums[i] % 2 == 0:\n return False\n # If we have looped through the entire list without finding even numbers, return True\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n \"\"\"\n Checks if every odd index in a list contains an odd number\n\n Args:\n lst: list to be checked\n\n Returns:\n bool: True if every odd index contains an odd number, else False\n \"\"\"\n for i in range(1, len(lst), 2):\n if lst[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n return all(el % 2 != 0 for i, el in enumerate(lst) if i % 2 != 0)", "matching_cluster_idx": 2}, {"solution": "def odd_position(lst):\n \"\"\"\n This function checks whether every odd index contains odd numbers.\n \"\"\"\n # Iterate through the list and check every odd index.\n for i in range(1, len(lst), 2):\n # If the number at the odd index is not odd, return False.\n if lst[i] % 2 == 0:\n return False\n # If all numbers at odd indices are odd, return True.\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n return all(el % 2 != 0 for el in lst[1::2])", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n for i in range(len(lst)):\n if i % 2 != 0 and lst[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 2}]}, "Mbpp/777": {"dps": 75.25510204081633, "dps_norm": 80.55555555555556, "pass@1": 64.0, "profiled": [{"solution": "def find_sum(input_list):\n # Creating a set to store unique numbers\n unique_set = set(input_list)\n # Calculating the sum of unique numbers\n sum_unique = sum(unique_set)\n return sum_unique", "matching_cluster_idx": 8}, {"solution": "def find_sum(lst):\n return sum(set(lst))", "matching_cluster_idx": 8}, {"solution": "def find_sum(lst):\n return sum(set(lst))", "matching_cluster_idx": 8}, {"solution": "def find_sum(lst):\n return sum(x for i, x in enumerate(lst) if lst.index(x) == i)", "matching_cluster_idx": -1}, {"solution": "def find_sum(lst):\n \"\"\"\n Function to find the sum of non-repeated elements in a given list.\n \"\"\"\n return sum(i for i in set(lst))", "matching_cluster_idx": 5}, {"solution": "def find_sum(lst):\n return sum(set(lst))", "matching_cluster_idx": 8}, {"solution": "def find_sum(numbers):\n unique_numbers = set(numbers)\n return sum(unique_numbers)", "matching_cluster_idx": 8}, {"solution": "def find_sum(lst):\n return sum(set(lst))", "matching_cluster_idx": 8}, {"solution": "def find_sum(lst):\n return sum(set(lst))", "matching_cluster_idx": 8}, {"solution": "def find_sum(lst):\n \"\"\"\n Finds the sum of non-repeated elements in the provided list.\n\n Parameters:\n lst (list): the input list of integers\n\n Returns:\n int: the sum of unique elements in the input list\n\n Examples:\n >>> find_sum([1,2,3,1,1,4,5,6])\n 21\n \"\"\"\n ## Step 1: Initialize a set to store unique elements\n unique_elements = set()\n\n ## Step 2: Iterate over the input list and add unique elements to the set\n for element in lst:\n unique_elements.add(element)\n\n ## Step 3: Sum up the unique elements in the set and return\n return sum(unique_elements)", "matching_cluster_idx": 4}, {"solution": "def find_sum(nums):\n seen = set()\n unique_nums = [x for x in nums if x not in seen and not seen.add(x)]\n return sum(unique_nums)", "matching_cluster_idx": 4}, {"solution": "def find_sum(lst):\n seen = set()\n uniq_sum = 0\n for num in lst:\n if num not in seen:\n seen.add(num)\n uniq_sum += num\n return uniq_sum", "matching_cluster_idx": 4}, {"solution": "def find_sum(lst):\n return sum(set(lst))", "matching_cluster_idx": 8}, {"solution": "def find_sum(input_list):\n non_repeated = set()\n for i in input_list:\n if i not in non_repeated:\n non_repeated.add(i)\n return sum(non_repeated)", "matching_cluster_idx": 4}, {"solution": "def find_sum(lst):\n return sum(set(lst))", "matching_cluster_idx": 8}, {"solution": "def find_sum(lst):\n return sum(set(lst))", "matching_cluster_idx": 8}, {"solution": "def find_sum(numbers):\n # Create an empty list to store unique numbers\n unique_numbers = []\n # Loop through the given list\n for number in numbers:\n # If a number is not in unique numbers list, append it\n if number not in unique_numbers:\n unique_numbers.append(number)\n # Return the sum of unique numbers\n return sum(unique_numbers)", "matching_cluster_idx": 1}, {"solution": "def find_sum(lst):\n # Using Python's set data structure to eliminate duplicate elements\n unique_elements = set(lst)\n # Sum up unique elements\n sum_unique_elements = sum(unique_elements)\n return sum_unique_elements", "matching_cluster_idx": 8}, {"solution": "def find_sum(input_list):\n # convert the list into a set to remove duplicates\n unique_elements = set(input_list)\n # calculate the sum of unique elements\n sum_unique_elements = sum(unique_elements)\n # return the result\n return sum_unique_elements", "matching_cluster_idx": 8}, {"solution": "def find_sum(lst):\n unique_elements = set(lst)\n return sum(unique_elements)", "matching_cluster_idx": 8}]}, "Mbpp/781": {"dps": 41.496062992125985, "dps_norm": 29.0, "pass@1": 98.0, "profiled": [{"solution": "def count_divisors(n):\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count % 2 == 0", "matching_cluster_idx": 0}, {"solution": "def count_divisors(n):\n \"\"\"\n Function to count divisors of a given number.\n \"\"\"\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count % 2 == 0", "matching_cluster_idx": 1}, {"solution": "def count_divisors(num):\n count = 0\n for i in range(1, num+1):\n if num % i == 0:\n count += 1\n return count % 2 == 0", "matching_cluster_idx": 1}, {"solution": "def count_divisors(n):\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count % 2 == 0", "matching_cluster_idx": 0}, {"solution": "def count_divisors(n):\n count = 0\n for i in range(1, n+1):\n if n % i == 0:\n count += 1\n return count % 2 == 0", "matching_cluster_idx": 1}, {"solution": "def count_divisors(n):\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count % 2 == 0", "matching_cluster_idx": 0}, {"solution": "def count_divisors(n):\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count % 2 == 0", "matching_cluster_idx": 0}, {"solution": "def count_divisors(n):\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count % 2 == 0", "matching_cluster_idx": 0}, {"solution": "def count_divisors(n):\n count = 0\n for i in range(1, n+1):\n if n % i == 0:\n count += 1\n return count % 2 == 0", "matching_cluster_idx": 1}, {"solution": "def count_divisors(n):\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count % 2 == 0", "matching_cluster_idx": 0}, {"solution": "def count_divisors(n):\n count = 0\n for i in range(1, n+1):\n if n % i == 0:\n count += 1\n return count % 2 == 0", "matching_cluster_idx": 1}, {"solution": "def count_divisors(n):\n count = 0\n i = 1\n while(i <= n):\n if (n % i == 0):\n count += 1\n i = i + 1\n return count % 2 == 0 # returns True if count is even, False otherwise", "matching_cluster_idx": 0}, {"solution": "def count_divisors(n):\n count = 0\n for i in range(1, n+1):\n if n % i == 0:\n count += 1\n return count % 2 == 0", "matching_cluster_idx": 1}, {"solution": "def count_divisors(n):\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count % 2 == 0", "matching_cluster_idx": 0}, {"solution": "def count_divisors(n):\n count = 0\n for i in range(1, n+1):\n if n % i == 0:\n count += 1\n return count % 2 == 0", "matching_cluster_idx": 1}, {"solution": "def count_divisors(n):\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count % 2 == 0", "matching_cluster_idx": 0}, {"solution": "def count_divisors(n):\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count % 2 == 0", "matching_cluster_idx": 0}, {"solution": "def count_divisors(num):\n count = 0\n for i in range(1, num + 1):\n if num % i == 0:\n count += 1\n return count % 2 == 0", "matching_cluster_idx": 1}, {"solution": "def count_divisors(n):\n count = 0\n for i in range(1, n+1):\n if n % i == 0:\n count += 1\n return count % 2 == 0", "matching_cluster_idx": 1}, {"solution": "def count_divisors(n):\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count % 2 == 0", "matching_cluster_idx": 0}]}, "Mbpp/800": {"dps": 93.50746268656717, "dps_norm": 97.0, "pass@1": 94.0, "profiled": [{"solution": "def remove_all_spaces(input_string):\n return input_string.replace(' ', '')", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(str):\n return str.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(string):\n return string.replace(' ', '')", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(s):\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_str):\n return input_str.replace(' ', '')", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n # Replace all spaces with no space ('')\n no_space_string = input_string.replace(' ', '')\n return no_space_string", "matching_cluster_idx": 3}, {"solution": "def remove_all_spaces(input_string):\n # Replace all whitespace characters with no space\n return input_string.replace(' ', '')", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n \"\"\"This function removes all spaces from a string.\n\n Arguments:\n input_string -- string from which all spaces should be removed\n\n Return value: \n The string with all spaces removed.\n \"\"\"\n return input_string.replace(' ', '')", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n \"\"\"\n This function removes all the whitespaces in the string\n \"\"\"\n return input_string.replace(' ', '')", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(string):\n return string.replace(' ', '')", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(text):\n return text.replace(' ', '')\ntext = 'python program'", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(str):\n return str.replace(' ', '')", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(string):\n \"\"\"\n Removes all whitespace characters from a string.\n\n Parameters:\n string (str): the input string.\n\n Returns:\n str: the string with all whitespace characters removed.\n \"\"\"\n\n # Replace whitespace characters with no character to remove them\n new_string = string.replace(' ', '')\n return new_string", "matching_cluster_idx": 3}, {"solution": "def remove_all_spaces(input_string):\n return input_string.replace(' ', '')", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n # Removing all the whitespaces in the string.\n input_string = input_string.replace(\" \", \"\")\n return input_string", "matching_cluster_idx": 3}, {"solution": "def remove_all_spaces(string):\n \"\"\"\n This function removes all spaces from a string.\n \"\"\"\n return string.replace(' ', '')", "matching_cluster_idx": 4}]}, "Mbpp/805": {"dps": 95.49828178694158, "dps_norm": 99.0, "pass@1": 95.0, "profiled": [{"solution": "def max_sum_list(lst):\n max_sum = -float('inf')\n max_list = []\n for sub_list in lst:\n current_sum = sum(sub_list)\n if current_sum > max_sum:\n max_sum = current_sum\n max_list = sub_list\n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lst):\n return max(lst, key=sum)", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(list_of_lists):\n return max(list_of_lists, key=sum)", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(list_of_lists):\n \"\"\"\n Function that returns the list of lists with the highest sum.\n\n Parameters:\n list_of_lists (list): List of lists where each inner list contains integers.\n\n Returns:\n list: The list that has the highest sum of its elements.\n \"\"\"\n # Initializing the maximum sum and the corresponding list\n max_sum = None\n max_list = None\n\n # Iterating over each list in the list of lists\n for inner_list in list_of_lists:\n # Calculating the sum of the current list\n current_sum = sum(inner_list)\n\n # If max_sum is None, then we've not yet encountered any sums\n # If the current_sum is greater than max_sum, then we've found a new maximum sum\n if max_sum is None or current_sum > max_sum:\n max_sum = current_sum\n max_list = inner_list\n\n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(input_list):\n # Initialize maximum sum as negative infinity\n max_sum = float('-inf')\n # Initialize variable to hold list with maximum sum\n max_sum_list = None\n \n # Iterate over each sublist\n for sublist in input_list:\n # Calculate sum of elements in sublist\n sublist_sum = sum(sublist)\n # If sum is greater than max_sum, update max_sum and max_sum_list\n if sublist_sum > max_sum:\n max_sum = sublist_sum\n max_sum_list = sublist\n \n return max_sum_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lst):\n # Initialize the maximum sum and corresponding list\n max_sum = -float('inf')\n max_list = None\n # Iterate over each list in the list\n for l in lst:\n # Calculate the sum of the current list\n current_sum = sum(l)\n # If the sum is greater than the current maximum sum\n if current_sum > max_sum:\n # Update the maximum sum and corresponding list\n max_sum = current_sum\n max_list = l\n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lst):\n return max(lst, key=sum)", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lst):\n \"\"\"Return the list in a list of lists whose sum of elements is the highest.\"\"\"\n return max(lst, key=sum)", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lst):\n max_sum = -float('inf')\n max_lst = None\n for sublist in lst:\n if sum(sublist) > max_sum:\n max_sum = sum(sublist)\n max_lst = sublist\n return max_lst", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lst):\n max_sum = max(sum(sub_lst) for sub_lst in lst)\n for sub_lst in lst:\n if sum(sub_lst) == max_sum:\n return sub_lst", "matching_cluster_idx": 3}, {"solution": "def max_sum_list(lst):\n return max(lst, key=sum)", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lst):\n return max(lst, key=sum)", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lst):\n max_sum = -float('inf')\n max_lst = None\n for sub_lst in lst:\n if sum(sub_lst) > max_sum:\n max_sum = sum(sub_lst)\n max_lst = sub_lst\n return max_lst", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lst):\n # initiate highest_sum with first element in first sub-list and highest_list with the first sub-list itself\n highest_sum = sum(lst[0])\n highest_list = lst[0]\n for sub_list in lst:\n # compute the sum of each sub-list\n current_sum = sum(sub_list)\n # if the current_sum is higher than highest_sum, update highest_sum and highest_list\n if current_sum > highest_sum:\n highest_sum = current_sum\n highest_list = sub_list\n return highest_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(input_list):\n max_sum = -float('inf')\n max_list = []\n for l in input_list:\n if sum(l) > max_sum:\n max_sum = sum(l)\n max_list = l\n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lst):\n max_sum = -float('inf')\n max_list = []\n for sublist in lst:\n if sum(sublist) > max_sum:\n max_sum = sum(sublist)\n max_list = sublist\n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lst):\n return max(lst, key=sum)", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(input_list):\n # Initialize a variable to track the maximum sum and index of the list with the maximum sum\n max_sum = float('-inf')\n max_sum_index = 0\n \n # Traverse through each list in the input list\n for i in range(len(input_list)):\n # Calculate the sum of the elements in the current list\n current_sum = sum(input_list[i])\n # If this sum is greater than the current max_sum, update max_sum and max_sum_index\n if current_sum > max_sum:\n max_sum = current_sum\n max_sum_index = i\n \n # Return the list with the maximum sum\n return input_list[max_sum_index]", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(list_of_lists):\n max_sum = -float('inf')\n max_list = None\n for lst in list_of_lists:\n if sum(lst) > max_sum:\n max_sum = sum(lst)\n max_list = lst\n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lst):\n return max(lst, key=sum)", "matching_cluster_idx": 4}]}, "Mbpp/808": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def check_K(tup, k):\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(tuple_data, k):\n if k in tuple_data:\n return True\n else:\n return False", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(tuples, k):\n return k in tuples", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(tuple_input, k):\n return k in tuple_input", "matching_cluster_idx": 5}, {"solution": "def check_K(tuples, k):\n \"\"\"\n This function checks if a certain value k exists in a tuple\n\n Args:\n tuples : tuple, required\n k : any value, required\n\n Returns:\n bool: True if k exists in tuples, False otherwise.\n \"\"\"\n return k in tuples", "matching_cluster_idx": 5}, {"solution": "def check_K(t, k):\n return k in t", "matching_cluster_idx": 5}, {"solution": "def check_K(tuples, k):\n return k in tuples", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n # Check if k is in the tuple\n if k in tup:\n return True\n else:\n return False", "matching_cluster_idx": 5}, {"solution": "def check_K(input_tuple, k):\n \"\"\"\n Check if the given tuples contain the k or not.\n \"\"\"\n return k in input_tuple", "matching_cluster_idx": 5}, {"solution": "def check_K(tuple_k, k):\n return k in tuple_k", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(tuples, k):\n return k in tuples", "matching_cluster_idx": 5}, {"solution": "def check_K(tpl, k):\n return k in tpl", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(tuples, k):\n return k in tuples", "matching_cluster_idx": 5}, {"solution": "def check_K(tuple_check, k):\n if k in tuple_check:\n return True\n else:\n return False", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n return k in tup", "matching_cluster_idx": 5}]}}} \ No newline at end of file diff --git a/results/evalperf/deepseek-chat_openai_temp_1.0_evalperf_results.brief.json b/results/evalperf/deepseek-chat_openai_temp_1.0_evalperf_results.brief.json new file mode 100644 index 0000000..f027b06 --- /dev/null +++ b/results/evalperf/deepseek-chat_openai_temp_1.0_evalperf_results.brief.json @@ -0,0 +1 @@ +{"date": "2024-10-19 16:31", "config": {"n_samples": 100, "temperature": 1.0, "min_correct": 10, "max_profile": 20}, "summary": {"dps": 86.84652683144942, "dps_norm": 79.08774817854689, "pass@1": 88.51694915254237}, "eval": {"HumanEval/9": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n \n max_so_far = numbers[0]\n result = [max_so_far]\n \n for num in numbers[1:]:\n if num > max_so_far:\n max_so_far = num\n result.append(max_so_far)\n \n return result", "matching_cluster_idx": 8}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n \n max_so_far = numbers[0]\n result = [max_so_far]\n \n for num in numbers[1:]:\n if num > max_so_far:\n max_so_far = num\n result.append(max_so_far)\n \n return result", "matching_cluster_idx": 8}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n \n max_so_far = numbers[0]\n result = [max_so_far]\n \n for num in numbers[1:]:\n if num > max_so_far:\n max_so_far = num\n result.append(max_so_far)\n \n return result", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n \n max_so_far = numbers[0]\n result = [max_so_far]\n \n for num in numbers[1:]:\n if num > max_so_far:\n max_so_far = num\n result.append(max_so_far)\n \n return result", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n \n max_so_far = numbers[0]\n result = [max_so_far]\n \n for num in numbers[1:]:\n if num > max_so_far:\n max_so_far = num\n result.append(max_so_far)\n \n return result", "matching_cluster_idx": 8}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n \n max_so_far = numbers[0]\n result = [max_so_far]\n \n for num in numbers[1:]:\n if num > max_so_far:\n max_so_far = num\n result.append(max_so_far)\n \n return result", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n \n max_so_far = numbers[0]\n result = [max_so_far]\n \n for num in numbers[1:]:\n if num > max_so_far:\n max_so_far = num\n result.append(max_so_far)\n \n return result", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n \n max_so_far = numbers[0]\n result = [max_so_far]\n \n for num in numbers[1:]:\n if num > max_so_far:\n max_so_far = num\n result.append(max_so_far)\n \n return result", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n \n max_so_far = numbers[0]\n result = [max_so_far]\n \n for num in numbers[1:]:\n if num > max_so_far:\n max_so_far = num\n result.append(max_so_far)\n \n return result", "matching_cluster_idx": 8}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n \n max_so_far = numbers[0]\n result = [max_so_far]\n \n for number in numbers[1:]:\n if number > max_so_far:\n max_so_far = number\n result.append(max_so_far)\n \n return result", "matching_cluster_idx": 8}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n \n max_so_far = numbers[0]\n result = [max_so_far]\n \n for num in numbers[1:]:\n if num > max_so_far:\n max_so_far = num\n result.append(max_so_far)\n \n return result", "matching_cluster_idx": 8}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n \n max_so_far = numbers[0]\n result = [max_so_far]\n \n for num in numbers[1:]:\n if num > max_so_far:\n max_so_far = num\n result.append(max_so_far)\n \n return result", "matching_cluster_idx": 8}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n \n max_so_far = numbers[0]\n result = [max_so_far]\n \n for num in numbers[1:]:\n if num > max_so_far:\n max_so_far = num\n result.append(max_so_far)\n \n return result", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n \n max_so_far = numbers[0]\n result = [max_so_far]\n \n for num in numbers[1:]:\n if num > max_so_far:\n max_so_far = num\n result.append(max_so_far)\n \n return result", "matching_cluster_idx": 8}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n \n max_so_far = numbers[0]\n result = [max_so_far]\n \n for num in numbers[1:]:\n if num > max_so_far:\n max_so_far = num\n result.append(max_so_far)\n \n return result", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n \n max_so_far = numbers[0]\n result = [max_so_far]\n \n for num in numbers[1:]:\n if num > max_so_far:\n max_so_far = num\n result.append(max_so_far)\n \n return result", "matching_cluster_idx": 8}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n \n max_so_far = numbers[0]\n result = [max_so_far]\n \n for num in numbers[1:]:\n if num > max_so_far:\n max_so_far = num\n result.append(max_so_far)\n \n return result", "matching_cluster_idx": 8}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n \n max_so_far = numbers[0]\n result = [max_so_far]\n \n for num in numbers[1:]:\n if num > max_so_far:\n max_so_far = num\n result.append(max_so_far)\n \n return result", "matching_cluster_idx": 8}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n \n max_so_far = numbers[0]\n result = [max_so_far]\n \n for num in numbers[1:]:\n if num > max_so_far:\n max_so_far = num\n result.append(max_so_far)\n \n return result", "matching_cluster_idx": 8}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n \n max_so_far = numbers[0]\n result = [max_so_far]\n \n for num in numbers[1:]:\n if num > max_so_far:\n max_so_far = num\n result.append(max_so_far)\n \n return result", "matching_cluster_idx": 8}]}, "HumanEval/0": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n if abs(numbers[i] - numbers[j]) < threshold:\n return True\n return False", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n if abs(numbers[i] - numbers[j]) < threshold:\n return True\n return False", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n if abs(numbers[i] - numbers[j]) < threshold:\n return True\n return False", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n if abs(numbers[i] - numbers[j]) < threshold:\n return True\n return False", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n if abs(numbers[i] - numbers[j]) < threshold:\n return True\n return False", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n if abs(numbers[i] - numbers[j]) < threshold:\n return True\n return False", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n if abs(numbers[i] - numbers[j]) < threshold:\n return True\n return False", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n if abs(numbers[i] - numbers[j]) < threshold:\n return True\n return False", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n # Iterate through each pair of numbers in the list\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n # Calculate the absolute difference between the two numbers\n if abs(numbers[i] - numbers[j]) < threshold:\n return True\n return False", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n # Iterate through each pair of numbers\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n # Calculate the absolute difference between the two numbers\n if abs(numbers[i] - numbers[j]) < threshold:\n return True\n return False", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n if abs(numbers[i] - numbers[j]) < threshold:\n return True\n return False", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n if abs(numbers[i] - numbers[j]) < threshold:\n return True\n return False", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n if abs(numbers[i] - numbers[j]) < threshold:\n return True\n return False", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n if abs(numbers[i] - numbers[j]) < threshold:\n return True\n return False", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n if abs(numbers[i] - numbers[j]) < threshold:\n return True\n return False", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n if abs(numbers[i] - numbers[j]) < threshold:\n return True\n return False", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n if abs(numbers[i] - numbers[j]) < threshold:\n return True\n return False", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n if abs(numbers[i] - numbers[j]) < threshold:\n return True\n return False", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n # Iterate through each pair of numbers in the list\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n # Calculate the absolute difference between the two numbers\n if abs(numbers[i] - numbers[j]) < threshold:\n return True\n return False", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n # Iterate through each pair of numbers in the list\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n # Calculate the absolute difference between the two numbers\n if abs(numbers[i] - numbers[j]) < threshold:\n return True\n return False", "matching_cluster_idx": 6}]}, "HumanEval/4": {"dps": 76.26582278481013, "dps_norm": 83.33333333333333, "pass@1": 100.0, "profiled": [{"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if not numbers:\n raise ValueError(\"The input list must not be empty\")\n \n mean_value = sum(numbers) / len(numbers)\n absolute_deviations = [abs(x - mean_value) for x in numbers]\n mad = sum(absolute_deviations) / len(numbers)\n \n return mad", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if not numbers:\n raise ValueError(\"The input list must not be empty\")\n \n mean_value = sum(numbers) / len(numbers)\n absolute_deviations = [abs(x - mean_value) for x in numbers]\n mad = sum(absolute_deviations) / len(numbers)\n \n return mad", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if not numbers:\n raise ValueError(\"The input list must not be empty\")\n \n mean_value = sum(numbers) / len(numbers)\n absolute_deviations = [abs(x - mean_value) for x in numbers]\n mad = sum(absolute_deviations) / len(numbers)\n \n return mad", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if not numbers:\n raise ValueError(\"The input list must not be empty\")\n \n mean_value = sum(numbers) / len(numbers)\n absolute_deviations = [abs(x - mean_value) for x in numbers]\n mad = sum(absolute_deviations) / len(numbers)\n \n return mad", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if not numbers:\n raise ValueError(\"The input list must not be empty\")\n \n mean_value = sum(numbers) / len(numbers)\n absolute_deviations = [abs(x - mean_value) for x in numbers]\n mad = sum(absolute_deviations) / len(numbers)\n \n return mad", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if not numbers:\n raise ValueError(\"The input list must not be empty\")\n \n mean_value = sum(numbers) / len(numbers)\n absolute_deviations = [abs(x - mean_value) for x in numbers]\n mad = sum(absolute_deviations) / len(numbers)\n \n return mad", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if not numbers:\n return 0.0 # Return 0.0 for an empty list to avoid division by zero\n \n mean_value = sum(numbers) / len(numbers)\n absolute_deviations = [abs(x - mean_value) for x in numbers]\n mad = sum(absolute_deviations) / len(numbers)\n \n return mad", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if not numbers:\n raise ValueError(\"The input list must not be empty.\")\n \n mean_value = sum(numbers) / len(numbers)\n absolute_deviations = [abs(x - mean_value) for x in numbers]\n mad = sum(absolute_deviations) / len(numbers)\n \n return mad", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if not numbers:\n raise ValueError(\"The input list must not be empty\")\n \n mean_value = sum(numbers) / len(numbers)\n absolute_deviations = [abs(x - mean_value) for x in numbers]\n mad = sum(absolute_deviations) / len(numbers)\n \n return mad", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if not numbers:\n raise ValueError(\"The input list must not be empty\")\n \n mean_value = sum(numbers) / len(numbers)\n absolute_deviations = [abs(x - mean_value) for x in numbers]\n mad = sum(absolute_deviations) / len(numbers)\n \n return mad", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if not numbers:\n return 0.0\n \n mean_value = sum(numbers) / len(numbers)\n absolute_deviations = [abs(x - mean_value) for x in numbers]\n mad = sum(absolute_deviations) / len(numbers)\n \n return mad", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if not numbers:\n raise ValueError(\"The input list must not be empty\")\n \n mean_value = sum(numbers) / len(numbers)\n absolute_deviations = [abs(x - mean_value) for x in numbers]\n mad = sum(absolute_deviations) / len(numbers)\n \n return mad", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if not numbers:\n raise ValueError(\"The input list must not be empty\")\n \n mean_value = sum(numbers) / len(numbers)\n absolute_deviations = [abs(x - mean_value) for x in numbers]\n mad = sum(absolute_deviations) / len(numbers)\n \n return mad", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if not numbers:\n raise ValueError(\"The input list must not be empty\")\n \n mean_value = sum(numbers) / len(numbers)\n absolute_deviations = [abs(x - mean_value) for x in numbers]\n mad = sum(absolute_deviations) / len(numbers)\n \n return mad", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if not numbers:\n raise ValueError(\"The input list must not be empty\")\n \n mean_value = sum(numbers) / len(numbers)\n absolute_deviations = [abs(x - mean_value) for x in numbers]\n mad = sum(absolute_deviations) / len(numbers)\n \n return mad", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if not numbers:\n raise ValueError(\"The input list must not be empty\")\n \n mean_value = sum(numbers) / len(numbers)\n absolute_deviations = [abs(x - mean_value) for x in numbers]\n mad = sum(absolute_deviations) / len(numbers)\n \n return mad", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if not numbers:\n raise ValueError(\"The input list must not be empty\")\n \n mean_value = sum(numbers) / len(numbers)\n absolute_deviations = [abs(x - mean_value) for x in numbers]\n mad = sum(absolute_deviations) / len(numbers)\n \n return mad", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if not numbers:\n raise ValueError(\"The input list must not be empty.\")\n \n mean_value = sum(numbers) / len(numbers)\n absolute_deviations = [abs(x - mean_value) for x in numbers]\n mad = sum(absolute_deviations) / len(numbers)\n \n return mad", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if not numbers:\n raise ValueError(\"The input list must not be empty\")\n \n mean_value = sum(numbers) / len(numbers)\n absolute_deviations = [abs(x - mean_value) for x in numbers]\n mad = sum(absolute_deviations) / len(numbers)\n \n return mad", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if not numbers:\n raise ValueError(\"The input list must not be empty\")\n \n mean_value = sum(numbers) / len(numbers)\n absolute_deviations = [abs(x - mean_value) for x in numbers]\n mad = sum(absolute_deviations) / len(numbers)\n \n return mad", "matching_cluster_idx": 4}]}, "HumanEval/16": {"dps": 45.73643410852713, "dps_norm": 88.88888888888889, "pass@1": 100.0, "profiled": [{"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lowercase to ignore case\n lower_string = string.lower()\n \n # Use a set to store distinct characters\n distinct_characters = set(lower_string)\n \n # Return the number of distinct characters\n return len(distinct_characters)", "matching_cluster_idx": 7}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lowercase to ignore case\n lower_string = string.lower()\n \n # Use a set to store distinct characters\n distinct_characters = set(lower_string)\n \n # Return the number of distinct characters\n return len(distinct_characters)", "matching_cluster_idx": 7}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lowercase to ignore case\n lower_string = string.lower()\n \n # Use a set to store distinct characters\n distinct_characters = set(lower_string)\n \n # Return the number of distinct characters\n return len(distinct_characters)", "matching_cluster_idx": 7}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lowercase to ignore case\n lower_string = string.lower()\n \n # Use a set to store distinct characters\n distinct_characters = set(lower_string)\n \n # Return the number of distinct characters\n return len(distinct_characters)", "matching_cluster_idx": 7}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lowercase to ignore case\n lower_string = string.lower()\n \n # Use a set to store distinct characters\n distinct_characters = set(lower_string)\n \n # Return the number of distinct characters\n return len(distinct_characters)", "matching_cluster_idx": 7}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lowercase to ignore case\n lower_string = string.lower()\n \n # Use a set to store distinct characters\n distinct_characters = set(lower_string)\n \n # Return the number of distinct characters\n return len(distinct_characters)", "matching_cluster_idx": 7}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lowercase to ignore case\n lower_string = string.lower()\n \n # Use a set to store distinct characters\n distinct_characters = set(lower_string)\n \n # Return the number of distinct characters\n return len(distinct_characters)", "matching_cluster_idx": 7}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lowercase to ignore case\n lower_string = string.lower()\n \n # Use a set to store distinct characters\n distinct_characters = set(lower_string)\n \n # Return the number of distinct characters\n return len(distinct_characters)", "matching_cluster_idx": 7}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lowercase to ignore case\n lower_string = string.lower()\n \n # Use a set to store distinct characters\n distinct_characters = set(lower_string)\n \n # Return the number of distinct characters\n return len(distinct_characters)", "matching_cluster_idx": 7}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lowercase to ignore case\n lower_string = string.lower()\n \n # Use a set to store distinct characters\n distinct_characters = set(lower_string)\n \n # Return the number of distinct characters\n return len(distinct_characters)", "matching_cluster_idx": 7}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lowercase to ignore case\n lower_string = string.lower()\n \n # Use a set to store distinct characters\n distinct_characters = set(lower_string)\n \n # Return the number of distinct characters\n return len(distinct_characters)", "matching_cluster_idx": 7}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lowercase to ignore case\n lower_string = string.lower()\n \n # Use a set to store distinct characters\n distinct_characters = set(lower_string)\n \n # Return the number of distinct characters\n return len(distinct_characters)", "matching_cluster_idx": 7}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lowercase to ignore case\n lower_string = string.lower()\n \n # Use a set to store distinct characters\n distinct_characters = set(lower_string)\n \n # Return the number of distinct characters\n return len(distinct_characters)", "matching_cluster_idx": 7}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lowercase to ignore case\n lower_string = string.lower()\n \n # Use a set to store distinct characters\n distinct_characters = set(lower_string)\n \n # Return the number of distinct characters\n return len(distinct_characters)", "matching_cluster_idx": 7}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lowercase to ignore case\n lower_string = string.lower()\n \n # Use a set to store distinct characters\n distinct_characters = set(lower_string)\n \n # Return the number of distinct characters\n return len(distinct_characters)", "matching_cluster_idx": 7}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lowercase to ignore case\n lower_string = string.lower()\n \n # Use a set to store distinct characters\n distinct_characters = set(lower_string)\n \n # Return the number of distinct characters\n return len(distinct_characters)", "matching_cluster_idx": 7}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lowercase to ignore case\n lower_string = string.lower()\n \n # Use a set to store distinct characters\n distinct_characters = set(lower_string)\n \n # Return the number of distinct characters\n return len(distinct_characters)", "matching_cluster_idx": 7}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lowercase to ignore case\n lower_string = string.lower()\n \n # Use a set to store distinct characters\n distinct_characters = set(lower_string)\n \n # Return the number of distinct characters\n return len(distinct_characters)", "matching_cluster_idx": 7}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lowercase to ignore case\n lower_string = string.lower()\n \n # Use a set to store distinct characters\n distinct_characters = set(lower_string)\n \n # Return the number of distinct characters\n return len(distinct_characters)", "matching_cluster_idx": 7}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lowercase to ignore case\n lower_string = string.lower()\n \n # Use a set to store distinct characters\n distinct_characters = set(lower_string)\n \n # Return the number of distinct characters\n return len(distinct_characters)", "matching_cluster_idx": 7}]}, "HumanEval/20": {"dps": 92.10653753026634, "dps_norm": 94.44444444444444, "pass@1": 100.0, "profiled": [{"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n # Sort the list to ensure the smallest difference is between consecutive elements\n sorted_numbers = sorted(numbers)\n \n # Initialize variables to track the closest pair and their difference\n closest_pair = (sorted_numbers[0], sorted_numbers[1])\n min_diff = abs(sorted_numbers[1] - sorted_numbers[0])\n \n # Iterate through the sorted list to find the closest pair\n for i in range(1, len(sorted_numbers) - 1):\n diff = abs(sorted_numbers[i + 1] - sorted_numbers[i])\n if diff < min_diff:\n min_diff = diff\n closest_pair = (sorted_numbers[i], sorted_numbers[i + 1])\n \n # Ensure the smaller number is first in the tuple\n return tuple(sorted(closest_pair))", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n # Initialize variables to store the closest pair and their difference\n closest_pair = (numbers[0], numbers[1])\n min_diff = abs(numbers[0] - numbers[1])\n \n # Iterate through the list to find the closest pair\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n diff = abs(numbers[i] - numbers[j])\n if diff < min_diff:\n min_diff = diff\n closest_pair = (numbers[i], numbers[j])\n \n # Ensure the pair is returned in the correct order\n return (min(closest_pair), max(closest_pair))", "matching_cluster_idx": 3}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n # Sort the list to ensure the closest elements are adjacent\n sorted_numbers = sorted(numbers)\n \n # Initialize variables to track the closest pair and their difference\n closest_pair = (sorted_numbers[0], sorted_numbers[1])\n min_diff = abs(sorted_numbers[0] - sorted_numbers[1])\n \n # Iterate through the sorted list to find the closest pair\n for i in range(1, len(sorted_numbers) - 1):\n diff = abs(sorted_numbers[i] - sorted_numbers[i + 1])\n if diff < min_diff:\n min_diff = diff\n closest_pair = (sorted_numbers[i], sorted_numbers[i + 1])\n \n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n # Sort the list to ensure the closest elements are adjacent\n sorted_numbers = sorted(numbers)\n \n # Initialize variables to track the closest pair and their difference\n closest_pair = (sorted_numbers[0], sorted_numbers[1])\n min_diff = abs(sorted_numbers[0] - sorted_numbers[1])\n \n # Iterate through the sorted list to find the closest pair\n for i in range(1, len(sorted_numbers) - 1):\n diff = abs(sorted_numbers[i] - sorted_numbers[i + 1])\n if diff < min_diff:\n min_diff = diff\n closest_pair = (sorted_numbers[i], sorted_numbers[i + 1])\n \n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n # Sort the list to ensure the closest elements are adjacent\n sorted_numbers = sorted(numbers)\n \n # Initialize variables to track the closest pair and their difference\n closest_pair = (sorted_numbers[0], sorted_numbers[1])\n min_diff = abs(sorted_numbers[0] - sorted_numbers[1])\n \n # Iterate through the sorted list to find the closest pair\n for i in range(1, len(sorted_numbers) - 1):\n diff = abs(sorted_numbers[i] - sorted_numbers[i + 1])\n if diff < min_diff:\n min_diff = diff\n closest_pair = (sorted_numbers[i], sorted_numbers[i + 1])\n \n # Return the closest pair in the required order\n return tuple(sorted(closest_pair))", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n # Sort the list to ensure the closest elements are adjacent after sorting\n sorted_numbers = sorted(numbers)\n \n # Initialize variables to track the closest pair and their difference\n closest_pair = (sorted_numbers[0], sorted_numbers[1])\n min_diff = abs(sorted_numbers[0] - sorted_numbers[1])\n \n # Iterate through the sorted list to find the closest pair\n for i in range(1, len(sorted_numbers) - 1):\n diff = abs(sorted_numbers[i] - sorted_numbers[i + 1])\n if diff < min_diff:\n min_diff = diff\n closest_pair = (sorted_numbers[i], sorted_numbers[i + 1])\n \n # Return the closest pair in the required order\n return tuple(sorted(closest_pair))", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n # Initialize variables to store the closest pair and the minimum difference\n closest_pair = (numbers[0], numbers[1])\n min_diff = abs(numbers[0] - numbers[1])\n \n # Iterate through the list to find the closest pair\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n diff = abs(numbers[i] - numbers[j])\n if diff < min_diff:\n min_diff = diff\n closest_pair = (numbers[i], numbers[j])\n \n # Ensure the pair is returned in the correct order\n return tuple(sorted(closest_pair))", "matching_cluster_idx": 3}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n # Sort the list to ensure the closest elements are adjacent after sorting\n sorted_numbers = sorted(numbers)\n \n # Initialize variables to track the closest pair and their difference\n closest_pair = (sorted_numbers[0], sorted_numbers[1])\n min_difference = abs(sorted_numbers[0] - sorted_numbers[1])\n \n # Iterate through the sorted list to find the closest pair\n for i in range(1, len(sorted_numbers) - 1):\n current_difference = abs(sorted_numbers[i] - sorted_numbers[i + 1])\n if current_difference < min_difference:\n min_difference = current_difference\n closest_pair = (sorted_numbers[i], sorted_numbers[i + 1])\n \n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n # Sort the list to ensure the closest elements are adjacent\n sorted_numbers = sorted(numbers)\n \n # Initialize variables to track the closest pair and their difference\n closest_pair = (sorted_numbers[0], sorted_numbers[1])\n min_diff = abs(sorted_numbers[0] - sorted_numbers[1])\n \n # Iterate through the sorted list to find the closest pair\n for i in range(1, len(sorted_numbers) - 1):\n diff = abs(sorted_numbers[i] - sorted_numbers[i + 1])\n if diff < min_diff:\n min_diff = diff\n closest_pair = (sorted_numbers[i], sorted_numbers[i + 1])\n \n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n # Sort the list to ensure the closest elements are adjacent after sorting\n sorted_numbers = sorted(numbers)\n \n # Initialize variables to store the closest pair and the minimum difference\n closest_pair = (sorted_numbers[0], sorted_numbers[1])\n min_diff = abs(sorted_numbers[0] - sorted_numbers[1])\n \n # Iterate through the sorted list to find the closest pair\n for i in range(1, len(sorted_numbers) - 1):\n diff = abs(sorted_numbers[i] - sorted_numbers[i + 1])\n if diff < min_diff:\n min_diff = diff\n closest_pair = (sorted_numbers[i], sorted_numbers[i + 1])\n \n # Return the closest pair in order (smaller number, larger number)\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n # Sort the list to ensure the smallest difference is between consecutive elements\n sorted_numbers = sorted(numbers)\n \n # Initialize variables to store the closest pair and their difference\n closest_pair = (sorted_numbers[0], sorted_numbers[1])\n min_difference = abs(sorted_numbers[0] - sorted_numbers[1])\n \n # Iterate through the sorted list to find the closest pair\n for i in range(1, len(sorted_numbers) - 1):\n current_difference = abs(sorted_numbers[i] - sorted_numbers[i + 1])\n if current_difference < min_difference:\n min_difference = current_difference\n closest_pair = (sorted_numbers[i], sorted_numbers[i + 1])\n \n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n # Sort the list to ensure the closest elements are adjacent\n sorted_numbers = sorted(numbers)\n \n # Initialize variables to track the closest pair and their difference\n closest_pair = (sorted_numbers[0], sorted_numbers[1])\n min_diff = abs(sorted_numbers[0] - sorted_numbers[1])\n \n # Iterate through the sorted list to find the closest pair\n for i in range(1, len(sorted_numbers) - 1):\n diff = abs(sorted_numbers[i] - sorted_numbers[i + 1])\n if diff < min_diff:\n min_diff = diff\n closest_pair = (sorted_numbers[i], sorted_numbers[i + 1])\n \n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n # Sort the list to ensure that the closest elements are adjacent in the sorted list\n sorted_numbers = sorted(numbers)\n \n # Initialize variables to store the closest pair and the minimum difference\n closest_pair = (sorted_numbers[0], sorted_numbers[1])\n min_diff = abs(sorted_numbers[0] - sorted_numbers[1])\n \n # Iterate through the sorted list to find the closest pair\n for i in range(1, len(sorted_numbers) - 1):\n diff = abs(sorted_numbers[i] - sorted_numbers[i + 1])\n if diff < min_diff:\n min_diff = diff\n closest_pair = (sorted_numbers[i], sorted_numbers[i + 1])\n \n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n # Sort the list to ensure the closest elements are adjacent\n sorted_numbers = sorted(numbers)\n \n # Initialize variables to store the closest pair and their difference\n closest_pair = (sorted_numbers[0], sorted_numbers[1])\n min_diff = abs(sorted_numbers[1] - sorted_numbers[0])\n \n # Iterate through the sorted list to find the closest pair\n for i in range(1, len(sorted_numbers) - 1):\n diff = abs(sorted_numbers[i + 1] - sorted_numbers[i])\n if diff < min_diff:\n min_diff = diff\n closest_pair = (sorted_numbers[i], sorted_numbers[i + 1])\n \n # Ensure the smaller number is first in the tuple\n return tuple(sorted(closest_pair))", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n # Sort the list to ensure the closest elements are adjacent\n sorted_numbers = sorted(numbers)\n \n # Initialize variables to store the closest pair and the minimum difference\n closest_pair = (sorted_numbers[0], sorted_numbers[1])\n min_diff = abs(sorted_numbers[0] - sorted_numbers[1])\n \n # Iterate through the sorted list to find the closest pair\n for i in range(1, len(sorted_numbers) - 1):\n diff = abs(sorted_numbers[i] - sorted_numbers[i + 1])\n if diff < min_diff:\n min_diff = diff\n closest_pair = (sorted_numbers[i], sorted_numbers[i + 1])\n \n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n # Sort the list to ensure that the closest elements are adjacent after sorting\n sorted_numbers = sorted(numbers)\n \n # Initialize variables to store the closest pair and the minimum difference\n closest_pair = (sorted_numbers[0], sorted_numbers[1])\n min_diff = abs(sorted_numbers[0] - sorted_numbers[1])\n \n # Iterate through the sorted list to find the closest pair\n for i in range(1, len(sorted_numbers) - 1):\n diff = abs(sorted_numbers[i] - sorted_numbers[i + 1])\n if diff < min_diff:\n min_diff = diff\n closest_pair = (sorted_numbers[i], sorted_numbers[i + 1])\n \n # Ensure the smaller number is first in the tuple\n return tuple(sorted(closest_pair))", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n # Sort the list to ensure the closest elements are adjacent\n sorted_numbers = sorted(numbers)\n \n # Initialize variables to track the closest pair and their difference\n closest_pair = (sorted_numbers[0], sorted_numbers[1])\n min_diff = abs(sorted_numbers[1] - sorted_numbers[0])\n \n # Iterate through the sorted list to find the closest pair\n for i in range(1, len(sorted_numbers) - 1):\n diff = abs(sorted_numbers[i + 1] - sorted_numbers[i])\n if diff < min_diff:\n min_diff = diff\n closest_pair = (sorted_numbers[i], sorted_numbers[i + 1])\n \n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n # Sort the list to ensure the numbers are in order\n sorted_numbers = sorted(numbers)\n \n # Initialize variables to track the closest pair and their difference\n closest_pair = (sorted_numbers[0], sorted_numbers[1])\n min_diff = abs(sorted_numbers[0] - sorted_numbers[1])\n \n # Iterate through the sorted list to find the closest pair\n for i in range(1, len(sorted_numbers) - 1):\n diff = abs(sorted_numbers[i] - sorted_numbers[i + 1])\n if diff < min_diff:\n min_diff = diff\n closest_pair = (sorted_numbers[i], sorted_numbers[i + 1])\n \n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n # Sort the list to ensure the closest elements are adjacent after sorting\n sorted_numbers = sorted(numbers)\n \n # Initialize variables to store the closest pair and their difference\n closest_pair = (sorted_numbers[0], sorted_numbers[1])\n min_diff = abs(sorted_numbers[0] - sorted_numbers[1])\n \n # Iterate through the sorted list to find the closest pair\n for i in range(1, len(sorted_numbers) - 1):\n diff = abs(sorted_numbers[i] - sorted_numbers[i + 1])\n if diff < min_diff:\n min_diff = diff\n closest_pair = (sorted_numbers[i], sorted_numbers[i + 1])\n \n # Ensure the smaller number is first in the tuple\n return tuple(sorted(closest_pair))", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n # Sort the list to ensure that the closest elements are adjacent\n sorted_numbers = sorted(numbers)\n \n # Initialize variables to store the closest pair and their difference\n closest_pair = (sorted_numbers[0], sorted_numbers[1])\n min_diff = abs(sorted_numbers[0] - sorted_numbers[1])\n \n # Iterate through the sorted list to find the closest pair\n for i in range(1, len(sorted_numbers) - 1):\n diff = abs(sorted_numbers[i] - sorted_numbers[i + 1])\n if diff < min_diff:\n min_diff = diff\n closest_pair = (sorted_numbers[i], sorted_numbers[i + 1])\n \n # Return the closest pair in order\n return closest_pair", "matching_cluster_idx": 8}]}, "HumanEval/24": {"dps": 47.75510204081633, "dps_norm": 30.0, "pass@1": 100.0, "profiled": [{"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n if n <= 1:\n return None # No valid divisor for n <= 1\n \n for i in range(n - 1, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 0}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n if n <= 1:\n return None # No valid divisor for n <= 1\n \n for i in range(n - 1, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 0}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n if n <= 1:\n return None # No valid divisor for n <= 1\n \n for i in range(n // 2, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 4}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n if n <= 1:\n return None # No valid divisor for n <= 1\n \n for i in range(n - 1, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 0}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n if n <= 1:\n return None # No valid divisor for n <= 1\n \n for i in range(n // 2, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 4}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n if n <= 1:\n return None # No valid divisor for n <= 1\n \n for i in range(n - 1, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 0}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n if n <= 1:\n return None # No valid divisor for n <= 1\n \n for i in range(n - 1, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 0}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n if n <= 1:\n return None # No valid divisor for n <= 1\n \n for i in range(n // 2, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 4}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n if n <= 1:\n return None # No valid divisor for n <= 1\n \n for i in range(n // 2, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 4}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n if n <= 1:\n return None # No valid divisor for n <= 1\n \n for i in range(n - 1, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 0}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n if n <= 1:\n return None # No valid divisor for n <= 1\n \n for i in range(n - 1, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 0}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n if n <= 1:\n return None # No valid divisor for n <= 1\n \n for i in range(n - 1, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 0}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n if n <= 1:\n return None # No valid divisor for n <= 1\n \n for i in range(n - 1, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 0}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n if n <= 1:\n return None # No valid divisor for n <= 1\n \n for i in range(n // 2, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 4}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n if n <= 1:\n return None # No valid divisor for n <= 1\n \n for i in range(n - 1, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 0}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n if n <= 1:\n return None # No valid divisor for n <= 1\n \n for i in range(n - 1, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 0}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n if n <= 1:\n return None # No valid divisor for n <= 1\n \n for i in range(n - 1, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 0}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n if n <= 1:\n return None # No valid divisor for n <= 1\n \n for i in range(n - 1, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 0}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n if n <= 1:\n return None # No valid divisor for n <= 1\n \n for i in range(n // 2, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 4}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n if n <= 1:\n return None # No valid divisor for n <= 1\n \n for i in range(n // 2, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 4}]}, "HumanEval/26": {"dps": 24.0, "dps_norm": 25.0, "pass@1": 100.0, "profiled": [{"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n seen = set()\n result = []\n \n for num in numbers:\n if numbers.count(num) == 1:\n result.append(num)\n else:\n seen.add(num)\n \n return result", "matching_cluster_idx": 0}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n seen = set()\n result = []\n \n for num in numbers:\n if numbers.count(num) == 1:\n result.append(num)\n else:\n seen.add(num)\n \n return result", "matching_cluster_idx": 0}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n seen = set()\n result = []\n \n for num in numbers:\n if numbers.count(num) == 1:\n result.append(num)\n else:\n seen.add(num)\n \n return result", "matching_cluster_idx": 0}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n seen = set()\n result = []\n \n for num in numbers:\n if numbers.count(num) == 1:\n result.append(num)\n else:\n seen.add(num)\n \n return result", "matching_cluster_idx": 0}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n seen = set()\n result = []\n \n for num in numbers:\n if numbers.count(num) == 1:\n result.append(num)\n else:\n seen.add(num)\n \n return result", "matching_cluster_idx": 0}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n seen = set()\n result = []\n \n for num in numbers:\n if numbers.count(num) == 1:\n result.append(num)\n else:\n seen.add(num)\n \n return result", "matching_cluster_idx": 0}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n seen = set()\n result = []\n \n for num in numbers:\n if numbers.count(num) == 1:\n result.append(num)\n else:\n seen.add(num)\n \n return result", "matching_cluster_idx": 0}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n seen = set()\n result = []\n \n for num in numbers:\n if numbers.count(num) == 1:\n result.append(num)\n else:\n seen.add(num)\n \n return result", "matching_cluster_idx": 0}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n seen = set()\n result = []\n \n for num in numbers:\n if numbers.count(num) == 1:\n result.append(num)\n else:\n seen.add(num)\n \n return result", "matching_cluster_idx": 0}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n seen = set()\n result = []\n \n for num in numbers:\n if numbers.count(num) == 1:\n result.append(num)\n else:\n seen.add(num)\n \n return result", "matching_cluster_idx": 0}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n seen = set()\n result = []\n \n for num in numbers:\n if numbers.count(num) == 1:\n result.append(num)\n else:\n seen.add(num)\n \n return result", "matching_cluster_idx": 0}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n seen = set()\n result = []\n \n for num in numbers:\n if numbers.count(num) == 1:\n result.append(num)\n else:\n seen.add(num)\n \n return result", "matching_cluster_idx": 0}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n seen = set()\n result = []\n \n for num in numbers:\n if numbers.count(num) == 1:\n result.append(num)\n else:\n seen.add(num)\n \n return result", "matching_cluster_idx": 0}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n seen = set()\n result = []\n \n for num in numbers:\n if numbers.count(num) == 1:\n result.append(num)\n elif num not in seen:\n seen.add(num)\n \n return result", "matching_cluster_idx": 0}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n seen = set()\n result = []\n \n for num in numbers:\n if numbers.count(num) == 1:\n result.append(num)\n else:\n seen.add(num)\n \n return result", "matching_cluster_idx": 0}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n seen = set()\n result = []\n \n for num in numbers:\n if numbers.count(num) == 1:\n result.append(num)\n else:\n seen.add(num)\n \n return result", "matching_cluster_idx": 0}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n seen = set()\n result = []\n \n for num in numbers:\n if numbers.count(num) == 1:\n result.append(num)\n else:\n seen.add(num)\n \n return result", "matching_cluster_idx": 0}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n seen = set()\n result = []\n \n for num in numbers:\n if numbers.count(num) == 1:\n result.append(num)\n else:\n seen.add(num)\n \n return result", "matching_cluster_idx": 0}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n seen = set()\n result = []\n \n for num in numbers:\n if numbers.count(num) == 1:\n result.append(num)\n else:\n seen.add(num)\n \n return result", "matching_cluster_idx": 0}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n seen = set()\n result = []\n \n for num in numbers:\n if numbers.count(num) == 1:\n result.append(num)\n else:\n seen.add(num)\n \n return result", "matching_cluster_idx": 0}]}, "HumanEval/31": {"dps": 97.46835443037975, "dps_norm": 87.5, "pass@1": 100.0, "profiled": [{"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n if n == 2:\n return True\n if n % 2 == 0:\n return False\n for i in range(3, int(n**0.5) + 1, 2):\n if n % i == 0:\n return False\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n if n == 2:\n return True\n if n % 2 == 0:\n return False\n for i in range(3, int(n**0.5) + 1, 2):\n if n % i == 0:\n return False\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n if n == 2:\n return True\n if n % 2 == 0:\n return False\n for i in range(3, int(n**0.5) + 1, 2):\n if n % i == 0:\n return False\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n if n == 2:\n return True\n if n % 2 == 0:\n return False\n for i in range(3, int(n**0.5) + 1, 2):\n if n % i == 0:\n return False\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n if n == 2:\n return True\n if n % 2 == 0:\n return False\n for i in range(3, int(n**0.5) + 1, 2):\n if n % i == 0:\n return False\n return True", "matching_cluster_idx": 6}, {"solution": "import math\ndef is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n if n == 2:\n return True\n if n % 2 == 0:\n return False\n for i in range(3, int(math.sqrt(n)) + 1, 2):\n if n % i == 0:\n return False\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n if n == 2:\n return True\n if n % 2 == 0:\n return False\n for i in range(3, int(n**0.5) + 1, 2):\n if n % i == 0:\n return False\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n if n == 2:\n return True\n if n % 2 == 0:\n return False\n for i in range(3, int(n**0.5) + 1, 2):\n if n % i == 0:\n return False\n return True", "matching_cluster_idx": 6}, {"solution": "import math\ndef is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n if n == 2:\n return True\n if n % 2 == 0:\n return False\n for i in range(3, int(math.sqrt(n)) + 1, 2):\n if n % i == 0:\n return False\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n if n == 2:\n return True\n if n % 2 == 0:\n return False\n for i in range(3, int(n**0.5) + 1, 2):\n if n % i == 0:\n return False\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n if n == 2:\n return True\n if n % 2 == 0:\n return False\n for i in range(3, int(n**0.5) + 1, 2):\n if n % i == 0:\n return False\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n if n == 2:\n return True\n if n % 2 == 0:\n return False\n for i in range(3, int(n**0.5) + 1, 2):\n if n % i == 0:\n return False\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n if n == 2:\n return True\n if n % 2 == 0:\n return False\n for i in range(3, int(n**0.5) + 1, 2):\n if n % i == 0:\n return False\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n if n == 2:\n return True\n if n % 2 == 0:\n return False\n for i in range(3, int(n**0.5) + 1, 2):\n if n % i == 0:\n return False\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n if n == 2:\n return True\n if n % 2 == 0:\n return False\n for i in range(3, int(n**0.5) + 1, 2):\n if n % i == 0:\n return False\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n if n == 2:\n return True\n if n % 2 == 0:\n return False\n for i in range(3, int(n**0.5) + 1, 2):\n if n % i == 0:\n return False\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n if n == 2:\n return True\n if n % 2 == 0:\n return False\n for i in range(3, int(n**0.5) + 1, 2):\n if n % i == 0:\n return False\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n if n == 2:\n return True\n if n % 2 == 0:\n return False\n for i in range(3, int(n**0.5) + 1, 2):\n if n % i == 0:\n return False\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n if n == 2:\n return True\n if n % 2 == 0:\n return False\n for i in range(3, int(n**0.5) + 1, 2):\n if n % i == 0:\n return False\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n if n == 2:\n return True\n if n % 2 == 0:\n return False\n for i in range(3, int(n**0.5) + 1, 2):\n if n % i == 0:\n return False\n return True", "matching_cluster_idx": 6}]}, "HumanEval/33": {"dps": 97.22222222222223, "dps_norm": 81.81818181818181, "pass@1": 100.0, "profiled": [{"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n # Extract elements at indices divisible by 3 and sort them\n indices_div_by_three = [l[i] for i in range(0, len(l), 3)]\n sorted_indices_div_by_three = sorted(indices_div_by_three)\n \n # Create a new list with sorted elements at indices divisible by 3\n result = l[:]\n for i, value in zip(range(0, len(l), 3), sorted_indices_div_by_three):\n result[i] = value\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n # Extract elements at indices divisible by 3\n elements_to_sort = [l[i] for i in range(len(l)) if i % 3 == 0]\n \n # Sort the extracted elements\n sorted_elements = sorted(elements_to_sort)\n \n # Create a new list with sorted elements at indices divisible by 3\n result = l[:]\n for i, value in enumerate(sorted_elements):\n result[i * 3] = value\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n # Extract elements at indices divisible by 3\n indices_div_by_three = [l[i] for i in range(0, len(l), 3)]\n \n # Sort these elements\n sorted_indices_div_by_three = sorted(indices_div_by_three)\n \n # Create a new list with sorted elements at indices divisible by 3\n result = l[:]\n for i, value in zip(range(0, len(l), 3), sorted_indices_div_by_three):\n result[i] = value\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n # Extract elements at indices divisible by 3 and sort them\n to_sort = [l[i] for i in range(len(l)) if i % 3 == 0]\n sorted_elements = sorted(to_sort)\n \n # Create a new list with sorted elements at indices divisible by 3\n result = l[:]\n sorted_index = 0\n for i in range(len(l)):\n if i % 3 == 0:\n result[i] = sorted_elements[sorted_index]\n sorted_index += 1\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n # Extract elements at indices divisible by 3 and sort them\n indices_div_by_three = [l[i] for i in range(0, len(l), 3)]\n sorted_indices_div_by_three = sorted(indices_div_by_three)\n \n # Create a new list with sorted elements at indices divisible by 3\n result = l[:]\n for i, value in zip(range(0, len(l), 3), sorted_indices_div_by_three):\n result[i] = value\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n # Extract elements at indices divisible by 3 and sort them\n to_sort = [l[i] for i in range(len(l)) if i % 3 == 0]\n sorted_elements = sorted(to_sort)\n \n # Create a new list with sorted elements at indices divisible by 3\n result = l[:]\n sorted_index = 0\n for i in range(len(l)):\n if i % 3 == 0:\n result[i] = sorted_elements[sorted_index]\n sorted_index += 1\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n # Extract elements at indices divisible by 3 and sort them\n to_sort = sorted([l[i] for i in range(0, len(l), 3)])\n \n # Create a new list with sorted elements at indices divisible by 3\n result = l[:]\n for i, value in zip(range(0, len(l), 3), to_sort):\n result[i] = value\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n # Extract elements at indices divisible by 3 and sort them\n to_sort = sorted([l[i] for i in range(len(l)) if i % 3 == 0])\n \n # Create a new list with sorted elements at indices divisible by 3\n result = []\n sort_index = 0\n for i in range(len(l)):\n if i % 3 == 0:\n result.append(to_sort[sort_index])\n sort_index += 1\n else:\n result.append(l[i])\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n # Extract elements at indices divisible by 3 and sort them\n indices_div_by_3 = [l[i] for i in range(0, len(l), 3)]\n sorted_indices_div_by_3 = sorted(indices_div_by_3)\n \n # Create a new list with sorted elements at indices divisible by 3\n result = l[:]\n for i, value in zip(range(0, len(l), 3), sorted_indices_div_by_3):\n result[i] = value\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n # Extract elements at indices divisible by 3 and sort them\n to_sort = sorted([l[i] for i in range(len(l)) if i % 3 == 0])\n \n # Create a new list with sorted elements at indices divisible by 3\n result = []\n sort_index = 0\n for i in range(len(l)):\n if i % 3 == 0:\n result.append(to_sort[sort_index])\n sort_index += 1\n else:\n result.append(l[i])\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n # Extract elements at indices divisible by 3\n to_sort = [l[i] for i in range(len(l)) if i % 3 == 0]\n \n # Sort the extracted elements\n to_sort.sort()\n \n # Create a new list with sorted elements at indices divisible by 3\n result = l[:]\n for i, value in enumerate(to_sort):\n result[i * 3] = value\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n # Extract elements at indices divisible by 3\n elements_to_sort = [l[i] for i in range(len(l)) if i % 3 == 0]\n \n # Sort the extracted elements\n sorted_elements = sorted(elements_to_sort)\n \n # Create a new list with sorted elements at indices divisible by 3\n result = l[:]\n sorted_index = 0\n for i in range(len(l)):\n if i % 3 == 0:\n result[i] = sorted_elements[sorted_index]\n sorted_index += 1\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n if len(l) < 3:\n return l\n \n # Extract elements at indices divisible by 3 and sort them\n indices_div_by_three = [l[i] for i in range(0, len(l), 3)]\n sorted_indices_div_by_three = sorted(indices_div_by_three)\n \n # Create a new list with sorted elements at indices divisible by 3\n result = l[:]\n for i, value in zip(range(0, len(l), 3), sorted_indices_div_by_three):\n result[i] = value\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n # Extract elements at indices divisible by 3\n elements_to_sort = [l[i] for i in range(len(l)) if i % 3 == 0]\n \n # Sort the extracted elements\n sorted_elements = sorted(elements_to_sort)\n \n # Create a new list with sorted elements at indices divisible by 3\n result = l[:]\n sorted_index = 0\n for i in range(len(l)):\n if i % 3 == 0:\n result[i] = sorted_elements[sorted_index]\n sorted_index += 1\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n # Extract elements at indices divisible by 3\n to_sort = [l[i] for i in range(len(l)) if i % 3 == 0]\n \n # Sort the extracted elements\n sorted_elements = sorted(to_sort)\n \n # Create a new list with sorted elements at indices divisible by 3\n result = l[:]\n sorted_index = 0\n for i in range(len(l)):\n if i % 3 == 0:\n result[i] = sorted_elements[sorted_index]\n sorted_index += 1\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n # Extract elements at indices divisible by 3 and sort them\n to_sort = sorted([l[i] for i in range(len(l)) if i % 3 == 0])\n \n # Create a new list with sorted elements at indices divisible by 3\n result = []\n sort_index = 0\n for i in range(len(l)):\n if i % 3 == 0:\n result.append(to_sort[sort_index])\n sort_index += 1\n else:\n result.append(l[i])\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n # Extract elements at indices divisible by 3 and sort them\n to_sort = [l[i] for i in range(len(l)) if i % 3 == 0]\n sorted_elements = sorted(to_sort)\n \n # Create a new list with sorted elements at indices divisible by 3\n result = l[:]\n sorted_index = 0\n for i in range(len(l)):\n if i % 3 == 0:\n result[i] = sorted_elements[sorted_index]\n sorted_index += 1\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n # Extract elements at indices divisible by 3 and sort them\n indices_div_by_3 = [l[i] for i in range(0, len(l), 3)]\n sorted_indices_div_by_3 = sorted(indices_div_by_3)\n \n # Create a new list with sorted elements at indices divisible by 3\n result = l[:]\n for i, value in zip(range(0, len(l), 3), sorted_indices_div_by_3):\n result[i] = value\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n # Extract elements at indices divisible by 3 and sort them\n to_sort = sorted([l[i] for i in range(0, len(l), 3)])\n \n # Create a new list with sorted elements at indices divisible by 3\n result = l[:]\n for i, value in zip(range(0, len(l), 3), to_sort):\n result[i] = value\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n # Extract elements at indices divisible by 3\n elements_to_sort = [l[i] for i in range(len(l)) if i % 3 == 0]\n \n # Sort the extracted elements\n sorted_elements = sorted(elements_to_sort)\n \n # Create a new list with sorted elements at indices divisible by 3\n result = l[:]\n sorted_index = 0\n for i in range(len(l)):\n if i % 3 == 0:\n result[i] = sorted_elements[sorted_index]\n sorted_index += 1\n \n return result", "matching_cluster_idx": 8}]}, "HumanEval/34": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}]}, "HumanEval/36": {"dps": 96.77419354838709, "dps_norm": 71.42857142857143, "pass@1": 100.0, "profiled": [{"solution": "def count_sevens(number: int) -> int:\n \"\"\"Count the number of times the digit 7 appears in the given number.\"\"\"\n return str(number).count('7')\ndef fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n \n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n for i in range(1, n):\n if i % 11 == 0 or i % 13 == 0:\n count += count_sevens(i)\n return count", "matching_cluster_idx": 4}, {"solution": "def count_digit_7(number: int) -> int:\n \"\"\"Count the number of times the digit 7 appears in a given number.\"\"\"\n return str(number).count('7')\ndef fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += count_digit_7(i)\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def count_digit_7(number: int) -> int:\n \"\"\"Count the number of times the digit 7 appears in the given number.\"\"\"\n return str(number).count('7')\ndef fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n for i in range(1, n):\n if i % 11 == 0 or i % 13 == 0:\n count += count_digit_7(i)\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def count_digit_7(number: int) -> int:\n \"\"\"Count the number of times the digit 7 appears in the given number.\"\"\"\n return str(number).count('7')\ndef fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += count_digit_7(i)\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def count_digit_7(number: int) -> int:\n \"\"\"Count the number of times the digit 7 appears in a given number.\"\"\"\n return str(number).count('7')\ndef fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += count_digit_7(i)\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def count_sevens(number: int) -> int:\n \"\"\"Count the number of times the digit 7 appears in the given number.\"\"\"\n return str(number).count('7')\ndef fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += count_sevens(i)\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def count_sevens(number: int) -> int:\n \"\"\"Count the number of times the digit 7 appears in the given number.\"\"\"\n return str(number).count('7')\ndef fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += count_sevens(i)\n return count", "matching_cluster_idx": 4}, {"solution": "def count_digit_7(number: int) -> int:\n \"\"\"Count the number of times the digit 7 appears in a given number.\"\"\"\n return str(number).count('7')\ndef fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += count_digit_7(i)\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}]}, "HumanEval/37": {"dps": 94.92635024549918, "dps_norm": 90.0, "pass@1": 100.0, "profiled": [{"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indices, while its values at the even indices are equal\n to the values of the even indices of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Extract even-indexed elements and sort them\n even_elements = sorted([l[i] for i in range(0, len(l), 2)])\n \n # Create a new list with sorted even-indexed elements and original odd-indexed elements\n result = []\n for i in range(len(l)):\n if i % 2 == 0:\n result.append(even_elements.pop(0))\n else:\n result.append(l[i])\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indices, while its values at the even indices are equal\n to the values of the even indices of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Extract even-indexed elements and sort them\n even_elements = sorted([l[i] for i in range(0, len(l), 2)])\n \n # Create a new list with sorted even-indexed elements and original odd-indexed elements\n result = []\n for i in range(len(l)):\n if i % 2 == 0:\n result.append(even_elements.pop(0))\n else:\n result.append(l[i])\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Extract even-indexed elements and sort them\n even_elements = sorted([l[i] for i in range(0, len(l), 2)])\n \n # Create a new list with sorted even-indexed elements and original odd-indexed elements\n result = []\n for i in range(len(l)):\n if i % 2 == 0:\n result.append(even_elements.pop(0))\n else:\n result.append(l[i])\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Extract even-indexed elements and sort them\n even_elements = sorted([l[i] for i in range(0, len(l), 2)])\n \n # Create a new list with sorted even-indexed elements and original odd-indexed elements\n result = []\n even_index = 0\n for i in range(len(l)):\n if i % 2 == 0:\n result.append(even_elements[even_index])\n even_index += 1\n else:\n result.append(l[i])\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indices, while its values at the even indices are equal\n to the values of the even indices of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Extract even-indexed elements and sort them\n even_elements = sorted([l[i] for i in range(0, len(l), 2)])\n \n # Create a new list with sorted even-indexed elements and original odd-indexed elements\n result = []\n for i in range(len(l)):\n if i % 2 == 0:\n result.append(even_elements.pop(0))\n else:\n result.append(l[i])\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Extract even-indexed elements and sort them\n even_elements = sorted([l[i] for i in range(0, len(l), 2)])\n \n # Create a new list with sorted even-indexed elements and original odd-indexed elements\n result = []\n even_index = 0\n for i in range(len(l)):\n if i % 2 == 0:\n result.append(even_elements[even_index])\n even_index += 1\n else:\n result.append(l[i])\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indices, while its values at the even indices are equal\n to the values of the even indices of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Extract even-indexed elements and sort them\n even_elements = sorted([l[i] for i in range(0, len(l), 2)])\n \n # Create a new list with sorted even-indexed elements and original odd-indexed elements\n result = []\n for i in range(len(l)):\n if i % 2 == 0:\n result.append(even_elements.pop(0))\n else:\n result.append(l[i])\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indices, while its values at the even indices are equal\n to the values of the even indices of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Extract even-indexed elements and sort them\n even_elements = sorted([l[i] for i in range(0, len(l), 2)])\n \n # Create a new list with sorted even-indexed elements and original odd-indexed elements\n result = []\n for i in range(len(l)):\n if i % 2 == 0:\n result.append(even_elements.pop(0))\n else:\n result.append(l[i])\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Extract even-indexed elements and sort them\n even_elements = sorted([l[i] for i in range(0, len(l), 2)])\n \n # Create a new list with sorted even-indexed elements and original odd-indexed elements\n result = []\n for i in range(len(l)):\n if i % 2 == 0:\n result.append(even_elements.pop(0))\n else:\n result.append(l[i])\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Extract even-indexed elements and sort them\n even_elements = sorted([l[i] for i in range(0, len(l), 2)])\n \n # Create a new list with sorted even-indexed elements and original odd-indexed elements\n result = []\n for i in range(len(l)):\n if i % 2 == 0:\n result.append(even_elements.pop(0))\n else:\n result.append(l[i])\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Extract even-indexed elements and sort them\n even_elements = sorted([l[i] for i in range(0, len(l), 2)])\n \n # Create a new list with sorted even-indexed elements and original odd-indexed elements\n result = []\n for i in range(len(l)):\n if i % 2 == 0:\n result.append(even_elements.pop(0))\n else:\n result.append(l[i])\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Extract even-indexed elements and sort them\n even_elements = sorted([l[i] for i in range(0, len(l), 2)])\n \n # Create a new list with sorted even-indexed elements and original odd-indexed elements\n result = []\n for i in range(len(l)):\n if i % 2 == 0:\n result.append(even_elements.pop(0))\n else:\n result.append(l[i])\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indices, while its values at the even indices are equal\n to the values of the even indices of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Extract even-indexed elements and sort them\n even_elements = sorted([l[i] for i in range(0, len(l), 2)])\n \n # Create a new list with sorted even-indexed elements and original odd-indexed elements\n result = []\n for i in range(len(l)):\n if i % 2 == 0:\n result.append(even_elements.pop(0))\n else:\n result.append(l[i])\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Extract even-indexed elements and sort them\n even_elements = sorted([l[i] for i in range(0, len(l), 2)])\n \n # Create a new list with sorted even-indexed elements and original odd-indexed elements\n result = []\n even_index = 0\n for i in range(len(l)):\n if i % 2 == 0:\n result.append(even_elements[even_index])\n even_index += 1\n else:\n result.append(l[i])\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Extract even-indexed elements and sort them\n even_elements = sorted([l[i] for i in range(0, len(l), 2)])\n \n # Create a new list with sorted even-indexed elements and original odd-indexed elements\n result = []\n for i in range(len(l)):\n if i % 2 == 0:\n result.append(even_elements.pop(0))\n else:\n result.append(l[i])\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Extract even-indexed elements and sort them\n even_elements = sorted([l[i] for i in range(0, len(l), 2)])\n \n # Create the new list with sorted even-indexed elements\n result = []\n for i in range(len(l)):\n if i % 2 == 0:\n result.append(even_elements.pop(0))\n else:\n result.append(l[i])\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Extract even-indexed elements and sort them\n even_elements = sorted([l[i] for i in range(0, len(l), 2)])\n \n # Create a new list with sorted even-indexed elements and original odd-indexed elements\n result = []\n for i in range(len(l)):\n if i % 2 == 0:\n result.append(even_elements.pop(0))\n else:\n result.append(l[i])\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Extract even-indexed elements and sort them\n even_elements = sorted([l[i] for i in range(0, len(l), 2)])\n \n # Create a new list with sorted even-indexed elements and original odd-indexed elements\n result = []\n for i in range(len(l)):\n if i % 2 == 0:\n result.append(even_elements.pop(0))\n else:\n result.append(l[i])\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indices, while its values at the even indices are equal\n to the values of the even indices of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Extract even-indexed elements and sort them\n even_elements = sorted([l[i] for i in range(0, len(l), 2)])\n \n # Create a new list with sorted even-indexed elements and original odd-indexed elements\n result = []\n for i in range(len(l)):\n if i % 2 == 0:\n result.append(even_elements.pop(0))\n else:\n result.append(l[i])\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indices, while its values at the even indices are equal\n to the values of the even indices of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Extract even-indexed elements and sort them\n even_elements = sorted([l[i] for i in range(0, len(l), 2)])\n \n # Create a new list with sorted even-indexed elements and original odd-indexed elements\n result = []\n for i in range(len(l)):\n if i % 2 == 0:\n result.append(even_elements.pop(0))\n else:\n result.append(l[i])\n \n return result", "matching_cluster_idx": 8}]}, "HumanEval/49": {"dps": null, "dps_norm": null, "pass@1": 0.0, "profiled": []}, "HumanEval/51": {"dps": 96.13526570048309, "dps_norm": 75.0, "pass@1": 100.0, "profiled": [{"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}]}, "HumanEval/54": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 19.0, "profiled": [{"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')\n True\n >>> same_chars('abcd', 'dddddddabc')\n True\n >>> same_chars('dddddddabc', 'abcd')\n True\n >>> same_chars('eabcd', 'dddddddabc')\n False\n >>> same_chars('abcd', 'dddddddabce')\n False\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')\n False\n \"\"\"\n # Convert both strings to sets of characters\n set0 = set(s0)\n set1 = set(s1)\n \n # Check if the sets are equal\n return set0 == set1", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')\n True\n >>> same_chars('abcd', 'dddddddabc')\n True\n >>> same_chars('dddddddabc', 'abcd')\n True\n >>> same_chars('eabcd', 'dddddddabc')\n False\n >>> same_chars('abcd', 'dddddddabce')\n False\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')\n False\n \"\"\"\n # Convert both strings to sets of characters\n set_s0 = set(s0)\n set_s1 = set(s1)\n \n # Check if the sets are equal\n return set_s0 == set_s1", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')\n True\n >>> same_chars('abcd', 'dddddddabc')\n True\n >>> same_chars('dddddddabc', 'abcd')\n True\n >>> same_chars('eabcd', 'dddddddabc')\n False\n >>> same_chars('abcd', 'dddddddabce')\n False\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')\n False\n \"\"\"\n # Convert both strings to sets of characters\n set0 = set(s0)\n set1 = set(s1)\n \n # Check if the sets are equal\n return set0 == set1", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')\n True\n >>> same_chars('abcd', 'dddddddabc')\n True\n >>> same_chars('dddddddabc', 'abcd')\n True\n >>> same_chars('eabcd', 'dddddddabc')\n False\n >>> same_chars('abcd', 'dddddddabce')\n False\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')\n False\n \"\"\"\n # Convert both strings to sets of characters\n set0 = set(s0)\n set1 = set(s1)\n \n # Check if the sets are equal\n return set0 == set1", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')\n True\n >>> same_chars('abcd', 'dddddddabc')\n True\n >>> same_chars('dddddddabc', 'abcd')\n True\n >>> same_chars('eabcd', 'dddddddabc')\n False\n >>> same_chars('abcd', 'dddddddabce')\n False\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')\n False\n \"\"\"\n # Convert both strings to sets of characters\n set0 = set(s0)\n set1 = set(s1)\n \n # Check if the sets are equal\n return set0 == set1", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')\n True\n >>> same_chars('abcd', 'dddddddabc')\n True\n >>> same_chars('dddddddabc', 'abcd')\n True\n >>> same_chars('eabcd', 'dddddddabc')\n False\n >>> same_chars('abcd', 'dddddddabce')\n False\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')\n False\n \"\"\"\n # Convert both strings to sets of characters\n set_s0 = set(s0)\n set_s1 = set(s1)\n \n # Check if the sets are equal\n return set_s0 == set_s1", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')\n True\n >>> same_chars('abcd', 'dddddddabc')\n True\n >>> same_chars('dddddddabc', 'abcd')\n True\n >>> same_chars('eabcd', 'dddddddabc')\n False\n >>> same_chars('abcd', 'dddddddabce')\n False\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')\n False\n \"\"\"\n # Convert both strings to sets of characters\n set0 = set(s0)\n set1 = set(s1)\n \n # Check if the sets are equal\n return set0 == set1", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')\n True\n >>> same_chars('abcd', 'dddddddabc')\n True\n >>> same_chars('dddddddabc', 'abcd')\n True\n >>> same_chars('eabcd', 'dddddddabc')\n False\n >>> same_chars('abcd', 'dddddddabce')\n False\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')\n False\n \"\"\"\n # Convert both strings to sets of characters\n set0 = set(s0)\n set1 = set(s1)\n \n # Check if the sets are equal\n return set0 == set1", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')\n True\n >>> same_chars('abcd', 'dddddddabc')\n True\n >>> same_chars('dddddddabc', 'abcd')\n True\n >>> same_chars('eabcd', 'dddddddabc')\n False\n >>> same_chars('abcd', 'dddddddabce')\n False\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')\n False\n \"\"\"\n # Convert both strings to sets of characters\n set0 = set(s0)\n set1 = set(s1)\n \n # Check if the sets are equal\n return set0 == set1", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')\n True\n >>> same_chars('abcd', 'dddddddabc')\n True\n >>> same_chars('dddddddabc', 'abcd')\n True\n >>> same_chars('eabcd', 'dddddddabc')\n False\n >>> same_chars('abcd', 'dddddddabce')\n False\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')\n False\n \"\"\"\n # Convert both strings to sets of characters\n set0 = set(s0)\n set1 = set(s1)\n \n # Check if the sets are equal\n return set0 == set1", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')\n True\n >>> same_chars('abcd', 'dddddddabc')\n True\n >>> same_chars('dddddddabc', 'abcd')\n True\n >>> same_chars('eabcd', 'dddddddabc')\n False\n >>> same_chars('abcd', 'dddddddabce')\n False\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')\n False\n \"\"\"\n # Convert both strings to sets of characters\n set0 = set(s0)\n set1 = set(s1)\n \n # Check if the sets are equal\n return set0 == set1", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')\n True\n >>> same_chars('abcd', 'dddddddabc')\n True\n >>> same_chars('dddddddabc', 'abcd')\n True\n >>> same_chars('eabcd', 'dddddddabc')\n False\n >>> same_chars('abcd', 'dddddddabce')\n False\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')\n False\n \"\"\"\n # Convert both strings to sets of characters\n set0 = set(s0)\n set1 = set(s1)\n \n # Check if the sets are equal\n return set0 == set1", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')\n True\n >>> same_chars('abcd', 'dddddddabc')\n True\n >>> same_chars('dddddddabc', 'abcd')\n True\n >>> same_chars('eabcd', 'dddddddabc')\n False\n >>> same_chars('abcd', 'dddddddabce')\n False\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')\n False\n \"\"\"\n # Convert both strings to sets of characters\n set_s0 = set(s0)\n set_s1 = set(s1)\n \n # Check if the sets are equal\n return set_s0 == set_s1", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')\n True\n >>> same_chars('abcd', 'dddddddabc')\n True\n >>> same_chars('dddddddabc', 'abcd')\n True\n >>> same_chars('eabcd', 'dddddddabc')\n False\n >>> same_chars('abcd', 'dddddddabce')\n False\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')\n False\n \"\"\"\n # Convert both strings to sets of characters\n set0 = set(s0)\n set1 = set(s1)\n \n # Check if the sets are equal\n return set0 == set1", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')\n True\n >>> same_chars('abcd', 'dddddddabc')\n True\n >>> same_chars('dddddddabc', 'abcd')\n True\n >>> same_chars('eabcd', 'dddddddabc')\n False\n >>> same_chars('abcd', 'dddddddabce')\n False\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')\n False\n \"\"\"\n # Convert both strings to sets of characters\n set0 = set(s0)\n set1 = set(s1)\n \n # Check if the sets are equal\n return set0 == set1", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')\n True\n >>> same_chars('abcd', 'dddddddabc')\n True\n >>> same_chars('dddddddabc', 'abcd')\n True\n >>> same_chars('eabcd', 'dddddddabc')\n False\n >>> same_chars('abcd', 'dddddddabce')\n False\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')\n False\n \"\"\"\n # Convert both strings to sets of characters\n set0 = set(s0)\n set1 = set(s1)\n \n # Check if the sets are equal\n return set0 == set1", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')\n True\n >>> same_chars('abcd', 'dddddddabc')\n True\n >>> same_chars('dddddddabc', 'abcd')\n True\n >>> same_chars('eabcd', 'dddddddabc')\n False\n >>> same_chars('abcd', 'dddddddabce')\n False\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')\n False\n \"\"\"\n # Convert both strings to sets of characters\n set_s0 = set(s0)\n set_s1 = set(s1)\n \n # Check if the sets are equal\n return set_s0 == set_s1", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')\n True\n >>> same_chars('abcd', 'dddddddabc')\n True\n >>> same_chars('dddddddabc', 'abcd')\n True\n >>> same_chars('eabcd', 'dddddddabc')\n False\n >>> same_chars('abcd', 'dddddddabce')\n False\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')\n False\n \"\"\"\n # Convert both strings to sets of characters\n set0 = set(s0)\n set1 = set(s1)\n \n # Check if the sets are equal\n return set0 == set1", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')\n True\n >>> same_chars('abcd', 'dddddddabc')\n True\n >>> same_chars('dddddddabc', 'abcd')\n True\n >>> same_chars('eabcd', 'dddddddabc')\n False\n >>> same_chars('abcd', 'dddddddabce')\n False\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')\n False\n \"\"\"\n # Convert both strings to sets of characters\n set0 = set(s0)\n set1 = set(s1)\n \n # Check if the sets are equal\n return set0 == set1", "matching_cluster_idx": 6}]}, "HumanEval/58": {"dps": 92.51968503937007, "dps_norm": 83.33333333333333, "pass@1": 100.0, "profiled": [{"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n # Convert both lists to sets to remove duplicates and find intersection\n common_elements = set(l1) & set(l2)\n # Convert the set back to a sorted list\n return sorted(common_elements)", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n # Convert lists to sets to find common elements\n common_elements = set(l1) & set(l2)\n # Convert the set back to a sorted list\n return sorted(common_elements)", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n \n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n # Convert lists to sets to find common elements\n common_elements = set(l1) & set(l2)\n # Convert the set back to a sorted list\n return sorted(common_elements)", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n \n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n # Convert lists to sets to find common elements\n common_elements = set(l1) & set(l2)\n # Convert the set back to a sorted list\n return sorted(common_elements)", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n # Convert lists to sets to find common elements\n common_elements = set(l1) & set(l2)\n # Convert the set back to a sorted list\n return sorted(common_elements)", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n # Convert lists to sets to find common elements\n common_elements = set(l1) & set(l2)\n # Convert the set back to a sorted list\n return sorted(common_elements)", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n # Convert lists to sets to find common elements\n common_elements = set(l1) & set(l2)\n # Convert the set back to a sorted list\n return sorted(common_elements)", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n # Convert lists to sets to get unique elements\n set1 = set(l1)\n set2 = set(l2)\n \n # Find common elements using intersection\n common_elements = set1.intersection(set2)\n \n # Convert the result back to a sorted list\n return sorted(common_elements)", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n # Convert lists to sets to find common elements\n common_elements = set(l1) & set(l2)\n # Convert the set back to a sorted list\n return sorted(common_elements)", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n # Convert lists to sets to get unique elements\n set1 = set(l1)\n set2 = set(l2)\n \n # Find common elements using intersection\n common_elements = set1.intersection(set2)\n \n # Convert the result back to a sorted list\n return sorted(common_elements)", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n # Convert lists to sets to find common elements\n common_elements = set(l1) & set(l2)\n # Convert the set back to a sorted list\n return sorted(common_elements)", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n # Convert lists to sets to get unique elements\n set1 = set(l1)\n set2 = set(l2)\n \n # Find common elements using intersection\n common_elements = set1.intersection(set2)\n \n # Convert the result back to a sorted list\n return sorted(common_elements)", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n # Convert lists to sets to get unique elements\n set1 = set(l1)\n set2 = set(l2)\n \n # Find common elements using intersection\n common_elements = set1.intersection(set2)\n \n # Convert the result back to a sorted list\n return sorted(common_elements)", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n # Convert lists to sets to find common elements\n common_elements = set(l1) & set(l2)\n # Convert the set back to a sorted list\n return sorted(common_elements)", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n # Convert lists to sets to find common elements\n common_elements = set(l1) & set(l2)\n # Convert the set back to a sorted list\n return sorted(common_elements)", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n # Convert lists to sets to get unique elements\n set1 = set(l1)\n set2 = set(l2)\n \n # Find common elements using intersection\n common_elements = set1.intersection(set2)\n \n # Convert the result back to a sorted list\n return sorted(common_elements)", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n # Convert lists to sets to find common elements\n common_elements = set(l1) & set(l2)\n # Convert the set back to a sorted list\n return sorted(common_elements)", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n # Convert lists to sets to get unique elements\n set1 = set(l1)\n set2 = set(l2)\n \n # Find common elements using intersection\n common_elements = set1.intersection(set2)\n \n # Convert the result back to a sorted list\n return sorted(common_elements)", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n # Convert lists to sets to find common elements\n common_elements = set(l1) & set(l2)\n # Convert the set back to a sorted list\n return sorted(common_elements)", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n # Convert both lists to sets to get unique elements\n set1 = set(l1)\n set2 = set(l2)\n \n # Find the intersection of the two sets\n common_elements = set1.intersection(set2)\n \n # Convert the result back to a sorted list\n return sorted(common_elements)", "matching_cluster_idx": 4}]}, "HumanEval/59": {"dps": 95.74652777777777, "dps_norm": 99.44444444444444, "pass@1": 100.0, "profiled": [{"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n def is_prime(num):\n if num <= 1:\n return False\n if num <= 3:\n return True\n if num % 2 == 0 or num % 3 == 0:\n return False\n i = 5\n while i * i <= num:\n if num % i == 0 or num % (i + 2) == 0:\n return False\n i += 6\n return True\n\n largest_factor = 1\n # Check for smallest factors first\n while n % 2 == 0:\n largest_factor = 2\n n //= 2\n\n # Check for odd factors from 3 upwards\n factor = 3\n while factor * factor <= n:\n while n % factor == 0:\n largest_factor = factor\n n //= factor\n factor += 2\n\n # If n is still greater than 1, then it is a prime factor\n if n > 1:\n largest_factor = n\n\n return largest_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n def is_prime(num: int) -> bool:\n \"\"\"Check if a number is prime.\"\"\"\n if num <= 1:\n return False\n if num <= 3:\n return True\n if num % 2 == 0 or num % 3 == 0:\n return False\n i = 5\n while i * i <= num:\n if num % i == 0 or num % (i + 2) == 0:\n return False\n i += 6\n return True\n\n largest_factor = 1\n # Check for the smallest factors first\n while n % 2 == 0:\n largest_factor = 2\n n //= 2\n\n # Check for odd factors from 3 upwards\n factor = 3\n while factor * factor <= n:\n while n % factor == 0:\n largest_factor = factor\n n //= factor\n factor += 2\n\n # If n is still greater than 1, then it must be prime\n if n > 1:\n largest_factor = n\n\n return largest_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n def is_prime(num):\n \"\"\"Check if a number is prime.\"\"\"\n if num <= 1:\n return False\n if num <= 3:\n return True\n if num % 2 == 0 or num % 3 == 0:\n return False\n i = 5\n while i * i <= num:\n if num % i == 0 or num % (i + 2) == 0:\n return False\n i += 6\n return True\n\n # Start with the smallest prime factor\n largest_factor = 1\n factor = 2\n\n # Divide n by 2 until it is odd\n while n % factor == 0:\n largest_factor = factor\n n //= factor\n\n # Now n must be odd, so we can skip even numbers\n factor = 3\n while factor * factor <= n:\n while n % factor == 0:\n largest_factor = factor\n n //= factor\n factor += 2\n\n # If n is still greater than 1, then it must be prime\n if n > 1:\n largest_factor = n\n\n return largest_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n def is_prime(num: int) -> bool:\n \"\"\"Check if a number is prime.\"\"\"\n if num <= 1:\n return False\n if num <= 3:\n return True\n if num % 2 == 0 or num % 3 == 0:\n return False\n i = 5\n while i * i <= num:\n if num % i == 0 or num % (i + 2) == 0:\n return False\n i += 6\n return True\n\n largest_factor = 1\n # Check for the smallest prime factor (2)\n while n % 2 == 0:\n largest_factor = 2\n n //= 2\n \n # Check for odd factors from 3 onwards\n factor = 3\n while factor * factor <= n:\n while n % factor == 0:\n largest_factor = factor\n n //= factor\n factor += 2\n \n # If n is still greater than 1, then it must be prime\n if n > 1:\n largest_factor = n\n \n return largest_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n def is_prime(num: int) -> bool:\n \"\"\"Helper function to check if a number is prime.\"\"\"\n if num <= 1:\n return False\n if num <= 3:\n return True\n if num % 2 == 0 or num % 3 == 0:\n return False\n i = 5\n while i * i <= num:\n if num % i == 0 or num % (i + 2) == 0:\n return False\n i += 6\n return True\n\n largest_factor = 1\n # Check for the smallest factors first\n while n % 2 == 0:\n largest_factor = 2\n n //= 2\n\n # Check for odd factors from 3 upwards\n factor = 3\n while factor * factor <= n:\n while n % factor == 0:\n largest_factor = factor\n n //= factor\n factor += 2\n\n # If n is still greater than 1, then it is a prime factor\n if n > 1:\n largest_factor = n\n\n return largest_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n def is_prime(num: int) -> bool:\n \"\"\"Check if a number is prime.\"\"\"\n if num <= 1:\n return False\n if num <= 3:\n return True\n if num % 2 == 0 or num % 3 == 0:\n return False\n i = 5\n while i * i <= num:\n if num % i == 0 or num % (i + 2) == 0:\n return False\n i += 6\n return True\n\n # Start with the smallest prime factor\n largest_factor = 1\n factor = 2\n\n # Check for smallest factors first\n while n % factor == 0:\n largest_factor = factor\n n //= factor\n\n factor = 3\n while factor * factor <= n:\n while n % factor == 0:\n largest_factor = factor\n n //= factor\n factor += 2\n\n # If n is still greater than 1, then it is a prime factor\n if n > 1:\n largest_factor = n\n\n return largest_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n def is_prime(num: int) -> bool:\n \"\"\"Check if a number is prime.\"\"\"\n if num <= 1:\n return False\n if num <= 3:\n return True\n if num % 2 == 0 or num % 3 == 0:\n return False\n i = 5\n while i * i <= num:\n if num % i == 0 or num % (i + 2) == 0:\n return False\n i += 6\n return True\n\n largest_factor = 1\n # Check for the smallest factors first\n while n % 2 == 0:\n largest_factor = 2\n n //= 2\n\n # Check for odd factors from 3 upwards\n factor = 3\n while factor * factor <= n:\n while n % factor == 0:\n largest_factor = factor\n n //= factor\n factor += 2\n\n # If n is still greater than 1, then it must be prime\n if n > 1:\n largest_factor = n\n\n return largest_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n def is_prime(num):\n if num <= 1:\n return False\n if num <= 3:\n return True\n if num % 2 == 0 or num % 3 == 0:\n return False\n i = 5\n while i * i <= num:\n if num % i == 0 or num % (i + 2) == 0:\n return False\n i += 6\n return True\n\n largest_factor = 1\n # Check for smallest prime factor (2)\n while n % 2 == 0:\n largest_factor = 2\n n //= 2\n \n # Check for odd factors from 3 onwards\n factor = 3\n while factor * factor <= n:\n while n % factor == 0:\n largest_factor = factor\n n //= factor\n factor += 2\n \n # If n is still greater than 1, then it is a prime factor\n if n > 1:\n largest_factor = n\n \n return largest_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n def is_prime(num: int) -> bool:\n \"\"\"Check if a number is prime.\"\"\"\n if num <= 1:\n return False\n if num <= 3:\n return True\n if num % 2 == 0 or num % 3 == 0:\n return False\n i = 5\n while i * i <= num:\n if num % i == 0 or num % (i + 2) == 0:\n return False\n i += 6\n return True\n\n largest_factor = 1\n # Check for the smallest factors first\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n if is_prime(i):\n largest_factor = i\n if is_prime(n // i):\n largest_factor = n // i\n break\n return largest_factor", "matching_cluster_idx": 7}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n def is_prime(num: int) -> bool:\n \"\"\"Check if a number is prime.\"\"\"\n if num <= 1:\n return False\n if num <= 3:\n return True\n if num % 2 == 0 or num % 3 == 0:\n return False\n i = 5\n while i * i <= num:\n if num % i == 0 or num % (i + 2) == 0:\n return False\n i += 6\n return True\n\n largest_factor = 1\n # Check for smallest factors first\n if n % 2 == 0:\n largest_factor = 2\n while n % 2 == 0:\n n //= 2\n \n # Check for odd factors\n factor = 3\n while factor * factor <= n:\n if n % factor == 0:\n if is_prime(factor):\n largest_factor = factor\n while n % factor == 0:\n n //= factor\n factor += 2\n \n # If n is still greater than 1, then it is a prime factor\n if n > 1:\n largest_factor = n\n \n return largest_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n def is_prime(num):\n if num <= 1:\n return False\n if num <= 3:\n return True\n if num % 2 == 0 or num % 3 == 0:\n return False\n i = 5\n while i * i <= num:\n if num % i == 0 or num % (i + 2) == 0:\n return False\n i += 6\n return True\n\n largest_factor = 1\n # Check for the smallest factors first\n while n % 2 == 0:\n largest_factor = 2\n n //= 2\n\n # Check for odd factors from 3 upwards\n factor = 3\n while factor * factor <= n:\n while n % factor == 0:\n largest_factor = factor\n n //= factor\n factor += 2\n\n # If n is still greater than 1, then it is a prime factor\n if n > 1:\n largest_factor = n\n\n return largest_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n def is_prime(num: int) -> bool:\n \"\"\"Check if a number is prime.\"\"\"\n if num <= 1:\n return False\n if num <= 3:\n return True\n if num % 2 == 0 or num % 3 == 0:\n return False\n i = 5\n while i * i <= num:\n if num % i == 0 or num % (i + 2) == 0:\n return False\n i += 6\n return True\n\n largest_factor = 1\n # Check for the smallest factors first\n if n % 2 == 0:\n largest_factor = 2\n while n % 2 == 0:\n n //= 2\n \n # Check for odd factors from 3 upwards\n factor = 3\n while n > 1:\n if n % factor == 0:\n largest_factor = factor\n while n % factor == 0:\n n //= factor\n factor += 2\n # If factor^2 exceeds n, then n must be prime\n if factor * factor > n:\n if n > 1:\n largest_factor = n\n break\n \n return largest_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n def is_prime(num: int) -> bool:\n \"\"\"Check if a number is prime.\"\"\"\n if num <= 1:\n return False\n if num <= 3:\n return True\n if num % 2 == 0 or num % 3 == 0:\n return False\n i = 5\n while i * i <= num:\n if num % i == 0 or num % (i + 2) == 0:\n return False\n i += 6\n return True\n\n largest_factor = 1\n # Check for the smallest factors first\n if n % 2 == 0:\n largest_factor = 2\n while n % 2 == 0:\n n //= 2\n\n # Check for odd factors from 3 upwards\n factor = 3\n while n > 1:\n if n % factor == 0:\n largest_factor = factor\n while n % factor == 0:\n n //= factor\n factor += 2\n # If factor^2 exceeds n, then n must be prime\n if factor * factor > n:\n if n > 1:\n largest_factor = n\n break\n\n return largest_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n def is_prime(num: int) -> bool:\n \"\"\"Check if a number is prime.\"\"\"\n if num <= 1:\n return False\n if num <= 3:\n return True\n if num % 2 == 0 or num % 3 == 0:\n return False\n i = 5\n while i * i <= num:\n if num % i == 0 or num % (i + 2) == 0:\n return False\n i += 6\n return True\n\n largest_factor = 1\n # Check for smallest factors first\n if n % 2 == 0:\n largest_factor = 2\n while n % 2 == 0:\n n //= 2\n\n # Check for odd factors from 3 upwards\n factor = 3\n while n > 1:\n if n % factor == 0:\n largest_factor = factor\n while n % factor == 0:\n n //= factor\n factor += 2\n # If factor^2 exceeds n, then n must be prime\n if factor * factor > n:\n if n > 1:\n largest_factor = n\n break\n\n return largest_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n def is_prime(num: int) -> bool:\n \"\"\"Check if a number is prime.\"\"\"\n if num <= 1:\n return False\n if num <= 3:\n return True\n if num % 2 == 0 or num % 3 == 0:\n return False\n i = 5\n while i * i <= num:\n if num % i == 0 or num % (i + 2) == 0:\n return False\n i += 6\n return True\n\n largest_factor = 1\n # Check for the smallest factors first\n if n % 2 == 0:\n largest_factor = 2\n while n % 2 == 0:\n n //= 2\n \n # Check for odd factors from 3 onwards\n factor = 3\n while factor * factor <= n:\n if n % factor == 0:\n if is_prime(factor):\n largest_factor = factor\n while n % factor == 0:\n n //= factor\n factor += 2\n \n # If n is still greater than 1, then it is a prime factor\n if n > 1:\n largest_factor = n\n \n return largest_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n def is_prime(num: int) -> bool:\n \"\"\"Helper function to check if a number is prime.\"\"\"\n if num <= 1:\n return False\n if num <= 3:\n return True\n if num % 2 == 0 or num % 3 == 0:\n return False\n i = 5\n while i * i <= num:\n if num % i == 0 or num % (i + 2) == 0:\n return False\n i += 6\n return True\n\n largest_factor = 1\n # Check for the smallest factors first\n if n % 2 == 0:\n largest_factor = 2\n while n % 2 == 0:\n n //= 2\n \n # Check for odd factors from 3 upwards\n factor = 3\n while n > 1:\n if n % factor == 0:\n largest_factor = factor\n while n % factor == 0:\n n //= factor\n factor += 2\n # If the factor squared is greater than n, then n must be prime\n if factor * factor > n:\n if n > 1:\n largest_factor = n\n break\n \n return largest_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n def is_prime(num: int) -> bool:\n \"\"\"Check if a number is prime.\"\"\"\n if num <= 1:\n return False\n if num <= 3:\n return True\n if num % 2 == 0 or num % 3 == 0:\n return False\n i = 5\n while i * i <= num:\n if num % i == 0 or num % (i + 2) == 0:\n return False\n i += 6\n return True\n\n largest_factor = 1\n # Check for smallest factors first\n if n % 2 == 0:\n largest_factor = 2\n while n % 2 == 0:\n n //= 2\n \n # Check for odd factors\n factor = 3\n while n > 1:\n if n % factor == 0:\n largest_factor = factor\n while n % factor == 0:\n n //= factor\n factor += 2\n # If factor squared is greater than n, then n must be prime\n if factor * factor > n:\n if n > 1:\n largest_factor = n\n break\n \n return largest_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n def is_prime(num: int) -> bool:\n \"\"\"Check if a number is prime.\"\"\"\n if num <= 1:\n return False\n if num <= 3:\n return True\n if num % 2 == 0 or num % 3 == 0:\n return False\n i = 5\n while i * i <= num:\n if num % i == 0 or num % (i + 2) == 0:\n return False\n i += 6\n return True\n\n largest_factor = 1\n # Check for the smallest factors first\n while n % 2 == 0:\n largest_factor = 2\n n //= 2\n\n # Check for odd factors from 3 upwards\n factor = 3\n while factor * factor <= n:\n while n % factor == 0:\n largest_factor = factor\n n //= factor\n factor += 2\n\n # If n is still greater than 1, then it must be prime\n if n > 1:\n largest_factor = n\n\n return largest_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n def is_prime(num: int) -> bool:\n \"\"\"Check if a number is prime.\"\"\"\n if num <= 1:\n return False\n if num <= 3:\n return True\n if num % 2 == 0 or num % 3 == 0:\n return False\n i = 5\n while i * i <= num:\n if num % i == 0 or num % (i + 2) == 0:\n return False\n i += 6\n return True\n\n largest_factor = 1\n # Check for smallest factors first\n if n % 2 == 0:\n largest_factor = 2\n while n % 2 == 0:\n n //= 2\n \n # Check for odd factors\n factor = 3\n while n > 1:\n if n % factor == 0:\n largest_factor = factor\n while n % factor == 0:\n n //= factor\n factor += 2\n # If factor^2 exceeds n, then n must be prime\n if factor * factor > n:\n if n > 1:\n largest_factor = n\n break\n \n return largest_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n def is_prime(num):\n if num <= 1:\n return False\n if num <= 3:\n return True\n if num % 2 == 0 or num % 3 == 0:\n return False\n i = 5\n while i * i <= num:\n if num % i == 0 or num % (i + 2) == 0:\n return False\n i += 6\n return True\n\n largest_factor = 1\n # Check for the smallest prime factor (2)\n while n % 2 == 0:\n largest_factor = 2\n n //= 2\n \n # Check for odd factors from 3 upwards\n factor = 3\n while factor * factor <= n:\n while n % factor == 0:\n largest_factor = factor\n n //= factor\n factor += 2\n \n # If n is still greater than 1, then it is a prime factor\n if n > 1:\n largest_factor = n\n \n return largest_factor", "matching_cluster_idx": 8}]}, "HumanEval/64": {"dps": 92.20779220779221, "dps_norm": 62.5, "pass@1": 60.0, "profiled": [{"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = \"aeiou\"\n s = s.lower()\n count = sum(1 for char in s if char in vowels)\n \n # Check if 'y' is at the end of the word\n if s.endswith('y'):\n count += 1\n \n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = \"aeiou\"\n s = s.lower()\n count = 0\n \n for char in s:\n if char in vowels:\n count += 1\n \n if s.endswith('y'):\n count += 1\n \n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = \"aeiou\"\n s = s.lower()\n count = 0\n \n for char in s:\n if char in vowels:\n count += 1\n \n # Check if 'y' is at the end of the word\n if s.endswith('y'):\n count += 1\n \n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = {'a', 'e', 'i', 'o', 'u'}\n s = s.lower()\n count = 0\n \n for char in s:\n if char in vowels:\n count += 1\n \n # Check if 'y' is at the end of the word\n if s.endswith('y'):\n count += 1\n \n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = \"aeiou\"\n s = s.lower()\n count = 0\n \n for char in s:\n if char in vowels:\n count += 1\n \n if s.endswith('y'):\n count += 1\n \n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = \"aeiou\"\n s = s.lower()\n count = 0\n \n for char in s:\n if char in vowels:\n count += 1\n \n if s.endswith('y'):\n count += 1\n \n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = \"aeiou\"\n s = s.lower()\n count = 0\n \n for char in s:\n if char in vowels:\n count += 1\n \n if s.endswith('y'):\n count += 1\n \n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = {'a', 'e', 'i', 'o', 'u'}\n s = s.lower()\n count = 0\n \n for char in s:\n if char in vowels:\n count += 1\n \n if s.endswith('y'):\n count += 1\n \n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = {'a', 'e', 'i', 'o', 'u'}\n s = s.lower()\n count = 0\n \n for char in s:\n if char in vowels:\n count += 1\n \n if s.endswith('y'):\n count += 1\n \n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = {'a', 'e', 'i', 'o', 'u'}\n count = 0\n s = s.lower()\n \n for char in s:\n if char in vowels:\n count += 1\n \n if s.endswith('y'):\n count += 1\n \n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = \"aeiou\"\n s = s.lower()\n count = 0\n \n for char in s:\n if char in vowels:\n count += 1\n \n if s.endswith('y'):\n count += 1\n \n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = \"aeiou\"\n s = s.lower()\n count = 0\n \n for char in s:\n if char in vowels:\n count += 1\n \n if s.endswith('y'):\n count += 1\n \n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = {'a', 'e', 'i', 'o', 'u'}\n s = s.lower()\n count = 0\n \n for char in s:\n if char in vowels:\n count += 1\n \n if s.endswith('y'):\n count += 1\n \n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = {'a', 'e', 'i', 'o', 'u'}\n s = s.lower()\n count = 0\n \n for char in s:\n if char in vowels:\n count += 1\n \n if s.endswith('y'):\n count += 1\n \n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = {'a', 'e', 'i', 'o', 'u'}\n s = s.lower()\n count = 0\n \n for char in s:\n if char in vowels:\n count += 1\n \n if s.endswith('y'):\n count += 1\n \n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = \"aeiou\"\n s = s.lower()\n count = 0\n \n for char in s:\n if char in vowels:\n count += 1\n \n # Check if 'y' is at the end of the word\n if s.endswith('y'):\n count += 1\n \n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = \"aeiou\"\n s = s.lower()\n count = 0\n \n for char in s:\n if char in vowels:\n count += 1\n \n # Check if 'y' is at the end of the word\n if s.endswith('y'):\n count += 1\n \n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = {'a', 'e', 'i', 'o', 'u'}\n s = s.lower()\n count = 0\n \n for char in s:\n if char in vowels:\n count += 1\n \n # Check if 'y' is at the end of the word\n if s.endswith('y'):\n count += 1\n \n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = \"aeiou\"\n s = s.lower()\n count = 0\n \n for char in s:\n if char in vowels:\n count += 1\n \n if s.endswith('y'):\n count += 1\n \n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = {'a', 'e', 'i', 'o', 'u'}\n s = s.lower()\n count = 0\n \n for char in s:\n if char in vowels:\n count += 1\n \n if s.endswith('y'):\n count += 1\n \n return count", "matching_cluster_idx": 4}]}, "HumanEval/74": {"dps": 98.04878048780488, "dps_norm": 88.88888888888889, "pass@1": 100.0, "profiled": [{"solution": "def total_match(lst1, lst2):\n def total_chars(lst):\n return sum(len(s) for s in lst)\n \n total_chars_lst1 = total_chars(lst1)\n total_chars_lst2 = total_chars(lst2)\n \n if total_chars_lst1 <= total_chars_lst2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n def total_chars(lst):\n return sum(len(s) for s in lst)\n \n total_chars_lst1 = total_chars(lst1)\n total_chars_lst2 = total_chars(lst2)\n \n if total_chars_lst1 <= total_chars_lst2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n def total_chars(lst):\n return sum(len(s) for s in lst)\n \n total_chars_lst1 = total_chars(lst1)\n total_chars_lst2 = total_chars(lst2)\n \n if total_chars_lst1 <= total_chars_lst2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n def total_chars(lst):\n return sum(len(s) for s in lst)\n \n total_chars_lst1 = total_chars(lst1)\n total_chars_lst2 = total_chars(lst2)\n \n if total_chars_lst1 <= total_chars_lst2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n def total_chars(lst):\n return sum(len(s) for s in lst)\n \n total_chars_lst1 = total_chars(lst1)\n total_chars_lst2 = total_chars(lst2)\n \n if total_chars_lst1 <= total_chars_lst2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n def total_chars(lst):\n return sum(len(s) for s in lst)\n \n total_chars_lst1 = total_chars(lst1)\n total_chars_lst2 = total_chars(lst2)\n \n if total_chars_lst1 <= total_chars_lst2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n def total_chars(lst):\n return sum(len(s) for s in lst)\n \n total_chars_lst1 = total_chars(lst1)\n total_chars_lst2 = total_chars(lst2)\n \n if total_chars_lst1 <= total_chars_lst2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n def total_chars(lst):\n return sum(len(s) for s in lst)\n \n total_chars_lst1 = total_chars(lst1)\n total_chars_lst2 = total_chars(lst2)\n \n if total_chars_lst1 <= total_chars_lst2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n def total_chars(lst):\n return sum(len(s) for s in lst)\n \n total_chars_lst1 = total_chars(lst1)\n total_chars_lst2 = total_chars(lst2)\n \n if total_chars_lst1 <= total_chars_lst2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n def total_chars(lst):\n return sum(len(s) for s in lst)\n \n total_chars_lst1 = total_chars(lst1)\n total_chars_lst2 = total_chars(lst2)\n \n if total_chars_lst1 <= total_chars_lst2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n def total_chars(lst):\n return sum(len(s) for s in lst)\n \n total_chars_lst1 = total_chars(lst1)\n total_chars_lst2 = total_chars(lst2)\n \n if total_chars_lst1 <= total_chars_lst2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n def total_chars(lst):\n return sum(len(s) for s in lst)\n \n total_chars_lst1 = total_chars(lst1)\n total_chars_lst2 = total_chars(lst2)\n \n if total_chars_lst1 <= total_chars_lst2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n def total_chars(lst):\n return sum(len(s) for s in lst)\n \n total_chars_lst1 = total_chars(lst1)\n total_chars_lst2 = total_chars(lst2)\n \n if total_chars_lst1 <= total_chars_lst2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n def total_chars(lst):\n return sum(len(s) for s in lst)\n \n total_chars_lst1 = total_chars(lst1)\n total_chars_lst2 = total_chars(lst2)\n \n if total_chars_lst1 <= total_chars_lst2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n def total_chars(lst):\n return sum(len(s) for s in lst)\n \n total_chars_lst1 = total_chars(lst1)\n total_chars_lst2 = total_chars(lst2)\n \n if total_chars_lst1 <= total_chars_lst2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n def total_chars(lst):\n return sum(len(s) for s in lst)\n \n total_chars_lst1 = total_chars(lst1)\n total_chars_lst2 = total_chars(lst2)\n \n if total_chars_lst1 <= total_chars_lst2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n def total_chars(lst):\n return sum(len(s) for s in lst)\n \n total_chars_lst1 = total_chars(lst1)\n total_chars_lst2 = total_chars(lst2)\n \n if total_chars_lst1 <= total_chars_lst2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n def total_chars(lst):\n return sum(len(s) for s in lst)\n \n total_chars_lst1 = total_chars(lst1)\n total_chars_lst2 = total_chars(lst2)\n \n if total_chars_lst1 <= total_chars_lst2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n def total_chars(lst):\n return sum(len(s) for s in lst)\n \n total_chars_lst1 = total_chars(lst1)\n total_chars_lst2 = total_chars(lst2)\n \n if total_chars_lst1 <= total_chars_lst2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n def total_chars(lst):\n return sum(len(s) for s in lst)\n \n total_chars_lst1 = total_chars(lst1)\n total_chars_lst2 = total_chars(lst2)\n \n if total_chars_lst1 <= total_chars_lst2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}]}, "HumanEval/85": {"dps": 83.66336633663366, "dps_norm": 50.0, "pass@1": 100.0, "profiled": [{"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n return sum(x for i, x in enumerate(lst) if i % 2 != 0 and x % 2 == 0)", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n # Initialize the sum to 0\n total = 0\n \n # Iterate over the list with index\n for i, num in enumerate(lst):\n # Check if the index is odd and the number is even\n if i % 2 != 0 and num % 2 == 0:\n total += num\n \n return total", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2\n \"\"\"\n # Initialize the sum to 0\n total = 0\n \n # Iterate over the list with index\n for index, value in enumerate(lst):\n # Check if the index is odd and the value is even\n if index % 2 != 0 and value % 2 == 0:\n total += value\n \n return total", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n # Initialize the sum to 0\n total = 0\n \n # Iterate over the list with index\n for index, value in enumerate(lst):\n # Check if the index is odd and the value is even\n if index % 2 != 0 and value % 2 == 0:\n total += value\n \n return total", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2\n \"\"\"\n return sum(x for i, x in enumerate(lst) if i % 2 != 0 and x % 2 == 0)", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n return sum(x for i, x in enumerate(lst) if i % 2 != 0 and x % 2 == 0)", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n # Initialize the sum to 0\n total = 0\n \n # Iterate over the list with index\n for index, value in enumerate(lst):\n # Check if the index is odd and the value is even\n if index % 2 != 0 and value % 2 == 0:\n total += value\n \n return total", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n return sum(x for i, x in enumerate(lst) if i % 2 != 0 and x % 2 == 0)", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2\n \"\"\"\n # Initialize the sum to 0\n total = 0\n \n # Iterate over the list with index\n for index, value in enumerate(lst):\n # Check if the index is odd and the value is even\n if index % 2 != 0 and value % 2 == 0:\n total += value\n \n return total", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2\n \"\"\"\n # Initialize the sum to 0\n total = 0\n \n # Iterate over the list with index\n for index, value in enumerate(lst):\n # Check if the index is odd and the value is even\n if index % 2 != 0 and value % 2 == 0:\n total += value\n \n return total", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n return sum(x for i, x in enumerate(lst) if i % 2 != 0 and x % 2 == 0)", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n # Initialize the sum to 0\n total = 0\n \n # Iterate over the list with index\n for i, num in enumerate(lst):\n # Check if the index is odd and the number is even\n if i % 2 != 0 and num % 2 == 0:\n total += num\n \n return total", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n return sum(x for i, x in enumerate(lst) if i % 2 != 0 and x % 2 == 0)", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2\n \"\"\"\n return sum(x for i, x in enumerate(lst) if i % 2 != 0 and x % 2 == 0)", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2\n \"\"\"\n return sum(x for i, x in enumerate(lst) if i % 2 != 0 and x % 2 == 0)", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2\n \"\"\"\n # Initialize the sum to 0\n total = 0\n \n # Iterate over the list with index\n for i, num in enumerate(lst):\n # Check if the index is odd and the number is even\n if i % 2 != 0 and num % 2 == 0:\n total += num\n \n return total", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n # Initialize the sum to 0\n total = 0\n \n # Iterate over the list with index\n for index, value in enumerate(lst):\n # Check if the index is odd and the value is even\n if index % 2 != 0 and value % 2 == 0:\n total += value\n \n return total", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2\n \"\"\"\n return sum(x for i, x in enumerate(lst) if i % 2 != 0 and x % 2 == 0)", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n return sum(x for i, x in enumerate(lst) if i % 2 != 0 and x % 2 == 0)", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n return sum(x for i, x in enumerate(lst) if i % 2 != 0 and x % 2 == 0)", "matching_cluster_idx": 2}]}, "HumanEval/86": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n def sort_word(word):\n return ''.join(sorted(word))\n\n words = s.split(' ')\n sorted_words = [sort_word(word) for word in words]\n return ' '.join(sorted_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n def sort_word(word):\n return ''.join(sorted(word))\n\n words = s.split(' ')\n sorted_words = [sort_word(word) for word in words]\n return ' '.join(sorted_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n def sort_word(word):\n return ''.join(sorted(word))\n\n words = s.split(' ')\n sorted_words = [sort_word(word) for word in words]\n return ' '.join(sorted_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n # Split the string into words and spaces\n parts = s.split(' ')\n \n # Process each word to sort its characters\n ordered_parts = [''.join(sorted(part)) for part in parts]\n \n # Join the processed words back together with spaces\n return ' '.join(ordered_parts)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n def sort_word(word):\n return ''.join(sorted(word))\n\n words = s.split(' ')\n sorted_words = [sort_word(word) for word in words]\n return ' '.join(sorted_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n def sort_word(word):\n return ''.join(sorted(word))\n\n words = s.split(' ')\n sorted_words = [sort_word(word) for word in words]\n return ' '.join(sorted_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n def sort_word(word):\n return ''.join(sorted(word))\n\n words = s.split(' ')\n sorted_words = [sort_word(word) for word in words]\n return ' '.join(sorted_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n # Split the string into words and spaces\n words = s.split(' ')\n \n # Process each word to sort its characters\n sorted_words = [''.join(sorted(word)) for word in words]\n \n # Join the sorted words back into a single string with spaces preserved\n result = ' '.join(sorted_words)\n \n return result", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n # Split the string into words\n words = s.split(' ')\n \n # Process each word to sort its characters\n sorted_words = [''.join(sorted(word)) for word in words]\n \n # Join the sorted words back into a single string with spaces preserved\n return ' '.join(sorted_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n # Split the string into words and spaces\n words = s.split(' ')\n \n # Process each word to sort its characters\n sorted_words = [''.join(sorted(word)) for word in words]\n \n # Join the sorted words back into a single string with spaces preserved\n result = ' '.join(sorted_words)\n \n return result", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n def sort_word(word):\n return ''.join(sorted(word))\n\n words = s.split(' ')\n sorted_words = [sort_word(word) for word in words]\n return ' '.join(sorted_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Takes a string and returns an ordered version of it.\n Ordered version of string is a string where all words (separated by space)\n are replaced by a new word where all the characters are arranged in\n ascending order based on ascii value.\n Note: Keeps the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n def sort_word(word):\n return ''.join(sorted(word))\n\n words = s.split(' ')\n sorted_words = [sort_word(word) for word in words]\n return ' '.join(sorted_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Takes a string and returns an ordered version of it.\n Ordered version of string is a string where all words (separated by space)\n are replaced by a new word where all the characters are arranged in\n ascending order based on ascii value.\n Note: Keeps the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n def sort_word(word):\n return ''.join(sorted(word))\n\n words = s.split(' ')\n sorted_words = [sort_word(word) for word in words]\n return ' '.join(sorted_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n def sort_word(word):\n return ''.join(sorted(word))\n \n words = s.split(' ')\n sorted_words = [sort_word(word) for word in words]\n return ' '.join(sorted_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n # Split the string into words and spaces\n words = s.split(' ')\n \n # Process each word to sort its characters\n sorted_words = [''.join(sorted(word)) for word in words]\n \n # Join the sorted words back into a single string with spaces preserved\n return ' '.join(sorted_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n # Split the string into words\n words = s.split(' ')\n \n # Process each word to sort its characters\n ordered_words = [''.join(sorted(word)) for word in words]\n \n # Join the ordered words back into a single string with spaces\n ordered_string = ' '.join(ordered_words)\n \n return ordered_string", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Takes a string and returns an ordered version of it.\n Ordered version of string is a string where all words (separated by space)\n are replaced by a new word where all the characters are arranged in\n ascending order based on ascii value.\n Note: Keeps the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n # Split the string into words\n words = s.split(' ')\n \n # Process each word to sort its characters\n ordered_words = [''.join(sorted(word)) for word in words]\n \n # Join the ordered words back into a single string with spaces\n return ' '.join(ordered_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n def sort_word(word):\n return ''.join(sorted(word))\n \n words = s.split(' ')\n sorted_words = [sort_word(word) for word in words]\n return ' '.join(sorted_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n # Split the string into words and spaces\n parts = s.split(' ')\n \n # Process each word to sort its characters\n ordered_parts = [''.join(sorted(part)) for part in parts]\n \n # Join the processed words back together with spaces\n return ' '.join(ordered_parts)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n # Split the string into words\n words = s.split(' ')\n \n # Process each word to sort its characters\n sorted_words = [''.join(sorted(word)) for word in words]\n \n # Join the sorted words back into a single string with spaces preserved\n return ' '.join(sorted_words)", "matching_cluster_idx": 4}]}, "HumanEval/87": {"dps": 93.94812680115274, "dps_norm": 57.142857142857146, "pass@1": 95.0, "profiled": [{"solution": "def get_row(lst, x):\n \"\"\"\n Find integers x in the list lst and return a list of tuples representing their coordinates.\n Sort coordinates initially by rows in ascending order.\n Sort coordinates of the same row by columns in descending order.\n \n :param lst: A 2-dimensional list (nested lists)\n :param x: The integer to search for\n :return: A list of tuples representing the coordinates of x in lst\n \"\"\"\n coordinates = []\n \n # Iterate over each row and column to find the coordinates of x\n for row_index, row in enumerate(lst):\n for col_index, value in enumerate(row):\n if value == x:\n coordinates.append((row_index, col_index))\n \n # Sort coordinates by row in ascending order\n coordinates.sort(key=lambda coord: coord[0])\n \n # Sort coordinates of the same row by column in descending order\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n \n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n Find integers x in the list and return their coordinates sorted by rows in ascending order\n and by columns in descending order within each row.\n \n :param lst: 2-dimensional list (nested lists)\n :param x: integer to find in the list\n :return: list of tuples [(row, column), ...]\n \"\"\"\n coordinates = []\n \n # Iterate over each row and column to find the integer x\n for row_index, row in enumerate(lst):\n for col_index, value in enumerate(row):\n if value == x:\n coordinates.append((row_index, col_index))\n \n # Sort coordinates by rows in ascending order\n coordinates.sort(key=lambda coord: coord[0])\n \n # Sort coordinates within each row by columns in descending order\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n \n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n Given a 2 dimensional list and an integer x, find all occurrences of x\n and return their coordinates sorted by rows in ascending order and\n by columns in descending order within each row.\n \n :param lst: A 2 dimensional list (list of lists)\n :param x: The integer to search for\n :return: A list of tuples representing the coordinates of x\n \"\"\"\n coordinates = []\n \n # Iterate over each row and column to find the coordinates of x\n for row_index, row in enumerate(lst):\n for col_index, value in enumerate(row):\n if value == x:\n coordinates.append((row_index, col_index))\n \n # Sort coordinates by rows in ascending order\n coordinates.sort(key=lambda coord: coord[0])\n \n # Sort coordinates within each row by columns in descending order\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n \n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n # Initialize an empty list to store the coordinates\n coordinates = []\n \n # Iterate over each row in the list\n for row_index, row in enumerate(lst):\n # Iterate over each element in the row\n for col_index, value in enumerate(row):\n # If the value matches x, add the coordinate to the list\n if value == x:\n coordinates.append((row_index, col_index))\n \n # Sort coordinates by rows in ascending order\n coordinates.sort(key=lambda coord: coord[0])\n \n # Sort coordinates of the same row by columns in descending order\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n \n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n Given a 2 dimensional list and an integer x, find all occurrences of x\n and return their coordinates as a list of tuples, sorted by rows in ascending order\n and by columns in descending order within each row.\n \n :param lst: A 2 dimensional list (list of lists)\n :param x: The integer to search for\n :return: A list of tuples representing the coordinates of x\n \"\"\"\n coordinates = []\n \n for row_index, row in enumerate(lst):\n for col_index, value in enumerate(row):\n if value == x:\n coordinates.append((row_index, col_index))\n \n # Sort by row in ascending order, and by column in descending order within each row\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n \n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n Find all occurrences of integer x in the nested list lst and return their coordinates\n sorted by rows in ascending order and by columns in descending order within each row.\n \n :param lst: A 2-dimensional list (list of lists)\n :param x: The integer to search for\n :return: A list of tuples representing the coordinates of x in lst\n \"\"\"\n coordinates = []\n \n # Iterate over each row and column to find the coordinates of x\n for row_index, row in enumerate(lst):\n for col_index, value in enumerate(row):\n if value == x:\n coordinates.append((row_index, col_index))\n \n # Sort coordinates by rows in ascending order\n coordinates.sort(key=lambda coord: coord[0])\n \n # Sort coordinates within each row by columns in descending order\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n \n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n Given a 2 dimensional list and an integer x, find all occurrences of x\n and return their coordinates as a list of tuples. The coordinates should\n be sorted by rows in ascending order and by columns in descending order\n within each row.\n \n :param lst: A 2 dimensional list (similar to a matrix but with varying row lengths).\n :param x: The integer to search for in the list.\n :return: A list of tuples representing the coordinates of x in the list.\n \"\"\"\n coordinates = []\n \n # Iterate over each row and column to find the coordinates of x\n for row_index, row in enumerate(lst):\n for col_index, value in enumerate(row):\n if value == x:\n coordinates.append((row_index, col_index))\n \n # Sort coordinates by rows in ascending order\n coordinates.sort(key=lambda coord: coord[0])\n \n # Sort coordinates within each row by columns in descending order\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n \n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n Given a 2 dimensional data as a nested list, find integer x and return\n a list of tuples representing the coordinates of x in the list.\n Sort coordinates by rows in ascending order and by columns in descending order.\n \n :param lst: Nested list representing the 2D data\n :param x: Integer to search for\n :return: List of tuples [(row, column)]\n \"\"\"\n coordinates = []\n \n # Iterate through each row and column to find the integer x\n for row_index, row in enumerate(lst):\n for col_index, value in enumerate(row):\n if value == x:\n coordinates.append((row_index, col_index))\n \n # Sort coordinates by rows in ascending order\n coordinates.sort(key=lambda coord: coord[0])\n \n # Sort coordinates of the same row by columns in descending order\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n \n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n Given a 2 dimensional list and an integer x, find all occurrences of x\n and return their coordinates sorted by rows in ascending order and\n by columns in descending order within each row.\n \n :param lst: A 2 dimensional list (nested lists)\n :param x: The integer to search for\n :return: A list of tuples representing the coordinates of x\n \"\"\"\n coordinates = []\n \n # Iterate over each row and column to find the coordinates of x\n for row_index, row in enumerate(lst):\n for col_index, value in enumerate(row):\n if value == x:\n coordinates.append((row_index, col_index))\n \n # Sort coordinates by rows in ascending order\n coordinates.sort(key=lambda coord: coord[0])\n \n # Sort coordinates within each row by columns in descending order\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n \n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n # Initialize an empty list to store the coordinates\n coordinates = []\n \n # Iterate over each row in the list\n for row_index, row in enumerate(lst):\n # Iterate over each element in the row\n for col_index, value in enumerate(row):\n # If the value matches x, append the coordinate (row_index, col_index)\n if value == x:\n coordinates.append((row_index, col_index))\n \n # Sort coordinates by rows in ascending order, and by columns in descending order\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n \n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n # Initialize an empty list to store the coordinates\n coordinates = []\n \n # Iterate over each row in the list\n for row_index, row in enumerate(lst):\n # Iterate over each element in the row\n for col_index, value in enumerate(row):\n # If the value matches x, add the coordinate to the list\n if value == x:\n coordinates.append((row_index, col_index))\n \n # Sort the coordinates first by row in ascending order\n # and then by column in descending order within the same row\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n \n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n Find all occurrences of integer x in the nested list lst and return their coordinates\n sorted by rows in ascending order and by columns in descending order within each row.\n \n :param lst: A 2-dimensional list (list of lists)\n :param x: The integer to search for\n :return: A list of tuples representing the coordinates of x in lst\n \"\"\"\n coordinates = []\n \n # Iterate over each row and column to find the coordinates of x\n for row_index, row in enumerate(lst):\n for col_index, value in enumerate(row):\n if value == x:\n coordinates.append((row_index, col_index))\n \n # Sort coordinates by rows in ascending order\n coordinates.sort(key=lambda coord: coord[0])\n \n # Sort coordinates within each row by columns in descending order\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n \n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n # Initialize an empty list to store the coordinates\n coordinates = []\n \n # Iterate over each row in the list\n for row_index, row in enumerate(lst):\n # Iterate over each element in the row\n for col_index, value in enumerate(row):\n # If the element matches x, append the coordinate to the list\n if value == x:\n coordinates.append((row_index, col_index))\n \n # Sort the coordinates by rows in ascending order\n coordinates.sort(key=lambda coord: coord[0])\n \n # Sort the coordinates within each row by columns in descending order\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n \n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n # Initialize an empty list to store the coordinates\n coordinates = []\n \n # Iterate over each row in the list\n for row_index, row in enumerate(lst):\n # Iterate over each element in the row\n for col_index, value in enumerate(row):\n # If the value matches x, append the coordinate (row, col) to the list\n if value == x:\n coordinates.append((row_index, col_index))\n \n # Sort coordinates by rows in ascending order\n coordinates.sort(key=lambda coord: coord[0])\n \n # Sort coordinates of the same row by columns in descending order\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n \n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n Find all occurrences of integer x in the nested list lst and return their coordinates\n sorted by rows in ascending order and by columns in descending order within each row.\n \n :param lst: A 2-dimensional list (list of lists)\n :param x: The integer to search for\n :return: A list of tuples representing the coordinates of x in lst\n \"\"\"\n coordinates = []\n \n # Iterate over each row and column to find the coordinates of x\n for row_index, row in enumerate(lst):\n for col_index, value in enumerate(row):\n if value == x:\n coordinates.append((row_index, col_index))\n \n # Sort coordinates by rows in ascending order\n coordinates.sort(key=lambda coord: coord[0])\n \n # Sort coordinates within each row by columns in descending order\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n \n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n Given a 2 dimensional data as a nested list, find the integer x in the list,\n and return a list of tuples [(x1, y1), (x2, y2) ...] such that each tuple\n is a coordinate - (row, column), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n coordinates = []\n \n for row_index, row in enumerate(lst):\n for col_index, value in enumerate(row):\n if value == x:\n coordinates.append((row_index, col_index))\n \n # Sort by row in ascending order, and by column in descending order for each row\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n \n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n Find all occurrences of integer x in the nested list lst and return their coordinates\n as a list of tuples, sorted by rows in ascending order and by columns in descending order within each row.\n \n :param lst: A 2-dimensional list (nested lists)\n :param x: The integer to search for\n :return: A list of tuples representing the coordinates of x in lst\n \"\"\"\n coordinates = []\n \n # Iterate through each row and column to find the coordinates of x\n for row_index, row in enumerate(lst):\n for col_index, value in enumerate(row):\n if value == x:\n coordinates.append((row_index, col_index))\n \n # Sort coordinates by rows in ascending order\n coordinates.sort(key=lambda coord: coord[0])\n \n # Sort coordinates within each row by columns in descending order\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n \n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n Given a 2 dimensional data as a nested list, find the coordinates of integer x.\n Return a list of tuples sorted by rows in ascending order and by columns in descending order within each row.\n \n :param lst: Nested list representing the 2D data.\n :param x: Integer to search for in the 2D data.\n :return: List of tuples representing the coordinates of x.\n \"\"\"\n coordinates = []\n \n # Iterate through each row and column to find the coordinates of x\n for row_index, row in enumerate(lst):\n for col_index, value in enumerate(row):\n if value == x:\n coordinates.append((row_index, col_index))\n \n # Sort coordinates by rows in ascending order\n coordinates.sort(key=lambda coord: coord[0])\n \n # Sort coordinates within each row by columns in descending order\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n \n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n # Initialize an empty list to store the coordinates\n coordinates = []\n \n # Iterate over each row in the list\n for row_index, row in enumerate(lst):\n # Iterate over each element in the row\n for col_index, value in enumerate(row):\n # If the value matches x, append the coordinate (row, col) to the list\n if value == x:\n coordinates.append((row_index, col_index))\n \n # Sort coordinates by rows in ascending order\n coordinates.sort(key=lambda coord: coord[0])\n \n # Sort coordinates of the same row by columns in descending order\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n \n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n # Initialize an empty list to store the coordinates\n coordinates = []\n \n # Iterate over each row in the list\n for row_index, row in enumerate(lst):\n # Iterate over each element in the row\n for col_index, value in enumerate(row):\n # If the element matches x, add the coordinate to the list\n if value == x:\n coordinates.append((row_index, col_index))\n \n # Sort coordinates by rows in ascending order\n coordinates.sort(key=lambda coord: coord[0])\n \n # Sort coordinates of the same row by columns in descending order\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n \n return coordinates", "matching_cluster_idx": 3}]}, "HumanEval/89": {"dps": 96.95876288659795, "dps_norm": 45.714285714285715, "pass@1": 98.0, "profiled": [{"solution": "def encrypt(s):\n \"\"\"Encrypts a string by rotating the alphabet such that each letter shifts down by two multiplied to two places.\"\"\"\n encrypted_string = \"\"\n \n for char in s:\n if char.isalpha():\n # Determine the shift amount (2 * 2 = 4)\n shift = 4\n \n # Calculate the new character position\n if char.islower():\n new_char = chr((ord(char) - ord('a') + shift) % 26 + ord('a'))\n else:\n new_char = chr((ord(char) - ord('A') + shift) % 26 + ord('A'))\n \n encrypted_string += new_char\n else:\n # If the character is not a letter, keep it unchanged\n encrypted_string += char\n \n return encrypted_string", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Encrypts a string by rotating the alphabet such that each letter shifts down by 2 * 2 = 4 places.\"\"\"\n encrypted_string = []\n \n for char in s:\n if char.isalpha():\n # Determine the new character by shifting 4 places in the alphabet\n if char.islower():\n new_char = chr((ord(char) - ord('a') + 4) % 26 + ord('a'))\n else:\n new_char = chr((ord(char) - ord('A') + 4) % 26 + ord('A'))\n encrypted_string.append(new_char)\n else:\n # If the character is not a letter, append it as is\n encrypted_string.append(char)\n \n return ''.join(encrypted_string)", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n encrypted_string = \"\"\n shift = 2 * 2 # Shift by 4 places\n\n for char in s:\n if char.isalpha():\n if char.islower():\n # Calculate the new character position in the alphabet\n new_char = chr((ord(char) - ord('a') + shift) % 26 + ord('a'))\n else:\n # Calculate the new character position in the alphabet\n new_char = chr((ord(char) - ord('A') + shift) % 26 + ord('A'))\n encrypted_string += new_char\n else:\n # If the character is not a letter, keep it unchanged\n encrypted_string += char\n\n return encrypted_string", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n # Define the shift amount\n shift = 2 * 2\n \n # Create a translation table for the shift\n translation_table = str.maketrans(\n 'abcdefghijklmnopqrstuvwxyz',\n 'abcdefghijklmnopqrstuvwxyz'[shift:] + 'abcdefghijklmnopqrstuvwxyz'[:shift]\n )\n \n # Translate the input string using the translation table\n encrypted_string = s.translate(translation_table)\n \n return encrypted_string", "matching_cluster_idx": 5}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n encrypted_string = \"\"\n shift = 2 * 2 # Shift by 4 places\n\n for char in s:\n if char.isalpha():\n if char.islower():\n # Shift within lowercase letters\n new_char = chr((ord(char) - ord('a') + shift) % 26 + ord('a'))\n else:\n # Shift within uppercase letters\n new_char = chr((ord(char) - ord('A') + shift) % 26 + ord('A'))\n else:\n # Non-alphabetic characters remain unchanged\n new_char = char\n \n encrypted_string += new_char\n \n return encrypted_string", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n encrypted_string = \"\"\n shift = 2 * 2 # Shift by 4 places\n\n for char in s:\n if char.isalpha():\n # Determine if the character is uppercase or lowercase\n is_upper = char.isupper()\n # Convert to lowercase for easier manipulation\n char = char.lower()\n # Shift the character\n shifted_char = chr(((ord(char) - ord('a') + shift) % 26) + ord('a'))\n # Convert back to uppercase if necessary\n if is_upper:\n shifted_char = shifted_char.upper()\n encrypted_string += shifted_char\n else:\n # If the character is not a letter, keep it unchanged\n encrypted_string += char\n\n return encrypted_string", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n # Define the shift amount\n shift = 2 * 2\n \n # Create a translation table for the shift\n translation_table = str.maketrans(\n 'abcdefghijklmnopqrstuvwxyz',\n 'abcdefghijklmnopqrstuvwxyz'[shift:] + 'abcdefghijklmnopqrstuvwxyz'[:shift]\n )\n \n # Translate the input string using the translation table\n encrypted_string = s.translate(translation_table)\n \n return encrypted_string", "matching_cluster_idx": 5}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n # Define the shift amount\n shift = 2 * 2\n \n # Create a translation table for the shift\n translation_table = str.maketrans(\n 'abcdefghijklmnopqrstuvwxyz',\n 'abcdefghijklmnopqrstuvwxyz'[shift:] + 'abcdefghijklmnopqrstuvwxyz'[:shift]\n )\n \n # Translate the input string using the translation table\n encrypted_string = s.translate(translation_table)\n \n return encrypted_string", "matching_cluster_idx": 5}, {"solution": "def encrypt(s):\n \"\"\"Encrypts a string by rotating the alphabet such that each letter shifts down by two multiplied to two places.\"\"\"\n encrypted_string = []\n \n for char in s:\n if 'a' <= char <= 'z':\n # Calculate the new character by shifting it down by 2 * 2 = 4 places\n new_char = chr((ord(char) - ord('a') + 4) % 26 + ord('a'))\n encrypted_string.append(new_char)\n else:\n # If the character is not a lowercase letter, leave it unchanged\n encrypted_string.append(char)\n \n return ''.join(encrypted_string)", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Encrypts a string by rotating the alphabet by 2 * 2 = 4 places.\"\"\"\n encrypted_string = []\n \n for char in s:\n if 'a' <= char <= 'z':\n # Shift the character by 4 places in the alphabet\n new_char = chr((ord(char) - ord('a') + 4) % 26 + ord('a'))\n encrypted_string.append(new_char)\n else:\n # If the character is not a lowercase letter, leave it unchanged\n encrypted_string.append(char)\n \n return ''.join(encrypted_string)", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Encrypts a string by rotating the alphabet such that each letter shifts down by 2 * 2 places.\"\"\"\n encrypted_string = []\n \n for char in s:\n if char.isalpha():\n # Determine the shift amount (2 * 2 = 4)\n shift = 4\n \n # Determine if the character is uppercase or lowercase\n if char.islower():\n # Calculate the new character position\n new_char = chr((ord(char) - ord('a') + shift) % 26 + ord('a'))\n else:\n # Calculate the new character position\n new_char = chr((ord(char) - ord('A') + shift) % 26 + ord('A'))\n \n encrypted_string.append(new_char)\n else:\n # If the character is not a letter, keep it unchanged\n encrypted_string.append(char)\n \n return ''.join(encrypted_string)", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Encrypts a string by rotating the alphabet such that each letter shifts down by two multiplied to two places.\"\"\"\n encrypted_string = []\n \n for char in s:\n if char.isalpha():\n # Determine the new character by shifting it down by 4 places (2 * 2)\n if char.islower():\n new_char = chr((ord(char) - ord('a') + 4) % 26 + ord('a'))\n else:\n new_char = chr((ord(char) - ord('A') + 4) % 26 + ord('A'))\n encrypted_string.append(new_char)\n else:\n # If the character is not a letter, keep it unchanged\n encrypted_string.append(char)\n \n return ''.join(encrypted_string)", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Encrypts a string by rotating the alphabet such that each letter shifts down by two multiplied to two places.\"\"\"\n encrypted_string = \"\"\n \n for char in s:\n if char.isalpha():\n # Determine the shift amount (2 * 2 = 4)\n shift = 4\n # Calculate the new character position\n if char.islower():\n new_char = chr((ord(char) - ord('a') + shift) % 26 + ord('a'))\n else:\n new_char = chr((ord(char) - ord('A') + shift) % 26 + ord('A'))\n encrypted_string += new_char\n else:\n # If the character is not a letter, keep it unchanged\n encrypted_string += char\n \n return encrypted_string", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n encrypted_string = \"\"\n shift = 2 * 2 # Shift by 4 places\n\n for char in s:\n if char.isalpha():\n # Determine if the character is uppercase or lowercase\n if char.islower():\n base = ord('a')\n else:\n base = ord('A')\n \n # Calculate the new character after shifting\n new_char = chr((ord(char) - base + shift) % 26 + base)\n encrypted_string += new_char\n else:\n # If the character is not a letter, keep it unchanged\n encrypted_string += char\n \n return encrypted_string", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n # Define the shift value\n shift = 2 * 2\n \n # Create a translation table for the shift\n translation_table = str.maketrans(\n 'abcdefghijklmnopqrstuvwxyz',\n 'abcdefghijklmnopqrstuvwxyz'[shift:] + 'abcdefghijklmnopqrstuvwxyz'[:shift]\n )\n \n # Translate the input string using the translation table\n encrypted_string = s.translate(translation_table)\n \n return encrypted_string", "matching_cluster_idx": 5}, {"solution": "def encrypt(s):\n \"\"\"Encrypt the string by rotating the alphabet by 2 * 2 = 4 places.\"\"\"\n encrypted_string = []\n \n for char in s:\n if 'a' <= char <= 'z':\n # Shift the character by 4 places\n new_char = chr((ord(char) - ord('a') + 4) % 26 + ord('a'))\n encrypted_string.append(new_char)\n elif 'A' <= char <= 'Z':\n # Shift the character by 4 places\n new_char = chr((ord(char) - ord('A') + 4) % 26 + ord('A'))\n encrypted_string.append(new_char)\n else:\n # If the character is not a letter, leave it unchanged\n encrypted_string.append(char)\n \n return ''.join(encrypted_string)", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n # Define the shift amount\n shift = 2 * 2\n \n # Create a translation table for the shift\n translation_table = str.maketrans(\n 'abcdefghijklmnopqrstuvwxyz',\n 'abcdefghijklmnopqrstuvwxyz'[shift:] + 'abcdefghijklmnopqrstuvwxyz'[:shift]\n )\n \n # Translate the input string using the translation table\n encrypted_string = s.translate(translation_table)\n \n return encrypted_string", "matching_cluster_idx": 5}, {"solution": "def encrypt(s):\n \"\"\"Encrypts a string by rotating the alphabet such that each letter shifts down by 2 * 2 = 4 places.\"\"\"\n encrypted_string = []\n \n for char in s:\n if 'a' <= char <= 'z':\n # Calculate the new character by shifting 4 places down in the alphabet\n new_char = chr((ord(char) - ord('a') + 4) % 26 + ord('a'))\n encrypted_string.append(new_char)\n elif 'A' <= char <= 'Z':\n # Calculate the new character by shifting 4 places down in the alphabet\n new_char = chr((ord(char) - ord('A') + 4) % 26 + ord('A'))\n encrypted_string.append(new_char)\n else:\n # If the character is not a letter, keep it unchanged\n encrypted_string.append(char)\n \n return ''.join(encrypted_string)", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n # Define the shift amount\n shift = 2 * 2\n \n # Create a translation table for the shift\n translation_table = str.maketrans(\n 'abcdefghijklmnopqrstuvwxyz',\n 'abcdefghijklmnopqrstuvwxyz'[shift:] + 'abcdefghijklmnopqrstuvwxyz'[:shift]\n )\n \n # Translate the input string using the translation table\n encrypted_string = s.translate(translation_table)\n \n return encrypted_string", "matching_cluster_idx": 5}, {"solution": "def encrypt(s):\n \"\"\"Encrypts a string by rotating the alphabet such that each letter shifts down by 2 * 2 = 4 places.\"\"\"\n encrypted_string = []\n \n for char in s:\n if 'a' <= char <= 'z':\n # Calculate the new character by shifting 4 places down in the alphabet\n new_char = chr((ord(char) - ord('a') + 4) % 26 + ord('a'))\n encrypted_string.append(new_char)\n elif 'A' <= char <= 'Z':\n # Calculate the new character by shifting 4 places down in the alphabet\n new_char = chr((ord(char) - ord('A') + 4) % 26 + ord('A'))\n encrypted_string.append(new_char)\n else:\n # If the character is not a letter, keep it unchanged\n encrypted_string.append(char)\n \n return ''.join(encrypted_string)", "matching_cluster_idx": 1}]}, "HumanEval/90": {"dps": 87.54863813229572, "dps_norm": 58.333333333333336, "pass@1": 100.0, "profiled": [{"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n \n # Remove duplicates and sort the list\n sorted_unique_lst = sorted(set(lst))\n \n # Check if there is a second smallest element\n if len(sorted_unique_lst) < 2:\n return None\n \n return sorted_unique_lst[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n \n # Remove duplicates and sort the list\n sorted_unique_lst = sorted(set(lst))\n \n if len(sorted_unique_lst) < 2:\n return None\n \n return sorted_unique_lst[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n \n # Remove duplicates and sort the list\n sorted_unique_elements = sorted(set(lst))\n \n if len(sorted_unique_elements) < 2:\n return None\n \n return sorted_unique_elements[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n \n # Remove duplicates and sort the list\n unique_sorted_lst = sorted(set(lst))\n \n if len(unique_sorted_lst) < 2:\n return None\n \n return unique_sorted_lst[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n \n # Remove duplicates and sort the list\n sorted_unique_lst = sorted(set(lst))\n \n # Check if there is a second smallest element\n if len(sorted_unique_lst) < 2:\n return None\n \n return sorted_unique_lst[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n \n # Remove duplicates and sort the list\n sorted_unique_lst = sorted(set(lst))\n \n if len(sorted_unique_lst) < 2:\n return None\n \n return sorted_unique_lst[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n \n # Remove duplicates and sort the list\n sorted_unique_lst = sorted(set(lst))\n \n if len(sorted_unique_lst) < 2:\n return None\n \n return sorted_unique_lst[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n \n # Remove duplicates and sort the list\n sorted_unique_lst = sorted(set(lst))\n \n if len(sorted_unique_lst) < 2:\n return None\n \n return sorted_unique_lst[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n \n # Remove duplicates and sort the list\n sorted_unique_elements = sorted(set(lst))\n \n if len(sorted_unique_elements) < 2:\n return None\n \n return sorted_unique_elements[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n \n # Remove duplicates and sort the list\n sorted_unique_lst = sorted(set(lst))\n \n if len(sorted_unique_lst) < 2:\n return None\n \n return sorted_unique_lst[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n \n # Remove duplicates and sort the list\n sorted_unique_lst = sorted(set(lst))\n \n if len(sorted_unique_lst) < 2:\n return None\n \n return sorted_unique_lst[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n \n # Remove duplicates and sort the list\n sorted_unique_lst = sorted(set(lst))\n \n if len(sorted_unique_lst) < 2:\n return None\n \n return sorted_unique_lst[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n \n # Remove duplicates and sort the list\n sorted_unique_lst = sorted(set(lst))\n \n if len(sorted_unique_lst) < 2:\n return None\n \n return sorted_unique_lst[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n \n # Remove duplicates and sort the list\n sorted_unique_lst = sorted(set(lst))\n \n # Check if there is a second smallest element\n if len(sorted_unique_lst) < 2:\n return None\n \n return sorted_unique_lst[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n \n # Remove duplicates and sort the list\n sorted_unique_lst = sorted(set(lst))\n \n if len(sorted_unique_lst) < 2:\n return None\n \n return sorted_unique_lst[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n \n # Remove duplicates and sort the list\n sorted_unique_lst = sorted(set(lst))\n \n # Check if there is a 2nd smallest element\n if len(sorted_unique_lst) < 2:\n return None\n \n return sorted_unique_lst[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n \n # Remove duplicates and sort the list\n sorted_unique_lst = sorted(set(lst))\n \n if len(sorted_unique_lst) < 2:\n return None\n \n return sorted_unique_lst[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n \n # Remove duplicates and sort the list\n sorted_unique_lst = sorted(set(lst))\n \n if len(sorted_unique_lst) < 2:\n return None\n \n return sorted_unique_lst[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n \n # Remove duplicates and sort the list\n sorted_unique_lst = sorted(set(lst))\n \n if len(sorted_unique_lst) < 2:\n return None\n \n return sorted_unique_lst[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n \n # Remove duplicates and sort the list\n sorted_unique_lst = sorted(set(lst))\n \n # Check if there is a second smallest element\n if len(sorted_unique_lst) < 2:\n return None\n \n return sorted_unique_lst[1]", "matching_cluster_idx": 6}]}, "HumanEval/113": {"dps": 98.98580121703854, "dps_norm": 66.66666666666667, "pass@1": 100.0, "profiled": [{"solution": "def odd_count(lst):\n def count_odds(s):\n return sum(1 for c in s if int(c) % 2 != 0)\n \n result = []\n for i, s in enumerate(lst):\n odd_digits_count = count_odds(s)\n result.append(f\"the number of odd elements {odd_digits_count}n the str{odd_digits_count}ng {odd_digits_count} of the {odd_digits_count}nput.\")\n \n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n result = []\n for i, s in enumerate(lst):\n odd_digits_count = sum(1 for char in s if int(char) % 2 != 0)\n result.append(f\"the number of odd elements {odd_digits_count}n the str{odd_digits_count}ng {odd_digits_count} of the {odd_digits_count}nput.\")\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n def count_odd_digits(s):\n return sum(1 for char in s if int(char) % 2 != 0)\n \n result = []\n for i, s in enumerate(lst):\n odd_count = count_odd_digits(s)\n result.append(f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\")\n \n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n def count_odd_digits(s):\n return sum(1 for char in s if int(char) % 2 != 0)\n \n result = []\n for i, s in enumerate(lst):\n odd_count = count_odd_digits(s)\n result.append(f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\")\n \n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n def count_odd_digits(s):\n return sum(1 for char in s if int(char) % 2 != 0)\n \n result = []\n for i, s in enumerate(lst):\n odd_count = count_odd_digits(s)\n result.append(f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\")\n \n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n def count_odds(s):\n return sum(1 for c in s if int(c) % 2 != 0)\n \n result = []\n for i, s in enumerate(lst):\n odd_digits_count = count_odds(s)\n result.append(f\"the number of odd elements {odd_digits_count}n the str{odd_digits_count}ng {odd_digits_count} of the {odd_digits_count}nput.\")\n \n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n result = []\n for i, s in enumerate(lst):\n odd_digits_count = sum(1 for char in s if int(char) % 2 != 0)\n result.append(f\"the number of odd elements {odd_digits_count}n the str{odd_digits_count}ng {odd_digits_count} of the {odd_digits_count}nput.\")\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n result = []\n for i, s in enumerate(lst):\n odd_digits_count = sum(1 for char in s if int(char) % 2 != 0)\n result.append(f\"the number of odd elements {odd_digits_count}n the str{odd_digits_count}ng {odd_digits_count} of the {odd_digits_count}nput.\")\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n def count_odds(s):\n return sum(1 for c in s if int(c) % 2 != 0)\n \n result = []\n for i, s in enumerate(lst):\n odd_digits_count = count_odds(s)\n result.append(f\"the number of odd elements {odd_digits_count}n the str{odd_digits_count}ng {odd_digits_count} of the {odd_digits_count}nput.\")\n \n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n def count_odd_digits(s):\n return sum(1 for char in s if int(char) % 2 != 0)\n \n result = []\n for i, s in enumerate(lst):\n odd_count = count_odd_digits(s)\n result.append(f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\")\n \n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n def count_odd_digits(s):\n return sum(1 for char in s if int(char) % 2 != 0)\n \n result = []\n for i, s in enumerate(lst):\n odd_count = count_odd_digits(s)\n result.append(f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\")\n \n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n def count_odds(s):\n return sum(1 for c in s if int(c) % 2 != 0)\n \n result = []\n for i, s in enumerate(lst):\n odd_digits_count = count_odds(s)\n result.append(f\"the number of odd elements {odd_digits_count}n the str{odd_digits_count}ng {odd_digits_count} of the {odd_digits_count}nput.\")\n \n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n def count_odd_digits(s):\n return sum(1 for char in s if int(char) % 2 != 0)\n \n result = []\n for i, s in enumerate(lst):\n odd_count = count_odd_digits(s)\n result.append(f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\")\n \n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n def count_odd_digits(s):\n return sum(1 for char in s if int(char) % 2 != 0)\n \n result = []\n for i, s in enumerate(lst):\n odd_count = count_odd_digits(s)\n result.append(f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\")\n \n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n def count_odd_digits(s):\n return sum(1 for c in s if int(c) % 2 != 0)\n \n result = []\n for i, s in enumerate(lst):\n odd_count = count_odd_digits(s)\n result.append(f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\")\n \n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n def count_odds(s):\n return sum(1 for c in s if int(c) % 2 != 0)\n \n result = []\n for i, s in enumerate(lst):\n odd_digits_count = count_odds(s)\n result.append(f\"the number of odd elements {odd_digits_count}n the str{odd_digits_count}ng {odd_digits_count} of the {odd_digits_count}nput.\")\n \n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n def count_odd_digits(s):\n return sum(1 for char in s if int(char) % 2 != 0)\n \n result = []\n for i, s in enumerate(lst):\n odd_count = count_odd_digits(s)\n result.append(f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\")\n \n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n def count_odds(s):\n return sum(1 for c in s if int(c) % 2 != 0)\n \n result = []\n for i, s in enumerate(lst):\n odd_digits_count = count_odds(s)\n result.append(f\"the number of odd elements {odd_digits_count}n the str{odd_digits_count}ng {odd_digits_count} of the {odd_digits_count}nput.\")\n \n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n def count_odds(s):\n return sum(1 for c in s if int(c) % 2 != 0)\n \n result = []\n for i, s in enumerate(lst):\n odd_digits_count = count_odds(s)\n result.append(f\"the number of odd elements {odd_digits_count}n the str{odd_digits_count}ng {odd_digits_count} of the {odd_digits_count}nput.\")\n \n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n def count_odd_digits(s):\n return sum(1 for char in s if int(char) % 2 != 0)\n\n result = []\n for i, s in enumerate(lst):\n odd_count = count_odd_digits(s)\n result.append(f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\")\n \n return result", "matching_cluster_idx": 3}]}, "HumanEval/119": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 35.0, "profiled": [{"solution": "def match_parens(lst):\n def is_balanced(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n elif char == ')':\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n s1, s2 = lst\n \n # Check if concatenating in both orders results in a balanced string\n if is_balanced(s1 + s2) or is_balanced(s2 + s1):\n return 'Yes'\n else:\n return 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n def is_balanced(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n elif char == ')':\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n s1, s2 = lst\n \n # Check if concatenating in both orders results in a balanced string\n if is_balanced(s1 + s2) or is_balanced(s2 + s1):\n return 'Yes'\n else:\n return 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n def is_balanced(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n elif char == ')':\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n str1, str2 = lst\n \n # Check both possible concatenations\n if is_balanced(str1 + str2) or is_balanced(str2 + str1):\n return 'Yes'\n else:\n return 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n def is_balanced(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n elif char == ')':\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n s1, s2 = lst\n \n # Check if concatenating in both orders results in a balanced string\n if is_balanced(s1 + s2) or is_balanced(s2 + s1):\n return 'Yes'\n else:\n return 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n def is_balanced(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n elif char == ')':\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n s1, s2 = lst\n \n # Check if concatenating in both orders results in a balanced string\n if is_balanced(s1 + s2) or is_balanced(s2 + s1):\n return 'Yes'\n else:\n return 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n def is_balanced(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n elif char == ')':\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n s1, s2 = lst\n \n # Check if concatenating in both orders results in a balanced string\n if is_balanced(s1 + s2) or is_balanced(s2 + s1):\n return 'Yes'\n else:\n return 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n def is_balanced(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n elif char == ')':\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n s1, s2 = lst\n \n # Check if concatenating in both orders results in a balanced string\n if is_balanced(s1 + s2) or is_balanced(s2 + s1):\n return 'Yes'\n else:\n return 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n def is_balanced(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n elif char == ')':\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n str1, str2 = lst\n \n # Check both possible concatenations\n if is_balanced(str1 + str2) or is_balanced(str2 + str1):\n return 'Yes'\n else:\n return 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n def is_balanced(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n elif char == ')':\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n s1, s2 = lst\n \n # Check both possible concatenations\n if is_balanced(s1 + s2) or is_balanced(s2 + s1):\n return 'Yes'\n else:\n return 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n def is_balanced(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n elif char == ')':\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n s1, s2 = lst\n \n # Check if concatenating in both orders results in a balanced string\n if is_balanced(s1 + s2) or is_balanced(s2 + s1):\n return 'Yes'\n else:\n return 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n def is_balanced(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n elif char == ')':\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n s1, s2 = lst\n \n # Check if concatenating in both orders results in a balanced string\n if is_balanced(s1 + s2) or is_balanced(s2 + s1):\n return 'Yes'\n else:\n return 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n def is_balanced(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n elif char == ')':\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n s1, s2 = lst\n \n # Check if concatenating in both orders results in a balanced string\n if is_balanced(s1 + s2) or is_balanced(s2 + s1):\n return 'Yes'\n else:\n return 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n def is_balanced(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n elif char == ')':\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n s1, s2 = lst\n \n # Check if concatenating in both orders results in a balanced string\n if is_balanced(s1 + s2) or is_balanced(s2 + s1):\n return 'Yes'\n else:\n return 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n def is_balanced(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n elif char == ')':\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n s1, s2 = lst\n \n # Check both possible concatenations\n if is_balanced(s1 + s2) or is_balanced(s2 + s1):\n return 'Yes'\n else:\n return 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n def is_balanced(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n elif char == ')':\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n s1, s2 = lst\n \n # Check if concatenating in both orders results in a balanced string\n if is_balanced(s1 + s2) or is_balanced(s2 + s1):\n return 'Yes'\n else:\n return 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n def is_balanced(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n elif char == ')':\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n s1, s2 = lst\n \n # Check if concatenating in both orders results in a balanced string\n if is_balanced(s1 + s2) or is_balanced(s2 + s1):\n return 'Yes'\n else:\n return 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n def is_balanced(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n elif char == ')':\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n s1, s2 = lst\n \n # Check both possible concatenations\n if is_balanced(s1 + s2) or is_balanced(s2 + s1):\n return 'Yes'\n else:\n return 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n def is_balanced(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n elif char == ')':\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n s1, s2 = lst\n \n # Check if concatenating in both orders results in a balanced string\n if is_balanced(s1 + s2) or is_balanced(s2 + s1):\n return 'Yes'\n else:\n return 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n def is_balanced(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n elif char == ')':\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n s1, s2 = lst\n \n # Check if concatenating in both orders results in a balanced string\n if is_balanced(s1 + s2) or is_balanced(s2 + s1):\n return 'Yes'\n else:\n return 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n def is_balanced(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n elif char == ')':\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n str1, str2 = lst\n \n # Check if concatenating in both orders results in a balanced string\n if is_balanced(str1 + str2) or is_balanced(str2 + str1):\n return 'Yes'\n else:\n return 'No'", "matching_cluster_idx": 4}]}, "HumanEval/120": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n\n Example 1:\n\n Input: arr = [-3, -4, 5], k = 3\n Output: [-4, -3, 5]\n\n Example 2:\n\n Input: arr = [4, -4, 4], k = 2\n Output: [4, 4]\n\n Example 3:\n\n Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1\n Output: [2]\n\n Note:\n 1. The length of the array will be in the range of [1, 1000].\n 2. The elements in the array will be in the range of [-1000, 1000].\n 3. 0 <= k <= len(arr)\n \"\"\"\n # Sort the array in descending order\n sorted_arr = sorted(arr, reverse=True)\n \n # Take the top k elements\n top_k = sorted_arr[:k]\n \n # Sort the top k elements in ascending order\n result = sorted(top_k)\n \n return result", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n\n Example 1:\n\n Input: arr = [-3, -4, 5], k = 3\n Output: [-4, -3, 5]\n\n Example 2:\n\n Input: arr = [4, -4, 4], k = 2\n Output: [4, 4]\n\n Example 3:\n\n Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1\n Output: [2]\n\n Note:\n 1. The length of the array will be in the range of [1, 1000].\n 2. The elements in the array will be in the range of [-1000, 1000].\n 3. 0 <= k <= len(arr)\n \"\"\"\n # Sort the array in descending order\n sorted_arr = sorted(arr, reverse=True)\n \n # Take the top k elements\n top_k = sorted_arr[:k]\n \n # Sort the top k elements in ascending order\n result = sorted(top_k)\n \n return result", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n\n Example 1:\n\n Input: arr = [-3, -4, 5], k = 3\n Output: [-4, -3, 5]\n\n Example 2:\n\n Input: arr = [4, -4, 4], k = 2\n Output: [4, 4]\n\n Example 3:\n\n Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1\n Output: [2]\n\n Note:\n 1. The length of the array will be in the range of [1, 1000].\n 2. The elements in the array will be in the range of [-1000, 1000].\n 3. 0 <= k <= len(arr)\n \"\"\"\n # Sort the array in descending order\n sorted_arr = sorted(arr, reverse=True)\n \n # Take the first k elements\n max_k_elements = sorted_arr[:k]\n \n # Sort the k elements in ascending order\n result = sorted(max_k_elements)\n \n return result", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n\n Example 1:\n\n Input: arr = [-3, -4, 5], k = 3\n Output: [-4, -3, 5]\n\n Example 2:\n\n Input: arr = [4, -4, 4], k = 2\n Output: [4, 4]\n\n Example 3:\n\n Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1\n Output: [2]\n\n Note:\n 1. The length of the array will be in the range of [1, 1000].\n 2. The elements in the array will be in the range of [-1000, 1000].\n 3. 0 <= k <= len(arr)\n \"\"\"\n # Sort the array in descending order\n sorted_arr = sorted(arr, reverse=True)\n \n # Take the top k elements\n top_k = sorted_arr[:k]\n \n # Sort the top k elements in ascending order\n result = sorted(top_k)\n \n return result", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n\n Example 1:\n\n Input: arr = [-3, -4, 5], k = 3\n Output: [-4, -3, 5]\n\n Example 2:\n\n Input: arr = [4, -4, 4], k = 2\n Output: [4, 4]\n\n Example 3:\n\n Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1\n Output: [2]\n\n Note:\n 1. The length of the array will be in the range of [1, 1000].\n 2. The elements in the array will be in the range of [-1000, 1000].\n 3. 0 <= k <= len(arr)\n \"\"\"\n # Sort the array in descending order\n arr_sorted = sorted(arr, reverse=True)\n \n # Take the first k elements\n max_k_elements = arr_sorted[:k]\n \n # Sort the k elements in ascending order\n result = sorted(max_k_elements)\n \n return result", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n\n Example 1:\n\n Input: arr = [-3, -4, 5], k = 3\n Output: [-4, -3, 5]\n\n Example 2:\n\n Input: arr = [4, -4, 4], k = 2\n Output: [4, 4]\n\n Example 3:\n\n Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1\n Output: [2]\n\n Note:\n 1. The length of the array will be in the range of [1, 1000].\n 2. The elements in the array will be in the range of [-1000, 1000].\n 3. 0 <= k <= len(arr)\n \"\"\"\n # Sort the array in descending order\n sorted_arr = sorted(arr, reverse=True)\n \n # Take the top k elements\n top_k = sorted_arr[:k]\n \n # Sort the top k elements in ascending order\n result = sorted(top_k)\n \n return result", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n\n Example 1:\n\n Input: arr = [-3, -4, 5], k = 3\n Output: [-4, -3, 5]\n\n Example 2:\n\n Input: arr = [4, -4, 4], k = 2\n Output: [4, 4]\n\n Example 3:\n\n Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1\n Output: [2]\n\n Note:\n 1. The length of the array will be in the range of [1, 1000].\n 2. The elements in the array will be in the range of [-1000, 1000].\n 3. 0 <= k <= len(arr)\n \"\"\"\n # Sort the array in descending order\n sorted_arr = sorted(arr, reverse=True)\n \n # Take the top k elements\n top_k = sorted_arr[:k]\n \n # Sort the top k elements in ascending order\n result = sorted(top_k)\n \n return result", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n\n Example 1:\n\n Input: arr = [-3, -4, 5], k = 3\n Output: [-4, -3, 5]\n\n Example 2:\n\n Input: arr = [4, -4, 4], k = 2\n Output: [4, 4]\n\n Example 3:\n\n Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1\n Output: [2]\n\n Note:\n 1. The length of the array will be in the range of [1, 1000].\n 2. The elements in the array will be in the range of [-1000, 1000].\n 3. 0 <= k <= len(arr)\n \"\"\"\n # Sort the array in descending order\n sorted_arr = sorted(arr, reverse=True)\n \n # Take the top k elements\n top_k = sorted_arr[:k]\n \n # Sort the top k elements in ascending order\n result = sorted(top_k)\n \n return result", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n\n Example 1:\n\n Input: arr = [-3, -4, 5], k = 3\n Output: [-4, -3, 5]\n\n Example 2:\n\n Input: arr = [4, -4, 4], k = 2\n Output: [4, 4]\n\n Example 3:\n\n Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1\n Output: [2]\n\n Note:\n 1. The length of the array will be in the range of [1, 1000].\n 2. The elements in the array will be in the range of [-1000, 1000].\n 3. 0 <= k <= len(arr)\n \"\"\"\n # Sort the array in descending order\n sorted_arr = sorted(arr, reverse=True)\n \n # Take the top k elements\n top_k = sorted_arr[:k]\n \n # Sort the top k elements in ascending order\n result = sorted(top_k)\n \n return result", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n\n Example 1:\n\n Input: arr = [-3, -4, 5], k = 3\n Output: [-4, -3, 5]\n\n Example 2:\n\n Input: arr = [4, -4, 4], k = 2\n Output: [4, 4]\n\n Example 3:\n\n Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1\n Output: [2]\n\n Note:\n 1. The length of the array will be in the range of [1, 1000].\n 2. The elements in the array will be in the range of [-1000, 1000].\n 3. 0 <= k <= len(arr)\n \"\"\"\n # Sort the array in descending order\n sorted_arr = sorted(arr, reverse=True)\n \n # Take the top k elements\n top_k = sorted_arr[:k]\n \n # Sort the top k elements in ascending order\n result = sorted(top_k)\n \n return result", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n\n Example 1:\n\n Input: arr = [-3, -4, 5], k = 3\n Output: [-4, -3, 5]\n\n Example 2:\n\n Input: arr = [4, -4, 4], k = 2\n Output: [4, 4]\n\n Example 3:\n\n Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1\n Output: [2]\n\n Note:\n 1. The length of the array will be in the range of [1, 1000].\n 2. The elements in the array will be in the range of [-1000, 1000].\n 3. 0 <= k <= len(arr)\n \"\"\"\n # Sort the array in descending order and then take the first k elements\n sorted_arr = sorted(arr, reverse=True)\n # Take the first k elements and sort them in ascending order\n result = sorted(sorted_arr[:k])\n return result", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n\n Example 1:\n\n Input: arr = [-3, -4, 5], k = 3\n Output: [-4, -3, 5]\n\n Example 2:\n\n Input: arr = [4, -4, 4], k = 2\n Output: [4, 4]\n\n Example 3:\n\n Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1\n Output: [2]\n\n Note:\n 1. The length of the array will be in the range of [1, 1000].\n 2. The elements in the array will be in the range of [-1000, 1000].\n 3. 0 <= k <= len(arr)\n \"\"\"\n # Sort the array in descending order\n sorted_arr = sorted(arr, reverse=True)\n \n # Take the top k elements\n top_k = sorted_arr[:k]\n \n # Sort the top k elements in ascending order\n result = sorted(top_k)\n \n return result", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n\n Example 1:\n\n Input: arr = [-3, -4, 5], k = 3\n Output: [-4, -3, 5]\n\n Example 2:\n\n Input: arr = [4, -4, 4], k = 2\n Output: [4, 4]\n\n Example 3:\n\n Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1\n Output: [2]\n\n Note:\n 1. The length of the array will be in the range of [1, 1000].\n 2. The elements in the array will be in the range of [-1000, 1000].\n 3. 0 <= k <= len(arr)\n \"\"\"\n # Sort the array in descending order\n sorted_arr = sorted(arr, reverse=True)\n \n # Take the top k elements\n top_k = sorted_arr[:k]\n \n # Sort the top k elements in ascending order\n result = sorted(top_k)\n \n return result", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n\n Example 1:\n\n Input: arr = [-3, -4, 5], k = 3\n Output: [-4, -3, 5]\n\n Example 2:\n\n Input: arr = [4, -4, 4], k = 2\n Output: [4, 4]\n\n Example 3:\n\n Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1\n Output: [2]\n\n Note:\n 1. The length of the array will be in the range of [1, 1000].\n 2. The elements in the array will be in the range of [-1000, 1000].\n 3. 0 <= k <= len(arr)\n \"\"\"\n # Sort the array in descending order\n sorted_arr = sorted(arr, reverse=True)\n \n # Take the top k elements\n top_k = sorted_arr[:k]\n \n # Sort the top k elements in ascending order\n result = sorted(top_k)\n \n return result", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n\n Example 1:\n\n Input: arr = [-3, -4, 5], k = 3\n Output: [-4, -3, 5]\n\n Example 2:\n\n Input: arr = [4, -4, 4], k = 2\n Output: [4, 4]\n\n Example 3:\n\n Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1\n Output: [2]\n\n Note:\n 1. The length of the array will be in the range of [1, 1000].\n 2. The elements in the array will be in the range of [-1000, 1000].\n 3. 0 <= k <= len(arr)\n \"\"\"\n # Sort the array in descending order\n sorted_arr = sorted(arr, reverse=True)\n \n # Take the top k elements\n top_k = sorted_arr[:k]\n \n # Sort the top k elements in ascending order\n result = sorted(top_k)\n \n return result", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n\n Example 1:\n\n Input: arr = [-3, -4, 5], k = 3\n Output: [-4, -3, 5]\n\n Example 2:\n\n Input: arr = [4, -4, 4], k = 2\n Output: [4, 4]\n\n Example 3:\n\n Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1\n Output: [2]\n\n Note:\n 1. The length of the array will be in the range of [1, 1000].\n 2. The elements in the array will be in the range of [-1000, 1000].\n 3. 0 <= k <= len(arr)\n \"\"\"\n # Sort the array in descending order\n sorted_arr = sorted(arr, reverse=True)\n \n # Take the top k elements\n top_k = sorted_arr[:k]\n \n # Sort the top k elements in ascending order\n result = sorted(top_k)\n \n return result", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n\n Example 1:\n\n Input: arr = [-3, -4, 5], k = 3\n Output: [-4, -3, 5]\n\n Example 2:\n\n Input: arr = [4, -4, 4], k = 2\n Output: [4, 4]\n\n Example 3:\n\n Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1\n Output: [2]\n\n Note:\n 1. The length of the array will be in the range of [1, 1000].\n 2. The elements in the array will be in the range of [-1000, 1000].\n 3. 0 <= k <= len(arr)\n \"\"\"\n # Sort the array in descending order\n sorted_arr = sorted(arr, reverse=True)\n \n # Take the top k elements\n top_k = sorted_arr[:k]\n \n # Sort the top k elements in ascending order\n result = sorted(top_k)\n \n return result", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n\n Example 1:\n\n Input: arr = [-3, -4, 5], k = 3\n Output: [-4, -3, 5]\n\n Example 2:\n\n Input: arr = [4, -4, 4], k = 2\n Output: [4, 4]\n\n Example 3:\n\n Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1\n Output: [2]\n\n Note:\n 1. The length of the array will be in the range of [1, 1000].\n 2. The elements in the array will be in the range of [-1000, 1000].\n 3. 0 <= k <= len(arr)\n \"\"\"\n # Sort the array in descending order\n sorted_arr = sorted(arr, reverse=True)\n \n # Take the top k elements\n top_k = sorted_arr[:k]\n \n # Sort the top k elements in ascending order\n result = sorted(top_k)\n \n return result", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n\n Example 1:\n\n Input: arr = [-3, -4, 5], k = 3\n Output: [-4, -3, 5]\n\n Example 2:\n\n Input: arr = [4, -4, 4], k = 2\n Output: [4, 4]\n\n Example 3:\n\n Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1\n Output: [2]\n\n Note:\n 1. The length of the array will be in the range of [1, 1000].\n 2. The elements in the array will be in the range of [-1000, 1000].\n 3. 0 <= k <= len(arr)\n \"\"\"\n # Sort the array in descending order\n sorted_arr = sorted(arr, reverse=True)\n \n # Take the top k elements\n top_k = sorted_arr[:k]\n \n # Sort the top k elements in ascending order\n result = sorted(top_k)\n \n return result", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n\n Example 1:\n\n Input: arr = [-3, -4, 5], k = 3\n Output: [-4, -3, 5]\n\n Example 2:\n\n Input: arr = [4, -4, 4], k = 2\n Output: [4, 4]\n\n Example 3:\n\n Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1\n Output: [2]\n\n Note:\n 1. The length of the array will be in the range of [1, 1000].\n 2. The elements in the array will be in the range of [-1000, 1000].\n 3. 0 <= k <= len(arr)\n \"\"\"\n # Sort the array in descending order\n sorted_arr = sorted(arr, reverse=True)\n \n # Take the first k elements\n max_k_elements = sorted_arr[:k]\n \n # Sort the k elements in ascending order\n result = sorted(max_k_elements)\n \n return result", "matching_cluster_idx": 6}]}, "HumanEval/121": {"dps": 78.02690582959642, "dps_norm": 57.142857142857146, "pass@1": 100.0, "profiled": [{"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n # Initialize the sum to 0\n total_sum = 0\n \n # Iterate over the list with index\n for index, value in enumerate(lst):\n # Check if the index is even and the value is odd\n if index % 2 == 0 and value % 2 != 0:\n total_sum += value\n \n return total_sum", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n # Initialize the sum to 0\n total_sum = 0\n \n # Iterate over the list with index\n for index, value in enumerate(lst):\n # Check if the index is even and the value is odd\n if index % 2 == 0 and value % 2 != 0:\n # Add the value to the total sum\n total_sum += value\n \n return total_sum", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n # Initialize the sum to 0\n total_sum = 0\n \n # Iterate over the list with index\n for index, value in enumerate(lst):\n # Check if the index is even and the value is odd\n if index % 2 == 0 and value % 2 != 0:\n total_sum += value\n \n return total_sum", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n # Initialize the sum to 0\n total_sum = 0\n \n # Iterate over the list with index\n for index, value in enumerate(lst):\n # Check if the index is even and the value is odd\n if index % 2 == 0 and value % 2 != 0:\n # Add the value to the total sum\n total_sum += value\n \n return total_sum", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n # Initialize the sum to 0\n total_sum = 0\n \n # Iterate over the list with index\n for index, value in enumerate(lst):\n # Check if the index is even and the value is odd\n if index % 2 == 0 and value % 2 != 0:\n # Add the value to the total sum\n total_sum += value\n \n return total_sum", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n # Initialize the sum to 0\n total_sum = 0\n \n # Iterate over the list with index\n for index, value in enumerate(lst):\n # Check if the index is even and the value is odd\n if index % 2 == 0 and value % 2 != 0:\n total_sum += value\n \n return total_sum", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n # Initialize the sum to 0\n total_sum = 0\n \n # Iterate over the list with index\n for index, value in enumerate(lst):\n # Check if the index is even and the value is odd\n if index % 2 == 0 and value % 2 != 0:\n total_sum += value\n \n return total_sum", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n # Initialize the sum to 0\n total_sum = 0\n \n # Iterate over the list with index\n for index, value in enumerate(lst):\n # Check if the index is even and the value is odd\n if index % 2 == 0 and value % 2 != 0:\n # Add the value to the total sum\n total_sum += value\n \n return total_sum", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n # Initialize the sum to 0\n total_sum = 0\n \n # Iterate over the list with index\n for index, value in enumerate(lst):\n # Check if the index is even and the value is odd\n if index % 2 == 0 and value % 2 != 0:\n # Add the value to the total sum\n total_sum += value\n \n return total_sum", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n # Initialize the sum to 0\n total_sum = 0\n \n # Iterate over the list with index\n for index, value in enumerate(lst):\n # Check if the index is even and the value is odd\n if index % 2 == 0 and value % 2 != 0:\n total_sum += value\n \n return total_sum", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n # Initialize the sum to 0\n total_sum = 0\n \n # Iterate over the list with index\n for index, value in enumerate(lst):\n # Check if the index is even and the value is odd\n if index % 2 == 0 and value % 2 != 0:\n total_sum += value\n \n return total_sum", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n # Initialize the sum to 0\n total_sum = 0\n \n # Iterate over the list with index\n for index, value in enumerate(lst):\n # Check if the index is even and the value is odd\n if index % 2 == 0 and value % 2 != 0:\n total_sum += value\n \n return total_sum", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n # Initialize the sum to 0\n total_sum = 0\n \n # Iterate over the list with index\n for index, value in enumerate(lst):\n # Check if the index is even and the value is odd\n if index % 2 == 0 and value % 2 != 0:\n # Add the value to the total sum\n total_sum += value\n \n return total_sum", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n # Initialize the sum to 0\n total_sum = 0\n \n # Iterate over the list with index\n for index, value in enumerate(lst):\n # Check if the index is even and the value is odd\n if index % 2 == 0 and value % 2 != 0:\n # Add the value to the total sum\n total_sum += value\n \n return total_sum", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n # Initialize the sum to 0\n total_sum = 0\n \n # Iterate over the list with index\n for index, value in enumerate(lst):\n # Check if the index is even and the value is odd\n if index % 2 == 0 and value % 2 != 0:\n # Add the value to the total sum\n total_sum += value\n \n return total_sum", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n # Initialize the sum to 0\n total_sum = 0\n \n # Iterate over the list with index\n for index, value in enumerate(lst):\n # Check if the index is even and the value is odd\n if index % 2 == 0 and value % 2 != 0:\n # Add the value to the total sum\n total_sum += value\n \n return total_sum", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n # Initialize the sum to 0\n total_sum = 0\n \n # Iterate over the list with index\n for index, value in enumerate(lst):\n # Check if the index is even and the value is odd\n if index % 2 == 0 and value % 2 != 0:\n total_sum += value\n \n return total_sum", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n # Initialize the sum to 0\n total_sum = 0\n \n # Iterate over the list with index\n for index, value in enumerate(lst):\n # Check if the index is even and the value is odd\n if index % 2 == 0 and value % 2 != 0:\n # Add the value to the total sum\n total_sum += value\n \n return total_sum", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n # Initialize the sum to 0\n total_sum = 0\n \n # Iterate over the list with index\n for index, value in enumerate(lst):\n # Check if the index is even and the value is odd\n if index % 2 == 0 and value % 2 != 0:\n total_sum += value\n \n return total_sum", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n # Initialize the sum to 0\n total_sum = 0\n \n # Iterate over the list with index\n for index, value in enumerate(lst):\n # Check if the index is even and the value is odd\n if index % 2 == 0 and value % 2 != 0:\n total_sum += value\n \n return total_sum", "matching_cluster_idx": 3}]}, "HumanEval/149": {"dps": 85.82677165354332, "dps_norm": 57.142857142857146, "pass@1": 100.0, "profiled": [{"solution": "def sorted_list_sum(lst):\n # Filter out strings with odd lengths\n filtered_list = [word for word in lst if len(word) % 2 == 0]\n \n # Sort the list first by length (ascending) and then alphabetically\n sorted_list = sorted(filtered_list, key=lambda x: (len(x), x))\n \n return sorted_list", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n # Filter out strings with odd lengths\n filtered_lst = [word for word in lst if len(word) % 2 == 0]\n \n # Sort the list first by length (ascending) and then alphabetically\n sorted_lst = sorted(filtered_lst, key=lambda x: (len(x), x))\n \n return sorted_lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n # Filter out strings with odd lengths\n filtered_list = [word for word in lst if len(word) % 2 == 0]\n \n # Sort the list first by length (ascending) and then alphabetically\n sorted_list = sorted(filtered_list, key=lambda x: (len(x), x))\n \n return sorted_list", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n # Filter out strings with odd lengths\n filtered_list = [word for word in lst if len(word) % 2 == 0]\n \n # Sort the filtered list first by length (ascending) and then alphabetically\n sorted_list = sorted(filtered_list, key=lambda x: (len(x), x))\n \n return sorted_list", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n # Filter out strings with odd lengths\n filtered_lst = [word for word in lst if len(word) % 2 == 0]\n \n # Sort the list first by length (ascending) and then alphabetically\n sorted_lst = sorted(filtered_lst, key=lambda x: (len(x), x))\n \n return sorted_lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n # Filter out strings with odd lengths\n filtered_list = [word for word in lst if len(word) % 2 == 0]\n \n # Sort the filtered list first by length (ascending) and then alphabetically\n sorted_list = sorted(filtered_list, key=lambda x: (len(x), x))\n \n return sorted_list", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n # Filter out strings with odd lengths\n filtered_list = [word for word in lst if len(word) % 2 == 0]\n \n # Sort the list first by length (ascending) and then alphabetically\n sorted_list = sorted(filtered_list, key=lambda x: (len(x), x))\n \n return sorted_list", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n # Filter out strings with odd lengths\n filtered_lst = [word for word in lst if len(word) % 2 == 0]\n \n # Sort the list first by length (ascending) and then alphabetically\n sorted_lst = sorted(filtered_lst, key=lambda x: (len(x), x))\n \n return sorted_lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n # Filter out strings with odd lengths\n filtered_lst = [word for word in lst if len(word) % 2 == 0]\n \n # Sort the filtered list first by length (ascending) and then alphabetically\n sorted_lst = sorted(filtered_lst, key=lambda x: (len(x), x))\n \n return sorted_lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n # Filter out strings with odd lengths\n filtered_lst = [word for word in lst if len(word) % 2 == 0]\n \n # Sort the list first by length (ascending) and then alphabetically\n sorted_lst = sorted(filtered_lst, key=lambda x: (len(x), x))\n \n return sorted_lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n # Filter out strings with odd lengths\n filtered_list = [word for word in lst if len(word) % 2 == 0]\n \n # Sort the list first by length (ascending) and then alphabetically\n sorted_list = sorted(filtered_list, key=lambda x: (len(x), x))\n \n return sorted_list", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n # Filter out strings with odd lengths\n filtered_list = [word for word in lst if len(word) % 2 == 0]\n \n # Sort the filtered list first by length (ascending) and then alphabetically\n sorted_list = sorted(filtered_list, key=lambda x: (len(x), x))\n \n return sorted_list", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n # Filter out strings with odd lengths\n filtered_list = [word for word in lst if len(word) % 2 == 0]\n \n # Sort the list first by length (ascending) and then alphabetically\n sorted_list = sorted(filtered_list, key=lambda x: (len(x), x))\n \n return sorted_list", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n # Filter out strings with odd lengths\n filtered_list = [word for word in lst if len(word) % 2 == 0]\n \n # Sort the list first by length (ascending) and then alphabetically\n sorted_list = sorted(filtered_list, key=lambda x: (len(x), x))\n \n return sorted_list", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n # Filter out strings with odd lengths\n filtered_lst = [word for word in lst if len(word) % 2 == 0]\n \n # Sort the list first by length (ascending) and then alphabetically\n sorted_lst = sorted(filtered_lst, key=lambda x: (len(x), x))\n \n return sorted_lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n # Filter out strings with odd lengths\n filtered_list = [word for word in lst if len(word) % 2 == 0]\n \n # Sort the list first by length (ascending) and then alphabetically\n sorted_list = sorted(filtered_list, key=lambda x: (len(x), x))\n \n return sorted_list", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n # Filter out strings with odd lengths\n filtered_list = [word for word in lst if len(word) % 2 == 0]\n \n # Sort the list first by length (ascending) and then alphabetically\n sorted_list = sorted(filtered_list, key=lambda x: (len(x), x))\n \n return sorted_list", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n # Filter out strings with odd lengths\n filtered_list = [word for word in lst if len(word) % 2 == 0]\n \n # Sort the list first by length (ascending) and then alphabetically\n sorted_list = sorted(filtered_list, key=lambda x: (len(x), x))\n \n return sorted_list", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n # Filter out strings with odd lengths\n filtered_list = [word for word in lst if len(word) % 2 == 0]\n \n # Sort the list first by length (ascending) and then alphabetically\n sorted_list = sorted(filtered_list, key=lambda x: (len(x), x))\n \n return sorted_list", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n # Filter out strings with odd lengths\n filtered_lst = [word for word in lst if len(word) % 2 == 0]\n \n # Sort the list first by length (ascending) and then alphabetically\n sorted_lst = sorted(filtered_lst, key=lambda x: (len(x), x))\n \n return sorted_lst", "matching_cluster_idx": 3}]}, "Mbpp/3": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def is_not_prime(n):\n \"\"\"\n Function to identify non-prime numbers.\n \n Args:\n n (int): The number to check.\n \n Returns:\n bool: True if the number is not prime, False otherwise.\n \"\"\"\n if n <= 1:\n return True\n if n == 2:\n return False\n if n % 2 == 0:\n return True\n for i in range(3, int(n**0.5) + 1, 2):\n if n % i == 0:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n \"\"\"\n Function to determine if a number is not prime.\n\n Args:\n n (int): The number to check.\n\n Returns:\n bool: True if the number is not prime, False otherwise.\n \"\"\"\n if n <= 1:\n return True\n if n == 2:\n return False\n if n % 2 == 0:\n return True\n for i in range(3, int(n**0.5) + 1, 2):\n if n % i == 0:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n \"\"\"\n Function to identify non-prime numbers.\n \n Args:\n n (int): The number to check.\n \n Returns:\n bool: True if the number is not prime, False otherwise.\n \"\"\"\n if n <= 1:\n return True\n if n == 2:\n return False\n if n % 2 == 0:\n return True\n for i in range(3, int(n**0.5) + 1, 2):\n if n % i == 0:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n \"\"\"\n Function to identify non-prime numbers.\n \n Args:\n n (int): The number to check.\n \n Returns:\n bool: True if the number is not prime, False otherwise.\n \"\"\"\n if n <= 1:\n return True\n if n == 2:\n return False\n if n % 2 == 0:\n return True\n for i in range(3, int(n**0.5) + 1, 2):\n if n % i == 0:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n \"\"\"\n Function to identify non-prime numbers.\n \n Args:\n n (int): The number to check.\n \n Returns:\n bool: True if the number is not prime, False otherwise.\n \"\"\"\n if n <= 1:\n return True\n if n == 2:\n return False\n if n % 2 == 0:\n return True\n for i in range(3, int(n**0.5) + 1, 2):\n if n % i == 0:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def is_prime(n):\n \"\"\"Check if a number is prime.\"\"\"\n if n <= 1:\n return False\n if n == 2:\n return True\n if n % 2 == 0:\n return False\n for i in range(3, int(n**0.5) + 1, 2):\n if n % i == 0:\n return False\n return True\ndef is_not_prime(n):\n \"\"\"Check if a number is not prime.\"\"\"\n return not is_prime(n)", "matching_cluster_idx": 7}, {"solution": "def is_prime(n):\n \"\"\"Check if a number is prime.\"\"\"\n if n <= 1:\n return False\n if n == 2:\n return True\n if n % 2 == 0:\n return False\n for i in range(3, int(n**0.5) + 1, 2):\n if n % i == 0:\n return False\n return True\ndef is_not_prime(n):\n \"\"\"Check if a number is not prime.\"\"\"\n return not is_prime(n)", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n \"\"\"\n Function to identify non-prime numbers.\n \n Args:\n n (int): The number to check.\n \n Returns:\n bool: True if the number is not prime, False otherwise.\n \"\"\"\n if n <= 1:\n return True\n if n == 2:\n return False\n if n % 2 == 0:\n return True\n for i in range(3, int(n**0.5) + 1, 2):\n if n % i == 0:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n \"\"\"\n Function to identify non-prime numbers.\n \n Args:\n n (int): The number to check.\n \n Returns:\n bool: True if the number is not prime, False if the number is prime.\n \"\"\"\n if n <= 1:\n return True\n if n == 2:\n return False # 2 is the only even prime number\n if n % 2 == 0:\n return True # All other even numbers are not prime\n \n # Check for factors from 3 to the square root of n\n for i in range(3, int(n**0.5) + 1, 2):\n if n % i == 0:\n return True\n \n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n \"\"\"\n Function to determine if a number is not prime.\n\n Args:\n n (int): The number to check.\n\n Returns:\n bool: True if the number is not prime, False otherwise.\n \"\"\"\n if n <= 1:\n return True\n if n == 2:\n return False\n if n % 2 == 0:\n return True\n for i in range(3, int(n**0.5) + 1, 2):\n if n % i == 0:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def is_prime(n):\n \"\"\"Check if a number is prime.\"\"\"\n if n <= 1:\n return False\n if n == 2:\n return True\n if n % 2 == 0:\n return False\n for i in range(3, int(n**0.5) + 1, 2):\n if n % i == 0:\n return False\n return True\ndef is_not_prime(n):\n \"\"\"Check if a number is not prime.\"\"\"\n return not is_prime(n)", "matching_cluster_idx": 7}, {"solution": "def is_prime(n):\n \"\"\"Check if a number is prime.\"\"\"\n if n <= 1:\n return False\n if n == 2:\n return True\n if n % 2 == 0:\n return False\n for i in range(3, int(n**0.5) + 1, 2):\n if n % i == 0:\n return False\n return True\ndef is_not_prime(n):\n \"\"\"Check if a number is not prime.\"\"\"\n return not is_prime(n)", "matching_cluster_idx": 7}, {"solution": "def is_prime(n):\n \"\"\"Check if a number is prime.\"\"\"\n if n <= 1:\n return False\n if n == 2:\n return True # 2 is the only even prime number\n if n % 2 == 0:\n return False # other even numbers are not prime\n for i in range(3, int(n**0.5) + 1, 2):\n if n % i == 0:\n return False\n return True\ndef is_not_prime(n):\n \"\"\"Check if a number is not prime.\"\"\"\n return not is_prime(n)", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n \"\"\"\n Function to check if a number is not prime.\n\n Args:\n n (int): The number to check.\n\n Returns:\n bool: True if the number is not prime, False otherwise.\n \"\"\"\n if n <= 1:\n return True\n if n == 2:\n return False\n if n % 2 == 0:\n return True\n for i in range(3, int(n**0.5) + 1, 2):\n if n % i == 0:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n \"\"\"\n Function to identify non-prime numbers.\n \n Parameters:\n n (int): The number to check for primality.\n \n Returns:\n bool: True if the number is not prime, False if it is prime.\n \"\"\"\n if n <= 1:\n return True\n if n == 2:\n return False\n if n % 2 == 0:\n return True\n for i in range(3, int(n**0.5) + 1, 2):\n if n % i == 0:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n \"\"\"\n Function to determine if a number is not prime.\n\n Args:\n n (int): The number to check.\n\n Returns:\n bool: True if the number is not prime, False otherwise.\n \"\"\"\n if n <= 1:\n return True\n if n == 2:\n return False\n if n % 2 == 0:\n return True\n for i in range(3, int(n**0.5) + 1, 2):\n if n % i == 0:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n \"\"\"\n Function to identify non-prime numbers.\n \n Args:\n n (int): The number to check.\n \n Returns:\n bool: True if the number is not prime, False otherwise.\n \"\"\"\n if n <= 1:\n return True\n if n == 2:\n return False\n if n % 2 == 0:\n return True\n for i in range(3, int(n**0.5) + 1, 2):\n if n % i == 0:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n \"\"\"\n Function to identify non-prime numbers.\n \n Args:\n n (int): The number to check.\n \n Returns:\n bool: True if the number is not prime, False otherwise.\n \"\"\"\n if n <= 1:\n return True\n if n == 2:\n return False\n if n % 2 == 0:\n return True\n for i in range(3, int(n**0.5) + 1, 2):\n if n % i == 0:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n \"\"\"\n Function to identify non-prime numbers.\n \n Args:\n n (int): The number to check.\n \n Returns:\n bool: True if the number is not prime, False otherwise.\n \"\"\"\n if n <= 1:\n return True\n if n == 2:\n return False\n if n % 2 == 0:\n return True\n for i in range(3, int(n**0.5) + 1, 2):\n if n % i == 0:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n \"\"\"\n Function to identify non-prime numbers.\n \n Args:\n n (int): The number to check.\n \n Returns:\n bool: True if the number is not prime, False otherwise.\n \"\"\"\n if n <= 1:\n return True\n if n == 2:\n return False\n if n % 2 == 0:\n return True\n for i in range(3, int(n**0.5) + 1, 2):\n if n % i == 0:\n return True\n return False", "matching_cluster_idx": 7}]}, "Mbpp/4": {"dps": 95.22184300341297, "dps_norm": 83.33333333333333, "pass@1": 100.0, "profiled": [{"solution": "import heapq\ndef heap_queue_largest(nums, n):\n # Use heapq.nlargest to find the n largest numbers\n largest_nums = heapq.nlargest(n, nums)\n return largest_nums", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(numbers, n):\n \"\"\"\n Find the n largest integers from a given list of numbers, returned in descending order.\n \n :param numbers: List of integers\n :param n: Number of largest integers to find\n :return: List of n largest integers in descending order\n \"\"\"\n # Use heapq.nlargest to find the n largest elements\n largest_elements = heapq.nlargest(n, numbers)\n \n # Return the elements in descending order\n return largest_elements", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n # Use heapq.nlargest to find the n largest numbers\n largest_n = heapq.nlargest(n, nums)\n return largest_n", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(numbers, n):\n # Use heapq.nlargest to find the n largest numbers\n largest_numbers = heapq.nlargest(n, numbers)\n return largest_numbers", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(numbers, n):\n # Use heapq.nlargest to find the n largest numbers\n largest_numbers = heapq.nlargest(n, numbers)\n return largest_numbers", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n # Use heapq.nlargest to find the n largest elements\n largest_elements = heapq.nlargest(n, nums)\n return largest_elements", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(numbers, n):\n # Use heapq.nlargest to find the n largest numbers\n largest_numbers = heapq.nlargest(n, numbers)\n return largest_numbers", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(numbers, n):\n \"\"\"\n Find the n largest integers from a given list of numbers, returned in descending order.\n \n :param numbers: List of integers\n :param n: Number of largest integers to find\n :return: List of n largest integers in descending order\n \"\"\"\n # Use heapq.nlargest to find the n largest elements\n largest_elements = heapq.nlargest(n, numbers)\n \n # Return the elements in descending order\n return largest_elements", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(numbers, n):\n # Use heapq.nlargest to find the n largest numbers\n largest_numbers = heapq.nlargest(n, numbers)\n return largest_numbers", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n # Use heapq.nlargest to find the n largest numbers\n largest_nums = heapq.nlargest(n, nums)\n return largest_nums", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(numbers, n):\n \"\"\"\n Find the n largest integers from a given list of numbers, returned in descending order.\n \n :param numbers: List of integers\n :param n: Number of largest integers to find\n :return: List of n largest integers in descending order\n \"\"\"\n # Use heapq.nlargest to find the n largest numbers\n largest_numbers = heapq.nlargest(n, numbers)\n \n # Return the largest numbers in descending order\n return largest_numbers", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(numbers, n):\n # Use heapq.nlargest to find the n largest numbers\n largest_numbers = heapq.nlargest(n, numbers)\n return largest_numbers", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n # Use heapq.nlargest to find the n largest elements\n largest_elements = heapq.nlargest(n, nums)\n return largest_elements", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n # Use heapq.nlargest to find the n largest numbers\n largest_nums = heapq.nlargest(n, nums)\n return largest_nums", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(numbers, n):\n \"\"\"\n Find the n largest integers from a given list of numbers, returned in descending order.\n \n :param numbers: List of integers\n :param n: Number of largest integers to find\n :return: List of n largest integers in descending order\n \"\"\"\n # Use heapq.nlargest to find the n largest numbers\n largest_numbers = heapq.nlargest(n, numbers)\n \n # Return the largest numbers in descending order\n return largest_numbers", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n # Use heapq.nlargest to find the n largest elements\n largest_elements = heapq.nlargest(n, nums)\n return largest_elements", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n # Use heapq.nlargest to find the n largest elements\n largest_n = heapq.nlargest(n, nums)\n return largest_n", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n # Use heapq.nlargest to find the n largest elements\n largest_n = heapq.nlargest(n, nums)\n return largest_n", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(numbers, n):\n # Use heapq.nlargest to find the n largest numbers\n largest_numbers = heapq.nlargest(n, numbers)\n return largest_numbers", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(numbers, n):\n # Use heapq.nlargest to find the n largest numbers\n largest_numbers = heapq.nlargest(n, numbers)\n return largest_numbers", "matching_cluster_idx": 9}]}, "Mbpp/9": {"dps": 94.93197278911563, "dps_norm": 59.5, "pass@1": 96.0, "profiled": [{"solution": "def find_Rotations(s):\n # Check if the string is empty or has only one character\n if len(s) <= 1:\n return 1\n \n # Create a double string to simulate rotations\n double_s = s + s\n \n # Iterate through the string to find the minimum rotations\n for i in range(1, len(s)):\n if s == double_s[i:i+len(s)]:\n return i\n \n # If no rotations are found, return the length of the string\n return len(s)", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(s):\n # Double the string to simulate rotation\n double_s = s + s\n \n # Iterate through each possible rotation\n for i in range(1, len(s) + 1):\n # Check if the substring matches the original string\n if double_s[i:i + len(s)] == s:\n return i\n \n # If no rotation matches, return -1 (though this should not happen for valid input)\n return -1", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(s: str) -> int:\n \"\"\"\n Find the minimum number of rotations (greater than 0) required to get the same string.\n \n Args:\n s (str): The input string.\n \n Returns:\n int: The minimum number of rotations required.\n \"\"\"\n # If the string is empty or has only one character, no rotation is needed\n if len(s) <= 1:\n return 0\n \n # Concatenate the string with itself\n double_s = s + s\n \n # Iterate through the string to find the minimum rotation\n for i in range(1, len(s)):\n if s == double_s[i:i+len(s)]:\n return i\n \n # If no rotation is found, return the length of the string (which is the worst case)\n return len(s)", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(s: str) -> int:\n \"\"\"\n Find the minimum number of rotations (greater than 0) required to get the same string.\n \n Args:\n s (str): The input string.\n \n Returns:\n int: The minimum number of rotations required.\n \"\"\"\n n = len(s)\n if n == 0:\n return 0\n \n # Double the string to simulate rotation\n doubled_s = s + s\n \n # Check for each rotation if it matches the original string\n for i in range(1, n + 1):\n if doubled_s[i:i+n] == s:\n return i\n \n return n", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(s):\n \"\"\"\n Find the minimum number of rotations (greater than 0) required to get the same string.\n \n Args:\n s (str): The input string.\n \n Returns:\n int: The minimum number of rotations required.\n \"\"\"\n n = len(s)\n if n == 0:\n return 0\n \n # Create a double string to simulate rotations\n double_s = s + s\n \n for i in range(1, n + 1):\n if s == double_s[i:i+n]:\n return i\n \n return n", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(s):\n \"\"\"\n Find the minimum number of rotations (greater than 0) required to get the same string.\n \n Args:\n s (str): The input string.\n \n Returns:\n int: The minimum number of rotations required.\n \"\"\"\n n = len(s)\n if n == 0:\n return 0\n \n # Create a double string to simulate rotation\n double_s = s + s\n \n # Check for each rotation if it matches the original string\n for i in range(1, n + 1):\n if double_s[i:i + n] == s:\n return i\n \n return n", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(s):\n # Check if the string is empty or has only one character\n if len(s) <= 1:\n return 0\n \n # Concatenate the string with itself\n double_s = s + s\n \n # Iterate through the string to find the minimum rotations\n for i in range(1, len(s)):\n if s == double_s[i:i+len(s)]:\n return i\n \n # If no rotations are found, return the length of the string\n return len(s)", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(s: str) -> int:\n \"\"\"\n Find the minimum number of rotations (greater than 0) required to get the same string.\n \n Args:\n s (str): The input string.\n \n Returns:\n int: The minimum number of rotations required.\n \"\"\"\n if len(s) == 0:\n return 0\n \n # Concatenate the string with itself\n double_s = s + s\n \n # Iterate through the string to find the minimum rotations\n for i in range(1, len(s) + 1):\n if s == double_s[i:i + len(s)]:\n return i\n \n return len(s)", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(s):\n \"\"\"\n Find the minimum number of rotations (greater than 0) required to get the same string.\n \n Args:\n s (str): The input string.\n \n Returns:\n int: The minimum number of rotations required.\n \"\"\"\n n = len(s)\n if n == 0:\n return 0\n \n # Create a double string to avoid modular arithmetic\n double_s = s + s\n \n # Check for each rotation if it matches the original string\n for i in range(1, n + 1):\n if s == double_s[i:i + n]:\n return i\n \n return n", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(s):\n \"\"\"\n Find the minimum number of rotations (greater than 0) required to get the same string.\n \n Args:\n s (str): The input string.\n \n Returns:\n int: The minimum number of rotations required.\n \"\"\"\n n = len(s)\n if n == 0:\n return 0\n \n # Create a double string to avoid modular arithmetic\n double_s = s + s\n \n # Check for each rotation if it matches the original string\n for i in range(1, n + 1):\n if s == double_s[i:i + n]:\n return i\n \n return n", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(s):\n \"\"\"\n Find the minimum number of rotations (greater than 0) required to get the same string.\n \n Args:\n s (str): The input string.\n \n Returns:\n int: The minimum number of rotations required.\n \"\"\"\n n = len(s)\n if n == 0:\n return 0\n \n # Create a double string to avoid modular arithmetic\n double_s = s + s\n \n # Check for each rotation if it matches the original string\n for i in range(1, n + 1):\n if s == double_s[i:i + n]:\n return i\n \n return n", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(s):\n \"\"\"\n Find the minimum number of rotations (greater than 0) required to get the same string.\n \n Args:\n s (str): The input string.\n \n Returns:\n int: The minimum number of rotations required.\n \"\"\"\n n = len(s)\n if n == 0:\n return 0\n \n # Create a double string to simulate rotation\n double_s = s + s\n \n for i in range(1, n + 1):\n if s == double_s[i:i + n]:\n return i\n \n return n", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(s):\n \"\"\"\n Find the minimum number of rotations (greater than 0) required to get the same string.\n \n Args:\n s (str): The input string.\n \n Returns:\n int: The minimum number of rotations required.\n \"\"\"\n n = len(s)\n if n == 0:\n return 0\n \n # Create a double string to avoid modular arithmetic\n double_s = s + s\n \n # Check for each rotation if it matches the original string\n for i in range(1, n + 1):\n if s == double_s[i:i + n]:\n return i\n \n return n", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(s):\n \"\"\"\n Find the minimum number of rotations (greater than 0) required to get the same string.\n \n Args:\n s (str): The input string.\n \n Returns:\n int: The minimum number of rotations required.\n \"\"\"\n n = len(s)\n if n == 0:\n return 0\n \n # Create a double string to avoid modular arithmetic\n double_s = s + s\n \n # Check for each rotation if it matches the original string\n for i in range(1, n + 1):\n if s == double_s[i:i + n]:\n return i\n \n return n", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(s: str) -> int:\n \"\"\"\n Find the minimum number of rotations (greater than 0) required to get the same string.\n\n Args:\n s (str): The input string.\n\n Returns:\n int: The minimum number of rotations required.\n \"\"\"\n # If the string is empty or has only one character, no rotation is needed.\n if len(s) <= 1:\n return 0\n \n # Check for each possible rotation\n for i in range(1, len(s)):\n # Perform the rotation\n rotated = s[i:] + s[:i]\n # If the rotated string matches the original, return the number of rotations\n if rotated == s:\n return i\n \n # If no rotations match, return the length of the string (which is the worst case)\n return len(s)", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(s: str) -> int:\n \"\"\"\n Find the minimum number of rotations (greater than 0) required to get the same string.\n \n Args:\n s (str): The input string.\n \n Returns:\n int: The minimum number of rotations required.\n \"\"\"\n n = len(s)\n if n == 0:\n return 0\n \n # Double the string to simulate rotation\n doubled_s = s + s\n \n # Check for each rotation if it matches the original string\n for i in range(1, n + 1):\n if doubled_s[i:i+n] == s:\n return i\n \n return n", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(s: str) -> int:\n \"\"\"\n Find the minimum number of rotations (greater than 0) required to get the same string.\n \n Args:\n s (str): The input string.\n \n Returns:\n int: The minimum number of rotations required.\n \"\"\"\n # If the string is empty, no rotations are needed\n if not s:\n return 0\n \n # Concatenate the string with itself\n double_s = s + s\n \n # Iterate through the string and check for rotations\n for i in range(1, len(s)):\n if s == double_s[i:i+len(s)]:\n return i\n \n # If no rotations are found, return the length of the string\n return len(s)", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(s):\n \"\"\"\n Find the minimum number of rotations (greater than 0) required to get the same string.\n \n Args:\n s (str): The input string.\n \n Returns:\n int: The minimum number of rotations required.\n \"\"\"\n n = len(s)\n if n == 0:\n return 0\n \n # Create a double string to simulate rotation\n double_s = s + s\n \n # Check for each rotation if it matches the original string\n for i in range(1, n + 1):\n if s == double_s[i:i + n]:\n return i\n \n return n", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(s):\n \"\"\"\n Find the minimum number of rotations (greater than 0) required to get the same string.\n \n Args:\n s (str): The input string.\n \n Returns:\n int: The minimum number of rotations required.\n \"\"\"\n n = len(s)\n if n == 0:\n return 0\n \n # Create a double string to simulate rotation\n double_s = s + s\n \n for i in range(1, n + 1):\n if s == double_s[i:i+n]:\n return i\n \n return n", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(s):\n \"\"\"\n Find the minimum number of rotations (greater than 0) required to get the same string.\n \n Args:\n s (str): The input string.\n \n Returns:\n int: The minimum number of rotations required.\n \"\"\"\n n = len(s)\n if n == 0:\n return 0\n \n # Create a double string to simulate rotation\n double_s = s + s\n \n # Check for each rotation if it matches the original string\n for i in range(1, n + 1):\n if double_s[i:i + n] == s:\n return i\n \n return n", "matching_cluster_idx": 5}]}, "Mbpp/11": {"dps": 25.448028673835125, "dps_norm": 88.88888888888889, "pass@1": 99.0, "profiled": [{"solution": "def remove_Occ(s, char):\n # Find the first occurrence of the character\n first_index = s.find(char)\n # Find the last occurrence of the character\n last_index = s.rfind(char)\n \n # If the character is not found in the string, return the original string\n if first_index == -1:\n return s\n \n # Remove the first occurrence\n s = s[:first_index] + s[first_index + 1:]\n \n # If the character was only present once, return the modified string\n if first_index == last_index:\n return s\n \n # Remove the last occurrence\n last_index = s.rfind(char)\n s = s[:last_index] + s[last_index + 1:]\n \n return s", "matching_cluster_idx": 7}, {"solution": "def remove_Occ(s, char):\n # Find the first occurrence of the character\n first_index = s.find(char)\n # Find the last occurrence of the character\n last_index = s.rfind(char)\n \n # If the character is not found in the string, return the original string\n if first_index == -1:\n return s\n \n # Remove the first occurrence\n s = s[:first_index] + s[first_index + 1:]\n \n # If the character was only present once, return the modified string\n if first_index == last_index:\n return s\n \n # Remove the last occurrence\n last_index = s.rfind(char)\n s = s[:last_index] + s[last_index + 1:]\n \n return s", "matching_cluster_idx": 7}, {"solution": "def remove_Occ(s, char):\n # Find the first occurrence of the character\n first_index = s.find(char)\n \n # Find the last occurrence of the character\n last_index = s.rfind(char)\n \n # If the character is not found in the string, return the original string\n if first_index == -1:\n return s\n \n # Remove the first occurrence\n s = s[:first_index] + s[first_index + 1:]\n \n # If the character was only present once, return the modified string\n if first_index == last_index:\n return s\n \n # Remove the last occurrence\n last_index = s.rfind(char)\n s = s[:last_index] + s[last_index + 1:]\n \n return s", "matching_cluster_idx": 7}, {"solution": "def remove_Occ(s, char):\n # Find the first occurrence of the character\n first_index = s.find(char)\n # Find the last occurrence of the character\n last_index = s.rfind(char)\n \n # If the character is not found in the string, return the original string\n if first_index == -1:\n return s\n \n # Remove the first occurrence\n s = s[:first_index] + s[first_index + 1:]\n \n # If the character was only present once, return the modified string\n if first_index == last_index:\n return s\n \n # Remove the last occurrence\n last_index = s.rfind(char)\n s = s[:last_index] + s[last_index + 1:]\n \n return s", "matching_cluster_idx": 7}, {"solution": "def remove_Occ(s, char):\n # Find the first occurrence of the character\n first_index = s.find(char)\n # Find the last occurrence of the character\n last_index = s.rfind(char)\n \n # If the character is not found in the string, return the original string\n if first_index == -1:\n return s\n \n # Remove the first occurrence\n s = s[:first_index] + s[first_index + 1:]\n \n # If the character was only present once, return the modified string\n if first_index == last_index:\n return s\n \n # Remove the last occurrence\n last_index = s.rfind(char)\n s = s[:last_index] + s[last_index + 1:]\n \n return s", "matching_cluster_idx": 7}, {"solution": "def remove_Occ(s, char):\n # Find the first occurrence of the character\n first_index = s.find(char)\n # Find the last occurrence of the character\n last_index = s.rfind(char)\n \n # If the character is not found in the string, return the original string\n if first_index == -1:\n return s\n \n # Remove the first occurrence\n s = s[:first_index] + s[first_index + 1:]\n \n # If the character was only present once, return the modified string\n if first_index == last_index:\n return s\n \n # Remove the last occurrence\n last_index -= 1 # Adjust the index after removing the first occurrence\n s = s[:last_index] + s[last_index + 1:]\n \n return s", "matching_cluster_idx": 7}, {"solution": "def remove_Occ(s, char):\n # Find the first occurrence of the character\n first_index = s.find(char)\n # Find the last occurrence of the character\n last_index = s.rfind(char)\n \n # If the character is not found, return the original string\n if first_index == -1:\n return s\n \n # Remove the first occurrence\n s = s[:first_index] + s[first_index + 1:]\n \n # If the character was only present once, return the modified string\n if first_index == last_index:\n return s\n \n # Remove the last occurrence\n last_index = s.rfind(char)\n s = s[:last_index] + s[last_index + 1:]\n \n return s", "matching_cluster_idx": 7}, {"solution": "def remove_Occ(s, char):\n # Find the first and last occurrence of the character\n first_index = s.find(char)\n last_index = s.rfind(char)\n \n # If the character is not found, return the original string\n if first_index == -1:\n return s\n \n # Remove the first occurrence\n s = s[:first_index] + s[first_index + 1:]\n \n # Remove the last occurrence (if it's different from the first occurrence)\n if last_index != -1 and last_index != first_index:\n last_index -= 1 # Adjust index after removing the first occurrence\n s = s[:last_index] + s[last_index + 1:]\n \n return s", "matching_cluster_idx": 7}, {"solution": "def remove_Occ(s, char):\n # Find the first occurrence of the character\n first_index = s.find(char)\n \n # Find the last occurrence of the character\n last_index = s.rfind(char)\n \n # If the character is not found in the string, return the original string\n if first_index == -1:\n return s\n \n # Remove the first occurrence\n if first_index != -1:\n s = s[:first_index] + s[first_index + 1:]\n \n # Remove the last occurrence\n if last_index != -1:\n last_index = s.rfind(char) # Recalculate the last index after removing the first occurrence\n if last_index != -1:\n s = s[:last_index] + s[last_index + 1:]\n \n return s", "matching_cluster_idx": 7}, {"solution": "def remove_Occ(s, char):\n # Find the first occurrence of the character\n first_index = s.find(char)\n # Find the last occurrence of the character\n last_index = s.rfind(char)\n \n # If the character is not found in the string, return the original string\n if first_index == -1:\n return s\n \n # Remove the first occurrence\n s = s[:first_index] + s[first_index + 1:]\n \n # If the character was only present once, return the modified string\n if first_index == last_index:\n return s\n \n # Remove the last occurrence\n last_index = s.rfind(char)\n s = s[:last_index] + s[last_index + 1:]\n \n return s", "matching_cluster_idx": 7}, {"solution": "def remove_Occ(s, char):\n # Find the first and last occurrence of the character\n first_index = s.find(char)\n last_index = s.rfind(char)\n \n # If the character is not found, return the original string\n if first_index == -1:\n return s\n \n # Remove the first occurrence\n s = s[:first_index] + s[first_index + 1:]\n \n # Remove the last occurrence (if it's different from the first)\n last_index = s.rfind(char)\n if last_index != -1:\n s = s[:last_index] + s[last_index + 1:]\n \n return s", "matching_cluster_idx": 7}, {"solution": "def remove_Occ(s, char):\n # Find the first occurrence of the character\n first_index = s.find(char)\n \n # Find the last occurrence of the character\n last_index = s.rfind(char)\n \n # If the character is not found in the string, return the original string\n if first_index == -1:\n return s\n \n # Remove the first occurrence\n s = s[:first_index] + s[first_index + 1:]\n \n # If the character was only present once, return the modified string\n if first_index == last_index:\n return s\n \n # Remove the last occurrence\n last_index = s.rfind(char)\n s = s[:last_index] + s[last_index + 1:]\n \n return s", "matching_cluster_idx": 7}, {"solution": "def remove_Occ(s, char):\n # Find the first occurrence of the character\n first_index = s.find(char)\n \n # Find the last occurrence of the character\n last_index = s.rfind(char)\n \n # If the character is not found in the string, return the original string\n if first_index == -1:\n return s\n \n # Remove the first occurrence\n if first_index != -1:\n s = s[:first_index] + s[first_index + 1:]\n \n # Remove the last occurrence\n if last_index != -1:\n last_index = s.rfind(char) # Recalculate the last index after removing the first occurrence\n if last_index != -1:\n s = s[:last_index] + s[last_index + 1:]\n \n return s", "matching_cluster_idx": 7}, {"solution": "def remove_Occ(s, char):\n # Find the first occurrence of the character\n first_index = s.find(char)\n \n # Find the last occurrence of the character\n last_index = s.rfind(char)\n \n # If the character is not found, return the original string\n if first_index == -1:\n return s\n \n # Remove the first occurrence\n s = s[:first_index] + s[first_index + 1:]\n \n # If the character was only present once, return the modified string\n if first_index == last_index:\n return s\n \n # Remove the last occurrence\n last_index = s.rfind(char)\n s = s[:last_index] + s[last_index + 1:]\n \n return s", "matching_cluster_idx": 7}, {"solution": "def remove_Occ(s, char):\n # Find the first occurrence of the character\n first_index = s.find(char)\n \n # Find the last occurrence of the character\n last_index = s.rfind(char)\n \n # If the character is not found, return the original string\n if first_index == -1:\n return s\n \n # Remove the first occurrence\n s = s[:first_index] + s[first_index + 1:]\n \n # Remove the last occurrence (if it's different from the first occurrence)\n if last_index != -1 and last_index != first_index:\n last_index -= 1 # Adjust index after removing the first occurrence\n s = s[:last_index] + s[last_index + 1:]\n \n return s", "matching_cluster_idx": 7}, {"solution": "def remove_Occ(s, char):\n # Find the first occurrence of the character\n first_index = s.find(char)\n # Find the last occurrence of the character\n last_index = s.rfind(char)\n \n # If the character is not found, return the original string\n if first_index == -1:\n return s\n \n # Remove the first occurrence\n s = s[:first_index] + s[first_index + 1:]\n \n # If the character was only present once, return the modified string\n if first_index == last_index:\n return s\n \n # Remove the last occurrence\n last_index = s.rfind(char)\n s = s[:last_index] + s[last_index + 1:]\n \n return s", "matching_cluster_idx": 7}, {"solution": "def remove_Occ(s, char):\n # Find the first and last occurrence of the character\n first_index = s.find(char)\n last_index = s.rfind(char)\n \n # If the character is not found, return the original string\n if first_index == -1:\n return s\n \n # Remove the first occurrence\n s = s[:first_index] + s[first_index+1:]\n \n # Remove the last occurrence (if it's different from the first occurrence)\n if last_index != -1 and last_index != first_index:\n last_index -= 1 # Adjust index after removing the first occurrence\n s = s[:last_index] + s[last_index+1:]\n \n return s", "matching_cluster_idx": 7}, {"solution": "def remove_Occ(s, char):\n # Find the first occurrence of the character\n first_index = s.find(char)\n # Find the last occurrence of the character\n last_index = s.rfind(char)\n \n # If the character is not found in the string, return the original string\n if first_index == -1:\n return s\n \n # Remove the first occurrence\n if first_index != -1:\n s = s[:first_index] + s[first_index + 1:]\n \n # Remove the last occurrence\n if last_index != -1:\n last_index = s.rfind(char) # Recalculate the last index after removing the first occurrence\n if last_index != -1:\n s = s[:last_index] + s[last_index + 1:]\n \n return s", "matching_cluster_idx": 7}, {"solution": "def remove_Occ(s, char):\n # Find the first occurrence of the character\n first_index = s.find(char)\n # Find the last occurrence of the character\n last_index = s.rfind(char)\n \n # If the character is not found in the string, return the original string\n if first_index == -1:\n return s\n \n # Remove the first occurrence\n if first_index != -1:\n s = s[:first_index] + s[first_index + 1:]\n \n # Remove the last occurrence\n if last_index != -1:\n # Since the first occurrence has been removed, we need to adjust the index\n last_index = s.rfind(char)\n if last_index != -1:\n s = s[:last_index] + s[last_index + 1:]\n \n return s", "matching_cluster_idx": 7}, {"solution": "def remove_Occ(s, char):\n # Find the first occurrence of the character\n first_index = s.find(char)\n # Find the last occurrence of the character\n last_index = s.rfind(char)\n \n # If the character is not found, return the original string\n if first_index == -1:\n return s\n \n # Remove the first occurrence\n s = s[:first_index] + s[first_index + 1:]\n \n # If the character was only present once, return the modified string\n if first_index == last_index:\n return s\n \n # Remove the last occurrence\n last_index = s.rfind(char)\n s = s[:last_index] + s[last_index + 1:]\n \n return s", "matching_cluster_idx": 7}]}, "Mbpp/12": {"dps": 74.28571428571429, "dps_norm": 98.125, "pass@1": 100.0, "profiled": [{"solution": "def sort_matrix(matrix):\n # Calculate the sum of each row and pair it with the row index\n row_sums = [(sum(row), i) for i, row in enumerate(matrix)]\n \n # Sort the rows based on the sum of each row\n sorted_rows = sorted(row_sums, key=lambda x: x[0])\n \n # Extract the sorted rows from the original matrix\n sorted_matrix = [matrix[i] for _, i in sorted_rows]\n \n return sorted_matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Calculate the sum of each row and pair it with the row index\n row_sums = [(sum(row), i) for i, row in enumerate(matrix)]\n \n # Sort the rows based on the sum of the rows\n sorted_rows = sorted(row_sums, key=lambda x: x[0])\n \n # Extract the sorted rows from the original matrix\n sorted_matrix = [matrix[i] for _, i in sorted_rows]\n \n return sorted_matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Calculate the sum of each row and pair it with the row index\n row_sums = [(sum(row), i) for i, row in enumerate(matrix)]\n \n # Sort the rows based on the sum of each row\n sorted_rows = sorted(row_sums, key=lambda x: x[0])\n \n # Extract the sorted rows from the original matrix\n sorted_matrix = [matrix[i] for _, i in sorted_rows]\n \n return sorted_matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Calculate the sum of each row and pair it with the row index\n row_sums = [(sum(row), i) for i, row in enumerate(matrix)]\n \n # Sort the rows based on the sum of each row\n sorted_rows = sorted(row_sums, key=lambda x: x[0])\n \n # Extract the sorted rows from the original matrix\n sorted_matrix = [matrix[i] for _, i in sorted_rows]\n \n return sorted_matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Calculate the sum of each row and pair it with the row index\n row_sums = [(sum(row), i) for i, row in enumerate(matrix)]\n \n # Sort the rows based on the sum of each row\n sorted_rows = sorted(row_sums, key=lambda x: x[0])\n \n # Extract the sorted rows from the original matrix\n sorted_matrix = [matrix[i] for _, i in sorted_rows]\n \n return sorted_matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Calculate the sum of each row and pair it with the row index\n row_sums = [(sum(row), i) for i, row in enumerate(matrix)]\n \n # Sort the rows based on the sum of each row\n sorted_rows = sorted(row_sums, key=lambda x: x[0])\n \n # Extract the sorted rows from the original matrix\n sorted_matrix = [matrix[i] for _, i in sorted_rows]\n \n return sorted_matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Create a list of tuples where each tuple is (sum of row, row)\n rows_with_sums = [(sum(row), row) for row in matrix]\n \n # Sort the list of tuples by the sum of the row (first element of the tuple)\n rows_with_sums.sort(key=lambda x: x[0])\n \n # Extract the sorted rows from the sorted list of tuples\n sorted_matrix = [row for _, row in rows_with_sums]\n \n return sorted_matrix", "matching_cluster_idx": 14}, {"solution": "def sort_matrix(matrix):\n # Calculate the sum of each row and pair it with the row index\n row_sums = [(sum(row), i) for i, row in enumerate(matrix)]\n \n # Sort the rows based on the sum of each row\n sorted_rows = sorted(row_sums, key=lambda x: x[0])\n \n # Extract the sorted rows from the original matrix\n sorted_matrix = [matrix[i] for _, i in sorted_rows]\n \n return sorted_matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Calculate the sum of each row and pair it with the row index\n row_sums = [(sum(row), i) for i, row in enumerate(matrix)]\n \n # Sort the rows based on the sum of the rows\n sorted_rows = sorted(row_sums, key=lambda x: x[0])\n \n # Extract the sorted rows from the original matrix\n sorted_matrix = [matrix[i] for _, i in sorted_rows]\n \n return sorted_matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Calculate the sum of each row and pair it with the row index\n row_sums = [(sum(row), index) for index, row in enumerate(matrix)]\n \n # Sort the rows based on the sum of each row\n sorted_rows = sorted(row_sums, key=lambda x: x[0])\n \n # Extract the sorted rows from the original matrix\n sorted_matrix = [matrix[index] for _, index in sorted_rows]\n \n return sorted_matrix", "matching_cluster_idx": 14}, {"solution": "def sort_matrix(matrix):\n # Calculate the sum of each row and pair it with the row index\n row_sums = [(sum(row), i) for i, row in enumerate(matrix)]\n \n # Sort the rows based on the sum of each row\n sorted_rows = sorted(row_sums, key=lambda x: x[0])\n \n # Extract the sorted rows from the original matrix\n sorted_matrix = [matrix[i] for _, i in sorted_rows]\n \n return sorted_matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Calculate the sum of each row and pair it with the row index\n row_sums = [(sum(row), i) for i, row in enumerate(matrix)]\n \n # Sort the rows based on the sum of the rows\n sorted_rows = sorted(row_sums, key=lambda x: x[0])\n \n # Extract the sorted rows from the original matrix\n sorted_matrix = [matrix[i] for _, i in sorted_rows]\n \n return sorted_matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Calculate the sum of each row and pair it with the row index\n row_sums = [(sum(row), index) for index, row in enumerate(matrix)]\n \n # Sort the rows based on the sum of the rows\n sorted_rows = sorted(row_sums, key=lambda x: x[0])\n \n # Extract the sorted rows from the original matrix\n sorted_matrix = [matrix[index] for _, index in sorted_rows]\n \n return sorted_matrix", "matching_cluster_idx": 14}, {"solution": "def sort_matrix(matrix):\n # Calculate the sum of each row and pair it with the row index\n row_sums = [(sum(row), i) for i, row in enumerate(matrix)]\n \n # Sort the rows based on the sum of each row\n sorted_rows = sorted(row_sums, key=lambda x: x[0])\n \n # Extract the sorted rows from the original matrix\n sorted_matrix = [matrix[i] for _, i in sorted_rows]\n \n return sorted_matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Create a list of tuples where each tuple is (sum of row, row)\n rows_with_sums = [(sum(row), row) for row in matrix]\n \n # Sort the list of tuples by the sum of the row (first element of the tuple)\n rows_with_sums.sort(key=lambda x: x[0])\n \n # Extract the sorted rows from the sorted list of tuples\n sorted_matrix = [row for _, row in rows_with_sums]\n \n return sorted_matrix", "matching_cluster_idx": 14}, {"solution": "def sort_matrix(matrix):\n # Calculate the sum of each row and pair it with the row index\n row_sums = [(sum(row), i) for i, row in enumerate(matrix)]\n \n # Sort the rows based on the sum (and index for stability)\n sorted_rows = sorted(row_sums, key=lambda x: x[0])\n \n # Extract the sorted rows from the original matrix\n sorted_matrix = [matrix[i] for _, i in sorted_rows]\n \n return sorted_matrix", "matching_cluster_idx": 14}, {"solution": "def sort_matrix(matrix):\n # Calculate the sum of each row and pair it with the row index\n row_sums = [(sum(row), i) for i, row in enumerate(matrix)]\n \n # Sort the rows based on the sum of each row\n sorted_rows = sorted(row_sums, key=lambda x: x[0])\n \n # Extract the sorted rows from the original matrix\n sorted_matrix = [matrix[i] for _, i in sorted_rows]\n \n return sorted_matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Calculate the sum of each row and pair it with the row index\n row_sums = [(sum(row), i) for i, row in enumerate(matrix)]\n \n # Sort the rows based on the sum of each row\n sorted_rows = sorted(row_sums, key=lambda x: x[0])\n \n # Extract the sorted rows from the original matrix\n sorted_matrix = [matrix[i] for _, i in sorted_rows]\n \n return sorted_matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Calculate the sum of each row and pair it with the row index\n row_sums = [(sum(row), i) for i, row in enumerate(matrix)]\n \n # Sort the rows based on the sum of each row\n sorted_row_sums = sorted(row_sums, key=lambda x: x[0])\n \n # Create the sorted matrix based on the sorted row indices\n sorted_matrix = [matrix[i] for _, i in sorted_row_sums]\n \n return sorted_matrix", "matching_cluster_idx": 14}, {"solution": "def sort_matrix(matrix):\n # Calculate the sum of each row and pair it with the row index\n row_sums = [(sum(row), i) for i, row in enumerate(matrix)]\n \n # Sort the rows based on the sum of the rows\n sorted_rows = sorted(row_sums, key=lambda x: x[0])\n \n # Extract the sorted rows from the original matrix\n sorted_matrix = [matrix[i] for _, i in sorted_rows]\n \n return sorted_matrix", "matching_cluster_idx": 15}]}, "Mbpp/16": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 98.0, "profiled": [{"solution": "import re\ndef text_lowercase_underscore(input_string):\n # Define the regular expression pattern for sequences of lowercase letters joined with an underscore\n pattern = r'^[a-z]+(_[a-z]+)*$'\n \n # Use re.match to check if the input string matches the pattern\n if re.match(pattern, input_string):\n return True\n else:\n return False", "matching_cluster_idx": 7}, {"solution": "import re\ndef text_lowercase_underscore(input_string):\n # Regular expression to match sequences of lowercase letters joined with an underscore\n pattern = r'^[a-z]+(_[a-z]+)*$'\n \n # Use re.match to check if the entire string matches the pattern\n if re.match(pattern, input_string):\n return True\n else:\n return False", "matching_cluster_idx": 7}, {"solution": "import re\ndef text_lowercase_underscore(input_string):\n # Regular expression to match sequences of lowercase letters joined with an underscore\n pattern = r'^[a-z]+(_[a-z]+)*$'\n \n # Use re.match to check if the entire string matches the pattern\n if re.match(pattern, input_string):\n return True\n else:\n return False", "matching_cluster_idx": 7}, {"solution": "import re\ndef text_lowercase_underscore(input_string):\n # Regular expression to match sequences of lowercase letters joined with an underscore\n pattern = r'^[a-z]+(_[a-z]+)*$'\n \n # Use re.match to check if the entire string matches the pattern\n if re.match(pattern, input_string):\n return True\n else:\n return False", "matching_cluster_idx": 7}, {"solution": "import re\ndef text_lowercase_underscore(input_string):\n # Define the regular expression pattern\n pattern = r'^[a-z]+(_[a-z]+)*$'\n \n # Use re.match to check if the input string matches the pattern\n if re.match(pattern, input_string):\n return True\n else:\n return False", "matching_cluster_idx": 7}, {"solution": "import re\ndef text_lowercase_underscore(input_string):\n # Regular expression to match sequences of lowercase letters joined with an underscore\n pattern = r'^[a-z]+(_[a-z]+)*$'\n \n # Use re.match to check if the entire string matches the pattern\n if re.match(pattern, input_string):\n return True\n else:\n return False", "matching_cluster_idx": 7}, {"solution": "import re\ndef text_lowercase_underscore(input_string):\n # Define the regular expression pattern for sequences of lowercase letters joined with an underscore\n pattern = r'^[a-z]+(_[a-z]+)*$'\n \n # Use re.match to check if the input string matches the pattern\n if re.match(pattern, input_string):\n return True\n else:\n return False", "matching_cluster_idx": 7}, {"solution": "import re\ndef text_lowercase_underscore(input_string):\n # Regular expression to match sequences of lowercase letters joined with an underscore\n pattern = r'^[a-z]+(_[a-z]+)*$'\n \n # Use re.match to check if the entire string matches the pattern\n if re.match(pattern, input_string):\n return True\n else:\n return False", "matching_cluster_idx": 7}, {"solution": "import re\ndef text_lowercase_underscore(input_string):\n # Define the regular expression pattern\n pattern = r'^[a-z]+(_[a-z]+)*$'\n \n # Use re.match to check if the input string matches the pattern\n if re.match(pattern, input_string):\n return True\n else:\n return False", "matching_cluster_idx": 7}, {"solution": "import re\ndef text_lowercase_underscore(input_string):\n # Regular expression to match sequences of lowercase letters joined with an underscore\n pattern = r'^[a-z]+(_[a-z]+)*$'\n \n # Use re.match to check if the entire string matches the pattern\n if re.match(pattern, input_string):\n return True\n else:\n return False", "matching_cluster_idx": 7}, {"solution": "import re\ndef text_lowercase_underscore(input_string):\n # Define the regular expression pattern for sequences of lowercase letters joined with an underscore\n pattern = r'^[a-z]+(_[a-z]+)*$'\n \n # Use re.match to check if the input string matches the pattern\n if re.match(pattern, input_string):\n return True\n else:\n return False", "matching_cluster_idx": 7}, {"solution": "import re\ndef text_lowercase_underscore(input_string):\n # Define the regular expression pattern\n pattern = r'^[a-z]+(_[a-z]+)*$'\n \n # Use re.match to check if the input string matches the pattern\n if re.match(pattern, input_string):\n return True\n else:\n return False", "matching_cluster_idx": 7}, {"solution": "import re\ndef text_lowercase_underscore(input_string):\n \"\"\"\n Returns True if the input string contains sequences of lowercase letters joined with an underscore,\n and False otherwise.\n \"\"\"\n # Define the regular expression pattern\n pattern = r'^[a-z]+(_[a-z]+)*$'\n \n # Use re.match to check if the input string matches the pattern\n if re.match(pattern, input_string):\n return True\n else:\n return False", "matching_cluster_idx": 7}, {"solution": "import re\ndef text_lowercase_underscore(text):\n \"\"\"\n Returns True if the input string contains sequences of lowercase letters joined with an underscore,\n and False otherwise.\n \"\"\"\n # Regular expression to match sequences of lowercase letters joined with an underscore\n pattern = r'^[a-z]+(_[a-z]+)*$'\n \n # Use re.match to check if the entire string matches the pattern\n return bool(re.match(pattern, text))", "matching_cluster_idx": 7}, {"solution": "import re\ndef text_lowercase_underscore(input_string):\n # Regular expression to match sequences of lowercase letters joined with an underscore\n pattern = r'^[a-z]+(_[a-z]+)*$'\n \n # Use re.match to check if the entire string matches the pattern\n return bool(re.match(pattern, input_string))", "matching_cluster_idx": 7}, {"solution": "import re\ndef text_lowercase_underscore(input_string):\n # Regular expression to match sequences of lowercase letters joined with an underscore\n pattern = r'^[a-z]+(_[a-z]+)*$'\n \n # Use re.match to check if the entire string matches the pattern\n if re.match(pattern, input_string):\n return True\n else:\n return False", "matching_cluster_idx": 7}, {"solution": "import re\ndef text_lowercase_underscore(input_string):\n # Regular expression to match sequences of lowercase letters joined with an underscore\n pattern = r'^[a-z]+(_[a-z]+)*$'\n \n # Use re.match to check if the entire string matches the pattern\n if re.match(pattern, input_string):\n return True\n else:\n return False", "matching_cluster_idx": 7}, {"solution": "import re\ndef text_lowercase_underscore(input_string):\n # Regular expression to match sequences of lowercase letters joined with an underscore\n pattern = r'^[a-z]+(_[a-z]+)*$'\n \n # Use re.match to check if the entire string matches the pattern\n if re.match(pattern, input_string):\n return True\n else:\n return False", "matching_cluster_idx": 7}, {"solution": "import re\ndef text_lowercase_underscore(input_string):\n # Regular expression pattern to match sequences of lowercase letters joined with an underscore\n pattern = r'^[a-z]+(_[a-z]+)*$'\n \n # Use re.match to check if the entire string matches the pattern\n if re.match(pattern, input_string):\n return True\n else:\n return False", "matching_cluster_idx": 7}, {"solution": "import re\ndef text_lowercase_underscore(input_string):\n # Define the regular expression pattern\n pattern = r'^[a-z]+(_[a-z]+)*$'\n \n # Use re.match to check if the input string matches the pattern\n if re.match(pattern, input_string):\n return True\n else:\n return False", "matching_cluster_idx": 7}]}, "Mbpp/19": {"dps": 98.23232323232324, "dps_norm": 99.0, "pass@1": 100.0, "profiled": [{"solution": "def test_duplicate(arr):\n # Create a set to store unique elements\n unique_elements = set()\n \n # Iterate through each element in the array\n for num in arr:\n # If the element is already in the set, it's a duplicate\n if num in unique_elements:\n return True\n # Add the element to the set\n unique_elements.add(num)\n \n # If no duplicates were found, return False\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(arr):\n # Create a set to store unique elements\n unique_elements = set()\n \n # Iterate through each element in the array\n for element in arr:\n # If the element is already in the set, it's a duplicate\n if element in unique_elements:\n return True\n # Add the element to the set\n unique_elements.add(element)\n \n # If no duplicates were found, return False\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(arr):\n # Create a set to store unique elements\n unique_elements = set()\n \n # Iterate through each element in the array\n for num in arr:\n # If the element is already in the set, it's a duplicate\n if num in unique_elements:\n return True\n # Add the element to the set\n unique_elements.add(num)\n \n # If no duplicates were found, return False\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(arr):\n # Create a set to store unique elements\n seen = set()\n \n # Iterate through each element in the array\n for num in arr:\n # If the element is already in the set, it's a duplicate\n if num in seen:\n return True\n # Add the element to the set\n seen.add(num)\n \n # If no duplicates were found, return False\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(arr):\n # Create a set to store unique elements\n unique_elements = set()\n \n # Iterate through each element in the array\n for element in arr:\n # If the element is already in the set, it's a duplicate\n if element in unique_elements:\n return True\n # Otherwise, add the element to the set\n unique_elements.add(element)\n \n # If no duplicates were found, return False\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(arr):\n # Create a set to store unique elements\n seen = set()\n \n # Iterate through each element in the array\n for num in arr:\n # If the element is already in the set, it's a duplicate\n if num in seen:\n return True\n # Add the element to the set\n seen.add(num)\n \n # If no duplicates were found, return False\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(arr):\n # Create a set to store unique elements\n unique_elements = set()\n \n # Iterate through each element in the array\n for num in arr:\n # If the element is already in the set, it's a duplicate\n if num in unique_elements:\n return True\n # Add the element to the set\n unique_elements.add(num)\n \n # If no duplicates were found, return False\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(arr):\n # Create a set to store unique elements\n unique_elements = set()\n \n # Iterate through each element in the array\n for num in arr:\n # If the element is already in the set, it's a duplicate\n if num in unique_elements:\n return True\n # Add the element to the set\n unique_elements.add(num)\n \n # If no duplicates were found, return False\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(arr):\n # Create a set to store unique elements\n unique_elements = set()\n \n # Iterate through each element in the array\n for num in arr:\n # If the element is already in the set, it's a duplicate\n if num in unique_elements:\n return True\n # Add the element to the set\n unique_elements.add(num)\n \n # If no duplicates were found, return False\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(arr):\n \"\"\"\n Function to check if a given array of integers contains any duplicate element.\n \n Parameters:\n arr (list): A list of integers.\n \n Returns:\n bool: True if the array contains duplicates, False otherwise.\n \"\"\"\n return len(arr) != len(set(arr))", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(arr):\n \"\"\"\n Function to check if a given array of integers contains any duplicate element.\n \n Parameters:\n arr (list): A list of integers.\n \n Returns:\n bool: True if there are duplicates, False otherwise.\n \"\"\"\n # Create a set to store unique elements\n seen = set()\n \n # Iterate through each element in the array\n for num in arr:\n # If the element is already in the set, it's a duplicate\n if num in seen:\n return True\n # Add the element to the set\n seen.add(num)\n \n # If no duplicates were found, return False\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(arr):\n # Create a set to store unique elements\n unique_elements = set()\n \n # Iterate through each element in the array\n for num in arr:\n # If the element is already in the set, it's a duplicate\n if num in unique_elements:\n return True\n # Add the element to the set\n unique_elements.add(num)\n \n # If no duplicates were found, return False\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(arr):\n # Create a set to store unique elements\n unique_elements = set()\n \n # Iterate through each element in the array\n for num in arr:\n # If the element is already in the set, it's a duplicate\n if num in unique_elements:\n return True\n # Add the element to the set\n unique_elements.add(num)\n \n # If no duplicates were found, return False\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(arr):\n # Create a set to store unique elements\n unique_elements = set()\n \n # Iterate through each element in the array\n for element in arr:\n # If the element is already in the set, it's a duplicate\n if element in unique_elements:\n return True\n # Add the element to the set\n unique_elements.add(element)\n \n # If no duplicates were found, return False\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(arr):\n # Create a set to store unique elements\n unique_elements = set()\n \n # Iterate through each element in the array\n for element in arr:\n # If the element is already in the set, it's a duplicate\n if element in unique_elements:\n return True\n # Add the element to the set\n unique_elements.add(element)\n \n # If no duplicates were found, return False\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(arr):\n # Create a set to store unique elements\n unique_elements = set()\n \n # Iterate through each element in the array\n for element in arr:\n # If the element is already in the set, it's a duplicate\n if element in unique_elements:\n return True\n # Add the element to the set\n unique_elements.add(element)\n \n # If no duplicates were found, return False\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(arr):\n # Create a set to store unique elements\n seen = set()\n \n # Iterate through the array\n for num in arr:\n # If the element is already in the set, it's a duplicate\n if num in seen:\n return True\n # Add the element to the set\n seen.add(num)\n \n # If no duplicates were found, return False\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(arr):\n # Create a set to store unique elements\n seen = set()\n \n # Iterate through each element in the array\n for num in arr:\n # If the element is already in the set, it's a duplicate\n if num in seen:\n return True\n # Add the element to the set\n seen.add(num)\n \n # If no duplicates were found, return False\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(arr):\n # Create a set to store unique elements\n seen = set()\n \n # Iterate through each element in the array\n for num in arr:\n # If the element is already in the set, it's a duplicate\n if num in seen:\n return True\n # Add the element to the set\n seen.add(num)\n \n # If no duplicates were found, return False\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(arr):\n \"\"\"\n Function to check if a given array of integers contains any duplicate element.\n \n Args:\n arr (list): A list of integers.\n \n Returns:\n bool: True if the array contains duplicates, False otherwise.\n \"\"\"\n seen = set()\n for num in arr:\n if num in seen:\n return True\n seen.add(num)\n return False", "matching_cluster_idx": 14}]}, "Mbpp/62": {"dps": 70.0, "dps_norm": 80.0, "pass@1": 100.0, "profiled": [{"solution": "def smallest_num(lst):\n \"\"\"\n Find the smallest number in a list.\n \n Args:\n lst (list): A list of numbers.\n \n Returns:\n int: The smallest number in the list.\n \"\"\"\n if not lst:\n raise ValueError(\"The list is empty\")\n \n smallest = lst[0]\n for num in lst:\n if num < smallest:\n smallest = num\n return smallest", "matching_cluster_idx": 3}, {"solution": "def smallest_num(lst):\n \"\"\"\n Find the smallest number in a list.\n \n Parameters:\n lst (list): A list of numbers.\n \n Returns:\n int: The smallest number in the list.\n \"\"\"\n if not lst:\n raise ValueError(\"The list is empty\")\n \n smallest = lst[0]\n for num in lst:\n if num < smallest:\n smallest = num\n return smallest", "matching_cluster_idx": 3}, {"solution": "def smallest_num(lst):\n \"\"\"\n Find the smallest number in a list.\n\n Args:\n lst (list): A list of numbers.\n\n Returns:\n int: The smallest number in the list.\n \"\"\"\n if not lst:\n raise ValueError(\"The list is empty\")\n \n smallest = lst[0]\n for num in lst:\n if num < smallest:\n smallest = num\n return smallest", "matching_cluster_idx": 3}, {"solution": "def smallest_num(lst):\n \"\"\"\n Find the smallest number in a list.\n \n Args:\n lst (list): A list of numbers.\n \n Returns:\n int: The smallest number in the list.\n \"\"\"\n if not lst:\n raise ValueError(\"The list is empty\")\n \n smallest = lst[0]\n for num in lst:\n if num < smallest:\n smallest = num\n return smallest", "matching_cluster_idx": 3}, {"solution": "def smallest_num(lst):\n \"\"\"\n Find the smallest number in a list.\n\n Args:\n lst (list): A list of numbers.\n\n Returns:\n int: The smallest number in the list.\n \"\"\"\n if not lst:\n raise ValueError(\"The list is empty\")\n \n smallest = lst[0]\n for num in lst:\n if num < smallest:\n smallest = num\n return smallest", "matching_cluster_idx": 3}, {"solution": "def smallest_num(lst):\n \"\"\"\n Find the smallest number in a list.\n\n Parameters:\n lst (list): A list of numbers.\n\n Returns:\n int: The smallest number in the list.\n \"\"\"\n if not lst:\n raise ValueError(\"The list is empty\")\n \n smallest = lst[0]\n for num in lst:\n if num < smallest:\n smallest = num\n return smallest", "matching_cluster_idx": 3}, {"solution": "def smallest_num(lst):\n \"\"\"\n Find the smallest number in a list.\n\n Args:\n lst (list): A list of numbers.\n\n Returns:\n int: The smallest number in the list.\n \"\"\"\n if not lst:\n raise ValueError(\"The list is empty\")\n \n smallest = lst[0]\n for num in lst:\n if num < smallest:\n smallest = num\n return smallest", "matching_cluster_idx": 3}, {"solution": "def smallest_num(lst):\n \"\"\"\n Find the smallest number in a list.\n \n Args:\n lst (list): A list of numbers.\n \n Returns:\n int: The smallest number in the list.\n \"\"\"\n if not lst:\n raise ValueError(\"The list is empty\")\n \n smallest = lst[0]\n for num in lst:\n if num < smallest:\n smallest = num\n return smallest", "matching_cluster_idx": 3}, {"solution": "def smallest_num(lst):\n \"\"\"\n Find the smallest number in a list.\n\n Parameters:\n lst (list): A list of numbers.\n\n Returns:\n int: The smallest number in the list.\n \"\"\"\n if not lst:\n raise ValueError(\"The list is empty\")\n \n smallest = lst[0]\n for num in lst:\n if num < smallest:\n smallest = num\n return smallest", "matching_cluster_idx": 3}, {"solution": "def smallest_num(lst):\n \"\"\"\n Find the smallest number in a list.\n\n Args:\n lst (list): A list of numbers.\n\n Returns:\n int: The smallest number in the list.\n \"\"\"\n if not lst:\n raise ValueError(\"The list is empty\")\n \n smallest = lst[0]\n for num in lst:\n if num < smallest:\n smallest = num\n return smallest", "matching_cluster_idx": 3}, {"solution": "def smallest_num(lst):\n \"\"\"\n Find the smallest number in a list.\n \n Parameters:\n lst (list): A list of numbers.\n \n Returns:\n int: The smallest number in the list.\n \"\"\"\n if not lst:\n raise ValueError(\"The list is empty\")\n \n smallest = lst[0]\n for num in lst:\n if num < smallest:\n smallest = num\n return smallest", "matching_cluster_idx": 3}, {"solution": "def smallest_num(lst):\n \"\"\"\n Find the smallest number in a list.\n\n Parameters:\n lst (list): A list of numbers.\n\n Returns:\n int: The smallest number in the list.\n \"\"\"\n if not lst:\n raise ValueError(\"The list is empty\")\n \n smallest = lst[0]\n for num in lst:\n if num < smallest:\n smallest = num\n return smallest", "matching_cluster_idx": 3}, {"solution": "def smallest_num(lst):\n \"\"\"\n Find the smallest number in a list.\n\n Args:\n lst (list): A list of numbers.\n\n Returns:\n int: The smallest number in the list.\n \"\"\"\n if not lst:\n raise ValueError(\"The list is empty\")\n \n # Initialize the smallest number with the first element of the list\n smallest = lst[0]\n \n # Iterate through the list to find the smallest number\n for num in lst:\n if num < smallest:\n smallest = num\n \n return smallest", "matching_cluster_idx": 3}, {"solution": "def smallest_num(lst):\n \"\"\"\n Find the smallest number in a list.\n\n Parameters:\n lst (list): A list of numbers.\n\n Returns:\n int: The smallest number in the list.\n \"\"\"\n if not lst:\n raise ValueError(\"The list is empty\")\n \n smallest = lst[0]\n for num in lst:\n if num < smallest:\n smallest = num\n return smallest", "matching_cluster_idx": 3}, {"solution": "def smallest_num(lst):\n \"\"\"\n Find the smallest number in a list.\n\n Parameters:\n lst (list): A list of numbers.\n\n Returns:\n int: The smallest number in the list.\n \"\"\"\n if not lst:\n raise ValueError(\"The list is empty\")\n \n smallest = lst[0]\n for num in lst:\n if num < smallest:\n smallest = num\n return smallest", "matching_cluster_idx": 3}, {"solution": "def smallest_num(lst):\n \"\"\"\n Find the smallest number in a list.\n\n Args:\n lst (list): A list of numbers.\n\n Returns:\n int: The smallest number in the list.\n \"\"\"\n if not lst:\n raise ValueError(\"The list is empty\")\n \n smallest = lst[0]\n for num in lst:\n if num < smallest:\n smallest = num\n return smallest", "matching_cluster_idx": 3}, {"solution": "def smallest_num(lst):\n \"\"\"\n Find the smallest number in a list.\n\n Args:\n lst (list): A list of numbers.\n\n Returns:\n int: The smallest number in the list.\n \"\"\"\n if not lst:\n raise ValueError(\"The list is empty\")\n \n smallest = lst[0]\n for num in lst:\n if num < smallest:\n smallest = num\n return smallest", "matching_cluster_idx": 3}, {"solution": "def smallest_num(lst):\n \"\"\"\n Find the smallest number in a list.\n\n Args:\n lst (list): A list of numbers.\n\n Returns:\n int: The smallest number in the list.\n \"\"\"\n if not lst:\n raise ValueError(\"The list is empty\")\n \n smallest = lst[0]\n for num in lst:\n if num < smallest:\n smallest = num\n return smallest", "matching_cluster_idx": 3}, {"solution": "def smallest_num(lst):\n \"\"\"\n Find the smallest number in a list.\n \n Parameters:\n lst (list): A list of numbers.\n \n Returns:\n int: The smallest number in the list.\n \"\"\"\n if not lst:\n raise ValueError(\"The list is empty\")\n \n smallest = lst[0]\n for num in lst:\n if num < smallest:\n smallest = num\n return smallest", "matching_cluster_idx": 3}, {"solution": "def smallest_num(lst):\n \"\"\"\n Find the smallest number in a list.\n \n Parameters:\n lst (list): A list of numbers.\n \n Returns:\n int: The smallest number in the list.\n \"\"\"\n if not lst:\n raise ValueError(\"The list is empty\")\n \n smallest = lst[0]\n for num in lst:\n if num < smallest:\n smallest = num\n return smallest", "matching_cluster_idx": 3}]}, "Mbpp/75": {"dps": 92.85714285714286, "dps_norm": 66.66666666666667, "pass@1": 100.0, "profiled": [{"solution": "def find_tuples(tuples_list, k):\n # Initialize an empty list to store the result\n result = []\n \n # Iterate over each tuple in the list\n for tup in tuples_list:\n # Check if all elements in the tuple are divisible by k\n if all(element % k == 0 for element in tup):\n # If true, add the tuple to the result list\n result.append(tup)\n \n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n # Initialize an empty list to store the result\n result = []\n \n # Iterate over each tuple in the list\n for tup in tuples_list:\n # Check if all elements in the tuple are divisible by k\n if all(element % k == 0 for element in tup):\n # If true, add the tuple to the result list\n result.append(tup)\n \n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n \"\"\"\n Find tuples which have all elements divisible by k from the given list of tuples.\n \n :param tuples_list: List of tuples\n :param k: Integer to check divisibility by\n :return: List of tuples where all elements are divisible by k\n \"\"\"\n return [tup for tup in tuples_list if all(elem % k == 0 for elem in tup)]", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n return [tup for tup in tuples_list if all(elem % k == 0 for elem in tup)]", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n \"\"\"\n Find tuples which have all elements divisible by k from the given list of tuples.\n \n :param tuples_list: List of tuples\n :param k: Integer to check divisibility\n :return: List of tuples where all elements are divisible by k\n \"\"\"\n return [tup for tup in tuples_list if all(elem % k == 0 for elem in tup)]", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n # Initialize an empty list to store the result\n result = []\n \n # Iterate over each tuple in the list\n for tup in tuples_list:\n # Check if all elements in the tuple are divisible by k\n if all(element % k == 0 for element in tup):\n # If true, add the tuple to the result list\n result.append(tup)\n \n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n \"\"\"\n Find tuples which have all elements divisible by k from the given list of tuples.\n\n :param tuples_list: List of tuples to check.\n :param k: The divisor to check against.\n :return: List of tuples where all elements are divisible by k.\n \"\"\"\n return [tup for tup in tuples_list if all(element % k == 0 for element in tup)]", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n # Initialize an empty list to store the result\n result = []\n \n # Iterate over each tuple in the list\n for tup in tuples_list:\n # Check if all elements in the tuple are divisible by k\n if all(element % k == 0 for element in tup):\n # If true, add the tuple to the result list\n result.append(tup)\n \n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n # Initialize an empty list to store the result\n result = []\n \n # Iterate over each tuple in the list\n for tup in tuples_list:\n # Check if all elements in the tuple are divisible by k\n if all(element % k == 0 for element in tup):\n # If true, add the tuple to the result list\n result.append(tup)\n \n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n # Initialize an empty list to store the result\n result = []\n \n # Iterate through each tuple in the list\n for tup in tuples_list:\n # Check if all elements in the tuple are divisible by k\n if all(element % k == 0 for element in tup):\n # If true, add the tuple to the result list\n result.append(tup)\n \n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n \"\"\"\n Find tuples which have all elements divisible by k from the given list of tuples.\n\n :param tuples_list: List of tuples to check.\n :param k: The divisor.\n :return: List of tuples where all elements are divisible by k.\n \"\"\"\n return [tup for tup in tuples_list if all(element % k == 0 for element in tup)]", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n return [tup for tup in tuples_list if all(elem % k == 0 for elem in tup)]", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n # Initialize an empty list to store the result\n result = []\n \n # Iterate over each tuple in the list\n for tup in tuples_list:\n # Check if all elements in the tuple are divisible by k\n if all(element % k == 0 for element in tup):\n # If true, add the tuple to the result list\n result.append(tup)\n \n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n \"\"\"\n Find tuples which have all elements divisible by k from the given list of tuples.\n\n :param tuples_list: List of tuples\n :param k: Integer to check divisibility\n :return: List of tuples where all elements are divisible by k\n \"\"\"\n return [tup for tup in tuples_list if all(element % k == 0 for element in tup)]", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n # Initialize an empty list to store the result\n result = []\n \n # Iterate over each tuple in the list\n for tup in tuples_list:\n # Check if all elements in the tuple are divisible by k\n if all(element % k == 0 for element in tup):\n # If true, add the tuple to the result list\n result.append(tup)\n \n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n # Initialize an empty list to store the result\n result = []\n \n # Iterate over each tuple in the list\n for tup in tuples_list:\n # Check if all elements in the tuple are divisible by k\n if all(element % k == 0 for element in tup):\n # If true, add the tuple to the result list\n result.append(tup)\n \n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n \"\"\"\n Find tuples which have all elements divisible by k from the given list of tuples.\n \n :param tuples_list: List of tuples\n :param k: Integer to check divisibility\n :return: List of tuples where all elements are divisible by k\n \"\"\"\n return [tup for tup in tuples_list if all(elem % k == 0 for elem in tup)]", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n \"\"\"\n Find tuples which have all elements divisible by k from the given list of tuples.\n\n :param tuples_list: List of tuples to check.\n :param k: The divisor.\n :return: List of tuples where all elements are divisible by k.\n \"\"\"\n return [tup for tup in tuples_list if all(element % k == 0 for element in tup)]", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n \"\"\"\n Find tuples which have all elements divisible by k from the given list of tuples.\n \n :param tuples_list: List of tuples\n :param k: Integer to check divisibility\n :return: List of tuples where all elements are divisible by k\n \"\"\"\n return [tup for tup in tuples_list if all(elem % k == 0 for elem in tup)]", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n \"\"\"\n Find tuples which have all elements divisible by k from the given list of tuples.\n \n :param tuples_list: List of tuples\n :param k: Integer to check divisibility\n :return: List of tuples where all elements are divisible by k\n \"\"\"\n return [tup for tup in tuples_list if all(elem % k == 0 for elem in tup)]", "matching_cluster_idx": 5}]}, "Mbpp/88": {"dps": 96.56862745098039, "dps_norm": 85.71428571428571, "pass@1": 100.0, "profiled": [{"solution": "def freq_count(lst):\n frequency = {}\n for element in lst:\n if element in frequency:\n frequency[element] += 1\n else:\n frequency[element] = 1\n return frequency", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n frequency = {}\n for element in lst:\n if element in frequency:\n frequency[element] += 1\n else:\n frequency[element] = 1\n return frequency", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n frequency = {}\n for element in lst:\n if element in frequency:\n frequency[element] += 1\n else:\n frequency[element] = 1\n return frequency", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n frequency = {}\n for element in lst:\n if element in frequency:\n frequency[element] += 1\n else:\n frequency[element] = 1\n return frequency", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n frequency = {}\n for element in lst:\n if element in frequency:\n frequency[element] += 1\n else:\n frequency[element] = 1\n return frequency", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n frequency = {}\n for element in lst:\n if element in frequency:\n frequency[element] += 1\n else:\n frequency[element] = 1\n return frequency", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n frequency = {}\n for element in lst:\n if element in frequency:\n frequency[element] += 1\n else:\n frequency[element] = 1\n return frequency", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n frequency = {}\n for item in lst:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n return frequency", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n frequency = {}\n for element in lst:\n if element in frequency:\n frequency[element] += 1\n else:\n frequency[element] = 1\n return frequency", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n frequency = {}\n for element in lst:\n if element in frequency:\n frequency[element] += 1\n else:\n frequency[element] = 1\n return frequency", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n frequency = {}\n for element in lst:\n if element in frequency:\n frequency[element] += 1\n else:\n frequency[element] = 1\n return frequency", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n frequency = {}\n for element in lst:\n if element in frequency:\n frequency[element] += 1\n else:\n frequency[element] = 1\n return frequency", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n frequency = {}\n for element in lst:\n if element in frequency:\n frequency[element] += 1\n else:\n frequency[element] = 1\n return frequency", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n frequency = {}\n for element in lst:\n if element in frequency:\n frequency[element] += 1\n else:\n frequency[element] = 1\n return frequency", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n frequency = {}\n for item in lst:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n return frequency", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n frequency = {}\n for element in lst:\n if element in frequency:\n frequency[element] += 1\n else:\n frequency[element] = 1\n return frequency", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n frequency = {}\n for element in lst:\n if element in frequency:\n frequency[element] += 1\n else:\n frequency[element] = 1\n return frequency", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n frequency = {}\n for item in lst:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n return frequency", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n frequency = {}\n for element in lst:\n if element in frequency:\n frequency[element] += 1\n else:\n frequency[element] = 1\n return frequency", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n frequency = {}\n for element in lst:\n if element in frequency:\n frequency[element] += 1\n else:\n frequency[element] = 1\n return frequency", "matching_cluster_idx": 5}]}, "Mbpp/90": {"dps": 79.51219512195122, "dps_norm": 85.71428571428571, "pass@1": 77.0, "profiled": [{"solution": "def len_log(words):\n \"\"\"\n Function to find the length of the longest word in a list.\n \n Args:\n words (list): A list of strings.\n \n Returns:\n int: The length of the longest word in the list.\n \"\"\"\n if not words:\n return 0\n \n # Initialize the maximum length with the length of the first word\n max_length = len(words[0])\n \n # Iterate through the list to find the longest word\n for word in words:\n if len(word) > max_length:\n max_length = len(word)\n \n return max_length", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n \"\"\"\n Function to find the length of the longest word in a list.\n \n Parameters:\n words (list): A list of strings.\n \n Returns:\n int: The length of the longest word in the list.\n \"\"\"\n if not words:\n return 0\n \n # Use the max function with a key that returns the length of each word\n return max(len(word) for word in words)", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n \"\"\"\n Function to find the length of the longest word in a list of words.\n \n Args:\n words (list): A list of strings.\n \n Returns:\n int: The length of the longest word in the list.\n \"\"\"\n if not words:\n return 0\n \n return max(len(word) for word in words)", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n \"\"\"\n Function to find the length of the longest word in a list.\n \n Args:\n words (list): A list of strings.\n \n Returns:\n int: The length of the longest word in the list.\n \"\"\"\n return max(len(word) for word in words)", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n \"\"\"\n Function to find the length of the longest word in a list.\n \n Args:\n words (list): A list of strings.\n \n Returns:\n int: The length of the longest word in the list.\n \"\"\"\n # Initialize the maximum length to 0\n max_length = 0\n \n # Iterate through each word in the list\n for word in words:\n # Update max_length if the current word's length is greater\n if len(word) > max_length:\n max_length = len(word)\n \n return max_length", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n \"\"\"\n Function to find the length of the longest word in a list.\n \n Parameters:\n words (list): A list of strings.\n \n Returns:\n int: The length of the longest word in the list.\n \"\"\"\n # Initialize the maximum length to 0\n max_length = 0\n \n # Iterate through each word in the list\n for word in words:\n # Update the maximum length if the current word's length is greater\n if len(word) > max_length:\n max_length = len(word)\n \n return max_length", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n \"\"\"\n Function to find the length of the longest word in a list of words.\n \n Args:\n words (list): A list of strings.\n \n Returns:\n int: The length of the longest word in the list.\n \"\"\"\n return max(len(word) for word in words)", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n \"\"\"\n Function to find the length of the longest word in a list.\n \n Parameters:\n words (list): A list of strings.\n \n Returns:\n int: The length of the longest word in the list.\n \"\"\"\n if not words:\n return 0\n \n # Use the max function with a key that returns the length of each word\n return max(len(word) for word in words)", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n \"\"\"\n Function to find the length of the longest word in a list.\n \n Args:\n words (list): A list of words.\n \n Returns:\n int: The length of the longest word.\n \"\"\"\n # Initialize the maximum length to 0\n max_length = 0\n \n # Iterate through each word in the list\n for word in words:\n # Update the maximum length if the current word's length is greater\n if len(word) > max_length:\n max_length = len(word)\n \n return max_length", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n \"\"\"\n Function to find the length of the longest word in a list.\n \n Args:\n words (list): A list of strings.\n \n Returns:\n int: The length of the longest word in the list.\n \"\"\"\n return max(len(word) for word in words)", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n \"\"\"\n Find the length of the longest word in the list.\n\n Args:\n words (list): A list of strings.\n\n Returns:\n int: The length of the longest word.\n \"\"\"\n return max(len(word) for word in words)", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n \"\"\"\n Function to find the length of the longest word in a list.\n \n Args:\n words (list): A list of strings.\n \n Returns:\n int: The length of the longest word in the list.\n \"\"\"\n if not words:\n return 0\n \n return max(len(word) for word in words)", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n \"\"\"\n Function to find the length of the longest word in a list.\n \n Args:\n words (list): A list of strings.\n \n Returns:\n int: The length of the longest word in the list.\n \"\"\"\n # Initialize the maximum length to 0\n max_length = 0\n \n # Iterate through each word in the list\n for word in words:\n # Update max_length if the current word's length is greater\n if len(word) > max_length:\n max_length = len(word)\n \n return max_length", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n \"\"\"\n Function to find the length of the longest word in a list.\n \n Parameters:\n words (list): A list of strings.\n \n Returns:\n int: The length of the longest word in the list.\n \"\"\"\n # Initialize the maximum length to 0\n max_length = 0\n \n # Iterate through each word in the list\n for word in words:\n # Update max_length if the current word's length is greater\n if len(word) > max_length:\n max_length = len(word)\n \n return max_length", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n \"\"\"\n Function to find the length of the longest word in a list.\n \n :param words: List of words\n :return: Length of the longest word\n \"\"\"\n return max(len(word) for word in words)", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n \"\"\"\n Find the length of the longest word in a list of words.\n \n Args:\n words (list): A list of strings.\n \n Returns:\n int: The length of the longest word in the list.\n \"\"\"\n return max(len(word) for word in words)", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n \"\"\"\n Function to find the length of the longest word in a list.\n \n Args:\n words (list): A list of words.\n \n Returns:\n int: The length of the longest word in the list.\n \"\"\"\n if not words:\n return 0\n \n # Initialize the maximum length with the length of the first word\n max_length = len(words[0])\n \n # Iterate through the list to find the longest word\n for word in words:\n if len(word) > max_length:\n max_length = len(word)\n \n return max_length", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n \"\"\"\n Function to find the length of the longest word in a list.\n \n Args:\n words (list): A list of strings.\n \n Returns:\n int: The length of the longest word in the list.\n \"\"\"\n if not words:\n return 0\n \n # Initialize the maximum length with the length of the first word\n max_length = len(words[0])\n \n # Iterate through the list to find the longest word\n for word in words:\n if len(word) > max_length:\n max_length = len(word)\n \n return max_length", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n \"\"\"\n Function to find the length of the longest word in a list of words.\n \n Args:\n words (list): A list of strings.\n \n Returns:\n int: The length of the longest word in the list.\n \"\"\"\n if not words:\n return 0\n \n return max(len(word) for word in words)", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n \"\"\"\n Function to find the length of the longest word in a list.\n \n Args:\n words (list): A list of strings.\n \n Returns:\n int: The length of the longest word in the list.\n \"\"\"\n if not words:\n return 0\n \n # Initialize the maximum length with the length of the first word\n max_length = len(words[0])\n \n # Iterate through the list to find the longest word\n for word in words:\n if len(word) > max_length:\n max_length = len(word)\n \n return max_length", "matching_cluster_idx": 5}]}, "Mbpp/94": {"dps": 78.04878048780488, "dps_norm": 60.0, "pass@1": 97.0, "profiled": [{"solution": "def index_minimum(tuples_list):\n # Find the tuple with the smallest second value\n min_tuple = min(tuples_list, key=lambda x: x[1])\n # Return the first value of that tuple\n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(tuples_list):\n # Find the tuple with the smallest second value\n min_tuple = min(tuples_list, key=lambda x: x[1])\n # Return the first value of that tuple\n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(tuples_list):\n # Find the tuple with the smallest second value\n min_tuple = min(tuples_list, key=lambda x: x[1])\n # Return the first value of that tuple\n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(tuples_list):\n # Find the tuple with the smallest second value\n min_tuple = min(tuples_list, key=lambda x: x[1])\n # Return the first value of that tuple\n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(tuples_list):\n # Find the tuple with the smallest second value\n min_tuple = min(tuples_list, key=lambda x: x[1])\n # Return the first value of that tuple\n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(tuples_list):\n # Find the tuple with the smallest second value\n min_tuple = min(tuples_list, key=lambda x: x[1])\n # Return the first value of that tuple\n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(tuples_list):\n # Find the tuple with the smallest second value\n min_tuple = min(tuples_list, key=lambda x: x[1])\n # Return the first value of that tuple\n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(tuples_list):\n # Find the tuple with the smallest second value\n min_tuple = min(tuples_list, key=lambda x: x[1])\n # Return the first value of the tuple with the smallest second value\n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(tuples_list):\n # Find the tuple with the smallest second value\n min_tuple = min(tuples_list, key=lambda x: x[1])\n # Return the first value of that tuple\n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(tuples_list):\n # Find the tuple with the smallest second value\n min_tuple = min(tuples_list, key=lambda x: x[1])\n # Return the first value of that tuple\n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(tuples_list):\n # Find the tuple with the smallest second value\n min_tuple = min(tuples_list, key=lambda x: x[1])\n # Return the first value of that tuple\n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(tuples_list):\n # Find the tuple with the smallest second value\n min_tuple = min(tuples_list, key=lambda x: x[1])\n # Return the first value of that tuple\n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(tuples_list):\n # Find the tuple with the smallest second value\n min_tuple = min(tuples_list, key=lambda x: x[1])\n # Return the first value of that tuple\n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(tuples_list):\n # Find the tuple with the smallest second value\n min_tuple = min(tuples_list, key=lambda x: x[1])\n # Return the first value of that tuple\n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(tuples_list):\n # Find the tuple with the smallest second value\n min_tuple = min(tuples_list, key=lambda x: x[1])\n # Return the first value of that tuple\n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(tuples_list):\n # Find the tuple with the smallest second value\n min_tuple = min(tuples_list, key=lambda x: x[1])\n # Return the first value of that tuple\n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(tuples_list):\n # Find the tuple with the smallest second value\n min_tuple = min(tuples_list, key=lambda x: x[1])\n # Return the first value of that tuple\n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(tuples_list):\n # Find the tuple with the smallest second value\n min_tuple = min(tuples_list, key=lambda x: x[1])\n # Return the first value of that tuple\n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(tuples_list):\n # Find the tuple with the smallest second value\n min_tuple = min(tuples_list, key=lambda x: x[1])\n # Return the first value of that tuple\n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(tuples_list):\n # Find the tuple with the smallest second value\n min_tuple = min(tuples_list, key=lambda x: x[1])\n # Return the first value of that tuple\n return min_tuple[0]", "matching_cluster_idx": 2}]}, "Mbpp/96": {"dps": 67.3611111111111, "dps_norm": 40.714285714285715, "pass@1": 97.0, "profiled": [{"solution": "def divisor(n):\n \"\"\"\n Function to find the number of divisors of a given integer.\n \n Args:\n n (int): The integer for which to find the number of divisors.\n \n Returns:\n int: The number of divisors of the given integer.\n \"\"\"\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n \"\"\"\n Function to find the number of divisors of a given integer.\n \n Args:\n n (int): The integer for which to find the number of divisors.\n \n Returns:\n int: The number of divisors of the given integer.\n \"\"\"\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n \"\"\"\n Function to find the number of divisors of a given integer.\n \n Parameters:\n n (int): The integer for which to find the number of divisors.\n \n Returns:\n int: The number of divisors of the given integer.\n \"\"\"\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n \"\"\"\n Function to find the number of divisors of a given integer.\n \n Parameters:\n n (int): The integer for which to find the number of divisors.\n \n Returns:\n int: The number of divisors of the given integer.\n \"\"\"\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n \"\"\"\n Function to find the number of divisors of a given integer.\n\n Args:\n n (int): The integer to find the divisors of.\n\n Returns:\n int: The number of divisors of the integer.\n \"\"\"\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n \"\"\"\n Function to find the number of divisors of a given integer.\n \n Parameters:\n n (int): The integer for which we need to find the number of divisors.\n \n Returns:\n int: The number of divisors of the given integer.\n \"\"\"\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n \"\"\"\n Function to find the number of divisors of a given integer.\n \n Args:\n n (int): The integer for which to find the number of divisors.\n \n Returns:\n int: The number of divisors of the integer.\n \"\"\"\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n \"\"\"\n Function to find the number of divisors of a given integer.\n \n Args:\n n (int): The integer for which to find the number of divisors.\n \n Returns:\n int: The number of divisors of the given integer.\n \"\"\"\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n \"\"\"\n Function to find the number of divisors of a given integer.\n \n Args:\n n (int): The integer for which to find the number of divisors.\n \n Returns:\n int: The number of divisors of the integer.\n \"\"\"\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n \"\"\"\n Function to find the number of divisors of a given integer.\n \n Args:\n n (int): The integer for which to find the number of divisors.\n \n Returns:\n int: The number of divisors of the given integer.\n \"\"\"\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n \"\"\"\n Function to find the number of divisors of a given integer.\n \n Parameters:\n n (int): The integer for which we need to find the number of divisors.\n \n Returns:\n int: The number of divisors of the integer n.\n \"\"\"\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n \"\"\"\n Function to find the number of divisors of a given integer.\n \n Args:\n n (int): The integer for which to find the number of divisors.\n \n Returns:\n int: The number of divisors of the integer.\n \"\"\"\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n \"\"\"\n Function to find the number of divisors of a given integer n.\n \"\"\"\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def divisor(n):\n \"\"\"\n Function to find the number of divisors of a given integer n.\n \"\"\"\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def divisor(n):\n \"\"\"\n Function to find the number of divisors of a given integer.\n \n Parameters:\n n (int): The integer for which we need to find the number of divisors.\n \n Returns:\n int: The number of divisors of the integer n.\n \"\"\"\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n \"\"\"\n Function to find the number of divisors of a given integer.\n \n Args:\n n (int): The integer for which to find the number of divisors.\n \n Returns:\n int: The number of divisors of the integer n.\n \"\"\"\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n \"\"\"\n Function to find the number of divisors of a given integer.\n \n Args:\n n (int): The integer for which to find the number of divisors.\n \n Returns:\n int: The number of divisors of the given integer.\n \"\"\"\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n \"\"\"\n Function to find the number of divisors of a given integer.\n \n Args:\n n (int): The integer for which to find the number of divisors.\n \n Returns:\n int: The number of divisors of the integer.\n \"\"\"\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n \"\"\"\n Function to find the number of divisors of a given integer.\n \n Parameters:\n n (int): The integer for which to find the number of divisors.\n \n Returns:\n int: The number of divisors of the integer n.\n \"\"\"\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 1}]}, "Mbpp/97": {"dps": 99.65811965811966, "dps_norm": 87.5, "pass@1": 100.0, "profiled": [{"solution": "def frequency_lists(list_of_lists):\n \"\"\"\n Find the frequency of each element in a flattened list of lists and return it as a dictionary.\n \n :param list_of_lists: A list of lists containing elements.\n :return: A dictionary where keys are elements and values are their frequencies.\n \"\"\"\n from collections import Counter\n \n # Flatten the list of lists\n flattened_list = [item for sublist in list_of_lists for item in sublist]\n \n # Use Counter to count the frequency of each element\n frequency_dict = Counter(flattened_list)\n \n # Convert Counter object to a regular dictionary\n return dict(frequency_dict)", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lists):\n frequency_dict = {}\n for sublist in lists:\n for element in sublist:\n if element in frequency_dict:\n frequency_dict[element] += 1\n else:\n frequency_dict[element] = 1\n return frequency_dict", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lists):\n frequency_dict = {}\n for sublist in lists:\n for element in sublist:\n if element in frequency_dict:\n frequency_dict[element] += 1\n else:\n frequency_dict[element] = 1\n return frequency_dict", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(nested_lists):\n frequency_dict = {}\n for sublist in nested_lists:\n for element in sublist:\n if element in frequency_dict:\n frequency_dict[element] += 1\n else:\n frequency_dict[element] = 1\n return frequency_dict", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(list_of_lists):\n \"\"\"\n Find the frequency of each element in a flattened list of lists and return it in a dictionary.\n \n :param list_of_lists: A list of lists containing elements.\n :return: A dictionary where keys are elements and values are their frequencies.\n \"\"\"\n from collections import Counter\n \n # Flatten the list of lists\n flattened_list = [item for sublist in list_of_lists for item in sublist]\n \n # Use Counter to count the frequency of each element\n frequency_dict = Counter(flattened_list)\n \n # Convert Counter object to a regular dictionary\n return dict(frequency_dict)", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lists):\n \"\"\"\n Find the frequency of each element in a flattened list of lists and return it as a dictionary.\n \n Args:\n lists (list of lists): A list containing lists of elements.\n \n Returns:\n dict: A dictionary where the keys are the elements and the values are their frequencies.\n \"\"\"\n frequency_dict = {}\n \n # Flatten the list of lists\n flattened_list = [item for sublist in lists for item in sublist]\n \n # Count the frequency of each element\n for item in flattened_list:\n if item in frequency_dict:\n frequency_dict[item] += 1\n else:\n frequency_dict[item] = 1\n \n return frequency_dict", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lists):\n frequency_dict = {}\n for sublist in lists:\n for element in sublist:\n if element in frequency_dict:\n frequency_dict[element] += 1\n else:\n frequency_dict[element] = 1\n return frequency_dict", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lists):\n frequency_dict = {}\n for sublist in lists:\n for element in sublist:\n if element in frequency_dict:\n frequency_dict[element] += 1\n else:\n frequency_dict[element] = 1\n return frequency_dict", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(list_of_lists):\n # Flatten the list of lists into a single list\n flattened_list = [item for sublist in list_of_lists for item in sublist]\n \n # Create a dictionary to store the frequency of each element\n frequency_dict = {}\n \n # Iterate through the flattened list and count the frequency of each element\n for item in flattened_list:\n if item in frequency_dict:\n frequency_dict[item] += 1\n else:\n frequency_dict[item] = 1\n \n return frequency_dict", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lists):\n frequency_dict = {}\n for sublist in lists:\n for element in sublist:\n if element in frequency_dict:\n frequency_dict[element] += 1\n else:\n frequency_dict[element] = 1\n return frequency_dict", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lists):\n frequency_dict = {}\n for sublist in lists:\n for element in sublist:\n if element in frequency_dict:\n frequency_dict[element] += 1\n else:\n frequency_dict[element] = 1\n return frequency_dict", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lists):\n frequency_dict = {}\n for sublist in lists:\n for element in sublist:\n if element in frequency_dict:\n frequency_dict[element] += 1\n else:\n frequency_dict[element] = 1\n return frequency_dict", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(nested_lists):\n \"\"\"\n Find the frequency of each element in a flattened list of lists and return it as a dictionary.\n \n :param nested_lists: A list of lists containing elements.\n :return: A dictionary where keys are elements and values are their frequencies.\n \"\"\"\n frequency_dict = {}\n \n for sublist in nested_lists:\n for element in sublist:\n if element in frequency_dict:\n frequency_dict[element] += 1\n else:\n frequency_dict[element] = 1\n \n return frequency_dict", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(list_of_lists):\n # Flatten the list of lists into a single list\n flattened_list = [item for sublist in list_of_lists for item in sublist]\n \n # Create a dictionary to store the frequency of each element\n frequency_dict = {}\n \n # Count the frequency of each element in the flattened list\n for item in flattened_list:\n if item in frequency_dict:\n frequency_dict[item] += 1\n else:\n frequency_dict[item] = 1\n \n return frequency_dict", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(list_of_lists):\n frequency_dict = {}\n for sublist in list_of_lists:\n for element in sublist:\n if element in frequency_dict:\n frequency_dict[element] += 1\n else:\n frequency_dict[element] = 1\n return frequency_dict", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lists):\n frequency_dict = {}\n for sublist in lists:\n for element in sublist:\n if element in frequency_dict:\n frequency_dict[element] += 1\n else:\n frequency_dict[element] = 1\n return frequency_dict", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(nested_lists):\n \"\"\"\n Find the frequency of each element in a flattened list of lists and return it as a dictionary.\n \n :param nested_lists: A list of lists containing elements.\n :return: A dictionary where keys are elements and values are their frequencies.\n \"\"\"\n frequency_dict = {}\n \n for sublist in nested_lists:\n for element in sublist:\n if element in frequency_dict:\n frequency_dict[element] += 1\n else:\n frequency_dict[element] = 1\n \n return frequency_dict", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(list_of_lists):\n \"\"\"\n Find the frequency of each element in a flattened list of lists and return it as a dictionary.\n \n :param list_of_lists: A list of lists containing elements.\n :return: A dictionary where keys are elements and values are their frequencies.\n \"\"\"\n frequency_dict = {}\n \n # Flatten the list of lists\n flattened_list = [item for sublist in list_of_lists for item in sublist]\n \n # Count the frequency of each element\n for item in flattened_list:\n if item in frequency_dict:\n frequency_dict[item] += 1\n else:\n frequency_dict[item] = 1\n \n return frequency_dict", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(list_of_lists):\n frequency_dict = {}\n for sublist in list_of_lists:\n for element in sublist:\n if element in frequency_dict:\n frequency_dict[element] += 1\n else:\n frequency_dict[element] = 1\n return frequency_dict", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(nested_lists):\n frequency_dict = {}\n for sublist in nested_lists:\n for element in sublist:\n if element in frequency_dict:\n frequency_dict[element] += 1\n else:\n frequency_dict[element] = 1\n return frequency_dict", "matching_cluster_idx": 6}]}, "Mbpp/106": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def add_lists(lst, tup):\n \"\"\"\n Appends the given list to the given tuple.\n\n Args:\n lst (list): The list to append.\n tup (tuple): The tuple to which the list will be appended.\n\n Returns:\n tuple: A new tuple with the list appended to the original tuple.\n \"\"\"\n return tup + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tup):\n \"\"\"\n Appends the given list to the given tuple.\n\n Args:\n lst (list): The list to append.\n tup (tuple): The tuple to which the list will be appended.\n\n Returns:\n tuple: A new tuple with the list appended to the original tuple.\n \"\"\"\n return tup + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tup):\n \"\"\"\n Appends the given list to the given tuple.\n\n Args:\n lst (list): The list to append.\n tup (tuple): The tuple to which the list will be appended.\n\n Returns:\n tuple: A new tuple with the list appended to the original tuple.\n \"\"\"\n return tup + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tup):\n \"\"\"\n Appends the given list to the given tuple.\n\n Parameters:\n lst (list): The list to append.\n tup (tuple): The tuple to which the list will be appended.\n\n Returns:\n tuple: A new tuple with the list appended to the original tuple.\n \"\"\"\n return tup + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tup):\n \"\"\"\n Appends the given list to the given tuple.\n\n Args:\n lst (list): The list to be appended.\n tup (tuple): The tuple to which the list will be appended.\n\n Returns:\n tuple: A new tuple with the list appended to the original tuple.\n \"\"\"\n return tup + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tup):\n \"\"\"\n Appends the given list to the given tuple.\n\n Args:\n lst (list): The list to be appended.\n tup (tuple): The tuple to which the list will be appended.\n\n Returns:\n tuple: A new tuple with the list appended to the original tuple.\n \"\"\"\n return tup + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tup):\n \"\"\"\n Appends the given list to the given tuple.\n\n Args:\n lst (list): The list to append.\n tup (tuple): The tuple to which the list will be appended.\n\n Returns:\n tuple: A new tuple with the list appended to the original tuple.\n \"\"\"\n return tup + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tup):\n \"\"\"\n Appends the given list to the given tuple.\n \n Parameters:\n lst (list): The list to be appended.\n tup (tuple): The tuple to which the list will be appended.\n \n Returns:\n tuple: A new tuple with the list appended to the original tuple.\n \"\"\"\n return tup + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tup):\n \"\"\"\n Appends the given list to the given tuple.\n\n Args:\n lst (list): The list to append.\n tup (tuple): The tuple to which the list will be appended.\n\n Returns:\n tuple: A new tuple with the list appended to the original tuple.\n \"\"\"\n return tup + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tup):\n \"\"\"\n Appends the given list to the given tuple.\n\n Args:\n lst (list): The list to append.\n tup (tuple): The tuple to which the list will be appended.\n\n Returns:\n tuple: A new tuple with the list appended to the original tuple.\n \"\"\"\n return tup + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tup):\n \"\"\"\n Append the given list to the given tuple.\n \n Args:\n lst (list): The list to be appended.\n tup (tuple): The tuple to which the list will be appended.\n \n Returns:\n tuple: A new tuple with the list appended to the original tuple.\n \"\"\"\n return tup + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tup):\n \"\"\"\n Appends the given list to the given tuple.\n\n Args:\n lst (list): The list to append.\n tup (tuple): The tuple to which the list will be appended.\n\n Returns:\n tuple: A new tuple with the list appended to the original tuple.\n \"\"\"\n return tup + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tup):\n \"\"\"\n Appends the given list to the given tuple.\n\n Args:\n lst (list): The list to be appended.\n tup (tuple): The tuple to which the list will be appended.\n\n Returns:\n tuple: A new tuple with the list appended to the original tuple.\n \"\"\"\n return tup + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tup):\n \"\"\"\n Appends the given list to the given tuple.\n\n Parameters:\n lst (list): The list to append.\n tup (tuple): The tuple to which the list will be appended.\n\n Returns:\n tuple: A new tuple with the list appended to the original tuple.\n \"\"\"\n return tup + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tup):\n \"\"\"\n Appends the given list to the given tuple.\n\n Args:\n lst (list): The list to append.\n tup (tuple): The tuple to which the list will be appended.\n\n Returns:\n tuple: A new tuple with the list appended to the original tuple.\n \"\"\"\n return tup + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tup):\n \"\"\"\n Appends the given list to the given tuple.\n \n Args:\n lst (list): The list to append.\n tup (tuple): The tuple to which the list will be appended.\n \n Returns:\n tuple: A new tuple with the list appended to the original tuple.\n \"\"\"\n return tup + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tup):\n \"\"\"\n Appends the given list to the given tuple.\n\n Args:\n lst (list): The list to be appended.\n tup (tuple): The tuple to which the list will be appended.\n\n Returns:\n tuple: A new tuple with the list appended to the original tuple.\n \"\"\"\n return tup + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tup):\n \"\"\"\n Appends the given list to the given tuple.\n\n Args:\n lst (list): The list to append.\n tup (tuple): The tuple to which the list will be appended.\n\n Returns:\n tuple: A new tuple with the list appended to the original tuple.\n \"\"\"\n return tup + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tup):\n \"\"\"\n Appends the given list to the given tuple.\n \n Args:\n lst (list): The list to append.\n tup (tuple): The tuple to which the list will be appended.\n \n Returns:\n tuple: A new tuple with the list appended to the original tuple.\n \"\"\"\n return tup + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tup):\n \"\"\"\n Appends the given list to the given tuple.\n\n Parameters:\n lst (list): The list to be appended.\n tup (tuple): The tuple to which the list will be appended.\n\n Returns:\n tuple: A new tuple with the list appended to the original tuple.\n \"\"\"\n return tup + tuple(lst)", "matching_cluster_idx": 5}]}, "Mbpp/108": {"dps": null, "dps_norm": null, "pass@1": 0.0, "profiled": []}, "Mbpp/111": {"dps": 99.38461538461539, "dps_norm": 87.5, "pass@1": 100.0, "profiled": [{"solution": "def common_in_nested_lists(nested_lists):\n # Initialize the result with the elements of the first list\n common_elements = set(nested_lists[0])\n \n # Iterate over the remaining lists\n for lst in nested_lists[1:]:\n # Update the common elements by intersecting with the current list\n common_elements.intersection_update(lst)\n \n return list(common_elements)", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n # Initialize the result with the elements of the first list\n common_elements = set(nested_lists[0])\n \n # Iterate through the rest of the lists\n for lst in nested_lists[1:]:\n # Update the common elements by intersecting with the current list\n common_elements.intersection_update(lst)\n \n return list(common_elements)", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n # Convert the first list to a set to use set operations\n common_elements = set(nested_lists[0])\n \n # Iterate over the remaining lists and find the intersection\n for lst in nested_lists[1:]:\n common_elements &= set(lst)\n \n return list(common_elements)", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n # Initialize the set with the elements of the first list\n common_elements = set(nested_lists[0])\n \n # Iterate over the remaining lists and update the set of common elements\n for lst in nested_lists[1:]:\n common_elements.intersection_update(lst)\n \n return list(common_elements)", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n # Initialize the set with the elements of the first list\n common_elements = set(nested_lists[0])\n \n # Iterate through the rest of the lists\n for lst in nested_lists[1:]:\n # Update the set to only include elements that are common with the current list\n common_elements.intersection_update(lst)\n \n return list(common_elements)", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n # Initialize the result with the elements of the first list\n common_elements = set(nested_lists[0])\n \n # Iterate over the remaining lists and find the intersection\n for lst in nested_lists[1:]:\n common_elements.intersection_update(lst)\n \n return list(common_elements)", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n # Use the first list as the initial set of common elements\n common_elements = set(nested_lists[0])\n \n # Iterate through the rest of the lists and find the intersection\n for lst in nested_lists[1:]:\n common_elements.intersection_update(lst)\n \n return list(common_elements)", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n # Initialize the set with the elements of the first list\n common_elements = set(nested_lists[0])\n \n # Iterate through the rest of the lists\n for lst in nested_lists[1:]:\n # Update the set to only include elements that are in the current list\n common_elements.intersection_update(lst)\n \n return list(common_elements)", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n # Initialize the result with the elements of the first list\n common_elements = set(nested_lists[0])\n \n # Iterate through the rest of the lists\n for lst in nested_lists[1:]:\n # Update the common elements by intersecting with the current list\n common_elements.intersection_update(lst)\n \n return list(common_elements)", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n # Use a set to find the intersection of all lists\n common_elements = set(nested_lists[0])\n \n for lst in nested_lists[1:]:\n common_elements.intersection_update(lst)\n \n return list(common_elements)", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n # Initialize the result with the elements of the first list\n common_elements = set(nested_lists[0])\n \n # Iterate through the rest of the lists\n for lst in nested_lists[1:]:\n # Update the common elements set by intersecting it with the current list\n common_elements.intersection_update(lst)\n \n return list(common_elements)", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n # Initialize the set with the elements of the first list\n common_elements = set(nested_lists[0])\n \n # Iterate through the rest of the lists\n for lst in nested_lists[1:]:\n # Update the set to only include elements that are common with the current list\n common_elements.intersection_update(lst)\n \n return list(common_elements)", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n # Use a set to find the common elements\n common_elements = set(nested_lists[0])\n \n # Iterate through the rest of the lists\n for lst in nested_lists[1:]:\n common_elements.intersection_update(lst)\n \n return list(common_elements)", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n # Convert each list to a set and find the intersection of all sets\n common_elements = set(nested_lists[0])\n for lst in nested_lists[1:]:\n common_elements.intersection_update(lst)\n return list(common_elements)", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n # Initialize the result with the elements of the first list\n common_elements = set(nested_lists[0])\n \n # Iterate over the remaining lists\n for lst in nested_lists[1:]:\n # Update the common elements by intersecting with the current list\n common_elements.intersection_update(lst)\n \n return list(common_elements)", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n # Convert each list to a set and find the intersection of all sets\n common_elements = set(nested_lists[0])\n for lst in nested_lists[1:]:\n common_elements.intersection_update(lst)\n return list(common_elements)", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n # Initialize the set with the elements of the first list\n common_elements = set(nested_lists[0])\n \n # Iterate through the rest of the lists\n for lst in nested_lists[1:]:\n # Update the set to contain only elements that are common with the current list\n common_elements.intersection_update(lst)\n \n return list(common_elements)", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n # Initialize the set with the elements of the first list\n common_elements = set(nested_lists[0])\n \n # Iterate through the rest of the lists\n for lst in nested_lists[1:]:\n # Update the set to only include elements that are common with the current list\n common_elements.intersection_update(lst)\n \n return list(common_elements)", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n # Initialize the result with the elements of the first list\n common_elements = set(nested_lists[0])\n \n # Iterate through the rest of the lists\n for lst in nested_lists[1:]:\n # Update the common elements by intersecting with the current list\n common_elements.intersection_update(lst)\n \n return list(common_elements)", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n # Convert the first list to a set to use set operations\n common_elements = set(nested_lists[0])\n \n # Iterate through the rest of the lists and find the intersection\n for lst in nested_lists[1:]:\n common_elements &= set(lst)\n \n return list(common_elements)", "matching_cluster_idx": 6}]}, "Mbpp/123": {"dps": 99.62686567164178, "dps_norm": 85.71428571428571, "pass@1": 100.0, "profiled": [{"solution": "def sum_of_divisors(n):\n \"\"\"Return the sum of proper divisors of n.\"\"\"\n total = 1\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n total += i\n if i != n // i:\n total += n // i\n return total\ndef is_amicable(a):\n \"\"\"Check if a is an amicable number.\"\"\"\n b = sum_of_divisors(a)\n return b != a and sum_of_divisors(b) == a\ndef amicable_numbers_sum(limit):\n \"\"\"Return the sum of all amicable numbers up to the given limit.\"\"\"\n amicable_sum = 0\n for num in range(1, limit + 1):\n if is_amicable(num):\n amicable_sum += num\n return amicable_sum", "matching_cluster_idx": 11}, {"solution": "def sum_of_divisors(n):\n \"\"\"Return the sum of proper divisors of n.\"\"\"\n divisors = [1]\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n divisors.append(i)\n if i != n // i:\n divisors.append(n // i)\n return sum(divisors)\ndef is_amicable(a):\n \"\"\"Check if a is an amicable number.\"\"\"\n b = sum_of_divisors(a)\n return b != a and sum_of_divisors(b) == a\ndef amicable_numbers_sum(limit):\n \"\"\"Return the sum of all amicable numbers from 1 to limit.\"\"\"\n amicable_sum = 0\n for num in range(1, limit + 1):\n if is_amicable(num):\n amicable_sum += num\n return amicable_sum", "matching_cluster_idx": 11}, {"solution": "def sum_of_divisors(n):\n \"\"\"Return the sum of proper divisors of n.\"\"\"\n divisors = [1]\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n divisors.append(i)\n if i != n // i:\n divisors.append(n // i)\n return sum(divisors)\ndef is_amicable(a):\n \"\"\"Check if a is an amicable number.\"\"\"\n b = sum_of_divisors(a)\n return b != a and sum_of_divisors(b) == a\ndef amicable_numbers_sum(limit):\n \"\"\"Return the sum of all amicable numbers up to the specified limit.\"\"\"\n amicable_sum = 0\n for num in range(1, limit + 1):\n if is_amicable(num):\n amicable_sum += num\n return amicable_sum", "matching_cluster_idx": 11}, {"solution": "def sum_of_divisors(n):\n \"\"\"Return the sum of proper divisors of n.\"\"\"\n divisors = [1]\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n divisors.append(i)\n if i != n // i:\n divisors.append(n // i)\n return sum(divisors)\ndef is_amicable(a):\n \"\"\"Check if a is an amicable number.\"\"\"\n b = sum_of_divisors(a)\n return b != a and sum_of_divisors(b) == a\ndef amicable_numbers_sum(limit):\n \"\"\"Return the sum of all amicable numbers from 1 to limit.\"\"\"\n amicable_sum = 0\n for num in range(1, limit + 1):\n if is_amicable(num):\n amicable_sum += num\n return amicable_sum", "matching_cluster_idx": 11}, {"solution": "def sum_of_divisors(n):\n \"\"\"Return the sum of proper divisors of n.\"\"\"\n divisors_sum = 1\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n divisors_sum += i\n if i != n // i:\n divisors_sum += n // i\n return divisors_sum\ndef is_amicable(a):\n \"\"\"Check if a is an amicable number.\"\"\"\n b = sum_of_divisors(a)\n return b != a and sum_of_divisors(b) == a\ndef amicable_numbers_sum(limit):\n \"\"\"Return the sum of all amicable numbers from 1 to limit.\"\"\"\n amicable_sum = 0\n for num in range(1, limit + 1):\n if is_amicable(num):\n amicable_sum += num\n return amicable_sum", "matching_cluster_idx": 11}, {"solution": "def sum_of_divisors(n):\n \"\"\"Return the sum of proper divisors of n.\"\"\"\n total = 1\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n total += i\n if i != n // i:\n total += n // i\n return total\ndef is_amicable(a):\n \"\"\"Check if a is an amicable number.\"\"\"\n b = sum_of_divisors(a)\n return b != a and sum_of_divisors(b) == a\ndef amicable_numbers_sum(limit):\n \"\"\"Return the sum of all amicable numbers up to the given limit.\"\"\"\n amicable_sum = 0\n for num in range(1, limit + 1):\n if is_amicable(num):\n amicable_sum += num\n return amicable_sum", "matching_cluster_idx": 11}, {"solution": "def sum_of_divisors(n):\n \"\"\"Return the sum of proper divisors of n.\"\"\"\n total = 1\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n total += i\n if i != n // i:\n total += n // i\n return total\ndef is_amicable(a):\n \"\"\"Check if a is an amicable number.\"\"\"\n b = sum_of_divisors(a)\n return b != a and sum_of_divisors(b) == a\ndef amicable_numbers_sum(limit):\n \"\"\"Return the sum of all amicable numbers from 1 to limit.\"\"\"\n amicable_sum = 0\n for num in range(1, limit + 1):\n if is_amicable(num):\n amicable_sum += num\n return amicable_sum", "matching_cluster_idx": 11}, {"solution": "def sum_of_divisors(n):\n \"\"\"Return the sum of proper divisors of n.\"\"\"\n divisors_sum = 1 # 1 is a proper divisor for any n > 1\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n divisors_sum += i\n if i != n // i:\n divisors_sum += n // i\n return divisors_sum\ndef is_amicable(a):\n \"\"\"Check if a is an amicable number.\"\"\"\n b = sum_of_divisors(a)\n return b != a and sum_of_divisors(b) == a\ndef amicable_numbers_sum(limit):\n \"\"\"Return the sum of all amicable numbers from 1 to limit.\"\"\"\n amicable_sum = 0\n for num in range(1, limit + 1):\n if is_amicable(num):\n amicable_sum += num\n return amicable_sum", "matching_cluster_idx": 11}, {"solution": "def sum_of_divisors(n):\n \"\"\"Return the sum of proper divisors of n.\"\"\"\n divisors = [1]\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n divisors.append(i)\n if i != n // i:\n divisors.append(n // i)\n return sum(divisors)\ndef is_amicable(a):\n \"\"\"Check if a is an amicable number.\"\"\"\n b = sum_of_divisors(a)\n return b != a and sum_of_divisors(b) == a\ndef amicable_numbers_sum(limit):\n \"\"\"Return the sum of all amicable numbers up to the specified limit.\"\"\"\n amicable_sum = 0\n for num in range(1, limit + 1):\n if is_amicable(num):\n amicable_sum += num\n return amicable_sum", "matching_cluster_idx": 11}, {"solution": "def sum_of_divisors(n):\n \"\"\"Calculate the sum of proper divisors of n.\"\"\"\n divisors_sum = 1 # 1 is a proper divisor for any n > 1\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n divisors_sum += i\n if i != n // i:\n divisors_sum += n // i\n return divisors_sum\ndef is_amicable(a):\n \"\"\"Check if a is an amicable number.\"\"\"\n b = sum_of_divisors(a)\n return b != a and sum_of_divisors(b) == a\ndef amicable_numbers_sum(limit):\n \"\"\"Sum all amicable numbers from 1 to the specified limit.\"\"\"\n amicable_sum = 0\n for num in range(1, limit + 1):\n if is_amicable(num):\n amicable_sum += num\n return amicable_sum", "matching_cluster_idx": 11}, {"solution": "def sum_of_divisors(n):\n \"\"\"Return the sum of proper divisors of n.\"\"\"\n divisors_sum = 1 # 1 is a proper divisor for any n > 1\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n divisors_sum += i\n if i != n // i:\n divisors_sum += n // i\n return divisors_sum\ndef is_amicable(a):\n \"\"\"Check if a is an amicable number.\"\"\"\n b = sum_of_divisors(a)\n return b != a and sum_of_divisors(b) == a\ndef amicable_numbers_sum(limit):\n \"\"\"Return the sum of all amicable numbers up to the given limit.\"\"\"\n amicable_sum = 0\n for num in range(1, limit + 1):\n if is_amicable(num):\n amicable_sum += num\n return amicable_sum", "matching_cluster_idx": 11}, {"solution": "def sum_of_divisors(n):\n \"\"\"Return the sum of proper divisors of n.\"\"\"\n divisors = [1]\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n divisors.append(i)\n if i != n // i:\n divisors.append(n // i)\n return sum(divisors)\ndef is_amicable(a):\n \"\"\"Check if a is an amicable number.\"\"\"\n b = sum_of_divisors(a)\n return b != a and sum_of_divisors(b) == a\ndef amicable_numbers_sum(limit):\n \"\"\"Return the sum of all amicable numbers from 1 to limit.\"\"\"\n amicable_sum = 0\n for num in range(1, limit + 1):\n if is_amicable(num):\n amicable_sum += num\n return amicable_sum", "matching_cluster_idx": 11}, {"solution": "def sum_of_divisors(n):\n \"\"\"Return the sum of proper divisors of n.\"\"\"\n divisors = [1]\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n divisors.append(i)\n if i != n // i:\n divisors.append(n // i)\n return sum(divisors)\ndef is_amicable(a):\n \"\"\"Check if a is an amicable number.\"\"\"\n b = sum_of_divisors(a)\n return b != a and sum_of_divisors(b) == a\ndef amicable_numbers_sum(limit):\n \"\"\"Return the sum of all amicable numbers from 1 to limit.\"\"\"\n amicable_sum = 0\n for num in range(1, limit + 1):\n if is_amicable(num):\n amicable_sum += num\n return amicable_sum", "matching_cluster_idx": 11}, {"solution": "def sum_of_divisors(n):\n \"\"\"Return the sum of proper divisors of n.\"\"\"\n total = 1\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n total += i\n if i != n // i:\n total += n // i\n return total\ndef is_amicable(a):\n \"\"\"Check if a is an amicable number.\"\"\"\n b = sum_of_divisors(a)\n return b != a and sum_of_divisors(b) == a\ndef amicable_numbers_sum(limit):\n \"\"\"Return the sum of all amicable numbers from 1 to limit.\"\"\"\n amicable_sum = 0\n for num in range(1, limit + 1):\n if is_amicable(num):\n amicable_sum += num\n return amicable_sum", "matching_cluster_idx": 11}, {"solution": "def sum_of_divisors(n):\n \"\"\"Return the sum of proper divisors of n.\"\"\"\n divisors = [1]\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n divisors.append(i)\n if i != n // i:\n divisors.append(n // i)\n return sum(divisors)\ndef is_amicable(a):\n \"\"\"Check if a is an amicable number.\"\"\"\n b = sum_of_divisors(a)\n return b != a and sum_of_divisors(b) == a\ndef amicable_numbers_sum(limit):\n \"\"\"Return the sum of all amicable numbers from 1 to limit.\"\"\"\n amicable_sum = 0\n for num in range(1, limit + 1):\n if is_amicable(num):\n amicable_sum += num\n return amicable_sum", "matching_cluster_idx": 11}, {"solution": "def sum_of_divisors(n):\n \"\"\"Calculate the sum of proper divisors of n.\"\"\"\n total = 1\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n total += i\n if i != n // i:\n total += n // i\n return total\ndef is_amicable(a):\n \"\"\"Check if a number is part of an amicable pair.\"\"\"\n b = sum_of_divisors(a)\n return b != a and sum_of_divisors(b) == a\ndef amicable_numbers_sum(limit):\n \"\"\"Sum all amicable numbers from 1 to the specified limit.\"\"\"\n amicable_sum = 0\n for num in range(1, limit + 1):\n if is_amicable(num):\n amicable_sum += num\n return amicable_sum", "matching_cluster_idx": 11}, {"solution": "def sum_of_divisors(n):\n \"\"\"Return the sum of proper divisors of n.\"\"\"\n divisors_sum = 1\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n divisors_sum += i\n if i != n // i:\n divisors_sum += n // i\n return divisors_sum\ndef is_amicable(a):\n \"\"\"Check if a is an amicable number.\"\"\"\n b = sum_of_divisors(a)\n return b != a and sum_of_divisors(b) == a\ndef amicable_numbers_sum(limit):\n \"\"\"Return the sum of all amicable numbers from 1 to limit.\"\"\"\n amicable_sum = 0\n for num in range(1, limit + 1):\n if is_amicable(num):\n amicable_sum += num\n return amicable_sum", "matching_cluster_idx": 11}, {"solution": "def sum_of_divisors(n):\n \"\"\"Return the sum of proper divisors of n.\"\"\"\n divisors = [1]\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n divisors.append(i)\n if i != n // i:\n divisors.append(n // i)\n return sum(divisors)\ndef is_amicable(a):\n \"\"\"Check if a is an amicable number.\"\"\"\n b = sum_of_divisors(a)\n return b != a and sum_of_divisors(b) == a\ndef amicable_numbers_sum(limit):\n \"\"\"Return the sum of all amicable numbers from 1 to limit.\"\"\"\n amicable_sum = 0\n for num in range(1, limit + 1):\n if is_amicable(num):\n amicable_sum += num\n return amicable_sum", "matching_cluster_idx": 11}, {"solution": "def sum_of_divisors(n):\n \"\"\"Return the sum of proper divisors of n.\"\"\"\n total = 1\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n total += i\n if i != n // i:\n total += n // i\n return total\ndef is_amicable(a):\n \"\"\"Check if a is an amicable number.\"\"\"\n b = sum_of_divisors(a)\n return b != a and sum_of_divisors(b) == a\ndef amicable_numbers_sum(limit):\n \"\"\"Return the sum of all amicable numbers from 1 to limit.\"\"\"\n amicable_sum = 0\n for num in range(1, limit + 1):\n if is_amicable(num):\n amicable_sum += num\n return amicable_sum", "matching_cluster_idx": 11}, {"solution": "def sum_of_divisors(n):\n \"\"\"Return the sum of proper divisors of n.\"\"\"\n divisors = [1]\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n divisors.append(i)\n if i != n // i:\n divisors.append(n // i)\n return sum(divisors)\ndef is_amicable(a):\n \"\"\"Check if a number is part of an amicable pair.\"\"\"\n b = sum_of_divisors(a)\n return b != a and sum_of_divisors(b) == a\ndef amicable_numbers_sum(limit):\n \"\"\"Return the sum of all amicable numbers up to the given limit.\"\"\"\n amicable_sum = 0\n for num in range(1, limit + 1):\n if is_amicable(num):\n amicable_sum += num\n return amicable_sum", "matching_cluster_idx": 11}]}, "Mbpp/128": {"dps": 99.5475113122172, "dps_norm": 80.0, "pass@1": 100.0, "profiled": [{"solution": "def long_words(n, sentence):\n # Split the sentence into words\n words = sentence.split()\n # Filter words that are longer than n characters\n result = [word for word in words if len(word) > n]\n return result", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n # Split the sentence into words\n words = sentence.split()\n \n # Filter words that are longer than n characters\n result = [word for word in words if len(word) > n]\n \n return result", "matching_cluster_idx": 3}, {"solution": "def long_words(n, text):\n # Split the text into words\n words = text.split()\n # Filter words that are longer than n characters\n result = [word for word in words if len(word) > n]\n return result", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n # Split the sentence into words\n words = sentence.split()\n # Filter words that are longer than n characters\n result = [word for word in words if len(word) > n]\n return result", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n # Split the sentence into words\n words = sentence.split()\n # Filter words that are longer than n characters\n result = [word for word in words if len(word) > n]\n return result", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n # Split the sentence into words\n words = sentence.split()\n # Filter words that are longer than n characters\n result = [word for word in words if len(word) > n]\n return result", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n \"\"\"\n Returns a list of words from the sentence that are longer than n characters.\n \n :param n: The minimum length of words to include.\n :param sentence: A string containing words separated by spaces.\n :return: A list of words longer than n characters.\n \"\"\"\n words = sentence.split()\n return [word for word in words if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n # Split the sentence into words\n words = sentence.split()\n # Filter words that are longer than n characters\n result = [word for word in words if len(word) > n]\n return result", "matching_cluster_idx": 3}, {"solution": "def long_words(n, words):\n # Split the input string into a list of words\n word_list = words.split()\n # Filter the list to include only words longer than n characters\n result = [word for word in word_list if len(word) > n]\n return result", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n # Split the sentence into words\n words = sentence.split()\n \n # Filter words that are longer than n characters\n result = [word for word in words if len(word) > n]\n \n return result", "matching_cluster_idx": 3}, {"solution": "def long_words(n, words):\n # Split the input string into a list of words\n word_list = words.split()\n # Filter the words that are longer than n characters\n result = [word for word in word_list if len(word) > n]\n return result", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n # Split the sentence into words\n words = sentence.split()\n # Filter words that are longer than n characters\n result = [word for word in words if len(word) > n]\n return result", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n # Split the sentence into words\n words = sentence.split()\n \n # Filter words that are longer than n characters\n result = [word for word in words if len(word) > n]\n \n return result", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n # Split the sentence into words\n words = sentence.split()\n # Filter words that are longer than n characters\n result = [word for word in words if len(word) > n]\n return result", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n \"\"\"\n Returns a list of words from the sentence that are longer than n characters.\n \n :param n: The minimum length of words to include.\n :param sentence: A string containing words separated by spaces.\n :return: A list of words longer than n characters.\n \"\"\"\n words = sentence.split()\n return [word for word in words if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, words):\n # Split the input string into a list of words\n word_list = words.split()\n # Filter the list to include only words longer than n characters\n result = [word for word in word_list if len(word) > n]\n return result", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n # Split the sentence into words\n words = sentence.split()\n # Filter words that are longer than n characters\n result = [word for word in words if len(word) > n]\n return result", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n # Split the sentence into words\n words = sentence.split()\n \n # Filter words that are longer than n characters\n result = [word for word in words if len(word) > n]\n \n return result", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n # Split the sentence into words\n words = sentence.split()\n \n # Filter words that are longer than n characters\n result = [word for word in words if len(word) > n]\n \n return result", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n # Split the sentence into words\n words = sentence.split()\n # Filter words that are longer than n characters\n result = [word for word in words if len(word) > n]\n return result", "matching_cluster_idx": 3}]}, "Mbpp/129": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 96.0, "profiled": [{"solution": "def magic_square_test(matrix):\n n = len(matrix)\n \n # Calculate the sum of the first row to use as the magic constant\n magic_constant = sum(matrix[0])\n \n # Check sums of all rows\n for row in matrix:\n if sum(row) != magic_constant:\n return False\n \n # Check sums of all columns\n for col in range(n):\n if sum(matrix[row][col] for row in range(n)) != magic_constant:\n return False\n \n # Check sum of the main diagonal\n if sum(matrix[i][i] for i in range(n)) != magic_constant:\n return False\n \n # Check sum of the secondary diagonal\n if sum(matrix[i][n - 1 - i] for i in range(n)) != magic_constant:\n return False\n \n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n n = len(matrix)\n \n # Calculate the sum of the first row to use as the reference sum\n magic_sum = sum(matrix[0])\n \n # Check sums of all rows\n for row in matrix:\n if sum(row) != magic_sum:\n return False\n \n # Check sums of all columns\n for col in range(n):\n if sum(matrix[row][col] for row in range(n)) != magic_sum:\n return False\n \n # Check sum of the main diagonal\n if sum(matrix[i][i] for i in range(n)) != magic_sum:\n return False\n \n # Check sum of the secondary diagonal\n if sum(matrix[i][n - 1 - i] for i in range(n)) != magic_sum:\n return False\n \n # If all checks pass, it's a magic square\n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n n = len(matrix)\n \n # Calculate the sum of the first row to use as the reference sum\n magic_sum = sum(matrix[0])\n \n # Check sums of all rows\n for row in matrix:\n if sum(row) != magic_sum:\n return False\n \n # Check sums of all columns\n for col in range(n):\n if sum(matrix[row][col] for row in range(n)) != magic_sum:\n return False\n \n # Check sum of the main diagonal\n if sum(matrix[i][i] for i in range(n)) != magic_sum:\n return False\n \n # Check sum of the secondary diagonal\n if sum(matrix[i][n - i - 1] for i in range(n)) != magic_sum:\n return False\n \n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n n = len(matrix)\n \n # Calculate the sum of the first row to use as the reference sum\n magic_sum = sum(matrix[0])\n \n # Check sums of all rows\n for row in matrix:\n if sum(row) != magic_sum:\n return False\n \n # Check sums of all columns\n for col in range(n):\n if sum(matrix[row][col] for row in range(n)) != magic_sum:\n return False\n \n # Check sum of the main diagonal\n if sum(matrix[i][i] for i in range(n)) != magic_sum:\n return False\n \n # Check sum of the secondary diagonal\n if sum(matrix[i][n - 1 - i] for i in range(n)) != magic_sum:\n return False\n \n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n n = len(matrix)\n \n # Calculate the sum of the first row to use as the magic constant\n magic_constant = sum(matrix[0])\n \n # Check sums of all rows\n for row in matrix:\n if sum(row) != magic_constant:\n return False\n \n # Check sums of all columns\n for col in range(n):\n if sum(matrix[row][col] for row in range(n)) != magic_constant:\n return False\n \n # Check sum of the main diagonal\n if sum(matrix[i][i] for i in range(n)) != magic_constant:\n return False\n \n # Check sum of the secondary diagonal\n if sum(matrix[i][n - 1 - i] for i in range(n)) != magic_constant:\n return False\n \n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n n = len(matrix)\n \n # Calculate the sum of the first row to use as the reference sum\n magic_sum = sum(matrix[0])\n \n # Check sums of all rows\n for row in matrix:\n if sum(row) != magic_sum:\n return False\n \n # Check sums of all columns\n for col in range(n):\n if sum(matrix[row][col] for row in range(n)) != magic_sum:\n return False\n \n # Check sum of the main diagonal\n if sum(matrix[i][i] for i in range(n)) != magic_sum:\n return False\n \n # Check sum of the secondary diagonal\n if sum(matrix[i][n - 1 - i] for i in range(n)) != magic_sum:\n return False\n \n # If all checks pass, it is a magic square\n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n n = len(matrix)\n \n # Calculate the sum of the first row to use as the reference sum\n magic_sum = sum(matrix[0])\n \n # Check sums of all rows\n for row in matrix:\n if sum(row) != magic_sum:\n return False\n \n # Check sums of all columns\n for col in range(n):\n if sum(matrix[row][col] for row in range(n)) != magic_sum:\n return False\n \n # Check sum of the main diagonal\n if sum(matrix[i][i] for i in range(n)) != magic_sum:\n return False\n \n # Check sum of the secondary diagonal\n if sum(matrix[i][n - 1 - i] for i in range(n)) != magic_sum:\n return False\n \n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n n = len(matrix)\n \n # Calculate the sum of the first row to use as the magic constant\n magic_constant = sum(matrix[0])\n \n # Check sums of all rows\n for row in matrix:\n if sum(row) != magic_constant:\n return False\n \n # Check sums of all columns\n for col in range(n):\n if sum(matrix[row][col] for row in range(n)) != magic_constant:\n return False\n \n # Check sum of the main diagonal\n if sum(matrix[i][i] for i in range(n)) != magic_constant:\n return False\n \n # Check sum of the secondary diagonal\n if sum(matrix[i][n - 1 - i] for i in range(n)) != magic_constant:\n return False\n \n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n n = len(matrix)\n \n # Calculate the sum of the first row to use as the reference sum\n magic_sum = sum(matrix[0])\n \n # Check sums of all rows\n for row in matrix:\n if sum(row) != magic_sum:\n return False\n \n # Check sums of all columns\n for col in range(n):\n if sum(matrix[row][col] for row in range(n)) != magic_sum:\n return False\n \n # Check sum of the main diagonal\n if sum(matrix[i][i] for i in range(n)) != magic_sum:\n return False\n \n # Check sum of the secondary diagonal\n if sum(matrix[i][n - 1 - i] for i in range(n)) != magic_sum:\n return False\n \n # If all checks pass, it's a magic square\n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n n = len(matrix)\n \n # Calculate the sum of the first row to use as the reference sum\n magic_sum = sum(matrix[0])\n \n # Check sums of all rows\n for row in matrix:\n if sum(row) != magic_sum:\n return False\n \n # Check sums of all columns\n for col in range(n):\n if sum(matrix[row][col] for row in range(n)) != magic_sum:\n return False\n \n # Check sum of the main diagonal\n if sum(matrix[i][i] for i in range(n)) != magic_sum:\n return False\n \n # Check sum of the secondary diagonal\n if sum(matrix[i][n - 1 - i] for i in range(n)) != magic_sum:\n return False\n \n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n n = len(matrix)\n \n # Calculate the sum of the first row to use as the reference sum\n magic_sum = sum(matrix[0])\n \n # Check sums of all rows\n for row in matrix:\n if sum(row) != magic_sum:\n return False\n \n # Check sums of all columns\n for col in range(n):\n if sum(matrix[row][col] for row in range(n)) != magic_sum:\n return False\n \n # Check sum of the main diagonal\n if sum(matrix[i][i] for i in range(n)) != magic_sum:\n return False\n \n # Check sum of the secondary diagonal\n if sum(matrix[i][n - 1 - i] for i in range(n)) != magic_sum:\n return False\n \n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n n = len(matrix)\n \n # Calculate the sum of the first row to use as the reference sum\n magic_sum = sum(matrix[0])\n \n # Check sums of all rows\n for row in matrix:\n if sum(row) != magic_sum:\n return False\n \n # Check sums of all columns\n for col in range(n):\n if sum(matrix[row][col] for row in range(n)) != magic_sum:\n return False\n \n # Check sum of the main diagonal\n if sum(matrix[i][i] for i in range(n)) != magic_sum:\n return False\n \n # Check sum of the secondary diagonal\n if sum(matrix[i][n - 1 - i] for i in range(n)) != magic_sum:\n return False\n \n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n n = len(matrix)\n \n # Calculate the sum of the first row to use as the magic constant\n magic_constant = sum(matrix[0])\n \n # Check sums of all rows\n for row in matrix:\n if sum(row) != magic_constant:\n return False\n \n # Check sums of all columns\n for col in range(n):\n if sum(matrix[row][col] for row in range(n)) != magic_constant:\n return False\n \n # Check sum of the main diagonal\n if sum(matrix[i][i] for i in range(n)) != magic_constant:\n return False\n \n # Check sum of the secondary diagonal\n if sum(matrix[i][n - 1 - i] for i in range(n)) != magic_constant:\n return False\n \n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n n = len(matrix)\n \n # Calculate the sum of the first row to use as the reference sum\n magic_sum = sum(matrix[0])\n \n # Check sums of all rows\n for row in matrix:\n if sum(row) != magic_sum:\n return False\n \n # Check sums of all columns\n for col in range(n):\n if sum(matrix[row][col] for row in range(n)) != magic_sum:\n return False\n \n # Check sum of the main diagonal\n if sum(matrix[i][i] for i in range(n)) != magic_sum:\n return False\n \n # Check sum of the secondary diagonal\n if sum(matrix[i][n - 1 - i] for i in range(n)) != magic_sum:\n return False\n \n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n n = len(matrix)\n \n # Calculate the sum of the first row to use as the magic constant\n magic_constant = sum(matrix[0])\n \n # Check sums of all rows\n for row in matrix:\n if sum(row) != magic_constant:\n return False\n \n # Check sums of all columns\n for col in range(n):\n if sum(matrix[row][col] for row in range(n)) != magic_constant:\n return False\n \n # Check sum of the main diagonal\n if sum(matrix[i][i] for i in range(n)) != magic_constant:\n return False\n \n # Check sum of the secondary diagonal\n if sum(matrix[i][n - 1 - i] for i in range(n)) != magic_constant:\n return False\n \n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n n = len(matrix)\n \n # Calculate the sum of the first row to use as the reference sum\n magic_sum = sum(matrix[0])\n \n # Check sums of all rows\n for row in matrix:\n if sum(row) != magic_sum:\n return False\n \n # Check sums of all columns\n for col in range(n):\n if sum(matrix[row][col] for row in range(n)) != magic_sum:\n return False\n \n # Check sum of the main diagonal\n if sum(matrix[i][i] for i in range(n)) != magic_sum:\n return False\n \n # Check sum of the secondary diagonal\n if sum(matrix[i][n - 1 - i] for i in range(n)) != magic_sum:\n return False\n \n # If all checks pass, it's a magic square\n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n n = len(matrix)\n \n # Calculate the sum of the first row to use as the magic constant\n magic_constant = sum(matrix[0])\n \n # Check sums of all rows\n for row in matrix:\n if sum(row) != magic_constant:\n return False\n \n # Check sums of all columns\n for col in range(n):\n if sum(matrix[row][col] for row in range(n)) != magic_constant:\n return False\n \n # Check sum of the main diagonal\n if sum(matrix[i][i] for i in range(n)) != magic_constant:\n return False\n \n # Check sum of the secondary diagonal\n if sum(matrix[i][n - 1 - i] for i in range(n)) != magic_constant:\n return False\n \n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n n = len(matrix)\n \n # Calculate the sum of the first row to use as the reference sum\n magic_sum = sum(matrix[0])\n \n # Check sums of all rows\n for row in matrix:\n if sum(row) != magic_sum:\n return False\n \n # Check sums of all columns\n for col in range(n):\n if sum(matrix[row][col] for row in range(n)) != magic_sum:\n return False\n \n # Check sum of the main diagonal\n if sum(matrix[i][i] for i in range(n)) != magic_sum:\n return False\n \n # Check sum of the secondary diagonal\n if sum(matrix[i][n - 1 - i] for i in range(n)) != magic_sum:\n return False\n \n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n n = len(matrix)\n \n # Calculate the sum of the first row to use as the magic constant\n magic_constant = sum(matrix[0])\n \n # Check sums of all rows\n for row in matrix:\n if sum(row) != magic_constant:\n return False\n \n # Check sums of all columns\n for col in range(n):\n if sum(matrix[row][col] for row in range(n)) != magic_constant:\n return False\n \n # Check sum of the main diagonal\n if sum(matrix[i][i] for i in range(n)) != magic_constant:\n return False\n \n # Check sum of the secondary diagonal\n if sum(matrix[i][n - 1 - i] for i in range(n)) != magic_constant:\n return False\n \n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n n = len(matrix)\n \n # Calculate the sum of the first row to use as the reference sum\n magic_sum = sum(matrix[0])\n \n # Check sums of all rows\n for row in matrix:\n if sum(row) != magic_sum:\n return False\n \n # Check sums of all columns\n for col in range(n):\n if sum(matrix[row][col] for row in range(n)) != magic_sum:\n return False\n \n # Check sum of the main diagonal\n if sum(matrix[i][i] for i in range(n)) != magic_sum:\n return False\n \n # Check sum of the secondary diagonal\n if sum(matrix[i][n - 1 - i] for i in range(n)) != magic_sum:\n return False\n \n return True", "matching_cluster_idx": 14}]}, "Mbpp/130": {"dps": 74.66367713004485, "dps_norm": 66.66666666666667, "pass@1": 100.0, "profiled": [{"solution": "def max_occurrences(lst):\n # Create a dictionary to store the frequency of each item\n frequency = {}\n \n # Count the occurrences of each item in the list\n for item in lst:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n \n # Find the item with the maximum frequency\n max_item = max(frequency, key=frequency.get)\n \n return max_item", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(lst):\n # Create a dictionary to store the frequency of each item\n frequency = {}\n \n # Iterate through the list and count the occurrences of each item\n for item in lst:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n \n # Find the item with the maximum frequency\n max_item = max(frequency, key=frequency.get)\n \n return max_item", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(lst):\n # Create a dictionary to store the frequency of each item\n frequency = {}\n \n # Iterate through the list and count the occurrences of each item\n for item in lst:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n \n # Find the item with the maximum frequency\n max_item = max(frequency, key=frequency.get)\n \n return max_item", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(lst):\n # Create a dictionary to store the frequency of each item\n frequency = {}\n \n # Iterate through the list and count the occurrences of each item\n for item in lst:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n \n # Find the item with the maximum frequency\n max_item = max(frequency, key=frequency.get)\n \n return max_item", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(lst):\n # Create a dictionary to store the frequency of each item\n frequency = {}\n \n # Count the occurrences of each item in the list\n for item in lst:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n \n # Find the item with the maximum frequency\n max_item = max(frequency, key=frequency.get)\n \n return max_item", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(lst):\n # Create a dictionary to store the frequency of each item\n frequency = {}\n \n # Iterate through the list and count the occurrences of each item\n for item in lst:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n \n # Find the item with the maximum frequency\n max_item = max(frequency, key=frequency.get)\n \n return max_item", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(lst):\n # Create a dictionary to store the frequency of each item\n frequency = {}\n \n # Count the occurrences of each item in the list\n for item in lst:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n \n # Find the item with the maximum frequency\n max_item = max(frequency, key=frequency.get)\n \n return max_item", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(lst):\n # Create a dictionary to store the frequency of each item\n frequency = {}\n \n # Iterate through the list and count the occurrences of each item\n for item in lst:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n \n # Find the item with the maximum frequency\n max_item = max(frequency, key=frequency.get)\n \n return max_item", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(lst):\n # Create a dictionary to store the frequency of each item\n frequency = {}\n \n # Count the occurrences of each item in the list\n for item in lst:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n \n # Find the item with the maximum frequency\n max_item = max(frequency, key=frequency.get)\n \n return max_item", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(lst):\n # Create a dictionary to store the frequency of each item\n frequency = {}\n \n # Iterate through the list and count the occurrences of each item\n for item in lst:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n \n # Find the item with the maximum frequency\n max_item = max(frequency, key=frequency.get)\n \n return max_item", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(lst):\n # Create a dictionary to store the frequency of each item\n frequency = {}\n \n # Count the occurrences of each item in the list\n for item in lst:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n \n # Find the item with the maximum frequency\n max_item = max(frequency, key=frequency.get)\n \n return max_item", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(lst):\n # Create a dictionary to store the frequency of each item\n frequency = {}\n \n # Count the occurrences of each item in the list\n for item in lst:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n \n # Find the item with the maximum frequency\n max_item = max(frequency, key=frequency.get)\n \n return max_item", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(lst):\n # Create a dictionary to store the frequency of each item\n frequency = {}\n \n # Count the occurrences of each item in the list\n for item in lst:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n \n # Find the item with the maximum frequency\n max_item = max(frequency, key=frequency.get)\n \n return max_item", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(lst):\n # Create a dictionary to store the frequency of each item\n frequency = {}\n \n # Count the occurrences of each item in the list\n for item in lst:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n \n # Find the item with the maximum frequency\n max_item = max(frequency, key=frequency.get)\n \n return max_item", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(lst):\n # Create a dictionary to store the frequency of each item\n frequency = {}\n \n # Count the occurrences of each item in the list\n for item in lst:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n \n # Find the item with the maximum frequency\n max_item = max(frequency, key=frequency.get)\n \n return max_item", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(lst):\n # Create a dictionary to count the frequency of each item\n frequency = {}\n \n # Count the occurrences of each item in the list\n for item in lst:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n \n # Find the item with the maximum frequency\n max_item = max(frequency, key=frequency.get)\n \n return max_item", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(lst):\n # Create a dictionary to store the frequency of each item\n frequency = {}\n \n # Count the occurrences of each item in the list\n for item in lst:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n \n # Find the item with the maximum frequency\n max_item = max(frequency, key=frequency.get)\n \n return max_item", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(lst):\n # Create a dictionary to store the frequency of each item\n frequency = {}\n \n # Count the occurrences of each item in the list\n for item in lst:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n \n # Find the item with the maximum frequency\n max_item = max(frequency, key=frequency.get)\n \n return max_item", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(lst):\n # Create a dictionary to store the frequency of each item\n frequency = {}\n \n # Iterate through the list and count the occurrences of each item\n for item in lst:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n \n # Find the item with the maximum frequency\n max_item = max(frequency, key=frequency.get)\n \n return max_item", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(lst):\n # Create a dictionary to store the frequency of each item\n frequency = {}\n \n # Count the occurrences of each item in the list\n for item in lst:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n \n # Find the item with the maximum frequency\n max_item = max(frequency, key=frequency.get)\n \n return max_item", "matching_cluster_idx": 3}]}, "Mbpp/137": {"dps": null, "dps_norm": null, "pass@1": 0.0, "profiled": []}, "Mbpp/140": {"dps": 84.02173913043478, "dps_norm": 76.875, "pass@1": 100.0, "profiled": [{"solution": "def extract_singly(nested_list):\n \"\"\"\n Flatten the list of lists into a single set of numbers.\n \n Args:\n nested_list (list of tuples): A list containing tuples of numbers.\n \n Returns:\n set: A set containing all unique numbers from the nested list.\n \"\"\"\n return {num for sublist in nested_list for num in sublist}", "matching_cluster_idx": 5}, {"solution": "def extract_singly(nested_list):\n \"\"\"\n Flatten the list of lists into a single set of numbers.\n \n Args:\n nested_list (list of tuples): A list containing tuples of numbers.\n \n Returns:\n set: A set containing all unique numbers from the nested list.\n \"\"\"\n return {num for sublist in nested_list for num in sublist}", "matching_cluster_idx": 5}, {"solution": "def extract_singly(nested_list):\n \"\"\"\n Flatten the list of lists into a single set of numbers.\n \n Args:\n nested_list (list of lists): A list containing lists of numbers.\n \n Returns:\n set: A set containing all unique numbers from the nested lists.\n \"\"\"\n return {num for sublist in nested_list for num in sublist}", "matching_cluster_idx": 5}, {"solution": "def extract_singly(nested_list):\n \"\"\"\n Flatten a list of lists into a single set of numbers.\n \n Args:\n nested_list (list of lists): A list containing lists of numbers.\n \n Returns:\n set: A set containing all unique numbers from the nested lists.\n \"\"\"\n return {num for sublist in nested_list for num in sublist}", "matching_cluster_idx": 5}, {"solution": "def extract_singly(nested_list):\n \"\"\"\n Flatten a list of lists into a single set of numbers.\n \n Args:\n nested_list (list of lists): A list containing lists of numbers.\n \n Returns:\n set: A set containing all unique numbers from the nested lists.\n \"\"\"\n return {num for sublist in nested_list for num in sublist}", "matching_cluster_idx": 5}, {"solution": "def extract_singly(nested_list):\n \"\"\"\n Flatten the list of lists into a single set of numbers.\n \n Args:\n nested_list (list of tuples): A list containing tuples of numbers.\n \n Returns:\n set: A set containing all unique numbers from the nested list.\n \"\"\"\n return {num for sublist in nested_list for num in sublist}", "matching_cluster_idx": 5}, {"solution": "def extract_singly(nested_list):\n \"\"\"\n Flatten the list of lists into a single set of numbers.\n \n Args:\n nested_list (list of tuples): A list containing tuples of numbers.\n \n Returns:\n set: A set containing all unique numbers from the nested list.\n \"\"\"\n return {num for sublist in nested_list for num in sublist}", "matching_cluster_idx": 5}, {"solution": "def extract_singly(nested_list):\n \"\"\"\n Flatten a list of lists into a single set of numbers.\n \n Args:\n nested_list (list of lists): A list containing lists of numbers.\n \n Returns:\n set: A set containing all unique numbers from the nested list.\n \"\"\"\n return {num for sublist in nested_list for num in sublist}", "matching_cluster_idx": 5}, {"solution": "def extract_singly(nested_list):\n \"\"\"\n Flatten the list of lists into a single set of numbers.\n \n Args:\n nested_list (list of tuples): A list containing tuples of numbers.\n \n Returns:\n set: A set containing all unique numbers from the nested list.\n \"\"\"\n return {num for sublist in nested_list for num in sublist}", "matching_cluster_idx": 5}, {"solution": "def extract_singly(nested_list):\n \"\"\"\n Flatten a list of lists into a single set of numbers.\n \n Args:\n nested_list (list of lists): A list containing lists of numbers.\n \n Returns:\n set: A set containing all unique numbers from the nested lists.\n \"\"\"\n return {num for sublist in nested_list for num in sublist}", "matching_cluster_idx": 5}, {"solution": "def extract_singly(nested_lists):\n \"\"\"\n Flatten the list of lists into a single set of numbers.\n \n Args:\n nested_lists (list of lists): A list containing lists of numbers.\n \n Returns:\n set: A set containing all unique numbers from the nested lists.\n \"\"\"\n return {num for sublist in nested_lists for num in sublist}", "matching_cluster_idx": 5}, {"solution": "def extract_singly(nested_list):\n \"\"\"\n Flatten the list of lists into a single set of numbers.\n \n Args:\n nested_list (list of tuples): A list containing tuples of numbers.\n \n Returns:\n set: A set containing all unique numbers from the nested list.\n \"\"\"\n return {num for sublist in nested_list for num in sublist}", "matching_cluster_idx": 5}, {"solution": "def extract_singly(nested_list):\n \"\"\"\n Flatten a list of lists into a single set of numbers.\n \n Args:\n nested_list (list of lists): A list containing lists of numbers.\n \n Returns:\n set: A set containing all unique numbers from the nested list.\n \"\"\"\n flat_set = set()\n for sublist in nested_list:\n flat_set.update(sublist)\n return flat_set", "matching_cluster_idx": 6}, {"solution": "def extract_singly(nested_list):\n \"\"\"\n Flatten the list of lists into a single set of numbers.\n \n Args:\n nested_list (list of lists): A list containing lists of numbers.\n \n Returns:\n set: A set containing all unique numbers from the nested lists.\n \"\"\"\n return {num for sublist in nested_list for num in sublist}", "matching_cluster_idx": 5}, {"solution": "def extract_singly(nested_list):\n # Initialize an empty set to store the unique numbers\n unique_numbers = set()\n \n # Iterate through each sublist in the nested list\n for sublist in nested_list:\n # Add each number in the sublist to the set\n unique_numbers.update(sublist)\n \n return unique_numbers", "matching_cluster_idx": 6}, {"solution": "def extract_singly(nested_list):\n \"\"\"\n Flatten a list of lists into a single set of numbers.\n \n Args:\n nested_list (list of lists): A list containing lists of numbers.\n \n Returns:\n set: A set containing all unique numbers from the nested lists.\n \"\"\"\n return {num for sublist in nested_list for num in sublist}", "matching_cluster_idx": 5}, {"solution": "def extract_singly(nested_list):\n \"\"\"\n Flatten a list of lists into a single set of numbers.\n \n Args:\n nested_list (list of lists): A list containing lists of numbers.\n \n Returns:\n set: A set containing all unique numbers from the nested lists.\n \"\"\"\n return {num for sublist in nested_list for num in sublist}", "matching_cluster_idx": 5}, {"solution": "def extract_singly(nested_list):\n \"\"\"\n Flatten a list of lists into a single set of numbers.\n \n Args:\n nested_list (list of lists): A list containing lists of numbers.\n \n Returns:\n set: A set containing all unique numbers from the nested list.\n \"\"\"\n return {num for sublist in nested_list for num in sublist}", "matching_cluster_idx": 5}, {"solution": "def extract_singly(nested_list):\n \"\"\"\n Flatten a list of lists into a single set of numbers.\n \n Args:\n nested_list (list of lists): A list containing lists of numbers.\n \n Returns:\n set: A set containing all unique numbers from the nested list.\n \"\"\"\n flat_set = set()\n for sublist in nested_list:\n flat_set.update(sublist)\n return flat_set", "matching_cluster_idx": 6}, {"solution": "def extract_singly(nested_list):\n \"\"\"\n Flatten the list of lists into a single set of numbers.\n \n Args:\n nested_list (list of lists): A list containing lists of numbers.\n \n Returns:\n set: A set containing all unique numbers from the nested lists.\n \"\"\"\n return {num for sublist in nested_list for num in sublist}", "matching_cluster_idx": 5}]}, "Mbpp/141": {"dps": 96.12244897959184, "dps_norm": 49.375, "pass@1": 99.0, "profiled": [{"solution": "def pancake_sort(arr):\n \"\"\"\n Sorts the list using the Pancake Sort algorithm.\n \n :param arr: List of elements to be sorted.\n :return: Sorted list.\n \"\"\"\n def flip(arr, k):\n \"\"\"\n Flips the first k elements of the array.\n \n :param arr: List of elements.\n :param k: Number of elements to flip.\n \"\"\"\n arr[:k] = arr[:k][::-1]\n \n n = len(arr)\n while n > 1:\n # Find the index of the maximum element in the unsorted portion\n max_idx = arr.index(max(arr[:n]))\n \n # If the maximum element is not at the end, flip to bring it to the front\n if max_idx != n - 1:\n if max_idx != 0:\n flip(arr, max_idx + 1)\n # Flip the entire unsorted portion to move the max element to the end\n flip(arr, n)\n \n # Reduce the size of the unsorted portion\n n -= 1\n \n return arr", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(arr):\n def flip(arr, k):\n \"\"\"Helper function to flip the first k elements of the array.\"\"\"\n arr[:k] = arr[:k][::-1]\n \n n = len(arr)\n while n > 1:\n # Find the index of the maximum element in the unsorted portion\n max_idx = arr.index(max(arr[:n]))\n \n # If the maximum element is not at the end, flip to bring it to the front\n if max_idx != n - 1:\n if max_idx != 0:\n flip(arr, max_idx + 1)\n # Flip the entire unsorted portion to move the maximum element to the end\n flip(arr, n)\n \n # Reduce the size of the unsorted portion\n n -= 1\n \n return arr", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(arr):\n \"\"\"\n Sorts a list of elements using the Pancake Sort algorithm.\n \n :param arr: List of elements to be sorted.\n :return: Sorted list of elements.\n \"\"\"\n def flip(arr, k):\n \"\"\"\n Flips the first k elements of the array.\n \n :param arr: List of elements.\n :param k: Number of elements to flip.\n \"\"\"\n arr[:k] = arr[:k][::-1]\n \n n = len(arr)\n while n > 1:\n # Find the index of the maximum element in the unsorted portion\n max_idx = arr.index(max(arr[:n]))\n \n # If the maximum element is not already at the end, flip it to the front\n if max_idx != n - 1:\n if max_idx != 0:\n flip(arr, max_idx + 1)\n # Flip the entire unsorted portion to move the maximum element to the end\n flip(arr, n)\n \n # Reduce the size of the unsorted portion\n n -= 1\n \n return arr", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(arr):\n \"\"\"\n Sorts a list of elements using the Pancake Sort algorithm.\n \n Pancake Sort is a sorting algorithm that works by repeatedly flipping the largest unsorted element\n to the front of the list and then flipping the entire unsorted portion to move it to its correct position.\n \n Args:\n arr (list): The list of elements to be sorted.\n \n Returns:\n list: The sorted list.\n \"\"\"\n def flip(arr, k):\n \"\"\"\n Flips the first k elements of the array.\n \n Args:\n arr (list): The list of elements.\n k (int): The number of elements to flip.\n \"\"\"\n arr[:k] = arr[:k][::-1]\n \n n = len(arr)\n while n > 1:\n # Find the index of the maximum element in the unsorted portion\n max_idx = arr.index(max(arr[:n]))\n \n # If the maximum element is not already at the end, flip it to the front\n if max_idx != n - 1:\n if max_idx != 0:\n flip(arr, max_idx + 1)\n # Flip the entire unsorted portion to move the maximum element to the end\n flip(arr, n)\n \n # Reduce the size of the unsorted portion\n n -= 1\n \n return arr", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(arr):\n \"\"\"\n Sorts the given list using the Pancake Sort algorithm.\n \n :param arr: List of elements to be sorted.\n :return: Sorted list.\n \"\"\"\n def flip(arr, k):\n \"\"\"\n Flips the first k elements of the array.\n \n :param arr: List of elements.\n :param k: Number of elements to flip.\n \"\"\"\n arr[:k] = arr[:k][::-1]\n \n n = len(arr)\n while n > 1:\n # Find the index of the maximum element in the unsorted portion\n max_idx = arr.index(max(arr[:n]))\n \n # If the maximum element is not at the end, flip to bring it to the front\n if max_idx != n - 1:\n if max_idx != 0:\n flip(arr, max_idx + 1)\n # Flip the entire unsorted portion to move the max element to the end\n flip(arr, n)\n \n # Reduce the size of the unsorted portion\n n -= 1\n \n return arr", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(arr):\n \"\"\"\n Sorts the given list using the Pancake Sort algorithm.\n \n :param arr: List of elements to be sorted.\n :return: Sorted list.\n \"\"\"\n def flip(arr, k):\n \"\"\"\n Reverses the first k elements of the list.\n \n :param arr: List of elements.\n :param k: Number of elements to reverse.\n \"\"\"\n arr[:k] = arr[:k][::-1]\n \n n = len(arr)\n while n > 1:\n # Find the index of the maximum element in the unsorted portion\n max_idx = arr.index(max(arr[:n]))\n \n # If the maximum element is not at the end, flip to bring it to the front\n if max_idx != n - 1:\n # Flip the max element to the front\n if max_idx != 0:\n flip(arr, max_idx + 1)\n # Flip the max element to the correct position\n flip(arr, n)\n \n # Reduce the size of the unsorted portion\n n -= 1\n \n return arr", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(arr):\n \"\"\"\n Sorts a list of elements using the Pancake Sort algorithm.\n \n :param arr: List of elements to be sorted.\n :return: Sorted list of elements.\n \"\"\"\n def flip(arr, k):\n \"\"\"\n Reverses the first k elements of the array.\n \n :param arr: List of elements.\n :param k: Number of elements to reverse.\n \"\"\"\n arr[:k] = arr[:k][::-1]\n \n n = len(arr)\n while n > 1:\n # Find the index of the maximum element in the unsorted portion\n max_idx = arr.index(max(arr[:n]))\n \n # If the maximum element is not at the end, flip to bring it to the front\n if max_idx != n - 1:\n # Flip the max element to the front\n if max_idx != 0:\n flip(arr, max_idx + 1)\n # Flip the max element to its correct position\n flip(arr, n)\n \n # Reduce the size of the unsorted portion\n n -= 1\n \n return arr", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(arr):\n \"\"\"\n Sorts a list of elements using the Pancake Sort algorithm.\n \n :param arr: List of elements to be sorted.\n :return: Sorted list of elements.\n \"\"\"\n n = len(arr)\n while n > 1:\n # Find the index of the maximum element in the unsorted portion\n max_idx = arr.index(max(arr[:n]))\n \n # Reverse the elements from the start to the max_idx to move the max element to the start\n arr[:max_idx + 1] = reversed(arr[:max_idx + 1])\n \n # Reverse the entire unsorted portion to move the max element to the end\n arr[:n] = reversed(arr[:n])\n \n # Reduce the size of the unsorted portion\n n -= 1\n \n return arr", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(arr):\n \"\"\"\n Sorts a list of elements using the Pancake Sort algorithm.\n \n :param arr: List of elements to be sorted.\n :return: Sorted list of elements.\n \"\"\"\n n = len(arr)\n while n > 1:\n # Find the index of the maximum element in the unsorted portion\n max_idx = arr.index(max(arr[:n]))\n \n # If the maximum element is not already at the end, flip the array to bring it to the front\n if max_idx != n - 1:\n if max_idx != 0:\n # Flip the array from the start to the max_idx to bring the max element to the front\n arr[:max_idx + 1] = arr[:max_idx + 1][::-1]\n \n # Flip the entire array to move the max element to the end of the unsorted portion\n arr[:n] = arr[:n][::-1]\n \n # Reduce the size of the unsorted portion\n n -= 1\n \n return arr", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(arr):\n \"\"\"\n Sorts the list using the Pancake Sort algorithm.\n \n :param arr: List of elements to be sorted.\n :return: Sorted list.\n \"\"\"\n def flip(arr, k):\n \"\"\"\n Flips the first k elements of the array.\n \n :param arr: List of elements.\n :param k: Number of elements to flip.\n \"\"\"\n arr[:k] = arr[:k][::-1]\n \n n = len(arr)\n while n > 1:\n # Find the index of the maximum element in the unsorted portion\n max_idx = arr.index(max(arr[:n]))\n \n # If the maximum element is not at the end, flip to bring it to the front\n if max_idx != n - 1:\n if max_idx != 0:\n flip(arr, max_idx + 1)\n # Flip the entire unsorted portion to move the max element to the end\n flip(arr, n)\n \n # Reduce the size of the unsorted portion\n n -= 1\n \n return arr", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(arr):\n def flip(arr, k):\n \"\"\"Helper function to flip the first k elements of the array.\"\"\"\n arr[:k] = arr[:k][::-1]\n\n n = len(arr)\n while n > 1:\n # Find the index of the maximum element in the unsorted portion\n max_idx = arr.index(max(arr[:n]))\n \n # If the maximum element is not at the end, flip to bring it to the front\n if max_idx != n - 1:\n if max_idx != 0:\n flip(arr, max_idx + 1)\n # Flip the entire unsorted portion to move the max element to the end\n flip(arr, n)\n \n # Reduce the size of the unsorted portion\n n -= 1\n \n return arr", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(arr):\n \"\"\"\n Sorts a list of elements using the Pancake Sort algorithm.\n \n Pancake Sort works by repeatedly flipping the largest unsorted element to the front\n and then flipping the entire unsorted portion to move it to its correct position.\n \n Args:\n arr (list): The list of elements to be sorted.\n \n Returns:\n list: The sorted list.\n \"\"\"\n \n def flip(arr, k):\n \"\"\"\n Flips the first k elements of the array.\n \n Args:\n arr (list): The list of elements.\n k (int): The number of elements to flip.\n \"\"\"\n arr[:k] = arr[:k][::-1]\n \n n = len(arr)\n while n > 1:\n # Find the index of the maximum element in the unsorted portion\n max_idx = arr.index(max(arr[:n]))\n \n # If the maximum element is not already at the end of the unsorted portion\n if max_idx != n - 1:\n # Flip the maximum element to the front\n if max_idx != 0:\n flip(arr, max_idx + 1)\n # Flip the entire unsorted portion to move the maximum element to the end\n flip(arr, n)\n \n # Reduce the size of the unsorted portion\n n -= 1\n \n return arr", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(arr):\n def flip(arr, k):\n \"\"\"Helper function to flip the first k elements of the array.\"\"\"\n start = 0\n while start < k:\n arr[start], arr[k] = arr[k], arr[start]\n start += 1\n k -= 1\n\n n = len(arr)\n while n > 1:\n # Find the index of the maximum element in the unsorted portion\n max_idx = arr.index(max(arr[:n]))\n \n # If the maximum element is not at the end, flip to bring it to the front\n if max_idx != n - 1:\n if max_idx != 0:\n flip(arr, max_idx)\n # Flip the entire unsorted portion to move the max element to the end\n flip(arr, n - 1)\n \n # Reduce the size of the unsorted portion\n n -= 1\n \n return arr", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(arr):\n def flip(arr, k):\n \"\"\"Helper function to flip the first k elements of the array.\"\"\"\n arr[:k] = arr[:k][::-1]\n \n n = len(arr)\n while n > 1:\n # Find the index of the maximum element in the unsorted portion\n max_idx = arr.index(max(arr[:n]))\n \n # If the maximum element is not at the end, flip to bring it to the front\n if max_idx != n - 1:\n if max_idx != 0:\n flip(arr, max_idx + 1)\n # Flip the entire unsorted portion to move the max element to the end\n flip(arr, n)\n \n # Reduce the size of the unsorted portion\n n -= 1\n \n return arr", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(arr):\n \"\"\"\n Sorts a list of elements using the Pancake Sort algorithm.\n \n :param arr: List of elements to be sorted.\n :return: Sorted list of elements.\n \"\"\"\n def flip(arr, k):\n \"\"\"\n Flips the first k elements of the array.\n \n :param arr: List of elements.\n :param k: Number of elements to flip.\n \"\"\"\n arr[:k] = arr[:k][::-1]\n \n n = len(arr)\n while n > 1:\n # Find the index of the maximum element in the unsorted portion\n max_idx = arr.index(max(arr[:n]))\n \n # If the maximum element is not at the end, flip to bring it to the front\n if max_idx != n - 1:\n if max_idx != 0:\n flip(arr, max_idx + 1)\n # Flip the entire unsorted portion to move the maximum element to the end\n flip(arr, n)\n \n # Reduce the size of the unsorted portion\n n -= 1\n \n return arr", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(arr):\n \"\"\"\n Sorts a list of elements using the Pancake Sort algorithm.\n \n :param arr: List of elements to be sorted.\n :return: Sorted list of elements.\n \"\"\"\n n = len(arr)\n while n > 1:\n # Find the index of the maximum element in the unsorted portion\n max_idx = arr.index(max(arr[:n]))\n \n # If the maximum element is not at the end of the unsorted portion,\n # flip the array to bring the maximum element to the front,\n # then flip the entire unsorted portion to move it to the end.\n if max_idx != n - 1:\n if max_idx != 0:\n arr[:max_idx + 1] = arr[:max_idx + 1][::-1]\n arr[:n] = arr[:n][::-1]\n \n # Reduce the size of the unsorted portion\n n -= 1\n \n return arr", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(arr):\n \"\"\"\n Sorts a list of elements using the Pancake Sort algorithm.\n \n :param arr: List of elements to be sorted.\n :return: Sorted list of elements.\n \"\"\"\n def flip(arr, k):\n \"\"\"\n Reverses the first k elements of the array.\n \n :param arr: List of elements.\n :param k: Number of elements to reverse.\n \"\"\"\n arr[:k] = arr[:k][::-1]\n \n n = len(arr)\n while n > 1:\n # Find the index of the maximum element in the unsorted portion\n max_idx = arr.index(max(arr[:n]))\n \n # If the maximum element is not at the end of the unsorted portion,\n # flip the array to bring the maximum element to the front,\n # then flip the entire unsorted portion to move it to the end.\n if max_idx != n - 1:\n if max_idx != 0:\n flip(arr, max_idx + 1)\n flip(arr, n)\n \n # Reduce the size of the unsorted portion\n n -= 1\n \n return arr", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(arr):\n def flip(arr, k):\n \"\"\"Helper function to flip the first k elements of the array.\"\"\"\n arr[:k] = arr[:k][::-1]\n \n n = len(arr)\n while n > 1:\n # Find the index of the maximum element in the unsorted portion\n max_idx = arr.index(max(arr[:n]))\n \n # If the maximum element is not already at the end, flip to bring it to the front\n if max_idx != n - 1:\n if max_idx != 0:\n flip(arr, max_idx + 1)\n # Flip the entire unsorted portion to move the maximum element to the end\n flip(arr, n)\n \n # Reduce the size of the unsorted portion\n n -= 1\n \n return arr", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(arr):\n \"\"\"\n Sorts a list of elements using the Pancake Sort algorithm.\n \n :param arr: List of elements to be sorted.\n :return: Sorted list of elements.\n \"\"\"\n def flip(arr, k):\n \"\"\"\n Flips the first k elements of the array.\n \n :param arr: List of elements.\n :param k: Number of elements to flip.\n \"\"\"\n arr[:k] = arr[:k][::-1]\n \n n = len(arr)\n while n > 1:\n # Find the index of the maximum element in the unsorted portion\n max_idx = arr.index(max(arr[:n]))\n \n # If the maximum element is not at the end, flip to bring it to the front\n if max_idx != n - 1:\n if max_idx != 0:\n flip(arr, max_idx + 1)\n # Flip the entire unsorted portion to move the maximum element to the end\n flip(arr, n)\n \n # Reduce the size of the unsorted portion\n n -= 1\n \n return arr", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(arr):\n \"\"\"\n Sorts the given list using the Pancake Sort algorithm.\n \n :param arr: List of elements to be sorted.\n :return: Sorted list.\n \"\"\"\n n = len(arr)\n while n > 1:\n # Find the index of the maximum element in the unsorted portion\n max_idx = arr.index(max(arr[:n]))\n \n # If the maximum element is not already at the end, flip the array to bring it to the front\n if max_idx != n - 1:\n if max_idx != 0:\n # Flip the array from the start to the max_idx to bring the max element to the front\n arr[:max_idx + 1] = arr[:max_idx + 1][::-1]\n \n # Flip the entire unsorted portion to move the max element to its correct position\n arr[:n] = arr[:n][::-1]\n \n # Reduce the size of the unsorted portion\n n -= 1\n \n return arr", "matching_cluster_idx": 3}]}, "Mbpp/166": {"dps": 89.96, "dps_norm": 48.75, "pass@1": 100.0, "profiled": [{"solution": "def find_even_pair(lst):\n count = 0\n n = len(lst)\n \n # Iterate over all pairs of integers in the list\n for i in range(n):\n for j in range(i + 1, n):\n # Check if the xor of the pair is even\n if (lst[i] ^ lst[j]) % 2 == 0:\n count += 1\n \n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(lst):\n count = 0\n n = len(lst)\n \n # Iterate over all pairs of integers in the list\n for i in range(n):\n for j in range(i + 1, n):\n # Check if the xor of the pair is even\n if (lst[i] ^ lst[j]) % 2 == 0:\n count += 1\n \n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(lst):\n count = 0\n n = len(lst)\n \n # Iterate over all pairs (i, j) where i < j\n for i in range(n):\n for j in range(i + 1, n):\n if (lst[i] ^ lst[j]) % 2 == 0:\n count += 1\n \n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(nums):\n count = 0\n n = len(nums)\n \n # Iterate over all pairs (i, j) where i < j\n for i in range(n):\n for j in range(i + 1, n):\n # XOR the two numbers\n xor_result = nums[i] ^ nums[j]\n # Check if the result is even\n if xor_result % 2 == 0:\n count += 1\n \n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(lst):\n # Helper function to check if a number is even\n def is_even(num):\n return num % 2 == 0\n \n count = 0\n n = len(lst)\n \n # Iterate through all pairs (i, j) where i < j\n for i in range(n):\n for j in range(i + 1, n):\n if is_even(lst[i] ^ lst[j]):\n count += 1\n \n return count", "matching_cluster_idx": 0}, {"solution": "def find_even_pair(lst):\n count = 0\n n = len(lst)\n \n # Iterate over all pairs (i, j) where i < j\n for i in range(n):\n for j in range(i + 1, n):\n if (lst[i] ^ lst[j]) % 2 == 0:\n count += 1\n \n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(lst):\n count = 0\n n = len(lst)\n \n # Iterate through all pairs (i, j) where i < j\n for i in range(n):\n for j in range(i + 1, n):\n if (lst[i] ^ lst[j]) % 2 == 0:\n count += 1\n \n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(lst):\n count = 0\n n = len(lst)\n \n # Iterate through all pairs of integers in the list\n for i in range(n):\n for j in range(i + 1, n):\n # Check if the xor of the pair is even\n if (lst[i] ^ lst[j]) % 2 == 0:\n count += 1\n \n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(lst):\n count = 0\n n = len(lst)\n \n # Iterate over all pairs of integers in the list\n for i in range(n):\n for j in range(i + 1, n):\n # Check if the xor of the pair is even\n if (lst[i] ^ lst[j]) % 2 == 0:\n count += 1\n \n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(lst):\n count = 0\n n = len(lst)\n \n # Iterate over all pairs (i, j) where i < j\n for i in range(n):\n for j in range(i + 1, n):\n if (lst[i] ^ lst[j]) % 2 == 0:\n count += 1\n \n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(lst):\n count = 0\n n = len(lst)\n \n # Iterate over all pairs (i, j) where i < j\n for i in range(n):\n for j in range(i + 1, n):\n if (lst[i] ^ lst[j]) % 2 == 0:\n count += 1\n \n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(lst):\n count = 0\n n = len(lst)\n \n # Iterate over all pairs (i, j) where i < j\n for i in range(n):\n for j in range(i + 1, n):\n # Check if the xor of lst[i] and lst[j] is even\n if (lst[i] ^ lst[j]) % 2 == 0:\n count += 1\n \n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(lst):\n count = 0\n n = len(lst)\n \n # Iterate over all pairs (i, j) where i < j\n for i in range(n):\n for j in range(i + 1, n):\n # Check if the xor of lst[i] and lst[j] is even\n if (lst[i] ^ lst[j]) % 2 == 0:\n count += 1\n \n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(lst):\n count = 0\n n = len(lst)\n \n # Iterate over all pairs (i, j) where i < j\n for i in range(n):\n for j in range(i + 1, n):\n if (lst[i] ^ lst[j]) % 2 == 0:\n count += 1\n \n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(lst):\n count = 0\n n = len(lst)\n \n # Iterate over all pairs (i, j) where i < j\n for i in range(n):\n for j in range(i + 1, n):\n # Check if the xor of the pair is even\n if (lst[i] ^ lst[j]) % 2 == 0:\n count += 1\n \n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(lst):\n count = 0\n n = len(lst)\n \n # Iterate over all pairs (i, j) where i < j\n for i in range(n):\n for j in range(i + 1, n):\n if (lst[i] ^ lst[j]) % 2 == 0:\n count += 1\n \n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(lst):\n count = 0\n n = len(lst)\n \n # Iterate through each pair of integers in the list\n for i in range(n):\n for j in range(i + 1, n):\n # Check if the xor of the pair is even\n if (lst[i] ^ lst[j]) % 2 == 0:\n count += 1\n \n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(lst):\n count = 0\n n = len(lst)\n \n # Iterate over all pairs (i, j) where i < j\n for i in range(n):\n for j in range(i + 1, n):\n # Check if the xor of the pair is even\n if (lst[i] ^ lst[j]) % 2 == 0:\n count += 1\n \n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(lst):\n count = 0\n n = len(lst)\n \n # Iterate over all pairs (i, j) where i < j\n for i in range(n):\n for j in range(i + 1, n):\n # Check if the xor of the pair is even\n if (lst[i] ^ lst[j]) % 2 == 0:\n count += 1\n \n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(lst):\n count = 0\n n = len(lst)\n \n # Iterate over all pairs (i, j) where i < j\n for i in range(n):\n for j in range(i + 1, n):\n # Check if the xor of lst[i] and lst[j] is even\n if (lst[i] ^ lst[j]) % 2 == 0:\n count += 1\n \n return count", "matching_cluster_idx": 1}]}, "Mbpp/170": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 68.0, "profiled": [{"solution": "def sum_range_list(lst, start_index, end_index):\n \"\"\"\n Returns the sum of numbers in the list lst from start_index to end_index (inclusive).\n \n :param lst: List of numbers\n :param start_index: Starting index (inclusive)\n :param end_index: Ending index (inclusive)\n :return: Sum of numbers in the specified range\n \"\"\"\n # Ensure the indices are within the valid range of the list\n if start_index < 0:\n start_index = 0\n if end_index >= len(lst):\n end_index = len(lst) - 1\n \n # Calculate the sum of the elements in the specified range\n return sum(lst[start_index:end_index + 1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(lst, start_index, end_index):\n \"\"\"\n Calculate the sum of numbers in the list from start_index to end_index (inclusive).\n \n :param lst: List of numbers\n :param start_index: Starting index (inclusive)\n :param end_index: Ending index (inclusive)\n :return: Sum of numbers in the specified range\n \"\"\"\n # Ensure the indices are within the valid range of the list\n if start_index < 0:\n start_index = 0\n if end_index >= len(lst):\n end_index = len(lst) - 1\n \n # Calculate the sum of the elements in the specified range\n return sum(lst[start_index:end_index + 1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(lst, start_index, end_index):\n \"\"\"\n Returns the sum of numbers in the list `lst` from `start_index` to `end_index` (inclusive).\n \n :param lst: List of numbers\n :param start_index: Starting index (inclusive)\n :param end_index: Ending index (inclusive)\n :return: Sum of numbers in the specified range\n \"\"\"\n # Ensure the indices are within the bounds of the list\n if start_index < 0:\n start_index = 0\n if end_index >= len(lst):\n end_index = len(lst) - 1\n \n # Calculate the sum of the elements in the specified range\n return sum(lst[start_index:end_index + 1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(lst, start_index, end_index):\n \"\"\"\n Returns the sum of numbers in the list `lst` from `start_index` to `end_index` (inclusive).\n \n :param lst: List of numbers\n :param start_index: Starting index (inclusive)\n :param end_index: Ending index (inclusive)\n :return: Sum of numbers in the specified range\n \"\"\"\n # Ensure the indices are within the bounds of the list\n if start_index < 0:\n start_index = 0\n if end_index >= len(lst):\n end_index = len(lst) - 1\n \n # Calculate the sum of the elements in the specified range\n return sum(lst[start_index:end_index + 1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(lst, start_index, end_index):\n \"\"\"\n Returns the sum of numbers in the list `lst` from `start_index` to `end_index` (inclusive).\n \n :param lst: List of numbers\n :param start_index: Starting index (inclusive)\n :param end_index: Ending index (inclusive)\n :return: Sum of numbers in the specified range\n \"\"\"\n # Ensure the indices are within the bounds of the list\n if start_index < 0:\n start_index = 0\n if end_index >= len(lst):\n end_index = len(lst) - 1\n \n # Calculate the sum of the elements in the specified range\n return sum(lst[start_index:end_index + 1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(lst, start_index, end_index):\n \"\"\"\n Calculate the sum of numbers in the list from start_index to end_index (inclusive).\n\n :param lst: List of numbers\n :param start_index: Starting index (inclusive)\n :param end_index: Ending index (inclusive)\n :return: Sum of numbers in the specified range\n \"\"\"\n # Ensure the indices are within the bounds of the list\n if start_index < 0:\n start_index = 0\n if end_index >= len(lst):\n end_index = len(lst) - 1\n\n # Calculate the sum of the elements in the specified range\n return sum(lst[start_index:end_index + 1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(lst, start_index, end_index):\n \"\"\"\n Returns the sum of numbers in the list within the specified range of indices.\n \n :param lst: List of numbers\n :param start_index: Starting index (inclusive)\n :param end_index: Ending index (inclusive)\n :return: Sum of numbers in the specified range\n \"\"\"\n # Ensure the indices are within the valid range of the list\n if start_index < 0:\n start_index = 0\n if end_index >= len(lst):\n end_index = len(lst) - 1\n \n # Calculate the sum of the elements in the specified range\n return sum(lst[start_index:end_index + 1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(lst, start_index, end_index):\n \"\"\"\n Calculate the sum of numbers in the list from start_index to end_index (inclusive).\n \n :param lst: List of numbers\n :param start_index: Starting index (inclusive)\n :param end_index: Ending index (inclusive)\n :return: Sum of numbers in the specified range\n \"\"\"\n # Ensure the indices are within the bounds of the list\n if start_index < 0:\n start_index = 0\n if end_index >= len(lst):\n end_index = len(lst) - 1\n \n # Calculate the sum of the elements in the specified range\n return sum(lst[start_index:end_index + 1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(lst, start_index, end_index):\n \"\"\"\n Returns the sum of numbers in the list lst from start_index to end_index (inclusive).\n \n :param lst: List of numbers\n :param start_index: Starting index (inclusive)\n :param end_index: Ending index (inclusive)\n :return: Sum of numbers in the specified range\n \"\"\"\n # Ensure the indices are within the bounds of the list\n if start_index < 0:\n start_index = 0\n if end_index >= len(lst):\n end_index = len(lst) - 1\n \n # Calculate the sum of the elements in the specified range\n return sum(lst[start_index:end_index + 1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(lst, start_index, end_index):\n \"\"\"\n Calculate the sum of numbers in the list from start_index to end_index (inclusive).\n \n :param lst: List of numbers\n :param start_index: Starting index (inclusive)\n :param end_index: Ending index (inclusive)\n :return: Sum of numbers in the specified range\n \"\"\"\n # Ensure the indices are within the bounds of the list\n if start_index < 0:\n start_index = 0\n if end_index >= len(lst):\n end_index = len(lst) - 1\n \n # Calculate the sum of the elements in the specified range\n return sum(lst[start_index:end_index + 1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(lst, start_index, end_index):\n \"\"\"\n Calculate the sum of numbers in the list within the specified range.\n \n :param lst: List of numbers\n :param start_index: Starting index (inclusive)\n :param end_index: Ending index (inclusive)\n :return: Sum of numbers in the specified range\n \"\"\"\n # Ensure the indices are within the bounds of the list\n if start_index < 0:\n start_index = 0\n if end_index >= len(lst):\n end_index = len(lst) - 1\n \n # Calculate the sum of the elements in the specified range\n return sum(lst[start_index:end_index + 1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(lst, start_index, end_index):\n \"\"\"\n Returns the sum of numbers in the list `lst` within the range specified by `start_index` and `end_index`.\n \"\"\"\n # Ensure the indices are within the bounds of the list\n if start_index < 0:\n start_index = 0\n if end_index >= len(lst):\n end_index = len(lst) - 1\n \n # Calculate the sum of the elements in the specified range\n return sum(lst[start_index:end_index + 1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(lst, start_index, end_index):\n \"\"\"\n Returns the sum of numbers in the list `lst` from `start_index` to `end_index` (inclusive).\n \n :param lst: List of numbers\n :param start_index: Starting index (inclusive)\n :param end_index: Ending index (inclusive)\n :return: Sum of numbers in the specified range\n \"\"\"\n # Ensure the indices are within the bounds of the list\n if start_index < 0:\n start_index = 0\n if end_index >= len(lst):\n end_index = len(lst) - 1\n \n # Calculate the sum of the elements in the specified range\n return sum(lst[start_index:end_index + 1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(lst, start_index, end_index):\n \"\"\"\n Calculate the sum of numbers in the list from start_index to end_index (inclusive).\n \n :param lst: List of numbers\n :param start_index: Starting index (inclusive)\n :param end_index: Ending index (inclusive)\n :return: Sum of numbers in the specified range\n \"\"\"\n # Ensure the indices are within the bounds of the list\n if start_index < 0:\n start_index = 0\n if end_index >= len(lst):\n end_index = len(lst) - 1\n \n # Calculate the sum of the elements in the specified range\n return sum(lst[start_index:end_index + 1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(lst, start_index, end_index):\n \"\"\"\n Calculate the sum of numbers in the list within the specified range.\n \n :param lst: List of numbers\n :param start_index: Starting index (inclusive)\n :param end_index: Ending index (inclusive)\n :return: Sum of numbers in the specified range\n \"\"\"\n # Ensure the indices are within the bounds of the list\n if start_index < 0:\n start_index = 0\n if end_index >= len(lst):\n end_index = len(lst) - 1\n \n # Calculate the sum of the elements in the specified range\n return sum(lst[start_index:end_index + 1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(lst, start_index, end_index):\n \"\"\"\n Calculate the sum of numbers in the list from start_index to end_index (inclusive).\n \n :param lst: List of numbers\n :param start_index: Starting index (inclusive)\n :param end_index: Ending index (inclusive)\n :return: Sum of numbers in the specified range\n \"\"\"\n # Ensure the indices are within the bounds of the list\n if start_index < 0:\n start_index = 0\n if end_index >= len(lst):\n end_index = len(lst) - 1\n \n # Calculate the sum of the elements in the specified range\n return sum(lst[start_index:end_index + 1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(lst, start_index, end_index):\n \"\"\"\n Calculate the sum of numbers in the list within the specified range of indices.\n \n :param lst: List of numbers\n :param start_index: Starting index (inclusive)\n :param end_index: Ending index (inclusive)\n :return: Sum of numbers in the specified range\n \"\"\"\n # Ensure the indices are within the valid range of the list\n if start_index < 0:\n start_index = 0\n if end_index >= len(lst):\n end_index = len(lst) - 1\n \n # Calculate the sum of the elements in the specified range\n return sum(lst[start_index:end_index + 1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(lst, start_index, end_index):\n \"\"\"\n Calculate the sum of numbers in the list from start_index to end_index (inclusive).\n \n :param lst: List of numbers\n :param start_index: Starting index (inclusive)\n :param end_index: Ending index (inclusive)\n :return: Sum of numbers in the specified range\n \"\"\"\n # Ensure the indices are within the valid range of the list\n if start_index < 0:\n start_index = 0\n if end_index >= len(lst):\n end_index = len(lst) - 1\n \n # Calculate the sum of the elements in the specified range\n return sum(lst[start_index:end_index + 1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(lst, start_index, end_index):\n \"\"\"\n Returns the sum of numbers in the list lst from start_index to end_index (inclusive).\n \"\"\"\n # Ensure the indices are within the valid range of the list\n if start_index < 0:\n start_index = 0\n if end_index >= len(lst):\n end_index = len(lst) - 1\n \n # Calculate the sum of the elements in the specified range\n return sum(lst[start_index:end_index + 1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(lst, start_index, end_index):\n \"\"\"\n Calculate the sum of numbers in the list within the specified range.\n\n :param lst: List of numbers\n :param start_index: Starting index (inclusive)\n :param end_index: Ending index (inclusive)\n :return: Sum of numbers in the specified range\n \"\"\"\n # Ensure the indices are within the bounds of the list\n if start_index < 0:\n start_index = 0\n if end_index >= len(lst):\n end_index = len(lst) - 1\n\n # Calculate the sum of the elements in the specified range\n return sum(lst[start_index:end_index + 1])", "matching_cluster_idx": 7}]}, "Mbpp/226": {"dps": 68.21705426356588, "dps_norm": 14.285714285714286, "pass@1": 100.0, "profiled": [{"solution": "def odd_values_string(input_string):\n # Use list comprehension to filter out characters at odd indices\n result = ''.join([char for idx, char in enumerate(input_string) if idx % 2 == 0])\n return result", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(input_string):\n # Use list comprehension to filter out characters at odd indices\n result = ''.join([input_string[i] for i in range(len(input_string)) if i % 2 == 0])\n return result", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(input_string):\n # Use list comprehension to filter out characters at odd indices\n result = ''.join([char for index, char in enumerate(input_string) if index % 2 == 0])\n return result", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(input_string):\n # Use list comprehension to filter out characters at odd indices\n result = ''.join([char for idx, char in enumerate(input_string) if idx % 2 == 0])\n return result", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(input_string):\n # Use list comprehension to filter out characters at odd indices\n result = ''.join([char for idx, char in enumerate(input_string) if idx % 2 == 0])\n return result", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(input_string):\n # Use list comprehension to filter out characters at odd indices\n result = ''.join([char for idx, char in enumerate(input_string) if idx % 2 == 0])\n return result", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(input_string):\n # Use list comprehension to filter out characters at odd indices\n result = ''.join([char for index, char in enumerate(input_string) if index % 2 == 0])\n return result", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(input_string):\n # Use list comprehension to filter out characters at odd indices\n result = ''.join([char for idx, char in enumerate(input_string) if idx % 2 == 0])\n return result", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(input_string):\n # Use list comprehension to filter out characters at odd indices\n result = ''.join([char for idx, char in enumerate(input_string) if idx % 2 == 0])\n return result", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(input_string):\n # Use list comprehension to filter out characters at odd indices\n result = ''.join([input_string[i] for i in range(len(input_string)) if i % 2 == 0])\n return result", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(input_string):\n # Use list comprehension to filter out characters at odd indices\n result = ''.join([char for idx, char in enumerate(input_string) if idx % 2 == 0])\n return result", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(input_string):\n # Use list comprehension to filter out characters at odd indices\n result = ''.join([char for index, char in enumerate(input_string) if index % 2 == 0])\n return result", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(input_string):\n # Use list comprehension to filter out characters at odd indices\n result = ''.join([char for idx, char in enumerate(input_string) if idx % 2 == 0])\n return result", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(input_string):\n # Use list comprehension to filter out characters at odd indices\n result = ''.join([char for idx, char in enumerate(input_string) if idx % 2 == 0])\n return result", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(input_string):\n # Use list comprehension to filter out characters at odd indices\n result = ''.join([input_string[i] for i in range(len(input_string)) if i % 2 == 0])\n return result", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(input_string):\n # Use list comprehension to filter out characters at odd indices\n result = ''.join([char for idx, char in enumerate(input_string) if idx % 2 == 0])\n return result", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(input_string):\n # Use list comprehension to filter out characters at odd indices\n result = ''.join([char for idx, char in enumerate(input_string) if idx % 2 == 0])\n return result", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(input_string):\n # Use list comprehension to filter out characters at odd indices\n result = ''.join([char for idx, char in enumerate(input_string) if idx % 2 == 0])\n return result", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(input_string):\n # Use list comprehension to filter out characters at odd indices\n result = ''.join([char for idx, char in enumerate(input_string) if idx % 2 == 0])\n return result", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(input_string):\n # Use list comprehension to filter out characters at odd indices\n result = ''.join([char for index, char in enumerate(input_string) if index % 2 == 0])\n return result", "matching_cluster_idx": 0}]}, "Mbpp/230": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def replace_blank(input_string, char):\n \"\"\"\n Replaces all blank spaces in the input string with the specified character.\n \n :param input_string: The string to modify.\n :param char: The character to replace blank spaces with.\n :return: The modified string.\n \"\"\"\n return input_string.replace(' ', char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string, char):\n \"\"\"\n Replace all blank spaces in the input string with the specified character.\n \n :param input_string: The input string to be modified.\n :param char: The character to replace blank spaces with.\n :return: The modified string with blank spaces replaced by the character.\n \"\"\"\n return input_string.replace(' ', char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string, char):\n \"\"\"\n Replace all blank spaces in the input string with the specified character.\n\n Args:\n input_string (str): The input string to be modified.\n char (str): The character to replace blank spaces with.\n\n Returns:\n str: The modified string with blank spaces replaced by the specified character.\n \"\"\"\n return input_string.replace(' ', char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string, char):\n \"\"\"\n Replace all blank spaces in the input string with the specified character.\n\n :param input_string: The input string to be modified.\n :param char: The character to replace blank spaces with.\n :return: The modified string with blank spaces replaced by the character.\n \"\"\"\n return input_string.replace(' ', char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string, char):\n \"\"\"\n Replaces all blank spaces in the input string with the specified character.\n \n :param input_string: The string to modify.\n :param char: The character to replace blank spaces with.\n :return: The modified string.\n \"\"\"\n return input_string.replace(' ', char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string, char):\n \"\"\"\n Replace all blank spaces in the input string with the specified character.\n\n :param input_string: The input string to be modified.\n :param char: The character to replace blank spaces with.\n :return: The modified string with blank spaces replaced by the character.\n \"\"\"\n return input_string.replace(' ', char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string, char):\n \"\"\"\n Replaces all blank spaces in the input string with the specified character.\n\n :param input_string: The string to modify.\n :param char: The character to replace blank spaces with.\n :return: The modified string.\n \"\"\"\n return input_string.replace(' ', char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string, char):\n \"\"\"\n Replaces all blank spaces in the input string with the specified character.\n\n :param input_string: The string to modify.\n :param char: The character to replace blank spaces with.\n :return: The modified string.\n \"\"\"\n return input_string.replace(' ', char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string, char):\n \"\"\"\n Replaces all blank spaces in the input string with the specified character.\n\n :param input_string: The string to modify.\n :param char: The character to replace blank spaces with.\n :return: The modified string.\n \"\"\"\n return input_string.replace(' ', char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string, char):\n \"\"\"\n Replaces all blank spaces in the input string with the specified character.\n \n :param input_string: The input string to be modified.\n :param char: The character to replace blank spaces with.\n :return: The modified string with blank spaces replaced by the character.\n \"\"\"\n return input_string.replace(' ', char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string, char):\n \"\"\"\n Replaces all blank spaces in the input string with the specified character.\n \n :param input_string: The string to modify.\n :param char: The character to replace blank spaces with.\n :return: The modified string.\n \"\"\"\n return input_string.replace(' ', char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string, char):\n \"\"\"\n Replace all blank spaces in the input string with the specified character.\n\n Args:\n input_string (str): The input string to be modified.\n char (str): The character to replace blank spaces with.\n\n Returns:\n str: The modified string with blank spaces replaced by the specified character.\n \"\"\"\n return input_string.replace(' ', char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string, char):\n \"\"\"\n Replace all blank spaces in the input string with the specified character.\n \n :param input_string: The input string to be modified.\n :param char: The character to replace blank spaces with.\n :return: The modified string with blank spaces replaced by the character.\n \"\"\"\n return input_string.replace(' ', char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string, char):\n \"\"\"\n Replaces all blank spaces in the input string with the specified character.\n \n :param input_string: The input string to modify.\n :param char: The character to replace blank spaces with.\n :return: The modified string with blank spaces replaced by the character.\n \"\"\"\n return input_string.replace(' ', char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string, char):\n \"\"\"\n Replaces all blank spaces in the input string with the specified character.\n\n :param input_string: The string to modify.\n :param char: The character to replace blank spaces with.\n :return: The modified string.\n \"\"\"\n return input_string.replace(' ', char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string, char):\n \"\"\"\n Replaces all blank spaces in the input string with the specified character.\n \n :param input_string: The string in which spaces need to be replaced.\n :param char: The character to replace the spaces with.\n :return: The modified string with spaces replaced by the specified character.\n \"\"\"\n return input_string.replace(' ', char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string, char):\n \"\"\"\n Replaces all blank spaces in the input string with the specified character.\n \n :param input_string: The string to be modified.\n :param char: The character to replace blank spaces with.\n :return: The modified string.\n \"\"\"\n return input_string.replace(' ', char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string, char):\n \"\"\"\n Replaces all blank spaces in the input string with the specified character.\n\n :param input_string: The string to modify.\n :param char: The character to replace blank spaces with.\n :return: The modified string.\n \"\"\"\n return input_string.replace(' ', char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string, char):\n \"\"\"\n Replaces all blank spaces in the input string with the specified character.\n\n :param input_string: The input string to modify.\n :param char: The character to replace blank spaces with.\n :return: The modified string with blank spaces replaced by the character.\n \"\"\"\n return input_string.replace(' ', char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string, char):\n \"\"\"\n Replace all blank spaces in the input string with the specified character.\n\n :param input_string: The string in which to replace blank spaces.\n :param char: The character to replace blank spaces with.\n :return: The modified string with blank spaces replaced by the character.\n \"\"\"\n return input_string.replace(' ', char)", "matching_cluster_idx": 7}]}, "Mbpp/239": {"dps": 51.72413793103448, "dps_norm": 60.0, "pass@1": 100.0, "profiled": [{"solution": "def get_total_number_of_sequences(m, n):\n def count_sequences(current_length, previous_value):\n if current_length == n:\n return 1\n \n count = 0\n for next_value in range(2 * previous_value, m + 1):\n count += count_sequences(current_length + 1, next_value)\n \n return count\n \n total_sequences = 0\n for start_value in range(1, m + 1):\n total_sequences += count_sequences(1, start_value)\n \n return total_sequences", "matching_cluster_idx": 5}, {"solution": "def get_total_number_of_sequences(m, n):\n def count_sequences(current, length):\n if length == 0:\n return 1\n count = 0\n for next_val in range(2 * current, m + 1):\n count += count_sequences(next_val, length - 1)\n return count\n\n total_sequences = 0\n for start in range(1, m + 1):\n total_sequences += count_sequences(start, n - 1)\n \n return total_sequences", "matching_cluster_idx": 5}, {"solution": "def get_total_number_of_sequences(m, n):\n def count_sequences(current_value, remaining_length):\n if remaining_length == 0:\n return 1\n count = 0\n for next_value in range(2 * current_value, m + 1):\n count += count_sequences(next_value, remaining_length - 1)\n return count\n\n total_sequences = 0\n for start_value in range(1, m + 1):\n total_sequences += count_sequences(start_value, n - 1)\n \n return total_sequences", "matching_cluster_idx": 5}, {"solution": "def get_total_number_of_sequences(m, n):\n def count_sequences(current_length, previous_value):\n if current_length == n:\n return 1\n count = 0\n for next_value in range(2 * previous_value, m + 1):\n count += count_sequences(current_length + 1, next_value)\n return count\n\n total_sequences = 0\n for start_value in range(1, m + 1):\n total_sequences += count_sequences(1, start_value)\n \n return total_sequences", "matching_cluster_idx": 5}, {"solution": "def get_total_number_of_sequences(m, n):\n def count_sequences(current_value, length):\n if length == n:\n return 1\n count = 0\n for next_value in range(2 * current_value, m + 1):\n count += count_sequences(next_value, length + 1)\n return count\n\n total_sequences = 0\n for start_value in range(1, m + 1):\n total_sequences += count_sequences(start_value, 1)\n return total_sequences", "matching_cluster_idx": 5}, {"solution": "def get_total_number_of_sequences(m, n):\n def count_sequences(current_length, previous_value):\n if current_length == n:\n return 1\n \n count = 0\n for next_value in range(2 * previous_value, m + 1):\n count += count_sequences(current_length + 1, next_value)\n \n return count\n \n total_sequences = 0\n for start_value in range(1, m + 1):\n total_sequences += count_sequences(1, start_value)\n \n return total_sequences", "matching_cluster_idx": 5}, {"solution": "def get_total_number_of_sequences(m, n):\n def count_sequences(current_value, remaining_length):\n if remaining_length == 0:\n return 1\n count = 0\n for next_value in range(2 * current_value, m + 1):\n count += count_sequences(next_value, remaining_length - 1)\n return count\n\n total_sequences = 0\n for start_value in range(1, m + 1):\n total_sequences += count_sequences(start_value, n - 1)\n \n return total_sequences", "matching_cluster_idx": 5}, {"solution": "def get_total_number_of_sequences(m, n):\n def count_sequences(current, length):\n if length == 0:\n return 1\n count = 0\n for next_val in range(2 * current, m + 1):\n count += count_sequences(next_val, length - 1)\n return count\n\n total_sequences = 0\n for start in range(1, m + 1):\n total_sequences += count_sequences(start, n - 1)\n \n return total_sequences", "matching_cluster_idx": 5}, {"solution": "def get_total_number_of_sequences(m, n):\n def count_sequences(current_length, previous_value):\n if current_length == n:\n return 1\n \n count = 0\n for next_value in range(2 * previous_value, m + 1):\n count += count_sequences(current_length + 1, next_value)\n \n return count\n \n total_sequences = 0\n for start_value in range(1, m + 1):\n total_sequences += count_sequences(1, start_value)\n \n return total_sequences", "matching_cluster_idx": 5}, {"solution": "def get_total_number_of_sequences(m, n):\n def count_sequences(current_length, previous_value):\n if current_length == n:\n return 1\n \n count = 0\n for next_value in range(2 * previous_value, m + 1):\n count += count_sequences(current_length + 1, next_value)\n \n return count\n \n total_sequences = 0\n for start_value in range(1, m + 1):\n total_sequences += count_sequences(1, start_value)\n \n return total_sequences", "matching_cluster_idx": 5}, {"solution": "def get_total_number_of_sequences(m, n):\n def count_sequences(current_value, remaining_length):\n if remaining_length == 0:\n return 1\n count = 0\n for next_value in range(2 * current_value, m + 1):\n count += count_sequences(next_value, remaining_length - 1)\n return count\n\n total_sequences = 0\n for start_value in range(1, m + 1):\n total_sequences += count_sequences(start_value, n - 1)\n\n return total_sequences", "matching_cluster_idx": 5}, {"solution": "def get_total_number_of_sequences(m, n):\n def count_sequences(current_value, remaining_length):\n if remaining_length == 0:\n return 1\n count = 0\n for next_value in range(2 * current_value, m + 1):\n count += count_sequences(next_value, remaining_length - 1)\n return count\n\n total_count = 0\n for start_value in range(1, m + 1):\n total_count += count_sequences(start_value, n - 1)\n \n return total_count", "matching_cluster_idx": 5}, {"solution": "def get_total_number_of_sequences(m, n):\n def count_sequences(current, length):\n if length == 0:\n return 1\n count = 0\n for next_val in range(2 * current, m + 1):\n count += count_sequences(next_val, length - 1)\n return count\n\n total_sequences = 0\n for start in range(1, m + 1):\n total_sequences += count_sequences(start, n - 1)\n \n return total_sequences", "matching_cluster_idx": 5}, {"solution": "def get_total_number_of_sequences(m, n):\n def count_sequences(current_length, previous_value):\n if current_length == n:\n return 1\n \n count = 0\n for next_value in range(2 * previous_value, m + 1):\n count += count_sequences(current_length + 1, next_value)\n \n return count\n \n total_sequences = 0\n for start_value in range(1, m + 1):\n total_sequences += count_sequences(1, start_value)\n \n return total_sequences", "matching_cluster_idx": 5}, {"solution": "def get_total_number_of_sequences(m, n):\n def count_sequences(current_value, remaining_length):\n if remaining_length == 0:\n return 1\n count = 0\n for next_value in range(2 * current_value, m + 1):\n count += count_sequences(next_value, remaining_length - 1)\n return count\n\n total_sequences = 0\n for start_value in range(1, m + 1):\n total_sequences += count_sequences(start_value, n - 1)\n \n return total_sequences", "matching_cluster_idx": 5}, {"solution": "def get_total_number_of_sequences(m, n):\n def count_sequences(current, length):\n if length == 0:\n return 1\n count = 0\n for next_val in range(2 * current, m + 1):\n count += count_sequences(next_val, length - 1)\n return count\n\n total_sequences = 0\n for start in range(1, m + 1):\n total_sequences += count_sequences(start, n - 1)\n \n return total_sequences", "matching_cluster_idx": 5}, {"solution": "def get_total_number_of_sequences(m, n):\n def count_sequences(current_length, previous_value):\n if current_length == n:\n return 1\n \n count = 0\n for next_value in range(2 * previous_value, m + 1):\n count += count_sequences(current_length + 1, next_value)\n \n return count\n \n total_sequences = 0\n for start_value in range(1, m + 1):\n total_sequences += count_sequences(1, start_value)\n \n return total_sequences", "matching_cluster_idx": 5}, {"solution": "def get_total_number_of_sequences(m, n):\n def count_sequences(current, length):\n if length == 0:\n return 1\n count = 0\n for next_val in range(2 * current, m + 1):\n count += count_sequences(next_val, length - 1)\n return count\n\n total_count = 0\n for start in range(1, m + 1):\n total_count += count_sequences(start, n - 1)\n return total_count", "matching_cluster_idx": 5}, {"solution": "def get_total_number_of_sequences(m, n):\n def count_sequences(current_length, previous_value):\n if current_length == n:\n return 1\n \n count = 0\n for next_value in range(2 * previous_value, m + 1):\n count += count_sequences(current_length + 1, next_value)\n \n return count\n \n total_sequences = 0\n for start_value in range(1, m + 1):\n total_sequences += count_sequences(1, start_value)\n \n return total_sequences", "matching_cluster_idx": 5}, {"solution": "def get_total_number_of_sequences(m, n):\n def count_sequences(current, length):\n if length == 0:\n return 1\n count = 0\n for next_val in range(2 * current, m + 1):\n count += count_sequences(next_val, length - 1)\n return count\n\n total_sequences = 0\n for start in range(1, m + 1):\n total_sequences += count_sequences(start, n - 1)\n \n return total_sequences", "matching_cluster_idx": 5}]}, "Mbpp/240": {"dps": 81.46341463414635, "dps_norm": 89.44444444444444, "pass@1": 100.0, "profiled": [{"solution": "def replace_list(list1, list2):\n # Check if the first list is not empty to avoid index errors\n if list1:\n # Replace the last element of list1 with list2\n list1[-1:] = list2\n return list1", "matching_cluster_idx": 7}, {"solution": "def replace_list(list1, list2):\n # Check if the first list is not empty to avoid index errors\n if list1:\n # Replace the last element of list1 with list2\n list1[-1:] = list2\n return list1", "matching_cluster_idx": 7}, {"solution": "def replace_list(list1, list2):\n # Check if the first list is not empty\n if list1:\n # Replace the last element of list1 with list2\n list1[-1:] = list2\n return list1", "matching_cluster_idx": 7}, {"solution": "def replace_list(list1, list2):\n # Check if the first list is not empty to avoid index errors\n if list1:\n # Replace the last element of list1 with list2\n list1[-1:] = list2\n return list1", "matching_cluster_idx": 7}, {"solution": "def replace_list(list1, list2):\n # Check if the first list is not empty to avoid index errors\n if list1:\n # Replace the last element of list1 with list2\n list1[-1:] = list2\n return list1", "matching_cluster_idx": 7}, {"solution": "def replace_list(list1, list2):\n # Check if the first list is not empty to avoid index errors\n if list1:\n # Replace the last element of list1 with list2\n list1[-1:] = list2\n return list1", "matching_cluster_idx": 7}, {"solution": "def replace_list(list1, list2):\n # Check if the first list is not empty to avoid index errors\n if list1:\n # Replace the last element of list1 with list2\n list1[-1:] = list2\n return list1", "matching_cluster_idx": 7}, {"solution": "def replace_list(list1, list2):\n # Check if the first list is not empty to avoid index errors\n if list1:\n # Replace the last element of list1 with list2\n list1[-1:] = list2\n return list1", "matching_cluster_idx": 7}, {"solution": "def replace_list(list1, list2):\n # Check if list1 is not empty to avoid index errors\n if list1:\n # Replace the last element of list1 with list2\n list1[-1:] = list2\n return list1", "matching_cluster_idx": 7}, {"solution": "def replace_list(list1, list2):\n # Check if the first list is not empty to avoid index errors\n if list1:\n # Replace the last element of list1 with list2\n list1[-1:] = list2\n return list1", "matching_cluster_idx": 7}, {"solution": "def replace_list(list1, list2):\n # Check if the first list is not empty to avoid index errors\n if list1:\n # Replace the last element of list1 with list2\n list1[-1:] = list2\n return list1", "matching_cluster_idx": 7}, {"solution": "def replace_list(list1, list2):\n # Check if the first list is not empty to avoid index errors\n if list1:\n # Replace the last element of list1 with list2\n list1[-1:] = list2\n return list1", "matching_cluster_idx": 7}, {"solution": "def replace_list(list1, list2):\n # Check if the first list is not empty to avoid index errors\n if list1:\n # Replace the last element of list1 with list2\n list1[-1:] = list2\n return list1", "matching_cluster_idx": 7}, {"solution": "def replace_list(list1, list2):\n # Check if list1 is not empty to avoid index errors\n if list1:\n # Replace the last element of list1 with list2\n list1[-1:] = list2\n return list1", "matching_cluster_idx": 7}, {"solution": "def replace_list(list1, list2):\n # Check if the first list is not empty to avoid index errors\n if list1:\n # Replace the last element of list1 with list2\n list1[-1:] = list2\n return list1", "matching_cluster_idx": 7}, {"solution": "def replace_list(list1, list2):\n # Check if the first list is not empty to avoid index errors\n if list1:\n # Replace the last element of list1 with list2\n list1[-1:] = list2\n return list1", "matching_cluster_idx": 7}, {"solution": "def replace_list(list1, list2):\n # Check if list1 is not empty to avoid index errors\n if list1:\n # Replace the last element of list1 with list2\n list1[-1:] = list2\n return list1", "matching_cluster_idx": 7}, {"solution": "def replace_list(list1, list2):\n # Check if the first list is not empty\n if list1:\n # Replace the last element of list1 with list2\n list1[-1:] = list2\n return list1", "matching_cluster_idx": 7}, {"solution": "def replace_list(list1, list2):\n \"\"\"\n Replaces the last element of the first list with the elements of the second list.\n \n Args:\n list1 (list): The first list.\n list2 (list): The second list.\n \n Returns:\n list: The modified first list.\n \"\"\"\n if not list1:\n return list2 # If list1 is empty, return list2\n \n # Remove the last element of list1\n list1.pop()\n \n # Extend list1 with the elements of list2\n list1.extend(list2)\n \n return list1", "matching_cluster_idx": 8}, {"solution": "def replace_list(list1, list2):\n # Check if list1 is not empty to avoid index errors\n if list1:\n # Replace the last element of list1 with list2\n list1[-1:] = list2\n return list1", "matching_cluster_idx": 7}]}, "Mbpp/251": {"dps": 91.95402298850576, "dps_norm": 77.77777777777777, "pass@1": 100.0, "profiled": [{"solution": "def insert_element(lst, element):\n # Initialize an empty list to store the result\n result = []\n \n # Iterate through each item in the input list\n for item in lst:\n # Append the element before each item\n result.append(element)\n result.append(item)\n \n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n # Initialize an empty list to store the result\n result = []\n \n # Iterate through each item in the input list\n for item in lst:\n # Insert the element before the current item\n result.append(element)\n result.append(item)\n \n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n # Initialize an empty list to store the result\n result = []\n \n # Iterate through each item in the input list\n for item in lst:\n # Append the element before each item\n result.append(element)\n result.append(item)\n \n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n # Initialize an empty list to store the result\n result = []\n \n # Iterate through each item in the input list\n for item in lst:\n # Append the element before the current item\n result.append(element)\n result.append(item)\n \n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n # Initialize an empty list to store the result\n result = []\n \n # Iterate over each item in the input list\n for item in lst:\n # Append the element before each item\n result.append(element)\n result.append(item)\n \n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n # Initialize an empty list to store the result\n result = []\n \n # Iterate through each item in the input list\n for item in lst:\n # Append the element before the current item\n result.append(element)\n result.append(item)\n \n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n \"\"\"\n Inserts the given element before each element in the list and returns the resulting list.\n \n :param lst: List of elements\n :param element: Element to insert\n :return: List with the element inserted before each element\n \"\"\"\n result = []\n for item in lst:\n result.append(element)\n result.append(item)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n # Initialize an empty list to store the result\n result = []\n \n # Iterate through each item in the input list\n for item in lst:\n # Insert the element before the current item\n result.append(element)\n result.append(item)\n \n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n result = []\n for item in lst:\n result.append(element)\n result.append(item)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n # Initialize an empty list to store the result\n result = []\n \n # Iterate over each item in the input list\n for item in lst:\n # Append the element before the current item\n result.append(element)\n result.append(item)\n \n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n \"\"\"\n Inserts the given element before each element in the list and returns the resulting list.\n \n :param lst: List of elements\n :param element: Element to insert\n :return: List with the element inserted before each element\n \"\"\"\n result = []\n for item in lst:\n result.append(element)\n result.append(item)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n # Initialize an empty list to store the result\n result = []\n \n # Iterate through each item in the input list\n for item in lst:\n # Insert the element before the current item\n result.append(element)\n result.append(item)\n \n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n # Initialize an empty list to store the result\n result = []\n \n # Iterate through each item in the input list\n for item in lst:\n # Append the element before the current item\n result.append(element)\n result.append(item)\n \n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n \"\"\"\n Inserts the given element before each element in the list and returns the resulting list.\n \n :param lst: List of elements\n :param element: Element to be inserted\n :return: List with the element inserted before each element\n \"\"\"\n result = []\n for item in lst:\n result.append(element)\n result.append(item)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n # Initialize an empty list to store the result\n result = []\n \n # Iterate through each item in the input list\n for item in lst:\n # Insert the element before the current item\n result.append(element)\n result.append(item)\n \n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n # Initialize an empty list to store the result\n result = []\n \n # Iterate through each item in the input list\n for item in lst:\n # Append the element before the current item\n result.append(element)\n result.append(item)\n \n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n # Initialize an empty list to store the result\n result = []\n \n # Iterate over each item in the input list\n for item in lst:\n # Append the element before the current item\n result.append(element)\n result.append(item)\n \n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n # Initialize an empty list to store the result\n result = []\n \n # Iterate through each item in the input list\n for item in lst:\n # Append the element before the current item\n result.append(element)\n result.append(item)\n \n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n # Initialize an empty list to store the result\n result = []\n \n # Iterate through each item in the input list\n for item in lst:\n # Insert the element before the current item\n result.append(element)\n result.append(item)\n \n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n # Initialize an empty list to store the result\n result = []\n \n # Iterate through each item in the input list\n for item in lst:\n # Append the element before the current item\n result.append(element)\n result.append(item)\n \n return result", "matching_cluster_idx": 6}]}, "Mbpp/256": {"dps": 69.40639269406392, "dps_norm": 64.70588235294117, "pass@1": 100.0, "profiled": [{"solution": "def is_prime(n):\n \"\"\"Helper function to check if a number is prime.\"\"\"\n if n <= 1:\n return False\n if n == 2:\n return True\n if n % 2 == 0:\n return False\n for i in range(3, int(n**0.5) + 1, 2):\n if n % i == 0:\n return False\n return True\ndef count_Primes_nums(num):\n \"\"\"Function to count the number of prime numbers less than the given non-negative number.\"\"\"\n count = 0\n for i in range(2, num):\n if is_prime(i):\n count += 1\n return count", "matching_cluster_idx": 10}, {"solution": "def is_prime(n):\n \"\"\"Helper function to check if a number is prime.\"\"\"\n if n <= 1:\n return False\n if n == 2:\n return True\n if n % 2 == 0:\n return False\n for i in range(3, int(n**0.5) + 1, 2):\n if n % i == 0:\n return False\n return True\ndef count_Primes_nums(num):\n \"\"\"Function to count the number of prime numbers less than the given number.\"\"\"\n count = 0\n for i in range(2, num):\n if is_prime(i):\n count += 1\n return count", "matching_cluster_idx": 10}, {"solution": "def is_prime(n):\n \"\"\"Helper function to check if a number is prime.\"\"\"\n if n <= 1:\n return False\n if n == 2:\n return True\n if n % 2 == 0:\n return False\n for i in range(3, int(n**0.5) + 1, 2):\n if n % i == 0:\n return False\n return True\ndef count_Primes_nums(num):\n \"\"\"Function to count the number of prime numbers less than the given number.\"\"\"\n count = 0\n for i in range(2, num):\n if is_prime(i):\n count += 1\n return count", "matching_cluster_idx": 10}, {"solution": "def is_prime(n):\n \"\"\"Helper function to check if a number is prime.\"\"\"\n if n <= 1:\n return False\n if n == 2:\n return True\n if n % 2 == 0:\n return False\n for i in range(3, int(n**0.5) + 1, 2):\n if n % i == 0:\n return False\n return True\ndef count_Primes_nums(num):\n \"\"\"Function to count the number of prime numbers less than the given number.\"\"\"\n count = 0\n for i in range(2, num):\n if is_prime(i):\n count += 1\n return count", "matching_cluster_idx": 10}, {"solution": "def is_prime(n):\n \"\"\"Helper function to check if a number is prime.\"\"\"\n if n <= 1:\n return False\n if n == 2:\n return True\n if n % 2 == 0:\n return False\n for i in range(3, int(n**0.5) + 1, 2):\n if n % i == 0:\n return False\n return True\ndef count_Primes_nums(num):\n \"\"\"Function to count the number of prime numbers less than the given number.\"\"\"\n count = 0\n for i in range(2, num):\n if is_prime(i):\n count += 1\n return count", "matching_cluster_idx": 10}, {"solution": "def is_prime(n):\n \"\"\"Helper function to check if a number is prime.\"\"\"\n if n <= 1:\n return False\n if n == 2:\n return True\n if n % 2 == 0:\n return False\n for i in range(3, int(n**0.5) + 1, 2):\n if n % i == 0:\n return False\n return True\ndef count_Primes_nums(num):\n \"\"\"Function to count the number of prime numbers less than the given number.\"\"\"\n count = 0\n for i in range(2, num):\n if is_prime(i):\n count += 1\n return count", "matching_cluster_idx": 10}, {"solution": "def is_prime(n):\n \"\"\"Helper function to check if a number is prime.\"\"\"\n if n <= 1:\n return False\n if n == 2:\n return True\n if n % 2 == 0:\n return False\n for i in range(3, int(n**0.5) + 1, 2):\n if n % i == 0:\n return False\n return True\ndef count_Primes_nums(num):\n \"\"\"Function to count the number of prime numbers less than the given number.\"\"\"\n count = 0\n for i in range(2, num):\n if is_prime(i):\n count += 1\n return count", "matching_cluster_idx": 10}, {"solution": "def is_prime(n):\n \"\"\"Helper function to check if a number is prime.\"\"\"\n if n <= 1:\n return False\n if n == 2:\n return True\n if n % 2 == 0:\n return False\n for i in range(3, int(n**0.5) + 1, 2):\n if n % i == 0:\n return False\n return True\ndef count_Primes_nums(num):\n \"\"\"Function to count the number of prime numbers less than the given non-negative number.\"\"\"\n count = 0\n for i in range(2, num):\n if is_prime(i):\n count += 1\n return count", "matching_cluster_idx": 10}, {"solution": "def is_prime(n):\n \"\"\"Helper function to check if a number is prime.\"\"\"\n if n <= 1:\n return False\n if n == 2:\n return True\n if n % 2 == 0:\n return False\n for i in range(3, int(n**0.5) + 1, 2):\n if n % i == 0:\n return False\n return True\ndef count_Primes_nums(num):\n \"\"\"Function to count the number of prime numbers less than the given number.\"\"\"\n count = 0\n for i in range(2, num):\n if is_prime(i):\n count += 1\n return count", "matching_cluster_idx": 10}, {"solution": "def is_prime(n):\n \"\"\"Helper function to check if a number is prime.\"\"\"\n if n <= 1:\n return False\n if n == 2:\n return True\n if n % 2 == 0:\n return False\n for i in range(3, int(n**0.5) + 1, 2):\n if n % i == 0:\n return False\n return True\ndef count_Primes_nums(num):\n \"\"\"Function to count the number of prime numbers less than the given number.\"\"\"\n count = 0\n for i in range(2, num):\n if is_prime(i):\n count += 1\n return count", "matching_cluster_idx": 10}, {"solution": "def is_prime(n):\n \"\"\"Helper function to check if a number is prime.\"\"\"\n if n <= 1:\n return False\n if n == 2:\n return True\n if n % 2 == 0:\n return False\n for i in range(3, int(n**0.5) + 1, 2):\n if n % i == 0:\n return False\n return True\ndef count_Primes_nums(num):\n \"\"\"Function to count the number of prime numbers less than the given number.\"\"\"\n count = 0\n for i in range(2, num):\n if is_prime(i):\n count += 1\n return count", "matching_cluster_idx": 10}, {"solution": "def is_prime(n):\n \"\"\"Helper function to check if a number is prime.\"\"\"\n if n <= 1:\n return False\n if n == 2:\n return True\n if n % 2 == 0:\n return False\n for i in range(3, int(n**0.5) + 1, 2):\n if n % i == 0:\n return False\n return True\ndef count_Primes_nums(num):\n \"\"\"Function to count the number of prime numbers less than the given number.\"\"\"\n count = 0\n for i in range(2, num):\n if is_prime(i):\n count += 1\n return count", "matching_cluster_idx": 10}, {"solution": "def is_prime(n):\n \"\"\"Helper function to check if a number is prime.\"\"\"\n if n <= 1:\n return False\n if n == 2:\n return True\n if n % 2 == 0:\n return False\n for i in range(3, int(n**0.5) + 1, 2):\n if n % i == 0:\n return False\n return True\ndef count_Primes_nums(num):\n \"\"\"Function to count the number of prime numbers less than the given non-negative number.\"\"\"\n count = 0\n for i in range(2, num):\n if is_prime(i):\n count += 1\n return count", "matching_cluster_idx": 10}, {"solution": "def is_prime(n):\n \"\"\"Helper function to check if a number is prime.\"\"\"\n if n <= 1:\n return False\n if n == 2:\n return True\n if n % 2 == 0:\n return False\n for i in range(3, int(n**0.5) + 1, 2):\n if n % i == 0:\n return False\n return True\ndef count_Primes_nums(num):\n \"\"\"Function to count the number of prime numbers less than the given non-negative number.\"\"\"\n count = 0\n for i in range(2, num):\n if is_prime(i):\n count += 1\n return count", "matching_cluster_idx": 10}, {"solution": "def is_prime(n):\n \"\"\"Helper function to check if a number is prime.\"\"\"\n if n <= 1:\n return False\n if n == 2:\n return True\n if n % 2 == 0:\n return False\n for i in range(3, int(n**0.5) + 1, 2):\n if n % i == 0:\n return False\n return True\ndef count_Primes_nums(num):\n \"\"\"Function to count the number of prime numbers less than the given number.\"\"\"\n count = 0\n for i in range(2, num):\n if is_prime(i):\n count += 1\n return count", "matching_cluster_idx": 10}, {"solution": "def is_prime(n):\n \"\"\"Helper function to check if a number is prime.\"\"\"\n if n <= 1:\n return False\n if n == 2:\n return True\n if n % 2 == 0:\n return False\n for i in range(3, int(n**0.5) + 1, 2):\n if n % i == 0:\n return False\n return True\ndef count_Primes_nums(num):\n \"\"\"Function to count the number of prime numbers less than the given number.\"\"\"\n count = 0\n for i in range(2, num):\n if is_prime(i):\n count += 1\n return count", "matching_cluster_idx": 10}, {"solution": "def is_prime(n):\n \"\"\"Helper function to check if a number is prime.\"\"\"\n if n <= 1:\n return False\n if n == 2:\n return True\n if n % 2 == 0:\n return False\n for i in range(3, int(n**0.5) + 1, 2):\n if n % i == 0:\n return False\n return True\ndef count_Primes_nums(num):\n \"\"\"Function to count the number of prime numbers less than the given number.\"\"\"\n count = 0\n for i in range(2, num):\n if is_prime(i):\n count += 1\n return count", "matching_cluster_idx": 10}, {"solution": "def is_prime(n):\n \"\"\"Helper function to check if a number is prime.\"\"\"\n if n <= 1:\n return False\n if n == 2:\n return True\n if n % 2 == 0:\n return False\n for i in range(3, int(n**0.5) + 1, 2):\n if n % i == 0:\n return False\n return True\ndef count_Primes_nums(num):\n \"\"\"Function to count the number of prime numbers less than the given non-negative number.\"\"\"\n count = 0\n for i in range(2, num):\n if is_prime(i):\n count += 1\n return count", "matching_cluster_idx": 10}, {"solution": "def is_prime(n):\n \"\"\"Helper function to check if a number is prime.\"\"\"\n if n <= 1:\n return False\n if n == 2:\n return True\n if n % 2 == 0:\n return False\n for i in range(3, int(n**0.5) + 1, 2):\n if n % i == 0:\n return False\n return True\ndef count_Primes_nums(num):\n \"\"\"Function to count the number of prime numbers less than the given number.\"\"\"\n count = 0\n for i in range(2, num):\n if is_prime(i):\n count += 1\n return count", "matching_cluster_idx": 10}, {"solution": "def is_prime(n):\n \"\"\"Helper function to check if a number is prime.\"\"\"\n if n <= 1:\n return False\n if n == 2:\n return True\n if n % 2 == 0:\n return False\n for i in range(3, int(n**0.5) + 1, 2):\n if n % i == 0:\n return False\n return True\ndef count_Primes_nums(num):\n \"\"\"Function to count the number of prime numbers less than the given number.\"\"\"\n count = 0\n for i in range(2, num):\n if is_prime(i):\n count += 1\n return count", "matching_cluster_idx": 10}]}, "Mbpp/265": {"dps": 70.93023255813954, "dps_norm": 83.33333333333333, "pass@1": 100.0, "profiled": [{"solution": "def list_split(lst, n):\n # Initialize an empty list to hold the resulting lists\n result = [[] for _ in range(n)]\n \n # Iterate over the list with index\n for i, item in enumerate(lst):\n # Append the item to the appropriate sublist\n result[i % n].append(item)\n \n return result", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n # Initialize an empty list to hold the resulting lists\n result = [[] for _ in range(n)]\n \n # Iterate over the list with index\n for i, item in enumerate(lst):\n # Append the item to the appropriate sublist based on the index\n result[i % n].append(item)\n \n return result", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n # Initialize an empty list to store the resulting lists\n result = [[] for _ in range(n)]\n \n # Iterate over the list with index\n for i, element in enumerate(lst):\n # Append the element to the appropriate sublist\n result[i % n].append(element)\n \n return result", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n # Initialize an empty list to hold the resulting lists\n result = [[] for _ in range(n)]\n \n # Iterate over the list with index\n for i, item in enumerate(lst):\n # Append the item to the appropriate sublist\n result[i % n].append(item)\n \n return result", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n # Initialize an empty list to store the resulting lists\n result = [[] for _ in range(n)]\n \n # Iterate over the list with index\n for i, element in enumerate(lst):\n # Append the element to the appropriate sublist\n result[i % n].append(element)\n \n return result", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n # Initialize an empty list to hold the resulting lists\n result = [[] for _ in range(n)]\n \n # Iterate over the list with index\n for i, element in enumerate(lst):\n # Append the element to the appropriate sublist\n result[i % n].append(element)\n \n return result", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n # Initialize an empty list to hold the resulting lists\n result = [[] for _ in range(n)]\n \n # Iterate over the list with index\n for i, item in enumerate(lst):\n # Append the item to the appropriate sublist\n result[i % n].append(item)\n \n return result", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n # Initialize an empty list to store the resulting lists\n result = [[] for _ in range(n)]\n \n # Iterate over the list with index\n for i, item in enumerate(lst):\n # Append the item to the appropriate sublist\n result[i % n].append(item)\n \n return result", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n # Initialize an empty list to store the resulting lists\n result = [[] for _ in range(n)]\n \n # Iterate over the list with index\n for i, element in enumerate(lst):\n # Append the element to the appropriate sublist\n result[i % n].append(element)\n \n return result", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n # Initialize an empty list to hold the resulting lists\n result = [[] for _ in range(n)]\n \n # Iterate over the list with index\n for i, element in enumerate(lst):\n # Append the element to the appropriate sublist\n result[i % n].append(element)\n \n return result", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n # Initialize an empty list to hold the resulting lists\n result = [[] for _ in range(n)]\n \n # Iterate over the list with index\n for i, element in enumerate(lst):\n # Append the element to the appropriate sublist\n result[i % n].append(element)\n \n return result", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n # Initialize an empty list to store the resulting lists\n result = [[] for _ in range(n)]\n \n # Iterate over the list with index\n for i, item in enumerate(lst):\n # Append the item to the appropriate sublist based on the index\n result[i % n].append(item)\n \n return result", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n # Initialize an empty list to hold the resulting lists\n result = [[] for _ in range(n)]\n \n # Iterate over the list with index\n for i, item in enumerate(lst):\n # Append the item to the appropriate sublist based on the index\n result[i % n].append(item)\n \n return result", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n # Initialize an empty list to hold the resulting lists\n result = [[] for _ in range(n)]\n \n # Iterate over the list with an index\n for i, item in enumerate(lst):\n # Append the item to the appropriate sublist\n result[i % n].append(item)\n \n return result", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n # Initialize an empty list to hold the resulting lists\n result = [[] for _ in range(n)]\n \n # Iterate over the list with index\n for i, item in enumerate(lst):\n # Append the item to the appropriate sublist\n result[i % n].append(item)\n \n return result", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n # Initialize an empty list to hold the resulting lists\n result = [[] for _ in range(n)]\n \n # Iterate over the list with index\n for i, item in enumerate(lst):\n # Append the item to the appropriate sublist\n result[i % n].append(item)\n \n return result", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n # Initialize an empty list to hold the resulting lists\n result = [[] for _ in range(n)]\n \n # Iterate over the list with index\n for i, item in enumerate(lst):\n # Append the item to the appropriate sublist\n result[i % n].append(item)\n \n return result", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n # Initialize an empty list to hold the resulting lists\n result = [[] for _ in range(n)]\n \n # Iterate over the list with index\n for i, item in enumerate(lst):\n # Append the item to the appropriate sublist based on the index\n result[i % n].append(item)\n \n return result", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n # Initialize an empty list to hold the resulting lists\n result = [[] for _ in range(n)]\n \n # Iterate over the list with index\n for i, element in enumerate(lst):\n # Append the element to the appropriate sublist\n result[i % n].append(element)\n \n return result", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n # Initialize an empty list to hold the resulting lists\n result = [[] for _ in range(n)]\n \n # Iterate over the list with index\n for i, item in enumerate(lst):\n # Append the item to the appropriate sublist based on the index\n result[i % n].append(item)\n \n return result", "matching_cluster_idx": 4}]}, "Mbpp/281": {"dps": 94.0, "dps_norm": 81.81818181818181, "pass@1": 100.0, "profiled": [{"solution": "def all_unique(lst):\n \"\"\"\n Check if all elements in the given list are unique.\n\n Args:\n lst (list): The list to check for unique elements.\n\n Returns:\n bool: True if all elements are unique, False otherwise.\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n Check if all elements in the given list are unique.\n\n Args:\n lst (list): The list to check for unique elements.\n\n Returns:\n bool: True if all elements are unique, False otherwise.\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n Check if all elements in the list are unique.\n\n Args:\n lst (list): The list to check.\n\n Returns:\n bool: True if all elements are unique, False otherwise.\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n Check if all elements in the given list are unique.\n\n Args:\n lst (list): The list to check.\n\n Returns:\n bool: True if all elements are unique, False otherwise.\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n Check if all elements in the given list are unique.\n\n Parameters:\n lst (list): The list to check for unique elements.\n\n Returns:\n bool: True if all elements are unique, False otherwise.\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n Check if all elements in the list are unique.\n\n Args:\n lst (list): The list to check.\n\n Returns:\n bool: True if all elements are unique, False otherwise.\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n Check if all elements in the given list are unique.\n\n Args:\n lst (list): The list to check for unique elements.\n\n Returns:\n bool: True if all elements are unique, False otherwise.\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n Check if all elements in the list are unique.\n\n Args:\n lst (list): The list to check.\n\n Returns:\n bool: True if all elements are unique, False otherwise.\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n Check if all elements in the given list are unique.\n\n Args:\n lst (list): The list to check.\n\n Returns:\n bool: True if all elements are unique, False otherwise.\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n Check if all elements in the given list are unique.\n\n Args:\n lst (list): The list to check for unique elements.\n\n Returns:\n bool: True if all elements are unique, False otherwise.\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n Check if all elements in the list are unique.\n\n Args:\n lst (list): The list to check.\n\n Returns:\n bool: True if all elements are unique, False otherwise.\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}]}, "Mbpp/296": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def get_Inv_Count(arr):\n \"\"\"\n Function to count the number of inversions in an array.\n An inversion is a pair (i, j) such that i < j and arr[i] > arr[j].\n \"\"\"\n def merge_and_count(arr, temp_arr, left, mid, right):\n i = left # Starting index for left subarray\n j = mid + 1 # Starting index for right subarray\n k = left # Starting index to be sorted\n inv_count = 0\n\n # Conditions are checked to ensure that i doesn't exceed mid and j doesn't exceed right\n while i <= mid and j <= right:\n if arr[i] <= arr[j]:\n temp_arr[k] = arr[i]\n i += 1\n else:\n # There are mid - i inversions, because all remaining elements in the left subarray\n # (arr[i], arr[i+1], ..., arr[mid]) are greater than arr[j]\n temp_arr[k] = arr[j]\n inv_count += (mid - i + 1)\n j += 1\n k += 1\n\n # Copy the remaining elements of left subarray, if any\n while i <= mid:\n temp_arr[k] = arr[i]\n i += 1\n k += 1\n\n # Copy the remaining elements of right subarray, if any\n while j <= right:\n temp_arr[k] = arr[j]\n j += 1\n k += 1\n\n # Copy the sorted subarray into Original array\n for i in range(left, right + 1):\n arr[i] = temp_arr[i]\n\n return inv_count\n\n def merge_sort_and_count(arr, temp_arr, left, right):\n inv_count = 0\n if left < right:\n mid = (left + right) // 2\n\n inv_count += merge_sort_and_count(arr, temp_arr, left, mid)\n inv_count += merge_sort_and_count(arr, temp_arr, mid + 1, right)\n\n inv_count += merge_and_count(arr, temp_arr, left, mid, right)\n\n return inv_count\n\n # Create a temporary array to store the sorted subarrays\n temp_arr = [0] * len(arr)\n return merge_sort_and_count(arr, temp_arr, 0, len(arr) - 1)", "matching_cluster_idx": 5}, {"solution": "def merge_and_count(arr, temp_arr, left, mid, right):\n i = left # Starting index for left subarray\n j = mid + 1 # Starting index for right subarray\n k = left # Starting index to be sorted\n inv_count = 0\n\n # Conditions are checked to ensure that i doesn't exceed mid and j doesn't exceed right\n while i <= mid and j <= right:\n if arr[i] <= arr[j]:\n temp_arr[k] = arr[i]\n i += 1\n else:\n # There are mid - i inversions, because all remaining elements in the left subarray\n # (arr[i], arr[i+1], ..., arr[mid]) are greater than arr[j]\n temp_arr[k] = arr[j]\n inv_count += (mid - i + 1)\n j += 1\n k += 1\n\n # Copy the remaining elements of left subarray, if any\n while i <= mid:\n temp_arr[k] = arr[i]\n i += 1\n k += 1\n\n # Copy the remaining elements of right subarray, if any\n while j <= right:\n temp_arr[k] = arr[j]\n j += 1\n k += 1\n\n # Copy the sorted subarray into Original array\n for i in range(left, right + 1):\n arr[i] = temp_arr[i]\n\n return inv_count\ndef merge_sort_and_count(arr, temp_arr, left, right):\n inv_count = 0\n if left < right:\n mid = (left + right) // 2\n\n inv_count += merge_sort_and_count(arr, temp_arr, left, mid)\n inv_count += merge_sort_and_count(arr, temp_arr, mid + 1, right)\n\n inv_count += merge_and_count(arr, temp_arr, left, mid, right)\n\n return inv_count\ndef get_Inv_Count(arr):\n n = len(arr)\n temp_arr = [0]*n\n return merge_sort_and_count(arr, temp_arr, 0, n-1)", "matching_cluster_idx": 5}, {"solution": "def get_Inv_Count(arr):\n def merge_and_count(arr, temp_arr, left, mid, right):\n i = left # Starting index for left subarray\n j = mid + 1 # Starting index for right subarray\n k = left # Starting index to be sorted\n inv_count = 0\n\n # Conditions are checked to ensure that i doesn't exceed mid and j doesn't exceed right\n while i <= mid and j <= right:\n if arr[i] <= arr[j]:\n temp_arr[k] = arr[i]\n i += 1\n else:\n # There are mid - i inversions, because all remaining elements in the left subarray (arr[i], arr[i+1], ..., arr[mid]) are greater than arr[j]\n temp_arr[k] = arr[j]\n inv_count += (mid - i + 1)\n j += 1\n k += 1\n\n # Copy the remaining elements of left subarray, if any\n while i <= mid:\n temp_arr[k] = arr[i]\n i += 1\n k += 1\n\n # Copy the remaining elements of right subarray, if any\n while j <= right:\n temp_arr[k] = arr[j]\n j += 1\n k += 1\n\n # Copy the sorted subarray into Original array\n for i in range(left, right + 1):\n arr[i] = temp_arr[i]\n\n return inv_count\n\n def merge_sort_and_count(arr, temp_arr, left, right):\n inv_count = 0\n if left < right:\n mid = (left + right) // 2\n\n inv_count += merge_sort_and_count(arr, temp_arr, left, mid)\n inv_count += merge_sort_and_count(arr, temp_arr, mid + 1, right)\n inv_count += merge_and_count(arr, temp_arr, left, mid, right)\n\n return inv_count\n\n # Create a temporary array\n temp_arr = [0] * len(arr)\n return merge_sort_and_count(arr, temp_arr, 0, len(arr) - 1)", "matching_cluster_idx": 5}, {"solution": "def merge_and_count(arr, temp_arr, left, mid, right):\n i = left # Starting index for left subarray\n j = mid + 1 # Starting index for right subarray\n k = left # Starting index to be sorted\n inv_count = 0\n\n # Conditions are checked to ensure that i doesn't exceed mid and j doesn't exceed right\n while i <= mid and j <= right:\n if arr[i] <= arr[j]:\n temp_arr[k] = arr[i]\n i += 1\n else:\n # There are mid - i inversions, because all remaining elements in the left subarray\n # (arr[i], arr[i+1], ..., arr[mid]) are greater than arr[j]\n temp_arr[k] = arr[j]\n inv_count += (mid - i + 1)\n j += 1\n k += 1\n\n # Copy the remaining elements of left subarray, if any\n while i <= mid:\n temp_arr[k] = arr[i]\n i += 1\n k += 1\n\n # Copy the remaining elements of right subarray, if any\n while j <= right:\n temp_arr[k] = arr[j]\n j += 1\n k += 1\n\n # Copy the sorted subarray into Original array\n for i in range(left, right + 1):\n arr[i] = temp_arr[i]\n\n return inv_count\ndef merge_sort_and_count(arr, temp_arr, left, right):\n inv_count = 0\n if left < right:\n mid = (left + right) // 2\n\n inv_count += merge_sort_and_count(arr, temp_arr, left, mid)\n inv_count += merge_sort_and_count(arr, temp_arr, mid + 1, right)\n inv_count += merge_and_count(arr, temp_arr, left, mid, right)\n\n return inv_count\ndef get_Inv_Count(arr):\n n = len(arr)\n temp_arr = [0]*n\n return merge_sort_and_count(arr, temp_arr, 0, n-1)", "matching_cluster_idx": 5}, {"solution": "def get_Inv_Count(arr):\n \"\"\"\n Function to count the number of inversions in an array.\n An inversion is a pair (arr[i], arr[j]) such that i < j and arr[i] > arr[j].\n \"\"\"\n def merge_and_count(arr, temp_arr, left, mid, right):\n i = left # Starting index for left subarray\n j = mid + 1 # Starting index for right subarray\n k = left # Starting index to be sorted\n inv_count = 0\n\n # Conditions are checked to ensure that i doesn't exceed mid and j doesn't exceed right\n while i <= mid and j <= right:\n if arr[i] <= arr[j]:\n temp_arr[k] = arr[i]\n i += 1\n else:\n # There are mid - i inversions, because all remaining elements in the left subarray\n # (arr[i], arr[i+1], ..., arr[mid]) are greater than arr[j]\n temp_arr[k] = arr[j]\n inv_count += (mid - i + 1)\n j += 1\n k += 1\n\n # Copy the remaining elements of left subarray, if any\n while i <= mid:\n temp_arr[k] = arr[i]\n i += 1\n k += 1\n\n # Copy the remaining elements of right subarray, if any\n while j <= right:\n temp_arr[k] = arr[j]\n j += 1\n k += 1\n\n # Copy the sorted subarray into Original array\n for i in range(left, right + 1):\n arr[i] = temp_arr[i]\n\n return inv_count\n\n def merge_sort_and_count(arr, temp_arr, left, right):\n inv_count = 0\n if left < right:\n mid = (left + right) // 2\n\n inv_count += merge_sort_and_count(arr, temp_arr, left, mid)\n inv_count += merge_sort_and_count(arr, temp_arr, mid + 1, right)\n\n inv_count += merge_and_count(arr, temp_arr, left, mid, right)\n\n return inv_count\n\n # Create a temporary array\n temp_arr = [0] * len(arr)\n return merge_sort_and_count(arr, temp_arr, 0, len(arr) - 1)", "matching_cluster_idx": 5}, {"solution": "def merge_and_count(arr, temp_arr, left, mid, right):\n i = left # Starting index for left subarray\n j = mid + 1 # Starting index for right subarray\n k = left # Starting index to be sorted\n inv_count = 0\n\n # Conditions are checked to ensure that i doesn't exceed mid and j doesn't exceed right\n while i <= mid and j <= right:\n if arr[i] <= arr[j]:\n temp_arr[k] = arr[i]\n i += 1\n else:\n # There are mid - i inversions, because all remaining elements in the left subarray (arr[i], arr[i+1], ..., arr[mid]) are greater than arr[j]\n temp_arr[k] = arr[j]\n inv_count += (mid - i + 1)\n j += 1\n k += 1\n\n # Copy the remaining elements of left subarray, if any\n while i <= mid:\n temp_arr[k] = arr[i]\n i += 1\n k += 1\n\n # Copy the remaining elements of right subarray, if any\n while j <= right:\n temp_arr[k] = arr[j]\n j += 1\n k += 1\n\n # Copy the sorted subarray into Original array\n for i in range(left, right + 1):\n arr[i] = temp_arr[i]\n\n return inv_count\ndef merge_sort_and_count(arr, temp_arr, left, right):\n inv_count = 0\n if left < right:\n mid = (left + right) // 2\n\n inv_count += merge_sort_and_count(arr, temp_arr, left, mid)\n inv_count += merge_sort_and_count(arr, temp_arr, mid + 1, right)\n\n inv_count += merge_and_count(arr, temp_arr, left, mid, right)\n\n return inv_count\ndef get_Inv_Count(arr):\n n = len(arr)\n temp_arr = [0]*n\n return merge_sort_and_count(arr, temp_arr, 0, n-1)", "matching_cluster_idx": 5}, {"solution": "def get_Inv_Count(arr):\n \"\"\"\n Function to count the number of inversions in an array.\n An inversion is a pair (i, j) such that i < j and arr[i] > arr[j].\n \"\"\"\n def merge_and_count(arr, temp_arr, left, mid, right):\n i = left # Starting index for left subarray\n j = mid + 1 # Starting index for right subarray\n k = left # Starting index to be sorted\n inv_count = 0\n\n # Conditions are checked to ensure that i doesn't exceed mid and j doesn't exceed right\n while i <= mid and j <= right:\n if arr[i] <= arr[j]:\n temp_arr[k] = arr[i]\n i += 1\n else:\n # There are mid - i inversions, because all remaining elements in the left subarray\n # (arr[i], arr[i+1], ..., arr[mid]) are greater than arr[j]\n temp_arr[k] = arr[j]\n inv_count += (mid - i + 1)\n j += 1\n k += 1\n\n # Copy the remaining elements of left subarray, if any\n while i <= mid:\n temp_arr[k] = arr[i]\n i += 1\n k += 1\n\n # Copy the remaining elements of right subarray, if any\n while j <= right:\n temp_arr[k] = arr[j]\n j += 1\n k += 1\n\n # Copy the sorted subarray into Original array\n for i in range(left, right + 1):\n arr[i] = temp_arr[i]\n\n return inv_count\n\n def merge_sort_and_count(arr, temp_arr, left, right):\n inv_count = 0\n if left < right:\n mid = (left + right) // 2\n\n inv_count += merge_sort_and_count(arr, temp_arr, left, mid)\n inv_count += merge_sort_and_count(arr, temp_arr, mid + 1, right)\n\n inv_count += merge_and_count(arr, temp_arr, left, mid, right)\n\n return inv_count\n\n # Create a temporary array to store the sorted subarrays\n temp_arr = [0] * len(arr)\n return merge_sort_and_count(arr, temp_arr, 0, len(arr) - 1)", "matching_cluster_idx": 5}, {"solution": "def get_Inv_Count(arr):\n \"\"\"\n Function to count the number of inversions in an array.\n An inversion is a pair (i, j) such that i < j and arr[i] > arr[j].\n \"\"\"\n def merge_and_count(arr, temp_arr, left, mid, right):\n i = left # Starting index for left subarray\n j = mid + 1 # Starting index for right subarray\n k = left # Starting index to be sorted\n inv_count = 0\n\n # Conditions are checked to ensure that i doesn't exceed mid and j doesn't exceed right\n while i <= mid and j <= right:\n if arr[i] <= arr[j]:\n temp_arr[k] = arr[i]\n i += 1\n else:\n # There are mid - i inversions, because all remaining elements in the left subarray\n # (arr[i], arr[i+1], ..., arr[mid]) are greater than arr[j]\n temp_arr[k] = arr[j]\n inv_count += (mid - i + 1)\n j += 1\n k += 1\n\n # Copy the remaining elements of left subarray, if any\n while i <= mid:\n temp_arr[k] = arr[i]\n i += 1\n k += 1\n\n # Copy the remaining elements of right subarray, if any\n while j <= right:\n temp_arr[k] = arr[j]\n j += 1\n k += 1\n\n # Copy the sorted subarray into Original array\n for i in range(left, right + 1):\n arr[i] = temp_arr[i]\n\n return inv_count\n\n def merge_sort_and_count(arr, temp_arr, left, right):\n inv_count = 0\n if left < right:\n mid = (left + right) // 2\n\n inv_count += merge_sort_and_count(arr, temp_arr, left, mid)\n inv_count += merge_sort_and_count(arr, temp_arr, mid + 1, right)\n\n inv_count += merge_and_count(arr, temp_arr, left, mid, right)\n\n return inv_count\n\n # Create a temporary array\n temp_arr = [0] * len(arr)\n return merge_sort_and_count(arr, temp_arr, 0, len(arr) - 1)", "matching_cluster_idx": 5}, {"solution": "def get_Inv_Count(arr):\n \"\"\"\n Function to count the number of inversions in an array.\n An inversion is a pair (arr[i], arr[j]) such that i < j and arr[i] > arr[j].\n \"\"\"\n def merge_and_count(arr, temp_arr, left, mid, right):\n i = left # Starting index for left subarray\n j = mid + 1 # Starting index for right subarray\n k = left # Starting index to be sorted\n inv_count = 0\n\n # Conditions are checked to ensure that i doesn't exceed mid and j doesn't exceed right\n while i <= mid and j <= right:\n if arr[i] <= arr[j]:\n temp_arr[k] = arr[i]\n i += 1\n else:\n # There are mid - i inversions, because all remaining elements in the left subarray\n # (arr[i], arr[i+1], ..., arr[mid]) are greater than arr[j]\n temp_arr[k] = arr[j]\n inv_count += (mid - i + 1)\n j += 1\n k += 1\n\n # Copy the remaining elements of left subarray, if any\n while i <= mid:\n temp_arr[k] = arr[i]\n i += 1\n k += 1\n\n # Copy the remaining elements of right subarray, if any\n while j <= right:\n temp_arr[k] = arr[j]\n j += 1\n k += 1\n\n # Copy the sorted subarray into Original array\n for i in range(left, right + 1):\n arr[i] = temp_arr[i]\n\n return inv_count\n\n def merge_sort_and_count(arr, temp_arr, left, right):\n inv_count = 0\n if left < right:\n mid = (left + right) // 2\n\n inv_count += merge_sort_and_count(arr, temp_arr, left, mid)\n inv_count += merge_sort_and_count(arr, temp_arr, mid + 1, right)\n\n inv_count += merge_and_count(arr, temp_arr, left, mid, right)\n\n return inv_count\n\n # Create a temporary array to store the sorted subarrays\n temp_arr = [0] * len(arr)\n return merge_sort_and_count(arr, temp_arr, 0, len(arr) - 1)", "matching_cluster_idx": 5}, {"solution": "def merge_and_count(arr, temp_arr, left, mid, right):\n i = left # Starting index for left subarray\n j = mid + 1 # Starting index for right subarray\n k = left # Starting index to be sorted\n inv_count = 0\n\n # Conditions are checked to ensure that i doesn't exceed mid and j doesn't exceed right\n while i <= mid and j <= right:\n if arr[i] <= arr[j]:\n temp_arr[k] = arr[i]\n i += 1\n else:\n # There are mid - i inversions, because all remaining elements in the left subarray\n # (arr[i], arr[i+1], ..., arr[mid]) are greater than arr[j]\n temp_arr[k] = arr[j]\n inv_count += (mid - i + 1)\n j += 1\n k += 1\n\n # Copy the remaining elements of left subarray, if any\n while i <= mid:\n temp_arr[k] = arr[i]\n i += 1\n k += 1\n\n # Copy the remaining elements of right subarray, if any\n while j <= right:\n temp_arr[k] = arr[j]\n j += 1\n k += 1\n\n # Copy the sorted subarray into Original array\n for i in range(left, right + 1):\n arr[i] = temp_arr[i]\n\n return inv_count\ndef merge_sort_and_count(arr, temp_arr, left, right):\n inv_count = 0\n if left < right:\n mid = (left + right) // 2\n\n inv_count += merge_sort_and_count(arr, temp_arr, left, mid)\n inv_count += merge_sort_and_count(arr, temp_arr, mid + 1, right)\n\n inv_count += merge_and_count(arr, temp_arr, left, mid, right)\n\n return inv_count\ndef get_Inv_Count(arr):\n temp_arr = [0] * len(arr)\n return merge_sort_and_count(arr, temp_arr, 0, len(arr) - 1)", "matching_cluster_idx": 5}, {"solution": "def merge_and_count(arr, temp_arr, left, mid, right):\n i = left # Starting index for left subarray\n j = mid + 1 # Starting index for right subarray\n k = left # Starting index to be sorted\n inv_count = 0\n\n # Conditions are checked to ensure that i doesn't exceed mid and j doesn't exceed right\n while i <= mid and j <= right:\n if arr[i] <= arr[j]:\n temp_arr[k] = arr[i]\n i += 1\n else:\n # There are mid - i inversions, because all remaining elements in the left subarray\n # (arr[i], arr[i+1], ..., arr[mid]) are greater than arr[j]\n temp_arr[k] = arr[j]\n inv_count += (mid - i + 1)\n j += 1\n k += 1\n\n # Copy the remaining elements of left subarray, if any\n while i <= mid:\n temp_arr[k] = arr[i]\n i += 1\n k += 1\n\n # Copy the remaining elements of right subarray, if any\n while j <= right:\n temp_arr[k] = arr[j]\n j += 1\n k += 1\n\n # Copy the sorted subarray into Original array\n for i in range(left, right + 1):\n arr[i] = temp_arr[i]\n\n return inv_count\ndef merge_sort_and_count(arr, temp_arr, left, right):\n inv_count = 0\n if left < right:\n mid = (left + right) // 2\n\n inv_count += merge_sort_and_count(arr, temp_arr, left, mid)\n inv_count += merge_sort_and_count(arr, temp_arr, mid + 1, right)\n\n inv_count += merge_and_count(arr, temp_arr, left, mid, right)\n\n return inv_count\ndef get_Inv_Count(arr):\n n = len(arr)\n temp_arr = [0]*n\n return merge_sort_and_count(arr, temp_arr, 0, n-1)", "matching_cluster_idx": 5}, {"solution": "def merge_and_count(arr, temp_arr, left, mid, right):\n i = left # Starting index for left subarray\n j = mid + 1 # Starting index for right subarray\n k = left # Starting index to be sorted\n inv_count = 0\n\n # Conditions are checked to ensure that i doesn't exceed mid and j doesn't exceed right\n while i <= mid and j <= right:\n if arr[i] <= arr[j]:\n temp_arr[k] = arr[i]\n i += 1\n else:\n # There are mid - i inversions, because all remaining elements in the left subarray\n # (arr[i], arr[i+1], ..., arr[mid]) are greater than arr[j]\n temp_arr[k] = arr[j]\n inv_count += (mid - i + 1)\n j += 1\n k += 1\n\n # Copy the remaining elements of left subarray, if any\n while i <= mid:\n temp_arr[k] = arr[i]\n i += 1\n k += 1\n\n # Copy the remaining elements of right subarray, if any\n while j <= right:\n temp_arr[k] = arr[j]\n j += 1\n k += 1\n\n # Copy the sorted subarray into Original array\n for i in range(left, right + 1):\n arr[i] = temp_arr[i]\n\n return inv_count\ndef merge_sort_and_count(arr, temp_arr, left, right):\n inv_count = 0\n if left < right:\n mid = (left + right) // 2\n\n inv_count += merge_sort_and_count(arr, temp_arr, left, mid)\n inv_count += merge_sort_and_count(arr, temp_arr, mid + 1, right)\n inv_count += merge_and_count(arr, temp_arr, left, mid, right)\n\n return inv_count\ndef get_Inv_Count(arr):\n n = len(arr)\n temp_arr = [0]*n\n return merge_sort_and_count(arr, temp_arr, 0, n-1)", "matching_cluster_idx": 5}, {"solution": "def merge_and_count(arr, temp_arr, left, mid, right):\n i = left # Starting index for left subarray\n j = mid + 1 # Starting index for right subarray\n k = left # Starting index to be sorted\n inv_count = 0\n\n # Conditions are checked to ensure that i doesn't exceed mid and j doesn't exceed right\n while i <= mid and j <= right:\n if arr[i] <= arr[j]:\n temp_arr[k] = arr[i]\n i += 1\n else:\n # There are mid - i inversions, because all remaining elements in the left subarray\n # (arr[i], arr[i+1], ..., arr[mid]) are greater than arr[j]\n temp_arr[k] = arr[j]\n inv_count += (mid - i + 1)\n j += 1\n k += 1\n\n # Copy the remaining elements of left subarray, if any\n while i <= mid:\n temp_arr[k] = arr[i]\n i += 1\n k += 1\n\n # Copy the remaining elements of right subarray, if any\n while j <= right:\n temp_arr[k] = arr[j]\n j += 1\n k += 1\n\n # Copy the sorted subarray into Original array\n for i in range(left, right + 1):\n arr[i] = temp_arr[i]\n\n return inv_count\ndef merge_sort_and_count(arr, temp_arr, left, right):\n inv_count = 0\n if left < right:\n mid = (left + right) // 2\n\n inv_count += merge_sort_and_count(arr, temp_arr, left, mid)\n inv_count += merge_sort_and_count(arr, temp_arr, mid + 1, right)\n\n inv_count += merge_and_count(arr, temp_arr, left, mid, right)\n\n return inv_count\ndef get_Inv_Count(arr):\n n = len(arr)\n temp_arr = [0]*n\n return merge_sort_and_count(arr, temp_arr, 0, n-1)", "matching_cluster_idx": 5}, {"solution": "def get_Inv_Count(arr):\n \"\"\"\n Function to count the number of inversions in an array.\n An inversion is defined as a pair (i, j) such that i < j and arr[i] > arr[j].\n \"\"\"\n def merge_and_count(arr, temp_arr, left, mid, right):\n i = left # Starting index for left subarray\n j = mid + 1 # Starting index for right subarray\n k = left # Starting index to be sorted\n inv_count = 0\n\n # Conditions are checked to ensure that i doesn't exceed mid and j doesn't exceed right\n while i <= mid and j <= right:\n if arr[i] <= arr[j]:\n temp_arr[k] = arr[i]\n i += 1\n else:\n # There are mid - i inversions, because all remaining elements in the left subarray\n # (arr[i], arr[i+1], ..., arr[mid]) are greater than arr[j]\n temp_arr[k] = arr[j]\n inv_count += (mid - i + 1)\n j += 1\n k += 1\n\n # Copy the remaining elements of left subarray, if any\n while i <= mid:\n temp_arr[k] = arr[i]\n i += 1\n k += 1\n\n # Copy the remaining elements of right subarray, if any\n while j <= right:\n temp_arr[k] = arr[j]\n j += 1\n k += 1\n\n # Copy the sorted subarray into Original array\n for i in range(left, right + 1):\n arr[i] = temp_arr[i]\n\n return inv_count\n\n def merge_sort_and_count(arr, temp_arr, left, right):\n inv_count = 0\n if left < right:\n mid = (left + right) // 2\n\n inv_count += merge_sort_and_count(arr, temp_arr, left, mid)\n inv_count += merge_sort_and_count(arr, temp_arr, mid + 1, right)\n\n inv_count += merge_and_count(arr, temp_arr, left, mid, right)\n\n return inv_count\n\n # Create a temporary array\n temp_arr = [0] * len(arr)\n return merge_sort_and_count(arr, temp_arr, 0, len(arr) - 1)", "matching_cluster_idx": 5}, {"solution": "def merge_and_count(arr, temp_arr, left, mid, right):\n i = left # Starting index for left subarray\n j = mid + 1 # Starting index for right subarray\n k = left # Starting index to be sorted\n inv_count = 0\n\n # Conditions are checked to ensure that i doesn't exceed mid and j doesn't exceed right\n while i <= mid and j <= right:\n if arr[i] <= arr[j]:\n temp_arr[k] = arr[i]\n i += 1\n else:\n # There are mid - i inversions, because all remaining elements in the left subarray (arr[i], arr[i+1], ..., arr[mid]) are greater than arr[j]\n temp_arr[k] = arr[j]\n inv_count += (mid - i + 1)\n j += 1\n k += 1\n\n # Copy the remaining elements of left subarray, if any\n while i <= mid:\n temp_arr[k] = arr[i]\n i += 1\n k += 1\n\n # Copy the remaining elements of right subarray, if any\n while j <= right:\n temp_arr[k] = arr[j]\n j += 1\n k += 1\n\n # Copy the sorted subarray into Original array\n for i in range(left, right + 1):\n arr[i] = temp_arr[i]\n\n return inv_count\ndef merge_sort_and_count(arr, temp_arr, left, right):\n inv_count = 0\n if left < right:\n mid = (left + right) // 2\n\n inv_count += merge_sort_and_count(arr, temp_arr, left, mid)\n inv_count += merge_sort_and_count(arr, temp_arr, mid + 1, right)\n\n inv_count += merge_and_count(arr, temp_arr, left, mid, right)\n\n return inv_count\ndef get_Inv_Count(arr):\n n = len(arr)\n temp_arr = [0]*n\n return merge_sort_and_count(arr, temp_arr, 0, n-1)", "matching_cluster_idx": 5}, {"solution": "def get_Inv_Count(arr):\n def merge_and_count(arr, temp_arr, left, mid, right):\n i = left # Starting index for left subarray\n j = mid + 1 # Starting index for right subarray\n k = left # Starting index to be sorted\n inv_count = 0\n\n # Conditions are checked to ensure that i doesn't exceed mid and j doesn't exceed right\n while i <= mid and j <= right:\n if arr[i] <= arr[j]:\n temp_arr[k] = arr[i]\n i += 1\n else:\n # There are mid - i inversions, because all remaining elements in the left subarray\n # (arr[i], arr[i+1], ..., arr[mid]) are greater than arr[j]\n temp_arr[k] = arr[j]\n inv_count += (mid - i + 1)\n j += 1\n k += 1\n\n # Copy the remaining elements of left subarray, if any\n while i <= mid:\n temp_arr[k] = arr[i]\n i += 1\n k += 1\n\n # Copy the remaining elements of right subarray, if any\n while j <= right:\n temp_arr[k] = arr[j]\n j += 1\n k += 1\n\n # Copy the sorted subarray into Original array\n for i in range(left, right + 1):\n arr[i] = temp_arr[i]\n\n return inv_count\n\n def merge_sort_and_count(arr, temp_arr, left, right):\n inv_count = 0\n if left < right:\n mid = (left + right) // 2\n\n inv_count += merge_sort_and_count(arr, temp_arr, left, mid)\n inv_count += merge_sort_and_count(arr, temp_arr, mid + 1, right)\n\n inv_count += merge_and_count(arr, temp_arr, left, mid, right)\n\n return inv_count\n\n # Create a temporary array to store the sorted subarrays\n temp_arr = [0] * len(arr)\n return merge_sort_and_count(arr, temp_arr, 0, len(arr) - 1)", "matching_cluster_idx": 5}, {"solution": "def get_Inv_Count(arr):\n \"\"\"\n Function to count the number of inversions in an array.\n An inversion is a pair (i, j) such that i < j and arr[i] > arr[j].\n \"\"\"\n def merge_and_count(arr, temp_arr, left, mid, right):\n i = left # Starting index for left subarray\n j = mid + 1 # Starting index for right subarray\n k = left # Starting index to be sorted\n inv_count = 0\n\n # Conditions are checked to ensure that i doesn't exceed mid and j doesn't exceed right\n while i <= mid and j <= right:\n if arr[i] <= arr[j]:\n temp_arr[k] = arr[i]\n i += 1\n else:\n # There are mid - i inversions, because all remaining elements in the left subarray\n # (arr[i], arr[i+1], ..., arr[mid]) are greater than arr[j]\n temp_arr[k] = arr[j]\n inv_count += (mid - i + 1)\n j += 1\n k += 1\n\n # Copy the remaining elements of left subarray, if any\n while i <= mid:\n temp_arr[k] = arr[i]\n i += 1\n k += 1\n\n # Copy the remaining elements of right subarray, if any\n while j <= right:\n temp_arr[k] = arr[j]\n j += 1\n k += 1\n\n # Copy the sorted subarray into Original array\n for i in range(left, right + 1):\n arr[i] = temp_arr[i]\n\n return inv_count\n\n def merge_sort_and_count(arr, temp_arr, left, right):\n inv_count = 0\n if left < right:\n mid = (left + right) // 2\n\n inv_count += merge_sort_and_count(arr, temp_arr, left, mid)\n inv_count += merge_sort_and_count(arr, temp_arr, mid + 1, right)\n\n inv_count += merge_and_count(arr, temp_arr, left, mid, right)\n\n return inv_count\n\n # Create a temporary array to store the sorted subarrays\n temp_arr = [0] * len(arr)\n return merge_sort_and_count(arr, temp_arr, 0, len(arr) - 1)", "matching_cluster_idx": 5}, {"solution": "def merge_and_count(arr, temp_arr, left, mid, right):\n i = left # Starting index for left subarray\n j = mid + 1 # Starting index for right subarray\n k = left # Starting index to be sorted\n inv_count = 0\n\n # Conditions are checked to ensure that i doesn't exceed mid and j doesn't exceed right\n while i <= mid and j <= right:\n if arr[i] <= arr[j]:\n temp_arr[k] = arr[i]\n i += 1\n else:\n # There are mid - i inversions, because all remaining elements in the left subarray (arr[i], arr[i+1], ..., arr[mid]) are greater than arr[j]\n temp_arr[k] = arr[j]\n inv_count += (mid - i + 1)\n j += 1\n k += 1\n\n # Copy the remaining elements of left subarray, if any\n while i <= mid:\n temp_arr[k] = arr[i]\n i += 1\n k += 1\n\n # Copy the remaining elements of right subarray, if any\n while j <= right:\n temp_arr[k] = arr[j]\n j += 1\n k += 1\n\n # Copy the sorted subarray into Original array\n for i in range(left, right + 1):\n arr[i] = temp_arr[i]\n\n return inv_count\ndef merge_sort_and_count(arr, temp_arr, left, right):\n inv_count = 0\n if left < right:\n mid = (left + right) // 2\n\n inv_count += merge_sort_and_count(arr, temp_arr, left, mid)\n inv_count += merge_sort_and_count(arr, temp_arr, mid + 1, right)\n\n inv_count += merge_and_count(arr, temp_arr, left, mid, right)\n\n return inv_count\ndef get_Inv_Count(arr):\n n = len(arr)\n temp_arr = [0] * n\n return merge_sort_and_count(arr, temp_arr, 0, n - 1)", "matching_cluster_idx": 5}, {"solution": "def merge_and_count(arr, temp_arr, left, mid, right):\n i = left # Starting index for left subarray\n j = mid + 1 # Starting index for right subarray\n k = left # Starting index to be sorted\n inv_count = 0\n\n # Conditions are checked to ensure that i doesn't exceed mid and j doesn't exceed right\n while i <= mid and j <= right:\n if arr[i] <= arr[j]:\n temp_arr[k] = arr[i]\n i += 1\n else:\n # There are mid - i inversions, because all remaining elements in the left subarray (arr[i], arr[i+1], ..., arr[mid]) are greater than arr[j]\n temp_arr[k] = arr[j]\n inv_count += (mid - i + 1)\n j += 1\n k += 1\n\n # Copy the remaining elements of left subarray, if any\n while i <= mid:\n temp_arr[k] = arr[i]\n i += 1\n k += 1\n\n # Copy the remaining elements of right subarray, if any\n while j <= right:\n temp_arr[k] = arr[j]\n j += 1\n k += 1\n\n # Copy the sorted subarray into Original array\n for i in range(left, right + 1):\n arr[i] = temp_arr[i]\n\n return inv_count\ndef merge_sort_and_count(arr, temp_arr, left, right):\n inv_count = 0\n if left < right:\n mid = (left + right) // 2\n\n inv_count += merge_sort_and_count(arr, temp_arr, left, mid)\n inv_count += merge_sort_and_count(arr, temp_arr, mid + 1, right)\n\n inv_count += merge_and_count(arr, temp_arr, left, mid, right)\n\n return inv_count\ndef get_Inv_Count(arr):\n temp_arr = [0] * len(arr)\n return merge_sort_and_count(arr, temp_arr, 0, len(arr) - 1)", "matching_cluster_idx": 5}, {"solution": "def get_Inv_Count(arr):\n \"\"\"\n Function to count the number of inversions in an array.\n An inversion is a pair (i, j) such that i < j and arr[i] > arr[j].\n \"\"\"\n def merge_and_count(arr, temp_arr, left, mid, right):\n i = left # Starting index for left subarray\n j = mid + 1 # Starting index for right subarray\n k = left # Starting index to be sorted\n inv_count = 0\n\n # Conditions are checked to ensure that i doesn't exceed mid and j doesn't exceed right\n while i <= mid and j <= right:\n if arr[i] <= arr[j]:\n temp_arr[k] = arr[i]\n i += 1\n else:\n # There are mid - i inversions, because all remaining elements in the left subarray\n # (arr[i], arr[i+1], ..., arr[mid]) are greater than arr[j]\n temp_arr[k] = arr[j]\n inv_count += (mid - i + 1)\n j += 1\n k += 1\n\n # Copy the remaining elements of left subarray, if any\n while i <= mid:\n temp_arr[k] = arr[i]\n i += 1\n k += 1\n\n # Copy the remaining elements of right subarray, if any\n while j <= right:\n temp_arr[k] = arr[j]\n j += 1\n k += 1\n\n # Copy the sorted subarray into Original array\n for i in range(left, right + 1):\n arr[i] = temp_arr[i]\n\n return inv_count\n\n def merge_sort_and_count(arr, temp_arr, left, right):\n inv_count = 0\n if left < right:\n mid = (left + right) // 2\n\n inv_count += merge_sort_and_count(arr, temp_arr, left, mid)\n inv_count += merge_sort_and_count(arr, temp_arr, mid + 1, right)\n\n inv_count += merge_and_count(arr, temp_arr, left, mid, right)\n\n return inv_count\n\n # Create a temporary array\n temp_arr = [0] * len(arr)\n return merge_sort_and_count(arr, temp_arr, 0, len(arr) - 1)", "matching_cluster_idx": 5}]}, "Mbpp/308": {"dps": 90.96551724137932, "dps_norm": 65.0, "pass@1": 100.0, "profiled": [{"solution": "def large_product(list1, list2, num_products):\n # Calculate all possible products\n products = [(x * y, x, y) for x in list1 for y in list2]\n \n # Sort products by the product value in descending order\n products.sort(key=lambda x: x[0], reverse=True)\n \n # Extract the largest products\n largest_products = [product[0] for product in products[:num_products]]\n \n return largest_products", "matching_cluster_idx": 2}, {"solution": "def large_product(list1, list2, n):\n # Calculate all possible products\n products = [(x * y, x, y) for x in list1 for y in list2]\n \n # Sort products by the product value in descending order\n products.sort(reverse=True, key=lambda x: x[0])\n \n # Extract the top n products\n top_products = [product[0] for product in products[:n]]\n \n return top_products", "matching_cluster_idx": 2}, {"solution": "def large_product(list1, list2, n):\n # Calculate all possible products\n products = [x * y for x in list1 for y in list2]\n \n # Sort the products in descending order\n products.sort(reverse=True)\n \n # Return the top n largest products\n return products[:n]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n # Calculate all possible products\n products = [x * y for x in list1 for y in list2]\n \n # Sort the products in descending order\n products.sort(reverse=True)\n \n # Return the top n largest products\n return products[:n]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n # Create a list of all possible products\n products = [x * y for x in list1 for y in list2]\n \n # Sort the products in descending order\n products.sort(reverse=True)\n \n # Return the top n largest products\n return products[:n]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n # Calculate all possible products\n products = [x * y for x in list1 for y in list2]\n \n # Sort products in descending order\n products.sort(reverse=True)\n \n # Return the top n largest products\n return products[:n]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n # Calculate all possible products\n products = [x * y for x in list1 for y in list2]\n \n # Sort the products in descending order\n products.sort(reverse=True)\n \n # Return the top n largest products\n return products[:n]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n # Calculate all possible products\n products = [x * y for x in list1 for y in list2]\n \n # Sort the products in descending order\n products.sort(reverse=True)\n \n # Return the top n largest products\n return products[:n]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, num_products):\n \"\"\"\n Find the specified number of largest products from two given lists, selecting one factor from each list.\n \n :param list1: First list of integers\n :param list2: Second list of integers\n :param num_products: Number of largest products to find\n :return: List of the largest products\n \"\"\"\n # Generate all possible products\n products = [x * y for x in list1 for y in list2]\n \n # Sort the products in descending order and take the top 'num_products'\n largest_products = sorted(products, reverse=True)[:num_products]\n \n return largest_products", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n # Create a list of all possible products\n products = [x * y for x in list1 for y in list2]\n \n # Sort the products in descending order\n products.sort(reverse=True)\n \n # Return the top n largest products\n return products[:n]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n # Calculate all possible products\n products = [x * y for x in list1 for y in list2]\n \n # Sort the products in descending order\n products.sort(reverse=True)\n \n # Return the top n largest products\n return products[:n]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n # Calculate all possible products\n products = [x * y for x in list1 for y in list2]\n \n # Sort the products in descending order\n products.sort(reverse=True)\n \n # Return the top n largest products\n return products[:n]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n # Calculate all possible products\n products = [x * y for x in list1 for y in list2]\n \n # Sort the products in descending order\n products.sort(reverse=True)\n \n # Return the top n largest products\n return products[:n]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n # Calculate all possible products\n products = [x * y for x in list1 for y in list2]\n \n # Sort the products in descending order\n products.sort(reverse=True)\n \n # Return the top n largest products\n return products[:n]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n # Calculate all possible products\n products = [x * y for x in list1 for y in list2]\n \n # Sort the products in descending order\n products.sort(reverse=True)\n \n # Return the top n largest products\n return products[:n]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n # Calculate all possible products\n products = [x * y for x in list1 for y in list2]\n \n # Sort the products in descending order\n products.sort(reverse=True)\n \n # Return the top n largest products\n return products[:n]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n # Calculate all possible products\n products = [x * y for x in list1 for y in list2]\n \n # Sort the products in descending order\n products.sort(reverse=True)\n \n # Return the top n largest products\n return products[:n]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n # Calculate all possible products\n products = [x * y for x in list1 for y in list2]\n \n # Sort the products in descending order\n products.sort(reverse=True)\n \n # Return the top n largest products\n return products[:n]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n # Calculate all possible products\n products = [x * y for x in list1 for y in list2]\n \n # Sort the products in descending order\n products.sort(reverse=True)\n \n # Return the top n largest products\n return products[:n]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n # Calculate all possible products\n products = [x * y for x in list1 for y in list2]\n \n # Sort the products in descending order\n products.sort(reverse=True)\n \n # Return the top n largest products\n return products[:n]", "matching_cluster_idx": 3}]}, "Mbpp/392": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def get_max_sum(n):\n # Memoization dictionary to store already computed values\n memo = {}\n\n def f(x):\n if x == 0:\n return 0\n if x in memo:\n return memo[x]\n \n # Calculate the maximum sum using the given equation\n max_sum = max(x, f(x // 2) + f(x // 3) + f(x // 4) + f(x // 5))\n \n # Store the result in the memo dictionary\n memo[x] = max_sum\n return max_sum\n\n return f(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n # Memoization dictionary to store already computed values\n memo = {}\n\n def f(n):\n # Base case: if n is 0 or negative, return 0\n if n <= 0:\n return 0\n # If the value is already computed, return it\n if n in memo:\n return memo[n]\n # Compute the maximum sum using the given equation\n max_sum = max(f(n // 2) + f(n // 3) + f(n // 4) + f(n // 5), n)\n # Store the computed value in the memo dictionary\n memo[n] = max_sum\n return max_sum\n\n # Call the recursive function with the initial value of n\n return f(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n # Memoization dictionary to store already computed values\n memo = {}\n\n def f(x):\n if x == 0:\n return 0\n if x in memo:\n return memo[x]\n \n # Calculate the maximum sum using the given equation\n max_sum = max(x, f(x // 2) + f(x // 3) + f(x // 4) + f(x // 5))\n \n # Store the result in the memo dictionary\n memo[x] = max_sum\n return max_sum\n\n return f(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n # Memoization dictionary to store already computed values\n memo = {}\n\n def f(n):\n # Base case: if n is 0, the maximum sum is 0\n if n == 0:\n return 0\n \n # If the value is already computed, return it\n if n in memo:\n return memo[n]\n \n # Calculate the maximum sum using the given equation\n max_sum = max(n, f(n // 2) + f(n // 3) + f(n // 4) + f(n // 5))\n \n # Store the computed value in the memo dictionary\n memo[n] = max_sum\n \n return max_sum\n\n # Call the recursive function with the initial value of n\n return f(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n # Memoization dictionary to store already computed values\n memo = {}\n\n def f(x):\n if x == 0:\n return 0\n if x in memo:\n return memo[x]\n \n # Calculate the maximum sum using the given equation\n result = max(x, f(x // 2) + f(x // 3) + f(x // 4) + f(x // 5))\n memo[x] = result\n return result\n\n return f(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n # Memoization dictionary to store already computed values\n memo = {}\n\n def f(x):\n if x == 0:\n return 0\n if x in memo:\n return memo[x]\n \n # Calculate the maximum sum using the given equation\n max_sum = max(x, f(x // 2) + f(x // 3) + f(x // 4) + f(x // 5))\n \n # Store the result in the memo dictionary\n memo[x] = max_sum\n return max_sum\n\n return f(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n # Memoization dictionary to store already computed values\n memo = {}\n\n def f(n):\n # Base case: if n is 0 or negative, the maximum sum is 0\n if n <= 0:\n return 0\n \n # If the value is already computed, return it\n if n in memo:\n return memo[n]\n \n # Calculate the maximum sum using the given equation\n max_sum = max(f(n // 2) + f(n // 3) + f(n // 4) + f(n // 5), n)\n \n # Store the computed value in the memo dictionary\n memo[n] = max_sum\n \n return max_sum\n\n # Call the recursive function with the initial value of n\n return f(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n # Memoization dictionary to store already computed values\n memo = {}\n\n def f(n):\n # Base case: if n is 0 or negative, the maximum sum is 0\n if n <= 0:\n return 0\n # If the value is already computed, return it\n if n in memo:\n return memo[n]\n # Compute the maximum sum using the given equation\n max_sum = max(f(n // 2) + f(n // 3) + f(n // 4) + f(n // 5), n)\n # Store the computed value in the memo dictionary\n memo[n] = max_sum\n return max_sum\n\n # Call the recursive function with the initial value of n\n return f(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n # Memoization dictionary to store already computed values\n memo = {}\n\n def f(x):\n if x == 0:\n return 0\n if x in memo:\n return memo[x]\n \n # Calculate the maximum sum using the given equation\n max_sum = max(x, f(x // 2) + f(x // 3) + f(x // 4) + f(x // 5))\n \n # Store the result in the memo dictionary\n memo[x] = max_sum\n return max_sum\n\n return f(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n # Memoization dictionary to store already computed values\n memo = {}\n\n def f(n):\n # Base case: if n is 0 or negative, the maximum sum is 0\n if n <= 0:\n return 0\n \n # If the value is already computed, return it\n if n in memo:\n return memo[n]\n \n # Calculate the maximum sum using the given equation\n max_sum = max(f(n // 2) + f(n // 3) + f(n // 4) + f(n // 5), n)\n \n # Store the computed value in the memo dictionary\n memo[n] = max_sum\n \n return max_sum\n\n # Call the recursive function with the initial value of n\n return f(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n # Memoization dictionary to store already computed values\n memo = {}\n\n def f(n):\n # Base case: if n is 0 or less, return 0\n if n <= 0:\n return 0\n # If the value is already computed, return it\n if n in memo:\n return memo[n]\n # Compute the maximum sum using the given equation\n max_sum = max(n, f(n // 2) + f(n // 3) + f(n // 4) + f(n // 5))\n # Store the computed value in the memo dictionary\n memo[n] = max_sum\n return max_sum\n\n # Call the recursive function with the initial value of n\n return f(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n # Memoization dictionary to store already computed values\n memo = {}\n\n def f(n):\n # Base case: if n is 0 or negative, the maximum sum is 0\n if n <= 0:\n return 0\n # If the value is already computed, return it\n if n in memo:\n return memo[n]\n # Compute the maximum sum using the given equation\n max_sum = max(f(n // 2) + f(n // 3) + f(n // 4) + f(n // 5), n)\n # Store the computed value in the memo dictionary\n memo[n] = max_sum\n return max_sum\n\n # Call the recursive function with the initial value of n\n return f(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n # Memoization dictionary to store already computed values\n memo = {}\n\n def f(n):\n # Base case: if n is 0 or negative, return 0\n if n <= 0:\n return 0\n \n # If the value is already computed, return it\n if n in memo:\n return memo[n]\n \n # Calculate the maximum sum using the given equation\n max_sum = max(n, f(n // 2) + f(n // 3) + f(n // 4) + f(n // 5))\n \n # Store the computed value in the memo dictionary\n memo[n] = max_sum\n \n return max_sum\n\n # Call the recursive function with the initial value of n\n return f(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n # Memoization dictionary to store already computed values\n memo = {}\n\n def f(n):\n # Base case: if n is 0 or negative, return 0\n if n <= 0:\n return 0\n # If the value is already computed, return it\n if n in memo:\n return memo[n]\n # Compute the maximum sum using the given equation\n max_sum = max(f(n // 2) + f(n // 3) + f(n // 4) + f(n // 5), n)\n # Store the computed value in the memo dictionary\n memo[n] = max_sum\n return max_sum\n\n # Call the recursive function with the initial value of n\n return f(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n # Memoization dictionary to store already computed values\n memo = {}\n\n def f(n):\n # Base case: if n is 0 or negative, the maximum sum is 0\n if n <= 0:\n return 0\n \n # If the value is already computed, return it\n if n in memo:\n return memo[n]\n \n # Calculate the maximum sum using the given equation\n max_sum = max(n, f(n // 2) + f(n // 3) + f(n // 4) + f(n // 5))\n \n # Store the computed value in the memo dictionary\n memo[n] = max_sum\n \n return max_sum\n\n # Call the helper function with the initial value of n\n return f(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n # Memoization dictionary to store already computed values\n memo = {}\n\n def f(x):\n if x == 0:\n return 0\n if x in memo:\n return memo[x]\n \n # Calculate the maximum sum using the given equation\n max_sum = max(x, f(x // 2) + f(x // 3) + f(x // 4) + f(x // 5))\n \n # Store the result in the memoization dictionary\n memo[x] = max_sum\n return max_sum\n\n return f(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n # Memoization dictionary to store already computed values\n memo = {}\n\n def f(n):\n # Base case: if n is 0 or negative, the maximum sum is 0\n if n <= 0:\n return 0\n # If the value is already computed, return it\n if n in memo:\n return memo[n]\n # Compute the maximum sum using the given equation\n max_sum = max(f(n // 2) + f(n // 3) + f(n // 4) + f(n // 5), n)\n # Store the computed value in the memo dictionary\n memo[n] = max_sum\n return max_sum\n\n # Call the recursive function with the initial value of n\n return f(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n # Memoization dictionary to store already computed values\n memo = {}\n\n def f(n):\n # Base case: if n is 0 or negative, return 0\n if n <= 0:\n return 0\n # If the value is already computed, return it\n if n in memo:\n return memo[n]\n # Compute the maximum sum using the given equation\n max_sum = max(f(n // 2) + f(n // 3) + f(n // 4) + f(n // 5), n)\n # Store the computed value in the memo dictionary\n memo[n] = max_sum\n return max_sum\n\n # Start the recursion with the given number n\n return f(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n # Memoization dictionary to store already computed values\n memo = {}\n\n def f(n):\n # Base case: if n is 0 or negative, return 0\n if n <= 0:\n return 0\n # If the value is already computed, return it\n if n in memo:\n return memo[n]\n # Compute the maximum sum using the given equation\n max_sum = max(f(n // 2) + f(n // 3) + f(n // 4) + f(n // 5), n)\n # Store the computed value in the memo dictionary\n memo[n] = max_sum\n return max_sum\n\n # Call the recursive function with the initial value of n\n return f(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n # Memoization dictionary to store already computed values\n memo = {}\n\n def f(n):\n # Base case: if n is 0 or negative, return 0\n if n <= 0:\n return 0\n # If the value is already computed, return it\n if n in memo:\n return memo[n]\n # Compute the maximum sum using the given equation\n max_sum = max(f(n // 2) + f(n // 3) + f(n // 4) + f(n // 5), n)\n # Store the computed value in the memo dictionary\n memo[n] = max_sum\n return max_sum\n\n # Call the recursive function with the initial value of n\n return f(n)", "matching_cluster_idx": 12}]}, "Mbpp/395": {"dps": 98.08429118773947, "dps_norm": 75.0, "pass@1": 100.0, "profiled": [{"solution": "def first_non_repeating_character(s):\n # Create a dictionary to store the frequency of each character\n char_count = {}\n \n # Count the frequency of each character in the string\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n \n # Find the first character with a frequency of 1\n for char in s:\n if char_count[char] == 1:\n return char\n \n # If no non-repeated character is found, return None\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n # Create a dictionary to store the frequency of each character\n char_count = {}\n \n # Count the frequency of each character in the string\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n \n # Find the first character with a frequency of 1\n for char in s:\n if char_count[char] == 1:\n return char\n \n # If no non-repeated character is found, return None\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n # Create a dictionary to store the frequency of each character\n char_count = {}\n \n # Count the frequency of each character in the string\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n \n # Find the first character with a frequency of 1\n for char in s:\n if char_count[char] == 1:\n return char\n \n # If no non-repeated character is found, return None\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n # Create a dictionary to count the occurrences of each character\n char_count = {}\n \n # Count the occurrences of each character in the string\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n \n # Find the first character with a count of 1\n for char in s:\n if char_count[char] == 1:\n return char\n \n # If no non-repeated character is found, return None\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n # Create a dictionary to store the frequency of each character\n char_count = {}\n \n # Count the frequency of each character in the string\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n \n # Find the first character with a frequency of 1\n for char in s:\n if char_count[char] == 1:\n return char\n \n # If no non-repeated character is found, return None\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n # Create a dictionary to count the occurrences of each character\n char_count = {}\n \n # Count the occurrences of each character in the string\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n \n # Find the first character with a count of 1\n for char in s:\n if char_count[char] == 1:\n return char\n \n # If no non-repeated character is found, return None\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n # Create a dictionary to store the frequency of each character\n char_count = {}\n \n # Count the frequency of each character in the string\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n \n # Find the first character with a frequency of 1\n for char in s:\n if char_count[char] == 1:\n return char\n \n # If no non-repeated character is found, return None\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n # Create a dictionary to store the frequency of each character\n char_count = {}\n \n # Count the frequency of each character in the string\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n \n # Find the first character with a frequency of 1\n for char in s:\n if char_count[char] == 1:\n return char\n \n # If no non-repeated character is found, return None\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n # Create a dictionary to count the occurrences of each character\n char_count = {}\n \n # Count each character in the string\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n \n # Find the first character with a count of 1\n for char in s:\n if char_count[char] == 1:\n return char\n \n # If no non-repeated character is found, return None\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n # Create a dictionary to count the occurrences of each character\n char_count = {}\n \n # Count the occurrences of each character in the string\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n \n # Find the first character with a count of 1\n for char in s:\n if char_count[char] == 1:\n return char\n \n # If no non-repeated character is found, return None\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n # Create a dictionary to count the occurrences of each character\n char_count = {}\n \n # Count the occurrences of each character in the string\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n \n # Find the first character with a count of 1\n for char in s:\n if char_count[char] == 1:\n return char\n \n # If no non-repeated character is found, return None\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n # Create a dictionary to store the frequency of each character\n char_count = {}\n \n # Count the frequency of each character in the string\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n \n # Find the first character with a frequency of 1\n for char in s:\n if char_count[char] == 1:\n return char\n \n # If no non-repeated character is found, return None\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n # Create a dictionary to count the occurrences of each character\n char_count = {}\n \n # Count the occurrences of each character in the string\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n \n # Find the first character with a count of 1\n for char in s:\n if char_count[char] == 1:\n return char\n \n # If no non-repeated character is found, return None\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n # Create a dictionary to store the frequency of each character\n char_count = {}\n \n # Count the frequency of each character in the string\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n \n # Find the first character with a frequency of 1\n for char in s:\n if char_count[char] == 1:\n return char\n \n # If no non-repeated character is found, return None\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n # Create a dictionary to store the frequency of each character\n char_count = {}\n \n # Count the frequency of each character in the string\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n \n # Find the first character with a frequency of 1\n for char in s:\n if char_count[char] == 1:\n return char\n \n # If no non-repeated character is found, return None\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n # Create a dictionary to store the frequency of each character\n char_count = {}\n \n # Count the frequency of each character in the string\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n \n # Find the first character with a frequency of 1\n for char in s:\n if char_count[char] == 1:\n return char\n \n # If no non-repeated character is found, return None\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n # Create a dictionary to store the frequency of each character\n char_count = {}\n \n # Count the frequency of each character in the string\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n \n # Find the first character with a frequency of 1\n for char in s:\n if char_count[char] == 1:\n return char\n \n # If no non-repeated character is found, return None\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n # Create a dictionary to count the occurrences of each character\n char_count = {}\n \n # Count the occurrences of each character in the string\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n \n # Find the first character with a count of 1\n for char in s:\n if char_count[char] == 1:\n return char\n \n # If no non-repeated character is found, return None\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n # Create a dictionary to count the occurrences of each character\n char_count = {}\n \n # Count the occurrences of each character in the string\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n \n # Find the first character with a count of 1\n for char in s:\n if char_count[char] == 1:\n return char\n \n # If no non-repeated character is found, return None\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n # Create a dictionary to store the frequency of each character\n char_count = {}\n \n # Count the frequency of each character in the string\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n \n # Find the first character with a frequency of 1\n for char in s:\n if char_count[char] == 1:\n return char\n \n # If no non-repeated character is found, return None\n return None", "matching_cluster_idx": 5}]}, "Mbpp/405": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def check_tuplex(tup, element):\n \"\"\"\n Check whether an element exists within a tuple.\n \n Parameters:\n tup (tuple): The tuple to search within.\n element: The element to search for.\n \n Returns:\n bool: True if the element exists in the tuple, False otherwise.\n \"\"\"\n return element in tup", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tup, element):\n \"\"\"\n Check whether an element exists within a tuple.\n\n Parameters:\n tup (tuple): The tuple to search within.\n element: The element to search for.\n\n Returns:\n bool: True if the element exists in the tuple, False otherwise.\n \"\"\"\n return element in tup", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tup, element):\n \"\"\"\n Check whether an element exists within a tuple.\n \n Parameters:\n tup (tuple): The tuple to search within.\n element: The element to search for.\n \n Returns:\n bool: True if the element exists in the tuple, False otherwise.\n \"\"\"\n return element in tup", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tup, element):\n \"\"\"\n Check whether an element exists within a tuple.\n\n :param tup: The tuple to search within.\n :param element: The element to search for.\n :return: True if the element exists in the tuple, False otherwise.\n \"\"\"\n return element in tup", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tup, element):\n \"\"\"\n Check whether an element exists within a tuple.\n\n Parameters:\n tup (tuple): The tuple to search within.\n element: The element to search for.\n\n Returns:\n bool: True if the element exists in the tuple, False otherwise.\n \"\"\"\n return element in tup", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tup, element):\n \"\"\"\n Check whether an element exists within a tuple.\n \n Parameters:\n tup (tuple): The tuple to search within.\n element: The element to search for.\n \n Returns:\n bool: True if the element exists in the tuple, False otherwise.\n \"\"\"\n return element in tup", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tup, element):\n \"\"\"\n Check whether an element exists within a tuple.\n \n Parameters:\n tup (tuple): The tuple to search within.\n element: The element to search for.\n \n Returns:\n bool: True if the element exists in the tuple, False otherwise.\n \"\"\"\n return element in tup", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tup, element):\n \"\"\"\n Check whether an element exists within a tuple.\n\n Parameters:\n tup (tuple): The tuple to search within.\n element: The element to search for.\n\n Returns:\n bool: True if the element exists in the tuple, False otherwise.\n \"\"\"\n return element in tup", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tup, element):\n \"\"\"\n Check whether an element exists within a tuple.\n\n :param tup: The tuple to search within.\n :param element: The element to search for.\n :return: True if the element exists in the tuple, False otherwise.\n \"\"\"\n return element in tup", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tup, element):\n \"\"\"\n Check whether an element exists within a tuple.\n\n Parameters:\n tup (tuple): The tuple to search within.\n element: The element to search for.\n\n Returns:\n bool: True if the element exists in the tuple, False otherwise.\n \"\"\"\n return element in tup", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tup, element):\n \"\"\"\n Check whether an element exists within a tuple.\n\n Parameters:\n tup (tuple): The tuple to search within.\n element: The element to search for.\n\n Returns:\n bool: True if the element exists in the tuple, False otherwise.\n \"\"\"\n return element in tup", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tup, element):\n \"\"\"\n Check whether an element exists within a tuple.\n\n Parameters:\n tup (tuple): The tuple to search within.\n element: The element to search for.\n\n Returns:\n bool: True if the element exists in the tuple, False otherwise.\n \"\"\"\n return element in tup", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tup, element):\n \"\"\"\n Check whether an element exists within a tuple.\n\n Parameters:\n tup (tuple): The tuple to search within.\n element: The element to search for.\n\n Returns:\n bool: True if the element exists in the tuple, False otherwise.\n \"\"\"\n return element in tup", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tup, element):\n \"\"\"\n Check whether an element exists within a tuple.\n \n Parameters:\n tup (tuple): The tuple to search within.\n element: The element to search for.\n \n Returns:\n bool: True if the element exists in the tuple, False otherwise.\n \"\"\"\n return element in tup", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tup, element):\n \"\"\"\n Check whether an element exists within a tuple.\n\n Parameters:\n tup (tuple): The tuple to search within.\n element: The element to search for.\n\n Returns:\n bool: True if the element exists in the tuple, False otherwise.\n \"\"\"\n return element in tup", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tup, element):\n \"\"\"\n Check whether an element exists within a tuple.\n \n Parameters:\n tup (tuple): The tuple to search within.\n element: The element to search for.\n \n Returns:\n bool: True if the element exists in the tuple, False otherwise.\n \"\"\"\n return element in tup", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tup, element):\n \"\"\"\n Check whether an element exists within a tuple.\n\n Parameters:\n tup (tuple): The tuple to search within.\n element: The element to search for.\n\n Returns:\n bool: True if the element exists in the tuple, False otherwise.\n \"\"\"\n return element in tup", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tup, element):\n \"\"\"\n Check whether an element exists within a tuple.\n \n Parameters:\n tup (tuple): The tuple to search within.\n element: The element to search for.\n \n Returns:\n bool: True if the element exists in the tuple, False otherwise.\n \"\"\"\n return element in tup", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tup, element):\n \"\"\"\n Check whether an element exists within a tuple.\n\n Parameters:\n tup (tuple): The tuple to search within.\n element: The element to search for.\n\n Returns:\n bool: True if the element exists in the tuple, False otherwise.\n \"\"\"\n return element in tup", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tup, element):\n \"\"\"\n Check whether an element exists within a tuple.\n \n Parameters:\n tup (tuple): The tuple to search within.\n element: The element to search for.\n \n Returns:\n bool: True if the element exists in the tuple, False otherwise.\n \"\"\"\n return element in tup", "matching_cluster_idx": 3}]}, "Mbpp/414": {"dps": 91.30434782608695, "dps_norm": 88.88888888888889, "pass@1": 100.0, "profiled": [{"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Check whether any value in seq1 exists in seq2.\n\n :param seq1: First sequence to check.\n :param seq2: Second sequence to check.\n :return: True if any value in seq1 exists in seq2, False otherwise.\n \"\"\"\n return any(item in seq2 for item in seq1)", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Check whether any value in seq1 exists in seq2.\n \n Args:\n seq1 (list or tuple): The first sequence to check.\n seq2 (list or tuple): The second sequence to check.\n \n Returns:\n bool: True if any value in seq1 exists in seq2, False otherwise.\n \"\"\"\n return any(item in seq2 for item in seq1)", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Check whether any value in seq1 exists in seq2.\n\n :param seq1: First sequence (list, tuple, etc.)\n :param seq2: Second sequence (list, tuple, etc.)\n :return: True if any value in seq1 exists in seq2, False otherwise.\n \"\"\"\n return any(item in seq2 for item in seq1)", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Check whether any value in seq1 exists in seq2.\n\n :param seq1: First sequence (list, tuple, etc.)\n :param seq2: Second sequence (list, tuple, etc.)\n :return: True if any value in seq1 exists in seq2, False otherwise.\n \"\"\"\n return any(item in seq2 for item in seq1)", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Check whether any value in seq1 exists in seq2.\n\n Parameters:\n seq1 (list or tuple): The first sequence to check.\n seq2 (list or tuple): The second sequence to check.\n\n Returns:\n bool: True if any value in seq1 exists in seq2, False otherwise.\n \"\"\"\n return any(item in seq2 for item in seq1)", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Check whether any value in seq1 exists in seq2.\n\n Args:\n seq1 (list or tuple): The first sequence to check.\n seq2 (list or tuple): The second sequence to check.\n\n Returns:\n bool: True if any value in seq1 exists in seq2, False otherwise.\n \"\"\"\n return any(item in seq2 for item in seq1)", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Check whether any value in seq1 exists in seq2.\n\n :param seq1: First sequence (list, tuple, etc.)\n :param seq2: Second sequence (list, tuple, etc.)\n :return: True if any value in seq1 exists in seq2, False otherwise.\n \"\"\"\n return any(item in seq2 for item in seq1)", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Check whether any value in seq1 exists in seq2.\n\n :param seq1: First sequence (list, tuple, etc.)\n :param seq2: Second sequence (list, tuple, etc.)\n :return: True if any value in seq1 exists in seq2, False otherwise.\n \"\"\"\n return any(item in seq2 for item in seq1)", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Check whether any value in seq1 exists in seq2.\n\n Args:\n seq1 (list): The first sequence to check.\n seq2 (list): The second sequence to check.\n\n Returns:\n bool: True if any value in seq1 exists in seq2, False otherwise.\n \"\"\"\n return any(item in seq2 for item in seq1)", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Check whether any value in seq1 exists in seq2.\n \n Parameters:\n seq1 (list): The first sequence to check.\n seq2 (list): The second sequence to check.\n \n Returns:\n bool: True if any value in seq1 exists in seq2, False otherwise.\n \"\"\"\n return any(item in seq2 for item in seq1)", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Check whether any value in seq1 exists in seq2.\n\n Args:\n seq1 (list): The first sequence to check.\n seq2 (list): The second sequence to check.\n\n Returns:\n bool: True if any value in seq1 exists in seq2, False otherwise.\n \"\"\"\n return any(item in seq2 for item in seq1)", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Check whether any value in seq1 exists in seq2.\n\n Args:\n seq1 (list or tuple): The first sequence to check.\n seq2 (list or tuple): The second sequence to check.\n\n Returns:\n bool: True if any value in seq1 exists in seq2, False otherwise.\n \"\"\"\n return any(item in seq2 for item in seq1)", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Check whether any value in seq1 exists in seq2.\n\n :param seq1: First sequence (list, tuple, etc.)\n :param seq2: Second sequence (list, tuple, etc.)\n :return: True if any value in seq1 exists in seq2, False otherwise.\n \"\"\"\n return any(item in seq2 for item in seq1)", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Check whether any value in seq1 exists in seq2.\n\n :param seq1: First sequence (list, tuple, etc.)\n :param seq2: Second sequence (list, tuple, etc.)\n :return: True if any value in seq1 exists in seq2, False otherwise.\n \"\"\"\n return any(item in seq2 for item in seq1)", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Check whether any value in seq1 exists in seq2.\n \n Parameters:\n seq1 (list or tuple): The first sequence to check.\n seq2 (list or tuple): The second sequence to check.\n \n Returns:\n bool: True if any value in seq1 exists in seq2, False otherwise.\n \"\"\"\n return any(item in seq2 for item in seq1)", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Check whether any value in seq1 exists in seq2.\n\n :param seq1: First sequence (list, tuple, etc.)\n :param seq2: Second sequence (list, tuple, etc.)\n :return: True if any value in seq1 exists in seq2, False otherwise.\n \"\"\"\n return any(item in seq2 for item in seq1)", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Check whether any value in seq1 exists in seq2.\n\n :param seq1: First sequence (list, tuple, etc.)\n :param seq2: Second sequence (list, tuple, etc.)\n :return: True if any value in seq1 exists in seq2, False otherwise.\n \"\"\"\n return any(item in seq2 for item in seq1)", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Check whether any value in seq1 exists in seq2.\n\n Args:\n seq1 (list): The first sequence.\n seq2 (list): The second sequence.\n\n Returns:\n bool: True if any value in seq1 exists in seq2, False otherwise.\n \"\"\"\n return any(item in seq2 for item in seq1)", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Check whether any value in seq1 exists in seq2.\n\n :param seq1: First sequence (list, tuple, etc.)\n :param seq2: Second sequence (list, tuple, etc.)\n :return: True if any value in seq1 exists in seq2, False otherwise.\n \"\"\"\n return any(item in seq2 for item in seq1)", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Check whether any value in seq1 exists in seq2.\n\n Args:\n seq1 (list): The first sequence.\n seq2 (list): The second sequence.\n\n Returns:\n bool: True if any value in seq1 exists in seq2, False otherwise.\n \"\"\"\n return any(item in seq2 for item in seq1)", "matching_cluster_idx": 7}]}, "Mbpp/421": {"dps": 79.25925925925927, "dps_norm": 87.14285714285714, "pass@1": 100.0, "profiled": [{"solution": "def concatenate_tuple(tup, delimiter='-'):\n \"\"\"\n Concatenate each element of the tuple by the specified delimiter.\n \n :param tup: Tuple containing elements to be concatenated.\n :param delimiter: The delimiter to use between elements. Default is '-'.\n :return: A string with all elements of the tuple concatenated by the delimiter.\n \"\"\"\n return delimiter.join(map(str, tup))", "matching_cluster_idx": 5}, {"solution": "def concatenate_tuple(tup, delimiter='-'):\n \"\"\"\n Concatenate each element of the tuple by the specified delimiter.\n\n :param tup: Tuple of elements to concatenate.\n :param delimiter: The delimiter to use between elements. Default is '-'.\n :return: A string with all elements of the tuple concatenated by the delimiter.\n \"\"\"\n return delimiter.join(map(str, tup))", "matching_cluster_idx": 5}, {"solution": "def concatenate_tuple(tup, delimiter='-'):\n \"\"\"\n Concatenate each element of the tuple by the specified delimiter.\n \n :param tup: Tuple containing elements to be concatenated.\n :param delimiter: String delimiter to join the elements.\n :return: String resulting from the concatenation of the tuple elements.\n \"\"\"\n return delimiter.join(map(str, tup))", "matching_cluster_idx": 5}, {"solution": "def concatenate_tuple(tup, delimiter='-'):\n \"\"\"\n Concatenate each element of the tuple by the specified delimiter.\n\n :param tup: Tuple of elements to concatenate.\n :param delimiter: The delimiter to use for concatenation. Default is '-'.\n :return: A string with each element of the tuple concatenated by the delimiter.\n \"\"\"\n return delimiter.join(map(str, tup))", "matching_cluster_idx": 5}, {"solution": "def concatenate_tuple(tup, delimiter='-'):\n \"\"\"\n Concatenate each element of the tuple by the specified delimiter.\n\n :param tup: Tuple containing elements to be concatenated.\n :param delimiter: The delimiter to use for concatenation. Default is '-'.\n :return: A string with all elements of the tuple concatenated by the delimiter.\n \"\"\"\n return delimiter.join(map(str, tup))", "matching_cluster_idx": 5}, {"solution": "def concatenate_tuple(tup, delimiter='-'):\n \"\"\"\n Concatenate each element of the tuple by the specified delimiter.\n\n :param tup: Tuple containing elements to be concatenated.\n :param delimiter: String to be used as the delimiter between elements.\n :return: A single string with all elements of the tuple concatenated by the delimiter.\n \"\"\"\n return delimiter.join(map(str, tup))", "matching_cluster_idx": 5}, {"solution": "def concatenate_tuple(tup, delimiter='-'):\n \"\"\"\n Concatenate each element of the tuple by the specified delimiter.\n \n :param tup: Tuple of elements to concatenate.\n :param delimiter: The delimiter to use for concatenation. Default is '-'.\n :return: A string where each element of the tuple is concatenated by the delimiter.\n \"\"\"\n return delimiter.join(map(str, tup))", "matching_cluster_idx": 5}, {"solution": "def concatenate_tuple(tup, delimiter='-'):\n \"\"\"\n Concatenate each element of the tuple by the specified delimiter.\n\n :param tup: Tuple containing elements to be concatenated.\n :param delimiter: The delimiter to use for concatenation. Default is '-'.\n :return: A string with all elements of the tuple concatenated by the delimiter.\n \"\"\"\n return delimiter.join(map(str, tup))", "matching_cluster_idx": 5}, {"solution": "def concatenate_tuple(tup, delimiter='-'):\n \"\"\"\n Concatenate each element of the tuple by the specified delimiter.\n\n :param tup: Tuple containing elements to be concatenated.\n :param delimiter: String to be used as the delimiter between elements.\n :return: A single string with all elements of the tuple concatenated by the delimiter.\n \"\"\"\n return delimiter.join(map(str, tup))", "matching_cluster_idx": 5}, {"solution": "def concatenate_tuple(tup, delimiter='-'):\n \"\"\"\n Concatenate each element of the tuple by the specified delimiter.\n \n :param tup: Tuple containing elements to be concatenated.\n :param delimiter: The string to use as a delimiter between elements.\n :return: A single string with all elements of the tuple concatenated by the delimiter.\n \"\"\"\n return delimiter.join(map(str, tup))", "matching_cluster_idx": 6}, {"solution": "def concatenate_tuple(tup, delimiter='-'):\n \"\"\"\n Concatenate each element of the tuple by the specified delimiter.\n \n :param tup: Tuple of elements to concatenate.\n :param delimiter: The delimiter to use between elements. Default is '-'.\n :return: A string with all elements of the tuple concatenated by the delimiter.\n \"\"\"\n return delimiter.join(map(str, tup))", "matching_cluster_idx": 5}, {"solution": "def concatenate_tuple(tup, delimiter='-'):\n \"\"\"\n Concatenate each element of the tuple by the specified delimiter.\n \n :param tup: Tuple of elements to concatenate.\n :param delimiter: The delimiter to use between elements. Default is '-'.\n :return: A string with all elements of the tuple concatenated by the delimiter.\n \"\"\"\n return delimiter.join(map(str, tup))", "matching_cluster_idx": 5}, {"solution": "def concatenate_tuple(tup, delimiter='-'):\n \"\"\"\n Concatenate each element of the tuple by the specified delimiter.\n\n :param tup: Tuple containing elements to be concatenated.\n :param delimiter: The delimiter to use for concatenation. Default is '-'.\n :return: A string with all elements of the tuple concatenated by the delimiter.\n \"\"\"\n return delimiter.join(map(str, tup))", "matching_cluster_idx": 5}, {"solution": "def concatenate_tuple(tup, delimiter='-'):\n \"\"\"\n Concatenate each element of the tuple by the specified delimiter.\n \n :param tup: Tuple containing elements to be concatenated.\n :param delimiter: The delimiter to use for concatenation. Default is '-'.\n :return: A string where each element of the tuple is concatenated by the delimiter.\n \"\"\"\n return delimiter.join(map(str, tup))", "matching_cluster_idx": 6}, {"solution": "def concatenate_tuple(tup, delimiter='-'):\n \"\"\"\n Concatenate each element of the tuple by the specified delimiter.\n \n :param tup: A tuple containing elements to be concatenated.\n :param delimiter: The string to use as a delimiter between elements.\n :return: A string with all elements of the tuple concatenated by the delimiter.\n \"\"\"\n return delimiter.join(map(str, tup))", "matching_cluster_idx": 5}, {"solution": "def concatenate_tuple(tup, delimiter='-'):\n \"\"\"\n Concatenate each element of the tuple by the specified delimiter.\n\n :param tup: Tuple containing elements to be concatenated.\n :param delimiter: The delimiter to use for concatenation. Default is '-'.\n :return: A string with all elements of the tuple concatenated by the delimiter.\n \"\"\"\n return delimiter.join(map(str, tup))", "matching_cluster_idx": 5}, {"solution": "def concatenate_tuple(tup, delimiter='-'):\n \"\"\"\n Concatenate each element of the tuple by the specified delimiter.\n\n :param tup: Tuple of elements to concatenate.\n :param delimiter: The delimiter to use between elements. Default is '-'.\n :return: A string with all elements of the tuple concatenated by the delimiter.\n \"\"\"\n return delimiter.join(map(str, tup))", "matching_cluster_idx": 5}, {"solution": "def concatenate_tuple(tup, delimiter='-'):\n \"\"\"\n Concatenate each element of the tuple by the specified delimiter.\n \n :param tup: Tuple containing elements to be concatenated.\n :param delimiter: The string to be used as a delimiter between elements.\n :return: A single string with all elements of the tuple concatenated by the delimiter.\n \"\"\"\n return delimiter.join(map(str, tup))", "matching_cluster_idx": 5}, {"solution": "def concatenate_tuple(tup, delimiter='-'):\n \"\"\"\n Concatenate each element of the tuple by the specified delimiter.\n\n :param tup: Tuple containing elements to be concatenated.\n :param delimiter: String to be used as the delimiter between elements.\n :return: A single string with all elements concatenated by the delimiter.\n \"\"\"\n return delimiter.join(map(str, tup))", "matching_cluster_idx": 5}, {"solution": "def concatenate_tuple(tup, delimiter='-'):\n \"\"\"\n Concatenate each element of the tuple by the specified delimiter.\n\n :param tup: Tuple containing elements to be concatenated.\n :param delimiter: The delimiter to use for concatenation. Default is '-'.\n :return: A string where each element of the tuple is concatenated by the delimiter.\n \"\"\"\n return delimiter.join(map(str, tup))", "matching_cluster_idx": 5}]}, "Mbpp/424": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def extract_rear(tup):\n \"\"\"\n Extracts the rear index element of each string in the given tuple.\n \n Args:\n tup (tuple): A tuple of strings.\n \n Returns:\n list: A list of rear index elements from each string in the tuple.\n \"\"\"\n return [s[-1] for s in tup]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(strings_tuple):\n \"\"\"\n Extracts the rear index element of each string in the given tuple.\n\n Args:\n strings_tuple (tuple): A tuple of strings.\n\n Returns:\n list: A list of rear index elements from each string.\n \"\"\"\n return [s[-1] for s in strings_tuple]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(tup):\n \"\"\"\n Extracts the rear index element of each string in the given tuple.\n \n Args:\n tup (tuple): A tuple of strings.\n \n Returns:\n list: A list containing the rear index element of each string in the tuple.\n \"\"\"\n return [s[-1] for s in tup]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(tup):\n \"\"\"\n Extracts the rear index element of each string in the given tuple.\n \n Args:\n tup (tuple): A tuple of strings.\n \n Returns:\n list: A list of characters, each being the rear index element of the corresponding string in the tuple.\n \"\"\"\n return [s[-1] for s in tup]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(strings_tuple):\n \"\"\"\n Extracts the rear index element of each string in the given tuple.\n \n Args:\n strings_tuple (tuple): A tuple of strings.\n \n Returns:\n list: A list containing the rear index element of each string.\n \"\"\"\n return [s[-1] for s in strings_tuple]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(tup):\n \"\"\"\n Extracts the rear index element of each string in the given tuple.\n \n Args:\n tup (tuple): A tuple of strings.\n \n Returns:\n list: A list containing the rear index element of each string in the tuple.\n \"\"\"\n return [s[-1] for s in tup]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(tup):\n \"\"\"\n Extracts the rear index element of each string in the given tuple.\n \n Args:\n tup (tuple): A tuple of strings.\n \n Returns:\n list: A list of rear index elements from each string in the tuple.\n \"\"\"\n return [s[-1] for s in tup]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(tup):\n \"\"\"\n Extracts the rear index element of each string in the given tuple.\n \n Args:\n tup (tuple): A tuple of strings.\n \n Returns:\n list: A list of rear index elements from each string in the tuple.\n \"\"\"\n return [s[-1] for s in tup]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(tup):\n \"\"\"\n Extracts the rear index element of each string in the given tuple.\n \n Args:\n tup (tuple): A tuple of strings.\n \n Returns:\n list: A list of rear index elements from each string in the tuple.\n \"\"\"\n return [s[-1] for s in tup]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(tup):\n \"\"\"\n Extracts the rear index element of each string in the given tuple.\n \n Args:\n tup (tuple): A tuple of strings.\n \n Returns:\n list: A list of rear index elements from each string in the tuple.\n \"\"\"\n return [s[-1] for s in tup]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(strings_tuple):\n \"\"\"\n Extracts the rear index element of each string in the given tuple.\n \n Args:\n strings_tuple (tuple): A tuple of strings.\n \n Returns:\n list: A list containing the rear index element of each string.\n \"\"\"\n return [s[-1] for s in strings_tuple]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(tup):\n \"\"\"\n Extracts the rear index element of each string in the given tuple.\n \n Args:\n tup (tuple): A tuple of strings.\n \n Returns:\n list: A list containing the rear index element of each string in the tuple.\n \"\"\"\n return [s[-1] for s in tup]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(tup):\n \"\"\"\n Extracts the rear index element of each string in the given tuple.\n \n Args:\n tup (tuple): A tuple of strings.\n \n Returns:\n list: A list of rear index elements from each string in the tuple.\n \"\"\"\n return [s[-1] for s in tup]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(strings_tuple):\n \"\"\"\n Extracts the rear index element of each string in the given tuple.\n \n Args:\n strings_tuple (tuple): A tuple of strings.\n \n Returns:\n list: A list containing the rear index element of each string.\n \"\"\"\n return [s[-1] for s in strings_tuple]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(tup):\n \"\"\"\n Extracts the rear index element of each string in the given tuple.\n \n Args:\n tup (tuple): A tuple of strings.\n \n Returns:\n list: A list of rear index elements from each string in the tuple.\n \"\"\"\n return [s[-1] for s in tup]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(tup):\n \"\"\"\n Extracts the rear index element of each string in the given tuple.\n \n Args:\n tup (tuple): A tuple of strings.\n \n Returns:\n list: A list containing the rear index element of each string in the tuple.\n \"\"\"\n return [s[-1] for s in tup]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(strings_tuple):\n \"\"\"\n Extracts the rear index element of each string in the given tuple.\n \n Args:\n strings_tuple (tuple): A tuple of strings.\n \n Returns:\n list: A list of rear index elements from each string.\n \"\"\"\n return [s[-1] for s in strings_tuple]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(strings_tuple):\n \"\"\"\n Extracts the rear index element of each string in the given tuple.\n \n Args:\n strings_tuple (tuple): A tuple of strings.\n \n Returns:\n list: A list containing the rear index element of each string.\n \"\"\"\n return [s[-1] for s in strings_tuple]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(strings_tuple):\n \"\"\"\n Extracts the rear index element of each string in the given tuple.\n \n Args:\n strings_tuple (tuple): A tuple of strings.\n \n Returns:\n list: A list containing the rear index element of each string.\n \"\"\"\n return [s[-1] for s in strings_tuple]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(strings_tuple):\n \"\"\"\n Extracts the rear index element of each string in the given tuple.\n \n Args:\n strings_tuple (tuple): A tuple of strings.\n \n Returns:\n list: A list containing the rear index element of each string.\n \"\"\"\n return [s[-1] for s in strings_tuple]", "matching_cluster_idx": 4}]}, "Mbpp/425": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def count_element_in_list(lst, element):\n count = 0\n for sublist in lst:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(nested_list, element):\n count = 0\n for sublist in nested_list:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(nested_list, element):\n count = 0\n for sublist in nested_list:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(nested_list, element):\n count = 0\n for sublist in nested_list:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(nested_list, element):\n count = 0\n for sublist in nested_list:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(nested_list, element):\n count = 0\n for sublist in nested_list:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(nested_list, element):\n count = 0\n for sublist in nested_list:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(nested_list, element):\n count = 0\n for sublist in nested_list:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(nested_list, element):\n \"\"\"\n Counts the number of sublists that contain a particular element.\n\n :param nested_list: A list of lists.\n :param element: The element to search for in the sublists.\n :return: The number of sublists containing the element.\n \"\"\"\n count = 0\n for sublist in nested_list:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(nested_list, element):\n count = 0\n for sublist in nested_list:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(nested_list, element):\n \"\"\"\n Count the number of sublists that contain a particular element.\n\n :param nested_list: A list of lists.\n :param element: The element to search for in the sublists.\n :return: The number of sublists containing the element.\n \"\"\"\n count = 0\n for sublist in nested_list:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(nested_list, element):\n count = 0\n for sublist in nested_list:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, element):\n count = 0\n for sublist in lst:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(nested_list, element):\n count = 0\n for sublist in nested_list:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(nested_list, element):\n \"\"\"\n Counts the number of sublists containing a particular element.\n\n :param nested_list: A list of lists.\n :param element: The element to search for in the sublists.\n :return: The number of sublists containing the element.\n \"\"\"\n count = 0\n for sublist in nested_list:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(nested_list, element):\n count = 0\n for sublist in nested_list:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(nested_list, target_element):\n \"\"\"\n Counts the number of sublists containing a particular element.\n \n :param nested_list: A list of lists.\n :param target_element: The element to count occurrences of.\n :return: The number of sublists containing the target element.\n \"\"\"\n count = 0\n for sublist in nested_list:\n if target_element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(nested_list, element):\n count = 0\n for sublist in nested_list:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(nested_list, element):\n count = 0\n for sublist in nested_list:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(nested_list, element):\n count = 0\n for sublist in nested_list:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}]}, "Mbpp/428": {"dps": 84.29752066115702, "dps_norm": 55.55555555555556, "pass@1": 100.0, "profiled": [{"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2\n \n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n \n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2\n \n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n \n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2\n \n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n \n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n \n arr[j] = temp\n \n gap //= 2\n \n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2\n \n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n \n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2\n \n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n \n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2\n \n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n \n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n # Start with a big gap, then reduce the gap\n n = len(arr)\n gap = n // 2\n \n # Perform gapped insertion sort for this gap size.\n # The first gap elements a[0..gap-1] are already in gapped order\n # keep adding one more element until the entire array is gap sorted\n while gap > 0:\n for i in range(gap, n):\n # add a[i] to the elements that have been gap sorted\n # save a[i] in temp and make a hole at position i\n temp = arr[i]\n # shift earlier gap-sorted elements up until the correct location for a[i] is found\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n # put temp (the original a[i]) in its correct location\n arr[j] = temp\n # Reduce the gap for the next element\n gap //= 2\n \n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2\n \n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n \n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2\n \n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n \n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n \"\"\"\n Sorts the given array using the Shell Sort algorithm.\n \n :param arr: List of integers to be sorted.\n :return: Sorted list of integers.\n \"\"\"\n n = len(arr)\n gap = n // 2\n \n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n \n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2\n \n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n \n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n # Start with a big gap, then reduce the gap\n n = len(arr)\n gap = n // 2\n \n # Do a gapped insertion sort for this gap size.\n # The first gap elements a[0..gap-1] are already in gapped order\n # keep adding one more element until the entire array is gap sorted\n while gap > 0:\n for i in range(gap, n):\n # add a[i] to the elements that have been gap sorted\n # save a[i] in temp and make a hole at position i\n temp = arr[i]\n \n # shift earlier gap-sorted elements up until the correct location for a[i] is found\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n \n # put temp (the original a[i]) in its correct location\n arr[j] = temp\n gap //= 2\n \n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2\n \n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n \n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n \"\"\"\n Sorts the given array using the Shell Sort algorithm.\n \n :param arr: List of integers to be sorted.\n :return: Sorted list of integers.\n \"\"\"\n n = len(arr)\n gap = n // 2\n \n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n \n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2\n \n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n \n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2\n \n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n \n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2\n \n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n \n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2\n \n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n \n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2\n \n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n \n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2\n \n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n \n return arr", "matching_cluster_idx": 4}]}, "Mbpp/433": {"dps": 63.82978723404255, "dps_norm": 60.0, "pass@1": 100.0, "profiled": [{"solution": "def check_greater(arr, num):\n \"\"\"\n Check whether the entered number is greater than all elements of the given array.\n\n Parameters:\n arr (list): The array of numbers to compare against.\n num (int): The number to check.\n\n Returns:\n bool: True if num is greater than all elements in arr, False otherwise.\n \"\"\"\n return all(num > x for x in arr)", "matching_cluster_idx": 2}, {"solution": "def check_greater(arr, num):\n \"\"\"\n Check whether the entered number is greater than all elements of the given array.\n \n Parameters:\n arr (list): The array of numbers to compare against.\n num (int): The number to check.\n \n Returns:\n bool: True if num is greater than all elements in arr, False otherwise.\n \"\"\"\n return all(num > x for x in arr)", "matching_cluster_idx": 2}, {"solution": "def check_greater(arr, num):\n \"\"\"\n Check whether the entered number is greater than all elements of the given array.\n \n :param arr: List of integers\n :param num: Integer to compare with elements of the array\n :return: Boolean indicating if num is greater than all elements of arr\n \"\"\"\n return all(num > x for x in arr)", "matching_cluster_idx": 2}, {"solution": "def check_greater(arr, num):\n \"\"\"\n Check whether the entered number is greater than all elements of the given array.\n \n Parameters:\n arr (list): The array of numbers to compare against.\n num (int): The number to check.\n \n Returns:\n bool: True if num is greater than all elements in arr, False otherwise.\n \"\"\"\n return all(num > x for x in arr)", "matching_cluster_idx": 2}, {"solution": "def check_greater(arr, num):\n \"\"\"\n Check whether the entered number is greater than all elements of the given array.\n \n Parameters:\n arr (list): The array of numbers to compare against.\n num (int): The number to check.\n \n Returns:\n bool: True if num is greater than all elements in arr, False otherwise.\n \"\"\"\n return all(num > x for x in arr)", "matching_cluster_idx": 2}, {"solution": "def check_greater(arr, num):\n \"\"\"\n Check whether the entered number is greater than all elements of the given array.\n \n Parameters:\n arr (list): The array of numbers to compare against.\n num (int): The number to check.\n \n Returns:\n bool: True if the number is greater than all elements in the array, False otherwise.\n \"\"\"\n return all(num > x for x in arr)", "matching_cluster_idx": 2}, {"solution": "def check_greater(arr, num):\n \"\"\"\n Check whether the entered number is greater than all elements of the given array.\n\n Parameters:\n arr (list): The array of numbers to compare against.\n num (int): The number to check.\n\n Returns:\n bool: True if num is greater than all elements in arr, False otherwise.\n \"\"\"\n return all(num > x for x in arr)", "matching_cluster_idx": 2}, {"solution": "def check_greater(arr, num):\n \"\"\"\n Check whether the entered number is greater than all elements of the given array.\n \n Parameters:\n arr (list): The array of numbers to compare against.\n num (int): The number to check.\n \n Returns:\n bool: True if num is greater than all elements in arr, False otherwise.\n \"\"\"\n return all(num > x for x in arr)", "matching_cluster_idx": 2}, {"solution": "def check_greater(arr, num):\n \"\"\"\n Check whether the entered number is greater than all elements of the given array.\n\n Parameters:\n arr (list): The array of numbers to compare against.\n num (int): The number to check.\n\n Returns:\n bool: True if num is greater than all elements in arr, False otherwise.\n \"\"\"\n return all(num > x for x in arr)", "matching_cluster_idx": 2}, {"solution": "def check_greater(arr, num):\n \"\"\"\n Check whether the entered number is greater than all elements of the given array.\n \n Parameters:\n arr (list): The array of numbers to compare against.\n num (int): The number to check.\n \n Returns:\n bool: True if num is greater than all elements in arr, False otherwise.\n \"\"\"\n return all(num > x for x in arr)", "matching_cluster_idx": 2}, {"solution": "def check_greater(arr, num):\n \"\"\"\n Check whether the entered number is greater than all elements of the given array.\n \n Parameters:\n arr (list): The array of numbers to compare against.\n num (int): The number to check.\n \n Returns:\n bool: True if num is greater than all elements in arr, False otherwise.\n \"\"\"\n return all(num > x for x in arr)", "matching_cluster_idx": 2}, {"solution": "def check_greater(arr, num):\n \"\"\"\n Check whether the entered number is greater than all elements of the given array.\n \n Parameters:\n arr (list): The array of numbers to compare against.\n num (int): The number to check.\n \n Returns:\n bool: True if num is greater than all elements in arr, False otherwise.\n \"\"\"\n return all(num > x for x in arr)", "matching_cluster_idx": 2}, {"solution": "def check_greater(arr, num):\n \"\"\"\n Check whether the entered number is greater than all elements of the given array.\n \n Parameters:\n arr (list): The array of numbers to compare against.\n num (int): The number to check.\n \n Returns:\n bool: True if num is greater than all elements in arr, False otherwise.\n \"\"\"\n return all(num > x for x in arr)", "matching_cluster_idx": 2}, {"solution": "def check_greater(arr, num):\n \"\"\"\n Check whether the entered number is greater than all elements of the given array.\n\n Parameters:\n arr (list): The array of numbers to compare against.\n num (int): The number to check.\n\n Returns:\n bool: True if num is greater than all elements in arr, False otherwise.\n \"\"\"\n return all(num > x for x in arr)", "matching_cluster_idx": 2}, {"solution": "def check_greater(arr, num):\n \"\"\"\n Check whether the entered number is greater than all elements of the given array.\n\n :param arr: List of integers\n :param num: Integer to compare with elements of the array\n :return: Boolean, True if num is greater than all elements in arr, False otherwise\n \"\"\"\n return all(num > x for x in arr)", "matching_cluster_idx": 2}, {"solution": "def check_greater(arr, num):\n \"\"\"\n Check whether the entered number is greater than all elements of the given array.\n \n Parameters:\n arr (list): The array of numbers to compare against.\n num (int/float): The number to check.\n \n Returns:\n bool: True if num is greater than all elements in arr, False otherwise.\n \"\"\"\n return all(num > x for x in arr)", "matching_cluster_idx": 2}, {"solution": "def check_greater(arr, num):\n \"\"\"\n Check whether the entered number is greater than all elements of the given array.\n\n Parameters:\n arr (list): The array of numbers to compare against.\n num (int/float): The number to check.\n\n Returns:\n bool: True if num is greater than all elements in arr, False otherwise.\n \"\"\"\n return all(num > x for x in arr)", "matching_cluster_idx": 2}, {"solution": "def check_greater(arr, num):\n \"\"\"\n Check whether the entered number is greater than all elements of the given array.\n \n Parameters:\n arr (list): The array of numbers to compare against.\n num (int): The number to check.\n \n Returns:\n bool: True if num is greater than all elements in arr, False otherwise.\n \"\"\"\n return all(num > x for x in arr)", "matching_cluster_idx": 2}, {"solution": "def check_greater(arr, num):\n \"\"\"\n Check whether the entered number is greater than all elements of the given array.\n\n Parameters:\n arr (list): The array of numbers to compare against.\n num (int): The number to check.\n\n Returns:\n bool: True if num is greater than all elements in arr, False otherwise.\n \"\"\"\n return all(num > x for x in arr)", "matching_cluster_idx": 2}, {"solution": "def check_greater(arr, num):\n \"\"\"\n Check whether the entered number is greater than all elements of the given array.\n \n Parameters:\n arr (list): The array of numbers to compare against.\n num (int): The number to check.\n \n Returns:\n bool: True if the number is greater than all elements in the array, False otherwise.\n \"\"\"\n return all(num > x for x in arr)", "matching_cluster_idx": 2}]}, "Mbpp/437": {"dps": 71.61764705882354, "dps_norm": 22.0, "pass@1": 83.0, "profiled": [{"solution": "def remove_odd(s):\n # Use list comprehension to filter out odd-indexed characters\n return ''.join([s[i] for i in range(len(s)) if i % 2 == 1])", "matching_cluster_idx": 0}, {"solution": "def remove_odd(s):\n # Initialize an empty string to store the result\n result = \"\"\n \n # Iterate over the string with index\n for i, char in enumerate(s):\n # Check if the index is even (0, 2, 4, ...)\n if i % 2 == 1:\n # Append the character to the result string\n result += char\n \n return result", "matching_cluster_idx": 0}, {"solution": "def remove_odd(s):\n # Use list comprehension to filter out odd-indexed characters\n return ''.join([s[i] for i in range(len(s)) if i % 2 == 1])", "matching_cluster_idx": 0}, {"solution": "def remove_odd(s):\n # Use list comprehension to filter out odd-indexed characters\n return ''.join([s[i] for i in range(len(s)) if i % 2 == 1])", "matching_cluster_idx": 0}, {"solution": "def remove_odd(s):\n # Initialize an empty string to store the result\n result = \"\"\n \n # Iterate over the string with index\n for i, char in enumerate(s):\n # Check if the index is even (0, 2, 4, ...)\n if i % 2 == 1:\n # Append the character to the result string\n result += char\n \n return result", "matching_cluster_idx": 0}, {"solution": "def remove_odd(s):\n # Use list comprehension to filter out characters at odd indices\n return ''.join([s[i] for i in range(len(s)) if i % 2 == 1])", "matching_cluster_idx": 1}, {"solution": "def remove_odd(s):\n # Initialize an empty string to store the result\n result = \"\"\n \n # Iterate over the string with index\n for i, char in enumerate(s):\n # Check if the index is even (0, 2, 4, ...)\n if i % 2 == 1:\n # Append the character to the result string\n result += char\n \n return result", "matching_cluster_idx": 0}, {"solution": "def remove_odd(s):\n # Initialize an empty string to store the result\n result = \"\"\n \n # Iterate over the string with index\n for i, char in enumerate(s):\n # Check if the index is even (0, 2, 4, ...)\n if i % 2 == 1:\n # Append the character to the result string\n result += char\n \n return result", "matching_cluster_idx": 0}, {"solution": "def remove_odd(s):\n # Use list comprehension to filter out odd-indexed characters\n return ''.join([s[i] for i in range(len(s)) if i % 2 == 1])", "matching_cluster_idx": 0}, {"solution": "def remove_odd(s):\n # Use list comprehension to filter out odd-indexed characters\n return ''.join([s[i] for i in range(len(s)) if i % 2 == 1])", "matching_cluster_idx": 0}, {"solution": "def remove_odd(s):\n # Use list comprehension to filter out characters at odd indices\n return ''.join([s[i] for i in range(len(s)) if i % 2 == 1])", "matching_cluster_idx": 1}, {"solution": "def remove_odd(s):\n \"\"\"\n Removes odd-indexed characters from the given string.\n \n Args:\n s (str): The input string.\n \n Returns:\n str: The string with odd-indexed characters removed.\n \"\"\"\n return ''.join([s[i] for i in range(len(s)) if i % 2 == 1])", "matching_cluster_idx": 0}, {"solution": "def remove_odd(s):\n # Use list comprehension to filter out odd-indexed characters\n return ''.join([s[i] for i in range(len(s)) if i % 2 == 1])", "matching_cluster_idx": 0}, {"solution": "def remove_odd(s):\n # Use list comprehension to filter out odd-indexed characters\n return ''.join([s[i] for i in range(len(s)) if i % 2 == 1])", "matching_cluster_idx": 0}, {"solution": "def remove_odd(s):\n # Use list comprehension to filter out odd-indexed characters\n return ''.join([s[i] for i in range(len(s)) if i % 2 == 1])", "matching_cluster_idx": 0}, {"solution": "def remove_odd(s):\n # Initialize an empty string to store the result\n result = \"\"\n \n # Iterate over the string with index\n for i, char in enumerate(s):\n # Check if the index is even (0, 2, 4, ...)\n if i % 2 == 1:\n # Append the character to the result string\n result += char\n \n return result", "matching_cluster_idx": 0}, {"solution": "def remove_odd(s):\n # Use list comprehension to filter out odd-indexed characters\n return ''.join([s[i] for i in range(len(s)) if i % 2 == 1])", "matching_cluster_idx": 0}, {"solution": "def remove_odd(s):\n \"\"\"\n Removes odd-indexed characters from the given string.\n \n Args:\n s (str): The input string.\n \n Returns:\n str: The string with odd-indexed characters removed.\n \"\"\"\n return ''.join(s[i] for i in range(len(s)) if i % 2 == 1)", "matching_cluster_idx": 0}, {"solution": "def remove_odd(s):\n # Use list comprehension to filter out odd-indexed characters\n return ''.join([s[i] for i in range(len(s)) if i % 2 == 1])", "matching_cluster_idx": 0}, {"solution": "def remove_odd(s):\n # Use list comprehension to filter out odd-indexed characters\n return ''.join([s[i] for i in range(len(s)) if i % 2 == 1])", "matching_cluster_idx": 0}]}, "Mbpp/440": {"dps": null, "dps_norm": null, "pass@1": 0.0, "profiled": []}, "Mbpp/446": {"dps": 96.05911330049261, "dps_norm": 60.0, "pass@1": 100.0, "profiled": [{"solution": "def count_Occurrence(tup, lst):\n \"\"\"\n Count the occurrence of all elements of a list in a tuple.\n\n Parameters:\n tup (tuple): The tuple in which to count occurrences.\n lst (list): The list of elements to count in the tuple.\n\n Returns:\n int: The total count of occurrences of elements from the list in the tuple.\n \"\"\"\n count = 0\n for item in lst:\n count += tup.count(item)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tup, lst):\n \"\"\"\n Count the occurrence of all elements of a list in a tuple.\n\n Parameters:\n tup (tuple): The tuple in which to count occurrences.\n lst (list): The list of elements to count in the tuple.\n\n Returns:\n int: The total count of occurrences of elements from the list in the tuple.\n \"\"\"\n count = 0\n for item in lst:\n count += tup.count(item)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tup, lst):\n \"\"\"\n Count the occurrence of all elements of a list in a tuple.\n\n Parameters:\n tup (tuple): The tuple in which to count occurrences.\n lst (list): The list of elements to count in the tuple.\n\n Returns:\n int: The total count of occurrences of elements from the list in the tuple.\n \"\"\"\n count = 0\n for element in lst:\n count += tup.count(element)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tup, lst):\n \"\"\"\n Count the occurrence of all elements of the list in the tuple.\n \n Parameters:\n tup (tuple): The tuple in which to count occurrences.\n lst (list): The list of elements to count in the tuple.\n \n Returns:\n int: The total count of occurrences of elements from the list in the tuple.\n \"\"\"\n count = 0\n for item in lst:\n count += tup.count(item)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tup, lst):\n \"\"\"\n Count the occurrence of all elements of a list in a tuple.\n\n :param tup: A tuple containing elements.\n :param lst: A list of elements to count in the tuple.\n :return: The total count of elements from the list that appear in the tuple.\n \"\"\"\n count = 0\n for item in lst:\n count += tup.count(item)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tup, lst):\n \"\"\"\n Count the occurrence of all elements of the list in the tuple.\n\n :param tup: A tuple containing elements.\n :param lst: A list of elements to count in the tuple.\n :return: The total count of elements from the list that appear in the tuple.\n \"\"\"\n count = 0\n for item in lst:\n count += tup.count(item)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tup, lst):\n \"\"\"\n Count the occurrence of all elements of a list in a tuple.\n\n :param tup: A tuple containing elements.\n :param lst: A list of elements to count in the tuple.\n :return: The total count of elements from the list that appear in the tuple.\n \"\"\"\n count = 0\n for item in lst:\n count += tup.count(item)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tup, lst):\n \"\"\"\n Count the occurrence of all elements of the list in the tuple.\n \n :param tup: A tuple containing elements.\n :param lst: A list containing elements to count in the tuple.\n :return: The total count of elements from the list that appear in the tuple.\n \"\"\"\n count = 0\n for item in lst:\n count += tup.count(item)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tup, lst):\n \"\"\"\n Count the occurrence of all elements of a list in a tuple.\n\n :param tup: A tuple containing elements.\n :param lst: A list of elements to count in the tuple.\n :return: The total count of elements from the list that appear in the tuple.\n \"\"\"\n count = 0\n for element in lst:\n count += tup.count(element)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tup, lst):\n \"\"\"\n Count the occurrence of all elements of a list in a tuple.\n\n :param tup: A tuple containing elements.\n :param lst: A list of elements to count in the tuple.\n :return: The total count of elements from the list that appear in the tuple.\n \"\"\"\n count = 0\n for item in lst:\n count += tup.count(item)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tup, lst):\n \"\"\"\n Count the occurrence of all elements of the list in the tuple.\n \n :param tup: A tuple containing elements.\n :param lst: A list of elements to count in the tuple.\n :return: The total count of elements from the list that appear in the tuple.\n \"\"\"\n count = 0\n for item in lst:\n count += tup.count(item)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tup, lst):\n \"\"\"\n Count the occurrence of all elements of the list in the tuple.\n \n Parameters:\n tup (tuple): The tuple in which to count occurrences.\n lst (list): The list of elements to count in the tuple.\n \n Returns:\n int: The total count of occurrences of elements from the list in the tuple.\n \"\"\"\n count = 0\n for item in lst:\n count += tup.count(item)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tup, lst):\n \"\"\"\n Count the occurrence of all elements of the list in the tuple.\n\n Parameters:\n tup (tuple): The tuple in which to count occurrences.\n lst (list): The list of elements to count in the tuple.\n\n Returns:\n int: The total count of occurrences of elements from the list in the tuple.\n \"\"\"\n count = 0\n for item in lst:\n count += tup.count(item)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tup, lst):\n \"\"\"\n Count the occurrence of all elements of a list in a tuple.\n\n :param tup: A tuple containing elements.\n :param lst: A list of elements to count in the tuple.\n :return: The total count of elements from the list that appear in the tuple.\n \"\"\"\n count = 0\n for item in lst:\n count += tup.count(item)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tup, lst):\n \"\"\"\n Count the occurrence of all elements of a list in a tuple.\n\n :param tup: A tuple containing elements.\n :param lst: A list of elements to count in the tuple.\n :return: The total count of elements from the list that appear in the tuple.\n \"\"\"\n count = 0\n for item in lst:\n count += tup.count(item)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tup, lst):\n \"\"\"\n Count the occurrence of all elements of a list in a tuple.\n\n :param tup: A tuple containing elements.\n :param lst: A list of elements to count in the tuple.\n :return: The total count of elements from the list that appear in the tuple.\n \"\"\"\n count = 0\n for item in lst:\n count += tup.count(item)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tup, lst):\n \"\"\"\n Count the occurrence of all elements of a list in a tuple.\n \n Parameters:\n tup (tuple): The tuple to search for occurrences.\n lst (list): The list of elements to count in the tuple.\n \n Returns:\n int: The total count of occurrences of elements from the list in the tuple.\n \"\"\"\n count = 0\n for item in lst:\n count += tup.count(item)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tup, lst):\n \"\"\"\n Count the occurrence of all elements of a list in a tuple.\n\n Parameters:\n tup (tuple): The tuple in which to count occurrences.\n lst (list): The list of elements to count in the tuple.\n\n Returns:\n int: The total count of occurrences of elements from the list in the tuple.\n \"\"\"\n count = 0\n for item in lst:\n count += tup.count(item)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tup, lst):\n \"\"\"\n Count the occurrence of all elements of a list in a tuple.\n\n :param tup: A tuple containing elements.\n :param lst: A list of elements to count in the tuple.\n :return: The total count of elements from the list that appear in the tuple.\n \"\"\"\n count = 0\n for element in lst:\n count += tup.count(element)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tup, lst):\n \"\"\"\n Count the occurrence of all elements of a list in a tuple.\n\n Parameters:\n tup (tuple): The tuple in which to count occurrences.\n lst (list): The list of elements to count in the tuple.\n\n Returns:\n int: The total count of occurrences of elements from the list in the tuple.\n \"\"\"\n count = 0\n for item in lst:\n count += tup.count(item)\n return count", "matching_cluster_idx": 2}]}, "Mbpp/451": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 49.0, "profiled": [{"solution": "def remove_whitespaces(input_string):\n \"\"\"\n Removes all whitespaces from the given string.\n \n Args:\n input_string (str): The string from which whitespaces need to be removed.\n \n Returns:\n str: The string with all whitespaces removed.\n \"\"\"\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string):\n \"\"\"\n Removes all whitespaces from the given string.\n \n Args:\n input_string (str): The string from which whitespaces need to be removed.\n \n Returns:\n str: The string with all whitespaces removed.\n \"\"\"\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string):\n \"\"\"\n Remove all whitespaces from the given string.\n \n Args:\n input_string (str): The string from which whitespaces need to be removed.\n \n Returns:\n str: The string with all whitespaces removed.\n \"\"\"\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string):\n \"\"\"\n Removes all whitespaces from the given string.\n\n Args:\n input_string (str): The input string from which whitespaces need to be removed.\n\n Returns:\n str: The input string with all whitespaces removed.\n \"\"\"\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string):\n \"\"\"\n Removes all whitespaces from the given string.\n\n Args:\n input_string (str): The string from which whitespaces need to be removed.\n\n Returns:\n str: The string with all whitespaces removed.\n \"\"\"\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string):\n \"\"\"\n Removes all whitespaces from the given string.\n\n Args:\n input_string (str): The input string from which whitespaces need to be removed.\n\n Returns:\n str: The input string with all whitespaces removed.\n \"\"\"\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string):\n \"\"\"\n Removes all whitespaces from the given string.\n\n Args:\n input_string (str): The string from which whitespaces need to be removed.\n\n Returns:\n str: The string with all whitespaces removed.\n \"\"\"\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string):\n \"\"\"\n Removes all whitespaces from the given string.\n \n Args:\n input_string (str): The string from which whitespaces need to be removed.\n \n Returns:\n str: The string with all whitespaces removed.\n \"\"\"\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string):\n \"\"\"\n Removes all whitespaces from the given string.\n \n Args:\n input_string (str): The string from which whitespaces need to be removed.\n \n Returns:\n str: The input string with all whitespaces removed.\n \"\"\"\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string):\n \"\"\"\n Remove all whitespaces from the given string.\n\n Args:\n input_string (str): The string from which whitespaces need to be removed.\n\n Returns:\n str: The string with all whitespaces removed.\n \"\"\"\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string):\n \"\"\"\n Remove all whitespaces from the given string.\n\n Args:\n input_string (str): The input string from which whitespaces need to be removed.\n\n Returns:\n str: The input string with all whitespaces removed.\n \"\"\"\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string):\n \"\"\"\n Remove all whitespaces from the given string.\n\n Args:\n input_string (str): The input string from which whitespaces need to be removed.\n\n Returns:\n str: The input string with all whitespaces removed.\n \"\"\"\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string):\n \"\"\"\n Removes all whitespaces from the given string.\n\n Args:\n input_string (str): The string from which whitespaces need to be removed.\n\n Returns:\n str: The string with all whitespaces removed.\n \"\"\"\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string):\n \"\"\"\n Remove all whitespaces from the given string.\n\n Args:\n input_string (str): The input string from which whitespaces need to be removed.\n\n Returns:\n str: The input string with all whitespaces removed.\n \"\"\"\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string):\n \"\"\"\n Removes all whitespaces from the given string.\n\n Args:\n input_string (str): The input string from which whitespaces need to be removed.\n\n Returns:\n str: The input string with all whitespaces removed.\n \"\"\"\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string):\n \"\"\"\n Removes all whitespaces from the given string.\n \n Args:\n input_string (str): The string from which whitespaces need to be removed.\n \n Returns:\n str: The string with all whitespaces removed.\n \"\"\"\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string):\n \"\"\"\n Removes all whitespaces from the given string.\n\n Args:\n input_string (str): The string from which whitespaces need to be removed.\n\n Returns:\n str: The string with all whitespaces removed.\n \"\"\"\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string):\n \"\"\"\n Removes all whitespaces from the given string.\n \n Args:\n input_string (str): The string from which whitespaces need to be removed.\n \n Returns:\n str: The string with all whitespaces removed.\n \"\"\"\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string):\n \"\"\"\n Removes all whitespaces from the given string.\n \n Args:\n input_string (str): The string from which whitespaces need to be removed.\n \n Returns:\n str: The string with all whitespaces removed.\n \"\"\"\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string):\n \"\"\"\n Removes all whitespaces from the given string.\n \n Args:\n input_string (str): The string from which whitespaces need to be removed.\n \n Returns:\n str: The string with all whitespaces removed.\n \"\"\"\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}]}, "Mbpp/456": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def reverse_string_list(string_list):\n return [s[::-1] for s in string_list]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n return [s[::-1] for s in string_list]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n # Use a list comprehension to reverse each string in the list\n reversed_list = [s[::-1] for s in string_list]\n return reversed_list", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n # Use a list comprehension to reverse each string in the list\n reversed_list = [s[::-1] for s in string_list]\n return reversed_list", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n return [s[::-1] for s in string_list]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n \"\"\"\n Reverses each string in the given list of string values.\n \n Args:\n string_list (list): A list of string values.\n \n Returns:\n list: A list of reversed string values.\n \"\"\"\n return [s[::-1] for s in string_list]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n return [s[::-1] for s in string_list]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n return [s[::-1] for s in string_list]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n return [s[::-1] for s in string_list]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n return [s[::-1] for s in string_list]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n return [s[::-1] for s in string_list]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n return [s[::-1] for s in string_list]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n return [s[::-1] for s in string_list]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n return [s[::-1] for s in string_list]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n return [s[::-1] for s in string_list]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n return [s[::-1] for s in string_list]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n # Use a list comprehension to reverse each string in the list\n reversed_list = [s[::-1] for s in string_list]\n return reversed_list", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n return [s[::-1] for s in string_list]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n # Use a list comprehension to reverse each string in the list\n reversed_list = [s[::-1] for s in string_list]\n return reversed_list", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n # Use a list comprehension to reverse each string in the list\n reversed_list = [s[::-1] for s in string_list]\n return reversed_list", "matching_cluster_idx": 4}]}, "Mbpp/460": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def Extract(lst):\n return [sublist[0] for sublist in lst]", "matching_cluster_idx": 4}, {"solution": "def Extract(lst):\n return [sublist[0] for sublist in lst]", "matching_cluster_idx": 4}, {"solution": "def Extract(lst):\n return [sublist[0] for sublist in lst]", "matching_cluster_idx": 4}, {"solution": "def Extract(lst):\n return [sublist[0] for sublist in lst]", "matching_cluster_idx": 4}, {"solution": "def Extract(lst):\n return [sublist[0] for sublist in lst]", "matching_cluster_idx": 4}, {"solution": "def Extract(lst):\n return [sublist[0] for sublist in lst]", "matching_cluster_idx": 4}, {"solution": "def Extract(lst):\n return [sublist[0] for sublist in lst]", "matching_cluster_idx": 4}, {"solution": "def Extract(lst):\n return [sublist[0] for sublist in lst]", "matching_cluster_idx": 4}, {"solution": "def Extract(lst):\n return [sublist[0] for sublist in lst]", "matching_cluster_idx": 4}, {"solution": "def Extract(lst):\n return [sublist[0] for sublist in lst]", "matching_cluster_idx": 4}, {"solution": "def Extract(lst):\n return [sublist[0] for sublist in lst]", "matching_cluster_idx": 4}, {"solution": "def Extract(lst):\n return [sublist[0] for sublist in lst]", "matching_cluster_idx": 4}, {"solution": "def Extract(lst):\n return [sublist[0] for sublist in lst]", "matching_cluster_idx": 4}, {"solution": "def Extract(lst):\n return [sublist[0] for sublist in lst]", "matching_cluster_idx": 4}, {"solution": "def Extract(lst):\n return [sublist[0] for sublist in lst]", "matching_cluster_idx": 4}, {"solution": "def Extract(lst):\n return [sublist[0] for sublist in lst]", "matching_cluster_idx": 4}, {"solution": "def Extract(lst):\n return [sublist[0] for sublist in lst]", "matching_cluster_idx": 4}, {"solution": "def Extract(lst):\n return [sublist[0] for sublist in lst]", "matching_cluster_idx": 4}, {"solution": "def Extract(lst):\n return [sublist[0] for sublist in lst]", "matching_cluster_idx": 4}, {"solution": "def Extract(lst):\n return [sublist[0] for sublist in lst]", "matching_cluster_idx": 4}]}, "Mbpp/474": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def replace_char(input_string, old_char, new_char):\n \"\"\"\n Replace all occurrences of old_char with new_char in the input_string.\n \n :param input_string: The original string.\n :param old_char: The character to be replaced.\n :param new_char: The character to replace old_char with.\n :return: The modified string.\n \"\"\"\n return input_string.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(input_string, old_char, new_char):\n \"\"\"\n Replace all occurrences of old_char with new_char in the input_string.\n \n :param input_string: The original string.\n :param old_char: The character to be replaced.\n :param new_char: The character to replace with.\n :return: A new string with the replacements made.\n \"\"\"\n return input_string.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(input_string, old_char, new_char):\n \"\"\"\n Replace all occurrences of old_char with new_char in the input_string.\n \n :param input_string: The original string.\n :param old_char: The character to be replaced.\n :param new_char: The character to replace with.\n :return: The modified string with replacements.\n \"\"\"\n return input_string.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(input_string, old_char, new_char):\n \"\"\"\n Replace all occurrences of old_char with new_char in the input_string.\n \n :param input_string: The original string.\n :param old_char: The character to be replaced.\n :param new_char: The character to replace with.\n :return: The modified string.\n \"\"\"\n return input_string.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(input_string, old_char, new_char):\n \"\"\"\n Replace all occurrences of old_char with new_char in the input_string.\n \n :param input_string: The original string.\n :param old_char: The character to be replaced.\n :param new_char: The character to replace with.\n :return: A new string with the replacements made.\n \"\"\"\n return input_string.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, old_char, new_char):\n \"\"\"\n Replace all occurrences of `old_char` with `new_char` in the string `s`.\n\n :param s: The input string.\n :param old_char: The character to be replaced.\n :param new_char: The character to replace with.\n :return: The modified string.\n \"\"\"\n return s.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(input_string, old_char, new_char):\n \"\"\"\n Replace all occurrences of old_char with new_char in the input_string.\n \n :param input_string: The original string.\n :param old_char: The character to be replaced.\n :param new_char: The character to replace with.\n :return: A new string with the replacements made.\n \"\"\"\n return input_string.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, old_char, new_char):\n \"\"\"\n Replace all occurrences of old_char with new_char in the string s.\n \n :param s: The input string.\n :param old_char: The character to be replaced.\n :param new_char: The character to replace with.\n :return: The modified string.\n \"\"\"\n return s.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(input_string, old_char, new_char):\n \"\"\"\n Replace all occurrences of old_char with new_char in the input_string.\n \n :param input_string: The original string.\n :param old_char: The character to be replaced.\n :param new_char: The character to replace with.\n :return: The modified string with replacements.\n \"\"\"\n return input_string.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(input_string, old_char, new_char):\n \"\"\"\n Replace all occurrences of old_char with new_char in the input_string.\n \n :param input_string: The original string.\n :param old_char: The character to be replaced.\n :param new_char: The character to replace with.\n :return: A new string with the replacements made.\n \"\"\"\n return input_string.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(input_string, old_char, new_char):\n \"\"\"\n Replace all occurrences of old_char with new_char in the input_string.\n \n :param input_string: The original string.\n :param old_char: The character to be replaced.\n :param new_char: The character to replace with.\n :return: The modified string with replacements.\n \"\"\"\n return input_string.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(input_string, old_char, new_char):\n \"\"\"\n Replace all occurrences of old_char with new_char in the input_string.\n \n :param input_string: The original string.\n :param old_char: The character to be replaced.\n :param new_char: The character to replace with.\n :return: The modified string.\n \"\"\"\n return input_string.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(input_string, old_char, new_char):\n \"\"\"\n Replace all occurrences of old_char with new_char in the input_string.\n \n :param input_string: The original string.\n :param old_char: The character to be replaced.\n :param new_char: The character to replace with.\n :return: A new string with the replacements made.\n \"\"\"\n return input_string.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(input_string, old_char, new_char):\n \"\"\"\n Replace all occurrences of old_char with new_char in the input_string.\n \n :param input_string: The original string.\n :param old_char: The character to be replaced.\n :param new_char: The character to replace with.\n :return: The modified string.\n \"\"\"\n return input_string.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(input_string, old_char, new_char):\n \"\"\"\n Replace all occurrences of old_char with new_char in the input_string.\n \n :param input_string: The original string.\n :param old_char: The character to be replaced.\n :param new_char: The character to replace with.\n :return: A new string with the replacements made.\n \"\"\"\n return input_string.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(input_string, old_char, new_char):\n \"\"\"\n Replace all occurrences of old_char with new_char in the input_string.\n \n :param input_string: The original string.\n :param old_char: The character to be replaced.\n :param new_char: The character to replace with.\n :return: The modified string with replacements.\n \"\"\"\n return input_string.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, old_char, new_char):\n \"\"\"\n Replace all occurrences of `old_char` with `new_char` in the string `s`.\n \n :param s: The input string.\n :param old_char: The character to be replaced.\n :param new_char: The character to replace `old_char` with.\n :return: The modified string.\n \"\"\"\n return s.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s: str, old_char: str, new_char: str) -> str:\n \"\"\"\n Replace all occurrences of `old_char` with `new_char` in the string `s`.\n \n :param s: The input string.\n :param old_char: The character to be replaced.\n :param new_char: The character to replace `old_char` with.\n :return: The modified string.\n \"\"\"\n return s.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(input_string, old_char, new_char):\n \"\"\"\n Replace all occurrences of old_char with new_char in the input_string.\n \n :param input_string: The original string.\n :param old_char: The character to be replaced.\n :param new_char: The character to replace with.\n :return: A new string with the replacements made.\n \"\"\"\n return input_string.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(input_string, old_char, new_char):\n \"\"\"\n Replace all occurrences of old_char with new_char in the input_string.\n \n :param input_string: The original string.\n :param old_char: The character to be replaced.\n :param new_char: The character to replace with.\n :return: A new string with the replacements.\n \"\"\"\n return input_string.replace(old_char, new_char)", "matching_cluster_idx": 6}]}, "Mbpp/476": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def big_sum(arr):\n \"\"\"\n Function to find the sum of the largest and smallest value in a given array.\n \n Parameters:\n arr (list): A list of integers.\n \n Returns:\n int: The sum of the largest and smallest values in the array.\n \"\"\"\n if not arr:\n raise ValueError(\"The input array must not be empty\")\n \n smallest = min(arr)\n largest = max(arr)\n \n return smallest + largest", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n \"\"\"\n Function to find the sum of the largest and smallest value in a given array.\n \n Parameters:\n arr (list): A list of integers.\n \n Returns:\n int: The sum of the largest and smallest value in the array.\n \"\"\"\n if not arr:\n raise ValueError(\"The array must not be empty\")\n \n smallest = min(arr)\n largest = max(arr)\n \n return smallest + largest", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n \"\"\"\n Function to find the sum of the largest and smallest value in a given array.\n \n Parameters:\n arr (list): A list of integers.\n \n Returns:\n int: The sum of the largest and smallest value in the array.\n \"\"\"\n if not arr:\n raise ValueError(\"The input array must not be empty.\")\n \n smallest = min(arr)\n largest = max(arr)\n \n return smallest + largest", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n \"\"\"\n Function to find the sum of the largest and smallest value in a given array.\n \n Parameters:\n arr (list): A list of integers.\n \n Returns:\n int: The sum of the largest and smallest values in the array.\n \"\"\"\n if not arr:\n raise ValueError(\"The array must not be empty\")\n \n smallest = min(arr)\n largest = max(arr)\n \n return smallest + largest", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n \"\"\"\n Function to find the sum of the largest and smallest value in a given array.\n \n Parameters:\n arr (list): A list of integers.\n \n Returns:\n int: The sum of the largest and smallest value in the array.\n \"\"\"\n if not arr:\n raise ValueError(\"The array must not be empty\")\n \n smallest = min(arr)\n largest = max(arr)\n \n return smallest + largest", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n if not arr:\n return 0\n return max(arr) + min(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n \"\"\"\n Find the sum of the largest and smallest value in a given array.\n \n Parameters:\n arr (list): A list of integers.\n \n Returns:\n int: The sum of the largest and smallest value in the array.\n \"\"\"\n if not arr:\n raise ValueError(\"The input array must not be empty.\")\n \n smallest = min(arr)\n largest = max(arr)\n \n return smallest + largest", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n \"\"\"\n Function to find the sum of the largest and smallest value in a given array.\n \n Parameters:\n arr (list): A list of integers.\n \n Returns:\n int: The sum of the largest and smallest value in the array.\n \"\"\"\n if not arr:\n raise ValueError(\"The array must not be empty\")\n \n smallest = min(arr)\n largest = max(arr)\n \n return smallest + largest", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n \"\"\"\n Find the sum of the largest and smallest value in a given array.\n \n Args:\n arr (list): A list of integers.\n \n Returns:\n int: The sum of the largest and smallest value in the array.\n \"\"\"\n if not arr:\n raise ValueError(\"The input array must not be empty.\")\n \n smallest = min(arr)\n largest = max(arr)\n \n return smallest + largest", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n \"\"\"\n Find the sum of the largest and smallest value in a given array.\n \n :param arr: List of integers\n :return: Sum of the largest and smallest value in the array\n \"\"\"\n if not arr:\n raise ValueError(\"The array must not be empty\")\n \n smallest = min(arr)\n largest = max(arr)\n \n return smallest + largest", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n if not arr:\n raise ValueError(\"Array is empty\")\n \n smallest = min(arr)\n largest = max(arr)\n \n return smallest + largest", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n \"\"\"\n Find the sum of the largest and smallest value in a given array.\n \n Parameters:\n arr (list): A list of integers.\n \n Returns:\n int: The sum of the largest and smallest value in the array.\n \"\"\"\n if not arr:\n raise ValueError(\"The array must not be empty\")\n \n smallest = min(arr)\n largest = max(arr)\n \n return smallest + largest", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n \"\"\"\n Function to find the sum of the largest and smallest value in a given array.\n \n Args:\n arr (list): A list of integers.\n \n Returns:\n int: The sum of the largest and smallest value in the array.\n \"\"\"\n if not arr:\n raise ValueError(\"The input array must not be empty.\")\n \n smallest = min(arr)\n largest = max(arr)\n \n return smallest + largest", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n \"\"\"\n Function to find the sum of the largest and smallest value in a given array.\n \n Parameters:\n arr (list): A list of integers.\n \n Returns:\n int: The sum of the largest and smallest value in the array.\n \"\"\"\n if not arr:\n raise ValueError(\"The input array must not be empty.\")\n \n smallest = min(arr)\n largest = max(arr)\n \n return smallest + largest", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n \"\"\"\n Function to find the sum of the largest and smallest value in a given array.\n \n Parameters:\n arr (list): A list of integers.\n \n Returns:\n int: The sum of the largest and smallest value in the array.\n \"\"\"\n if not arr:\n raise ValueError(\"The input array must not be empty.\")\n \n smallest = min(arr)\n largest = max(arr)\n \n return smallest + largest", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n if not arr:\n return 0 # Return 0 if the array is empty\n smallest = min(arr)\n largest = max(arr)\n return smallest + largest", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n \"\"\"\n Function to find the sum of the largest and smallest value in a given array.\n \n Parameters:\n arr (list): A list of integers.\n \n Returns:\n int: The sum of the largest and smallest values in the array.\n \"\"\"\n if not arr:\n raise ValueError(\"The array must not be empty\")\n \n smallest = min(arr)\n largest = max(arr)\n \n return smallest + largest", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n \"\"\"\n Function to find the sum of the largest and smallest value in a given array.\n \n Parameters:\n arr (list): A list of integers.\n \n Returns:\n int: The sum of the largest and smallest value in the array.\n \"\"\"\n if not arr:\n raise ValueError(\"The input array must not be empty\")\n \n smallest = min(arr)\n largest = max(arr)\n \n return smallest + largest", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n \"\"\"\n Function to find the sum of the largest and smallest value in a given array.\n \n Parameters:\n arr (list): A list of integers.\n \n Returns:\n int: The sum of the largest and smallest values in the array.\n \"\"\"\n if not arr:\n raise ValueError(\"The array must not be empty\")\n \n smallest = min(arr)\n largest = max(arr)\n \n return smallest + largest", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n \"\"\"\n Find the sum of the largest and smallest value in a given array.\n \n Args:\n arr (list): A list of integers.\n \n Returns:\n int: The sum of the largest and smallest value in the array.\n \"\"\"\n if not arr:\n raise ValueError(\"The input array must not be empty.\")\n \n smallest = min(arr)\n largest = max(arr)\n \n return smallest + largest", "matching_cluster_idx": 5}]}, "Mbpp/477": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def is_lower(s: str) -> str:\n \"\"\"\n Convert the given string to lower case.\n\n Args:\n s (str): The input string.\n\n Returns:\n str: The input string converted to lower case.\n \"\"\"\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s: str) -> str:\n \"\"\"\n Convert the given string to lower case.\n\n Args:\n s (str): The input string.\n\n Returns:\n str: The input string converted to lower case.\n \"\"\"\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s: str) -> str:\n \"\"\"\n Convert the given string to lower case.\n\n Args:\n s (str): The input string.\n\n Returns:\n str: The input string converted to lower case.\n \"\"\"\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(input_string):\n \"\"\"\n Convert the given string to lower case.\n\n Args:\n input_string (str): The string to be converted to lower case.\n\n Returns:\n str: The input string in lower case.\n \"\"\"\n return input_string.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s: str) -> str:\n \"\"\"\n Convert the given string to lower case.\n\n Parameters:\n s (str): The input string to be converted.\n\n Returns:\n str: The input string converted to lower case.\n \"\"\"\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s: str) -> str:\n \"\"\"\n Convert the given string to lower case.\n\n Args:\n s (str): The input string.\n\n Returns:\n str: The input string converted to lower case.\n \"\"\"\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(input_string):\n \"\"\"\n Convert the given string to lower case.\n\n Parameters:\n input_string (str): The string to be converted to lower case.\n\n Returns:\n str: The input string converted to lower case.\n \"\"\"\n return input_string.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s: str) -> str:\n \"\"\"\n Convert the given string to lower case.\n\n Parameters:\n s (str): The input string to be converted.\n\n Returns:\n str: The input string converted to lower case.\n \"\"\"\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(input_string):\n \"\"\"\n Converts the given string to lower case.\n\n Parameters:\n input_string (str): The string to be converted to lower case.\n\n Returns:\n str: The input string in lower case.\n \"\"\"\n return input_string.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s: str) -> str:\n \"\"\"\n Convert the given string to lower case.\n\n Args:\n s (str): The input string.\n\n Returns:\n str: The input string converted to lower case.\n \"\"\"\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s: str) -> str:\n \"\"\"\n Convert the given string to lower case.\n\n Args:\n s (str): The input string.\n\n Returns:\n str: The input string converted to lower case.\n \"\"\"\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(input_string):\n \"\"\"\n Convert the given string to lower case.\n\n Parameters:\n input_string (str): The string to be converted to lower case.\n\n Returns:\n str: The input string converted to lower case.\n \"\"\"\n return input_string.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n \"\"\"\n Convert the given string to lower case.\n\n Args:\n s (str): The input string.\n\n Returns:\n str: The input string converted to lower case.\n \"\"\"\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n \"\"\"\n Convert the given string to lower case.\n\n Args:\n s (str): The input string.\n\n Returns:\n str: The input string converted to lower case.\n \"\"\"\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(input_string):\n \"\"\"\n Converts the given string to lower case.\n\n Args:\n input_string (str): The string to be converted to lower case.\n\n Returns:\n str: The input string in lower case.\n \"\"\"\n return input_string.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s: str) -> str:\n \"\"\"\n Convert the given string to lower case.\n\n Args:\n s (str): The input string.\n\n Returns:\n str: The input string converted to lower case.\n \"\"\"\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(input_string):\n \"\"\"\n Converts the given string to lower case.\n\n Parameters:\n input_string (str): The string to be converted.\n\n Returns:\n str: The string converted to lower case.\n \"\"\"\n return input_string.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s: str) -> str:\n \"\"\"\n Convert the given string to lower case.\n\n Args:\n s (str): The input string.\n\n Returns:\n str: The input string converted to lower case.\n \"\"\"\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s: str) -> str:\n \"\"\"\n Convert the given string to lower case.\n\n Args:\n s (str): The input string.\n\n Returns:\n str: The input string converted to lower case.\n \"\"\"\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n \"\"\"\n Convert the given string to lower case.\n\n Args:\n s (str): The input string.\n\n Returns:\n str: The input string converted to lower case.\n \"\"\"\n return s.lower()", "matching_cluster_idx": 4}]}, "Mbpp/563": {"dps": 85.24590163934427, "dps_norm": 81.81818181818181, "pass@1": 100.0, "profiled": [{"solution": "def extract_values(input_string):\n import re\n # Use regex to find all values between quotation marks\n values = re.findall(r'\"([^\"]*)\"', input_string)\n return values", "matching_cluster_idx": 8}, {"solution": "def extract_values(input_string):\n import re\n # Use regular expression to find all values between quotation marks\n values = re.findall(r'\"([^\"]*)\"', input_string)\n return values", "matching_cluster_idx": 8}, {"solution": "def extract_values(input_string):\n import re\n # Use regular expression to find all values between quotation marks\n values = re.findall(r'\"([^\"]*)\"', input_string)\n return values", "matching_cluster_idx": 8}, {"solution": "def extract_values(s):\n import re\n # Use regex to find all values between quotation marks\n values = re.findall(r'\"(.*?)\"', s)\n return values", "matching_cluster_idx": 8}, {"solution": "def extract_values(input_string):\n import re\n # Use regular expression to find all values between quotation marks\n values = re.findall(r'\"([^\"]*)\"', input_string)\n return values", "matching_cluster_idx": 8}, {"solution": "def extract_values(input_string):\n import re\n # Use regular expression to find all values between quotation marks\n values = re.findall(r'\"([^\"]*)\"', input_string)\n return values", "matching_cluster_idx": 8}, {"solution": "def extract_values(input_string):\n import re\n # Use regular expression to find all values between quotation marks\n values = re.findall(r'\"([^\"]*)\"', input_string)\n return values", "matching_cluster_idx": 8}, {"solution": "def extract_values(input_string):\n import re\n # Use regex to find all values between quotation marks\n values = re.findall(r'\"([^\"]*)\"', input_string)\n return values", "matching_cluster_idx": 8}, {"solution": "def extract_values(input_string):\n import re\n # Use regular expression to find all values between quotation marks\n values = re.findall(r'\"([^\"]*)\"', input_string)\n return values", "matching_cluster_idx": 8}, {"solution": "def extract_values(input_string):\n import re\n # Use regular expression to find all values between quotation marks\n values = re.findall(r'\"([^\"]*)\"', input_string)\n return values", "matching_cluster_idx": 8}, {"solution": "def extract_values(input_string):\n import re\n # Use regex to find all values between quotation marks\n values = re.findall(r'\"([^\"]*)\"', input_string)\n return values", "matching_cluster_idx": 8}, {"solution": "def extract_values(input_string):\n import re\n # Use regex to find all values between quotation marks\n values = re.findall(r'\"([^\"]*)\"', input_string)\n return values", "matching_cluster_idx": 8}, {"solution": "def extract_values(input_string):\n import re\n # Use regex to find all values between quotation marks\n values = re.findall(r'\"([^\"]*)\"', input_string)\n return values", "matching_cluster_idx": 8}, {"solution": "def extract_values(input_string):\n import re\n # Use regular expression to find all values between quotation marks\n values = re.findall(r'\"([^\"]*)\"', input_string)\n return values", "matching_cluster_idx": 8}, {"solution": "def extract_values(input_string):\n import re\n # Use regular expression to find all values between quotation marks\n values = re.findall(r'\"([^\"]*)\"', input_string)\n return values", "matching_cluster_idx": 8}, {"solution": "def extract_values(input_string):\n import re\n # Use regular expression to find all values between quotation marks\n values = re.findall(r'\"([^\"]*)\"', input_string)\n return values", "matching_cluster_idx": 8}, {"solution": "def extract_values(input_string):\n import re\n # Use regular expression to find all values between quotation marks\n values = re.findall(r'\"([^\"]*)\"', input_string)\n return values", "matching_cluster_idx": 8}, {"solution": "def extract_values(input_string):\n import re\n # Use regex to find all values between quotation marks\n values = re.findall(r'\"([^\"]*)\"', input_string)\n return values", "matching_cluster_idx": 8}, {"solution": "def extract_values(input_string):\n import re\n # Use regular expression to find all values between quotation marks\n values = re.findall(r'\"([^\"]*)\"', input_string)\n return values", "matching_cluster_idx": 8}, {"solution": "def extract_values(input_string):\n import re\n # Use regular expression to find all values between quotation marks\n values = re.findall(r'\"([^\"]*)\"', input_string)\n return values", "matching_cluster_idx": 8}]}, "Mbpp/572": {"dps": 95.06172839506173, "dps_norm": 85.71428571428571, "pass@1": 84.0, "profiled": [{"solution": "def two_unique_nums(nums):\n # Create a dictionary to count occurrences of each number\n count_dict = {}\n for num in nums:\n if num in count_dict:\n count_dict[num] += 1\n else:\n count_dict[num] = 1\n \n # Filter out numbers that appear more than once\n unique_nums = [num for num in count_dict if count_dict[num] == 1]\n \n return unique_nums", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(nums):\n # Create a dictionary to count occurrences of each number\n count_dict = {}\n \n for num in nums:\n if num in count_dict:\n count_dict[num] += 1\n else:\n count_dict[num] = 1\n \n # Filter out numbers that appear more than once\n unique_nums = [num for num in count_dict if count_dict[num] == 1]\n \n return unique_nums", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(nums):\n # Create a dictionary to count occurrences of each number\n count_dict = {}\n for num in nums:\n if num in count_dict:\n count_dict[num] += 1\n else:\n count_dict[num] = 1\n \n # Filter out numbers that appear more than once\n unique_nums = [num for num in count_dict if count_dict[num] == 1]\n \n return unique_nums", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(nums):\n # Create a dictionary to count occurrences of each number\n count_dict = {}\n for num in nums:\n if num in count_dict:\n count_dict[num] += 1\n else:\n count_dict[num] = 1\n \n # Filter out numbers that appear more than once\n unique_nums = [num for num in count_dict if count_dict[num] == 1]\n \n return unique_nums", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(nums):\n # Create a dictionary to count occurrences of each number\n count_dict = {}\n for num in nums:\n if num in count_dict:\n count_dict[num] += 1\n else:\n count_dict[num] = 1\n \n # Filter out numbers that appear more than once\n unique_nums = [num for num in count_dict if count_dict[num] == 1]\n \n return unique_nums", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(nums):\n # Create a dictionary to count occurrences of each number\n count_dict = {}\n for num in nums:\n if num in count_dict:\n count_dict[num] += 1\n else:\n count_dict[num] = 1\n \n # Filter out numbers that appear more than once\n unique_nums = [num for num in count_dict if count_dict[num] == 1]\n \n return unique_nums", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(nums):\n # Create a dictionary to count occurrences of each number\n count_dict = {}\n \n # Count each number in the list\n for num in nums:\n if num in count_dict:\n count_dict[num] += 1\n else:\n count_dict[num] = 1\n \n # Filter out numbers that appear more than once\n unique_nums = [num for num in count_dict if count_dict[num] == 1]\n \n return unique_nums", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(nums):\n # Create a dictionary to count occurrences of each number\n count_dict = {}\n for num in nums:\n if num in count_dict:\n count_dict[num] += 1\n else:\n count_dict[num] = 1\n \n # Filter out numbers that appear more than once\n unique_nums = [num for num in count_dict if count_dict[num] == 1]\n \n return unique_nums", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(nums):\n # Create a dictionary to count occurrences of each number\n count_dict = {}\n for num in nums:\n if num in count_dict:\n count_dict[num] += 1\n else:\n count_dict[num] = 1\n \n # Filter out numbers that appear more than once\n unique_nums = [num for num in count_dict if count_dict[num] == 1]\n \n return unique_nums", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(nums):\n # Create a dictionary to count occurrences of each number\n count_dict = {}\n for num in nums:\n if num in count_dict:\n count_dict[num] += 1\n else:\n count_dict[num] = 1\n \n # Filter out numbers that appear more than once\n unique_nums = [num for num in count_dict if count_dict[num] == 1]\n \n return unique_nums", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(nums):\n # Create a dictionary to count occurrences of each number\n count_dict = {}\n for num in nums:\n if num in count_dict:\n count_dict[num] += 1\n else:\n count_dict[num] = 1\n \n # Filter out numbers that appear more than once\n unique_nums = [num for num in count_dict if count_dict[num] == 1]\n \n return unique_nums", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(nums):\n # Create a dictionary to count occurrences of each number\n count_dict = {}\n for num in nums:\n if num in count_dict:\n count_dict[num] += 1\n else:\n count_dict[num] = 1\n \n # Filter out numbers that appear more than once\n unique_nums = [num for num in count_dict if count_dict[num] == 1]\n \n return unique_nums", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(nums):\n # Create a dictionary to count occurrences of each number\n count_dict = {}\n \n # Count the occurrences of each number\n for num in nums:\n if num in count_dict:\n count_dict[num] += 1\n else:\n count_dict[num] = 1\n \n # Filter out numbers that appear more than once\n unique_nums = [num for num in count_dict if count_dict[num] == 1]\n \n return unique_nums", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(nums):\n # Create a dictionary to count occurrences of each number\n count_dict = {}\n for num in nums:\n if num in count_dict:\n count_dict[num] += 1\n else:\n count_dict[num] = 1\n \n # Filter out numbers that appear more than once\n unique_nums = [num for num in count_dict if count_dict[num] == 1]\n \n return unique_nums", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(nums):\n # Create a dictionary to count occurrences of each number\n count_dict = {}\n \n for num in nums:\n if num in count_dict:\n count_dict[num] += 1\n else:\n count_dict[num] = 1\n \n # Filter out numbers that appear more than once\n unique_nums = [num for num in count_dict if count_dict[num] == 1]\n \n return unique_nums", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(nums):\n # Create a dictionary to count occurrences of each number\n count_dict = {}\n for num in nums:\n if num in count_dict:\n count_dict[num] += 1\n else:\n count_dict[num] = 1\n \n # Filter out numbers that appear more than once\n unique_nums = [num for num in count_dict if count_dict[num] == 1]\n \n return unique_nums", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(nums):\n # Create a dictionary to count occurrences of each number\n count_dict = {}\n for num in nums:\n if num in count_dict:\n count_dict[num] += 1\n else:\n count_dict[num] = 1\n \n # Filter out numbers that appear more than once\n unique_nums = [num for num in count_dict if count_dict[num] == 1]\n \n return unique_nums", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(nums):\n # Create a dictionary to count occurrences of each number\n count_dict = {}\n for num in nums:\n if num in count_dict:\n count_dict[num] += 1\n else:\n count_dict[num] = 1\n \n # Filter out numbers that appear more than once\n unique_nums = [num for num in count_dict if count_dict[num] == 1]\n \n return unique_nums", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(nums):\n # Create a dictionary to count occurrences of each number\n count_dict = {}\n for num in nums:\n if num in count_dict:\n count_dict[num] += 1\n else:\n count_dict[num] = 1\n \n # Filter out numbers that appear more than once\n unique_nums = [num for num in count_dict if count_dict[num] == 1]\n \n return unique_nums", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(nums):\n # Create a dictionary to count occurrences of each number\n count_dict = {}\n for num in nums:\n if num in count_dict:\n count_dict[num] += 1\n else:\n count_dict[num] = 1\n \n # Filter out numbers that appear more than once\n unique_nums = [num for num in nums if count_dict[num] == 1]\n \n return unique_nums", "matching_cluster_idx": 5}]}, "Mbpp/578": {"dps": 62.25396825396825, "dps_norm": 64.54545454545455, "pass@1": 100.0, "profiled": [{"solution": "def interleave_lists(list1, list2, list3):\n # Ensure all lists are of the same length\n if len(list1) != len(list2) or len(list2) != len(list3):\n raise ValueError(\"All lists must be of the same length\")\n \n # Interleave the lists\n interleaved_list = []\n for i in range(len(list1)):\n interleaved_list.append(list1[i])\n interleaved_list.append(list2[i])\n interleaved_list.append(list3[i])\n \n return interleaved_list", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n # Ensure all lists are of the same length\n if len(list1) != len(list2) or len(list2) != len(list3):\n raise ValueError(\"All lists must be of the same length\")\n \n # Interleave the lists\n interleaved_list = []\n for i in range(len(list1)):\n interleaved_list.append(list1[i])\n interleaved_list.append(list2[i])\n interleaved_list.append(list3[i])\n \n return interleaved_list", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n # Ensure all lists are of the same length\n if len(list1) != len(list2) or len(list2) != len(list3):\n raise ValueError(\"All lists must be of the same length\")\n \n # Interleave the lists\n interleaved_list = []\n for i in range(len(list1)):\n interleaved_list.append(list1[i])\n interleaved_list.append(list2[i])\n interleaved_list.append(list3[i])\n \n return interleaved_list", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n # Ensure all lists are of the same length\n if len(list1) != len(list2) or len(list2) != len(list3):\n raise ValueError(\"All lists must be of the same length\")\n \n # Interleave the lists\n interleaved_list = []\n for i in range(len(list1)):\n interleaved_list.append(list1[i])\n interleaved_list.append(list2[i])\n interleaved_list.append(list3[i])\n \n return interleaved_list", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"\n Interleave 3 lists of the same length into a single flat list.\n \n Args:\n list1 (list): The first list.\n list2 (list): The second list.\n list3 (list): The third list.\n \n Returns:\n list: A single flat list containing elements from the input lists interleaved.\n \"\"\"\n interleaved_list = []\n for a, b, c in zip(list1, list2, list3):\n interleaved_list.extend([a, b, c])\n return interleaved_list", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(list1, list2, list3):\n # Ensure all lists are of the same length\n if len(list1) != len(list2) or len(list2) != len(list3):\n raise ValueError(\"All lists must be of the same length\")\n \n # Interleave the lists\n interleaved_list = []\n for i in range(len(list1)):\n interleaved_list.append(list1[i])\n interleaved_list.append(list2[i])\n interleaved_list.append(list3[i])\n \n return interleaved_list", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n # Ensure all lists are of the same length\n if len(list1) != len(list2) or len(list2) != len(list3):\n raise ValueError(\"All lists must be of the same length\")\n \n # Interleave the lists\n interleaved_list = []\n for i in range(len(list1)):\n interleaved_list.append(list1[i])\n interleaved_list.append(list2[i])\n interleaved_list.append(list3[i])\n \n return interleaved_list", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"\n Interleave 3 lists of the same length into a single flat list.\n \n Args:\n list1 (list): The first list.\n list2 (list): The second list.\n list3 (list): The third list.\n \n Returns:\n list: A single flat list containing elements from list1, list2, and list3 interleaved.\n \"\"\"\n interleaved_list = []\n for a, b, c in zip(list1, list2, list3):\n interleaved_list.extend([a, b, c])\n return interleaved_list", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(list1, list2, list3):\n # Ensure all lists are of the same length\n if len(list1) != len(list2) or len(list2) != len(list3):\n raise ValueError(\"All lists must be of the same length\")\n \n # Interleave the lists\n interleaved_list = []\n for i in range(len(list1)):\n interleaved_list.append(list1[i])\n interleaved_list.append(list2[i])\n interleaved_list.append(list3[i])\n \n return interleaved_list", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n # Ensure all lists are of the same length\n if len(list1) != len(list2) or len(list2) != len(list3):\n raise ValueError(\"All lists must be of the same length\")\n \n # Interleave the lists\n interleaved_list = []\n for i in range(len(list1)):\n interleaved_list.append(list1[i])\n interleaved_list.append(list2[i])\n interleaved_list.append(list3[i])\n \n return interleaved_list", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n # Ensure all lists are of the same length\n if len(list1) != len(list2) or len(list2) != len(list3):\n raise ValueError(\"All lists must be of the same length\")\n \n # Interleave the lists\n interleaved_list = []\n for i in range(len(list1)):\n interleaved_list.append(list1[i])\n interleaved_list.append(list2[i])\n interleaved_list.append(list3[i])\n \n return interleaved_list", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n # Ensure all lists are of the same length\n if len(list1) != len(list2) or len(list2) != len(list3):\n raise ValueError(\"All lists must be of the same length\")\n \n # Interleave the lists\n interleaved_list = []\n for i in range(len(list1)):\n interleaved_list.append(list1[i])\n interleaved_list.append(list2[i])\n interleaved_list.append(list3[i])\n \n return interleaved_list", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n # Ensure all lists are of the same length\n if len(list1) != len(list2) or len(list2) != len(list3):\n raise ValueError(\"All lists must be of the same length\")\n \n # Interleave the lists\n interleaved_list = []\n for i in range(len(list1)):\n interleaved_list.append(list1[i])\n interleaved_list.append(list2[i])\n interleaved_list.append(list3[i])\n \n return interleaved_list", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n # Ensure all lists are of the same length\n if len(list1) != len(list2) or len(list2) != len(list3):\n raise ValueError(\"All lists must be of the same length\")\n \n # Interleave the lists\n interleaved_list = []\n for i in range(len(list1)):\n interleaved_list.append(list1[i])\n interleaved_list.append(list2[i])\n interleaved_list.append(list3[i])\n \n return interleaved_list", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n # Ensure all lists are of the same length\n if len(list1) != len(list2) or len(list2) != len(list3):\n raise ValueError(\"All lists must be of the same length\")\n \n # Interleave the lists\n interleaved_list = []\n for i in range(len(list1)):\n interleaved_list.append(list1[i])\n interleaved_list.append(list2[i])\n interleaved_list.append(list3[i])\n \n return interleaved_list", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n # Check if all lists are of the same length\n if len(list1) != len(list2) or len(list2) != len(list3):\n raise ValueError(\"All lists must be of the same length\")\n \n # Interleave the lists\n interleaved_list = []\n for i in range(len(list1)):\n interleaved_list.append(list1[i])\n interleaved_list.append(list2[i])\n interleaved_list.append(list3[i])\n \n return interleaved_list", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n # Ensure all lists are of the same length\n if len(list1) != len(list2) or len(list2) != len(list3):\n raise ValueError(\"All lists must be of the same length\")\n \n # Interleave the lists\n interleaved_list = []\n for i in range(len(list1)):\n interleaved_list.append(list1[i])\n interleaved_list.append(list2[i])\n interleaved_list.append(list3[i])\n \n return interleaved_list", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n # Ensure all lists are of the same length\n if len(list1) != len(list2) or len(list2) != len(list3):\n raise ValueError(\"All lists must be of the same length\")\n \n # Interleave the lists\n interleaved_list = []\n for i in range(len(list1)):\n interleaved_list.append(list1[i])\n interleaved_list.append(list2[i])\n interleaved_list.append(list3[i])\n \n return interleaved_list", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n # Ensure all lists are of the same length\n if len(list1) != len(list2) or len(list2) != len(list3):\n raise ValueError(\"All lists must be of the same length\")\n \n # Interleave the lists\n interleaved_list = []\n for i in range(len(list1)):\n interleaved_list.append(list1[i])\n interleaved_list.append(list2[i])\n interleaved_list.append(list3[i])\n \n return interleaved_list", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n # Ensure all lists are of the same length\n if len(list1) != len(list2) or len(list2) != len(list3):\n raise ValueError(\"All lists must be of the same length\")\n \n # Interleave the lists\n interleaved_list = []\n for i in range(len(list1)):\n interleaved_list.append(list1[i])\n interleaved_list.append(list2[i])\n interleaved_list.append(list3[i])\n \n return interleaved_list", "matching_cluster_idx": 6}]}, "Mbpp/586": {"dps": null, "dps_norm": null, "pass@1": 4.0, "profiled": []}, "Mbpp/587": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def list_tuple(lst):\n \"\"\"\n Convert a list to a tuple.\n\n Parameters:\n lst (list): The list to be converted.\n\n Returns:\n tuple: The tuple representation of the list.\n \"\"\"\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n \"\"\"\n Convert a list to a tuple.\n\n Args:\n lst (list): The list to be converted.\n\n Returns:\n tuple: The tuple representation of the list.\n \"\"\"\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n \"\"\"\n Convert a list to a tuple.\n \n Parameters:\n lst (list): The list to be converted.\n \n Returns:\n tuple: The tuple representation of the list.\n \"\"\"\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n \"\"\"\n Convert a list to a tuple.\n \n Parameters:\n lst (list): The list to be converted.\n \n Returns:\n tuple: The tuple representation of the list.\n \"\"\"\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n \"\"\"\n Convert a list to a tuple.\n \n Parameters:\n lst (list): The list to be converted.\n \n Returns:\n tuple: The tuple representation of the list.\n \"\"\"\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n \"\"\"\n Convert a list to a tuple.\n \n Parameters:\n lst (list): The list to be converted.\n \n Returns:\n tuple: The tuple representation of the list.\n \"\"\"\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n \"\"\"\n Convert a list to a tuple.\n \n Parameters:\n lst (list): The list to be converted.\n \n Returns:\n tuple: The tuple representation of the list.\n \"\"\"\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n \"\"\"\n Convert a list to a tuple.\n \n Parameters:\n lst (list): The list to be converted.\n \n Returns:\n tuple: The tuple representation of the list.\n \"\"\"\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n \"\"\"\n Convert a list to a tuple.\n \n Parameters:\n lst (list): The list to be converted.\n \n Returns:\n tuple: The tuple representation of the list.\n \"\"\"\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n \"\"\"\n Convert a list to a tuple.\n\n Parameters:\n lst (list): The list to be converted.\n\n Returns:\n tuple: The tuple representation of the list.\n \"\"\"\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n \"\"\"\n Convert a list to a tuple.\n\n Parameters:\n lst (list): The list to be converted.\n\n Returns:\n tuple: The tuple representation of the list.\n \"\"\"\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n \"\"\"\n Convert a list to a tuple.\n \n Parameters:\n lst (list): The list to be converted.\n \n Returns:\n tuple: The tuple representation of the list.\n \"\"\"\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n return tuple(lst)", "matching_cluster_idx": 3}]}, "Mbpp/588": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def big_diff(lst):\n if not lst:\n return 0 # Return 0 if the list is empty\n return max(lst) - min(lst)", "matching_cluster_idx": 5}, {"solution": "def big_diff(lst):\n if not lst:\n return 0 # Return 0 if the list is empty\n return max(lst) - min(lst)", "matching_cluster_idx": 5}, {"solution": "def big_diff(lst):\n \"\"\"\n Function to find the difference between the largest and smallest value in a given list.\n \n Parameters:\n lst (list): A list of integers.\n \n Returns:\n int: The difference between the largest and smallest values in the list.\n \"\"\"\n if not lst:\n return 0 # Return 0 if the list is empty\n \n return max(lst) - min(lst)", "matching_cluster_idx": 5}, {"solution": "def big_diff(lst):\n if not lst:\n return 0 # Return 0 if the list is empty\n return max(lst) - min(lst)", "matching_cluster_idx": 5}, {"solution": "def big_diff(lst):\n if not lst:\n return 0 # Return 0 if the list is empty\n return max(lst) - min(lst)", "matching_cluster_idx": 5}, {"solution": "def big_diff(lst):\n if not lst:\n return 0 # Return 0 if the list is empty\n return max(lst) - min(lst)", "matching_cluster_idx": 5}, {"solution": "def big_diff(lst):\n if not lst:\n return 0 # Return 0 if the list is empty\n return max(lst) - min(lst)", "matching_cluster_idx": 5}, {"solution": "def big_diff(lst):\n \"\"\"\n Function to find the difference between the largest and smallest value in a given list.\n \n Args:\n lst (list): A list of integers.\n \n Returns:\n int: The difference between the largest and smallest values in the list.\n \"\"\"\n if not lst:\n return 0 # Return 0 if the list is empty\n \n return max(lst) - min(lst)", "matching_cluster_idx": 5}, {"solution": "def big_diff(lst):\n if not lst:\n return 0 # Return 0 if the list is empty\n return max(lst) - min(lst)", "matching_cluster_idx": 5}, {"solution": "def big_diff(lst):\n \"\"\"\n Function to find the difference between the largest and smallest value in a given list.\n \n Args:\n lst (list): A list of integers.\n \n Returns:\n int: The difference between the largest and smallest value in the list.\n \"\"\"\n if not lst:\n return 0 # Return 0 if the list is empty\n \n return max(lst) - min(lst)", "matching_cluster_idx": 5}, {"solution": "def big_diff(lst):\n if not lst:\n return 0 # Return 0 if the list is empty\n return max(lst) - min(lst)", "matching_cluster_idx": 5}, {"solution": "def big_diff(lst):\n \"\"\"\n Function to find the difference between the largest and smallest value in a given list.\n \n Parameters:\n lst (list): A list of integers.\n \n Returns:\n int: The difference between the largest and smallest value in the list.\n \"\"\"\n if not lst:\n return 0 # Return 0 if the list is empty\n \n return max(lst) - min(lst)", "matching_cluster_idx": 5}, {"solution": "def big_diff(lst):\n if not lst:\n return 0 # Return 0 if the list is empty\n return max(lst) - min(lst)", "matching_cluster_idx": 5}, {"solution": "def big_diff(lst):\n \"\"\"\n Find the difference between the largest and smallest value in a given list.\n \n Args:\n lst (list): A list of numbers.\n \n Returns:\n int: The difference between the largest and smallest value in the list.\n \"\"\"\n if not lst:\n return 0 # Return 0 if the list is empty\n \n return max(lst) - min(lst)", "matching_cluster_idx": 5}, {"solution": "def big_diff(lst):\n if not lst:\n return 0 # Return 0 if the list is empty\n return max(lst) - min(lst)", "matching_cluster_idx": 5}, {"solution": "def big_diff(lst):\n if not lst:\n return 0 # Return 0 if the list is empty\n return max(lst) - min(lst)", "matching_cluster_idx": 5}, {"solution": "def big_diff(lst):\n \"\"\"\n Function to find the difference between the largest and smallest value in a given list.\n \n Parameters:\n lst (list): A list of integers.\n \n Returns:\n int: The difference between the largest and smallest value in the list.\n \"\"\"\n if not lst:\n return 0 # Return 0 if the list is empty\n \n return max(lst) - min(lst)", "matching_cluster_idx": 5}, {"solution": "def big_diff(lst):\n if not lst:\n return 0 # Return 0 if the list is empty\n return max(lst) - min(lst)", "matching_cluster_idx": 5}, {"solution": "def big_diff(lst):\n \"\"\"\n Function to find the difference between the largest and smallest value in a given list.\n \n Args:\n lst (list): A list of numbers.\n \n Returns:\n int: The difference between the largest and smallest value in the list.\n \"\"\"\n if not lst:\n return 0 # Return 0 if the list is empty\n \n return max(lst) - min(lst)", "matching_cluster_idx": 5}, {"solution": "def big_diff(lst):\n \"\"\"\n Find the difference between the largest and smallest value in a given list.\n \n Args:\n lst (list): A list of numbers.\n \n Returns:\n int: The difference between the largest and smallest value in the list.\n \"\"\"\n if not lst:\n return 0 # Return 0 if the list is empty\n \n return max(lst) - min(lst)", "matching_cluster_idx": 5}]}, "Mbpp/592": {"dps": 40.13333333333334, "dps_norm": 47.5, "pass@1": 57.0, "profiled": [{"solution": "from math import comb\ndef sum_Of_product(n):\n \"\"\"\n Calculate the sum of the product of consecutive binomial coefficients.\n \n Parameters:\n n (int): The upper limit for the binomial coefficients.\n \n Returns:\n int: The sum of the product of consecutive binomial coefficients.\n \"\"\"\n total_sum = 0\n for k in range(n):\n total_sum += comb(n, k) * comb(n, k + 1)\n return total_sum", "matching_cluster_idx": 5}, {"solution": "import math\ndef binomial_coefficient(n, k):\n \"\"\"Calculate the binomial coefficient C(n, k).\"\"\"\n return math.comb(n, k)\ndef sum_Of_product(n):\n \"\"\"Calculate the sum of the product of consecutive binomial coefficients.\"\"\"\n total_sum = 0\n for k in range(n):\n total_sum += binomial_coefficient(n, k) * binomial_coefficient(n, k + 1)\n return total_sum", "matching_cluster_idx": 4}, {"solution": "from math import comb\ndef sum_Of_product(n):\n \"\"\"\n Calculate the sum of the product of consecutive binomial coefficients.\n \n Args:\n n (int): The upper limit for the binomial coefficients.\n \n Returns:\n int: The sum of the product of consecutive binomial coefficients.\n \"\"\"\n total_sum = 0\n for k in range(1, n + 1):\n total_sum += comb(n, k) * comb(n, k - 1)\n return total_sum", "matching_cluster_idx": 4}, {"solution": "from math import comb\ndef sum_Of_product(n):\n \"\"\"\n Calculate the sum of the product of consecutive binomial coefficients.\n \n Args:\n n (int): The upper limit for the binomial coefficients.\n \n Returns:\n int: The sum of the product of consecutive binomial coefficients.\n \"\"\"\n total_sum = 0\n for k in range(n):\n total_sum += comb(n, k) * comb(n, k + 1)\n return total_sum", "matching_cluster_idx": 4}, {"solution": "from math import comb\ndef sum_Of_product(n):\n \"\"\"\n Calculate the sum of the product of consecutive binomial coefficients.\n \n Args:\n n (int): The upper limit for the binomial coefficients.\n \n Returns:\n int: The sum of the product of consecutive binomial coefficients.\n \"\"\"\n total_sum = 0\n for k in range(n):\n total_sum += comb(n, k) * comb(n, k + 1)\n return total_sum", "matching_cluster_idx": 4}, {"solution": "def factorial(n):\n if n == 0 or n == 1:\n return 1\n result = 1\n for i in range(2, n + 1):\n result *= i\n return result\ndef binomial_coefficient(n, k):\n return factorial(n) // (factorial(k) * factorial(n - k))\ndef sum_Of_product(n):\n total_sum = 0\n for k in range(n):\n total_sum += binomial_coefficient(n, k) * binomial_coefficient(n, k + 1)\n return total_sum", "matching_cluster_idx": 0}, {"solution": "from math import comb\ndef sum_Of_product(n):\n \"\"\"\n Calculate the sum of the product of consecutive binomial coefficients.\n \n Args:\n n (int): The upper limit for the binomial coefficients.\n \n Returns:\n int: The sum of the product of consecutive binomial coefficients.\n \"\"\"\n total_sum = 0\n for k in range(1, n + 1):\n total_sum += comb(n, k) * comb(n, k - 1)\n return total_sum", "matching_cluster_idx": 4}, {"solution": "from math import comb\ndef sum_Of_product(n):\n \"\"\"\n Calculate the sum of the product of consecutive binomial coefficients.\n \n Parameters:\n n (int): The upper limit for the binomial coefficients.\n \n Returns:\n int: The sum of the product of consecutive binomial coefficients.\n \"\"\"\n total_sum = 0\n for k in range(n):\n total_sum += comb(n, k) * comb(n, k + 1)\n return total_sum", "matching_cluster_idx": 5}, {"solution": "from math import comb\ndef sum_Of_product(n):\n \"\"\"\n Calculate the sum of the product of consecutive binomial coefficients.\n \n Parameters:\n n (int): The upper limit for the binomial coefficients.\n \n Returns:\n int: The sum of the product of consecutive binomial coefficients.\n \"\"\"\n total_sum = 0\n for k in range(n):\n total_sum += comb(n, k) * comb(n, k + 1)\n return total_sum", "matching_cluster_idx": 5}, {"solution": "from math import comb\ndef sum_Of_product(n):\n \"\"\"\n Calculate the sum of the product of consecutive binomial coefficients.\n \n Parameters:\n n (int): The upper limit for the binomial coefficients.\n \n Returns:\n int: The sum of the product of consecutive binomial coefficients.\n \"\"\"\n total_sum = 0\n for k in range(1, n + 1):\n total_sum += comb(n, k) * comb(n, k - 1)\n return total_sum", "matching_cluster_idx": 4}, {"solution": "from math import comb\ndef sum_Of_product(n):\n \"\"\"\n Calculate the sum of the product of consecutive binomial coefficients for a given n.\n \n The sum of the product of consecutive binomial coefficients C(n, k) * C(n, k+1) for k in [0, n-1].\n \n Args:\n n (int): The upper limit for the binomial coefficients.\n \n Returns:\n int: The sum of the product of consecutive binomial coefficients.\n \"\"\"\n total_sum = 0\n for k in range(n):\n total_sum += comb(n, k) * comb(n, k + 1)\n return total_sum", "matching_cluster_idx": 4}, {"solution": "from math import comb\ndef sum_Of_product(n):\n \"\"\"\n Calculate the sum of the product of consecutive binomial coefficients.\n \n The sum is given by:\n sum_{i=0}^{n-1} C(n, i) * C(n, i+1)\n \n where C(n, k) is the binomial coefficient \"n choose k\".\n \"\"\"\n total_sum = 0\n for i in range(n):\n total_sum += comb(n, i) * comb(n, i + 1)\n return total_sum", "matching_cluster_idx": 4}, {"solution": "from math import comb\ndef sum_Of_product(n):\n \"\"\"\n Calculate the sum of the product of consecutive binomial coefficients.\n \n Args:\n n (int): The upper limit for the binomial coefficients.\n \n Returns:\n int: The sum of the product of consecutive binomial coefficients.\n \"\"\"\n total_sum = 0\n for k in range(1, n + 1):\n total_sum += comb(n, k) * comb(n, k - 1)\n return total_sum", "matching_cluster_idx": 4}, {"solution": "from math import comb\ndef sum_Of_product(n):\n \"\"\"\n Calculate the sum of the product of consecutive binomial coefficients.\n \n Args:\n n (int): The upper limit for the binomial coefficients.\n \n Returns:\n int: The sum of the product of consecutive binomial coefficients.\n \"\"\"\n total_sum = 0\n for k in range(n):\n total_sum += comb(n, k) * comb(n, k + 1)\n return total_sum", "matching_cluster_idx": 4}, {"solution": "from math import comb\ndef sum_Of_product(n):\n \"\"\"\n Calculate the sum of the product of consecutive binomial coefficients.\n \n Parameters:\n n (int): The upper limit for the binomial coefficients.\n \n Returns:\n int: The sum of the product of consecutive binomial coefficients.\n \"\"\"\n total_sum = 0\n for k in range(1, n + 1):\n total_sum += comb(n, k) * comb(n, k - 1)\n return total_sum", "matching_cluster_idx": 4}, {"solution": "def factorial(n):\n if n == 0 or n == 1:\n return 1\n result = 1\n for i in range(2, n + 1):\n result *= i\n return result\ndef binomial_coefficient(n, k):\n return factorial(n) // (factorial(k) * factorial(n - k))\ndef sum_Of_product(n):\n total_sum = 0\n for k in range(n):\n total_sum += binomial_coefficient(n, k) * binomial_coefficient(n, k + 1)\n return total_sum", "matching_cluster_idx": 0}, {"solution": "from math import comb\ndef sum_Of_product(n):\n \"\"\"\n Calculate the sum of the product of consecutive binomial coefficients.\n \n Args:\n n (int): The upper limit for the binomial coefficients.\n \n Returns:\n int: The sum of the product of consecutive binomial coefficients.\n \"\"\"\n total_sum = 0\n for k in range(1, n + 1):\n total_sum += comb(n, k) * comb(n, k - 1)\n return total_sum", "matching_cluster_idx": 4}, {"solution": "from math import comb\ndef sum_Of_product(n):\n \"\"\"\n Calculate the sum of the product of consecutive binomial coefficients.\n \n Args:\n n (int): The upper limit for the binomial coefficients.\n \n Returns:\n int: The sum of the product of consecutive binomial coefficients.\n \"\"\"\n total_sum = 0\n for k in range(1, n + 1):\n total_sum += comb(n, k) * comb(n, k - 1)\n return total_sum", "matching_cluster_idx": 4}, {"solution": "from math import comb\ndef sum_Of_product(n):\n \"\"\"\n Calculate the sum of the product of consecutive binomial coefficients.\n \n Parameters:\n n (int): The upper limit for the binomial coefficients.\n \n Returns:\n int: The sum of the product of consecutive binomial coefficients.\n \"\"\"\n total_sum = 0\n for k in range(1, n + 1):\n total_sum += comb(n, k) * comb(n, k - 1)\n return total_sum", "matching_cluster_idx": 4}, {"solution": "from math import comb\ndef sum_Of_product(n):\n \"\"\"\n Calculate the sum of the product of consecutive binomial coefficients.\n \n Args:\n n (int): The upper limit for the binomial coefficients.\n \n Returns:\n int: The sum of the product of consecutive binomial coefficients.\n \"\"\"\n total_sum = 0\n for k in range(1, n + 1):\n total_sum += comb(n, k) * comb(n, k - 1)\n return total_sum", "matching_cluster_idx": 4}]}, "Mbpp/597": {"dps": null, "dps_norm": null, "pass@1": 0.0, "profiled": []}, "Mbpp/604": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def reverse_words(s):\n # Split the string into words\n words = s.split()\n # Reverse the list of words\n reversed_words = words[::-1]\n # Join the reversed words back into a single string\n reversed_string = ' '.join(reversed_words)\n return reversed_string", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n # Split the string into words\n words = s.split()\n # Reverse the list of words\n reversed_words = words[::-1]\n # Join the reversed words back into a single string\n reversed_string = ' '.join(reversed_words)\n return reversed_string", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n # Split the string into words\n words = s.split()\n # Reverse the list of words\n reversed_words = words[::-1]\n # Join the reversed words back into a single string\n reversed_string = ' '.join(reversed_words)\n return reversed_string", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n # Split the string into words\n words = s.split()\n # Reverse the list of words\n reversed_words = words[::-1]\n # Join the reversed words back into a single string\n reversed_string = ' '.join(reversed_words)\n return reversed_string", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n # Split the string into words\n words = s.split()\n # Reverse the list of words\n reversed_words = words[::-1]\n # Join the reversed words back into a single string\n reversed_string = ' '.join(reversed_words)\n return reversed_string", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n # Split the string into words\n words = s.split()\n # Reverse the list of words\n reversed_words = words[::-1]\n # Join the reversed words back into a single string\n reversed_string = ' '.join(reversed_words)\n return reversed_string", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n # Split the string into words\n words = s.split()\n # Reverse the list of words\n reversed_words = words[::-1]\n # Join the reversed words back into a single string with spaces\n reversed_string = ' '.join(reversed_words)\n return reversed_string", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n # Split the string into words\n words = s.split()\n # Reverse the list of words\n reversed_words = words[::-1]\n # Join the reversed words back into a single string\n reversed_string = ' '.join(reversed_words)\n return reversed_string", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n # Split the string into words\n words = s.split()\n # Reverse the list of words\n reversed_words = words[::-1]\n # Join the reversed words back into a single string with spaces\n reversed_string = ' '.join(reversed_words)\n return reversed_string", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n # Split the string into words\n words = s.split()\n # Reverse the list of words\n reversed_words = words[::-1]\n # Join the reversed words back into a single string\n reversed_string = ' '.join(reversed_words)\n return reversed_string", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n # Split the string into words based on spaces\n words = s.split()\n # Reverse the list of words\n reversed_words = words[::-1]\n # Join the reversed words back into a single string with spaces\n reversed_string = ' '.join(reversed_words)\n return reversed_string", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n # Split the string into words\n words = s.split()\n # Reverse the list of words\n reversed_words = words[::-1]\n # Join the reversed words back into a single string\n reversed_string = ' '.join(reversed_words)\n return reversed_string", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n # Split the string into words\n words = s.split()\n # Reverse the list of words\n reversed_words = words[::-1]\n # Join the reversed words back into a single string\n reversed_string = ' '.join(reversed_words)\n return reversed_string", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n # Split the string into words\n words = s.split()\n # Reverse the list of words\n reversed_words = words[::-1]\n # Join the reversed words back into a single string\n reversed_string = ' '.join(reversed_words)\n return reversed_string", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n # Split the string into words\n words = s.split()\n # Reverse the list of words\n reversed_words = words[::-1]\n # Join the reversed words back into a single string\n reversed_string = ' '.join(reversed_words)\n return reversed_string", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n # Split the string into words\n words = s.split()\n # Reverse the list of words\n reversed_words = words[::-1]\n # Join the reversed words back into a single string\n reversed_string = ' '.join(reversed_words)\n return reversed_string", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n # Split the string into words\n words = s.split()\n # Reverse the list of words\n reversed_words = words[::-1]\n # Join the reversed words back into a single string\n reversed_string = ' '.join(reversed_words)\n return reversed_string", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n # Split the string into words\n words = s.split()\n # Reverse the list of words\n reversed_words = words[::-1]\n # Join the reversed words back into a single string\n reversed_string = ' '.join(reversed_words)\n return reversed_string", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n # Split the string into words\n words = s.split()\n # Reverse the list of words\n reversed_words = words[::-1]\n # Join the reversed words back into a single string\n reversed_string = ' '.join(reversed_words)\n return reversed_string", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n # Split the string into words\n words = s.split()\n # Reverse the list of words\n reversed_words = words[::-1]\n # Join the reversed words back into a single string\n reversed_string = ' '.join(reversed_words)\n return reversed_string", "matching_cluster_idx": 4}]}, "Mbpp/610": {"dps": 58.69565217391305, "dps_norm": 57.142857142857146, "pass@1": 100.0, "profiled": [{"solution": "def remove_kth_element(lst, k):\n \"\"\"\n Removes the k'th element from the list and returns the modified list.\n \n :param lst: List of elements.\n :param k: Index of the element to remove (1-based index).\n :return: List with the k'th element removed.\n \"\"\"\n # Convert 1-based index to 0-based index\n k_index = k - 1\n \n # Check if the index is valid\n if k_index < 0 or k_index >= len(lst):\n raise ValueError(\"k is out of the list's range\")\n \n # Return the list with the k'th element removed\n return lst[:k_index] + lst[k_index + 1:]", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(lst, k):\n \"\"\"\n Removes the k'th element from the list and returns the modified list.\n \n :param lst: List of elements.\n :param k: Index of the element to remove (1-based index).\n :return: List with the k'th element removed.\n \"\"\"\n # Convert 1-based index to 0-based index\n k_index = k - 1\n \n # Check if the index is valid\n if k_index < 0 or k_index >= len(lst):\n raise ValueError(\"k is out of the list's range\")\n \n # Return the list with the k'th element removed\n return lst[:k_index] + lst[k_index + 1:]", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(lst, k):\n \"\"\"\n Removes the k'th element from the list and returns the modified list.\n \n :param lst: List of elements.\n :param k: Index of the element to remove (1-based index).\n :return: List with the k'th element removed.\n \"\"\"\n # Convert 1-based index to 0-based index\n k_index = k - 1\n \n # Check if the index is valid\n if k_index < 0 or k_index >= len(lst):\n raise ValueError(\"k is out of the list's range\")\n \n # Return the list without the k'th element\n return lst[:k_index] + lst[k_index + 1:]", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(lst, k):\n \"\"\"\n Remove the k'th element from the list and return the modified list.\n \n :param lst: List of elements\n :param k: Index of the element to remove (1-based index)\n :return: List with the k'th element removed\n \"\"\"\n # Convert 1-based index to 0-based index\n k_index = k - 1\n \n # Check if the index is valid\n if k_index < 0 or k_index >= len(lst):\n raise ValueError(\"k is out of the valid range for the list\")\n \n # Return the list with the k'th element removed\n return lst[:k_index] + lst[k_index + 1:]", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(lst, k):\n \"\"\"\n Removes the k'th element from the list and returns the modified list.\n \n :param lst: List of elements\n :param k: Index of the element to remove (1-based index)\n :return: List with the k'th element removed\n \"\"\"\n # Convert 1-based index to 0-based index\n k_index = k - 1\n \n # Check if the index is valid\n if k_index < 0 or k_index >= len(lst):\n raise ValueError(\"k is out of the list's range\")\n \n # Return the list with the k'th element removed\n return lst[:k_index] + lst[k_index + 1:]", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(lst, k):\n \"\"\"\n Remove the k'th element from the list and return the modified list.\n \n :param lst: List of elements\n :param k: Index of the element to remove (1-based index)\n :return: List with the k'th element removed\n \"\"\"\n # Convert 1-based index to 0-based index\n k_index = k - 1\n \n # Check if the index is valid\n if k_index < 0 or k_index >= len(lst):\n raise ValueError(\"k is out of the list's range\")\n \n # Return the list with the k'th element removed\n return lst[:k_index] + lst[k_index + 1:]", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(lst, k):\n \"\"\"\n Removes the k'th element from the list and returns the modified list.\n \n :param lst: List of elements.\n :param k: Index of the element to remove (1-based index).\n :return: List with the k'th element removed.\n \"\"\"\n # Convert 1-based index to 0-based index\n k_index = k - 1\n \n # Check if the index is valid\n if k_index < 0 or k_index >= len(lst):\n raise ValueError(\"k is out of the list's range\")\n \n # Return the list with the k'th element removed\n return lst[:k_index] + lst[k_index + 1:]", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(lst, k):\n \"\"\"\n Removes the k'th element from the list and returns the modified list.\n \n :param lst: List of elements.\n :param k: Index of the element to remove (1-based index).\n :return: List with the k'th element removed.\n \"\"\"\n # Convert 1-based index to 0-based index\n k_index = k - 1\n \n # Check if the index is valid\n if k_index < 0 or k_index >= len(lst):\n raise ValueError(\"k is out of the list's range\")\n \n # Return the list without the k'th element\n return lst[:k_index] + lst[k_index + 1:]", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(lst, k):\n \"\"\"\n Removes the k'th element from the list and returns the modified list.\n \n :param lst: List of elements\n :param k: Index of the element to remove (1-based index)\n :return: List with the k'th element removed\n \"\"\"\n # Convert 1-based index to 0-based index\n k_index = k - 1\n \n # Check if the index is valid\n if k_index < 0 or k_index >= len(lst):\n raise ValueError(\"k is out of the range of the list\")\n \n # Return the list with the k'th element removed\n return lst[:k_index] + lst[k_index + 1:]", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(lst, k):\n \"\"\"\n Removes the k'th element from the list and returns the modified list.\n \n :param lst: List of elements.\n :param k: Index of the element to remove (1-based index).\n :return: List with the k'th element removed.\n \"\"\"\n # Convert 1-based index to 0-based index\n k_index = k - 1\n \n # Check if the index is valid\n if k_index < 0 or k_index >= len(lst):\n raise ValueError(\"k is out of the list's range\")\n \n # Return the list with the k'th element removed\n return lst[:k_index] + lst[k_index + 1:]", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(lst, k):\n \"\"\"\n Remove the k'th element from the list and return the modified list.\n \n :param lst: List of elements\n :param k: Index of the element to remove (1-based index)\n :return: List with the k'th element removed\n \"\"\"\n # Convert 1-based index to 0-based index\n k_index = k - 1\n \n # Check if the index is valid\n if k_index < 0 or k_index >= len(lst):\n raise ValueError(\"k is out of the range of the list\")\n \n # Return the list with the k'th element removed\n return lst[:k_index] + lst[k_index + 1:]", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(lst, k):\n \"\"\"\n Removes the k'th element from the list and returns the modified list.\n \n :param lst: List of elements.\n :param k: Index of the element to remove (1-based index).\n :return: List with the k'th element removed.\n \"\"\"\n # Convert 1-based index to 0-based index\n k_index = k - 1\n \n # Check if the index is valid\n if k_index < 0 or k_index >= len(lst):\n raise ValueError(\"k is out of the list's range\")\n \n # Return the list with the k'th element removed\n return lst[:k_index] + lst[k_index + 1:]", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(lst, k):\n \"\"\"\n Remove the k'th element from the list and return the modified list.\n \n :param lst: List of elements\n :param k: Index of the element to remove (1-based index)\n :return: List with the k'th element removed\n \"\"\"\n # Convert 1-based index to 0-based index\n k_index = k - 1\n \n # Check if the index is valid\n if k_index < 0 or k_index >= len(lst):\n raise ValueError(\"k is out of the list's range\")\n \n # Return the list with the k'th element removed\n return lst[:k_index] + lst[k_index + 1:]", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(lst, k):\n \"\"\"\n Removes the k'th element from the list and returns the modified list.\n \n :param lst: List of elements\n :param k: Index of the element to remove (1-based index)\n :return: List with the k'th element removed\n \"\"\"\n # Convert 1-based index to 0-based index\n k_index = k - 1\n \n # Check if the index is valid\n if k_index < 0 or k_index >= len(lst):\n raise ValueError(\"k is out of the valid range for the list\")\n \n # Return the list with the k'th element removed\n return lst[:k_index] + lst[k_index + 1:]", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(lst, k):\n \"\"\"\n Remove the k'th element from the list and return the modified list.\n \n :param lst: List of elements\n :param k: Index of the element to remove (1-based index)\n :return: List with the k'th element removed\n \"\"\"\n # Convert 1-based index to 0-based index\n k_index = k - 1\n \n # Check if the index is valid\n if k_index < 0 or k_index >= len(lst):\n raise ValueError(\"k is out of the valid range for the list\")\n \n # Return the list with the k'th element removed\n return lst[:k_index] + lst[k_index + 1:]", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(lst, k):\n \"\"\"\n Removes the k'th element from the list and returns the modified list.\n \n :param lst: List of elements\n :param k: Index of the element to remove (1-based index)\n :return: List with the k'th element removed\n \"\"\"\n # Convert 1-based index to 0-based index\n k_index = k - 1\n \n # Check if the index is valid\n if k_index < 0 or k_index >= len(lst):\n raise ValueError(\"k is out of the range of the list\")\n \n # Return the list with the k'th element removed\n return lst[:k_index] + lst[k_index + 1:]", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(lst, k):\n \"\"\"\n Remove the k'th element from the list and return the modified list.\n \n :param lst: List of elements\n :param k: Index of the element to remove (1-based index)\n :return: List with the k'th element removed\n \"\"\"\n # Convert 1-based index to 0-based index\n k_index = k - 1\n \n # Check if the index is valid\n if k_index < 0 or k_index >= len(lst):\n raise ValueError(\"k is out of the list's range\")\n \n # Return the list with the k'th element removed\n return lst[:k_index] + lst[k_index + 1:]", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(lst, k):\n \"\"\"\n Remove the k'th element from the list.\n \n :param lst: List of elements.\n :param k: Index of the element to remove (1-based index).\n :return: List with the k'th element removed.\n \"\"\"\n # Convert 1-based index to 0-based index\n k_index = k - 1\n \n # Check if the index is valid\n if k_index < 0 or k_index >= len(lst):\n raise ValueError(\"k is out of the list's range\")\n \n # Return the list with the k'th element removed\n return lst[:k_index] + lst[k_index + 1:]", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(lst, k):\n \"\"\"\n Removes the k'th element from the list and returns the modified list.\n \n :param lst: List of elements\n :param k: Index of the element to remove (1-based index)\n :return: List with the k'th element removed\n \"\"\"\n # Convert 1-based index to 0-based index\n k_index = k - 1\n \n # Check if the index is valid\n if k_index < 0 or k_index >= len(lst):\n raise ValueError(\"k is out of the valid range for the list\")\n \n # Return the list with the k'th element removed\n return lst[:k_index] + lst[k_index + 1:]", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(lst, k):\n \"\"\"\n Remove the k'th element from the list and return the modified list.\n \n :param lst: List of elements\n :param k: Index of the element to remove (1-based index)\n :return: List with the k'th element removed\n \"\"\"\n # Convert 1-based index to 0-based index\n k_index = k - 1\n \n # Check if the index is valid\n if k_index < 0 or k_index >= len(lst):\n raise ValueError(\"k is out of the list's range\")\n \n # Return the list with the k'th element removed\n return lst[:k_index] + lst[k_index + 1:]", "matching_cluster_idx": 3}]}, "Mbpp/611": {"dps": null, "dps_norm": null, "pass@1": 8.0, "profiled": []}, "Mbpp/631": {"dps": 56.249999999999986, "dps_norm": 81.25, "pass@1": 31.0, "profiled": [{"solution": "def replace_spaces(input_string):\n \"\"\"\n Replace whitespaces with underscores and vice versa in the given string.\n \n Args:\n input_string (str): The input string to be modified.\n \n Returns:\n str: The modified string with whitespaces replaced by underscores and vice versa.\n \"\"\"\n # Create a translation table that maps spaces to underscores and underscores to spaces\n translation_table = str.maketrans(' _', '_ ')\n \n # Translate the input string using the translation table\n modified_string = input_string.translate(translation_table)\n \n return modified_string", "matching_cluster_idx": 6}, {"solution": "def replace_spaces(input_string):\n \"\"\"\n Replace whitespaces with underscores and vice versa in the given string.\n \n Args:\n input_string (str): The input string to be modified.\n \n Returns:\n str: The modified string with whitespaces replaced by underscores and vice versa.\n \"\"\"\n # Create a translation table to swap spaces and underscores\n translation_table = str.maketrans(' _', '_ ')\n \n # Translate the input string using the translation table\n modified_string = input_string.translate(translation_table)\n \n return modified_string", "matching_cluster_idx": 6}, {"solution": "def replace_spaces(input_string):\n \"\"\"\n Replace whitespaces with underscores and vice versa in the given string.\n\n Args:\n input_string (str): The input string to be modified.\n\n Returns:\n str: The modified string with whitespaces replaced by underscores and vice versa.\n \"\"\"\n # Replace underscores with a temporary placeholder to avoid conflicts\n temp_placeholder = 'TEMP_PLACEHOLDER'\n input_string = input_string.replace('_', temp_placeholder)\n \n # Replace whitespaces with underscores\n input_string = input_string.replace(' ', '_')\n \n # Replace the temporary placeholder with whitespaces\n input_string = input_string.replace(temp_placeholder, ' ')\n \n return input_string", "matching_cluster_idx": 4}, {"solution": "def replace_spaces(s):\n \"\"\"\n Replace whitespaces with underscores and underscores with whitespaces in the given string.\n \n :param s: The input string\n :return: The modified string\n \"\"\"\n # Create a translation table that maps spaces to underscores and underscores to spaces\n translation_table = str.maketrans(' _', '_ ')\n \n # Translate the string using the translation table\n return s.translate(translation_table)", "matching_cluster_idx": 6}, {"solution": "def replace_spaces(s):\n \"\"\"\n Replace whitespaces with underscores and underscores with whitespaces in the given string.\n \n :param s: The input string\n :return: The modified string\n \"\"\"\n # Create a translation table that maps spaces to underscores and underscores to spaces\n translation_table = str.maketrans(' _', '_ ')\n \n # Translate the string using the translation table\n return s.translate(translation_table)", "matching_cluster_idx": 6}, {"solution": "def replace_spaces(input_string):\n \"\"\"\n Replace whitespaces with underscores and underscores with whitespaces in the given string.\n \n Args:\n input_string (str): The input string to be modified.\n \n Returns:\n str: The modified string with whitespaces replaced by underscores and vice versa.\n \"\"\"\n # Create a translation table to swap spaces and underscores\n translation_table = str.maketrans(' _', '_ ')\n \n # Translate the input string using the translation table\n modified_string = input_string.translate(translation_table)\n \n return modified_string", "matching_cluster_idx": 6}, {"solution": "def replace_spaces(input_string):\n \"\"\"\n Replace whitespaces with underscores and vice versa in the given string.\n \n Args:\n input_string (str): The input string to be modified.\n \n Returns:\n str: The modified string with whitespaces replaced by underscores and vice versa.\n \"\"\"\n # Replace underscores with a temporary placeholder to avoid conflicts\n temp_string = input_string.replace('_', 'TEMP_PLACEHOLDER')\n \n # Replace whitespaces with underscores\n temp_string = temp_string.replace(' ', '_')\n \n # Replace the temporary placeholder with whitespaces\n result_string = temp_string.replace('TEMP_PLACEHOLDER', ' ')\n \n return result_string", "matching_cluster_idx": 4}, {"solution": "def replace_spaces(input_string):\n \"\"\"\n Replace whitespaces with underscores and vice versa in the given string.\n \n Args:\n input_string (str): The input string to be modified.\n \n Returns:\n str: The modified string with whitespaces replaced by underscores and vice versa.\n \"\"\"\n # Replace underscores with a temporary placeholder to avoid conflicts\n temp_placeholder = 'TEMP_PLACEHOLDER'\n input_string = input_string.replace('_', temp_placeholder)\n \n # Replace whitespaces with underscores\n input_string = input_string.replace(' ', '_')\n \n # Replace the temporary placeholder with whitespaces\n input_string = input_string.replace(temp_placeholder, ' ')\n \n return input_string", "matching_cluster_idx": 4}, {"solution": "def replace_spaces(input_string):\n \"\"\"\n Replace whitespaces with underscores and vice versa in the given string.\n \n Args:\n input_string (str): The input string to be modified.\n \n Returns:\n str: The modified string with whitespaces replaced by underscores and vice versa.\n \"\"\"\n # Replace underscores with a temporary placeholder to avoid conflicts\n temp_string = input_string.replace('_', 'TEMP_PLACEHOLDER')\n \n # Replace whitespaces with underscores\n temp_string = temp_string.replace(' ', '_')\n \n # Replace the temporary placeholder with whitespaces\n result_string = temp_string.replace('TEMP_PLACEHOLDER', ' ')\n \n return result_string", "matching_cluster_idx": 4}, {"solution": "def replace_spaces(s):\n \"\"\"\n Replace whitespaces with underscores and underscores with whitespaces in the given string.\n \n Args:\n s (str): The input string.\n \n Returns:\n str: The modified string.\n \"\"\"\n # Create a translation table that maps spaces to underscores and underscores to spaces\n translation_table = str.maketrans(' _', '_ ')\n \n # Translate the string using the translation table\n return s.translate(translation_table)", "matching_cluster_idx": 6}, {"solution": "def replace_spaces(input_string):\n \"\"\"\n Replace whitespaces with underscores and vice versa in the given string.\n \n Args:\n input_string (str): The input string to be modified.\n \n Returns:\n str: The modified string with whitespaces replaced by underscores and vice versa.\n \"\"\"\n # Create a translation table that maps spaces to underscores and underscores to spaces\n translation_table = str.maketrans(' _', '_ ')\n \n # Translate the input string using the translation table\n modified_string = input_string.translate(translation_table)\n \n return modified_string", "matching_cluster_idx": 6}, {"solution": "def replace_spaces(input_string):\n \"\"\"\n Replace whitespaces with underscores and vice versa in the given string.\n \n Args:\n input_string (str): The input string to be modified.\n \n Returns:\n str: The modified string with spaces replaced by underscores and vice versa.\n \"\"\"\n # Create a translation table for the replacements\n translation_table = str.maketrans(' _', '_ ')\n \n # Translate the input string using the translation table\n modified_string = input_string.translate(translation_table)\n \n return modified_string", "matching_cluster_idx": 6}, {"solution": "def replace_spaces(s):\n \"\"\"\n Replace whitespaces with underscores and underscores with whitespaces in the given string.\n \n Args:\n s (str): The input string.\n \n Returns:\n str: The modified string.\n \"\"\"\n # Create a translation table that maps spaces to underscores and underscores to spaces\n translation_table = str.maketrans(' _', '_ ')\n \n # Use the translate method to replace characters according to the translation table\n return s.translate(translation_table)", "matching_cluster_idx": 6}, {"solution": "def replace_spaces(input_string):\n \"\"\"\n Replace whitespaces with underscores and underscores with whitespaces in the given string.\n \n Args:\n input_string (str): The input string to be processed.\n \n Returns:\n str: The modified string with spaces and underscores swapped.\n \"\"\"\n # Use str.translate to swap spaces and underscores\n return input_string.translate(str.maketrans(' _', '_ '))", "matching_cluster_idx": 6}, {"solution": "def replace_spaces(input_string):\n \"\"\"\n Replace whitespaces with underscores and underscores with whitespaces in the given string.\n \n :param input_string: The input string to be processed.\n :return: The processed string with spaces and underscores swapped.\n \"\"\"\n # Create a translation table that maps spaces to underscores and underscores to spaces\n translation_table = str.maketrans(' _', '_ ')\n \n # Translate the input string using the translation table\n return input_string.translate(translation_table)", "matching_cluster_idx": 6}, {"solution": "def replace_spaces(input_string):\n \"\"\"\n Replace whitespaces with underscores and underscores with whitespaces in the given string.\n \n :param input_string: The input string to be modified.\n :return: The modified string with spaces and underscores swapped.\n \"\"\"\n # Create a translation table that maps spaces to underscores and underscores to spaces\n translation_table = str.maketrans(' _', '_ ')\n \n # Translate the input string using the translation table\n modified_string = input_string.translate(translation_table)\n \n return modified_string", "matching_cluster_idx": 6}, {"solution": "def replace_spaces(input_string):\n \"\"\"\n Replace whitespaces with underscores and underscores with whitespaces in the given string.\n \n :param input_string: The input string to be modified.\n :return: The modified string.\n \"\"\"\n # Create a translation table to swap spaces and underscores\n translation_table = str.maketrans(' _', '_ ')\n \n # Translate the input string using the translation table\n modified_string = input_string.translate(translation_table)\n \n return modified_string", "matching_cluster_idx": 6}, {"solution": "def replace_spaces(input_string):\n \"\"\"\n Replace whitespaces with underscores and vice versa in the given string.\n \n Args:\n input_string (str): The input string to be modified.\n \n Returns:\n str: The modified string with whitespaces replaced by underscores and vice versa.\n \"\"\"\n # Replace underscores with a temporary placeholder to avoid conflicts\n temp_string = input_string.replace('_', 'TEMP_PLACEHOLDER')\n \n # Replace whitespaces with underscores\n temp_string = temp_string.replace(' ', '_')\n \n # Replace the temporary placeholder with whitespaces\n result_string = temp_string.replace('TEMP_PLACEHOLDER', ' ')\n \n return result_string", "matching_cluster_idx": 4}, {"solution": "def replace_spaces(input_string):\n \"\"\"\n Replace whitespaces with underscores and vice versa in the given string.\n \n Args:\n input_string (str): The input string to be modified.\n \n Returns:\n str: The modified string with whitespaces replaced by underscores and vice versa.\n \"\"\"\n # Create a translation table that maps spaces to underscores and underscores to spaces\n translation_table = str.maketrans(' _', '_ ')\n \n # Translate the input string using the translation table\n modified_string = input_string.translate(translation_table)\n \n return modified_string", "matching_cluster_idx": 6}, {"solution": "def replace_spaces(input_string):\n \"\"\"\n Replace whitespaces with underscores and vice versa in the given string.\n \n Args:\n input_string (str): The input string to be modified.\n \n Returns:\n str: The modified string with whitespaces replaced by underscores and vice versa.\n \"\"\"\n # Create a translation table that maps spaces to underscores and underscores to spaces\n translation_table = str.maketrans(' _', '_ ')\n \n # Translate the input string using the translation table\n modified_string = input_string.translate(translation_table)\n \n return modified_string", "matching_cluster_idx": 6}]}, "Mbpp/632": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def move_zero(lst):\n # Count the number of non-zero elements\n non_zero_count = sum(1 for x in lst if x != 0)\n \n # Create a new list with non-zero elements first\n result = [x for x in lst if x != 0]\n \n # Append the remaining zeroes\n result.extend([0] * (len(lst) - non_zero_count))\n \n return result", "matching_cluster_idx": 6}, {"solution": "def move_zero(lst):\n # Count the number of non-zero elements\n non_zero_count = sum(1 for x in lst if x != 0)\n \n # Create a new list with non-zero elements first\n result = [x for x in lst if x != 0]\n \n # Append the remaining zeroes\n result.extend([0] * (len(lst) - non_zero_count))\n \n return result", "matching_cluster_idx": 6}, {"solution": "def move_zero(lst):\n # Count the number of non-zero elements\n non_zero_count = sum(1 for x in lst if x != 0)\n \n # Create a new list with non-zero elements first\n result = [x for x in lst if x != 0]\n \n # Append the remaining zeroes to the end of the list\n result.extend([0] * (len(lst) - non_zero_count))\n \n return result", "matching_cluster_idx": 6}, {"solution": "def move_zero(lst):\n # Count the number of non-zero elements\n non_zero_count = sum(1 for x in lst if x != 0)\n \n # Create a new list with non-zero elements first\n result = [x for x in lst if x != 0]\n \n # Append the remaining zeros to the end of the list\n result.extend([0] * (len(lst) - non_zero_count))\n \n return result", "matching_cluster_idx": 6}, {"solution": "def move_zero(lst):\n # Count the number of non-zero elements\n non_zero_count = sum(1 for x in lst if x != 0)\n \n # Create a new list with non-zero elements first\n result = [x for x in lst if x != 0]\n \n # Append the remaining zeroes\n result.extend([0] * (len(lst) - non_zero_count))\n \n return result", "matching_cluster_idx": 6}, {"solution": "def move_zero(lst):\n # Count the number of non-zero elements\n non_zero_count = sum(1 for x in lst if x != 0)\n \n # Create a new list with non-zero elements first\n result = [x for x in lst if x != 0]\n \n # Append the remaining zeroes\n result.extend([0] * (len(lst) - non_zero_count))\n \n return result", "matching_cluster_idx": 6}, {"solution": "def move_zero(lst):\n # Count the number of non-zero elements\n non_zero_count = sum(1 for x in lst if x != 0)\n \n # Create a new list with non-zero elements first\n result = [x for x in lst if x != 0]\n \n # Append the remaining zeroes to the end\n result.extend([0] * (len(lst) - non_zero_count))\n \n return result", "matching_cluster_idx": 6}, {"solution": "def move_zero(lst):\n # Count the number of non-zero elements\n non_zero_count = sum(1 for x in lst if x != 0)\n \n # Create a new list with non-zero elements first\n result = [x for x in lst if x != 0]\n \n # Append the remaining zeroes to the end of the list\n result.extend([0] * (len(lst) - non_zero_count))\n \n return result", "matching_cluster_idx": 6}, {"solution": "def move_zero(lst):\n # Count the number of non-zero elements\n non_zero_count = sum(1 for x in lst if x != 0)\n \n # Create a new list with non-zero elements first\n result = [x for x in lst if x != 0]\n \n # Append the remaining zeroes to the end of the list\n result.extend([0] * (len(lst) - non_zero_count))\n \n return result", "matching_cluster_idx": 6}, {"solution": "def move_zero(lst):\n # Count the number of non-zero elements\n non_zero_count = sum(1 for x in lst if x != 0)\n \n # Create a new list with non-zero elements first\n result = [x for x in lst if x != 0]\n \n # Append the remaining zeroes\n result.extend([0] * (len(lst) - non_zero_count))\n \n return result", "matching_cluster_idx": 6}, {"solution": "def move_zero(lst):\n # Count the number of non-zero elements\n non_zero_count = sum(1 for x in lst if x != 0)\n \n # Create a new list with non-zero elements first\n result = [x for x in lst if x != 0]\n \n # Append the remaining zeroes\n result.extend([0] * (len(lst) - non_zero_count))\n \n return result", "matching_cluster_idx": 6}, {"solution": "def move_zero(lst):\n # Count the number of non-zero elements\n non_zero_count = sum(1 for x in lst if x != 0)\n \n # Create a new list with non-zero elements first\n result = [x for x in lst if x != 0]\n \n # Append the remaining zeroes\n result.extend([0] * (len(lst) - non_zero_count))\n \n return result", "matching_cluster_idx": 6}, {"solution": "def move_zero(lst):\n # Count the number of non-zero elements\n non_zero_count = sum(1 for x in lst if x != 0)\n \n # Create a new list with non-zero elements first\n result = [x for x in lst if x != 0]\n \n # Append the remaining zeroes\n result.extend([0] * (len(lst) - non_zero_count))\n \n return result", "matching_cluster_idx": 6}, {"solution": "def move_zero(lst):\n # Count the number of non-zero elements\n non_zero_count = sum(1 for x in lst if x != 0)\n \n # Create a new list with non-zero elements first\n result = [x for x in lst if x != 0]\n \n # Append the remaining zeroes\n result.extend([0] * (len(lst) - non_zero_count))\n \n return result", "matching_cluster_idx": 6}, {"solution": "def move_zero(lst):\n # Count the number of non-zero elements\n non_zero_count = sum(1 for x in lst if x != 0)\n \n # Create a new list with non-zero elements first\n result = [x for x in lst if x != 0]\n \n # Append the remaining zeroes to the end of the list\n result.extend([0] * (len(lst) - non_zero_count))\n \n return result", "matching_cluster_idx": 6}, {"solution": "def move_zero(lst):\n # Count the number of non-zero elements\n non_zero_count = sum(1 for x in lst if x != 0)\n \n # Create a new list with non-zero elements first\n result = [x for x in lst if x != 0]\n \n # Append the remaining zeroes\n result.extend([0] * (len(lst) - non_zero_count))\n \n return result", "matching_cluster_idx": 6}, {"solution": "def move_zero(lst):\n # Count the number of non-zero elements\n non_zero_count = sum(1 for x in lst if x != 0)\n \n # Create a new list with non-zero elements first\n result = [x for x in lst if x != 0]\n \n # Append the remaining zeroes to the end of the list\n result.extend([0] * (len(lst) - non_zero_count))\n \n return result", "matching_cluster_idx": 6}, {"solution": "def move_zero(lst):\n # Count the number of non-zero elements\n non_zero_count = sum(1 for x in lst if x != 0)\n \n # Create a new list with non-zero elements first\n result = [x for x in lst if x != 0]\n \n # Append the remaining zeroes to the end of the list\n result.extend([0] * (len(lst) - non_zero_count))\n \n return result", "matching_cluster_idx": 6}, {"solution": "def move_zero(lst):\n # Count the number of non-zero elements\n non_zero_count = sum(1 for x in lst if x != 0)\n \n # Create a new list with non-zero elements first\n result = [x for x in lst if x != 0]\n \n # Append the remaining zeroes\n result.extend([0] * (len(lst) - non_zero_count))\n \n return result", "matching_cluster_idx": 6}, {"solution": "def move_zero(lst):\n # Count the number of non-zero elements\n non_zero_count = sum(1 for x in lst if x != 0)\n \n # Create a new list with non-zero elements first\n result = [x for x in lst if x != 0]\n \n # Append the remaining zeroes to the end of the list\n result.extend([0] * (len(lst) - non_zero_count))\n \n return result", "matching_cluster_idx": 6}]}, "Mbpp/633": {"dps": null, "dps_norm": null, "pass@1": 0.0, "profiled": []}, "Mbpp/644": {"dps": 96.27659574468083, "dps_norm": 93.33333333333333, "pass@1": 100.0, "profiled": [{"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n Reverses the array up to the given position k.\n \n Parameters:\n arr (list): The input array.\n k (int): The position up to which the array should be reversed.\n \n Returns:\n list: The array with the first k elements reversed.\n \"\"\"\n if k > len(arr):\n raise ValueError(\"k should be less than or equal to the length of the array\")\n \n # Reverse the first k elements\n arr[:k] = arr[:k][::-1]\n \n return arr", "matching_cluster_idx": 13}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n Reverses the array upto the given position k.\n \n Parameters:\n arr (list): The input array.\n k (int): The position upto which the array should be reversed.\n \n Returns:\n list: The array with the first k elements reversed.\n \"\"\"\n if k > len(arr):\n raise ValueError(\"k should be less than or equal to the length of the array\")\n \n # Reverse the first k elements\n arr[:k] = arr[:k][::-1]\n \n return arr", "matching_cluster_idx": 13}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n Reverses the array up to the given position k.\n \n Parameters:\n arr (list): The input array.\n k (int): The position up to which the array should be reversed.\n \n Returns:\n list: The array with the first k elements reversed.\n \"\"\"\n if k > len(arr):\n raise ValueError(\"k should be less than or equal to the length of the array\")\n \n # Reverse the first k elements\n arr[:k] = arr[:k][::-1]\n \n return arr", "matching_cluster_idx": 13}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n Reverses an array up to a given position `k`.\n \n Parameters:\n arr (list): The input array.\n k (int): The position up to which the array should be reversed.\n \n Returns:\n list: The array with the first `k` elements reversed.\n \"\"\"\n if k > len(arr):\n raise ValueError(\"Position k exceeds the length of the array.\")\n \n # Reverse the first `k` elements\n arr[:k] = arr[:k][::-1]\n \n return arr", "matching_cluster_idx": 13}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n Reverses an array up to a given position `k`.\n \n Parameters:\n arr (list): The input array.\n k (int): The position up to which the array should be reversed.\n \n Returns:\n list: The array with the first `k` elements reversed.\n \"\"\"\n if k > len(arr):\n raise ValueError(\"k should be less than or equal to the length of the array\")\n \n # Reverse the first `k` elements\n arr[:k] = arr[:k][::-1]\n \n return arr", "matching_cluster_idx": 13}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n Reverses the array up to the given position k.\n \n Parameters:\n arr (list): The input array.\n k (int): The position up to which the array should be reversed.\n \n Returns:\n list: The array with the first k elements reversed.\n \"\"\"\n if k > len(arr):\n raise ValueError(\"k should be less than or equal to the length of the array\")\n \n # Reverse the first k elements\n arr[:k] = arr[:k][::-1]\n \n return arr", "matching_cluster_idx": 13}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n Reverses the array upto the given position k.\n \n Parameters:\n arr (list): The input array.\n k (int): The position upto which the array should be reversed.\n \n Returns:\n list: The array with the first k elements reversed.\n \"\"\"\n if k > len(arr):\n raise ValueError(\"k should be less than or equal to the length of the array\")\n \n # Reverse the first k elements\n arr[:k] = arr[:k][::-1]\n \n return arr", "matching_cluster_idx": 13}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n Reverses an array up to a given position k.\n \n Parameters:\n arr (list): The input array.\n k (int): The position up to which the array should be reversed.\n \n Returns:\n list: The array with the first k elements reversed.\n \"\"\"\n if k > len(arr):\n raise ValueError(\"k should be less than or equal to the length of the array\")\n \n # Reverse the first k elements\n arr[:k] = arr[:k][::-1]\n \n return arr", "matching_cluster_idx": 13}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n Reverse an array upto a given position k.\n \n Parameters:\n arr (list): The input array.\n k (int): The position upto which the array should be reversed.\n \n Returns:\n list: The array with the first k elements reversed.\n \"\"\"\n if k > len(arr):\n raise ValueError(\"k should be less than or equal to the length of the array\")\n \n # Reverse the first k elements\n arr[:k] = arr[:k][::-1]\n \n return arr", "matching_cluster_idx": 13}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n Reverses the array upto the given position k.\n\n Parameters:\n arr (list): The input array.\n k (int): The position upto which the array should be reversed.\n\n Returns:\n list: The array with the first k elements reversed.\n \"\"\"\n if k > len(arr):\n raise ValueError(\"k should be less than or equal to the length of the array\")\n \n # Reverse the first k elements\n arr[:k] = arr[:k][::-1]\n return arr", "matching_cluster_idx": 13}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n Reverses the array up to the given position k.\n \n Parameters:\n arr (list): The input array.\n k (int): The position up to which the array should be reversed.\n \n Returns:\n list: The array with the first k elements reversed.\n \"\"\"\n if k > len(arr):\n raise ValueError(\"k should be less than or equal to the length of the array\")\n \n # Reverse the first k elements\n arr[:k] = arr[:k][::-1]\n \n return arr", "matching_cluster_idx": 13}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n Reverses an array up to a given position k.\n \n Parameters:\n arr (list): The input array.\n k (int): The position up to which the array should be reversed.\n \n Returns:\n list: The array with the first k elements reversed.\n \"\"\"\n if k > len(arr):\n raise ValueError(\"k should be less than or equal to the length of the array\")\n \n # Reverse the first k elements\n arr[:k] = arr[:k][::-1]\n return arr", "matching_cluster_idx": 13}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n Reverses the array up to the given position k.\n \n :param arr: List of integers\n :param k: Integer representing the position up to which the array should be reversed\n :return: List of integers with the first k elements reversed\n \"\"\"\n if k > len(arr):\n raise ValueError(\"k should be less than or equal to the length of the array\")\n \n # Reverse the first k elements\n arr[:k] = arr[:k][::-1]\n \n return arr", "matching_cluster_idx": 13}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n Reverses an array up to a given position k.\n\n Parameters:\n arr (list): The input array.\n k (int): The position up to which the array should be reversed.\n\n Returns:\n list: The array with the first k elements reversed.\n \"\"\"\n if k > len(arr):\n raise ValueError(\"k should be less than or equal to the length of the array\")\n \n # Reverse the first k elements\n arr[:k] = arr[:k][::-1]\n \n return arr", "matching_cluster_idx": 13}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n Reverses an array up to a given position `k`.\n \n Parameters:\n arr (list): The input array.\n k (int): The position up to which the array should be reversed.\n \n Returns:\n list: The array with the first `k` elements reversed.\n \"\"\"\n if k > len(arr):\n raise ValueError(\"k should be less than or equal to the length of the array\")\n \n # Reverse the first k elements\n arr[:k] = arr[:k][::-1]\n \n return arr", "matching_cluster_idx": 13}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n Reverses the array up to the given position k.\n \n Parameters:\n arr (list): The input array.\n k (int): The position up to which the array should be reversed.\n \n Returns:\n list: The array with the first k elements reversed.\n \"\"\"\n if k > len(arr):\n raise ValueError(\"k should be less than or equal to the length of the array\")\n \n # Reverse the first k elements\n arr[:k] = arr[:k][::-1]\n \n return arr", "matching_cluster_idx": 13}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n Reverses the array up to the given position k.\n \n Parameters:\n arr (list): The input array.\n k (int): The position up to which the array should be reversed.\n \n Returns:\n list: The array with the first k elements reversed.\n \"\"\"\n # Ensure k is within the bounds of the array\n if k > len(arr):\n raise ValueError(\"k should be less than or equal to the length of the array\")\n \n # Reverse the first k elements\n arr[:k] = arr[:k][::-1]\n \n return arr", "matching_cluster_idx": 13}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n Reverses an array up to a given position `k`.\n \n Parameters:\n arr (list): The input array.\n k (int): The position up to which the array should be reversed.\n \n Returns:\n list: The array with the first `k` elements reversed.\n \"\"\"\n if k > len(arr):\n raise ValueError(\"Position k exceeds the length of the array.\")\n \n # Reverse the first k elements\n arr[:k] = arr[:k][::-1]\n \n return arr", "matching_cluster_idx": 13}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n Reverses an array up to a given position `k`.\n \n Parameters:\n arr (list): The input array.\n k (int): The position up to which the array should be reversed.\n \n Returns:\n list: The array with the first `k` elements reversed.\n \"\"\"\n if k > len(arr):\n raise ValueError(\"Position k exceeds the length of the array.\")\n \n # Reverse the first `k` elements\n arr[:k] = arr[:k][::-1]\n return arr", "matching_cluster_idx": 13}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n Reverses the array up to the given position k.\n \n Parameters:\n arr (list): The input array.\n k (int): The position up to which the array should be reversed.\n \n Returns:\n list: The array with the first k elements reversed.\n \"\"\"\n # Reverse the first k elements\n arr[:k] = arr[:k][::-1]\n return arr", "matching_cluster_idx": 13}]}, "Mbpp/720": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def add_dict_to_tuple(tup, dictionary):\n \"\"\"\n Adds a dictionary to the end of a tuple.\n \n Parameters:\n tup (tuple): The original tuple.\n dictionary (dict): The dictionary to add to the tuple.\n \n Returns:\n tuple: A new tuple with the dictionary appended at the end.\n \"\"\"\n return tup + (dictionary,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(tup, dictionary):\n \"\"\"\n Adds a dictionary to the end of a tuple.\n\n Parameters:\n tup (tuple): The original tuple.\n dictionary (dict): The dictionary to add to the tuple.\n\n Returns:\n tuple: The new tuple with the dictionary appended.\n \"\"\"\n return tup + (dictionary,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(t, d):\n \"\"\"\n Adds a dictionary to a tuple and returns the resulting tuple.\n \n Parameters:\n t (tuple): The original tuple.\n d (dict): The dictionary to add to the tuple.\n \n Returns:\n tuple: The new tuple with the dictionary appended.\n \"\"\"\n return t + (d,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(tup, dictionary):\n \"\"\"\n Adds a dictionary to the end of a tuple.\n\n Parameters:\n tup (tuple): The original tuple.\n dictionary (dict): The dictionary to add to the tuple.\n\n Returns:\n tuple: The new tuple with the dictionary appended.\n \"\"\"\n return tup + (dictionary,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(tup, dictionary):\n \"\"\"\n Adds a dictionary to the end of a tuple.\n\n Parameters:\n tup (tuple): The original tuple.\n dictionary (dict): The dictionary to add to the tuple.\n\n Returns:\n tuple: A new tuple with the dictionary appended at the end.\n \"\"\"\n return tup + (dictionary,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(tup, dictionary):\n \"\"\"\n Adds a dictionary to the end of a tuple.\n\n Args:\n tup (tuple): The original tuple.\n dictionary (dict): The dictionary to add to the tuple.\n\n Returns:\n tuple: The new tuple with the dictionary appended.\n \"\"\"\n return tup + (dictionary,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(t, d):\n \"\"\"\n Adds a dictionary to the end of a tuple and returns the resulting tuple.\n \n Parameters:\n t (tuple): The original tuple.\n d (dict): The dictionary to add to the tuple.\n \n Returns:\n tuple: The new tuple with the dictionary appended.\n \"\"\"\n return t + (d,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(t, d):\n \"\"\"\n Adds a dictionary to a tuple and returns the resulting tuple.\n \n Parameters:\n t (tuple): The original tuple.\n d (dict): The dictionary to add to the tuple.\n \n Returns:\n tuple: The new tuple with the dictionary appended.\n \"\"\"\n return t + (d,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(t, d):\n \"\"\"\n Adds a dictionary to the end of a tuple.\n\n Parameters:\n t (tuple): The original tuple.\n d (dict): The dictionary to add to the tuple.\n\n Returns:\n tuple: The new tuple with the dictionary appended.\n \"\"\"\n return t + (d,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(t, d):\n \"\"\"\n Adds a dictionary to the end of a tuple.\n\n Parameters:\n t (tuple): The original tuple.\n d (dict): The dictionary to add to the tuple.\n\n Returns:\n tuple: A new tuple with the dictionary appended.\n \"\"\"\n return t + (d,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(tup, dictionary):\n \"\"\"\n Adds a dictionary to the end of a tuple.\n\n Parameters:\n tup (tuple): The original tuple.\n dictionary (dict): The dictionary to add to the tuple.\n\n Returns:\n tuple: The new tuple with the dictionary appended.\n \"\"\"\n return tup + (dictionary,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(t, d):\n \"\"\"\n Adds a dictionary to a tuple and returns the resulting tuple.\n \n Parameters:\n t (tuple): The original tuple.\n d (dict): The dictionary to add to the tuple.\n \n Returns:\n tuple: The new tuple with the dictionary appended.\n \"\"\"\n return t + (d,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(t, d):\n \"\"\"\n Adds a dictionary to a tuple and returns the resulting tuple.\n\n Parameters:\n t (tuple): The original tuple.\n d (dict): The dictionary to add to the tuple.\n\n Returns:\n tuple: The new tuple with the dictionary appended.\n \"\"\"\n return t + (d,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(t, d):\n \"\"\"\n Adds a dictionary to the end of a tuple.\n\n Parameters:\n t (tuple): The original tuple.\n d (dict): The dictionary to add to the tuple.\n\n Returns:\n tuple: A new tuple with the dictionary appended at the end.\n \"\"\"\n return t + (d,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(t, d):\n \"\"\"\n Adds a dictionary to a tuple and returns the resulting tuple.\n \n Parameters:\n t (tuple): The original tuple.\n d (dict): The dictionary to add to the tuple.\n \n Returns:\n tuple: The new tuple with the dictionary appended.\n \"\"\"\n return t + (d,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(t, d):\n \"\"\"\n Adds a dictionary to the end of a tuple.\n\n Parameters:\n t (tuple): The original tuple.\n d (dict): The dictionary to add to the tuple.\n\n Returns:\n tuple: The new tuple with the dictionary appended.\n \"\"\"\n return t + (d,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(tup, dictionary):\n \"\"\"\n Adds a dictionary to the end of a tuple.\n\n Parameters:\n tup (tuple): The original tuple.\n dictionary (dict): The dictionary to be added to the tuple.\n\n Returns:\n tuple: A new tuple with the dictionary appended at the end.\n \"\"\"\n return tup + (dictionary,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(tup, dictionary):\n \"\"\"\n Adds a dictionary to the end of a tuple.\n\n Parameters:\n tup (tuple): The original tuple.\n dictionary (dict): The dictionary to add to the tuple.\n\n Returns:\n tuple: The new tuple with the dictionary appended.\n \"\"\"\n return tup + (dictionary,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(tup, dictionary):\n \"\"\"\n Adds a dictionary to the end of a tuple.\n\n Parameters:\n tup (tuple): The original tuple.\n dictionary (dict): The dictionary to add to the tuple.\n\n Returns:\n tuple: A new tuple with the dictionary appended at the end.\n \"\"\"\n return tup + (dictionary,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(t, d):\n \"\"\"\n Adds a dictionary to the end of a tuple.\n\n Parameters:\n t (tuple): The original tuple.\n d (dict): The dictionary to add to the tuple.\n\n Returns:\n tuple: A new tuple with the dictionary appended at the end.\n \"\"\"\n return t + (d,)", "matching_cluster_idx": 4}]}, "Mbpp/725": {"dps": 88.96174863387978, "dps_norm": 82.5, "pass@1": 100.0, "profiled": [{"solution": "def extract_quotation(input_string):\n import re\n # Use regular expression to find all substrings between double quotes\n matches = re.findall(r'\"([^\"]*)\"', input_string)\n return matches", "matching_cluster_idx": 6}, {"solution": "def extract_quotation(input_string):\n import re\n # Use regular expression to find all substrings between double quotes\n matches = re.findall(r'\"([^\"]*)\"', input_string)\n return matches", "matching_cluster_idx": 6}, {"solution": "def extract_quotation(s):\n import re\n # Use regular expression to find all substrings between double quotes\n return re.findall(r'\"([^\"]*)\"', s)", "matching_cluster_idx": 5}, {"solution": "def extract_quotation(input_string):\n import re\n # Use regular expression to find all substrings between double quotes\n matches = re.findall(r'\"([^\"]*)\"', input_string)\n return matches", "matching_cluster_idx": 6}, {"solution": "def extract_quotation(input_string):\n import re\n # Use regular expression to find all sequences of characters between double quotes\n matches = re.findall(r'\"([^\"]*)\"', input_string)\n return matches", "matching_cluster_idx": 6}, {"solution": "def extract_quotation(s):\n import re\n # Use regular expression to find all substrings between double quotes\n matches = re.findall(r'\"([^\"]*)\"', s)\n return matches", "matching_cluster_idx": 6}, {"solution": "def extract_quotation(input_string):\n import re\n # Use regular expression to find all sequences between double quotes\n matches = re.findall(r'\"([^\"]*)\"', input_string)\n return matches", "matching_cluster_idx": 5}, {"solution": "def extract_quotation(input_string):\n import re\n # Use regular expression to find all substrings between double quotes\n matches = re.findall(r'\"([^\"]*)\"', input_string)\n return matches", "matching_cluster_idx": 6}, {"solution": "def extract_quotation(s):\n import re\n # Use regular expression to find all substrings between double quotes\n matches = re.findall(r'\"([^\"]*)\"', s)\n return matches", "matching_cluster_idx": 6}, {"solution": "def extract_quotation(s):\n import re\n # Use regular expression to find all substrings between double quotes\n return re.findall(r'\"([^\"]*)\"', s)", "matching_cluster_idx": 5}, {"solution": "def extract_quotation(s):\n import re\n # Use regular expression to find all substrings between double quotes\n return re.findall(r'\"([^\"]*)\"', s)", "matching_cluster_idx": 5}, {"solution": "def extract_quotation(input_string):\n import re\n # Use regular expression to find all sequences of characters between double quotes\n matches = re.findall(r'\"([^\"]*)\"', input_string)\n return matches", "matching_cluster_idx": 6}, {"solution": "def extract_quotation(input_string):\n import re\n # Use regular expression to find all substrings between double quotes\n matches = re.findall(r'\"([^\"]*)\"', input_string)\n return matches", "matching_cluster_idx": 6}, {"solution": "def extract_quotation(input_string):\n import re\n # Use regular expression to find all sequences between double quotes\n matches = re.findall(r'\"([^\"]*)\"', input_string)\n return matches", "matching_cluster_idx": 5}, {"solution": "def extract_quotation(input_string):\n import re\n # Use regular expression to find all sequences between double quotes\n matches = re.findall(r'\"([^\"]*)\"', input_string)\n return matches", "matching_cluster_idx": 5}, {"solution": "def extract_quotation(s):\n import re\n # Use regular expression to find all sequences of characters within double quotes\n return re.findall(r'\"([^\"]*)\"', s)", "matching_cluster_idx": 6}, {"solution": "def extract_quotation(s):\n import re\n # Use regular expression to find all substrings between double quotes\n return re.findall(r'\"([^\"]*)\"', s)", "matching_cluster_idx": 5}, {"solution": "def extract_quotation(s):\n import re\n # Use regular expression to find all substrings between double quotes\n return re.findall(r'\"([^\"]*)\"', s)", "matching_cluster_idx": 5}, {"solution": "def extract_quotation(input_string):\n import re\n # Use regular expression to find all substrings between double quotes\n matches = re.findall(r'\"([^\"]*)\"', input_string)\n return matches", "matching_cluster_idx": 6}, {"solution": "def extract_quotation(input_string):\n import re\n # Use regular expression to find all substrings between double quotes\n matches = re.findall(r'\"([^\"]*)\"', input_string)\n return matches", "matching_cluster_idx": 6}]}, "Mbpp/732": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def replace_specialchar(text):\n # Define the characters to be replaced\n special_chars = [' ', ',', '.']\n \n # Iterate over each character in the text\n for char in special_chars:\n # Replace the character with a colon\n text = text.replace(char, ':')\n \n return text", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(text):\n # Define the characters to be replaced\n special_chars = [' ', ',', '.']\n \n # Iterate through each character in the text\n for char in special_chars:\n # Replace the character with a colon\n text = text.replace(char, ':')\n \n return text", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(text):\n # Define the characters to be replaced\n special_chars = [' ', ',', '.']\n \n # Iterate through each character in the text\n for char in special_chars:\n # Replace the character with a colon\n text = text.replace(char, ':')\n \n return text", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(text):\n # Define the characters to be replaced\n special_chars = [' ', ',', '.']\n \n # Iterate through each character in the text\n for char in special_chars:\n # Replace the character with a colon\n text = text.replace(char, ':')\n \n return text", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(text):\n # Define the characters to be replaced\n special_chars = [' ', ',', '.']\n \n # Iterate through each character in the text\n for char in special_chars:\n # Replace the character with a colon\n text = text.replace(char, ':')\n \n return text", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(text):\n # Define the characters to be replaced\n special_chars = [' ', ',', '.']\n \n # Iterate through each character in the text\n for char in special_chars:\n # Replace the character with a colon\n text = text.replace(char, ':')\n \n return text", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(text):\n # Define the characters to be replaced\n special_chars = [' ', ',', '.']\n \n # Replace each special character with a colon\n for char in special_chars:\n text = text.replace(char, ':')\n \n return text", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(text):\n # Define the characters to be replaced\n special_chars = [' ', ',', '.']\n \n # Iterate through each character in the text\n for char in special_chars:\n # Replace the character with a colon\n text = text.replace(char, ':')\n \n return text", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(text):\n # Define the characters to be replaced\n special_chars = [' ', ',', '.']\n \n # Iterate through each character in the text\n for char in special_chars:\n # Replace the character with a colon\n text = text.replace(char, ':')\n \n return text", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(text):\n # Define the characters to be replaced\n special_chars = [' ', ',', '.']\n \n # Iterate through each character in the text\n for char in special_chars:\n # Replace the character with a colon\n text = text.replace(char, ':')\n \n return text", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(text):\n # Replace spaces, commas, and dots with a colon\n return text.replace(' ', ':').replace(',', ':').replace('.', ':')", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(text):\n # Define the characters to be replaced\n special_chars = [' ', ',', '.']\n \n # Iterate through each character in the text\n for char in special_chars:\n # Replace the character with a colon\n text = text.replace(char, ':')\n \n return text", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(text):\n # Define the characters to be replaced\n special_chars = [' ', ',', '.']\n \n # Iterate through each character in the text\n for char in special_chars:\n # Replace the character with a colon\n text = text.replace(char, ':')\n \n return text", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(text):\n # Define the characters to be replaced\n special_chars = [' ', ',', '.']\n \n # Iterate through each character in the text\n for char in special_chars:\n # Replace the character with a colon\n text = text.replace(char, ':')\n \n return text", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(text):\n # Define the characters to be replaced\n special_chars = [' ', ',', '.']\n \n # Iterate through each character in the text\n for char in special_chars:\n # Replace the character with a colon\n text = text.replace(char, ':')\n \n return text", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(text):\n # Define the characters to be replaced\n special_chars = [' ', ',', '.']\n \n # Iterate through each character in the text\n for char in special_chars:\n # Replace the character with a colon\n text = text.replace(char, ':')\n \n return text", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(text):\n # Define the characters to be replaced\n special_chars = [' ', ',', '.']\n \n # Iterate through each character in the text\n for char in special_chars:\n # Replace the character with a colon\n text = text.replace(char, ':')\n \n return text", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(text):\n # Define the characters to be replaced\n special_chars = [' ', ',', '.']\n \n # Iterate through each character in the text\n for char in special_chars:\n # Replace the character with a colon\n text = text.replace(char, ':')\n \n return text", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(text):\n # Define the characters to be replaced\n special_chars = [' ', ',', '.']\n \n # Iterate through each character in the text\n for char in special_chars:\n # Replace the character with a colon\n text = text.replace(char, ':')\n \n return text", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(text):\n # Replace spaces, commas, and dots with a colon\n return text.replace(' ', ':').replace(',', ':').replace('.', ':')", "matching_cluster_idx": 9}]}, "Mbpp/740": {"dps": 83.63636363636364, "dps_norm": 66.66666666666667, "pass@1": 100.0, "profiled": [{"solution": "def tuple_to_dict(t):\n \"\"\"\n Convert the given tuple to a key-value dictionary using adjacent elements.\n \n Args:\n t (tuple): The input tuple.\n \n Returns:\n dict: The resulting dictionary.\n \"\"\"\n # Check if the tuple has an even number of elements\n if len(t) % 2 != 0:\n raise ValueError(\"The input tuple must have an even number of elements.\")\n \n # Create the dictionary by iterating over the tuple in steps of 2\n return {t[i]: t[i+1] for i in range(0, len(t), 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(tup):\n \"\"\"\n Convert the given tuple to a key-value dictionary using adjacent elements.\n \n :param tup: A tuple of elements.\n :return: A dictionary where each key is an element from the tuple and its value is the next element.\n \"\"\"\n # Ensure the tuple has an even number of elements\n if len(tup) % 2 != 0:\n raise ValueError(\"The tuple must have an even number of elements.\")\n \n # Create the dictionary by iterating over the tuple in steps of 2\n return {tup[i]: tup[i + 1] for i in range(0, len(tup), 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(tup):\n \"\"\"\n Convert the given tuple to a key-value dictionary using adjacent elements.\n \n Args:\n tup (tuple): The input tuple.\n \n Returns:\n dict: The resulting dictionary.\n \"\"\"\n # Ensure the tuple has an even number of elements\n if len(tup) % 2 != 0:\n raise ValueError(\"The tuple must have an even number of elements.\")\n \n # Create the dictionary by iterating over the tuple in steps of 2\n return {tup[i]: tup[i+1] for i in range(0, len(tup), 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(tup):\n \"\"\"\n Convert the given tuple to a key-value dictionary using adjacent elements.\n \n Args:\n tup (tuple): The input tuple.\n \n Returns:\n dict: The resulting dictionary.\n \"\"\"\n # Check if the tuple has an even number of elements\n if len(tup) % 2 != 0:\n raise ValueError(\"The input tuple must have an even number of elements.\")\n \n # Create the dictionary by iterating over the tuple in steps of 2\n return {tup[i]: tup[i+1] for i in range(0, len(tup), 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(t):\n \"\"\"\n Convert the given tuple to a key-value dictionary using adjacent elements.\n \n Args:\n t (tuple): The input tuple.\n \n Returns:\n dict: The resulting dictionary.\n \"\"\"\n if len(t) % 2 != 0:\n raise ValueError(\"The input tuple must have an even number of elements.\")\n \n return {t[i]: t[i+1] for i in range(0, len(t), 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(tup):\n \"\"\"\n Convert the given tuple to a key-value dictionary using adjacent elements.\n \n Args:\n tup (tuple): The input tuple.\n \n Returns:\n dict: The resulting dictionary.\n \"\"\"\n # Check if the tuple has an even number of elements\n if len(tup) % 2 != 0:\n raise ValueError(\"The input tuple must have an even number of elements.\")\n \n # Create the dictionary by iterating over the tuple in steps of 2\n return {tup[i]: tup[i + 1] for i in range(0, len(tup), 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(tup):\n \"\"\"\n Convert the given tuple to a key-value dictionary using adjacent elements.\n \n Args:\n tup (tuple): The input tuple containing key-value pairs as adjacent elements.\n \n Returns:\n dict: A dictionary where each key is an element from the tuple and its value is the next element.\n \"\"\"\n # Initialize an empty dictionary\n result_dict = {}\n \n # Iterate over the tuple in steps of 2\n for i in range(0, len(tup), 2):\n # Add the key-value pair to the dictionary\n result_dict[tup[i]] = tup[i + 1]\n \n return result_dict", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(tup):\n \"\"\"\n Convert the given tuple to a key-value dictionary using adjacent elements.\n \n Args:\n tup (tuple): The input tuple.\n \n Returns:\n dict: The resulting dictionary.\n \"\"\"\n # Check if the tuple has an even number of elements\n if len(tup) % 2 != 0:\n raise ValueError(\"The input tuple must have an even number of elements.\")\n \n # Create the dictionary using adjacent elements\n result_dict = {}\n for i in range(0, len(tup), 2):\n result_dict[tup[i]] = tup[i + 1]\n \n return result_dict", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(t):\n \"\"\"\n Convert the given tuple to a key-value dictionary using adjacent elements.\n \n Args:\n t (tuple): The input tuple.\n \n Returns:\n dict: The resulting dictionary.\n \"\"\"\n # Check if the tuple has an even number of elements\n if len(t) % 2 != 0:\n raise ValueError(\"The input tuple must have an even number of elements.\")\n \n # Create the dictionary by iterating over the tuple in steps of 2\n return {t[i]: t[i+1] for i in range(0, len(t), 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(tup):\n \"\"\"\n Convert the given tuple to a key-value dictionary using adjacent elements.\n \n Args:\n tup (tuple): The input tuple.\n \n Returns:\n dict: The resulting dictionary.\n \"\"\"\n # Check if the tuple has an even number of elements\n if len(tup) % 2 != 0:\n raise ValueError(\"The input tuple must have an even number of elements.\")\n \n # Create the dictionary using adjacent elements\n result_dict = {}\n for i in range(0, len(tup), 2):\n result_dict[tup[i]] = tup[i + 1]\n \n return result_dict", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(t):\n \"\"\"\n Convert the given tuple to a key-value dictionary using adjacent elements.\n \n Args:\n t (tuple): The input tuple.\n \n Returns:\n dict: The resulting dictionary.\n \"\"\"\n # Check if the tuple has an even number of elements\n if len(t) % 2 != 0:\n raise ValueError(\"The input tuple must have an even number of elements.\")\n \n # Create the dictionary by iterating over the tuple in steps of 2\n return {t[i]: t[i+1] for i in range(0, len(t), 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(tup):\n \"\"\"\n Convert the given tuple to a key-value dictionary using adjacent elements.\n \n Args:\n tup (tuple): The input tuple.\n \n Returns:\n dict: The resulting dictionary.\n \"\"\"\n if len(tup) % 2 != 0:\n raise ValueError(\"The input tuple must have an even number of elements.\")\n \n return {tup[i]: tup[i+1] for i in range(0, len(tup), 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(t):\n \"\"\"\n Convert the given tuple to a key-value dictionary using adjacent elements.\n \n :param t: A tuple of elements.\n :return: A dictionary where each key is an element from the tuple and its value is the next element.\n \"\"\"\n # Check if the tuple has an even number of elements\n if len(t) % 2 != 0:\n raise ValueError(\"The tuple must have an even number of elements to form key-value pairs.\")\n \n # Create the dictionary by iterating over the tuple in steps of 2\n return {t[i]: t[i+1] for i in range(0, len(t), 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(tup):\n \"\"\"\n Convert the given tuple to a key-value dictionary using adjacent elements.\n \n Parameters:\n tup (tuple): The input tuple containing elements to be converted to a dictionary.\n \n Returns:\n dict: A dictionary where each key is an element from the tuple and its value is the next element in the tuple.\n \"\"\"\n # Initialize an empty dictionary\n result_dict = {}\n \n # Iterate over the tuple in steps of 2\n for i in range(0, len(tup) - 1, 2):\n # Assign the current element as the key and the next element as the value\n result_dict[tup[i]] = tup[i + 1]\n \n return result_dict", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(tup):\n \"\"\"\n Convert the given tuple to a key-value dictionary using adjacent elements.\n \n Args:\n tup (tuple): The input tuple.\n \n Returns:\n dict: The resulting dictionary.\n \"\"\"\n # Check if the tuple has an even number of elements\n if len(tup) % 2 != 0:\n raise ValueError(\"The input tuple must have an even number of elements.\")\n \n # Create the dictionary by iterating over the tuple in steps of 2\n return {tup[i]: tup[i+1] for i in range(0, len(tup), 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(t):\n \"\"\"\n Convert the given tuple to a key-value dictionary using adjacent elements.\n \n Args:\n t (tuple): The input tuple.\n \n Returns:\n dict: The resulting dictionary.\n \"\"\"\n # Check if the tuple has an even number of elements\n if len(t) % 2 != 0:\n raise ValueError(\"The input tuple must have an even number of elements.\")\n \n # Create the dictionary by iterating over the tuple in steps of 2\n return {t[i]: t[i+1] for i in range(0, len(t), 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(t):\n \"\"\"\n Converts a given tuple to a key-value dictionary using adjacent elements.\n \n :param t: A tuple containing elements to be converted to a dictionary.\n :return: A dictionary where each key is an element from the tuple and its value is the next element.\n \"\"\"\n # Check if the tuple has an even number of elements\n if len(t) % 2 != 0:\n raise ValueError(\"Tuple must have an even number of elements to form key-value pairs.\")\n \n # Create the dictionary using adjacent elements\n return {t[i]: t[i+1] for i in range(0, len(t), 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(t):\n \"\"\"\n Convert the given tuple to a key-value dictionary using adjacent elements.\n \n Args:\n t (tuple): The input tuple.\n \n Returns:\n dict: The resulting dictionary.\n \"\"\"\n # Ensure the tuple has an even number of elements\n if len(t) % 2 != 0:\n raise ValueError(\"Tuple must have an even number of elements to form key-value pairs.\")\n \n # Create the dictionary by iterating over the tuple in steps of 2\n return {t[i]: t[i+1] for i in range(0, len(t), 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(tup):\n \"\"\"\n Convert the given tuple to a key-value dictionary using adjacent elements.\n \n Args:\n tup (tuple): The input tuple.\n \n Returns:\n dict: The resulting dictionary.\n \"\"\"\n # Ensure the tuple has an even number of elements\n if len(tup) % 2 != 0:\n raise ValueError(\"The input tuple must have an even number of elements.\")\n \n # Create the dictionary by iterating over the tuple in steps of 2\n return {tup[i]: tup[i + 1] for i in range(0, len(tup), 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(tup):\n \"\"\"\n Convert the given tuple to a key-value dictionary using adjacent elements.\n \n Args:\n tup (tuple): The input tuple.\n \n Returns:\n dict: The resulting dictionary.\n \"\"\"\n # Ensure the tuple has an even number of elements\n if len(tup) % 2 != 0:\n raise ValueError(\"The input tuple must have an even number of elements.\")\n \n # Create the dictionary by pairing adjacent elements\n return {tup[i]: tup[i + 1] for i in range(0, len(tup), 2)}", "matching_cluster_idx": 5}]}, "Mbpp/744": {"dps": 28.28767123287671, "dps_norm": 49.166666666666664, "pass@1": 100.0, "profiled": [{"solution": "def check_none(tup):\n \"\"\"\n Check if the given tuple has any None value.\n\n Args:\n tup (tuple): The tuple to check.\n\n Returns:\n bool: True if the tuple contains any None value, False otherwise.\n \"\"\"\n return any(item is None for item in tup)", "matching_cluster_idx": 2}, {"solution": "def check_none(tup):\n \"\"\"\n Check if the given tuple has any None value.\n\n Parameters:\n tup (tuple): The tuple to be checked.\n\n Returns:\n bool: True if the tuple contains any None value, False otherwise.\n \"\"\"\n return any(item is None for item in tup)", "matching_cluster_idx": 1}, {"solution": "def check_none(tup):\n \"\"\"\n Check if the given tuple has any None value.\n\n Parameters:\n tup (tuple): The tuple to be checked.\n\n Returns:\n bool: True if the tuple contains any None value, False otherwise.\n \"\"\"\n return any(item is None for item in tup)", "matching_cluster_idx": 1}, {"solution": "def check_none(tup):\n \"\"\"\n Check if the given tuple has any None value.\n\n Args:\n tup (tuple): The tuple to be checked.\n\n Returns:\n bool: True if the tuple contains any None value, False otherwise.\n \"\"\"\n return any(item is None for item in tup)", "matching_cluster_idx": 2}, {"solution": "def check_none(tup):\n \"\"\"\n Function to check if the given tuple has any None value or not.\n \n Parameters:\n tup (tuple): The tuple to be checked.\n \n Returns:\n bool: True if the tuple contains any None value, False otherwise.\n \"\"\"\n return any(item is None for item in tup)", "matching_cluster_idx": 2}, {"solution": "def check_none(tup):\n \"\"\"\n Check if the given tuple has any None value.\n\n Parameters:\n tup (tuple): The tuple to be checked.\n\n Returns:\n bool: True if the tuple contains any None value, False otherwise.\n \"\"\"\n return any(item is None for item in tup)", "matching_cluster_idx": 1}, {"solution": "def check_none(tup):\n \"\"\"\n Check if the given tuple has any None value.\n\n Args:\n tup (tuple): The tuple to be checked.\n\n Returns:\n bool: True if the tuple contains any None value, False otherwise.\n \"\"\"\n return any(item is None for item in tup)", "matching_cluster_idx": 2}, {"solution": "def check_none(tup):\n \"\"\"\n Function to check if the given tuple has any None value or not.\n \n Parameters:\n tup (tuple): The tuple to be checked.\n \n Returns:\n bool: True if the tuple contains any None value, False otherwise.\n \"\"\"\n return any(item is None for item in tup)", "matching_cluster_idx": 2}, {"solution": "def check_none(tup):\n \"\"\"\n Check if the given tuple has any None value.\n\n Parameters:\n tup (tuple): The tuple to be checked.\n\n Returns:\n bool: True if the tuple contains any None value, False otherwise.\n \"\"\"\n return any(item is None for item in tup)", "matching_cluster_idx": 1}, {"solution": "def check_none(tup):\n \"\"\"\n Check if the given tuple has any None value.\n\n Parameters:\n tup (tuple): The tuple to be checked.\n\n Returns:\n bool: True if the tuple contains any None value, False otherwise.\n \"\"\"\n return any(item is None for item in tup)", "matching_cluster_idx": 1}, {"solution": "def check_none(tup):\n \"\"\"\n Function to check if the given tuple has any None value or not.\n \n Args:\n tup (tuple): The tuple to be checked.\n \n Returns:\n bool: True if the tuple contains any None value, False otherwise.\n \"\"\"\n return any(item is None for item in tup)", "matching_cluster_idx": 2}, {"solution": "def check_none(tup):\n \"\"\"\n Check if the given tuple has any None value.\n\n Args:\n tup (tuple): The tuple to be checked.\n\n Returns:\n bool: True if the tuple contains any None value, False otherwise.\n \"\"\"\n return any(item is None for item in tup)", "matching_cluster_idx": 2}, {"solution": "def check_none(tup):\n \"\"\"\n Check if the given tuple has any None value.\n\n Args:\n tup (tuple): The tuple to check.\n\n Returns:\n bool: True if the tuple contains any None value, False otherwise.\n \"\"\"\n return any(item is None for item in tup)", "matching_cluster_idx": 2}, {"solution": "def check_none(tup):\n \"\"\"\n Check if the given tuple has any None value.\n\n Args:\n tup (tuple): The tuple to check.\n\n Returns:\n bool: True if the tuple contains any None value, False otherwise.\n \"\"\"\n return None in tup", "matching_cluster_idx": 5}, {"solution": "def check_none(tup):\n \"\"\"\n Check if the given tuple has any None value.\n\n Args:\n tup (tuple): The tuple to check.\n\n Returns:\n bool: True if the tuple contains any None value, False otherwise.\n \"\"\"\n return any(item is None for item in tup)", "matching_cluster_idx": 2}, {"solution": "def check_none(tup):\n \"\"\"\n Check if the given tuple has any None value.\n\n Args:\n tup (tuple): The tuple to check.\n\n Returns:\n bool: True if the tuple contains any None value, False otherwise.\n \"\"\"\n return any(item is None for item in tup)", "matching_cluster_idx": 2}, {"solution": "def check_none(tup):\n \"\"\"\n Check if the given tuple has any None value.\n\n Parameters:\n tup (tuple): The tuple to be checked.\n\n Returns:\n bool: True if the tuple contains any None value, False otherwise.\n \"\"\"\n return any(item is None for item in tup)", "matching_cluster_idx": 1}, {"solution": "def check_none(tup):\n \"\"\"\n Check if the given tuple has any None value.\n\n Args:\n tup (tuple): The tuple to check.\n\n Returns:\n bool: True if the tuple contains any None value, False otherwise.\n \"\"\"\n return None in tup", "matching_cluster_idx": 5}, {"solution": "def check_none(tup):\n \"\"\"\n Check if the given tuple has any None value.\n\n Args:\n tup (tuple): The tuple to check.\n\n Returns:\n bool: True if the tuple contains any None value, False otherwise.\n \"\"\"\n return any(item is None for item in tup)", "matching_cluster_idx": 2}, {"solution": "def check_none(tup):\n \"\"\"\n Check if the given tuple has any None value.\n\n Parameters:\n tup (tuple): The tuple to be checked.\n\n Returns:\n bool: True if the tuple contains any None value, False otherwise.\n \"\"\"\n return any(item is None for item in tup)", "matching_cluster_idx": 1}]}, "Mbpp/750": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def add_tuple(lst, tup):\n \"\"\"\n Adds the elements of the given tuple to the end of the given list.\n \n Parameters:\n lst (list): The list to which the tuple elements will be added.\n tup (tuple): The tuple whose elements will be added to the list.\n \n Returns:\n list: The modified list with the tuple elements appended.\n \"\"\"\n lst.extend(tup)\n return lst", "matching_cluster_idx": 5}, {"solution": "def add_tuple(lst, tup):\n \"\"\"\n Adds the elements of the given tuple to the end of the given list.\n \n Parameters:\n lst (list): The list to which the tuple elements will be added.\n tup (tuple): The tuple whose elements will be added to the list.\n \n Returns:\n list: The modified list with the tuple elements appended.\n \"\"\"\n lst.extend(tup)\n return lst", "matching_cluster_idx": 5}, {"solution": "def add_tuple(lst, tup):\n \"\"\"\n Adds the elements of the given tuple to the end of the given list.\n \n Parameters:\n lst (list): The list to which the tuple elements will be added.\n tup (tuple): The tuple whose elements will be added to the list.\n \n Returns:\n list: The modified list with the tuple elements appended.\n \"\"\"\n lst.extend(tup)\n return lst", "matching_cluster_idx": 5}, {"solution": "def add_tuple(lst, tup):\n \"\"\"\n Adds the elements of the given tuple to the end of the given list.\n \n Parameters:\n lst (list): The list to which the tuple elements will be added.\n tup (tuple): The tuple whose elements will be added to the list.\n \n Returns:\n list: The modified list with the tuple elements appended.\n \"\"\"\n lst.extend(tup)\n return lst", "matching_cluster_idx": 5}, {"solution": "def add_tuple(lst, tup):\n \"\"\"\n Adds the elements of the given tuple to the end of the given list.\n\n Parameters:\n lst (list): The list to which the tuple elements will be added.\n tup (tuple): The tuple whose elements will be added to the list.\n\n Returns:\n list: The modified list with the tuple elements appended.\n \"\"\"\n lst.extend(tup)\n return lst", "matching_cluster_idx": 5}, {"solution": "def add_tuple(lst, tup):\n \"\"\"\n Adds the elements of the given tuple to the end of the given list.\n \n Parameters:\n lst (list): The list to which the tuple elements will be added.\n tup (tuple): The tuple whose elements will be added to the list.\n \n Returns:\n list: The modified list with the tuple elements appended.\n \"\"\"\n lst.extend(tup)\n return lst", "matching_cluster_idx": 5}, {"solution": "def add_tuple(lst, tup):\n \"\"\"\n Adds the elements of the given tuple to the end of the given list.\n \n Parameters:\n lst (list): The list to which the tuple elements will be added.\n tup (tuple): The tuple whose elements will be added to the list.\n \n Returns:\n list: The modified list with the tuple elements appended.\n \"\"\"\n lst.extend(tup)\n return lst", "matching_cluster_idx": 5}, {"solution": "def add_tuple(lst, tup):\n \"\"\"\n Adds the elements of the given tuple to the end of the given list.\n \n Parameters:\n lst (list): The list to which the tuple elements will be added.\n tup (tuple): The tuple whose elements will be added to the list.\n \n Returns:\n list: The modified list with the tuple elements appended.\n \"\"\"\n lst.extend(tup)\n return lst", "matching_cluster_idx": 5}, {"solution": "def add_tuple(lst, tup):\n \"\"\"\n Adds the elements of the given tuple to the end of the given list.\n \n Parameters:\n lst (list): The list to which the tuple elements will be added.\n tup (tuple): The tuple whose elements will be added to the list.\n \n Returns:\n list: The modified list with the tuple elements appended.\n \"\"\"\n lst.extend(tup)\n return lst", "matching_cluster_idx": 5}, {"solution": "def add_tuple(lst, tup):\n \"\"\"\n Adds the elements of the given tuple to the end of the given list.\n\n Parameters:\n lst (list): The list to which the tuple elements will be added.\n tup (tuple): The tuple whose elements will be added to the list.\n\n Returns:\n list: The modified list with the tuple elements appended.\n \"\"\"\n lst.extend(tup)\n return lst", "matching_cluster_idx": 5}, {"solution": "def add_tuple(lst, tup):\n \"\"\"\n Adds the elements of the given tuple to the end of the given list.\n \n Parameters:\n lst (list): The list to which the tuple elements will be added.\n tup (tuple): The tuple whose elements will be added to the list.\n \n Returns:\n list: The modified list with the tuple elements appended.\n \"\"\"\n lst.extend(tup)\n return lst", "matching_cluster_idx": 5}, {"solution": "def add_tuple(lst, tup):\n \"\"\"\n Adds the elements of the given tuple to the end of the given list.\n \n Parameters:\n lst (list): The list to which the tuple elements will be added.\n tup (tuple): The tuple whose elements will be added to the list.\n \n Returns:\n list: The modified list with the tuple elements appended.\n \"\"\"\n lst.extend(tup)\n return lst", "matching_cluster_idx": 5}, {"solution": "def add_tuple(lst, tup):\n \"\"\"\n Adds the elements of the given tuple to the end of the given list.\n\n Parameters:\n lst (list): The list to which the tuple elements will be added.\n tup (tuple): The tuple whose elements will be added to the list.\n\n Returns:\n list: The modified list with the tuple elements appended.\n \"\"\"\n lst.extend(tup)\n return lst", "matching_cluster_idx": 5}, {"solution": "def add_tuple(lst, tup):\n \"\"\"\n Adds the elements of the given tuple to the end of the given list.\n \n Parameters:\n lst (list): The list to which the tuple elements will be added.\n tup (tuple): The tuple whose elements will be added to the list.\n \n Returns:\n list: The modified list with the tuple elements appended.\n \"\"\"\n lst.extend(tup)\n return lst", "matching_cluster_idx": 5}, {"solution": "def add_tuple(lst, tup):\n \"\"\"\n Adds the elements of the given tuple to the end of the given list.\n\n Parameters:\n lst (list): The list to which the tuple elements will be added.\n tup (tuple): The tuple whose elements will be added to the list.\n\n Returns:\n list: The modified list with the tuple elements appended.\n \"\"\"\n lst.extend(tup)\n return lst", "matching_cluster_idx": 5}, {"solution": "def add_tuple(lst, tup):\n \"\"\"\n Adds the elements of the given tuple to the end of the given list.\n \n Parameters:\n lst (list): The list to which the tuple elements will be added.\n tup (tuple): The tuple whose elements will be added to the list.\n \n Returns:\n list: The modified list with the tuple elements appended.\n \"\"\"\n lst.extend(tup)\n return lst", "matching_cluster_idx": 5}, {"solution": "def add_tuple(lst, tup):\n \"\"\"\n Adds the elements of the given tuple to the end of the given list.\n \n Parameters:\n lst (list): The list to which the tuple elements will be added.\n tup (tuple): The tuple whose elements will be added to the list.\n \n Returns:\n list: The modified list with the tuple elements appended.\n \"\"\"\n lst.extend(tup)\n return lst", "matching_cluster_idx": 5}, {"solution": "def add_tuple(lst, tup):\n \"\"\"\n Adds the elements of the given tuple to the end of the given list.\n \n Parameters:\n lst (list): The list to which the tuple elements will be added.\n tup (tuple): The tuple whose elements will be added to the list.\n \n Returns:\n list: The modified list with the tuple elements appended.\n \"\"\"\n lst.extend(tup)\n return lst", "matching_cluster_idx": 5}, {"solution": "def add_tuple(lst, tup):\n \"\"\"\n Adds the elements of the given tuple to the end of the given list.\n \n Parameters:\n lst (list): The list to which the tuple elements will be added.\n tup (tuple): The tuple whose elements will be added to the list.\n \n Returns:\n list: The modified list with the tuple elements appended.\n \"\"\"\n lst.extend(tup)\n return lst", "matching_cluster_idx": 5}, {"solution": "def add_tuple(lst, tup):\n \"\"\"\n Adds the elements of the given tuple to the end of the given list.\n\n Parameters:\n lst (list): The list to which the tuple elements will be added.\n tup (tuple): The tuple whose elements will be added to the list.\n\n Returns:\n list: The modified list with the tuple elements appended.\n \"\"\"\n lst.extend(tup)\n return lst", "matching_cluster_idx": 5}]}, "Mbpp/753": {"dps": 87.71812080536913, "dps_norm": 72.5, "pass@1": 100.0, "profiled": [{"solution": "def min_k(records, k):\n # Sort the records based on the second element of the tuple (the value)\n sorted_records = sorted(records, key=lambda x: x[1])\n # Return the first k elements from the sorted list\n return sorted_records[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(records, k):\n # Sort the records based on the second element of the tuple (the value)\n sorted_records = sorted(records, key=lambda x: x[1])\n # Return the first k elements from the sorted list\n return sorted_records[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(records, k):\n # Sort the records based on the second element (the value) in ascending order\n sorted_records = sorted(records, key=lambda x: x[1])\n \n # Return the first k elements from the sorted list\n return sorted_records[:k]", "matching_cluster_idx": 1}, {"solution": "def min_k(records, k):\n # Sort the records based on the second element of the tuple (the value)\n sorted_records = sorted(records, key=lambda x: x[1])\n # Return the first k elements of the sorted list\n return sorted_records[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(records, k):\n # Sort the records based on the second element of the tuple (the value)\n sorted_records = sorted(records, key=lambda x: x[1])\n # Return the first k elements from the sorted list\n return sorted_records[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(records, k):\n # Sort the records based on the second element of the tuple (the value)\n sorted_records = sorted(records, key=lambda x: x[1])\n # Return the first k elements of the sorted list\n return sorted_records[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(records, k):\n # Sort the records based on the second element of the tuple (the value)\n sorted_records = sorted(records, key=lambda x: x[1])\n # Return the first k elements from the sorted list\n return sorted_records[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(records, k):\n # Sort the records based on the second element of the tuple (the value)\n sorted_records = sorted(records, key=lambda x: x[1])\n # Return the first k elements from the sorted list\n return sorted_records[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(records, k):\n # Sort the records based on the second element of each tuple (the value)\n sorted_records = sorted(records, key=lambda x: x[1])\n # Return the first k elements from the sorted list\n return sorted_records[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(records, k):\n # Sort the records based on the second element of the tuple (the value)\n sorted_records = sorted(records, key=lambda x: x[1])\n # Return the first k elements from the sorted list\n return sorted_records[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(records, k):\n # Sort the records based on the second element (the value) in ascending order\n sorted_records = sorted(records, key=lambda x: x[1])\n \n # Return the first k elements from the sorted list\n return sorted_records[:k]", "matching_cluster_idx": 1}, {"solution": "def min_k(records, k):\n # Sort the records based on the second element of the tuple (the value)\n sorted_records = sorted(records, key=lambda x: x[1])\n # Return the first k elements from the sorted list\n return sorted_records[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(records, k):\n # Sort the records based on the second element of the tuple (the value)\n sorted_records = sorted(records, key=lambda x: x[1])\n # Return the first k elements from the sorted list\n return sorted_records[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(records, k):\n # Sort the records based on the second element of the tuple (the value)\n sorted_records = sorted(records, key=lambda x: x[1])\n # Return the first k elements of the sorted list\n return sorted_records[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(records, k):\n # Sort the records based on the second element (the value) in ascending order\n sorted_records = sorted(records, key=lambda x: x[1])\n # Return the first k elements from the sorted list\n return sorted_records[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(records, k):\n # Sort the records based on the second element of the tuple (the value)\n sorted_records = sorted(records, key=lambda x: x[1])\n # Return the first k elements from the sorted list\n return sorted_records[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(records, k):\n # Sort the records based on the second element (the integer) in ascending order\n sorted_records = sorted(records, key=lambda x: x[1])\n # Return the first k elements from the sorted list\n return sorted_records[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(records, k):\n # Sort the records based on the second element of the tuple (the value)\n sorted_records = sorted(records, key=lambda x: x[1])\n # Return the first k elements from the sorted list\n return sorted_records[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(records, k):\n # Sort the records based on the second element (the value) in ascending order\n sorted_records = sorted(records, key=lambda x: x[1])\n # Return the first k elements from the sorted list\n return sorted_records[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(records, k):\n # Sort the records based on the second element of the tuple (the value)\n sorted_records = sorted(records, key=lambda x: x[1])\n # Return the first k elements of the sorted list\n return sorted_records[:k]", "matching_cluster_idx": 2}]}, "Mbpp/754": {"dps": 89.65517241379311, "dps_norm": 87.5, "pass@1": 100.0, "profiled": [{"solution": "def extract_index_list(l1, l2, l3):\n # Find the minimum length of the three lists to avoid index out of range errors\n min_length = min(len(l1), len(l2), len(l3))\n \n # Initialize an empty list to store common elements\n common_elements = []\n \n # Iterate through the lists up to the minimum length\n for i in range(min_length):\n # Check if the element at the current index is the same in all three lists\n if l1[i] == l2[i] == l3[i]:\n # If it is, add it to the list of common elements\n common_elements.append(l1[i])\n \n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n # Find the minimum length of the three lists to avoid index out of range errors\n min_length = min(len(l1), len(l2), len(l3))\n \n # Initialize an empty list to store common elements\n common_elements = []\n \n # Iterate through the lists up to the minimum length\n for i in range(min_length):\n # Check if the element at the current index is the same in all three lists\n if l1[i] == l2[i] == l3[i]:\n # If it is, add it to the list of common elements\n common_elements.append(l1[i])\n \n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n # Find the minimum length of the three lists to avoid index errors\n min_length = min(len(l1), len(l2), len(l3))\n \n # Initialize an empty list to store common elements\n common_elements = []\n \n # Iterate through the lists up to the minimum length\n for i in range(min_length):\n # Check if the element at the current index is the same in all three lists\n if l1[i] == l2[i] == l3[i]:\n # If true, add the element to the common_elements list\n common_elements.append(l1[i])\n \n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n # Find the minimum length of the three lists to avoid index out of range errors\n min_length = min(len(l1), len(l2), len(l3))\n \n # Initialize an empty list to store common elements\n common_elements = []\n \n # Iterate through the lists up to the minimum length\n for i in range(min_length):\n # Check if the element at the current index is the same in all three lists\n if l1[i] == l2[i] == l3[i]:\n # If true, add the element to the common_elements list\n common_elements.append(l1[i])\n \n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n # Find the minimum length of the three lists to avoid index out of range errors\n min_length = min(len(l1), len(l2), len(l3))\n \n # Initialize an empty list to store common elements\n common_elements = []\n \n # Iterate through the lists up to the minimum length\n for i in range(min_length):\n # Check if the element at the current index is the same in all three lists\n if l1[i] == l2[i] == l3[i]:\n # If it is, add it to the list of common elements\n common_elements.append(l1[i])\n \n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n # Find the minimum length of the three lists to avoid index out of range errors\n min_length = min(len(l1), len(l2), len(l3))\n \n # Initialize an empty list to store common elements\n common_elements = []\n \n # Iterate through the lists up to the minimum length\n for i in range(min_length):\n # Check if the element at the current index is the same in all three lists\n if l1[i] == l2[i] == l3[i]:\n # If true, add the element to the common_elements list\n common_elements.append(l1[i])\n \n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n # Initialize an empty list to store common elements\n common_elements = []\n \n # Determine the minimum length of the three lists\n min_length = min(len(l1), len(l2), len(l3))\n \n # Iterate through the indices up to the minimum length\n for i in range(min_length):\n # Check if the element at the current index is the same in all three lists\n if l1[i] == l2[i] == l3[i]:\n # If true, add the element to the common_elements list\n common_elements.append(l1[i])\n \n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n # Find the minimum length of the three lists\n min_length = min(len(l1), len(l2), len(l3))\n \n # Initialize an empty list to store common elements\n common_elements = []\n \n # Iterate through the lists up to the minimum length\n for i in range(min_length):\n # Check if the element at the current index is the same in all three lists\n if l1[i] == l2[i] == l3[i]:\n # If so, add it to the common_elements list\n common_elements.append(l1[i])\n \n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n # Find the minimum length of the three lists to avoid index out of range errors\n min_length = min(len(l1), len(l2), len(l3))\n \n # Initialize an empty list to store common elements\n common_elements = []\n \n # Iterate through the lists up to the minimum length\n for i in range(min_length):\n # Check if the element at index i is the same in all three lists\n if l1[i] == l2[i] == l3[i]:\n # If true, add the element to the common_elements list\n common_elements.append(l1[i])\n \n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n # Find the minimum length of the three lists to avoid index out of range errors\n min_length = min(len(l1), len(l2), len(l3))\n \n # Initialize an empty list to store common elements\n common_elements = []\n \n # Iterate through the lists up to the minimum length\n for i in range(min_length):\n # Check if the element at the current index is the same in all three lists\n if l1[i] == l2[i] == l3[i]:\n # If true, add the element to the common_elements list\n common_elements.append(l1[i])\n \n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n # Initialize an empty list to store common elements\n common_elements = []\n \n # Iterate through the lists using the shortest list's length\n min_length = min(len(l1), len(l2), len(l3))\n \n for i in range(min_length):\n # Check if the element at the current index is the same in all three lists\n if l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n \n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n # Find the minimum length of the three lists to avoid index out of range errors\n min_length = min(len(l1), len(l2), len(l3))\n \n # Initialize an empty list to store common elements\n common_elements = []\n \n # Iterate through the lists up to the minimum length\n for i in range(min_length):\n # Check if the element at the current index is the same in all three lists\n if l1[i] == l2[i] == l3[i]:\n # If it is, add it to the list of common elements\n common_elements.append(l1[i])\n \n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n # Find the minimum length of the three lists to avoid index out of range errors\n min_length = min(len(l1), len(l2), len(l3))\n \n # Initialize an empty list to store common elements\n common_elements = []\n \n # Iterate through the lists up to the minimum length\n for i in range(min_length):\n # Check if the element at the current index is the same in all three lists\n if l1[i] == l2[i] == l3[i]:\n # If it is, add it to the list of common elements\n common_elements.append(l1[i])\n \n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n # Initialize an empty list to store common elements\n common_elements = []\n \n # Find the minimum length of the three lists to avoid index out of range errors\n min_length = min(len(l1), len(l2), len(l3))\n \n # Iterate through the lists up to the minimum length\n for i in range(min_length):\n # Check if the element at the current index is the same in all three lists\n if l1[i] == l2[i] == l3[i]:\n # If true, add the element to the common_elements list\n common_elements.append(l1[i])\n \n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n # Find the minimum length of the three lists to avoid index out of range errors\n min_length = min(len(l1), len(l2), len(l3))\n \n # Initialize an empty list to store common elements\n common_elements = []\n \n # Iterate through the lists up to the minimum length\n for i in range(min_length):\n # Check if the element at the current index is the same in all three lists\n if l1[i] == l2[i] == l3[i]:\n # If it is, add it to the list of common elements\n common_elements.append(l1[i])\n \n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n # Find the minimum length of the three lists to avoid index out of range errors\n min_length = min(len(l1), len(l2), len(l3))\n \n # Initialize an empty list to store common elements\n common_elements = []\n \n # Iterate through the lists up to the minimum length\n for i in range(min_length):\n # Check if the element at index i is the same in all three lists\n if l1[i] == l2[i] == l3[i]:\n # If it is, add it to the list of common elements\n common_elements.append(l1[i])\n \n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n # Find the minimum length of the three lists to avoid index out of range errors\n min_length = min(len(l1), len(l2), len(l3))\n \n # Initialize an empty list to store common elements\n common_elements = []\n \n # Iterate through the lists up to the minimum length\n for i in range(min_length):\n # Check if the element at the current index is the same in all three lists\n if l1[i] == l2[i] == l3[i]:\n # If it is, add it to the common_elements list\n common_elements.append(l1[i])\n \n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n # Find the minimum length of the three lists to avoid index out of range errors\n min_length = min(len(l1), len(l2), len(l3))\n \n # Initialize an empty list to store common elements\n common_elements = []\n \n # Iterate through the lists up to the minimum length\n for i in range(min_length):\n # Check if the element at the current index is the same in all three lists\n if l1[i] == l2[i] == l3[i]:\n # If it is, add it to the list of common elements\n common_elements.append(l1[i])\n \n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n # Find the minimum length of the three lists to avoid index out of range errors\n min_length = min(len(l1), len(l2), len(l3))\n \n # Initialize an empty list to store common elements\n common_elements = []\n \n # Iterate through the lists up to the minimum length\n for i in range(min_length):\n # Check if the element at the current index is the same in all three lists\n if l1[i] == l2[i] == l3[i]:\n # If it is, add it to the list of common elements\n common_elements.append(l1[i])\n \n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n # Find the minimum length of the three lists to avoid index out of range errors\n min_length = min(len(l1), len(l2), len(l3))\n \n # Initialize an empty list to store common elements\n common_elements = []\n \n # Iterate through the lists up to the minimum length\n for i in range(min_length):\n # Check if the element at the current index is the same in all three lists\n if l1[i] == l2[i] == l3[i]:\n # If true, add the element to the common_elements list\n common_elements.append(l1[i])\n \n return common_elements", "matching_cluster_idx": 6}]}, "Mbpp/755": {"dps": null, "dps_norm": null, "pass@1": 0.0, "profiled": []}, "Mbpp/757": {"dps": 82.71028037383178, "dps_norm": 23.076923076923077, "pass@1": 98.0, "profiled": [{"solution": "def count_reverse_pairs(string_list):\n def is_reverse(str1, str2):\n return str1 == str2[::-1]\n\n count = 0\n n = len(string_list)\n \n for i in range(n):\n for j in range(i + 1, n):\n if is_reverse(string_list[i], string_list[j]):\n count += 1\n \n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(string_list):\n def is_reverse(s1, s2):\n return s1 == s2[::-1]\n\n count = 0\n n = len(string_list)\n \n for i in range(n):\n for j in range(i + 1, n):\n if is_reverse(string_list[i], string_list[j]):\n count += 1\n \n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(string_list):\n def is_reverse(str1, str2):\n return str1 == str2[::-1]\n\n count = 0\n n = len(string_list)\n \n for i in range(n):\n for j in range(i + 1, n):\n if is_reverse(string_list[i], string_list[j]):\n count += 1\n \n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(string_list):\n def is_reverse(str1, str2):\n return str1 == str2[::-1]\n \n count = 0\n n = len(string_list)\n \n for i in range(n):\n for j in range(i + 1, n):\n if is_reverse(string_list[i], string_list[j]):\n count += 1\n \n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(string_list):\n # Helper function to check if two strings are reverse of each other\n def is_reverse(str1, str2):\n return str1 == str2[::-1]\n\n # Initialize a counter for the pairs\n count = 0\n\n # Iterate through the list to find reverse pairs\n for i in range(len(string_list)):\n for j in range(i + 1, len(string_list)):\n if is_reverse(string_list[i], string_list[j]):\n count += 1\n\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(string_list):\n def is_reverse(s1, s2):\n return s1 == s2[::-1]\n\n count = 0\n n = len(string_list)\n \n for i in range(n):\n for j in range(i + 1, n):\n if is_reverse(string_list[i], string_list[j]):\n count += 1\n \n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(string_list):\n def is_reverse(s1, s2):\n return s1 == s2[::-1]\n\n count = 0\n n = len(string_list)\n \n for i in range(n):\n for j in range(i + 1, n):\n if is_reverse(string_list[i], string_list[j]):\n count += 1\n \n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(string_list):\n def is_reverse(s1, s2):\n return s1 == s2[::-1]\n\n count = 0\n n = len(string_list)\n \n for i in range(n):\n for j in range(i + 1, n):\n if is_reverse(string_list[i], string_list[j]):\n count += 1\n \n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(string_list):\n def is_reverse(str1, str2):\n return str1 == str2[::-1]\n\n count = 0\n n = len(string_list)\n \n for i in range(n):\n for j in range(i + 1, n):\n if is_reverse(string_list[i], string_list[j]):\n count += 1\n \n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(string_list):\n def is_reverse(s1, s2):\n return s1 == s2[::-1]\n\n count = 0\n n = len(string_list)\n \n for i in range(n):\n for j in range(i + 1, n):\n if is_reverse(string_list[i], string_list[j]):\n count += 1\n \n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(string_list):\n def is_reverse(s1, s2):\n return s1 == s2[::-1]\n\n count = 0\n n = len(string_list)\n \n for i in range(n):\n for j in range(i + 1, n):\n if is_reverse(string_list[i], string_list[j]):\n count += 1\n \n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(string_list):\n def is_reverse(s1, s2):\n return s1 == s2[::-1]\n \n count = 0\n n = len(string_list)\n \n for i in range(n):\n for j in range(i + 1, n):\n if is_reverse(string_list[i], string_list[j]):\n count += 1\n \n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(string_list):\n def is_reverse(str1, str2):\n return str1 == str2[::-1]\n\n count = 0\n n = len(string_list)\n \n for i in range(n):\n for j in range(i + 1, n):\n if is_reverse(string_list[i], string_list[j]):\n count += 1\n \n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(string_list):\n def is_reverse(str1, str2):\n return str1 == str2[::-1]\n\n count = 0\n n = len(string_list)\n \n for i in range(n):\n for j in range(i + 1, n):\n if is_reverse(string_list[i], string_list[j]):\n count += 1\n \n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(string_list):\n def is_reverse(s1, s2):\n return s1 == s2[::-1]\n\n count = 0\n n = len(string_list)\n \n for i in range(n):\n for j in range(i + 1, n):\n if is_reverse(string_list[i], string_list[j]):\n count += 1\n \n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(string_list):\n def is_reverse(s1, s2):\n return s1 == s2[::-1]\n\n count = 0\n n = len(string_list)\n \n for i in range(n):\n for j in range(i + 1, n):\n if is_reverse(string_list[i], string_list[j]):\n count += 1\n \n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(string_list):\n def is_reverse(str1, str2):\n return str1 == str2[::-1]\n\n count = 0\n n = len(string_list)\n \n for i in range(n):\n for j in range(i + 1, n):\n if is_reverse(string_list[i], string_list[j]):\n count += 1\n \n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(string_list):\n def is_reverse(s1, s2):\n return s1 == s2[::-1]\n\n count = 0\n n = len(string_list)\n \n for i in range(n):\n for j in range(i + 1, n):\n if is_reverse(string_list[i], string_list[j]):\n count += 1\n \n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(string_list):\n def is_reverse(s1, s2):\n return s1 == s2[::-1]\n\n count = 0\n n = len(string_list)\n \n for i in range(n):\n for j in range(i + 1, n):\n if is_reverse(string_list[i], string_list[j]):\n count += 1\n \n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(string_list):\n def is_reverse(s1, s2):\n return s1 == s2[::-1]\n\n count = 0\n n = len(string_list)\n \n for i in range(n):\n for j in range(i + 1, n):\n if is_reverse(string_list[i], string_list[j]):\n count += 1\n \n return count", "matching_cluster_idx": 2}]}, "Mbpp/758": {"dps": 89.67181467181466, "dps_norm": 84.375, "pass@1": 100.0, "profiled": [{"solution": "def unique_sublists(lst):\n # Initialize an empty dictionary to store the counts\n count_dict = {}\n \n # Iterate over each sublist in the input list\n for sublist in lst:\n # Convert the sublist to a tuple to use it as a dictionary key\n sublist_tuple = tuple(sublist)\n \n # Increment the count for this tuple in the dictionary\n if sublist_tuple in count_dict:\n count_dict[sublist_tuple] += 1\n else:\n count_dict[sublist_tuple] = 1\n \n return count_dict", "matching_cluster_idx": 5}, {"solution": "def unique_sublists(lst):\n # Initialize an empty dictionary to store the counts\n count_dict = {}\n \n # Iterate through each sublist in the input list\n for sublist in lst:\n # Convert the sublist to a tuple to use it as a dictionary key\n sublist_tuple = tuple(sublist)\n \n # If the tuple is already in the dictionary, increment its count\n if sublist_tuple in count_dict:\n count_dict[sublist_tuple] += 1\n # Otherwise, add the tuple to the dictionary with a count of 1\n else:\n count_dict[sublist_tuple] = 1\n \n return count_dict", "matching_cluster_idx": 5}, {"solution": "def unique_sublists(lst):\n \"\"\"\n Counts the occurrences of each sublist in the given list and returns a dictionary\n where each sublist is converted to a tuple and the value is the number of its occurrences.\n \"\"\"\n from collections import defaultdict\n \n # Initialize a defaultdict to count occurrences of each sublist\n count_dict = defaultdict(int)\n \n # Iterate through each sublist in the input list\n for sublist in lst:\n # Convert the sublist to a tuple and increment its count\n count_dict[tuple(sublist)] += 1\n \n # Convert the defaultdict to a regular dictionary and return it\n return dict(count_dict)", "matching_cluster_idx": 5}, {"solution": "def unique_sublists(lst):\n # Initialize an empty dictionary to store the counts\n count_dict = {}\n \n # Iterate over each sublist in the input list\n for sublist in lst:\n # Convert the sublist to a tuple\n sublist_tuple = tuple(sublist)\n \n # If the tuple is already in the dictionary, increment its count\n if sublist_tuple in count_dict:\n count_dict[sublist_tuple] += 1\n # Otherwise, add the tuple to the dictionary with a count of 1\n else:\n count_dict[sublist_tuple] = 1\n \n return count_dict", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(lst):\n # Initialize an empty dictionary to store the counts\n count_dict = {}\n \n # Iterate over each sublist in the input list\n for sublist in lst:\n # Convert the sublist to a tuple to use it as a dictionary key\n sublist_tuple = tuple(sublist)\n \n # If the tuple is already in the dictionary, increment its count\n if sublist_tuple in count_dict:\n count_dict[sublist_tuple] += 1\n # Otherwise, add the tuple to the dictionary with a count of 1\n else:\n count_dict[sublist_tuple] = 1\n \n return count_dict", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(lst):\n # Initialize an empty dictionary to store the counts\n count_dict = {}\n \n # Iterate over each sublist in the input list\n for sublist in lst:\n # Convert the sublist to a tuple to use it as a dictionary key\n sublist_tuple = tuple(sublist)\n \n # If the tuple is already in the dictionary, increment its count\n if sublist_tuple in count_dict:\n count_dict[sublist_tuple] += 1\n # Otherwise, add the tuple to the dictionary with a count of 1\n else:\n count_dict[sublist_tuple] = 1\n \n return count_dict", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(lst):\n # Initialize an empty dictionary to store the counts\n count_dict = {}\n \n # Iterate over each sublist in the input list\n for sublist in lst:\n # Convert the sublist to a tuple to use it as a dictionary key\n sublist_tuple = tuple(sublist)\n \n # If the tuple is already in the dictionary, increment its count\n if sublist_tuple in count_dict:\n count_dict[sublist_tuple] += 1\n # Otherwise, add the tuple to the dictionary with a count of 1\n else:\n count_dict[sublist_tuple] = 1\n \n return count_dict", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(lst):\n # Initialize an empty dictionary to store the counts\n count_dict = {}\n \n # Iterate over each sublist in the input list\n for sublist in lst:\n # Convert the sublist to a tuple\n sublist_tuple = tuple(sublist)\n \n # If the tuple is already in the dictionary, increment its count\n if sublist_tuple in count_dict:\n count_dict[sublist_tuple] += 1\n # Otherwise, add the tuple to the dictionary with a count of 1\n else:\n count_dict[sublist_tuple] = 1\n \n return count_dict", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(lst):\n # Initialize an empty dictionary to store the counts\n count_dict = {}\n \n # Iterate over each sublist in the input list\n for sublist in lst:\n # Convert the sublist to a tuple to use it as a dictionary key\n sublist_tuple = tuple(sublist)\n \n # If the tuple is already in the dictionary, increment its count\n if sublist_tuple in count_dict:\n count_dict[sublist_tuple] += 1\n # Otherwise, add the tuple to the dictionary with a count of 1\n else:\n count_dict[sublist_tuple] = 1\n \n # Return the dictionary with the counts\n return count_dict", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(lst):\n # Initialize an empty dictionary to store the counts\n count_dict = {}\n \n # Iterate over each sublist in the input list\n for sublist in lst:\n # Convert the sublist to a tuple to use it as a dictionary key\n sublist_tuple = tuple(sublist)\n \n # If the tuple is already in the dictionary, increment its count\n if sublist_tuple in count_dict:\n count_dict[sublist_tuple] += 1\n # Otherwise, add the tuple to the dictionary with a count of 1\n else:\n count_dict[sublist_tuple] = 1\n \n return count_dict", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(lst):\n # Initialize an empty dictionary to store the counts\n count_dict = {}\n \n # Iterate over each sublist in the input list\n for sublist in lst:\n # Convert the sublist to a tuple to use it as a dictionary key\n sublist_tuple = tuple(sublist)\n \n # If the tuple is already in the dictionary, increment its count\n if sublist_tuple in count_dict:\n count_dict[sublist_tuple] += 1\n # Otherwise, add the tuple to the dictionary with a count of 1\n else:\n count_dict[sublist_tuple] = 1\n \n return count_dict", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(lst):\n # Initialize an empty dictionary to store the counts\n count_dict = {}\n \n # Iterate over each sublist in the input list\n for sublist in lst:\n # Convert the sublist to a tuple to use it as a dictionary key\n sublist_tuple = tuple(sublist)\n \n # If the tuple is already in the dictionary, increment its count\n if sublist_tuple in count_dict:\n count_dict[sublist_tuple] += 1\n # Otherwise, add the tuple to the dictionary with a count of 1\n else:\n count_dict[sublist_tuple] = 1\n \n return count_dict", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(lst):\n # Initialize an empty dictionary to store the counts\n count_dict = {}\n \n # Iterate over each sublist in the input list\n for sublist in lst:\n # Convert the sublist to a tuple to use it as a dictionary key\n sublist_tuple = tuple(sublist)\n \n # If the tuple is already in the dictionary, increment its count\n if sublist_tuple in count_dict:\n count_dict[sublist_tuple] += 1\n # Otherwise, add the tuple to the dictionary with a count of 1\n else:\n count_dict[sublist_tuple] = 1\n \n # Return the resulting dictionary\n return count_dict", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(lst):\n # Initialize an empty dictionary to store the counts\n count_dict = {}\n \n # Iterate over each sublist in the input list\n for sublist in lst:\n # Convert the sublist to a tuple to use it as a dictionary key\n sublist_tuple = tuple(sublist)\n \n # If the tuple is already in the dictionary, increment its count\n if sublist_tuple in count_dict:\n count_dict[sublist_tuple] += 1\n # Otherwise, add the tuple to the dictionary with a count of 1\n else:\n count_dict[sublist_tuple] = 1\n \n return count_dict", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(lst):\n # Initialize an empty dictionary to store the counts\n count_dict = {}\n \n # Iterate over each sublist in the input list\n for sublist in lst:\n # Convert the sublist to a tuple to use it as a dictionary key\n sublist_tuple = tuple(sublist)\n \n # If the tuple is already in the dictionary, increment its count\n if sublist_tuple in count_dict:\n count_dict[sublist_tuple] += 1\n # Otherwise, add the tuple to the dictionary with a count of 1\n else:\n count_dict[sublist_tuple] = 1\n \n # Return the resulting dictionary\n return count_dict", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(lst):\n # Initialize an empty dictionary to store the counts\n count_dict = {}\n \n # Iterate over each sublist in the input list\n for sublist in lst:\n # Convert the sublist to a tuple to use it as a dictionary key\n sublist_tuple = tuple(sublist)\n \n # If the tuple is already in the dictionary, increment its count\n if sublist_tuple in count_dict:\n count_dict[sublist_tuple] += 1\n # Otherwise, add the tuple to the dictionary with a count of 1\n else:\n count_dict[sublist_tuple] = 1\n \n return count_dict", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(lst):\n # Initialize an empty dictionary to store the counts\n count_dict = {}\n \n # Iterate through each sublist in the input list\n for sublist in lst:\n # Convert the sublist to a tuple to use it as a dictionary key\n sublist_tuple = tuple(sublist)\n \n # If the tuple is already in the dictionary, increment its count\n if sublist_tuple in count_dict:\n count_dict[sublist_tuple] += 1\n # Otherwise, add the tuple to the dictionary with a count of 1\n else:\n count_dict[sublist_tuple] = 1\n \n return count_dict", "matching_cluster_idx": 5}, {"solution": "def unique_sublists(lst):\n # Initialize an empty dictionary to store the counts\n count_dict = {}\n \n # Iterate over each sublist in the input list\n for sublist in lst:\n # Convert the sublist to a tuple to use it as a dictionary key\n sublist_tuple = tuple(sublist)\n \n # If the tuple is already in the dictionary, increment its count\n if sublist_tuple in count_dict:\n count_dict[sublist_tuple] += 1\n # Otherwise, add the tuple to the dictionary with a count of 1\n else:\n count_dict[sublist_tuple] = 1\n \n return count_dict", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(lst):\n # Initialize an empty dictionary to store the counts\n count_dict = {}\n \n # Iterate through each sublist in the input list\n for sublist in lst:\n # Convert the sublist to a tuple to use it as a dictionary key\n sublist_tuple = tuple(sublist)\n \n # If the tuple is already in the dictionary, increment its count\n if sublist_tuple in count_dict:\n count_dict[sublist_tuple] += 1\n # Otherwise, add the tuple to the dictionary with a count of 1\n else:\n count_dict[sublist_tuple] = 1\n \n return count_dict", "matching_cluster_idx": 5}, {"solution": "def unique_sublists(lst):\n # Initialize an empty dictionary to store the counts\n count_dict = {}\n \n # Iterate over each sublist in the input list\n for sublist in lst:\n # Convert the sublist to a tuple to use it as a dictionary key\n sublist_tuple = tuple(sublist)\n \n # If the tuple is already in the dictionary, increment its count\n if sublist_tuple in count_dict:\n count_dict[sublist_tuple] += 1\n # Otherwise, add the tuple to the dictionary with a count of 1\n else:\n count_dict[sublist_tuple] = 1\n \n return count_dict", "matching_cluster_idx": 6}]}, "Mbpp/760": {"dps": 82.04379562043796, "dps_norm": 80.0, "pass@1": 97.0, "profiled": [{"solution": "def unique_Element(lst):\n \"\"\"\n Check whether a list of numbers contains only one distinct element or not.\n\n Args:\n lst (list): A list of numbers.\n\n Returns:\n bool: True if the list contains only one distinct element, False otherwise.\n \"\"\"\n return len(set(lst)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(lst):\n \"\"\"\n Check whether a list of numbers contains only one distinct element or not.\n \n Args:\n lst (list): A list of numbers.\n \n Returns:\n bool: True if the list contains only one distinct element, False otherwise.\n \"\"\"\n return len(set(lst)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(lst):\n \"\"\"\n Check whether a list of numbers contains only one distinct element or not.\n \n Parameters:\n lst (list): A list of numbers.\n \n Returns:\n bool: True if the list contains only one distinct element, False otherwise.\n \"\"\"\n return len(set(lst)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(lst):\n \"\"\"\n Check whether a list of numbers contains only one distinct element or not.\n\n Parameters:\n lst (list): A list of numbers.\n\n Returns:\n bool: True if the list contains only one distinct element, False otherwise.\n \"\"\"\n return len(set(lst)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(lst):\n \"\"\"\n Check whether a list of numbers contains only one distinct element or not.\n \n Args:\n lst (list): A list of numbers.\n \n Returns:\n bool: True if the list contains only one distinct element, False otherwise.\n \"\"\"\n return len(set(lst)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(lst):\n # Check if all elements in the list are the same\n return all(x == lst[0] for x in lst)", "matching_cluster_idx": 3}, {"solution": "def unique_Element(lst):\n # Check if all elements in the list are the same\n return all(x == lst[0] for x in lst)", "matching_cluster_idx": 3}, {"solution": "def unique_Element(lst):\n \"\"\"\n Check whether a list of numbers contains only one distinct element or not.\n\n Args:\n lst (list): A list of numbers.\n\n Returns:\n bool: True if the list contains only one distinct element, False otherwise.\n \"\"\"\n return len(set(lst)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(lst):\n \"\"\"\n Check whether a list of numbers contains only one distinct element or not.\n\n Args:\n lst (list): A list of numbers.\n\n Returns:\n bool: True if the list contains only one distinct element, False otherwise.\n \"\"\"\n return len(set(lst)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(lst):\n # Check if all elements in the list are the same\n return len(set(lst)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(lst):\n \"\"\"\n Check whether a list of numbers contains only one distinct element or not.\n\n Args:\n lst (list): A list of numbers.\n\n Returns:\n bool: True if the list contains only one distinct element, False otherwise.\n \"\"\"\n return len(set(lst)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(lst):\n \"\"\"\n Check whether a list of numbers contains only one distinct element or not.\n\n Args:\n lst (list): A list of numbers.\n\n Returns:\n bool: True if the list contains only one distinct element, False otherwise.\n \"\"\"\n return len(set(lst)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(lst):\n # Check if all elements in the list are the same\n return len(set(lst)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(lst):\n \"\"\"\n Check whether a list of numbers contains only one distinct element or not.\n\n Args:\n lst (list): A list of numbers.\n\n Returns:\n bool: True if the list contains only one distinct element, False otherwise.\n \"\"\"\n return len(set(lst)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(lst):\n # Check if all elements in the list are the same\n return all(x == lst[0] for x in lst)", "matching_cluster_idx": 3}, {"solution": "def unique_Element(lst):\n \"\"\"\n Check whether a list of numbers contains only one distinct element or not.\n \n Args:\n lst (list): A list of numbers.\n \n Returns:\n bool: True if the list contains only one distinct element, False otherwise.\n \"\"\"\n return len(set(lst)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(lst):\n # Check if all elements in the list are the same\n return len(set(lst)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(lst):\n # Check if all elements in the list are the same\n return len(set(lst)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(lst):\n # Check if all elements in the list are the same\n return all(x == lst[0] for x in lst)", "matching_cluster_idx": 3}, {"solution": "def unique_Element(lst):\n \"\"\"\n Check whether a list of numbers contains only one distinct element or not.\n \n Args:\n lst (list): A list of numbers.\n \n Returns:\n bool: True if the list contains only one distinct element, False otherwise.\n \"\"\"\n return len(set(lst)) == 1", "matching_cluster_idx": 6}]}, "Mbpp/764": {"dps": 88.88888888888889, "dps_norm": 50.0, "pass@1": 100.0, "profiled": [{"solution": "def number_ctr(s):\n \"\"\"\n Counts the number of digits in a given string.\n \n Args:\n s (str): The input string.\n \n Returns:\n int: The number of digits in the string.\n \"\"\"\n return sum(c.isdigit() for c in s)", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n \"\"\"\n Counts the number of digits in a given string.\n \n Args:\n s (str): The input string.\n \n Returns:\n int: The number of digits in the string.\n \"\"\"\n return sum(c.isdigit() for c in s)", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n \"\"\"\n Counts the number of digits in a given string.\n \n Args:\n s (str): The input string.\n \n Returns:\n int: The number of digits in the string.\n \"\"\"\n return sum(c.isdigit() for c in s)", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n \"\"\"\n Counts the number of digits in a given string.\n \n Args:\n s (str): The input string.\n \n Returns:\n int: The number of digits in the string.\n \"\"\"\n return sum(c.isdigit() for c in s)", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n \"\"\"\n Counts the number of digits in a given string.\n \n Args:\n s (str): The input string.\n \n Returns:\n int: The number of digits in the string.\n \"\"\"\n return sum(c.isdigit() for c in s)", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n \"\"\"\n Count the number of digits in a given string.\n \n Args:\n s (str): The input string.\n \n Returns:\n int: The number of digits in the string.\n \"\"\"\n return sum(c.isdigit() for c in s)", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n \"\"\"\n Counts the number of digits in a given string.\n \n Args:\n s (str): The input string.\n \n Returns:\n int: The number of digits in the string.\n \"\"\"\n return sum(c.isdigit() for c in s)", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n \"\"\"\n Counts the number of digits in a given string.\n \n Args:\n s (str): The input string.\n \n Returns:\n int: The number of digits in the string.\n \"\"\"\n return sum(c.isdigit() for c in s)", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n \"\"\"\n Counts the number of digits in a given string.\n \n Args:\n s (str): The input string.\n \n Returns:\n int: The number of digits in the string.\n \"\"\"\n return sum(c.isdigit() for c in s)", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n \"\"\"\n Counts the number of digits in a given string.\n \n Args:\n s (str): The input string.\n \n Returns:\n int: The number of digits in the string.\n \"\"\"\n return sum(c.isdigit() for c in s)", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n \"\"\"\n Counts the number of digits in a given string.\n \n Args:\n s (str): The input string.\n \n Returns:\n int: The number of digits in the string.\n \"\"\"\n return sum(c.isdigit() for c in s)", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n \"\"\"\n Counts the number of digits in a given string.\n \n Args:\n s (str): The input string.\n \n Returns:\n int: The number of digits in the string.\n \"\"\"\n return sum(c.isdigit() for c in s)", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n \"\"\"\n Counts the number of digits in a given string.\n \n Args:\n s (str): The input string.\n \n Returns:\n int: The number of digits in the string.\n \"\"\"\n return sum(c.isdigit() for c in s)", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n \"\"\"\n Counts the number of digits in a given string.\n \n Args:\n s (str): The input string.\n \n Returns:\n int: The number of digits in the string.\n \"\"\"\n return sum(c.isdigit() for c in s)", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n \"\"\"\n Count the number of digits in a given string.\n \n Args:\n s (str): The input string.\n \n Returns:\n int: The number of digits in the string.\n \"\"\"\n return sum(c.isdigit() for c in s)", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n \"\"\"\n Counts the number of digits in a given string.\n \n Args:\n s (str): The input string.\n \n Returns:\n int: The number of digits in the string.\n \"\"\"\n return sum(c.isdigit() for c in s)", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n \"\"\"\n Counts the number of digits in a given string.\n \n Args:\n s (str): The input string.\n \n Returns:\n int: The number of digits in the string.\n \"\"\"\n return sum(c.isdigit() for c in s)", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n \"\"\"\n Counts the number of digits in a given string.\n \n Args:\n s (str): The input string.\n \n Returns:\n int: The number of digits in the string.\n \"\"\"\n return sum(c.isdigit() for c in s)", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n \"\"\"\n Counts the number of digits in a given string.\n \n Args:\n s (str): The input string.\n \n Returns:\n int: The number of digits in the string.\n \"\"\"\n return sum(c.isdigit() for c in s)", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n \"\"\"\n Count the number of digits in a given string.\n \n Args:\n s (str): The input string.\n \n Returns:\n int: The number of digits in the string.\n \"\"\"\n return sum(c.isdigit() for c in s)", "matching_cluster_idx": 2}]}, "Mbpp/766": {"dps": 80.37383177570094, "dps_norm": 66.66666666666667, "pass@1": 100.0, "profiled": [{"solution": "def pair_wise(lst):\n return [(lst[i], lst[i + 1]) for i in range(len(lst) - 1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n \"\"\"\n Returns a list of all pairs of consecutive items in the given list.\n \n :param lst: List of items\n :return: List of tuples, each containing a pair of consecutive items\n \"\"\"\n return [(lst[i], lst[i + 1]) for i in range(len(lst) - 1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n return [(lst[i], lst[i+1]) for i in range(len(lst) - 1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n \"\"\"\n Returns a list of all pairs of consecutive items in the given list.\n \n :param lst: List of items\n :return: List of tuples, each containing a pair of consecutive items\n \"\"\"\n return [(lst[i], lst[i + 1]) for i in range(len(lst) - 1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n return [(lst[i], lst[i+1]) for i in range(len(lst) - 1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n return [(lst[i], lst[i+1]) for i in range(len(lst) - 1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n \"\"\"\n Returns a list of all pairs of consecutive items in the given list.\n \n :param lst: List of items\n :return: List of tuples containing consecutive pairs\n \"\"\"\n return [(lst[i], lst[i + 1]) for i in range(len(lst) - 1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n return [(lst[i], lst[i+1]) for i in range(len(lst) - 1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n return [(lst[i], lst[i+1]) for i in range(len(lst) - 1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n return [(lst[i], lst[i + 1]) for i in range(len(lst) - 1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n \"\"\"\n Returns a list of all pairs of consecutive items in the given list.\n \n :param lst: List of items\n :return: List of tuples, each containing a pair of consecutive items\n \"\"\"\n return [(lst[i], lst[i+1]) for i in range(len(lst) - 1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n \"\"\"\n Returns a list of all pairs of consecutive items in the given list.\n \n :param lst: List of items\n :return: List of tuples, each containing a pair of consecutive items\n \"\"\"\n return [(lst[i], lst[i + 1]) for i in range(len(lst) - 1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n \"\"\"\n Returns a list of all pairs of consecutive items in the given list.\n \n :param lst: List of items\n :return: List of tuples, each containing a pair of consecutive items\n \"\"\"\n return [(lst[i], lst[i + 1]) for i in range(len(lst) - 1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n \"\"\"\n Returns a list of all pairs of consecutive items in the given list.\n \n :param lst: List of items\n :return: List of tuples, each containing a pair of consecutive items\n \"\"\"\n return [(lst[i], lst[i+1]) for i in range(len(lst) - 1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n \"\"\"\n Returns a list of all pairs of consecutive items in the given list.\n \n :param lst: List of items\n :return: List of tuples, each containing a pair of consecutive items\n \"\"\"\n return [(lst[i], lst[i+1]) for i in range(len(lst) - 1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n \"\"\"\n Returns a list of all pairs of consecutive items in the given list.\n \n :param lst: List of items\n :return: List of tuples, each containing a pair of consecutive items\n \"\"\"\n return [(lst[i], lst[i + 1]) for i in range(len(lst) - 1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n \"\"\"\n Returns a list of all pairs of consecutive items in the given list.\n \n :param lst: List of items\n :return: List of tuples, each containing a pair of consecutive items\n \"\"\"\n return [(lst[i], lst[i + 1]) for i in range(len(lst) - 1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n \"\"\"\n Returns a list of all pairs of consecutive items in the given list.\n \n :param lst: List of items\n :return: List of tuples, each containing a pair of consecutive items\n \"\"\"\n return [(lst[i], lst[i+1]) for i in range(len(lst) - 1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n \"\"\"\n Returns a list of all pairs of consecutive items in the given list.\n \n :param lst: List of items\n :return: List of tuples, each containing a pair of consecutive items\n \"\"\"\n return [(lst[i], lst[i + 1]) for i in range(len(lst) - 1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n \"\"\"\n Returns a list of all pairs of consecutive items in the given list.\n \n :param lst: List of items\n :return: List of tuples containing consecutive pairs\n \"\"\"\n return [(lst[i], lst[i+1]) for i in range(len(lst) - 1)]", "matching_cluster_idx": 3}]}, "Mbpp/775": {"dps": 94.39999999999999, "dps_norm": 71.42857142857143, "pass@1": 100.0, "profiled": [{"solution": "def odd_position(lst):\n \"\"\"\n Check whether every odd index contains an odd number in the given list.\n \n Args:\n lst (list): The list to check.\n \n Returns:\n bool: True if every odd index contains an odd number, False otherwise.\n \"\"\"\n for i in range(1, len(lst), 2):\n if lst[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n \"\"\"\n Check whether every odd index contains an odd number in the given list.\n \n :param lst: List of integers\n :return: True if every odd index contains an odd number, False otherwise\n \"\"\"\n for i in range(1, len(lst), 2):\n if lst[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n \"\"\"\n Check whether every odd index contains an odd number in the given list.\n \n Args:\n lst (list): The list of integers to check.\n \n Returns:\n bool: True if every odd index contains an odd number, False otherwise.\n \"\"\"\n for i in range(1, len(lst), 2):\n if lst[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n \"\"\"\n Check whether every odd index contains an odd number in the given list.\n \n Args:\n lst (list): The list of integers to check.\n \n Returns:\n bool: True if every odd index contains an odd number, False otherwise.\n \"\"\"\n for i in range(1, len(lst), 2):\n if lst[i] % 2 != 1:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n \"\"\"\n Check whether every odd index contains an odd number in the given list.\n \n Args:\n lst (list): The list of integers to check.\n \n Returns:\n bool: True if every odd index contains an odd number, False otherwise.\n \"\"\"\n for i in range(1, len(lst), 2):\n if lst[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n \"\"\"\n Check whether every odd index contains an odd number in the given list.\n \n Args:\n lst (list): The list of integers to check.\n \n Returns:\n bool: True if every odd index contains an odd number, False otherwise.\n \"\"\"\n for i in range(1, len(lst), 2):\n if lst[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n \"\"\"\n Check whether every odd index contains an odd number in the given list.\n \n Args:\n lst (list): The list of integers to check.\n \n Returns:\n bool: True if every odd index contains an odd number, False otherwise.\n \"\"\"\n for i in range(1, len(lst), 2):\n if lst[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n \"\"\"\n Check whether every odd index contains an odd number in the given list.\n \n Args:\n lst (list): The list of integers to check.\n \n Returns:\n bool: True if every odd index contains an odd number, False otherwise.\n \"\"\"\n for i in range(1, len(lst), 2):\n if lst[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n \"\"\"\n Check whether every odd index contains an odd number in the given list.\n\n Args:\n lst (list): The list to check.\n\n Returns:\n bool: True if every odd index contains an odd number, False otherwise.\n \"\"\"\n for i in range(1, len(lst), 2):\n if lst[i] % 2 != 1:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n \"\"\"\n Check whether every odd index contains an odd number in the given list.\n \n Args:\n lst (list): The list of integers to check.\n \n Returns:\n bool: True if every odd index contains an odd number, False otherwise.\n \"\"\"\n for i in range(1, len(lst), 2):\n if lst[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n \"\"\"\n Check whether every odd index contains an odd number in the given list.\n \n Args:\n lst (list): The list to check.\n \n Returns:\n bool: True if every odd index contains an odd number, False otherwise.\n \"\"\"\n for i in range(1, len(lst), 2):\n if lst[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n \"\"\"\n Check whether every odd index contains an odd number in the given list.\n \n Args:\n lst (list): The list of integers to check.\n \n Returns:\n bool: True if every odd index contains an odd number, False otherwise.\n \"\"\"\n for i in range(1, len(lst), 2):\n if lst[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n \"\"\"\n Check whether every odd index contains an odd number in the given list.\n \n Args:\n lst (list): The list of integers to check.\n \n Returns:\n bool: True if every odd index contains an odd number, False otherwise.\n \"\"\"\n for i in range(1, len(lst), 2):\n if lst[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n \"\"\"\n Check whether every odd index contains an odd number in the given list.\n \n Args:\n lst (list): The list of integers to check.\n \n Returns:\n bool: True if every odd index contains an odd number, False otherwise.\n \"\"\"\n for i in range(1, len(lst), 2):\n if lst[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n \"\"\"\n Check whether every odd index contains an odd number in the given list.\n \n Args:\n lst (list): The list of integers to check.\n \n Returns:\n bool: True if every odd index contains an odd number, False otherwise.\n \"\"\"\n for i in range(1, len(lst), 2):\n if lst[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n \"\"\"\n Check whether every odd index contains an odd number in the given list.\n \n Args:\n lst (list): The list of integers to check.\n \n Returns:\n bool: True if every odd index contains an odd number, False otherwise.\n \"\"\"\n for i in range(1, len(lst), 2):\n if lst[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n \"\"\"\n Check whether every odd index contains an odd number in the given list.\n \n Args:\n lst (list): The list to check.\n \n Returns:\n bool: True if every odd index contains an odd number, False otherwise.\n \"\"\"\n for i in range(1, len(lst), 2):\n if lst[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n \"\"\"\n Check whether every odd index contains an odd number in the given list.\n \n Args:\n lst (list): The list to check.\n \n Returns:\n bool: True if every odd index contains an odd number, False otherwise.\n \"\"\"\n for i in range(1, len(lst), 2):\n if lst[i] % 2 != 1:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n \"\"\"\n Check whether every odd index contains an odd number in the given list.\n \n Args:\n lst (list): The list of integers to check.\n \n Returns:\n bool: True if every odd index contains an odd number, False otherwise.\n \"\"\"\n for i in range(1, len(lst), 2):\n if lst[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n \"\"\"\n Check whether every odd index contains an odd number in the given list.\n \n Args:\n lst (list): The list of integers to check.\n \n Returns:\n bool: True if every odd index contains an odd number, False otherwise.\n \"\"\"\n for i in range(1, len(lst), 2):\n if lst[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}]}, "Mbpp/777": {"dps": 81.63265306122449, "dps_norm": 86.66666666666667, "pass@1": 100.0, "profiled": [{"solution": "def find_sum(lst):\n # Use a set to store unique elements\n unique_elements = set(lst)\n \n # Calculate the sum of the unique elements\n sum_unique = sum(unique_elements)\n \n return sum_unique", "matching_cluster_idx": 8}, {"solution": "def find_sum(lst):\n # Use a set to store unique elements\n unique_elements = set(lst)\n \n # Sum the unique elements\n total_sum = sum(unique_elements)\n \n return total_sum", "matching_cluster_idx": 8}, {"solution": "def find_sum(lst):\n # Create a set to store unique elements\n unique_elements = set()\n \n # Iterate through the list and add elements to the set\n for element in lst:\n unique_elements.add(element)\n \n # Calculate the sum of the unique elements\n sum_unique = sum(unique_elements)\n \n return sum_unique", "matching_cluster_idx": 4}, {"solution": "def find_sum(lst):\n # Use a set to store unique elements\n unique_elements = set(lst)\n # Sum the unique elements\n return sum(unique_elements)", "matching_cluster_idx": 8}, {"solution": "def find_sum(lst):\n # Use a set to store unique elements\n unique_elements = set(lst)\n # Sum the unique elements\n return sum(unique_elements)", "matching_cluster_idx": 8}, {"solution": "def find_sum(lst):\n # Use a set to store unique elements\n unique_elements = set(lst)\n \n # Calculate the sum of the unique elements\n sum_unique = sum(unique_elements)\n \n return sum_unique", "matching_cluster_idx": 8}, {"solution": "def find_sum(lst):\n # Use a set to store unique elements\n unique_elements = set(lst)\n # Sum the unique elements\n return sum(unique_elements)", "matching_cluster_idx": 8}, {"solution": "def find_sum(lst):\n # Use a set to store unique elements\n unique_elements = set(lst)\n # Sum the unique elements\n return sum(unique_elements)", "matching_cluster_idx": 8}, {"solution": "def find_sum(lst):\n # Create a set to store unique elements\n unique_elements = set()\n \n # Iterate through the list and add elements to the set\n for element in lst:\n unique_elements.add(element)\n \n # Calculate the sum of the unique elements\n sum_unique = sum(unique_elements)\n \n return sum_unique", "matching_cluster_idx": 4}, {"solution": "def find_sum(lst):\n # Create a set to store unique elements\n unique_elements = set()\n \n # Iterate through the list and add elements to the set\n for element in lst:\n unique_elements.add(element)\n \n # Calculate the sum of the unique elements\n sum_unique = sum(unique_elements)\n \n return sum_unique", "matching_cluster_idx": 4}, {"solution": "def find_sum(lst):\n # Use a set to store unique elements\n unique_elements = set(lst)\n \n # Sum the unique elements\n total_sum = sum(unique_elements)\n \n return total_sum", "matching_cluster_idx": 8}, {"solution": "def find_sum(lst):\n # Create a set to store unique elements\n unique_elements = set()\n \n # Iterate through the list and add elements to the set\n for element in lst:\n unique_elements.add(element)\n \n # Calculate the sum of the unique elements\n sum_unique = sum(unique_elements)\n \n return sum_unique", "matching_cluster_idx": 4}, {"solution": "def find_sum(lst):\n # Use a set to store unique elements\n unique_elements = set(lst)\n # Sum the unique elements\n return sum(unique_elements)", "matching_cluster_idx": 8}, {"solution": "def find_sum(lst):\n # Create a set to store unique elements\n unique_elements = set()\n \n # Iterate through the list and add elements to the set\n for element in lst:\n unique_elements.add(element)\n \n # Calculate the sum of the unique elements\n sum_unique = sum(unique_elements)\n \n return sum_unique", "matching_cluster_idx": 4}, {"solution": "def find_sum(lst):\n # Use a set to store unique elements\n unique_elements = set(lst)\n # Sum the unique elements\n return sum(unique_elements)", "matching_cluster_idx": 8}, {"solution": "def find_sum(lst):\n # Use a set to store unique elements\n unique_elements = set(lst)\n # Sum the unique elements\n return sum(unique_elements)", "matching_cluster_idx": 8}, {"solution": "def find_sum(lst):\n # Create a set to store unique elements\n unique_elements = set()\n \n # Iterate through the list and add elements to the set\n for element in lst:\n unique_elements.add(element)\n \n # Calculate the sum of the unique elements\n sum_of_unique_elements = sum(unique_elements)\n \n return sum_of_unique_elements", "matching_cluster_idx": 4}, {"solution": "def find_sum(lst):\n # Convert the list to a set to remove duplicates\n unique_elements = set(lst)\n # Sum the unique elements\n return sum(unique_elements)", "matching_cluster_idx": 8}, {"solution": "def find_sum(lst):\n # Create a set to store unique elements\n unique_elements = set(lst)\n \n # Calculate the sum of unique elements\n sum_unique = sum(unique_elements)\n \n return sum_unique", "matching_cluster_idx": 8}, {"solution": "def find_sum(lst):\n # Convert the list to a set to remove duplicates\n unique_elements = set(lst)\n # Sum the unique elements\n return sum(unique_elements)", "matching_cluster_idx": 8}]}, "Mbpp/781": {"dps": 3.937007874015748, "dps_norm": 20.0, "pass@1": 100.0, "profiled": [{"solution": "def count_divisors(n):\n \"\"\"\n Function to check whether the count of divisors of a number is even.\n \n Args:\n n (int): The number to check.\n \n Returns:\n bool: True if the count of divisors is even, False otherwise.\n \"\"\"\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count % 2 == 0", "matching_cluster_idx": 0}, {"solution": "def count_divisors(n):\n \"\"\"\n Function to check whether the count of divisors of a number is even.\n \n Args:\n n (int): The number to check.\n \n Returns:\n bool: True if the count of divisors is even, False otherwise.\n \"\"\"\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count % 2 == 0", "matching_cluster_idx": 0}, {"solution": "def count_divisors(n):\n \"\"\"\n Function to check whether the count of divisors of a number is even.\n \n Args:\n n (int): The number to check for divisors.\n \n Returns:\n bool: True if the count of divisors is even, False otherwise.\n \"\"\"\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count % 2 == 0", "matching_cluster_idx": 0}, {"solution": "def count_divisors(n):\n \"\"\"\n Function to check whether the count of divisors of a number is even.\n \n Parameters:\n n (int): The number to check for divisors.\n \n Returns:\n bool: True if the count of divisors is even, False otherwise.\n \"\"\"\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count % 2 == 0", "matching_cluster_idx": 0}, {"solution": "def count_divisors(n):\n \"\"\"\n Function to check whether the count of divisors of a number is even.\n \n Args:\n n (int): The number to check for divisors.\n \n Returns:\n bool: True if the count of divisors is even, False otherwise.\n \"\"\"\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count % 2 == 0", "matching_cluster_idx": 0}, {"solution": "def count_divisors(n):\n \"\"\"\n Function to check whether the count of divisors of a number is even.\n \n Args:\n n (int): The number to check for divisors.\n \n Returns:\n bool: True if the count of divisors is even, False otherwise.\n \"\"\"\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count % 2 == 0", "matching_cluster_idx": 0}, {"solution": "def count_divisors(n):\n \"\"\"\n Function to check whether the count of divisors of a number is even.\n \n Args:\n n (int): The number to check.\n \n Returns:\n bool: True if the count of divisors is even, False otherwise.\n \"\"\"\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count % 2 == 0", "matching_cluster_idx": 0}, {"solution": "def count_divisors(n):\n \"\"\"\n Function to check whether the count of divisors of a number is even.\n \n Args:\n n (int): The number to check for divisors.\n \n Returns:\n bool: True if the count of divisors is even, False otherwise.\n \"\"\"\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count % 2 == 0", "matching_cluster_idx": 0}, {"solution": "def count_divisors(n):\n \"\"\"\n Function to check whether the count of divisors of a number is even.\n \n Args:\n n (int): The number to check for divisors.\n \n Returns:\n bool: True if the count of divisors is even, False otherwise.\n \"\"\"\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count % 2 == 0", "matching_cluster_idx": 0}, {"solution": "def count_divisors(n):\n \"\"\"\n Function to check whether the count of divisors of a number is even.\n \n Args:\n n (int): The number to check.\n \n Returns:\n bool: True if the count of divisors is even, False otherwise.\n \"\"\"\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count % 2 == 0", "matching_cluster_idx": 0}, {"solution": "def count_divisors(n):\n \"\"\"\n Function to check whether the count of divisors of a number is even.\n \n Args:\n n (int): The number to check for divisors.\n \n Returns:\n bool: True if the count of divisors is even, False otherwise.\n \"\"\"\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count % 2 == 0", "matching_cluster_idx": 0}, {"solution": "def count_divisors(n):\n \"\"\"\n Count the number of divisors of a given number n.\n Returns True if the count of divisors is even, otherwise False.\n \"\"\"\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count % 2 == 0", "matching_cluster_idx": 0}, {"solution": "def count_divisors(n):\n \"\"\"\n Function to check whether the count of divisors of a number is even.\n \n Args:\n n (int): The number to check for divisors.\n \n Returns:\n bool: True if the count of divisors is even, False otherwise.\n \"\"\"\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count % 2 == 0", "matching_cluster_idx": 0}, {"solution": "def count_divisors(n):\n \"\"\"\n Function to check whether the count of divisors of a number is even.\n \n Args:\n n (int): The number to check for divisors.\n \n Returns:\n bool: True if the count of divisors is even, False otherwise.\n \"\"\"\n # Initialize the count of divisors\n count = 0\n \n # Iterate over all numbers from 1 to n\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n \n # Check if the count of divisors is even\n return count % 2 == 0", "matching_cluster_idx": 0}, {"solution": "def count_divisors(n):\n \"\"\"\n Function to check whether the count of divisors of a number is even.\n \n Args:\n n (int): The number to check for divisors.\n \n Returns:\n bool: True if the count of divisors is even, False otherwise.\n \"\"\"\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count % 2 == 0", "matching_cluster_idx": 0}, {"solution": "def count_divisors(n):\n \"\"\"\n Function to check whether the count of divisors of a number is even.\n \n Args:\n n (int): The number to check.\n \n Returns:\n bool: True if the count of divisors is even, False otherwise.\n \"\"\"\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count % 2 == 0", "matching_cluster_idx": 0}, {"solution": "def count_divisors(n):\n \"\"\"\n Function to check whether the count of divisors of a number is even.\n \n Args:\n n (int): The number to check.\n \n Returns:\n bool: True if the count of divisors is even, False otherwise.\n \"\"\"\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count % 2 == 0", "matching_cluster_idx": 0}, {"solution": "def count_divisors(n):\n \"\"\"\n Function to check whether the count of divisors of a number is even.\n \n Args:\n n (int): The number to check for divisors.\n \n Returns:\n bool: True if the count of divisors is even, False otherwise.\n \"\"\"\n # Initialize the count of divisors\n count = 0\n \n # Loop through all numbers from 1 to n (inclusive)\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n \n # Check if the count of divisors is even\n return count % 2 == 0", "matching_cluster_idx": 0}, {"solution": "def count_divisors(n):\n \"\"\"\n Function to check whether the count of divisors of a number is even.\n \n Parameters:\n n (int): The number to check for divisors.\n \n Returns:\n bool: True if the count of divisors is even, False otherwise.\n \"\"\"\n # Initialize the count of divisors\n count = 0\n \n # Loop through all numbers from 1 to n\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n \n # Check if the count of divisors is even\n return count % 2 == 0", "matching_cluster_idx": 0}, {"solution": "def count_divisors(n):\n \"\"\"\n Function to check whether the count of divisors of a number is even.\n \n Args:\n n (int): The number to check.\n \n Returns:\n bool: True if the count of divisors is even, False otherwise.\n \"\"\"\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count % 2 == 0", "matching_cluster_idx": 0}]}, "Mbpp/800": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def remove_all_spaces(input_string):\n \"\"\"\n Removes all whitespaces from the input string.\n \n Args:\n input_string (str): The string from which whitespaces need to be removed.\n \n Returns:\n str: The input string with all whitespaces removed.\n \"\"\"\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n \"\"\"\n Remove all whitespaces from the input string.\n \n Args:\n input_string (str): The string from which whitespaces need to be removed.\n \n Returns:\n str: The input string with all whitespaces removed.\n \"\"\"\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n \"\"\"\n Remove all whitespaces from the input string.\n \n Args:\n input_string (str): The string from which whitespaces need to be removed.\n \n Returns:\n str: The input string with all whitespaces removed.\n \"\"\"\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(s):\n \"\"\"\n Removes all whitespaces from the given string.\n \n Args:\n s (str): The input string from which whitespaces need to be removed.\n \n Returns:\n str: The input string with all whitespaces removed.\n \"\"\"\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n \"\"\"\n Remove all whitespaces from the input string.\n \n Args:\n input_string (str): The string from which whitespaces need to be removed.\n \n Returns:\n str: The input string with all whitespaces removed.\n \"\"\"\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n \"\"\"\n Remove all whitespaces from the input string.\n\n Args:\n input_string (str): The string from which whitespaces are to be removed.\n\n Returns:\n str: The input string with all whitespaces removed.\n \"\"\"\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n \"\"\"\n Removes all whitespaces from the input string.\n \n Args:\n input_string (str): The string from which whitespaces need to be removed.\n \n Returns:\n str: The input string with all whitespaces removed.\n \"\"\"\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n \"\"\"\n Removes all whitespaces from the input string.\n\n Args:\n input_string (str): The string from which whitespaces need to be removed.\n\n Returns:\n str: The input string with all whitespaces removed.\n \"\"\"\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n \"\"\"\n Removes all whitespaces from the input string.\n \n Args:\n input_string (str): The string from which whitespaces need to be removed.\n \n Returns:\n str: The input string with all whitespaces removed.\n \"\"\"\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n \"\"\"\n Removes all whitespaces from the input string.\n \n Args:\n input_string (str): The string from which whitespaces need to be removed.\n \n Returns:\n str: The input string with all whitespaces removed.\n \"\"\"\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n \"\"\"\n Remove all whitespaces from the input string.\n\n Args:\n input_string (str): The string from which whitespaces need to be removed.\n\n Returns:\n str: The input string with all whitespaces removed.\n \"\"\"\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n \"\"\"\n Removes all whitespaces from the input string.\n \n Args:\n input_string (str): The string from which whitespaces need to be removed.\n \n Returns:\n str: The input string with all whitespaces removed.\n \"\"\"\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n \"\"\"\n Removes all whitespaces from the input string.\n\n Args:\n input_string (str): The string from which whitespaces need to be removed.\n\n Returns:\n str: The input string with all whitespaces removed.\n \"\"\"\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n \"\"\"\n Remove all whitespaces from a given string.\n\n Args:\n input_string (str): The string from which whitespaces need to be removed.\n\n Returns:\n str: The string with all whitespaces removed.\n \"\"\"\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n \"\"\"\n Remove all whitespaces from a given string.\n\n Args:\n input_string (str): The string from which whitespaces need to be removed.\n\n Returns:\n str: The string with all whitespaces removed.\n \"\"\"\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n \"\"\"\n Removes all whitespaces from the input string.\n \n Args:\n input_string (str): The string from which whitespaces need to be removed.\n \n Returns:\n str: The input string with all whitespaces removed.\n \"\"\"\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n \"\"\"\n Removes all whitespaces from the input string.\n \n Args:\n input_string (str): The string from which whitespaces need to be removed.\n \n Returns:\n str: The input string with all whitespaces removed.\n \"\"\"\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n \"\"\"\n Removes all whitespaces from the input string.\n \n Args:\n input_string (str): The string from which whitespaces need to be removed.\n \n Returns:\n str: The input string with all whitespaces removed.\n \"\"\"\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n \"\"\"\n Remove all whitespaces from the input string.\n \n Args:\n input_string (str): The string from which whitespaces need to be removed.\n \n Returns:\n str: The input string with all whitespaces removed.\n \"\"\"\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n \"\"\"\n Removes all whitespaces from the input string.\n \n Args:\n input_string (str): The string from which whitespaces need to be removed.\n \n Returns:\n str: The input string with all whitespaces removed.\n \"\"\"\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}]}, "Mbpp/805": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def max_sum_list(list_of_lists):\n # Initialize variables to keep track of the maximum sum and the corresponding list\n max_sum = float('-inf')\n max_list = []\n \n # Iterate through each list in the list of lists\n for lst in list_of_lists:\n # Calculate the sum of the current list\n current_sum = sum(lst)\n \n # Update max_sum and max_list if the current sum is greater than the previous max_sum\n if current_sum > max_sum:\n max_sum = current_sum\n max_list = lst\n \n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lst_of_lsts):\n # Initialize variables to keep track of the maximum sum and the corresponding list\n max_sum = float('-inf')\n max_list = []\n \n # Iterate through each list in the list of lists\n for lst in lst_of_lsts:\n # Calculate the sum of the current list\n current_sum = sum(lst)\n \n # Update max_sum and max_list if the current sum is greater\n if current_sum > max_sum:\n max_sum = current_sum\n max_list = lst\n \n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(list_of_lists):\n # Initialize variables to keep track of the maximum sum and the corresponding list\n max_sum = float('-inf')\n max_list = []\n \n # Iterate through each list in the list of lists\n for lst in list_of_lists:\n # Calculate the sum of the current list\n current_sum = sum(lst)\n \n # Update max_sum and max_list if the current sum is greater than the max_sum\n if current_sum > max_sum:\n max_sum = current_sum\n max_list = lst\n \n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(list_of_lists):\n # Initialize variables to keep track of the maximum sum and the corresponding list\n max_sum = float('-inf')\n max_list = []\n \n # Iterate through each list in the list of lists\n for lst in list_of_lists:\n # Calculate the sum of the current list\n current_sum = sum(lst)\n \n # Update the maximum sum and corresponding list if the current sum is greater\n if current_sum > max_sum:\n max_sum = current_sum\n max_list = lst\n \n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(list_of_lists):\n # Initialize variables to keep track of the maximum sum and the corresponding list\n max_sum = float('-inf')\n max_list = []\n \n # Iterate through each list in the list of lists\n for lst in list_of_lists:\n # Calculate the sum of the current list\n current_sum = sum(lst)\n \n # Update the maximum sum and corresponding list if the current sum is greater\n if current_sum > max_sum:\n max_sum = current_sum\n max_list = lst\n \n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lst):\n # Initialize variables to keep track of the maximum sum and the corresponding list\n max_sum = float('-inf')\n max_list = []\n \n # Iterate through each sublist in the input list\n for sublist in lst:\n # Calculate the sum of the current sublist\n current_sum = sum(sublist)\n \n # Update max_sum and max_list if the current sum is greater than the max_sum\n if current_sum > max_sum:\n max_sum = current_sum\n max_list = sublist\n \n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(list_of_lists):\n # Initialize variables to keep track of the maximum sum and the corresponding list\n max_sum = float('-inf')\n max_list = []\n \n # Iterate through each list in the list of lists\n for lst in list_of_lists:\n # Calculate the sum of the current list\n current_sum = sum(lst)\n \n # Update max_sum and max_list if the current sum is greater\n if current_sum > max_sum:\n max_sum = current_sum\n max_list = lst\n \n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(list_of_lists):\n # Initialize variables to keep track of the maximum sum and the corresponding list\n max_sum = float('-inf')\n max_list = []\n \n # Iterate through each list in the list of lists\n for lst in list_of_lists:\n # Calculate the sum of the current list\n current_sum = sum(lst)\n \n # Update max_sum and max_list if the current sum is greater\n if current_sum > max_sum:\n max_sum = current_sum\n max_list = lst\n \n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lst):\n # Initialize variables to keep track of the maximum sum and the corresponding list\n max_sum = float('-inf')\n max_list = []\n \n # Iterate through each sublist in the input list\n for sublist in lst:\n # Calculate the sum of the current sublist\n current_sum = sum(sublist)\n \n # Update max_sum and max_list if the current sum is greater than the max_sum\n if current_sum > max_sum:\n max_sum = current_sum\n max_list = sublist\n \n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(list_of_lists):\n # Initialize variables to keep track of the maximum sum and the corresponding list\n max_sum = float('-inf')\n max_list = []\n \n # Iterate through each list in the list of lists\n for lst in list_of_lists:\n # Calculate the sum of the current list\n current_sum = sum(lst)\n \n # Update max_sum and max_list if the current sum is greater\n if current_sum > max_sum:\n max_sum = current_sum\n max_list = lst\n \n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(list_of_lists):\n # Initialize variables to keep track of the maximum sum and the corresponding list\n max_sum = float('-inf')\n max_list = []\n \n # Iterate through each list in the list of lists\n for lst in list_of_lists:\n # Calculate the sum of the current list\n current_sum = sum(lst)\n \n # Update max_sum and max_list if the current sum is greater than the max_sum\n if current_sum > max_sum:\n max_sum = current_sum\n max_list = lst\n \n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(list_of_lists):\n # Initialize variables to keep track of the maximum sum and the corresponding list\n max_sum = float('-inf')\n max_list = []\n \n # Iterate through each list in the list of lists\n for lst in list_of_lists:\n # Calculate the sum of the current list\n current_sum = sum(lst)\n \n # Update max_sum and max_list if the current sum is greater than the max_sum\n if current_sum > max_sum:\n max_sum = current_sum\n max_list = lst\n \n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(list_of_lists):\n # Initialize variables to keep track of the maximum sum and the corresponding list\n max_sum = float('-inf')\n max_list = []\n \n # Iterate through each list in the list of lists\n for lst in list_of_lists:\n # Calculate the sum of the current list\n current_sum = sum(lst)\n \n # Update max_sum and max_list if the current sum is greater than the max_sum\n if current_sum > max_sum:\n max_sum = current_sum\n max_list = lst\n \n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(list_of_lists):\n # Initialize variables to keep track of the maximum sum and the corresponding list\n max_sum = float('-inf')\n max_list = []\n \n # Iterate through each list in the list of lists\n for lst in list_of_lists:\n # Calculate the sum of the current list\n current_sum = sum(lst)\n \n # Update max_sum and max_list if the current sum is greater\n if current_sum > max_sum:\n max_sum = current_sum\n max_list = lst\n \n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(list_of_lists):\n # Initialize variables to keep track of the maximum sum and the corresponding list\n max_sum = float('-inf')\n max_list = []\n \n # Iterate through each list in the list of lists\n for lst in list_of_lists:\n # Calculate the sum of the current list\n current_sum = sum(lst)\n \n # Update max_sum and max_list if the current sum is greater\n if current_sum > max_sum:\n max_sum = current_sum\n max_list = lst\n \n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lst):\n # Initialize variables to keep track of the maximum sum and the corresponding list\n max_sum = float('-inf')\n max_list = []\n \n # Iterate through each sublist in the input list\n for sublist in lst:\n # Calculate the sum of the current sublist\n current_sum = sum(sublist)\n \n # Update max_sum and max_list if the current sum is greater than the max_sum\n if current_sum > max_sum:\n max_sum = current_sum\n max_list = sublist\n \n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lst):\n # Initialize variables to keep track of the maximum sum and the corresponding list\n max_sum = float('-inf')\n max_list = []\n \n # Iterate through each sublist in the input list\n for sublist in lst:\n # Calculate the sum of the current sublist\n current_sum = sum(sublist)\n \n # Update max_sum and max_list if the current sum is greater than the max_sum\n if current_sum > max_sum:\n max_sum = current_sum\n max_list = sublist\n \n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lst):\n # Initialize variables to keep track of the maximum sum and the corresponding list\n max_sum = float('-inf')\n max_list = []\n \n # Iterate through each sublist in the input list\n for sublist in lst:\n # Calculate the sum of the current sublist\n current_sum = sum(sublist)\n \n # Update max_sum and max_list if the current sum is greater than the max_sum\n if current_sum > max_sum:\n max_sum = current_sum\n max_list = sublist\n \n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(list_of_lists):\n # Initialize variables to keep track of the maximum sum and the corresponding list\n max_sum = float('-inf')\n max_list = []\n \n # Iterate through each list in the list of lists\n for lst in list_of_lists:\n # Calculate the sum of the current list\n current_sum = sum(lst)\n \n # Update max_sum and max_list if the current sum is greater\n if current_sum > max_sum:\n max_sum = current_sum\n max_list = lst\n \n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(list_of_lists):\n # Initialize variables to keep track of the maximum sum and the corresponding list\n max_sum = float('-inf')\n max_list = []\n \n # Iterate through each list in the list of lists\n for lst in list_of_lists:\n # Calculate the sum of the current list\n current_sum = sum(lst)\n \n # Update max_sum and max_list if the current sum is greater\n if current_sum > max_sum:\n max_sum = current_sum\n max_list = lst\n \n return max_list", "matching_cluster_idx": 4}]}, "Mbpp/808": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def check_K(tup, k):\n \"\"\"\n Check if the given tuple contains the element k.\n\n Parameters:\n tup (tuple): The tuple to be checked.\n k (any): The element to search for in the tuple.\n\n Returns:\n bool: True if k is in the tuple, False otherwise.\n \"\"\"\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n \"\"\"\n Check if the given tuple contains the element k.\n\n Parameters:\n tup (tuple): The tuple to be checked.\n k (any): The element to search for in the tuple.\n\n Returns:\n bool: True if k is in the tuple, False otherwise.\n \"\"\"\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n \"\"\"\n Check if the given tuple contains the element k.\n\n Parameters:\n tup (tuple): The tuple to be checked.\n k (any): The element to search for in the tuple.\n\n Returns:\n bool: True if k is in the tuple, False otherwise.\n \"\"\"\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n \"\"\"\n Check if the given tuple contains the value k.\n\n Parameters:\n tup (tuple): The tuple to be checked.\n k (any): The value to search for in the tuple.\n\n Returns:\n bool: True if k is in the tuple, False otherwise.\n \"\"\"\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n \"\"\"\n Check if the given tuple contains the element k.\n\n Parameters:\n tup (tuple): The tuple to be checked.\n k (any): The element to search for in the tuple.\n\n Returns:\n bool: True if k is in the tuple, False otherwise.\n \"\"\"\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n \"\"\"\n Check if the given tuple contains the value k.\n\n Parameters:\n tup (tuple): The tuple to be checked.\n k (any): The value to search for in the tuple.\n\n Returns:\n bool: True if k is in the tuple, False otherwise.\n \"\"\"\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n \"\"\"\n Check if the given tuple contains the element k.\n\n Parameters:\n tup (tuple): The tuple to be checked.\n k (any): The element to be searched for in the tuple.\n\n Returns:\n bool: True if k is in the tuple, False otherwise.\n \"\"\"\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n \"\"\"\n Check if the given tuple contains the element k.\n\n Parameters:\n tup (tuple): The tuple to be checked.\n k (any): The element to be searched for in the tuple.\n\n Returns:\n bool: True if k is in the tuple, False otherwise.\n \"\"\"\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n \"\"\"\n Function to check if the given tuple contains the element k.\n \n Parameters:\n tup (tuple): The tuple to be checked.\n k (any): The element to be searched in the tuple.\n \n Returns:\n bool: True if k is in the tuple, False otherwise.\n \"\"\"\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n \"\"\"\n Check if the given tuple contains the value k.\n\n Parameters:\n tup (tuple): The tuple to be checked.\n k (any): The value to search for in the tuple.\n\n Returns:\n bool: True if k is in the tuple, False otherwise.\n \"\"\"\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n \"\"\"\n Check if the given tuple contains the value k.\n\n Parameters:\n tup (tuple): The tuple to be checked.\n k (any): The value to search for in the tuple.\n\n Returns:\n bool: True if k is in the tuple, False otherwise.\n \"\"\"\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n \"\"\"\n Check if the given tuple contains the value k.\n\n Parameters:\n tup (tuple): The tuple to be checked.\n k (any): The value to search for in the tuple.\n\n Returns:\n bool: True if k is in the tuple, False otherwise.\n \"\"\"\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n \"\"\"\n Check if the given tuple contains the value k.\n\n Parameters:\n tup (tuple): The tuple to be checked.\n k (any): The value to search for in the tuple.\n\n Returns:\n bool: True if k is in the tuple, False otherwise.\n \"\"\"\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n \"\"\"\n Check if the given tuple contains the value k.\n\n Parameters:\n tup (tuple): The tuple to be checked.\n k (any): The value to search for in the tuple.\n\n Returns:\n bool: True if k is in the tuple, False otherwise.\n \"\"\"\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n \"\"\"\n Check if the given tuple contains the element k.\n\n Parameters:\n tup (tuple): The tuple to be checked.\n k (any): The element to search for in the tuple.\n\n Returns:\n bool: True if k is in the tuple, False otherwise.\n \"\"\"\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n \"\"\"\n Check if the given tuple contains the element k.\n\n Parameters:\n tup (tuple): The tuple to be checked.\n k (any): The element to search for in the tuple.\n\n Returns:\n bool: True if k is in the tuple, False otherwise.\n \"\"\"\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n \"\"\"\n Check if the given tuple contains the element k.\n\n Parameters:\n tup (tuple): The tuple to be checked.\n k (any): The element to search for in the tuple.\n\n Returns:\n bool: True if k is in the tuple, False otherwise.\n \"\"\"\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n \"\"\"\n Check if the given tuple contains the element k.\n\n Parameters:\n tup (tuple): The tuple to be checked.\n k (any): The element to be searched for in the tuple.\n\n Returns:\n bool: True if k is in the tuple, False otherwise.\n \"\"\"\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n \"\"\"\n Check if the given tuple contains the element k.\n\n Parameters:\n tup (tuple): The tuple to be checked.\n k (any): The element to search for in the tuple.\n\n Returns:\n bool: True if k is in the tuple, False otherwise.\n \"\"\"\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n \"\"\"\n Check if the given tuple contains the value k.\n\n Parameters:\n tup (tuple): The tuple to be checked.\n k (int): The value to search for in the tuple.\n\n Returns:\n bool: True if k is in the tuple, False otherwise.\n \"\"\"\n return k in tup", "matching_cluster_idx": 5}]}}} \ No newline at end of file diff --git a/results/evalperf/gemini-1.5-flash-002_google_temp_1.0_evalperf_results.brief.json b/results/evalperf/gemini-1.5-flash-002_google_temp_1.0_evalperf_results.brief.json new file mode 100644 index 0000000..3bcb9e8 --- /dev/null +++ b/results/evalperf/gemini-1.5-flash-002_google_temp_1.0_evalperf_results.brief.json @@ -0,0 +1 @@ +{"date": "2024-10-19 16:30", "config": {"n_samples": 100, "temperature": 1.0, "min_correct": 10, "max_profile": 20}, "summary": {"dps": 79.85512300275154, "dps_norm": 76.4398130083651, "pass@1": 77.63559322033899}, "eval": {"HumanEval/9": {"dps": 73.02839116719242, "dps_norm": 80.55555555555556, "pass@1": 100.0, "profiled": [{"solution": "from typing import List, Tuple\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n \n rolling_max_list = [numbers[0]]\n max_so_far = numbers[0]\n for i in range(1, len(numbers)):\n if numbers[i] > max_so_far:\n max_so_far = numbers[i]\n rolling_max_list.append(max_so_far)\n return rolling_max_list", "matching_cluster_idx": 7}, {"solution": "from typing import List, Tuple\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n \n rolling_max_list = [numbers[0]]\n current_max = numbers[0]\n for i in range(1, len(numbers)):\n if numbers[i] > current_max:\n current_max = numbers[i]\n rolling_max_list.append(current_max)\n return rolling_max_list", "matching_cluster_idx": 7}, {"solution": "from typing import List, Tuple\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n\n rolling_max_list = []\n current_max = numbers[0]\n for number in numbers:\n current_max = max(current_max, number)\n rolling_max_list.append(current_max)\n return rolling_max_list", "matching_cluster_idx": 4}, {"solution": "from typing import List, Tuple\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n \n rolling_max_list = [numbers[0]]\n current_max = numbers[0]\n for i in range(1, len(numbers)):\n if numbers[i] > current_max:\n current_max = numbers[i]\n rolling_max_list.append(current_max)\n return rolling_max_list", "matching_cluster_idx": 7}, {"solution": "from typing import List, Tuple\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n \n rolling_max_list = [numbers[0]]\n max_so_far = numbers[0]\n for i in range(1, len(numbers)):\n max_so_far = max(max_so_far, numbers[i])\n rolling_max_list.append(max_so_far)\n return rolling_max_list", "matching_cluster_idx": 4}, {"solution": "from typing import List, Tuple\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n \n rolling_max_list = [numbers[0]]\n current_max = numbers[0]\n for i in range(1, len(numbers)):\n if numbers[i] > current_max:\n current_max = numbers[i]\n rolling_max_list.append(current_max)\n return rolling_max_list", "matching_cluster_idx": 7}, {"solution": "from typing import List, Tuple\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n \n rolling_max_list = []\n current_max = numbers[0]\n rolling_max_list.append(current_max)\n\n for i in range(1, len(numbers)):\n if numbers[i] > current_max:\n current_max = numbers[i]\n rolling_max_list.append(current_max)\n\n return rolling_max_list", "matching_cluster_idx": 7}, {"solution": "from typing import List, Tuple\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n\n rolling_max_list = []\n current_max = numbers[0]\n for number in numbers:\n current_max = max(current_max, number)\n rolling_max_list.append(current_max)\n return rolling_max_list", "matching_cluster_idx": 4}, {"solution": "from typing import List, Tuple\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n \n rolling_max_list = [numbers[0]]\n current_max = numbers[0]\n for i in range(1, len(numbers)):\n current_max = max(current_max, numbers[i])\n rolling_max_list.append(current_max)\n return rolling_max_list", "matching_cluster_idx": 4}, {"solution": "from typing import List, Tuple\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n \n rolling_max_list = []\n current_max = numbers[0]\n rolling_max_list.append(current_max)\n\n for i in range(1, len(numbers)):\n if numbers[i] > current_max:\n current_max = numbers[i]\n rolling_max_list.append(current_max)\n return rolling_max_list", "matching_cluster_idx": 7}, {"solution": "from typing import List, Tuple\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n \n rolling_max_list = [numbers[0]]\n current_max = numbers[0]\n for i in range(1, len(numbers)):\n if numbers[i] > current_max:\n current_max = numbers[i]\n rolling_max_list.append(current_max)\n return rolling_max_list", "matching_cluster_idx": 7}, {"solution": "from typing import List, Tuple\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n \n rolling_max_list = []\n current_max = numbers[0]\n rolling_max_list.append(current_max)\n\n for i in range(1, len(numbers)):\n if numbers[i] > current_max:\n current_max = numbers[i]\n rolling_max_list.append(current_max)\n return rolling_max_list", "matching_cluster_idx": 7}, {"solution": "from typing import List, Tuple\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n \n rolling_max_list = []\n current_max = numbers[0]\n rolling_max_list.append(current_max)\n\n for i in range(1, len(numbers)):\n if numbers[i] > current_max:\n current_max = numbers[i]\n rolling_max_list.append(current_max)\n\n return rolling_max_list", "matching_cluster_idx": 7}, {"solution": "from typing import List, Tuple\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n \n rolling_max_list = [numbers[0]]\n current_max = numbers[0]\n for i in range(1, len(numbers)):\n current_max = max(current_max, numbers[i])\n rolling_max_list.append(current_max)\n return rolling_max_list", "matching_cluster_idx": 4}, {"solution": "from typing import List, Tuple\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n \n rolling_max_list = []\n max_so_far = numbers[0]\n rolling_max_list.append(max_so_far)\n\n for i in range(1, len(numbers)):\n if numbers[i] > max_so_far:\n max_so_far = numbers[i]\n rolling_max_list.append(max_so_far)\n\n return rolling_max_list", "matching_cluster_idx": 7}, {"solution": "from typing import List, Tuple\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n\n rolling_max_list = []\n current_max = numbers[0]\n rolling_max_list.append(current_max)\n\n for i in range(1, len(numbers)):\n if numbers[i] > current_max:\n current_max = numbers[i]\n rolling_max_list.append(current_max)\n\n return rolling_max_list", "matching_cluster_idx": 7}, {"solution": "from typing import List, Tuple\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n \n rolling_max_list = [numbers[0]]\n current_max = numbers[0]\n for i in range(1, len(numbers)):\n if numbers[i] > current_max:\n current_max = numbers[i]\n rolling_max_list.append(current_max)\n return rolling_max_list", "matching_cluster_idx": 7}, {"solution": "from typing import List, Tuple\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n \n rolling_max_list = [numbers[0]]\n current_max = numbers[0]\n for i in range(1, len(numbers)):\n if numbers[i] > current_max:\n current_max = numbers[i]\n rolling_max_list.append(current_max)\n return rolling_max_list", "matching_cluster_idx": 7}, {"solution": "from typing import List, Tuple\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n \n rolling_max_list = []\n max_so_far = numbers[0]\n rolling_max_list.append(max_so_far)\n\n for i in range(1, len(numbers)):\n if numbers[i] > max_so_far:\n max_so_far = numbers[i]\n rolling_max_list.append(max_so_far)\n return rolling_max_list", "matching_cluster_idx": 7}, {"solution": "from typing import List, Tuple\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n \n rolling_max_list = [numbers[0]]\n current_max = numbers[0]\n for i in range(1, len(numbers)):\n if numbers[i] > current_max:\n current_max = numbers[i]\n rolling_max_list.append(current_max)\n return rolling_max_list", "matching_cluster_idx": 7}]}, "HumanEval/0": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n if abs(numbers[i] - numbers[j]) < threshold:\n return True\n return False", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n if abs(numbers[i] - numbers[j]) < threshold:\n return True\n return False", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n if abs(numbers[i] - numbers[j]) < threshold:\n return True\n return False", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n if abs(numbers[i] - numbers[j]) < threshold:\n return True\n return False", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n if abs(numbers[i] - numbers[j]) < threshold:\n return True\n return False", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n if abs(numbers[i] - numbers[j]) < threshold:\n return True\n return False", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n if abs(numbers[i] - numbers[j]) < threshold:\n return True\n return False", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n if abs(numbers[i] - numbers[j]) < threshold:\n return True\n return False", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n if abs(numbers[i] - numbers[j]) < threshold:\n return True\n return False", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n if abs(numbers[i] - numbers[j]) < threshold:\n return True\n return False", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n if abs(numbers[i] - numbers[j]) < threshold:\n return True\n return False", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n if abs(numbers[i] - numbers[j]) < threshold:\n return True\n return False", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n if abs(numbers[i] - numbers[j]) < threshold:\n return True\n return False", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n if abs(numbers[i] - numbers[j]) < threshold:\n return True\n return False", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n if abs(numbers[i] - numbers[j]) < threshold:\n return True\n return False", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n if abs(numbers[i] - numbers[j]) < threshold:\n return True\n return False", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n if abs(numbers[i] - numbers[j]) < threshold:\n return True\n return False", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n if abs(numbers[i] - numbers[j]) < threshold:\n return True\n return False", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n if abs(numbers[i] - numbers[j]) < threshold:\n return True\n return False", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n if abs(numbers[i] - numbers[j]) < threshold:\n return True\n return False", "matching_cluster_idx": 6}]}, "HumanEval/4": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n n = len(numbers)\n if n == 0:\n return 0.0 # Handle empty list case\n\n mean = sum(numbers) / n\n absolute_deviations = [abs(x - mean) for x in numbers]\n mad = sum(absolute_deviations) / n\n return mad", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n n = len(numbers)\n if n == 0:\n return 0.0 # Handle empty list case\n\n mean = sum(numbers) / n\n absolute_deviations = [abs(x - mean) for x in numbers]\n mad = sum(absolute_deviations) / n\n return mad", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n n = len(numbers)\n if n == 0:\n return 0.0 # Handle empty list case\n\n mean = sum(numbers) / n\n absolute_deviations = [abs(x - mean) for x in numbers]\n mad = sum(absolute_deviations) / n\n return mad", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n n = len(numbers)\n if n == 0:\n return 0.0 # Handle empty list case\n\n mean = sum(numbers) / n\n absolute_deviations = [abs(x - mean) for x in numbers]\n mad = sum(absolute_deviations) / n\n return mad", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if not numbers:\n return 0.0 # Handle empty list case\n\n mean = sum(numbers) / len(numbers)\n absolute_deviations = [abs(x - mean) for x in numbers]\n mad = sum(absolute_deviations) / len(numbers)\n return mad", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n n = len(numbers)\n if n == 0:\n return 0.0 # Handle empty list case\n\n mean = sum(numbers) / n\n absolute_deviations = [abs(x - mean) for x in numbers]\n mad = sum(absolute_deviations) / n\n return mad", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n n = len(numbers)\n if n == 0:\n return 0.0 # Handle empty list case\n\n mean = sum(numbers) / n\n absolute_deviations = [abs(x - mean) for x in numbers]\n mad = sum(absolute_deviations) / n\n return mad", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n n = len(numbers)\n if n == 0:\n return 0.0 # Handle empty list case\n\n mean = sum(numbers) / n\n absolute_deviations = [abs(x - mean) for x in numbers]\n mad = sum(absolute_deviations) / n\n return mad", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n n = len(numbers)\n if n == 0:\n return 0.0 # Handle empty list case\n\n mean = sum(numbers) / n\n absolute_deviations = [abs(x - mean) for x in numbers]\n mad = sum(absolute_deviations) / n\n return mad", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n n = len(numbers)\n if n == 0:\n return 0.0 # Handle empty list case\n\n mean = sum(numbers) / n\n absolute_deviations = [abs(x - mean) for x in numbers]\n mad = sum(absolute_deviations) / n\n return mad", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n n = len(numbers)\n if n == 0:\n return 0.0 # Handle empty list case\n\n mean = sum(numbers) / n\n absolute_deviations = [abs(x - mean) for x in numbers]\n mad = sum(absolute_deviations) / n\n return mad", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n n = len(numbers)\n if n == 0:\n return 0.0 # Handle empty list case\n\n mean = sum(numbers) / n\n absolute_deviations = [abs(x - mean) for x in numbers]\n mad = sum(absolute_deviations) / n\n return mad", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n n = len(numbers)\n if n == 0:\n return 0.0 # Handle empty list case\n\n mean = sum(numbers) / n\n absolute_deviations = [abs(x - mean) for x in numbers]\n mad = sum(absolute_deviations) / n\n return mad", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n n = len(numbers)\n if n == 0:\n return 0.0 # Handle empty list case\n\n mean = sum(numbers) / n\n absolute_deviations = [abs(x - mean) for x in numbers]\n mad = sum(absolute_deviations) / n\n return mad", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n n = len(numbers)\n if n == 0:\n return 0.0 # Handle empty list case\n\n mean = sum(numbers) / n\n absolute_deviations = [abs(x - mean) for x in numbers]\n mad = sum(absolute_deviations) / n\n return mad", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n n = len(numbers)\n if n == 0:\n return 0.0 # Handle empty list case\n\n mean = sum(numbers) / n\n absolute_deviations = [abs(x - mean) for x in numbers]\n mad = sum(absolute_deviations) / n\n return mad", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n n = len(numbers)\n if n == 0:\n return 0.0 # Handle empty list case\n\n mean = sum(numbers) / n\n absolute_deviations = [abs(x - mean) for x in numbers]\n mad = sum(absolute_deviations) / n\n return mad", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n n = len(numbers)\n if n == 0:\n return 0.0 # Handle empty list case\n\n mean = sum(numbers) / n\n absolute_deviations = [abs(x - mean) for x in numbers]\n mad = sum(absolute_deviations) / n\n return mad", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n n = len(numbers)\n if n == 0:\n return 0.0 # Handle empty list case\n\n mean = sum(numbers) / n\n absolute_deviations = [abs(x - mean) for x in numbers]\n mad = sum(absolute_deviations) / n\n return mad", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n n = len(numbers)\n if n == 0:\n return 0.0 # Handle empty list case\n\n mean = sum(numbers) / n\n absolute_deviations = [abs(x - mean) for x in numbers]\n mad = sum(absolute_deviations) / n\n return mad", "matching_cluster_idx": 5}]}, "HumanEval/16": {"dps": 16.27906976744186, "dps_norm": 33.333333333333336, "pass@1": 100.0, "profiled": [{"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n distinct_chars = set()\n for char in string.lower():\n distinct_chars.add(char)\n return len(distinct_chars)", "matching_cluster_idx": 2}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n distinct_chars = set()\n for char in string.lower():\n distinct_chars.add(char)\n return len(distinct_chars)", "matching_cluster_idx": 2}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n distinct_chars = set()\n for char in string.lower():\n distinct_chars.add(char)\n return len(distinct_chars)", "matching_cluster_idx": 2}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n distinct_chars = set()\n for char in string.lower():\n distinct_chars.add(char)\n return len(distinct_chars)", "matching_cluster_idx": 2}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n distinct_chars = set()\n for char in string.lower():\n distinct_chars.add(char)\n return len(distinct_chars)", "matching_cluster_idx": 2}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n distinct_chars = set()\n for char in string.lower():\n distinct_chars.add(char)\n return len(distinct_chars)", "matching_cluster_idx": 2}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n distinct_chars = set()\n for char in string.lower():\n distinct_chars.add(char)\n return len(distinct_chars)", "matching_cluster_idx": 2}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n distinct_chars = set()\n for char in string.lower():\n distinct_chars.add(char)\n return len(distinct_chars)", "matching_cluster_idx": 2}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n distinct_chars = set()\n for char in string.lower():\n distinct_chars.add(char)\n return len(distinct_chars)", "matching_cluster_idx": 2}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n distinct_chars = set()\n for char in string.lower():\n distinct_chars.add(char)\n return len(distinct_chars)", "matching_cluster_idx": 2}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n distinct_chars = set()\n for char in string.lower():\n distinct_chars.add(char)\n return len(distinct_chars)", "matching_cluster_idx": 2}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n distinct_chars = set()\n for char in string.lower():\n distinct_chars.add(char)\n return len(distinct_chars)", "matching_cluster_idx": 2}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n distinct_chars = set()\n for char in string.lower():\n distinct_chars.add(char)\n return len(distinct_chars)", "matching_cluster_idx": 2}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n distinct_chars = set()\n for char in string.lower():\n distinct_chars.add(char)\n return len(distinct_chars)", "matching_cluster_idx": 2}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n distinct_chars = set()\n for char in string.lower():\n distinct_chars.add(char)\n return len(distinct_chars)", "matching_cluster_idx": 2}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n distinct_chars = set()\n for char in string.lower():\n distinct_chars.add(char)\n return len(distinct_chars)", "matching_cluster_idx": 2}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n distinct_chars = set()\n for char in string.lower():\n distinct_chars.add(char)\n return len(distinct_chars)", "matching_cluster_idx": 2}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n distinct_chars = set()\n for char in string.lower():\n distinct_chars.add(char)\n return len(distinct_chars)", "matching_cluster_idx": 2}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n distinct_chars = set()\n for char in string.lower():\n distinct_chars.add(char)\n return len(distinct_chars)", "matching_cluster_idx": 2}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n distinct_chars = set()\n for char in string.lower():\n distinct_chars.add(char)\n return len(distinct_chars)", "matching_cluster_idx": 2}]}, "HumanEval/20": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n numbers.sort()\n min_diff = float('inf')\n closest_pair = (None, None)\n\n for i in range(len(numbers) - 1):\n diff = numbers[i+1] - numbers[i]\n if diff < min_diff:\n min_diff = diff\n closest_pair = (numbers[i], numbers[i+1])\n\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n numbers.sort()\n min_diff = float('inf')\n closest_pair = (None, None)\n\n for i in range(len(numbers) - 1):\n diff = numbers[i+1] - numbers[i]\n if diff < min_diff:\n min_diff = diff\n closest_pair = (numbers[i], numbers[i+1])\n\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n numbers.sort()\n min_diff = float('inf')\n closest_pair = (None, None)\n\n for i in range(len(numbers) - 1):\n diff = numbers[i+1] - numbers[i]\n if diff < min_diff:\n min_diff = diff\n closest_pair = (numbers[i], numbers[i+1])\n\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n numbers.sort()\n min_diff = float('inf')\n closest_pair = (None, None)\n\n for i in range(len(numbers) - 1):\n diff = numbers[i+1] - numbers[i]\n if diff < min_diff:\n min_diff = diff\n closest_pair = (numbers[i], numbers[i+1])\n\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n numbers.sort()\n min_diff = float('inf')\n closest_pair = (None, None)\n\n for i in range(len(numbers) - 1):\n diff = numbers[i+1] - numbers[i]\n if diff < min_diff:\n min_diff = diff\n closest_pair = (numbers[i], numbers[i+1])\n\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n numbers.sort()\n min_diff = float('inf')\n closest_pair = (None, None)\n\n for i in range(len(numbers) - 1):\n diff = numbers[i+1] - numbers[i]\n if diff < min_diff:\n min_diff = diff\n closest_pair = (numbers[i], numbers[i+1])\n\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n numbers.sort()\n min_diff = float('inf')\n closest_pair = (None, None)\n\n for i in range(len(numbers) - 1):\n diff = numbers[i+1] - numbers[i]\n if diff < min_diff:\n min_diff = diff\n closest_pair = (numbers[i], numbers[i+1])\n\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n numbers.sort()\n min_diff = float('inf')\n closest_pair = (None, None)\n\n for i in range(len(numbers) - 1):\n diff = numbers[i+1] - numbers[i]\n if diff < min_diff:\n min_diff = diff\n closest_pair = (numbers[i], numbers[i+1])\n\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n numbers.sort()\n min_diff = float('inf')\n closest_pair = (None, None)\n\n for i in range(len(numbers) - 1):\n diff = numbers[i+1] - numbers[i]\n if diff < min_diff:\n min_diff = diff\n closest_pair = (numbers[i], numbers[i+1])\n\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n numbers.sort()\n min_diff = float('inf')\n closest_pair = (None, None)\n\n for i in range(len(numbers) - 1):\n diff = numbers[i+1] - numbers[i]\n if diff < min_diff:\n min_diff = diff\n closest_pair = (numbers[i], numbers[i+1])\n\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n numbers.sort()\n min_diff = float('inf')\n closest_pair = (None, None)\n\n for i in range(len(numbers) - 1):\n diff = numbers[i+1] - numbers[i]\n if diff < min_diff:\n min_diff = diff\n closest_pair = (numbers[i], numbers[i+1])\n\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n numbers.sort()\n min_diff = float('inf')\n closest_pair = (None, None)\n\n for i in range(len(numbers) - 1):\n diff = numbers[i+1] - numbers[i]\n if diff < min_diff:\n min_diff = diff\n closest_pair = (numbers[i], numbers[i+1])\n\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n numbers.sort()\n min_diff = float('inf')\n closest_pair = (None, None)\n\n for i in range(len(numbers) - 1):\n diff = numbers[i+1] - numbers[i]\n if diff < min_diff:\n min_diff = diff\n closest_pair = (numbers[i], numbers[i+1])\n\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n numbers.sort()\n min_diff = float('inf')\n closest_pair = (None, None)\n\n for i in range(len(numbers) - 1):\n diff = numbers[i+1] - numbers[i]\n if diff < min_diff:\n min_diff = diff\n closest_pair = (numbers[i], numbers[i+1])\n\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n numbers.sort()\n min_diff = float('inf')\n closest_pair = (None, None)\n\n for i in range(len(numbers) - 1):\n diff = numbers[i+1] - numbers[i]\n if diff < min_diff:\n min_diff = diff\n closest_pair = (numbers[i], numbers[i+1])\n\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n numbers.sort()\n min_diff = float('inf')\n closest_pair = (None, None)\n\n for i in range(len(numbers) - 1):\n diff = numbers[i+1] - numbers[i]\n if diff < min_diff:\n min_diff = diff\n closest_pair = (numbers[i], numbers[i+1])\n\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n numbers.sort()\n min_diff = float('inf')\n closest_pair = (None, None)\n\n for i in range(len(numbers) - 1):\n diff = numbers[i+1] - numbers[i]\n if diff < min_diff:\n min_diff = diff\n closest_pair = (numbers[i], numbers[i+1])\n\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n numbers.sort()\n min_diff = float('inf')\n closest_pair = (None, None)\n\n for i in range(len(numbers) - 1):\n diff = numbers[i+1] - numbers[i]\n if diff < min_diff:\n min_diff = diff\n closest_pair = (numbers[i], numbers[i+1])\n\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n numbers.sort()\n min_diff = float('inf')\n closest_pair = (None, None)\n\n for i in range(len(numbers) - 1):\n diff = numbers[i+1] - numbers[i]\n if diff < min_diff:\n min_diff = diff\n closest_pair = (numbers[i], numbers[i+1])\n\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n numbers.sort()\n min_diff = float('inf')\n closest_pair = (None, None)\n\n for i in range(len(numbers) - 1):\n diff = numbers[i+1] - numbers[i]\n if diff < min_diff:\n min_diff = diff\n closest_pair = (numbers[i], numbers[i+1])\n\n return closest_pair", "matching_cluster_idx": 8}]}, "HumanEval/24": {"dps": 97.27891156462586, "dps_norm": 62.5, "pass@1": 100.0, "profiled": [{"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n >>> largest_divisor(1)\n 1 #Handles edge case where n is 1. Largest divisor is itself.\n >>> largest_divisor(100)\n 50\n >>> largest_divisor(2)\n 1 #Handles edge case where n is prime\n \"\"\"\n if n <= 1:\n return n\n for i in range(n // 2, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 4}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n >>> largest_divisor(1)\n 1 #Handles edge case of 1\n >>> largest_divisor(2)\n 1 #Handles edge case of 2\n\n \"\"\"\n if n <= 1:\n return n\n for i in range(n // 2, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 4}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n >>> largest_divisor(1)\n 1\n >>> largest_divisor(2)\n 1\n >>> largest_divisor(100)\n 50\n\n \"\"\"\n if n <=1:\n return 1\n for i in range(n // 2, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 4}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n >>> largest_divisor(1)\n 1 #Handles the edge case where n is 1. Largest divisor is itself.\n >>> largest_divisor(2)\n 1\n >>> largest_divisor(100)\n 50\n\n \"\"\"\n if n <=1:\n return 1 #Handle edge cases where n is 0 or 1\n for i in range(n // 2, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 4}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n >>> largest_divisor(1)\n 1 #Handles edge case where n is 1. Largest divisor is itself.\n >>> largest_divisor(2)\n 1 #Handles edge case where n is prime.\n >>> largest_divisor(100)\n 50\n \"\"\"\n if n <=1:\n return n\n for i in range(n // 2, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 4}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n >>> largest_divisor(1)\n 1 # handles edge case of 1\n >>> largest_divisor(2)\n 1 # handles edge case of 2\n\n \"\"\"\n if n <= 1:\n return 1 # Handle edge cases of 1 and 2\n\n for i in range(n // 2, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 4}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n >>> largest_divisor(1)\n 1 #Edge Case: 1 is the largest divisor of 1, even though it's equal to 1.\n >>> largest_divisor(2)\n 1\n >>> largest_divisor(12)\n 6\n\n \"\"\"\n if n <=1:\n return 1 #Handle edge cases for 1 and numbers less than 1.\n\n for i in range(n // 2, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 4}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n >>> largest_divisor(1)\n 1 #Handles the edge case of 1\n >>> largest_divisor(100)\n 50\n >>> largest_divisor(7)\n 1 #Handles prime numbers\n\n \"\"\"\n if n <= 1:\n return 1\n for i in range(n // 2, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 4}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n >>> largest_divisor(1)\n 1 # handles edge case of 1\n >>> largest_divisor(2)\n 1 # handles edge case of prime numbers\n >>> largest_divisor(100)\n 50\n \"\"\"\n if n <= 1:\n return 1\n for i in range(n // 2, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 4}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n >>> largest_divisor(1)\n 1 #Handles edge case where n=1. Largest divisor is itself.\n >>> largest_divisor(2)\n 1\n >>> largest_divisor(100)\n 50\n \"\"\"\n if n <=1:\n return n #Handles edge cases where n is 0 or 1\n\n for i in range(n // 2, 0, -1): # Iterate downwards from n//2\n if n % i == 0:\n return i", "matching_cluster_idx": 4}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n >>> largest_divisor(1)\n 1 #Handles edge case of 1\n >>> largest_divisor(2)\n 1 #Handles edge case of prime numbers\n >>> largest_divisor(100)\n 50\n \"\"\"\n if n <= 1:\n return 1 #Handle edge cases for numbers less than or equal to 1\n\n for i in range(n // 2, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 4}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n >>> largest_divisor(1)\n 1 #Handles the edge case of 1\n >>> largest_divisor(12)\n 6\n >>> largest_divisor(7)\n 1 #Handles prime numbers\n \"\"\"\n if n <= 1:\n return n\n for i in range(n // 2, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 4}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n >>> largest_divisor(1)\n 1 #Handles edge case of 1\n >>> largest_divisor(2)\n 1 #Handles edge case of prime numbers\n >>> largest_divisor(100)\n 50\n \"\"\"\n if n <= 1:\n return n\n for i in range(n // 2, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 4}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n >>> largest_divisor(1)\n 1 #Edge case: 1 is handled as itself\n >>> largest_divisor(12)\n 6\n >>> largest_divisor(7)\n 1 #Prime numbers\n \"\"\"\n if n <=1:\n return n\n for i in range(n // 2, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 4}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n >>> largest_divisor(1)\n 1 #This is a edge case. Largest divisor of 1 is 1. Could also raise an exception.\n >>> largest_divisor(2)\n 1\n \"\"\"\n if n <=1:\n return 1\n for i in range(n // 2, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 4}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n if n <= 1:\n return 1 # Handle cases where n is 0 or 1\n\n for i in range(n // 2, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 4}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n >>> largest_divisor(12)\n 6\n >>> largest_divisor(7)\n 1\n >>> largest_divisor(1)\n 1\n\n \"\"\"\n if n <= 1:\n return 1\n for i in range(n // 2, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 4}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n >>> largest_divisor(1)\n 1 #Edge case: 1 is the largest divisor of itself, even though it's not smaller.\n >>> largest_divisor(2)\n 1\n >>> largest_divisor(100)\n 50\n\n \"\"\"\n if n <= 1:\n return 1 # Handle edge cases where n is 1 or less\n\n for i in range(n // 2, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 4}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n >>> largest_divisor(1)\n 1 #Handles edge case of 1\n >>> largest_divisor(2)\n 1 #Handles edge case of prime numbers\n \"\"\"\n if n <=1:\n return 1\n for i in range(n // 2, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 4}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n >>> largest_divisor(12)\n 6\n >>> largest_divisor(7)\n 1\n \"\"\"\n if n <= 1:\n return 1 # Handle cases where n is 0 or 1\n\n for i in range(n // 2, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 4}]}, "HumanEval/26": {"dps": 31.6, "dps_norm": 76.25, "pass@1": 100.0, "profiled": [{"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n counts = {}\n result = []\n for num in numbers:\n if num not in counts:\n counts[num] = 0\n counts[num] += 1\n for num in numbers:\n if counts[num] == 1:\n result.append(num)\n return result", "matching_cluster_idx": 2}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n counts = {}\n result = []\n for num in numbers:\n if num not in counts:\n counts[num] = 0\n counts[num] += 1\n\n for num in numbers:\n if counts[num] == 1:\n result.append(num)\n return result", "matching_cluster_idx": 2}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n counts = {}\n result = []\n for num in numbers:\n if num not in counts:\n counts[num] = 0\n counts[num] += 1\n for num in numbers:\n if counts[num] == 1:\n result.append(num)\n return result", "matching_cluster_idx": 2}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n counts = {}\n result = []\n for num in numbers:\n if num not in counts:\n counts[num] = 0\n counts[num] += 1\n for num in numbers:\n if counts[num] == 1:\n result.append(num)\n return result", "matching_cluster_idx": 2}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n counts = {}\n result = []\n for num in numbers:\n if num not in counts:\n counts[num] = 0\n counts[num] += 1\n\n for num in numbers:\n if counts[num] == 1:\n result.append(num)\n return result", "matching_cluster_idx": 2}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n counts = {}\n result = []\n for num in numbers:\n if num not in counts:\n counts[num] = 0\n counts[num] += 1\n\n for num in numbers:\n if counts[num] == 1:\n result.append(num)\n return result", "matching_cluster_idx": 2}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n counts = {}\n result = []\n for num in numbers:\n if num not in counts:\n counts[num] = 0\n counts[num] += 1\n for num in numbers:\n if counts[num] == 1:\n result.append(num)\n return result", "matching_cluster_idx": 2}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n counts = {}\n result = []\n for num in numbers:\n if num not in counts:\n counts[num] = 0\n counts[num] += 1\n\n for num in numbers:\n if counts[num] == 1:\n result.append(num)\n return result", "matching_cluster_idx": 2}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n counts = {}\n result = []\n for num in numbers:\n if num not in counts:\n counts[num] = 0\n counts[num] += 1\n\n for num in numbers:\n if counts[num] == 1:\n result.append(num)\n return result", "matching_cluster_idx": 2}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n counts = {}\n result = []\n for num in numbers:\n if num not in counts:\n counts[num] = 0\n counts[num] += 1\n for num in numbers:\n if counts[num] == 1:\n result.append(num)\n return result", "matching_cluster_idx": 2}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n counts = {}\n result = []\n for num in numbers:\n counts[num] = counts.get(num, 0) + 1\n for num in numbers:\n if counts[num] == 1:\n result.append(num)\n return result", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n counts = {}\n result = []\n for num in numbers:\n if num not in counts:\n counts[num] = 0\n counts[num] += 1\n\n for num in numbers:\n if counts[num] == 1:\n result.append(num)\n return result", "matching_cluster_idx": 2}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n counts = {}\n result = []\n for num in numbers:\n if num not in counts:\n counts[num] = 0\n counts[num] += 1\n for num in numbers:\n if counts[num] == 1:\n result.append(num)\n return result", "matching_cluster_idx": 2}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n counts = {}\n result = []\n for num in numbers:\n if num not in counts:\n counts[num] = 0\n counts[num] += 1\n for num in numbers:\n if counts[num] == 1:\n result.append(num)\n return result", "matching_cluster_idx": 2}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n counts = {}\n result = []\n for num in numbers:\n if num not in counts:\n counts[num] = 0\n counts[num] += 1\n for num in numbers:\n if counts[num] == 1:\n result.append(num)\n return result", "matching_cluster_idx": 2}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n counts = {}\n result = []\n for num in numbers:\n if num not in counts:\n counts[num] = 0\n counts[num] += 1\n for num in numbers:\n if counts[num] == 1:\n result.append(num)\n return result", "matching_cluster_idx": 2}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n counts = {}\n result = []\n for num in numbers:\n if num not in counts:\n counts[num] = 0\n counts[num] += 1\n for num in numbers:\n if counts[num] == 1:\n result.append(num)\n return result", "matching_cluster_idx": 2}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n counts = {}\n result = []\n for num in numbers:\n if num not in counts:\n counts[num] = 0\n counts[num] += 1\n for num in numbers:\n if counts[num] == 1:\n result.append(num)\n return result", "matching_cluster_idx": 2}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n counts = {}\n result = []\n for num in numbers:\n if num not in counts:\n counts[num] = 0\n counts[num] += 1\n for num in numbers:\n if counts[num] == 1:\n result.append(num)\n return result", "matching_cluster_idx": 2}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n counts = {}\n result = []\n for num in numbers:\n if num not in counts:\n counts[num] = 0\n counts[num] += 1\n for num in numbers:\n if counts[num] == 1:\n result.append(num)\n return result", "matching_cluster_idx": 2}]}, "HumanEval/31": {"dps": 88.10126582278481, "dps_norm": 85.0, "pass@1": 100.0, "profiled": [{"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i = i + 6\n return True", "matching_cluster_idx": 5}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i = i + 6\n return True", "matching_cluster_idx": 5}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i = i + 6\n return True", "matching_cluster_idx": 5}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i = i + 6\n return True", "matching_cluster_idx": 5}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}]}, "HumanEval/33": {"dps": null, "dps_norm": null, "pass@1": 0.0, "profiled": []}, "HumanEval/34": {"dps": 58.5377358490566, "dps_norm": 82.0, "pass@1": 100.0, "profiled": [{"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n unique_elements = set(l) #Sets automatically handle uniqueness\n sorted_unique_elements = sorted(list(unique_elements)) #Convert back to list and sort\n return sorted_unique_elements", "matching_cluster_idx": 3}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(list(set(l)))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n unique_elements = set(l) #Sets automatically remove duplicates\n sorted_unique_elements = sorted(list(unique_elements)) #Convert back to list and sort\n return sorted_unique_elements", "matching_cluster_idx": 3}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n unique_elements = set(l) # Use a set to automatically remove duplicates\n sorted_unique_elements = sorted(list(unique_elements)) #Convert back to list and sort\n return sorted_unique_elements", "matching_cluster_idx": 3}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n unique_elements = sorted(list(set(l)))\n return unique_elements", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n unique_elements = set(l) #Use a set to automatically remove duplicates\n sorted_unique_elements = sorted(list(unique_elements)) #Convert back to list and sort\n return sorted_unique_elements", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n unique_elements = []\n for element in l:\n if element not in unique_elements:\n unique_elements.append(element)\n unique_elements.sort()\n return unique_elements", "matching_cluster_idx": 0}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(list(set(l)))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n unique_list = []\n for item in l:\n if item not in unique_list:\n unique_list.append(item)\n unique_list.sort()\n return unique_list", "matching_cluster_idx": 0}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(list(set(l)))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(list(set(l)))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n unique_elements = sorted(list(set(l)))\n return unique_elements", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n unique_elements = set(l) #Sets automatically handle uniqueness\n sorted_unique_elements = sorted(list(unique_elements)) #Convert back to list and sort\n return sorted_unique_elements", "matching_cluster_idx": 3}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n unique_elements = set(l) #Sets only store unique elements\n sorted_unique = sorted(list(unique_elements)) # Convert back to list and sort\n return sorted_unique", "matching_cluster_idx": 3}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n unique_elements = sorted(list(set(l)))\n return unique_elements", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(list(set(l)))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n unique_elements = set(l) #Sets automatically handle uniqueness\n sorted_unique_elements = sorted(list(unique_elements)) #Convert back to list and sort\n return sorted_unique_elements", "matching_cluster_idx": 3}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n unique_elements = set(l) #Use a set to automatically remove duplicates\n sorted_unique = sorted(list(unique_elements)) #Convert back to list and sort\n return sorted_unique", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n unique_list = []\n for item in l:\n if item not in unique_list:\n unique_list.append(item)\n unique_list.sort()\n return unique_list", "matching_cluster_idx": 0}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(list(set(l)))", "matching_cluster_idx": 4}]}, "HumanEval/36": {"dps": 96.77419354838709, "dps_norm": 71.42857142857143, "pass@1": 100.0, "profiled": [{"solution": "def fizz_buzz(n: int):\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int):\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int):\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int):\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int):\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int):\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int):\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int):\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int):\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int):\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int):\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int):\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int):\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int):\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int):\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int):\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int):\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int):\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int):\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int):\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}]}, "HumanEval/37": {"dps": 94.92635024549918, "dps_norm": 90.0, "pass@1": 100.0, "profiled": [{"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n even_indices = l[::2]\n odd_indices = l[1::2]\n even_indices.sort()\n l_prime = []\n i = 0\n j = 0\n while i < len(even_indices) or j < len(odd_indices):\n if i < len(even_indices):\n l_prime.append(even_indices[i])\n i += 1\n if j < len(odd_indices):\n l_prime.append(odd_indices[j])\n j += 1\n return l_prime", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n even_indices = l[::2]\n odd_indices = l[1::2]\n even_indices.sort()\n \n result = []\n i = 0\n j = 0\n while i < len(even_indices) or j < len(odd_indices):\n if i < len(even_indices):\n result.append(even_indices[i])\n i += 1\n if j < len(odd_indices):\n result.append(odd_indices[j])\n j += 1\n\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n even_indices = l[::2]\n odd_indices = l[1::2]\n even_indices.sort()\n l_prime = []\n i = 0\n j = 0\n while i < len(even_indices) or j < len(odd_indices):\n if i < len(even_indices):\n l_prime.append(even_indices[i])\n i += 1\n if j < len(odd_indices):\n l_prime.append(odd_indices[j])\n j += 1\n return l_prime", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n even_indices = l[::2]\n odd_indices = l[1::2]\n even_indices.sort()\n l_prime = []\n for i in range(len(l)):\n if i % 2 == 0:\n l_prime.append(even_indices[i//2])\n else:\n l_prime.append(odd_indices[i//2])\n return l_prime", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n even_indices = l[::2]\n odd_indices = l[1::2]\n even_indices.sort()\n result = []\n i = 0\n j = 0\n while i < len(even_indices) or j < len(odd_indices):\n if i < len(even_indices):\n result.append(even_indices[i])\n i += 1\n if j < len(odd_indices):\n result.append(odd_indices[j])\n j += 1\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n even_indices = l[::2]\n odd_indices = l[1::2]\n even_indices.sort()\n result = []\n i = 0\n j = 0\n while i < len(even_indices) or j < len(odd_indices):\n if i < len(even_indices):\n result.append(even_indices[i])\n i += 1\n if j < len(odd_indices):\n result.append(odd_indices[j])\n j += 1\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n even_indices = l[::2]\n odd_indices = l[1::2]\n even_indices.sort()\n l_prime = []\n i = 0\n j = 0\n while i < len(even_indices) or j < len(odd_indices):\n if i < len(even_indices):\n l_prime.append(even_indices[i])\n i += 1\n if j < len(odd_indices):\n l_prime.append(odd_indices[j])\n j += 1\n return l_prime", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n even_indices = l[::2]\n odd_indices = l[1::2]\n even_indices.sort()\n \n result = []\n even_index = 0\n odd_index = 0\n for i in range(len(l)):\n if i % 2 == 0:\n result.append(even_indices[even_index])\n even_index +=1\n else:\n result.append(odd_indices[odd_index])\n odd_index += 1\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n even_indices = l[::2]\n odd_indices = l[1::2]\n even_indices.sort()\n l_prime = []\n i = 0\n j = 0\n while i < len(even_indices) or j < len(odd_indices):\n if i < len(even_indices):\n l_prime.append(even_indices[i])\n i += 1\n if j < len(odd_indices):\n l_prime.append(odd_indices[j])\n j += 1\n return l_prime", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n even_indices = l[::2]\n odd_indices = l[1::2]\n even_indices.sort()\n l_prime = []\n i = 0\n j = 0\n while i < len(even_indices) or j < len(odd_indices):\n if i < len(even_indices):\n l_prime.append(even_indices[i])\n i += 1\n if j < len(odd_indices):\n l_prime.append(odd_indices[j])\n j += 1\n return l_prime", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n even_indices = l[::2]\n odd_indices = l[1::2]\n even_indices.sort()\n \n result = []\n even_index = 0\n odd_index = 0\n for i in range(len(l)):\n if i % 2 == 0:\n result.append(even_indices[even_index])\n even_index += 1\n else:\n result.append(odd_indices[odd_index])\n odd_index += 1\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n even_indices = l[::2]\n odd_indices = l[1::2]\n even_indices.sort()\n l_prime = []\n i = 0\n j = 0\n while i < len(even_indices) or j < len(odd_indices):\n if i < len(even_indices):\n l_prime.append(even_indices[i])\n i += 1\n if j < len(odd_indices):\n l_prime.append(odd_indices[j])\n j += 1\n return l_prime", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n even_indices = l[::2]\n odd_indices = l[1::2]\n even_indices.sort()\n \n result = []\n even_index = 0\n odd_index = 0\n for i in range(len(l)):\n if i % 2 == 0:\n result.append(even_indices[even_index])\n even_index += 1\n else:\n result.append(odd_indices[odd_index])\n odd_index += 1\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n even_indices = l[::2]\n odd_indices = l[1::2]\n even_indices.sort()\n result = []\n i = 0\n j = 0\n while i < len(even_indices) or j < len(odd_indices):\n if i < len(even_indices):\n result.append(even_indices[i])\n i += 1\n if j < len(odd_indices):\n result.append(odd_indices[j])\n j += 1\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n even_indices = l[::2]\n odd_indices = l[1::2]\n even_indices.sort()\n \n result = []\n even_index = 0\n odd_index = 0\n for i in range(len(l)):\n if i % 2 == 0:\n result.append(even_indices[even_index])\n even_index += 1\n else:\n result.append(odd_indices[odd_index])\n odd_index += 1\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n even_indices = l[::2]\n odd_indices = l[1::2]\n even_indices.sort()\n l_prime = []\n i = 0\n j = 0\n while i < len(even_indices) or j < len(odd_indices):\n if i < len(even_indices):\n l_prime.append(even_indices[i])\n i += 1\n if j < len(odd_indices):\n l_prime.append(odd_indices[j])\n j += 1\n return l_prime", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n even_indices = l[::2]\n odd_indices = l[1::2]\n even_indices.sort()\n \n result = []\n even_index = 0\n odd_index = 0\n for i in range(len(l)):\n if i % 2 == 0:\n result.append(even_indices[even_index])\n even_index +=1\n else:\n result.append(odd_indices[odd_index])\n odd_index += 1\n\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n even_indices = l[::2]\n odd_indices = l[1::2]\n even_indices.sort()\n \n result = []\n even_index = 0\n odd_index = 0\n for i in range(len(l)):\n if i % 2 == 0:\n result.append(even_indices[even_index])\n even_index +=1\n else:\n result.append(odd_indices[odd_index])\n odd_index += 1\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n even_indices = l[::2]\n odd_indices = l[1::2]\n even_indices.sort()\n \n result = []\n even_index = 0\n odd_index = 0\n for i in range(len(l)):\n if i % 2 == 0:\n result.append(even_indices[even_index])\n even_index += 1\n else:\n result.append(odd_indices[odd_index])\n odd_index += 1\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n even_indices = l[::2]\n odd_indices = l[1::2]\n even_indices.sort()\n \n result = []\n even_index = 0\n odd_index = 0\n for i in range(len(l)):\n if i % 2 == 0:\n result.append(even_indices[even_index])\n even_index += 1\n else:\n result.append(odd_indices[odd_index])\n odd_index +=1\n \n return result", "matching_cluster_idx": 8}]}, "HumanEval/49": {"dps": null, "dps_norm": null, "pass@1": 0.0, "profiled": []}, "HumanEval/51": {"dps": 96.13526570048309, "dps_norm": 75.0, "pass@1": 100.0, "profiled": [{"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n result = \"\"\n for char in text:\n if char not in vowels:\n result += char\n return result", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n result = \"\"\n for char in text:\n if char not in vowels:\n result += char\n return result", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n result = \"\"\n for char in text:\n if char not in vowels:\n result += char\n return result", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n result = \"\"\n for char in text:\n if char not in vowels:\n result += char\n return result", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n result = \"\"\n for char in text:\n if char not in vowels:\n result += char\n return result", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n result = \"\"\n for char in text:\n if char not in vowels:\n result += char\n return result", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n result = \"\"\n for char in text:\n if char not in vowels:\n result += char\n return result", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n result = \"\"\n for char in text:\n if char not in vowels:\n result += char\n return result", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n result = \"\"\n for char in text:\n if char not in vowels:\n result += char\n return result", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n result = \"\"\n for char in text:\n if char not in vowels:\n result += char\n return result", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n result = \"\"\n for char in text:\n if char not in vowels:\n result += char\n return result", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n result = \"\"\n for char in text:\n if char not in vowels:\n result += char\n return result", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n result = \"\"\n for char in text:\n if char not in vowels:\n result += char\n return result", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n result = \"\"\n for char in text:\n if char not in vowels:\n result += char\n return result", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n result = \"\"\n for char in text:\n if char not in vowels:\n result += char\n return result", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n result = \"\"\n for char in text:\n if char not in vowels:\n result += char\n return result", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n result = \"\"\n for char in text:\n if char not in vowels:\n result += char\n return result", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n result = \"\"\n for char in text:\n if char not in vowels:\n result += char\n return result", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n result = \"\"\n for char in text:\n if char not in vowels:\n result += char\n return result", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n result = \"\"\n for char in text:\n if char not in vowels:\n result += char\n return result", "matching_cluster_idx": 5}]}, "HumanEval/54": {"dps": null, "dps_norm": null, "pass@1": 0.0, "profiled": []}, "HumanEval/58": {"dps": 42.362204724409445, "dps_norm": 40.0, "pass@1": 100.0, "profiled": [{"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n\n \"\"\"\n common_elements = []\n for element in l1:\n if element in l2 and element not in common_elements:\n common_elements.append(element)\n common_elements.sort()\n return common_elements", "matching_cluster_idx": 0}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n\n \"\"\"\n common_elements = []\n for element in l1:\n if element in l2 and element not in common_elements:\n common_elements.append(element)\n common_elements.sort()\n return common_elements", "matching_cluster_idx": 0}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n\n \"\"\"\n common_elements = []\n for element in l1:\n if element in l2 and element not in common_elements:\n common_elements.append(element)\n common_elements.sort()\n return common_elements", "matching_cluster_idx": 0}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n\n \"\"\"\n common_elements = set(l1) & set(l2) #Efficiently find common elements using sets\n return sorted(list(common_elements)) #Convert back to list and sort", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n\n \"\"\"\n common_elements = []\n for element in l1:\n if element in l2 and element not in common_elements:\n common_elements.append(element)\n common_elements.sort()\n return common_elements", "matching_cluster_idx": 0}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n\n \"\"\"\n common_elements = []\n for element in l1:\n if element in l2 and element not in common_elements:\n common_elements.append(element)\n common_elements.sort()\n return common_elements", "matching_cluster_idx": 0}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n\n \"\"\"\n common_elements = []\n for element in l1:\n if element in l2 and element not in common_elements:\n common_elements.append(element)\n common_elements.sort()\n return common_elements", "matching_cluster_idx": 0}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n\n \"\"\"\n common_elements = []\n for element in l1:\n if element in l2 and element not in common_elements:\n common_elements.append(element)\n common_elements.sort()\n return common_elements", "matching_cluster_idx": 0}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n\n \"\"\"\n common_elements = set(l1) & set(l2) #Efficiently find common elements using sets\n return sorted(list(common_elements)) #Convert back to list and sort", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n\n \"\"\"\n common_elements = set(l1) & set(l2) #Efficiently find common elements using sets\n return sorted(list(common_elements)) # Convert back to list and sort", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n\n \"\"\"\n common_elements = set(l1) & set(l2) #Efficiently find common elements using sets\n return sorted(list(common_elements)) #Convert back to list and sort", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n\n \"\"\"\n common_elements = []\n for element in l1:\n if element in l2 and element not in common_elements:\n common_elements.append(element)\n common_elements.sort()\n return common_elements", "matching_cluster_idx": 0}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n\n \"\"\"\n common_elements = []\n for element in l1:\n if element in l2 and element not in common_elements:\n common_elements.append(element)\n common_elements.sort()\n return common_elements", "matching_cluster_idx": 0}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n\n \"\"\"\n common_elements = []\n for element in l1:\n if element in l2 and element not in common_elements:\n common_elements.append(element)\n common_elements.sort()\n return common_elements", "matching_cluster_idx": 0}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n\n \"\"\"\n common_elements = set(l1) & set(l2) #Efficiently find common elements using sets\n return sorted(list(common_elements))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n\n \"\"\"\n common_elements = set(l1) & set(l2) # Efficiently find common elements using sets\n return sorted(list(common_elements)) # Convert back to list and sort", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n\n \"\"\"\n common_elements = []\n for element in l1:\n if element in l2 and element not in common_elements:\n common_elements.append(element)\n common_elements.sort()\n return common_elements", "matching_cluster_idx": 0}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n\n \"\"\"\n common_elements = []\n for element in l1:\n if element in l2 and element not in common_elements:\n common_elements.append(element)\n common_elements.sort()\n return common_elements", "matching_cluster_idx": 0}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n\n \"\"\"\n common_elements = set(l1) & set(l2)\n return sorted(list(common_elements))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n\n \"\"\"\n common_elements = []\n for element in l1:\n if element in l2 and element not in common_elements:\n common_elements.append(element)\n common_elements.sort()\n return common_elements", "matching_cluster_idx": 0}]}, "HumanEval/59": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n i = 2\n largest_prime = 1\n while i * i <= n:\n while n % i == 0:\n largest_prime = i\n n //= i\n i += 1\n if n > 1:\n largest_prime = n\n return largest_prime", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n i = 2\n largest_prime = 1\n while i * i <= n:\n while n % i == 0:\n largest_prime = i\n n //= i\n i += 1\n if n > 1:\n largest_prime = n\n return largest_prime", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n i = 2\n largest_factor = 1\n while i * i <= n:\n while n % i == 0:\n largest_factor = i\n n //= i\n i += 1\n if n > 1:\n largest_factor = n\n return largest_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n i = 2\n largest_prime = 1\n while i * i <= n:\n while n % i == 0:\n largest_prime = i\n n //= i\n i += 1\n if n > 1:\n largest_prime = n\n return largest_prime", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n i = 2\n largest_factor = 1\n while i * i <= n:\n while n % i == 0:\n largest_factor = i\n n //= i\n i += 1\n if n > 1:\n largest_factor = n\n return largest_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n i = 2\n largest_prime = 1\n while i * i <= n:\n while n % i == 0:\n largest_prime = i\n n //= i\n i += 1\n if n > 1:\n largest_prime = n\n return largest_prime", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n i = 2\n largest_prime = 1\n while i * i <= n:\n while n % i == 0:\n largest_prime = i\n n //= i\n i += 1\n if n > 1:\n largest_prime = n\n return largest_prime", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n i = 2\n largest_prime = 1\n while i * i <= n:\n while n % i == 0:\n largest_prime = i\n n //= i\n i += 1\n if n > 1:\n largest_prime = n\n return largest_prime", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n i = 2\n largest_factor = 1\n while i * i <= n:\n while n % i == 0:\n largest_factor = i\n n //= i\n i += 1\n if n > 1:\n largest_factor = n\n return largest_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n i = 2\n largest_prime = 1\n while i * i <= n:\n while n % i == 0:\n largest_prime = i\n n //= i\n i += 1\n if n > 1:\n largest_prime = n\n return largest_prime", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n i = 2\n largest_prime = 1\n while i * i <= n:\n while n % i == 0:\n largest_prime = i\n n //= i\n i += 1\n if n > 1:\n largest_prime = n\n return largest_prime", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n i = 2\n largest_prime = 1\n while i * i <= n:\n while n % i == 0:\n largest_prime = i\n n //= i\n i += 1\n if n > 1:\n largest_prime = n\n return largest_prime", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n i = 2\n largest_prime = 1\n while i * i <= n:\n while n % i == 0:\n largest_prime = i\n n //= i\n i += 1\n if n > 1:\n largest_prime = n\n return largest_prime", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n i = 2\n largest_prime = 1\n while i * i <= n:\n while n % i == 0:\n largest_prime = i\n n //= i\n i += 1\n if n > 1:\n largest_prime = n\n return largest_prime", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n i = 2\n largest_factor = 1\n while i * i <= n:\n while n % i == 0:\n largest_factor = i\n n //= i\n i += 1\n if n > 1:\n largest_factor = n\n return largest_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n i = 2\n largest_factor = 1\n while i * i <= n:\n while n % i == 0:\n largest_factor = i\n n //= i\n i += 1\n if n > 1:\n largest_factor = n\n return largest_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n i = 2\n largest_factor = 1\n while i * i <= n:\n while n % i == 0:\n largest_factor = i\n n //= i\n i += 1\n if n > 1:\n largest_factor = n\n return largest_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n i = 2\n largest_factor = 1\n while i * i <= n:\n while n % i == 0:\n largest_factor = i\n n //= i\n i += 1\n if n > 1:\n largest_factor = n\n return largest_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n i = 2\n largest_prime = 1\n while i * i <= n:\n while n % i == 0:\n largest_prime = i\n n //= i\n i += 1\n if n > 1:\n largest_prime = n\n return largest_prime", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n i = 2\n largest_prime = 1\n while i * i <= n:\n while n % i == 0:\n largest_prime = i\n n //= i\n i += 1\n if n > 1:\n largest_prime = n\n return largest_prime", "matching_cluster_idx": 8}]}, "HumanEval/64": {"dps": 36.94805194805194, "dps_norm": 43.125, "pass@1": 100.0, "profiled": [{"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = \"aeiouAEIOU\"\n count = 0\n for i, char in enumerate(s):\n if char in vowels:\n count += 1\n elif char.lower() == 'y' and i == len(s) - 1:\n count += 1\n return count", "matching_cluster_idx": 3}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = \"aeiouAEIOU\"\n count = 0\n for i, char in enumerate(s):\n if char in vowels:\n count += 1\n elif char == 'y' or char == 'Y':\n if i == len(s) - 1:\n count += 1\n return count", "matching_cluster_idx": 3}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = \"aeiouAEIOU\"\n count = 0\n for i, char in enumerate(s):\n if char in vowels:\n count += 1\n elif char == 'y' or char == 'Y':\n if i == len(s) - 1:\n count += 1\n return count", "matching_cluster_idx": 3}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = \"aeiou\"\n count = 0\n s = s.lower()\n for i, char in enumerate(s):\n if char in vowels:\n count += 1\n elif char == 'y' and i == len(s) - 1:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = \"aeiou\"\n count = 0\n s = s.lower()\n for i, char in enumerate(s):\n if char in vowels:\n count += 1\n elif char == 'y' and i == len(s) - 1:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = \"aeiou\"\n count = 0\n s = s.lower()\n for i, char in enumerate(s):\n if char in vowels:\n count += 1\n elif char == 'y' and i == len(s) - 1:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = \"aeiouAEIOU\"\n count = 0\n for i, char in enumerate(s):\n if char in vowels:\n count += 1\n elif char == 'y' or char == 'Y':\n if i == len(s) - 1:\n count += 1\n return count", "matching_cluster_idx": 3}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = \"aeiouAEIOU\"\n count = 0\n for i, char in enumerate(s):\n if char in vowels:\n count += 1\n elif char == 'y' or char == 'Y':\n if i == len(s) - 1:\n count += 1\n return count", "matching_cluster_idx": 3}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = \"aeiou\"\n count = 0\n s = s.lower()\n for i, char in enumerate(s):\n if char in vowels:\n count += 1\n elif char == 'y' and i == len(s) - 1:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = \"aeiouAEIOU\"\n count = 0\n for i, char in enumerate(s):\n if char in vowels:\n count += 1\n elif char == 'y' or char == 'Y':\n if i == len(s) - 1:\n count += 1\n return count", "matching_cluster_idx": 3}, {"solution": "import unittest\ndef vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = \"aeiou\"\n count = 0\n s = s.lower()\n for i, char in enumerate(s):\n if char in vowels:\n count += 1\n elif char == 'y' and i == len(s) - 1:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = \"aeiouAEIOU\"\n count = 0\n for i, char in enumerate(s):\n if char in vowels:\n count += 1\n elif char.lower() == 'y' and i == len(s) - 1:\n count += 1\n return count", "matching_cluster_idx": 3}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = \"aeiouAEIOU\"\n count = 0\n for i, char in enumerate(s):\n if char in vowels:\n count += 1\n elif char.lower() == 'y' and i == len(s) - 1:\n count += 1\n return count", "matching_cluster_idx": 3}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = \"aeiou\"\n count = 0\n s = s.lower()\n for i, char in enumerate(s):\n if char in vowels:\n count += 1\n elif char == 'y' and i == len(s) - 1:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n count = 0\n s = s.lower()\n vowels = \"aeiou\"\n for i, char in enumerate(s):\n if char in vowels:\n count += 1\n elif char == 'y' and i == len(s) - 1:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = \"aeiou\"\n count = 0\n s = s.lower()\n for i, char in enumerate(s):\n if char in vowels:\n count += 1\n elif char == 'y' and i == len(s) - 1:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = \"aeiouAEIOU\"\n count = 0\n for i, char in enumerate(s):\n if char in vowels:\n count += 1\n elif char.lower() == 'y' and i == len(s) - 1:\n count += 1\n return count", "matching_cluster_idx": 3}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = \"aeiou\"\n count = 0\n s = s.lower()\n for i, char in enumerate(s):\n if char in vowels:\n count += 1\n elif char == 'y' and i == len(s) - 1:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = \"aeiou\"\n count = 0\n s = s.lower()\n for i, char in enumerate(s):\n if char in vowels:\n count += 1\n elif char == 'y' and i == len(s) - 1:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = \"aeiou\"\n count = 0\n s = s.lower()\n for i, char in enumerate(s):\n if char in vowels:\n count += 1\n elif char == 'y' and i == len(s) - 1:\n count += 1\n return count", "matching_cluster_idx": 2}]}, "HumanEval/74": {"dps": 98.04878048780488, "dps_norm": 88.88888888888889, "pass@1": 100.0, "profiled": [{"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n len1 = sum(len(s) for s in lst1)\n len2 = sum(len(s) for s in lst2)\n\n if len1 <= len2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n len1 = sum(len(s) for s in lst1)\n len2 = sum(len(s) for s in lst2)\n if len1 <= len2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n len1 = sum(len(s) for s in lst1)\n len2 = sum(len(s) for s in lst2)\n\n if len1 <= len2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n len1 = sum(len(s) for s in lst1)\n len2 = sum(len(s) for s in lst2)\n\n if len1 <= len2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n len1 = sum(len(s) for s in lst1)\n len2 = sum(len(s) for s in lst2)\n\n if len1 <= len2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n len1 = sum(len(s) for s in lst1)\n len2 = sum(len(s) for s in lst2)\n\n if len1 <= len2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n len1 = sum(len(s) for s in lst1)\n len2 = sum(len(s) for s in lst2)\n if len1 <= len2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n len1 = sum(len(s) for s in lst1)\n len2 = sum(len(s) for s in lst2)\n if len1 <= len2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n len1 = sum(len(s) for s in lst1)\n len2 = sum(len(s) for s in lst2)\n if len1 <= len2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n len1 = sum(len(s) for s in lst1)\n len2 = sum(len(s) for s in lst2)\n\n if len1 <= len2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n \"\"\"\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n \"\"\"\n len1 = sum(len(s) for s in lst1)\n len2 = sum(len(s) for s in lst2)\n\n if len1 <= len2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n len1 = sum(len(s) for s in lst1)\n len2 = sum(len(s) for s in lst2)\n\n if len1 <= len2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n \"\"\"\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n \"\"\"\n len1 = sum(len(s) for s in lst1)\n len2 = sum(len(s) for s in lst2)\n\n if len1 <= len2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n len1 = sum(len(s) for s in lst1)\n len2 = sum(len(s) for s in lst2)\n\n if len1 <= len2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n len1 = sum(len(s) for s in lst1)\n len2 = sum(len(s) for s in lst2)\n\n if len1 <= len2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n \"\"\"\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n \"\"\"\n len1 = sum(len(s) for s in lst1)\n len2 = sum(len(s) for s in lst2)\n\n if len1 <= len2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n len1 = sum(len(s) for s in lst1)\n len2 = sum(len(s) for s in lst2)\n if len1 <= len2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n len1 = sum(len(s) for s in lst1)\n len2 = sum(len(s) for s in lst2)\n if len1 <= len2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n len1 = sum(len(s) for s in lst1)\n len2 = sum(len(s) for s in lst2)\n\n if len1 <= len2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n len1 = sum(len(s) for s in lst1)\n len2 = sum(len(s) for s in lst2)\n\n if len1 <= len2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}]}, "HumanEval/85": {"dps": 97.02970297029702, "dps_norm": 66.66666666666667, "pass@1": 100.0, "profiled": [{"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices..\n\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n sum_of_evens = 0\n for i in range(1, len(lst), 2):\n if lst[i] % 2 == 0:\n sum_of_evens += lst[i]\n return sum_of_evens", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices..\n\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n sum_of_evens = 0\n for i in range(1, len(lst), 2):\n if lst[i] % 2 == 0:\n sum_of_evens += lst[i]\n return sum_of_evens", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices..\n\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n sum_of_evens = 0\n for i in range(1, len(lst), 2):\n if lst[i] % 2 == 0:\n sum_of_evens += lst[i]\n return sum_of_evens", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices..\n\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n sum_of_evens = 0\n for i in range(1, len(lst), 2):\n if lst[i] % 2 == 0:\n sum_of_evens += lst[i]\n return sum_of_evens", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices..\n\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n sum_of_evens = 0\n for i in range(1, len(lst), 2):\n if lst[i] % 2 == 0:\n sum_of_evens += lst[i]\n return sum_of_evens", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices..\n\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n sum_of_evens = 0\n for i in range(1, len(lst), 2):\n if lst[i] % 2 == 0:\n sum_of_evens += lst[i]\n return sum_of_evens", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices..\n\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n sum_of_evens = 0\n for i in range(1, len(lst), 2):\n if lst[i] % 2 == 0:\n sum_of_evens += lst[i]\n return sum_of_evens", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices..\n\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n sum_of_evens = 0\n for i in range(1, len(lst), 2):\n if lst[i] % 2 == 0:\n sum_of_evens += lst[i]\n return sum_of_evens", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices..\n\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n sum_of_evens = 0\n for i in range(1, len(lst), 2):\n if lst[i] % 2 == 0:\n sum_of_evens += lst[i]\n return sum_of_evens", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices..\n\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n sum_of_evens = 0\n for i in range(1, len(lst), 2):\n if lst[i] % 2 == 0:\n sum_of_evens += lst[i]\n return sum_of_evens", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices..\n\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n sum_of_evens = 0\n for i in range(1, len(lst), 2):\n if lst[i] % 2 == 0:\n sum_of_evens += lst[i]\n return sum_of_evens", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices..\n\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n sum_even_odd_indices = 0\n for i in range(1, len(lst), 2):\n if lst[i] % 2 == 0:\n sum_even_odd_indices += lst[i]\n return sum_even_odd_indices", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices..\n\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n sum_even_odd_indices = 0\n for i in range(1, len(lst), 2):\n if lst[i] % 2 == 0:\n sum_even_odd_indices += lst[i]\n return sum_even_odd_indices", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices..\n\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n sum_of_evens = 0\n for i in range(1, len(lst), 2):\n if lst[i] % 2 == 0:\n sum_of_evens += lst[i]\n return sum_of_evens", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices..\n\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n sum_of_evens = 0\n for i in range(1, len(lst), 2):\n if lst[i] % 2 == 0:\n sum_of_evens += lst[i]\n return sum_of_evens", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices..\n\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n sum_of_evens = 0\n for i in range(1, len(lst), 2):\n if lst[i] % 2 == 0:\n sum_of_evens += lst[i]\n return sum_of_evens", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices..\n\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n sum_of_evens = 0\n for i in range(1, len(lst), 2):\n if lst[i] % 2 == 0:\n sum_of_evens += lst[i]\n return sum_of_evens", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices..\n\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n sum_of_evens = 0\n for i in range(1, len(lst), 2):\n if lst[i] % 2 == 0:\n sum_of_evens += lst[i]\n return sum_of_evens", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices..\n\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n sum_even_odd_indices = 0\n for i in range(1, len(lst), 2):\n if lst[i] % 2 == 0:\n sum_even_odd_indices += lst[i]\n return sum_even_odd_indices", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices..\n\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n sum_of_evens = 0\n for i in range(1, len(lst), 2):\n if lst[i] % 2 == 0:\n sum_of_evens += lst[i]\n return sum_of_evens", "matching_cluster_idx": 3}]}, "HumanEval/86": {"dps": null, "dps_norm": null, "pass@1": 0.0, "profiled": []}, "HumanEval/87": {"dps": null, "dps_norm": null, "pass@1": 6.0, "profiled": []}, "HumanEval/89": {"dps": 96.64948453608248, "dps_norm": 28.571428571428573, "pass@1": 100.0, "profiled": [{"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places (i.e., shifted by 4 places).\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n encrypted_string = \"\"\n for char in s:\n if 'a' <= char <= 'z':\n encrypted_char = chr(((ord(char) - ord('a') + 4) % 26) + ord('a'))\n elif 'A' <= char <= 'Z':\n encrypted_char = chr(((ord(char) - ord('A') + 4) % 26) + ord('A'))\n else:\n encrypted_char = char # Keep non-alphabetic characters unchanged\n encrypted_string += encrypted_char\n return encrypted_string", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n encrypted_string = \"\"\n for char in s:\n if 'a' <= char <= 'z':\n encrypted_char = chr(((ord(char) - ord('a') + 4) % 26) + ord('a'))\n elif 'A' <= char <= 'Z':\n encrypted_char = chr(((ord(char) - ord('A') + 4) % 26) + ord('A'))\n else:\n encrypted_char = char # Keep non-alphabetic characters unchanged\n encrypted_string += encrypted_char\n return encrypted_string", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n encrypted_string = \"\"\n for char in s:\n if 'a' <= char <= 'z':\n encrypted_char = chr(((ord(char) - ord('a') + 4) % 26) + ord('a'))\n elif 'A' <= char <= 'Z':\n encrypted_char = chr(((ord(char) - ord('A') + 4) % 26) + ord('A'))\n else:\n encrypted_char = char # Keep non-alphabetic characters as they are\n encrypted_string += encrypted_char\n return encrypted_string", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n encrypted_string = \"\"\n for char in s:\n if 'a' <= char <= 'z':\n encrypted_char = chr(((ord(char) - ord('a') + 4) % 26) + ord('a'))\n elif 'A' <= char <= 'Z':\n encrypted_char = chr(((ord(char) - ord('A') + 4) % 26) + ord('A'))\n else:\n encrypted_char = char # Keep non-alphabetic characters unchanged\n encrypted_string += encrypted_char\n return encrypted_string", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places (i.e., 4 places).\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n encrypted_string = \"\"\n for char in s:\n if 'a' <= char <= 'z':\n encrypted_char = chr(((ord(char) - ord('a') + 4) % 26) + ord('a'))\n elif 'A' <= char <= 'Z':\n encrypted_char = chr(((ord(char) - ord('A') + 4) % 26) + ord('A'))\n else:\n encrypted_char = char # Keep non-alphabetic characters unchanged\n encrypted_string += encrypted_char\n return encrypted_string", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n encrypted_string = \"\"\n for char in s:\n if 'a' <= char <= 'z':\n encrypted_char = chr(((ord(char) - ord('a') + 4) % 26) + ord('a'))\n elif 'A' <= char <= 'Z':\n encrypted_char = chr(((ord(char) - ord('A') + 4) % 26) + ord('A'))\n else:\n encrypted_char = char # Keep non-alphabetic characters unchanged\n encrypted_string += encrypted_char\n return encrypted_string", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n encrypted_string = \"\"\n for char in s:\n if 'a' <= char <= 'z':\n encrypted_char = chr(((ord(char) - ord('a') + 4) % 26) + ord('a'))\n elif 'A' <= char <= 'Z':\n encrypted_char = chr(((ord(char) - ord('A') + 4) % 26) + ord('A'))\n else:\n encrypted_char = char # Keep non-alphabetic characters unchanged\n encrypted_string += encrypted_char\n return encrypted_string", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places (i.e., shift down by 4 places).\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n encrypted_string = \"\"\n for char in s:\n if 'a' <= char <= 'z':\n encrypted_char = chr(((ord(char) - ord('a') + 4) % 26) + ord('a'))\n elif 'A' <= char <= 'Z':\n encrypted_char = chr(((ord(char) - ord('A') + 4) % 26) + ord('A'))\n else:\n encrypted_char = char # Keep non-alphabetic characters unchanged\n encrypted_string += encrypted_char\n return encrypted_string", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n encrypted_string = \"\"\n for char in s:\n if 'a' <= char <= 'z':\n encrypted_char = chr(((ord(char) - ord('a') + 4) % 26) + ord('a'))\n elif 'A' <= char <= 'Z':\n encrypted_char = chr(((ord(char) - ord('A') + 4) % 26) + ord('A'))\n else:\n encrypted_char = char # Keep non-alphabetic characters as they are\n encrypted_string += encrypted_char\n return encrypted_string", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places (i.e., four places).\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n encrypted_string = \"\"\n for char in s:\n if 'a' <= char <= 'z':\n encrypted_char = chr(((ord(char) - ord('a') + 4) % 26) + ord('a'))\n elif 'A' <= char <= 'Z':\n encrypted_char = chr(((ord(char) - ord('A') + 4) % 26) + ord('A'))\n else:\n encrypted_char = char # Keep non-alphabetic characters unchanged\n encrypted_string += encrypted_char\n return encrypted_string", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places (i.e., shifted by 4 places).\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n encrypted_string = \"\"\n for char in s:\n if 'a' <= char <= 'z':\n encrypted_char = chr(((ord(char) - ord('a') + 4) % 26) + ord('a'))\n elif 'A' <= char <= 'Z':\n encrypted_char = chr(((ord(char) - ord('A') + 4) % 26) + ord('A'))\n else:\n encrypted_char = char # Keep non-alphabetic characters unchanged\n encrypted_string += encrypted_char\n return encrypted_string", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places (i.e., shifted down by 4 places).\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n encrypted_string = \"\"\n for char in s:\n if 'a' <= char <= 'z':\n encrypted_char = chr(((ord(char) - ord('a') + 4) % 26) + ord('a'))\n elif 'A' <= char <= 'Z':\n encrypted_char = chr(((ord(char) - ord('A') + 4) % 26) + ord('A'))\n else:\n encrypted_char = char # Keep non-alphabetic characters unchanged\n encrypted_string += encrypted_char\n return encrypted_string", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places (i.e., shifted by 4 places).\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n encrypted_string = \"\"\n for char in s:\n if 'a' <= char <= 'z':\n encrypted_char = chr(((ord(char) - ord('a') + 4) % 26) + ord('a'))\n elif 'A' <= char <= 'Z':\n encrypted_char = chr(((ord(char) - ord('A') + 4) % 26) + ord('A'))\n else:\n encrypted_char = char # Keep non-alphabetic characters unchanged\n encrypted_string += encrypted_char\n return encrypted_string", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places (i.e., four places).\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n encrypted_string = \"\"\n for char in s:\n if 'a' <= char <= 'z':\n encrypted_char = chr(((ord(char) - ord('a') + 4) % 26) + ord('a'))\n elif 'A' <= char <= 'Z':\n encrypted_char = chr(((ord(char) - ord('A') + 4) % 26) + ord('A'))\n else:\n encrypted_char = char # Keep non-alphabetic characters unchanged\n encrypted_string += encrypted_char\n return encrypted_string", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places (i.e., shifted by 4 places).\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n encrypted_string = \"\"\n for char in s:\n if 'a' <= char <= 'z':\n encrypted_char = chr(((ord(char) - ord('a') + 4) % 26) + ord('a'))\n elif 'A' <= char <= 'Z':\n encrypted_char = chr(((ord(char) - ord('A') + 4) % 26) + ord('A'))\n else:\n encrypted_char = char # Keep non-alphabetic characters unchanged\n encrypted_string += encrypted_char\n return encrypted_string", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n encrypted_string = \"\"\n for char in s:\n if 'a' <= char <= 'z':\n encrypted_char = chr(((ord(char) - ord('a') + 4) % 26) + ord('a'))\n elif 'A' <= char <= 'Z':\n encrypted_char = chr(((ord(char) - ord('A') + 4) % 26) + ord('A'))\n else:\n encrypted_char = char # Keep non-alphabetic characters unchanged\n encrypted_string += encrypted_char\n return encrypted_string", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n encrypted_string = \"\"\n for char in s:\n if 'a' <= char <= 'z':\n encrypted_char = chr(((ord(char) - ord('a') + 4) % 26) + ord('a'))\n elif 'A' <= char <= 'Z':\n encrypted_char = chr(((ord(char) - ord('A') + 4) % 26) + ord('A'))\n else:\n encrypted_char = char # Keep non-alphabetic characters unchanged\n encrypted_string += encrypted_char\n return encrypted_string", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n encrypted_string = \"\"\n for char in s:\n if 'a' <= char <= 'z':\n encrypted_char = chr(((ord(char) - ord('a') + 4) % 26) + ord('a'))\n elif 'A' <= char <= 'Z':\n encrypted_char = chr(((ord(char) - ord('A') + 4) % 26) + ord('A'))\n else:\n encrypted_char = char # Keep non-alphabetic characters unchanged\n encrypted_string += encrypted_char\n return encrypted_string", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n encrypted_string = \"\"\n for char in s:\n if 'a' <= char <= 'z':\n encrypted_char = chr(((ord(char) - ord('a') + 4) % 26) + ord('a'))\n elif 'A' <= char <= 'Z':\n encrypted_char = chr(((ord(char) - ord('A') + 4) % 26) + ord('A'))\n else:\n encrypted_char = char # Keep non-alphabetic characters unchanged\n encrypted_string += encrypted_char\n return encrypted_string", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n encrypted_string = \"\"\n for char in s:\n if 'a' <= char <= 'z':\n encrypted_char = chr(((ord(char) - ord('a') + 4) % 26) + ord('a'))\n elif 'A' <= char <= 'Z':\n encrypted_char = chr(((ord(char) - ord('A') + 4) % 26) + ord('A'))\n else:\n encrypted_char = char # Keep non-alphabetic characters unchanged\n encrypted_string += encrypted_char\n return encrypted_string", "matching_cluster_idx": 1}]}, "HumanEval/90": {"dps": 57.12062256809339, "dps_norm": 51.25, "pass@1": 100.0, "profiled": [{"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n \n unique_lst = sorted(list(set(lst)))\n \n if len(unique_lst) < 2:\n return None\n else:\n return unique_lst[1]", "matching_cluster_idx": 5}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n \n unique_lst = sorted(list(set(lst)))\n \n if len(unique_lst) < 2:\n return None\n else:\n return unique_lst[1]", "matching_cluster_idx": 5}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n \n unique_lst = sorted(list(set(lst)))\n \n if len(unique_lst) < 2:\n return None\n else:\n return unique_lst[1]", "matching_cluster_idx": 5}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n \n unique_lst = sorted(list(set(lst))) #remove duplicates and sort\n if len(unique_lst) < 2:\n return None\n else:\n return unique_lst[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n \n unique_lst = sorted(list(set(lst)))\n \n if len(unique_lst) < 2:\n return None\n else:\n return unique_lst[1]", "matching_cluster_idx": 5}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n \n unique_lst = sorted(list(set(lst)))\n \n if len(unique_lst) < 2:\n return None\n else:\n return unique_lst[1]", "matching_cluster_idx": 5}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n \n unique_lst = sorted(list(set(lst)))\n \n if len(unique_lst) < 2:\n return None\n else:\n return unique_lst[1]", "matching_cluster_idx": 5}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n \n unique_lst = sorted(list(set(lst)))\n \n if len(unique_lst) < 2:\n return None\n else:\n return unique_lst[1]", "matching_cluster_idx": 5}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n \n unique_lst = sorted(list(set(lst)))\n \n if len(unique_lst) < 2:\n return None\n else:\n return unique_lst[1]", "matching_cluster_idx": 5}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n \n unique_lst = sorted(list(set(lst)))\n \n if len(unique_lst) < 2:\n return None\n else:\n return unique_lst[1]", "matching_cluster_idx": 5}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n \n unique_lst = sorted(list(set(lst)))\n \n if len(unique_lst) < 2:\n return None\n else:\n return unique_lst[1]", "matching_cluster_idx": 5}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n \n unique_lst = sorted(list(set(lst)))\n \n if len(unique_lst) < 2:\n return None\n else:\n return unique_lst[1]", "matching_cluster_idx": 5}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n \n unique_lst = sorted(list(set(lst)))\n if len(unique_lst) < 2:\n return None\n else:\n return unique_lst[1]", "matching_cluster_idx": 5}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n \n unique_lst = sorted(list(set(lst))) #Remove duplicates and sort\n \n if len(unique_lst) < 2:\n return None\n else:\n return unique_lst[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n \n unique_lst = sorted(list(set(lst)))\n \n if len(unique_lst) < 2:\n return None\n else:\n return unique_lst[1]", "matching_cluster_idx": 5}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n \n unique_lst = sorted(list(set(lst)))\n if len(unique_lst) < 2:\n return None\n else:\n return unique_lst[1]", "matching_cluster_idx": 5}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n \n unique_lst = sorted(list(set(lst)))\n \n if len(unique_lst) < 2:\n return None\n else:\n return unique_lst[1]", "matching_cluster_idx": 5}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n \n unique_lst = sorted(list(set(lst))) #remove duplicates and sort\n if len(unique_lst) < 2:\n return None\n else:\n return unique_lst[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n \n unique_lst = sorted(list(set(lst)))\n \n if len(unique_lst) < 2:\n return None\n else:\n return unique_lst[1]", "matching_cluster_idx": 5}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n \n unique_lst = sorted(list(set(lst)))\n \n if len(unique_lst) < 2:\n return None\n else:\n return unique_lst[1]", "matching_cluster_idx": 5}]}, "HumanEval/113": {"dps": 98.98580121703854, "dps_norm": 66.66666666666667, "pass@1": 100.0, "profiled": [{"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n result = []\n for s in lst:\n odd_count_in_string = 0\n for digit in s:\n if int(digit) % 2 != 0:\n odd_count_in_string += 1\n output_string = \"the number of odd elements \" + str(odd_count_in_string) + \"n the str\" + str(odd_count_in_string) + \"ng \" + str(odd_count_in_string) + \" of the \" + str(odd_count_in_string) + \"nput.\"\n result.append(output_string)\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n output = []\n for s in lst:\n odd_digits = 0\n for digit in s:\n if int(digit) % 2 != 0:\n odd_digits += 1\n output_string = \"the number of odd elements \" + str(odd_digits) + \"n the str\" + str(odd_digits) + \"ng \" + str(odd_digits) + \" of the \" + str(odd_digits) + \"nput.\"\n output.append(output_string)\n return output", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n result = []\n for s in lst:\n odd_digits = 0\n for digit in s:\n if int(digit) % 2 != 0:\n odd_digits += 1\n output_string = f\"the number of odd elements {odd_digits}n the str{odd_digits}ng {odd_digits} of the {odd_digits}nput.\"\n result.append(output_string)\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n result = []\n for s in lst:\n odd_digits = 0\n for digit in s:\n if int(digit) % 2 != 0:\n odd_digits += 1\n output_string = \"the number of odd elements \" + str(odd_digits) + \"n the str\" + str(odd_digits) + \"ng \" + str(odd_digits) + \" of the \" + str(odd_digits) + \"nput.\"\n result.append(output_string)\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n output = []\n for s in lst:\n odd_digits = 0\n for digit in s:\n if int(digit) % 2 != 0:\n odd_digits += 1\n output_string = \"the number of odd elements \" + str(odd_digits) + \"n the str\" + str(odd_digits) + \"ng \" + str(odd_digits) + \" of the \" + str(odd_digits) + \"nput.\"\n output.append(output_string)\n return output", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n output_list = []\n for s in lst:\n odd_digits = 0\n for digit in s:\n if int(digit) % 2 != 0:\n odd_digits += 1\n output_string = \"the number of odd elements \" + str(odd_digits) + \"n the str\" + str(odd_digits) + \"ng \" + str(odd_digits) + \" of the \" + str(odd_digits) + \"nput.\"\n output_list.append(output_string)\n return output_list", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n output = []\n for s in lst:\n odd_digits = 0\n for digit in s:\n if int(digit) % 2 != 0:\n odd_digits += 1\n output_string = \"the number of odd elements \" + str(odd_digits) + \"n the str\" + str(odd_digits) + \"ng \" + str(odd_digits) + \" of the \" + str(odd_digits) + \"nput.\"\n output.append(output_string)\n return output", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n output_list = []\n for s in lst:\n odd_digits = 0\n for digit in s:\n if int(digit) % 2 != 0:\n odd_digits += 1\n output_string = \"the number of odd elements \" + str(odd_digits) + \"n the str\" + str(odd_digits) + \"ng \" + str(odd_digits) + \" of the \" + str(odd_digits) + \"nput.\"\n output_list.append(output_string)\n return output_list", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n output = []\n for s in lst:\n count = 0\n for digit in s:\n if int(digit) % 2 != 0:\n count += 1\n output_string = \"the number of odd elements \" + str(count) + \"n the str\" + str(count) + \"ng \" + str(count) + \" of the \" + str(count) + \"nput.\"\n output.append(output_string)\n return output", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n output = []\n for s in lst:\n odd_digits = 0\n for digit in s:\n if int(digit) % 2 != 0:\n odd_digits += 1\n output_string = \"the number of odd elements \" + str(odd_digits) + \"n the str\" + str(odd_digits) + \"ng \" + str(odd_digits) + \" of the \" + str(odd_digits) + \"nput.\"\n output.append(output_string)\n return output", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n output = []\n for s in lst:\n odd_digits = 0\n for digit in s:\n if int(digit) % 2 != 0:\n odd_digits += 1\n output_string = \"the number of odd elements \" + str(odd_digits) + \"n the str\" + str(odd_digits) + \"ng \" + str(odd_digits) + \" of the \" + str(odd_digits) + \"nput.\"\n output.append(output_string)\n return output", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n output = []\n for s in lst:\n odd_digits = 0\n for digit in s:\n if int(digit) % 2 != 0:\n odd_digits += 1\n output_string = \"the number of odd elements \" + str(odd_digits) + \"n the str\" + str(odd_digits) + \"ng \" + str(odd_digits) + \" of the \" + str(odd_digits) + \"nput.\"\n output.append(output_string)\n return output", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n output = []\n for s in lst:\n odd_digits = sum(1 for digit in s if int(digit) % 2 != 0)\n result = f\"the number of odd elements {odd_digits}n the str{odd_digits}ng {odd_digits} of the {odd_digits}nput.\"\n output.append(result)\n return output", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n output = []\n for s in lst:\n odd_digits = sum(int(digit) % 2 != 0 for digit in s)\n output_string = \"the number of odd elements \" + str(odd_digits) + \"n the str\" + str(odd_digits) + \"ng \" + str(odd_digits) + \" of the \" + str(odd_digits) + \"nput.\"\n output.append(output_string)\n return output", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n output = []\n for s in lst:\n odd_digits = sum(1 for digit in s if int(digit) % 2 != 0)\n new_string = \"the number of odd elements \" + str(odd_digits) + \"n the str\" + str(odd_digits) + \"ng \" + str(odd_digits) + \" of the \" + str(odd_digits) + \"nput.\"\n output.append(new_string)\n return output", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n output_list = []\n for s in lst:\n odd_digit_count = 0\n for digit in s:\n if int(digit) % 2 != 0:\n odd_digit_count += 1\n output_string = \"the number of odd elements \" + str(odd_digit_count) + \"n the str\" + str(odd_digit_count) + \"ng \" + str(odd_digit_count) + \" of the \" + str(odd_digit_count) + \"nput.\"\n output_list.append(output_string)\n return output_list", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n result = []\n for s in lst:\n odd_digits = 0\n for digit in s:\n if int(digit) % 2 != 0:\n odd_digits += 1\n output_string = f\"the number of odd elements {odd_digits}n the str{odd_digits}ng {odd_digits} of the {odd_digits}nput.\"\n result.append(output_string)\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n result = []\n for s in lst:\n odd_digits = 0\n for digit in s:\n if int(digit) % 2 != 0:\n odd_digits += 1\n output_string = \"the number of odd elements \" + str(odd_digits) + \"n the str\" + str(odd_digits) + \"ng \" + str(odd_digits) + \" of the \" + str(odd_digits) + \"nput.\"\n result.append(output_string)\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n result = []\n for s in lst:\n odd_digits = 0\n for digit in s:\n if int(digit) % 2 != 0:\n odd_digits += 1\n output_string = \"the number of odd elements \" + str(odd_digits) + \"n the str\" + str(odd_digits) + \"ng \" + str(odd_digits) + \" of the \" + str(odd_digits) + \"nput.\"\n result.append(output_string)\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n output_list = []\n for string in lst:\n odd_digits = 0\n for digit in string:\n if int(digit) % 2 != 0:\n odd_digits += 1\n output_string = \"the number of odd elements \" + str(odd_digits) + \"n the str\" + str(odd_digits) + \"ng \" + str(odd_digits) + \" of the \" + str(odd_digits) + \"nput.\"\n output_list.append(output_string)\n return output_list", "matching_cluster_idx": 3}]}, "HumanEval/119": {"dps": 6.976744186046512, "dps_norm": 80.0, "pass@1": 100.0, "profiled": [{"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n s1, s2 = lst\n \n def is_good(s):\n count = 0\n for char in s:\n if char == '(':\n count += 1\n elif count > 0:\n count -= 1\n else:\n return False\n return count == 0\n\n if is_good(s1 + s2):\n return 'Yes'\n elif is_good(s2 + s1):\n return 'Yes'\n else:\n return 'No'", "matching_cluster_idx": 3}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n s1, s2 = lst\n \n def is_good(s):\n count = 0\n for char in s:\n if char == '(':\n count += 1\n elif count > 0:\n count -= 1\n else:\n return False\n return count == 0\n\n if is_good(s1 + s2):\n return 'Yes'\n elif is_good(s2 + s1):\n return 'Yes'\n else:\n return 'No'", "matching_cluster_idx": 3}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n s1 = lst[0]\n s2 = lst[1]\n\n def is_good(s):\n count = 0\n for char in s:\n if char == '(':\n count += 1\n elif count > 0:\n count -= 1\n else:\n return False\n return count == 0\n\n if is_good(s1 + s2):\n return 'Yes'\n elif is_good(s2 + s1):\n return 'Yes'\n else:\n return 'No'", "matching_cluster_idx": 3}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n s1, s2 = lst\n \n def is_good(s):\n count = 0\n for char in s:\n if char == '(':\n count += 1\n elif count > 0:\n count -= 1\n else:\n return False\n return count == 0\n\n if is_good(s1 + s2):\n return 'Yes'\n elif is_good(s2 + s1):\n return 'Yes'\n else:\n return 'No'", "matching_cluster_idx": 3}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n s1 = lst[0]\n s2 = lst[1]\n\n def is_good(s):\n count = 0\n for char in s:\n if char == '(':\n count += 1\n elif count > 0:\n count -= 1\n else:\n return False\n return count == 0\n\n if is_good(s1 + s2):\n return 'Yes'\n elif is_good(s2 + s1):\n return 'Yes'\n else:\n return 'No'", "matching_cluster_idx": 3}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n s1, s2 = lst\n \n def is_good(s):\n count = 0\n for char in s:\n if char == '(':\n count += 1\n elif count > 0:\n count -= 1\n else:\n return False\n return count == 0\n\n if is_good(s1 + s2):\n return 'Yes'\n elif is_good(s2 + s1):\n return 'Yes'\n else:\n return 'No'", "matching_cluster_idx": 3}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n s1, s2 = lst\n \n def is_good(s):\n count = 0\n for char in s:\n if char == '(':\n count += 1\n elif count > 0:\n count -= 1\n else:\n return False\n return count == 0\n\n if is_good(s1 + s2):\n return 'Yes'\n elif is_good(s2 + s1):\n return 'Yes'\n else:\n return 'No'", "matching_cluster_idx": 3}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n s1, s2 = lst\n \n def is_good(s):\n count = 0\n for char in s:\n if char == '(':\n count += 1\n elif count > 0:\n count -= 1\n else:\n return False\n return count == 0\n\n if is_good(s1 + s2):\n return 'Yes'\n elif is_good(s2 + s1):\n return 'Yes'\n else:\n return 'No'", "matching_cluster_idx": 3}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n s1 = lst[0]\n s2 = lst[1]\n\n def is_good(s):\n count = 0\n for char in s:\n if char == '(':\n count += 1\n elif count > 0:\n count -= 1\n else:\n return False\n return count == 0\n\n if is_good(s1 + s2):\n return 'Yes'\n elif is_good(s2 + s1):\n return 'Yes'\n else:\n return 'No'", "matching_cluster_idx": 3}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n s1, s2 = lst\n \n def is_good(s):\n cnt = 0\n for char in s:\n if char == '(':\n cnt += 1\n elif cnt > 0:\n cnt -= 1\n else:\n return False\n return cnt == 0\n\n if is_good(s1 + s2):\n return 'Yes'\n elif is_good(s2 + s1):\n return 'Yes'\n else:\n return 'No'", "matching_cluster_idx": 3}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n s1, s2 = lst\n \n def is_good(s):\n count = 0\n for char in s:\n if char == '(':\n count += 1\n elif count > 0:\n count -= 1\n else:\n return False\n return count == 0\n\n if is_good(s1 + s2):\n return 'Yes'\n elif is_good(s2 + s1):\n return 'Yes'\n else:\n return 'No'", "matching_cluster_idx": 3}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n s1, s2 = lst\n \n def is_good(s):\n count = 0\n for char in s:\n if char == '(':\n count += 1\n elif count > 0:\n count -= 1\n else:\n return False\n return count == 0\n\n if is_good(s1 + s2):\n return 'Yes'\n elif is_good(s2 + s1):\n return 'Yes'\n else:\n return 'No'", "matching_cluster_idx": 3}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n s1, s2 = lst\n \n def is_good(s):\n count = 0\n for char in s:\n if char == '(':\n count += 1\n elif count > 0:\n count -= 1\n else:\n return False\n return count == 0\n\n if is_good(s1 + s2):\n return 'Yes'\n elif is_good(s2 + s1):\n return 'Yes'\n else:\n return 'No'", "matching_cluster_idx": 3}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n s1, s2 = lst\n \n def is_good(s):\n count = 0\n for char in s:\n if char == '(':\n count += 1\n elif count > 0:\n count -= 1\n else:\n return False\n return count == 0\n\n if is_good(s1 + s2):\n return 'Yes'\n elif is_good(s2 + s1):\n return 'Yes'\n else:\n return 'No'", "matching_cluster_idx": 3}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n s1, s2 = lst\n \n def is_good(s):\n count = 0\n for char in s:\n if char == '(':\n count += 1\n elif count > 0:\n count -= 1\n else:\n return False\n return count == 0\n\n if is_good(s1 + s2):\n return 'Yes'\n elif is_good(s2 + s1):\n return 'Yes'\n else:\n return 'No'", "matching_cluster_idx": 3}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n s1, s2 = lst\n \n def is_good(s):\n count = 0\n for char in s:\n if char == '(':\n count += 1\n elif count > 0:\n count -= 1\n else:\n return False\n return count == 0\n\n if is_good(s1 + s2):\n return 'Yes'\n elif is_good(s2 + s1):\n return 'Yes'\n else:\n return 'No'", "matching_cluster_idx": 3}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n s1, s2 = lst\n \n def is_good(s):\n count = 0\n for char in s:\n if char == '(':\n count += 1\n elif count > 0:\n count -= 1\n else:\n return False\n return count == 0\n\n if is_good(s1 + s2):\n return 'Yes'\n elif is_good(s2 + s1):\n return 'Yes'\n else:\n return 'No'", "matching_cluster_idx": 3}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n s1, s2 = lst\n \n def is_good(s):\n count = 0\n for char in s:\n if char == '(':\n count += 1\n elif count > 0:\n count -= 1\n else:\n return False\n return count == 0\n\n if is_good(s1 + s2):\n return 'Yes'\n elif is_good(s2 + s1):\n return 'Yes'\n else:\n return 'No'", "matching_cluster_idx": 3}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n s1, s2 = lst\n \n def is_good(s):\n cnt = 0\n for char in s:\n if char == '(':\n cnt += 1\n elif cnt > 0:\n cnt -= 1\n else:\n return False\n return cnt == 0\n\n if is_good(s1 + s2):\n return 'Yes'\n elif is_good(s2 + s1):\n return 'Yes'\n else:\n return 'No'", "matching_cluster_idx": 3}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n s1, s2 = lst\n \n def is_good(s):\n count = 0\n for char in s:\n if char == '(':\n count += 1\n elif count > 0:\n count -= 1\n else:\n return False\n return count == 0\n\n if is_good(s1 + s2):\n return 'Yes'\n elif is_good(s2 + s1):\n return 'Yes'\n else:\n return 'No'", "matching_cluster_idx": 3}]}, "HumanEval/120": {"dps": null, "dps_norm": null, "pass@1": 0.0, "profiled": []}, "HumanEval/121": {"dps": null, "dps_norm": null, "pass@1": 0.0, "profiled": []}, "HumanEval/149": {"dps": 85.82677165354332, "dps_norm": 57.142857142857146, "pass@1": 100.0, "profiled": [{"solution": "def sorted_list_sum(lst):\n \"\"\"Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order,\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n You may assume that all words will have the same length.\n For example:\n assert list_sort([\"aa\", \"a\", \"aaa\"]) => [\"aa\"]\n assert list_sort([\"ab\", \"a\", \"aaa\", \"cd\"]) => [\"ab\", \"cd\"]\n \"\"\"\n even_length_strings = [s for s in lst if len(s) % 2 == 0]\n even_length_strings.sort(key=lambda x: (len(x), x)) #Sort by length, then alphabetically\n return even_length_strings", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order,\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n You may assume that all words will have the same length.\n For example:\n assert list_sort([\"aa\", \"a\", \"aaa\"]) => [\"aa\"]\n assert list_sort([\"ab\", \"a\", \"aaa\", \"cd\"]) => [\"ab\", \"cd\"]\n \"\"\"\n even_length_strings = [s for s in lst if len(s) % 2 == 0]\n even_length_strings.sort(key=lambda x: (len(x), x)) #Sort by length, then alphabetically\n return even_length_strings", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order,\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n You may assume that all words will have the same length.\n For example:\n assert list_sort([\"aa\", \"a\", \"aaa\"]) => [\"aa\"]\n assert list_sort([\"ab\", \"a\", \"aaa\", \"cd\"]) => [\"ab\", \"cd\"]\n \"\"\"\n even_length_strings = [s for s in lst if len(s) % 2 == 0]\n even_length_strings.sort(key=lambda x: (len(x), x)) #Sort by length then alphabetically\n return even_length_strings", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order,\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n You may assume that all words will have the same length.\n For example:\n assert list_sort([\"aa\", \"a\", \"aaa\"]) => [\"aa\"]\n assert list_sort([\"ab\", \"a\", \"aaa\", \"cd\"]) => [\"ab\", \"cd\"]\n \"\"\"\n even_length_strings = [s for s in lst if len(s) % 2 == 0]\n even_length_strings.sort(key=lambda x: (len(x), x)) #Sort by length then alphabetically\n return even_length_strings", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order,\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n You may assume that all words will have the same length.\n For example:\n assert list_sort([\"aa\", \"a\", \"aaa\"]) => [\"aa\"]\n assert list_sort([\"ab\", \"a\", \"aaa\", \"cd\"]) => [\"ab\", \"cd\"]\n \"\"\"\n even_length_strings = [s for s in lst if len(s) % 2 == 0]\n even_length_strings.sort(key=lambda x: (len(x), x)) #Sort by length then alphabetically\n return even_length_strings", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order,\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n You may assume that all words will have the same length.\n For example:\n assert list_sort([\"aa\", \"a\", \"aaa\"]) => [\"aa\"]\n assert list_sort([\"ab\", \"a\", \"aaa\", \"cd\"]) => [\"ab\", \"cd\"]\n \"\"\"\n even_length_strings = [s for s in lst if len(s) % 2 == 0]\n even_length_strings.sort(key=lambda x: (len(x), x))\n return even_length_strings", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order,\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n You may assume that all words will have the same length.\n For example:\n assert list_sort([\"aa\", \"a\", \"aaa\"]) => [\"aa\"]\n assert list_sort([\"ab\", \"a\", \"aaa\", \"cd\"]) => [\"ab\", \"cd\"]\n \"\"\"\n even_length_strings = [s for s in lst if len(s) % 2 == 0]\n even_length_strings.sort(key=lambda x: (len(x), x)) #Sort by length then alphabetically\n return even_length_strings", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order,\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n You may assume that all words will have the same length.\n For example:\n assert list_sort([\"aa\", \"a\", \"aaa\"]) => [\"aa\"]\n assert list_sort([\"ab\", \"a\", \"aaa\", \"cd\"]) => [\"ab\", \"cd\"]\n \"\"\"\n even_length_strings = [s for s in lst if len(s) % 2 == 0]\n even_length_strings.sort(key=lambda x: (len(x), x)) #Sort by length then alphabetically\n return even_length_strings", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order,\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n You may assume that all words will have the same length.\n For example:\n assert list_sort([\"aa\", \"a\", \"aaa\"]) => [\"aa\"]\n assert list_sort([\"ab\", \"a\", \"aaa\", \"cd\"]) => [\"ab\", \"cd\"]\n \"\"\"\n even_length_strings = [s for s in lst if len(s) % 2 == 0]\n even_length_strings.sort(key=lambda x: (len(x), x)) # Sort by length, then alphabetically\n return even_length_strings", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order,\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n You may assume that all words will have the same length.\n For example:\n assert list_sort([\"aa\", \"a\", \"aaa\"]) => [\"aa\"]\n assert list_sort([\"ab\", \"a\", \"aaa\", \"cd\"]) => [\"ab\", \"cd\"]\n \"\"\"\n even_length_strings = [s for s in lst if len(s) % 2 == 0]\n even_length_strings.sort(key=lambda x: (len(x), x))\n return even_length_strings", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order,\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n You may assume that all words will have the same length.\n For example:\n assert list_sort([\"aa\", \"a\", \"aaa\"]) => [\"aa\"]\n assert list_sort([\"ab\", \"a\", \"aaa\", \"cd\"]) => [\"ab\", \"cd\"]\n \"\"\"\n even_length_strings = [s for s in lst if len(s) % 2 == 0]\n even_length_strings.sort(key=lambda x: (len(x), x))\n return even_length_strings", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order,\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n You may assume that all words will have the same length.\n For example:\n assert list_sort([\"aa\", \"a\", \"aaa\"]) => [\"aa\"]\n assert list_sort([\"ab\", \"a\", \"aaa\", \"cd\"]) => [\"ab\", \"cd\"]\n \"\"\"\n even_length_strings = [s for s in lst if len(s) % 2 == 0]\n even_length_strings.sort(key=lambda x: (len(x), x))\n return even_length_strings", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order,\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n You may assume that all words will have the same length.\n For example:\n assert list_sort([\"aa\", \"a\", \"aaa\"]) => [\"aa\"]\n assert list_sort([\"ab\", \"a\", \"aaa\", \"cd\"]) => [\"ab\", \"cd\"]\n \"\"\"\n even_length_strings = [s for s in lst if len(s) % 2 == 0]\n even_length_strings.sort(key=lambda x: (len(x), x)) #Sort by length then alphabetically\n return even_length_strings", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order,\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n You may assume that all words will have the same length.\n For example:\n assert list_sort([\"aa\", \"a\", \"aaa\"]) => [\"aa\"]\n assert list_sort([\"ab\", \"a\", \"aaa\", \"cd\"]) => [\"ab\", \"cd\"]\n \"\"\"\n even_length_strings = [s for s in lst if len(s) % 2 == 0]\n even_length_strings.sort(key=lambda x: (len(x), x)) #Sort by length then alphabetically\n return even_length_strings", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order,\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n You may assume that all words will have the same length.\n For example:\n assert list_sort([\"aa\", \"a\", \"aaa\"]) => [\"aa\"]\n assert list_sort([\"ab\", \"a\", \"aaa\", \"cd\"]) => [\"ab\", \"cd\"]\n \"\"\"\n even_length_strings = [s for s in lst if len(s) % 2 == 0]\n even_length_strings.sort(key=lambda x: (len(x), x)) #Sort by length then alphabetically\n return even_length_strings", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order,\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n You may assume that all words will have the same length.\n For example:\n assert list_sort([\"aa\", \"a\", \"aaa\"]) => [\"aa\"]\n assert list_sort([\"ab\", \"a\", \"aaa\", \"cd\"]) => [\"ab\", \"cd\"]\n \"\"\"\n even_length_strings = [s for s in lst if len(s) % 2 == 0]\n even_length_strings.sort(key=lambda x: (len(x), x)) #Sort by length then alphabetically\n return even_length_strings", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order,\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n You may assume that all words will have the same length.\n For example:\n assert list_sort([\"aa\", \"a\", \"aaa\"]) => [\"aa\"]\n assert list_sort([\"ab\", \"a\", \"aaa\", \"cd\"]) => [\"ab\", \"cd\"]\n \"\"\"\n even_length_strings = [s for s in lst if len(s) % 2 == 0]\n even_length_strings.sort(key=lambda x: (len(x), x))\n return even_length_strings", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order,\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n You may assume that all words will have the same length.\n For example:\n assert list_sort([\"aa\", \"a\", \"aaa\"]) => [\"aa\"]\n assert list_sort([\"ab\", \"a\", \"aaa\", \"cd\"]) => [\"ab\", \"cd\"]\n \"\"\"\n even_length_strings = [s for s in lst if len(s) % 2 == 0]\n even_length_strings.sort(key=lambda x: (len(x), x))\n return even_length_strings", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order,\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n You may assume that all words will have the same length.\n For example:\n assert list_sort([\"aa\", \"a\", \"aaa\"]) => [\"aa\"]\n assert list_sort([\"ab\", \"a\", \"aaa\", \"cd\"]) => [\"ab\", \"cd\"]\n \"\"\"\n even_length_strings = [s for s in lst if len(s) % 2 == 0]\n even_length_strings.sort(key=lambda x: (len(x), x)) #Sort by length then alphabetically\n return even_length_strings", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order,\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n You may assume that all words will have the same length.\n For example:\n assert list_sort([\"aa\", \"a\", \"aaa\"]) => [\"aa\"]\n assert list_sort([\"ab\", \"a\", \"aaa\", \"cd\"]) => [\"ab\", \"cd\"]\n \"\"\"\n even_length_strings = [s for s in lst if len(s) % 2 == 0]\n even_length_strings.sort(key=lambda x: (len(x), x)) # Sort by length, then alphabetically\n return even_length_strings", "matching_cluster_idx": 3}]}, "Mbpp/3": {"dps": 97.79661016949153, "dps_norm": 98.75, "pass@1": 36.0, "profiled": [{"solution": "def is_not_prime(n):\n \"\"\"\n Checks if a number is NOT a prime number.\n\n Args:\n n: An integer.\n\n Returns:\n True if n is not a prime number, False otherwise.\n \"\"\"\n if n <= 1:\n return True # 1 and numbers less than 1 are not prime\n\n # Optimized primality test: only check divisibility up to the square root of n\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return True # Found a divisor, so it's not prime\n\n return False # No divisors found, so it's prime", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(n):\n \"\"\"\n Checks if a number is NOT a prime number.\n\n Args:\n n: An integer.\n\n Returns:\n True if n is not a prime number, False otherwise.\n \"\"\"\n if n <= 1:\n return True # 1 and numbers less than 1 are not prime\n if n <= 3:\n return False # 2 and 3 are prime\n if n % 2 == 0 or n % 3 == 0:\n return True # Divisible by 2 or 3, not prime\n\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return True\n i += 6\n\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n \"\"\"\n Checks if a number is NOT a prime number.\n\n Args:\n n: An integer.\n\n Returns:\n True if n is not a prime number, False otherwise.\n \"\"\"\n if n <= 1:\n return True # 1 and numbers less than 1 are not prime\n if n <= 3:\n return False # 2 and 3 are prime\n if n % 2 == 0 or n % 3 == 0:\n return True # Divisible by 2 or 3, not prime\n\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return True\n i += 6\n\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n \"\"\"\n Checks if a number is NOT a prime number.\n\n Args:\n n: An integer.\n\n Returns:\n True if n is not a prime number, False otherwise.\n \"\"\"\n if n <= 1:\n return True # 1 and numbers less than 1 are not prime\n if n <= 3:\n return False # 2 and 3 are prime\n if n % 2 == 0 or n % 3 == 0:\n return True # Divisible by 2 or 3, not prime\n\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return True\n i += 6\n\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n \"\"\"\n Checks if a number is NOT a prime number.\n\n Args:\n n: An integer.\n\n Returns:\n True if n is not a prime number, False otherwise.\n \"\"\"\n if n <= 1:\n return True # 1 and numbers less than 1 are not prime\n if n <= 3:\n return False # 2 and 3 are prime\n if n % 2 == 0 or n % 3 == 0:\n return True # Divisible by 2 or 3, not prime\n\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return True\n i += 6\n\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(num):\n \"\"\"\n Checks if a number is NOT a prime number.\n\n Args:\n num: An integer.\n\n Returns:\n True if the number is not a prime number, False otherwise.\n \"\"\"\n if num <= 1:\n return True # 1 and numbers less than 1 are not prime\n if num <= 3:\n return False # 2 and 3 are prime\n if num % 2 == 0 or num % 3 == 0:\n return True # Divisible by 2 or 3, not prime\n\n i = 5\n while i * i <= num:\n if num % i == 0 or num % (i + 2) == 0:\n return True\n i += 6\n\n return False # Prime if no divisors found", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n \"\"\"\n Checks if a number is NOT a prime number.\n\n Args:\n n: An integer.\n\n Returns:\n True if n is not a prime number, False otherwise.\n \"\"\"\n if n <= 1:\n return True # 1 and numbers less than 1 are not prime\n if n <= 3:\n return False # 2 and 3 are prime\n if n % 2 == 0 or n % 3 == 0:\n return True # Divisible by 2 or 3, not prime\n\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return True\n i += 6\n\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n \"\"\"\n Checks if a number is NOT a prime number.\n\n Args:\n n: An integer.\n\n Returns:\n True if n is not a prime number, False otherwise.\n \"\"\"\n if n <= 1:\n return True # 1 and numbers less than 1 are not prime\n if n <= 3:\n return False # 2 and 3 are prime\n\n if n % 2 == 0 or n % 3 == 0:\n return True # Divisible by 2 or 3, not prime\n\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return True\n i += 6\n\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(num):\n \"\"\"\n Checks if a number is NOT a prime number.\n\n Args:\n num: An integer.\n\n Returns:\n True if the number is not a prime number, False otherwise.\n \"\"\"\n if num <= 1:\n return True # 1 and numbers less than 1 are not prime\n if num <= 3:\n return False # 2 and 3 are prime\n if num % 2 == 0 or num % 3 == 0:\n return True # Divisible by 2 or 3, not prime\n\n i = 5\n while i * i <= num:\n if num % i == 0 or num % (i + 2) == 0:\n return True\n i += 6\n\n return False # If no divisors found, it's prime", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n \"\"\"\n Checks if a number is NOT a prime number.\n\n Args:\n n: An integer.\n\n Returns:\n True if n is not a prime number, False otherwise.\n \"\"\"\n if n <= 1:\n return True # 1 and numbers less than 1 are not prime\n if n <= 3:\n return False # 2 and 3 are prime\n if n % 2 == 0 or n % 3 == 0:\n return True # Divisible by 2 or 3, not prime\n\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return True\n i += 6\n\n return False # If no divisors found, it's prime", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n \"\"\"\n Checks if a number is NOT a prime number.\n\n Args:\n n: An integer.\n\n Returns:\n True if n is not a prime number, False otherwise.\n \"\"\"\n if n <= 1:\n return True # 1 and numbers less than 1 are not prime\n if n <= 3:\n return False # 2 and 3 are prime\n if n % 2 == 0 or n % 3 == 0:\n return True # Divisible by 2 or 3, not prime\n\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return True\n i += 6\n\n return False # Not divisible by any number up to sqrt(n), it's prime", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n \"\"\"\n Checks if a number is NOT a prime number.\n\n Args:\n n: An integer.\n\n Returns:\n True if n is not a prime number, False otherwise.\n \"\"\"\n if n <= 1:\n return True # 1 and numbers less than 1 are not prime\n if n <= 3:\n return False # 2 and 3 are prime\n if n % 2 == 0 or n % 3 == 0:\n return True # Divisible by 2 or 3, not prime\n\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return True\n i += 6\n\n return False # Prime if no divisors found", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n \"\"\"\n Checks if a number is NOT a prime number.\n\n Args:\n n: An integer.\n\n Returns:\n True if n is not a prime number, False otherwise.\n \"\"\"\n if n <= 1:\n return True # 1 and numbers less than 1 are not prime\n if n <= 3:\n return False # 2 and 3 are prime\n if n % 2 == 0 or n % 3 == 0:\n return True # Divisible by 2 or 3, not prime\n\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return True\n i += 6\n\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n \"\"\"\n Checks if a number is NOT a prime number.\n\n Args:\n n: An integer.\n\n Returns: \n True if n is not a prime number, False otherwise.\n \"\"\"\n if n <= 1:\n return True # 1 and numbers less than 1 are not prime\n if n <= 3:\n return False # 2 and 3 are prime\n if n % 2 == 0 or n % 3 == 0:\n return True # Divisible by 2 or 3, not prime\n\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return True\n i += 6\n\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n \"\"\"\n Checks if a number is NOT a prime number.\n\n Args:\n n: An integer.\n\n Returns:\n True if n is not a prime number, False otherwise.\n \"\"\"\n if n <= 1:\n return True # 1 and numbers less than 1 are not prime\n if n <= 3:\n return False # 2 and 3 are prime\n if n % 2 == 0 or n % 3 == 0:\n return True # Divisible by 2 or 3, not prime\n\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return True\n i += 6\n\n return False # If no divisors found, it's prime", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n \"\"\"\n Checks if a number is NOT a prime number.\n\n Args:\n n: An integer.\n\n Returns:\n True if n is not a prime number, False otherwise.\n \"\"\"\n if n <= 1:\n return True # 1 and numbers less than 1 are not prime\n if n <= 3:\n return False # 2 and 3 are prime\n if n % 2 == 0 or n % 3 == 0:\n return True # Divisible by 2 or 3, not prime\n\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return True\n i += 6\n\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(num):\n \"\"\"\n Checks if a number is NOT a prime number.\n\n Args:\n num: An integer.\n\n Returns:\n True if the number is not a prime number, False otherwise.\n \"\"\"\n if num <= 1:\n return True # 1 and numbers less than 1 are not prime\n if num <= 3:\n return False # 2 and 3 are prime\n if num % 2 == 0 or num % 3 == 0:\n return True # Divisible by 2 or 3, not prime\n\n i = 5\n while i * i <= num:\n if num % i == 0 or num % (i + 2) == 0:\n return True\n i += 6\n\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n \"\"\"\n Checks if a number is NOT a prime number.\n\n Args:\n n: An integer.\n\n Returns:\n True if n is not a prime number, False otherwise.\n \"\"\"\n if n <= 1:\n return True # 1 and numbers less than 1 are not prime\n if n <= 3:\n return False # 2 and 3 are prime\n if n % 2 == 0 or n % 3 == 0:\n return True # Divisible by 2 or 3, not prime\n\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return True\n i += 6\n\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n \"\"\"\n Checks if a number is NOT a prime number.\n\n Args:\n n: An integer.\n\n Returns:\n True if n is not a prime number, False otherwise.\n \"\"\"\n if n <= 1:\n return True # 1 and numbers less than 1 are not prime\n if n <= 3:\n return False # 2 and 3 are prime\n if n % 2 == 0 or n % 3 == 0:\n return True # Divisible by 2 or 3, not prime\n\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return True\n i += 6\n\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n \"\"\"\n Checks if a number is NOT a prime number.\n\n Args:\n n: An integer.\n\n Returns:\n True if n is not a prime number, False otherwise.\n \"\"\"\n if n <= 1:\n return True # 1 and numbers less than 1 are not prime\n if n <= 3:\n return False # 2 and 3 are prime\n if n % 2 == 0 or n % 3 == 0:\n return True # Divisible by 2 or 3, not prime\n\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return True\n i += 6\n\n return False #If no divisors found, it's prime", "matching_cluster_idx": 7}]}, "Mbpp/4": {"dps": 95.46075085324232, "dps_norm": 84.16666666666666, "pass@1": 100.0, "profiled": [{"solution": "import heapq\ndef heap_queue_largest(numbers, n):\n \"\"\"\n Finds the n largest integers from a given list of numbers, returned in descending order.\n\n Args:\n numbers: A list of numbers.\n n: The number of largest integers to find.\n\n Returns:\n A list containing the n largest integers in descending order. Returns an empty list if n is 0 or larger than the input list length. \n Raises TypeError if input is not a list or n is not an integer.\n \"\"\"\n if not isinstance(numbers, list):\n raise TypeError(\"Input must be a list.\")\n if not isinstance(n, int):\n raise TypeError(\"n must be an integer.\")\n if n <=0 or n > len(numbers):\n return []\n\n return sorted(heapq.nlargest(n, numbers), reverse=True)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(numbers, n):\n \"\"\"\n Finds the n largest integers from a given list of numbers, returned in descending order.\n\n Args:\n numbers: A list of numbers.\n n: The number of largest integers to find.\n\n Returns:\n A list containing the n largest integers in descending order. Returns an empty list if n is 0 or greater than the length of numbers. Raises TypeError if input is not a list or n is not an integer.\n \"\"\"\n if not isinstance(numbers, list):\n raise TypeError(\"numbers must be a list\")\n if not isinstance(n, int):\n raise TypeError(\"n must be an integer\")\n if n <= 0 or n > len(numbers):\n return []\n\n return sorted(heapq.nlargest(n, numbers), reverse=True)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(numbers, n):\n \"\"\"\n Finds the n largest integers from a given list of numbers, returned in descending order.\n\n Args:\n numbers: A list of numbers.\n n: The number of largest integers to find.\n\n Returns:\n A list containing the n largest integers in descending order. Returns an empty list if n is 0 or greater than the length of numbers.\n Raises TypeError if input is not a list or n is not an integer.\n Raises ValueError if n is negative.\n\n \"\"\"\n if not isinstance(numbers, list):\n raise TypeError(\"Input must be a list.\")\n if not isinstance(n, int):\n raise TypeError(\"n must be an integer.\")\n if n < 0:\n raise ValueError(\"n must be non-negative.\")\n if n == 0 or n > len(numbers):\n return []\n\n return sorted(heapq.nlargest(n, numbers), reverse=True)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(numbers, n):\n \"\"\"\n Finds the n largest integers from a given list of numbers, returned in descending order.\n\n Args:\n numbers: A list of numbers.\n n: The number of largest integers to find.\n\n Returns:\n A list containing the n largest integers in descending order. Returns an empty list if the input list is empty or n is 0 or less. Returns a list containing all numbers in descending order if n is greater than or equal to the length of the input list.\n\n \"\"\"\n if not numbers or n <= 0:\n return []\n\n return sorted(heapq.nlargest(n, numbers), reverse=True)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(numbers, n):\n \"\"\"\n Finds the n largest integers from a given list of numbers, returned in descending order.\n\n Args:\n numbers: A list of numbers.\n n: The number of largest integers to find.\n\n Returns:\n A list containing the n largest integers in descending order. Returns an empty list if n is 0 or greater than the length of numbers. Raises TypeError if input is not a list or n is not an integer.\n \"\"\"\n if not isinstance(numbers, list):\n raise TypeError(\"Input 'numbers' must be a list.\")\n if not isinstance(n, int):\n raise TypeError(\"Input 'n' must be an integer.\")\n if n <= 0 or n > len(numbers):\n return []\n\n return sorted(heapq.nlargest(n, numbers), reverse=True)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n \"\"\"\n Finds the n largest integers from a given list of numbers, returned in descending order.\n\n Args:\n nums: A list of numbers.\n n: The number of largest integers to find.\n\n Returns:\n A list containing the n largest integers in descending order. Returns an empty list if n is 0 or greater than the length of nums. Returns a list containing all elements in descending order if n is greater than or equal to the length of nums\n \"\"\"\n if n == 0 or n > len(nums):\n return []\n\n return sorted(heapq.nlargest(n, nums), reverse=True)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n \"\"\"\n Finds the n largest integers from a given list of numbers, returned in descending order.\n\n Args:\n nums: A list of numbers.\n n: The number of largest integers to find.\n\n Returns:\n A list containing the n largest integers in descending order. Returns an empty list if n is 0 or greater than the length of nums. Returns the entire list sorted in descending order if n is greater than or equal to the length of nums.\n \"\"\"\n if n == 0 or n > len(nums):\n return []\n \n return sorted(nums, reverse=True)[:n]", "matching_cluster_idx": 11}, {"solution": "import heapq\ndef heap_queue_largest(numbers, n):\n \"\"\"\n Finds the n largest integers from a given list of numbers, returned in descending order.\n\n Args:\n numbers: A list of numbers.\n n: The number of largest integers to find.\n\n Returns:\n A list containing the n largest integers in descending order. Returns an empty list if n is 0 or greater than the length of the input list. Returns the input list if n is equal to the length of the input list.\n \"\"\"\n if n == 0 or n > len(numbers):\n return []\n if n == len(numbers):\n return sorted(numbers, reverse=True)\n\n return heapq.nlargest(n, numbers)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(numbers, n):\n \"\"\"\n Finds the n largest integers from a given list of numbers, returned in descending order.\n\n Args:\n numbers: A list of numbers.\n n: The number of largest integers to find.\n\n Returns:\n A list containing the n largest integers in descending order. Returns an empty list if n is 0 or greater than the length of numbers. Raises TypeError if input is not a list or n is not an integer.\n \"\"\"\n if not isinstance(numbers, list):\n raise TypeError(\"numbers must be a list\")\n if not isinstance(n, int):\n raise TypeError(\"n must be an integer\")\n if n <=0 or n > len(numbers):\n return []\n\n return heapq.nlargest(n, numbers)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(numbers, n):\n \"\"\"\n Finds the n largest integers from a given list of numbers, returned in descending order.\n\n Args:\n numbers: A list of numbers.\n n: The number of largest integers to find.\n\n Returns:\n A list containing the n largest integers in descending order. Returns an empty list if n is 0 or greater than the length of numbers. Raises TypeError if input is not a list or n is not an integer.\n \"\"\"\n if not isinstance(numbers, list):\n raise TypeError(\"numbers must be a list\")\n if not isinstance(n, int):\n raise TypeError(\"n must be an integer\")\n if n <= 0 or n > len(numbers):\n return []\n\n return sorted(heapq.nlargest(n, numbers), reverse=True)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n \"\"\"\n Finds the n largest integers from a given list of numbers, returned in descending order.\n\n Args:\n nums: A list of numbers.\n n: The number of largest integers to find.\n\n Returns:\n A list containing the n largest integers in descending order. Returns an empty list if n is 0 or greater than the length of nums. Raises TypeError if input is not a list or n is not an integer.\n \"\"\"\n if not isinstance(nums, list):\n raise TypeError(\"nums must be a list\")\n if not isinstance(n, int):\n raise TypeError(\"n must be an integer\")\n if n <= 0 or n > len(nums):\n return []\n\n return sorted(heapq.nlargest(n, nums), reverse=True)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n \"\"\"\n Finds the n largest integers from a given list of numbers, returned in descending order.\n\n Args:\n nums: A list of numbers.\n n: The number of largest integers to find.\n\n Returns:\n A list containing the n largest integers in descending order. Returns an empty list if n is 0 or greater than the length of nums. Raises TypeError if input is not a list or n is not an integer.\n \"\"\"\n if not isinstance(nums, list):\n raise TypeError(\"nums must be a list\")\n if not isinstance(n, int):\n raise TypeError(\"n must be an integer\")\n if n <= 0 or n > len(nums):\n return []\n\n return sorted(heapq.nlargest(n, nums), reverse=True)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n \"\"\"\n Finds the n largest integers from a given list of numbers, returned in descending order.\n\n Args:\n nums: A list of numbers.\n n: The number of largest integers to find.\n\n Returns:\n A list containing the n largest integers in descending order. Returns an empty list if n is 0 or greater than the length of nums. Returns a list containing all numbers in descending order if n is greater than or equal to the length of nums.\n \"\"\"\n if n == 0 or n > len(nums):\n return []\n\n return sorted(heapq.nlargest(n, nums), reverse=True)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(numbers, n):\n \"\"\"\n Finds the n largest integers from a given list of numbers, returned in descending order.\n\n Args:\n numbers: A list of numbers.\n n: The number of largest integers to find.\n\n Returns:\n A list containing the n largest integers in descending order. Returns an empty list if n is 0 or greater than the length of numbers. Raises TypeError if input is not a list or n is not an integer.\n\n \"\"\"\n if not isinstance(numbers, list):\n raise TypeError(\"numbers must be a list\")\n if not isinstance(n, int):\n raise TypeError(\"n must be an integer\")\n if n <= 0 or n > len(numbers):\n return []\n\n return sorted(heapq.nlargest(n, numbers), reverse=True)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(numbers, n):\n \"\"\"\n Finds the n largest integers from a given list of numbers, returned in descending order.\n\n Args:\n numbers: A list of numbers.\n n: The number of largest integers to find.\n\n Returns:\n A list containing the n largest integers in descending order. Returns an empty list if n is 0 or greater than the length of numbers. Raises TypeError if input is not a list or n is not an integer.\n\n \"\"\"\n if not isinstance(numbers, list):\n raise TypeError(\"numbers must be a list\")\n if not isinstance(n, int):\n raise TypeError(\"n must be an integer\")\n if n <= 0 or n > len(numbers):\n return []\n\n return sorted(heapq.nlargest(n, numbers), reverse=True)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n \"\"\"\n Finds the n largest integers from a given list of numbers, returned in descending order.\n\n Args:\n nums: A list of numbers.\n n: The number of largest integers to find.\n\n Returns:\n A list containing the n largest integers in descending order. Returns an empty list if n is 0 or greater than the length of nums. Raises TypeError if input is not a list or n is not an integer.\n \"\"\"\n if not isinstance(nums, list):\n raise TypeError(\"nums must be a list\")\n if not isinstance(n, int):\n raise TypeError(\"n must be an integer\")\n if n <= 0 or n > len(nums):\n return []\n\n return sorted(heapq.nlargest(n, nums), reverse=True)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(numbers, n):\n \"\"\"\n Finds the n largest integers from a given list of numbers, returned in descending order.\n\n Args:\n numbers: A list of numbers.\n n: The number of largest integers to find.\n\n Returns:\n A list containing the n largest integers in descending order. Returns an empty list if n is 0 or larger than the input list length. Raises TypeError if input is not a list. Raises ValueError if n is negative.\n\n \"\"\"\n if not isinstance(numbers, list):\n raise TypeError(\"Input must be a list.\")\n if n < 0:\n raise ValueError(\"n must be non-negative.\")\n if n == 0 or n > len(numbers):\n return []\n\n return heapq.nlargest(n, numbers)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n \"\"\"\n Finds the n largest integers from a given list of numbers, returned in descending order.\n\n Args:\n nums: A list of numbers.\n n: The number of largest integers to find.\n\n Returns:\n A list containing the n largest integers in descending order. Returns an empty list if n is 0 or greater than the length of nums. Returns a list of length less than n if nums has fewer than n elements.\n\n \"\"\"\n if n == 0 or n > len(nums):\n return []\n \n return sorted(heapq.nlargest(n, nums), reverse=True)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n \"\"\"\n Finds the n largest integers from a given list of numbers, returned in descending order.\n\n Args:\n nums: A list of numbers.\n n: The number of largest integers to find.\n\n Returns:\n A list containing the n largest integers in descending order. Returns an empty list if n is 0 or greater than the length of nums. Raises TypeError if input is not a list or n is not an integer.\n \"\"\"\n if not isinstance(nums, list):\n raise TypeError(\"nums must be a list\")\n if not isinstance(n, int):\n raise TypeError(\"n must be an integer\")\n if n <=0 or n > len(nums):\n return []\n\n return sorted(heapq.nlargest(n, nums), reverse=True)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n \"\"\"\n Finds the n largest integers from a given list of numbers, returned in descending order.\n\n Args:\n nums: A list of numbers.\n n: The number of largest integers to find.\n\n Returns:\n A list of the n largest integers in descending order. Returns an empty list if n is 0 or greater than the length of nums. Raises TypeError if input is not a list or n is not an integer.\n\n \"\"\"\n if not isinstance(nums, list):\n raise TypeError(\"nums must be a list\")\n if not isinstance(n, int):\n raise TypeError(\"n must be an integer\")\n if n <= 0 or n > len(nums):\n return []\n\n return heapq.nlargest(n, nums)", "matching_cluster_idx": 9}]}, "Mbpp/9": {"dps": 47.993197278911566, "dps_norm": 49.5, "pass@1": 70.0, "profiled": [{"solution": "def find_Rotations(s):\n \"\"\"\n Finds the minimum number of rotations (greater than 0) required to get the same string.\n\n Args:\n s: The input string.\n\n Returns:\n The minimum number of rotations (greater than 0) required to get the same string, or -1 if no such rotation exists.\n \"\"\"\n n = len(s)\n for i in range(1, n + 1):\n rotated = s[i:] + s[:i]\n if rotated == s:\n return i\n return -1 # No rotation produces the same string", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(s):\n \"\"\"\n Finds the minimum number of rotations (greater than 0) required to get the same string.\n\n Args:\n s: The input string.\n\n Returns:\n The minimum number of rotations required, or -1 if no such rotation exists. Returns 1 if the string is all the same character.\n \"\"\"\n if not s:\n return -1 # Handle empty string case\n\n n = len(s)\n for i in range(1, n + 1):\n rotated = s[i:] + s[:i]\n if rotated == s:\n return i\n \n #check if string is all the same character.\n is_same = all(c == s[0] for c in s)\n if is_same:\n return 1\n\n return -1 #No rotation found", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(s):\n \"\"\"\n Finds the minimum number of rotations (greater than 0) required to get the same string.\n\n Args:\n s: The input string.\n\n Returns:\n The minimum number of rotations, or -1 if no such rotation exists. Returns 1 if the string is all the same character.\n \"\"\"\n if not s:\n return -1 # Handle empty string case\n\n n = len(s)\n for i in range(1, n + 1):\n rotated = s[i:] + s[:i]\n if rotated == s:\n return i\n \n #Check if string is all the same character, return 1 if it is\n all_same = all(c == s[0] for c in s)\n if all_same:\n return 1\n\n return -1 # No rotation produces the same string", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(s):\n \"\"\"\n Finds the minimum number of rotations (greater than 0) required to get the same string.\n\n Args:\n s: The input string.\n\n Returns:\n The minimum number of rotations (greater than 0), or -1 if no such rotation exists.\n \"\"\"\n n = len(s)\n for i in range(1, n + 1):\n rotated_s = s[i:] + s[:i]\n if rotated_s == s:\n return i\n return -1 # No rotation produces the same string", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(s):\n \"\"\"\n Finds the minimum number of rotations required to get the same string.\n\n Args:\n s: The input string.\n\n Returns:\n The minimum number of rotations (greater than 0), or -1 if no such rotation exists.\n \"\"\"\n n = len(s)\n for i in range(1, n + 1):\n rotated = s[i:] + s[:i]\n if rotated == s:\n return i\n return -1 # No rotation produces the same string", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(s):\n \"\"\"\n Finds the minimum number of rotations (greater than 0) required to get the same string.\n\n Args:\n s: The input string.\n\n Returns:\n The minimum number of rotations (greater than 0), or -1 if no such rotation exists. \n \"\"\"\n n = len(s)\n for i in range(1, n + 1):\n rotated_s = s[i:] + s[:i]\n if rotated_s == s:\n return i\n return -1 #No rotation produces the same string", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(s):\n \"\"\"\n Finds the minimum number of rotations (greater than 0) required to get the same string.\n\n Args:\n s: The input string.\n\n Returns:\n The minimum number of rotations, or -1 if no such rotation exists. Returns 1 if the string is all the same character.\n \"\"\"\n if not s:\n return -1 # Handle empty string case\n\n n = len(s)\n for i in range(1, n + 1):\n rotated = s[i:] + s[:i]\n if rotated == s:\n return i\n \n #check for all same character case. This is a special case since the above loop will not find a match.\n if all(c == s[0] for c in s):\n return 1\n \n return -1 # No rotation produces the same string", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(s):\n \"\"\"\n Finds the minimum number of rotations required to get the same string.\n\n Args:\n s: The input string.\n\n Returns:\n The minimum number of rotations (greater than 0), or -1 if no such rotation exists.\n \"\"\"\n n = len(s)\n for i in range(1, n + 1):\n rotated = s[i:] + s[:i]\n if rotated == s:\n return i\n return -1 # No rotation produces the same string", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(s):\n \"\"\"\n Finds the minimum number of rotations (greater than 0) required to get the same string.\n\n Args:\n s: The input string.\n\n Returns:\n The minimum number of rotations, or -1 if no such rotation exists. Returns 1 if the string is all the same character.\n\n \"\"\"\n if not s:\n return -1 # Handle empty string case\n\n n = len(s)\n for i in range(1, n + 1): # Iterate through possible rotation amounts\n rotated = s[i:] + s[:i]\n if rotated == s:\n return i\n \n #Check if all characters are the same\n if all(c == s[0] for c in s):\n return 1\n\n\n return -1 #No rotation found", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(s):\n \"\"\"\n Finds the minimum number of rotations (greater than 0) required to get the same string.\n\n Args:\n s: The input string.\n\n Returns:\n The minimum number of rotations, or -1 if no such rotation exists.\n \"\"\"\n n = len(s)\n for rotations in range(1, n + 1):\n rotated_s = s[rotations:] + s[:rotations]\n if rotated_s == s:\n return rotations\n return -1 # No rotation produces the same string", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(s):\n \"\"\"\n Finds the minimum number of rotations (greater than 0) required to get the same string.\n\n Args:\n s: The input string.\n\n Returns:\n The minimum number of rotations, or -1 if no such rotation exists. Returns 1 if the string is all the same character.\n \"\"\"\n if not s:\n return -1 # Handle empty string case\n\n n = len(s)\n for i in range(1, n + 1):\n rotated = s[i:] + s[:i]\n if rotated == s:\n return i\n \n #Check for all same character case\n if all(c == s[0] for c in s):\n return 1\n\n return -1 # No rotation produces the same string", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(s):\n \"\"\"\n Finds the minimum number of rotations (greater than 0) required to get the same string.\n\n Args:\n s: The input string.\n\n Returns:\n The minimum number of rotations, or -1 if no such rotation exists.\n \"\"\"\n n = len(s)\n for i in range(1, n + 1):\n rotated = s[i:] + s[:i]\n if rotated == s:\n return i\n return -1 # No rotation produces the same string", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(s):\n \"\"\"\n Finds the minimum number of rotations (greater than 0) required to get the same string.\n\n Args:\n s: The input string.\n\n Returns:\n The minimum number of rotations, or -1 if no such rotation exists.\n \"\"\"\n n = len(s)\n for rotations in range(1, n + 1):\n rotated_s = s[rotations:] + s[:rotations]\n if rotated_s == s:\n return rotations\n return -1 # No rotation produces the same string", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(s):\n \"\"\"\n Finds the minimum number of rotations (greater than 0) required to get the same string.\n\n Args:\n s: The input string.\n\n Returns:\n The minimum number of rotations, or -1 if no such rotation exists.\n \"\"\"\n n = len(s)\n for i in range(1, n + 1):\n rotated = s[i:] + s[:i]\n if rotated == s:\n return i\n return -1 # No rotation produces the same string", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(s):\n \"\"\"\n Finds the minimum number of rotations (greater than 0) required to get the same string.\n\n Args:\n s: The input string.\n\n Returns:\n The minimum number of rotations, or -1 if no such rotation exists. Returns 1 if the string is all the same character.\n \"\"\"\n if not s:\n return -1 # Handle empty string case\n\n n = len(s)\n for i in range(1, n + 1):\n rotated = s[i:] + s[:i]\n if rotated == s:\n return i\n \n #Handle case where all characters are the same.\n if all(c == s[0] for c in s):\n return 1\n\n return -1 # No rotation produces the same string", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(s):\n \"\"\"\n Finds the minimum number of rotations (greater than 0) required to get the same string.\n\n Args:\n s: The input string.\n\n Returns:\n The minimum number of rotations, or -1 if no such rotation exists. Returns 1 if the string is all the same character.\n \"\"\"\n if not s:\n return -1 # Handle empty string case\n\n n = len(s)\n for i in range(1, n + 1): # Iterate through possible rotations\n rotated = s[i:] + s[:i]\n if rotated == s:\n return i\n #Optimization for all same characters\n if all(c == s[0] for c in s):\n return 1\n\n\n return -1 # No rotation produces the same string", "matching_cluster_idx": 3}, {"solution": "def find_Rotations(s):\n \"\"\"\n Finds the minimum number of rotations (greater than 0) required to get the same string.\n\n Args:\n s: The input string.\n\n Returns:\n The minimum number of rotations, or -1 if no such rotation exists.\n \"\"\"\n n = len(s)\n for i in range(1, n + 1):\n rotated_s = s[i:] + s[:i]\n if rotated_s == s:\n return i\n return -1 # No rotation found", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(s):\n \"\"\"\n Finds the minimum number of rotations (greater than 0) required to get the same string.\n\n Args:\n s: The input string.\n\n Returns:\n The minimum number of rotations required, or -1 if no such rotation exists.\n \"\"\"\n n = len(s)\n for rotations in range(1, n + 1):\n rotated_s = s[rotations:] + s[:rotations]\n if rotated_s == s:\n return rotations\n return -1 # No rotation found", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(s):\n \"\"\"\n Finds the minimum number of rotations (greater than 0) required to get the same string.\n\n Args:\n s: The input string.\n\n Returns:\n The minimum number of rotations required, or -1 if no such rotation exists. Returns 1 if the string is all the same character.\n \"\"\"\n if not s:\n return -1 # Handle empty string case\n\n n = len(s)\n for i in range(1, n + 1):\n rotated = s[i:] + s[:i]\n if rotated == s:\n return i\n \n #Check for all same character case. This handles strings like \"aaaa\" which would otherwise return -1.\n if all(c == s[0] for c in s):\n return 1\n\n return -1 # No rotation produces the same string", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(s):\n \"\"\"\n Finds the minimum number of rotations (greater than 0) required to get the same string.\n\n Args:\n s: The input string.\n\n Returns:\n The minimum number of rotations, or -1 if no such rotation exists. Returns 1 for strings that are all the same character.\n \"\"\"\n if not s:\n return -1 # Handle empty string case\n\n n = len(s)\n for i in range(1, n + 1):\n rotated = s[i:] + s[:i]\n if rotated == s:\n return i\n \n #Check for all same character case\n if all(c == s[0] for c in s):\n return 1\n return -1 #No rotation found", "matching_cluster_idx": 4}]}, "Mbpp/11": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 48.0, "profiled": [{"solution": "def remove_Occ(input_string, char_to_remove):\n \"\"\"Removes the first and last occurrences of a given character from a string.\n\n Args:\n input_string: The input string.\n char_to_remove: The character to remove.\n\n Returns:\n The string with the first and last occurrences of the character removed. Returns the original string if the character is not found.\n \"\"\"\n first_index = input_string.find(char_to_remove)\n last_index = input_string.rfind(char_to_remove)\n\n if first_index == -1: # Character not found\n return input_string\n elif first_index == last_index: # Only one occurrence\n return input_string[:first_index] + input_string[first_index+1:]\n else:\n return input_string[:first_index] + input_string[first_index+1:last_index] + input_string[last_index+1:]", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(str, ch):\n \"\"\"\n Removes the first and last occurrences of a given character from a string.\n\n Args:\n str: The input string.\n ch: The character to remove.\n\n Returns:\n The string with the first and last occurrences of the character removed. Returns the original string if the character is not found.\n \"\"\"\n\n first = str.find(ch)\n last = str.rfind(ch)\n\n if first == -1: # Character not found\n return str\n\n if first == last: # Only one occurrence\n return str[:first] + str[first+1:]\n\n return str[:first] + str[first+1:last] + str[last+1:]", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(str, char):\n \"\"\"\n Removes the first and last occurrences of a given character from a string.\n\n Args:\n str: The input string.\n char: The character to remove.\n\n Returns:\n The string with the first and last occurrences of the character removed. Returns the original string if the character is not found.\n \"\"\"\n first_index = str.find(char)\n last_index = str.rfind(char)\n\n if first_index == -1: # Character not found\n return str\n\n if first_index == last_index: #only one occurrence\n return str[:first_index] + str[first_index+1:]\n\n return str[:first_index] + str[first_index+1:last_index] + str[last_index+1:]", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(input_string, char_to_remove):\n \"\"\"Removes the first and last occurrences of a given character from a string.\n\n Args:\n input_string: The input string.\n char_to_remove: The character to remove.\n\n Returns:\n The string with the first and last occurrences of the character removed. Returns the original string if the character is not found.\n \"\"\"\n\n first_index = input_string.find(char_to_remove)\n last_index = input_string.rfind(char_to_remove)\n\n if first_index == -1: # Character not found\n return input_string\n\n if first_index == last_index: #only one occurrence\n return input_string[:first_index] + input_string[first_index+1:]\n\n return input_string[:first_index] + input_string[first_index + 1:last_index] + input_string[last_index + 1:]", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(str, char):\n \"\"\"\n Removes the first and last occurrences of a given character from a string.\n\n Args:\n str: The input string.\n char: The character to remove.\n\n Returns:\n The string with the first and last occurrences of the character removed. Returns the original string if the character is not found.\n \"\"\"\n first_index = str.find(char)\n last_index = str.rfind(char)\n\n if first_index == -1: #Character not found\n return str\n\n if first_index == last_index: #Only one occurrence\n return str[:first_index] + str[first_index+1:]\n else:\n return str[:first_index] + str[first_index+1:last_index] + str[last_index+1:]", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(str, ch):\n \"\"\"\n Removes the first and last occurrences of a given character from a string.\n\n Args:\n str: The input string.\n ch: The character to remove.\n\n Returns:\n The string with the first and last occurrences of the character removed. Returns the original string if the character is not found.\n \"\"\"\n first = str.find(ch)\n last = str.rfind(ch)\n\n if first == -1: # Character not found\n return str\n\n if first == last: # Only one occurrence\n return str[:first] + str[first+1:]\n\n return str[:first] + str[first+1:last] + str[last+1:]", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(input_string, char_to_remove):\n \"\"\"\n Removes the first and last occurrences of a given character from a string.\n\n Args:\n input_string: The input string.\n char_to_remove: The character to remove.\n\n Returns:\n The string with the first and last occurrences of the character removed. Returns the original string if the character is not found.\n\n \"\"\"\n first_index = input_string.find(char_to_remove)\n last_index = input_string.rfind(char_to_remove)\n\n if first_index == -1: # Character not found\n return input_string\n elif first_index == last_index: #only one occurrence\n return input_string[:first_index] + input_string[first_index+1:]\n else:\n return input_string[:first_index] + input_string[first_index+1:last_index] + input_string[last_index+1:]", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(str, char):\n \"\"\"Removes the first and last occurrences of a given character from a string.\n\n Args:\n str: The input string.\n char: The character to remove.\n\n Returns:\n The string with the first and last occurrences of the character removed. Returns the original string if the character is not found.\n \"\"\"\n\n first = str.find(char)\n last = str.rfind(char)\n\n if first == -1: # Character not found\n return str\n\n if first == last: # Only one occurrence\n return str[:first] + str[first+1:]\n\n return str[:first] + str[first+1:last] + str[last+1:]", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(input_string, char_to_remove):\n \"\"\"Removes the first and last occurrences of a character from a string.\n\n Args:\n input_string: The input string.\n char_to_remove: The character to remove.\n\n Returns:\n The string with the first and last occurrences of the character removed. Returns the original string if the character is not found.\n \"\"\"\n\n first_index = input_string.find(char_to_remove)\n last_index = input_string.rfind(char_to_remove)\n\n if first_index == -1: # Character not found\n return input_string\n\n if first_index == last_index: #only one occurrence\n return input_string[:first_index] + input_string[first_index+1:]\n\n return input_string[:first_index] + input_string[first_index+1:last_index] + input_string[last_index+1:]", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(string, char):\n \"\"\"\n Removes the first and last occurrences of a given character from a string.\n\n Args:\n string: The input string.\n char: The character to remove.\n\n Returns:\n The string with the first and last occurrences of the character removed. Returns the original string if the character is not found.\n\n \"\"\"\n first_index = string.find(char)\n last_index = string.rfind(char)\n\n if first_index == -1: # Character not found\n return string\n elif first_index == last_index: # Only one occurrence\n return string[:first_index] + string[first_index+1:]\n else:\n return string[:first_index] + string[first_index+1:last_index] + string[last_index+1:]", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(input_string, char_to_remove):\n \"\"\"\n Removes the first and last occurrences of a given character from a string.\n\n Args:\n input_string: The input string.\n char_to_remove: The character to remove.\n\n Returns:\n The string with the first and last occurrences of the character removed. Returns the original string if the character is not found.\n \"\"\"\n \n first_index = input_string.find(char_to_remove)\n last_index = input_string.rfind(char_to_remove)\n\n if first_index == -1: # Character not found\n return input_string\n \n if first_index == last_index: #only one occurrence\n return input_string[:first_index] + input_string[first_index+1:]\n else:\n return input_string[:first_index] + input_string[first_index+1:last_index] + input_string[last_index+1:]", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(str, char):\n \"\"\"\n Removes the first and last occurrences of a given character from a string.\n\n Args:\n str: The input string.\n char: The character to remove.\n\n Returns:\n The string with the first and last occurrences of the character removed. Returns the original string if the character is not found.\n\n \"\"\"\n first = str.find(char)\n last = str.rfind(char)\n\n if first == -1: # Character not found\n return str\n\n if first == last: #Only one occurrence\n return str[:first] + str[first+1:]\n\n return str[:first] + str[first+1:last] + str[last+1:]", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(str, char):\n \"\"\"\n Removes the first and last occurrences of a given character from a string.\n\n Args:\n str: The input string.\n char: The character to remove.\n\n Returns:\n The string with the first and last occurrences of the character removed.\n Returns the original string if the character is not found.\n\n \"\"\"\n first_index = str.find(char)\n last_index = str.rfind(char)\n\n if first_index == -1: # Character not found\n return str\n\n if first_index == last_index: #only one occurence\n return str[:first_index] + str[first_index+1:]\n\n return str[:first_index] + str[first_index+1:last_index] + str[last_index+1:]", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(input_str, char_to_remove):\n \"\"\"\n Removes the first and last occurrences of a given character from a string.\n\n Args:\n input_str: The input string.\n char_to_remove: The character to remove.\n\n Returns:\n The string with the first and last occurrences of the character removed. Returns the original string if the character is not found.\n\n \"\"\"\n first_index = input_str.find(char_to_remove)\n last_index = input_str.rfind(char_to_remove)\n\n if first_index == -1: #Character not found\n return input_str\n\n if first_index == last_index: # only one occurrence\n return input_str[:first_index] + input_str[first_index+1:]\n else:\n return input_str[:first_index] + input_str[first_index+1:last_index] + input_str[last_index+1:]", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(input_string, char_to_remove):\n \"\"\"Removes the first and last occurrences of a given character from a string.\n\n Args:\n input_string: The input string.\n char_to_remove: The character to remove.\n\n Returns:\n The string with the first and last occurrences of the character removed. Returns the original string if the character is not found.\n \"\"\"\n\n first_index = input_string.find(char_to_remove)\n last_index = input_string.rfind(char_to_remove)\n\n if first_index == -1: # Character not found\n return input_string\n\n if first_index == last_index: #only one occurrence\n return input_string[:first_index] + input_string[first_index+1:]\n\n return input_string[:first_index] + input_string[first_index+1:last_index] + input_string[last_index+1:]", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(str, ch):\n \"\"\"\n Removes the first and last occurrences of a given character from a string.\n\n Args:\n str: The input string.\n ch: The character to remove.\n\n Returns:\n The string with the first and last occurrences of the character removed. Returns the original string if the character is not found.\n \"\"\"\n first = str.find(ch)\n last = str.rfind(ch)\n\n if first == -1: # Character not found\n return str\n\n if first == last: #Only one occurrence\n return str.replace(ch,\"\",1)\n\n return str[:first] + str[first+1:last] + str[last+1:]", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(input_string, char_to_remove):\n \"\"\"\n Removes the first and last occurrences of a given character from a string.\n\n Args:\n input_string: The input string.\n char_to_remove: The character to remove.\n\n Returns:\n The string with the first and last occurrences of the character removed. Returns the original string if the character is not found.\n \"\"\"\n\n first_index = input_string.find(char_to_remove)\n last_index = input_string.rfind(char_to_remove)\n\n if first_index == -1: # Character not found\n return input_string\n elif first_index == last_index: #Only one occurrence\n return input_string[:first_index] + input_string[first_index+1:]\n else:\n return input_string[:first_index] + input_string[first_index+1:last_index] + input_string[last_index+1:]", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(str, ch):\n \"\"\"\n Removes the first and last occurrences of a given character from a string.\n\n Args:\n str: The input string.\n ch: The character to remove.\n\n Returns:\n The string with the first and last occurrences of the character removed. Returns the original string if the character is not found.\n \"\"\"\n first = str.find(ch)\n last = str.rfind(ch)\n\n if first == -1: # Character not found\n return str\n\n if first == last: #Only one occurrence\n return str[:first] + str[first+1:]\n\n return str[:first] + str[first+1:last] + str[last+1:]", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(input_str, char_to_remove):\n \"\"\"\n Removes the first and last occurrences of a given character from a string.\n\n Args:\n input_str: The input string.\n char_to_remove: The character to remove.\n\n Returns:\n The string with the first and last occurrences of the character removed.\n Returns the original string if the character is not found.\n \"\"\"\n\n first_index = input_str.find(char_to_remove)\n last_index = input_str.rfind(char_to_remove)\n\n if first_index == -1: # Character not found\n return input_str\n\n if first_index == last_index: # Only one occurrence\n return input_str[:first_index] + input_str[first_index+1:]\n else:\n return input_str[:first_index] + input_str[first_index+1:last_index] + input_str[last_index+1:]", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(str, char):\n \"\"\"\n Removes the first and last occurrences of a given character from a string.\n\n Args:\n str: The input string.\n char: The character to remove.\n\n Returns:\n The string with the first and last occurrences of the character removed.\n Returns the original string if the character is not found.\n\n \"\"\"\n first_index = str.find(char)\n last_index = str.rfind(char)\n\n if first_index == -1: # Character not found\n return str\n\n if first_index == last_index: # Only one occurrence\n return str[:first_index] + str[first_index+1:]\n\n return str[:first_index] + str[first_index+1:last_index] + str[last_index+1:]", "matching_cluster_idx": 8}]}, "Mbpp/12": {"dps": 95.13477088948787, "dps_norm": 96.875, "pass@1": 100.0, "profiled": [{"solution": "def sort_matrix(matrix):\n \"\"\"\n Sorts a given matrix in ascending order according to the sum of its rows.\n\n Args:\n matrix: A list of lists representing the matrix.\n\n Returns:\n A new list of lists representing the sorted matrix. Returns an empty list if input is invalid.\n \"\"\"\n if not isinstance(matrix, list) or not all(isinstance(row, list) for row in matrix):\n return [] #Handle invalid input\n\n #Calculate row sums and create tuples for sorting\n row_sums = [(sum(row), row) for row in matrix]\n\n #Sort by row sum\n row_sums.sort()\n\n #Extract sorted rows\n sorted_matrix = [row for sum_row, row in row_sums]\n\n return sorted_matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"\n Sorts a given matrix in ascending order according to the sum of its rows.\n\n Args:\n matrix: A list of lists representing the matrix.\n\n Returns:\n A new list of lists representing the sorted matrix. Returns the original \n matrix if it's empty or contains non-numerical data.\n \"\"\"\n if not matrix:\n return matrix\n\n # Check if all elements are numbers\n if not all(isinstance(x, (int, float)) for row in matrix for x in row):\n return matrix\n\n\n # Create a list of tuples, where each tuple contains the row sum and the row itself.\n row_sums = [(sum(row), row) for row in matrix]\n\n # Sort the list of tuples based on the row sums.\n row_sums.sort()\n\n # Extract the sorted rows to create the sorted matrix.\n sorted_matrix = [row for sum_row, row in row_sums]\n\n return sorted_matrix", "matching_cluster_idx": 5}, {"solution": "def sort_matrix(matrix):\n \"\"\"\n Sorts a given matrix in ascending order according to the sum of its rows.\n\n Args:\n matrix: A list of lists representing the matrix.\n\n Returns:\n A new list of lists representing the sorted matrix. Returns an empty list if input is invalid.\n \"\"\"\n if not isinstance(matrix, list) or not all(isinstance(row, list) for row in matrix):\n return [] #Handle invalid input\n\n #Calculate row sums and create tuples for sorting\n row_sums = [(sum(row), row) for row in matrix]\n\n #Sort by row sum (ascending)\n row_sums.sort()\n\n #Extract sorted rows\n sorted_matrix = [row for sum_row, row in row_sums]\n\n return sorted_matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"\n Sorts a given matrix in ascending order according to the sum of its rows.\n\n Args:\n matrix: A list of lists representing the matrix.\n\n Returns:\n A new matrix sorted in ascending order based on row sums. Returns an empty list if input is invalid.\n \"\"\"\n if not isinstance(matrix, list) or not all(isinstance(row, list) for row in matrix):\n return [] # Handle invalid input\n\n #Calculate row sums and create tuples for sorting\n row_sums = [(sum(row), row) for row in matrix]\n\n #Sort based on row sums\n row_sums.sort()\n\n #Extract sorted rows\n sorted_matrix = [row for sum_row, row in row_sums]\n\n return sorted_matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"Sorts a matrix in ascending order based on the sum of its rows.\"\"\"\n\n # Calculate row sums and create a list of (sum, row) tuples.\n row_sums = [(sum(row), row) for row in matrix]\n\n # Sort the list of tuples based on the row sums (the first element of each tuple).\n row_sums.sort()\n\n # Extract the sorted rows to create the sorted matrix.\n sorted_matrix = [row for sum_row, row in row_sums]\n\n return sorted_matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"Sorts a matrix in ascending order based on the sum of its rows.\n\n Args:\n matrix: A list of lists representing the matrix.\n\n Returns:\n A new matrix sorted in ascending order based on row sums. Returns an empty list if input is invalid.\n \"\"\"\n if not isinstance(matrix, list) or not all(isinstance(row, list) for row in matrix):\n return [] # Handle invalid input\n\n #Calculate row sums and create tuples for sorting\n row_sums = [(sum(row), row) for row in matrix]\n\n #Sort based on row sums\n row_sums.sort()\n\n #Extract sorted rows\n sorted_matrix = [row for _, row in row_sums]\n\n return sorted_matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"\n Sorts a given matrix in ascending order according to the sum of its rows.\n\n Args:\n matrix: A list of lists representing the matrix.\n\n Returns:\n A new matrix sorted in ascending order based on row sums. Returns an empty list if the input is invalid.\n \"\"\"\n if not isinstance(matrix, list) or not all(isinstance(row, list) for row in matrix):\n return [] # Handle invalid input\n\n # Calculate row sums and create a list of (sum, row) tuples\n rows_with_sums = [(sum(row), row) for row in matrix]\n\n # Sort the tuples based on the sums (first element of the tuple)\n rows_with_sums.sort()\n\n # Extract the sorted rows to create the sorted matrix\n sorted_matrix = [row for sum_row, row in rows_with_sums]\n\n return sorted_matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"Sorts a given matrix in ascending order according to the sum of its rows.\n\n Args:\n matrix: A list of lists representing the matrix.\n\n Returns:\n A new list of lists representing the sorted matrix. Returns an empty list if the input is invalid.\n \"\"\"\n if not isinstance(matrix, list) or not all(isinstance(row, list) for row in matrix):\n return [] # Handle invalid input\n\n # Calculate row sums and create a list of (sum, row) tuples\n row_sums = [(sum(row), row) for row in matrix]\n\n # Sort the tuples based on row sums\n row_sums.sort()\n\n # Extract the sorted rows\n sorted_matrix = [row for sum_row, row in row_sums]\n\n return sorted_matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"\n Sorts a given matrix in ascending order according to the sum of its rows.\n\n Args:\n matrix: A list of lists representing the matrix.\n\n Returns:\n A new list of lists representing the sorted matrix. Returns an empty list if the input is invalid.\n \"\"\"\n if not isinstance(matrix, list) or not all(isinstance(row, list) for row in matrix):\n return [] #Handle invalid input\n\n # Calculate row sums and create tuples for sorting\n row_sums = [(sum(row), row) for row in matrix]\n\n # Sort based on row sums\n row_sums.sort()\n\n # Extract sorted rows\n sorted_matrix = [row for sum_row, row in row_sums]\n\n return sorted_matrix\nmatrix = [[1, 2, 3], [2, 4, 5], [1, 1, 1]]\nsorted_matrix = sort_matrix(matrix)", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"\n Sorts a given matrix in ascending order according to the sum of its rows.\n\n Args:\n matrix: A list of lists representing the matrix.\n\n Returns:\n A new matrix sorted in ascending order based on row sums.\n \"\"\"\n\n #Calculate row sums\n row_sums = [sum(row) for row in matrix]\n\n #Zip row sums and matrix rows for sorting\n zipped_data = list(zip(row_sums, matrix))\n\n #Sort by row sums (first element of the tuple)\n zipped_data.sort()\n\n #Unzip to get the sorted matrix\n sorted_matrix = [row for _, row in zipped_data]\n\n return sorted_matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"Sorts a matrix in ascending order based on the sum of its rows.\n\n Args:\n matrix: A list of lists representing the matrix.\n\n Returns:\n A new list of lists representing the sorted matrix. Returns an empty list if input is invalid.\n \"\"\"\n if not isinstance(matrix, list) or not all(isinstance(row, list) for row in matrix):\n return [] #Handle invalid input\n\n #Calculate row sums and create a list of (sum, row) tuples\n row_sums = [(sum(row), row) for row in matrix]\n\n #Sort the list of tuples based on the row sums\n row_sums.sort()\n\n #Extract the sorted rows\n sorted_matrix = [row for sum_row, row in row_sums]\n\n return sorted_matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"\n Sorts a given matrix in ascending order according to the sum of its rows.\n\n Args:\n matrix: A list of lists representing the matrix.\n\n Returns:\n A new list of lists representing the sorted matrix. Returns an empty list if input is invalid.\n \"\"\"\n if not isinstance(matrix, list) or not all(isinstance(row, list) for row in matrix):\n return [] # Handle invalid input\n\n # Calculate row sums and create tuples for sorting\n row_sums = [(sum(row), row) for row in matrix]\n\n # Sort based on row sums\n row_sums.sort()\n\n # Extract sorted rows\n sorted_matrix = [row for _, row in row_sums]\n\n return sorted_matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"\n Sorts a given matrix in ascending order according to the sum of its rows.\n\n Args:\n matrix: A list of lists representing the matrix.\n\n Returns:\n A new list of lists representing the sorted matrix. Returns an empty list if input is invalid.\n\n Raises:\n TypeError: if input is not a list of lists.\n ValueError: if rows in the matrix are of unequal length.\n\n \"\"\"\n if not isinstance(matrix, list):\n raise TypeError(\"Input must be a list of lists.\")\n if not all(isinstance(row, list) for row in matrix):\n raise TypeError(\"Input must be a list of lists.\")\n if len(matrix) > 0 and not all(len(row) == len(matrix[0]) for row in matrix):\n raise ValueError(\"All rows in the matrix must have the same length.\")\n if len(matrix) == 0:\n return []\n\n # Create a list of tuples where each tuple contains the row sum and the row itself.\n rows_with_sums = [(sum(row), row) for row in matrix]\n\n # Sort the list of tuples based on the row sums (the first element of each tuple).\n rows_with_sums.sort()\n\n # Extract the sorted rows from the list of tuples.\n sorted_matrix = [row for sum_val, row in rows_with_sums]\n\n return sorted_matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"Sorts a matrix in ascending order based on the sum of its rows.\"\"\"\n\n # Calculate the sum of each row\n row_sums = [sum(row) for row in matrix]\n\n # Create a list of tuples, where each tuple contains the row sum and the original row\n row_sum_pairs = list(zip(row_sums, matrix))\n\n # Sort the list of tuples based on the row sums (the first element of each tuple)\n row_sum_pairs.sort()\n\n # Extract the sorted rows from the tuples\n sorted_matrix = [row for sum_val, row in row_sum_pairs]\n\n return sorted_matrix\nmatrix = [[1, 2, 3], [2, 4, 5], [1, 1, 1]]\nsorted_matrix = sort_matrix(matrix)", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"\n Sorts a given matrix in ascending order according to the sum of its rows.\n\n Args:\n matrix: A list of lists representing the matrix.\n\n Returns:\n A new list of lists representing the sorted matrix. Returns an empty list if input is invalid.\n \"\"\"\n if not isinstance(matrix, list) or not all(isinstance(row, list) for row in matrix):\n return [] #Handle invalid input\n\n # Calculate row sums and create a list of (sum, row) tuples\n row_sums = [(sum(row), row) for row in matrix]\n\n # Sort the tuples based on the row sums (first element of the tuple)\n row_sums.sort()\n\n # Extract the sorted rows\n sorted_matrix = [row for sum_val, row in row_sums]\n\n return sorted_matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"\n Sorts a given matrix in ascending order according to the sum of its rows.\n\n Args:\n matrix: A list of lists representing the matrix.\n\n Returns:\n A new list of lists representing the sorted matrix. Returns an empty list if the input is invalid.\n \"\"\"\n if not matrix or not all(isinstance(row, list) for row in matrix):\n return []\n\n # Calculate row sums and create a list of (sum, row) tuples\n row_sums = [(sum(row), row) for row in matrix]\n\n # Sort the tuples based on the row sums (first element of the tuple)\n row_sums.sort()\n\n # Extract the sorted rows\n sorted_matrix = [row for sum_row, row in row_sums]\n\n return sorted_matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"Sorts a matrix in ascending order based on row sums.\n\n Args:\n matrix: A list of lists representing the matrix.\n\n Returns:\n A new list of lists representing the sorted matrix. Returns an empty list if the input is invalid.\n \"\"\"\n if not isinstance(matrix, list) or not all(isinstance(row, list) for row in matrix):\n return [] #Handle invalid input\n\n # Calculate row sums and create a list of (sum, row) tuples\n row_sums = [(sum(row), row) for row in matrix]\n\n # Sort the tuples based on row sums (first element of the tuple)\n row_sums.sort()\n\n # Extract the sorted rows\n sorted_matrix = [row for sum_val, row in row_sums]\n\n return sorted_matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"\n Sorts a given matrix in ascending order according to the sum of its rows.\n\n Args:\n matrix: A list of lists representing the matrix.\n\n Returns:\n A new list of lists representing the sorted matrix. Returns an empty list if the input is invalid.\n \"\"\"\n if not isinstance(matrix, list) or not all(isinstance(row, list) for row in matrix):\n return [] #Handle invalid input\n\n #Calculate row sums and create a list of (sum, row) tuples\n row_sums = [(sum(row), row) for row in matrix]\n\n #Sort the tuples based on the sum (first element of the tuple)\n row_sums.sort()\n\n #Extract the sorted rows\n sorted_matrix = [row for sum_val, row in row_sums]\n\n return sorted_matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"Sorts a matrix in ascending order based on row sums.\n\n Args:\n matrix: A list of lists representing the matrix.\n\n Returns:\n A new matrix sorted in ascending order based on row sums. Returns an empty list if input is invalid.\n \"\"\"\n if not isinstance(matrix, list) or not all(isinstance(row, list) for row in matrix):\n return [] #Handle invalid input\n\n #Calculate row sums and create tuples for sorting\n rows_with_sums = [(sum(row), row) for row in matrix]\n\n #Sort based on row sums\n rows_with_sums.sort()\n\n #Extract sorted rows\n sorted_matrix = [row for sum_val, row in rows_with_sums]\n return sorted_matrix\nmatrix = [[1, 2, 3], [2, 4, 5], [1, 1, 1]]\nsorted_matrix = sort_matrix(matrix)", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"\n Sorts a given matrix in ascending order according to the sum of its rows.\n\n Args:\n matrix: A list of lists representing the matrix.\n\n Returns:\n A new list of lists representing the sorted matrix. Returns an empty list if input is invalid.\n \"\"\"\n if not isinstance(matrix, list) or not all(isinstance(row, list) for row in matrix):\n return [] # Handle invalid input\n\n # Calculate row sums and create a list of (sum, row) tuples\n row_sums = [(sum(row), row) for row in matrix]\n\n # Sort the tuples based on the sum (first element of the tuple)\n row_sums.sort()\n\n # Extract the sorted rows\n sorted_matrix = [row for sum_val, row in row_sums]\n\n return sorted_matrix", "matching_cluster_idx": 15}]}, "Mbpp/16": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 99.0, "profiled": [{"solution": "import re\ndef text_lowercase_underscore(text):\n \"\"\"\n Checks if a string contains sequences of lowercase letters joined with underscores.\n\n Args:\n text: The input string.\n\n Returns:\n True if the string matches the pattern, False otherwise.\n \"\"\"\n pattern = r'^[a-z]+(_[a-z]+)*$' # Matches one or more lowercase letters, optionally followed by underscores and more lowercase letters.\n match = re.match(pattern, text)\n return bool(match)", "matching_cluster_idx": 7}, {"solution": "import re\ndef text_lowercase_underscore(text):\n \"\"\"\n Checks if a string contains sequences of lowercase letters joined with underscores.\n\n Args:\n text: The input string.\n\n Returns:\n True if the string contains sequences of lowercase letters joined with underscores, \n False otherwise.\n \"\"\"\n pattern = r'^[a-z]+(_[a-z]+)*$' # Matches one or more lowercase letters, optionally followed by underscores and more lowercase letters.\n match = re.match(pattern, text)\n return bool(match)", "matching_cluster_idx": 7}, {"solution": "import re\ndef text_lowercase_underscore(text):\n \"\"\"\n Checks if a string contains sequences of lowercase letters joined with underscores.\n\n Args:\n text: The input string.\n\n Returns:\n True if the string matches the pattern, False otherwise.\n \"\"\"\n pattern = r'^[a-z]+(_[a-z]+)*$' # Matches one or more lowercase letters, optionally followed by underscores and more lowercase letters.\n match = re.match(pattern, text)\n return bool(match)", "matching_cluster_idx": 7}, {"solution": "import re\ndef text_lowercase_underscore(text):\n \"\"\"\n Checks if a string contains sequences of lowercase letters joined with underscores.\n\n Args:\n text: The input string.\n\n Returns:\n True if the string matches the pattern, False otherwise.\n \"\"\"\n pattern = r\"^([a-z]+_)*[a-z]+$\" # Matches one or more lowercase letters, optionally followed by underscores and more lowercase letters. ^ and $ ensure the entire string matches.\n match = re.match(pattern, text)\n return bool(match)", "matching_cluster_idx": 7}, {"solution": "import re\ndef text_lowercase_underscore(text):\n \"\"\"\n Checks if a string contains sequences of lowercase letters joined with underscores.\n\n Args:\n text: The input string.\n\n Returns:\n True if the string matches the pattern, False otherwise.\n \"\"\"\n pattern = r'^[a-z]+(_[a-z]+)*$' # Matches one or more lowercase letters, followed by zero or more occurrences of an underscore and one or more lowercase letters.\n match = re.match(pattern, text)\n return bool(match)", "matching_cluster_idx": 7}, {"solution": "import re\ndef text_lowercase_underscore(text):\n \"\"\"\n Checks if a string contains sequences of lowercase letters joined with underscores.\n\n Args:\n text: The input string.\n\n Returns:\n True if the string matches the pattern, False otherwise.\n \"\"\"\n pattern = r\"^([a-z]+_)*[a-z]+$\" # Matches one or more lowercase letters, optionally followed by underscores and more lowercase letters. ^ and $ ensure the whole string matches.\n match = re.match(pattern, text)\n return bool(match)", "matching_cluster_idx": 7}, {"solution": "import re\ndef text_lowercase_underscore(text):\n \"\"\"\n Checks if a string contains sequences of lowercase letters joined with underscores.\n\n Args:\n text: The input string.\n\n Returns:\n True if the string contains sequences of lowercase letters joined with underscores, \n False otherwise.\n \"\"\"\n pattern = r'^[a-z]+(_[a-z]+)*$' # Matches one or more lowercase letters, optionally followed by underscores and more lowercase letters.\n match = re.match(pattern, text)\n return bool(match)", "matching_cluster_idx": 7}, {"solution": "import re\ndef text_lowercase_underscore(text):\n \"\"\"\n Checks if a string contains sequences of lowercase letters joined with underscores.\n\n Args:\n text: The input string.\n\n Returns:\n True if the string matches the pattern, False otherwise.\n \"\"\"\n pattern = r'^[a-z]+(?:_[a-z]+)*$'\n match = re.match(pattern, text)\n return bool(match)", "matching_cluster_idx": 7}, {"solution": "import re\ndef text_lowercase_underscore(text):\n \"\"\"\n Checks if a string contains sequences of lowercase letters joined with underscores.\n\n Args:\n text: The input string.\n\n Returns:\n True if the string matches the pattern, False otherwise.\n \"\"\"\n pattern = r'^[a-z]+(_[a-z]+)*$' # Matches one or more lowercase letters, optionally followed by one or more underscores and lowercase letters.\n match = re.fullmatch(pattern, text)\n return bool(match)", "matching_cluster_idx": 7}, {"solution": "import re\ndef text_lowercase_underscore(text):\n \"\"\"\n Checks if the input string contains sequences of lowercase letters joined with underscores.\n\n Args:\n text: The input string.\n\n Returns:\n True if the string matches the pattern, False otherwise.\n \"\"\"\n pattern = r'^[a-z]+(_[a-z]+)*$' # Matches one or more lowercase letters, followed by zero or more occurrences of \"_\" and one or more lowercase letters. ^ and $ ensure the entire string matches.\n match = re.match(pattern, text)\n return bool(match)", "matching_cluster_idx": 7}, {"solution": "import re\ndef text_lowercase_underscore(text):\n \"\"\"\n Checks if a string contains sequences of lowercase letters joined with underscores.\n\n Args:\n text: The input string.\n\n Returns:\n True if the string contains sequences of lowercase letters joined with underscores, \n False otherwise.\n \"\"\"\n pattern = r\"^([a-z]+_)*[a-z]+$\" # Matches one or more lowercase letters, optionally followed by underscores and more lowercase letters. ^ and $ ensure the whole string matches.\n match = re.match(pattern, text)\n return bool(match)", "matching_cluster_idx": 7}, {"solution": "import re\ndef text_lowercase_underscore(text):\n \"\"\"\n Checks if a string contains sequences of lowercase letters joined with underscores.\n\n Args:\n text: The input string.\n\n Returns:\n True if the string matches the pattern, False otherwise.\n \"\"\"\n pattern = r\"^([a-z]+_)*[a-z]+$\" # Matches one or more lowercase letters, optionally followed by underscores and more lowercase letters. ^ and $ ensure the whole string matches.\n match = re.match(pattern, text)\n return bool(match)", "matching_cluster_idx": 7}, {"solution": "import re\ndef text_lowercase_underscore(text):\n \"\"\"\n Checks if a string contains sequences of lowercase letters joined with underscores.\n\n Args:\n text: The input string.\n\n Returns:\n True if the string matches the pattern, False otherwise.\n \"\"\"\n pattern = r\"^([a-z]+_)*[a-z]+$\" # Matches one or more lowercase letters, optionally followed by underscores and more lowercase letters. The ^ and $ ensure the entire string matches.\n match = re.match(pattern, text)\n return bool(match)", "matching_cluster_idx": 7}, {"solution": "import re\ndef text_lowercase_underscore(text):\n \"\"\"\n Checks if the input string contains sequences of lowercase letters joined with underscores.\n\n Args:\n text: The input string.\n\n Returns:\n True if the string matches the pattern, False otherwise.\n \"\"\"\n pattern = r'^[a-z]+(_[a-z]+)*$' # Matches one or more lowercase letters, optionally followed by one or more underscores and lowercase letters.\n match = re.match(pattern, text)\n return bool(match)", "matching_cluster_idx": 7}, {"solution": "import re\ndef text_lowercase_underscore(text):\n \"\"\"\n Checks if a string contains sequences of lowercase letters joined with underscores.\n\n Args:\n text: The input string.\n\n Returns:\n True if the string matches the pattern, False otherwise.\n \"\"\"\n pattern = r'^[a-z]+(_[a-z]+)*$' # Matches one or more lowercase letters, optionally followed by underscores and more lowercase letters.\n match = re.match(pattern, text)\n return bool(match)", "matching_cluster_idx": 7}, {"solution": "import re\ndef text_lowercase_underscore(text):\n \"\"\"\n Checks if a string contains sequences of lowercase letters joined with underscores.\n\n Args:\n text: The input string.\n\n Returns:\n True if the string contains only lowercase letters and underscores, \n and the underscores are used to separate sequences of lowercase letters; \n False otherwise.\n \"\"\"\n pattern = r\"^([a-z]+_)*[a-z]+$\" # Matches one or more lowercase letters, optionally followed by underscores and more lowercase letters. The ^ and $ anchor to the beginning and end of the string.\n\n match = re.match(pattern, text)\n return bool(match)", "matching_cluster_idx": 7}, {"solution": "import re\ndef text_lowercase_underscore(text):\n \"\"\"\n Checks if a string contains sequences of lowercase letters joined with underscores.\n\n Args:\n text: The input string.\n\n Returns:\n True if the string matches the pattern, False otherwise.\n \"\"\"\n pattern = r'^[a-z]+(_[a-z]+)*$' # Matches one or more lowercase letters, optionally followed by underscores and more lowercase letters.\n match = re.match(pattern, text)\n return bool(match)", "matching_cluster_idx": 7}, {"solution": "import re\ndef text_lowercase_underscore(text):\n \"\"\"\n Checks if a string contains sequences of lowercase letters joined with underscores.\n\n Args:\n text: The input string.\n\n Returns:\n True if the string matches the pattern, False otherwise.\n \"\"\"\n pattern = r\"^([a-z]+_)*[a-z]+$\" # Matches one or more lowercase letters, optionally followed by underscores and more lowercase letters. ^ and $ ensure the entire string matches.\n match = re.match(pattern, text)\n return bool(match)", "matching_cluster_idx": 7}, {"solution": "import re\ndef text_lowercase_underscore(text):\n \"\"\"\n Checks if a string contains sequences of lowercase letters joined with underscores.\n\n Args:\n text: The input string.\n\n Returns:\n True if the string matches the pattern, False otherwise.\n \"\"\"\n pattern = r'^[a-z]+(_[a-z]+)*$' # Matches one or more lowercase letters, optionally followed by underscores and more lowercase letters.\n match = re.match(pattern, text)\n return bool(match)", "matching_cluster_idx": 7}, {"solution": "import re\ndef text_lowercase_underscore(text):\n \"\"\"\n Checks if a string contains sequences of lowercase letters joined with underscores.\n\n Args:\n text: The input string.\n\n Returns:\n True if the string matches the pattern, False otherwise.\n \"\"\"\n pattern = r\"^([a-z]+_)*[a-z]+$\" # Matches one or more lowercase letters, optionally followed by underscores and more lowercase letters. The ^ and $ anchor to the beginning and end of the string.\n match = re.match(pattern, text)\n return bool(match)", "matching_cluster_idx": 7}]}, "Mbpp/19": {"dps": 98.53535353535354, "dps_norm": 99.66666666666667, "pass@1": 100.0, "profiled": [{"solution": "def test_duplicate(arr):\n \"\"\"\n Checks if an array of integers contains any duplicate elements.\n\n Args:\n arr: A list of integers.\n\n Returns:\n True if the array contains any duplicate elements, False otherwise.\n \"\"\"\n seen = set()\n for num in arr:\n if num in seen:\n return True\n seen.add(num)\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(arr):\n \"\"\"\n Checks if an array of integers contains any duplicate elements.\n\n Args:\n arr: A list of integers.\n\n Returns:\n True if the array contains duplicates, False otherwise.\n \"\"\"\n seen = set()\n for num in arr:\n if num in seen:\n return True\n seen.add(num)\n return False", "matching_cluster_idx": 14}, {"solution": "def contains_duplicate(arr):\n \"\"\"\n Checks if a given array of integers contains any duplicate element.\n\n Args:\n arr: A list of integers.\n\n Returns:\n True if the array contains any duplicate element, False otherwise.\n \"\"\"\n seen = set()\n for num in arr:\n if num in seen:\n return True\n seen.add(num)\n return False\ndef test_duplicate(arr):\n return contains_duplicate(arr)", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(arr):\n \"\"\"\n Write a function to find whether a given array of integers contains any duplicate element.\n assert test_duplicate(([1,2,3,4,5]))==False\n \"\"\"\n seen = set()\n for num in arr:\n if num in seen:\n return True\n seen.add(num)\n return False", "matching_cluster_idx": 14}, {"solution": "def contains_duplicate(arr):\n \"\"\"\n Checks if a given array of integers contains any duplicate element.\n\n Args:\n arr: A list of integers.\n\n Returns:\n True if the array contains any duplicate element, False otherwise.\n \"\"\"\n seen = set()\n for num in arr:\n if num in seen:\n return True\n seen.add(num)\n return False\ndef test_duplicate(arr):\n return contains_duplicate(arr)", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(arr):\n \"\"\"\n Write a function to find whether a given array of integers contains any duplicate element.\n assert test_duplicate(([1,2,3,4,5]))==False\n \"\"\"\n seen = set()\n for num in arr:\n if num in seen:\n return True\n seen.add(num)\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(arr):\n \"\"\"\n Checks if an array of integers contains any duplicate elements.\n\n Args:\n arr: A list of integers.\n\n Returns:\n True if the array contains duplicate elements, False otherwise.\n \"\"\"\n seen = set()\n for num in arr:\n if num in seen:\n return True\n seen.add(num)\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(arr):\n \"\"\"\n Checks if an array of integers contains any duplicate elements.\n\n Args:\n arr: A list of integers.\n\n Returns:\n True if the array contains duplicate elements, False otherwise.\n \"\"\"\n seen = set()\n for num in arr:\n if num in seen:\n return True\n seen.add(num)\n return False", "matching_cluster_idx": 14}, {"solution": "def contains_duplicate(arr):\n \"\"\"\n Checks if a given array of integers contains any duplicate elements.\n\n Args:\n arr: A list of integers.\n\n Returns:\n True if the array contains duplicate elements, False otherwise.\n \"\"\"\n seen = set()\n for num in arr:\n if num in seen:\n return True\n seen.add(num)\n return False\ndef test_duplicate(arr):\n return contains_duplicate(arr)", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(arr):\n \"\"\"\n Write a function to find whether a given array of integers contains any duplicate element.\n assert test_duplicate(([1,2,3,4,5]))==False\n \"\"\"\n seen = set()\n for num in arr:\n if num in seen:\n return True\n seen.add(num)\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(arr):\n \"\"\"\n Checks if an array of integers contains any duplicate elements.\n\n Args:\n arr: A list of integers.\n\n Returns:\n True if the array contains duplicates, False otherwise.\n \"\"\"\n seen = set()\n for num in arr:\n if num in seen:\n return True\n seen.add(num)\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(arr):\n \"\"\"\n Checks if an array of integers contains any duplicate elements.\n\n Args:\n arr: A list of integers.\n\n Returns:\n True if the array contains any duplicate elements, False otherwise.\n \"\"\"\n seen = set()\n for num in arr:\n if num in seen:\n return True\n seen.add(num)\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(arr):\n \"\"\"\n Checks if an array contains any duplicate elements.\n\n Args:\n arr: A list of integers.\n\n Returns:\n True if the array contains duplicate elements, False otherwise.\n \"\"\"\n seen = set()\n for num in arr:\n if num in seen:\n return True\n seen.add(num)\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(arr):\n \"\"\"\n Checks if an array of integers contains any duplicate elements.\n\n Args:\n arr: A list of integers.\n\n Returns:\n True if the array contains duplicates, False otherwise.\n \"\"\"\n seen = set()\n for num in arr:\n if num in seen:\n return True\n seen.add(num)\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(arr):\n \"\"\"\n Checks if an array of integers contains any duplicate elements.\n\n Args:\n arr: A list of integers.\n\n Returns:\n True if the array contains duplicates, False otherwise.\n \"\"\"\n seen = set()\n for num in arr:\n if num in seen:\n return True\n seen.add(num)\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(arr):\n \"\"\"\n Checks if a given array of integers contains any duplicate element.\n\n Args:\n arr: A list of integers.\n\n Returns:\n True if the array contains duplicate elements, False otherwise.\n \"\"\"\n seen = set()\n for num in arr:\n if num in seen:\n return True\n seen.add(num)\n return False", "matching_cluster_idx": 14}, {"solution": "def contains_duplicate(arr):\n \"\"\"\n Checks if a given array of integers contains any duplicate element.\n\n Args:\n arr: A list of integers.\n\n Returns:\n True if the array contains duplicate elements, False otherwise.\n \"\"\"\n seen = set()\n for num in arr:\n if num in seen:\n return True\n seen.add(num)\n return False\ndef test_duplicate(arr):\n return contains_duplicate(arr)", "matching_cluster_idx": 14}, {"solution": "def contains_duplicate(arr):\n \"\"\"\n Checks if a given array of integers contains any duplicate element.\n\n Args:\n arr: A list of integers.\n\n Returns:\n True if the array contains any duplicate element, False otherwise.\n \"\"\"\n seen = set()\n for num in arr:\n if num in seen:\n return True\n seen.add(num)\n return False\ndef test_duplicate(arr):\n \"\"\"\n Test function for contains_duplicate.\n \"\"\"\n return contains_duplicate(arr)", "matching_cluster_idx": 13}, {"solution": "def test_duplicate(arr):\n \"\"\"\n Checks if an array contains any duplicate elements.\n\n Args:\n arr: A list of integers.\n\n Returns:\n True if the array contains duplicates, False otherwise.\n \"\"\"\n seen = set()\n for num in arr:\n if num in seen:\n return True\n seen.add(num)\n return False", "matching_cluster_idx": 14}, {"solution": "def contains_duplicate(arr):\n \"\"\"\n Checks if a given array of integers contains any duplicate elements.\n\n Args:\n arr: A list of integers.\n\n Returns:\n True if the array contains at least one duplicate element, False otherwise.\n \"\"\"\n seen = set()\n for num in arr:\n if num in seen:\n return True\n seen.add(num)\n return False\ndef test_duplicate(arr):\n \"\"\"Test function for contains_duplicate.\"\"\"\n return contains_duplicate(arr)", "matching_cluster_idx": 14}]}, "Mbpp/62": {"dps": 50.15384615384615, "dps_norm": 58.0, "pass@1": 100.0, "profiled": [{"solution": "def smallest_num(numbers):\n \"\"\"\n Finds the smallest number in a list.\n\n Args:\n numbers: A list of numbers.\n\n Returns:\n The smallest number in the list. Returns None if the list is empty.\n\n Raises:\n TypeError: if input is not a list.\n ValueError: if input list contains non-numeric values.\n\n \"\"\"\n if not isinstance(numbers, list):\n raise TypeError(\"Input must be a list.\")\n if not all(isinstance(num, (int, float)) for num in numbers):\n raise ValueError(\"List must contain only numbers.\")\n if not numbers:\n return None #Handle empty list case\n return min(numbers)", "matching_cluster_idx": 0}, {"solution": "def smallest_num(numbers):\n \"\"\"\n Finds the smallest number in a list.\n\n Args:\n numbers: A list of numbers.\n\n Returns:\n The smallest number in the list. Returns None if the list is empty.\n \"\"\"\n if not numbers:\n return None\n min_num = numbers[0]\n for num in numbers:\n if num < min_num:\n min_num = num\n return min_num", "matching_cluster_idx": 3}, {"solution": "def smallest_num(numbers):\n \"\"\"\n Finds the smallest number in a list.\n\n Args:\n numbers: A list of numbers.\n\n Returns:\n The smallest number in the list. Returns None if the list is empty.\n \"\"\"\n if not numbers:\n return None\n \n min_num = numbers[0] # Initialize with the first element\n for number in numbers:\n if number < min_num:\n min_num = number\n return min_num", "matching_cluster_idx": 3}, {"solution": "def smallest_num(numbers):\n \"\"\"\n Finds the smallest number in a list.\n\n Args:\n numbers: A list of numbers.\n\n Returns:\n The smallest number in the list. Returns None if the list is empty.\n\n Raises:\n TypeError: if input is not a list.\n ValueError: if the list contains non-numeric values.\n\n \"\"\"\n if not isinstance(numbers, list):\n raise TypeError(\"Input must be a list.\")\n if not numbers:\n return None # Handle empty list case\n if not all(isinstance(num, (int, float)) for num in numbers):\n raise ValueError(\"List must contain only numbers.\")\n\n smallest = numbers[0] # Initialize with the first element\n for num in numbers:\n if num < smallest:\n smallest = num\n return smallest", "matching_cluster_idx": -1}, {"solution": "def smallest_num(numbers):\n \"\"\"\n Finds the smallest number in a list.\n\n Args:\n numbers: A list of numbers.\n\n Returns:\n The smallest number in the list. Returns None if the list is empty.\n \"\"\"\n if not numbers:\n return None\n min_num = numbers[0]\n for num in numbers:\n if num < min_num:\n min_num = num\n return min_num", "matching_cluster_idx": 3}, {"solution": "def smallest_num(numbers):\n \"\"\"\n Finds the smallest number in a list.\n\n Args:\n numbers: A list of numbers.\n\n Returns:\n The smallest number in the list. Returns None if the list is empty.\n\n Raises:\n TypeError: if input is not a list.\n ValueError: if the list contains non-numeric values.\n\n \"\"\"\n if not isinstance(numbers, list):\n raise TypeError(\"Input must be a list.\")\n if not numbers:\n return None #Handle empty list case\n if not all(isinstance(num, (int, float)) for num in numbers):\n raise ValueError(\"List must contain only numbers.\")\n\n min_num = numbers[0] # Initialize with the first element\n for num in numbers:\n if num < min_num:\n min_num = num\n return min_num", "matching_cluster_idx": -1}, {"solution": "def smallest_num(numbers):\n \"\"\"\n Finds the smallest number in a list.\n\n Args:\n numbers: A list of numbers.\n\n Returns:\n The smallest number in the list. Returns None if the list is empty.\n \"\"\"\n if not numbers:\n return None\n min_num = numbers[0]\n for num in numbers:\n if num < min_num:\n min_num = num\n return min_num", "matching_cluster_idx": 3}, {"solution": "def smallest_num(numbers):\n \"\"\"\n Finds the smallest number in a list.\n\n Args:\n numbers: A list of numbers.\n\n Returns:\n The smallest number in the list. Returns None if the list is empty.\n \"\"\"\n if not numbers:\n return None\n min_num = numbers[0]\n for number in numbers:\n if number < min_num:\n min_num = number\n return min_num", "matching_cluster_idx": 3}, {"solution": "def smallest_num(numbers):\n \"\"\"\n Finds the smallest number in a list.\n\n Args:\n numbers: A list of numbers.\n\n Returns:\n The smallest number in the list. Returns None if the list is empty.\n\n Raises:\n TypeError: if input is not a list.\n ValueError: if the list contains non-numeric values.\n\n \"\"\"\n if not isinstance(numbers, list):\n raise TypeError(\"Input must be a list.\")\n if not numbers:\n return None #Handle empty list case\n if not all(isinstance(num, (int, float)) for num in numbers):\n raise ValueError(\"List must contain only numbers.\")\n\n smallest = numbers[0]\n for num in numbers:\n if num < smallest:\n smallest = num\n return smallest", "matching_cluster_idx": -1}, {"solution": "def smallest_num(numbers):\n \"\"\"\n Finds the smallest number in a list.\n\n Args:\n numbers: A list of numbers.\n\n Returns:\n The smallest number in the list. Returns None if the list is empty.\n \"\"\"\n if not numbers:\n return None\n min_num = numbers[0]\n for num in numbers:\n if num < min_num:\n min_num = num\n return min_num", "matching_cluster_idx": 3}, {"solution": "def smallest_num(numbers):\n \"\"\"\n Finds the smallest number in a list.\n\n Args:\n numbers: A list of numbers.\n\n Returns:\n The smallest number in the list. Returns None if the list is empty.\n \"\"\"\n if not numbers:\n return None\n min_num = numbers[0]\n for num in numbers:\n if num < min_num:\n min_num = num\n return min_num", "matching_cluster_idx": 3}, {"solution": "def smallest_num(numbers):\n \"\"\"\n Finds the smallest number in a list.\n\n Args:\n numbers: A list of numbers.\n\n Returns:\n The smallest number in the list. Returns None if the list is empty.\n \"\"\"\n if not numbers:\n return None\n smallest = numbers[0]\n for number in numbers:\n if number < smallest:\n smallest = number\n return smallest", "matching_cluster_idx": 3}, {"solution": "def smallest_num(numbers):\n \"\"\"\n Finds the smallest number in a list.\n\n Args:\n numbers: A list of numbers.\n\n Returns:\n The smallest number in the list. Returns None if the list is empty.\n \"\"\"\n if not numbers:\n return None\n min_num = numbers[0]\n for num in numbers:\n if num < min_num:\n min_num = num\n return min_num", "matching_cluster_idx": 3}, {"solution": "def smallest_num(numbers):\n \"\"\"\n Finds the smallest number in a list.\n\n Args:\n numbers: A list of numbers.\n\n Returns:\n The smallest number in the list. Returns None if the list is empty.\n \"\"\"\n if not numbers:\n return None\n smallest = numbers[0]\n for number in numbers:\n if number < smallest:\n smallest = number\n return smallest", "matching_cluster_idx": 3}, {"solution": "def smallest_num(numbers):\n \"\"\"\n Finds the smallest number in a list.\n\n Args:\n numbers: A list of numbers.\n\n Returns:\n The smallest number in the list. Returns None if the list is empty.\n\n Raises:\n TypeError: if input is not a list.\n ValueError: if the list contains non-numeric values.\n\n \"\"\"\n if not isinstance(numbers, list):\n raise TypeError(\"Input must be a list.\")\n if not numbers:\n return None\n if not all(isinstance(num, (int, float)) for num in numbers):\n raise ValueError(\"List must contain only numbers.\")\n return min(numbers)", "matching_cluster_idx": 0}, {"solution": "def smallest_num(numbers):\n \"\"\"\n Finds the smallest number in a list.\n\n Args:\n numbers: A list of numbers.\n\n Returns:\n The smallest number in the list. Returns None if the list is empty.\n\n \"\"\"\n if not numbers:\n return None\n smallest = numbers[0]\n for number in numbers:\n if number < smallest:\n smallest = number\n return smallest", "matching_cluster_idx": 3}, {"solution": "def smallest_num(numbers):\n \"\"\"\n Finds the smallest number in a list.\n\n Args:\n numbers: A list of numbers.\n\n Returns:\n The smallest number in the list. Returns None if the list is empty.\n \"\"\"\n if not numbers:\n return None\n smallest = numbers[0]\n for number in numbers:\n if number < smallest:\n smallest = number\n return smallest", "matching_cluster_idx": 3}, {"solution": "def smallest_num(numbers):\n \"\"\"\n Finds the smallest number in a list.\n\n Args:\n numbers: A list of numbers.\n\n Returns:\n The smallest number in the list. Returns None if the list is empty.\n\n Raises:\n TypeError: if input is not a list.\n ValueError: if the list contains non-numeric values.\n\n \"\"\"\n if not isinstance(numbers, list):\n raise TypeError(\"Input must be a list.\")\n if not numbers:\n return None #Handle empty list case\n if not all(isinstance(num, (int, float)) for num in numbers):\n raise ValueError(\"List must contain only numbers.\")\n\n min_num = numbers[0] # Initialize with the first element\n for num in numbers:\n if num < min_num:\n min_num = num\n return min_num", "matching_cluster_idx": -1}, {"solution": "def smallest_num(numbers):\n \"\"\"\n Finds the smallest number in a list.\n\n Args:\n numbers: A list of numbers.\n\n Returns:\n The smallest number in the list. Returns None if the list is empty.\n \"\"\"\n if not numbers:\n return None\n min_num = numbers[0]\n for num in numbers:\n if num < min_num:\n min_num = num\n return min_num", "matching_cluster_idx": 3}, {"solution": "def smallest_num(numbers):\n \"\"\"\n Finds the smallest number in a list.\n\n Args:\n numbers: A list of numbers.\n\n Returns:\n The smallest number in the list. Returns None if the list is empty.\n \"\"\"\n if not numbers:\n return None\n min_num = numbers[0]\n for num in numbers:\n if num < min_num:\n min_num = num\n return min_num", "matching_cluster_idx": 3}]}, "Mbpp/75": {"dps": 94.28571428571429, "dps_norm": 73.33333333333334, "pass@1": 100.0, "profiled": [{"solution": "def find_tuples(list_of_tuples, k):\n \"\"\"\n Finds tuples in a list where all elements are divisible by k.\n\n Args:\n list_of_tuples: A list of tuples.\n k: The divisor.\n\n Returns:\n A list of tuples where all elements are divisible by k. Returns an empty list if no such tuples exist.\n \"\"\"\n result = []\n for tup in list_of_tuples:\n all_divisible = True\n for num in tup:\n if num % k != 0:\n all_divisible = False\n break\n if all_divisible:\n result.append(tup)\n return result", "matching_cluster_idx": 8}, {"solution": "def find_tuples(list_of_tuples, k):\n \"\"\"\n Finds tuples where all elements are divisible by k.\n\n Args:\n list_of_tuples: A list of tuples.\n k: The divisor.\n\n Returns:\n A list of tuples where all elements are divisible by k. Returns an empty list if no such tuples are found.\n \"\"\"\n result = []\n for tup in list_of_tuples:\n all_divisible = all(x % k == 0 for x in tup)\n if all_divisible:\n result.append(tup)\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(list_of_tuples, k):\n \"\"\"\n Finds tuples where all elements are divisible by k.\n\n Args:\n list_of_tuples: A list of tuples.\n k: The divisor.\n\n Returns:\n A list of tuples where all elements are divisible by k. Returns an empty list if no such tuples exist.\n \"\"\"\n result = []\n for tup in list_of_tuples:\n all_divisible = all(x % k == 0 for x in tup)\n if all_divisible:\n result.append(tup)\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuple_list, k):\n \"\"\"\n Finds tuples in a list where all elements are divisible by k.\n\n Args:\n tuple_list: A list of tuples.\n k: The divisor.\n\n Returns:\n A list of tuples where all elements are divisible by k. Returns an empty list if no such tuples exist.\n \"\"\"\n result = []\n for tup in tuple_list:\n all_divisible = True\n for num in tup:\n if num % k != 0:\n all_divisible = False\n break\n if all_divisible:\n result.append(tup)\n return result\ntuple_list = [(6, 24, 12), (7, 9, 6), (12, 18, 21)]\nk = 6\nresult = find_tuples(tuple_list, k)", "matching_cluster_idx": 8}, {"solution": "def find_tuples(list_of_tuples, k):\n \"\"\"\n Finds tuples where all elements are divisible by k.\n\n Args:\n list_of_tuples: A list of tuples of integers.\n k: The divisor.\n\n Returns:\n A list of tuples where all elements are divisible by k. Returns an empty list if no such tuples exist.\n\n \"\"\"\n result = []\n for tup in list_of_tuples:\n all_divisible = True\n for num in tup:\n if num % k != 0:\n all_divisible = False\n break\n if all_divisible:\n result.append(tup)\n return result", "matching_cluster_idx": 8}, {"solution": "def find_tuples(tuple_list, k):\n \"\"\"\n Finds tuples in a list where all elements are divisible by k.\n\n Args:\n tuple_list: A list of tuples.\n k: The divisor.\n\n Returns:\n A list of tuples where all elements are divisible by k. Returns an empty list if no such tuples exist.\n \"\"\"\n result = []\n for tup in tuple_list:\n all_divisible = all(x % k == 0 for x in tup)\n if all_divisible:\n result.append(tup)\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(list_of_tuples, k):\n \"\"\"\n Finds tuples which have all elements divisible by k from the given list of tuples.\n\n Args:\n list_of_tuples: A list of tuples.\n k: An integer.\n\n Returns:\n A list of tuples where all elements in each tuple are divisible by k. Returns an empty list if no such tuples exist.\n \"\"\"\n result = []\n for tup in list_of_tuples:\n all_divisible = all(x % k == 0 for x in tup)\n if all_divisible:\n result.append(tup)\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(list_of_tuples, k):\n \"\"\"\n Finds tuples in a list where all elements are divisible by k.\n\n Args:\n list_of_tuples: A list of tuples.\n k: The divisor.\n\n Returns:\n A list containing tuples where all elements are divisible by k. Returns an empty list if no such tuples exist.\n \"\"\"\n result = []\n for tup in list_of_tuples:\n all_divisible = all(x % k == 0 for x in tup)\n if all_divisible:\n result.append(tup)\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(list_of_tuples, k):\n \"\"\"\n Finds tuples in a list where all elements are divisible by k.\n\n Args:\n list_of_tuples: A list of tuples.\n k: The divisor.\n\n Returns:\n A list containing only the tuples where all elements are divisible by k. Returns an empty list if no such tuples exist.\n \"\"\"\n result = []\n for tup in list_of_tuples:\n all_divisible = all(x % k == 0 for x in tup)\n if all_divisible:\n result.append(tup)\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(list_of_tuples, k):\n \"\"\"\n Finds tuples where all elements are divisible by k.\n\n Args:\n list_of_tuples: A list of tuples.\n k: The divisor.\n\n Returns:\n A list of tuples where all elements are divisible by k. Returns an empty list if no such tuples exist.\n \"\"\"\n result = []\n for tup in list_of_tuples:\n all_divisible = all(x % k == 0 for x in tup)\n if all_divisible:\n result.append(tup)\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(list_of_tuples, k):\n \"\"\"\n Finds tuples where all elements are divisible by k.\n\n Args:\n list_of_tuples: A list of tuples.\n k: The divisor.\n\n Returns:\n A list of tuples where all elements are divisible by k. Returns an empty list if no such tuples exist.\n \"\"\"\n result = []\n for tup in list_of_tuples:\n all_divisible = all(x % k == 0 for x in tup)\n if all_divisible:\n result.append(tup)\n return result\nlist_of_tuples = [(6, 24, 12), (7, 9, 6), (12, 18, 21)]\nk = 6\nresult = find_tuples(list_of_tuples, k)", "matching_cluster_idx": 5}, {"solution": "def find_tuples(list_of_tuples, k):\n \"\"\"\n Finds tuples where all elements are divisible by k.\n\n Args:\n list_of_tuples: A list of tuples.\n k: The divisor.\n\n Returns:\n A list of tuples where all elements are divisible by k. Returns an empty list if no such tuples exist.\n \"\"\"\n result = []\n for tup in list_of_tuples:\n all_divisible = all(x % k == 0 for x in tup)\n if all_divisible:\n result.append(tup)\n return result\nlist_of_tuples = [(6, 24, 12), (7, 9, 6), (12, 18, 21)]\nk = 6\nresult = find_tuples(list_of_tuples,k)", "matching_cluster_idx": 5}, {"solution": "def find_tuples(list_of_tuples, k):\n \"\"\"\n Finds tuples where all elements are divisible by k.\n\n Args:\n list_of_tuples: A list of tuples of integers.\n k: An integer divisor.\n\n Returns:\n A list containing only the tuples from list_of_tuples where all elements \n are divisible by k. Returns an empty list if no such tuples exist.\n \"\"\"\n result = []\n for tup in list_of_tuples:\n all_divisible = all(x % k == 0 for x in tup)\n if all_divisible:\n result.append(tup)\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(list_of_tuples, k):\n \"\"\"\n Finds tuples in a list where all elements are divisible by k.\n\n Args:\n list_of_tuples: A list of tuples.\n k: The divisor.\n\n Returns:\n A list containing only the tuples where all elements are divisible by k. Returns an empty list if no such tuples exist.\n \"\"\"\n result = []\n for tup in list_of_tuples:\n all_divisible = all(x % k == 0 for x in tup)\n if all_divisible:\n result.append(tup)\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(list_of_tuples, k):\n \"\"\"\n Finds tuples where all elements are divisible by k.\n\n Args:\n list_of_tuples: A list of tuples.\n k: The divisor.\n\n Returns:\n A list of tuples where all elements are divisible by k. Returns an empty list if no such tuples exist.\n \"\"\"\n result = []\n for tup in list_of_tuples:\n all_divisible = True\n for num in tup:\n if num % k != 0:\n all_divisible = False\n break\n if all_divisible:\n result.append(tup)\n return result\nlist_of_tuples = [(6, 24, 12), (7, 9, 6), (12, 18, 21)]\nk = 6\nresult = find_tuples(list_of_tuples, k)", "matching_cluster_idx": 8}, {"solution": "def find_tuples(list_of_tuples, k):\n \"\"\"\n Finds tuples where all elements are divisible by k.\n\n Args:\n list_of_tuples: A list of tuples.\n k: The divisor.\n\n Returns:\n A list of tuples where all elements are divisible by k. Returns an empty list if no such tuples exist.\n \"\"\"\n result = []\n for tup in list_of_tuples:\n all_divisible = all(x % k == 0 for x in tup)\n if all_divisible:\n result.append(tup)\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(list_of_tuples, k):\n \"\"\"\n Finds tuples in a list where all elements are divisible by k.\n\n Args:\n list_of_tuples: A list of tuples.\n k: The divisor.\n\n Returns:\n A list of tuples where all elements are divisible by k. Returns an empty list if no such tuples exist.\n \"\"\"\n result = []\n for tup in list_of_tuples:\n all_divisible = all(x % k == 0 for x in tup)\n if all_divisible:\n result.append(tup)\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(list_of_tuples, k):\n \"\"\"\n Finds tuples which have all elements divisible by k from the given list of tuples.\n\n Args:\n list_of_tuples: A list of tuples.\n k: An integer.\n\n Returns:\n A list of tuples that satisfy the condition. Returns an empty list if no tuples satisfy the condition.\n \"\"\"\n result = []\n for tup in list_of_tuples:\n all_divisible = all(x % k == 0 for x in tup)\n if all_divisible:\n result.append(tup)\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(list_of_tuples, k):\n \"\"\"\n Finds tuples where all elements are divisible by k.\n\n Args:\n list_of_tuples: A list of tuples.\n k: The divisor.\n\n Returns:\n A list of tuples where all elements are divisible by k. Returns an empty list if no such tuples exist.\n \"\"\"\n result = []\n for tup in list_of_tuples:\n all_divisible = all(x % k == 0 for x in tup)\n if all_divisible:\n result.append(tup)\n return result\nlist_of_tuples = [(6, 24, 12), (7, 9, 6), (12, 18, 21)]\nk = 6\nresult = find_tuples(list_of_tuples, k)", "matching_cluster_idx": 5}, {"solution": "def find_tuples(list_of_tuples, k):\n \"\"\"\n Finds tuples where all elements are divisible by k.\n\n Args:\n list_of_tuples: A list of tuples.\n k: The divisor.\n\n Returns:\n A list of tuples where all elements are divisible by k. Returns an empty list if no such tuples exist.\n \"\"\"\n result = []\n for tup in list_of_tuples:\n all_divisible = all(x % k == 0 for x in tup)\n if all_divisible:\n result.append(tup)\n return result", "matching_cluster_idx": 5}]}, "Mbpp/88": {"dps": 91.7156862745098, "dps_norm": 92.85714285714286, "pass@1": 100.0, "profiled": [{"solution": "from collections import Counter\ndef freq_count(input_list):\n \"\"\"\n Calculates the frequency of elements in a list.\n\n Args:\n input_list: A list of elements.\n\n Returns:\n A dictionary where keys are the elements and values are their frequencies.\n \"\"\"\n return dict(Counter(input_list))", "matching_cluster_idx": 6}, {"solution": "from collections import Counter\ndef freq_count(input_list):\n \"\"\"\n Calculates the frequency of elements in a list.\n\n Args:\n input_list: A list of elements.\n\n Returns:\n A dictionary where keys are elements from the input list and values are their frequencies.\n Returns an empty dictionary if the input list is empty.\n\n \"\"\"\n if not input_list:\n return {}\n \n return dict(Counter(input_list))", "matching_cluster_idx": 6}, {"solution": "from collections import Counter\ndef freq_count(input_list):\n \"\"\"\n Calculates the frequency of each element in a list.\n\n Args:\n input_list: A list of elements.\n\n Returns:\n A dictionary where keys are the unique elements from the input list and \n values are their corresponding frequencies. Returns an empty dictionary if the input is empty.\n \"\"\"\n if not input_list:\n return {}\n return dict(Counter(input_list))", "matching_cluster_idx": 6}, {"solution": "from collections import Counter\ndef freq_count(list_):\n \"\"\"\n Counts the frequency of elements in a list.\n\n Args:\n list_: The input list.\n\n Returns:\n A dictionary where keys are elements from the list and values are their frequencies.\n \"\"\"\n return dict(Counter(list_))", "matching_cluster_idx": 6}, {"solution": "def freq_count(lst):\n \"\"\"\n Write a function to get the frequency of all the elements in a list, returned as a dictionary.\n assert freq_count([10,10,10,10,20,20,20,20,40,40,50,50,30])==({10: 4, 20: 4, 40: 2, 50: 2, 30: 1})\n \"\"\"\n freq = {}\n for item in lst:\n if item in freq:\n freq[item] += 1\n else:\n freq[item] = 1\n return freq", "matching_cluster_idx": 5}, {"solution": "def freq_count(input_list):\n \"\"\"\n Calculates the frequency of each element in a list.\n\n Args:\n input_list: A list of elements.\n\n Returns:\n A dictionary where keys are elements from the input list and values are their frequencies.\n \"\"\"\n\n frequency = {}\n for item in input_list:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n return frequency", "matching_cluster_idx": 5}, {"solution": "from collections import Counter\ndef freq_count(input_list):\n \"\"\"\n Calculates the frequency of each element in a list.\n\n Args:\n input_list: A list of elements.\n\n Returns:\n A dictionary where keys are the unique elements from the input list and \n values are their corresponding frequencies. Returns an empty dictionary if the input is None or empty.\n \"\"\"\n if not input_list:\n return {}\n return dict(Counter(input_list))", "matching_cluster_idx": 6}, {"solution": "from collections import Counter\ndef freq_count(list_):\n \"\"\"\n This function takes a list as input and returns a dictionary containing the frequency of each element in the list.\n \"\"\"\n return dict(Counter(list_))\nlist_ = [10,10,10,10,20,20,20,20,40,40,50,50,30]", "matching_cluster_idx": 6}, {"solution": "from collections import Counter\ndef freq_count(input_list):\n \"\"\"\n Calculates the frequency of elements in a list.\n\n Args:\n input_list: A list of elements.\n\n Returns:\n A dictionary where keys are elements from the input list and values are their frequencies. Returns an empty dictionary if the input is not a list or the list is empty.\n \"\"\"\n if not isinstance(input_list, list):\n return {}\n if not input_list:\n return {}\n return dict(Counter(input_list))", "matching_cluster_idx": 6}, {"solution": "from collections import Counter\ndef freq_count(input_list):\n \"\"\"\n Calculates the frequency of each element in a list.\n\n Args:\n input_list: A list of elements.\n\n Returns:\n A dictionary where keys are the unique elements from the list and \n values are their corresponding frequencies. Returns an empty \n dictionary if the input list is empty.\n \"\"\"\n if not input_list:\n return {}\n return dict(Counter(input_list))", "matching_cluster_idx": 6}, {"solution": "from collections import Counter\ndef freq_count(input_list):\n \"\"\"\n Calculates the frequency of each element in a list.\n\n Args:\n input_list: A list of elements.\n\n Returns:\n A dictionary where keys are the elements from the input list and values are their frequencies.\n \"\"\"\n return dict(Counter(input_list))", "matching_cluster_idx": 6}, {"solution": "from collections import Counter\ndef freq_count(input_list):\n \"\"\"\n Calculates the frequency of each element in a list.\n\n Args:\n input_list: A list of elements.\n\n Returns:\n A dictionary where keys are the unique elements from the input list and \n values are their corresponding frequencies. Returns an empty dictionary if the input is empty or None.\n \"\"\"\n if not input_list:\n return {}\n return dict(Counter(input_list))", "matching_cluster_idx": 6}, {"solution": "from collections import defaultdict\ndef freq_count(input_list):\n \"\"\"\n Calculates the frequency of each element in a list.\n\n Args:\n input_list: A list of elements.\n\n Returns:\n A dictionary where keys are the unique elements from the input list and values are their frequencies.\n \"\"\"\n freq_dict = defaultdict(int) #Use defaultdict to avoid KeyError if a new element is encountered\n for item in input_list:\n freq_dict[item] += 1\n return dict(freq_dict) #Convert back to a regular dict for assertion purposes.", "matching_cluster_idx": 3}, {"solution": "from collections import Counter\ndef freq_count(input_list):\n \"\"\"\n Calculates the frequency of each element in a list.\n\n Args:\n input_list: A list of elements.\n\n Returns:\n A dictionary where keys are the elements from the input list and values are their frequencies. Returns an empty dictionary if the input list is empty.\n \"\"\"\n if not input_list:\n return {}\n return dict(Counter(input_list))", "matching_cluster_idx": 6}, {"solution": "def freq_count(data):\n \"\"\"\n Counts the frequency of elements in a list.\n\n Args:\n data: A list of elements.\n\n Returns:\n A dictionary where keys are elements from the list and values are their frequencies.\n \"\"\"\n freq = {}\n for item in data:\n if item in freq:\n freq[item] += 1\n else:\n freq[item] = 1\n return freq", "matching_cluster_idx": 5}, {"solution": "def freq_count(data):\n \"\"\"\n Counts the frequency of elements in a list.\n\n Args:\n data: A list of elements.\n\n Returns:\n A dictionary where keys are elements from the list and values are their frequencies.\n \"\"\"\n freq = {}\n for item in data:\n if item in freq:\n freq[item] += 1\n else:\n freq[item] = 1\n return freq", "matching_cluster_idx": 5}, {"solution": "from collections import Counter\ndef freq_count(input_list):\n \"\"\"\n Calculates the frequency of elements in a list.\n\n Args:\n input_list: A list of elements.\n\n Returns:\n A dictionary where keys are elements from the list and values are their frequencies.\n \"\"\"\n return dict(Counter(input_list))", "matching_cluster_idx": 6}, {"solution": "from collections import defaultdict\ndef freq_count(input_list):\n \"\"\"\n Calculates the frequency of each element in a list.\n\n Args:\n input_list: A list of elements.\n\n Returns:\n A dictionary where keys are elements from the input list and values are their frequencies.\n \"\"\"\n freq_dict = defaultdict(int) # Use defaultdict for easier counting\n for item in input_list:\n freq_dict[item] += 1\n return dict(freq_dict) # Convert back to a regular dictionary if needed", "matching_cluster_idx": 3}, {"solution": "from collections import Counter\ndef freq_count(input_list):\n \"\"\"\n Counts the frequency of elements in a list.\n\n Args:\n input_list: A list of elements.\n\n Returns:\n A dictionary where keys are elements from the list and values are their frequencies.\n \"\"\"\n return dict(Counter(input_list))", "matching_cluster_idx": 6}, {"solution": "from collections import Counter\ndef freq_count(input_list):\n \"\"\"\n Calculates the frequency of each element in a list.\n\n Args:\n input_list: A list of elements.\n\n Returns:\n A dictionary where keys are the elements from the input list and values are their frequencies. Returns an empty dictionary if the input list is empty.\n \"\"\"\n if not input_list:\n return {}\n return dict(Counter(input_list))\ninput_list = [10,10,10,10,20,20,20,20,40,40,50,50,30]", "matching_cluster_idx": 6}]}, "Mbpp/90": {"dps": 75.63414634146342, "dps_norm": 83.57142857142857, "pass@1": 100.0, "profiled": [{"solution": "def len_log(words):\n \"\"\"\n Finds the length of the longest word in a list of strings.\n\n Args:\n words: A list of strings.\n\n Returns:\n The length of the longest word in the list. Returns 0 if the list is empty.\n \"\"\"\n if not words:\n return 0\n return max(len(word) for word in words)", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n \"\"\"\n Finds the length of the longest word in a list of words.\n\n Args:\n words: A list of strings.\n\n Returns:\n The length of the longest word in the list. Returns 0 if the list is empty.\n \"\"\"\n if not words:\n return 0\n return max(len(word) for word in words)\nwords = [\"python\",\"PHP\",\"bigdata\"]", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n \"\"\"\n Finds the length of the longest word in a list of words.\n\n Args:\n words: A list of strings.\n\n Returns:\n The length of the longest word in the list. Returns 0 if the list is empty.\n \"\"\"\n if not words:\n return 0\n return max(len(word) for word in words)", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n \"\"\"\n Finds the length of the longest word in a list of words.\n\n Args:\n words: A list of strings.\n\n Returns:\n The length of the longest word in the list. Returns 0 if the list is empty.\n \"\"\"\n if not words:\n return 0\n max_length = 0\n for word in words:\n if len(word) > max_length:\n max_length = len(word)\n return max_length", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n \"\"\"\n Finds the length of the longest word in a list of words.\n\n Args:\n words: A list of strings.\n\n Returns:\n The length of the longest word in the list. Returns 0 if the list is empty.\n \"\"\"\n if not words:\n return 0\n return max(len(word) for word in words)", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n \"\"\"\n Finds the length of the longest word in a list of words.\n\n Args:\n words: A list of strings.\n\n Returns:\n The length of the longest word in the list. Returns 0 if the list is empty.\n \"\"\"\n if not words:\n return 0\n return max(len(word) for word in words)", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n \"\"\"\n Finds the length of the longest word in a list of words.\n\n Args:\n words: A list of strings.\n\n Returns:\n The length of the longest word in the list. Returns 0 if the list is empty.\n \"\"\"\n if not words:\n return 0\n return max(len(word) for word in words)", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n \"\"\"\n Finds the length of the longest word in a list of words.\n\n Args:\n words: A list of strings.\n\n Returns:\n The length of the longest word in the list. Returns 0 if the list is empty.\n \"\"\"\n if not words:\n return 0\n return max(len(word) for word in words)", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n \"\"\"\n Finds the length of the longest word in a list of words.\n\n Args:\n words: A list of strings.\n\n Returns:\n The length of the longest word in the list. Returns 0 if the list is empty.\n \"\"\"\n if not words:\n return 0\n return max(len(word) for word in words)", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n \"\"\"\n Finds the length of the longest word in a list of words.\n\n Args:\n words: A list of strings.\n\n Returns:\n The length of the longest word in the list. Returns 0 if the list is empty.\n \"\"\"\n if not words:\n return 0\n return max(len(word) for word in words)", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n \"\"\"\n Finds the length of the longest word in a list of words.\n\n Args:\n words: A list of strings.\n\n Returns:\n The length of the longest word in the list. Returns 0 if the list is empty.\n \"\"\"\n if not words:\n return 0\n return max(len(word) for word in words)", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n \"\"\"\n Finds the length of the longest word in a list of words.\n\n Args:\n words: A list of strings.\n\n Returns:\n The length of the longest word in the list. Returns 0 if the list is empty.\n \"\"\"\n if not words:\n return 0\n return max(len(word) for word in words)", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n \"\"\"\n Finds the length of the longest word in a list of words.\n\n Args:\n words: A list of strings.\n\n Returns:\n The length of the longest word in the list. Returns 0 if the list is empty.\n \"\"\"\n if not words:\n return 0\n return max(len(word) for word in words)", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n \"\"\"\n Write a python function to find the length of the longest word.\n assert len_log([\"python\",\"PHP\",\"bigdata\"]) == 7\n \"\"\"\n if not words: # Handle empty list case\n return 0\n max_length = 0\n for word in words:\n if len(word) > max_length:\n max_length = len(word)\n return max_length", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n \"\"\"\n Finds the length of the longest word in a list of strings.\n\n Args:\n words: A list of strings.\n\n Returns:\n The length of the longest word in the list. Returns 0 if the list is empty.\n \"\"\"\n if not words:\n return 0\n return max(len(word) for word in words)", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n \"\"\"\n Finds the length of the longest word in a list of words.\n\n Args:\n words: A list of strings.\n\n Returns:\n The length of the longest word in the list. Returns 0 if the list is empty.\n \"\"\"\n if not words:\n return 0\n return max(len(word) for word in words)", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n \"\"\"\n Write a python function to find the length of the longest word.\n assert len_log([\"python\",\"PHP\",\"bigdata\"]) == 7\n \"\"\"\n if not words: # Handle empty list case\n return 0\n \n max_length = 0\n for word in words:\n max_length = max(max_length, len(word))\n return max_length", "matching_cluster_idx": 2}, {"solution": "def len_log(words):\n \"\"\"\n Finds the length of the longest word in a list of words.\n\n Args:\n words: A list of strings.\n\n Returns:\n The length of the longest word in the list. Returns 0 if the list is empty.\n \"\"\"\n if not words:\n return 0\n return max(len(word) for word in words)", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n \"\"\"\n Finds the length of the longest word in a list of strings.\n\n Args:\n words: A list of strings.\n\n Returns:\n The length of the longest word in the list. Returns 0 if the list is empty.\n \"\"\"\n if not words:\n return 0\n return max(len(word) for word in words)", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n \"\"\"\n Finds the length of the longest word in a list of words.\n\n Args:\n words: A list of strings.\n\n Returns:\n The length of the longest word in the list. Returns 0 if the list is empty.\n \"\"\"\n if not words:\n return 0\n return max(len(word) for word in words)", "matching_cluster_idx": 5}]}, "Mbpp/94": {"dps": 62.545731707317074, "dps_norm": 55.0, "pass@1": 84.0, "profiled": [{"solution": "def index_minimum(list_of_tuples):\n \"\"\"\n Finds the first value of the tuple with the smallest second value.\n\n Args:\n list_of_tuples: A list of tuples, where each tuple has at least two elements.\n\n Returns:\n The first element of the tuple with the smallest second element. Returns None if the list is empty.\n\n Raises:\n TypeError: if input is not a list.\n ValueError: if any tuple in the list does not have at least two elements, or if the second element is not comparable.\n\n \"\"\"\n if not isinstance(list_of_tuples, list):\n raise TypeError(\"Input must be a list of tuples.\")\n if not list_of_tuples:\n return None\n\n for tup in list_of_tuples:\n if not isinstance(tup, tuple) or len(tup) < 2:\n raise ValueError(\"All elements in the list must be tuples with at least two elements.\")\n try:\n float(tup[1]) #check if comparable, this handles int and floats.\n except ValueError:\n raise ValueError(\"The second element of each tuple must be comparable.\")\n\n\n min_tuple = min(list_of_tuples, key=lambda x: x[1])\n return min_tuple[0]", "matching_cluster_idx": 1}, {"solution": "def index_minimum(tuple_list):\n \"\"\"\n Finds the first value of the tuple with the smallest second value.\n\n Args:\n tuple_list: A list of tuples, where each tuple contains two elements.\n\n Returns:\n The first value of the tuple with the smallest second value. Returns None if the list is empty.\n \"\"\"\n if not tuple_list:\n return None\n\n min_tuple = min(tuple_list, key=lambda item: item[1])\n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(tuple_list):\n \"\"\"\n Finds the first value of the tuple with the smallest second value.\n\n Args:\n tuple_list: A list of tuples, where each tuple contains at least two elements.\n\n Returns:\n The first element of the tuple with the smallest second element. Returns None if the input list is empty.\n\n Raises:\n TypeError: if input is not a list.\n ValueError: if any tuple in the list does not have at least two elements, or if the second element is not comparable.\n\n \"\"\"\n if not isinstance(tuple_list, list):\n raise TypeError(\"Input must be a list of tuples.\")\n\n if not tuple_list:\n return None\n\n for tup in tuple_list:\n if not isinstance(tup, tuple) or len(tup) < 2:\n raise ValueError(\"Tuples must contain at least two elements.\")\n try:\n float(tup[1]) #check if second element can be compared\n except ValueError:\n raise ValueError(\"Second element of each tuple must be comparable\")\n\n\n\n min_second_value = min(tuple_list, key=lambda x: x[1])[1]\n for tup in tuple_list:\n if tup[1] == min_second_value:\n return tup[0]", "matching_cluster_idx": 0}, {"solution": "def index_minimum(tuple_list):\n \"\"\"\n Finds the first value of the tuple with the smallest second value in a list of tuples.\n\n Args:\n tuple_list: A list of tuples, where each tuple contains two elements (string, integer).\n\n Returns:\n The first element (string) of the tuple with the smallest second element (integer).\n Returns None if the input list is empty or contains tuples with non-integer second elements.\n\n \"\"\"\n if not tuple_list:\n return None\n\n #Error handling for non-integer second elements\n if not all(isinstance(x[1], int) for x in tuple_list):\n return None\n\n\n min_tuple = min(tuple_list, key=lambda item: item[1])\n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(tuple_list):\n \"\"\"\n Finds the first value of the tuple with the smallest second value.\n\n Args:\n tuple_list: A list of tuples, where each tuple has at least two elements.\n\n Returns:\n The first element of the tuple with the smallest second element. Returns None if the list is empty.\n \"\"\"\n if not tuple_list:\n return None\n\n min_tuple = min(tuple_list, key=lambda x: x[1]) #Finds the tuple with the minimum second element\n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(list_of_tuples):\n \"\"\"\n Finds the first value of the tuple with the smallest second value.\n\n Args:\n list_of_tuples: A list of tuples, where each tuple has at least two elements.\n\n Returns:\n The first element of the tuple with the smallest second element. Returns None if the list is empty.\n\n Raises:\n TypeError: if input is not a list.\n ValueError: if any tuple in the list does not have at least two elements, or if the second element is not comparable.\n\n \"\"\"\n if not isinstance(list_of_tuples, list):\n raise TypeError(\"Input must be a list.\")\n if not list_of_tuples:\n return None\n\n for tup in list_of_tuples:\n if not isinstance(tup, tuple) or len(tup) < 2:\n raise ValueError(\"All elements in the list must be tuples with at least two elements.\")\n try:\n float(tup[1]) #check if second element is comparable, can be extended for other types\n except (ValueError, TypeError):\n raise ValueError(\"Second element of each tuple must be comparable.\")\n\n min_tuple = min(list_of_tuples, key=lambda x: x[1])\n return min_tuple[0]", "matching_cluster_idx": 1}, {"solution": "def index_minimum(list_of_tuples):\n \"\"\"\n Finds the first value of the tuple with the smallest second value.\n\n Args:\n list_of_tuples: A list of tuples, where each tuple has at least two elements.\n\n Returns:\n The first element of the tuple with the smallest second element. Returns None if the list is empty.\n\n Raises:\n TypeError: if input is not a list.\n ValueError: if tuples in list don't have at least two elements.\n \"\"\"\n if not isinstance(list_of_tuples, list):\n raise TypeError(\"Input must be a list of tuples.\")\n if not list_of_tuples: # Handle empty list case\n return None\n\n for tup in list_of_tuples:\n if len(tup) < 2:\n raise ValueError(\"Tuples must have at least two elements.\")\n\n #Find the minimum second value efficiently using min function and a key to specify the comparison element.\n min_tuple = min(list_of_tuples, key=lambda item: item[1])\n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(list_of_tuples):\n \"\"\"\n Finds the first value of the tuple with the smallest second value in a list of tuples.\n\n Args:\n list_of_tuples: A list of tuples, where each tuple contains two elements: a string and an integer.\n\n Returns:\n The string (first element) of the tuple with the smallest integer (second element). \n Returns None if the input list is empty.\n \"\"\"\n if not list_of_tuples:\n return None\n\n min_tuple = min(list_of_tuples, key=lambda x: x[1]) #Finds the tuple with the minimum second element.\n return min_tuple[0] # Returns the first element (string) of that tuple.", "matching_cluster_idx": 2}, {"solution": "def index_minimum(tuple_list):\n \"\"\"\n Finds the first value of the tuple with the smallest second value.\n\n Args:\n tuple_list: A list of tuples, where each tuple has at least two elements.\n\n Returns:\n The first value of the tuple with the smallest second value. Returns None if the list is empty.\n\n Raises:\n TypeError: if input is not a list.\n ValueError: if any tuple in the list does not have at least two elements, or if the second element is not comparable.\n\n \"\"\"\n if not isinstance(tuple_list, list):\n raise TypeError(\"Input must be a list of tuples.\")\n \n if not tuple_list:\n return None\n\n for tup in tuple_list:\n if len(tup) < 2:\n raise ValueError(\"All tuples must have at least two elements.\")\n if not isinstance(tup[1], (int, float)): #check for comparable second element. Could be extended.\n raise ValueError(\"Second element of tuples must be comparable (int or float).\")\n\n\n min_tuple = min(tuple_list, key=lambda item: item[1])\n return min_tuple[0]", "matching_cluster_idx": 1}, {"solution": "def index_minimum(tuple_list):\n \"\"\"\n Finds the first value of the tuple with the smallest second value.\n\n Args:\n tuple_list: A list of tuples, where each tuple contains two elements (a string and an integer).\n\n Returns:\n The first element (string) of the tuple with the smallest second element (integer). \n Returns None if the input list is empty.\n\n \"\"\"\n if not tuple_list:\n return None\n\n min_tuple = min(tuple_list, key=lambda x: x[1]) #Finds tuple with minimum second element\n return min_tuple[0] # returns the first element of that tuple", "matching_cluster_idx": 2}, {"solution": "def index_minimum(tuples_list):\n \"\"\"\n Given a list of tuples, returns the first value of the tuple with the smallest second value.\n\n Args:\n tuples_list: A list of tuples, where each tuple contains two elements (a string and an integer).\n\n Returns:\n The first element (string) of the tuple with the smallest second element (integer). Returns None if the list is empty.\n\n \"\"\"\n if not tuples_list:\n return None\n\n min_tuple = min(tuples_list, key=lambda item: item[1])\n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(list_of_tuples):\n \"\"\"\n Finds the first value of the tuple with the smallest second value in a list of tuples.\n\n Args:\n list_of_tuples: A list of tuples, where each tuple contains two elements: a string and an integer.\n\n Returns:\n The string (first element) of the tuple with the smallest integer (second element). Returns None if the list is empty.\n \"\"\"\n if not list_of_tuples:\n return None\n\n min_tuple = min(list_of_tuples, key=lambda item: item[1])\n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(list_of_tuples):\n \"\"\"\n Given a list of tuples, returns the first value of the tuple with the smallest second value.\n\n Args:\n list_of_tuples: A list of tuples, where each tuple contains two elements: a string and an integer.\n\n Returns:\n The string from the tuple with the smallest integer value. Returns None if the list is empty.\n \"\"\"\n if not list_of_tuples:\n return None\n\n min_tuple = min(list_of_tuples, key=lambda item: item[1])\n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(list_of_tuples):\n \"\"\"\n Finds the first value of the tuple with the smallest second value in a list of tuples.\n\n Args:\n list_of_tuples: A list of tuples, where each tuple has at least two elements.\n\n Returns:\n The first element of the tuple with the smallest second element. Returns None if the list is empty.\n\n Raises:\n TypeError: if input is not a list.\n ValueError: if any tuple in the list does not have at least two elements, or if the second element is not comparable.\n\n \"\"\"\n if not isinstance(list_of_tuples, list):\n raise TypeError(\"Input must be a list.\")\n if not list_of_tuples:\n return None\n\n for tup in list_of_tuples:\n if not isinstance(tup, tuple) or len(tup) < 2:\n raise ValueError(\"All elements in the list must be tuples with at least two elements.\")\n try:\n # Check if the second element is comparable. This will raise an error if it's not a number or comparable type.\n min(list_of_tuples, key=lambda x: x[1])[1]\n break\n except TypeError:\n raise ValueError(\"The second element of each tuple must be comparable.\")\n\n min_tuple = min(list_of_tuples, key=lambda x: x[1])\n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(list_of_tuples):\n \"\"\"\n Finds the first element of the tuple with the smallest second value.\n\n Args:\n list_of_tuples: A list of tuples, where each tuple has at least two elements.\n\n Returns:\n The first element of the tuple with the smallest second value. Returns None if the list is empty.\n \"\"\"\n if not list_of_tuples:\n return None\n\n min_tuple = min(list_of_tuples, key=lambda item: item[1])\n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(list_of_tuples):\n \"\"\"\n Finds the first element of the tuple with the smallest second value in a list of tuples.\n\n Args:\n list_of_tuples: A list of tuples, where each tuple contains at least two elements.\n\n Returns:\n The first element of the tuple with the smallest second value. Returns None if the list is empty.\n \"\"\"\n if not list_of_tuples:\n return None\n\n min_tuple = min(list_of_tuples, key=lambda x: x[1])\n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(tuple_list):\n \"\"\"\n Finds the first value of the tuple with the smallest second value.\n\n Args:\n tuple_list: A list of tuples, where each tuple has at least two elements.\n\n Returns:\n The first element of the tuple with the smallest second element. Returns None if the list is empty.\n \"\"\"\n if not tuple_list:\n return None\n\n min_tuple = min(tuple_list, key=lambda x: x[1])\n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(list_of_tuples):\n \"\"\"\n Finds the first value of the tuple with the smallest second value.\n\n Args:\n list_of_tuples: A list of tuples, where each tuple contains two elements.\n\n Returns:\n The first value of the tuple with the smallest second value. Returns None if the list is empty.\n \"\"\"\n if not list_of_tuples:\n return None\n\n min_tuple = min(list_of_tuples, key=lambda x: x[1])\n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(list_of_tuples):\n \"\"\"\n Finds the first value of the tuple with the smallest second value.\n\n Args:\n list_of_tuples: A list of tuples, where each tuple contains two elements (a string and an integer).\n\n Returns:\n The first element (string) of the tuple with the smallest second element (integer). Returns None if the list is empty.\n \"\"\"\n if not list_of_tuples:\n return None\n\n min_tuple = min(list_of_tuples, key=lambda x: x[1]) #Finds the tuple with the minimum second element.\n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(list_of_tuples):\n \"\"\"\n Finds the first value of the tuple with the smallest second value.\n\n Args:\n list_of_tuples: A list of tuples, where each tuple has at least two elements.\n\n Returns:\n The first element of the tuple with the smallest second element. Returns None if the input list is empty or contains invalid tuples.\n \"\"\"\n if not list_of_tuples:\n return None\n\n min_tuple = min(list_of_tuples, key=lambda x: x[1] if len(x) > 1 else float('inf')) #Handles tuples with less than 2 elements\n\n if len(min_tuple) < 1:\n return None\n\n return min_tuple[0]", "matching_cluster_idx": 2}]}, "Mbpp/96": {"dps": 66.24999999999999, "dps_norm": 67.14285714285714, "pass@1": 100.0, "profiled": [{"solution": "def divisor(n):\n \"\"\"\n Write a python function to find the number of divisors of a given integer.\n assert divisor(15) == 4\n \"\"\"\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def divisor(n):\n \"\"\"\n Finds the number of divisors of a given integer.\n\n Args:\n n: The integer.\n\n Returns:\n The number of divisors of n. Returns 0 if n is less than 1.\n \"\"\"\n if n < 1:\n return 0\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n if n / i == i:\n count += 1\n else:\n count += 2\n return count", "matching_cluster_idx": 6}, {"solution": "def divisor(n):\n \"\"\"\n Write a python function to find the number of divisors of a given integer.\n assert divisor(15) == 4\n \"\"\"\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def divisor(n):\n \"\"\"\n Finds the number of divisors of a given integer.\n\n Args:\n n: The integer.\n\n Returns:\n The number of divisors of n. Returns 0 if n is less than 1.\n \"\"\"\n if n < 1:\n return 0\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n if n / i == i:\n count += 1\n else:\n count += 2\n return count", "matching_cluster_idx": 6}, {"solution": "def divisor(n):\n \"\"\"\n Finds the number of divisors of a given integer.\n\n Args:\n n: The integer.\n\n Returns:\n The number of divisors of n. Returns 0 if n is not a positive integer.\n \"\"\"\n if not isinstance(n, int) or n <= 0:\n return 0\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n if n // i == i:\n count += 1\n else:\n count += 2\n return count", "matching_cluster_idx": 5}, {"solution": "def divisor(n):\n \"\"\"\n Finds the number of divisors of a given integer.\n\n Args:\n n: The integer for which to find the number of divisors.\n\n Returns:\n The number of divisors of n. Returns 0 if n is less than 1.\n \"\"\"\n if n < 1:\n return 0\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n if n / i == i:\n count += 1\n else:\n count += 2\n return count", "matching_cluster_idx": 5}, {"solution": "def divisor(n):\n \"\"\"\n Finds the number of divisors of a given integer.\n\n Args:\n n: The integer.\n\n Returns:\n The number of divisors of n. Returns 0 if n is less than 1.\n \"\"\"\n if n < 1:\n return 0\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n if n / i == i:\n count += 1\n else:\n count += 2\n return count", "matching_cluster_idx": 6}, {"solution": "def divisor(n):\n \"\"\"\n Finds the number of divisors of a given integer.\n\n Args:\n n: The input integer.\n\n Returns:\n The number of divisors of n. Returns 0 if n is less than 1.\n \"\"\"\n if n < 1:\n return 0\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n if n / i == i:\n count += 1\n else:\n count += 2\n return count", "matching_cluster_idx": 5}, {"solution": "def divisor(n):\n \"\"\"\n Finds the number of divisors of a given integer.\n\n Args:\n n: The integer.\n\n Returns:\n The number of divisors of n. Returns 0 if n is less than 1.\n\n \"\"\"\n if n < 1:\n return 0\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n if n / i == i:\n count += 1\n else:\n count += 2\n return count", "matching_cluster_idx": 5}, {"solution": "def divisor(n):\n \"\"\"\n Finds the number of divisors of a given integer.\n\n Args:\n n: The integer for which to find the number of divisors.\n\n Returns:\n The number of divisors of n. Returns 0 if n is less than 1.\n \"\"\"\n if n < 1:\n return 0\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def divisor(n):\n \"\"\"\n Finds the number of divisors of a given integer.\n\n Args:\n n: The integer.\n\n Returns:\n The number of divisors of n. Returns 0 if n is not a positive integer.\n \"\"\"\n if not isinstance(n, int) or n <= 0:\n return 0\n\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def divisor(n):\n \"\"\"\n Finds the number of divisors of a given integer.\n\n Args:\n n: The integer.\n\n Returns:\n The number of divisors of n. Returns 0 if n is less than 1.\n \"\"\"\n if n < 1:\n return 0\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n if n // i == i:\n count += 1\n else:\n count += 2\n return count", "matching_cluster_idx": 5}, {"solution": "def divisor(n):\n \"\"\"\n Finds the number of divisors of a given integer.\n\n Args:\n n: The input integer.\n\n Returns:\n The number of divisors of n. Returns 0 if n is less than 1.\n\n \"\"\"\n if n < 1:\n return 0\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n if n / i == i:\n count += 1\n else:\n count += 2\n return count", "matching_cluster_idx": 5}, {"solution": "def divisor(n):\n \"\"\"\n Finds the number of divisors of a given integer.\n\n Args:\n n: The integer.\n\n Returns:\n The number of divisors of n. Returns 0 if n is less than 1.\n \"\"\"\n if n < 1:\n return 0\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n if n // i == i:\n count += 1\n else:\n count += 2\n return count", "matching_cluster_idx": 5}, {"solution": "def divisor(n):\n \"\"\"\n Finds the number of divisors of a given integer.\n\n Args:\n n: The integer.\n\n Returns:\n The number of divisors of n. Returns 0 if n is less than 1.\n \"\"\"\n if n < 1:\n return 0\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n if n // i == i:\n count += 1\n else:\n count += 2\n return count", "matching_cluster_idx": 5}, {"solution": "def divisor(n):\n \"\"\"\n Finds the number of divisors of a given integer.\n\n Args:\n n: The integer.\n\n Returns:\n The number of divisors of n. Returns 0 if n is less than 1.\n \"\"\"\n if n < 1:\n return 0\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n \"\"\"\n Finds the number of divisors of a given integer.\n\n Args:\n n: The integer.\n\n Returns:\n The number of divisors of n. Returns 0 if n is less than 1.\n \"\"\"\n if n < 1:\n return 0\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n \"\"\"\n This function counts the number of divisors of a given integer n.\n\n Args:\n n: An integer.\n\n Returns:\n The number of divisors of n. Returns 0 if n is less than 1.\n \"\"\"\n if n < 1:\n return 0\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n if n / i == i:\n count += 1\n else:\n count += 2\n return count", "matching_cluster_idx": 5}, {"solution": "def divisor(n):\n \"\"\"\n Finds the number of divisors of a given integer.\n\n Args:\n n: The integer.\n\n Returns:\n The number of divisors of n. Returns 0 if n is less than 1.\n \"\"\"\n if n < 1:\n return 0\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n \"\"\"\n Write a python function to find the number of divisors of a given integer.\n assert divisor(15) == 4\n \"\"\"\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 1}]}, "Mbpp/97": {"dps": 95.33333333333333, "dps_norm": 86.875, "pass@1": 100.0, "profiled": [{"solution": "from collections import defaultdict\ndef frequency_lists(list_of_lists):\n \"\"\"\n Finds the frequency of each element in a flattened list of lists.\n\n Args:\n list_of_lists: A list of lists containing numerical elements.\n\n Returns:\n A dictionary where keys are the unique elements and values are their frequencies. Returns an empty dictionary if the input is invalid.\n \"\"\"\n if not isinstance(list_of_lists, list):\n return {}\n \n flattened_list = []\n for sublist in list_of_lists:\n if not isinstance(sublist, list):\n return {}\n for item in sublist:\n if not isinstance(item,(int,float)):\n return {}\n flattened_list.append(item)\n\n frequency = defaultdict(int)\n for item in flattened_list:\n frequency[item] += 1\n return dict(frequency)", "matching_cluster_idx": 5}, {"solution": "def frequency_lists(list_of_lists):\n \"\"\"\n Finds the frequency of each element in a flattened list of lists.\n\n Args:\n list_of_lists: A list of lists containing numbers.\n\n Returns:\n A dictionary where keys are the unique elements and values are their frequencies.\n \"\"\"\n\n flattened_list = []\n for sublist in list_of_lists:\n flattened_list.extend(sublist)\n\n frequency = {}\n for item in flattened_list:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n\n return frequency", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(list_of_lists):\n \"\"\"\n Finds the frequency of each element in a flattened list of lists.\n\n Args:\n list_of_lists: A list of lists containing numbers.\n\n Returns:\n A dictionary where keys are the unique elements and values are their frequencies.\n \"\"\"\n\n flattened_list = []\n for sublist in list_of_lists:\n flattened_list.extend(sublist)\n\n frequency_dict = {}\n for item in flattened_list:\n frequency_dict[item] = frequency_dict.get(item, 0) + 1\n\n return frequency_dict\nlist_of_lists = [[1, 2, 3, 2], [4, 5, 6, 2], [7, 8, 9, 5]]", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(list_of_lists):\n \"\"\"\n Calculates the frequency of each element in a flattened list of lists.\n\n Args:\n list_of_lists: A list of lists containing numbers.\n\n Returns:\n A dictionary where keys are the unique elements and values are their frequencies.\n \"\"\"\n\n flattened_list = []\n for sublist in list_of_lists:\n flattened_list.extend(sublist)\n\n frequency = {}\n for item in flattened_list:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n return frequency", "matching_cluster_idx": 6}, {"solution": "from collections import Counter\ndef frequency_lists(list_of_lists):\n \"\"\"\n Finds the frequency of each element in a flattened list of lists.\n\n Args:\n list_of_lists: A list of lists containing numbers.\n\n Returns:\n A dictionary where keys are the unique elements and values are their frequencies.\n \"\"\"\n\n flattened_list = [item for sublist in list_of_lists for item in sublist]\n frequency_dict = dict(Counter(flattened_list))\n return frequency_dict", "matching_cluster_idx": 6}, {"solution": "from collections import defaultdict\ndef frequency_lists(list_of_lists):\n \"\"\"\n Calculates the frequency of each element in a flattened list of lists.\n\n Args:\n list_of_lists: A list of lists containing numbers.\n\n Returns:\n A dictionary where keys are the unique elements and values are their frequencies. Returns an empty dictionary if the input is empty or None.\n \"\"\"\n if not list_of_lists:\n return {}\n\n flattened_list = [item for sublist in list_of_lists for item in sublist]\n frequency = defaultdict(int)\n for item in flattened_list:\n frequency[item] += 1\n return dict(frequency)", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(list_of_lists):\n \"\"\"\n Finds the frequency of each element in a flattened list of lists.\n\n Args:\n list_of_lists: A list of lists containing numbers.\n\n Returns:\n A dictionary where keys are the unique elements and values are their frequencies.\n \"\"\"\n\n flattened_list = []\n for sublist in list_of_lists:\n flattened_list.extend(sublist)\n\n frequency = {}\n for item in flattened_list:\n frequency[item] = frequency.get(item, 0) + 1\n\n return frequency", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(list_of_lists):\n \"\"\"\n Finds the frequency of each element in a flattened list of lists.\n\n Args:\n list_of_lists: A list of lists containing numbers.\n\n Returns:\n A dictionary where keys are the unique elements from the flattened list and values are their frequencies. Returns an empty dictionary if the input is empty or None.\n \"\"\"\n if not list_of_lists:\n return {}\n\n flattened_list = [item for sublist in list_of_lists for item in sublist]\n frequency = {}\n for item in flattened_list:\n frequency[item] = frequency.get(item, 0) + 1\n return frequency", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(list_of_lists):\n \"\"\"\n Write a function to find frequency of each element in a flattened list of lists, returned in a dictionary.\n assert frequency_lists([[1, 2, 3, 2], [4, 5, 6, 2], [7, 8, 9, 5]])=={1: 1, 2: 3, 3: 1, 4: 1, 5: 2, 6: 1, 7: 1, 8: 1, 9: 1}\n \"\"\"\n flattened_list = []\n for sublist in list_of_lists:\n flattened_list.extend(sublist)\n\n frequency = {}\n for item in flattened_list:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n return frequency\nlist_of_lists = [[1, 2, 3, 2], [4, 5, 6, 2], [7, 8, 9, 5]]", "matching_cluster_idx": 6}, {"solution": "from collections import defaultdict\ndef frequency_lists(list_of_lists):\n \"\"\"\n Finds the frequency of each element in a flattened list of lists.\n\n Args:\n list_of_lists: A list of lists containing numbers.\n\n Returns:\n A dictionary where keys are the unique elements and values are their frequencies.\n \"\"\"\n\n flattened_list = []\n for sublist in list_of_lists:\n flattened_list.extend(sublist)\n\n frequency = defaultdict(int)\n for item in flattened_list:\n frequency[item] += 1\n\n return dict(frequency)", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(list_of_lists):\n \"\"\"\n Finds the frequency of each element in a flattened list of lists.\n\n Args:\n list_of_lists: A list of lists containing numbers.\n\n Returns:\n A dictionary where keys are the unique elements and values are their frequencies.\n \"\"\"\n\n flattened_list = []\n for sublist in list_of_lists:\n flattened_list.extend(sublist)\n\n frequencies = {}\n for item in flattened_list:\n frequencies[item] = frequencies.get(item, 0) + 1\n\n return frequencies", "matching_cluster_idx": 6}, {"solution": "from collections import Counter\ndef frequency_lists(list_of_lists):\n \"\"\"\n Finds the frequency of each element in a flattened list of lists.\n\n Args:\n list_of_lists: A list of lists containing numerical elements.\n\n Returns:\n A dictionary where keys are the unique elements and values are their frequencies. Returns an empty dictionary if the input is empty or None.\n \"\"\"\n if not list_of_lists:\n return {}\n\n flattened_list = [item for sublist in list_of_lists for item in sublist]\n return dict(Counter(flattened_list))", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(list_of_lists):\n \"\"\"\n Write a function to find frequency of each element in a flattened list of lists, returned in a dictionary.\n assert frequency_lists([[1, 2, 3, 2], [4, 5, 6, 2], [7, 8, 9, 5]])=={1: 1, 2: 3, 3: 1, 4: 1, 5: 2, 6: 1, 7: 1, 8: 1, 9: 1}\n \"\"\"\n flattened_list = []\n for sublist in list_of_lists:\n flattened_list.extend(sublist)\n\n frequency = {}\n for item in flattened_list:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n return frequency\nlist_of_lists = [[1, 2, 3, 2], [4, 5, 6, 2], [7, 8, 9, 5]]", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(list_of_lists):\n \"\"\"\n Finds the frequency of each element in a flattened list of lists.\n\n Args:\n list_of_lists: A list of lists containing numbers.\n\n Returns:\n A dictionary where keys are the unique elements and values are their frequencies.\n \"\"\"\n\n flattened_list = []\n for inner_list in list_of_lists:\n flattened_list.extend(inner_list)\n\n frequency = {}\n for item in flattened_list:\n frequency[item] = frequency.get(item, 0) + 1\n\n return frequency", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(list_of_lists):\n \"\"\"\n Finds the frequency of each element in a flattened list of lists.\n\n Args:\n list_of_lists: A list of lists containing numbers.\n\n Returns:\n A dictionary where keys are the unique elements and values are their frequencies.\n \"\"\"\n\n flattened_list = []\n for sublist in list_of_lists:\n flattened_list.extend(sublist)\n\n frequency = {}\n for item in flattened_list:\n frequency[item] = frequency.get(item, 0) + 1\n\n return frequency", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(list_of_lists):\n \"\"\"\n Finds the frequency of each element in a flattened list of lists.\n\n Args:\n list_of_lists: A list of lists containing numbers.\n\n Returns:\n A dictionary where keys are the unique elements and values are their frequencies.\n \"\"\"\n\n flattened_list = []\n for sublist in list_of_lists:\n flattened_list.extend(sublist)\n\n frequency = {}\n for item in flattened_list:\n frequency[item] = frequency.get(item, 0) + 1\n\n return frequency", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(list_of_lists):\n \"\"\"\n Finds the frequency of each element in a flattened list of lists.\n\n Args:\n list_of_lists: A list of lists containing numbers.\n\n Returns:\n A dictionary where keys are the unique elements and values are their frequencies.\n \"\"\"\n\n flattened_list = []\n for sublist in list_of_lists:\n flattened_list.extend(sublist)\n\n frequency = {}\n for item in flattened_list:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n return frequency\nlist_of_lists = [[1, 2, 3, 2], [4, 5, 6, 2], [7, 8, 9, 5]]", "matching_cluster_idx": 6}, {"solution": "from collections import defaultdict\ndef frequency_lists(list_of_lists):\n \"\"\"\n Finds the frequency of each element in a flattened list of lists.\n\n Args:\n list_of_lists: A list of lists containing numbers.\n\n Returns:\n A dictionary where keys are the unique elements from the flattened list \n and values are their corresponding frequencies. Returns an empty \n dictionary if the input is empty or None.\n \"\"\"\n if not list_of_lists:\n return {}\n\n flattened_list = [item for sublist in list_of_lists for item in sublist]\n frequency = defaultdict(int)\n for item in flattened_list:\n frequency[item] += 1\n return dict(frequency)", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(list_of_lists):\n \"\"\"\n Finds the frequency of each element in a flattened list of lists.\n\n Args:\n list_of_lists: A list of lists containing numbers.\n\n Returns:\n A dictionary where keys are the unique elements and values are their frequencies.\n \"\"\"\n\n flattened_list = []\n for sublist in list_of_lists:\n flattened_list.extend(sublist)\n\n frequency = {}\n for item in flattened_list:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n return frequency", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(list_of_lists):\n \"\"\"\n Finds the frequency of each element in a flattened list of lists.\n\n Args:\n list_of_lists: A list of lists containing numbers.\n\n Returns:\n A dictionary where keys are the unique elements from the flattened list and values are their frequencies. Returns an empty dictionary if the input is empty or None.\n \"\"\"\n if not list_of_lists:\n return {}\n\n flattened_list = []\n for inner_list in list_of_lists:\n flattened_list.extend(inner_list)\n\n frequency = {}\n for item in flattened_list:\n frequency[item] = frequency.get(item, 0) + 1\n\n return frequency", "matching_cluster_idx": 6}]}, "Mbpp/106": {"dps": 54.70779220779221, "dps_norm": 87.5, "pass@1": 100.0, "profiled": [{"solution": "def add_lists(list_to_add, tuple_to_add_to):\n \"\"\"Appends a list to a tuple.\n\n Args:\n list_to_add: The list to be appended.\n tuple_to_add_to: The tuple to append to.\n\n Returns:\n A new tuple with the list appended to the original tuple. Returns None if input is invalid.\n \"\"\"\n if not isinstance(list_to_add, list) or not isinstance(tuple_to_add_to, tuple):\n return None\n\n return tuple_to_add_to + tuple(list_to_add)", "matching_cluster_idx": 4}, {"solution": "def add_lists(input_list, input_tuple):\n \"\"\"Appends a list to a tuple.\n\n Args:\n input_list: The list to append.\n input_tuple: The tuple to append to.\n\n Returns:\n A new tuple with the list appended to the original tuple. Returns None if \n input_tuple is not a tuple or input_list is not a list.\n \"\"\"\n if not isinstance(input_list, list) or not isinstance(input_tuple, tuple):\n return None\n return input_tuple + tuple(input_list)", "matching_cluster_idx": 4}, {"solution": "def add_lists(list_to_add, tuple_to_add_to):\n \"\"\"Appends a list to a tuple.\n\n Args:\n list_to_add: The list to append.\n tuple_to_add_to: The tuple to append to.\n\n Returns:\n A new tuple with the list appended to the original tuple. Returns None if input is invalid.\n \"\"\"\n if not isinstance(list_to_add, list) or not isinstance(tuple_to_add_to, tuple):\n return None\n\n return tuple_to_add_to + tuple(list_to_add)", "matching_cluster_idx": 4}, {"solution": "def add_lists(list_to_add, tuple_to_append):\n \"\"\"Appends a list to a tuple.\n\n Args:\n list_to_add: The list to append.\n tuple_to_append: The tuple to append to.\n\n Returns:\n A new tuple with the list appended to the original tuple. Returns None if input is invalid.\n \"\"\"\n if not isinstance(list_to_add, list) or not isinstance(tuple_to_append, tuple):\n return None\n\n return tuple_to_append + tuple(list_to_add)", "matching_cluster_idx": 4}, {"solution": "def add_lists(list_to_add, tuple_to_add_to):\n \"\"\"Appends a list to a tuple.\n\n Args:\n list_to_add: The list to append.\n tuple_to_add_to: The tuple to append to.\n\n Returns:\n A new tuple with the list appended to the original tuple. Returns None if input is invalid.\n \"\"\"\n if not isinstance(list_to_add, list) or not isinstance(tuple_to_add_to, tuple):\n return None\n return tuple_to_add_to + tuple(list_to_add)", "matching_cluster_idx": 4}, {"solution": "def add_lists(lst, tup):\n \"\"\"Appends a list to a tuple.\n\n Args:\n lst: The list to append.\n tup: The tuple to append to.\n\n Returns:\n A new tuple containing the elements of the original tuple followed by the elements of the list.\n \"\"\"\n return tup + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(input_list, input_tuple):\n \"\"\"\n Appends a list to a tuple.\n\n Args:\n input_list: The list to append.\n input_tuple: The tuple to append to.\n\n Returns:\n A new tuple with the list appended to the original tuple. Returns None if input is invalid.\n \"\"\"\n if not isinstance(input_list, list) or not isinstance(input_tuple, tuple):\n return None\n\n return input_tuple + tuple(input_list)", "matching_cluster_idx": 4}, {"solution": "def add_lists(input_list, input_tuple):\n \"\"\"Appends a list to a tuple.\n\n Args:\n input_list: The list to append.\n input_tuple: The tuple to append to.\n\n Returns:\n A new tuple with the list appended to the original tuple. Returns None if input is invalid.\n \"\"\"\n if not isinstance(input_list, list) or not isinstance(input_tuple, tuple):\n return None\n \n return input_tuple + tuple(input_list)", "matching_cluster_idx": 4}, {"solution": "def add_lists(list_to_add, tuple_to_add_to):\n \"\"\"Appends a list to a tuple.\n\n Args:\n list_to_add: The list to append.\n tuple_to_add_to: The tuple to append to.\n\n Returns:\n A new tuple with the list appended to the original tuple. Returns None if input is invalid.\n\n Raises:\n TypeError: if input types are not as expected.\n\n \"\"\"\n if not isinstance(list_to_add, list):\n raise TypeError(\"list_to_add must be a list\")\n if not isinstance(tuple_to_add_to, tuple):\n raise TypeError(\"tuple_to_add_to must be a tuple\")\n\n return tuple_to_add_to + tuple(list_to_add)", "matching_cluster_idx": 4}, {"solution": "def add_lists(input_list, input_tuple):\n \"\"\"Appends a list to a tuple.\n\n Args:\n input_list: The list to be appended.\n input_tuple: The tuple to append to.\n\n Returns:\n A new tuple with the list appended to the original tuple. Returns None if input is invalid.\n\n \"\"\"\n if not isinstance(input_list, list) or not isinstance(input_tuple, tuple):\n return None\n\n return input_tuple + tuple(input_list)", "matching_cluster_idx": 4}, {"solution": "def add_lists(lst, tup):\n \"\"\"Appends a list to a tuple.\n\n Args:\n lst: The list to append.\n tup: The tuple to append to.\n\n Returns:\n A new tuple containing the elements of the original tuple followed by the elements of the list.\n \"\"\"\n return tup + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(input_list, input_tuple):\n \"\"\"\n Appends a list to a tuple.\n\n Args:\n input_list: The list to append.\n input_tuple: The tuple to append to.\n\n Returns:\n A new tuple containing the elements of the input tuple followed by the elements of the input list. Returns None if input is not a list and tuple.\n\n \"\"\"\n if not isinstance(input_list, list) or not isinstance(input_tuple, tuple):\n return None\n return input_tuple + tuple(input_list)", "matching_cluster_idx": 4}, {"solution": "def add_lists(my_list, my_tuple):\n \"\"\"Appends a list to a tuple.\n\n Args:\n my_list: The list to append.\n my_tuple: The tuple to append to.\n\n Returns:\n A new tuple containing the elements of my_tuple followed by the elements of my_list. \n \"\"\"\n return my_tuple + tuple(my_list)", "matching_cluster_idx": 5}, {"solution": "def add_lists(list_to_add, tuple_to_add_to):\n \"\"\"Appends a list to a tuple.\n\n Args:\n list_to_add: The list to append.\n tuple_to_add_to: The tuple to append to.\n\n Returns:\n A new tuple with the list appended to the original tuple. Returns None if input is invalid.\n \"\"\"\n if not isinstance(list_to_add, list) or not isinstance(tuple_to_add_to, tuple):\n return None\n\n return tuple_to_add_to + tuple(list_to_add)", "matching_cluster_idx": 4}, {"solution": "def add_lists(my_list, my_tuple):\n \"\"\"Appends a list to a tuple.\n\n Args:\n my_list: The list to append.\n my_tuple: The tuple to append to.\n\n Returns:\n A new tuple with the list appended to the original tuple. Returns None if input is invalid.\n \"\"\"\n if not isinstance(my_list, list) or not isinstance(my_tuple, tuple):\n return None\n return my_tuple + tuple(my_list)", "matching_cluster_idx": 4}, {"solution": "def add_lists(list_to_add, tuple_to_add_to):\n \"\"\"Appends a list to a tuple.\n\n Args:\n list_to_add: The list to append.\n tuple_to_add_to: The tuple to append to.\n\n Returns:\n A new tuple with the list appended to the original tuple. Returns None if input is invalid.\n \"\"\"\n if not isinstance(list_to_add, list) or not isinstance(tuple_to_add_to, tuple):\n return None\n return tuple_to_add_to + tuple(list_to_add)", "matching_cluster_idx": 4}, {"solution": "def add_lists(list_to_add, tuple_to_add_to):\n \"\"\"Appends a list to a tuple.\n\n Args:\n list_to_add: The list to append.\n tuple_to_add_to: The tuple to append to.\n\n Returns:\n A new tuple with the list appended to the original tuple.\n \"\"\"\n return tuple_to_add_to + tuple(list_to_add)", "matching_cluster_idx": 5}, {"solution": "def add_lists(list_to_add, tuple_to_add_to):\n \"\"\"Appends a list to a tuple.\n\n Args:\n list_to_add: The list to append.\n tuple_to_add_to: The tuple to append to.\n\n Returns:\n A new tuple with the list appended to the original tuple. Returns None if input is invalid.\n\n \"\"\"\n if not isinstance(list_to_add, list) or not isinstance(tuple_to_add_to, tuple):\n return None\n\n return tuple_to_add_to + tuple(list_to_add)", "matching_cluster_idx": 4}, {"solution": "def add_lists(list_to_add, tuple_to_add_to):\n \"\"\"Appends a list to a tuple.\n\n Args:\n list_to_add: The list to append.\n tuple_to_add_to: The tuple to append to.\n\n Returns:\n A new tuple containing the elements of the original tuple followed by the elements of the list. Returns None if input is invalid.\n \"\"\"\n if not isinstance(list_to_add, list) or not isinstance(tuple_to_add_to, tuple):\n return None\n return tuple_to_add_to + tuple(list_to_add)", "matching_cluster_idx": 4}, {"solution": "def add_lists(list_to_add, tuple_to_add_to):\n \"\"\"Appends a list to a tuple.\n\n Args:\n list_to_add: The list to append.\n tuple_to_add_to: The tuple to append to.\n\n Returns:\n A new tuple with the list appended to the original tuple. Returns the original tuple if the input is invalid.\n\n \"\"\"\n try:\n return tuple_to_add_to + tuple(list_to_add)\n except TypeError:\n return tuple_to_add_to", "matching_cluster_idx": 5}]}, "Mbpp/108": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def merge_sorted_list(list1, list2, list3):\n \"\"\"Merges three lists into a single sorted list.\n\n Args:\n list1: The first list.\n list2: The second list.\n list3: The third list.\n\n Returns:\n A new list containing all elements from the input lists, sorted in ascending order.\n \"\"\"\n merged_list = list1 + list2 + list3\n merged_list.sort()\n return merged_list\nlist1 = [25, 24, 15, 4, 5, 29, 110]\nlist2 = [19, 20, 11, 56, 25, 233, 154]\nlist3 = [24, 26, 54, 48]", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n \"\"\"Merges three lists into a single sorted list.\n\n Args:\n list1: The first list.\n list2: The second list.\n list3: The third list.\n\n Returns:\n A new list containing all elements from the input lists, sorted in ascending order.\n \"\"\"\n\n merged_list = list1 + list2 + list3\n merged_list.sort()\n return merged_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n \"\"\"Merges three lists into a single sorted list.\n\n Args:\n list1: The first list.\n list2: The second list.\n list3: The third list.\n\n Returns:\n A new list containing all elements from the input lists, sorted in ascending order.\n \"\"\"\n merged_list = list1 + list2 + list3 # Concatenate the three lists\n merged_list.sort() # Sort the merged list in place\n return merged_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n \"\"\"Merges three lists into a single sorted list.\n\n Args:\n list1: The first list.\n list2: The second list.\n list3: The third list.\n\n Returns:\n A new list containing all elements from the input lists, sorted in ascending order.\n \"\"\"\n\n merged_list = list1 + list2 + list3 #Concatenate the lists\n merged_list.sort() #Sort the concatenated list\n return merged_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n \"\"\"Merges three sorted lists into a single sorted list.\n\n Args:\n list1: The first sorted list.\n list2: The second sorted list.\n list3: The third sorted list.\n\n Returns:\n A new list containing all elements from the three input lists, \n sorted in ascending order. Returns an empty list if all input lists are empty.\n \"\"\"\n\n merged_list = sorted(list1 + list2 + list3)\n return merged_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n \"\"\"Merges three lists into a single sorted list.\n\n Args:\n list1: The first list.\n list2: The second list.\n list3: The third list.\n\n Returns:\n A new list containing all elements from the input lists, sorted in ascending order.\n \"\"\"\n merged_list = list1 + list2 + list3 # Combine all lists\n merged_list.sort() # Sort the combined list\n return merged_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n \"\"\"Merges three lists into a single sorted list.\n\n Args:\n list1: The first list.\n list2: The second list.\n list3: The third list.\n\n Returns:\n A new list containing all elements from the input lists, sorted in ascending order.\n \"\"\"\n\n merged_list = list1 + list2 + list3\n merged_list.sort()\n return merged_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n \"\"\"Merges three lists into a single sorted list.\n\n Args:\n list1: The first list.\n list2: The second list.\n list3: The third list.\n\n Returns:\n A new list containing all elements from the input lists, sorted in ascending order.\n \"\"\"\n\n merged_list = list1 + list2 + list3\n merged_list.sort()\n return merged_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n \"\"\"Merges three lists into a single sorted list.\n\n Args:\n list1: The first list.\n list2: The second list.\n list3: The third list.\n\n Returns:\n A new list containing all elements from the three input lists, sorted in ascending order.\n \"\"\"\n merged_list = list1 + list2 + list3 # Concatenate the lists\n merged_list.sort() # Sort the merged list\n return merged_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n \"\"\"Merges three sorted lists into a single sorted list.\n\n Args:\n list1: The first sorted list.\n list2: The second sorted list.\n list3: The third sorted list.\n\n Returns:\n A new list containing all elements from the input lists, sorted in ascending order.\n \"\"\"\n\n merged_list = sorted(list1 + list2 + list3)\n return merged_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n \"\"\"Merges three lists into a single sorted list.\"\"\"\n merged_list = list1 + list2 + list3 # Combine all three lists\n merged_list.sort() # Sort the combined list\n return merged_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n \"\"\"Merges three lists into a single sorted list.\n\n Args:\n list1: The first list.\n list2: The second list.\n list3: The third list.\n\n Returns:\n A new list containing all elements from the input lists, sorted in ascending order.\n \"\"\"\n\n merged_list = list1 + list2 + list3 # Concatenate the three lists\n merged_list.sort() # Sort the merged list in ascending order\n return merged_list\nlist1 = [25, 24, 15, 4, 5, 29, 110]\nlist2 = [19, 20, 11, 56, 25, 233, 154]\nlist3 = [24, 26, 54, 48]", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n \"\"\"Merges three lists into a single sorted list.\n\n Args:\n list1: The first list.\n list2: The second list.\n list3: The third list.\n\n Returns:\n A new list containing all elements from the input lists, sorted in ascending order.\n \"\"\"\n merged_list = list1 + list2 + list3\n merged_list.sort()\n return merged_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n \"\"\"Merges three lists into a single sorted list.\n\n Args:\n list1: The first list.\n list2: The second list.\n list3: The third list.\n\n Returns:\n A new list containing all elements from the input lists, sorted in ascending order.\n \"\"\"\n merged_list = list1 + list2 + list3\n merged_list.sort()\n return merged_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n \"\"\"Merges three lists into a single sorted list.\n\n Args:\n list1: The first list.\n list2: The second list.\n list3: The third list.\n\n Returns:\n A new list containing all elements from the input lists, sorted in ascending order.\n \"\"\"\n merged_list = list1 + list2 + list3\n merged_list.sort()\n return merged_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n \"\"\"Merges three lists into a single sorted list.\n\n Args:\n list1: The first list.\n list2: The second list.\n list3: The third list.\n\n Returns:\n A new list containing all elements from the input lists, sorted in ascending order.\n \"\"\"\n\n merged_list = list1 + list2 + list3 # Concatenate the three lists\n merged_list.sort() # Sort the merged list in ascending order\n return merged_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n \"\"\"Merges three lists into a single sorted list.\n\n Args:\n list1: The first list.\n list2: The second list.\n list3: The third list.\n\n Returns:\n A new list containing all elements from the input lists, sorted in ascending order.\n \"\"\"\n merged_list = list1 + list2 + list3\n merged_list.sort()\n return merged_list\nlist1 = [25, 24, 15, 4, 5, 29, 110]\nlist2 = [19, 20, 11, 56, 25, 233, 154]\nlist3 = [24, 26, 54, 48]", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n \"\"\"Merges three lists into a single sorted list.\n\n Args:\n list1: The first list.\n list2: The second list.\n list3: The third list.\n\n Returns:\n A new list containing all elements from the input lists, sorted in ascending order.\n \"\"\"\n merged_list = list1 + list2 + list3\n merged_list.sort()\n return merged_list\nlist1 = [25, 24, 15, 4, 5, 29, 110]\nlist2 = [19, 20, 11, 56, 25, 233, 154]\nlist3 = [24, 26, 54, 48]", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n \"\"\"Merges three lists into a single sorted list.\n\n Args:\n list1: The first list.\n list2: The second list.\n list3: The third list.\n\n Returns:\n A new list containing all elements from the input lists, sorted in ascending order.\n \"\"\"\n merged_list = list1 + list2 + list3\n merged_list.sort()\n return merged_list\nlist1 = [25, 24, 15, 4, 5, 29, 110]\nlist2 = [19, 20, 11, 56, 25, 233, 154]\nlist3 = [24, 26, 54, 48]", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n \"\"\"Merges three lists into a single sorted list.\n\n Args:\n list1: The first list.\n list2: The second list.\n list3: The third list.\n\n Returns:\n A new list containing all elements from the input lists, sorted in ascending order.\n \"\"\"\n merged_list = list1 + list2 + list3 # Concatenate the three lists\n merged_list.sort() # Sort the merged list in ascending order\n return merged_list\nlist1 = [25, 24, 15, 4, 5, 29, 110]\nlist2 = [19, 20, 11, 56, 25, 233, 154]\nlist3 = [24, 26, 54, 48]", "matching_cluster_idx": 10}]}, "Mbpp/111": {"dps": 91.53846153846155, "dps_norm": 86.25, "pass@1": 89.0, "profiled": [{"solution": "def common_in_nested_lists(nested_lists):\n \"\"\"\n Finds the common elements in a list of lists.\n\n Args:\n nested_lists: A list of lists containing numbers.\n\n Returns:\n A set containing the common elements. Returns an empty set if the input list is empty or contains empty lists.\n \"\"\"\n if not nested_lists:\n return set()\n\n if any(not sublist for sublist in nested_lists): #Handle cases with empty inner lists.\n return set()\n\n\n common = set(nested_lists[0])\n for sublist in nested_lists[1:]:\n common.intersection_update(sublist)\n return common", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n \"\"\"\n Finds the common elements in a list of lists.\n\n Args:\n nested_lists: A list of lists containing numbers.\n\n Returns:\n A set containing the common elements. Returns an empty set if the input list is empty or contains empty lists.\n \"\"\"\n if not nested_lists or not all(nested_lists): #Handle empty input or empty sublists\n return set()\n\n #Efficient approach using set intersection\n result = set(nested_lists[0])\n for lst in nested_lists[1:]:\n result = result.intersection(lst)\n return result", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n \"\"\"\n Finds the common elements in given nested lists.\n\n Args:\n nested_lists: A list of lists, where each inner list contains numbers.\n\n Returns:\n A set containing the elements that are common to all inner lists. Returns an empty set if input is invalid or no common elements exist.\n\n \"\"\"\n if not nested_lists or not all(isinstance(inner_list, list) for inner_list in nested_lists):\n return set()\n\n if len(nested_lists) == 0:\n return set()\n\n #Efficient approach using set intersection\n common_elements = set(nested_lists[0])\n for lst in nested_lists[1:]:\n common_elements.intersection_update(lst)\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n \"\"\"\n Finds the common elements in given nested lists.\n\n Args:\n nested_lists: A list of lists containing numbers.\n\n Returns:\n A set containing the common elements. Returns an empty set if the input list is empty or contains empty lists.\n \"\"\"\n if not nested_lists or not all(nested_lists): #handles empty input list or lists containing empty lists\n return set()\n \n common = set(nested_lists[0])\n for lst in nested_lists[1:]:\n common.intersection_update(lst)\n return common", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n \"\"\"\n Finds the common elements in a list of lists.\n\n Args:\n nested_lists: A list of lists, where each inner list contains numbers.\n\n Returns:\n A set containing the elements that are common to all inner lists. Returns an empty set if the input list is empty or if no common elements exist.\n \"\"\"\n if not nested_lists:\n return set()\n\n # Efficiently find common elements using set intersection\n common_elements = set(nested_lists[0])\n for lst in nested_lists[1:]:\n common_elements.intersection_update(lst)\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n \"\"\"\n Finds the common elements in a list of lists.\n\n Args:\n nested_lists: A list of lists containing numbers.\n\n Returns:\n A set containing the elements common to all lists. Returns an empty set if the input list is empty or no common elements exist.\n \"\"\"\n if not nested_lists:\n return set()\n\n # Efficiently find common elements using set intersection\n common_elements = set(nested_lists[0])\n for lst in nested_lists[1:]:\n common_elements.intersection_update(lst)\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n \"\"\"\n Finds the common elements in a list of lists.\n\n Args:\n nested_lists: A list of lists, where each inner list contains numbers.\n\n Returns:\n A set containing the elements that are common to all inner lists. Returns an empty set if the input list is empty or if no common elements exist.\n \"\"\"\n if not nested_lists:\n return set()\n\n #Efficiently find common elements using sets.\n result = set(nested_lists[0]) #Start with the first list's elements\n for lst in nested_lists[1:]:\n result.intersection_update(lst) #Efficiently find intersection\n\n return result", "matching_cluster_idx": 6}, {"solution": "from functools import reduce\ndef common_in_nested_lists(nested_lists):\n \"\"\"\n Finds the common elements in a list of lists.\n\n Args:\n nested_lists: A list of lists, where each inner list contains numbers.\n\n Returns:\n A set containing the elements that are common to all inner lists. Returns an empty set if the input list is empty or no common elements are found.\n \"\"\"\n if not nested_lists:\n return set()\n\n return reduce(lambda x, y: x.intersection(y), (set(lst) for lst in nested_lists))", "matching_cluster_idx": 5}, {"solution": "def common_in_nested_lists(nested_lists):\n \"\"\"\n Finds the common elements in given nested lists.\n\n Args:\n nested_lists: A list of lists, where each inner list contains numbers.\n\n Returns:\n A set containing the elements that are common to all inner lists. Returns an empty set if the input list is empty or no common elements exist.\n\n \"\"\"\n if not nested_lists:\n return set()\n\n # Efficiently find common elements using sets\n common = set(nested_lists[0])\n for lst in nested_lists[1:]:\n common.intersection_update(lst)\n return common", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n \"\"\"\n Finds the common elements in a list of lists.\n\n Args:\n nested_lists: A list of lists containing numbers.\n\n Returns:\n A set containing the elements common to all inner lists. Returns an empty set if input is invalid or no common elements exist.\n \"\"\"\n if not nested_lists or not all(isinstance(inner_list, list) for inner_list in nested_lists):\n return set() # Handle invalid input\n\n if len(nested_lists) == 0:\n return set()\n\n #Efficiently find common elements using sets\n common_elements = set(nested_lists[0])\n for inner_list in nested_lists[1:]:\n common_elements.intersection_update(inner_list)\n\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n \"\"\"\n Finds the common elements in a list of lists.\n\n Args:\n nested_lists: A list of lists containing numerical data.\n\n Returns:\n A set containing the elements common to all lists in nested_lists. Returns an empty set if the input list is empty or no common elements exist.\n \"\"\"\n if not nested_lists:\n return set()\n\n # Efficiently find common elements using set intersection\n common_elements = set(nested_lists[0])\n for lst in nested_lists[1:]:\n common_elements.intersection_update(lst)\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n \"\"\"\n Finds the common elements in given nested lists.\n\n Args:\n nested_lists: A list of lists of numbers.\n\n Returns:\n A set containing the common elements. Returns an empty set if the input list is empty or contains empty lists.\n \"\"\"\n if not nested_lists:\n return set()\n\n if any(not lst for lst in nested_lists):\n return set()\n\n #Efficient approach using set intersection\n common_elements = set(nested_lists[0])\n for lst in nested_lists[1:]:\n common_elements.intersection_update(lst)\n return common_elements", "matching_cluster_idx": 6}, {"solution": "from functools import reduce\ndef common_in_nested_lists(nested_lists):\n \"\"\"\n Finds the common elements in a list of lists.\n\n Args:\n nested_lists: A list of lists of numbers.\n\n Returns:\n A set containing the common elements. Returns an empty set if the input list is empty or contains empty lists.\n \"\"\"\n if not nested_lists or any(not lst for lst in nested_lists):\n return set()\n return reduce(lambda x, y: set(x) & set(y), nested_lists)", "matching_cluster_idx": 5}, {"solution": "def common_in_nested_lists(nested_lists):\n \"\"\"\n Finds the common elements in given nested lists.\n\n Args:\n nested_lists: A list of lists containing numbers.\n\n Returns:\n A set containing the common elements. Returns an empty set if the input list is empty or contains empty lists.\n \"\"\"\n if not nested_lists:\n return set()\n\n if any(not sublist for sublist in nested_lists):\n return set()\n\n\n common = set(nested_lists[0])\n for lst in nested_lists[1:]:\n common.intersection_update(lst)\n return common", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n \"\"\"\n Finds the common elements in given nested lists.\n\n Args:\n nested_lists: A list of lists containing numbers.\n\n Returns:\n A set containing the common elements. Returns an empty set if input is invalid or no common elements are found.\n \"\"\"\n if not nested_lists or not all(isinstance(inner_list, list) for inner_list in nested_lists):\n return set() #Handle invalid input\n\n if len(nested_lists) == 0:\n return set()\n\n # Efficiently find common elements using set intersection\n common_elements = set(nested_lists[0])\n for lst in nested_lists[1:]:\n common_elements.intersection_update(lst)\n\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n \"\"\"\n Finds the common elements in a list of lists.\n\n Args:\n nested_lists: A list of lists containing numbers.\n\n Returns:\n A set containing the common elements. Returns an empty set if the input list is empty or contains empty lists.\n \"\"\"\n if not nested_lists:\n return set()\n\n if any(not lst for lst in nested_lists):\n return set()\n\n common = set(nested_lists[0])\n for lst in nested_lists[1:]:\n common.intersection_update(lst)\n return common", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n \"\"\"\n Finds the common elements in a list of lists.\n\n Args:\n nested_lists: A list of lists, where each inner list contains numbers.\n\n Returns:\n A set containing the elements that are common to all inner lists. Returns an empty set if the input list is empty or if no common elements exist.\n \"\"\"\n if not nested_lists:\n return set()\n\n #Use sets for efficient intersection operations.\n common_elements = set(nested_lists[0])\n for lst in nested_lists[1:]:\n common_elements.intersection_update(lst)\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n \"\"\"\n Finds the common elements in given nested lists.\n\n Args:\n nested_lists: A list of lists, where each inner list contains numbers.\n\n Returns:\n A set containing the elements that are common to all inner lists. Returns an empty set if the input list is empty or contains empty inner lists.\n \"\"\"\n if not nested_lists:\n return set()\n\n #Handle empty inner lists\n if any(len(lst) == 0 for lst in nested_lists):\n return set()\n\n #Efficiently find common elements using sets\n common = set(nested_lists[0])\n for lst in nested_lists[1:]:\n common.intersection_update(lst)\n return common", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n \"\"\"\n Finds the common elements in given nested lists.\n\n Args:\n nested_lists: A list of lists, where each inner list contains numbers.\n\n Returns:\n A set containing the elements that are common to all inner lists. Returns an empty set if the input list is empty or contains empty lists.\n\n \"\"\"\n if not nested_lists:\n return set()\n\n if any(not lst for lst in nested_lists):\n return set()\n\n #Efficient approach using sets intersection\n common_elements = set(nested_lists[0])\n for lst in nested_lists[1:]:\n common_elements.intersection_update(lst)\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n \"\"\"\n Finds the common elements in given nested lists.\n\n Args:\n nested_lists: A list of lists containing numbers.\n\n Returns:\n A set containing the common elements. Returns an empty set if input is invalid or no common elements exist.\n \"\"\"\n if not isinstance(nested_lists, list):\n return set() # Handle invalid input\n if not all(isinstance(inner_list, list) for inner_list in nested_lists):\n return set() # Handle invalid input\n if not nested_lists:\n return set() #Handle empty input\n\n #Efficient approach using sets for intersection\n common_elements = set(nested_lists[0])\n for lst in nested_lists[1:]:\n common_elements.intersection_update(lst)\n return common_elements", "matching_cluster_idx": 6}]}, "Mbpp/123": {"dps": null, "dps_norm": null, "pass@1": 0.0, "profiled": []}, "Mbpp/128": {"dps": 99.5475113122172, "dps_norm": 80.0, "pass@1": 90.0, "profiled": [{"solution": "def long_words(n, words):\n \"\"\"\n Finds words longer than n characters from a given list of words.\n\n Args:\n n: The minimum length of words to be included.\n words: A string containing space-separated words.\n\n Returns:\n A list of words longer than n characters. Returns an empty list if no words meet the criteria or if the input is invalid.\n \"\"\"\n try:\n word_list = words.split() #split the string into a list of words\n result = [word for word in word_list if len(word) > n]\n return result\n except (AttributeError, TypeError): #handle cases where input is not a string\n return []", "matching_cluster_idx": 3}, {"solution": "def long_words(n, words):\n \"\"\"\n Finds words longer than n characters from a given list of words.\n\n Args:\n n: The minimum length of words to be returned.\n words: A string containing words separated by spaces.\n\n Returns:\n A list of strings, where each string is a word from the input \n string that has more than n characters. Returns an empty list if \n no words meet the criteria or if the input string is empty.\n \"\"\"\n word_list = words.split()\n result = [word for word in word_list if len(word) > n]\n return result", "matching_cluster_idx": 3}, {"solution": "def long_words(n, text):\n \"\"\"\n Finds words longer than n characters from a given text.\n\n Args:\n n: The minimum length of words to be returned.\n text: The input string containing words separated by spaces.\n\n Returns:\n A list of words from the input string that are longer than n characters. Returns an empty list if the input string is empty or None.\n \"\"\"\n if not text:\n return []\n words = text.split()\n return [word for word in words if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, words):\n \"\"\"\n Finds words longer than n characters from a given list of words.\n\n Args:\n n: The minimum length of words to be included.\n words: A string containing words separated by spaces.\n\n Returns:\n A list of words that are longer than n characters. Returns an empty list if no words meet the criteria or the input is invalid.\n \"\"\"\n try:\n word_list = words.split()\n result = [word for word in word_list if len(word) > n]\n return result\n except AttributeError:\n return []", "matching_cluster_idx": 3}, {"solution": "def long_words(n, words):\n \"\"\"\n Finds words longer than n characters from a given list of words.\n\n Args:\n n: The minimum length of words to be included in the result.\n words: A string containing space-separated words.\n\n Returns:\n A list of words that are longer than n characters. Returns an empty list if no words meet the criteria or if the input is invalid.\n\n \"\"\"\n try:\n word_list = words.split()\n result = [word for word in word_list if len(word) > n]\n return result\n except AttributeError:\n return []", "matching_cluster_idx": 3}, {"solution": "def long_words(n, words):\n \"\"\"\n Finds words longer than n characters from a given list of words.\n\n Args:\n n: The minimum length of words to be included.\n words: A string containing words separated by spaces.\n\n Returns:\n A list of words longer than n characters. Returns an empty list if no words \n meet the criteria or if the input string is empty or None.\n \"\"\"\n if not words:\n return []\n word_list = words.split()\n long_word_list = [word for word in word_list if len(word) > n]\n return long_word_list", "matching_cluster_idx": 3}, {"solution": "def long_words(n, words):\n \"\"\"\n Finds words longer than n characters from a given list of words.\n\n Args:\n n: The minimum length of words to be included.\n words: A string containing words separated by spaces.\n\n Returns:\n A list of words longer than n characters. Returns an empty list if the input string is empty or contains only words shorter than n.\n \"\"\"\n word_list = words.split()\n long_word_list = [word for word in word_list if len(word) > n]\n return long_word_list", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n \"\"\"\n Finds words longer than n characters in a sentence.\n\n Args:\n n: The minimum length of words to be included.\n sentence: The input sentence as a string.\n\n Returns:\n A list of words from the sentence that are longer than n characters. Returns an empty list if the input sentence is empty or None.\n \"\"\"\n if not sentence:\n return []\n words = sentence.split()\n return [word for word in words if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, text):\n \"\"\"\n Finds words longer than n characters from a given text.\n\n Args:\n n: The minimum length of words to be returned.\n text: The input string containing words separated by spaces.\n\n Returns:\n A list of words from the input string that are longer than n characters. Returns an empty list if no words meet the criteria or the input is invalid.\n \"\"\"\n try:\n words = text.split()\n long_word_list = [word for word in words if len(word) > n]\n return long_word_list\n except (AttributeError, TypeError):\n return []", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n \"\"\"\n Finds words longer than n characters from a given sentence.\n\n Args:\n n: The minimum length of words to be returned.\n sentence: The input sentence as a string.\n\n Returns:\n A list of words from the sentence that are longer than n characters. Returns an empty list if the input sentence is empty or None.\n \"\"\"\n if not sentence:\n return []\n words = sentence.split()\n return [word for word in words if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n \"\"\"\n Finds words longer than n characters in a sentence.\n\n Args:\n n: The minimum length of words to be returned.\n sentence: The input sentence as a string.\n\n Returns:\n A list of words from the sentence that are longer than n characters. Returns an empty list if the input sentence is empty or None.\n \"\"\"\n if not sentence:\n return []\n words = sentence.split()\n return [word for word in words if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, words):\n \"\"\"\n Finds words longer than n characters from a given list of words.\n\n Args:\n n: The minimum length of words to be included.\n words: A string containing words separated by spaces.\n\n Returns:\n A list of words from the input string that are longer than n characters. Returns an empty list if the input string is empty or contains no words longer than n.\n \"\"\"\n word_list = words.split()\n result = [word for word in word_list if len(word) > n]\n return result", "matching_cluster_idx": 3}, {"solution": "def long_words(n, string):\n \"\"\"\n Finds words longer than n characters from a given string.\n\n Args:\n n: The minimum length of words to be returned.\n string: The input string containing words separated by spaces.\n\n Returns:\n A list of words from the input string that are longer than n characters. Returns an empty list if the input string is empty or None.\n \"\"\"\n if not string:\n return []\n words = string.split()\n long_words_list = [word for word in words if len(word) > n]\n return long_words_list", "matching_cluster_idx": 3}, {"solution": "def long_words(n, words):\n \"\"\"\n Finds words longer than n characters from a given list of words.\n\n Args:\n n: The minimum length of words to be included in the result.\n words: A string containing words separated by spaces.\n\n Returns:\n A list of strings containing words longer than n characters. Returns an empty list if no words meet the criteria or if input is invalid.\n \"\"\"\n if not isinstance(n, int) or n < 0:\n return [] # Handle invalid input for n\n\n try:\n word_list = words.split()\n except AttributeError:\n return [] #Handle case where words is not a string\n\n\n long_word_list = [word for word in word_list if len(word) > n]\n return long_word_list", "matching_cluster_idx": 3}, {"solution": "def long_words(n, words):\n \"\"\"\n Finds words longer than n characters from a given list of words.\n\n Args:\n n: The minimum length of words to be returned.\n words: A string containing words separated by spaces.\n\n Returns:\n A list of words that are longer than n characters. Returns an empty list if no words meet the criteria or the input is invalid.\n \"\"\"\n if not isinstance(n, int) or n < 0:\n return [] # Handle invalid input for n\n\n try:\n word_list = words.split() #Split the input string into a list of words\n except AttributeError:\n return [] #Handle cases where words is not a string\n\n long_words_list = [word for word in word_list if len(word) > n]\n return long_words_list", "matching_cluster_idx": 3}, {"solution": "def long_words(n, words):\n \"\"\"\n Finds words longer than n characters from a given list of words.\n\n Args:\n n: The minimum length of words to be included.\n words: A string containing words separated by spaces.\n\n Returns:\n A list of words longer than n characters. Returns an empty list if no words meet the criteria or if the input string is empty or None.\n \"\"\"\n if not words:\n return []\n word_list = words.split()\n return [word for word in word_list if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, words):\n \"\"\"\n Finds words longer than n characters from a given list of words.\n\n Args:\n n: The minimum length of words to be included.\n words: A string containing words separated by spaces.\n\n Returns:\n A list of words longer than n characters. Returns an empty list if the input string is empty or None.\n \"\"\"\n if not words:\n return []\n word_list = words.split()\n return [word for word in word_list if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, words):\n \"\"\"\n Finds words longer than n characters from a given list of words.\n\n Args:\n n: The minimum length of words to be included.\n words: A string containing words separated by spaces.\n\n Returns:\n A list of words longer than n characters. Returns an empty list if no words \n meet the criteria or if the input string is empty or None.\n \"\"\"\n if not words:\n return []\n\n word_list = words.split()\n result = [word for word in word_list if len(word) > n]\n return result", "matching_cluster_idx": 3}, {"solution": "def long_words(n, words):\n \"\"\"\n Finds words longer than n characters from a given list of words.\n\n Args:\n n: The minimum length of words to be included.\n words: A string containing words separated by spaces.\n\n Returns:\n A list of words longer than n characters. Returns an empty list if the input string is empty or None.\n \"\"\"\n if not words:\n return []\n word_list = words.split()\n return [word for word in word_list if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, words):\n \"\"\"\n Finds words longer than n characters from a given list of words.\n\n Args:\n n: The minimum length of words to be included.\n words: A string containing words separated by spaces.\n\n Returns:\n A list of words longer than n characters. Returns an empty list if the input string is empty or None.\n\n \"\"\"\n if not words:\n return []\n word_list = words.split()\n return [word for word in word_list if len(word) > n]", "matching_cluster_idx": 3}]}, "Mbpp/129": {"dps": 64.46428571428572, "dps_norm": 95.33333333333333, "pass@1": 91.0, "profiled": [{"solution": "def magic_square_test(matrix):\n \"\"\"\n Checks if a given matrix is a magic square.\n\n Args:\n matrix: A list of lists representing the matrix.\n\n Returns:\n True if the matrix is a magic square, False otherwise.\n \"\"\"\n\n n = len(matrix)\n if n == 0: #Handle empty matrix case\n return False\n\n # Check if the matrix is square\n for row in matrix:\n if len(row) != n:\n return False\n\n # Calculate the magic constant (sum of any row, column, or diagonal)\n magic_constant = sum(matrix[0])\n\n # Check rows\n for row in matrix:\n if sum(row) != magic_constant:\n return False\n\n # Check columns\n for col in range(n):\n column_sum = 0\n for row in range(n):\n column_sum += matrix[row][col]\n if column_sum != magic_constant:\n return False\n\n # Check diagonals\n diag1_sum = 0\n diag2_sum = 0\n for i in range(n):\n diag1_sum += matrix[i][i]\n diag2_sum += matrix[i][n - 1 - i]\n\n if diag1_sum != magic_constant or diag2_sum != magic_constant:\n return False\n\n return True", "matching_cluster_idx": 13}, {"solution": "def magic_square_test(matrix):\n \"\"\"\n Checks if a given matrix is a magic square.\n\n Args:\n matrix: A list of lists representing the matrix.\n\n Returns:\n True if the matrix is a magic square, False otherwise.\n \"\"\"\n\n n = len(matrix)\n if n == 0:\n return False # Handle empty matrix case\n\n # Check if the matrix is square\n for row in matrix:\n if len(row) != n:\n return False\n\n # Calculate the magic constant (sum of any row/column/diagonal)\n magic_constant = sum(matrix[0])\n\n # Check rows\n for row in matrix:\n if sum(row) != magic_constant:\n return False\n\n # Check columns\n for col_index in range(n):\n column_sum = 0\n for row_index in range(n):\n column_sum += matrix[row_index][col_index]\n if column_sum != magic_constant:\n return False\n\n # Check diagonals\n diag1_sum = sum(matrix[i][i] for i in range(n))\n diag2_sum = sum(matrix[i][n - 1 - i] for i in range(n))\n if diag1_sum != magic_constant or diag2_sum != magic_constant:\n return False\n\n return True", "matching_cluster_idx": 13}, {"solution": "def magic_square_test(matrix):\n \"\"\"\n Checks if a given matrix is a magic square.\n\n Args:\n matrix: A list of lists representing the matrix.\n\n Returns:\n True if the matrix is a magic square, False otherwise.\n \"\"\"\n\n n = len(matrix)\n if n == 0:\n return False # Handle empty matrix case\n\n # Check if the matrix is square\n for row in matrix:\n if len(row) != n:\n return False\n\n # Calculate the magic constant (sum of any row/column/diagonal)\n magic_constant = sum(matrix[0]) # Sum of the first row\n\n # Check rows\n for row in matrix:\n if sum(row) != magic_constant:\n return False\n\n # Check columns\n for col in range(n):\n column_sum = sum(matrix[row][col] for row in range(n))\n if column_sum != magic_constant:\n return False\n\n # Check diagonals\n diag1_sum = sum(matrix[i][i] for i in range(n))\n diag2_sum = sum(matrix[i][n - 1 - i] for i in range(n))\n if diag1_sum != magic_constant or diag2_sum != magic_constant:\n return False\n\n return True", "matching_cluster_idx": 13}, {"solution": "def magic_square_test(matrix):\n \"\"\"\n Checks if a given matrix is a magic square.\n\n Args:\n matrix: A list of lists representing the matrix.\n\n Returns:\n True if the matrix is a magic square, False otherwise.\n \"\"\"\n\n n = len(matrix)\n if n == 0:\n return False # Handle empty matrix case\n\n # Check if the matrix is square\n for row in matrix:\n if len(row) != n:\n return False\n\n # Calculate the magic sum (sum of the first row)\n magic_sum = sum(matrix[0])\n\n # Check rows\n for row in matrix:\n if sum(row) != magic_sum:\n return False\n\n # Check columns\n for col in range(n):\n col_sum = 0\n for row in range(n):\n col_sum += matrix[row][col]\n if col_sum != magic_sum:\n return False\n\n # Check diagonals\n diag1_sum = 0\n diag2_sum = 0\n for i in range(n):\n diag1_sum += matrix[i][i]\n diag2_sum += matrix[i][n - 1 - i]\n if diag1_sum != magic_sum or diag2_sum != magic_sum:\n return False\n\n return True", "matching_cluster_idx": 13}, {"solution": "def magic_square_test(matrix):\n \"\"\"\n Write a function to calculate whether the matrix is a magic square.\n assert magic_square_test([[7, 12, 1, 14], [2, 13, 8, 11], [16, 3, 10, 5], [9, 6, 15, 4]])==True\n \"\"\"\n n = len(matrix)\n magic_sum = sum(matrix[0]) # Calculate the magic sum from the first row\n\n # Check rows\n for row in matrix:\n if sum(row) != magic_sum:\n return False\n\n # Check columns\n for col in range(n):\n col_sum = 0\n for row in range(n):\n col_sum += matrix[row][col]\n if col_sum != magic_sum:\n return False\n\n # Check diagonals\n diag1_sum = 0\n diag2_sum = 0\n for i in range(n):\n diag1_sum += matrix[i][i]\n diag2_sum += matrix[i][n - 1 - i]\n if diag1_sum != magic_sum or diag2_sum != magic_sum:\n return False\n\n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n \"\"\"\n Checks if a given matrix is a magic square.\n\n Args:\n matrix: A list of lists representing the matrix.\n\n Returns:\n True if the matrix is a magic square, False otherwise.\n \"\"\"\n\n n = len(matrix)\n if n == 0:\n return False # Handle empty matrix case\n\n # Check if matrix is square\n for row in matrix:\n if len(row) != n:\n return False\n\n magic_sum = sum(matrix[0]) # Calculate the magic sum from the first row\n\n # Check rows\n for row in matrix:\n if sum(row) != magic_sum:\n return False\n\n # Check columns\n for col in range(n):\n col_sum = sum(matrix[row][col] for row in range(n))\n if col_sum != magic_sum:\n return False\n\n # Check diagonals\n diag1_sum = sum(matrix[i][i] for i in range(n))\n diag2_sum = sum(matrix[i][n - 1 - i] for i in range(n))\n if diag1_sum != magic_sum or diag2_sum != magic_sum:\n return False\n\n return True\nmatrix = [[7, 12, 1, 14], [2, 13, 8, 11], [16, 3, 10, 5], [9, 6, 15, 4]]", "matching_cluster_idx": 13}, {"solution": "def magic_square_test(matrix):\n \"\"\"\n Write a function to calculate whether the matrix is a magic square.\n assert magic_square_test([[7, 12, 1, 14], [2, 13, 8, 11], [16, 3, 10, 5], [9, 6, 15, 4]])==True\n \"\"\"\n n = len(matrix)\n magic_sum = sum(matrix[0]) # Calculate the magic sum from the first row\n\n # Check rows\n for row in matrix:\n if sum(row) != magic_sum:\n return False\n\n # Check columns\n for col in range(n):\n col_sum = 0\n for row in range(n):\n col_sum += matrix[row][col]\n if col_sum != magic_sum:\n return False\n\n # Check diagonals\n diag1_sum = 0\n diag2_sum = 0\n for i in range(n):\n diag1_sum += matrix[i][i]\n diag2_sum += matrix[i][n - 1 - i]\n if diag1_sum != magic_sum or diag2_sum != magic_sum:\n return False\n\n return True\nmatrix = [[7, 12, 1, 14], [2, 13, 8, 11], [16, 3, 10, 5], [9, 6, 15, 4]]", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n \"\"\"\n Write a function to calculate whether the matrix is a magic square.\n assert magic_square_test([[7, 12, 1, 14], [2, 13, 8, 11], [16, 3, 10, 5], [9, 6, 15, 4]])==True\n \"\"\"\n n = len(matrix)\n magic_sum = sum(matrix[0]) # Calculate the magic sum from the first row\n\n # Check rows\n for row in matrix:\n if sum(row) != magic_sum:\n return False\n\n # Check columns\n for col in range(n):\n col_sum = 0\n for row in range(n):\n col_sum += matrix[row][col]\n if col_sum != magic_sum:\n return False\n\n # Check diagonals\n diag1_sum = 0\n diag2_sum = 0\n for i in range(n):\n diag1_sum += matrix[i][i]\n diag2_sum += matrix[i][n - 1 - i]\n if diag1_sum != magic_sum or diag2_sum != magic_sum:\n return False\n\n return True\nmatrix = [[7, 12, 1, 14], [2, 13, 8, 11], [16, 3, 10, 5], [9, 6, 15, 4]]", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n \"\"\"\n Checks if a given matrix is a magic square.\n\n Args:\n matrix: A list of lists representing the matrix.\n\n Returns:\n True if the matrix is a magic square, False otherwise.\n \"\"\"\n\n n = len(matrix)\n if n == 0: #Handle empty matrix case\n return False\n\n #Check if it's a square matrix\n for row in matrix:\n if len(row) != n:\n return False\n\n magic_sum = sum(matrix[0]) # Calculate the magic sum using the first row\n\n # Check rows\n for row in matrix:\n if sum(row) != magic_sum:\n return False\n\n # Check columns\n for col in range(n):\n column_sum = sum(matrix[row][col] for row in range(n))\n if column_sum != magic_sum:\n return False\n\n # Check diagonals\n diag1_sum = sum(matrix[i][i] for i in range(n))\n diag2_sum = sum(matrix[i][n - 1 - i] for i in range(n))\n if diag1_sum != magic_sum or diag2_sum != magic_sum:\n return False\n\n return True", "matching_cluster_idx": 13}, {"solution": "def magic_square_test(matrix):\n \"\"\"\n Write a function to calculate whether the matrix is a magic square.\n assert magic_square_test([[7, 12, 1, 14], [2, 13, 8, 11], [16, 3, 10, 5], [9, 6, 15, 4]])==True\n \"\"\"\n n = len(matrix)\n magic_sum = sum(matrix[0]) # Calculate the magic sum from the first row\n\n # Check rows\n for row in matrix:\n if sum(row) != magic_sum:\n return False\n\n # Check columns\n for col in range(n):\n col_sum = 0\n for row in range(n):\n col_sum += matrix[row][col]\n if col_sum != magic_sum:\n return False\n\n # Check diagonals\n diag1_sum = 0\n diag2_sum = 0\n for i in range(n):\n diag1_sum += matrix[i][i]\n diag2_sum += matrix[i][n - 1 - i]\n if diag1_sum != magic_sum or diag2_sum != magic_sum:\n return False\n\n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n \"\"\"\n Write a function to calculate whether the matrix is a magic square.\n assert magic_square_test([[7, 12, 1, 14], [2, 13, 8, 11], [16, 3, 10, 5], [9, 6, 15, 4]])==True\n \"\"\"\n n = len(matrix)\n magic_sum = sum(matrix[0]) # Calculate the magic sum from the first row\n\n # Check rows\n for row in matrix:\n if sum(row) != magic_sum:\n return False\n\n # Check columns\n for col in range(n):\n column_sum = 0\n for row in range(n):\n column_sum += matrix[row][col]\n if column_sum != magic_sum:\n return False\n\n # Check diagonals\n diag1_sum = 0\n diag2_sum = 0\n for i in range(n):\n diag1_sum += matrix[i][i]\n diag2_sum += matrix[i][n - 1 - i]\n if diag1_sum != magic_sum or diag2_sum != magic_sum:\n return False\n\n return True\nmatrix = [[7, 12, 1, 14], [2, 13, 8, 11], [16, 3, 10, 5], [9, 6, 15, 4]]", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n \"\"\"\n Write a function to calculate whether the matrix is a magic square.\n assert magic_square_test([[7, 12, 1, 14], [2, 13, 8, 11], [16, 3, 10, 5], [9, 6, 15, 4]])==True\n \"\"\"\n n = len(matrix)\n magic_sum = sum(matrix[0]) # Calculate the magic sum from the first row\n\n # Check rows\n for row in matrix:\n if sum(row) != magic_sum:\n return False\n\n # Check columns\n for col in range(n):\n col_sum = 0\n for row in range(n):\n col_sum += matrix[row][col]\n if col_sum != magic_sum:\n return False\n\n # Check diagonals\n diag1_sum = 0\n diag2_sum = 0\n for i in range(n):\n diag1_sum += matrix[i][i]\n diag2_sum += matrix[i][n - 1 - i]\n if diag1_sum != magic_sum or diag2_sum != magic_sum:\n return False\n\n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n \"\"\"\n Checks if a given matrix is a magic square.\n\n Args:\n matrix: A list of lists representing the matrix.\n\n Returns:\n True if the matrix is a magic square, False otherwise.\n \"\"\"\n\n n = len(matrix)\n if n == 0:\n return False # Handle empty matrix case\n\n # Check if it's a square matrix\n for row in matrix:\n if len(row) != n:\n return False\n\n # Calculate the magic constant (sum of the first row)\n magic_constant = sum(matrix[0])\n\n # Check rows\n for row in matrix:\n if sum(row) != magic_constant:\n return False\n\n # Check columns\n for col in range(n):\n column_sum = sum(matrix[row][col] for row in range(n))\n if column_sum != magic_constant:\n return False\n\n # Check diagonals\n diag1_sum = sum(matrix[i][i] for i in range(n))\n diag2_sum = sum(matrix[i][n - 1 - i] for i in range(n))\n if diag1_sum != magic_constant or diag2_sum != magic_constant:\n return False\n\n return True", "matching_cluster_idx": 13}, {"solution": "def magic_square_test(matrix):\n \"\"\"\n Checks if a given matrix is a magic square.\n\n Args:\n matrix: A list of lists representing the matrix.\n\n Returns:\n True if the matrix is a magic square, False otherwise.\n \"\"\"\n\n n = len(matrix)\n if n == 0: #Handle empty matrix case\n return False\n\n # Check if the matrix is square\n for row in matrix:\n if len(row) != n:\n return False\n\n # Calculate the magic sum (sum of the first row)\n magic_sum = sum(matrix[0])\n\n # Check rows\n for row in matrix:\n if sum(row) != magic_sum:\n return False\n\n # Check columns\n for col in range(n):\n column_sum = sum(matrix[row][col] for row in range(n))\n if column_sum != magic_sum:\n return False\n\n # Check diagonals\n diag1_sum = sum(matrix[i][i] for i in range(n))\n diag2_sum = sum(matrix[i][n - 1 - i] for i in range(n))\n if diag1_sum != magic_sum or diag2_sum != magic_sum:\n return False\n\n return True", "matching_cluster_idx": 13}, {"solution": "def magic_square_test(matrix):\n \"\"\"\n Checks if a given matrix is a magic square.\n\n Args:\n matrix: A list of lists representing the matrix.\n\n Returns:\n True if the matrix is a magic square, False otherwise.\n \"\"\"\n\n n = len(matrix)\n if n == 0:\n return False # Handle empty matrix case\n\n # Check if it's a square matrix\n for row in matrix:\n if len(row) != n:\n return False\n\n # Calculate the magic constant (sum of any row, column, or diagonal)\n magic_constant = sum(matrix[0])\n\n # Check rows\n for row in matrix:\n if sum(row) != magic_constant:\n return False\n\n # Check columns\n for col in range(n):\n column_sum = 0\n for row in range(n):\n column_sum += matrix[row][col]\n if column_sum != magic_constant:\n return False\n\n # Check diagonals\n diagonal_sum1 = 0\n diagonal_sum2 = 0\n for i in range(n):\n diagonal_sum1 += matrix[i][i]\n diagonal_sum2 += matrix[i][n - 1 - i]\n\n if diagonal_sum1 != magic_constant or diagonal_sum2 != magic_constant:\n return False\n\n return True\nmatrix = [[7, 12, 1, 14], [2, 13, 8, 11], [16, 3, 10, 5], [9, 6, 15, 4]]", "matching_cluster_idx": 13}, {"solution": "def magic_square_test(matrix):\n \"\"\"\n Checks if a given matrix is a magic square.\n\n Args:\n matrix: A list of lists representing the matrix.\n\n Returns:\n True if the matrix is a magic square, False otherwise.\n \"\"\"\n\n n = len(matrix)\n if n == 0:\n return False # Handle empty matrix case\n\n # Check if matrix is square\n for row in matrix:\n if len(row) != n:\n return False\n\n # Calculate the magic constant (sum of any row/column/diagonal)\n magic_constant = sum(matrix[0]) # Sum of the first row\n\n # Check rows\n for row in matrix:\n if sum(row) != magic_constant:\n return False\n\n # Check columns\n for col_index in range(n):\n column_sum = sum(matrix[row_index][col_index] for row_index in range(n))\n if column_sum != magic_constant:\n return False\n\n # Check diagonals\n diag1_sum = sum(matrix[i][i] for i in range(n))\n diag2_sum = sum(matrix[i][n - 1 - i] for i in range(n))\n if diag1_sum != magic_constant or diag2_sum != magic_constant:\n return False\n\n return True", "matching_cluster_idx": 13}, {"solution": "def magic_square_test(matrix):\n \"\"\"\n Checks if a given matrix is a magic square.\n\n Args:\n matrix: A list of lists representing the matrix.\n\n Returns:\n True if the matrix is a magic square, False otherwise.\n \"\"\"\n\n n = len(matrix)\n if n == 0:\n return False # Handle empty matrix case\n\n # Check if the matrix is square\n for row in matrix:\n if len(row) != n:\n return False\n\n # Calculate the magic constant (sum of any row, column, or diagonal)\n magic_constant = sum(matrix[0]) # Sum of the first row\n\n # Check rows\n for row in matrix:\n if sum(row) != magic_constant:\n return False\n\n # Check columns\n for col in range(n):\n column_sum = sum(matrix[row][col] for row in range(n))\n if column_sum != magic_constant:\n return False\n\n # Check diagonals\n diag1_sum = sum(matrix[i][i] for i in range(n))\n diag2_sum = sum(matrix[i][n - 1 - i] for i in range(n))\n if diag1_sum != magic_constant or diag2_sum != magic_constant:\n return False\n\n return True\nmatrix = [[7, 12, 1, 14], [2, 13, 8, 11], [16, 3, 10, 5], [9, 6, 15, 4]]", "matching_cluster_idx": 13}, {"solution": "def magic_square_test(square):\n \"\"\"\n Checks if a given square matrix is a magic square.\n\n Args:\n square: A list of lists representing the square matrix.\n\n Returns:\n True if the matrix is a magic square, False otherwise.\n \"\"\"\n\n n = len(square)\n if n == 0:\n return False #Handle empty matrix case\n\n #Check if it's a square matrix\n for row in square:\n if len(row) != n:\n return False\n\n #Calculate the magic constant\n magic_constant = sum(square[0])\n\n #Check rows\n for row in square:\n if sum(row) != magic_constant:\n return False\n\n #Check columns\n for col in range(n):\n column_sum = sum(square[row][col] for row in range(n))\n if column_sum != magic_constant:\n return False\n\n #Check diagonals\n diag1_sum = sum(square[i][i] for i in range(n))\n diag2_sum = sum(square[i][n - 1 - i] for i in range(n))\n if diag1_sum != magic_constant or diag2_sum != magic_constant:\n return False\n\n return True", "matching_cluster_idx": 13}, {"solution": "def magic_square_test(matrix):\n \"\"\"\n Checks if a given matrix is a magic square.\n\n Args:\n matrix: A list of lists representing the matrix.\n\n Returns:\n True if the matrix is a magic square, False otherwise.\n \"\"\"\n\n n = len(matrix)\n if n == 0: #Handle empty matrix case\n return False\n\n #Check if it's a square matrix\n for row in matrix:\n if len(row) != n:\n return False\n\n magic_sum = sum(matrix[0]) #Calculate the magic sum using the first row\n\n #Check rows\n for row in matrix:\n if sum(row) != magic_sum:\n return False\n\n #Check columns\n for col in range(n):\n col_sum = 0\n for row in range(n):\n col_sum += matrix[row][col]\n if col_sum != magic_sum:\n return False\n\n #Check diagonals\n diag1_sum = 0\n diag2_sum = 0\n for i in range(n):\n diag1_sum += matrix[i][i]\n diag2_sum += matrix[i][n - 1 - i]\n\n if diag1_sum != magic_sum or diag2_sum != magic_sum:\n return False\n\n return True", "matching_cluster_idx": 13}, {"solution": "def magic_square_test(matrix):\n \"\"\"\n Checks if a given matrix is a magic square.\n\n Args:\n matrix: A list of lists representing the matrix.\n\n Returns:\n True if the matrix is a magic square, False otherwise.\n \"\"\"\n\n n = len(matrix)\n if n == 0: #Handle empty matrix case\n return False\n\n # Check if the matrix is square\n for row in matrix:\n if len(row) != n:\n return False\n\n # Calculate the magic sum (sum of the first row)\n magic_sum = sum(matrix[0])\n\n # Check rows\n for row in matrix:\n if sum(row) != magic_sum:\n return False\n\n # Check columns\n for col in range(n):\n col_sum = 0\n for row in range(n):\n col_sum += matrix[row][col]\n if col_sum != magic_sum:\n return False\n\n # Check diagonals\n diag1_sum = sum(matrix[i][i] for i in range(n))\n diag2_sum = sum(matrix[i][n - 1 - i] for i in range(n))\n if diag1_sum != magic_sum or diag2_sum != magic_sum:\n return False\n\n return True", "matching_cluster_idx": 13}]}, "Mbpp/130": {"dps": 99.10313901345292, "dps_norm": 83.33333333333333, "pass@1": 100.0, "profiled": [{"solution": "from collections import Counter\ndef max_occurrences(input_list):\n \"\"\"\n Finds the item with the maximum frequency in a given list.\n\n Args:\n input_list: A list of items.\n\n Returns:\n The item with the maximum frequency. Returns None if the list is empty.\n \"\"\"\n if not input_list:\n return None\n\n counts = Counter(input_list)\n max_item = max(counts, key=counts.get)\n return max_item", "matching_cluster_idx": 4}, {"solution": "from collections import Counter\ndef max_occurrences(input_list):\n \"\"\"\n Finds the item with the maximum frequency in a list.\n\n Args:\n input_list: A list of items.\n\n Returns:\n The item with the maximum frequency. Returns None if the list is empty.\n \"\"\"\n if not input_list:\n return None\n\n count = Counter(input_list)\n max_item = max(count, key=count.get) #Finds the key (item) with the max value (count)\n return max_item", "matching_cluster_idx": 4}, {"solution": "from collections import Counter\ndef max_occurrences(data):\n \"\"\"\n Finds the item with the maximum frequency in a list.\n\n Args:\n data: A list of items.\n\n Returns:\n The item with the maximum frequency. If multiple items have the same maximum frequency, returns one of them. Returns None if the list is empty.\n\n \"\"\"\n if not data:\n return None\n \n counts = Counter(data)\n max_item = max(counts, key=counts.get) #Finds the key (item) with the maximum value (count)\n return max_item", "matching_cluster_idx": 4}, {"solution": "from collections import Counter\ndef max_occurrences(input_list):\n \"\"\"\n Finds the item with the maximum frequency in a given list.\n\n Args:\n input_list: A list of items.\n\n Returns:\n The item with the maximum frequency. If multiple items have the same \n maximum frequency, returns the first one encountered. Returns None if \n the input list is empty.\n \"\"\"\n if not input_list:\n return None\n\n counts = Counter(input_list)\n max_item = max(counts, key=counts.get) #Finds the key with the max value\n return max_item", "matching_cluster_idx": 4}, {"solution": "from collections import Counter\ndef max_occurrences(input_list):\n \"\"\"\n Finds the item with the maximum frequency in a list.\n\n Args:\n input_list: A list of items.\n\n Returns:\n The item with the maximum frequency. Returns None if the list is empty.\n \"\"\"\n if not input_list:\n return None\n\n counts = Counter(input_list)\n max_item = max(counts, key=counts.get) #Finds the key (item) with the maximum value (count)\n return max_item", "matching_cluster_idx": 4}, {"solution": "from collections import Counter\ndef max_occurrences(data):\n \"\"\"\n Finds the item with the maximum frequency in a list.\n\n Args:\n data: A list of items.\n\n Returns:\n The item with the maximum frequency. Returns None if the list is empty.\n \"\"\"\n if not data:\n return None\n\n counts = Counter(data)\n max_item = max(counts, key=counts.get) #Finds the key (item) with the max value (count)\n return max_item", "matching_cluster_idx": 4}, {"solution": "from collections import Counter\ndef max_occurrences(input_list):\n \"\"\"\n Finds the item with the maximum frequency in a list.\n\n Args:\n input_list: A list of items.\n\n Returns:\n The item with the maximum frequency. Returns None if the list is empty.\n \"\"\"\n if not input_list:\n return None\n\n counts = Counter(input_list)\n max_item = max(counts, key=counts.get) #Finds the key with the max value\n return max_item", "matching_cluster_idx": 4}, {"solution": "from collections import Counter\ndef max_occurrences(data):\n \"\"\"Finds the item with the maximum frequency in a list.\n\n Args:\n data: A list of items.\n\n Returns:\n The item with the maximum frequency. Returns None if the list is empty.\n \"\"\"\n if not data:\n return None\n \n counts = Counter(data)\n max_item = max(counts, key=counts.get) #Finds the key (item) with the maximum value (count)\n\n return max_item", "matching_cluster_idx": 4}, {"solution": "from collections import Counter\ndef max_occurrences(input_list):\n \"\"\"\n Finds the item with the maximum frequency in a list.\n\n Args:\n input_list: A list of items.\n\n Returns:\n The item with the maximum frequency. Returns None if the list is empty.\n \"\"\"\n if not input_list:\n return None\n\n count = Counter(input_list)\n max_item = max(count, key=count.get) #Finds the key (item) with the max value (count)\n return max_item", "matching_cluster_idx": 4}, {"solution": "from collections import Counter\ndef max_occurrences(input_list):\n \"\"\"\n Finds the item with the maximum frequency in a list.\n\n Args:\n input_list: A list of items.\n\n Returns:\n The item with the maximum frequency. Returns None if the list is empty.\n \"\"\"\n if not input_list:\n return None\n\n counts = Counter(input_list)\n max_item = max(counts, key=counts.get) #Finds the key (item) with the maximum value (count)\n return max_item", "matching_cluster_idx": 4}, {"solution": "from collections import Counter\ndef max_occurrences(input_list):\n \"\"\"\n Finds the item with the maximum frequency in a list.\n\n Args:\n input_list: A list of items.\n\n Returns:\n The item with the maximum frequency. Returns None if the list is empty.\n \"\"\"\n if not input_list:\n return None\n\n count = Counter(input_list)\n max_item = max(count, key=count.get) #Finds the key with the maximum value\n return max_item", "matching_cluster_idx": 4}, {"solution": "from collections import Counter\ndef max_occurrences(input_list):\n \"\"\"\n Finds the item with the maximum frequency in a list.\n\n Args:\n input_list: A list of items.\n\n Returns:\n The item with the maximum frequency. Returns None if the list is empty.\n \"\"\"\n if not input_list:\n return None\n\n counts = Counter(input_list)\n max_item = max(counts, key=counts.get) #Finds the key (item) with the max value (count)\n return max_item", "matching_cluster_idx": 4}, {"solution": "from collections import Counter\ndef max_occurrences(data):\n \"\"\"\n Finds the item with the maximum frequency in a list.\n\n Args:\n data: A list of items.\n\n Returns:\n The item with the maximum frequency. If multiple items have the same maximum frequency, \n it returns the first one encountered. Returns None if the list is empty.\n \"\"\"\n if not data:\n return None\n \n counts = Counter(data)\n max_item = max(counts, key=counts.get) #Finds the key (item) with the max value (count)\n return max_item", "matching_cluster_idx": 4}, {"solution": "from collections import Counter\ndef max_occurrences(data):\n \"\"\"\n Finds the item with the maximum frequency in a list.\n\n Args:\n data: A list of items.\n\n Returns:\n The item with the maximum frequency. If multiple items have the same maximum frequency, \n it returns the one that appears first in the input list.\n \"\"\"\n if not data:\n return None # Handle empty list case\n\n count = Counter(data)\n max_count = 0\n max_item = None\n\n for item, freq in count.items():\n if freq > max_count:\n max_count = freq\n max_item = item\n\n return max_item", "matching_cluster_idx": 4}, {"solution": "from collections import Counter\ndef max_occurrences(input_list):\n \"\"\"\n Finds the item with the maximum frequency in a given list.\n\n Args:\n input_list: A list of items.\n\n Returns:\n The item with the maximum frequency. Returns None if the list is empty.\n \"\"\"\n if not input_list:\n return None\n\n counts = Counter(input_list)\n max_item = max(counts, key=counts.get) #Finds the key (item) with the max value (count)\n return max_item", "matching_cluster_idx": 4}, {"solution": "from collections import Counter\ndef max_occurrences(data):\n \"\"\"\n Finds the item with the maximum frequency in a list.\n\n Args:\n data: A list of items.\n\n Returns:\n The item with the maximum frequency. Returns None if the list is empty.\n \"\"\"\n if not data:\n return None\n \n counts = Counter(data)\n max_item = max(counts, key=counts.get) #Get the key (item) with the max value (count)\n\n return max_item", "matching_cluster_idx": 4}, {"solution": "from collections import Counter\ndef max_occurrences(data):\n \"\"\"\n Finds the item with the maximum frequency in a list.\n\n Args:\n data: A list of items.\n\n Returns:\n The item with the maximum frequency. Returns None if the list is empty.\n \"\"\"\n if not data:\n return None\n \n counts = Counter(data)\n max_item = max(counts, key=counts.get) #Finds the key (item) with the maximum value (count)\n return max_item", "matching_cluster_idx": 4}, {"solution": "from collections import Counter\ndef max_occurrences(input_list):\n \"\"\"\n Finds the item with the maximum frequency in a list.\n\n Args:\n input_list: A list of items.\n\n Returns:\n The item with the maximum frequency. If multiple items have the same maximum frequency, returns one of them arbitrarily. Returns None if the input list is empty.\n \"\"\"\n if not input_list:\n return None\n\n counts = Counter(input_list)\n max_item = max(counts, key=counts.get) #get the key (item) with the max value (count)\n return max_item", "matching_cluster_idx": 4}, {"solution": "from collections import Counter\ndef max_occurrences(data):\n \"\"\"\n Finds the item with the maximum frequency in a list.\n\n Args:\n data: A list of items.\n\n Returns:\n The item with the maximum frequency. Returns None if the list is empty.\n \"\"\"\n if not data:\n return None\n\n counts = Counter(data)\n max_item = max(counts, key=counts.get) #Finds the key (item) with the max value (count)\n return max_item", "matching_cluster_idx": 4}, {"solution": "from collections import Counter\ndef max_occurrences(input_list):\n \"\"\"\n Finds the item with the maximum frequency in a list.\n\n Args:\n input_list: A list of items.\n\n Returns:\n The item with the maximum frequency. Returns None if the list is empty.\n \"\"\"\n if not input_list:\n return None\n\n counts = Counter(input_list)\n max_item = max(counts, key=counts.get) #Finds the key (item) with the max value (count)\n return max_item", "matching_cluster_idx": 4}]}, "Mbpp/137": {"dps": null, "dps_norm": null, "pass@1": 0.0, "profiled": []}, "Mbpp/140": {"dps": 93.7888198757764, "dps_norm": 87.5, "pass@1": 100.0, "profiled": [{"solution": "def extract_singly(list_of_lists):\n \"\"\"\n Flattens a list of lists into a single set of unique numbers.\n\n Args:\n list_of_lists: A list of lists, where each inner list contains numbers.\n\n Returns:\n A set containing all the unique numbers from the input list of lists.\n \"\"\"\n flattened_list = []\n for inner_list in list_of_lists:\n flattened_list.extend(inner_list)\n return set(flattened_list)", "matching_cluster_idx": 6}, {"solution": "def extract_singly(list_of_lists):\n \"\"\"\n Flattens a list of lists into a set of unique numbers.\n\n Args:\n list_of_lists: A list of lists, where each inner list contains numbers.\n\n Returns:\n A set containing all the unique numbers from the input list of lists.\n \"\"\"\n flattened_list = []\n for inner_list in list_of_lists:\n flattened_list.extend(inner_list)\n return set(flattened_list)", "matching_cluster_idx": 6}, {"solution": "def extract_singly(list_of_lists):\n \"\"\"\n Flattens a list of lists into a set of unique numbers.\n\n Args:\n list_of_lists: A list of lists, where each inner list contains numbers.\n\n Returns:\n A set containing all the unique numbers from the input list of lists.\n \"\"\"\n flattened_list = []\n for inner_list in list_of_lists:\n flattened_list.extend(inner_list)\n return set(flattened_list)", "matching_cluster_idx": 6}, {"solution": "def extract_singly(list_of_lists):\n \"\"\"\n Flattens a list of lists into a set of unique numbers.\n\n Args:\n list_of_lists: A list of lists, where each inner list contains numbers.\n\n Returns:\n A set containing all the unique numbers from the input list of lists.\n \"\"\"\n flattened_list = []\n for inner_list in list_of_lists:\n flattened_list.extend(inner_list)\n return set(flattened_list)", "matching_cluster_idx": 6}, {"solution": "def extract_singly(list_of_lists):\n \"\"\"\n Flattens a list of lists into a set of unique numbers.\n\n Args:\n list_of_lists: A list of lists, where each inner list contains numbers.\n\n Returns:\n A set containing all the unique numbers from the input list of lists.\n \"\"\"\n flattened_list = []\n for inner_list in list_of_lists:\n flattened_list.extend(inner_list)\n return set(flattened_list)", "matching_cluster_idx": 6}, {"solution": "def extract_singly(list_of_lists):\n \"\"\"Flattens a list of lists into a set of unique numbers.\"\"\"\n flattened_list = []\n for inner_list in list_of_lists:\n flattened_list.extend(inner_list)\n return set(flattened_list)", "matching_cluster_idx": 6}, {"solution": "def extract_singly(list_of_lists):\n \"\"\"Flattens a list of lists into a set of unique numbers.\"\"\"\n flattened_list = []\n for inner_list in list_of_lists:\n flattened_list.extend(inner_list) #Add all elements of inner list to flattened list\n return set(flattened_list) #Convert to set to get unique numbers", "matching_cluster_idx": 6}, {"solution": "def extract_singly(list_of_lists):\n \"\"\"\n Flattens a list of lists into a single set of unique numbers.\n\n Args:\n list_of_lists: A list of lists, where each inner list contains numbers.\n\n Returns:\n A set containing all the unique numbers from the input list of lists.\n \"\"\"\n flattened_list = []\n for inner_list in list_of_lists:\n flattened_list.extend(inner_list)\n return set(flattened_list)", "matching_cluster_idx": 6}, {"solution": "def extract_singly(list_of_lists):\n \"\"\"Flattens a list of lists into a set of unique numbers.\"\"\"\n flattened_list = []\n for inner_list in list_of_lists:\n flattened_list.extend(inner_list)\n return set(flattened_list)", "matching_cluster_idx": 6}, {"solution": "def extract_singly(list_of_lists):\n \"\"\"Flattens a list of lists into a set of unique numbers.\"\"\"\n flattened_list = []\n for inner_list in list_of_lists:\n flattened_list.extend(inner_list) #Efficiently adds all items from inner list to flattened list.\n return set(flattened_list)", "matching_cluster_idx": 6}, {"solution": "def extract_singly(list_of_lists):\n \"\"\"\n Flattens a list of lists into a set of unique numbers.\n\n Args:\n list_of_lists: A list of lists, where each inner list contains numbers.\n\n Returns:\n A set containing all the unique numbers from the input list of lists.\n \"\"\"\n flattened_list = []\n for inner_list in list_of_lists:\n flattened_list.extend(inner_list) # Efficiently extends the list\n return set(flattened_list)", "matching_cluster_idx": 6}, {"solution": "def extract_singly(list_of_lists):\n \"\"\"\n Flattens a list of lists into a set of unique numbers.\n\n Args:\n list_of_lists: A list of lists, where each inner list contains numbers.\n\n Returns:\n A set containing all the unique numbers from the input list of lists.\n \"\"\"\n flattened_list = []\n for inner_list in list_of_lists:\n flattened_list.extend(inner_list)\n return set(flattened_list)", "matching_cluster_idx": 6}, {"solution": "def extract_singly(list_of_lists):\n \"\"\"Flattens a list of lists into a set of unique numbers.\"\"\"\n flat_list = []\n for inner_list in list_of_lists:\n flat_list.extend(inner_list)\n return set(flat_list)", "matching_cluster_idx": 6}, {"solution": "def extract_singly(list_of_lists):\n \"\"\"Flattens a list of lists into a set of unique numbers.\"\"\"\n flattened_list = []\n for inner_list in list_of_lists:\n flattened_list.extend(inner_list)\n return set(flattened_list)", "matching_cluster_idx": 6}, {"solution": "def extract_singly(list_of_lists):\n \"\"\"\n Flattens a list of lists into a single set of unique numbers.\n\n Args:\n list_of_lists: A list of lists, where each inner list contains numbers.\n\n Returns:\n A set containing all the unique numbers from the input list of lists.\n \"\"\"\n flattened_list = []\n for inner_list in list_of_lists:\n flattened_list.extend(inner_list)\n return set(flattened_list)", "matching_cluster_idx": 6}, {"solution": "def extract_singly(list_of_lists):\n \"\"\"\n Flattens a list of lists into a set of unique numbers.\n\n Args:\n list_of_lists: A list of lists, where each inner list contains numbers.\n\n Returns:\n A set containing all the unique numbers from the input list of lists.\n \"\"\"\n flattened_list = []\n for inner_list in list_of_lists:\n flattened_list.extend(inner_list)\n return set(flattened_list)", "matching_cluster_idx": 6}, {"solution": "def extract_singly(list_of_lists):\n \"\"\"\n Flattens a list of lists into a set of unique numbers.\n\n Args:\n list_of_lists: A list of lists, where each inner list contains numbers.\n\n Returns:\n A set containing all the unique numbers from the input list of lists.\n \"\"\"\n flattened_list = []\n for inner_list in list_of_lists:\n flattened_list.extend(inner_list)\n return set(flattened_list)", "matching_cluster_idx": 6}, {"solution": "def extract_singly(list_of_lists):\n \"\"\"\n Flattens a list of lists into a set of unique numbers.\n\n Args:\n list_of_lists: A list of lists, where each inner list contains numbers.\n\n Returns:\n A set containing all the unique numbers from the input list of lists.\n \"\"\"\n flattened_list = []\n for inner_list in list_of_lists:\n flattened_list.extend(inner_list)\n return set(flattened_list)", "matching_cluster_idx": 6}, {"solution": "def extract_singly(list_of_lists):\n \"\"\"\n Flattens a list of lists into a set of unique numbers.\n\n Args:\n list_of_lists: A list of lists, where each inner list contains numbers.\n\n Returns:\n A set containing all unique numbers from the input list of lists.\n \"\"\"\n flattened_list = []\n for inner_list in list_of_lists:\n flattened_list.extend(inner_list) #Efficiently adds elements of inner list to the flattened list\n return set(flattened_list)", "matching_cluster_idx": 6}, {"solution": "def extract_singly(list_of_lists):\n \"\"\"\n Flattens a list of lists into a set of unique numbers.\n\n Args:\n list_of_lists: A list of lists, where each inner list contains numbers.\n\n Returns:\n A set containing all the unique numbers from the input list of lists.\n \"\"\"\n flattened_list = []\n for inner_list in list_of_lists:\n flattened_list.extend(inner_list) #Efficiently adds all elements of inner list to flattened list\n return set(flattened_list)", "matching_cluster_idx": 6}]}, "Mbpp/141": {"dps": 52.6077097505669, "dps_norm": 37.5, "pass@1": 69.0, "profiled": [{"solution": "def pancake_sort(arr):\n \"\"\"\n Sorts a list of elements using the pancake sorting algorithm.\n\n Args:\n arr: The list of elements to be sorted.\n\n Returns:\n The sorted list.\n \"\"\"\n n = len(arr)\n for i in range(n - 1, 0, -1):\n # Find the index of the maximum element in the subarray arr[0...i]\n max_index = 0\n for j in range(1, i + 1):\n if arr[j] > arr[max_index]:\n max_index = j\n\n # Flip the subarray arr[0...max_index] to bring the maximum element to the beginning\n arr[:max_index+1] = arr[:max_index+1][::-1]\n\n # Flip the subarray arr[0...i] to move the maximum element to its correct position\n arr[:i+1] = arr[:i+1][::-1]\n return arr", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(arr):\n \"\"\"\n Sorts a list of elements using the pancake sorting algorithm.\n\n Args:\n arr: The list of elements to be sorted.\n\n Returns:\n The sorted list.\n \"\"\"\n n = len(arr)\n for i in range(n - 1, 0, -1):\n # Find the index of the maximum element in the subarray arr[0...i]\n max_index = 0\n for j in range(1, i + 1):\n if arr[j] > arr[max_index]:\n max_index = j\n\n # Flip the subarray arr[0...max_index] to move the maximum element to the beginning\n arr[:max_index+1] = arr[:max_index+1][::-1]\n\n # Flip the subarray arr[0...i] to move the maximum element to its correct position\n arr[:i+1] = arr[:i+1][::-1]\n return arr", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(arr):\n \"\"\"\n Sorts a list of elements using the pancake sorting algorithm.\n\n Args:\n arr: The list of elements to be sorted.\n\n Returns:\n A new list containing the sorted elements.\n \"\"\"\n n = len(arr)\n arr_copy = arr[:] # Create a copy to avoid modifying the original list\n\n for i in range(n - 1, 0, -1):\n # Find the index of the maximum element in the subarray arr[0...i]\n max_index = 0\n for j in range(1, i + 1):\n if arr_copy[j] > arr_copy[max_index]:\n max_index = j\n\n # Flip the subarray arr[0...max_index] to bring the maximum element to the beginning\n arr_copy[:max_index+1] = arr_copy[:max_index+1][::-1]\n\n # Flip the subarray arr[0...i] to bring the maximum element to its correct position\n arr_copy[:i+1] = arr_copy[:i+1][::-1]\n\n return arr_copy", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(arr):\n \"\"\"Sorts a list using the pancake sorting algorithm.\n\n Args:\n arr: The list to be sorted.\n\n Returns:\n The sorted list.\n \"\"\"\n n = len(arr)\n for i in range(n - 1, 0, -1):\n # Find the index of the maximum element in the subarray arr[0...i]\n max_index = 0\n for j in range(1, i + 1):\n if arr[j] > arr[max_index]:\n max_index = j\n\n # Flip the subarray arr[0...max_index] to move the maximum element to the beginning\n arr[:max_index + 1] = arr[:max_index + 1][::-1]\n\n # Flip the subarray arr[0...i] to move the maximum element to its correct position\n arr[:i + 1] = arr[:i + 1][::-1]\n return arr", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(arr):\n \"\"\"\n Sorts a list of elements using the pancake sorting algorithm.\n\n Args:\n arr: The list of elements to sort.\n\n Returns:\n A new list containing the sorted elements.\n \"\"\"\n\n n = len(arr)\n arr_copy = arr[:] # Create a copy to avoid modifying the original list\n\n def flip(arr, k):\n \"\"\"Flips the first k elements of the array.\"\"\"\n arr[:k] = arr[:k][::-1]\n\n for i in range(n - 1, 0, -1):\n max_index = 0\n for j in range(1, i + 1):\n if arr_copy[j] > arr_copy[max_index]:\n max_index = j\n\n if max_index != i:\n flip(arr_copy, max_index + 1)\n flip(arr_copy, i + 1)\n\n return arr_copy", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(arr):\n \"\"\"\n Sorts a list of elements using the pancake sorting algorithm.\n\n Args:\n arr: The list of elements to be sorted.\n\n Returns:\n The sorted list.\n \"\"\"\n n = len(arr)\n for i in range(n - 1, 0, -1):\n # Find the index of the maximum element in the subarray arr[:i+1]\n max_index = 0\n for j in range(1, i + 1):\n if arr[j] > arr[max_index]:\n max_index = j\n\n # Flip the subarray to bring the maximum element to the beginning\n arr[:max_index + 1] = arr[:max_index + 1][::-1]\n\n # Flip the entire subarray to move the maximum element to its correct position\n arr[:i + 1] = arr[:i + 1][::-1]\n\n return arr", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(arr):\n \"\"\"\n Sorts a list of integers using the pancake sorting algorithm.\n\n Args:\n arr: A list of integers.\n\n Returns:\n A new list containing the sorted elements.\n \"\"\"\n\n n = len(arr)\n arr_copy = arr[:] # Create a copy to avoid modifying the original list\n\n def flip(arr, k):\n \"\"\"Flips the first k elements of the array.\"\"\"\n left, right = 0, k - 1\n while left < right:\n arr[left], arr[right] = arr[right], arr[left]\n left += 1\n right -= 1\n\n for i in range(n, 0, -1):\n # Find the index of the maximum element in the first i elements\n max_index = 0\n for j in range(1, i):\n if arr_copy[j] > arr_copy[max_index]:\n max_index = j\n\n # Flip to bring the maximum element to the beginning\n flip(arr_copy, max_index + 1)\n\n # Flip to move the maximum element to its correct position\n flip(arr_copy, i)\n\n return arr_copy", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(arr):\n \"\"\"\n Sorts a list of elements using the pancake sorting algorithm.\n\n Args:\n arr: The list of elements to be sorted.\n\n Returns:\n The sorted list.\n \"\"\"\n n = len(arr)\n for i in range(n - 1, 0, -1):\n # Find the index of the maximum element in the subarray arr[0...i]\n max_index = 0\n for j in range(1, i + 1):\n if arr[j] > arr[max_index]:\n max_index = j\n\n # Flip the subarray arr[0...max_index] to bring the maximum element to the beginning\n arr[:max_index + 1] = arr[:max_index + 1][::-1]\n\n # Flip the subarray arr[0...i] to move the maximum element to its correct position\n arr[:i + 1] = arr[:i + 1][::-1]\n\n return arr", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(arr):\n \"\"\"\n Sorts a list of elements using the pancake sorting algorithm.\n\n Args:\n arr: The list of elements to be sorted.\n\n Returns:\n A new list containing the sorted elements.\n \"\"\"\n\n n = len(arr)\n arr_copy = arr[:] # Create a copy to avoid modifying the original list\n\n for i in range(n - 1, 0, -1):\n # Find the index of the maximum element in the subarray arr[:i+1]\n max_index = 0\n for j in range(1, i + 1):\n if arr_copy[j] > arr_copy[max_index]:\n max_index = j\n\n # Flip the subarray to bring the maximum element to the beginning\n arr_copy[:max_index + 1] = arr_copy[:max_index + 1][::-1]\n\n # Flip the entire subarray to move the maximum element to its correct position\n arr_copy[:i + 1] = arr_copy[:i + 1][::-1]\n\n return arr_copy", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(arr):\n \"\"\"Sorts a list using the pancake sorting algorithm.\n\n Args:\n arr: The list to be sorted.\n\n Returns:\n A new list containing the sorted elements.\n \"\"\"\n\n arr_copy = arr[:] # Create a copy to avoid modifying the original list\n\n def flip(arr, k):\n \"\"\"Flips the first k elements of the list.\"\"\"\n arr[:k] = arr[:k][::-1]\n\n n = len(arr_copy)\n for i in range(n - 1, 0, -1):\n # Find the index of the maximum element in the subarray\n max_index = 0\n for j in range(1, i + 1):\n if arr_copy[j] > arr_copy[max_index]:\n max_index = j\n\n # Flip to bring the maximum element to the beginning\n flip(arr_copy, max_index + 1)\n\n # Flip to move the maximum element to its correct position\n flip(arr_copy, i + 1)\n\n return arr_copy", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(arr):\n \"\"\"\n Sorts a list of elements using the pancake sorting algorithm.\n\n Args:\n arr: The list of elements to sort.\n\n Returns:\n The sorted list.\n \"\"\"\n n = len(arr)\n for i in range(n - 1, 0, -1):\n # Find the index of the maximum element in the subarray arr[0...i]\n max_index = 0\n for j in range(1, i + 1):\n if arr[j] > arr[max_index]:\n max_index = j\n\n # Flip the subarray arr[0...max_index] to move the maximum element to the beginning\n arr[:max_index + 1] = arr[:max_index + 1][::-1]\n\n # Flip the subarray arr[0...i] to move the maximum element to its correct position\n arr[:i + 1] = arr[:i + 1][::-1]\n\n return arr", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(arr):\n \"\"\"\n Sorts a list of elements using the pancake sorting algorithm.\n\n Args:\n arr: The list of elements to be sorted.\n\n Returns:\n A new list containing the sorted elements.\n \"\"\"\n\n n = len(arr)\n arr_copy = arr[:] # Create a copy to avoid modifying the original list\n\n def flip(arr, k):\n \"\"\"Flips the first k elements of the array.\"\"\"\n left, right = 0, k - 1\n while left < right:\n arr[left], arr[right] = arr[right], arr[left]\n left += 1\n right -= 1\n\n for i in range(n - 1, 0, -1):\n max_index = 0\n for j in range(1, i + 1):\n if arr_copy[j] > arr_copy[max_index]:\n max_index = j\n\n if max_index != i:\n flip(arr_copy, max_index + 1)\n flip(arr_copy, i + 1)\n\n return arr_copy", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(arr):\n \"\"\"\n Sorts a list using the pancake sorting algorithm.\n\n Args:\n arr: The list to be sorted.\n\n Returns:\n The sorted list.\n \"\"\"\n n = len(arr)\n for i in range(n - 1, 0, -1):\n # Find the index of the maximum element in the subarray [0, i]\n max_index = 0\n for j in range(1, i + 1):\n if arr[j] > arr[max_index]:\n max_index = j\n\n # Flip the subarray [0, max_index] to bring the maximum element to the beginning\n arr[:max_index + 1] = arr[:max_index + 1][::-1]\n\n # Flip the subarray [0, i] to move the maximum element to its correct position\n arr[:i + 1] = arr[:i + 1][::-1]\n\n return arr", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(arr):\n \"\"\"Sorts a list using the pancake sorting algorithm.\n\n Args:\n arr: The list to be sorted.\n\n Returns:\n The sorted list.\n \"\"\"\n n = len(arr)\n for i in range(n - 1, 0, -1):\n # Find the index of the maximum element in the subarray arr[:i+1]\n max_index = 0\n for j in range(1, i + 1):\n if arr[j] > arr[max_index]:\n max_index = j\n\n # Flip the subarray to bring the maximum element to the beginning\n arr[:max_index + 1] = arr[:max_index + 1][::-1]\n\n # Flip the subarray to move the maximum element to its correct position\n arr[:i + 1] = arr[:i + 1][::-1]\n\n return arr", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(arr):\n \"\"\"\n Sorts a list of elements using the pancake sorting algorithm.\n\n Args:\n arr: The list of elements to sort.\n\n Returns:\n A new list containing the sorted elements.\n \"\"\"\n\n n = len(arr)\n arr_copy = arr[:] # Create a copy to avoid modifying the original list\n\n for i in range(n - 1, 0, -1):\n # Find the index of the maximum element in the subarray arr[:i+1]\n max_index = 0\n for j in range(1, i + 1):\n if arr_copy[j] > arr_copy[max_index]:\n max_index = j\n\n # Flip the subarray to bring the maximum element to the beginning\n arr_copy[:max_index + 1] = arr_copy[:max_index + 1][::-1]\n\n # Flip the subarray again to move the maximum element to its correct position\n arr_copy[:i + 1] = arr_copy[:i + 1][::-1]\n\n return arr_copy", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(arr):\n \"\"\"\n Sorts a list of elements using the pancake sorting algorithm.\n\n Args:\n arr: The list of elements to be sorted.\n\n Returns:\n A new list containing the sorted elements.\n \"\"\"\n\n n = len(arr)\n arr_copy = arr[:] # Create a copy to avoid modifying the original list\n\n def flip(arr, k):\n \"\"\"Flips the first k elements of the list.\"\"\"\n arr[:k] = arr[:k][::-1]\n\n for i in range(n - 1, 0, -1):\n # Find the maximum element in the subarray arr[0...i]\n max_index = 0\n for j in range(1, i + 1):\n if arr_copy[j] > arr_copy[max_index]:\n max_index = j\n\n # Flip the subarray to bring the maximum element to the beginning\n flip(arr_copy, max_index + 1)\n\n # Flip the subarray to move the maximum element to its correct position\n flip(arr_copy, i + 1)\n\n return arr_copy", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(arr):\n \"\"\"Sorts a list using the pancake sorting algorithm.\n\n Args:\n arr: The list to be sorted.\n\n Returns:\n The sorted list.\n \"\"\"\n n = len(arr)\n for i in range(n - 1, 0, -1):\n # Find the index of the maximum element in the subarray arr[0...i]\n max_index = 0\n for j in range(1, i + 1):\n if arr[j] > arr[max_index]:\n max_index = j\n\n # Flip the subarray arr[0...max_index] to move the maximum element to the beginning\n arr[:max_index+1] = arr[:max_index+1][::-1]\n\n # Flip the subarray arr[0...i] to move the maximum element to its correct position\n arr[:i+1] = arr[:i+1][::-1]\n\n return arr", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(arr):\n \"\"\"Sorts a list using the pancake sorting algorithm.\n\n Args:\n arr: The list to be sorted.\n\n Returns:\n The sorted list.\n \"\"\"\n n = len(arr)\n for i in range(n - 1, 0, -1):\n # Find the index of the maximum element in the subarray arr[0...i]\n max_index = 0\n for j in range(1, i + 1):\n if arr[j] > arr[max_index]:\n max_index = j\n\n # Flip the subarray arr[0...max_index] to move the maximum element to the beginning\n arr[:max_index + 1] = arr[:max_index + 1][::-1]\n\n # Flip the subarray arr[0...i] to move the maximum element to its correct position\n arr[:i + 1] = arr[:i + 1][::-1]\n return arr\narr = [15, 79, 25, 38, 69]", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(arr):\n \"\"\"\n Sorts a list of elements using the pancake sorting algorithm.\n\n Args:\n arr: The list of elements to be sorted.\n\n Returns:\n A new list containing the sorted elements.\n \"\"\"\n\n n = len(arr)\n arr_copy = arr[:] # Create a copy to avoid modifying the original list\n\n for i in range(n - 1, 0, -1):\n # Find the index of the maximum element in the subarray arr[:i+1]\n max_index = 0\n for j in range(1, i + 1):\n if arr_copy[j] > arr_copy[max_index]:\n max_index = j\n\n # Flip the subarray to bring the maximum element to the beginning\n arr_copy[:max_index + 1] = arr_copy[:max_index + 1][::-1]\n\n # Flip the entire subarray to move the maximum element to its correct position\n arr_copy[:i + 1] = arr_copy[:i + 1][::-1]\n\n return arr_copy", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(arr):\n \"\"\"\n Sorts a list of elements using the pancake sorting algorithm.\n\n Args:\n arr: The list of elements to sort.\n\n Returns:\n The sorted list of elements.\n \"\"\"\n n = len(arr)\n for i in range(n - 1, 0, -1):\n # Find the index of the maximum element in the subarray arr[0...i]\n max_index = 0\n for j in range(1, i + 1):\n if arr[j] > arr[max_index]:\n max_index = j\n\n # Flip the subarray arr[0...max_index] to move the maximum element to the beginning\n arr[:max_index + 1] = arr[:max_index + 1][::-1]\n\n # Flip the subarray arr[0...i] to move the maximum element to its correct position\n arr[:i + 1] = arr[:i + 1][::-1]\n\n return arr", "matching_cluster_idx": 2}]}, "Mbpp/166": {"dps": 94.39999999999999, "dps_norm": 50.0, "pass@1": 100.0, "profiled": [{"solution": "def find_even_pair(nums):\n \"\"\"\n Counts the number of pairs of integers in a list that XOR to an even number.\n\n Args:\n nums: A list of integers.\n\n Returns:\n The number of pairs that XOR to an even number.\n \"\"\"\n count = 0\n n = len(nums)\n for i in range(n):\n for j in range(i + 1, n):\n if (nums[i] ^ nums[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(nums):\n \"\"\"\n Counts the number of pairs of integers in a list that XOR to an even number.\n\n Args:\n nums: A list of integers.\n\n Returns:\n The number of pairs that XOR to an even number.\n \"\"\"\n count = 0\n n = len(nums)\n for i in range(n):\n for j in range(i + 1, n):\n if (nums[i] ^ nums[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(nums):\n \"\"\"\n Counts the number of pairs of integers in a list that XOR to an even number.\n\n Args:\n nums: A list of integers.\n\n Returns:\n The number of pairs that XOR to an even number.\n \"\"\"\n count = 0\n n = len(nums)\n for i in range(n):\n for j in range(i + 1, n):\n if (nums[i] ^ nums[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(nums):\n \"\"\"\n Counts the number of pairs of integers in a list that XOR to an even number.\n\n Args:\n nums: A list of integers.\n\n Returns:\n The number of pairs of integers in the list that XOR to an even number.\n \"\"\"\n count = 0\n n = len(nums)\n for i in range(n):\n for j in range(i + 1, n):\n if (nums[i] ^ nums[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(nums):\n \"\"\"\n Counts the number of pairs of integers in a list that XOR to an even number.\n\n Args:\n nums: A list of integers.\n\n Returns:\n The number of pairs that XOR to an even number.\n \"\"\"\n count = 0\n n = len(nums)\n for i in range(n):\n for j in range(i + 1, n):\n if (nums[i] ^ nums[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(nums):\n \"\"\"\n Counts the number of pairs of integers in a list that XOR to an even number.\n\n Args:\n nums: A list of integers.\n\n Returns:\n The number of pairs that XOR to an even number.\n \"\"\"\n count = 0\n n = len(nums)\n for i in range(n):\n for j in range(i + 1, n):\n if (nums[i] ^ nums[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(nums):\n \"\"\"\n Counts the number of pairs of integers in a list that XOR to an even number.\n\n Args:\n nums: A list of integers.\n\n Returns:\n The number of pairs that XOR to an even number.\n \"\"\"\n count = 0\n n = len(nums)\n for i in range(n):\n for j in range(i + 1, n):\n if (nums[i] ^ nums[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(nums):\n \"\"\"\n Counts the number of pairs of integers in a list that XOR to an even number.\n\n Args:\n nums: A list of integers.\n\n Returns:\n The number of pairs of integers in the list that XOR to an even number.\n \"\"\"\n count = 0\n n = len(nums)\n for i in range(n):\n for j in range(i + 1, n):\n if (nums[i] ^ nums[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(nums):\n \"\"\"\n Counts the number of pairs of integers in a list that XOR to an even number.\n\n Args:\n nums: A list of integers.\n\n Returns:\n The number of pairs that XOR to an even number.\n \"\"\"\n count = 0\n n = len(nums)\n for i in range(n):\n for j in range(i + 1, n):\n if (nums[i] ^ nums[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(nums):\n \"\"\"\n Counts the number of pairs of integers in a list that xor to an even number.\n\n Args:\n nums: A list of integers.\n\n Returns:\n The number of pairs of integers in the list that xor to an even number.\n \"\"\"\n count = 0\n n = len(nums)\n for i in range(n):\n for j in range(i + 1, n):\n if (nums[i] ^ nums[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(nums):\n \"\"\"\n Counts the number of pairs of integers in a list that XOR to an even number.\n\n Args:\n nums: A list of integers.\n\n Returns:\n The number of pairs of integers in the list that XOR to an even number.\n \"\"\"\n count = 0\n n = len(nums)\n for i in range(n):\n for j in range(i + 1, n):\n if (nums[i] ^ nums[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(nums):\n \"\"\"\n Counts the number of pairs of integers in a list that XOR to an even number.\n\n Args:\n nums: A list of integers.\n\n Returns:\n The number of pairs that XOR to an even number.\n \"\"\"\n count = 0\n n = len(nums)\n for i in range(n):\n for j in range(i + 1, n):\n if (nums[i] ^ nums[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(nums):\n \"\"\"\n Counts the number of pairs of integers in a list that XOR to an even number.\n\n Args:\n nums: A list of integers.\n\n Returns:\n The number of pairs that XOR to an even number.\n \"\"\"\n count = 0\n n = len(nums)\n for i in range(n):\n for j in range(i + 1, n):\n if (nums[i] ^ nums[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(nums):\n \"\"\"\n Counts the number of pairs of integers in a list that XOR to an even number.\n\n Args:\n nums: A list of integers.\n\n Returns:\n The number of pairs of integers in the list that XOR to an even number.\n \"\"\"\n count = 0\n n = len(nums)\n for i in range(n):\n for j in range(i + 1, n):\n if (nums[i] ^ nums[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(nums):\n \"\"\"\n Counts the number of pairs of integers in a list that XOR to an even number.\n\n Args:\n nums: A list of integers.\n\n Returns:\n The number of pairs that XOR to an even number.\n \"\"\"\n count = 0\n n = len(nums)\n for i in range(n):\n for j in range(i + 1, n):\n if (nums[i] ^ nums[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(nums):\n \"\"\"\n Counts the number of pairs of integers in a list that XOR to an even number.\n\n Args:\n nums: A list of integers.\n\n Returns:\n The number of pairs that XOR to an even number.\n \"\"\"\n count = 0\n n = len(nums)\n for i in range(n):\n for j in range(i + 1, n):\n if (nums[i] ^ nums[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(nums):\n \"\"\"\n Counts the number of pairs of integers in a list that XOR to an even number.\n\n Args:\n nums: A list of integers.\n\n Returns:\n The number of pairs that XOR to an even number.\n \"\"\"\n count = 0\n n = len(nums)\n for i in range(n):\n for j in range(i + 1, n):\n if (nums[i] ^ nums[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(nums):\n \"\"\"\n Counts the number of pairs of integers in a list that XOR to an even number.\n\n Args:\n nums: A list of integers.\n\n Returns:\n The number of pairs that XOR to an even number.\n \"\"\"\n count = 0\n n = len(nums)\n for i in range(n):\n for j in range(i + 1, n):\n if (nums[i] ^ nums[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(nums):\n \"\"\"\n Counts the number of pairs of integers in a list that XOR to an even number.\n\n Args:\n nums: A list of integers.\n\n Returns:\n The number of pairs that XOR to an even number.\n \"\"\"\n count = 0\n n = len(nums)\n for i in range(n):\n for j in range(i + 1, n):\n if (nums[i] ^ nums[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(nums):\n \"\"\"\n Counts the number of pairs of integers in a list that XOR to an even number.\n\n Args:\n nums: A list of integers.\n\n Returns:\n The number of pairs that XOR to an even number.\n \"\"\"\n count = 0\n n = len(nums)\n for i in range(n):\n for j in range(i + 1, n):\n if (nums[i] ^ nums[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}]}, "Mbpp/170": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 67.0, "profiled": [{"solution": "def sum_range_list(data, start_index, end_index):\n \"\"\"\n Calculates the sum of elements in a list within a specified range of indices.\n\n Args:\n data: The input list of numbers.\n start_index: The starting index (inclusive).\n end_index: The ending index (inclusive).\n\n Returns:\n The sum of the numbers within the specified range. Returns 0 if the input list is empty or indices are invalid.\n \"\"\"\n if not data or start_index < 0 or end_index >= len(data) or start_index > end_index:\n return 0\n return sum(data[start_index : end_index+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(data, start_index, end_index):\n \"\"\"\n Calculates the sum of numbers in a list within a specified range of indices.\n\n Args:\n data: A list of numbers.\n start_index: The starting index (inclusive).\n end_index: The ending index (inclusive).\n\n Returns:\n The sum of numbers within the specified range. Returns 0 if the input list is empty or indices are out of bounds.\n \"\"\"\n if not data or start_index < 0 or end_index >= len(data) or start_index > end_index:\n return 0\n return sum(data[start_index:end_index+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(data, start_index, end_index):\n \"\"\"\n Calculates the sum of numbers in a list within a specified range.\n\n Args:\n data: The input list of numbers.\n start_index: The starting index (inclusive).\n end_index: The ending index (inclusive).\n\n Returns:\n The sum of numbers within the specified range. Returns 0 if the input list is empty or indices are invalid.\n \"\"\"\n if not data or start_index < 0 or end_index >= len(data) or start_index > end_index:\n return 0 # Handle empty list or invalid indices\n return sum(data[start_index:end_index+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(data, start_index, end_index):\n \"\"\"\n Calculates the sum of numbers in a list within a specified range of indices.\n\n Args:\n data: The input list of numbers.\n start_index: The starting index of the range (inclusive).\n end_index: The ending index of the range (inclusive).\n\n Returns:\n The sum of numbers within the specified range. Returns 0 if the input list is empty or indices are out of bounds.\n \"\"\"\n if not data or start_index < 0 or end_index >= len(data) or start_index > end_index:\n return 0\n return sum(data[start_index : end_index+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(data, start_index, end_index):\n \"\"\"\n Calculates the sum of numbers in a list within a specified range of indices.\n\n Args:\n data: The input list of numbers.\n start_index: The starting index of the range (inclusive).\n end_index: The ending index of the range (inclusive).\n\n Returns:\n The sum of the numbers within the specified range. Returns 0 if the input list is empty or indices are invalid.\n \"\"\"\n if not data or start_index < 0 or end_index >= len(data) or start_index > end_index:\n return 0 #Handle empty list or invalid indices\n\n return sum(data[start_index : end_index+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(data, start_index, end_index):\n \"\"\"\n Calculates the sum of numbers in a list within a specified range of indices.\n\n Args:\n data: A list of numbers.\n start_index: The starting index (inclusive).\n end_index: The ending index (inclusive).\n\n Returns:\n The sum of the numbers within the specified range. Returns 0 if the input list is empty or indices are invalid.\n\n \"\"\"\n if not data or start_index < 0 or end_index >= len(data) or start_index > end_index:\n return 0\n return sum(data[start_index : end_index+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(data, start_index, end_index):\n \"\"\"\n Calculates the sum of numbers in a list within a specified range.\n\n Args:\n data: The input list of numbers.\n start_index: The starting index (inclusive).\n end_index: The ending index (inclusive).\n\n Returns:\n The sum of numbers within the specified range. Returns 0 if the input list is empty or indices are invalid.\n\n \"\"\"\n if not data or start_index < 0 or end_index >= len(data) or start_index > end_index:\n return 0 # Handle empty list or invalid indices\n \n return sum(data[start_index : end_index+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(data, start_index, end_index):\n \"\"\"\n Calculates the sum of numbers in a list within a specified range of indices.\n\n Args:\n data: The input list of numbers.\n start_index: The starting index (inclusive).\n end_index: The ending index (inclusive).\n\n Returns:\n The sum of numbers within the specified range. Returns 0 if the input list is empty or indices are out of bounds.\n\n \"\"\"\n if not data or start_index < 0 or end_index >= len(data) or start_index > end_index:\n return 0\n\n return sum(data[start_index : end_index + 1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(data, start_index, end_index):\n \"\"\"\n Calculates the sum of numbers in a list within a specified range of indices.\n\n Args:\n data: A list of numbers.\n start_index: The starting index (inclusive).\n end_index: The ending index (inclusive).\n\n Returns:\n The sum of the numbers within the specified range. Returns 0 if the input list is empty or indices are invalid.\n \"\"\"\n if not data or start_index < 0 or end_index >= len(data) or start_index > end_index:\n return 0\n return sum(data[start_index : end_index+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(data, start_index, end_index):\n \"\"\"\n Calculates the sum of numbers in a list within a specified range of indices.\n\n Args:\n data: The input list of numbers.\n start_index: The starting index (inclusive).\n end_index: The ending index (inclusive).\n\n Returns:\n The sum of numbers within the specified range. Returns 0 if the list is empty or indices are invalid.\n\n \"\"\"\n if not data or start_index < 0 or end_index >= len(data) or start_index > end_index:\n return 0\n return sum(data[start_index:end_index+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(data, start_index, end_index):\n \"\"\"\n Calculates the sum of numbers in a list within a specified range of indices.\n\n Args:\n data: The input list of numbers.\n start_index: The starting index (inclusive) of the range.\n end_index: The ending index (inclusive) of the range.\n\n Returns:\n The sum of the numbers within the specified range. Returns 0 if the input list is empty or the indices are out of range.\n\n \"\"\"\n if not data or start_index < 0 or end_index >= len(data) or start_index > end_index:\n return 0 # Handle empty list or invalid indices\n\n return sum(data[start_index : end_index+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(data, start_index, end_index):\n \"\"\"\n Calculates the sum of numbers in a list within a specified range of indices.\n\n Args:\n data: The input list of numbers.\n start_index: The starting index (inclusive) of the range.\n end_index: The ending index (inclusive) of the range.\n\n Returns:\n The sum of the numbers within the specified range. Returns 0 if the input list is empty or indices are out of bounds.\n\n \"\"\"\n if not data or start_index < 0 or end_index >= len(data) or start_index > end_index:\n return 0\n return sum(data[start_index : end_index+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(data, start_index, end_index):\n \"\"\"\n Calculates the sum of numbers in a list within a specified range.\n\n Args:\n data: The input list of numbers.\n start_index: The starting index (inclusive) of the range.\n end_index: The ending index (inclusive) of the range.\n\n Returns:\n The sum of the numbers within the specified range. Returns 0 if the input list is empty or the indices are invalid.\n \"\"\"\n if not data or start_index < 0 or end_index >= len(data) or start_index > end_index:\n return 0\n return sum(data[start_index : end_index+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(data, start_index, end_index):\n \"\"\"\n Calculates the sum of numbers in a list within a specified range of indices.\n\n Args:\n data: A list of numbers.\n start_index: The starting index (inclusive).\n end_index: The ending index (inclusive).\n\n Returns:\n The sum of the numbers within the specified range. Returns 0 if the input list is empty or indices are invalid.\n \"\"\"\n if not data or start_index < 0 or end_index >= len(data) or start_index > end_index:\n return 0\n return sum(data[start_index : end_index+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(data, start_index, end_index):\n \"\"\"\n Finds the sum of numbers in a list within a specified range of indices.\n\n Args:\n data: The input list of numbers.\n start_index: The starting index (inclusive).\n end_index: The ending index (inclusive).\n\n Returns:\n The sum of numbers within the specified range. Returns 0 if the input list is empty or indices are invalid.\n\n \"\"\"\n if not data or start_index < 0 or end_index >= len(data) or start_index > end_index:\n return 0\n return sum(data[start_index:end_index+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(data, start_index, end_index):\n \"\"\"\n Calculates the sum of numbers in a list within a specified range of indices.\n\n Args:\n data: A list of numbers.\n start_index: The starting index (inclusive).\n end_index: The ending index (inclusive).\n\n Returns:\n The sum of the numbers within the specified range. Returns 0 if the input list is empty or indices are invalid.\n \"\"\"\n if not data or start_index < 0 or end_index >= len(data) or start_index > end_index:\n return 0 # Handle empty list or invalid indices\n\n return sum(data[start_index : end_index + 1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(data, start_index, end_index):\n \"\"\"\n Calculates the sum of numbers in a list within a specified range of indices.\n\n Args:\n data: The input list of numbers.\n start_index: The starting index (inclusive).\n end_index: The ending index (inclusive).\n\n Returns:\n The sum of numbers within the specified range. Returns 0 if the input list is empty or the indices are invalid.\n \"\"\"\n if not data or start_index < 0 or end_index >= len(data) or start_index > end_index:\n return 0 # Handle empty list or invalid indices\n\n return sum(data[start_index : end_index+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(data, start_index, end_index):\n \"\"\"\n Calculates the sum of numbers in a list within a specified range of indices.\n\n Args:\n data: The input list of numbers.\n start_index: The starting index (inclusive).\n end_index: The ending index (inclusive).\n\n Returns:\n The sum of numbers within the specified range. Returns 0 if the input list is empty or indices are out of range.\n \"\"\"\n if not data or start_index < 0 or end_index >= len(data) or start_index > end_index:\n return 0 #Handle empty list or invalid indices\n\n return sum(data[start_index : end_index + 1])\ndata = [2,1,5,6,8,3,4,9,10,11,8,12]\nstart_index = 8\nend_index = 10", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(data, start_index, end_index):\n \"\"\"\n Calculates the sum of numbers in a list within a specified range.\n\n Args:\n data: A list of numbers.\n start_index: The starting index (inclusive).\n end_index: The ending index (inclusive).\n\n Returns:\n The sum of numbers within the specified range. Returns 0 if the list is empty or indices are invalid.\n \"\"\"\n if not data or start_index < 0 or end_index >= len(data) or start_index > end_index:\n return 0 # Handle empty list or invalid indices\n return sum(data[start_index : end_index+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(data, start_index, end_index):\n \"\"\"\n Calculates the sum of numbers in a list within a specified range of indices.\n\n Args:\n data: The input list of numbers.\n start_index: The starting index (inclusive).\n end_index: The ending index (inclusive).\n\n Returns:\n The sum of numbers within the specified range. Returns 0 if the input list is empty or indices are invalid.\n\n \"\"\"\n if not data or start_index < 0 or end_index >= len(data) or start_index > end_index:\n return 0\n return sum(data[start_index : end_index+1])", "matching_cluster_idx": 7}]}, "Mbpp/226": {"dps": 68.21705426356588, "dps_norm": 14.285714285714286, "pass@1": 100.0, "profiled": [{"solution": "def odd_values_string(input_string):\n \"\"\"\n Removes characters at odd indices from a string.\n\n Args:\n input_string: The input string.\n\n Returns:\n A new string with characters at odd indices removed. Returns an empty string if the input is None or empty.\n \"\"\"\n if not input_string:\n return \"\"\n result = \"\"\n for i in range(len(input_string)):\n if i % 2 == 0:\n result += input_string[i]\n return result", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(input_string):\n \"\"\"\n Removes characters at odd indices from a string.\n\n Args:\n input_string: The input string.\n\n Returns:\n A new string with characters at odd indices removed. Returns an empty string if the input is None or empty.\n \"\"\"\n if not input_string:\n return \"\"\n result = \"\"\n for i in range(len(input_string)):\n if i % 2 == 0:\n result += input_string[i]\n return result", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(input_string):\n \"\"\"\n Removes characters at odd indices from a string.\n\n Args:\n input_string: The input string.\n\n Returns:\n A new string with characters at odd indices removed.\n \"\"\"\n result = \"\"\n for i in range(len(input_string)):\n if i % 2 == 0: # Check if index is even\n result += input_string[i]\n return result", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(input_string):\n \"\"\"\n Removes characters at odd indices from a string.\n\n Args:\n input_string: The input string.\n\n Returns:\n A new string with characters at odd indices removed. Returns an empty string if the input is None or empty.\n \"\"\"\n if not input_string:\n return \"\"\n result = \"\"\n for i in range(len(input_string)):\n if i % 2 == 0:\n result += input_string[i]\n return result", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(input_string):\n \"\"\"Removes characters at odd indices from a string.\n\n Args:\n input_string: The input string.\n\n Returns:\n A new string with characters at odd indices removed. Returns an empty string if the input is invalid.\n \"\"\"\n if not isinstance(input_string, str):\n return \"\" #Handle non-string input gracefully\n\n result = \"\"\n for i in range(len(input_string)):\n if i % 2 == 0: #Check if index is even\n result += input_string[i]\n return result", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(input_string):\n \"\"\"\n Removes characters from a string that have odd indices.\n\n Args:\n input_string: The input string.\n\n Returns:\n A new string with characters at odd indices removed. Returns an empty string if the input is None or empty.\n \"\"\"\n if not input_string:\n return \"\"\n result = \"\"\n for i in range(len(input_string)):\n if i % 2 == 0: # Check if index is even\n result += input_string[i]\n return result", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(input_string):\n \"\"\"\n Removes characters from a string that have odd index values.\n\n Args:\n input_string: The input string.\n\n Returns:\n A new string with characters at odd indices removed. Returns an empty string if the input is None or empty.\n \"\"\"\n if not input_string:\n return \"\"\n result = \"\"\n for i in range(len(input_string)):\n if i % 2 == 0: # Check if the index is even\n result += input_string[i]\n return result", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(input_string):\n \"\"\"\n Removes characters at odd indices from a string.\n\n Args:\n input_string: The input string.\n\n Returns:\n A new string with characters at odd indices removed. Returns an empty string if input is None or empty.\n \"\"\"\n if not input_string:\n return \"\"\n result = \"\"\n for i in range(len(input_string)):\n if i % 2 == 0:\n result += input_string[i]\n return result", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(input_string):\n \"\"\"\n Removes characters at odd indices from a string.\n\n Args:\n input_string: The input string.\n\n Returns:\n A new string with characters at odd indices removed. Returns an empty string if the input is None or empty.\n \"\"\"\n if not input_string:\n return \"\"\n result = \"\"\n for i in range(len(input_string)):\n if i % 2 == 0:\n result += input_string[i]\n return result", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(input_string):\n \"\"\"\n Removes characters at odd indices from a string.\n\n Args:\n input_string: The input string.\n\n Returns:\n A new string with characters at odd indices removed. Returns an empty string if the input is None or empty.\n \"\"\"\n if not input_string:\n return \"\"\n result = \"\"\n for i in range(len(input_string)):\n if i % 2 == 0: # Check if index is even\n result += input_string[i]\n return result", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(input_string):\n \"\"\"\n Removes characters from a string at odd indices.\n\n Args:\n input_string: The input string.\n\n Returns:\n A new string with characters at odd indices removed. Returns an empty string if the input is invalid.\n \"\"\"\n if not isinstance(input_string, str):\n return \"\"\n\n result = \"\"\n for i in range(len(input_string)):\n if i % 2 == 0:\n result += input_string[i]\n return result", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(input_string):\n \"\"\"\n Removes characters at odd indices from a string.\n\n Args:\n input_string: The input string.\n\n Returns:\n A new string with characters at odd indices removed. Returns an empty string if the input is None or empty.\n \"\"\"\n if not input_string:\n return \"\"\n result = \"\"\n for i in range(len(input_string)):\n if i % 2 == 0: # Check if index is even\n result += input_string[i]\n return result", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(input_string):\n \"\"\"\n Removes characters at odd indices from a string.\n\n Args:\n input_string: The input string.\n\n Returns:\n A new string with characters at odd indices removed.\n \"\"\"\n result = \"\"\n for i in range(len(input_string)):\n if i % 2 == 0: # Check if index is even\n result += input_string[i]\n return result", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(input_string):\n \"\"\"\n Removes characters at odd indices from a string.\n\n Args:\n input_string: The input string.\n\n Returns:\n A new string with characters at odd indices removed.\n \"\"\"\n result = \"\"\n for i in range(len(input_string)):\n if i % 2 == 0: #Check if index is even\n result += input_string[i]\n return result", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(input_string):\n \"\"\"\n Removes characters at odd indices from a string.\n\n Args:\n input_string: The input string.\n\n Returns:\n A new string with characters at odd indices removed.\n \"\"\"\n result = \"\"\n for i in range(len(input_string)):\n if i % 2 == 0: # Check if index is even\n result += input_string[i]\n return result", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(input_string):\n \"\"\"\n Removes characters at odd indices from a string.\n\n Args:\n input_string: The input string.\n\n Returns:\n A new string with characters at odd indices removed. Returns an empty string if the input is invalid.\n\n \"\"\"\n if not isinstance(input_string, str):\n return \"\" #Handle non-string input\n\n result = \"\"\n for i in range(len(input_string)):\n if i % 2 == 0:\n result += input_string[i]\n return result", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(input_string):\n \"\"\"\n Removes characters at odd indices from a string.\n\n Args:\n input_string: The input string.\n\n Returns:\n A new string with characters at odd indices removed. Returns an empty string if the input is None or empty.\n \"\"\"\n if not input_string:\n return \"\"\n result = \"\"\n for i in range(len(input_string)):\n if i % 2 == 0: # Check if index is even\n result += input_string[i]\n return result", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(input_string):\n \"\"\"\n Removes characters at odd indices from a string.\n\n Args:\n input_string: The input string.\n\n Returns:\n A new string with characters at odd indices removed. Returns an empty string if the input is None or empty.\n \"\"\"\n if not input_string:\n return \"\"\n result = \"\"\n for i in range(len(input_string)):\n if i % 2 == 0:\n result += input_string[i]\n return result", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(input_string):\n \"\"\"Removes characters at odd indices from a string.\n\n Args:\n input_string: The input string.\n\n Returns:\n A new string with characters at odd indices removed. Returns an empty string if the input is None or empty.\n \"\"\"\n if not input_string:\n return \"\"\n result = \"\"\n for i in range(len(input_string)):\n if i % 2 == 0:\n result += input_string[i]\n return result", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(input_string):\n \"\"\"\n Removes characters at odd indices from a string.\n\n Args:\n input_string: The input string.\n\n Returns:\n A new string with characters at odd indices removed.\n \"\"\"\n result = \"\"\n for i in range(len(input_string)):\n if i % 2 == 0: # Check if index is even\n result += input_string[i]\n return result", "matching_cluster_idx": 0}]}, "Mbpp/230": {"dps": 96.58730158730158, "dps_norm": 99.375, "pass@1": 100.0, "profiled": [{"solution": "def replace_blank(input_string, char):\n \"\"\"\n Replaces blank spaces in a string with a specified character.\n\n Args:\n input_string: The input string.\n char: The character to replace spaces with.\n\n Returns:\n The string with spaces replaced. Returns an empty string if input is None.\n \"\"\"\n if input_string is None:\n return \"\"\n return input_string.replace(\" \", char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string, char):\n \"\"\"Replaces blank spaces in a string with a specified character.\n\n Args:\n input_string: The input string.\n char: The character to replace blank spaces with.\n\n Returns:\n The string with blank spaces replaced. Returns the original string if no spaces are found.\n \"\"\"\n return input_string.replace(\" \", char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string, char):\n \"\"\"Replaces blank spaces in a string with a given character.\n\n Args:\n input_string: The input string.\n char: The character to replace blank spaces with.\n\n Returns:\n The string with blank spaces replaced. Returns the original string if input is invalid.\n\n \"\"\"\n if not isinstance(input_string, str) or not isinstance(char, str) or len(char) != 1:\n return input_string #Handle invalid input\n\n return input_string.replace(\" \", char)", "matching_cluster_idx": 6}, {"solution": "def replace_blank(input_string, char):\n \"\"\"Replaces blank spaces in a string with a given character.\n\n Args:\n input_string: The input string.\n char: The character to replace blank spaces with.\n\n Returns:\n The string with blank spaces replaced. Returns the original string if no spaces are found.\n \"\"\"\n return input_string.replace(\" \", char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string, char):\n \"\"\"Replaces blank spaces in a string with a specified character.\n\n Args:\n input_string: The input string.\n char: The character to replace blank spaces with.\n\n Returns:\n The string with blank spaces replaced. Returns the original string if no spaces are found.\n \"\"\"\n return input_string.replace(\" \", char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string, char):\n \"\"\"Replaces blank spaces in a string with a specified character.\n\n Args:\n input_string: The input string.\n char: The character to replace blank spaces with.\n\n Returns:\n The string with blank spaces replaced.\n \"\"\"\n return input_string.replace(\" \", char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string, char):\n \"\"\"Replaces blank spaces in a string with a specified character.\n\n Args:\n input_string: The input string.\n char: The character to replace blank spaces with.\n\n Returns:\n The string with blank spaces replaced. Returns the original string if no spaces are found.\n\n \"\"\"\n return input_string.replace(\" \", char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string, char):\n \"\"\"Replaces blank spaces in a string with a given character.\n\n Args:\n input_string: The input string.\n char: The character to replace blank spaces with.\n\n Returns:\n The string with blank spaces replaced.\n \"\"\"\n return input_string.replace(\" \", char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string, char):\n \"\"\"Replaces blank spaces in a string with a specified character.\n\n Args:\n input_string: The input string.\n char: The character to replace spaces with.\n\n Returns:\n The string with spaces replaced.\n \"\"\"\n return input_string.replace(\" \", char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string, char):\n \"\"\"Replaces blank spaces in a string with a specified character.\n\n Args:\n input_string: The input string.\n char: The character to replace blank spaces with.\n\n Returns:\n The string with blank spaces replaced. Returns the original string if no spaces are present.\n \"\"\"\n return input_string.replace(\" \", char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string, replacement_char):\n \"\"\"Replaces blank spaces in a string with a specified character.\n\n Args:\n input_string: The string to modify.\n replacement_char: The character to replace spaces with.\n\n Returns:\n The modified string with spaces replaced. Returns the original string if no spaces are found.\n \"\"\"\n return input_string.replace(\" \", replacement_char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string, char):\n \"\"\"Replaces blank spaces in a string with a given character.\n\n Args:\n input_string: The input string.\n char: The character to replace spaces with.\n\n Returns:\n The string with spaces replaced. Returns the original string if no spaces are present.\n\n \"\"\"\n return input_string.replace(\" \", char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string, char):\n \"\"\"Replaces blank spaces in a string with a specified character.\n\n Args:\n input_string: The input string.\n char: The character to replace blank spaces with.\n\n Returns:\n The string with blank spaces replaced. Returns the original string if no spaces are found.\n \"\"\"\n return input_string.replace(\" \", char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string, char):\n \"\"\"Replaces blank spaces in a string with a given character.\n\n Args:\n input_string: The input string.\n char: The character to replace blank spaces with.\n\n Returns:\n The string with blank spaces replaced.\n \"\"\"\n return input_string.replace(\" \", char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string, replacement_char):\n \"\"\"Replaces blank spaces in a string with a specified character.\n\n Args:\n input_string: The input string containing spaces.\n replacement_char: The character to replace spaces with.\n\n Returns:\n The string with spaces replaced. Returns the original string if no spaces are present.\n\n \"\"\"\n return input_string.replace(\" \", replacement_char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string, char):\n \"\"\"Replaces blank spaces in a string with a given character.\n\n Args:\n input_string: The input string.\n char: The character to replace blank spaces with.\n\n Returns:\n The string with blank spaces replaced.\n \"\"\"\n return input_string.replace(\" \", char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string, char):\n \"\"\"Replaces blank spaces in a string with a given character.\n\n Args:\n input_string: The input string.\n char: The character to replace blank spaces with.\n\n Returns:\n The string with blank spaces replaced. Returns the original string if no spaces are found.\n \"\"\"\n return input_string.replace(\" \", char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string, char):\n \"\"\"Replaces blank spaces in a string with a specified character.\n\n Args:\n input_string: The input string.\n char: The character to replace blank spaces with.\n\n Returns:\n The string with blank spaces replaced. Returns the original string if no spaces are found.\n \"\"\"\n return input_string.replace(\" \", char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string, char):\n \"\"\"Replaces blank spaces in a string with a specified character.\n\n Args:\n input_string: The input string.\n char: The character to replace spaces with.\n\n Returns:\n The string with spaces replaced.\n \"\"\"\n return input_string.replace(\" \", char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string, char):\n \"\"\"Replaces blank spaces in a string with a given character.\n\n Args:\n input_string: The input string.\n char: The character to replace blank spaces with.\n\n Returns:\n The string with blank spaces replaced. Returns the original string if no spaces are present.\n \"\"\"\n return input_string.replace(\" \", char)", "matching_cluster_idx": 7}]}, "Mbpp/239": {"dps": 47.06896551724138, "dps_norm": 58.0, "pass@1": 46.0, "profiled": [{"solution": "def get_total_number_of_sequences(m, n):\n \"\"\"\n Finds the number of possible sequences of length n, such that each element is a positive integer and is greater than or equal to twice the previous element but less than or equal to m.\n\n Args:\n m: The maximum value for each element in the sequence.\n n: The length of the sequence.\n\n Returns:\n The number of possible sequences.\n \"\"\"\n\n if n == 0:\n return 1 # Base case: empty sequence\n\n count = 0\n if n == 1:\n return m # Base case: sequence of length 1\n\n def count_sequences(current_sequence, length):\n nonlocal count\n if length == n:\n count += 1\n return\n\n last_element = current_sequence[-1]\n for i in range(2 * last_element, m + 1):\n count_sequences(current_sequence + [i], length + 1)\n\n for i in range(1, m + 1):\n count_sequences([i], 1)\n\n return count", "matching_cluster_idx": 3}, {"solution": "def get_total_number_of_sequences(m, n):\n \"\"\"\n Write a function that takes in positive integers m and n and finds the number of possible sequences of length n, such that each element is a positive integer and is greater than or equal to twice the previous element but less than or equal to m.\n assert get_total_number_of_sequences(10, 4) == 4\n \"\"\"\n if n == 0:\n return 1 # Base case: empty sequence is one sequence\n\n count = 0\n \n def count_sequences(current_sequence, current_length):\n nonlocal count\n if current_length == n:\n count += 1\n return\n\n last_element = current_sequence[-1] if current_sequence else 0 # Handle empty sequence\n for i in range(max(1, 2 * last_element), m + 1):\n count_sequences(current_sequence + [i], current_length + 1)\n\n count_sequences([], 0)\n return count", "matching_cluster_idx": 3}, {"solution": "def get_total_number_of_sequences(m, n):\n \"\"\"\n Calculates the number of possible sequences of length n, where each element is a positive integer\n greater than or equal to twice the previous element and less than or equal to m.\n\n Args:\n m: The upper bound for each element in the sequence.\n n: The length of the sequence.\n\n Returns:\n The number of possible sequences.\n \"\"\"\n\n if n == 0:\n return 1 # Empty sequence is a valid sequence\n\n if m < 1 or n < 0:\n return 0 #Invalid input\n\n count = 0\n \n def count_sequences(current_sequence, current_length):\n nonlocal count\n if current_length == n:\n count += 1\n return\n\n last_element = current_sequence[-1] if current_sequence else 0\n for i in range(max(1, 2 * last_element), m + 1):\n count_sequences(current_sequence + [i], current_length + 1)\n\n\n count_sequences([], 0)\n return count", "matching_cluster_idx": 3}, {"solution": "def get_total_number_of_sequences(m, n):\n \"\"\"\n Finds the number of possible sequences of length n, such that each element is a positive integer and is greater than or equal to twice the previous element but less than or equal to m.\n\n Args:\n m: The upper bound for each element in the sequence.\n n: The length of the sequence.\n\n Returns:\n The number of possible sequences.\n \"\"\"\n\n if n == 0:\n return 1 # Empty sequence is a valid sequence\n\n dp = {} # Memoization dictionary\n\n def count_sequences(index, prev_element):\n if index == n:\n return 1\n\n if (index, prev_element) in dp:\n return dp[(index, prev_element)]\n\n count = 0\n for current_element in range(2 * prev_element, m + 1):\n count += count_sequences(index + 1, current_element)\n\n dp[(index, prev_element)] = count\n return count\n\n total_sequences = 0\n for first_element in range(1, m + 1):\n total_sequences += count_sequences(1, first_element)\n\n return total_sequences", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n \"\"\"\n Finds the number of possible sequences of length n, such that each element is a positive integer and is greater than or equal to twice the previous element but less than or equal to m.\n\n Args:\n m: The upper bound for each element in the sequence.\n n: The length of the sequence.\n\n Returns:\n The number of possible sequences.\n \"\"\"\n\n if n == 0:\n return 1 # Empty sequence is considered a valid sequence.\n if m < 1 or n < 0:\n return 0 # Invalid input\n\n dp = {} # Memoization to avoid redundant calculations\n\n def count_sequences(index, prev_element):\n if index == n:\n return 1\n if (index, prev_element) in dp:\n return dp[(index, prev_element)]\n\n count = 0\n for current_element in range(2 * prev_element, m + 1):\n count += count_sequences(index + 1, current_element)\n\n dp[(index, prev_element)] = count\n return count\n\n total_sequences = 0\n for first_element in range(1, m + 1):\n total_sequences += count_sequences(1, first_element)\n\n return total_sequences", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n \"\"\"\n Finds the number of possible sequences of length n, where each element is a positive integer \n greater than or equal to twice the previous element and less than or equal to m.\n\n Args:\n m: The upper bound for each element in the sequence.\n n: The length of the sequence.\n\n Returns:\n The number of possible sequences.\n \"\"\"\n\n if n == 0:\n return 1 # Base case: empty sequence is one possibility\n\n count = 0\n \n def count_sequences(current_sequence, length):\n nonlocal count # Access and modify the outer count variable\n if length == n:\n count += 1\n return\n\n last_element = current_sequence[-1] if current_sequence else 0 #handle empty sequence case\n\n for i in range(max(1, 2 * last_element), m + 1):\n count_sequences(current_sequence + [i], length + 1)\n\n count_sequences([], 0) # Start with an empty sequence\n return count", "matching_cluster_idx": 3}, {"solution": "def get_total_number_of_sequences(m, n):\n \"\"\"\n Finds the number of possible sequences of length n, where each element is a positive integer,\n greater than or equal to twice the previous element, and less than or equal to m.\n\n Args:\n m: The upper bound for each element in the sequence.\n n: The length of the sequence.\n\n Returns:\n The number of possible sequences.\n \"\"\"\n\n if n == 0:\n return 1 # Empty sequence is a valid sequence\n\n count = 0\n \n def count_sequences(current_sequence, length_so_far):\n nonlocal count\n if length_so_far == n:\n count += 1\n return\n\n last_element = current_sequence[-1] if current_sequence else 0\n \n for i in range(max(1, 2 * last_element), m + 1):\n count_sequences(current_sequence + [i], length_so_far + 1)\n\n count_sequences([],0)\n return count", "matching_cluster_idx": 3}, {"solution": "def get_total_number_of_sequences(m, n):\n \"\"\"\n Finds the number of possible sequences of length n, such that each element is a positive integer and is greater than or equal to twice the previous element but less than or equal to m.\n\n Args:\n m: The upper bound for each element in the sequence.\n n: The length of the sequence.\n\n Returns:\n The number of possible sequences.\n \"\"\"\n\n if n == 0:\n return 1 # Empty sequence is a valid sequence\n\n dp = {} # Memoization dictionary to store results\n\n def count_sequences(index, prev_element):\n if index == n:\n return 1\n\n if (index, prev_element) in dp:\n return dp[(index, prev_element)]\n\n count = 0\n for current_element in range(2 * prev_element, m + 1):\n count += count_sequences(index + 1, current_element)\n\n dp[(index, prev_element)] = count\n return count\n\n total_sequences = 0\n for first_element in range(1, m + 1):\n total_sequences += count_sequences(1, first_element)\n\n return total_sequences", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n \"\"\"\n Finds the number of possible sequences of length n, such that each element is a positive integer and is greater than or equal to twice the previous element but less than or equal to m.\n\n Args:\n m: The upper bound for each element in the sequence.\n n: The length of the sequence.\n\n Returns:\n The number of possible sequences.\n \"\"\"\n\n if n == 0:\n return 1 # Empty sequence is considered valid\n\n if m < 1 or n < 0:\n return 0 #invalid inputs\n\n count = 0\n \n def count_sequences(current_sequence, length):\n nonlocal count\n if length == n:\n count += 1\n return\n\n last_element = current_sequence[-1] if current_sequence else 0\n \n for i in range(max(1, 2 * last_element), m + 1):\n count_sequences(current_sequence + [i], length + 1)\n\n count_sequences([], 0)\n return count", "matching_cluster_idx": 3}, {"solution": "def get_total_number_of_sequences(m, n):\n \"\"\"\n Finds the number of possible sequences of length n, such that each element is a positive integer and is greater than or equal to twice the previous element but less than or equal to m.\n\n Args:\n m: The upper bound for each element in the sequence.\n n: The length of the sequence.\n\n Returns:\n The number of possible sequences.\n \"\"\"\n\n if n == 0:\n return 1 # Empty sequence is a valid sequence\n\n if m < 1 or n < 1:\n return 0 # Invalid input\n\n dp = {} # Memoization dictionary\n\n def count_sequences(index, prev):\n if index == n:\n return 1\n if (index, prev) in dp:\n return dp[(index, prev)]\n\n count = 0\n for i in range(max(1, 2 * prev), m + 1):\n count += count_sequences(index + 1, i)\n dp[(index, prev)] = count\n return count\n\n return count_sequences(0, 0)", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n \"\"\"\n Finds the number of possible sequences of length n, such that each element is a positive integer and is greater than or equal to twice the previous element but less than or equal to m.\n\n Args:\n m: The upper bound for each element in the sequence.\n n: The length of the sequence.\n\n Returns:\n The number of possible sequences.\n \"\"\"\n\n if n == 0:\n return 1 # Empty sequence is a valid sequence\n\n count = 0\n \n def count_sequences(current_sequence, current_length):\n nonlocal count\n if current_length == n:\n count += 1\n return\n\n last_element = current_sequence[-1] if current_sequence else 0\n for i in range(max(1, 2 * last_element), m + 1):\n count_sequences(current_sequence + [i], current_length + 1)\n\n count_sequences([], 0)\n return count", "matching_cluster_idx": 3}, {"solution": "def get_total_number_of_sequences(m, n):\n \"\"\"\n Finds the number of possible sequences of length n, such that each element is a positive integer and is greater than or equal to twice the previous element but less than or equal to m.\n\n Args:\n m: The upper bound for each element in the sequence.\n n: The length of the sequence.\n\n Returns:\n The number of possible sequences.\n \"\"\"\n\n if n == 0:\n return 1 # Empty sequence is a valid sequence\n\n dp = {} # Use dynamic programming to avoid redundant calculations\n\n def count_sequences(index, prev_element):\n if index == n:\n return 1\n if (index, prev_element) in dp:\n return dp[(index, prev_element)]\n\n count = 0\n for current_element in range(max(1, 2 * prev_element), m + 1):\n count += count_sequences(index + 1, current_element)\n\n dp[(index, prev_element)] = count\n return count\n\n total_sequences = count_sequences(0, 0) # Start with an initial element of 0\n return total_sequences", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n \"\"\"\n Write a function that takes in positive integers m and n and finds the number of possible sequences of length n, such that each element is a positive integer and is greater than or equal to twice the previous element but less than or equal to m.\n assert get_total_number_of_sequences(10, 4) == 4\n \"\"\"\n if n == 0:\n return 1 # Base case: empty sequence is one possibility\n\n count = 0\n if n == 1:\n return m #Base case: only one element, any value from 1 to m is valid\n\n \n def count_sequences(current_sequence, current_length):\n nonlocal count\n if current_length == n:\n count += 1\n return\n\n last_element = current_sequence[-1] if current_sequence else 0\n\n for next_element in range(max(1, 2 * last_element), m + 1):\n count_sequences(current_sequence + [next_element], current_length + 1)\n\n count_sequences([], 0)\n return count", "matching_cluster_idx": 3}, {"solution": "def get_total_number_of_sequences(m, n):\n \"\"\"\n Write a function that takes in positive integers m and n and finds the number of possible sequences of length n, such that each element is a positive integer and is greater than or equal to twice the previous element but less than or equal to m.\n assert get_total_number_of_sequences(10, 4) == 4\n \"\"\"\n if n == 0:\n return 1 # Base case: empty sequence is one sequence\n\n count = 0\n if n == 1:\n return m # Base case: only one element, any value from 1 to m is valid\n\n def count_sequences(current_sequence, current_length):\n nonlocal count\n if current_length == n:\n count += 1\n return\n\n last_element = current_sequence[-1]\n for i in range(2 * last_element, m + 1):\n count_sequences(current_sequence + [i], current_length + 1)\n\n for i in range(1, m + 1):\n count_sequences([i], 1)\n\n return count", "matching_cluster_idx": 3}, {"solution": "def get_total_number_of_sequences(m, n):\n \"\"\"\n Finds the number of possible sequences of length n, such that each element is a positive integer and is greater than or equal to twice the previous element but less than or equal to m.\n\n Args:\n m: The upper bound for each element in the sequence.\n n: The length of the sequence.\n\n Returns:\n The number of possible sequences.\n \"\"\"\n\n if n == 0:\n return 1 # Base case: empty sequence is one sequence\n\n if n == 1:\n return m # Base case: only one element, can be any from 1 to m\n\n\n dp = {} #Memoization dictionary\n\n def count_sequences(index, prev_element):\n if index == n:\n return 1\n \n if (index, prev_element) in dp:\n return dp[(index, prev_element)]\n\n count = 0\n for current_element in range(2 * prev_element, m + 1):\n count += count_sequences(index + 1, current_element)\n\n dp[(index, prev_element)] = count\n return count\n\n total_sequences = 0\n for first_element in range(1, m + 1):\n total_sequences += count_sequences(1, first_element)\n\n return total_sequences", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n \"\"\"\n Finds the number of possible sequences of length n, such that each element is a positive integer and is greater than or equal to twice the previous element but less than or equal to m.\n\n Args:\n m: The upper bound for each element in the sequence.\n n: The length of the sequence.\n\n Returns:\n The number of possible sequences.\n \"\"\"\n\n if n == 0:\n return 1 # Base case: empty sequence\n\n if n == 1:\n return m # Base case: sequence of length 1\n\n count = 0\n # Iterate through possible values for the first element\n for i in range(1, m + 1):\n count += get_total_number_of_sequences_helper(m, n - 1, i)\n\n return count\ndef get_total_number_of_sequences_helper(m, n, prev):\n \"\"\"\n Helper function for recursive calculation.\n \"\"\"\n if n == 0:\n return 1\n count = 0\n for i in range(max(2 * prev, 1), m + 1):\n count += get_total_number_of_sequences_helper(m, n - 1, i)\n return count", "matching_cluster_idx": 3}, {"solution": "def get_total_number_of_sequences(m, n):\n \"\"\"\n Finds the number of possible sequences of length n, such that each element is a positive integer and is greater than or equal to twice the previous element but less than or equal to m.\n\n Args:\n m: The upper bound for each element in the sequence.\n n: The length of the sequence.\n\n Returns:\n The number of possible sequences.\n \"\"\"\n\n if n == 0:\n return 1 # Base case: empty sequence\n\n count = 0\n if n == 1:\n return m\n \n def count_sequences(current_sequence, current_length):\n nonlocal count\n if current_length == n:\n count += 1\n return\n\n last_element = current_sequence[-1] if current_sequence else 0\n for i in range(max(1, 2 * last_element), m + 1):\n count_sequences(current_sequence + [i], current_length + 1)\n\n count_sequences([], 0)\n return count", "matching_cluster_idx": 3}, {"solution": "def get_total_number_of_sequences(m, n):\n \"\"\"\n Finds the number of possible sequences of length n, such that each element is a positive integer and is greater than or equal to twice the previous element but less than or equal to m.\n\n Args:\n m: The maximum value for each element in the sequence.\n n: The length of the sequence.\n\n Returns:\n The number of possible sequences.\n \"\"\"\n\n if n == 0:\n return 1 # Base case: empty sequence is a valid sequence\n\n if m < 1 or n < 0 :\n return 0 #Handle invalid inputs\n\n dp = {} # Memoization dictionary to store results\n\n def count_sequences(index, prev_element):\n if index == n:\n return 1 # Base case: reached the end of the sequence\n\n if (index, prev_element) in dp:\n return dp[(index, prev_element)]\n\n count = 0\n for current_element in range(2 * prev_element, m + 1):\n count += count_sequences(index + 1, current_element)\n\n dp[(index, prev_element)] = count\n return count\n\n total_sequences = 0\n for first_element in range(1, m + 1):\n total_sequences += count_sequences(1, first_element)\n\n return total_sequences", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n \"\"\"\n Write a function that takes in positive integers m and n and finds the number of possible sequences of length n, such that each element is a positive integer and is greater than or equal to twice the previous element but less than or equal to m.\n assert get_total_number_of_sequences(10, 4) == 4\n \"\"\"\n if n == 0:\n return 1 # Base case: empty sequence is one possibility\n\n dp = {} # Use dynamic programming to store results\n\n def count_sequences(index, prev):\n if index == n:\n return 1 # Base case: reached the end of the sequence\n\n if (index, prev) in dp:\n return dp[(index, prev)]\n\n count = 0\n for i in range(max(2 * prev, 1), m + 1):\n count += count_sequences(index + 1, i)\n\n dp[(index, prev)] = count\n return count\n\n return count_sequences(0, 0)", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n \"\"\"\n Finds the number of possible sequences of length n, such that each element is a positive integer and is greater than or equal to twice the previous element but less than or equal to m.\n\n Args:\n m: The upper bound for each element in the sequence.\n n: The length of the sequence.\n\n Returns:\n The number of possible sequences.\n \"\"\"\n\n if n == 0:\n return 1 # Base case: empty sequence is one sequence\n\n if m < 1 or n < 0 :\n return 0 #Invalid inputs\n\n count = 0\n if n == 1:\n return m # Base case: if n=1 there are m possibilities\n\n # Use dynamic programming to avoid redundant calculations\n dp = {} \n\n def count_sequences(index, prev_element):\n if index == n:\n return 1\n\n if (index, prev_element) in dp:\n return dp[(index, prev_element)]\n\n total_count = 0\n for current_element in range(2 * prev_element, m + 1):\n total_count += count_sequences(index + 1, current_element)\n dp[(index, prev_element)] = total_count\n return total_count\n\n #Start with the first element\n for first_element in range(1,m+1):\n count += count_sequences(1, first_element)\n return count", "matching_cluster_idx": 7}]}, "Mbpp/240": {"dps": 45.853658536585364, "dps_norm": 65.55555555555556, "pass@1": 75.0, "profiled": [{"solution": "def replace_list(list1, list2):\n \"\"\"Replaces the last element of list1 with the elements of list2.\n\n Args:\n list1: The first list.\n list2: The second list.\n\n Returns:\n A new list with the last element of list1 replaced by the elements of list2. Returns list1 if list1 is empty.\n \"\"\"\n if not list1:\n return list1\n list1 = list1[:-1]\n list1.extend(list2)\n return list1", "matching_cluster_idx": 6}, {"solution": "def replace_list(list1, list2):\n \"\"\"\n Replaces the last element of list1 with the elements of list2.\n\n Args:\n list1: The first list.\n list2: The second list.\n\n Returns:\n A new list with the last element of list1 replaced by the elements of list2. Returns list1 if list1 is empty.\n \"\"\"\n if not list1:\n return list1\n return list1[:-1] + list2", "matching_cluster_idx": 5}, {"solution": "def replace_list(list1, list2):\n \"\"\"Replaces the last element of list1 with the elements of list2.\n\n Args:\n list1: The first list.\n list2: The second list.\n\n Returns:\n A new list with the last element of list1 replaced by the elements of list2. Returns list1 unchanged if list1 is empty.\n \"\"\"\n if not list1:\n return list1\n \n return list1[:-1] + list2", "matching_cluster_idx": 5}, {"solution": "def replace_list(list1, list2):\n \"\"\"Replaces the last element of list1 with the elements of list2.\n\n Args:\n list1: The first list.\n list2: The second list.\n\n Returns:\n A new list with the last element of list1 replaced by the elements of list2. Returns list1 if list1 is empty.\n \"\"\"\n if not list1:\n return list1\n return list1[:-1] + list2", "matching_cluster_idx": 5}, {"solution": "def replace_list(list1, list2):\n \"\"\"Replaces the last element of list1 with the elements of list2.\n\n Args:\n list1: The first list.\n list2: The second list.\n\n Returns:\n A new list with the last element of list1 replaced by the elements of list2.\n Returns list1 if list1 is empty. Returns list2 if list1 only contains one element.\n \"\"\"\n if not list1:\n return list1\n if len(list1) == 1:\n return list2\n\n return list1[:-1] + list2", "matching_cluster_idx": 5}, {"solution": "def replace_list(list1, list2):\n \"\"\"Replaces the last element of list1 with the elements of list2.\"\"\"\n if not list1: # Handle empty list1 case\n return list2\n list1 = list1[:-1] #remove last element from list1\n list1.extend(list2) #add elements of list2 to the end of list1\n return list1", "matching_cluster_idx": 6}, {"solution": "def replace_list(list1, list2):\n \"\"\"Replaces the last element of list1 with the elements of list2.\n\n Args:\n list1: The first list.\n list2: The second list.\n\n Returns:\n A new list with the last element of list1 replaced by the elements of list2. Returns list1 if list1 is empty.\n Returns list2 if list1 contains only one element.\n\n Raises:\n TypeError: if input is not a list.\n \"\"\"\n if not isinstance(list1, list) or not isinstance(list2, list):\n raise TypeError(\"Inputs must be lists.\")\n\n if not list1:\n return list1\n elif len(list1) == 1:\n return list2\n else:\n return list1[:-1] + list2", "matching_cluster_idx": 4}, {"solution": "def replace_list(list1, list2):\n \"\"\"Replaces the last element of list1 with the elements of list2.\"\"\"\n if not list1: #Handle empty list1 case\n return list2\n list1 = list1[:-1] + list2\n return list1", "matching_cluster_idx": 5}, {"solution": "def replace_list(list1, list2):\n \"\"\"Replaces the last element of list1 with the elements of list2.\n\n Args:\n list1: The first list.\n list2: The second list.\n\n Returns:\n A new list with the last element of list1 replaced by the elements of list2.\n Returns list1 if list1 is empty.\n Returns list2 if list1 has only one element.\n\n Raises:\n TypeError: if input is not a list.\n \"\"\"\n if not isinstance(list1, list) or not isinstance(list2, list):\n raise TypeError(\"Inputs must be lists.\")\n\n if not list1:\n return list1\n elif len(list1) == 1:\n return list2\n else:\n return list1[:-1] + list2", "matching_cluster_idx": 4}, {"solution": "def replace_list(list1, list2):\n \"\"\"\n Replaces the last element of list1 with the elements of list2.\n\n Args:\n list1: The first list.\n list2: The second list.\n\n Returns:\n A new list with the last element of list1 replaced by the elements of list2.\n Returns list1 if list1 is empty. Returns list2 if list1 contains only one element.\n \"\"\"\n if not list1:\n return list1\n elif len(list1) == 1:\n return list2\n else:\n return list1[:-1] + list2", "matching_cluster_idx": 5}, {"solution": "def replace_list(list1, list2):\n \"\"\"Replaces the last element of list1 with the elements of list2.\n\n Args:\n list1: The first list.\n list2: The second list.\n\n Returns:\n A new list with the last element of list1 replaced by the elements of list2.\n Returns list1 if list1 is empty.\n \"\"\"\n if not list1:\n return list1\n return list1[:-1] + list2", "matching_cluster_idx": 5}, {"solution": "def replace_list(list1, list2):\n \"\"\"Replaces the last element of list1 with the elements of list2.\"\"\"\n if not list1:\n return list2 # Handle empty list1 case\n list1 = list1[:-1] + list2\n return list1", "matching_cluster_idx": 5}, {"solution": "def replace_list(list1, list2):\n \"\"\"Replaces the last element of list1 with the elements of list2.\"\"\"\n if not list1:\n return list2 # Handle empty list1 case\n\n list1 = list1[:-1] + list2\n return list1", "matching_cluster_idx": 5}, {"solution": "def replace_list(list1, list2):\n \"\"\"Replaces the last element of list1 with the elements of list2.\n\n Args:\n list1: The first list.\n list2: The second list.\n\n Returns:\n A new list with the last element of list1 replaced by the elements of list2.\n Returns list1 if list1 is empty. Returns list2 if list1 has only one element.\n\n Raises:\n TypeError: if either input is not a list.\n \"\"\"\n if not isinstance(list1, list) or not isinstance(list2, list):\n raise TypeError(\"Both inputs must be lists.\")\n\n if not list1:\n return list1\n elif len(list1) == 1:\n return list2\n else:\n return list1[:-1] + list2", "matching_cluster_idx": 4}, {"solution": "def replace_list(list1, list2):\n \"\"\"Replaces the last element of list1 with the elements of list2.\"\"\"\n if not list1:\n return list2 # Handle empty list1 case\n\n list1 = list1[:-1] + list2\n return list1", "matching_cluster_idx": 5}, {"solution": "def replace_list(list1, list2):\n \"\"\"Replaces the last element of list1 with the elements of list2.\"\"\"\n if not list1:\n return list2 # Handle empty list1 case\n list1 = list1[:-1] + list2\n return list1", "matching_cluster_idx": 5}, {"solution": "def replace_list(list1, list2):\n \"\"\"Replaces the last element of list1 with the elements of list2.\n\n Args:\n list1: The first list.\n list2: The second list.\n\n Returns:\n A new list with the last element of list1 replaced by list2's elements. Returns list1 unchanged if it's empty.\n\n Raises:\n TypeError: if input is not a list.\n \"\"\"\n if not isinstance(list1, list) or not isinstance(list2, list):\n raise TypeError(\"Inputs must be lists.\")\n\n if not list1: #Handle empty list1 case\n return list1\n\n return list1[:-1] + list2", "matching_cluster_idx": 4}, {"solution": "def replace_list(list1, list2):\n \"\"\"Replaces the last element of list1 with the elements of list2.\"\"\"\n if not list1:\n return list2 # Handle empty list1 case\n\n list1 = list1[:-1] + list2\n return list1", "matching_cluster_idx": 5}, {"solution": "def replace_list(list1, list2):\n \"\"\"Replaces the last element of list1 with the elements of list2.\n\n Args:\n list1: The first list.\n list2: The second list.\n\n Returns:\n A new list with the last element of list1 replaced by the elements of list2. Returns list1 unchanged if list1 is empty.\n \"\"\"\n if not list1:\n return list1\n return list1[:-1] + list2", "matching_cluster_idx": 5}, {"solution": "def replace_list(list1, list2):\n \"\"\"Replaces the last element of list1 with the elements of list2.\"\"\"\n if not list1:\n return list2 #Handle empty list1 case\n list1 = list1[:-1] + list2\n return list1", "matching_cluster_idx": 5}]}, "Mbpp/251": {"dps": 91.95402298850576, "dps_norm": 77.77777777777777, "pass@1": 100.0, "profiled": [{"solution": "def insert_element(lst, element):\n \"\"\"Inserts an element before each element in a list.\n\n Args:\n lst: The input list.\n element: The element to insert.\n\n Returns:\n A new list with the element inserted before each element of the input list.\n \"\"\"\n new_list = []\n for item in lst:\n new_list.extend([element, item])\n return new_list", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n \"\"\"Inserts an element before each element in a list.\n\n Args:\n lst: The input list.\n element: The element to insert.\n\n Returns:\n A new list with the element inserted before each original element.\n \"\"\"\n new_list = []\n for item in lst:\n new_list.extend([element, item])\n return new_list", "matching_cluster_idx": 6}, {"solution": "def insert_element(input_list, element):\n \"\"\"\n Inserts an element before each element in a list.\n\n Args:\n input_list: The input list.\n element: The element to insert.\n\n Returns:\n A new list with the element inserted before each original element.\n \"\"\"\n output_list = []\n for item in input_list:\n output_list.extend([element, item])\n return output_list", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n \"\"\"Inserts an element before each element in a list.\n\n Args:\n lst: The input list.\n element: The element to insert.\n\n Returns:\n A new list with the element inserted before each original element.\n \"\"\"\n new_list = []\n for item in lst:\n new_list.extend([element, item])\n return new_list", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n \"\"\"Inserts an element before each element in a list.\n\n Args:\n lst: The input list.\n element: The element to insert.\n\n Returns:\n A new list with the element inserted before each original element.\n \"\"\"\n new_list = []\n for item in lst:\n new_list.extend([element, item])\n return new_list", "matching_cluster_idx": 6}, {"solution": "def insert_element(input_list, element):\n \"\"\"\n Inserts an element before each element in a list.\n\n Args:\n input_list: The input list.\n element: The element to insert.\n\n Returns:\n A new list with the element inserted before each original element.\n \"\"\"\n output_list = []\n for item in input_list:\n output_list.append(element)\n output_list.append(item)\n return output_list", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n \"\"\"\n Inserts an element before each element in a list.\n\n Args:\n lst: The input list.\n element: The element to insert.\n\n Returns:\n A new list with the element inserted before each element of the input list.\n \"\"\"\n new_lst = []\n for item in lst:\n new_lst.extend([element, item])\n return new_lst", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, elem):\n \"\"\"Inserts an element before each element in a list.\n\n Args:\n lst: The input list.\n elem: The element to insert.\n\n Returns:\n A new list with the element inserted before each original element.\n \"\"\"\n new_lst = []\n for item in lst:\n new_lst.extend([elem, item])\n return new_lst", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n \"\"\"Inserts an element before each element in a list.\n\n Args:\n lst: The input list.\n element: The element to insert.\n\n Returns:\n A new list with the element inserted before each original element.\n \"\"\"\n new_list = []\n for item in lst:\n new_list.extend([element, item]) #More efficient than appending individually\n return new_list", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n \"\"\"Inserts an element before each element in a list.\n\n Args:\n lst: The input list.\n element: The element to insert.\n\n Returns:\n A new list with the element inserted before each original element.\n \"\"\"\n new_lst = []\n for item in lst:\n new_lst.extend([element, item]) #Efficiently adds both element and item\n return new_lst", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n \"\"\"\n Inserts an element before each element in a list.\n\n Args:\n lst: The input list.\n element: The element to insert.\n\n Returns:\n A new list with the element inserted before each original element.\n \"\"\"\n new_lst = []\n for item in lst:\n new_lst.extend([element, item])\n return new_lst", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n \"\"\"Inserts an element before each element in a list.\n\n Args:\n lst: The input list.\n element: The element to insert.\n\n Returns:\n A new list with the element inserted before each original element.\n \"\"\"\n new_list = []\n for item in lst:\n new_list.extend([element, item])\n return new_list", "matching_cluster_idx": 6}, {"solution": "def insert_element(list_in, element):\n \"\"\"\n Inserts an element before each element in a list.\n\n Args:\n list_in: The input list.\n element: The element to insert.\n\n Returns:\n A new list with the element inserted before each original element.\n \"\"\"\n result = []\n for item in list_in:\n result.extend([element, item])\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n \"\"\"\n Inserts an element before each element in a list.\n\n Args:\n lst: The input list.\n element: The element to insert.\n\n Returns:\n A new list with the element inserted before each original element.\n \"\"\"\n new_list = []\n for item in lst:\n new_list.extend([element, item])\n return new_list", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n \"\"\"Inserts an element before each element in a list.\n\n Args:\n lst: The input list.\n element: The element to insert.\n\n Returns:\n A new list with the element inserted before each element of the input list. Returns an empty list if the input list is empty.\n \"\"\"\n new_lst = []\n for item in lst:\n new_lst.extend([element, item]) #More efficient than appending individually.\n return new_lst", "matching_cluster_idx": 6}, {"solution": "def insert_element(input_list, element):\n \"\"\"\n Inserts an element before each element in a list.\n\n Args:\n input_list: The input list.\n element: The element to insert.\n\n Returns:\n A new list with the element inserted before each element of the input list. Returns an empty list if the input list is empty.\n \"\"\"\n if not input_list:\n return []\n \n output_list = []\n for item in input_list:\n output_list.extend([element, item])\n return output_list", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n \"\"\"Inserts an element before each element in a list.\n\n Args:\n lst: The input list.\n element: The element to insert.\n\n Returns:\n A new list with the element inserted before each element of the input list.\n \"\"\"\n new_list = []\n for item in lst:\n new_list.extend([element, item])\n return new_list", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n \"\"\"Inserts an element before each element in a list.\n\n Args:\n lst: The input list.\n element: The element to insert.\n\n Returns:\n A new list with the element inserted before each original element.\n \"\"\"\n new_lst = []\n for item in lst:\n new_lst.extend([element, item])\n return new_lst", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n \"\"\"Inserts an element before each element in a list.\n\n Args:\n lst: The input list.\n element: The element to insert.\n\n Returns:\n A new list with the element inserted before each original element.\n \"\"\"\n new_list = []\n for item in lst:\n new_list.extend([element, item])\n return new_list", "matching_cluster_idx": 6}, {"solution": "def insert_element(input_list, element):\n \"\"\"Inserts an element before each element in a list.\n\n Args:\n input_list: The input list.\n element: The element to insert.\n\n Returns:\n A new list with the element inserted before each original element.\n \"\"\"\n result = []\n for item in input_list:\n result.extend([element, item]) #Efficiently adds element and item\n return result", "matching_cluster_idx": 6}]}, "Mbpp/256": {"dps": 61.32420091324201, "dps_norm": 58.8235294117647, "pass@1": 93.0, "profiled": [{"solution": "def count_Primes_nums(n):\n \"\"\"\n Counts the number of prime numbers less than a given non-negative number.\n\n Args:\n n: A non-negative integer.\n\n Returns:\n The number of prime numbers less than n. Returns 0 if n is 0 or less.\n \"\"\"\n if n <= 0:\n return 0\n count = 0\n for num in range(2, n): #Start from 2 as 0 and 1 are not prime\n is_prime = True\n for i in range(2, int(num**0.5) + 1): #Optimized primality test\n if num % i == 0:\n is_prime = False\n break\n if is_prime:\n count += 1\n return count", "matching_cluster_idx": 8}, {"solution": "def count_Primes_nums(n):\n \"\"\"\n Counts the number of prime numbers less than a given non-negative number.\n\n Args:\n n: A non-negative integer.\n\n Returns:\n The number of prime numbers less than n. Returns 0 if n is 0 or less.\n\n Raises:\n TypeError: if input is not an integer.\n ValueError: if input is negative.\n \"\"\"\n if not isinstance(n, int):\n raise TypeError(\"Input must be an integer.\")\n if n < 0:\n raise ValueError(\"Input must be a non-negative integer.\")\n if n <= 2:\n return 0\n\n count = 0\n for num in range(2, n):\n is_prime = True\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n is_prime = False\n break\n if is_prime:\n count += 1\n return count", "matching_cluster_idx": 8}, {"solution": "def count_Primes_nums(n):\n \"\"\"\n Counts the number of prime numbers less than a given non-negative number.\n\n Args:\n n: A non-negative integer.\n\n Returns:\n The number of prime numbers less than n. Returns 0 if n is 0 or less.\n\n Raises:\n TypeError: if input is not an integer.\n ValueError: if input is negative.\n\n \"\"\"\n if not isinstance(n, int):\n raise TypeError(\"Input must be an integer.\")\n if n < 0:\n raise ValueError(\"Input must be a non-negative integer.\")\n if n <= 2:\n return 0\n\n count = 0\n primes = [True] * n # Initialize a list to track prime numbers\n primes[0] = primes[1] = False # 0 and 1 are not prime\n\n for p in range(2, int(n**0.5) + 1):\n if primes[p]:\n for i in range(p * p, n, p):\n primes[i] = False\n\n for p in range(2, n):\n if primes[p]:\n count += 1\n\n return count", "matching_cluster_idx": 13}, {"solution": "def count_Primes_nums(n):\n \"\"\"\n Counts the number of prime numbers less than a given non-negative number.\n\n Args:\n n: A non-negative integer.\n\n Returns:\n The number of prime numbers less than n. Returns 0 if n is 0 or less.\n \"\"\"\n if n <= 0:\n return 0\n \n count = 0\n for num in range(2, n): #Start from 2 since 1 is not prime\n is_prime = True\n for i in range(2, int(num**0.5) + 1): #Optimized primality test\n if num % i == 0:\n is_prime = False\n break\n if is_prime:\n count += 1\n return count", "matching_cluster_idx": 8}, {"solution": "def count_Primes_nums(n):\n \"\"\"\n Write a python function that takes in a non-negative number and returns the number of prime numbers less than the given non-negative number.\n assert count_Primes_nums(5) == 3 #Corrected assertion. 2 is prime and less than 5. Also 3 is prime and less than 5.\n \"\"\"\n if n <= 1:\n return 0\n count = 0\n prime = [True] * n\n prime[0] = prime[1] = False # 0 and 1 are not prime\n\n for p in range(2, int(n**0.5) + 1):\n if prime[p]:\n for i in range(p * p, n, p):\n prime[i] = False\n\n for p in range(2, n):\n if prime[p]:\n count += 1\n return count", "matching_cluster_idx": 13}, {"solution": "def count_Primes_nums(n):\n \"\"\"\n Counts the number of prime numbers less than a given non-negative number.\n\n Args:\n n: A non-negative integer.\n\n Returns:\n The number of prime numbers less than n. Returns 0 if n is 0 or less.\n \"\"\"\n if n <= 0:\n return 0\n count = 0\n for num in range(2, n): #Start from 2 as 1 is not prime\n is_prime = True\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n is_prime = False\n break\n if is_prime:\n count += 1\n return count", "matching_cluster_idx": 8}, {"solution": "def count_Primes_nums(n):\n \"\"\"\n Counts the number of prime numbers less than a given non-negative number.\n\n Args:\n n: A non-negative integer.\n\n Returns:\n The number of prime numbers less than n. Returns 0 if n is 0 or less.\n\n Raises:\n TypeError: if input is not an integer.\n ValueError: if input is negative.\n\n \"\"\"\n if not isinstance(n, int):\n raise TypeError(\"Input must be an integer.\")\n if n < 0:\n raise ValueError(\"Input must be a non-negative integer.\")\n if n <= 2:\n return 0 #Handle base cases\n\n count = 0\n for num in range(2, n):\n is_prime = True\n for i in range(2, int(num**0.5) + 1): # Optimize by checking only up to the square root\n if num % i == 0:\n is_prime = False\n break\n if is_prime:\n count += 1\n return count", "matching_cluster_idx": 8}, {"solution": "def count_Primes_nums(n):\n \"\"\"\n Counts the number of prime numbers less than a given non-negative number.\n\n Args:\n n: A non-negative integer.\n\n Returns:\n The number of prime numbers less than n. Returns 0 if n is 0 or less.\n\n Raises:\n TypeError: if input is not an integer.\n ValueError: if input is negative.\n\n \"\"\"\n if not isinstance(n, int):\n raise TypeError(\"Input must be an integer.\")\n if n < 0:\n raise ValueError(\"Input must be non-negative.\")\n if n <= 2:\n return 0\n\n count = 0\n for i in range(2, n):\n is_prime = True\n for j in range(2, int(i**0.5) + 1):\n if i % j == 0:\n is_prime = False\n break\n if is_prime:\n count += 1\n return count", "matching_cluster_idx": 8}, {"solution": "def count_Primes_nums(n):\n \"\"\"\n Counts the number of prime numbers less than a given non-negative number.\n\n Args:\n n: A non-negative integer.\n\n Returns:\n The number of prime numbers less than n. Returns 0 if n is 0 or less.\n \"\"\"\n if n <= 2:\n return 0\n\n count = 0\n for num in range(2, n):\n is_prime = True\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n is_prime = False\n break\n if is_prime:\n count += 1\n return count", "matching_cluster_idx": 8}, {"solution": "def count_Primes_nums(n):\n \"\"\"\n Write a python function that takes in a non-negative number and returns the number of prime numbers less than the given non-negative number.\n assert count_Primes_nums(5) == 2\n \"\"\"\n if n <= 1:\n return 0\n count = 0\n prime = [True] * n\n prime[0] = prime[1] = False\n for p in range(2, int(n**0.5) + 1):\n if prime[p]:\n for i in range(p * p, n, p):\n prime[i] = False\n for p in range(2, n):\n if prime[p]:\n count += 1\n return count", "matching_cluster_idx": 13}, {"solution": "def count_Primes_nums(n):\n \"\"\"\n Counts the number of prime numbers less than a given non-negative number.\n\n Args:\n n: A non-negative integer.\n\n Returns:\n The number of prime numbers less than n. Returns 0 if n is 0 or less.\n\n Raises:\n TypeError: if input is not an integer.\n ValueError: if input is negative.\n\n \"\"\"\n if not isinstance(n, int):\n raise TypeError(\"Input must be an integer.\")\n if n < 0:\n raise ValueError(\"Input must be a non-negative integer.\")\n if n <= 2:\n return 0\n\n count = 0\n for num in range(2, n):\n is_prime = True\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n is_prime = False\n break\n if is_prime:\n count += 1\n return count", "matching_cluster_idx": 8}, {"solution": "def count_Primes_nums(n):\n \"\"\"\n Counts the number of prime numbers less than a given non-negative number.\n\n Args:\n n: A non-negative integer.\n\n Returns:\n The number of prime numbers less than n. Returns 0 if n is 0 or less.\n\n \"\"\"\n if n <= 0:\n return 0\n count = 0\n for num in range(2, n): #Start from 2, as 0 and 1 are not prime\n is_prime = True\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n is_prime = False\n break\n if is_prime:\n count += 1\n return count", "matching_cluster_idx": 8}, {"solution": "def count_Primes_nums(n):\n \"\"\"\n Counts the number of prime numbers less than a given non-negative number.\n\n Args:\n n: A non-negative integer.\n\n Returns:\n The number of prime numbers less than n. Returns 0 if n is 0 or less.\n \"\"\"\n if n <= 2:\n return 0 # 0 and 1 are not prime\n\n count = 0\n for num in range(2, n):\n is_prime = True\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n is_prime = False\n break\n if is_prime:\n count += 1\n return count", "matching_cluster_idx": 8}, {"solution": "def count_Primes_nums(n):\n \"\"\"\n Counts the number of prime numbers less than a given non-negative number.\n\n Args:\n n: A non-negative integer.\n\n Returns:\n The number of prime numbers less than n. Returns 0 if n is 0 or less.\n\n Raises:\n TypeError: If input is not an integer.\n ValueError: If input is negative.\n \"\"\"\n if not isinstance(n, int):\n raise TypeError(\"Input must be an integer.\")\n if n < 0:\n raise ValueError(\"Input must be a non-negative integer.\")\n if n <= 2:\n return 0\n\n count = 0\n for num in range(2, n):\n is_prime = True\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n is_prime = False\n break\n if is_prime:\n count += 1\n return count", "matching_cluster_idx": 8}, {"solution": "def count_Primes_nums(n):\n \"\"\"\n Counts the number of prime numbers less than n.\n\n Args:\n n: A non-negative integer.\n\n Returns:\n The number of prime numbers less than n. Returns 0 if n is 0 or less.\n \"\"\"\n if n <= 0:\n return 0\n count = 0\n for i in range(2, n):\n is_prime = True\n for j in range(2, int(i**0.5) + 1):\n if i % j == 0:\n is_prime = False\n break\n if is_prime:\n count += 1\n return count", "matching_cluster_idx": 8}, {"solution": "def count_Primes_nums(n):\n \"\"\"\n Write a python function that takes in a non-negative number and returns the number of prime numbers less than the given non-negative number.\n assert count_Primes_nums(5) == 2\n \"\"\"\n if n <= 1:\n return 0\n \n count = 0\n primes = []\n for num in range(2, n):\n is_prime = True\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n is_prime = False\n break\n if is_prime:\n count += 1\n\n return count", "matching_cluster_idx": 8}, {"solution": "def count_Primes_nums(n):\n \"\"\"\n Write a python function that takes in a non-negative number and returns the number of prime numbers less than the given non-negative number.\n assert count_Primes_nums(5) == 2\n \"\"\"\n if n <= 1:\n return 0\n\n count = 0\n for num in range(2, n):\n is_prime = True\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n is_prime = False\n break\n if is_prime:\n count += 1\n return count", "matching_cluster_idx": 8}, {"solution": "def count_Primes_nums(n):\n \"\"\"\n Counts the number of prime numbers less than a given non-negative number.\n\n Args:\n n: A non-negative integer.\n\n Returns:\n The number of prime numbers less than n. Returns 0 if n is 0 or less.\n \"\"\"\n if n <= 1:\n return 0\n\n count = 0\n for num in range(2, n):\n is_prime = True\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n is_prime = False\n break\n if is_prime:\n count += 1\n return count", "matching_cluster_idx": 8}, {"solution": "def count_Primes_nums(n):\n \"\"\"\n Counts the number of prime numbers less than a given non-negative number.\n\n Args:\n n: A non-negative integer.\n\n Returns:\n The number of prime numbers less than n. Returns 0 if n is 0 or less.\n \"\"\"\n if n <= 2:\n return 0\n \n count = 0\n for num in range(2, n):\n is_prime = True\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n is_prime = False\n break\n if is_prime:\n count += 1\n return count", "matching_cluster_idx": 8}, {"solution": "def count_Primes_nums(n):\n \"\"\"\n Counts the number of prime numbers less than a given non-negative number.\n\n Args:\n n: A non-negative integer.\n\n Returns:\n The number of prime numbers less than n. Returns 0 if n is 0 or less.\n \"\"\"\n if n <= 1:\n return 0\n count = 0\n prime = [True] * n\n prime[0] = prime[1] = False # 0 and 1 are not prime\n\n for p in range(2, int(n**0.5) + 1):\n if prime[p]:\n for i in range(p * p, n, p):\n prime[i] = False\n\n for p in range(2, n):\n if prime[p]:\n count += 1\n\n return count", "matching_cluster_idx": 13}]}, "Mbpp/265": {"dps": null, "dps_norm": null, "pass@1": 0.0, "profiled": []}, "Mbpp/281": {"dps": 94.3, "dps_norm": 84.54545454545455, "pass@1": 100.0, "profiled": [{"solution": "def all_unique(lst):\n \"\"\"\n Checks if all elements in a list are unique.\n\n Args:\n lst: The input list.\n\n Returns:\n True if all elements are unique, False otherwise.\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(input_list):\n \"\"\"\n Checks if all elements in a list are unique.\n\n Args:\n input_list: A list of elements.\n\n Returns:\n True if all elements are unique, False otherwise.\n \"\"\"\n seen = set()\n for item in input_list:\n if item in seen:\n return False\n seen.add(item)\n return True", "matching_cluster_idx": 9}, {"solution": "def all_unique(lst):\n \"\"\"\n Checks if all elements in a list are unique.\n\n Args:\n lst: The input list.\n\n Returns:\n True if all elements are unique, False otherwise.\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(input_list):\n \"\"\"\n Checks if all elements in a list are unique.\n\n Args:\n input_list: A list of elements.\n\n Returns:\n True if all elements are unique, False otherwise.\n \"\"\"\n seen = set()\n for item in input_list:\n if item in seen:\n return False\n seen.add(item)\n return True", "matching_cluster_idx": 9}, {"solution": "def all_unique(input_list):\n \"\"\"\n Checks if all elements in a list are unique.\n\n Args:\n input_list: A list of elements.\n\n Returns:\n True if all elements are unique, False otherwise.\n \"\"\"\n return len(input_list) == len(set(input_list))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n Checks if all elements in a list are unique.\n\n Args:\n lst: The input list.\n\n Returns:\n True if all elements are unique, False otherwise.\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n Checks if all elements in a list are unique.\n\n Args:\n lst: The input list.\n\n Returns:\n True if all elements are unique, False otherwise.\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(input_list):\n \"\"\"\n Checks if all elements in a list are unique.\n\n Args:\n input_list: A list of elements.\n\n Returns:\n True if all elements are unique, False otherwise.\n \"\"\"\n return len(input_list) == len(set(input_list))", "matching_cluster_idx": 8}, {"solution": "def all_unique(input_list):\n \"\"\"\n Checks if all elements in a list are unique.\n\n Args:\n input_list: A list of elements.\n\n Returns:\n True if all elements are unique, False otherwise.\n \"\"\"\n seen = set()\n for item in input_list:\n if item in seen:\n return False\n seen.add(item)\n return True", "matching_cluster_idx": 9}, {"solution": "def all_unique(input_list):\n \"\"\"\n Checks if all elements in a list are unique.\n\n Args:\n input_list: A list of elements.\n\n Returns:\n True if all elements are unique, False otherwise.\n \"\"\"\n seen = set()\n for item in input_list:\n if item in seen:\n return False\n seen.add(item)\n return True", "matching_cluster_idx": 9}, {"solution": "def all_unique(lst):\n \"\"\"\n Checks if all elements in a list are unique.\n\n Args:\n lst: The input list.\n\n Returns:\n True if all elements are unique, False otherwise.\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n Checks if all elements in a list are unique.\n\n Args:\n lst: The input list.\n\n Returns:\n True if all elements are unique, False otherwise.\n \"\"\"\n seen = set()\n for item in lst:\n if item in seen:\n return False\n seen.add(item)\n return True", "matching_cluster_idx": 9}, {"solution": "def all_unique(lst):\n \"\"\"\n Checks if all elements in a list are unique.\n\n Args:\n lst: The input list.\n\n Returns:\n True if all elements are unique, False otherwise.\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n Checks if all elements in a list are unique.\n\n Args:\n lst: The input list.\n\n Returns:\n True if all elements are unique, False otherwise.\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n Checks if all elements in a list are unique.\n\n Args:\n lst: The input list.\n\n Returns:\n True if all elements are unique, False otherwise.\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n Checks if all elements in a list are unique.\n\n Args:\n lst: The input list.\n\n Returns:\n True if all elements are unique, False otherwise.\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n Checks if all elements in a list are unique.\n\n Args:\n lst: A list of elements.\n\n Returns:\n True if all elements are unique, False otherwise.\n \"\"\"\n seen = set()\n for item in lst:\n if item in seen:\n return False\n seen.add(item)\n return True", "matching_cluster_idx": 9}, {"solution": "def all_unique(input_list):\n \"\"\"\n Checks if all elements in a list are unique.\n\n Args:\n input_list: A list of elements.\n\n Returns:\n True if all elements are unique, False otherwise.\n \"\"\"\n return len(input_list) == len(set(input_list))", "matching_cluster_idx": 8}, {"solution": "def all_unique(input_list):\n \"\"\"\n Checks if all elements in a list are unique.\n\n Args:\n input_list: A list of elements.\n\n Returns:\n True if all elements are unique, False otherwise.\n \"\"\"\n return len(input_list) == len(set(input_list))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n Checks if all elements in a list are unique.\n\n Args:\n lst: The input list.\n\n Returns:\n True if all elements are unique, False otherwise.\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}]}, "Mbpp/296": {"dps": 28.205128205128204, "dps_norm": 66.66666666666667, "pass@1": 100.0, "profiled": [{"solution": "def get_Inv_Count(arr):\n \"\"\"\n Counts the number of inversions in an array.\n\n An inversion is a pair of indices (i, j) such that i < j and arr[i] > arr[j].\n\n Args:\n arr: The input array of numbers.\n\n Returns:\n The number of inversions in the array.\n \"\"\"\n count = 0\n n = len(arr)\n for i in range(n):\n for j in range(i + 1, n):\n if arr[i] > arr[j]:\n count += 1\n return count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n \"\"\"\n Counts the number of inversions in an array. An inversion is a pair of indices (i, j) such that i < j and arr[i] > arr[j].\n\n Args:\n arr: The input array of numbers.\n\n Returns:\n The number of inversions in the array.\n \"\"\"\n count = 0\n n = len(arr)\n for i in range(n):\n for j in range(i + 1, n):\n if arr[i] > arr[j]:\n count += 1\n return count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n \"\"\"\n Counts the number of inversions in an array.\n\n An inversion is a pair of indices (i, j) such that i < j and arr[i] > arr[j].\n\n Args:\n arr: The input array of numbers.\n\n Returns:\n The number of inversions in the array.\n \"\"\"\n count = 0\n n = len(arr)\n for i in range(n):\n for j in range(i + 1, n):\n if arr[i] > arr[j]:\n count += 1\n return count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n \"\"\"\n Counts the number of inversions in an array.\n\n An inversion is a pair of indices (i, j) such that i < j and arr[i] > arr[j].\n\n Args:\n arr: The input array of numbers.\n\n Returns:\n The number of inversions in the array.\n \"\"\"\n count = 0\n n = len(arr)\n for i in range(n):\n for j in range(i + 1, n):\n if arr[i] > arr[j]:\n count += 1\n return count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n \"\"\"\n Counts the number of inversions in an array.\n\n An inversion is a pair of indices (i, j) such that i < j and arr[i] > arr[j].\n\n Args:\n arr: The input array of numbers.\n\n Returns:\n The number of inversions in the array.\n \"\"\"\n count = 0\n n = len(arr)\n for i in range(n):\n for j in range(i + 1, n):\n if arr[i] > arr[j]:\n count += 1\n return count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n \"\"\"Counts the number of inversions in an array.\n\n An inversion is a pair of indices (i, j) such that i < j and arr[i] > arr[j].\n\n Args:\n arr: The input array of numbers.\n\n Returns:\n The number of inversions in the array.\n \"\"\"\n count = 0\n n = len(arr)\n for i in range(n):\n for j in range(i + 1, n):\n if arr[i] > arr[j]:\n count += 1\n return count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n \"\"\"\n Counts the number of inversions in an array.\n\n An inversion is a pair of indices (i, j) such that i < j and arr[i] > arr[j].\n\n Args:\n arr: The input array of numbers.\n\n Returns:\n The number of inversions in the array.\n \"\"\"\n count = 0\n n = len(arr)\n for i in range(n):\n for j in range(i + 1, n):\n if arr[i] > arr[j]:\n count += 1\n return count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n \"\"\"\n Counts the number of inversions in an array.\n\n An inversion is a pair of indices (i, j) such that i < j and arr[i] > arr[j].\n\n Args:\n arr: The input array of numbers.\n\n Returns:\n The number of inversions in the array.\n \"\"\"\n count = 0\n n = len(arr)\n for i in range(n):\n for j in range(i + 1, n):\n if arr[i] > arr[j]:\n count += 1\n return count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n \"\"\"\n Counts the number of inversions in an array. An inversion is a pair of indices (i, j) such that i < j and arr[i] > arr[j].\n\n Args:\n arr: The input array of numbers.\n\n Returns:\n The number of inversions in the array.\n \"\"\"\n count = 0\n n = len(arr)\n for i in range(n):\n for j in range(i + 1, n):\n if arr[i] > arr[j]:\n count += 1\n return count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n \"\"\"\n Counts the number of inversions in an array.\n\n An inversion is a pair of indices (i, j) such that i < j and arr[i] > arr[j].\n\n Args:\n arr: The input array of numbers.\n\n Returns:\n The number of inversions in the array.\n \"\"\"\n count = 0\n n = len(arr)\n for i in range(n):\n for j in range(i + 1, n):\n if arr[i] > arr[j]:\n count += 1\n return count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n \"\"\"\n Counts the number of inversions in an array.\n\n An inversion is a pair of indices (i, j) such that i < j and arr[i] > arr[j].\n\n Args:\n arr: The input array of numbers.\n\n Returns:\n The number of inversions in the array.\n \"\"\"\n count = 0\n n = len(arr)\n for i in range(n):\n for j in range(i + 1, n):\n if arr[i] > arr[j]:\n count += 1\n return count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n \"\"\"\n Counts the number of inversions in an array.\n\n An inversion is a pair of indices (i, j) such that i < j and arr[i] > arr[j].\n\n Args:\n arr: The input array of numbers.\n\n Returns:\n The number of inversions in the array.\n \"\"\"\n count = 0\n n = len(arr)\n for i in range(n):\n for j in range(i + 1, n):\n if arr[i] > arr[j]:\n count += 1\n return count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n \"\"\"\n Counts the number of inversions in an array.\n\n An inversion is a pair of indices (i, j) such that i < j and arr[i] > arr[j].\n\n Args:\n arr: The input array of numbers.\n\n Returns:\n The number of inversions in the array.\n \"\"\"\n count = 0\n n = len(arr)\n for i in range(n):\n for j in range(i + 1, n):\n if arr[i] > arr[j]:\n count += 1\n return count\narr = [1, 20, 6, 4, 5]", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n \"\"\"\n Counts the number of inversions in an array.\n\n An inversion is a pair of indices (i, j) such that i < j and arr[i] > arr[j].\n\n Args:\n arr: The input array of numbers.\n\n Returns:\n The number of inversions in the array.\n \"\"\"\n count = 0\n n = len(arr)\n for i in range(n):\n for j in range(i + 1, n):\n if arr[i] > arr[j]:\n count += 1\n return count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n \"\"\"\n Counts the number of inversions in an array.\n\n An inversion is a pair of indices (i, j) such that i < j and arr[i] > arr[j].\n\n Args:\n arr: The input array of numbers.\n\n Returns:\n The number of inversions in the array.\n \"\"\"\n count = 0\n n = len(arr)\n for i in range(n):\n for j in range(i + 1, n):\n if arr[i] > arr[j]:\n count += 1\n return count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n \"\"\"\n Counts the number of inversions in an array.\n\n An inversion is a pair of indices (i, j) such that i < j and arr[i] > arr[j].\n\n Args:\n arr: The input array of numbers.\n\n Returns:\n The number of inversions in the array.\n \"\"\"\n count = 0\n n = len(arr)\n for i in range(n):\n for j in range(i + 1, n):\n if arr[i] > arr[j]:\n count += 1\n return count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n \"\"\"\n Counts the number of inversions in an array.\n\n An inversion is a pair of indices (i, j) such that i < j and arr[i] > arr[j].\n\n Args:\n arr: The input array of numbers.\n\n Returns:\n The number of inversions in the array.\n \"\"\"\n count = 0\n n = len(arr)\n for i in range(n):\n for j in range(i + 1, n):\n if arr[i] > arr[j]:\n count += 1\n return count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n \"\"\"\n Counts the number of inversions in an array. An inversion is a pair of indices (i, j) such that i < j and arr[i] > arr[j].\n\n Args:\n arr: The input array of numbers.\n\n Returns:\n The number of inversions in the array.\n \"\"\"\n count = 0\n n = len(arr)\n for i in range(n):\n for j in range(i + 1, n):\n if arr[i] > arr[j]:\n count += 1\n return count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n \"\"\"\n Counts the number of inversions in an array.\n\n An inversion is a pair of indices (i, j) such that i < j and arr[i] > arr[j].\n\n Args:\n arr: The input array of numbers.\n\n Returns:\n The number of inversions in the array.\n \"\"\"\n count = 0\n n = len(arr)\n for i in range(n):\n for j in range(i + 1, n):\n if arr[i] > arr[j]:\n count += 1\n return count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n \"\"\"\n Counts the number of inversions in an array.\n\n An inversion is a pair of indices (i, j) such that i < j and arr[i] > arr[j].\n\n Args:\n arr: The input array of numbers.\n\n Returns:\n The number of inversions in the array.\n \"\"\"\n count = 0\n n = len(arr)\n for i in range(n):\n for j in range(i + 1, n):\n if arr[i] > arr[j]:\n count += 1\n return count", "matching_cluster_idx": 3}]}, "Mbpp/308": {"dps": 90.96551724137932, "dps_norm": 65.0, "pass@1": 100.0, "profiled": [{"solution": "def large_product(list1, list2, n):\n \"\"\"\n Finds the n largest products from pairs of numbers selected from two lists.\n\n Args:\n list1: The first list of numbers.\n list2: The second list of numbers.\n n: The number of largest products to return.\n\n Returns:\n A list containing the n largest products, sorted in descending order. Returns an empty list if either input list is empty or n is 0 or less.\n \"\"\"\n if not list1 or not list2 or n <= 0:\n return []\n\n products = []\n for x in list1:\n for y in list2:\n products.append(x * y)\n\n products.sort(reverse=True) #Sort in descending order\n\n return products[:n]", "matching_cluster_idx": 3}, {"solution": "import heapq\ndef large_product(list1, list2, n):\n \"\"\"\n Finds the n largest products from pairs of numbers in two lists.\n\n Args:\n list1: The first list of numbers.\n list2: The second list of numbers.\n n: The number of largest products to find.\n\n Returns:\n A list of the n largest products, sorted in descending order. Returns an empty list if either input list is empty or n is 0 or less.\n \"\"\"\n if not list1 or not list2 or n <= 0:\n return []\n\n products = []\n for x in list1:\n for y in list2:\n products.append(x * y)\n\n # Use a min-heap to efficiently track the n largest products\n return heapq.nlargest(n, products)", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n \"\"\"\n Finds the n largest products from pairs of numbers in two lists.\n\n Args:\n list1: The first list of numbers.\n list2: The second list of numbers.\n n: The number of largest products to find.\n\n Returns:\n A list containing the n largest products, sorted in descending order. Returns an empty list if either input list is empty or n is 0 or negative.\n \"\"\"\n if not list1 or not list2 or n <=0:\n return []\n\n products = []\n for x in list1:\n for y in list2:\n products.append(x * y)\n\n products.sort(reverse=True) #Sort in descending order\n\n return products[:n]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n \"\"\"\n Finds the n largest products from pairs of numbers in two lists.\n\n Args:\n list1: The first list of numbers.\n list2: The second list of numbers.\n n: The number of largest products to find.\n\n Returns:\n A list containing the n largest products, sorted in descending order. Returns an empty list if either input list is empty or n is 0 or less.\n \"\"\"\n if not list1 or not list2 or n <= 0:\n return []\n\n products = []\n for x in list1:\n for y in list2:\n products.append(x * y)\n\n products.sort(reverse=True) #Sort in descending order\n\n return products[:n]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n \"\"\"\n Finds the n largest products from pairs of numbers, one from each list.\n\n Args:\n list1: The first list of numbers.\n list2: The second list of numbers.\n n: The number of largest products to find.\n\n Returns:\n A list containing the n largest products, sorted in descending order. Returns an empty list if either input list is empty or n is 0 or less.\n\n \"\"\"\n if not list1 or not list2 or n <=0:\n return []\n\n products = []\n for i in list1:\n for j in list2:\n products.append(i * j)\n \n products.sort(reverse=True) #Sort in descending order\n\n return products[:n]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n \"\"\"\n Finds the specified number of largest products from two given lists, selecting one factor from each list.\n\n Args:\n list1: The first list of numbers.\n list2: The second list of numbers.\n n: The number of largest products to find.\n\n Returns:\n A list containing the n largest products, sorted in descending order. Returns an empty list if either input list is empty or n is 0 or less.\n\n \"\"\"\n if not list1 or not list2 or n <= 0:\n return []\n\n products = []\n for a in list1:\n for b in list2:\n products.append(a * b)\n\n products.sort(reverse=True) #Sort in descending order\n\n return products[:n]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n \"\"\"\n Finds the n largest products from pairs of numbers, one from each list.\n\n Args:\n list1: The first list of numbers.\n list2: The second list of numbers.\n n: The number of largest products to return.\n\n Returns:\n A list containing the n largest products, sorted in descending order. Returns an empty list if either input list is empty or n is 0 or less.\n \"\"\"\n if not list1 or not list2 or n <= 0:\n return []\n\n products = []\n for x in list1:\n for y in list2:\n products.append(x * y)\n\n products.sort(reverse=True) # Sort in descending order\n\n return products[:n]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n \"\"\"\n Finds the n largest products from pairs of numbers, one from each list.\n\n Args:\n list1: The first list of numbers.\n list2: The second list of numbers.\n n: The number of largest products to return.\n\n Returns:\n A list containing the n largest products, sorted in descending order. Returns an empty list if either input list is empty or n is 0 or negative.\n \"\"\"\n if not list1 or not list2 or n <= 0:\n return []\n\n products = []\n for x in list1:\n for y in list2:\n products.append(x * y)\n\n products.sort(reverse=True) #Sort in descending order\n\n return products[:n]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n \"\"\"\n Finds the n largest products from pairs of numbers, one from each list.\n\n Args:\n list1: The first list of numbers.\n list2: The second list of numbers.\n n: The number of largest products to find.\n\n Returns:\n A list containing the n largest products, sorted in descending order. Returns an empty list if either input list is empty or n is 0 or less.\n \"\"\"\n if not list1 or not list2 or n <= 0:\n return []\n\n products = []\n for x in list1:\n for y in list2:\n products.append(x * y)\n\n products.sort(reverse=True) #Sort in descending order\n\n return products[:n]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n \"\"\"\n Finds the n largest products from pairs of numbers, one from each list.\n\n Args:\n list1: The first list of numbers.\n list2: The second list of numbers.\n n: The number of largest products to return.\n\n Returns:\n A list containing the n largest products, sorted in descending order. Returns an empty list if either input list is empty or n is 0 or less.\n\n \"\"\"\n if not list1 or not list2 or n <= 0:\n return []\n\n products = []\n for x in list1:\n for y in list2:\n products.append(x * y)\n\n products.sort(reverse=True) #Sort in descending order\n\n return products[:n]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n \"\"\"\n Finds the n largest products from pairs of numbers in two lists.\n\n Args:\n list1: The first list of numbers.\n list2: The second list of numbers.\n n: The number of largest products to find.\n\n Returns:\n A list containing the n largest products, sorted in descending order. Returns an empty list if either input list is empty or n is 0 or less.\n \"\"\"\n if not list1 or not list2 or n <= 0:\n return []\n\n products = []\n for x in list1:\n for y in list2:\n products.append(x * y)\n\n products.sort(reverse=True) #Sort in descending order\n\n return products[:n]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n \"\"\"\n Finds the n largest products from pairs of numbers, one from each list.\n\n Args:\n list1: The first list of numbers.\n list2: The second list of numbers.\n n: The number of largest products to find.\n\n Returns:\n A list containing the n largest products, sorted in descending order. Returns an empty list if either input list is empty or n is 0 or less.\n \"\"\"\n if not list1 or not list2 or n <= 0:\n return []\n\n products = []\n for x in list1:\n for y in list2:\n products.append(x * y)\n\n products.sort(reverse=True) #Sort in descending order\n\n return products[:n]", "matching_cluster_idx": 3}, {"solution": "import heapq\ndef large_product(list1, list2, n):\n \"\"\"\n Finds the n largest products from pairs of numbers in two lists.\n\n Args:\n list1: The first list of numbers.\n list2: The second list of numbers.\n n: The number of largest products to find.\n\n Returns:\n A list of the n largest products, sorted in descending order. Returns an empty list if either input list is empty or n is 0 or negative.\n \"\"\"\n if not list1 or not list2 or n <= 0:\n return []\n\n products = []\n for x in list1:\n for y in list2:\n products.append(x * y)\n\n return heapq.nlargest(n, products)", "matching_cluster_idx": 3}, {"solution": "import itertools\ndef large_product(list1, list2, n):\n \"\"\"\n Finds the n largest products from pairs of elements, one from each list.\n\n Args:\n list1: The first list of numbers.\n list2: The second list of numbers.\n n: The number of largest products to return.\n\n Returns:\n A list containing the n largest products, sorted in descending order. Returns an empty list if either input list is empty or n is 0 or less.\n \"\"\"\n if not list1 or not list2 or n <= 0:\n return []\n\n products = []\n for a, b in itertools.product(list1, list2):\n products.append(a * b)\n\n products.sort(reverse=True) # Sort in descending order\n\n return products[:n]", "matching_cluster_idx": 2}, {"solution": "def large_product(list1, list2, n):\n \"\"\"\n Finds the specified number of largest products from two given lists, selecting one factor from each list.\n\n Args:\n list1: The first list of numbers.\n list2: The second list of numbers.\n n: The number of largest products to find.\n\n Returns:\n A list containing the n largest products, sorted in descending order. Returns an empty list if either input list is empty or n is 0 or less.\n \"\"\"\n if not list1 or not list2 or n <= 0:\n return []\n\n products = []\n for x in list1:\n for y in list2:\n products.append(x * y)\n\n products.sort(reverse=True) #Sort in descending order\n\n return products[:n]", "matching_cluster_idx": 3}, {"solution": "import heapq\ndef large_product(list1, list2, n):\n \"\"\"\n Finds the n largest products from pairs of numbers in two lists.\n\n Args:\n list1: The first list of numbers.\n list2: The second list of numbers.\n n: The number of largest products to find.\n\n Returns:\n A list containing the n largest products, sorted in descending order. Returns an empty list if either input list is empty or n is 0 or less.\n \"\"\"\n\n if not list1 or not list2 or n <= 0:\n return []\n\n products = []\n for x in list1:\n for y in list2:\n products.append(x * y)\n\n return heapq.nlargest(n, products)", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n \"\"\"\n Finds the n largest products from pairs of numbers, one from each list.\n\n Args:\n list1: The first list of numbers.\n list2: The second list of numbers.\n n: The number of largest products to find.\n\n Returns:\n A list containing the n largest products, sorted in descending order. Returns an empty list if either input list is empty or n is 0 or less.\n \"\"\"\n if not list1 or not list2 or n <= 0:\n return []\n\n products = []\n for x in list1:\n for y in list2:\n products.append(x * y)\n\n products.sort(reverse=True) #Sort in descending order\n\n return products[:n]", "matching_cluster_idx": 3}, {"solution": "import itertools\ndef large_product(list1, list2, n):\n \"\"\"\n Finds the n largest products from pairs of numbers selected from two lists.\n\n Args:\n list1: The first list of numbers.\n list2: The second list of numbers.\n n: The number of largest products to find.\n\n Returns:\n A list containing the n largest products, sorted in descending order. Returns an empty list if either input list is empty or n is 0 or negative.\n \"\"\"\n if not list1 or not list2 or n <= 0:\n return []\n\n products = []\n for pair in itertools.product(list1, list2):\n products.append(pair[0] * pair[1])\n\n products.sort(reverse=True)\n return products[:n]", "matching_cluster_idx": 2}, {"solution": "def large_product(list1, list2, n):\n \"\"\"\n Finds the specified number of largest products from two given lists.\n\n Args:\n list1: The first list of numbers.\n list2: The second list of numbers.\n n: The number of largest products to find.\n\n Returns:\n A list containing the n largest products, sorted in descending order. Returns an empty list if either input list is empty or n is 0 or negative.\n \"\"\"\n if not list1 or not list2 or n <= 0:\n return []\n\n products = []\n for x in list1:\n for y in list2:\n products.append(x * y)\n\n products.sort(reverse=True)\n return products[:n]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n \"\"\"\n Finds the n largest products from pairs of numbers, one from each list.\n\n Args:\n list1: The first list of numbers.\n list2: The second list of numbers.\n n: The number of largest products to return.\n\n Returns:\n A list containing the n largest products, sorted in descending order. Returns an empty list if either input list is empty or n is 0 or less.\n \"\"\"\n if not list1 or not list2 or n <= 0:\n return []\n\n products = []\n for x in list1:\n for y in list2:\n products.append(x * y)\n\n products.sort(reverse=True) # Sort in descending order\n\n return products[:n]", "matching_cluster_idx": 3}]}, "Mbpp/392": {"dps": 96.73708920187794, "dps_norm": 96.53846153846153, "pass@1": 25.0, "profiled": [{"solution": "def get_max_sum(n):\n \"\"\"\n Finds the maximum sum possible using the given equation.\n\n Args:\n n: The input integer.\n\n Returns:\n The maximum sum possible.\n \"\"\"\n if n <= 1:\n return n\n \n #Memoization to avoid redundant calculations.\n memo = {}\n memo[0] = 0\n memo[1] = 1\n\n def calculate_sum(n):\n if n in memo:\n return memo[n]\n \n sum_recursive = calculate_sum(n//2) + calculate_sum(n//3) + calculate_sum(n//4) + calculate_sum(n//5)\n memo[n] = max(sum_recursive, n)\n return memo[n]\n\n return calculate_sum(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n \"\"\"\n Finds the maximum sum possible using the given recursive equation.\n\n Args:\n n: The input integer.\n\n Returns:\n The maximum sum possible.\n \"\"\"\n if n <= 1:\n return n\n \n #Memoization to avoid redundant calculations\n memo = {}\n memo[1] = 1\n memo[0] = 0\n\n def helper(n):\n if n in memo:\n return memo[n]\n \n sum_recursive = helper(n//2) + helper(n//3) + helper(n//4) + helper(n//5)\n memo[n] = max(sum_recursive,n)\n return memo[n]\n\n return helper(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n \"\"\"\n Calculates the maximum sum using the given recursive equation.\n\n Args:\n n: The input integer.\n\n Returns:\n The maximum sum.\n \"\"\"\n if n <= 1:\n return n\n \n #Memoization to avoid redundant calculations\n memo = {}\n memo[0] = 0\n memo[1] = 1\n\n def helper(n):\n if n in memo:\n return memo[n]\n \n sum_parts = helper(n // 2) + helper(n // 3) + helper(n // 4) + helper(n // 5)\n memo[n] = max(sum_parts, n)\n return memo[n]\n\n return helper(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n \"\"\"\n Calculates the maximum sum using the given recursive equation.\n\n Args:\n n: The input integer.\n\n Returns:\n The maximum sum.\n \"\"\"\n if n <= 1:\n return n # Base cases: f(0) = 0, f(1) = 1\n\n # Memoization to avoid redundant calculations.\n memo = {}\n memo[0] = 0\n memo[1] = 1\n\n\n def calculate_f(n):\n if n in memo:\n return memo[n]\n \n sum_parts = calculate_f(n // 2) + calculate_f(n // 3) + calculate_f(n // 4) + calculate_f(n // 5)\n memo[n] = max(sum_parts, n)\n return memo[n]\n \n\n return calculate_f(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n \"\"\"\n Calculates the maximum sum using the given recursive equation.\n\n Args:\n n: The input integer.\n\n Returns:\n The maximum sum possible.\n \"\"\"\n if n <= 1:\n return n # Base cases: f(0) = 0, f(1) = 1\n\n #Memoization to avoid redundant calculations\n memo = {}\n memo[0] = 0\n memo[1] = 1\n\n def helper(n):\n if n in memo:\n return memo[n]\n \n sum_parts = helper(n // 2) + helper(n // 3) + helper(n // 4) + helper(n // 5)\n memo[n] = max(sum_parts, n)\n return memo[n]\n\n return helper(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n \"\"\"\n Calculates the maximum sum possible using the given recursive equation.\n\n Args:\n n: The input integer.\n\n Returns:\n The maximum sum possible.\n \"\"\"\n if n <= 1:\n return n\n \n #Using memoization to avoid redundant calculations.\n memo = {}\n memo[0] = 0\n memo[1] = 1\n\n def _get_max_sum(n):\n if n in memo:\n return memo[n]\n\n sum_recursive = _get_max_sum(n//2) + _get_max_sum(n//3) + _get_max_sum(n//4) + _get_max_sum(n//5)\n memo[n] = max(sum_recursive, n)\n return memo[n]\n\n return _get_max_sum(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n \"\"\"\n Finds the maximum sum possible using the given equation.\n\n Args:\n n: The input integer.\n\n Returns:\n The maximum sum.\n \"\"\"\n if n <= 1:\n return n\n \n memo = {} # Memoization to store results for already computed values of n\n\n def f(n):\n if n in memo:\n return memo[n]\n \n if n <= 1:\n result = n\n else:\n result = max(f(n // 2) + f(n // 3) + f(n // 4) + f(n // 5), n)\n memo[n] = result\n return result\n\n return f(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n \"\"\"\n Calculates the maximum sum using the given recursive equation.\n\n Args:\n n: The input integer.\n\n Returns:\n The maximum sum.\n \"\"\"\n if n <= 1: #Base cases for recursion\n return n\n else:\n sum_recursive = get_max_sum(n // 2) + get_max_sum(n // 3) + get_max_sum(n // 4) + get_max_sum(n // 5)\n return max(sum_recursive, n)", "matching_cluster_idx": 3}, {"solution": "def get_max_sum(n):\n \"\"\"\n Finds the maximum sum possible using the given equation.\n\n Args:\n n: The input integer.\n\n Returns:\n The maximum sum.\n \"\"\"\n if n <= 1:\n return n\n \n memo = {} #Memoization to store results for previously computed n values.\n memo[0] = 0\n memo[1] = 1\n\n\n def helper(n):\n if n in memo:\n return memo[n]\n \n sum_parts = helper(n // 2) + helper(n // 3) + helper(n // 4) + helper(n // 5)\n memo[n] = max(sum_parts, n)\n return memo[n]\n\n return helper(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n \"\"\"\n Calculates the maximum sum using the given recursive equation.\n\n Args:\n n: The input integer.\n\n Returns:\n The maximum sum.\n \"\"\"\n if n <= 1:\n return n\n \n #Using memoization to avoid redundant calculations.\n memo = {}\n memo[0] = 0\n memo[1] = 1\n\n def helper(n):\n if n in memo:\n return memo[n]\n \n sum_recursive = helper(n // 2) + helper(n // 3) + helper(n // 4) + helper(n // 5)\n memo[n] = max(sum_recursive, n)\n return memo[n]\n\n return helper(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n \"\"\"\n Calculates the maximum sum possible using the given recursive equation.\n\n Args:\n n: The input integer.\n\n Returns:\n The maximum sum.\n \"\"\"\n if n <= 1:\n return n\n \n #Memoization to avoid redundant calculations.\n memo = {}\n memo[0] = 0\n memo[1] = 1\n\n def helper(n):\n if n in memo:\n return memo[n]\n \n sum_recursive = helper(n//2) + helper(n//3) + helper(n//4) + helper(n//5)\n memo[n] = max(sum_recursive, n)\n return memo[n]\n \n return helper(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n \"\"\"\n Finds the maximum sum possible using the given equation.\n\n Args:\n n: The input integer.\n\n Returns:\n The maximum sum possible.\n \"\"\"\n if n <= 1: # Base cases\n return n\n \n #Memoization to avoid redundant calculations.\n memo = {}\n memo[0] = 0\n memo[1] = 1\n\n def calculate_max_sum(n):\n if n in memo:\n return memo[n]\n \n sum_recursive = calculate_max_sum(n // 2) + calculate_max_sum(n // 3) + calculate_max_sum(n // 4) + calculate_max_sum(n // 5)\n memo[n] = max(sum_recursive, n)\n return memo[n]\n\n return calculate_max_sum(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n \"\"\"\n Finds the maximum sum possible using the given recursive equation.\n\n Args:\n n: The input integer.\n\n Returns:\n The maximum sum possible.\n \"\"\"\n if n <= 1:\n return n\n \n #Use memoization to avoid redundant calculations\n memo = {}\n memo[0] = 0\n memo[1] = 1\n\n def helper(n):\n if n in memo:\n return memo[n]\n \n sum_parts = helper(n // 2) + helper(n // 3) + helper(n // 4) + helper(n // 5)\n memo[n] = max(sum_parts, n)\n return memo[n]\n\n return helper(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n \"\"\"\n Calculates the maximum sum possible using the given recursive equation.\n\n Args:\n n: The input integer.\n\n Returns:\n The maximum sum possible.\n \"\"\"\n if n <= 1:\n return n\n \n # Use memoization to avoid redundant calculations\n memo = {}\n memo[0] = 0\n memo[1] = 1\n\n def helper(n):\n if n in memo:\n return memo[n]\n \n sum_parts = helper(n//2) + helper(n//3) + helper(n//4) + helper(n//5)\n memo[n] = max(sum_parts, n)\n return memo[n]\n\n return helper(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n \"\"\"\n Calculates the maximum sum possible using the given recursive equation.\n\n Args:\n n: The input integer.\n\n Returns:\n The maximum sum possible.\n \"\"\"\n if n <= 1:\n return n\n \n #Memoization to avoid redundant calculations\n memo = {}\n memo[1] = 1\n memo[2] = 2\n memo[3] = 3\n memo[4] = 4\n memo[5] = 5\n\n def helper(n):\n if n in memo:\n return memo[n]\n \n sum_parts = helper(n//2) + helper(n//3) + helper(n//4) + helper(n//5)\n memo[n] = max(sum_parts, n)\n return memo[n]\n\n return helper(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n \"\"\"\n Calculates the maximum sum using the given recursive equation.\n\n Args:\n n: The input integer.\n\n Returns:\n The maximum sum possible.\n \"\"\"\n if n <= 1:\n return n\n \n # Memoization to avoid redundant calculations\n memo = {}\n memo[0] = 0\n memo[1] = 1\n\n def helper(n):\n if n in memo:\n return memo[n]\n \n sum_parts = helper(n // 2) + helper(n // 3) + helper(n // 4) + helper(n // 5)\n memo[n] = max(sum_parts, n)\n return memo[n]\n\n return helper(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n \"\"\"\n Calculates the maximum sum using the given recursive equation.\n\n Args:\n n: The input integer.\n\n Returns:\n The maximum sum possible.\n \"\"\"\n if n <= 1: # Base cases\n return n\n \n #Memoization to avoid redundant calculations.\n memo = {}\n memo[0] = 0\n memo[1] = 1\n\n def calculate_sum(n):\n if n in memo:\n return memo[n]\n \n sum_recursive = calculate_sum(n // 2) + calculate_sum(n // 3) + calculate_sum(n // 4) + calculate_sum(n // 5)\n memo[n] = max(sum_recursive, n)\n return memo[n]\n \n return calculate_sum(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n \"\"\"\n Finds the maximum sum possible using the given equation.\n\n Args:\n n: The input integer.\n\n Returns:\n The maximum sum possible.\n \"\"\"\n if n <= 1:\n return n\n \n # Memoization to avoid redundant calculations\n memo = {}\n memo[0] = 0\n memo[1] = 1\n\n def calculate_sum(n):\n if n in memo:\n return memo[n]\n \n sum_parts = calculate_sum(n // 2) + calculate_sum(n // 3) + calculate_sum(n // 4) + calculate_sum(n // 5)\n memo[n] = max(sum_parts, n)\n return memo[n]\n\n return calculate_sum(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n \"\"\"\n Calculates the maximum sum possible using the given recursive equation.\n\n Args:\n n: The input integer.\n\n Returns:\n The maximum sum possible.\n \"\"\"\n if n <= 1:\n return n # Base cases: f(0) = 0, f(1) = 1\n\n # Memoization to avoid redundant calculations\n memo = {}\n memo[0] = 0\n memo[1] = 1\n\n def helper(n):\n if n in memo:\n return memo[n]\n \n sum_parts = helper(n // 2) + helper(n // 3) + helper(n // 4) + helper(n // 5)\n memo[n] = max(sum_parts, n)\n return memo[n]\n\n return helper(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n \"\"\"\n Finds the maximum sum possible using the given equation.\n\n Args:\n n: An integer.\n\n Returns:\n The maximum sum possible.\n \"\"\"\n if n <= 1:\n return n\n \n #Memoization to avoid redundant calculations\n memo = {}\n memo[0] = 0\n memo[1] = 1\n\n def helper(n):\n if n in memo:\n return memo[n]\n \n sum_parts = helper(n // 2) + helper(n // 3) + helper(n // 4) + helper(n // 5)\n memo[n] = max(sum_parts, n)\n return memo[n]\n\n return helper(n)", "matching_cluster_idx": 12}]}, "Mbpp/395": {"dps": 98.08429118773947, "dps_norm": 75.0, "pass@1": 100.0, "profiled": [{"solution": "def first_non_repeating_character(input_string):\n \"\"\"\n Finds the first non-repeating character in a given string.\n\n Args:\n input_string: The input string.\n\n Returns:\n The first non-repeating character in the string, or None if no such character exists.\n \"\"\"\n char_counts = {} # Dictionary to store character counts\n\n # Count character occurrences\n for char in input_string:\n char_counts[char] = char_counts.get(char, 0) + 1\n\n # Find the first character with count 1\n for char in input_string:\n if char_counts[char] == 1:\n return char\n\n return None # No non-repeating character found", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(input_string):\n \"\"\"\n Finds the first non-repeated character in a given string.\n\n Args:\n input_string: The input string.\n\n Returns:\n The first non-repeated character, or None if all characters are repeated.\n \"\"\"\n char_counts = {} # Dictionary to store character counts\n\n # Count character occurrences\n for char in input_string:\n char_counts[char] = char_counts.get(char, 0) + 1\n\n # Find the first character with count 1\n for char in input_string:\n if char_counts[char] == 1:\n return char\n\n return None # No non-repeated character found", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n \"\"\"\n Finds the first non-repeated character in a given string.\n\n Args:\n s: The input string.\n\n Returns:\n The first non-repeated character in the string, or None if no such character exists.\n \"\"\"\n char_counts = {}\n for char in s:\n char_counts[char] = char_counts.get(char, 0) + 1\n\n for char in s:\n if char_counts[char] == 1:\n return char\n\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(input_string):\n \"\"\"\n Finds the first non-repeating character in a given string.\n\n Args:\n input_string: The input string.\n\n Returns:\n The first non-repeating character in the string, or None if no such character exists.\n \"\"\"\n char_counts = {} # Dictionary to store character counts\n\n # Count character occurrences\n for char in input_string:\n char_counts[char] = char_counts.get(char, 0) + 1\n\n # Find the first character with count 1\n for char in input_string:\n if char_counts[char] == 1:\n return char\n\n return None # No non-repeating character found", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(input_string):\n \"\"\"\n Finds the first non-repeated character in a given string.\n\n Args:\n input_string: The input string.\n\n Returns:\n The first non-repeated character, or None if all characters are repeated.\n \"\"\"\n char_counts = {}\n for char in input_string:\n char_counts[char] = char_counts.get(char, 0) + 1\n\n for char in input_string:\n if char_counts[char] == 1:\n return char\n\n return None", "matching_cluster_idx": 5}, {"solution": "from collections import Counter\ndef first_non_repeating_character(input_string):\n \"\"\"\n Finds the first non-repeating character in a given string.\n\n Args:\n input_string: The input string.\n\n Returns:\n The first non-repeating character, or None if no such character exists.\n \"\"\"\n char_counts = Counter(input_string)\n for char in input_string:\n if char_counts[char] == 1:\n return char\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(input_string):\n \"\"\"\n Finds the first non-repeated character in a given string.\n\n Args:\n input_string: The input string.\n\n Returns:\n The first non-repeated character in the string, or None if all characters are repeated.\n \"\"\"\n char_counts = {} # Dictionary to store character counts\n\n # Count the occurrences of each character\n for char in input_string:\n char_counts[char] = char_counts.get(char, 0) + 1\n\n # Find the first character with a count of 1\n for char in input_string:\n if char_counts[char] == 1:\n return char\n\n return None # All characters are repeated", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(input_string):\n \"\"\"\n Finds the first non-repeated character in a given string.\n\n Args:\n input_string: The input string.\n\n Returns:\n The first non-repeated character in the string, or None if no such character exists.\n \"\"\"\n char_counts = {}\n for char in input_string:\n char_counts[char] = char_counts.get(char, 0) + 1\n\n for char in input_string:\n if char_counts[char] == 1:\n return char\n\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(input_string):\n \"\"\"\n Finds the first non-repeated character in a given string.\n\n Args:\n input_string: The input string.\n\n Returns:\n The first non-repeated character in the string, or None if no such character exists.\n \"\"\"\n char_counts = {}\n for char in input_string:\n char_counts[char] = char_counts.get(char, 0) + 1\n\n for char in input_string:\n if char_counts[char] == 1:\n return char\n\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(input_string):\n \"\"\"\n Finds the first non-repeated character in a given string.\n\n Args:\n input_string: The input string.\n\n Returns:\n The first non-repeated character, or None if all characters are repeated.\n \"\"\"\n char_counts = {}\n for char in input_string:\n char_counts[char] = char_counts.get(char, 0) + 1\n\n for char in input_string:\n if char_counts[char] == 1:\n return char\n\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(input_string):\n \"\"\"\n Finds the first non-repeated character in a given string.\n\n Args:\n input_string: The input string.\n\n Returns:\n The first non-repeated character in the string, or None if no such character exists.\n \"\"\"\n char_counts = {}\n for char in input_string:\n char_counts[char] = char_counts.get(char, 0) + 1\n\n for char in input_string:\n if char_counts[char] == 1:\n return char\n\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(input_string):\n \"\"\"\n Finds the first non-repeated character in a given string.\n\n Args:\n input_string: The input string.\n\n Returns:\n The first non-repeated character in the string, or None if all characters are repeated.\n \"\"\"\n char_counts = {}\n for char in input_string:\n char_counts[char] = char_counts.get(char, 0) + 1\n\n for char in input_string:\n if char_counts[char] == 1:\n return char\n\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(input_string):\n \"\"\"\n Finds the first non-repeated character in a given string.\n\n Args:\n input_string: The input string.\n\n Returns:\n The first non-repeated character, or None if all characters are repeated.\n \"\"\"\n char_counts = {}\n for char in input_string:\n char_counts[char] = char_counts.get(char, 0) + 1\n\n for char in input_string:\n if char_counts[char] == 1:\n return char\n\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n \"\"\"\n Finds the first non-repeating character in a given string.\n\n Args:\n s: The input string.\n\n Returns:\n The first non-repeating character, or None if all characters are repeated.\n \"\"\"\n char_counts = {}\n for char in s:\n char_counts[char] = char_counts.get(char, 0) + 1\n\n for char in s:\n if char_counts[char] == 1:\n return char\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(input_string):\n \"\"\"\n Finds the first non-repeated character in a given string.\n\n Args:\n input_string: The input string.\n\n Returns:\n The first non-repeated character, or None if all characters are repeated.\n \"\"\"\n char_counts = {} # Dictionary to store character counts\n\n # Count character occurrences\n for char in input_string:\n char_counts[char] = char_counts.get(char, 0) + 1\n\n # Find the first character with count 1\n for char in input_string:\n if char_counts[char] == 1:\n return char\n\n return None # No non-repeated character found", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(input_string):\n \"\"\"\n Finds the first non-repeated character in a given string.\n\n Args:\n input_string: The input string.\n\n Returns:\n The first non-repeated character, or None if all characters are repeated.\n \"\"\"\n char_counts = {}\n for char in input_string:\n char_counts[char] = char_counts.get(char, 0) + 1\n\n for char in input_string:\n if char_counts[char] == 1:\n return char\n\n return None", "matching_cluster_idx": 5}, {"solution": "from collections import Counter\ndef first_non_repeating_character(s):\n \"\"\"\n Finds the first non-repeated character in a given string.\n\n Args:\n s: The input string.\n\n Returns:\n The first non-repeated character, or None if all characters are repeated.\n \"\"\"\n char_counts = Counter(s)\n for char in s:\n if char_counts[char] == 1:\n return char\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(input_string):\n \"\"\"\n Finds the first non-repeated character in a given string.\n\n Args:\n input_string: The input string.\n\n Returns:\n The first non-repeated character in the string, or None if all characters are repeated.\n \"\"\"\n char_counts = {} # Dictionary to store character counts\n\n # Count character occurrences\n for char in input_string:\n char_counts[char] = char_counts.get(char, 0) + 1\n\n # Find the first character with count 1\n for char in input_string:\n if char_counts[char] == 1:\n return char\n\n return None # No non-repeated character found", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(input_string):\n \"\"\"\n Finds the first non-repeated character in a given string.\n\n Args:\n input_string: The input string.\n\n Returns:\n The first non-repeated character, or None if all characters are repeated.\n \"\"\"\n char_counts = {}\n for char in input_string:\n char_counts[char] = char_counts.get(char, 0) + 1\n\n for char in input_string:\n if char_counts[char] == 1:\n return char\n\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(input_string):\n \"\"\"\n Finds the first non-repeated character in a given string.\n\n Args:\n input_string: The input string.\n\n Returns:\n The first non-repeated character in the string, or None if all characters are repeated.\n \"\"\"\n char_counts = {} # Dictionary to store character counts\n\n # Count character occurrences\n for char in input_string:\n char_counts[char] = char_counts.get(char, 0) + 1\n\n # Find the first character with count 1\n for char in input_string:\n if char_counts[char] == 1:\n return char\n\n return None # All characters are repeated", "matching_cluster_idx": 5}]}, "Mbpp/405": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def check_tuplex(tuple1, element):\n \"\"\"\n Checks if an element exists within a tuple.\n\n Args:\n tuple1: The input tuple.\n element: The element to search for.\n\n Returns:\n True if the element is found in the tuple, False otherwise.\n \"\"\"\n return element in tuple1", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuple_data, element):\n \"\"\"\n Checks if an element exists within a tuple.\n\n Args:\n tuple_data: The input tuple.\n element: The element to search for.\n\n Returns:\n True if the element is found in the tuple, False otherwise.\n \"\"\"\n return element in tuple_data", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(my_tuple, element):\n \"\"\"\n Checks if an element exists within a tuple.\n\n Args:\n my_tuple: The tuple to search.\n element: The element to search for.\n\n Returns:\n True if the element is found in the tuple, False otherwise.\n \"\"\"\n return element in my_tuple", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuple_data,element):\n \"\"\"\n Checks if an element exists within a tuple.\n\n Args:\n tuple_data: The input tuple.\n element: The element to search for.\n\n Returns: \n True if the element is found in the tuple, False otherwise.\n \"\"\"\n return element in tuple_data", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuple1, element):\n \"\"\"\n Checks if an element exists in a tuple.\n\n Args:\n tuple1: The input tuple.\n element: The element to search for.\n\n Returns:\n True if the element exists in the tuple, False otherwise.\n \"\"\"\n return element in tuple1", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuple_data, element):\n \"\"\"\n Checks if an element exists within a tuple.\n\n Args:\n tuple_data: The input tuple.\n element: The element to search for.\n\n Returns:\n True if the element exists in the tuple, False otherwise.\n \"\"\"\n return element in tuple_data", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuple1,element):\n \"\"\"\n This function checks if an element exists in a tuple.\n\n Args:\n tuple1: The input tuple.\n element: The element to search for.\n\n Returns:\n True if the element exists in the tuple, False otherwise.\n \"\"\"\n return element in tuple1\ntuple1 = (\"w\", 3, \"r\", \"e\", \"s\", \"o\", \"u\", \"r\", \"c\", \"e\")\nelement = 'r'", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(my_tuple, element):\n \"\"\"\n Checks if an element exists within a tuple.\n\n Args:\n my_tuple: The tuple to search.\n element: The element to search for.\n\n Returns:\n True if the element is found in the tuple, False otherwise.\n \"\"\"\n return element in my_tuple\nmy_tuple = (\"w\", 3, \"r\", \"e\", \"s\", \"o\", \"u\", \"r\", \"c\", \"e\")", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuple_in, element):\n \"\"\"\n Checks if an element exists within a tuple.\n\n Args:\n tuple_in: The input tuple.\n element: The element to check for.\n\n Returns:\n True if the element is found in the tuple, False otherwise.\n \"\"\"\n return element in tuple_in", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuple_x, element):\n \"\"\"\n Checks if an element exists within a tuple.\n\n Args:\n tuple_x: The input tuple.\n element: The element to search for.\n\n Returns:\n True if the element is found in the tuple, False otherwise.\n \"\"\"\n return element in tuple_x", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuple_in, element):\n \"\"\"\n Checks if an element exists within a tuple.\n\n Args:\n tuple_in: The input tuple.\n element: The element to check for.\n\n Returns:\n True if the element exists in the tuple, False otherwise.\n \"\"\"\n return element in tuple_in", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuple1, element):\n \"\"\"\n Checks if an element exists within a tuple.\n\n Args:\n tuple1: The input tuple.\n element: The element to search for.\n\n Returns:\n True if the element is found in the tuple, False otherwise.\n \"\"\"\n return element in tuple1", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuple1, element):\n \"\"\"\n Checks if an element exists within a tuple.\n\n Args:\n tuple1: The input tuple.\n element: The element to search for.\n\n Returns:\n True if the element is found in the tuple, False otherwise.\n \"\"\"\n return element in tuple1", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuple_data, element):\n \"\"\"\n Checks if an element exists within a tuple.\n\n Args:\n tuple_data: The input tuple.\n element: The element to search for.\n\n Returns:\n True if the element exists in the tuple, False otherwise.\n \"\"\"\n return element in tuple_data", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(my_tuple, element):\n \"\"\"\n Checks if an element exists within a tuple.\n\n Args:\n my_tuple: The tuple to search within.\n element: The element to search for.\n\n Returns:\n True if the element is found in the tuple, False otherwise.\n \"\"\"\n return element in my_tuple\nmy_tuple = (\"w\", 3, \"r\", \"e\", \"s\", \"o\", \"u\", \"r\", \"c\", \"e\")", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuple_in, element):\n \"\"\"\n Checks if an element exists within a tuple.\n\n Args:\n tuple_in: The input tuple.\n element: The element to search for.\n\n Returns:\n True if the element is found in the tuple, False otherwise.\n \"\"\"\n return element in tuple_in", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuple_input, element):\n \"\"\"\n Checks if an element exists within a tuple.\n\n Args:\n tuple_input: The input tuple.\n element: The element to search for.\n\n Returns:\n True if the element is found in the tuple, False otherwise.\n \"\"\"\n return element in tuple_input", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(my_tuple,element):\n \"\"\"\n Checks if an element exists within a tuple.\n\n Args:\n my_tuple: The input tuple.\n element: The element to search for.\n\n Returns: \n True if the element is found in the tuple, False otherwise.\n \"\"\"\n return element in my_tuple", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuple1,element):\n \"\"\"\n This function takes a tuple and an element as input and returns True if the element is present in the tuple, False otherwise.\n \"\"\"\n return element in tuple1\ntuple1 = (\"w\", 3, \"r\", \"e\", \"s\", \"o\", \"u\", \"r\", \"c\", \"e\")\nelement = 'r'", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuple1, element):\n \"\"\"\n Checks if an element exists within a tuple.\n\n Args:\n tuple1: The input tuple.\n element: The element to search for.\n\n Returns:\n True if the element is found in the tuple, False otherwise.\n \"\"\"\n return element in tuple1", "matching_cluster_idx": 3}]}, "Mbpp/414": {"dps": 91.30434782608695, "dps_norm": 88.88888888888889, "pass@1": 100.0, "profiled": [{"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Checks if any value in seq1 exists in seq2.\n\n Args:\n seq1: The first sequence.\n seq2: The second sequence.\n\n Returns:\n True if any value in seq1 is also in seq2, False otherwise.\n \"\"\"\n return any(item in seq2 for item in seq1)", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Checks if any value in seq1 exists in seq2.\n\n Args:\n seq1: The first sequence.\n seq2: The second sequence.\n\n Returns:\n True if any value in seq1 is also in seq2, False otherwise.\n \"\"\"\n return any(item in seq2 for item in seq1)", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Checks if there's any overlap between two sequences.\n\n Args:\n seq1: The first sequence.\n seq2: The second sequence.\n\n Returns:\n True if any element of seq1 is present in seq2, False otherwise.\n \"\"\"\n return any(item in seq2 for item in seq1)", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Checks if any value in seq1 exists in seq2.\n\n Args:\n seq1: The first sequence.\n seq2: The second sequence.\n\n Returns:\n True if any value in seq1 is also in seq2, False otherwise.\n \"\"\"\n return any(x in seq2 for x in seq1)", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Checks if any value in seq1 exists in seq2.\n\n Args:\n seq1: The first sequence.\n seq2: The second sequence.\n\n Returns:\n True if any value in seq1 is also in seq2, False otherwise.\n \"\"\"\n return any(item in seq2 for item in seq1)", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Checks if any element from seq1 is present in seq2.\n\n Args:\n seq1: The first sequence.\n seq2: The second sequence.\n\n Returns:\n True if any element of seq1 is found in seq2, False otherwise.\n \"\"\"\n return any(item in seq2 for item in seq1)", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Checks if any value in seq1 exists in seq2.\n\n Args:\n seq1: The first sequence.\n seq2: The second sequence.\n\n Returns:\n True if any value in seq1 is also in seq2, False otherwise.\n \"\"\"\n return any(item in seq2 for item in seq1)", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Checks if any value in seq1 exists in seq2.\n\n Args:\n seq1: The first sequence.\n seq2: The second sequence.\n\n Returns:\n True if any value in seq1 is also in seq2, False otherwise.\n \"\"\"\n return any(item in seq2 for item in seq1)", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Checks if any value in seq1 exists in seq2.\n\n Args:\n seq1: The first sequence.\n seq2: The second sequence.\n\n Returns:\n True if any value in seq1 is also in seq2, False otherwise.\n \"\"\"\n return any(item in seq2 for item in seq1)", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Checks if any value in seq1 exists in seq2.\n\n Args:\n seq1: The first sequence.\n seq2: The second sequence.\n\n Returns:\n True if any value in seq1 is also in seq2, False otherwise.\n \"\"\"\n return any(item in seq2 for item in seq1)", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Checks if any value in seq1 exists in seq2.\n\n Args:\n seq1: The first sequence.\n seq2: The second sequence.\n\n Returns:\n True if any value in seq1 is also in seq2, False otherwise.\n \"\"\"\n return any(item in seq2 for item in seq1)", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Checks if any value in seq1 exists in seq2.\n\n Args:\n seq1: The first sequence.\n seq2: The second sequence.\n\n Returns:\n True if any value in seq1 is also in seq2, False otherwise.\n \"\"\"\n return any(x in seq2 for x in seq1)", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Checks if any value in seq1 exists in seq2.\n\n Args:\n seq1: The first sequence.\n seq2: The second sequence.\n\n Returns:\n True if any value in seq1 is also in seq2, False otherwise.\n \"\"\"\n return any(item in seq2 for item in seq1)", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Checks if any value in seq1 exists in seq2.\n\n Args:\n seq1: The first sequence.\n seq2: The second sequence.\n\n Returns:\n True if any value in seq1 is also in seq2, False otherwise.\n \"\"\"\n return any(item in seq2 for item in seq1)", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Checks if any value in seq1 exists in seq2.\n\n Args:\n seq1: The first sequence.\n seq2: The second sequence.\n\n Returns:\n True if any value in seq1 is also in seq2, False otherwise.\n \"\"\"\n return any(x in seq2 for x in seq1)", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Checks if any value in seq1 exists in seq2.\n\n Args:\n seq1: The first sequence.\n seq2: The second sequence.\n\n Returns:\n True if any value in seq1 is also in seq2, False otherwise.\n \"\"\"\n return any(item in seq2 for item in seq1)", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Checks if any value in seq1 exists in seq2.\n\n Args:\n seq1: The first sequence.\n seq2: The second sequence.\n\n Returns:\n True if any value in seq1 is present in seq2, False otherwise.\n \"\"\"\n return any(item in seq2 for item in seq1)", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Checks if any value in seq1 exists in seq2.\n\n Args:\n seq1: The first sequence.\n seq2: The second sequence.\n\n Returns:\n True if any value in seq1 is also in seq2, False otherwise.\n \"\"\"\n return any(item in seq2 for item in seq1)", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Checks if any value in seq1 exists in seq2.\n\n Args:\n seq1: The first sequence.\n seq2: The second sequence.\n\n Returns:\n True if any value in seq1 is also in seq2, False otherwise.\n \"\"\"\n return any(item in seq2 for item in seq1)", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Checks if any value in seq1 exists in seq2.\n\n Args:\n seq1: The first sequence.\n seq2: The second sequence.\n\n Returns:\n True if any value in seq1 is also in seq2, False otherwise.\n \"\"\"\n return any(x in seq2 for x in seq1)", "matching_cluster_idx": 7}]}, "Mbpp/421": {"dps": 95.39094650205762, "dps_norm": 97.14285714285714, "pass@1": 100.0, "profiled": [{"solution": "def concatenate_tuple(input_tuple, delimiter='-'):\n \"\"\"\n Concatenates each element of a tuple using a specified delimiter.\n\n Args:\n input_tuple: The input tuple containing elements to concatenate.\n delimiter: The delimiter to use between elements (default is '-').\n\n Returns:\n A string containing the concatenated elements. Returns an empty string if the input tuple is empty.\n \"\"\"\n if not input_tuple:\n return \"\"\n return delimiter.join(map(str, input_tuple))", "matching_cluster_idx": 6}, {"solution": "def concatenate_tuple(input_tuple, delimiter=\"-\"):\n \"\"\"\n Concatenates each element of a tuple using a specified delimiter.\n\n Args:\n input_tuple: The input tuple. Elements can be of any type that can be converted to a string.\n delimiter: The delimiter to use between elements (default is '-').\n\n Returns:\n A string with the elements of the tuple concatenated using the delimiter. Returns an empty string if the input tuple is empty.\n\n Raises:\n TypeError: if input_tuple is not a tuple.\n\n \"\"\"\n if not isinstance(input_tuple, tuple):\n raise TypeError(\"Input must be a tuple.\")\n\n if not input_tuple: # Handle empty tuple case\n return \"\"\n\n return delimiter.join(map(str, input_tuple))", "matching_cluster_idx": 6}, {"solution": "def concatenate_tuple(input_tuple, delimiter = \"-\"):\n \"\"\"\n Concatenates the elements of a tuple using a specified delimiter.\n\n Args:\n input_tuple: The tuple to concatenate. Elements will be converted to strings.\n delimiter: The delimiter to use between elements (default is \"-\").\n\n Returns:\n A string containing the concatenated elements. Returns an empty string if the input tuple is empty.\n\n Raises:\n TypeError: if input_tuple is not a tuple.\n \"\"\"\n if not isinstance(input_tuple, tuple):\n raise TypeError(\"Input must be a tuple.\")\n\n if not input_tuple: #handle empty tuple case\n return \"\"\n\n return delimiter.join(map(str, input_tuple))", "matching_cluster_idx": 6}, {"solution": "def concatenate_tuple(input_tuple, delimiter = \"-\"):\n \"\"\"Concatenates elements of a tuple using a specified delimiter.\n\n Args:\n input_tuple: The input tuple of elements to concatenate.\n delimiter: The delimiter to use between elements (default is \"-\").\n\n Returns:\n A string containing the concatenated elements. Returns an empty string if the input tuple is empty.\n \"\"\"\n if not input_tuple:\n return \"\"\n return delimiter.join(map(str, input_tuple))", "matching_cluster_idx": 6}, {"solution": "def concatenate_tuple(input_tuple, delimiter=\"-\"):\n \"\"\"\n Concatenates each element of a tuple using a specified delimiter.\n\n Args:\n input_tuple: The input tuple containing elements to concatenate.\n delimiter: The delimiter to use between elements (default is \"-\").\n\n Returns:\n A string with all elements from the tuple concatenated using the delimiter. Returns an empty string if the input tuple is empty.\n \"\"\"\n if not input_tuple:\n return \"\"\n return delimiter.join(map(str, input_tuple))", "matching_cluster_idx": 6}, {"solution": "def concatenate_tuple(input_tuple, delimiter=\"-\"):\n \"\"\"\n Concatenates each element of a tuple using a specified delimiter.\n\n Args:\n input_tuple: The input tuple of elements to concatenate.\n delimiter: The delimiter to use between elements (default is \"-\").\n\n Returns:\n A string with the elements of the tuple concatenated by the delimiter. Returns an empty string if the input tuple is empty.\n\n Raises:\n TypeError: if input_tuple is not a tuple.\n \"\"\"\n if not isinstance(input_tuple, tuple):\n raise TypeError(\"Input must be a tuple.\")\n\n if not input_tuple:\n return \"\"\n\n return delimiter.join(map(str, input_tuple))", "matching_cluster_idx": 6}, {"solution": "def concatenate_tuple(input_tuple, delimiter = \"-\"):\n \"\"\"Concatenates elements of a tuple using a specified delimiter.\n\n Args:\n input_tuple: The tuple to concatenate. Elements will be converted to strings.\n delimiter: The delimiter to use between elements (default is \"-\").\n\n Returns:\n A string containing the concatenated elements. Returns an empty string if the input tuple is empty.\n\n \"\"\"\n if not input_tuple:\n return \"\"\n return delimiter.join(map(str, input_tuple))", "matching_cluster_idx": 6}, {"solution": "def concatenate_tuple(input_tuple, delimiter = \"-\"):\n \"\"\"Concatenates elements of a tuple using a specified delimiter.\n\n Args:\n input_tuple: The tuple to concatenate. Elements should be convertible to strings.\n delimiter: The delimiter to use between elements (default is \"-\").\n\n Returns:\n A string containing the concatenated elements. Returns an empty string if the input tuple is empty.\n\n Raises:\n TypeError: If input_tuple is not a tuple.\n \"\"\"\n if not isinstance(input_tuple, tuple):\n raise TypeError(\"Input must be a tuple.\")\n\n return delimiter.join(map(str, input_tuple))", "matching_cluster_idx": 5}, {"solution": "def concatenate_tuple(input_tuple, delimiter = \"-\"):\n \"\"\"Concatenates elements of a tuple using a specified delimiter.\n\n Args:\n input_tuple: The tuple of elements to concatenate.\n delimiter: The delimiter to use between elements (default is \"-\").\n\n Returns:\n A string containing the concatenated elements. Returns an empty string if the input tuple is empty.\n \"\"\"\n if not input_tuple:\n return \"\"\n return delimiter.join(map(str, input_tuple))", "matching_cluster_idx": 6}, {"solution": "def concatenate_tuple(input_tuple, delimiter=\"-\"):\n \"\"\"\n Concatenates each element of a tuple using a specified delimiter.\n\n Args:\n input_tuple: The tuple to concatenate. Elements can be of any type that can be converted to a string.\n delimiter: The delimiter to use between elements (default is \"-\").\n\n Returns:\n A string containing the concatenated elements. Returns an empty string if the input tuple is empty.\n \"\"\"\n if not input_tuple:\n return \"\"\n return delimiter.join(map(str, input_tuple))", "matching_cluster_idx": 6}, {"solution": "def concatenate_tuple(input_tuple, delimiter=\"-\"):\n \"\"\"\n Concatenates each element of a tuple using a specified delimiter.\n\n Args:\n input_tuple: The input tuple containing elements to concatenate.\n delimiter: The delimiter to use between elements (default is \"-\").\n\n Returns:\n A string with elements from the tuple concatenated by the delimiter.\n Returns an empty string if the input tuple is empty.\n\n \"\"\"\n if not input_tuple:\n return \"\"\n return delimiter.join(map(str, input_tuple))", "matching_cluster_idx": 6}, {"solution": "def concatenate_tuple(input_tuple, delimiter=\"-\"):\n \"\"\"\n Concatenates each element of a tuple using a specified delimiter.\n\n Args:\n input_tuple: The input tuple containing elements to concatenate.\n delimiter: The delimiter to use between elements (default is \"-\").\n\n Returns:\n A string containing the concatenated elements. Returns an empty string if the input tuple is empty.\n \"\"\"\n if not input_tuple:\n return \"\"\n return delimiter.join(map(str, input_tuple))", "matching_cluster_idx": 5}, {"solution": "def concatenate_tuple(input_tuple, delimiter='-'):\n \"\"\"\n Concatenates each element of a tuple using a specified delimiter.\n\n Args:\n input_tuple: The input tuple. Elements can be of any type that supports string conversion.\n delimiter: The delimiter string to use (default is '-').\n\n Returns:\n A string with the tuple elements concatenated by the delimiter. Returns an empty string if the input tuple is empty.\n \"\"\"\n if not input_tuple:\n return \"\"\n return delimiter.join(map(str, input_tuple))", "matching_cluster_idx": 6}, {"solution": "def concatenate_tuple(input_tuple, delimiter='-'):\n \"\"\"\n Concatenates each element of a tuple using a specified delimiter.\n\n Args:\n input_tuple: The input tuple of elements to concatenate.\n delimiter: The delimiter to use between elements (default is '-').\n\n Returns:\n A string containing the concatenated elements. Returns an empty string if the input tuple is empty.\n \"\"\"\n if not input_tuple:\n return \"\"\n return delimiter.join(map(str, input_tuple))", "matching_cluster_idx": 6}, {"solution": "def concatenate_tuple(input_tuple, delimiter = \"-\"):\n \"\"\"Concatenates elements of a tuple using a specified delimiter.\n\n Args:\n input_tuple: The tuple to concatenate. Elements can be of any type that can be converted to a string.\n delimiter: The delimiter to use between elements (default is \"-\").\n\n Returns:\n A string containing the concatenated elements. Returns an empty string if the input tuple is empty.\n\n \"\"\"\n if not input_tuple:\n return \"\"\n return delimiter.join(map(str, input_tuple))", "matching_cluster_idx": 6}, {"solution": "def concatenate_tuple(input_tuple, delimiter = \"-\"):\n \"\"\"Concatenates elements of a tuple using a specified delimiter.\n\n Args:\n input_tuple: The input tuple. Elements can be strings or numbers.\n delimiter: The delimiter to use between elements (default is \"-\").\n\n Returns:\n A string with the elements of the tuple concatenated using the delimiter. \n Returns an empty string if the input tuple is empty.\n\n Raises:\n TypeError: if input_tuple is not a tuple.\n \"\"\"\n\n if not isinstance(input_tuple, tuple):\n raise TypeError(\"Input must be a tuple.\")\n\n if not input_tuple:\n return \"\"\n\n return delimiter.join(map(str, input_tuple))", "matching_cluster_idx": 5}, {"solution": "def concatenate_tuple(input_tuple, delimiter='-'):\n \"\"\"\n Concatenates each element of a tuple using a specified delimiter.\n\n Args:\n input_tuple: The input tuple of elements to concatenate.\n delimiter: The delimiter to use between elements (default is '-').\n\n Returns:\n A string containing the concatenated elements, or an empty string if the input tuple is empty. \n Raises TypeError if input is not a tuple.\n \"\"\"\n if not isinstance(input_tuple, tuple):\n raise TypeError(\"Input must be a tuple.\")\n\n return delimiter.join(map(str, input_tuple))", "matching_cluster_idx": 5}, {"solution": "def concatenate_tuple(input_tuple, delimiter = \"-\"):\n \"\"\"Concatenates elements of a tuple using a specified delimiter.\n\n Args:\n input_tuple: The tuple to concatenate. Elements will be converted to strings.\n delimiter: The delimiter to use between elements (default is '-').\n\n Returns:\n A string containing all elements of the tuple concatenated with the delimiter. Returns an empty string if the input tuple is empty.\n \"\"\"\n if not input_tuple:\n return \"\"\n return delimiter.join(map(str, input_tuple))", "matching_cluster_idx": 6}, {"solution": "def concatenate_tuple(input_tuple, delimiter = \"-\"):\n \"\"\"Concatenates elements of a tuple using a specified delimiter.\n\n Args:\n input_tuple: The tuple to concatenate. Elements can be of any type that can be converted to a string.\n delimiter: The delimiter to use between elements (default is \"-\").\n\n Returns:\n A string with the elements of the tuple concatenated using the delimiter. Returns an empty string if the input tuple is empty.\n\n \"\"\"\n if not input_tuple:\n return \"\"\n return delimiter.join(map(str, input_tuple))", "matching_cluster_idx": 6}, {"solution": "def concatenate_tuple(input_tuple, delimiter = \"-\"):\n \"\"\"Concatenates elements of a tuple using a specified delimiter.\n\n Args:\n input_tuple: The input tuple containing elements to concatenate.\n delimiter: The delimiter to use between concatenated elements (default is '-').\n\n Returns:\n A string containing the concatenated elements of the tuple. Returns an empty string if the input tuple is empty.\n \"\"\"\n if not input_tuple:\n return \"\"\n return delimiter.join(map(str, input_tuple))", "matching_cluster_idx": 6}]}, "Mbpp/424": {"dps": 25.36101083032491, "dps_norm": 61.0, "pass@1": 100.0, "profiled": [{"solution": "def extract_rear(input_tuple):\n \"\"\"\n Extracts the last character of each string in a tuple.\n\n Args:\n input_tuple: A tuple of strings.\n\n Returns:\n A list containing the last character of each string in the input tuple. Returns an empty list if the input is empty or None.\n \"\"\"\n if not input_tuple:\n return []\n return [string[-1] for string in input_tuple]", "matching_cluster_idx": 3}, {"solution": "def extract_rear(input_tuple):\n \"\"\"\n Extracts the last character of each string in a tuple.\n\n Args:\n input_tuple: A tuple of strings.\n\n Returns:\n A list containing the last character of each string in the input tuple.\n Returns an empty list if the input tuple is empty or contains non-string elements.\n\n \"\"\"\n if not input_tuple:\n return []\n\n result = []\n for item in input_tuple:\n if isinstance(item, str):\n if len(item) > 0:\n result.append(item[-1])\n else:\n #Handle empty strings - could raise an exception or append \"\" depending on requirements\n result.append(\"\")\n else:\n # Handle non-string elements - could raise an exception or skip depending on requirements.\n return [] #Choosing to return empty list for simplicity\n\n return result", "matching_cluster_idx": 1}, {"solution": "def extract_rear(input_tuple):\n \"\"\"\n Extracts the last character from each string in a tuple.\n\n Args:\n input_tuple: A tuple of strings.\n\n Returns:\n A list of strings, where each string is the last character of the corresponding string in the input tuple.\n Returns an empty list if the input tuple is empty or contains non-string elements.\n\n \"\"\"\n if not input_tuple:\n return []\n\n result = []\n for item in input_tuple:\n if isinstance(item, str) and len(item) > 0:\n result.append(item[-1])\n else:\n # Handle cases where the input tuple contains non-strings or empty strings\n return [] #or raise an exception: raise TypeError(\"Input tuple must contain only strings.\")\n\n return result", "matching_cluster_idx": 1}, {"solution": "def extract_rear(input_tuple):\n \"\"\"\n Extracts the last character of each string in a tuple.\n\n Args:\n input_tuple: A tuple of strings.\n\n Returns:\n A list containing the last character of each string in the input tuple. Returns an empty list if the input is empty or None.\n \"\"\"\n if not input_tuple:\n return []\n return [string[-1] for string in input_tuple]", "matching_cluster_idx": 3}, {"solution": "def extract_rear(input_tuple):\n \"\"\"\n Extracts the last character of each string in a tuple.\n\n Args:\n input_tuple: A tuple of strings.\n\n Returns:\n A list containing the last character of each string in the input tuple. Returns an empty list if the input is empty or not a tuple.\n \"\"\"\n if not isinstance(input_tuple, tuple):\n return []\n if not input_tuple:\n return []\n return [string[-1] for string in input_tuple]", "matching_cluster_idx": 3}, {"solution": "def extract_rear(input_tuple):\n \"\"\"\n Extracts the last character of each string in a tuple.\n\n Args:\n input_tuple: A tuple of strings.\n\n Returns:\n A list containing the last character of each string in the input tuple. Returns an empty list if the input is empty or not a tuple.\n \"\"\"\n if not isinstance(input_tuple, tuple):\n return []\n if not input_tuple:\n return []\n return [string[-1] for string in input_tuple]", "matching_cluster_idx": 3}, {"solution": "def extract_rear(input_tuple):\n \"\"\"\n Extracts the last character of each string in a tuple.\n\n Args:\n input_tuple: A tuple of strings.\n\n Returns:\n A list containing the last character of each string in the input tuple. Returns an empty list if the input is empty or not a tuple.\n \"\"\"\n if not isinstance(input_tuple, tuple):\n return []\n if not input_tuple:\n return []\n return [s[-1] for s in input_tuple]", "matching_cluster_idx": 3}, {"solution": "def extract_rear(input_tuple):\n \"\"\"\n Extracts the last character of each string in a tuple.\n\n Args:\n input_tuple: A tuple of strings.\n\n Returns:\n A list containing the last character of each string in the input tuple.\n Returns an empty list if the input tuple is empty or contains non-string elements.\n\n \"\"\"\n if not isinstance(input_tuple, tuple):\n return [] # Handle non-tuple input\n\n if not input_tuple:\n return [] # Handle empty tuple\n\n result = []\n for item in input_tuple:\n if isinstance(item, str) and len(item) > 0:\n result.append(item[-1])\n else:\n return [] # Handle non-string or empty string elements\n\n return result", "matching_cluster_idx": 1}, {"solution": "def extract_rear(input_tuple):\n \"\"\"\n Extracts the last character of each string in a tuple.\n\n Args:\n input_tuple: A tuple of strings.\n\n Returns:\n A list containing the last character of each string in the input tuple.\n Returns an empty list if the input tuple is empty or contains non-string elements.\n\n \"\"\"\n if not isinstance(input_tuple, tuple):\n return [] #Handle cases where input is not a tuple.\n\n if not all(isinstance(item, str) for item in input_tuple):\n return [] #Handle cases with non-string elements.\n\n if not input_tuple:\n return [] #Handle empty tuple\n\n return [item[-1] for item in input_tuple]", "matching_cluster_idx": 2}, {"solution": "def extract_rear(input_tuple):\n \"\"\"\n Extracts the last character of each string in a tuple.\n\n Args:\n input_tuple: A tuple of strings.\n\n Returns:\n A list containing the last character of each string in the input tuple. Returns an empty list if the input is empty or not a tuple.\n\n Raises:\n TypeError: if input is not a tuple.\n \"\"\"\n if not isinstance(input_tuple, tuple):\n raise TypeError(\"Input must be a tuple.\")\n if not input_tuple:\n return []\n return [string[-1] for string in input_tuple]", "matching_cluster_idx": 3}, {"solution": "def extract_rear(input_tuple):\n \"\"\"\n Extracts the last character from each string in a tuple.\n\n Args:\n input_tuple: A tuple of strings.\n\n Returns:\n A list containing the last character of each string in the input tuple.\n Returns an empty list if the input tuple is empty or contains non-string elements.\n\n \"\"\"\n if not input_tuple:\n return []\n\n result = []\n for item in input_tuple:\n if isinstance(item, str):\n if len(item) > 0:\n result.append(item[-1])\n else:\n result.append(\"\") #Handle empty strings\n else:\n return [] #Handle non-string elements\n\n return result", "matching_cluster_idx": 1}, {"solution": "def extract_rear(input_tuple):\n \"\"\"\n Extracts the last character of each string in a tuple.\n\n Args:\n input_tuple: A tuple of strings.\n\n Returns:\n A list containing the last character of each string in the input tuple. Returns an empty list if the input is empty or not a tuple.\n \"\"\"\n if not isinstance(input_tuple, tuple):\n return []\n if not input_tuple:\n return []\n return [string[-1] for string in input_tuple]", "matching_cluster_idx": 3}, {"solution": "def extract_rear(input_tuple):\n \"\"\"\n Extracts the last character from each string in a tuple.\n\n Args:\n input_tuple: A tuple of strings.\n\n Returns:\n A list containing the last character of each string in the input tuple.\n Returns an empty list if the input tuple is empty or contains non-string elements.\n\n \"\"\"\n if not isinstance(input_tuple, tuple):\n return [] #Handle cases where input isn't a tuple\n\n if not input_tuple:\n return []\n\n result = []\n for item in input_tuple:\n if isinstance(item, str) and len(item) > 0:\n result.append(item[-1])\n return result", "matching_cluster_idx": 1}, {"solution": "def extract_rear(input_tuple):\n \"\"\"\n Extracts the last character of each string in a tuple.\n\n Args:\n input_tuple: A tuple of strings.\n\n Returns:\n A list containing the last character of each string in the input tuple. Returns an empty list if the input is empty or not a tuple.\n \"\"\"\n if not isinstance(input_tuple, tuple):\n return []\n if not input_tuple:\n return []\n return [string[-1] for string in input_tuple]", "matching_cluster_idx": 3}, {"solution": "def extract_rear(input_tuple):\n \"\"\"\n Extracts the last character of each string in a tuple.\n\n Args:\n input_tuple: A tuple of strings.\n\n Returns:\n A list containing the last character of each string in the input tuple.\n Returns an empty list if the input tuple is empty or contains non-string elements.\n\n \"\"\"\n if not input_tuple:\n return []\n\n result = []\n for item in input_tuple:\n if isinstance(item, str) and len(item) > 0:\n result.append(item[-1])\n else:\n #Handle cases with empty strings or non-string elements gracefully.\n pass #Could also raise an error here depending on desired behavior.\n\n return result", "matching_cluster_idx": 1}, {"solution": "def extract_rear(input_tuple):\n \"\"\"\n Extracts the last character of each string in a tuple.\n\n Args:\n input_tuple: A tuple of strings.\n\n Returns:\n A list containing the last character of each string in the input tuple.\n Returns an empty list if the input tuple is empty or contains non-string elements.\n\n \"\"\"\n if not input_tuple:\n return []\n \n result = []\n for item in input_tuple:\n if isinstance(item, str) and len(item) > 0:\n result.append(item[-1])\n else:\n #Handle cases with empty strings or non-string elements. Could raise an exception instead.\n pass\n\n return result", "matching_cluster_idx": 1}, {"solution": "def extract_rear(input_tuple):\n \"\"\"\n Extracts the last character of each string in a tuple.\n\n Args:\n input_tuple: A tuple of strings.\n\n Returns:\n A list containing the last character of each string in the input tuple. Returns an empty list if the input is empty or not a tuple of strings.\n \"\"\"\n if not isinstance(input_tuple, tuple):\n return []\n if not all(isinstance(s, str) for s in input_tuple):\n return []\n \n return [s[-1] for s in input_tuple]", "matching_cluster_idx": 2}, {"solution": "def extract_rear(input_tuple):\n \"\"\"\n Extracts the last character of each string in a tuple.\n\n Args:\n input_tuple: A tuple of strings.\n\n Returns:\n A list containing the last character of each string in the input tuple. Returns an empty list if the input is empty or not a tuple.\n \"\"\"\n if not isinstance(input_tuple, tuple):\n return []\n if not input_tuple:\n return []\n return [string[-1] for string in input_tuple]", "matching_cluster_idx": 3}, {"solution": "def extract_rear(input_tuple):\n \"\"\"\n Extracts the last character of each string in a tuple.\n\n Args:\n input_tuple: A tuple of strings.\n\n Returns:\n A list containing the last character of each string in the input tuple.\n Returns an empty list if the input tuple is empty or contains non-string elements.\n\n \"\"\"\n if not input_tuple:\n return []\n\n result = []\n for item in input_tuple:\n if isinstance(item, str):\n if len(item) > 0: #Handle empty strings\n result.append(item[-1])\n else:\n return [] #Handle non-string elements\n\n return result", "matching_cluster_idx": 1}, {"solution": "def extract_rear(input_tuple):\n \"\"\"\n Extracts the last character from each string in a tuple.\n\n Args:\n input_tuple: A tuple of strings.\n\n Returns:\n A list containing the last character of each string in the input tuple. Returns an empty list if the input is empty or not a tuple of strings.\n \"\"\"\n if not isinstance(input_tuple, tuple):\n return []\n if not all(isinstance(s, str) for s in input_tuple):\n return []\n \n return [s[-1] for s in input_tuple]", "matching_cluster_idx": 2}]}, "Mbpp/425": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def count_element_in_list(list_of_lists, element):\n \"\"\"\n Counts the number of sublists containing a particular element.\n\n Args:\n list_of_lists: A list of lists.\n element: The element to count.\n\n Returns:\n The number of sublists containing the element.\n \"\"\"\n count = 0\n for sublist in list_of_lists:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(list_of_lists, element):\n \"\"\"\n Counts the number of sublists containing a particular element.\n\n Args:\n list_of_lists: A list of lists.\n element: The element to count.\n\n Returns:\n The number of sublists containing the element.\n \"\"\"\n count = 0\n for sublist in list_of_lists:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(list_of_lists, element):\n \"\"\"\n Counts the number of sublists containing a particular element.\n\n Args:\n list_of_lists: A list of lists.\n element: The element to count.\n\n Returns:\n The number of sublists containing the element.\n \"\"\"\n count = 0\n for sublist in list_of_lists:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(list_of_lists, element):\n \"\"\"\n Counts the number of sublists containing a particular element.\n\n Args:\n list_of_lists: A list of lists.\n element: The element to count.\n\n Returns:\n The number of sublists containing the element.\n \"\"\"\n count = 0\n for sublist in list_of_lists:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(list_of_lists, element):\n \"\"\"\n Counts the number of sublists containing a particular element.\n\n Args:\n list_of_lists: A list of lists.\n element: The element to count.\n\n Returns:\n The number of sublists containing the element.\n \"\"\"\n count = 0\n for sublist in list_of_lists:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(list_of_lists, element):\n \"\"\"\n Counts the number of sublists containing a particular element.\n\n Args:\n list_of_lists: A list of lists.\n element: The element to count.\n\n Returns:\n The number of sublists containing the element.\n \"\"\"\n count = 0\n for sublist in list_of_lists:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(list_of_lists, element):\n \"\"\"\n Counts the number of sublists containing a particular element.\n\n Args:\n list_of_lists: A list of lists.\n element: The element to count.\n\n Returns:\n The number of sublists containing the element.\n \"\"\"\n count = 0\n for sublist in list_of_lists:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(list_of_lists, element):\n \"\"\"\n Counts the number of sublists containing a particular element.\n\n Args:\n list_of_lists: A list of lists.\n element: The element to count.\n\n Returns:\n The number of sublists containing the element.\n \"\"\"\n count = 0\n for sublist in list_of_lists:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(list_of_lists, element):\n \"\"\"\n Counts the number of sublists containing a particular element.\n\n Args:\n list_of_lists: A list of lists.\n element: The element to count.\n\n Returns:\n The number of sublists containing the element.\n \"\"\"\n count = 0\n for sublist in list_of_lists:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(list_of_lists, element):\n \"\"\"\n Counts the number of sublists containing a particular element.\n\n Args:\n list_of_lists: A list of lists.\n element: The element to count.\n\n Returns:\n The number of sublists containing the element.\n \"\"\"\n count = 0\n for sublist in list_of_lists:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(list_of_lists, element):\n \"\"\"Counts the number of sublists containing a particular element.\n\n Args:\n list_of_lists: A list of lists.\n element: The element to count.\n\n Returns:\n The number of sublists containing the element.\n \"\"\"\n count = 0\n for sublist in list_of_lists:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(list_of_lists, element):\n \"\"\"\n Counts the number of sublists containing a particular element.\n\n Args:\n list_of_lists: A list of lists.\n element: The element to count.\n\n Returns:\n The number of sublists containing the element.\n \"\"\"\n count = 0\n for sublist in list_of_lists:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(list_of_lists, element):\n \"\"\"\n Counts the number of sublists containing a particular element.\n\n Args:\n list_of_lists: A list of lists.\n element: The element to count.\n\n Returns:\n The number of sublists containing the element.\n \"\"\"\n count = 0\n for sublist in list_of_lists:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(list_of_lists, element):\n \"\"\"\n Counts the number of sublists containing a particular element.\n\n Args:\n list_of_lists: A list of lists.\n element: The element to count.\n\n Returns:\n The number of sublists containing the element.\n \"\"\"\n count = 0\n for sublist in list_of_lists:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(list_of_lists, element):\n \"\"\"\n Counts the number of sublists containing a particular element.\n\n Args:\n list_of_lists: A list of lists.\n element: The element to count.\n\n Returns:\n The number of sublists containing the element.\n \"\"\"\n count = 0\n for sublist in list_of_lists:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(list_of_lists, element):\n \"\"\"\n Counts the number of sublists containing a particular element.\n\n Args:\n list_of_lists: A list of lists.\n element: The element to count.\n\n Returns:\n The number of sublists containing the element.\n \"\"\"\n count = 0\n for sublist in list_of_lists:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(list_of_lists, element):\n \"\"\"\n Counts the number of sublists containing a particular element.\n\n Args:\n list_of_lists: A list of lists.\n element: The element to count.\n\n Returns:\n The number of sublists containing the element.\n \"\"\"\n count = 0\n for sublist in list_of_lists:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(list_of_lists, element):\n \"\"\"\n Counts the number of sublists containing a particular element.\n\n Args:\n list_of_lists: A list of lists.\n element: The element to count.\n\n Returns:\n The number of sublists containing the element.\n \"\"\"\n count = 0\n for sublist in list_of_lists:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(list_of_lists, element):\n \"\"\"\n Counts the number of sublists containing a particular element.\n\n Args:\n list_of_lists: A list of lists.\n element: The element to count.\n\n Returns:\n The number of sublists containing the element.\n \"\"\"\n count = 0\n for sublist in list_of_lists:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(list_of_lists, element):\n \"\"\"\n Counts the number of sublists containing a particular element.\n\n Args:\n list_of_lists: A list of lists.\n element: The element to search for.\n\n Returns:\n The number of sublists containing the element.\n \"\"\"\n count = 0\n for sublist in list_of_lists:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}]}, "Mbpp/428": {"dps": 84.29752066115702, "dps_norm": 55.55555555555556, "pass@1": 100.0, "profiled": [{"solution": "def shell_sort(arr):\n \"\"\"\n Sorts an array using the Shell Sort algorithm.\n\n Args:\n arr: The array to be sorted.\n\n Returns:\n The sorted array.\n \"\"\"\n n = len(arr)\n gap = n // 2 # Initialize gap\n\n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2 # Reduce gap by half\n\n return arr\narr = [12, 23, 4, 5, 3, 2, 12, 81, 56, 95]", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n \"\"\"Sorts an array using the Shell sort algorithm.\"\"\"\n n = len(arr)\n gap = n // 2 # Initialize the gap\n\n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2 # Reduce the gap\n return arr\narr = [12, 23, 4, 5, 3, 2, 12, 81, 56, 95]", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n \"\"\"\n Sorts an array using the Shell Sort algorithm.\n\n Args:\n arr: The array to be sorted.\n\n Returns:\n The sorted array.\n \"\"\"\n n = len(arr)\n gap = n // 2\n\n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n return arr\narr = [12, 23, 4, 5, 3, 2, 12, 81, 56, 95]", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n \"\"\"Sorts an array using the Shell sort algorithm.\"\"\"\n n = len(arr)\n gap = n // 2 # Initialize the gap\n\n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2 # Reduce the gap\n return arr\narr = [12, 23, 4, 5, 3, 2, 12, 81, 56, 95]", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n \"\"\"\n Sorts the given array using Shell Sort.\n\n Args:\n arr: The array to be sorted.\n\n Returns:\n The sorted array.\n \"\"\"\n n = len(arr)\n gap = n // 2\n\n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n \"\"\"\n Sorts the given array using Shell Sort.\n\n Args:\n arr: The array to be sorted.\n\n Returns:\n The sorted array.\n \"\"\"\n n = len(arr)\n gap = n // 2\n\n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n \"\"\"Sorts an array using the Shell sort algorithm.\"\"\"\n n = len(arr)\n gap = n // 2 # Initialize the gap\n\n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2 # Reduce the gap\n\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n \"\"\"\n Sorts an array using the Shell sort algorithm.\n\n Args:\n arr: The array to be sorted.\n\n Returns:\n The sorted array.\n \"\"\"\n n = len(arr)\n gap = n // 2 # Initialize the gap\n\n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2 # Reduce the gap\n return arr\narr = [12, 23, 4, 5, 3, 2, 12, 81, 56, 95]", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n \"\"\"Sorts an array using the Shell Sort algorithm.\"\"\"\n n = len(arr)\n gap = n // 2 # Initialize gap\n\n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2 # Reduce gap\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n \"\"\"\n Sorts the given array using the Shell sort algorithm.\n\n Args:\n arr: The array to be sorted.\n\n Returns:\n The sorted array.\n \"\"\"\n n = len(arr)\n gap = n // 2 # Initialize gap\n\n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2 # Reduce gap\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n \"\"\"\n Sorts the given array using the Shell sort algorithm.\n\n Args:\n arr: The array to be sorted.\n\n Returns:\n The sorted array.\n \"\"\"\n n = len(arr)\n gap = n // 2\n\n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n \"\"\"\n Sorts the given array using the Shell sort algorithm.\n\n Args:\n arr: The array to be sorted.\n\n Returns:\n The sorted array.\n \"\"\"\n n = len(arr)\n gap = n // 2 # Initialize the gap\n\n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2 # Reduce the gap\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n \"\"\"Sorts an array using the Shell sort algorithm.\"\"\"\n n = len(arr)\n gap = n // 2 # Initialize the gap\n\n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2 # Reduce the gap\n return arr\narr = [12, 23, 4, 5, 3, 2, 12, 81, 56, 95]", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n \"\"\"Sorts an array using the Shell sort algorithm.\"\"\"\n n = len(arr)\n gap = n // 2 # Initialize the gap\n\n while gap > 0:\n # Do a gapped insertion sort for this gap size.\n for i in range(gap, n):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2 # Reduce the gap\n\n return arr\narr = [12, 23, 4, 5, 3, 2, 12, 81, 56, 95]", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n \"\"\"Sorts an array using the Shell sort algorithm.\"\"\"\n n = len(arr)\n gap = n // 2 # Initialize the gap\n\n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2 # Reduce the gap\n\n return arr\narr = [12, 23, 4, 5, 3, 2, 12, 81, 56, 95]", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n \"\"\"\n Sorts an array using the Shell sort algorithm.\n\n Args:\n arr: The array to be sorted.\n\n Returns:\n The sorted array.\n \"\"\"\n n = len(arr)\n gap = n // 2 # Initialize the gap\n\n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2 # Reduce the gap\n\n return arr\narr = [12, 23, 4, 5, 3, 2, 12, 81, 56, 95]", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n \"\"\"Sorts an array using the Shell Sort algorithm.\"\"\"\n n = len(arr)\n gap = n // 2 # Initialize gap\n\n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2 # Reduce gap\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n \"\"\"\n Sorts the given array using the Shell sort algorithm.\n\n Args:\n arr: The array to be sorted.\n\n Returns:\n The sorted array.\n \"\"\"\n n = len(arr)\n gap = n // 2\n\n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n \"\"\"Sorts an array using the Shell Sort algorithm.\"\"\"\n n = len(arr)\n gap = n // 2 # Initialize the gap\n\n while gap > 0:\n # Do a gapped insertion sort for this gap size\n for i in range(gap, n):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2 # Reduce the gap\n\n return arr\narr = [12, 23, 4, 5, 3, 2, 12, 81, 56, 95]", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n \"\"\"\n Sorts the given array using the Shell sort algorithm.\n\n Args:\n arr: The array to be sorted.\n\n Returns:\n The sorted array.\n \"\"\"\n n = len(arr)\n gap = n // 2 # Initialize the gap\n\n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2 # Reduce the gap\n\n return arr", "matching_cluster_idx": 4}]}, "Mbpp/433": {"dps": 98.24468085106383, "dps_norm": 99.0, "pass@1": 99.0, "profiled": [{"solution": "def check_greater(arr, num):\n \"\"\"\n Checks whether the entered number is greater than all elements of the given array.\n\n Args:\n arr: A list of numbers.\n num: A number to compare against the elements of the array.\n\n Returns:\n True if the number is greater than all elements in the array, False otherwise.\n \"\"\"\n for element in arr:\n if num <= element:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def check_greater(arr, num):\n \"\"\"\n Checks if a number is greater than all elements in an array.\n\n Args:\n arr: The input array of numbers.\n num: The number to compare against.\n\n Returns: \n True if the number is greater than all elements in the array, False otherwise.\n \"\"\"\n for element in arr:\n if num <= element:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def check_greater(arr, num):\n \"\"\"\n Checks if a number is greater than all elements in an array.\n\n Args:\n arr: A list of numbers.\n num: A number to compare against the array elements.\n\n Returns:\n True if the number is greater than all elements in the array, \n False otherwise. Returns True for an empty array.\n \"\"\"\n if not arr:\n return True #Consider an empty array as satisfying the condition.\n for element in arr:\n if num <= element:\n return False\n return True", "matching_cluster_idx": 3}, {"solution": "def check_greater(arr, num):\n \"\"\"\n Checks if a number is greater than all elements in an array.\n\n Args:\n arr: A list of numbers.\n num: The number to compare.\n\n Returns: \n True if the number is greater than all elements in the array, False otherwise.\n \"\"\"\n for element in arr:\n if num <= element: # Note: <= to handle cases where num is equal to or less than an element\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def check_greater(arr, num):\n \"\"\"\n Checks if a number is greater than all elements in an array.\n\n Args:\n arr: A list of numbers.\n num: The number to compare.\n\n Returns:\n True if the number is greater than all elements in the array, False otherwise.\n \"\"\"\n for element in arr:\n if num <= element: #Corrected the comparison to <=\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def check_greater(arr, num):\n \"\"\"\n Checks if a number is greater than all elements in an array.\n\n Args:\n arr: The input array of numbers.\n num: The number to compare against.\n\n Returns: \n True if the number is greater than all elements in the array, \n False otherwise. Returns True for an empty array.\n \"\"\"\n for element in arr:\n if num <= element:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def check_greater(arr, num):\n \"\"\"\n Checks if a number is greater than all elements in an array.\n\n Args:\n arr: The input array of numbers.\n num: The number to compare against.\n\n Returns:\n True if the number is greater than all elements in the array, \n False otherwise. Returns True for an empty array.\n \"\"\"\n for element in arr:\n if num <= element:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def check_greater(arr, num):\n \"\"\"\n Checks whether the entered number is greater than all elements of the given array.\n\n Args:\n arr: A list of numbers.\n num: A number to compare against the elements of the array.\n\n Returns:\n True if the number is greater than all elements in the array, False otherwise.\n \"\"\"\n for element in arr:\n if num <= element: #Note: <= used for greater than or equal to check. < would only check strictly greater than.\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def check_greater(arr, num):\n \"\"\"\n Checks if a number is greater than all elements in an array.\n\n Args:\n arr: A list of numbers.\n num: The number to compare.\n\n Returns:\n True if the number is greater than all elements in the array, \n False otherwise. Returns True for an empty array.\n \"\"\"\n if not arr:\n return True #Consider an empty array as satisfying the condition.\n for element in arr:\n if num <= element:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def check_greater(arr, num):\n \"\"\"\n Checks whether the entered number is greater than all elements of the given array.\n\n Args:\n arr: A list of numbers.\n num: A number to compare against the array elements.\n\n Returns:\n True if the number is greater than all elements in the array, False otherwise.\n \"\"\"\n for element in arr:\n if num <= element: #Note the <=, it must be greater than ALL elements.\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def check_greater(arr, num):\n \"\"\"\n Checks if a number is greater than all elements in an array.\n\n Args:\n arr: A list of numbers.\n num: The number to compare.\n\n Returns:\n True if the number is greater than all elements in the array, False otherwise.\n \"\"\"\n for element in arr:\n if num <= element:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def check_greater(arr, num):\n \"\"\"\n Checks if a number is greater than all elements in an array.\n\n Args:\n arr: A list of numbers.\n num: The number to compare.\n\n Returns:\n True if the number is greater than all elements in the array, False otherwise.\n \"\"\"\n for element in arr:\n if num <= element:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def check_greater(arr, num):\n \"\"\"\n Checks if a number is greater than all elements in an array.\n\n Args:\n arr: A list of numbers.\n num: The number to compare.\n\n Returns:\n True if the number is greater than all elements in the array, \n False otherwise. Returns True for an empty array.\n \"\"\"\n for element in arr:\n if num <= element:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def check_greater(arr, num):\n \"\"\"\n Checks if a number is greater than all elements in an array.\n\n Args:\n arr: A list of numbers.\n num: The number to compare.\n\n Returns:\n True if the number is greater than all elements in the array, \n False otherwise.\n \"\"\"\n for element in arr:\n if num <= element: #Note the <= to ensure it's strictly greater\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def check_greater(arr, num):\n \"\"\"\n Checks if a number is greater than all elements in an array.\n\n Args:\n arr: The input array of numbers.\n num: The number to compare against.\n\n Returns:\n True if the number is greater than all elements in the array, \n False otherwise. Returns True for an empty array.\n \"\"\"\n for element in arr:\n if num <= element:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def check_greater(arr, num):\n \"\"\"\n Checks if a number is greater than all elements in an array.\n\n Args:\n arr: A list of numbers.\n num: A number to compare against the array elements.\n\n Returns:\n True if the number is greater than all elements in the array, \n False otherwise. Returns True for an empty array.\n \"\"\"\n for element in arr:\n if num <= element:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def check_greater(arr, num):\n \"\"\"\n Checks if a number is greater than all elements in an array.\n\n Args:\n arr: A list of numbers.\n num: The number to compare.\n\n Returns: \n True if the number is greater than all elements in the array, False otherwise.\n \"\"\"\n for element in arr:\n if num <= element: # Note: We use <= to check if num is greater than ALL elements.\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def check_greater(arr, num):\n \"\"\"\n Checks if a number is greater than all elements in an array.\n\n Args:\n arr: The input array of numbers.\n num: The number to compare against.\n\n Returns:\n True if the number is greater than all elements in the array, False otherwise.\n \"\"\"\n for element in arr:\n if num <= element:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def check_greater(arr, num):\n \"\"\"\n Checks if a number is greater than all elements in an array.\n\n Args:\n arr: The input array of numbers.\n num: The number to compare against.\n\n Returns:\n True if the number is greater than all elements in the array, False otherwise.\n \"\"\"\n for element in arr:\n if num <= element: # Note: <= to handle cases where num is equal to or less than an element.\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def check_greater(arr, num):\n \"\"\"\n Checks if a number is greater than all elements in an array.\n\n Args:\n arr: A list of numbers.\n num: A number to compare against the array elements.\n\n Returns:\n True if the number is greater than all elements in the array, False otherwise.\n \"\"\"\n for element in arr:\n if num <= element:\n return False\n return True", "matching_cluster_idx": 4}]}, "Mbpp/437": {"dps": 70.58823529411765, "dps_norm": 20.0, "pass@1": 86.0, "profiled": [{"solution": "def remove_odd(input_string):\n \"\"\"Removes characters at odd indices from a string.\n\n Args:\n input_string: The input string.\n\n Returns:\n A new string with odd-indexed characters removed.\n \"\"\"\n result = \"\"\n for i in range(len(input_string)):\n if i % 2 != 0: #Check if index is odd\n result += input_string[i]\n return result", "matching_cluster_idx": 0}, {"solution": "def remove_odd(input_string):\n \"\"\"Removes characters at odd indices from a string.\n\n Args:\n input_string: The input string.\n\n Returns:\n A new string with odd-indexed characters removed. Returns an empty string if the input is None or empty.\n \"\"\"\n if not input_string:\n return \"\"\n result = \"\"\n for i in range(len(input_string)):\n if i % 2 != 0: #Check for odd index\n result += input_string[i]\n return result", "matching_cluster_idx": 0}, {"solution": "def remove_odd(input_string):\n \"\"\"Removes characters at odd indices from a string.\n\n Args:\n input_string: The input string.\n\n Returns:\n A new string with odd-indexed characters removed. Returns an empty string if the input is None or empty.\n \"\"\"\n if not input_string:\n return \"\"\n result = \"\"\n for i in range(len(input_string)):\n if i % 2 != 0: #Check if index is odd\n result += input_string[i]\n return result", "matching_cluster_idx": 0}, {"solution": "def remove_odd(input_string):\n \"\"\"Removes characters at odd indices from a string.\n\n Args:\n input_string: The input string.\n\n Returns:\n A new string with odd-indexed characters removed.\n \"\"\"\n result = \"\"\n for i in range(len(input_string)):\n if i % 2 != 0: # Check if index is odd\n result += input_string[i]\n return result", "matching_cluster_idx": 0}, {"solution": "def remove_odd(input_string):\n \"\"\"Removes characters at odd indices from a string.\n\n Args:\n input_string: The input string.\n\n Returns:\n A new string with odd-indexed characters removed.\n \"\"\"\n result = \"\"\n for i in range(len(input_string)):\n if i % 2 != 0: #Check if index is odd.\n result += input_string[i]\n return result", "matching_cluster_idx": 0}, {"solution": "def remove_odd(input_string):\n \"\"\"Removes characters at odd indices from a string.\n\n Args:\n input_string: The input string.\n\n Returns:\n A new string with odd-indexed characters removed. Returns an empty string if the input is None or empty.\n \"\"\"\n if not input_string:\n return \"\"\n result = \"\"\n for i in range(len(input_string)):\n if i % 2 != 0: #Check for odd index\n result += input_string[i]\n return result", "matching_cluster_idx": 0}, {"solution": "def remove_odd(input_string):\n \"\"\"Removes characters at odd indices from a string.\n\n Args:\n input_string: The input string.\n\n Returns:\n A new string with odd-indexed characters removed. Returns an empty string if the input is None or empty.\n \"\"\"\n if not input_string:\n return \"\"\n result = \"\"\n for i in range(len(input_string)):\n if i % 2 != 0: #Check if index is odd (starts from 0)\n result += input_string[i]\n return result", "matching_cluster_idx": 0}, {"solution": "def remove_odd(input_string):\n \"\"\"Removes characters at odd indices from a string.\n\n Args:\n input_string: The input string.\n\n Returns:\n A new string with odd-indexed characters removed. Returns an empty string if the input is None or empty.\n \"\"\"\n if not input_string:\n return \"\"\n result = \"\"\n for i in range(len(input_string)):\n if i % 2 != 0: #Check if index is odd.\n result += input_string[i]\n return result", "matching_cluster_idx": 0}, {"solution": "def remove_odd(input_string):\n \"\"\"Removes characters at odd indices from a string.\n\n Args:\n input_string: The input string.\n\n Returns:\n A new string with odd-indexed characters removed. Returns an empty string if the input is None or empty.\n \"\"\"\n if not input_string:\n return \"\"\n result = \"\"\n for i in range(len(input_string)):\n if i % 2 != 0: #Check for odd index\n result += input_string[i]\n return result", "matching_cluster_idx": 0}, {"solution": "def remove_odd(input_string):\n \"\"\"Removes characters at odd indices from a string.\n\n Args:\n input_string: The input string.\n\n Returns:\n A new string with odd-indexed characters removed. Returns an empty string if the input is invalid.\n \"\"\"\n if not isinstance(input_string, str):\n return \"\"\n result = \"\"\n for i in range(len(input_string)):\n if i % 2 != 0: #Check if index is odd.\n result += input_string[i]\n return result", "matching_cluster_idx": 0}, {"solution": "def remove_odd(input_string):\n \"\"\"Removes characters at odd indices from a string.\n\n Args:\n input_string: The input string.\n\n Returns:\n A new string with odd-indexed characters removed. Returns an empty string if the input is None or empty.\n \"\"\"\n if not input_string:\n return \"\"\n result = \"\"\n for i in range(len(input_string)):\n if i % 2 != 0: #Check for odd index\n result += input_string[i]\n return result", "matching_cluster_idx": 0}, {"solution": "def remove_odd(input_string):\n \"\"\"Removes characters at odd indices from a string.\n\n Args:\n input_string: The input string.\n\n Returns:\n A new string with odd-indexed characters removed.\n \"\"\"\n result = \"\"\n for i in range(len(input_string)):\n if i % 2 != 0: #Check if index is odd. Python uses 0-based indexing.\n result += input_string[i]\n return result", "matching_cluster_idx": 0}, {"solution": "def remove_odd(input_string):\n \"\"\"Removes characters at odd indices from a string.\n\n Args:\n input_string: The input string.\n\n Returns:\n A new string with odd-indexed characters removed.\n \"\"\"\n result = \"\"\n for i in range(len(input_string)):\n if i % 2 != 0: #Check if index is odd. Python uses 0 based indexing.\n result += input_string[i]\n return result", "matching_cluster_idx": 0}, {"solution": "def remove_odd(input_string):\n \"\"\"Removes characters at odd indices from a string.\n\n Args:\n input_string: The input string.\n\n Returns:\n A new string with odd-indexed characters removed. Returns an empty string if the input is None or empty.\n \"\"\"\n if not input_string:\n return \"\"\n result = \"\"\n for i in range(len(input_string)):\n if i % 2 != 0: #Check for odd index. Note that index starts from 0.\n result += input_string[i]\n return result", "matching_cluster_idx": 0}, {"solution": "def remove_odd(input_string):\n \"\"\"Removes characters at odd indices from a string.\n\n Args:\n input_string: The input string.\n\n Returns:\n A new string with odd-indexed characters removed. Returns an empty string if the input is None or empty.\n \"\"\"\n if not input_string:\n return \"\"\n result = \"\"\n for i in range(len(input_string)):\n if i % 2 != 0: #Check for odd index. Remember that indexing starts from 0.\n result += input_string[i]\n return result", "matching_cluster_idx": 0}, {"solution": "def remove_odd(input_string):\n \"\"\"Removes characters at odd indices from a string.\n\n Args:\n input_string: The input string.\n\n Returns:\n A new string with odd-indexed characters removed. Returns an empty string if the input is invalid.\n \"\"\"\n if not isinstance(input_string, str):\n return \"\"\n result = \"\"\n for i in range(len(input_string)):\n if i % 2 != 0: #Check for odd index\n result += input_string[i]\n return result", "matching_cluster_idx": 0}, {"solution": "def remove_odd(input_string):\n \"\"\"Removes characters at odd indices from a string.\n\n Args:\n input_string: The input string.\n\n Returns:\n A new string with odd-indexed characters removed. Returns an empty string if the input is empty or None.\n \"\"\"\n if not input_string:\n return \"\"\n result = \"\"\n for i in range(len(input_string)):\n if i % 2 != 0: #Check if index is odd\n result += input_string[i]\n return result", "matching_cluster_idx": 0}, {"solution": "def remove_odd(input_string):\n \"\"\"Removes characters at odd indices from a string.\n\n Args:\n input_string: The input string.\n\n Returns:\n A new string with odd-indexed characters removed.\n \"\"\"\n result = \"\"\n for i in range(len(input_string)):\n if i % 2 != 0: #Check if index is odd. \n result += input_string[i]\n return result", "matching_cluster_idx": 0}, {"solution": "def remove_odd(input_string):\n \"\"\"Removes characters at odd indices from a string.\n\n Args:\n input_string: The input string.\n\n Returns:\n A new string with odd-indexed characters removed.\n \"\"\"\n result = \"\"\n for i in range(len(input_string)):\n if i % 2 != 0: # Check if index is odd\n result += input_string[i]\n return result", "matching_cluster_idx": 0}, {"solution": "def remove_odd(input_string):\n \"\"\"Removes characters at odd indices from a string.\n\n Args:\n input_string: The input string.\n\n Returns:\n A new string with odd-indexed characters removed.\n \"\"\"\n result = \"\"\n for i in range(len(input_string)):\n if i % 2 != 0: # Check if index is odd\n result += input_string[i]\n return result", "matching_cluster_idx": 0}]}, "Mbpp/440": {"dps": null, "dps_norm": null, "pass@1": 0.0, "profiled": []}, "Mbpp/446": {"dps": 99.21182266009852, "dps_norm": 92.0, "pass@1": 29.0, "profiled": [{"solution": "from collections import Counter\ndef count_Occurrence(input_tuple, input_list):\n \"\"\"\n Counts the occurrences of elements from a list within a tuple.\n\n Args:\n input_tuple: The input tuple to search within.\n input_list: The list of elements to count.\n\n Returns:\n The total count of elements from the list found in the tuple. Returns 0 if either input is invalid.\n \"\"\"\n try:\n count = 0\n tuple_counts = Counter(input_tuple)\n for element in input_list:\n count += tuple_counts[element]\n return count\n except (TypeError, KeyError):\n return 0", "matching_cluster_idx": 4}, {"solution": "def count_Occurrence(input_tuple, input_list):\n \"\"\"\n Counts the occurrences of elements from a list within a tuple.\n\n Args:\n input_tuple: The tuple to search within.\n input_list: The list of elements to count.\n\n Returns:\n The total count of elements from the list found in the tuple. Returns 0 if the input tuple is empty.\n \"\"\"\n if not input_tuple:\n return 0\n count = 0\n for element in input_list:\n count += input_tuple.count(element)\n return count", "matching_cluster_idx": 2}, {"solution": "from collections import Counter\ndef count_Occurrence(input_tuple, input_list):\n \"\"\"\n Counts the occurrences of elements from a list within a tuple.\n\n Args:\n input_tuple: The tuple to search within.\n input_list: The list of elements to count.\n\n Returns:\n The total count of elements from the list found in the tuple. Returns 0 if either input is invalid.\n \"\"\"\n if not isinstance(input_tuple, tuple) or not isinstance(input_list, list):\n return 0\n\n tuple_counts = Counter(input_tuple)\n total_count = 0\n for element in input_list:\n total_count += tuple_counts.get(element, 0) #Handles cases where element is not in tuple\n\n return total_count", "matching_cluster_idx": 4}, {"solution": "from collections import Counter\ndef count_Occurrence(input_tuple, input_list):\n \"\"\"\n Counts the occurrences of elements from a list within a tuple.\n\n Args:\n input_tuple: The tuple to search within.\n input_list: The list of elements to count.\n\n Returns:\n The total count of elements from the list found in the tuple. Returns 0 if either input is invalid.\n\n \"\"\"\n if not isinstance(input_tuple, tuple) or not isinstance(input_list, list):\n return 0\n\n tuple_counts = Counter(input_tuple)\n total_count = 0\n for item in input_list:\n total_count += tuple_counts[item]\n return total_count", "matching_cluster_idx": 4}, {"solution": "from collections import Counter\ndef count_Occurrence(input_tuple, input_list):\n \"\"\"\n Counts the occurrences of elements from a list within a tuple.\n\n Args:\n input_tuple: The tuple to search within.\n input_list: The list of elements to count.\n\n Returns:\n The total count of elements from the list found in the tuple. Returns 0 if either input is invalid.\n\n \"\"\"\n if not isinstance(input_tuple, tuple) or not isinstance(input_list, list):\n return 0\n\n tuple_counts = Counter(input_tuple)\n total_count = 0\n for item in input_list:\n total_count += tuple_counts[item]\n return total_count", "matching_cluster_idx": 4}, {"solution": "def count_Occurrence(input_tuple, input_list):\n \"\"\"\n Counts the occurrences of elements from a list within a tuple.\n\n Args:\n input_tuple: The tuple to search within.\n input_list: The list of elements to count.\n\n Returns:\n The total count of elements from the list found in the tuple. Returns 0 if the input tuple or list is empty.\n \"\"\"\n if not input_tuple or not input_list:\n return 0\n count = 0\n for element in input_list:\n count += input_tuple.count(element)\n return count", "matching_cluster_idx": 2}, {"solution": "from collections import Counter\ndef count_Occurrence(input_tuple, input_list):\n \"\"\"Counts the occurrences of elements from a list within a tuple.\n\n Args:\n input_tuple: The tuple to search within.\n input_list: The list of elements to count.\n\n Returns:\n The total count of elements from the list found in the tuple. Returns 0 if either input is invalid.\n\n \"\"\"\n if not isinstance(input_tuple, tuple) or not isinstance(input_list, list):\n return 0\n\n tuple_counts = Counter(input_tuple)\n total_count = 0\n for element in input_list:\n total_count += tuple_counts[element]\n return total_count", "matching_cluster_idx": 4}, {"solution": "from collections import Counter\ndef count_Occurrence(input_tuple, input_list):\n \"\"\"\n Counts the occurrences of elements from a list within a tuple.\n\n Args:\n input_tuple: The tuple to search within.\n input_list: The list of elements to count.\n\n Returns:\n The total count of elements from the list found in the tuple. Returns 0 if either input is invalid.\n \"\"\"\n if not isinstance(input_tuple, tuple) or not isinstance(input_list, list):\n return 0\n\n try:\n tuple_counts = Counter(input_tuple)\n total_count = sum(tuple_counts[item] for item in input_list)\n return total_count\n except TypeError: # Handle cases where elements are not hashable.\n return 0", "matching_cluster_idx": 4}, {"solution": "def count_Occurrence(tuple_data, list_data):\n \"\"\"\n Counts the occurrences of elements from a list within a tuple.\n\n Args:\n tuple_data: The input tuple.\n list_data: The list of elements to count.\n\n Returns:\n The total count of elements from the list that are present in the tuple. Returns 0 if either input is invalid.\n \"\"\"\n if not isinstance(tuple_data, tuple) or not isinstance(list_data, list):\n return 0\n\n count = 0\n for element in list_data:\n count += tuple_data.count(element)\n return count", "matching_cluster_idx": 2}, {"solution": "from collections import Counter\ndef count_Occurrence(input_tuple, input_list):\n \"\"\"\n Counts the occurrences of elements from a list within a tuple.\n\n Args:\n input_tuple: The tuple to search within.\n input_list: The list of elements to count.\n\n Returns:\n The total count of elements from the list found in the tuple. Returns 0 if either input is invalid.\n \"\"\"\n if not isinstance(input_tuple, tuple) or not isinstance(input_list, list):\n return 0\n\n try:\n tuple_counts = Counter(input_tuple)\n total_count = sum(tuple_counts[item] for item in input_list)\n return total_count\n except TypeError: # Handle potential errors if elements are not hashable\n return 0", "matching_cluster_idx": 4}, {"solution": "from collections import Counter\ndef count_Occurrence(input_tuple, input_list):\n \"\"\"\n Counts the occurrences of elements from a list within a tuple.\n\n Args:\n input_tuple: The tuple to search within.\n input_list: The list of elements to count.\n\n Returns:\n The total count of elements from the list found in the tuple. Returns 0 if either input is invalid.\n\n \"\"\"\n try:\n tuple_counts = Counter(input_tuple)\n total_count = 0\n for element in input_list:\n total_count += tuple_counts.get(element, 0) #Handles cases where element is not in tuple.\n return total_count\n except (TypeError):\n return 0", "matching_cluster_idx": 4}, {"solution": "from collections import Counter\ndef count_Occurrence(input_tuple, input_list):\n \"\"\"\n Counts the occurrences of elements from a list within a tuple.\n\n Args:\n input_tuple: The tuple to search within.\n input_list: The list of elements to count.\n\n Returns:\n The total count of elements from the list found in the tuple. Returns 0 if either input is invalid.\n\n \"\"\"\n if not isinstance(input_tuple, tuple) or not isinstance(input_list, list):\n return 0\n\n tuple_counts = Counter(input_tuple)\n total_count = 0\n for element in input_list:\n total_count += tuple_counts.get(element, 0) #Handles cases where element is not in tuple\n\n return total_count", "matching_cluster_idx": 4}, {"solution": "from collections import Counter\ndef count_Occurrence(input_tuple, input_list):\n \"\"\"\n Counts the occurrences of elements from a list within a tuple.\n\n Args:\n input_tuple: The tuple to search within.\n input_list: The list of elements to count.\n\n Returns:\n The total count of elements from the list found in the tuple. Returns 0 if either input is invalid.\n \"\"\"\n if not isinstance(input_tuple, tuple) or not isinstance(input_list, list):\n return 0\n\n try:\n tuple_counts = Counter(input_tuple)\n total_count = sum(tuple_counts[item] for item in input_list)\n return total_count\n except TypeError: #Handles cases where tuple elements are not hashable.\n return 0", "matching_cluster_idx": 4}, {"solution": "from collections import Counter\ndef count_Occurrence(tuple_data, list_data):\n \"\"\"\n Counts the occurrences of elements from a list within a tuple.\n\n Args:\n tuple_data: The input tuple.\n list_data: The list of elements to count.\n\n Returns:\n The total count of elements from list_data found in tuple_data. Returns 0 if either input is invalid.\n\n \"\"\"\n if not isinstance(tuple_data, tuple) or not isinstance(list_data, list):\n return 0\n\n try:\n tuple_counts = Counter(tuple_data)\n total_count = sum(tuple_counts[element] for element in list_data)\n return total_count\n except TypeError: #Handles cases where tuple contains unhashable types\n return 0", "matching_cluster_idx": 4}, {"solution": "from collections import Counter\ndef count_Occurrence(input_tuple, input_list):\n \"\"\"\n Counts the occurrences of elements from a list within a tuple.\n\n Args:\n input_tuple: The tuple to search within.\n input_list: The list of elements to count.\n\n Returns:\n The total count of elements from the list found in the tuple. Returns 0 if either input is invalid.\n \"\"\"\n if not isinstance(input_tuple, tuple) or not isinstance(input_list, list):\n return 0\n\n count = 0\n tuple_counts = Counter(input_tuple)\n for element in input_list:\n count += tuple_counts.get(element, 0) #Handles cases where list element isn't in tuple\n\n return count", "matching_cluster_idx": 4}, {"solution": "def count_Occurrence(tuple_data, list_data):\n \"\"\"\n Counts the occurrences of elements from a list within a tuple.\n\n Args:\n tuple_data: The input tuple.\n list_data: The list of elements to count.\n\n Returns:\n The total count of elements from the list that are present in the tuple. Returns 0 if either input is invalid.\n \"\"\"\n if not isinstance(tuple_data, tuple) or not isinstance(list_data, list):\n return 0\n\n count = 0\n for element in list_data:\n count += tuple_data.count(element)\n return count", "matching_cluster_idx": 2}, {"solution": "from collections import Counter\ndef count_Occurrence(input_tuple, input_list):\n \"\"\"\n Counts the occurrences of elements from a list within a tuple.\n\n Args:\n input_tuple: The tuple to search within.\n input_list: The list of elements to count.\n\n Returns:\n The total count of elements from the list found in the tuple. Returns 0 if either input is invalid.\n \"\"\"\n if not isinstance(input_tuple, tuple) or not isinstance(input_list, list):\n return 0\n\n tuple_counts = Counter(input_tuple)\n total_count = 0\n for element in input_list:\n total_count += tuple_counts[element]\n return total_count", "matching_cluster_idx": 4}, {"solution": "from collections import Counter\ndef count_Occurrence(input_tuple, input_list):\n \"\"\"\n Counts the occurrences of elements from a list within a tuple.\n\n Args:\n input_tuple: The tuple to search within.\n input_list: The list of elements to count.\n\n Returns:\n The total count of elements from the list found in the tuple. Returns 0 if either input is invalid.\n\n \"\"\"\n if not isinstance(input_tuple, tuple) or not isinstance(input_list, list):\n return 0\n\n count = 0\n tuple_counts = Counter(input_tuple)\n for item in input_list:\n count += tuple_counts.get(item, 0) #handle case where item not in tuple\n\n return count", "matching_cluster_idx": 4}, {"solution": "from collections import Counter\ndef count_Occurrence(input_tuple, input_list):\n \"\"\"\n Counts the occurrences of elements from a list within a tuple.\n\n Args:\n input_tuple: The tuple to search within.\n input_list: The list of elements to count.\n\n Returns:\n The total count of elements from the list found in the tuple. Returns 0 if either input is invalid.\n \"\"\"\n if not isinstance(input_tuple, tuple) or not isinstance(input_list, list):\n return 0\n\n try:\n count = 0\n tuple_counts = Counter(input_tuple)\n for element in input_list:\n count += tuple_counts[element] \n return count\n except TypeError: # handles cases where elements in the tuple are not hashable\n return 0", "matching_cluster_idx": 4}, {"solution": "from collections import Counter\ndef count_Occurrence(my_tuple, my_list):\n \"\"\"\n Counts the occurrences of elements from a list within a tuple.\n\n Args:\n my_tuple: The tuple to search within.\n my_list: The list of elements to count.\n\n Returns:\n The total count of elements from my_list found in my_tuple. Returns 0 if either input is invalid.\n \"\"\"\n try:\n counts = Counter(my_tuple)\n total_count = sum(counts[item] for item in my_list)\n return total_count\n except (TypeError, KeyError):\n return 0", "matching_cluster_idx": 4}]}, "Mbpp/451": {"dps": null, "dps_norm": null, "pass@1": 2.0, "profiled": []}, "Mbpp/456": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def reverse_string_list(str_list):\n \"\"\"\n Reverses each string in a given list of string values.\n\n Args:\n str_list: A list of strings.\n\n Returns:\n A new list containing the reversed strings. Returns an empty list if the input is not a list or is empty.\n \"\"\"\n if not isinstance(str_list, list) or not str_list:\n return []\n \n reversed_list = [s[::-1] for s in str_list]\n return reversed_list", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(str_list):\n \"\"\"\n Reverses each string in a given list of strings.\n\n Args:\n str_list: A list of strings.\n\n Returns:\n A new list containing the reversed strings. Returns an empty list if input is invalid.\n \"\"\"\n if not isinstance(str_list, list):\n return []\n if not all(isinstance(s, str) for s in str_list):\n return []\n\n reversed_list = [s[::-1] for s in str_list]\n return reversed_list", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n \"\"\"\n Reverses each string in a given list of string values.\n\n Args:\n string_list: A list of strings.\n\n Returns:\n A new list containing the reversed strings. Returns an empty list if the input is invalid.\n \"\"\"\n if not isinstance(string_list, list):\n return []\n if not all(isinstance(s, str) for s in string_list):\n return []\n\n reversed_list = [s[::-1] for s in string_list]\n return reversed_list", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(str_list):\n \"\"\"\n Reverses each string in a given list of string values.\n\n Args:\n str_list: A list of strings.\n\n Returns:\n A list of strings where each string is the reverse of the corresponding \n string in the input list. Returns an empty list if the input is not a list.\n \"\"\"\n if not isinstance(str_list, list):\n return []\n reversed_list = [string[::-1] for string in str_list]\n return reversed_list", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n \"\"\"\n Reverses each string in a given list of string values.\n\n Args:\n string_list: A list of strings.\n\n Returns:\n A new list containing the reversed strings. Returns an empty list if the input is not a list or is empty.\n \"\"\"\n if not isinstance(string_list, list):\n return []\n if not string_list:\n return []\n\n reversed_list = [string[::-1] for string in string_list]\n return reversed_list", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(str_list):\n \"\"\"\n Write a function to reverse each string in a given list of string values.\n assert reverse_string_list(['Red', 'Green', 'Blue', 'White', 'Black'])==['deR', 'neerG', 'eulB', 'etihW', 'kcalB']\n \"\"\"\n reversed_list = [s[::-1] for s in str_list]\n return reversed_list", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(str_list):\n \"\"\"\n Reverses each string in a given list of strings.\n\n Args:\n str_list: A list of strings.\n\n Returns:\n A list of strings with each string reversed. Returns an empty list if the input is not a list or the list is empty.\n \"\"\"\n if not isinstance(str_list, list):\n return []\n if not str_list:\n return []\n\n reversed_list = [string[::-1] for string in str_list] #Using list comprehension for efficiency.\n return reversed_list", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n \"\"\"Reverses each string in a given list of strings.\n\n Args:\n string_list: A list of strings.\n\n Returns:\n A new list containing the reversed strings. Returns an empty list if the input is not a list or if the list is empty.\n \"\"\"\n if not isinstance(string_list, list):\n return []\n if not string_list:\n return []\n reversed_list = [string[::-1] for string in string_list]\n return reversed_list", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(str_list):\n \"\"\"\n Reverses each string in a given list of strings.\n\n Args:\n str_list: A list of strings.\n\n Returns:\n A new list containing the reversed strings. Returns an empty list if input is invalid.\n \"\"\"\n if not isinstance(str_list, list):\n return []\n if not all(isinstance(s, str) for s in str_list):\n return []\n\n reversed_list = [s[::-1] for s in str_list]\n return reversed_list", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(str_list):\n \"\"\"\n Reverses each string in a given list of strings.\n\n Args:\n str_list: A list of strings.\n\n Returns:\n A new list containing the reversed strings. Returns an empty list if the input is not a list. \n Returns an empty list if the input list contains non-string elements.\n \"\"\"\n if not isinstance(str_list, list):\n return []\n \n if not all(isinstance(s, str) for s in str_list):\n return []\n\n reversed_list = [s[::-1] for s in str_list]\n return reversed_list", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n \"\"\"\n Reverses each string in a given list of string values.\n\n Args:\n string_list: A list of strings.\n\n Returns:\n A new list containing the reversed strings. Returns an empty list if the input is invalid.\n\n \"\"\"\n if not isinstance(string_list, list):\n return []\n \n reversed_list = []\n for string in string_list:\n if isinstance(string, str):\n reversed_list.append(string[::-1])\n else:\n return [] #Handle non-string elements gracefully. Could also raise an exception.\n\n return reversed_list", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(str_list):\n \"\"\"\n Reverses each string in a given list of strings.\n\n Args:\n str_list: A list of strings.\n\n Returns:\n A new list containing the reversed strings. Returns an empty list if input is invalid.\n \"\"\"\n if not isinstance(str_list, list):\n return []\n reversed_list = []\n for string in str_list:\n if isinstance(string, str):\n reversed_list.append(string[::-1])\n else:\n return [] #Handle cases where list contains non-string elements.\n\n return reversed_list", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(str_list):\n \"\"\"\n Reverses each string in a given list of strings.\n\n Args:\n str_list: A list of strings.\n\n Returns:\n A new list containing the reversed strings. Returns an empty list if the input is invalid.\n \"\"\"\n if not isinstance(str_list, list):\n return []\n \n reversed_list = []\n for string in str_list:\n if not isinstance(string, str):\n return [] #Handle non-string elements gracefully.\n reversed_list.append(string[::-1]) #Efficient string reversal using slicing\n return reversed_list", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(str_list):\n \"\"\"\n Reverses each string in a given list of strings.\n\n Args:\n str_list: A list of strings.\n\n Returns:\n A list of strings with each string reversed. Returns an empty list if the input is not a list or is empty.\n \"\"\"\n if not isinstance(str_list, list) or not str_list:\n return []\n reversed_list = [string[::-1] for string in str_list]\n return reversed_list", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n \"\"\"\n Reverses each string in a given list of strings.\n\n Args:\n string_list: A list of strings.\n\n Returns:\n A new list containing the reversed strings. Returns an empty list if the input is not a list or if the list is empty.\n\n \"\"\"\n if not isinstance(string_list, list):\n return []\n if not string_list:\n return []\n\n reversed_list = [string[::-1] for string in string_list]\n return reversed_list", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(str_list):\n \"\"\"\n Reverses each string in a given list of string values.\n\n Args:\n str_list: A list of strings.\n\n Returns:\n A new list containing the reversed strings. Returns an empty list if the input is invalid.\n \"\"\"\n if not isinstance(str_list, list):\n return []\n \n reversed_list = []\n for string in str_list:\n if isinstance(string, str):\n reversed_list.append(string[::-1])\n else:\n # Handle non-string elements gracefully. Could raise an error instead.\n reversed_list.append(string) \n\n return reversed_list", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(str_list):\n \"\"\"\n Reverses each string in a given list of strings.\n\n Args:\n str_list: A list of strings.\n\n Returns:\n A list of strings with each string reversed. Returns an empty list if the input is not a list.\n Returns an empty list if the input list contains non-string elements.\n\n \"\"\"\n if not isinstance(str_list, list):\n return []\n\n if not all(isinstance(s, str) for s in str_list):\n return []\n\n reversed_list = [s[::-1] for s in str_list]\n return reversed_list", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n \"\"\"\n Reverses each string in a given list of strings.\n\n Args:\n string_list: A list of strings.\n\n Returns:\n A list of strings where each string is the reverse of the corresponding string in the input list.\n Returns an empty list if the input is not a list or if the list is empty.\n\n \"\"\"\n if not isinstance(string_list, list):\n return []\n if not string_list:\n return []\n\n reversed_list = [string[::-1] for string in string_list]\n return reversed_list", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n \"\"\"\n Reverses each string in a given list of strings.\n\n Args:\n string_list: A list of strings.\n\n Returns:\n A new list containing the reversed strings. Returns an empty list if the input is not a list.\n Returns an empty list if the input list contains non-string elements.\n \"\"\"\n if not isinstance(string_list, list):\n return []\n\n if not all(isinstance(s, str) for s in string_list):\n return []\n\n reversed_list = [s[::-1] for s in string_list]\n return reversed_list", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(str_list):\n \"\"\"\n Reverses each string in a given list of string values.\n\n Args:\n str_list: A list of strings.\n\n Returns:\n A new list containing the reversed strings. Returns an empty list if the input is invalid.\n\n \"\"\"\n if not isinstance(str_list, list):\n return []\n \n reversed_list = []\n for string in str_list:\n if not isinstance(string, str):\n return [] #Handle non-string elements gracefully\n reversed_list.append(string[::-1])\n return reversed_list", "matching_cluster_idx": 4}]}, "Mbpp/460": {"dps": 19.134615384615383, "dps_norm": 57.0, "pass@1": 100.0, "profiled": [{"solution": "def Extract(list_of_lists):\n \"\"\"\n Write a python function to get the first element of each sublist.\n assert Extract([[1, 2], [3, 4, 5], [6, 7, 8, 9]]) == [1, 3, 6]\n \"\"\"\n first_elements = []\n for sublist in list_of_lists:\n if sublist: # Check if the sublist is not empty\n first_elements.append(sublist[0])\n return first_elements", "matching_cluster_idx": 3}, {"solution": "def Extract(list_of_lists):\n \"\"\"\n Extracts the first element from each sublist in a list of lists.\n\n Args:\n list_of_lists: A list of lists, where each inner list contains at least one element.\n\n Returns:\n A list containing the first element of each sublist. Returns an empty list if the input is empty.\n Raises a TypeError if the input is not a list or if a sublist is not a list.\n Raises a ValueError if any sublist is empty.\n \"\"\"\n\n if not isinstance(list_of_lists, list):\n raise TypeError(\"Input must be a list of lists.\")\n\n if not list_of_lists:\n return []\n\n first_elements = []\n for sublist in list_of_lists:\n if not isinstance(sublist, list):\n raise TypeError(\"All sublists must be lists.\")\n if not sublist:\n raise ValueError(\"Sublists cannot be empty.\")\n first_elements.append(sublist[0])\n\n return first_elements", "matching_cluster_idx": 1}, {"solution": "def Extract(list_of_lists):\n \"\"\"\n Extracts the first element from each sublist in a list of lists.\n\n Args:\n list_of_lists: A list of lists.\n\n Returns:\n A list containing the first element of each sublist. Returns an empty list if the input is empty or contains empty sublists.\n\n \"\"\"\n if not list_of_lists:\n return []\n return [sublist[0] for sublist in list_of_lists if sublist]", "matching_cluster_idx": 3}, {"solution": "def Extract(lst):\n \"\"\"\n Write a python function to get the first element of each sublist.\n assert Extract([[1, 2], [3, 4, 5], [6, 7, 8, 9]]) == [1, 3, 6]\n \"\"\"\n return [sublist[0] for sublist in lst]", "matching_cluster_idx": 3}, {"solution": "def Extract(matrix):\n \"\"\"\n Extracts the first element from each sublist in a list of lists.\n\n Args:\n matrix: A list of lists (a matrix).\n\n Returns:\n A list containing the first element of each sublist in the input matrix.\n Returns an empty list if the input matrix is empty or contains empty sublists.\n\n \"\"\"\n if not matrix:\n return []\n return [sublist[0] for sublist in matrix if sublist]", "matching_cluster_idx": 3}, {"solution": "def Extract(list_of_lists):\n \"\"\"\n Write a python function to get the first element of each sublist.\n assert Extract([[1, 2], [3, 4, 5], [6, 7, 8, 9]]) == [1, 3, 6]\n \"\"\"\n first_elements = []\n for sublist in list_of_lists:\n if sublist: # Check if the sublist is not empty\n first_elements.append(sublist[0])\n return first_elements", "matching_cluster_idx": 3}, {"solution": "def Extract(list_of_lists):\n \"\"\"\n Write a python function to get the first element of each sublist.\n assert Extract([[1, 2], [3, 4, 5], [6, 7, 8, 9]]) == [1, 3, 6]\n \"\"\"\n first_elements = []\n for sublist in list_of_lists:\n if sublist: #handle empty sublists\n first_elements.append(sublist[0])\n return first_elements", "matching_cluster_idx": 2}, {"solution": "def Extract(list_of_lists):\n \"\"\"\n Extracts the first element from each sublist in a list of lists.\n\n Args:\n list_of_lists: A list of lists, where each sublist contains at least one element.\n\n Returns:\n A new list containing the first element of each sublist. Returns an empty list if the input is empty.\n Raises a TypeError if the input is not a list. Raises a ValueError if any sublist is empty.\n\n \"\"\"\n if not isinstance(list_of_lists, list):\n raise TypeError(\"Input must be a list of lists.\")\n \n if not list_of_lists:\n return []\n\n first_elements = []\n for sublist in list_of_lists:\n if not isinstance(sublist, list):\n raise TypeError(\"Input must be a list of lists.\")\n if not sublist:\n raise ValueError(\"Sublists cannot be empty.\")\n first_elements.append(sublist[0])\n return first_elements", "matching_cluster_idx": 1}, {"solution": "def Extract(list_of_lists):\n \"\"\"\n Extracts the first element from each sublist in a list of lists.\n\n Args:\n list_of_lists: A list of lists, where each sublist contains at least one element.\n\n Returns:\n A new list containing the first element of each sublist. Returns an empty list if the input is empty.\n Raises a TypeError if the input is not a list or if any sublist is not a list.\n Raises a ValueError if any sublist is empty.\n\n \"\"\"\n if not isinstance(list_of_lists, list):\n raise TypeError(\"Input must be a list of lists.\")\n\n if not list_of_lists: #Handle empty input list\n return []\n\n first_elements = []\n for sublist in list_of_lists:\n if not isinstance(sublist, list):\n raise TypeError(\"All sublists must be lists.\")\n if not sublist:\n raise ValueError(\"Sublists cannot be empty.\")\n first_elements.append(sublist[0])\n return first_elements", "matching_cluster_idx": 1}, {"solution": "def Extract(list_of_lists):\n \"\"\"\n Write a python function to get the first element of each sublist.\n assert Extract([[1, 2], [3, 4, 5], [6, 7, 8, 9]]) == [1, 3, 6]\n \"\"\"\n first_elements = []\n for sublist in list_of_lists:\n if sublist: #check for empty sublists to avoid IndexError\n first_elements.append(sublist[0])\n return first_elements", "matching_cluster_idx": 3}, {"solution": "def Extract(list_of_lists):\n \"\"\"\n Write a python function to get the first element of each sublist.\n assert Extract([[1, 2], [3, 4, 5], [6, 7, 8, 9]]) == [1, 3, 6]\n \"\"\"\n first_elements = []\n for sublist in list_of_lists:\n if sublist: #Check if sublist is not empty\n first_elements.append(sublist[0])\n return first_elements", "matching_cluster_idx": 3}, {"solution": "def Extract(lists):\n \"\"\"\n Extracts the first element from each sublist in a list of lists.\n\n Args:\n lists: A list of lists, where each sublist contains at least one element.\n\n Returns:\n A list containing the first element of each sublist. Returns an empty list if the input is empty.\n Raises a TypeError if input is not a list.\n Raises a ValueError if any sublist is empty.\n\n \"\"\"\n if not isinstance(lists, list):\n raise TypeError(\"Input must be a list of lists.\")\n \n if not lists:\n return []\n\n first_elements = []\n for sublist in lists:\n if not isinstance(sublist, list):\n raise TypeError(\"Input must be a list of lists.\")\n if not sublist:\n raise ValueError(\"Sublists cannot be empty.\")\n first_elements.append(sublist[0])\n return first_elements", "matching_cluster_idx": 1}, {"solution": "def Extract(list_of_lists):\n \"\"\"\n Extracts the first element from each sublist in a list of lists.\n\n Args:\n list_of_lists: A list of lists, where each sublist contains at least one element.\n\n Returns:\n A new list containing the first element of each sublist. Returns an empty list if the input is empty.\n Raises TypeError if input is not a list. Raises ValueError if any sublist is empty.\n \"\"\"\n if not isinstance(list_of_lists, list):\n raise TypeError(\"Input must be a list of lists.\")\n \n if not list_of_lists:\n return []\n\n first_elements = []\n for sublist in list_of_lists:\n if not isinstance(sublist, list):\n raise TypeError(\"Input must be a list of lists.\")\n if not sublist:\n raise ValueError(\"Sublists cannot be empty.\")\n first_elements.append(sublist[0])\n return first_elements", "matching_cluster_idx": 1}, {"solution": "def Extract(list_of_lists):\n \"\"\"\n Extracts the first element from each sublist within a list of lists.\n\n Args:\n list_of_lists: A list of lists, where each sublist contains at least one element.\n\n Returns:\n A new list containing the first element of each sublist. Returns an empty list if the input is empty. Raises an error if a sublist is empty.\n \"\"\"\n if not list_of_lists:\n return []\n \n first_elements = []\n for sublist in list_of_lists:\n if not sublist:\n raise ValueError(\"Sublist cannot be empty\")\n first_elements.append(sublist[0])\n return first_elements", "matching_cluster_idx": 2}, {"solution": "def Extract(list_of_lists):\n \"\"\"\n Extracts the first element from each sublist in a list of lists.\n\n Args:\n list_of_lists: A list of lists, where each sublist contains at least one element.\n\n Returns:\n A new list containing the first element of each sublist. Returns an empty list if the input is empty. Raises an exception if a sublist is empty.\n \"\"\"\n if not list_of_lists:\n return []\n \n first_elements = []\n for sublist in list_of_lists:\n if not sublist:\n raise ValueError(\"Sublist cannot be empty\")\n first_elements.append(sublist[0])\n return first_elements", "matching_cluster_idx": 2}, {"solution": "def Extract(data):\n \"\"\"\n Extracts the first element from each sublist in a list of lists.\n\n Args:\n data: A list of lists.\n\n Returns:\n A list containing the first element of each sublist. Returns an empty list if the input is empty or not a list of lists.\n \"\"\"\n if not isinstance(data, list):\n return []\n if not data:\n return []\n if not all(isinstance(sublist, list) for sublist in data):\n return []\n\n result = []\n for sublist in data:\n if sublist: # Check if sublist is not empty\n result.append(sublist[0])\n return result", "matching_cluster_idx": 1}, {"solution": "def Extract(list_of_lists):\n \"\"\"\n Extracts the first element from each sublist in a list of lists.\n\n Args:\n list_of_lists: A list of lists, where each sublist contains at least one element.\n\n Returns:\n A new list containing the first element of each sublist. Returns an empty list if the input is empty.\n Raises a TypeError if the input is not a list or if any sublist is not a list.\n \"\"\"\n if not isinstance(list_of_lists, list):\n raise TypeError(\"Input must be a list of lists.\")\n \n if not list_of_lists: #Handle empty list case\n return []\n\n first_elements = []\n for sublist in list_of_lists:\n if not isinstance(sublist, list):\n raise TypeError(\"All sublists must be lists.\")\n if not sublist: #Handle empty sublist case. Could also raise an error here.\n continue #Skip empty sublists.\n first_elements.append(sublist[0])\n return first_elements", "matching_cluster_idx": 1}, {"solution": "def Extract(List):\n \"\"\"\n This function takes a list of lists as input and returns a new list containing the first element of each sublist.\n\n Args:\n List: A list of lists.\n\n Returns:\n A new list containing the first element of each sublist. Returns an empty list if the input is empty or not a list of lists.\n \"\"\"\n if not isinstance(List, list):\n return []\n if not List:\n return []\n \n first_elements = []\n for sublist in List:\n if isinstance(sublist, list) and sublist: #Check if sublist is a list and not empty\n first_elements.append(sublist[0])\n return first_elements", "matching_cluster_idx": 1}, {"solution": "def Extract(list_of_lists):\n \"\"\"\n Extracts the first element from each sublist in a list of lists.\n\n Args:\n list_of_lists: A list of lists.\n\n Returns:\n A list containing the first element of each sublist. Returns an empty list if the input is empty or contains empty sublists. Raises TypeError if input is not a list.\n \"\"\"\n if not isinstance(list_of_lists, list):\n raise TypeError(\"Input must be a list of lists.\")\n\n first_elements = []\n for sublist in list_of_lists:\n if not isinstance(sublist, list):\n raise TypeError(\"Input must be a list of lists.\")\n if sublist: #check for empty sublist\n first_elements.append(sublist[0])\n return first_elements", "matching_cluster_idx": 1}, {"solution": "def Extract(list_of_lists):\n \"\"\"\n Extracts the first element from each sublist in a list of lists.\n\n Args:\n list_of_lists: A list of lists, where each sublist contains at least one element.\n\n Returns:\n A new list containing the first element of each sublist. Returns an empty list if the input is empty.\n Raises a TypeError if input is not a list. Raises a ValueError if any sublist is empty.\n \"\"\"\n if not isinstance(list_of_lists, list):\n raise TypeError(\"Input must be a list of lists.\")\n \n if not list_of_lists:\n return []\n\n first_elements = []\n for sublist in list_of_lists:\n if not isinstance(sublist, list):\n raise TypeError(\"Input must be a list of lists.\")\n if not sublist:\n raise ValueError(\"Sublists cannot be empty.\")\n first_elements.append(sublist[0])\n return first_elements", "matching_cluster_idx": 1}]}, "Mbpp/474": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def replace_char(input_string, char_to_replace, replacement_char):\n \"\"\"\n Replaces all occurrences of a character in a string with another character.\n\n Args:\n input_string: The string to modify.\n char_to_replace: The character to be replaced.\n replacement_char: The character to replace with.\n\n Returns:\n The modified string with the characters replaced. Returns the original string if char_to_replace is not found.\n \"\"\"\n return input_string.replace(char_to_replace, replacement_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(input_string, char_to_replace, replacement_char):\n \"\"\"Replaces all occurrences of a character in a string with another character.\n\n Args:\n input_string: The string to modify.\n char_to_replace: The character to be replaced.\n replacement_char: The character to replace with.\n\n Returns:\n The modified string with characters replaced. Returns the original string if char_to_replace is not found.\n \"\"\"\n return input_string.replace(char_to_replace, replacement_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(input_string, char_to_replace, replacement_char):\n \"\"\"Replaces all occurrences of a character in a string with another character.\n\n Args:\n input_string: The input string.\n char_to_replace: The character to be replaced.\n replacement_char: The character to replace with.\n\n Returns:\n The string with the characters replaced. Returns the original string if char_to_replace is not found.\n \"\"\"\n return input_string.replace(char_to_replace, replacement_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(input_string, char_to_replace, replacement_char):\n \"\"\"Replaces all occurrences of a character in a string with another character.\n\n Args:\n input_string: The string to modify.\n char_to_replace: The character to be replaced.\n replacement_char: The character to replace with.\n\n Returns:\n The modified string with the character replaced. Returns the original string if char_to_replace is not found.\n \"\"\"\n return input_string.replace(char_to_replace, replacement_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(input_string, char_to_replace, replacement_char):\n \"\"\"Replaces all occurrences of a character in a string with another character.\n\n Args:\n input_string: The string to modify.\n char_to_replace: The character to be replaced.\n replacement_char: The character to replace with.\n\n Returns:\n The modified string with the characters replaced. Returns the original string if char_to_replace is not found.\n \"\"\"\n return input_string.replace(char_to_replace, replacement_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(input_string, char_to_replace, replacement_char):\n \"\"\"\n Replaces all occurrences of a character in a string with another character.\n\n Args:\n input_string: The input string.\n char_to_replace: The character to be replaced.\n replacement_char: The character to replace with.\n\n Returns:\n The string with the characters replaced. Returns the original string if char_to_replace is not found.\n \"\"\"\n return input_string.replace(char_to_replace, replacement_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(input_string, char_to_replace, replacement_char):\n \"\"\"\n Replaces all occurrences of a character in a string with another character.\n\n Args:\n input_string: The string to modify.\n char_to_replace: The character to be replaced.\n replacement_char: The character to replace with.\n\n Returns:\n The modified string with the character replaced. Returns the original string if char_to_replace is not found.\n\n \"\"\"\n return input_string.replace(char_to_replace, replacement_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(input_string, char_to_replace, replacement_char):\n \"\"\"Replaces all occurrences of a character in a string with another character.\n\n Args:\n input_string: The string in which to replace characters.\n char_to_replace: The character to be replaced.\n replacement_char: The character to replace with.\n\n Returns:\n The string with the characters replaced. Returns the original string if char_to_replace is not found.\n\n \"\"\"\n return input_string.replace(char_to_replace, replacement_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(input_string, char_to_replace, replacement_char):\n \"\"\"Replaces all occurrences of a character in a string with another character.\n\n Args:\n input_string: The string to modify.\n char_to_replace: The character to be replaced.\n replacement_char: The character to replace with.\n\n Returns:\n The modified string with the replacements made. Returns the original string if char_to_replace is not found.\n\n \"\"\"\n return input_string.replace(char_to_replace, replacement_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(input_string, char_to_replace, replacement_char):\n \"\"\"Replaces all occurrences of a character in a string with another character.\n\n Args:\n input_string: The input string.\n char_to_replace: The character to be replaced.\n replacement_char: The character to replace with.\n\n Returns:\n The string with the characters replaced. Returns the original string if char_to_replace is not found.\n \"\"\"\n return input_string.replace(char_to_replace, replacement_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(input_string, char_to_replace, replacement_char):\n \"\"\"Replaces all occurrences of a character in a string with another character.\n\n Args:\n input_string: The string to modify.\n char_to_replace: The character to be replaced.\n replacement_char: The character to replace with.\n\n Returns:\n The modified string with characters replaced. Returns the original string if char_to_replace is not found.\n \"\"\"\n return input_string.replace(char_to_replace, replacement_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(input_string, char_to_replace, replacement_char):\n \"\"\"Replaces all occurrences of a character in a string with another character.\n\n Args:\n input_string: The string to modify.\n char_to_replace: The character to be replaced.\n replacement_char: The character to replace with.\n\n Returns:\n The modified string with the character replaced. Returns the original string if char_to_replace is not found.\n \"\"\"\n return input_string.replace(char_to_replace, replacement_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(input_string, char_to_replace, replacement_char):\n \"\"\"\n Replaces all occurrences of a specified character in a string with another character.\n\n Args:\n input_string: The input string.\n char_to_replace: The character to be replaced.\n replacement_char: The character to replace with.\n\n Returns:\n The modified string with the character replaced. Returns the original string if char_to_replace is not found.\n\n \"\"\"\n return input_string.replace(char_to_replace, replacement_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(input_string, char_to_replace, replacement_char):\n \"\"\"\n Replaces all occurrences of a character in a string with another character.\n\n Args:\n input_string: The input string.\n char_to_replace: The character to be replaced.\n replacement_char: The character to replace with.\n\n Returns:\n The string with the characters replaced. Returns the original string if char_to_replace is not found.\n \"\"\"\n return input_string.replace(char_to_replace, replacement_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(input_string, char_to_replace, replacement_char):\n \"\"\"Replaces all occurrences of a character in a string with another character.\n\n Args:\n input_string: The string to modify.\n char_to_replace: The character to be replaced.\n replacement_char: The character to replace with.\n\n Returns:\n The modified string with the characters replaced. Returns the original string if char_to_replace is not found.\n\n \"\"\"\n return input_string.replace(char_to_replace, replacement_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(input_string, char_to_replace, replacement_char):\n \"\"\"\n Replaces all occurrences of a specific character in a string with another character.\n\n Args:\n input_string: The input string.\n char_to_replace: The character to be replaced.\n replacement_char: The character to replace with.\n\n Returns:\n The string with the characters replaced. Returns the original string if char_to_replace is not found.\n \"\"\"\n return input_string.replace(char_to_replace, replacement_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(input_string, char_to_replace, replacement_char):\n \"\"\"\n Replaces all occurrences of a character in a string with another character.\n\n Args:\n input_string: The string to modify.\n char_to_replace: The character to be replaced.\n replacement_char: The character to replace with.\n\n Returns:\n The modified string with the replacements made. Returns the original string if char_to_replace is not found.\n \"\"\"\n return input_string.replace(char_to_replace, replacement_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(input_string, char_to_replace, replacement_char):\n \"\"\"\n Replaces all occurrences of a character in a string with another character.\n\n Args:\n input_string: The input string.\n char_to_replace: The character to be replaced.\n replacement_char: The character to replace with.\n\n Returns:\n The modified string with characters replaced. Returns the original string if char_to_replace is not found.\n \"\"\"\n return input_string.replace(char_to_replace, replacement_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(input_string, char_to_replace, replacement_char):\n \"\"\"\n Replaces all occurrences of a character in a string with another character.\n\n Args:\n input_string: The input string.\n char_to_replace: The character to be replaced.\n replacement_char: The character to replace with.\n\n Returns:\n The modified string with the characters replaced. Returns the original string if char_to_replace is not found.\n\n \"\"\"\n return input_string.replace(char_to_replace, replacement_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(input_string, char_to_replace, replacement_char):\n \"\"\"Replaces all occurrences of a character in a string with another character.\n\n Args:\n input_string: The string to modify.\n char_to_replace: The character to be replaced.\n replacement_char: The character to replace with.\n\n Returns:\n The modified string with the character replaced. Returns the original string if char_to_replace is not found.\n\n \"\"\"\n return input_string.replace(char_to_replace, replacement_char)", "matching_cluster_idx": 6}]}, "Mbpp/476": {"dps": 73.89261744966443, "dps_norm": 83.33333333333333, "pass@1": 100.0, "profiled": [{"solution": "def big_sum(arr):\n \"\"\"\n Finds the sum of the largest and smallest values in a given array.\n\n Args:\n arr: A list of numbers.\n\n Returns:\n The sum of the largest and smallest numbers in the array. Returns 0 if the array is empty.\n\n Raises:\n TypeError: if input is not a list.\n ValueError: if input list contains non-numeric values.\n\n \"\"\"\n if not isinstance(arr, list):\n raise TypeError(\"Input must be a list.\")\n if not arr:\n return 0\n if not all(isinstance(x, (int, float)) for x in arr):\n raise ValueError(\"List must contain only numbers.\")\n\n min_val = min(arr)\n max_val = max(arr)\n return min_val + max_val", "matching_cluster_idx": 1}, {"solution": "def big_sum(arr):\n \"\"\"\n Finds the sum of the largest and smallest values in a given array.\n\n Args:\n arr: A list of numbers.\n\n Returns:\n The sum of the largest and smallest values in the array. Returns 0 for an empty array.\n \"\"\"\n if not arr:\n return 0\n return max(arr) + min(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n \"\"\"\n Finds the sum of the largest and smallest values in a given array.\n\n Args:\n arr: A list of numbers.\n\n Returns:\n The sum of the largest and smallest numbers in the array. Returns 0 for an empty array.\n \"\"\"\n if not arr:\n return 0\n return max(arr) + min(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n \"\"\"\n Finds the sum of the largest and smallest values in an array.\n\n Args:\n arr: A list of numbers.\n\n Returns:\n The sum of the largest and smallest numbers in the array. Returns 0 for empty arrays.\n \"\"\"\n if not arr:\n return 0\n return max(arr) + min(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n \"\"\"\n Finds the sum of the largest and smallest values in a given array.\n\n Args:\n arr: A list of numbers.\n\n Returns:\n The sum of the largest and smallest numbers in the array. Returns 0 if the array is empty.\n\n Raises:\n TypeError: if input is not a list.\n ValueError: if input list contains non-numeric values.\n\n \"\"\"\n if not isinstance(arr, list):\n raise TypeError(\"Input must be a list.\")\n if not arr:\n return 0\n if not all(isinstance(x, (int, float)) for x in arr):\n raise ValueError(\"List must contain only numbers.\")\n\n min_val = min(arr)\n max_val = max(arr)\n return min_val + max_val", "matching_cluster_idx": 1}, {"solution": "def big_sum(arr):\n \"\"\"\n Finds the sum of the largest and smallest values in an array.\n\n Args:\n arr: A list of numbers.\n\n Returns:\n The sum of the largest and smallest numbers in the array. Returns 0 for empty arrays.\n \"\"\"\n if not arr:\n return 0\n return max(arr) + min(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n \"\"\"\n Finds the sum of the largest and smallest values in a given array.\n\n Args:\n arr: A list of numbers.\n\n Returns:\n The sum of the largest and smallest numbers in the array. Returns 0 for empty arrays.\n\n Raises:\n TypeError: if input is not a list.\n ValueError: if input list contains non-numeric values.\n\n \"\"\"\n if not isinstance(arr, list):\n raise TypeError(\"Input must be a list.\")\n if not all(isinstance(x, (int, float)) for x in arr):\n raise ValueError(\"List must contain only numbers.\")\n if not arr:\n return 0 #Handle empty list case.\n return max(arr) + min(arr)", "matching_cluster_idx": 1}, {"solution": "def big_sum(arr):\n \"\"\"\n Write a python function to find the sum of the largest and smallest value in a given array.\n assert big_sum([1,2,3]) == 4\n \"\"\"\n if not arr:\n return 0 # Handle empty array case\n \n min_val = arr[0]\n max_val = arr[0]\n for num in arr:\n if num < min_val:\n min_val = num\n if num > max_val:\n max_val = num\n return min_val + max_val", "matching_cluster_idx": 3}, {"solution": "def big_sum(arr):\n \"\"\"\n Write a python function to find the sum of the largest and smallest value in a given array.\n assert big_sum([1,2,3]) == 4\n \"\"\"\n if not arr:\n return 0 # Handle empty array case\n\n min_val = arr[0]\n max_val = arr[0]\n\n for num in arr:\n if num < min_val:\n min_val = num\n if num > max_val:\n max_val = num\n\n return min_val + max_val", "matching_cluster_idx": 3}, {"solution": "def big_sum(arr):\n \"\"\"\n Finds the sum of the largest and smallest values in an array.\n\n Args:\n arr: A list of numbers.\n\n Returns:\n The sum of the largest and smallest numbers in the array. Returns 0 for empty arrays.\n \"\"\"\n if not arr:\n return 0\n return max(arr) + min(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n \"\"\"\n Finds the sum of the largest and smallest values in an array.\n\n Args:\n arr: A list of numbers.\n\n Returns:\n The sum of the largest and smallest numbers in the array. Returns 0 for empty arrays.\n \"\"\"\n if not arr:\n return 0\n else:\n return max(arr) + min(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n \"\"\"\n Finds the sum of the largest and smallest values in a given array.\n\n Args:\n arr: A list of numbers.\n\n Returns:\n The sum of the largest and smallest numbers in the array. Returns 0 for empty arrays.\n \"\"\"\n if not arr:\n return 0\n return max(arr) + min(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n \"\"\"\n Finds the sum of the largest and smallest values in an array.\n\n Args:\n arr: A list of numbers.\n\n Returns:\n The sum of the largest and smallest numbers in the array. Returns 0 for empty arrays.\n \"\"\"\n if not arr:\n return 0\n return max(arr) + min(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n \"\"\"\n Finds the sum of the largest and smallest values in a given array.\n\n Args:\n arr: A list of numbers.\n\n Returns:\n The sum of the largest and smallest values in the array. Returns 0 for empty arrays.\n \"\"\"\n if not arr:\n return 0\n return max(arr) + min(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n \"\"\"\n Finds the sum of the largest and smallest values in a given array.\n\n Args:\n arr: A list of numbers.\n\n Returns:\n The sum of the largest and smallest numbers in the array. Returns 0 for empty arrays.\n \"\"\"\n if not arr:\n return 0\n return max(arr) + min(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n \"\"\"\n Finds the sum of the largest and smallest values in an array.\n\n Args:\n arr: A list of numbers.\n\n Returns:\n The sum of the largest and smallest numbers in the array.\n Returns 0 if the array is empty.\n \"\"\"\n if not arr:\n return 0\n return max(arr) + min(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n \"\"\"\n Finds the sum of the largest and smallest values in a given array.\n\n Args:\n arr: A list of numbers.\n\n Returns:\n The sum of the largest and smallest numbers in the array. Returns 0 for empty arrays.\n \"\"\"\n if not arr:\n return 0\n return max(arr) + min(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n \"\"\"\n Finds the sum of the largest and smallest values in a given array.\n\n Args:\n arr: A list of numbers.\n\n Returns:\n The sum of the largest and smallest numbers in the array. Returns 0 for an empty array.\n \"\"\"\n if not arr:\n return 0\n return max(arr) + min(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n \"\"\"\n Finds the sum of the largest and smallest values in a given array.\n\n Args:\n arr: A list of numbers.\n\n Returns:\n The sum of the largest and smallest numbers in the array. Returns 0 for empty arrays.\n \"\"\"\n if not arr:\n return 0\n return max(arr) + min(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n \"\"\"\n Finds the sum of the largest and smallest values in a given array.\n\n Args:\n arr: A list of numbers.\n\n Returns:\n The sum of the largest and smallest numbers in the array. Returns 0 for empty arrays.\n\n Raises:\n TypeError: if input is not a list.\n ValueError: if input list contains non-numeric values.\n\n \"\"\"\n if not isinstance(arr, list):\n raise TypeError(\"Input must be a list.\")\n if not all(isinstance(x, (int, float)) for x in arr):\n raise ValueError(\"List must contain only numbers.\")\n if not arr:\n return 0 # Handle empty list case\n\n return max(arr) + min(arr)", "matching_cluster_idx": 1}]}, "Mbpp/477": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def is_lower(input_string):\n \"\"\"\n Converts a given string to lowercase.\n\n Args:\n input_string: The string to convert.\n\n Returns:\n The lowercase version of the input string.\n \"\"\"\n return input_string.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(input_string):\n \"\"\"Converts a given string to lowercase.\n\n Args:\n input_string: The string to convert.\n\n Returns:\n The lowercase version of the input string.\n \"\"\"\n return input_string.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(input_string):\n \"\"\"\n Converts the given string to lower case.\n\n Args:\n input_string: The string to convert.\n\n Returns:\n The lower case version of the input string.\n \"\"\"\n return input_string.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(input_string):\n \"\"\"Converts a given string to lowercase.\n\n Args:\n input_string: The string to convert.\n\n Returns:\n The lowercase version of the input string.\n \"\"\"\n return input_string.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(input_string):\n \"\"\"Converts a given string to lowercase.\n\n Args:\n input_string: The string to convert.\n\n Returns:\n The lowercase version of the input string.\n \"\"\"\n return input_string.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(input_string):\n \"\"\"Converts a given string to lowercase.\n\n Args:\n input_string: The string to convert.\n\n Returns:\n The lowercase version of the input string.\n \"\"\"\n return input_string.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(input_string):\n \"\"\"\n Converts a given string to lowercase.\n\n Args:\n input_string: The string to convert.\n\n Returns:\n The lowercase version of the input string.\n \"\"\"\n return input_string.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(input_string):\n \"\"\"Converts a given string to lowercase.\n\n Args:\n input_string: The string to convert.\n\n Returns:\n The lowercase version of the input string.\n \"\"\"\n return input_string.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(input_string):\n \"\"\"Converts a given string to lowercase.\n\n Args:\n input_string: The string to convert.\n\n Returns:\n The lowercase version of the input string.\n \"\"\"\n return input_string.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(input_string):\n \"\"\"\n Converts the given string to lower case.\n\n Args:\n input_string: The string to convert.\n\n Returns:\n The lower case version of the string.\n \"\"\"\n return input_string.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(input_string):\n \"\"\"Converts a given string to lowercase.\n\n Args:\n input_string: The string to convert.\n\n Returns:\n The lowercase version of the input string.\n \"\"\"\n return input_string.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(input_string):\n \"\"\"\n Converts the given string to lower case.\n\n Args:\n input_string: The string to convert.\n\n Returns:\n The lower case version of the string.\n \"\"\"\n return input_string.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(input_string):\n \"\"\"\n Converts the given string to lower case.\n\n Args:\n input_string: The string to convert.\n\n Returns:\n The lower case version of the input string.\n \"\"\"\n return input_string.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(input_string):\n \"\"\"Converts a given string to lowercase.\n\n Args:\n input_string: The string to convert.\n\n Returns:\n The lowercase version of the input string.\n \"\"\"\n return input_string.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(input_string):\n \"\"\"\n Converts the given string to lower case.\n\n Args:\n input_string: The string to convert.\n\n Returns:\n The lower case version of the string.\n \"\"\"\n return input_string.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(input_string):\n \"\"\"Converts a given string to lowercase.\n\n Args:\n input_string: The string to convert.\n\n Returns:\n The lowercase version of the input string.\n \"\"\"\n return input_string.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(input_string):\n \"\"\"\n Converts the given string to lower case.\n\n Args:\n input_string: The string to convert.\n\n Returns:\n The lower case version of the input string.\n \"\"\"\n return input_string.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(input_string):\n \"\"\"Converts a given string to lowercase.\n\n Args:\n input_string: The string to convert.\n\n Returns:\n The lowercase version of the input string.\n \"\"\"\n return input_string.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(input_string):\n \"\"\"\n Converts the given string to lower case.\n\n Args:\n input_string: The string to convert.\n\n Returns:\n The lower case version of the string.\n \"\"\"\n return input_string.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(input_string):\n \"\"\"Converts a given string to lowercase.\n\n Args:\n input_string: The string to convert.\n\n Returns:\n The lowercase version of the input string.\n \"\"\"\n return input_string.lower()", "matching_cluster_idx": 4}]}, "Mbpp/563": {"dps": 80.3825136612022, "dps_norm": 80.9090909090909, "pass@1": 98.0, "profiled": [{"solution": "import re\ndef extract_values(input_string):\n \"\"\"\n Extracts values between quotation marks from a string.\n\n Args:\n input_string: The input string containing values enclosed in quotation marks.\n\n Returns:\n A list of strings, where each string is a value extracted from the input string.\n Returns an empty list if no values are found. Handles nested quotes poorly.\n \"\"\"\n matches = re.findall(r'\"([^\"]*)\"', input_string) #Finds all strings inside double quotes\n return matches", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(input_string):\n \"\"\"\n Extracts values enclosed in double quotes from a string.\n\n Args:\n input_string: The input string containing values in double quotes.\n\n Returns:\n A list of strings, where each string is a value extracted from \n the input string. Returns an empty list if no values are found.\n \"\"\"\n \n values = re.findall(r'\"(.*?)\"', input_string)\n return values", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(input_string):\n \"\"\"\n Extracts values enclosed in double quotes from a string.\n\n Args:\n input_string: The input string containing values in double quotes.\n\n Returns:\n A list of strings, where each string is a value extracted from \n the input string. Returns an empty list if no values are found.\n \"\"\"\n \n #Use regular expression to find all strings enclosed in double quotes.\n values = re.findall(r'\"([^\"]*)\"', input_string) \n return values", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(input_string):\n \"\"\"\n Extracts values enclosed in double quotes from a string.\n\n Args:\n input_string: The input string containing values in double quotes.\n\n Returns:\n A list of strings, where each string is a value extracted from the input string. Returns an empty list if no values are found.\n \"\"\"\n values = re.findall(r'\"(.*?)\"', input_string)\n return values", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(input_string):\n \"\"\"\n Extracts values enclosed in double quotes from a string.\n\n Args:\n input_string: The input string containing values in double quotes.\n\n Returns:\n A list of strings, where each string is a value extracted from \n the input string. Returns an empty list if no values are found.\n \"\"\"\n \n # Use regular expression to find all strings enclosed in double quotes\n matches = re.findall(r'\"(.*?)\"', input_string)\n return matches", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(input_string):\n \"\"\"\n Extracts values enclosed in double quotes from a string.\n\n Args:\n input_string: The input string containing values in double quotes.\n\n Returns:\n A list of strings, where each string is a value extracted from the input string. Returns an empty list if no values are found.\n \"\"\"\n matches = re.findall(r'\"(.*?)\"', input_string)\n return matches", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(input_string):\n \"\"\"\n Extracts values enclosed in double quotes from a string.\n\n Args:\n input_string: The input string containing quoted values.\n\n Returns:\n A list of strings, where each string is a value extracted from \n the input string. Returns an empty list if no quoted values are found.\n \"\"\"\n matches = re.findall(r'\"([^\"]*)\"', input_string)\n return matches", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(input_string):\n \"\"\"\n Extracts values between quotation marks from a string.\n\n Args:\n input_string: The input string containing values enclosed in quotation marks.\n\n Returns:\n A list of strings, where each string is a value extracted from the input string.\n Returns an empty list if no values are found. Handles nested quotes poorly.\n \"\"\"\n \n #Using regular expressions for a more robust solution. This handles spaces within the quotes\n matches = re.findall(r'\"([^\"]*)\"', input_string) \n return matches", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(input_string):\n \"\"\"\n Extracts values between quotation marks from a string.\n\n Args:\n input_string: The input string containing values enclosed in quotation marks.\n\n Returns:\n A list of strings, where each string is a value extracted from the input string. Returns an empty list if no values are found.\n \"\"\"\n #Use regular expression to find all strings enclosed in double quotes.\n matches = re.findall(r'\"([^\"]*)\"', input_string)\n return matches", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(input_string):\n \"\"\"\n Extracts values between quotation marks from a string.\n\n Args:\n input_string: The input string containing values enclosed in quotation marks.\n\n Returns:\n A list of strings, where each string is a value extracted from the input string.\n Returns an empty list if no values are found. Handles nested quotes gracefully.\n \"\"\"\n matches = re.findall(r'\"([^\"]*)\"', input_string) #Finds all strings within double quotes\n return matches", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(input_string):\n \"\"\"\n Extracts values enclosed in double quotes from a string.\n\n Args:\n input_string: The input string containing values in double quotes.\n\n Returns:\n A list of strings, where each string is a value extracted from the input string.\n Returns an empty list if no values are found. Handles escaped quotes.\n \"\"\"\n # Use a regular expression to find all strings enclosed in double quotes, handling escaped quotes\n matches = re.findall(r'\"([^\"\\\\]*(?:\\\\.[^\"\\\\]*)*)\"', input_string)\n return matches", "matching_cluster_idx": 7}, {"solution": "import re\ndef extract_values(input_string):\n \"\"\"\n Extracts values enclosed in double quotes from a string.\n\n Args:\n input_string: The input string containing values in double quotes.\n\n Returns:\n A list of strings, where each string is a value extracted from \n the input string. Returns an empty list if no values are found.\n \"\"\"\n matches = re.findall(r'\"([^\"]*)\"', input_string)\n return matches", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(input_string):\n \"\"\"\n Extracts values between quotation marks from a string.\n\n Args:\n input_string: The input string containing values enclosed in quotation marks.\n\n Returns:\n A list of strings, where each string is a value extracted from the input string. Returns an empty list if no values are found.\n \"\"\"\n matches = re.findall(r'\"(.*?)\"', input_string)\n return matches", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(input_string):\n \"\"\"\n Extracts values enclosed in double quotes from a string.\n\n Args:\n input_string: The input string containing values in double quotes.\n\n Returns:\n A list of strings, where each string is a value extracted from the input string.\n Returns an empty list if no values are found. Handles cases with escaped quotes.\n \"\"\"\n \n #Use a regular expression to find all strings enclosed in double quotes, handling escaped quotes\n matches = re.findall(r'\"([^\"\\\\]*(?:\\\\.[^\"\\\\]*)*)\"', input_string)\n return matches", "matching_cluster_idx": 7}, {"solution": "import re\ndef extract_values(input_string):\n \"\"\"\n Extracts values enclosed in double quotes from a string.\n\n Args:\n input_string: The input string containing values in double quotes.\n\n Returns:\n A list of strings, where each string is a value extracted from the input string.\n Returns an empty list if no values are found.\n \"\"\"\n matches = re.findall(r'\"([^\"]*)\"', input_string)\n return matches", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(input_string):\n \"\"\"\n Extracts values enclosed in double quotes from a string.\n\n Args:\n input_string: The input string containing quoted values.\n\n Returns:\n A list of strings, where each string is a value extracted from \n the input string. Returns an empty list if no quoted values are found.\n \"\"\"\n \n # Use regular expression to find all strings enclosed in double quotes.\n matches = re.findall(r'\"([^\"]*)\"', input_string)\n return matches", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(input_string):\n \"\"\"\n Extracts values enclosed in double quotes from a string.\n\n Args:\n input_string: The input string containing values in double quotes.\n\n Returns:\n A list of strings, where each string is a value extracted from the input string. Returns an empty list if no values are found.\n \"\"\"\n \n # Use regular expression to find all strings enclosed in double quotes\n matches = re.findall(r'\"(.*?)\"', input_string)\n return matches", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(input_string):\n \"\"\"\n Extracts values between quotation marks from a string.\n\n Args:\n input_string: The input string containing values enclosed in quotation marks.\n\n Returns:\n A list of strings, where each string is a value extracted from the input string. Returns an empty list if no values are found.\n \"\"\"\n matches = re.findall(r'\"(.*?)\"', input_string)\n return matches\ninput_string = '\"Python\", \"PHP\", \"Java\"'", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(input_string):\n \"\"\"\n Extracts values enclosed in double quotes from a string.\n\n Args:\n input_string: The input string containing values in double quotes.\n\n Returns:\n A list of strings, where each string is a value extracted from the input string. Returns an empty list if no values are found.\n \"\"\"\n #Use regular expression to find all strings enclosed in double quotes\n matches = re.findall(r'\"(.*?)\"', input_string)\n return matches", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(input_string):\n \"\"\"\n Extracts values between quotation marks from a string.\n\n Args:\n input_string: The input string containing values enclosed in quotation marks.\n\n Returns:\n A list of strings, where each string is a value extracted from the input string. Returns an empty list if no values are found.\n \"\"\"\n matches = re.findall(r'\"([^\"]*)\"', input_string)\n return matches", "matching_cluster_idx": 8}]}, "Mbpp/572": {"dps": 57.345679012345684, "dps_norm": 76.42857142857143, "pass@1": 39.0, "profiled": [{"solution": "def two_unique_nums(nums):\n \"\"\"\n Write a python function to remove duplicate numbers from a given number of lists.\n assert two_unique_nums([1,2,3,2,3,4,5]) == [1, 4, 5]\n \"\"\"\n seen = set()\n result = []\n for num in nums:\n if num not in seen:\n seen.add(num)\n result.append(num)\n \n #The problem description is ambiguous. It says \"remove duplicate numbers\" but the assertion only seems to keep numbers that appear only once.\n #This section addresses the ambiguity by only keeping numbers that appear once.\n\n counts = {}\n for num in nums:\n counts[num] = counts.get(num, 0) + 1\n \n final_result = [num for num in result if counts[num] == 1]\n\n return final_result", "matching_cluster_idx": 4}, {"solution": "def two_unique_nums(nums):\n \"\"\"\n Write a python function to remove duplicate numbers from a given number of lists.\n assert two_unique_nums([1,2,3,2,3,4,5]) == [1, 4, 5]\n \"\"\"\n seen = set()\n result = []\n for num in nums:\n if num not in seen:\n seen.add(num)\n result.append(num)\n \n # This part addresses the specific assertion. The original problem statement was ambiguous.\n # This ensures only numbers that appear only once in the original list are kept.\n counts = {}\n for num in nums:\n counts[num] = counts.get(num, 0) + 1\n \n final_result = []\n for num in result:\n if counts[num] == 1:\n final_result.append(num)\n \n return final_result", "matching_cluster_idx": 4}, {"solution": "def two_unique_nums(nums):\n \"\"\"\n Write a python function to remove duplicate numbers from a given number of lists.\n assert two_unique_nums([1,2,3,2,3,4,5]) == [1, 4, 5]\n \"\"\"\n seen = set()\n result = []\n for num in nums:\n if num not in seen:\n seen.add(num)\n result.append(num)\n \n #The problem statement is slightly ambiguous. This version keeps only numbers appearing only once.\n counts = {}\n for num in nums:\n counts[num] = counts.get(num,0) + 1\n\n final_result = [num for num in result if counts[num] == 1]\n\n return final_result", "matching_cluster_idx": 4}, {"solution": "def two_unique_nums(nums):\n \"\"\"\n Removes duplicate numbers from a list, keeping only numbers that appear exactly once.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n A new list containing only the numbers that appeared exactly once in the input list. \n The order of elements is preserved from the original list.\n \"\"\"\n counts = {}\n for num in nums:\n counts[num] = counts.get(num, 0) + 1\n\n unique_nums = []\n for num in nums:\n if counts[num] == 1:\n unique_nums.append(num)\n return unique_nums", "matching_cluster_idx": 4}, {"solution": "def two_unique_nums(nums):\n \"\"\"\n Removes duplicate numbers from a given list, leaving only numbers that appear exactly once.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n A list containing only the numbers that appeared exactly once in the input list. \n Returns an empty list if the input is invalid.\n \"\"\"\n if not isinstance(nums, list):\n return [] # Handle invalid input\n\n counts = {}\n for num in nums:\n counts[num] = counts.get(num, 0) + 1\n\n unique_nums = [num for num, count in counts.items() if count == 1]\n return unique_nums", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(nums):\n \"\"\"\n Write a python function to remove duplicate numbers from a given number of lists.\n assert two_unique_nums([1,2,3,2,3,4,5]) == [1, 4, 5]\n \"\"\"\n seen = set()\n result = []\n for num in nums:\n if num not in seen:\n seen.add(num)\n result.append(num)\n \n #The problem description implies we should only keep numbers appearing exactly twice. The assert is wrong. This section addresses that implied requirement. The docstring is incorrect.\n counts = {}\n for num in nums:\n counts[num] = counts.get(num, 0) + 1\n\n final_result = []\n for num, count in counts.items():\n if count == 1:\n final_result.append(num)\n return final_result", "matching_cluster_idx": 4}, {"solution": "def two_unique_nums(nums):\n \"\"\"\n Write a python function to remove duplicate numbers from a given number of lists.\n assert two_unique_nums([1,2,3,2,3,4,5]) == [1, 4, 5]\n \"\"\"\n seen = set()\n result = []\n for num in nums:\n if num not in seen:\n seen.add(num)\n result.append(num)\n \n #The problem statement is ambiguous. Should it only return unique numbers\n #that appear once, or should it return unique numbers regardless of frequency?\n #The assertion implies the former. This section implements that.\n counts = {}\n for num in nums:\n counts[num] = counts.get(num,0) + 1\n \n final_result = []\n for num in result:\n if counts[num] == 1:\n final_result.append(num)\n return final_result", "matching_cluster_idx": 4}, {"solution": "def two_unique_nums(nums):\n \"\"\"\n Write a python function to remove duplicate numbers from a given number of lists.\n assert two_unique_nums([1,2,3,2,3,4,5]) == [1, 4, 5]\n \"\"\"\n seen = set()\n result = []\n for num in nums:\n if num not in seen:\n seen.add(num)\n result.append(num)\n \n #To get only the numbers that appear exactly once. The original prompt was ambiguous\n counts = {}\n for x in nums:\n counts[x] = counts.get(x,0) + 1\n \n final_result = [x for x in result if counts[x] == 1]\n\n\n return final_result", "matching_cluster_idx": 4}, {"solution": "def two_unique_nums(nums):\n \"\"\"\n Write a python function to remove duplicate numbers from a given number of lists.\n assert two_unique_nums([1,2,3,2,3,4,5]) == [1, 4, 5]\n \"\"\"\n counts = {}\n for num in nums:\n counts[num] = counts.get(num, 0) + 1\n\n unique_nums = []\n for num, count in counts.items():\n if count == 1:\n unique_nums.append(num)\n return unique_nums", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(nums):\n \"\"\"\n Write a python function to remove duplicate numbers from a given number of lists.\n assert two_unique_nums([1,2,3,2,3,4,5]) == [1, 4, 5]\n \"\"\"\n seen = set()\n result = []\n for num in nums:\n if num not in seen:\n seen.add(num)\n result.append(num)\n \n #This part addresses the specific assertion example, implying only numbers appearing twice or more should be removed.\n counts = {}\n for num in nums:\n counts[num] = counts.get(num, 0) + 1\n \n final_result = []\n for num in result:\n if counts[num] == 1:\n final_result.append(num)\n \n return final_result", "matching_cluster_idx": 4}, {"solution": "def two_unique_nums(nums):\n \"\"\"\n Write a python function to remove duplicate numbers from a given number of lists.\n assert two_unique_nums([1,2,3,2,3,4,5]) == [1, 4, 5]\n \"\"\"\n seen = set()\n result = []\n for num in nums:\n if num not in seen:\n seen.add(num)\n result.append(num)\n \n #The problem statement is unclear. It states removing duplicates but the assert shows only unique numbers appearing only once.\n #This section handles the case where it's actually intended to remove elements appearing more than once.\n\n counts = {}\n for num in nums:\n counts[num] = counts.get(num,0) +1\n\n final_result = []\n for num in result:\n if counts[num] == 1:\n final_result.append(num)\n\n return final_result", "matching_cluster_idx": 4}, {"solution": "def two_unique_nums(nums):\n \"\"\"\n Removes duplicate numbers from a list, keeping only numbers that appear exactly once.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n A new list containing only the numbers that appeared exactly once in the input list. The order is preserved from the original list.\n \"\"\"\n counts = {}\n for num in nums:\n counts[num] = counts.get(num, 0) + 1\n\n unique_nums = []\n for num in nums:\n if counts[num] == 1:\n unique_nums.append(num)\n\n return unique_nums", "matching_cluster_idx": 4}, {"solution": "def two_unique_nums(nums):\n \"\"\"\n Removes duplicate numbers from a given list, keeping only numbers that appear exactly once.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n A new list containing only the numbers that appeared exactly once in the input list. The order is preserved from the original list.\n \"\"\"\n counts = {}\n for num in nums:\n counts[num] = counts.get(num, 0) + 1\n\n unique_nums = []\n for num in nums:\n if counts[num] == 1:\n unique_nums.append(num)\n\n return unique_nums", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(nums):\n \"\"\"\n Write a python function to remove duplicate numbers from a given number of lists.\n assert two_unique_nums([1,2,3,2,3,4,5]) == [1, 4, 5]\n \"\"\"\n seen = set()\n result = []\n for num in nums:\n if num not in seen:\n seen.add(num)\n result.append(num)\n \n #This part addresses the assertion example. The prompt was slightly unclear\n # about whether to return only numbers appearing twice, or removing duplicates\n # entirely. This next section finds numbers that appear only once.\n\n counts = {}\n for num in nums:\n counts[num] = counts.get(num, 0) + 1\n\n final_result = []\n for num in result:\n if counts[num] == 1:\n final_result.append(num)\n\n return final_result", "matching_cluster_idx": 4}, {"solution": "def two_unique_nums(nums):\n \"\"\"\n Write a python function to remove duplicate numbers from a given number of lists.\n assert two_unique_nums([1,2,3,2,3,4,5]) == [1, 4, 5]\n \"\"\"\n counts = {}\n for num in nums:\n counts[num] = counts.get(num, 0) + 1\n\n unique_nums = []\n for num, count in counts.items():\n if count == 1:\n unique_nums.append(num)\n\n return unique_nums", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(nums):\n \"\"\"\n Write a python function to remove duplicate numbers from a given number of lists.\n assert two_unique_nums([1,2,3,2,3,4,5]) == [1, 4, 5]\n \"\"\"\n seen = set()\n result = []\n for num in nums:\n if num not in seen:\n seen.add(num)\n result.append(num)\n \n #This section handles the assertion failure scenario described in the comments.\n #The problem statement is ambiguous. This section assumes the intent is to \n #return only numbers that appear exactly once in the input list.\n\n counts = {}\n for num in nums:\n counts[num] = counts.get(num, 0) + 1\n\n final_result = []\n for num in result:\n if counts[num] == 1:\n final_result.append(num)\n\n return final_result", "matching_cluster_idx": 4}, {"solution": "def two_unique_nums(nums):\n \"\"\"\n Removes duplicate numbers from a given list, returning only numbers that appear exactly once.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n A list containing only the numbers that appeared exactly once in the input list. The order is preserved from the original list.\n \"\"\"\n counts = {}\n for num in nums:\n counts[num] = counts.get(num, 0) + 1\n \n result = []\n for num in nums:\n if counts[num] == 1:\n result.append(num)\n return result", "matching_cluster_idx": 4}, {"solution": "def two_unique_nums(nums):\n \"\"\"\n Removes duplicate numbers from a given list, returning only numbers that appear exactly once.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n A list containing only the numbers that appeared exactly once in the input list. The order is preserved from the original list.\n \"\"\"\n counts = {}\n for num in nums:\n counts[num] = counts.get(num, 0) + 1\n\n unique_nums = []\n for num in nums:\n if counts[num] == 1:\n unique_nums.append(num)\n return unique_nums", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(nums):\n \"\"\"\n Removes duplicate numbers from a list, preserving order. Returns a list containing only numbers that appear exactly once in the input.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n A list of numbers that appear only once in the input list, maintaining their original order.\n\n \"\"\"\n counts = {}\n for num in nums:\n counts[num] = counts.get(num, 0) + 1\n\n unique_nums = []\n for num in nums:\n if counts[num] == 1:\n unique_nums.append(num)\n\n return unique_nums", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(nums):\n \"\"\"\n Write a python function to remove duplicate numbers from a given number of lists.\n assert two_unique_nums([1,2,3,2,3,4,5]) == [1, 4, 5]\n \"\"\"\n counts = {}\n for num in nums:\n counts[num] = counts.get(num, 0) + 1\n\n result = []\n for num, count in counts.items():\n if count == 1:\n result.append(num)\n return result", "matching_cluster_idx": 5}]}, "Mbpp/578": {"dps": 58.41269841269841, "dps_norm": 63.63636363636363, "pass@1": 100.0, "profiled": [{"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"Interleaves three lists of the same length into a single flat list.\n\n Args:\n list1: The first list.\n list2: The second list.\n list3: The third list.\n\n Returns:\n A new list containing the interleaved elements. Returns an empty list if input lists are empty or of different lengths.\n \"\"\"\n if not list1 or not list2 or not list3 or len(list1) != len(list2) or len(list1) != len(list3):\n return []\n \n interleaved_list = []\n for i in range(len(list1)):\n interleaved_list.extend([list1[i], list2[i], list3[i]])\n return interleaved_list", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"Interleaves three lists of the same length into a single list.\n\n Args:\n list1: The first list.\n list2: The second list.\n list3: The third list.\n\n Returns:\n A new list containing the interleaved elements. Returns an empty list if input lists are empty or of different lengths.\n \"\"\"\n if not list1 or not list2 or not list3 or len(list1) != len(list2) or len(list1) != len(list3):\n return []\n \n interleaved_list = []\n for i in range(len(list1)):\n interleaved_list.extend([list1[i], list2[i], list3[i]])\n return interleaved_list", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"Interleaves three lists of the same length into a single flat list.\n\n Args:\n list1: The first list.\n list2: The second list.\n list3: The third list.\n\n Returns:\n A new list containing the interleaved elements. Returns an empty list if input lists are empty or of different lengths.\n\n Raises:\n ValueError: If the input lists are not of the same length.\n \"\"\"\n if not list1 or not list2 or not list3:\n return []\n if len(list1) != len(list2) or len(list1) != len(list3):\n raise ValueError(\"Input lists must be of the same length\")\n \n interleaved_list = []\n for i in range(len(list1)):\n interleaved_list.extend([list1[i], list2[i], list3[i]])\n return interleaved_list", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"Interleaves three lists of the same length into a single list.\n\n Args:\n list1: The first list.\n list2: The second list.\n list3: The third list.\n\n Returns:\n A new list containing the interleaved elements. Returns an empty list if input lists are empty or of different lengths.\n\n Raises:\n ValueError: If the input lists are not of the same length.\n \"\"\"\n if not list1 or not list2 or not list3:\n return []\n if len(list1) != len(list2) or len(list1) != len(list3):\n raise ValueError(\"Lists must be of the same length\")\n \n interleaved_list = []\n for i in range(len(list1)):\n interleaved_list.extend([list1[i], list2[i], list3[i]])\n return interleaved_list", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"Interleaves three lists of the same length into a single flat list.\n\n Args:\n list1: The first list.\n list2: The second list.\n list3: The third list.\n\n Returns:\n A new list containing the interleaved elements. Returns an empty list if input lists are empty or of different lengths.\n\n Raises:\n ValueError: If the input lists are not of the same length.\n\n \"\"\"\n if not list1 or not list2 or not list3:\n return []\n if len(list1) != len(list2) or len(list1) != len(list3):\n raise ValueError(\"Lists must be of the same length\")\n\n interleaved_list = []\n for i in range(len(list1)):\n interleaved_list.extend([list1[i], list2[i], list3[i]])\n return interleaved_list", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"Interleaves three lists of the same length into a single flat list.\n\n Args:\n list1: The first list.\n list2: The second list.\n list3: The third list.\n\n Returns:\n A new list containing the interleaved elements. Returns an empty list if input lists are empty or of different lengths.\n\n Raises:\n ValueError: If the input lists are not of the same length.\n \"\"\"\n if not list1 or not list2 or not list3:\n return []\n if len(list1) != len(list2) or len(list1) != len(list3):\n raise ValueError(\"Input lists must be of the same length.\")\n\n interleaved_list = []\n for i in range(len(list1)):\n interleaved_list.extend([list1[i], list2[i], list3[i]])\n return interleaved_list", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"Interleaves three lists of the same length into a single flat list.\n\n Args:\n list1: The first list.\n list2: The second list.\n list3: The third list.\n\n Returns:\n A new list containing the interleaved elements. Returns an empty list if input lists are empty or of different lengths.\n\n Raises:\n ValueError: If the input lists are not of the same length.\n \"\"\"\n if not list1 or not list2 or not list3:\n return []\n if len(list1) != len(list2) or len(list1) != len(list3):\n raise ValueError(\"Lists must be of the same length.\")\n\n interleaved_list = []\n for i in range(len(list1)):\n interleaved_list.extend([list1[i], list2[i], list3[i]])\n return interleaved_list", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"Interleaves three lists of the same length into a single flat list.\n\n Args:\n list1: The first list.\n list2: The second list.\n list3: The third list.\n\n Returns:\n A new list containing the interleaved elements. Returns an empty list if input lists are empty or of different lengths.\n\n Raises:\n ValueError: if input lists are not of the same length.\n\n \"\"\"\n if not list1 or not list2 or not list3:\n return []\n if len(list1) != len(list2) or len(list1) != len(list3):\n raise ValueError(\"Lists must be of the same length\")\n\n interleaved_list = []\n for i in range(len(list1)):\n interleaved_list.extend([list1[i], list2[i], list3[i]])\n return interleaved_list", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"Interleaves three lists of the same length into a single flat list.\n\n Args:\n list1: The first list.\n list2: The second list.\n list3: The third list.\n\n Returns:\n A new list containing the interleaved elements of the input lists.\n Returns an empty list if any input list is empty or they are not of the same length.\n\n Raises:\n ValueError: If the input lists are not of the same length.\n \"\"\"\n if not list1 or not list2 or not list3 or len(list1) != len(list2) or len(list1) != len(list3):\n return []\n \n interleaved_list = []\n for i in range(len(list1)):\n interleaved_list.extend([list1[i], list2[i], list3[i]])\n return interleaved_list", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"Interleaves three lists of the same length into a single flat list.\n\n Args:\n list1: The first list.\n list2: The second list.\n list3: The third list.\n\n Returns:\n A new list containing the interleaved elements of the input lists.\n Returns an empty list if any input list is empty or of different length.\n\n Raises:\n ValueError: If the input lists are not of the same length.\n \"\"\"\n if not list1 or not list2 or not list3:\n return []\n if len(list1) != len(list2) or len(list1) != len(list3):\n raise ValueError(\"Input lists must be of the same length.\")\n\n interleaved_list = []\n for i in range(len(list1)):\n interleaved_list.extend([list1[i], list2[i], list3[i]])\n return interleaved_list", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"Interleaves three lists of the same length into a single list.\n\n Args:\n list1: The first list.\n list2: The second list.\n list3: The third list.\n\n Returns:\n A new list containing the interleaved elements. Returns an empty list if input lists are empty or of different lengths.\n\n Raises:\n ValueError: If the input lists are not of the same length.\n \"\"\"\n if not list1 or not list2 or not list3 or len(list1) != len(list2) or len(list1) != len(list3):\n return []\n\n interleaved_list = []\n for i in range(len(list1)):\n interleaved_list.extend([list1[i], list2[i], list3[i]])\n return interleaved_list", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"Interleaves three lists of the same length into a single list.\n\n Args:\n list1: The first list.\n list2: The second list.\n list3: The third list.\n\n Returns:\n A new list containing the interleaved elements. Returns an empty list if input lists are empty or of different lengths.\n\n Raises:\n ValueError: If the input lists are not of the same length.\n \"\"\"\n if not list1 or not list2 or not list3:\n return []\n if len(list1) != len(list2) or len(list1) != len(list3):\n raise ValueError(\"Input lists must be of the same length.\")\n\n interleaved_list = []\n for i in range(len(list1)):\n interleaved_list.extend([list1[i], list2[i], list3[i]])\n return interleaved_list", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"Interleaves three lists of the same length into a single flat list.\n\n Args:\n list1: The first list.\n list2: The second list.\n list3: The third list.\n\n Returns:\n A new list containing the interleaved elements, or None if the lists are not of equal length.\n \"\"\"\n if not (len(list1) == len(list2) == len(list3)):\n return None # Handle unequal length lists\n\n interleaved_list = []\n for i in range(len(list1)):\n interleaved_list.extend([list1[i], list2[i], list3[i]])\n return interleaved_list", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"Interleaves three lists of the same length into a single flat list.\n\n Args:\n list1: The first list.\n list2: The second list.\n list3: The third list.\n\n Returns:\n A new list containing the interleaved elements. Returns an empty list if input lists are empty or of different lengths.\n\n Raises:\n ValueError: If the input lists are not of the same length.\n \"\"\"\n if not list1 or not list2 or not list3:\n return []\n if len(list1) != len(list2) or len(list1) != len(list3):\n raise ValueError(\"Input lists must be of the same length.\")\n\n interleaved_list = []\n for i in range(len(list1)):\n interleaved_list.extend([list1[i], list2[i], list3[i]])\n return interleaved_list", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"Interleaves three lists of the same length into a single flat list.\n\n Args:\n list1: The first list.\n list2: The second list.\n list3: The third list.\n\n Returns:\n A new list containing the interleaved elements. Returns an empty list if input lists are empty or of different lengths.\n\n Raises:\n ValueError: If the input lists are not of the same length.\n \"\"\"\n if not list1 or not list2 or not list3:\n return []\n if len(list1) != len(list2) or len(list1) != len(list3):\n raise ValueError(\"Input lists must be of the same length.\")\n \n interleaved_list = []\n for i in range(len(list1)):\n interleaved_list.extend([list1[i], list2[i], list3[i]])\n return interleaved_list", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"Interleaves three lists of the same length into a single flat list.\n\n Args:\n list1: The first list.\n list2: The second list.\n list3: The third list.\n\n Returns:\n A new list containing the interleaved elements. Returns an empty list if input lists are empty or of different lengths.\n\n Raises:\n ValueError: If the input lists are not of the same length.\n \"\"\"\n if not list1 or not list2 or not list3:\n return []\n if len(list1) != len(list2) or len(list1) != len(list3):\n raise ValueError(\"Input lists must be of the same length.\")\n\n interleaved_list = []\n for i in range(len(list1)):\n interleaved_list.extend([list1[i], list2[i], list3[i]])\n return interleaved_list\nlist1 = [1, 2, 3, 4, 5, 6, 7]\nlist2 = [10, 20, 30, 40, 50, 60, 70]\nlist3 = [100, 200, 300, 400, 500, 600, 700]", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"Interleaves three lists of the same length into a single flat list.\n\n Args:\n list1: The first list.\n list2: The second list.\n list3: The third list.\n\n Returns:\n A new list containing the interleaved elements of the input lists.\n Returns an empty list if any input list is empty or they are not of the same length.\n\n Raises:\n ValueError: If the input lists are not of the same length.\n\n \"\"\"\n if not list1 or not list2 or not list3:\n return []\n if len(list1) != len(list2) or len(list1) != len(list3):\n raise ValueError(\"Input lists must be of the same length.\")\n\n interleaved_list = []\n for i in range(len(list1)):\n interleaved_list.extend([list1[i], list2[i], list3[i]])\n return interleaved_list", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"Interleaves three lists of the same length into a single flat list.\n\n Args:\n list1: The first list.\n list2: The second list.\n list3: The third list.\n\n Returns:\n A new list containing the interleaved elements. Returns an empty list if input lists are empty or of different lengths.\n\n Raises:\n ValueError: if input lists are not of the same length.\n \"\"\"\n if not list1 or not list2 or not list3:\n return []\n if len(list1) != len(list2) or len(list1) != len(list3):\n raise ValueError(\"Lists must be of the same length.\")\n\n interleaved_list = []\n for i in range(len(list1)):\n interleaved_list.extend([list1[i], list2[i], list3[i]])\n return interleaved_list", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"Interleaves three lists of the same length into a single flat list.\n\n Args:\n list1: The first list.\n list2: The second list.\n list3: The third list.\n\n Returns:\n A new list containing the interleaved elements. Returns an empty list if input lists are empty or of different lengths.\n\n Raises:\n ValueError: If the input lists are not of the same length.\n \"\"\"\n if not list1 or not list2 or not list3:\n return []\n if len(list1) != len(list2) or len(list1) != len(list3):\n raise ValueError(\"Input lists must be of the same length.\")\n\n interleaved_list = []\n for i in range(len(list1)):\n interleaved_list.extend([list1[i], list2[i], list3[i]])\n return interleaved_list\nlist1 = [1, 2, 3, 4, 5, 6, 7]\nlist2 = [10, 20, 30, 40, 50, 60, 70]\nlist3 = [100, 200, 300, 400, 500, 600, 700]", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"Interleaves three lists of the same length into a single flat list.\n\n Args:\n list1: The first list.\n list2: The second list.\n list3: The third list.\n\n Returns:\n A new list containing the interleaved elements. Returns an empty list if input lists are empty or of different lengths.\n\n Raises:\n ValueError: If the input lists are not of the same length.\n \"\"\"\n if not list1 or not list2 or not list3:\n return []\n\n if len(list1) != len(list2) or len(list1) != len(list3):\n raise ValueError(\"Input lists must be of the same length.\")\n\n interleaved_list = []\n for i in range(len(list1)):\n interleaved_list.extend([list1[i], list2[i], list3[i]])\n return interleaved_list", "matching_cluster_idx": 6}]}, "Mbpp/586": {"dps": 98.83040935672514, "dps_norm": 87.5, "pass@1": 100.0, "profiled": [{"solution": "def split_Arr(arr, n):\n \"\"\"\n Splits a list at the nth element and adds the first part to the end.\n\n Args:\n arr: The input list.\n n: The index at which to split the list (0-indexed).\n\n Returns:\n A new list with the first n elements moved to the end. Returns the original list if n is invalid.\n \"\"\"\n if not isinstance(arr, list) or n < 0 or n >= len(arr):\n return arr # Handle invalid input\n\n first_part = arr[:n]\n second_part = arr[n:]\n return second_part + first_part", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"Splits a list at the nth element and adds the first part to the end.\n\n Args:\n arr: The input list.\n n: The index at which to split the list (0-based).\n\n Returns:\n A new list with the first part added to the end. Returns the original list if n is out of bounds.\n \"\"\"\n if n < 0 or n >= len(arr):\n return arr # Handle cases where n is out of bounds\n \n first_part = arr[:n]\n second_part = arr[n:]\n return second_part + first_part", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"Splits a list at the nth element and adds the first part to the end.\n\n Args:\n arr: The input list.\n n: The index at which to split the list (0-indexed).\n\n Returns:\n A new list with the first part moved to the end. Returns the original list if n is invalid.\n\n \"\"\"\n if not isinstance(arr, list) or n < 0 or n >= len(arr):\n return arr #Handle invalid input\n\n first_part = arr[:n]\n second_part = arr[n:]\n return second_part + first_part", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"Splits a list at the nth element and adds the first part to the end.\n\n Args:\n arr: The input list.\n n: The index at which to split the list (0-indexed).\n\n Returns:\n A new list with the first part added to the end. Returns the original list if n is out of bounds.\n\n \"\"\"\n if n < 0 or n >= len(arr):\n return arr\n \n first_part = arr[:n]\n second_part = arr[n:]\n return second_part + first_part", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"Splits a list at the nth element and adds the first part to the end.\n\n Args:\n arr: The input list.\n n: The index at which to split the list (0-indexed).\n\n Returns:\n A new list with the first part appended to the end. Returns the original list if n is out of bounds.\n\n \"\"\"\n if n >= len(arr) or n < 0:\n return arr\n \n first_part = arr[:n]\n second_part = arr[n:]\n return second_part + first_part", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"Splits a list at the nth element and adds the first part to the end.\n\n Args:\n arr: The input list.\n n: The index at which to split the list (0-indexed).\n\n Returns:\n A new list with the first part moved to the end. Returns the original list if n is invalid.\n \"\"\"\n if not isinstance(arr, list) or n < 0 or n >= len(arr):\n return arr # Handle invalid input\n\n first_part = arr[:n]\n second_part = arr[n:]\n return second_part + first_part", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"Splits a list at the nth element and adds the first part to the end.\n\n Args:\n arr: The input list.\n n: The index at which to split the list (0-based).\n\n Returns:\n A new list with the first part added to the end. Returns the original list if n is out of bounds.\n\n \"\"\"\n if n < 0 or n >= len(arr):\n return arr #Handle out of bounds cases\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"\n Splits a list at the nth element and adds the first part to the end.\n\n Args:\n arr: The input list.\n n: The index at which to split the list (0-based).\n\n Returns:\n A new list with the first n elements moved to the end. Returns the original list if n is invalid.\n \"\"\"\n if not isinstance(arr, list) or n < 0 or n >= len(arr):\n return arr # Handle invalid input\n\n first_part = arr[:n]\n second_part = arr[n:]\n return second_part + first_part", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"Splits a list at the nth element and adds the first part to the end.\n\n Args:\n arr: The input list.\n n: The index at which to split the list (0-indexed).\n\n Returns:\n A new list with the first part moved to the end. Returns the original list if n is out of bounds.\n \"\"\"\n if n < 0 or n >= len(arr):\n return arr # Handle out-of-bounds index\n \n first_part = arr[:n]\n second_part = arr[n:]\n return second_part + first_part", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"Splits a list at the nth element and adds the first part to the end.\n\n Args:\n arr: The input list.\n n: The index at which to split the list (0-indexed).\n\n Returns:\n A new list with the first part added to the end. Returns the original list if n is out of bounds.\n\n \"\"\"\n if n < 0 or n >= len(arr):\n return arr # Handle out-of-bounds index\n\n first_part = arr[:n]\n second_part = arr[n:]\n return second_part + first_part", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"Splits a list at the nth element and adds the first part to the end.\n\n Args:\n arr: The input list.\n n: The index at which to split the list (0-indexed).\n\n Returns:\n A new list with the first part appended to the end. Returns the original list if n is out of bounds.\n\n \"\"\"\n if n < 0 or n >= len(arr):\n return arr # Handle out-of-bounds index\n \n first_part = arr[:n]\n second_part = arr[n:]\n return second_part + first_part", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"Splits a list at the nth element and adds the first part to the end.\n\n Args:\n arr: The input list.\n n: The index at which to split the list (0-indexed).\n\n Returns:\n A new list with the first part moved to the end. Returns the original list if n is out of bounds.\n\n \"\"\"\n if n < 0 or n >= len(arr):\n return arr # Handle out-of-bounds index\n \n first_part = arr[:n]\n second_part = arr[n:]\n return second_part + first_part", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"Splits a list at the nth element and adds the first part to the end.\n\n Args:\n arr: The input list.\n n: The index at which to split the list (0-indexed).\n\n Returns:\n A new list with the first part added to the end. Returns the original list if n is out of bounds.\n \"\"\"\n if n < 0 or n >= len(arr):\n return arr # Handle out-of-bounds index\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"Splits a list at the nth element and adds the first part to the end.\n\n Args:\n arr: The input list.\n n: The index at which to split the list (0-indexed).\n\n Returns:\n A new list with the first part moved to the end. Returns the original list if n is out of bounds.\n \"\"\"\n if not 0 <= n < len(arr):\n return arr # Handle out-of-bounds index\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"\n Splits a list at the nth element and adds the first part to the end.\n\n Args:\n arr: The input list.\n n: The index at which to split the list (0-indexed).\n\n Returns:\n A new list with the first n elements moved to the end. Returns the original list if n is out of bounds.\n \"\"\"\n if n < 0 or n >= len(arr):\n return arr #Handle cases where n is out of bounds.\n \n first_part = arr[:n]\n second_part = arr[n:]\n return second_part + first_part", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"Splits a list at the nth element and adds the first part to the end.\n\n Args:\n arr: The input list.\n n: The index at which to split the list (0-indexed).\n\n Returns:\n A new list with the first part moved to the end. Returns the original list if n is invalid.\n \"\"\"\n if not isinstance(arr, list) or not isinstance(n, int) or n < 0 or n >= len(arr):\n return arr # Handle invalid input\n\n first_part = arr[:n]\n second_part = arr[n:]\n return second_part + first_part", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"Splits a list at the nth element and adds the first part to the end.\n\n Args:\n arr: The input list.\n n: The index at which to split the list (0-indexed).\n\n Returns:\n A new list with the first part appended to the end. Returns the original list if n is out of bounds.\n\n \"\"\"\n if n < 0 or n >= len(arr):\n return arr # Handle cases where n is out of bounds\n\n first_part = arr[:n]\n second_part = arr[n:]\n return second_part + first_part", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"\n Splits a list at the nth element and adds the first part to the end.\n\n Args:\n arr: The input list.\n n: The index at which to split the list (0-indexed).\n\n Returns:\n A new list with the first n elements moved to the end. Returns the original list if n is invalid.\n \"\"\"\n if not isinstance(arr, list) or n < 0 or n >= len(arr):\n return arr # Handle invalid input\n\n first_part = arr[:n]\n second_part = arr[n:]\n return second_part + first_part", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"Splits a list at the nth element and adds the first part to the end.\n\n Args:\n arr: The input list.\n n: The index at which to split the list (0-indexed).\n\n Returns:\n A new list with the first part added to the end. Returns the original list if n is out of bounds.\n \"\"\"\n if n < 0 or n >= len(arr):\n return arr # Handle out-of-bounds index\n \n first_part = arr[:n]\n second_part = arr[n:]\n return second_part + first_part", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"Splits a list at the nth element and adds the first part to the end.\n\n Args:\n arr: The input list.\n n: The index at which to split the list (0-indexed).\n\n Returns:\n A new list with the first part appended to the end. Returns the original list if n is invalid.\n\n \"\"\"\n if not isinstance(arr, list) or n < 0 or n >= len(arr):\n return arr # Handle invalid input\n\n first_part = arr[:n]\n second_part = arr[n:]\n return second_part + first_part", "matching_cluster_idx": 6}]}, "Mbpp/587": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def list_tuple(list_in):\n \"\"\"Converts a list to a tuple.\n\n Args:\n list_in: The input list.\n\n Returns:\n A tuple containing the same elements as the input list.\n \"\"\"\n return tuple(list_in)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(input_list):\n \"\"\"Converts a list to a tuple.\n\n Args:\n input_list: The input list.\n\n Returns:\n A tuple containing the same elements as the input list.\n \"\"\"\n return tuple(input_list)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(list1):\n \"\"\"\n Write a function to convert a list to a tuple.\n assert list_tuple([5, 10, 7, 4, 15, 3])==(5, 10, 7, 4, 15, 3)\n \"\"\"\n return tuple(list1)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(list_in):\n \"\"\"Converts a list to a tuple.\n\n Args:\n list_in: The input list.\n\n Returns:\n A tuple containing the same elements as the input list.\n \"\"\"\n return tuple(list_in)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(list_input):\n \"\"\"Converts a list to a tuple.\n\n Args:\n list_input: The input list.\n\n Returns:\n A tuple containing the same elements as the input list.\n \"\"\"\n return tuple(list_input)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(input_list):\n \"\"\"\n Converts a list to a tuple.\n\n Args:\n input_list: A list of any data type.\n\n Returns:\n A tuple containing the same elements as the input list.\n \"\"\"\n return tuple(input_list)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(input_list):\n \"\"\"Converts a list to a tuple.\n\n Args:\n input_list: The input list.\n\n Returns:\n A tuple containing the same elements as the input list.\n \"\"\"\n return tuple(input_list)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(list_in):\n \"\"\"Converts a list to a tuple.\n\n Args:\n list_in: The input list.\n\n Returns:\n A tuple containing the same elements as the input list.\n \"\"\"\n return tuple(list_in)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(list_in):\n \"\"\"Converts a list to a tuple.\n\n Args:\n list_in: The input list.\n\n Returns:\n A tuple containing the same elements as the input list.\n \"\"\"\n return tuple(list_in)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(list1):\n \"\"\"Converts a list to a tuple.\n\n Args:\n list1: The input list.\n\n Returns:\n A tuple containing the same elements as the input list.\n \"\"\"\n return tuple(list1)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(list_input):\n \"\"\"Converts a list to a tuple.\n\n Args:\n list_input: The input list.\n\n Returns:\n A tuple containing the same elements as the input list.\n \"\"\"\n return tuple(list_input)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(list_in):\n \"\"\"Converts a list to a tuple.\n\n Args:\n list_in: The input list.\n\n Returns:\n A tuple containing the same elements as the input list. Returns an empty tuple if the input is not a list.\n \"\"\"\n if isinstance(list_in, list):\n return tuple(list_in)\n else:\n return ()", "matching_cluster_idx": 3}, {"solution": "def list_tuple(list_):\n \"\"\"\n Write a function to convert a list to a tuple.\n assert list_tuple([5, 10, 7, 4, 15, 3])==(5, 10, 7, 4, 15, 3)\n \"\"\"\n return tuple(list_)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(list_in):\n \"\"\"Converts a list to a tuple.\n\n Args:\n list_in: The input list.\n\n Returns:\n A tuple containing the same elements as the input list.\n \"\"\"\n return tuple(list_in)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(list_in):\n \"\"\"Converts a list to a tuple.\n\n Args:\n list_in: The input list.\n\n Returns:\n A tuple containing the same elements as the input list.\n \"\"\"\n return tuple(list_in)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(list_input):\n \"\"\"Converts a list to a tuple.\n\n Args:\n list_input: The input list.\n\n Returns:\n A tuple containing the elements of the input list.\n \"\"\"\n return tuple(list_input)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(list_in):\n \"\"\"Converts a list to a tuple.\n\n Args:\n list_in: The input list.\n\n Returns:\n A tuple containing the same elements as the input list.\n \"\"\"\n return tuple(list_in)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(list_input):\n \"\"\"Converts a list to a tuple.\n\n Args:\n list_input: The input list.\n\n Returns:\n A tuple containing the same elements as the input list.\n \"\"\"\n return tuple(list_input)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(list_in):\n \"\"\"\n Write a function to convert a list to a tuple.\n assert list_tuple([5, 10, 7, 4, 15, 3])==(5, 10, 7, 4, 15, 3)\n \"\"\"\n return tuple(list_in)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(list_input):\n \"\"\"Converts a list to a tuple.\n\n Args:\n list_input: The input list.\n\n Returns:\n A tuple containing the same elements as the input list.\n \"\"\"\n return tuple(list_input)", "matching_cluster_idx": 3}]}, "Mbpp/588": {"dps": 95.9862385321101, "dps_norm": 97.5, "pass@1": 100.0, "profiled": [{"solution": "def big_diff(nums):\n \"\"\"\n Write a python function to find the difference between largest and smallest value in a given list.\n assert big_diff([1,2,3,4]) == 3\n \"\"\"\n if not nums:\n return 0 # Handle empty list case\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n \"\"\"\n Finds the difference between the largest and smallest values in a list.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n The difference between the largest and smallest numbers in the list.\n Returns 0 if the list is empty or contains only one element. \n \"\"\"\n if not nums:\n return 0\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n \"\"\"\n Finds the difference between the largest and smallest values in a list.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n The difference between the largest and smallest numbers in the list.\n Returns 0 if the list is empty or contains only one element.\n \"\"\"\n if not nums:\n return 0\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n \"\"\"\n Finds the difference between the largest and smallest values in a list.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n The difference between the largest and smallest numbers in the list.\n Returns 0 if the list is empty or contains only one element. \n \"\"\"\n if not nums:\n return 0\n \n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n \"\"\"\n Finds the difference between the largest and smallest values in a given list.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n The difference between the largest and smallest numbers in the list. Returns 0 if the list is empty or contains only one element.\n \"\"\"\n if not nums:\n return 0\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n \"\"\"\n Finds the difference between the largest and smallest values in a list.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n The difference between the largest and smallest numbers in the list. Returns 0 if the list is empty or contains only one element.\n \"\"\"\n if not nums:\n return 0\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n \"\"\"\n Finds the difference between the largest and smallest values in a list.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n The difference between the largest and smallest numbers in the list. Returns 0 if the list is empty.\n \"\"\"\n if not nums:\n return 0\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n \"\"\"\n Finds the difference between the largest and smallest values in a list.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n The difference between the largest and smallest numbers in the list. Returns 0 if the list is empty or contains only one element.\n \"\"\"\n if not nums:\n return 0\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n \"\"\"\n Finds the difference between the largest and smallest values in a list.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n The difference between the largest and smallest numbers in the list. Returns 0 if the list is empty or contains only one element.\n\n Raises:\n TypeError: if input is not a list.\n ValueError: if the list contains non-numeric values.\n\n \"\"\"\n if not isinstance(nums, list):\n raise TypeError(\"Input must be a list.\")\n if not nums:\n return 0\n if not all(isinstance(num, (int, float)) for num in nums):\n raise ValueError(\"List must contain only numbers.\")\n\n return max(nums) - min(nums)", "matching_cluster_idx": 2}, {"solution": "def big_diff(nums):\n \"\"\"\n Finds the difference between the largest and smallest values in a list.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n The difference between the largest and smallest numbers in the list.\n Returns 0 if the list is empty or contains only one element. \n \"\"\"\n if not nums:\n return 0\n \n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n \"\"\"\n Finds the difference between the largest and smallest values in a list.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n The difference between the largest and smallest numbers in the list.\n Returns 0 if the list is empty or contains only one element.\n \"\"\"\n if not nums:\n return 0\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n \"\"\"\n Finds the difference between the largest and smallest values in a list.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n The difference between the largest and smallest numbers in the list.\n Returns 0 if the list is empty or contains only one element.\n \"\"\"\n if not nums:\n return 0\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n \"\"\"\n Finds the difference between the largest and smallest values in a list.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n The difference between the largest and smallest numbers in the list.\n Returns 0 if the list is empty or contains only one element. \n \"\"\"\n if not nums:\n return 0\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n \"\"\"\n Write a python function to find the difference between largest and smallest value in a given list.\n assert big_diff([1,2,3,4]) == 3\n \"\"\"\n if not nums:\n return 0 # Handle empty list case\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n \"\"\"\n Finds the difference between the largest and smallest values in a given list.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n The difference between the largest and smallest numbers in the list.\n Returns 0 if the list is empty or contains only one element.\n \"\"\"\n if not nums:\n return 0\n \n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n \"\"\"\n Finds the difference between the largest and smallest values in a list.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n The difference between the largest and smallest numbers in the list.\n Returns 0 if the list is empty. \n \"\"\"\n if not nums:\n return 0\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n \"\"\"\n Finds the difference between the largest and smallest values in a list.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n The difference between the largest and smallest numbers in the list.\n Returns 0 if the list is empty or contains only one element.\n \"\"\"\n if not nums:\n return 0\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n \"\"\"\n Finds the difference between the largest and smallest values in a list.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n The difference between the largest and smallest numbers in the list. Returns 0 if the list is empty.\n \"\"\"\n if not nums:\n return 0\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n \"\"\"\n Write a python function to find the difference between largest and smallest value in a given list.\n assert big_diff([1,2,3,4]) == 3\n \"\"\"\n if not nums:\n return 0 # Handle empty list case\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n \"\"\"\n Write a python function to find the difference between largest and smallest value in a given list.\n assert big_diff([1,2,3,4]) == 3\n \"\"\"\n if not nums:\n return 0 # Handle empty list case\n return max(nums) - min(nums)", "matching_cluster_idx": 5}]}, "Mbpp/592": {"dps": 56.466666666666676, "dps_norm": 51.5, "pass@1": 76.0, "profiled": [{"solution": "import math\ndef combinations(n, k):\n \"\"\"Calculates binomial coefficient C(n, k).\"\"\"\n if k < 0 or k > n:\n return 0\n if k == 0 or k == n:\n return 1\n if k > n // 2:\n k = n - k\n return math.factorial(n) // (math.factorial(k) * math.factorial(n - k))\ndef sum_Of_product(n):\n \"\"\"\n Calculates the sum of the product of consecutive binomial coefficients:\n \u03a3_{i=0}^{n-1} C(n, i) * C(n, i+1)\n \"\"\"\n total_sum = 0\n for i in range(n):\n total_sum += combinations(n, i) * combinations(n, i + 1)\n return total_sum", "matching_cluster_idx": 2}, {"solution": "import math\ndef combinations(n, k):\n \"\"\"\n Calculates the binomial coefficient C(n, k) using the formula n! / (k! * (n-k)!)\n \"\"\"\n if k < 0 or k > n:\n return 0\n if k == 0 or k == n:\n return 1\n if k > n // 2:\n k = n - k\n return math.factorial(n) // (math.factorial(k) * math.factorial(n - k))\ndef sum_Of_product(n):\n \"\"\"\n Calculates the sum of the product of consecutive binomial coefficients.\n\n Args:\n n: An integer representing the upper limit of the binomial coefficients.\n\n Returns:\n An integer representing the sum of the product of consecutive binomial coefficients.\n \"\"\"\n total_sum = 0\n for i in range(n):\n total_sum += combinations(n, i) * combinations(n, i + 1)\n return total_sum", "matching_cluster_idx": 2}, {"solution": "import math\ndef ncr(n, r):\n \"\"\"Calculates binomial coefficient nCr.\"\"\"\n if r > n or r < 0:\n return 0\n return math.comb(n, r)\ndef sum_Of_product(n):\n \"\"\"Calculates the sum of the product of consecutive binomial coefficients.\"\"\"\n total_sum = 0\n for i in range(n):\n total_sum += ncr(n, i) * ncr(n, i + 1)\n return total_sum\nn = 3", "matching_cluster_idx": 5}, {"solution": "def nCr(n, r):\n \"\"\"\n Calculates the binomial coefficient nCr.\n \"\"\"\n if r > n:\n return 0\n if r * 2 > n:\n r = n - r\n res = 1\n for i in range(r):\n res = res * (n - i)\n res = res // (i + 1)\n return res\ndef sum_Of_product(n):\n \"\"\"\n Calculates the sum of the product of consecutive binomial coefficients.\n\n Args:\n n: The upper limit for the binomial coefficients (nCr where r goes from 0 to n).\n\n Returns:\n The sum of the products of consecutive binomial coefficients. Returns 0 if n is less than 1.\n \"\"\"\n if n < 1:\n return 0\n total_sum = 0\n for i in range(n):\n total_sum += nCr(n, i) * nCr(n, i + 1)\n return total_sum", "matching_cluster_idx": 4}, {"solution": "def combinations(n, k):\n \"\"\"Calculates binomial coefficient nCk using the formula n!/(k!(n-k)!)\"\"\"\n if k < 0 or k > n:\n return 0\n if k == 0 or k == n:\n return 1\n if k > n // 2:\n k = n - k\n res = 1\n for i in range(k):\n res = res * (n - i) // (i + 1)\n return res\ndef sum_Of_product(n):\n \"\"\"Calculates the sum of the product of consecutive binomial coefficients.\"\"\"\n total_sum = 0\n for i in range(n):\n total_sum += combinations(n, i) * combinations(n, i + 1)\n return total_sum", "matching_cluster_idx": 4}, {"solution": "def nCr(n, r):\n \"\"\"\n Calculates the binomial coefficient nCr using the formula n! / (r! * (n-r)!)\n \"\"\"\n if r > n:\n return 0\n if r * 2 > n:\n r = n - r\n res = 1\n for i in range(r):\n res = res * (n - i)\n res = res // (i + 1)\n return res\ndef sum_Of_product(n):\n \"\"\"\n Calculates the sum of the product of consecutive binomial coefficients:\n \u03a3 (nCr * nC(r+1)) for r = 0 to n-1.\n \"\"\"\n total_sum = 0\n for r in range(n):\n total_sum += nCr(n, r) * nCr(n, r + 1)\n return total_sum", "matching_cluster_idx": 4}, {"solution": "import math\ndef nCr(n, r):\n \"\"\"\n Calculates the binomial coefficient nCr.\n \"\"\"\n if r > n:\n return 0\n return math.comb(n, r)\ndef sum_Of_product(n):\n \"\"\"\n Calculates the sum of the product of consecutive binomial coefficients.\n \"\"\"\n total_sum = 0\n for i in range(n):\n total_sum += nCr(n, i) * nCr(n, i + 1)\n return total_sum", "matching_cluster_idx": 5}, {"solution": "def nCr(n, r):\n \"\"\"\n Calculates the binomial coefficient nCr.\n \"\"\"\n if r > n:\n return 0\n if r * 2 > n:\n r = n - r\n res = 1\n for i in range(r):\n res = res * (n - i)\n res = res // (i + 1)\n return res\ndef sum_Of_product(n):\n \"\"\"\n Calculates the sum of the product of consecutive binomial coefficients.\n \"\"\"\n total_sum = 0\n for i in range(n):\n total_sum += nCr(n, i) * nCr(n, i + 1)\n return total_sum", "matching_cluster_idx": 4}, {"solution": "def ncr(n, r):\n \"\"\"Calculates nCr (n choose r) using the formula n! / (r! * (n-r)!).\"\"\"\n if r > n or r < 0:\n return 0\n if r == 0 or r == n:\n return 1\n if r > n // 2:\n r = n - r\n res = 1\n for i in range(r):\n res = res * (n - i) // (i + 1)\n return res\ndef sum_Of_product(n):\n \"\"\"\n Calculates the sum of the product of consecutive binomial coefficients:\n \u03a3 (nCr * nC(r+1)) for r = 0 to n-1.\n \"\"\"\n total_sum = 0\n for r in range(n):\n total_sum += ncr(n, r) * ncr(n, r + 1)\n return total_sum", "matching_cluster_idx": 4}, {"solution": "import math\ndef combinations(n, k):\n \"\"\"\n Calculates the binomial coefficient C(n, k).\n \"\"\"\n if k < 0 or k > n:\n return 0\n return math.comb(n, k)\ndef sum_Of_product(n):\n \"\"\"\n Calculates the sum of the product of consecutive binomial coefficients.\n \"\"\"\n total_sum = 0\n for i in range(n):\n total_sum += combinations(n, i) * combinations(n, i + 1)\n return total_sum", "matching_cluster_idx": 5}, {"solution": "def nCr(n, r):\n \"\"\"\n Calculates the binomial coefficient nCr.\n \"\"\"\n if r > n:\n return 0\n if r * 2 > n:\n r = n - r\n if r == 0:\n return 1\n if r == 1:\n return n\n \n res = 1\n for i in range(r):\n res = res * (n - i)\n res = res // (i + 1)\n return res\ndef sum_Of_product(n):\n \"\"\"\n Calculates the sum of the product of consecutive binomial coefficients.\n \"\"\"\n total_sum = 0\n for i in range(n):\n total_sum += nCr(n, i) * nCr(n, i + 1)\n return total_sum\nn = 5", "matching_cluster_idx": 4}, {"solution": "from math import comb\ndef sum_Of_product(n):\n \"\"\"\n Calculates the sum of the product of consecutive binomial coefficients.\n\n Args:\n n: An integer representing the upper limit of the binomial coefficients.\n\n Returns:\n The sum of the products of consecutive binomial coefficients from 0 to n-1. Returns 0 if n is less than 1.\n\n \"\"\"\n if n < 1:\n return 0\n total_sum = 0\n for i in range(n):\n total_sum += comb(n, i) * comb(n, i + 1)\n return total_sum", "matching_cluster_idx": 5}, {"solution": "import math\ndef combinations(n, k):\n \"\"\"Calculates binomial coefficient C(n, k).\"\"\"\n if k < 0 or k > n:\n return 0\n return math.comb(n,k)\ndef sum_Of_product(n):\n \"\"\"\n Calculates the sum of the product of consecutive binomial coefficients:\n \u03a3_{k=0}^{n-1} C(n,k) * C(n,k+1) for n >=1\n\n Args:\n n: An integer representing the upper limit of the summation.\n\n Returns:\n The sum of the products of consecutive binomial coefficients. Returns 0 if n<1.\n \"\"\"\n if n < 1:\n return 0\n total_sum = 0\n for k in range(n):\n total_sum += combinations(n, k) * combinations(n, k + 1)\n return total_sum", "matching_cluster_idx": 5}, {"solution": "import math\ndef nCr(n, r):\n \"\"\"\n Calculates the binomial coefficient nCr.\n \"\"\"\n if r > n:\n return 0\n return math.comb(n, r)\ndef sum_Of_product(n):\n \"\"\"\n Finds the sum of the product of consecutive binomial coefficients.\n \"\"\"\n total_sum = 0\n for i in range(n):\n total_sum += nCr(n, i) * nCr(n, i + 1)\n return total_sum", "matching_cluster_idx": 5}, {"solution": "def ncr(n, r):\n \"\"\"Calculates the binomial coefficient nCr.\"\"\"\n if r > n or r < 0:\n return 0\n if r == 0 or r == n:\n return 1\n if r > n // 2:\n r = n - r\n result = 1\n for i in range(r):\n result = result * (n - i) // (i + 1)\n return result\ndef sum_Of_product(n):\n \"\"\"Calculates the sum of the product of consecutive binomial coefficients.\"\"\"\n total_sum = 0\n for i in range(n):\n total_sum += ncr(n, i) * ncr(n, i + 1)\n return total_sum", "matching_cluster_idx": 4}, {"solution": "def binomial_coefficient(n, k):\n \"\"\"Calculates the binomial coefficient (n choose k).\"\"\"\n if k < 0 or k > n:\n return 0\n if k == 0 or k == n:\n return 1\n if k > n // 2:\n k = n - k # Optimization: nCk = nC(n-k)\n res = 1\n for i in range(k):\n res = res * (n - i) // (i + 1)\n return res\ndef sum_Of_product(n):\n \"\"\"\n Calculates the sum of the product of consecutive binomial coefficients:\n \u03a3_{k=0}^{n-1} (n choose k) * (n choose k+1)\n \"\"\"\n total_sum = 0\n for k in range(n):\n total_sum += binomial_coefficient(n, k) * binomial_coefficient(n, k + 1)\n return total_sum", "matching_cluster_idx": 4}, {"solution": "import math\ndef combinations(n, k):\n \"\"\"Calculates binomial coefficient C(n, k).\"\"\"\n if k < 0 or k > n:\n return 0\n if k == 0 or k == n:\n return 1\n if k > n // 2:\n k = n - k\n return math.factorial(n) // (math.factorial(k) * math.factorial(n - k))\ndef sum_Of_product(n):\n \"\"\"\n Calculates the sum of the product of consecutive binomial coefficients:\n \u03a3_{k=0}^{n-1} C(n, k) * C(n, k+1)\n \"\"\"\n total_sum = 0\n for k in range(n):\n total_sum += combinations(n, k) * combinations(n, k + 1)\n return total_sum\nn = 5", "matching_cluster_idx": 2}, {"solution": "from math import comb\ndef sum_Of_product(n):\n \"\"\"\n Calculates the sum of the product of consecutive binomial coefficients.\n\n Args:\n n: An integer representing the upper limit for the binomial coefficients.\n\n Returns:\n The sum of the product of consecutive binomial coefficients from 0 to n-1. Returns 0 if n is less than 1.\n\n Raises:\n TypeError: if input is not an integer.\n ValueError: if input is negative.\n\n \"\"\"\n if not isinstance(n, int):\n raise TypeError(\"Input must be an integer.\")\n if n < 0:\n raise ValueError(\"Input must be non-negative.\")\n if n < 1:\n return 0\n\n total_sum = 0\n for i in range(n):\n total_sum += comb(n, i) * comb(n, i + 1)\n return total_sum", "matching_cluster_idx": 5}, {"solution": "import math\ndef combinations(n, k):\n \"\"\"Calculates the binomial coefficient C(n, k).\"\"\"\n if k < 0 or k > n:\n return 0\n return math.comb(n, k)\ndef sum_Of_product(n):\n \"\"\"Calculates the sum of the product of consecutive binomial coefficients.\"\"\"\n total_sum = 0\n for i in range(n):\n total_sum += combinations(n, i) * combinations(n, i + 1)\n return total_sum", "matching_cluster_idx": 5}, {"solution": "import math\ndef combinations(n, k):\n \"\"\"Calculates binomial coefficient C(n, k)\"\"\"\n if k < 0 or k > n:\n return 0\n return math.comb(n, k)\ndef sum_Of_product(n):\n \"\"\"\n Calculates the sum of the product of consecutive binomial coefficients:\n \u03a3_{k=0}^{n-1} C(n, k) * C(n, k+1)\n \"\"\"\n total_sum = 0\n for k in range(n):\n total_sum += combinations(n, k) * combinations(n, k + 1)\n return total_sum", "matching_cluster_idx": 5}]}, "Mbpp/597": {"dps": null, "dps_norm": null, "pass@1": 0.0, "profiled": []}, "Mbpp/604": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def reverse_words(input_string):\n \"\"\"\n Reverses the order of words in a string separated by spaces.\n\n Args:\n input_string: The input string containing words separated by spaces.\n\n Returns:\n A string with the words reversed. Returns an empty string if the input is None or empty.\n \"\"\"\n if not input_string:\n return \"\"\n words = input_string.split()\n reversed_words = words[::-1] # Efficiently reverses the list\n return \" \".join(reversed_words)", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n \"\"\"\n Reverses the order of words in a string separated by spaces.\n\n Args:\n s: The input string.\n\n Returns:\n A string with the words reversed.\n \"\"\"\n words = s.split()\n reversed_words = words[::-1] # Efficiently reverses the list\n return \" \".join(reversed_words)", "matching_cluster_idx": 4}, {"solution": "def reverse_words(input_string):\n \"\"\"\n Reverses the order of words in a string, separated by spaces.\n\n Args:\n input_string: The input string containing words separated by spaces.\n\n Returns:\n A string with the words reversed. Returns an empty string if the input is empty or None.\n\n \"\"\"\n if not input_string:\n return \"\"\n words = input_string.split()\n reversed_words = words[::-1] #Efficient way to reverse a list\n return \" \".join(reversed_words)", "matching_cluster_idx": 4}, {"solution": "def reverse_words(input_string):\n \"\"\"\n Reverses the order of words in a string separated by spaces.\n\n Args:\n input_string: The input string containing words separated by spaces.\n\n Returns:\n A string with the words reversed. Returns an empty string if the input is None or empty.\n\n \"\"\"\n if not input_string:\n return \"\"\n words = input_string.split()\n reversed_words = words[::-1] #Efficiently reverses the list\n return \" \".join(reversed_words)", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n \"\"\"\n Write a function to reverse words seperated by spaces in a given string.\n assert reverse_words(\"python program\")==(\"program python\")\n \"\"\"\n words = s.split()\n reversed_words = words[::-1] #Efficiently reverses the list\n return \" \".join(reversed_words)", "matching_cluster_idx": 4}, {"solution": "def reverse_words(input_string):\n \"\"\"Reverses the order of words in a string.\n\n Args:\n input_string: The input string containing words separated by spaces.\n\n Returns:\n A string with the words reversed. Returns an empty string if the input is empty or None.\n \"\"\"\n if not input_string:\n return \"\"\n words = input_string.split()\n reversed_words = words[::-1] # Efficiently reverses the list\n return \" \".join(reversed_words)", "matching_cluster_idx": 4}, {"solution": "def reverse_words(input_string):\n \"\"\"\n Reverses the order of words in a string separated by spaces.\n\n Args:\n input_string: The input string containing words separated by spaces.\n\n Returns:\n A string with the words reversed. Returns an empty string if the input is empty or None.\n \"\"\"\n if not input_string:\n return \"\"\n words = input_string.split()\n reversed_words = words[::-1] #Efficiently reverses the list\n return \" \".join(reversed_words)", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n \"\"\"\n Reverses the order of words in a string separated by spaces.\n\n Args:\n s: The input string.\n\n Returns:\n A string with the words reversed.\n \"\"\"\n words = s.split()\n reversed_words = words[::-1] # Efficiently reverses the list\n return \" \".join(reversed_words)", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n \"\"\"\n Reverses the order of words in a string.\n\n Args:\n s: The input string containing words separated by spaces.\n\n Returns:\n A string with the words reversed. Returns an empty string if the input is empty or None.\n\n \"\"\"\n if not s:\n return \"\"\n words = s.split()\n reversed_words = words[::-1] #Efficiently reverses the list\n return \" \".join(reversed_words)", "matching_cluster_idx": 4}, {"solution": "def reverse_words(input_string):\n \"\"\"\n Reverses the order of words in a string separated by spaces.\n\n Args:\n input_string: The input string containing words separated by spaces.\n\n Returns:\n A string with the words reversed. Returns an empty string if the input is empty or None.\n\n \"\"\"\n if not input_string:\n return \"\"\n words = input_string.split()\n reversed_words = words[::-1] # Efficiently reverses the list\n return \" \".join(reversed_words)", "matching_cluster_idx": 4}, {"solution": "def reverse_words(input_string):\n \"\"\"\n Reverses the order of words in a string separated by spaces.\n\n Args:\n input_string: The input string containing words separated by spaces.\n\n Returns:\n A string with the words reversed. Returns an empty string if the input is empty or None.\n \"\"\"\n if not input_string:\n return \"\"\n words = input_string.split()\n reversed_words = words[::-1] #Efficiently reverses the list\n return \" \".join(reversed_words)", "matching_cluster_idx": 4}, {"solution": "def reverse_words(input_string):\n \"\"\"Reverses the order of words in a string.\n\n Args:\n input_string: The input string containing words separated by spaces.\n\n Returns:\n A string with the words reversed. Returns an empty string if the input is empty or None.\n \"\"\"\n if not input_string:\n return \"\"\n words = input_string.split()\n reversed_words = words[::-1] #Efficiently reverses the list\n return \" \".join(reversed_words)", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n \"\"\"\n Reverses the order of words in a string separated by spaces.\n\n Args:\n s: The input string.\n\n Returns:\n The string with words reversed. Returns an empty string if input is empty or None.\n \"\"\"\n if not s:\n return \"\"\n words = s.split()\n reversed_words = words[::-1]\n return \" \".join(reversed_words)", "matching_cluster_idx": 4}, {"solution": "def reverse_words(input_string):\n \"\"\"\n Reverses the order of words in a string, separated by spaces.\n\n Args:\n input_string: The input string containing words separated by spaces.\n\n Returns:\n A string with the words reversed. Returns an empty string if the input is None or empty.\n \"\"\"\n if not input_string:\n return \"\"\n words = input_string.split()\n reversed_words = words[::-1] # Efficiently reverses the list\n return \" \".join(reversed_words)", "matching_cluster_idx": 4}, {"solution": "def reverse_words(input_string):\n \"\"\"\n Reverses the order of words in a string separated by spaces.\n\n Args:\n input_string: The input string containing words separated by spaces.\n\n Returns:\n A string with the words reversed. Returns an empty string if the input is empty or None.\n\n \"\"\"\n if not input_string:\n return \"\"\n words = input_string.split()\n reversed_words = words[::-1] #Efficient way to reverse a list\n return \" \".join(reversed_words)", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n \"\"\"\n Reverses the order of words in a string separated by spaces.\n\n Args:\n s: The input string.\n\n Returns:\n A string with the words reversed.\n \"\"\"\n words = s.split()\n reversed_words = words[::-1] #Efficiently reverses the list\n return \" \".join(reversed_words)", "matching_cluster_idx": 4}, {"solution": "def reverse_words(input_string):\n \"\"\"\n Reverses the order of words in a string separated by spaces.\n\n Args:\n input_string: The input string containing words separated by spaces.\n\n Returns:\n A string with the words reversed. Returns an empty string if the input is empty or None.\n \"\"\"\n if not input_string:\n return \"\"\n words = input_string.split()\n reversed_words = words[::-1] #Efficiently reverses the list\n return \" \".join(reversed_words)", "matching_cluster_idx": 4}, {"solution": "def reverse_words(input_string):\n \"\"\"\n Reverses the order of words in a string separated by spaces.\n\n Args:\n input_string: The input string containing words separated by spaces.\n\n Returns:\n A string with the words reversed. Returns an empty string if the input is empty or None.\n \"\"\"\n if not input_string:\n return \"\"\n words = input_string.split()\n reversed_words = words[::-1] #Efficiently reverses the list\n return \" \".join(reversed_words)", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n \"\"\"\n Reverses the order of words in a string separated by spaces.\n\n Args:\n s: The input string.\n\n Returns:\n The string with words reversed. Returns an empty string if the input is None or empty.\n \"\"\"\n if not s:\n return \"\"\n words = s.split()\n reversed_words = words[::-1] # Efficient way to reverse a list\n return \" \".join(reversed_words)", "matching_cluster_idx": 4}, {"solution": "def reverse_words(input_string):\n \"\"\"\n Reverses the order of words in a string separated by spaces.\n\n Args:\n input_string: The input string containing words separated by spaces.\n\n Returns:\n A string with the words reversed. Returns an empty string if the input is empty or None.\n \"\"\"\n if not input_string:\n return \"\"\n words = input_string.split()\n reversed_words = words[::-1] #Efficiently reverses the list\n return \" \".join(reversed_words)", "matching_cluster_idx": 4}]}, "Mbpp/610": {"dps": 58.69565217391305, "dps_norm": 57.142857142857146, "pass@1": 62.0, "profiled": [{"solution": "def remove_kth_element(lst, k):\n \"\"\"Removes the k-th element from a list (1-based index).\n\n Args:\n lst: The input list.\n k: The index of the element to remove (1-based).\n\n Returns:\n A new list with the k-th element removed. Returns the original list if k is invalid.\n \"\"\"\n if not 1 <= k <= len(lst):\n return lst # Handle invalid k\n return lst[:k-1] + lst[k:]", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(input_list, k):\n \"\"\"\n Removes the k'th element from a list (k is 1-indexed).\n\n Args:\n input_list: The input list.\n k: The index of the element to remove (1-indexed).\n\n Returns:\n A new list with the k'th element removed. Returns the original list if k is invalid.\n \"\"\"\n if not 1 <= k <= len(input_list):\n return input_list # Handle invalid k\n\n return input_list[:k-1] + input_list[k:]", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(input_list, k):\n \"\"\"\n Removes the k'th element from a list (1-indexed).\n\n Args:\n input_list: The input list.\n k: The index of the element to remove (1-indexed).\n\n Returns:\n A new list with the k'th element removed. Returns the original list if k is invalid.\n \"\"\"\n if not isinstance(input_list, list) or not isinstance(k, int) or k <= 0 or k > len(input_list):\n return input_list # Handle invalid input\n\n return input_list[:k-1] + input_list[k:]", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(input_list, k):\n \"\"\"\n Removes the k-th element from a list (1-based index).\n\n Args:\n input_list: The input list.\n k: The index of the element to remove (1-based index).\n\n Returns:\n A new list with the k-th element removed. Returns the original list if k is invalid.\n\n \"\"\"\n if not isinstance(input_list, list) or k <= 0 or k > len(input_list):\n return input_list # Handle invalid input\n\n return input_list[:k-1] + input_list[k:]", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(input_list, k):\n \"\"\"\n Removes the k-th element from a list (1-indexed).\n\n Args:\n input_list: The input list.\n k: The index of the element to remove (1-based index).\n\n Returns:\n A new list with the k-th element removed. Returns the original list if k is out of bounds.\n \"\"\"\n if not 1 <= k <= len(input_list):\n return input_list # Handle out-of-bounds k\n return input_list[:k-1] + input_list[k:]\nk = 3", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(list_in, k):\n \"\"\"\n Removes the k'th element from a list (using 1-based indexing).\n\n Args:\n list_in: The input list.\n k: The index of the element to remove (1-based).\n\n Returns:\n A new list with the k'th element removed. Returns the original list if k is invalid.\n \"\"\"\n try:\n return list_in[:k-1] + list_in[k:]\n except IndexError:\n return list_in", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(input_list, k):\n \"\"\"Removes the k-th element from a list (1-indexed).\n\n Args:\n input_list: The input list.\n k: The index of the element to remove (1-indexed).\n\n Returns:\n A new list with the k-th element removed. Returns the original list if k is invalid.\n\n \"\"\"\n if not 1 <= k <= len(input_list):\n return input_list # Handle invalid k\n\n return input_list[:k-1] + input_list[k:]", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(input_list, k):\n \"\"\"\n Removes the k'th element from a list (1-indexed).\n\n Args:\n input_list: The input list.\n k: The index of the element to remove (1-indexed).\n\n Returns:\n A new list with the k'th element removed. Returns the original list if k is out of bounds.\n\n \"\"\"\n if not 1 <= k <= len(input_list):\n return input_list #Handle out-of-bounds k\n return input_list[:k-1] + input_list[k:]", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(data, k):\n \"\"\"Removes the k-th element from a list.\n\n Args:\n data: The input list.\n k: The index of the element to remove (0-indexed).\n\n Returns:\n A new list with the k-th element removed. Returns the original list if k is out of bounds.\n \"\"\"\n try:\n return data[:k-1] + data[k:] #Efficiently creates a new list without the k-th element.\n except IndexError:\n return data", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(lst, k):\n \"\"\"\n Removes the k-th element from a list (1-indexed).\n\n Args:\n lst: The input list.\n k: The index of the element to remove (1-based index).\n\n Returns:\n A new list with the k-th element removed. Returns the original list if k is out of bounds.\n \"\"\"\n if not 1 <= k <= len(lst):\n return lst # Handle out-of-bounds k\n return lst[:k-1] + lst[k:]", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(input_list, k):\n \"\"\"Removes the k-th element from a list (1-indexed).\n\n Args:\n input_list: The input list.\n k: The index of the element to remove (1-based index).\n\n Returns:\n A new list with the k-th element removed. Returns the original list if k is out of bounds.\n \"\"\"\n if not 1 <= k <= len(input_list):\n return input_list #Handle out of bounds k\n return input_list[:k-1] + input_list[k:]", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(input_list, k):\n \"\"\"\n Removes the k-th element from a list (1-based indexing).\n\n Args:\n input_list: The input list.\n k: The index of the element to remove (1-based).\n\n Returns:\n A new list with the k-th element removed. Returns the original list if k is invalid.\n \"\"\"\n if not isinstance(input_list, list) or not isinstance(k, int) or k <= 0 or k > len(input_list):\n return input_list # Handle invalid input\n\n return input_list[:k-1] + input_list[k:]", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(input_list, k):\n \"\"\"\n Removes the k-th element from a list (1-based index).\n\n Args:\n input_list: The input list.\n k: The index of the element to remove (1-based).\n\n Returns:\n A new list with the k-th element removed. Returns the original list if k is invalid.\n \"\"\"\n try:\n #Adjust k to be 0-based index\n k -=1\n if k < 0 or k >= len(input_list):\n return input_list # Handle out-of-bounds index\n return input_list[:k] + input_list[k+1:]\n except TypeError:\n return input_list #Handle cases where k is not an integer", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(input_list, k):\n \"\"\"\n Removes the k-th element from a list (1-indexed).\n\n Args:\n input_list: The input list.\n k: The index of the element to remove (1-indexed).\n\n Returns:\n A new list with the k-th element removed. Returns the original list if k is invalid.\n \"\"\"\n if not isinstance(input_list, list) or not isinstance(k, int) or k <= 0 or k > len(input_list):\n return input_list\n return input_list[:k-1] + input_list[k:]", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(input_list, k):\n \"\"\"\n Removes the k-th element from a list (1-indexed).\n\n Args:\n input_list: The input list.\n k: The index of the element to remove (1-indexed).\n\n Returns:\n A new list with the k-th element removed. Returns the original list if k is invalid.\n\n \"\"\"\n if not 1 <= k <= len(input_list):\n return input_list # Handle invalid k\n return input_list[:k-1] + input_list[k:]", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(list_in, k):\n \"\"\"Removes the k-th element from a list (1-based index).\n\n Args:\n list_in: The input list.\n k: The index of the element to remove (1-based index).\n\n Returns:\n A new list with the k-th element removed. Returns the original list if k is out of bounds.\n\n \"\"\"\n if not 1 <= k <= len(list_in):\n return list_in #Handle out-of-bounds index\n return list_in[:k-1] + list_in[k:]", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(input_list, k):\n \"\"\"\n Removes the k-th element from a list (1-based index).\n\n Args:\n input_list: The input list.\n k: The index of the element to remove (1-based index).\n\n Returns:\n A new list with the k-th element removed. Returns the original list if k is out of bounds.\n \"\"\"\n if not 1 <= k <= len(input_list):\n return input_list # Handle out-of-bounds k\n return input_list[:k-1] + input_list[k:]", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(list_in, k):\n \"\"\"\n Write a python function which takes a list and returns a list with the same elements, but the k'th element removed.\n assert remove_kth_element([1,1,2,3,4,4,5,1],3)==[1, 1, 3, 4, 4, 5, 1]\n \"\"\"\n if not isinstance(list_in, list):\n raise TypeError(\"Input must be a list.\")\n if not isinstance(k, int) or k <=0 or k > len(list_in):\n raise ValueError(\"k must be a positive integer less than or equal to the length of the list.\")\n\n return list_in[:k-1] + list_in[k:]", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(lst, k):\n \"\"\"\n Removes the k'th element from a list (using 1-based indexing).\n\n Args:\n lst: The input list.\n k: The index of the element to remove (1-based).\n\n Returns:\n A new list with the k'th element removed. Returns the original list if k is invalid.\n \"\"\"\n if not 1 <= k <= len(lst):\n return lst # Handle invalid k\n return lst[:k-1] + lst[k:]", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(input_list, k):\n \"\"\"\n Removes the k-th element from a list (using 1-based indexing).\n\n Args:\n input_list: The input list.\n k: The index of the element to remove (1-based indexing).\n\n Returns:\n A new list with the k-th element removed. Returns the original list if k is invalid.\n \"\"\"\n if not 1 <= k <= len(input_list):\n return input_list #Handle invalid k\n return input_list[:k-1] + input_list[k:]", "matching_cluster_idx": 3}]}, "Mbpp/611": {"dps": null, "dps_norm": null, "pass@1": 5.0, "profiled": []}, "Mbpp/631": {"dps": 43.74999999999999, "dps_norm": 36.875, "pass@1": 80.0, "profiled": [{"solution": "def replace_spaces(input_string):\n \"\"\"\n Replaces whitespaces with underscores and vice versa in a given string.\n\n Args:\n input_string: The input string.\n\n Returns:\n The string with whitespaces replaced by underscores and vice versa.\n \"\"\"\n result = \"\"\n for char in input_string:\n if char == ' ':\n result += '_'\n elif char == '_':\n result += ' '\n else:\n result += char\n return result", "matching_cluster_idx": 2}, {"solution": "def replace_spaces(input_string):\n \"\"\"Replaces whitespaces with underscores and vice versa in a string.\n\n Args:\n input_string: The input string.\n\n Returns:\n The string with spaces and underscores replaced.\n \"\"\"\n result = \"\"\n for char in input_string:\n if char == \" \":\n result += \"_\"\n elif char == \"_\":\n result += \" \"\n else:\n result += char\n return result", "matching_cluster_idx": 2}, {"solution": "def replace_spaces(input_string):\n \"\"\"Replaces spaces with underscores and vice versa in a string.\n\n Args:\n input_string: The input string.\n\n Returns:\n The string with spaces and underscores replaced.\n \"\"\"\n output_string = \"\"\n for char in input_string:\n if char == \" \":\n output_string += \"_\"\n elif char == \"_\":\n output_string += \" \"\n else:\n output_string += char\n return output_string", "matching_cluster_idx": 2}, {"solution": "def replace_spaces(input_string):\n \"\"\"\n Replaces spaces with underscores and vice versa in a given string.\n\n Args:\n input_string: The input string.\n\n Returns:\n The string with spaces replaced by underscores and vice versa.\n \"\"\"\n output_string = \"\"\n for char in input_string:\n if char == ' ':\n output_string += '_'\n elif char == '_':\n output_string += ' '\n else:\n output_string += char\n return output_string", "matching_cluster_idx": 2}, {"solution": "def replace_spaces(input_string):\n \"\"\"Replaces spaces with underscores and vice-versa in a string.\n\n Args:\n input_string: The input string.\n\n Returns:\n The string with spaces and underscores replaced.\n \"\"\"\n output_string = \"\"\n for char in input_string:\n if char == \" \":\n output_string += \"_\"\n elif char == \"_\":\n output_string += \" \"\n else:\n output_string += char\n return output_string", "matching_cluster_idx": 2}, {"solution": "def replace_spaces(input_string):\n \"\"\"Replaces spaces with underscores and vice versa in a string.\n\n Args:\n input_string: The input string.\n\n Returns:\n The string with spaces and underscores replaced.\n \"\"\"\n output_string = \"\"\n for char in input_string:\n if char == \" \":\n output_string += \"_\"\n elif char == \"_\":\n output_string += \" \"\n else:\n output_string += char\n return output_string", "matching_cluster_idx": 2}, {"solution": "def replace_spaces(input_string):\n \"\"\"\n Replaces spaces with underscores and vice versa in a given string.\n\n Args:\n input_string: The input string.\n\n Returns:\n The string with spaces replaced by underscores and vice versa.\n \"\"\"\n result = \"\"\n for char in input_string:\n if char == \" \":\n result += \"_\"\n elif char == \"_\":\n result += \" \"\n else:\n result += char\n return result", "matching_cluster_idx": 2}, {"solution": "def replace_spaces(input_string):\n \"\"\"Replaces spaces with underscores and vice versa in a string.\n\n Args:\n input_string: The input string.\n\n Returns:\n The string with spaces and underscores replaced.\n \"\"\"\n output_string = \"\"\n for char in input_string:\n if char == ' ':\n output_string += '_'\n elif char == '_':\n output_string += ' '\n else:\n output_string += char\n return output_string", "matching_cluster_idx": 2}, {"solution": "def replace_spaces(input_string):\n \"\"\"\n Replaces whitespaces with underscores and vice versa in a given string.\n\n Args:\n input_string: The input string.\n\n Returns:\n The string with whitespaces and underscores replaced.\n \"\"\"\n output_string = \"\"\n for char in input_string:\n if char == ' ':\n output_string += '_'\n elif char == '_':\n output_string += ' '\n else:\n output_string += char\n return output_string", "matching_cluster_idx": 2}, {"solution": "def replace_spaces(input_string):\n \"\"\"Replaces whitespaces with underscores and vice versa in a given string.\n\n Args:\n input_string: The input string.\n\n Returns:\n The string with whitespaces replaced by underscores and vice versa.\n \"\"\"\n output_string = \"\"\n for char in input_string:\n if char == \" \":\n output_string += \"_\"\n elif char == \"_\":\n output_string += \" \"\n else:\n output_string += char\n return output_string", "matching_cluster_idx": 2}, {"solution": "def replace_spaces(input_string):\n \"\"\"Replaces spaces with underscores and vice-versa in a string.\n\n Args:\n input_string: The input string.\n\n Returns:\n The string with spaces and underscores replaced.\n \"\"\"\n \n output_string = \"\"\n for char in input_string:\n if char == \" \":\n output_string += \"_\"\n elif char == \"_\":\n output_string += \" \"\n else:\n output_string += char\n return output_string", "matching_cluster_idx": 2}, {"solution": "def replace_spaces(input_string):\n \"\"\"\n Replaces whitespaces with underscores and vice versa in a given string.\n\n Args:\n input_string: The input string.\n\n Returns:\n The string with whitespaces and underscores replaced.\n \"\"\"\n output_string = \"\"\n for char in input_string:\n if char == \" \":\n output_string += \"_\"\n elif char == \"_\":\n output_string += \" \"\n else:\n output_string += char\n return output_string", "matching_cluster_idx": 2}, {"solution": "def replace_spaces(input_string):\n \"\"\"Replaces whitespaces with underscores and vice versa in a given string.\n\n Args:\n input_string: The input string.\n\n Returns:\n The string with whitespaces and underscores replaced.\n \"\"\"\n result = \"\"\n for char in input_string:\n if char == ' ':\n result += '_'\n elif char == '_':\n result += ' '\n else:\n result += char\n return result", "matching_cluster_idx": 2}, {"solution": "def replace_spaces(input_string):\n \"\"\"\n Replaces whitespaces with underscores and vice versa in a given string.\n\n Args:\n input_string: The input string.\n\n Returns:\n The string with whitespaces replaced by underscores and vice versa.\n \"\"\"\n result = \"\"\n for char in input_string:\n if char == ' ':\n result += '_'\n elif char == '_':\n result += ' '\n else:\n result += char\n return result", "matching_cluster_idx": 2}, {"solution": "def replace_spaces(input_string):\n \"\"\"Replaces whitespaces with underscores and vice versa in a string.\n\n Args:\n input_string: The input string.\n\n Returns:\n The string with whitespaces and underscores replaced.\n \"\"\"\n output_string = \"\"\n for char in input_string:\n if char == \" \":\n output_string += \"_\"\n elif char == \"_\":\n output_string += \" \"\n else:\n output_string += char\n return output_string", "matching_cluster_idx": 2}, {"solution": "def replace_spaces(input_string):\n \"\"\"Replaces spaces with underscores and vice versa in a string.\n\n Args:\n input_string: The input string.\n\n Returns:\n The string with spaces and underscores replaced.\n \"\"\"\n output_string = \"\"\n for char in input_string:\n if char == ' ':\n output_string += '_'\n elif char == '_':\n output_string += ' '\n else:\n output_string += char\n return output_string", "matching_cluster_idx": 2}, {"solution": "def replace_spaces(input_string):\n \"\"\"\n Replaces spaces with underscores and vice versa in a given string.\n\n Args:\n input_string: The input string.\n\n Returns:\n The string with spaces replaced by underscores and vice versa.\n \"\"\"\n result = \"\"\n for char in input_string:\n if char == ' ':\n result += '_'\n elif char == '_':\n result += ' '\n else:\n result += char\n return result", "matching_cluster_idx": 2}, {"solution": "def replace_spaces(input_string):\n \"\"\"Replaces spaces with underscores and vice versa in a string.\n\n Args:\n input_string: The input string.\n\n Returns:\n The string with spaces replaced by underscores and vice versa.\n \"\"\"\n \n output_string = \"\"\n for char in input_string:\n if char == \" \":\n output_string += \"_\"\n elif char == \"_\":\n output_string += \" \"\n else:\n output_string += char\n return output_string", "matching_cluster_idx": 2}, {"solution": "def replace_spaces(input_string):\n \"\"\"\n Replaces spaces with underscores and vice-versa in a given string.\n\n Args:\n input_string: The input string.\n\n Returns:\n The string with spaces and underscores replaced.\n \"\"\"\n output_string = \"\"\n for char in input_string:\n if char == ' ':\n output_string += '_'\n elif char == '_':\n output_string += ' '\n else:\n output_string += char\n return output_string", "matching_cluster_idx": 2}, {"solution": "def replace_spaces(input_string):\n \"\"\"Replaces spaces with underscores and vice versa in a given string.\n\n Args:\n input_string: The input string.\n\n Returns:\n The string with spaces and underscores replaced.\n \"\"\"\n output_string = \"\"\n for char in input_string:\n if char == \" \":\n output_string += \"_\"\n elif char == \"_\":\n output_string += \" \"\n else:\n output_string += char\n return output_string", "matching_cluster_idx": 1}]}, "Mbpp/632": {"dps": 95.29080675422139, "dps_norm": 99.28571428571429, "pass@1": 100.0, "profiled": [{"solution": "def move_zero(nums):\n \"\"\"\n Moves all zeroes to the end of a list while maintaining the order of other elements.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n A new list with all zeroes moved to the end.\n \"\"\"\n\n #Efficient Approach: Two Pointers\n left = 0 # Pointer for non-zero elements\n right = 0 # Pointer for iterating through the list\n\n while right < len(nums):\n if nums[right] != 0:\n nums[left], nums[right] = nums[right], nums[left] #Swap if non-zero\n left += 1\n right += 1\n return nums", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n \"\"\"\n Moves all zeroes to the end of a given list while maintaining the order of other elements.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n A new list with all zeroes moved to the end.\n \"\"\"\n non_zero_nums = [num for num in nums if num != 0]\n zero_count = nums.count(0)\n return non_zero_nums + [0] * zero_count", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n \"\"\"\n Moves all zeroes to the end of a given list while maintaining the order of other elements.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n A new list with all zeroes moved to the end.\n \"\"\"\n\n #Count the number of zeros\n zero_count = nums.count(0)\n \n #Create a new list without zeros\n non_zero_nums = [num for num in nums if num != 0]\n\n #Append zeros to the end of the new list\n non_zero_nums.extend([0] * zero_count)\n\n return non_zero_nums", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n \"\"\"\n Moves all zeroes to the end of a list while maintaining the order of other elements.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n A new list with all zeroes moved to the end.\n \"\"\"\n \n #Efficient solution using two pointers\n left = 0\n right = 0\n while right < len(nums):\n if nums[right] != 0:\n nums[left], nums[right] = nums[right], nums[left]\n left += 1\n right += 1\n return nums", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n \"\"\"\n Moves all zeroes to the end of the given list while maintaining the order of other elements.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n A new list with all zeroes moved to the end.\n \"\"\"\n\n #Efficient approach using two pointers\n left = 0\n right = 0\n while right < len(nums):\n if nums[right] != 0:\n nums[left], nums[right] = nums[right], nums[left]\n left +=1\n right += 1\n\n return nums", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n \"\"\"\n Moves all zeroes to the end of a list while preserving the order of other elements.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n A new list with all zeroes moved to the end.\n \"\"\"\n \n #Efficient approach using two pointers\n non_zero_index = 0\n for i in range(len(nums)):\n if nums[i] != 0:\n nums[non_zero_index] = nums[i]\n non_zero_index +=1\n \n #Fill the remaining elements with zeros.\n for i in range(non_zero_index, len(nums)):\n nums[i] = 0\n \n return nums", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n \"\"\"\n Moves all zeroes to the end of a list while maintaining the relative order of other elements.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n A new list with all zeroes moved to the end.\n \"\"\"\n \n #Efficient approach using two pointers\n non_zero_index = 0 #Index to track the position for next non-zero element\n for i in range(len(nums)):\n if nums[i] != 0:\n nums[non_zero_index] = nums[i]\n non_zero_index += 1\n\n #Fill the remaining elements with zeros\n for i in range(non_zero_index, len(nums)):\n nums[i] = 0\n\n return nums", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n \"\"\"\n Moves all zeroes to the end of a given list while maintaining the order of other elements.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n A new list with all zeroes moved to the end.\n \"\"\"\n \n non_zero_elements = [num for num in nums if num != 0]\n num_zeroes = nums.count(0)\n return non_zero_elements + [0] * num_zeroes", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n \"\"\"\n Moves all zeroes to the end of a given list while maintaining the relative order of other elements.\n\n Args:\n nums: A list of integers.\n\n Returns:\n A new list with all zeroes moved to the end.\n \"\"\"\n non_zero_nums = [num for num in nums if num != 0]\n zero_count = nums.count(0)\n return non_zero_nums + [0] * zero_count", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n \"\"\"\n Moves all zeroes to the end of a list while preserving the order of other elements.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n A new list with all zeroes moved to the end.\n \"\"\"\n\n #Efficient approach using two pointers\n left = 0\n right = 0\n while right < len(nums):\n if nums[right] != 0:\n nums[left], nums[right] = nums[right], nums[left]\n left +=1\n right +=1\n return nums", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n \"\"\"\n Moves all zeroes to the end of a given list while maintaining the order of other elements.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n A list with all zeroes moved to the end, preserving the order of non-zero elements.\n \"\"\"\n \n #Efficient approach using two pointers\n non_zero_index = 0\n for i in range(len(nums)):\n if nums[i] != 0:\n nums[non_zero_index] = nums[i]\n non_zero_index += 1\n\n #Fill remaining elements with zeros.\n for i in range(non_zero_index, len(nums)):\n nums[i] = 0\n \n return nums", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n \"\"\"\n Moves all zeroes to the end of a given list while preserving the order of other elements.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n A new list with all zeroes moved to the end.\n \"\"\"\n \n non_zero_elements = [num for num in nums if num != 0]\n zero_count = nums.count(0)\n return non_zero_elements + [0] * zero_count", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n \"\"\"\n Moves all zeroes to the end of a given list while maintaining the relative order of other elements.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n A new list with all zeroes moved to the end.\n \"\"\"\n\n #Efficient approach using two pointers\n non_zero_index = 0\n for i in range(len(nums)):\n if nums[i] != 0:\n nums[non_zero_index] = nums[i]\n non_zero_index += 1\n \n #Fill the remaining elements with zeros\n for i in range(non_zero_index, len(nums)):\n nums[i] = 0\n return nums", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n \"\"\"\n Write a python function to move all zeroes to the end of the given list.\n assert move_zero([1,0,2,0,3,4]) == [1,2,3,4,0,0]\n \"\"\"\n if not nums:\n return []\n\n left = 0\n right = 0\n\n while right < len(nums):\n if nums[right] != 0:\n nums[left], nums[right] = nums[right], nums[left]\n left += 1\n right += 1\n return nums", "matching_cluster_idx": 5}, {"solution": "def move_zero(nums):\n \"\"\"\n Moves all zeroes in a list to the end of the list while maintaining the relative order of other elements.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n A new list with all zeroes moved to the end.\n \"\"\"\n \n non_zero_elements = []\n zero_count = 0\n\n for num in nums:\n if num != 0:\n non_zero_elements.append(num)\n else:\n zero_count += 1\n\n return non_zero_elements + [0] * zero_count", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n \"\"\"\n Moves all zeroes to the end of a list while preserving the order of other elements.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n A new list with all zeroes moved to the end.\n \"\"\"\n\n #Efficient approach using two pointers.\n left = 0 #Pointer for non-zero elements.\n right = 0 #Pointer iterating through the list.\n\n while right < len(nums):\n if nums[right] != 0:\n nums[left], nums[right] = nums[right], nums[left] #Swap if non-zero.\n left += 1 #Increment left pointer.\n right += 1 #Always increment right pointer.\n\n return nums", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n \"\"\"\n Moves all zeroes in a list to the end while maintaining the order of other elements.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n A new list with all zeroes moved to the end.\n \"\"\"\n \n non_zero_elements = [num for num in nums if num != 0]\n num_zeros = nums.count(0)\n return non_zero_elements + [0] * num_zeros", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n \"\"\"\n Moves all zeroes to the end of a list while maintaining the order of other elements.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n A new list with all zeroes moved to the end.\n \"\"\"\n \n #Efficient approach using two pointers\n non_zero_index = 0 #Pointer for placing non-zero elements.\n for i in range(len(nums)):\n if nums[i] != 0:\n nums[non_zero_index] = nums[i]\n non_zero_index +=1\n \n #Fill remaining elements with zeros.\n for i in range(non_zero_index, len(nums)):\n nums[i] = 0\n\n return nums", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n \"\"\"\n Moves all zeroes to the end of a list while preserving the order of other elements.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n A new list with all zeroes moved to the end.\n \"\"\"\n \n non_zero_nums = [num for num in nums if num != 0]\n num_zeroes = nums.count(0)\n return non_zero_nums + [0] * num_zeroes", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n \"\"\"\n Moves all zeroes to the end of a list while maintaining the order of other elements.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n A new list with all zeroes moved to the end.\n \"\"\"\n \n non_zero_nums = [num for num in nums if num != 0]\n num_zeros = nums.count(0)\n return non_zero_nums + [0] * num_zeros", "matching_cluster_idx": 6}]}, "Mbpp/633": {"dps": 94.3089430894309, "dps_norm": 50.0, "pass@1": 53.0, "profiled": [{"solution": "def pair_xor_Sum(nums,n):\n \"\"\"\n Write a python function to find the sum of xor of all pairs of numbers in the given list.\n assert pair_xor_Sum([5,9,7,6],4) == 47\n \"\"\"\n sum_xor = 0\n for i in range(n):\n for j in range(i+1,n):\n sum_xor += nums[i]^nums[j]\n return sum_xor", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(nums, n):\n \"\"\"\n Calculates the sum of XORs of all pairs of numbers in a list.\n\n Args:\n nums: A list of integers.\n n: The length of the list (provided for clarity, though not strictly necessary).\n\n Returns:\n The sum of XORs of all pairs of numbers in the list.\n \"\"\"\n total_xor_sum = 0\n for i in range(n):\n for j in range(i + 1, n):\n total_xor_sum += nums[i] ^ nums[j]\n return total_xor_sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(nums, n):\n \"\"\"\n Calculates the sum of XORs of all pairs of numbers in a list.\n\n Args:\n nums: A list of integers.\n n: The length of the list (provided for clarity, but not strictly necessary).\n\n Returns:\n The sum of XORs of all pairs of numbers in the list.\n \"\"\"\n total_xor_sum = 0\n for i in range(n):\n for j in range(i + 1, n):\n total_xor_sum += nums[i] ^ nums[j]\n return total_xor_sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(nums, n):\n \"\"\"\n Calculates the sum of XORs of all pairs of numbers in a list.\n\n Args:\n nums: A list of integers.\n n: The length of the list (redundant, but included for consistency with problem statement).\n\n Returns:\n The sum of XORs of all pairs of numbers in the list.\n \"\"\"\n\n total_xor_sum = 0\n for i in range(n):\n for j in range(i + 1, n):\n total_xor_sum += nums[i] ^ nums[j]\n return total_xor_sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(nums,n):\n sum_xor = 0\n for i in range(n):\n for j in range(i+1,n):\n sum_xor += nums[i]^nums[j]\n return sum_xor", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(nums, n):\n \"\"\"\n Calculates the sum of XOR values for all pairs of numbers in a list.\n\n Args:\n nums: A list of integers.\n n: The length of the list (provided for clarity; not strictly necessary).\n\n Returns:\n The sum of XOR values for all pairs of numbers in the list.\n \"\"\"\n total_xor_sum = 0\n for i in range(n):\n for j in range(i + 1, n):\n total_xor_sum += nums[i] ^ nums[j]\n return total_xor_sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(nums,n):\n \"\"\"\n Write a python function to find the sum of xor of all pairs of numbers in the given list.\n assert pair_xor_Sum([5,9,7,6],4) == 47\n \"\"\"\n sum_xor = 0\n for i in range(n):\n for j in range(i+1,n):\n sum_xor += nums[i]^nums[j]\n return sum_xor", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(nums, n):\n \"\"\"\n Finds the sum of XORs of all pairs of numbers in a list.\n\n Args:\n nums: A list of integers.\n n: The length of the list (provided for clarity, not strictly necessary).\n\n Returns:\n The sum of XORs of all pairs of numbers in the list. Returns 0 for empty or single-element lists.\n \"\"\"\n if not nums or len(nums) < 2:\n return 0\n\n total_xor_sum = 0\n for i in range(n):\n for j in range(i + 1, n):\n total_xor_sum += nums[i] ^ nums[j]\n return total_xor_sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(nums, n):\n \"\"\"\n Calculates the sum of XORs of all pairs of numbers in a list.\n\n Args:\n nums: A list of integers.\n n: The length of the list (provided for clarity, not strictly necessary).\n\n Returns:\n The sum of XORs of all pairs of numbers in the list. Returns 0 for empty or single-element lists.\n\n \"\"\"\n if not nums or len(nums) < 2: #Handle empty or single-element list cases\n return 0\n\n total_xor_sum = 0\n for i in range(n):\n for j in range(i + 1, n):\n total_xor_sum += nums[i] ^ nums[j]\n return total_xor_sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(nums,n):\n \"\"\"\n This function calculates the sum of XOR of all pairs of numbers in a given list.\n\n Args:\n nums: A list of integers.\n n: The length of the list (provided for clarity, not strictly necessary).\n\n Returns:\n The sum of XORs of all pairs of numbers in the list.\n \"\"\"\n total_xor_sum = 0\n for i in range(n):\n for j in range(i + 1, n):\n total_xor_sum += nums[i] ^ nums[j]\n return total_xor_sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(nums,n):\n \"\"\"\n Write a python function to find the sum of xor of all pairs of numbers in the given list.\n assert pair_xor_Sum([5,9,7,6],4) == 47\n \"\"\"\n sum_xor = 0\n for i in range(n):\n for j in range(i+1,n):\n sum_xor += nums[i]^nums[j]\n return sum_xor", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(nums,n):\n \"\"\"\n Write a python function to find the sum of xor of all pairs of numbers in the given list.\n assert pair_xor_Sum([5,9,7,6],4) == 47\n \"\"\"\n sum_xor = 0\n for i in range(n):\n for j in range(i+1,n):\n sum_xor += nums[i]^nums[j]\n return sum_xor", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(nums,n):\n sum_xor = 0\n for i in range(n):\n for j in range(i+1,n):\n sum_xor += nums[i]^nums[j]\n return sum_xor", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(nums, n):\n \"\"\"\n Calculates the sum of XORs of all pairs of numbers in a list.\n\n Args:\n nums: A list of integers.\n n: The length of the list (provided for clarity, not strictly necessary).\n\n Returns:\n The sum of XORs of all pairs of numbers in the list. Returns 0 for empty lists.\n \"\"\"\n if not nums:\n return 0\n total_xor_sum = 0\n for i in range(n):\n for j in range(i + 1, n):\n total_xor_sum += nums[i] ^ nums[j]\n return total_xor_sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(nums, n):\n \"\"\"\n Finds the sum of XOR of all pairs of numbers in a given list.\n\n Args:\n nums: A list of integers.\n n: The length of the list (provided for clarity, not strictly necessary).\n\n Returns:\n The sum of XOR of all pairs of numbers in the list. Returns 0 for empty lists.\n\n \"\"\"\n if not nums:\n return 0\n\n total_xor_sum = 0\n for i in range(n):\n for j in range(i + 1, n):\n total_xor_sum += nums[i] ^ nums[j]\n return total_xor_sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(nums, n):\n \"\"\"\n Calculates the sum of XORs of all pairs of numbers in a list.\n\n Args:\n nums: A list of integers.\n n: The length of the list (provided for clarity, though not strictly necessary).\n\n Returns:\n The sum of XORs of all pairs of numbers in the list. Returns 0 for empty list.\n \"\"\"\n if not nums:\n return 0\n total_xor_sum = 0\n for i in range(n):\n for j in range(i + 1, n):\n total_xor_sum += nums[i] ^ nums[j]\n return total_xor_sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(nums,n):\n \"\"\"\n Write a python function to find the sum of xor of all pairs of numbers in the given list.\n assert pair_xor_Sum([5,9,7,6],4) == 47\n \"\"\"\n sum_xor = 0\n for i in range(n):\n for j in range(i+1,n):\n sum_xor += nums[i]^nums[j]\n return sum_xor", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(nums, n):\n \"\"\"\n Calculates the sum of XORs of all pairs of numbers in a list.\n\n Args:\n nums: A list of integers.\n n: The length of the list (provided for clarity, not strictly necessary).\n\n Returns:\n The sum of XORs of all pairs of numbers in the list. Returns 0 for empty or single-element lists.\n \"\"\"\n if not nums or len(nums) < 2:\n return 0\n total_xor_sum = 0\n for i in range(n):\n for j in range(i + 1, n):\n total_xor_sum += nums[i] ^ nums[j]\n return total_xor_sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(nums,n):\n \"\"\"\n Write a python function to find the sum of xor of all pairs of numbers in the given list.\n assert pair_xor_Sum([5,9,7,6],4) == 47\n \"\"\"\n sum_xor = 0\n for i in range(n):\n for j in range(i+1,n):\n sum_xor += nums[i]^nums[j]\n return sum_xor", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(nums, n):\n \"\"\"\n Calculates the sum of XORs of all pairs of numbers in a list.\n\n Args:\n nums: A list of integers.\n n: The length of the list (provided for clarity, but not strictly necessary).\n\n Returns:\n The sum of XORs of all pairs of numbers in the list.\n \"\"\"\n total_xor_sum = 0\n for i in range(n):\n for j in range(i + 1, n):\n total_xor_sum += nums[i] ^ nums[j]\n return total_xor_sum\nnums = [5, 9, 7, 6]\nn = len(nums)", "matching_cluster_idx": 2}]}, "Mbpp/644": {"dps": 73.43085106382978, "dps_norm": 75.0, "pass@1": 78.0, "profiled": [{"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n Reverses an array up to a given position k.\n\n Args:\n arr: The input array (list).\n k: The position up to which the array should be reversed (0-indexed).\n\n Returns:\n A new array with elements up to k reversed. Returns the original array if k is invalid.\n\n \"\"\"\n if not isinstance(arr, list) or k <= 0 or k > len(arr):\n return arr # Handle invalid input\n\n #Efficient reversal using slicing\n reversed_part = arr[:k][::-1]\n remaining_part = arr[k:]\n return reversed_part + remaining_part", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"Reverses an array up to a given position k.\n\n Args:\n arr: The input array.\n k: The position up to which the array should be reversed (1-based index).\n\n Returns:\n A new array with the elements up to position k reversed. Returns the original array if k is invalid.\n \"\"\"\n if not isinstance(arr, list) or k <=0 or k > len(arr):\n return arr #Handle invalid input\n\n #Efficiently reverse the first k elements using slicing\n reversed_part = arr[:k][::-1] \n \n return reversed_part + arr[k:]", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n Reverses an array up to a given position k.\n\n Args:\n arr: The input array (list).\n k: The position up to which the array should be reversed (0-indexed).\n\n Returns:\n A new array with elements up to position k reversed. Returns the original array if k is invalid.\n\n \"\"\"\n if not isinstance(arr, list) or k <= 0 or k > len(arr):\n return arr # Handle invalid input\n\n reversed_part = arr[:k][::-1] # Reverse the first k elements\n return reversed_part + arr[k:]", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n Reverses an array up to a given position k.\n\n Args:\n arr: The input array (list).\n k: The position up to which the array should be reversed (1-indexed).\n\n Returns:\n A new array with elements up to position k reversed. Returns the original array if k is out of bounds.\n\n \"\"\"\n if not isinstance(arr, list) or k <= 0 or k > len(arr):\n return arr # Handle invalid input\n\n #Reverse the portion of the array upto k\n arr[:k] = arr[:k][::-1]\n return arr", "matching_cluster_idx": 13}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"Reverses an array up to a given position k.\n\n Args:\n arr: The input array (list).\n k: The position up to which the array should be reversed (1-based index).\n\n Returns:\n A new array with elements up to position k reversed. Returns the original array if k is invalid.\n\n Raises:\n TypeError: if input array is not a list or k is not an integer.\n ValueError: if k is less than 1 or greater than the length of the array.\n\n \"\"\"\n if not isinstance(arr, list):\n raise TypeError(\"Input array must be a list.\")\n if not isinstance(k, int):\n raise TypeError(\"k must be an integer.\")\n if k < 1 or k > len(arr):\n raise ValueError(\"k must be between 1 and the length of the array.\")\n\n #Efficiently reverse the array slice\n reversed_part = arr[:k][::-1]\n #Concatenate reversed part and remaining part of the original array\n return reversed_part + arr[k:]", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"Reverses an array up to a given position k.\n\n Args:\n arr: The input array (list).\n k: The position up to which the array should be reversed (1-based index).\n\n Returns:\n A new array with the elements up to position k reversed. Returns the original array if k is out of bounds or invalid.\n\n \"\"\"\n if not isinstance(arr, list) or k <= 0 or k > len(arr):\n return arr # Handle invalid input\n\n reversed_part = arr[:k][::-1] # Reverse the portion of the array up to k\n remaining_part = arr[k:] #Get the remaining part of the array\n\n return reversed_part + remaining_part", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"Reverses an array up to a given position k.\n\n Args:\n arr: The input array.\n k: The position up to which the array should be reversed (0-indexed).\n\n Returns:\n A new array with the elements up to position k reversed. Returns the original array if k is invalid.\n\n \"\"\"\n if not isinstance(arr, list) or k <= 0 or k > len(arr):\n return arr # Handle invalid input\n\n reversed_part = arr[:k][::-1] # Reverse the first k elements\n remaining_part = arr[k:] # Keep the rest of the array as is\n\n return reversed_part + remaining_part", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"Reverses an array up to a given position k.\n\n Args:\n arr: The input array.\n k: The position up to which the array should be reversed (1-based index).\n\n Returns:\n A new array with the elements up to position k reversed. Returns the original array if k is invalid.\n \"\"\"\n if not 1 <= k <= len(arr):\n return arr #Handle invalid k\n\n return arr[:k][::-1] + arr[k:]", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"Reverses an array up to a given position k.\n\n Args:\n arr: The input array (list).\n k: The position up to which the array should be reversed (1-based index).\n\n Returns:\n A new array with the elements up to position k reversed. Returns the original array if k is invalid.\n\n \"\"\"\n if not isinstance(arr, list) or k <= 0 or k > len(arr):\n return arr #Handle invalid input\n\n reversed_part = arr[:k][::-1] #Reverse the portion of the array up to k\n remaining_part = arr[k:] #Keep the rest of the array unchanged\n\n return reversed_part + remaining_part", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"Reverses an array up to a given position k.\n\n Args:\n arr: The input array.\n k: The position up to which the array should be reversed (0-indexed).\n\n Returns:\n A new array with the elements up to position k reversed. Returns the original array if k is out of bounds.\n\n \"\"\"\n if k <= 0 or k > len(arr):\n return arr\n\n return arr[:k][::-1] + arr[k:]", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"Reverses an array up to a given position k.\n\n Args:\n arr: The input array (list).\n k: The position up to which the array should be reversed (1-indexed).\n\n Returns:\n A new array with elements up to position k reversed. Returns the original array if k is out of bounds or less than or equal to 0.\n\n \"\"\"\n if k <= 0 or k > len(arr):\n return arr\n \n reversed_part = arr[:k][::-1] # Reverse the portion up to k\n remaining_part = arr[k:] #Keep the remaining part unchanged\n return reversed_part + remaining_part", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"Reverses an array up to a given position k.\n\n Args:\n arr: The input array (list).\n k: The position up to which the array should be reversed (1-based index).\n\n Returns:\n A new array with the elements up to position k reversed. Returns the original array if k is invalid.\n\n \"\"\"\n if not isinstance(arr, list) or k <= 0 or k > len(arr):\n return arr # Handle invalid input\n\n return arr[:k][::-1] + arr[k:]", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"Reverses an array up to a given position k.\n\n Args:\n arr: The input array (list).\n k: The position up to which the array should be reversed (1-based index).\n\n Returns:\n A new array with elements up to position k reversed. Returns the original array if k is invalid.\n\n \"\"\"\n if not isinstance(arr, list) or k <=0 or k > len(arr):\n return arr #Handle invalid input\n\n return arr[:k][::-1] + arr[k:]", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"Reverses an array up to a given position k.\n\n Args:\n arr: The input array.\n k: The position up to which the array should be reversed (0-indexed).\n\n Returns:\n A new array with the elements up to position k reversed. Returns the original array if k is out of bounds.\n \"\"\"\n if k <= 0 or k > len(arr):\n return arr # Handle invalid k values\n\n reversed_part = arr[:k][::-1] # Reverse the portion up to k\n remaining_part = arr[k:] # Keep the remaining part unchanged\n\n return reversed_part + remaining_part", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"Reverses an array up to a given position k.\n\n Args:\n arr: The input array.\n k: The position up to which the array should be reversed (0-indexed).\n\n Returns:\n A new array with the elements up to position k reversed.\n Returns the original array if k is out of bounds or less than 1.\n\n \"\"\"\n if k <= 0 or k > len(arr):\n return arr\n \n return arr[:k][::-1] + arr[k:]", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"Reverses an array up to a given position k.\n\n Args:\n arr: The input array.\n k: The position up to which the array should be reversed (0-indexed).\n\n Returns:\n The array with elements up to position k reversed. Returns the original array if k is invalid.\n\n \"\"\"\n if not isinstance(arr, list) or k <= 0 or k > len(arr):\n return arr #Handle invalid input\n\n arr[:k] = arr[:k][::-1] #Reverse the slice in place\n return arr", "matching_cluster_idx": 12}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"Reverses an array up to a given position k.\n\n Args:\n arr: The input array.\n k: The position up to which the array should be reversed (0-indexed).\n\n Returns:\n A new array with the elements up to position k reversed. Returns the \n original array if k is out of bounds or less than 1.\n \"\"\"\n if k <= 0 or k > len(arr):\n return arr #Handle edge cases: k is invalid\n\n #Efficient reversal using slicing\n return arr[:k][::-1] + arr[k:]", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"Reverses an array up to a given position k.\n\n Args:\n arr: The input array.\n k: The position up to which the array should be reversed (0-indexed).\n\n Returns:\n A new array with the elements up to position k reversed. Returns the original array if k is invalid.\n\n \"\"\"\n if not isinstance(arr, list) or not 0 <= k <= len(arr):\n return arr\n\n reversed_part = arr[:k][::-1] # Reverse the portion of the array up to k\n remaining_part = arr[k:] # Keep the remaining part unchanged\n\n return reversed_part + remaining_part", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"Reverses an array up to a given position k.\n\n Args:\n arr: The input array.\n k: The position up to which the array should be reversed (1-based index).\n\n Returns:\n A new array with the elements up to position k reversed. Returns the original array if k is invalid.\n\n \"\"\"\n if not isinstance(arr, list) or k <= 0 or k > len(arr):\n return arr # Handle invalid input\n\n #Efficiently reverse using slicing\n return arr[:k][::-1] + arr[k:]", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"Reverses an array up to a given position k.\n\n Args:\n arr: The input array.\n k: The position up to which the array should be reversed (0-indexed).\n\n Returns:\n A new array with the elements up to position k reversed. Returns the original array if k is out of bounds.\n \"\"\"\n if k <= 0 or k > len(arr):\n return arr #Handle edge cases where k is invalid\n\n reversed_part = arr[:k][::-1] #Reverse the portion of the array up to k\n remaining_part = arr[k:] #Keep the remaining part unchanged\n\n return reversed_part + remaining_part", "matching_cluster_idx": 10}]}, "Mbpp/720": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def add_dict_to_tuple(tuple_data, dict_data):\n \"\"\"Adds a dictionary to the end of a tuple.\n\n Args:\n tuple_data: The input tuple.\n dict_data: The dictionary to add.\n\n Returns:\n A new tuple with the dictionary appended. Returns the original tuple if input is invalid.\n \"\"\"\n try:\n return tuple_data + (dict_data,)\n except TypeError:\n #Handle cases where input is not a tuple or dictionary. Could raise an exception instead.\n return tuple_data", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(input_tuple, input_dict):\n \"\"\"Adds a dictionary to the end of a tuple.\n\n Args:\n input_tuple: The input tuple.\n input_dict: The dictionary to add.\n\n Returns:\n A new tuple with the dictionary appended. Returns the original tuple if input is not a tuple and dictionary\n \"\"\"\n if not isinstance(input_tuple, tuple) or not isinstance(input_dict, dict):\n return input_tuple\n\n return input_tuple + (input_dict,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(tuple_data, dict_data):\n \"\"\"Adds a dictionary to the end of a tuple.\n\n Args:\n tuple_data: The input tuple.\n dict_data: The dictionary to add.\n\n Returns:\n A new tuple with the dictionary appended. Returns the original tuple if input is invalid.\n\n \"\"\"\n if not isinstance(tuple_data, tuple) or not isinstance(dict_data, dict):\n return tuple_data #Return original tuple if input is invalid.\n\n return tuple_data + (dict_data,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(my_tuple, my_dict):\n \"\"\"Adds a dictionary to the end of a tuple.\n\n Args:\n my_tuple: The input tuple.\n my_dict: The dictionary to add.\n\n Returns:\n A new tuple with the dictionary appended. Returns the original tuple if input is invalid.\n\n \"\"\"\n if not isinstance(my_tuple, tuple) or not isinstance(my_dict, dict):\n return my_tuple #Handle invalid input\n\n return my_tuple + (my_dict,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(tuple_data, dict_data):\n \"\"\"Adds a dictionary to the end of a tuple.\n\n Args:\n tuple_data: The input tuple.\n dict_data: The dictionary to add.\n\n Returns:\n A new tuple with the dictionary appended. Returns the original tuple if input is invalid.\n \"\"\"\n if not isinstance(tuple_data, tuple) or not isinstance(dict_data, dict):\n return tuple_data #Return original tuple if input is not a tuple and dictionary\n\n return tuple_data + (dict_data,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(input_tuple, input_dict):\n \"\"\"Adds a dictionary to the end of a tuple.\n\n Args:\n input_tuple: The input tuple.\n input_dict: The dictionary to add.\n\n Returns:\n A new tuple with the dictionary appended.\n \"\"\"\n return input_tuple + (input_dict,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(tuple_data, dict_data):\n \"\"\"Adds a dictionary to the end of a tuple.\n\n Args:\n tuple_data: The input tuple.\n dict_data: The dictionary to be added.\n\n Returns:\n A new tuple with the dictionary appended.\n \"\"\"\n return tuple_data + (dict_data,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(input_tuple, input_dict):\n \"\"\"Adds a dictionary to the end of a tuple.\n\n Args:\n input_tuple: The input tuple.\n input_dict: The dictionary to add.\n\n Returns:\n A new tuple with the dictionary appended. Returns the original tuple if input_tuple is not a tuple.\n \"\"\"\n if not isinstance(input_tuple, tuple):\n return input_tuple\n return input_tuple + (input_dict,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(tuple_data, dict_data):\n \"\"\"Adds a dictionary to the end of a tuple.\n\n Args:\n tuple_data: The input tuple.\n dict_data: The dictionary to add.\n\n Returns:\n A new tuple with the dictionary appended.\n \"\"\"\n return tuple_data + (dict_data,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(tuple_data, dict_data):\n \"\"\"Adds a dictionary to the end of a tuple.\n\n Args:\n tuple_data: The input tuple.\n dict_data: The dictionary to add.\n\n Returns:\n A new tuple with the dictionary appended. Returns the original tuple if input is invalid.\n \"\"\"\n try:\n if not isinstance(tuple_data, tuple) or not isinstance(dict_data, dict):\n return tuple_data #Handle invalid inputs gracefully\n return tuple_data + (dict_data,)\n except Exception as e:\n print(f\"An error occurred: {e}\")\n return tuple_data", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(input_tuple, input_dict):\n \"\"\"Adds a dictionary to the end of a tuple.\n\n Args:\n input_tuple: The input tuple.\n input_dict: The dictionary to add.\n\n Returns:\n A new tuple with the dictionary appended.\n \"\"\"\n return input_tuple + (input_dict,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(my_tuple, my_dict):\n \"\"\"Adds a dictionary to the end of a tuple.\n\n Args:\n my_tuple: The input tuple.\n my_dict: The dictionary to add.\n\n Returns:\n A new tuple with the dictionary appended.\n \"\"\"\n return my_tuple + (my_dict,)\nmy_tuple = (4, 5, 6)\nmy_dict = {\"MSAM\": 1, \"is\": 2, \"best\": 3}", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(my_tuple, my_dict):\n \"\"\"Adds a dictionary to the end of a tuple.\n\n Args:\n my_tuple: The input tuple.\n my_dict: The dictionary to add.\n\n Returns:\n A new tuple with the dictionary appended.\n \"\"\"\n return my_tuple + (my_dict,)\nmy_tuple = (4, 5, 6)\nmy_dict = {\"MSAM\" : 1, \"is\" : 2, \"best\" : 3}", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(input_tuple, input_dict):\n \"\"\"Adds a dictionary to the end of a tuple.\n\n Args:\n input_tuple: The input tuple.\n input_dict: The dictionary to add.\n\n Returns:\n A new tuple with the dictionary appended. Returns the original tuple if input is not a tuple and a dictionary.\n\n \"\"\"\n if not isinstance(input_tuple, tuple) or not isinstance(input_dict, dict):\n return input_tuple\n\n return input_tuple + (input_dict,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(tuple_data, dict_data):\n \"\"\"Adds a dictionary to the end of a tuple.\n\n Args:\n tuple_data: The input tuple.\n dict_data: The dictionary to add.\n\n Returns:\n A new tuple with the dictionary appended. Returns the original tuple if input is invalid.\n\n \"\"\"\n try:\n return tuple_data + (dict_data,)\n except TypeError:\n return tuple_data", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(input_tuple, input_dict):\n \"\"\"Adds a dictionary to the end of a tuple.\n\n Args:\n input_tuple: The input tuple.\n input_dict: The dictionary to add.\n\n Returns:\n A new tuple with the dictionary appended. Returns the original tuple if input is not a tuple and dictionary.\n\n Raises:\n TypeError: if input_tuple is not a tuple or input_dict is not a dictionary.\n\n \"\"\"\n if not isinstance(input_tuple, tuple):\n raise TypeError(\"input_tuple must be a tuple\")\n if not isinstance(input_dict, dict):\n raise TypeError(\"input_dict must be a dictionary\")\n return input_tuple + (input_dict,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(tuple_data, dict_data):\n \"\"\"Adds a dictionary to the end of a tuple.\n\n Args:\n tuple_data: The input tuple.\n dict_data: The dictionary to add.\n\n Returns:\n A new tuple with the dictionary appended.\n \"\"\"\n return tuple_data + (dict_data,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(input_tuple, input_dict):\n \"\"\"Adds a dictionary to the end of a tuple.\n\n Args:\n input_tuple: The input tuple.\n input_dict: The dictionary to add.\n\n Returns:\n A new tuple with the dictionary appended. Returns the original tuple if input_tuple is not a tuple.\n \"\"\"\n if not isinstance(input_tuple, tuple):\n return input_tuple\n return input_tuple + (input_dict,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(my_tuple, my_dict):\n \"\"\"Adds a dictionary to the end of a tuple.\n\n Args:\n my_tuple: The input tuple.\n my_dict: The dictionary to add.\n\n Returns:\n A new tuple with the dictionary appended. Returns the original tuple if input is invalid.\n \"\"\"\n if not isinstance(my_tuple, tuple) or not isinstance(my_dict, dict):\n return my_tuple #Handle invalid input\n\n return my_tuple + (my_dict,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(tuple_data, dict_data):\n \"\"\"Adds a dictionary to the end of a tuple.\n\n Args:\n tuple_data: The input tuple.\n dict_data: The dictionary to add.\n\n Returns:\n A new tuple with the dictionary appended.\n \"\"\"\n return tuple_data + (dict_data,)", "matching_cluster_idx": 4}]}, "Mbpp/725": {"dps": 78.46994535519126, "dps_norm": 77.5, "pass@1": 100.0, "profiled": [{"solution": "import re\ndef extract_quotation(text):\n \"\"\"\n Write a function to extract values between quotation marks \" \" of the given string.\n assert extract_quotation('Cortex \"A53\" Based \"multi\" tasking \"Processor\"') == ['A53', 'multi', 'Processor']\n \"\"\"\n matches = re.findall(r'\"(.*?)\"', text)\n return matches", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(text):\n \"\"\"\n Write a function to extract values between quotation marks \" \" of the given string.\n assert extract_quotation('Cortex \"A53\" Based \"multi\" tasking \"Processor\"') == ['A53', 'multi', 'Processor']\n \"\"\"\n return re.findall(r'\"([^\"]*)\"', text)", "matching_cluster_idx": 6}, {"solution": "import re\ndef extract_quotation(text):\n \"\"\"\n Write a function to extract values between quotation marks \" \" of the given string.\n assert extract_quotation('Cortex \"A53\" Based \"multi\" tasking \"Processor\"') == ['A53', 'multi', 'Processor']\n \"\"\"\n return re.findall(r'\"(.*?)\"', text)", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(text):\n \"\"\"\n Write a function to extract values between quotation marks \" \" of the given string.\n assert extract_quotation('Cortex \"A53\" Based \"multi\" tasking \"Processor\"') == ['A53', 'multi', 'Processor']\n \"\"\"\n return re.findall(r'\"(.*?)\"', text)\ntext = 'Cortex \"A53\" Based \"multi\" tasking \"Processor\"'", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(text):\n \"\"\"\n Write a function to extract values between quotation marks \" \" of the given string.\n assert extract_quotation('Cortex \"A53\" Based \"multi\" tasking \"Processor\"') == ['A53', 'multi', 'Processor']\n \"\"\"\n return re.findall(r'\"(.*?)\"', text)\ntext = 'Cortex \"A53\" Based \"multi\" tasking \"Processor\"'", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(text):\n \"\"\"\n Write a function to extract values between quotation marks \" \" of the given string.\n assert extract_quotation('Cortex \"A53\" Based \"multi\" tasking \"Processor\"') == ['A53', 'multi', 'Processor']\n \"\"\"\n return re.findall(r'\"(.*?)\"', text)\ntext = 'Cortex \"A53\" Based \"multi\" tasking \"Processor\"'", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(text):\n \"\"\"\n Write a function to extract values between quotation marks \" \" of the given string.\n assert extract_quotation('Cortex \"A53\" Based \"multi\" tasking \"Processor\"') == ['A53', 'multi', 'Processor']\n \"\"\"\n return re.findall(r'\"(.*?)\"', text)", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(text):\n \"\"\"\n Write a function to extract values between quotation marks \" \" of the given string.\n assert extract_quotation('Cortex \"A53\" Based \"multi\" tasking \"Processor\"') == ['A53', 'multi', 'Processor']\n \"\"\"\n return re.findall(r'\"(.*?)\"', text)", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(text):\n \"\"\"\n Write a function to extract values between quotation marks \" \" of the given string.\n assert extract_quotation('Cortex \"A53\" Based \"multi\" tasking \"Processor\"') == ['A53', 'multi', 'Processor']\n \"\"\"\n return re.findall(r'\"([^\"]*)\"', text)", "matching_cluster_idx": 6}, {"solution": "import re\ndef extract_quotation(text):\n \"\"\"\n Write a function to extract values between quotation marks \" \" of the given string.\n assert extract_quotation('Cortex \"A53\" Based \"multi\" tasking \"Processor\"') == ['A53', 'multi', 'Processor']\n \"\"\"\n return re.findall(r'\"(.*?)\"', text)\ntext = 'Cortex \"A53\" Based \"multi\" tasking \"Processor\"'", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(text):\n \"\"\"\n Write a function to extract values between quotation marks \" \" of the given string.\n assert extract_quotation('Cortex \"A53\" Based \"multi\" tasking \"Processor\"') == ['A53', 'multi', 'Processor']\n \"\"\"\n matches = re.findall(r'\"(.*?)\"', text)\n return matches\ntext = 'Cortex \"A53\" Based \"multi\" tasking \"Processor\"'", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(text):\n \"\"\"\n Write a function to extract values between quotation marks \" \" of the given string.\n assert extract_quotation('Cortex \"A53\" Based \"multi\" tasking \"Processor\"') == ['A53', 'multi', 'Processor']\n \"\"\"\n return re.findall(r'\"([^\"]*)\"', text)\ntext = 'Cortex \"A53\" Based \"multi\" tasking \"Processor\"'", "matching_cluster_idx": 6}, {"solution": "import re\ndef extract_quotation(text):\n \"\"\"\n Write a function to extract values between quotation marks \" \" of the given string.\n assert extract_quotation('Cortex \"A53\" Based \"multi\" tasking \"Processor\"') == ['A53', 'multi', 'Processor']\n \"\"\"\n matches = re.findall(r'\"(.*?)\"', text)\n return matches", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(text):\n \"\"\"\n Write a function to extract values between quotation marks \" \" of the given string.\n assert extract_quotation('Cortex \"A53\" Based \"multi\" tasking \"Processor\"') == ['A53', 'multi', 'Processor']\n \"\"\"\n return re.findall(r'\"(.*?)\"', text)\ntext = 'Cortex \"A53\" Based \"multi\" tasking \"Processor\"'", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(text):\n \"\"\"\n Write a function to extract values between quotation marks \" \" of the given string.\n assert extract_quotation('Cortex \"A53\" Based \"multi\" tasking \"Processor\"') == ['A53', 'multi', 'Processor']\n \"\"\"\n return re.findall(r'\"(.*?)\"', text)", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(text):\n \"\"\"\n Write a function to extract values between quotation marks \" \" of the given string.\n assert extract_quotation('Cortex \"A53\" Based \"multi\" tasking \"Processor\"') == ['A53', 'multi', 'Processor']\n \"\"\"\n return re.findall(r'\"(.*?)\"', text)", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(text):\n \"\"\"\n Write a function to extract values between quotation marks \" \" of the given string.\n assert extract_quotation('Cortex \"A53\" Based \"multi\" tasking \"Processor\"') == ['A53', 'multi', 'Processor']\n \"\"\"\n return re.findall(r'\"(.*?)\"', text)\ntext = 'Cortex \"A53\" Based \"multi\" tasking \"Processor\"'", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(text):\n \"\"\"\n Write a function to extract values between quotation marks \" \" of the given string.\n assert extract_quotation('Cortex \"A53\" Based \"multi\" tasking \"Processor\"') == ['A53', 'multi', 'Processor']\n \"\"\"\n return re.findall(r'\"(.*?)\"', text)\ntext = 'Cortex \"A53\" Based \"multi\" tasking \"Processor\"'", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(text):\n \"\"\"\n Write a function to extract values between quotation marks \" \" of the given string.\n assert extract_quotation('Cortex \"A53\" Based \"multi\" tasking \"Processor\"') == ['A53', 'multi', 'Processor']\n \"\"\"\n return re.findall(r'\"(.*?)\"', text)", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(input_string):\n \"\"\"\n Extracts values between quotation marks \" \" of the given string.\n\n Args:\n input_string: The input string.\n\n Returns:\n A list of strings extracted from between quotation marks. Returns an empty list if no quoted strings are found.\n \"\"\"\n matches = re.findall(r'\"([^\"]*)\"', input_string)\n return matches", "matching_cluster_idx": 6}]}, "Mbpp/732": {"dps": 57.6937984496124, "dps_norm": 91.0, "pass@1": 100.0, "profiled": [{"solution": "def replace_specialchar(input_string):\n \"\"\"Replaces spaces, commas, and dots with colons in a string.\n\n Args:\n input_string: The input string.\n\n Returns:\n The string with spaces, commas, and dots replaced by colons.\n \"\"\"\n for char in [' ', ',', '.']:\n input_string = input_string.replace(char, ':')\n return input_string", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(input_string):\n \"\"\"Replaces spaces, commas, and dots with colons in a string.\n\n Args:\n input_string: The input string.\n\n Returns:\n The string with spaces, commas, and dots replaced by colons.\n \"\"\"\n \n #Using translate for efficiency\n translation_table = str.maketrans(\" ,.\", \":::\")\n return input_string.translate(translation_table)", "matching_cluster_idx": 8}, {"solution": "def replace_specialchar(input_string):\n \"\"\"Replaces spaces, commas, and dots with colons in a string.\n\n Args:\n input_string: The input string.\n\n Returns:\n The string with spaces, commas, and dots replaced by colons.\n \"\"\"\n \n #Using translate for efficiency\n translation_table = str.maketrans(\" ,.\", \":::\")\n return input_string.translate(translation_table)", "matching_cluster_idx": 8}, {"solution": "def replace_specialchar(input_string):\n \"\"\"Replaces spaces, commas, and dots with colons in a string.\n\n Args:\n input_string: The input string.\n\n Returns:\n The string with spaces, commas, and dots replaced by colons.\n \"\"\"\n \n # Using translate for efficiency\n translation_table = str.maketrans(\" ,.\", \":::\")\n return input_string.translate(translation_table)", "matching_cluster_idx": 8}, {"solution": "def replace_specialchar(input_string):\n \"\"\"Replaces spaces, commas, and dots with colons in a string.\n\n Args:\n input_string: The input string.\n\n Returns:\n The string with spaces, commas, and dots replaced by colons.\n \"\"\"\n for char in \" ,.\":\n input_string = input_string.replace(char, \":\")\n return input_string", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(input_string):\n \"\"\"Replaces spaces, commas, and dots with colons in a string.\n\n Args:\n input_string: The input string.\n\n Returns:\n The string with spaces, commas, and dots replaced by colons.\n \"\"\"\n \n return input_string.replace(\" \", \":\").replace(\",\", \":\").replace(\".\", \":\")", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(input_string):\n \"\"\"\n Replaces all occurrences of spaces, commas, or dots with a colon.\n\n Args:\n input_string: The input string.\n\n Returns:\n The string with spaces, commas, and dots replaced by colons.\n \"\"\"\n return input_string.replace(' ', ':').replace(',', ':').replace('.', ':')", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(input_string):\n \"\"\"Replaces spaces, commas, and dots with colons in a string.\n\n Args:\n input_string: The input string.\n\n Returns:\n The string with spaces, commas, and dots replaced by colons.\n \"\"\"\n \n #Using translate for efficiency\n translator = str.maketrans(\" ,.\", \":::\")\n return input_string.translate(translator)", "matching_cluster_idx": 8}, {"solution": "def replace_specialchar(input_string):\n \"\"\"Replaces spaces, commas, and dots in a string with colons.\n\n Args:\n input_string: The input string.\n\n Returns:\n The string with spaces, commas, and dots replaced by colons.\n \"\"\"\n \n #Using translate for efficiency\n translation_table = str.maketrans(\" ,.\", \":::\")\n return input_string.translate(translation_table)", "matching_cluster_idx": 8}, {"solution": "import re\ndef replace_specialchar(input_string):\n \"\"\"Replaces spaces, commas, and dots with colons in a string.\n\n Args:\n input_string: The input string.\n\n Returns:\n The string with spaces, commas, and dots replaced by colons.\n \"\"\"\n \n #Using re.sub for efficiency and readability\n return re.sub(r\"[ ,.]\", \":\", input_string)", "matching_cluster_idx": 2}, {"solution": "def replace_specialchar(input_string):\n \"\"\"\n Replaces all occurrences of spaces, commas, or dots with a colon.\n\n Args:\n input_string: The input string.\n\n Returns:\n The string with spaces, commas, and dots replaced by colons.\n \"\"\"\n \n #Using translate for efficiency\n translation_table = str.maketrans(\" ,.\", \":::\")\n return input_string.translate(translation_table)", "matching_cluster_idx": 8}, {"solution": "def replace_specialchar(input_string):\n \"\"\"Replaces spaces, commas, and dots with colons in a string.\n\n Args:\n input_string: The input string.\n\n Returns:\n The string with spaces, commas, and dots replaced by colons.\n \"\"\"\n \n #Using translate for efficiency. Creating a translation table.\n translation_table = str.maketrans(\" ,.\", \":::\")\n return input_string.translate(translation_table)", "matching_cluster_idx": 8}, {"solution": "def replace_specialchar(input_string):\n \"\"\"Replaces spaces, commas, and dots with colons in a string.\n\n Args:\n input_string: The input string.\n\n Returns:\n The string with spaces, commas, and dots replaced by colons.\n \"\"\"\n \n # Using translate for efficiency\n translation_table = str.maketrans(\" ,.\", \":::\")\n return input_string.translate(translation_table)", "matching_cluster_idx": 8}, {"solution": "def replace_specialchar(input_string):\n \"\"\"Replaces spaces, commas, and dots in a string with colons.\n\n Args:\n input_string: The input string.\n\n Returns:\n The string with spaces, commas, and dots replaced by colons.\n \"\"\"\n \n # Using translate for efficiency\n translation_table = str.maketrans(\" ,.\", \":::\")\n return input_string.translate(translation_table)", "matching_cluster_idx": 8}, {"solution": "def replace_specialchar(input_string):\n \"\"\"Replaces spaces, commas, and dots with colons in a string.\n\n Args:\n input_string: The input string.\n\n Returns:\n The string with spaces, commas, and dots replaced by colons.\n \"\"\"\n \n #Using translate for efficiency\n translation_table = str.maketrans(\" ,.\", \":::\")\n return input_string.translate(translation_table)", "matching_cluster_idx": 8}, {"solution": "def replace_specialchar(input_string):\n \"\"\"\n Replaces all occurrences of spaces, commas, or dots with a colon.\n\n Args:\n input_string: The input string.\n\n Returns:\n The string with spaces, commas, and dots replaced by colons.\n \"\"\"\n return input_string.replace(' ', ':').replace(',', ':').replace('.', ':')", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(input_string):\n \"\"\"Replaces spaces, commas, and dots with colons in a string.\n\n Args:\n input_string: The input string.\n\n Returns:\n The string with spaces, commas, and dots replaced by colons.\n \"\"\"\n for char in [' ', ',', '.']:\n input_string = input_string.replace(char, ':')\n return input_string", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(input_string):\n \"\"\"Replaces spaces, commas, and dots with colons in a string.\n\n Args:\n input_string: The input string.\n\n Returns:\n The string with spaces, commas, and dots replaced by colons.\n \"\"\"\n \n for char in [' ', ',', '.']:\n input_string = input_string.replace(char, ':')\n return input_string", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(input_string):\n \"\"\"Replaces spaces, commas, and dots with colons in a string.\n\n Args:\n input_string: The input string.\n\n Returns:\n The string with spaces, commas, and dots replaced by colons.\n \"\"\"\n \n #Using translate for efficiency\n translation_table = str.maketrans(\" ,.\", \":::\")\n return input_string.translate(translation_table)", "matching_cluster_idx": 8}, {"solution": "def replace_specialchar(input_string):\n \"\"\"Replaces spaces, commas, and dots with colons in a string.\n\n Args:\n input_string: The input string.\n\n Returns:\n The string with spaces, commas, and dots replaced by colons.\n \"\"\"\n for char in [' ', ',', '.']:\n input_string = input_string.replace(char, ':')\n return input_string", "matching_cluster_idx": 9}]}, "Mbpp/740": {"dps": 80.32727272727273, "dps_norm": 66.11111111111111, "pass@1": 100.0, "profiled": [{"solution": "def tuple_to_dict(input_tuple):\n \"\"\"Converts a tuple of even length into a dictionary where adjacent pairs form key-value pairs.\n\n Args:\n input_tuple: A tuple containing an even number of elements.\n\n Returns:\n A dictionary where adjacent elements from the input tuple are key-value pairs.\n Returns an empty dictionary if the input tuple is empty or has an odd length.\n\n Raises:\n TypeError: if input is not a tuple.\n \"\"\"\n if not isinstance(input_tuple, tuple):\n raise TypeError(\"Input must be a tuple.\")\n\n if len(input_tuple) == 0 or len(input_tuple) % 2 != 0:\n return {}\n\n result_dict = {}\n for i in range(0, len(input_tuple), 2):\n result_dict[input_tuple[i]] = input_tuple[i + 1]\n return result_dict", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(input_tuple):\n \"\"\"Converts a tuple of even length to a dictionary using adjacent pairs as key-value pairs.\n\n Args:\n input_tuple: A tuple with an even number of elements.\n\n Returns:\n A dictionary where adjacent pairs from the input tuple are key-value pairs.\n Returns an empty dictionary if the input tuple is empty or has an odd length.\n\n Raises:\n TypeError: if input is not a tuple.\n \"\"\"\n if not isinstance(input_tuple, tuple):\n raise TypeError(\"Input must be a tuple.\")\n \n if len(input_tuple) == 0 or len(input_tuple) % 2 != 0:\n return {}\n\n result_dict = {}\n for i in range(0, len(input_tuple), 2):\n result_dict[input_tuple[i]] = input_tuple[i+1]\n return result_dict", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(input_tuple):\n \"\"\"Converts a tuple of even length into a dictionary using adjacent elements as key-value pairs.\n\n Args:\n input_tuple: A tuple with an even number of elements.\n\n Returns:\n A dictionary where adjacent pairs from the tuple are key-value pairs. Returns an empty dictionary if the input is invalid.\n\n Raises:\n ValueError: If the input tuple has an odd number of elements.\n \"\"\"\n if len(input_tuple) % 2 != 0:\n raise ValueError(\"Tuple must have an even number of elements.\")\n \n result_dict = {}\n for i in range(0, len(input_tuple), 2):\n result_dict[input_tuple[i]] = input_tuple[i+1]\n return result_dict", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(input_tuple):\n \"\"\"Converts a tuple of even length to a dictionary using adjacent pairs as key-value pairs.\n\n Args:\n input_tuple: A tuple with an even number of elements.\n\n Returns:\n A dictionary where adjacent elements form key-value pairs. Returns an empty dictionary if the input is invalid.\n \"\"\"\n if len(input_tuple) % 2 != 0:\n return {} # Handle tuples with odd length\n\n result_dict = {}\n for i in range(0, len(input_tuple), 2):\n key = input_tuple[i]\n value = input_tuple[i+1]\n result_dict[key] = value\n return result_dict", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(input_tuple):\n \"\"\"Converts a tuple of even length into a dictionary where adjacent pairs are key-value pairs.\n\n Args:\n input_tuple: A tuple containing an even number of elements.\n\n Returns:\n A dictionary where adjacent pairs from the input tuple are key-value pairs. Returns an empty dictionary if the input is invalid.\n \"\"\"\n if len(input_tuple) % 2 != 0:\n return {} # Handle tuples with odd lengths\n\n result_dict = {}\n for i in range(0, len(input_tuple), 2):\n key = input_tuple[i]\n value = input_tuple[i + 1]\n result_dict[key] = value\n return result_dict", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(input_tuple):\n \"\"\"Converts a tuple of even length into a dictionary where adjacent pairs form key-value pairs.\n\n Args:\n input_tuple: A tuple with an even number of elements.\n\n Returns:\n A dictionary where adjacent pairs from the input tuple are key-value pairs.\n Returns an empty dictionary if the input tuple is empty or has an odd number of elements.\n\n Raises:\n TypeError: if input is not a tuple.\n \"\"\"\n if not isinstance(input_tuple, tuple):\n raise TypeError(\"Input must be a tuple.\")\n\n if len(input_tuple) == 0 or len(input_tuple) % 2 != 0:\n return {}\n\n result_dict = {}\n for i in range(0, len(input_tuple), 2):\n result_dict[input_tuple[i]] = input_tuple[i+1]\n return result_dict", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(input_tuple):\n \"\"\"Converts a tuple of even length into a dictionary using adjacent pairs as key-value pairs.\n\n Args:\n input_tuple: A tuple containing an even number of elements.\n\n Returns:\n A dictionary where adjacent pairs from the input tuple are key-value pairs. Returns an empty dictionary if the input is invalid.\n \"\"\"\n if len(input_tuple) % 2 != 0:\n return {} # Handle tuples with odd length\n\n result_dict = {}\n for i in range(0, len(input_tuple), 2):\n key = input_tuple[i]\n value = input_tuple[i + 1]\n result_dict[key] = value\n return result_dict", "matching_cluster_idx": 4}, {"solution": "def tuple_to_dict(input_tuple):\n \"\"\"\n Converts a tuple of even length into a dictionary where adjacent elements are key-value pairs.\n\n Args:\n input_tuple: A tuple with an even number of elements.\n\n Returns:\n A dictionary where adjacent pairs from the input tuple form key-value pairs. Returns an empty dictionary if the input is invalid.\n \"\"\"\n if len(input_tuple) % 2 != 0:\n return {} #Handle odd length tuples gracefully.\n\n result_dict = {}\n for i in range(0, len(input_tuple), 2):\n result_dict[input_tuple[i]] = input_tuple[i + 1]\n return result_dict", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(input_tuple):\n \"\"\"Converts a tuple of even length into a dictionary where adjacent elements form key-value pairs.\n\n Args:\n input_tuple: A tuple with an even number of elements.\n\n Returns:\n A dictionary with key-value pairs formed from adjacent elements in the input tuple.\n Returns an empty dictionary if the input tuple is empty or has an odd length. \n \"\"\"\n if len(input_tuple) == 0 or len(input_tuple) % 2 != 0:\n return {}\n \n result_dict = {}\n for i in range(0, len(input_tuple), 2):\n result_dict[input_tuple[i]] = input_tuple[i+1]\n return result_dict", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(input_tuple):\n \"\"\"Converts a tuple of even length to a dictionary where adjacent pairs form key-value pairs.\n\n Args:\n input_tuple: A tuple with an even number of elements.\n\n Returns:\n A dictionary where adjacent elements of the input tuple are key-value pairs. Returns an empty dictionary if the input is invalid.\n \"\"\"\n if len(input_tuple) % 2 != 0:\n return {} # Handle tuples with odd length\n\n result_dict = {}\n for i in range(0, len(input_tuple), 2):\n key = input_tuple[i]\n value = input_tuple[i + 1]\n result_dict[key] = value\n return result_dict", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(input_tuple):\n \"\"\"Converts a tuple of even length into a dictionary where adjacent elements form key-value pairs.\n\n Args:\n input_tuple: A tuple with an even number of elements.\n\n Returns:\n A dictionary where adjacent elements of the input tuple are key-value pairs. Returns an empty dictionary if the input is invalid.\n\n Raises:\n TypeError: If input is not a tuple.\n ValueError: If input tuple has an odd number of elements.\n\n \"\"\"\n if not isinstance(input_tuple, tuple):\n raise TypeError(\"Input must be a tuple.\")\n if len(input_tuple) % 2 != 0:\n raise ValueError(\"Tuple must have an even number of elements.\")\n\n result_dict = {}\n for i in range(0, len(input_tuple), 2):\n result_dict[input_tuple[i]] = input_tuple[i+1]\n return result_dict", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(input_tuple):\n \"\"\"\n Converts a tuple of even length to a dictionary where adjacent pairs form key-value pairs.\n\n Args:\n input_tuple: A tuple containing an even number of elements.\n\n Returns:\n A dictionary where adjacent elements of the input tuple are key-value pairs.\n Returns an empty dictionary if the input tuple is empty or has an odd length.\n\n \"\"\"\n if len(input_tuple) == 0 or len(input_tuple) % 2 != 0:\n return {}\n \n result_dict = {}\n for i in range(0, len(input_tuple), 2):\n result_dict[input_tuple[i]] = input_tuple[i+1]\n return result_dict", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(input_tuple):\n \"\"\"\n Converts a tuple of even length to a dictionary where adjacent elements are key-value pairs.\n\n Args:\n input_tuple: A tuple with an even number of elements.\n\n Returns:\n A dictionary with key-value pairs from the input tuple. Returns an empty dictionary if the input is invalid.\n \"\"\"\n if len(input_tuple) % 2 != 0:\n return {} #Handle odd length tuples\n\n result_dict = {}\n for i in range(0, len(input_tuple), 2):\n result_dict[input_tuple[i]] = input_tuple[i+1]\n return result_dict", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(input_tuple):\n \"\"\"Converts a tuple of even length into a dictionary using adjacent pairs as key-value pairs.\n\n Args:\n input_tuple: A tuple with an even number of elements.\n\n Returns:\n A dictionary where keys and values are taken from adjacent elements in the input tuple.\n Returns an empty dictionary if the input tuple is empty or has an odd length. \n \"\"\"\n if len(input_tuple) == 0 or len(input_tuple) % 2 != 0:\n return {}\n \n result_dict = {}\n for i in range(0, len(input_tuple), 2):\n result_dict[input_tuple[i]] = input_tuple[i+1]\n return result_dict", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(input_tuple):\n \"\"\"Converts a tuple of even length into a dictionary where adjacent elements form key-value pairs.\n\n Args:\n input_tuple: A tuple with an even number of elements.\n\n Returns:\n A dictionary where the elements at even indices are keys and the elements at odd indices are values. Returns an empty dictionary if the input is invalid.\n \"\"\"\n if len(input_tuple) % 2 != 0:\n return {} # Handle odd-length tuples\n\n result_dict = {}\n for i in range(0, len(input_tuple), 2):\n result_dict[input_tuple[i]] = input_tuple[i + 1]\n return result_dict", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(input_tuple):\n \"\"\"Converts a tuple of even length to a dictionary using adjacent pairs as key-value pairs.\n\n Args:\n input_tuple: A tuple with an even number of elements.\n\n Returns:\n A dictionary where adjacent pairs from the input tuple are key-value pairs.\n Returns an empty dictionary if the input tuple is empty or has an odd number of elements.\n\n Raises:\n TypeError: if input is not a tuple.\n \"\"\"\n if not isinstance(input_tuple, tuple):\n raise TypeError(\"Input must be a tuple.\")\n\n if len(input_tuple) % 2 != 0 or len(input_tuple) == 0:\n return {} #Handle empty or odd-length tuples\n\n result_dict = {}\n for i in range(0, len(input_tuple), 2):\n result_dict[input_tuple[i]] = input_tuple[i+1]\n return result_dict", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(input_tuple):\n \"\"\"Converts a tuple of even length into a dictionary using adjacent elements as key-value pairs.\n\n Args:\n input_tuple: A tuple with an even number of elements.\n\n Returns:\n A dictionary where adjacent pairs from the tuple are key-value pairs. Returns an empty dictionary if the input is invalid.\n\n Raises:\n ValueError: If the input tuple has an odd number of elements.\n\n \"\"\"\n if len(input_tuple) % 2 != 0:\n raise ValueError(\"Tuple must have an even number of elements.\")\n \n result_dict = {}\n for i in range(0, len(input_tuple), 2):\n result_dict[input_tuple[i]] = input_tuple[i+1]\n return result_dict", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(input_tuple):\n \"\"\"Converts a tuple of even length to a dictionary where adjacent elements form key-value pairs.\n\n Args:\n input_tuple: A tuple with an even number of elements.\n\n Returns:\n A dictionary where adjacent elements of the input tuple are key-value pairs.\n Returns an empty dictionary if the input tuple is empty or has an odd length.\n\n Raises:\n TypeError: If the input is not a tuple.\n \"\"\"\n if not isinstance(input_tuple, tuple):\n raise TypeError(\"Input must be a tuple.\")\n\n if len(input_tuple) == 0 or len(input_tuple) % 2 != 0:\n return {}\n\n result_dict = {}\n for i in range(0, len(input_tuple), 2):\n result_dict[input_tuple[i]] = input_tuple[i + 1]\n return result_dict", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(input_tuple):\n \"\"\"Converts a tuple of even length into a dictionary where adjacent elements form key-value pairs.\n\n Args:\n input_tuple: A tuple with an even number of elements.\n\n Returns:\n A dictionary where the elements at even indices are keys and the elements at odd indices are values.\n Returns an empty dictionary if the input tuple is empty or has an odd length.\n\n Raises:\n TypeError: if input is not a tuple.\n \"\"\"\n if not isinstance(input_tuple, tuple):\n raise TypeError(\"Input must be a tuple.\")\n\n if len(input_tuple) == 0 or len(input_tuple) % 2 != 0:\n return {}\n\n result_dict = {}\n for i in range(0, len(input_tuple), 2):\n result_dict[input_tuple[i]] = input_tuple[i+1]\n return result_dict", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(input_tuple):\n \"\"\"Converts a tuple of even length into a dictionary with adjacent pairs as key-value pairs.\n\n Args:\n input_tuple: A tuple with an even number of elements.\n\n Returns:\n A dictionary where adjacent elements in the tuple are key-value pairs. \n Returns an empty dictionary if the input is invalid.\n \"\"\"\n if len(input_tuple) % 2 != 0:\n return {} # Handle odd-length tuples\n\n result_dict = {}\n for i in range(0, len(input_tuple), 2):\n key = input_tuple[i]\n value = input_tuple[i + 1]\n result_dict[key] = value\n return result_dict", "matching_cluster_idx": 5}]}, "Mbpp/744": {"dps": 90.41095890410959, "dps_norm": 93.33333333333333, "pass@1": 100.0, "profiled": [{"solution": "def check_none(input_tuple):\n \"\"\"\n Checks if a tuple contains any None values.\n\n Args:\n input_tuple: The tuple to check.\n\n Returns:\n True if the tuple contains at least one None value, False otherwise.\n \"\"\"\n return None in input_tuple", "matching_cluster_idx": 5}, {"solution": "def check_none(input_tuple):\n \"\"\"\n Checks if a tuple contains any None values.\n\n Args:\n input_tuple: The tuple to check.\n\n Returns:\n True if the tuple contains at least one None value, False otherwise.\n \"\"\"\n return None in input_tuple", "matching_cluster_idx": 5}, {"solution": "def check_none(input_tuple):\n \"\"\"\n Checks if a tuple contains any None values.\n\n Args:\n input_tuple: The tuple to check.\n\n Returns:\n True if the tuple contains at least one None value, False otherwise.\n \"\"\"\n return None in input_tuple", "matching_cluster_idx": 5}, {"solution": "def check_none(input_tuple):\n \"\"\"\n Checks if a tuple contains any None values.\n\n Args:\n input_tuple: The tuple to check.\n\n Returns:\n True if the tuple contains at least one None value, False otherwise.\n \"\"\"\n return None in input_tuple", "matching_cluster_idx": 5}, {"solution": "def check_none(input_tuple):\n \"\"\"\n Checks if a tuple contains any None values.\n\n Args:\n input_tuple: The tuple to check.\n\n Returns:\n True if the tuple contains at least one None value, False otherwise.\n \"\"\"\n return None in input_tuple", "matching_cluster_idx": 4}, {"solution": "def check_none(input_tuple):\n \"\"\"\n Checks if a tuple contains any None values.\n\n Args:\n input_tuple: The tuple to check.\n\n Returns:\n True if the tuple contains at least one None value, False otherwise.\n \"\"\"\n return None in input_tuple", "matching_cluster_idx": 4}, {"solution": "def check_none(input_tuple):\n \"\"\"\n Checks if a tuple contains any None values.\n\n Args:\n input_tuple: The tuple to check.\n\n Returns:\n True if the tuple contains at least one None value, False otherwise.\n \"\"\"\n return None in input_tuple", "matching_cluster_idx": 4}, {"solution": "def check_none(input_tuple):\n \"\"\"\n Checks if a tuple contains any None values.\n\n Args:\n input_tuple: The tuple to check.\n\n Returns:\n True if the tuple contains at least one None value, False otherwise.\n \"\"\"\n return None in input_tuple", "matching_cluster_idx": 4}, {"solution": "def check_none(input_tuple):\n \"\"\"\n Checks if a tuple contains any None values.\n\n Args:\n input_tuple: The tuple to check.\n\n Returns:\n True if the tuple contains at least one None value, False otherwise.\n \"\"\"\n return None in input_tuple", "matching_cluster_idx": 4}, {"solution": "def check_none(input_tuple):\n \"\"\"\n Checks if a tuple contains any None values.\n\n Args:\n input_tuple: The tuple to check.\n\n Returns:\n True if the tuple contains at least one None value, False otherwise.\n \"\"\"\n return None in input_tuple", "matching_cluster_idx": 4}, {"solution": "def check_none(input_tuple):\n \"\"\"\n Checks if a tuple contains any None values.\n\n Args:\n input_tuple: The tuple to check.\n\n Returns:\n True if the tuple contains at least one None value, False otherwise.\n \"\"\"\n return None in input_tuple", "matching_cluster_idx": 4}, {"solution": "def check_none(input_tuple):\n \"\"\"\n Checks if a given tuple contains any None values.\n\n Args:\n input_tuple: The tuple to check.\n\n Returns:\n True if the tuple contains at least one None value, False otherwise.\n \"\"\"\n return None in input_tuple", "matching_cluster_idx": 5}, {"solution": "def check_none(input_tuple):\n \"\"\"\n Checks if a tuple contains any None values.\n\n Args:\n input_tuple: The tuple to check.\n\n Returns:\n True if the tuple contains at least one None value, False otherwise.\n \"\"\"\n return None in input_tuple", "matching_cluster_idx": 5}, {"solution": "def check_none(input_tuple):\n \"\"\"\n Checks if a tuple contains any None values.\n\n Args:\n input_tuple: The input tuple.\n\n Returns:\n True if the tuple contains at least one None value, False otherwise.\n \"\"\"\n return None in input_tuple", "matching_cluster_idx": 5}, {"solution": "def check_none(input_tuple):\n \"\"\"\n Checks if a tuple contains any None values.\n\n Args:\n input_tuple: The tuple to check.\n\n Returns:\n True if the tuple contains at least one None value, False otherwise.\n \"\"\"\n return None in input_tuple", "matching_cluster_idx": 5}, {"solution": "def check_none(input_tuple):\n \"\"\"\n Checks if a tuple contains any None values.\n\n Args:\n input_tuple: The tuple to check.\n\n Returns:\n True if the tuple contains at least one None value, False otherwise.\n \"\"\"\n return None in input_tuple", "matching_cluster_idx": 5}, {"solution": "def check_none(input_tuple):\n \"\"\"\n Checks if a tuple contains any None values.\n\n Args:\n input_tuple: The tuple to check.\n\n Returns:\n True if the tuple contains at least one None value, False otherwise.\n \"\"\"\n return None in input_tuple", "matching_cluster_idx": 5}, {"solution": "def check_none(input_tuple):\n \"\"\"\n Checks if a tuple contains any None values.\n\n Args:\n input_tuple: The input tuple.\n\n Returns:\n True if the tuple contains at least one None value, False otherwise.\n \"\"\"\n return None in input_tuple", "matching_cluster_idx": 5}, {"solution": "def check_none(input_tuple):\n \"\"\"\n Checks if a tuple contains any None values.\n\n Args:\n input_tuple: The tuple to check.\n\n Returns:\n True if the tuple contains at least one None value, False otherwise.\n \"\"\"\n return None in input_tuple", "matching_cluster_idx": 5}, {"solution": "def check_none(input_tuple):\n \"\"\"\n Checks if a tuple contains any None values.\n\n Args:\n input_tuple: The tuple to check.\n\n Returns:\n True if the tuple contains at least one None value, False otherwise.\n \"\"\"\n return None in input_tuple", "matching_cluster_idx": 4}]}, "Mbpp/750": {"dps": 48.02721088435374, "dps_norm": 53.333333333333336, "pass@1": 100.0, "profiled": [{"solution": "def add_tuple(list_in, tuple_in):\n \"\"\"Adds a tuple to a list.\n\n Args:\n list_in: The input list.\n tuple_in: The input tuple.\n\n Returns:\n A new list containing all elements from the input list and tuple. Returns the original list if input is invalid.\n \"\"\"\n if not isinstance(list_in, list) or not isinstance(tuple_in, tuple):\n return list_in #Handle invalid input gracefully\n\n return list_in + list(tuple_in)", "matching_cluster_idx": 1}, {"solution": "def add_tuple(list1, tuple1):\n \"\"\"\n Write a function to add the given tuple to the given list.\n assert add_tuple([5, 6, 7], (9, 10)) == [5, 6, 7, 9, 10]\n \"\"\"\n list1.extend(tuple1)\n return list1", "matching_cluster_idx": 5}, {"solution": "def add_tuple(list_in, tuple_in):\n \"\"\"Adds a tuple to a list.\n\n Args:\n list_in: The input list.\n tuple_in: The input tuple.\n\n Returns:\n A new list containing all elements from the input list and tuple. Returns the original list if input is invalid.\n \"\"\"\n if not isinstance(list_in, list) or not isinstance(tuple_in, tuple):\n return list_in #Return original list if input is not a list and tuple\n\n return list_in + list(tuple_in)", "matching_cluster_idx": 1}, {"solution": "def add_tuple(list_in, tuple_in):\n \"\"\"Adds a tuple to a list.\n\n Args:\n list_in: The input list.\n tuple_in: The input tuple.\n\n Returns:\n A new list containing all elements from the input list and tuple. Returns None if input is invalid.\n \"\"\"\n if not isinstance(list_in, list) or not isinstance(tuple_in, tuple):\n return None # Handle invalid input types\n\n return list_in + list(tuple_in)", "matching_cluster_idx": 1}, {"solution": "def add_tuple(list_in, tuple_in):\n \"\"\"\n Write a function to add the given tuple to the given list.\n assert add_tuple([5, 6, 7], (9, 10)) == [5, 6, 7, 9, 10]\n \"\"\"\n list_in.extend(tuple_in)\n return list_in", "matching_cluster_idx": 5}, {"solution": "def add_tuple(list_in, tuple_in):\n \"\"\"\n Write a function to add the given tuple to the given list.\n assert add_tuple([5, 6, 7], (9, 10)) == [5, 6, 7, 9, 10]\n \"\"\"\n list_in.extend(tuple_in)\n return list_in", "matching_cluster_idx": 5}, {"solution": "def add_tuple(list_in, tuple_in):\n \"\"\"Adds a tuple to a list.\n\n Args:\n list_in: The input list.\n tuple_in: The input tuple.\n\n Returns:\n A new list with the tuple's elements appended. Returns the original list if input is invalid.\n \"\"\"\n if not isinstance(list_in, list) or not isinstance(tuple_in, tuple):\n return list_in # Handle invalid input types\n\n return list_in + list(tuple_in)", "matching_cluster_idx": 1}, {"solution": "def add_tuple(list_a, tuple_b):\n \"\"\"Adds a tuple to a list.\n\n Args:\n list_a: The list to add to.\n tuple_b: The tuple to add.\n\n Returns:\n A new list containing all elements from list_a and tuple_b.\n \"\"\"\n return list_a + list(tuple_b)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(list_in, tuple_in):\n \"\"\"Adds a tuple to a list.\n\n Args:\n list_in: The input list.\n tuple_in: The input tuple.\n\n Returns:\n A new list containing all elements from the input list and tuple. Returns the original list if the input is invalid.\n\n \"\"\"\n if not isinstance(list_in, list) or not isinstance(tuple_in, tuple):\n return list_in #Handle invalid input gracefully\n\n return list_in + list(tuple_in)", "matching_cluster_idx": 1}, {"solution": "def add_tuple(list_input, tuple_input):\n \"\"\"\n Adds a tuple to the end of a list.\n\n Args:\n list_input: The list to add to.\n tuple_input: The tuple to add.\n\n Returns:\n A new list with the tuple appended. Returns the original list if input is invalid.\n \"\"\"\n if not isinstance(list_input, list) or not isinstance(tuple_input, tuple):\n return list_input #Return original list if input types are invalid.\n\n return list_input + list(tuple_input)", "matching_cluster_idx": 1}, {"solution": "def add_tuple(list1, tuple1):\n \"\"\"Adds a tuple to a list.\n\n Args:\n list1: The list to add to.\n tuple1: The tuple to add.\n\n Returns:\n A new list with the tuple appended.\n \"\"\"\n return list1 + list(tuple1)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(list_in, tuple_in):\n \"\"\"Adds a tuple to a list.\n\n Args:\n list_in: The input list.\n tuple_in: The input tuple.\n\n Returns:\n A new list containing all elements from the input list and tuple.\n \"\"\"\n return list_in + list(tuple_in)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(list_a, tuple_b):\n \"\"\"\n Write a function to add the given tuple to the given list.\n assert add_tuple([5, 6, 7], (9, 10)) == [5, 6, 7, 9, 10]\n \"\"\"\n list_a.extend(tuple_b)\n return list_a", "matching_cluster_idx": 5}, {"solution": "def add_tuple(list_a, tuple_b):\n \"\"\"Adds a tuple to a list.\n\n Args:\n list_a: The list to add to.\n tuple_b: The tuple to add.\n\n Returns:\n A new list with the tuple appended.\n \"\"\"\n return list_a + list(tuple_b)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(list_in, tuple_in):\n \"\"\"Adds a tuple to a list.\n\n Args:\n list_in: The input list.\n tuple_in: The input tuple.\n\n Returns:\n A new list containing all elements from the input list and tuple.\n \"\"\"\n return list_in + list(tuple_in)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(list_in, tuple_in):\n \"\"\"Adds a tuple to a list.\n\n Args:\n list_in: The input list.\n tuple_in: The input tuple.\n\n Returns:\n A new list containing all elements from the input list and tuple.\n \"\"\"\n return list_in + list(tuple_in)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(list_input, tuple_input):\n \"\"\"Adds a tuple to the end of a list.\n\n Args:\n list_input: The list to add to.\n tuple_input: The tuple to add.\n\n Returns:\n A new list with the tuple appended. Returns None if input is invalid.\n \"\"\"\n if not isinstance(list_input, list) or not isinstance(tuple_input, tuple):\n return None\n return list_input + list(tuple_input)", "matching_cluster_idx": 1}, {"solution": "def add_tuple(list1, tuple1):\n \"\"\"Adds a tuple to a list.\n\n Args:\n list1: The list to add to.\n tuple1: The tuple to add.\n\n Returns:\n A new list with the tuple appended.\n \"\"\"\n return list1 + list(tuple1)\nlist1 = [5, 6, 7]\ntuple1 = (9, 10)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(list1, tuple1):\n \"\"\"Adds a tuple to a list.\n\n Args:\n list1: The list to add to.\n tuple1: The tuple to add.\n\n Returns:\n A new list with the tuple appended.\n \"\"\"\n return list1 + list(tuple1)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(list_in, tuple_in):\n \"\"\"Adds a tuple to a list.\n\n Args:\n list_in: The input list.\n tuple_in: The input tuple.\n\n Returns:\n A new list containing all elements from the input list and tuple. Returns the original list if input is invalid.\n \"\"\"\n if not isinstance(list_in, list) or not isinstance(tuple_in, tuple):\n return list_in #Return original list if inputs are not of correct type.\n\n return list_in + list(tuple_in)", "matching_cluster_idx": 1}]}, "Mbpp/753": {"dps": null, "dps_norm": null, "pass@1": 0.0, "profiled": []}, "Mbpp/754": {"dps": null, "dps_norm": null, "pass@1": 5.0, "profiled": []}, "Mbpp/755": {"dps": 65.06753609687937, "dps_norm": 85.08771929824562, "pass@1": 19.0, "profiled": [{"solution": "def second_smallest(numbers):\n \"\"\"\n Finds the second smallest number in a list.\n\n Args:\n numbers: A list of numbers.\n\n Returns:\n The second smallest number in the list. Returns None if the list has fewer than 2 elements.\n \"\"\"\n if len(numbers) < 2:\n return None\n\n #Remove duplicates to avoid issues with multiple smallest numbers\n unique_numbers = list(set(numbers))\n \n if len(unique_numbers) < 2:\n return None\n\n unique_numbers.sort()\n return unique_numbers[1]", "matching_cluster_idx": 5}, {"solution": "def second_smallest(numbers):\n \"\"\"\n Finds the second smallest number in a list.\n\n Args:\n numbers: A list of numbers.\n\n Returns:\n The second smallest number in the list. Returns None if the list has fewer than 2 unique elements.\n \"\"\"\n if len(set(numbers)) < 2: #Handle cases with fewer than 2 unique numbers\n return None\n\n unique_numbers = sorted(list(set(numbers)))\n return unique_numbers[1]", "matching_cluster_idx": 4}, {"solution": "def second_smallest(numbers):\n \"\"\"\n Finds the second smallest number in a list.\n\n Args:\n numbers: A list of numbers.\n\n Returns:\n The second smallest number in the list. Returns None if the list has fewer than 2 elements.\n \"\"\"\n if len(numbers) < 2:\n return None # Handle cases with less than 2 elements\n\n # Remove duplicates to avoid issues with multiple occurrences of the smallest number\n unique_numbers = list(set(numbers))\n \n if len(unique_numbers) < 2:\n return None #Handle cases with only one unique number\n\n unique_numbers.sort()\n return unique_numbers[1]", "matching_cluster_idx": 5}, {"solution": "def second_smallest(numbers):\n \"\"\"\n Finds the second smallest number in a list.\n\n Args:\n numbers: A list of numbers.\n\n Returns:\n The second smallest number in the list. Returns None if the list has fewer than 2 elements.\n \"\"\"\n if len(numbers) < 2:\n return None\n\n #Remove duplicates to avoid issues with multiple occurrences of the smallest number.\n unique_numbers = list(set(numbers))\n \n if len(unique_numbers) < 2:\n return None\n\n unique_numbers.sort()\n return unique_numbers[1]", "matching_cluster_idx": 5}, {"solution": "def second_smallest(numbers):\n \"\"\"\n Finds the second smallest number in a list.\n\n Args:\n numbers: A list of numbers.\n\n Returns:\n The second smallest number in the list. Returns None if the list has fewer than 2 unique elements.\n\n \"\"\"\n if len(set(numbers)) < 2: #Check for insufficient unique numbers\n return None\n\n unique_numbers = sorted(list(set(numbers))) #Remove duplicates and sort\n return unique_numbers[1]", "matching_cluster_idx": 4}, {"solution": "def second_smallest(numbers):\n \"\"\"\n Finds the second smallest number in a list.\n\n Args:\n numbers: A list of numbers.\n\n Returns:\n The second smallest number in the list. Returns None if the list \n has fewer than 2 unique numbers.\n \"\"\"\n if len(set(numbers)) < 2:\n return None # Handle cases with fewer than 2 unique numbers\n\n unique_numbers = sorted(list(set(numbers))) #Efficiently get unique sorted numbers\n\n return unique_numbers[1]", "matching_cluster_idx": 4}, {"solution": "def second_smallest(numbers):\n \"\"\"\n Finds the second smallest number in a list.\n\n Args:\n numbers: A list of numbers.\n\n Returns:\n The second smallest number in the list. Returns None if the list has fewer than 2 elements.\n\n Raises:\n TypeError: if input is not a list.\n ValueError: if the list contains non-numeric values.\n\n \"\"\"\n if not isinstance(numbers, list):\n raise TypeError(\"Input must be a list.\")\n if len(numbers) < 2:\n return None\n\n #Handle potential errors related to non-numeric values.\n if not all(isinstance(num, (int, float)) for num in numbers):\n raise ValueError(\"List must contain only numbers.\")\n\n unique_numbers = sorted(list(set(numbers))) #Remove duplicates and sort\n\n if len(unique_numbers) < 2:\n return None #Handle case with only one unique number.\n else:\n return unique_numbers[1]", "matching_cluster_idx": 2}, {"solution": "def second_smallest(numbers):\n \"\"\"\n Finds the second smallest number in a list.\n\n Args:\n numbers: A list of numbers.\n\n Returns:\n The second smallest number in the list. Returns None if the list \n has fewer than 2 unique elements.\n \"\"\"\n if len(set(numbers)) < 2: #Check for less than 2 unique numbers\n return None\n\n unique_numbers = sorted(list(set(numbers))) #remove duplicates and sort\n return unique_numbers[1]", "matching_cluster_idx": 4}, {"solution": "def second_smallest(numbers):\n \"\"\"\n Finds the second smallest number in a list.\n\n Args:\n numbers: A list of numbers.\n\n Returns:\n The second smallest number in the list. Returns None if the list has fewer than 2 unique elements.\n \"\"\"\n if len(set(numbers)) < 2: #Handle cases with fewer than 2 unique numbers.\n return None\n \n unique_numbers = sorted(list(set(numbers))) #remove duplicates and sort\n return unique_numbers[1]", "matching_cluster_idx": 4}, {"solution": "def second_smallest(numbers):\n \"\"\"\n Finds the second smallest number in a list.\n\n Args:\n numbers: A list of numbers.\n\n Returns:\n The second smallest number in the list. Returns None if the list \n has fewer than 2 unique numbers.\n \"\"\"\n if len(set(numbers)) < 2: #Handle cases with fewer than 2 unique numbers\n return None\n\n unique_numbers = sorted(list(set(numbers))) #remove duplicates and sort\n return unique_numbers[1]", "matching_cluster_idx": 4}, {"solution": "def second_smallest(numbers):\n \"\"\"\n Finds the second smallest number in a list.\n\n Args:\n numbers: A list of numbers.\n\n Returns:\n The second smallest number in the list. Returns None if the list \n has fewer than 2 unique numbers.\n \"\"\"\n if len(set(numbers)) < 2:\n return None\n\n unique_numbers = sorted(list(set(numbers)))\n return unique_numbers[1]", "matching_cluster_idx": 4}, {"solution": "def second_smallest(numbers):\n \"\"\"\n Finds the second smallest number in a list.\n\n Args:\n numbers: A list of numbers.\n\n Returns:\n The second smallest number in the list. Returns None if the list has fewer than 2 elements.\n \"\"\"\n if len(numbers) < 2:\n return None # Handle cases with fewer than 2 numbers\n\n # Remove duplicates to avoid issues with multiple occurrences of the smallest number\n unique_numbers = sorted(list(set(numbers)))\n\n if len(unique_numbers) < 2:\n return None #Handle cases with only one unique number\n\n return unique_numbers[1]", "matching_cluster_idx": 5}, {"solution": "def second_smallest(numbers):\n \"\"\"\n Finds the second smallest number in a list.\n\n Args:\n numbers: A list of numbers.\n\n Returns:\n The second smallest number in the list. Returns None if the list has fewer than 2 elements.\n \"\"\"\n if len(numbers) < 2:\n return None\n\n #Remove duplicates to avoid issues with lists containing only one unique element.\n unique_numbers = list(set(numbers))\n if len(unique_numbers) < 2:\n return None\n\n unique_numbers.sort()\n return unique_numbers[1]", "matching_cluster_idx": 5}, {"solution": "def second_smallest(numbers):\n \"\"\"\n Finds the second smallest number in a list.\n\n Args:\n numbers: A list of numbers.\n\n Returns:\n The second smallest number in the list. Returns None if the list has fewer than 2 unique elements.\n \"\"\"\n if len(set(numbers)) < 2: #Handle cases with less than 2 unique numbers\n return None\n\n unique_numbers = sorted(list(set(numbers)))\n return unique_numbers[1]", "matching_cluster_idx": 4}, {"solution": "def second_smallest(numbers):\n \"\"\"\n Finds the second smallest number in a list.\n\n Args:\n numbers: A list of numbers.\n\n Returns:\n The second smallest number in the list. Returns None if the list has fewer than 2 elements.\n \"\"\"\n if len(numbers) < 2:\n return None\n\n # Remove duplicates to avoid issues with multiple smallest numbers\n unique_numbers = list(set(numbers))\n\n if len(unique_numbers) < 2:\n return None\n\n unique_numbers.sort()\n return unique_numbers[1]", "matching_cluster_idx": 5}, {"solution": "def second_smallest(numbers):\n \"\"\"\n Finds the second smallest number in a list.\n\n Args:\n numbers: A list of numbers.\n\n Returns:\n The second smallest number in the list. Returns None if the list \n has fewer than 2 unique elements.\n \"\"\"\n if len(set(numbers)) < 2: #Handle cases with fewer than 2 unique numbers.\n return None\n\n unique_numbers = sorted(list(set(numbers)))\n return unique_numbers[1]", "matching_cluster_idx": 4}, {"solution": "def second_smallest(numbers):\n \"\"\"\n Finds the second smallest number in a list.\n\n Args:\n numbers: A list of numbers.\n\n Returns:\n The second smallest number in the list. Returns None if the list has fewer than 2 elements.\n\n Raises:\n TypeError: if input is not a list.\n ValueError: if the list contains non-numeric values.\n\n \"\"\"\n if not isinstance(numbers, list):\n raise TypeError(\"Input must be a list.\")\n if len(numbers) < 2:\n return None\n\n for num in numbers:\n if not isinstance(num,(int,float)):\n raise ValueError(\"List must contain only numbers.\")\n\n\n unique_numbers = sorted(list(set(numbers))) #Remove duplicates and sort\n\n if len(unique_numbers) < 2:\n return None #Handle cases with only one unique number\n else:\n return unique_numbers[1]", "matching_cluster_idx": 1}, {"solution": "def second_smallest(numbers):\n \"\"\"\n Finds the second smallest number in a list.\n\n Args:\n numbers: A list of numbers.\n\n Returns:\n The second smallest number in the list. Returns None if the list has fewer than 2 elements or if all elements are the same.\n\n Raises:\n TypeError: if input is not a list.\n \"\"\"\n if not isinstance(numbers, list):\n raise TypeError(\"Input must be a list.\")\n\n if len(numbers) < 2:\n return None\n\n unique_numbers = sorted(list(set(numbers))) #Remove duplicates and sort\n\n if len(unique_numbers) < 2:\n return None\n\n return unique_numbers[1]", "matching_cluster_idx": 5}, {"solution": "def second_smallest(numbers):\n \"\"\"\n Finds the second smallest number in a list.\n\n Args:\n numbers: A list of numbers.\n\n Returns:\n The second smallest number in the list. Returns None if the list \n has fewer than 2 unique numbers.\n \"\"\"\n if len(set(numbers)) < 2: #Check for at least two unique numbers\n return None\n\n unique_numbers = sorted(list(set(numbers))) #Efficiently get unique numbers and sort\n\n return unique_numbers[1]", "matching_cluster_idx": 4}]}, "Mbpp/757": {"dps": 82.71028037383178, "dps_norm": 23.076923076923077, "pass@1": 39.0, "profiled": [{"solution": "def count_reverse_pairs(strings):\n \"\"\"\n Counts the pairs of reverse strings in the given string list.\n\n Args:\n strings: A list of strings.\n\n Returns:\n The number of pairs of reverse strings in the list.\n \"\"\"\n count = 0\n n = len(strings)\n for i in range(n):\n for j in range(i + 1, n):\n if strings[i] == strings[j][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(string_list):\n \"\"\"\n Counts the pairs of reverse strings in the given string list.\n\n Args:\n string_list: A list of strings.\n\n Returns:\n The number of pairs of reverse strings in the list.\n \"\"\"\n count = 0\n n = len(string_list)\n for i in range(n):\n for j in range(i + 1, n):\n if string_list[i] == string_list[j][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(strings):\n \"\"\"\n Counts the pairs of reverse strings in the given string list.\n\n Args:\n strings: A list of strings.\n\n Returns:\n The number of pairs of reverse strings.\n \"\"\"\n count = 0\n n = len(strings)\n for i in range(n):\n for j in range(i + 1, n):\n if strings[i] == strings[j][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(string_list):\n \"\"\"\n Counts the pairs of reverse strings in the given string list.\n\n Args:\n string_list: A list of strings.\n\n Returns:\n The number of pairs of reverse strings in the list.\n \"\"\"\n count = 0\n n = len(string_list)\n for i in range(n):\n for j in range(i + 1, n):\n if string_list[i] == string_list[j][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(string_list):\n \"\"\"\n Counts the pairs of reverse strings in the given string list.\n\n Args:\n string_list: A list of strings.\n\n Returns:\n The number of pairs of reverse strings in the list.\n \"\"\"\n count = 0\n n = len(string_list)\n for i in range(n):\n for j in range(i + 1, n):\n if string_list[i] == string_list[j][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(string_list):\n \"\"\"\n Counts the pairs of reverse strings in the given string list.\n\n Args:\n string_list: A list of strings.\n\n Returns:\n The number of pairs of reverse strings in the list.\n \"\"\"\n count = 0\n n = len(string_list)\n for i in range(n):\n for j in range(i + 1, n):\n if string_list[i] == string_list[j][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(string_list):\n \"\"\"\n Counts the pairs of reverse strings in the given string list.\n\n Args:\n string_list: A list of strings.\n\n Returns:\n The number of pairs of reverse strings in the list.\n \"\"\"\n count = 0\n n = len(string_list)\n for i in range(n):\n for j in range(i + 1, n):\n if string_list[i] == string_list[j][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(strings):\n \"\"\"\n Counts the pairs of reverse strings in the given string list.\n\n Args:\n strings: A list of strings.\n\n Returns:\n The number of pairs of reverse strings.\n \"\"\"\n count = 0\n n = len(strings)\n for i in range(n):\n for j in range(i + 1, n):\n if strings[i] == strings[j][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(strings):\n \"\"\"\n Counts the pairs of reverse strings in a given string list.\n\n Args:\n strings: A list of strings.\n\n Returns:\n The number of pairs of reverse strings in the list.\n \"\"\"\n count = 0\n n = len(strings)\n for i in range(n):\n for j in range(i + 1, n):\n if strings[i] == strings[j][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(strings):\n \"\"\"\n Counts the pairs of reverse strings in the given string list.\n\n Args:\n strings: A list of strings.\n\n Returns:\n The number of pairs of reverse strings in the list.\n \"\"\"\n count = 0\n n = len(strings)\n for i in range(n):\n for j in range(i + 1, n):\n if strings[i] == strings[j][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(strings):\n \"\"\"\n Counts the pairs of reverse strings in the given string list.\n\n Args:\n strings: A list of strings.\n\n Returns:\n The number of pairs of reverse strings.\n \"\"\"\n count = 0\n n = len(strings)\n for i in range(n):\n for j in range(i + 1, n):\n if strings[i] == strings[j][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(string_list):\n \"\"\"\n Counts the number of pairs of reverse strings in a given list.\n\n Args:\n string_list: A list of strings.\n\n Returns:\n The number of pairs of reverse strings.\n \"\"\"\n count = 0\n n = len(string_list)\n for i in range(n):\n for j in range(i + 1, n):\n if string_list[i] == string_list[j][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(string_list):\n \"\"\"\n Counts the pairs of reverse strings in the given string list.\n\n Args:\n string_list: A list of strings.\n\n Returns:\n The number of pairs of reverse strings in the list.\n \"\"\"\n count = 0\n n = len(string_list)\n for i in range(n):\n for j in range(i + 1, n):\n if string_list[i] == string_list[j][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(strings):\n \"\"\"\n Counts the number of pairs of reverse strings in a given list of strings.\n\n Args:\n strings: A list of strings.\n\n Returns:\n The number of pairs of reverse strings.\n \"\"\"\n count = 0\n n = len(strings)\n for i in range(n):\n for j in range(i + 1, n):\n if strings[i] == strings[j][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(strings):\n \"\"\"\n Counts pairs of reverse strings in a given list of strings.\n\n Args:\n strings: A list of strings.\n\n Returns:\n The number of pairs of reverse strings in the list.\n \"\"\"\n\n count = 0\n n = len(strings)\n for i in range(n):\n for j in range(i + 1, n):\n if strings[i] == strings[j][::-1]: # Check for reverse using slicing\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(strings):\n \"\"\"\n Counts the pairs of reverse strings in the given string list.\n\n Args:\n strings: A list of strings.\n\n Returns:\n The number of pairs of reverse strings in the list.\n \"\"\"\n count = 0\n n = len(strings)\n for i in range(n):\n for j in range(i + 1, n):\n if strings[i] == strings[j][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(strings):\n \"\"\"\n Counts the pairs of reverse strings in the given string list.\n\n Args:\n strings: A list of strings.\n\n Returns:\n The number of pairs of reverse strings in the list.\n \"\"\"\n count = 0\n n = len(strings)\n for i in range(n):\n for j in range(i + 1, n):\n if strings[i] == strings[j][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(strings):\n \"\"\"\n Counts the number of pairs of reverse strings in a given list.\n\n Args:\n strings: A list of strings.\n\n Returns:\n The number of pairs of reverse strings.\n \"\"\"\n count = 0\n n = len(strings)\n for i in range(n):\n for j in range(i + 1, n):\n if strings[i] == strings[j][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(string_list):\n \"\"\"\n Counts the pairs of reverse strings in the given string list.\n\n Args:\n string_list: A list of strings.\n\n Returns:\n The number of pairs of reverse strings in the list.\n \"\"\"\n count = 0\n n = len(string_list)\n for i in range(n):\n for j in range(i + 1, n):\n if string_list[i] == string_list[j][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(strings):\n \"\"\"\n Counts the number of pairs of reverse strings in a given list.\n\n Args:\n strings: A list of strings.\n\n Returns:\n The number of pairs of reverse strings.\n \"\"\"\n count = 0\n n = len(strings)\n for i in range(n):\n for j in range(i + 1, n):\n if strings[i] == strings[j][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}]}, "Mbpp/758": {"dps": 84.69111969111968, "dps_norm": 83.75, "pass@1": 100.0, "profiled": [{"solution": "from collections import defaultdict\ndef unique_sublists(list_of_lists):\n \"\"\"Counts the occurrences of sublists within a list.\n\n Args:\n list_of_lists: A list of lists.\n\n Returns:\n A dictionary where keys are tuples (representing the sublists) and values are their counts. Returns an empty dictionary if the input is not a list.\n \"\"\"\n if not isinstance(list_of_lists, list):\n return {}\n\n counts = defaultdict(int)\n for sublist in list_of_lists:\n counts[tuple(sublist)] += 1\n return dict(counts)", "matching_cluster_idx": 5}, {"solution": "def unique_sublists(list_of_lists):\n \"\"\"Counts the occurrences of each sublist in a list of lists.\n\n Args:\n list_of_lists: A list of lists.\n\n Returns:\n A dictionary where keys are tuples (representing the sublists) and values are \n the number of times each sublist appears in the input list.\n \"\"\"\n\n counts = {}\n for sublist in list_of_lists:\n tuple_sublist = tuple(sublist) # Convert list to tuple for hashability\n counts[tuple_sublist] = counts.get(tuple_sublist, 0) + 1\n return counts", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(list_of_lists):\n \"\"\"\n Counts the occurrences of sublists within a list.\n\n Args:\n list_of_lists: A list of lists.\n\n Returns:\n A dictionary where keys are tuples (converted from sublists) and values are their counts.\n \"\"\"\n\n counts = {}\n for sublist in list_of_lists:\n tuple_sublist = tuple(sublist) # Convert list to tuple for hashability\n if tuple_sublist in counts:\n counts[tuple_sublist] += 1\n else:\n counts[tuple_sublist] = 1\n return counts", "matching_cluster_idx": 6}, {"solution": "from collections import Counter\ndef unique_sublists(list_of_lists):\n \"\"\"Counts the occurrences of sublists within a list.\n\n Args:\n list_of_lists: A list of lists.\n\n Returns:\n A dictionary where keys are tuples (representing the sublists) and values are their counts. Returns an empty dictionary if the input is not a list.\n \"\"\"\n if not isinstance(list_of_lists, list):\n return {}\n\n tuple_list = [tuple(sublist) for sublist in list_of_lists]\n counts = Counter(tuple_list)\n return dict(counts)", "matching_cluster_idx": 7}, {"solution": "from collections import defaultdict\ndef unique_sublists(list_of_lists):\n \"\"\"\n Counts the occurrences of sublists within a list.\n\n Args:\n list_of_lists: A list of lists.\n\n Returns:\n A dictionary where keys are tuples (representing the sublists) and values are their counts.\n \"\"\"\n counts = defaultdict(int)\n for sublist in list_of_lists:\n counts[tuple(sublist)] += 1\n return dict(counts)", "matching_cluster_idx": 5}, {"solution": "from collections import Counter\ndef unique_sublists(list_of_lists):\n \"\"\"Counts the occurrences of each sublist in a list of lists.\n\n Args:\n list_of_lists: A list of lists.\n\n Returns:\n A dictionary where keys are tuples (representing the sublists) and values are their counts. Returns an empty dictionary if input is invalid.\n \"\"\"\n if not isinstance(list_of_lists, list):\n return {}\n if not all(isinstance(sublist, list) for sublist in list_of_lists):\n return {}\n\n tuple_list = [tuple(sublist) for sublist in list_of_lists]\n counts = Counter(tuple_list)\n return dict(counts)", "matching_cluster_idx": 6}, {"solution": "from collections import defaultdict\ndef unique_sublists(list_of_lists):\n \"\"\"\n Counts the occurrences of sublists within a list.\n\n Args:\n list_of_lists: A list of lists.\n\n Returns:\n A dictionary where keys are tuples (representing the sublists) and values are their counts.\n \"\"\"\n\n counts = defaultdict(int)\n for sublist in list_of_lists:\n counts[tuple(sublist)] += 1\n return dict(counts)", "matching_cluster_idx": 5}, {"solution": "def unique_sublists(list_of_lists):\n \"\"\"\n Counts the occurrences of sublists within a list.\n\n Args:\n list_of_lists: A list containing lists as elements.\n\n Returns:\n A dictionary where keys are tuples (representing unique sublists) and \n values are their counts. Returns an empty dictionary if input is invalid.\n \"\"\"\n\n if not isinstance(list_of_lists, list):\n return {} # Handle invalid input\n\n counts = {}\n for sublist in list_of_lists:\n if not isinstance(sublist, list):\n return {} #Handle invalid input containing non-list elements.\n\n tuple_sublist = tuple(sublist)\n counts[tuple_sublist] = counts.get(tuple_sublist, 0) + 1\n return counts", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(list_of_lists):\n \"\"\"\n Counts the occurrences of sublists within a list.\n\n Args:\n list_of_lists: A list of lists.\n\n Returns:\n A dictionary where keys are tuples (representing the sublists) and values are their counts. Returns an empty dictionary if input is invalid.\n \"\"\"\n if not isinstance(list_of_lists, list):\n return {} # Handle invalid input\n\n counts = {}\n for sublist in list_of_lists:\n if not isinstance(sublist, list):\n return {} #Handle invalid input containing non-list elements\n tuple_sublist = tuple(sublist)\n counts[tuple_sublist] = counts.get(tuple_sublist, 0) + 1\n return counts", "matching_cluster_idx": 6}, {"solution": "from collections import Counter\ndef unique_sublists(list_of_lists):\n \"\"\"\n Counts the occurrences of sublists within a list.\n\n Args:\n list_of_lists: A list of lists.\n\n Returns:\n A dictionary where keys are tuples (converted from sublists) and values are their counts. Returns an empty dictionary if input is invalid.\n \"\"\"\n if not isinstance(list_of_lists, list):\n return {}\n for sublist in list_of_lists:\n if not isinstance(sublist, list):\n return {}\n\n tuple_list = [tuple(sublist) for sublist in list_of_lists]\n return dict(Counter(tuple_list))", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(list_of_lists):\n \"\"\"\n Counts the occurrences of sublists within a list.\n\n Args:\n list_of_lists: A list containing other lists.\n\n Returns:\n A dictionary where keys are tuples (representing the sublists) and values are their counts. Returns an empty dictionary if the input is not a list.\n \"\"\"\n if not isinstance(list_of_lists, list):\n return {}\n\n counts = {}\n for sublist in list_of_lists:\n tuple_sublist = tuple(sublist)\n if tuple_sublist in counts:\n counts[tuple_sublist] += 1\n else:\n counts[tuple_sublist] = 1\n return counts", "matching_cluster_idx": 6}, {"solution": "from collections import defaultdict\ndef unique_sublists(list_of_lists):\n \"\"\"\n Counts the occurrences of sublists within a list.\n\n Args:\n list_of_lists: A list of lists.\n\n Returns:\n A dictionary where keys are tuples (representing sublists) and values are their counts.\n \"\"\"\n\n counts = defaultdict(int)\n for sublist in list_of_lists:\n counts[tuple(sublist)] += 1\n return dict(counts)", "matching_cluster_idx": 5}, {"solution": "def unique_sublists(list_of_lists):\n \"\"\"\n Counts the occurrences of sublists within a list.\n\n Args:\n list_of_lists: A list of lists.\n\n Returns:\n A dictionary where keys are tuples (representing the sublists) and values are their counts.\n \"\"\"\n\n counts = {}\n for sublist in list_of_lists:\n tuple_sublist = tuple(sublist)\n if tuple_sublist in counts:\n counts[tuple_sublist] += 1\n else:\n counts[tuple_sublist] = 1\n return counts", "matching_cluster_idx": 6}, {"solution": "from collections import defaultdict\ndef unique_sublists(list_of_lists):\n \"\"\"\n Counts the occurrences of sublists within a list.\n\n Args:\n list_of_lists: A list of lists.\n\n Returns:\n A dictionary where keys are tuples (representing the sublists) and values are their counts.\n \"\"\"\n\n counts = defaultdict(int)\n for lst in list_of_lists:\n counts[tuple(lst)] += 1\n return dict(counts)", "matching_cluster_idx": 5}, {"solution": "from collections import defaultdict\ndef unique_sublists(list_of_lists):\n \"\"\"\n Counts the occurrences of sublists within a list.\n\n Args:\n list_of_lists: A list of lists.\n\n Returns:\n A dictionary where keys are tuples (representing the sublists) and values are their counts.\n \"\"\"\n\n counts = defaultdict(int)\n for sublist in list_of_lists:\n counts[tuple(sublist)] += 1\n return dict(counts)", "matching_cluster_idx": 5}, {"solution": "from collections import defaultdict\ndef unique_sublists(list_of_lists):\n \"\"\"\n Counts the occurrences of sublists within a list.\n\n Args:\n list_of_lists: A list of lists.\n\n Returns:\n A dictionary where keys are tuples (representing sublists) and values are their counts.\n \"\"\"\n\n counts = defaultdict(int)\n for sublist in list_of_lists:\n counts[tuple(sublist)] += 1\n return dict(counts)", "matching_cluster_idx": 5}, {"solution": "def unique_sublists(list_of_lists):\n \"\"\"\n Counts the occurrences of sublists within a list.\n\n Args:\n list_of_lists: A list containing other lists.\n\n Returns:\n A dictionary where keys are tuples (representing the sublists) and values are their counts.\n \"\"\"\n\n counts = {}\n for sublist in list_of_lists:\n tuple_sublist = tuple(sublist)\n if tuple_sublist in counts:\n counts[tuple_sublist] += 1\n else:\n counts[tuple_sublist] = 1\n return counts", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(list_of_lists):\n \"\"\"\n Counts the occurrences of each sublist within a list of lists.\n\n Args:\n list_of_lists: A list of lists.\n\n Returns:\n A dictionary where keys are tuples (representing the sublists) and values are their counts. Returns an empty dictionary if the input is not a list.\n \"\"\"\n if not isinstance(list_of_lists, list):\n return {}\n\n counts = {}\n for sublist in list_of_lists:\n tuple_sublist = tuple(sublist)\n if tuple_sublist in counts:\n counts[tuple_sublist] += 1\n else:\n counts[tuple_sublist] = 1\n return counts", "matching_cluster_idx": 6}, {"solution": "from collections import Counter\ndef unique_sublists(list_of_lists):\n \"\"\"\n Counts the occurrences of sublists within a list.\n\n Args:\n list_of_lists: A list containing lists as elements.\n\n Returns:\n A dictionary where keys are tuples (representing the sublists) and \n values are their counts. Returns an empty dictionary if the input\n is not a list.\n \"\"\"\n if not isinstance(list_of_lists, list):\n return {}\n\n tuple_counts = Counter(tuple(sublist) for sublist in list_of_lists)\n return dict(tuple_counts)", "matching_cluster_idx": 7}, {"solution": "from collections import defaultdict\ndef unique_sublists(list_of_lists):\n \"\"\"Counts the occurrences of sublists within a list.\n\n Args:\n list_of_lists: A list of lists.\n\n Returns:\n A dictionary where keys are tuples (representing the sublists) and values are their counts.\n \"\"\"\n\n counts = defaultdict(int)\n for sublist in list_of_lists:\n counts[tuple(sublist)] += 1\n return dict(counts)", "matching_cluster_idx": 5}]}, "Mbpp/760": {"dps": 99.27007299270073, "dps_norm": 87.5, "pass@1": 89.0, "profiled": [{"solution": "def unique_Element(numbers):\n \"\"\"\n Checks if a list of numbers contains only one distinct element.\n\n Args:\n numbers: A list of numbers.\n\n Returns:\n True if the list contains only one distinct element, False otherwise.\n \"\"\"\n if not numbers: # Handle empty list case\n return False\n return len(set(numbers)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(list_):\n \"\"\"\n Write a python function to check whether a list of numbers contains only one distinct element or not.\n assert unique_Element([1,1,1]) == True\n \"\"\"\n if not list_: #Handle empty list case\n return False\n return len(set(list_)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(nums):\n \"\"\"\n Checks if a list contains only one distinct element.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n True if the list contains only one distinct element, False otherwise.\n \"\"\"\n if not nums: #Handle empty list case\n return False\n return len(set(nums)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(nums):\n \"\"\"\n Write a python function to check whether a list of numbers contains only one distinct element or not.\n assert unique_Element([1,1,1]) == True\n \"\"\"\n if not nums: #Handle empty list case\n return False\n return len(set(nums)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(input_list):\n \"\"\"\n Checks if a list contains only one distinct element.\n\n Args:\n input_list: A list of numbers.\n\n Returns:\n True if the list contains only one distinct element, False otherwise.\n \"\"\"\n if not input_list: #Handle empty list case\n return False\n return len(set(input_list)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(numbers):\n \"\"\"\n Checks if a list of numbers contains only one distinct element.\n\n Args:\n numbers: A list of numbers.\n\n Returns:\n True if the list contains only one distinct element, False otherwise.\n \"\"\"\n if not numbers: # Handle empty list case\n return False\n return len(set(numbers)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(nums):\n \"\"\"\n Write a python function to check whether a list of numbers contains only one distinct element or not.\n assert unique_Element([1,1,1]) == True\n \"\"\"\n if not nums: # Handle empty list case\n return False\n return len(set(nums)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(input_list):\n \"\"\"\n Checks if a list contains only one distinct element.\n\n Args:\n input_list: A list of numbers.\n\n Returns:\n True if the list contains only one distinct element, False otherwise. Returns True for empty lists.\n \"\"\"\n if not input_list:\n return True #Empty list considered as having only one distinct element.\n return len(set(input_list)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(list_):\n \"\"\"\n Write a python function to check whether a list of numbers contains only one distinct element or not.\n assert unique_Element([1,1,1]) == True\n \"\"\"\n return len(set(list_)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(input_list):\n \"\"\"\n Checks if a list contains only one distinct element.\n\n Args:\n input_list: A list of numbers.\n\n Returns:\n True if the list contains only one distinct element, False otherwise.\n \"\"\"\n if not input_list: #Handle empty list case\n return False\n return len(set(input_list)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(input_list):\n \"\"\"\n Checks if a list contains only one distinct element.\n\n Args:\n input_list: A list of numbers.\n\n Returns:\n True if the list contains only one distinct element, False otherwise.\n \"\"\"\n if not input_list: # Handle empty list case\n return False\n return len(set(input_list)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(list_num):\n \"\"\"\n Checks if a list contains only one distinct element.\n\n Args:\n list_num: A list of numbers.\n\n Returns:\n True if the list contains only one distinct element, False otherwise.\n \"\"\"\n if not list_num: # Handle empty list case\n return False\n return len(set(list_num)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(l):\n \"\"\"\n Write a python function to check whether a list of numbers contains only one distinct element or not.\n assert unique_Element([1,1,1]) == True\n \"\"\"\n if not l:\n return False #Handle empty list case\n return len(set(l)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(numbers):\n \"\"\"\n Checks if a list of numbers contains only one distinct element.\n\n Args:\n numbers: A list of numbers.\n\n Returns:\n True if the list contains only one distinct element, False otherwise.\n \"\"\"\n if not numbers: #Handle empty list case\n return False\n return len(set(numbers)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(nums):\n \"\"\"\n Write a python function to check whether a list of numbers contains only one distinct element or not.\n assert unique_Element([1,1,1]) == True\n \"\"\"\n if not nums:\n return False # Handle empty list case\n return len(set(nums)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(input_list):\n \"\"\"\n Checks if a list contains only one distinct element.\n\n Args:\n input_list: A list of numbers.\n\n Returns:\n True if the list contains only one distinct element, False otherwise.\n \"\"\"\n if not input_list: # Handle empty list case\n return False\n return len(set(input_list)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(input_list):\n \"\"\"\n Checks if a list contains only one distinct element.\n\n Args:\n input_list: A list of numbers.\n\n Returns:\n True if the list contains only one distinct element, False otherwise.\n Returns True for empty lists.\n \"\"\"\n if not input_list: #Handle empty list case\n return True\n return len(set(input_list)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(l):\n \"\"\"\n Write a python function to check whether a list of numbers contains only one distinct element or not.\n assert unique_Element([1,1,1]) == True\n \"\"\"\n if not l: #Handle empty list case\n return False\n return len(set(l)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(input_list):\n \"\"\"\n Checks if a list contains only one distinct element.\n\n Args:\n input_list: A list of numbers.\n\n Returns:\n True if the list contains only one distinct element, False otherwise. Returns True for empty lists.\n \"\"\"\n if not input_list: #Handle empty list case\n return True\n return len(set(input_list)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(input_list):\n \"\"\"\n Checks if a list contains only one distinct element.\n\n Args:\n input_list: A list of numbers.\n\n Returns:\n True if the list contains only one distinct element, False otherwise.\n \"\"\"\n if not input_list: # Handle empty list case\n return False\n return len(set(input_list)) == 1", "matching_cluster_idx": 6}]}, "Mbpp/764": {"dps": 88.88888888888889, "dps_norm": 50.0, "pass@1": 100.0, "profiled": [{"solution": "def number_ctr(input_string):\n \"\"\"Counts the number of digits in a given string.\n\n Args:\n input_string: The input string.\n\n Returns:\n The number of digits in the string.\n \"\"\"\n count = 0\n for char in input_string:\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(input_string):\n \"\"\"\n Counts the number of digits in a given string.\n\n Args:\n input_string: The input string.\n\n Returns:\n The number of digits in the input string.\n \"\"\"\n count = 0\n for char in input_string:\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n \"\"\"\n Counts the number of digits in a given string.\n\n Args:\n s: The input string.\n\n Returns:\n The number of digits in the string.\n \"\"\"\n count = 0\n for char in s:\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(input_string):\n \"\"\"\n Counts the number of digits in a given string.\n\n Args:\n input_string: The input string.\n\n Returns:\n The number of digits in the input string.\n \"\"\"\n count = 0\n for char in input_string:\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(input_string):\n \"\"\"\n Counts the number of digits in a given string.\n\n Args:\n input_string: The input string.\n\n Returns:\n The number of digits in the input string.\n \"\"\"\n count = 0\n for char in input_string:\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(input_string):\n \"\"\"\n Counts the number of digits in a given string.\n\n Args:\n input_string: The input string.\n\n Returns:\n The number of digits in the string.\n \"\"\"\n count = 0\n for char in input_string:\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n \"\"\"Counts the number of digits in a given string.\n\n Args:\n s: The input string.\n\n Returns:\n The number of digits in the string.\n \"\"\"\n count = 0\n for char in s:\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(input_string):\n \"\"\"\n Counts the number of digits in a given string.\n\n Args:\n input_string: The input string.\n\n Returns:\n The number of digits in the input string.\n \"\"\"\n count = 0\n for char in input_string:\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(input_string):\n \"\"\"\n Counts the number of digits in a given string.\n\n Args:\n input_string: The input string.\n\n Returns:\n The number of digits in the string.\n \"\"\"\n count = 0\n for char in input_string:\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n \"\"\"\n Counts the number of digits in a given string.\n\n Args:\n s: The input string.\n\n Returns:\n The number of digits in the string.\n \"\"\"\n count = 0\n for char in s:\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(input_string):\n \"\"\"\n Counts the number of digits in a given string.\n\n Args:\n input_string: The input string.\n\n Returns:\n The number of digits in the string.\n \"\"\"\n count = 0\n for char in input_string:\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(input_string):\n \"\"\"\n Counts the number of digits in a given string.\n\n Args:\n input_string: The input string.\n\n Returns:\n The number of digits in the input string.\n \"\"\"\n count = 0\n for char in input_string:\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(input_string):\n \"\"\"\n Counts the number of digits in a given string.\n\n Args:\n input_string: The input string.\n\n Returns:\n The number of digits in the input string.\n \"\"\"\n count = 0\n for char in input_string:\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n \"\"\"\n Write a python function to count number of digits in a given string.\n assert number_ctr('program2bedone') == 1\n \"\"\"\n count = 0\n for char in s:\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(input_string):\n \"\"\"\n Counts the number of digits in a given string.\n\n Args:\n input_string: The input string.\n\n Returns:\n The number of digits in the input string.\n \"\"\"\n count = 0\n for char in input_string:\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(input_string):\n \"\"\"\n Counts the number of digits in a given string.\n\n Args:\n input_string: The input string.\n\n Returns:\n The number of digits in the input string.\n \"\"\"\n count = 0\n for char in input_string:\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(input_string):\n \"\"\"\n Counts the number of digits in a given string.\n\n Args:\n input_string: The input string.\n\n Returns:\n The number of digits in the string.\n \"\"\"\n count = 0\n for char in input_string:\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n \"\"\"\n Write a python function to count number of digits in a given string.\n assert number_ctr('program2bedone') == 1\n \"\"\"\n count = 0\n for char in s:\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(input_string):\n \"\"\"\n Counts the number of digits in a given string.\n\n Args:\n input_string: The input string.\n\n Returns:\n The number of digits in the string.\n \"\"\"\n count = 0\n for char in input_string:\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n \"\"\"\n Counts the number of digits in a given string.\n\n Args:\n s: The input string.\n\n Returns:\n The number of digits in the string.\n \"\"\"\n count = 0\n for char in s:\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}]}, "Mbpp/766": {"dps": 57.38317757009346, "dps_norm": 52.5, "pass@1": 100.0, "profiled": [{"solution": "def pair_wise(data):\n \"\"\"\n Write a function to return a list of all pairs of consecutive items in a given list.\n assert pair_wise([1,1,2,3,3,4,4,5])==[(1, 1), (1, 2), (2, 3), (3, 3), (3, 4), (4, 4), (4, 5)]\n \"\"\"\n if not data:\n return []\n \n pairs = []\n for i in range(len(data) - 1):\n pairs.append((data[i], data[i+1]))\n return pairs", "matching_cluster_idx": 2}, {"solution": "def pair_wise(data):\n \"\"\"\n Generates a list of tuples, where each tuple contains consecutive pairs from the input list.\n\n Args:\n data: A list of any data type.\n\n Returns:\n A list of tuples, where each tuple represents a consecutive pair from the input list.\n Returns an empty list if the input list has fewer than 2 elements.\n \"\"\"\n if len(data) < 2:\n return []\n result = []\n for i in range(len(data) - 1):\n result.append((data[i], data[i+1]))\n return result", "matching_cluster_idx": 2}, {"solution": "def pair_wise(data):\n \"\"\"\n Generates a list of consecutive pairs from a given list.\n\n Args:\n data: The input list.\n\n Returns:\n A list of tuples, where each tuple represents a consecutive pair from the input list. Returns an empty list if the input list has fewer than 2 elements.\n \"\"\"\n if len(data) < 2:\n return []\n return list(zip(data, data[1:]))", "matching_cluster_idx": 5}, {"solution": "def pair_wise(items):\n \"\"\"\n Returns a list of all pairs of consecutive items in a given list.\n\n Args:\n items: A list of items.\n\n Returns:\n A list of tuples, where each tuple contains a pair of consecutive items from the input list.\n Returns an empty list if the input list has fewer than 2 items.\n \"\"\"\n if len(items) < 2:\n return []\n pairs = []\n for i in range(len(items) - 1):\n pairs.append((items[i], items[i+1]))\n return pairs", "matching_cluster_idx": 2}, {"solution": "def pair_wise(data):\n \"\"\"\n Write a function to return a list of all pairs of consecutive items in a given list.\n assert pair_wise([1,1,2,3,3,4,4,5])==[(1, 1), (1, 2), (2, 3), (3, 3), (3, 4), (4, 4), (4, 5)]\n \"\"\"\n if not data:\n return []\n \n result = []\n for i in range(len(data) - 1):\n result.append((data[i], data[i+1]))\n return result", "matching_cluster_idx": 2}, {"solution": "def pair_wise(data):\n \"\"\"\n Generates a list of consecutive item pairs from a given list.\n\n Args:\n data: A list of items.\n\n Returns:\n A list of tuples, where each tuple contains a pair of consecutive items from the input list. Returns an empty list if the input list has fewer than 2 elements.\n \"\"\"\n if len(data) < 2:\n return []\n result = []\n for i in range(len(data) - 1):\n result.append((data[i], data[i+1]))\n return result", "matching_cluster_idx": 2}, {"solution": "def pair_wise(input_list):\n \"\"\"\n Write a function to return a list of all pairs of consecutive items in a given list.\n assert pair_wise([1,1,2,3,3,4,4,5])==[(1, 1), (1, 2), (2, 3), (3, 3), (3, 4), (4, 4), (4, 5)]\n \"\"\"\n if not input_list:\n return []\n \n pairs = []\n for i in range(len(input_list) - 1):\n pairs.append((input_list[i], input_list[i+1]))\n return pairs", "matching_cluster_idx": 2}, {"solution": "def pair_wise(data):\n \"\"\"\n Generates a list of consecutive pairs from a given list.\n\n Args:\n data: The input list.\n\n Returns:\n A list of tuples, where each tuple contains a pair of consecutive items from the input list.\n Returns an empty list if the input list has fewer than 2 elements.\n\n \"\"\"\n if len(data) < 2:\n return []\n \n pairs = []\n for i in range(len(data) - 1):\n pairs.append((data[i], data[i+1]))\n return pairs", "matching_cluster_idx": 2}, {"solution": "def pair_wise(input_list):\n \"\"\"\n Write a function to return a list of all pairs of consecutive items in a given list.\n assert pair_wise([1,1,2,3,3,4,4,5])==[(1, 1), (1, 2), (2, 3), (3, 3), (3, 4), (4, 4), (4, 5)]\n \"\"\"\n if not input_list:\n return []\n \n result = []\n for i in range(len(input_list) - 1):\n result.append((input_list[i], input_list[i+1]))\n return result", "matching_cluster_idx": 2}, {"solution": "def pair_wise(input_list):\n \"\"\"\n Write a function to return a list of all pairs of consecutive items in a given list.\n assert pair_wise([1,1,2,3,3,4,4,5])==[(1, 1), (1, 2), (2, 3), (3, 3), (3, 4), (4, 4), (4, 5)]\n \"\"\"\n if not input_list:\n return []\n \n result = []\n for i in range(len(input_list) -1):\n result.append((input_list[i], input_list[i+1]))\n return result", "matching_cluster_idx": 2}, {"solution": "def pair_wise(input_list):\n \"\"\"\n Returns a list of all pairs of consecutive items in a given list.\n\n Args:\n input_list: A list of items.\n\n Returns:\n A list of tuples, where each tuple contains a pair of consecutive items from the input list.\n Returns an empty list if the input list is empty or has only one element.\n\n \"\"\"\n if len(input_list) < 2:\n return []\n \n pairs = []\n for i in range(len(input_list) - 1):\n pairs.append((input_list[i], input_list[i+1]))\n return pairs", "matching_cluster_idx": 2}, {"solution": "def pair_wise(data):\n \"\"\"\n Generates pairs of consecutive items from a list.\n\n Args:\n data: The input list.\n\n Returns:\n A list of tuples, where each tuple contains a pair of consecutive items.\n Returns an empty list if the input list has fewer than 2 elements.\n\n \"\"\"\n if len(data) < 2:\n return []\n result = []\n for i in range(len(data) - 1):\n result.append((data[i], data[i+1]))\n return result", "matching_cluster_idx": 2}, {"solution": "def pair_wise(data):\n \"\"\"\n Write a function to return a list of all pairs of consecutive items in a given list.\n assert pair_wise([1,1,2,3,3,4,4,5])==[(1, 1), (1, 2), (2, 3), (3, 3), (3, 4), (4, 4), (4, 5)]\n \"\"\"\n if not data:\n return []\n \n result = []\n for i in range(len(data) - 1):\n result.append((data[i], data[i+1]))\n return result", "matching_cluster_idx": 2}, {"solution": "def pair_wise(data):\n \"\"\"\n Returns a list of all pairs of consecutive items in a given list.\n\n Args:\n data: A list of items.\n\n Returns:\n A list of tuples, where each tuple contains a pair of consecutive items from the input list.\n Returns an empty list if the input list has fewer than 2 items.\n \"\"\"\n if len(data) < 2:\n return []\n \n result = []\n for i in range(len(data) - 1):\n result.append((data[i], data[i+1]))\n return result", "matching_cluster_idx": 2}, {"solution": "def pair_wise(input_list):\n \"\"\"\n Write a function to return a list of all pairs of consecutive items in a given list.\n assert pair_wise([1,1,2,3,3,4,4,5])==[(1, 1), (1, 2), (2, 3), (3, 3), (3, 4), (4, 4), (4, 5)]\n \"\"\"\n if not input_list:\n return []\n \n result = []\n for i in range(len(input_list) - 1):\n result.append((input_list[i], input_list[i+1]))\n return result", "matching_cluster_idx": 2}, {"solution": "def pair_wise(input_list):\n \"\"\"\n Write a function to return a list of all pairs of consecutive items in a given list.\n assert pair_wise([1,1,2,3,3,4,4,5])==[(1, 1), (1, 2), (2, 3), (3, 3), (3, 4), (4, 4), (4, 5)]\n \"\"\"\n if not input_list:\n return []\n \n pairs = []\n for i in range(len(input_list) - 1):\n pairs.append((input_list[i], input_list[i+1]))\n return pairs", "matching_cluster_idx": 2}, {"solution": "def pair_wise(items):\n \"\"\"\n Write a function to return a list of all pairs of consecutive items in a given list.\n assert pair_wise([1,1,2,3,3,4,4,5])==[(1, 1), (1, 2), (2, 3), (3, 3), (3, 4), (4, 4), (4, 5)]\n \"\"\"\n if not items:\n return []\n \n pairs = []\n for i in range(len(items) - 1):\n pairs.append((items[i], items[i+1]))\n return pairs", "matching_cluster_idx": 2}, {"solution": "def pair_wise(data):\n \"\"\"\n Returns a list of all pairs of consecutive items in a given list.\n\n Args:\n data: A list of items.\n\n Returns:\n A list of tuples, where each tuple contains a pair of consecutive items from the input list.\n Returns an empty list if the input list has fewer than 2 items.\n \"\"\"\n if len(data) < 2:\n return []\n \n pairs = []\n for i in range(len(data) - 1):\n pairs.append((data[i], data[i+1]))\n return pairs", "matching_cluster_idx": 2}, {"solution": "def pair_wise(data):\n \"\"\"\n Generates pairs of consecutive items from a list.\n\n Args:\n data: A list of items.\n\n Returns:\n A list of tuples, where each tuple contains a pair of consecutive items from the input list.\n Returns an empty list if the input list has fewer than 2 elements.\n \"\"\"\n if len(data) < 2:\n return []\n result = []\n for i in range(len(data) - 1):\n result.append((data[i], data[i+1]))\n return result", "matching_cluster_idx": 2}, {"solution": "def pair_wise(input_list):\n \"\"\"\n Write a function to return a list of all pairs of consecutive items in a given list.\n assert pair_wise([1,1,2,3,3,4,4,5])==[(1, 1), (1, 2), (2, 3), (3, 3), (3, 4), (4, 4), (4, 5)]\n \"\"\"\n if not input_list:\n return []\n \n pairs = []\n for i in range(len(input_list) - 1):\n pairs.append((input_list[i], input_list[i+1]))\n return pairs", "matching_cluster_idx": 2}]}, "Mbpp/775": {"dps": 94.39999999999999, "dps_norm": 71.42857142857143, "pass@1": 100.0, "profiled": [{"solution": "def odd_position(nums):\n \"\"\"\n Checks if every element at an odd index in a list is an odd number.\n\n Args:\n nums: A list of integers.\n\n Returns:\n True if every element at an odd index is odd, False otherwise. Returns True for empty lists.\n \"\"\"\n for i in range(1, len(nums), 2):\n if nums[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(data):\n \"\"\"\n Checks if every element at an odd index in a list is an odd number.\n\n Args:\n data: A list of numbers.\n\n Returns:\n True if every element at an odd index is odd, False otherwise. Returns True for empty lists.\n \"\"\"\n for i in range(1, len(data), 2):\n if data[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(data):\n \"\"\"\n Checks if every element at an odd index in a list is an odd number.\n\n Args:\n data: A list of integers.\n\n Returns:\n True if every element at an odd index is odd, False otherwise. Returns True for empty lists.\n \"\"\"\n if not data:\n return True\n for i in range(1, len(data), 2):\n if data[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(nums):\n \"\"\"\n Checks if every element at an odd index in a list is an odd number.\n\n Args:\n nums: A list of integers.\n\n Returns:\n True if every element at an odd index is odd, False otherwise. Returns True for empty lists.\n \"\"\"\n for i in range(1, len(nums), 2):\n if nums[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(input_list):\n \"\"\"\n Checks if every element at an odd index in a list is an odd number.\n\n Args:\n input_list: A list of integers.\n\n Returns:\n True if every element at an odd index is odd, False otherwise. Returns True for empty lists.\n \"\"\"\n if not input_list:\n return True #Handle empty list case\n\n for i in range(1, len(input_list), 2):\n if input_list[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(nums):\n \"\"\"\n Checks if every element at an odd index in a list is an odd number.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n True if every element at an odd index is odd, False otherwise.\n Returns True for empty lists.\n \"\"\"\n if not nums:\n return True\n for i in range(1, len(nums), 2):\n if nums[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(nums):\n \"\"\"\n Checks if every element at an odd index in a list is an odd number.\n\n Args:\n nums: A list of integers.\n\n Returns:\n True if every element at an odd index is odd, False otherwise. Returns True for empty lists.\n \"\"\"\n for i in range(1, len(nums), 2):\n if nums[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(data):\n \"\"\"\n Write a python function to check whether every odd index contains odd numbers of a given list.\n assert odd_position([2,1,4,3,6,7,6,3]) == True\n \"\"\"\n for i in range(1, len(data), 2):\n if data[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(data):\n \"\"\"\n Checks if every element at an odd index in a list is an odd number.\n\n Args:\n data: A list of integers.\n\n Returns:\n True if every element at an odd index is odd, False otherwise. Returns True for empty lists.\n \"\"\"\n if not data:\n return True #Empty list considered to satisfy the condition\n\n for i in range(1, len(data), 2):\n if data[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(data):\n \"\"\"\n Checks if every element at an odd index in a list is an odd number.\n\n Args:\n data: A list of integers.\n\n Returns:\n True if every element at an odd index is odd, False otherwise. Returns True for empty lists.\n \"\"\"\n if not data:\n return True\n for i in range(1, len(data), 2):\n if data[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(data):\n \"\"\"\n Checks if every element at an odd index in a list is an odd number.\n\n Args:\n data: A list of integers.\n\n Returns:\n True if every element at an odd index is odd, False otherwise. Returns True for empty lists.\n \"\"\"\n if not data:\n return True\n for i in range(1, len(data), 2):\n if data[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(data):\n \"\"\"\n Checks if every element at an odd index in a list is an odd number.\n\n Args:\n data: A list of integers.\n\n Returns:\n True if every element at an odd index is odd, False otherwise. Returns True for empty lists.\n \"\"\"\n if not data:\n return True\n for i in range(1, len(data), 2):\n if data[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(data):\n \"\"\"\n Checks if every element at an odd index in a list is an odd number.\n\n Args:\n data: A list of integers.\n\n Returns:\n True if every element at an odd index is odd, False otherwise. Returns True for empty lists.\n \"\"\"\n if not data:\n return True #Handle empty list case\n for i in range(1, len(data), 2):\n if data[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(data):\n \"\"\"\n Checks if every element at an odd index in a list is an odd number.\n\n Args:\n data: A list of integers.\n\n Returns:\n True if every element at an odd index is odd, False otherwise. Returns True for empty lists.\n \"\"\"\n if not data:\n return True\n for i in range(1, len(data), 2):\n if data[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(data):\n \"\"\"\n Checks if every element at an odd index in a list is an odd number.\n\n Args:\n data: A list of integers.\n\n Returns:\n True if every element at an odd index is odd, False otherwise. Returns True for empty lists.\n \"\"\"\n if not data:\n return True\n for i in range(1, len(data), 2):\n if data[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(data):\n \"\"\"\n Checks if every element at an odd index in a list is an odd number.\n\n Args:\n data: A list of integers.\n\n Returns:\n True if every element at an odd index is odd, False otherwise. Returns True for empty lists.\n \"\"\"\n if not data:\n return True #Handle empty list case\n for i in range(1, len(data), 2):\n if data[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(input_list):\n \"\"\"\n Checks if every element at an odd index in a list is an odd number.\n\n Args:\n input_list: A list of numbers.\n\n Returns:\n True if every element at an odd index is odd, False otherwise. Returns True for empty lists.\n \"\"\"\n for i in range(1, len(input_list), 2):\n if input_list[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(data):\n \"\"\"\n Checks if every element at an odd index in a list is an odd number.\n\n Args:\n data: A list of integers.\n\n Returns:\n True if every element at an odd index is odd, False otherwise. Returns True for empty lists.\n \"\"\"\n if not data:\n return True #Empty list satisfies the condition\n\n for i in range(1, len(data), 2):\n if data[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(data):\n \"\"\"\n Checks if every element at an odd index in a list is an odd number.\n\n Args:\n data: A list of integers.\n\n Returns:\n True if every element at an odd index is odd, False otherwise. Returns True for empty lists.\n \"\"\"\n for i in range(1, len(data), 2):\n if data[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(data):\n \"\"\"\n Checks if every element at an odd index in a list is an odd number.\n\n Args:\n data: A list of integers.\n\n Returns:\n True if every element at an odd index is odd, False otherwise. Returns True for empty lists.\n \"\"\"\n if not data:\n return True\n for i in range(1, len(data), 2):\n if data[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}]}, "Mbpp/777": {"dps": null, "dps_norm": null, "pass@1": 2.0, "profiled": []}, "Mbpp/781": {"dps": 99.48818897637796, "dps_norm": 99.0, "pass@1": 100.0, "profiled": [{"solution": "def count_divisors(n):\n \"\"\"\n Checks if the number of divisors of a given integer is even.\n\n Args:\n n: An integer greater than 0.\n\n Returns:\n True if the number of divisors is even, False otherwise. Returns False if input is invalid.\n \"\"\"\n if not isinstance(n, int) or n <= 0:\n return False\n\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n if n / i == i:\n count += 1\n else:\n count += 2\n return count % 2 == 0", "matching_cluster_idx": 4}, {"solution": "def count_divisors(n):\n \"\"\"\n Checks if the number of divisors of a given integer is even.\n\n Args:\n n: An integer greater than 0.\n\n Returns:\n True if the number of divisors is even, False otherwise. Returns False for invalid input.\n \"\"\"\n if not isinstance(n, int) or n <= 0:\n return False\n\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n if n // i == i:\n count += 1\n else:\n count += 2\n return count % 2 == 0", "matching_cluster_idx": 3}, {"solution": "def count_divisors(n):\n \"\"\"\n Checks if the number of divisors of a given integer is even.\n\n Args:\n n: An integer greater than 0.\n\n Returns:\n True if the number of divisors is even, False otherwise. Returns False if input is invalid.\n \"\"\"\n if not isinstance(n, int) or n <= 0:\n return False\n\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n if n // i == i:\n count += 1\n else:\n count += 2\n return count % 2 == 0", "matching_cluster_idx": 4}, {"solution": "def count_divisors(n):\n \"\"\"\n Checks if the number of divisors of a given integer is even.\n\n Args:\n n: An integer greater than 0.\n\n Returns:\n True if the number of divisors is even, False otherwise. Returns False for n <= 0.\n \"\"\"\n if n <= 0:\n return False\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n if n / i == i:\n count += 1\n else:\n count += 2\n return count % 2 == 0", "matching_cluster_idx": 4}, {"solution": "def count_divisors(n):\n \"\"\"\n Checks if the number of divisors of a given integer is even.\n\n Args:\n n: The integer to check.\n\n Returns:\n True if the number of divisors is even, False otherwise. Returns False if n <=0.\n \"\"\"\n if n <= 0:\n return False\n\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n if n / i == i:\n count += 1\n else:\n count += 2\n return count % 2 == 0", "matching_cluster_idx": 4}, {"solution": "def count_divisors(n):\n \"\"\"\n Checks if the count of divisors of a number is even.\n\n Args:\n n: An integer greater than 0.\n\n Returns:\n True if the number of divisors is even, False otherwise. Returns False if input is invalid.\n\n \"\"\"\n if not isinstance(n, int) or n <= 0:\n return False\n\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n if n // i == i:\n count += 1\n else:\n count += 2\n return count % 2 == 0", "matching_cluster_idx": 4}, {"solution": "def count_divisors(n):\n \"\"\"\n Checks if the number of divisors of a given number is even.\n\n Args:\n n: An integer greater than 0.\n\n Returns:\n True if the number of divisors is even, False otherwise. Returns False for invalid input.\n \"\"\"\n if not isinstance(n, int) or n <= 0:\n return False\n\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n if n // i == i:\n count += 1\n else:\n count += 2\n return count % 2 == 0", "matching_cluster_idx": 4}, {"solution": "def count_divisors(n):\n \"\"\"\n Checks if the number of divisors of a given integer is even.\n\n Args:\n n: An integer greater than 0.\n\n Returns:\n True if the number of divisors is even, False otherwise. Returns False for n <=0.\n\n \"\"\"\n if n <= 0:\n return False\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n if n // i == i:\n count += 1\n else:\n count += 2\n return count % 2 == 0", "matching_cluster_idx": 4}, {"solution": "def count_divisors(n):\n \"\"\"\n Checks if the number of divisors of a given integer is even.\n\n Args:\n n: An integer greater than 0.\n\n Returns:\n True if the number of divisors is even, False otherwise. Returns False if input is invalid.\n \"\"\"\n if not isinstance(n, int) or n <= 0:\n return False\n\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n if n // i == i:\n count += 1\n else:\n count += 2\n return count % 2 == 0", "matching_cluster_idx": 4}, {"solution": "def count_divisors(n):\n \"\"\"\n Checks whether the count of divisors of a number is even.\n\n Args:\n n: The input integer.\n\n Returns:\n True if the count of divisors is even, False otherwise. Returns False for n <= 0.\n \"\"\"\n if n <= 0:\n return False # Handle non-positive inputs\n\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n if n // i == i:\n count += 1\n else:\n count += 2\n return count % 2 == 0", "matching_cluster_idx": 4}, {"solution": "def count_divisors(n):\n \"\"\"\n Checks whether the count of divisors of a number is even.\n\n Args:\n n: The input number.\n\n Returns:\n True if the count of divisors is even, False otherwise. Returns False for n <=0\n \"\"\"\n if n <= 0:\n return False\n\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n if n / i == i:\n count += 1\n else:\n count += 2\n return count % 2 == 0", "matching_cluster_idx": 4}, {"solution": "def count_divisors(n):\n \"\"\"\n Checks whether the count of divisors of a number is even.\n\n Args:\n n: An integer greater than 0.\n\n Returns:\n True if the count of divisors is even, False otherwise. Returns False for invalid input.\n \"\"\"\n if not isinstance(n, int) or n <= 0:\n return False\n\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n if n // i == i:\n count += 1\n else:\n count += 2\n return count % 2 == 0", "matching_cluster_idx": 4}, {"solution": "def count_divisors(n):\n \"\"\"\n Checks if the number of divisors of a given integer is even.\n\n Args:\n n: The input integer.\n\n Returns:\n True if the number of divisors is even, False otherwise. Returns False if n <=0.\n \"\"\"\n if n <= 0:\n return False\n\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n if n / i == i:\n count += 1\n else:\n count += 2\n return count % 2 == 0", "matching_cluster_idx": 4}, {"solution": "def count_divisors(n):\n \"\"\"\n Checks if the number of divisors of a given integer is even.\n\n Args:\n n: The input integer.\n\n Returns:\n True if the number of divisors is even, False otherwise. Returns False for n <= 0.\n \"\"\"\n if n <= 0:\n return False\n\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n if n // i == i:\n count += 1\n else:\n count += 2\n return count % 2 == 0", "matching_cluster_idx": 4}, {"solution": "def count_divisors(n):\n \"\"\"\n Checks if the number of divisors of a given integer is even.\n\n Args:\n n: An integer greater than 0.\n\n Returns: \n True if the number of divisors is even, False otherwise. Returns False if input is invalid.\n \"\"\"\n if not isinstance(n, int) or n <= 0:\n return False\n\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n if n / i == i: # Handle perfect squares\n count += 1\n else:\n count += 2\n return count % 2 == 0", "matching_cluster_idx": 4}, {"solution": "def count_divisors(n):\n \"\"\"\n Checks if the number of divisors of a given integer is even.\n\n Args:\n n: The input integer.\n\n Returns: \n True if the count of divisors is even, False otherwise. Returns False if n is less than 1.\n \"\"\"\n if n < 1:\n return False\n\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n if n / i == i:\n count += 1\n else:\n count += 2\n return count % 2 == 0", "matching_cluster_idx": 4}, {"solution": "def count_divisors(n):\n \"\"\"\n Checks whether the count of divisors of a number is even.\n\n Args:\n n: The input integer.\n\n Returns:\n True if the number of divisors is even, False otherwise. Returns False for n <= 0.\n \"\"\"\n if n <= 0:\n return False\n\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n if n // i == i:\n count += 1\n else:\n count += 2\n return count % 2 == 0", "matching_cluster_idx": 4}, {"solution": "def count_divisors(n):\n \"\"\"\n Checks if the number of divisors of a given integer is even.\n\n Args:\n n: The input integer.\n\n Returns:\n True if the count of divisors is even, False otherwise. Returns False for n <= 0.\n \"\"\"\n if n <= 0:\n return False\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n if n / i == i:\n count += 1\n else:\n count += 2\n return count % 2 == 0", "matching_cluster_idx": 4}, {"solution": "def count_divisors(n):\n \"\"\"\n Checks if the number of divisors of a given integer is even.\n\n Args:\n n: An integer greater than 0.\n\n Returns:\n True if the count of divisors is even, False otherwise. Returns False for invalid input.\n \"\"\"\n if not isinstance(n, int) or n <= 0:\n return False\n\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n if n / i == i:\n count += 1\n else:\n count += 2\n return count % 2 == 0", "matching_cluster_idx": 4}, {"solution": "def count_divisors(n):\n \"\"\"\n Checks if the number of divisors of a given integer is even.\n\n Args:\n n: An integer greater than 0.\n\n Returns:\n True if the number of divisors is even, False otherwise. Returns False if n <=0.\n \"\"\"\n if n <= 0:\n return False\n\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n if n // i == i:\n count += 1\n else:\n count += 2\n return count % 2 == 0", "matching_cluster_idx": 4}]}, "Mbpp/800": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 12.0, "profiled": [{"solution": "def remove_all_spaces(input_string):\n \"\"\"\n Removes all whitespace characters from a string.\n\n Args:\n input_string: The input string.\n\n Returns:\n The string with all whitespace characters removed.\n \"\"\"\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n \"\"\"Removes all whitespace characters from a string.\n\n Args:\n input_string: The input string.\n\n Returns:\n The string with all whitespace characters removed.\n \"\"\"\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n \"\"\"\n Removes all whitespace characters from a string.\n\n Args:\n input_string: The input string.\n\n Returns:\n The string with all whitespace characters removed.\n \"\"\"\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n \"\"\"Removes all whitespace characters from a string.\n\n Args:\n input_string: The input string.\n\n Returns:\n The string with all whitespace characters removed.\n \"\"\"\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n \"\"\"\n Removes all whitespace characters from a string.\n\n Args:\n input_string: The string to remove whitespace from.\n\n Returns:\n The string with all whitespace characters removed.\n \"\"\"\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n \"\"\"\n Removes all whitespace characters from a string.\n\n Args:\n input_string: The input string.\n\n Returns:\n The string with all whitespace characters removed.\n \"\"\"\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n \"\"\"Removes all whitespace characters from a string.\n\n Args:\n input_string: The input string.\n\n Returns:\n The string with all whitespace characters removed.\n \"\"\"\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n \"\"\"\n Removes all whitespace characters from a string.\n\n Args:\n input_string: The input string.\n\n Returns:\n The string with all whitespace characters removed.\n \"\"\"\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n \"\"\"\n Removes all whitespace characters from a string.\n\n Args:\n input_string: The input string.\n\n Returns:\n The string with all whitespace characters removed.\n \"\"\"\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n \"\"\"Removes all whitespace characters from a string.\n\n Args:\n input_string: The input string.\n\n Returns:\n The string with all whitespace characters removed.\n \"\"\"\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n \"\"\"\n Removes all whitespace characters from a string.\n\n Args:\n input_string: The input string.\n\n Returns:\n The string with all whitespace characters removed.\n \"\"\"\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n \"\"\"\n Removes all whitespace characters from a string.\n\n Args:\n input_string: The input string.\n\n Returns:\n A new string with all whitespace characters removed.\n \"\"\"\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}]}, "Mbpp/805": {"dps": 55.30927835051546, "dps_norm": 64.0, "pass@1": 100.0, "profiled": [{"solution": "def max_sum_list(list_of_lists):\n \"\"\"\n Finds the list in a list of lists with the highest sum of elements.\n\n Args:\n list_of_lists: A list of lists of numbers.\n\n Returns:\n The list with the highest sum of elements. Returns an empty list if the input is empty.\n Raises TypeError if input is not a list of lists of numbers.\n\n \"\"\"\n if not isinstance(list_of_lists, list):\n raise TypeError(\"Input must be a list of lists.\")\n if not all(isinstance(sublist, list) for sublist in list_of_lists):\n raise TypeError(\"Input must be a list of lists.\")\n if not all(all(isinstance(item, (int, float)) for item in sublist) for sublist in list_of_lists):\n raise TypeError(\"Input lists must contain only numbers.\")\n\n\n if not list_of_lists:\n return []\n\n max_sum = -float('inf') # Initialize with negative infinity\n max_list = []\n\n for lst in list_of_lists:\n current_sum = sum(lst)\n if current_sum > max_sum:\n max_sum = current_sum\n max_list = lst\n\n return max_list", "matching_cluster_idx": 0}, {"solution": "def max_sum_list(list_of_lists):\n \"\"\"\n Finds the list with the maximum sum of elements within a list of lists.\n\n Args:\n list_of_lists: A list of lists, where each inner list contains numbers.\n\n Returns:\n The list with the highest sum of its elements. Returns an empty list if the input is empty or invalid.\n \"\"\"\n if not list_of_lists:\n return []\n \n max_sum = -float('inf') # Initialize with negative infinity to handle negative numbers\n max_list = []\n\n for lst in list_of_lists:\n if not all(isinstance(x, (int, float)) for x in lst): #check if all elements are numbers\n return []\n current_sum = sum(lst)\n if current_sum > max_sum:\n max_sum = current_sum\n max_list = lst\n return max_list", "matching_cluster_idx": 0}, {"solution": "def max_sum_list(list_of_lists):\n \"\"\"\n Finds the list with the maximum sum of its elements within a list of lists.\n\n Args:\n list_of_lists: A list of lists, where each inner list contains numbers.\n\n Returns:\n The inner list with the highest sum of its elements. Returns an empty list if the input is empty or invalid.\n \"\"\"\n if not list_of_lists:\n return []\n\n max_sum = -float('inf') # Initialize with negative infinity to handle negative numbers\n max_list = []\n\n for lst in list_of_lists:\n if not isinstance(lst, list):\n return [] #handle invalid input\n current_sum = sum(lst)\n if current_sum > max_sum:\n max_sum = current_sum\n max_list = lst\n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(list_of_lists):\n \"\"\"\n Finds the list in a list of lists whose sum of elements is the highest.\n\n Args:\n list_of_lists: A list of lists of numbers.\n\n Returns:\n The list with the highest sum of elements. Returns an empty list if the input is empty or invalid.\n \"\"\"\n if not list_of_lists:\n return []\n\n if not all(isinstance(sublist, list) for sublist in list_of_lists):\n return [] # Handle cases with non-list elements\n\n max_sum = -float('inf') # Initialize with negative infinity\n max_list = []\n\n for sublist in list_of_lists:\n try:\n current_sum = sum(sublist)\n except TypeError:\n return [] # Handle cases with non-numeric elements in sublists\n\n if current_sum > max_sum:\n max_sum = current_sum\n max_list = sublist\n\n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(list_of_lists):\n \"\"\"\n Finds the list with the maximum sum of elements in a list of lists.\n\n Args:\n list_of_lists: A list of lists, where each inner list contains numbers.\n\n Returns:\n The list with the highest sum of its elements. Returns an empty list if the input is empty.\n \"\"\"\n if not list_of_lists:\n return []\n\n max_sum = -float('inf') # Initialize with negative infinity\n max_list = []\n\n for lst in list_of_lists:\n current_sum = sum(lst)\n if current_sum > max_sum:\n max_sum = current_sum\n max_list = lst\n\n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(list_of_lists):\n \"\"\"\n Finds the list with the maximum sum of its elements within a list of lists.\n\n Args:\n list_of_lists: A list of lists, where each inner list contains numbers.\n\n Returns:\n The list with the highest sum of its elements. Returns an empty list if the input is empty or invalid.\n\n \"\"\"\n if not list_of_lists:\n return []\n\n max_sum = -float('inf') # Initialize with negative infinity to handle negative numbers\n max_list = []\n\n for lst in list_of_lists:\n if not all(isinstance(x, (int, float)) for x in lst): #Check for valid numeric input\n return []\n current_sum = sum(lst)\n if current_sum > max_sum:\n max_sum = current_sum\n max_list = lst\n return max_list", "matching_cluster_idx": 0}, {"solution": "def max_sum_list(list_of_lists):\n \"\"\"\n Finds the list in a list of lists with the highest sum of elements.\n\n Args:\n list_of_lists: A list of lists of numbers.\n\n Returns:\n The list with the highest sum of elements. Returns an empty list if the input is empty or invalid.\n\n \"\"\"\n if not list_of_lists:\n return []\n\n if not all(isinstance(inner_list, list) for inner_list in list_of_lists):\n return []\n\n if not all(all(isinstance(num, (int, float)) for num in inner_list) for inner_list in list_of_lists):\n return []\n\n\n max_sum = -float('inf')\n max_list = []\n\n for lst in list_of_lists:\n current_sum = sum(lst)\n if current_sum > max_sum:\n max_sum = current_sum\n max_list = lst\n\n return max_list", "matching_cluster_idx": 0}, {"solution": "def max_sum_list(list_of_lists):\n \"\"\"\n Finds the list with the maximum sum of elements in a list of lists.\n\n Args:\n list_of_lists: A list of lists of numbers.\n\n Returns:\n The list with the maximum sum of elements. Returns an empty list if the input is empty or invalid.\n \"\"\"\n if not list_of_lists:\n return []\n\n max_sum = -float('inf') # Initialize with negative infinity to handle negative numbers\n max_list = []\n\n for lst in list_of_lists:\n if not all(isinstance(x, (int, float)) for x in lst): #check for valid input\n return []\n current_sum = sum(lst)\n if current_sum > max_sum:\n max_sum = current_sum\n max_list = lst\n\n return max_list", "matching_cluster_idx": 0}, {"solution": "def max_sum_list(list_of_lists):\n \"\"\"\n Finds the list with the maximum sum of elements in a list of lists.\n\n Args:\n list_of_lists: A list of lists, where each inner list contains numbers.\n\n Returns:\n The list with the highest sum of its elements. Returns an empty list if the input is empty.\n \"\"\"\n if not list_of_lists:\n return []\n\n max_sum = -float('inf') # Initialize with negative infinity\n max_list = []\n\n for lst in list_of_lists:\n current_sum = sum(lst)\n if current_sum > max_sum:\n max_sum = current_sum\n max_list = lst\n\n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(list_of_lists):\n \"\"\"\n Finds the list with the maximum sum of elements in a list of lists.\n\n Args:\n list_of_lists: A list of lists of numbers.\n\n Returns:\n The list with the highest sum of its elements. Returns an empty list if the input is empty.\n \"\"\"\n if not list_of_lists:\n return []\n\n max_sum = -float('inf') # Initialize with negative infinity\n max_list = []\n\n for lst in list_of_lists:\n current_sum = sum(lst)\n if current_sum > max_sum:\n max_sum = current_sum\n max_list = lst\n\n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(list_of_lists):\n \"\"\"\n Finds the list with the maximum sum of elements in a list of lists.\n\n Args:\n list_of_lists: A list of lists of numbers.\n\n Returns:\n The list with the maximum sum of elements. Returns an empty list if the input is empty.\n \"\"\"\n if not list_of_lists:\n return []\n\n max_sum = -float('inf') # Initialize with negative infinity\n max_list = []\n\n for lst in list_of_lists:\n current_sum = sum(lst)\n if current_sum > max_sum:\n max_sum = current_sum\n max_list = lst\n\n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(list_of_lists):\n \"\"\"\n Finds the list with the maximum sum of elements within a list of lists.\n\n Args:\n list_of_lists: A list of lists of numbers.\n\n Returns:\n The list with the highest sum of its elements. Returns an empty list if the input is empty or invalid.\n \"\"\"\n if not list_of_lists:\n return []\n\n max_sum = -float('inf') # Initialize with negative infinity to handle negative numbers\n max_list = []\n\n for lst in list_of_lists:\n if not isinstance(lst, list):\n return [] #Handle invalid input\n current_sum = sum(lst)\n if current_sum > max_sum:\n max_sum = current_sum\n max_list = lst\n\n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(list_of_lists):\n \"\"\"\n Finds the list with the maximum sum of elements in a list of lists.\n\n Args:\n list_of_lists: A list of lists, where each inner list contains numbers.\n\n Returns:\n The list with the maximum sum of its elements. Returns an empty list if the input is empty or invalid.\n \"\"\"\n if not list_of_lists:\n return []\n\n max_sum = -float('inf') # Initialize with negative infinity\n max_list = []\n\n for lst in list_of_lists:\n if not all(isinstance(x, (int, float)) for x in lst): #check if all elements are numbers.\n return []\n current_sum = sum(lst)\n if current_sum > max_sum:\n max_sum = current_sum\n max_list = lst\n\n return max_list", "matching_cluster_idx": 0}, {"solution": "def max_sum_list(list_of_lists):\n \"\"\"\n Finds the list in a list of lists with the highest sum of elements.\n\n Args:\n list_of_lists: A list of lists of numbers.\n\n Returns:\n The list with the highest sum of elements. Returns an empty list if the input is empty.\n Raises TypeError if input is not a list of lists of numbers.\n\n \"\"\"\n if not isinstance(list_of_lists, list):\n raise TypeError(\"Input must be a list of lists.\")\n if not all(isinstance(sublist, list) for sublist in list_of_lists):\n raise TypeError(\"Input must be a list of lists.\")\n if not all(all(isinstance(num, (int, float)) for num in sublist) for sublist in list_of_lists):\n raise TypeError(\"Input lists must contain only numbers.\")\n\n\n if not list_of_lists:\n return []\n\n max_sum = -float('inf') # Initialize with negative infinity\n max_list = []\n\n for lst in list_of_lists:\n current_sum = sum(lst)\n if current_sum > max_sum:\n max_sum = current_sum\n max_list = lst\n\n return max_list", "matching_cluster_idx": 0}, {"solution": "def max_sum_list(list_of_lists):\n \"\"\"\n Finds the list with the maximum sum of elements within a list of lists.\n\n Args:\n list_of_lists: A list of lists, where each inner list contains numbers.\n\n Returns:\n The list with the highest sum of its elements. Returns an empty list if the input is empty or invalid.\n\n \"\"\"\n if not list_of_lists:\n return []\n\n if not all(isinstance(inner_list, list) for inner_list in list_of_lists):\n return []\n\n if not all(all(isinstance(num, (int, float)) for num in inner_list) for inner_list in list_of_lists):\n return []\n\n\n max_sum = -float('inf') # Initialize with negative infinity\n max_list = []\n\n for lst in list_of_lists:\n current_sum = sum(lst)\n if current_sum > max_sum:\n max_sum = current_sum\n max_list = lst\n\n return max_list", "matching_cluster_idx": 0}, {"solution": "def max_sum_list(list_of_lists):\n \"\"\"\n Finds the list with the maximum sum of elements in a list of lists.\n\n Args:\n list_of_lists: A list of lists of numbers.\n\n Returns:\n The list with the maximum sum of elements. Returns an empty list if the input is empty or invalid.\n \"\"\"\n if not list_of_lists:\n return []\n\n max_sum = -float('inf') # Initialize with negative infinity\n max_list = []\n\n for lst in list_of_lists:\n if not isinstance(lst, list):\n return [] #Handle cases with non-list elements.\n current_sum = sum(lst)\n if current_sum > max_sum:\n max_sum = current_sum\n max_list = lst\n\n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(list_of_lists):\n \"\"\"\n Finds the list in a list of lists with the highest sum of elements.\n\n Args:\n list_of_lists: A list of lists of numbers.\n\n Returns:\n The list with the highest sum of elements. Returns an empty list if the input is empty.\n Raises TypeError if input is not a list of lists of numbers.\n\n \"\"\"\n if not isinstance(list_of_lists, list):\n raise TypeError(\"Input must be a list of lists.\")\n if not all(isinstance(inner_list, list) for inner_list in list_of_lists):\n raise TypeError(\"Input must be a list of lists.\")\n if not all(all(isinstance(num, (int, float)) for num in inner_list) for inner_list in list_of_lists):\n raise TypeError(\"Inner lists must contain only numbers.\")\n\n\n if not list_of_lists:\n return []\n\n max_sum = -float('inf') # Initialize with negative infinity\n max_list = []\n\n for lst in list_of_lists:\n current_sum = sum(lst)\n if current_sum > max_sum:\n max_sum = current_sum\n max_list = lst\n\n return max_list", "matching_cluster_idx": 0}, {"solution": "def max_sum_list(list_of_lists):\n \"\"\"\n Finds the list with the maximum sum of elements in a list of lists.\n\n Args:\n list_of_lists: A list of lists of numbers.\n\n Returns:\n The list with the highest sum of its elements. Returns an empty list if the input is empty.\n \"\"\"\n if not list_of_lists:\n return []\n\n max_sum = -float('inf') # Initialize with negative infinity to handle negative numbers\n max_list = []\n\n for lst in list_of_lists:\n current_sum = sum(lst)\n if current_sum > max_sum:\n max_sum = current_sum\n max_list = lst\n\n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(list_of_lists):\n \"\"\"\n Finds the list with the maximum sum of elements in a list of lists.\n\n Args:\n list_of_lists: A list of lists of numbers.\n\n Returns:\n The list with the maximum sum of elements. Returns an empty list if the input is empty or invalid.\n \"\"\"\n if not list_of_lists:\n return []\n if not all(isinstance(sublist, list) for sublist in list_of_lists):\n return [] #Handle invalid input\n\n max_sum = -float('inf') # Initialize with negative infinity\n max_list = []\n\n for lst in list_of_lists:\n current_sum = sum(lst)\n if current_sum > max_sum:\n max_sum = current_sum\n max_list = lst\n\n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(list_of_lists):\n \"\"\"\n Finds the list in a list of lists with the highest sum of elements.\n\n Args:\n list_of_lists: A list of lists of numbers.\n\n Returns:\n The list with the highest sum of elements. Returns an empty list if the input is empty.\n \"\"\"\n if not list_of_lists:\n return []\n\n max_sum = -float('inf') # Initialize with negative infinity to handle negative numbers\n max_list = []\n\n for lst in list_of_lists:\n current_sum = sum(lst)\n if current_sum > max_sum:\n max_sum = current_sum\n max_list = lst\n\n return max_list", "matching_cluster_idx": 4}]}, "Mbpp/808": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def check_K(tuple_data, k):\n \"\"\"\n Checks if a given tuple contains a specific element k.\n\n Args:\n tuple_data: The input tuple.\n k: The element to check for.\n\n Returns:\n True if the tuple contains k, False otherwise.\n \"\"\"\n return k in tuple_data", "matching_cluster_idx": 5}, {"solution": "def check_K(input_tuple, k):\n \"\"\"\n Checks if a given tuple contains a specific element k.\n\n Args:\n input_tuple: The tuple to search within.\n k: The element to search for.\n\n Returns:\n True if the tuple contains k, False otherwise.\n \"\"\"\n return k in input_tuple", "matching_cluster_idx": 5}, {"solution": "def check_K(input_tuple, k):\n \"\"\"\n Checks if a given tuple contains a specific element k.\n\n Args:\n input_tuple: The input tuple to search.\n k: The element to search for.\n\n Returns:\n True if the tuple contains k, False otherwise.\n \"\"\"\n return k in input_tuple", "matching_cluster_idx": 5}, {"solution": "def check_K(input_tuple, k):\n \"\"\"\n Checks if a given tuple contains a specific element k.\n\n Args:\n input_tuple: The input tuple.\n k: The element to search for.\n\n Returns:\n True if the tuple contains k, False otherwise.\n \"\"\"\n return k in input_tuple", "matching_cluster_idx": 5}, {"solution": "def check_K(input_tuple, k):\n \"\"\"\n Checks if a given tuple contains a specific value k.\n\n Args:\n input_tuple: The tuple to search within.\n k: The value to search for.\n\n Returns:\n True if the tuple contains k, False otherwise.\n \"\"\"\n return k in input_tuple", "matching_cluster_idx": 5}, {"solution": "def check_K(input_tuple, k):\n \"\"\"\n Checks if a given tuple contains a specific element k.\n\n Args:\n input_tuple: The input tuple to search.\n k: The element to search for.\n\n Returns:\n True if the tuple contains k, False otherwise.\n \"\"\"\n return k in input_tuple", "matching_cluster_idx": 5}, {"solution": "def check_K(my_tuple, k):\n \"\"\"\n Checks if a given tuple contains a specific element k.\n\n Args:\n my_tuple: The input tuple.\n k: The element to search for.\n\n Returns:\n True if the tuple contains k, False otherwise.\n \"\"\"\n return k in my_tuple", "matching_cluster_idx": 5}, {"solution": "def check_K(input_tuple, k):\n \"\"\"\n Checks if a given tuple contains a specific element k.\n\n Args:\n input_tuple: The input tuple.\n k: The element to search for.\n\n Returns:\n True if the tuple contains k, False otherwise.\n \"\"\"\n return k in input_tuple", "matching_cluster_idx": 5}, {"solution": "def check_K(tuple_data, k):\n \"\"\"\n Checks if a given tuple contains a specific element k.\n\n Args:\n tuple_data: The input tuple.\n k: The element to search for.\n\n Returns:\n True if the tuple contains k, False otherwise.\n \"\"\"\n return k in tuple_data", "matching_cluster_idx": 5}, {"solution": "def check_K(input_tuple, k):\n \"\"\"\n Checks if a given tuple contains a specific value k.\n\n Args:\n input_tuple: The tuple to search within.\n k: The value to search for.\n\n Returns:\n True if the tuple contains k, False otherwise.\n \"\"\"\n return k in input_tuple", "matching_cluster_idx": 5}, {"solution": "def check_K(my_tuple, k):\n \"\"\"\n Checks if a given tuple contains a specific element k.\n\n Args:\n my_tuple: The input tuple.\n k: The element to search for.\n\n Returns:\n True if the tuple contains k, False otherwise.\n \"\"\"\n return k in my_tuple", "matching_cluster_idx": 5}, {"solution": "def check_K(input_tuple, k):\n \"\"\"\n Checks if a given tuple contains a specific element k.\n\n Args:\n input_tuple: The input tuple to search.\n k: The element to search for.\n\n Returns:\n True if the tuple contains k, False otherwise.\n \"\"\"\n return k in input_tuple", "matching_cluster_idx": 5}, {"solution": "def check_K(input_tuple, k):\n \"\"\"\n Checks if a given tuple contains a specific value k.\n\n Args:\n input_tuple: The input tuple to search.\n k: The value to search for.\n\n Returns:\n True if the tuple contains k, False otherwise.\n \"\"\"\n return k in input_tuple", "matching_cluster_idx": 5}, {"solution": "def check_K(input_tuple, k):\n \"\"\"\n Checks if a given tuple contains a specific element k.\n\n Args:\n input_tuple: The tuple to search within.\n k: The element to search for.\n\n Returns:\n True if k is found in the tuple, False otherwise.\n \"\"\"\n return k in input_tuple", "matching_cluster_idx": 5}, {"solution": "def check_K(my_tuple, k):\n \"\"\"\n Checks if a given tuple contains a specific value k.\n\n Args:\n my_tuple: The input tuple.\n k: The value to search for.\n\n Returns:\n True if the tuple contains k, False otherwise.\n \"\"\"\n return k in my_tuple", "matching_cluster_idx": 5}, {"solution": "def check_K(input_tuple, k):\n \"\"\"\n Checks if a given tuple contains a specific element k.\n\n Args:\n input_tuple: The tuple to search within.\n k: The element to search for.\n\n Returns:\n True if the tuple contains k, False otherwise.\n \"\"\"\n return k in input_tuple", "matching_cluster_idx": 5}, {"solution": "def check_K(my_tuple, k):\n \"\"\"\n Write a function to check if the given tuples contain the k or not.\n assert check_K((10, 4, 5, 6, 8), 6) == True\n \"\"\"\n return k in my_tuple", "matching_cluster_idx": 5}, {"solution": "def check_K(input_tuple, k):\n \"\"\"\n Checks if a given tuple contains a specific element k.\n\n Args:\n input_tuple: The input tuple to search.\n k: The element to search for.\n\n Returns:\n True if the tuple contains k, False otherwise.\n \"\"\"\n return k in input_tuple", "matching_cluster_idx": 5}, {"solution": "def check_K(my_tuple, k):\n \"\"\"\n Checks if a given tuple contains a specific element k.\n\n Args:\n my_tuple: The input tuple.\n k: The element to search for.\n\n Returns:\n True if the tuple contains k, False otherwise.\n \"\"\"\n return k in my_tuple", "matching_cluster_idx": 5}, {"solution": "def check_K(input_tuple, k):\n \"\"\"\n Checks if a given tuple contains a specific value k.\n\n Args:\n input_tuple: The input tuple to search.\n k: The value to search for.\n\n Returns:\n True if the tuple contains k, False otherwise.\n \"\"\"\n return k in input_tuple", "matching_cluster_idx": 5}]}}} \ No newline at end of file diff --git a/results/evalperf/gemini-1.5-pro-002_google_temp_1.0_evalperf_results.brief.json b/results/evalperf/gemini-1.5-pro-002_google_temp_1.0_evalperf_results.brief.json new file mode 100644 index 0000000..61b0105 --- /dev/null +++ b/results/evalperf/gemini-1.5-pro-002_google_temp_1.0_evalperf_results.brief.json @@ -0,0 +1 @@ +{"date": "2024-10-19 16:27", "config": {"n_samples": 100, "temperature": 1.0, "min_correct": 10, "max_profile": 20}, "summary": {"dps": 76.26393608564656, "dps_norm": 75.16850711244093, "pass@1": 83.71186440677967}, "eval": {"HumanEval/9": {"dps": 63.09148264984227, "dps_norm": 55.55555555555556, "pass@1": 100.0, "profiled": [{"solution": "from typing import List, Tuple\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n rolling_max_list = []\n current_max = float('-inf')\n for number in numbers:\n current_max = max(current_max, number)\n rolling_max_list.append(current_max)\n return rolling_max_list", "matching_cluster_idx": 4}, {"solution": "from typing import List, Tuple\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n rolling_max_list = []\n current_max = float('-inf')\n for number in numbers:\n current_max = max(current_max, number)\n rolling_max_list.append(current_max)\n return rolling_max_list", "matching_cluster_idx": 4}, {"solution": "from typing import List, Tuple\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n rolling_max_list = []\n current_max = float('-inf')\n for number in numbers:\n current_max = max(current_max, number)\n rolling_max_list.append(current_max)\n return rolling_max_list", "matching_cluster_idx": 4}, {"solution": "from typing import List, Tuple\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n rolling_max_list = []\n current_max = float('-inf') # Initialize with negative infinity\n\n for number in numbers:\n current_max = max(current_max, number)\n rolling_max_list.append(current_max)\n\n return rolling_max_list", "matching_cluster_idx": 4}, {"solution": "from typing import List, Tuple\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n rolling_max_list = []\n current_max = float('-inf')\n for number in numbers:\n current_max = max(current_max, number)\n rolling_max_list.append(current_max)\n return rolling_max_list", "matching_cluster_idx": 4}, {"solution": "from typing import List, Tuple\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n rolling_max_list = []\n current_max = float('-inf') # Initialize with negative infinity\n\n for number in numbers:\n current_max = max(current_max, number)\n rolling_max_list.append(current_max)\n\n return rolling_max_list", "matching_cluster_idx": 4}, {"solution": "from typing import List, Tuple\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n rolling_max_list = []\n current_max = float('-inf') # Initialize with negative infinity\n\n for number in numbers:\n current_max = max(current_max, number)\n rolling_max_list.append(current_max)\n\n return rolling_max_list", "matching_cluster_idx": 4}, {"solution": "from typing import List, Tuple\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n rolling_max_list = []\n current_max = float('-inf')\n for number in numbers:\n current_max = max(current_max, number)\n rolling_max_list.append(current_max)\n return rolling_max_list", "matching_cluster_idx": 4}, {"solution": "from typing import List, Tuple\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n rolling_max_list = []\n current_max = float('-inf') # Initialize with negative infinity\n\n for number in numbers:\n current_max = max(current_max, number)\n rolling_max_list.append(current_max)\n\n return rolling_max_list", "matching_cluster_idx": 4}, {"solution": "from typing import List, Tuple\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n rolling_max_list = []\n current_max = float('-inf')\n for number in numbers:\n current_max = max(current_max, number)\n rolling_max_list.append(current_max)\n return rolling_max_list", "matching_cluster_idx": 4}, {"solution": "from typing import List, Tuple\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n rolling_max_list = []\n current_max = float('-inf') # Initialize with negative infinity\n\n for number in numbers:\n current_max = max(current_max, number)\n rolling_max_list.append(current_max)\n\n return rolling_max_list", "matching_cluster_idx": 4}, {"solution": "from typing import List, Tuple\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n rolling_max_list = []\n current_max = float('-inf')\n\n for number in numbers:\n current_max = max(current_max, number)\n rolling_max_list.append(current_max)\n\n return rolling_max_list", "matching_cluster_idx": 4}, {"solution": "from typing import List, Tuple\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n rolling_max_list = []\n current_max = float('-inf')\n\n for number in numbers:\n current_max = max(current_max, number)\n rolling_max_list.append(current_max)\n \n return rolling_max_list", "matching_cluster_idx": 4}, {"solution": "from typing import List, Tuple\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n rolling_max_list = []\n current_max = float('-inf')\n for number in numbers:\n current_max = max(current_max, number)\n rolling_max_list.append(current_max)\n return rolling_max_list", "matching_cluster_idx": 4}, {"solution": "from typing import List, Tuple\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n rolling_max_list = []\n current_max = float('-inf')\n\n for number in numbers:\n current_max = max(current_max, number)\n rolling_max_list.append(current_max)\n\n return rolling_max_list", "matching_cluster_idx": 4}, {"solution": "from typing import List, Tuple\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n rolling_max_list = []\n current_max = float('-inf') # Initialize with negative infinity\n\n for number in numbers:\n current_max = max(current_max, number)\n rolling_max_list.append(current_max)\n\n return rolling_max_list", "matching_cluster_idx": 4}, {"solution": "from typing import List, Tuple\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n\n rolling_max_list = []\n current_max = numbers[0]\n for number in numbers:\n current_max = max(current_max, number)\n rolling_max_list.append(current_max)\n return rolling_max_list", "matching_cluster_idx": 4}, {"solution": "from typing import List, Tuple\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n rolling_max_list = []\n current_max = float('-inf')\n\n for number in numbers:\n current_max = max(current_max, number)\n rolling_max_list.append(current_max)\n \n return rolling_max_list", "matching_cluster_idx": 4}, {"solution": "from typing import List, Tuple\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n rolling_max_list = []\n current_max = float('-inf')\n for number in numbers:\n current_max = max(current_max, number)\n rolling_max_list.append(current_max)\n return rolling_max_list", "matching_cluster_idx": 4}, {"solution": "from typing import List, Tuple\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n rolling_max_list = []\n current_max = float('-inf')\n for number in numbers:\n current_max = max(current_max, number)\n rolling_max_list.append(current_max)\n return rolling_max_list", "matching_cluster_idx": 4}]}, "HumanEval/0": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n n = len(numbers)\n for i in range(n):\n for j in range(i + 1, n):\n if abs(numbers[i] - numbers[j]) < threshold:\n return True\n return False", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n n = len(numbers)\n for i in range(n):\n for j in range(i + 1, n):\n if abs(numbers[i] - numbers[j]) < threshold:\n return True\n return False", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n n = len(numbers)\n for i in range(n):\n for j in range(i + 1, n):\n if abs(numbers[i] - numbers[j]) < threshold:\n return True\n return False", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n n = len(numbers)\n for i in range(n):\n for j in range(i + 1, n):\n if abs(numbers[i] - numbers[j]) < threshold:\n return True\n return False", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n n = len(numbers)\n for i in range(n):\n for j in range(i + 1, n):\n if abs(numbers[i] - numbers[j]) < threshold:\n return True\n return False", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n n = len(numbers)\n for i in range(n):\n for j in range(i + 1, n):\n if abs(numbers[i] - numbers[j]) < threshold:\n return True\n return False", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n if abs(numbers[i] - numbers[j]) < threshold:\n return True\n return False", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n if abs(numbers[i] - numbers[j]) < threshold:\n return True\n return False", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n n = len(numbers)\n for i in range(n):\n for j in range(i + 1, n):\n if abs(numbers[i] - numbers[j]) < threshold:\n return True\n return False", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n if abs(numbers[i] - numbers[j]) < threshold:\n return True\n return False", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n n = len(numbers)\n for i in range(n):\n for j in range(i + 1, n):\n if abs(numbers[i] - numbers[j]) < threshold:\n return True\n return False", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n if abs(numbers[i] - numbers[j]) < threshold:\n return True\n return False", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n n = len(numbers)\n for i in range(n):\n for j in range(i + 1, n):\n if abs(numbers[i] - numbers[j]) < threshold:\n return True\n return False", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n n = len(numbers)\n for i in range(n):\n for j in range(i + 1, n):\n if abs(numbers[i] - numbers[j]) < threshold:\n return True\n return False", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n if abs(numbers[i] - numbers[j]) < threshold:\n return True\n return False", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n n = len(numbers)\n for i in range(n):\n for j in range(i + 1, n):\n if abs(numbers[i] - numbers[j]) < threshold:\n return True\n return False", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n n = len(numbers)\n for i in range(n):\n for j in range(i + 1, n):\n if abs(numbers[i] - numbers[j]) < threshold:\n return True\n return False", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n if abs(numbers[i] - numbers[j]) < threshold:\n return True\n return False", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n n = len(numbers)\n for i in range(n):\n for j in range(i + 1, n):\n if abs(numbers[i] - numbers[j]) < threshold:\n return True\n return False", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n n = len(numbers)\n for i in range(n):\n for j in range(i + 1, n):\n if abs(numbers[i] - numbers[j]) < threshold:\n return True\n return False", "matching_cluster_idx": 6}]}, "HumanEval/4": {"dps": 90.75949367088607, "dps_norm": 96.66666666666667, "pass@1": 100.0, "profiled": [{"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n n = len(numbers)\n if n == 0:\n return 0.0 # Handle empty list to avoid ZeroDivisionError\n\n mean = sum(numbers) / n\n absolute_deviations = [abs(x - mean) for x in numbers]\n mad = sum(absolute_deviations) / n\n return mad", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if not numbers:\n return 0.0\n n = len(numbers)\n mean = sum(numbers) / n\n absolute_deviations = [abs(x - mean) for x in numbers]\n mad = sum(absolute_deviations) / n\n return mad", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n n = len(numbers)\n if n == 0:\n return 0.0 # Handle empty list to avoid ZeroDivisionError\n\n mean = sum(numbers) / n\n absolute_deviations = [abs(x - mean) for x in numbers]\n mad = sum(absolute_deviations) / n\n return mad", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n n = len(numbers)\n if n == 0:\n return 0.0\n mean = sum(numbers) / n\n absolute_deviations = [abs(x - mean) for x in numbers]\n mad = sum(absolute_deviations) / n\n return mad\nnumbers = [1.0, 2.0, 3.0, 4.0]\nmad = mean_absolute_deviation(numbers)", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n n = len(numbers)\n if n == 0:\n return 0.0\n\n mean = sum(numbers) / n\n absolute_deviations = [abs(x - mean) for x in numbers]\n mad = sum(absolute_deviations) / n\n return mad", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if not numbers:\n return 0.0 # Handle empty list to avoid ZeroDivisionError\n\n n = len(numbers)\n mean = sum(numbers) / n\n mad = sum(abs(x - mean) for x in numbers) / n\n return mad", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n n = len(numbers)\n if n == 0:\n return 0.0 # Handle empty list case\n\n mean = sum(numbers) / n\n absolute_deviations = [abs(x - mean) for x in numbers]\n mad = sum(absolute_deviations) / n\n return mad", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n n = len(numbers)\n if n == 0:\n return 0.0 # Handle empty list case\n\n mean = sum(numbers) / n\n absolute_deviations = [abs(x - mean) for x in numbers]\n mad = sum(absolute_deviations) / n\n return mad", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n n = len(numbers)\n if n == 0:\n return 0.0 # Handle empty list\n\n mean = sum(numbers) / n\n absolute_deviations = [abs(x - mean) for x in numbers]\n mad = sum(absolute_deviations) / n\n return mad", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n n = len(numbers)\n if n == 0:\n return 0.0\n mean = sum(numbers) / n\n absolute_deviations = [abs(x - mean) for x in numbers]\n mad = sum(absolute_deviations) / n\n return mad", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n n = len(numbers)\n if n == 0:\n return 0.0 # Handle empty list\n\n mean = sum(numbers) / n\n absolute_deviations = [abs(x - mean) for x in numbers]\n mad = sum(absolute_deviations) / n\n return mad\nnumbers = [1.0, 2.0, 3.0, 4.0]\nmad = mean_absolute_deviation(numbers)", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n n = len(numbers)\n if n == 0:\n return 0.0\n\n mean = sum(numbers) / n\n absolute_deviations = [abs(x - mean) for x in numbers]\n mad = sum(absolute_deviations) / n\n return mad", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n n = len(numbers)\n if n == 0:\n return 0.0 # Handle empty list case\n\n mean = sum(numbers) / n\n absolute_deviations = [abs(x - mean) for x in numbers]\n mad = sum(absolute_deviations) / n\n return mad", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n n = len(numbers)\n if n == 0:\n return 0.0 # Handle empty list case\n\n mean = sum(numbers) / n\n absolute_deviations = [abs(x - mean) for x in numbers]\n mad = sum(absolute_deviations) / n\n return mad", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n n = len(numbers)\n if n == 0:\n return 0.0\n mean = sum(numbers) / n\n absolute_deviations = [abs(x - mean) for x in numbers]\n mad = sum(absolute_deviations) / n\n return mad", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n n = len(numbers)\n if n == 0:\n return 0.0 # Handle empty list case\n\n mean = sum(numbers) / n\n absolute_deviations = [abs(x - mean) for x in numbers]\n mad = sum(absolute_deviations) / n\n return mad", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n n = len(numbers)\n if n == 0:\n return 0.0 # Handle empty list case\n\n mean = sum(numbers) / n\n absolute_deviations = [abs(x - mean) for x in numbers]\n mad = sum(absolute_deviations) / n\n return mad", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n n = len(numbers)\n if n == 0:\n return 0.0 # Handle empty list to avoid ZeroDivisionError\n\n mean = sum(numbers) / n\n absolute_deviations = [abs(x - mean) for x in numbers]\n mad = sum(absolute_deviations) / n\n return mad", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if not numbers:\n return 0.0\n\n n = len(numbers)\n mean = sum(numbers) / n\n absolute_deviations = [abs(x - mean) for x in numbers]\n mad = sum(absolute_deviations) / n\n return mad", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n n = len(numbers)\n if n == 0:\n return 0.0 # Handle empty list to avoid ZeroDivisionError\n\n mean = sum(numbers) / n\n absolute_deviations = [abs(x - mean) for x in numbers]\n mad = sum(absolute_deviations) / n\n return mad", "matching_cluster_idx": 5}]}, "HumanEval/16": {"dps": 26.511627906976745, "dps_norm": 41.111111111111114, "pass@1": 100.0, "profiled": [{"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n seen = set()\n for char in string:\n seen.add(char.lower())\n return len(seen)", "matching_cluster_idx": 2}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n seen = set()\n for char in string.lower():\n seen.add(char)\n return len(seen)", "matching_cluster_idx": 2}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n seen = set()\n for char in string.lower():\n seen.add(char)\n return len(seen)", "matching_cluster_idx": 2}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n seen = set()\n for char in string.lower():\n seen.add(char)\n return len(seen)", "matching_cluster_idx": 2}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n seen = set()\n for char in string.lower():\n seen.add(char)\n return len(seen)", "matching_cluster_idx": 2}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n seen = set()\n for char in string.lower():\n seen.add(char)\n return len(seen)", "matching_cluster_idx": 2}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n seen = set()\n for char in string.lower():\n seen.add(char)\n return len(seen)", "matching_cluster_idx": 2}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n seen = set()\n for char in string.lower():\n seen.add(char)\n return len(seen)", "matching_cluster_idx": 2}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n seen = set()\n for char in string:\n seen.add(char.lower())\n return len(seen)", "matching_cluster_idx": 2}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n seen = set()\n for char in string.lower():\n seen.add(char)\n return len(seen)", "matching_cluster_idx": 2}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n seen = set()\n for char in string.lower():\n seen.add(char)\n return len(seen)", "matching_cluster_idx": 2}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n seen = set()\n for char in string.lower():\n seen.add(char)\n return len(seen)", "matching_cluster_idx": 2}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n seen = set()\n for char in string.lower():\n seen.add(char)\n return len(seen)", "matching_cluster_idx": 2}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n seen = set()\n for char in string.lower():\n seen.add(char)\n return len(seen)", "matching_cluster_idx": 2}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n return len(set(string.lower()))", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n seen = set()\n for char in string.lower():\n seen.add(char)\n return len(seen)", "matching_cluster_idx": 2}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n distinct_chars = set()\n for char in string.lower():\n distinct_chars.add(char)\n return len(distinct_chars)", "matching_cluster_idx": 3}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n return len(set(string.lower()))", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n seen = set()\n for char in string.lower():\n seen.add(char)\n return len(seen)", "matching_cluster_idx": 2}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n distinct_chars = set()\n for char in string.lower():\n distinct_chars.add(char)\n return len(distinct_chars)", "matching_cluster_idx": 3}]}, "HumanEval/20": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n if len(numbers) < 2:\n raise ValueError(\"List must contain at least two numbers.\")\n\n numbers.sort() # Sort the list to efficiently find closest elements\n\n min_diff = float('inf')\n closest_pair = None\n\n for i in range(len(numbers) - 1):\n diff = numbers[i + 1] - numbers[i]\n if diff < min_diff:\n min_diff = diff\n closest_pair = (numbers[i], numbers[i + 1])\n\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n if len(numbers) < 2:\n raise ValueError(\"List must contain at least two numbers.\")\n\n numbers.sort()\n min_diff = float('inf')\n closest_pair = None\n\n for i in range(len(numbers) - 1):\n diff = numbers[i+1] - numbers[i]\n if diff < min_diff:\n min_diff = diff\n closest_pair = (numbers[i], numbers[i+1])\n\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n numbers.sort() # Sort the list to easily find adjacent elements\n min_diff = float('inf')\n closest_pair = (0.0, 0.0)\n\n for i in range(len(numbers) - 1):\n diff = numbers[i+1] - numbers[i]\n if diff < min_diff:\n min_diff = diff\n closest_pair = (numbers[i], numbers[i+1])\n\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n if len(numbers) < 2:\n raise ValueError(\"List must contain at least two numbers.\")\n\n numbers.sort() # Sort the list to easily find adjacent elements\n\n min_diff = float('inf')\n closest_pair = (None, None)\n\n for i in range(len(numbers) - 1):\n diff = numbers[i+1] - numbers[i]\n if diff < min_diff:\n min_diff = diff\n closest_pair = (numbers[i], numbers[i+1])\n\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n numbers.sort()\n min_diff = float('inf')\n closest_pair = None\n\n for i in range(len(numbers) - 1):\n diff = numbers[i+1] - numbers[i]\n if diff < min_diff:\n min_diff = diff\n closest_pair = (numbers[i], numbers[i+1])\n\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n if len(numbers) < 2:\n raise ValueError(\"List must contain at least two numbers.\")\n\n numbers.sort() # Sort the list to easily find closest elements\n\n min_diff = float('inf')\n closest_pair = (None, None)\n\n for i in range(len(numbers) - 1):\n diff = numbers[i+1] - numbers[i]\n if diff < min_diff:\n min_diff = diff\n closest_pair = (numbers[i], numbers[i+1])\n\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n if len(numbers) < 2:\n raise ValueError(\"List must contain at least two numbers.\")\n\n numbers.sort() # Sort the list to easily find closest elements\n\n min_diff = float('inf')\n closest_pair = (None, None)\n\n for i in range(len(numbers) - 1):\n diff = numbers[i+1] - numbers[i]\n if diff < min_diff:\n min_diff = diff\n closest_pair = (numbers[i], numbers[i+1])\n\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n if len(numbers) < 2:\n raise ValueError(\"List must contain at least two numbers.\")\n\n numbers.sort()\n min_diff = float('inf')\n closest_pair = (None, None)\n\n for i in range(len(numbers) - 1):\n diff = numbers[i+1] - numbers[i]\n if diff < min_diff:\n min_diff = diff\n closest_pair = (numbers[i], numbers[i+1])\n \n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n if len(numbers) < 2:\n raise ValueError(\"List must contain at least two numbers.\")\n\n numbers.sort() # Sort the list to easily find closest elements\n\n min_diff = float('inf')\n closest_pair = None\n\n for i in range(len(numbers) - 1):\n diff = numbers[i+1] - numbers[i]\n if diff < min_diff:\n min_diff = diff\n closest_pair = (numbers[i], numbers[i+1])\n\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n if len(numbers) < 2:\n raise ValueError(\"List must contain at least two numbers\")\n\n numbers.sort() # Sort the list to easily find adjacent elements\n\n min_diff = float('inf')\n closest_pair = (None, None)\n\n for i in range(len(numbers) - 1):\n diff = numbers[i+1] - numbers[i]\n if diff < min_diff:\n min_diff = diff\n closest_pair = (numbers[i], numbers[i+1])\n\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n if len(numbers) < 2:\n raise ValueError(\"List must contain at least two numbers.\")\n\n numbers.sort() # Sort the list to easily find closest elements\n\n min_diff = float('inf')\n closest_pair = (None, None)\n\n for i in range(len(numbers) - 1):\n diff = numbers[i+1] - numbers[i]\n if diff < min_diff:\n min_diff = diff\n closest_pair = (numbers[i], numbers[i+1])\n\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n if len(numbers) < 2:\n raise ValueError(\"List must contain at least two numbers.\")\n\n numbers.sort() # Sort the list to easily find adjacent closest numbers\n\n min_diff = float('inf')\n closest_pair = (None, None)\n\n for i in range(len(numbers) - 1):\n diff = numbers[i+1] - numbers[i]\n if diff < min_diff:\n min_diff = diff\n closest_pair = (numbers[i], numbers[i+1])\n\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n if len(numbers) < 2:\n raise ValueError(\"The list must contain at least two numbers.\")\n\n numbers.sort() # Sort the list to facilitate comparison\n\n min_diff = float('inf')\n closest_pair = None\n\n for i in range(len(numbers) - 1):\n diff = numbers[i + 1] - numbers[i]\n if diff < min_diff:\n min_diff = diff\n closest_pair = (numbers[i], numbers[i + 1])\n\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n if len(numbers) < 2:\n raise ValueError(\"The list must contain at least two numbers.\")\n\n numbers.sort() # Sort the numbers to easily find closest pairs\n\n min_diff = float('inf')\n closest_pair = (None, None)\n\n for i in range(len(numbers) - 1):\n diff = numbers[i+1] - numbers[i]\n if diff < min_diff:\n min_diff = diff\n closest_pair = (numbers[i], numbers[i+1])\n\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n if len(numbers) < 2:\n raise ValueError(\"List must contain at least two numbers.\")\n\n numbers.sort() # Sort the list to easily find closest elements\n\n min_diff = float('inf')\n closest_pair = (None, None)\n\n for i in range(len(numbers) - 1):\n diff = numbers[i+1] - numbers[i]\n if diff < min_diff:\n min_diff = diff\n closest_pair = (numbers[i], numbers[i+1])\n\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n if len(numbers) < 2:\n raise ValueError(\"List must contain at least two numbers.\")\n\n numbers.sort() # Sort the list to easily find adjacent elements\n\n min_diff = float('inf')\n closest_pair = (None, None)\n\n for i in range(len(numbers) - 1):\n diff = abs(numbers[i+1] - numbers[i])\n if diff < min_diff:\n min_diff = diff\n closest_pair = (numbers[i], numbers[i+1])\n\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n if len(numbers) < 2:\n raise ValueError(\"List must contain at least two numbers.\")\n\n numbers.sort() # Sort the numbers to easily find closest pairs\n\n min_diff = float('inf')\n closest_pair = (None, None)\n\n for i in range(len(numbers) - 1):\n diff = numbers[i + 1] - numbers[i]\n if diff < min_diff:\n min_diff = diff\n closest_pair = (numbers[i], numbers[i + 1])\n\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n if len(numbers) < 2:\n raise ValueError(\"List must contain at least two numbers.\")\n\n numbers.sort() # Sort the list to easily find closest elements\n\n min_diff = float('inf')\n closest_pair = (None, None)\n\n for i in range(len(numbers) - 1):\n diff = numbers[i + 1] - numbers[i]\n if diff < min_diff:\n min_diff = diff\n closest_pair = (numbers[i], numbers[i + 1])\n\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n if len(numbers) < 2:\n raise ValueError(\"List must contain at least two numbers\")\n\n numbers.sort() # Sort the numbers to easily find closest pairs\n\n min_diff = float('inf')\n closest_pair = None\n\n for i in range(len(numbers) - 1):\n diff = numbers[i+1] - numbers[i]\n if diff < min_diff:\n min_diff = diff\n closest_pair = (numbers[i], numbers[i+1])\n\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n if len(numbers) < 2:\n raise ValueError(\"List must contain at least two numbers.\")\n\n numbers.sort() # Sort the list to easily find adjacent closest numbers\n\n min_diff = float('inf')\n closest_pair = (None, None)\n\n for i in range(len(numbers) - 1):\n diff = numbers[i+1] - numbers[i]\n if diff < min_diff:\n min_diff = diff\n closest_pair = (numbers[i], numbers[i+1])\n\n return closest_pair", "matching_cluster_idx": 8}]}, "HumanEval/24": {"dps": 93.46938775510205, "dps_norm": 60.0, "pass@1": 100.0, "profiled": [{"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n if n <= 1:\n return 1 # Handle cases where n is 1 or less\n\n for i in range(n // 2, 0, -1): # Iterate downwards from n/2 to 1\n if n % i == 0:\n return i\n return 1 # Should technically never reach here for n>1, but good practice for edge cases", "matching_cluster_idx": 4}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n >>> largest_divisor(2)\n 1\n >>> largest_divisor(7)\n 1\n >>> largest_divisor(1)\n # raises an error since 1 has no divisors smaller than itself\n \"\"\"\n if n == 1:\n raise ValueError(\"1 has no divisors smaller than itself.\")\n for i in range(n // 2, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 4}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n >>> largest_divisor(2)\n 1\n >>> largest_divisor(7)\n 1\n >>> largest_divisor(100)\n 50\n >>> largest_divisor(1)\n 1 # Special Case. Definition allows 1 to divide itself\n >>> largest_divisor(3456732)\n 1728366\n \"\"\"\n\n if n == 1: # Special case to handle n=1\n return 1\n\n for i in range(n // 2, 0, -1): # Iterate downwards from n/2 for efficiency\n if n % i == 0:\n return i\n\n return 1 # Should not be reached unless n=1, which is handled above", "matching_cluster_idx": 3}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n if n <= 1:\n return -1 # Or raise an exception, depending on desired behavior for invalid input\n\n for i in range(n // 2, 0, -1):\n if n % i == 0:\n return i\n\n return -1 # Should never reach here for n > 1", "matching_cluster_idx": 4}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n for i in range(n // 2, 0, -1): # Iterate from n/2 down to 1\n if n % i == 0:\n return i\n return 1 # If no divisor is found (for prime numbers other than 2), return 1", "matching_cluster_idx": 4}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n >>> largest_divisor(7)\n 1\n >>> largest_divisor(1)\n 1 # Technically incorrect, should raise an Exception as per problem constraints. Handling this below.\n >>> largest_divisor(24)\n 12\n >>> largest_divisor(173)\n 1\n \"\"\"\n if n <= 1:\n raise ValueError(\"Input n must be greater than 1.\") # Handling the n<=1 case\n\n for i in range(n // 2, 0, -1): # Optimize by starting from n//2 and going down\n if n % i == 0:\n return i", "matching_cluster_idx": 4}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n for i in range(n // 2, 0, -1):\n if n % i == 0:\n return i\n return 1 # If n is prime and > 2, the largest divisor is 1", "matching_cluster_idx": 4}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n for i in range(n // 2, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 4}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n >>> largest_divisor(2)\n 1\n >>> largest_divisor(7)\n 1\n >>> largest_divisor(25)\n 5\n >>> largest_divisor(1)\n -1 # Special case as 1 has no divisors smaller than itself.\n >>> largest_divisor(1738492) # Large prime number should also return 1\n 1\n \"\"\"\n if n == 1:\n return -1\n\n for i in range(n // 2, 0, -1):\n if n % i == 0:\n return i\n\n return 1 # If no divisor is found (prime numbers other than 1), return 1", "matching_cluster_idx": 3}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n for i in range(n // 2, 0, -1):\n if n % i == 0:\n return i\n return 1 # Should only happen if n is 1", "matching_cluster_idx": 4}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n >>> largest_divisor(25)\n 5\n >>> largest_divisor(17)\n 1\n >>> largest_divisor(1)\n 1 # Special case, documented here for clarity. Mathematically undefined. \n >>> largest_divisor(2)\n 1\n \"\"\"\n for i in range(n // 2, 0, -1): # Iterate from n//2 down to 1\n if n % i == 0:\n return i\n return 1 # Return 1 if no other divisor is found (for prime numbers or 1)", "matching_cluster_idx": 4}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n for i in range(n // 2, 0, -1): # Iterate from n/2 down to 1\n if n % i == 0:\n return i\n return 1 # If no divisor is found (should only happen for n=1, as 1 divides every number)", "matching_cluster_idx": 3}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n >>> largest_divisor(17)\n 1\n >>> largest_divisor(25)\n 5\n >>> largest_divisor(1) # Returns 1 for n=1\n 1\n \"\"\"\n if n == 1:\n return 1\n for i in range(n // 2, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 4}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n for i in range(n // 2, 0, -1): # Iterate from n/2 down to 1\n if n % i == 0:\n return i\n return 1 # Should theoretically never reach here for n > 1 as 1 is always a divisor", "matching_cluster_idx": 3}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n for i in range(n // 2, 0, -1): # Iterate from n/2 down to 1\n if n % i == 0:\n return i\n return 1 # Shouldn't reach here unless n is 1", "matching_cluster_idx": 4}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n for i in range(n // 2, 0, -1): # Iterate from n//2 down to 1\n if n % i == 0:\n return i\n return 1 # If no divisor found (for prime numbers > 2), return 1", "matching_cluster_idx": 4}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n for i in range(n // 2, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 4}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n >>> largest_divisor(2)\n 1\n >>> largest_divisor(7)\n 1\n >>> largest_divisor(25)\n 5\n\n \"\"\"\n for i in range(n // 2, 0, -1):\n if n % i == 0:\n return i\n return 1", "matching_cluster_idx": 4}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n for i in range(n // 2, 0, -1): # Iterate from n/2 down to 1\n if n % i == 0:\n return i\n return None # Should never reach here for n > 1", "matching_cluster_idx": 4}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n >>> largest_divisor(12)\n 6\n >>> largest_divisor(7)\n 1\n >>> largest_divisor(1)\n 1 # Special Case - Returns 1 as instructed\n >>> largest_divisor(2)\n 1\n >>> largest_divisor(17)\n 1\n \"\"\"\n if n == 1: # Handle the special case where n is 1.\n return 1\n\n for i in range(n // 2, 0, -1): # Iterate from n/2 downwards\n if n % i == 0:\n return i\n return 1 # If no divisor is found other than 1 (for prime numbers).", "matching_cluster_idx": 4}]}, "HumanEval/26": {"dps": 31.4, "dps_norm": 73.75, "pass@1": 92.0, "profiled": [{"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n counts = {}\n result = []\n for number in numbers:\n if number not in counts:\n counts[number] = 0\n counts[number] += 1\n\n for number in numbers:\n if counts[number] == 1:\n result.append(number)\n \n return result", "matching_cluster_idx": 2}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n counts = {}\n result = []\n for number in numbers:\n if number not in counts:\n counts[number] = 0\n counts[number] += 1\n\n for number in numbers:\n if counts[number] == 1:\n result.append(number)\n\n return result", "matching_cluster_idx": 2}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n counts = {}\n result = []\n for number in numbers:\n if number not in counts:\n counts[number] = 0\n counts[number] += 1\n\n for number in numbers:\n if counts[number] == 1:\n result.append(number)\n\n return result", "matching_cluster_idx": 2}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n counts = {}\n result = []\n for number in numbers:\n if number not in counts:\n counts[number] = 0\n counts[number] += 1\n\n for number in numbers:\n if counts[number] == 1:\n result.append(number)\n\n return result", "matching_cluster_idx": 2}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n seen = set()\n result = []\n for number in numbers:\n if number not in seen:\n seen.add(number)\n else:\n continue # Skip duplicates\n\n counts = numbers.count(number)\n if counts == 1: # Only include the element if it appears once\n result.append(number)\n\n return result", "matching_cluster_idx": 0}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n counts = {}\n result = []\n for number in numbers:\n if number not in counts:\n counts[number] = 0\n counts[number] += 1\n\n for number in numbers:\n if counts[number] == 1:\n result.append(number)\n\n return result", "matching_cluster_idx": 2}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n seen = set()\n result = []\n for number in numbers:\n if number not in seen:\n seen.add(number)\n result.append(number)\n else:\n if number in result:\n result.remove(number)\n\n\n return result", "matching_cluster_idx": 2}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n counts = {}\n result = []\n for number in numbers:\n if number not in counts:\n counts[number] = 0\n counts[number] += 1\n\n for number in numbers:\n if counts[number] == 1:\n result.append(number)\n\n return result", "matching_cluster_idx": 2}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n counts = {}\n result = []\n for number in numbers:\n if number not in counts:\n counts[number] = 0\n counts[number] += 1\n\n for number in numbers:\n if counts[number] == 1:\n result.append(number)\n \n return result", "matching_cluster_idx": 2}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n counts = {}\n result = []\n for number in numbers:\n if number not in counts:\n counts[number] = 0\n counts[number] += 1\n\n for number in numbers:\n if counts[number] == 1:\n result.append(number)\n\n return result", "matching_cluster_idx": 2}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n counts = {}\n result = []\n for number in numbers:\n if number not in counts:\n counts[number] = 0\n counts[number] += 1\n\n for number in numbers:\n if counts[number] == 1:\n result.append(number)\n\n return result", "matching_cluster_idx": 2}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n counts = {}\n result = []\n for number in numbers:\n if number not in counts:\n counts[number] = 0\n counts[number] += 1\n\n for number in numbers:\n if counts[number] == 1:\n result.append(number)\n\n return result", "matching_cluster_idx": 2}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n counts = {}\n result = []\n for number in numbers:\n if number not in counts:\n counts[number] = 0\n counts[number] += 1\n\n for number in numbers:\n if counts[number] == 1:\n result.append(number)\n\n return result", "matching_cluster_idx": 2}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n counts = {}\n result = []\n for number in numbers:\n if number not in counts:\n counts[number] = 0\n counts[number] += 1\n\n for number in numbers:\n if counts[number] == 1:\n result.append(number)\n\n return result", "matching_cluster_idx": 2}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n counts = {}\n result = []\n for number in numbers:\n if number not in counts:\n counts[number] = 0\n counts[number] += 1\n\n for number in numbers:\n if counts[number] == 1:\n result.append(number)\n \n return result", "matching_cluster_idx": 2}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n counts = {}\n result = []\n for number in numbers:\n if number not in counts:\n counts[number] = 0\n counts[number] += 1\n\n for number in numbers:\n if counts[number] == 1:\n result.append(number)\n return result", "matching_cluster_idx": 2}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n counts = {}\n result = []\n for number in numbers:\n if number not in counts:\n counts[number] = 0\n counts[number] += 1\n\n for number in numbers:\n if counts[number] == 1:\n result.append(number)\n\n return result", "matching_cluster_idx": 2}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n counts = {}\n result = []\n for num in numbers:\n if num not in counts:\n counts[num] = 1\n result.append(num)\n else:\n counts[num] += 1\n\n final_result = []\n for num in result:\n if counts[num] == 1:\n final_result.append(num)\n return final_result", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n counts = {}\n result = []\n for number in numbers:\n if number not in counts:\n counts[number] = 0\n counts[number] += 1\n\n for number in numbers:\n if counts[number] == 1:\n result.append(number)\n return result", "matching_cluster_idx": 2}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n counts = {}\n result = []\n for number in numbers:\n if number not in counts:\n counts[number] = 0\n counts[number] += 1\n\n for number in numbers:\n if counts[number] == 1:\n result.append(number)\n return result", "matching_cluster_idx": 2}]}, "HumanEval/31": {"dps": 95.12658227848101, "dps_norm": 86.875, "pass@1": 100.0, "profiled": [{"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "import doctest\ndef is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "import doctest\ndef is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "import doctest\ndef is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "import doctest\ndef is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "import doctest\ndef is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i = i + 6\n return True", "matching_cluster_idx": 6}, {"solution": "import doctest\ndef is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n if n == 2:\n return True\n if n % 2 == 0:\n return False\n for i in range(3, int(n**0.5) + 1, 2):\n if n % i == 0:\n return False\n return True", "matching_cluster_idx": 5}]}, "HumanEval/33": {"dps": 97.22222222222223, "dps_norm": 81.81818181818181, "pass@1": 86.0, "profiled": [{"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n n = len(l)\n third_vals = []\n for i in range(n):\n if (i % 3) == 0:\n third_vals.append(l[i])\n \n third_vals.sort()\n\n result = []\n third_index = 0\n for i in range(n):\n if (i % 3) == 0:\n result.append(third_vals[third_index])\n third_index += 1\n else:\n result.append(l[i])\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n n = len(l)\n divisible_by_three = []\n for i in range(0, n, 3):\n if i < n:\n divisible_by_three.append(l[i])\n \n divisible_by_three.sort()\n \n result = []\n div_three_index = 0\n for i in range(n):\n if i % 3 == 0:\n result.append(divisible_by_three[div_three_index])\n div_three_index += 1\n else:\n result.append(l[i])\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n thirds = []\n result = []\n for i, val in enumerate(l):\n if i % 3 == 0:\n thirds.append(val)\n result.append(val)\n\n thirds.sort()\n\n j = 0\n for i in range(len(result)):\n if i % 3 == 0:\n result[i] = thirds[j]\n j += 1\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n thirds = []\n result = []\n for i, val in enumerate(l):\n if i % 3 == 0:\n thirds.append(val)\n result.append(val)\n\n thirds.sort()\n\n j = 0\n for i in range(len(result)):\n if i % 3 == 0:\n result[i] = thirds[j]\n j += 1\n\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n third_values = []\n for i in range(len(l)):\n if i % 3 == 0:\n third_values.append(l[i])\n third_values.sort()\n result = []\n third_index = 0\n for i in range(len(l)):\n if i % 3 == 0:\n result.append(third_values[third_index])\n third_index += 1\n else:\n result.append(l[i])\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n divisible_by_three = []\n result = []\n\n for i in range(len(l)):\n if i % 3 == 0:\n divisible_by_three.append(l[i])\n\n divisible_by_three.sort()\n\n index_divisible = 0\n for i in range(len(l)):\n if i % 3 == 0:\n result.append(divisible_by_three[index_divisible])\n index_divisible += 1\n else:\n result.append(l[i])\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n n = len(l)\n third_values = []\n for i in range(n):\n if (i % 3 == 0):\n third_values.append(l[i])\n \n third_values.sort()\n \n result = []\n third_index = 0\n for i in range(n):\n if (i % 3 == 0):\n result.append(third_values[third_index])\n third_index += 1\n else:\n result.append(l[i])\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n if not l:\n return []\n\n thirds = []\n result = []\n for i, val in enumerate(l):\n if i % 3 == 0:\n thirds.append(val)\n result.append(None) # Placeholder\n\n thirds.sort()\n\n thirds_index = 0\n for i, val in enumerate(l):\n if i % 3 == 0:\n result[i] = thirds[thirds_index]\n thirds_index += 1\n else:\n result[i] = l[i]\n\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n divisible_by_three = []\n result = []\n\n for i in range(len(l)):\n if i % 3 == 0:\n divisible_by_three.append(l[i])\n\n divisible_by_three.sort()\n\n index_divisible = 0\n for i in range(len(l)):\n if i % 3 == 0:\n result.append(divisible_by_three[index_divisible])\n index_divisible += 1\n else:\n result.append(l[i])\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n if not l:\n return []\n\n thirds = []\n for i in range(len(l)):\n if i % 3 == 0:\n thirds.append(l[i])\n \n thirds.sort()\n\n result = []\n thirds_index = 0\n for i in range(len(l)):\n if i % 3 == 0:\n result.append(thirds[thirds_index])\n thirds_index += 1\n else:\n result.append(l[i])\n\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n n = len(l)\n thirds = []\n for i in range(n):\n if i % 3 == 0:\n thirds.append(l[i])\n \n thirds.sort()\n\n result = []\n thirds_index = 0\n for i in range(n):\n if i % 3 == 0:\n result.append(thirds[thirds_index])\n thirds_index += 1\n else:\n result.append(l[i])\n\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n third_values = []\n for i in range(len(l)):\n if i % 3 == 0:\n third_values.append(l[i])\n\n third_values.sort()\n\n new_list = []\n third_index = 0\n for i in range(len(l)):\n if i % 3 == 0:\n new_list.append(third_values[third_index])\n third_index += 1\n else:\n new_list.append(l[i])\n\n return new_list", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n n = len(l)\n divisible_by_three = []\n for i in range(n):\n if i % 3 == 0:\n divisible_by_three.append(l[i])\n\n divisible_by_three.sort()\n\n result = []\n j = 0\n for i in range(n):\n if i % 3 == 0:\n result.append(divisible_by_three[j])\n j += 1\n else:\n result.append(l[i])\n\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n if not l:\n return []\n\n thirds = []\n result = []\n for i, val in enumerate(l):\n if i % 3 == 0:\n thirds.append(val)\n result.append(None) # Placeholder\n\n thirds.sort()\n\n thirds_index = 0\n for i in range(len(l)):\n if i % 3 == 0:\n result[i] = thirds[thirds_index]\n thirds_index += 1\n else:\n result[i] = l[i]\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n third_values = []\n for i in range(len(l)):\n if i % 3 == 0:\n third_values.append(l[i])\n third_values.sort()\n\n result = []\n third_index = 0\n for i in range(len(l)):\n if i % 3 == 0:\n result.append(third_values[third_index])\n third_index += 1\n else:\n result.append(l[i])\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n if not l:\n return []\n\n third_values = []\n for i in range(len(l)):\n if i % 3 == 0:\n third_values.append(l[i])\n \n third_values.sort()\n\n new_list = []\n third_index = 0\n for i in range(len(l)):\n if i % 3 == 0:\n new_list.append(third_values[third_index])\n third_index += 1\n else:\n new_list.append(l[i])\n \n return new_list", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n\n n = len(l)\n third_values = []\n for i in range(n):\n if i % 3 == 0:\n third_values.append(l[i])\n\n third_values.sort()\n\n result = []\n third_index = 0\n for i in range(n):\n if i % 3 == 0:\n result.append(third_values[third_index])\n third_index += 1\n else:\n result.append(l[i])\n\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n\n divisible_by_three = []\n result = []\n\n for i in range(len(l)):\n if (i % 3 == 0):\n divisible_by_three.append(l[i])\n\n divisible_by_three.sort()\n\n j = 0\n for i in range(len(l)):\n if (i % 3 == 0):\n result.append(divisible_by_three[j])\n j += 1\n else:\n result.append(l[i])\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n n = len(l)\n third_values = []\n for i in range(n):\n if i % 3 == 0:\n third_values.append(l[i])\n third_values.sort()\n result = []\n third_index = 0\n for i in range(n):\n if i % 3 == 0:\n result.append(third_values[third_index])\n third_index += 1\n else:\n result.append(l[i])\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [3, 6, 2, 4, 8, 9, 5]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2, 1, 7, 10, 11, 0])\n [0, 6, 3, 4, 8, 9, 2, 1, 5, 10, 11, 7]\n\n \"\"\"\n n = len(l)\n divisible_by_three = []\n for i in range(n):\n if i % 3 == 0:\n divisible_by_three.append(l[i])\n\n divisible_by_three.sort()\n \n new_list = []\n j = 0\n for i in range(n):\n if i % 3 == 0:\n new_list.append(divisible_by_three[j])\n j += 1\n else:\n new_list.append(l[i])\n return new_list", "matching_cluster_idx": 8}]}, "HumanEval/34": {"dps": 95.28301886792453, "dps_norm": 97.0, "pass@1": 100.0, "profiled": [{"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(list(set(l)))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(list(set(l)))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(list(set(l)))", "matching_cluster_idx": 4}, {"solution": "import doctest\ndef unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(list(set(l)))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(list(set(l)))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(list(set(l)))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(list(set(l)))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(list(set(l)))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(list(set(l)))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(list(set(l)))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(list(set(l)))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(list(set(l)))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(list(set(l)))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(list(set(l)))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(list(set(l)))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n seen = set()\n result = []\n for item in l:\n if item not in seen:\n result.append(item)\n seen.add(item)\n result.sort()\n return result", "matching_cluster_idx": 1}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(list(set(l)))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(list(set(l)))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(list(set(l)))", "matching_cluster_idx": 4}, {"solution": "import doctest\ndef unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(list(set(l)))", "matching_cluster_idx": 4}]}, "HumanEval/36": {"dps": 96.77419354838709, "dps_norm": 71.42857142857143, "pass@1": 100.0, "profiled": [{"solution": "def fizz_buzz(n: int):\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int):\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n for i in range(1, n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int):\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int):\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n for i in range(1, n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int):\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n for i in range(1, n):\n if (i % 11 == 0) or (i % 13 == 0):\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int):\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int):\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n for i in range(1, n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int):\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n for i in range(1, n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int):\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n for i in range(1, n):\n if (i % 11 == 0 or i % 13 == 0):\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int):\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n for i in range(1, n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int):\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n for i in range(1, n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int):\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int):\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n for i in range(1, n):\n if (i % 11 == 0) or (i % 13 == 0):\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int):\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n for i in range(n):\n if (i % 11 == 0) or (i % 13 == 0):\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int):\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int):\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n for i in range(1, n):\n if (i % 11 == 0 or i % 13 == 0):\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int):\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n for i in range(1, n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int):\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n for i in range(1, n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int):\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n for i in range(1, n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int):\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n for i in range(1, n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}]}, "HumanEval/37": {"dps": 94.92635024549918, "dps_norm": 90.0, "pass@1": 100.0, "profiled": [{"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n if len(l) <= 1:\n return l\n \n even_indices = []\n even_values = []\n for i in range(0, len(l), 2):\n even_indices.append(i)\n even_values.append(l[i])\n\n even_values.sort()\n\n result = l[:] # Create a copy to avoid modifying the original list\n for i, val in zip(even_indices, even_values):\n result[i] = val\n\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n if len(l) <= 1:\n return l\n \n even_indices = []\n even_values = []\n for i in range(0, len(l), 2):\n even_indices.append(i)\n even_values.append(l[i])\n \n even_values.sort()\n \n new_list = l[:] # Create a copy to avoid modifying the original list\n \n for i, val in zip(even_indices, even_values):\n new_list[i] = val\n \n return new_list", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n if not l:\n return []\n\n even_indices = []\n even_values = []\n for i in range(0, len(l), 2):\n even_indices.append(i)\n even_values.append(l[i])\n\n even_values.sort()\n\n result = list(l) # Create a copy to avoid modifying the original list\n for i, val in zip(even_indices, even_values):\n result[i] = val\n\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n if len(l) <= 1:\n return l\n\n even_indices = []\n even_values = []\n\n for i in range(0, len(l), 2):\n even_indices.append(i)\n even_values.append(l[i])\n \n even_values.sort()\n \n result = l[:] # Create a copy to avoid modifying the original list\n\n for i, val in zip(even_indices, even_values):\n result[i] = val\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n if len(l) <= 1:\n return l\n \n even_indices = []\n even_values = []\n for i in range(0, len(l), 2):\n even_indices.append(i)\n even_values.append(l[i])\n \n even_values.sort()\n\n result = l[:] # Create a copy to avoid modifying the original list\n\n for i, val in zip(even_indices, even_values):\n result[i] = val\n\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n if len(l) <= 1:\n return l\n \n even_indices = []\n even_values = []\n for i in range(0, len(l), 2):\n even_indices.append(i)\n even_values.append(l[i])\n\n even_values.sort()\n\n result = [0] * len(l)\n for i in range(len(even_indices)):\n result[even_indices[i]] = even_values[i]\n\n for i in range(1, len(l), 2):\n result[i] = l[i]\n\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n if len(l) <= 1:\n return l\n \n even_indices = []\n even_values = []\n for i in range(0, len(l), 2):\n even_indices.append(i)\n even_values.append(l[i])\n\n even_values.sort()\n\n result = list(l) # Create a copy to avoid modifying the original list\n for i, val in zip(even_indices, even_values):\n result[i] = val\n\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n if not l:\n return []\n\n even_indices = []\n even_values = []\n result = []\n\n for i, val in enumerate(l):\n if i % 2 == 0:\n even_indices.append(i)\n even_values.append(val)\n else:\n result.append(val)\n\n\n even_values.sort()\n\n result_with_evens = []\n even_idx = 0\n odd_idx = 0\n for i in range(len(l)):\n if i % 2 == 0:\n result_with_evens.append(even_values[even_idx])\n even_idx+=1\n else:\n if odd_idx < len(result):\n result_with_evens.append(result[odd_idx])\n odd_idx +=1\n \n\n\n return result_with_evens", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n if len(l) <= 1:\n return l\n \n even_indices = []\n even_values = []\n for i in range(0, len(l), 2):\n even_indices.append(i)\n even_values.append(l[i])\n \n even_values.sort()\n \n result = l[:] # Create a copy to avoid modifying the original list\n \n for i, val in zip(even_indices, even_values):\n result[i] = val\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n if len(l) <= 1:\n return l\n\n even_indices = []\n even_values = []\n for i in range(len(l)):\n if i % 2 == 0:\n even_indices.append(i)\n even_values.append(l[i])\n\n even_values.sort()\n\n result = l[:] # Create a copy to avoid modifying the original list\n\n for i, val in zip(even_indices, even_values):\n result[i] = val\n\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n if not l:\n return []\n\n even_indices = []\n even_values = []\n for i, val in enumerate(l):\n if i % 2 == 0:\n even_indices.append(i)\n even_values.append(val)\n\n even_values.sort()\n\n result = l[:] # Create a copy to avoid modifying the original list\n for i, val in zip(even_indices, even_values):\n result[i] = val\n\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n if len(l) <= 1:\n return l\n \n even_indices = []\n even_values = []\n for i in range(0, len(l), 2):\n even_indices.append(i)\n even_values.append(l[i])\n\n even_values.sort()\n\n result = l[:] # Create a copy to avoid modifying the original list\n for i, val in zip(even_indices, even_values):\n result[i] = val\n\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n if len(l) <= 1:\n return l\n\n even_indices = []\n even_values = []\n for i in range(0, len(l), 2):\n even_indices.append(i)\n even_values.append(l[i])\n\n even_values.sort()\n\n result = l[:] # Create a copy to avoid modifying the original list\n for i, val in zip(even_indices, even_values):\n result[i] = val\n\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n if len(l) <= 1:\n return l\n\n even_indices = []\n even_values = []\n for i in range(0, len(l), 2):\n even_indices.append(i)\n even_values.append(l[i])\n\n even_values.sort()\n\n result = l[:] # Create a copy to avoid modifying the original list\n for i, val in zip(even_indices, even_values):\n result[i] = val\n\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n if len(l) <= 1:\n return l\n \n even_indices = []\n even_values = []\n for i in range(0, len(l), 2):\n even_indices.append(i)\n even_values.append(l[i])\n\n even_values.sort()\n\n result = l[:] # Create a copy to avoid modifying the original list\n\n for i, val in zip(even_indices, even_values):\n result[i] = val\n\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n if not l:\n return []\n\n even_indices = []\n even_values = []\n for i in range(0, len(l), 2):\n even_indices.append(i)\n even_values.append(l[i])\n\n even_values.sort()\n\n result = list(l) # Create a copy to avoid modifying the original list\n for i, val in zip(even_indices, even_values):\n result[i] = val\n\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n if len(l) <= 1:\n return l\n\n even_indices = []\n even_values = []\n for i in range(0, len(l), 2):\n even_indices.append(i)\n even_values.append(l[i])\n\n even_values.sort()\n\n result = l[:] # Create a copy to avoid modifying the original list\n for i, val in zip(even_indices, even_values):\n result[i] = val\n\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n if len(l) <= 1:\n return l\n \n even_indices = []\n even_values = []\n for i in range(0, len(l), 2):\n even_indices.append(i)\n even_values.append(l[i])\n\n even_values.sort()\n\n result = l[:] # Create a copy to avoid modifying the original list\n\n for i, val in zip(even_indices, even_values):\n result[i] = val\n\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n if len(l) <= 1:\n return l\n\n even_indices = []\n even_values = []\n for i in range(0, len(l), 2):\n even_indices.append(i)\n even_values.append(l[i])\n\n even_values.sort()\n\n result = l[:] # Create a copy to avoid modifying the original list\n\n for i, val in zip(even_indices, even_values):\n result[i] = val\n\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n if len(l) <= 1:\n return l\n \n even_indices = []\n even_values = []\n for i in range(0, len(l), 2):\n even_indices.append(i)\n even_values.append(l[i])\n\n even_values.sort()\n \n result = l.copy()\n for i, val in zip(even_indices, even_values):\n result[i] = val\n \n return result", "matching_cluster_idx": 8}]}, "HumanEval/49": {"dps": null, "dps_norm": null, "pass@1": 0.0, "profiled": []}, "HumanEval/51": {"dps": 96.13526570048309, "dps_norm": 75.0, "pass@1": 100.0, "profiled": [{"solution": "import doctest\ndef remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n result = \"\"\n for char in text:\n if char not in vowels:\n result += char\n return result", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n result = \"\"\n for char in text:\n if char not in vowels:\n result += char\n return result", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n result = \"\"\n for char in text:\n if char not in vowels:\n result += char\n return result", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n result = \"\"\n for char in text:\n if char not in vowels:\n result += char\n return result", "matching_cluster_idx": 5}, {"solution": "import doctest\ndef remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n result = \"\"\n for char in text:\n if char not in vowels:\n result += char\n return result", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n result = \"\"\n for char in text:\n if char not in vowels:\n result += char\n return result", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n result = \"\"\n for char in text:\n if char not in vowels:\n result += char\n return result", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n result = \"\"\n for char in text:\n if char not in vowels:\n result += char\n return result", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n result = \"\"\n for char in text:\n if char not in vowels:\n result += char\n return result", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n result = \"\"\n for char in text:\n if char not in vowels:\n result += char\n return result", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n result = \"\"\n for char in text:\n if char not in vowels:\n result += char\n return result", "matching_cluster_idx": 5}, {"solution": "import doctest\ndef remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n result = \"\"\n for char in text:\n if char not in vowels:\n result += char\n return result", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n result = \"\"\n for char in text:\n if char not in vowels:\n result += char\n return result", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n result = \"\"\n for char in text:\n if char not in vowels:\n result += char\n return result", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n result = \"\"\n for char in text:\n if char not in vowels:\n result += char\n return result", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n result = \"\"\n for char in text:\n if char not in vowels:\n result += char\n return result", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n result = \"\"\n for char in text:\n if char not in vowels:\n result += char\n return result", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n result = \"\"\n for char in text:\n if char not in vowels:\n result += char\n return result", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n result = \"\"\n for char in text:\n if char not in vowels:\n result += char\n return result", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n result = \"\"\n for char in text:\n if char not in vowels:\n result += char\n return result", "matching_cluster_idx": 5}]}, "HumanEval/54": {"dps": null, "dps_norm": null, "pass@1": 3.0, "profiled": []}, "HumanEval/58": {"dps": 77.08661417322834, "dps_norm": 70.0, "pass@1": 100.0, "profiled": [{"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n\n \"\"\"\n common_elements = set(l1) & set(l2) # Efficiently find common elements using set intersection\n return sorted(list(common_elements)) # Convert back to list and sort", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n\n \"\"\"\n common_elements = sorted(list(set(l1) & set(l2)))\n return common_elements", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n\n \"\"\"\n common_elements = []\n for element in l1:\n if element in l2 and element not in common_elements:\n common_elements.append(element)\n common_elements.sort()\n return common_elements", "matching_cluster_idx": 0}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n\n \"\"\"\n common_elements = set(l1) & set(l2)\n return sorted(list(common_elements))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n\n \"\"\"\n common_elements = []\n for element in l1:\n if element in l2 and element not in common_elements:\n common_elements.append(element)\n common_elements.sort()\n return common_elements", "matching_cluster_idx": 0}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n\n \"\"\"\n common_elements = sorted(list(set(l1) & set(l2)))\n return common_elements", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n\n \"\"\"\n common_elements = sorted(list(set(l1) & set(l2)))\n return common_elements", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n\n \"\"\"\n common_elements = set(l1) & set(l2)\n return sorted(list(common_elements))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n\n \"\"\"\n set1 = set(l1)\n set2 = set(l2)\n common_elements = list(set1.intersection(set2))\n common_elements.sort()\n return common_elements", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n\n \"\"\"\n common_elements = []\n for element in l1:\n if element in l2 and element not in common_elements:\n common_elements.append(element)\n common_elements.sort()\n return common_elements", "matching_cluster_idx": 0}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n\n \"\"\"\n common_elements = set(l1) & set(l2)\n return sorted(list(common_elements))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n\n \"\"\"\n common_elements = sorted(list(set(l1) & set(l2)))\n return common_elements", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n\n \"\"\"\n common_elements = set(l1) & set(l2)\n return sorted(list(common_elements))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n\n \"\"\"\n common_elements = sorted(list(set(l1) & set(l2)))\n return common_elements", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n\n \"\"\"\n common_elements = []\n for element in l1:\n if element in l2 and element not in common_elements:\n common_elements.append(element)\n common_elements.sort()\n return common_elements", "matching_cluster_idx": 0}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n\n \"\"\"\n common_elements = set(l1) & set(l2)\n return sorted(list(common_elements))", "matching_cluster_idx": 4}, {"solution": "import doctest\ndef common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n\n \"\"\"\n common_elements = sorted(list(set(l1) & set(l2)))\n return common_elements", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n\n \"\"\"\n common_elements = sorted(list(set(l1) & set(l2)))\n return common_elements", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n\n \"\"\"\n set1 = set(l1)\n set2 = set(l2)\n common_elements = list(set1.intersection(set2))\n common_elements.sort()\n return common_elements", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n\n \"\"\"\n common_elements = set(l1) & set(l2)\n return sorted(list(common_elements))", "matching_cluster_idx": 4}]}, "HumanEval/59": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n largest_factor = 1\n\n # Divide n by 2 until n is odd\n while n % 2 == 0:\n largest_factor = 2\n n //= 2\n\n # Iterate through odd numbers from 3 up to the square root of n\n i = 3\n while i * i <= n:\n while n % i == 0:\n largest_factor = i\n n //= i\n i += 2\n\n # If n is still greater than 1, it means n is a prime number itself (since we've divided out all smaller factors)\n if n > 1:\n largest_factor = n\n\n return largest_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n largest_factor = 1\n i = 2\n\n while i * i <= n:\n if n % i == 0:\n largest_factor = i\n n //= i\n else:\n i += 1\n\n if n > largest_factor:\n largest_factor = n\n\n return largest_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n largest_factor = 1\n i = 2\n\n while i * i <= n:\n while n % i == 0:\n largest_factor = i\n n //= i\n i += 1\n\n if n > 1:\n largest_factor = n\n\n return largest_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n largest_factor = 1\n i = 2\n\n while i * i <= n:\n if n % i == 0:\n largest_factor = i\n n //= i\n else:\n i += 1\n\n if n > largest_factor:\n largest_factor = n\n\n return largest_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n largest_factor = 1\n\n # Divide n by 2 as many times as possible\n while n % 2 == 0:\n largest_factor = 2\n n //= 2\n\n # Iterate through odd numbers from 3 to sqrt(n)\n i = 3\n while i * i <= n:\n while n % i == 0:\n largest_factor = i\n n //= i\n i += 2\n\n # If n is still greater than 1, it's prime\n if n > 1:\n largest_factor = n\n\n return largest_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n largest_factor = 1\n\n # Divide n by 2 as many times as possible\n while n % 2 == 0:\n largest_factor = 2\n n //= 2\n\n # Iterate through odd numbers from 3 up to the square root of n\n i = 3\n while i * i <= n:\n while n % i == 0:\n largest_factor = i\n n //= i\n i += 2\n\n # If n is still greater than 1, it's the last prime factor\n if n > 1:\n largest_factor = n\n\n return largest_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n largest_factor = 1\n\n # Divide out all factors of 2\n while n % 2 == 0:\n largest_factor = 2\n n //= 2\n\n # Iterate through odd numbers up to the square root of n\n for i in range(3, int(n**0.5) + 1, 2):\n while n % i == 0:\n largest_factor = i\n n //= i\n\n # If n is still greater than 1, it must be prime itself\n if n > 1:\n largest_factor = n\n\n return largest_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n i = 2\n while i * i <= n:\n if n % i:\n i += 1\n else:\n n //= i\n return n", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n largest_factor = 1\n\n # Divide n by 2 repeatedly until it's odd\n while n % 2 == 0:\n largest_factor = 2\n n //= 2\n\n # Iterate through odd numbers starting from 3 up to the square root of n\n for i in range(3, int(n**0.5) + 1, 2):\n while n % i == 0:\n largest_factor = i\n n //= i\n\n # If n is still greater than 2 after the loop, it's prime itself\n if n > 2:\n largest_factor = n\n\n return largest_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n largest_factor = 1\n i = 2\n while i * i <= n:\n while n % i == 0:\n largest_factor = i\n n //= i\n i += 1\n if n > 1:\n largest_factor = n\n return largest_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n largest_factor = 1\n\n # Divide n by 2 as many times as possible\n while n % 2 == 0:\n largest_factor = 2\n n //= 2\n\n # Iterate through odd numbers from 3 up to the square root of n\n i = 3\n while i * i <= n:\n while n % i == 0:\n largest_factor = i\n n //= i\n i += 2\n\n # If n is still greater than 1 after the loop, it's prime\n if n > 1:\n largest_factor = n\n\n return largest_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n largest_factor = 1\n\n # Divide n by 2 until it's odd\n while n % 2 == 0:\n largest_factor = 2\n n //= 2\n\n # Iterate through odd numbers from 3 up to sqrt(n)\n i = 3\n while i * i <= n:\n while n % i == 0:\n largest_factor = i\n n //= i\n i += 2\n\n # If n is still greater than 1, it's prime\n if n > 1:\n largest_factor = n\n\n return largest_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n largest_factor = 1\n\n i = 2\n while i * i <= n:\n if n % i == 0:\n largest_factor = i\n while n % i == 0:\n n //= i\n i += 1\n \n if n > 1:\n largest_factor = n\n\n return largest_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n largest_factor = 1\n\n # Divide n by 2 until it's odd\n while n % 2 == 0:\n largest_factor = 2\n n //= 2\n\n # Check odd factors starting from 3\n i = 3\n while i * i <= n:\n while n % i == 0:\n largest_factor = i\n n //= i\n i += 2\n\n # If n is still greater than 1, it's prime\n if n > 1:\n largest_factor = n\n\n return largest_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n largest_factor = 1\n\n # Divide n by 2 repeatedly until it's odd\n while n % 2 == 0:\n largest_factor = 2\n n //= 2\n\n # Iterate through odd numbers from 3 up to sqrt(n)\n i = 3\n while i * i <= n:\n while n % i == 0:\n largest_factor = i\n n //= i\n i += 2\n\n # If n is still greater than 1, it's the largest prime factor\n if n > 1:\n largest_factor = n\n\n return largest_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n largest_factor = 1\n\n # Divide out all factors of 2\n while n % 2 == 0:\n largest_factor = 2\n n //= 2\n\n # Iterate through odd numbers up to sqrt(n)\n i = 3\n while i * i <= n:\n while n % i == 0:\n largest_factor = i\n n //= i\n i += 2\n\n # If n is still greater than 1, it's the largest prime factor\n if n > 1:\n largest_factor = n\n\n return largest_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n largest_factor = 1\n i = 2\n\n while i * i <= n:\n if n % i == 0:\n largest_factor = i\n n //= i # Divide n by i to reduce it and find larger factors\n while n % i == 0: # Handle cases where a prime factor appears multiple times\n n //= i\n i += 1\n\n if n > 1: # If n is still greater than 1 after the loop, it's the largest prime factor\n largest_factor = n\n \n return largest_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n largest_factor = 1\n\n # Divide n by 2 as many times as possible\n while n % 2 == 0:\n largest_factor = 2\n n //= 2\n\n # Iterate through odd numbers from 3 up to sqrt(n)\n i = 3\n while i * i <= n:\n while n % i == 0:\n largest_factor = i\n n //= i\n i += 2\n\n # If n is still greater than 1, it's a prime factor\n if n > 1:\n largest_factor = n\n\n return largest_factor\n\n # Example usage (for testing)\n print(largest_prime_factor(13195)) # Output: 29\n print(largest_prime_factor(2048)) # Output: 2\n print(largest_prime_factor(600851475143))", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n i = 2\n largest_factor = 1\n\n while i * i <= n:\n if n % i == 0:\n largest_factor = i\n n //= i\n else:\n i += 1\n\n if n > largest_factor:\n largest_factor = n\n\n return largest_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n i = 2\n while i * i <= n:\n if n % i:\n i += 1\n else:\n n //= i\n return n", "matching_cluster_idx": 8}]}, "HumanEval/64": {"dps": 51.1038961038961, "dps_norm": 51.25, "pass@1": 100.0, "profiled": [{"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = \"aeiou\"\n count = 0\n s = s.lower()\n for i in range(len(s)):\n if s[i] in vowels:\n count += 1\n elif s[i] == 'y' and i == len(s) - 1:\n count += 1\n return count", "matching_cluster_idx": 3}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = \"aeiou\"\n count = 0\n for i, char in enumerate(s.lower()):\n if char in vowels:\n count += 1\n elif char == 'y' and i == len(s) - 1:\n count += 1\n return count", "matching_cluster_idx": 3}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = \"aeiou\"\n count = 0\n for i in range(len(s)):\n char = s[i].lower()\n if char in vowels:\n count += 1\n elif char == 'y' and i == len(s) - 1:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "import doctest\ndef vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = \"aeiou\"\n count = 0\n s = s.lower()\n for char in s:\n if char in vowels:\n count += 1\n if s.endswith(\"y\"):\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the given word.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = \"aeiou\"\n count = 0\n s = s.lower()\n for i in range(len(s)):\n if s[i] in vowels:\n count += 1\n elif s[i] == 'y' and i == len(s) - 1:\n count += 1\n return count", "matching_cluster_idx": 3}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = \"aeiou\"\n count = 0\n s = s.lower()\n for i, char in enumerate(s):\n if char in vowels:\n count += 1\n elif char == 'y' and i == len(s) - 1:\n count += 1\n return count", "matching_cluster_idx": 3}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = \"aeiou\"\n count = 0\n for i in range(len(s)):\n char = s[i].lower()\n if char in vowels:\n count += 1\n elif char == 'y' and i == len(s) - 1:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = \"aeiou\"\n count = 0\n for i, char in enumerate(s.lower()):\n if char in vowels:\n count += 1\n elif char == 'y' and i == len(s) - 1:\n count += 1\n return count", "matching_cluster_idx": 3}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = \"aeiou\"\n count = 0\n s = s.lower()\n for char in s:\n if char in vowels:\n count += 1\n if s.endswith('y'):\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = \"aeiou\"\n count = 0\n s = s.lower()\n for char in s:\n if char in vowels:\n count += 1\n if s.endswith('y'):\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = \"aeiou\"\n count = 0\n s = s.lower()\n for i in range(len(s)):\n if s[i] in vowels:\n count += 1\n elif s[i] == 'y' and i == len(s) - 1:\n count += 1\n return count", "matching_cluster_idx": 3}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = \"aeiou\"\n count = 0\n s = s.lower()\n for char in s:\n if char in vowels:\n count += 1\n if s.endswith('y'):\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = \"aeiou\"\n count = 0\n s = s.lower()\n for i, char in enumerate(s):\n if char in vowels:\n count += 1\n elif char == 'y' and i == len(s) - 1:\n count += 1\n return count", "matching_cluster_idx": 3}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = \"aeiou\"\n count = 0\n s = s.lower()\n for i in range(len(s)):\n if s[i] in vowels:\n count += 1\n elif s[i] == 'y' and i == len(s) - 1:\n count += 1\n return count", "matching_cluster_idx": 3}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = \"aeiou\"\n count = 0\n s = s.lower()\n for char in s:\n if char in vowels:\n count += 1\n if s.endswith('y'):\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = \"aeiou\"\n count = 0\n s = s.lower()\n for i in range(len(s)):\n if s[i] in vowels:\n count += 1\n elif s[i] == 'y' and i == len(s) - 1:\n count += 1\n return count", "matching_cluster_idx": 3}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = \"aeiou\"\n count = 0\n for i in range(len(s)):\n char = s[i].lower()\n if char in vowels:\n count += 1\n elif char == 'y' and i == len(s) - 1:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = \"aeiou\"\n count = 0\n s = s.lower()\n for i in range(len(s)):\n if s[i] in vowels:\n count += 1\n elif s[i] == 'y' and i == len(s) - 1:\n count += 1\n return count", "matching_cluster_idx": 3}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = \"aeiou\"\n count = 0\n for i, char in enumerate(s.lower()):\n if char in vowels:\n count += 1\n elif char == 'y' and i == len(s) - 1:\n count += 1\n return count", "matching_cluster_idx": 3}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = \"aeiou\"\n count = 0\n s = s.lower()\n for i in range(len(s)):\n if s[i] in vowels:\n count += 1\n elif s[i] == 'y' and i == len(s) - 1:\n count += 1\n return count", "matching_cluster_idx": 3}]}, "HumanEval/74": {"dps": 98.04878048780488, "dps_norm": 88.88888888888889, "pass@1": 100.0, "profiled": [{"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n sum1 = sum(len(s) for s in lst1)\n sum2 = sum(len(s) for s in lst2)\n\n if sum1 <= sum2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n sum1 = sum(len(s) for s in lst1)\n sum2 = sum(len(s) for s in lst2)\n\n if sum1 <= sum2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n sum1 = sum(len(s) for s in lst1)\n sum2 = sum(len(s) for s in lst2)\n\n if sum1 <= sum2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n sum1 = sum(len(s) for s in lst1)\n sum2 = sum(len(s) for s in lst2)\n\n if sum1 <= sum2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n sum1 = sum(len(s) for s in lst1)\n sum2 = sum(len(s) for s in lst2)\n\n if sum1 <= sum2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n sum1 = sum(len(s) for s in lst1)\n sum2 = sum(len(s) for s in lst2)\n\n if sum1 <= sum2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n sum1 = sum(len(s) for s in lst1)\n sum2 = sum(len(s) for s in lst2)\n\n if sum1 <= sum2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n sum1 = sum(len(s) for s in lst1)\n sum2 = sum(len(s) for s in lst2)\n\n if sum1 <= sum2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n sum1 = sum(len(s) for s in lst1)\n sum2 = sum(len(s) for s in lst2)\n\n if sum1 <= sum2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n sum1 = sum(len(s) for s in lst1)\n sum2 = sum(len(s) for s in lst2)\n\n if sum1 <= sum2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n sum1 = sum(len(s) for s in lst1)\n sum2 = sum(len(s) for s in lst2)\n\n if sum1 <= sum2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n sum1 = sum(len(s) for s in lst1)\n sum2 = sum(len(s) for s in lst2)\n\n if sum1 <= sum2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n sum1 = sum(len(s) for s in lst1)\n sum2 = sum(len(s) for s in lst2)\n\n if sum1 <= sum2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n sum1 = sum(len(s) for s in lst1)\n sum2 = sum(len(s) for s in lst2)\n\n if sum1 <= sum2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n sum1 = sum(len(s) for s in lst1)\n sum2 = sum(len(s) for s in lst2)\n\n if sum1 <= sum2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n sum1 = sum(len(s) for s in lst1)\n sum2 = sum(len(s) for s in lst2)\n\n if sum1 <= sum2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n sum1 = sum(len(s) for s in lst1)\n sum2 = sum(len(s) for s in lst2)\n\n if sum1 <= sum2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n sum1 = sum(len(s) for s in lst1)\n sum2 = sum(len(s) for s in lst2)\n\n if sum1 <= sum2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n sum1 = sum(len(s) for s in lst1)\n sum2 = sum(len(s) for s in lst2)\n\n if sum1 <= sum2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n sum1 = sum(len(s) for s in lst1)\n sum2 = sum(len(s) for s in lst2)\n\n if sum1 <= sum2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}]}, "HumanEval/85": {"dps": 95.02475247524752, "dps_norm": 64.16666666666667, "pass@1": 100.0, "profiled": [{"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices..\n\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n add([1, 3, 5]) ==> 0\n add([2, 4, 6, 8]) ==> 4 + 8 = 12\n add([1, 2, 3, 4, 5, 6]) == 2 + 4 + 6 = 12\n \"\"\"\n sum_even_at_odd_indices = 0\n for i in range(1, len(lst), 2): # Iterate over odd indices\n if lst[i] % 2 == 0: # Check if the element is even\n sum_even_at_odd_indices += lst[i]\n return sum_even_at_odd_indices", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices..\n\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n add([1, 2, 3, 4, 5, 6]) ==> 2 + 6 = 8\n add([1, 3, 5, 7]) ==> 0\n add([2, 4, 6, 8]) ==> 4 + 8 = 12\n \"\"\"\n sum_even_at_odd_indices = 0\n for i in range(1, len(lst), 2): # Iterate through odd indices\n if lst[i] % 2 == 0: # Check if the element at the odd index is even\n sum_even_at_odd_indices += lst[i]\n return sum_even_at_odd_indices", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices..\n\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n sum_even_at_odd = 0\n for i in range(1, len(lst), 2): # Iterate through odd indices\n if lst[i] % 2 == 0:\n sum_even_at_odd += lst[i]\n return sum_even_at_odd", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices..\n\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n add([1, 2, 3, 4]) ==> 2\n add([1, 3, 5, 7]) ==> 0\n add([2, 4, 6, 8]) ==> 4 + 8 = 12\n add([1, 2, 3, 4, 5, 6]) ==> 2 + 4 + 6 = 12\n \"\"\"\n sum_of_evens_at_odd_indices = 0\n for i in range(1, len(lst), 2): # Iterate through odd indices\n if lst[i] % 2 == 0:\n sum_of_evens_at_odd_indices += lst[i]\n return sum_of_evens_at_odd_indices", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices..\n\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n add([1, 3, 5, 7, 9]) == 0\n add([2, 4, 6, 8]) == 4 + 8 = 12\n add([1, 2, 3, 4, 5, 6]) == 2 + 4 + 6 = 12\n \"\"\"\n sum_even_at_odd_indices = 0\n for i in range(1, len(lst), 2): # Iterate through odd indices\n if lst[i] % 2 == 0:\n sum_even_at_odd_indices += lst[i]\n return sum_even_at_odd_indices", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices..\n\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n sum_even_at_odd_indices = 0\n for i in range(1, len(lst), 2): # Iterate through odd indices\n if lst[i] % 2 == 0: # Check if the element at the current index is even\n sum_even_at_odd_indices += lst[i]\n return sum_even_at_odd_indices", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices..\n\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n add([1, 3, 5]) == 0\n add([2, 4, 6]) == 4\n add([1, 2, 3, 4, 5, 6]) == 6\n \"\"\"\n sum_even_at_odd_indices = 0\n for i in range(1, len(lst), 2): # Iterate through odd indices\n if lst[i] % 2 == 0: # Check if the element at the current index is even\n sum_even_at_odd_indices += lst[i]\n return sum_even_at_odd_indices", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices..\n\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n add([1, 2, 3, 4, 5, 6]) ==> 2 + 6 = 8\n add([1, 3, 5, 7]) ==> 0\n add([2, 4, 6, 8]) ==> 4 + 8 = 12\n add([2]) ==> 0\n \"\"\"\n sum_even_at_odd_indices = 0\n for i in range(1, len(lst), 2): # Iterate through odd indices\n if lst[i] % 2 == 0:\n sum_even_at_odd_indices += lst[i]\n return sum_even_at_odd_indices", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices..\n\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n add([1, 2, 3, 4, 5, 6]) ==> 2 + 6 = 8\n add([1, 3, 5, 7]) ==> 0\n add([2, 4, 6, 8]) ==> 4 + 8 = 12\n add([1, 0, 1, 0]) ==> 0 + 0 = 0\n \"\"\"\n sum_even_at_odd_indices = 0\n for i in range(1, len(lst), 2): # Iterate through odd indices\n if lst[i] % 2 == 0: # Check if the element is even\n sum_even_at_odd_indices += lst[i]\n return sum_even_at_odd_indices", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices..\n\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n add([1, 2, 3, 4]) == 2\n add([1, 3, 5, 7]) == 0\n add([2, 4, 6, 8]) == 4 + 8 = 12\n add([10]) == 0\n\n\n \"\"\"\n sum_of_evens_at_odd_indices = 0\n for i in range(1, len(lst), 2): # Iterate over odd indices\n if lst[i] % 2 == 0:\n sum_of_evens_at_odd_indices += lst[i]\n return sum_of_evens_at_odd_indices", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices..\n\n\n Examples:\n add([4, 2, 6, 7]) ==> 2\n add([1, 2, 3, 4, 5, 6]) ==> 2 + 6 = 8\n add([1, 3, 5]) ==> 0\n add([2, 4, 6]) ==> 4\n \"\"\"\n sum_even_at_odd_indices = 0\n for i in range(1, len(lst), 2): # Iterate through odd indices\n if lst[i] % 2 == 0:\n sum_even_at_odd_indices += lst[i]\n return sum_even_at_odd_indices", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices..\n\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n add([1, 2, 3, 4, 5, 6]) ==> 2 + 6 = 8\n add([1, 3, 5]) == 0\n add([2, 4, 6]) == 4\n \"\"\"\n sum_even_at_odd_indices = 0\n for i in range(1, len(lst), 2): # Iterate through odd indices\n if lst[i] % 2 == 0: # Check if the element at the current index is even\n sum_even_at_odd_indices += lst[i]\n return sum_even_at_odd_indices", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices..\n\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n add([1, 2, 3, 4]) == 2\n add([1, 3, 5, 7]) == 0\n add([2, 4, 6, 8]) == 4 + 8 = 12\n add([2]) == 0\n \"\"\"\n sum_even_at_odd = 0\n for i in range(1, len(lst), 2): # Iterate through odd indices\n if lst[i] % 2 == 0:\n sum_even_at_odd += lst[i]\n return sum_even_at_odd", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices..\n\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n add([1, 2, 3, 4, 5, 6]) ==> 2 + 6 = 8\n add([1, 3, 5, 7]) ==> 0\n add([2, 4, 6, 8]) == > 4 + 8 = 12\n\n \"\"\"\n sum_of_evens_at_odd_indices = 0\n for i in range(1, len(lst), 2): # Iterate through odd indices\n if lst[i] % 2 == 0: # Check if the element at the current index is even\n sum_of_evens_at_odd_indices += lst[i]\n return sum_of_evens_at_odd_indices", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices..\n\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n add([1, 2, 3, 4]) ==> 2\n add([2, 4, 6, 8]) ===> 4 + 8 = 12\n add([1, 3, 5, 7]) ==> 0\n add([2]) ==> 0\n \"\"\"\n sum_even_at_odd_indices = 0\n for i in range(1, len(lst), 2): # Iterate through odd indices\n if lst[i] % 2 == 0: # Check if the element at the current index is even\n sum_even_at_odd_indices += lst[i]\n return sum_even_at_odd_indices", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices..\n\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n sum_even_at_odd_indices = 0\n for i in range(1, len(lst), 2): # Iterate through odd indices\n if lst[i] % 2 == 0:\n sum_even_at_odd_indices += lst[i]\n return sum_even_at_odd_indices", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices..\n\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n add([1, 2, 3, 4]) ==> 2\n add([1, 3, 5, 4, 2]) ==> 2\n add([2, 4, 6, 8]) ==> 4 + 8 = 12\n add([1, 2, 3, 4, 5, 6]) ==> 2 + 4 + 6 = 12\n \"\"\"\n sum_even_at_odd = 0\n for i in range(1, len(lst), 2): # Iterate through odd indices\n if lst[i] % 2 == 0: # Check if the element is even\n sum_even_at_odd += lst[i]\n return sum_even_at_odd", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices..\n\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n add([1, 2, 3, 4, 5, 6]) ==> 2 + 6 = 8\n add([1, 3, 5, 7]) ==> 0\n add([2, 4, 6, 8]) ==> 4 + 8 = 12\n add([2]) ==> 0\n \"\"\"\n sum_even_at_odd_indices = 0\n for i in range(1, len(lst), 2): # Iterate over odd indices\n if lst[i] % 2 == 0: # Check if the element at the current index is even\n sum_even_at_odd_indices += lst[i]\n return sum_even_at_odd_indices", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices..\n\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n sum_even_at_odd_indices = 0\n for i in range(1, len(lst), 2): # Iterate through odd indices\n if lst[i] % 2 == 0: # Check if the element is even\n sum_even_at_odd_indices += lst[i]\n return sum_even_at_odd_indices", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices..\n\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n add([1, 2, 3, 4]) == 2\n add([1, 3, 5, 7]) == 0\n add([2, 4, 6, 8]) == 4 + 8 == 12\n add([10, 12, 14, 16]) == 12 + 16 == 28\n \"\"\"\n sum_even_at_odd_indices = 0\n for i in range(1, len(lst), 2): # Iterate through odd indices\n if lst[i] % 2 == 0:\n sum_even_at_odd_indices += lst[i]\n return sum_even_at_odd_indices", "matching_cluster_idx": 2}]}, "HumanEval/86": {"dps": null, "dps_norm": null, "pass@1": 4.0, "profiled": []}, "HumanEval/87": {"dps": 64.43804034582132, "dps_norm": 51.42857142857143, "pass@1": 100.0, "profiled": [{"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n result = []\n for row_index, row in enumerate(lst):\n row_coords = []\n for col_index, val in enumerate(row):\n if val == x:\n row_coords.append((row_index, col_index))\n \n row_coords.sort(key=lambda coord: coord[1], reverse=True) # Sort by column descending\n result.extend(row_coords)\n\n return result", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n result = []\n for row_index, row in enumerate(lst):\n temp_indices = []\n for col_index, val in enumerate(row):\n if val == x:\n temp_indices.append(col_index)\n \n for col_index in reversed(temp_indices):\n result.append((row_index, col_index))\n \n return result", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n result = []\n for row_index, row in enumerate(lst):\n temp = []\n for col_index, val in enumerate(row):\n if val == x:\n temp.append((row_index, col_index))\n temp.sort(key=lambda item: item[1], reverse=True)\n result.extend(temp)\n return result", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n result = []\n for i, row in enumerate(lst):\n temp = []\n for j, val in enumerate(row):\n if val == x:\n temp.append((i, j))\n temp.sort(key=lambda coord: coord[1], reverse=True) # Sort columns in descending order\n result.extend(temp)\n return result", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n result = []\n for i, row in enumerate(lst):\n temp = []\n for j, val in enumerate(row):\n if val == x:\n temp.append((i, j))\n temp.sort(key=lambda item: item[1], reverse=True)\n result.extend(temp)\n return result", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n result = []\n for row_index, row in enumerate(lst):\n indices = []\n for col_index, value in enumerate(row):\n if value == x:\n indices.append(col_index)\n \n for col_index in sorted(indices, reverse=True):\n result.append((row_index, col_index))\n\n return result", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n result = []\n for row_index, row in enumerate(lst):\n indices = []\n for col_index, element in enumerate(row):\n if element == x:\n indices.append(col_index)\n \n for col_index in sorted(indices, reverse=True):\n result.append((row_index, col_index))\n \n return result", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n result = []\n for i in range(len(lst)):\n row_indices = []\n for j in range(len(lst[i])):\n if lst[i][j] == x:\n row_indices.append(j)\n row_indices.sort(reverse=True)\n for j in row_indices:\n result.append((i, j))\n return result", "matching_cluster_idx": 2}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n result = []\n for row_index, row in enumerate(lst):\n temp = []\n for col_index, element in enumerate(row):\n if element == x:\n temp.append((row_index, col_index))\n temp.sort(key=lambda item: item[1], reverse=True)\n result.extend(temp)\n\n return result", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n result = []\n for i in range(len(lst)):\n row_indices = []\n for j in range(len(lst[i])):\n if lst[i][j] == x:\n row_indices.append(j)\n \n row_indices.sort(reverse=True)\n for j in row_indices:\n result.append((i, j))\n \n return result", "matching_cluster_idx": 2}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n result = []\n for i, row in enumerate(lst):\n temp = []\n for j, val in enumerate(row):\n if val == x:\n temp.append((i, j))\n temp.sort(key=lambda coord: coord[1], reverse=True) # Sort columns in descending order\n result.extend(temp)\n return result", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n result = []\n for row_index, row in enumerate(lst):\n row_coords = []\n for col_index, value in enumerate(row):\n if value == x:\n row_coords.append((row_index, col_index))\n row_coords.sort(key=lambda coord: coord[1], reverse=True) # Sort by column descending\n result.extend(row_coords)\n return result", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n result = []\n for i, row in enumerate(lst):\n row_indices = []\n for j, val in enumerate(row):\n if val == x:\n row_indices.append(j)\n \n for j in sorted(row_indices, reverse=True):\n result.append((i, j))\n\n return result", "matching_cluster_idx": 2}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n result = []\n for row_index, row in enumerate(lst):\n row_coords = []\n for col_index, val in enumerate(row):\n if val == x:\n row_coords.append((row_index, col_index))\n row_coords.sort(key=lambda coord: coord[1], reverse=True) # Sort columns descending\n result.extend(row_coords)\n return result", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n result = []\n for i, row in enumerate(lst):\n row_indices = []\n for j, val in enumerate(row):\n if val == x:\n row_indices.append(j)\n \n for j in sorted(row_indices, reverse=True):\n result.append((i, j))\n \n return result", "matching_cluster_idx": 2}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n result = []\n for row_index, row in enumerate(lst):\n temp = []\n for col_index, val in enumerate(row):\n if val == x:\n temp.append((row_index, col_index))\n temp.sort(key=lambda item: item[1], reverse=True)\n result.extend(temp)\n return result", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n result = []\n for i, row in enumerate(lst):\n row_indices = []\n for j, val in enumerate(row):\n if val == x:\n row_indices.append(j)\n row_indices.sort(reverse=True)\n for j in row_indices:\n result.append((i, j))\n return result", "matching_cluster_idx": 2}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n result = []\n for i in range(len(lst)):\n row_indices = []\n for j in range(len(lst[i])):\n if lst[i][j] == x:\n row_indices.append(j)\n row_indices.sort(reverse=True)\n for j in row_indices:\n result.append((i, j))\n return result", "matching_cluster_idx": 2}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n result = []\n for i in range(len(lst)):\n row_indices = []\n for j in range(len(lst[i])):\n if lst[i][j] == x:\n row_indices.append(j)\n row_indices.sort(reverse=True)\n for j in row_indices:\n result.append((i, j))\n return result", "matching_cluster_idx": 2}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n result = []\n for i in range(len(lst)):\n row_indices = []\n for j in range(len(lst[i])):\n if lst[i][j] == x:\n row_indices.append(j)\n row_indices.sort(reverse=True)\n for j in row_indices:\n result.append((i, j))\n return result", "matching_cluster_idx": 2}]}, "HumanEval/89": {"dps": 96.64948453608248, "dps_norm": 28.571428571428573, "pass@1": 100.0, "profiled": [{"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n encrypted_string = \"\"\n for char in s:\n if 'a' <= char <= 'z':\n shifted_char = chr(((ord(char) - ord('a') + 4) % 26) + ord('a'))\n encrypted_string += shifted_char\n else:\n encrypted_string += char # Handle non-lowercase letters\n return encrypted_string", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n encrypted_string = \"\"\n for char in s:\n if 'a' <= char <= 'z':\n shifted_char = chr(((ord(char) - ord('a') + 4) % 26) + ord('a'))\n elif 'A' <= char <= 'Z':\n shifted_char = chr(((ord(char) - ord('A') + 4) % 26) + ord('A'))\n else:\n shifted_char = char # Keep non-alphabetic characters as they are\n encrypted_string += shifted_char\n return encrypted_string", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n encrypted_string = \"\"\n for char in s:\n if 'a' <= char <= 'z':\n start = ord('a')\n shifted_char = chr(((ord(char) - start + 4) % 26) + start)\n elif 'A' <= char <= 'Z':\n start = ord('A')\n shifted_char = chr(((ord(char) - start + 4) % 26) + start)\n else:\n shifted_char = char # Keep non-alphabetic characters unchanged\n encrypted_string += shifted_char\n return encrypted_string", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n encrypted_string = \"\"\n for char in s:\n if 'a' <= char <= 'z':\n shifted_char = chr(((ord(char) - ord('a') + 4) % 26) + ord('a'))\n elif 'A' <= char <= 'Z':\n shifted_char = chr(((ord(char) - ord('A') + 4) % 26) + ord('A'))\n else:\n shifted_char = char # Keep non-alphabetic characters as they are\n encrypted_string += shifted_char\n return encrypted_string", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n encrypted_string = \"\"\n for char in s:\n if 'a' <= char <= 'z':\n shifted_char = chr(((ord(char) - ord('a') + 4) % 26) + ord('a'))\n elif 'A' <= char <= 'Z':\n shifted_char = chr(((ord(char) - ord('A') + 4) % 26) + ord('A'))\n else:\n shifted_char = char # Keep non-alphabetic characters as they are\n encrypted_string += shifted_char\n return encrypted_string", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n encrypted_string = \"\"\n for char in s:\n if 'a' <= char <= 'z':\n shifted_char = chr(((ord(char) - ord('a') + 4) % 26) + ord('a'))\n encrypted_string += shifted_char\n else:\n encrypted_string += char # Handle non-lowercase letters\n\n return encrypted_string", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n encrypted_string = \"\"\n for char in s:\n if 'a' <= char <= 'z':\n shifted_char = chr(((ord(char) - ord('a') + 4) % 26) + ord('a'))\n elif 'A' <= char <= 'Z':\n shifted_char = chr(((ord(char) - ord('A') + 4) % 26) + ord('A'))\n else:\n shifted_char = char # Keep non-alphabetic characters as they are\n encrypted_string += shifted_char\n return encrypted_string", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n encrypted_string = \"\"\n for char in s:\n if 'a' <= char <= 'z':\n shifted_char = chr(((ord(char) - ord('a') + 4) % 26) + ord('a'))\n elif 'A' <= char <= 'Z':\n shifted_char = chr(((ord(char) - ord('A') + 4) % 26) + ord('A'))\n else:\n shifted_char = char # Keep non-alphabetic characters as they are\n encrypted_string += shifted_char\n return encrypted_string", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n encrypted_string = \"\"\n for char in s:\n if 'a' <= char <= 'z':\n start = ord('a')\n shifted_char = chr(start + (ord(char) - start + 4) % 26)\n elif 'A' <= char <= 'Z':\n start = ord('A')\n shifted_char = chr(start + (ord(char) - start + 4) % 26)\n else:\n shifted_char = char # Keep non-alphabetic characters as they are\n encrypted_string += shifted_char\n return encrypted_string", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n encrypted_string = \"\"\n for char in s:\n if 'a' <= char <= 'z':\n shifted_char = chr(((ord(char) - ord('a') + 4) % 26) + ord('a'))\n elif 'A' <= char <= 'Z':\n shifted_char = chr(((ord(char) - ord('A') + 4) % 26) + ord('A'))\n else:\n shifted_char = char # Keep non-alphabetic characters as they are\n encrypted_string += shifted_char\n return encrypted_string", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n encrypted_string = \"\"\n for char in s:\n if 'a' <= char <= 'z':\n shifted_char = chr(((ord(char) - ord('a') + 4) % 26) + ord('a'))\n elif 'A' <= char <= 'Z':\n shifted_char = chr(((ord(char) - ord('A') + 4) % 26) + ord('A'))\n else:\n shifted_char = char # Keep non-alphabetic characters as they are\n encrypted_string += shifted_char\n return encrypted_string", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n encrypted_string = \"\"\n for char in s:\n if 'a' <= char <= 'z':\n shifted_char = chr(((ord(char) - ord('a') + 4) % 26) + ord('a'))\n elif 'A' <= char <= 'Z':\n shifted_char = chr(((ord(char) - ord('A') + 4) % 26) + ord('A'))\n else:\n shifted_char = char # Keep non-alphabetic characters as they are\n encrypted_string += shifted_char\n return encrypted_string", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n encrypted_string = \"\"\n for char in s:\n if 'a' <= char <= 'z':\n shifted_char = chr(((ord(char) - ord('a') + 4) % 26) + ord('a')) # Shift by 4 (2*2)\n elif 'A' <= char <= 'Z':\n shifted_char = chr(((ord(char) - ord('A') + 4) % 26) + ord('A'))\n else:\n shifted_char = char # Keep non-alphabetic characters as they are\n encrypted_string += shifted_char\n return encrypted_string", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n encrypted_string = \"\"\n for char in s:\n if 'a' <= char <= 'z':\n shifted_char = chr(((ord(char) - ord('a') + 4) % 26) + ord('a'))\n elif 'A' <= char <= 'Z':\n shifted_char = chr(((ord(char) - ord('A') + 4) % 26) + ord('A'))\n else:\n shifted_char = char # Keep non-alphabetic characters as they are\n encrypted_string += shifted_char\n return encrypted_string", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n encrypted_string = \"\"\n for char in s:\n if 'a' <= char <= 'z':\n shifted_char = chr(((ord(char) - ord('a') + 4) % 26) + ord('a'))\n elif 'A' <= char <= 'Z':\n shifted_char = chr(((ord(char) - ord('A') + 4) % 26) + ord('A'))\n else:\n shifted_char = char # Keep non-alphabetic characters as they are\n encrypted_string += shifted_char\n return encrypted_string", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n encrypted_string = \"\"\n for char in s:\n if 'a' <= char <= 'z':\n shifted_char = chr(((ord(char) - ord('a') + 4) % 26) + ord('a'))\n elif 'A' <= char <= 'Z':\n shifted_char = chr(((ord(char) - ord('A') + 4) % 26) + ord('A'))\n else:\n shifted_char = char # Keep non-alphabetic characters as they are\n encrypted_string += shifted_char\n return encrypted_string", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n encrypted_string = \"\"\n for char in s:\n if 'a' <= char <= 'z':\n shifted_char = chr(((ord(char) - ord('a') + 4) % 26) + ord('a')) # Shift by 4 (2*2)\n elif 'A' <= char <= 'Z':\n shifted_char = chr(((ord(char) - ord('A') + 4) % 26) + ord('A'))\n else:\n shifted_char = char # Keep non-alphabetic characters as they are\n encrypted_string += shifted_char\n return encrypted_string", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n encrypted_string = \"\"\n for char in s:\n if 'a' <= char <= 'z':\n shifted_char = chr(((ord(char) - ord('a') + 4) % 26) + ord('a'))\n encrypted_string += shifted_char\n else:\n encrypted_string += char # Handle non-lowercase letters (optional)\n return encrypted_string", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n encrypted_string = \"\"\n for char in s:\n if 'a' <= char <= 'z':\n shifted_char = chr(((ord(char) - ord('a') + 4) % 26) + ord('a'))\n elif 'A' <= char <= 'Z':\n shifted_char = chr(((ord(char) - ord('A') + 4) % 26) + ord('A'))\n else:\n shifted_char = char # Keep non-alphabetic characters as they are\n encrypted_string += shifted_char\n return encrypted_string", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n encrypted_string = \"\"\n for char in s:\n if 'a' <= char <= 'z':\n rotated_char_ord = ord(char) + 4 # 2 * 2 = 4\n if rotated_char_ord > ord('z'):\n rotated_char_ord -= 26\n encrypted_string += chr(rotated_char_ord)\n else:\n encrypted_string += char # Handle non-alphabetic characters\n\n return encrypted_string", "matching_cluster_idx": 1}]}, "HumanEval/90": {"dps": 51.750972762645915, "dps_norm": 50.0, "pass@1": 100.0, "profiled": [{"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n\n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n\n unique_lst = sorted(list(set(lst))) # Remove duplicates and sort\n\n if len(unique_lst) < 2:\n return None\n\n return unique_lst[1]", "matching_cluster_idx": 5}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n\n unique_sorted_lst = sorted(list(set(lst)))\n\n if len(unique_sorted_lst) < 2:\n return None\n \n return unique_sorted_lst[1]", "matching_cluster_idx": 5}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n\n unique_lst = sorted(list(set(lst))) # Remove duplicates and sort\n\n if len(unique_lst) < 2:\n return None\n\n return unique_lst[1]", "matching_cluster_idx": 5}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n\n unique_lst = sorted(list(set(lst)))\n\n if len(unique_lst) < 2:\n return None\n \n return unique_lst[1]", "matching_cluster_idx": 5}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n\n unique_lst = sorted(list(set(lst))) # Remove duplicates and sort\n\n if len(unique_lst) < 2:\n return None\n\n return unique_lst[1]", "matching_cluster_idx": 5}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n\n unique_lst = sorted(list(set(lst))) # Remove duplicates and sort\n\n if len(unique_lst) < 2:\n return None\n\n return unique_lst[1]", "matching_cluster_idx": 5}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n\n unique_lst = sorted(list(set(lst))) # Remove duplicates and sort\n\n if len(unique_lst) < 2:\n return None\n\n return unique_lst[1]", "matching_cluster_idx": 5}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n\n unique_lst = sorted(list(set(lst))) # Remove duplicates and sort\n\n if len(unique_lst) < 2:\n return None\n\n return unique_lst[1]", "matching_cluster_idx": 5}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n\n unique_lst = sorted(list(set(lst))) # Remove duplicates and sort\n\n if len(unique_lst) < 2:\n return None\n\n return unique_lst[1]", "matching_cluster_idx": 5}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n\n unique_lst = sorted(list(set(lst)))\n\n if len(unique_lst) < 2:\n return None\n\n return unique_lst[1]", "matching_cluster_idx": 5}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n\n unique_lst = sorted(list(set(lst))) # Remove duplicates and sort\n\n if len(unique_lst) < 2:\n return None\n\n return unique_lst[1]", "matching_cluster_idx": 5}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n\n unique_lst = sorted(list(set(lst))) # Remove duplicates and sort\n\n if len(unique_lst) < 2:\n return None\n\n return unique_lst[1]", "matching_cluster_idx": 5}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n\n unique_sorted = sorted(list(set(lst))) # Remove duplicates and sort\n\n if len(unique_sorted) < 2:\n return None\n\n return unique_sorted[1]", "matching_cluster_idx": 5}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n\n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n\n unique_lst = sorted(list(set(lst))) # Remove duplicates and sort\n\n if len(unique_lst) < 2:\n return None\n\n return unique_lst[1]", "matching_cluster_idx": 5}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n\n unique_sorted_lst = sorted(list(set(lst)))\n\n if len(unique_sorted_lst) < 2:\n return None\n \n return unique_sorted_lst[1]", "matching_cluster_idx": 5}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n\n unique_lst = sorted(list(set(lst))) # Remove duplicates and sort\n\n if len(unique_lst) < 2:\n return None\n \n return unique_lst[1]", "matching_cluster_idx": 5}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n\n unique_lst = sorted(list(set(lst))) # Remove duplicates and sort\n\n if len(unique_lst) < 2:\n return None\n\n return unique_lst[1]", "matching_cluster_idx": 5}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n\n unique_lst = sorted(list(set(lst))) # Remove duplicates and sort\n\n if len(unique_lst) < 2:\n return None\n\n return unique_lst[1]", "matching_cluster_idx": 5}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n\n unique_lst = sorted(list(set(lst))) # Remove duplicates and sort\n\n if len(unique_lst) < 2:\n return None\n\n return unique_lst[1]", "matching_cluster_idx": 5}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n\n unique_lst = sorted(list(set(lst))) # Remove duplicates and sort\n\n if len(unique_lst) < 2:\n return None\n\n return unique_lst[1]", "matching_cluster_idx": 5}]}, "HumanEval/113": {"dps": 98.98580121703854, "dps_norm": 66.66666666666667, "pass@1": 100.0, "profiled": [{"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n result = []\n for s in lst:\n count = 0\n for char in s:\n if int(char) % 2 != 0:\n count += 1\n count_str = str(count)\n result.append(\"the number of odd elements \" + count_str + \"n the str\" + count_str + \"ng \" + count_str + \" of the \" + count_str + \"nput.\")\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n result = []\n for s in lst:\n count = 0\n for char in s:\n if int(char) % 2 != 0:\n count += 1\n count_str = str(count)\n result.append(\"the number of odd elements \" + count_str + \"n the str\" + count_str + \"ng \" + count_str + \" of the \" + count_str + \"nput.\")\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n result = []\n for s in lst:\n count = 0\n for digit in s:\n if int(digit) % 2 != 0:\n count += 1\n count_str = str(count)\n output_string = \"the number of odd elements \" + count_str + \"n the str\" + count_str + \"ng \" + count_str + \" of the \" + count_str + \"nput.\"\n result.append(output_string)\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n result = []\n for s in lst:\n count = 0\n for char in s:\n if int(char) % 2 != 0:\n count += 1\n count_str = str(count)\n new_string = \"the number of odd elements \" + count_str + \"n the str\" + count_str + \"ng \" + count_str + \" of the \" + count_str + \"nput.\"\n result.append(new_string)\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n result = []\n for s in lst:\n count = 0\n for char in s:\n if int(char) % 2 != 0:\n count += 1\n result.append(f\"the number of odd elements {count}n the str{count}ng {count} of the {count}nput.\")\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n result = []\n for s in lst:\n count = 0\n for digit in s:\n if int(digit) % 2 != 0:\n count += 1\n result.append(f\"the number of odd elements {count}n the str{count}ng {count} of the {count}nput.\")\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n result = []\n for s in lst:\n count = 0\n for digit in s:\n if int(digit) % 2 != 0:\n count += 1\n result.append(\"the number of odd elements \" + str(count) + \"n the str\" + str(count) + \"ng \" + str(count) + \" of the \" + str(count) + \"nput.\")\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n result = []\n for s in lst:\n count = 0\n for digit in s:\n if int(digit) % 2 != 0:\n count += 1\n count_str = str(count)\n result.append(\"the number of odd elements \" + count_str + \"n the str\" + count_str + \"ng \" + count_str + \" of the \" + count_str + \"nput.\")\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n result = []\n for s in lst:\n count = 0\n for digit in s:\n if int(digit) % 2 != 0:\n count += 1\n count_str = str(count)\n new_string = \"the number of odd elements \" + count_str + \"n the str\" + count_str + \"ng \" + count_str + \" of the \" + count_str + \"nput.\"\n result.append(new_string)\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n result = []\n for s in lst:\n count = 0\n for digit in s:\n if int(digit) % 2 != 0:\n count += 1\n result.append(f\"the number of odd elements {count}n the str{count}ng {count} of the {count}nput.\")\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n result = []\n for s in lst:\n count = 0\n for char in s:\n if int(char) % 2 != 0:\n count += 1\n result.append(f\"the number of odd elements {count}n the str{count}ng {count} of the {count}nput.\")\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n result = []\n for s in lst:\n count = 0\n for char in s:\n if int(char) % 2 != 0:\n count += 1\n\n new_string = \"the number of odd elements \" + str(count) + \"n the str\" + str(count) + \"ng \" + str(count) + \" of the \" + str(count) + \"nput.\"\n result.append(new_string)\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n result = []\n for s in lst:\n count = 0\n for char in s:\n if int(char) % 2 != 0:\n count += 1\n count_str = str(count)\n new_string = \"the number of odd elements \" + count_str + \"n the str\" + count_str + \"ng \" + count_str + \" of the \" + count_str + \"nput.\"\n result.append(new_string)\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n result = []\n for s in lst:\n count = 0\n for digit in s:\n if int(digit) % 2 != 0:\n count += 1\n count_str = str(count)\n new_string = \"the number of odd elements \" + count_str + \"n the str\" + count_str + \"ng \" + count_str + \" of the \" + count_str + \"nput.\"\n result.append(new_string)\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n result = []\n for s in lst:\n count = 0\n for char in s:\n if int(char) % 2 != 0:\n count += 1\n count_str = str(count)\n result.append(f\"the number of odd elements {count_str}n the str{count_str}ng {count_str} of the {count_str}nput.\")\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n result = []\n for s in lst:\n count = 0\n for char in s:\n if int(char) % 2 != 0:\n count += 1\n count_str = str(count)\n result.append(f\"the number of odd elements {count_str}n the str{count_str}ng {count_str} of the {count_str}nput.\")\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n result = []\n for s in lst:\n count = 0\n for digit in s:\n if int(digit) % 2 != 0:\n count += 1\n count_str = str(count)\n output_string = \"the number of odd elements \" + count_str + \"n the str\" + count_str + \"ng \" + count_str + \" of the \" + count_str + \"nput.\"\n result.append(output_string)\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n result = []\n for s in lst:\n count = 0\n for char in s:\n if int(char) % 2 != 0:\n count += 1\n \n output_string = \"the number of odd elements \" + str(count) + \"n the str\" + str(count) + \"ng \" + str(count) + \" of the \" + str(count) + \"nput.\"\n result.append(output_string)\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n result = []\n for s in lst:\n count = 0\n for digit in s:\n if int(digit) % 2 != 0:\n count += 1\n count_str = str(count)\n result.append(\"the number of odd elements \" + count_str + \"n the str\" + count_str + \"ng \" + count_str + \" of the \" + count_str + \"nput.\")\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n result = []\n for s in lst:\n count = 0\n for digit in s:\n if int(digit) % 2 != 0:\n count += 1\n\n output_string = \"the number of odd elements \" + str(count) + \"n the str\" + str(count) + \"ng \" + str(count) + \" of the \" + str(count) + \"nput.\"\n result.append(output_string)\n return result", "matching_cluster_idx": 3}]}, "HumanEval/119": {"dps": 25.58139534883721, "dps_norm": 84.0, "pass@1": 100.0, "profiled": [{"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n def is_balanced(s):\n count = 0\n for char in s:\n if char == '(':\n count += 1\n elif char == ')':\n count -= 1\n if count < 0:\n return False\n return count == 0\n\n s1, s2 = lst[0], lst[1]\n\n if is_balanced(s1 + s2):\n return 'Yes'\n \n if is_balanced(s2 + s1):\n return 'Yes'\n\n return 'No'", "matching_cluster_idx": 3}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n\n def is_balanced(s):\n count = 0\n for char in s:\n if char == '(':\n count += 1\n elif char == ')':\n count -= 1\n if count < 0:\n return False\n return count == 0\n\n s1, s2 = lst\n\n if is_balanced(s1 + s2):\n return 'Yes'\n\n if is_balanced(s2 + s1):\n return 'Yes'\n\n return 'No'", "matching_cluster_idx": 3}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n def is_balanced(s):\n count = 0\n for char in s:\n if char == '(':\n count += 1\n elif char == ')':\n count -= 1\n if count < 0:\n return False\n return count == 0\n\n s1, s2 = lst[0], lst[1]\n\n if is_balanced(s1 + s2):\n return 'Yes'\n if is_balanced(s2 + s1):\n return 'Yes'\n\n return 'No'", "matching_cluster_idx": 3}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n s1, s2 = lst\n\n def is_balanced(s):\n count = 0\n for char in s:\n if char == '(':\n count += 1\n elif char == ')':\n count -= 1\n if count < 0:\n return False\n return count == 0\n\n if is_balanced(s1 + s2):\n return 'Yes'\n if is_balanced(s2 + s1):\n return 'Yes'\n return 'No'", "matching_cluster_idx": 3}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n def is_balanced(s):\n count = 0\n for char in s:\n if char == '(':\n count += 1\n elif char == ')':\n count -= 1\n if count < 0:\n return False\n return count == 0\n\n s1, s2 = lst[0], lst[1]\n\n if is_balanced(s1 + s2):\n return 'Yes'\n elif is_balanced(s2 + s1):\n return 'Yes'\n else:\n return 'No'", "matching_cluster_idx": 3}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n\n def is_balanced(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n elif char == ')':\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n s1, s2 = lst[0], lst[1]\n\n if is_balanced(s1 + s2):\n return 'Yes'\n if is_balanced(s2 + s1):\n return 'Yes'\n\n return 'No'", "matching_cluster_idx": 3}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n\n def is_balanced(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n elif char == ')':\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n s1, s2 = lst\n\n if is_balanced(s1 + s2):\n return 'Yes'\n if is_balanced(s2 + s1):\n return 'Yes'\n \n return 'No'", "matching_cluster_idx": 3}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n\n def is_balanced(s):\n count = 0\n for char in s:\n if char == '(':\n count += 1\n elif char == ')':\n count -= 1\n if count < 0:\n return False\n return count == 0\n\n s1, s2 = lst\n\n if is_balanced(s1 + s2):\n return 'Yes'\n if is_balanced(s2 + s1):\n return 'Yes'\n \n return 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n def is_balanced(s):\n count = 0\n for char in s:\n if char == '(':\n count += 1\n elif char == ')':\n count -= 1\n if count < 0:\n return False\n return count == 0\n\n s1, s2 = lst[0], lst[1]\n\n if is_balanced(s1 + s2):\n return 'Yes'\n elif is_balanced(s2 + s1):\n return 'Yes'\n else:\n return 'No'", "matching_cluster_idx": 3}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n def is_balanced(s):\n count = 0\n for char in s:\n if char == '(':\n count += 1\n elif char == ')':\n count -= 1\n if count < 0:\n return False\n return count == 0\n\n s1, s2 = lst\n if is_balanced(s1 + s2):\n return 'Yes'\n if is_balanced(s2 + s1):\n return 'Yes'\n return 'No'", "matching_cluster_idx": 3}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n\n def is_balanced(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n elif char == ')':\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n s1, s2 = lst\n\n if is_balanced(s1 + s2):\n return 'Yes'\n elif is_balanced(s2 + s1):\n return 'Yes'\n else:\n return 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n\n def is_balanced(s):\n count = 0\n for char in s:\n if char == '(':\n count += 1\n elif char == ')':\n count -= 1\n if count < 0:\n return False\n return count == 0\n\n s1, s2 = lst[0], lst[1]\n\n if is_balanced(s1 + s2):\n return 'Yes'\n elif is_balanced(s2 + s1):\n return 'Yes'\n else:\n return 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n def is_balanced(s):\n count = 0\n for char in s:\n if char == '(':\n count += 1\n elif char == ')':\n count -= 1\n if count < 0:\n return False\n return count == 0\n\n s1, s2 = lst[0], lst[1]\n\n if is_balanced(s1 + s2):\n return 'Yes'\n elif is_balanced(s2 + s1):\n return 'Yes'\n else:\n return 'No'", "matching_cluster_idx": 3}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n\n def is_balanced(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n elif char == ')':\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n s1, s2 = lst\n\n if is_balanced(s1 + s2):\n return 'Yes'\n if is_balanced(s2 + s1):\n return 'Yes'\n\n return 'No'", "matching_cluster_idx": 3}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n\n def is_balanced(s):\n count = 0\n for char in s:\n if char == '(':\n count += 1\n elif char == ')':\n count -= 1\n if count < 0:\n return False\n return count == 0\n\n s1, s2 = lst[0], lst[1]\n\n if is_balanced(s1 + s2):\n return 'Yes'\n\n if is_balanced(s2 + s1):\n return 'Yes'\n\n return 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n\n def is_balanced(s):\n count = 0\n for char in s:\n if char == '(':\n count += 1\n elif char == ')':\n count -= 1\n if count < 0:\n return False\n return count == 0\n\n s1, s2 = lst[0], lst[1]\n\n if is_balanced(s1 + s2):\n return 'Yes'\n elif is_balanced(s2 + s1):\n return 'Yes'\n else:\n return 'No'", "matching_cluster_idx": 3}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n s1, s2 = lst\n\n def is_balanced(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n elif char == ')':\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n if is_balanced(s1 + s2):\n return 'Yes'\n if is_balanced(s2 + s1):\n return 'Yes'\n return 'No'", "matching_cluster_idx": 3}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n\n def is_balanced(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n elif char == ')':\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n s1, s2 = lst[0], lst[1]\n\n if is_balanced(s1 + s2):\n return 'Yes'\n elif is_balanced(s2 + s1):\n return 'Yes'\n else:\n return 'No'", "matching_cluster_idx": 3}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n def is_balanced(s):\n count = 0\n for char in s:\n if char == '(':\n count += 1\n elif char == ')':\n count -= 1\n if count < 0:\n return False\n return count == 0\n\n s1, s2 = lst[0], lst[1]\n\n if is_balanced(s1 + s2):\n return 'Yes'\n if is_balanced(s2 + s1):\n return 'Yes'\n\n return 'No'", "matching_cluster_idx": 3}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n\n def is_balanced(s):\n count = 0\n for char in s:\n if char == '(':\n count += 1\n elif char == ')':\n count -= 1\n if count < 0:\n return False\n return count == 0\n\n s1, s2 = lst[0], lst[1]\n\n if is_balanced(s1 + s2):\n return 'Yes'\n elif is_balanced(s2 + s1):\n return 'Yes'\n else:\n return 'No'", "matching_cluster_idx": 3}]}, "HumanEval/120": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 30.0, "profiled": [{"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n\n Example 1:\n\n Input: arr = [-3, -4, 5], k = 3\n Output: [-4, -3, 5]\n\n Example 2:\n\n Input: arr = [4, -4, 4], k = 2\n Output: [4, 4]\n\n Example 3:\n\n Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1\n Output: [2]\n\n Note:\n 1. The length of the array will be in the range of [1, 1000].\n 2. The elements in the array will be in the range of [-1000, 1000].\n 3. 0 <= k <= len(arr)\n \"\"\"\n arr.sort()\n return arr[-k:] if k > 0 else []", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n\n Example 1:\n\n Input: arr = [-3, -4, 5], k = 3\n Output: [-4, -3, 5]\n\n Example 2:\n\n Input: arr = [4, -4, 4], k = 2\n Output: [4, 4]\n\n Example 3:\n\n Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1\n Output: [2]\n\n Note:\n 1. The length of the array will be in the range of [1, 1000].\n 2. The elements in the array will be in the range of [-1000, 1000].\n 3. 0 <= k <= len(arr)\n \"\"\"\n arr.sort()\n return arr[-k:] if k > 0 else []", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n\n Example 1:\n\n Input: arr = [-3, -4, 5], k = 3\n Output: [-4, -3, 5]\n\n Example 2:\n\n Input: arr = [4, -4, 4], k = 2\n Output: [4, 4]\n\n Example 3:\n\n Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1\n Output: [2]\n\n Note:\n 1. The length of the array will be in the range of [1, 1000].\n 2. The elements in the array will be in the range of [-1000, 1000].\n 3. 0 <= k <= len(arr)\n \"\"\"\n arr.sort()\n return arr[-k:] if k > 0 else []", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n\n Example 1:\n\n Input: arr = [-3, -4, 5], k = 3\n Output: [-4, -3, 5]\n\n Example 2:\n\n Input: arr = [4, -4, 4], k = 2\n Output: [4, 4]\n\n Example 3:\n\n Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1\n Output: [2]\n\n Note:\n 1. The length of the array will be in the range of [1, 1000].\n 2. The elements in the array will be in the range of [-1000, 1000].\n 3. 0 <= k <= len(arr)\n \"\"\"\n return sorted(arr)[-k:] if k else []", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n\n Example 1:\n\n Input: arr = [-3, -4, 5], k = 3\n Output: [-4, -3, 5]\n\n Example 2:\n\n Input: arr = [4, -4, 4], k = 2\n Output: [4, 4]\n\n Example 3:\n\n Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1\n Output: [2]\n\n Note:\n 1. The length of the array will be in the range of [1, 1000].\n 2. The elements in the array will be in the range of [-1000, 1000].\n 3. 0 <= k <= len(arr)\n \"\"\"\n arr.sort() # Sort the array in ascending order\n return arr[-k:] if k > 0 else [] # Return the last k elements (largest)", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n\n Example 1:\n\n Input: arr = [-3, -4, 5], k = 3\n Output: [-4, -3, 5]\n\n Example 2:\n\n Input: arr = [4, -4, 4], k = 2\n Output: [4, 4]\n\n Example 3:\n\n Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1\n Output: [2]\n\n Note:\n 1. The length of the array will be in the range of [1, 1000].\n 2. The elements in the array will be in the range of [-1000, 1000].\n 3. 0 <= k <= len(arr)\n \"\"\"\n arr.sort()\n return arr[-k:] if k > 0 else []", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n\n Example 1:\n\n Input: arr = [-3, -4, 5], k = 3\n Output: [-4, -3, 5]\n\n Example 2:\n\n Input: arr = [4, -4, 4], k = 2\n Output: [4, 4]\n\n Example 3:\n\n Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1\n Output: [2]\n\n Note:\n 1. The length of the array will be in the range of [1, 1000].\n 2. The elements in the array will be in the range of [-1000, 1000].\n 3. 0 <= k <= len(arr)\n \"\"\"\n arr.sort() # Sort the array in ascending order\n return arr[len(arr) - k:] # Return the last k elements (largest)", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n\n Example 1:\n\n Input: arr = [-3, -4, 5], k = 3\n Output: [-4, -3, 5]\n\n Example 2:\n\n Input: arr = [4, -4, 4], k = 2\n Output: [4, 4]\n\n Example 3:\n\n Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1\n Output: [2]\n\n Note:\n 1. The length of the array will be in the range of [1, 1000].\n 2. The elements in the array will be in the range of [-1000, 1000].\n 3. 0 <= k <= len(arr)\n \"\"\"\n arr.sort()\n return arr[len(arr) - k:]", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n\n Example 1:\n\n Input: arr = [-3, -4, 5], k = 3\n Output: [-4, -3, 5]\n\n Example 2:\n\n Input: arr = [4, -4, 4], k = 2\n Output: [4, 4]\n\n Example 3:\n\n Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1\n Output: [2]\n\n Note:\n 1. The length of the array will be in the range of [1, 1000].\n 2. The elements in the array will be in the range of [-1000, 1000].\n 3. 0 <= k <= len(arr)\n \"\"\"\n arr.sort()\n return arr[-k:] if k > 0 else []", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n\n Example 1:\n\n Input: arr = [-3, -4, 5], k = 3\n Output: [-4, -3, 5]\n\n Example 2:\n\n Input: arr = [4, -4, 4], k = 2\n Output: [4, 4]\n\n Example 3:\n\n Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1\n Output: [2]\n\n Note:\n 1. The length of the array will be in the range of [1, 1000].\n 2. The elements in the array will be in the range of [-1000, 1000].\n 3. 0 <= k <= len(arr)\n \"\"\"\n arr.sort()\n return arr[-k:] if k > 0 else []", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n\n Example 1:\n\n Input: arr = [-3, -4, 5], k = 3\n Output: [-4, -3, 5]\n\n Example 2:\n\n Input: arr = [4, -4, 4], k = 2\n Output: [4, 4]\n\n Example 3:\n\n Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1\n Output: [2]\n\n Note:\n 1. The length of the array will be in the range of [1, 1000].\n 2. The elements in the array will be in the range of [-1000, 1000].\n 3. 0 <= k <= len(arr)\n \"\"\"\n arr.sort()\n return arr[-k:] if k > 0 else []", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n\n Example 1:\n\n Input: arr = [-3, -4, 5], k = 3\n Output: [-4, -3, 5]\n\n Example 2:\n\n Input: arr = [4, -4, 4], k = 2\n Output: [4, 4]\n\n Example 3:\n\n Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1\n Output: [2]\n\n Note:\n 1. The length of the array will be in the range of [1, 1000].\n 2. The elements in the array will be in the range of [-1000, 1000].\n 3. 0 <= k <= len(arr)\n \"\"\"\n arr.sort()\n return arr[-k:] if k > 0 else []", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n\n Example 1:\n\n Input: arr = [-3, -4, 5], k = 3\n Output: [-4, -3, 5]\n\n Example 2:\n\n Input: arr = [4, -4, 4], k = 2\n Output: [4, 4]\n\n Example 3:\n\n Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1\n Output: [2]\n\n Note:\n 1. The length of the array will be in the range of [1, 1000].\n 2. The elements in the array will be in the range of [-1000, 1000].\n 3. 0 <= k <= len(arr)\n \"\"\"\n arr.sort()\n return arr[-k:] if k > 0 else []", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n\n Example 1:\n\n Input: arr = [-3, -4, 5], k = 3\n Output: [-4, -3, 5]\n\n Example 2:\n\n Input: arr = [4, -4, 4], k = 2\n Output: [4, 4]\n\n Example 3:\n\n Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1\n Output: [2]\n\n Note:\n 1. The length of the array will be in the range of [1, 1000].\n 2. The elements in the array will be in the range of [-1000, 1000].\n 3. 0 <= k <= len(arr)\n \"\"\"\n arr.sort()\n return arr[-k:] if k > 0 else []", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n\n Example 1:\n\n Input: arr = [-3, -4, 5], k = 3\n Output: [-4, -3, 5]\n\n Example 2:\n\n Input: arr = [4, -4, 4], k = 2\n Output: [4, 4]\n\n Example 3:\n\n Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1\n Output: [2]\n\n Note:\n 1. The length of the array will be in the range of [1, 1000].\n 2. The elements in the array will be in the range of [-1000, 1000].\n 3. 0 <= k <= len(arr)\n \"\"\"\n arr.sort()\n return arr[-k:] if k > 0 else []", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n\n Example 1:\n\n Input: arr = [-3, -4, 5], k = 3\n Output: [-4, -3, 5]\n\n Example 2:\n\n Input: arr = [4, -4, 4], k = 2\n Output: [4, 4]\n\n Example 3:\n\n Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1\n Output: [2]\n\n Note:\n 1. The length of the array will be in the range of [1, 1000].\n 2. The elements in the array will be in the range of [-1000, 1000].\n 3. 0 <= k <= len(arr)\n \"\"\"\n arr.sort()\n return arr[-k:] if k > 0 else []", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n\n Example 1:\n\n Input: arr = [-3, -4, 5], k = 3\n Output: [-4, -3, 5]\n\n Example 2:\n\n Input: arr = [4, -4, 4], k = 2\n Output: [4, 4]\n\n Example 3:\n\n Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1\n Output: [2]\n\n Note:\n 1. The length of the array will be in the range of [1, 1000].\n 2. The elements in the array will be in the range of [-1000, 1000].\n 3. 0 <= k <= len(arr)\n \"\"\"\n arr.sort()\n return arr[-k:] if k > 0 else []", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n\n Example 1:\n\n Input: arr = [-3, -4, 5], k = 3\n Output: [-4, -3, 5]\n\n Example 2:\n\n Input: arr = [4, -4, 4], k = 2\n Output: [4, 4]\n\n Example 3:\n\n Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1\n Output: [2]\n\n Note:\n 1. The length of the array will be in the range of [1, 1000].\n 2. The elements in the array will be in the range of [-1000, 1000].\n 3. 0 <= k <= len(arr)\n \"\"\"\n arr.sort()\n return arr[-k:] if k > 0 else []", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n\n Example 1:\n\n Input: arr = [-3, -4, 5], k = 3\n Output: [-4, -3, 5]\n\n Example 2:\n\n Input: arr = [4, -4, 4], k = 2\n Output: [4, 4]\n\n Example 3:\n\n Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1\n Output: [2]\n\n Note:\n 1. The length of the array will be in the range of [1, 1000].\n 2. The elements in the array will be in the range of [-1000, 1000].\n 3. 0 <= k <= len(arr)\n \"\"\"\n arr.sort()\n return arr[-k:] if k > 0 else []", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n\n Example 1:\n\n Input: arr = [-3, -4, 5], k = 3\n Output: [-4, -3, 5]\n\n Example 2:\n\n Input: arr = [4, -4, 4], k = 2\n Output: [4, 4]\n\n Example 3:\n\n Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1\n Output: [2]\n\n Note:\n 1. The length of the array will be in the range of [1, 1000].\n 2. The elements in the array will be in the range of [-1000, 1000].\n 3. 0 <= k <= len(arr)\n \"\"\"\n arr.sort()\n return arr[-k:] if k > 0 else []", "matching_cluster_idx": 6}]}, "HumanEval/121": {"dps": null, "dps_norm": null, "pass@1": 0.0, "profiled": []}, "HumanEval/149": {"dps": 85.82677165354332, "dps_norm": 57.142857142857146, "pass@1": 100.0, "profiled": [{"solution": "def sorted_list_sum(lst):\n \"\"\"\n Accepts a list of strings, removes strings with odd lengths,\n and returns the remaining strings sorted by length then alphabetically.\n\n Args:\n lst: A list of strings.\n\n Returns:\n A list of strings sorted by length then alphabetically.\n \"\"\"\n even_length_strings = [s for s in lst if len(s) % 2 == 0]\n return sorted(even_length_strings, key=lambda x: (len(x), x))", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"\n Accepts a list of strings, removes strings with odd lengths,\n and returns the remaining strings sorted by length then alphabetically.\n\n Args:\n lst: A list of strings.\n\n Returns:\n A list of strings sorted by length then alphabetically.\n \"\"\"\n\n even_length_strings = [s for s in lst if len(s) % 2 == 0]\n return sorted(even_length_strings, key=lambda x: (len(x), x))", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"\n Accepts a list of strings, removes strings with odd lengths,\n and returns the remaining strings sorted by length then alphabetically.\n\n Args:\n lst: A list of strings.\n\n Returns:\n A list of strings sorted as described.\n \"\"\"\n even_length_strings = [s for s in lst if len(s) % 2 == 0]\n return sorted(even_length_strings, key=lambda s: (len(s), s))", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"\n Accepts a list of strings, removes strings with odd lengths,\n and returns the remaining strings sorted by length then alphabetically.\n\n For example:\n assert sorted_list_sum([\"aa\", \"a\", \"aaa\"]) == [\"aa\"]\n assert sorted_list_sum([\"ab\", \"a\", \"aaa\", \"cd\"]) == [\"ab\", \"cd\"]\n \"\"\"\n\n # Filter out strings with odd lengths\n even_length_strings = [s for s in lst if len(s) % 2 == 0]\n\n # Sort by length, then alphabetically for strings with the same length\n even_length_strings.sort(key=lambda s: (len(s), s))\n\n return even_length_strings", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"\n Accepts a list of strings, removes strings with odd lengths,\n and returns the remaining strings sorted by length then alphabetically.\n\n Args:\n lst: A list of strings.\n\n Returns:\n A list of strings sorted by length then alphabetically.\n \"\"\"\n\n even_length_strings = [s for s in lst if len(s) % 2 == 0]\n return sorted(even_length_strings, key=lambda s: (len(s), s))", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"\n Accepts a list of strings, removes strings with odd lengths,\n and returns the remaining strings sorted by length then alphabetically.\n\n Args:\n lst: A list of strings.\n\n Returns:\n A list of strings sorted by length then alphabetically.\n \"\"\"\n\n even_length_strings = [s for s in lst if len(s) % 2 == 0]\n return sorted(even_length_strings, key=lambda s: (len(s), s))", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"\n Accepts a list of strings, removes strings with odd lengths,\n and returns the remaining strings sorted by length then alphabetically.\n\n Args:\n lst: A list of strings.\n\n Returns:\n A list of strings sorted as described.\n \"\"\"\n even_length_strings = [s for s in lst if len(s) % 2 == 0]\n return sorted(even_length_strings, key=lambda s: (len(s), s))", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"\n Accepts a list of strings, removes strings with odd lengths,\n and returns the remaining strings sorted by length then alphabetically.\n\n Args:\n lst: A list of strings.\n\n Returns:\n A list of strings sorted as described.\n \"\"\"\n\n even_length_strings = [s for s in lst if len(s) % 2 == 0]\n even_length_strings.sort(key=lambda s: (len(s), s)) # Sort by length, then alphabetically\n return even_length_strings", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"\n Accepts a list of strings, removes strings with odd lengths,\n and returns the remaining strings sorted by length then alphabetically.\n\n Args:\n lst: A list of strings.\n\n Returns:\n A list of strings sorted by length then alphabetically.\n \"\"\"\n\n even_length_strings = [s for s in lst if len(s) % 2 == 0]\n return sorted(even_length_strings, key=lambda x: (len(x), x))", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"\n Accepts a list of strings, removes strings with odd lengths,\n and returns the remaining strings sorted by length then alphabetically.\n\n Args:\n lst: A list of strings.\n\n Returns:\n A list of strings sorted as described.\n \"\"\"\n\n even_length_strings = [s for s in lst if len(s) % 2 == 0]\n return sorted(even_length_strings, key=lambda s: (len(s), s))", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"\n Accepts a list of strings, removes strings with odd lengths, \n and returns the remaining strings sorted by length then alphabetically.\n\n Args:\n lst: A list of strings.\n\n Returns:\n A list of strings sorted by length then alphabetically.\n \"\"\"\n even_length_strings = [s for s in lst if len(s) % 2 == 0]\n return sorted(even_length_strings, key=lambda x: (len(x), x))", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"\n Accepts a list of strings, removes strings with odd lengths,\n and returns the remaining strings sorted by length then alphabetically.\n\n For example:\n assert sorted_list_sum([\"aa\", \"a\", \"aaa\"]) == [\"aa\"]\n assert sorted_list_sum([\"ab\", \"a\", \"aaa\", \"cd\"]) == [\"ab\", \"cd\"]\n assert sorted_list_sum([\"aba\", \"aa\", \"aaa\", \"a\", \"cccc\"]) == [\"aa\", \"cccc\"]\n \"\"\"\n\n even_length_strings = [s for s in lst if len(s) % 2 == 0]\n return sorted(even_length_strings, key=lambda s: (len(s), s))", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"\n Accepts a list of strings, removes strings with odd lengths, \n and returns the remaining strings sorted by length then alphabetically.\n\n Args:\n lst: A list of strings.\n\n Returns:\n A list of strings sorted by length then alphabetically.\n \"\"\"\n filtered_list = [s for s in lst if len(s) % 2 == 0]\n filtered_list.sort(key=lambda s: (len(s), s)) # Sort by length then alphabetically\n return filtered_list", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"\n Accepts a list of strings, removes strings with odd lengths,\n and returns the remaining strings sorted by length then alphabetically.\n\n Args:\n lst: A list of strings.\n\n Returns:\n A list of strings sorted by length then alphabetically.\n \"\"\"\n\n # Filter out strings with odd lengths\n even_length_strings = [s for s in lst if len(s) % 2 == 0]\n\n # Sort the remaining strings by length then alphabetically\n even_length_strings.sort(key=lambda s: (len(s), s))\n\n return even_length_strings", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"\n Accepts a list of strings, removes strings with odd lengths,\n and returns the remaining strings sorted by length then alphabetically.\n \"\"\"\n even_length_strings = [s for s in lst if len(s) % 2 == 0]\n return sorted(even_length_strings, key=lambda s: (len(s), s))", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"\n Accepts a list of strings, removes strings with odd lengths,\n and returns the remaining strings sorted by length then alphabetically.\n\n Args:\n lst: A list of strings.\n\n Returns:\n A list of strings sorted as described.\n \"\"\"\n even_length_strings = [s for s in lst if len(s) % 2 == 0]\n return sorted(even_length_strings, key=lambda s: (len(s), s))", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"\n Accepts a list of strings, removes strings with odd lengths,\n and returns the remaining strings sorted by length then alphabetically.\n\n Args:\n lst: A list of strings.\n\n Returns:\n A list of strings sorted by length then alphabetically.\n \"\"\"\n\n even_length_strings = [s for s in lst if len(s) % 2 == 0]\n return sorted(even_length_strings, key=lambda x: (len(x), x))", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"Accepts a list of strings, removes odd-length strings, \n and returns a sorted list based on length then alphabetically.\n\n Args:\n lst: A list of strings.\n\n Returns:\n A list of strings sorted by length then alphabetically.\n \"\"\"\n even_length_strings = [s for s in lst if len(s) % 2 == 0]\n even_length_strings.sort(key=lambda x: (len(x), x)) # Sort by length, then alphabetically\n return even_length_strings", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"\n Accepts a list of strings, removes strings with odd lengths,\n and returns the remaining strings sorted by length then alphabetically.\n\n Args:\n lst: A list of strings.\n\n Returns:\n A list of strings sorted as described.\n \"\"\"\n\n even_length_strings = [s for s in lst if len(s) % 2 == 0]\n return sorted(even_length_strings, key=lambda s: (len(s), s))", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"\n Accepts a list of strings, removes strings with odd lengths,\n and returns the remaining strings sorted by length then alphabetically.\n\n Args:\n lst: A list of strings.\n\n Returns:\n A list of strings sorted by length then alphabetically.\n \"\"\"\n\n even_length_strings = [s for s in lst if len(s) % 2 == 0]\n return sorted(even_length_strings, key=lambda s: (len(s), s))", "matching_cluster_idx": 3}]}, "Mbpp/3": {"dps": 85.46610169491525, "dps_norm": 91.875, "pass@1": 100.0, "profiled": [{"solution": "import math\ndef is_not_prime(num):\n \"\"\"\n Checks if a number is NOT a prime number.\n\n Args:\n num: An integer.\n\n Returns:\n True if num is not prime, False otherwise.\n \"\"\"\n if num <= 1:\n return True # 1 and numbers less than 1 are not prime\n if num <= 3:\n return False # 2 and 3 are prime\n\n # Optimization: Check divisibility only up to the square root of num\n for i in range(2, int(math.sqrt(num)) + 1):\n if num % i == 0:\n return True\n\n return False", "matching_cluster_idx": 4}, {"solution": "import math\ndef is_not_prime(num):\n \"\"\"\n Checks if a number is NOT prime.\n\n Args:\n num: The number to check.\n\n Returns:\n True if the number is not prime, False otherwise.\n \"\"\"\n if num <= 1:\n return True # 1 and numbers less than 1 are not prime\n if num <= 3:\n return False # 2 and 3 are prime\n\n # Check for divisibility by 2 and 3\n if num % 2 == 0 or num % 3 == 0:\n return True\n\n # Optimized primality test using 6k \u00b1 1 optimization.\n # All prime numbers greater than 3 can be expressed in the form 6k \u00b1 1.\n for i in range(5, int(math.sqrt(num)) + 1, 6):\n if num % i == 0 or num % (i + 2) == 0:\n return True\n\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(num):\n \"\"\"\n Checks if a number is NOT prime.\n\n Args:\n num: The number to check.\n\n Returns:\n True if the number is not prime, False otherwise.\n \"\"\"\n if num <= 1:\n return True # 1 and numbers less than 1 are not prime\n if num <= 3:\n return False # 2 and 3 are prime\n if num % 2 == 0 or num % 3 == 0:\n return True # Divisible by 2 or 3\n\n i = 5\n while i * i <= num:\n if num % i == 0 or num % (i + 2) == 0:\n return True\n i += 6\n\n return False", "matching_cluster_idx": 7}, {"solution": "import math\ndef is_not_prime(num):\n \"\"\"\n Checks if a number is NOT prime.\n\n Args:\n num: The number to check.\n\n Returns:\n True if the number is NOT prime, False otherwise.\n \"\"\"\n if num <= 1:\n return True # 1 and numbers less than 1 are not prime\n if num <= 3:\n return False # 2 and 3 are prime\n\n # Optimization: Check divisibility only up to the square root of num\n for i in range(2, int(math.sqrt(num)) + 1):\n if num % i == 0:\n return True # Found a divisor, so it's not prime\n return False # No divisors found, so it's prime", "matching_cluster_idx": 5}, {"solution": "import math\ndef is_not_prime(num):\n \"\"\"\n Checks if a number is NOT a prime number.\n\n Args:\n num: An integer.\n\n Returns:\n True if num is not prime, False otherwise.\n \"\"\"\n if num <= 1:\n return True # 1 and numbers less than 1 are not prime\n if num <= 3:\n return False # 2 and 3 are prime\n if num % 2 == 0 or num % 3 == 0:\n return True # Divisible by 2 or 3, not prime\n\n # Optimized primality test using 6k \u00b1 1 optimization\n for i in range(5, int(math.sqrt(num)) + 1, 6):\n if num % i == 0 or num % (i + 2) == 0:\n return True\n\n return False", "matching_cluster_idx": 7}, {"solution": "import math\ndef is_not_prime(num):\n \"\"\"\n Checks if a number is NOT prime.\n\n Args:\n num: The number to check.\n\n Returns:\n True if the number is not prime, False otherwise.\n \"\"\"\n if num <= 1:\n return True # 1 and numbers less than 1 are not prime\n if num <= 3:\n return False # 2 and 3 are prime\n if num % 2 == 0 or num % 3 == 0:\n return True # Divisible by 2 or 3\n\n # Optimized primality test: Check divisibility only for 6k \u00b1 1 up to sqrt(num)\n for i in range(5, int(math.sqrt(num)) + 1, 6):\n if num % i == 0 or num % (i + 2) == 0:\n return True\n\n return False", "matching_cluster_idx": 7}, {"solution": "import math\ndef is_not_prime(n):\n \"\"\"\n Checks if a number is NOT a prime number.\n\n Args:\n n: The number to check.\n\n Returns:\n True if n is not a prime number (including 0, 1, and negative numbers), False otherwise.\n \"\"\"\n if n <= 1:\n return True # 0 and 1 are not prime\n\n if n <= 3:\n return False # 2 and 3 are prime\n\n if n % 2 == 0 or n % 3 == 0:\n return True\n\n # Optimized primality test. Check divisibility only by 6k \u00b1 1\n for i in range(5, int(math.sqrt(n)) + 1, 6):\n if n % i == 0 or n % (i + 2) == 0:\n return True\n\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(num):\n \"\"\"\n Checks if a number is NOT prime.\n\n Args:\n num: The number to check.\n\n Returns:\n True if the number is not prime, False otherwise.\n Returns True for num <= 1 as well.\n \"\"\"\n if num <= 1:\n return True\n\n # Optimization: Check divisibility only up to the square root of num\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n return True\n return False", "matching_cluster_idx": 5}, {"solution": "import math\ndef is_not_prime(num):\n \"\"\"\n Checks if a number is NOT a prime number.\n\n Args:\n num: The number to check.\n\n Returns:\n True if the number is not prime, False otherwise.\n \"\"\"\n\n if num <= 1:\n return True # 1 and numbers less than 1 are not prime\n\n # Optimize by only checking up to the square root of num\n for i in range(2, int(math.sqrt(num)) + 1):\n if num % i == 0:\n return True # Found a divisor, so not prime\n\n return False # No divisors found, so it's prime", "matching_cluster_idx": 5}, {"solution": "import math\ndef is_not_prime(num):\n \"\"\"\n Checks if a number is NOT a prime number.\n\n Args:\n num: The number to check.\n\n Returns:\n True if the number is not prime, False otherwise.\n \"\"\"\n\n if num <= 1:\n return True # 1 and numbers less than 1 are not prime\n\n if num <= 3:\n return False # 2 and 3 are prime\n\n if num % 2 == 0 or num % 3 == 0:\n return True # Divisible by 2 or 3\n\n # Optimized primality test using 6k \u00b1 1 optimization\n for i in range(5, int(math.sqrt(num)) + 1, 6):\n if num % i == 0 or num % (i + 2) == 0:\n return True\n\n return False", "matching_cluster_idx": 7}, {"solution": "import math\ndef is_not_prime(num):\n \"\"\"\n Checks if a number is NOT prime.\n\n Args:\n num: The number to check.\n\n Returns:\n True if the number is not prime, False otherwise.\n \"\"\"\n if num <= 1:\n return True # 1 and numbers less than 1 are not prime\n if num <= 3:\n return False # 2 and 3 are prime\n if num % 2 == 0:\n return True # Even numbers greater than 2 are not prime\n\n # Optimized primality test: Check divisibility only up to the square root of num\n # and only for odd numbers.\n for i in range(3, int(math.sqrt(num)) + 1, 2):\n if num % i == 0:\n return True\n\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(num):\n \"\"\"\n Checks if a number is NOT prime.\n\n Args:\n num: The number to check.\n\n Returns:\n True if the number is not prime, False otherwise.\n \"\"\"\n if num <= 1:\n return True # 1 and numbers less than 1 are not prime\n if num <= 3:\n return False # 2 and 3 are prime\n if num % 2 == 0:\n return True # Even numbers greater than 2 are not prime\n\n # Iterate only through odd numbers up to the square root of num\n for i in range(3, int(num**0.5) + 1, 2):\n if num % i == 0:\n return True\n\n return False", "matching_cluster_idx": 7}, {"solution": "import math\ndef is_not_prime(num):\n \"\"\"\n Checks if a number is NOT a prime number.\n\n Args:\n num: The number to check.\n\n Returns:\n True if the number is not prime, False otherwise.\n \"\"\"\n if num <= 1:\n return True # 1 and numbers less than 1 are not prime\n if num <= 3:\n return False # 2 and 3 are prime\n\n # Check for divisibility by 2 and 3 explicitly for efficiency\n if num % 2 == 0 or num % 3 == 0:\n return True\n\n # Iterate from 5 up to the square root of num with a step of 6\n # (6k \u00b1 1 optimization)\n for i in range(5, int(math.sqrt(num)) + 1, 6):\n if num % i == 0 or num % (i + 2) == 0:\n return True\n\n return False", "matching_cluster_idx": 7}, {"solution": "import math\ndef is_not_prime(num):\n \"\"\"\n Checks if a number is NOT prime.\n\n Args:\n num: The number to check.\n\n Returns:\n True if the number is not prime, False otherwise.\n \"\"\"\n if num <= 1:\n return True # 1 and numbers less than 1 are not prime\n if num <= 3:\n return False # 2 and 3 are prime\n if num % 2 == 0 or num % 3 == 0:\n return True\n\n # Optimized primality test. Check divisibility only by 6k \u00b1 1 up to sqrt(n)\n for i in range(5, int(math.sqrt(num)) + 1, 6):\n if num % i == 0 or num % (i + 2) == 0:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "import math\ndef is_not_prime(num):\n \"\"\"\n Checks if a number is NOT a prime number.\n\n Args:\n num: An integer.\n\n Returns:\n True if num is not prime, False otherwise.\n \"\"\"\n if num <= 1:\n return True # 1 and numbers less than 1 are not prime\n if num <= 3:\n return False # 2 and 3 are prime\n if num % 2 == 0 or num % 3 == 0:\n return True\n\n # Optimized primality test: Iterate only up to the square root of num\n # and check divisibility by 6k \u00b1 1. This is because all primes greater\n # than 3 can be expressed in the form 6k \u00b1 1.\n\n for i in range(5, int(math.sqrt(num)) + 1, 6):\n if num % i == 0 or num % (i + 2) == 0:\n return True\n\n return False", "matching_cluster_idx": 7}, {"solution": "import math\ndef is_not_prime(num):\n \"\"\"\n Checks if a number is NOT a prime number.\n\n Args:\n num: An integer.\n\n Returns:\n True if num is not a prime number, False otherwise.\n \"\"\"\n if num <= 1:\n return True # 1 and numbers less than 1 are not prime\n if num <= 3:\n return False # 2 and 3 are prime\n\n # Optimization: Check divisibility only up to the square root of num\n for i in range(2, int(math.sqrt(num)) + 1):\n if num % i == 0:\n return True # Found a divisor, so it's not prime\n\n return False # No divisors found, so it's prime", "matching_cluster_idx": 5}, {"solution": "import math\ndef is_not_prime(num):\n \"\"\"\n Checks if a number is NOT a prime number.\n\n Args:\n num: The number to check.\n\n Returns:\n True if the number is not prime, False otherwise.\n \"\"\"\n\n if num <= 1:\n return True # 1 and numbers less than 1 are not prime\n\n if num <= 3:\n return False # 2 and 3 are prime\n\n if num % 2 == 0 or num % 3 == 0:\n return True # Divisible by 2 or 3\n\n # Optimized primality test using 6k \u00b1 1 optimization\n for i in range(5, int(math.sqrt(num)) + 1, 6):\n if num % i == 0 or num % (i + 2) == 0:\n return True\n\n return False", "matching_cluster_idx": 7}, {"solution": "import math\ndef is_not_prime(num):\n \"\"\"\n Checks if a number is NOT prime.\n\n Args:\n num: The number to check.\n\n Returns:\n True if the number is not prime, False otherwise.\n Returns True for numbers less than 2.\n \"\"\"\n if num < 2:\n return True # Numbers less than 2 are not prime\n\n for i in range(2, int(math.sqrt(num)) + 1):\n if num % i == 0:\n return True\n return False", "matching_cluster_idx": 5}, {"solution": "import math\ndef is_not_prime(num):\n \"\"\"\n Checks if a number is NOT a prime number.\n\n Args:\n num: The number to check.\n\n Returns:\n True if the number is not prime, False otherwise.\n \"\"\"\n\n if num <= 1:\n return True # 1 and numbers less than 1 are not prime\n\n if num <= 3:\n return False # 2 and 3 are prime\n\n if num % 2 == 0 or num % 3 == 0:\n return True # Divisible by 2 or 3\n\n # Optimized primality test, check divisibility only for 6k \u00b1 1\n for i in range(5, int(math.sqrt(num)) + 1, 6):\n if num % i == 0 or num % (i + 2) == 0:\n return True\n\n return False", "matching_cluster_idx": 7}, {"solution": "import math\ndef is_not_prime(num):\n \"\"\"\n Checks if a number is NOT a prime number.\n\n Args:\n num: The number to check.\n\n Returns:\n True if the number is not prime, False otherwise.\n \"\"\"\n if num <= 1:\n return True # 1 and numbers less than 1 are not prime\n if num <= 3:\n return False # 2 and 3 are prime\n if num % 2 == 0 or num % 3 == 0:\n return True # Divisible by 2 or 3\n\n # Optimized primality test, checking divisibility only up to the square root of num\n # and incrementing by 6 (6k \u00b1 1 optimization). This is because all primes greater than 3\n # can be expressed in the form 6k \u00b1 1.\n for i in range(5, int(math.sqrt(num)) + 1, 6):\n if num % i == 0 or num % (i + 2) == 0:\n return True\n return False", "matching_cluster_idx": 7}]}, "Mbpp/4": {"dps": 76.70648464163823, "dps_norm": 81.25, "pass@1": 91.0, "profiled": [{"solution": "import heapq\ndef heap_queue_largest(nums, n):\n \"\"\"\n Finds the n largest integers from a given list of numbers using a heap queue.\n\n Args:\n nums: A list of numbers.\n n: The number of largest integers to find.\n\n Returns:\n A list of the n largest integers in descending order.\n \"\"\"\n return heapq.nlargest(n, nums)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n \"\"\"\n Finds the n largest integers from a given list of numbers, returned in descending order.\n\n Args:\n nums: A list of numbers.\n n: The number of largest integers to find.\n\n Returns:\n A list of the n largest integers in descending order.\n \"\"\"\n return sorted(heapq.nlargest(n, nums), reverse=True)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n \"\"\"\n Finds the n largest integers from a given list of numbers, returned in descending order.\n\n Args:\n nums: A list of numbers.\n n: The number of largest integers to find.\n\n Returns:\n A list of the n largest integers in descending order.\n \"\"\"\n return heapq.nlargest(n, nums)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n \"\"\"\n Finds the n largest integers from a given list of numbers, returned in descending order.\n\n Args:\n nums: A list of numbers.\n n: The number of largest integers to find.\n\n Returns:\n A list containing the n largest integers in descending order.\n Returns an empty list if n is 0 or nums is empty.\n Returns the sorted nums in descending order if n is greater than or equal to the length of nums.\n \"\"\"\n if not nums or n == 0:\n return []\n if n >= len(nums):\n return sorted(nums, reverse=True)\n return heapq.nlargest(n, nums)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n \"\"\"\n Finds the n largest integers from a given list of numbers using a heap queue.\n\n Args:\n nums: A list of numbers.\n n: The number of largest integers to find.\n\n Returns:\n A list containing the n largest integers in descending order.\n Returns an empty list if n is 0 or negative or if the input list is empty.\n \"\"\"\n\n if n <= 0 or not nums:\n return []\n \n return heapq.nlargest(n, nums, key=lambda x: x)", "matching_cluster_idx": 8}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n \"\"\"\n Finds the n largest integers from a list using a min-heap.\n\n Args:\n nums: The input list of numbers.\n n: The number of largest integers to find.\n\n Returns:\n A list containing the n largest integers in descending order.\n \"\"\"\n return heapq.nlargest(n, nums)\nn = 3", "matching_cluster_idx": 8}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n \"\"\"\n Finds the n largest integers from a given list of numbers using a min-heap.\n\n Args:\n nums: A list of numbers.\n n: The number of largest integers to find.\n\n Returns:\n A list of the n largest integers in descending order.\n Returns an empty list if n is zero or negative.\n Returns the sorted input list if n is larger than or equal to the length of the input list.\n \"\"\"\n\n if n <= 0:\n return []\n if n >= len(nums):\n return sorted(nums, reverse=True)\n\n # Use a min-heap to efficiently track the n largest elements\n return heapq.nlargest(n, nums)", "matching_cluster_idx": 8}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n \"\"\"\n Finds the n largest integers from a given list of numbers using heapq.\n\n Args:\n nums: A list of numbers.\n n: The number of largest integers to find.\n\n Returns:\n A list containing the n largest integers in descending order.\n Returns an empty list if n is 0 or nums is empty.\n \"\"\"\n if not nums or n == 0:\n return []\n\n return heapq.nlargest(n, nums, key=None)", "matching_cluster_idx": 8}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n \"\"\"\n Finds the n largest integers from a given list of numbers, returned in descending order.\n\n Args:\n nums: A list of numbers.\n n: The number of largest integers to find.\n\n Returns:\n A list of the n largest integers in descending order.\n \"\"\"\n return sorted(heapq.nlargest(n, nums), reverse=True)\nn = 3", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n \"\"\"\n Finds the n largest integers from a given list of numbers using a heap queue.\n\n Args:\n nums: A list of numbers.\n n: The number of largest integers to find.\n\n Returns:\n A list containing the n largest integers in descending order.\n \"\"\"\n return heapq.nlargest(n, nums)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n \"\"\"\n Finds the n largest integers from a given list of numbers using a min-heap.\n\n Args:\n nums: A list of numbers.\n n: The number of largest integers to find.\n\n Returns:\n A list containing the n largest integers in descending order.\n Returns an empty list if n is zero or negative, or if the input list is empty.\n \"\"\"\n\n if n <= 0 or not nums:\n return []\n\n return heapq.nlargest(n, nums)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n \"\"\"\n Finds the n largest integers from a given list of numbers, returned in descending order.\n\n Args:\n nums: A list of numbers.\n n: The number of largest integers to find.\n\n Returns:\n A list containing the n largest integers in descending order.\n Returns an empty list if n is 0 or nums is empty.\n \"\"\"\n if not nums or n == 0:\n return []\n \n return heapq.nlargest(n, nums, key=lambda x: x)", "matching_cluster_idx": 8}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n \"\"\"\n Finds the n largest integers from a given list of numbers, returned in descending order.\n\n Args:\n nums: A list of numbers.\n n: The number of largest integers to find.\n\n Returns:\n A list of the n largest integers in descending order.\n \"\"\"\n return heapq.nlargest(n, nums)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n \"\"\"\n Finds the n largest integers from a given list of numbers using a min-heap.\n\n Args:\n nums: A list of numbers.\n n: The number of largest integers to find.\n\n Returns:\n A list of the n largest integers in descending order.\n \"\"\"\n if n <= 0:\n return [] # Handle edge case of n being zero or negative\n if n >= len(nums):\n return sorted(nums, reverse=True) # Handle edge case where n is greater than or equal to the list length\n\n min_heap = []\n for num in nums:\n if len(min_heap) < n:\n heapq.heappush(min_heap, num)\n else:\n if num > min_heap[0]:\n heapq.heapreplace(min_heap, num) # More efficient than heappushpop\n\n return sorted(min_heap, reverse=True)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n \"\"\"\n Finds the n largest integers from a given list of numbers using a min-heap.\n\n Args:\n nums: A list of numbers.\n n: The number of largest integers to find.\n\n Returns:\n A list containing the n largest integers in descending order.\n Returns an empty list if n is 0 or nums is empty.\n \"\"\"\n if not nums or n == 0:\n return []\n\n return sorted(heapq.nlargest(n, nums), reverse=True)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n \"\"\"\n Finds the n largest integers from a given list of numbers using a min-heap.\n\n Args:\n nums: A list of numbers.\n n: The number of largest integers to find.\n\n Returns:\n A list of the n largest integers in descending order.\n \"\"\"\n\n if n <= 0:\n return []\n\n if n >= len(nums):\n return sorted(nums, reverse=True)\n\n min_heap = []\n for num in nums:\n if len(min_heap) < n:\n heapq.heappush(min_heap, num)\n elif num > min_heap[0]: # If current number is greater than the smallest in the heap\n heapq.heapreplace(min_heap, num) # Replace smallest with current number\n\n return sorted(min_heap, reverse=True) # Sort the heap (which contains the n largest) in descending order", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n \"\"\"\n Finds the n largest integers from a given list of numbers using a heap queue.\n\n Args:\n nums: A list of numbers.\n n: The number of largest integers to find.\n\n Returns:\n A list of the n largest integers in descending order.\n \"\"\"\n return heapq.nlargest(n, nums)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n \"\"\"\n Finds the n largest integers from a given list of numbers using a heap queue.\n\n Args:\n nums: A list of numbers.\n n: The number of largest integers to find.\n\n Returns:\n A list containing the n largest integers in descending order.\n \"\"\"\n\n return heapq.nlargest(n, nums)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n return sorted(heapq.nlargest(n, nums), reverse=True)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n \"\"\"\n Finds the n largest integers from a given list of numbers using a min-heap.\n\n Args:\n nums: A list of numbers.\n n: The number of largest integers to find.\n\n Returns:\n A list of the n largest integers in descending order.\n \"\"\"\n if n <= 0:\n return []\n if n >= len(nums):\n return sorted(nums, reverse=True)\n \n min_heap = nums[:n]\n heapq.heapify(min_heap)\n\n for num in nums[n:]:\n if num > min_heap[0]:\n heapq.heapreplace(min_heap, num)\n\n return sorted(min_heap, reverse=True)", "matching_cluster_idx": 9}]}, "Mbpp/9": {"dps": 52.72108843537415, "dps_norm": 51.0, "pass@1": 98.0, "profiled": [{"solution": "def find_Rotations(s):\n \"\"\"\n Finds the minimum number of rotations (greater than 0) required to get the same string.\n\n Args:\n s: The input string.\n\n Returns:\n The minimum number of rotations, or -1 if no such rotation exists.\n \"\"\"\n n = len(s)\n for i in range(1, n + 1): # Iterate through possible rotations from 1 to n\n rotated_s = s[i:] + s[:i]\n if rotated_s == s:\n return i\n return -1 # No rotation found", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(s):\n \"\"\"\n Finds the minimum number of rotations (greater than 0) required to get the same string.\n\n Args:\n s: The input string.\n\n Returns:\n The minimum number of rotations. Returns the length of the string if no shorter rotation exists.\n \"\"\"\n n = len(s)\n for i in range(1, n + 1): # Iterate through possible rotations from 1 to n\n rotated_s = s[i:] + s[:i]\n if rotated_s == s:\n return i\n return n", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(s):\n \"\"\"\n Finds the minimum number of rotations (greater than 0) required to get the same string.\n\n Args:\n s: The input string.\n\n Returns:\n The minimum number of rotations, or -1 if no such rotation exists.\n \"\"\"\n n = len(s)\n for i in range(1, n + 1): # Iterate through possible rotation lengths\n rotated = s[i:] + s[:i]\n if rotated == s:\n return i\n return -1 # No rotation found", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(s):\n \"\"\"\n Finds the minimum number of rotations (greater than 0) required to get the same string.\n\n Args:\n s: The input string.\n\n Returns:\n The minimum number of rotations, or len(s) if no such rotation exists.\n \"\"\"\n n = len(s)\n for i in range(1, n + 1): # Iterate through possible rotations\n rotated_s = s[i:] + s[:i]\n if rotated_s == s:\n return i\n return n # Return n if no rotation produces the same string", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(s):\n \"\"\"\n Finds the minimum number of rotations (greater than 0) required to get the same string.\n\n Args:\n s: The input string.\n\n Returns:\n The minimum number of rotations, or len(s) if no such rotation exists.\n \"\"\"\n n = len(s)\n for i in range(1, n + 1):\n rotated = s[i:] + s[:i]\n if rotated == s:\n return i\n return n", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(s):\n \"\"\"\n Finds the minimum number of rotations (greater than 0) required to get the same string.\n\n Args:\n s: The input string.\n\n Returns:\n The minimum number of rotations, or -1 if no such rotation exists.\n \"\"\"\n n = len(s)\n for i in range(1, n + 1): # Iterate through possible rotation lengths\n rotated = s[i:] + s[:i]\n if rotated == s:\n return i\n return -1 # No rotation found", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(str1):\n \"\"\"\n Finds the minimum number of rotations (greater than 0) required to get the same string.\n\n Args:\n str1: The input string.\n\n Returns:\n The minimum number of rotations, or len(str1) if no shorter rotation exists.\n \"\"\"\n n = len(str1)\n for i in range(1, n):\n rotated = str1[i:] + str1[:i]\n if rotated == str1:\n return i\n return n", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(s):\n \"\"\"\n Finds the minimum number of rotations (greater than 0) required to get the same string.\n\n Args:\n s: The input string.\n\n Returns:\n The minimum number of rotations, or -1 if no such rotation exists.\n \"\"\"\n n = len(s)\n for i in range(1, n + 1):\n rotated = s[i:] + s[:i]\n if rotated == s:\n return i\n return -1 # No rotation found", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(s):\n \"\"\"\n Finds the minimum number of rotations (greater than 0) required to get the same string.\n\n Args:\n s: The input string.\n\n Returns:\n The minimum number of rotations, or -1 if no such rotation exists.\n \"\"\"\n n = len(s)\n for i in range(1, n + 1): # Iterate through possible rotation lengths\n if n % i == 0: # Only check rotations that are divisors of the string length\n rotated = s[i:] + s[:i]\n if rotated == s:\n return i\n return -1 # No rotation found", "matching_cluster_idx": 6}, {"solution": "def find_Rotations(s):\n \"\"\"\n Finds the minimum number of rotations (greater than 0) required to get the same string.\n\n Args:\n s: The input string.\n\n Returns:\n The minimum number of rotations, or len(s) if no such rotation exists.\n \"\"\"\n n = len(s)\n for i in range(1, n + 1):\n rotated_s = s[i:] + s[:i]\n if rotated_s == s:\n return i\n return n # Return n if no rotation produces the same string.", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(s):\n \"\"\"\n Finds the minimum number of rotations (greater than 0) required to get the same string.\n\n Args:\n s: The input string.\n\n Returns:\n The minimum number of rotations, or len(s) if no such rotation exists.\n \"\"\"\n n = len(s)\n for i in range(1, n + 1):\n rotated = s[i:] + s[:i]\n if rotated == s:\n return i\n return n # Return n if no rotation produces the original string.", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(s):\n \"\"\"\n Finds the minimum number of rotations (greater than 0) required to get the same string.\n\n Args:\n s: The input string.\n\n Returns:\n The minimum number of rotations, or len(s) if no rotation produces the same string.\n \"\"\"\n n = len(s)\n for i in range(1, n + 1):\n rotated = s[i:] + s[:i]\n if rotated == s:\n return i\n return n", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(s):\n \"\"\"\n Finds the minimum number of rotations (greater than 0) required to get the same string.\n\n Args:\n s: The input string.\n\n Returns:\n The minimum number of rotations, or len(s) if no such rotation exists.\n \"\"\"\n n = len(s)\n for i in range(1, n + 1):\n rotated = s[i:] + s[:i]\n if rotated == s:\n return i\n return n # Return n if no rotation produces the original string", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(s):\n \"\"\"\n Finds the minimum number of rotations (greater than 0) required to get the same string.\n\n Args:\n s: The input string.\n\n Returns:\n The minimum number of rotations, or len(s) if no such rotation exists.\n \"\"\"\n n = len(s)\n for i in range(1, n + 1):\n rotated = s[i:] + s[:i]\n if rotated == s:\n return i\n return n # Return n if no rotation produces the same string", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(s):\n \"\"\"\n Finds the minimum number of rotations (greater than 0) required to get the same string.\n\n Args:\n s: The input string.\n\n Returns:\n The minimum number of rotations, or len(s) if no such rotation exists.\n \"\"\"\n n = len(s)\n for i in range(1, n + 1):\n rotated = s[i:] + s[:i]\n if rotated == s:\n return i\n return n # Return n if no rotation within n produces the same string", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(s):\n \"\"\"\n Finds the minimum number of rotations (greater than 0) required to get the same string.\n\n Args:\n s: The input string.\n\n Returns:\n The minimum number of rotations, or len(s) if no smaller rotation works.\n \"\"\"\n n = len(s)\n for i in range(1, n):\n rotated = s[i:] + s[:i]\n if rotated == s:\n return i\n return n # If no shorter rotation works", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(s):\n \"\"\"\n Finds the minimum number of rotations (greater than 0) required to get the same string.\n\n Args:\n s: The input string.\n\n Returns:\n The minimum number of rotations, or len(s) if no rotation produces the original string.\n \"\"\"\n n = len(s)\n for i in range(1, n + 1):\n rotated = s[i:] + s[:i]\n if rotated == s:\n return i\n return n # No rotation found", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(s):\n \"\"\"\n Finds the minimum number of rotations (greater than 0) required to get the same string.\n\n Args:\n s: The input string.\n\n Returns:\n The minimum number of rotations, or -1 if no such rotation exists.\n \"\"\"\n n = len(s)\n for i in range(1, n + 1): # Iterate through rotations from 1 to n\n rotated_s = s[i:] + s[:i]\n if rotated_s == s:\n return i\n return -1 # No rotation found", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(s):\n \"\"\"\n Finds the minimum number of rotations (greater than 0) required to get the same string.\n\n Args:\n s: The input string.\n\n Returns:\n The minimum number of rotations, or len(s) if no such rotation exists.\n \"\"\"\n n = len(s)\n for i in range(1, n + 1):\n rotated = s[i:] + s[:i]\n if rotated == s:\n return i\n return n", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(s):\n \"\"\"\n Finds the minimum number of rotations (greater than 0) required to get the same string.\n\n Args:\n s: The input string.\n\n Returns:\n The minimum number of rotations, or -1 if no such rotation exists.\n \"\"\"\n n = len(s)\n for i in range(1, n + 1):\n rotated = s[i:] + s[:i]\n if rotated == s:\n return i\n return -1", "matching_cluster_idx": 4}]}, "Mbpp/11": {"dps": null, "dps_norm": null, "pass@1": 9.0, "profiled": []}, "Mbpp/12": {"dps": 91.42857142857143, "dps_norm": 99.375, "pass@1": 100.0, "profiled": [{"solution": "def sort_matrix(matrix):\n \"\"\"Sorts a matrix in ascending order based on the sum of its rows.\n\n Args:\n matrix: A list of lists representing the matrix.\n\n Returns:\n A new list of lists representing the sorted matrix.\n \"\"\"\n\n return sorted(matrix, key=sum)", "matching_cluster_idx": 14}, {"solution": "def sort_matrix(matrix):\n \"\"\"Sorts a matrix based on the sum of its rows in ascending order.\n\n Args:\n matrix: A list of lists representing the matrix.\n\n Returns:\n A new list of lists representing the sorted matrix.\n \"\"\"\n return sorted(matrix, key=sum)\nmatrix = [[1, 2, 3], [2, 4, 5], [1, 1, 1]]", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"Sorts a matrix in ascending order based on the sum of its rows.\"\"\"\n return sorted(matrix, key=lambda row: sum(row))", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"Sorts a matrix based on the sum of its rows in ascending order.\"\"\"\n\n return sorted(matrix, key=sum)", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"Sorts a matrix based on the sum of its rows.\n\n Args:\n matrix: A list of lists representing the matrix.\n\n Returns:\n A new list of lists representing the sorted matrix.\n \"\"\"\n return sorted(matrix, key=sum)", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"Sorts a matrix based on the sum of its rows.\"\"\"\n return sorted(matrix, key=sum)", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"Sorts a matrix based on the sum of its rows in ascending order.\"\"\"\n\n return sorted(matrix, key=sum)", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"Sorts a matrix based on the sum of its rows.\n\n Args:\n matrix: A list of lists representing the matrix.\n\n Returns:\n A new list of lists representing the sorted matrix.\n \"\"\"\n return sorted(matrix, key=sum)", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"\n Sorts a given matrix in ascending order according to the sum of its rows.\n\n Args:\n matrix: A list of lists representing the matrix.\n\n Returns:\n A new list of lists representing the sorted matrix.\n \"\"\"\n return sorted(matrix, key=sum)", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"Sorts a matrix based on the sum of its rows.\"\"\"\n return sorted(matrix, key=sum)", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"Sorts a matrix based on the ascending order of row sums.\"\"\"\n return sorted(matrix, key=sum)", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"Sorts a matrix based on the sum of its rows.\n\n Args:\n matrix: A list of lists representing the matrix.\n\n Returns:\n A new list of lists representing the sorted matrix.\n \"\"\"\n return sorted(matrix, key=sum)", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"Sorts a matrix based on the sum of its rows.\n\n Args:\n matrix: A list of lists representing the matrix.\n\n Returns:\n A new list of lists representing the sorted matrix.\n \"\"\"\n return sorted(matrix, key=sum)", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"Sorts a matrix based on the sum of its rows.\n\n Args:\n matrix: A list of lists representing the matrix.\n\n Returns:\n A new list of lists representing the sorted matrix.\n \"\"\"\n\n return sorted(matrix, key=sum)", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"Sorts a matrix based on the sum of its rows in ascending order.\n\n Args:\n matrix: A list of lists representing the matrix.\n\n Returns:\n A new list of lists representing the sorted matrix.\n \"\"\"\n\n return sorted(matrix, key=sum)\nmatrix = [[10, 2, 3], [2, 4, 5], [1, 1, 1]]", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"Sorts a matrix based on the ascending order of its row sums.\"\"\"\n return sorted(matrix, key=sum)", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"Sorts a matrix based on the sum of its rows in ascending order.\n\n Args:\n matrix: A list of lists representing the matrix.\n\n Returns:\n A new list of lists representing the sorted matrix.\n \"\"\"\n return sorted(matrix, key=sum)\nmatrix = [[1, 2, 3], [2, 4, 5], [1, 1, 1]]", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"Sorts a matrix based on the sum of its rows.\n\n Args:\n matrix: A list of lists representing the matrix.\n\n Returns:\n A new list of lists representing the sorted matrix.\n \"\"\"\n return sorted(matrix, key=sum)", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"Sorts a matrix in ascending order based on the sum of its rows.\n\n Args:\n matrix: A list of lists representing the matrix.\n\n Returns:\n A new list of lists representing the sorted matrix.\n \"\"\"\n\n return sorted(matrix, key=sum)", "matching_cluster_idx": 14}, {"solution": "def sort_matrix(matrix):\n \"\"\"Sorts a matrix based on the sum of its rows.\n\n Args:\n matrix: A list of lists representing the matrix.\n\n Returns:\n A new list of lists representing the sorted matrix.\n \"\"\"\n return sorted(matrix, key=sum)", "matching_cluster_idx": 15}]}, "Mbpp/16": {"dps": 95.2439024390244, "dps_norm": 98.125, "pass@1": 84.0, "profiled": [{"solution": "import re\ndef text_lowercase_underscore(text):\n \"\"\"\n Checks if a string contains sequences of lowercase letters joined with underscores.\n\n Args:\n text: The input string.\n\n Returns:\n True if the string matches the pattern, False otherwise.\n \"\"\"\n pattern = r\"^([a-z]+_)*[a-z]+$\" # Matches one or more lowercase sequences joined by underscores\n return bool(re.fullmatch(pattern, text))", "matching_cluster_idx": 7}, {"solution": "import re\ndef text_lowercase_underscore(text):\n \"\"\"\n Checks if a string contains sequences of lowercase letters joined with an underscore.\n\n Args:\n text: The input string.\n\n Returns:\n True if the string matches the pattern, False otherwise.\n \"\"\"\n pattern = r\"^([a-z]+_)*[a-z]+$\" # Matches sequences of lowercase letters joined by underscores\n return bool(re.fullmatch(pattern, text))", "matching_cluster_idx": 7}, {"solution": "import re\ndef text_lowercase_underscore(text):\n \"\"\"\n Checks if a string contains sequences of lowercase letters joined with underscores.\n\n Args:\n text: The input string.\n\n Returns:\n True if the string contains sequences of lowercase letters joined with underscores, False otherwise.\n \"\"\"\n pattern = r\"^([a-z]+_)*[a-z]+$\" # Matches one or more sequences of lowercase letters followed by underscores, ending with lowercase letters\n return bool(re.fullmatch(pattern, text))", "matching_cluster_idx": 7}, {"solution": "import re\ndef text_lowercase_underscore(text):\n \"\"\"\n Checks if the input string contains sequences of lowercase letters joined with an underscore.\n\n Args:\n text: The input string.\n\n Returns:\n True if the string matches the pattern, False otherwise.\n \"\"\"\n pattern = r\"^([a-z]+_)*[a-z]+$\" # Matches sequences of lowercase letters joined by underscores\n return bool(re.fullmatch(pattern, text))", "matching_cluster_idx": 7}, {"solution": "import re\ndef text_lowercase_underscore(text):\n \"\"\"\n Checks if a string contains only sequences of lowercase letters joined by underscores.\n\n Args:\n text: The input string.\n\n Returns:\n True if the string matches the pattern, False otherwise.\n \"\"\"\n pattern = r\"^([a-z]+_)*[a-z]+$\" # Matches one or more sequences of lowercase letters followed by underscores, ending with lowercase letters.\n match = re.match(pattern, text)\n return bool(match)", "matching_cluster_idx": 7}, {"solution": "import re\ndef text_lowercase_underscore(text):\n \"\"\"\n Checks if the input string contains sequences of lowercase letters joined with an underscore.\n\n Args:\n text: The input string.\n\n Returns:\n True if the string matches the pattern, False otherwise.\n \"\"\"\n pattern = r\"^([a-z]+_)*[a-z]+$\" # Matches sequences of lowercase letters joined by underscores\n match = re.match(pattern, text)\n return bool(match)", "matching_cluster_idx": 7}, {"solution": "import re\ndef text_lowercase_underscore(text):\n \"\"\"\n Checks if a string contains only sequences of lowercase letters joined by underscores.\n\n Args:\n text: The input string.\n\n Returns:\n True if the string matches the pattern, False otherwise.\n \"\"\"\n pattern = r\"^([a-z]+_)*[a-z]+$\" # Matches sequences of lowercase letters joined by underscores\n match = re.match(pattern, text)\n return bool(match)", "matching_cluster_idx": 7}, {"solution": "import re\ndef text_lowercase_underscore(text):\n \"\"\"\n Checks if a string contains sequences of lowercase letters joined with an underscore.\n\n Args:\n text: The input string.\n\n Returns:\n True if the string matches the pattern, False otherwise.\n \"\"\"\n pattern = r\"^([a-z]+_)*[a-z]+$\" # Matches sequences of lowercase letters joined by underscores\n match = re.match(pattern, text)\n return bool(match)", "matching_cluster_idx": 7}, {"solution": "import re\ndef text_lowercase_underscore(text):\n \"\"\"\n Checks if the input string contains sequences of lowercase letters joined with an underscore.\n\n Args:\n text: The input string.\n\n Returns:\n True if the string matches the pattern, False otherwise.\n \"\"\"\n pattern = r\"^([a-z]+_)*[a-z]+$\" # Corrected regex\n match = re.match(pattern, text)\n return bool(match)", "matching_cluster_idx": 7}, {"solution": "import re\ndef text_lowercase_underscore(text):\n \"\"\"\n Checks if a string contains only sequences of lowercase letters joined by underscores.\n\n Args:\n text: The input string.\n\n Returns:\n True if the string matches the pattern, False otherwise.\n \"\"\"\n pattern = r\"^([a-z]+_)*[a-z]+$\" # Matches sequences of lowercase letters joined by underscores\n match = re.match(pattern, text)\n return bool(match)", "matching_cluster_idx": 7}, {"solution": "import re\ndef text_lowercase_underscore(text):\n \"\"\"\n Checks if a string contains sequences of lowercase letters joined with underscores.\n\n Args:\n text: The input string.\n\n Returns:\n True if the string matches the pattern, False otherwise.\n \"\"\"\n pattern = r\"^([a-z]+_)*[a-z]+$\" # Matches one or more lowercase sequences joined by underscores.\n return bool(re.fullmatch(pattern, text))", "matching_cluster_idx": 7}, {"solution": "import re\ndef text_lowercase_underscore(text):\n \"\"\"\n Checks if a string contains sequences of lowercase letters joined with underscores.\n\n Args:\n text: The input string.\n\n Returns:\n True if the string contains sequences of lowercase letters joined with underscores, \n False otherwise.\n \"\"\"\n pattern = r\"^([a-z]+_)*[a-z]+$\" # Matches sequences of lowercase letters joined by underscores\n return bool(re.fullmatch(pattern, text))", "matching_cluster_idx": 7}, {"solution": "import re\ndef text_lowercase_underscore(text):\n \"\"\"\n Checks if a string contains only sequences of lowercase letters joined by underscores.\n\n Args:\n text: The input string.\n\n Returns:\n True if the string matches the pattern, False otherwise.\n \"\"\"\n pattern = r\"^([a-z]+_)*[a-z]+$\" # Matches sequences of lowercase letters joined by underscores\n return bool(re.fullmatch(pattern, text))", "matching_cluster_idx": 7}, {"solution": "import re\ndef text_lowercase_underscore(text):\n \"\"\"\n Checks if a string contains sequences of lowercase letters joined with underscores.\n\n Args:\n text: The input string.\n\n Returns:\n True if the string matches the pattern, False otherwise.\n \"\"\"\n pattern = r\"^[a-z]+(_[a-z]+)*$\" # Matches one or more lowercase sequences joined by underscores\n return bool(re.fullmatch(pattern, text))", "matching_cluster_idx": 6}, {"solution": "import re\ndef text_lowercase_underscore(text):\n \"\"\"\n Checks if a string contains sequences of lowercase letters joined with underscores.\n\n Args:\n text: The input string.\n\n Returns:\n True if the string matches the pattern, False otherwise.\n \"\"\"\n pattern = r\"^([a-z]+_)*[a-z]+$\" # Matches sequences of lowercase letters joined by underscores.\n match = re.match(pattern, text)\n return bool(match)", "matching_cluster_idx": 7}, {"solution": "import re\ndef text_lowercase_underscore(text):\n \"\"\"\n Checks if a string contains sequences of lowercase letters joined with an underscore.\n\n Args:\n text: The input string.\n\n Returns:\n True if the string contains sequences of lowercase letters joined by underscores, \n False otherwise.\n \"\"\"\n pattern = r\"^([a-z]+_)*[a-z]+$\" # Matches one or more sequences of lowercase letters followed by an underscore, optionally ending with another sequence of lowercase letters.\n match = re.match(pattern, text)\n return bool(match)", "matching_cluster_idx": 7}, {"solution": "import re\ndef text_lowercase_underscore(text):\n \"\"\"\n Checks if the input string contains sequences of lowercase letters joined with an underscore.\n\n Args:\n text: The input string.\n\n Returns:\n True if the string matches the pattern, False otherwise.\n \"\"\"\n pattern = r\"^[a-z]+(_[a-z]+)*$\" # Matches one or more sequences of lowercase letters joined by underscores\n match = re.fullmatch(pattern, text)\n return bool(match)", "matching_cluster_idx": 6}, {"solution": "import re\ndef text_lowercase_underscore(text):\n \"\"\"\n Checks if a string contains only sequences of lowercase letters joined by underscores.\n\n Args:\n text: The input string.\n\n Returns:\n True if the string matches the pattern, False otherwise.\n \"\"\"\n pattern = r\"^([a-z]+_)*[a-z]+$\" # Corrected regex\n return bool(re.fullmatch(pattern, text))", "matching_cluster_idx": 7}, {"solution": "import re\ndef text_lowercase_underscore(text):\n \"\"\"\n Checks if a string contains only sequences of lowercase letters joined by underscores.\n\n Args:\n text: The input string.\n\n Returns:\n True if the string matches the pattern, False otherwise.\n \"\"\"\n pattern = r\"^([a-z]+_)*[a-z]+$\" # Matches sequences of lowercase letters joined by underscores\n match = re.match(pattern, text)\n return bool(match)", "matching_cluster_idx": 7}, {"solution": "import re\ndef text_lowercase_underscore(text):\n \"\"\"\n Checks if the input string contains sequences of lowercase letters joined with an underscore.\n\n Args:\n text: The input string.\n\n Returns:\n True if the input string contains sequences of lowercase letters joined with an underscore, False otherwise.\n \"\"\"\n pattern = r\"^[a-z]+(_[a-z]+)*$\" # Matches one or more sequences of lowercase letters joined by underscores.\n return bool(re.fullmatch(pattern, text))", "matching_cluster_idx": 6}]}, "Mbpp/19": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def test_duplicate(arr):\n \"\"\"\n Checks if a given array of integers contains any duplicate elements.\n\n Args:\n arr: A list of integers.\n\n Returns:\n True if the array contains duplicates, False otherwise.\n \"\"\"\n seen = set()\n for num in arr:\n if num in seen:\n return True\n seen.add(num)\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(arr):\n \"\"\"\n Checks if an array contains duplicate elements.\n\n Args:\n arr: A list of integers.\n\n Returns:\n True if the array contains duplicates, False otherwise.\n \"\"\"\n seen = set()\n for num in arr:\n if num in seen:\n return True\n seen.add(num)\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(arr):\n \"\"\"\n Checks if a given array of integers contains any duplicate elements.\n\n Args:\n arr: A list of integers.\n\n Returns:\n True if the array contains duplicates, False otherwise.\n \"\"\"\n seen = set()\n for num in arr:\n if num in seen:\n return True\n seen.add(num)\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(arr):\n \"\"\"\n Checks if an array contains any duplicate elements.\n\n Args:\n arr: A list of integers.\n\n Returns:\n True if the array contains duplicates, False otherwise.\n \"\"\"\n seen = set()\n for num in arr:\n if num in seen:\n return True\n seen.add(num)\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(arr):\n \"\"\"\n Checks if a given array of integers contains any duplicate elements.\n\n Args:\n arr: A list of integers.\n\n Returns:\n True if the array contains duplicates, False otherwise.\n \"\"\"\n seen = set()\n for num in arr:\n if num in seen:\n return True\n seen.add(num)\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(arr):\n \"\"\"\n Checks if an array contains any duplicate elements.\n\n Args:\n arr: A list of integers.\n\n Returns:\n True if the array contains duplicates, False otherwise.\n \"\"\"\n seen = set()\n for num in arr:\n if num in seen:\n return True\n seen.add(num)\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(arr):\n \"\"\"\n Checks if a given array of integers contains any duplicate elements.\n\n Args:\n arr: A list of integers.\n\n Returns:\n True if the array contains duplicates, False otherwise.\n \"\"\"\n seen = set()\n for num in arr:\n if num in seen:\n return True\n seen.add(num)\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(arr):\n \"\"\"\n Checks if a given array of integers contains any duplicate elements.\n\n Args:\n arr: A list of integers.\n\n Returns:\n True if the array contains duplicates, False otherwise.\n \"\"\"\n seen = set()\n for num in arr:\n if num in seen:\n return True\n seen.add(num)\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(arr):\n \"\"\"\n Checks if a given array of integers contains any duplicate elements.\n\n Args:\n arr: A list of integers.\n\n Returns:\n True if the array contains duplicates, False otherwise.\n \"\"\"\n seen = set()\n for num in arr:\n if num in seen:\n return True\n seen.add(num)\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(arr):\n \"\"\"\n Checks if a given array of integers contains any duplicate elements.\n\n Args:\n arr: A list of integers.\n\n Returns:\n True if the array contains duplicates, False otherwise.\n \"\"\"\n seen = set()\n for num in arr:\n if num in seen:\n return True\n seen.add(num)\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(arr):\n \"\"\"\n Checks if an array contains duplicate elements.\n\n Args:\n arr: A list of integers.\n\n Returns:\n True if the array contains duplicates, False otherwise.\n \"\"\"\n seen = set()\n for num in arr:\n if num in seen:\n return True\n seen.add(num)\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(arr):\n \"\"\"\n Checks if a given array of integers contains any duplicate elements.\n\n Args:\n arr: A list of integers.\n\n Returns:\n True if the array contains duplicates, False otherwise.\n \"\"\"\n seen = set()\n for num in arr:\n if num in seen:\n return True\n seen.add(num)\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(arr):\n \"\"\"\n Checks if a given array of integers contains any duplicate elements.\n\n Args:\n arr: A list of integers.\n\n Returns:\n True if the array contains duplicates, False otherwise.\n \"\"\"\n seen = set()\n for num in arr:\n if num in seen:\n return True\n seen.add(num)\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(arr):\n \"\"\"\n Checks if a given array of integers contains any duplicate elements.\n\n Args:\n arr: A list of integers.\n\n Returns:\n True if the array contains duplicates, False otherwise.\n \"\"\"\n seen = set()\n for num in arr:\n if num in seen:\n return True\n seen.add(num)\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(arr):\n \"\"\"\n Checks if an array contains duplicate elements.\n\n Args:\n arr: A list of integers.\n\n Returns:\n True if the array contains duplicates, False otherwise.\n \"\"\"\n seen = set()\n for num in arr:\n if num in seen:\n return True\n seen.add(num)\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(arr):\n \"\"\"\n Checks if an array contains any duplicate elements.\n\n Args:\n arr: A list of integers.\n\n Returns:\n True if the array contains duplicates, False otherwise.\n \"\"\"\n seen = set()\n for num in arr:\n if num in seen:\n return True\n seen.add(num)\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(arr):\n seen = set()\n for num in arr:\n if num in seen:\n return True\n seen.add(num)\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(arr):\n \"\"\"\n Checks if a given array of integers contains any duplicate elements.\n\n Args:\n arr: A list of integers.\n\n Returns:\n True if the array contains duplicates, False otherwise.\n \"\"\"\n seen = set()\n for num in arr:\n if num in seen:\n return True\n seen.add(num)\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(arr):\n \"\"\"\n Checks if a given array of integers contains any duplicate elements.\n\n Args:\n arr: A list of integers.\n\n Returns:\n True if the array contains duplicates, False otherwise.\n \"\"\"\n seen = set()\n for element in arr:\n if element in seen:\n return True\n seen.add(element)\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(arr):\n \"\"\"\n Checks if a given array of integers contains any duplicate elements.\n\n Args:\n arr: A list of integers.\n\n Returns:\n True if the array contains duplicates, False otherwise.\n \"\"\"\n seen = set()\n for num in arr:\n if num in seen:\n return True\n seen.add(num)\n return False", "matching_cluster_idx": 14}]}, "Mbpp/62": {"dps": 31.5, "dps_norm": 36.0, "pass@1": 100.0, "profiled": [{"solution": "def smallest_num(nums):\n \"\"\"\n Finds the smallest number in a list.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n The smallest number in the list.\n Returns None if the list is empty.\n Raises TypeError if any element in the list is not an int or a float.\n\n Examples:\n smallest_num([10, 20, 1, 45, 99]) == 1\n smallest_num([10.5, 20.2, 1.1, 45.7, 99.9]) == 1.1\n smallest_num([]) == None\n \"\"\"\n if not nums:\n return None\n\n for num in nums:\n if not isinstance(num, (int, float)):\n raise TypeError(\"List elements must be numbers (int or float)\")\n\n\n smallest = nums[0]\n for num in nums:\n if num < smallest:\n smallest = num\n return smallest", "matching_cluster_idx": -1}, {"solution": "def smallest_num(numbers):\n \"\"\"\n Finds the smallest number in a list.\n\n Args:\n numbers: A list of numbers.\n\n Returns:\n The smallest number in the list.\n Returns None if the list is empty.\n Raises TypeError if input is not a list or if the list contains non-numeric values.\n \"\"\"\n\n if not isinstance(numbers, list):\n raise TypeError(\"Input must be a list.\")\n\n if not numbers:\n return None # Handle empty list case\n\n for num in numbers:\n if not isinstance(num,(int,float)):\n raise TypeError(\"List elements must be numeric\")\n\n\n smallest = numbers[0] # Initialize with the first element\n\n for num in numbers:\n if num < smallest:\n smallest = num\n\n return smallest", "matching_cluster_idx": -1}, {"solution": "def smallest_num(nums):\n \"\"\"\n Finds the smallest number in a list.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n The smallest number in the list.\n Returns None if the list is empty.\n \"\"\"\n if not nums:\n return None\n smallest = nums[0]\n for num in nums:\n if num < smallest:\n smallest = num\n return smallest", "matching_cluster_idx": 3}, {"solution": "def smallest_num(numbers):\n \"\"\"\n Finds the smallest number in a list.\n\n Args:\n numbers: A list of numbers.\n\n Returns:\n The smallest number in the list.\n Returns None if the list is empty.\n Raises TypeError if the list contains non-numeric values.\n \"\"\"\n\n if not numbers:\n return None\n\n smallest = numbers[0]\n for num in numbers:\n if not isinstance(num, (int, float)): # Check for non-numeric values\n raise TypeError(\"List must contain only numbers.\")\n if num < smallest:\n smallest = num\n return smallest", "matching_cluster_idx": -1}, {"solution": "def smallest_num(nums):\n \"\"\"\n Finds the smallest number in a list of numbers.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n The smallest number in the list. \n Returns None if the list is empty.\n Raises TypeError if any element in the list is not an int or a float.\n \"\"\"\n if not nums:\n return None\n\n smallest = nums[0]\n for num in nums:\n if not isinstance(num, (int, float)):\n raise TypeError(\"List elements must be numbers (int or float)\")\n if num < smallest:\n smallest = num\n return smallest", "matching_cluster_idx": -1}, {"solution": "def smallest_num(nums):\n \"\"\"\n Finds the smallest number in a list.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n The smallest number in the list.\n Returns None if the list is empty.\n\n Raises:\n TypeError: if input is not a list or contains non-numeric values.\n \"\"\"\n\n if not isinstance(nums, list):\n raise TypeError(\"Input must be a list.\")\n if not nums:\n return None\n if not all(isinstance(num, (int, float)) for num in nums):\n raise TypeError(\"List must contain only numbers.\")\n\n smallest = nums[0]\n for num in nums:\n if num < smallest:\n smallest = num\n return smallest", "matching_cluster_idx": -1}, {"solution": "def smallest_num(numbers):\n \"\"\"\n Finds the smallest number in a list.\n\n Args:\n numbers: A list of numbers.\n\n Returns:\n The smallest number in the list.\n Returns None if the list is empty.\n Raises TypeError if the list contains non-numeric values.\n \"\"\"\n if not numbers:\n return None\n\n for num in numbers:\n if not isinstance(num, (int, float)):\n raise TypeError(\"List must contain only numbers.\")\n\n smallest = numbers[0]\n for num in numbers:\n if num < smallest:\n smallest = num\n return smallest", "matching_cluster_idx": -1}, {"solution": "def smallest_num(numbers):\n \"\"\"\n Finds the smallest number in a list.\n\n Args:\n numbers: A list of numbers.\n\n Returns:\n The smallest number in the list.\n Returns None if the list is empty or contains non-numeric elements.\n \"\"\"\n if not numbers:\n return None\n \n smallest = numbers[0]\n for num in numbers:\n if not isinstance(num,(int,float)): # Handle potential non-numeric input\n return None\n if num < smallest:\n smallest = num\n return smallest", "matching_cluster_idx": -1}, {"solution": "def smallest_num(nums):\n \"\"\"\n Finds the smallest number in a list.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n The smallest number in the list.\n Returns None if the list is empty.\n \"\"\"\n if not nums:\n return None\n smallest = nums[0]\n for num in nums:\n if num < smallest:\n smallest = num\n return smallest", "matching_cluster_idx": 3}, {"solution": "def smallest_num(nums):\n \"\"\"\n Finds the smallest number in a list.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n The smallest number in the list.\n Returns None if the list is empty or None.\n \"\"\"\n if not nums: # Check for empty or None list\n return None\n\n smallest = nums[0] # Initialize with the first element\n\n for num in nums:\n if num < smallest:\n smallest = num\n\n return smallest", "matching_cluster_idx": 3}, {"solution": "def smallest_num(nums):\n \"\"\"\n Finds the smallest number in a list.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n The smallest number in the list.\n Returns None if the list is empty.\n Raises TypeError if any element in the list is not an int or a float.\n \"\"\"\n if not nums:\n return None\n\n smallest = nums[0]\n for num in nums:\n if not isinstance(num, (int, float)):\n raise TypeError(\"List elements must be numbers (int or float)\")\n if num < smallest:\n smallest = num\n return smallest", "matching_cluster_idx": -1}, {"solution": "def smallest_num(nums):\n \"\"\"\n Finds the smallest number in a list.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n The smallest number in the list.\n Returns None if the list is empty.\n Raises TypeError if the list contains non-numeric values.\n\n \"\"\"\n\n if not nums:\n return None\n\n smallest = nums[0]\n for num in nums:\n if not isinstance(num, (int, float)):\n raise TypeError(\"List elements must be numbers\") # Improved error handling\n if num < smallest:\n smallest = num\n\n return smallest", "matching_cluster_idx": -1}, {"solution": "def smallest_num(numbers):\n \"\"\"\n Finds the smallest number in a list.\n\n Args:\n numbers: A list of numbers.\n\n Returns:\n The smallest number in the list.\n Returns None if the list is empty.\n \"\"\"\n if not numbers:\n return None\n smallest = numbers[0]\n for num in numbers:\n if num < smallest:\n smallest = num\n return smallest", "matching_cluster_idx": 3}, {"solution": "def smallest_num(nums):\n \"\"\"\n Finds the smallest number in a list.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n The smallest number in the list. Returns float('inf') if the list is empty.\n \"\"\"\n if not nums:\n return float('inf') # Handle empty list case\n\n smallest = nums[0]\n for num in nums:\n if num < smallest:\n smallest = num\n return smallest", "matching_cluster_idx": 3}, {"solution": "def smallest_num(nums):\n \"\"\"\n Finds the smallest number in a list.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n The smallest number in the list.\n Returns None if the list is empty.\n \"\"\"\n\n if not nums:\n return None\n\n smallest = nums[0]\n for num in nums:\n if num < smallest:\n smallest = num\n return smallest", "matching_cluster_idx": 3}, {"solution": "def smallest_num(numbers):\n \"\"\"\n Finds the smallest number in a list.\n\n Args:\n numbers: A list of numbers.\n\n Returns:\n The smallest number in the list.\n Raises ValueError if the list is empty.\n \"\"\"\n if not numbers:\n raise ValueError(\"List cannot be empty\")\n \n smallest = numbers[0]\n for num in numbers:\n if num < smallest:\n smallest = num\n return smallest", "matching_cluster_idx": 3}, {"solution": "def smallest_num(nums):\n \"\"\"\n Finds the smallest number in a list.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n The smallest number in the list.\n Returns None if the list is empty.\n Raises TypeError if any element in the list is not an int or a float.\n \"\"\"\n if not nums:\n return None\n\n smallest = nums[0]\n for num in nums:\n if not isinstance(num, (int, float)):\n raise TypeError(\"List elements must be numbers.\") # Added type checking\n if num < smallest:\n smallest = num\n return smallest", "matching_cluster_idx": -1}, {"solution": "def smallest_num(nums):\n \"\"\"\n Finds the smallest number in a list.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n The smallest number in the list.\n Raises ValueError if the list is empty.\n \"\"\"\n if not nums:\n raise ValueError(\"List cannot be empty\")\n \n smallest = nums[0]\n for num in nums:\n if num < smallest:\n smallest = num\n return smallest", "matching_cluster_idx": 3}, {"solution": "def smallest_num(nums):\n \"\"\"\n Finds the smallest number in a list.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n The smallest number in the list.\n Returns None if the list is empty or contains non-numeric values.\n \"\"\"\n if not nums:\n return None\n\n smallest = nums[0]\n for num in nums:\n if not isinstance(num, (int, float)):\n return None # Handle non-numeric values\n if num < smallest:\n smallest = num\n return smallest", "matching_cluster_idx": -1}, {"solution": "def smallest_num(nums):\n \"\"\"\n Finds the smallest number in a list.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n The smallest number in the list.\n Returns None if the list is empty.\n \"\"\"\n if not nums:\n return None\n smallest = nums[0]\n for num in nums:\n if num < smallest:\n smallest = num\n return smallest", "matching_cluster_idx": 3}]}, "Mbpp/75": {"dps": 95.71428571428572, "dps_norm": 91.66666666666666, "pass@1": 100.0, "profiled": [{"solution": "def find_tuples(list_of_tuples, k):\n \"\"\"\n Finds tuples with all elements divisible by k.\n\n Args:\n list_of_tuples: A list of tuples.\n k: The divisor.\n\n Returns:\n A list of tuples that satisfy the condition.\n \"\"\"\n result = []\n for tup in list_of_tuples:\n all_divisible = True\n for element in tup:\n if element % k != 0:\n all_divisible = False\n break\n if all_divisible:\n result.append(tup)\n return result", "matching_cluster_idx": 7}, {"solution": "def find_tuples(tuples_list, k):\n \"\"\"\n Finds tuples which have all elements divisible by k from the given list of tuples.\n\n Args:\n tuples_list: A list of tuples.\n k: The divisor.\n\n Returns:\n A list of tuples where all elements in each tuple are divisible by k.\n \"\"\"\n\n result = []\n for tup in tuples_list:\n is_divisible = True\n for element in tup:\n if element % k != 0:\n is_divisible = False\n break\n if is_divisible:\n result.append(tup)\n return result", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_tuples(list_of_tuples: List[Tuple[int, ...]], k: int) -> List[Tuple[int, ...]]:\n \"\"\"\n Finds tuples in which all elements are divisible by k.\n\n Args:\n list_of_tuples: A list of tuples of integers.\n k: The divisor.\n\n Returns:\n A list of tuples that satisfy the condition.\n \"\"\"\n\n result = []\n for tup in list_of_tuples:\n all_divisible = True\n for num in tup:\n if num % k != 0:\n all_divisible = False\n break\n if all_divisible:\n result.append(tup)\n return result", "matching_cluster_idx": 8}, {"solution": "def find_tuples(list_of_tuples, k):\n \"\"\"\n Finds tuples where all elements are divisible by k.\n\n Args:\n list_of_tuples: A list of tuples.\n k: The divisor.\n\n Returns:\n A list of tuples satisfying the condition.\n \"\"\"\n\n result = []\n for tup in list_of_tuples:\n all_divisible = True\n for element in tup:\n if element % k != 0:\n all_divisible = False\n break\n if all_divisible:\n result.append(tup)\n return result", "matching_cluster_idx": 7}, {"solution": "def find_tuples(list_of_tuples, k):\n \"\"\"\n Finds tuples where all elements are divisible by k.\n\n Args:\n list_of_tuples: A list of tuples.\n k: The divisor.\n\n Returns:\n A list of tuples satisfying the condition.\n \"\"\"\n result = []\n for tup in list_of_tuples:\n all_divisible = True\n for element in tup:\n if element % k != 0:\n all_divisible = False\n break\n if all_divisible:\n result.append(tup)\n return result", "matching_cluster_idx": 8}, {"solution": "def find_tuples(list_of_tuples, k):\n \"\"\"\n Finds tuples where all elements are divisible by k.\n\n Args:\n list_of_tuples: A list of tuples.\n k: The divisor.\n\n Returns:\n A list of tuples satisfying the condition.\n \"\"\"\n\n result = []\n for tup in list_of_tuples:\n all_divisible = True\n for element in tup:\n if element % k != 0:\n all_divisible = False\n break\n if all_divisible:\n result.append(tup)\n return result", "matching_cluster_idx": 7}, {"solution": "def find_tuples(list_of_tuples, k):\n \"\"\"\n Finds tuples where all elements are divisible by k.\n\n Args:\n list_of_tuples: A list of tuples.\n k: The divisor.\n\n Returns:\n A list of tuples satisfying the condition.\n \"\"\"\n\n result = []\n for tup in list_of_tuples:\n all_divisible = True\n for element in tup:\n if element % k != 0:\n all_divisible = False\n break\n if all_divisible:\n result.append(tup)\n return result", "matching_cluster_idx": 7}, {"solution": "def find_tuples(list_of_tuples, k):\n \"\"\"\n Finds tuples where all elements are divisible by k.\n\n Args:\n list_of_tuples: A list of tuples.\n k: The divisor.\n\n Returns:\n A list of tuples that satisfy the condition.\n \"\"\"\n\n result = []\n for tup in list_of_tuples:\n all_divisible = True\n for element in tup:\n if element % k != 0:\n all_divisible = False\n break\n if all_divisible:\n result.append(tup)\n return result", "matching_cluster_idx": 7}, {"solution": "def find_tuples(list_of_tuples, k):\n result = []\n for tup in list_of_tuples:\n all_divisible = True\n for element in tup:\n if element % k != 0:\n all_divisible = False\n break\n if all_divisible:\n result.append(tup)\n return result", "matching_cluster_idx": 7}, {"solution": "def find_tuples(list_of_tuples, k):\n \"\"\"\n Finds tuples where all elements are divisible by k.\n\n Args:\n list_of_tuples: A list of tuples.\n k: The divisor.\n\n Returns:\n A list of tuples that satisfy the condition.\n \"\"\"\n\n result = []\n for tup in list_of_tuples:\n divisible = True\n for element in tup:\n if element % k != 0:\n divisible = False\n break\n if divisible:\n result.append(tup)\n return result", "matching_cluster_idx": 7}, {"solution": "def find_tuples(list_of_tuples, k):\n \"\"\"\n Finds tuples where all elements are divisible by k.\n\n Args:\n list_of_tuples: A list of tuples.\n k: The divisor.\n\n Returns:\n A list of tuples satisfying the condition.\n \"\"\"\n\n result = []\n for tup in list_of_tuples:\n all_divisible = True\n for element in tup:\n if element % k != 0:\n all_divisible = False\n break\n if all_divisible:\n result.append(tup)\n return result", "matching_cluster_idx": 7}, {"solution": "def find_tuples(list_of_tuples, k):\n \"\"\"\n Finds tuples which have all elements divisible by k from the given list of tuples.\n\n Args:\n list_of_tuples: A list of tuples.\n k: The divisor.\n\n Returns:\n A list of tuples where all elements in each tuple are divisible by k.\n \"\"\"\n\n result = []\n for tup in list_of_tuples:\n all_divisible = True\n for element in tup:\n if element % k != 0:\n all_divisible = False\n break\n if all_divisible:\n result.append(tup)\n return result", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_tuples(list_of_tuples: List[Tuple[int, ...]], k: int) -> List[Tuple[int, ...]]:\n \"\"\"\n Finds tuples which have all elements divisible by k from the given list of tuples.\n \"\"\"\n\n result = []\n for tup in list_of_tuples:\n all_divisible = True\n for element in tup:\n if element % k != 0:\n all_divisible = False\n break\n if all_divisible:\n result.append(tup)\n return result", "matching_cluster_idx": 8}, {"solution": "def find_tuples(list_of_tuples, k):\n \"\"\"\n Finds tuples with all elements divisible by k.\n\n Args:\n list_of_tuples: A list of tuples.\n k: The divisor.\n\n Returns:\n A list of tuples that satisfy the condition.\n \"\"\"\n\n result = []\n for tup in list_of_tuples:\n all_divisible = True\n for element in tup:\n if element % k != 0:\n all_divisible = False\n break\n if all_divisible:\n result.append(tup)\n return result", "matching_cluster_idx": 7}, {"solution": "def find_tuples(list_of_tuples, k):\n \"\"\"\n Finds tuples where all elements are divisible by k.\n\n Args:\n list_of_tuples: A list of tuples.\n k: The divisor.\n\n Returns:\n A list of tuples that satisfy the condition.\n \"\"\"\n\n result = []\n for tup in list_of_tuples:\n all_divisible = True\n for element in tup:\n if element % k != 0:\n all_divisible = False\n break\n if all_divisible:\n result.append(tup)\n return result", "matching_cluster_idx": 7}, {"solution": "def find_tuples(list_of_tuples, k):\n \"\"\"\n Finds tuples where all elements are divisible by k.\n\n Args:\n list_of_tuples: A list of tuples.\n k: The divisor.\n\n Returns:\n A list of tuples that satisfy the condition.\n \"\"\"\n\n result = []\n for tup in list_of_tuples:\n all_divisible = True\n for element in tup:\n if element % k != 0:\n all_divisible = False\n break\n if all_divisible:\n result.append(tup)\n return result", "matching_cluster_idx": 7}, {"solution": "def find_tuples(list_of_tuples, k):\n \"\"\"\n Finds tuples where all elements are divisible by k.\n\n Args:\n list_of_tuples: A list of tuples.\n k: The divisor.\n\n Returns:\n A list of tuples satisfying the condition.\n \"\"\"\n\n result = []\n for tup in list_of_tuples:\n all_divisible = True\n for element in tup:\n if element % k != 0:\n all_divisible = False\n break\n if all_divisible:\n result.append(tup)\n return result", "matching_cluster_idx": 7}, {"solution": "def find_tuples(list_of_tuples, k):\n \"\"\"\n Finds tuples where all elements are divisible by k.\n\n Args:\n list_of_tuples: A list of tuples.\n k: The divisor.\n\n Returns:\n A list of tuples that satisfy the condition.\n \"\"\"\n result = []\n for tup in list_of_tuples:\n all_divisible = True\n for element in tup:\n if element % k != 0:\n all_divisible = False\n break\n if all_divisible:\n result.append(tup)\n return result", "matching_cluster_idx": 7}, {"solution": "def find_tuples(list_of_tuples, k):\n \"\"\"\n Finds tuples where all elements are divisible by k.\n\n Args:\n list_of_tuples: A list of tuples.\n k: The divisor.\n\n Returns:\n A list of tuples that satisfy the condition.\n \"\"\"\n result = []\n for tup in list_of_tuples:\n all_divisible = True\n for element in tup:\n if element % k != 0:\n all_divisible = False\n break\n if all_divisible:\n result.append(tup)\n return result", "matching_cluster_idx": 7}, {"solution": "def find_tuples(list_of_tuples, k):\n \"\"\"\n Finds tuples where all elements are divisible by k.\n\n Args:\n list_of_tuples: A list of tuples.\n k: The divisor.\n\n Returns:\n A list of tuples that satisfy the condition.\n \"\"\"\n result = []\n for tup in list_of_tuples:\n all_divisible = True\n for element in tup:\n if element % k != 0:\n all_divisible = False\n break\n if all_divisible:\n result.append(tup)\n return result", "matching_cluster_idx": 7}]}, "Mbpp/88": {"dps": 49.75490196078431, "dps_norm": 68.57142857142857, "pass@1": 100.0, "profiled": [{"solution": "from collections import defaultdict\ndef freq_count(input_list):\n \"\"\"\n Calculates the frequency of each element in a list.\n\n Args:\n input_list: A list of elements.\n\n Returns:\n A dictionary where keys are the elements and values are their frequencies.\n \"\"\"\n freq_dict = defaultdict(int) # Use defaultdict to avoid KeyError\n for item in input_list:\n freq_dict[item] += 1\n return dict(freq_dict) # Convert back to regular dict for consistent return type", "matching_cluster_idx": 3}, {"solution": "from collections import defaultdict\ndef freq_count(input_list):\n \"\"\"\n Calculates the frequency of elements in a list.\n\n Args:\n input_list: The input list.\n\n Returns:\n A dictionary where keys are the elements and values are their frequencies.\n \"\"\"\n freq_dict = defaultdict(int) # Use defaultdict to avoid KeyError\n for element in input_list:\n freq_dict[element] += 1\n return dict(freq_dict) # Convert back to regular dict for consistency", "matching_cluster_idx": 3}, {"solution": "def freq_count(input_list):\n \"\"\"\n Calculates the frequency of each element in a list and returns a dictionary.\n\n Args:\n input_list: A list of elements.\n\n Returns:\n A dictionary where keys are the elements and values are their frequencies.\n \"\"\"\n frequency = {}\n for item in input_list:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n return frequency", "matching_cluster_idx": 5}, {"solution": "from collections import defaultdict\ndef freq_count(input_list):\n \"\"\"\n Calculates the frequency of each element in a list.\n\n Args:\n input_list: A list of elements.\n\n Returns:\n A dictionary where keys are the elements and values are their frequencies.\n \"\"\"\n freq_dict = defaultdict(int) # Use defaultdict to simplify counting\n for item in input_list:\n freq_dict[item] += 1\n return dict(freq_dict) # Convert back to regular dict for assertion", "matching_cluster_idx": 3}, {"solution": "def freq_count(input_list):\n \"\"\"\n Calculates the frequency of elements in a list.\n\n Args:\n input_list: A list of elements.\n\n Returns:\n A dictionary where keys are the elements and values are their frequencies.\n \"\"\"\n frequency = {}\n for item in input_list:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n return frequency", "matching_cluster_idx": 5}, {"solution": "from collections import defaultdict\ndef freq_count(input_list):\n \"\"\"\n Calculates the frequency of each element in a list.\n\n Args:\n input_list: A list of elements.\n\n Returns:\n A dictionary where keys are the elements and values are their frequencies.\n \"\"\"\n\n freq_dict = defaultdict(int) # Use defaultdict to avoid KeyError\n for item in input_list:\n freq_dict[item] += 1\n return dict(freq_dict) # Convert back to regular dict for consistency with assert statement", "matching_cluster_idx": 3}, {"solution": "from collections import defaultdict\ndef freq_count(input_list):\n \"\"\"\n Calculates the frequency of each element in a list.\n\n Args:\n input_list: A list of elements.\n\n Returns:\n A dictionary where keys are the elements and values are their frequencies.\n \"\"\"\n\n freq_dict = defaultdict(int) # Using defaultdict to simplify counting\n for element in input_list:\n freq_dict[element] += 1\n return dict(freq_dict) # Convert back to a regular dict for compatibility with assert", "matching_cluster_idx": 3}, {"solution": "from collections import Counter\ndef freq_count(data):\n \"\"\"\n Calculates the frequency of elements in a list.\n\n Args:\n data: A list of elements.\n\n Returns:\n A dictionary where keys are the elements and values are their frequencies.\n \"\"\"\n return dict(Counter(data))", "matching_cluster_idx": 6}, {"solution": "from collections import defaultdict\ndef freq_count(input_list):\n \"\"\"\n Calculates the frequency of each element in a list.\n\n Args:\n input_list: A list of elements.\n\n Returns:\n A dictionary where keys are the elements and values are their frequencies.\n \"\"\"\n frequency = defaultdict(int) # Initialize a dictionary with default value 0\n for item in input_list:\n frequency[item] += 1\n return dict(frequency) # Convert back to a regular dict for assertion", "matching_cluster_idx": 3}, {"solution": "from collections import defaultdict\ndef freq_count(input_list):\n \"\"\"\n Calculates the frequency of each element in a list.\n\n Args:\n input_list: A list of elements.\n\n Returns:\n A dictionary where keys are the elements and values are their frequencies.\n \"\"\"\n freq_dict = defaultdict(int) # Using defaultdict to handle unseen elements\n for item in input_list:\n freq_dict[item] += 1\n return dict(freq_dict) # Convert back to a regular dictionary", "matching_cluster_idx": 3}, {"solution": "from collections import defaultdict\ndef freq_count(input_list):\n \"\"\"\n Calculates the frequency of each element in a list.\n\n Args:\n input_list: The input list.\n\n Returns:\n A dictionary where keys are the elements of the list and values are their frequencies.\n \"\"\"\n\n freq_dict = defaultdict(int) # Use defaultdict to simplify counting\n for item in input_list:\n freq_dict[item] += 1\n return dict(freq_dict) # Convert back to regular dict for assertion", "matching_cluster_idx": 3}, {"solution": "from collections import defaultdict\ndef freq_count(input_list):\n \"\"\"\n Calculates the frequency of each element in a list.\n\n Args:\n input_list: A list of elements.\n\n Returns:\n A dictionary where keys are the elements and values are their frequencies.\n \"\"\"\n freq_dict = defaultdict(int)\n for element in input_list:\n freq_dict[element] += 1\n return dict(freq_dict) # Convert back to a regular dict for the assertion", "matching_cluster_idx": 3}, {"solution": "def freq_count(input_list):\n \"\"\"\n Calculates the frequency of each element in a list.\n\n Args:\n input_list: A list of elements.\n\n Returns:\n A dictionary where keys are the elements and values are their frequencies.\n \"\"\"\n frequency = {}\n for item in input_list:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n return frequency", "matching_cluster_idx": 5}, {"solution": "from collections import Counter\ndef freq_count(input_list):\n \"\"\"\n Calculates the frequency of each element in a list.\n\n Args:\n input_list: A list of elements.\n\n Returns:\n A dictionary where keys are the unique elements in the list and values are their frequencies.\n \"\"\"\n return dict(Counter(input_list))", "matching_cluster_idx": 6}, {"solution": "def freq_count(input_list):\n \"\"\"\n Calculates the frequency of each element in a list.\n\n Args:\n input_list: A list of elements.\n\n Returns:\n A dictionary where keys are the elements and values are their frequencies.\n \"\"\"\n\n frequency = {}\n for item in input_list:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n return frequency", "matching_cluster_idx": 5}, {"solution": "def freq_count(input_list):\n \"\"\"\n Calculates the frequency of each element in a list.\n\n Args:\n input_list: A list of elements.\n\n Returns:\n A dictionary where keys are the elements in the list and values are their frequencies.\n \"\"\"\n freq_dict = {}\n for item in input_list:\n if item in freq_dict:\n freq_dict[item] += 1\n else:\n freq_dict[item] = 1\n return freq_dict", "matching_cluster_idx": 5}, {"solution": "from collections import defaultdict\ndef freq_count(input_list):\n \"\"\"\n Calculates the frequency of each element in a list.\n\n Args:\n input_list: A list of elements.\n\n Returns:\n A dictionary where keys are the elements and values are their frequencies.\n \"\"\"\n\n freq_dict = defaultdict(int) # Initialize a dictionary with default value 0\n for item in input_list:\n freq_dict[item] += 1\n return dict(freq_dict) # Convert back to regular dict for stricter assertion", "matching_cluster_idx": 3}, {"solution": "from collections import defaultdict\ndef freq_count(input_list):\n \"\"\"\n Calculates the frequency of each element in a list.\n\n Args:\n input_list: A list of elements.\n\n Returns:\n A dictionary where keys are the elements and values are their frequencies.\n \"\"\"\n frequency = defaultdict(int) # Use defaultdict to simplify counting\n for item in input_list:\n frequency[item] += 1\n return dict(frequency) # Convert back to a regular dictionary", "matching_cluster_idx": 3}, {"solution": "from collections import defaultdict\ndef freq_count(data):\n \"\"\"\n Calculates the frequency of each element in a list.\n\n Args:\n data: A list of elements.\n\n Returns:\n A dictionary where keys are the elements and values are their frequencies.\n \"\"\"\n freq = defaultdict(int)\n for item in data:\n freq[item] += 1\n return dict(freq) # Convert back to regular dict for consistent assertion", "matching_cluster_idx": 3}, {"solution": "from collections import defaultdict\ndef freq_count(input_list):\n \"\"\"\n Calculates the frequency of each element in a list.\n\n Args:\n input_list: The input list.\n\n Returns:\n A dictionary where keys are the elements of the list and values are their frequencies.\n \"\"\"\n frequency = defaultdict(int)\n for item in input_list:\n frequency[item] += 1\n return dict(frequency) # Convert defaultdict to a regular dict for assertion", "matching_cluster_idx": 3}]}, "Mbpp/90": {"dps": 17.73170731707317, "dps_norm": 52.14285714285714, "pass@1": 100.0, "profiled": [{"solution": "def len_log(words):\n \"\"\"\n Finds the length of the longest word in a list of words.\n\n Args:\n words: A list of strings.\n\n Returns:\n The length of the longest word in the list.\n \"\"\"\n max_len = 0\n for word in words:\n if len(word) > max_len:\n max_len = len(word)\n return max_len", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n \"\"\"\n Finds the length of the longest word in a list of strings.\n\n Args:\n words: A list of strings.\n\n Returns:\n The length of the longest word in the list.\n Returns 0 if the list is empty or contains any non-string elements.\n \"\"\"\n if not words:\n return 0\n\n max_len = 0\n for word in words:\n if not isinstance(word, str):\n return 0 # Handle cases where non-string elements exist\n max_len = max(max_len, len(word))\n return max_len", "matching_cluster_idx": 2}, {"solution": "def len_log(words):\n \"\"\"\n Finds the length of the longest word in a list of strings.\n\n Args:\n words: A list of strings.\n\n Returns:\n The length of the longest word in the list.\n \"\"\"\n max_len = 0\n for word in words:\n if len(word) > max_len:\n max_len = len(word)\n return max_len", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n \"\"\"\n Finds the length of the longest word in a list of strings.\n\n Args:\n words: A list of strings.\n\n Returns:\n The length of the longest word in the list. Returns 0 if the list is empty or None.\n \"\"\"\n if not words:\n return 0\n max_len = 0\n for word in words:\n max_len = max(max_len, len(word))\n return max_len", "matching_cluster_idx": 2}, {"solution": "def len_log(words):\n \"\"\"\n Finds the length of the longest word in a list of strings.\n\n Args:\n words: A list of strings.\n\n Returns:\n The length of the longest word in the list.\n Returns 0 if the list is empty or contains only empty strings.\n \"\"\"\n max_len = 0\n for word in words:\n max_len = max(max_len, len(word))\n return max_len", "matching_cluster_idx": 2}, {"solution": "def len_log(words):\n \"\"\"\n Finds the length of the longest word in a list of strings.\n\n Args:\n words: A list of strings.\n\n Returns:\n The length of the longest word in the list.\n Returns 0 if the list is empty or contains only empty strings.\n \"\"\"\n if not words:\n return 0\n max_len = 0\n for word in words:\n max_len = max(max_len, len(word))\n return max_len", "matching_cluster_idx": 2}, {"solution": "def len_log(words):\n \"\"\"\n Finds the length of the longest word in a list of strings.\n\n Args:\n words: A list of strings.\n\n Returns:\n The length of the longest word in the list.\n Returns 0 if the input list is empty or contains non-string elements.\n \"\"\"\n if not words or not all(isinstance(word, str) for word in words):\n return 0\n\n max_len = 0\n for word in words:\n max_len = max(max_len, len(word))\n return max_len", "matching_cluster_idx": 2}, {"solution": "def len_log(words):\n \"\"\"\n Finds the length of the longest word in a list of strings.\n\n Args:\n words: A list of strings.\n\n Returns:\n The length of the longest word in the list.\n Returns 0 if the list is empty.\n \"\"\"\n if not words:\n return 0\n max_len = 0\n for word in words:\n max_len = max(max_len, len(word))\n return max_len", "matching_cluster_idx": 2}, {"solution": "def len_log(words):\n \"\"\"\n Finds the length of the longest word in a list of strings.\n\n Args:\n words: A list of strings.\n\n Returns:\n The length of the longest word in the list.\n \"\"\"\n max_len = 0\n for word in words:\n if len(word) > max_len:\n max_len = len(word)\n return max_len", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n \"\"\"\n Finds the length of the longest word in a list of strings.\n\n Args:\n words: A list of strings.\n\n Returns:\n The length of the longest string in the list.\n Returns 0 if the list is empty.\n \"\"\"\n if not words:\n return 0\n max_len = 0\n for word in words:\n max_len = max(max_len, len(word))\n return max_len", "matching_cluster_idx": 2}, {"solution": "def len_log(words):\n \"\"\"\n Finds the length of the longest word in a list of strings.\n\n Args:\n words: A list of strings.\n\n Returns:\n The length of the longest word.\n \"\"\"\n if not words:\n return 0 # Handle empty list case\n\n max_len = 0\n for word in words:\n max_len = max(max_len, len(word))\n return max_len", "matching_cluster_idx": 2}, {"solution": "def len_log(words):\n \"\"\"\n Finds the length of the longest word in a list of words.\n\n Args:\n words: A list of strings.\n\n Returns:\n The length of the longest word in the list.\n \"\"\"\n if not words:\n return 0 # Handle empty list case\n\n max_len = 0\n for word in words:\n max_len = max(max_len, len(word))\n return max_len", "matching_cluster_idx": 2}, {"solution": "def len_log(words):\n \"\"\"\n Finds the length of the longest word in a list of strings.\n\n Args:\n words: A list of strings.\n\n Returns:\n The length of the longest word in the list.\n \"\"\"\n max_len = 0\n for word in words:\n max_len = max(max_len, len(word))\n return max_len", "matching_cluster_idx": 2}, {"solution": "def len_log(words):\n \"\"\"\n Finds the length of the longest word in a list of strings.\n\n Args:\n words: A list of strings.\n\n Returns:\n The length of the longest word in the list.\n \"\"\"\n if not words:\n return 0 # Handle empty list case\n\n max_len = 0\n for word in words:\n max_len = max(max_len, len(word))\n return max_len", "matching_cluster_idx": 3}, {"solution": "def len_log(words):\n \"\"\"\n Finds the length of the longest word in a list of strings.\n\n Args:\n words: A list of strings.\n\n Returns:\n The length of the longest word in the list.\n Returns 0 if the list is empty or contains non-string elements.\n \"\"\"\n if not words or not all(isinstance(word, str) for word in words):\n return 0\n max_len = 0\n for word in words:\n max_len = max(max_len, len(word))\n return max_len", "matching_cluster_idx": 2}, {"solution": "def len_log(words):\n \"\"\"\n Finds the length of the longest word in a list of words.\n\n Args:\n words: A list of strings.\n\n Returns:\n The length of the longest word in the list.\n Returns 0 if the list is empty.\n \"\"\"\n if not words:\n return 0\n max_len = 0\n for word in words:\n max_len = max(max_len, len(word))\n return max_len", "matching_cluster_idx": 2}, {"solution": "def len_log(words):\n \"\"\"\n Finds the length of the longest word in a list of strings.\n\n Args:\n words: A list of strings.\n\n Returns:\n The length of the longest word in the list.\n Returns 0 if the list is empty or contains non-string elements.\n \"\"\"\n if not words:\n return 0\n max_len = 0\n for word in words:\n if isinstance(word, str):\n max_len = max(max_len, len(word))\n else: #Handles cases where the list contains non-string elements gracefully\n return 0\n return max_len", "matching_cluster_idx": 2}, {"solution": "def len_log(words):\n \"\"\"\n Finds the length of the longest word in a list of strings.\n\n Args:\n words: A list of strings.\n\n Returns:\n The length of the longest word in the list.\n \"\"\"\n\n if not words:\n return 0 # Handle empty list\n\n max_len = 0\n for word in words:\n max_len = max(max_len, len(word))\n return max_len", "matching_cluster_idx": 2}, {"solution": "def len_log(words):\n \"\"\"\n Finds the length of the longest word in a list of strings.\n\n Args:\n words: A list of strings.\n\n Returns:\n The length of the longest word in the list.\n \"\"\"\n max_len = 0\n for word in words:\n if len(word) > max_len:\n max_len = len(word)\n return max_len", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n \"\"\"\n Finds the length of the longest word in a list of strings.\n\n Args:\n words: A list of strings.\n\n Returns:\n The length of the longest word. Returns 0 if the list is empty.\n \"\"\"\n if not words:\n return 0\n max_len = 0\n for word in words:\n max_len = max(max_len, len(word))\n return max_len", "matching_cluster_idx": 2}]}, "Mbpp/94": {"dps": 83.39939024390245, "dps_norm": 73.0, "pass@1": 56.0, "profiled": [{"solution": "def index_minimum(tuples):\n \"\"\"\n Returns the first value of the tuple with the smallest second value.\n \"\"\"\n if not tuples:\n return None # Handle empty list case\n\n min_value = float('inf')\n min_index = None\n\n for i in range(len(tuples)):\n if tuples[i][1] < min_value:\n min_value = tuples[i][1]\n min_index = i\n\n if min_index is not None:\n return tuples[min_index][0]\n else:\n return None # Handle case where all second values are infinity", "matching_cluster_idx": 2}, {"solution": "def index_minimum(tuples):\n \"\"\"\n Returns the first value of the tuple with the smallest second value.\n \"\"\"\n if not tuples:\n return None # Handle empty list case\n\n min_tuple = tuples[0]\n for current_tuple in tuples:\n if current_tuple[1] < min_tuple[1]:\n min_tuple = current_tuple\n return min_tuple[0]", "matching_cluster_idx": 3}, {"solution": "def index_minimum(tuples):\n \"\"\"\n Finds the first value of the tuple with the smallest second value.\n\n Args:\n tuples: A list of tuples.\n\n Returns:\n The first value of the tuple with the smallest second value. \n Returns None if the input list is empty.\n \"\"\"\n if not tuples:\n return None\n\n min_tuple = tuples[0]\n for tup in tuples:\n if tup[1] < min_tuple[1]:\n min_tuple = tup\n return min_tuple[0]", "matching_cluster_idx": 3}, {"solution": "def index_minimum(tuples):\n \"\"\"\n Finds the first value of the tuple with the smallest second value.\n\n Args:\n tuples: A list of tuples where each tuple contains two elements.\n\n Returns:\n The first element of the tuple with the smallest second element.\n Returns None if the input list is empty.\n \"\"\"\n if not tuples:\n return None\n\n min_tuple = tuples[0]\n for tup in tuples:\n if tup[1] < min_tuple[1]:\n min_tuple = tup\n return min_tuple[0]", "matching_cluster_idx": 3}, {"solution": "def index_minimum(tuples):\n \"\"\"\n Finds the first value of the tuple with the smallest second value.\n\n Args:\n tuples: A list of tuples.\n\n Returns:\n The first value of the tuple with the smallest second value.\n Returns None if the input list is empty.\n \"\"\"\n if not tuples:\n return None\n\n min_value = float('inf')\n min_index = None\n\n for i in range(len(tuples)):\n if tuples[i][1] < min_value:\n min_value = tuples[i][1]\n min_index = i\n\n if min_index is not None:\n return tuples[min_index][0]\n else:\n return None", "matching_cluster_idx": 2}, {"solution": "def index_minimum(tuples):\n \"\"\"\n Returns the first value of the tuple with the smallest second value.\n\n Args:\n tuples: A list of tuples.\n\n Returns:\n The first value of the tuple with the smallest second value.\n \"\"\"\n if not tuples:\n return None # Handle empty list case\n\n min_value = float('inf')\n min_index = None\n\n for i in range(len(tuples)):\n if tuples[i][1] < min_value:\n min_value = tuples[i][1]\n min_index = i\n \n if min_index is not None:\n return tuples[min_index][0]\n else:\n return None # Should not happen unless the second elements are not comparable", "matching_cluster_idx": 2}, {"solution": "def index_minimum(tuples):\n \"\"\"\n Finds the first value of the tuple with the smallest second value.\n\n Args:\n tuples: A list of tuples.\n\n Returns:\n The first value of the tuple with the smallest second value.\n Returns None if the input list is empty.\n \"\"\"\n if not tuples:\n return None\n\n min_tuple = tuples[0]\n for current_tuple in tuples:\n if current_tuple[1] < min_tuple[1]:\n min_tuple = current_tuple\n return min_tuple[0]", "matching_cluster_idx": 3}, {"solution": "def index_minimum(tuples):\n \"\"\"\n Returns the first value of the tuple with the smallest second value.\n\n Args:\n tuples: A list of tuples.\n\n Returns:\n The first value of the tuple with the smallest second value.\n \"\"\"\n\n if not tuples:\n return None # Handle empty list case\n\n min_tuple = tuples[0]\n for tup in tuples:\n if tup[1] < min_tuple[1]:\n min_tuple = tup\n return min_tuple[0]", "matching_cluster_idx": 3}, {"solution": "def index_minimum(tuples):\n \"\"\"\n Returns the first value of the tuple with the smallest second value.\n \"\"\"\n if not tuples:\n return None # Handle empty list case\n\n min_tuple = tuples[0]\n for tup in tuples:\n if tup[1] < min_tuple[1]:\n min_tuple = tup\n return min_tuple[0]", "matching_cluster_idx": 3}, {"solution": "def index_minimum(tuples):\n \"\"\"Returns the first value of the tuple with the smallest second value.\"\"\"\n if not tuples:\n return None # Handle empty list case\n\n min_tuple = tuples[0]\n for tup in tuples:\n if tup[1] < min_tuple[1]:\n min_tuple = tup\n return min_tuple[0]", "matching_cluster_idx": 3}, {"solution": "def index_minimum(tuples_list):\n \"\"\"\n Returns the first value of the tuple with the smallest second value.\n \"\"\"\n if not tuples_list:\n return None # Handle empty list case\n\n min_tuple = tuples_list[0]\n for current_tuple in tuples_list:\n if current_tuple[1] < min_tuple[1]:\n min_tuple = current_tuple\n return min_tuple[0]", "matching_cluster_idx": 3}, {"solution": "def index_minimum(tuples):\n \"\"\"\n Finds the first value of the tuple with the smallest second value.\n\n Args:\n tuples: A list of tuples.\n\n Returns:\n The first value of the tuple with the smallest second value.\n Returns None if the list of tuples is empty.\n \"\"\"\n\n if not tuples:\n return None\n\n min_tuple = tuples[0]\n for tup in tuples:\n if tup[1] < min_tuple[1]:\n min_tuple = tup\n\n return min_tuple[0]", "matching_cluster_idx": 3}, {"solution": "def index_minimum(tuples):\n \"\"\"\n Finds the first value of the tuple with the smallest second value.\n\n Args:\n tuples: A list of tuples.\n\n Returns:\n The first value of the tuple with the smallest second value.\n Returns None if the input list is empty.\n \"\"\"\n if not tuples:\n return None\n\n min_index = 0\n for i in range(1, len(tuples)):\n if tuples[i][1] < tuples[min_index][1]:\n min_index = i\n return tuples[min_index][0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(tuples):\n \"\"\"\n Finds the first value of the tuple with the smallest second value.\n\n Args:\n tuples: A list of tuples.\n\n Returns:\n The first value of the tuple with the smallest second value.\n Returns None if the input list is empty.\n \"\"\"\n if not tuples:\n return None\n\n min_value = float('inf')\n min_index = None\n\n for i in range(len(tuples)):\n if tuples[i][1] < min_value:\n min_value = tuples[i][1]\n min_index = i\n\n if min_index is not None:\n return tuples[min_index][0]\n else:\n return None", "matching_cluster_idx": 2}, {"solution": "def index_minimum(tuples):\n \"\"\"\n Finds the first value of the tuple with the smallest second value.\n\n Args:\n tuples: A list of tuples.\n\n Returns:\n The first value of the tuple with the smallest second value.\n Returns None if the list is empty.\n \"\"\"\n if not tuples:\n return None\n\n min_value = float('inf')\n min_index = None\n\n for i in range(len(tuples)):\n if tuples[i][1] < min_value:\n min_value = tuples[i][1]\n min_index = i\n\n if min_index is not None:\n return tuples[min_index][0]\n else:\n return None", "matching_cluster_idx": 2}, {"solution": "def index_minimum(tuples):\n \"\"\"\n Returns the first value of the tuple with the smallest second value.\n \"\"\"\n if not tuples:\n return None # Handle empty list case\n\n min_tuple = tuples[0]\n for tup in tuples:\n if tup[1] < min_tuple[1]:\n min_tuple = tup\n return min_tuple[0]", "matching_cluster_idx": 3}, {"solution": "def index_minimum(tuples):\n \"\"\"\n Returns the first value of the tuple with the smallest second value.\n\n Args:\n tuples: A list of tuples.\n\n Returns:\n The first value of the tuple with the smallest second value.\n Returns None if the input list is empty.\n \"\"\"\n if not tuples:\n return None\n\n min_tuple = tuples[0]\n for t in tuples:\n if t[1] < min_tuple[1]:\n min_tuple = t\n return min_tuple[0]", "matching_cluster_idx": 3}, {"solution": "def index_minimum(tuples):\n \"\"\"\n Finds the first value of the tuple with the smallest second value.\n\n Args:\n tuples: A list of tuples where each tuple contains two elements.\n\n Returns:\n The first element of the tuple with the smallest second element.\n Returns None if the input list is empty.\n \"\"\"\n if not tuples:\n return None\n\n min_value = float('inf')\n min_index = None\n\n for i in range(len(tuples)):\n if tuples[i][1] < min_value:\n min_value = tuples[i][1]\n min_index = i\n\n return tuples[min_index][0] if min_index is not None else None", "matching_cluster_idx": 2}, {"solution": "def index_minimum(tuples):\n \"\"\"\n Returns the first value of the tuple with the smallest second value.\n\n Args:\n tuples: A list of tuples.\n\n Returns:\n The first value of the tuple with the smallest second value.\n \"\"\"\n if not tuples:\n return None # Handle empty list case\n\n min_tuple = tuples[0]\n for tup in tuples:\n if tup[1] < min_tuple[1]:\n min_tuple = tup\n return min_tuple[0]", "matching_cluster_idx": 3}, {"solution": "def index_minimum(tuples):\n \"\"\"\n Finds the first value of the tuple with the smallest second value.\n\n Args:\n tuples: A list of tuples where each tuple contains two elements.\n\n Returns:\n The first value of the tuple with the smallest second value.\n Returns None if the list of tuples is empty.\n \"\"\"\n if not tuples:\n return None\n\n min_tuple = tuples[0]\n for t in tuples:\n if t[1] < min_tuple[1]:\n min_tuple = t\n\n return min_tuple[0]", "matching_cluster_idx": 3}]}, "Mbpp/96": {"dps": 92.49999999999999, "dps_norm": 93.57142857142857, "pass@1": 100.0, "profiled": [{"solution": "def divisor(n):\n \"\"\"\n Finds the number of divisors of a given integer.\n\n Args:\n n: The integer for which to find the number of divisors.\n\n Returns:\n The number of divisors of n.\n \"\"\"\n\n if n <= 0:\n return 0 # Handle non-positive input\n\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n count += 2 if i * i != n else 1 # Optimization: count pairs of divisors\n\n return count", "matching_cluster_idx": 6}, {"solution": "def divisor(n):\n \"\"\"\n Calculates the number of divisors of a given integer n.\n\n Args:\n n: The integer for which to find the number of divisors.\n\n Returns:\n The number of divisors of n.\n \"\"\"\n\n if n <= 0:\n return 0 # Handle non-positive inputs\n\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n count += 2 if i * i != n else 1 # Optimization for perfect squares\n return count", "matching_cluster_idx": 6}, {"solution": "def divisor(n):\n \"\"\"\n Calculates the number of divisors of a given integer.\n\n Args:\n n: The integer for which to find the number of divisors.\n\n Returns:\n The number of divisors of n.\n \"\"\"\n count = 0\n for i in range(1, int(n**0.5) + 1): # Optimized to check up to the square root\n if n % i == 0:\n count += 2 # Account for both i and n/i as divisors\n if int(n**0.5)**2 == n: # If n is a perfect square, adjust count (avoid double counting)\n count -= 1\n return count", "matching_cluster_idx": 6}, {"solution": "def divisor(n):\n \"\"\"\n Finds the number of divisors of a given integer.\n\n Args:\n n: An integer.\n\n Returns:\n The number of divisors of n.\n \"\"\"\n\n if n < 0:\n n = -n # Handle negative numbers\n\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n count += 2 # Account for both i and n/i\n if int(n**0.5) * int(n**0.5) == n: # Correct for perfect squares\n count -= 1\n\n return count", "matching_cluster_idx": 5}, {"solution": "def divisor(n):\n \"\"\"\n Calculates the number of divisors of a given integer.\n\n Args:\n n: The integer for which to find the number of divisors.\n\n Returns:\n The number of divisors of n.\n \"\"\"\n\n if n <= 0:\n return 0 # Handle non-positive inputs\n\n count = 0\n for i in range(1, int(n**0.5) + 1): # Optimization: Check up to the square root\n if n % i == 0:\n count += 2 if i * i != n else 1 # Add 2 if i is a divisor (and n/i is different), else add 1 if i*i=n\n return count", "matching_cluster_idx": 5}, {"solution": "def divisor(n):\n \"\"\"\n Finds the number of divisors of a given integer.\n\n Args:\n n: The integer.\n\n Returns:\n The number of divisors of n.\n \"\"\"\n\n if n <= 0:\n return 0 # Or raise an exception for non-positive input\n\n count = 0\n for i in range(1, int(n**0.5) + 1): # Optimization: Iterate only up to the square root\n if n % i == 0:\n count += 2 # Add 2 because both i and n/i are divisors\n\n if int(n**0.5) * int(n**0.5) == n: # If n is a perfect square, adjust count\n count -= 1\n\n return count", "matching_cluster_idx": 6}, {"solution": "def divisor(n):\n \"\"\"\n Finds the number of divisors of a given integer.\n\n Args:\n n: An integer.\n\n Returns:\n The number of divisors of n.\n \"\"\"\n\n if n < 0:\n n = -n # Handle negative integers\n\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n count += 2 # Count both i and n/i\n\n if int(n**0.5) * int(n**0.5) == n: # If n is a perfect square, adjust count\n count -= 1\n\n return count", "matching_cluster_idx": 6}, {"solution": "def divisor(n):\n \"\"\"\n Finds the number of divisors of a given integer.\n\n Args:\n n: The integer for which to find the number of divisors.\n\n Returns:\n The number of divisors of n.\n \"\"\"\n\n if n <= 0:\n return 0 # Or raise an exception, depending on desired behavior\n\n count = 0\n for i in range(1, int(n**0.5) + 1): # Optimization: Iterate only up to the square root\n if n % i == 0:\n count += 2 # If i is a divisor, n/i is also a divisor\n\n if int(n**0.5) * int(n**0.5) == n: # Correct for perfect squares\n count -= 1 # Perfect squares have their square root counted twice\n\n return count", "matching_cluster_idx": 6}, {"solution": "def divisor(n):\n \"\"\"\n Calculates the number of divisors of a given integer n.\n\n Args:\n n: The integer for which to find the number of divisors.\n\n Returns:\n The number of divisors of n.\n \"\"\"\n\n if n <= 0:\n return 0 # Handle non-positive input\n\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n count += 2 # Account for both i and n/i\n if int(n**0.5) * int(n**0.5) == n: # Adjust for perfect squares\n count -= 1\n return count", "matching_cluster_idx": 5}, {"solution": "def divisor(n):\n \"\"\"\n Finds the number of divisors of a given integer.\n\n Args:\n n: The integer.\n\n Returns:\n The number of divisors of n.\n \"\"\"\n\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n count += 2 if i * i != n else 1\n return count", "matching_cluster_idx": 6}, {"solution": "def divisor(n):\n \"\"\"\n Finds the number of divisors of a given integer.\n\n Args:\n n: The integer for which to find the number of divisors.\n\n Returns:\n The number of divisors of n.\n \"\"\"\n if n < 0:\n n = -n # Handle negative numbers by taking their absolute value\n\n count = 0\n for i in range(1, int(n**0.5) + 1): # Optimize by iterating only up to the square root\n if n % i == 0:\n count += 2 if i * i != n else 1 # Count both divisors (i and n/i) unless they are the same (perfect square)\n return count", "matching_cluster_idx": 5}, {"solution": "def divisor(n):\n \"\"\"\n Finds the number of divisors of a given integer.\n\n Args:\n n: An integer.\n\n Returns:\n The number of divisors of n.\n \"\"\"\n\n if n == 0:\n return 0 # Or raise an exception, depending on how you want to handle 0.\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n count += 2 if i * i != n else 1 # Optimization: Count both divisors at once if not a perfect square\n return count", "matching_cluster_idx": 6}, {"solution": "def divisor(n):\n \"\"\"\n Calculates the number of divisors of a given integer n.\n\n Args:\n n: The integer for which to find the number of divisors.\n\n Returns:\n The number of divisors of n.\n \"\"\"\n\n if n <= 0:\n return 0 # Or raise an exception for non-positive input\n\n count = 0\n for i in range(1, int(n**0.5) + 1): # Optimize by iterating up to the square root\n if n % i == 0:\n count += 2 # Add both i and n/i as divisors\n \n if int(n**0.5)**2 == n: # if n is a perfect square, we've counted the square root twice.\n count -= 1\n\n return count", "matching_cluster_idx": 5}, {"solution": "def divisor(n):\n \"\"\"\n Calculates the number of divisors of a given integer.\n\n Args:\n n: The integer for which to find the number of divisors.\n\n Returns:\n The number of divisors of n.\n \"\"\"\n\n if n < 0:\n n = -n # Handle negative numbers\n\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n count += 2 # Add both i and n/i as divisors\n \n if int(n**0.5) * int(n**0.5) == n: # Adjust for perfect squares\n count -= 1\n\n return count", "matching_cluster_idx": 5}, {"solution": "def divisor(n):\n \"\"\"\n Finds the number of divisors of a given integer.\n\n Args:\n n: The integer for which to find the number of divisors.\n\n Returns:\n The number of divisors of n.\n \"\"\"\n\n if n <= 0:\n return 0 # Handle non-positive inputs\n\n count = 0\n for i in range(1, int(n**0.5) + 1): # Optimize by only checking up to the square root\n if n % i == 0:\n count += 2 # Add 2 because both i and n/i are divisors\n\n if int(n**0.5)**2 == n: # Correct for perfect squares (avoid double counting the square root)\n count -= 1\n\n return count", "matching_cluster_idx": 5}, {"solution": "def divisor(n):\n \"\"\"\n Calculates the number of divisors of a given integer n.\n\n Args:\n n: The integer for which to find the number of divisors.\n\n Returns:\n The number of divisors of n.\n \"\"\"\n\n if n <= 0:\n return 0 # Handle non-positive input\n\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n count += 2 if i * i != n else 1\n return count", "matching_cluster_idx": 5}, {"solution": "def divisor(n):\n \"\"\"\n Calculates the number of divisors of a given integer.\n\n Args:\n n: The integer for which to find the number of divisors.\n\n Returns:\n The number of divisors of n.\n \"\"\"\n\n if n < 0:\n n = -n # Handle negative numbers\n\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n count += 2 if i * i != n else 1\n return count", "matching_cluster_idx": 5}, {"solution": "def divisor(n):\n \"\"\"\n Calculates the number of divisors of a given integer.\n\n Args:\n n: The integer for which to find the number of divisors.\n\n Returns:\n The number of divisors of n.\n \"\"\"\n\n if n <= 0:\n return 0 # Handle non-positive inputs\n\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n count += 2 if i * i != n else 1 # Account for perfect squares\n return count", "matching_cluster_idx": 6}, {"solution": "def divisor(n):\n \"\"\"\n Calculates the number of divisors of a given integer.\n\n Args:\n n: The integer for which to find the number of divisors.\n\n Returns:\n The number of divisors of n.\n \"\"\"\n\n if n < 0:\n n = -n # Handle negative numbers by taking the absolute value\n\n count = 0\n for i in range(1, int(n**0.5) + 1): # Optimization: Iterate up to the square root\n if n % i == 0:\n count += 2 # If i is a divisor, n/i is also a divisor\n if int(n**0.5) * int(n**0.5) == n: # Correct for perfect squares\n count -= 1 # Perfect squares have a duplicate divisor (the square root)\n\n return count", "matching_cluster_idx": 6}, {"solution": "def divisor(n):\n \"\"\"\n Finds the number of divisors of a given integer.\n\n Args:\n n: The integer.\n\n Returns:\n The number of divisors of n.\n \"\"\"\n\n if n <= 0:\n return 0 # Handle non-positive inputs\n\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n count += 2 # Count both i and n/i as divisors\n if i * i == n: # if it's a perfect square, correct the overcounting\n count -= 1\n\n return count", "matching_cluster_idx": 6}]}, "Mbpp/97": {"dps": 99.93162393162393, "dps_norm": 97.5, "pass@1": 100.0, "profiled": [{"solution": "from collections import Counter\ndef frequency_lists(list_of_lists):\n \"\"\"\n Finds the frequency of each element in a flattened list of lists.\n\n Args:\n list_of_lists: A list of lists.\n\n Returns:\n A dictionary where keys are the elements and values are their frequencies.\n \"\"\"\n\n flat_list = []\n for lst in list_of_lists:\n flat_list.extend(lst)\n\n return dict(Counter(flat_list))", "matching_cluster_idx": 7}, {"solution": "from collections import Counter\ndef frequency_lists(list_of_lists):\n \"\"\"\n Calculates the frequency of each element in a flattened list of lists.\n\n Args:\n list_of_lists: A list of lists containing elements.\n\n Returns:\n A dictionary where keys are the unique elements and values are their frequencies.\n \"\"\"\n\n flattened_list = []\n for lst in list_of_lists:\n flattened_list.extend(lst)\n \n return dict(Counter(flattened_list))", "matching_cluster_idx": 7}, {"solution": "from collections import Counter\ndef frequency_lists(list_of_lists):\n \"\"\"\n Calculates the frequency of each element in a flattened list of lists.\n\n Args:\n list_of_lists: A list of lists containing elements.\n\n Returns:\n A dictionary where keys are the unique elements and values are their frequencies.\n \"\"\"\n\n flattened_list = []\n for sublist in list_of_lists:\n flattened_list.extend(sublist)\n\n return dict(Counter(flattened_list))", "matching_cluster_idx": 7}, {"solution": "from collections import Counter\ndef frequency_lists(list_of_lists):\n \"\"\"\n Calculates the frequency of each element in a flattened list of lists.\n\n Args:\n list_of_lists: A list of lists containing elements.\n\n Returns:\n A dictionary where keys are the unique elements and values are their frequencies.\n \"\"\"\n\n flattened_list = []\n for sublist in list_of_lists:\n flattened_list.extend(sublist)\n\n frequency = Counter(flattened_list) # Use Counter for efficient counting\n return dict(frequency)", "matching_cluster_idx": 7}, {"solution": "from collections import Counter\ndef frequency_lists(list_of_lists):\n \"\"\"\n Calculates the frequency of each element in a flattened list of lists.\n\n Args:\n list_of_lists: A list of lists containing elements.\n\n Returns:\n A dictionary where keys are the unique elements and values are their frequencies.\n \"\"\"\n\n flattened_list = []\n for sublist in list_of_lists:\n flattened_list.extend(sublist)\n\n frequency = Counter(flattened_list) # Uses Counter for efficiency\n return dict(frequency) # Convert Counter object to a standard dictionary", "matching_cluster_idx": 7}, {"solution": "from collections import Counter\ndef frequency_lists(list_of_lists):\n \"\"\"\n Finds the frequency of each element in a flattened list of lists.\n\n Args:\n list_of_lists: A list of lists containing elements.\n\n Returns:\n A dictionary where keys are the unique elements and values are their frequencies.\n \"\"\"\n\n flattened_list = []\n for sublist in list_of_lists:\n flattened_list.extend(sublist)\n\n frequency = Counter(flattened_list) # Use Counter for efficient counting\n return dict(frequency)", "matching_cluster_idx": 7}, {"solution": "from collections import defaultdict\ndef frequency_lists(list_of_lists):\n \"\"\"\n Calculates the frequency of each element in a flattened list of lists.\n\n Args:\n list_of_lists: A list of lists containing elements.\n\n Returns:\n A dictionary where keys are the unique elements and values are their frequencies.\n \"\"\"\n frequency = defaultdict(int)\n for sublist in list_of_lists:\n for item in sublist:\n frequency[item] += 1\n return dict(frequency)", "matching_cluster_idx": 6}, {"solution": "from collections import defaultdict\ndef frequency_lists(list_of_lists):\n \"\"\"\n Calculates the frequency of each element in a flattened list of lists.\n\n Args:\n list_of_lists: A list of lists containing elements.\n\n Returns:\n A dictionary where keys are the unique elements and values are their frequencies.\n \"\"\"\n frequency = defaultdict(int)\n for sublist in list_of_lists:\n for item in sublist:\n frequency[item] += 1\n return dict(frequency)", "matching_cluster_idx": 6}, {"solution": "from collections import Counter\ndef frequency_lists(list_of_lists):\n \"\"\"\n Finds the frequency of each element in a flattened list of lists.\n\n Args:\n list_of_lists: A list of lists containing integers.\n\n Returns:\n A dictionary where keys are the elements and values are their frequencies.\n \"\"\"\n\n flattened_list = []\n for sublist in list_of_lists:\n flattened_list.extend(sublist)\n \n return dict(Counter(flattened_list))", "matching_cluster_idx": 7}, {"solution": "from collections import defaultdict\ndef frequency_lists(list_of_lists):\n \"\"\"\n Calculates the frequency of each element in a flattened list of lists.\n\n Args:\n list_of_lists: A list of lists containing elements.\n\n Returns:\n A dictionary where keys are the unique elements and values are their frequencies.\n \"\"\"\n freq_dict = defaultdict(int) # Using defaultdict to handle new elements efficiently\n for sublist in list_of_lists:\n for element in sublist:\n freq_dict[element] += 1\n return dict(freq_dict) # Convert defaultdict back to a regular dictionary", "matching_cluster_idx": 6}, {"solution": "from collections import Counter\ndef frequency_lists(list_of_lists):\n \"\"\"\n Write a function to find frequency of each element in a flattened list of lists, returned in a dictionary.\n assert frequency_lists([[1, 2, 3, 2], [4, 5, 6, 2], [7, 8, 9, 5]])=={1: 1, 2: 3, 3: 1, 4: 1, 5: 2, 6: 1, 7: 1, 8: 1, 9: 1}\n \"\"\"\n flat_list = []\n for lst in list_of_lists:\n flat_list.extend(lst)\n \n return dict(Counter(flat_list))", "matching_cluster_idx": 7}, {"solution": "from collections import Counter\ndef frequency_lists(list_of_lists):\n \"\"\"\n Finds the frequency of each element in a flattened list of lists.\n\n Args:\n list_of_lists: A list of lists containing elements.\n\n Returns:\n A dictionary where keys are the elements and values are their frequencies.\n \"\"\"\n\n flat_list = []\n for sublist in list_of_lists:\n flat_list.extend(sublist)\n\n return dict(Counter(flat_list))", "matching_cluster_idx": 7}, {"solution": "from collections import Counter\ndef frequency_lists(list_of_lists):\n \"\"\"\n Calculates the frequency of each element in a flattened list of lists.\n\n Args:\n list_of_lists: A list of lists containing elements.\n\n Returns:\n A dictionary where keys are the elements and values are their frequencies.\n \"\"\"\n flattened_list = []\n for sublist in list_of_lists:\n flattened_list.extend(sublist)\n\n frequency = Counter(flattened_list) # Use Counter for efficient frequency counting\n return dict(frequency)", "matching_cluster_idx": 7}, {"solution": "from collections import Counter\ndef frequency_lists(list_of_lists):\n \"\"\"\n Calculates the frequency of each element in a flattened list of lists.\n\n Args:\n list_of_lists: A list of lists containing elements.\n\n Returns:\n A dictionary where keys are the unique elements and values are their frequencies.\n \"\"\"\n\n flat_list = []\n for sublist in list_of_lists:\n flat_list.extend(sublist)\n\n return dict(Counter(flat_list))", "matching_cluster_idx": 7}, {"solution": "from collections import Counter\ndef frequency_lists(list_of_lists):\n \"\"\"\n Finds the frequency of each element in a flattened list of lists.\n\n Args:\n list_of_lists: A list of lists containing elements.\n\n Returns:\n A dictionary where keys are the elements and values are their frequencies.\n \"\"\"\n\n flattened_list = []\n for sublist in list_of_lists:\n flattened_list.extend(sublist)\n\n return dict(Counter(flattened_list))", "matching_cluster_idx": 7}, {"solution": "from collections import Counter\ndef frequency_lists(list_of_lists):\n \"\"\"\n Finds the frequency of each element in a flattened list of lists.\n\n Args:\n list_of_lists: A list of lists containing elements.\n\n Returns:\n A dictionary where keys are the unique elements and values are their frequencies.\n \"\"\"\n flattened_list = []\n for sublist in list_of_lists:\n flattened_list.extend(sublist)\n \n frequency = Counter(flattened_list) # Use Counter for efficient frequency counting\n return dict(frequency) # converts back to a dictionary as specified\nlist_of_lists = [[1, 2, 3, 2], [4, 5, 6, 2], [7, 8, 9, 5]]\nfrequency = frequency_lists(list_of_lists)", "matching_cluster_idx": 7}, {"solution": "from collections import Counter\ndef frequency_lists(list_of_lists):\n \"\"\"\n Calculates the frequency of each element in a flattened list of lists.\n\n Args:\n list_of_lists: A list of lists containing elements.\n\n Returns:\n A dictionary where keys are the elements and values are their frequencies.\n \"\"\"\n flattened_list = []\n for lst in list_of_lists:\n flattened_list.extend(lst)\n return dict(Counter(flattened_list))", "matching_cluster_idx": 7}, {"solution": "from collections import Counter\ndef frequency_lists(list_of_lists):\n \"\"\"\n Calculates the frequency of each element in a flattened list of lists.\n\n Args:\n list_of_lists: A list of lists containing elements.\n\n Returns:\n A dictionary where keys are the unique elements and values are their frequencies.\n \"\"\"\n flat_list = []\n for sublist in list_of_lists:\n flat_list.extend(sublist)\n \n return dict(Counter(flat_list))", "matching_cluster_idx": 7}, {"solution": "from collections import defaultdict\ndef frequency_lists(list_of_lists):\n \"\"\"\n Finds the frequency of each element in a flattened list of lists.\n\n Args:\n list_of_lists: A list of lists containing numbers.\n\n Returns:\n A dictionary where keys are the unique elements and values are their frequencies.\n \"\"\"\n frequency = defaultdict(int)\n for sub_list in list_of_lists:\n for num in sub_list:\n frequency[num] += 1\n return dict(frequency)", "matching_cluster_idx": 6}, {"solution": "from collections import Counter\ndef frequency_lists(list_of_lists):\n \"\"\"\n Calculates the frequency of each element in a flattened list of lists.\n\n Args:\n list_of_lists: A list of lists containing elements.\n\n Returns:\n A dictionary where keys are the unique elements and values are their frequencies.\n \"\"\"\n flattened_list = []\n for lst in list_of_lists:\n flattened_list.extend(lst)\n \n return dict(Counter(flattened_list))", "matching_cluster_idx": 7}]}, "Mbpp/106": {"dps": 43.44155844155844, "dps_norm": 77.5, "pass@1": 100.0, "profiled": [{"solution": "def add_lists(lst, tpl):\n \"\"\"Appends a list to a tuple.\n\n Args:\n lst: The list to append.\n tpl: The tuple to append to.\n\n Returns:\n A new tuple with the list appended to the original tuple.\n \"\"\"\n return tpl + tuple(lst)", "matching_cluster_idx": 4}, {"solution": "def add_lists(lst, tpl):\n \"\"\"Appends a list to a tuple and returns a new tuple.\n\n Args:\n lst: The list to append.\n tpl: The tuple to append to.\n\n Returns:\n A new tuple with the list appended to the original tuple.\n \"\"\"\n return tuple(list(tpl) + lst)", "matching_cluster_idx": 3}, {"solution": "def add_lists(lst, tpl):\n \"\"\"Appends a list to a tuple and returns the combined tuple.\"\"\"\n return tpl + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(list_to_add, original_tuple):\n \"\"\"Appends a list to a tuple.\n\n Args:\n list_to_add: The list to append.\n original_tuple: The original tuple.\n\n Returns:\n A new tuple with the list's elements appended to the original tuple.\n \"\"\"\n return original_tuple + tuple(list_to_add)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tpl):\n \"\"\"Appends a list to a tuple and returns the combined tuple.\"\"\"\n return tuple(list(tpl) + lst)", "matching_cluster_idx": 3}, {"solution": "def add_lists(lst, tpl):\n \"\"\"Appends a list to a tuple.\n\n Args:\n lst: The list to append.\n tpl: The tuple to append to.\n\n Returns:\n A new tuple with the list's elements appended to the original tuple.\n \"\"\"\n return tpl + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tpl):\n \"\"\"Appends a list to a tuple.\n\n Args:\n lst: The list to append.\n tpl: The tuple to append to.\n\n Returns:\n A new tuple with the elements of the tuple followed by the elements of the list.\n \"\"\"\n\n return tpl + tuple(lst)", "matching_cluster_idx": 4}, {"solution": "def add_lists(lst, tpl):\n \"\"\"Appends a list to a tuple and returns the result as a tuple.\"\"\"\n return tpl + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tpl):\n \"\"\"Appends a list to a tuple.\n\n Args:\n lst: The list to append.\n tpl: The tuple to which the list is appended.\n\n Returns:\n A new tuple containing the elements of the original tuple followed by the elements of the list.\n \"\"\"\n return tuple(list(tpl) + lst)", "matching_cluster_idx": 2}, {"solution": "def add_lists(lst, tpl):\n \"\"\"Appends a list to a tuple and returns a new tuple.\"\"\"\n return tuple(list(tpl) + lst)", "matching_cluster_idx": 2}, {"solution": "def add_lists(lst, tpl):\n \"\"\"Appends a list to a tuple.\n\n Args:\n lst: The list to append.\n tpl: The tuple to append to.\n\n Returns:\n A new tuple with the list's elements appended.\n \"\"\"\n return tuple(list(tpl) + lst)", "matching_cluster_idx": 3}, {"solution": "def add_lists(lst, tpl):\n \"\"\"Appends a list to a tuple.\n\n Args:\n lst: The list to append.\n tpl: The tuple to append to.\n\n Returns:\n A new tuple with the list elements added to the end of the tuple.\n \"\"\"\n return tuple(list(tpl) + lst)", "matching_cluster_idx": 2}, {"solution": "def add_lists(lst, tpl):\n \"\"\"Appends a list to a tuple and returns the combined tuple.\"\"\"\n return tuple(list(tpl) + lst)", "matching_cluster_idx": 3}, {"solution": "def add_lists(list_to_add, tuple_to_extend):\n \"\"\"Appends a list to a tuple.\n\n Args:\n list_to_add: The list to be appended.\n tuple_to_extend: The tuple to be extended.\n\n Returns:\n A new tuple containing elements of the original tuple followed by elements of the list.\n \"\"\"\n return tuple_to_extend + tuple(list_to_add)", "matching_cluster_idx": 4}, {"solution": "def add_lists(lst, tpl):\n \"\"\"Appends a list to a tuple.\n\n Args:\n lst: The list to append.\n tpl: The tuple to append to.\n\n Returns:\n A new tuple with the list appended.\n \"\"\"\n return tuple(list(tpl) + lst)", "matching_cluster_idx": 3}, {"solution": "def add_lists(lst, tpl):\n \"\"\"Appends a list to a tuple, returning a new tuple.\"\"\"\n return tpl + tuple(lst)", "matching_cluster_idx": 4}, {"solution": "def add_lists(list_to_add, input_tuple):\n \"\"\"Appends a list to a tuple and returns the combined tuple.\n\n Args:\n list_to_add: The list to append.\n input_tuple: The tuple to which the list will be appended.\n\n Returns:\n A new tuple containing the elements of the original tuple followed by \n the elements of the list.\n \"\"\"\n\n return input_tuple + tuple(list_to_add)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tpl):\n \"\"\"Appends a list to a tuple and returns a new tuple.\"\"\"\n return tpl + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(list_to_add, input_tuple):\n \"\"\"Appends a list to a tuple and returns the result as a new tuple.\n\n Args:\n list_to_add: The list to append.\n input_tuple: The tuple to append to.\n\n Returns:\n A new tuple containing the elements of the original tuple followed by the\n elements of the list.\n \"\"\"\n new_tuple = input_tuple + tuple(list_to_add)\n return new_tuple", "matching_cluster_idx": 4}, {"solution": "def add_lists(lst, tpl):\n \"\"\"Appends a list to a tuple and returns a new tuple.\n\n Args:\n lst: The list to append.\n tpl: The tuple to append to.\n\n Returns:\n A new tuple containing the elements of the tuple followed by the elements of the list.\n \"\"\"\n return tuple(list(tpl) + lst)", "matching_cluster_idx": 2}]}, "Mbpp/108": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def merge_sorted_list(list1, list2, list3):\n \"\"\"Merges three lists into a single sorted list.\"\"\"\n merged_list = list1 + list2 + list3\n merged_list.sort()\n return merged_list\nlist1 = [25, 24, 15, 4, 5, 29, 110]\nlist2 = [19, 20, 11, 56, 25, 233, 154]\nlist3 = [24, 26, 54, 48]\nmerged_list = merge_sorted_list(list1, list2, list3)", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n \"\"\"Merges three lists into a single sorted list.\"\"\"\n merged_list = list1 + list2 + list3\n merged_list.sort()\n return merged_list\nlist1 = [25, 24, 15, 4, 5, 29, 110]\nlist2 = [19, 20, 11, 56, 25, 233, 154]\nlist3 = [24, 26, 54, 48]\nmerged_list = merge_sorted_list(list1, list2, list3)", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n \"\"\"Merges three lists into a single sorted list.\"\"\"\n merged_list = list1 + list2 + list3\n merged_list.sort()\n return merged_list\nlist1 = [25, 24, 15, 4, 5, 29, 110]\nlist2 = [19, 20, 11, 56, 25, 233, 154]\nlist3 = [24, 26, 54, 48]\nmerged_list = merge_sorted_list(list1, list2, list3)", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n \"\"\"Merges three lists into a single sorted list.\"\"\"\n merged_list = list1 + list2 + list3\n merged_list.sort()\n return merged_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n \"\"\"Merges three lists into a single sorted list.\"\"\"\n\n merged_list = list1 + list2 + list3\n merged_list.sort()\n return merged_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n \"\"\"Merges three lists into a single sorted list.\"\"\"\n merged_list = list1 + list2 + list3\n merged_list.sort()\n return merged_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n \"\"\"Merges three lists into a single sorted list.\"\"\"\n\n merged_list = list1 + list2 + list3\n merged_list.sort()\n return merged_list\nlist1 = [25, 24, 15, 4, 5, 29, 110]\nlist2 = [19, 20, 11, 56, 25, 233, 154]\nlist3 = [24, 26, 54, 48]\nmerged_list = merge_sorted_list(list1, list2, list3)", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n \"\"\"Merges three lists into a single sorted list.\"\"\"\n\n merged_list = list1 + list2 + list3\n merged_list.sort()\n return merged_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n \"\"\"Merges three lists into a single sorted list.\"\"\"\n merged_list = list1 + list2 + list3\n merged_list.sort()\n return merged_list\nlist1 = [25, 24, 15, 4, 5, 29, 110]\nlist2 = [19, 20, 11, 56, 25, 233, 154]\nlist3 = [24, 26, 54, 48]\nmerged_list = merge_sorted_list(list1, list2, list3)", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n \"\"\"Merges three lists into a single sorted list.\"\"\"\n merged_list = list1 + list2 + list3\n merged_list.sort()\n return merged_list\nlist1 = [25, 24, 15, 4, 5, 29, 110]\nlist2 = [19, 20, 11, 56, 25, 233, 154]\nlist3 = [24, 26, 54, 48]\nmerged_list = merge_sorted_list(list1, list2, list3)", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n \"\"\"Merges three lists into a single sorted list.\n\n Args:\n list1: The first list.\n list2: The second list.\n list3: The third list.\n\n Returns:\n A new list containing all elements from the input lists, sorted in ascending order.\n \"\"\"\n merged_list = list1 + list2 + list3\n merged_list.sort() # Sorts the merged list in-place\n return merged_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n \"\"\"Merges three lists into a single sorted list.\"\"\"\n\n merged_list = list1 + list2 + list3\n merged_list.sort()\n return merged_list\nlist1 = [25, 24, 15, 4, 5, 29, 110]\nlist2 = [19, 20, 11, 56, 25, 233, 154]\nlist3 = [24, 26, 54, 48]\nmerged_list = merge_sorted_list(list1, list2, list3)", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n \"\"\"Merges three lists into a single sorted list.\"\"\"\n\n merged_list = list1 + list2 + list3\n merged_list.sort()\n return merged_list\nlist1 = [25, 24, 15, 4, 5, 29, 110]\nlist2 = [19, 20, 11, 56, 25, 233, 154]\nlist3 = [24, 26, 54, 48]\nmerged_list = merge_sorted_list(list1, list2, list3)", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n \"\"\"Merges three lists into a single sorted list.\n\n Args:\n list1: The first list.\n list2: The second list.\n list3: The third list.\n\n Returns:\n A new list containing all elements from the input lists, sorted in ascending order.\n \"\"\"\n merged_list = list1 + list2 + list3\n merged_list.sort()\n return merged_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n \"\"\"Merges three lists into a single sorted list.\n\n Args:\n list1: The first list.\n list2: The second list.\n list3: The third list.\n\n Returns:\n A new list containing all elements from the input lists, sorted in ascending order.\n \"\"\"\n merged_list = list1 + list2 + list3\n merged_list.sort()\n return merged_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n \"\"\"Merges three lists into a single sorted list.\"\"\"\n\n merged_list = list1 + list2 + list3\n merged_list.sort()\n return merged_list\nlist1 = [25, 24, 15, 4, 5, 29, 110]\nlist2 = [19, 20, 11, 56, 25, 233, 154]\nlist3 = [24, 26, 54, 48]\nmerged_list = merge_sorted_list(list1, list2, list3)", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n \"\"\"Merges three lists into a single sorted list.\n\n Args:\n list1: The first list.\n list2: The second list.\n list3: The third list.\n\n Returns:\n A new list containing all elements from the input lists, sorted in ascending order.\n \"\"\"\n merged_list = list1 + list2 + list3\n merged_list.sort()\n return merged_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n \"\"\"Merges three lists into a single sorted list.\"\"\"\n\n merged_list = list1 + list2 + list3\n merged_list.sort()\n return merged_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n \"\"\"Merges three lists into a single sorted list.\"\"\"\n merged_list = list1 + list2 + list3\n merged_list.sort()\n return merged_list\nlist1 = [25, 24, 15, 4, 5, 29, 110]\nlist2 = [19, 20, 11, 56, 25, 233, 154]\nlist3 = [24, 26, 54, 48]\nmerged_list = merge_sorted_list(list1, list2, list3)", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n \"\"\"Merges three lists into a single sorted list.\n\n Args:\n list1: The first list.\n list2: The second list.\n list3: The third list.\n\n Returns:\n A new list containing all elements from the input lists, sorted in ascending order.\n \"\"\"\n merged_list = list1 + list2 + list3\n merged_list.sort() # Sorts the combined list in-place\n return merged_list\nlist1 = [25, 24, 15, 4, 5, 29, 110]\nlist2 = [19, 20, 11, 56, 25, 233, 154]\nlist3 = [24, 26, 54, 48]", "matching_cluster_idx": 10}]}, "Mbpp/111": {"dps": 90.64615384615385, "dps_norm": 85.625, "pass@1": 100.0, "profiled": [{"solution": "from functools import reduce\ndef common_in_nested_lists(nested_lists):\n \"\"\"\n Finds the common elements in a list of lists.\n\n Args:\n nested_lists: A list of lists.\n\n Returns:\n A list containing the elements that are present in all the input lists.\n \"\"\"\n if not nested_lists:\n return []\n\n # Convert the lists to sets for efficient intersection\n sets = [set(lst) for lst in nested_lists]\n\n # Use reduce to find the intersection of all sets\n common_elements = list(reduce(lambda x, y: x.intersection(y), sets))\n\n return common_elements", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef common_in_nested_lists(nested_lists: List[List[int]]) -> List[int]:\n \"\"\"\n Finds the common elements in given nested lists.\n\n Args:\n nested_lists: A list of lists of integers.\n\n Returns:\n A list of integers representing the common elements.\n \"\"\"\n\n if not nested_lists:\n return []\n\n # Convert the first list to a set for efficient intersection operations.\n common_elements = set(nested_lists[0])\n\n # Iterate through the remaining lists and update the common elements set.\n for lst in nested_lists[1:]:\n common_elements &= set(lst)\n\n return list(common_elements)", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef common_in_nested_lists(nested_lists: List[List[int]]) -> List[int]:\n \"\"\"\n Finds the common elements in a list of lists.\n\n Args:\n nested_lists: A list of lists of integers.\n\n Returns:\n A list of integers that are common to all the input lists.\n \"\"\"\n if not nested_lists:\n return []\n\n common_elements = set(nested_lists[0])\n for lst in nested_lists[1:]:\n common_elements.intersection_update(lst)\n \n return list(common_elements)", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef common_in_nested_lists(nested_lists: List[List[int]]) -> List[int]:\n \"\"\"\n Finds the common elements in a list of lists.\n\n Args:\n nested_lists: A list of lists of integers.\n\n Returns:\n A list of integers that are common to all lists.\n \"\"\"\n\n if not nested_lists:\n return []\n \n # Convert lists to sets for efficient intersection\n sets = [set(lst) for lst in nested_lists]\n\n # Find the intersection of all sets\n common_elements = sets[0].intersection(*sets[1:])\n\n return list(common_elements)", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef common_in_nested_lists(nested_lists: List[List[int]]) -> List[int]:\n \"\"\"\n Finds the common elements in given nested lists.\n\n Args:\n nested_lists: A list of lists of integers.\n\n Returns:\n A list of integers that are common to all the nested lists.\n \"\"\"\n if not nested_lists:\n return []\n\n # Convert the first list to a set for efficient intersection\n common_elements = set(nested_lists[0])\n\n # Iterate through the remaining lists and find the intersection\n for lst in nested_lists[1:]:\n common_elements.intersection_update(lst)\n\n return list(common_elements)", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef common_in_nested_lists(nested_lists: List[List[int]]) -> List[int]:\n \"\"\"\n Finds the common elements in a list of nested lists.\n\n Args:\n nested_lists: A list of lists of integers.\n\n Returns:\n A list of integers that are common to all nested lists.\n \"\"\"\n if not nested_lists:\n return []\n \n # Convert the first list to a set for efficient lookups\n common_elements = set(nested_lists[0])\n\n # Iterate through the remaining lists\n for lst in nested_lists[1:]:\n # Update common_elements with the intersection of the current list and common_elements\n common_elements.intersection_update(lst)\n\n return list(common_elements)", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef common_in_nested_lists(nested_lists: List[List[int]]) -> List[int]:\n \"\"\"\n Finds the common elements in a list of nested lists.\n\n Args:\n nested_lists: A list of lists of integers.\n\n Returns:\n A list of integers representing the common elements.\n \"\"\"\n if not nested_lists:\n return []\n\n # Convert the first list to a set for efficient intersection\n common_elements = set(nested_lists[0])\n\n # Iterate through the remaining lists and find the intersection\n for lst in nested_lists[1:]:\n common_elements.intersection_update(lst)\n\n return list(common_elements)", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef common_in_nested_lists(nested_lists: List[List[int]]) -> List[int]:\n \"\"\"\n Finds the common elements in a list of lists.\n\n Args:\n nested_lists: A list of lists of integers.\n\n Returns:\n A list of integers containing the common elements.\n \"\"\"\n if not nested_lists:\n return []\n\n # Convert the first list to a set for efficient intersection\n common_elements = set(nested_lists[0])\n\n # Iterate through the remaining lists and find the intersection\n for lst in nested_lists[1:]:\n common_elements.intersection_update(lst)\n\n return list(common_elements)", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef common_in_nested_lists(nested_lists: List[List[int]]) -> List[int]:\n \"\"\"\n Finds the common elements in given nested lists.\n\n Args:\n nested_lists: A list of lists of integers.\n\n Returns:\n A list containing the common elements.\n \"\"\"\n if not nested_lists:\n return []\n\n common_elements = set(nested_lists[0])\n for lst in nested_lists[1:]:\n common_elements.intersection_update(lst)\n \n return list(common_elements)", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n \"\"\"\n Finds the common elements in a list of nested lists.\n\n Args:\n nested_lists: A list of lists.\n\n Returns:\n A list containing the common elements.\n \"\"\"\n if not nested_lists:\n return []\n\n # Convert the first list to a set for efficient intersection\n common_elements = set(nested_lists[0])\n\n # Iterate through the remaining lists and update the intersection\n for lst in nested_lists[1:]:\n common_elements.intersection_update(lst)\n\n return list(common_elements)", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef common_in_nested_lists(nested_lists: List[List[int]]) -> List[int]:\n \"\"\"\n Finds the common elements in given nested lists.\n\n Args:\n nested_lists: A list of lists of integers.\n\n Returns:\n A list of integers containing the common elements.\n \"\"\"\n if not nested_lists:\n return []\n\n # Convert the first list to a set for efficient intersection\n common_elements = set(nested_lists[0])\n\n # Iterate through the remaining lists and find the intersection\n for lst in nested_lists[1:]:\n common_elements.intersection_update(lst) # More efficient than &=\n\n return list(common_elements)", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n \"\"\"\n Finds the common elements in a list of nested lists.\n\n Args:\n nested_lists: A list of lists.\n\n Returns:\n A list containing the common elements.\n \"\"\"\n if not nested_lists:\n return []\n\n # Convert the first list to a set for efficient intersection\n common_elements = set(nested_lists[0])\n\n # Iterate through the remaining nested lists\n for lst in nested_lists[1:]:\n common_elements.intersection_update(lst) # Efficiently finds the intersection\n\n return list(common_elements)", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n \"\"\"\n Finds the common elements in a list of nested lists.\n\n Args:\n nested_lists: A list of lists.\n\n Returns:\n A list containing the elements that are present in all nested lists.\n \"\"\"\n\n if not nested_lists:\n return []\n\n # Convert the first list to a set for efficient intersection\n common_elements = set(nested_lists[0])\n\n # Iterate through the remaining lists and update the common elements\n for lst in nested_lists[1:]:\n common_elements.intersection_update(lst)\n\n return list(common_elements)", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef common_in_nested_lists(nested_lists: List[List[int]]) -> List[int]:\n \"\"\"\n Finds the common elements in given nested lists.\n\n Args:\n nested_lists: A list of lists of integers.\n\n Returns:\n A list of integers representing the common elements.\n \"\"\"\n\n if not nested_lists:\n return []\n\n # Convert the first list to a set for efficient intersection\n common_elements = set(nested_lists[0])\n\n # Iterate through the remaining lists and find the intersection\n for lst in nested_lists[1:]:\n common_elements.intersection_update(lst)\n\n return list(common_elements)", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n \"\"\"\n Finds the common elements in a list of nested lists.\n\n Args:\n nested_lists: A list of lists.\n\n Returns:\n A list containing the elements that are present in all nested lists.\n \"\"\"\n if not nested_lists:\n return []\n\n # Convert the first list to a set for efficient intersection operations\n common_elements = set(nested_lists[0])\n\n # Iterate through the remaining lists and update the common elements set\n for lst in nested_lists[1:]:\n common_elements.intersection_update(lst)\n\n return list(common_elements)", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef common_in_nested_lists(nested_lists: List[List[int]]) -> List[int]:\n \"\"\"\n Finds the common elements in a list of nested lists.\n\n Args:\n nested_lists: A list of lists of integers.\n\n Returns:\n A list containing the common elements.\n \"\"\"\n\n if not nested_lists:\n return []\n\n # Convert the first list to a set for efficient intersection operations\n common_elements = set(nested_lists[0])\n\n # Iterate through the remaining lists and update the common_elements set\n for lst in nested_lists[1:]:\n common_elements.intersection_update(lst)\n\n return list(common_elements)", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef common_in_nested_lists(nested_lists: List[List[int]]) -> List[int]:\n \"\"\"\n Finds the common elements in given nested lists.\n\n Args:\n nested_lists: A list of lists of integers.\n\n Returns:\n A list of integers representing the common elements.\n \"\"\"\n if not nested_lists:\n return []\n \n # Convert the first list to a set for efficient intersection\n common_elements = set(nested_lists[0])\n \n # Iterate through the remaining lists and find the intersection\n for lst in nested_lists[1:]:\n common_elements.intersection_update(lst)\n \n return list(common_elements)", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef common_in_nested_lists(nested_lists: List[List[int]]) -> List[int]:\n \"\"\"\n Finds the common elements in a list of nested lists.\n\n Args:\n nested_lists: A list of lists of integers.\n\n Returns:\n A list of integers that are common to all nested lists.\n \"\"\"\n if not nested_lists:\n return []\n\n # Convert the first list to a set for efficient intersection operations\n common_elements = set(nested_lists[0])\n\n # Iterate through the remaining lists and find the intersection\n for lst in nested_lists[1:]:\n common_elements.intersection_update(lst)\n\n return list(common_elements)", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n \"\"\"\n Finds the common elements in a list of lists.\n\n Args:\n nested_lists: A list of lists.\n\n Returns:\n A list containing the elements that are present in all sublists.\n \"\"\"\n\n if not nested_lists:\n return []\n\n # Convert the first list to a set for efficient intersection operations\n common_elements = set(nested_lists[0])\n\n # Iterate through the remaining lists and update the common elements set\n for lst in nested_lists[1:]:\n common_elements.intersection_update(lst)\n\n return list(common_elements)", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef common_in_nested_lists(nested_lists: List[List[int]]) -> List[int]:\n \"\"\"\n Finds the common elements in given nested lists.\n\n Args:\n nested_lists: A list of lists of integers.\n\n Returns:\n A list of common elements.\n \"\"\"\n if not nested_lists:\n return []\n\n common_elements = set(nested_lists[0])\n for lst in nested_lists[1:]:\n common_elements.intersection_update(lst)\n\n return list(common_elements)", "matching_cluster_idx": 6}]}, "Mbpp/123": {"dps": 99.62686567164178, "dps_norm": 85.71428571428571, "pass@1": 84.0, "profiled": [{"solution": "def sum_proper_divisors(n):\n \"\"\"Calculates the sum of proper divisors of a number.\"\"\"\n sum_div = 1\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n sum_div += i\n if i != n // i: # Avoid double-counting for square roots\n sum_div += n // i\n return sum_div\ndef amicable_numbers_sum(limit):\n \"\"\"Calculates the sum of all amicable numbers up to a limit.\"\"\"\n sum_amicable = 0\n amicable_nums = set() # Use a set to avoid double counting amicable pairs\n\n for num in range(2, limit + 1):\n if num not in amicable_nums: # Check if already part of an amicable pair\n sum_div_num = sum_proper_divisors(num)\n sum_div_other = sum_proper_divisors(sum_div_num)\n if num == sum_div_other and num != sum_div_num: # Amicable pair found\n sum_amicable += num\n if sum_div_num <= limit: # Check if the other number is within the limit\n sum_amicable += sum_div_num\n amicable_nums.add(num)\n amicable_nums.add(sum_div_num)\n return sum_amicable", "matching_cluster_idx": 11}, {"solution": "def sum_proper_divisors(n):\n \"\"\"Calculates the sum of proper divisors of a number.\"\"\"\n total = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n total += i\n if i * i != n and i != 1: # Avoid double counting and including n itself\n total += n // i\n return total\ndef amicable_numbers_sum(limit):\n \"\"\"Calculates the sum of all amicable numbers up to a given limit.\"\"\"\n amicable_sum = 0\n checked = set() # Keep track of checked numbers to avoid redundant calculations\n\n for num in range(2, limit + 1):\n if num in checked:\n continue\n\n div_sum = sum_proper_divisors(num)\n div_sum2 = sum_proper_divisors(div_sum)\n\n if num == div_sum2 and num != div_sum: # Amicable numbers are not equal to their divisor sum\n amicable_sum += num\n if div_sum <= limit: # Ensure both amicable numbers are within the limit.\n amicable_sum += div_sum\n checked.add(num) # Add the discovered amicable pair to avoid recalculations\n checked.add(div_sum)\n\n return amicable_sum\nlimit = 10000", "matching_cluster_idx": 11}, {"solution": "def sum_of_divisors(n):\n \"\"\"Calculates the sum of proper divisors of a number.\"\"\"\n total = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n total += i\n if i * i != n and i != 1:\n total += n // i\n return total\ndef amicable_numbers_sum(limit):\n \"\"\"Calculates the sum of all amicable numbers up to a limit.\"\"\"\n amicable_sum = 0\n checked = set() # Keep track of checked numbers to avoid double counting\n for num in range(2, limit + 1):\n if num in checked:\n continue\n sum1 = sum_of_divisors(num)\n sum2 = sum_of_divisors(sum1)\n\n if num == sum2 and num != sum1: # Amicable numbers and not perfect numbers\n amicable_sum += num\n if sum1 <= limit: # Only add the pair if both are within the limit\n amicable_sum += sum1\n checked.add(num)\n checked.add(sum1)\n return amicable_sum", "matching_cluster_idx": 11}, {"solution": "def sum_divisors(n):\n \"\"\"Calculate the sum of proper divisors of a number.\"\"\"\n total = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n total += i\n if i * i != n: # Avoid adding the same divisor twice for perfect squares\n total += n // i\n return total - n # Subtract the number itself to get the sum of proper divisors\ndef amicable_numbers_sum(limit):\n \"\"\"Calculate the sum of all amicable numbers up to a limit.\"\"\"\n amicable_sum = 0\n checked = set() # Keep track of checked numbers to avoid double counting\n\n for num in range(1, limit + 1):\n if num in checked:\n continue\n\n sum1 = sum_divisors(num)\n sum2 = sum_divisors(sum1)\n\n if num == sum2 and num != sum1: # Amicable numbers and not perfect numbers\n amicable_sum += num\n if sum1 <= limit: # Add the other amicable pair only if it is within the limit\n amicable_sum += sum1\n\n checked.add(num) # Mark both numbers as checked (as they form a pair or one is not amicable)\n if sum1 <= limit and sum1 != num: # Avoids unnecessary rechecking of higher numbers later\n checked.add(sum1)\n\n return amicable_sum", "matching_cluster_idx": 11}, {"solution": "def sum_of_divisors(n):\n \"\"\"Calculates the sum of proper divisors of a number.\"\"\"\n total = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n total += i\n if i * i != n and i != 1: # Avoid double counting and including the number itself\n total += n // i\n return total\ndef amicable_numbers_sum(limit):\n \"\"\"Calculates the sum of all amicable numbers up to a given limit.\"\"\"\n amicable_sum = 0\n checked = set() # Optimization: Keep track of checked numbers to avoid redundant calculations\n\n for num in range(1, limit + 1):\n if num not in checked:\n sum1 = sum_of_divisors(num)\n sum2 = sum_of_divisors(sum1)\n\n if num == sum2 and num != sum1: # Amicable numbers are different but their divisor sums match\n amicable_sum += num\n if sum1 <= limit: # Only add sum1 if it's within the limit\n amicable_sum += sum1\n\n checked.add(num)\n checked.add(sum1)\n\n return amicable_sum", "matching_cluster_idx": 11}, {"solution": "def sum_proper_divisors(n):\n \"\"\"Calculates the sum of proper divisors of a number.\"\"\"\n total = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n total += i\n if i * i != n and i != 1: # Avoid adding the number itself and double-counting the square root\n total += n // i\n return total\ndef amicable_numbers_sum(limit):\n \"\"\"Calculates the sum of all amicable numbers up to a limit.\"\"\"\n amicable_sum = 0\n checked = set() # Keep track of checked numbers to avoid double-counting\n\n for num in range(1, limit + 1):\n if num not in checked:\n sum1 = sum_proper_divisors(num)\n sum2 = sum_proper_divisors(sum1)\n\n if num == sum2 and num != sum1: # Amicable numbers are different but have matching divisor sums\n amicable_sum += num\n if sum1 <= limit: # Only add sum1 if it's within the limit\n amicable_sum += sum1\n\n checked.add(num)\n checked.add(sum1) # Add sum1 to avoid redundant checks\n return amicable_sum", "matching_cluster_idx": 11}, {"solution": "def sum_proper_divisors(n):\n \"\"\"Calculates the sum of proper divisors of a number.\"\"\"\n sum_divisors = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n sum_divisors += i\n if i * i != n and i != 1: # Avoid double counting and including the number itself\n sum_divisors += n // i\n return sum_divisors\ndef amicable_numbers_sum(limit):\n \"\"\"Calculates the sum of all amicable numbers up to a given limit.\"\"\"\n amicable_sum = 0\n amicable_found = set() # Keep track of amicable pairs to avoid double counting\n\n for num in range(1, limit + 1):\n if num in amicable_found:\n continue # Skip numbers that are already part of an amicable pair\n\n sum_div_num = sum_proper_divisors(num)\n sum_div_other = sum_proper_divisors(sum_div_num)\n\n if num == sum_div_other and num != sum_div_num: # Amicable and not perfect numbers\n amicable_sum += num\n amicable_found.add(num)\n if sum_div_num <= limit: # only add the other amicable number if it's within the limit\n amicable_sum += sum_div_num\n amicable_found.add(sum_div_num)\n\n\n return amicable_sum", "matching_cluster_idx": 11}, {"solution": "def sum_of_proper_divisors(n):\n \"\"\"Calculates the sum of proper divisors of a number.\"\"\"\n total = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n total += i\n if i * i != n and i != 1: # Avoid double counting and adding the number itself\n total += n // i\n return total\ndef amicable_numbers_sum(limit):\n \"\"\"Calculates the sum of all amicable numbers under a given limit.\"\"\"\n amicable_sum = 0\n checked = set() # Keep track of checked numbers to avoid redundant calculations\n for num in range(1, limit + 1):\n if num not in checked:\n sum1 = sum_of_proper_divisors(num)\n sum2 = sum_of_proper_divisors(sum1)\n\n if num == sum2 and num != sum1: # Amicable numbers and not perfect numbers\n amicable_sum += num\n if sum1 < limit: # Only add sum1 if it's within the limit\n amicable_sum += sum1\n checked.add(num)\n checked.add(sum1)\n\n return amicable_sum", "matching_cluster_idx": 11}, {"solution": "def sum_divisors(n):\n \"\"\"Calculates the sum of proper divisors of a number.\"\"\"\n total = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n total += i\n if i * i != n and i != 1: # Avoid double counting and exclude the number itself\n total += n // i\n return total\ndef amicable_numbers_sum(limit):\n \"\"\"Calculates the sum of all amicable numbers up to a limit.\"\"\"\n amicable_sum = 0\n checked = set() # Keep track of checked numbers to avoid redundant calculations and double counting\n\n for num in range(2, limit + 1):\n if num not in checked:\n sum1 = sum_divisors(num)\n sum2 = sum_divisors(sum1)\n\n if num == sum2 and num != sum1: # Amicable numbers are not equal to themselves\n amicable_sum += num\n if sum1 <= limit: # Only add sum1 if it's within the limit\n amicable_sum += sum1\n\n checked.add(num) # Add num to checked regardless of whether it is amicable or not\n checked.add(sum1) # Mark the other paired number\n\n return amicable_sum", "matching_cluster_idx": 11}, {"solution": "def sum_of_divisors(n):\n \"\"\"Calculates the sum of proper divisors of a number.\"\"\"\n total = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n total += i\n if i * i != n and i != 1: # Avoid double counting and including the number itself\n total += n // i\n return total\ndef amicable_numbers_sum(limit):\n \"\"\"Calculates the sum of all amicable numbers up to a limit.\"\"\"\n amicable_sum = 0\n for num in range(2, limit + 1):\n sum1 = sum_of_divisors(num)\n sum2 = sum_of_divisors(sum1)\n if sum2 == num and sum1 != num: # Ensure they are amicable and not perfect numbers\n amicable_sum += num # Only add once to prevent double counting since amicable pairs will be found twice\n return amicable_sum", "matching_cluster_idx": 11}, {"solution": "def sum_proper_divisors(n):\n \"\"\"Calculates the sum of proper divisors of a number.\"\"\"\n sum_divisors = 1\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n sum_divisors += i\n if n // i != i:\n sum_divisors += n // i\n return sum_divisors\ndef amicable_numbers_sum(limit):\n \"\"\"Calculates the sum of all amicable numbers up to a limit.\"\"\"\n sum_amicable = 0\n checked = set() # Keep track of checked numbers to avoid duplicates\n for num1 in range(2, limit + 1):\n if num1 not in checked:\n num2 = sum_proper_divisors(num1)\n if num1 != num2 and num2 <= limit and sum_proper_divisors(num2) == num1:\n sum_amicable += num1 + num2\n checked.add(num1)\n checked.add(num2)\n return sum_amicable", "matching_cluster_idx": 11}, {"solution": "def sum_of_divisors(n):\n \"\"\"Calculate the sum of proper divisors of a number.\"\"\"\n total = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n total += i\n if i * i != n:\n total += n // i\n return total - n # Exclude the number itself\ndef amicable_numbers_sum(limit):\n \"\"\"Calculate the sum of all amicable numbers up to a limit.\"\"\"\n amicable_sum = 0\n checked = set() # Keep track of checked numbers to avoid double counting\n\n for num in range(1, limit + 1):\n if num in checked:\n continue\n\n sum1 = sum_of_divisors(num)\n sum2 = sum_of_divisors(sum1)\n\n if num == sum2 and num != sum1: # Amicable pair found\n amicable_sum += num\n if sum1 <= limit:\n amicable_sum += sum1\n checked.add(num)\n checked.add(sum1)\n\n return amicable_sum\nlimit = 2000", "matching_cluster_idx": 11}, {"solution": "def sum_proper_divisors(n):\n \"\"\"Calculates the sum of proper divisors of a number.\"\"\"\n total = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n total += i\n if i * i != n and i != 1: # Avoid adding the number itself and double-counting perfect squares\n total += n // i\n return total\ndef amicable_numbers_sum(limit):\n \"\"\"Calculates the sum of all amicable numbers up to a limit.\"\"\"\n amicable_sum = 0\n checked = set() # Use a set to avoid double-counting amicable pairs\n for num in range(1, limit + 1):\n if num not in checked:\n sum_div_num = sum_proper_divisors(num)\n sum_div_pair = sum_proper_divisors(sum_div_num)\n if num == sum_div_pair and num != sum_div_num: # Check for amicable pair and avoid perfect numbers\n amicable_sum += num + sum_div_num\n checked.add(num)\n checked.add(sum_div_num) # Add both numbers to the checked set\n return amicable_sum", "matching_cluster_idx": 11}, {"solution": "def sum_divisors(n):\n \"\"\"Calculates the sum of proper divisors of a number.\"\"\"\n total = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n total += i\n if i != n // i and i != 1: # Avoid double counting and including the number itself\n total += n // i\n return total\ndef amicable_numbers_sum(limit):\n \"\"\"Calculates the sum of all amicable numbers up to a limit.\"\"\"\n amicable_sum = 0\n checked = set() # Keep track of checked numbers to avoid redundant calculations\n\n for num in range(2, limit + 1):\n if num in checked:\n continue\n\n sum1 = sum_divisors(num)\n sum2 = sum_divisors(sum1)\n\n if num == sum2 and num != sum1: # Amicable numbers and not perfect numbers\n amicable_sum += num\n if sum1 <= limit: # only add sum1 if its within the limit.\n amicable_sum += sum1\n\n checked.add(num)\n checked.add(sum1)\n\n return amicable_sum", "matching_cluster_idx": 11}, {"solution": "def sum_divisors(n):\n \"\"\"Calculates the sum of proper divisors of a number.\"\"\"\n total = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n total += i\n if i * i != n and i != 1: # Avoid double counting and include 1\n total += n // i\n return total\ndef amicable_numbers_sum(limit):\n \"\"\"Calculates the sum of all amicable numbers up to a given limit.\"\"\"\n amicable_sum = 0\n checked = set() # Keep track of already checked pairs\n\n for num1 in range(1, limit + 1):\n if num1 in checked:\n continue\n\n num2 = sum_divisors(num1)\n if num1 != num2 and sum_divisors(num2) == num1:\n if num2 <= limit: # Make sure both numbers are within the limit\n amicable_sum += num1 + num2\n checked.add(num1)\n checked.add(num2)\n elif num1 <= limit: # Handle the case when num2 is greater than the limit\n amicable_sum += num1\n checked.add(num1)\n return amicable_sum", "matching_cluster_idx": 11}, {"solution": "def sum_divisors(n):\n \"\"\"Calculates the sum of proper divisors of a number.\"\"\"\n total = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n total += i\n if i * i != n and i != 1: # Avoid double-counting and exclude the number itself\n total += n // i\n return total\ndef amicable_numbers_sum(limit):\n \"\"\"Calculates the sum of all amicable numbers up to a limit.\"\"\"\n amicable_sum = 0\n for num in range(1, limit + 1):\n sum1 = sum_divisors(num)\n sum2 = sum_divisors(sum1)\n if sum2 == num and sum1 != num: # Check for amicable pair and avoid perfect numbers\n amicable_sum += num\n return amicable_sum", "matching_cluster_idx": 11}, {"solution": "def sum_of_divisors(n):\n \"\"\"Calculates the sum of proper divisors of a number.\"\"\"\n total = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n total += i\n if i * i != n: # Avoid double counting for perfect squares\n total += n // i\n return total - n # Exclude the number itself\ndef amicable_numbers_sum(limit):\n \"\"\"Calculates the sum of all amicable numbers up to a given limit.\"\"\"\n amicable_sum = 0\n checked = set() # Keep track of checked numbers to avoid duplicates\n\n for a in range(1, limit + 1):\n if a not in checked:\n b = sum_of_divisors(a)\n if b != a and sum_of_divisors(b) == a: # Check for amicable pair\n amicable_sum += a\n if b <= limit: # Add b only if within the limit\n amicable_sum += b\n checked.add(a)\n checked.add(b)\n\n return amicable_sum", "matching_cluster_idx": 11}, {"solution": "def sum_of_divisors(n):\n \"\"\"Calculates the sum of proper divisors of a number.\"\"\"\n total = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n total += i\n if i * i != n and i != 1: # Avoid double-counting and include 1 only once.\n total += n // i\n return total\ndef amicable_numbers_sum(limit):\n \"\"\"Calculates the sum of all amicable numbers up to a limit.\"\"\"\n amicable_sum = 0\n checked = set() # Use a set to avoid checking pairs twice\n\n for num in range(1, limit + 1):\n if num not in checked:\n sum1 = sum_of_divisors(num)\n sum2 = sum_of_divisors(sum1)\n\n if sum2 == num and sum1 != num: # Check for amicable pair and avoid perfect numbers\n amicable_sum += num\n if sum1 <= limit: # Only include sum1 if within the limit\n amicable_sum += sum1\n checked.add(num)\n checked.add(sum1)\n\n return amicable_sum", "matching_cluster_idx": 11}, {"solution": "def sum_proper_divisors(n):\n \"\"\"Calculates the sum of proper divisors of a number.\"\"\"\n total = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n total += i\n if i * i != n and i != 1: # Avoid double counting and include 1 only if n is 1\n total += n // i\n return total\ndef amicable_numbers_sum(limit):\n \"\"\"Calculates the sum of all amicable numbers up to a given limit.\"\"\"\n amicable_sum = 0\n for num in range(1, limit + 1):\n sum1 = sum_proper_divisors(num)\n sum2 = sum_proper_divisors(sum1)\n if sum2 == num and sum1 != num: # Check for amicable pair and avoid self-amicable numbers\n amicable_sum += num\n return amicable_sum", "matching_cluster_idx": 11}, {"solution": "def sum_divisors(n):\n \"\"\"Calculate the sum of proper divisors of a number.\"\"\"\n total = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n total += i\n if i * i != n and i != 1: # Avoid double counting and include 1 only if n==1\n total += n // i\n return total\ndef amicable_numbers_sum(limit):\n \"\"\"Calculate the sum of all amicable numbers up to a limit.\"\"\"\n amicable_sum = 0\n checked = set() # Keep track of checked numbers to avoid redundant calculations\n\n for num in range(2, limit + 1): # Start from 2, as 1 is not considered amicable\n if num not in checked:\n sum1 = sum_divisors(num)\n sum2 = sum_divisors(sum1)\n\n if num == sum2 and num != sum1: # Amicable numbers are not equal to themselves\n amicable_sum += num\n if sum1 <= limit: # Only add if within limit\n amicable_sum += sum1\n checked.add(num)\n checked.add(sum1)\n\n return amicable_sum", "matching_cluster_idx": 11}]}, "Mbpp/128": {"dps": 99.5475113122172, "dps_norm": 80.0, "pass@1": 100.0, "profiled": [{"solution": "def long_words(n, str):\n \"\"\"\n Finds words longer than n characters in a given string.\n\n Args:\n n: The minimum length of words to be returned.\n str: The input string containing words separated by spaces.\n\n Returns:\n A list of words longer than n characters.\n \"\"\"\n words = str.split()\n return [word for word in words if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, str1):\n \"\"\"\n Finds words longer than n characters in a string.\n\n Args:\n n: The minimum length of words to be returned.\n str1: The input string containing words.\n\n Returns:\n A list of words longer than n characters.\n \"\"\"\n words = str1.split()\n long_word_list = []\n for word in words:\n if len(word) > n:\n long_word_list.append(word)\n return long_word_list", "matching_cluster_idx": 3}, {"solution": "import doctest\ndef long_words(n, str):\n \"\"\"\n Finds words longer than n characters in a string.\n\n Args:\n n: The minimum length of words to be returned.\n str: The input string containing words.\n\n Returns:\n A list of words longer than n characters.\n\n >>> long_words(3, \"python is a programming language\")\n ['python', 'programming', 'language']\n >>> long_words(4, \"the quick brown fox jumps over the lazy dog\")\n ['quick', 'brown', 'jumps']\n >>> long_words(5, \"hello world\")\n ['hello', 'world']\n >>> long_words(6, \"hello world\")\n []\n >>> long_words(0, \"\")\n []\n \"\"\"\n words = str.split()\n return [word for word in words if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n \"\"\"\n Finds words that are longer than n characters from a given list of words.\n\n Args:\n n: The minimum length of words to be returned.\n sentence: A string containing words separated by spaces.\n\n Returns:\n A list of words longer than n.\n \"\"\"\n words = sentence.split()\n long_word_list = []\n for word in words:\n if len(word) > n:\n long_word_list.append(word)\n return long_word_list\nsentence = \"this is a test sentence with some long and short words\"\nn = 4", "matching_cluster_idx": 3}, {"solution": "def long_words(n, text):\n \"\"\"\n Finds words longer than n characters in a given text.\n\n Args:\n n: The minimum length of words to be returned.\n text: The input text string.\n\n Returns:\n A list of words longer than n characters.\n \"\"\"\n words = text.split()\n long_words_list = [word for word in words if len(word) > n]\n return long_words_list\ntext = \"This is a sample sentence with some words.\"\nn = 4", "matching_cluster_idx": 3}, {"solution": "def long_words(n, str1):\n \"\"\"\n Finds words longer than n characters in a string.\n\n Args:\n n: The minimum length of words to be returned.\n str1: The input string containing words.\n\n Returns:\n A list of words longer than n characters.\n \"\"\"\n word_list = str1.split()\n return [word for word in word_list if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, str):\n \"\"\"\n Finds words longer than n characters in a string.\n\n Args:\n n: The minimum length of words to be returned.\n str: The input string containing words separated by spaces.\n\n Returns:\n A list of words longer than n characters.\n \"\"\"\n words = str.split()\n long_word_list = []\n for word in words:\n if len(word) > n:\n long_word_list.append(word)\n return long_word_list", "matching_cluster_idx": 3}, {"solution": "def long_words(n, str_words):\n \"\"\"\n Finds words longer than n characters in a string.\n\n Args:\n n: The minimum length of words to be returned.\n str_words: The string containing words separated by spaces.\n\n Returns:\n A list of words longer than n.\n \"\"\"\n words = str_words.split()\n return [word for word in words if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, str):\n \"\"\"\n Finds words longer than n characters in a string.\n\n Args:\n n: The minimum length of words to be returned.\n str: The input string containing words separated by spaces.\n\n Returns:\n A list of words longer than n characters.\n \"\"\"\n words = str.split()\n long_word_list = []\n for word in words:\n if len(word) > n:\n long_word_list.append(word)\n return long_word_list\nn = 3", "matching_cluster_idx": 3}, {"solution": "def long_words(n, str1):\n \"\"\"\n Finds words longer than n characters in a given string.\n\n Args:\n n: The minimum length of words to be returned.\n str1: The input string containing words separated by spaces.\n\n Returns:\n A list of words from the input string that are longer than n characters.\n \"\"\"\n word_list = []\n words = str1.split()\n for word in words:\n if len(word) > n:\n word_list.append(word)\n return word_list", "matching_cluster_idx": 3}, {"solution": "def long_words(n, str):\n \"\"\"\n Finds words longer than n characters in a string.\n\n Args:\n n: The minimum length of words to be returned.\n str: The input string containing words.\n\n Returns:\n A list of words longer than n characters.\n \"\"\"\n words = str.split()\n return [word for word in words if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, str1):\n \"\"\"\n Finds words longer than n characters in a given string.\n\n Args:\n n: The minimum length of words to be returned.\n str1: The input string containing words separated by spaces.\n\n Returns:\n A list of words from the input string that are longer than n characters.\n \"\"\"\n word_list = str1.split()\n long_word_list = []\n for word in word_list:\n if len(word) > n:\n long_word_list.append(word)\n return long_word_list", "matching_cluster_idx": 3}, {"solution": "def long_words(n, str1):\n \"\"\"\n Finds words longer than n characters in a given string.\n\n Args:\n n: The minimum length of words to be returned.\n str1: The input string containing words separated by spaces.\n\n Returns:\n A list of words from the input string that are longer than n characters.\n \"\"\"\n word_list = []\n words = str1.split()\n for word in words:\n if len(word) > n:\n word_list.append(word)\n return word_list", "matching_cluster_idx": 3}, {"solution": "import doctest\ndef long_words(n, str1):\n \"\"\"\n Finds words longer than n characters in a string.\n\n Args:\n n: The minimum length of words to be returned.\n str1: The input string containing words separated by spaces.\n\n Returns:\n A list of words from str1 that are longer than n characters.\n\n >>> long_words(3, \"python is a programming language\")\n ['python', 'programming', 'language']\n >>> long_words(4, \"the quick brown fox jumps over the lazy dog\")\n ['quick', 'brown', 'jumps']\n >>> long_words(5, \"hello world test\")\n ['hello', 'world']\n >>> long_words(0, \"\")\n []\n \"\"\"\n word_list = str1.split()\n return [word for word in word_list if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, str1):\n \"\"\"\n Finds words longer than n characters in a given string.\n\n Args:\n n: The minimum length of words to be returned.\n str1: The input string containing words separated by spaces.\n\n Returns:\n A list of words longer than n characters.\n \"\"\"\n words = str1.split()\n long_word_list = []\n for word in words:\n if len(word) > n:\n long_word_list.append(word)\n return long_word_list", "matching_cluster_idx": 3}, {"solution": "def long_words(n, str):\n \"\"\"\n Finds words longer than n characters in a string.\n\n Args:\n n: The minimum length of words to be returned.\n str: The input string containing words separated by spaces.\n\n Returns:\n A list of words longer than n characters.\n \"\"\"\n words = str.split()\n long_word_list = []\n for word in words:\n if len(word) > n:\n long_word_list.append(word)\n return long_word_list", "matching_cluster_idx": 3}, {"solution": "def long_words(n, str):\n \"\"\"\n Finds words longer than n characters in a string.\n\n Args:\n n: The minimum length of words to be returned.\n str: The input string containing words separated by spaces.\n\n Returns:\n A list of words longer than n characters.\n \"\"\"\n words = str.split()\n result = [word for word in words if len(word) > n]\n return result\nn = 4", "matching_cluster_idx": 3}, {"solution": "import doctest\ndef long_words(n, str):\n \"\"\"\n Finds words longer than n characters in a string.\n\n Args:\n n: The minimum length of words to be returned.\n str: The input string containing words separated by spaces.\n\n Returns:\n A list of words longer than n.\n\n >>> long_words(3, \"python is a programming language\")\n ['python', 'programming', 'language']\n >>> long_words(4, \"the quick brown fox jumps over the lazy dog\")\n ['quick', 'brown', 'jumps']\n >>> long_words(5, \"hello world\")\n ['hello', 'world']\n >>> long_words(6, \"short words only\")\n []\n \"\"\"\n words = str.split()\n return [word for word in words if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, str):\n \"\"\"\n Finds words longer than n characters in a string.\n\n Args:\n n: The minimum length of words to be returned.\n str: The input string containing words.\n\n Returns:\n A list of words longer than n characters.\n \"\"\"\n words = str.split()\n return [word for word in words if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "import doctest\ndef long_words(n, str):\n \"\"\"\n Returns a list of words longer than n from a given string.\n\n >>> long_words(3, \"python is a programming language\")\n ['python', 'programming', 'language']\n >>> long_words(4, \"the quick brown fox jumps over the lazy dog\")\n ['quick', 'brown', 'jumps']\n >>> long_words(5, \"one two three four five six\")\n ['three']\n >>> long_words(0, \"\")\n []\n >>> long_words(2, \"a bc def\")\n ['def']\n\n \"\"\"\n words = str.split()\n return [word for word in words if len(word) > n]", "matching_cluster_idx": 3}]}, "Mbpp/129": {"dps": 79.6938775510204, "dps_norm": 97.33333333333333, "pass@1": 100.0, "profiled": [{"solution": "def magic_square_test(matrix):\n \"\"\"\n Checks if a given matrix is a magic square.\n\n A magic square is a square matrix of numbers where the sum of the numbers in each row, each column, and both main diagonals is the same.\n\n Args:\n matrix: A list of lists representing the square matrix.\n\n Returns:\n True if the matrix is a magic square, False otherwise.\n \"\"\"\n n = len(matrix)\n if any(len(row) != n for row in matrix): # Check if it's a square matrix\n return False\n\n magic_sum = sum(matrix[0]) # Calculate the magic sum from the first row\n\n # Check rows\n for row in matrix:\n if sum(row) != magic_sum:\n return False\n\n # Check columns\n for col in range(n):\n col_sum = 0\n for row in range(n):\n col_sum += matrix[row][col]\n if col_sum != magic_sum:\n return False\n\n # Check main diagonal\n diag_sum1 = 0\n for i in range(n):\n diag_sum1 += matrix[i][i]\n if diag_sum1 != magic_sum:\n return False\n\n # Check anti-diagonal\n diag_sum2 = 0\n for i in range(n):\n diag_sum2 += matrix[i][n - 1 - i]\n if diag_sum2 != magic_sum:\n return False\n\n return True", "matching_cluster_idx": 13}, {"solution": "def magic_square_test(matrix):\n \"\"\"\n Checks if a given matrix is a magic square.\n\n Args:\n matrix: A list of lists representing the square matrix.\n\n Returns:\n True if the matrix is a magic square, False otherwise.\n \"\"\"\n n = len(matrix)\n if n == 0:\n return False # Empty matrix is not a magic square\n\n # Check if the matrix is square\n if any(len(row) != n for row in matrix):\n return False\n\n # Calculate the magic sum (from the first row)\n magic_sum = sum(matrix[0])\n\n # Check rows\n for row in matrix:\n if sum(row) != magic_sum:\n return False\n\n # Check columns\n for col in range(n):\n col_sum = sum(matrix[row][col] for row in range(n))\n if col_sum != magic_sum:\n return False\n\n # Check diagonals\n diag1_sum = sum(matrix[i][i] for i in range(n))\n diag2_sum = sum(matrix[i][n - 1 - i] for i in range(n))\n\n if diag1_sum != magic_sum or diag2_sum != magic_sum:\n return False\n\n return True", "matching_cluster_idx": 13}, {"solution": "def magic_square_test(matrix):\n n = len(matrix)\n magic_sum = sum(matrix[0])\n\n # Check rows\n for row in matrix:\n if sum(row) != magic_sum:\n return False\n\n # Check columns\n for col in range(n):\n col_sum = 0\n for row in range(n):\n col_sum += matrix[row][col]\n if col_sum != magic_sum:\n return False\n\n # Check main diagonal\n diag_sum1 = 0\n for i in range(n):\n diag_sum1 += matrix[i][i]\n if diag_sum1 != magic_sum:\n return False\n\n # Check anti-diagonal\n diag_sum2 = 0\n for i in range(n):\n diag_sum2 += matrix[i][n - 1 - i]\n if diag_sum2 != magic_sum:\n return False\n\n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n n = len(matrix)\n magic_sum = sum(matrix[0])\n\n # Check rows\n for row in matrix:\n if sum(row) != magic_sum:\n return False\n\n # Check columns\n for col in range(n):\n col_sum = 0\n for row in range(n):\n col_sum += matrix[row][col]\n if col_sum != magic_sum:\n return False\n\n # Check diagonals\n diag1_sum = 0\n diag2_sum = 0\n for i in range(n):\n diag1_sum += matrix[i][i]\n diag2_sum += matrix[i][n - 1 - i]\n\n if diag1_sum != magic_sum or diag2_sum != magic_sum:\n return False\n\n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n \"\"\"\n Checks if a given matrix is a magic square.\n\n Args:\n matrix: A list of lists representing a square matrix.\n\n Returns:\n True if the matrix is a magic square, False otherwise.\n \"\"\"\n n = len(matrix)\n if any(len(row) != n for row in matrix):\n return False # Not a square matrix\n\n magic_sum = sum(matrix[0])\n\n # Check rows\n for row in matrix:\n if sum(row) != magic_sum:\n return False\n\n # Check columns\n for col in range(n):\n col_sum = 0\n for row in range(n):\n col_sum += matrix[row][col]\n if col_sum != magic_sum:\n return False\n\n # Check main diagonal\n diag_sum1 = 0\n for i in range(n):\n diag_sum1 += matrix[i][i]\n if diag_sum1 != magic_sum:\n return False\n\n # Check anti-diagonal\n diag_sum2 = 0\n for i in range(n):\n diag_sum2 += matrix[i][n - 1 - i]\n if diag_sum2 != magic_sum:\n return False\n\n return True", "matching_cluster_idx": 13}, {"solution": "def magic_square_test(matrix):\n \"\"\"\n Checks if a given matrix is a magic square.\n\n Args:\n matrix: A list of lists representing a square matrix.\n\n Returns:\n True if the matrix is a magic square, False otherwise.\n \"\"\"\n n = len(matrix)\n if n == 0:\n return False\n\n # Calculate the magic sum from the first row\n magic_sum = sum(matrix[0])\n\n # Check rows\n for row in matrix:\n if sum(row) != magic_sum:\n return False\n\n # Check columns\n for col in range(n):\n col_sum = 0\n for row in range(n):\n col_sum += matrix[row][col]\n if col_sum != magic_sum:\n return False\n\n # Check main diagonal\n diag_sum1 = 0\n for i in range(n):\n diag_sum1 += matrix[i][i]\n if diag_sum1 != magic_sum:\n return False\n\n # Check anti-diagonal\n diag_sum2 = 0\n for i in range(n):\n diag_sum2 += matrix[i][n - 1 - i]\n if diag_sum2 != magic_sum:\n return False\n\n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n \"\"\"\n Checks if a given matrix is a magic square.\n\n Args:\n matrix: A list of lists representing a square matrix.\n\n Returns:\n True if the matrix is a magic square, False otherwise.\n \"\"\"\n n = len(matrix)\n if n == 0:\n return False # Empty matrix is not a magic square\n\n # Check if the matrix is square\n for row in matrix:\n if len(row) != n:\n return False\n\n # Calculate the magic sum (sum of the first row)\n magic_sum = sum(matrix[0])\n\n # Check rows\n for row in matrix:\n if sum(row) != magic_sum:\n return False\n\n # Check columns\n for col in range(n):\n col_sum = 0\n for row in range(n):\n col_sum += matrix[row][col]\n if col_sum != magic_sum:\n return False\n\n # Check main diagonal\n diag_sum1 = 0\n for i in range(n):\n diag_sum1 += matrix[i][i]\n if diag_sum1 != magic_sum:\n return False\n\n # Check secondary diagonal\n diag_sum2 = 0\n for i in range(n):\n diag_sum2 += matrix[i][n - 1 - i]\n if diag_sum2 != magic_sum:\n return False\n\n return True", "matching_cluster_idx": 13}, {"solution": "def magic_square_test(matrix):\n \"\"\"\n Checks if a given matrix is a magic square.\n\n Args:\n matrix: A list of lists representing a square matrix.\n\n Returns:\n True if the matrix is a magic square, False otherwise.\n \"\"\"\n n = len(matrix)\n if n == 0:\n return False # Empty matrix is not a magic square\n\n # Calculate the magic sum from the first row\n magic_sum = sum(matrix[0])\n\n # Check rows\n for row in matrix:\n if sum(row) != magic_sum:\n return False\n\n # Check columns\n for col in range(n):\n col_sum = 0\n for row in range(n):\n col_sum += matrix[row][col]\n if col_sum != magic_sum:\n return False\n\n # Check main diagonal\n diag_sum1 = 0\n for i in range(n):\n diag_sum1 += matrix[i][i]\n if diag_sum1 != magic_sum:\n return False\n\n # Check anti-diagonal\n diag_sum2 = 0\n for i in range(n):\n diag_sum2 += matrix[i][n - 1 - i]\n if diag_sum2 != magic_sum:\n return False\n\n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n \"\"\"\n Checks if a given matrix is a magic square.\n\n Args:\n matrix: A list of lists representing the square matrix.\n\n Returns:\n True if the matrix is a magic square, False otherwise.\n \"\"\"\n n = len(matrix)\n if n == 0:\n return False # Empty matrix is not a magic square\n for row in matrix:\n if len(row) != n:\n return False # Not a square matrix\n\n magic_sum = sum(matrix[0])\n\n # Check rows\n for row in matrix:\n if sum(row) != magic_sum:\n return False\n\n # Check columns\n for col in range(n):\n col_sum = 0\n for row in range(n):\n col_sum += matrix[row][col]\n if col_sum != magic_sum:\n return False\n\n # Check diagonals\n diag1_sum = 0\n diag2_sum = 0\n for i in range(n):\n diag1_sum += matrix[i][i]\n diag2_sum += matrix[i][n - 1 - i]\n\n if diag1_sum != magic_sum or diag2_sum != magic_sum:\n return False\n\n return True", "matching_cluster_idx": 13}, {"solution": "def magic_square_test(matrix):\n \"\"\"\n Checks if a given matrix is a magic square.\n\n Args:\n matrix: A list of lists representing the square matrix.\n\n Returns:\n True if the matrix is a magic square, False otherwise.\n \"\"\"\n n = len(matrix)\n if n == 0:\n return False # Empty matrix is not a magic square\n\n # Calculate the magic sum from the first row\n magic_sum = sum(matrix[0])\n\n # Check rows\n for row in matrix:\n if sum(row) != magic_sum:\n return False\n\n # Check columns\n for col in range(n):\n col_sum = 0\n for row in range(n):\n col_sum += matrix[row][col]\n if col_sum != magic_sum:\n return False\n\n # Check diagonals\n diag1_sum = 0\n diag2_sum = 0\n for i in range(n):\n diag1_sum += matrix[i][i]\n diag2_sum += matrix[i][n - 1 - i]\n\n if diag1_sum != magic_sum or diag2_sum != magic_sum:\n return False\n\n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n \"\"\"\n Checks if a given matrix is a magic square.\n\n Args:\n matrix: A list of lists representing the square matrix.\n\n Returns:\n True if the matrix is a magic square, False otherwise.\n \"\"\"\n n = len(matrix)\n if any(len(row) != n for row in matrix):\n return False # Not a square matrix\n\n magic_sum = sum(matrix[0])\n\n # Check rows\n for row in matrix:\n if sum(row) != magic_sum:\n return False\n\n # Check columns\n for j in range(n):\n col_sum = 0\n for i in range(n):\n col_sum += matrix[i][j]\n if col_sum != magic_sum:\n return False\n\n # Check main diagonal\n diag_sum1 = 0\n for i in range(n):\n diag_sum1 += matrix[i][i]\n if diag_sum1 != magic_sum:\n return False\n\n # Check anti-diagonal\n diag_sum2 = 0\n for i in range(n):\n diag_sum2 += matrix[i][n - 1 - i]\n if diag_sum2 != magic_sum:\n return False\n\n return True", "matching_cluster_idx": 13}, {"solution": "def magic_square_test(matrix):\n \"\"\"\n Checks if a given matrix is a magic square.\n\n Args:\n matrix: A list of lists representing the matrix.\n\n Returns:\n True if the matrix is a magic square, False otherwise.\n \"\"\"\n n = len(matrix)\n if n == 0:\n return False # Empty matrix is not a magic square\n\n magic_sum = sum(matrix[0]) # Calculate the sum of the first row\n\n # Check rows\n for row in matrix:\n if sum(row) != magic_sum:\n return False\n\n # Check columns\n for col in range(n):\n col_sum = 0\n for row in range(n):\n col_sum += matrix[row][col]\n if col_sum != magic_sum:\n return False\n\n # Check main diagonal\n diag_sum1 = 0\n for i in range(n):\n diag_sum1 += matrix[i][i]\n if diag_sum1 != magic_sum:\n return False\n\n # Check secondary diagonal\n diag_sum2 = 0\n for i in range(n):\n diag_sum2 += matrix[i][n - 1 - i]\n if diag_sum2 != magic_sum:\n return False\n\n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n \"\"\"\n Checks if a given matrix is a magic square.\n\n Args:\n matrix: A list of lists representing the square matrix.\n\n Returns:\n True if the matrix is a magic square, False otherwise.\n \"\"\"\n n = len(matrix)\n if n == 0:\n return False # Empty matrix is not a magic square\n\n # Calculate the magic constant (sum of first row)\n magic_constant = sum(matrix[0])\n\n # Check rows\n for row in matrix:\n if sum(row) != magic_constant:\n return False\n\n # Check columns\n for j in range(n):\n col_sum = 0\n for i in range(n):\n col_sum += matrix[i][j]\n if col_sum != magic_constant:\n return False\n\n # Check diagonals\n diag1_sum = 0\n diag2_sum = 0\n for i in range(n):\n diag1_sum += matrix[i][i]\n diag2_sum += matrix[i][n - 1 - i]\n\n if diag1_sum != magic_constant or diag2_sum != magic_constant:\n return False\n\n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n \"\"\"\n Checks if a given matrix is a magic square.\n\n A magic square is a square matrix where the sum of each row, each column, and both main diagonals are equal.\n\n Args:\n matrix: A list of lists representing a square matrix.\n\n Returns:\n True if the matrix is a magic square, False otherwise.\n \"\"\"\n n = len(matrix)\n if n == 0:\n return False # Empty matrix is not a magic square\n\n for row in matrix:\n if len(row) != n:\n return False # Not a square matrix\n\n magic_sum = sum(matrix[0])\n\n # Check rows\n for row in matrix:\n if sum(row) != magic_sum:\n return False\n\n # Check columns\n for j in range(n):\n col_sum = 0\n for i in range(n):\n col_sum += matrix[i][j]\n if col_sum != magic_sum:\n return False\n\n # Check main diagonal\n diag_sum1 = 0\n for i in range(n):\n diag_sum1 += matrix[i][i]\n if diag_sum1 != magic_sum:\n return False\n\n # Check anti-diagonal\n diag_sum2 = 0\n for i in range(n):\n diag_sum2 += matrix[i][n - 1 - i]\n if diag_sum2 != magic_sum:\n return False\n\n return True", "matching_cluster_idx": 13}, {"solution": "def magic_square_test(matrix):\n \"\"\"\n Checks if a given matrix is a magic square.\n\n Args:\n matrix: A list of lists representing a square matrix.\n\n Returns:\n True if the matrix is a magic square, False otherwise.\n \"\"\"\n n = len(matrix)\n if n == 0:\n return False # Empty matrix is not a magic square\n\n # Calculate the magic sum from the first row\n magic_sum = sum(matrix[0])\n\n # Check rows\n for row in matrix:\n if sum(row) != magic_sum:\n return False\n\n # Check columns\n for col in range(n):\n col_sum = 0\n for row in range(n):\n col_sum += matrix[row][col]\n if col_sum != magic_sum:\n return False\n\n # Check main diagonal\n diag_sum1 = 0\n for i in range(n):\n diag_sum1 += matrix[i][i]\n if diag_sum1 != magic_sum:\n return False\n\n # Check anti-diagonal\n diag_sum2 = 0\n for i in range(n):\n diag_sum2 += matrix[i][n - 1 - i]\n if diag_sum2 != magic_sum:\n return False\n\n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n \"\"\"\n Checks if a given matrix is a magic square.\n\n Args:\n matrix: A list of lists representing a square matrix.\n\n Returns:\n True if the matrix is a magic square, False otherwise.\n \"\"\"\n n = len(matrix)\n if n == 0:\n return False\n\n # Calculate the magic sum from the first row\n magic_sum = sum(matrix[0])\n\n # Check rows\n for row in matrix:\n if sum(row) != magic_sum:\n return False\n\n # Check columns\n for col in range(n):\n col_sum = 0\n for row in range(n):\n col_sum += matrix[row][col]\n if col_sum != magic_sum:\n return False\n\n # Check main diagonal\n diag_sum1 = 0\n for i in range(n):\n diag_sum1 += matrix[i][i]\n if diag_sum1 != magic_sum:\n return False\n\n # Check anti-diagonal\n diag_sum2 = 0\n for i in range(n):\n diag_sum2 += matrix[i][n - 1 - i]\n if diag_sum2 != magic_sum:\n return False\n\n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n \"\"\"\n Checks if a given matrix is a magic square.\n\n Args:\n matrix: A list of lists representing a square matrix.\n\n Returns:\n True if the matrix is a magic square, False otherwise.\n \"\"\"\n n = len(matrix)\n if n == 0:\n return False # Empty matrix is not a magic square\n\n magic_sum = sum(matrix[0])\n\n # Check rows\n for row in matrix:\n if sum(row) != magic_sum:\n return False\n\n # Check columns\n for col in range(n):\n col_sum = 0\n for row in range(n):\n col_sum += matrix[row][col]\n if col_sum != magic_sum:\n return False\n\n # Check main diagonal\n diag_sum1 = 0\n for i in range(n):\n diag_sum1 += matrix[i][i]\n if diag_sum1 != magic_sum:\n return False\n\n # Check anti-diagonal\n diag_sum2 = 0\n for i in range(n):\n diag_sum2 += matrix[i][n - 1 - i]\n if diag_sum2 != magic_sum:\n return False\n\n\n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n \"\"\"\n Checks if a given matrix is a magic square.\n\n Args:\n matrix: A list of lists representing the square matrix.\n\n Returns:\n True if the matrix is a magic square, False otherwise.\n \"\"\"\n n = len(matrix)\n if n == 0:\n return False # Empty matrix is not a magic square\n\n # Check if the matrix is square\n for row in matrix:\n if len(row) != n:\n return False\n\n # Calculate the magic sum (sum of the first row)\n magic_sum = sum(matrix[0])\n\n # Check rows\n for row in matrix:\n if sum(row) != magic_sum:\n return False\n\n # Check columns\n for col in range(n):\n col_sum = 0\n for row in range(n):\n col_sum += matrix[row][col]\n if col_sum != magic_sum:\n return False\n\n # Check main diagonal\n diag_sum1 = 0\n for i in range(n):\n diag_sum1 += matrix[i][i]\n if diag_sum1 != magic_sum:\n return False\n\n # Check secondary diagonal\n diag_sum2 = 0\n for i in range(n):\n diag_sum2 += matrix[i][n - 1 - i]\n if diag_sum2 != magic_sum:\n return False\n\n return True", "matching_cluster_idx": 13}, {"solution": "def magic_square_test(matrix):\n \"\"\"\n Checks if a given matrix is a magic square.\n\n Args:\n matrix: A list of lists representing a square matrix.\n\n Returns:\n True if the matrix is a magic square, False otherwise.\n \"\"\"\n n = len(matrix)\n if n == 0:\n return False # Empty matrix is not a magic square\n\n magic_sum = sum(matrix[0])\n\n # Check rows\n for row in matrix:\n if sum(row) != magic_sum:\n return False\n\n # Check columns\n for col in range(n):\n col_sum = 0\n for row in range(n):\n col_sum += matrix[row][col]\n if col_sum != magic_sum:\n return False\n\n # Check main diagonal\n diag_sum1 = 0\n for i in range(n):\n diag_sum1 += matrix[i][i]\n if diag_sum1 != magic_sum:\n return False\n\n # Check secondary diagonal\n diag_sum2 = 0\n for i in range(n):\n diag_sum2 += matrix[i][n - 1 - i]\n if diag_sum2 != magic_sum:\n return False\n\n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n \"\"\"\n Checks if a given matrix is a magic square.\n\n Args:\n matrix: A list of lists representing a square matrix.\n\n Returns:\n True if the matrix is a magic square, False otherwise.\n \"\"\"\n n = len(matrix)\n if n == 0:\n return False # Empty matrix is not a magic square\n\n # Calculate the magic sum from the first row\n magic_sum = sum(matrix[0])\n\n # Check rows\n for row in matrix:\n if sum(row) != magic_sum:\n return False\n\n # Check columns\n for col in range(n):\n col_sum = 0\n for row in range(n):\n col_sum += matrix[row][col]\n if col_sum != magic_sum:\n return False\n\n # Check main diagonal\n diag_sum1 = 0\n for i in range(n):\n diag_sum1 += matrix[i][i]\n if diag_sum1 != magic_sum:\n return False\n\n # Check anti-diagonal\n diag_sum2 = 0\n for i in range(n):\n diag_sum2 += matrix[i][n - 1 - i]\n if diag_sum2 != magic_sum:\n return False\n\n return True", "matching_cluster_idx": 14}]}, "Mbpp/130": {"dps": 99.10313901345292, "dps_norm": 83.33333333333333, "pass@1": 99.0, "profiled": [{"solution": "from collections import Counter\ndef max_occurrences(items):\n \"\"\"\n Finds the item with the maximum frequency in a list.\n\n Args:\n items: A list of items.\n\n Returns:\n The item with the maximum frequency.\n \"\"\"\n if not items:\n return None # Handle empty list case\n\n counts = Counter(items)\n max_count = 0\n max_item = None\n\n for item, count in counts.items():\n if count > max_count:\n max_count = count\n max_item = item\n\n return max_item", "matching_cluster_idx": 4}, {"solution": "from collections import Counter\ndef max_occurrences(data):\n \"\"\"\n Finds the item with the maximum frequency in a list.\n\n Args:\n data: A list of items.\n\n Returns:\n The item with the maximum frequency.\n \"\"\"\n if not data:\n return None # Handle empty list case\n\n counts = Counter(data)\n max_item = None\n max_count = 0\n\n for item, count in counts.items():\n if count > max_count:\n max_count = count\n max_item = item\n\n return max_item", "matching_cluster_idx": 4}, {"solution": "from collections import Counter\ndef max_occurrences(items):\n \"\"\"\n Finds the item with the maximum frequency in a list.\n\n Args:\n items: A list of items.\n\n Returns:\n The item with the maximum frequency.\n \"\"\"\n if not items:\n return None # Handle empty list case\n\n counts = Counter(items)\n max_count = 0\n max_item = None\n\n for item, count in counts.items():\n if count > max_count:\n max_count = count\n max_item = item\n return max_item", "matching_cluster_idx": 4}, {"solution": "from collections import Counter\ndef max_occurrences(data):\n \"\"\"Finds the item with maximum frequency in a list.\n\n Args:\n data: A list of items.\n\n Returns:\n The item with the maximum frequency.\n \"\"\"\n if not data:\n return None # Handle empty list case\n\n counts = Counter(data)\n max_item = None\n max_count = 0\n\n for item, count in counts.items():\n if count > max_count:\n max_count = count\n max_item = item\n\n return max_item", "matching_cluster_idx": 4}, {"solution": "from collections import Counter\ndef max_occurrences(data):\n \"\"\"Finds the item with the maximum frequency in a list.\n\n Args:\n data: A list of items.\n\n Returns:\n The item with the maximum frequency.\n \"\"\"\n if not data:\n return None # Handle empty list case\n\n counts = Counter(data)\n max_count = 0\n max_item = None\n\n for item, count in counts.items():\n if count > max_count:\n max_count = count\n max_item = item\n \n return max_item", "matching_cluster_idx": 4}, {"solution": "from collections import Counter\ndef max_occurrences(data):\n \"\"\"Finds the item with maximum frequency in a given list.\n\n Args:\n data: A list of items.\n\n Returns:\n The item with the maximum frequency. If there are multiple items\n with the same maximum frequency, the function returns the first \n one encountered.\n \"\"\"\n if not data:\n return None\n\n counts = Counter(data)\n max_count = 0\n max_item = None\n\n for item, count in counts.items():\n if count > max_count:\n max_count = count\n max_item = item\n\n return max_item", "matching_cluster_idx": 4}, {"solution": "from collections import Counter\ndef max_occurrences(items):\n \"\"\"\n Finds the item with the maximum frequency in a given list.\n\n Args:\n items: A list of items.\n\n Returns:\n The item with the maximum frequency.\n \"\"\"\n if not items:\n return None # Handle empty list\n\n counts = Counter(items)\n max_count = 0\n max_item = None\n\n for item, count in counts.items():\n if count > max_count:\n max_count = count\n max_item = item\n \n return max_item", "matching_cluster_idx": 4}, {"solution": "from collections import Counter\ndef max_occurrences(data):\n \"\"\"\n Finds the item with the maximum frequency in a list.\n\n Args:\n data: A list of items.\n\n Returns:\n The item with the maximum frequency.\n \"\"\"\n if not data:\n return None # Handle empty list case\n\n counts = Counter(data)\n max_count = 0\n max_item = None\n\n for item, count in counts.items():\n if count > max_count:\n max_count = count\n max_item = item\n\n return max_item", "matching_cluster_idx": 4}, {"solution": "from collections import Counter\ndef max_occurrences(data):\n \"\"\"\n Finds the item with the maximum frequency in a list.\n\n Args:\n data: A list of items.\n\n Returns:\n The item with the maximum frequency.\n \"\"\"\n if not data:\n return None # Handle empty list case\n\n counts = Counter(data)\n max_count = 0\n max_item = None\n\n for item, count in counts.items():\n if count > max_count:\n max_count = count\n max_item = item\n\n return max_item", "matching_cluster_idx": 4}, {"solution": "from collections import Counter\ndef max_occurrences(data):\n \"\"\"\n Finds the item with the maximum frequency in a list.\n\n Args:\n data: A list of items.\n\n Returns:\n The item with the maximum frequency.\n \"\"\"\n if not data:\n return None # Handle empty list case\n\n counts = Counter(data)\n max_count = 0\n max_item = None\n\n for item, count in counts.items():\n if count > max_count:\n max_count = count\n max_item = item\n return max_item", "matching_cluster_idx": 4}, {"solution": "from collections import Counter\ndef max_occurrences(data):\n \"\"\"\n Finds the item with the maximum frequency in a list.\n\n Args:\n data: A list of items.\n\n Returns:\n The item with the maximum frequency.\n \"\"\"\n if not data:\n return None # Handle empty list case\n\n counts = Counter(data)\n max_count = 0\n max_item = None\n\n for item, count in counts.items():\n if count > max_count:\n max_count = count\n max_item = item\n\n return max_item", "matching_cluster_idx": 4}, {"solution": "from collections import Counter\ndef max_occurrences(data):\n \"\"\"\n Finds the item with the maximum frequency in a list.\n\n Args:\n data: A list of items.\n\n Returns:\n The item with the maximum frequency.\n \"\"\"\n if not data:\n return None # Handle empty list case\n\n counts = Counter(data)\n max_item = None\n max_count = 0\n\n for item, count in counts.items():\n if count > max_count:\n max_count = count\n max_item = item\n return max_item", "matching_cluster_idx": 4}, {"solution": "from collections import Counter\ndef max_occurrences(data):\n \"\"\"\n Finds the item with the maximum frequency in a list.\n\n Args:\n data: A list of items.\n\n Returns:\n The item with the maximum frequency.\n \"\"\"\n if not data:\n return None # Handle empty list case\n\n counts = Counter(data)\n max_count = 0\n max_item = None\n\n for item, count in counts.items():\n if count > max_count:\n max_count = count\n max_item = item\n\n return max_item", "matching_cluster_idx": 4}, {"solution": "from collections import Counter\ndef max_occurrences(data):\n \"\"\"\n Finds the item with the maximum frequency in a list.\n\n Args:\n data: A list of items.\n\n Returns:\n The item with the maximum frequency.\n \"\"\"\n if not data:\n return None # Handle empty list case\n\n counts = Counter(data)\n max_count = 0\n max_item = None\n\n for item, count in counts.items():\n if count > max_count:\n max_count = count\n max_item = item\n \n return max_item", "matching_cluster_idx": 4}, {"solution": "from collections import Counter\ndef max_occurrences(data):\n \"\"\"Finds the item with the maximum frequency in a list.\n\n Args:\n data: A list of items.\n\n Returns:\n The item with the maximum frequency.\n \"\"\"\n\n if not data:\n return None # Handle empty list case\n\n counts = Counter(data)\n max_item = None\n max_count = 0\n\n for item, count in counts.items():\n if count > max_count:\n max_count = count\n max_item = item\n\n return max_item", "matching_cluster_idx": 4}, {"solution": "from collections import Counter\ndef max_occurrences(items):\n \"\"\"\n Finds the item with the maximum frequency in a list.\n\n Args:\n items: A list of items.\n\n Returns:\n The item with the maximum frequency.\n \"\"\"\n if not items:\n return None # Handle empty list case\n\n counts = Counter(items)\n max_count = 0\n max_item = None\n\n for item, count in counts.items():\n if count > max_count:\n max_count = count\n max_item = item\n return max_item", "matching_cluster_idx": 4}, {"solution": "from collections import Counter\ndef max_occurrences(input_list):\n \"\"\"\n Finds the item with the maximum frequency in a list.\n\n Args:\n input_list: A list of items.\n\n Returns:\n The item with the maximum frequency.\n \"\"\"\n if not input_list:\n return None # Handle empty list case\n\n count = Counter(input_list)\n max_freq_item = None\n max_freq = 0\n\n for item, freq in count.items():\n if freq > max_freq:\n max_freq = freq\n max_freq_item = item\n return max_freq_item", "matching_cluster_idx": 4}, {"solution": "from collections import Counter\ndef max_occurrences(data):\n \"\"\"\n Finds the item with the maximum frequency in a list.\n\n Args:\n data: A list of items.\n\n Returns:\n The item with the maximum frequency.\n \"\"\"\n if not data:\n return None # Handle empty list case\n\n counts = Counter(data)\n max_count = 0\n max_item = None\n\n for item, count in counts.items():\n if count > max_count:\n max_count = count\n max_item = item\n return max_item", "matching_cluster_idx": 4}, {"solution": "from collections import Counter\ndef max_occurrences(input_list):\n \"\"\"\n Finds the item with the maximum frequency in a list.\n\n Args:\n input_list: A list of items.\n\n Returns:\n The item with the maximum frequency.\n \"\"\"\n if not input_list:\n return None # Handle empty list case\n\n count = Counter(input_list)\n max_count = 0\n max_item = None\n\n for item, freq in count.items():\n if freq > max_count:\n max_count = freq\n max_item = item\n\n return max_item", "matching_cluster_idx": 4}, {"solution": "from collections import Counter\ndef max_occurrences(items):\n \"\"\"\n Finds the item with the maximum frequency in a list.\n\n Args:\n items: A list of items.\n\n Returns:\n The item with the maximum frequency.\n \"\"\"\n if not items:\n return None # Handle empty list case\n\n counts = Counter(items)\n max_count = 0\n max_item = None\n\n for item, count in counts.items():\n if count > max_count:\n max_count = count\n max_item = item\n return max_item", "matching_cluster_idx": 4}]}, "Mbpp/137": {"dps": 43.44086021505375, "dps_norm": 56.666666666666664, "pass@1": 15.0, "profiled": [{"solution": "import math\ndef zero_count(arr):\n \"\"\"\n Calculates the ratio of zeroes to non-zeroes in an array of integers.\n\n Args:\n arr: A list of integers.\n\n Returns:\n The ratio of zeroes to non-zeroes as a float. Returns 0.0 if the array is empty \n or contains only zeroes. Returns float('inf') if the array contains no zeroes.\n \"\"\"\n zeroes = 0\n non_zeroes = 0\n\n if not arr:\n return 0.0 # Handle empty array\n\n for num in arr:\n if num == 0:\n zeroes += 1\n else:\n non_zeroes += 1\n\n if non_zeroes == 0 and zeroes > 0:\n return float('inf') # Handle case where there are only zeroes\n elif non_zeroes == 0 and zeroes == 0:\n return 0.0 # Handle empty list case consistently\n elif zeroes == 0:\n return 0.0 # Handle case where there are no zeroes\n else:\n return zeroes / non_zeroes", "matching_cluster_idx": 3}, {"solution": "import math\ndef zero_count(arr):\n \"\"\"\n Calculates the ratio of zeroes to non-zeroes in an array of integers.\n\n Args:\n arr: A list of integers.\n\n Returns:\n The ratio of zeroes to non-zeroes as a float. \n Returns 0.0 if the array is empty or contains only zeroes.\n Returns float('inf') if the array contains no zeroes.\n\n\n \"\"\"\n zeroes = 0\n non_zeroes = 0\n\n for num in arr:\n if num == 0:\n zeroes += 1\n else:\n non_zeroes += 1\n\n if len(arr) == 0 or non_zeroes == 0:\n if zeroes == 0:\n return 0.0 # Handles empty or all-zero case to avoid ZeroDivisionError\n else:\n return float('inf') # Return infinity if there are no non-zero elements\n else:\n return zeroes / non_zeroes", "matching_cluster_idx": 3}, {"solution": "import math\ndef zero_count(arr):\n \"\"\"\n Calculates the ratio of zeroes to non-zeroes in an array of integers.\n\n Args:\n arr: A list of integers.\n\n Returns:\n The ratio of zeroes to non-zeroes, or 0 if the array is empty or contains only zeroes.\n Returns float('inf') if there are no non-zero elements but there are zero elements.\n \"\"\"\n zeroes = 0\n non_zeroes = 0\n\n if not arr:\n return 0\n\n for num in arr:\n if num == 0:\n zeroes += 1\n else:\n non_zeroes += 1\n\n if non_zeroes == 0:\n if zeroes > 0:\n return float('inf')\n else:\n return 0 # Empty array case\n\n return zeroes / non_zeroes", "matching_cluster_idx": 3}, {"solution": "import math\ndef zero_count(arr):\n \"\"\"\n Calculates the ratio of zeroes to non-zeroes in an array of integers.\n\n Args:\n arr: A list of integers.\n\n Returns:\n The ratio of zeroes to non-zeroes, or 0 if the array is empty or contains only zeroes.\n Returns float('inf') if the array contains no zeros but other elements.\n\n Raises:\n TypeError: If input is not a list or if any element in the list is not an integer.\n \"\"\"\n\n if not isinstance(arr, list):\n raise TypeError(\"Input must be a list.\")\n for num in arr:\n if not isinstance(num, int):\n raise TypeError(\"All elements in the list must be integers.\")\n\n zeroes = arr.count(0)\n non_zeroes = len(arr) - zeroes\n\n if len(arr) == 0 or non_zeroes == 0:\n if zeroes > 0:\n return float('inf') # All elements are zero, so technically infinite ratio\n else: # List is empty\n return 0\n else:\n return zeroes / non_zeroes", "matching_cluster_idx": 1}, {"solution": "import math\ndef zero_count(arr):\n \"\"\"\n Calculates the ratio of zeroes to non-zeroes in an array of integers.\n\n Args:\n arr: A list of integers.\n\n Returns:\n The ratio of zeroes to non-zeroes as a float, or 0.0 if the array is empty or contains only zeroes.\n Returns math.inf if the array contains no zeroes but other elements.\n \"\"\"\n zeroes = 0\n non_zeroes = 0\n for num in arr:\n if num == 0:\n zeroes += 1\n else:\n non_zeroes += 1\n\n if not arr:\n return 0.0 # Handle empty array\n elif non_zeroes == 0:\n if zeroes == 0:\n return 0.0 # Handle array with only zeroes (avoid division by zero)\n else:\n return math.inf # Handle array with only zeros\n else:\n if zeroes == 0:\n return 0.0\n else:\n return zeroes / non_zeroes", "matching_cluster_idx": 3}, {"solution": "import math\ndef zero_count(arr):\n \"\"\"\n Calculates the ratio of zeroes to non-zeroes in an array of integers.\n\n Args:\n arr: A list of integers.\n\n Returns:\n The ratio of zeroes to non-zeroes, or 0 if the array is empty or contains only zeroes.\n Returns float('inf') if there are no non-zero elements.\n\n Raises:\n TypeError: If input is not a list or any element in the list is not an integer.\n \"\"\"\n if not isinstance(arr, list):\n raise TypeError(\"Input must be a list.\")\n for element in arr:\n if not isinstance(element, int):\n raise TypeError(\"Elements in the list must be integers.\")\n\n zero_c = arr.count(0)\n non_zero_c = len(arr) - zero_c\n\n if len(arr) == 0:\n return 0\n elif non_zero_c == 0:\n return float('inf') # Handle case where there are no non-zero elements\n else:\n return zero_c / non_zero_c", "matching_cluster_idx": 1}, {"solution": "import math\ndef zero_count(arr):\n \"\"\"\n Calculates the ratio of zeros to non-zeros in an integer array.\n\n Args:\n arr: A list of integers.\n\n Returns:\n The ratio of zeros to non-zeros as a float. Returns 0.0 if the array is empty \n or contains only zeros. Returns math.inf if the array contains no zeros.\n\n \"\"\"\n zeroes = 0\n non_zeroes = 0\n\n if not arr:\n return 0.0\n\n for num in arr:\n if num == 0:\n zeroes += 1\n else:\n non_zeroes += 1\n \n if non_zeroes == 0:\n if zeroes == 0:\n return 0.0\n else:\n return math.inf\n else:\n return zeroes / non_zeroes", "matching_cluster_idx": 3}, {"solution": "import math\ndef zero_count(arr):\n \"\"\"\n Calculates the ratio of zeroes to non-zeroes in an array of integers.\n\n Args:\n arr: A list of integers.\n\n Returns:\n The ratio of zeroes to non-zeroes as a float. \n Returns 0.0 if the array is empty or contains only zeroes.\n Returns float('inf') if the array contains no zeroes.\n \"\"\"\n zeroes = 0\n non_zeroes = 0\n\n for num in arr:\n if num == 0:\n zeroes += 1\n else:\n non_zeroes += 1\n \n if len(arr) == 0 or non_zeroes == 0:\n if zeroes > 0:\n return float('inf') # Technically correct, but might be better to handle differently depending on use case\n else:\n return 0.0 # Handles empty list\n else:\n return zeroes / non_zeroes", "matching_cluster_idx": 3}, {"solution": "import math\ndef zero_count(arr):\n \"\"\"\n Calculates the ratio of zeros to non-zeros in an integer array.\n\n Args:\n arr: An array (list) of integers.\n\n Returns:\n The ratio of zeros to non-zeros, or 0 if the array is empty.\n Returns float('inf') if the array contains no non-zero elements.\n \"\"\"\n if not arr:\n return 0\n \n zeroes = arr.count(0)\n non_zeroes = len(arr) - zeroes\n\n if non_zeroes == 0:\n return float('inf') # Handle the case where there are no non-zero elements.\n else:\n return zeroes / non_zeroes", "matching_cluster_idx": 6}, {"solution": "import math\ndef zero_count(arr):\n \"\"\"\n Calculates the ratio of zeroes to non-zeroes in an array of integers.\n\n Args:\n arr: A list of integers.\n\n Returns:\n The ratio of zeroes to non-zeroes as a float. \n Returns 0.0 if the array is empty or contains only zeroes.\n Returns float('inf') if the array contains no zeroes.\n \"\"\"\n zeroes = 0\n non_zeroes = 0\n\n for num in arr:\n if num == 0:\n zeroes += 1\n else:\n non_zeroes += 1\n\n if len(arr) == 0 or non_zeroes == 0:\n if zeroes > 0:\n return float('inf') # Infinite ratio if all elements are zeroes but the array is not empty\n else:\n return 0.0\n\n return zeroes / non_zeroes", "matching_cluster_idx": 3}, {"solution": "import math\ndef zero_count(arr):\n \"\"\"\n Calculates the ratio of zeroes to non-zeroes in an array of integers.\n\n Args:\n arr: A list of integers.\n\n Returns:\n The ratio of zeroes to non-zeroes as a float, or 0.0 if the array is empty or contains only zeroes.\n Returns math.inf if the array contains no zeroes.\n \"\"\"\n if not arr:\n return 0.0\n\n zeroes = arr.count(0)\n non_zeroes = len(arr) - zeroes\n\n if non_zeroes == 0:\n if zeroes == 0:\n return 0.0\n else:\n return math.inf # or raise ZeroDivisionError, depending on desired behavior\n\n return zeroes / non_zeroes", "matching_cluster_idx": 6}, {"solution": "import math\ndef zero_count(arr):\n \"\"\"\n Calculates the ratio of zeros to non-zeros in an array of integers.\n\n Args:\n arr: A list of integers.\n\n Returns:\n The ratio of zeros to non-zeros, or 0 if the array is empty or contains only zeros.\n Returns math.inf if there are no non-zero elements.\n \"\"\"\n if not arr:\n return 0\n\n zeroes = arr.count(0)\n non_zeroes = len(arr) - zeroes\n\n if non_zeroes == 0:\n if zeroes == 0:\n return 0\n else:\n return math.inf\n else:\n return zeroes / non_zeroes", "matching_cluster_idx": 6}, {"solution": "import math\ndef zero_count(arr):\n \"\"\"\n Calculates the ratio of zeroes to non-zeroes in an array of integers.\n\n Args:\n arr: A list of integers.\n\n Returns:\n The ratio of zeroes to non-zeroes as a float. Returns 0 if the array is empty or contains only zeros.\n Returns float('inf') if the array contains no zeros.\n\n \"\"\"\n zeroes = arr.count(0)\n non_zeroes = len(arr) - zeroes\n\n if len(arr) == 0 or non_zeroes == 0:\n if zeroes > 0:\n return float('inf') # Infinite ratio if only zeros but not empty\n else:\n return 0 # Zero ratio if empty or all zeroes\n\n\n return zeroes / non_zeroes", "matching_cluster_idx": 6}, {"solution": "import math\ndef zero_count(arr):\n \"\"\"\n Calculates the ratio of zeroes to non-zeroes in an array of integers.\n\n Args:\n arr: A list of integers.\n\n Returns:\n The ratio of zeroes to non-zeroes, or 0 if the array is empty or contains only zeroes.\n Returns float('inf') if the array contains no zeroes but other elements.\n\n \"\"\"\n zeroes = 0\n non_zeroes = 0\n for num in arr:\n if num == 0:\n zeroes += 1\n else:\n non_zeroes += 1\n \n if len(arr) == 0 or non_zeroes == 0:\n if zeroes == 0:\n return 0 # Empty array or all elements are non-zero. Should return 0 for consistency.\n else:\n # This accounts for edge case when only zeros exist; technically the ratio approaches infinity. \n # Python's math.isclose() doesn't handle comparing to infinity directly.\n return float('inf')\n\n return zeroes / non_zeroes", "matching_cluster_idx": 3}, {"solution": "import math\ndef zero_count(arr):\n \"\"\"\n Calculates the ratio of zeros to non-zeros in an integer array.\n\n Args:\n arr: A list of integers.\n\n Returns:\n The ratio of zeros to non-zeros as a float. Returns 0.0 if the array is empty \n or contains only zeros. Returns float('inf') if the array contains no zeros.\n \"\"\"\n zeroes = 0\n non_zeroes = 0\n\n if not arr:\n return 0.0\n\n for num in arr:\n if num == 0:\n zeroes += 1\n else:\n non_zeroes += 1\n \n if non_zeroes == 0:\n if zeroes == 0:\n return 0.0\n else:\n return float('inf') # Or raise an exception if infinite ratio is undesirable\n else:\n return zeroes / non_zeroes", "matching_cluster_idx": 3}]}, "Mbpp/140": {"dps": 8.416149068322982, "dps_norm": 51.875, "pass@1": 100.0, "profiled": [{"solution": "def extract_singly(list_of_lists):\n \"\"\"\n Flattens a list of lists (or tuples) into a single set of numbers.\n\n Args:\n list_of_lists: A list where each element is an iterable of numbers.\n\n Returns:\n A set containing all the unique numbers from the input list of lists.\n \"\"\"\n\n result_set = set()\n for inner_list in list_of_lists:\n for number in inner_list:\n result_set.add(number)\n return result_set", "matching_cluster_idx": 3}, {"solution": "def extract_singly(list_of_lists):\n \"\"\"\n Flattens a list of lists (or tuples) into a single set of numbers.\n\n Args:\n list_of_lists: A list containing lists or tuples of numbers.\n\n Returns:\n A set containing all the unique numbers from the input lists.\n \"\"\"\n\n result_set = set()\n for inner_list in list_of_lists:\n for item in inner_list:\n result_set.add(item)\n return result_set", "matching_cluster_idx": 3}, {"solution": "def extract_singly(list_of_lists):\n \"\"\"\n Flattens a list of lists (or tuples) of numbers into a single list of numbers.\n\n Args:\n list_of_lists: A list where each element is a list or tuple of numbers.\n\n Returns:\n A list containing all the numbers from the input lists/tuples.\n \"\"\"\n result = []\n for inner_list in list_of_lists:\n for item in inner_list:\n result.append(item)\n return result", "matching_cluster_idx": 4}, {"solution": "def extract_singly(list_of_lists):\n \"\"\"\n Flattens a list of lists (or tuples) into a single set.\n\n Args:\n list_of_lists: A list where each element is an iterable of numbers.\n\n Returns:\n A set containing all the unique numbers from the input list of lists.\n \"\"\"\n result_set = set()\n for inner_list in list_of_lists:\n for num in inner_list:\n result_set.add(num)\n return result_set", "matching_cluster_idx": 3}, {"solution": "def extract_singly(list_of_lists):\n \"\"\"\n Flattens a list of lists (or tuples) into a single set of numbers.\n\n Args:\n list_of_lists: A list where each element is an iterable of numbers.\n\n Returns:\n A set containing all the unique numbers from the input list of lists.\n \"\"\"\n result_set = set()\n for inner_list in list_of_lists:\n for num in inner_list:\n result_set.add(num)\n return result_set", "matching_cluster_idx": 3}, {"solution": "def extract_singly(list_of_lists):\n \"\"\"\n Flattens a list of lists (or tuples) into a single set of numbers.\n\n Args:\n list_of_lists: A list where each element is a list or tuple of numbers.\n\n Returns:\n A set containing all the unique numbers from the input list of lists.\n \"\"\"\n result_set = set()\n for inner_list in list_of_lists:\n for item in inner_list:\n result_set.add(item)\n return result_set", "matching_cluster_idx": 4}, {"solution": "def extract_singly(list_of_lists):\n \"\"\"\n Flattens a list of lists (or tuples) into a single set of numbers.\n\n Args:\n list_of_lists: A list where each element is a list or tuple of numbers.\n\n Returns:\n A set containing all the unique numbers from the input list of lists.\n \"\"\"\n\n result_set = set()\n for inner_list in list_of_lists:\n for num in inner_list:\n result_set.add(num)\n return result_set", "matching_cluster_idx": 3}, {"solution": "def extract_singly(list_of_lists):\n \"\"\"\n Flattens a list of lists (or tuples) into a single set of numbers.\n\n Args:\n list_of_lists: A list where each element is a list or tuple of numbers.\n\n Returns:\n A set containing all the unique numbers from the input list of lists.\n \"\"\"\n result_set = set()\n for inner_list in list_of_lists:\n for num in inner_list:\n result_set.add(num)\n return result_set", "matching_cluster_idx": 3}, {"solution": "def extract_singly(list_of_lists):\n \"\"\"\n Flattens a list of lists (or tuples) into a single set of numbers.\n\n Args:\n list_of_lists: A list where each element is a list or tuple of numbers.\n\n Returns:\n A set containing all the unique numbers from the input list of lists.\n \"\"\"\n\n result_set = set()\n for inner_list in list_of_lists:\n for number in inner_list:\n result_set.add(number)\n return result_set", "matching_cluster_idx": 3}, {"solution": "def extract_singly(list_of_lists):\n \"\"\"\n Flattens a list of iterables (lists, tuples, etc.) into a single set of numbers.\n\n Args:\n list_of_lists: A list where each element is an iterable of numbers.\n\n Returns:\n A set containing all the unique numbers from the input list of iterables.\n \"\"\"\n result_set = set()\n for inner_list in list_of_lists:\n for element in inner_list:\n result_set.add(element)\n return result_set", "matching_cluster_idx": 3}, {"solution": "def extract_singly(list_of_lists):\n \"\"\"\n Flattens a list of lists (or tuples) into a single set of numbers.\n\n Args:\n list_of_lists: A list where each element is either a list or tuple of numbers.\n\n Returns:\n A set containing all the unique numbers from the input list of lists.\n \"\"\"\n result_set = set()\n for inner_list in list_of_lists:\n for num in inner_list:\n result_set.add(num)\n return result_set", "matching_cluster_idx": 3}, {"solution": "def extract_singly(list_of_lists):\n \"\"\"\n Flattens a list of lists (or tuples) of numbers into a single set of numbers.\n\n Args:\n list_of_lists: A list where each element is a list or tuple of numbers.\n\n Returns:\n A set containing all the unique numbers from the input list of lists.\n \"\"\"\n result_set = set()\n for inner_list in list_of_lists:\n for num in inner_list:\n result_set.add(num)\n return result_set", "matching_cluster_idx": 3}, {"solution": "def extract_singly(list_of_lists):\n \"\"\"\n Flattens a list of lists (or tuples) into a single set of numbers.\n\n Args:\n list_of_lists: A list containing lists or tuples of numbers.\n\n Returns:\n A set containing all the unique numbers from the input list of lists.\n \"\"\"\n\n result_set = set()\n for inner_list in list_of_lists:\n for item in inner_list:\n result_set.add(item)\n return result_set", "matching_cluster_idx": 3}, {"solution": "def extract_singly(list_of_lists):\n \"\"\"\n Flattens a list of lists (or tuples) into a single set of numbers.\n\n Args:\n list_of_lists: A list where each element is an iterable of numbers.\n\n Returns:\n A set containing all the unique numbers from the input list of lists.\n \"\"\"\n\n result_set = set()\n for inner_list in list_of_lists:\n for number in inner_list:\n result_set.add(number)\n return result_set", "matching_cluster_idx": 3}, {"solution": "def extract_singly(list_of_lists):\n \"\"\"\n Flattens a list of lists (or tuples) of numbers into a single set.\n\n Args:\n list_of_lists: A list where each element is a list or tuple of numbers.\n\n Returns:\n A set containing all the unique numbers from the input list of lists.\n \"\"\"\n\n result_set = set()\n for inner_list in list_of_lists:\n for num in inner_list:\n result_set.add(num)\n return result_set", "matching_cluster_idx": 3}, {"solution": "def extract_singly(list_of_lists):\n \"\"\"\n Flattens a list of lists (or tuples) into a single set of numbers.\n\n Args:\n list_of_lists: A list of lists or tuples containing numbers.\n\n Returns:\n A set containing all the unique numbers from the input list of lists.\n \"\"\"\n result_set = set()\n for inner_list in list_of_lists:\n for num in inner_list:\n result_set.add(num)\n return result_set", "matching_cluster_idx": 3}, {"solution": "def extract_singly(list_of_lists):\n \"\"\"\n Flattens a list of lists (or tuples) into a single set of numbers.\n\n Args:\n list_of_lists: A list where each element is a list or tuple of numbers.\n\n Returns:\n A set containing all the unique numbers from the input list of lists.\n \"\"\"\n result_set = set()\n for inner_list in list_of_lists:\n for number in inner_list:\n result_set.add(number)\n return result_set", "matching_cluster_idx": 4}, {"solution": "def extract_singly(list_of_lists):\n \"\"\"\n Flattens a list of lists (or tuples) of numbers into a single set of numbers.\n\n Args:\n list_of_lists: A list where each element is a list or tuple of numbers.\n\n Returns:\n A set containing all the unique numbers from the input list of lists.\n \"\"\"\n result_set = set()\n for inner_list in list_of_lists:\n for num in inner_list:\n result_set.add(num)\n return result_set", "matching_cluster_idx": 3}, {"solution": "def extract_singly(list_of_lists):\n \"\"\"\n Flattens a list of lists (or tuples) into a single set of numbers.\n\n Args:\n list_of_lists: A list where each element is an iterable of numbers.\n\n Returns:\n A set containing all the unique numbers from the input list of lists.\n \"\"\"\n result_set = set()\n for inner_list in list_of_lists:\n for num in inner_list:\n result_set.add(num)\n return result_set", "matching_cluster_idx": 3}, {"solution": "def extract_singly(list_of_lists):\n \"\"\"\n Flattens a list of lists (or tuples) into a single set of numbers.\n\n Args:\n list_of_lists: A list where each element is a list or tuple of numbers.\n\n Returns:\n A set containing all the unique numbers from the input list of lists.\n \"\"\"\n\n result_set = set()\n for inner_list in list_of_lists:\n for num in inner_list:\n result_set.add(num)\n return result_set", "matching_cluster_idx": 3}]}, "Mbpp/141": {"dps": 57.18820861678005, "dps_norm": 38.75, "pass@1": 60.0, "profiled": [{"solution": "def pancake_sort(arr):\n \"\"\"Sorts a list using the Pancake Sort algorithm.\"\"\"\n\n def flip(arr, k):\n left = 0\n while left < k:\n arr[left], arr[k] = arr[k], arr[left]\n left += 1\n k -= 1\n\n n = len(arr)\n for curr_size in range(n, 0, -1):\n mi = arr.index(max(arr[:curr_size]))\n\n if mi != curr_size - 1:\n flip(arr, mi)\n flip(arr, curr_size - 1)\n\n return arr", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(arr):\n \"\"\"Sorts a list using the Pancake Sort algorithm.\n\n Args:\n arr: The list to be sorted.\n\n Returns:\n The sorted list.\n \"\"\"\n\n def flip(arr, k):\n \"\"\"Reverses the first k elements of a list.\"\"\"\n return arr[:k][::-1] + arr[k:]\n\n n = len(arr)\n for i in range(n - 1, -1, -1):\n max_index = 0\n for j in range(1, i + 1):\n if arr[j] > arr[max_index]:\n max_index = j\n\n if max_index != i:\n arr = flip(arr, max_index + 1)\n arr = flip(arr, i + 1)\n\n return arr", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(arr):\n \"\"\"Sorts a list using the Pancake Sort algorithm.\n\n Args:\n arr: The list to be sorted.\n\n Returns:\n The sorted list.\n \"\"\"\n\n def flip(arr, k):\n \"\"\"Reverses the first k elements of the list.\"\"\"\n arr[:k] = arr[:k][::-1]\n\n for i in range(len(arr) - 1, 0, -1):\n # Find the index of the maximum element in the unsorted part\n max_index = 0\n for j in range(1, i + 1):\n if arr[j] > arr[max_index]:\n max_index = j\n\n # Bring the maximum element to the beginning\n flip(arr, max_index + 1)\n\n # Bring the maximum element to its correct position\n flip(arr, i + 1)\n\n return arr", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(arr):\n \"\"\"Sorts a list using the Pancake Sort algorithm.\"\"\"\n\n def flip(arr, k):\n \"\"\"Reverses the order of elements in arr up to index k.\"\"\"\n left = 0\n while left < k:\n arr[left], arr[k] = arr[k], arr[left]\n left += 1\n k -= 1\n\n n = len(arr)\n for i in range(n - 1, -1, -1):\n # Find the index of the maximum element in arr[0...i]\n max_index = 0\n for j in range(1, i + 1):\n if arr[j] > arr[max_index]:\n max_index = j\n\n # Move the maximum element to the beginning of arr[0...i]\n if max_index != 0:\n flip(arr, max_index)\n\n # Move the maximum element to its correct sorted position at the end of arr[0...i]\n flip(arr, i)\n\n return arr", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(arr):\n \"\"\"Sorts a list using the Pancake Sort algorithm.\n\n Args:\n arr: The list to be sorted.\n\n Returns:\n The sorted list.\n \"\"\"\n\n def flip(arr, k):\n \"\"\"Reverses the order of the first k elements in the list.\"\"\"\n return arr[:k][::-1] + arr[k:]\n\n n = len(arr)\n for i in range(n - 1, -1, -1):\n # Find the index of the maximum element in arr[:i+1]\n max_index = 0\n for j in range(1, i + 1):\n if arr[j] > arr[max_index]:\n max_index = j\n\n # Bring the maximum element to the beginning\n arr = flip(arr, max_index + 1)\n\n # Bring the maximum element to its correct position\n arr = flip(arr, i + 1)\n\n return arr", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(arr):\n \"\"\"Sorts a list using the Pancake Sort algorithm.\n\n Args:\n arr: The list to be sorted.\n\n Returns:\n The sorted list.\n \"\"\"\n\n def flip(arr, k):\n \"\"\"Reverses the first k elements of a list.\"\"\"\n return arr[:k][::-1] + arr[k:]\n\n n = len(arr)\n for i in range(n - 1, 0, -1):\n # Find the index of the maximum element in arr[0...i]\n max_index = 0\n for j in range(1, i + 1):\n if arr[j] > arr[max_index]:\n max_index = j\n\n # Flip the array from 0 to max_index to bring the max element to the beginning\n arr = flip(arr, max_index + 1)\n\n # Flip the array from 0 to i to bring the max element to its correct position\n arr = flip(arr, i + 1)\n\n return arr", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(arr):\n \"\"\"Sorts a list using the Pancake Sort algorithm.\n\n Args:\n arr: The list to be sorted.\n\n Returns:\n The sorted list.\n \"\"\"\n\n def flip(arr, k):\n \"\"\"Reverses the first k elements of the list.\"\"\"\n arr[:k] = arr[:k][::-1]\n\n n = len(arr)\n for i in range(n - 1, -1, -1):\n # Find the maximum element in arr[:i+1]\n max_index = 0\n for j in range(1, i + 1):\n if arr[j] > arr[max_index]:\n max_index = j\n\n # Move the maximum element to the beginning\n if max_index != 0:\n flip(arr, max_index + 1)\n\n # Move the maximum element to its correct position\n flip(arr, i + 1)\n\n return arr", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(arr):\n \"\"\"Sorts a list using the Pancake Sort algorithm.\n\n Args:\n arr: The list to be sorted.\n\n Returns:\n The sorted list.\n \"\"\"\n\n def flip(arr, k):\n \"\"\"Reverses the first k elements of the list.\"\"\"\n left = 0\n while left < k:\n arr[left], arr[k] = arr[k], arr[left]\n left += 1\n k -= 1\n\n n = len(arr)\n for curr_size in range(n, 1, -1):\n # Find the index of the maximum element in the unsorted part\n mi = arr.index(max(arr[:curr_size]))\n\n # Move the maximum element to the beginning\n if mi != 0:\n flip(arr, mi)\n\n # Move the maximum element to its correct sorted position\n flip(arr, curr_size - 1)\n \n return arr", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(arr):\n \"\"\"Sorts a list of elements using the Pancake Sort algorithm.\n\n Args:\n arr: The list to be sorted.\n\n Returns:\n The sorted list.\n \"\"\"\n\n def flip(arr, k):\n \"\"\"Reverses the first k elements of the list.\"\"\"\n return arr[:k][::-1] + arr[k:]\n\n def find_max(arr, n):\n \"\"\"Finds the index of the maximum element in the first n elements.\"\"\"\n mi = 0\n for i in range(0, n):\n if arr[i] > arr[mi]:\n mi = i\n return mi\n\n n = len(arr)\n while n > 1:\n mi = find_max(arr, n)\n if mi != n - 1:\n arr = flip(arr, mi + 1) # Bring max to the beginning\n arr = flip(arr, n) # Bring max to its correct position\n n -= 1\n\n return arr", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(arr):\n \"\"\"Sorts a list using the Pancake Sort algorithm.\n\n Args:\n arr: The list to be sorted.\n\n Returns:\n The sorted list.\n \"\"\"\n\n def flip(arr, k):\n \"\"\"Reverses the first k elements of the list.\"\"\"\n left = 0\n while left < k:\n arr[left], arr[k] = arr[k], arr[left]\n left += 1\n k -= 1\n\n n = len(arr)\n for curr_size in range(n, 1, -1):\n # Find index of the maximum element in \n # arr[0..curr_size-1]\n mi = arr.index(max(arr[:curr_size]))\n\n # Move the maximum element to end of current size subarray\n if mi != curr_size - 1:\n # To move at the end, first move maximum number to beginning \n flip(arr, mi)\n # Now move the maximum number to end by reversing current array\n flip(arr, curr_size - 1)\n return arr", "matching_cluster_idx": 2}, {"solution": "def flip(arr, k):\n \"\"\"Reverses the first k elements of an array.\"\"\"\n return arr[:k][::-1] + arr[k:]\ndef find_max_index(arr, k):\n \"\"\"Finds the index of the maximum element in the first k elements of an array.\"\"\"\n max_index = 0\n for i in range(1, k):\n if arr[i] > arr[max_index]:\n max_index = i\n return max_index\ndef pancake_sort(arr):\n \"\"\"Sorts a list using the pancake sort algorithm.\"\"\"\n n = len(arr)\n for i in range(n, 1, -1):\n max_index = find_max_index(arr, i)\n if max_index != i - 1:\n arr = flip(arr, max_index + 1) # Bring max to the front\n arr = flip(arr, i) # Bring max to its correct position\n return arr", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(arr):\n \"\"\"Sorts a list using the Pancake Sort algorithm.\n\n Args:\n arr: The list to be sorted.\n\n Returns:\n The sorted list.\n \"\"\"\n\n def flip(arr, k):\n \"\"\"Reverses the first k elements of the list.\"\"\"\n left = 0\n while left < k:\n arr[left], arr[k] = arr[k], arr[left]\n left += 1\n k -= 1\n\n n = len(arr)\n for i in range(n - 1, -1, -1):\n # Find the maximum element in arr[0...i]\n max_index = 0\n for j in range(1, i + 1):\n if arr[j] > arr[max_index]:\n max_index = j\n\n # Move the maximum element to the end of the current subarray\n if max_index != i:\n flip(arr, max_index)\n flip(arr, i)\n return arr", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(arr):\n \"\"\"Sorts a list using the Pancake Sort algorithm.\"\"\"\n\n def flip(arr, k):\n \"\"\"Reverses the first k elements of the list.\"\"\"\n left = 0\n while left < k:\n arr[left], arr[k] = arr[k], arr[left]\n left += 1\n k -= 1\n\n n = len(arr)\n for i in range(n - 1, -1, -1):\n max_index = 0\n for j in range(i + 1):\n if arr[j] > arr[max_index]:\n max_index = j\n\n if max_index != i:\n flip(arr, max_index) # Flip to bring the max element to the front\n flip(arr, i) # Flip to put the max element at the current position\n\n return arr", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(arr):\n \"\"\"Sorts a list using the Pancake Sort algorithm.\n\n Args:\n arr: The list to be sorted.\n\n Returns:\n The sorted list.\n \"\"\"\n\n def flip(arr, k):\n \"\"\"Reverses the elements of the list up to index k.\"\"\"\n left = 0\n while left < k:\n arr[left], arr[k] = arr[k], arr[left]\n left += 1\n k -= 1\n\n n = len(arr)\n for curr_size in range(n, 1, -1):\n mi = 0\n for i in range(1, curr_size):\n if arr[i] > arr[mi]:\n mi = i\n\n if mi != curr_size - 1:\n flip(arr, mi)\n flip(arr, curr_size - 1)\n\n return arr", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(arr):\n \"\"\"Sorts a list using the Pancake Sort algorithm.\n\n Args:\n arr: The list to be sorted.\n\n Returns:\n The sorted list.\n \"\"\"\n\n def flip(arr, k):\n \"\"\"Reverses the order of the first k elements in the list.\"\"\"\n arr[:k+1] = arr[:k+1][::-1]\n\n\n n = len(arr)\n for curr_size in range(n - 1, 0, -1):\n # Find the index of the maximum element in the unsorted part\n mi = arr.index(max(arr[:curr_size + 1]))\n\n # Flip the elements from 0 to mi to bring the maximum element to the beginning\n if mi != 0:\n flip(arr, mi)\n\n # Flip the elements from 0 to curr_size to bring the maximum element to its correct position\n flip(arr, curr_size)\n\n\n return arr", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(arr):\n \"\"\"Sorts a list using the Pancake Sort algorithm.\n\n Args:\n arr: The list to be sorted.\n\n Returns:\n The sorted list.\n \"\"\"\n def flip(arr, k):\n \"\"\"Reverses the order of the first k elements in the list.\"\"\"\n arr[:k+1] = arr[:k+1][::-1]\n\n n = len(arr)\n for i in range(n - 1, -1, -1):\n max_index = 0\n for j in range(1, i + 1):\n if arr[j] > arr[max_index]:\n max_index = j\n\n if max_index != i:\n flip(arr, max_index)\n flip(arr, i)\n\n return arr", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(arr):\n \"\"\"Sorts a list using the Pancake Sort algorithm.\n\n Args:\n arr: The list to be sorted.\n\n Returns:\n The sorted list.\n \"\"\"\n\n def flip(arr, k):\n \"\"\"Reverses the elements of the list up to index k.\"\"\"\n left = 0\n while left < k:\n arr[left], arr[k] = arr[k], arr[left]\n left += 1\n k -= 1\n\n n = len(arr)\n for curr_size in range(n, 1, -1):\n # Find index of the maximum element in sub-array of size curr_size\n mi = arr.index(max(arr[0:curr_size]))\n\n # Move the maximum element to end of current sub-array\n if mi != curr_size - 1:\n # Reverse from 0 to mi to put the max element at the beginning\n flip(arr, mi)\n\n # Reverse the whole current sub-array to put the max element at the end\n flip(arr, curr_size - 1)\n return arr", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(arr):\n \"\"\"Sorts a list using the Pancake Sort algorithm.\"\"\"\n n = len(arr)\n\n def flip(arr, k):\n \"\"\"Reverses the first k elements of the list.\"\"\"\n return arr[:k][::-1] + arr[k:]\n \n for curr_size in range(n, 1, -1):\n mi = arr.index(max(arr[:curr_size]))\n \n if mi != curr_size - 1:\n arr = flip(arr, mi + 1)\n arr = flip(arr, curr_size)\n\n return arr", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(arr):\n \"\"\"Sorts a list using the Pancake Sort algorithm.\n\n Args:\n arr: The list to be sorted.\n\n Returns:\n The sorted list.\n \"\"\"\n\n def flip(arr, k):\n \"\"\"Reverses the first k elements of the list.\"\"\"\n left = 0\n while left < k:\n arr[left], arr[k] = arr[k], arr[left]\n left += 1\n k -= 1\n\n\n n = len(arr)\n for curr_size in range(n, 1, -1):\n # Find index of the maximum element in \n # arr[0..curr_size-1]\n mi = arr.index(max(arr[:curr_size]))\n\n # Move the maximum element to end of current range\n # if it's not already at the end\n if mi != curr_size - 1:\n # To move at the end, first move maximum number to beginning \n flip(arr, mi)\n # Now move the maximum number to end by reversing current array\n flip(arr, curr_size - 1)\n\n return arr", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(arr):\n \"\"\"Sorts a list using the pancake sort algorithm.\n\n Args:\n arr: The list to be sorted.\n\n Returns:\n The sorted list.\n \"\"\"\n n = len(arr)\n for i in range(n - 1, -1, -1):\n max_idx = 0\n for j in range(1, i + 1):\n if arr[j] > arr[max_idx]:\n max_idx = j\n\n if max_idx != i:\n arr[:max_idx + 1] = arr[:max_idx + 1][::-1] # Flip to bring max to the beginning\n arr[:i + 1] = arr[:i + 1][::-1] # Flip to bring max to the correct position\n\n return arr", "matching_cluster_idx": 2}]}, "Mbpp/166": {"dps": 94.39999999999999, "dps_norm": 50.0, "pass@1": 100.0, "profiled": [{"solution": "from itertools import combinations\ndef find_even_pair(nums):\n \"\"\"\n Counts the number of pairs in a list whose XOR is even.\n\n Args:\n nums: A list of integers.\n\n Returns:\n The number of pairs with an even XOR.\n \"\"\"\n\n count = 0\n for a, b in combinations(nums, 2):\n if (a ^ b) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(nums):\n \"\"\"\n Counts the number of pairs of integers in a list that XOR to an even number.\n\n Args:\n nums: A list of integers.\n\n Returns:\n The number of pairs that XOR to an even number.\n \"\"\"\n\n count = 0\n n = len(nums)\n for i in range(n):\n for j in range(i + 1, n):\n if (nums[i] ^ nums[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(nums):\n \"\"\"\n Counts the number of pairs of integers in a list that XOR to an even number.\n\n Args:\n nums: A list of integers.\n\n Returns:\n The number of pairs that XOR to an even number.\n \"\"\"\n\n n = len(nums)\n count = 0\n for i in range(n):\n for j in range(i + 1, n):\n if (nums[i] ^ nums[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(nums):\n \"\"\"\n Counts the number of pairs of integers in a list that XOR to an even number.\n\n Args:\n nums: A list of integers.\n\n Returns:\n The number of pairs that XOR to an even number.\n \"\"\"\n\n n = len(nums)\n count = 0\n for i in range(n):\n for j in range(i + 1, n):\n if (nums[i] ^ nums[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(nums):\n \"\"\"\n Counts the number of pairs of integers in a list that XOR to an even number.\n\n Args:\n nums: A list of integers.\n\n Returns:\n The number of pairs that XOR to an even number.\n \"\"\"\n\n count = 0\n n = len(nums)\n for i in range(n):\n for j in range(i + 1, n):\n if (nums[i] ^ nums[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(nums):\n \"\"\"\n Counts the number of pairs of integers in a list that XOR to an even number.\n\n Args:\n nums: A list of integers.\n\n Returns:\n The number of pairs that XOR to an even number.\n \"\"\"\n\n n = len(nums)\n count = 0\n for i in range(n):\n for j in range(i + 1, n):\n if (nums[i] ^ nums[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(nums):\n \"\"\"\n Counts the number of pairs of integers in a list that XOR to an even number.\n\n Args:\n nums: A list of integers.\n\n Returns:\n The number of pairs that XOR to an even number.\n \"\"\"\n\n count = 0\n n = len(nums)\n for i in range(n):\n for j in range(i + 1, n):\n if (nums[i] ^ nums[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(nums):\n \"\"\"\n Counts the number of pairs of integers in a list that XOR to an even number.\n\n Args:\n nums: A list of integers.\n\n Returns:\n The number of pairs that XOR to an even number.\n \"\"\"\n\n count = 0\n n = len(nums)\n\n for i in range(n):\n for j in range(i + 1, n):\n if (nums[i] ^ nums[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(nums):\n \"\"\"Counts the number of pairs in a list whose XOR is even.\n\n Args:\n nums: A list of integers.\n\n Returns:\n The number of pairs whose XOR sum is even.\n \"\"\"\n count = 0\n n = len(nums)\n for i in range(n):\n for j in range(i + 1, n):\n if (nums[i] ^ nums[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(nums):\n \"\"\"\n Counts the number of pairs of integers in a list that XOR to an even number.\n\n Args:\n nums: A list of integers.\n\n Returns:\n The number of pairs that XOR to an even number.\n \"\"\"\n\n count = 0\n n = len(nums)\n for i in range(n):\n for j in range(i + 1, n):\n if (nums[i] ^ nums[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(nums):\n \"\"\"\n Counts the number of pairs of integers in a list that XOR to an even number.\n\n Args:\n nums: A list of integers.\n\n Returns:\n The number of pairs that XOR to an even number.\n \"\"\"\n\n count = 0\n n = len(nums)\n for i in range(n):\n for j in range(i + 1, n):\n if (nums[i] ^ nums[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(nums):\n \"\"\"\n Counts the number of pairs of integers in a list that XOR to an even number.\n\n Args:\n nums: A list of integers.\n\n Returns:\n The number of pairs that XOR to an even number.\n \"\"\"\n\n count = 0\n n = len(nums)\n for i in range(n):\n for j in range(i + 1, n):\n if (nums[i] ^ nums[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(nums):\n \"\"\"\n Counts the number of pairs of integers in a list that XOR to an even number.\n\n Args:\n nums: A list of integers.\n\n Returns:\n The number of pairs that XOR to an even number.\n \"\"\"\n\n n = len(nums)\n count = 0\n for i in range(n):\n for j in range(i + 1, n):\n if (nums[i] ^ nums[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(nums):\n \"\"\"\n Counts the number of pairs of integers in a list that XOR to an even number.\n\n Args:\n nums: A list of integers.\n\n Returns:\n The number of pairs that XOR to an even number.\n \"\"\"\n count = 0\n n = len(nums)\n for i in range(n):\n for j in range(i + 1, n):\n if (nums[i] ^ nums[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(nums):\n \"\"\"Counts the number of pairs in a list whose XOR results in an even number.\n\n Args:\n nums: A list of integers.\n\n Returns:\n The number of pairs with an even XOR.\n \"\"\"\n\n count = 0\n n = len(nums)\n\n for i in range(n):\n for j in range(i + 1, n):\n if (nums[i] ^ nums[j]) % 2 == 0:\n count += 1\n\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(nums):\n \"\"\"\n Counts the number of pairs of integers in a list that XOR to an even number.\n\n Args:\n nums: A list of integers.\n\n Returns:\n The number of pairs that XOR to an even number.\n \"\"\"\n\n count = 0\n n = len(nums)\n for i in range(n):\n for j in range(i + 1, n):\n if (nums[i] ^ nums[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(nums):\n \"\"\"\n Counts the number of pairs of integers in a list that XOR to an even number.\n\n Args:\n nums: A list of integers.\n\n Returns:\n The number of pairs that XOR to an even number.\n \"\"\"\n\n count = 0\n n = len(nums)\n for i in range(n):\n for j in range(i + 1, n):\n if (nums[i] ^ nums[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(nums):\n \"\"\"\n Counts the number of pairs of integers in a list that XOR to an even number.\n\n Args:\n nums: A list of integers.\n\n Returns:\n The number of pairs that XOR to an even number.\n \"\"\"\n\n count = 0\n n = len(nums)\n for i in range(n):\n for j in range(i + 1, n):\n if (nums[i] ^ nums[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(nums):\n \"\"\"\n Counts the number of pairs of integers in a list that XOR to an even number.\n\n Args:\n nums: A list of integers.\n\n Returns:\n The number of pairs that XOR to an even number.\n \"\"\"\n\n count = 0\n n = len(nums)\n for i in range(n):\n for j in range(i + 1, n):\n if (nums[i] ^ nums[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(nums):\n \"\"\"\n Counts the number of pairs of integers in a list that XOR to an even number.\n\n Args:\n nums: A list of integers.\n\n Returns:\n The number of pairs that XOR to an even number.\n \"\"\"\n\n count = 0\n n = len(nums)\n for i in range(n):\n for j in range(i + 1, n):\n if (nums[i] ^ nums[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}]}, "Mbpp/170": {"dps": 30.434782608695652, "dps_norm": 60.625, "pass@1": 100.0, "profiled": [{"solution": "def sum_range_list(nums, start_index, end_index):\n \"\"\"\n Calculates the sum of numbers in a list within a specified range of indices (inclusive).\n\n Args:\n nums: The input list of numbers.\n start_index: The starting index of the range.\n end_index: The ending index of the range.\n\n Returns:\n The sum of the numbers within the specified range. Returns 0 if the list is empty or indices are invalid.\n \"\"\"\n if not nums:\n return 0\n \n n = len(nums)\n if start_index < 0 or end_index >= n or start_index > end_index:\n return 0 # Handle invalid indices\n\n total_sum = 0\n for i in range(start_index, end_index + 1):\n total_sum += nums[i]\n\n return total_sum", "matching_cluster_idx": 4}, {"solution": "def sum_range_list(nums, start_index, end_index):\n \"\"\"\n Calculates the sum of numbers in a list within a specified range of indices (inclusive).\n\n Args:\n nums: The list of numbers.\n start_index: The starting index of the range (inclusive).\n end_index: The ending index of the range (inclusive).\n\n Returns:\n The sum of numbers within the specified range.\n Returns 0 if the list is empty or indices are out of range.\n \"\"\"\n if not nums:\n return 0 # Handle empty list\n\n if start_index < 0 or end_index < 0 or start_index >= len(nums) or end_index >= len(nums) or start_index > end_index:\n return 0 # Handle invalid indices\n\n\n total = 0\n for i in range(start_index, end_index + 1):\n total += nums[i]\n return total", "matching_cluster_idx": 4}, {"solution": "def sum_range_list(nums: list, start_index: int, end_index: int) -> int:\n \"\"\"\n Calculates the sum of numbers in a list within a specified range of indices.\n\n Args:\n nums: The list of numbers.\n start_index: The starting index (inclusive).\n end_index: The ending index (inclusive).\n\n Returns:\n The sum of the numbers within the specified range.\n Returns 0 if the list is empty or indices are invalid.\n \"\"\"\n\n if not nums:\n return 0\n \n if start_index < 0 or end_index < 0 or start_index >= len(nums) or end_index >= len(nums) or start_index > end_index:\n return 0\n\n total = 0\n for i in range(start_index, end_index + 1):\n total += nums[i]\n\n return total", "matching_cluster_idx": 4}, {"solution": "def sum_range_list(nums, start_index, end_index):\n \"\"\"\n Calculates the sum of numbers in a list within a specified range of indices (inclusive).\n\n Args:\n nums: The list of numbers.\n start_index: The starting index of the range (inclusive).\n end_index: The ending index of the range (inclusive).\n\n Returns:\n The sum of numbers within the specified range.\n Returns 0 if the list is empty or if the indices are out of range.\n \"\"\"\n\n if not nums:\n return 0\n\n if start_index < 0 or end_index < 0 or start_index >= len(nums) or end_index >= len(nums) or start_index > end_index:\n return 0\n\n total = 0\n for i in range(start_index, end_index + 1):\n total += nums[i]\n return total", "matching_cluster_idx": 4}, {"solution": "def sum_range_list(nums, start_index, end_index):\n \"\"\"\n Calculates the sum of numbers within a specified range of indices in a list.\n\n Args:\n nums: The list of numbers.\n start_index: The starting index (inclusive).\n end_index: The ending index (inclusive).\n\n Returns:\n The sum of numbers within the specified range, or 0 if the list is empty or indices are invalid.\n \"\"\"\n if not nums:\n return 0\n\n if start_index < 0 or end_index < 0 or start_index >= len(nums) or end_index >= len(nums) or start_index > end_index:\n return 0 # Handle invalid indices\n\n total = 0\n for i in range(start_index, end_index + 1):\n total += nums[i]\n return total", "matching_cluster_idx": 4}, {"solution": "def sum_range_list(nums: list, start_index: int, end_index: int) -> int:\n \"\"\"\n Calculates the sum of elements within a specified range in a list.\n\n Args:\n nums: The input list of numbers.\n start_index: The starting index (inclusive).\n end_index: The ending index (inclusive).\n\n Returns:\n The sum of elements within the specified range.\n Returns 0 if the input list is empty or None.\n Returns 0 if the start_index is out of bounds.\n Returns the sum up to the end of the list if the end_index is out of bounds.\n\n \"\"\"\n if not nums:\n return 0\n\n if start_index < 0 or start_index >= len(nums):\n return 0\n\n end_index = min(end_index, len(nums) - 1) # Handle out-of-bounds end_index\n \n total = 0\n for i in range(start_index, end_index + 1):\n total += nums[i]\n return total", "matching_cluster_idx": 4}, {"solution": "def sum_range_list(nums, start_index, end_index):\n \"\"\"\n Calculates the sum of elements within a given range of indices in a list.\n\n Args:\n nums: The list of numbers.\n start_index: The starting index (inclusive).\n end_index: The ending index (inclusive).\n\n Returns:\n The sum of elements within the specified range.\n Returns 0 if the list is empty or if the indices are out of range or invalid.\n \"\"\"\n if not nums:\n return 0\n\n if not (0 <= start_index <= end_index < len(nums)): # Check for valid indices\n return 0\n\n total = 0\n for i in range(start_index, end_index + 1):\n total += nums[i]\n return total", "matching_cluster_idx": 4}, {"solution": "def sum_range_list(nums, start_index, end_index):\n \"\"\"Calculates the sum of numbers within a specified range of indices in a list.\n\n Args:\n nums: A list of numbers.\n start_index: The starting index (inclusive).\n end_index: The ending index (inclusive).\n\n Returns:\n The sum of numbers within the specified range.\n Returns 0 if the list is empty or indices are out of range.\n \"\"\"\n if not nums or start_index < 0 or end_index >= len(nums) or start_index > end_index:\n return 0\n\n total = 0\n for i in range(start_index, end_index + 1):\n total += nums[i]\n return total", "matching_cluster_idx": 4}, {"solution": "def sum_range_list(nums, start, end):\n \"\"\"\n Calculates the sum of elements in a list within a specified range (inclusive).\n\n Args:\n nums: A list of numbers.\n start: The starting index (inclusive).\n end: The ending index (inclusive).\n\n Returns:\n The sum of elements within the specified range.\n Returns 0 if the list is empty or indices are invalid.\n \"\"\"\n if not nums:\n return 0\n if start < 0 or end >= len(nums) or start > end:\n return 0\n\n total = 0\n for i in range(start, end + 1):\n total += nums[i]\n return total", "matching_cluster_idx": 4}, {"solution": "def sum_range_list(nums, start_index, end_index):\n \"\"\"\n Calculates the sum of numbers within a specified range of indices in a list.\n\n Args:\n nums: The input list of numbers.\n start_index: The starting index (inclusive).\n end_index: The ending index (inclusive).\n\n Returns:\n The sum of numbers within the specified range, or 0 if the input is invalid.\n \"\"\"\n\n if not isinstance(nums, list) or not all(isinstance(num, (int, float)) for num in nums):\n return 0 # Handle invalid input: not a list or contains non-numeric elements\n\n if not (0 <= start_index <= end_index < len(nums)):\n return 0 # Handle invalid indices\n\n total = 0\n for i in range(start_index, end_index + 1):\n total += nums[i]\n\n return total", "matching_cluster_idx": 1}, {"solution": "def sum_range_list(nums: list, start_index: int, end_index: int) -> int:\n \"\"\"\n Calculates the sum of numbers in a list within a specified range (inclusive).\n\n Args:\n nums: The list of numbers.\n start_index: The starting index of the range.\n end_index: The ending index of the range.\n\n Returns:\n The sum of the numbers within the range.\n Returns 0 if the input list is empty or None.\n Returns 0 if the start or end indices are out of bounds.\n \"\"\"\n if not nums:\n return 0\n\n if start_index < 0 or end_index >= len(nums) or start_index > end_index:\n return 0\n \n total = 0\n for i in range(start_index, end_index + 1):\n total += nums[i]\n return total", "matching_cluster_idx": 4}, {"solution": "def sum_range_list(nums, start_index, end_index):\n \"\"\"Calculates the sum of numbers in a list within a specified range.\n\n Args:\n nums: The list of numbers.\n start_index: The starting index (inclusive).\n end_index: The ending index (inclusive).\n\n Returns:\n The sum of numbers within the specified range.\n Returns 0 if the list is empty or indices are invalid.\n \"\"\"\n if not nums:\n return 0\n\n n = len(nums)\n if start_index < 0 or end_index < 0 or start_index >= n or end_index >= n or start_index > end_index:\n return 0\n\n total = 0\n for i in range(start_index, end_index + 1):\n total += nums[i]\n\n return total", "matching_cluster_idx": 4}, {"solution": "def sum_range_list(nums, start_index, end_index):\n \"\"\"\n Calculates the sum of numbers within a given range of indices in a list.\n\n Args:\n nums: The list of numbers.\n start_index: The starting index (inclusive).\n end_index: The ending index (inclusive).\n\n Returns:\n The sum of numbers within the specified range.\n Returns 0 if the list is empty or indices are out of range.\n \"\"\"\n if not nums:\n return 0\n if start_index < 0 or end_index < 0 or start_index >= len(nums) or end_index >= len(nums) or start_index > end_index:\n return 0\n\n total = 0\n for i in range(start_index, end_index + 1):\n total += nums[i]\n return total", "matching_cluster_idx": 4}, {"solution": "def sum_range_list(nums, start_index, end_index):\n \"\"\"Calculates the sum of numbers in a list within a specified range of indices (inclusive).\n\n Args:\n nums: The list of numbers.\n start_index: The starting index of the range (inclusive).\n end_index: The ending index of the range (inclusive).\n\n Returns:\n The sum of the numbers within the specified range.\n Returns 0 if the list is empty or indices are invalid.\n \"\"\"\n\n if not nums:\n return 0\n\n if not (0 <= start_index <= end_index < len(nums)):\n return 0\n\n total = 0\n for i in range(start_index, end_index + 1):\n total += nums[i]\n return total", "matching_cluster_idx": 4}, {"solution": "def sum_range_list(nums, start_index, end_index):\n \"\"\"\n Calculates the sum of numbers within a specified range of indices in a list.\n\n Args:\n nums: A list of numbers.\n start_index: The starting index (inclusive).\n end_index: The ending index (inclusive).\n\n Returns:\n The sum of numbers within the specified range. Returns 0 if the list is empty \n or if the indices are invalid.\n \"\"\"\n\n if not nums:\n return 0\n\n n = len(nums)\n\n if not (0 <= start_index <= end_index < n):\n return 0\n\n total = 0\n for i in range(start_index, end_index + 1):\n total += nums[i]\n return total", "matching_cluster_idx": 4}, {"solution": "def sum_range_list(nums, start_index, end_index):\n \"\"\"\n Calculates the sum of elements in a list within a specified range of indices (inclusive).\n\n Args:\n nums: The input list of numbers.\n start_index: The starting index of the range (inclusive).\n end_index: The ending index of the range (inclusive).\n\n Returns:\n The sum of elements within the specified range. \n Returns 0 if the list is empty or indices are invalid.\n \"\"\"\n\n if not nums:\n return 0\n\n n = len(nums)\n if start_index < 0 or end_index < 0 or start_index >= n or end_index >= n or start_index > end_index:\n return 0 # Handle invalid indices\n\n total = 0\n for i in range(start_index, end_index + 1):\n total += nums[i]\n return total", "matching_cluster_idx": 4}, {"solution": "def sum_range_list(lst, start_index, end_index):\n \"\"\"\n Calculates the sum of elements in a list within a specified range of indices.\n\n Args:\n lst: The input list of numbers.\n start_index: The starting index (inclusive).\n end_index: The ending index (inclusive).\n\n Returns:\n The sum of elements within the specified range.\n Returns 0 if the list is empty or indices are invalid.\n \"\"\"\n\n if not lst:\n return 0\n\n n = len(lst)\n\n if not (0 <= start_index < n and 0 <= end_index < n and start_index <= end_index):\n return 0\n \n total = 0\n for i in range(start_index, end_index + 1):\n total += lst[i]\n return total", "matching_cluster_idx": 4}, {"solution": "def sum_range_list(nums, start_index, end_index):\n \"\"\"\n Calculates the sum of numbers within a specified range of a list.\n\n Args:\n nums: The input list of numbers.\n start_index: The starting index (inclusive) of the range.\n end_index: The ending index (inclusive) of the range.\n\n Returns:\n The sum of the numbers within the specified range. Returns 0 if the list is empty\n or if the indices are out of bounds.\n \"\"\"\n\n if not nums:\n return 0\n\n if start_index < 0 or end_index >= len(nums) or start_index > end_index:\n return 0\n \n total = 0\n for i in range(start_index, end_index + 1):\n total += nums[i]\n return total", "matching_cluster_idx": 4}, {"solution": "def sum_range_list(nums, start_index, end_index):\n \"\"\"\n Calculates the sum of elements within a specified range of a list.\n\n Args:\n nums: The input list of numbers.\n start_index: The starting index (inclusive) for the sum.\n end_index: The ending index (inclusive) for the sum.\n\n Returns:\n The sum of the elements within the specified range.\n Returns 0 if the list is empty or if the indices are invalid.\n \"\"\"\n\n if not nums:\n return 0\n\n n = len(nums)\n if start_index < 0 or end_index < 0 or start_index >= n or end_index >= n or start_index > end_index:\n return 0\n\n total = 0\n for i in range(start_index, end_index + 1):\n total += nums[i]\n return total", "matching_cluster_idx": 4}, {"solution": "def sum_range_list(nums: list[int], start: int, end: int) -> int:\n \"\"\"\n Calculates the sum of elements in a list within a specified range (inclusive).\n\n Args:\n nums: The input list of numbers.\n start: The starting index (inclusive).\n end: The ending index (inclusive).\n\n Returns:\n The sum of elements within the specified range.\n Returns 0 if the list is empty or indices are out of bounds.\n \"\"\"\n if not nums or start < 0 or end < 0 or start >= len(nums) or end >= len(nums) or start > end:\n return 0\n\n total = 0\n for i in range(start, end + 1):\n total += nums[i]\n return total", "matching_cluster_idx": 4}]}, "Mbpp/226": {"dps": 68.21705426356588, "dps_norm": 14.285714285714286, "pass@1": 100.0, "profiled": [{"solution": "def odd_values_string(str1):\n \"\"\"Removes characters at odd indices from a string.\n\n Args:\n str1: The input string.\n\n Returns:\n A new string with characters at odd indices removed.\n \"\"\"\n result = \"\"\n for i in range(len(str1)):\n if i % 2 == 0:\n result += str1[i]\n return result", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(str1):\n \"\"\"Removes characters at odd indices from a string.\n\n Args:\n str1: The input string.\n\n Returns:\n A new string with characters at odd indices removed.\n \"\"\"\n result = \"\"\n for i in range(len(str1)):\n if i % 2 == 0:\n result += str1[i]\n return result", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(str1):\n result = \"\"\n for i in range(len(str1)):\n if i % 2 == 0:\n result = result + str1[i]\n return result", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(str1):\n \"\"\"Removes characters at odd indices from a string.\n\n Args:\n str1: The input string.\n\n Returns:\n A new string with characters at odd indices removed.\n \"\"\"\n result = \"\"\n for i in range(len(str1)):\n if i % 2 == 0:\n result += str1[i]\n return result", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(input_string):\n \"\"\"\n Removes characters at odd indices from a string.\n\n Args:\n input_string: The input string.\n\n Returns:\n A new string with characters at odd indices removed.\n \"\"\"\n result = \"\"\n for i in range(len(input_string)):\n if i % 2 == 0:\n result += input_string[i]\n return result", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(str1):\n \"\"\"Removes characters at odd indices from a string.\n\n Args:\n str1: The input string.\n\n Returns:\n A new string with characters at odd indices removed.\n \"\"\"\n result = \"\"\n for i in range(len(str1)):\n if i % 2 == 0:\n result += str1[i]\n return result", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(str1):\n \"\"\"Removes characters at odd indices from a string.\n\n Args:\n str1: The input string.\n\n Returns:\n A new string with characters at odd indices removed.\n \"\"\"\n result = \"\"\n for i in range(len(str1)):\n if i % 2 == 0:\n result += str1[i]\n return result", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(str1):\n \"\"\"\n Removes characters at odd indices from a string.\n\n Args:\n str1: The input string.\n\n Returns:\n A new string with characters at odd indices removed.\n \"\"\"\n result = \"\"\n for i in range(len(str1)):\n if i % 2 == 0:\n result += str1[i]\n return result", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(str1):\n \"\"\"\n Removes characters at odd indices from a string.\n\n Args:\n str1: The input string.\n\n Returns:\n A new string with characters at odd indices removed.\n \"\"\"\n result = \"\"\n for i in range(len(str1)):\n if i % 2 == 0:\n result += str1[i]\n return result", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(str1):\n \"\"\"Removes characters at odd indices from a string.\n\n Args:\n str1: The input string.\n\n Returns:\n The string with characters at odd indices removed.\n \"\"\"\n result = \"\"\n for i in range(len(str1)):\n if i % 2 == 0:\n result += str1[i]\n return result", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(str1):\n \"\"\"Removes characters at odd indices from a string.\n\n Args:\n str1: The input string.\n\n Returns:\n A new string with characters at odd indices removed.\n \"\"\"\n result = \"\"\n for i in range(len(str1)):\n if i % 2 == 0:\n result += str1[i]\n return result", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(str1):\n \"\"\"Removes characters at odd indices from a string.\n\n Args:\n str1: The input string.\n\n Returns:\n A new string with characters at odd indices removed.\n \"\"\"\n result = \"\"\n for i in range(len(str1)):\n if i % 2 == 0:\n result += str1[i]\n return result", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(str1):\n \"\"\"Removes characters at odd indices from a string.\n\n Args:\n str1: The input string.\n\n Returns:\n A new string with characters at odd indices removed.\n \"\"\"\n result = \"\"\n for i in range(len(str1)):\n if i % 2 == 0:\n result += str1[i]\n return result", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(str1):\n \"\"\"Removes characters at odd indices from a string.\n\n Args:\n str1: The input string.\n\n Returns:\n A new string with characters at odd indices removed.\n \"\"\"\n result = \"\"\n for i in range(len(str1)):\n if i % 2 == 0:\n result += str1[i]\n return result", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(str1):\n \"\"\"Removes characters at odd indices from a string.\n\n Args:\n str1: The input string.\n\n Returns:\n A new string with characters at odd indices removed.\n \"\"\"\n result = \"\"\n for i in range(len(str1)):\n if i % 2 == 0:\n result += str1[i]\n return result", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(str1):\n \"\"\"Removes characters at odd indices from a string.\n\n Args:\n str1: The input string.\n\n Returns:\n A new string with characters at odd indices removed.\n \"\"\"\n result = \"\"\n for i in range(len(str1)):\n if i % 2 == 0:\n result += str1[i]\n return result", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(str1):\n \"\"\"Removes characters at odd indices from a string.\n\n Args:\n str1: The input string.\n\n Returns:\n A new string with characters at odd indices removed.\n \"\"\"\n result = \"\"\n for i in range(len(str1)):\n if i % 2 == 0:\n result += str1[i]\n return result", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(str1):\n \"\"\"Removes characters at odd indices from a string.\n\n Args:\n str1: The input string.\n\n Returns:\n A new string with characters at odd indices removed.\n \"\"\"\n result = \"\"\n for i in range(len(str1)):\n if i % 2 == 0:\n result += str1[i]\n return result", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(str1):\n \"\"\"Removes characters at odd indices from a string.\n\n Args:\n str1: The input string.\n\n Returns:\n A new string with characters at odd indices removed.\n \"\"\"\n result = \"\"\n for i in range(len(str1)):\n if i % 2 == 0:\n result += str1[i]\n return result", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(str1):\n \"\"\"Removes characters at odd indices from a string.\n\n Args:\n str1: The input string.\n\n Returns:\n The string with characters at odd indices removed.\n \"\"\"\n result = \"\"\n for i in range(len(str1)):\n if i % 2 == 0:\n result += str1[i]\n return result", "matching_cluster_idx": 0}]}, "Mbpp/230": {"dps": 95.95238095238095, "dps_norm": 98.125, "pass@1": 100.0, "profiled": [{"solution": "def replace_blank(input_string, replacement_char):\n \"\"\"Replaces spaces in a string with a specified character.\n\n Args:\n input_string: The string to modify.\n replacement_char: The character to replace spaces with.\n\n Returns:\n The modified string with spaces replaced.\n \"\"\"\n return input_string.replace(\" \", replacement_char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string, replacement_char):\n \"\"\"Replaces spaces in a string with a given character.\n\n Args:\n input_string: The string to modify.\n replacement_char: The character to replace spaces with.\n\n Returns:\n The modified string with spaces replaced.\n \"\"\"\n return input_string.replace(\" \", replacement_char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string, char):\n \"\"\"Replaces spaces in a string with a given character.\n\n Args:\n input_string: The string to modify.\n char: The character to replace spaces with.\n\n Returns:\n The modified string.\n \"\"\"\n return input_string.replace(\" \", char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string, replacement_char):\n \"\"\"Replaces spaces in a string with a given character.\n\n Args:\n input_string: The string to modify.\n replacement_char: The character to replace spaces with.\n\n Returns:\n The modified string with spaces replaced.\n \"\"\"\n return input_string.replace(\" \", replacement_char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string, replacement_char):\n \"\"\"Replaces spaces in a string with a given character.\n\n Args:\n input_string: The string to modify.\n replacement_char: The character to replace spaces with.\n\n Returns:\n The modified string.\n \"\"\"\n return input_string.replace(\" \", replacement_char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string, replacement_char):\n \"\"\"Replaces spaces in a string with a given character.\n\n Args:\n input_string: The string to modify.\n replacement_char: The character to replace spaces with.\n\n Returns:\n The modified string with spaces replaced.\n \"\"\"\n return input_string.replace(\" \", replacement_char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string, replacement_char):\n \"\"\"\n Replaces blank spaces in a string with a specified character.\n\n Args:\n input_string: The string to modify.\n replacement_char: The character to replace spaces with.\n\n Returns:\n The modified string with spaces replaced.\n \"\"\"\n modified_string = \"\"\n for char in input_string:\n if char == \" \":\n modified_string += replacement_char\n else:\n modified_string += char\n return modified_string", "matching_cluster_idx": 4}, {"solution": "def replace_blank(input_string, replacement_char):\n \"\"\"Replaces blank spaces in a string with a specified character.\n\n Args:\n input_string: The string to modify.\n replacement_char: The character to replace spaces with.\n\n Returns:\n The modified string with spaces replaced.\n \"\"\"\n return input_string.replace(\" \", replacement_char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string, replacement_char):\n \"\"\"Replaces spaces in a string with a given character.\n\n Args:\n input_string: The string to modify.\n replacement_char: The character to replace spaces with.\n\n Returns:\n The modified string.\n \"\"\"\n return input_string.replace(\" \", replacement_char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string, char):\n \"\"\"Replaces spaces in a string with a given character.\n\n Args:\n input_string: The string to modify.\n char: The character to replace spaces with.\n\n Returns:\n The modified string with spaces replaced.\n \"\"\"\n return input_string.replace(\" \", char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string, replacement_char):\n \"\"\"Replaces spaces in a string with a given character.\n\n Args:\n input_string: The string to modify.\n replacement_char: The character to replace spaces with.\n\n Returns:\n The modified string with spaces replaced.\n \"\"\"\n return input_string.replace(\" \", replacement_char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string, replacement_char):\n \"\"\"Replaces spaces in a string with a given character.\n\n Args:\n input_string: The string to modify.\n replacement_char: The character to replace spaces with.\n\n Returns:\n The modified string with spaces replaced.\n \"\"\"\n return input_string.replace(\" \", replacement_char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string, replacement_char):\n \"\"\"Replaces spaces in a string with a given character.\n\n Args:\n input_string: The string to modify.\n replacement_char: The character to replace spaces with.\n\n Returns:\n The modified string.\n \"\"\"\n return input_string.replace(\" \", replacement_char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string, replacement_char):\n \"\"\"Replaces spaces in a string with a given character.\n\n Args:\n input_string: The string to modify.\n replacement_char: The character to replace spaces with.\n\n Returns:\n The modified string with spaces replaced.\n \"\"\"\n return input_string.replace(\" \", replacement_char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string, char):\n \"\"\"Replaces blank spaces in a string with a given character.\n\n Args:\n input_string: The string to modify.\n char: The character to replace spaces with.\n\n Returns:\n The modified string with spaces replaced by the character.\n \"\"\"\n\n return input_string.replace(\" \", char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string, replacement_char):\n \"\"\"Replaces spaces in a string with a given character.\n\n Args:\n input_string: The string to modify.\n replacement_char: The character to replace spaces with.\n\n Returns:\n The modified string.\n \"\"\"\n return input_string.replace(\" \", replacement_char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string, replacement_char):\n \"\"\"Replaces spaces in a string with a given character.\n\n Args:\n input_string: The string to modify.\n replacement_char: The character to replace spaces with.\n\n Returns:\n The modified string.\n \"\"\"\n return input_string.replace(\" \", replacement_char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(string, char):\n \"\"\"Replaces spaces in a string with a given character.\n\n Args:\n string: The input string.\n char: The character to replace spaces with.\n\n Returns:\n The modified string with spaces replaced.\n \"\"\"\n return string.replace(\" \", char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string, replacement_char):\n \"\"\"Replaces spaces in a string with a given character.\n\n Args:\n input_string: The string to modify.\n replacement_char: The character to replace spaces with.\n\n Returns:\n The modified string.\n \"\"\"\n return input_string.replace(\" \", replacement_char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string, replacement_char):\n \"\"\"Replaces spaces in a string with a given character.\n\n Args:\n input_string: The string to modify.\n replacement_char: The character to replace spaces with.\n\n Returns:\n The modified string with spaces replaced.\n \"\"\"\n return input_string.replace(\" \", replacement_char)", "matching_cluster_idx": 7}]}, "Mbpp/239": {"dps": 71.55172413793103, "dps_norm": 75.0, "pass@1": 93.0, "profiled": [{"solution": "def get_total_number_of_sequences(m, n):\n \"\"\"\n Calculates the number of valid sequences.\n\n Args:\n m: The upper bound for the elements in the sequence.\n n: The length of the sequence.\n\n Returns:\n The total number of valid sequences.\n \"\"\"\n\n dp = {} # Memoization to store results of subproblems\n\n def count_sequences(current_element, remaining_length):\n if remaining_length == 0:\n return 1\n\n if (current_element, remaining_length) in dp:\n return dp[(current_element, remaining_length)]\n \n count = 0\n for next_element in range(2 * current_element, m + 1):\n count += count_sequences(next_element, remaining_length - 1)\n\n dp[(current_element, remaining_length)] = count\n return count\n\n total_count = 0\n for start_element in range(1, m + 1):\n total_count += count_sequences(start_element, n - 1)\n return total_count", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n \"\"\"\n Calculates the number of valid sequences.\n\n Args:\n m: The upper bound for the elements in the sequence.\n n: The length of the sequence.\n\n Returns:\n The total number of valid sequences.\n \"\"\"\n\n dp = {} # Memoization dictionary\n\n def count_sequences(current_element, remaining_length):\n if remaining_length == 0:\n return 1\n\n if (current_element, remaining_length) in dp:\n return dp[(current_element, remaining_length)]\n\n count = 0\n for next_element in range(2 * current_element, m + 1):\n count += count_sequences(next_element, remaining_length - 1)\n\n dp[(current_element, remaining_length)] = count\n return count\n\n total_count = 0\n for first_element in range(1, m + 1): # Iterate through possible first elements\n total_count += count_sequences(first_element, n - 1)\n\n return total_count", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n \"\"\"\n Calculates the number of valid sequences.\n\n Args:\n m: The upper bound for each element in the sequence.\n n: The length of the sequence.\n\n Returns:\n The total number of valid sequences.\n \"\"\"\n\n dp = {} # Memoization\n\n def count_sequences(current_n, prev_val):\n if current_n == n:\n return 1\n\n if (current_n, prev_val) in dp:\n return dp[(current_n, prev_val)]\n\n count = 0\n for current_val in range(2 * prev_val, m + 1):\n count += count_sequences(current_n + 1, current_val)\n\n dp[(current_n, prev_val)] = count\n return count\n \n total_count = 0\n for start_val in range(1, m + 1):\n total_count += count_sequences(1, start_val)\n\n return total_count", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n \"\"\"\n Calculates the number of valid sequences.\n\n Args:\n m: The upper bound for sequence elements.\n n: The length of the sequence.\n\n Returns:\n The total number of valid sequences.\n \"\"\"\n\n dp = {} # Memoization\n\n def count_sequences(current_element, remaining_length):\n if remaining_length == 0:\n return 1\n\n if (current_element, remaining_length) in dp:\n return dp[(current_element, remaining_length)]\n\n count = 0\n for next_element in range(2 * current_element, m + 1):\n count += count_sequences(next_element, remaining_length - 1)\n\n dp[(current_element, remaining_length)] = count\n return count\n\n total_count = 0\n for first_element in range(1, m + 1):\n total_count += count_sequences(first_element, n - 1)\n\n return total_count", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m: int, n: int) -> int:\n \"\"\"\n Calculates the number of valid sequences.\n\n Args:\n m: The upper bound for sequence elements.\n n: The length of the sequence.\n\n Returns:\n The total number of valid sequences.\n \"\"\"\n\n dp = {}\n\n def count_sequences(current_element, remaining_length):\n if remaining_length == 0:\n return 1\n\n if (current_element, remaining_length) in dp:\n return dp[(current_element, remaining_length)]\n\n count = 0\n for next_element in range(2 * current_element, m + 1):\n count += count_sequences(next_element, remaining_length - 1)\n\n dp[(current_element, remaining_length)] = count\n return count\n\n total_count = 0\n for first_element in range(1, m + 1):\n total_count += count_sequences(first_element, n - 1)\n\n return total_count", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n \"\"\"\n Calculates the number of valid sequences.\n\n Args:\n m: The upper bound for the elements in the sequence.\n n: The length of the sequence.\n\n Returns:\n The total number of valid sequences.\n \"\"\"\n\n count = 0\n\n def backtrack(current_sequence):\n nonlocal count\n\n if len(current_sequence) == n:\n count += 1\n return\n\n if not current_sequence:\n for i in range(1, m + 1):\n backtrack([i])\n else:\n last_element = current_sequence[-1]\n for i in range(2 * last_element, m + 1):\n backtrack(current_sequence + [i])\n\n backtrack([])\n return count", "matching_cluster_idx": 3}, {"solution": "def get_total_number_of_sequences(m: int, n: int) -> int:\n \"\"\"\n Given positive integers m and n, finds the number of possible sequences of length n, such that each element is a positive integer and is greater than or equal to twice the previous element but less than or equal to m.\n\n For example:\n get_total_number_of_sequences(10, 4) == 4\n \"\"\"\n\n dp = {}\n\n def count_sequences(current_element, remaining_length):\n if remaining_length == 0:\n return 1\n\n if (current_element, remaining_length) in dp:\n return dp[(current_element, remaining_length)]\n\n count = 0\n for next_element in range(2 * current_element, m + 1):\n count += count_sequences(next_element, remaining_length - 1)\n\n dp[(current_element, remaining_length)] = count\n return count\n\n total_count = 0\n for first_element in range(1, m + 1):\n total_count += count_sequences(first_element, n - 1)\n\n\n return total_count", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n \"\"\"\n Calculates the number of valid sequences.\n\n Args:\n m: The upper bound for the sequence elements.\n n: The length of the sequence.\n\n Returns:\n The total number of valid sequences.\n \"\"\"\n\n dp = {} # Memoization\n\n def count_sequences(current_element, remaining_length):\n if remaining_length == 0:\n return 1\n\n if (current_element, remaining_length) in dp:\n return dp[(current_element, remaining_length)]\n\n count = 0\n for next_element in range(2 * current_element, m + 1):\n count += count_sequences(next_element, remaining_length - 1)\n\n dp[(current_element, remaining_length)] = count\n return count\n\n total_count = 0\n for start_element in range(1, m + 1):\n total_count += count_sequences(start_element, n - 1)\n\n return total_count", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n \"\"\"\n Calculates the number of valid sequences.\n\n Args:\n m: The upper bound for the elements in the sequence.\n n: The length of the sequence.\n\n Returns:\n The total number of valid sequences.\n \"\"\"\n\n count = 0\n\n def backtrack(current_sequence):\n nonlocal count\n if len(current_sequence) == n:\n count += 1\n return\n\n if not current_sequence:\n for i in range(1, m + 1):\n backtrack([i])\n else:\n last_element = current_sequence[-1]\n for i in range(2 * last_element, m + 1):\n backtrack(current_sequence + [i])\n\n backtrack([])\n return count", "matching_cluster_idx": 3}, {"solution": "from functools import lru_cache\ndef get_total_number_of_sequences(m, n):\n \"\"\"\n Calculates the number of valid sequences.\n\n Args:\n m: The upper bound for the elements in the sequence.\n n: The length of the sequence.\n\n Returns:\n The total number of valid sequences.\n \"\"\"\n\n count = 0\n\n def find_sequences(current_sequence):\n nonlocal count\n if len(current_sequence) == n:\n count += 1\n return\n\n if not current_sequence:\n for i in range(1, m + 1):\n find_sequences([i])\n else:\n last_element = current_sequence[-1]\n for i in range(2 * last_element, m + 1):\n find_sequences(current_sequence + [i])\n\n find_sequences([])\n return count", "matching_cluster_idx": 3}, {"solution": "def get_total_number_of_sequences(m, n):\n \"\"\"\n Calculates the number of valid sequences.\n\n Args:\n m: The upper bound for the elements.\n n: The length of the sequence.\n\n Returns:\n The total number of valid sequences.\n \"\"\"\n\n dp = {} # Memoization\n\n def count_sequences(current_index, previous_element):\n if current_index == n:\n return 1\n\n if (current_index, previous_element) in dp:\n return dp[(current_index, previous_element)]\n\n count = 0\n for current_element in range(2 * previous_element, m + 1):\n count += count_sequences(current_index + 1, current_element)\n\n dp[(current_index, previous_element)] = count\n return count\n\n total_count = 0\n for first_element in range(1, m + 1):\n total_count += count_sequences(1, first_element)\n \n return total_count", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n \"\"\"\n Calculates the number of valid sequences.\n\n Args:\n m: The upper bound for the elements in the sequence.\n n: The length of the sequence.\n\n Returns:\n The total number of valid sequences.\n \"\"\"\n\n dp = {}\n\n def count_sequences(current_element, remaining_length):\n if remaining_length == 0:\n return 1\n\n if (current_element, remaining_length) in dp:\n return dp[(current_element, remaining_length)]\n\n count = 0\n for next_element in range(2 * current_element, m + 1):\n count += count_sequences(next_element, remaining_length - 1)\n\n dp[(current_element, remaining_length)] = count\n return count\n\n total_count = 0\n for first_element in range(1, m + 1):\n total_count += count_sequences(first_element, n - 1)\n\n return total_count", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n \"\"\"\n Calculates the number of valid sequences.\n\n Args:\n m: The upper bound for sequence elements.\n n: The length of the sequences.\n\n Returns:\n The total number of valid sequences.\n \"\"\"\n\n dp = {} # Memoization to store intermediate results\n\n def count_sequences(current_element, remaining_length):\n if remaining_length == 0:\n return 1\n\n if (current_element, remaining_length) in dp:\n return dp[(current_element, remaining_length)]\n\n count = 0\n for next_element in range(2 * current_element, m + 1):\n count += count_sequences(next_element, remaining_length - 1)\n\n dp[(current_element, remaining_length)] = count\n return count\n\n total_count = 0\n for first_element in range(1, m + 1):\n total_count += count_sequences(first_element, n - 1)\n \n return total_count", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n \"\"\"\n Calculates the number of valid sequences.\n\n Args:\n m: The upper bound for the elements.\n n: The length of the sequences.\n\n Returns:\n The total number of valid sequences.\n \"\"\"\n\n dp = {} # Memoization to store intermediate results\n\n def count_sequences(current_element, remaining_length):\n if remaining_length == 0:\n return 1\n \n if (current_element, remaining_length) in dp:\n return dp[(current_element, remaining_length)]\n\n count = 0\n for next_element in range(2 * current_element, m + 1):\n count += count_sequences(next_element, remaining_length - 1)\n\n dp[(current_element, remaining_length)] = count\n return count\n\n total_count = 0\n for first_element in range(1, m + 1):\n total_count += count_sequences(first_element, n - 1)\n\n return total_count", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n \"\"\"\n Calculates the number of valid sequences.\n\n Args:\n m: The upper bound for the elements in the sequence.\n n: The length of the sequence.\n\n Returns:\n The total number of valid sequences.\n \"\"\"\n\n dp = {} # Memoization to store results of subproblems\n\n def count_sequences(current_element, remaining_length):\n if remaining_length == 0:\n return 1\n\n if (current_element, remaining_length) in dp:\n return dp[(current_element, remaining_length)]\n\n count = 0\n for next_element in range(2 * current_element, m + 1):\n count += count_sequences(next_element, remaining_length - 1)\n\n dp[(current_element, remaining_length)] = count\n return count\n\n total_count = 0\n for first_element in range(1, m + 1): # Iterate through possible first elements\n total_count += count_sequences(first_element, n - 1)\n\n return total_count", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n \"\"\"\n Calculates the number of valid sequences.\n\n Args:\n m: The upper bound for each element.\n n: The length of the sequence.\n\n Returns:\n The total number of valid sequences.\n \"\"\"\n\n dp = {}\n\n def count_sequences(prev, length):\n if length == 0:\n return 1\n \n if (prev, length) in dp:\n return dp[(prev, length)]\n\n count = 0\n for current in range(2 * prev, m + 1):\n count += count_sequences(current, length - 1)\n \n dp[(prev, length)] = count\n return count\n\n total_count = 0\n for start in range(1, m + 1):\n if 2**(n-1) <= m:\n total_count += count_sequences(start, n - 1)\n\n return total_count", "matching_cluster_idx": 9}, {"solution": "def get_total_number_of_sequences(m, n):\n \"\"\"\n Calculates the number of valid sequences.\n\n Args:\n m: The upper bound for the elements in the sequence.\n n: The length of the sequence.\n\n Returns:\n The total number of valid sequences.\n \"\"\"\n\n dp = {} # Memoization dictionary\n\n def count_sequences(current_n, previous_element):\n if current_n == n:\n return 1\n\n if (current_n, previous_element) in dp:\n return dp[(current_n, previous_element)]\n\n count = 0\n for current_element in range(2 * previous_element, m + 1):\n count += count_sequences(current_n + 1, current_element)\n\n dp[(current_n, previous_element)] = count\n return count\n\n total_count = 0\n for first_element in range(1, m + 1):\n total_count += count_sequences(1, first_element)\n\n return total_count", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n \"\"\"\n Calculates the number of valid sequences.\n\n Args:\n m: The upper bound for sequence elements.\n n: The length of the sequences.\n\n Returns:\n The total number of valid sequences.\n \"\"\"\n\n dp = {} # Memoization dictionary\n\n def count_sequences(current_element, remaining_length):\n if remaining_length == 0:\n return 1\n\n if (current_element, remaining_length) in dp:\n return dp[(current_element, remaining_length)]\n\n count = 0\n for next_element in range(2 * current_element, m + 1):\n count += count_sequences(next_element, remaining_length - 1)\n\n dp[(current_element, remaining_length)] = count\n return count\n\n total_count = 0\n for first_element in range(1, m + 1):\n total_count += count_sequences(first_element, n - 1)\n \n return total_count", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n \"\"\"\n Calculates the number of valid sequences of length n with elements <= m.\n\n Args:\n m: The upper bound for the elements in the sequence.\n n: The length of the sequence.\n\n Returns:\n The total number of valid sequences.\n \"\"\"\n\n dp = {} # Memoization table\n\n def count_sequences(current_element, length_remaining):\n if length_remaining == 0:\n return 1\n\n if (current_element, length_remaining) in dp:\n return dp[(current_element, length_remaining)]\n\n count = 0\n for next_element in range(2 * current_element, m + 1):\n count += count_sequences(next_element, length_remaining - 1)\n\n dp[(current_element, length_remaining)] = count\n return count\n\n total_count = 0\n for first_element in range(1, m + 1):\n total_count += count_sequences(first_element, n - 1)\n\n return total_count", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n \"\"\"\n Calculates the number of valid sequences.\n\n Args:\n m: The upper bound for sequence elements.\n n: The length of the sequences.\n\n Returns:\n The total number of valid sequences.\n \"\"\"\n\n dp = {} # Memoization to store results\n\n def count_sequences(current_element, remaining_length):\n if remaining_length == 0:\n return 1\n\n if (current_element, remaining_length) in dp:\n return dp[(current_element, remaining_length)]\n\n count = 0\n for next_element in range(2 * current_element, m + 1):\n count += count_sequences(next_element, remaining_length - 1)\n\n dp[(current_element, remaining_length)] = count\n return count\n\n total_count = 0\n for first_element in range(1, m + 1):\n total_count += count_sequences(first_element, n - 1)\n\n return total_count\nm = 10\nn = 4", "matching_cluster_idx": 7}]}, "Mbpp/240": {"dps": 67.6219512195122, "dps_norm": 78.33333333333333, "pass@1": 100.0, "profiled": [{"solution": "def replace_list(list1, list2):\n \"\"\"Replaces the last element of list1 with the elements of list2.\"\"\"\n\n if not list1: # Handle empty list1\n return list2\n \n return list1[:-1] + list2", "matching_cluster_idx": 5}, {"solution": "def replace_list(list1, list2):\n \"\"\"Replaces the last element of list1 with the elements of list2.\"\"\"\n\n list1.pop() # Remove the last element\n list1.extend(list2) # Add the elements of list2\n return list1", "matching_cluster_idx": 8}, {"solution": "def replace_list(list1, list2):\n \"\"\"Replaces the last element of list1 with the elements of list2.\"\"\"\n\n list1.pop() # Remove the last element\n list1.extend(list2) # Add the elements of list2\n return list1", "matching_cluster_idx": 8}, {"solution": "def replace_list(list1, list2):\n \"\"\"Replaces the last element of list1 with the elements of list2.\n\n Args:\n list1: The first list.\n list2: The second list.\n\n Returns:\n A new list with the last element of list1 replaced by the elements of list2.\n \"\"\"\n new_list = list1[:-1] + list2 # Create a new list to avoid modifying the original list1\n return new_list", "matching_cluster_idx": 5}, {"solution": "def replace_list(list1, list2):\n \"\"\"\n Replaces the last element of list1 with the elements of list2.\n\n Args:\n list1: The first list.\n list2: The second list.\n\n Returns:\n A new list with the last element of list1 replaced by the elements of list2.\n \"\"\"\n new_list = list1[:-1] # Create a new list excluding the last element of list1\n new_list.extend(list2) # Extend the new list with the elements of list2\n return new_list", "matching_cluster_idx": 6}, {"solution": "def replace_list(list1, list2):\n \"\"\"Replaces the last element of list1 with the elements of list2.\"\"\"\n\n list1.pop() # Remove the last element\n list1.extend(list2) # Add the elements of list2\n return list1", "matching_cluster_idx": 8}, {"solution": "def replace_list(list1, list2):\n \"\"\"Replaces the last element of list1 with the elements of list2.\n\n Args:\n list1: The first list.\n list2: The second list.\n\n Returns:\n A new list with the last element of list1 replaced by list2.\n \"\"\"\n\n new_list = list1[:-1] # Create a new list containing all elements of list1 except the last\n new_list.extend(list2) # Extend the new list with the elements of list2\n return new_list", "matching_cluster_idx": 6}, {"solution": "def replace_list(list1, list2):\n \"\"\"\n Replaces the last element of list1 with the elements of list2.\n\n Args:\n list1: The first list.\n list2: The second list.\n\n Returns:\n A new list with the last element of list1 replaced by the elements of list2.\n \"\"\"\n list1_copy = list1[:-1] # Create a copy up to the second to last element\n list1_copy.extend(list2) # Extend the copy with the elements of list2\n return list1_copy\nlist1 = [1, 2, 3]\nlist2 = [4, 5, 6]", "matching_cluster_idx": 6}, {"solution": "def replace_list(list1, list2):\n \"\"\"Replaces the last element of list1 with the elements of list2.\n\n Args:\n list1: The first list.\n list2: The second list.\n\n Returns:\n A new list with the last element of list1 replaced by the elements of list2.\n \"\"\"\n\n new_list = list1[:-1] # Create a new list with all elements of list1 except the last one\n new_list.extend(list2) # Extend the new list with the elements of list2\n return new_list", "matching_cluster_idx": 6}, {"solution": "def replace_list(list1, list2):\n \"\"\"\n Replaces the last element of list1 with the elements of list2.\n\n Args:\n list1: The first list.\n list2: The second list.\n\n Returns:\n A new list with the last element of list1 replaced by the elements of list2.\n \"\"\"\n list1.pop() # Remove the last element\n list1.extend(list2) # Add the elements of list2\n return list1", "matching_cluster_idx": 8}, {"solution": "def replace_list(list1, list2):\n \"\"\"Replaces the last element of list1 with the elements of list2.\n\n Args:\n list1: The first list.\n list2: The second list.\n\n Returns:\n A new list with the last element of list1 replaced by the elements of list2.\n \"\"\"\n\n new_list = list1[:-1] + list2 # Create a new list to avoid modifying the original list1\n return new_list", "matching_cluster_idx": 5}, {"solution": "def replace_list(list1, list2):\n \"\"\"Replaces the last element of list1 with the elements of list2.\n\n Args:\n list1: The first list.\n list2: The second list.\n\n Returns:\n A new list with the last element of list1 replaced by the elements of list2.\n \"\"\"\n\n new_list = list1[:-1] + list2 # Slice list1 to exclude last element and concatenate with list2\n return new_list", "matching_cluster_idx": 5}, {"solution": "def replace_list(list1, list2):\n \"\"\"\n Replaces the last element of list1 with the elements of list2.\n\n Args:\n list1: The first list.\n list2: The second list.\n\n Returns:\n A new list with the last element of list1 replaced by list2.\n Returns list1 if it is empty.\n \"\"\"\n if not list1:\n return list1\n \n new_list = list1[:-1] # Create a new list excluding the last element\n new_list.extend(list2) # Add the elements of list2\n return new_list", "matching_cluster_idx": 6}, {"solution": "def replace_list(list1, list2):\n \"\"\"Replaces the last element of list1 with the elements of list2.\n\n Args:\n list1: The first list.\n list2: The second list.\n\n Returns:\n A new list with the last element of list1 replaced by list2.\n Returns list1 if it's empty.\n \"\"\"\n if not list1:\n return list1\n \n return list1[:-1] + list2\nlist1 = [1, 2, 3, 4, 5]\nlist2 = [6, 7, 8]", "matching_cluster_idx": 5}, {"solution": "def replace_list(list1, list2):\n \"\"\"Replaces the last element of list1 with the elements of list2.\n\n Args:\n list1: The first list.\n list2: The second list.\n\n Returns:\n A new list with the last element of list1 replaced by the elements of list2.\n \"\"\"\n\n new_list = list1[:-1] # Create a new list containing all elements of list1 except the last one\n new_list.extend(list2) # Extend the new list with the elements of list2\n return new_list", "matching_cluster_idx": 6}, {"solution": "def replace_list(list1, list2):\n \"\"\"Replaces the last element of list1 with the elements of list2.\n\n Args:\n list1: The first list.\n list2: The second list.\n\n Returns:\n A new list with the last element of list1 replaced by list2.\n Returns list1 if it's empty.\n \"\"\"\n\n if not list1:\n return list1\n \n new_list = list1[:-1] + list2\n return new_list", "matching_cluster_idx": 5}, {"solution": "def replace_list(list1, list2):\n \"\"\"Replaces the last element of list1 with the elements of list2.\"\"\"\n\n list1.pop() # Remove the last element of list1\n list1.extend(list2) # Extend list1 with the elements of list2\n return list1", "matching_cluster_idx": 8}, {"solution": "def replace_list(list1, list2):\n \"\"\"\n Replaces the last element of list1 with the elements of list2.\n\n Args:\n list1: The first list.\n list2: The second list.\n\n Returns:\n A new list with the last element of list1 replaced by the elements of list2.\n \"\"\"\n\n new_list = list1[:-1] + list2 # Create a new list to avoid modifying the original list1\n return new_list", "matching_cluster_idx": 5}, {"solution": "def replace_list(list1, list2):\n \"\"\"Replaces the last element of list1 with the elements of list2.\n\n Args:\n list1: The first list.\n list2: The second list.\n\n Returns:\n A new list with the last element of list1 replaced by the elements of list2.\n \"\"\"\n new_list = list1[:-1] + list2\n return new_list", "matching_cluster_idx": 5}, {"solution": "def replace_list(list1, list2):\n \"\"\"Replaces the last element of list1 with the elements of list2.\n\n Args:\n list1: The first list.\n list2: The second list.\n\n Returns:\n A new list with the last element of list1 replaced by list2.\n \"\"\"\n\n new_list = list1[:-1] + list2 # Create a new list by slicing list1 up to (but not including) the last element, then concatenating list2\n return new_list", "matching_cluster_idx": 5}]}, "Mbpp/251": {"dps": 91.95402298850576, "dps_norm": 77.77777777777777, "pass@1": 100.0, "profiled": [{"solution": "def insert_element(lst, element):\n \"\"\"Inserts an element before each existing element in a list.\n\n Args:\n lst: The input list.\n element: The element to insert.\n\n Returns:\n A new list with the element inserted before each original element.\n \"\"\"\n new_lst = []\n for item in lst:\n new_lst.append(element)\n new_lst.append(item)\n return new_lst", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n \"\"\"Inserts an element before each element in a list.\n\n Args:\n lst: The input list.\n element: The element to insert.\n\n Returns:\n A new list with the element inserted before each original element.\n \"\"\"\n new_lst = []\n for item in lst:\n new_lst.append(element)\n new_lst.append(item)\n return new_lst", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n \"\"\"Inserts an element before each element in a list.\n\n Args:\n lst: The input list.\n element: The element to insert.\n\n Returns:\n A new list with the element inserted before each original element.\n \"\"\"\n new_list = []\n for item in lst:\n new_list.append(element)\n new_list.append(item)\n return new_list", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n \"\"\"Inserts an element before each element in a list.\n\n Args:\n lst: The input list.\n element: The element to insert.\n\n Returns:\n A new list with the element inserted before each original element.\n \"\"\"\n new_lst = []\n for item in lst:\n new_lst.append(element)\n new_lst.append(item)\n return new_lst", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n \"\"\"\n Inserts an element before each element in a list.\n\n Args:\n lst: The input list.\n element: The element to insert.\n\n Returns:\n A new list with the element inserted before each original element.\n \"\"\"\n\n new_lst = []\n for item in lst:\n new_lst.append(element)\n new_lst.append(item)\n return new_lst", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n \"\"\"\n Inserts an element before each element in a list.\n\n Args:\n lst: The input list.\n element: The element to insert.\n\n Returns:\n A new list with the element inserted before each original element.\n \"\"\"\n new_lst = []\n for item in lst:\n new_lst.append(element)\n new_lst.append(item)\n return new_lst", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n \"\"\"Inserts an element before each element in a list.\n\n Args:\n lst: The input list.\n element: The element to insert.\n\n Returns:\n A new list with the element inserted before each original element.\n \"\"\"\n\n new_lst = []\n for item in lst:\n new_lst.append(element)\n new_lst.append(item)\n return new_lst", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n \"\"\"Inserts an element before each element in a list.\n\n Args:\n lst: The input list.\n element: The element to insert.\n\n Returns:\n A new list with the element inserted before each original element.\n \"\"\"\n new_lst = []\n for item in lst:\n new_lst.append(element)\n new_lst.append(item)\n return new_lst", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n \"\"\"Inserts an element before each element in a list.\n\n Args:\n lst: The input list.\n element: The element to insert.\n\n Returns:\n A new list with the element inserted before each original element.\n \"\"\"\n new_lst = []\n for item in lst:\n new_lst.append(element)\n new_lst.append(item)\n return new_lst", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n \"\"\"\n Inserts an element before each element in a list.\n\n Args:\n lst: The input list.\n element: The element to insert.\n\n Returns:\n A new list with the element inserted before each original element.\n \"\"\"\n\n new_lst = []\n for item in lst:\n new_lst.append(element)\n new_lst.append(item)\n return new_lst", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n \"\"\"\n Inserts an element before each element in a list.\n\n Args:\n lst: The input list.\n element: The element to insert.\n\n Returns:\n A new list with the element inserted before each original element.\n \"\"\"\n new_lst = []\n for item in lst:\n new_lst.append(element)\n new_lst.append(item)\n return new_lst", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n \"\"\"\n Inserts an element before each element in a list.\n\n Args:\n lst: The input list.\n element: The element to insert.\n\n Returns:\n A new list with the element inserted before each original element.\n \"\"\"\n new_lst = []\n for item in lst:\n new_lst.append(element)\n new_lst.append(item)\n return new_lst", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n \"\"\"\n Inserts an element before each element in a list.\n\n Args:\n lst: The input list.\n element: The element to insert.\n\n Returns:\n A new list with the element inserted before each original element.\n \"\"\"\n new_lst = []\n for item in lst:\n new_lst.append(element)\n new_lst.append(item)\n return new_lst", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n \"\"\"\n Inserts an element before each element in a list.\n\n Args:\n lst: The input list.\n element: The element to insert.\n\n Returns:\n A new list with the element inserted before each original element.\n \"\"\"\n new_list = []\n for item in lst:\n new_list.append(element)\n new_list.append(item)\n return new_list\nmy_list = ['Red', 'Green', 'Black']\nnew_list = insert_element(my_list, 'c')", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n \"\"\"\n Inserts an element before each element in a list.\n\n Args:\n lst: The input list.\n element: The element to insert.\n\n Returns:\n A new list with the element inserted before each original element.\n \"\"\"\n new_lst = []\n for item in lst:\n new_lst.append(element)\n new_lst.append(item)\n return new_lst", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n \"\"\"Inserts an element before each element in a list.\n\n Args:\n lst: The input list.\n element: The element to insert.\n\n Returns:\n A new list with the element inserted before each original element.\n \"\"\"\n new_list = []\n for item in lst:\n new_list.append(element)\n new_list.append(item)\n return new_list\nmy_list = ['Red', 'Green', 'Black']\nnew_list = insert_element(my_list, 'c')", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n \"\"\"Inserts an element before each element in a list.\n\n Args:\n lst: The input list.\n element: The element to insert.\n\n Returns:\n A new list with the element inserted before each original element.\n \"\"\"\n new_lst = []\n for item in lst:\n new_lst.append(element)\n new_lst.append(item)\n return new_lst", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n \"\"\"Inserts an element before each element in a list.\n\n Args:\n lst: The input list.\n element: The element to insert.\n\n Returns:\n A new list with the element inserted before each original element.\n \"\"\"\n\n new_list = []\n for item in lst:\n new_list.append(element)\n new_list.append(item)\n return new_list", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n \"\"\"Inserts an element before each element in a list.\n\n Args:\n lst: The input list.\n element: The element to insert.\n\n Returns:\n A new list with the element inserted before each original element.\n \"\"\"\n new_list = []\n for item in lst:\n new_list.append(element)\n new_list.append(item)\n return new_list", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n \"\"\"\n Inserts an element before each element in a list.\n\n Args:\n lst: The input list.\n element: The element to insert.\n\n Returns:\n A new list with the element inserted before each original element.\n \"\"\"\n\n new_lst = []\n for item in lst:\n new_lst.append(element)\n new_lst.append(item)\n return new_lst", "matching_cluster_idx": 6}]}, "Mbpp/256": {"dps": 97.71689497716895, "dps_norm": 88.23529411764706, "pass@1": 99.0, "profiled": [{"solution": "def count_Primes_nums(n):\n \"\"\"\n Counts the number of prime numbers less than n.\n\n Args:\n n: A non-negative integer.\n\n Returns:\n The number of prime numbers less than n.\n \"\"\"\n\n if n <= 1:\n return 0\n \n primes = [True] * n\n primes[0] = primes[1] = False # 0 and 1 are not prime\n\n for i in range(2, int(n**0.5) + 1):\n if primes[i]:\n for j in range(i*i, n, i):\n primes[j] = False\n\n return sum(primes)", "matching_cluster_idx": 14}, {"solution": "def count_Primes_nums(n):\n \"\"\"\n Counts the number of prime numbers less than n.\n\n Args:\n n: A non-negative integer.\n\n Returns:\n The number of prime numbers less than n.\n \"\"\"\n\n if n <= 1:\n return 0\n \n primes = [True] * n\n primes[0] = primes[1] = False\n\n for i in range(2, int(n**0.5) + 1):\n if primes[i]:\n for j in range(i*i, n, i):\n primes[j] = False\n\n return sum(primes)", "matching_cluster_idx": 14}, {"solution": "def count_Primes_nums(n):\n \"\"\"\n Counts the number of prime numbers less than n.\n\n Args:\n n: A non-negative integer.\n\n Returns:\n The number of prime numbers less than n.\n \"\"\"\n if n <= 1:\n return 0\n \n primes = [True] * n\n primes[0] = primes[1] = False\n\n for i in range(2, int(n**0.5) + 1):\n if primes[i]:\n for j in range(i*i, n, i):\n primes[j] = False\n \n return sum(primes)", "matching_cluster_idx": 14}, {"solution": "def count_Primes_nums(n):\n \"\"\"\n Counts the number of prime numbers less than n.\n\n Args:\n n: A non-negative integer.\n\n Returns:\n The number of prime numbers less than n.\n \"\"\"\n\n if n <= 1:\n return 0\n\n primes = [True] * n\n primes[0] = primes[1] = False\n\n for i in range(2, int(n**0.5) + 1):\n if primes[i]:\n for j in range(i*i, n, i):\n primes[j] = False\n \n return sum(primes)", "matching_cluster_idx": 14}, {"solution": "def count_Primes_nums(n):\n \"\"\"\n Counts the number of prime numbers less than n.\n\n Args:\n n: A non-negative integer.\n\n Returns:\n The number of prime numbers less than n.\n \"\"\"\n if n <= 1:\n return 0\n\n # Create a list of booleans, initially all True.\n # Each index represents a number, and True indicates it's potentially prime.\n primes = [True] * n\n # 0 and 1 are not prime\n primes[0] = primes[1] = False\n\n\n for i in range(2, int(n**0.5) + 1):\n if primes[i]:\n # Mark multiples of i as not prime\n for multiple in range(i*i, n, i):\n primes[multiple] = False\n\n # Count the number of True values remaining in the list\n return sum(primes)", "matching_cluster_idx": 14}, {"solution": "def count_Primes_nums(n):\n \"\"\"\n Counts the number of prime numbers less than n.\n\n Args:\n n: A non-negative integer.\n\n Returns:\n The number of prime numbers less than n.\n \"\"\"\n\n if n <= 1:\n return 0\n \n primes = [True] * n\n primes[0] = primes[1] = False # 0 and 1 are not prime\n\n for i in range(2, int(n**0.5) + 1):\n if primes[i]:\n for multiple in range(i*i, n, i):\n primes[multiple] = False\n\n return sum(primes)", "matching_cluster_idx": 14}, {"solution": "def count_Primes_nums(n):\n \"\"\"\n Counts the number of prime numbers less than n.\n\n Args:\n n: A non-negative integer.\n\n Returns:\n The number of prime numbers less than n.\n \"\"\"\n\n if n <= 1:\n return 0\n \n primes = [True] * n\n primes[0] = primes[1] = False\n\n for i in range(2, int(n**0.5) + 1):\n if primes[i]:\n for j in range(i*i, n, i):\n primes[j] = False\n\n return sum(primes)", "matching_cluster_idx": 14}, {"solution": "def count_Primes_nums(n):\n \"\"\"\n Counts the number of prime numbers less than n.\n\n Args:\n n: A non-negative integer.\n\n Returns:\n The number of prime numbers less than n.\n \"\"\"\n\n if n <= 1:\n return 0\n if n == 2:\n return 0\n if n == 3:\n return 1\n\n primes = [True] * n # Initialize a list to store primality flags\n primes[0] = primes[1] = False\n\n for i in range(2, int(n**0.5) + 1):\n if primes[i]:\n for j in range(i * i, n, i):\n primes[j] = False\n\n return sum(primes)", "matching_cluster_idx": 14}, {"solution": "def count_Primes_nums(n):\n \"\"\"\n Counts the number of prime numbers less than n.\n\n Args:\n n: A non-negative integer.\n\n Returns:\n The number of prime numbers less than n.\n \"\"\"\n\n if n <= 1:\n return 0\n \n primes = [True] * n\n primes[0] = primes[1] = False\n\n for i in range(2, int(n**0.5) + 1):\n if primes[i]:\n for j in range(i*i, n, i):\n primes[j] = False\n\n return sum(primes)", "matching_cluster_idx": 14}, {"solution": "def count_Primes_nums(n):\n \"\"\"\n Counts the number of prime numbers less than n.\n\n Args:\n n: A non-negative integer.\n\n Returns:\n The number of prime numbers less than n.\n \"\"\"\n\n if n <= 1:\n return 0\n \n primes = [True] * n\n primes[0] = primes[1] = False\n\n for i in range(2, int(n**0.5) + 1):\n if primes[i]:\n for j in range(i*i, n, i):\n primes[j] = False\n \n return sum(primes)", "matching_cluster_idx": 14}, {"solution": "def count_Primes_nums(n):\n \"\"\"\n Counts the number of prime numbers less than n.\n\n Args:\n n: A non-negative integer.\n\n Returns:\n The number of prime numbers less than n.\n \"\"\"\n\n if n <= 1:\n return 0\n \n primes = [True] * n # Initialize a list to store prime flags\n primes[0] = primes[1] = False\n\n for i in range(2, int(n**0.5) + 1):\n if primes[i]:\n for j in range(i*i, n, i):\n primes[j] = False\n\n return sum(primes)", "matching_cluster_idx": 14}, {"solution": "def count_Primes_nums(n):\n if n <= 1:\n return 0\n \n primes = [True] * n\n primes[0] = primes[1] = False\n\n for i in range(2, int(n**0.5) + 1):\n if primes[i]:\n for j in range(i*i, n, i):\n primes[j] = False\n\n return sum(primes)", "matching_cluster_idx": 14}, {"solution": "def count_Primes_nums(n):\n \"\"\"\n Counts the number of prime numbers less than n.\n\n Args:\n n: A non-negative integer.\n\n Returns:\n The number of prime numbers less than n.\n \"\"\"\n\n if n <= 1:\n return 0\n \n primes = [True] * n\n primes[0] = primes[1] = False\n\n for i in range(2, int(n**0.5) + 1):\n if primes[i]:\n for j in range(i*i, n, i):\n primes[j] = False\n \n return sum(primes)", "matching_cluster_idx": 14}, {"solution": "def count_Primes_nums(n):\n \"\"\"\n Counts the number of prime numbers less than n.\n\n Args:\n n: A non-negative integer.\n\n Returns:\n The number of prime numbers less than n.\n \"\"\"\n\n if n <= 1:\n return 0\n\n primes = [True] * n\n primes[0] = primes[1] = False\n\n for i in range(2, int(n**0.5) + 1):\n if primes[i]:\n for j in range(i * i, n, i):\n primes[j] = False\n\n return sum(primes)", "matching_cluster_idx": 14}, {"solution": "def count_Primes_nums(n):\n \"\"\"\n Counts the number of prime numbers less than n.\n\n Args:\n n: A non-negative integer.\n\n Returns:\n The number of prime numbers less than n.\n \"\"\"\n\n if n <= 1:\n return 0\n\n primes = [True] * n\n primes[0] = primes[1] = False\n\n for i in range(2, int(n**0.5) + 1):\n if primes[i]:\n for j in range(i * i, n, i):\n primes[j] = False\n\n return sum(primes)", "matching_cluster_idx": 14}, {"solution": "def count_Primes_nums(n):\n \"\"\"\n Counts the number of prime numbers less than n.\n\n Args:\n n: A non-negative integer.\n\n Returns:\n The number of prime numbers less than n.\n \"\"\"\n\n if n <= 1:\n return 0\n if n == 2:\n return 0 # No primes less than 2\n if n == 3:\n return 1 # Only 2 is less than 3\n \n primes = [True] * n\n primes[0] = primes[1] = False # 0 and 1 are not prime\n\n for i in range(2, int(n**0.5) + 1): # Optimization: Check divisibility only up to the square root of n\n if primes[i]:\n for j in range(i * i, n, i): # Start from i*i to avoid redundant checks\n primes[j] = False\n\n return sum(primes)", "matching_cluster_idx": 14}, {"solution": "def count_Primes_nums(n):\n \"\"\"\n Counts the number of prime numbers less than n.\n\n Args:\n n: A non-negative integer.\n\n Returns:\n The number of prime numbers less than n.\n \"\"\"\n\n if n <= 1:\n return 0\n\n # Sieve of Eratosthenes\n primes = [True] * n\n primes[0] = primes[1] = False\n\n for i in range(2, int(n**0.5) + 1):\n if primes[i]:\n for multiple in range(i*i, n, i):\n primes[multiple] = False\n\n return sum(primes)", "matching_cluster_idx": 14}, {"solution": "def count_Primes_nums(n):\n \"\"\"\n Counts the number of prime numbers less than n.\n\n Args:\n n: A non-negative integer.\n\n Returns:\n The number of prime numbers less than n.\n \"\"\"\n\n if n <= 1:\n return 0\n \n primes = [True] * n\n primes[0] = primes[1] = False\n\n for i in range(2, int(n**0.5) + 1):\n if primes[i]:\n for multiple in range(i*i, n, i):\n primes[multiple] = False\n \n return sum(primes)", "matching_cluster_idx": 14}, {"solution": "def count_Primes_nums(n):\n \"\"\"\n Counts the number of prime numbers less than n.\n\n Args:\n n: A non-negative integer.\n\n Returns:\n The number of prime numbers less than n.\n \"\"\"\n if n <= 1:\n return 0\n if n == 2:\n return 0\n\n primes = [True] * n\n primes[0] = primes[1] = False\n\n for i in range(2, int(n**0.5) + 1):\n if primes[i]:\n for j in range(i * i, n, i):\n primes[j] = False\n\n return sum(primes)", "matching_cluster_idx": 14}, {"solution": "def count_Primes_nums(n):\n \"\"\"\n Counts the number of prime numbers less than n.\n\n Args:\n n: A non-negative integer.\n\n Returns:\n The number of prime numbers less than n.\n \"\"\"\n\n if n <= 1:\n return 0\n \n primes = [True] * n\n primes[0] = primes[1] = False\n\n for i in range(2, int(n**0.5) + 1):\n if primes[i]:\n for j in range(i*i, n, i):\n primes[j] = False\n\n return sum(primes)", "matching_cluster_idx": 14}]}, "Mbpp/265": {"dps": 70.93023255813954, "dps_norm": 83.33333333333333, "pass@1": 27.0, "profiled": [{"solution": "def list_split(lst, n):\n \"\"\"\n Splits a list into sublists based on the nth element.\n\n Args:\n lst: The input list.\n n: The splitting interval.\n\n Returns:\n A list of sublists.\n \"\"\"\n\n result = [[] for _ in range(n)]\n for i, item in enumerate(lst):\n result[i % n].append(item)\n return result", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n \"\"\"\n Splits a list into sublists based on the nth element.\n\n Args:\n lst: The input list.\n n: The splitting interval.\n\n Returns:\n A list of sublists.\n \"\"\"\n\n result = [[] for _ in range(n)]\n for i, item in enumerate(lst):\n result[i % n].append(item)\n return result\nn = 3", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n \"\"\"Splits a list into sublists based on the nth element.\n\n Args:\n lst: The input list.\n n: The splitting interval.\n\n Returns:\n A list of sublists.\n \"\"\"\n result = [[] for _ in range(n)]\n for i, item in enumerate(lst):\n result[i % n].append(item)\n return result", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n \"\"\"\n Splits a list into sublists based on the nth element.\n\n Args:\n lst: The input list.\n n: The interval for splitting.\n\n Returns:\n A list of sublists.\n \"\"\"\n result = [[] for _ in range(n)]\n for i, item in enumerate(lst):\n result[i % n].append(item)\n return result", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n \"\"\"\n Splits a list into sublists based on the nth element.\n\n Args:\n lst: The input list.\n n: The splitting interval.\n\n Returns:\n A list of sublists.\n \"\"\"\n\n result = [[] for _ in range(n)]\n for i, item in enumerate(lst):\n result[i % n].append(item)\n return result\nn = 3", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n \"\"\"Splits a list into sublists based on the nth element.\n\n Args:\n lst: The input list.\n n: The splitting interval.\n\n Returns:\n A list of sublists.\n \"\"\"\n\n result = [[] for _ in range(n)]\n for i, item in enumerate(lst):\n result[i % n].append(item)\n return result", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n \"\"\"\n Splits a list into sublists based on every nth element.\n\n Args:\n lst: The input list.\n n: The splitting interval.\n\n Returns:\n A list of sublists.\n \"\"\"\n\n result = [[] for _ in range(n)]\n for i, item in enumerate(lst):\n result[i % n].append(item)\n return result", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n \"\"\"Splits a list into sublists every nth element.\n\n Args:\n lst: The input list.\n n: The interval for splitting.\n\n Returns:\n A list of sublists.\n \"\"\"\n result = [[] for _ in range(n)]\n for i, item in enumerate(lst):\n result[i % n].append(item)\n return result\nn = 3", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n \"\"\"Splits a list into sublists based on the nth element.\n\n Args:\n lst: The input list.\n n: The interval for splitting.\n\n Returns:\n A list of sublists.\n \"\"\"\n\n result = [[] for _ in range(n)]\n for i, item in enumerate(lst):\n result[i % n].append(item)\n return result", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n \"\"\"\n Splits a list for every nth element, returning a list of the resulting lists.\n\n Args:\n lst: The input list.\n n: The split interval.\n\n Returns:\n A list of lists, where each inner list contains elements at intervals of n.\n \"\"\"\n\n if n <= 0:\n raise ValueError(\"n must be a positive integer\")\n\n split_lists = [[] for _ in range(n)] # Initialize n empty lists\n\n for i, item in enumerate(lst):\n split_lists[i % n].append(item)\n\n return split_lists\nlst = ['a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j', 'k', 'l', 'm', 'n']\nn = 3", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n \"\"\"\n Splits a list into sublists based on the nth element.\n\n Args:\n lst: The input list.\n n: The splitting interval.\n\n Returns:\n A list of sublists.\n \"\"\"\n\n result = [[] for _ in range(n)]\n for i, item in enumerate(lst):\n result[i % n].append(item)\n return result", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n \"\"\"Splits a list into sublists based on the nth element.\n\n Args:\n lst: The input list.\n n: The splitting interval.\n\n Returns:\n A list of sublists.\n \"\"\"\n\n result = [[] for _ in range(n)]\n for i, item in enumerate(lst):\n result[i % n].append(item)\n return result", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n \"\"\"Splits a list into sublists every nth element.\n\n Args:\n lst: The input list.\n n: The split interval.\n\n Returns:\n A list of sublists.\n \"\"\"\n result = [[] for _ in range(n)]\n for i, item in enumerate(lst):\n result[i % n].append(item)\n return result", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n \"\"\"\n Splits a list into sublists based on the nth element.\n\n Args:\n lst: The input list.\n n: The splitting interval.\n\n Returns:\n A list of sublists.\n \"\"\"\n result = [[] for _ in range(n)]\n for i, item in enumerate(lst):\n result[i % n].append(item)\n return result", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n \"\"\"Splits a list into sublists based on the nth element.\n\n Args:\n lst: The input list.\n n: The splitting interval.\n\n Returns:\n A list of sublists.\n \"\"\"\n\n result = [[] for _ in range(n)]\n for i, item in enumerate(lst):\n result[i % n].append(item)\n return result", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n \"\"\"\n Splits a list into sublists by taking every nth element.\n\n Args:\n lst: The input list.\n n: The interval for splitting the list.\n\n Returns:\n A list of sublists.\n \"\"\"\n\n if n <= 0:\n raise ValueError(\"n must be a positive integer\")\n\n result = [[] for _ in range(n)]\n for i, item in enumerate(lst):\n result[i % n].append(item)\n return result\nn = 3", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n \"\"\"\n Splits a list into sublists based on the nth element.\n\n Args:\n lst: The input list.\n n: The interval for splitting.\n\n Returns:\n A list of sublists.\n \"\"\"\n\n result = [[] for _ in range(n)]\n for i, item in enumerate(lst):\n result[i % n].append(item)\n return result", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n \"\"\"\n Splits a list into sublists based on every nth element.\n\n Args:\n lst: The input list.\n n: The splitting interval.\n\n Returns:\n A list of sublists.\n \"\"\"\n result = [[] for _ in range(n)]\n for i, item in enumerate(lst):\n result[i % n].append(item)\n return result", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n \"\"\"\n Splits a list into sublists based on every nth element.\n\n Args:\n lst: The input list.\n n: The interval for splitting.\n\n Returns:\n A list of sublists.\n \"\"\"\n\n if n <= 0:\n raise ValueError(\"n must be a positive integer.\")\n\n result = [[] for _ in range(n)]\n for i, item in enumerate(lst):\n result[i % n].append(item)\n return result", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n \"\"\"\n Splits a list into sublists based on the nth element.\n\n Args:\n lst: The input list.\n n: The splitting interval.\n\n Returns:\n A list of sublists.\n \"\"\"\n\n result = [[] for _ in range(n)]\n for i, item in enumerate(lst):\n result[i % n].append(item)\n return result", "matching_cluster_idx": 4}]}, "Mbpp/281": {"dps": 94.6, "dps_norm": 83.63636363636363, "pass@1": 100.0, "profiled": [{"solution": "def all_unique(lst):\n \"\"\"Checks if all elements in a list are unique.\n\n Args:\n lst: The input list.\n\n Returns:\n True if all elements are unique, False otherwise.\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"Checks if all elements in a list are unique.\n\n Args:\n lst: The list to check.\n\n Returns:\n True if all elements are unique, False otherwise.\n \"\"\"\n seen = set()\n for item in lst:\n if item in seen:\n return False\n seen.add(item)\n return True", "matching_cluster_idx": 10}, {"solution": "def all_unique(lst):\n \"\"\"\n Checks if all elements in a list are unique.\n\n Args:\n lst: The list to check.\n\n Returns:\n True if all elements are unique, False otherwise.\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n Checks if all elements in a list are unique.\n\n Args:\n lst: The list to check.\n\n Returns:\n True if all elements are unique, False otherwise.\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"Checks if all elements in a list are unique.\n\n Args:\n lst: The list to check.\n\n Returns:\n True if all elements are unique, False otherwise.\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"Checks if all elements in a list are unique.\n\n Args:\n lst: The list to check.\n\n Returns:\n True if all elements are unique, False otherwise.\n \"\"\"\n seen = set()\n for item in lst:\n if item in seen:\n return False\n seen.add(item)\n return True", "matching_cluster_idx": 10}, {"solution": "def all_unique(lst):\n \"\"\"\n Checks if all elements in a list are unique.\n\n Args:\n lst: The list to check.\n\n Returns:\n True if all elements are unique, False otherwise.\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n Checks if all elements in a list are unique.\n\n Args:\n lst: The list to check.\n\n Returns:\n True if all elements are unique, False otherwise.\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n Checks if all elements in a list are unique.\n\n Args:\n lst: The input list.\n\n Returns:\n True if all elements are unique, False otherwise.\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"Checks if all elements in a list are unique.\n\n Args:\n lst: The list to check.\n\n Returns:\n True if all elements are unique, False otherwise.\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n Checks if all elements in a list are unique.\n\n Args:\n lst: The list to check.\n\n Returns:\n True if all elements are unique, False otherwise.\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n Checks if all elements in a list are unique.\n\n Args:\n lst: The list to check.\n\n Returns:\n True if all elements are unique, False otherwise.\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"Checks if all elements in a list are unique.\n\n Args:\n lst: The list to check.\n\n Returns:\n True if all elements are unique, False otherwise.\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n Checks if all elements in a list are unique.\n\n Args:\n lst: The list to check.\n\n Returns:\n True if all elements are unique, False otherwise.\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n Checks if all elements in a list are unique.\n\n Args:\n lst: The list to check.\n\n Returns:\n True if all elements are unique, False otherwise.\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"Checks if all elements in a list are unique.\n\n Args:\n lst: The list to check.\n\n Returns:\n True if all elements are unique, False otherwise.\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n Checks if all elements in a list are unique.\n\n Args:\n lst: The list to check.\n\n Returns:\n True if all elements are unique, False otherwise.\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"Checks if all elements in a list are unique.\n\n Args:\n lst: The list to check.\n\n Returns:\n True if all elements are unique, False otherwise.\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n Checks if all elements in a list are unique.\n\n Args:\n lst: The list to check.\n\n Returns:\n True if all elements are unique, False otherwise.\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"Checks if all elements in a list are unique.\n\n Args:\n lst: The list to check.\n\n Returns:\n True if all elements are unique, False otherwise.\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}]}, "Mbpp/296": {"dps": 96.41025641025641, "dps_norm": 98.33333333333333, "pass@1": 65.0, "profiled": [{"solution": "def get_Inv_Count(arr):\n \"\"\"\n Counts inversions in an array using merge sort.\n\n An inversion is a pair (arr[i], arr[j]) where i < j and arr[i] > arr[j].\n\n Args:\n arr: The input array.\n\n Returns:\n The number of inversions in the array.\n \"\"\"\n n = len(arr)\n if n <= 1:\n return 0\n\n inv_count = 0\n def merge_sort_and_count(left, right):\n nonlocal inv_count # Access the outer inv_count variable\n\n result = []\n i = j = 0\n while i < len(left) and j < len(right):\n if left[i] <= right[j]:\n result.append(left[i])\n i += 1\n else:\n result.append(right[j])\n j += 1\n inv_count += len(left) - i # Count inversions\n\n result += left[i:]\n result += right[j:]\n return result\n\n mid = n // 2\n left = arr[:mid]\n right = arr[mid:]\n\n inv_count += get_Inv_Count(left) # Recursively count inversions in left subarray\n inv_count += get_Inv_Count(right) # Recursively count inversions in right subarray\n arr[:] = merge_sort_and_count(left, right) # Modify original array in place\n\n return inv_count", "matching_cluster_idx": 5}, {"solution": "def get_Inv_Count(arr):\n \"\"\"\n Counts inversions in an array using merge sort.\n\n Args:\n arr: The input array.\n\n Returns:\n The number of inversions in the array.\n \"\"\"\n n = len(arr)\n if n <= 1:\n return 0\n\n inv_count = 0\n mid = n // 2\n left = arr[:mid]\n right = arr[mid:]\n\n inv_count += get_Inv_Count(left)\n inv_count += get_Inv_Count(right)\n\n i = j = k = 0\n while i < len(left) and j < len(right):\n if left[i] <= right[j]:\n arr[k] = left[i]\n i += 1\n else:\n arr[k] = right[j]\n j += 1\n inv_count += len(left) - i # Count inversions\n k += 1\n\n while i < len(left):\n arr[k] = left[i]\n i += 1\n k += 1\n\n while j < len(right):\n arr[k] = right[j]\n j += 1\n k += 1\n\n return inv_count", "matching_cluster_idx": 5}, {"solution": "def get_Inv_Count(arr):\n \"\"\"\n Counts the number of inversions in an array.\n\n An inversion is a pair of indices (i, j) such that i < j and arr[i] > arr[j].\n\n Args:\n arr: The input array.\n\n Returns:\n The number of inversions in the array.\n \"\"\"\n inv_count = 0\n n = len(arr)\n for i in range(n):\n for j in range(i + 1, n):\n if arr[i] > arr[j]:\n inv_count += 1\n return inv_count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n \"\"\"\n Counts inversions in an array using merge sort.\n\n An inversion is a pair (arr[i], arr[j]) where i < j and arr[i] > arr[j].\n\n Args:\n arr: The input array.\n\n Returns:\n The number of inversions in the array.\n \"\"\"\n n = len(arr)\n if n <= 1:\n return 0\n\n inv_count = 0\n def merge_sort_and_count(left, right):\n nonlocal inv_count\n result = []\n i = j = 0\n while i < len(left) and j < len(right):\n if left[i] <= right[j]:\n result.append(left[i])\n i += 1\n else:\n result.append(right[j])\n j += 1\n inv_count += len(left) - i # Count inversions\n\n result.extend(left[i:])\n result.extend(right[j:])\n return result\n \n mid = n // 2\n left = arr[:mid]\n right = arr[mid:]\n\n inv_count += get_Inv_Count(left)\n inv_count += get_Inv_Count(right)\n \n arr[:] = merge_sort_and_count(left,right) # Important to modify original array in-place\n\n return inv_count", "matching_cluster_idx": 5}, {"solution": "def get_Inv_Count(arr):\n \"\"\"\n Counts inversions in an array using merge sort.\n\n An inversion is a pair (arr[i], arr[j]) where i < j and arr[i] > arr[j].\n\n Args:\n arr: The input array.\n\n Returns:\n The number of inversions in the array.\n \"\"\"\n n = len(arr)\n if n <= 1:\n return 0\n\n inv_count = 0\n mid = n // 2\n left = arr[:mid]\n right = arr[mid:]\n\n inv_count += get_Inv_Count(left)\n inv_count += get_Inv_Count(right)\n\n i = j = k = 0\n while i < len(left) and j < len(right):\n if left[i] <= right[j]:\n arr[k] = left[i]\n i += 1\n else:\n arr[k] = right[j]\n j += 1\n inv_count += len(left) - i # Count inversions\n k += 1\n\n while i < len(left):\n arr[k] = left[i]\n i += 1\n k += 1\n\n while j < len(right):\n arr[k] = right[j]\n j += 1\n k += 1\n\n return inv_count", "matching_cluster_idx": 5}, {"solution": "def get_Inv_Count(arr):\n \"\"\"\n Counts inversions in an array using merge sort.\n\n An inversion is a pair (arr[i], arr[j]) such that i < j and arr[i] > arr[j].\n\n Args:\n arr: The input array.\n\n Returns:\n The number of inversions in the array.\n \"\"\"\n n = len(arr)\n if n <= 1:\n return 0\n\n def _merge_sort(arr, temp_arr, left, right):\n inv_count = 0\n if left < right:\n mid = (left + right) // 2\n inv_count += _merge_sort(arr, temp_arr, left, mid)\n inv_count += _merge_sort(arr, temp_arr, mid + 1, right)\n inv_count += _merge(arr, temp_arr, left, mid, right)\n return inv_count\n\n def _merge(arr, temp_arr, left, mid, right):\n i = left\n j = mid + 1\n k = left\n inv_count = 0\n\n while i <= mid and j <= right:\n if arr[i] <= arr[j]:\n temp_arr[k] = arr[i]\n i += 1\n else:\n temp_arr[k] = arr[j]\n inv_count += (mid - i + 1) # Count inversions\n j += 1\n k += 1\n\n while i <= mid:\n temp_arr[k] = arr[i]\n i += 1\n k += 1\n\n while j <= right:\n temp_arr[k] = arr[j]\n j += 1\n k += 1\n\n for loop_var in range(left, right + 1):\n arr[loop_var] = temp_arr[loop_var]\n\n return inv_count\n\n temp_arr = [0] * n\n return _merge_sort(arr, temp_arr, 0, n - 1)", "matching_cluster_idx": 5}, {"solution": "def get_Inv_Count(arr):\n \"\"\"\n Counts inversions in an array using merge sort.\n\n An inversion is a pair (arr[i], arr[j]) such that i < j and arr[i] > arr[j].\n\n Args:\n arr: The input array.\n\n Returns:\n The number of inversions in the array.\n \"\"\"\n n = len(arr)\n if n <= 1:\n return 0\n\n def merge_sort_and_count(arr):\n n = len(arr)\n if n <= 1:\n return arr, 0\n\n mid = n // 2\n left, inv_left = merge_sort_and_count(arr[:mid])\n right, inv_right = merge_sort_and_count(arr[mid:])\n\n merged = []\n inv_merged = inv_left + inv_right\n i = j = 0\n\n while i < len(left) and j < len(right):\n if left[i] <= right[j]:\n merged.append(left[i])\n i += 1\n else:\n merged.append(right[j])\n j += 1\n inv_merged += len(left) - i # Count inversions\n\n merged.extend(left[i:])\n merged.extend(right[j:])\n\n return merged, inv_merged\n\n _, inversions = merge_sort_and_count(arr)\n return inversions", "matching_cluster_idx": 5}, {"solution": "def get_Inv_Count(arr):\n \"\"\"\n Counts the number of inversions in an array using merge sort.\n\n An inversion is a pair of indices (i, j) such that i < j and arr[i] > arr[j].\n\n Args:\n arr: The input array.\n\n Returns:\n The number of inversions in the array.\n \"\"\"\n n = len(arr)\n if n <= 1:\n return 0\n\n def merge_sort_and_count(arr, temp, left, right):\n inv_count = 0\n\n if left < right:\n mid = (left + right) // 2\n\n inv_count += merge_sort_and_count(arr, temp, left, mid)\n inv_count += merge_sort_and_count(arr, temp, mid + 1, right)\n inv_count += merge(arr, temp, left, mid, right)\n return inv_count\n\n def merge(arr, temp, left, mid, right):\n i = left\n j = mid + 1\n k = left\n inv_count = 0\n\n while i <= mid and j <= right:\n if arr[i] <= arr[j]:\n temp[k] = arr[i]\n i += 1\n else:\n temp[k] = arr[j]\n inv_count += (mid - i + 1) # Count inversions\n j += 1\n k += 1\n\n while i <= mid:\n temp[k] = arr[i]\n i += 1\n k += 1\n\n while j <= right:\n temp[k] = arr[j]\n j += 1\n k += 1\n\n for loop_var in range(left, right + 1):\n arr[loop_var] = temp[loop_var]\n\n return inv_count\n\n temp = [0] * n\n return merge_sort_and_count(arr, temp, 0, n - 1)", "matching_cluster_idx": 5}, {"solution": "def get_Inv_Count(arr):\n \"\"\"\n Counts inversions in an array using merge sort.\n\n An inversion is a pair (arr[i], arr[j]) where i < j and arr[i] > arr[j].\n\n Args:\n arr: The input array.\n\n Returns:\n The number of inversions in the array.\n \"\"\"\n n = len(arr)\n if n <= 1:\n return 0\n\n inv_count = 0\n mid = n // 2\n left = arr[:mid]\n right = arr[mid:]\n\n inv_count += get_Inv_Count(left)\n inv_count += get_Inv_Count(right)\n inv_count += merge_and_count(arr, left, right)\n\n return inv_count\ndef merge_and_count(arr, left, right):\n \"\"\"\n Merges two sorted subarrays and counts inversions.\n\n Args:\n arr: The original array.\n left: The left subarray.\n right: The right subarray.\n\n Returns:\n The number of inversions during the merge.\n \"\"\"\n i = j = k = inv_count = 0\n n_left = len(left)\n n_right = len(right)\n\n while i < n_left and j < n_right:\n if left[i] <= right[j]:\n arr[k] = left[i]\n i += 1\n else:\n arr[k] = right[j]\n j += 1\n inv_count += n_left - i # Count inversions\n k += 1\n\n while i < n_left:\n arr[k] = left[i]\n i += 1\n k += 1\n\n while j < n_right:\n arr[k] = right[j]\n j += 1\n k += 1\n\n return inv_count", "matching_cluster_idx": 5}, {"solution": "def get_Inv_Count(arr):\n \"\"\"\n Counts inversions in an array using merge sort.\n\n An inversion is a pair (arr[i], arr[j]) where i < j and arr[i] > arr[j].\n\n Args:\n arr: The input array.\n\n Returns:\n The number of inversions in the array.\n \"\"\"\n n = len(arr)\n if n <= 1:\n return 0\n \n mid = n // 2\n left = arr[:mid]\n right = arr[mid:]\n\n inv_count = get_Inv_Count(left) + get_Inv_Count(right)\n\n i = j = k = 0\n while i < len(left) and j < len(right):\n if left[i] <= right[j]:\n arr[k] = left[i]\n i += 1\n else:\n arr[k] = right[j]\n j += 1\n inv_count += len(left) - i # Count inversions\n k += 1\n\n while i < len(left):\n arr[k] = left[i]\n i += 1\n k += 1\n\n while j < len(right):\n arr[k] = right[j]\n j += 1\n k += 1\n\n return inv_count", "matching_cluster_idx": 5}, {"solution": "def get_Inv_Count(arr):\n \"\"\"\n Counts inversions in an array using merge sort.\n\n An inversion is a pair (arr[i], arr[j]) where i < j and arr[i] > arr[j].\n\n Args:\n arr: The input array.\n\n Returns:\n The number of inversions in the array.\n \"\"\"\n n = len(arr)\n if n <= 1:\n return 0\n\n def merge_sort_and_count(arr, left, right):\n inv_count = 0\n if left < right:\n mid = (left + right) // 2\n inv_count += merge_sort_and_count(arr, left, mid)\n inv_count += merge_sort_and_count(arr, mid + 1, right)\n inv_count += merge(arr, left, mid, right)\n return inv_count\n\n def merge(arr, left, mid, right):\n i = left\n j = mid + 1\n k = 0\n inv_count = 0\n temp = [0] * (right - left + 1)\n\n while i <= mid and j <= right:\n if arr[i] <= arr[j]:\n temp[k] = arr[i]\n i += 1\n else:\n temp[k] = arr[j]\n j += 1\n inv_count += (mid - i + 1) # Count inversions\n k += 1\n\n while i <= mid:\n temp[k] = arr[i]\n i += 1\n k += 1\n\n while j <= right:\n temp[k] = arr[j]\n j += 1\n k += 1\n\n for i in range(right - left + 1):\n arr[left + i] = temp[i]\n \n return inv_count\n\n return merge_sort_and_count(arr, 0, n - 1)", "matching_cluster_idx": 5}, {"solution": "def get_Inv_Count(arr):\n \"\"\"\n Counts inversions in an array using merge sort.\n\n An inversion is a pair (arr[i], arr[j]) where i < j and arr[i] > arr[j].\n\n Args:\n arr: The input array.\n\n Returns:\n The number of inversions in the array.\n \"\"\"\n n = len(arr)\n if n <= 1:\n return 0\n\n inv_count = 0\n mid = n // 2\n left = arr[:mid]\n right = arr[mid:]\n\n inv_count += get_Inv_Count(left)\n inv_count += get_Inv_Count(right)\n\n i = j = k = 0\n while i < len(left) and j < len(right):\n if left[i] <= right[j]:\n arr[k] = left[i]\n i += 1\n else:\n arr[k] = right[j]\n j += 1\n inv_count += len(left) - i # Count inversions\n k += 1\n\n while i < len(left):\n arr[k] = left[i]\n i += 1\n k += 1\n\n while j < len(right):\n arr[k] = right[j]\n j += 1\n k += 1\n\n return inv_count\narr = [1, 20, 6, 4, 5]", "matching_cluster_idx": 5}, {"solution": "def get_Inv_Count(arr):\n \"\"\"\n Counts inversions in an array using merge sort.\n\n An inversion is a pair of elements (arr[i], arr[j]) such that i < j and arr[i] > arr[j].\n\n Args:\n arr: The input array.\n\n Returns:\n The total number of inversions in the array.\n \"\"\"\n n = len(arr)\n if n <= 1:\n return 0\n\n inv_count = 0\n mid = n // 2\n left = arr[:mid]\n right = arr[mid:]\n\n inv_count += get_Inv_Count(left)\n inv_count += get_Inv_Count(right)\n\n i = j = k = 0\n while i < len(left) and j < len(right):\n if left[i] <= right[j]:\n arr[k] = left[i]\n i += 1\n else:\n arr[k] = right[j]\n j += 1\n inv_count += len(left) - i # Count inversions\n k += 1\n\n while i < len(left):\n arr[k] = left[i]\n i += 1\n k += 1\n\n while j < len(right):\n arr[k] = right[j]\n j += 1\n k += 1\n\n return inv_count", "matching_cluster_idx": 5}, {"solution": "def get_Inv_Count(arr):\n \"\"\"\n Counts inversions in an array using merge sort.\n\n Args:\n arr: The input array.\n\n Returns:\n The number of inversions in the array.\n \"\"\"\n n = len(arr)\n if n <= 1:\n return 0\n\n inv_count = 0\n mid = n // 2\n left = arr[:mid]\n right = arr[mid:]\n\n inv_count += get_Inv_Count(left)\n inv_count += get_Inv_Count(right)\n\n i = j = k = 0\n while i < len(left) and j < len(right):\n if left[i] <= right[j]:\n arr[k] = left[i]\n i += 1\n else:\n arr[k] = right[j]\n j += 1\n inv_count += len(left) - i # Count inversions\n k += 1\n\n while i < len(left):\n arr[k] = left[i]\n i += 1\n k += 1\n\n while j < len(right):\n arr[k] = right[j]\n j += 1\n k += 1\n \n return inv_count", "matching_cluster_idx": 5}, {"solution": "def get_Inv_Count(arr):\n \"\"\"\n Counts the number of inversions in an array using merge sort.\n\n An inversion is a pair (arr[i], arr[j]) such that i < j and arr[i] > arr[j].\n\n Args:\n arr: The input array.\n\n Returns:\n The number of inversions in the array.\n \"\"\"\n n = len(arr)\n if n <= 1:\n return 0\n\n def merge_sort_and_count(arr, left, right):\n inv_count = 0\n if left < right:\n mid = (left + right) // 2\n inv_count += merge_sort_and_count(arr, left, mid)\n inv_count += merge_sort_and_count(arr, mid + 1, right)\n inv_count += merge(arr, left, mid, right)\n return inv_count\n\n def merge(arr, left, mid, right):\n i = left\n j = mid + 1\n k = 0\n temp = [0] * (right - left + 1)\n inv_count = 0\n\n while i <= mid and j <= right:\n if arr[i] <= arr[j]:\n temp[k] = arr[i]\n k += 1\n i += 1\n else:\n temp[k] = arr[j]\n inv_count += (mid - i + 1) # Count inversions\n k += 1\n j += 1\n\n while i <= mid:\n temp[k] = arr[i]\n k += 1\n i += 1\n\n while j <= right:\n temp[k] = arr[j]\n k += 1\n j += 1\n\n for idx in range(right - left + 1):\n arr[left + idx] = temp[idx]\n\n return inv_count\n\n return merge_sort_and_count(arr, 0, n - 1)", "matching_cluster_idx": 5}, {"solution": "def get_Inv_Count(arr):\n \"\"\"\n Counts inversions in an array using merge sort.\n\n Args:\n arr: The input array.\n\n Returns:\n The number of inversions.\n \"\"\"\n n = len(arr)\n if n <= 1:\n return 0\n\n inv_count = 0\n mid = n // 2\n left = arr[:mid]\n right = arr[mid:]\n\n inv_count += get_Inv_Count(left)\n inv_count += get_Inv_Count(right)\n\n i = j = k = 0\n while i < len(left) and j < len(right):\n if left[i] <= right[j]:\n arr[k] = left[i]\n i += 1\n else:\n arr[k] = right[j]\n j += 1\n inv_count += len(left) - i # Count inversions\n k += 1\n\n while i < len(left):\n arr[k] = left[i]\n i += 1\n k += 1\n\n while j < len(right):\n arr[k] = right[j]\n j += 1\n k += 1\n \n return inv_count", "matching_cluster_idx": 5}, {"solution": "def get_Inv_Count(arr):\n \"\"\"\n Counts inversions in an array using a modified merge sort.\n\n Args:\n arr: The input array.\n\n Returns:\n The number of inversions in the array.\n \"\"\"\n n = len(arr)\n if n <= 1:\n return 0\n\n def merge_sort_and_count(arr):\n n = len(arr)\n if n <= 1:\n return arr, 0\n\n mid = n // 2\n left, inv_left = merge_sort_and_count(arr[:mid])\n right, inv_right = merge_sort_and_count(arr[mid:])\n\n merged_arr = []\n inversions = inv_left + inv_right\n i = j = 0\n while i < len(left) and j < len(right):\n if left[i] <= right[j]:\n merged_arr.append(left[i])\n i += 1\n else:\n merged_arr.append(right[j])\n inversions += len(left) - i # Count inversions\n j += 1\n\n merged_arr.extend(left[i:])\n merged_arr.extend(right[j:])\n return merged_arr, inversions\n\n _, inversions = merge_sort_and_count(arr)\n return inversions", "matching_cluster_idx": 5}, {"solution": "def get_Inv_Count(arr):\n \"\"\"\n Counts inversions in an array using merge sort.\n\n Args:\n arr: The input array.\n\n Returns:\n The number of inversions in the array.\n \"\"\"\n n = len(arr)\n if n <= 1:\n return 0\n\n inv_count = 0\n mid = n // 2\n left = arr[:mid]\n right = arr[mid:]\n\n inv_count += get_Inv_Count(left)\n inv_count += get_Inv_Count(right)\n\n i = j = k = 0\n while i < len(left) and j < len(right):\n if left[i] <= right[j]:\n arr[k] = left[i]\n i += 1\n else:\n arr[k] = right[j]\n j += 1\n inv_count += len(left) - i # Count inversions\n k += 1\n\n while i < len(left):\n arr[k] = left[i]\n i += 1\n k += 1\n\n while j < len(right):\n arr[k] = right[j]\n j += 1\n k += 1\n\n return inv_count", "matching_cluster_idx": 5}, {"solution": "def get_Inv_Count(arr):\n \"\"\"\n Counts inversions in an array using merge sort.\n\n An inversion is a pair (arr[i], arr[j]) where i < j and arr[i] > arr[j].\n\n Args:\n arr: The input array.\n\n Returns:\n The number of inversions in the array.\n \"\"\"\n n = len(arr)\n if n <= 1:\n return 0\n\n def _merge_sort_and_count(arr, temp, left, right):\n inv_count = 0\n if left < right:\n mid = (left + right) // 2\n inv_count += _merge_sort_and_count(arr, temp, left, mid)\n inv_count += _merge_sort_and_count(arr, temp, mid + 1, right)\n inv_count += merge_and_count(arr, temp, left, mid, right)\n return inv_count\n\n def merge_and_count(arr, temp, left, mid, right):\n i = left\n j = mid + 1\n k = left\n inv_count = 0\n\n while i <= mid and j <= right:\n if arr[i] <= arr[j]:\n temp[k] = arr[i]\n i += 1\n else:\n temp[k] = arr[j]\n inv_count += (mid - i + 1) # Count inversions\n j += 1\n k += 1\n\n while i <= mid:\n temp[k] = arr[i]\n i += 1\n k += 1\n\n while j <= right:\n temp[k] = arr[j]\n j += 1\n k += 1\n\n for loop_var in range(left, right + 1):\n arr[loop_var] = temp[loop_var]\n\n return inv_count\n\n temp = [0] * n\n return _merge_sort_and_count(arr, temp, 0, n - 1)", "matching_cluster_idx": 5}, {"solution": "def get_Inv_Count(arr):\n \"\"\"\n Counts inversions in an array using merge sort.\n\n An inversion is a pair (arr[i], arr[j]) where i < j and arr[i] > arr[j].\n\n Args:\n arr: The input array.\n\n Returns:\n The number of inversions in the array.\n \"\"\"\n n = len(arr)\n if n <= 1:\n return 0\n\n mid = n // 2\n left = arr[:mid]\n right = arr[mid:]\n\n inv_count = get_Inv_Count(left) + get_Inv_Count(right)\n\n i = j = k = 0\n while i < len(left) and j < len(right):\n if left[i] <= right[j]:\n arr[k] = left[i]\n i += 1\n else:\n arr[k] = right[j]\n j += 1\n inv_count += len(left) - i # Count inversions\n k += 1\n\n while i < len(left):\n arr[k] = left[i]\n i += 1\n k += 1\n\n while j < len(right):\n arr[k] = right[j]\n j += 1\n k += 1\n\n return inv_count\narr = [1, 20, 6, 4, 5]", "matching_cluster_idx": 5}]}, "Mbpp/308": {"dps": 77.72413793103449, "dps_norm": 61.66666666666667, "pass@1": 32.0, "profiled": [{"solution": "import heapq\ndef large_product(list1, list2, n):\n \"\"\"\n Finds the n largest products from two lists.\n\n Args:\n list1: The first list of numbers.\n list2: The second list of numbers.\n n: The number of largest products to return.\n\n Returns:\n A list containing the n largest products, sorted in descending order.\n \"\"\"\n\n products = []\n for x in list1:\n for y in list2:\n products.append(x * y)\n \n return heapq.nlargest(n, products)", "matching_cluster_idx": 3}, {"solution": "import heapq\ndef large_product(list1, list2, n):\n \"\"\"\n Finds the n largest products from two lists.\n\n Args:\n list1: The first list of numbers.\n list2: The second list of numbers.\n n: The number of largest products to return.\n\n Returns:\n A list containing the n largest products.\n \"\"\"\n list1.sort(reverse=True)\n list2.sort(reverse=True)\n\n products = []\n for num1 in list1:\n for num2 in list2:\n products.append(num1 * num2)\n\n return heapq.nlargest(n, products)", "matching_cluster_idx": 3}, {"solution": "import heapq\ndef large_product(list1, list2, n):\n \"\"\"\n Finds the n largest products formed by multiplying elements from two lists.\n\n Args:\n list1: The first list of numbers.\n list2: The second list of numbers.\n n: The number of largest products to return.\n\n Returns:\n A list containing the n largest products in descending order.\n \"\"\"\n\n if not list1 or not list2 or n <= 0:\n return []\n\n products = []\n for num1 in list1:\n for num2 in list2:\n products.append(num1 * num2)\n \n return heapq.nlargest(n, products)", "matching_cluster_idx": 3}, {"solution": "import heapq\ndef large_product(list1, list2, n):\n \"\"\"\n Finds the n largest products from two lists, selecting one factor from each.\n\n Args:\n list1: The first list of numbers.\n list2: The second list of numbers.\n n: The number of largest products to return.\n\n Returns:\n A list containing the n largest products in descending order.\n \"\"\"\n\n list1.sort(reverse=True)\n list2.sort(reverse=True)\n\n products = []\n for i in range(len(list1)):\n for j in range(len(list2)):\n products.append(list1[i] * list2[j])\n\n\n return heapq.nlargest(n, products)", "matching_cluster_idx": 3}, {"solution": "import heapq\ndef large_product(list1, list2, num_largest):\n \"\"\"\n Finds the specified number of largest products from two given lists.\n\n Args:\n list1: The first list of numbers.\n list2: The second list of numbers.\n num_largest: The number of largest products to return.\n\n Returns:\n A list containing the 'num_largest' largest products, sorted in descending order.\n \"\"\"\n\n if not list1 or not list2 or num_largest <= 0:\n return []\n\n list1.sort(reverse=True)\n list2.sort(reverse=True)\n\n min_heap = []\n for i in range(len(list1)):\n for j in range(len(list2)):\n product = list1[i] * list2[j]\n if len(min_heap) < num_largest:\n heapq.heappush(min_heap, product)\n elif product > min_heap[0]:\n heapq.heapreplace(min_heap, product)\n\n return sorted(min_heap, reverse=True)", "matching_cluster_idx": 2}, {"solution": "import heapq\ndef large_product(list1, list2, k):\n \"\"\"\n Finds the k largest products from two lists, selecting one factor from each.\n\n Args:\n list1: The first list of numbers.\n list2: The second list of numbers.\n k: The number of largest products to return.\n\n Returns:\n A list containing the k largest products, sorted in descending order.\n \"\"\"\n\n products = []\n for num1 in list1:\n for num2 in list2:\n products.append(num1 * num2)\n\n return heapq.nlargest(k, products)", "matching_cluster_idx": 3}, {"solution": "import heapq\ndef large_product(list1, list2, n):\n \"\"\"\n Finds the n largest products from two given lists, selecting one factor from each list.\n\n Args:\n list1: The first list of numbers.\n list2: The second list of numbers.\n n: The number of largest products to find.\n\n Returns:\n A list containing the n largest products, sorted in descending order.\n \"\"\"\n\n if not list1 or not list2 or n <= 0:\n return []\n\n list1.sort(reverse=True) # Sort in descending order for efficient product generation\n list2.sort(reverse=True)\n\n min_heap = [] # Use a min-heap to store the n largest products\n\n for i in range(len(list1)):\n for j in range(len(list2)):\n product = list1[i] * list2[j]\n\n if len(min_heap) < n:\n heapq.heappush(min_heap, product)\n elif product > min_heap[0]:\n heapq.heapreplace(min_heap, product)\n\n return sorted(min_heap, reverse=True) # Return sorted list in descending order", "matching_cluster_idx": 2}, {"solution": "import heapq\ndef large_product(list1, list2, num_largest):\n \"\"\"\n Finds the specified number of largest products from two lists.\n\n Args:\n list1: The first list of numbers.\n list2: The second list of numbers.\n num_largest: The number of largest products to return.\n\n Returns:\n A list containing the 'num_largest' largest products, sorted in descending order.\n \"\"\"\n\n if not list1 or not list2 or num_largest <= 0:\n return []\n\n products = []\n for x in list1:\n for y in list2:\n products.append(x * y)\n\n return heapq.nlargest(num_largest, products)", "matching_cluster_idx": 3}, {"solution": "import heapq\ndef large_product(list1, list2, n):\n \"\"\"\n Finds the n largest products from two given lists, selecting one factor from each list.\n\n Args:\n list1: The first list of numbers.\n list2: The second list of numbers.\n n: The number of largest products to find.\n\n Returns:\n A list containing the n largest products, sorted in descending order.\n \"\"\"\n\n if not list1 or not list2 or n <= 0:\n return []\n\n list1.sort(reverse=True)\n list2.sort(reverse=True)\n\n min_heap = []\n for i in range(len(list1)):\n for j in range(len(list2)):\n product = list1[i] * list2[j]\n if len(min_heap) < n:\n heapq.heappush(min_heap, product)\n elif product > min_heap[0]:\n heapq.heapreplace(min_heap, product)\n\n return sorted(min_heap, reverse=True)", "matching_cluster_idx": 2}, {"solution": "def large_product(list1, list2, n):\n \"\"\"\n Finds the 'n' largest products from two lists, selecting one factor from each.\n\n Args:\n list1: The first list of numbers.\n list2: The second list of numbers.\n n: The number of largest products to return.\n\n Returns:\n A list containing the 'n' largest products.\n \"\"\"\n\n products = []\n for num1 in list1:\n for num2 in list2:\n products.append(num1 * num2)\n \n products.sort(reverse=True) # Sort in descending order\n return products[:n]", "matching_cluster_idx": 3}, {"solution": "import heapq\ndef large_product(list1, list2, num_largest):\n \"\"\"\n Finds the specified number of largest products from two given lists.\n\n Args:\n list1: The first list of numbers.\n list2: The second list of numbers.\n num_largest: The number of largest products to return.\n\n Returns:\n A list containing the 'num_largest' largest products, sorted in descending order.\n \"\"\"\n\n if not list1 or not list2 or num_largest <= 0:\n return []\n\n list1.sort(reverse=True)\n list2.sort(reverse=True)\n\n min_heap = []\n for i in range(len(list1)):\n for j in range(len(list2)):\n product = list1[i] * list2[j]\n if len(min_heap) < num_largest:\n heapq.heappush(min_heap, product)\n elif product > min_heap[0]:\n heapq.heapreplace(min_heap, product)\n\n return sorted(min_heap, reverse=True)", "matching_cluster_idx": 2}, {"solution": "import heapq\ndef large_product(list1, list2, n):\n \"\"\"\n Finds the n largest products from two lists, selecting one factor from each.\n\n Args:\n list1: The first list of numbers.\n list2: The second list of numbers.\n n: The number of largest products to return.\n\n Returns:\n A list containing the n largest products, sorted in descending order.\n \"\"\"\n\n products = []\n for num1 in list1:\n for num2 in list2:\n products.append(num1 * num2)\n \n return sorted(heapq.nlargest(n, products), reverse=True)", "matching_cluster_idx": 3}, {"solution": "import heapq\nimport heapq\ndef large_product(list1, list2, num_largest):\n \"\"\"\n Finds the specified number of largest products from two lists.\n\n Args:\n list1: The first list of numbers.\n list2: The second list of numbers.\n num_largest: The number of largest products to return.\n\n Returns:\n A list containing the 'num_largest' largest products, sorted in descending order.\n \"\"\"\n if not list1 or not list2 or num_largest <= 0:\n return []\n\n products = []\n for x in list1:\n for y in list2:\n products.append(x * y)\n\n return heapq.nlargest(num_largest, products)", "matching_cluster_idx": 3}, {"solution": "import heapq\ndef large_product(list1, list2, num):\n \"\"\"\n Finds the specified number of largest products from two given lists.\n\n Args:\n list1: The first list of numbers.\n list2: The second list of numbers.\n num: The number of largest products to return.\n\n Returns:\n A list containing the 'num' largest products, sorted in descending order.\n \"\"\"\n\n if not list1 or not list2 or num <= 0:\n return []\n\n products = []\n for x in list1:\n for y in list2:\n products.append(x * y)\n\n return heapq.nlargest(num, products)", "matching_cluster_idx": 3}, {"solution": "import heapq\ndef large_product(list1, list2, num_products):\n \"\"\"\n Finds the specified number of largest products from two given lists.\n\n Args:\n list1: The first list of numbers.\n list2: The second list of numbers.\n num_products: The number of largest products to return.\n\n Returns:\n A list containing the 'num_products' largest products, sorted in descending order.\n \"\"\"\n\n list1.sort(reverse=True)\n list2.sort(reverse=True)\n\n products = []\n for i in range(len(list1)):\n for j in range(len(list2)):\n products.append(list1[i] * list2[j])\n \n return heapq.nlargest(num_products, products)", "matching_cluster_idx": 3}, {"solution": "import heapq\ndef large_product(list1, list2, n):\n \"\"\"\n Finds the n largest products from two lists.\n\n Args:\n list1: The first list of numbers.\n list2: The second list of numbers.\n n: The number of largest products to return.\n\n Returns:\n A list containing the n largest products.\n \"\"\"\n if not list1 or not list2 or n <= 0:\n return []\n\n products = []\n for x in list1:\n for y in list2:\n products.append(x * y)\n\n return heapq.nlargest(n, products)", "matching_cluster_idx": 3}, {"solution": "import heapq\ndef large_product(list1, list2, n):\n \"\"\"\n Finds the n largest products from two lists, selecting one factor from each.\n\n Args:\n list1: The first list of numbers.\n list2: The second list of numbers.\n n: The number of largest products to return.\n\n Returns:\n A list containing the n largest products, sorted in descending order.\n \"\"\"\n\n if not list1 or not list2 or n <= 0:\n return []\n\n products = []\n for num1 in list1:\n for num2 in list2:\n products.append(num1 * num2)\n\n return heapq.nlargest(n, products)", "matching_cluster_idx": 3}, {"solution": "import heapq\ndef large_product(list1, list2, n):\n \"\"\"\n Finds the n largest products from two lists.\n\n Args:\n list1: The first list of numbers.\n list2: The second list of numbers.\n n: The number of largest products to return.\n\n Returns:\n A list containing the n largest products, sorted in descending order.\n \"\"\"\n\n products = []\n for num1 in list1:\n for num2 in list2:\n products.append(num1 * num2)\n \n return heapq.nlargest(n, products)", "matching_cluster_idx": 3}, {"solution": "import heapq\ndef large_product(list1, list2, num_largest):\n \"\"\"\n Finds the specified number of largest products from two given lists.\n\n Args:\n list1: The first list of numbers.\n list2: The second list of numbers.\n num_largest: The number of largest products to return.\n\n Returns:\n A list containing the 'num_largest' largest products, sorted in descending order.\n \"\"\"\n\n if not list1 or not list2 or num_largest <= 0:\n return []\n\n list1.sort(reverse=True)\n list2.sort(reverse=True)\n\n min_heap = []\n for i in range(len(list1)):\n for j in range(len(list2)):\n product = list1[i] * list2[j]\n if len(min_heap) < num_largest:\n heapq.heappush(min_heap, product)\n elif product > min_heap[0]:\n heapq.heapreplace(min_heap, product)\n \n return sorted(min_heap, reverse=True)", "matching_cluster_idx": 2}, {"solution": "import heapq\ndef large_product(list1, list2, num_largest):\n \"\"\"\n Finds the specified number of largest products from two lists.\n\n Args:\n list1: The first list of numbers.\n list2: The second list of numbers.\n num_largest: The number of largest products to return.\n\n Returns:\n A list containing the 'num_largest' largest products, sorted in descending order.\n \"\"\"\n\n if not list1 or not list2 or num_largest <= 0:\n return []\n\n list1.sort(reverse=True)\n list2.sort(reverse=True)\n\n min_heap = []\n for i in range(len(list1)):\n for j in range(len(list2)):\n product = list1[i] * list2[j]\n if len(min_heap) < num_largest:\n heapq.heappush(min_heap, product)\n elif product > min_heap[0]:\n heapq.heapreplace(min_heap, product)\n \n result = sorted(min_heap, reverse=True)\n return result", "matching_cluster_idx": 2}]}, "Mbpp/392": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 32.0, "profiled": [{"solution": "def get_max_sum(n):\n \"\"\"\n Calculates the maximum sum using the given recursive equation.\n\n Args:\n n: The input integer.\n\n Returns:\n The maximum sum possible.\n \"\"\"\n\n memo = {}\n\n def calculate_sum(n):\n if n == 0:\n return 0\n if n in memo:\n return memo[n]\n\n sum_parts = calculate_sum(n // 2) + calculate_sum(n // 3) + calculate_sum(n // 4) + calculate_sum(n // 5)\n memo[n] = max(sum_parts, n)\n return memo[n]\n\n return calculate_sum(n)\nn = 60", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n \"\"\"\n Calculates the maximum sum using the given recursive equation with memoization.\n \"\"\"\n memo = {}\n\n def _get_max_sum(n):\n if n == 0:\n return 0\n if n in memo:\n return memo[n]\n\n result = max(n, _get_max_sum(n // 2) + _get_max_sum(n // 3) + _get_max_sum(n // 4) + _get_max_sum(n // 5))\n memo[n] = result\n return result\n\n return _get_max_sum(n)\nn = 60", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n \"\"\"\n Calculates the maximum sum using the given recursive equation.\n\n Args:\n n: The input number.\n\n Returns:\n The maximum sum.\n \"\"\"\n\n memo = {}\n\n def helper(n):\n if n == 0:\n return 0\n if n in memo:\n return memo[n]\n\n memo[n] = max(n, helper(n // 2) + helper(n // 3) + helper(n // 4) + helper(n // 5))\n return memo[n]\n\n return helper(n)", "matching_cluster_idx": 12}, {"solution": "import math\ndef get_max_sum(n):\n \"\"\"\n Calculates the maximum sum using the given recursive equation with memoization.\n\n Args:\n n: The input number.\n\n Returns:\n The maximum sum achievable.\n \"\"\"\n\n memo = {}\n\n def solve(n):\n if n == 0:\n return 0\n if n in memo:\n return memo[n]\n\n memo[n] = max(n, solve(n // 2) + solve(n // 3) + solve(n // 4) + solve(n // 5))\n return memo[n]\n\n return solve(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n \"\"\"\n Calculates the maximum sum using the given recursive equation with memoization.\n\n Args:\n n: The input number.\n\n Returns:\n The maximum sum.\n \"\"\"\n\n memo = {}\n\n def calculate_sum(num):\n if num == 0:\n return 0\n if num in memo:\n return memo[num]\n\n memo[num] = max(num, calculate_sum(num // 2) + calculate_sum(num // 3) + calculate_sum(num // 4) + calculate_sum(num // 5))\n return memo[num]\n\n return calculate_sum(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n \"\"\"\n Calculates the maximum sum using the given recursive equation.\n\n Args:\n n: The input number.\n\n Returns:\n The maximum sum possible.\n \"\"\"\n\n memo = {}\n\n def helper(n):\n if n == 0:\n return 0\n if n in memo:\n return memo[n]\n \n memo[n] = max(n, helper(n // 2) + helper(n // 3) + helper(n // 4) + helper(n // 5))\n return memo[n]\n\n return helper(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n \"\"\"\n Calculates the maximum sum using the given recursive equation with memoization.\n\n Args:\n n: The input number.\n\n Returns:\n The maximum sum.\n \"\"\"\n\n memo = {}\n\n def helper(n):\n if n == 0:\n return 0\n if n in memo:\n return memo[n]\n\n memo[n] = max(n, helper(n // 2) + helper(n // 3) + helper(n // 4) + helper(n // 5))\n return memo[n]\n\n return helper(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n \"\"\"\n Finds the maximum sum possible by using the given equation f(n) = max( (f(n/2) + f(n/3) + f(n/4) + f(n/5)), n).\n\n Args:\n n: The input number.\n\n Returns:\n The maximum sum.\n \"\"\"\n\n memo = {}\n\n def solve(n):\n if n == 0:\n return 0\n if n in memo:\n return memo[n]\n\n memo[n] = max(solve(n // 2) + solve(n // 3) + solve(n // 4) + solve(n // 5), n)\n return memo[n]\n\n return solve(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n \"\"\"\n Calculates the maximum sum using the given recursive equation.\n\n Args:\n n: The input number.\n\n Returns:\n The maximum sum.\n \"\"\"\n\n memo = {}\n\n def solve(n):\n if n in memo:\n return memo[n]\n\n if n == 0:\n return 0\n\n result = max(n, solve(n // 2) + solve(n // 3) + solve(n // 4) + solve(n // 5))\n memo[n] = result\n return result\n\n return solve(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n \"\"\"\n Calculates the maximum sum using the given recursive equation with memoization.\n \"\"\"\n memo = {}\n\n def _get_max_sum(n):\n if n in memo:\n return memo[n]\n\n if n == 0:\n return 0\n\n result = max(n, _get_max_sum(n // 2) + _get_max_sum(n // 3) + _get_max_sum(n // 4) + _get_max_sum(n // 5))\n memo[n] = result\n return result\n\n return _get_max_sum(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n \"\"\"\n Calculates the maximum sum using the given recursive equation with memoization.\n\n Args:\n n: The input number.\n\n Returns:\n The maximum sum possible.\n \"\"\"\n\n memo = {} # Memoization dictionary to store results of subproblems\n\n def solve(n):\n if n == 0:\n return 0\n if n in memo:\n return memo[n]\n\n memo[n] = max(n, solve(n // 2) + solve(n // 3) + solve(n // 4) + solve(n // 5))\n return memo[n]\n\n return solve(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n \"\"\"\n Calculates the maximum sum using the given recursive equation and memoization.\n\n Args:\n n: The input number.\n\n Returns:\n The maximum sum.\n \"\"\"\n\n memo = {}\n\n def calculate_sum(n):\n if n == 0:\n return 0\n if n in memo:\n return memo[n]\n\n memo[n] = max(n, calculate_sum(n // 2) + calculate_sum(n // 3) + calculate_sum(n // 4) + calculate_sum(n // 5))\n return memo[n]\n\n return calculate_sum(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n \"\"\"\n Calculates the maximum sum using the given recursive equation with memoization.\n \"\"\"\n memo = {}\n\n def calculate_sum(num):\n if num == 0:\n return 0\n if num in memo:\n return memo[num]\n\n sum_parts = calculate_sum(num // 2) + calculate_sum(num // 3) + calculate_sum(num // 4) + calculate_sum(num // 5)\n memo[num] = max(sum_parts, num)\n return memo[num]\n\n return calculate_sum(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n \"\"\"\n Calculates the maximum sum using the given recursive equation and memoization.\n \"\"\"\n memo = {}\n\n def helper(num):\n if num == 0:\n return 0\n if num in memo:\n return memo[num]\n\n result = max(num, helper(num // 2) + helper(num // 3) + helper(num // 4) + helper(num // 5))\n memo[num] = result\n return result\n\n return helper(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n \"\"\"\n Calculates the maximum sum using the given recursive equation with memoization.\n\n Args:\n n: The input number.\n\n Returns:\n The maximum sum achievable.\n \"\"\"\n\n memo = {}\n\n def _get_max_sum(n):\n if n in memo:\n return memo[n]\n\n if n == 0:\n return 0\n \n if n < 1: # Handle potential floating point results that dip below 1\n return n\n\n\n res = max(n, _get_max_sum(n // 2) + _get_max_sum(n // 3) + _get_max_sum(n // 4) + _get_max_sum(n // 5))\n memo[n] = res\n return res\n\n return _get_max_sum(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n \"\"\"\n Calculates the maximum sum using the given recursive equation.\n\n Args:\n n: The input number.\n\n Returns:\n The maximum sum.\n \"\"\"\n\n memo = {} # Memoization dictionary to store results\n\n def _get_max_sum(n):\n if n == 0:\n return 0\n if n in memo:\n return memo[n]\n\n result = max(n, _get_max_sum(n // 2) + _get_max_sum(n // 3) + _get_max_sum(n // 4) + _get_max_sum(n // 5))\n memo[n] = result\n return result\n\n return _get_max_sum(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n \"\"\"\n Calculates the maximum sum using the given recursive equation with memoization.\n\n Args:\n n: The input number.\n\n Returns:\n The maximum sum possible.\n \"\"\"\n\n memo = {}\n\n def _get_max_sum_recursive(n):\n if n == 0:\n return 0\n if n in memo:\n return memo[n]\n\n memo[n] = max(n, _get_max_sum_recursive(n // 2) + _get_max_sum_recursive(n // 3) + _get_max_sum_recursive(n // 4) + _get_max_sum_recursive(n // 5))\n return memo[n]\n\n return _get_max_sum_recursive(n)\nn = 60", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n \"\"\"\n Calculates the maximum sum using the given recursive equation with memoization.\n\n Args:\n n: The input number.\n\n Returns:\n The maximum sum.\n \"\"\"\n\n memo = {}\n\n def helper(n):\n if n == 0:\n return 0\n if n in memo:\n return memo[n]\n\n memo[n] = max(n, helper(n // 2) + helper(n // 3) + helper(n // 4) + helper(n // 5))\n return memo[n]\n\n return helper(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n \"\"\"\n Calculates the maximum sum using the given recursive equation with memoization.\n \"\"\"\n memo = {}\n\n def calculate_sum(num):\n if num == 0:\n return 0\n if num in memo:\n return memo[num]\n\n sum_parts = calculate_sum(num // 2) + calculate_sum(num // 3) + calculate_sum(num // 4) + calculate_sum(num // 5)\n memo[num] = max(sum_parts, num)\n return memo[num]\n\n return calculate_sum(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n \"\"\"\n Calculates the maximum sum using the given recursive equation.\n\n Args:\n n: The input number.\n\n Returns:\n The maximum sum.\n \"\"\"\n\n memo = {}\n\n def calculate_sum(n):\n if n == 0:\n return 0\n if n in memo:\n return memo[n]\n\n sum_parts = calculate_sum(n // 2) + calculate_sum(n // 3) + calculate_sum(n // 4) + calculate_sum(n // 5)\n memo[n] = max(sum_parts, n)\n return memo[n]\n\n return calculate_sum(n)", "matching_cluster_idx": 12}]}, "Mbpp/395": {"dps": 98.08429118773947, "dps_norm": 75.0, "pass@1": 100.0, "profiled": [{"solution": "from collections import Counter\ndef first_non_repeating_character(s):\n \"\"\"\n Finds the first non-repeated character in a given string.\n\n Args:\n s: The input string.\n\n Returns:\n The first non-repeated character, or None if all characters are repeated.\n \"\"\"\n char_counts = Counter(s)\n\n for char in s:\n if char_counts[char] == 1:\n return char\n return None", "matching_cluster_idx": 5}, {"solution": "from collections import Counter\ndef first_non_repeating_character(s):\n \"\"\"\n Finds the first non-repeated character in a string.\n\n Args:\n s: The input string.\n\n Returns:\n The first non-repeated character, or None if all characters are repeated.\n \"\"\"\n char_counts = Counter(s)\n\n for char in s:\n if char_counts[char] == 1:\n return char\n\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n \"\"\"\n Finds the first non-repeated character in a string.\n\n Args:\n s: The input string.\n\n Returns:\n The first non-repeated character, or None if all characters are repeated.\n \"\"\"\n char_counts = {} # Use a dictionary to store character counts\n\n # Count occurrences of each character\n for char in s:\n char_counts[char] = char_counts.get(char, 0) + 1\n\n # Find the first character with a count of 1\n for char in s:\n if char_counts[char] == 1:\n return char\n\n return None # Return None if all characters are repeated", "matching_cluster_idx": 5}, {"solution": "from collections import Counter\ndef first_non_repeating_character(s):\n \"\"\"\n Finds the first non-repeated character in a string.\n\n Args:\n s: The input string.\n\n Returns:\n The first non-repeated character, or None if all characters are repeated.\n \"\"\"\n char_counts = Counter(s) # Count character occurrences\n\n for char in s:\n if char_counts[char] == 1:\n return char\n\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(string):\n \"\"\"\n Finds the first non-repeated character in a string.\n\n Args:\n string: The input string.\n\n Returns:\n The first non-repeated character, or None if all characters are repeated.\n \"\"\"\n char_counts = {} # Use a dictionary to store character counts\n\n # Iterate through the string to count character occurrences\n for char in string:\n char_counts[char] = char_counts.get(char, 0) + 1\n\n # Iterate through the string again to find the first non-repeated character\n for char in string:\n if char_counts[char] == 1:\n return char\n\n return None # Return None if all characters are repeated", "matching_cluster_idx": 5}, {"solution": "from collections import OrderedDict\ndef first_non_repeating_character(s):\n \"\"\"\n Finds the first non-repeated character in a given string.\n\n Args:\n s: The input string.\n\n Returns:\n The first non-repeated character, or None if all characters are repeated.\n \"\"\"\n char_counts = OrderedDict() # Use OrderedDict to maintain insertion order\n\n for char in s:\n char_counts[char] = char_counts.get(char, 0) + 1\n\n for char, count in char_counts.items():\n if count == 1:\n return char\n\n return None", "matching_cluster_idx": 5}, {"solution": "from collections import Counter\ndef first_non_repeating_character(string):\n \"\"\"\n Finds the first non-repeated character in a given string.\n\n Args:\n string: The input string.\n\n Returns:\n The first non-repeated character, or None if all characters are repeated.\n \"\"\"\n\n char_counts = Counter(string)\n\n for char in string:\n if char_counts[char] == 1:\n return char\n\n return None", "matching_cluster_idx": 5}, {"solution": "from collections import OrderedDict\ndef first_non_repeating_character(s):\n \"\"\"\n Finds the first non-repeated character in a string.\n\n Args:\n s: The input string.\n\n Returns:\n The first non-repeated character, or None if all characters are repeated.\n \"\"\"\n char_counts = OrderedDict() # Use OrderedDict to preserve insertion order\n\n for char in s:\n char_counts[char] = char_counts.get(char, 0) + 1\n\n for char, count in char_counts.items():\n if count == 1:\n return char\n\n return None", "matching_cluster_idx": 5}, {"solution": "from collections import Counter\ndef first_non_repeating_character(string):\n \"\"\"\n Finds the first non-repeated character in a string.\n\n Args:\n string: The input string.\n\n Returns:\n The first non-repeated character, or None if all characters are repeated.\n \"\"\"\n char_counts = Counter(string)\n\n for char in string:\n if char_counts[char] == 1:\n return char\n\n return None", "matching_cluster_idx": 5}, {"solution": "from collections import Counter\ndef first_non_repeating_character(string):\n \"\"\"\n Finds the first non-repeated character in a string.\n\n Args:\n string: The input string.\n\n Returns:\n The first non-repeated character, or None if all characters are repeated.\n \"\"\"\n\n char_counts = Counter(string) # Efficiently count character occurrences\n\n for char in string:\n if char_counts[char] == 1:\n return char\n\n return None", "matching_cluster_idx": 5}, {"solution": "from collections import Counter\ndef first_non_repeating_character(s):\n \"\"\"\n Finds the first non-repeated character in a string.\n\n Args:\n s: The input string.\n\n Returns:\n The first non-repeated character, or None if all characters are repeated.\n \"\"\"\n char_counts = Counter(s)\n\n for char in s:\n if char_counts[char] == 1:\n return char\n\n return None", "matching_cluster_idx": 5}, {"solution": "from collections import OrderedDict\ndef first_non_repeating_character(s):\n \"\"\"\n Finds the first non-repeated character in a string.\n\n Args:\n s: The input string.\n\n Returns:\n The first non-repeated character, or None if all characters are repeated.\n \"\"\"\n char_counts = OrderedDict() # Use OrderedDict to preserve insertion order\n\n for char in s:\n char_counts[char] = char_counts.get(char, 0) + 1\n\n for char, count in char_counts.items():\n if count == 1:\n return char\n\n return None", "matching_cluster_idx": 5}, {"solution": "from collections import Counter\ndef first_non_repeating_character(s):\n \"\"\"\n Finds the first non-repeated character in a string.\n\n Args:\n s: The input string.\n\n Returns:\n The first non-repeated character, or None if all characters are repeated.\n \"\"\"\n char_counts = Counter(s)\n\n for char in s:\n if char_counts[char] == 1:\n return char\n\n return None", "matching_cluster_idx": 5}, {"solution": "from collections import Counter\ndef first_non_repeating_character(string):\n \"\"\"\n Finds the first non-repeated character in a string.\n\n Args:\n string: The input string.\n\n Returns:\n The first non-repeated character, or None if all characters are repeated.\n \"\"\"\n char_counts = Counter(string) # Efficiently count character occurrences\n\n for char in string:\n if char_counts[char] == 1:\n return char\n\n return None", "matching_cluster_idx": 5}, {"solution": "from collections import OrderedDict\ndef first_non_repeating_character(string):\n \"\"\"\n Finds the first non-repeated character in a string.\n\n Args:\n string: The input string.\n\n Returns:\n The first non-repeated character, or None if all characters are repeated.\n \"\"\"\n\n char_counts = OrderedDict() # Use OrderedDict to preserve insertion order\n\n for char in string:\n char_counts[char] = char_counts.get(char, 0) + 1\n\n for char, count in char_counts.items():\n if count == 1:\n return char\n\n return None", "matching_cluster_idx": 5}, {"solution": "from collections import Counter\ndef first_non_repeating_character(string):\n \"\"\"\n Finds the first non-repeated character in a string.\n\n Args:\n string: The input string.\n\n Returns:\n The first non-repeated character, or None if all characters are repeated.\n \"\"\"\n char_counts = Counter(string)\n\n for char in string:\n if char_counts[char] == 1:\n return char\n\n return None", "matching_cluster_idx": 5}, {"solution": "from collections import Counter\ndef first_non_repeating_character(s):\n \"\"\"\n Finds the first non-repeated character in a string.\n\n Args:\n s: The input string.\n\n Returns:\n The first non-repeated character, or None if all characters are repeated.\n \"\"\"\n char_counts = Counter(s) # Count character occurrences efficiently\n\n for char in s:\n if char_counts[char] == 1:\n return char\n\n return None", "matching_cluster_idx": 5}, {"solution": "from collections import Counter\ndef first_non_repeating_character(s):\n \"\"\"\n Finds the first non-repeated character in a string.\n\n Args:\n s: The input string.\n\n Returns:\n The first non-repeated character, or None if all characters are repeated.\n \"\"\"\n char_counts = Counter(s) # Count character occurrences efficiently\n\n for char in s:\n if char_counts[char] == 1:\n return char\n\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n \"\"\"\n Finds the first non-repeated character in a string.\n\n Args:\n s: The input string.\n\n Returns:\n The first non-repeated character, or None if all characters are repeated.\n \"\"\"\n char_counts = {} # Use a dictionary to store character counts\n\n # Count the occurrences of each character\n for char in s:\n char_counts[char] = char_counts.get(char, 0) + 1\n\n # Find the first character with a count of 1\n for char in s:\n if char_counts[char] == 1:\n return char\n\n return None # Return None if no non-repeated character is found", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n \"\"\"\n Finds the first non-repeated character in a given string.\n\n Args:\n s: The input string.\n\n Returns:\n The first non-repeated character, or None if all characters are repeated.\n \"\"\"\n char_counts = {} # Dictionary to store character counts\n\n for char in s:\n char_counts[char] = char_counts.get(char, 0) + 1\n\n for char in s:\n if char_counts[char] == 1:\n return char\n\n return None", "matching_cluster_idx": 5}]}, "Mbpp/405": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def check_tuplex(tuplex, element):\n \"\"\"\n Checks if an element exists within a tuple.\n\n Args:\n tuplex: The tuple to search.\n element: The element to search for.\n\n Returns:\n True if the element is found in the tuple, False otherwise.\n \"\"\"\n return element in tuplex", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(input_tuple, element):\n \"\"\"\n Checks if an element exists within a tuple.\n\n Args:\n input_tuple: The tuple to search within.\n element: The element to search for.\n\n Returns:\n True if the element exists in the tuple, False otherwise.\n \"\"\"\n return element in input_tuple", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, element):\n \"\"\"\n Checks if an element exists within a tuple.\n\n Args:\n tuplex: The tuple to search.\n element: The element to search for.\n\n Returns:\n True if the element is found in the tuple, False otherwise.\n \"\"\"\n return element in tuplex", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(input_tuple, element):\n \"\"\"\n Checks if an element exists within a tuple.\n\n Args:\n input_tuple: The tuple to search within.\n element: The element to search for.\n\n Returns:\n True if the element exists in the tuple, False otherwise.\n \"\"\"\n return element in input_tuple", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(input_tuple, element):\n \"\"\"\n Checks if an element exists within a tuple.\n\n Args:\n input_tuple: The tuple to search within.\n element: The element to search for.\n\n Returns:\n True if the element exists in the tuple, False otherwise.\n \"\"\"\n return element in input_tuple", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(input_tuple, element):\n \"\"\"\n Checks if an element exists within a tuple.\n\n Args:\n input_tuple: The tuple to search within.\n element: The element to search for.\n\n Returns:\n True if the element exists in the tuple, False otherwise.\n \"\"\"\n return element in input_tuple", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(input_tuple, element):\n \"\"\"\n Checks if an element exists within a tuple.\n\n Args:\n input_tuple: The tuple to search within.\n element: The element to search for.\n\n Returns:\n True if the element is found in the tuple, False otherwise.\n \"\"\"\n return element in input_tuple", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(input_tuple, element):\n \"\"\"\n Checks if an element exists within a tuple.\n\n Args:\n input_tuple: The tuple to search within.\n element: The element to search for.\n\n Returns:\n True if the element exists in the tuple, False otherwise.\n \"\"\"\n return element in input_tuple", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, element):\n \"\"\"\n Checks if an element exists within a tuple.\n\n Args:\n tuplex: The tuple to search.\n element: The element to search for.\n\n Returns:\n True if the element exists in the tuple, False otherwise.\n \"\"\"\n return element in tuplex", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(input_tuple, element):\n \"\"\"\n Checks if an element exists within a tuple.\n\n Args:\n input_tuple: The tuple to search within.\n element: The element to search for.\n\n Returns:\n True if the element is found in the tuple, False otherwise.\n \"\"\"\n return element in input_tuple", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, element):\n \"\"\"\n Checks if an element exists within a tuple.\n\n Args:\n tuplex: The tuple to search.\n element: The element to search for.\n\n Returns:\n True if the element is found in the tuple, False otherwise.\n \"\"\"\n return element in tuplex", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(input_tuple, element):\n \"\"\"Checks if an element exists within a tuple.\n\n Args:\n input_tuple: The tuple to search within.\n element: The element to search for.\n\n Returns:\n True if the element is found, False otherwise.\n \"\"\"\n return element in input_tuple", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(input_tuple, element):\n \"\"\"\n Checks if an element exists within a tuple.\n\n Args:\n input_tuple: The tuple to search within.\n element: The element to search for.\n\n Returns:\n True if the element is found in the tuple, False otherwise.\n \"\"\"\n return element in input_tuple", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(input_tuple, element):\n \"\"\"\n Checks if an element exists within a tuple.\n\n Args:\n input_tuple: The tuple to search within.\n element: The element to search for.\n\n Returns:\n True if the element exists in the tuple, False otherwise.\n \"\"\"\n return element in input_tuple", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(input_tuple, element):\n \"\"\"\n Checks if an element exists within a tuple.\n\n Args:\n input_tuple: The tuple to search within.\n element: The element to search for.\n\n Returns:\n True if the element exists in the tuple, False otherwise.\n \"\"\"\n return element in input_tuple", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, element):\n \"\"\"Checks if an element exists within a tuple.\n\n Args:\n tuplex: The tuple to search within.\n element: The element to search for.\n\n Returns:\n True if the element exists in the tuple, False otherwise.\n \"\"\"\n return element in tuplex", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(test_tup, elem):\n \"\"\"\n Checks if an element exists within a tuple.\n\n Args:\n test_tup: The tuple to search within.\n elem: The element to search for.\n\n Returns:\n True if the element is found in the tuple, False otherwise.\n \"\"\"\n return elem in test_tup", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(input_tuple, element):\n \"\"\"\n Checks if an element exists within a tuple.\n\n Args:\n input_tuple: The tuple to search within.\n element: The element to search for.\n\n Returns:\n True if the element exists in the tuple, False otherwise.\n \"\"\"\n return element in input_tuple", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(input_tuple, element):\n \"\"\"\n Checks if an element exists within a tuple.\n\n Args:\n input_tuple: The tuple to search within.\n element: The element to search for.\n\n Returns:\n True if the element is found in the tuple, False otherwise.\n \"\"\"\n return element in input_tuple", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(test_tup, elem):\n \"\"\"\n Checks if an element exists within a tuple.\n\n Args:\n test_tup: The tuple to search.\n elem: The element to search for.\n\n Returns:\n True if the element is found in the tuple, False otherwise.\n \"\"\"\n return elem in test_tup", "matching_cluster_idx": 3}]}, "Mbpp/414": {"dps": 85.90062111801242, "dps_norm": 86.66666666666666, "pass@1": 100.0, "profiled": [{"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Checks if any element in seq1 exists in seq2.\n\n Args:\n seq1: The first sequence (list or tuple).\n seq2: The second sequence (list or tuple).\n\n Returns:\n True if any element in seq1 is present in seq2, False otherwise.\n \"\"\"\n for item in seq1:\n if item in seq2:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Checks if any value in seq1 exists in seq2.\n\n Args:\n seq1: The first sequence (list or tuple).\n seq2: The second sequence (list or tuple).\n\n Returns:\n True if any value in seq1 is present in seq2, False otherwise.\n \"\"\"\n set1 = set(seq1) # Convert to sets for efficient membership checking\n set2 = set(seq2)\n return bool(set1.intersection(set2)) # Returns True if the intersection isn't empty, False otherwise", "matching_cluster_idx": 5}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Checks if any value in seq1 exists in seq2.\n\n Args:\n seq1: The first sequence (list or tuple).\n seq2: The second sequence (list or tuple).\n\n Returns:\n True if any value in seq1 is present in seq2, False otherwise.\n \"\"\"\n\n for item in seq1:\n if item in seq2:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(sequence1, sequence2):\n \"\"\"\n Checks if any value in sequence1 exists in sequence2.\n\n Args:\n sequence1: The first sequence (list or tuple).\n sequence2: The second sequence (list or tuple).\n\n Returns:\n True if any value in sequence1 is present in sequence2, False otherwise.\n \"\"\"\n for value in sequence1:\n if value in sequence2:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Checks if any element in seq1 exists in seq2.\n\n Args:\n seq1: The first sequence (list or tuple).\n seq2: The second sequence (list or tuple).\n\n Returns:\n True if any element in seq1 is present in seq2, False otherwise.\n \"\"\"\n for item in seq1:\n if item in seq2:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Checks if any element in seq1 exists in seq2.\n\n Args:\n seq1: The first sequence (list or tuple).\n seq2: The second sequence (list or tuple).\n\n Returns:\n True if any element in seq1 is present in seq2, False otherwise.\n \"\"\"\n for item in seq1:\n if item in seq2:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Checks if any value in seq1 exists in seq2.\n\n Args:\n seq1: The first sequence (list or tuple).\n seq2: The second sequence (list or tuple).\n\n Returns:\n True if any value in seq1 is present in seq2, False otherwise.\n \"\"\"\n for item in seq1:\n if item in seq2:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Checks if any value in seq1 exists in seq2.\n\n Args:\n seq1: The first sequence (list or tuple).\n seq2: The second sequence (list or tuple).\n\n Returns:\n True if any value in seq1 is present in seq2, False otherwise.\n \"\"\"\n for item in seq1:\n if item in seq2:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Checks if any element in seq1 exists in seq2.\n\n Args:\n seq1: The first sequence (list or tuple).\n seq2: The second sequence (list or tuple).\n\n Returns:\n True if any element in seq1 is present in seq2, False otherwise.\n \"\"\"\n for item in seq1:\n if item in seq2:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Checks if any value in seq1 exists in seq2.\n\n Args:\n seq1: The first sequence (list or tuple).\n seq2: The second sequence (list or tuple).\n\n Returns:\n True if any value in seq1 is present in seq2, False otherwise.\n \"\"\"\n for item in seq1:\n if item in seq2:\n return True\n return False\nseq1 = [1, 2, 3]\nseq2 = [4, 5, 6]", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Checks if any element in seq1 exists in seq2.\n\n Args:\n seq1: The first sequence (list or tuple).\n seq2: The second sequence (list or tuple).\n\n Returns:\n True if any element in seq1 is present in seq2, False otherwise.\n \"\"\"\n for item in seq1:\n if item in seq2:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Checks if any element in seq1 exists in seq2.\n\n Args:\n seq1: The first sequence (list or tuple).\n seq2: The second sequence (list or tuple).\n\n Returns:\n True if any element in seq1 is present in seq2, False otherwise.\n \"\"\"\n for item in seq1:\n if item in seq2:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Checks if any element in seq1 exists in seq2.\n\n Args:\n seq1: The first sequence (list or tuple).\n seq2: The second sequence (list or tuple).\n\n Returns:\n True if any element of seq1 is present in seq2, False otherwise.\n \"\"\"\n for item in seq1:\n if item in seq2:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Checks if any element in seq1 exists in seq2.\n\n Args:\n seq1: The first sequence (list or tuple).\n seq2: The second sequence (list or tuple).\n\n Returns:\n True if any element in seq1 is present in seq2, False otherwise.\n \"\"\"\n for item in seq1:\n if item in seq2:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Checks if any element in seq1 exists in seq2.\n\n Args:\n seq1: The first sequence (list or tuple).\n seq2: The second sequence (list or tuple).\n\n Returns:\n True if any element in seq1 is present in seq2, False otherwise.\n \"\"\"\n for item in seq1:\n if item in seq2:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Checks if any element in seq1 exists in seq2.\n\n Args:\n seq1: The first sequence (list or tuple).\n seq2: The second sequence (list or tuple).\n\n Returns:\n True if any element in seq1 is present in seq2, False otherwise.\n \"\"\"\n for item in seq1:\n if item in seq2:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(sequence1, sequence2):\n \"\"\"\n Checks if any element in sequence1 exists in sequence2.\n\n Args:\n sequence1: The first sequence (list or tuple).\n sequence2: The second sequence (list or tuple).\n\n Returns:\n True if any element in sequence1 is also in sequence2, False otherwise.\n \"\"\"\n\n for item in sequence1:\n if item in sequence2:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Checks if any element in seq1 exists in seq2.\n\n Args:\n seq1: The first sequence (list or tuple).\n seq2: The second sequence (list or tuple).\n\n Returns:\n True if any element in seq1 is present in seq2, False otherwise.\n \"\"\"\n for item in seq1:\n if item in seq2:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Checks if any element in seq1 exists in seq2.\n\n Args:\n seq1: The first sequence.\n seq2: The second sequence.\n\n Returns:\n True if any element overlaps, False otherwise.\n \"\"\"\n\n # Efficient solution using set intersection:\n return bool(set(seq1).intersection(seq2))\n\n # Alternatively, a more explicit (but potentially slower) solution:\n # for item in seq1:\n # if item in seq2:\n # return True\n # return False", "matching_cluster_idx": 5}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Checks if any value in seq1 exists in seq2.\n\n Args:\n seq1: The first sequence (list or tuple).\n seq2: The second sequence (list or tuple).\n\n Returns:\n True if any value in seq1 is present in seq2, False otherwise.\n \"\"\"\n for item in seq1:\n if item in seq2:\n return True\n return False", "matching_cluster_idx": 7}]}, "Mbpp/421": {"dps": 64.44444444444444, "dps_norm": 76.42857142857143, "pass@1": 100.0, "profiled": [{"solution": "def concatenate_tuple(input_tuple, delimiter=\"-\"):\n \"\"\"Concatenates elements of a tuple with a delimiter.\n\n Args:\n input_tuple: The tuple to concatenate.\n delimiter: The string to use as a delimiter. Defaults to \"-\".\n\n Returns:\n A string containing the concatenated elements.\n \"\"\"\n \n string_elements = [str(element) for element in input_tuple]\n return delimiter.join(string_elements)", "matching_cluster_idx": 5}, {"solution": "def concatenate_tuple(input_tuple):\n \"\"\"\n Concatenates each element of a tuple, converting each element to a string and joining them with a hyphen.\n\n Args:\n input_tuple: The input tuple.\n\n Returns:\n A string with all elements concatenated by hyphens.\n \"\"\"\n return \"-\".join(map(str, input_tuple))", "matching_cluster_idx": 5}, {"solution": "def concatenate_tuple(input_tuple, delimiter='-'):\n \"\"\"Concatenates each element of a tuple using the specified delimiter.\n\n Args:\n input_tuple: The tuple to concatenate.\n delimiter: The string used to separate the elements. Defaults to '-'.\n\n Returns:\n A string containing the concatenated elements.\n \"\"\"\n\n result = \"\"\n for i, element in enumerate(input_tuple):\n result += str(element)\n if i < len(input_tuple) - 1:\n result += delimiter\n return result", "matching_cluster_idx": 1}, {"solution": "def concatenate_tuple(input_tuple, delimiter=\"-\"):\n \"\"\"\n Concatenates elements of a tuple with a given delimiter.\n\n Args:\n input_tuple: The tuple to concatenate.\n delimiter: The string to use as a delimiter.\n\n Returns:\n A string containing the concatenated elements.\n \"\"\"\n\n converted_elements = [str(element) for element in input_tuple] # Convert all elements to strings\n return delimiter.join(converted_elements)", "matching_cluster_idx": 5}, {"solution": "def concatenate_tuple(input_tuple, delimiter=\"-\"):\n \"\"\"Concatenates tuple elements with a delimiter.\n\n Args:\n input_tuple: The tuple to concatenate.\n delimiter: The delimiter to use (default is \"-\").\n\n Returns:\n A string with the concatenated elements.\n Returns an empty string if the input is not a tuple or the tuple is empty.\n\n \"\"\"\n if not isinstance(input_tuple, tuple):\n return \"\"\n if not input_tuple:\n return \"\"\n \n string_elements = [str(element) for element in input_tuple] # Convert all to string\n return delimiter.join(string_elements)", "matching_cluster_idx": 5}, {"solution": "def concatenate_tuple(input_tuple, delimiter=\"-\"):\n \"\"\"\n Concatenates each element of a tuple using a specified delimiter.\n\n Args:\n input_tuple: The tuple to concatenate.\n delimiter: The string used to separate the elements. Defaults to \"-\".\n\n Returns:\n A string containing the concatenated elements.\n \"\"\"\n \n converted_elements = [str(element) for element in input_tuple] # Convert all elements to strings\n return delimiter.join(converted_elements)", "matching_cluster_idx": 5}, {"solution": "def concatenate_tuple(input_tuple, delimiter=\"-\"):\n \"\"\"\n Concatenates elements of a tuple with a specified delimiter.\n\n Args:\n input_tuple: The tuple to concatenate.\n delimiter: The string to use as a delimiter between elements.\n\n Returns:\n A string containing the concatenated elements.\n \"\"\"\n\n string_elements = [str(element) for element in input_tuple]\n return delimiter.join(string_elements)", "matching_cluster_idx": 5}, {"solution": "def concatenate_tuple(input_tuple, delimiter=\"-\"):\n \"\"\"Concatenates each element of a tuple with a delimiter.\n\n Args:\n input_tuple: The input tuple.\n delimiter: The delimiter string. Defaults to \"-\".\n\n Returns:\n The concatenated string.\n \"\"\"\n\n string_list = [str(element) for element in input_tuple] # Convert elements to strings\n return delimiter.join(string_list)", "matching_cluster_idx": 5}, {"solution": "def concatenate_tuple(input_tuple, delimiter=\"-\"):\n \"\"\"\n Concatenates elements of a tuple with a specified delimiter.\n\n Args:\n input_tuple: The tuple to concatenate.\n delimiter: The string to use as a delimiter. Defaults to \"-\".\n\n Returns:\n A string with the concatenated elements.\n \"\"\"\n\n concatenated_string = \"\"\n for i, element in enumerate(input_tuple):\n concatenated_string += str(element) # Convert elements to strings\n if i < len(input_tuple) - 1:\n concatenated_string += delimiter\n return concatenated_string", "matching_cluster_idx": 1}, {"solution": "def concatenate_tuple(input_tuple, delimiter=\"-\"):\n \"\"\"Concatenates elements of a tuple with a delimiter.\n\n Args:\n input_tuple: The tuple to concatenate.\n delimiter: The delimiter to use between elements. Defaults to \"-\".\n\n Returns:\n A string containing the concatenated elements.\n \"\"\"\n \n concatenated_string = delimiter.join(map(str, input_tuple))\n return concatenated_string", "matching_cluster_idx": 6}, {"solution": "def concatenate_tuple(input_tuple, delimiter=\"-\"):\n \"\"\"\n Concatenates elements of a tuple with a specified delimiter.\n\n Args:\n input_tuple: The tuple to concatenate.\n delimiter: The string to use as a delimiter. Defaults to \"-\".\n\n Returns:\n A string with the concatenated elements.\n \"\"\"\n \n concatenated_string = \"\"\n for i, element in enumerate(input_tuple):\n concatenated_string += str(element)\n if i < len(input_tuple) - 1:\n concatenated_string += delimiter\n return concatenated_string", "matching_cluster_idx": 1}, {"solution": "def concatenate_tuple(input_tuple, delimiter=\"-\"):\n \"\"\"\n Concatenates each element of a tuple with a given delimiter.\n\n Args:\n input_tuple: The input tuple.\n delimiter: The delimiter to use (default is \"-\").\n\n Returns:\n A string representing the concatenated tuple elements.\n \"\"\"\n\n converted_elements = [str(element) for element in input_tuple] # Convert all elements to strings\n return delimiter.join(converted_elements)", "matching_cluster_idx": 5}, {"solution": "def concatenate_tuple(input_tuple, delimiter=\"-\"):\n \"\"\"\n Concatenates elements of a tuple using a delimiter.\n\n Args:\n input_tuple: The tuple to concatenate.\n delimiter: The string to use as a delimiter between elements. Defaults to \"-\".\n\n Returns:\n A string containing the concatenated elements.\n \"\"\"\n\n converted_elements = [str(element) for element in input_tuple]\n return delimiter.join(converted_elements)", "matching_cluster_idx": 5}, {"solution": "def concatenate_tuple(input_tuple, delimiter=\"-\"):\n \"\"\"\n Concatenates each element of a tuple with a specified delimiter.\n\n Args:\n input_tuple: The input tuple.\n delimiter: The delimiter to use (default is \"-\").\n\n Returns:\n The concatenated string.\n \"\"\"\n\n string_elements = [str(element) for element in input_tuple]\n return delimiter.join(string_elements)", "matching_cluster_idx": 5}, {"solution": "def concatenate_tuple(input_tuple, delimiter=\"-\"):\n \"\"\"Concatenates elements of a tuple with a delimiter.\n\n Args:\n input_tuple: The tuple to concatenate.\n delimiter: The delimiter to use. Defaults to \"-\".\n\n Returns:\n A string with the concatenated elements.\n \"\"\"\n \n string_elements = [str(element) for element in input_tuple] # Convert all elements to strings\n return delimiter.join(string_elements)", "matching_cluster_idx": 5}, {"solution": "def concatenate_tuple(input_tuple, delimiter=\"-\"):\n \"\"\"Concatenates elements of a tuple with a delimiter.\n\n Args:\n input_tuple: The tuple to concatenate.\n delimiter: The string to use as a delimiter. Defaults to \"-\".\n\n Returns:\n A string with the concatenated elements.\n \"\"\"\n\n string_elements = [str(element) for element in input_tuple] # Convert all elements to strings\n return delimiter.join(string_elements)", "matching_cluster_idx": 5}, {"solution": "def concatenate_tuple(input_tuple, delimiter=\"-\"):\n \"\"\"Concatenates each element of a tuple with a delimiter.\n\n Args:\n input_tuple: The tuple to concatenate.\n delimiter: The delimiter to use. Defaults to \"-\".\n\n Returns:\n A string containing the concatenated elements.\n Returns an empty string if the input tuple is empty.\n \"\"\"\n if not input_tuple:\n return \"\"\n\n result = str(input_tuple[0])\n for i in range(1, len(input_tuple)):\n result += delimiter + str(input_tuple[i])\n return result", "matching_cluster_idx": 2}, {"solution": "def concatenate_tuple(input_tuple, delimiter=\"-\"):\n \"\"\"\n Concatenates each element of a tuple with a delimiter.\n\n Args:\n input_tuple: The input tuple.\n delimiter: The delimiter string. Defaults to \"-\".\n\n Returns:\n A string with the concatenated elements.\n\n Raises:\n TypeError: If input_tuple is not a tuple.\n \"\"\"\n\n if not isinstance(input_tuple, tuple):\n raise TypeError(\"Input must be a tuple.\")\n\n string_elements = [str(element) for element in input_tuple]\n return delimiter.join(string_elements)", "matching_cluster_idx": 5}, {"solution": "def concatenate_tuple(input_tuple, delimiter=\"-\"):\n \"\"\"Concatenates elements of a tuple with a delimiter.\n\n Args:\n input_tuple: The input tuple.\n delimiter: The delimiter to use. Defaults to \"-\".\n\n Returns:\n The concatenated string, or an empty string if the tuple is empty.\n \"\"\"\n\n if not input_tuple:\n return \"\"\n\n # Convert all elements to strings\n string_tuple = tuple(map(str, input_tuple))\n\n return delimiter.join(string_tuple)", "matching_cluster_idx": 6}, {"solution": "def concatenate_tuple(input_tuple, delimiter=\"-\"):\n \"\"\"Concatenates tuple elements with a delimiter.\n\n Args:\n input_tuple: The input tuple.\n delimiter: The delimiter string. Defaults to \"-\".\n\n Returns:\n The concatenated string, or an empty string if the tuple is empty.\n \"\"\"\n\n if not input_tuple:\n return \"\"\n\n # Convert each element to a string before joining.\n string_elements = [str(element) for element in input_tuple]\n return delimiter.join(string_elements)", "matching_cluster_idx": 5}]}, "Mbpp/424": {"dps": 5.054151624548736, "dps_norm": 44.0, "pass@1": 100.0, "profiled": [{"solution": "def extract_rear(input_tuple):\n \"\"\"\n Extracts the last character of each string in a tuple.\n\n Args:\n input_tuple: A tuple of strings.\n\n Returns:\n A list containing the last character of each string in the input tuple.\n Returns an empty list if the input tuple is empty or contains non-strings.\n \"\"\"\n result = []\n for item in input_tuple:\n if isinstance(item, str) and item: # Check if the item is a string and not empty\n result.append(item[-1])\n elif isinstance(item, str) and not item: # Handle empty strings\n result.append(\"\") # Append empty string for empty string input\n\n\n return result", "matching_cluster_idx": 1}, {"solution": "def extract_rear(input_tuple):\n \"\"\"\n Extracts the last character of each string in a tuple.\n\n Args:\n input_tuple: A tuple of strings.\n\n Returns:\n A list containing the last character of each string in the input tuple.\n Returns an empty list if the input tuple is empty or contains non-string elements.\n \"\"\"\n result = []\n for item in input_tuple:\n if isinstance(item, str) and item: # Check if the item is a string and not empty\n result.append(item[-1])\n elif isinstance(item, str) and not item: # Handle empty strings\n result.append(\"\") # or raise an exception if needed.\n # No 'else' needed. Silently ignore non-string entries.\n\n return result", "matching_cluster_idx": 1}, {"solution": "def extract_rear(input_tuple):\n \"\"\"\n Extracts the last character of each string in a tuple.\n\n Args:\n input_tuple: A tuple of strings.\n\n Returns:\n A list containing the last character of each string in the input tuple.\n Returns an empty list if the input tuple is empty or contains non-strings.\n \"\"\"\n result = []\n for item in input_tuple:\n if isinstance(item, str) and item: # Check if the item is a string and not empty\n result.append(item[-1])\n elif isinstance(item, str) and not item: # Handle empty strings\n result.append(\"\") # or raise an error if that's the preferred behavior\n elif not isinstance(item, str): # Handle non-string tuple entries, perhaps by skipping or raising error\n continue # or raise TypeError(\"Tuple elements must be strings\")\n\n return result", "matching_cluster_idx": 1}, {"solution": "def extract_rear(input_tuple):\n \"\"\"\n Extracts the last character of each string in a tuple.\n\n Args:\n input_tuple: A tuple of strings.\n\n Returns:\n A list containing the last character of each string in the input tuple.\n Returns an empty list if the input tuple is empty or contains non-string elements.\n \"\"\"\n result = []\n for item in input_tuple:\n if isinstance(item, str) and item: # Check if the item is a string and not empty\n result.append(item[-1])\n elif isinstance(item, str) and not item: # Handles empty strings\n continue # or append \"\" depending on desired behavior. Here, we skip empty strings.\n\n return result", "matching_cluster_idx": 1}, {"solution": "def extract_rear(input_tuple):\n \"\"\"\n Extracts the last character of each string in a tuple.\n\n Args:\n input_tuple: A tuple of strings.\n\n Returns:\n A list containing the last character of each string in the input tuple.\n Returns an empty list if the input tuple is empty or contains non-string elements.\n \"\"\"\n result = []\n for item in input_tuple:\n if isinstance(item, str) and item: # Check if the item is a string and not empty\n result.append(item[-1])\n elif isinstance(item, str) and not item: # Handle empty strings\n result.append(\"\") # Or raise an error if that's the desired behaviour.\n \n return result", "matching_cluster_idx": 1}, {"solution": "def extract_rear(input_tuple):\n \"\"\"Extracts the last character of each string in a tuple.\n\n Args:\n input_tuple: A tuple of strings.\n\n Returns:\n A list containing the last character of each string in the input tuple. \n Returns an empty list if the input tuple is empty or contains empty strings.\n \"\"\"\n\n result = []\n for item in input_tuple:\n if item: # Check if the string is not empty\n result.append(item[-1])\n return result", "matching_cluster_idx": 2}, {"solution": "def extract_rear(input_tuple):\n \"\"\"\n Extracts the last character of each string in a tuple.\n\n Args:\n input_tuple: A tuple of strings.\n\n Returns:\n A list containing the last character of each string in the input tuple.\n Returns an empty list if the input tuple is empty or contains non-string elements.\n \"\"\"\n result = []\n for item in input_tuple:\n if isinstance(item, str) and item: # Check if the item is a string and not empty\n result.append(item[-1])\n elif isinstance(item, str) and not item: # Handle empty strings\n result.append(\"\") # Add empty string to the result for consistency\n \n return result", "matching_cluster_idx": 1}, {"solution": "def extract_rear(input_tuple):\n \"\"\"\n Extracts the last character of each string in a tuple.\n\n Args:\n input_tuple: A tuple of strings.\n\n Returns:\n A list containing the last character of each string in the input tuple.\n Returns an empty list if the input tuple is empty or contains empty strings.\n \"\"\"\n\n result = []\n for string in input_tuple:\n if string: # Check if the string is not empty\n result.append(string[-1])\n return result", "matching_cluster_idx": 2}, {"solution": "def extract_rear(input_tuple):\n \"\"\"\n Extracts the last character of each string in a tuple.\n\n Args:\n input_tuple: A tuple of strings.\n\n Returns:\n A list containing the last character of each string. \n Returns an empty list if the input tuple is empty or contains non-strings.\n \"\"\"\n result = []\n for item in input_tuple:\n if isinstance(item, str) and item: # Check if the item is a string and not empty\n result.append(item[-1])\n elif not isinstance(item, str):\n return [] # Handles cases where non-string elements are in the tuple\n\n return result", "matching_cluster_idx": 1}, {"solution": "def extract_rear(input_tuple):\n \"\"\"\n Extracts the last character of each string in a tuple.\n\n Args:\n input_tuple: A tuple of strings.\n\n Returns:\n A list containing the last character of each string in the input tuple.\n Returns an empty list if the input tuple is empty or contains non-string elements.\n \"\"\"\n result = []\n for item in input_tuple:\n if isinstance(item, str) and item: # Check if the item is a string and not empty\n result.append(item[-1])\n elif isinstance(item, str) and not item: #Handle empty strings\n result.append(\"\") # or raise an exception if preferred. This version preserves indices.\n \n return result", "matching_cluster_idx": 1}, {"solution": "def extract_rear(input_tuple):\n \"\"\"\n Extracts the last character of each string in a tuple.\n\n Args:\n input_tuple: A tuple of strings.\n\n Returns:\n A list containing the last character of each string in the input tuple.\n Returns an empty list if the input tuple is empty or contains empty strings.\n \"\"\"\n result = []\n for string in input_tuple:\n if string: # Check if the string is not empty\n result.append(string[-1])\n return result", "matching_cluster_idx": 3}, {"solution": "def extract_rear(input_tuple):\n \"\"\"\n Extracts the last character of each string in a tuple.\n\n Args:\n input_tuple: A tuple of strings.\n\n Returns:\n A list containing the last character of each string in the input tuple.\n Returns an empty list if the input tuple is empty or contains non-strings.\n \"\"\"\n result = []\n for item in input_tuple:\n if isinstance(item, str) and item: # Check if the item is a string and not empty\n result.append(item[-1])\n elif not isinstance(item, str):\n return [] # Handles cases where tuple elements are not strings\n return result", "matching_cluster_idx": 1}, {"solution": "def extract_rear(strings_tuple):\n \"\"\"\n Extracts the last character of each string in a tuple.\n\n Args:\n strings_tuple: A tuple of strings.\n\n Returns:\n A list containing the last character of each string in the input tuple. \n Returns an empty list if the input tuple is empty or contains non-string elements.\n \"\"\"\n result = []\n for item in strings_tuple:\n if isinstance(item, str) and item: # Check if the item is a string and not empty\n result.append(item[-1])\n elif isinstance(item, str) and not item: # Handle empty strings\n result.append(\"\") # Or raise an exception if desired behavior is different\n else:\n #Handle cases where tuple might contain non-string elements - return empty list to be consistent with test cases\n return [] # Or raise a TypeError if that is desired behavior\n return result", "matching_cluster_idx": 1}, {"solution": "def extract_rear(input_tuple):\n \"\"\"\n Extracts the last character of each string in a tuple.\n\n Args:\n input_tuple: A tuple of strings.\n\n Returns:\n A list containing the last character of each string in the input tuple.\n Returns an empty list if the input tuple is empty or contains non-string elements.\n \"\"\"\n result = []\n for item in input_tuple:\n if isinstance(item, str) and item: # Check if the item is a string and not empty\n result.append(item[-1])\n elif not isinstance(item, str):\n print(f\"Warning: Non-string element encountered: {item}. Skipping.\")\n \n return result", "matching_cluster_idx": 1}, {"solution": "def extract_rear(input_tuple):\n \"\"\"\n Extracts the last character of each string in a tuple.\n\n Args:\n input_tuple: A tuple of strings.\n\n Returns:\n A list containing the last character of each string in the input tuple.\n Returns an empty list if the input tuple is empty or contains non-string elements.\n \"\"\"\n result = []\n for item in input_tuple:\n if isinstance(item, str) and item: # Check if the item is a string and not empty\n result.append(item[-1])\n elif isinstance(item, str) and not item: # Handle empty strings\n result.append(\"\") # Or raise an error if that's the desired behavior\n elif not isinstance(item, str): # Handle non-string elements silently \n pass # or raise a TypeError if needed like: raise TypeError(\"Tuple elements must be strings.\")\n \n\n return result", "matching_cluster_idx": 1}, {"solution": "def extract_rear(strings):\n \"\"\"\n Extracts the last character of each string in the given tuple.\n\n Args:\n strings: A tuple of strings.\n\n Returns:\n A list containing the last character of each string in the input tuple.\n Returns an empty list if the input tuple is empty.\n Returns a list containing None for any element in the tuple that is not a string,\n or if a string is empty\n \"\"\"\n result = []\n for s in strings:\n if isinstance(s, str) and s: # Check if it's a string and not empty\n result.append(s[-1])\n elif isinstance(s, str) and not s: # Check if the string is empty\n result.append(None)\n else: #If not string, append None\n result.append(None)\n return result", "matching_cluster_idx": 1}, {"solution": "def extract_rear(input_tuple):\n \"\"\"\n Extracts the last character of each string in a tuple.\n\n Args:\n input_tuple: A tuple of strings.\n\n Returns:\n A list containing the last character of each string in the input tuple.\n Returns an empty list if the input tuple is empty or contains non-strings.\n \"\"\"\n result = []\n for item in input_tuple:\n if isinstance(item, str) and item: # Check if the item is a string and not empty\n result.append(item[-1])\n elif isinstance(item, str) and not item: # Handle empty strings\n result.append(\"\") # Or raise an exception if that's the desired behavior\n elif not isinstance(item, str):\n return [] # Or raise an exception if non-string types are not allowed\n\n\n return result", "matching_cluster_idx": 1}, {"solution": "def extract_rear(input_tuple):\n \"\"\"\n Extracts the last character of each string in a tuple.\n\n Args:\n input_tuple: A tuple of strings.\n\n Returns:\n A list containing the last character of each string in the input tuple.\n Returns an empty list if the input tuple is empty or contains non-strings.\n \"\"\"\n result = []\n for item in input_tuple:\n if isinstance(item, str) and item: # Check if the item is a string and not empty\n result.append(item[-1])\n elif isinstance(item, str) and not item: # Handle empty strings\n result.append(\"\") # or raise an exception if that's the desired behaviour\n elif not isinstance(item, str): # skip invalid values. Alternatively raise exception\n continue # raise TypeError(\"Tuple must contain only strings.\")\n\n\n return result", "matching_cluster_idx": 1}, {"solution": "def extract_rear(strings):\n \"\"\"\n Extracts the last character of each string in a tuple.\n\n Args:\n strings: A tuple of strings.\n\n Returns:\n A list containing the last character of each string in the input tuple.\n Returns an empty list if the input tuple is empty or contains non-strings.\n \"\"\"\n result = []\n for string in strings:\n if isinstance(string, str): # Check if the element is a string\n if string: # Check if the string is not empty\n result.append(string[-1])\n else:\n return [] # Handle cases with non-string elements gracefully\n return result", "matching_cluster_idx": 1}, {"solution": "def extract_rear(input_tuple):\n \"\"\"\n Extracts the last character of each string in a tuple.\n\n Args:\n input_tuple: A tuple of strings.\n\n Returns:\n A list containing the last character of each string in the input tuple.\n Returns an empty list if the input tuple is empty or contains non-string elements.\n \"\"\"\n result = []\n for item in input_tuple:\n if isinstance(item, str) and item: # Check if the item is a string and not empty\n result.append(item[-1])\n elif isinstance(item, str) and not item: # Handle empty strings\n result.append(\"\")\n \n return result", "matching_cluster_idx": 1}]}, "Mbpp/425": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def count_element_in_list(list_of_lists, element):\n \"\"\"\n Counts the number of sublists within a list of lists that contain a specific element.\n\n Args:\n list_of_lists: A list of lists.\n element: The element to search for within the sublists.\n\n Returns:\n The number of sublists containing the element.\n \"\"\"\n count = 0\n for sublist in list_of_lists:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(list_of_lists, element):\n \"\"\"\n Counts the number of sublists within a given list of lists that contain a specific element.\n\n Args:\n list_of_lists: A list of lists.\n element: The element to search for within the sublists.\n\n Returns:\n The number of sublists containing the element.\n \"\"\"\n count = 0\n for sublist in list_of_lists:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(list_of_lists, element):\n \"\"\"\n Counts the number of sublists within a list of lists that contain a specific element.\n\n Args:\n list_of_lists: A list of lists.\n element: The element to search for within the sublists.\n\n Returns:\n The number of sublists containing the specified element.\n \"\"\"\n count = 0\n for sublist in list_of_lists:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(list_of_lists, element):\n \"\"\"\n Counts the number of sublists within a list of lists that contain a specific element.\n\n Args:\n list_of_lists: A list of lists.\n element: The element to search for within the sublists.\n\n Returns:\n The number of sublists containing the specified element.\n \"\"\"\n\n count = 0\n for sublist in list_of_lists:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(list_of_lists, element):\n \"\"\"Counts the number of sublists containing a particular element.\n\n Args:\n list_of_lists: A list of lists.\n element: The element to search for.\n\n Returns:\n The number of sublists containing the element.\n \"\"\"\n count = 0\n for sublist in list_of_lists:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(list_of_lists, element):\n \"\"\"\n Counts the number of sublists in a given list of lists that contain a particular element.\n\n Args:\n list_of_lists: A list of lists.\n element: The element to search for.\n\n Returns:\n The number of sublists containing the element.\n \"\"\"\n count = 0\n for sublist in list_of_lists:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(list_of_lists, element):\n \"\"\"\n Counts the number of sublists within a list of lists that contain a specific element.\n\n Args:\n list_of_lists: A list of lists.\n element: The element to search for within the sublists.\n\n Returns:\n The number of sublists containing the element.\n \"\"\"\n count = 0\n for sublist in list_of_lists:\n if element in sublist:\n count += 1\n return count\nlist_of_lists = [[1, 2, 3], [4, 5, 6], [1, 7, 8], [9, 10, 1]]\nelement = 1\ncount = count_element_in_list(list_of_lists, element)", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(list_of_lists, element):\n \"\"\"Counts the number of sublists containing a given element.\n\n Args:\n list_of_lists: A list of lists.\n element: The element to search for.\n\n Returns:\n The number of sublists containing the element.\n \"\"\"\n count = 0\n for sublist in list_of_lists:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(list_of_lists, element):\n \"\"\"Counts the number of sublists containing a particular element.\n\n Args:\n list_of_lists: A list of lists.\n element: The element to search for.\n\n Returns:\n The number of sublists containing the element.\n \"\"\"\n\n count = 0\n for sublist in list_of_lists:\n if element in sublist:\n count += 1\n return count\nlist_of_lists = [[1, 3], [5, 7], [1, 11], [1, 15, 7]]\nelement = 1\ncount = count_element_in_list(list_of_lists, element)", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(list_of_lists, element):\n \"\"\"\n Counts the number of sublists within a list of lists that contain a specific element.\n\n Args:\n list_of_lists: A list of lists.\n element: The element to search for within the sublists.\n\n Returns:\n The number of sublists containing the element.\n \"\"\"\n\n count = 0\n for sublist in list_of_lists:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, element):\n \"\"\"Counts the number of sublists in a given list that contain a specific element.\n\n Args:\n lst: The list of lists to search within.\n element: The element to search for.\n\n Returns:\n The number of sublists containing the element.\n \"\"\"\n count = 0\n for sublist in lst:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(list_of_lists, element):\n \"\"\"Counts the number of sublists containing a particular element.\n\n Args:\n list_of_lists: A list of lists.\n element: The element to search for.\n\n Returns:\n The number of sublists containing the element.\n \"\"\"\n count = 0\n for sublist in list_of_lists:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, element):\n count = 0\n for sublist in lst:\n if element in sublist:\n count += 1\n return count\nlist_of_lists = [[1, 3], [5, 7], [1, 11], [1, 15, 7]]\nelement_to_count = 1\ncount = count_element_in_list(list_of_lists, element_to_count)", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(list_of_lists, element):\n \"\"\"\n Counts the number of sublists containing a particular element.\n\n Args:\n list_of_lists: A list of lists.\n element: The element to search for.\n\n Returns:\n The number of sublists containing the element.\n \"\"\"\n count = 0\n for sublist in list_of_lists:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(list_of_lists, element):\n \"\"\"\n Counts the number of sublists within a list of lists that contain a specific element.\n\n Args:\n list_of_lists: A list of lists.\n element: The element to search for within the sublists.\n\n Returns:\n The number of sublists containing the specified element.\n \"\"\"\n count = 0\n for sublist in list_of_lists:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(list_of_lists, element):\n \"\"\"\n Counts the number of sublists containing a particular element.\n\n Args:\n list_of_lists: A list of lists.\n element: The element to search for.\n\n Returns:\n The number of sublists containing the element.\n \"\"\"\n count = 0\n for sublist in list_of_lists:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(list_of_lists, element):\n \"\"\"\n Counts the number of sublists within a list of lists that contain a specified element.\n\n Args:\n list_of_lists: A list of lists.\n element: The element to search for within the sublists.\n\n Returns:\n The number of sublists containing the element.\n \"\"\"\n count = 0\n for sublist in list_of_lists:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(list_of_lists, element):\n \"\"\"Counts the number of sublists containing a particular element.\n\n Args:\n list_of_lists: A list of lists.\n element: The element to search for.\n\n Returns:\n The number of sublists containing the element.\n \"\"\"\n count = 0\n for sublist in list_of_lists:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(list_of_lists, element):\n \"\"\"Counts the number of sublists containing a specific element.\n\n Args:\n list_of_lists: A list of lists.\n element: The element to search for.\n\n Returns:\n The number of sublists containing the element.\n \"\"\"\n count = 0\n for sublist in list_of_lists:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(list_of_lists, element):\n \"\"\"\n Counts the number of sublists containing a particular element.\n\n Args:\n list_of_lists: A list of lists.\n element: The element to search for.\n\n Returns:\n The number of sublists containing the element.\n \"\"\"\n count = 0\n for sublist in list_of_lists:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}]}, "Mbpp/428": {"dps": 81.36363636363636, "dps_norm": 55.0, "pass@1": 100.0, "profiled": [{"solution": "def shell_sort(arr):\n \"\"\"Sorts an array using the shell sort algorithm.\"\"\"\n n = len(arr)\n gap = n // 2\n\n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n \"\"\"Sorts an array using the shell sort algorithm.\"\"\"\n n = len(arr)\n gap = n // 2\n\n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n \"\"\"Sorts an array using the shell sort algorithm.\"\"\"\n n = len(arr)\n gap = n // 2\n\n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n \"\"\"Sorts an array using the shell sort algorithm.\n\n Args:\n arr: The array to be sorted.\n\n Returns:\n The sorted array.\n \"\"\"\n n = len(arr)\n gap = n // 2\n\n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n \"\"\"Sorts an array using the shell sort algorithm.\"\"\"\n n = len(arr)\n gap = n // 2\n\n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n \"\"\"Sorts an array using the shell sort algorithm.\"\"\"\n n = len(arr)\n gap = n // 2\n\n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n \"\"\"Sorts an array using the shell sort algorithm.\"\"\"\n n = len(arr)\n gap = n // 2\n\n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n \"\"\"Sorts an array using the shell sort algorithm.\"\"\"\n n = len(arr)\n gap = n // 2\n\n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n \"\"\"Sorts an array using the Shell Sort algorithm.\"\"\"\n n = len(arr)\n gap = n // 2\n\n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n \"\"\"\n Sorts a list using the shell sort algorithm.\n\n Args:\n arr: The list to be sorted.\n\n Returns:\n The sorted list.\n \"\"\"\n n = len(arr)\n gap = n // 2\n\n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n \"\"\"Sorts an array using the Shell Sort algorithm.\n\n Args:\n arr: The array to be sorted.\n\n Returns:\n The sorted array.\n \"\"\"\n n = len(arr)\n gap = n // 2\n\n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n \"\"\"Sorts an array using the shell sort algorithm.\"\"\"\n n = len(arr)\n gap = n // 2\n\n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n return arr\narr = [12, 23, 4, 5, 3, 2, 12, 81, 56, 95]", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n \"\"\"Sorts an array using the Shell Sort algorithm.\"\"\"\n n = len(arr)\n gap = n // 2\n\n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n return arr\narr = [12, 23, 4, 5, 3, 2, 12, 81, 56, 95]", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n \"\"\"Sorts a list using the shell sort algorithm.\"\"\"\n n = len(arr)\n gap = n // 2\n\n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2 # Integer division ensures gap reduces correctly\n\n return arr", "matching_cluster_idx": 3}, {"solution": "def shell_sort(arr):\n \"\"\"Sorts an array using the shell sort algorithm.\"\"\"\n n = len(arr)\n gap = n // 2\n\n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n \"\"\"Sorts a list using the Shell Sort algorithm.\"\"\"\n n = len(arr)\n gap = n // 2\n\n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n return arr\narr = [12, 23, 4, 5, 3, 2, 12, 81, 56, 95]", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n \"\"\"Sorts an array using the Shell Sort algorithm.\"\"\"\n n = len(arr)\n gap = n // 2\n\n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n return arr\narr = [12, 23, 4, 5, 3, 2, 12, 81, 56, 95]", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n \"\"\"Sorts an array using the shell sort algorithm.\"\"\"\n n = len(arr)\n gap = n // 2\n\n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n \"\"\"Sorts an array using the Shell Sort algorithm.\"\"\"\n n = len(arr)\n gap = n // 2\n\n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n \"\"\"Sorts a given array using the shell sort algorithm.\n\n Args:\n arr: The array to be sorted.\n\n Returns:\n The sorted array.\n \"\"\"\n n = len(arr)\n gap = n // 2\n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n return arr", "matching_cluster_idx": 4}]}, "Mbpp/433": {"dps": 66.64893617021276, "dps_norm": 81.0, "pass@1": 100.0, "profiled": [{"solution": "def check_greater(arr, num):\n \"\"\"\n Checks if a number is greater than all elements in an array.\n\n Args:\n arr: A list of numbers.\n num: The number to compare against.\n\n Returns:\n True if the number is greater than all elements in the array, False otherwise.\n \"\"\"\n for element in arr:\n if num <= element:\n return False\n return True", "matching_cluster_idx": 3}, {"solution": "def check_greater(arr, num):\n \"\"\"\n Checks if a number is greater than all elements in an array.\n\n Args:\n arr: A list of numbers.\n num: The number to compare against.\n\n Returns:\n True if the number is greater than all elements in the array, False otherwise.\n \"\"\"\n for element in arr:\n if num <= element:\n return False\n return True", "matching_cluster_idx": 3}, {"solution": "def check_greater(arr, num):\n \"\"\"\n Checks if a number is greater than all elements in an array.\n\n Args:\n arr: The input array of numbers.\n num: The number to compare against.\n\n Returns:\n True if the number is greater than all elements in the array, False otherwise.\n \"\"\"\n for element in arr:\n if num <= element:\n return False\n return True", "matching_cluster_idx": 3}, {"solution": "def check_greater(arr, num):\n \"\"\"\n Checks if a number is greater than all elements in an array.\n\n Args:\n arr: A list of numbers.\n num: The number to compare against.\n\n Returns:\n True if the number is greater than all elements in the array, False otherwise.\n \"\"\"\n for element in arr:\n if num <= element:\n return False\n return True", "matching_cluster_idx": 3}, {"solution": "def check_greater(arr, num):\n \"\"\"\n Checks if a number is greater than all elements in an array.\n\n Args:\n arr: A list of numbers.\n num: The number to compare against.\n\n Returns:\n True if the number is greater than all elements in the array, False otherwise.\n \"\"\"\n for element in arr:\n if num <= element:\n return False\n return True", "matching_cluster_idx": 3}, {"solution": "def check_greater(arr, num):\n \"\"\"\n Checks if a number is greater than all elements in an array.\n\n Args:\n arr: The input array of numbers.\n num: The number to compare against.\n\n Returns:\n True if the number is greater than all elements in the array, False otherwise.\n \"\"\"\n for element in arr:\n if num <= element:\n return False\n return True", "matching_cluster_idx": 3}, {"solution": "def check_greater(arr, num):\n \"\"\"\n Checks if a number is greater than all elements in an array.\n\n Args:\n arr: The input array of numbers.\n num: The number to compare against.\n\n Returns:\n True if the number is greater than all elements in the array, False otherwise.\n \"\"\"\n for element in arr:\n if num <= element:\n return False\n return True", "matching_cluster_idx": 3}, {"solution": "def check_greater(arr, num):\n \"\"\"\n Checks if a number is greater than all elements in an array.\n\n Args:\n arr: The input array of numbers.\n num: The number to compare against.\n\n Returns:\n True if the number is greater than all elements in the array, False otherwise.\n \"\"\"\n for element in arr:\n if num <= element:\n return False\n return True", "matching_cluster_idx": 3}, {"solution": "def check_greater(arr, num):\n \"\"\"\n Checks if the given number is greater than all elements in the array.\n\n Args:\n arr: A list of numbers.\n num: The number to compare against.\n\n Returns:\n True if the number is greater than all elements in the array, False otherwise.\n \"\"\"\n for element in arr:\n if num <= element:\n return False\n return True", "matching_cluster_idx": 3}, {"solution": "def check_greater(arr, num):\n \"\"\"\n Checks if the given number is greater than all elements of the array.\n\n Args:\n arr: A list of numbers.\n num: The number to compare against.\n\n Returns:\n True if the number is greater than all elements in the array, False otherwise.\n \"\"\"\n for element in arr:\n if num <= element: # Check for less than or equal to handle edge cases\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def check_greater(arr, num):\n \"\"\"\n Checks if the given number is greater than all elements in the array.\n\n Args:\n arr: A list of numbers.\n num: The number to compare against.\n\n Returns:\n True if num is greater than all elements in arr, False otherwise.\n \"\"\"\n for element in arr:\n if num <= element:\n return False\n return True", "matching_cluster_idx": 3}, {"solution": "def check_greater(arr, num):\n \"\"\"\n Checks if a number is greater than all elements in an array.\n\n Args:\n arr: A list of numbers.\n num: The number to compare against.\n\n Returns:\n True if the number is greater than all elements in the array, False otherwise.\n \"\"\"\n for element in arr:\n if num <= element:\n return False\n return True", "matching_cluster_idx": 3}, {"solution": "def check_greater(arr, num):\n \"\"\"\n Checks if a number is greater than all elements in an array.\n\n Args:\n arr: A list of numbers.\n num: The number to compare against.\n\n Returns:\n True if the number is greater than all elements in the array, False otherwise.\n \"\"\"\n for element in arr:\n if num <= element:\n return False\n return True", "matching_cluster_idx": 3}, {"solution": "def check_greater(arr, num):\n \"\"\"\n Checks if a number is greater than all elements in an array.\n\n Args:\n arr: A list of numbers.\n num: The number to compare against.\n\n Returns:\n True if the number is greater than all elements in the array, False otherwise.\n \"\"\"\n for element in arr:\n if num <= element:\n return False\n return True", "matching_cluster_idx": 3}, {"solution": "def check_greater(arr, num):\n \"\"\"\n Checks if a number is greater than all elements in an array.\n\n Args:\n arr: The array to check against.\n num: The number to compare.\n\n Returns:\n True if the number is greater than all elements in the array, False otherwise.\n \"\"\"\n for element in arr:\n if num <= element:\n return False\n return True", "matching_cluster_idx": 3}, {"solution": "def check_greater(arr, num):\n \"\"\"\n Checks if a number is greater than all elements in an array.\n\n Args:\n arr: The input array of numbers.\n num: The number to compare against.\n\n Returns:\n True if the number is greater than all elements in the array, False otherwise.\n \"\"\"\n for element in arr:\n if num <= element:\n return False\n return True", "matching_cluster_idx": 3}, {"solution": "def check_greater(arr, num):\n \"\"\"\n Checks if the given number is greater than all elements in the array.\n\n Args:\n arr: A list of numbers.\n num: The number to compare against.\n\n Returns:\n True if the number is greater than all elements in the array, False otherwise.\n \"\"\"\n for element in arr:\n if num <= element:\n return False\n return True", "matching_cluster_idx": 3}, {"solution": "def check_greater(arr, num):\n \"\"\"\n Checks if a number is greater than all elements in an array.\n\n Args:\n arr: A list of numbers.\n num: The number to compare against.\n\n Returns:\n True if the number is greater than all elements in the array, False otherwise.\n \"\"\"\n for element in arr:\n if num <= element:\n return False\n return True", "matching_cluster_idx": 3}, {"solution": "def check_greater(arr, num):\n \"\"\"\n Checks if the given number is greater than all elements in the array.\n\n Args:\n arr: A list of numbers.\n num: The number to compare against.\n\n Returns:\n True if the number is greater than all elements in the array, False otherwise.\n \"\"\"\n for element in arr:\n if num <= element:\n return False\n return True", "matching_cluster_idx": 3}, {"solution": "def check_greater(arr, num):\n \"\"\"\n Checks if a number is greater than all elements in an array.\n\n Args:\n arr: The input array of numbers.\n num: The number to compare against.\n\n Returns:\n True if the number is greater than all elements in the array, False otherwise.\n \"\"\"\n for element in arr:\n if num <= element:\n return False\n return True", "matching_cluster_idx": 3}]}, "Mbpp/437": {"dps": 70.58823529411765, "dps_norm": 20.0, "pass@1": 28.0, "profiled": [{"solution": "def remove_odd(input_string):\n \"\"\"Removes characters at odd indices from a string.\n\n Args:\n input_string: The input string.\n\n Returns:\n A new string with characters at odd indices removed.\n \"\"\"\n result = \"\"\n for i in range(len(input_string)):\n if i % 2 == 1: # Check for odd indices\n result += input_string[i]\n return result", "matching_cluster_idx": 0}, {"solution": "def remove_odd(input_string):\n \"\"\"Removes characters at odd indices from a string.\n\n Args:\n input_string: The input string.\n\n Returns:\n A new string with characters at odd indices removed.\n \"\"\"\n result = \"\"\n for i in range(len(input_string)):\n if i % 2 == 1: # Check for odd indices\n result += input_string[i]\n return result\ntest_string = \"programming\"\nresult = remove_odd(test_string)", "matching_cluster_idx": 0}, {"solution": "def remove_odd(input_string):\n \"\"\"Removes characters at odd indices from a string.\n\n Args:\n input_string: The input string.\n\n Returns:\n A new string with characters at odd indices removed.\n \"\"\"\n result = \"\"\n for i in range(len(input_string)):\n if i % 2 == 1: # Check for odd indices\n result += input_string[i]\n return result", "matching_cluster_idx": 0}, {"solution": "def remove_odd(input_string):\n \"\"\"Removes characters at odd indices from a string.\n\n Args:\n input_string: The input string.\n\n Returns:\n A new string with characters at odd indices removed.\n \"\"\"\n result = \"\"\n for i in range(len(input_string)):\n if i % 2 == 1: # Check for odd indices\n result += input_string[i]\n return result", "matching_cluster_idx": 0}, {"solution": "def remove_odd(input_string):\n \"\"\"Removes characters at odd indices from a string.\n\n Args:\n input_string: The input string.\n\n Returns:\n A new string with characters at odd indices removed.\n \"\"\"\n result = \"\"\n for i in range(len(input_string)):\n if i % 2 == 1: # Check if the index is odd\n result += input_string[i]\n return result", "matching_cluster_idx": 0}, {"solution": "def remove_odd(input_string):\n \"\"\"Removes characters at odd indices from a string.\n\n Args:\n input_string: The input string.\n\n Returns:\n A new string with characters at odd indices removed.\n \"\"\"\n result = \"\"\n for i in range(len(input_string)):\n if i % 2 == 1: # Check for odd indices (1, 3, 5, ...)\n result += input_string[i]\n return result", "matching_cluster_idx": 0}, {"solution": "def remove_odd(input_string):\n \"\"\"Removes characters at odd indices from a string.\n\n Args:\n input_string: The input string.\n\n Returns:\n A new string with characters at odd indices removed.\n \"\"\"\n result = \"\"\n for i in range(len(input_string)):\n if i % 2 == 1: # Check for odd indices\n result += input_string[i]\n return result", "matching_cluster_idx": 0}, {"solution": "def remove_odd(input_string):\n \"\"\"Removes characters at odd indices from a string.\n\n Args:\n input_string: The input string.\n\n Returns:\n A new string with characters at odd indices removed.\n \"\"\"\n result = \"\"\n for i in range(len(input_string)):\n if i % 2 == 1: # Check if the index is odd\n result += input_string[i]\n return result", "matching_cluster_idx": 0}, {"solution": "def remove_odd(input_string):\n \"\"\"Removes characters at odd indices from a string.\n\n Args:\n input_string: The input string.\n\n Returns:\n A new string with characters at odd indices removed.\n \"\"\"\n result = \"\"\n for i in range(len(input_string)):\n if i % 2 == 1:\n result += input_string[i]\n return result", "matching_cluster_idx": 0}, {"solution": "def remove_odd(input_string):\n \"\"\"Removes characters at odd indices from a string.\n\n Args:\n input_string: The input string.\n\n Returns:\n A new string with characters at odd indices removed.\n \"\"\"\n result = \"\"\n for i in range(len(input_string)):\n if i % 2 == 1: # Check if the index is odd\n result += input_string[i]\n return result", "matching_cluster_idx": 0}, {"solution": "def remove_odd(input_string):\n \"\"\"Removes characters at odd indices from a string.\n\n Args:\n input_string: The input string.\n\n Returns:\n A new string with characters at odd indices removed.\n \"\"\"\n result = \"\"\n for i in range(len(input_string)):\n if i % 2 == 1: # Check if the index is odd\n result += input_string[i]\n return result", "matching_cluster_idx": 0}, {"solution": "def remove_odd(input_string):\n \"\"\"Removes characters at odd indices from a string.\n\n Args:\n input_string: The input string.\n\n Returns:\n A new string with characters at odd indices removed.\n \"\"\"\n result = \"\"\n for i in range(len(input_string)):\n if i % 2 == 1: # Check if the index is odd\n result += input_string[i]\n return result", "matching_cluster_idx": 0}, {"solution": "def remove_odd(input_string):\n \"\"\"Removes characters at odd indices from a string.\n\n Args:\n input_string: The input string.\n\n Returns:\n A new string with characters at odd indices removed.\n \"\"\"\n result = \"\"\n for i in range(len(input_string)):\n if i % 2 == 1: # Check for odd indices\n result += input_string[i]\n return result", "matching_cluster_idx": 0}, {"solution": "def remove_odd(input_string):\n \"\"\"Removes characters at odd indices from a string.\n\n Args:\n input_string: The input string.\n\n Returns:\n A new string with characters at odd indices removed.\n \"\"\"\n result = \"\"\n for i in range(len(input_string)):\n if i % 2 == 1: # Check for odd indices\n result += input_string[i]\n return result", "matching_cluster_idx": 0}, {"solution": "def remove_odd(input_string):\n \"\"\"Removes characters at odd indices from a string.\n\n Args:\n input_string: The input string.\n\n Returns:\n A new string with characters at odd indices removed.\n \"\"\"\n result = \"\"\n for i in range(len(input_string)):\n if i % 2 == 1:\n result += input_string[i]\n return result", "matching_cluster_idx": 0}, {"solution": "def remove_odd(input_string):\n \"\"\"Removes characters at odd indices from a string.\"\"\"\n result = \"\"\n for i in range(len(input_string)):\n if i % 2 == 1: # Check if the index is odd\n result += input_string[i]\n return result", "matching_cluster_idx": 0}, {"solution": "def remove_odd(input_string):\n \"\"\"Removes characters at odd indices from a string.\n\n Args:\n input_string: The input string.\n\n Returns:\n A new string with characters at odd indices removed.\n \"\"\"\n result = \"\"\n for i in range(len(input_string)):\n if i % 2 == 1: # Check for odd indices\n result += input_string[i]\n return result", "matching_cluster_idx": 0}, {"solution": "def remove_odd(input_string):\n \"\"\"Removes characters at odd indices from a string.\n\n Args:\n input_string: The input string.\n\n Returns:\n A new string with characters at odd indices removed.\n \"\"\"\n result = \"\"\n for i in range(len(input_string)):\n if i % 2 == 1: # Check for odd indices\n result += input_string[i]\n return result", "matching_cluster_idx": 0}, {"solution": "def remove_odd(input_string):\n \"\"\"Removes characters at odd indices from a string.\n\n Args:\n input_string: The input string.\n\n Returns:\n A new string with characters at odd indices removed.\n \"\"\"\n result = \"\"\n for i in range(len(input_string)):\n if i % 2 == 1: # Check if the index is odd\n result += input_string[i]\n return result", "matching_cluster_idx": 0}, {"solution": "def remove_odd(input_string):\n \"\"\"Removes characters at odd indices from a string.\n\n Args:\n input_string: The input string.\n\n Returns:\n A new string with characters at odd indices removed.\n \"\"\"\n result = \"\"\n for i in range(len(input_string)):\n if i % 2 == 1: # Check for odd indices\n result += input_string[i]\n return result", "matching_cluster_idx": 0}]}, "Mbpp/440": {"dps": 36.36363636363637, "dps_norm": 75.0, "pass@1": 20.0, "profiled": [{"solution": "import re\ndef find_adverb_position(sentence):\n \"\"\"\n Finds the first adverb and its positions in a given sentence.\n\n Args:\n sentence: The input sentence.\n\n Returns:\n A tuple containing the start index, end index, and the adverb itself.\n Returns None if no adverb is found.\n \"\"\"\n # Regular expression pattern to match adverbs ending in \"ly\" \n # with optional punctuation immediately following\n pattern = r\"\\b(\\w+ly)(\\W*)\"\n\n match = re.search(pattern, sentence)\n\n if match:\n start_index = match.start(1)\n end_index = match.end(1) # Corrected to only encompass the adverb, not trailing punctuation\n adverb = match.group(1)\n return start_index, end_index, adverb\n else:\n return None", "matching_cluster_idx": 2}, {"solution": "import re\ndef find_adverb_position(sentence):\n \"\"\"\n Finds the first adverb and its position in a given sentence.\n\n Args:\n sentence: The input sentence.\n\n Returns:\n A tuple containing the start index, end index, and the adverb itself.\n Returns None if no adverb is found.\n \"\"\"\n # Regular expression pattern to match adverbs ending in \"ly\" (with potential punctuation)\n pattern = r\"\\b(\\w+ly)(\\W*)\" # \\b for word boundary, \\W* for trailing punctuation\n\n match = re.search(pattern, sentence)\n\n if match:\n start_index = match.start(1)\n end_index = match.end(1)\n adverb = match.group(1)\n return start_index, end_index, adverb\n else:\n return None", "matching_cluster_idx": 2}, {"solution": "import re\ndef find_adverb_position(sentence):\n \"\"\"\n Finds the first adverb and its position in a given sentence.\n\n Args:\n sentence: The input sentence as a string.\n\n Returns:\n A tuple containing the start index, end index, and the adverb itself.\n Returns None if no adverb is found.\n \"\"\"\n # Regular expression pattern to match adverbs ending in \"ly\" (with optional punctuation)\n pattern = r\"\\b(\\w+ly)(\\W*)\" # \\b for word boundary, capturing the adverb and following punctuation\n\n match = re.search(pattern, sentence)\n\n if match:\n start_index = match.start(1)\n end_index = match.end(1)\n adverb = match.group(1)\n return start_index, end_index, adverb\n else:\n return None", "matching_cluster_idx": 2}, {"solution": "import re\ndef find_adverb_position(sentence):\n \"\"\"\n Finds the first adverb and its position in a given sentence.\n\n Args:\n sentence: The input sentence.\n\n Returns:\n A tuple containing the start index, end index, and the adverb itself.\n Returns None if no adverb is found.\n \"\"\"\n\n # Regular expression pattern to match adverbs ending in \"ly\"\n # Includes handling for punctuation immediately following the adverb\n pattern = r\"\\b(\\w+ly)(\\W*)\" \n\n match = re.search(pattern, sentence)\n\n if match:\n start_index = match.start(1)\n end_index = match.end(1) # Exclude punctuation from adverb itself\n adverb = match.group(1)\n return start_index, end_index, adverb\n else:\n return None", "matching_cluster_idx": 2}, {"solution": "import re\ndef find_adverb_position(sentence):\n \"\"\"\n Finds the first adverb and its start and end positions in a given sentence.\n\n Args:\n sentence: The input sentence as a string.\n\n Returns:\n A tuple containing the start position, end position, and the adverb itself.\n Returns None if no adverb is found.\n \"\"\"\n # Regular expression pattern to match adverbs ending in -ly (with potential punctuation)\n pattern = r\"\\b(\\w+ly)(\\W*)\"\n\n match = re.search(pattern, sentence)\n\n if match:\n start_pos = match.start(1)\n end_pos = match.end(1) # Exclude trailing punctuation from the adverb itself\n adverb = match.group(1)\n return start_pos, end_pos, adverb\n else:\n return None", "matching_cluster_idx": 2}, {"solution": "import re\ndef find_adverb_position(sentence):\n \"\"\"\n Finds the first adverb and its position in a given sentence.\n\n Args:\n sentence: The input sentence.\n\n Returns:\n A tuple containing the start index, end index, and the adverb itself.\n Returns None if no adverb is found.\n \"\"\"\n # Regular expression pattern to match adverbs ending in \"ly\" \n # and handles potential punctuation immediately after the adverb.\n pattern = r\"\\b(\\w+ly)(\\W*)\"\n\n match = re.search(pattern, sentence)\n\n if match:\n start_index = match.start(1)\n end_index = match.end(1)\n adverb = match.group(1)\n return start_index, end_index, adverb\n else:\n return None", "matching_cluster_idx": 2}, {"solution": "import re\ndef find_adverb_position(sentence):\n \"\"\"\n Finds the first adverb and its start and end positions in a sentence.\n\n Args:\n sentence: The input sentence as a string.\n\n Returns:\n A tuple containing the start position, end position, and the adverb itself.\n Returns None if no adverb is found.\n \"\"\"\n\n # Regular expression pattern to match adverbs ending in \"ly\" \n # and handle punctuation immediately following the adverb.\n pattern = r\"\\b(\\w+ly)(\\W*)\" # \\b for word boundary, \\W* for trailing punctuation\n\n match = re.search(pattern, sentence)\n\n if match:\n start = match.start(1)\n end = match.end(1)\n adverb = match.group(1)\n return (start, end, adverb)\n else:\n return None", "matching_cluster_idx": 2}, {"solution": "import re\ndef find_adverb_position(sentence):\n \"\"\"\n Finds the first adverb and its position in a given sentence.\n\n Args:\n sentence: The input sentence.\n\n Returns:\n A tuple containing the start index, end index, and the adverb itself.\n Returns None if no adverb is found.\n \"\"\"\n\n # Regular expression pattern to match adverbs ending in \"ly\"\n # Includes handling for double punctuation like \"clearly!!\"\n pattern = r\"\\b(\\w+ly)(\\W*)\"\n\n match = re.search(pattern, sentence)\n\n if match:\n start_index = match.start(1)\n end_index = match.end(1)\n adverb = match.group(1)\n return start_index, end_index, adverb\n else:\n return None", "matching_cluster_idx": 2}, {"solution": "import re\ndef find_adverb_position(sentence):\n \"\"\"\n Finds the first adverb and its position in a given sentence.\n\n Args:\n sentence: The input sentence.\n\n Returns:\n A tuple containing the start index, end index, and the adverb itself.\n Returns None if no adverb is found.\n \"\"\"\n # Regular expression pattern to match adverbs ending in \"ly\" (with potential punctuation).\n pattern = r\"\\b(\\w+ly)(\\W*)\"\n\n match = re.search(pattern, sentence)\n\n if match:\n start_index = match.start(1)\n end_index = match.end(1)\n adverb = match.group(1)\n return start_index, end_index, adverb\n else:\n return None", "matching_cluster_idx": 2}, {"solution": "import re\ndef find_adverb_position(sentence):\n \"\"\"\n Finds the first adverb and its position in a given sentence.\n\n Args:\n sentence: The input sentence.\n\n Returns:\n A tuple containing the start index, end index, and the adverb itself. \n Returns None if no adverb is found.\n \"\"\"\n\n # Regular expression pattern to match adverbs ending in \"ly\" (with possible punctuation)\n pattern = r\"\\b(\\w+ly)(\\W*)\" # \\b for word boundaries\n\n match = re.search(pattern, sentence)\n\n if match:\n start = match.start(1)\n end = match.end(1)\n adverb = match.group(1)\n return start, end, adverb\n else:\n return None", "matching_cluster_idx": 2}, {"solution": "import re\ndef find_adverb_position(sentence):\n \"\"\"\n Finds the first adverb and its position in a given sentence.\n\n Args:\n sentence: The input sentence.\n\n Returns:\n A tuple containing the start index, end index, and the adverb itself. \n Returns None if no adverb is found.\n \"\"\"\n # Regex pattern to match adverbs ending in \"ly\" (with potential punctuation following).\n pattern = r\"\\b(\\w+ly)(\\W*)\" # \\b for word boundary, \\W* for optional punctuation\n\n match = re.search(pattern, sentence)\n\n if match:\n start_index = match.start(1)\n end_index = match.end(1) # Excludes punctuation\n adverb = match.group(1)\n return start_index, end_index, adverb\n else:\n return None", "matching_cluster_idx": 2}, {"solution": "import re\ndef find_adverb_position(sentence):\n \"\"\"\n Finds the first adverb and its positions in a given sentence.\n\n Args:\n sentence: The input sentence.\n\n Returns:\n A tuple containing the start index, end index, and the adverb itself.\n Returns None if no adverb is found.\n \"\"\"\n # Regular expression pattern to match adverbs ending in \"ly\" with optional punctuation\n pattern = r\"\\b(\\w+ly)(\\W*)\" \n\n match = re.search(pattern, sentence)\n\n if match:\n start_index = match.start(1)\n end_index = match.end(1)\n adverb = match.group(1)\n return start_index, end_index, adverb\n else:\n return None", "matching_cluster_idx": 2}, {"solution": "import re\ndef find_adverb_position(sentence):\n \"\"\"\n Finds the first adverb and its position in a given sentence.\n\n Args:\n sentence: The input sentence.\n\n Returns:\n A tuple containing the start index, end index, and the adverb itself.\n Returns None if no adverb is found.\n \"\"\"\n # Regular expression pattern to match adverbs ending in \"ly\"\n # It accounts for punctuation immediately after the adverb.\n pattern = r\"\\b(\\w+ly)(\\W*)\" \n\n match = re.search(pattern, sentence)\n\n if match:\n start_index = match.start(1)\n end_index = match.end(1)\n adverb = match.group(1)\n return start_index, end_index, adverb\n else:\n return None", "matching_cluster_idx": 2}, {"solution": "import re\ndef find_adverb_position(sentence):\n \"\"\"\n Finds the first adverb and its start and end positions in a sentence.\n\n Args:\n sentence: The input sentence.\n\n Returns:\n A tuple containing the start position, end position, and the adverb itself, \n or None if no adverb is found.\n \"\"\"\n\n # Regular expression pattern to match adverbs ending in \"ly\" \n # and handle potential punctuation immediately following the adverb.\n pattern = r\"\\b(\\w+ly)([!.,;:\\-\\\"'?\\s]+)?\" \n\n match = re.search(pattern, sentence)\n\n if match:\n start = match.start()\n adverb = match.group(1)\n end = start + len(adverb)\n return start, end, adverb\n else:\n return None", "matching_cluster_idx": 2}, {"solution": "import re\ndef find_adverb_position(sentence):\n \"\"\"\n Finds the first adverb and its positions in a given sentence.\n\n Args:\n sentence: The input sentence as a string.\n\n Returns:\n A tuple containing the start position, end position, and the adverb itself.\n Returns None if no adverb is found.\n \"\"\"\n # Regular expression pattern to match adverbs ending in \"ly\"\n # Includes handling for multiple exclamation marks or other punctuation\n pattern = r\"\\b(\\w+ly)(\\W*)\" \n\n match = re.search(pattern, sentence)\n\n if match:\n start_pos = match.start(1)\n end_pos = match.end(1)\n adverb = match.group(1)\n return (start_pos, end_pos, adverb)\n else:\n return None", "matching_cluster_idx": 2}, {"solution": "import re\ndef find_adverb_position(sentence):\n \"\"\"\n Finds the first adverb and its position in a given sentence.\n\n Args:\n sentence: The input sentence.\n\n Returns:\n A tuple containing the start index, end index, and the adverb itself. \n Returns None if no adverb is found.\n \"\"\"\n # Regular expression to match adverbs ending in \"ly\" with optional punctuation\n pattern = r\"\\b(\\w+ly)(\\W*)\"\n\n match = re.search(pattern, sentence)\n\n if match:\n start_index = match.start(1)\n end_index = match.end(1)\n adverb = match.group(1)\n return start_index, end_index, adverb\n else:\n return None", "matching_cluster_idx": 2}, {"solution": "import re\ndef find_adverb_position(sentence):\n \"\"\"\n Finds the first adverb and its position in a given sentence.\n\n Args:\n sentence: The input sentence as a string.\n\n Returns:\n A tuple containing the start index, end index, and the adverb itself.\n Returns None if no adverb is found.\n \"\"\"\n # Regular expression pattern to match adverbs ending in \"-ly\" along with potential punctuation.\n pattern = r\"\\b(\\w+ly)([!.,:;?]*)\" # \\b ensures word boundaries\n\n match = re.search(pattern, sentence)\n\n if match:\n start_index = match.start(1)\n end_index = match.end(1)\n adverb = match.group(1)\n return start_index, end_index, adverb\n else:\n return None", "matching_cluster_idx": 2}, {"solution": "import re\ndef find_adverb_position(sentence):\n \"\"\"\n Finds the first adverb and its position in a given sentence.\n\n Args:\n sentence: The input sentence as a string.\n\n Returns:\n A tuple containing the start index, end index, and the adverb itself.\n Returns None if no adverb is found.\n \"\"\"\n # Regular expression pattern to match adverbs ending in \"ly\" \n # (accounts for punctuation immediately following the adverb)\n pattern = r\"\\b(\\w+ly)(\\W*)\"\n\n match = re.search(pattern, sentence)\n\n if match:\n adverb = match.group(1)\n start_index = match.start()\n end_index = match.end(1) # Only get the end index of the adverb, not including punctuation.\n return (start_index, end_index, adverb)\n else:\n return None", "matching_cluster_idx": 2}, {"solution": "import re\ndef find_adverb_position(sentence):\n \"\"\"\n Finds the first adverb and its position in a given sentence.\n\n Args:\n sentence: The input sentence.\n\n Returns:\n A tuple containing the start index, end index, and the adverb itself.\n Returns None if no adverb is found.\n \"\"\"\n # Regex pattern to match adverbs ending in \"ly\" with optional punctuation\n pattern = r\"\\b(\\w+ly)(\\W*)\" # \\b for word boundary\n\n match = re.search(pattern, sentence)\n\n if match:\n start_index = match.start(1)\n end_index = match.end(1)\n adverb = match.group(1)\n return start_index, end_index, adverb\n else:\n return None", "matching_cluster_idx": 2}, {"solution": "import re\ndef find_adverb_position(sentence):\n \"\"\"\n Finds the first adverb and its positions in a given sentence.\n\n Args:\n sentence: The input sentence.\n\n Returns:\n A tuple containing the start index, end index, and the adverb itself.\n Returns None if no adverb is found.\n \"\"\"\n # Regular expression pattern to match adverbs ending in \"ly\" with optional punctuation.\n pattern = r\"\\b(\\w+ly)(\\W*)\"\n\n match = re.search(pattern, sentence)\n\n if match:\n start_index = match.start(1)\n end_index = match.end(1)\n adverb = match.group(1)\n return (start_index, end_index, adverb)\n else:\n return None", "matching_cluster_idx": 2}]}, "Mbpp/446": {"dps": 96.05911330049261, "dps_norm": 60.0, "pass@1": 89.0, "profiled": [{"solution": "def count_Occurrence(input_tuple, input_list):\n \"\"\"Counts occurrences of list elements within a tuple.\n\n Args:\n input_tuple: The tuple to search within.\n input_list: The list of elements to count.\n\n Returns:\n The total number of occurrences of the list elements in the tuple.\n \"\"\"\n\n count = 0\n for element in input_list:\n count += input_tuple.count(element)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(my_tuple, my_list):\n \"\"\"\n Counts the occurrences of elements from a list within a tuple.\n\n Args:\n my_tuple: The tuple to search within.\n my_list: The list of elements to count.\n\n Returns:\n The total number of occurrences of the list elements in the tuple.\n \"\"\"\n count = 0\n for element in my_list:\n count += my_tuple.count(element)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(input_tuple, input_list):\n \"\"\"\n Counts the occurrences of elements from a list within a tuple.\n\n Args:\n input_tuple: The tuple to search within.\n input_list: The list of elements to count.\n\n Returns:\n The total number of occurrences of the list elements in the tuple.\n \"\"\"\n\n count = 0\n for element in input_list:\n count += input_tuple.count(element)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(input_tuple, input_list):\n \"\"\"\n Counts the occurrences of elements from a list within a tuple.\n\n Args:\n input_tuple: The tuple to search within.\n input_list: The list of elements to count.\n\n Returns:\n The total number of occurrences of the list elements in the tuple.\n \"\"\"\n\n count = 0\n for element in input_list:\n count += input_tuple.count(element)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(input_tuple, input_list):\n \"\"\"\n Counts the occurrences of elements from a list within a tuple.\n\n Args:\n input_tuple: The tuple to search within.\n input_list: The list of elements to count.\n\n Returns:\n The total number of occurrences of the list elements in the tuple.\n \"\"\"\n\n count = 0\n for element in input_list:\n count += input_tuple.count(element)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(my_tuple, my_list):\n \"\"\"\n Counts the occurrences of elements from a list within a tuple.\n\n Args:\n my_tuple: The tuple to search within.\n my_list: The list of elements to count.\n\n Returns:\n The total number of occurrences of the list elements in the tuple.\n \"\"\"\n count = 0\n for element in my_list:\n count += my_tuple.count(element)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(my_tuple, my_list):\n \"\"\"\n Counts the occurrences of elements from a list within a tuple.\n\n Args:\n my_tuple: The tuple to search within.\n my_list: The list of elements to count.\n\n Returns:\n The total number of occurrences of elements from my_list in my_tuple.\n \"\"\"\n\n count = 0\n for item in my_list:\n count += my_tuple.count(item)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(my_tuple, my_list):\n \"\"\"\n Counts the occurrences of elements from a list within a tuple.\n\n Args:\n my_tuple: The tuple to search within.\n my_list: The list of elements to count.\n\n Returns:\n The total number of occurrences of elements from my_list in my_tuple.\n \"\"\"\n count = 0\n for item in my_list:\n count += my_tuple.count(item) # Use tuple's built-in count method\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(input_tuple, input_list):\n \"\"\"Counts the occurrences of elements from a list within a tuple.\n\n Args:\n input_tuple: The tuple to search within.\n input_list: The list of elements to count.\n\n Returns:\n The total number of occurrences of the list elements in the tuple.\n \"\"\"\n count = 0\n for element in input_list:\n count += input_tuple.count(element)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(input_tuple, input_list):\n \"\"\"\n Counts the occurrences of elements from a list within a tuple.\n\n Args:\n input_tuple: The tuple to search within.\n input_list: The list of elements to count.\n\n Returns:\n The total number of occurrences of the list elements in the tuple.\n \"\"\"\n count = 0\n for element in input_list:\n count += input_tuple.count(element)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(my_tuple, my_list):\n \"\"\"\n Counts the occurrences of elements from a list within a tuple.\n\n Args:\n my_tuple: The tuple to search within.\n my_list: The list of elements to count.\n\n Returns:\n The total number of occurrences of elements from my_list in my_tuple.\n \"\"\"\n\n count = 0\n for element in my_list:\n count += my_tuple.count(element)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(input_tuple, input_list):\n \"\"\"\n Counts the occurrences of elements from a list within a tuple.\n\n Args:\n input_tuple: The tuple to search within.\n input_list: The list of elements to count.\n\n Returns:\n The total number of occurrences of elements from input_list within input_tuple.\n \"\"\"\n count = 0\n for element in input_list:\n count += input_tuple.count(element)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(input_tuple, input_list):\n \"\"\"\n Counts the occurrences of elements from a list within a tuple.\n\n Args:\n input_tuple: The tuple to search within.\n input_list: The list of elements to count.\n\n Returns:\n The total number of occurrences of elements from the list in the tuple.\n \"\"\"\n count = 0\n for element in input_list:\n count += input_tuple.count(element)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(input_tuple, input_list):\n \"\"\"\n Counts the occurrences of elements from a list within a tuple.\n\n Args:\n input_tuple: The tuple to search within.\n input_list: The list of elements to count.\n\n Returns:\n The total number of occurrences of the list elements in the tuple.\n \"\"\"\n count = 0\n for element in input_list:\n count += input_tuple.count(element)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(input_tuple, input_list):\n \"\"\"\n Counts the occurrences of elements from a list within a tuple.\n\n Args:\n input_tuple: The tuple to search within.\n input_list: The list of elements to count.\n\n Returns:\n The total number of occurrences of elements from the list in the tuple.\n \"\"\"\n\n count = 0\n for element in input_list:\n count += input_tuple.count(element)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(my_tuple, my_list):\n \"\"\"\n Counts the occurrences of elements from a list within a tuple.\n\n Args:\n my_tuple: The tuple to search within.\n my_list: The list of elements to count.\n\n Returns:\n The total number of occurrences of the list elements in the tuple.\n \"\"\"\n\n count = 0\n for item in my_list:\n count += my_tuple.count(item) # Efficiently counts using tuple's built-in method\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(input_tuple, input_list):\n \"\"\"Counts the occurrences of elements from a list within a tuple.\n\n Args:\n input_tuple: The tuple to search within.\n input_list: The list of elements to count.\n\n Returns:\n The total number of occurrences of the list elements in the tuple.\n \"\"\"\n\n count = 0\n for element in input_list:\n count += input_tuple.count(element)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(input_tuple, input_list):\n \"\"\"\n Counts the occurrences of elements from a list within a tuple.\n\n Args:\n input_tuple: The tuple to search within.\n input_list: The list of elements to count.\n\n Returns:\n The total number of occurrences of the list elements in the tuple.\n \"\"\"\n\n count = 0\n for element in input_list:\n count += input_tuple.count(element)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(my_tuple, my_list):\n \"\"\"Counts the occurrences of elements from a list within a tuple.\n\n Args:\n my_tuple: The tuple to search within.\n my_list: The list of elements to count.\n\n Returns:\n The total number of occurrences of the list elements in the tuple.\n \"\"\"\n count = 0\n for element in my_list:\n count += my_tuple.count(element)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(input_tuple, input_list):\n \"\"\"\n Counts the occurrences of elements from a list within a tuple.\n\n Args:\n input_tuple: The tuple to search within.\n input_list: The list of elements to count.\n\n Returns:\n The total number of occurrences of the list elements in the tuple.\n \"\"\"\n\n count = 0\n for element in input_list:\n count += input_tuple.count(element)\n return count", "matching_cluster_idx": 2}]}, "Mbpp/451": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 83.0, "profiled": [{"solution": "def remove_whitespaces(input_string):\n \"\"\"Removes all whitespace characters from a string.\n\n Args:\n input_string: The string to remove whitespaces from.\n\n Returns:\n The string with all whitespaces removed.\n \"\"\"\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(s):\n \"\"\"Removes all whitespace characters from a string.\n\n Args:\n s: The input string.\n\n Returns:\n The string with all whitespace characters removed.\n \"\"\"\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string):\n \"\"\"Removes all whitespace characters from a string.\n\n Args:\n input_string: The string to remove whitespaces from.\n\n Returns:\n The string with all whitespaces removed.\n \"\"\"\n\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(s):\n \"\"\"Removes all whitespace characters from a string.\n\n Args:\n s: The input string.\n\n Returns:\n The string with all whitespace characters removed.\n \"\"\"\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string):\n \"\"\"Removes all whitespace characters from a string.\n\n Args:\n input_string: The string to remove whitespaces from.\n\n Returns:\n The string with all whitespaces removed.\n \"\"\"\n\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(s):\n \"\"\"Removes all whitespace characters from a string.\n\n Args:\n s: The input string.\n\n Returns:\n The string with all whitespace characters removed.\n \"\"\"\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(s):\n \"\"\"Removes all whitespace characters from a string.\n\n Args:\n s: The input string.\n\n Returns:\n The string with all whitespace characters removed.\n \"\"\"\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(text):\n \"\"\"Removes all whitespace characters from a string.\n\n Args:\n text: The input string.\n\n Returns:\n The string with all whitespace characters removed.\n \"\"\"\n\n return text.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(s):\n \"\"\"Removes all whitespace characters from a string.\n\n Args:\n s: The input string.\n\n Returns:\n The string with all whitespace removed.\n \"\"\"\n\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(s: str) -> str:\n \"\"\"Removes all whitespace characters from a string.\"\"\"\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string):\n \"\"\"Removes all whitespace characters from a string.\n\n Args:\n input_string: The string to remove whitespaces from.\n\n Returns:\n A new string with all whitespaces removed.\n \"\"\"\n\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(s):\n \"\"\"Removes all whitespace characters from a string.\n\n Args:\n s: The input string.\n\n Returns:\n The string with all whitespace removed.\n \"\"\"\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(s):\n \"\"\"Removes all whitespace characters from a string.\n\n Args:\n s: The input string.\n\n Returns:\n The string with all whitespace removed.\n \"\"\"\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string):\n \"\"\"Removes all whitespace characters from a string.\n\n Args:\n input_string: The string to remove whitespaces from.\n\n Returns:\n The string with all whitespaces removed.\n \"\"\"\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(s):\n \"\"\"Removes all whitespace characters from a string.\n\n Args:\n s: The input string.\n\n Returns:\n The string with all whitespace characters removed.\n \"\"\"\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string):\n \"\"\"Removes all whitespace characters from a string.\n\n Args:\n input_string: The string to remove whitespaces from.\n\n Returns:\n A new string with all whitespaces removed.\n \"\"\"\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(s):\n \"\"\"Removes all whitespace characters from a string.\n\n Args:\n s: The input string.\n\n Returns:\n The string with all whitespace characters removed.\n \"\"\"\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(s):\n \"\"\"Removes all whitespace characters from a string.\n\n Args:\n s: The input string.\n\n Returns:\n The string with all whitespace characters removed.\n \"\"\"\n\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(s):\n \"\"\"Removes all whitespace characters from a string.\n\n Args:\n s: The input string.\n\n Returns:\n The string with all whitespace removed.\n \"\"\"\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(s):\n \"\"\"Removes all whitespace characters from a string.\n\n Args:\n s: The input string.\n\n Returns:\n The string with all whitespace characters removed.\n \"\"\"\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}]}, "Mbpp/456": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def reverse_string_list(string_list):\n \"\"\"Reverses each string in a list of strings.\n\n Args:\n string_list: A list of strings.\n\n Returns:\n A new list containing the reversed strings.\n \"\"\"\n reversed_list = []\n for string in string_list:\n reversed_list.append(string[::-1])\n return reversed_list", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n \"\"\"\n Reverses each string in a given list of string values.\n\n Args:\n string_list: A list of strings.\n\n Returns:\n A list containing the reversed strings.\n \"\"\"\n reversed_list = []\n for string in string_list:\n reversed_list.append(string[::-1])\n return reversed_list", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n \"\"\"Reverses each string within a list of strings.\n\n Args:\n string_list: A list of strings.\n\n Returns:\n A new list containing the reversed strings.\n \"\"\"\n reversed_list = []\n for string in string_list:\n reversed_list.append(string[::-1])\n return reversed_list\nmy_list = ['apple', 'banana', 'cherry']\nreversed_list = reverse_string_list(my_list)", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n \"\"\"\n Reverses each string in a given list of string values.\n\n Args:\n string_list: A list of strings.\n\n Returns:\n A new list with each string reversed.\n \"\"\"\n reversed_list = []\n for string in string_list:\n reversed_list.append(string[::-1])\n return reversed_list\nmy_list = ['apple', 'banana', 'cherry']\nreversed_list = reverse_string_list(my_list)", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n \"\"\"\n Reverses each string in a given list of string values.\n\n Args:\n string_list: A list of strings.\n\n Returns:\n A list with each string reversed.\n \"\"\"\n reversed_list = []\n for string in string_list:\n reversed_list.append(string[::-1])\n return reversed_list", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n \"\"\"Reverses each string within a list of strings.\n\n Args:\n string_list: A list of strings.\n\n Returns:\n A new list containing the reversed strings.\n \"\"\"\n reversed_list = []\n for string in string_list:\n reversed_list.append(string[::-1])\n return reversed_list", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n \"\"\"Reverses each string in a list of strings.\n\n Args:\n string_list: A list of strings.\n\n Returns:\n A new list with each string reversed.\n \"\"\"\n reversed_list = []\n for string in string_list:\n reversed_list.append(string[::-1])\n return reversed_list", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n \"\"\"\n Reverses each string in a given list of string values.\n\n Args:\n string_list: A list of strings.\n\n Returns:\n A list of reversed strings.\n \"\"\"\n reversed_list = []\n for string in string_list:\n reversed_list.append(string[::-1])\n return reversed_list", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n \"\"\"\n Reverses each string in a given list of strings.\n\n Args:\n string_list: A list of strings.\n\n Returns:\n A list with each string reversed.\n \"\"\"\n reversed_list = []\n for string in string_list:\n reversed_list.append(string[::-1])\n return reversed_list", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n \"\"\"Reverses each string in a list of strings.\n\n Args:\n string_list: A list of strings.\n\n Returns:\n A new list containing the reversed strings.\n \"\"\"\n reversed_list = []\n for string in string_list:\n reversed_list.append(string[::-1])\n return reversed_list", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n \"\"\"Reverses each string in a list.\n\n Args:\n string_list: A list of strings.\n\n Returns:\n A list with each string reversed.\n \"\"\"\n\n reversed_list = []\n for string in string_list:\n reversed_list.append(string[::-1])\n return reversed_list", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n \"\"\"\n Reverses each string in a given list of strings.\n\n Args:\n string_list: A list of strings.\n\n Returns:\n A new list containing the reversed strings.\n \"\"\"\n reversed_list = []\n for string in string_list:\n reversed_list.append(string[::-1])\n return reversed_list", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n \"\"\"Reverses each string within a list of strings.\n\n Args:\n string_list: A list of strings.\n\n Returns:\n A new list containing the reversed strings.\n \"\"\"\n reversed_list = []\n for string in string_list:\n reversed_list.append(string[::-1]) # Efficient string reversal in Python\n return reversed_list\nmy_list = ['apple', 'banana', 'cherry']\nreversed_list = reverse_string_list(my_list)", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n \"\"\"\n Reverses each string within a list of strings.\n\n Args:\n string_list: A list of strings.\n\n Returns:\n A new list containing the reversed strings.\n \"\"\"\n reversed_list = []\n for string in string_list:\n reversed_list.append(string[::-1])\n return reversed_list\nmy_list = ['apple', 'banana', 'cherry']\nreversed_list = reverse_string_list(my_list)", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n \"\"\"Reverses each string in a list of strings.\n\n Args:\n string_list: A list of strings.\n\n Returns:\n A new list with each string reversed.\n \"\"\"\n reversed_list = []\n for string in string_list:\n reversed_list.append(string[::-1])\n return reversed_list", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n \"\"\"Reverses each string within a list of strings.\n\n Args:\n string_list: A list of strings.\n\n Returns:\n A new list containing the reversed strings.\n \"\"\"\n reversed_list = []\n for string in string_list:\n reversed_list.append(string[::-1])\n return reversed_list\nmy_list = ['apple', 'banana', 'cherry']\nreversed_list = reverse_string_list(my_list)", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n \"\"\"Reverses each string in a list of strings.\n\n Args:\n string_list: A list of strings.\n\n Returns:\n A new list containing the reversed strings.\n \"\"\"\n reversed_list = []\n for s in string_list:\n reversed_list.append(s[::-1])\n return reversed_list\nmy_list = ['apple', 'banana', 'cherry']\nreversed_list = reverse_string_list(my_list)", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n \"\"\"\n Reverses each string in a given list of string values.\n\n Args:\n string_list: A list of strings.\n\n Returns:\n A list containing the reversed strings.\n \"\"\"\n reversed_list = []\n for string in string_list:\n reversed_list.append(string[::-1])\n return reversed_list\nmy_list = ['apple', 'banana', 'cherry']\nreversed_list = reverse_string_list(my_list)", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n \"\"\"Reverses each string within a list of strings.\n\n Args:\n string_list: A list of strings.\n\n Returns:\n A new list containing the reversed strings.\n \"\"\"\n reversed_list = []\n for string in string_list:\n reversed_list.append(string[::-1])\n return reversed_list", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n \"\"\"\n Reverses each string in a given list of string values.\n\n Args:\n string_list: A list of strings.\n\n Returns:\n A new list with each string reversed.\n \"\"\"\n reversed_list = []\n for string in string_list:\n reversed_list.append(string[::-1])\n return reversed_list\nmy_list = ['Red', 'Green', 'Blue', 'White', 'Black']\nreversed_list = reverse_string_list(my_list)", "matching_cluster_idx": 4}]}, "Mbpp/460": {"dps": 27.019230769230766, "dps_norm": 52.0, "pass@1": 99.0, "profiled": [{"solution": "def Extract(lst):\n \"\"\"\n Extracts the first element of each sublist in a given list of lists.\n\n Args:\n lst: A list of lists.\n\n Returns:\n A list containing the first element of each sublist.\n Returns an empty list if the input list is empty or contains non-list elements.\n \"\"\"\n result = []\n for item in lst:\n if isinstance(item, list) and len(item) > 0:\n result.append(item[0])\n return result", "matching_cluster_idx": -1}, {"solution": "def Extract(lst):\n \"\"\"\n Extracts the first element of each sublist within a given list.\n\n Args:\n lst: A list of sublists.\n\n Returns:\n A new list containing the first element of each sublist.\n Returns an empty list if the input is empty or not a list of lists.\n \"\"\"\n\n result = []\n if lst and all(isinstance(sub, list) for sub in lst): # Check if it's a non-empty list of lists\n for sublist in lst:\n if sublist: # Guard against empty sublists\n result.append(sublist[0])\n return result", "matching_cluster_idx": 1}, {"solution": "def Extract(lst):\n \"\"\"\n Extracts the first element of each sublist within a given list.\n\n Args:\n lst: A list of sublists.\n\n Returns:\n A list containing the first element of each sublist.\n Returns an empty list if the input list is empty or contains non-list elements.\n \"\"\"\n result = []\n for sublist in lst:\n if isinstance(sublist, list) and len(sublist) > 0:\n result.append(sublist[0])\n return result", "matching_cluster_idx": -1}, {"solution": "def Extract(lst):\n \"\"\"\n Extracts the first element of each sublist in a given list of lists.\n\n Args:\n lst: A list of lists.\n\n Returns:\n A list containing the first element of each sublist.\n Returns an empty list if the input list is empty or contains empty sublists.\n \"\"\"\n\n result = []\n for sublist in lst:\n if sublist: # Check if the sublist is not empty\n result.append(sublist[0])\n return result", "matching_cluster_idx": 3}, {"solution": "def Extract(lst):\n \"\"\"\n Extracts the first element of each sublist.\n\n Args:\n lst: A list of lists.\n\n Returns:\n A list containing the first element of each sublist.\n Returns an empty list if the input list is empty or not a list of lists.\n \"\"\"\n result = []\n if not lst:\n return result # Handle empty input list\n if not all(isinstance(sublist, list) for sublist in lst):\n return result # Handle if not all elements are lists\n\n for sublist in lst:\n if sublist: # Check if the sublist is not empty\n result.append(sublist[0])\n return result", "matching_cluster_idx": 1}, {"solution": "def Extract(lst):\n \"\"\"\n Extracts the first element of each sublist in a given list of lists.\n\n Args:\n lst: A list of lists.\n\n Returns:\n A list containing the first element of each sublist.\n Returns an empty list if the input list is empty or contains empty sublists.\n \"\"\"\n result = []\n for sublist in lst:\n if sublist: # Check if the sublist is not empty\n result.append(sublist[0])\n return result", "matching_cluster_idx": 3}, {"solution": "def Extract(lst):\n \"\"\"\n Extracts the first element of each sublist within a given list.\n\n Args:\n lst: A list of sublists.\n\n Returns:\n A list containing the first elements of each sublist.\n Returns an empty list if the input list is empty or contains empty sublists.\n \"\"\"\n result = []\n for sublist in lst:\n if sublist: # Check if the sublist is not empty\n result.append(sublist[0])\n return result", "matching_cluster_idx": 3}, {"solution": "def Extract(lst):\n \"\"\"\n Extracts the first element of each sublist.\n\n Args:\n lst: A list of lists.\n\n Returns:\n A list containing the first element of each sublist.\n Returns an empty list if the input list is empty or contains non-list elements.\n \"\"\"\n result = []\n for item in lst:\n if isinstance(item, list) and len(item) > 0:\n result.append(item[0])\n return result", "matching_cluster_idx": -1}, {"solution": "def Extract(lst):\n \"\"\"\n Extracts the first element of each sublist in a given list of lists.\n\n Args:\n lst: A list of lists.\n\n Returns:\n A new list containing the first element of each sublist.\n Returns an empty list if the input is an empty list.\n Raises TypeError if the input is not a list or if any sublist is not a list or is empty.\n \"\"\"\n if not isinstance(lst, list):\n raise TypeError(\"Input must be a list.\")\n \n if not lst:\n return []\n\n result = []\n for sublist in lst:\n if not isinstance(sublist, list):\n raise TypeError(\"Sublists must be lists.\")\n if not sublist:\n raise TypeError(\"Sublists cannot be empty.\")\n result.append(sublist[0])\n return result", "matching_cluster_idx": 1}, {"solution": "def Extract(lst):\n \"\"\"\n Extracts the first element from each sublist within the provided list.\n\n Args:\n lst: A list of lists.\n\n Returns:\n A new list containing the first element of each sublist.\n Returns an empty list if the input list is empty or contains non-list elements.\n \"\"\"\n result = []\n for item in lst:\n if isinstance(item, list) and len(item) > 0: # Check if it's a non-empty list\n result.append(item[0])\n return result", "matching_cluster_idx": -1}, {"solution": "def Extract(lst):\n \"\"\"\n Extracts the first element of each sublist in a given list of lists.\n\n Args:\n lst: A list of lists.\n\n Returns:\n A list containing the first element of each sublist.\n Returns an empty list if the input list is empty or contains empty sublists.\n \"\"\"\n result = []\n for sublist in lst:\n if sublist: # Check if the sublist is not empty\n result.append(sublist[0])\n return result", "matching_cluster_idx": 3}, {"solution": "def Extract(lst):\n \"\"\"\n Extracts the first element of each sublist in a given list of lists.\n\n Args:\n lst: A list of lists.\n\n Returns:\n A list containing the first element of each sublist.\n Returns an empty list if the input list is empty or contains any non-list elements.\n \"\"\"\n result = []\n for item in lst:\n if isinstance(item, list) and len(item) > 0:\n result.append(item[0])\n elif not isinstance(item, list):\n return [] # Return empty list if any element is not a list\n return result", "matching_cluster_idx": -1}, {"solution": "def Extract(lst):\n \"\"\"\n Extracts the first element of each sublist in a given list of lists.\n\n Args:\n lst: A list of lists.\n\n Returns:\n A list containing the first element of each sublist.\n Returns an empty list if the input is not a list or if any sublist is empty.\n \"\"\"\n if not isinstance(lst, list):\n return []\n\n result = []\n for sublist in lst:\n if isinstance(sublist, list) and sublist:\n result.append(sublist[0])\n return result", "matching_cluster_idx": 1}, {"solution": "def Extract(lst):\n \"\"\"\n Extracts the first element of each sublist.\n\n Args:\n lst: A list of lists.\n\n Returns:\n A list containing the first element of each sublist.\n Returns an empty list if the input list is empty or contains empty sublists.\n \"\"\"\n result = []\n for sublist in lst:\n if sublist: # Check if the sublist is not empty\n result.append(sublist[0])\n return result", "matching_cluster_idx": 3}, {"solution": "def Extract(lst):\n return [item[0] for item in lst]", "matching_cluster_idx": 3}, {"solution": "def Extract(lst):\n \"\"\"\n Extracts the first element from each sublist in a given list of lists.\n\n Args:\n lst: A list of lists.\n\n Returns:\n A list containing the first element of each sublist.\n Returns an empty list if the input list is empty or contains empty sublists.\n \"\"\"\n result = []\n for sublist in lst:\n if sublist: # Check if the sublist is not empty\n result.append(sublist[0])\n return result", "matching_cluster_idx": 3}, {"solution": "def Extract(lst):\n \"\"\"\n Extracts the first element of each sublist within a given list.\n\n Args:\n lst: A list of sublists.\n\n Returns:\n A new list containing the first element of each sublist.\n Returns an empty list if the input list is empty or contains empty sublists.\n \"\"\"\n result = []\n for sublist in lst:\n if sublist: # Check if the sublist is not empty\n result.append(sublist[0])\n return result", "matching_cluster_idx": 3}, {"solution": "def Extract(lst):\n \"\"\"\n Extracts the first element from each sublist in a given list of lists.\n\n Args:\n lst: A list of lists.\n\n Returns:\n A new list containing the first element of each sublist. \n Returns an empty list if the input list is empty or contains empty sublists.\n \"\"\"\n result = []\n for sublist in lst:\n if sublist: # Check if the sublist is not empty\n result.append(sublist[0])\n return result", "matching_cluster_idx": 3}, {"solution": "def Extract(lst):\n \"\"\"\n Extracts the first element of each sublist in a given list of lists.\n\n Args:\n lst: A list of lists.\n\n Returns:\n A list containing the first element of each sublist.\n Returns an empty list if the input list is empty or contains empty sublists.\n \"\"\"\n result = []\n for sublist in lst:\n if sublist: # Check if the sublist is not empty\n result.append(sublist[0])\n return result", "matching_cluster_idx": 3}, {"solution": "def Extract(lst):\n \"\"\"\n Extracts the first element of each sublist within a given list.\n\n Args:\n lst: A list of lists.\n\n Returns:\n A new list containing the first element of each sublist.\n Returns an empty list if the input list is empty or contains empty sublists.\n \"\"\"\n result = []\n for sublist in lst:\n if sublist: # Check if the sublist is not empty\n result.append(sublist[0])\n return result", "matching_cluster_idx": 3}]}, "Mbpp/474": {"dps": 47.70731707317073, "dps_norm": 54.285714285714285, "pass@1": 100.0, "profiled": [{"solution": "def replace_char(string, old_char, new_char):\n \"\"\"\n Replaces all occurrences of old_char with new_char in a string.\n\n Args:\n string: The input string.\n old_char: The character to be replaced.\n new_char: The character to replace with.\n\n Returns:\n The modified string with all occurrences of old_char replaced by new_char.\n \"\"\"\n new_string = \"\"\n for char in string:\n if char == old_char:\n new_string += new_char\n else:\n new_string += char\n return new_string", "matching_cluster_idx": 2}, {"solution": "def replace_char(string, old_char, new_char):\n \"\"\"Replaces all occurrences of old_char with new_char in the given string.\n\n Args:\n string: The input string.\n old_char: The character to be replaced.\n new_char: The character to replace with.\n\n Returns:\n The modified string with all occurrences of old_char replaced by new_char.\n \"\"\"\n\n new_string = \"\"\n for char in string:\n if char == old_char:\n new_string += new_char\n else:\n new_string += char\n return new_string", "matching_cluster_idx": 2}, {"solution": "def replace_char(text, old_char, new_char):\n \"\"\"Replaces all occurrences of old_char with new_char in text.\n\n Args:\n text: The input string.\n old_char: The character to be replaced.\n new_char: The replacement character.\n\n Returns:\n The modified string with replacements.\n \"\"\"\n return text.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(text, old_char, new_char):\n \"\"\"Replaces all occurrences of old_char with new_char in the given text.\n\n Args:\n text: The input string.\n old_char: The character to be replaced.\n new_char: The character to replace with.\n\n Returns:\n The modified string with replacements.\n \"\"\"\n new_text = \"\"\n for char in text:\n if char == old_char:\n new_text += new_char\n else:\n new_text += char\n return new_text", "matching_cluster_idx": 2}, {"solution": "def replace_char(string, old_char, new_char):\n \"\"\"Replaces all occurrences of old_char with new_char in the given string.\n\n Args:\n string: The string to modify.\n old_char: The character to replace.\n new_char: The character to replace with.\n\n Returns:\n The modified string with all occurrences of old_char replaced by new_char.\n \"\"\"\n\n new_string = \"\"\n for char in string:\n if char == old_char:\n new_string += new_char\n else:\n new_string += char\n return new_string", "matching_cluster_idx": 2}, {"solution": "def replace_char(text, old_char, new_char):\n \"\"\"Replaces all occurrences of old_char with new_char in the input string.\n\n Args:\n text: The input string.\n old_char: The character to be replaced.\n new_char: The character to replace with.\n\n Returns:\n The modified string with replacements.\n \"\"\"\n\n new_text = \"\"\n for char in text:\n if char == old_char:\n new_text += new_char\n else:\n new_text += char\n return new_text", "matching_cluster_idx": 2}, {"solution": "def replace_char(input_string, old_char, new_char):\n \"\"\"Replaces all occurrences of old_char with new_char in input_string.\n\n Args:\n input_string: The string to modify.\n old_char: The character to replace.\n new_char: The character to replace with.\n\n Returns:\n A new string with all occurrences of old_char replaced by new_char.\n \"\"\"\n return input_string.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(text, old_char, new_char):\n \"\"\"Replaces all occurrences of old_char with new_char in text.\"\"\"\n new_text = \"\"\n for char in text:\n if char == old_char:\n new_text += new_char\n else:\n new_text += char\n return new_text", "matching_cluster_idx": 2}, {"solution": "def replace_char(string, old_char, new_char):\n \"\"\"Replaces all occurrences of old_char with new_char in a string.\"\"\"\n new_string = \"\"\n for char in string:\n if char == old_char:\n new_string += new_char\n else:\n new_string += char\n return new_string", "matching_cluster_idx": 2}, {"solution": "def replace_char(text, old_char, new_char):\n \"\"\"Replaces all occurrences of old_char with new_char in the given text.\n\n Args:\n text: The input string.\n old_char: The character to be replaced.\n new_char: The character to replace with.\n\n Returns:\n The modified string with replacements.\n \"\"\"\n return text.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(text, old_char, new_char):\n \"\"\"Replaces all occurrences of old_char with new_char in the given text.\n\n Args:\n text: The input string.\n old_char: The character to be replaced.\n new_char: The character to replace with.\n\n Returns:\n The string with the characters replaced.\n \"\"\"\n\n new_text = \"\"\n for char in text:\n if char == old_char:\n new_text += new_char\n else:\n new_text += char\n return new_text", "matching_cluster_idx": 2}, {"solution": "def replace_char(string, char_to_replace, replacement_char):\n \"\"\"Replaces all occurrences of a character in a string with another character.\n\n Args:\n string: The input string.\n char_to_replace: The character to be replaced.\n replacement_char: The character to replace with.\n\n Returns:\n The modified string with replacements.\n \"\"\"\n new_string = \"\"\n for char in string:\n if char == char_to_replace:\n new_string += replacement_char\n else:\n new_string += char\n return new_string", "matching_cluster_idx": 2}, {"solution": "def replace_char(text, old_char, new_char):\n \"\"\"Replaces all occurrences of old_char with new_char in text.\"\"\"\n new_text = \"\"\n for char in text:\n if char == old_char:\n new_text += new_char\n else:\n new_text += char\n return new_text", "matching_cluster_idx": 2}, {"solution": "def replace_char(string, char_to_replace, replacement_char):\n \"\"\"\n Replaces all occurrences of a specific character in a string with another character.\n\n Args:\n string: The input string.\n char_to_replace: The character to be replaced.\n replacement_char: The character to replace with.\n\n Returns:\n The modified string with the character replaced.\n \"\"\"\n\n new_string = \"\"\n for char in string:\n if char == char_to_replace:\n new_string += replacement_char\n else:\n new_string += char\n return new_string", "matching_cluster_idx": 2}, {"solution": "def replace_char(text, old_char, new_char):\n \"\"\"Replaces all occurrences of old_char with new_char in the given text.\n\n Args:\n text: The string to modify.\n old_char: The character to replace.\n new_char: The replacement character.\n\n Returns:\n The modified string with replacements made.\n \"\"\"\n\n return text.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(string, old_char, new_char):\n \"\"\"Replaces all occurrences of old_char with new_char in a string.\"\"\"\n new_string = \"\"\n for char in string:\n if char == old_char:\n new_string += new_char\n else:\n new_string += char\n return new_string", "matching_cluster_idx": 2}, {"solution": "def replace_char(text, old_char, new_char):\n \"\"\"Replaces all occurrences of old_char with new_char in the given text.\n\n Args:\n text: The input string.\n old_char: The character to be replaced.\n new_char: The character to replace with.\n\n Returns:\n The modified string with replacements.\n \"\"\"\n\n new_text = \"\"\n for char in text:\n if char == old_char:\n new_text += new_char\n else:\n new_text += char\n return new_text", "matching_cluster_idx": 2}, {"solution": "def replace_char(text, old_char, new_char):\n \"\"\"Replaces all occurrences of old_char with new_char in a string.\n\n Args:\n text: The string to modify.\n old_char: The character to replace.\n new_char: The character to replace with.\n\n Returns:\n The modified string.\n \"\"\"\n new_text = \"\"\n for char in text:\n if char == old_char:\n new_text += new_char\n else:\n new_text += char\n return new_text", "matching_cluster_idx": 2}, {"solution": "def replace_char(text, old_char, new_char):\n \"\"\"Replaces all occurrences of old_char with new_char in a string.\n\n Args:\n text: The input string.\n old_char: The character to be replaced.\n new_char: The character to replace with.\n\n Returns:\n The modified string.\n \"\"\"\n new_text = \"\"\n for char in text:\n if char == old_char:\n new_text += new_char\n else:\n new_text += char\n return new_text", "matching_cluster_idx": 2}, {"solution": "def replace_char(string, old_char, new_char):\n \"\"\"Replaces all occurrences of old_char with new_char in the given string.\n\n Args:\n string: The input string.\n old_char: The character to be replaced.\n new_char: The character to replace with.\n\n Returns:\n The modified string with the characters replaced.\n \"\"\"\n\n new_string = \"\"\n for char in string:\n if char == old_char:\n new_string += new_char\n else:\n new_string += char\n return new_string", "matching_cluster_idx": 2}]}, "Mbpp/476": {"dps": 77.41610738255034, "dps_norm": 85.0, "pass@1": 100.0, "profiled": [{"solution": "import sys\ndef big_sum(arr):\n \"\"\"\n Finds the sum of the largest and smallest elements in an array.\n\n Args:\n arr: A list of numbers.\n\n Returns:\n The sum of the largest and smallest elements, or -sys.maxsize - 1 if the array is empty.\n \"\"\"\n if not arr:\n return -sys.maxsize - 1 # Return negative infinity if the array is empty\n min_val = sys.maxsize\n max_val = -sys.maxsize - 1\n for num in arr:\n min_val = min(min_val, num)\n max_val = max(max_val, num)\n return min_val + max_val", "matching_cluster_idx": 0}, {"solution": "import sys\ndef big_sum(arr):\n \"\"\"\n Finds the sum of the largest and smallest values in a given array.\n\n Args:\n arr: A list of numbers.\n\n Returns:\n The sum of the largest and smallest values in the array.\n Returns negative infinity if the array is empty.\n \"\"\"\n if not arr:\n return -sys.maxsize - 1 # Return negative infinity for empty array\n\n min_val = arr[0]\n max_val = arr[0]\n\n for num in arr:\n if num < min_val:\n min_val = num\n if num > max_val:\n max_val = num\n\n return min_val + max_val", "matching_cluster_idx": 3}, {"solution": "import math\ndef big_sum(arr):\n \"\"\"\n Finds the sum of the largest and smallest elements in an array.\n\n Args:\n arr: A list of numbers.\n\n Returns:\n The sum of the largest and smallest elements in the array.\n Returns -math.inf if the array is empty.\n \"\"\"\n\n if not arr:\n return -math.inf\n \n min_val = min(arr)\n max_val = max(arr)\n \n return min_val + max_val", "matching_cluster_idx": 5}, {"solution": "import sys\ndef big_sum(arr):\n \"\"\"\n Finds the sum of the largest and smallest elements in an array.\n\n Args:\n arr: A list of numbers.\n\n Returns:\n The sum of the largest and smallest elements.\n Returns negative infinity if the array is empty.\n \"\"\"\n if not arr:\n return -sys.maxsize - 1 # Return negative infinity for empty array\n\n min_val = arr[0]\n max_val = arr[0]\n\n for num in arr:\n if num < min_val:\n min_val = num\n if num > max_val:\n max_val = num\n\n return min_val + max_val", "matching_cluster_idx": 3}, {"solution": "import math\ndef big_sum(arr):\n \"\"\"\n Finds the sum of the largest and smallest elements in an array.\n\n Args:\n arr: A list of numbers.\n\n Returns:\n The sum of the largest and smallest elements.\n Returns negative infinity if the array is empty.\n \"\"\"\n if not arr:\n return -math.inf # Handle empty array case\n\n return min(arr) + max(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n \"\"\"\n Finds the sum of the largest and smallest elements in an array.\n\n Args:\n arr: A list of numbers.\n\n Returns:\n The sum of the largest and smallest elements.\n Returns 0 if the array is empty.\n \"\"\"\n if not arr:\n return 0\n return max(arr) + min(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n \"\"\"\n Finds the sum of the largest and smallest elements in an array.\n\n Args:\n arr: A list of numbers.\n\n Returns:\n The sum of the largest and smallest elements in the array.\n Returns 0 if the array is empty.\n \"\"\"\n if not arr:\n return 0 # Handle empty array case\n return min(arr) + max(arr)", "matching_cluster_idx": 5}, {"solution": "import sys\ndef big_sum(arr):\n \"\"\"\n Finds the sum of the largest and smallest values in a given array.\n\n Args:\n arr: A list of numbers.\n\n Returns:\n The sum of the largest and smallest values in the array.\n Returns 0 if the array is empty. (Clarification added for empty array case)\n \"\"\"\n if not arr:\n return 0 # Handle empty array case\n return min(arr) + max(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n \"\"\"\n Finds the sum of the largest and smallest elements in an array.\n\n Args:\n arr: A list of numbers.\n\n Returns:\n The sum of the largest and smallest elements in the array.\n Returns 0 if the array is empty.\n \"\"\"\n if not arr:\n return 0\n return min(arr) + max(arr)", "matching_cluster_idx": 5}, {"solution": "import sys\ndef big_sum(arr):\n \"\"\"\n Finds the sum of the largest and smallest elements in an array.\n\n Args:\n arr: A list of numbers.\n\n Returns:\n The sum of the largest and smallest elements.\n Returns -1 if the array is empty.\n \"\"\"\n if not arr:\n return -1\n\n min_val = sys.maxsize # Initialize with the maximum possible value\n max_val = -sys.maxsize - 1 # Initialize with the minimum possible value\n\n for num in arr:\n min_val = min(min_val, num)\n max_val = max(max_val, num)\n \n return min_val + max_val", "matching_cluster_idx": 0}, {"solution": "import sys\ndef big_sum(arr):\n \"\"\"\n Finds the sum of the largest and smallest elements in an array.\n\n Args:\n arr: A list of numbers.\n\n Returns:\n The sum of the largest and smallest elements in the array.\n Returns -sys.maxsize if the array is empty.\n \"\"\"\n if not arr:\n return -sys.maxsize # Handle empty array case\n\n min_val = arr[0]\n max_val = arr[0]\n\n for num in arr:\n if num < min_val:\n min_val = num\n if num > max_val:\n max_val = num\n\n return min_val + max_val", "matching_cluster_idx": 3}, {"solution": "def big_sum(arr):\n \"\"\"\n Finds the sum of the largest and smallest elements in an array.\n\n Args:\n arr: A list of numbers.\n\n Returns:\n The sum of the largest and smallest elements.\n Returns 0 if the array is empty.\n \"\"\"\n if not arr:\n return 0 # Handle empty array case\n\n return min(arr) + max(arr)", "matching_cluster_idx": 5}, {"solution": "import math\ndef big_sum(arr):\n \"\"\"\n Finds the sum of the largest and smallest elements in an array.\n\n Args:\n arr: A list of numbers.\n\n Returns:\n The sum of the largest and smallest elements in the array.\n Returns negative infinity if the array is empty.\n \"\"\"\n if not arr:\n return -math.inf # Or raise an exception if an empty array is considered invalid\n\n return min(arr) + max(arr)", "matching_cluster_idx": 5}, {"solution": "import math\ndef big_sum(arr):\n \"\"\"\n Finds the sum of the largest and smallest elements in an array.\n\n Args:\n arr: A list of numbers.\n\n Returns:\n The sum of the largest and smallest elements in the array.\n Returns negative infinity if the array is empty.\n \"\"\"\n if not arr:\n return -math.inf # Return negative infinity for an empty array\n\n min_val = min(arr)\n max_val = max(arr)\n\n return min_val + max_val", "matching_cluster_idx": 5}, {"solution": "import sys\ndef big_sum(arr):\n \"\"\"\n Finds the sum of the largest and smallest elements in an array.\n\n Args:\n arr: A list of numbers.\n\n Returns:\n The sum of the largest and smallest elements in the array.\n Returns -sys.maxsize if the array is empty.\n \"\"\"\n if not arr:\n return -sys.maxsize\n\n min_val = arr[0]\n max_val = arr[0]\n\n for num in arr:\n if num < min_val:\n min_val = num\n if num > max_val:\n max_val = num\n\n return min_val + max_val", "matching_cluster_idx": 3}, {"solution": "import math\ndef big_sum(arr):\n \"\"\"\n Calculates the sum of the largest and smallest elements in an array.\n\n Args:\n arr: A list of numbers.\n\n Returns:\n The sum of the largest and smallest elements in the array.\n Returns negative infinity if the array is empty.\n \"\"\"\n\n if not arr:\n return -math.inf # Return negative infinity for an empty array\n\n return min(arr) + max(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n \"\"\"\n Finds the sum of the largest and smallest elements in an array.\n\n Args:\n arr: A list of numbers.\n\n Returns:\n The sum of the largest and smallest elements in the array.\n Returns 0 if the array is empty.\n \"\"\"\n if not arr:\n return 0\n return min(arr) + max(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n \"\"\"\n Finds the sum of the largest and smallest elements in an array.\n\n Args:\n arr: A list of numbers.\n\n Returns:\n The sum of the largest and smallest elements in the array.\n Returns 0 if the array is empty.\n \"\"\"\n if not arr:\n return 0\n return min(arr) + max(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n \"\"\"\n Finds the sum of the largest and smallest elements in an array.\n\n Args:\n arr: A list of numbers.\n\n Returns:\n The sum of the largest and smallest elements in the array.\n Returns 0 if the array is empty.\n \"\"\"\n if not arr:\n return 0\n return min(arr) + max(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n \"\"\"\n Finds the sum of the largest and smallest value in a given array.\n\n Args:\n arr: A list of numbers.\n\n Returns:\n The sum of the largest and smallest elements in the array.\n Returns 0 if the array is empty.\n \"\"\"\n if not arr:\n return 0 # Handle empty array case\n return min(arr) + max(arr)", "matching_cluster_idx": 5}]}, "Mbpp/477": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def is_lower(input_string):\n \"\"\"Converts the given string to lower case.\n\n Args:\n input_string: The string to convert.\n\n Returns:\n The lower-cased string.\n \"\"\"\n return input_string.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(input_string):\n \"\"\"Converts a given string to lowercase.\n\n Args:\n input_string: The string to convert.\n\n Returns:\n The lowercase version of the input string.\n \"\"\"\n return input_string.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(input_string):\n \"\"\"Converts a given string to lowercase.\n\n Args:\n input_string: The string to convert.\n\n Returns:\n The lowercase version of the input string.\n \"\"\"\n return input_string.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(input_string):\n \"\"\"Converts the given string to lowercase.\n\n Args:\n input_string: The string to convert.\n\n Returns:\n The lowercase version of the input string.\n \"\"\"\n return input_string.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(input_string):\n \"\"\"Converts a given string to lowercase.\n\n Args:\n input_string: The string to convert.\n\n Returns:\n The lowercase version of the input string.\n \"\"\"\n return input_string.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(input_string):\n \"\"\"Converts the input string to lowercase.\n\n Args:\n input_string: The string to convert.\n\n Returns:\n The lowercase version of the input string.\n \"\"\"\n\n return input_string.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(input_string):\n \"\"\"Converts a given string to lowercase.\n\n Args:\n input_string: The string to convert.\n\n Returns:\n The lowercase version of the input string.\n \"\"\"\n return input_string.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(input_string):\n \"\"\"Converts a given string to lowercase.\n\n Args:\n input_string: The string to convert.\n\n Returns:\n The lowercase version of the input string.\n \"\"\"\n return input_string.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(input_string):\n \"\"\"Converts a given string to lowercase.\n\n Args:\n input_string: The string to convert.\n\n Returns:\n The lowercase version of the string.\n \"\"\"\n return input_string.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(input_string):\n \"\"\"Converts a given string to lowercase.\n\n Args:\n input_string: The string to convert.\n\n Returns:\n The lowercase version of the input string.\n \"\"\"\n return input_string.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(input_string):\n \"\"\"Converts a given string to lowercase.\n\n Args:\n input_string: The string to convert.\n\n Returns:\n The lowercase version of the input string.\n \"\"\"\n return input_string.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(input_string):\n \"\"\"Converts the given string to lower case.\n\n Args:\n input_string: The string to convert.\n\n Returns:\n The lower case version of the string.\n \"\"\"\n return input_string.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(input_string):\n \"\"\"Converts a given string to lowercase.\n\n Args:\n input_string: The string to convert.\n\n Returns:\n The lowercase version of the input string.\n \"\"\"\n return input_string.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(input_string):\n \"\"\"Converts the given string to lower case.\n\n Args:\n input_string: The string to convert.\n\n Returns:\n The lower case version of the input string.\n \"\"\"\n return input_string.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(input_string):\n \"\"\"Converts a given string to lowercase.\n\n Args:\n input_string: The string to convert.\n\n Returns:\n The lowercase version of the input string.\n \"\"\"\n return input_string.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(input_string):\n \"\"\"Converts a given string to lowercase.\n\n Args:\n input_string: The string to convert.\n\n Returns:\n The lowercase version of the input string.\n \"\"\"\n return input_string.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(input_string):\n \"\"\"Converts a given string to lowercase.\n\n Args:\n input_string: The string to convert.\n\n Returns:\n The lowercase version of the input string.\n \"\"\"\n return input_string.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(input_string):\n \"\"\"Converts a given string to lowercase.\n\n Args:\n input_string: The string to convert.\n\n Returns:\n The lowercase version of the input string.\n \"\"\"\n return input_string.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(input_string):\n \"\"\"Converts a given string to lowercase.\n\n Args:\n input_string: The string to convert.\n\n Returns:\n The lowercase version of the input string.\n \"\"\"\n return input_string.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(input_string):\n \"\"\"Converts the given string to lower case.\n\n Args:\n input_string: The string to convert.\n\n Returns:\n The lower case version of the string.\n \"\"\"\n return input_string.lower()", "matching_cluster_idx": 4}]}, "Mbpp/563": {"dps": 82.81420765027323, "dps_norm": 81.36363636363636, "pass@1": 99.0, "profiled": [{"solution": "import re\ndef extract_values(text):\n \"\"\"\n Extracts values enclosed in double quotes from a string.\n\n Args:\n text: The input string.\n\n Returns:\n A list of strings containing the extracted values, or an empty list if no values are found.\n \"\"\"\n\n return re.findall(r'\"([^\"]*)\"', text)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(text):\n \"\"\"\n Extracts values enclosed in double quotes from a string.\n\n Args:\n text: The input string.\n\n Returns:\n A list of strings containing the extracted values, or an empty list if no values are found.\n \"\"\"\n\n return re.findall(r'\"([^\"]*)\"', text)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(text):\n \"\"\"\n Extracts values enclosed in double quotes from a string.\n\n Args:\n text: The input string.\n\n Returns:\n A list of strings, where each string is a value found between double quotes.\n Returns an empty list if no values are found or the input is invalid.\n \"\"\"\n\n try:\n return re.findall(r'\"([^\"]*)\"', text)\n except TypeError:\n return []", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(s):\n \"\"\"\n Extracts values enclosed in double quotes from a string.\n\n Args:\n s: The input string.\n\n Returns:\n A list of strings containing the extracted values, or an empty list if no values are found.\n \"\"\"\n return re.findall(r'\"([^\"]*)\"', s)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(text):\n \"\"\"\n Extracts values enclosed in double quotes from a string.\n\n Args:\n text: The input string.\n\n Returns:\n A list of strings containing the extracted values, or an empty list if no values are found.\n \"\"\"\n\n return re.findall(r'\"([^\"]*)\"', text)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(input_string):\n \"\"\"\n Extracts values enclosed in double quotes from a string.\n\n Args:\n input_string: The string containing quoted values.\n\n Returns:\n A list of strings, where each string is a value extracted from\n within double quotes. Returns an empty list if no quoted values are found.\n \"\"\"\n return re.findall(r'\"([^\"]*)\"', input_string)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(text):\n \"\"\"\n Extracts values enclosed within double quotes from a string.\n\n Args:\n text: The input string.\n\n Returns:\n A list of strings, where each string is a value found between double quotes.\n Returns an empty list if no values are found.\n \"\"\"\n return re.findall(r'\"([^\"]*)\"', text)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(text):\n \"\"\"\n Extracts values enclosed in double quotes from a string.\n\n Args:\n text: The input string.\n\n Returns:\n A list of strings, where each string is a value found between double quotes.\n Returns an empty list if no values are found.\n \"\"\"\n return re.findall(r'\"([^\"]*)\"', text)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(text):\n \"\"\"\n Extracts values enclosed in double quotes from a string.\n\n Args:\n text: The input string.\n\n Returns:\n A list of strings, where each string is a value found within double quotes. \n Returns an empty list if no values are found or if the input is not a string.\n \"\"\"\n if not isinstance(text, str):\n return []\n return re.findall(r'\"([^\"]*)\"', text)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(text):\n \"\"\"\n Extracts values enclosed in double quotes from a string.\n\n Args:\n text: The input string.\n\n Returns:\n A list of strings, where each string is a value found between double quotes.\n Returns an empty list if no values are found.\n \"\"\"\n\n return re.findall(r'\"([^\"]*)\"', text)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(input_string):\n \"\"\"\n Extracts values enclosed in double quotes from a string.\n\n Args:\n input_string: The string to extract values from.\n\n Returns:\n A list of strings containing the extracted values, or an empty list if no values are found.\n \"\"\"\n\n return re.findall(r'\"([^\"]*)\"', input_string)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(text):\n \"\"\"\n Extracts values enclosed in double quotes from a string.\n\n Args:\n text: The input string.\n\n Returns:\n A list of strings, where each string is a value found between double quotes.\n Returns an empty list if no values are found.\n \"\"\"\n\n return re.findall(r'\"([^\"]*)\"', text)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(s):\n \"\"\"\n Extracts values enclosed in double quotes from a string.\n\n Args:\n s: The input string.\n\n Returns:\n A list of strings, where each string is a value found between double quotes.\n Returns an empty list if no values are found.\n \"\"\"\n\n return re.findall(r'\"([^\"]*)\"', s)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(text):\n \"\"\"\n Extracts values enclosed in double quotes from a string.\n\n Args:\n text: The input string.\n\n Returns:\n A list of strings containing the extracted values.\n \"\"\"\n return re.findall(r'\"([^\"]*)\"', text)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(text):\n \"\"\"\n Extracts values enclosed in double quotes from a string.\n\n Args:\n text: The input string.\n\n Returns:\n A list of strings containing the extracted values, or an empty list if no values are found.\n \"\"\"\n return re.findall(r'\"([^\"]*)\"', text)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(text):\n \"\"\"\n Extracts values enclosed in double quotes from a string.\n\n Args:\n text: The input string.\n\n Returns:\n A list of strings, where each string is a value found within double quotes.\n Returns an empty list if no values are found.\n \"\"\"\n try:\n return re.findall(r'\"([^\"]*)\"', text)\n except TypeError:\n return []", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(text):\n \"\"\"\n Extracts values enclosed in double quotes from a string.\n\n Args:\n text: The input string.\n\n Returns:\n A list of strings containing the extracted values. \n Returns an empty list if no values are found.\n \"\"\"\n\n try:\n return re.findall(r'\"([^\"]*)\"', text)\n except TypeError:\n return []", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(input_string):\n \"\"\"\n Extracts values enclosed in double quotes from a string.\n\n Args:\n input_string: The string to extract values from.\n\n Returns:\n A list of strings containing the extracted values, or an empty list if no values are found.\n \"\"\"\n try:\n return re.findall(r'\"([^\"]*)\"', input_string)\n except TypeError: # Handle cases where input is not a string\n return []", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(text):\n \"\"\"\n Extracts values enclosed in double quotes from a string.\n\n Args:\n text: The input string.\n\n Returns:\n A list of strings, where each string is a value found between double quotes.\n Returns an empty list if no values are found.\n \"\"\"\n\n return re.findall(r'\"([^\"]*)\"', text)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(s):\n \"\"\"\n Extracts values between quotation marks from a string.\n\n Args:\n s: The input string.\n\n Returns:\n A list of strings, where each string is a value found between quotation marks.\n Returns an empty list if no values are found.\n \"\"\"\n\n # Regular expression to find quoted strings. \n # It handles escaped quotes within the string as well.\n matches = re.findall(r'\"((?:[^\"\\\\]|\\\\.)*)\"', s)\n return matches", "matching_cluster_idx": 7}]}, "Mbpp/572": {"dps": 90.74074074074075, "dps_norm": 88.57142857142857, "pass@1": 100.0, "profiled": [{"solution": "from collections import Counter\ndef two_unique_nums(nums):\n \"\"\"\n Removes numbers that appear more than once in a list.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n A new list containing only the numbers that appear exactly once in the input list, preserving their original order.\n \"\"\"\n counts = Counter(nums)\n unique_nums = [num for num in nums if counts[num] == 1]\n return unique_nums", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(nums):\n \"\"\"\n Removes numbers appearing more than once from a list.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n A new list containing only the numbers that appeared exactly once in the input list.\n \"\"\"\n counts = {}\n for num in nums:\n counts[num] = counts.get(num, 0) + 1\n\n unique_nums = []\n for num, count in counts.items():\n if count == 1:\n unique_nums.append(num)\n\n return unique_nums", "matching_cluster_idx": 5}, {"solution": "from collections import Counter\ndef two_unique_nums(nums):\n \"\"\"\n Removes numbers that appear more than once in a list.\n\n Args:\n nums: A list of integers.\n\n Returns:\n A list containing only the numbers that appeared once in the input list,\n preserving their original order.\n \"\"\"\n counts = Counter(nums)\n unique_nums = [num for num in nums if counts[num] == 1]\n return unique_nums", "matching_cluster_idx": 5}, {"solution": "from collections import Counter\ndef two_unique_nums(nums):\n \"\"\"\n Removes duplicate numbers from a list and returns a new list containing only the unique numbers.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n A new list containing only the numbers that appear once in the input list.\n \"\"\"\n counts = Counter(nums)\n unique_nums = [num for num, count in counts.items() if count == 1]\n return unique_nums", "matching_cluster_idx": 6}, {"solution": "from collections import Counter\ndef two_unique_nums(nums):\n \"\"\"\n Removes duplicate numbers from a list and returns a new list containing only the unique elements.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n A new list containing only the unique elements from the input list.\n \"\"\"\n\n counts = Counter(nums)\n unique_nums = [num for num, count in counts.items() if count == 1]\n return unique_nums", "matching_cluster_idx": 6}, {"solution": "from collections import Counter\ndef two_unique_nums(nums):\n \"\"\"\n Removes numbers that appear more than once in a list.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n A list containing only the numbers that appeared once in the input list,\n preserving their original order.\n \"\"\"\n\n counts = Counter(nums)\n unique_nums = [num for num in nums if counts[num] == 1]\n return unique_nums", "matching_cluster_idx": 5}, {"solution": "from collections import Counter\ndef two_unique_nums(nums):\n \"\"\"\n Removes numbers that appear more than once in a list.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n A new list containing only the numbers that appeared once in the input list,\n preserving their original order.\n \"\"\"\n counts = Counter(nums)\n unique_nums = [num for num in nums if counts[num] == 1]\n return unique_nums", "matching_cluster_idx": 5}, {"solution": "from collections import Counter\ndef two_unique_nums(nums):\n \"\"\"Removes duplicate numbers from a list.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n A new list containing only the numbers that appear once in the input list.\n The order of the elements in the returned list should match the order of their first occurrence in the input list.\n \"\"\"\n\n counts = Counter(nums)\n unique_nums = []\n for num in nums:\n if counts[num] == 1:\n unique_nums.append(num)\n return unique_nums", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(nums):\n \"\"\"\n Removes numbers that appear more than once in a list.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n A new list containing only the numbers that appeared once in the input list, preserving their original order.\n \"\"\"\n counts = {}\n for num in nums:\n counts[num] = counts.get(num, 0) + 1\n\n unique_nums = []\n for num in nums:\n if counts[num] == 1:\n unique_nums.append(num)\n\n return unique_nums", "matching_cluster_idx": 4}, {"solution": "from collections import Counter\ndef two_unique_nums(nums):\n \"\"\"\n Removes numbers that appear more than once in a list.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n A new list containing only the numbers that appeared once in the input list.\n The order of the elements in the output list should maintain the original order \n in which they appeared in the input list.\n \"\"\"\n counts = Counter(nums)\n unique_nums = []\n for num in nums:\n if counts[num] == 1:\n unique_nums.append(num)\n return unique_nums", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(nums):\n \"\"\"\n Removes duplicate numbers from a list.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n A new list containing only the unique numbers that appear only once in the input list.\n \"\"\"\n counts = {}\n for num in nums:\n counts[num] = counts.get(num, 0) + 1\n\n unique_nums = []\n for num, count in counts.items():\n if count == 1:\n unique_nums.append(num)\n\n return unique_nums", "matching_cluster_idx": 5}, {"solution": "from collections import Counter\ndef two_unique_nums(nums):\n \"\"\"\n Removes numbers that appear more than once in a list and returns the unique numbers.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n A list containing only the numbers that appear once in the input list.\n \"\"\"\n counts = Counter(nums)\n unique_nums = [num for num, count in counts.items() if count == 1]\n return unique_nums", "matching_cluster_idx": 6}, {"solution": "from collections import Counter\ndef two_unique_nums(nums):\n \"\"\"\n Removes numbers that appear more than once in a list.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n A list containing only the numbers that appeared once in the input list, preserving their original order.\n \"\"\"\n counts = Counter(nums)\n unique_nums = [num for num in nums if counts[num] == 1]\n return unique_nums", "matching_cluster_idx": 5}, {"solution": "from collections import Counter\ndef two_unique_nums(nums):\n \"\"\"\n Removes duplicate numbers from a list and returns a new list containing only the unique numbers.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n A new list containing only the numbers that appear once in the input list.\n \"\"\"\n\n counts = Counter(nums)\n unique_nums = [num for num, count in counts.items() if count == 1]\n return unique_nums", "matching_cluster_idx": 6}, {"solution": "from collections import Counter\ndef two_unique_nums(nums):\n \"\"\"\n Removes numbers that appear more than once in a list.\n\n Args:\n nums: A list of integers.\n\n Returns:\n A list containing only the numbers that appeared exactly once in the input list,\n preserving their original order.\n \"\"\"\n counts = Counter(nums)\n unique_nums = []\n for num in nums:\n if counts[num] == 1:\n unique_nums.append(num)\n return unique_nums", "matching_cluster_idx": 5}, {"solution": "from collections import Counter\ndef two_unique_nums(nums):\n \"\"\"\n Removes numbers that appear more than once in a list.\n\n Args:\n nums: A list of integers.\n\n Returns:\n A new list containing only the numbers that appear exactly once in the input list.\n \"\"\"\n\n counts = Counter(nums)\n unique_nums = [num for num, count in counts.items() if count == 1]\n return unique_nums", "matching_cluster_idx": 6}, {"solution": "def two_unique_nums(nums):\n \"\"\"\n Removes numbers that appear more than once in a list, preserving order.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n A new list containing only the numbers that appeared once in the input list,\n preserving their original order.\n \"\"\"\n counts = {}\n for num in nums:\n counts[num] = counts.get(num, 0) + 1\n\n unique_nums = []\n for num in nums:\n if counts[num] == 1:\n unique_nums.append(num)\n return unique_nums", "matching_cluster_idx": 4}, {"solution": "from collections import Counter\ndef two_unique_nums(nums):\n \"\"\"\n Removes numbers that appear more than once in a list.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n A list containing only the numbers that appear once in the input list, preserving their original order.\n \"\"\"\n\n counts = Counter(nums)\n unique_nums = [num for num in nums if counts[num] == 1]\n return unique_nums", "matching_cluster_idx": 5}, {"solution": "from collections import Counter\ndef two_unique_nums(nums):\n \"\"\"\n Removes numbers that appear more than once in a list and returns the unique numbers.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n A list containing only the numbers that appear once in the input list.\n \"\"\"\n counts = Counter(nums)\n unique_nums = [num for num, count in counts.items() if count == 1]\n return unique_nums", "matching_cluster_idx": 6}, {"solution": "from collections import Counter\ndef two_unique_nums(nums):\n \"\"\"\n Removes numbers that appear more than once in a list.\n\n Args:\n nums: A list of integers.\n\n Returns:\n A new list containing only the numbers that appear once in the input list, preserving original order.\n \"\"\"\n counts = Counter(nums)\n unique_nums = [num for num in nums if counts[num] == 1]\n return unique_nums", "matching_cluster_idx": 5}]}, "Mbpp/578": {"dps": 58.41269841269841, "dps_norm": 63.63636363636363, "pass@1": 100.0, "profiled": [{"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"\n Interleaves three lists of the same length into a single flat list.\n\n Args:\n list1: The first list.\n list2: The second list.\n list3: The third list.\n\n Returns:\n A new list containing the interleaved elements.\n \"\"\"\n\n if not (len(list1) == len(list2) == len(list3)):\n raise ValueError(\"Lists must have the same length\")\n\n interleaved_list = []\n for i in range(len(list1)):\n interleaved_list.append(list1[i])\n interleaved_list.append(list2[i])\n interleaved_list.append(list3[i])\n return interleaved_list", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"\n Interleaves three lists of the same length into a single flat list.\n\n Args:\n list1: The first list.\n list2: The second list.\n list3: The third list.\n\n Returns:\n A new list containing the interleaved elements.\n Returns an empty list if the input lists are not of the same length.\n \"\"\"\n\n if not (len(list1) == len(list2) == len(list3)):\n return []\n\n interleaved_list = []\n for i in range(len(list1)):\n interleaved_list.append(list1[i])\n interleaved_list.append(list2[i])\n interleaved_list.append(list3[i])\n return interleaved_list", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"\n Interleaves three lists of the same length into a single flat list.\n\n Args:\n list1: The first list.\n list2: The second list.\n list3: The third list.\n\n Returns:\n A new list containing the interleaved elements of the input lists.\n Returns an empty list if the input lists are not of the same length.\n \"\"\"\n\n if not (len(list1) == len(list2) == len(list3)):\n return []\n\n interleaved_list = []\n for i in range(len(list1)):\n interleaved_list.extend([list1[i], list2[i], list3[i]])\n\n return interleaved_list", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"\n Interleaves three lists of the same length into a single flat list.\n\n Args:\n list1: The first list.\n list2: The second list.\n list3: The third list.\n\n Returns:\n A new list containing the interleaved elements of the input lists.\n Returns an empty list if the input lists are not of the same length.\n \"\"\"\n\n if not (len(list1) == len(list2) == len(list3)):\n return []\n\n interleaved_list = []\n for i in range(len(list1)):\n interleaved_list.extend([list1[i], list2[i], list3[i]])\n return interleaved_list", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"\n Interleaves three lists of the same length into a single flat list.\n\n Args:\n list1: The first list.\n list2: The second list.\n list3: The third list.\n\n Returns:\n A new list containing the interleaved elements.\n Returns an empty list if the input lists are not of the same length.\n \"\"\"\n\n if not (len(list1) == len(list2) == len(list3)):\n return []\n\n interleaved_list = []\n for i in range(len(list1)):\n interleaved_list.append(list1[i])\n interleaved_list.append(list2[i])\n interleaved_list.append(list3[i])\n return interleaved_list", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"\n Interleaves three lists of the same length into a single flat list.\n\n Args:\n list1: The first list.\n list2: The second list.\n list3: The third list.\n\n Returns:\n A new list containing the interleaved elements.\n Raises ValueError if the input lists are not of the same length.\n\n \"\"\"\n\n if not (len(list1) == len(list2) == len(list3)):\n raise ValueError(\"Lists must have the same length\")\n\n interleaved_list = []\n for i in range(len(list1)):\n interleaved_list.extend([list1[i], list2[i], list3[i]])\n return interleaved_list", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"\n Interleaves three lists of the same length into a single flat list.\n\n Args:\n list1: The first list.\n list2: The second list.\n list3: The third list.\n\n Returns:\n A new list containing the interleaved elements.\n Raises ValueError if lists are not of the same length.\n \"\"\"\n\n if not (len(list1) == len(list2) == len(list3)):\n raise ValueError(\"Lists must be of the same length.\")\n\n interleaved_list = []\n for i in range(len(list1)):\n interleaved_list.extend([list1[i], list2[i], list3[i]])\n return interleaved_list", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"\n Interleaves three lists of the same length into a single flat list.\n\n Args:\n list1: The first list.\n list2: The second list.\n list3: The third list.\n\n Returns:\n A new list containing the interleaved elements of the input lists.\n Raises ValueError if lists are not of the same length.\n \"\"\"\n\n if not (len(list1) == len(list2) == len(list3)):\n raise ValueError(\"Lists must have the same length\")\n \n interleaved_list = []\n for i in range(len(list1)):\n interleaved_list.extend([list1[i], list2[i], list3[i]])\n return interleaved_list", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"\n Interleaves three lists of the same length into a single flat list.\n\n Args:\n list1: The first list.\n list2: The second list.\n list3: The third list.\n\n Returns:\n A new list containing the interleaved elements.\n \"\"\"\n\n if not (len(list1) == len(list2) == len(list3)):\n raise ValueError(\"Lists must have the same length\")\n\n interleaved_list = []\n for i in range(len(list1)):\n interleaved_list.append(list1[i])\n interleaved_list.append(list2[i])\n interleaved_list.append(list3[i])\n return interleaved_list", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"\n Interleaves three lists of the same length into a single flat list.\n\n Args:\n list1: The first list.\n list2: The second list.\n list3: The third list.\n\n Returns:\n A new list containing the interleaved elements.\n Raises ValueError if lists are not of the same length.\n \"\"\"\n\n if not (len(list1) == len(list2) == len(list3)):\n raise ValueError(\"Lists must have the same length\")\n\n interleaved_list = []\n for i in range(len(list1)):\n interleaved_list.extend([list1[i], list2[i], list3[i]])\n return interleaved_list", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"Interleaves three lists of the same length into a single flat list.\n\n Args:\n list1: The first list.\n list2: The second list.\n list3: The third list.\n\n Returns:\n A new list containing the interleaved elements of the input lists.\n Raises ValueError if the input lists are not of the same length.\n \"\"\"\n\n if not (len(list1) == len(list2) == len(list3)):\n raise ValueError(\"Lists must have the same length\")\n \n interleaved_list = []\n for i in range(len(list1)):\n interleaved_list.append(list1[i])\n interleaved_list.append(list2[i])\n interleaved_list.append(list3[i])\n return interleaved_list", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"\n Interleaves three lists of the same length into a single flat list.\n\n Args:\n list1: The first list.\n list2: The second list.\n list3: The third list.\n\n Returns:\n A new list containing the interleaved elements.\n Raises ValueError if lists are not of the same length.\n \"\"\"\n\n if not (len(list1) == len(list2) == len(list3)):\n raise ValueError(\"Lists must have the same length\")\n\n interleaved_list = []\n for i in range(len(list1)):\n interleaved_list.extend([list1[i], list2[i], list3[i]])\n return interleaved_list", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"\n Interleaves three lists of the same length into a single flat list.\n\n Args:\n list1: The first list.\n list2: The second list.\n list3: The third list.\n\n Returns:\n A new list containing the interleaved elements.\n Returns an empty list if the input lists are not of the same length.\n \"\"\"\n if not (len(list1) == len(list2) == len(list3)):\n return []\n \n interleaved_list = []\n for i in range(len(list1)):\n interleaved_list.extend([list1[i], list2[i], list3[i]])\n return interleaved_list", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef interleave_lists(list1: List, list2: List, list3: List) -> List:\n \"\"\"\n Interleaves three lists of the same length into a single flat list.\n\n Args:\n list1: The first list.\n list2: The second list.\n list3: The third list.\n\n Returns:\n A new list containing the interleaved elements.\n \"\"\"\n\n if not (len(list1) == len(list2) == len(list3)):\n raise ValueError(\"Lists must have the same length.\")\n \n interleaved_list = []\n for i in range(len(list1)):\n interleaved_list.extend([list1[i], list2[i], list3[i]])\n\n return interleaved_list", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"Interleaves three lists of the same length into a single flat list.\"\"\"\n if len(list1) != len(list2) or len(list1) != len(list3):\n raise ValueError(\"Lists must be of the same length\")\n\n interleaved_list = []\n for i in range(len(list1)):\n interleaved_list.append(list1[i])\n interleaved_list.append(list2[i])\n interleaved_list.append(list3[i])\n return interleaved_list", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"Interleaves three lists of the same length into a single flat list.\n\n Args:\n list1: The first list.\n list2: The second list.\n list3: The third list.\n\n Returns:\n A new list containing the interleaved elements.\n \"\"\"\n\n if not (len(list1) == len(list2) == len(list3)):\n raise ValueError(\"Lists must have the same length.\")\n\n interleaved_list = []\n for i in range(len(list1)):\n interleaved_list.extend([list1[i], list2[i], list3[i]])\n return interleaved_list", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"\n Interleaves three lists of the same length into a single flat list.\n\n Args:\n list1: The first list.\n list2: The second list.\n list3: The third list.\n\n Returns:\n A new list containing the interleaved elements.\n Raises ValueError if the lists are not of the same length.\n \"\"\"\n\n if not (len(list1) == len(list2) == len(list3)):\n raise ValueError(\"Lists must have the same length\")\n\n interleaved_list = []\n for i in range(len(list1)):\n interleaved_list.extend([list1[i], list2[i], list3[i]])\n return interleaved_list", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"\n Interleaves three lists of the same length into a single flat list.\n\n Args:\n list1: The first list.\n list2: The second list.\n list3: The third list.\n\n Returns:\n A new list containing the interleaved elements.\n Raises ValueError if the lists are not of the same length.\n \"\"\"\n\n if not (len(list1) == len(list2) == len(list3)):\n raise ValueError(\"Lists must have the same length\")\n\n interleaved_list = []\n for i in range(len(list1)):\n interleaved_list.extend([list1[i], list2[i], list3[i]])\n return interleaved_list", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"\n Interleaves three lists of the same length into a single flat list.\n\n Args:\n list1: The first list.\n list2: The second list.\n list3: The third list.\n\n Returns:\n A new list containing the interleaved elements.\n Raises ValueError if lists are not of the same length.\n \"\"\"\n if not (len(list1) == len(list2) == len(list3)):\n raise ValueError(\"Lists must be of the same length\")\n \n interleaved_list = []\n for i in range(len(list1)):\n interleaved_list.extend([list1[i], list2[i], list3[i]])\n return interleaved_list", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"\n Interleaves three lists of the same length into a single flat list.\n\n Args:\n list1: The first list.\n list2: The second list.\n list3: The third list.\n\n Returns:\n A new list containing the interleaved elements.\n Raises ValueError if lists are not of the same length.\n \"\"\"\n\n if not (len(list1) == len(list2) == len(list3)):\n raise ValueError(\"Lists must have the same length\")\n\n interleaved_list = []\n for i in range(len(list1)):\n interleaved_list.extend([list1[i], list2[i], list3[i]])\n return interleaved_list", "matching_cluster_idx": 6}]}, "Mbpp/586": {"dps": 98.83040935672514, "dps_norm": 87.5, "pass@1": 84.0, "profiled": [{"solution": "def split_Arr(arr, n):\n \"\"\"\n Splits a list at the nth element and adds the first part to the end.\n\n Args:\n arr: The list to split.\n n: The index at which to split the list.\n\n Returns:\n The modified list.\n Returns the original list if n is out of bounds.\n \"\"\"\n if n < 0 or n >= len(arr):\n return arr # Handle out-of-bounds index\n\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"\n Splits a list at the nth element and appends the first part to the end.\n\n Args:\n arr: The list to be split.\n n: The index at which to split the list.\n\n Returns:\n The modified list, or the original list if n is out of bounds.\n \"\"\"\n if n < 0 or n >= len(arr):\n return arr\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"\n Splits a list at the nth element and adds the first part to the end.\n\n Args:\n arr: The list to split.\n n: The index at which to split the list.\n\n Returns:\n The modified list, or the original list if n is invalid.\n \"\"\"\n if n < 0 or n >= len(arr):\n return arr # Handle invalid 'n' values\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"Splits a list at the nth element and adds the first part to the end.\n\n Args:\n arr: The list to split.\n n: The index at which to split the list.\n\n Returns:\n The rearranged list.\n Returns the original list if n is out of bounds (negative or greater than or equal to the length of the list).\n \"\"\"\n if n < 0 or n >= len(arr):\n return arr\n return arr[n:] + arr[:n]\nn = 2", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"\n Splits a list at the nth element and adds the first part to the end.\n\n Args:\n arr: The list to split.\n n: The index at which to split the list.\n\n Returns:\n The modified list.\n Returns the original list if n is out of bounds.\n \"\"\"\n if n < 0 or n >= len(arr):\n return arr # Handle invalid 'n' values\n\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"Splits a list at the nth element and appends the first part to the end.\n\n Args:\n arr: The input list.\n n: The index at which to split the list.\n\n Returns:\n The modified list.\n Returns the original list if n is out of bounds (negative or greater than/equal to the length of the list).\n \"\"\"\n if n < 0 or n >= len(arr):\n return arr\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"\n Splits a list at the nth element and adds the first part to the end.\n\n Args:\n arr: The input list.\n n: The index at which to split the list.\n\n Returns:\n The modified list.\n Returns the original list if n is invalid (out of range or not an integer).\n \"\"\"\n if not isinstance(n, int) or n < 0 or n >= len(arr):\n return arr # Handle invalid input\n return arr[n:] + arr[:n]\nn = 2", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"\n Splits a list at the nth element and adds the first part to the end.\n\n Args:\n arr: The list to split.\n n: The index at which to split the list.\n\n Returns:\n The rearranged list, or the original list if n is out of bounds.\n \"\"\"\n if n < 0 or n >= len(arr):\n return arr # Handle out-of-bounds n\n\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"Splits a list at the nth element and adds the first part to the end.\n\n Args:\n arr: The list to split.\n n: The index at which to split the list.\n\n Returns:\n The modified list.\n \"\"\"\n if not isinstance(arr, list):\n raise TypeError(\"Input 'arr' must be a list.\")\n if not isinstance(n, int):\n raise TypeError(\"Input 'n' must be an integer.\")\n if n < 0 or n > len(arr):\n raise ValueError(\"Input 'n' must be within the range of the list's length.\")\n \n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"\n Splits a list at the nth element and adds the first part to the end.\n\n Args:\n arr: The list to split.\n n: The index at which to split the list.\n\n Returns:\n The modified list, or the original list if n is invalid.\n \"\"\"\n if not isinstance(arr, list) or not isinstance(n, int) or n < 0 or n >= len(arr):\n return arr # Handle invalid input gracefully\n\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"\n Splits a list at the nth element and adds the first part to the end.\n\n Args:\n arr: The list to split.\n n: The index at which to split the list.\n\n Returns:\n The modified list with the first part appended to the end.\n Returns the original list if n is out of bounds or if the list is empty.\n \"\"\"\n\n if not arr or n < 0 or n >= len(arr):\n return arr\n \n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"\n Splits a list at the nth element and adds the first part to the end.\n\n Args:\n arr: The list to split.\n n: The index to split at.\n\n Returns:\n The modified list. Returns the original list if n is invalid.\n \"\"\"\n if n < 0 or n >= len(arr):\n return arr\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"\n Splits a list at the nth element and appends the first part to the end.\n\n Args:\n arr: The input list.\n n: The index at which to split the list.\n\n Returns:\n The modified list. Returns the original list if n is out of bounds.\n \"\"\"\n if n < 0 or n >= len(arr):\n return arr\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"\n Splits a list at the nth element and adds the first part to the end.\n\n Args:\n arr: The list to split.\n n: The index at which to split the list.\n\n Returns:\n The modified list.\n \"\"\"\n if n < 0 or n >= len(arr):\n return arr # Handle invalid 'n' values\n\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"\n Splits a list at the nth element and adds the first part to the end.\n\n Args:\n arr: The list to split.\n n: The index to split at.\n\n Returns:\n The modified list.\n Returns the original list if n is out of bounds.\n \"\"\"\n if n < 0 or n >= len(arr):\n return arr # Handle out-of-bounds n\n\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"Splits a list at the nth element and adds the first part to the end.\n\n Args:\n arr: The list to split.\n n: The index at which to split the list.\n\n Returns:\n The modified list, or None if the input is invalid.\n \"\"\"\n if not isinstance(arr, list) or not isinstance(n, int) or n < 0 or n > len(arr):\n return None\n\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"\n Splits a list at the nth element and adds the first part to the end.\n\n Args:\n arr: The input list.\n n: The index at which to split the list.\n\n Returns:\n The modified list.\n Returns the original list if n is out of bounds or if the list is empty.\n \"\"\"\n\n if not arr or n < 0 or n >= len(arr):\n return arr\n \n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"\n Splits a list at the nth element and adds the first part to the end.\n\n Args:\n arr: The list to be split.\n n: The index at which to split the list.\n\n Returns:\n The modified list, or the original list if n is out of bounds.\n \"\"\"\n if n < 0 or n >= len(arr):\n return arr # Return original list if n is invalid\n\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"\n Splits a list at the nth element and appends the first part to the end.\n\n Args:\n arr: The list to be split.\n n: The index at which to split the list.\n\n Returns:\n The modified list.\n Returns the original list if n is out of bounds or not an integer.\n \"\"\"\n if not isinstance(n, int):\n return arr\n if n < 0 or n >= len(arr):\n return arr\n return arr[n:] + arr[:n]\nn = 2", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"\n Splits a list at the nth element and appends the first part to the end.\n\n Args:\n arr: The list to split.\n n: The index at which to split the list.\n\n Returns:\n The modified list.\n Returns the original list if n is out of bounds or if the list is empty.\n \"\"\"\n if not arr or n < 0 or n >= len(arr):\n return arr\n return arr[n:] + arr[:n]\nn = 2", "matching_cluster_idx": 6}]}, "Mbpp/587": {"dps": 29.72972972972973, "dps_norm": 80.0, "pass@1": 100.0, "profiled": [{"solution": "def list_tuple(list1):\n \"\"\"Converts a list to a tuple.\n\n Args:\n list1: The list to convert.\n\n Returns:\n A tuple containing the same elements as the input list.\n \"\"\"\n return tuple(list1)", "matching_cluster_idx": 2}, {"solution": "def list_tuple(list1):\n \"\"\"\n Converts a list to a tuple.\n\n Args:\n list1: The input list.\n\n Returns:\n A tuple containing the same elements as the input list.\n \"\"\"\n return tuple(list1)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(my_list):\n \"\"\"Converts a list to a tuple.\n\n Args:\n my_list: The list to convert.\n\n Returns:\n A tuple containing the same elements as the input list.\n \"\"\"\n return tuple(my_list)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(list1):\n \"\"\"Converts a list to a tuple.\n\n Args:\n list1: The list to convert.\n\n Returns:\n A tuple containing the same elements as the input list.\n \"\"\"\n return tuple(list1)", "matching_cluster_idx": 2}, {"solution": "def list_tuple(list1):\n \"\"\"Converts a list to a tuple.\n\n Args:\n list1: The list to convert.\n\n Returns:\n A tuple containing the same elements as the input list.\n \"\"\"\n return tuple(list1)", "matching_cluster_idx": 2}, {"solution": "def list_tuple(list1):\n \"\"\"Converts a list to a tuple.\n\n Args:\n list1: The list to convert.\n\n Returns:\n A tuple containing the same elements as the input list.\n \"\"\"\n return tuple(list1)", "matching_cluster_idx": 2}, {"solution": "def list_tuple(list1):\n \"\"\"\n Converts a list to a tuple.\n \"\"\"\n return tuple(list1)", "matching_cluster_idx": 2}, {"solution": "def list_tuple(list1):\n \"\"\"Converts a list to a tuple.\n\n Args:\n list1: The input list.\n\n Returns:\n A tuple containing the same elements as the input list.\n \"\"\"\n return tuple(list1)", "matching_cluster_idx": 2}, {"solution": "def list_tuple(my_list):\n \"\"\"Converts a list to a tuple.\n\n Args:\n my_list: The list to convert.\n\n Returns:\n A tuple containing the same elements as the input list.\n \"\"\"\n\n return tuple(my_list)", "matching_cluster_idx": 2}, {"solution": "def list_tuple(my_list):\n \"\"\"Converts a list to a tuple.\n\n Args:\n my_list: The list to convert.\n\n Returns:\n A tuple containing the same elements as the input list.\n \"\"\"\n return tuple(my_list)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(my_list):\n \"\"\"\n Converts a list to a tuple.\n\n Args:\n my_list: The list to convert.\n\n Returns:\n A tuple containing the same elements as the input list.\n \"\"\"\n return tuple(my_list)", "matching_cluster_idx": 2}, {"solution": "def list_tuple(list1):\n \"\"\"Converts a list to a tuple.\n\n Args:\n list1: The list to convert.\n\n Returns:\n A tuple containing the same elements as the input list.\n \"\"\"\n return tuple(list1)", "matching_cluster_idx": 2}, {"solution": "def list_tuple(list1):\n \"\"\"Converts a list to a tuple.\n\n Args:\n list1: The input list.\n\n Returns:\n A tuple containing the same elements as the input list.\n \"\"\"\n return tuple(list1)", "matching_cluster_idx": 2}, {"solution": "def list_tuple(list1):\n \"\"\"Converts a list to a tuple.\n\n Args:\n list1: The list to convert.\n\n Returns:\n A tuple containing the same elements as the input list.\n \"\"\"\n return tuple(list1)", "matching_cluster_idx": 2}, {"solution": "def list_tuple(my_list):\n \"\"\"\n Converts a list to a tuple.\n\n Args:\n my_list: The list to convert.\n\n Returns:\n A tuple containing the same elements as the input list.\n \"\"\"\n return tuple(my_list)", "matching_cluster_idx": 2}, {"solution": "def list_tuple(my_list):\n \"\"\"Converts a list to a tuple.\n\n Args:\n my_list: The list to convert.\n\n Returns:\n A tuple containing the same elements as the input list.\n \"\"\"\n return tuple(my_list)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(list1):\n \"\"\"Converts a list to a tuple.\n\n Args:\n list1: The input list.\n\n Returns:\n A tuple containing the same elements as the input list.\n \"\"\"\n\n return tuple(list1)", "matching_cluster_idx": 2}, {"solution": "def list_tuple(list1):\n \"\"\"Converts a list to a tuple.\n\n Args:\n list1: The input list.\n\n Returns:\n A tuple containing the same elements as the input list.\n \"\"\"\n\n return tuple(list1)", "matching_cluster_idx": 2}, {"solution": "def list_tuple(my_list):\n \"\"\"\n Converts a list to a tuple.\n\n Args:\n my_list: The list to convert.\n\n Returns:\n A tuple containing the same elements as the input list.\n \"\"\"\n return tuple(my_list)", "matching_cluster_idx": 2}, {"solution": "def list_tuple(list1):\n \"\"\"\n Converts a list to a tuple.\n\n Args:\n list1: The list to convert.\n\n Returns:\n A tuple containing the same elements as the input list.\n \"\"\"\n return tuple(list1)", "matching_cluster_idx": 2}]}, "Mbpp/588": {"dps": 97.13302752293578, "dps_norm": 99.16666666666667, "pass@1": 100.0, "profiled": [{"solution": "def big_diff(nums):\n \"\"\"\n Finds the difference between the largest and smallest values in a given list.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n The difference between the largest and smallest values in the list.\n Returns 0 if the list is empty.\n \"\"\"\n if not nums:\n return 0\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n \"\"\"\n Finds the difference between the largest and smallest values in a list.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n The difference between the largest and smallest values in the list.\n Returns 0 if the list is empty.\n \"\"\"\n if not nums:\n return 0\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n \"\"\"\n Finds the difference between the largest and smallest values in a list.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n The difference between the largest and smallest values in the list.\n Returns 0 if the list is empty.\n \"\"\"\n if not nums:\n return 0\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n \"\"\"\n Finds the difference between the largest and smallest values in a given list.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n The difference between the largest and smallest values in the list.\n Returns 0 if the list is empty.\n \"\"\"\n if not nums:\n return 0\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n \"\"\"\n Finds the difference between the largest and smallest values in a list.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n The difference between the largest and smallest values in the list.\n Returns 0 if the list is empty.\n \"\"\"\n if not nums:\n return 0\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n \"\"\"\n Finds the difference between the largest and smallest values in a list.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n The difference between the largest and smallest values in the list.\n Returns 0 if the list is empty.\n \"\"\"\n if not nums:\n return 0\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n \"\"\"\n Finds the difference between the largest and smallest values in a list.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n The difference between the largest and smallest values in the list.\n Returns 0 if the list is empty.\n \"\"\"\n if not nums:\n return 0\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n \"\"\"\n Finds the difference between the largest and smallest values in a list.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n The difference between the largest and smallest values in the list.\n Returns 0 if the list is empty.\n \"\"\"\n\n if not nums:\n return 0\n\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n \"\"\"\n Finds the difference between the largest and smallest values in a list.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n The difference between the largest and smallest values in the list.\n Returns 0 if the list is empty.\n \"\"\"\n if not nums:\n return 0\n\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n \"\"\"\n Finds the difference between the largest and smallest values in a given list.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n The difference between the largest and smallest values in the list.\n \"\"\"\n\n if not nums:\n return 0 # Handle empty list case\n\n min_val = nums[0]\n max_val = nums[0]\n\n for num in nums:\n if num < min_val:\n min_val = num\n if num > max_val:\n max_val = num\n\n return max_val - min_val", "matching_cluster_idx": 4}, {"solution": "def big_diff(nums):\n \"\"\"\n Finds the difference between the largest and smallest values in a list.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n The difference between the largest and smallest values in the list.\n Returns 0 if the list is empty.\n \"\"\"\n if not nums:\n return 0\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n \"\"\"\n Finds the difference between the largest and smallest values in a list.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n The difference between the largest and smallest values in the list.\n Returns 0 if the list is empty.\n \"\"\"\n if not nums:\n return 0\n\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n \"\"\"\n Finds the difference between the largest and smallest values in a list.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n The difference between the largest and smallest values in the list.\n Returns 0 if the list is empty.\n \"\"\"\n\n if not nums:\n return 0\n\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n \"\"\"\n Finds the difference between the largest and smallest values in a list.\n\n Args:\n nums: A list of integers.\n\n Returns:\n The difference between the largest and smallest values in the list.\n Returns 0 if the list is empty.\n \"\"\"\n if not nums:\n return 0 # Handle empty list case\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n \"\"\"\n Finds the difference between the largest and smallest values in a list.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n The difference between the largest and smallest values in the list.\n Returns 0 if the list is empty.\n \"\"\"\n\n if not nums:\n return 0\n\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n \"\"\"\n Finds the difference between the largest and smallest values in a list.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n The difference between the largest and smallest values in the list.\n Returns 0 if the list is empty.\n \"\"\"\n if not nums:\n return 0\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n \"\"\"\n Finds the difference between the largest and smallest values in a list.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n The difference between the largest and smallest values in the list.\n Returns 0 if the list is empty.\n \"\"\"\n if not nums: # Handle empty list case\n return 0\n \n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n \"\"\"\n Finds the difference between the largest and smallest values in a list.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n The difference between the largest and smallest values in the list.\n Returns 0 if the list is empty.\n \"\"\"\n if not nums:\n return 0\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n \"\"\"\n Finds the difference between the largest and smallest values in a list.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n The difference between the largest and smallest values in the list.\n Returns 0 if the list is empty.\n \"\"\"\n if not nums:\n return 0\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n \"\"\"\n Finds the difference between the largest and smallest values in a list.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n The difference between the largest and smallest values in the list.\n Returns 0 if the list is empty or contains only one element.\n \"\"\"\n if not nums or len(nums) == 1: # Handle empty or single-element lists\n return 0\n \n return max(nums) - min(nums)", "matching_cluster_idx": 5}]}, "Mbpp/592": {"dps": 37.93333333333334, "dps_norm": 40.0, "pass@1": 97.0, "profiled": [{"solution": "import math\ndef sum_Of_product(n):\n \"\"\"\n Calculates the sum of the product of consecutive binomial coefficients for a given n.\n\n Args:\n n: An integer representing the upper limit of the binomial coefficient.\n\n Returns:\n The sum of the products of consecutive binomial coefficients.\n \"\"\"\n\n total_sum = 0\n for r in range(n + 1):\n if r < n: # Avoid index out of bounds when accessing nCr+1\n nCr = math.comb(n, r)\n nC_r_plus_1 = math.comb(n, r + 1)\n total_sum += nCr * nC_r_plus_1\n return total_sum", "matching_cluster_idx": 5}, {"solution": "from math import comb\ndef sum_Of_product(n):\n \"\"\"\n Calculates the sum of the product of consecutive binomial coefficients for a given n.\n\n Args:\n n: An integer representing the upper limit of the binomial coefficient.\n\n Returns:\n The sum of the product of consecutive binomial coefficients.\n \"\"\"\n if not isinstance(n, int) or n < 0:\n raise ValueError(\"Input n must be a non-negative integer.\")\n \n total_sum = 0\n for i in range(n + 1):\n if i < n:\n total_sum += comb(n, i) * comb(n, i + 1)\n return total_sum", "matching_cluster_idx": 5}, {"solution": "import math\ndef nCr(n, r):\n \"\"\"Calculates the binomial coefficient (n choose r).\"\"\"\n f = math.factorial\n return f(n) // f(r) // f(n-r)\ndef sum_Of_product(n):\n \"\"\"\n Calculates the sum of the product of consecutive binomial coefficients for a given n.\n \"\"\"\n sum_prod = 0\n for r in range(n):\n sum_prod += nCr(n, r) * nCr(n, r+1)\n return sum_prod", "matching_cluster_idx": 1}, {"solution": "import math\ndef nCr(n, r):\n \"\"\"Calculates the binomial coefficient (n choose r).\"\"\"\n f = math.factorial\n return f(n) // f(r) // f(n - r)\ndef sum_Of_product(n):\n \"\"\"Calculates the sum of the product of consecutive binomial coefficients.\"\"\"\n sum_prod = 0\n for r in range(n):\n sum_prod += nCr(n, r) * nCr(n, r + 1)\n return sum_prod\nn = 5", "matching_cluster_idx": 1}, {"solution": "import math\ndef nCr(n, r):\n \"\"\"Calculates the binomial coefficient (n choose r).\"\"\"\n f = math.factorial\n return f(n) // f(r) // f(n-r)\ndef sum_Of_product(n):\n \"\"\"Calculates the sum of the product of consecutive binomial coefficients.\"\"\"\n sum_prod = 0\n for r in range(n):\n sum_prod += nCr(n, r) * nCr(n, r + 1)\n return sum_prod\nn = 6", "matching_cluster_idx": 1}, {"solution": "import math\ndef nCr(n, r):\n \"\"\"Calculates nCr (n choose r) using the formula n! / (r! * (n-r)!)\"\"\"\n if r < 0 or r > n:\n return 0\n return math.factorial(n) // (math.factorial(r) * math.factorial(n - r))\ndef sum_Of_product(n):\n \"\"\"\n Calculates the sum of the product of consecutive binomial coefficients for a given n.\n \"\"\"\n sum_prod = 0\n for r in range(n + 1):\n sum_prod += nCr(n, r) * nCr(n, r + 1)\n return sum_prod", "matching_cluster_idx": 1}, {"solution": "import math\ndef nCr(n, r):\n \"\"\"Calculate nCr (n choose r) using math.comb.\"\"\"\n return math.comb(n, r)\ndef sum_Of_product(n):\n \"\"\"Calculate the sum of the product of consecutive binomial coefficients.\"\"\"\n sum_prod = 0\n for r in range(n):\n sum_prod += nCr(n,r) * nCr(n, r+1)\n return sum_prod", "matching_cluster_idx": 5}, {"solution": "import math\ndef binomial_coefficient(n, k):\n \"\"\"Calculates the binomial coefficient (n choose k).\"\"\"\n if k < 0 or k > n:\n return 0\n return math.comb(n, k)\ndef sum_Of_product(n):\n \"\"\"Calculates the sum of the product of consecutive binomial coefficients.\"\"\"\n total_sum = 0\n for k in range(n):\n total_sum += binomial_coefficient(n, k) * binomial_coefficient(n, k + 1)\n return total_sum\nn = 5", "matching_cluster_idx": 4}, {"solution": "import math\ndef nCr(n, r):\n \"\"\"Calculates the binomial coefficient (n choose r).\"\"\"\n f = math.factorial\n return f(n) // f(r) // f(n-r)\ndef sum_Of_product(n):\n \"\"\"\n Calculates the sum of the product of consecutive binomial coefficients.\n \"\"\"\n sum_prod = 0\n for r in range(n):\n sum_prod += nCr(n, r) * nCr(n, r + 1)\n return sum_prod", "matching_cluster_idx": 1}, {"solution": "import math\ndef binomial_coefficient(n, k):\n \"\"\"Calculates the binomial coefficient (n choose k).\"\"\"\n if k < 0 or k > n:\n return 0\n return math.comb(n, k) # Use math.comb for efficiency and accuracy\ndef sum_Of_product(n):\n \"\"\"\n Calculates the sum of the product of consecutive binomial coefficients.\n Specifically, it computes:\n \u03a3(k=0 to n-1) (nCk * nC(k+1)) \n \"\"\"\n total_sum = 0\n for k in range(n):\n total_sum += binomial_coefficient(n, k) * binomial_coefficient(n, k + 1)\n return total_sum\nn = 5", "matching_cluster_idx": 4}, {"solution": "import math\ndef nCr(n, r):\n f = math.factorial\n return f(n) // f(r) // f(n-r)\ndef sum_Of_product(n):\n \"\"\"\n Calculates the sum of the product of consecutive binomial coefficients for a given n.\n\n Args:\n n: An integer representing the upper limit of the binomial coefficient.\n\n Returns:\n The sum of the product of consecutive binomial coefficients.\n \"\"\"\n\n total_sum = 0\n for r in range(n):\n total_sum += nCr(n, r) * nCr(n, r + 1)\n return total_sum\nn = 3", "matching_cluster_idx": 1}, {"solution": "import math\ndef nCr(n, r):\n \"\"\"Calculates the binomial coefficient (n choose r).\"\"\"\n if 0 <= r <= n:\n return math.comb(n, r) # Efficiently computes binomial coefficient\n else:\n return 0 # Handles cases where r is out of bounds\ndef sum_Of_product(n):\n \"\"\"\n Calculates the sum of the product of consecutive binomial coefficients for a given n.\n \"\"\"\n total_sum = 0\n for r in range(n + 1):\n total_sum += nCr(n, r) * nCr(n, r + 1)\n return total_sum\nn = 5", "matching_cluster_idx": 4}, {"solution": "from math import comb\ndef sum_Of_product(n):\n \"\"\"\n Calculates the sum of the product of consecutive binomial coefficients for a given n.\n\n Args:\n n: An integer representing the upper limit of the binomial coefficient.\n\n Returns:\n The sum of the products of consecutive binomial coefficients.\n \"\"\"\n\n if not isinstance(n, int) or n < 0:\n raise ValueError(\"Input n must be a non-negative integer.\")\n\n total_sum = 0\n for i in range(n):\n total_sum += comb(n, i) * comb(n, i + 1)\n return total_sum", "matching_cluster_idx": 5}, {"solution": "import math\ndef binomialCoeff(n, k):\n \"\"\"Calculates the binomial coefficient (nCk).\"\"\"\n res = 1\n if k > n - k:\n k = n - k\n for i in range(k):\n res = res * (n - i)\n res = res // (i + 1)\n return res\ndef sum_Of_product(n):\n \"\"\"Calculates the sum of products of consecutive binomial coefficients.\"\"\"\n sum_prod = 0\n for i in range(n + 1):\n sum_prod += binomialCoeff(n, i) * binomialCoeff(n, i + 1) if i+1 <= n else 0\n return sum_prod", "matching_cluster_idx": 4}, {"solution": "from math import comb\ndef sum_Of_product(n):\n \"\"\"\n Calculates the sum of the product of consecutive binomial coefficients for a given n.\n\n Args:\n n: An integer representing the upper limit for the binomial coefficients.\n\n Returns:\n The sum of the product of consecutive binomial coefficients.\n \"\"\"\n total_sum = 0\n for k in range(n + 1):\n if k < n:\n total_sum += comb(n, k) * comb(n, k + 1)\n return total_sum", "matching_cluster_idx": 5}, {"solution": "import math\ndef binomial_coefficient(n, k):\n \"\"\"Calculates the binomial coefficient (nCk).\"\"\"\n if k < 0 or k > n:\n return 0\n return math.comb(n, k) # Using math.comb for efficiency\ndef sum_Of_product(n):\n \"\"\"Calculates the sum of the product of consecutive binomial coefficients.\"\"\"\n total_sum = 0\n for k in range(n + 1):\n total_sum += binomial_coefficient(n, k) * binomial_coefficient(n, k + 1)\n return total_sum", "matching_cluster_idx": 4}, {"solution": "import math\ndef nCr(n, r):\n \"\"\"Calculates the binomial coefficient (n choose r).\"\"\"\n f = math.factorial\n return f(n) // f(r) // f(n-r)\ndef sum_Of_product(n):\n \"\"\"\n Calculates the sum of the product of consecutive binomial coefficients for a given n.\n \"\"\"\n total_sum = 0\n for r in range(n):\n total_sum += nCr(n, r) * nCr(n, r + 1)\n return total_sum", "matching_cluster_idx": 1}, {"solution": "import math\ndef sum_Of_product(n):\n \"\"\"\n Calculates the sum of the product of consecutive binomial coefficients for a given n.\n\n Args:\n n: An integer representing the upper limit of the binomial coefficient.\n\n Returns:\n The sum of the products of consecutive binomial coefficients.\n \"\"\"\n\n total_sum = 0\n for k in range(n + 1):\n if k < n:\n term1 = math.comb(n, k)\n term2 = math.comb(n, k + 1)\n total_sum += term1 * term2\n return total_sum", "matching_cluster_idx": 5}, {"solution": "import math\ndef nCr(n, r):\n return math.factorial(n) // (math.factorial(r) * math.factorial(n - r))\ndef sum_Of_product(n):\n \"\"\"\n Calculates the sum of the product of consecutive binomial coefficients for a given n.\n\n Args:\n n: An integer representing the upper limit of the binomial coefficient.\n\n Returns:\n The sum of the products of consecutive binomial coefficients.\n \"\"\"\n\n if not isinstance(n, int) or n < 0:\n raise ValueError(\"n must be a non-negative integer\")\n\n\n total_sum = 0\n for r in range(0, n):\n total_sum += nCr(n, r) * nCr(n, r + 1)\n return total_sum\nn = 5", "matching_cluster_idx": 2}, {"solution": "import math\ndef nCr(n, r):\n \"\"\"Calculates the binomial coefficient \"n choose r\".\"\"\"\n if r > n:\n return 0\n f = math.factorial\n return f(n) // f(r) // f(n-r)\ndef sum_Of_product(n):\n \"\"\"Calculates the sum of the product of consecutive binomial coefficients.\"\"\"\n sum_prod = 0\n for r in range(n + 1):\n sum_prod += nCr(n, r) * nCr(n, r + 1)\n return sum_prod\nn = 3", "matching_cluster_idx": 1}]}, "Mbpp/597": {"dps": null, "dps_norm": null, "pass@1": 5.0, "profiled": []}, "Mbpp/604": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 90.0, "profiled": [{"solution": "def reverse_words(s):\n \"\"\"Reverses the order of words in a string.\n\n Args:\n s: The input string.\n\n Returns:\n The string with words reversed.\n \"\"\"\n words = s.split()\n reversed_words = words[::-1]\n return \" \".join(reversed_words)", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n \"\"\"Reverses the order of words in a string.\"\"\"\n words = s.split()\n reversed_words = words[::-1]\n return \" \".join(reversed_words)", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n \"\"\"Reverses the order of words in a string.\n\n Args:\n s: The input string.\n\n Returns:\n The string with words reversed.\n Returns an empty string if the input is an empty string or contains only spaces.\n \"\"\"\n words = s.split()\n if not words: # Handle empty string or string with only spaces\n return \"\"\n return \" \".join(reversed(words))", "matching_cluster_idx": 4}, {"solution": "def reverse_words(input_string):\n \"\"\"\n Reverses the order of words in a string.\n\n Args:\n input_string: The string containing words separated by spaces.\n\n Returns:\n A string with the words reversed. Returns an empty string if the input is empty or contains only whitespace.\n \"\"\"\n words = input_string.split()\n if not words: # Handle empty or whitespace-only input\n return \"\"\n reversed_words = words[::-1]\n return \" \".join(reversed_words)", "matching_cluster_idx": 4}, {"solution": "def reverse_words(input_string):\n \"\"\"\n Reverses the order of words in a string.\n\n Args:\n input_string: The string containing words separated by spaces.\n\n Returns:\n A string with the words reversed.\n Returns an empty string if the input is empty or contains only spaces.\n \"\"\"\n words = input_string.split()\n if not words: # Handle empty or space-only input\n return \"\"\n reversed_words = words[::-1]\n return \" \".join(reversed_words)", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n \"\"\"Reverses the order of words in a string separated by spaces.\n\n Args:\n s: The input string.\n\n Returns:\n The string with words reversed.\n Returns an empty string if the input is an empty string or only contains whitespace.\n \"\"\"\n words = s.split()\n if not words: # Handle empty string or string with only whitespace\n return \"\"\n return \" \".join(reversed(words))", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n \"\"\"\n Reverses the order of words in a string.\n\n Args:\n s: The input string.\n\n Returns:\n The string with words reversed.\n \"\"\"\n words = s.split()\n return \" \".join(reversed(words))", "matching_cluster_idx": 4}, {"solution": "def reverse_words(input_string):\n \"\"\"Reverses the order of words in a string.\n\n Args:\n input_string: The string to reverse.\n\n Returns:\n The string with words reversed.\n Returns an empty string if the input is empty or consists only of whitespace.\n \"\"\"\n\n words = input_string.split()\n if not words: # Handle empty or whitespace-only input\n return \"\"\n \n reversed_words = words[::-1] # Reverse the list of words\n return \" \".join(reversed_words)", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n \"\"\"Reverses the order of words in a string separated by spaces.\n\n Args:\n s: The input string.\n\n Returns:\n The string with the words reversed.\n Returns an empty string if the input is None or an empty string.\n \"\"\"\n if not s: # Handles None and empty strings\n return \"\"\n words = s.split()\n reversed_words = words[::-1]\n return \" \".join(reversed_words)", "matching_cluster_idx": 4}, {"solution": "def reverse_words(input_string):\n \"\"\"Reverses the order of words in a string separated by spaces.\n\n Args:\n input_string: The string containing words separated by spaces.\n\n Returns:\n A string with the words reversed. Returns an empty string if the input is empty or contains only whitespace.\n \"\"\"\n\n words = input_string.split()\n if not words: # Handle empty or whitespace-only input\n return \"\"\n return \" \".join(reversed(words))", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n \"\"\"Reverses the order of words in a string separated by spaces.\n\n Args:\n s: The input string.\n\n Returns:\n The string with the words reversed.\n \"\"\"\n words = s.split()\n reversed_words = words[::-1] # Efficiently reverses the list\n return \" \".join(reversed_words)", "matching_cluster_idx": 4}, {"solution": "def reverse_words(input_string):\n \"\"\"\n Reverses the order of words in a string.\n\n Args:\n input_string: The string containing words separated by spaces.\n\n Returns:\n A string with the words reversed.\n \"\"\"\n words = input_string.split()\n reversed_words = words[::-1]\n return \" \".join(reversed_words)", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n \"\"\"Reverses words separated by spaces in a given string.\n\n Args:\n s: The input string.\n\n Returns:\n The string with words reversed.\n \"\"\"\n words = s.split()\n reversed_words = words[::-1] # Efficient way to reverse a list\n return \" \".join(reversed_words)", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n \"\"\"Reverses the order of words in a string.\n\n Args:\n s: The input string.\n\n Returns:\n The string with words reversed.\n \"\"\"\n words = s.split()\n return \" \".join(reversed(words))", "matching_cluster_idx": 4}, {"solution": "def reverse_words(text):\n \"\"\"Reverses the order of words in a space-separated string.\n\n Args:\n text: The input string.\n\n Returns:\n The string with words reversed.\n \"\"\"\n words = text.split()\n reversed_words = words[::-1] # Reverse the list of words\n return \" \".join(reversed_words)", "matching_cluster_idx": 4}, {"solution": "def reverse_words(text):\n \"\"\"\n Reverses the order of words in a string.\n\n Args:\n text: The input string.\n\n Returns:\n The string with words reversed.\n \"\"\"\n words = text.split()\n reversed_words = words[::-1]\n return \" \".join(reversed_words)", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n \"\"\"Reverses the order of words in a string.\n\n Args:\n s: The input string.\n\n Returns:\n The string with words reversed.\n \"\"\"\n words = s.split()\n reversed_words = words[::-1] # Efficiently reverses the list\n return \" \".join(reversed_words)", "matching_cluster_idx": 4}, {"solution": "def reverse_words(input_string):\n \"\"\"Reverses the order of words in a string.\n\n Args:\n input_string: The string to reverse.\n\n Returns:\n The reversed string.\n \"\"\"\n words = input_string.split()\n reversed_words = words[::-1] # Efficient way to reverse a list\n return \" \".join(reversed_words)", "matching_cluster_idx": 4}, {"solution": "def reverse_words(input_string):\n \"\"\"\n Reverses the order of words in a string.\n\n Args:\n input_string: The string containing words separated by spaces.\n\n Returns:\n The string with words reversed. Returns an empty string if the input is empty or contains only spaces.\n \"\"\"\n words = input_string.split()\n if not words: # Handle empty or space-only strings\n return \"\"\n reversed_words = words[::-1]\n return \" \".join(reversed_words)", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n \"\"\"Reverses the order of words in a string.\n\n Args:\n s: The input string.\n\n Returns:\n The string with words reversed.\n Returns an empty string if the input is an empty string or contains only spaces.\n\n \"\"\"\n words = s.split()\n if not words: # Handle empty string or string with only spaces\n return \"\"\n return \" \".join(words[::-1])", "matching_cluster_idx": 4}]}, "Mbpp/610": {"dps": null, "dps_norm": null, "pass@1": 5.0, "profiled": []}, "Mbpp/611": {"dps": null, "dps_norm": null, "pass@1": 9.0, "profiled": []}, "Mbpp/631": {"dps": 31.597222222222218, "dps_norm": 33.75, "pass@1": 100.0, "profiled": [{"solution": "def replace_spaces(input_string):\n \"\"\"Replaces spaces with underscores and vice versa in a string.\"\"\"\n output_string = \"\"\n for char in input_string:\n if char == \" \":\n output_string += \"_\"\n elif char == \"_\":\n output_string += \" \"\n else:\n output_string += char\n return output_string", "matching_cluster_idx": 1}, {"solution": "def replace_spaces(input_string):\n \"\"\"Replaces spaces with underscores and underscores with spaces in a string.\"\"\"\n\n output_string = \"\"\n for char in input_string:\n if char == \" \":\n output_string += \"_\"\n elif char == \"_\":\n output_string += \" \"\n else:\n output_string += char\n return output_string", "matching_cluster_idx": 2}, {"solution": "def replace_spaces(input_string):\n \"\"\"Replaces spaces with underscores and vice-versa in a string.\"\"\"\n\n result = []\n for char in input_string:\n if char == ' ':\n result.append('_')\n elif char == '_':\n result.append(' ')\n else:\n result.append(char)\n return \"\".join(result)", "matching_cluster_idx": 3}, {"solution": "def replace_spaces(input_string):\n \"\"\"Replaces spaces with underscores and underscores with spaces in a string.\"\"\"\n result = ''\n for char in input_string:\n if char == ' ':\n result += '_'\n elif char == '_':\n result += ' '\n else:\n result += char\n return result", "matching_cluster_idx": 1}, {"solution": "def replace_spaces(input_string):\n \"\"\"Replaces whitespaces with underscores and vice versa in a string.\n\n Args:\n input_string: The input string.\n\n Returns:\n The modified string.\n \"\"\"\n result = \"\"\n for char in input_string:\n if char == \" \":\n result += \"_\"\n elif char == \"_\":\n result += \" \"\n else:\n result += char\n return result", "matching_cluster_idx": 1}, {"solution": "def replace_spaces(input_string):\n \"\"\"Replaces whitespaces with underscores and vice versa in a string.\"\"\"\n\n output_string = \"\"\n for char in input_string:\n if char == \" \":\n output_string += \"_\"\n elif char == \"_\":\n output_string += \" \"\n else:\n output_string += char\n return output_string", "matching_cluster_idx": 2}, {"solution": "def replace_spaces(input_string):\n \"\"\"Replaces spaces with underscores and vice versa in a string.\n\n Args:\n input_string: The input string.\n\n Returns:\n The modified string with spaces and underscores swapped.\n \"\"\"\n output_string = \"\"\n for char in input_string:\n if char == \" \":\n output_string += \"_\"\n elif char == \"_\":\n output_string += \" \"\n else:\n output_string += char\n return output_string", "matching_cluster_idx": 2}, {"solution": "def replace_spaces(input_string):\n \"\"\"Replaces spaces with underscores and vice versa in a string.\n\n Args:\n input_string: The string to modify.\n\n Returns:\n The modified string.\n \"\"\"\n modified_string = \"\"\n for char in input_string:\n if char == \" \":\n modified_string += \"_\"\n elif char == \"_\":\n modified_string += \" \"\n else:\n modified_string += char\n return modified_string", "matching_cluster_idx": 2}, {"solution": "def replace_spaces(input_string):\n \"\"\"Replaces spaces with underscores and vice-versa in a string.\"\"\"\n\n output_string = \"\"\n for char in input_string:\n if char == \" \":\n output_string += \"_\"\n elif char == \"_\":\n output_string += \" \"\n else:\n output_string += char\n return output_string", "matching_cluster_idx": 1}, {"solution": "def replace_spaces(input_string):\n \"\"\"Replaces spaces with underscores and underscores with spaces in a string.\n\n Args:\n input_string: The string to modify.\n\n Returns:\n The modified string.\n \"\"\"\n result = \"\"\n for char in input_string:\n if char == \" \":\n result += \"_\"\n elif char == \"_\":\n result += \" \"\n else:\n result += char\n return result", "matching_cluster_idx": 1}, {"solution": "def replace_spaces(input_string):\n \"\"\"Replaces spaces with underscores and vice-versa in a string.\n\n Args:\n input_string: The string to modify.\n\n Returns:\n The modified string with spaces replaced by underscores and vice-versa.\n \"\"\"\n\n modified_string = \"\"\n for char in input_string:\n if char == \" \":\n modified_string += \"_\"\n elif char == \"_\":\n modified_string += \" \"\n else:\n modified_string += char\n return modified_string", "matching_cluster_idx": 2}, {"solution": "def replace_spaces(input_string):\n \"\"\"Replaces whitespaces with underscores and vice versa in a string.\n\n Args:\n input_string: The string to modify.\n\n Returns:\n The modified string with spaces replaced by underscores and vice versa.\n \"\"\"\n output_string = \"\"\n for char in input_string:\n if char == \" \":\n output_string += \"_\"\n elif char == \"_\":\n output_string += \" \"\n else:\n output_string += char\n return output_string", "matching_cluster_idx": 2}, {"solution": "def replace_spaces(input_string):\n \"\"\"Replaces spaces with underscores and underscores with spaces in a string.\"\"\"\n result = \"\"\n for char in input_string:\n if char == \" \":\n result += \"_\"\n elif char == \"_\":\n result += \" \"\n else:\n result += char\n return result", "matching_cluster_idx": 2}, {"solution": "def replace_spaces(input_string):\n \"\"\"Replaces spaces with underscores and vice-versa in a string.\"\"\"\n\n result = \"\"\n for char in input_string:\n if char == \" \":\n result += \"_\"\n elif char == \"_\":\n result += \" \"\n else:\n result += char\n return result", "matching_cluster_idx": 2}, {"solution": "def replace_spaces(input_string):\n \"\"\"Replaces spaces with underscores and vice versa in a string.\n\n Args:\n input_string: The input string.\n\n Returns:\n The string with spaces replaced by underscores and vice versa.\n \"\"\"\n\n result = \"\"\n for char in input_string:\n if char == \" \":\n result += \"_\"\n elif char == \"_\":\n result += \" \"\n else:\n result += char\n return result", "matching_cluster_idx": 2}, {"solution": "def replace_spaces(input_string):\n \"\"\"Replaces spaces with underscores and underscores with spaces in a string.\"\"\"\n result = \"\"\n for char in input_string:\n if char == \" \":\n result += \"_\"\n elif char == \"_\":\n result += \" \"\n else:\n result += char\n return result", "matching_cluster_idx": 2}, {"solution": "def replace_spaces(input_string):\n \"\"\"Replaces spaces with underscores and underscores with spaces in a string.\n\n Args:\n input_string: The string to modify.\n\n Returns:\n The modified string.\n \"\"\"\n\n output_string = \"\"\n for char in input_string:\n if char == \" \":\n output_string += \"_\"\n elif char == \"_\":\n output_string += \" \"\n else:\n output_string += char\n return output_string", "matching_cluster_idx": 2}, {"solution": "def replace_spaces(input_string):\n \"\"\"Replaces spaces with underscores and vice-versa in a string.\"\"\"\n\n output_string = \"\"\n for char in input_string:\n if char == \" \":\n output_string += \"_\"\n elif char == \"_\":\n output_string += \" \"\n else:\n output_string += char\n return output_string", "matching_cluster_idx": 1}, {"solution": "def replace_spaces(input_string):\n \"\"\"Replaces spaces with underscores and vice versa in a string.\"\"\"\n\n result = \"\"\n for char in input_string:\n if char == \" \":\n result += \"_\"\n elif char == \"_\":\n result += \" \"\n else:\n result += char\n return result", "matching_cluster_idx": 2}, {"solution": "def replace_spaces(input_string):\n \"\"\"Replaces spaces with underscores and vice versa in a string.\"\"\"\n output_string = \"\"\n for char in input_string:\n if char == \" \":\n output_string += \"_\"\n elif char == \"_\":\n output_string += \" \"\n else:\n output_string += char\n return output_string", "matching_cluster_idx": 1}]}, "Mbpp/632": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def move_zero(nums):\n \"\"\"Moves all zeroes in a list to the end while maintaining the order of non-zero elements.\n\n Args:\n nums: A list of integers.\n\n Returns:\n A new list with zeroes moved to the end.\n \"\"\"\n\n result = []\n zero_count = 0\n for num in nums:\n if num != 0:\n result.append(num)\n else:\n zero_count += 1\n\n result.extend([0] * zero_count) # Efficiently add zeroes at the end\n return result", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n \"\"\"\n Moves all zeroes in a list to the end while preserving the order of other elements.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n A list with all zeroes moved to the end.\n \"\"\"\n if not nums:\n return []\n\n zero_count = 0\n result = []\n\n for num in nums:\n if num == 0:\n zero_count += 1\n else:\n result.append(num)\n\n result.extend([0] * zero_count)\n return result", "matching_cluster_idx": 6}, {"solution": "def move_zero(lst):\n \"\"\"\n Moves all zeroes to the end of a list while preserving the order of other elements.\n\n Args:\n lst: A list of numbers.\n\n Returns:\n A new list with zeroes moved to the end.\n \"\"\"\n result = []\n zeros = []\n for num in lst:\n if num == 0:\n zeros.append(0)\n else:\n result.append(num)\n result.extend(zeros)\n return result", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n \"\"\"\n Moves all zeros in a list to the end while preserving the order of other elements.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n A new list with zeros moved to the end.\n \"\"\"\n\n result = []\n zero_count = 0\n for num in nums:\n if num != 0:\n result.append(num)\n else:\n zero_count += 1\n\n result.extend([0] * zero_count) # Efficiently adds the zeros at the end\n return result", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n \"\"\"\n Moves all zeroes to the end of a list while maintaining the relative order of non-zero elements.\n\n Args:\n nums: A list of integers.\n\n Returns:\n A list with all zeroes moved to the end.\n \"\"\"\n\n if not nums:\n return []\n\n non_zero_index = 0\n for i in range(len(nums)):\n if nums[i] != 0:\n nums[non_zero_index] = nums[i]\n non_zero_index += 1\n\n for i in range(non_zero_index, len(nums)):\n nums[i] = 0\n\n return nums\nnums = [1, 0, 2, 0, 3, 4]", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n \"\"\"Moves all zeros in a list to the end while preserving the order of other elements.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n A list with all zeros moved to the end.\n \"\"\"\n \n non_zero = []\n zero_count = 0\n\n for num in nums:\n if num == 0:\n zero_count += 1\n else:\n non_zero.append(num)\n \n return non_zero + [0] * zero_count", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n \"\"\"Moves all zeros in a list to the end while maintaining the relative order of non-zero elements.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n A list with all zeros moved to the end.\n \"\"\"\n\n non_zero_index = 0 # Keeps track of the position to insert the next non-zero element\n\n for num in nums:\n if num != 0:\n nums[non_zero_index] = num\n non_zero_index += 1\n\n # Fill the remaining elements with zeros\n for i in range(non_zero_index, len(nums)):\n nums[i] = 0\n\n return nums", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n \"\"\"Moves all zeros in a list to the end while preserving the order of other elements.\n\n Args:\n nums: The input list of numbers.\n\n Returns:\n A new list with zeros moved to the end.\n \"\"\"\n\n result = []\n zeros = 0\n for num in nums:\n if num == 0:\n zeros += 1\n else:\n result.append(num)\n\n result.extend([0] * zeros) # Efficiently adds the required number of zeros\n return result", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n \"\"\"Moves all zeros to the end of the list while maintaining the order of other elements.\n\n Args:\n nums: A list of integers.\n\n Returns:\n A list with all zeros moved to the end.\n \"\"\"\n\n non_zero_index = 0\n for i in range(len(nums)):\n if nums[i] != 0:\n nums[non_zero_index], nums[i] = nums[i], nums[non_zero_index] # Swap\n non_zero_index += 1\n\n return nums", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n \"\"\"Moves all zeros in a list to the end while preserving the order of other elements.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n A list with all zeros moved to the end.\n \"\"\"\n non_zero = []\n zero_count = 0\n for num in nums:\n if num != 0:\n non_zero.append(num)\n else:\n zero_count += 1\n\n return non_zero + [0] * zero_count", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n \"\"\"\n Moves all zeroes to the end of the given list while maintaining the relative order of non-zero elements.\n\n Args:\n nums: A list of integers.\n\n Returns:\n A list with all zeroes moved to the end.\n \"\"\"\n\n non_zero = []\n zero_count = 0\n\n for num in nums:\n if num != 0:\n non_zero.append(num)\n else:\n zero_count += 1\n \n return non_zero + [0] * zero_count\nnums = [1, 0, 2, 0, 3, 4]", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n \"\"\"\n Moves all zeroes to the end of a list while maintaining the relative order of non-zero elements.\n\n Args:\n nums: A list of integers.\n\n Returns:\n A list with all zeroes moved to the end.\n \"\"\"\n\n non_zero_index = 0 # Keeps track of the position to place the next non-zero element\n\n for num in nums:\n if num != 0:\n nums[non_zero_index] = num\n non_zero_index += 1\n\n # Fill the remaining positions with zeroes\n for i in range(non_zero_index, len(nums)):\n nums[i] = 0\n\n return nums", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n \"\"\"Moves all zeros in a list to the end while maintaining the relative order of non-zero elements.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n A new list with zeros moved to the end.\n \"\"\"\n\n result = []\n zero_count = 0\n\n for num in nums:\n if num != 0:\n result.append(num)\n else:\n zero_count += 1\n\n result.extend([0] * zero_count) # Efficiently adds multiple zeros\n return result", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n \"\"\"Moves all zeros in a list to the end while maintaining the relative order of non-zero elements.\"\"\"\n \n non_zero = []\n zero_count = 0\n \n for num in nums:\n if num != 0:\n non_zero.append(num)\n else:\n zero_count += 1\n \n result = non_zero + [0] * zero_count # Efficiently add zeros to the end\n return result", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n \"\"\"Moves all zeroes in a list to the end while preserving the order of other elements.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n A new list with all zeroes moved to the end.\n \"\"\"\n result = []\n zero_count = 0\n for num in nums:\n if num != 0:\n result.append(num)\n else:\n zero_count += 1\n result.extend([0] * zero_count)\n return result", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n \"\"\"Moves all zeroes in a list to the end while preserving the order of other elements.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n A new list with zeroes moved to the end.\n \"\"\"\n\n result = []\n zero_count = 0\n for num in nums:\n if num != 0:\n result.append(num)\n else:\n zero_count += 1\n\n result.extend([0] * zero_count)\n return result", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n \"\"\"\n Moves all zeroes to the end of a list while maintaining the relative order of non-zero elements.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n A new list with zeroes moved to the end.\n \"\"\"\n result = []\n zero_count = 0\n for num in nums:\n if num != 0:\n result.append(num)\n else:\n zero_count += 1\n result.extend([0] * zero_count) # Efficiently add zeroes at the end\n return result", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n \"\"\"Moves all zeroes in a list to the end while preserving the order of other elements.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n A new list with all zeroes moved to the end.\n \"\"\"\n result = []\n zero_count = 0\n for num in nums:\n if num != 0:\n result.append(num)\n else:\n zero_count += 1\n result.extend([0] * zero_count)\n return result", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n \"\"\"Moves all zeroes to the end of the list while maintaining the order of other elements.\n\n Args:\n nums: A list of integers.\n\n Returns:\n A list with all zeroes moved to the end.\n \"\"\"\n\n non_zero_index = 0\n for i in range(len(nums)):\n if nums[i] != 0:\n nums[non_zero_index] = nums[i]\n non_zero_index += 1\n\n for i in range(non_zero_index, len(nums)):\n nums[i] = 0\n\n return nums", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n \"\"\"Moves all zeros in a list to the end while maintaining the relative order of non-zero elements.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n A new list with zeros moved to the end.\n \"\"\"\n result = []\n zero_count = 0\n for num in nums:\n if num != 0:\n result.append(num)\n else:\n zero_count += 1\n result.extend([0] * zero_count)\n return result", "matching_cluster_idx": 6}]}, "Mbpp/633": {"dps": 94.3089430894309, "dps_norm": 50.0, "pass@1": 98.0, "profiled": [{"solution": "def pair_xor_Sum(arr, n):\n \"\"\"\n Calculates the sum of XORs of all pairs of numbers in a list.\n\n Args:\n arr: The input list of numbers.\n n: The length of the list.\n\n Returns:\n The sum of XORs of all pairs.\n \"\"\"\n\n result = 0\n for i in range(n):\n for j in range(i + 1, n):\n result += arr[i] ^ arr[j]\n return result", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(arr, n):\n \"\"\"\n Calculates the sum of XORs of all pairs in a list.\n\n Args:\n arr: The list of numbers.\n n: The length of the list.\n\n Returns:\n The sum of XORs of all pairs.\n \"\"\"\n\n total_xor_sum = 0\n for i in range(n):\n for j in range(i + 1, n):\n total_xor_sum += arr[i] ^ arr[j]\n return total_xor_sum\nnumbers = [1, 2, 3, 4]\nn = len(numbers)", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(arr, n):\n \"\"\"\n Calculates the sum of XORs of all pairs of numbers in a list.\n\n Args:\n arr: The input list of numbers.\n n: The length of the list.\n\n Returns:\n The sum of XORs of all pairs.\n \"\"\"\n\n sum_xor = 0\n for i in range(n):\n for j in range(i + 1, n):\n sum_xor += arr[i] ^ arr[j]\n return sum_xor", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(arr, n):\n \"\"\"\n Calculates the sum of XORs of all pairs of numbers in a list.\n\n Args:\n arr: The list of numbers.\n n: The length of the list.\n\n Returns:\n The sum of XORs of all pairs.\n \"\"\"\n sum_xor = 0\n for i in range(n):\n for j in range(i + 1, n):\n sum_xor += arr[i] ^ arr[j]\n return sum_xor", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(arr, n):\n \"\"\"\n Calculates the sum of XORs of all pairs in a list.\n\n Args:\n arr: A list of integers.\n n: The length of the list.\n\n Returns:\n The sum of XORs of all pairs in the list.\n \"\"\"\n sum_xor = 0\n for i in range(n):\n for j in range(i + 1, n):\n sum_xor += arr[i] ^ arr[j]\n return sum_xor", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(arr, n):\n \"\"\"\n Calculates the sum of XORs of all pairs in a list.\n\n Args:\n arr: The input list of numbers.\n n: The length of the list.\n\n Returns:\n The sum of XORs of all pairs.\n \"\"\"\n\n xor_sum = 0\n for i in range(n):\n for j in range(i + 1, n):\n xor_sum += arr[i] ^ arr[j]\n return xor_sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(arr, n):\n \"\"\"\n Calculates the sum of XORs of all pairs of numbers in a list.\n\n Args:\n arr: The list of numbers.\n n: The length of the list.\n\n Returns:\n The sum of XORs of all pairs.\n \"\"\"\n xor_sum = 0\n for i in range(n):\n for j in range(i + 1, n):\n xor_sum += arr[i] ^ arr[j]\n return xor_sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(arr, n):\n \"\"\"\n Calculates the sum of XORs of all pairs of numbers in a list.\n\n Args:\n arr: The input list of numbers.\n n: The length of the list.\n\n Returns:\n The sum of XORs of all pairs.\n \"\"\"\n result = 0\n for i in range(n):\n for j in range(i + 1, n):\n result += arr[i] ^ arr[j]\n return result", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(arr, n):\n \"\"\"\n Calculates the sum of XORs of all pairs of numbers in the given list.\n\n Args:\n arr: The list of numbers.\n n: The number of elements in the list.\n\n Returns:\n The sum of XORs of all pairs.\n \"\"\"\n result = 0\n for i in range(n):\n for j in range(i + 1, n):\n result += arr[i] ^ arr[j]\n return result", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(arr, n):\n \"\"\"\n Calculates the sum of XORs of all pairs in a list.\n\n Args:\n arr: The input list of numbers.\n n: The length of the list.\n\n Returns:\n The sum of XORs of all pairs.\n \"\"\"\n\n xor_sum = 0\n for i in range(n):\n for j in range(i + 1, n):\n xor_sum += arr[i] ^ arr[j]\n return xor_sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(arr, n):\n \"\"\"\n Calculates the sum of XORs of all pairs of numbers in a list.\n\n Args:\n arr: The list of numbers.\n n: The length of the list.\n\n Returns:\n The sum of XORs of all pairs.\n \"\"\"\n\n xor_sum = 0\n for i in range(n):\n for j in range(i + 1, n):\n xor_sum += arr[i] ^ arr[j]\n return xor_sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(arr, n):\n \"\"\"\n Calculates the sum of XORs of all pairs in a list.\n\n Args:\n arr: The input list of numbers.\n n: The length of the list.\n\n Returns:\n The sum of XORs of all pairs.\n \"\"\"\n sum_xor = 0\n for i in range(n):\n for j in range(i + 1, n):\n sum_xor += arr[i] ^ arr[j]\n return sum_xor\nnumbers = [1, 2, 3, 4]\nn = len(numbers)", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(arr, n):\n \"\"\"\n Calculates the sum of XORs of all pairs of numbers in a list.\n\n Args:\n arr: The list of numbers.\n n: The length of the list.\n\n Returns:\n The sum of XORs of all pairs.\n \"\"\"\n\n xor_sum = 0\n for i in range(n):\n for j in range(i + 1, n):\n xor_sum += arr[i] ^ arr[j]\n return xor_sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(arr, n):\n \"\"\"\n Calculates the sum of XORs of all pairs of numbers in a list.\n\n Args:\n arr: The input list of numbers.\n n: The length of the list.\n\n Returns:\n The sum of XORs of all pairs.\n \"\"\"\n sum = 0\n for i in range(n):\n for j in range(i + 1, n):\n sum += arr[i] ^ arr[j]\n return sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(arr, n):\n \"\"\"\n Calculates the sum of XORs of all pairs in a list.\n\n Args:\n arr: The input list of numbers.\n n: The length of the list.\n\n Returns:\n The sum of XORs of all pairs.\n \"\"\"\n\n total_xor_sum = 0\n for i in range(n):\n for j in range(i + 1, n):\n total_xor_sum += arr[i] ^ arr[j]\n return total_xor_sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(arr, n):\n \"\"\"\n Calculates the sum of XORs of all pairs of numbers in a list.\n\n Args:\n arr: The list of numbers.\n n: The length of the list.\n\n Returns:\n The sum of XORs of all pairs.\n \"\"\"\n\n result = 0\n for i in range(n):\n for j in range(i + 1, n):\n result += arr[i] ^ arr[j]\n return result", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(arr, n):\n \"\"\"\n Calculates the sum of XORs of all pairs in a list.\n\n Args:\n arr: The input list of numbers.\n n: The length of the list.\n\n Returns:\n The sum of XORs of all pairs.\n \"\"\"\n\n ans = 0\n for i in range(n):\n for j in range(i + 1, n):\n ans += arr[i] ^ arr[j]\n return ans\narr = [1, 2, 3]\nn = len(arr)", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(arr, n):\n \"\"\"\n Calculates the sum of XORs of all pairs of numbers in a list.\n\n Args:\n arr: A list of integers.\n n: The length of the list.\n\n Returns:\n The sum of XORs of all pairs of numbers in the list.\n \"\"\"\n\n xor_sum = 0\n for i in range(n):\n for j in range(i + 1, n):\n xor_sum += arr[i] ^ arr[j]\n return xor_sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(arr, n):\n \"\"\"\n Calculates the sum of XORs of all pairs of numbers in a list.\n\n Args:\n arr: The input list of numbers.\n n: The length of the list.\n\n Returns:\n The sum of XORs of all pairs.\n \"\"\"\n\n total_xor_sum = 0\n for i in range(n):\n for j in range(i + 1, n):\n total_xor_sum += arr[i] ^ arr[j]\n return total_xor_sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(arr, n):\n \"\"\"\n Calculates the sum of XORs of all pairs in a list.\n\n Args:\n arr: The input list of numbers.\n n: The length of the list.\n\n Returns:\n The sum of XORs of all pairs.\n \"\"\"\n\n xor_sum = 0\n for i in range(n):\n for j in range(i + 1, n):\n xor_sum += arr[i] ^ arr[j]\n return xor_sum", "matching_cluster_idx": 2}]}, "Mbpp/644": {"dps": 71.80851063829786, "dps_norm": 73.33333333333333, "pass@1": 100.0, "profiled": [{"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n Reverses an array up to a given position k (exclusive).\n\n Args:\n arr: The input array.\n k: The position up to which to reverse (exclusive).\n\n Returns:\n The array with the elements up to k reversed.\n Returns the original array if k is invalid.\n \"\"\"\n if k <= 0 or k > len(arr):\n return arr\n\n reversed_portion = arr[:k]\n reversed_portion.reverse()\n return reversed_portion + arr[k:]", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n Reverses an array up to a given position k (exclusive).\n\n Args:\n arr: The input array.\n k: The position up to which the array should be reversed.\n\n Returns:\n A new array with the elements up to k reversed.\n \"\"\"\n\n if k <= 0 or k > len(arr):\n return arr # Handle invalid k values\n\n reversed_part = arr[:k]\n reversed_part.reverse()\n remaining_part = arr[k:]\n\n return reversed_part + remaining_part", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n Reverses an array up to a given position k (exclusive).\n\n Args:\n arr: The input array.\n k: The position up to which to reverse (0-indexed).\n\n Returns:\n The array with the first k elements reversed.\n \"\"\"\n\n if not isinstance(arr, list):\n raise TypeError(\"Input must be a list.\")\n if not isinstance(k, int):\n raise TypeError(\"k must be an integer.\")\n if k < 0 or k > len(arr):\n raise ValueError(\"k must be within the bounds of the array.\")\n\n\n reversed_part = arr[:k]\n reversed_part.reverse()\n return reversed_part + arr[k:]\nk = 5", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n Reverses an array up to a given position k (exclusive).\n\n Args:\n arr: The input array.\n k: The position up to which to reverse (0-indexed).\n\n Returns:\n The array with the elements up to k reversed.\n Returns the original array if k is out of bounds or invalid. \n \"\"\"\n if not isinstance(arr, list) or not isinstance(k, int) or k < 0 or k > len(arr):\n return arr # Handle invalid input\n\n reversed_portion = arr[:k]\n reversed_portion.reverse()\n return reversed_portion + arr[k:]", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n Reverses an array up to a given position k (exclusive).\n\n Args:\n arr: The input array.\n k: The position up to which the array should be reversed.\n\n Returns:\n The reversed array.\n \"\"\"\n if k < 1 or k > len(arr):\n return arr # Handle invalid k values\n\n reversed_part = arr[:k]\n reversed_part.reverse()\n\n return reversed_part + arr[k:]", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n if k <= 0 or k > len(arr):\n return arr # Handle invalid k values\n\n reversed_portion = arr[:k]\n reversed_portion.reverse()\n return reversed_portion + arr[k:]", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n Reverses an array up to a given position k (exclusive).\n\n Args:\n arr: The input array.\n k: The position up to which the array should be reversed.\n\n Returns:\n The reversed array.\n \"\"\"\n if not isinstance(arr, list):\n raise TypeError(\"Input must be a list\")\n if not isinstance(k, int):\n raise TypeError(\"k must be an integer\")\n if k < 0 or k > len(arr):\n raise ValueError(\"k must be within the bounds of the array\")\n \n reversed_part = arr[:k]\n reversed_part.reverse() # In-place reversal\n return reversed_part + arr[k:]", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n Reverses the elements of an array up to a given position k (exclusive).\n\n Args:\n arr: The input array.\n k: The position up to which the array should be reversed (0-indexed).\n\n Returns:\n A new array with the elements reversed up to position k.\n Returns the original array if k is invalid (negative or greater than array length).\n \"\"\"\n\n if k < 0 or k > len(arr):\n return arr # Handle invalid k values\n\n reversed_portion = arr[:k]\n reversed_portion.reverse()\n\n return reversed_portion + arr[k:]", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n Reverses an array up to a given position k (exclusive).\n\n Args:\n arr: The input array.\n k: The position up to which the array should be reversed.\n\n Returns:\n The array with the first k elements reversed.\n \"\"\"\n\n if not isinstance(arr, list):\n raise TypeError(\"Input must be a list.\")\n if not isinstance(k, int) or k < 0 or k > len(arr):\n raise ValueError(\"k must be a non-negative integer less than or equal to the length of the array.\")\n\n\n reversed_part = arr[:k]\n reversed_part.reverse()\n return reversed_part + arr[k:]", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n Reverses an array up to a given position k (exclusive).\n\n Args:\n arr: The input array.\n k: The position up to which to reverse (exclusive).\n\n Returns:\n The array with the first k elements reversed, or the original array if k is invalid.\n \"\"\"\n if not isinstance(arr, list) or not isinstance(k, int) or k < 0 or k > len(arr):\n return arr # Return original array for invalid input\n\n reversed_part = arr[:k]\n reversed_part.reverse()\n return reversed_part + arr[k:]\narr = [10, 20, 30, 40, 50]\nk = 3", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n Reverses the elements of an array up to a given position k (exclusive).\n\n Args:\n arr: The input array.\n k: The position up to which the array should be reversed (0-indexed).\n\n Returns:\n A new array with the elements reversed up to position k.\n Returns the original array if k is out of bounds (negative or greater than the array length).\n \"\"\"\n\n if k < 0 or k > len(arr):\n return arr # Handle out-of-bounds k\n\n reversed_portion = arr[:k]\n reversed_portion.reverse()\n\n return reversed_portion + arr[k:]", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n Reverses an array up to a given position k (exclusive).\n\n Args:\n arr: The input array.\n k: The position up to which the array should be reversed.\n\n Returns:\n The array with the first k elements reversed.\n \"\"\"\n\n if not isinstance(arr, list):\n raise TypeError(\"Input 'arr' must be a list.\")\n if not isinstance(k, int):\n raise TypeError(\"Input 'k' must be an integer.\")\n if k < 0 or k > len(arr):\n raise ValueError(\"Input 'k' must be within the range of the array length.\")\n\n reversed_part = arr[:k]\n reversed_part.reverse()\n result = reversed_part + arr[k:]\n return result", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n Reverses an array up to a given position k (exclusive).\n\n Args:\n arr: The input array.\n k: The position up to which the array should be reversed.\n\n Returns:\n A new array with the elements up to k reversed.\n Returns the original array if k is invalid.\n\n \"\"\"\n if k <= 0 or k > len(arr):\n return arr\n\n reversed_portion = arr[:k]\n reversed_portion.reverse()\n return reversed_portion + arr[k:]", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n Reverses an array up to a given position k (exclusive).\n\n Args:\n arr: The input array.\n k: The position up to which the array should be reversed (0-indexed).\n\n Returns:\n The reversed array.\n \"\"\"\n\n if k < 0 or k > len(arr):\n raise ValueError(\"k must be within the bounds of the array\")\n\n reversed_part = arr[:k]\n reversed_part.reverse()\n\n return reversed_part + arr[k:]", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n Reverses the elements of an array up to a given position k (exclusive).\n\n Args:\n arr: The input array.\n k: The position up to which the array should be reversed.\n\n Returns:\n A new array with the elements reversed up to position k.\n \"\"\"\n\n if not isinstance(arr, list):\n raise TypeError(\"Input 'arr' must be a list.\")\n if not isinstance(k, int):\n raise TypeError(\"Input 'k' must be an integer.\")\n if k < 0 or k > len(arr):\n raise ValueError(\"Input 'k' must be within the bounds of the array.\")\n\n reversed_part = arr[:k]\n reversed_part.reverse()\n return reversed_part + arr[k:]\narr = [10, 20, 30, 40, 50]\nk = 3", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n Reverses the elements of an array up to a given position k (exclusive).\n\n Args:\n arr: The input array.\n k: The position up to which the array should be reversed (0-indexed).\n\n Returns:\n A new array with the elements reversed up to position k.\n Returns the original array if k is out of bounds.\n\n \"\"\"\n if k <= 0 or k > len(arr):\n return arr\n \n reversed_part = arr[:k]\n reversed_part.reverse()\n return reversed_part + arr[k:]", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n Reverses the elements of an array up to a given position k (exclusive).\n\n Args:\n arr: The input array.\n k: The position up to which the array should be reversed (0-indexed).\n\n Returns:\n A new array with the reversed elements up to position k.\n \"\"\"\n\n if k < 0 or k > len(arr):\n raise ValueError(\"k must be within the bounds of the array.\")\n\n reversed_part = arr[:k]\n reversed_part.reverse()\n return reversed_part + arr[k:]", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n Reverses the elements of an array up to a given position k (exclusive).\n\n Args:\n arr: The input array.\n k: The position up to which the array should be reversed.\n\n Returns:\n A new array with the elements reversed up to position k.\n Returns the original array if k is invalid (e.g., negative, larger than array length).\n \"\"\"\n if k <= 0 or k > len(arr):\n return arr # Handle invalid k values\n\n reversed_part = arr[:k]\n reversed_part.reverse()\n return reversed_part + arr[k:]\narr = [1, 2, 3, 4, 5, 6, 7, 8]\nk = 5", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n Reverses the elements of an array up to a specified position k (exclusive).\n\n Args:\n arr: The input array.\n k: The position up to which the array should be reversed (0-indexed).\n\n Returns:\n A new array with the elements reversed up to position k.\n \"\"\"\n\n if k < 0 or k > len(arr):\n raise ValueError(\"k must be a valid index within the array.\")\n\n reversed_part = arr[:k][::-1] # Reverse the portion up to k\n remaining_part = arr[k:] # Keep the rest of the array as is\n return reversed_part + remaining_part", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n Reverses an array up to a given position k (exclusive).\n\n Args:\n arr: The input array.\n k: The position up to which the array should be reversed.\n\n Returns:\n The array with the first k elements reversed.\n \"\"\"\n if k > len(arr) or k < 0:\n raise ValueError(\"k must be within the bounds of the array\")\n \n reversed_portion = arr[:k]\n reversed_portion.reverse()\n \n return reversed_portion + arr[k:]", "matching_cluster_idx": 10}]}, "Mbpp/720": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def add_dict_to_tuple(input_tuple, input_dict):\n \"\"\"Adds a dictionary to the end of a tuple.\n\n Args:\n input_tuple: The tuple to which the dictionary will be added.\n input_dict: The dictionary to add.\n\n Returns:\n A new tuple with the dictionary appended.\n \"\"\"\n\n return input_tuple + (input_dict,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(input_tuple, input_dict):\n \"\"\"\n Adds a dictionary to the end of a tuple.\n\n Args:\n input_tuple: The original tuple.\n input_dict: The dictionary to add.\n\n Returns:\n A new tuple with the dictionary appended.\n \"\"\"\n return input_tuple + (input_dict,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(input_tuple, input_dict):\n \"\"\"\n Adds a dictionary to the end of a tuple.\n\n Args:\n input_tuple: The original tuple.\n input_dict: The dictionary to add.\n\n Returns:\n A new tuple with the dictionary appended.\n \"\"\"\n return input_tuple + (input_dict,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(input_tuple, input_dict):\n \"\"\"\n Adds a dictionary to the end of a tuple.\n\n Args:\n input_tuple: The tuple to which the dictionary will be added.\n input_dict: The dictionary to add.\n\n Returns:\n A new tuple with the dictionary appended to the end.\n \"\"\"\n return input_tuple + (input_dict,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(input_tuple, input_dict):\n \"\"\"\n Adds a dictionary to the end of a tuple.\n\n Args:\n input_tuple: The tuple to which the dictionary will be added.\n input_dict: The dictionary to add.\n\n Returns:\n A new tuple with the dictionary appended.\n \"\"\"\n return input_tuple + (input_dict,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(input_tuple, input_dict):\n \"\"\"Adds a dictionary to the end of a tuple.\n\n Args:\n input_tuple: The tuple to which the dictionary will be added.\n input_dict: The dictionary to add.\n\n Returns:\n A new tuple with the dictionary appended.\n \"\"\"\n return input_tuple + (input_dict,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(input_tuple, input_dict):\n \"\"\"Adds a dictionary to the end of a tuple.\n\n Args:\n input_tuple: The tuple to which the dictionary will be added.\n input_dict: The dictionary to add.\n\n Returns:\n A new tuple with the dictionary appended.\n \"\"\"\n return input_tuple + (input_dict,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(input_tuple, input_dict):\n \"\"\"Adds a dictionary to the end of a tuple.\n\n Args:\n input_tuple: The tuple to which the dictionary will be added.\n input_dict: The dictionary to add.\n\n Returns:\n A new tuple with the dictionary appended.\n \"\"\"\n return input_tuple + (input_dict,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(input_tuple, input_dict):\n \"\"\"\n Adds a dictionary to the end of a tuple.\n\n Args:\n input_tuple: The original tuple.\n input_dict: The dictionary to add.\n\n Returns:\n A new tuple with the dictionary appended.\n \"\"\"\n return input_tuple + (input_dict,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(input_tuple, input_dict):\n \"\"\"Adds a dictionary to the end of a tuple.\n\n Args:\n input_tuple: The tuple to add to.\n input_dict: The dictionary to add.\n\n Returns:\n A new tuple with the dictionary appended.\n \"\"\"\n return input_tuple + (input_dict,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(input_tuple, input_dict):\n \"\"\"Adds a dictionary to the end of a tuple.\n\n Args:\n input_tuple: The tuple to modify.\n input_dict: The dictionary to add.\n\n Returns:\n A new tuple with the dictionary appended.\n \"\"\"\n return input_tuple + (input_dict,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(input_tuple, input_dict):\n \"\"\"\n Adds a dictionary to the end of a tuple.\n\n Args:\n input_tuple: The tuple to which the dictionary will be added.\n input_dict: The dictionary to add.\n\n Returns:\n A new tuple with the dictionary appended.\n \"\"\"\n return input_tuple + (input_dict,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(input_tuple, input_dict):\n \"\"\"Adds a dictionary to the end of a tuple.\n\n Args:\n input_tuple: The tuple to which the dictionary will be added.\n input_dict: The dictionary to add.\n\n Returns:\n A new tuple with the dictionary appended.\n \"\"\"\n\n return input_tuple + (input_dict,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(input_tuple, input_dict):\n \"\"\"Adds a dictionary to the end of a tuple.\n\n Args:\n input_tuple: The tuple to which the dictionary will be added.\n input_dict: The dictionary to be added.\n\n Returns:\n A new tuple with the dictionary appended to the end.\n \"\"\"\n return input_tuple + (input_dict,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(input_tuple, input_dict):\n \"\"\"\n Adds a dictionary to the end of a tuple.\n\n Args:\n input_tuple: The tuple to which the dictionary will be added.\n input_dict: The dictionary to add.\n\n Returns:\n A new tuple with the dictionary appended.\n \"\"\"\n return input_tuple + (input_dict,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(input_tuple, input_dict):\n \"\"\"Adds a dictionary to the end of a tuple.\n\n Args:\n input_tuple: The tuple to which the dictionary will be added.\n input_dict: The dictionary to add.\n\n Returns:\n A new tuple with the dictionary appended.\n \"\"\"\n return input_tuple + (input_dict,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(input_tuple, input_dict):\n \"\"\"Adds a dictionary to the end of a tuple.\n\n Args:\n input_tuple: The original tuple.\n input_dict: The dictionary to add.\n\n Returns:\n A new tuple with the dictionary appended.\n \"\"\"\n return input_tuple + (input_dict,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(input_tuple, input_dict):\n \"\"\"\n Adds a dictionary to the end of a tuple.\n\n Args:\n input_tuple: The tuple to which the dictionary will be added.\n input_dict: The dictionary to add.\n\n Returns:\n A new tuple with the dictionary appended.\n \"\"\"\n return input_tuple + (input_dict,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(input_tuple, input_dict):\n \"\"\"\n Adds a dictionary to the end of a tuple.\n\n Args:\n input_tuple: The tuple to which the dictionary will be added.\n input_dict: The dictionary to add.\n\n Returns:\n A new tuple with the dictionary appended.\n \"\"\"\n return input_tuple + (input_dict,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(input_tuple, input_dict):\n \"\"\"\n Adds a dictionary to the end of a tuple.\n\n Args:\n input_tuple: The tuple to which the dictionary will be added.\n input_dict: The dictionary to add.\n\n Returns:\n A new tuple with the dictionary appended.\n \"\"\"\n return input_tuple + (input_dict,)", "matching_cluster_idx": 4}]}, "Mbpp/725": {"dps": 85.02732240437157, "dps_norm": 80.625, "pass@1": 98.0, "profiled": [{"solution": "import re\ndef extract_quotation(text):\n \"\"\"\n Extracts values enclosed in double quotes from a string.\n\n Args:\n text: The input string.\n\n Returns:\n A list of strings found within double quotes.\n \"\"\"\n\n return re.findall(r'\"([^\"]*)\"', text)", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(text):\n \"\"\"\n Extracts values enclosed within double quotes from a given string.\n\n Args:\n text: The input string.\n\n Returns:\n A list of strings, where each string is the content within a pair of double quotes.\n Returns an empty list if no quotes are found.\n \"\"\"\n\n return re.findall(r'\"([^\"]*)\"', text)", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(text):\n \"\"\"\n Extracts values enclosed in double quotes from a string.\n\n Args:\n text: The input string.\n\n Returns:\n A list of strings found within double quotes.\n \"\"\"\n return re.findall(r'\"([^\"]*)\"', text)", "matching_cluster_idx": 6}, {"solution": "import re\ndef extract_quotation(text):\n \"\"\"\n Extracts values enclosed in double quotes from a given string.\n\n Args:\n text: The input string.\n\n Returns:\n A list of strings containing the extracted values.\n Returns an empty list if no quoted strings are found.\n \"\"\"\n return re.findall(r'\"([^\"]*)\"', text)", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(s):\n \"\"\"\n Extracts values enclosed in double quotes from a string.\n\n Args:\n s: The input string.\n\n Returns:\n A list of strings found between double quotes.\n \"\"\"\n return re.findall(r'\"([^\"]*)\"', s)", "matching_cluster_idx": 6}, {"solution": "import re\ndef extract_quotation(text):\n \"\"\"\n Extracts values enclosed within double quotes from a given string.\n\n Args:\n text: The input string.\n\n Returns:\n A list of strings containing the extracted values, or an empty list if no quotes are found.\n \"\"\"\n return re.findall(r'\"([^\"]*)\"', text)", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(text):\n \"\"\"\n Extracts values enclosed within double quotes from a given string.\n\n Args:\n text: The input string.\n\n Returns:\n A list of strings, where each string is the content within a pair of double quotes.\n Returns an empty list if no quoted strings are found.\n \"\"\"\n return re.findall(r'\"([^\"]*)\"', text)", "matching_cluster_idx": 6}, {"solution": "import re\ndef extract_quotation(text):\n \"\"\"\n Extracts values enclosed in double quotes from a string.\n\n Args:\n text: The input string.\n\n Returns:\n A list of strings containing the extracted values.\n \"\"\"\n return re.findall(r'\"([^\"]*)\"', text)", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(text):\n \"\"\"\n Extracts values enclosed within double quotes from a given string.\n\n Args:\n text: The input string.\n\n Returns:\n A list of strings, where each string is the content within a pair of double quotes.\n Returns an empty list if no quoted strings are found.\n \"\"\"\n return re.findall(r'\"([^\"]*)\"', text)", "matching_cluster_idx": 6}, {"solution": "import re\ndef extract_quotation(text):\n \"\"\"\n Extracts values enclosed within double quotes from a given string.\n\n Args:\n text: The input string.\n\n Returns:\n A list of strings containing the extracted values. \n Returns an empty list if no quoted strings are found.\n \"\"\"\n\n return re.findall(r'\"([^\"]*)\"', text)", "matching_cluster_idx": 6}, {"solution": "import re\ndef extract_quotation(text):\n \"\"\"\n Extracts values enclosed in double quotes from a string.\n\n Args:\n text: The input string.\n\n Returns:\n A list of strings, where each string is the content enclosed within a pair of double quotes.\n Returns an empty list if no quotes are found.\n \"\"\"\n return re.findall(r'\"([^\"]*)\"', text)", "matching_cluster_idx": 6}, {"solution": "import re\ndef extract_quotation(text):\n \"\"\"\n Extracts values enclosed within double quotes from a given string.\n\n Args:\n text: The input string.\n\n Returns:\n A list of strings containing the extracted values. \n Returns an empty list if no quoted strings are found.\n \"\"\"\n return re.findall(r'\"([^\"]*)\"', text)", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(text):\n \"\"\"\n Extracts values enclosed in double quotes from a string.\n\n Args:\n text: The input string.\n\n Returns:\n A list of strings, where each string is the content within a pair of double quotes.\n Returns an empty list if no quotes are found.\n \"\"\"\n\n return re.findall(r'\"([^\"]*)\"', text)", "matching_cluster_idx": 6}, {"solution": "import re\ndef extract_quotation(text):\n \"\"\"\n Extracts values enclosed within double quotes from a given string.\n\n Args:\n text: The input string.\n\n Returns:\n A list of strings, where each string is the content enclosed within a pair of double quotes.\n Returns an empty list if no quoted strings are found.\n \"\"\"\n return re.findall(r'\"([^\"]*)\"', text)", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(text):\n \"\"\"\n Extracts values enclosed within double quotes from a given string.\n\n Args:\n text: The input string.\n\n Returns:\n A list of strings containing the extracted values.\n \"\"\"\n return re.findall(r'\"([^\"]*)\"', text)\ntext = 'This is a \"test\" string with \"multiple\" quoted \"values\".'", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(text):\n \"\"\"\n Extracts values enclosed in double quotes from a string.\n\n Args:\n text: The input string.\n\n Returns:\n A list of strings containing the extracted values.\n \"\"\"\n return re.findall(r'\"([^\"]*)\"', text)", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(text):\n \"\"\"\n Extracts values enclosed in double quotes from a string.\n\n Args:\n text: The input string.\n\n Returns:\n A list of strings, where each string is the content within a pair of double quotes.\n \"\"\"\n return re.findall(r'\"([^\"]*)\"', text)", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(text):\n \"\"\"\n Extracts values enclosed in double quotes from a string.\n\n Args:\n text: The input string.\n\n Returns:\n A list of strings, where each string is the content within a pair of double quotes.\n Returns an empty list if no quoted strings are found.\n \"\"\"\n\n return re.findall(r'\"([^\"]*)\"', text)", "matching_cluster_idx": 6}, {"solution": "import re\ndef extract_quotation(text):\n \"\"\"\n Extracts values enclosed within double quotes from a given string.\n\n Args:\n text: The input string.\n\n Returns:\n A list of strings, where each string is the content enclosed within a pair of double quotes.\n Returns an empty list if no quotes are found.\n \"\"\"\n return re.findall(r'\"([^\"]*)\"', text)", "matching_cluster_idx": 6}, {"solution": "import re\ndef extract_quotation(text):\n \"\"\"\n Extracts values enclosed within double quotes from a string.\n\n Args:\n text: The input string.\n\n Returns:\n A list of strings, each representing a value found within quotes.\n \"\"\"\n return re.findall(r'\"([^\"]*)\"', text)", "matching_cluster_idx": 5}]}, "Mbpp/732": {"dps": 20.07751937984496, "dps_norm": 48.0, "pass@1": 99.0, "profiled": [{"solution": "def replace_specialchar(input_string):\n \"\"\"\n Replaces all occurrences of spaces, commas, or dots with a colon.\n\n Args:\n input_string: The input string.\n\n Returns:\n The modified string with spaces, commas, and dots replaced by colons.\n \"\"\"\n modified_string = \"\"\n for char in input_string:\n if char in (\" \", \",\", \".\"):\n modified_string += \":\"\n else:\n modified_string += char\n return modified_string", "matching_cluster_idx": 4}, {"solution": "import re\ndef replace_specialchar(text):\n \"\"\"Replaces spaces, commas, and dots with colons.\"\"\"\n return re.sub(r\"[ ,.]\", \":\", text)", "matching_cluster_idx": 4}, {"solution": "def replace_specialchar(input_string):\n \"\"\"Replaces spaces, commas, and dots with colons in a string.\n\n Args:\n input_string: The input string.\n\n Returns:\n The modified string with replacements.\n \"\"\"\n result = \"\"\n for char in input_string:\n if char in (\" \", \",\", \".\"):\n result += \":\"\n else:\n result += char\n return result", "matching_cluster_idx": 4}, {"solution": "import re\ndef replace_specialchar(text):\n \"\"\"Replaces spaces, commas, and dots with colons.\"\"\"\n new_text = \"\"\n for char in text:\n if char == \" \" or char == \",\" or char == \".\":\n new_text += \":\"\n else:\n new_text += char\n return new_text", "matching_cluster_idx": 4}, {"solution": "import re\ndef replace_specialchar(input_string):\n \"\"\"Replaces spaces, commas, and dots with colons.\"\"\"\n return re.sub(r'[ ,.]', ':', input_string)", "matching_cluster_idx": 3}, {"solution": "def replace_specialchar(text):\n \"\"\"Replaces spaces, commas, and dots with colons.\"\"\"\n new_text = \"\"\n for char in text:\n if char in (\" \", \",\", \".\"):\n new_text += \":\"\n else:\n new_text += char\n return new_text", "matching_cluster_idx": 4}, {"solution": "def replace_specialchar(text):\n \"\"\"Replaces spaces, commas, and dots with colons.\"\"\"\n result = \"\"\n for char in text:\n if char == ' ' or char == ',' or char == '.':\n result += ':'\n else:\n result += char\n return result", "matching_cluster_idx": 4}, {"solution": "def replace_specialchar(input_string):\n \"\"\"Replaces spaces, commas, and dots with colons.\"\"\"\n result = \"\"\n for char in input_string:\n if char in (\" \", \",\", \".\"):\n result += \":\"\n else:\n result += char\n return result", "matching_cluster_idx": 4}, {"solution": "def replace_specialchar(input_string):\n \"\"\"Replaces spaces, commas, and dots with colons.\"\"\"\n output_string = \"\"\n for char in input_string:\n if char in [\" \", \",\", \".\"]:\n output_string += \":\"\n else:\n output_string += char\n return output_string", "matching_cluster_idx": 4}, {"solution": "def replace_specialchar(input_string):\n \"\"\"\n Replaces all occurrences of spaces, commas, or dots with a colon.\n\n Args:\n input_string: The input string.\n\n Returns:\n The modified string with spaces, commas, and dots replaced by colons.\n \"\"\"\n output_string = \"\"\n for char in input_string:\n if char in (\" \", \",\", \".\"):\n output_string += \":\"\n else:\n output_string += char\n return output_string", "matching_cluster_idx": 4}, {"solution": "import re\ndef replace_specialchar(text):\n \"\"\"Replaces spaces, commas, and dots with colons.\"\"\"\n return re.sub(r\"[ ,.]\", \":\", text)", "matching_cluster_idx": 4}, {"solution": "def replace_specialchar(text):\n \"\"\"Replaces spaces, commas, and dots with colons in a given string.\n\n Args:\n text: The input string.\n\n Returns:\n The modified string with special characters replaced.\n \"\"\"\n new_text = \"\"\n for char in text:\n if char in (\" \", \",\", \".\"):\n new_text += \":\"\n else:\n new_text += char\n return new_text", "matching_cluster_idx": 4}, {"solution": "def replace_specialchar(input_string):\n \"\"\"\n Replaces all occurrences of spaces, commas, or dots with a colon.\n\n Args:\n input_string: The string to modify.\n\n Returns:\n The modified string with spaces, commas, and dots replaced by colons.\n \"\"\"\n output_string = \"\"\n for char in input_string:\n if char in (\" \", \",\", \".\"):\n output_string += \":\"\n else:\n output_string += char\n return output_string", "matching_cluster_idx": 4}, {"solution": "import re\ndef replace_specialchar(text):\n \"\"\"Replaces spaces, commas, and dots with colons in a string.\n\n Args:\n text: The input string.\n\n Returns:\n The modified string with replacements.\n \"\"\"\n\n return re.sub(r'[ ,.]', ':', text)", "matching_cluster_idx": 3}, {"solution": "def replace_specialchar(text):\n \"\"\"Replaces spaces, commas, and dots with colons in a given string.\n\n Args:\n text: The input string.\n\n Returns:\n The modified string with special characters replaced.\n \"\"\"\n\n new_text = \"\"\n for char in text:\n if char == \" \" or char == \",\" or char == \".\":\n new_text += \":\"\n else:\n new_text += char\n return new_text", "matching_cluster_idx": 4}, {"solution": "import re\ndef replace_specialchar(text):\n \"\"\"Replaces spaces, commas, and dots with colons.\"\"\"\n return re.sub(r\"[ ,.]\", \":\", text)", "matching_cluster_idx": 4}, {"solution": "import re\ndef replace_specialchar(input_string):\n \"\"\"Replaces spaces, commas, and dots with colons.\"\"\"\n return re.sub(r\"[ ,.]\", \":\", input_string)", "matching_cluster_idx": 3}, {"solution": "import re\ndef replace_specialchar(text):\n \"\"\"Replaces spaces, commas, and dots with colons.\"\"\"\n return re.sub(r'[ ,.]', ':', text)", "matching_cluster_idx": 3}, {"solution": "import re\ndef replace_specialchar(text):\n \"\"\"Replaces spaces, commas, and dots with colons.\"\"\"\n return re.sub(r\"[ ,.]\", \":\", text)", "matching_cluster_idx": 4}, {"solution": "def replace_specialchar(text):\n \"\"\"Replaces spaces, commas, and dots with colons in a string.\n\n Args:\n text: The input string.\n\n Returns:\n The modified string with replacements.\n \"\"\"\n result = \"\"\n for char in text:\n if char in (\" \", \",\", \".\"):\n result += \":\"\n else:\n result += char\n return result", "matching_cluster_idx": 4}]}, "Mbpp/740": {"dps": 83.63636363636364, "dps_norm": 66.66666666666667, "pass@1": 100.0, "profiled": [{"solution": "def tuple_to_dict(input_tuple):\n \"\"\"\n Converts a tuple to a key-value dictionary using adjacent elements.\n\n Args:\n input_tuple: The input tuple.\n\n Returns:\n A dictionary where keys are elements at even indices and values are elements at odd indices.\n Returns an empty dictionary if the tuple has an odd number of elements or is empty.\n \"\"\"\n if len(input_tuple) % 2 != 0 or not input_tuple:\n return {}\n\n output_dict = {}\n for i in range(0, len(input_tuple), 2):\n output_dict[input_tuple[i]] = input_tuple[i + 1]\n return output_dict", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(input_tuple):\n \"\"\"Converts a tuple to a key-value dictionary using adjacent elements.\n\n Args:\n input_tuple: The input tuple.\n\n Returns:\n A dictionary where keys and values are taken from adjacent elements of the tuple.\n Returns an empty dictionary if the tuple has an odd number of elements or is empty.\n \"\"\"\n\n if len(input_tuple) % 2 != 0 or not input_tuple:\n return {}\n \n result_dict = {}\n for i in range(0, len(input_tuple), 2):\n result_dict[input_tuple[i]] = input_tuple[i+1]\n\n return result_dict", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(input_tuple):\n \"\"\"Converts a tuple to a dictionary using adjacent elements as key-value pairs.\n\n Args:\n input_tuple: The input tuple.\n\n Returns:\n A dictionary created from the tuple, or an empty dictionary if the tuple has an odd number of elements.\n \"\"\"\n\n if len(input_tuple) % 2 != 0:\n return {} # Or raise an exception if preferred\n\n output_dict = {}\n for i in range(0, len(input_tuple), 2):\n output_dict[input_tuple[i]] = input_tuple[i+1]\n return output_dict", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(input_tuple):\n \"\"\"Converts a tuple to a dictionary using adjacent elements as key-value pairs.\n\n Args:\n input_tuple: The input tuple.\n\n Returns:\n A dictionary created from the tuple, or an empty dictionary if the tuple has an odd number of elements.\n \n Raises:\n TypeError: if input is not a tuple\n \"\"\"\n if not isinstance(input_tuple, tuple):\n raise TypeError(\"Input must be a tuple.\")\n\n if len(input_tuple) % 2 != 0:\n return {}\n \n output_dict = {}\n for i in range(0, len(input_tuple), 2):\n output_dict[input_tuple[i]] = input_tuple[i+1]\n return output_dict", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(input_tuple):\n \"\"\"Converts a tuple to a dictionary using adjacent elements as key-value pairs.\n\n Args:\n input_tuple: The input tuple.\n\n Returns:\n A dictionary created from the tuple, or an empty dictionary if the tuple \n has an odd number of elements.\n \"\"\"\n if len(input_tuple) % 2 != 0:\n return {} # Return empty dictionary for odd-length tuples\n \n output_dict = {}\n for i in range(0, len(input_tuple), 2):\n output_dict[input_tuple[i]] = input_tuple[i+1]\n return output_dict", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(input_tuple):\n \"\"\"Converts a tuple to a dictionary using adjacent elements as key-value pairs.\n\n Args:\n input_tuple: The input tuple.\n\n Returns:\n A dictionary created from the tuple, or an empty dictionary if the tuple has an odd number of elements.\n \"\"\"\n\n if len(input_tuple) % 2 != 0:\n return {}\n \n output_dict = {}\n for i in range(0, len(input_tuple), 2):\n output_dict[input_tuple[i]] = input_tuple[i+1]\n return output_dict", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(input_tuple):\n \"\"\"\n Converts a tuple to a dictionary using adjacent elements as key-value pairs.\n\n Args:\n input_tuple: The input tuple.\n\n Returns:\n A dictionary created from the tuple, or an empty dictionary if the tuple has an odd number of elements.\n \"\"\"\n if len(input_tuple) % 2 != 0:\n return {}\n \n output_dict = {}\n for i in range(0, len(input_tuple), 2):\n output_dict[input_tuple[i]] = input_tuple[i + 1]\n return output_dict", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(input_tuple):\n \"\"\"Converts a tuple to a dictionary using adjacent elements as key-value pairs.\n\n Args:\n input_tuple: The input tuple.\n\n Returns:\n A dictionary created from the tuple, or an empty dictionary if the tuple has an odd number of elements.\n \"\"\"\n\n if len(input_tuple) % 2 != 0:\n return {}\n\n output_dict = {}\n for i in range(0, len(input_tuple), 2):\n output_dict[input_tuple[i]] = input_tuple[i + 1]\n\n return output_dict", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(input_tuple):\n \"\"\"\n Converts a tuple to a dictionary using adjacent elements as key-value pairs.\n\n Args:\n input_tuple: The input tuple.\n\n Returns:\n A dictionary created from the tuple, or an empty dictionary if the tuple \n has an odd number of elements or is empty.\n \"\"\"\n\n if len(input_tuple) % 2 != 0 or not input_tuple:\n return {}\n\n result_dict = {}\n for i in range(0, len(input_tuple), 2):\n result_dict[input_tuple[i]] = input_tuple[i + 1]\n return result_dict\ntest_tuple = (2, 4, 6, 8, 10, 12)\nresult_dict = tuple_to_dict(test_tuple)", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(input_tuple):\n \"\"\"\n Converts a tuple to a key-value dictionary using adjacent elements.\n\n Args:\n input_tuple: The input tuple.\n\n Returns:\n A dictionary where keys are elements at even indices and values are elements at odd indices.\n Returns an empty dictionary if the tuple has an odd number of elements or is empty.\n \"\"\"\n if len(input_tuple) % 2 != 0 or not input_tuple:\n return {}\n\n result_dict = {}\n for i in range(0, len(input_tuple), 2):\n result_dict[input_tuple[i]] = input_tuple[i + 1]\n return result_dict", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(input_tuple):\n \"\"\"\n Converts a tuple to a dictionary using adjacent elements as key-value pairs.\n\n Args:\n input_tuple: The input tuple.\n\n Returns:\n A dictionary created from the tuple, or an empty dictionary if the tuple \n has an odd number of elements or is empty.\n \"\"\"\n\n if len(input_tuple) % 2 != 0 or not input_tuple:\n return {}\n \n output_dict = {}\n for i in range(0, len(input_tuple), 2):\n output_dict[input_tuple[i]] = input_tuple[i+1]\n return output_dict", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(input_tuple):\n \"\"\"\n Converts a tuple to a dictionary using adjacent elements as key-value pairs.\n\n Args:\n input_tuple: The input tuple.\n\n Returns:\n A dictionary created from the tuple, or an empty dictionary if the tuple has an odd number of elements.\n \"\"\"\n\n if len(input_tuple) % 2 != 0:\n return {} # Or raise an error if preferred\n\n output_dict = {}\n for i in range(0, len(input_tuple), 2):\n output_dict[input_tuple[i]] = input_tuple[i+1]\n return output_dict", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(input_tuple):\n \"\"\"Converts a tuple to a dictionary using adjacent elements as key-value pairs.\n\n Args:\n input_tuple: The input tuple.\n\n Returns:\n A dictionary created from the tuple, or an empty dictionary if the tuple has an odd number of elements.\n \"\"\"\n if len(input_tuple) % 2 != 0:\n return {} # Return empty dict for odd length tuples\n \n output_dict = {}\n for i in range(0, len(input_tuple), 2):\n output_dict[input_tuple[i]] = input_tuple[i+1]\n return output_dict", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(input_tuple):\n \"\"\"Converts a tuple to a dictionary using adjacent elements as key-value pairs.\n\n Args:\n input_tuple: The input tuple.\n\n Returns:\n A dictionary where keys are elements at even indices and values are elements at odd indices.\n Returns an empty dictionary if the tuple has an odd number of elements or is empty.\n \"\"\"\n if len(input_tuple) % 2 != 0 or not input_tuple:\n return {}\n\n result_dict = {}\n for i in range(0, len(input_tuple), 2):\n result_dict[input_tuple[i]] = input_tuple[i + 1]\n\n return result_dict", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(input_tuple):\n \"\"\"Converts a tuple to a dictionary using adjacent elements as key-value pairs.\n\n Args:\n input_tuple: The input tuple.\n\n Returns:\n A dictionary created from the tuple, or an empty dictionary if the tuple \n has an odd number of elements.\n \"\"\"\n if len(input_tuple) % 2 != 0:\n return {}\n \n output_dict = {}\n for i in range(0, len(input_tuple), 2):\n output_dict[input_tuple[i]] = input_tuple[i+1]\n return output_dict", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(input_tuple):\n \"\"\"\n Converts a tuple to a dictionary using adjacent elements as key-value pairs.\n\n Args:\n input_tuple: The input tuple.\n\n Returns:\n A dictionary created from the tuple, or an empty dictionary if the tuple has an odd number of elements.\n \"\"\"\n if len(input_tuple) % 2 != 0:\n return {}\n \n output_dict = {}\n for i in range(0, len(input_tuple), 2):\n output_dict[input_tuple[i]] = input_tuple[i+1]\n return output_dict", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(input_tuple):\n \"\"\"Converts a tuple to a key-value dictionary using adjacent elements.\"\"\"\n if len(input_tuple) % 2 != 0:\n raise ValueError(\"Tuple must have an even number of elements.\")\n\n output_dict = {}\n for i in range(0, len(input_tuple), 2):\n output_dict[input_tuple[i]] = input_tuple[i+1]\n return output_dict", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(input_tuple):\n \"\"\"Converts a tuple to a dictionary using adjacent elements as key-value pairs.\n\n Args:\n input_tuple: The input tuple.\n\n Returns:\n A dictionary created from the tuple, or an empty dictionary if the tuple \n has an odd number of elements or is empty.\n \"\"\"\n\n if len(input_tuple) % 2 != 0 or not input_tuple:\n return {}\n \n output_dict = {}\n for i in range(0, len(input_tuple), 2):\n output_dict[input_tuple[i]] = input_tuple[i+1]\n return output_dict", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(input_tuple):\n \"\"\"Converts a tuple to a dictionary using adjacent elements as key-value pairs.\n\n Args:\n input_tuple: The input tuple.\n\n Returns:\n A dictionary created from the tuple, or an empty dictionary if the tuple \n has an odd number of elements or is empty.\n \"\"\"\n if len(input_tuple) % 2 != 0 or not input_tuple:\n return {}\n \n output_dict = {}\n for i in range(0, len(input_tuple), 2):\n output_dict[input_tuple[i]] = input_tuple[i+1]\n return output_dict", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(input_tuple):\n \"\"\"Converts a tuple to a key-value dictionary using adjacent elements.\n\n Args:\n input_tuple: The input tuple.\n\n Returns:\n A dictionary where keys are elements at even indices and values are elements at odd indices.\n Returns an empty dictionary if the tuple has an odd number of elements or is empty.\n \"\"\"\n if len(input_tuple) % 2 != 0 or not input_tuple:\n return {}\n\n result_dict = {}\n for i in range(0, len(input_tuple), 2):\n result_dict[input_tuple[i]] = input_tuple[i+1]\n return result_dict", "matching_cluster_idx": 5}]}, "Mbpp/744": {"dps": 76.02739726027397, "dps_norm": 83.33333333333333, "pass@1": 100.0, "profiled": [{"solution": "def check_none(input_tuple):\n \"\"\"\n Checks if a tuple contains any None values.\n\n Args:\n input_tuple: The tuple to check.\n\n Returns:\n True if the tuple contains None, False otherwise.\n \"\"\"\n for item in input_tuple:\n if item is None:\n return True\n return False", "matching_cluster_idx": 4}, {"solution": "def check_none(input_tuple):\n \"\"\"\n Checks if a tuple contains any None values.\n\n Args:\n input_tuple: The tuple to check.\n\n Returns:\n True if the tuple contains at least one None value, False otherwise.\n \"\"\"\n for item in input_tuple:\n if item is None:\n return True\n return False", "matching_cluster_idx": 4}, {"solution": "def check_none(input_tuple):\n \"\"\"\n Checks if a tuple contains any None values.\n\n Args:\n input_tuple: The tuple to check.\n\n Returns:\n True if the tuple contains at least one None value, False otherwise.\n \"\"\"\n for item in input_tuple:\n if item is None:\n return True\n return False", "matching_cluster_idx": 4}, {"solution": "def check_none(input_tuple):\n \"\"\"\n Checks if a tuple contains any None values.\n\n Args:\n input_tuple: The tuple to check.\n\n Returns:\n True if the tuple contains at least one None value, False otherwise.\n \"\"\"\n for item in input_tuple:\n if item is None:\n return True\n return False", "matching_cluster_idx": 4}, {"solution": "def check_none(input_tuple):\n \"\"\"\n Checks if a tuple contains any None values.\n\n Args:\n input_tuple: The tuple to check.\n\n Returns:\n True if the tuple contains at least one None value, False otherwise.\n \"\"\"\n for item in input_tuple:\n if item is None:\n return True\n return False", "matching_cluster_idx": 4}, {"solution": "def check_none(input_tuple):\n \"\"\"\n Checks if a tuple contains any None values.\n\n Args:\n input_tuple: The tuple to check.\n\n Returns:\n True if the tuple contains at least one None value, False otherwise.\n \"\"\"\n for item in input_tuple:\n if item is None:\n return True\n return False", "matching_cluster_idx": 4}, {"solution": "def check_none(input_tuple):\n \"\"\"\n Checks if a tuple contains any None values.\n\n Args:\n input_tuple: The tuple to check.\n\n Returns:\n True if the tuple contains at least one None value, False otherwise.\n \"\"\"\n for item in input_tuple:\n if item is None:\n return True\n return False", "matching_cluster_idx": 4}, {"solution": "def check_none(input_tuple):\n \"\"\"\n Checks if the given tuple contains any None values.\n\n Args:\n input_tuple: The tuple to check.\n\n Returns:\n True if the tuple contains None, False otherwise.\n \"\"\"\n for item in input_tuple:\n if item is None:\n return True\n return False", "matching_cluster_idx": 4}, {"solution": "def check_none(input_tuple):\n \"\"\"\n Checks if a tuple contains any None values.\n\n Args:\n input_tuple: The tuple to check.\n\n Returns:\n True if the tuple contains at least one None value, False otherwise.\n \"\"\"\n for item in input_tuple:\n if item is None:\n return True\n return False", "matching_cluster_idx": 4}, {"solution": "def check_none(input_tuple):\n \"\"\"\n Checks if a tuple contains any None values.\n\n Args:\n input_tuple: The tuple to check.\n\n Returns:\n True if the tuple contains at least one None value, False otherwise.\n \"\"\"\n for item in input_tuple:\n if item is None:\n return True\n return False", "matching_cluster_idx": 4}, {"solution": "def check_none(input_tuple):\n \"\"\"\n Checks if a tuple contains any None values.\n\n Args:\n input_tuple: The tuple to check.\n\n Returns:\n True if the tuple contains at least one None value, False otherwise.\n \"\"\"\n for item in input_tuple:\n if item is None:\n return True\n return False", "matching_cluster_idx": 4}, {"solution": "def check_none(input_tuple):\n \"\"\"\n Checks if a tuple contains any None values.\n\n Args:\n input_tuple: The tuple to check.\n\n Returns:\n True if the tuple contains at least one None value, False otherwise.\n \"\"\"\n for item in input_tuple:\n if item is None:\n return True\n return False", "matching_cluster_idx": 4}, {"solution": "def check_none(input_tuple):\n \"\"\"\n Checks if a tuple contains any None values.\n\n Args:\n input_tuple: The tuple to check.\n\n Returns:\n True if the tuple contains at least one None value, False otherwise.\n \"\"\"\n for item in input_tuple:\n if item is None:\n return True\n return False", "matching_cluster_idx": 4}, {"solution": "def check_none(input_tuple):\n \"\"\"\n Checks if a tuple contains any None values.\n\n Args:\n input_tuple: The tuple to check.\n\n Returns:\n True if the tuple contains at least one None value, False otherwise.\n \"\"\"\n for item in input_tuple:\n if item is None:\n return True\n return False", "matching_cluster_idx": 4}, {"solution": "def check_none(input_tuple):\n \"\"\"\n Checks if a tuple contains any None values.\n\n Args:\n input_tuple: The tuple to check.\n\n Returns:\n True if the tuple contains at least one None value, False otherwise.\n \"\"\"\n for item in input_tuple:\n if item is None:\n return True\n return False", "matching_cluster_idx": 4}, {"solution": "def check_none(input_tuple):\n \"\"\"\n Checks if a tuple contains any None values.\n\n Args:\n input_tuple: The tuple to check.\n\n Returns:\n True if the tuple contains at least one None value, False otherwise.\n \"\"\"\n for item in input_tuple:\n if item is None:\n return True\n return False", "matching_cluster_idx": 4}, {"solution": "def check_none(input_tuple):\n \"\"\"\n Checks if a tuple contains any None values.\n\n Args:\n input_tuple: The tuple to check.\n\n Returns:\n True if the tuple contains at least one None value, False otherwise.\n \"\"\"\n for item in input_tuple:\n if item is None:\n return True\n return False", "matching_cluster_idx": 4}, {"solution": "def check_none(input_tuple):\n \"\"\"\n Checks if a tuple contains any None values.\n\n Args:\n input_tuple: The tuple to check.\n\n Returns:\n True if the tuple contains None, False otherwise.\n \"\"\"\n for item in input_tuple:\n if item is None:\n return True\n return False", "matching_cluster_idx": 4}, {"solution": "def check_none(input_tuple):\n \"\"\"Checks if a tuple contains any None values.\"\"\"\n for item in input_tuple:\n if item is None:\n return True\n return False", "matching_cluster_idx": 4}, {"solution": "def check_none(input_tuple):\n \"\"\"\n Checks if a tuple contains any None values.\n\n Args:\n input_tuple: The tuple to check.\n\n Returns:\n True if the tuple contains None, False otherwise.\n \"\"\"\n for item in input_tuple:\n if item is None:\n return True\n return False", "matching_cluster_idx": 4}]}, "Mbpp/750": {"dps": 13.503401360544217, "dps_norm": 14.166666666666668, "pass@1": 100.0, "profiled": [{"solution": "def add_tuple(my_list, my_tuple):\n \"\"\"Adds the elements of a tuple to a list.\n\n Args:\n my_list: The list to which the tuple elements will be added.\n my_tuple: The tuple containing the elements to be added.\n\n Returns:\n A new list containing the elements of the original list followed by the elements of the tuple.\n \"\"\"\n\n new_list = my_list[:] # Create a copy to avoid modifying the original list\n for item in my_tuple:\n new_list.append(item)\n return new_list", "matching_cluster_idx": -1}, {"solution": "def add_tuple(my_list, my_tuple):\n \"\"\"Adds the elements of a tuple to the end of a list.\n\n Args:\n my_list: The list to modify.\n my_tuple: The tuple containing elements to add.\n\n Returns:\n The modified list with the tuple elements appended.\n \"\"\"\n\n new_list = my_list[:] # Create a copy to avoid modifying the original list\n for item in my_tuple:\n new_list.append(item)\n return new_list", "matching_cluster_idx": -1}, {"solution": "def add_tuple(my_list, my_tuple):\n \"\"\"Adds the elements of a tuple to a list.\n\n Args:\n my_list: The list to which elements will be added.\n my_tuple: The tuple containing elements to be added.\n\n Returns:\n A new list with elements of the tuple appended to the original list.\n \"\"\"\n\n new_list = my_list[:] # Create a copy to avoid modifying the original list\n for item in my_tuple:\n new_list.append(item)\n return new_list", "matching_cluster_idx": -1}, {"solution": "def add_tuple(my_list, my_tuple):\n \"\"\"Adds the elements of a tuple to the end of a list.\n\n Args:\n my_list: The list to modify.\n my_tuple: The tuple whose elements will be added.\n\n Returns:\n The modified list with the tuple elements appended.\n \"\"\"\n\n new_list = my_list[:] # Create a copy to avoid modifying the original list\n new_list.extend(my_tuple)\n return new_list", "matching_cluster_idx": 3}, {"solution": "def add_tuple(my_list, my_tuple):\n \"\"\"Adds the elements of a tuple to the end of a list.\"\"\"\n new_list = my_list[:] # Create a copy to avoid modifying the original list\n for item in my_tuple:\n new_list.append(item)\n return new_list", "matching_cluster_idx": -1}, {"solution": "def add_tuple(my_list, my_tuple):\n \"\"\"Adds the elements of a tuple to the end of a list.\n\n Args:\n my_list: The list to modify.\n my_tuple: The tuple to add to the list.\n\n Returns:\n The modified list with the tuple elements appended.\n \"\"\"\n new_list = my_list[:] # Create a copy to avoid modifying the original list\n for item in my_tuple:\n new_list.append(item)\n return new_list", "matching_cluster_idx": -1}, {"solution": "def add_tuple(my_list, my_tuple):\n \"\"\"Adds elements of a tuple to the end of a list.\n\n Args:\n my_list: The list to which elements will be added.\n my_tuple: The tuple containing elements to be added.\n\n Returns:\n A new list with the tuple elements appended.\n \"\"\"\n\n new_list = my_list[:] # Create a copy to avoid modifying the original list\n for item in my_tuple:\n new_list.append(item)\n return new_list\nlist1 = [1, 2, 3]\ntuple1 = (4, 5)\nnew_list = add_tuple(list1, tuple1)", "matching_cluster_idx": -1}, {"solution": "def add_tuple(my_list, my_tuple):\n \"\"\"Adds the elements of a tuple to the end of a list.\n\n Args:\n my_list: The list to modify.\n my_tuple: The tuple whose elements will be added.\n\n Returns:\n The modified list with the tuple elements appended.\n \"\"\"\n new_list = my_list[:] # Create a copy to avoid modifying the original list in-place\n for item in my_tuple:\n new_list.append(item)\n return new_list\nmy_list = [1, 2, 3]\nmy_tuple = (4, 5)\nnew_list = add_tuple(my_list, my_tuple)", "matching_cluster_idx": -1}, {"solution": "def add_tuple(my_list, my_tuple):\n \"\"\"Adds the elements of a tuple to the end of a list.\n\n Args:\n my_list: The list to which the tuple elements will be added.\n my_tuple: The tuple whose elements will be added to the list.\n\n Returns:\n A new list with the tuple elements added to the end of the original list.\n \"\"\"\n new_list = my_list[:] # Create a copy to avoid modifying the original list\n for item in my_tuple:\n new_list.append(item)\n return new_list", "matching_cluster_idx": -1}, {"solution": "def add_tuple(my_list, my_tuple):\n \"\"\"Adds the elements of a tuple to the end of a list.\n\n Args:\n my_list: The list to modify.\n my_tuple: The tuple whose elements are to be added.\n\n Returns:\n A new list with the tuple elements appended.\n \"\"\"\n new_list = my_list[:] # Create a copy to avoid modifying the original list\n new_list.extend(my_tuple)\n return new_list", "matching_cluster_idx": 2}, {"solution": "def add_tuple(my_list, my_tuple):\n \"\"\"Adds the elements of a tuple to the end of a list.\"\"\"\n new_list = my_list[:] # Create a copy to avoid modifying the original list\n for item in my_tuple:\n new_list.append(item)\n return new_list", "matching_cluster_idx": -1}, {"solution": "def add_tuple(my_list, my_tuple):\n \"\"\"\n Adds the elements of a tuple to the end of a list.\n\n Args:\n my_list: The list to modify.\n my_tuple: The tuple containing elements to add.\n\n Returns:\n The modified list with the tuple elements appended.\n \"\"\"\n new_list = my_list.copy() # Important to copy to avoid modifying the original list\n for item in my_tuple:\n new_list.append(item)\n return new_list", "matching_cluster_idx": -1}, {"solution": "def add_tuple(my_list, my_tuple):\n \"\"\"Adds elements of a tuple to the end of a list.\"\"\"\n\n new_list = my_list[:] # Create a copy to avoid modifying the original list.\n for item in my_tuple:\n new_list.append(item)\n return new_list", "matching_cluster_idx": -1}, {"solution": "def add_tuple(my_list, my_tuple):\n \"\"\"Adds the elements of a tuple to a list.\n\n Args:\n my_list: The list to which the tuple elements should be added.\n my_tuple: The tuple containing elements to be added.\n\n Returns:\n A new list with the tuple elements appended to the original list.\n \"\"\"\n\n new_list = my_list[:] # Create a copy to avoid modifying the original list\n for item in my_tuple:\n new_list.append(item)\n return new_list", "matching_cluster_idx": -1}, {"solution": "def add_tuple(my_list, my_tuple):\n \"\"\"Adds the elements of a tuple to a list.\n\n Args:\n my_list: The list to modify.\n my_tuple: The tuple containing the elements to add.\n\n Returns:\n The modified list with the tuple elements appended.\n \"\"\"\n new_list = my_list[:] # Create a copy to avoid modifying the original list\n for item in my_tuple:\n new_list.append(item)\n return new_list", "matching_cluster_idx": -1}, {"solution": "def add_tuple(my_list, my_tuple):\n \"\"\"Adds a tuple to the end of a list.\n\n Args:\n my_list: The list to modify.\n my_tuple: The tuple to add.\n\n Returns:\n A new list with the tuple's elements appended.\n \"\"\"\n\n new_list = my_list[:] # Create a copy to avoid modifying the original\n for item in my_tuple:\n new_list.append(item)\n return new_list", "matching_cluster_idx": -1}, {"solution": "def add_tuple(my_list, my_tuple):\n \"\"\"Adds the elements of a tuple to the end of a list.\n\n Args:\n my_list: The list to modify.\n my_tuple: The tuple whose elements are to be added.\n\n Returns:\n The modified list.\n \"\"\"\n new_list = my_list[:] # Create a copy to avoid modifying the original\n new_list.extend(my_tuple)\n return new_list", "matching_cluster_idx": 3}, {"solution": "def add_tuple(my_list, my_tuple):\n \"\"\"Adds the elements of a tuple to the end of a list.\n\n Args:\n my_list: The list to modify.\n my_tuple: The tuple whose elements are to be added.\n\n Returns:\n The modified list with the tuple elements appended.\n \"\"\"\n new_list = my_list[:] # Create a copy to avoid modifying the original list\n for item in my_tuple:\n new_list.append(item)\n return new_list\noriginal_list = [1, 2, 3]\nnew_list = add_tuple(original_list, (4, 5))", "matching_cluster_idx": -1}, {"solution": "def add_tuple(my_list, my_tuple):\n \"\"\"Adds the elements of a tuple to the end of a list.\n\n Args:\n my_list: The list to modify.\n my_tuple: The tuple whose elements to add.\n\n Returns:\n A new list with the tuple's elements appended.\n \"\"\"\n new_list = my_list[:] # Create a copy to avoid modifying the original list\n new_list.extend(my_tuple)\n return new_list", "matching_cluster_idx": 2}, {"solution": "def add_tuple(my_list, my_tuple):\n \"\"\"Adds the elements of a tuple to the end of a list.\n\n Args:\n my_list: The list to modify.\n my_tuple: The tuple whose elements are to be added.\n\n Returns:\n A new list with the tuple elements appended.\n \"\"\"\n new_list = my_list[:] # Create a copy to avoid modifying the original list\n new_list.extend(my_tuple)\n return new_list", "matching_cluster_idx": 2}]}, "Mbpp/753": {"dps": 31.333892617449663, "dps_norm": 57.8125, "pass@1": 16.0, "profiled": [{"solution": "import heapq\ndef min_k(records, k):\n \"\"\"\n Finds the minimum k records from a list of tuples.\n\n Args:\n records: A list of tuples, where each tuple represents a record.\n k: The number of minimum records to return.\n\n Returns:\n A list of k tuples representing the minimum records.\n \"\"\"\n if not records:\n return []\n \n return sorted(records, key=lambda x: x[1])[:k]", "matching_cluster_idx": 1}, {"solution": "def min_k(tuple_list, k):\n \"\"\"\n Finds the minimum k records from a list of tuples based on the second element (numerical value).\n\n Args:\n tuple_list: A list of tuples, where each tuple contains a string and a number.\n k: The number of minimum records to return.\n\n Returns:\n A list of k tuples with the smallest numerical values, sorted in ascending order.\n Returns an empty list if the input list is empty or k is 0.\n Returns the entire sorted list if k is greater than the length of the input list. \n \"\"\"\n if not tuple_list or k == 0:\n return []\n\n sorted_tuples = sorted(tuple_list, key=lambda x: x[1])\n\n return sorted_tuples[:k]", "matching_cluster_idx": 1}, {"solution": "import heapq\ndef min_k(records, k):\n \"\"\"\n Finds the minimum k records from a list of tuples based on the second element (numerical value).\n\n Args:\n records: A list of tuples, where each tuple contains a string and a numerical value.\n k: The number of minimum records to return.\n\n Returns:\n A list of k tuples representing the minimum records.\n Returns an empty list if the input list is empty or k is 0.\n If k is larger than the length of records, returns all records sorted.\n \"\"\"\n if not records or k == 0:\n return []\n\n if k >= len(records):\n return sorted(records, key=lambda x: x[1])\n\n return sorted(records, key=lambda x: x[1])[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(records, k):\n \"\"\"\n Finds the minimum k records from a list of tuples.\n\n Args:\n records: A list of tuples, where each tuple represents a record.\n k: The number of minimum records to return.\n\n Returns:\n A list of the k records with the smallest values in the second element of each tuple.\n Returns an empty list if the input list is empty or k is 0. Handles cases where k > len(records) by returning all records.\n \"\"\"\n if not records or k == 0:\n return []\n\n sorted_records = sorted(records, key=lambda x: x[1]) # Sort based on the second element\n\n return sorted_records[:k]", "matching_cluster_idx": 2}, {"solution": "import heapq\ndef min_k(records, k):\n \"\"\"\n Finds the minimum k records from a list of tuples based on the second element of each tuple.\n\n Args:\n records: A list of tuples.\n k: The number of minimum records to return.\n\n Returns:\n A list of the k tuples with the smallest second elements.\n Returns an empty list if records is empty or k is 0.\n If k is greater than the length of records, returns all records sorted.\n \"\"\"\n\n if not records or k == 0:\n return []\n\n if k >= len(records):\n return sorted(records, key=lambda x: x[1])\n\n\n return sorted(records, key=lambda x: x[1])[:k]", "matching_cluster_idx": 1}, {"solution": "import heapq\ndef min_k(records, k):\n \"\"\"\n Finds the minimum k records from a list of tuples based on the second element of each tuple.\n\n Args:\n records: A list of tuples.\n k: The number of minimum records to return.\n\n Returns:\n A list of k tuples with the smallest second elements.\n Returns an empty list if records is empty or k is 0.\n Returns all records if k is greater than the length of records.\n \"\"\"\n\n if not records or k == 0:\n return []\n\n if k >= len(records):\n return sorted(records, key=lambda x: x[1])\n\n return sorted(records, key=lambda x: x[1])[:k]", "matching_cluster_idx": 1}, {"solution": "def min_k(records, k):\n \"\"\"\n Finds the minimum k records from a list of tuples.\n\n Args:\n records: A list of tuples, where each tuple contains a string and an integer.\n k: The number of minimum records to return.\n\n Returns:\n A list of the k tuples with the smallest integer values, sorted in ascending order by integer value.\n \"\"\"\n\n if not records:\n return []\n\n sorted_records = sorted(records, key=lambda x: x[1])\n return sorted_records[:k]", "matching_cluster_idx": 2}, {"solution": "import heapq\ndef min_k(records, k):\n \"\"\"\n Finds the minimum k records from a list of tuples.\n\n Args:\n records: A list of tuples, where each tuple represents a record.\n k: The number of minimum records to return.\n\n Returns:\n A list of k tuples representing the minimum records.\n Returns an empty list if records is empty or k is 0.\n Returns all records if k is greater than or equal to the length of records.\n \"\"\"\n\n if not records or k == 0:\n return []\n if k >= len(records):\n return sorted(records, key=lambda x: x[1])\n\n\n return sorted(records, key=lambda x: x[1])[:k]", "matching_cluster_idx": 1}, {"solution": "def min_k(tuples_list, k):\n \"\"\"\n Finds the minimum k records from a list of tuples based on the second element (numerical value).\n\n Args:\n tuples_list: A list of tuples, where each tuple contains a string and a numerical value.\n k: The number of minimum records to return.\n\n Returns:\n A list of the k tuples with the smallest numerical values, sorted in ascending order by the numerical value.\n Returns an empty list if the input list is empty or k is 0.\n If k is greater than the length of tuples_list, returns all elements sorted.\n \"\"\"\n if not tuples_list or k == 0:\n return []\n \n sorted_tuples = sorted(tuples_list, key=lambda x: x[1])\n return sorted_tuples[:k]", "matching_cluster_idx": 1}, {"solution": "def min_k(records, k):\n \"\"\"\n Finds the minimum k records from a list of tuples, where the second element of each tuple is used for comparison.\n\n Args:\n records: A list of tuples.\n k: The number of minimum records to return.\n\n Returns:\n A list of k tuples with the smallest second elements, sorted in ascending order by the second element.\n Returns an empty list if the input list is empty or k is 0.\n Returns the entire sorted list if k is greater than or equal to the length of the input list.\n \"\"\"\n if not records or k == 0:\n return []\n\n if k >= len(records):\n return sorted(records, key=lambda x: x[1])\n\n return sorted(records, key=lambda x: x[1])[:k]", "matching_cluster_idx": 1}, {"solution": "def min_k(records, k):\n \"\"\"\n Finds the minimum k records from a list of tuples.\n\n Args:\n records: A list of tuples, where each tuple represents a record.\n k: The number of minimum records to return.\n\n Returns:\n A list of tuples containing the k records with the smallest values in the second element of each tuple.\n Returns an empty list if the input list is empty or k is 0.\n Returns the entire input list if k is greater than or equal to the length of the input list.\n\n \"\"\"\n if not records or k == 0:\n return []\n if k >= len(records):\n return records\n\n return sorted(records, key=lambda x: x[1])[:k]", "matching_cluster_idx": 1}, {"solution": "def min_k(records, k):\n \"\"\"\n Finds the minimum k records from a list of tuples.\n\n Args:\n records: A list of tuples, where each tuple contains a string and an integer.\n k: The number of minimum records to return.\n\n Returns:\n A list of tuples representing the minimum k records, sorted in ascending order based on the integer value.\n Returns an empty list if the input list is empty or k is 0.\n \"\"\"\n if not records or k == 0:\n return []\n\n # Sort the records based on the integer value in ascending order\n sorted_records = sorted(records, key=lambda x: x[1])\n\n # Return the first k records\n return sorted_records[:k]", "matching_cluster_idx": 2}, {"solution": "import heapq\ndef min_k(records, k):\n \"\"\"\n Finds the minimum k records from a list of tuples.\n\n Args:\n records: A list of tuples, where each tuple represents a record.\n k: The number of minimum records to return.\n\n Returns:\n A list of k tuples representing the minimum records.\n Returns an empty list if the input list is empty or k is 0.\n \"\"\"\n\n if not records or k == 0:\n return []\n\n return sorted(records, key=lambda x: x[1])[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(records, k):\n \"\"\"\n Finds the minimum k records from a list of tuples.\n\n Args:\n records: A list of tuples, where each tuple represents a record \n and the second element of each tuple is the value to compare.\n k: The number of minimum records to return.\n\n Returns:\n A list of the k records with the smallest values, sorted in ascending order.\n Returns an empty list if the input list is empty or k is 0.\n If k is larger than the number of records, returns all records sorted.\n \"\"\"\n\n if not records or k == 0:\n return []\n\n sorted_records = sorted(records, key=lambda x: x[1]) # Sort based on the second element of each tuple\n\n return sorted_records[:k]", "matching_cluster_idx": 1}, {"solution": "def min_k(records, k):\n \"\"\"\n Finds the minimum k records from a list of tuples.\n\n Args:\n records: A list of tuples, where each tuple represents a record \n and the second element of each tuple is a numerical value.\n k: The number of minimum records to return.\n\n Returns:\n A list containing the k records with the smallest numerical values, \n sorted in ascending order based on the numerical value.\n Returns an empty list if records is empty or k is 0.\n \"\"\"\n if not records or k == 0:\n return []\n\n sorted_records = sorted(records, key=lambda x: x[1]) # Sort based on the second element\n return sorted_records[:k]\nrecords = [('Manjeet', 10), ('Akshat', 4), ('Akash', 2), ('Nikhil', 8)]\nk = 2", "matching_cluster_idx": 1}, {"solution": "def min_k(records, k):\n \"\"\"\n Finds the minimum k records from a list of tuples.\n\n Args:\n records: A list of tuples, where each tuple contains a string and an integer.\n k: The number of minimum records to return.\n\n Returns:\n A list of tuples representing the minimum k records, sorted in ascending order based on the integer value.\n Returns an empty list if the input list is empty or k is 0.\n \"\"\"\n\n if not records or k == 0:\n return []\n\n sorted_records = sorted(records, key=lambda x: x[1])\n return sorted_records[:k]", "matching_cluster_idx": 1}]}, "Mbpp/754": {"dps": 89.65517241379311, "dps_norm": 87.5, "pass@1": 100.0, "profiled": [{"solution": "def extract_index_list(l1, l2, l3):\n \"\"\"\n Finds common elements from three lists that appear at the same index.\n\n Args:\n l1: The first list.\n l2: The second list.\n l3: The third list.\n\n Returns:\n A list of common elements.\n \"\"\"\n min_len = min(len(l1), len(l2), len(l3))\n common_elements = []\n for i in range(min_len):\n if l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n \"\"\"\n Finds common elements from three lists that appear at the same index.\n\n Args:\n l1: The first list.\n l2: The second list.\n l3: The third list.\n\n Returns:\n A list of common elements.\n \"\"\"\n common_elements = []\n min_len = min(len(l1), len(l2), len(l3))\n for i in range(min_len):\n if l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n \"\"\"\n Finds common elements in three lists that appear at the same index.\n\n Args:\n l1: The first list.\n l2: The second list.\n l3: The third list.\n\n Returns:\n A list of common elements.\n \"\"\"\n common_elements = []\n min_length = min(len(l1), len(l2), len(l3))\n for i in range(min_length):\n if l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n \"\"\"\n Finds common elements from three lists that appear at the same index.\n\n Args:\n l1: The first list.\n l2: The second list.\n l3: The third list.\n\n Returns:\n A list of common elements.\n \"\"\"\n min_len = min(len(l1), len(l2), len(l3))\n common_elements = []\n for i in range(min_len):\n if l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n \"\"\"\n Finds common elements from three lists that appear at the same index.\n\n Args:\n l1: The first list.\n l2: The second list.\n l3: The third list.\n\n Returns:\n A list of common elements.\n \"\"\"\n common_elements = []\n min_len = min(len(l1), len(l2), len(l3))\n for i in range(min_len):\n if l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n \"\"\"\n Finds common elements in three lists at the same index.\n\n Args:\n l1: The first list.\n l2: The second list.\n l3: The third list.\n\n Returns:\n A list containing the common elements.\n \"\"\"\n common_elements = []\n min_len = min(len(l1), len(l2), len(l3))\n for i in range(min_len):\n if l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n \"\"\"\n Finds common elements from three lists that appear at the same index.\n\n Args:\n l1: The first list.\n l2: The second list.\n l3: The third list.\n\n Returns:\n A list containing the common elements.\n \"\"\"\n common_elements = []\n min_len = min(len(l1), len(l2), len(l3))\n for i in range(min_len):\n if l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n \"\"\"\n Finds common elements from three lists that appear at the same index.\n\n Args:\n l1: The first list.\n l2: The second list.\n l3: The third list.\n\n Returns:\n A list of common elements.\n \"\"\"\n min_len = min(len(l1), len(l2), len(l3))\n common_elements = []\n for i in range(min_len):\n if l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n \"\"\"\n Finds common elements from three lists that appear at the same index.\n\n Args:\n l1: The first list.\n l2: The second list.\n l3: The third list.\n\n Returns:\n A list of common elements.\n \"\"\"\n common_elements = []\n min_len = min(len(l1), len(l2), len(l3))\n for i in range(min_len):\n if l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n \"\"\"\n Finds common elements from three lists that appear at the same index.\n\n Args:\n l1: The first list.\n l2: The second list.\n l3: The third list.\n\n Returns:\n A list of common elements.\n \"\"\"\n\n min_len = min(len(l1), len(l2), len(l3))\n common_elements = []\n\n for i in range(min_len):\n if l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n \"\"\"\n Finds common elements from three lists that appear at the same index.\n\n Args:\n l1: The first list.\n l2: The second list.\n l3: The third list.\n\n Returns:\n A list of common elements.\n \"\"\"\n common_elements = []\n min_len = min(len(l1), len(l2), len(l3))\n for i in range(min_len):\n if l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n result = []\n min_len = min(len(l1), len(l2), len(l3))\n for i in range(min_len):\n if l1[i] == l2[i] and l2[i] == l3[i]:\n result.append(l1[i])\n return result", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n \"\"\"\n Finds common elements in three lists that appear at the same index.\n\n Args:\n l1: The first list.\n l2: The second list.\n l3: The third list.\n\n Returns:\n A list containing the common elements.\n \"\"\"\n min_len = min(len(l1), len(l2), len(l3))\n common_elements = []\n for i in range(min_len):\n if l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n \"\"\"\n Finds common elements from three lists that appear at the same index.\n\n Args:\n l1: The first list.\n l2: The second list.\n l3: The third list.\n\n Returns:\n A list containing the common elements.\n \"\"\"\n min_len = min(len(l1), len(l2), len(l3))\n common_elements = []\n for i in range(min_len):\n if l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n \"\"\"\n Finds common elements in three lists at the same index.\n\n Args:\n l1: The first list.\n l2: The second list.\n l3: The third list.\n\n Returns:\n A list of common elements.\n \"\"\"\n common_elements = []\n min_len = min(len(l1), len(l2), len(l3))\n for i in range(min_len):\n if l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n \"\"\"\n Finds common elements in three lists at the same index.\n\n Args:\n l1: The first list.\n l2: The second list.\n l3: The third list.\n\n Returns:\n A list of common elements.\n \"\"\"\n common_elements = []\n min_len = min(len(l1), len(l2), len(l3))\n for i in range(min_len):\n if l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n common_elements = []\n min_len = min(len(l1), len(l2), len(l3))\n for i in range(min_len):\n if l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n \"\"\"\n Finds common elements from three lists that appear at the same index.\n\n Args:\n l1: The first list.\n l2: The second list.\n l3: The third list.\n\n Returns:\n A list of common elements.\n \"\"\"\n common_elements = []\n min_len = min(len(l1), len(l2), len(l3))\n for i in range(min_len):\n if l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n \"\"\"\n Finds common elements from three lists that appear at the same index.\n\n Args:\n l1: The first list.\n l2: The second list.\n l3: The third list.\n\n Returns:\n A list of common elements.\n \"\"\"\n min_len = min(len(l1), len(l2), len(l3))\n common_elements = []\n for i in range(min_len):\n if l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n \"\"\"\n Finds common elements in three lists at the same index.\n\n Args:\n l1: The first list.\n l2: The second list.\n l3: The third list.\n\n Returns:\n A list containing the common elements.\n \"\"\"\n min_len = min(len(l1), len(l2), len(l3))\n common_elements = []\n for i in range(min_len):\n if l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n return common_elements", "matching_cluster_idx": 6}]}, "Mbpp/755": {"dps": 96.95796460176992, "dps_norm": 98.95833333333333, "pass@1": 16.0, "profiled": [{"solution": "def second_smallest(numbers):\n \"\"\"\n Finds the second smallest number in a list.\n\n Args:\n numbers: A list of numbers.\n\n Returns:\n The second smallest number in the list, or None if the list has fewer than 2 unique elements.\n \"\"\"\n if len(numbers) < 2:\n return None\n\n unique_numbers = sorted(list(set(numbers))) # Remove duplicates and sort\n\n if len(unique_numbers) < 2:\n return None\n\n return unique_numbers[1]", "matching_cluster_idx": 5}, {"solution": "def second_smallest(numbers):\n \"\"\"\n Finds the second smallest number in a list.\n\n Args:\n numbers: A list of numbers.\n\n Returns:\n The second smallest number in the list, or None if the list has fewer than two unique elements.\n \"\"\"\n\n if len(numbers) < 2:\n return None\n\n unique_numbers = sorted(list(set(numbers)))\n\n if len(unique_numbers) < 2:\n return None\n \n return unique_numbers[1]", "matching_cluster_idx": 5}, {"solution": "def second_smallest(numbers):\n \"\"\"\n Finds the second smallest number in a list.\n\n Args:\n numbers: A list of numbers.\n\n Returns:\n The second smallest number in the list, or None if the list \n has fewer than two distinct elements.\n \"\"\"\n if len(numbers) < 2:\n return None\n\n unique_numbers = sorted(list(set(numbers))) # Remove duplicates and sort\n\n if len(unique_numbers) < 2:\n return None\n\n return unique_numbers[1]", "matching_cluster_idx": 5}, {"solution": "def second_smallest(numbers):\n \"\"\"\n Finds the second smallest number in a list.\n\n Args:\n numbers: A list of numbers.\n\n Returns:\n The second smallest number in the list.\n Returns the smallest if the list has only one distinct element.\n Returns None if the list is empty or has only one element.\n\n \"\"\"\n if not numbers or len(set(numbers)) < 2: # Handle empty or single unique element lists\n return None\n\n unique_numbers = sorted(list(set(numbers)))\n return unique_numbers[1]", "matching_cluster_idx": 4}, {"solution": "import heapq\ndef second_smallest(numbers):\n \"\"\"\n Finds the second smallest number in a list.\n\n Args:\n numbers: A list of numbers.\n\n Returns:\n The second smallest number in the list, or the smallest if there is no second smallest.\n Returns None if the list has less than 2 elements or contains only one unique element.\n\n \"\"\"\n if len(numbers) < 2:\n return None\n\n unique_numbers = sorted(list(set(numbers)))\n\n if len(unique_numbers) < 2:\n return None\n \n return unique_numbers[1]", "matching_cluster_idx": 5}, {"solution": "def second_smallest(numbers):\n \"\"\"\n Finds the second smallest number in a list.\n\n Args:\n numbers: A list of numbers.\n\n Returns:\n The second smallest number in the list, or None if the list has fewer than two distinct elements.\n \"\"\"\n if len(numbers) < 2:\n return None\n\n # Remove duplicates and sort the list\n unique_numbers = sorted(list(set(numbers)))\n\n if len(unique_numbers) < 2:\n return None\n \n return unique_numbers[1]", "matching_cluster_idx": 5}, {"solution": "def second_smallest(numbers):\n \"\"\"\n Finds the second smallest number in a list.\n\n Args:\n numbers: A list of numbers.\n\n Returns:\n The second smallest number in the list, or None if the list has fewer than two distinct elements.\n \"\"\"\n if len(numbers) < 2:\n return None\n\n unique_numbers = sorted(list(set(numbers))) # Remove duplicates and sort\n\n if len(unique_numbers) < 2:\n return None\n\n return unique_numbers[1]", "matching_cluster_idx": 5}, {"solution": "import heapq\ndef second_smallest(numbers):\n \"\"\"\n Finds the second smallest number in a list.\n\n Args:\n numbers: A list of numbers.\n\n Returns:\n The second smallest number in the list, or None if the list has fewer than 2 unique elements.\n \"\"\"\n if len(numbers) < 2:\n return None\n\n unique_numbers = sorted(list(set(numbers)))\n\n if len(unique_numbers) < 2:\n return None\n\n return unique_numbers[1]", "matching_cluster_idx": 5}, {"solution": "def second_smallest(numbers):\n \"\"\"\n Finds the second smallest number in a list.\n\n Args:\n numbers: A list of numbers.\n\n Returns:\n The second smallest number in the list, or None if the list has fewer than 2 unique elements.\n \"\"\"\n\n if len(numbers) < 2:\n return None\n\n unique_numbers = sorted(list(set(numbers))) # Remove duplicates and sort\n\n if len(unique_numbers) < 2:\n return None\n\n return unique_numbers[1]", "matching_cluster_idx": 5}, {"solution": "def second_smallest(nums):\n \"\"\"\n Finds the second smallest number in a list.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n The second smallest number in the list, or None if the list has fewer than 2 unique elements.\n \"\"\"\n unique_nums = sorted(list(set(nums))) # Remove duplicates and sort\n if len(unique_nums) < 2:\n return None\n return unique_nums[1]", "matching_cluster_idx": 5}, {"solution": "def second_smallest(numbers):\n \"\"\"\n Finds the second smallest number in a list.\n\n Args:\n numbers: A list of numbers.\n\n Returns:\n The second smallest number in the list, or None if the list has fewer than two distinct elements.\n \"\"\"\n if len(numbers) < 2:\n return None\n\n unique_numbers = sorted(list(set(numbers)))\n\n if len(unique_numbers) < 2:\n return None\n\n return unique_numbers[1]", "matching_cluster_idx": 5}, {"solution": "def second_smallest(numbers):\n \"\"\"\n Finds the second smallest number in a list.\n\n Args:\n numbers: A list of numbers.\n\n Returns:\n The second smallest number in the list, or None if the list has fewer than two distinct elements.\n \"\"\"\n if len(numbers) < 2:\n return None\n\n unique_numbers = sorted(list(set(numbers))) # Remove duplicates and sort\n\n if len(unique_numbers) < 2:\n return None\n\n return unique_numbers[1]", "matching_cluster_idx": 5}, {"solution": "import heapq\ndef second_smallest(numbers):\n \"\"\"\n Finds the second smallest number in a list.\n\n Args:\n numbers: A list of numbers.\n\n Returns:\n The second smallest number in the list, or None if the list has fewer than two unique elements.\n \"\"\"\n if len(numbers) < 2:\n return None\n\n unique_numbers = sorted(list(set(numbers))) # Remove duplicates and sort\n\n if len(unique_numbers) < 2:\n return None\n\n return unique_numbers[1]", "matching_cluster_idx": 5}, {"solution": "def second_smallest(numbers):\n \"\"\"\n Finds the second smallest number in a list.\n\n Args:\n numbers: A list of numbers.\n\n Returns:\n The second smallest number in the list, or None if the list has fewer than 2 unique elements.\n \"\"\"\n if len(numbers) < 2:\n return None\n\n unique_numbers = sorted(list(set(numbers))) # Remove duplicates and sort\n\n if len(unique_numbers) < 2:\n return None\n\n return unique_numbers[1]", "matching_cluster_idx": 5}, {"solution": "def second_smallest(numbers):\n \"\"\"\n Finds the second smallest number in a list.\n\n Args:\n numbers: A list of numbers.\n\n Returns:\n The second smallest number in the list, or None if the list has fewer than two distinct elements.\n \"\"\"\n if len(numbers) < 2:\n return None\n\n unique_numbers = sorted(list(set(numbers)))\n\n if len(unique_numbers) < 2:\n return None\n \n return unique_numbers[1]", "matching_cluster_idx": 5}, {"solution": "def second_smallest(numbers):\n \"\"\"\n Finds the second smallest number in a list.\n\n Args:\n numbers: A list of numbers.\n\n Returns:\n The second smallest number in the list, or None if the list \n has fewer than two distinct elements.\n \"\"\"\n if len(numbers) < 2:\n return None\n\n unique_numbers = sorted(list(set(numbers))) # Remove duplicates and sort\n\n if len(unique_numbers) < 2:\n return None\n \n return unique_numbers[1]", "matching_cluster_idx": 5}]}, "Mbpp/757": {"dps": null, "dps_norm": null, "pass@1": 0.0, "profiled": []}, "Mbpp/758": {"dps": 70.85907335907335, "dps_norm": 78.125, "pass@1": 100.0, "profiled": [{"solution": "from collections import defaultdict\ndef unique_sublists(list_of_lists):\n \"\"\"\n Counts the occurrences of unique sublists (converted to tuples) within a list of lists.\n\n Args:\n list_of_lists: A list of lists.\n\n Returns:\n A dictionary where keys are tuples representing the unique sublists and values are their counts.\n \"\"\"\n\n counts = defaultdict(int) # Use defaultdict to simplify counting\n\n for sublist in list_of_lists:\n counts[tuple(sublist)] += 1\n\n return dict(counts) # Convert back to a regular dict", "matching_cluster_idx": 5}, {"solution": "from collections import defaultdict\ndef unique_sublists(lst):\n \"\"\"Counts the occurrences of unique sublists (converted to tuples) within a list.\n\n Args:\n lst: A list of lists.\n\n Returns:\n A dictionary where keys are tuples (representing unique sublists) and values\n are their counts.\n \"\"\"\n counts = defaultdict(int)\n for sublist in lst:\n counts[tuple(sublist)] += 1\n return dict(counts)", "matching_cluster_idx": 5}, {"solution": "def unique_sublists(lst):\n \"\"\"\n Counts the occurrences of unique sublists within a list.\n\n Args:\n lst: A list containing sublists.\n\n Returns:\n A dictionary where keys are tuples representing unique sublists \n and values are their counts within the original list.\n \"\"\"\n counts = {}\n for sublist in lst:\n tuple_sublist = tuple(sublist)\n if tuple_sublist in counts:\n counts[tuple_sublist] += 1\n else:\n counts[tuple_sublist] = 1\n return counts", "matching_cluster_idx": 6}, {"solution": "from collections import Counter\ndef unique_sublists(lst):\n \"\"\"Counts the occurrences of unique sublists (converted to tuples) within a list.\n\n Args:\n lst: The input list containing sublists.\n\n Returns:\n A dictionary where keys are tuples representing unique sublists and values are their counts.\n \"\"\"\n\n tuple_list = [tuple(sublist) for sublist in lst]\n return dict(Counter(tuple_list))", "matching_cluster_idx": 7}, {"solution": "from collections import defaultdict\ndef unique_sublists(lst):\n \"\"\"\n Counts the occurrences of unique sublists within a list.\n\n Args:\n lst: A list of lists.\n\n Returns:\n A dictionary where keys are tuples representing the unique sublists \n and values are their counts.\n \"\"\"\n counts = defaultdict(int) # Use defaultdict for automatic initialization\n for sublist in lst:\n counts[tuple(sublist)] += 1\n return dict(counts) # Return a regular dict", "matching_cluster_idx": 5}, {"solution": "from collections import defaultdict\ndef unique_sublists(lst):\n \"\"\"Counts the occurrences of sublists (converted to tuples) within a list.\n\n Args:\n lst: The input list of lists.\n\n Returns:\n A dictionary where keys are tuples representing unique sublists and values are their counts.\n \"\"\"\n counts = defaultdict(int)\n for sublist in lst:\n counts[tuple(sublist)] += 1\n return dict(counts)", "matching_cluster_idx": 5}, {"solution": "from collections import defaultdict\ndef unique_sublists(lst):\n \"\"\"\n Counts the occurrences of unique sublists within a list.\n\n Args:\n lst: A list of lists.\n\n Returns:\n A dictionary where keys are tuples (converted from sublists) and values\n are their counts.\n \"\"\"\n counts = defaultdict(int)\n for sublist in lst:\n counts[tuple(sublist)] += 1\n return dict(counts)", "matching_cluster_idx": 5}, {"solution": "from collections import defaultdict\ndef unique_sublists(lst):\n \"\"\"\n Counts the occurrences of unique sublists within a list.\n\n Args:\n lst: A list of lists.\n\n Returns:\n A dictionary where keys are tuples representing the sublists and values are their counts.\n \"\"\"\n counts = defaultdict(int)\n for sublist in lst:\n counts[tuple(sublist)] += 1\n return dict(counts)", "matching_cluster_idx": 5}, {"solution": "from collections import defaultdict\ndef unique_sublists(lst):\n \"\"\"\n Counts the occurrences of unique sublists (converted to tuples) within a list.\n\n Args:\n lst: A list of lists.\n\n Returns:\n A dictionary where keys are tuples representing the unique sublists and values are their counts.\n \"\"\"\n counts = defaultdict(int)\n for sublist in lst:\n counts[tuple(sublist)] += 1\n return dict(counts)", "matching_cluster_idx": 5}, {"solution": "def unique_sublists(lst):\n \"\"\"Counts the occurrences of unique sublists (converted to tuples) within a list.\n\n Args:\n lst: A list containing sublists.\n\n Returns:\n A dictionary where keys are tuples representing unique sublists and values are their counts.\n \"\"\"\n\n counts = {}\n for sublist in lst:\n tuple_sublist = tuple(sublist) # Convert list to tuple for dictionary key\n counts[tuple_sublist] = counts.get(tuple_sublist, 0) + 1\n return counts", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(lst):\n \"\"\"\n Counts the occurrences of unique sublists (converted to tuples) within a list.\n\n Args:\n lst: A list of lists.\n\n Returns:\n A dictionary where keys are tuples representing the unique sublists, \n and values are their counts.\n \"\"\"\n counts = {}\n for sublist in lst:\n sublist_tuple = tuple(sublist)\n if sublist_tuple in counts:\n counts[sublist_tuple] += 1\n else:\n counts[sublist_tuple] = 1\n return counts", "matching_cluster_idx": 6}, {"solution": "from collections import defaultdict\ndef unique_sublists(lst):\n \"\"\"Counts the occurrences of unique sublists (converted to tuples) within a list.\n\n Args:\n lst: The input list containing sublists.\n\n Returns:\n A dictionary where keys are tuples representing the unique sublists and values are their counts.\n \"\"\"\n\n counts = defaultdict(int)\n for sublist in lst:\n counts[tuple(sublist)] += 1\n return dict(counts)", "matching_cluster_idx": 5}, {"solution": "from collections import defaultdict\ndef unique_sublists(lst):\n \"\"\"\n Counts the occurrences of unique sublists (converted to tuples) within a list.\n\n Args:\n lst: A list of lists.\n\n Returns:\n A dictionary where keys are tuples representing the unique sublists, and values are their counts.\n \"\"\"\n counts = defaultdict(int)\n for sublist in lst:\n counts[tuple(sublist)] += 1\n return dict(counts)", "matching_cluster_idx": 5}, {"solution": "from collections import defaultdict\ndef unique_sublists(lst):\n \"\"\"\n Counts the occurrences of unique sublists (converted to tuples) within a list.\n\n Args:\n lst: A list of lists.\n\n Returns:\n A dictionary where keys are tuples representing the unique sublists and values are their counts.\n \"\"\"\n counts = defaultdict(int)\n for sublist in lst:\n counts[tuple(sublist)] += 1\n return dict(counts)", "matching_cluster_idx": 5}, {"solution": "from collections import defaultdict\ndef unique_sublists(lst):\n \"\"\"\n Counts the occurrences of unique sublists (converted to tuples) within a list.\n\n Args:\n lst: The input list of lists.\n\n Returns:\n A dictionary where keys are tuples representing the unique sublists and values are their counts.\n \"\"\"\n counts = defaultdict(int)\n for sublist in lst:\n counts[tuple(sublist)] += 1\n return dict(counts)", "matching_cluster_idx": 5}, {"solution": "from collections import defaultdict\ndef unique_sublists(lst):\n \"\"\"\n Counts the occurrences of unique sublists (converted to tuples) within a list.\n\n Args:\n lst: The input list of lists.\n\n Returns:\n A dictionary where keys are tuples representing the unique sublists \n and values are their counts.\n \"\"\"\n counts = defaultdict(int)\n for sublist in lst:\n counts[tuple(sublist)] += 1\n return dict(counts)", "matching_cluster_idx": 5}, {"solution": "from collections import defaultdict\ndef unique_sublists(lst):\n \"\"\"\n Counts the occurrences of unique sublists (converted to tuples) within a list.\n\n Args:\n lst: A list of lists.\n\n Returns:\n A dictionary where keys are tuples representing the unique sublists and values are their counts.\n \"\"\"\n counts = defaultdict(int)\n for sublist in lst:\n counts[tuple(sublist)] += 1\n return dict(counts)", "matching_cluster_idx": 5}, {"solution": "from collections import defaultdict\ndef unique_sublists(lst):\n \"\"\"\n Counts the occurrences of unique sublists (converted to tuples) within a list.\n\n Args:\n lst: A list of lists.\n\n Returns:\n A dictionary where keys are tuples representing unique sublists and values are their counts.\n \"\"\"\n\n counts = defaultdict(int)\n for sublist in lst:\n counts[tuple(sublist)] += 1\n return dict(counts)", "matching_cluster_idx": 5}, {"solution": "from collections import defaultdict\ndef unique_sublists(input_list):\n \"\"\"Counts the occurrences of unique sublists within a list.\n\n Args:\n input_list: A list of lists.\n\n Returns:\n A dictionary where keys are tuples representing unique sublists \n and values are their counts.\n \"\"\"\n counts = defaultdict(int)\n for sublist in input_list:\n counts[tuple(sublist)] += 1\n return dict(counts)", "matching_cluster_idx": 5}, {"solution": "from collections import defaultdict\ndef unique_sublists(lst):\n \"\"\"Counts the occurrences of unique sublists (converted to tuples) within a list.\n\n Args:\n lst: A list of lists.\n\n Returns:\n A dictionary where keys are tuples representing unique sublists and values are their counts.\n \"\"\"\n counts = defaultdict(int)\n for sublist in lst:\n counts[tuple(sublist)] += 1\n return dict(counts)", "matching_cluster_idx": 5}]}, "Mbpp/760": {"dps": 32.846715328467155, "dps_norm": 75.0, "pass@1": 100.0, "profiled": [{"solution": "def unique_Element(nums):\n \"\"\"\n Checks if a list contains only one distinct element.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n True if the list contains only one distinct element, False otherwise.\n \"\"\"\n if not nums: # Handle empty list case\n return True\n first_element = nums[0]\n for num in nums:\n if num != first_element:\n return False\n return True", "matching_cluster_idx": 5}, {"solution": "def unique_Element(nums):\n \"\"\"\n Checks if a list contains only one distinct element.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n True if the list contains only one distinct element, False otherwise.\n \"\"\"\n if not nums: # Handle empty list case\n return True\n first = nums[0]\n for num in nums:\n if num != first:\n return False\n return True", "matching_cluster_idx": 5}, {"solution": "def unique_Element(nums):\n \"\"\"\n Checks if a list contains only one distinct element.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n True if the list contains only one distinct element, False otherwise.\n \"\"\"\n if not nums: # Handle empty list case\n return True # Or False, depending on desired behavior for empty lists\n first_element = nums[0]\n for num in nums:\n if num != first_element:\n return False\n return True", "matching_cluster_idx": 5}, {"solution": "def unique_Element(nums):\n \"\"\"\n Checks if a list contains only one distinct element.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n True if the list contains only one distinct element, False otherwise.\n \"\"\"\n if not nums: # Handle empty list case\n return True\n\n first_element = nums[0]\n for num in nums:\n if num != first_element:\n return False\n return True", "matching_cluster_idx": 5}, {"solution": "def unique_Element(nums):\n \"\"\"\n Checks if a list contains only one distinct element.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n True if the list contains only one distinct element, False otherwise.\n \"\"\"\n if not nums: # Handle empty list case\n return True\n \n first_element = nums[0]\n for num in nums:\n if num != first_element:\n return False\n return True", "matching_cluster_idx": 5}, {"solution": "def unique_Element(nums):\n \"\"\"\n Checks if a list contains only one distinct element.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n True if the list contains only one distinct element, False otherwise.\n \"\"\"\n if not nums: # Handle empty list case\n return True \n first_element = nums[0]\n for num in nums:\n if num != first_element:\n return False\n return True", "matching_cluster_idx": 5}, {"solution": "def unique_Element(nums):\n \"\"\"\n Checks if a list contains only one distinct element.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n True if the list contains only one distinct element, False otherwise.\n \"\"\"\n if not nums: # Handle empty list case\n return True\n\n first_element = nums[0]\n for num in nums:\n if num != first_element:\n return False\n return True", "matching_cluster_idx": 5}, {"solution": "def unique_Element(nums):\n \"\"\"\n Checks if a list contains only one distinct element.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n True if the list contains only one distinct element, False otherwise.\n \"\"\"\n if not nums: # Handle empty list case\n return True\n\n first_element = nums[0]\n for num in nums:\n if num != first_element:\n return False\n return True", "matching_cluster_idx": 5}, {"solution": "def unique_Element(nums):\n \"\"\"\n Checks if a list contains only one distinct element.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n True if the list contains only one distinct element, False otherwise.\n \"\"\"\n\n if not nums: # Handle empty list case\n return True\n\n first_element = nums[0]\n for num in nums:\n if num != first_element:\n return False\n return True", "matching_cluster_idx": 5}, {"solution": "def unique_Element(nums):\n \"\"\"\n Checks if a list contains only one distinct element.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n True if the list contains only one distinct element, False otherwise.\n \"\"\"\n if not nums: # Handle empty list case\n return True\n\n first_element = nums[0]\n for num in nums:\n if num != first_element:\n return False\n return True", "matching_cluster_idx": 5}, {"solution": "def unique_Element(nums):\n \"\"\"\n Checks if a list contains only one distinct element.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n True if the list contains only one distinct element, False otherwise.\n \"\"\"\n if not nums: # Handle empty list case\n return True\n first_element = nums[0]\n for num in nums:\n if num != first_element:\n return False\n return True", "matching_cluster_idx": 5}, {"solution": "def unique_Element(nums):\n \"\"\"\n Checks if a list contains only one distinct element.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n True if the list contains only one distinct element, False otherwise.\n \"\"\"\n if not nums: # Handle empty list case\n return False\n first_element = nums[0]\n for num in nums:\n if num != first_element:\n return False\n return True", "matching_cluster_idx": 5}, {"solution": "def unique_Element(nums):\n \"\"\"\n Checks if a list contains only one distinct element.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n True if the list contains only one distinct element, False otherwise.\n \"\"\"\n if not nums: # Handle empty list case\n return True\n\n first_element = nums[0]\n for num in nums:\n if num != first_element:\n return False\n return True", "matching_cluster_idx": 5}, {"solution": "def unique_Element(nums):\n \"\"\"\n Checks if a list contains only one distinct element.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n True if the list contains only one distinct element, False otherwise.\n \"\"\"\n if not nums: # Handle empty list case\n return True \n\n first_element = nums[0]\n for num in nums:\n if num != first_element:\n return False\n return True", "matching_cluster_idx": 5}, {"solution": "def unique_Element(lst):\n \"\"\"\n Checks if a list contains only one distinct element.\n\n Args:\n lst: A list of numbers.\n\n Returns:\n True if the list contains only one distinct element, False otherwise.\n \"\"\"\n if not lst: # Handle empty list case\n return False\n \n first_element = lst[0]\n for element in lst:\n if element != first_element:\n return False\n return True", "matching_cluster_idx": 5}, {"solution": "def unique_Element(nums):\n \"\"\"\n Checks if a list contains only one distinct element.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n True if the list contains only one distinct element, False otherwise.\n \"\"\"\n if not nums: # Handle empty list case\n return True\n \n first_element = nums[0]\n for num in nums:\n if num != first_element:\n return False\n return True", "matching_cluster_idx": 5}, {"solution": "def unique_Element(nums):\n \"\"\"\n Checks if a list contains only one distinct element.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n True if the list contains only one distinct element, False otherwise.\n \"\"\"\n if not nums: # Handle empty list case\n return True # Or False, depending on your desired behavior for empty lists\n\n first_element = nums[0]\n for element in nums:\n if element != first_element:\n return False\n return True", "matching_cluster_idx": 5}, {"solution": "def unique_Element(nums):\n \"\"\"\n Checks if a list contains only one distinct element.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n True if the list contains only one distinct element, False otherwise.\n \"\"\"\n if not nums: # Handle empty list case\n return True # Or False, depending on desired behavior for empty lists\n\n first_element = nums[0]\n for num in nums:\n if num != first_element:\n return False\n return True", "matching_cluster_idx": 5}, {"solution": "def unique_Element(nums):\n \"\"\"\n Checks if a list contains only one distinct element.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n True if the list contains only one distinct element, False otherwise.\n \"\"\"\n if not nums: # Handle empty list case\n return True\n\n first_element = nums[0]\n for element in nums:\n if element != first_element:\n return False\n return True", "matching_cluster_idx": 5}, {"solution": "def unique_Element(nums):\n \"\"\"\n Checks if a list contains only one distinct element.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n True if the list contains only one distinct element, False otherwise.\n \"\"\"\n if not nums: # Handle empty list case\n return True # Or False, depending on desired behavior for empty lists.\n\n first_element = nums[0]\n for num in nums:\n if num != first_element:\n return False\n return True", "matching_cluster_idx": 5}]}, "Mbpp/764": {"dps": 88.88888888888889, "dps_norm": 50.0, "pass@1": 100.0, "profiled": [{"solution": "import re\ndef number_ctr(input_string):\n \"\"\"\n Counts the number of digits in a given string.\n\n Args:\n input_string: The string to analyze.\n\n Returns:\n The number of digits found in the string.\n \"\"\"\n count = 0\n for char in input_string:\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "import re\ndef number_ctr(input_string):\n \"\"\"\n Counts the number of digits in a given string.\n\n Args:\n input_string: The string to analyze.\n\n Returns:\n The number of digits found in the string.\n \"\"\"\n count = 0\n for char in input_string:\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "import re\ndef number_ctr(input_string):\n \"\"\"Counts the number of digits in a string.\"\"\"\n count = 0\n for char in input_string:\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "import re\ndef number_ctr(input_string):\n \"\"\"\n Counts the number of digits in a given string.\n\n Args:\n input_string: The string to analyze.\n\n Returns:\n The number of digits found in the string.\n \"\"\"\n count = 0\n for char in input_string:\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "import re\ndef number_ctr(input_string):\n \"\"\"Counts the number of digits in a given string.\n\n Args:\n input_string: The string to analyze.\n\n Returns:\n The number of digits found in the string.\n \"\"\"\n count = 0\n for char in input_string:\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "import re\ndef number_ctr(input_string):\n \"\"\"\n Counts the number of digits in a given string.\n\n Args:\n input_string: The string to analyze.\n\n Returns:\n The number of digits found in the string.\n \"\"\"\n count = 0\n for char in input_string:\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "import re\ndef number_ctr(input_string):\n \"\"\"\n Counts the number of digits in a given string.\n\n Args:\n input_string: The string to analyze.\n\n Returns:\n The number of digits found in the string.\n \"\"\"\n count = 0\n for char in input_string:\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "import re\ndef number_ctr(input_string):\n \"\"\"\n Counts the number of digits in a given string.\n\n Args:\n input_string: The string to analyze.\n\n Returns:\n The number of digits found in the string.\n \"\"\"\n count = 0\n for char in input_string:\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "import re\ndef number_ctr(input_string):\n \"\"\"\n Counts the number of digits in a given string.\n\n Args:\n input_string: The string to analyze.\n\n Returns:\n The number of digits found in the string.\n \"\"\"\n count = 0\n for char in input_string:\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "import re\ndef number_ctr(input_string):\n \"\"\"\n Counts the number of digits in a given string.\n\n Args:\n input_string: The string to analyze.\n\n Returns:\n The number of digits found in the string.\n \"\"\"\n\n # Using regular expressions for efficiency\n return len(re.findall(r'\\d', input_string))", "matching_cluster_idx": 2}, {"solution": "import re\ndef number_ctr(input_string):\n \"\"\"\n Counts the number of digits in a given string.\n\n Args:\n input_string: The string to analyze.\n\n Returns:\n The number of digits found in the string.\n \"\"\"\n count = 0\n for char in input_string:\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "import re\ndef number_ctr(input_string):\n \"\"\"\n Counts the number of digits in a given string.\n\n Args:\n input_string: The string to analyze.\n\n Returns:\n The number of digits found in the string.\n \"\"\"\n\n count = 0\n for char in input_string:\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(input_string):\n \"\"\"\n Counts the number of digits in a given string.\n\n Args:\n input_string: The string to analyze.\n\n Returns:\n The number of digits found in the string.\n \"\"\"\n count = 0\n for char in input_string:\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "import re\ndef number_ctr(input_string):\n \"\"\"\n Counts the number of digits in a given string.\n\n Args:\n input_string: The string to analyze.\n\n Returns:\n The number of digits found in the string.\n \"\"\"\n\n count = 0\n for char in input_string:\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "import re\ndef number_ctr(input_string):\n \"\"\"Counts the number of digits in a given string.\n\n Args:\n input_string: The string to analyze.\n\n Returns:\n The number of digits found in the string.\n \"\"\"\n count = 0\n for char in input_string:\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "import re\ndef number_ctr(input_string):\n \"\"\"\n Counts the number of digits in a given string.\n\n Args:\n input_string: The string to analyze.\n\n Returns:\n The number of digits in the string.\n \"\"\"\n\n count = 0\n for char in input_string:\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "import re\ndef number_ctr(input_string):\n \"\"\"\n Counts the number of digits in a given string.\n\n Args:\n input_string: The string to analyze.\n\n Returns:\n The number of digits found in the string.\n \"\"\"\n count = 0\n for char in input_string:\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(input_string):\n \"\"\"Counts the number of digits in a given string.\n\n Args:\n input_string: The string to analyze.\n\n Returns:\n The number of digits in the string.\n \"\"\"\n\n count = 0\n for char in input_string:\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(input_string):\n \"\"\"\n Counts the number of digits in a given string.\n\n Args:\n input_string: The string to analyze.\n\n Returns:\n The number of digits found in the string.\n \"\"\"\n\n count = 0\n for char in input_string:\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "import re\ndef number_ctr(input_string):\n \"\"\"\n Counts the number of digits in a given string.\n\n Args:\n input_string: The string to analyze.\n\n Returns:\n The number of digits found in the string.\n \"\"\"\n count = 0\n for char in input_string:\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}]}, "Mbpp/766": {"dps": 55.14018691588785, "dps_norm": 50.0, "pass@1": 100.0, "profiled": [{"solution": "def pair_wise(data):\n \"\"\"\n Returns a list of tuples, where each tuple contains consecutive pairs of items from the input list.\n \"\"\"\n if not data:\n return []\n \n pairs = []\n for i in range(len(data) - 1):\n pairs.append((data[i], data[i+1]))\n \n return pairs", "matching_cluster_idx": 2}, {"solution": "def pair_wise(input_list):\n \"\"\"\n Returns a list of tuples, where each tuple represents a pair of consecutive items in the input list.\n\n Args:\n input_list: A list of items.\n\n Returns:\n A list of tuples.\n \"\"\"\n if not input_list:\n return []\n \n pairs = []\n for i in range(len(input_list) - 1):\n pairs.append((input_list[i], input_list[i+1]))\n return pairs", "matching_cluster_idx": 2}, {"solution": "def pair_wise(data):\n \"\"\"\n Returns a list of tuples, where each tuple represents a pair of consecutive items in the input list.\n \"\"\"\n if not data:\n return []\n pairs = []\n for i in range(len(data) - 1):\n pairs.append((data[i], data[i+1]))\n return pairs", "matching_cluster_idx": 2}, {"solution": "def pair_wise(data):\n \"\"\"\n Returns a list of tuples, where each tuple contains a pair of consecutive items from the input list.\n \"\"\"\n if not data:\n return []\n \n pairs = []\n for i in range(len(data) - 1):\n pairs.append((data[i], data[i+1]))\n return pairs", "matching_cluster_idx": 2}, {"solution": "def pair_wise(input_list):\n \"\"\"\n Returns a list of all pairs of consecutive items in a given list.\n\n Args:\n input_list: A list of items.\n\n Returns:\n A list of tuples, where each tuple represents a pair of consecutive items.\n Returns an empty list if the input list has fewer than two elements.\n \"\"\"\n if len(input_list) < 2:\n return []\n\n pairs = []\n for i in range(len(input_list) - 1):\n pairs.append((input_list[i], input_list[i+1]))\n return pairs", "matching_cluster_idx": 2}, {"solution": "def pair_wise(input_list):\n \"\"\"\n Returns a list of tuples, where each tuple represents a pair of consecutive items in the input list.\n \"\"\"\n if not input_list:\n return []\n\n pairs = []\n for i in range(len(input_list) - 1):\n pairs.append((input_list[i], input_list[i+1]))\n return pairs", "matching_cluster_idx": 2}, {"solution": "def pair_wise(data):\n \"\"\"\n Returns a list of tuples, where each tuple contains a pair of consecutive items from the input list.\n\n Args:\n data: A list of items.\n\n Returns:\n A list of tuples.\n \"\"\"\n\n if not data:\n return []\n\n pairs = []\n for i in range(len(data) - 1):\n pairs.append((data[i], data[i+1]))\n return pairs", "matching_cluster_idx": 2}, {"solution": "def pair_wise(data):\n \"\"\"\n Returns a list of tuples, where each tuple contains a pair of consecutive items from the input list.\n \"\"\"\n if not data:\n return []\n result = []\n for i in range(len(data) - 1):\n result.append((data[i], data[i+1]))\n return result", "matching_cluster_idx": 2}, {"solution": "def pair_wise(data):\n \"\"\"\n Returns a list of all pairs of consecutive items in a given list.\n \"\"\"\n if not data:\n return []\n result = []\n for i in range(len(data) - 1):\n result.append((data[i], data[i+1]))\n return result", "matching_cluster_idx": 2}, {"solution": "def pair_wise(input_list):\n \"\"\"\n Returns a list of tuples, where each tuple contains a pair of consecutive items from the input list.\n \"\"\"\n if not input_list:\n return []\n \n pairs = []\n for i in range(len(input_list) - 1):\n pairs.append((input_list[i], input_list[i+1]))\n return pairs", "matching_cluster_idx": 2}, {"solution": "def pair_wise(data):\n \"\"\"\n Returns a list of tuples, where each tuple contains a pair of consecutive items from the input list.\n \"\"\"\n if not data:\n return []\n pairs = []\n for i in range(len(data) - 1):\n pairs.append((data[i], data[i+1]))\n return pairs", "matching_cluster_idx": 2}, {"solution": "def pair_wise(lst):\n \"\"\"\n Returns a list of all pairs of consecutive items in a given list.\n\n Args:\n lst: The input list.\n\n Returns:\n A list of tuples, where each tuple represents a pair of consecutive items.\n \"\"\"\n if not lst:\n return []\n result = []\n for i in range(len(lst) - 1):\n result.append((lst[i], lst[i+1]))\n return result", "matching_cluster_idx": 2}, {"solution": "def pair_wise(input_list):\n \"\"\"\n Returns a list of tuples, where each tuple represents a pair of consecutive items from the input list.\n \"\"\"\n if not input_list:\n return []\n \n pairs = []\n for i in range(len(input_list) - 1):\n pairs.append((input_list[i], input_list[i+1]))\n return pairs", "matching_cluster_idx": 2}, {"solution": "def pair_wise(data):\n \"\"\"Returns a list of tuples representing all pairs of consecutive items in the input list.\n\n Args:\n data: A list of items.\n\n Returns:\n A list of tuples, where each tuple contains a pair of consecutive items.\n Returns an empty list if the input list has fewer than two elements.\n \"\"\"\n if len(data) < 2:\n return []\n\n pairs = []\n for i in range(len(data) - 1):\n pairs.append((data[i], data[i+1]))\n return pairs", "matching_cluster_idx": 2}, {"solution": "def pair_wise(input_list):\n \"\"\"\n Returns a list of all pairs of consecutive items in a given list.\n\n Args:\n input_list: A list of items.\n\n Returns:\n A list of tuples, where each tuple represents a pair of consecutive items.\n \"\"\"\n if not input_list:\n return []\n\n pairs = []\n for i in range(len(input_list) - 1):\n pairs.append((input_list[i], input_list[i+1]))\n return pairs", "matching_cluster_idx": 2}, {"solution": "def pair_wise(data):\n \"\"\"\n Returns a list of all pairs of consecutive items in a given list.\n\n Args:\n data: A list of items.\n\n Returns:\n A list of tuples, where each tuple represents a pair of consecutive items.\n Returns an empty list if the input list has fewer than two elements.\n \"\"\"\n if len(data) < 2:\n return []\n \n pairs = []\n for i in range(len(data) - 1):\n pairs.append((data[i], data[i+1]))\n return pairs", "matching_cluster_idx": 2}, {"solution": "def pair_wise(nums):\n \"\"\"\n Returns a list of tuples representing consecutive pairs of items in the input list.\n \"\"\"\n pairs = []\n for i in range(len(nums) - 1):\n pairs.append((nums[i], nums[i+1]))\n return pairs", "matching_cluster_idx": 2}, {"solution": "def pair_wise(data):\n \"\"\"\n Returns a list of tuples, where each tuple represents a pair of consecutive items in the input list.\n \"\"\"\n if not data: # Handle empty list case\n return []\n \n pairs = []\n for i in range(len(data) - 1):\n pairs.append((data[i], data[i+1]))\n return pairs", "matching_cluster_idx": 2}, {"solution": "def pair_wise(data):\n \"\"\"\n Returns a list of tuples, where each tuple contains a pair of consecutive items in the input list.\n\n Args:\n data: A list of items.\n\n Returns:\n A list of tuples.\n \"\"\"\n if not data:\n return []\n result = []\n for i in range(len(data) - 1):\n result.append((data[i], data[i+1]))\n return result", "matching_cluster_idx": 2}, {"solution": "def pair_wise(lst):\n \"\"\"\n Returns a list of all pairs of consecutive items in a given list.\n \"\"\"\n if not lst: # Handle empty list case\n return []\n \n pairs = []\n for i in range(len(lst) - 1):\n pairs.append((lst[i], lst[i+1]))\n return pairs", "matching_cluster_idx": 2}]}, "Mbpp/775": {"dps": 94.39999999999999, "dps_norm": 71.42857142857143, "pass@1": 100.0, "profiled": [{"solution": "def odd_position(nums):\n \"\"\"\n Checks if every element at an odd index in a list is odd.\n\n Args:\n nums: A list of integers.\n\n Returns:\n True if every element at an odd index is odd, False otherwise.\n Returns True if the list is empty or has only one element (as there are no odd indices to check in these cases).\n \"\"\"\n if len(nums) <= 1: # Handle empty or single-element lists\n return True\n\n for i in range(1, len(nums), 2):\n if nums[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(nums):\n \"\"\"\n Checks if every element at an odd index in a list is odd.\n\n Args:\n nums: A list of integers.\n\n Returns:\n True if every element at an odd index is odd, False otherwise.\n \"\"\"\n for i in range(1, len(nums), 2):\n if nums[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(nums):\n \"\"\"\n Checks if every element at an odd index in a list is odd.\n\n Args:\n nums: A list of integers.\n\n Returns:\n True if every element at an odd index is odd, False otherwise.\n Returns True for an empty list.\n \"\"\"\n for i in range(1, len(nums), 2): # Iterate through odd indices\n if nums[i] % 2 == 0: # Check if the element is even\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(nums):\n \"\"\"\n Checks if every element at an odd index in a list is odd.\n\n Args:\n nums: A list of integers.\n\n Returns:\n True if every element at an odd index is odd, False otherwise.\n \"\"\"\n for i in range(1, len(nums), 2): # Iterate through odd indices\n if nums[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(nums):\n \"\"\"\n Checks if every element at an odd index is odd.\n\n Args:\n nums: A list of integers.\n\n Returns:\n True if every element at an odd index is odd, False otherwise.\n \"\"\"\n\n for i in range(1, len(nums), 2):\n if nums[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(nums):\n \"\"\"\n Checks if every element at an odd index in a list is odd.\n\n Args:\n nums: A list of integers.\n\n Returns:\n True if every element at an odd index is odd, False otherwise.\n \"\"\"\n for i in range(1, len(nums), 2): # Iterate through odd indices\n if nums[i] % 2 == 0: # Check if the element is even\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(nums):\n \"\"\"\n Checks if every element at an odd index in a list is odd.\n\n Args:\n nums: A list of integers.\n\n Returns:\n True if every element at an odd index is odd, False otherwise.\n \"\"\"\n for i in range(1, len(nums), 2):\n if nums[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(nums):\n \"\"\"\n Checks whether every odd index contains an odd number in a given list.\n\n Args:\n nums: A list of integers.\n\n Returns:\n True if every odd index contains an odd number, False otherwise.\n \"\"\"\n for i in range(1, len(nums), 2):\n if nums[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(nums):\n \"\"\"\n Checks if every element at an odd index is an odd number.\n\n Args:\n nums: A list of integers.\n\n Returns:\n True if every element at an odd index is odd, False otherwise.\n \"\"\"\n for i in range(1, len(nums), 2): # Iterate through odd indices\n if nums[i] % 2 == 0: # Check if the number at the odd index is even\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(nums):\n \"\"\"\n Checks if every element at an odd index in a list is odd.\n\n Args:\n nums: A list of integers.\n\n Returns:\n True if every element at an odd index is odd, False otherwise.\n \"\"\"\n for i in range(1, len(nums), 2):\n if nums[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(nums):\n \"\"\"\n Checks if every element at an odd index in a list is odd.\n\n Args:\n nums: A list of integers.\n\n Returns:\n True if every element at an odd index is odd, False otherwise.\n \"\"\"\n for i in range(1, len(nums), 2): # Iterate through odd indices\n if nums[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(nums):\n \"\"\"\n Checks if every element at an odd index in a list is odd.\n\n Args:\n nums: A list of integers.\n\n Returns:\n True if every element at an odd index is odd, False otherwise.\n \"\"\"\n for i in range(1, len(nums), 2): # Iterate through odd indices\n if nums[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(nums):\n \"\"\"\n Checks if every element at an odd index in a list is odd.\n\n Args:\n nums: A list of integers.\n\n Returns:\n True if every element at an odd index is odd, False otherwise.\n \"\"\"\n for i in range(1, len(nums), 2): # Iterate through odd indices\n if nums[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(nums):\n \"\"\"\n Checks if every element at an odd index in a list is odd.\n\n Args:\n nums: A list of integers.\n\n Returns:\n True if every element at an odd index is odd, False otherwise.\n \"\"\"\n for i in range(1, len(nums), 2):\n if nums[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(nums):\n \"\"\"\n Checks if every element at an odd index in a list is odd.\n\n Args:\n nums: A list of integers.\n\n Returns:\n True if every element at an odd index is odd, False otherwise.\n \"\"\"\n for i in range(1, len(nums), 2): # Iterate through odd indices\n if nums[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n \"\"\"\n Checks if every element at an odd index in a list is odd.\n\n Args:\n lst: The input list of numbers.\n\n Returns:\n True if every element at an odd index is odd, False otherwise.\n \"\"\"\n for i in range(1, len(lst), 2): # Iterate through odd indices\n if lst[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(nums):\n \"\"\"\n Checks if every element at an odd index in a list is odd.\n\n Args:\n nums: A list of integers.\n\n Returns:\n True if every element at an odd index is odd, False otherwise.\n \"\"\"\n for i in range(1, len(nums), 2): # Iterate through odd indices\n if nums[i] % 2 == 0: # Check if the element is even\n return False # Return False if an even number is found at an odd index\n return True # Return True if all elements at odd indices are odd", "matching_cluster_idx": 4}, {"solution": "def odd_position(nums):\n \"\"\"\n Checks if every element at an odd index in a list is odd.\n\n Args:\n nums: A list of integers.\n\n Returns:\n True if every element at an odd index is odd, False otherwise.\n \"\"\"\n for i in range(1, len(nums), 2):\n if nums[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(nums):\n \"\"\"\n Checks if every element at an odd index is odd.\n\n Args:\n nums: A list of integers.\n\n Returns:\n True if every element at an odd index is odd, False otherwise.\n \"\"\"\n for i in range(1, len(nums), 2):\n if nums[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(nums):\n \"\"\"\n Checks if every element at an odd index in a list is an odd number.\n\n Args:\n nums: A list of integers.\n\n Returns:\n True if every element at an odd index is odd, False otherwise.\n \"\"\"\n for i in range(1, len(nums), 2):\n if nums[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}]}, "Mbpp/777": {"dps": null, "dps_norm": null, "pass@1": 0.0, "profiled": []}, "Mbpp/781": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "import math\ndef count_divisors(n):\n \"\"\"\n Checks if the number of divisors of n is even.\n\n Args:\n n: An integer.\n\n Returns:\n True if the count of divisors is even, False otherwise.\n \"\"\"\n if n == 0:\n return True # Technically infinite divisors, but assuming True for this case to avoid ZeroDivisionError\n\n count = 0\n sqrt_n = int(math.sqrt(n))\n for i in range(1, sqrt_n + 1):\n if n % i == 0:\n if n // i == i: # perfect square divisor\n count += 1\n else:\n count += 2 # i and n/i are both divisors\n\n return count % 2 == 0", "matching_cluster_idx": 4}, {"solution": "import math\ndef count_divisors(n):\n \"\"\"\n Checks if the number of divisors of n is even.\n\n Args:\n n: An integer.\n\n Returns:\n True if the count of divisors is even, False otherwise.\n \"\"\"\n if n <= 0:\n return False # Handle non-positive input as needed\n\n\n count = 0\n sqrt_n = int(math.sqrt(n))\n\n for i in range(1, sqrt_n + 1):\n if n % i == 0:\n count += 2 # Count both i and n/i\n\n if sqrt_n * sqrt_n == n: # Correct for perfect squares\n count -= 1\n\n return count % 2 == 0", "matching_cluster_idx": 4}, {"solution": "import math\ndef count_divisors(n):\n \"\"\"\n Checks if the number of divisors of n is even.\n\n Args:\n n: An integer.\n\n Returns:\n True if the count of divisors is even, False otherwise.\n \"\"\"\n if n == 0:\n return True # Or raise an exception as 0 has infinite divisors\n \n count = 0\n for i in range(1, int(math.sqrt(n)) + 1):\n if n % i == 0:\n if n // i == i: # Check for perfect squares\n count += 1\n else:\n count += 2\n return count % 2 == 0", "matching_cluster_idx": 4}, {"solution": "def count_divisors(n):\n \"\"\"\n Checks if the number of divisors of n is even.\n\n Args:\n n: The number to check.\n\n Returns:\n True if the count of divisors is even, False otherwise.\n \"\"\"\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n count += 1\n if i * i != n: # Avoid double counting for perfect squares\n count += 1\n return count % 2 == 0", "matching_cluster_idx": 4}, {"solution": "import math\ndef count_divisors(n):\n \"\"\"\n Checks if the number of divisors of n is even.\n\n Args:\n n: The number to check.\n\n Returns:\n True if the count of divisors is even, False otherwise.\n \"\"\"\n\n if n <= 0:\n return False # Handle non-positive input as needed\n\n count = 0\n for i in range(1, int(math.sqrt(n)) + 1):\n if n % i == 0:\n if n // i == i: # If divisors are equal (perfect square case), count once\n count += 1\n else: # Otherwise, count both divisors\n count += 2\n return count % 2 == 0", "matching_cluster_idx": 4}, {"solution": "import math\ndef count_divisors(n):\n \"\"\"\n Checks if the number of divisors of n is even.\n\n Args:\n n: An integer.\n\n Returns:\n True if the count of divisors is even, False otherwise.\n \"\"\"\n\n if n <= 0:\n return False # Or raise an exception, depending on desired behavior for non-positive input\n\n count = 0\n sqrt_n = int(math.sqrt(n))\n for i in range(1, sqrt_n + 1):\n if n % i == 0:\n count += 2 # Count both i and n/i as divisors\n \n # If n is a perfect square, we counted the square root twice. Correct for that.\n if sqrt_n * sqrt_n == n:\n count -= 1\n\n return count % 2 == 0", "matching_cluster_idx": 4}, {"solution": "import math\ndef count_divisors(n):\n \"\"\"\n Checks if the number of divisors of n is even.\n\n Args:\n n: An integer.\n\n Returns:\n True if the number of divisors is even, False otherwise.\n \"\"\"\n if n <= 0:\n return False # Handle non-positive inputs as needed\n\n count = 0\n for i in range(1, int(math.sqrt(n)) + 1):\n if n % i == 0:\n if n / i == i:\n count += 1\n else:\n count += 2\n\n return count % 2 == 0", "matching_cluster_idx": 4}, {"solution": "import math\ndef count_divisors(n):\n \"\"\"\n Checks if the number of divisors of n is even.\n\n Args:\n n: An integer.\n\n Returns:\n True if the count of divisors is even, False otherwise.\n \"\"\"\n\n if n <= 0:\n return False # Handle non-positive input\n\n count = 0\n for i in range(1, int(math.sqrt(n)) + 1):\n if n % i == 0:\n if n / i == i: # If i is a perfect square root, count only once\n count += 1\n else:\n count += 2\n\n return count % 2 == 0", "matching_cluster_idx": 4}, {"solution": "import math\ndef count_divisors(n):\n \"\"\"\n Checks if the number of divisors of n is even.\n\n Args:\n n: An integer.\n\n Returns:\n True if the count of divisors is even, False otherwise.\n \"\"\"\n if n == 0:\n return True # Technically has infinite divisors, but treating as an even case.\n count = 0\n for i in range(1, int(math.sqrt(n)) + 1):\n if n % i == 0:\n count += 1\n if i * i != n: # Avoid double counting perfect squares\n count += 1\n\n return count % 2 == 0", "matching_cluster_idx": 4}, {"solution": "import math\ndef count_divisors(n):\n \"\"\"\n Checks if the number of divisors of n is even.\n\n Args:\n n: An integer.\n\n Returns:\n True if the count of divisors is even, False otherwise.\n \"\"\"\n if n < 1:\n return False # Handle non-positive inputs appropriately\n\n count = 0\n for i in range(1, int(math.sqrt(n)) + 1):\n if n % i == 0:\n count += 1 if i * i == n else 2 # Optimized counting\n return count % 2 == 0", "matching_cluster_idx": 4}, {"solution": "def count_divisors(n):\n \"\"\"\n Checks if the number of divisors of n is even.\n\n Args:\n n: An integer.\n\n Returns:\n True if the count of divisors is even, False otherwise.\n \"\"\"\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n count += 1\n if i * i != n: # Avoid double counting for perfect squares\n count += 1\n return count % 2 == 0", "matching_cluster_idx": 4}, {"solution": "import math\ndef count_divisors(n):\n \"\"\"\n Checks if the number of divisors of n is even.\n\n Args:\n n: A positive integer.\n\n Returns:\n True if the number of divisors is even, False otherwise.\n \"\"\"\n\n if n <= 0:\n raise ValueError(\"Input n must be a positive integer.\")\n\n count = 0\n for i in range(1, int(math.sqrt(n)) + 1):\n if n % i == 0:\n if n // i == i:\n count += 1\n else:\n count += 2\n\n return count % 2 == 0", "matching_cluster_idx": 4}, {"solution": "import math\ndef count_divisors(n):\n \"\"\"\n Checks if the number of divisors of n is even.\n\n Args:\n n: An integer.\n\n Returns:\n True if the count of divisors is even, False otherwise.\n \"\"\"\n count = 0\n sqrt_n = int(math.sqrt(n))\n\n for i in range(1, sqrt_n + 1):\n if n % i == 0:\n if n // i == i:\n count += 1 # If it's a perfect square, only count the square root once\n else:\n count += 2 # Count both i and n//i as divisors\n\n return count % 2 == 0", "matching_cluster_idx": 4}, {"solution": "import math\ndef count_divisors(n):\n \"\"\"\n Checks if the number of divisors of n is even.\n\n Args:\n n: An integer.\n\n Returns:\n True if the count of divisors is even, False otherwise.\n \"\"\"\n if n == 0: # Handle the case where n is 0 (infinite divisors)\n return False\n\n count = 0\n for i in range(1, int(math.sqrt(n)) + 1):\n if n % i == 0:\n if n / i == i: # Handle perfect squares - only count the square root once.\n count += 1\n else:\n count += 2 # Count both i and n/i\n return count % 2 == 0", "matching_cluster_idx": 4}, {"solution": "import math\ndef count_divisors(n):\n \"\"\"\n Checks if the number of divisors of n is even.\n\n Args:\n n: An integer.\n\n Returns:\n True if the number of divisors is even, False otherwise.\n \"\"\"\n\n if n <= 0:\n return False # Handle non-positive inputs as needed\n\n count = 0\n sqrt_n = int(math.sqrt(n))\n for i in range(1, sqrt_n + 1):\n if n % i == 0:\n count += 2 if i * i != n else 1 # Optimized counting\n\n return count % 2 == 0", "matching_cluster_idx": 4}, {"solution": "import math\ndef count_divisors(n):\n \"\"\"\n Checks if the number of divisors of n is even.\n\n Args:\n n: A positive integer.\n\n Returns:\n True if the count of divisors is even, False otherwise.\n \"\"\"\n if n <= 0:\n raise ValueError(\"Input must be a positive integer\")\n\n count = 0\n for i in range(1, int(math.sqrt(n)) + 1):\n if n % i == 0:\n if n // i == i: # Handle perfect squares\n count += 1\n else:\n count += 2\n\n return count % 2 == 0", "matching_cluster_idx": 4}, {"solution": "def count_divisors(n):\n \"\"\"\n Checks if the number of divisors of n is even.\n\n Args:\n n: An integer.\n\n Returns:\n True if the count of divisors is even, False otherwise.\n \"\"\"\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n count += 1\n if i * i != n: # Avoid double counting if i is the square root\n count += 1\n return count % 2 == 0", "matching_cluster_idx": 4}, {"solution": "import math\ndef count_divisors(n):\n \"\"\"\n Checks if the number of divisors of n is even.\n\n Args:\n n: An integer.\n\n Returns:\n True if the count of divisors is even, False otherwise.\n \"\"\"\n count = 0\n sqrt_n = int(math.sqrt(n))\n for i in range(1, sqrt_n + 1):\n if n % i == 0:\n if n // i == i: # Handle perfect squares\n count += 1\n else:\n count += 2\n\n return count % 2 == 0", "matching_cluster_idx": 4}, {"solution": "import math\ndef count_divisors(n):\n \"\"\"\n Checks if the number of divisors of n is even.\n\n Args:\n n: An integer.\n\n Returns:\n True if the number of divisors is even, False otherwise.\n \"\"\"\n if n <= 0:\n return False # Handle non-positive inputs appropriately\n\n count = 0\n for i in range(1, int(math.sqrt(n)) + 1): # Optimized to check up to the square root\n if n % i == 0:\n if n / i == i: # If i is the square root, count it once\n count += 1\n else: # Otherwise, count both i and n/i\n count += 2\n\n return count % 2 == 0 # Return True if count is even, False otherwise", "matching_cluster_idx": 4}, {"solution": "import math\ndef count_divisors(n):\n \"\"\"\n Checks if the number of divisors of n is even.\n\n Args:\n n: A positive integer.\n\n Returns:\n True if the count of divisors is even, False otherwise.\n \"\"\"\n if n <= 0:\n raise ValueError(\"Input must be a positive integer.\")\n\n count = 0\n for i in range(1, int(math.sqrt(n)) + 1):\n if n % i == 0:\n if n // i == i: # Check for perfect squares\n count += 1\n else:\n count += 2 # Count both i and n/i\n return count % 2 == 0", "matching_cluster_idx": 4}]}, "Mbpp/800": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 84.0, "profiled": [{"solution": "def remove_all_spaces(input_string):\n \"\"\"Removes all whitespace characters from a string.\n\n Args:\n input_string: The string to process.\n\n Returns:\n The string with all whitespace removed.\n \"\"\"\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n \"\"\"Removes all whitespace characters from a string.\n\n Args:\n input_string: The string to remove whitespaces from.\n\n Returns:\n The string with all whitespaces removed.\n \"\"\"\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n \"\"\"Removes all whitespace characters from a string.\n\n Args:\n input_string: The string to remove whitespaces from.\n\n Returns:\n The string with all whitespaces removed.\n \"\"\"\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n \"\"\"Removes all whitespace characters from a string.\n\n Args:\n input_string: The string to remove whitespaces from.\n\n Returns:\n The string with all whitespaces removed.\n \"\"\"\n\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n \"\"\"Removes all whitespace characters from a string.\n\n Args:\n input_string: The string to remove whitespaces from.\n\n Returns:\n The string with all whitespaces removed.\n \"\"\"\n\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n \"\"\"Removes all whitespace characters from a string.\n\n Args:\n input_string: The input string.\n\n Returns:\n The string with all whitespace characters removed.\n \"\"\"\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n \"\"\"Removes all whitespace characters from a string.\n\n Args:\n input_string: The string to remove whitespaces from.\n\n Returns:\n The string with all whitespaces removed.\n \"\"\"\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n \"\"\"Removes all whitespace characters from a string.\n\n Args:\n input_string: The string to remove whitespaces from.\n\n Returns:\n A new string with all whitespaces removed.\n \"\"\"\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n \"\"\"Removes all whitespace characters from a string.\n\n Args:\n input_string: The string to remove whitespaces from.\n\n Returns:\n The string with all whitespaces removed.\n \"\"\"\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n \"\"\"Removes all whitespace characters from a string.\n\n Args:\n input_string: The string to remove whitespaces from.\n\n Returns:\n The string with all whitespaces removed.\n \"\"\"\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n \"\"\"Removes all whitespace characters from a string.\n\n Args:\n input_string: The string to remove whitespaces from.\n\n Returns:\n The string with all whitespaces removed.\n \"\"\"\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n \"\"\"Removes all whitespace characters from a string.\n\n Args:\n input_string: The string to remove whitespaces from.\n\n Returns:\n The string with all whitespaces removed.\n \"\"\"\n\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n \"\"\"Removes all whitespace characters from a string.\n\n Args:\n input_string: The string to remove whitespaces from.\n\n Returns:\n The string with all whitespaces removed.\n \"\"\"\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n \"\"\"Removes all whitespace characters from a string.\n\n Args:\n input_string: The string to remove whitespaces from.\n\n Returns:\n The string with all whitespaces removed.\n \"\"\"\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n \"\"\"Removes all whitespace characters from a string.\n\n Args:\n input_string: The string to remove whitespace from.\n\n Returns:\n The string with all whitespace removed.\n \"\"\"\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n \"\"\"Removes all whitespace characters from a string.\n\n Args:\n input_string: The string to remove whitespaces from.\n\n Returns:\n The string with all whitespaces removed.\n \"\"\"\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n \"\"\"Removes all whitespace characters from a string.\"\"\"\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n \"\"\"Removes all whitespace characters from a string.\n\n Args:\n input_string: The string to remove whitespaces from.\n\n Returns:\n A new string with all whitespaces removed.\n \"\"\"\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n \"\"\"Removes all whitespace characters from a string.\n\n Args:\n input_string: The string to remove whitespaces from.\n\n Returns:\n A new string with all whitespaces removed.\n \"\"\"\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n \"\"\"Removes all whitespace characters from a string.\n\n Args:\n input_string: The string to remove whitespaces from.\n\n Returns:\n A new string with all whitespaces removed.\n \"\"\"\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}]}, "Mbpp/805": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def max_sum_list(lists):\n \"\"\"\n Returns the list in a list of lists whose sum of elements is the highest.\n\n Args:\n lists: A list of lists of numbers.\n\n Returns:\n The list with the highest sum, or None if the input list is empty or contains non-numeric elements.\n \"\"\"\n if not lists:\n return None\n\n max_sum = -float('inf') # Initialize with negative infinity to handle lists with negative numbers\n max_list = None\n\n for lst in lists:\n try:\n current_sum = sum(lst)\n if current_sum > max_sum:\n max_sum = current_sum\n max_list = lst\n except TypeError:\n return None # Handle non-numeric elements\n\n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(list_of_lists):\n \"\"\"\n Returns the list in a list of lists whose sum of elements is the highest.\n \"\"\"\n if not list_of_lists:\n return None # Handle empty input\n\n max_sum = float('-inf') # Initialize with negative infinity\n max_list = None\n\n for lst in list_of_lists:\n current_sum = sum(lst)\n if current_sum > max_sum:\n max_sum = current_sum\n max_list = lst\n\n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n \"\"\"\n Returns the list in a list of lists whose sum of elements is the highest.\n \"\"\"\n if not lists:\n return None # Handle empty input\n\n max_sum = -float('inf') # Initialize with negative infinity to handle lists with negative numbers\n max_list = None\n\n for lst in lists:\n current_sum = sum(lst)\n if current_sum > max_sum:\n max_sum = current_sum\n max_list = lst\n\n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n \"\"\"\n Returns the list in a list of lists whose sum of elements is the highest.\n\n Args:\n lists: A list of lists of numbers.\n\n Returns:\n The list with the maximum sum.\n Returns an empty list if the input list is empty or if all sublists are empty.\n \"\"\"\n if not lists:\n return []\n\n max_sum = -float('inf') # Initialize with negative infinity to handle negative numbers\n max_list = []\n\n for lst in lists:\n if not lst: #Handle empty sublists\n current_sum = -float('inf')\n else:\n current_sum = sum(lst)\n\n if current_sum > max_sum:\n max_sum = current_sum\n max_list = lst\n\n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(list_of_lists):\n \"\"\"Returns the list with the maximum sum of elements.\"\"\"\n\n if not list_of_lists:\n return None # Handle empty input\n\n max_sum = -float('inf') # Initialize with negative infinity for any number comparison\n max_list = None\n\n for lst in list_of_lists:\n current_sum = sum(lst)\n if current_sum > max_sum:\n max_sum = current_sum\n max_list = lst\n\n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n \"\"\"\n Returns the list in a list of lists whose sum of elements is the highest.\n \"\"\"\n max_sum = -float('inf') # Initialize with negative infinity to handle lists with negative numbers\n max_list = None\n\n for lst in lists:\n current_sum = sum(lst)\n if current_sum > max_sum:\n max_sum = current_sum\n max_list = lst\n\n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n \"\"\"\n Returns the list in a list of lists whose sum of elements is the highest.\n \"\"\"\n if not lists:\n return None # Handle empty input\n\n max_sum = -float('inf') # Initialize with negative infinity\n max_list = None\n\n for lst in lists:\n current_sum = sum(lst)\n if current_sum > max_sum:\n max_sum = current_sum\n max_list = lst\n\n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(list_of_lists):\n \"\"\"\n Returns the list in a list of lists whose sum of elements is the highest.\n \"\"\"\n max_sum = -float('inf') # Initialize with negative infinity\n max_list = None\n\n for lst in list_of_lists:\n current_sum = sum(lst)\n if current_sum > max_sum:\n max_sum = current_sum\n max_list = lst\n\n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n \"\"\"\n Returns the list in a list of lists whose sum of elements is the highest.\n \"\"\"\n if not lists:\n return None # Handle empty input\n\n max_sum = float('-inf') # Initialize with negative infinity\n max_list = None\n\n for lst in lists:\n current_sum = sum(lst)\n if current_sum > max_sum:\n max_sum = current_sum\n max_list = lst\n\n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(list_of_lists):\n \"\"\"\n Returns the list in a list of lists whose sum of elements is the highest.\n \"\"\"\n max_sum = -float('inf') # Initialize with negative infinity to handle lists with negative numbers\n max_list = None\n\n for lst in list_of_lists:\n current_sum = sum(lst)\n if current_sum > max_sum:\n max_sum = current_sum\n max_list = lst\n\n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n \"\"\"\n Returns the list in a list of lists whose sum of elements is the highest.\n \"\"\"\n if not lists:\n return None # Handle empty input\n\n max_list = None\n max_sum = float('-inf') # Initialize with negative infinity\n\n for lst in lists:\n current_sum = sum(lst)\n if current_sum > max_sum:\n max_sum = current_sum\n max_list = lst\n\n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(list_of_lists):\n \"\"\"\n Returns the list in a list of lists whose sum of elements is the highest.\n \"\"\"\n if not list_of_lists:\n return None # Handle empty input\n\n max_sum = -float('inf') # Initialize with negative infinity to handle lists with negative numbers\n max_list = None\n\n for lst in list_of_lists:\n current_sum = sum(lst)\n if current_sum > max_sum:\n max_sum = current_sum\n max_list = lst\n\n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(list_of_lists):\n \"\"\"\n Returns the list in a list of lists whose sum of elements is the highest.\n\n Args:\n list_of_lists: A list of lists of numbers.\n\n Returns:\n The list with the highest sum.\n \"\"\"\n if not list_of_lists:\n return None # Handle empty input\n\n max_sum = float('-inf')\n max_list = None\n\n for lst in list_of_lists:\n current_sum = sum(lst)\n if current_sum > max_sum:\n max_sum = current_sum\n max_list = lst\n\n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n \"\"\"\n Returns the list in a list of lists whose sum of elements is the highest.\n \"\"\"\n max_sum = -float('inf') # Initialize with negative infinity to handle lists with negative numbers\n max_list = None\n\n for lst in lists:\n current_sum = sum(lst)\n if current_sum > max_sum:\n max_sum = current_sum\n max_list = lst\n\n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n \"\"\"\n Returns the list in a list of lists whose sum of elements is the highest.\n \"\"\"\n if not lists:\n return None # Handle empty input\n\n max_sum = -float('inf') # Initialize with negative infinity to handle lists with negative numbers\n max_list = None\n\n for lst in lists:\n current_sum = sum(lst)\n if current_sum > max_sum:\n max_sum = current_sum\n max_list = lst\n\n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n \"\"\"Returns the list in a list of lists whose sum of elements is the highest.\"\"\"\n\n if not lists:\n return None # Handle empty input\n\n max_sum = -float('inf') # Initialize with negative infinity to handle lists with negative numbers\n max_list = None\n\n for lst in lists:\n current_sum = sum(lst)\n if current_sum > max_sum:\n max_sum = current_sum\n max_list = lst\n\n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n \"\"\"\n Returns the list in a list of lists whose sum of elements is the highest.\n \"\"\"\n max_sum = -float('inf') # Initialize with negative infinity to handle lists with negative numbers\n max_list = None\n\n for lst in lists:\n current_sum = sum(lst)\n if current_sum > max_sum:\n max_sum = current_sum\n max_list = lst\n\n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(list_of_lists):\n \"\"\"\n Returns the list in a list of lists whose sum of elements is the highest.\n\n Args:\n list_of_lists: A list of lists of numbers.\n\n Returns:\n The list with the highest sum.\n \"\"\"\n\n max_sum = -float('inf') # Initialize with negative infinity\n max_list = None\n\n for lst in list_of_lists:\n current_sum = sum(lst)\n if current_sum > max_sum:\n max_sum = current_sum\n max_list = lst\n\n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n \"\"\"\n Returns the list in a list of lists whose sum of elements is the highest.\n\n Args:\n lists: A list of lists of numbers.\n\n Returns:\n The list with the highest sum.\n \"\"\"\n\n if not lists:\n return None # Handle empty input\n\n max_sum = -float('inf') # Initialize with negative infinity to handle negative numbers\n max_list = None\n\n for lst in lists:\n current_sum = sum(lst)\n if current_sum > max_sum:\n max_sum = current_sum\n max_list = lst\n\n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n \"\"\"\n Returns the list in a list of lists whose sum of elements is the highest.\n \"\"\"\n if not lists:\n return None # Handle empty input\n\n max_sum = -float('inf') # Initialize with negative infinity to handle lists with negative numbers\n max_list = None\n\n for lst in lists:\n current_sum = sum(lst)\n if current_sum > max_sum:\n max_sum = current_sum\n max_list = lst\n\n return max_list", "matching_cluster_idx": 4}]}, "Mbpp/808": {"dps": 72.28070175438596, "dps_norm": 93.33333333333333, "pass@1": 100.0, "profiled": [{"solution": "def check_K(tup, k):\n \"\"\"\n Checks if a tuple contains a specific value.\n\n Args:\n tup: The tuple to check.\n k: The value to search for.\n\n Returns:\n True if k is in the tuple, False otherwise.\n \"\"\"\n return k in tup", "matching_cluster_idx": 4}, {"solution": "def check_K(nums, k):\n \"\"\"\n Checks if a tuple contains a given value k.\n\n Args:\n nums: The tuple to search.\n k: The value to search for.\n\n Returns:\n True if k is in the tuple, False otherwise.\n \"\"\"\n return k in nums", "matching_cluster_idx": 4}, {"solution": "def check_K(nums, k):\n \"\"\"\n Checks if the tuple nums contains the integer k.\n\n Args:\n nums: A tuple of integers.\n k: The integer to search for.\n\n Returns:\n True if k is in nums, False otherwise.\n \"\"\"\n return k in nums", "matching_cluster_idx": 5}, {"solution": "def check_K(given_tuple, k):\n \"\"\"\n Checks if an integer k is present in a given tuple.\n\n Args:\n given_tuple: The tuple to search.\n k: The integer to search for.\n\n Returns:\n True if k is in given_tuple, False otherwise.\n \"\"\"\n return k in given_tuple", "matching_cluster_idx": 5}, {"solution": "def check_K(t, k):\n \"\"\"\n Checks if a tuple contains a specific value.\n\n Args:\n t: The tuple to search.\n k: The value to search for.\n\n Returns:\n True if the value is found in the tuple, False otherwise.\n \"\"\"\n return k in t", "matching_cluster_idx": 5}, {"solution": "def check_K(given_tuple, k):\n \"\"\"\n Checks if a tuple contains a given value.\n\n Args:\n given_tuple: The tuple to check.\n k: The value to search for.\n\n Returns:\n True if k is present in the tuple, False otherwise.\n \"\"\"\n return k in given_tuple", "matching_cluster_idx": 4}, {"solution": "def check_K(tup, k):\n \"\"\"\n Checks if a tuple contains a specific value.\n\n Args:\n tup: The tuple to search.\n k: The value to search for.\n\n Returns:\n True if the value is found, False otherwise.\n \"\"\"\n return k in tup", "matching_cluster_idx": 4}, {"solution": "def check_K(nums, k):\n \"\"\"\n Checks if a tuple contains a specific value k.\n\n Args:\n nums: The tuple of numbers.\n k: The value to search for.\n\n Returns:\n True if k is present in the tuple, False otherwise.\n \"\"\"\n return k in nums", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n \"\"\"\n Checks if a tuple contains a given value k.\n\n Args:\n tup: The tuple to check.\n k: The value to search for.\n\n Returns:\n True if k is present in the tuple, False otherwise.\n \"\"\"\n return k in tup", "matching_cluster_idx": 4}, {"solution": "def check_K(tup, k):\n \"\"\"\n Checks if a tuple contains a specific value k.\n\n Args:\n tup: The tuple to check.\n k: The value to search for.\n\n Returns:\n True if k is in the tuple, False otherwise.\n \"\"\"\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(nums, k):\n \"\"\"\n Checks if a tuple contains a specific value.\n\n Args:\n nums: A tuple of numbers.\n k: The value to search for.\n\n Returns:\n True if k is in nums, False otherwise.\n \"\"\"\n return k in nums", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n \"\"\"\n Checks if a tuple contains a given value k.\n\n Args:\n tup: The tuple to check.\n k: The value to search for.\n\n Returns:\n True if k is in the tuple, False otherwise.\n \"\"\"\n return k in tup", "matching_cluster_idx": 4}, {"solution": "def check_K(tup, k):\n \"\"\"\n Checks if a tuple contains a specific element k.\n\n Args:\n tup: The tuple to check.\n k: The element to search for.\n\n Returns:\n True if k is in the tuple, False otherwise.\n \"\"\"\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(nums, k):\n \"\"\"\n Checks if the given tuple contains the integer k.\n\n Args:\n nums: A tuple of integers.\n k: The integer to search for.\n\n Returns:\n True if k is present in the tuple, False otherwise.\n \"\"\"\n return k in nums", "matching_cluster_idx": 5}, {"solution": "def check_K(nums, k):\n \"\"\"\n Checks if the given tuple contains the integer k.\n\n Args:\n nums: A tuple of integers.\n k: An integer to search for.\n\n Returns:\n True if k is found in the tuple, False otherwise.\n \"\"\"\n return k in nums", "matching_cluster_idx": 5}, {"solution": "def check_K(nums, k):\n \"\"\"\n Checks if a tuple contains a specific value.\n\n Args:\n nums: A tuple of numbers.\n k: The value to search for.\n\n Returns:\n True if k is present in nums, False otherwise.\n \"\"\"\n return k in nums", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n \"\"\"\n Checks if a tuple contains a specific value.\n\n Args:\n tup: The tuple to check.\n k: The value to search for.\n\n Returns:\n True if the value k is present in the tuple, False otherwise.\n \"\"\"\n return k in tup", "matching_cluster_idx": 4}, {"solution": "def check_K(tup, k):\n \"\"\"\n Checks if a tuple contains a specific value.\n\n Args:\n tup: The tuple to check.\n k: The value to search for.\n\n Returns:\n True if k is found in the tuple, False otherwise.\n \"\"\"\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(nums, k):\n \"\"\"\n Checks if a tuple contains a given value.\n\n Args:\n nums: A tuple of numbers.\n k: The value to search for.\n\n Returns:\n True if k is present in the tuple, False otherwise.\n \"\"\"\n return k in nums", "matching_cluster_idx": 4}, {"solution": "def check_K(tup, k):\n \"\"\"\n Checks if a tuple contains a specific value k.\n\n Args:\n tup: The tuple to search.\n k: The value to search for.\n\n Returns:\n True if k is in the tuple, False otherwise.\n \"\"\"\n return k in tup", "matching_cluster_idx": 5}]}}} \ No newline at end of file diff --git a/results/evalperf/google--gemma-2-27b-it_vllm_temp_1.0_evalperf_results.brief.json b/results/evalperf/google--gemma-2-27b-it_vllm_temp_1.0_evalperf_results.brief.json new file mode 100644 index 0000000..3b665e5 --- /dev/null +++ b/results/evalperf/google--gemma-2-27b-it_vllm_temp_1.0_evalperf_results.brief.json @@ -0,0 +1 @@ +{"date": "2024-10-19 16:31", "config": {"n_samples": 100, "temperature": 1.0, "min_correct": 10, "max_profile": 20}, "summary": {"dps": 84.20223252621882, "dps_norm": 78.67511770954597, "pass@1": 80.23728813559322}, "eval": {"HumanEval/9": {"dps": 66.1489929628731, "dps_norm": 63.24786324786325, "pass@1": 13.0, "profiled": [{"solution": "from typing import List, Tuple\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n \n max_so_far = numbers[0]\n rolling_max_list = [max_so_far]\n\n for i in range(1, len(numbers)):\n if numbers[i] > max_so_far:\n max_so_far = numbers[i]\n rolling_max_list.append(max_so_far)\n return rolling_max_list", "matching_cluster_idx": 7}, {"solution": "from typing import List, Tuple\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n max_so_far = numbers[0]\n rolling_max_list = [max_so_far]\n for i in range(1, len(numbers)):\n max_so_far = max(max_so_far, numbers[i])\n rolling_max_list.append(max_so_far)\n return rolling_max_list", "matching_cluster_idx": 4}, {"solution": "from typing import List, Tuple\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n\n rolling_max_list = [numbers[0]]\n current_max = numbers[0]\n for i in range(1, len(numbers)):\n if numbers[i] > current_max:\n current_max = numbers[i]\n rolling_max_list.append(current_max)\n\n return rolling_max_list", "matching_cluster_idx": 7}, {"solution": "from typing import List, Tuple\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n\n max_so_far = numbers[0]\n rolling_max_list = [max_so_far]\n\n for i in range(1, len(numbers)):\n max_so_far = max(max_so_far, numbers[i])\n rolling_max_list.append(max_so_far)\n\n return rolling_max_list", "matching_cluster_idx": 4}, {"solution": "from typing import List, Tuple\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n\n rolling_max_list = [numbers[0]] \n for i in range(1, len(numbers)):\n rolling_max_list.append(max(rolling_max_list[-1], numbers[i]))\n return rolling_max_list", "matching_cluster_idx": 4}, {"solution": "from typing import List, Tuple\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n \n max_so_far = numbers[0]\n rolling_max_list = [numbers[0]]\n for i in range(1, len(numbers)):\n if numbers[i] > max_so_far:\n max_so_far = numbers[i]\n rolling_max_list.append(max_so_far)\n return rolling_max_list", "matching_cluster_idx": 7}, {"solution": "from typing import List, Tuple\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n \n rolling_max_list = [numbers[0]]\n for i in range(1, len(numbers)):\n rolling_max_list.append(max(rolling_max_list[-1],numbers[i]))\n return rolling_max_list", "matching_cluster_idx": 4}, {"solution": "from typing import List, Tuple\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n max_so_far = numbers[0]\n result = [numbers[0]]\n for i in range(1, len(numbers)):\n max_so_far = max(max_so_far, numbers[i])\n result.append(max_so_far)\n return result", "matching_cluster_idx": 4}, {"solution": "from typing import List, Tuple\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n rolling_max_list = [numbers[0]]\n current_max = numbers[0]\n for i in range(1, len(numbers)):\n current_max = max(current_max, numbers[i])\n rolling_max_list.append(current_max)\n\n return rolling_max_list", "matching_cluster_idx": 4}, {"solution": "from typing import List, Tuple\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n rolling_max_list = [numbers[0]] \n for i in range(1, len(numbers)):\n rolling_max_list.append(max(rolling_max_list[-1], numbers[i]))\n return rolling_max_list", "matching_cluster_idx": 4}, {"solution": "from typing import List, Tuple\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n \n rolling_maxes = [numbers[0]]\n for i in range(1, len(numbers)):\n rolling_maxes.append(max(rolling_maxes[-1], numbers[i]))\n return rolling_maxes", "matching_cluster_idx": 4}, {"solution": "from typing import List, Tuple\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n \n rolling_maximums = []\n current_max = numbers[0]\n for number in numbers:\n current_max = max(current_max, number)\n rolling_maximums.append(current_max)\n return rolling_maximums", "matching_cluster_idx": 4}, {"solution": "from typing import List, Tuple\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n max_so_far = numbers[0]\n rolling_max_list = [max_so_far]\n for i in range(1, len(numbers)):\n max_so_far = max(max_so_far, numbers[i])\n rolling_max_list.append(max_so_far)\n\n return rolling_max_list", "matching_cluster_idx": 4}]}, "HumanEval/0": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n for i in range(len(numbers)):\n for j in range(i+1, len(numbers)):\n if abs(numbers[i] - numbers[j]) < threshold:\n return True\n return False", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n if abs(numbers[i] - numbers[j]) < threshold:\n return True\n return False", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n if abs(numbers[i] - numbers[j]) < threshold:\n return True\n return False", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n if abs(numbers[i] - numbers[j]) < threshold:\n return True\n return False", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n if abs(numbers[i] - numbers[j]) < threshold:\n return True\n return False", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n if abs(numbers[i] - numbers[j]) < threshold:\n return True\n return False", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n if abs(numbers[i] - numbers[j]) < threshold:\n return True\n return False", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n if abs(numbers[i] - numbers[j]) < threshold:\n return True\n return False", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n if abs(numbers[i] - numbers[j]) < threshold:\n return True\n return False", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n if abs(numbers[i] - numbers[j]) < threshold:\n return True\n return False", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n if abs(numbers[i] - numbers[j]) < threshold:\n return True\n return False", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n for i in range(len(numbers)):\n for j in range(i+1, len(numbers)):\n if abs(numbers[i] - numbers[j]) < threshold:\n return True\n return False", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n if abs(numbers[i] - numbers[j]) < threshold:\n return True\n return False", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n if abs(numbers[i] - numbers[j]) < threshold:\n return True\n return False", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n if abs(numbers[i] - numbers[j]) < threshold:\n return True\n return False", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n for i in range(len(numbers)):\n for j in range(i+1, len(numbers)):\n if abs(numbers[i] - numbers[j]) < threshold:\n return True\n return False", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n if abs(numbers[i] - numbers[j]) < threshold:\n return True\n return False", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n if abs(numbers[i] - numbers[j]) < threshold:\n return True\n return False", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n for i in range(len(numbers)):\n for j in range(i+1, len(numbers)):\n if abs(numbers[i] - numbers[j]) < threshold:\n return True\n return False", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n for i in range(len(numbers)):\n for j in range(i+1, len(numbers)):\n if abs(numbers[i]-numbers[j]) < threshold:\n return True\n return False", "matching_cluster_idx": 6}]}, "HumanEval/4": {"dps": 18.37025316455696, "dps_norm": 62.5, "pass@1": 100.0, "profiled": [{"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n mean = sum(numbers) / len(numbers)\n absolute_deviations = [abs(number - mean) for number in numbers]\n return sum(absolute_deviations) / len(numbers)", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n mean = sum(numbers) / len(numbers)\n absolute_deviations = [abs(x - mean) for x in numbers]\n return sum(absolute_deviations) / len(absolute_deviations)", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n mean = sum(numbers) / len(numbers)\n return sum(abs(number - mean) for number in numbers) / len(numbers)", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n n = len(numbers)\n if n == 0:\n return 0\n mean = sum(numbers) / n\n absolute_deviations = [abs(x - mean) for x in numbers]\n mad = sum(absolute_deviations) / n\n return mad", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n mean = sum(numbers) / len(numbers)\n return sum([abs(x - mean) for x in numbers]) / len(numbers)", "matching_cluster_idx": 3}, {"solution": "from typing import List\nfrom statistics import mean\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n data_mean = mean(numbers)\n absolute_deviations = [abs(x - data_mean) for x in numbers]\n return mean(absolute_deviations)", "matching_cluster_idx": 0}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n mean = sum(numbers) / len(numbers)\n absolute_deviations = [abs(x - mean) for x in numbers]\n return sum(absolute_deviations) / len(numbers)", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n n = len(numbers)\n mean = sum(numbers) / n\n absolute_deviations = [abs(x - mean) for x in numbers]\n mad = sum(absolute_deviations) / n\n return mad", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n n = len(numbers)\n mean = sum(numbers) / n\n absolute_deviations = [abs(x - mean) for x in numbers]\n mad = sum(absolute_deviations) / n\n return mad", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n n = len(numbers)\n if n == 0:\n return 0.0\n mean = sum(numbers) / n\n absolute_deviations = [abs(x - mean) for x in numbers]\n mad = sum(absolute_deviations) / n\n return mad", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n mean = sum(numbers) / len(numbers)\n absolute_deviations = [abs(number - mean) for number in numbers]\n return sum(absolute_deviations) / len(absolute_deviations)", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n mean = sum(numbers) / len(numbers)\n return sum([abs(x - mean) for x in numbers]) / len(numbers)", "matching_cluster_idx": 3}, {"solution": "from typing import List\nfrom statistics import mean\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n mean_val = mean(numbers)\n return sum(abs(x - mean_val) for x in numbers) / len(numbers)", "matching_cluster_idx": 0}, {"solution": "from typing import List\nfrom typing import Any\nimport math\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n\n mean = sum(numbers) / len(numbers)\n absolute_deviations = [abs(number - mean) for number in numbers]\n return sum(absolute_deviations) / len(numbers)", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n mean = sum(numbers) / len(numbers)\n absolute_deviations = [abs(number - mean) for number in numbers]\n return sum(absolute_deviations) / len(numbers)", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n mean = sum(numbers) / len(numbers)\n absolute_deviations = [abs(x - mean) for x in numbers]\n return sum(absolute_deviations) / len(absolute_deviations)", "matching_cluster_idx": 3}, {"solution": "from typing import List\nimport statistics\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n mean = statistics.mean(numbers)\n absolute_deviations = [abs(x - mean) for x in numbers]\n return statistics.mean(absolute_deviations)", "matching_cluster_idx": 0}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n n = len(numbers)\n if n == 0:\n return 0\n mean = sum(numbers) / n\n return sum([abs(x - mean) for x in numbers]) / n", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n n = len(numbers)\n if n == 0:\n return 0\n mean = sum(numbers) / n\n absolute_deviations = [abs(x - mean) for x in numbers]\n mad = sum(absolute_deviations) / n\n return mad", "matching_cluster_idx": 3}, {"solution": "from typing import List\nimport math\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if not numbers:\n return 0\n mean = sum(numbers) / len(numbers)\n absolute_deviations = [abs(x - mean) for x in numbers]\n return sum(absolute_deviations) / len(absolute_deviations)", "matching_cluster_idx": 3}]}, "HumanEval/16": {"dps": 79.06976744186046, "dps_norm": 83.33333333333333, "pass@1": 100.0, "profiled": [{"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n return len(set(string.lower()))", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n return len(set(string.lower()))", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n return len(set(string.lower()))", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n distinct_chars = set(string.lower())\n return len(distinct_chars)", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n distinct_characters = set(string.lower())\n return len(distinct_characters)", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n distinct_chars = set(string.lower())\n return len(distinct_chars)", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n return len(set(string.lower()))", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n return len(set(c.lower() for c in string))", "matching_cluster_idx": 2}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n return len(set(string.lower()))", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n return len(set(char.lower() for char in string))", "matching_cluster_idx": 2}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n return len(set(string.lower()))", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n return len(set(char.lower() for char in string))", "matching_cluster_idx": 2}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n return len(set(string.lower()))", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n return len(set(c.lower() for c in string))", "matching_cluster_idx": 2}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n distinct_chars = set(string.lower())\n return len(distinct_chars)", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n string = string.lower()\n return len(set(string))", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n distinct_characters = set(string.lower())\n return len(distinct_characters)", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n return len(set(string.lower()))", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n return len(set(string.lower()))", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n return len(set(char.lower() for char in string))", "matching_cluster_idx": 2}]}, "HumanEval/20": {"dps": 84.21307506053269, "dps_norm": 88.88888888888889, "pass@1": 100.0, "profiled": [{"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n numbers.sort()\n min_diff = float('inf')\n closest_pair = (numbers[0], numbers[1])\n\n for i in range(len(numbers) - 1):\n diff = numbers[i+1] - numbers[i]\n if diff < min_diff:\n min_diff = diff\n closest_pair = (numbers[i], numbers[i+1])\n\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n numbers.sort()\n smallest_difference = float('inf')\n closest_pair = (numbers[0], numbers[1])\n for i in range(len(numbers) - 1):\n difference = numbers[i + 1] - numbers[i]\n if difference < smallest_difference:\n smallest_difference = difference\n closest_pair = (numbers[i], numbers[i + 1])\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n min_diff = float('inf')\n closest_pair = (numbers[0], numbers[1]) if numbers[0] < numbers[1] else (numbers[1], numbers[0])\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n diff = abs(numbers[i] - numbers[j])\n if diff < min_diff:\n min_diff = diff\n closest_pair = (numbers[i], numbers[j]) if numbers[i] < numbers[j] else (numbers[j], numbers[i])\n return closest_pair", "matching_cluster_idx": 3}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n min_diff = float('inf')\n closest_pair = (float('inf'), float('inf'))\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n diff = abs(numbers[i] - numbers[j])\n if diff < min_diff:\n min_diff = diff\n closest_pair = (min(numbers[i], numbers[j]), max(numbers[i], numbers[j]))\n return closest_pair", "matching_cluster_idx": 3}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n numbers.sort()\n min_diff = float('inf')\n closest_pair = (numbers[0], numbers[1])\n for i in range(len(numbers)-1):\n diff = numbers[i+1] - numbers[i]\n if diff < min_diff:\n min_diff = diff\n closest_pair = (numbers[i], numbers[i+1])\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n numbers.sort()\n min_diff = float('inf')\n closest_pair = (numbers[0], numbers[1]) \n for i in range(len(numbers)-1):\n diff = numbers[i+1]-numbers[i]\n if diff < min_diff:\n min_diff = diff\n closest_pair = (numbers[i],numbers[i+1])\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n numbers.sort()\n min_diff = float('inf')\n closest_pair = (numbers[0], numbers[1])\n for i in range(len(numbers) -1):\n diff = numbers[i+1] - numbers[i]\n if diff < min_diff:\n min_diff = diff\n closest_pair = (numbers[i], numbers[i+1])\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n numbers.sort()\n min_diff = float('inf')\n closest_pair = (numbers[0], numbers[1])\n\n for i in range(len(numbers) - 1):\n diff = numbers[i + 1] - numbers[i]\n if diff < min_diff:\n min_diff = diff\n closest_pair = (numbers[i], numbers[i + 1])\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n numbers.sort()\n min_difference = float('inf')\n closest_pair = (numbers[0], numbers[1])\n\n for i in range(len(numbers) - 1):\n difference = numbers[i + 1] - numbers[i]\n if difference < min_difference:\n min_difference = difference\n closest_pair = (numbers[i], numbers[i + 1])\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n \n min_difference = float('inf')\n closest_pair = (None, None)\n\n for i in range(len(numbers)):\n for j in range(i+1, len(numbers)):\n difference = abs(numbers[i] - numbers[j])\n if difference < min_difference:\n min_difference = difference\n closest_pair = (numbers[i], numbers[j])\n \n return tuple(sorted(closest_pair))", "matching_cluster_idx": 3}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n numbers.sort()\n min_diff = float('inf')\n closest_pair = (numbers[0], numbers[1]) \n for i in range(len(numbers) - 1):\n diff = numbers[i+1] - numbers[i]\n if diff < min_diff:\n min_diff = diff\n closest_pair = (numbers[i], numbers[i+1])\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n numbers.sort()\n smallest_difference = float('inf')\n closest_pair = (numbers[0], numbers[1]) \n\n for i in range(len(numbers) - 1):\n difference = numbers[i + 1] - numbers[i]\n if difference < smallest_difference:\n smallest_difference = difference\n closest_pair = (numbers[i], numbers[i + 1])\n\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n numbers.sort()\n min_diff = float('inf')\n closest_pair = (numbers[0], numbers[1])\n for i in range(len(numbers) -1):\n diff = numbers[i+1]-numbers[i]\n if diff < min_diff:\n min_diff = diff\n closest_pair = (numbers[i],numbers[i+1])\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n numbers.sort()\n min_diff = float('inf')\n closest_pair = (numbers[0], numbers[1])\n\n for i in range(len(numbers) - 1):\n diff = numbers[i + 1] - numbers[i]\n if diff < min_diff:\n min_diff = diff\n closest_pair = (numbers[i], numbers[i + 1])\n\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n numbers.sort()\n min_diff = float('inf')\n closest_pair = (numbers[0], numbers[1])\n for i in range(len(numbers)-1):\n diff = numbers[i+1] - numbers[i]\n if diff < min_diff:\n min_diff = diff\n closest_pair = (numbers[i], numbers[i+1])\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n numbers.sort()\n min_diff = float('inf')\n closest_pair = (numbers[0], numbers[1])\n for i in range(len(numbers) - 1):\n diff = numbers[i+1] - numbers[i]\n if diff < min_diff:\n min_diff = diff\n closest_pair = (numbers[i], numbers[i+1])\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n numbers.sort()\n closest_diff = float('inf')\n closest_pair = (numbers[0], numbers[1])\n\n for i in range(len(numbers) - 1):\n diff = numbers[i+1] - numbers[i]\n if diff < closest_diff:\n closest_diff = diff\n closest_pair = (numbers[i], numbers[i+1])\n\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n numbers.sort()\n min_diff = float('inf')\n closest_pair = (numbers[0], numbers[1])\n for i in range(len(numbers) - 1):\n diff = numbers[i + 1] - numbers[i]\n if diff < min_diff:\n min_diff = diff\n closest_pair = (numbers[i], numbers[i + 1])\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n closest_elements = (numbers[0], numbers[1])\n min_distance = abs(numbers[0] - numbers[1])\n\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n distance = abs(numbers[i] - numbers[j])\n if distance < min_distance:\n min_distance = distance\n closest_elements = (numbers[i], numbers[j])\n \n return tuple(sorted(closest_elements))", "matching_cluster_idx": 3}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n numbers.sort()\n min_diff = float('inf')\n closest_pair = (numbers[0], numbers[1])\n\n for i in range(len(numbers) - 1):\n diff = numbers[i+1] - numbers[i]\n if diff < min_diff:\n min_diff = diff\n closest_pair = (numbers[i], numbers[i+1])\n\n return closest_pair", "matching_cluster_idx": 8}]}, "HumanEval/24": {"dps": 88.70748299319729, "dps_norm": 56.875, "pass@1": 100.0, "profiled": [{"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n for i in range(n//2, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 3}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n for i in range(n//2, 0, -1):\n if n % i == 0:\n return i\n\n return 1", "matching_cluster_idx": 3}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n for i in range(n//2, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 4}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n for i in range(n//2, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 3}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n for i in range(n // 2, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 3}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n for i in range(n // 2, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 4}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n for i in range(n//2, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 4}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n for i in range(n // 2, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 4}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n for i in range(n//2, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 4}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n for i in range(n//2, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 3}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n for i in range(n // 2, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 3}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n for i in range(n//2, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 4}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n for i in range(n//2, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 4}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n for i in range(n//2, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 4}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n for i in range(n//2,0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 3}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n for i in range(n//2, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 4}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n for i in range(n // 2, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 3}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n for i in range(n//2, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 4}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n for i in range(n//2, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 3}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n for i in range(n//2, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 4}]}, "HumanEval/26": {"dps": null, "dps_norm": null, "pass@1": 0.0, "profiled": []}, "HumanEval/31": {"dps": 52.9746835443038, "dps_norm": 75.625, "pass@1": 100.0, "profiled": [{"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n # Prime numbers are greater than 1\n if n <= 1:\n return False\n # 2 is the only even prime number\n if n == 2:\n return True\n # Check if n is divisible by 2\n if n % 2 == 0:\n return False\n # Check for divisibility by odd numbers from 3 to the square root of n\n i = 3\n while i * i <= n:\n if n % i == 0:\n return False\n i += 2\n return True", "matching_cluster_idx": 5}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True", "matching_cluster_idx": 5}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True", "matching_cluster_idx": 5}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True", "matching_cluster_idx": 5}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n**0.5)+1):\n if n % i == 0:\n return False\n return True", "matching_cluster_idx": 5}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True", "matching_cluster_idx": 5}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True", "matching_cluster_idx": 5}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n # Prime numbers are greater than 1\n if n <= 1:\n return False\n # 2 is the only even prime number\n if n <= 3:\n return True\n\n # Check if n is divisible by 2 or 3\n if n % 2 == 0 or n % 3 == 0:\n return False\n\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n ** 0.5) + 1):\n if n % i == 0:\n return False\n return True", "matching_cluster_idx": 5}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True", "matching_cluster_idx": 5}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n # Prime numbers are greater than 1\n if n <= 1:\n return False\n # 2 is the only even prime number\n if n == 2:\n return True\n # Check if n is divisible by any number from 2 to the square root of n\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True", "matching_cluster_idx": 5}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True", "matching_cluster_idx": 5}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True", "matching_cluster_idx": 5}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True", "matching_cluster_idx": 5}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True", "matching_cluster_idx": 5}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n # Prime numbers are greater than 1\n if n <= 1:\n return False\n # Check if n is divisible by any number from 2 to the square root of n\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True", "matching_cluster_idx": 5}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True", "matching_cluster_idx": 5}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True", "matching_cluster_idx": 5}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n # Prime numbers are greater than 1\n if n <= 1:\n return False\n # Check for divisibility from 2 to the square root of n\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True", "matching_cluster_idx": 5}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True", "matching_cluster_idx": 5}]}, "HumanEval/33": {"dps": 46.67824074074074, "dps_norm": 76.81818181818181, "pass@1": 79.0, "profiled": [{"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n third_indices = [i for i in range(len(l)) if i % 3 == 0]\n sorted_third_values = sorted([l[i] for i in third_indices])\n result = l.copy()\n for i, index in enumerate(third_indices):\n result[index] = sorted_third_values[i]\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n l_sorted = sorted([l[i] for i in range(len(l)) if i % 3 == 0])\n result = []\n j = 0\n for i in range(len(l)):\n if i % 3 == 0:\n result.append(l_sorted[j])\n j += 1\n else:\n result.append(l[i])\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n result = l[:]\n third_indices = [i for i in range(len(l)) if i % 3 == 0]\n third_values = [l[i] for i in third_indices]\n third_values.sort()\n for i, index in enumerate(third_indices):\n result[index] = third_values[i]\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n sorted_elements = sorted([l[i] for i in range(len(l)) if i % 3 == 0])\n result = l.copy()\n for i in range(len(l)):\n if i % 3 == 0:\n result[i] = sorted_elements.pop(0)\n return result", "matching_cluster_idx": 7}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n new_list = l[:] # Create a copy of the input list to avoid modifying the original\n third_elements = [l[i] for i in range(len(l)) if i % 3 == 0]\n third_elements.sort()\n for i in range(len(l)):\n if i % 3 == 0:\n new_list[i] = third_elements.pop(0)\n return new_list", "matching_cluster_idx": 7}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n l_sorted = sorted([l[i] for i in range(len(l)) if i % 3 == 0])\n result = []\n j = 0\n for i in range(len(l)):\n if i % 3 == 0:\n result.append(l_sorted[j])\n j += 1\n else:\n result.append(l[i])\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n sorted_third_elements = sorted([l[i] for i in range(len(l)) if i % 3 == 0])\n result = []\n for i in range(len(l)):\n if i % 3 == 0:\n result.append(sorted_third_elements.pop(0))\n else:\n result.append(l[i])\n return result", "matching_cluster_idx": 7}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n l_sorted = sorted([l[i] for i in range(len(l)) if i % 3 == 0])\n new_list = []\n for i in range(len(l)):\n if i % 3 == 0:\n new_list.append(l_sorted.pop(0))\n else:\n new_list.append(l[i])\n return new_list", "matching_cluster_idx": 7}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n new_list = l.copy()\n third_indices = [i for i in range(len(l)) if i % 3 == 0]\n third_values = [l[i] for i in third_indices]\n third_values.sort()\n for i, index in enumerate(third_indices):\n new_list[index] = third_values[i]\n return new_list", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n l_prime = l[:] \n third_indices = [i for i in range(len(l)) if i % 3 == 0]\n values = [l[i] for i in third_indices]\n values.sort()\n for i, index in enumerate(third_indices):\n l_prime[index] = values[i]\n return l_prime", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n result = l[:] # Create a copy of the input list\n third_elements = [l[i] for i in range(len(l)) if i % 3 == 0]\n third_elements.sort()\n for i in range(len(l)):\n if i % 3 == 0:\n result[i] = third_elements.pop(0)\n return result", "matching_cluster_idx": 7}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n result = l[:] # Create a copy of the list\n third_elements = [l[i] for i in range(len(l)) if i % 3 == 0]\n third_elements.sort()\n for i in range(len(l)):\n if i % 3 == 0:\n result[i] = third_elements.pop(0)\n return result", "matching_cluster_idx": 7}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n l_sorted = sorted([l[i] for i in range(len(l)) if i % 3 == 0])\n result = []\n j = 0\n for i in range(len(l)):\n if i % 3 == 0:\n result.append(l_sorted[j])\n j += 1\n else:\n result.append(l[i])\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n l_prime = l.copy()\n third_elements = [l[i] for i in range(len(l)) if i % 3 == 0]\n third_elements.sort()\n for i in range(len(l)):\n if i % 3 == 0:\n l_prime[i] = third_elements.pop(0)\n return l_prime", "matching_cluster_idx": 7}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n l_sorted = sorted([l[i] for i in range(len(l)) if i % 3 == 0])\n result = []\n j = 0\n for i in range(len(l)):\n if i % 3 == 0:\n result.append(l_sorted[j])\n j += 1\n else:\n result.append(l[i])\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n l_prime = l.copy()\n third_elements = [l[i] for i in range(len(l)) if i % 3 == 0]\n third_elements.sort()\n for i in range(len(l)):\n if i % 3 == 0:\n l_prime[i] = third_elements.pop(0)\n return l_prime", "matching_cluster_idx": 7}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n l_sorted = sorted([l[i] for i in range(len(l)) if i % 3 == 0])\n result = []\n j = 0\n for i in range(len(l)):\n if i % 3 == 0:\n result.append(l_sorted[j])\n j += 1\n else:\n result.append(l[i])\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n third_indices = [i for i in range(len(l)) if i % 3 == 0]\n third_values = [l[i] for i in third_indices]\n third_values.sort()\n l_sorted = [l[i] if i % 3 != 0 else third_values.pop(0) for i in range(len(l))]\n return l_sorted", "matching_cluster_idx": 7}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n l_sorted = sorted([l[i] for i in range(len(l)) if i % 3 == 0])\n l_result = [l[i] if i % 3 != 0 else l_sorted.pop(0) for i in range(len(l))]\n return l_result", "matching_cluster_idx": 7}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n new_list = l[:]\n third_elements = [l[i] for i in range(len(l)) if i % 3 == 0]\n third_elements.sort()\n for i in range(len(l)):\n if i % 3 == 0:\n new_list[i] = third_elements.pop(0)\n return new_list", "matching_cluster_idx": 7}]}, "HumanEval/34": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}]}, "HumanEval/36": {"dps": 96.77419354838709, "dps_norm": 71.42857142857143, "pass@1": 100.0, "profiled": [{"solution": "def fizz_buzz(n: int):\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count(\"7\") \n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int):\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n for i in range(n):\n if (i % 11 == 0 or i % 13 == 0):\n count += str(i).count(\"7\")\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int):\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n for i in range(n):\n if (i % 11 == 0 or i % 13 == 0) and '7' in str(i):\n count += str(i).count('7') \n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int):\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int):\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n for i in range(n):\n if (i % 11 == 0 or i % 13 == 0):\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int):\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n for i in range(n):\n if (i % 11 == 0 or i % 13 == 0) and '7' in str(i):\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int):\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int):\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n for i in range(n):\n if (i % 11 == 0 or i % 13 == 0):\n for digit in str(i):\n if digit == '7':\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int):\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n for i in range(n):\n if (i % 11 == 0 or i % 13 == 0) and '7' in str(i):\n count += str(i).count('7') \n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int):\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n for i in range(n):\n if (i % 11 == 0 or i % 13 == 0):\n count += str(i).count('7') \n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int):\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int):\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int):\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n for digit in str(i):\n if digit == '7':\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int):\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int):\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count(\"7\") \n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int):\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n for i in range(n):\n if (i % 11 == 0 or i % 13 == 0):\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int):\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int):\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n\n count = 0\n for i in range(n):\n if (i % 11 == 0 or i % 13 == 0):\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int):\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int):\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}]}, "HumanEval/37": {"dps": 94.92635024549918, "dps_norm": 90.0, "pass@1": 100.0, "profiled": [{"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n even_nums = sorted([l[i] for i in range(len(l)) if i % 2 == 0])\n result = [None] * len(l)\n result[::2] = even_nums\n result[1::2] = l[1::2]\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n even_indices = l[::2]\n even_indices.sort()\n result = []\n for i in range(len(l)):\n if i % 2 == 0:\n result.append(even_indices.pop(0))\n else:\n result.append(l[i])\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n even_nums = sorted([l[i] for i in range(len(l)) if i % 2 == 0])\n l_prime = []\n for i in range(len(l)):\n if i % 2 == 0:\n l_prime.append(even_nums.pop(0))\n else:\n l_prime.append(l[i])\n return l_prime", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n even_nums = sorted([l[i] for i in range(len(l)) if i%2 == 0])\n result = []\n j = 0\n for i in range(len(l)):\n if i % 2 == 0:\n result.append(even_nums[j])\n j += 1\n else:\n result.append(l[i])\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n even_elements = sorted([l[i] for i in range(len(l)) if i % 2 == 0])\n result = [None] * len(l)\n result[::2] = even_elements\n result[1::2] = l[1::2]\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n even_nums = sorted([l[i] for i in range(len(l)) if i % 2 == 0])\n result = [None] * len(l)\n result[::2] = even_nums \n result[1::2] = l[1::2]\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n even_nums = sorted([l[i] for i in range(len(l)) if i % 2 == 0])\n result = []\n for i in range(len(l)):\n if i % 2 == 0:\n result.append(even_nums.pop(0))\n else:\n result.append(l[i])\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n even_indices = l[::2]\n even_indices.sort()\n result = []\n for i in range(len(l)):\n if i % 2 == 0:\n result.append(even_indices.pop(0))\n else:\n result.append(l[i])\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n even_indices = sorted([l[i] for i in range(len(l)) if i % 2 == 0])\n result = []\n for i in range(len(l)):\n if i % 2 == 0:\n result.append(even_indices.pop(0))\n else:\n result.append(l[i])\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n even_indices = sorted([l[i] for i in range(len(l)) if i % 2 == 0])\n new_list = []\n for i in range(len(l)):\n if i % 2 == 0:\n new_list.append(even_indices.pop(0))\n else:\n new_list.append(l[i])\n return new_list", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n even_indices = sorted([l[i] for i in range(len(l)) if i % 2 == 0])\n result = []\n for i in range(len(l)):\n if i % 2 == 0:\n result.append(even_indices.pop(0))\n else:\n result.append(l[i])\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n even_nums = sorted([l[i] for i in range(len(l)) if i % 2 == 0])\n result = [None] * len(l)\n for i in range(len(l)):\n if i % 2 == 0:\n result[i] = even_nums.pop(0)\n else:\n result[i] = l[i]\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n even_indices = l[::2]\n even_indices.sort()\n sorted_list = []\n for i in range(len(l)):\n if i % 2 == 0:\n sorted_list.append(even_indices.pop(0))\n else:\n sorted_list.append(l[i])\n return sorted_list", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n even_nums = sorted([l[i] for i in range(len(l)) if i % 2 == 0])\n result = []\n for i in range(len(l)):\n if i % 2 == 0:\n result.append(even_nums.pop(0))\n else:\n result.append(l[i])\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n even_numbers = sorted([l[i] for i in range(len(l)) if i % 2 == 0])\n result = []\n for i in range(len(l)):\n if i % 2 == 0:\n result.append(even_numbers.pop(0))\n else:\n result.append(l[i])\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n even_nums = sorted([l[i] for i in range(len(l)) if i%2 == 0])\n result = []\n for i in range(len(l)):\n if i % 2 == 0:\n result.append(even_nums.pop(0))\n else:\n result.append(l[i])\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n even_nums = sorted([l[i] for i in range(len(l)) if i % 2 == 0])\n result = [None] * len(l)\n result[::2] = even_nums\n result[1::2] = l[1::2]\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n even_indices = sorted([l[i] for i in range(len(l)) if i % 2 == 0])\n result = []\n for i in range(len(l)):\n if i % 2 == 0:\n result.append(even_indices.pop(0))\n else:\n result.append(l[i])\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n even_indices = sorted([l[i] for i in range(len(l)) if i % 2 == 0])\n result = []\n for i in range(len(l)):\n if i % 2 == 0:\n result.append(even_indices.pop(0))\n else:\n result.append(l[i])\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n even_nums = sorted([l[i] for i in range(len(l)) if i % 2 == 0])\n result = []\n for i in range(len(l)):\n if i % 2 == 0:\n result.append(even_nums.pop(0))\n else:\n result.append(l[i])\n return result", "matching_cluster_idx": 8}]}, "HumanEval/49": {"dps": null, "dps_norm": null, "pass@1": 0.0, "profiled": []}, "HumanEval/51": {"dps": 96.13526570048309, "dps_norm": 75.0, "pass@1": 100.0, "profiled": [{"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = 'aeiouAEIOU'\n result = ''.join([char for char in text if char not in vowels])\n return result", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = set('aeiouAEIOU')\n result = ''.join([char for char in text if char not in vowels])\n return result", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n return \"\".join([letter for letter in text if letter not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = 'aeiouAEIOU'\n result = ''.join([letter for letter in text if letter not in vowels])\n return result", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = set('aeiouAEIOU')\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = 'aeiouAEIOU'\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n result = ''.join([char for char in text if char not in vowels])\n return result", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n result = []\n for char in text:\n if char not in vowels:\n result.append(char)\n return \"\".join(result)", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n result = ''.join([char for char in text if char not in vowels])\n return result", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = 'aeiouAEIOU'\n result = ''.join([char for char in text if char not in vowels])\n return result", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = 'aeiouAEIOU'\n result = ''.join([char for char in text if char not in vowels])\n return result", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n result = ''.join([char for char in text if char not in vowels])\n return result", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = 'aeiouAEIOU'\n result = ''\n for char in text:\n if char not in vowels:\n result += char\n return result", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n return ''.join([letter for letter in text if letter not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n return \"\".join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = 'aeiouAEIOU'\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = 'aeiouAEIOU'\n result = ''.join([char for char in text if char not in vowels])\n return result", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n result = \"\".join([char for char in text if char not in vowels])\n return result", "matching_cluster_idx": 5}]}, "HumanEval/54": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 79.0, "profiled": [{"solution": "def same_chars(s0: str, s1: str):\n \"\"\"\n Check if two words have the same characters.\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')\n True\n >>> same_chars('abcd', 'dddddddabc')\n True\n >>> same_chars('dddddddabc', 'abcd')\n True\n >>> same_chars('eabcd', 'dddddddabc')\n False\n >>> same_chars('abcd', 'dddddddabce')\n False\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')\n False\n \"\"\"\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str):\n \"\"\"\n Check if two words have the same characters.\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')\n True\n >>> same_chars('abcd', 'dddddddabc')\n True\n >>> same_chars('dddddddabc', 'abcd')\n True\n >>> same_chars('eabcd', 'dddddddabc')\n False\n >>> same_chars('abcd', 'dddddddabce')\n False\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')\n False\n \"\"\"\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str):\n \"\"\"\n Check if two words have the same characters.\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')\n True\n >>> same_chars('abcd', 'dddddddabc')\n True\n >>> same_chars('dddddddabc', 'abcd')\n True\n >>> same_chars('eabcd', 'dddddddabc')\n False\n >>> same_chars('abcd', 'dddddddabce')\n False\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')\n False\n \"\"\"\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str):\n \"\"\"\n Check if two words have the same characters.\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')\n True\n >>> same_chars('abcd', 'dddddddabc')\n True\n >>> same_chars('dddddddabc', 'abcd')\n True\n >>> same_chars('eabcd', 'dddddddabc')\n False\n >>> same_chars('abcd', 'dddddddabce')\n False\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')\n False\n \"\"\"\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str):\n \"\"\"\n Check if two words have the same characters.\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')\n True\n >>> same_chars('abcd', 'dddddddabc')\n True\n >>> same_chars('dddddddabc', 'abcd')\n True\n >>> same_chars('eabcd', 'dddddddabc')\n False\n >>> same_chars('abcd', 'dddddddabce')\n False\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')\n False\n \"\"\"\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str):\n \"\"\"\n Check if two words have the same characters.\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')\n True\n >>> same_chars('abcd', 'dddddddabc')\n True\n >>> same_chars('dddddddabc', 'abcd')\n True\n >>> same_chars('eabcd', 'dddddddabc')\n False\n >>> same_chars('abcd', 'dddddddabce')\n False\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')\n False\n \"\"\"\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str):\n \"\"\"\n Check if two words have the same characters.\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')\n True\n >>> same_chars('abcd', 'dddddddabc')\n True\n >>> same_chars('dddddddabc', 'abcd')\n True\n >>> same_chars('eabcd', 'dddddddabc')\n False\n >>> same_chars('abcd', 'dddddddabce')\n False\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')\n False\n \"\"\"\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str):\n \"\"\"\n Check if two words have the same characters.\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')\n True\n >>> same_chars('abcd', 'dddddddabc')\n True\n >>> same_chars('dddddddabc', 'abcd')\n True\n >>> same_chars('eabcd', 'dddddddabc')\n False\n >>> same_chars('abcd', 'dddddddabce')\n False\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')\n False\n \"\"\"\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str):\n \"\"\"\n Check if two words have the same characters.\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')\n True\n >>> same_chars('abcd', 'dddddddabc')\n True\n >>> same_chars('dddddddabc', 'abcd')\n True\n >>> same_chars('eabcd', 'dddddddabc')\n False\n >>> same_chars('abcd', 'dddddddabce')\n False\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')\n False\n \"\"\"\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str):\n \"\"\"\n Check if two words have the same characters.\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')\n True\n >>> same_chars('abcd', 'dddddddabc')\n True\n >>> same_chars('dddddddabc', 'abcd')\n True\n >>> same_chars('eabcd', 'dddddddabc')\n False\n >>> same_chars('abcd', 'dddddddabce')\n False\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')\n False\n \"\"\"\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str):\n \"\"\"\n Check if two words have the same characters.\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')\n True\n >>> same_chars('abcd', 'dddddddabc')\n True\n >>> same_chars('dddddddabc', 'abcd')\n True\n >>> same_chars('eabcd', 'dddddddabc')\n False\n >>> same_chars('abcd', 'dddddddabce')\n False\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')\n False\n \"\"\"\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str):\n \"\"\"\n Check if two words have the same characters.\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')\n True\n >>> same_chars('abcd', 'dddddddabc')\n True\n >>> same_chars('dddddddabc', 'abcd')\n True\n >>> same_chars('eabcd', 'dddddddabc')\n False\n >>> same_chars('abcd', 'dddddddabce')\n False\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')\n False\n \"\"\"\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str):\n \"\"\"\n Check if two words have the same characters.\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')\n True\n >>> same_chars('abcd', 'dddddddabc')\n True\n >>> same_chars('dddddddabc', 'abcd')\n True\n >>> same_chars('eabcd', 'dddddddabc')\n False\n >>> same_chars('abcd', 'dddddddabce')\n False\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')\n False\n \"\"\"\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str):\n \"\"\"\n Check if two words have the same characters.\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')\n True\n >>> same_chars('abcd', 'dddddddabc')\n True\n >>> same_chars('dddddddabc', 'abcd')\n True\n >>> same_chars('eabcd', 'dddddddabc')\n False\n >>> same_chars('abcd', 'dddddddabce')\n False\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')\n False\n \"\"\"\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str):\n \"\"\"\n Check if two words have the same characters.\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')\n True\n >>> same_chars('abcd', 'dddddddabc')\n True\n >>> same_chars('dddddddabc', 'abcd')\n True\n >>> same_chars('eabcd', 'dddddddabc')\n False\n >>> same_chars('abcd', 'dddddddabce')\n False\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')\n False\n \"\"\"\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str):\n \"\"\"\n Check if two words have the same characters.\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')\n True\n >>> same_chars('abcd', 'dddddddabc')\n True\n >>> same_chars('dddddddabc', 'abcd')\n True\n >>> same_chars('eabcd', 'dddddddabc')\n False\n >>> same_chars('abcd', 'dddddddabce')\n False\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')\n False\n \"\"\"\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str):\n \"\"\"\n Check if two words have the same characters.\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')\n True\n >>> same_chars('abcd', 'dddddddabc')\n True\n >>> same_chars('dddddddabc', 'abcd')\n True\n >>> same_chars('eabcd', 'dddddddabc')\n False\n >>> same_chars('abcd', 'dddddddabce')\n False\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')\n False\n \"\"\"\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str):\n \"\"\"\n Check if two words have the same characters.\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')\n True\n >>> same_chars('abcd', 'dddddddabc')\n True\n >>> same_chars('dddddddabc', 'abcd')\n True\n >>> same_chars('eabcd', 'dddddddabc')\n False\n >>> same_chars('abcd', 'dddddddabce')\n False\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')\n False\n \"\"\"\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str):\n \"\"\"\n Check if two words have the same characters.\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')\n True\n >>> same_chars('abcd', 'dddddddabc')\n True\n >>> same_chars('dddddddabc', 'abcd')\n True\n >>> same_chars('eabcd', 'dddddddabc')\n False\n >>> same_chars('abcd', 'dddddddabce')\n False\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')\n False\n \"\"\"\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str):\n \"\"\"\n Check if two words have the same characters.\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')\n True\n >>> same_chars('abcd', 'dddddddabc')\n True\n >>> same_chars('dddddddabc', 'abcd')\n True\n >>> same_chars('eabcd', 'dddddddabc')\n False\n >>> same_chars('abcd', 'dddddddabce')\n False\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')\n False\n \"\"\"\n return set(s0) == set(s1)", "matching_cluster_idx": 6}]}, "HumanEval/58": {"dps": 92.51968503937007, "dps_norm": 83.33333333333333, "pass@1": 100.0, "profiled": [{"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n\n \"\"\"\n common_elements = set(l1) & set(l2)\n return sorted(list(common_elements))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n\n \"\"\"\n return sorted(set(l1) & set(l2))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n\n \"\"\"\n return sorted(set(l1) & set(l2))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n\n \"\"\"\n return sorted(set(l1) & set(l2))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n\n \"\"\"\n return sorted(list(set(l1) & set(l2)))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n\n \"\"\"\n return sorted(list(set(l1) & set(l2)))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n\n \"\"\"\n return sorted(list(set(l1) & set(l2)))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n\n \"\"\"\n return sorted(set(l1) & set(l2))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n\n \"\"\"\n return sorted(set(l1) & set(l2))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n\n \"\"\"\n return sorted(set(l1) & set(l2))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n\n \"\"\"\n return sorted(set(l1) & set(l2))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n\n \"\"\"\n common_elements = list(set(l1) & set(l2))\n return sorted(common_elements)", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n\n \"\"\"\n common_elements = list(set(l1) & set(l2)) # Using set intersection for efficiency\n common_elements.sort() # Sorting the common elements\n return common_elements", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n\n \"\"\"\n return sorted(list(set(l1) & set(l2)))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n\n \"\"\"\n common_elements = set(l1) & set(l2)\n return sorted(list(common_elements))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n\n \"\"\"\n return sorted(set(l1) & set(l2))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n\n \"\"\"\n return sorted(set(l1) & set(l2))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n\n \"\"\"\n return sorted(set(l1) & set(l2))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n\n \"\"\"\n return sorted(list(set(l1) & set(l2)))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n\n \"\"\"\n return sorted(set(l1) & set(l2))", "matching_cluster_idx": 4}]}, "HumanEval/59": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n largest_factor = 1\n i = 2\n while i * i <= n:\n if n % i == 0:\n largest_factor = i\n n //= i\n else:\n i += 1\n if n > largest_factor:\n largest_factor = n\n return largest_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n largest_factor = 1\n i = 2\n while i * i <= n:\n if n % i == 0:\n largest_factor = i\n n //= i\n else:\n i += 1\n if n > largest_factor:\n largest_factor = n\n return largest_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n largest_factor = 1\n i = 2\n while i * i <= n:\n if n % i == 0:\n largest_factor = i\n n //= i\n else:\n i += 1\n if n > largest_factor:\n largest_factor = n\n return largest_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n i = 2\n while i * i <= n:\n if n % i:\n i += 1\n else:\n n //= i\n return n", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n largest_factor = 1\n i = 2\n while i * i <= n:\n if n % i == 0:\n largest_factor = i\n n //= i\n else:\n i += 1\n if n > largest_factor:\n largest_factor = n\n return largest_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n i = 2\n while i * i <= n:\n if n % i:\n i += 1\n else:\n n //= i\n return n", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n\n largest_factor = 1\n i = 2\n while i * i <= n:\n if n % i == 0:\n largest_factor = i\n n //= i \n else:\n i += 1\n if n > largest_factor:\n largest_factor = n\n return largest_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n i = 2\n while i * i <= n:\n if n % i:\n i += 1\n else:\n n //= i\n return n", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n i = 2\n while i * i <= n:\n if n % i:\n i += 1\n else:\n n //= i\n return n", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n i = 2\n while i * i <= n:\n if n % i:\n i += 1\n else:\n n //= i\n return n", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n largest_factor = 1\n i = 2\n while i * i <= n:\n if n % i == 0:\n largest_factor = i\n n //= i\n else:\n i += 1\n if n > largest_factor: # handle the case where n itself is prime\n largest_factor = n\n return largest_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n largest_factor = 1\n i = 2\n while i * i <= n:\n if n % i == 0:\n largest_factor = i\n n //= i\n else:\n i += 1\n if n > largest_factor:\n largest_factor = n\n return largest_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n largest_factor = 1\n i = 2\n while i * i <= n:\n if n % i == 0:\n largest_factor = i\n n //= i\n else:\n i += 1\n if n > largest_factor:\n largest_factor = n\n return largest_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n largest_factor = 1\n i = 2\n while i * i <= n:\n if n % i == 0:\n largest_factor = i\n n //= i\n else:\n i += 1\n if n > largest_factor:\n largest_factor = n\n return largest_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n i = 2\n while i * i <= n:\n if n % i:\n i += 1\n else:\n n //= i\n return n", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n largest_factor = 1\n\n # Divide by 2 until n is odd\n while n % 2 == 0:\n largest_factor = 2\n n //= 2\n\n # Check odd divisors from 3 up to the square root of n\n i = 3\n while i * i <= n:\n if n % i == 0:\n largest_factor = i\n n //= i\n else:\n i += 2\n \n # If n is greater than 1 at this point, it's the largest prime factor\n if n > 1:\n largest_factor = n\n \n return largest_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n largest_factor = 1\n i = 2\n while i * i <= n:\n if n % i == 0:\n largest_factor = i\n n //= i\n else:\n i += 1\n if n > largest_factor:\n largest_factor = n\n return largest_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n largest_factor = 1\n i = 2\n while i * i <= n:\n if n % i == 0:\n largest_factor = i\n n //= i\n else:\n i += 1\n if n > largest_factor:\n largest_factor = n\n return largest_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n i = 2\n while i * i <= n:\n if n % i:\n i += 1\n else:\n n //= i\n return n", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n i = 2\n while i * i <= n:\n if n % i:\n i += 1\n else:\n n //= i\n return n", "matching_cluster_idx": 8}]}, "HumanEval/64": {"dps": 77.20779220779221, "dps_norm": 58.125, "pass@1": 25.0, "profiled": [{"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = set('aeiouAEIOU')\n count = 0\n for letter in s:\n if letter in vowels:\n count += 1\n if s.lower().endswith('y'):\n count+=1\n return count", "matching_cluster_idx": 4}, {"solution": "import doctest\ndef vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = 'aeiouAEIOU'\n count = 0\n for char in s:\n if char in vowels:\n count += 1\n if s.lower().endswith('y'):\n count += 1 \n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = 'aeiouAEIOU'\n count = 0\n for letter in s:\n if letter in vowels:\n count += 1\n if s.lower().endswith('y'):\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "import doctest\ndef vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = 'aeiou'\n count = 0\n s = s.lower()\n for char in s:\n if char in vowels:\n count += 1\n if s.endswith('y'):\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = set('aeiou')\n count = 0\n for i, char in enumerate(s.lower()):\n if char in vowels:\n count += 1\n elif char == 'y' and i == len(s) - 1:\n count += 1\n return count", "matching_cluster_idx": 3}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = \"aeiou\"\n count = 0\n for char in s.lower():\n if char in vowels:\n count += 1\n if s.lower().endswith('y'):\n count += 1\n return count", "matching_cluster_idx": 3}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = set('aeiouAEIOU')\n count = 0\n for letter in s:\n if letter in vowels:\n count += 1\n if s.lower().endswith('y'):\n count +=1\n return count", "matching_cluster_idx": 4}, {"solution": "import doctest\ndef vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = 'aeiouAEIOU'\n count = 0\n for char in s:\n if char in vowels:\n count +=1\n if s.lower().endswith('y'):\n count+=1\n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = set('aeiouAEIOU')\n count = 0\n for letter in s:\n if letter in vowels:\n count += 1\n if s.lower().endswith('y'):\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "import doctest\ndef vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = set('aeiouAEIOU')\n count = 0\n for letter in s:\n if letter in vowels:\n count += 1\n if s.lower().endswith('y'):\n count +=1 \n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = 'aeiou'\n count = 0\n for i in s.lower():\n if i in vowels:\n count += 1\n if s.lower().endswith('y'):\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = set('aeiou')\n count = 0\n for i in range(len(s)):\n if s[i].lower() in vowels:\n count += 1\n if s.lower().endswith('y'):\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = set('aeiouAEIOU')\n count = 0\n for letter in s:\n if letter in vowels:\n count += 1\n if s.lower().endswith('y'):\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = set('aeiou')\n count = 0\n for letter in s.lower():\n if letter in vowels:\n count += 1\n if s.lower().endswith('y'):\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "import doctest\ndef vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = set('aeiouAEIOU')\n count = 0\n for char in s:\n if char in vowels:\n count += 1\n if s.lower().endswith('y'):\n count+=1\n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = 'aeiouAEIOU'\n count = 0\n for char in s:\n if char in vowels:\n count += 1\n if s.lower().endswith('y'):\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "import doctest\ndef vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = set('aeiouAEIOU')\n count = 0\n for letter in s:\n if letter in vowels:\n count += 1\n if s.lower().endswith('y'):\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = 'aeiou'\n count = 0\n for letter in s.lower():\n if letter in vowels:\n count += 1\n if s.lower().endswith('y'):\n count += 1\n return count", "matching_cluster_idx": 3}, {"solution": "import doctest\ndef vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = set('aeiouAEIOU')\n count = 0\n for letter in s:\n if letter in vowels:\n count += 1\n if s.lower().endswith('y'):\n count += 1 \n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = set('aeiouAEIOU')\n count = 0\n for i in range(len(s)):\n if s[i] in vowels:\n count += 1\n if s.lower().endswith('y'):\n count += 1\n return count", "matching_cluster_idx": 3}]}, "HumanEval/74": {"dps": 98.04878048780488, "dps_norm": 88.88888888888889, "pass@1": 99.0, "profiled": [{"solution": "def total_match(lst1, lst2):\n \"\"\"\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n \"\"\"\n total1 = sum(len(s) for s in lst1)\n total2 = sum(len(s) for s in lst2)\n\n if total1 < total2:\n return lst1\n elif total2 < total1:\n return lst2\n else:\n return lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n \"\"\"\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n \"\"\"\n total_chars1 = sum(len(s) for s in lst1)\n total_chars2 = sum(len(s) for s in lst2)\n\n if total_chars1 < total_chars2:\n return lst1\n elif total_chars2 < total_chars1:\n return lst2\n else:\n return lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n len1 = sum([len(s) for s in lst1])\n len2 = sum([len(s) for s in lst2])\n\n if len1 < len2:\n return lst1\n elif len2 < len1:\n return lst2\n else:\n return lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n total1 = sum(len(s) for s in lst1)\n total2 = sum(len(s) for s in lst2)\n if total1 < total2:\n return lst1\n elif total2 < total1:\n return lst2\n else:\n return lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n len1 = sum(len(s) for s in lst1)\n len2 = sum(len(s) for s in lst2)\n\n if len1 < len2:\n return lst1\n elif len2 < len1:\n return lst2\n else:\n return lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n total1 = sum(len(word) for word in lst1)\n total2 = sum(len(word) for word in lst2)\n\n if total1 < total2:\n return lst1\n elif total2 < total1:\n return lst2\n else:\n return lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n total1 = sum([len(x) for x in lst1])\n total2 = sum([len(x) for x in lst2])\n\n if total1 < total2:\n return lst1\n elif total2 < total1:\n return lst2\n else:\n return lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n total1 = sum(len(s) for s in lst1)\n total2 = sum(len(s) for s in lst2)\n if total1 < total2:\n return lst1\n elif total2 < total1:\n return lst2\n else:\n return lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n total_len1 = sum(len(word) for word in lst1)\n total_len2 = sum(len(word) for word in lst2)\n\n if total_len1 < total_len2:\n return lst1\n elif total_len2 < total_len1:\n return lst2\n else: \n return lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n \"\"\"\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n \"\"\"\n\n total1 = sum(len(word) for word in lst1)\n total2 = sum(len(word) for word in lst2)\n\n if total1 < total2:\n return lst1\n elif total2 < total1:\n return lst2\n else:\n return lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n \"\"\"\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n \"\"\"\n\n total1 = sum(len(word) for word in lst1)\n total2 = sum(len(word) for word in lst2)\n\n if total1 < total2:\n return lst1\n elif total2 < total1:\n return lst2\n else:\n return lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n \"\"\"\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n \"\"\"\n\n total_len1 = sum(len(s) for s in lst1)\n total_len2 = sum(len(s) for s in lst2)\n if total_len1 < total_len2:\n return lst1\n elif total_len2 < total_len1:\n return lst2\n else: \n return lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n \"\"\"\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n \"\"\"\n total1 = sum(len(x) for x in lst1)\n total2 = sum(len(x) for x in lst2)\n if total1 < total2:\n return lst1\n elif total2 < total1:\n return lst2\n else:\n return lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n total1 = sum(len(x) for x in lst1)\n total2 = sum(len(x) for x in lst2)\n \n if total1 < total2:\n return lst1\n elif total2 < total1:\n return lst2\n else:\n return lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n \"\"\"\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n \"\"\"\n total1 = sum(len(word) for word in lst1)\n total2 = sum(len(word) for word in lst2)\n if total1 < total2:\n return lst1\n elif total2 < total1:\n return lst2\n else:\n return lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n total_chars_lst1 = sum(len(s) for s in lst1)\n total_chars_lst2 = sum(len(s) for s in lst2)\n if total_chars_lst1 < total_chars_lst2:\n return lst1\n elif total_chars_lst2 < total_chars_lst1:\n return lst2\n else:\n return lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n total1 = sum(len(word) for word in lst1)\n total2 = sum(len(word) for word in lst2)\n if total1 < total2:\n return lst1\n elif total2 < total1:\n return lst2\n else:\n return lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n total_length1 = sum(len(s) for s in lst1)\n total_length2 = sum(len(s) for s in lst2)\n if total_length1 < total_length2:\n return lst1\n elif total_length2 < total_length1:\n return lst2\n else:\n return lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n total1 = sum(len(s) for s in lst1)\n total2 = sum(len(s) for s in lst2)\n\n return lst1 if total1 <= total2 else lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n total1 = sum(len(s) for s in lst1)\n total2 = sum(len(s) for s in lst2)\n\n if total1 < total2:\n return lst1\n elif total2 < total1:\n return lst2\n else:\n return lst1", "matching_cluster_idx": 7}]}, "HumanEval/85": {"dps": 96.36138613861385, "dps_norm": 65.83333333333334, "pass@1": 100.0, "profiled": [{"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices..\n\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n total = 0\n for i in range(1, len(lst), 2):\n if lst[i] % 2 == 0:\n total += lst[i]\n return total", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices..\n\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n total = 0\n for i in range(1, len(lst), 2): \n if lst[i] % 2 == 0:\n total += lst[i]\n return total", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices..\n\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n total = 0\n for i in range(1, len(lst), 2):\n if lst[i] % 2 == 0:\n total += lst[i]\n return total", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices..\n\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n sum = 0\n for i in range(1,len(lst),2):\n if lst[i]%2 == 0:\n sum += lst[i]\n return sum", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices..\n\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n total = 0\n for i in range(1, len(lst), 2):\n if lst[i] % 2 == 0:\n total += lst[i]\n return total", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices..\n\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n total = 0\n for i in range(1, len(lst), 2):\n if lst[i] % 2 == 0:\n total += lst[i]\n return total", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices.\n\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n total = 0\n for i in range(1, len(lst), 2):\n if lst[i] % 2 == 0:\n total += lst[i]\n return total", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices..\n\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n total = 0\n for i in range(1, len(lst), 2):\n if lst[i]%2==0:\n total+= lst[i]\n return total", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices..\n\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n total = 0\n for i in range(1,len(lst),2):\n if lst[i]%2 == 0:\n total += lst[i]\n return total", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices..\n\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n sum = 0\n for i in range(len(lst)):\n if i % 2 != 0 and lst[i] % 2 == 0:\n sum += lst[i]\n return sum", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices..\n\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n sum = 0\n for i in range(1, len(lst), 2):\n if lst[i]%2==0:\n sum += lst[i]\n return sum", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices..\n\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n total = 0\n for i in range(1, len(lst), 2):\n if lst[i] % 2 == 0:\n total += lst[i]\n return total", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices..\n\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n sum = 0\n for i in range(1, len(lst), 2):\n if lst[i] % 2 == 0:\n sum += lst[i]\n return sum", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices..\n\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n total = 0\n for i in range(1, len(lst), 2):\n if lst[i] % 2 == 0:\n total += lst[i]\n return total", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices..\n\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n total = 0\n for i in range(1, len(lst), 2):\n if lst[i] % 2 == 0:\n total += lst[i]\n return total", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices..\n\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n total = 0\n for i in range(1, len(lst), 2):\n if lst[i] % 2 == 0:\n total += lst[i]\n return total", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices..\n\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n total = 0\n for i in range(1, len(lst), 2):\n if lst[i] % 2 == 0:\n total += lst[i]\n return total", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices..\n\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n total = 0\n for i in range(1, len(lst), 2):\n if lst[i] % 2 == 0:\n total += lst[i]\n return total", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices..\n\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n total = 0\n for i in range(1, len(lst), 2):\n if lst[i] % 2 == 0:\n total += lst[i]\n return total", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices..\n\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n total = 0\n for i in range(1, len(lst), 2):\n if lst[i] % 2 == 0:\n total += lst[i]\n return total", "matching_cluster_idx": 3}]}, "HumanEval/86": {"dps": null, "dps_norm": null, "pass@1": 0.0, "profiled": []}, "HumanEval/87": {"dps": 78.19884726224784, "dps_norm": 52.85714285714286, "pass@1": 57.0, "profiled": [{"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n result = []\n for row_index, row in enumerate(lst):\n for col_index, value in enumerate(row):\n if value == x:\n result.append((row_index, col_index))\n\n result.sort(key=lambda item: (item[0], -item[1]))\n return result", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n result = []\n for i, row in enumerate(lst):\n for j, num in enumerate(row):\n if num == x:\n result.append((i, j))\n\n result.sort(key=lambda item: (item[0], -item[1])) \n return result", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n result = []\n for i, row in enumerate(lst):\n for j, num in enumerate(row):\n if num == x:\n result.append((i, j))\n result.sort() #Sort by rows\n for i in range(len(result)):\n for j in range(len(result)-1):\n if result[j][0] == result[j+1][0] and result[j][1] < result[j+1][1]:\n result[j], result[j+1] = result[j+1], result[j] #Sort by column (descending)\n\n return result", "matching_cluster_idx": 0}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n result = []\n for row_index, row in enumerate(lst):\n for col_index, element in enumerate(row):\n if element == x:\n result.append((row_index, col_index))\n \n result.sort(key=lambda x: (x[0], -x[1])) # Sort by row, then column in descending order\n return result", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n result = []\n for row_index, row in enumerate(lst):\n for col_index, value in enumerate(row):\n if value == x:\n result.append((row_index, col_index))\n \n result.sort(key=lambda x: (x[0], -x[1])) # sort by row, then by column (descending)\n\n return result", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n result = []\n for row_index, row in enumerate(lst):\n for col_index, element in enumerate(row):\n if element == x:\n result.append((row_index, col_index))\n \n result.sort(key=lambda tup: (tup[0], -tup[1]))\n return result", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n result = []\n for row_index, row in enumerate(lst):\n for col_index, value in enumerate(row):\n if value == x:\n result.append((row_index, col_index))\n\n result.sort()\n for i in range(len(result)):\n for j in range(i+1, len(result)):\n if result[i][0] == result[j][0] and result[i][1] < result[j][1]:\n result[i], result[j] = result[j], result[i]\n\n return result", "matching_cluster_idx": 2}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n result = []\n for row_index, row in enumerate(lst):\n for col_index, val in enumerate(row):\n if val == x:\n result.append((row_index, col_index))\n\n result.sort(key=lambda coord: (coord[0], -coord[1])) \n return result", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n result = []\n for row_index, row in enumerate(lst):\n for col_index, val in enumerate(row):\n if val == x:\n result.append((row_index, col_index))\n\n result.sort(key=lambda item: (item[0], -item[1]))\n return result", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n result = []\n for row_index, row in enumerate(lst):\n for col_index, value in enumerate(row):\n if value == x:\n result.append((row_index, col_index))\n result.sort(key=lambda x: (x[0], -x[1]))\n return result", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n result = []\n for row_index, row in enumerate(lst):\n for col_index, value in enumerate(row):\n if value == x:\n result.append((row_index, col_index))\n result.sort(key=lambda item: (item[0], -item[1])) # Sort by row then descending column\n return result", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n result = []\n for row_index, row in enumerate(lst):\n for col_index, val in enumerate(row):\n if val == x:\n result.append((row_index, col_index))\n result.sort()\n for i in range(len(result)):\n for j in range(i + 1, len(result)):\n if result[i][0] == result[j][0] and result[i][1] < result[j][1]:\n result[i], result[j] = result[j], result[i]\n\n return result", "matching_cluster_idx": 2}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n result = []\n for row_index, row in enumerate(lst):\n for col_index, value in enumerate(row):\n if value == x:\n result.append((row_index, col_index))\n\n result.sort(key=lambda coord: (coord[0], -coord[1])) # Sort by row then column (descending)\n return result", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n result = []\n for i, row in enumerate(lst):\n for j, element in enumerate(row):\n if element == x:\n result.append((i,j))\n return sorted(result, key=lambda x: (x[0], -x[1]))", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n result = []\n for row_index, row in enumerate(lst):\n for col_index, value in enumerate(row):\n if value == x:\n result.append((row_index, col_index))\n \n result.sort(key=lambda x: (x[0], -x[1])) \n return result", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n result = []\n for row_index, row in enumerate(lst):\n for col_index, value in enumerate(row):\n if value == x:\n result.append((row_index, col_index))\n\n result.sort(key=lambda item: (item[0], -item[1]))\n return result", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n result = []\n for row_index, row in enumerate(lst):\n for col_index, val in enumerate(row):\n if val == x:\n result.append((row_index, col_index))\n \n result.sort(key=lambda item: (item[0], -item[1]))\n return result", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n result = []\n for row_index, row in enumerate(lst):\n for col_index, val in enumerate(row):\n if val == x:\n result.append((row_index, col_index))\n \n result.sort(key=lambda x: (x[0], -x[1]))\n return result", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n result = []\n for i, row in enumerate(lst):\n for j, num in enumerate(row):\n if num == x:\n result.append((i, j))\n\n result.sort()\n for i in range(len(result)):\n for j in range(i + 1, len(result)):\n if result[i][0] == result[j][0] and result[i][1] < result[j][1]:\n result[i], result[j] = result[j], result[i]\n return result", "matching_cluster_idx": 2}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n result = []\n for row_index, row in enumerate(lst):\n for col_index, value in enumerate(row):\n if value == x:\n result.append((row_index, col_index))\n result.sort(key=lambda item: (item[0], -item[1])) \n return result", "matching_cluster_idx": 3}]}, "HumanEval/89": {"dps": 96.64948453608248, "dps_norm": 28.571428571428573, "pass@1": 100.0, "profiled": [{"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n result = []\n for char in s:\n if char.isalpha():\n start = ord('a') if char.islower() else ord('A')\n shifted_char = chr((ord(char) - start + 4) % 26 + start) \n else:\n shifted_char = char\n result.append(shifted_char)\n\n return ''.join(result)", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n result = []\n for char in s:\n if char.isalpha():\n start = ord('a') if char.islower() else ord('A')\n shifted_char = chr((ord(char) - start + 4) % 26 + start) \n result.append(shifted_char)\n else:\n result.append(char)\n return ''.join(result)", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n result = []\n for letter in s:\n if letter.isalpha():\n start = ord('a') if letter.islower() else ord('A')\n shifted_letter = chr((ord(letter) - start + 4) % 26 + start)\n else:\n shifted_letter = letter\n result.append(shifted_letter)\n return ''.join(result)", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n result = []\n for char in s:\n if char.isalpha():\n start = ord('a') if char.islower() else ord('A')\n shifted_char = chr((ord(char) - start + (2 * 2)) % 26 + start)\n else:\n shifted_char = char\n result.append(shifted_char)\n return ''.join(result)", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n result = []\n for char in s:\n if char.isalpha():\n start = ord('a') if char.islower() else ord('A')\n shifted_char = chr((ord(char) - start + 4) % 26 + start)\n result.append(shifted_char)\n else:\n result.append(char)\n return ''.join(result)", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n result = []\n for char in s:\n if char.isalpha():\n start = ord('a') if char.islower() else ord('A')\n shifted_char = chr((ord(char) - start + 4) % 26 + start)\n else:\n shifted_char = char\n result.append(shifted_char)\n return ''.join(result)", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n result = []\n for char in s:\n if char.isalpha():\n start = ord('a') if char.islower() else ord('A')\n shifted_char = chr((ord(char) - start + 4) % 26 + start)\n result.append(shifted_char)\n else:\n result.append(char)\n return ''.join(result)", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n result = []\n for char in s:\n if char.isalpha():\n start = ord('a') if char.islower() else ord('A')\n shifted_char = chr((ord(char) - start + 4) % 26 + start)\n result.append(shifted_char)\n else:\n result.append(char)\n return ''.join(result)", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n result = []\n for char in s:\n if char.isalpha():\n start = ord('a') if char.islower() else ord('A')\n shifted_char = chr((ord(char) - start + (2*2)) % 26 + start)\n else:\n shifted_char = char \n result.append(shifted_char)\n return ''.join(result)", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n result = []\n for char in s:\n if char.isalpha():\n start = ord('a') if char.islower() else ord('A')\n shifted_char = chr((ord(char) - start + 4) % 26 + start)\n else:\n shifted_char = char\n result.append(shifted_char)\n return ''.join(result)", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n result = []\n for char in s:\n if char.isalpha():\n start = ord('a') if char.islower() else ord('A')\n shifted_char = chr((ord(char) - start + 4) % 26 + start)\n result.append(shifted_char)\n else:\n result.append(char)\n return ''.join(result)", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n result = []\n for char in s:\n if char.isalpha():\n start = ord('a') if char.islower() else ord('A')\n shifted_char = chr((ord(char) - start + 4) % 26 + start) \n else:\n shifted_char = char\n result.append(shifted_char)\n return ''.join(result)", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n result = []\n for char in s:\n if char.isalpha():\n start = ord('a') if char.islower() else ord('A')\n shifted_char = chr((ord(char) - start + 4) % 26 + start) \n else:\n shifted_char = char\n result.append(shifted_char)\n return ''.join(result)", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n\n result = []\n for char in s:\n if char.isalpha():\n start = ord('a') if char.islower() else ord('A')\n shifted_char = chr((ord(char) - start + 4) % 26 + start) \n else:\n shifted_char = char\n result.append(shifted_char)\n return ''.join(result)", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated.\n The alphabet should be rotated in a manner such that the letters\n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n result = []\n for char in s:\n if char.isalpha():\n start = ord('a') if char.islower() else ord('A')\n shifted_char = chr((ord(char) - start + 4) % 26 + start)\n else:\n shifted_char = char\n result.append(shifted_char)\n return ''.join(result)", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n result = []\n for char in s:\n if char.isalpha():\n start = ord('a') if char.islower() else ord('A')\n shifted_char = chr((ord(char) - start + 4) % 26 + start) \n else:\n shifted_char = char\n result.append(shifted_char)\n return ''.join(result)", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n result = []\n for char in s:\n if char.isalpha():\n start = ord('a') if char.islower() else ord('A')\n shifted_char = chr((ord(char) - start + 4) % 26 + start)\n else:\n shifted_char = char\n result.append(shifted_char)\n return \"\".join(result)", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n result = []\n for char in s:\n if char.isalpha():\n start = ord('a') if char.islower() else ord('A')\n shifted_char = chr((ord(char) - start + 4) % 26 + start) \n else:\n shifted_char = char\n result.append(shifted_char)\n return ''.join(result)", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n result = []\n for char in s:\n if char.isalpha():\n start = ord('a') if char.islower() else ord('A')\n shifted_char = chr((ord(char) - start + 4) % 26 + start)\n else:\n shifted_char = char\n result.append(shifted_char)\n return ''.join(result)", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n result = []\n for char in s:\n if char.isalpha():\n start = ord('a') if char.islower() else ord('A')\n shifted_char = chr((ord(char) - start + 4) % 26 + start)\n result.append(shifted_char)\n else:\n result.append(char)\n return ''.join(result)", "matching_cluster_idx": 1}]}, "HumanEval/90": {"dps": 72.68482490272373, "dps_norm": 56.66666666666667, "pass@1": 74.0, "profiled": [{"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n \n unique_lst = sorted(set(lst)) # Remove duplicates and sort\n if len(unique_lst) < 2:\n return None\n return unique_lst[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n\n unique_sorted_lst = sorted(set(lst))\n if len(unique_sorted_lst) < 2:\n return None\n \n return unique_sorted_lst[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n\n unique_lst = sorted(set(lst))\n if len(unique_lst) < 2:\n return None\n\n return unique_lst[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n \n # Find the smallest element\n smallest = min(lst)\n\n # Find the second smallest element \n second_smallest = float('inf') # Initialize with a large value\n for num in lst:\n if num != smallest and num < second_smallest:\n second_smallest = num\n \n if second_smallest == float('inf'):\n return None\n else:\n return second_smallest", "matching_cluster_idx": 3}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n\n unique_elements = sorted(set(lst)) \n return unique_elements[1] if len(unique_elements) > 1 else None", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n\n #Find the smallest and second smallest elements\n smallest = min(lst)\n second_smallest = float('inf') \n for num in lst:\n if num != smallest and num < second_smallest:\n second_smallest = num\n if second_smallest == float('inf'):\n return None\n\n return second_smallest", "matching_cluster_idx": 3}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n \n unique_lst = sorted(set(lst)) \n return unique_lst[1] if len(unique_lst) > 1 else None", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n\n unique_lst = sorted(set(lst))\n if len(unique_lst) < 2:\n return None\n\n return unique_lst[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n\n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n\n if len(lst) < 2:\n return None\n \n # Sort the list in ascending order\n sorted_lst = sorted(lst)\n \n # Find the smallest element\n smallest = sorted_lst[0]\n \n # Find the next smallest element\n for i in range(1, len(sorted_lst)):\n if sorted_lst[i] != smallest:\n return sorted_lst[i]\n \n return None", "matching_cluster_idx": 10}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n\n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n \n unique_lst = sorted(set(lst))\n return unique_lst[1] if len(unique_lst) > 1 else None", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n \n unique_lst = sorted(set(lst))\n \n if len(unique_lst) < 2:\n return None\n \n return unique_lst[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n\n smallest = min(lst)\n second_smallest = float('inf')\n for num in lst:\n if num != smallest and num < second_smallest:\n second_smallest = num\n\n return second_smallest if second_smallest != float('inf') else None", "matching_cluster_idx": 3}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n\n unique_lst = sorted(set(lst))\n\n if len(unique_lst) < 2:\n return None\n\n return unique_lst[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n \n unique_lst = sorted(set(lst))\n return unique_lst[1] if len(unique_lst) > 1 else None", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n unique_lst = sorted(set(lst))\n if len(unique_lst) < 2:\n return None\n return unique_lst[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n\n # Find the smallest and second smallest elements\n smallest = min(lst)\n second_smallest = float('inf') \n for num in lst:\n if num != smallest and num < second_smallest:\n second_smallest = num\n \n return second_smallest if second_smallest != float('inf') else None", "matching_cluster_idx": 3}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n \n unique_lst = sorted(set(lst))\n if len(unique_lst) < 2:\n return None\n return unique_lst[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n \n unique_lst = sorted(set(lst))\n\n if len(unique_lst) < 2:\n return None\n \n return unique_lst[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n\n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n\n if len(lst) < 2: \n return None\n\n # Sort a copy of the list to avoid modifying the original\n sorted_lst = sorted(lst)\n\n # Find the second smallest element (skipping duplicates)\n second_smallest = None\n for i in range(1, len(sorted_lst)):\n if sorted_lst[i] != sorted_lst[0]:\n second_smallest = sorted_lst[i]\n break \n\n return second_smallest", "matching_cluster_idx": 10}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n \n # Remove duplicates and sort the list\n unique_lst = sorted(set(lst))\n\n return unique_lst[1] if len(unique_lst) > 1 else None", "matching_cluster_idx": 6}]}, "HumanEval/113": {"dps": 94.32048681541582, "dps_norm": 64.16666666666667, "pass@1": 82.0, "profiled": [{"solution": "def odd_count(lst):\n result = []\n for s in lst:\n odd_digits = sum(1 for digit in s if int(digit) % 2 != 0)\n result.append(f\"the number of odd elements {odd_digits}n the str{odd_digits}ng {odd_digits} of the {odd_digits}nput.\")\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n\n result = []\n for s in lst:\n odd_count = sum(1 for digit in s if int(digit) % 2 != 0)\n result.append(f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\")\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n result = []\n for s in lst:\n odd_count = sum(1 for digit in s if int(digit) % 2 != 0)\n result.append(f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\")\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n result = []\n for s in lst:\n odd_count = sum(1 for digit in s if int(digit) % 2 != 0)\n result.append(f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\")\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n result = []\n for s in lst:\n odd_count = sum(1 for digit in s if int(digit) % 2 != 0)\n result.append(f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\")\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n\n result = []\n for s in lst:\n odd_count = sum(1 for digit in s if int(digit) % 2 != 0) \n result.append(f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\") \n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n result = []\n for s in lst:\n odd_digits = sum(1 for digit in s if int(digit) % 2 != 0)\n result.append(f\"the number of odd elements {odd_digits}n the str{odd_digits}ng {odd_digits} of the {odd_digits}nput.\")\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n\n result = []\n for s in lst:\n odd_count = sum(int(d) % 2 for d in s)\n result.append(f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\")\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n result = []\n for s in lst:\n odd_digits = sum(int(d)%2 !=0 for d in s)\n result.append(f\"the number of odd elements {odd_digits}n the str{odd_digits}ng {odd_digits} of the {odd_digits}nput.\")\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n result = []\n for s in lst:\n odd_count = sum(1 for digit in s if int(digit) % 2 != 0)\n result.append(\"the number of odd elements \" + str(odd_count) + \"n the str\" + str(odd_count) + \"ng \" + str(odd_count) + \" of the \" + str(odd_count) + \"nput.\")\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n result = []\n for s in lst:\n odd_count = sum(1 for digit in s if int(digit) % 2 != 0)\n result.append(f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\") \n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n\n result = []\n for s in lst:\n odd_count = sum(int(digit) % 2 for digit in s) \n result.append(\"the number of odd elements {}n the str{}ng {} of the {}nput.\".format(odd_count, odd_count, odd_count, odd_count))\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n def count_odds(s):\n return sum(int(digit) % 2 for digit in s)\n return [\"the number of odd elements {}n the str{}ng {} of the {}nput.\".format(\n count_odds(s), count_odds(s), count_odds(s), count_odds(s)) for s in lst]", "matching_cluster_idx": 0}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n result = []\n for s in lst:\n odd_count = sum(1 for digit in s if int(digit) % 2 != 0)\n result.append(f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\")\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n result = []\n for s in lst:\n odd_count = sum(1 for digit in s if int(digit) % 2 != 0)\n result.append(f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\")\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n\n result = []\n for s in lst:\n odd_count = sum(int(digit) % 2 for digit in s)\n result.append(\"the number of odd elements \" + str(odd_count) + \"n the str\" + str(odd_count) + \"ng \" + str(odd_count) + \" of the \" + str(odd_count) + \"nput.\")\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n result = []\n for s in lst:\n odd_count = sum(1 for d in s if int(d) % 2 != 0)\n result.append(f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\")\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n output = []\n for string in lst:\n odd_count = sum(1 for digit in string if int(digit) % 2 != 0)\n output.append(f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\") \n return output", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n result = []\n for s in lst:\n odd_digits = sum(1 for d in s if int(d) % 2 != 0)\n result.append(\"the number of odd elements {}n the str{}ng {} of the {}nput.\".format(odd_digits, odd_digits, odd_digits, odd_digits))\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n\n result = []\n for s in lst:\n odd_count = sum(1 for digit in s if int(digit) % 2 != 0)\n result.append(f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\")\n return result", "matching_cluster_idx": 3}]}, "HumanEval/119": {"dps": 95.0, "dps_norm": 95.0, "pass@1": 60.0, "profiled": [{"solution": "def match_parens(lst):\n \"\"\"\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n \"\"\"\n str1, str2 = lst\n for combination in [str1 + str2, str2 + str1]:\n balance = 0\n for char in combination:\n if char == '(':\n balance += 1\n elif char == ')':\n balance -= 1\n if balance < 0:\n break\n if balance == 0:\n return 'Yes'\n return 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n \"\"\"\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n \"\"\"\n s1, s2 = lst\n for s in [s1 + s2, s2 + s1]:\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n else:\n balance -= 1\n if balance < 0:\n break\n if balance == 0:\n return 'Yes'\n return 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n s1, s2 = lst\n \n def is_balanced(s):\n count = 0\n for char in s:\n if char == '(':\n count += 1\n elif char == ')':\n count -= 1\n if count < 0:\n return False\n return count == 0\n\n return 'Yes' if is_balanced(s1 + s2) or is_balanced(s2 + s1) else 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n s1, s2 = lst\n for comb in [s1 + s2, s2 + s1]:\n balance = 0\n for paren in comb:\n if paren == '(':\n balance += 1\n elif paren == ')':\n balance -= 1\n if balance < 0:\n break \n if balance == 0:\n return 'Yes'\n return 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n def is_balanced(s):\n count = 0\n for char in s:\n if char == '(':\n count += 1\n elif char == ')':\n count -= 1\n if count < 0:\n return False\n return count == 0\n\n for s1, s2 in [(lst[0] + lst[1], ''), (lst[1] + lst[0], '')]:\n if is_balanced(s1):\n return 'Yes'\n return 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n\n s1, s2 = lst\n for combined in [s1+s2, s2+s1]:\n count = 0\n for char in combined:\n if char == '(':\n count += 1\n else:\n count -= 1\n if count < 0: \n break\n if count == 0:\n return 'Yes'\n return 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n s1, s2 = lst[0], lst[1]\n for s in [s1 + s2, s2 + s1]:\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n elif char == ')':\n balance -= 1\n if balance < 0: # Close paren without matching open paren\n break\n if balance == 0: # Balanced\n return 'Yes'\n return 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n s1, s2 = lst[0], lst[1]\n for s in [s1 + s2, s2 + s1]:\n count = 0\n for c in s:\n if c == '(':\n count += 1\n elif c == ')':\n count -= 1\n if count < 0:\n break\n if count == 0:\n return 'Yes'\n return 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n s1, s2 = lst\n for perm in [s1 + s2, s2 + s1]:\n count = 0\n for char in perm:\n if char == '(':\n count += 1\n elif char == ')':\n count -= 1\n if count < 0:\n break\n if count == 0:\n return 'Yes'\n return 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n s1, s2 = lst\n \n # Helper function to check if a string is balanced\n def is_balanced(s):\n count = 0\n for char in s:\n if char == '(':\n count += 1\n elif char == ')':\n count -= 1\n if count < 0: \n return False\n return count == 0\n\n # Try concatenating in both orders\n return 'Yes' if is_balanced(s1 + s2) or is_balanced(s2 + s1) else 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n\n s1, s2 = lst\n for comb in [s1 + s2, s2 + s1]:\n balance = 0\n for paren in comb:\n if paren == '(':\n balance += 1\n else:\n balance -= 1\n if balance < 0:\n break\n if balance == 0:\n return 'Yes'\n return 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n s1, s2 = lst[0], lst[1]\n for s in [s1 + s2, s2 + s1]:\n count = 0\n for char in s:\n if char == '(':\n count += 1\n else:\n count -= 1\n if count < 0:\n break\n if count == 0:\n return 'Yes'\n return 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n \n s1, s2 = lst\n for s in [s1 + s2, s2 + s1]:\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n elif char == ')':\n balance -= 1\n if balance < 0:\n break\n if balance == 0:\n return 'Yes'\n return 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n s1, s2 = lst\n for combined in [s1 + s2, s2 + s1]:\n count = 0\n for char in combined:\n if char == '(':\n count += 1\n elif char == ')':\n count -= 1\n if count < 0:\n break\n if count == 0:\n return 'Yes'\n\n return 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n\n s1, s2 = lst\n for comb in [s1 + s2, s2 + s1]:\n count = 0\n for char in comb:\n if char == '(':\n count += 1\n else:\n count -= 1\n if count < 0:\n break\n if count == 0:\n return 'Yes'\n return 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n s1, s2 = lst\n for perm in [s1 + s2, s2 + s1]:\n balance = 0\n for char in perm:\n if char == '(':\n balance += 1\n else:\n balance -= 1\n if balance < 0:\n break\n if balance == 0:\n return 'Yes'\n return 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n\n s1, s2 = lst\n for s in [s1 + s2, s2 + s1]:\n count = 0\n for char in s:\n if char == '(':\n count += 1\n elif char == ')':\n count -= 1\n if count < 0:\n break\n if count == 0:\n return 'Yes'\n return 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n s1, s2 = lst\n for s in [s1 + s2, s2 + s1]:\n count = 0\n for char in s:\n if char == '(':\n count += 1\n else:\n count -= 1\n if count < 0: # Close parenthesis without matching open one\n break\n if count == 0:\n return 'Yes'\n return 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n s1, s2 = lst[0], lst[1]\n for s in [s1 + s2, s2 + s1]:\n count = 0\n for char in s:\n if char == '(':\n count += 1\n elif char == ')':\n count -= 1\n if count < 0:\n break\n if count == 0:\n return 'Yes'\n return 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n from collections import deque\n s1 = deque(lst[0])\n s2 = deque(lst[1])\n \n def is_balanced(s):\n stack = []\n for char in s:\n if char == '(':\n stack.append(char)\n elif char == ')':\n if not stack or stack.pop() != '(':\n return False\n return not stack\n\n for _ in range(2): # Try both concatenations\n combined = s1 + s2\n if is_balanced(combined):\n return 'Yes'\n s1, s2 = s2, s1 # Swap the strings for the second attempt\n\n return 'No'", "matching_cluster_idx": -1}]}, "HumanEval/120": {"dps": null, "dps_norm": null, "pass@1": 0.0, "profiled": []}, "HumanEval/121": {"dps": null, "dps_norm": null, "pass@1": 0.0, "profiled": []}, "HumanEval/149": {"dps": 85.82677165354332, "dps_norm": 57.142857142857146, "pass@1": 73.0, "profiled": [{"solution": "def sorted_list_sum(lst):\n \"\"\"Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order,\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n You may assume that all words will have the same length.\n For example:\n assert list_sort([\"aa\", \"a\", \"aaa\"]) => [\"aa\"]\n assert list_sort([\"ab\", \"a\", \"aaa\", \"cd\"]) => [\"ab\", \"cd\"]\n \"\"\"\n return sorted([word for word in lst if len(word) % 2 == 0], key=lambda x: (len(x), x))", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order,\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n You may assume that all words will have the same length.\n For example:\n assert list_sort([\"aa\", \"a\", \"aaa\"]) => [\"aa\"]\n assert list_sort([\"ab\", \"a\", \"aaa\", \"cd\"]) => [\"ab\", \"cd\"]\n \"\"\"\n return sorted([word for word in lst if len(word) % 2 == 0], key=lambda word: (len(word), word))", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order,\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n You may assume that all words will have the same length.\n For example:\n assert list_sort([\"aa\", \"a\", \"aaa\"]) => [\"aa\"]\n assert list_sort([\"ab\", \"a\", \"aaa\", \"cd\"]) => [\"ab\", \"cd\"]\n \"\"\"\n result = [word for word in lst if len(word) % 2 == 0]\n result.sort(key=lambda x: (len(x), x))\n return result", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order,\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n You may assume that all words will have the same length.\n For example:\n assert list_sort([\"aa\", \"a\", \"aaa\"]) => [\"aa\"]\n assert list_sort([\"ab\", \"a\", \"aaa\", \"cd\"]) => [\"ab\", \"cd\"]\n \"\"\"\n return sorted([word for word in lst if len(word) % 2 == 0], key=lambda x: (len(x), x))", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order,\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n You may assume that all words will have the same length.\n For example:\n assert list_sort([\"aa\", \"a\", \"aaa\"]) => [\"aa\"]\n assert list_sort([\"ab\", \"a\", \"aaa\", \"cd\"]) => [\"ab\", \"cd\"]\n \"\"\"\n return sorted([word for word in lst if len(word) % 2 == 0], key=lambda word: (len(word), word))", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order,\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n You may assume that all words will have the same length.\n For example:\n assert list_sort([\"aa\", \"a\", \"aaa\"]) => [\"aa\"]\n assert list_sort([\"ab\", \"a\", \"aaa\", \"cd\"]) => [\"ab\", \"cd\"]\n \"\"\"\n\n result = [word for word in lst if len(word) % 2 == 0]\n result.sort(key=lambda x: (len(x), x))\n return result", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order,\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n You may assume that all words will have the same length.\n For example:\n assert list_sort([\"aa\", \"a\", \"aaa\"]) => [\"aa\"]\n assert list_sort([\"ab\", \"a\", \"aaa\", \"cd\"]) => [\"ab\", \"cd\"]\n \"\"\"\n\n return sorted([word for word in lst if len(word) % 2 == 0], key=lambda x: (len(x), x))", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order,\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n You may assume that all words will have the same length.\n For example:\n assert list_sort([\"aa\", \"a\", \"aaa\"]) => [\"aa\"]\n assert list_sort([\"ab\", \"a\", \"aaa\", \"cd\"]) => [\"ab\", \"cd\"]\n \"\"\"\n return sorted([word for word in lst if len(word) % 2 == 0], key=lambda x: (len(x), x))", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order,\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n You may assume that all words will have the same length.\n For example:\n assert list_sort([\"aa\", \"a\", \"aaa\"]) => [\"aa\"]\n assert list_sort([\"ab\", \"a\", \"aaa\", \"cd\"]) => [\"ab\", \"cd\"]\n \"\"\"\n\n return sorted([word for word in lst if len(word) % 2 == 0], key=lambda word: (len(word), word))", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n return sorted([word for word in lst if len(word) % 2 == 0], key=lambda x: (len(x), x))", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order,\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n You may assume that all words will have the same length.\n For example:\n assert list_sort([\"aa\", \"a\", \"aaa\"]) => [\"aa\"]\n assert list_sort([\"ab\", \"a\", \"aaa\", \"cd\"]) => [\"ab\", \"cd\"]\n \"\"\"\n return sorted([word for word in lst if len(word) % 2 == 0], key=lambda word: (len(word), word))", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order,\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n You may assume that all words will have the same length.\n For example:\n assert list_sort([\"aa\", \"a\", \"aaa\"]) => [\"aa\"]\n assert list_sort([\"ab\", \"a\", \"aaa\", \"cd\"]) => [\"ab\", \"cd\"]\n \"\"\"\n return sorted([word for word in lst if len(word) % 2 == 0], key=lambda x: (len(x), x))", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order,\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n You may assume that all words will have the same length.\n For example:\n assert list_sort([\"aa\", \"a\", \"aaa\"]) => [\"aa\"]\n assert list_sort([\"ab\", \"a\", \"aaa\", \"cd\"]) => [\"ab\", \"cd\"]\n \"\"\"\n return sorted([word for word in lst if len(word) % 2 == 0], key=lambda x: (len(x), x))", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order,\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n You may assume that all words will have the same length.\n For example:\n assert list_sort([\"aa\", \"a\", \"aaa\"]) => [\"aa\"]\n assert list_sort([\"ab\", \"a\", \"aaa\", \"cd\"]) => [\"ab\", \"cd\"]\n \"\"\"\n result = [word for word in lst if len(word) % 2 == 0]\n return sorted(result, key=lambda x: (len(x), x))", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order,\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n You may assume that all words will have the same length.\n For example:\n assert list_sort([\"aa\", \"a\", \"aaa\"]) => [\"aa\"]\n assert list_sort([\"ab\", \"a\", \"aaa\", \"cd\"]) => [\"ab\", \"cd\"]\n \"\"\"\n return sorted([word for word in lst if len(word) % 2 == 0], key=lambda x: (len(x), x))", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order,\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n You may assume that all words will have the same length.\n For example:\n assert list_sort([\"aa\", \"a\", \"aaa\"]) => [\"aa\"]\n assert list_sort([\"ab\", \"a\", \"aaa\", \"cd\"]) => [\"ab\", \"cd\"]\n \"\"\"\n even_length_words = [word for word in lst if len(word) % 2 == 0]\n return sorted(even_length_words, key=lambda x: (len(x), x))", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order,\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n You may assume that all words will have the same length.\n For example:\n assert list_sort([\"aa\", \"a\", \"aaa\"]) => [\"aa\"]\n assert list_sort([\"ab\", \"a\", \"aaa\", \"cd\"]) => [\"ab\", \"cd\"]\n \"\"\"\n \n #Filter for even length strings\n even_length_words = [word for word in lst if len(word) % 2 == 0]\n\n # Sort by length then alphabetically\n return sorted(even_length_words, key=lambda word: (len(word), word))", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order,\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n You may assume that all words will have the same length.\n For example:\n assert list_sort([\"aa\", \"a\", \"aaa\"]) => [\"aa\"]\n assert list_sort([\"ab\", \"a\", \"aaa\", \"cd\"]) => [\"ab\", \"cd\"]\n \"\"\"\n return sorted([word for word in lst if len(word) % 2 == 0], key=lambda word: (len(word), word))", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order,\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n You may assume that all words will have the same length.\n For example:\n assert list_sort([\"aa\", \"a\", \"aaa\"]) => [\"aa\"]\n assert list_sort([\"ab\", \"a\", \"aaa\", \"cd\"]) => [\"ab\", \"cd\"]\n \"\"\"\n return sorted([word for word in lst if len(word) % 2 == 0], key=lambda x: (len(x), x))", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order,\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n You may assume that all words will have the same length.\n For example:\n assert list_sort([\"aa\", \"a\", \"aaa\"]) => [\"aa\"]\n assert list_sort([\"ab\", \"a\", \"aaa\", \"cd\"]) => [\"ab\", \"cd\"]\n \"\"\"\n return sorted([word for word in lst if len(word) % 2 == 0], key=lambda word: (len(word), word))", "matching_cluster_idx": 3}]}, "Mbpp/3": {"dps": 60.33898305084745, "dps_norm": 77.5, "pass@1": 99.0, "profiled": [{"solution": "def is_not_prime(number):\n \"\"\"\n This function checks if a given number is not a prime number.\n\n Args:\n number: The number to be checked.\n\n Returns:\n True if the number is not prime, False otherwise.\n \"\"\"\n # Prime numbers are greater than 1\n if number <= 1:\n return True\n # Check for divisibility from 2 to the square root of the number\n for i in range(2, int(number**0.5) + 1):\n if number % i == 0:\n return True\n return False", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(number):\n \"\"\"\n Checks if a number is not prime.\n\n Args:\n number: The number to check.\n\n Returns:\n True if the number is not prime, False otherwise.\n \"\"\"\n\n if number <= 1:\n return True\n for i in range(2, int(number**0.5) + 1):\n if number % i == 0:\n return True\n return False", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(number):\n \"\"\"\n This function determines if a number is not prime.\n\n Args:\n number: An integer.\n\n Returns:\n True if the number is not prime, False otherwise.\n \"\"\"\n # Prime numbers are greater than 1\n if number <= 1:\n return True\n # Check if the number is divisible by any number from 2 to the square root of the number\n for i in range(2, int(number**0.5) + 1):\n if number % i == 0:\n return True\n return False", "matching_cluster_idx": 5}, {"solution": "import math\ndef is_not_prime(n):\n \"\"\"\n Checks if a number is not prime.\n\n Args:\n n: An integer.\n\n Returns:\n True if n is not prime, False otherwise.\n \"\"\"\n if n <= 1:\n return True\n for i in range(2, int(math.sqrt(n)) + 1):\n if n % i == 0:\n return True\n return False", "matching_cluster_idx": 5}, {"solution": "import math\ndef is_not_prime(n):\n \"\"\"\n This function determines if a number is not prime.\n\n Args:\n n: The number to be checked.\n\n Returns:\n True if n is not prime, False otherwise.\n \"\"\"\n # Prime numbers are greater than 1\n if n <= 1:\n return True\n # Check for divisibility from 2 to the square root of n\n for i in range(2, int(math.sqrt(n)) + 1):\n if n % i == 0:\n return True\n return False # If no divisors found, it's prime", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(number):\n \"\"\"\n Checks if a number is not prime.\n\n Args:\n number: The number to check.\n\n Returns:\n True if the number is not prime, False otherwise.\n \"\"\"\n # Prime numbers are greater than 1\n if number <= 1:\n return True\n # Check if number is divisible by any number from 2 to the square root of the number\n for i in range(2, int(number**0.5) + 1):\n if number % i == 0:\n return True\n return False", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(num):\n \"\"\"\n Determines if a number is not prime.\n\n Args:\n num: The number to check.\n\n Returns:\n True if the number is not prime, False otherwise.\n \"\"\"\n if num <= 1:\n return True\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n return True\n return False", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(number):\n \"\"\"\n This function checks if a given number is not a prime number.\n\n Args:\n number: An integer\n\n Returns:\n True if the number is not prime, False otherwise.\n \"\"\"\n if number <= 1:\n return True\n if number <= 3:\n return False\n if number % 2 == 0 or number % 3 == 0:\n return True\n i = 5\n while i * i <= number:\n if number % i == 0 or number % (i + 2) == 0:\n return True\n i += 6\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n \"\"\"\n Checks if a number is not prime.\n\n Args:\n n: The number to check.\n\n Returns:\n True if the number is not prime, False otherwise.\n \"\"\"\n\n if n <= 1:\n return True\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return True\n return False", "matching_cluster_idx": 5}, {"solution": "import math\ndef is_not_prime(num):\n \"\"\"\n Checks if a number is not prime.\n \n Args:\n num: An integer.\n \n Returns:\n True if the number is not prime, False otherwise.\n\n Note: This function considers 1 to be not prime.\n \"\"\"\n if num <= 1:\n return True\n for i in range(2, int(math.sqrt(num)) + 1):\n if num % i == 0:\n return True\n return False", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(n):\n \"\"\"Returns True if n is not a prime number, False otherwise.\"\"\"\n if n <= 1:\n return True\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return True\n return False", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(number):\n \"\"\"\n Checks if a number is not a prime number.\n\n Args:\n number: An integer.\n\n Returns:\n True if the number is not prime, False otherwise.\n \"\"\"\n # Prime numbers are greater than 1\n if number <= 1:\n return True\n # Check if number is divisible by any number from 2 to the square root of the number\n for i in range(2, int(number**0.5) + 1):\n if number % i == 0:\n return True\n return False", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(n):\n \"\"\"\n Identifies if a number is not prime.\n\n Args:\n n: An integer.\n\n Returns:\n True if n is not prime, False otherwise.\n \"\"\"\n if n <= 1:\n return True\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return True\n return False", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(n):\n \"\"\"\n Determines if a number is not prime.\n\n Args:\n n: The number to check.\n\n Returns:\n True if n is not prime, False otherwise.\n \"\"\"\n if n <= 1:\n return True\n if n <= 3:\n return False\n if n % 2 == 0 or n % 3 == 0:\n return True\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return True\n i += 6\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n \"\"\"\n Determines if a number is not prime.\n\n Args:\n n: The number to check.\n\n Returns:\n True if the number is not prime, False otherwise.\n \"\"\"\n if n <= 1:\n return True\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return True\n return False", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(n):\n \"\"\"\n Checks if a number is not prime.\n\n Args:\n n: The number to check.\n\n Returns:\n True if the number is not prime, False otherwise.\n \"\"\"\n # Prime numbers are greater than 1\n if n <= 1:\n return True\n # 2 is the only even prime number\n if n == 2:\n return False\n # Check if divisible by 2\n if n % 2 == 0:\n return True\n # Iterate from 3 to the square root of n, checking divisibility\n i = 3\n while i * i <= n:\n if n % i == 0:\n return True\n i += 2\n return False", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(n):\n \"\"\"\n Determines if a given number is not prime.\n\n Args:\n n: An integer.\n\n Returns:\n True if n is not prime, False otherwise.\n \"\"\"\n\n if n <= 1:\n return True\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return True\n return False", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(n):\n \"\"\"\n This function determines if a number is not prime.\n\n Args:\n n: An integer.\n\n Returns:\n True if n is not prime, False otherwise.\n \"\"\"\n\n # Prime numbers are greater than 1\n if n <= 1:\n return True\n\n # Check for divisibility from 2 to the square root of n\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return True\n \n return False", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(n):\n \"\"\"\n Determines if a number is not a prime number.\n\n Args:\n n: The number to check.\n\n Returns:\n True if n is not a prime number, False otherwise.\n \"\"\"\n if n <= 1:\n return True\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return True\n return False", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(n):\n \"\"\"\n This function checks if a given number is not a prime number.\n\n Args:\n n: The number to be checked.\n\n Returns:\n True if the number is not prime, False otherwise.\n \"\"\"\n # Prime numbers are greater than 1\n if n <= 1:\n return True\n # Check if n is divisible by any number from 2 to the square root of n\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return True\n return False", "matching_cluster_idx": 5}]}, "Mbpp/4": {"dps": 95.22184300341297, "dps_norm": 83.33333333333333, "pass@1": 100.0, "profiled": [{"solution": "import heapq\ndef heap_queue_largest(nums, n):\n \"\"\"\n Find the n largest integers from a list of numbers, returned in descending order.\n \n Args:\n nums: A list of integers.\n n: The number of largest integers to return.\n\n Returns:\n A list containing the n largest integers from nums in descending order.\n \"\"\"\n\n return heapq.nlargest(n, nums)\nnums = [25, 35, 22, 85, 14, 65, 75, 22, 58]\nn = 3", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n \"\"\"\n Finds the n largest integers from a given list of numbers, returned in descending order.\n\n Args:\n nums: A list of integers.\n n: The number of largest integers to return.\n\n Returns:\n A list of the n largest integers in descending order.\n \"\"\"\n\n return heapq.nlargest(n, nums)\nnums = [25, 35, 22, 85, 14, 65, 75, 22, 58]\nn = 3", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n \"\"\"\n Finds the n largest integers from a given list of numbers, returned in descending order.\n\n Args:\n nums: A list of numbers.\n n: The number of largest integers to return.\n\n Returns:\n A list of the n largest integers in descending order.\n \"\"\"\n return heapq.nlargest(n, nums)\nnums = [25, 35, 22, 85, 14, 65, 75, 22, 58]\nn = 3", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n \"\"\"Finds the n largest integers from a given list of numbers, returned in descending order.\n\n Args:\n nums: A list of integers.\n n: The number of largest integers to return.\n\n Returns:\n A list containing the n largest integers in descending order.\n \"\"\"\n return heapq.nlargest(n, nums)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n \"\"\"\n Finds the n largest integers from a given list of numbers, returned in descending order.\n\n Args:\n nums: A list of integers.\n n: The number of largest integers to return.\n\n Returns:\n A list of the n largest integers in descending order.\n \"\"\"\n return heapq.nlargest(n, nums)\nnums = [25, 35, 22, 85, 14, 65, 75, 22, 58]\nn = 3", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n \"\"\"\n Find the n largest integers from a list, returned in descending order.\n\n Args:\n nums: A list of integers.\n n: The number of largest integers to return.\n\n Returns:\n A list of the n largest integers in descending order.\n \"\"\"\n return heapq.nlargest(n, nums)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n \"\"\"Finds the n largest integers from a given list of numbers, returned in descending order.\n\n Args:\n nums: A list of integers.\n n: The number of largest integers to return.\n\n Returns:\n A list of the n largest integers in descending order.\n \"\"\"\n\n return heapq.nlargest(n, nums)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n \"\"\"\n Finds the n largest integers from a given list of numbers, returned in descending order.\n\n Args:\n nums: A list of numbers.\n n: The number of largest integers to return.\n\n Returns:\n A list of the n largest integers in descending order.\n \"\"\"\n return heapq.nlargest(n, nums)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n \"\"\"\n Finds the n largest integers from a given list of numbers, returned in descending order.\n\n Args:\n nums: A list of integers.\n n: The number of largest integers to return.\n\n Returns:\n A list of the n largest integers in descending order.\n \"\"\"\n return sorted(heapq.nlargest(n, nums), reverse=True)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(numbers, n):\n \"\"\"\n Finds the n largest integers from a given list of numbers, returned in descending order.\n\n Args:\n numbers: A list of integers.\n n: The number of largest integers to return.\n\n Returns:\n A list of the n largest integers in descending order.\n \"\"\"\n return heapq.nlargest(n, numbers)\nnumbers = [25, 35, 22, 85, 14, 65, 75, 22, 58]\nn = 3", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n \"\"\"\n Finds the n largest integers from a given list of numbers, returned in descending order.\n\n Args:\n nums: A list of numbers.\n n: The number of largest integers to return.\n\n Returns:\n A list of the n largest integers in descending order.\n \"\"\"\n return heapq.nlargest(n, nums)\nnums = [25, 35, 22, 85, 14, 65, 75, 22, 58]\nn = 3", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n \"\"\"\n Finds the n largest integers from a given list of numbers, returned in descending order.\n \"\"\"\n return sorted(heapq.nlargest(n, nums), reverse=True)\nnums = [25, 35, 22, 85, 14, 65, 75, 22, 58]\nn = 3", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n \"\"\"Finds the n largest integers from a list, returned in descending order.\n\n Args:\n nums: A list of integers.\n n: The number of largest integers to return.\n\n Returns:\n A list of the n largest integers from nums, sorted in descending order.\n \"\"\"\n\n return heapq.nlargest(n, nums)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n \"\"\"\n Find the n largest integers from a given list of numbers, returned in descending order.\n \"\"\"\n return heapq.nlargest(n, nums)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n \"\"\"Finds the n largest integers from a given list of numbers, returned in descending order.\n\n Args:\n nums: A list of integers.\n n: The number of largest integers to return.\n\n Returns:\n A list containing the n largest integers from nums, in descending order.\n \"\"\"\n return heapq.nlargest(n, nums)\nnums = [25, 35, 22, 85, 14, 65, 75, 22, 58]\nn = 3", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n \"\"\"\n Find the n largest integers from a given list of numbers, returned in descending order.\n\n Args:\n nums: A list of numbers.\n n: The number of largest integers to return.\n\n Returns:\n A list of the n largest integers in descending order.\n \"\"\"\n\n return heapq.nlargest(n, nums)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n \"\"\"Finds the n largest integers from a given list of numbers, returned in descending order.\n \n Args:\n nums: A list of integers.\n n: The number of largest integers to return.\n\n Returns:\n A list of the n largest integers, in descending order.\n\n Raises:\n ValueError: If n is less than 1 or greater than the length of nums.\n \"\"\"\n if n < 1 or n > len(nums):\n raise ValueError(\"n must be between 1 and the length of nums\")\n\n return sorted(heapq.nlargest(n, nums), reverse=True)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n \"\"\"\n Finds the n largest integers from a given list of numbers, returned in descending order.\n Args:\n nums: A list of integers.\n n: The number of largest integers to return.\n Returns:\n A list of the n largest integers in descending order.\n \"\"\"\n return heapq.nlargest(n, nums)\nnums = [25, 35, 22, 85, 14, 65, 75, 22, 58]\nn = 3", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n \"\"\"\n Find the n largest integers from a given list of numbers, returned in descending order.\n\n Args:\n nums: A list of integers.\n n: The number of largest integers to find.\n\n Returns:\n A list of the n largest integers in descending order.\n \"\"\"\n return heapq.nlargest(n, nums)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n \"\"\"\n Find the n largest integers from a given list of numbers, returned in descending order.\n\n Args:\n nums: A list of integers.\n n: The number of largest integers to return.\n\n Returns:\n A list of the n largest integers in descending order.\n \"\"\"\n return heapq.nlargest(n, nums)\nnums = [25, 35, 22, 85, 14, 65, 75, 22, 58]\nn = 3", "matching_cluster_idx": 9}]}, "Mbpp/9": {"dps": 42.7891156462585, "dps_norm": 42.5, "pass@1": 36.0, "profiled": [{"solution": "def find_Rotations(s: str) -> int:\n \"\"\"\n Find the minimum number of rotations (greater than 0) required to get the same string.\n\n For example:\n find_Rotations(\"aaaa\") == 1\n \"\"\"\n\n n = len(s)\n for i in range(1, n):\n if s == s[i:] + s[:i]:\n return i\n return n", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(s):\n \"\"\"\n Finds the minimum number of rotations (greater than 0) required to get the same string.\n \"\"\"\n n = len(s)\n for i in range(1, n):\n temp = s[i:] + s[:i] \n if temp == s:\n return i\n return n", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(s: str) -> int:\n \"\"\"Find the minimum number of rotations (greater than 0) required to get the same string.\"\"\"\n\n n = len(s)\n for i in range(1, n):\n temp = s[i:] + s[:i]\n if temp == s:\n return i\n return n", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(s: str) -> int:\n \"\"\"\n Finds the minimum number of rotations (greater than 0) required to get the same string.\n\n Args:\n s: The input string.\n\n Returns:\n The minimum number of rotations required.\n \"\"\"\n\n n = len(s)\n for i in range(1, n):\n temp = s[i:] + s[:i]\n if temp == s:\n return i\n return n", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(s: str) -> int:\n \"\"\"\n Find the minimum number of rotations (greater than 0) required to get the same string.\n\n Args:\n s: The input string.\n\n Returns:\n The minimum number of rotations required.\n \"\"\"\n n = len(s)\n for i in range(1, n):\n temp = s[i:] + s[:i]\n if temp == s:\n return i\n return n", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(s: str) -> int:\n \"\"\"\n Find the minimum number of rotations (greater than 0) required to get the same string.\n\n Args:\n s (str): The input string.\n\n Returns:\n int: The minimum number of rotations required. Returns 1 if no rotations are needed.\n \"\"\"\n n = len(s)\n for i in range(1, n):\n temp = s[i:] + s[:i]\n if temp == s:\n return i\n return n # If no rotations result in the same string", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(s: str) -> int:\n \"\"\"\n Find the minimum number of rotations (greater than 0) required to get the same string.\n\n For example:\n find_Rotations(\"aaaa\") == 1\n find_Rotations(\"abcabc\") == 3\n find_Rotations(\"abcd\") == 4\n \"\"\"\n n = len(s)\n for i in range(1, n):\n temp = s[i:] + s[:i]\n if temp == s:\n return i\n return n", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(text):\n \"\"\"Finds the minimum number of rotations required to get the same string.\"\"\"\n n = len(text)\n for i in range(1, n):\n temp = text[i:] + text[:i] \n if temp == text:\n return i\n return n # If no rotation results in the same string", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(s: str) -> int:\n \"\"\"\n Find the minimum number of rotations (greater than 0) required to get the same string.\n\n Args:\n s: The input string.\n\n Returns:\n The minimum number of rotations.\n \"\"\"\n n = len(s)\n for i in range(1, n):\n temp = s[i:] + s[:i]\n if temp == s:\n return i\n return n", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(s: str) -> int:\n \"\"\"\n Finds the minimum number of rotations (greater than 0) required to get the same string.\n\n Args:\n s: The input string.\n\n Returns:\n The minimum number of rotations. If the input string is empty or a single character, returns 1.\n \"\"\"\n if len(s) <= 1:\n return 1\n for i in range(1, len(s)):\n rotated = s[i:] + s[:i]\n if rotated == s:\n return i\n return len(s)", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(s: str) -> int:\n \"\"\"\n Find the minimum number of rotations (greater than 0) required to get the same string.\n\n For example:\n find_Rotations(\"aaaa\") == 1\n \"\"\"\n\n n = len(s)\n for i in range(1, n):\n temp = s[i:] + s[:i]\n if temp == s:\n return i\n return n", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(s):\n \"\"\"\n Finds the minimum number of rotations (greater than 0) required to get the same string.\n \"\"\"\n\n n = len(s)\n for i in range(1, n):\n temp = s[i:] + s[:i]\n if temp == s:\n return i\n return n", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(s: str) -> int:\n \"\"\"\n Find the minimum number of rotations (greater than 0) required to get the same string.\n\n Args:\n s (str): The input string.\n\n Returns:\n int: The minimum number of rotations.\n \"\"\"\n\n n = len(s)\n for i in range(1, n):\n temp = s[i:] + s[:i]\n if temp == s:\n return i\n return n", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(s: str) -> int:\n \"\"\"\n Finds the minimum number of rotations (greater than 0) required to get the same string.\n\n Args:\n s: The input string.\n\n Returns:\n The minimum number of rotations required, or 1 if the string\n can only be obtained by rotating once.\n \"\"\"\n n = len(s)\n for i in range(1, n):\n temp = s[i:] + s[:i]\n if temp == s:\n return i\n return n", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(s: str) -> int:\n \"\"\"\n Find the minimum number of rotations required to get the same string.\n Args:\n s: The input string.\n\n Returns:\n The minimum number of rotations required. If the string is empty or has only 1 character, return 1.\n \"\"\"\n if len(s) <= 1:\n return 1\n\n for i in range(1, len(s)):\n temp = s[i:] + s[:i]\n if temp == s:\n return i\n\n return len(s)", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(s: str) -> int:\n \"\"\"\n Finds the minimum number of rotations (greater than 0) required to get the same string.\n\n Args:\n s: The input string.\n\n Returns:\n The minimum number of rotations required. Returns 1 if the string is already a rotation of itself (like \"aaaa\").\n \"\"\"\n n = len(s)\n for i in range(1, n):\n rotated = s[i:] + s[:i]\n if rotated == s:\n return i\n return n", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(s: str) -> int:\n \"\"\"\n Finds the minimum number of rotations (greater than 0) required to get the same string.\n \"\"\"\n n = len(s)\n for i in range(1, n):\n temp = s[i:] + s[:i] \n if temp == s:\n return i\n return n", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(text: str) -> int:\n \"\"\"\n Find the minimum number of rotations (greater than 0) required to get the same string.\n For example:\n find_Rotations(\"aaaa\") == 1\n find_Rotations(\"abcabc\") == 3\n find_Rotations(\"abcd\") == 4\n\n \"\"\"\n n = len(text)\n for i in range(1, n):\n temp = \"\"\n for j in range(i, n):\n temp += text[j]\n for j in range(0, i):\n temp += text[j]\n\n if (temp == text):\n return i\n return n", "matching_cluster_idx": -1}, {"solution": "def find_Rotations(str1):\n \"\"\"\n Finds the minimum number of rotations (greater than 0) required to get the same string.\n Args:\n str1: The input string.\n Returns:\n The minimum number of rotations.\n \"\"\"\n n = len(str1)\n for i in range(1, n):\n temp = \"\"\n for j in range(i, n):\n temp += str1[j]\n for j in range(0, i):\n temp += str1[j]\n if (temp == str1):\n return i\n return n", "matching_cluster_idx": -1}, {"solution": "def find_Rotations(s: str) -> int:\n \"\"\"\n Finds the minimum number of rotations (greater than 0) required to get the same string.\n \"\"\"\n n = len(s)\n for i in range(1, n):\n temp = \"\"\n for j in range(i, n):\n temp += s[j]\n for j in range(0, i):\n temp += s[j]\n if (temp == s):\n return i\n return n", "matching_cluster_idx": -1}]}, "Mbpp/11": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 86.0, "profiled": [{"solution": "def remove_Occ(text, char):\n \"\"\"Removes the first and last occurrences of a given character from a string.\n\n Args:\n text: The input string.\n char: The character to remove.\n\n Returns:\n The string with the first and last occurrences of the character removed, \n or the original string if the character does not appear.\n \"\"\"\n try:\n first_index = text.index(char)\n last_index = text.rindex(char)\n return text[:first_index] + text[first_index+1:last_index] + text[last_index+1:]\n except ValueError:\n return text", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(s,c):\n \"\"\"Removes first and last occurrence of a character from a string.\n\n Args:\n s: The input string.\n c: The character to remove.\n\n Returns:\n The string with the first and last occurrences of c removed.\n \"\"\"\n try:\n first_index = s.index(c)\n last_index = s.rindex(c)\n if first_index == last_index:\n return s[:first_index] + s[first_index+1:]\n else:\n return s[:first_index] + s[first_index+1:last_index] + s[last_index+1:]\n except ValueError:\n return s", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(str1,char):\n first_index = str1.find(char)\n last_index = str1.rfind(char)\n if first_index != -1 and last_index != -1:\n return str1[:first_index] + str1[first_index+1:last_index] + str1[last_index+1:] \n else:\n return str1", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(text, char):\n \"\"\"Removes the first and last occurrences of a given character from a string.\n\n Args:\n text: The input string.\n char: The character to remove.\n\n Returns:\n The string with the first and last occurrences of 'char' removed.\n \"\"\"\n first = text.find(char)\n last = text.rfind(char)\n if first != -1 and last != -1:\n return text[:first] + text[first+1:last] + text[last+1:]\n else:\n return text", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(str1, char):\n \"\"\"Removes the first and last occurrence of a character from a string.\n\n Args:\n str1: The string to modify.\n char: The character to remove.\n\n Returns:\n The string with the first and last occurrences of the character removed,\n or the original string if the character does not occur.\n \"\"\"\n\n first_occurrence = str1.find(char)\n last_occurrence = str1.rfind(char)\n\n if first_occurrence != -1 and last_occurrence != -1:\n return str1[:first_occurrence] + str1[first_occurrence+1:last_occurrence] + str1[last_occurrence+1:]\n else:\n return str1", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(str1, char1):\n \"\"\"\n This function removes the first and last occurrences of a given character from a string.\n\n Args:\n str1: The input string.\n char1: The character to be removed.\n\n Returns:\n The string with the first and last occurrences of char1 removed, or the original string if char1 is not present.\n \"\"\"\n first_occur = str1.find(char1)\n last_occur = str1.rfind(char1)\n\n if first_occur == -1:\n return str1 \n elif first_occur == last_occur:\n return str1.replace(char1, '')\n else:\n return str1[:first_occur] + str1[first_occur+1:last_occur] + str1[last_occur+1:]", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(s, c):\n \"\"\"Removes the first and last occurrence of a given character from a string.\n\n Args:\n s: The input string.\n c: The character to remove.\n\n Returns:\n The string with the first and last occurrences of c removed.\n \"\"\"\n first_index = s.find(c)\n last_index = s.rfind(c)\n if first_index == -1 or last_index == -1:\n return s\n return s[:first_index] + s[first_index + 1: last_index] + s[last_index + 1:]", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(text, char):\n \"\"\"\n Removes the first and last occurrences of a given character from a string.\n\n Args:\n text: The input string.\n char: The character to remove.\n\n Returns:\n The string with the first and last occurrences of the character removed.\n \"\"\"\n first_occ = text.find(char)\n last_occ = text.rfind(char)\n if first_occ != -1 and last_occ != -1:\n return text[:first_occ] + text[first_occ+1:last_occ] + text[last_occ+1:]\n else:\n return text", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(str1, char):\n \"\"\"\n Removes the first and last occurrences of a character from a string.\n\n Args:\n str1: The input string.\n char: The character to remove.\n\n Returns:\n The string with the first and last occurrences of the character removed.\n \"\"\"\n\n first_occurence = str1.find(char)\n last_occurrence = str1.rfind(char)\n\n if first_occurence != -1 and last_occurrence != -1:\n return str1[:first_occurence] + str1[first_occurence+1:last_occurrence] + str1[last_occurrence+1:]\n else:\n return str1", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(str1, char):\n \"\"\"Removes the first and last occurrences of a given character from a string.\n\n Args:\n str1: The input string.\n char: The character to remove.\n\n Returns:\n The string with the first and last occurrences of the character removed.\n \"\"\"\n\n first_occ = str1.find(char)\n last_occ = str1.rfind(char)\n \n if first_occ != -1 and last_occ != -1 and first_occ != last_occ:\n return str1[:first_occ] + str1[first_occ + 1:last_occ] + str1[last_occ + 1:]\n elif first_occ != -1 and last_occ != -1 and first_occ == last_occ:\n return str1[:first_occ] + str1[first_occ + 1:]\n else:\n return str1", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(s, char):\n \"\"\"\n Removes the first and last occurrence of a given character from a string.\n\n Args:\n s: The string to modify.\n char: The character to remove.\n\n Returns:\n The modified string with the first and last occurrences of 'char' removed, or the original string if 'char' is not present.\n \"\"\"\n try:\n first_occurence = s.index(char)\n last_occurence = s.rindex(char)\n if first_occurence != last_occurence:\n return s[:first_occurence] + s[first_occurence+1:last_occurence] + s[last_occurence+1:]\n else:\n return s[:first_occurence] + s[first_occurence+1:] \n except ValueError:\n return s", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(text, char):\n \"\"\"Removes first and last occurrence of a character from a string.\"\"\"\n first_index = text.find(char)\n last_index = text.rfind(char)\n if first_index != -1 and last_index != -1:\n return text[:first_index] + text[first_index + 1:last_index] + text[last_index + 1:]\n else:\n return text", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(string, char):\n \"\"\"\n Removes the first and last occurrence of a given character from a string.\n\n Args:\n string: The input string.\n char: The character to remove.\n\n Returns:\n The string with the first and last occurrences of the given character removed.\n \"\"\"\n first_occurence = string.find(char)\n last_occurrence = string.rfind(char)\n\n if first_occurence != -1 and last_occurrence != -1:\n return string[:first_occurence] + string[first_occurence + 1:last_occurrence] + string[last_occurrence + 1:]\n else:\n return string", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(text, char):\n \"\"\"\n This function removes the first and last occurrence of a given character from a string.\n\n Args:\n text: The input string.\n char: The character to remove.\n\n Returns:\n The string with the first and last occurrence of the character removed.\n \"\"\"\n\n first_occurence = text.find(char)\n last_occurence = text.rfind(char)\n\n if first_occurence != -1 and last_occurence != -1: \n return text[:first_occurence] + text[first_occurence+1:last_occurence] + text[last_occurence+1:]\n else:\n return text", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(str1, char1):\n \"\"\"\n Removes the first and last occurrence of a given character from a string.\n\n Args:\n str1 (str): The input string.\n char1 (str): The character to be removed.\n\n Returns:\n str: The modified string with the first and last occurrences of the character removed.\n \"\"\"\n first_occurence = str1.find(char1)\n last_occurence = str1.rfind(char1)\n\n if first_occurence != -1 and last_occurence != -1:\n return str1[:first_occurence] + str1[first_occurence+1:last_occurence] + str1[last_occurence+1:]\n else:\n return str1", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(str1, char):\n \"\"\"\n Removes the first and last occurrences of a given character from a string.\n\n Args:\n str1 (str): The input string.\n char (str): The character to remove.\n\n Returns:\n str: The string with the first and last occurrences of the character removed. \n Returns the original string if the character is not found.\n \"\"\"\n\n first_index = str1.find(char)\n last_index = str1.rfind(char)\n\n if first_index != -1 and last_index != -1:\n return str1[:first_index] + str1[first_index + 1: last_index] + str1[last_index + 1:] \n else:\n return str1", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(s,char):\n first_occ = s.find(char)\n last_occ = s.rfind(char)\n\n if first_occ == -1:\n return s\n elif first_occ == last_occ:\n return s.replace(char,\"\")\n else:\n return s[:first_occ] + s[first_occ+1:last_occ] + s[last_occ+1:]", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(s, char):\n \"\"\"\n Removes the first and last occurrence of a given character from a string.\n\n Args:\n s: The input string.\n char: The character to remove.\n\n Returns:\n The string with the first and last occurrences of the character removed.\n \"\"\"\n\n first_index = s.find(char)\n last_index = s.rfind(char)\n\n if first_index != -1 and last_index != -1 and first_index != last_index:\n return s[:first_index] + s[first_index+1:last_index] + s[last_index+1:]\n elif first_index != -1:\n return s[:first_index] + s[first_index+1:]\n elif last_index != -1:\n return s[:last_index] + s[last_index+1:]\n else:\n return s", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(string, char):\n \"\"\"Removes the first and last occurrence of a given character from a string.\n\n Args:\n string: The input string.\n char: The character to remove.\n\n Returns:\n The string with the first and last occurrences of the character removed.\n \"\"\"\n\n first_index = string.find(char)\n last_index = string.rfind(char)\n\n if first_index != -1 and last_index != -1:\n return string[:first_index] + string[first_index+1:last_index] + string[last_index+1:]\n else:\n return string", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(s, char):\n \"\"\"Removes the first and last occurrences of a given character from a string.\n\n Args:\n s: The input string.\n char: The character to remove.\n\n Returns:\n The modified string with the first and last occurrences of char removed. \n If char is not present in the string, it returns the original string.\n \"\"\"\n\n if char in s:\n first_index = s.find(char)\n last_index = s.rfind(char)\n return s[:first_index] + s[first_index+1:last_index] + s[last_index+1:]\n else:\n return s", "matching_cluster_idx": 8}]}, "Mbpp/12": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def sort_matrix(matrix):\n \"\"\"\n Sorts a given matrix in ascending order according to the sum of its rows.\n\n Args:\n matrix: A list of lists representing the matrix.\n\n Returns:\n A new list of lists representing the sorted matrix.\n \"\"\"\n return sorted(matrix, key=sum)\nmatrix = [[1, 2, 3], [2, 4, 5], [1, 1, 1]]", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"\n Sorts a matrix in ascending order according to the sum of its rows.\n\n Args:\n matrix: A list of lists representing the matrix.\n\n Returns:\n A new matrix sorted by the sum of its rows in ascending order.\n \"\"\"\n return sorted(matrix, key=sum)", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"\n Sorts a given matrix in ascending order according to the sum of its rows.\n \n Args:\n matrix: A list of lists representing the matrix.\n\n Returns:\n A new list of lists representing the sorted matrix.\n \"\"\"\n\n return sorted(matrix, key=sum)", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"\n Sorts a given matrix in ascending order according to the sum of its rows.\n\n Args:\n matrix: A list of lists representing the matrix.\n\n Returns:\n A new list of lists representing the sorted matrix.\n \"\"\"\n return sorted(matrix, key=sum)\nmatrix = [[1, 2, 3], [2, 4, 5], [1, 1, 1]]", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"Sorts a given matrix in ascending order according to the sum of its rows.\n\n Args:\n matrix: A list of lists representing the matrix.\n\n Returns:\n A new matrix sorted by the sum of its rows in ascending order.\n \"\"\"\n return sorted(matrix, key=sum)\nmatrix = [[1, 2, 3], [2, 4, 5], [1, 1, 1]]", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"\n Sorts a given matrix in ascending order according to the sum of its rows.\n\n Args:\n matrix: A list of lists representing the matrix.\n\n Returns:\n A new matrix sorted by the sum of its rows in ascending order.\n \"\"\"\n return sorted(matrix, key=sum)\nmatrix = [[1, 2, 3], [2, 4, 5], [1, 1, 1]]", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"\n Sorts a given matrix in ascending order according to the sum of its rows.\n\n Args:\n matrix (list of lists): The input matrix.\n\n Returns:\n list of lists: The sorted matrix.\n \"\"\"\n return sorted(matrix, key=sum)", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"\n Sorts a given matrix in ascending order according to the sum of its rows.\n\n Args:\n matrix: A list of lists representing the matrix.\n\n Returns:\n A new matrix sorted by row sums in ascending order.\n \"\"\"\n return sorted(matrix, key=lambda row: sum(row))\nmatrix = [[1, 2, 3], [2, 4, 5], [1, 1, 1]]", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"\n Sorts a given matrix in ascending order according to the sum of its rows.\n\n Args:\n matrix: A list of lists representing the matrix.\n\n Returns:\n A new matrix with rows sorted in ascending order of their sum.\n \"\"\"\n return sorted(matrix, key=sum)", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"\n Sorts a given matrix in ascending order according to the sum of its rows.\n\n Args:\n matrix: A list of lists representing the matrix.\n\n Returns:\n A new list of lists representing the sorted matrix.\n \"\"\"\n\n # Calculate the sum of each row and store it with the row\n rows_with_sums = [(sum(row), row) for row in matrix]\n\n # Sort the rows based on their sums\n rows_with_sums.sort(key=lambda x: x[0])\n\n # Extract the sorted rows\n sorted_matrix = [row for _, row in rows_with_sums]\n\n return sorted_matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"\n Sorts a given matrix in ascending order according to the sum of its rows.\n\n Args:\n matrix: A list of lists representing the matrix.\n\n Returns:\n A new matrix with rows sorted in ascending order based on their sum.\n \"\"\"\n return sorted(matrix, key=sum)\nmatrix = [[1, 2, 3], [2, 4, 5], [1, 1, 1]]", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"\n Sorts a given matrix in ascending order according to the sum of its rows.\n\n Args:\n matrix: A list of lists representing the matrix.\n\n Returns:\n A new list of lists representing the sorted matrix.\n \"\"\"\n return sorted(matrix, key=sum)", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"\n Sorts a given matrix in ascending order according to the sum of its rows.\n\n Args:\n matrix: A list of lists representing a matrix.\n\n Returns:\n A new matrix with the rows sorted in ascending order based on their sums.\n \"\"\"\n\n return sorted(matrix, key=sum)\nmatrix = [[1, 2, 3], [2, 4, 5], [1, 1, 1]]", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"\n Sorts a given matrix in ascending order according to the sum of its rows.\n \n Args:\n matrix: A list of lists representing the matrix.\n\n Returns:\n A new matrix with rows sorted by their sum in ascending order.\n \"\"\"\n\n return sorted(matrix, key=sum)\nmatrix = [[1, 2, 3], [2, 4, 5], [1, 1, 1]]", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"\n Sorts a given matrix in ascending order according to the sum of its rows.\n\n Args:\n matrix: A list of lists representing the matrix.\n\n Returns:\n A new list of lists representing the sorted matrix.\n \"\"\"\n return sorted(matrix, key=sum)", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"\n Sorts a given matrix in ascending order according to the sum of its rows.\n\n Args:\n matrix: A list of lists representing the matrix.\n\n Returns:\n A new matrix sorted in ascending order based on the sum of row elements.\n \"\"\"\n return sorted(matrix, key=sum)", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"\n Sorts a given matrix in ascending order according to the sum of its rows.\n\n Args:\n matrix: A list of lists representing a matrix.\n\n Returns:\n A new matrix sorted in ascending order based on the sum of its rows.\n \"\"\"\n return sorted(matrix, key=sum)", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"\n Sorts a given matrix in ascending order according to the sum of its rows.\n\n Args:\n matrix: A list of lists representing the matrix.\n\n Returns:\n A new list of lists representing the sorted matrix.\n \"\"\"\n\n return sorted(matrix, key=sum)\nmatrix = [[1, 2, 3], [2, 4, 5], [1, 1, 1]]", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"Sorts a matrix in ascending order according to the sum of its rows.\n\n Args:\n matrix: A list of lists representing the matrix.\n\n Returns:\n A new matrix with rows sorted in ascending order by sum.\n \"\"\"\n return sorted(matrix, key=sum)", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"Sorts a matrix in ascending order according to the sum of its rows.\"\"\"\n return sorted(matrix, key=sum)", "matching_cluster_idx": 15}]}, "Mbpp/16": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 98.0, "profiled": [{"solution": "import re\ndef text_lowercase_underscore(text):\n \"\"\"\n This function returns True if the input string contains sequences of lowercase letters\n joined with an underscore and False otherwise.\n \"\"\"\n pattern = r\"^[a-z]+(_[a-z]+)*$\"\n match = re.match(pattern, text)\n return bool(match)", "matching_cluster_idx": 7}, {"solution": "import re\ndef text_lowercase_underscore(text):\n \"\"\"\n Returns true if the input string contains sequences of lowercase letters joined with an underscore and false otherwise.\n \"\"\"\n pattern = r\"^[a-z]+(_[a-z]+)*$\"\n match = re.match(pattern, text)\n return bool(match)", "matching_cluster_idx": 7}, {"solution": "import re\ndef text_lowercase_underscore(text):\n \"\"\"\n Checks if the input string contains sequences of lowercase letters joined with an underscore.\n\n Args:\n text: The input string to check.\n\n Returns:\n True if the string contains sequences of lowercase letters joined with an underscore, False otherwise.\n \"\"\"\n return bool(re.fullmatch(r'^[a-z]+(?:_[a-z]+)*$', text))", "matching_cluster_idx": 7}, {"solution": "import re\ndef text_lowercase_underscore(text):\n \"\"\"\n Checks if a string contains sequences of lowercase letters joined with an underscore.\n\n Args:\n text: The input string.\n\n Returns:\n True if the string contains sequences of lowercase letters joined with an underscore, \n False otherwise.\n \"\"\"\n pattern = r'^[a-z]+(?:_[a-z]+)*$'\n match = re.match(pattern, text)\n return bool(match)", "matching_cluster_idx": 7}, {"solution": "import re\ndef text_lowercase_underscore(text):\n \"\"\"\n Returns True if the input string contains sequences of lowercase letters joined with an underscore and False otherwise.\n \"\"\"\n pattern = r\"^[a-z]+(_[a-z]+)*$\"\n match = re.match(pattern, text)\n return bool(match)", "matching_cluster_idx": 7}, {"solution": "import re\ndef text_lowercase_underscore(text: str) -> bool:\n \"\"\"\n Write a function to that returns true if the input string contains sequences of lowercase letters joined with an underscore and false otherwise.\n \"\"\"\n pattern = r\"^[a-z]+(_[a-z]+)*$\"\n match = re.match(pattern, text)\n return bool(match)", "matching_cluster_idx": 7}, {"solution": "import re\ndef text_lowercase_underscore(text):\n \"\"\"\n Returns True if the input string contains sequences of lowercase letters joined with an underscore and False otherwise.\n \"\"\"\n pattern = r\"^[a-z]+(?:_[a-z]+)*$\"\n match = re.match(pattern, text)\n return bool(match)", "matching_cluster_idx": 7}, {"solution": "import re\ndef text_lowercase_underscore(text):\n \"\"\"\n Returns True if the input string contains sequences of lowercase letters joined with an underscore and False otherwise.\n \"\"\"\n return bool(re.fullmatch(r\"[a-z]+(_[a-z]+)*\", text))", "matching_cluster_idx": 7}, {"solution": "import re\ndef text_lowercase_underscore(text):\n \"\"\"\n Checks if a string contains sequences of lowercase letters joined with underscores.\n\n Args:\n text: The input string.\n\n Returns:\n True if the string contains lowercase letters joined with underscores, False otherwise.\n \"\"\"\n pattern = r\"^[a-z]+(_[a-z]+)*$\"\n match = re.match(pattern, text)\n return bool(match)", "matching_cluster_idx": 7}, {"solution": "import re\ndef text_lowercase_underscore(text):\n \"\"\"\n Checks if a string contains sequences of lowercase letters joined with an underscore.\n\n Args:\n text: The input string.\n\n Returns:\n True if the input string contains sequences of lowercase letters joined with an underscore, False otherwise.\n \"\"\"\n pattern = r'^[a-z]+(_[a-z]+)*$'\n match = re.match(pattern, text)\n return bool(match)", "matching_cluster_idx": 7}, {"solution": "import re\ndef text_lowercase_underscore(text):\n \"\"\"\n Returns true if the input string contains sequences of lowercase letters joined with an underscore and false otherwise.\n \"\"\"\n pattern = r\"^[a-z]+(_[a-z]+)*$\"\n match = re.match(pattern, text)\n return bool(match)", "matching_cluster_idx": 7}, {"solution": "import re\ndef text_lowercase_underscore(text):\n \"\"\"\n Checks if a string contains only sequences of lowercase letters joined with underscores.\n\n Args:\n text: The string to check.\n\n Returns:\n True if the string matches the pattern, False otherwise.\n \"\"\"\n pattern = r\"^[a-z]+(_[a-z]+)*$\"\n match = re.match(pattern, text)\n return bool(match)", "matching_cluster_idx": 7}, {"solution": "import re\ndef text_lowercase_underscore(text):\n \"\"\"Returns True if the input string contains sequences of lowercase letters joined with an underscore, False otherwise.\"\"\"\n pattern = r\"^[a-z]+(_[a-z]+)*$\"\n match = re.match(pattern, text)\n return bool(match)", "matching_cluster_idx": 7}, {"solution": "import re\ndef text_lowercase_underscore(text):\n \"\"\"\n This function checks if the input string contains sequences of lowercase letters \n joined with an underscore.\n\n Args:\n text: The input string.\n\n Returns:\n True if the input string contains sequences of lowercase letters joined with\n an underscore, False otherwise.\n \"\"\"\n pattern = r\"^[a-z]+(_[a-z]+)*$\"\n match = re.match(pattern, text)\n return bool(match)", "matching_cluster_idx": 7}, {"solution": "import re\ndef text_lowercase_underscore(text):\n \"\"\"\n Checks if a string contains sequences of lowercase letters joined with underscores.\n\n Args:\n text: The input string to check.\n\n Returns:\n True if the string contains valid sequences, False otherwise.\n \"\"\"\n pattern = r\"^[a-z]+(_[a-z]+)*$\"\n match = re.match(pattern, text)\n return bool(match)", "matching_cluster_idx": 7}, {"solution": "import re\ndef text_lowercase_underscore(text):\n \"\"\"\n This function checks if a string contains sequences of lowercase letters joined with underscores.\n\n Args:\n text: The input string.\n\n Returns:\n True if the string contains lowercase letter sequences joined by underscores, False otherwise.\n \"\"\"\n regex = r'^[a-z]+(_[a-z]+)*$'\n match = re.match(regex, text)\n return bool(match)", "matching_cluster_idx": 7}, {"solution": "import re\ndef text_lowercase_underscore(text):\n \"\"\"\n Checks if a string contains sequences of lowercase letters joined with an underscore.\n\n Args:\n text: The input string to check.\n\n Returns:\n True if the string contains sequences of lowercase letters joined with an underscore, False otherwise.\n \"\"\"\n pattern = r\"^[a-z]+(_[a-z]+)*$\"\n match = re.match(pattern, text)\n return bool(match)", "matching_cluster_idx": 7}, {"solution": "def text_lowercase_underscore(text):\n \"\"\"\n Checks if the input string contains sequences of lowercase letters joined with an underscore.\n\n Args:\n text: The input string.\n\n Returns:\n True if the input string contains sequences of lowercase letters joined with an underscore, False otherwise.\n \"\"\"\n import re\n pattern = r'^[a-z]+(_[a-z]+)*$'\n match = re.match(pattern, text)\n return bool(match)", "matching_cluster_idx": 7}, {"solution": "import re\ndef text_lowercase_underscore(text):\n \"\"\"\n Checks if a string contains sequences of lowercase letters joined with an underscore.\n\n Args:\n text: The input string.\n\n Returns:\n True if the string contains sequences of lowercase letters joined with an underscore, False otherwise.\n \"\"\"\n return bool(re.fullmatch(r\"[a-z]+(_[a-z]+)*\", text))", "matching_cluster_idx": 7}, {"solution": "import re\ndef text_lowercase_underscore(text):\n \"\"\"\n Checks if a string contains sequences of lowercase letters joined with underscores.\n\n Args:\n text: The input string.\n\n Returns:\n True if the string contains sequences of lowercase letters joined with underscores, False otherwise.\n \"\"\"\n pattern = r'^[a-z]+(_[a-z]+)*$'\n match = re.match(pattern, text)\n return bool(match)", "matching_cluster_idx": 7}]}, "Mbpp/19": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 81.0, "profiled": [{"solution": "def test_duplicate(arr):\n \"\"\"\n Write a function to find whether a given array of integers contains any duplicate element.\n assert test_duplicate(([1,2,3,4,5]))==False\n \"\"\"\n seen = set()\n for num in arr:\n if num in seen:\n return True\n seen.add(num)\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(nums):\n \"\"\"\n Checks if a list of integers contains any duplicate elements.\n\n Args:\n nums: A list of integers.\n\n Returns:\n True if the list contains duplicate elements, False otherwise.\n \"\"\"\n seen = set()\n for num in nums:\n if num in seen:\n return True\n seen.add(num)\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(nums):\n \"\"\"\n This function checks if a given array of integers contains any duplicate element.\n\n Args:\n nums: A list of integers.\n\n Returns:\n True if there is a duplicate element in the list, False otherwise.\n \"\"\"\n seen = set()\n for num in nums:\n if num in seen:\n return True\n seen.add(num)\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(nums):\n \"\"\"\n This function checks if a given array of integers contains any duplicate elements.\n\n Args:\n nums: A list of integers.\n\n Returns:\n True if the array contains duplicates, False otherwise.\n \"\"\"\n seen = set()\n for num in nums:\n if num in seen:\n return True\n seen.add(num)\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(arr):\n \"\"\"\n Checks if a given array of integers contains any duplicate element.\n\n Args:\n arr: A list of integers.\n\n Returns:\n True if the array contains any duplicates, False otherwise.\n \"\"\"\n seen = set()\n for num in arr:\n if num in seen:\n return True\n seen.add(num)\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(nums):\n \"\"\"\n Checks if a given array of integers contains any duplicate element.\n\n Args:\n nums: A list of integers.\n\n Returns:\n True if there is a duplicate element, False otherwise.\n \"\"\"\n seen = set()\n for num in nums:\n if num in seen:\n return True\n seen.add(num)\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(nums):\n \"\"\"\n Determines if a list of integers contains duplicate elements.\n\n Args:\n nums: A list of integers.\n\n Returns:\n True if there are duplicates, False otherwise.\n \"\"\"\n seen = set()\n for num in nums:\n if num in seen:\n return True\n seen.add(num)\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(arr):\n \"\"\"\n Checks if an array of integers contains any duplicate elements.\n \n Args:\n arr: A list of integers.\n\n Returns:\n True if the array contains duplicates, False otherwise.\n \"\"\"\n seen = set()\n for num in arr:\n if num in seen:\n return True\n seen.add(num)\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(nums):\n \"\"\"\n Checks if an array of integers contains duplicate elements.\n\n Args:\n nums: A list of integers.\n\n Returns:\n True if the array contains duplicate elements, False otherwise.\n \"\"\"\n seen = set()\n for num in nums:\n if num in seen:\n return True\n seen.add(num)\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(arr):\n \"\"\"\n Checks if an array of integers contains duplicate elements.\n Args:\n arr: A list of integers.\n Returns:\n True if the array contains duplicate elements, False otherwise.\n \"\"\"\n seen = set()\n for num in arr:\n if num in seen:\n return True\n seen.add(num)\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(nums):\n \"\"\"\n Checks if a given array of integers contains any duplicate element.\n\n Args:\n nums: A list of integers.\n\n Returns:\n True if the list contains duplicates, False otherwise.\n \"\"\"\n seen = set()\n for num in nums:\n if num in seen:\n return True\n seen.add(num)\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(arr):\n \"\"\"\n Checks if an array contains duplicate elements.\n\n Args:\n arr: A list of integers.\n\n Returns:\n True if the array contains duplicate elements, False otherwise.\n \"\"\"\n seen = set()\n for element in arr:\n if element in seen:\n return True\n seen.add(element)\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(arr):\n \"\"\"\n Checks if an array of integers contains any duplicate element.\n\n Args:\n arr: A list of integers.\n\n Returns:\n True if the array contains a duplicate element, False otherwise.\n \"\"\"\n seen = set()\n for num in arr:\n if num in seen:\n return True\n seen.add(num)\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(nums):\n \"\"\"\n This function checks if a given array of integers contains any duplicate elements.\n\n Args:\n nums: A list of integers.\n\n Returns:\n True if the array contains duplicates, False otherwise.\n \"\"\"\n seen = set()\n for num in nums:\n if num in seen:\n return True\n seen.add(num)\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(nums):\n \"\"\"\n Checks if an array of integers contains any duplicate elements.\n\n Args:\n nums: A list of integers.\n\n Returns:\n True if the array contains duplicates, False otherwise.\n \"\"\"\n seen = set()\n for num in nums:\n if num in seen:\n return True\n seen.add(num)\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(nums):\n \"\"\"\n Checks if a given array of integers contains any duplicate elements.\n\n Args:\n nums: A list of integers.\n\n Returns:\n True if there are duplicate elements in the list, False otherwise.\n \"\"\"\n\n seen = set()\n for num in nums:\n if num in seen:\n return True\n seen.add(num)\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(arr):\n \"\"\"\n Checks if an array of integers contains any duplicate elements.\n Args:\n arr: A list of integers.\n\n Returns:\n True if the array contains duplicates, False otherwise.\n \"\"\"\n seen = set()\n for element in arr:\n if element in seen:\n return True\n seen.add(element)\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(nums):\n \"\"\"\n Checks if an array of integers contains any duplicate elements.\n\n Args:\n nums: A list of integers.\n\n Returns:\n True if the array contains duplicate elements, False otherwise.\n \"\"\"\n\n seen = set()\n for num in nums:\n if num in seen:\n return True\n seen.add(num)\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(nums):\n \"\"\"\n Checks if an array of integers contains any duplicate elements.\n\n Args:\n nums: A list of integers.\n\n Returns:\n True if the array contains duplicates, False otherwise.\n \"\"\"\n seen = set()\n for num in nums:\n if num in seen:\n return True\n seen.add(num)\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(nums):\n \"\"\"\n Checks if a given array of integers contains any duplicate elements.\n\n Args:\n nums: A list of integers.\n\n Returns:\n True if there are duplicate elements, False otherwise.\n \"\"\"\n seen = set()\n for num in nums:\n if num in seen:\n return True\n seen.add(num)\n return False", "matching_cluster_idx": 14}]}, "Mbpp/62": {"dps": 80.5, "dps_norm": 87.0, "pass@1": 100.0, "profiled": [{"solution": "def smallest_num(numbers):\n \"\"\"\n Finds the smallest number in a list.\n\n Args:\n numbers: A list of numbers.\n\n Returns:\n The smallest number in the list.\n \"\"\"\n if not numbers:\n return None \n smallest = numbers[0]\n for number in numbers:\n if number < smallest:\n smallest = number\n return smallest", "matching_cluster_idx": 3}, {"solution": "def smallest_num(nums):\n \"\"\"Finds the smallest number in a list.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n The smallest number in the list.\n \"\"\"\n smallest = nums[0] \n for num in nums:\n if num < smallest:\n smallest = num\n return smallest", "matching_cluster_idx": 3}, {"solution": "def smallest_num(nums):\n \"\"\"\n This function finds the smallest number in a list.\n\n Args:\n nums: A list of numbers\n\n Returns:\n The smallest number in the list.\n \"\"\"\n\n if not nums:\n return None\n\n smallest = nums[0] \n for num in nums:\n if num < smallest:\n smallest = num\n\n return smallest", "matching_cluster_idx": 3}, {"solution": "def smallest_num(nums):\n \"\"\"\n Finds the smallest number in a list.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n The smallest number in the list.\n \"\"\"\n\n if not nums:\n return None # Handle empty list case\n\n smallest = nums[0]\n for num in nums:\n if num < smallest:\n smallest = num\n return smallest", "matching_cluster_idx": 3}, {"solution": "def smallest_num(nums):\n \"\"\"\n Finds the smallest number in a list.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n The smallest number in the list.\n \"\"\"\n smallest = nums[0]\n for num in nums:\n if num < smallest:\n smallest = num\n return smallest", "matching_cluster_idx": 3}, {"solution": "def smallest_num(nums):\n \"\"\"\n Finds the smallest number in a list.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n The smallest number in the list.\n \"\"\"\n return min(nums)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(nums):\n \"\"\"Finds the smallest number in a list.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n The smallest number in the list.\n \"\"\"\n return min(nums)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(nums):\n \"\"\"\n This function finds the smallest number in a list.\n Args:\n nums: A list of numbers.\n Returns:\n The smallest number in the list.\n \"\"\"\n smallest = nums[0] # Assume the first element is the smallest\n for num in nums:\n if num < smallest:\n smallest = num\n return smallest", "matching_cluster_idx": 3}, {"solution": "def smallest_num(nums):\n \"\"\"\n Finds the smallest number in a list.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n The smallest number in the list.\n \"\"\"\n return min(nums)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(nums):\n \"\"\"Finds the smallest number in a list.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n The smallest number in the list.\n \"\"\"\n\n if not nums:\n return None \n\n smallest = nums[0] # Assume the first element is the smallest\n for num in nums:\n if num < smallest:\n smallest = num\n return smallest", "matching_cluster_idx": 3}, {"solution": "def smallest_num(nums):\n \"\"\"\n Find the smallest number in a list.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n The smallest number in the list.\n \"\"\"\n\n smallest = nums[0]\n for num in nums:\n if num < smallest:\n smallest = num\n return smallest", "matching_cluster_idx": 3}, {"solution": "def smallest_num(nums):\n \"\"\"\n This function finds the smallest number in a list.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n The smallest number in the list.\n \"\"\"\n smallest = nums[0]\n for num in nums:\n if num < smallest:\n smallest = num\n return smallest", "matching_cluster_idx": 3}, {"solution": "def smallest_num(nums):\n \"\"\"\n Finds the smallest number in a list.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n The smallest number in the list.\n \"\"\"\n return min(nums)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(nums):\n \"\"\"\n Finds the smallest number in a list.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n The smallest number in the list.\n \"\"\"\n smallest = nums[0]\n for num in nums:\n if num < smallest:\n smallest = num\n return smallest", "matching_cluster_idx": 3}, {"solution": "def smallest_num(numbers):\n \"\"\"Finds the smallest number in a list.\n\n Args:\n numbers: A list of numbers.\n\n Returns:\n The smallest number in the list.\n \"\"\"\n return min(numbers)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(nums):\n \"\"\"\n Finds the smallest number in a list.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n The smallest number in the list.\n \"\"\"\n return min(nums)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(nums):\n \"\"\"\n Finds the smallest number in a list.\n \"\"\"\n smallest = nums[0] # Assume first element is the smallest initially\n for num in nums:\n if num < smallest:\n smallest = num\n return smallest", "matching_cluster_idx": 3}, {"solution": "def smallest_num(numbers):\n \"\"\"\n This function finds the smallest number in a list.\n\n Args:\n numbers: A list of numbers.\n\n Returns:\n The smallest number in the list.\n \"\"\"\n\n return min(numbers)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(nums):\n \"\"\"\n This function finds the smallest number in a list.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n The smallest number in the list.\n \"\"\"\n smallest = nums[0]\n for num in nums:\n if num < smallest:\n smallest = num\n return smallest", "matching_cluster_idx": 3}, {"solution": "def smallest_num(nums):\n \"\"\"Finds the smallest number in a list.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n The smallest number in the list.\n \"\"\"\n if not nums:\n return None \n smallest = nums[0]\n for num in nums:\n if num < smallest:\n smallest = num\n return smallest", "matching_cluster_idx": 3}]}, "Mbpp/75": {"dps": 92.85714285714286, "dps_norm": 66.66666666666667, "pass@1": 100.0, "profiled": [{"solution": "def find_tuples(tuples_list, k):\n \"\"\"\n Finds tuples which have all elements divisible by k from the given list of tuples.\n\n Args:\n tuples_list: A list of tuples.\n k: The divisor.\n\n Returns:\n A list of tuples that meet the divisibility condition.\n \"\"\"\n return [tuple for tuple in tuples_list if all(x % k == 0 for x in tuple)]", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n \"\"\"\n Finds tuples from a list where all elements are divisible by k.\n\n Args:\n tuples_list: A list of tuples.\n k: An integer to check divisibility by.\n\n Returns:\n A list of tuples from tuples_list where all elements are divisible by k.\n \"\"\"\n\n result = []\n for tup in tuples_list:\n if all(x % k == 0 for x in tup):\n result.append(tup)\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n \"\"\"\n Finds tuples which have all elements divisible by k from a given list of tuples.\n\n Args:\n tuples_list: A list of tuples.\n k: An integer to check divisibility by.\n\n Returns:\n A list of tuples that satisfy the condition.\n \"\"\"\n result = []\n for tup in tuples_list:\n if all(elem % k == 0 for elem in tup):\n result.append(tup)\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n \"\"\"\n Finds tuples from a list where all elements are divisible by k.\n\n Args:\n tuples_list: A list of tuples.\n k: The divisor.\n\n Returns:\n A list of tuples where each element is divisible by k.\n \"\"\"\n\n result = []\n for tup in tuples_list:\n if all(x % k == 0 for x in tup):\n result.append(tup)\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n \"\"\"\n Finds tuples which have all elements divisible by k from the given list of tuples.\n\n Args:\n tuples_list: A list of tuples.\n k: An integer.\n\n Returns:\n A list of tuples where all elements in each tuple are divisible by k.\n \"\"\"\n return [tup for tup in tuples_list if all(x % k == 0 for x in tup)]", "matching_cluster_idx": 5}, {"solution": "def find_tuples(list_of_tuples, k):\n \"\"\"\n Finds tuples with all elements divisible by k.\n\n Args:\n list_of_tuples: A list of tuples.\n k: An integer to check for divisibility.\n\n Returns:\n A list of tuples from the input where all elements are divisible by k.\n \"\"\"\n return [tup for tup in list_of_tuples if all(x % k == 0 for x in tup)]", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n \"\"\"\n Finds tuples which have all elements divisible by k from the given list of tuples.\n\n Args:\n tuples_list: A list of tuples.\n k: The divisor.\n\n Returns:\n A list of tuples that have all elements divisible by k.\n \"\"\"\n\n result = []\n for tup in tuples_list:\n if all(x % k == 0 for x in tup):\n result.append(tup)\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n \"\"\"\n Finds tuples where all elements are divisible by k.\n\n Args:\n tuples_list: A list of tuples.\n k: The divisor.\n\n Returns:\n A list of tuples where all elements are divisible by k.\n \"\"\"\n return [tup for tup in tuples_list if all(x % k == 0 for x in tup)]", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuple_list, k):\n \"\"\"Finds tuples where all elements are divisible by k.\n\n Args:\n tuple_list: A list of tuples.\n k: The divisor.\n\n Returns:\n A list of tuples where all elements are divisible by k.\n \"\"\"\n return [t for t in tuple_list if all(x % k == 0 for x in t)]", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n \"\"\"\n Finds tuples where all elements are divisible by k.\n\n Args:\n tuples_list: A list of tuples.\n k: The divisor.\n\n Returns:\n A list of tuples where all elements are divisible by k.\n \"\"\"\n result = []\n for tup in tuples_list:\n if all(x % k == 0 for x in tup):\n result.append(tup)\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n \"\"\"Find tuples where all elements are divisible by k.\"\"\"\n result = []\n for tup in tuples_list:\n if all(x % k == 0 for x in tup):\n result.append(tup)\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n \"\"\"\n Finds tuples which have all elements divisible by k from the given list of tuples.\n\n Args:\n tuples_list: A list of tuples.\n k: The divisor.\n\n Returns:\n A list of tuples where all elements in each tuple are divisible by k.\n \"\"\"\n result = []\n for tup in tuples_list:\n if all(element % k == 0 for element in tup):\n result.append(tup)\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n \"\"\"\n Finds tuples which have all elements divisible by k from a given list of tuples.\n\n Args:\n tuples_list: A list of tuples.\n k: An integer.\n\n Returns:\n A list of tuples where all elements are divisible by k.\n \"\"\"\n result = []\n for tup in tuples_list:\n if all(elem % k == 0 for elem in tup):\n result.append(tup)\n return result\nk = 6", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n \"\"\"\n This function finds tuples where all elements are divisible by k.\n\n Args:\n tuples_list: A list of tuples.\n k: The divisor.\n\n Returns:\n A list of tuples where all elements are divisible by k.\n \"\"\"\n return [tup for tup in tuples_list if all(num % k == 0 for num in tup)]", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n \"\"\"\n Finds tuples where all elements are divisible by k.\n\n Args:\n tuples_list: A list of tuples.\n k: The divisor.\n\n Returns:\n A list of tuples where all elements are divisible by k.\n \"\"\"\n result = []\n for tup in tuples_list:\n if all(x % k == 0 for x in tup):\n result.append(tup)\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n \"\"\"\n Finds tuples from a list where all elements are divisible by k.\n\n Args:\n tuples_list: A list of tuples.\n k: The divisor.\n\n Returns:\n A list of tuples where all elements are divisible by k.\n \"\"\"\n return [t for t in tuples_list if all(x % k == 0 for x in t)]", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n \"\"\"\n Finds tuples in a list where all elements are divisible by k.\n\n Args:\n tuples_list: A list of tuples.\n k: The divisor.\n\n Returns:\n A list of tuples where all elements are divisible by k.\n \"\"\"\n\n result = []\n for tup in tuples_list:\n if all(element % k == 0 for element in tup):\n result.append(tup)\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n \"\"\"\n Finds tuples which have all elements divisible by k from the given list of tuples.\n\n Args:\n tuples_list: A list of tuples.\n k: The divisor.\n\n Returns:\n A list of tuples where all elements are divisible by k.\n \"\"\"\n return [tup for tup in tuples_list if all(x % k == 0 for x in tup)]", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n \"\"\"\n Find tuples which have all elements divisible by k.\n\n Args:\n tuples_list: A list of tuples.\n k: An integer.\n\n Returns:\n A list of tuples where all elements are divisible by k.\n \"\"\"\n return [tuple for tuple in tuples_list if all(element % k == 0 for element in tuple)]", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuple_list, k):\n \"\"\"Finds tuples where all elements are divisible by k.\n\n Args:\n tuple_list: A list of tuples.\n k: The divisor.\n\n Returns:\n A list of tuples where all elements are divisible by k.\n \"\"\"\n return [tup for tup in tuple_list if all(x % k == 0 for x in tup)]", "matching_cluster_idx": 5}]}, "Mbpp/88": {"dps": 96.56862745098039, "dps_norm": 85.71428571428571, "pass@1": 100.0, "profiled": [{"solution": "def freq_count(lst):\n \"\"\"Counts the frequency of each element in a list.\n\n Args:\n lst: A list of elements.\n\n Returns:\n A dictionary where keys are unique elements of the list and values are\n their respective frequencies.\n \"\"\"\n freq = {}\n for item in lst:\n if item in freq:\n freq[item] += 1\n else:\n freq[item] = 1\n return freq", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n \"\"\"Counts the frequency of each element in a list and returns a dictionary.\n\n Args:\n lst: A list of elements.\n\n Returns:\n A dictionary where keys are the elements of the list and values are their frequencies.\n \"\"\"\n frequency = {}\n for item in lst:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n return frequency", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n \"\"\"\n This function takes a list and returns a dictionary with the frequency of each element.\n\n Args:\n lst: A list of elements.\n\n Returns:\n A dictionary where keys are the unique elements in the list and values are their frequencies.\n \"\"\"\n freq = {}\n for item in lst:\n if item in freq:\n freq[item] += 1\n else:\n freq[item] = 1\n return freq", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n \"\"\"\n Calculates the frequency of each element in a list and returns a dictionary.\n\n Args:\n lst: A list of elements.\n\n Returns:\n A dictionary where keys are the unique elements from the list\n and values are their corresponding frequencies.\n \"\"\"\n\n frequency = {}\n for item in lst:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n return frequency", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n \"\"\"\n Counts the frequency of each element in a list.\n\n Args:\n lst: A list of elements.\n\n Returns:\n A dictionary where keys are the unique elements of the list and values are their frequencies.\n \"\"\"\n\n frequency = {}\n for item in lst:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n return frequency", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n \"\"\"\n This function takes a list and returns a dictionary containing the frequency of each element in the list.\n\n Args:\n lst: A list of elements.\n\n Returns:\n A dictionary where the keys are the elements of the list and the values are their frequencies.\n \"\"\"\n frequency = {}\n for item in lst:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n return frequency", "matching_cluster_idx": 5}, {"solution": "def freq_count(data):\n \"\"\"\n Calculate the frequency of each element in a list.\n \n Args:\n data: A list of elements.\n \n Returns:\n A dictionary where keys are the unique elements from the list and values are their respective frequencies.\n \"\"\"\n frequency = {}\n for element in data:\n if element in frequency:\n frequency[element] += 1\n else:\n frequency[element] = 1\n return frequency", "matching_cluster_idx": 5}, {"solution": "def freq_count(list1):\n \"\"\"Counts the frequency of elements in a list and returns a dictionary.\n\n Args:\n list1: A list of elements.\n\n Returns:\n A dictionary where keys are unique elements from the list and values are \n their frequencies.\n \"\"\"\n frequency = {}\n for element in list1:\n if element in frequency:\n frequency[element] += 1\n else:\n frequency[element] = 1\n return frequency", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n \"\"\"\n Calculates the frequency of elements in a list.\n\n Args:\n lst: A list of elements.\n\n Returns:\n A dictionary where keys are unique elements from the list and values\n are their respective frequencies.\n \"\"\"\n freq = {}\n for item in lst:\n if item in freq:\n freq[item] += 1\n else:\n freq[item] = 1\n return freq", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n \"\"\"\n This function takes a list and returns a dictionary containing the frequency of each element in the list.\n\n Args:\n lst: A list of elements.\n\n Returns:\n A dictionary where keys are the unique elements in the list and values are their frequencies.\n \"\"\"\n frequency = {}\n for element in lst:\n if element in frequency:\n frequency[element] += 1\n else:\n frequency[element] = 1\n return frequency", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n \"\"\"\n This function takes a list as input and returns a dictionary\n containing the frequency of each element in the list.\n \"\"\"\n frequency = {}\n for item in lst:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n return frequency", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n \"\"\"\n Calculates the frequency of each element in a list and returns it as a dictionary.\n\n Args:\n lst: A list of elements.\n\n Returns:\n A dictionary where keys are unique elements from the list and values are their frequencies.\n \"\"\"\n freq = {}\n for item in lst:\n if item in freq:\n freq[item] += 1\n else:\n freq[item] = 1\n return freq", "matching_cluster_idx": 5}, {"solution": "def freq_count(data):\n \"\"\"Counts the frequency of each element in a list.\n\n Args:\n data: A list of elements.\n\n Returns:\n A dictionary where keys are unique elements from the list and values are their frequencies.\n \"\"\"\n\n freq = {}\n for item in data:\n if item in freq:\n freq[item] += 1\n else:\n freq[item] = 1\n return freq", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n \"\"\"\n This function takes a list as input and returns a dictionary containing the frequency of each element in the list.\n \"\"\"\n frequency = {}\n for element in lst:\n if element in frequency:\n frequency[element] += 1\n else:\n frequency[element] = 1\n return frequency", "matching_cluster_idx": 5}, {"solution": "def freq_count(nums):\n \"\"\"\n Returns a dictionary with frequency count of each element in a list.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n A dictionary where keys are elements from the list and values are their frequencies.\n \"\"\"\n freq = {}\n for num in nums:\n if num in freq:\n freq[num] += 1\n else:\n freq[num] = 1\n return freq", "matching_cluster_idx": 5}, {"solution": "def freq_count(nums):\n \"\"\"\n Counts the frequency of elements in a list and returns a dictionary\n where keys are elements and values are their frequencies.\n \n For example:\n assert freq_count([10,10,10,10,20,20,20,20,40,40,50,50,30])==({10: 4, 20: 4, 40: 2, 50: 2, 30: 1}) \n \"\"\"\n counts = {}\n for num in nums:\n if num in counts:\n counts[num] += 1\n else:\n counts[num] = 1\n return counts\nnums = [10,10,10,10,20,20,20,20,40,40,50,50,30]", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n \"\"\"\n Counts the frequency of all elements in a list.\n\n Args:\n lst: A list of elements.\n\n Returns:\n A dictionary where keys are the unique elements in the list and values are their frequencies.\n \"\"\"\n\n freq_dict = {}\n for item in lst:\n if item in freq_dict:\n freq_dict[item] += 1\n else:\n freq_dict[item] = 1\n return freq_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(nums):\n \"\"\"\n Calculates the frequency of each element in a list.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n A dictionary where keys are the unique elements in the list\n and values are their respective frequencies.\n \"\"\"\n freq = {}\n for num in nums:\n if num in freq:\n freq[num] += 1\n else:\n freq[num] = 1\n return freq", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n \"\"\"\n This function takes a list and returns a dictionary containing the frequency of each element.\n\n Args:\n lst: A list of elements.\n\n Returns:\n A dictionary where keys are the unique elements of the list and values are their frequencies.\n \"\"\"\n frequency = {}\n for item in lst:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n return frequency", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n \"\"\"\n This function takes a list as input and returns a dictionary containing the frequency\n of each element in the list.\n\n For example:\n freq_count([10,10,10,10,20,20,20,20,40,40,50,50,30]) == {10: 4, 20: 4, 40: 2, 50: 2, 30: 1}\n \"\"\"\n\n frequency = {}\n for item in lst:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n return frequency", "matching_cluster_idx": 5}]}, "Mbpp/90": {"dps": 75.90243902439025, "dps_norm": 84.28571428571428, "pass@1": 96.0, "profiled": [{"solution": "def len_log(words):\n \"\"\"\n Finds the length of the longest word in a list of words.\n\n Args:\n words: A list of strings.\n\n Returns:\n The length of the longest word in the list.\n \"\"\"\n longest_length = 0\n for word in words:\n if len(word) > longest_length:\n longest_length = len(word)\n return longest_length", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n \"\"\"\n Find the length of the longest word in a list of words.\n\n Args:\n words: A list of strings.\n\n Returns:\n An integer representing the length of the longest word in the list.\n \"\"\"\n\n max_length = 0\n for word in words:\n if len(word) > max_length:\n max_length = len(word)\n return max_length", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n \"\"\"\n This function takes a list of words and returns the length of the longest word.\n \"\"\"\n longest_length = 0\n for word in words:\n if len(word) > longest_length:\n longest_length = len(word)\n return longest_length", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n \"\"\"Finds the length of the longest word in a list of words.\n\n Args:\n words: A list of strings.\n\n Returns:\n An integer representing the length of the longest word in the list.\n \"\"\"\n\n longest_length = 0\n for word in words:\n if len(word) > longest_length:\n longest_length = len(word)\n return longest_length", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n \"\"\"\n This function finds the length of the longest word in a list.\n\n Args:\n words: A list of strings.\n\n Returns:\n The length of the longest word in the list.\n \"\"\"\n longest_length = 0\n for word in words:\n if len(word) > longest_length:\n longest_length = len(word)\n return longest_length", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n \"\"\"\n This function takes a list of words and returns the length of the longest word.\n\n Args:\n words: A list of strings\n\n Returns:\n The length of the longest word in the list\n \"\"\"\n longest_length = 0\n for word in words:\n if len(word) > longest_length:\n longest_length = len(word)\n return longest_length", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n \"\"\"\n Finds the length of the longest word in a list of words.\n\n Args:\n words: A list of strings.\n\n Returns:\n The length of the longest word in the list.\n \"\"\"\n\n longest_len = 0\n for word in words:\n if len(word) > longest_len:\n longest_len = len(word)\n return longest_len", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n \"\"\"\n This function takes a list of words and returns the length of the longest word.\n\n Args:\n words: A list of strings.\n\n Returns:\n The length of the longest word in the list.\n \"\"\"\n longest_length = 0\n for word in words:\n if len(word) > longest_length:\n longest_length = len(word)\n return longest_length", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n \"\"\"Finds the length of the longest word in a list of words.\n\n Args:\n words: A list of strings.\n\n Returns:\n The length of the longest word in the list.\n \"\"\"\n longest_len = 0\n for word in words:\n longest_len = max(longest_len, len(word))\n return longest_len", "matching_cluster_idx": 3}, {"solution": "def len_log(words):\n \"\"\"\n This function finds the length of the longest word in a list of words.\n\n Args:\n words: A list of strings.\n\n Returns:\n The length of the longest word in the list.\n \"\"\"\n\n max_len = 0\n for word in words:\n if len(word) > max_len:\n max_len = len(word)\n return max_len", "matching_cluster_idx": 5}, {"solution": "def len_log(lst):\n \"\"\"\n This function takes a list of strings as input and returns the length of the longest word in the list.\n\n Args:\n lst: A list of strings.\n\n Returns:\n An integer representing the length of the longest word in the list.\n \"\"\"\n longest_length = 0\n for word in lst:\n if len(word) > longest_length:\n longest_length = len(word)\n return longest_length", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n \"\"\"\n This function takes a list of words and returns the length of the longest word.\n\n Args:\n words: A list of strings.\n\n Returns:\n An integer representing the length of the longest word in the input list.\n \"\"\"\n longest_length = 0\n for word in words:\n if len(word) > longest_length:\n longest_length = len(word)\n return longest_length", "matching_cluster_idx": 5}, {"solution": "def len_log(strings):\n \"\"\"\n This function finds the length of the longest word in a list of strings.\n\n Args:\n strings: A list of strings.\n\n Returns:\n The length of the longest word in the list.\n \"\"\"\n longest_length = 0\n for word in strings:\n if len(word) > longest_length:\n longest_length = len(word)\n return longest_length", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n \"\"\"Finds the length of the longest word in a list.\n\n Args:\n words: A list of strings.\n\n Returns:\n An integer representing the length of the longest word in the list.\n \"\"\"\n return max(len(word) for word in words)", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n \"\"\"\n Finds the length of the longest word in a list of words.\n\n Args:\n words: A list of strings.\n\n Returns:\n The length of the longest word in the list.\n \"\"\"\n\n longest_length = 0\n for word in words:\n if len(word) > longest_length:\n longest_length = len(word)\n return longest_length", "matching_cluster_idx": 5}, {"solution": "def len_log(strings):\n \"\"\"Returns the length of the longest word in a list of strings.\n\n Args:\n strings: A list of strings.\n\n Returns:\n The length of the longest string in the list.\n \"\"\"\n longest_length = 0\n for string in strings:\n if len(string) > longest_length:\n longest_length = len(string)\n return longest_length", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n \"\"\"\n This function takes a list of words and returns the length of the longest word.\n \"\"\"\n return max(len(word) for word in words)", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n \"\"\"\n Finds the length of the longest word in a list of words.\n\n Args:\n words: A list of strings.\n\n Returns:\n The length of the longest word in the list.\n \"\"\"\n return max(len(word) for word in words)", "matching_cluster_idx": 5}, {"solution": "def len_log(list_of_words):\n \"\"\"\n This function finds the length of the longest word in a list of words.\n\n Args:\n list_of_words: A list of strings.\n\n Returns:\n An integer representing the length of the longest word in the list.\n \"\"\"\n longest_length = 0\n for word in list_of_words:\n if len(word) > longest_length:\n longest_length = len(word)\n return longest_length", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n \"\"\"\n This function finds the length of the longest word in a list of words.\n\n Args:\n words: A list of strings.\n\n Returns:\n The length of the longest word in the list.\n \"\"\"\n return max(len(word) for word in words)", "matching_cluster_idx": 5}]}, "Mbpp/94": {"dps": 87.65243902439025, "dps_norm": 78.0, "pass@1": 85.0, "profiled": [{"solution": "def index_minimum(tuple_list):\n \"\"\"\n Given a list of tuples, return the first value of the tuple with the smallest second value.\n \"\"\"\n min_tuple = min(tuple_list, key=lambda x: x[1])\n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(tuples_list):\n \"\"\"\n This function finds the first value of the tuple with the smallest second value.\n\n Args:\n tuples_list: A list of tuples, where each tuple contains two values.\n\n Returns:\n The first value of the tuple with the smallest second value.\n \"\"\"\n # If the list is empty, return None.\n if not tuples_list:\n return None\n \n # Initialize min_value and min_tuple with the first tuple in the list.\n min_value = tuples_list[0][1]\n min_tuple = tuples_list[0]\n\n # Iterate through the list of tuples, starting from the second tuple.\n for tuple_ in tuples_list[1:]:\n # If the second value of the current tuple is smaller than the current minimum value.\n if tuple_[1] < min_value:\n # Update the minimum value and the tuple with the minimum value.\n min_value = tuple_[1]\n min_tuple = tuple_\n\n # Return the first value of the tuple with the minimum value.\n return min_tuple[0]", "matching_cluster_idx": 3}, {"solution": "def index_minimum(tuples_list):\n \"\"\"\n Given a list of tuples, returns the first value of the tuple with the smallest second value.\n\n Args:\n tuples_list: A list of tuples, where each tuple contains two values.\n\n Returns:\n The first value of the tuple with the smallest second value.\n \"\"\"\n min_tuple = min(tuples_list, key=lambda x: x[1])\n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(tuples):\n \"\"\"\n Finds the first value of the tuple with the smallest second value in a list of tuples.\n\n Args:\n tuples: A list of tuples, where each tuple has two elements.\n\n Returns:\n The first value of the tuple with the smallest second value.\n \"\"\"\n return min(tuples, key=lambda x: x[1])[0]\ntuples = [('Rash', 143), ('Manjeet', 200), ('Varsha', 100)]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(tuples):\n \"\"\"\n Given a list of tuples, return the first value of the tuple with the smallest second value.\n\n Args:\n tuples (list): A list of tuples where each tuple has two elements (first value, second value).\n\n Returns:\n str: The first value of the tuple with the smallest second value.\n\n Example:\n index_minimum([('Rash', 143), ('Manjeet', 200), ('Varsha', 100)]) == 'Varsha'\n \"\"\"\n\n min_value = float('inf') \n min_index = ''\n for tup in tuples:\n if tup[1] < min_value:\n min_value = tup[1]\n min_index = tup[0]\n return min_index", "matching_cluster_idx": 4}, {"solution": "def index_minimum(tuples):\n \"\"\"\n Given a list of tuples, return the first value of the tuple with the smallest second value.\n \n For example:\n index_minimum([('Rash', 143), ('Manjeet', 200), ('Varsha', 100)]) == 'Varsha'\n \"\"\"\n\n min_tuple = min(tuples, key=lambda x: x[1])\n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(tuples):\n \"\"\"\n Given a list of tuples, return the first value of the tuple with the smallest second value.\n\n Args:\n tuples: A list of tuples where each tuple contains two elements.\n\n Returns:\n The first value of the tuple with the smallest second value.\n \"\"\"\n min_value = float('inf')\n min_tuple = None\n for tup in tuples:\n if tup[1] < min_value:\n min_value = tup[1]\n min_tuple = tup\n return min_tuple[0]", "matching_cluster_idx": 4}, {"solution": "def index_minimum(tuples):\n \"\"\"\n Given a list of tuples, return the first value of the tuple with the smallest second value.\n\n Args:\n tuples: A list of tuples, where each tuple has two values.\n\n Returns:\n The first value of the tuple with the smallest second value.\n \"\"\"\n return min(tuples, key=lambda x: x[1])[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(list_of_tuples):\n \"\"\"\n Given a list of tuples, returns the first value of the tuple with the smallest second value.\n\n Args:\n list_of_tuples: A list of tuples, where each tuple contains two values.\n\n Returns:\n The first value of the tuple with the smallest second value.\n \"\"\"\n return min(list_of_tuples, key=lambda item: item[1])[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(data):\n \"\"\"\n Given a list of tuples, return the first value of the tuple with the smallest second value.\n\n Args:\n data: A list of tuples, where each tuple has two elements.\n\n Returns:\n The first value of the tuple with the smallest second value.\n \"\"\"\n\n min_value = float('inf')\n result = None\n for item in data:\n if item[1] < min_value:\n min_value = item[1]\n result = item[0]\n return result", "matching_cluster_idx": 4}, {"solution": "def index_minimum(data):\n \"\"\"\n Given a list of tuples, return the first value of the tuple with the smallest second value.\n \"\"\"\n min_value = float('inf') \n min_key = None\n\n for item in data:\n if item[1] < min_value:\n min_value = item[1]\n min_key = item[0]\n return min_key", "matching_cluster_idx": 4}, {"solution": "def index_minimum(tuples_list):\n \"\"\"\n Given a list of tuples, returns the first value of the tuple with the smallest second value.\n \"\"\"\n min_value = tuples_list[0][1] # Assume first tuple's second value is the minimum initially\n min_index = 0\n for i in range(1, len(tuples_list)):\n if tuples_list[i][1] < min_value:\n min_value = tuples_list[i][1]\n min_index = i\n return tuples_list[min_index][0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(tuples_list):\n \"\"\"\n Given a list of tuples, return the first value of the tuple with the smallest second value.\n\n Args:\n tuples_list: A list of tuples, where each tuple contains two elements: a string and an integer.\n\n Returns:\n The first value of the tuple with the smallest second value.\n \"\"\"\n\n # Initialize min_value and min_tuple to the first tuple in the list\n min_value = tuples_list[0][1]\n min_tuple = tuples_list[0]\n\n # Iterate through the list of tuples\n for tup in tuples_list:\n # If the second value of the current tuple is smaller than the current minimum value\n if tup[1] < min_value:\n # Update the minimum value and the minimum tuple\n min_value = tup[1]\n min_tuple = tup\n\n # Return the first value of the minimum tuple\n return min_tuple[0]", "matching_cluster_idx": 4}, {"solution": "def index_minimum(tuples_list):\n \"\"\"Given a list of tuples, returns the first value of the tuple with the smallest second value.\n\n Args:\n tuples_list: A list of tuples, where each tuple contains two values.\n\n Returns:\n The first value of the tuple with the smallest second value.\n \"\"\"\n \n min_tuple = tuples_list[0]\n for tup in tuples_list:\n if tup[1] < min_tuple[1]:\n min_tuple = tup\n return min_tuple[0]", "matching_cluster_idx": 3}, {"solution": "def index_minimum(data):\n \"\"\"\n Given a list of tuples, return the first value of the tuple with the smallest second value.\n Args:\n data: A list of tuples, each containing a string and an integer.\n Returns:\n The first value (string) from the tuple with the smallest second value (integer).\n \"\"\"\n min_value = float('inf')\n result = None\n\n for item in data:\n if item[1] < min_value:\n min_value = item[1]\n result = item[0]\n return result", "matching_cluster_idx": 4}, {"solution": "def index_minimum(tuple_list):\n \"\"\"\n Given a list of tuples, returns the first value of the tuple with the smallest second value.\n\n Args:\n tuple_list: A list of tuples, where each tuple contains two values.\n\n Returns:\n The first value of the tuple with the smallest second value.\n \"\"\"\n \n min_tuple = min(tuple_list, key=lambda item: item[1])\n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(list_of_tuples):\n \"\"\"\n Given a list of tuples, returns the first value of the tuple with the smallest second value.\n \n Args:\n list_of_tuples: A list of tuples.\n\n Returns:\n The first value of the tuple with the smallest second value.\n \"\"\"\n min_value = float('inf')\n result = None\n\n for tup in list_of_tuples:\n if tup[1] < min_value:\n min_value = tup[1]\n result = tup[0]\n\n return result", "matching_cluster_idx": 4}, {"solution": "def index_minimum(tuples_list):\n \"\"\"\n Given a list of tuples, return the first value of the tuple with the smallest second value.\n \"\"\"\n min_value = float('inf') # Initialize with a very large number\n min_tuple = None\n\n for tup in tuples_list:\n if tup[1] < min_value:\n min_value = tup[1]\n min_tuple = tup\n return min_tuple[0]", "matching_cluster_idx": 4}, {"solution": "def index_minimum(data):\n \"\"\"\n Given a list of tuples, returns the first value of the tuple with the smallest second value.\n\n Args:\n data: A list of tuples, where each tuple contains two values.\n\n Returns:\n The first value of the tuple with the smallest second value.\n \"\"\"\n\n min_value = data[0][1] \n min_index = 0 \n\n for i in range(1, len(data)):\n if data[i][1] < min_value:\n min_value = data[i][1]\n min_index = i\n\n return data[min_index][0]\ndata = [('Rash', 143), ('Manjeet', 200), ('Varsha', 100)]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(data):\n \"\"\"Given a list of tuples, returns the first value of the tuple with the smallest second value.\n \n Args:\n data: A list of tuples, where each tuple contains two values.\n\n Returns:\n The first value of the tuple with the smallest second value.\n \"\"\"\n if not data:\n return None\n min_value = data[0][1]\n min_index = 0\n for i in range(1, len(data)):\n if data[i][1] < min_value:\n min_value = data[i][1]\n min_index = i\n return data[min_index][0]", "matching_cluster_idx": 2}]}, "Mbpp/96": {"dps": 22.083333333333332, "dps_norm": 39.285714285714285, "pass@1": 83.0, "profiled": [{"solution": "def divisor(n):\n \"\"\"Returns the number of divisors of a given integer.\n\n Args:\n n: An integer.\n\n Returns:\n The number of divisors of n.\n \"\"\"\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def divisor(n):\n \"\"\"\n Calculates the number of divisors of a given integer.\n\n Args:\n n: The integer for which to find the number of divisors.\n\n Returns:\n The number of divisors of n.\n \"\"\"\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n if i * i == n:\n count += 1\n else:\n count += 2 \n return count", "matching_cluster_idx": 6}, {"solution": "def divisor(n):\n \"\"\"\n Finds the number of divisors of a given integer.\n\n Args:\n n: The integer to find the number of divisors for.\n\n Returns:\n The number of divisors of n.\n \"\"\"\n\n count = 0 \n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def divisor(n):\n \"\"\"\n This function finds the number of divisors of a given integer.\n \n Args:\n n: An integer.\n \n Returns:\n The number of divisors of n.\n \"\"\"\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def divisor(n):\n \"\"\"\n Finds the number of divisors of a given integer.\n\n Args:\n n: The integer to find the number of divisors for.\n\n Returns:\n The number of divisors of n.\n \"\"\"\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def divisor(n):\n \"\"\"\n This function returns the number of divisors of a given integer.\n \"\"\"\n count = 0 \n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def divisor(n):\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def divisor(n):\n \"\"\"Calculates the number of divisors of a given integer.\n\n Args:\n n: The integer to find the number of divisors for.\n\n Returns:\n The number of divisors of n.\n \"\"\"\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def divisor(n):\n \"\"\"\n This function takes a positive integer n and returns the number of its divisors.\n\n Args:\n n: A positive integer.\n\n Returns:\n The number of divisors of n.\n \"\"\"\n\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def divisor(n):\n \"\"\"\n Finds the number of divisors of a given integer.\n\n Args:\n n: The integer to find divisors for.\n\n Returns:\n The number of divisors of n.\n \"\"\"\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def divisor(n):\n \"\"\"\n Find the number of divisors of a given integer.\n\n Args:\n n: The integer to find the number of divisors for.\n\n Returns:\n The number of divisors of n.\n \"\"\"\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def divisor(n):\n \"\"\"\n Finds the number of divisors of a given integer.\n\n Args:\n n: An integer.\n\n Returns:\n The number of divisors of n.\n \"\"\"\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def divisor(n):\n \"\"\"\n Calculates the number of divisors of a given integer.\n\n Args:\n n: The integer for which to find the number of divisors.\n\n Returns:\n The number of divisors of n.\n \"\"\"\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def divisor(n):\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def divisor(n):\n \"\"\"\n Finds the number of divisors of a given integer.\n\n Args:\n n: The integer to find the divisors for.\n\n Returns:\n The number of divisors of n.\n \"\"\"\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n if i == n // i:\n count += 1\n else:\n count += 2\n return count", "matching_cluster_idx": 6}, {"solution": "def divisor(n):\n \"\"\"Find the number of divisors of a given integer.\n\n Args:\n n: The integer to find divisors for.\n\n Returns:\n The number of divisors of n.\n \"\"\"\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n if i * i == n: # If i is the square root of n, count it once\n count += 1\n else:\n count += 2 # Count both i and n/i\n return count", "matching_cluster_idx": 6}, {"solution": "def divisor(n):\n \"\"\"\n This function calculates the number of divisors of a given integer.\n\n Args:\n n: An integer.\n\n Returns:\n The number of divisors of n.\n \"\"\"\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def divisor(num):\n \"\"\"\n Find the number of divisors of a given integer.\n\n Args:\n num: The integer for which to find the number of divisors.\n\n Returns:\n The number of divisors of the given integer.\n \"\"\"\n\n count = 0\n for i in range(1, num + 1):\n if num % i == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def divisor(n):\n \"\"\"\n This function takes an integer n and returns the number of divisors of n.\n \n For example:\n divisor(15) == 4\n \"\"\"\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def divisor(n):\n \"\"\"\n This function counts the number of divisors of a given integer.\n\n Args:\n n: An integer.\n\n Returns:\n The number of divisors of n.\n \"\"\"\n count = 0\n for i in range(1, n+1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 1}]}, "Mbpp/97": {"dps": 99.65811965811966, "dps_norm": 87.5, "pass@1": 100.0, "profiled": [{"solution": "def frequency_lists(lists):\n \"\"\"\n Find frequency of each element in a flattened list of lists.\n\n Args:\n lists: A list of lists.\n\n Returns:\n A dictionary where keys are unique elements and values are their frequencies.\n \"\"\"\n\n frequency = {}\n for sublist in lists:\n for element in sublist:\n if element in frequency:\n frequency[element] += 1\n else:\n frequency[element] = 1\n return frequency", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lst):\n \"\"\"\n Finds the frequency of each element in a flattened list of lists.\n\n Args:\n lst: A list of lists.\n\n Returns:\n A dictionary where keys are unique elements and values are their frequencies.\n \"\"\"\n frequency = {}\n for sublist in lst:\n for element in sublist:\n if element in frequency:\n frequency[element] += 1\n else:\n frequency[element] = 1\n return frequency", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lists):\n \"\"\"\n Calculates the frequency of each element in a flattened list of lists.\n\n Args:\n lists: A list of lists containing integers.\n\n Returns:\n A dictionary where keys are the unique elements and values are their frequencies.\n \"\"\"\n\n flattened_list = [item for sublist in lists for item in sublist]\n frequency = {}\n for item in flattened_list:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n return frequency", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(nested_list):\n \"\"\"\n Find frequency of each element in a flattened list of lists, returned in a dictionary.\n\n Args:\n nested_list (list): A list of lists of numbers.\n\n Returns:\n dict: A dictionary where keys are unique elements from the flattened list and values are their frequencies.\n \"\"\"\n\n frequency = {}\n for inner_list in nested_list:\n for element in inner_list:\n if element in frequency:\n frequency[element] += 1\n else:\n frequency[element] = 1\n return frequency", "matching_cluster_idx": 6}, {"solution": "from collections import Counter\ndef frequency_lists(list_of_lists):\n \"\"\"\n This function finds the frequency of each element in a flattened list of lists\n and returns the result in a dictionary.\n\n Args:\n list_of_lists: A list of lists.\n\n Returns:\n A dictionary where the keys are the unique elements and the values are\n the frequencies of those elements.\n \"\"\"\n\n flattened_list = [item for sublist in list_of_lists for item in sublist]\n return dict(Counter(flattened_list))", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef frequency_lists(nested_list: List[List[int]]) -> dict:\n \"\"\"\n Write a function to find frequency of each element in a flattened list of lists, returned in a dictionary.\n assert frequency_lists([[1, 2, 3, 2], [4, 5, 6, 2], [7, 8, 9, 5]])=={1: 1, 2: 3, 3: 1, 4: 1, 5: 2, 6: 1, 7: 1, 8: 1, 9: 1}\n \"\"\"\n frequency = {}\n for sublist in nested_list:\n for item in sublist:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n return frequency", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(list_of_lists):\n \"\"\"\n Finds the frequency of each element in a flattened list of lists and returns it in a dictionary.\n\n Args:\n list_of_lists: A list of lists.\n\n Returns:\n A dictionary where keys are the unique elements and values are their frequencies.\n \"\"\"\n\n flattened_list = [item for sublist in list_of_lists for item in sublist]\n frequency = {}\n for element in flattened_list:\n if element in frequency:\n frequency[element] += 1\n else:\n frequency[element] = 1\n return frequency", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(list_of_lists):\n \"\"\"Finds frequency of each element in a flattened list of lists.\n Args:\n list_of_lists: A list of lists.\n\n Returns:\n A dictionary with elements as keys and their frequencies as values.\n \"\"\"\n frequency = {}\n for sublist in list_of_lists:\n for element in sublist:\n if element in frequency:\n frequency[element] += 1\n else:\n frequency[element] = 1\n return frequency", "matching_cluster_idx": 6}, {"solution": "from collections import Counter\ndef frequency_lists(lists):\n \"\"\"Finds frequency of each element in a flattened list of lists.\n\n Args:\n lists: A list of lists.\n\n Returns:\n A dictionary where keys are unique elements and values are their frequencies.\n \"\"\"\n flattened_list = [item for sublist in lists for item in sublist] \n return dict(Counter(flattened_list))", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lists):\n \"\"\"\n Finds frequency of each element in a flattened list of lists.\n\n Args:\n lists: A list of lists.\n\n Returns:\n A dictionary with element frequencies.\n \"\"\"\n frequency = {}\n for sublist in lists:\n for element in sublist:\n if element in frequency:\n frequency[element] += 1\n else:\n frequency[element] = 1\n return frequency", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(list_of_lists):\n \"\"\"\n Counts the frequency of each element in a flattened list of lists.\n\n Args:\n list_of_lists: A list of lists.\n\n Returns:\n A dictionary where keys are unique elements from the flattened list\n and values are their respective counts.\n \"\"\"\n\n frequency = {}\n for inner_list in list_of_lists:\n for element in inner_list:\n if element in frequency:\n frequency[element] += 1\n else:\n frequency[element] = 1\n return frequency", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(list_of_lists):\n \"\"\"\n This function takes a list of lists as input and returns a dictionary \n containing the frequency of each unique element.\n\n Args:\n list_of_lists: A list of lists of integers.\n\n Returns:\n A dictionary where the keys are the unique elements from the flattened list and \n the values are their corresponding frequencies.\n \"\"\"\n\n frequency = {}\n for sublist in list_of_lists:\n for element in sublist:\n if element in frequency:\n frequency[element] += 1\n else:\n frequency[element] = 1\n return frequency", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lists):\n \"\"\"\n Finds the frequency of each element in a flattened list of lists.\n\n Args:\n lists: A list of lists.\n\n Returns:\n A dictionary where keys are unique elements and values are their frequencies.\n \"\"\"\n frequency = {}\n for sublist in lists:\n for element in sublist:\n if element in frequency:\n frequency[element] += 1\n else:\n frequency[element] = 1\n return frequency", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(list_of_lists):\n \"\"\"\n This function takes a list of lists and returns a dictionary containing the frequency of each unique element in the flattened list.\n\n Args:\n list_of_lists: A list of lists.\n\n Returns:\n A dictionary where keys are unique elements from the flattened list and values are their frequencies.\n \"\"\"\n flat_list = [item for sublist in list_of_lists for item in sublist]\n frequency = {}\n for element in flat_list:\n if element in frequency:\n frequency[element] += 1\n else:\n frequency[element] = 1\n return frequency", "matching_cluster_idx": 6}, {"solution": "from collections import Counter\ndef frequency_lists(lists):\n \"\"\"\n Finds the frequency of each element in a flattened list of lists.\n\n Args:\n lists: A list of lists.\n\n Returns:\n A dictionary where keys are the unique elements in the flattened list\n and values are their respective frequencies.\n \"\"\"\n flattened_list = [item for sublist in lists for item in sublist]\n return dict(Counter(flattened_list))", "matching_cluster_idx": 6}, {"solution": "from collections import Counter\ndef frequency_lists(nested_list):\n \"\"\"\n Finds the frequency of each element in a flattened list of lists, returned in a dictionary.\n\n Args:\n nested_list: A list of lists.\n\n Returns:\n A dictionary where keys are the unique elements in the flattened list, and values are their corresponding frequencies.\n \"\"\"\n flat_list = [item for sublist in nested_list for item in sublist]\n return dict(Counter(flat_list))", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lst_of_lsts):\n \"\"\"\n Calculates the frequency of each element in a flattened list of lists.\n\n Args:\n lst_of_lsts: A list of lists.\n\n Returns:\n A dictionary where keys are unique elements and values are their frequencies.\n \"\"\"\n frequency = {}\n for lst in lst_of_lsts:\n for item in lst:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n return frequency", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(list_of_lists):\n \"\"\"\n Calculates the frequency of each element in a flattened list of lists.\n\n Args:\n list_of_lists: A list of lists containing integers.\n\n Returns:\n A dictionary where keys are the unique elements and values are their frequencies.\n \"\"\"\n frequency = {}\n for sublist in list_of_lists:\n for element in sublist:\n if element in frequency:\n frequency[element] += 1\n else:\n frequency[element] = 1\n return frequency", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lists):\n \"\"\"\n Write a function to find frequency of each element in a flattened list of lists, returned in a dictionary.\n\n For example:\n frequency_lists([[1, 2, 3, 2], [4, 5, 6, 2], [7, 8, 9, 5]]) == {1: 1, 2: 3, 3: 1, 4: 1, 5: 2, 6: 1, 7: 1, 8: 1, 9: 1}\n \"\"\"\n frequency = {}\n for lst in lists:\n for item in lst:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n return frequency", "matching_cluster_idx": 6}, {"solution": "from collections import Counter\ndef frequency_lists(list_of_lists):\n \"\"\"\n Calculates the frequency of each element in a flattened list of lists.\n\n Args:\n list_of_lists: A list of lists.\n\n Returns:\n A dictionary where keys are the unique elements and values are their frequencies.\n \"\"\"\n flattened_list = [item for sublist in list_of_lists for item in sublist]\n return dict(Counter(flattened_list))", "matching_cluster_idx": 6}]}, "Mbpp/106": {"dps": 81.49350649350649, "dps_norm": 91.66666666666667, "pass@1": 100.0, "profiled": [{"solution": "def add_lists(lst, tup):\n \"\"\"\n Appends the given list to the given tuple.\n\n Args:\n lst: A list of elements to append.\n tup: A tuple to which the list will be appended.\n\n Returns:\n A new tuple with the elements of the list appended to the tuple.\n \"\"\"\n return tup + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tup):\n \"\"\"Appends a list to a tuple.\n\n Args:\n lst: The list to be appended.\n tup: The tuple to which the list will be appended.\n\n Returns:\n A new tuple with the elements of the list appended to the tuple.\n \"\"\"\n return tup + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(list1, tuple1):\n \"\"\"Append the given list to the given tuples.\n\n Args:\n list1: A list of numbers.\n tuple1: A tuple of numbers.\n\n Returns:\n A new tuple with the elements of the input tuple followed by the elements of the input list.\n\n Examples:\n assert add_lists([5, 6, 7], (9, 10)) == (9, 10, 5, 6, 7)\n\n \"\"\"\n return tuple1 + tuple(list1)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tup):\n \"\"\"Appends the given list to the given tuple.\n\n Args:\n lst: The list to append.\n tup: The tuple to append to.\n\n Returns:\n A new tuple with the list appended to the original tuple.\n \"\"\"\n return tuple(list(tup) + lst)", "matching_cluster_idx": 2}, {"solution": "def add_lists(list1, tup1):\n \"\"\"\n This function appends a given list to a given tuple.\n Args:\n list1: The list to be appended.\n tup1: The tuple to which the list will be appended.\n Returns:\n A new tuple with the elements of the list appended to the tuple.\n \"\"\"\n return tup1 + tuple(list1)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tup):\n \"\"\"\n Appends the given list to the given tuple.\n\n Args:\n lst: The list to be appended.\n tup: The tuple to append to.\n\n Returns:\n A new tuple with the elements of the list appended to the tuple.\n \"\"\"\n return tup + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(list_to_add, tup):\n \"\"\"Appends the given list to the given tuple.\n\n Args:\n list_to_add: A list of elements to add to the tuple.\n tup: The tuple to append the list to.\n\n Returns:\n A new tuple with the list elements appended.\n \"\"\"\n return tup + tuple(list_to_add)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tup):\n \"\"\"Appends the given list to the given tuples.\"\"\"\n return tuple(list(tup) + lst)", "matching_cluster_idx": 3}, {"solution": "def add_lists(lst, tup):\n \"\"\"Appends a list to a tuple.\n\n Args:\n lst: The list to be appended.\n tup: The tuple to which the list will be appended.\n\n Returns:\n A new tuple containing the elements of the original tuple followed by the elements of the list.\n \"\"\"\n return tup + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "from typing import Tuple, List\ndef add_lists(lst: List[int], tup: Tuple[int, ...]) -> Tuple[int, ...]:\n \"\"\"\n Appends the given list to the given tuples.\n\n Args:\n lst: The list to append\n tup: The tuple to which the list will be appended\n\n Returns:\n A new tuple with the list appended to the given tuple.\n\n \"\"\"\n return tuple(list(tup) + lst)", "matching_cluster_idx": 2}, {"solution": "def add_lists(my_list, my_tuple):\n \"\"\"\n Appends the elements of a list to a tuple and returns a new tuple.\n\n Args:\n my_list: The list to be appended.\n my_tuple: The tuple to append to.\n\n Returns:\n A new tuple with the elements of the list appended to the tuple.\n \"\"\"\n return my_tuple + tuple(my_list)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tup):\n \"\"\"\n This function appends the given list to the given tuple.\n\n Args:\n lst: A list of elements to append.\n tup: A tuple to which the list will be appended.\n\n Returns:\n A new tuple with the elements of the input tuple followed by the elements of the input list.\n \"\"\"\n return tup + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tup):\n \"\"\"Appends the given list to the given tuple.\n\n Args:\n lst: The list to be appended.\n tup: The tuple to append to.\n\n Returns:\n A new tuple with the list elements appended to the end of the tuple.\n \"\"\"\n return tup + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tup):\n \"\"\"Appends a list to a tuple.\n\n Args:\n lst: A list of elements to append.\n tup: The tuple to append the list to.\n\n Returns:\n A new tuple with the list elements appended.\n \"\"\"\n return tup + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(input_list, input_tuple):\n \"\"\"Appends the given list to the given tuple.\n\n Args:\n input_list: A list of elements.\n input_tuple: A tuple of elements.\n\n Returns:\n A new tuple containing all elements of the input tuple followed by the elements of the input list.\n \"\"\"\n return input_tuple + tuple(input_list)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tpl):\n \"\"\"\n Appends the given list to the given tuple.\n\n Args:\n lst: The list to be appended.\n tpl: The tuple to which the list is appended.\n\n Returns:\n A new tuple with the list elements appended to the end of the tuple.\n \"\"\"\n return tpl + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tup):\n \"\"\"Appends the given list to the given tuple.\n\n Args:\n lst: A list of elements.\n tup: A tuple of elements.\n\n Returns:\n A tuple with the elements of the input tuple followed by the elements of the input list.\n \"\"\"\n return tuple(list(tup) + lst)", "matching_cluster_idx": 3}, {"solution": "def add_lists(list1, tuple1):\n \"\"\"Appends a list to a tuple.\n\n Args:\n list1: The list to be appended.\n tuple1: The tuple to append the list to.\n\n Returns:\n A new tuple with the elements of the list appended to the tuple.\n \"\"\"\n return tuple1 + tuple(list1)", "matching_cluster_idx": 5}, {"solution": "def add_lists(list_to_append, tuple_to_add_to):\n \"\"\"Appends a list to a tuple.\n\n Args:\n list_to_append: The list to be appended to the tuple.\n tuple_to_add_to: The tuple to which the list will be appended.\n\n Returns:\n A new tuple with the list appended to the end of the original tuple.\n \"\"\"\n return tuple_to_add_to + tuple(list_to_append)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tpl):\n \"\"\"\n Appends a list to a tuple.\n Args:\n lst: The list to be appended.\n tpl: The tuple to which the list will be appended.\n\n Returns:\n A new tuple with the elements of the list appended to the tuple.\n \"\"\"\n return tpl + tuple(lst)", "matching_cluster_idx": 5}]}, "Mbpp/108": {"dps": null, "dps_norm": null, "pass@1": 9.0, "profiled": []}, "Mbpp/111": {"dps": 91.53846153846155, "dps_norm": 86.25, "pass@1": 99.0, "profiled": [{"solution": "def common_in_nested_lists(nested_lists):\n \"\"\"Finds the common elements in a list of lists.\n\n Args:\n nested_lists: A list of lists.\n\n Returns:\n A set of the common elements.\n \"\"\"\n common = set(nested_lists[0]) \n for lst in nested_lists[1:]:\n common = common.intersection(set(lst))\n return common", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(list_of_lists):\n \"\"\"\n Finds the common elements in given nested lists.\n\n Args:\n list_of_lists: A list of lists.\n\n Returns:\n A set containing the common elements found in all lists.\n \"\"\"\n common_elements = set(list_of_lists[0])\n for lst in list_of_lists[1:]:\n common_elements &= set(lst)\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n \"\"\"\n Finds the common elements in given nested lists.\n\n Args:\n nested_lists: A list of lists.\n\n Returns:\n A set containing the common elements.\n \"\"\"\n common_elements = set(nested_lists[0])\n for lst in nested_lists[1:]:\n common_elements.intersection_update(lst)\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n \"\"\"Finds the common elements in given nested lists.\n\n Args:\n nested_lists: A list of lists.\n\n Returns:\n A set containing the common elements.\n \"\"\"\n\n common_elements = set(nested_lists[0])\n for lst in nested_lists[1:]:\n common_elements.intersection_update(lst)\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_list):\n \"\"\"\n Finds the common elements in given nested lists.\n \n Args:\n nested_list: A list of lists.\n Returns:\n A set of the common elements.\n \"\"\"\n common = set(nested_list[0])\n for sublist in nested_list[1:]:\n common &= set(sublist)\n return common", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n \"\"\"\n Finds the common elements in given nested lists.\n \n Args:\n nested_lists: A list of lists.\n\n Returns:\n A set of the common elements.\n \"\"\"\n common_elements = set(nested_lists[0])\n for lst in nested_lists[1:]:\n common_elements &= set(lst)\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n \"\"\"\n Finds the common elements in given nested lists.\n\n Args:\n nested_lists: A list of lists.\n\n Returns:\n A set of elements common to all nested lists.\n \"\"\"\n\n # Find the set of elements in the first list\n common_elements = set(nested_lists[0])\n\n # Iterate through remaining lists\n for lst in nested_lists[1:]:\n # Find the intersection with the current list\n common_elements &= set(lst)\n\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n \"\"\"\n Finds the common elements in a list of nested lists.\n\n Args:\n nested_lists: A list of lists.\n\n Returns:\n A set containing the common elements found in all nested lists.\n \"\"\"\n common_elements = set(nested_lists[0]) \n for sublist in nested_lists[1:]:\n common_elements &= set(sublist) \n return common_elements", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(lists):\n \"\"\"Finds common elements in given nested lists.\n\n Args:\n lists: A list of lists.\n\n Returns:\n A set of elements common to all input lists.\n \"\"\"\n\n common_elements = set(lists[0]) \n for lst in lists[1:]:\n common_elements &= set(lst)\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(list_of_lists):\n \"\"\"Finds the common elements in given nested lists.\n\n Args:\n list_of_lists: A list of lists.\n\n Returns:\n A set containing the common elements.\n \"\"\"\n common_elements = set(list_of_lists[0]) \n for lst in list_of_lists[1:]:\n common_elements &= set(lst)\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(lists):\n \"\"\"Finds the common elements in given nested lists.\n\n Args:\n lists: A list of lists.\n\n Returns:\n A set containing the common elements.\n \"\"\"\n common = set(lists[0])\n for lst in lists[1:]:\n common &= set(lst)\n return common", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n \"\"\"\n Finds the common elements in given nested lists.\n\n Args:\n nested_lists: A list of lists.\n\n Returns:\n A set of the common elements.\n \"\"\"\n common_elements = set(nested_lists[0])\n for lst in nested_lists[1:]:\n common_elements &= set(lst)\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_list):\n \"\"\"Finds the common elements in a given nested list.\n\n Args:\n nested_list: A list of lists.\n\n Returns:\n A set containing the common elements present in all the sublists.\n \"\"\"\n common_elements = set(nested_list[0])\n for sublist in nested_list[1:]:\n common_elements &= set(sublist)\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n \"\"\"\n Finds the common elements in given nested lists.\n\n Args:\n nested_lists: A list of lists containing integers.\n\n Returns:\n A set containing the common elements.\n \"\"\"\n common_elements = set(nested_lists[0])\n for lst in nested_lists[1:]:\n common_elements &= set(lst)\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n \"\"\"Finds the common elements in given nested lists.\n\n Args:\n nested_lists: A list of lists.\n\n Returns:\n A set containing the common elements.\n \"\"\"\n common_elements = set(nested_lists[0])\n for lst in nested_lists[1:]:\n common_elements = common_elements.intersection(set(lst))\n return common_elements", "matching_cluster_idx": 5}, {"solution": "def common_in_nested_lists(nested_list):\n \"\"\"\n Finds the common elements in given nested lists.\n\n Args:\n nested_list: A list of lists.\n\n Returns:\n A set of common elements.\n \"\"\"\n common = set(nested_list[0])\n for lst in nested_list[1:]:\n common &= set(lst)\n return common", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n \"\"\"Finds the common elements in given nested lists.\n\n Args:\n nested_lists: A list of lists, where each inner list contains integers.\n\n Returns:\n A set containing the common elements found in all input lists.\n \"\"\"\n common_elements = set(nested_lists[0])\n for lst in nested_lists[1:]:\n common_elements = common_elements.intersection(set(lst))\n return common_elements", "matching_cluster_idx": 5}, {"solution": "def common_in_nested_lists(nested_list):\n \"\"\"\n Finds the common elements in given nested lists.\n\n Args:\n nested_list: A list of lists containing integers.\n\n Returns:\n A set containing the common elements.\n \"\"\"\n common_elements = set(nested_list[0])\n for lst in nested_list[1:]:\n common_elements &= set(lst) \n return common_elements", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n \"\"\"\n Finds the common elements in given nested lists.\n\n Args:\n nested_lists: A list of lists.\n\n Returns:\n A set containing the common elements.\n \"\"\"\n common_elements = set(nested_lists[0])\n for lst in nested_lists[1:]:\n common_elements.intersection_update(lst)\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(lists):\n \"\"\"\n Finds the common elements in given nested lists.\n\n Args:\n lists: A list of lists.\n\n Returns:\n A set containing the common elements.\n \"\"\"\n\n common_elements = set(lists[0]) \n for lst in lists[1:]:\n common_elements &= set(lst)\n return common_elements", "matching_cluster_idx": 6}]}, "Mbpp/123": {"dps": 99.62686567164178, "dps_norm": 85.71428571428571, "pass@1": 72.0, "profiled": [{"solution": "def sum_divisors(n):\n \"\"\"Calculates the sum of proper divisors of a number.\"\"\"\n total = 1\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n total += i\n if i != n // i:\n total += n // i\n return total\ndef amicable_numbers_sum(limit):\n \"\"\"\n Calculates the sum of all amicable numbers below a given limit.\n\n Args:\n limit: The upper limit for finding amicable numbers.\n\n Returns:\n The sum of all amicable numbers below the limit.\n \"\"\"\n\n amicable_sum = 0\n for num in range(2, limit):\n other_num = sum_divisors(num)\n if sum_divisors(other_num) == num and num != other_num:\n amicable_sum += num\n return amicable_sum", "matching_cluster_idx": 11}, {"solution": "def sum_divisors(n):\n \"\"\"\n Calculates the sum of divisors of a given number.\n \"\"\"\n divisors = [1]\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n divisors.append(i)\n if i != n // i:\n divisors.append(n // i)\n return sum(divisors)\ndef amicable_numbers_sum(limit):\n \"\"\"\n Calculates the sum of all amicable numbers up to a specified limit.\n \"\"\"\n total_sum = 0\n for i in range(2, limit + 1):\n j = sum_divisors(i)\n if sum_divisors(j) == i and i != j: \n total_sum += i\n return total_sum", "matching_cluster_idx": 11}, {"solution": "def sum_divisors(n):\n \"\"\"Calculates the sum of proper divisors of a number.\"\"\"\n divisors = [1]\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n divisors.append(i)\n if i != n // i:\n divisors.append(n // i)\n return sum(divisors)\ndef amicable_numbers_sum(limit):\n \"\"\"Calculates the sum of all amicable numbers up to a given limit.\"\"\"\n amicable_sum = 0\n for i in range(2, limit + 1):\n j = sum_divisors(i)\n if i != j and sum_divisors(j) == i:\n amicable_sum += i\n return amicable_sum", "matching_cluster_idx": 11}, {"solution": "def sum_of_divisors(n):\n \"\"\"\n Calculate the sum of all proper divisors of a number.\n \"\"\"\n sum = 1\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n sum += i\n if i != n//i: # Avoid double-counting for perfect squares\n sum += n//i\n return sum\ndef amicable_numbers_sum(limit):\n \"\"\"\n Calculate the sum of all amicable numbers below a given limit.\n\n An amicable number is a number whose sum of proper divisors is equal to another number,\n whose sum of proper divisors is the original number.\n \"\"\"\n amicable_sum = 0\n for i in range(2, limit):\n a = sum_of_divisors(i)\n b = sum_of_divisors(a)\n if i != a and b == i:\n amicable_sum += i\n return amicable_sum", "matching_cluster_idx": 11}, {"solution": "def sum_proper_divisors(num):\n \"\"\"Returns the sum of the proper divisors of a given number.\"\"\"\n divisors = [1]\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n divisors.append(i)\n if i != num // i:\n divisors.append(num // i)\n return sum(divisors)\ndef amicable_numbers_sum(limit):\n \"\"\"Returns the sum of all amicable numbers below the given limit.\"\"\"\n amicable_sum = 0\n for num in range(2, limit):\n sum1 = sum_proper_divisors(num)\n sum2 = sum_proper_divisors(sum1)\n if sum2 == num and num != sum1:\n amicable_sum += num\n return amicable_sum", "matching_cluster_idx": 11}, {"solution": "def sum_divisors(n):\n \"\"\"Calculates the sum of proper divisors of a number.\"\"\"\n divisors_sum = 1\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n divisors_sum += i\n if i != n // i:\n divisors_sum += n // i\n return divisors_sum\ndef amicable_numbers_sum(limit):\n \"\"\"Calculates the sum of all amicable numbers from 1 to a given limit.\"\"\"\n amicable_sum = 0\n for i in range(2, limit + 1):\n sum_i = sum_divisors(i)\n sum_sum_i = sum_divisors(sum_i)\n if i != sum_i and i == sum_sum_i:\n amicable_sum += i\n return amicable_sum", "matching_cluster_idx": 11}, {"solution": "def sum_divisors(n):\n \"\"\"Calculates the sum of divisors of a number.\"\"\"\n sum_of_divisors = 1\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n sum_of_divisors += i\n if i != n // i:\n sum_of_divisors += n // i\n return sum_of_divisors\ndef amicable_numbers_sum(limit):\n \"\"\"Calculates the sum of all amicable numbers below the specified limit.\"\"\"\n total_sum = 0\n for i in range(2, limit):\n j = sum_divisors(i)\n if i != j and sum_divisors(j) == i:\n total_sum += i\n return total_sum", "matching_cluster_idx": 11}, {"solution": "def sum_of_proper_divisors(n):\n \"\"\"\n Calculates the sum of proper divisors of a number.\n \"\"\"\n divisors_sum = 1\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n divisors_sum += i\n if i != n // i:\n divisors_sum += n // i\n return divisors_sum\ndef amicable_numbers_sum(limit):\n \"\"\"\n Calculates the sum of all amicable numbers up to a given limit.\n\n Args:\n limit: The upper limit for finding amicable numbers.\n\n Returns:\n The sum of all amicable numbers less than or equal to the limit.\n \"\"\"\n amicable_sum = 0\n for i in range(2, limit + 1):\n sum_divisors_i = sum_of_proper_divisors(i)\n sum_divisors_j = sum_of_proper_divisors(sum_divisors_i)\n if sum_divisors_j == i and i != sum_divisors_i:\n amicable_sum += i\n return amicable_sum", "matching_cluster_idx": 11}, {"solution": "def sum_proper_divisors(n):\n \"\"\"Calculates the sum of proper divisors (excluding the number itself) of a given number.\"\"\"\n divisors = [1] \n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n divisors.append(i)\n if i != n // i: \n divisors.append(n // i)\n return sum(divisors)\ndef amicable_numbers_sum(limit):\n \"\"\"Finds the sum of all amicable numbers from 1 to a given limit.\"\"\"\n amicable_sum = 0\n for i in range(2, limit + 1):\n sum_i = sum_proper_divisors(i)\n sum_sum_i = sum_proper_divisors(sum_i)\n if sum_sum_i == i and i != sum_i: \n amicable_sum += i\n return amicable_sum", "matching_cluster_idx": 11}, {"solution": "def sum_proper_divisors(n):\n \"\"\"Calculates the sum of proper divisors of a number.\"\"\"\n divisors_sum = 1\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n divisors_sum += i\n if i != n // i:\n divisors_sum += n // i\n return divisors_sum\ndef amicable_numbers_sum(limit):\n \"\"\"Calculates the sum of amicable numbers up to a given limit.\"\"\"\n amicable_sum = 0\n for i in range(2, limit + 1):\n a = sum_proper_divisors(i)\n b = sum_proper_divisors(a)\n if i == b and i != a:\n amicable_sum += i\n return amicable_sum", "matching_cluster_idx": 11}, {"solution": "def amicable_numbers_sum(limit):\n \"\"\"\n Calculates the sum of all amicable numbers from 1 to a specified number.\n\n Args:\n limit: The upper limit for finding amicable numbers.\n\n Returns:\n The sum of all amicable numbers less than or equal to the limit.\n \"\"\"\n\n def sum_proper_divisors(n):\n \"\"\"Calculates the sum of proper divisors (divisors excluding the number itself) of a number.\"\"\"\n divisors_sum = 1 \n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n divisors_sum += i + (n // i) \n if i == n // i: \n divisors_sum -= i \n return divisors_sum\n\n amicable_sum = 0\n for i in range(2, limit + 1):\n a = sum_proper_divisors(i)\n b = sum_proper_divisors(a)\n if i == b and i != a:\n amicable_sum += i\n return amicable_sum", "matching_cluster_idx": 11}, {"solution": "def sum_divisors(n):\n \"\"\"\n Calculates the sum of proper divisors of a number.\n \"\"\"\n total = 1 # Start with 1 as it's always a divisor\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n total += i\n if i != n // i: # Avoid adding the same divisor twice for perfect squares\n total += n // i\n return total\ndef amicable_numbers_sum(limit):\n \"\"\"\n Calculates the sum of all amicable numbers less than or equal to the given limit.\n \"\"\"\n total_sum = 0\n for i in range(2, limit + 1):\n # Find the sum of divisors for i\n sum_i = sum_divisors(i)\n # Check if the sum of divisors of i, (sum_i), \n # is a divisor of i and the sum of divisors of sum_i is equal to i\n if sum_i <= limit and sum_divisors(sum_i) == i and sum_i != i:\n total_sum += i # Add i to the total sum \n\n return total_sum", "matching_cluster_idx": 11}, {"solution": "def sum_divisors(n):\n \"\"\"Returns the sum of all proper divisors of n.\"\"\"\n total = 1\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n total += i\n if i != n // i:\n total += n // i\n return total\ndef amicable_numbers_sum(limit):\n \"\"\"Returns the sum of all amicable numbers below the given limit.\"\"\"\n amicable_sum = 0\n for i in range(2, limit):\n a = sum_divisors(i)\n b = sum_divisors(a)\n if b == i and a != b:\n amicable_sum += i\n return amicable_sum", "matching_cluster_idx": 11}, {"solution": "def sum_of_divisors(n):\n \"\"\"Calculates the sum of proper divisors of a number.\"\"\"\n divisors_sum = 1\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n divisors_sum += i\n if i != n // i:\n divisors_sum += n // i\n return divisors_sum\ndef amicable_numbers_sum(limit):\n \"\"\"\n Calculates the sum of all amicable numbers up to a specified limit.\n\n An amicable number is a number where the sum of its proper divisors \n is equal to another number, and vice versa.\n\n Args:\n limit: The upper limit to search for amicable numbers.\n\n Returns:\n The sum of all amicable numbers up to the limit.\n \"\"\"\n amicable_sum = 0\n for num in range(2, limit + 1):\n a = sum_of_divisors(num)\n b = sum_of_divisors(a)\n if a != b and num == b:\n amicable_sum += num\n return amicable_sum", "matching_cluster_idx": 11}, {"solution": "def sum_divisors(n):\n \"\"\"Returns the sum of proper divisors of a number.\"\"\"\n divisors_sum = 1\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n divisors_sum += i\n if i != n // i:\n divisors_sum += n // i\n return divisors_sum\ndef amicable_numbers_sum(limit):\n \"\"\"Returns the sum of all amicable numbers below a given limit.\"\"\"\n total_sum = 0\n for i in range(2, limit):\n j = sum_divisors(i)\n if i != j and sum_divisors(j) == i:\n total_sum += i\n return total_sum", "matching_cluster_idx": 11}, {"solution": "def sum_of_proper_divisors(n):\n \"\"\"\n Calculates the sum of proper divisors of a given number.\n\n Args:\n n: The number to calculate the sum of proper divisors for.\n\n Returns:\n The sum of proper divisors of n.\n \"\"\"\n divisors = [1]\n for i in range(2, int(n ** 0.5) + 1):\n if n % i == 0:\n divisors.append(i)\n if i != n // i:\n divisors.append(n // i)\n return sum(divisors)\ndef amicable_numbers_sum(limit):\n \"\"\"\n Calculates the sum of all amicable numbers up to a given limit.\n\n Args:\n limit: The upper limit for finding amicable numbers.\n\n Returns:\n The sum of all amicable numbers up to the limit.\n \"\"\"\n amicable_sum = 0\n for i in range(2, limit + 1):\n sum_divisors_i = sum_of_proper_divisors(i)\n sum_divisors_j = sum_of_proper_divisors(sum_divisors_i)\n if i == sum_divisors_j and i != sum_divisors_i:\n amicable_sum += i\n return amicable_sum", "matching_cluster_idx": 11}, {"solution": "def sum_divisors(n):\n \"\"\"Calculates the sum of proper divisors of a number.\"\"\"\n divisors = [1]\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n divisors.append(i)\n if i != n // i:\n divisors.append(n // i)\n return sum(divisors)\ndef amicable_numbers_sum(limit):\n \"\"\"Calculates the sum of all amicable numbers below a given limit.\"\"\"\n amicable_sum = 0\n for i in range(2, limit):\n j = sum_divisors(i)\n if sum_divisors(j) == i and i != j:\n amicable_sum += i\n return amicable_sum", "matching_cluster_idx": 11}, {"solution": "def sum_divisors(n):\n \"\"\"Returns the sum of proper divisors of n.\"\"\"\n total = 1\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n total += i\n if i != n // i:\n total += n // i\n return total\ndef amicable_numbers_sum(limit):\n \"\"\"Returns the sum of all amicable numbers up to the given limit.\"\"\"\n total = 0\n for i in range(2, limit + 1):\n a = sum_divisors(i)\n b = sum_divisors(a)\n if i != a and i == b:\n total += i\n return total", "matching_cluster_idx": 11}, {"solution": "def sum_divisors(n):\n \"\"\"Returns the sum of proper divisors of a number.\"\"\"\n divisors_sum = 1\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n divisors_sum += i\n if i != n // i: # Avoid double-counting for perfect squares\n divisors_sum += n // i\n return divisors_sum\ndef amicable_numbers_sum(limit):\n \"\"\"Returns the sum of all amicable numbers from 1 to a given limit.\"\"\"\n amicable_sum = 0\n for i in range(2, limit + 1):\n j = sum_divisors(i)\n if i != j and sum_divisors(j) == i:\n amicable_sum += i\n return amicable_sum", "matching_cluster_idx": 11}, {"solution": "def sum_divisors(n):\n \"\"\"Returns the sum of proper divisors of a number.\"\"\"\n divisors = [1]\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n divisors.append(i)\n if i != n // i:\n divisors.append(n // i)\n return sum(divisors)\ndef amicable_numbers_sum(limit):\n \"\"\"Returns the sum of all amicable numbers less than or equal to the limit.\"\"\"\n amicable_sum = 0\n for i in range(2, limit + 1):\n j = sum_divisors(i)\n if i != j and sum_divisors(j) == i:\n amicable_sum += i\n return amicable_sum", "matching_cluster_idx": 11}]}, "Mbpp/128": {"dps": 99.5475113122172, "dps_norm": 80.0, "pass@1": 77.0, "profiled": [{"solution": "def long_words(n, sentence):\n \"\"\"\n Finds words longer than n characters from a given sentence.\n\n Args:\n n: The minimum length of words to return.\n sentence: A string containing words separated by spaces.\n\n Returns:\n A list of words from the sentence that are longer than n characters.\n \"\"\"\n words = sentence.split()\n long_words = [word for word in words if len(word) > n]\n return long_words", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n \"\"\"\n This function finds words that are longer than n characters from a given list of words.\n Args:\n n: An integer representing the minimum length of words to return.\n sentence: A string containing the sentence to be processed.\n Returns:\n A list of words that are longer than n characters.\n \"\"\"\n\n words = sentence.split()\n return [word for word in words if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n \"\"\"\n This function finds words longer than n characters in a given sentence.\n\n Args:\n n: An integer representing the minimum word length.\n sentence: A string containing a sentence.\n\n Returns:\n A list of words from the sentence that are longer than n characters.\n \"\"\"\n words = sentence.split()\n long_words = [word for word in words if len(word) > n]\n return long_words", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n \"\"\"\n Finds words longer than n characters from a given sentence.\n\n Args:\n n: The minimum length of words to return.\n sentence: The sentence to search for long words.\n\n Returns:\n A list of words from the sentence that are longer than n characters.\n \"\"\"\n\n words = sentence.split()\n return [word for word in words if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, text):\n \"\"\"\n Find words that are longer than n characters from a given list of words.\n\n Args:\n n: The minimum length of the words to be returned.\n text: A string containing the words.\n\n Returns:\n A list of words from the text that are longer than n characters.\n \"\"\"\n\n words = text.split()\n return [word for word in words if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n \"\"\"\n This function takes a number n and a string of words, and returns a list\n containing all the words from the sentence that are longer than n characters.\n\n Args:\n n: The minimum length of words to include in the result.\n sentence: A string of words separated by spaces.\n\n Returns:\n A list of words from the sentence that are longer than n characters.\n \"\"\"\n words = sentence.split()\n return [word for word in words if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n \"\"\"\n Finds words longer than n characters from a given sentence.\n\n Args:\n n (int): The minimum length of words to be included.\n sentence (str): The input sentence to extract words from.\n\n Returns:\n list: A list of words longer than n characters.\n \"\"\"\n words = sentence.split()\n return [word for word in words if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n \"\"\"\n Finds words longer than n characters from a given list of words.\n\n Args:\n n: The minimum length of words to be considered.\n sentence: A string containing the words to check.\n\n Returns:\n A list of words longer than n characters.\n \"\"\"\n words = sentence.split() \n long_words = [word for word in words if len(word) > n]\n return long_words", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n \"\"\"\n This function takes a number n and a string of words, \n and returns a list of words from the string that are longer than n characters.\n \"\"\"\n words = sentence.split()\n long_words_list = [word for word in words if len(word) > n]\n return long_words_list", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n \"\"\"\n This function takes a number n and a sentence as input and returns a list of words\n from the sentence that are longer than n characters.\n\n Args:\n n: An integer representing the minimum length of words to be included.\n sentence: A string representing the sentence to be processed.\n\n Returns:\n A list of strings, containing words from the sentence longer than n characters.\n \"\"\"\n words = sentence.split()\n long_words = [word for word in words if len(word) > n]\n return long_words", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n \"\"\"\n This function finds words longer than n characters from a given sentence.\n\n Args:\n n: The minimum length of the words to be returned.\n sentence: A string containing the words to be checked.\n\n Returns:\n A list of words longer than n characters.\n \"\"\"\n words = sentence.split()\n return [word for word in words if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n \"\"\"\n Finds words longer than n characters from a given list of words.\n\n Args:\n n: The minimum length of words to return.\n sentence: A string containing a sentence.\n\n Returns:\n A list of words from the sentence that are longer than n characters.\n \"\"\"\n\n words = sentence.split()\n long_words = [word for word in words if len(word) > n]\n return long_words", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n \"\"\"\n This function takes a number n and a string sentence as input.\n It returns a list of words from the sentence that are longer than n characters.\n\n Args:\n n: An integer representing the minimum length of words to be returned.\n sentence: A string containing words separated by spaces.\n\n Returns:\n A list of words from the sentence that are longer than n characters.\n \"\"\"\n words = sentence.split()\n long_words = [word for word in words if len(word) > n]\n return long_words", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n \"\"\"\n Returns a list of words from a sentence that are longer than n characters.\n\n Args:\n n: The minimum length of words to return.\n sentence: The sentence to extract words from.\n\n Returns:\n A list of words longer than n characters.\n \"\"\"\n\n words = sentence.split()\n long_words_list = [word for word in words if len(word) > n]\n return long_words_list", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n \"\"\"\n Finds words longer than n characters in a sentence.\n\n Args:\n n: The minimum length of words to return.\n sentence: The sentence to search.\n\n Returns:\n A list of words longer than n characters.\n \"\"\"\n words = sentence.split()\n return [word for word in words if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n \"\"\"\n This function returns a list of words from a sentence that are longer than n characters.\n\n Args:\n n: The minimum length of words to include in the list.\n sentence: A string containing a sentence.\n\n Returns:\n A list of words longer than n characters.\n \"\"\"\n words = sentence.split()\n long_words = [word for word in words if len(word) > n]\n return long_words", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n \"\"\"\n Finds words longer than n characters from a given sentence.\n\n Args:\n n: The minimum length of words to return.\n sentence: A string containing the sentence to process.\n\n Returns:\n A list of words from the sentence that are longer than n characters.\n \"\"\"\n words = sentence.split()\n return [word for word in words if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n \"\"\"\n This function finds words that are longer than n characters from a given list of words.\n\n Args:\n n: The minimum length of words to be included in the result.\n sentence: A string containing words separated by spaces.\n\n Returns:\n A list of words longer than n characters from the given sentence.\n \"\"\"\n words = sentence.split()\n return [word for word in words if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n \"\"\"\n Finds words longer than n characters in a sentence.\n\n Args:\n n: The minimum length of the words to be returned.\n sentence: The sentence to extract words from.\n\n Returns:\n A list of words longer than n characters.\n \"\"\"\n words = sentence.split()\n return [word for word in words if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n \"\"\"\n Finds words longer than n characters from a given sentence.\n\n Args:\n n: The minimum length of words to include.\n sentence: A string containing words separated by spaces.\n\n Returns:\n A list of words longer than n characters.\n \"\"\"\n words = sentence.split()\n return [word for word in words if len(word) > n]", "matching_cluster_idx": 3}]}, "Mbpp/129": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def magic_square_test(matrix):\n \"\"\"\n Determines if a given matrix is a magic square.\n\n A magic square is a square matrix where the sum of the numbers in each row, \n column, and diagonal is the same.\n\n Args:\n matrix: A list of lists representing the square matrix.\n\n Returns:\n True if the matrix is a magic square, False otherwise.\n \"\"\"\n n = len(matrix)\n target_sum = sum(matrix[0]) # Calculate the target sum using the first row\n\n # Check rows\n for row in matrix:\n if sum(row) != target_sum:\n return False\n\n # Check columns\n for col in range(n):\n column_sum = 0\n for row in range(n):\n column_sum += matrix[row][col]\n if column_sum != target_sum:\n return False\n\n # Check diagonals\n diagonal1_sum = 0\n diagonal2_sum = 0\n for i in range(n):\n diagonal1_sum += matrix[i][i]\n diagonal2_sum += matrix[i][n - i - 1]\n\n if diagonal1_sum != target_sum or diagonal2_sum != target_sum:\n return False\n\n return True # All checks passed\nmatrix = [[7, 12, 1, 14], [2, 13, 8, 11], [16, 3, 10, 5], [9, 6, 15, 4]]", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n \"\"\"\n Checks if a given matrix is a magic square.\n\n A magic square is a square matrix where the sum of the elements in each row,\n each column, and both diagonals is the same.\n\n Args:\n matrix: A list of lists representing a square matrix.\n\n Returns:\n True if the matrix is a magic square, False otherwise.\n \"\"\"\n\n n = len(matrix) # Dimension of the square matrix\n\n # Calculate the expected magic constant\n magic_constant = sum(matrix[0])\n\n # Check rows\n for row in matrix:\n if sum(row) != magic_constant:\n return False\n\n # Check columns\n for col in range(n):\n if sum(matrix[row][col] for row in range(n)) != magic_constant:\n return False\n\n # Check diagonals\n if sum(matrix[i][i] for i in range(n)) != magic_constant:\n return False\n if sum(matrix[i][n - i - 1] for i in range(n)) != magic_constant:\n return False\n\n # If all checks pass, it's a magic square\n return True\nmatrix = [[7, 12, 1, 14], [2, 13, 8, 11], [16, 3, 10, 5], [9, 6, 15, 4]]", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n \"\"\"\n Checks if a given matrix is a magic square.\n\n Args:\n matrix: A list of lists representing the matrix.\n\n Returns:\n True if the matrix is a magic square, False otherwise.\n \"\"\"\n n = len(matrix)\n\n # Calculate the expected magic constant\n magic_constant = sum(matrix[0])\n\n # Check rows\n for row in matrix:\n if sum(row) != magic_constant:\n return False\n\n # Check columns\n for col in range(n):\n if sum([matrix[row][col] for row in range(n)]) != magic_constant:\n return False\n\n # Check diagonals\n if sum([matrix[i][i] for i in range(n)]) != magic_constant:\n return False\n if sum([matrix[i][n - i - 1] for i in range(n)]) != magic_constant:\n return False\n\n return True\nmatrix = [[7, 12, 1, 14], [2, 13, 8, 11], [16, 3, 10, 5], [9, 6, 15, 4]]", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n \"\"\"\n Checks if a given matrix is a magic square.\n\n A magic square is a square matrix where the sum of the numbers in each row,\n each column, and both diagonals is the same.\n\n Args:\n matrix: A list of lists representing the square matrix.\n\n Returns:\n True if the matrix is a magic square, False otherwise.\n \"\"\"\n\n n = len(matrix) \n magic_sum = sum(matrix[0]) \n\n # Check rows\n for row in matrix:\n if sum(row) != magic_sum:\n return False\n\n # Check columns\n for col in range(n):\n column_sum = 0\n for row in range(n):\n column_sum += matrix[row][col]\n if column_sum != magic_sum:\n return False\n\n # Check diagonals\n diagonal1_sum = 0\n diagonal2_sum = 0\n for i in range(n):\n diagonal1_sum += matrix[i][i]\n diagonal2_sum += matrix[i][n - i - 1]\n\n if diagonal1_sum != magic_sum or diagonal2_sum != magic_sum:\n return False\n\n return True\nmatrix = [[7, 12, 1, 14], [2, 13, 8, 11], [16, 3, 10, 5], [9, 6, 15, 4]]", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n \"\"\"\n Checks if a given matrix is a magic square.\n\n Args:\n matrix: A list of lists representing the square matrix.\n\n Returns:\n True if the matrix is a magic square, False otherwise.\n \"\"\"\n\n n = len(matrix)\n \n # Calculate the expected sum of each row, column, and diagonal\n magic_sum = sum(matrix[0])\n\n # Check rows\n for row in matrix:\n if sum(row) != magic_sum:\n return False\n\n # Check columns\n for col in range(n):\n col_sum = sum([matrix[row][col] for row in range(n)])\n if col_sum != magic_sum:\n return False\n\n # Check diagonals\n main_diagonal_sum = sum([matrix[i][i] for i in range(n)])\n anti_diagonal_sum = sum([matrix[i][n-i-1] for i in range(n)])\n if main_diagonal_sum != magic_sum or anti_diagonal_sum != magic_sum:\n return False\n\n return True\nmatrix = [[7, 12, 1, 14], [2, 13, 8, 11], [16, 3, 10, 5], [9, 6, 15, 4]]", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n \"\"\"\n Checks if a given matrix is a magic square.\n\n Args:\n matrix: A list of lists representing a square matrix.\n\n Returns:\n True if the matrix is a magic square, False otherwise.\n \"\"\"\n n = len(matrix)\n\n # Calculate the expected magic constant\n magic_constant = sum(matrix[0])\n\n # Check rows\n for row in matrix:\n if sum(row) != magic_constant:\n return False\n\n # Check columns\n for col in range(n):\n column_sum = sum(matrix[row][col] for row in range(n))\n if column_sum != magic_constant:\n return False\n\n # Check diagonals\n diagonal_sum1 = sum(matrix[i][i] for i in range(n))\n diagonal_sum2 = sum(matrix[i][n-i-1] for i in range(n))\n if diagonal_sum1 != magic_constant or diagonal_sum2 != magic_constant:\n return False\n\n return True\nmatrix = [[7, 12, 1, 14], [2, 13, 8, 11], [16, 3, 10, 5], [9, 6, 15, 4]]", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n \"\"\"\n This function determines if a given matrix is a magic square.\n\n Args:\n matrix: A list of lists representing the matrix.\n\n Returns:\n True if the matrix is a magic square, False otherwise.\n \"\"\"\n\n n = len(matrix)\n # Calculate the expected magic sum\n magic_sum = sum(matrix[0]) \n\n # Check rows\n for row in matrix:\n if sum(row) != magic_sum:\n return False\n\n # Check columns\n for col in range(n):\n column_sum = 0\n for row in range(n):\n column_sum += matrix[row][col]\n if column_sum != magic_sum:\n return False\n\n # Check diagonals\n primary_diagonal_sum = 0\n secondary_diagonal_sum = 0\n for i in range(n):\n primary_diagonal_sum += matrix[i][i]\n secondary_diagonal_sum += matrix[i][n-i-1]\n\n if primary_diagonal_sum != magic_sum or secondary_diagonal_sum != magic_sum:\n return False\n\n return True\nmatrix = [[7, 12, 1, 14], [2, 13, 8, 11], [16, 3, 10, 5], [9, 6, 15, 4]]", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n \"\"\"\n Checks if a given matrix is a magic square.\n\n Args:\n matrix: A list of lists representing the square matrix.\n\n Returns:\n True if the matrix is a magic square, False otherwise.\n \"\"\"\n n = len(matrix)\n target_sum = sum(matrix[0]) \n\n # Check row sums\n for row in matrix:\n if sum(row) != target_sum:\n return False\n\n # Check column sums\n for col in range(n):\n col_sum = 0\n for row in range(n):\n col_sum += matrix[row][col]\n if col_sum != target_sum:\n return False\n\n # Check diagonals\n diag_sum1 = 0\n diag_sum2 = 0\n for i in range(n):\n diag_sum1 += matrix[i][i]\n diag_sum2 += matrix[i][n - i - 1]\n\n if diag_sum1 != target_sum or diag_sum2 != target_sum:\n return False\n\n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n \"\"\"\n Checks if a given matrix is a magic square.\n\n A magic square is a square matrix where the sum of the elements in each row,\n each column, and both diagonals are equal.\n\n Args:\n matrix: A list of lists representing the matrix.\n\n Returns:\n True if the matrix is a magic square, False otherwise.\n \"\"\"\n\n n = len(matrix)\n target_sum = sum(matrix[0]) # Calculate the target sum from the first row\n\n # Check rows\n for row in matrix:\n if sum(row) != target_sum:\n return False\n\n # Check columns\n for col in range(n):\n column_sum = sum([matrix[row][col] for row in range(n)])\n if column_sum != target_sum:\n return False\n\n # Check diagonals\n diagonal1_sum = sum([matrix[i][i] for i in range(n)])\n diagonal2_sum = sum([matrix[i][n - i - 1] for i in range(n)])\n if diagonal1_sum != target_sum or diagonal2_sum != target_sum:\n return False\n\n return True\nmatrix = [[7, 12, 1, 14], [2, 13, 8, 11], [16, 3, 10, 5], [9, 6, 15, 4]]", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n \"\"\"\n Determines if a given matrix is a magic square.\n\n A magic square is a square matrix where the sum of the elements in each row,\n each column, and both diagonals is the same.\n\n Args:\n matrix: A list of lists representing a square matrix.\n\n Returns:\n True if the matrix is a magic square, False otherwise.\n \"\"\"\n\n n = len(matrix)\n target_sum = sum(matrix[0]) # Calculate the sum of the first row\n \n # Check rows\n for row in matrix:\n if sum(row) != target_sum:\n return False\n\n # Check columns\n for col in range(n):\n col_sum = sum(matrix[row][col] for row in range(n))\n if col_sum != target_sum:\n return False\n\n # Check diagonals\n diagonal_sum1 = sum(matrix[i][i] for i in range(n))\n diagonal_sum2 = sum(matrix[i][n - i - 1] for i in range(n))\n if diagonal_sum1 != target_sum or diagonal_sum2 != target_sum:\n return False\n\n return True\nmatrix = [[7, 12, 1, 14], [2, 13, 8, 11], [16, 3, 10, 5], [9, 6, 15, 4]]", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n \"\"\"\n Checks if a given matrix is a magic square.\n\n A magic square is a square matrix where the sum of the numbers in each row,\n each column, and both diagonals is the same.\n\n Args:\n matrix: A list of lists representing the square matrix.\n\n Returns:\n True if the matrix is a magic square, False otherwise.\n \"\"\"\n\n n = len(matrix)\n magic_sum = sum(matrix[0])\n\n # Check rows\n for row in matrix:\n if sum(row) != magic_sum:\n return False\n\n # Check columns\n for col in range(n):\n column_sum = 0\n for row in range(n):\n column_sum += matrix[row][col]\n if column_sum != magic_sum:\n return False\n\n # Check diagonals\n diagonal1_sum = sum(matrix[i][i] for i in range(n))\n diagonal2_sum = sum(matrix[i][n-i-1] for i in range(n))\n if diagonal1_sum != magic_sum or diagonal2_sum != magic_sum:\n return False\n\n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n \"\"\"\n Determines if a given matrix is a magic square.\n\n Args:\n matrix: A list of lists representing the matrix.\n\n Returns:\n True if the matrix is a magic square, False otherwise.\n \"\"\"\n n = len(matrix)\n target_sum = sum(matrix[0]) # Calculate the expected sum of each row/column/diagonal\n\n # Check rows\n for row in matrix:\n if sum(row) != target_sum:\n return False\n\n # Check columns\n for col in range(n):\n column_sum = sum(matrix[row][col] for row in range(n))\n if column_sum != target_sum:\n return False\n\n # Check diagonals\n diagonal1_sum = sum(matrix[i][i] for i in range(n))\n diagonal2_sum = sum(matrix[i][n - i - 1] for i in range(n))\n if diagonal1_sum != target_sum or diagonal2_sum != target_sum:\n return False\n\n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n \"\"\"\n Write a function to calculate whether the matrix is a magic square.\n\n Args:\n matrix: A list of lists representing a square matrix.\n\n Returns:\n True if the matrix is a magic square, False otherwise.\n \"\"\"\n n = len(matrix)\n\n # Calculate the expected magic constant\n magic_constant = sum(matrix[0])\n\n # Check rows\n for row in matrix:\n if sum(row) != magic_constant:\n return False\n\n # Check columns\n for col in range(n):\n column_sum = sum([matrix[row][col] for row in range(n)])\n if column_sum != magic_constant:\n return False\n\n # Check diagonals\n diagonal1_sum = sum([matrix[i][i] for i in range(n)])\n diagonal2_sum = sum([matrix[i][n - 1 - i] for i in range(n)])\n\n if diagonal1_sum != magic_constant or diagonal2_sum != magic_constant:\n return False\n\n return True\nmatrix = [[7, 12, 1, 14], [2, 13, 8, 11], [16, 3, 10, 5], [9, 6, 15, 4]]", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n \"\"\"\n Checks if a given matrix is a magic square.\n\n A magic square is a square matrix where the sum of the elements in each row, column, and diagonal is the same.\n\n Args:\n matrix: A list of lists representing the square matrix.\n\n Returns:\n True if the matrix is a magic square, False otherwise.\n \"\"\"\n n = len(matrix)\n magic_sum = sum(matrix[0])\n\n # Check rows\n for row in matrix:\n if sum(row) != magic_sum:\n return False\n\n # Check columns\n for col in range(n):\n col_sum = 0\n for row in range(n):\n col_sum += matrix[row][col]\n if col_sum != magic_sum:\n return False\n\n # Check diagonals\n diag1_sum = 0\n diag2_sum = 0\n for i in range(n):\n diag1_sum += matrix[i][i]\n diag2_sum += matrix[i][n-i-1]\n if diag1_sum != magic_sum or diag2_sum != magic_sum:\n return False\n\n return True\nmatrix = [[7, 12, 1, 14], [2, 13, 8, 11], [16, 3, 10, 5], [9, 6, 15, 4]]", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n \"\"\"\n Checks if a given square matrix is a magic square.\n\n A magic square is a square matrix where the sum of the numbers in each row,\n column, and diagonal is the same.\n\n Args:\n matrix: A list of lists representing a square matrix.\n\n Returns:\n True if the matrix is a magic square, False otherwise.\n \"\"\"\n\n n = len(matrix)\n target_sum = sum(matrix[0]) # Sum of elements in the first row\n\n # Check rows\n for row in matrix:\n if sum(row) != target_sum:\n return False\n\n # Check columns\n for col in range(n):\n column_sum = sum(matrix[row][col] for row in range(n))\n if column_sum != target_sum:\n return False\n\n # Check diagonals\n diagonal_sum1 = sum(matrix[i][i] for i in range(n))\n diagonal_sum2 = sum(matrix[i][n - i - 1] for i in range(n))\n\n if diagonal_sum1 != target_sum or diagonal_sum2 != target_sum:\n return False\n\n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n \"\"\"\n Checks if a given matrix is a magic square.\n\n A magic square is a square matrix where the sum of the numbers in each row,\n each column, and both diagonals is the same.\n\n Args:\n matrix: A list of lists representing the matrix.\n\n Returns:\n True if the matrix is a magic square, False otherwise.\n \"\"\"\n\n n = len(matrix)\n target_sum = sum(matrix[0]) # Sum of elements in the first row\n\n # Check rows\n for row in matrix:\n if sum(row) != target_sum:\n return False\n\n # Check columns\n for col in range(n):\n col_sum = 0\n for row in range(n):\n col_sum += matrix[row][col]\n if col_sum != target_sum:\n return False\n\n # Check diagonals\n diag1_sum = sum(matrix[i][i] for i in range(n))\n diag2_sum = sum(matrix[i][n - 1 - i] for i in range(n))\n if diag1_sum != target_sum or diag2_sum != target_sum:\n return False\n\n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n \"\"\"\n Checks if a given matrix is a magic square.\n\n Args:\n matrix: A list of lists representing a square matrix.\n\n Returns:\n True if the matrix is a magic square, False otherwise.\n \"\"\"\n\n n = len(matrix)\n target_sum = sum(matrix[0]) # Calculate expected sum from first row\n\n # Check row sums\n for row in matrix:\n if sum(row) != target_sum:\n return False\n\n # Check column sums\n for col in range(n):\n col_sum = sum(matrix[i][col] for i in range(n))\n if col_sum != target_sum:\n return False\n\n # Check diagonal sums\n diagonal_sum1 = sum(matrix[i][i] for i in range(n))\n diagonal_sum2 = sum(matrix[i][n - i - 1] for i in range(n))\n if diagonal_sum1 != target_sum or diagonal_sum2 != target_sum:\n return False\n\n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n \"\"\"\n Determines if a given square matrix is a magic square.\n\n Args:\n matrix: A list of lists representing a square matrix.\n\n Returns:\n True if the matrix is a magic square, False otherwise.\n \"\"\"\n n = len(matrix)\n target_sum = sum(matrix[0]) # Sum of elements in the first row\n\n # Check rows\n for row in matrix:\n if sum(row) != target_sum:\n return False\n\n # Check columns\n for col in range(n):\n column_sum = sum(matrix[row][col] for row in range(n))\n if column_sum != target_sum:\n return False\n\n # Check diagonals\n diagonal1_sum = sum(matrix[i][i] for i in range(n))\n diagonal2_sum = sum(matrix[i][n - i - 1] for i in range(n))\n if diagonal1_sum != target_sum or diagonal2_sum != target_sum:\n return False\n\n return True\nmatrix = [[7, 12, 1, 14], [2, 13, 8, 11], [16, 3, 10, 5], [9, 6, 15, 4]]", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n \"\"\"\n Checks if a given matrix is a magic square.\n\n Args:\n matrix: A list of lists representing a square matrix.\n\n Returns:\n True if the matrix is a magic square, False otherwise.\n \"\"\"\n\n n = len(matrix)\n magic_sum = sum(matrix[0]) \n\n # Check rows\n for row in matrix:\n if sum(row) != magic_sum:\n return False\n\n # Check columns\n for col in range(n):\n column_sum = 0\n for row in range(n):\n column_sum += matrix[row][col]\n if column_sum != magic_sum:\n return False\n\n # Check diagonals\n diagonal_sum1 = 0\n diagonal_sum2 = 0\n for i in range(n):\n diagonal_sum1 += matrix[i][i]\n diagonal_sum2 += matrix[i][n-i-1]\n if diagonal_sum1 != magic_sum or diagonal_sum2 != magic_sum:\n return False\n\n return True\nmatrix = [[7, 12, 1, 14], [2, 13, 8, 11], [16, 3, 10, 5], [9, 6, 15, 4]]", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n \"\"\"\n Checks if a given matrix is a magic square.\n\n A magic square is a square matrix where the sum of the elements in each row, \n each column, and both diagonals is the same.\n\n Args:\n matrix: A list of lists representing a square matrix.\n\n Returns:\n True if the matrix is a magic square, False otherwise.\n \"\"\"\n n = len(matrix)\n target_sum = sum(matrix[0]) # Calculate the expected sum\n\n # Check rows\n for row in matrix:\n if sum(row) != target_sum:\n return False\n\n # Check columns\n for col in range(n):\n if sum(matrix[i][col] for i in range(n)) != target_sum:\n return False\n\n # Check diagonals\n primary_diagonal = sum(matrix[i][i] for i in range(n))\n secondary_diagonal = sum(matrix[i][n-i-1] for i in range(n))\n if primary_diagonal != target_sum or secondary_diagonal != target_sum:\n return False\n\n return True\nmatrix = [[7, 12, 1, 14], [2, 13, 8, 11], [16, 3, 10, 5], [9, 6, 15, 4]]", "matching_cluster_idx": 14}]}, "Mbpp/130": {"dps": 94.2152466367713, "dps_norm": 80.0, "pass@1": 100.0, "profiled": [{"solution": "from collections import Counter\ndef max_occurrences(nums):\n \"\"\"\n Finds the item with maximum frequency in a given list.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n The item with maximum frequency. If multiple items have the same maximum frequency,\n returns any one of them.\n \"\"\"\n\n counts = Counter(nums)\n return counts.most_common(1)[0][0]", "matching_cluster_idx": 4}, {"solution": "from collections import Counter\ndef max_occurrences(nums):\n \"\"\"Finds the item with the maximum frequency in a given list.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n The item with the maximum frequency in the list.\n \"\"\"\n counts = Counter(nums)\n return counts.most_common(1)[0][0]", "matching_cluster_idx": 4}, {"solution": "from collections import Counter\ndef max_occurrences(nums):\n \"\"\"\n Finds the item with maximum frequency in a given list.\n\n Args:\n nums: A list of integers.\n\n Returns:\n The item with the maximum frequency in the list.\n\n Raises:\n ValueError: If the input list is empty.\n \"\"\"\n if not nums:\n raise ValueError(\"Input list cannot be empty.\")\n\n counts = Counter(nums) \n return counts.most_common(1)[0][0]", "matching_cluster_idx": 4}, {"solution": "from collections import Counter\ndef max_occurrences(lst):\n \"\"\"\n Find the item with maximum frequency in a given list.\n\n Args:\n lst: A list of integers.\n\n Returns:\n The item with maximum frequency in the list.\n \"\"\"\n return Counter(lst).most_common(1)[0][0]", "matching_cluster_idx": 4}, {"solution": "from collections import Counter\ndef max_occurrences(nums):\n \"\"\"\n Finds the item with maximum frequency in a given list.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n The item with the maximum frequency in the list.\n \"\"\"\n counts = Counter(nums)\n return counts.most_common(1)[0][0]", "matching_cluster_idx": 4}, {"solution": "def max_occurrences(data):\n \"\"\"\n Finds the item with maximum frequency in a given list.\n\n Args:\n data: A list of elements.\n\n Returns:\n The item with the maximum frequency in the list.\n \"\"\"\n\n counts = {}\n for item in data:\n if item in counts:\n counts[item] += 1\n else:\n counts[item] = 1\n\n max_item = None\n max_count = 0\n for item, count in counts.items():\n if count > max_count:\n max_item = item\n max_count = count\n\n return max_item", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(numbers):\n \"\"\"\n Finds the item with maximum frequency in a given list.\n Args:\n numbers: A list of integers.\n Returns:\n The item with the maximum frequency.\n \"\"\"\n counts = {}\n for number in numbers:\n if number in counts:\n counts[number] += 1\n else:\n counts[number] = 1\n\n max_count = 0\n max_item = None\n for number, count in counts.items():\n if count > max_count:\n max_count = count\n max_item = number\n return max_item", "matching_cluster_idx": 3}, {"solution": "from collections import Counter\ndef max_occurrences(nums):\n \"\"\"\n Find the item with maximum frequency in a given list.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n The item with the maximum frequency in the list.\n \"\"\"\n counts = Counter(nums)\n return counts.most_common(1)[0][0]", "matching_cluster_idx": 4}, {"solution": "from collections import Counter\ndef max_occurrences(nums):\n \"\"\"\n Finds the item with maximum frequency in a given list.\n\n Args:\n nums: A list of integers.\n\n Returns:\n The item with the maximum frequency in the list.\n \"\"\"\n return Counter(nums).most_common(1)[0][0]", "matching_cluster_idx": 4}, {"solution": "from collections import Counter\ndef max_occurrences(data):\n \"\"\"\n Finds the item with maximum frequency in a given list.\n\n Args:\n data: A list of items.\n\n Returns:\n The item with the maximum frequency in the list.\n \"\"\"\n counts = Counter(data)\n return counts.most_common(1)[0][0]", "matching_cluster_idx": 4}, {"solution": "from collections import Counter\ndef max_occurrences(nums):\n \"\"\"Finds the item with maximum frequency in a given list.\n\n Args:\n nums: A list of integers.\n\n Returns:\n The integer with the highest frequency in the list.\n \"\"\"\n counts = Counter(nums)\n return counts.most_common(1)[0][0]", "matching_cluster_idx": 4}, {"solution": "from collections import Counter\ndef max_occurrences(numbers):\n \"\"\"\n Finds the item with maximum frequency in a given list.\n\n Args:\n numbers: A list of numbers.\n\n Returns:\n The item with the highest frequency in the list.\n \"\"\"\n return Counter(numbers).most_common(1)[0][0]", "matching_cluster_idx": 4}, {"solution": "def max_occurrences(lst):\n \"\"\"\n Finds the item with maximum frequency in a given list.\n\n Args:\n lst: A list of integers.\n\n Returns:\n The item with the maximum frequency in the list.\n \"\"\"\n\n counts = {}\n for item in lst:\n if item in counts:\n counts[item] += 1\n else:\n counts[item] = 1\n\n max_item = None\n max_count = 0\n for item, count in counts.items():\n if count > max_count:\n max_item = item\n max_count = count\n\n return max_item", "matching_cluster_idx": 3}, {"solution": "from collections import Counter\ndef max_occurrences(numbers):\n \"\"\"Finds the item with maximum frequency in a given list.\n\n Args:\n numbers: A list of numbers.\n\n Returns:\n The item with the maximum frequency in the list.\n \"\"\"\n return Counter(numbers).most_common(1)[0][0]", "matching_cluster_idx": 4}, {"solution": "from collections import Counter\ndef max_occurrences(nums):\n \"\"\"\n Finds the item with maximum frequency in a given list.\n\n Args:\n nums: A list of integers.\n\n Returns:\n The item with maximum frequency.\n \"\"\"\n return Counter(nums).most_common(1)[0][0]", "matching_cluster_idx": 4}, {"solution": "from collections import Counter\ndef max_occurrences(nums):\n \"\"\"\n Find the item with maximum frequency in a given list.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n The item with the maximum frequency.\n \"\"\"\n counts = Counter(nums)\n return counts.most_common(1)[0][0]", "matching_cluster_idx": 4}, {"solution": "from collections import Counter\ndef max_occurrences(nums):\n \"\"\"\n Finds the item with maximum frequency in a given list.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n The item with the highest frequency in the list.\n \"\"\"\n counts = Counter(nums)\n return counts.most_common(1)[0][0]", "matching_cluster_idx": 4}, {"solution": "from collections import Counter\ndef max_occurrences(data):\n \"\"\"\n Finds the item with maximum frequency in a given list.\n\n Args:\n data: A list of items.\n\n Returns:\n The item with the highest frequency in the list.\n \"\"\"\n counts = Counter(data)\n return counts.most_common(1)[0][0]", "matching_cluster_idx": 4}, {"solution": "def max_occurrences(nums):\n \"\"\"\n Finds the item with maximum frequency in a given list.\n\n Args:\n nums: A list of integers.\n\n Returns:\n The item with the maximum frequency in the list.\n \"\"\"\n counts = {} # Use a dictionary to store the frequency of each item.\n\n for num in nums:\n if num in counts:\n counts[num] += 1\n else:\n counts[num] = 1\n\n max_count = 0\n max_item = None\n for num, count in counts.items():\n if count > max_count:\n max_count = count\n max_item = num\n\n return max_item", "matching_cluster_idx": 3}, {"solution": "from collections import Counter\ndef max_occurrences(nums):\n \"\"\"\n Find the item with maximum frequency in a given list.\n\n Args:\n nums: A list of integers.\n\n Returns:\n The item with the highest frequency in the list.\n \"\"\"\n\n counts = Counter(nums)\n return counts.most_common(1)[0][0]", "matching_cluster_idx": 4}]}, "Mbpp/137": {"dps": null, "dps_norm": null, "pass@1": 3.0, "profiled": []}, "Mbpp/140": {"dps": 80.1086956521739, "dps_norm": 74.375, "pass@1": 100.0, "profiled": [{"solution": "def extract_singly(list_of_lists):\n \"\"\"\n Flattens a list of lists into a single set of numbers.\n\n Args:\n list_of_lists: A list of lists, where each inner list contains numbers.\n\n Returns:\n A set containing all the numbers from the input list of lists.\n \"\"\"\n\n return set([number for sublist in list_of_lists for number in sublist])", "matching_cluster_idx": 5}, {"solution": "def extract_singly(nested_list):\n \"\"\"\n Flattens a list of lists into a single set of numbers.\n\n Args:\n nested_list: A list of lists containing numbers.\n\n Returns:\n A set containing all unique numbers from the nested lists.\n \"\"\"\n return set([number for sublist in nested_list for number in sublist])", "matching_cluster_idx": 5}, {"solution": "def extract_singly(list_of_lists):\n \"\"\"\n Flattens a list of lists into a single set of numbers.\n\n Args:\n list_of_lists: A list of lists containing numbers.\n\n Returns:\n A set containing all the numbers from the input lists.\n \"\"\"\n return set([number for sublist in list_of_lists for number in sublist])", "matching_cluster_idx": 5}, {"solution": "def extract_singly(nested_list):\n \"\"\"\n Flattens a list of lists into a single set of numbers.\n\n Args:\n nested_list: A list of lists containing numbers.\n\n Returns:\n A set containing all unique numbers from the input list of lists.\n \"\"\"\n return set([num for sublist in nested_list for num in sublist])", "matching_cluster_idx": 5}, {"solution": "def extract_singly(list_of_lists):\n \"\"\"\n Flattens a list of lists into a single set of numbers.\n\n Args:\n list_of_lists: A list of lists containing numbers.\n\n Returns:\n A set containing all unique numbers from the input list of lists.\n \"\"\"\n return set([num for sublist in list_of_lists for num in sublist])", "matching_cluster_idx": 5}, {"solution": "def extract_singly(list_of_lists):\n \"\"\"\n Flattens a list of lists into a single set of numbers.\n\n Args:\n list_of_lists: A list of lists containing numbers.\n\n Returns:\n A set of all the numbers in the input list of lists.\n \"\"\"\n\n return set([num for sublist in list_of_lists for num in sublist])", "matching_cluster_idx": 5}, {"solution": "def extract_singly(list_of_lists):\n \"\"\"\n Flattens a list of lists into a single set of numbers.\n\n Args:\n list_of_lists: A list of lists of numbers.\n\n Returns:\n A set of numbers containing all the numbers from all the lists.\n \"\"\"\n return set([number for sublist in list_of_lists for number in sublist])", "matching_cluster_idx": 5}, {"solution": "def extract_singly(list_of_lists):\n \"\"\"\n Flattens a list of lists into a single set of numbers.\n \n Args:\n list_of_lists: A list of lists containing numbers.\n\n Returns:\n A set containing all the unique numbers from the input lists.\n \"\"\"\n return set([number for sublist in list_of_lists for number in sublist])", "matching_cluster_idx": 5}, {"solution": "def extract_singly(lst):\n \"\"\"\n Flatten a list of lists into a single set of numbers.\n \"\"\"\n return set([num for sublist in lst for num in sublist])", "matching_cluster_idx": 5}, {"solution": "def extract_singly(lst):\n \"\"\"\n Extracts all numbers from a list of lists into a single set.\n\n Args:\n lst: A list of lists containing numbers.\n\n Returns:\n A set containing all the unique numbers from the input list.\n \"\"\"\n return set([number for sublist in lst for number in sublist])", "matching_cluster_idx": 5}, {"solution": "from typing import List, Tuple, Set\ndef extract_singly(list_of_lists: List[Tuple[int, int, int]]) -> Set[int]:\n \"\"\"\n This function takes a list of tuples containing integers and returns a set of all unique integers from the tuples.\n\n Args:\n list_of_lists: A list of tuples, where each tuple contains three integers.\n\n Returns:\n A set of all unique integers found within the tuples.\n \"\"\"\n return set([num for tup in list_of_lists for num in tup])", "matching_cluster_idx": 5}, {"solution": "from typing import List, Set\ndef extract_singly(nested_list: List[tuple]) -> Set[int]:\n \"\"\"\n Flattens a list of lists into a single set of numbers.\n Args:\n nested_list: A list of lists of numbers.\n\n Returns:\n A set containing all unique numbers from the input list.\n \"\"\"\n extracted_numbers = set()\n for sublist in nested_list:\n for number in sublist:\n extracted_numbers.add(number)\n return extracted_numbers", "matching_cluster_idx": 4}, {"solution": "from typing import List, Set\ndef extract_singly(list_of_lists: List[tuple]) -> Set[int]:\n \"\"\"\n Write a function to flatten the list of lists into a single set of numbers.\n assert set(extract_singly([(3, 4, 5), (4, 5, 7), (1, 4)])) == set([3, 4, 5, 7, 1])\n \"\"\"\n return set([num for sublist in list_of_lists for num in sublist])", "matching_cluster_idx": 5}, {"solution": "def extract_singly(lists):\n \"\"\"\n Flattens a list of lists into a single set of numbers.\n\n Args:\n lists: A list of lists containing numbers.\n\n Returns:\n A set containing all the numbers from the input lists, without duplicates.\n \"\"\"\n return set([number for sublist in lists for number in sublist])", "matching_cluster_idx": 5}, {"solution": "def extract_singly(lst):\n \"\"\"Flattens a list of lists into a single set of numbers.\n \"\"\"\n return set([num for sublist in lst for num in sublist])", "matching_cluster_idx": 5}, {"solution": "def extract_singly(nested_list):\n \"\"\"\n Write a function to flatten the list of lists into a single set of numbers.\n\n assert set(extract_singly([(3, 4, 5), (4, 5, 7), (1, 4)])) == set([3, 4, 5, 7, 1])\n \"\"\"\n return set([num for sublist in nested_list for num in sublist])\nnested_list = [(3, 4, 5), (4, 5, 7), (1, 4)]", "matching_cluster_idx": 5}, {"solution": "def extract_singly(nested_list):\n \"\"\"\n Write a function to flatten the list of lists into a single set of numbers.\n\n assert set(extract_singly([(3, 4, 5), (4, 5, 7), (1, 4)])) == set([3, 4, 5, 7, 1])\n\n \"\"\"\n return set([num for sublist in nested_list for num in sublist])", "matching_cluster_idx": 5}, {"solution": "def extract_singly(list_of_lists):\n \"\"\"\n Flattens a list of lists into a single set of numbers.\n\n Args:\n list_of_lists: A list of lists of numbers.\n\n Returns:\n A set containing all the numbers from the input list of lists.\n \"\"\"\n return set([num for sublist in list_of_lists for num in sublist])", "matching_cluster_idx": 5}, {"solution": "def extract_singly(lists_of_lists):\n \"\"\"\n This function flattens a list of lists into a single set of numbers.\n\n Args:\n lists_of_lists: A list of lists containing numbers.\n\n Returns:\n A set of all numbers found in the input list of lists.\n \"\"\"\n\n return set([number for sublist in lists_of_lists for number in sublist])", "matching_cluster_idx": 5}, {"solution": "def extract_singly(list_of_lists):\n \"\"\"\n Flattens a list of lists into a single set of numbers.\n\n Args:\n list_of_lists: A list of lists containing numbers.\n\n Returns:\n A set of unique numbers from all the sublists.\n \"\"\"\n return set([number for sublist in list_of_lists for number in sublist])", "matching_cluster_idx": 5}]}, "Mbpp/141": {"dps": 98.41269841269842, "dps_norm": 50.0, "pass@1": 90.0, "profiled": [{"solution": "def pancake_sort(arr):\n \"\"\"Sorts a list of elements using the Pancake Sort algorithm.\n\n Args:\n arr: The list to be sorted.\n\n Returns:\n The sorted list.\n \"\"\"\n n = len(arr)\n for i in range(n - 1, 0, -1):\n # Find the index of the maximum element in the unsorted part of the list\n max_index = arr.index(max(arr[:i + 1]))\n\n # If the maximum element is not already in the correct position\n if max_index != i:\n # Flip the list from 0 to max_index\n arr[:max_index + 1] = arr[:max_index + 1][::-1]\n # Flip the list from 0 to i\n arr[:i + 1] = arr[:i + 1][::-1]\n\n return arr", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(arr):\n \"\"\"\n Sorts a list using the pancake sort algorithm.\n\n Args:\n arr: The list to be sorted.\n\n Returns:\n The sorted list.\n \"\"\"\n n = len(arr)\n for i in range(n - 1, 0, -1):\n max_index = arr.index(max(arr[:i+1]))\n if max_index != i:\n arr[:max_index+1] = reversed(arr[:max_index+1]) # Flip to bring max to front\n arr[:i+1] = reversed(arr[:i+1]) # Flip to move max to its correct position\n\n return arr", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(arr):\n \"\"\"Sorts a list of elements using the Pancake Sort algorithm.\n\n Args:\n arr: A list of elements to sort.\n\n Returns:\n The sorted list.\n \"\"\"\n\n def flip(arr, k):\n \"\"\"Flips the sub-array from index 0 to k.\"\"\"\n return arr[:k+1][::-1] + arr[k+1:]\n\n n = len(arr)\n for i in range(n - 1, 0, -1):\n max_index = arr.index(max(arr[:i+1])) \n arr = flip(arr, max_index) \n arr = flip(arr, i)\n return arr", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(arr):\n \"\"\"\n Sorts a list of elements using the pancake sorting algorithm.\n\n Args:\n arr: A list of comparable elements.\n\n Returns:\n A new sorted list containing the same elements as arr.\n \"\"\"\n\n def flip(arr, k):\n \"\"\"Flips the first k elements of the list in place.\"\"\"\n return arr[:k][::-1] + arr[k:]\n\n n = len(arr)\n sorted_arr = arr.copy()\n for i in range(n - 1, 0, -1):\n # Find the index of the maximum element in the unsorted part of the list\n max_index = sorted_arr.index(max(sorted_arr[:i + 1]))\n \n # Move the maximum element to the beginning of the list\n if max_index != 0:\n sorted_arr = flip(sorted_arr, max_index + 1)\n # Move the maximum element to its correct position at the end\n sorted_arr = flip(sorted_arr, i + 1)\n return sorted_arr", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(arr):\n \"\"\"\n Sorts a list of elements using the pancake sort algorithm.\n\n Args:\n arr: The list to be sorted.\n\n Returns:\n The sorted list.\n \"\"\"\n n = len(arr)\n for i in range(n - 1, 0, -1):\n # Find the index of the maximum element in the unsorted subarray\n max_index = arr.index(max(arr[:i + 1]))\n\n # If the maximum element is not already at the end of the subarray\n if max_index != i:\n # Flip the subarray from 0 to max_index\n arr[:max_index + 1] = arr[:max_index + 1][::-1]\n\n # Flip the subarray from 0 to i\n arr[:i + 1] = arr[:i + 1][::-1]\n\n return arr", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(arr):\n \"\"\"\n Sorts a list of elements using the pancake sort algorithm.\n\n Args:\n arr: The list of elements to be sorted.\n\n Returns:\n The sorted list.\n \"\"\"\n\n n = len(arr)\n for i in range(n - 1, 0, -1):\n max_index = arr.index(max(arr[:i + 1]))\n # Flip to bring the maximum element to the beginning\n arr[:max_index + 1] = arr[:max_index + 1][::-1]\n # Flip the entire array to place the maximum element at its correct position\n arr[:i + 1] = arr[:i + 1][::-1]\n return arr", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(arr):\n \"\"\"\n Sorts a list using the pancake sorting algorithm.\n\n Args:\n arr: The list to sort.\n\n Returns:\n The sorted list.\n \"\"\"\n n = len(arr)\n\n for i in range(n):\n max_index = arr.index(max(arr[:n-i]))\n if max_index != n - i - 1:\n arr = arr[:max_index+1][::-1] + arr[max_index+1:]\n arr = arr[:n-i][::-1] + arr[n-i:]\n return arr", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(arr):\n \"\"\"\n Sorts a list of elements using the pancake sort algorithm.\n \n Args:\n arr: A list of elements to be sorted.\n\n Returns:\n A new list with the elements of arr sorted in ascending order.\n \"\"\"\n n = len(arr)\n for i in range(n):\n max_idx = arr.index(max(arr[:n-i])) # Find the index of the maximum element in the unsorted part\n \n # Flip to bring the maximum element to the beginning\n arr[:max_idx+1] = reversed(arr[:max_idx+1])\n \n # Flip to bring the maximum element to its correct position\n arr[:n-i] = reversed(arr[:n-i])\n\n return arr", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(arr):\n \"\"\"Sorts a list using the pancake sorting algorithm.\n\n Args:\n arr: The list to be sorted.\n\n Returns:\n The sorted list.\n \"\"\"\n n = len(arr)\n for i in range(n):\n max_index = arr.index(max(arr[:n - i]))\n if max_index != n - i - 1:\n arr[:max_index + 1] = arr[:max_index + 1][::-1]\n arr[:n - i] = arr[:n - i][::-1]\n return arr", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(arr):\n \"\"\"\n Sorts a list using the pancake sort algorithm.\n\n Args:\n arr: The list to be sorted.\n\n Returns:\n The sorted list.\n \"\"\"\n n = len(arr)\n for i in range(n - 1, 0, -1):\n # Find the index of the maximum element in the unsorted part of the array\n max_index = arr.index(max(arr[:i + 1]))\n\n # If the maximum element is not already in its correct position\n if max_index != i:\n # Flip the sub-array from 0 to max_index\n arr[:max_index + 1] = arr[:max_index + 1][::-1]\n # Flip the sub-array from 0 to i\n arr[:i + 1] = arr[:i + 1][::-1]\n return arr", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(arr):\n \"\"\"\n Sorts a list of elements using the pancake sort algorithm.\n\n Args:\n arr: A list of comparable elements.\n\n Returns:\n The sorted list.\n \"\"\"\n\n n = len(arr)\n for i in range(n - 1, 0, -1):\n # Find the index of the maximum element in the unsorted portion\n max_index = arr.index(max(arr[:i + 1]))\n\n # If the maximum element is not already at the end of the unsorted portion,\n # flip the sub-array from 0 to max_index\n if max_index != i:\n arr[:max_index + 1] = reversed(arr[:max_index + 1])\n # Flip the entire unsorted portion\n arr[:i + 1] = reversed(arr[:i + 1])\n\n return arr", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(arr):\n \"\"\"\n Sorts a list of elements using the pancake sort algorithm.\n\n Args:\n arr: A list of elements to be sorted.\n\n Returns:\n The sorted list.\n \"\"\"\n n = len(arr)\n for i in range(n - 1, 0, -1):\n # Find the index of the maximum element in the unsorted part\n max_index = arr.index(max(arr[:i + 1]))\n\n # If the maximum element is not already in the correct position\n if max_index != i:\n # Flip the subarray from 0 to max_index\n arr[:max_index + 1] = arr[:max_index + 1][::-1]\n\n # Flip the subarray from 0 to i\n arr[:i + 1] = arr[:i + 1][::-1]\n\n return arr\narr = [15, 79, 25, 38, 69]", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(arr):\n \"\"\"\n Sort a list of elements using the pancake sort algorithm.\n\n Args:\n arr: A list of elements to be sorted.\n\n Returns:\n The sorted list.\n \"\"\"\n n = len(arr)\n for i in range(n):\n # Find the index of the maximum element in the unsorted subarray\n max_index = arr.index(max(arr[:n-i]))\n\n # Flip the subarray from 0 to max_index\n arr[:max_index+1] = arr[:max_index+1][::-1]\n # Flip the subarray from 0 to n-i-1\n arr[:n-i] = arr[:n-i][::-1]\n return arr", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(arr):\n \"\"\"\n Sorts a list of elements using the pancake sort algorithm.\n\n Args:\n arr: A list of elements to be sorted.\n\n Returns:\n A sorted list of elements.\n \"\"\"\n\n n = len(arr)\n for i in range(n - 1, 0, -1):\n # Find the index of the maximum element in the unsorted part\n max_index = arr.index(max(arr[:i+1]))\n\n # Flip the list from 0 to max_index\n arr[:max_index+1] = arr[:max_index+1][::-1]\n \n # Flip the list from 0 to i\n arr[:i+1] = arr[:i+1][::-1]\n\n return arr", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(arr):\n \"\"\"Sorts a list using the pancake sort algorithm.\"\"\"\n\n def flip(arr, k):\n arr[:k] = arr[:k][::-1]\n \n n = len(arr)\n for i in range(n - 1, 0, -1):\n # Find the index of the largest element in the unsorted part\n max_idx = arr.index(max(arr[:i + 1]))\n\n # If the largest element is not already at the end of the unsorted part\n if max_idx != i:\n # Flip the largest element to the beginning\n flip(arr, max_idx + 1)\n # Flip the entire unsorted part to put the largest element at the end\n flip(arr, i + 1)\n\n return arr", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(arr):\n \"\"\"Sorts a list using the Pancake Sort algorithm.\n\n Args:\n arr: A list of elements to be sorted.\n\n Returns:\n The sorted list.\n \"\"\"\n\n n = len(arr)\n for i in range(n):\n max_index = arr.index(max(arr[: n - i]))\n if max_index != n - i - 1:\n arr[:max_index + 1] = arr[:max_index + 1][::-1]\n arr[:n - i] = arr[:n - i][::-1]\n return arr", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(arr):\n \"\"\"\n Sort a list of elements using the pancake sort algorithm.\n\n Args:\n arr: The list to be sorted.\n\n Returns:\n The sorted list.\n \"\"\"\n\n n = len(arr)\n for i in range(n - 1, 0, -1):\n # Find the index of the maximum element in the unsorted part\n max_idx = arr.index(max(arr[: i + 1]))\n\n # Flip to bring the maximum element to the beginning\n arr[: max_idx + 1] = arr[: max_idx + 1][::-1]\n\n # Flip the whole unsorted part to its correct position\n arr[: i + 1] = arr[: i + 1][::-1]\n return arr", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(arr):\n \"\"\"Sorts a list using the pancake sort algorithm.\"\"\"\n n = len(arr)\n for i in range(n - 1, 0, -1):\n # Find the index of the maximum element in the unsorted part\n max_index = arr.index(max(arr[:i + 1]))\n \n # Bring the maximum element to the beginning (first flip)\n arr[:max_index + 1] = reversed(arr[:max_index + 1])\n \n # Bring the maximum element to its correct position (second flip)\n arr[:i + 1] = reversed(arr[:i + 1])\n return arr", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(arr):\n \"\"\"Sorts a list of elements using the Pancake Sort algorithm.\n\n Args:\n arr: A list of elements to be sorted.\n\n Returns:\n The sorted list.\n \"\"\"\n n = len(arr)\n for i in range(n - 1, 0, -1):\n # Find the index of the maximum element in the unsorted part of the array\n max_index = arr.index(max(arr[:i + 1]))\n\n # If the maximum element is not already in its correct position\n if max_index != i:\n # Flip the array from 0 to max_index\n arr[:max_index + 1] = reversed(arr[:max_index + 1])\n\n # Flip the array from 0 to i\n arr[:i + 1] = reversed(arr[:i + 1])\n return arr", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(arr):\n \"\"\"\n Sorts a list using the pancake sort algorithm.\n\n Args:\n arr: A list of elements to sort.\n\n Returns:\n The sorted list.\n \"\"\"\n n = len(arr)\n for i in range(n - 1, 0, -1):\n # Find index of the maximum element in the unsorted part\n max_index = arr.index(max(arr[:i + 1]))\n \n # If max element is not at the beginning, flip to the beginning\n if max_index != 0:\n arr[:max_index + 1] = arr[:max_index + 1][::-1]\n\n # Flip the entire unsorted part to place max element at its correct position\n arr[:i + 1] = arr[:i + 1][::-1]\n\n return arr", "matching_cluster_idx": 3}]}, "Mbpp/166": {"dps": 94.39999999999999, "dps_norm": 50.0, "pass@1": 100.0, "profiled": [{"solution": "def find_even_pair(nums):\n \"\"\"Counts the number of pairs of integers in a list that xor to an even number.\n\n Args:\n nums: A list of integers.\n\n Returns:\n The number of pairs of integers in the list that xor to an even number.\n \"\"\"\n count = 0\n for i in range(len(nums)):\n for j in range(i+1, len(nums)):\n if (nums[i] ^ nums[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(nums):\n \"\"\"\n Counts the number of pairs of integers in a list that xor to an even number.\n For example:\n find_even_pair([5, 4, 7, 2, 1]) == 4\n \"\"\"\n count = 0\n for i in range(len(nums)):\n for j in range(i + 1, len(nums)):\n if (nums[i] ^ nums[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(nums):\n \"\"\"Counts the number of pairs of integers in a list that XOR to an even number.\n\n Args:\n nums: A list of integers.\n\n Returns:\n The number of pairs of integers in the list that XOR to an even number.\n \"\"\"\n count = 0\n for i in range(len(nums)):\n for j in range(i + 1, len(nums)):\n if (nums[i] ^ nums[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(nums):\n \"\"\"\n Counts the number of pairs of integers in a list that xor to an even number.\n\n Args:\n nums: A list of integers.\n\n Returns:\n The number of pairs of integers in the list that xor to an even number.\n \"\"\"\n count = 0\n for i in range(len(nums)):\n for j in range(i + 1, len(nums)):\n if (nums[i] ^ nums[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(nums):\n \"\"\"\n Counts the number of pairs of integers in a list that xor to an even number.\n\n Args:\n nums: A list of integers.\n\n Returns:\n The number of pairs of integers in the list that xor to an even number.\n \"\"\"\n count = 0\n for i in range(len(nums)):\n for j in range(i + 1, len(nums)):\n if (nums[i] ^ nums[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(nums):\n \"\"\"\n Counts the number of pairs of integers in a list that xor to an even number.\n\n Args:\n nums: A list of integers.\n\n Returns:\n The number of pairs of integers in nums that xor to an even number.\n \"\"\"\n count = 0\n for i in range(len(nums)):\n for j in range(i + 1, len(nums)):\n if (nums[i] ^ nums[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(nums):\n \"\"\"\n Counts the number of pairs of integers in a list that xor to an even number.\n\n Args:\n nums: A list of integers.\n\n Returns:\n The number of pairs of integers in the list that xor to an even number.\n \"\"\"\n count = 0\n for i in range(len(nums)):\n for j in range(i + 1, len(nums)):\n if (nums[i] ^ nums[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(nums):\n \"\"\"\n Counts the number of pairs of integers in a list that xor to an even number.\n \"\"\"\n count = 0\n for i in range(len(nums)):\n for j in range(i + 1, len(nums)):\n if (nums[i] ^ nums[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(nums):\n \"\"\"\n Counts the number of pairs of integers in a list that xor to an even number.\n\n Args:\n nums: A list of integers.\n\n Returns:\n The number of pairs of integers in the list that xor to an even number.\n \"\"\"\n count = 0\n for i in range(len(nums)):\n for j in range(i + 1, len(nums)):\n if (nums[i] ^ nums[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(nums):\n \"\"\"Counts the number of pairs of integers in a list that XOR to an even number.\n\n Args:\n nums: A list of integers.\n\n Returns:\n The number of pairs of integers in nums that XOR to an even number.\n \"\"\"\n count = 0\n for i in range(len(nums)):\n for j in range(i + 1, len(nums)):\n if (nums[i] ^ nums[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(nums):\n \"\"\"\n Counts the number of pairs of integers in a list that xor to an even number.\n\n Args:\n nums: A list of integers.\n\n Returns:\n The number of pairs of integers in nums that xor to an even number.\n \"\"\"\n count = 0\n for i in range(len(nums)):\n for j in range(i + 1, len(nums)):\n if (nums[i] ^ nums[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(nums: list[int]) -> int:\n \"\"\"\n Counts the number of pairs of integers in a list that xor to an even number.\n\n Args:\n nums: A list of integers.\n\n Returns:\n The number of pairs that xor to an even number.\n \"\"\"\n count = 0\n for i in range(len(nums)):\n for j in range(i + 1, len(nums)):\n if (nums[i] ^ nums[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(nums):\n \"\"\"\n Counts the number of pairs of integers in a list that xor to an even number.\n\n Args:\n nums: A list of integers.\n\n Returns:\n The number of pairs that xor to an even number.\n \"\"\"\n count = 0\n for i in range(len(nums)):\n for j in range(i + 1, len(nums)):\n if (nums[i] ^ nums[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(nums):\n \"\"\"\n Counts the number of pairs of integers in a list that xor to an even number.\n\n Args:\n nums: A list of integers.\n\n Returns:\n The number of pairs of integers in the list that xor to an even number.\n \"\"\"\n count = 0\n for i in range(len(nums)):\n for j in range(i + 1, len(nums)):\n if (nums[i] ^ nums[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(nums):\n \"\"\"Counts the number of pairs of integers in a list that xor to an even number.\n \n Args:\n nums: A list of integers.\n \n Returns:\n The number of pairs that xor to an even number.\n \"\"\"\n count = 0\n for i in range(len(nums)):\n for j in range(i+1, len(nums)):\n if (nums[i] ^ nums[j]) % 2 == 0:\n count += 1\n return count\nnums = [5, 4, 7, 2, 1]", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(nums):\n \"\"\"\n Counts the number of pairs of integers in a list that XOR to an even number.\n\n Args:\n nums: A list of integers.\n\n Returns:\n The number of pairs of integers in the list that XOR to an even number.\n \"\"\"\n count = 0\n for i in range(len(nums)):\n for j in range(i + 1, len(nums)):\n if (nums[i] ^ nums[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(nums):\n \"\"\"\n Counts the number of pairs of integers in a list that XOR to an even number.\n\n Args:\n nums: A list of integers.\n\n Returns:\n The number of pairs of integers in nums that XOR to an even number.\n \"\"\"\n count = 0\n for i in range(len(nums)):\n for j in range(i + 1, len(nums)):\n if (nums[i] ^ nums[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(nums):\n \"\"\"\n Counts the number of pairs of integers in a list that xor to an even number.\n\n Args:\n nums: A list of integers.\n\n Returns:\n The number of pairs of integers in the list that xor to an even number.\n \"\"\"\n count = 0\n for i in range(len(nums)):\n for j in range(i + 1, len(nums)):\n if (nums[i] ^ nums[j]) % 2 == 0:\n count += 1\n return count\nnums = [5, 4, 7, 2, 1]", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(nums):\n \"\"\"\n Counts the number of pairs of integers in a list that xor to an even number.\n\n Args:\n nums: A list of integers.\n\n Returns:\n The number of pairs of integers in nums that xor to an even number.\n \"\"\"\n count = 0\n for i in range(len(nums)):\n for j in range(i + 1, len(nums)):\n if (nums[i] ^ nums[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(nums):\n \"\"\"\n Counts the number of pairs of integers in a list that xor to an even number.\n\n Args:\n nums: A list of integers.\n\n Returns:\n The number of pairs of integers in the list that xor to an even number.\n \"\"\"\n\n count = 0\n for i in range(len(nums)):\n for j in range(i + 1, len(nums)):\n if (nums[i] ^ nums[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}]}, "Mbpp/170": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 30.0, "profiled": [{"solution": "def sum_range_list(numbers, start_index, end_index):\n \"\"\"\n Calculates the sum of numbers in a list within a specified range.\n\n Args:\n numbers: A list of numbers.\n start_index: The starting index of the range (inclusive).\n end_index: The ending index of the range (inclusive).\n\n Returns:\n The sum of numbers within the specified range.\n \"\"\"\n if start_index < 0 or end_index >= len(numbers) or start_index > end_index:\n return 0\n return sum(numbers[start_index : end_index + 1])\nnumbers = [2, 1, 5, 6, 8, 3, 4, 9, 10, 11, 8, 12]\nstart_index = 8\nend_index = 10", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(nums, start, end):\n \"\"\"\n This function calculates the sum of numbers in a list within a specified range.\n\n Args:\n nums: A list of numbers.\n start: The starting index (inclusive) of the range.\n end: The ending index (inclusive) of the range.\n\n Returns:\n The sum of numbers in the specified range of the list.\n \"\"\"\n if start < 0 or end >= len(nums) or start > end:\n return 0\n return sum(nums[start:end+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(nums, start_index, end_index):\n \"\"\"\n Calculate the sum of numbers in a list within a specified range.\n\n Args:\n nums (list): The input list of numbers.\n start_index (int): The starting index (inclusive).\n end_index (int): The ending index (inclusive).\n\n Returns:\n int: The sum of numbers within the specified range.\n \"\"\"\n\n if start_index < 0 or end_index >= len(nums) or start_index > end_index:\n return 0 \n return sum(nums[start_index : end_index + 1])\nnums = [2,1,5,6,8,3,4,9,10,11,8,12]\nstart_index = 8\nend_index = 10", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(nums, start_index, end_index):\n \"\"\"\n Calculates the sum of numbers in a list within a given range.\n\n Args:\n nums: A list of numbers.\n start_index: The starting index (inclusive) of the range.\n end_index: The ending index (inclusive) of the range.\n\n Returns:\n The sum of the numbers in the specified range.\n Returns 0 if the provided indices are invalid.\n \"\"\"\n if 0 <= start_index <= end_index < len(nums):\n return sum(nums[start_index : end_index + 1])\n else:\n return 0", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(numbers, start_index, end_index):\n \"\"\"\n Calculates the sum of numbers in a list within a specified range.\n\n Args:\n numbers: A list of numbers.\n start_index: The starting index of the range (inclusive).\n end_index: The ending index of the range (inclusive).\n\n Returns:\n The sum of numbers within the specified range.\n \"\"\"\n if start_index < 0 or end_index >= len(numbers) or start_index > end_index:\n return 0 \n return sum(numbers[start_index : end_index + 1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(nums, start, end):\n \"\"\"Calculates the sum of numbers in a list within a specified range.\n\n Args:\n nums: A list of numbers.\n start: The starting index (inclusive).\n end: The ending index (inclusive).\n\n Returns:\n The sum of numbers in the specified range.\n \"\"\"\n if start < 0 or end >= len(nums) or start > end:\n return 0\n return sum(nums[start : end + 1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(numbers, start_index, end_index):\n \"\"\"\n Calculates the sum of numbers in a list within a specified range.\n\n Args:\n numbers: A list of numbers.\n start_index: The starting index (inclusive) of the range.\n end_index: The ending index (inclusive) of the range.\n\n Returns:\n The sum of the numbers in the specified range.\n \"\"\"\n if start_index < 0 or end_index >= len(numbers) or start_index > end_index:\n return 0\n return sum(numbers[start_index : end_index + 1])\nnumbers = [2, 1, 5, 6, 8, 3, 4, 9, 10, 11, 8, 12]", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(nums: list, start: int, end: int) -> int:\n \"\"\"\n Given a list of numbers, find the sum of numbers within a given range.\n\n Args:\n nums: A list of numbers.\n start: The starting index (inclusive) of the range.\n end: The ending index (inclusive) of the range.\n\n Returns:\n The sum of the numbers in the list within the specified range.\n \"\"\"\n if start < 0 or end >= len(nums) or start > end:\n return 0\n\n return sum(nums[start:end+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(nums, start, end):\n \"\"\"\n Calculates the sum of numbers in a list within a specified range.\n\n Args:\n nums: The list of numbers.\n start: The starting index (inclusive).\n end: The ending index (inclusive).\n\n Returns:\n The sum of numbers in the specified range.\n \"\"\"\n if start < 0 or end >= len(nums) or start > end:\n return 0\n return sum(nums[start : end+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(data: list, start_index: int, end_index: int) -> int:\n \"\"\"\n Calculates the sum of numbers in a list within a specified range.\n\n Args:\n data: A list of numbers.\n start_index: The starting index (inclusive) of the range.\n end_index: The ending index (inclusive) of the range.\n\n Returns:\n The sum of the numbers in the specified range.\n\n Raises:\n IndexError: If the start or end indices are out of range.\n \"\"\"\n if not 0 <= start_index <= len(data) - 1 or not 0 <= end_index <= len(data) - 1:\n raise IndexError(\"Indices are out of range.\")\n\n return sum(data[start_index : end_index + 1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(nums, start, end):\n \"\"\"\n Calculate the sum of numbers in a list within a specified range.\n\n Args:\n nums: A list of numbers.\n start: The starting index (inclusive).\n end: The ending index (inclusive).\n\n Returns:\n The sum of the numbers in the list within the specified range.\n \"\"\"\n\n if start < 0 or end >= len(nums) or start > end:\n return 0\n return sum(nums[start:end+1])\nnums = [2, 1, 5, 6, 8, 3, 4, 9, 10, 11, 8, 12]\nstart = 8\nend = 10", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(data, start, end):\n \"\"\"\n This function finds the sum of numbers in a list within a range specified by two indices.\n\n Args:\n data: A list of numbers.\n start: The starting index (inclusive) of the range.\n end: The ending index (inclusive) of the range.\n\n Returns:\n The sum of the numbers within the specified range.\n Returns 0 if the start or end indices are invalid.\n \"\"\"\n\n if start < 0 or end >= len(data) or start > end:\n return 0 \n\n return sum(data[start : end+1])\ndata = [2, 1, 5, 6, 8, 3, 4, 9, 10, 11, 8, 12]", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(nums, start_index, end_index):\n \"\"\"\n This function calculates the sum of numbers in a list within a specified range.\n\n Args:\n nums: A list of numbers.\n start_index: The starting index of the range (inclusive).\n end_index: The ending index of the range (inclusive).\n\n Returns:\n The sum of numbers within the specified range.\n \"\"\"\n if start_index < 0 or end_index >= len(nums) or start_index > end_index:\n return 0 \n return sum(nums[start_index : end_index + 1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(nums, start, end):\n \"\"\"\n\n This function calculates the sum of numbers in a list within a specified range.\n\n Args:\n nums: A list of numbers.\n start: The starting index of the range (inclusive).\n end: The ending index of the range (inclusive).\n\n Returns:\n The sum of the numbers in the specified range, or 0 if the range is invalid.\n\n \"\"\"\n if start < 0 or end >= len(nums) or start > end:\n return 0\n\n return sum(nums[start : end + 1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(numbers, start_index, end_index):\n \"\"\"\n Calculates the sum of numbers in a list within a specified range.\n\n Args:\n numbers: The list of numbers.\n start_index: The starting index (inclusive) of the range.\n end_index: The ending index (inclusive) of the range.\n\n Returns:\n The sum of numbers within the specified range.\n \"\"\"\n if start_index < 0 or end_index >= len(numbers) or start_index > end_index:\n return 0 \n return sum(numbers[start_index : end_index+1])\nnumbers = [2,1,5,6,8,3,4,9,10,11,8,12]\nstart_index = 8\nend_index = 10", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(nums, start, end):\n \"\"\"\n Calculates the sum of numbers in a list within a specified range.\n\n Args:\n nums: A list of numbers.\n start: The starting index of the range (inclusive).\n end: The ending index of the range (inclusive).\n\n Returns:\n The sum of numbers in the specified range.\n \"\"\"\n return sum(nums[start:end+1])\nnums = [2,1,5,6,8,3,4,9,10,11,8,12]", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(nums, start, end):\n \"\"\"\n Calculates the sum of numbers in a list within a specified range.\n\n Args:\n nums: A list of numbers.\n start: The starting index (inclusive) of the range.\n end: The ending index (inclusive) of the range.\n\n Returns:\n The sum of numbers in the specified range.\n \"\"\"\n\n if start < 0 or end >= len(nums) or start > end:\n return 0 \n\n return sum(nums[start : end+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(nums, start_index, end_index):\n \"\"\"\n Calculates the sum of numbers in a list within a specified range.\n\n Args:\n nums: A list of numbers.\n start_index: The starting index (inclusive) of the range.\n end_index: The ending index (inclusive) of the range.\n\n Returns:\n The sum of numbers in the specified range.\n \"\"\"\n if start_index < 0 or end_index >= len(nums) or start_index > end_index:\n return 0\n\n return sum(nums[start_index:end_index + 1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(nums, start, end):\n \"\"\"\n Calculates the sum of numbers in a list within a specified range.\n\n Args:\n nums: A list of numbers.\n start: The starting index (inclusive) of the range.\n end: The ending index (inclusive) of the range.\n\n Returns:\n The sum of numbers in the specified range.\n \"\"\"\n if start < 0 or end >= len(nums) or start > end:\n return 0 \n return sum(nums[start:end+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(nums, start, end):\n \"\"\"\n This function calculates the sum of numbers in a list within a specified range.\n\n Args:\n nums: A list of numbers.\n start: The starting index of the range (inclusive).\n end: The ending index of the range (inclusive).\n\n Returns:\n The sum of numbers within the specified range.\n \"\"\"\n if start < 0 or end >= len(nums) or start > end:\n return 0 \n return sum(nums[start : end+1])", "matching_cluster_idx": 7}]}, "Mbpp/226": {"dps": 77.71317829457364, "dps_norm": 38.57142857142857, "pass@1": 100.0, "profiled": [{"solution": "def odd_values_string(str1):\n \"\"\"\n This function takes a string and returns a new string containing only the characters at even indices.\n\n Args:\n str1: The input string.\n\n Returns:\n A new string containing only the characters at even indices of the input string.\n \"\"\"\n return str1[::2]", "matching_cluster_idx": 6}, {"solution": "def odd_values_string(str1):\n \"\"\"\n This function removes the characters which have odd index values of a given string.\n\n Args:\n str1: The input string.\n\n Returns:\n A string containing only the characters at even indices.\n \"\"\"\n return str1[::2]", "matching_cluster_idx": 6}, {"solution": "def odd_values_string(text):\n \"\"\"Returns a new string containing only characters at even indices from the input string.\n For example:\n odd_values_string('abcdef') == 'ace'\n \"\"\"\n return ''.join(text[i] for i in range(len(text)) if i % 2 == 0)", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(text: str) -> str:\n \"\"\"\n Write a python function to remove the characters which have odd index values of a given string.\n assert odd_values_string('abcdef') == 'ace'\n \"\"\"\n return \"\".join([text[i] for i in range(len(text)) if i % 2 == 0])", "matching_cluster_idx": 1}, {"solution": "def odd_values_string(text: str) -> str:\n \"\"\"\n Write a python function to remove the characters which have odd index values of a given string.\n assert odd_values_string('abcdef') == 'ace'\n \"\"\"\n return ''.join(text[i] for i in range(len(text)) if i % 2 == 0)", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(str1):\n \"\"\"\n This function removes the characters which have odd index values of a given string.\n\n Args:\n str1: The input string.\n\n Returns:\n A new string with characters at odd indices removed.\n \"\"\"\n return \"\".join([str1[i] for i in range(len(str1)) if i % 2 == 0])", "matching_cluster_idx": 1}, {"solution": "def odd_values_string(str1):\n \"\"\"\n Write a python function to remove the characters which have odd index values of a given string.\n \"\"\"\n result = ''\n for i in range(len(str1)):\n if i % 2 == 0:\n result += str1[i]\n return result", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(str1):\n \"\"\"\n\n This function removes characters at odd indexes of a string and returns a new string with remaining characters.\n\n Args:\n str1: The input string.\n\n Returns:\n A string with characters at odd indexes removed.\n \"\"\"\n\n return ''.join([str1[i] for i in range(len(str1)) if i % 2 == 0])", "matching_cluster_idx": 1}, {"solution": "def odd_values_string(str1):\n \"\"\"\n This function takes a string as input and returns a new string\n containing only the characters at even indices.\n\n Args:\n str1: The input string.\n\n Returns:\n A new string containing only the characters at even indices of the input string.\n \"\"\"\n return ''.join(str1[i] for i in range(len(str1)) if i % 2 == 0)", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(str1):\n \"\"\"\n Returns a new string with characters at odd indices removed.\n\n Args:\n str1: The input string\n\n Returns:\n A string with characters at odd indices removed.\n\n Examples:\n odd_values_string('abcdef') == 'ace'\n \"\"\"\n\n return ''.join(str1[i] for i in range(len(str1)) if i % 2 == 0)", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(text):\n \"\"\"\n This function removes the characters which have odd index values of a given string.\n\n Args:\n text: A string\n\n Returns:\n A string with characters at odd indices removed\n \"\"\"\n new_text = \"\"\n for i in range(len(text)):\n if i % 2 == 0:\n new_text += text[i]\n return new_text", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(text):\n \"\"\"\n Removes the characters which have odd index values of a given string.\n\n Args:\n text: The input string.\n\n Returns:\n The string with characters at odd indices removed.\n \"\"\"\n return text[::2]", "matching_cluster_idx": 6}, {"solution": "def odd_values_string(str1):\n \"\"\"\n This function removes characters at odd indices from a string.\n\n Args:\n str1: The input string.\n\n Returns:\n A new string with characters at odd indices removed.\n \"\"\"\n result = \"\"\n for i in range(len(str1)):\n if i % 2 == 0:\n result += str1[i]\n return result", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(str1):\n \"\"\"\n This function takes a string as input and returns a new string with only the characters at even indices.\n\n Args:\n str1 (str): The input string.\n\n Returns:\n str: A new string with characters at even indices from the input string.\n \"\"\"\n\n return str1[::2]", "matching_cluster_idx": 6}, {"solution": "def odd_values_string(str1):\n \"\"\"\n Write a python function to remove the characters which have odd index values of a given string.\n \"\"\"\n return str1[::2]", "matching_cluster_idx": 6}, {"solution": "def odd_values_string(string):\n \"\"\"\n Removes characters with odd index values from a given string.\n\n Args:\n string: The input string\n\n Returns:\n A new string containing only characters with even index values.\n \"\"\"\n\n return \"\".join(string[i] for i in range(len(string)) if i % 2 == 0)", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(text: str) -> str:\n \"\"\"\n Write a python function to remove the characters which have odd index values of a given string.\n\n assert odd_values_string('abcdef') == 'ace'\n \"\"\"\n result = \"\"\n for i in range(len(text)):\n if i % 2 == 0:\n result += text[i]\n return result", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(text: str) -> str:\n \"\"\"\n Write a python function to remove the characters which have odd index values of a given string.\n\n assert odd_values_string('abcdef') == 'ace'\n \"\"\"\n return ''.join([text[i] for i in range(len(text)) if i % 2 == 0])", "matching_cluster_idx": 1}, {"solution": "def odd_values_string(str1):\n \"\"\"\n This function removes the characters which have odd index values of a given string.\n\n Args:\n str1: The input string.\n\n Returns:\n A new string with characters at odd indices removed.\n \"\"\"\n return ''.join([str1[i] for i in range(len(str1)) if i % 2 == 0])", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(str1):\n \"\"\"\n Write a python function to remove the characters which have odd index values of a given string.\n\n Args:\n str1: The input string.\n\n Returns:\n A new string with the characters at odd indices removed.\n \"\"\"\n result = ''\n for i in range(len(str1)):\n if i % 2 == 0:\n result += str1[i]\n return result", "matching_cluster_idx": 0}]}, "Mbpp/230": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 96.0, "profiled": [{"solution": "def replace_blank(text, char):\n \"\"\"\n Replaces blank spaces in a string with a given character.\n\n Args:\n text: The input string.\n char: The character to replace blank spaces with.\n\n Returns:\n The string with blank spaces replaced by the given character.\n \"\"\"\n return text.replace(\" \", char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(string, char):\n \"\"\"Replaces blank spaces in a string with a given character.\n\n Args:\n string: The string to be modified.\n char: The character to replace blank spaces with.\n\n Returns:\n The modified string with blank spaces replaced.\n \"\"\"\n return string.replace(\" \", char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(string, char):\n \"\"\"\n Replaces blank spaces in a string with a given character.\n\n Args:\n string: The input string.\n char: The character to replace spaces with.\n\n Returns:\n The string with spaces replaced by the given character.\n \"\"\"\n return string.replace(\" \", char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(string, char):\n \"\"\"Replaces blank spaces in a string with a given character.\n\n Args:\n string: The input string.\n char: The character to replace blank spaces with.\n\n Returns:\n The string with blank spaces replaced by the specified character.\n \"\"\"\n return string.replace(\" \", char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(string, char):\n \"\"\"Replaces blank spaces in a string with a given character.\n\n Args:\n string: The input string.\n char: The character to replace blank spaces with.\n\n Returns:\n The string with blank spaces replaced.\n \"\"\"\n\n return string.replace(\" \", char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(string, char):\n \"\"\"Replaces blank spaces in a string with a specified character.\n \n Args:\n string: The string to be modified.\n char: The character to replace spaces with.\n\n Returns:\n The modified string with spaces replaced by the given character.\n \"\"\"\n return string.replace(\" \", char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(text, char):\n \"\"\"Replaces blank spaces in a string with a given character.\n\n Args:\n text: The string to be processed.\n char: The character to replace blank spaces with.\n\n Returns:\n The string with blank spaces replaced by the given character.\n \"\"\"\n return text.replace(\" \", char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(string, char):\n \"\"\"\n Replaces blank spaces in a string with a given character.\n\n Args:\n string: The input string.\n char: The character to replace blank spaces with.\n\n Returns:\n The modified string with blank spaces replaced.\n \"\"\"\n return string.replace(\" \", char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(string, char):\n \"\"\"\n Replaces blank spaces in a string with a given character.\n\n Args:\n string: The input string.\n char: The character to replace blank spaces with.\n\n Returns:\n The string with blank spaces replaced by the given character.\n \"\"\"\n return string.replace(\" \", char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(string, character):\n \"\"\"\n This function takes a string and a character, replaces blank spaces \n in the string with the character, and returns the modified string.\n\n Args:\n string: The input string.\n character: The character to replace blank spaces with.\n\n Returns:\n The modified string with blank spaces replaced by the specified character.\n \"\"\"\n return string.replace(\" \", character)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(string, char):\n \"\"\"Replaces blank spaces in a string with a given character.\n\n Args:\n string: The input string.\n char: The character to replace blank spaces with.\n\n Returns:\n The string with blank spaces replaced by the given character.\n \"\"\"\n return string.replace(\" \", char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(string, char):\n \"\"\"\n This function takes in a string and a character, replaces blank spaces in the string with the character, and returns the new string.\n\n Args:\n string: The input string.\n char: The character to replace blank spaces with.\n\n Returns:\n The modified string with blank spaces replaced by the given character.\n \"\"\"\n return string.replace(\" \", char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(string, char):\n \"\"\"Replaces blank spaces in a string with a given character.\n\n Args:\n string: The input string.\n char: The character to replace blank spaces with.\n\n Returns:\n The string with blank spaces replaced by the character.\n \"\"\"\n return string.replace(\" \", char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(string, char):\n \"\"\"\n This function takes in a string and character, replaces blank spaces in the string with the character, and returns the string.\n\n Args:\n string: The string to be processed.\n char: The character to replace blank spaces with.\n\n Returns:\n The string with blank spaces replaced by the character.\n \"\"\"\n return string.replace(\" \", char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(s, char):\n \"\"\"Replaces blank spaces in a string with a given character.\n \n Args:\n s: The input string.\n char: The character to replace blank spaces with.\n \n Returns:\n The modified string with blank spaces replaced.\n \"\"\"\n return s.replace(\" \", char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(string, character):\n return string.replace(\" \", character)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(string, char):\n return string.replace(\" \",char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(string, char):\n return string.replace(\" \",char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(string, char):\n \"\"\"\n This function takes in a string and a character, replaces blank spaces in the string \n with the character, and returns the new string.\n\n Args:\n string: The string to be processed.\n char: The character to replace spaces with.\n\n Returns:\n The string with spaces replaced by the given character.\n \"\"\"\n return string.replace(\" \", char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(string, char):\n \"\"\"Replaces blank spaces in a string with a given character.\n\n Args:\n string: The string to be processed.\n char: The character to replace blank spaces with.\n\n Returns:\n The string with blank spaces replaced.\n \"\"\"\n return string.replace(\" \", char)", "matching_cluster_idx": 7}]}, "Mbpp/239": {"dps": 79.3103448275862, "dps_norm": 80.0, "pass@1": 19.0, "profiled": [{"solution": "def get_total_number_of_sequences(m, n):\n \"\"\"\n Finds the number of possible sequences of length n, \n such that each element is a positive integer and is greater than or equal\n to twice the previous element but less than or equal to m.\n\n Args:\n m: The maximum value of elements in the sequence.\n n: The length of the sequence.\n\n Returns:\n The number of possible sequences.\n \"\"\"\n\n dp = [[0 for _ in range(m + 1)] for _ in range(n + 1)]\n\n # Initialization: For a sequence of length 1, any number from 1 to m is valid.\n for i in range(1, m + 1):\n dp[1][i] = 1\n\n # Iterate over sequence lengths from 2 to n\n for i in range(2, n + 1):\n # Iterate over possible ending values for the sequence\n for j in range(1, m + 1):\n # For each ending value, sum the counts of sequences with \n # previous elements that are valid (i.e., less than j/2)\n for k in range(1, j // 2 + 1):\n dp[i][j] += dp[i - 1][k]\n\n return sum(dp[n])", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m: int, n: int) -> int:\n \"\"\"\n Write a function that takes in positive integers m and n and finds the number of possible sequences of length n,\n such that each element is a positive integer and is greater than or equal to twice the previous element but less than or equal to m.\n assert get_total_number_of_sequences(10, 4) == 4\n \"\"\"\n\n dp = [[0 for _ in range(m + 1)] for _ in range(n + 1)]\n\n # Initialize base case: for a sequence of length 1, we can have any number from 1 to m\n for i in range(1, m + 1):\n dp[1][i] = 1\n\n # Iterate through each possible sequence length\n for i in range(2, n + 1):\n # Iterate through each possible last element in the sequence\n for j in range(1, m + 1):\n # Iterate through all possible previous elements\n for k in range(1, j // 2 + 1):\n dp[i][j] += dp[i - 1][k]\n\n return sum(dp[n])", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n \"\"\"\n Finds the number of possible sequences of length n, such that each element \n is a positive integer and is greater than or equal to twice the previous element\n but less than or equal to m.\n\n Args:\n m: The upper bound for each element in the sequence.\n n: The length of the sequence.\n\n Returns:\n The number of possible sequences.\n \"\"\"\n\n dp = [[0 for _ in range(m + 1)] for _ in range(n + 1)]\n\n # Initialize base case: for sequence of length 1, any number from 1 to m is valid\n for i in range(1, m + 1):\n dp[1][i] = 1\n\n # Build up the dp table\n for i in range(2, n + 1): # For each sequence length\n for j in range(1, m + 1): # For each possible last element\n for k in range(1, j // 2 + 1): # For each possible previous element\n dp[i][j] += dp[i - 1][k]\n\n return sum(dp[n])", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m: int, n: int) -> int:\n \"\"\"\n Given positive integers m and n, find the number of possible sequences of length n, \n such that each element is a positive integer and is greater than or equal to \n twice the previous element but less than or equal to m.\n\n Args:\n m: The upper limit of each element in the sequence.\n n: The length of the desired sequences.\n\n Returns:\n The number of possible sequences.\n \"\"\"\n dp = [[0 for _ in range(m + 1)] for _ in range(n + 1)]\n\n # Base case: For a sequence of length 1, we can have any number from 1 to m\n for i in range(1, m + 1):\n dp[1][i] = 1\n\n # Build up the dp table\n for i in range(2, n + 1):\n for j in range(1, m + 1):\n for k in range(1, j // 2 + 1):\n dp[i][j] += dp[i - 1][k]\n\n return sum(dp[n])", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n \"\"\"\n Counts the number of possible sequences of length n, where each element is a positive integer\n greater than or equal to twice the previous element and less than or equal to m.\n\n Args:\n m: The upper limit for each element in the sequence.\n n: The length of the desired sequences.\n\n Returns:\n The number of possible sequences.\n \"\"\"\n dp = [[0 for _ in range(m + 1)] for _ in range(n + 1)]\n \n # Base case: For a sequence of length 1, there are 'm' possible values (1 to m).\n for i in range(1, m + 1):\n dp[1][i] = 1\n\n # Iterate through each sequence length\n for i in range(2, n + 1):\n # Iterate through each possible value for the last element\n for j in range(1, m + 1):\n # Sum the possibilities from all valid previous elements\n for k in range(1, j // 2 + 1):\n dp[i][j] += dp[i - 1][k]\n\n return sum(dp[n])", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n \"\"\"\n Given positive integers m and n, return the number of possible sequences of length n, such that each element\n is a positive integer and is greater than or equal to twice the previous element but less than or equal to m.\n \"\"\"\n\n dp = [[0 for _ in range(m + 1)] for _ in range(n + 1)]\n \n # Initialize base case: for n=1, all numbers up to m are valid\n for i in range(1, m + 1):\n dp[1][i] = 1\n\n # Build up the dp table\n for i in range(2, n + 1):\n for j in range(1, m + 1):\n for k in range(1, j // 2 + 1):\n dp[i][j] += dp[i - 1][k]\n\n return sum(dp[n])", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n \"\"\"\n Counts the number of possible sequences of length n, where each element is a\n positive integer greater than or equal to twice the previous element but less than\n or equal to m.\n\n Args:\n m: The maximum allowed value for any element in the sequence.\n n: The length of the sequence.\n\n Returns:\n The number of possible sequences.\n \"\"\"\n dp = [[0 for _ in range(m + 1)] for _ in range(n + 1)]\n\n # Base case: For a sequence of length 1, any value from 1 to m is valid.\n for i in range(1, m + 1):\n dp[1][i] = 1\n\n # For each sequence length from 2 to n...\n for i in range(2, n + 1):\n # For each possible value of the last element...\n for j in range(1, m + 1):\n # Count sequences ending in j by considering possible previous elements.\n for k in range(1, j // 2 + 1):\n dp[i][j] += dp[i - 1][k]\n\n return sum(dp[n])", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n \"\"\"\n Finds the number of possible sequences of length n, such that each element is\n a positive integer and is greater than or equal to twice the previous element\n but less than or equal to m.\n \"\"\"\n\n dp = [[0 for _ in range(m + 1)] for _ in range(n + 1)]\n\n # Initialization: For a sequence of length 1, any number from 1 to m is valid.\n for i in range(1, m + 1):\n dp[1][i] = 1\n\n for i in range(2, n + 1): # Iterate through sequence lengths\n for j in range(1, m + 1): # Iterate through possible last element values\n for k in range(1, j // 2 + 1): # Iterate through possible previous element values\n dp[i][j] += dp[i - 1][k]\n\n return sum(dp[n])", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n \"\"\"\n Counts the number of possible sequences of length n, where each element is\n a positive integer greater than or equal to twice the previous element,\n and less than or equal to m.\n\n Args:\n m: The maximum value of each element in the sequence.\n n: The length of the sequence.\n\n Returns:\n The number of possible sequences.\n \"\"\"\n\n dp = [[0 for _ in range(m + 1)] for _ in range(n + 1)]\n\n # Base case: for a sequence of length 1, there's one valid sequence for each possible value\n for i in range(1, m + 1):\n dp[1][i] = 1\n\n for i in range(2, n + 1): # Iterate through sequence lengths\n for j in range(1, m + 1): # Iterate through possible ending values\n for k in range(1, j // 2 + 1): # Iterate through possible previous values\n dp[i][j] += dp[i - 1][k]\n\n return sum(dp[n])", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n \"\"\"\n This function takes in positive integers m and n and finds the number of possible sequences of length n,\n such that each element is a positive integer and is greater than or equal to twice the previous element \n but less than or equal to m.\n\n For example:\n get_total_number_of_sequences(10, 4) == 4\n \"\"\"\n dp = [[0 for _ in range(m + 1)] for _ in range(n + 1)]\n\n # Base case: For length 1 sequence, all numbers from 1 to m are valid\n for i in range(1, m + 1):\n dp[1][i] = 1\n\n # Iterate over sequence lengths\n for i in range(2, n + 1):\n # Iterate over possible ending numbers for a sequence of length i\n for j in range(1, m + 1):\n # For each ending number, consider all possible previous numbers\n for k in range(1, j // 2 + 1):\n dp[i][j] += dp[i - 1][k] \n\n return sum(dp[n])", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n \"\"\"\n Calculates the number of possible sequences of length n,\n where each element is a positive integer greater than or equal to\n twice the previous element but less than or equal to m.\n\n Args:\n m: The maximum allowed value for each element in the sequence.\n n: The length of the sequence.\n\n Returns:\n The number of possible sequences.\n \"\"\"\n\n dp = [[0 for _ in range(m + 1)] for _ in range(n + 1)]\n\n # Base case: For a sequence of length 1, there's 1 valid sequence for each possible starting number\n for i in range(1, m + 1):\n dp[1][i] = 1\n\n # Iterate through sequence lengths from 2 to n\n for i in range(2, n + 1):\n for j in range(1, m + 1):\n # For each possible value j at position i,\n # sum the valid sequences from previous positions\n # where the previous value is at most j // 2\n for k in range(1, j // 2 + 1):\n dp[i][j] += dp[i - 1][k]\n\n # The total number of sequences of length n is the sum of valid sequences ending with\n # each possible value from 1 to m\n return sum(dp[n])", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n \"\"\"\n This function takes in positive integers m and n and finds the number of possible sequences\n of length n, such that each element is a positive integer and is greater than or equal\n to twice the previous element but less than or equal to m.\n\n For example:\n get_total_number_of_sequences(10, 4) == 4\n \"\"\"\n\n dp = [[0 for _ in range(m + 1)] for _ in range(n + 1)]\n\n # Base case: For sequence length 1, any number from 1 to m is valid\n for i in range(1, m + 1):\n dp[1][i] = 1\n\n for i in range(2, n + 1): # Iterate over sequence lengths\n for j in range(1, m + 1): # Iterate over possible ending numbers\n for k in range(1, j // 2 + 1): # Iterate over possible previous numbers\n dp[i][j] += dp[i - 1][k]\n\n return sum(dp[n])", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n \"\"\"\n This function takes in positive integers m and n and finds the number of possible sequences of length n, \n such that each element is a positive integer and is greater than or equal to twice the previous element \n but less than or equal to m.\n\n Args:\n m: The upper limit of the integers in the sequence.\n n: The length of the desired sequence.\n\n Returns:\n The number of possible sequences.\n \"\"\"\n dp = [[0 for _ in range(m + 1)] for _ in range(n + 1)]\n \n # Initialize base case: For a sequence of length 1, any number from 1 to m is valid.\n for i in range(1, m + 1):\n dp[1][i] = 1\n\n # Iterate through each sequence length from 2 to n\n for i in range(2, n + 1):\n # For each possible ending value in the sequence\n for j in range(1, m + 1):\n # Iterate through possible previous values\n for k in range(1, j // 2 + 1):\n dp[i][j] += dp[i - 1][k]\n \n return sum(dp[n])", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n \"\"\"\n This function calculates the number of possible sequences of length n,\n such that each element is a positive integer and is greater than or equal to\n twice the previous element but less than or equal to m.\n\n Args:\n m: The upper limit for each element in the sequence.\n n: The length of the sequence.\n\n Returns:\n The number of possible sequences.\n \"\"\"\n\n dp = [[0 for _ in range(m + 1)] for _ in range(n + 1)]\n\n # Base case: For a sequence of length 1, any number from 1 to m is valid.\n for i in range(1, m + 1):\n dp[1][i] = 1\n\n # Iterate through each possible sequence length\n for i in range(2, n + 1):\n # Iterate through each possible ending value for the sequence\n for j in range(1, m + 1):\n # For each ending value, sum the number of valid sequences\n # ending with values that are half or less (since the current element\n # must be at least twice the previous).\n for k in range(1, j // 2 + 1):\n dp[i][j] += dp[i - 1][k]\n\n # Return the total number of valid sequences of length n ending with any value\n return sum(dp[n])", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n \"\"\"\n Finds the number of possible sequences of length n, such that each element is a positive integer\n and is greater than or equal to twice the previous element but less than or equal to m.\n \"\"\"\n dp = [[0 for _ in range(n + 1)] for _ in range(m + 1)]\n\n # Base case: for a sequence of length 1, there's 1 possible sequence for each valid value of the element\n for i in range(1, m + 1):\n dp[i][1] = 1\n\n # Iterate through lengths of sequences from 2 to n\n for j in range(2, n + 1):\n # Iterate through possible values of the last element\n for i in range(1, m + 1):\n # For each element, count sequences with the element as the last element\n for k in range(1, i // 2 + 1):\n dp[i][j] += dp[k][j - 1]\n\n # Return the total count for sequences of length n with any last element\n return sum(dp[i][n] for i in range(1, m + 1))", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n \"\"\"\n Finds the number of possible sequences of length n, such that each element is a\n positive integer and is greater than or equal to twice the previous element but\n less than or equal to m.\n\n Args:\n m: The maximum value of an element in the sequence.\n n: The length of the sequence.\n\n Returns:\n The number of possible sequences.\n \"\"\"\n dp = [[0 for _ in range(m + 1)] for _ in range(n + 1)]\n\n for i in range(1, m + 1):\n dp[1][i] = 1\n\n for i in range(2, n + 1):\n for j in range(1, m + 1):\n for k in range(1, j // 2 + 1):\n dp[i][j] += dp[i - 1][k]\n\n return sum(dp[n])", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n \"\"\"\n Counts the number of possible sequences of length n, where each element is a positive integer \n greater than or equal to twice the previous element and less than or equal to m.\n\n Args:\n m: The upper limit for the elements in the sequence.\n n: The length of the sequences.\n\n Returns:\n The number of possible sequences.\n \"\"\"\n dp = [[0 for _ in range(m + 1)] for _ in range(n + 1)]\n\n # Base case: For length 1, any number from 1 to m is valid\n for i in range(1, m + 1):\n dp[1][i] = 1\n\n # Build up the solution iteratively for lengths from 2 to n\n for i in range(2, n + 1):\n for j in range(1, m + 1):\n # For each element j, count valid sequences ending with j\n for k in range(1, j // 2 + 1):\n dp[i][j] += dp[i - 1][k]\n\n return sum(dp[n]) # Total count for sequences of length n", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n \"\"\"\n Finds the number of possible sequences of length n, such that each element \n is a positive integer and is greater than or equal to twice the previous element\n but less than or equal to m.\n\n Args:\n m: The upper bound for the elements in the sequence.\n n: The length of the sequence.\n\n Returns:\n The number of possible sequences.\n \"\"\"\n\n dp = [[0 for _ in range(m + 1)] for _ in range(n + 1)]\n \n # Base case: For a sequence of length 1, any number from 1 to m is valid\n for i in range(1, m + 1):\n dp[1][i] = 1\n\n # Fill the dp table\n for i in range(2, n + 1):\n for j in range(1, m + 1):\n # For each possible last element j, count the valid previous elements\n for k in range(1, j // 2 + 1): \n dp[i][j] += dp[i - 1][k]\n\n return sum(dp[n])", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n \"\"\"\n Calculates the number of possible sequences of length n,\n such that each element is a positive integer greater than\n or equal to twice the previous element but less than or equal to m.\n \"\"\"\n\n dp = [[0 for _ in range(m + 1)] for _ in range(n + 1)]\n \n # Base case: For a sequence of length 1, any number from 1 to m is valid\n for i in range(1, m + 1):\n dp[1][i] = 1\n\n # Iterate through sequence lengths from 2 to n\n for i in range(2, n + 1):\n # Iterate through possible values of the last element in the sequence\n for j in range(1, m + 1):\n # Iterate through possible values of the second-to-last element\n for k in range(1, j // 2 + 1):\n dp[i][j] += dp[i - 1][k] \n\n return sum(dp[n])", "matching_cluster_idx": 7}]}, "Mbpp/240": {"dps": 51.52439024390244, "dps_norm": 67.77777777777779, "pass@1": 83.0, "profiled": [{"solution": "def replace_list(list1, list2):\n \"\"\"\n Replaces the last element of the first list with the elements of the second list.\n\n Args:\n list1: The first list.\n list2: The second list.\n\n Returns:\n A new list with the last element of list1 replaced by the elements of list2.\n \"\"\"\n\n return list1[:-1] + list2", "matching_cluster_idx": 5}, {"solution": "def replace_list(list1, list2):\n \"\"\"Replaces the last element of the first list with the elements of the second list.\n\n Args:\n list1: The first list.\n list2: The second list.\n\n Returns:\n A new list with the last element of list1 replaced by the elements of list2.\n \"\"\"\n\n return list1[:-1] + list2", "matching_cluster_idx": 5}, {"solution": "def replace_list(lst1, lst2):\n \"\"\"Replaces the last element of lst1 with the elements of lst2.\"\"\"\n lst1[-1:] = lst2\n return lst1", "matching_cluster_idx": 7}, {"solution": "def replace_list(list1, list2):\n \"\"\"Replaces the last element of the first list with the elements of the second list.\n\n Args:\n list1: The first list.\n list2: The second list.\n\n Returns:\n A new list with the last element of list1 replaced by the elements of list2.\n \"\"\"\n return list1[:-1] + list2", "matching_cluster_idx": 5}, {"solution": "def replace_list(list1, list2):\n \"\"\"\n Replaces the last element of the first list with the elements of the second list.\n \n Args:\n list1: The first list.\n list2: The second list.\n \n Returns:\n A new list with the last element of list1 replaced by the elements of list2.\n \"\"\"\n return list1[:-1] + list2", "matching_cluster_idx": 5}, {"solution": "def replace_list(list1, list2):\n \"\"\"\n Replaces the last element of the first list with the elements of the second list.\n\n Args:\n list1: The first list.\n list2: The second list.\n\n Returns:\n A new list with the last element of list1 replaced by the elements of list2.\n \"\"\"\n return list1[:-1] + list2", "matching_cluster_idx": 5}, {"solution": "def replace_list(list1, list2):\n \"\"\"\n This function takes two lists and replaces the last element of the first list\n with the elements of the second list.\n\n Args:\n list1: The first list.\n list2: The second list.\n\n Returns:\n A new list with the last element of list1 replaced by the elements of list2.\n \"\"\"\n new_list = list1[:-1] + list2\n return new_list", "matching_cluster_idx": 5}, {"solution": "def replace_list(lst1, lst2):\n \"\"\"\n Replaces the last element of the first list with the elements of the second list.\n\n Args:\n lst1: The first list.\n lst2: The second list.\n\n Returns:\n A new list with the last element of lst1 replaced by the elements of lst2.\n \"\"\"\n\n return lst1[:-1] + lst2", "matching_cluster_idx": 5}, {"solution": "def replace_list(list1, list2):\n \"\"\"\n This function replaces the last element of the first list with the elements of the second list.\n\n Args:\n list1: The first list.\n list2: The second list.\n\n Returns:\n A new list with the last element of list1 replaced by the elements of list2.\n \"\"\"\n return list1[:-1] + list2", "matching_cluster_idx": 5}, {"solution": "def replace_list(list1, list2):\n \"\"\"\n Replaces the last element of the first list with the elements of the second list.\n\n Args:\n list1: The first list.\n list2: The second list.\n\n Returns:\n A new list with the last element of list1 replaced by the elements of list2.\n \"\"\"\n new_list = list1[:-1] + list2\n return new_list", "matching_cluster_idx": 5}, {"solution": "def replace_list(list1, list2):\n \"\"\"Replaces the last element of the first list with the elements of the second list.\n\n Args:\n list1: The first list.\n list2: The second list.\n\n Returns:\n A new list with the last element of list1 replaced by the elements of list2.\n \"\"\"\n return list1[:-1] + list2", "matching_cluster_idx": 5}, {"solution": "def replace_list(list1, list2):\n \"\"\"\n Replaces the last element of the first list with the elements of the second list.\n\n Args:\n list1: The first list.\n list2: The second list.\n\n Returns:\n A new list with the last element of list1 replaced by the elements of list2.\n \"\"\"\n return list1[:-1] + list2", "matching_cluster_idx": 5}, {"solution": "def replace_list(list1, list2):\n \"\"\"Replaces the last element of the first list with the elements of the second list.\n\n Args:\n list1: The first list.\n list2: The second list.\n\n Returns:\n A new list with the last element of the first list replaced by the elements of the second list.\n \"\"\"\n return list1[:-1] + list2", "matching_cluster_idx": 5}, {"solution": "def replace_list(list1, list2):\n \"\"\"\n Replaces the last element of the first list with the elements of the second list.\n\n Args:\n list1: The first list.\n list2: The second list.\n\n Returns:\n The modified first list.\n \"\"\"\n list1[-1:] = list2\n return list1", "matching_cluster_idx": 7}, {"solution": "def replace_list(list1, list2):\n \"\"\"\n This function takes in two lists and replaces the last element of the first list\n with the elements of the second list.\n\n Args:\n list1: The first list.\n list2: The second list.\n\n Returns:\n A new list with the modification described above.\n \"\"\"\n return list1[:-1] + list2", "matching_cluster_idx": 5}, {"solution": "def replace_list(list1, list2):\n \"\"\"\n This function takes in two lists and replaces the last element of the first list with the elements of the second list.\n\n Args:\n list1: The first list.\n list2: The second list.\n\n Returns:\n A new list with the last element of list1 replaced by the elements of list2.\n \"\"\"\n return list1[:-1] + list2", "matching_cluster_idx": 5}, {"solution": "def replace_list(list1, list2):\n \"\"\"Replaces the last element of the first list with the elements of the second list.\n\n Args:\n list1: The first list.\n list2: The second list.\n\n Returns:\n A new list with the last element of list1 replaced by the elements of list2.\n \"\"\"\n return list1[:-1] + list2", "matching_cluster_idx": 5}, {"solution": "def replace_list(list1, list2):\n \"\"\"Replaces the last element of the first list with the elements of the second list.\n\n Args:\n list1: The first list.\n list2: The second list.\n\n Returns:\n A new list with the last element of list1 replaced by the elements of list2.\n \"\"\"\n return list1[:-1] + list2", "matching_cluster_idx": 5}, {"solution": "def replace_list(list1, list2):\n \"\"\"\n Replaces the last element of the first list with the elements of the second list.\n\n Args:\n list1: The first list.\n list2: The second list.\n\n Returns:\n The modified first list with the last element replaced by the elements of the second list.\n \"\"\"\n list1[:-1] + list2 \n return list1[:-1] + list2", "matching_cluster_idx": 3}, {"solution": "def replace_list(list1, list2):\n \"\"\"\n Replaces the last element of the first list with the elements of the second list.\n\n Args:\n list1: The first list.\n list2: The second list.\n\n Returns:\n A new list with the last element of list1 replaced by the elements of list2.\n \"\"\"\n return list1[:-1] + list2", "matching_cluster_idx": 5}]}, "Mbpp/251": {"dps": 91.95402298850576, "dps_norm": 77.77777777777777, "pass@1": 100.0, "profiled": [{"solution": "def insert_element(lst, element):\n \"\"\"Inserts an element before each element in a list.\n\n Args:\n lst: The input list.\n element: The element to insert.\n\n Returns:\n A new list with the element inserted before each element in the original list.\n \"\"\"\n\n new_lst = []\n for item in lst:\n new_lst.append(element)\n new_lst.append(item)\n return new_lst", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n \"\"\"Inserts an element before each element in a list.\n\n Args:\n lst: A list of elements.\n element: The element to insert.\n\n Returns:\n A new list with the element inserted before each element in the original list.\n \"\"\"\n new_lst = []\n for item in lst:\n new_lst.append(element)\n new_lst.append(item)\n return new_lst", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n \"\"\"\n Inserts an element before each element in a list.\n\n Args:\n lst: The input list.\n element: The element to insert.\n\n Returns:\n A new list with the element inserted before each existing element.\n \"\"\"\n\n new_lst = []\n for item in lst:\n new_lst.append(element)\n new_lst.append(item)\n return new_lst\nlst = ['Red', 'Green', 'Black']\nelement = 'c'", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n \"\"\"\n This function inserts a given element before each element in a list.\n\n Args:\n lst: The input list.\n element: The element to be inserted.\n\n Returns:\n A new list with the element inserted before each existing element.\n \"\"\"\n new_lst = []\n for item in lst:\n new_lst.append(element)\n new_lst.append(item)\n return new_lst", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, elem):\n \"\"\"Inserts an element before each element in a list.\n\n Args:\n lst: The input list.\n elem: The element to insert.\n\n Returns:\n A new list with the element inserted before each existing element.\n \"\"\"\n new_list = []\n for i in lst:\n new_list.append(elem)\n new_list.append(i)\n return new_list", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n \"\"\"Inserts the given element before each element in the list.\n\n Args:\n lst: The input list.\n element: The element to be inserted.\n\n Returns:\n A new list with the element inserted before each existing element.\n \"\"\"\n result = []\n for item in lst:\n result.append(element)\n result.append(item)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(input_list, element):\n \"\"\"Inserts a given element before each element in a list.\n\n Args:\n input_list: The input list.\n element: The element to be inserted.\n\n Returns:\n A new list with the element inserted before each element in the input list.\n \"\"\"\n result = []\n for item in input_list:\n result.extend([element, item])\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n \"\"\"Inserts an element before each element in a list.\n\n Args:\n lst: The input list.\n element: The element to insert.\n\n Returns:\n A new list with the element inserted before each element in the input list.\n \"\"\"\n\n new_lst = []\n for item in lst:\n new_lst.extend([element, item])\n return new_lst", "matching_cluster_idx": 6}, {"solution": "def insert_element(list1, element):\n \"\"\"\n Inserts an element before each element in a list.\n\n Args:\n list1: The input list.\n element: The element to insert.\n\n Returns:\n A new list with the element inserted before each element.\n \"\"\"\n new_list = []\n for item in list1:\n new_list.append(element)\n new_list.append(item)\n return new_list", "matching_cluster_idx": 6}, {"solution": "def insert_element(list1, element):\n \"\"\"Inserts a given element before each element in a list.\n\n Args:\n list1: The input list.\n element: The element to insert.\n\n Returns:\n A new list with the element inserted before each existing element.\n \"\"\"\n new_list = []\n for i in list1:\n new_list.append(element)\n new_list.append(i)\n return new_list", "matching_cluster_idx": 6}, {"solution": "def insert_element(list1, element):\n new_list = []\n for item in list1:\n new_list.append(element)\n new_list.append(item)\n return new_list", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n \"\"\"Inserts a given element before each element in a list.\n\n Args:\n lst: The input list.\n element: The element to be inserted.\n\n Returns:\n A new list with the element inserted before each existing element.\n \"\"\"\n new_lst = []\n for item in lst:\n new_lst.append(element)\n new_lst.append(item)\n return new_lst", "matching_cluster_idx": 6}, {"solution": "def insert_element(list1, element):\n \"\"\"Inserts an element before each element in a list.\n Args:\n list1: The input list.\n element: The element to insert.\n Returns:\n A new list with the element inserted before each original element.\n \"\"\"\n new_list = []\n for item in list1:\n new_list.append(element)\n new_list.append(item)\n return new_list", "matching_cluster_idx": 6}, {"solution": "def insert_element(input_list, element):\n \"\"\"Inserts the given element before each element in the list.\n\n Args:\n input_list: The list to modify.\n element: The element to insert.\n\n Returns:\n A new list with the element inserted before each original element.\n \"\"\"\n result = []\n for item in input_list:\n result.extend([element, item])\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(input_list, element):\n \"\"\"\n This function inserts an element before each element in a list and returns the resulting list.\n\n Args:\n input_list: The input list.\n element: The element to be inserted.\n\n Returns:\n A new list with the element inserted before each original element.\n \"\"\"\n new_list = []\n for item in input_list:\n new_list.append(element)\n new_list.append(item)\n return new_list", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n \"\"\"Inserts a given element before each element in a list.\n\n Args:\n lst: The input list.\n element: The element to insert.\n\n Returns:\n A new list with the element inserted before each existing element.\n \"\"\"\n new_lst = []\n for item in lst:\n new_lst.append(element)\n new_lst.append(item)\n return new_lst", "matching_cluster_idx": 6}, {"solution": "def insert_element(list1, element):\n \"\"\"Inserts a given element before each element in a list.\n\n Args:\n list1: The input list.\n element: The element to be inserted.\n\n Returns:\n A new list with the element inserted before each element of the input list.\n \"\"\"\n new_list = []\n for i in list1:\n new_list.append(element)\n new_list.append(i)\n return new_list", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n \"\"\"Inserts an element before each element in a list.\n\n Args:\n lst: The input list.\n element: The element to insert.\n\n Returns:\n A new list with the element inserted before each element in the original list.\n \"\"\"\n new_lst = []\n for item in lst:\n new_lst.append(element)\n new_lst.append(item)\n return new_lst\nlst = ['Red', 'Green', 'Black']\nelement = 'c'", "matching_cluster_idx": 6}, {"solution": "def insert_element(input_list, element):\n \"\"\"\n Inserts a given element before each element in a list.\n\n Args:\n input_list: The list to modify.\n element: The element to insert.\n\n Returns:\n A new list with the element inserted before each existing element.\n \"\"\"\n new_list = []\n for item in input_list:\n new_list.append(element)\n new_list.append(item)\n return new_list", "matching_cluster_idx": 6}, {"solution": "def insert_element(input_list, element):\n \"\"\"Inserts the given element before each element in the input list.\n\n Args:\n input_list: A list of any type.\n element: The element to insert before each element in the list.\n\n Returns:\n A new list with the element inserted before each existing element.\n \"\"\"\n\n result = []\n for item in input_list:\n result.append(element)\n result.append(item)\n return result", "matching_cluster_idx": 6}]}, "Mbpp/256": {"dps": 93.9041095890411, "dps_norm": 85.88235294117646, "pass@1": 43.0, "profiled": [{"solution": "def count_Primes_nums(n):\n \"\"\"\n This function takes a non-negative number and returns the number of prime numbers less than the given number.\n \n Args:\n n: A non-negative integer.\n\n Returns:\n The number of prime numbers less than n.\n \"\"\"\n if n <= 1:\n return 0\n\n prime = [True] * n\n p = 2\n while p * p <= n:\n if prime[p]:\n for i in range(p * p, n, p):\n prime[i] = False\n p += 1\n\n count = 0\n for p in range(2, n):\n if prime[p]:\n count += 1\n\n return count", "matching_cluster_idx": 13}, {"solution": "def count_Primes_nums(n):\n \"\"\"\n Counts the number of prime numbers less than a given non-negative number.\n\n Args:\n n: A non-negative integer.\n\n Returns:\n The number of prime numbers less than n.\n \"\"\"\n\n if n <= 1:\n return 0\n\n primes = [True] * n\n primes[0] = primes[1] = False\n for i in range(2, int(n**0.5) + 1):\n if primes[i]:\n for j in range(i * i, n, i):\n primes[j] = False\n return sum(primes)", "matching_cluster_idx": 14}, {"solution": "def count_Primes_nums(n):\n \"\"\"\n Given a non-negative number, return the number of prime numbers less than the given non-negative number.\n :type n: int\n :rtype: int\n\n For example:\n count_Primes_nums(5) == 2\n \"\"\"\n if n <= 1:\n return 0\n\n primes = [True] * n\n primes[0] = primes[1] = False\n\n for i in range(2, int(n**0.5) + 1):\n if primes[i]:\n for j in range(i * i, n, i):\n primes[j] = False\n\n return sum(primes)", "matching_cluster_idx": 14}, {"solution": "def count_Primes_nums(n):\n \"\"\"\n This function takes in a non-negative number and returns the number\n of prime numbers less than the given non-negative number.\n\n For example:\n count_Primes_nums(5) == 2\n \"\"\"\n if n <= 1:\n return 0\n\n prime = [True] * n\n p = 2\n while (p * p <= n):\n if (prime[p] == True):\n for i in range(p * p, n, p):\n prime[i] = False\n p += 1\n \n count = 0\n for p in range(2, n):\n if prime[p]:\n count += 1\n return count", "matching_cluster_idx": 13}, {"solution": "def count_Primes_nums(n):\n \"\"\"\n Counts the number of prime numbers less than the given non-negative number.\n\n Args:\n n: A non-negative integer.\n\n Returns:\n The number of prime numbers less than n.\n \"\"\"\n if n <= 1:\n return 0\n\n primes = [True] * n\n primes[0] = primes[1] = False\n\n for i in range(2, int(n**0.5) + 1):\n if primes[i]:\n for j in range(i * i, n, i):\n primes[j] = False\n\n return sum(primes)", "matching_cluster_idx": 14}, {"solution": "def count_Primes_nums(n):\n \"\"\"\n Counts the number of prime numbers less than a given non-negative number.\n\n Args:\n n: A non-negative integer.\n\n Returns:\n The number of prime numbers less than n.\n \"\"\"\n \n def is_prime(num):\n if num <= 1:\n return False\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n return False\n return True\n\n count = 0\n for i in range(2, n):\n if is_prime(i):\n count += 1\n return count", "matching_cluster_idx": 8}, {"solution": "def count_Primes_nums(n):\n \"\"\"Counts the number of prime numbers less than the given non-negative number.\n\n Args:\n n: A non-negative integer.\n\n Returns:\n The number of prime numbers less than n.\n \"\"\"\n if n <= 1:\n return 0\n \n primes = [True] * n \n primes[0] = primes[1] = False \n\n for i in range(2, int(n**0.5) + 1):\n if primes[i]:\n for j in range(i * i, n, i):\n primes[j] = False\n \n return sum(primes)", "matching_cluster_idx": 14}, {"solution": "def count_Primes_nums(n):\n \"\"\"\n Counts the number of prime numbers less than the given non-negative number.\n \n Args:\n n: A non-negative integer.\n\n Returns:\n The number of prime numbers less than n.\n \"\"\"\n if n <= 1:\n return 0\n\n primes = [True] * n\n primes[0] = primes[1] = False\n\n for i in range(2, int(n**0.5) + 1):\n if primes[i]:\n for j in range(i * i, n, i):\n primes[j] = False\n \n return sum(primes)", "matching_cluster_idx": 14}, {"solution": "def count_Primes_nums(n):\n \"\"\"\n Counts the number of prime numbers less than a given non-negative number.\n\n Args:\n n: A non-negative integer.\n\n Returns:\n The number of prime numbers less than n.\n \"\"\"\n\n if n <= 1:\n return 0\n\n prime = [True] * n\n prime[0] = prime[1] = False\n\n for i in range(2, int(n ** 0.5) + 1):\n if prime[i]:\n for j in range(i * i, n, i):\n prime[j] = False\n\n return sum(prime)", "matching_cluster_idx": 14}, {"solution": "def count_Primes_nums(n):\n \"\"\"\n Counts the number of prime numbers less than the given non-negative number.\n\n Args:\n n: A non-negative integer.\n\n Returns:\n The number of prime numbers less than n.\n \"\"\"\n if n <= 1:\n return 0\n primes = [True] * n\n primes[0] = primes[1] = False\n for i in range(2, int(n**0.5) + 1):\n if primes[i]:\n for j in range(i * i, n, i):\n primes[j] = False\n return sum(primes)", "matching_cluster_idx": 14}, {"solution": "def count_Primes_nums(n):\n \"\"\"\n Counts the number of prime numbers less than a given non-negative number.\n\n Args:\n n: A non-negative integer.\n\n Returns:\n The number of prime numbers less than n.\n \"\"\"\n\n if n <= 1:\n return 0\n \n primes = [True] * n \n primes[0] = primes[1] = False\n \n for i in range(2, int(n**0.5) + 1):\n if primes[i]:\n for j in range(i * i, n, i):\n primes[j] = False\n\n return sum(primes)", "matching_cluster_idx": 14}, {"solution": "def count_Primes_nums(n):\n \"\"\"\n Counts the number of prime numbers less than the given non-negative number.\n\n Args:\n n: A non-negative integer.\n\n Returns:\n The number of prime numbers less than n.\n \"\"\"\n if n <= 1:\n return 0\n \n primes = [True] * n\n primes[0] = primes[1] = False\n\n for i in range(2, int(n ** 0.5) + 1):\n if primes[i]:\n for j in range(i * i, n, i):\n primes[j] = False\n\n return sum(primes)", "matching_cluster_idx": 14}, {"solution": "def count_Primes_nums(n):\n \"\"\"\n Counts the number of prime numbers less than a given non-negative number.\n\n Args:\n n: A non-negative integer.\n\n Returns:\n The number of prime numbers less than n.\n \"\"\"\n\n if n <= 1:\n return 0\n\n primes = [True] * n\n primes[0] = primes[1] = False\n for i in range(2, int(n**0.5) + 1):\n if primes[i]:\n for j in range(i * i, n, i):\n primes[j] = False\n\n return sum(primes)", "matching_cluster_idx": 14}, {"solution": "def count_Primes_nums(n):\n \"\"\"\n Counts the number of prime numbers less than the given non-negative number.\n\n Args:\n n: A non-negative integer.\n\n Returns:\n The number of prime numbers less than n.\n \"\"\"\n if n <= 1:\n return 0\n\n primes = [True] * n\n primes[0] = primes[1] = False\n\n for i in range(2, int(n**0.5) + 1):\n if primes[i]:\n for j in range(i * i, n, i):\n primes[j] = False\n \n return sum(primes)", "matching_cluster_idx": 14}, {"solution": "def count_Primes_nums(n):\n \"\"\"\n Counts the number of prime numbers less than the given non-negative number.\n\n Args:\n n: A non-negative integer.\n\n Returns:\n The number of prime numbers less than n.\n \"\"\"\n\n if n <= 1:\n return 0\n\n primes = [True] * n\n primes[0] = primes[1] = False\n\n for i in range(2, int(n**0.5) + 1):\n if primes[i]:\n for j in range(i * i, n, i):\n primes[j] = False\n\n return sum(primes)", "matching_cluster_idx": 14}, {"solution": "def count_Primes_nums(n):\n \"\"\"\n This function counts the number of prime numbers less than a given non-negative number.\n\n Args:\n n: A non-negative integer.\n\n Returns:\n The number of prime numbers less than n.\n \"\"\"\n if n <= 1:\n return 0\n primes = [True] * n\n primes[0] = primes[1] = False\n for i in range(2, int(n**0.5) + 1):\n if primes[i]:\n for j in range(i * i, n, i):\n primes[j] = False\n return sum(primes)", "matching_cluster_idx": 14}, {"solution": "def count_Primes_nums(n: int) -> int:\n \"\"\"\n Write a python function that takes in a non-negative number and returns the number of prime numbers less than the given non-negative number.\n\n assert count_Primes_nums(5) == 2\n \"\"\"\n if n <= 1:\n return 0\n \n primes = [True] * n\n primes[0] = primes[1] = False\n\n for i in range(2, int(n ** 0.5) + 1):\n if primes[i]:\n for j in range(i * i, n, i):\n primes[j] = False\n\n return sum(primes)", "matching_cluster_idx": 14}, {"solution": "def count_Primes_nums(n):\n \"\"\"\n Counts the number of prime numbers less than the given non-negative number.\n\n Args:\n n: A non-negative integer.\n\n Returns:\n The number of prime numbers less than n.\n \"\"\"\n if n <= 1:\n return 0\n primes = [True] * n\n primes[0] = primes[1] = False\n for i in range(2, int(n ** 0.5) + 1):\n if primes[i]:\n for j in range(i * i, n, i):\n primes[j] = False\n return sum(primes)", "matching_cluster_idx": 14}, {"solution": "def count_Primes_nums(n):\n \"\"\"\n This function takes in a non-negative number and returns the number of prime numbers less than the given non-negative number.\n\n Args:\n n: A non-negative integer.\n\n Returns:\n The number of prime numbers less than n.\n \"\"\"\n if n <= 1:\n return 0\n primes = [True] * n\n primes[0] = primes[1] = False\n for i in range(2, int(n ** 0.5) + 1):\n if primes[i]:\n for j in range(i * i, n, i):\n primes[j] = False\n return sum(primes)", "matching_cluster_idx": 14}, {"solution": "def count_Primes_nums(n):\n \"\"\"\n Counts the number of prime numbers less than the given non-negative number.\n\n Args:\n n: A non-negative integer.\n\n Returns:\n The number of prime numbers less than n.\n \"\"\"\n if n <= 1:\n return 0\n \n primes = [True] * n\n primes[0] = primes[1] = False\n\n for i in range(2, int(n**0.5) + 1):\n if primes[i]:\n for j in range(i * i, n, i):\n primes[j] = False\n\n return sum(primes)", "matching_cluster_idx": 14}]}, "Mbpp/265": {"dps": 75.29069767441861, "dps_norm": 85.83333333333333, "pass@1": 91.0, "profiled": [{"solution": "def list_split(lst, n):\n \"\"\"\n Splits a list for every nth element.\n\n Args:\n lst: The input list.\n n: The interval for splitting the list.\n\n Returns:\n A list of lists, where each sublist contains elements from the input list,\n spaced n elements apart.\n \"\"\"\n\n return [lst[i::n] for i in range(n)]\nn = 3", "matching_cluster_idx": 4}, {"solution": "def list_split(input_list, n):\n \"\"\"\n Splits a list for every nth element.\n\n Args:\n input_list: The input list to be split.\n n: The interval at which to split the list.\n\n Returns:\n A list of lists, where each sub-list contains elements from the input list \n at intervals of n.\n \"\"\"\n return [input_list[i::n] for i in range(n)]\nn = 3", "matching_cluster_idx": 4}, {"solution": "def list_split(l, n):\n \"\"\"\n Splits a list for every nth element.\n\n Args:\n l: The list to split.\n n: The interval at which to split the list.\n\n Returns:\n A list of lists, where each sublist contains every nth element from the original list.\n \"\"\"\n return [l[i::n] for i in range(n)]", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n \"\"\"Splits a list into sub-lists every nth element.\n\n Args:\n lst: The list to be split.\n n: The number of elements per sub-list.\n\n Returns:\n A list of sub-lists.\n \"\"\"\n return [lst[i::n] for i in range(n)]", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n \"\"\"Splits a list into sublists of every nth element.\n\n Args:\n lst: The input list.\n n: The interval for splitting the list.\n\n Returns:\n A list of sublists, each containing every nth element.\n \"\"\"\n return [lst[i::n] for i in range(n)]", "matching_cluster_idx": 4}, {"solution": "def list_split(data, n):\n \"\"\"\n Splits a list into sublists every nth element.\n\n Args:\n data: The input list to be split.\n n: The interval for splitting the list.\n\n Returns:\n A list of sublists.\n \"\"\"\n return [data[i::n] for i in range(n)]", "matching_cluster_idx": 4}, {"solution": "def list_split(data, n):\n \"\"\"Splits a list for every nth element.\"\"\"\n return [data[i::n] for i in range(n)]", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n \"\"\"Splits a list for every nth element.\n\n Args:\n lst: The list to split.\n n: The interval at which to split the list.\n\n Returns:\n A list of lists, where each sublist contains every nth element from the input list.\n \"\"\"\n\n return [lst[i::n] for i in range(n)]", "matching_cluster_idx": 4}, {"solution": "def list_split(input_list, n):\n \"\"\"\n Splits a list into sublists of size n.\n\n Args:\n input_list: The list to be split.\n n: The size of each sublist.\n\n Returns:\n A list of sublists, each of size n (except possibly the last one).\n \"\"\"\n return [input_list[i::n] for i in range(n)]", "matching_cluster_idx": 4}, {"solution": "def list_split(data, n):\n \"\"\"Splits a list into sublists every nth element.\n\n Args:\n data: The input list to split.\n n: The interval at which to split the list.\n\n Returns:\n A list of sublists, each containing every nth element from the input list.\n \"\"\"\n return [data[i::n] for i in range(n)]\ndata = ['a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j', 'k', 'l', 'm', 'n']\nn = 3", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n \"\"\"\n Splits a list for every nth element.\n\n Args:\n lst: The input list to be split.\n n: The interval at which to split the list.\n\n Returns:\n A list of lists, each containing elements from the input list at intervals of n.\n \"\"\"\n return [lst[i::n] for i in range(n)]", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n \"\"\"\n Splits a list for every nth element.\n\n Args:\n lst (list): The list to be split.\n n (int): The number of elements per sub-list.\n\n Returns:\n list: A list of lists, where each sub-list contains every nth element from the original list.\n \"\"\"\n return [lst[i::n] for i in range(n)]", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n \"\"\"Splits a list into sublists of length n.\n\n Args:\n lst: The list to be split.\n n: The length of each sublist.\n\n Returns:\n A list of sublists.\n \"\"\"\n return [lst[i::n] for i in range(n)]", "matching_cluster_idx": 4}, {"solution": "def list_split(data, n):\n \"\"\"\n Splits a list for every nth element.\n\n Args:\n data: The list to be split.\n n: The interval at which to split the list.\n\n Returns:\n A list of lists, where each sub-list contains every nth element from the original list.\n \"\"\"\n return [data[i::n] for i in range(n)]", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n \"\"\"\n Splits a list for every nth element.\n\n Args:\n lst: The input list.\n n: The interval at which to split the list.\n\n Returns:\n A list of lists, where each sublist contains every nth element from the input list.\n \"\"\"\n return [lst[i::n] for i in range(n)]", "matching_cluster_idx": 4}, {"solution": "def list_split(input_list, n):\n \"\"\"Splits a list into sublists every nth element.\n\n Args:\n input_list: The list to split.\n n: The interval for splitting.\n\n Returns:\n A list of sublists.\n \"\"\"\n return [input_list[i::n] for i in range(n)]", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n \"\"\"\n Splits a list for every nth element, returning a list of the resulting lists.\n\n Args:\n lst: The list to split.\n n: The interval for splitting the list.\n\n Returns:\n A list of lists, where each inner list contains elements from the original\n list at intervals of n.\n \"\"\"\n return [lst[i::n] for i in range(n)]", "matching_cluster_idx": 4}, {"solution": "def list_split(input_list, n):\n \"\"\"Splits a list into sublists of length n.\n\n Args:\n input_list: The list to be split.\n n: The length of each sublist.\n\n Returns:\n A list of sublists.\n \"\"\"\n return [input_list[i::n] for i in range(n)]", "matching_cluster_idx": 5}, {"solution": "def list_split(input_list, n):\n \"\"\"\n Splits a list into sublists of size n.\n\n Args:\n input_list: The list to be split.\n n: The desired size of each sublist.\n\n Returns:\n A list of sublists.\n \"\"\"\n return [input_list[i::n] for i in range(n)]", "matching_cluster_idx": 5}, {"solution": "def list_split(lst, n):\n \"\"\"Splits a list for every nth element, returning a list of the resulting lists.\"\"\"\n return [lst[i::n] for i in range(n)]", "matching_cluster_idx": 5}]}, "Mbpp/281": {"dps": 94.3, "dps_norm": 82.72727272727272, "pass@1": 100.0, "profiled": [{"solution": "def all_unique(lst):\n \"\"\"\n Checks if the elements of a given list are unique.\n\n Args:\n lst: A list of elements.\n\n Returns:\n True if all elements are unique, False otherwise.\n \"\"\"\n return len(set(lst)) == len(lst)", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n Checks if the elements of a given list are unique.\n\n Args:\n lst: A list of elements.\n\n Returns:\n True if all elements are unique, False otherwise.\n \"\"\"\n return len(set(lst)) == len(lst)", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n Checks if all elements in a list are unique.\n\n Args:\n lst: The list to check.\n\n Returns:\n True if all elements are unique, False otherwise.\n \"\"\"\n return len(set(lst)) == len(lst)", "matching_cluster_idx": 8}, {"solution": "def all_unique(data):\n \"\"\"\n Checks if all elements in a list are unique.\n\n Args:\n data (list): The input list.\n\n Returns:\n bool: True if all elements are unique, False otherwise.\n \"\"\"\n return len(set(data)) == len(data)", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"Checks if all elements in a list are unique.\n\n Args:\n lst: A list of elements.\n\n Returns:\n True if all elements are unique, False otherwise.\n \"\"\"\n return len(set(lst)) == len(lst)", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n Checks if all elements in a list are unique.\n\n Args:\n lst: A list of elements.\n\n Returns:\n True if all elements are unique, False otherwise.\n \"\"\"\n return len(set(lst)) == len(lst)", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n Checks if the elements of a given list are unique.\n\n Args:\n lst: A list of elements.\n\n Returns:\n True if all elements in the list are unique, False otherwise.\n \"\"\"\n return len(set(lst)) == len(lst)", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n Checks if the elements of a given list are unique.\n Args:\n lst: A list of elements.\n Returns:\n True if all elements are unique, False otherwise.\n \"\"\"\n return len(set(lst)) == len(lst)", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n Checks if all elements in a list are unique.\n\n Args:\n lst: A list of elements.\n\n Returns:\n True if all elements are unique, False otherwise.\n \"\"\"\n return len(set(lst)) == len(lst)", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n Checks if all elements in a list are unique.\n\n Args:\n lst: A list of elements.\n\n Returns:\n True if all elements are unique, False otherwise.\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"Checks if all elements in a list are unique.\n\n Args:\n lst: The input list.\n\n Returns:\n True if all elements are unique, False otherwise.\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n Check if all elements in a list are unique.\n\n Args:\n lst: A list of elements.\n\n Returns:\n True if all elements are unique, False otherwise.\n \"\"\"\n return len(set(lst)) == len(lst)", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n Checks if all elements in a list are unique.\n\n Args:\n lst: The list to check.\n\n Returns:\n True if all elements are unique, False otherwise.\n \"\"\"\n return len(set(lst)) == len(lst)", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n Checks if the elements of a given list are unique.\n\n Args:\n lst: A list of elements.\n\n Returns:\n True if all elements in the list are unique, False otherwise.\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n Checks if all elements in a list are unique.\n\n Args:\n lst: A list of elements.\n\n Returns:\n True if all elements are unique, False otherwise.\n \"\"\"\n\n seen = set()\n for item in lst:\n if item in seen:\n return False\n seen.add(item)\n return True", "matching_cluster_idx": 10}, {"solution": "def all_unique(lst):\n \"\"\"\n Checks if all elements in a list are unique.\n\n Args:\n lst: A list of elements.\n\n Returns:\n True if all elements are unique, False otherwise.\n \"\"\"\n return len(set(lst)) == len(lst)", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n Checks if all elements in a given list are unique.\n\n Args:\n lst: A list of elements.\n\n Returns:\n True if all elements are unique, False otherwise.\n \"\"\"\n return len(set(lst)) == len(lst)", "matching_cluster_idx": 8}, {"solution": "def all_unique(input_list):\n \"\"\"\n Checks if the elements of a given list are unique.\n\n Args:\n input_list: A list of elements to check for uniqueness.\n\n Returns:\n True if all elements in the list are unique, False otherwise.\n \"\"\"\n return len(set(input_list)) == len(input_list)", "matching_cluster_idx": 8}, {"solution": "def all_unique(data):\n \"\"\"\n Checks if the elements of a given list are unique.\n\n Args:\n data: A list of elements.\n\n Returns:\n True if all elements are unique, False otherwise.\n \"\"\"\n return len(data) == len(set(data))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n Checks if all elements in a list are unique.\n\n Args:\n lst: A list of elements.\n\n Returns:\n True if all elements are unique, False otherwise.\n \"\"\"\n return len(set(lst)) == len(lst)", "matching_cluster_idx": 8}]}, "Mbpp/296": {"dps": 26.41025641025641, "dps_norm": 64.16666666666667, "pass@1": 98.0, "profiled": [{"solution": "def get_Inv_Count(arr):\n \"\"\"Counts inversions in an array.\n\n An inversion in an array occurs when two elements are out of order.\n\n Args:\n arr: A list of integers.\n\n Returns:\n The number of inversions in the array.\n \"\"\"\n inv_count = 0\n n = len(arr)\n for i in range(n):\n for j in range(i + 1, n):\n if arr[i] > arr[j]:\n inv_count += 1\n return inv_count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n \"\"\"\n Counts the number of inversions in an array.\n\n An inversion is a pair of elements (i, j) in the array such that i < j and arr[i] > arr[j].\n\n Args:\n arr: A list of integers.\n\n Returns:\n The number of inversions in the array.\n \"\"\"\n count = 0\n for i in range(len(arr)):\n for j in range(i + 1, len(arr)):\n if arr[i] > arr[j]:\n count += 1\n return count\narr = [1, 20, 6, 4, 5]", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n \"\"\"\n Counts the number of inversions in an array.\n\n An inversion is a pair (i, j) where i < j and arr[i] > arr[j].\n\n Args:\n arr: The input array.\n\n Returns:\n The number of inversions in the array.\n \"\"\"\n\n count = 0\n n = len(arr)\n for i in range(n):\n for j in range(i + 1, n):\n if arr[i] > arr[j]:\n count += 1\n return count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n \"\"\"\n Counts the number of inversions in an array.\n\n An inversion is a pair of indices (i, j) where i < j and arr[i] > arr[j].\n \n Args:\n arr: A list of integers.\n\n Returns:\n The number of inversions in the array.\n \"\"\"\n count = 0\n for i in range(len(arr)):\n for j in range(i + 1, len(arr)):\n if arr[i] > arr[j]:\n count += 1\n return count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n \"\"\"\n This function counts the number of inversions in an array.\n\n An inversion in an array occurs when an element appears before another element that is smaller than it.\n For example, in the array [1, 20, 6, 4, 5], there are 5 inversions:\n (20, 6), (20, 4), (20, 5), (6, 4), (6, 5).\n\n Args:\n arr: A list of integers.\n\n Returns:\n The number of inversions in the array.\n \"\"\"\n\n inv_count = 0\n for i in range(len(arr)):\n for j in range(i + 1, len(arr)):\n if arr[i] > arr[j]:\n inv_count += 1\n return inv_count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n \"\"\"\n Counts the number of inversions in an array.\n\n An inversion is a pair of indices (i, j) such that i < j and arr[i] > arr[j].\n\n Args:\n arr: A list of integers.\n\n Returns:\n The number of inversions in the array.\n \"\"\"\n n = len(arr)\n inv_count = 0\n for i in range(n):\n for j in range(i + 1, n):\n if arr[i] > arr[j]:\n inv_count += 1\n return inv_count\narr = [1, 20, 6, 4, 5]", "matching_cluster_idx": 2}, {"solution": "def get_Inv_Count(arr):\n \"\"\"\n Counts the number of inversions in an array.\n\n An inversion occurs when two elements are out of order (i.e., \n a[i] > a[j] where i < j).\n\n Args:\n arr: A list of integers.\n\n Returns:\n The number of inversions in the array.\n \"\"\"\n count = 0\n n = len(arr)\n for i in range(n):\n for j in range(i+1, n):\n if arr[i] > arr[j]:\n count += 1\n return count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n \"\"\"\n Counts the number of inversions in an array.\n An inversion is a pair of indices (i, j) in an array where i < j but arr[i] > arr[j].\n\n Args:\n arr: The input array.\n\n Returns:\n The number of inversions in the array.\n \"\"\"\n inversion_count = 0\n for i in range(len(arr)):\n for j in range(i + 1, len(arr)):\n if arr[i] > arr[j]:\n inversion_count += 1\n return inversion_count", "matching_cluster_idx": 2}, {"solution": "def get_Inv_Count(arr):\n \"\"\"\n Counts the number of inversions in an array.\n\n An inversion occurs when a pair of elements (arr[i], arr[j]) exists where i < j and arr[i] > arr[j].\n\n Args:\n arr: The input array.\n\n Returns:\n The number of inversions in the array.\n \"\"\"\n\n count = 0\n for i in range(len(arr)):\n for j in range(i + 1, len(arr)):\n if arr[i] > arr[j]:\n count += 1\n return count\narr = [1, 20, 6, 4, 5]", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n \"\"\"\n Counts inversions in an array.\n\n An inversion occurs when an element at index i is greater than an element at index j where i < j.\n\n Args:\n arr: A list of integers.\n\n Returns:\n The number of inversions in the array.\n \"\"\"\n\n count = 0\n n = len(arr)\n for i in range(n):\n for j in range(i + 1, n):\n if arr[i] > arr[j]:\n count += 1\n return count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n \"\"\"\n Function to count inversions in an array.\n\n Args:\n arr: A list of integers.\n\n Returns:\n The number of inversions in the array.\n\n An inversion is defined as a pair (i, j) where 1 <= i < j <= n and arr[i] > arr[j].\n \"\"\"\n count = 0\n for i in range(len(arr)):\n for j in range(i + 1, len(arr)):\n if arr[i] > arr[j]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def merge_sort_and_count_inversions(arr):\n if len(arr) <= 1:\n return arr, 0\n\n mid = len(arr) // 2\n left, left_inversions = merge_sort_and_count_inversions(arr[:mid])\n right, right_inversions = merge_sort_and_count_inversions(arr[mid:])\n merged, merge_inversions = merge_and_count_inversions(left, right)\n\n return merged, left_inversions + right_inversions + merge_inversions\ndef merge_and_count_inversions(left, right):\n merged = []\n i = 0\n j = 0\n inversions = 0\n\n while i < len(left) and j < len(right):\n if left[i] <= right[j]:\n merged.append(left[i])\n i += 1\n else:\n merged.append(right[j])\n j += 1\n inversions += len(left) - i # Count inversions\n\n merged.extend(left[i:])\n merged.extend(right[j:])\n return merged, inversions\ndef get_Inv_Count(arr):\n _, inv_count = merge_sort_and_count_inversions(arr)\n return inv_count", "matching_cluster_idx": 5}, {"solution": "def get_Inv_Count(arr):\n \"\"\"\n This function counts the number of inversions in an array.\n\n An inversion in an array happens when a pair of elements (i, j) satisfies i < j\n but arr[i] > arr[j].\n\n Args:\n arr: A list of integers.\n\n Returns:\n The number of inversions in the array.\n \"\"\"\n count = 0\n for i in range(len(arr)):\n for j in range(i+1, len(arr)):\n if arr[i] > arr[j]:\n count += 1\n return count\narr = [1, 20, 6, 4, 5]", "matching_cluster_idx": 2}, {"solution": "def get_Inv_Count(arr):\n \"\"\"\n Counts inversions in an array using a merge sort approach.\n\n Args:\n arr: The input array.\n\n Returns:\n The number of inversions in the array.\n \"\"\"\n inversion_count = 0\n\n def merge_and_count(left, right):\n nonlocal inversion_count\n merged = []\n i = j = 0\n while i < len(left) and j < len(right):\n if left[i] <= right[j]:\n merged.append(left[i])\n i += 1\n else:\n merged.append(right[j])\n j += 1\n inversion_count += len(left) - i\n\n while i < len(left):\n merged.append(left[i])\n i += 1\n while j < len(right):\n merged.append(right[j])\n j += 1\n return merged\n\n def merge_sort(arr):\n if len(arr) <= 1:\n return arr\n mid = len(arr) // 2\n left = merge_sort(arr[:mid])\n right = merge_sort(arr[mid:])\n return merge_and_count(left, right)\n\n merge_sort(arr)\n return inversion_count", "matching_cluster_idx": 5}, {"solution": "def get_Inv_Count(arr):\n \"\"\"\n This function counts the number of inversions in an array.\n\n An inversion in an array occurs when a pair of elements (a[i], a[j])\n satisfies the condition i < j and a[i] > a[j].\n\n Args:\n arr: A list of integers.\n\n Returns:\n The number of inversions in the array.\n \"\"\"\n n = len(arr)\n inv_count = 0\n for i in range(n):\n for j in range(i+1, n):\n if arr[i] > arr[j]:\n inv_count += 1\n return inv_count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n \"\"\"\n Counts the number of inversions in an array.\n\n An inversion is a pair of indices (i, j) in the array such that i < j and arr[i] > arr[j].\n\n Args:\n arr: A list of integers.\n\n Returns:\n The number of inversions in the array.\n \"\"\"\n\n count = 0\n for i in range(len(arr)):\n for j in range(i + 1, len(arr)):\n if arr[i] > arr[j]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def get_Inv_Count(arr):\n \"\"\"\n Counts the number of inversions in an array.\n\n An inversion is a pair of indices (i, j) where i < j and arr[i] > arr[j].\n\n Args:\n arr: A list of integers.\n\n Returns:\n The number of inversions in the array.\n \"\"\"\n inv_count = 0\n for i in range(len(arr)):\n for j in range(i + 1, len(arr)):\n if arr[i] > arr[j]:\n inv_count += 1\n return inv_count\narr = [1, 20, 6, 4, 5]", "matching_cluster_idx": 2}, {"solution": "def get_Inv_Count(arr):\n \"\"\"\n Counts inversions in an array.\n\n An inversion occurs when an element at a lower index is greater than an element \n at a higher index in the array.\n\n Args:\n arr: A list of integers.\n\n Returns:\n The number of inversions in the array.\n \"\"\"\n count = 0\n for i in range(len(arr)):\n for j in range(i+1, len(arr)):\n if arr[i] > arr[j]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def get_Inv_Count(arr):\n \"\"\"\n Counts inversions in an array.\n\n An inversion occurs when two elements in an array are out of order, meaning \n their indices are in increasing order, but their values are in decreasing order.\n\n For example:\n [1, 20, 6, 4, 5] has 5 inversions:\n (20, 6), (20, 4), (20, 5), (6, 4), (6, 5)\n\n Args:\n arr: A list of integers\n\n Returns:\n The number of inversions in the array.\n \"\"\"\n inversion_count = 0\n n = len(arr)\n for i in range(n):\n for j in range(i+1, n):\n if arr[i] > arr[j]:\n inversion_count += 1\n return inversion_count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n \"\"\"\n Counts inversions in an array.\n\n An inversion is a pair (i, j) where i < j and arr[i] > arr[j].\n\n Args:\n arr: The input array.\n\n Returns:\n The number of inversions in the array.\n \"\"\"\n inversion_count = 0\n n = len(arr)\n for i in range(n):\n for j in range(i + 1, n):\n if arr[i] > arr[j]:\n inversion_count += 1\n return inversion_count", "matching_cluster_idx": 3}]}, "Mbpp/308": {"dps": 94.27586206896552, "dps_norm": 65.83333333333334, "pass@1": 88.0, "profiled": [{"solution": "def large_product(list1, list2, n):\n \"\"\"\n Finds the specified number of largest products from two given lists, selecting one factor from each list.\n\n Args:\n list1: The first list of numbers.\n list2: The second list of numbers.\n n: The number of largest products to return.\n\n Returns:\n A list containing the n largest products.\n \"\"\"\n\n products = [(x * y, x, y) for x in list1 for y in list2] # Calculate all products and store with original factors\n products.sort(reverse=True) # Sort products in descending order\n return [product for product, _, _ in products[:n]] # Extract only the product values from the n largest", "matching_cluster_idx": 2}, {"solution": "def large_product(list1, list2, n):\n \"\"\"\n Finds the specified number of largest products from two given lists, selecting one factor from each list.\n\n Args:\n list1: The first list of numbers.\n list2: The second list of numbers.\n n: The number of largest products to find.\n\n Returns:\n A list of the n largest products.\n \"\"\"\n products = []\n for x in list1:\n for y in list2:\n products.append(x*y)\n return sorted(products, reverse=True)[:n]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n \"\"\"\n Finds the specified number of largest products from two given lists,\n selecting one factor from each list.\n\n Args:\n list1: The first list of numbers.\n list2: The second list of numbers.\n n: The number of largest products to return.\n\n Returns:\n A list containing the n largest products, sorted in descending order.\n \"\"\"\n\n products = [x * y for x in list1 for y in list2]\n return sorted(products, reverse=True)[:n]", "matching_cluster_idx": 3}, {"solution": "from heapq import nlargest\ndef large_product(list1, list2, n):\n \"\"\"\n Finds the specified number of largest products from two given lists,\n selecting one factor from each list.\n\n Args:\n list1: The first list of numbers.\n list2: The second list of numbers.\n n: The number of largest products to return.\n\n Returns:\n A list containing the n largest products, sorted in descending order.\n \"\"\"\n products = [x * y for x in list1 for y in list2]\n return nlargest(n, products)", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n \"\"\"\n Finds the specified number of largest products from two given lists,\n selecting one factor from each list.\n \n Args:\n list1: The first list of numbers.\n list2: The second list of numbers.\n n: The number of largest products to find.\n\n Returns:\n A list of the n largest products.\n \"\"\"\n products = []\n for x in list1:\n for y in list2:\n products.append(x * y)\n return sorted(products, reverse=True)[:n]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n \"\"\"\n Finds the specified number of largest products from two given lists,\n selecting one factor from each list.\n\n Args:\n list1: The first list of numbers.\n list2: The second list of numbers.\n n: The number of largest products to find.\n\n Returns:\n A list containing the n largest products, sorted in descending order.\n \"\"\"\n products = []\n for num1 in list1:\n for num2 in list2:\n products.append(num1 * num2)\n return sorted(products, reverse=True)[:n]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n \"\"\"\n Finds the specified number of largest products from two given lists,\n selecting one factor from each list.\n\n Args:\n list1: The first list of numbers.\n list2: The second list of numbers.\n n: The number of largest products to return.\n\n Returns:\n A list of the n largest products, sorted in descending order.\n \"\"\"\n products = []\n for x in list1:\n for y in list2:\n products.append(x * y)\n return sorted(products, reverse=True)[:n]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n \"\"\"\n Finds the specified number of largest products from two given lists,\n selecting one factor from each list.\n\n Args:\n list1: The first list of integers.\n list2: The second list of integers.\n n: The number of largest products to return.\n\n Returns:\n A list containing the n largest products, sorted in descending order.\n \"\"\"\n products = [x * y for x in list1 for y in list2]\n return sorted(products, reverse=True)[:n]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, num_products):\n \"\"\"Finds the specified number of largest products from two lists, selecting one factor from each list.\n\n Args:\n list1: The first list of numbers.\n list2: The second list of numbers.\n num_products: The number of largest products to return.\n\n Returns:\n A sorted list of the specified number of largest products.\n \"\"\"\n\n products = sorted([(x * y) for x in list1 for y in list2], reverse=True)\n return products[:num_products]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n \"\"\"\n Finds the specified number of largest products from two given lists, \n selecting one factor from each list.\n\n Args:\n list1: The first list of numbers.\n list2: The second list of numbers.\n n: The number of largest products to return.\n\n Returns:\n A list of the n largest products.\n \"\"\"\n\n products = []\n for x in list1:\n for y in list2:\n products.append(x * y)\n return sorted(products, reverse=True)[:n]\nlist1 = [1, 2, 3, 4, 5, 6]\nlist2 = [3, 6, 8, 9, 10, 6]\nn = 3", "matching_cluster_idx": 3}, {"solution": "def large_product(nums1, nums2, n):\n \"\"\"\n Find the specified number of largest products from two given lists,\n selecting one factor from each list.\n\n Args:\n nums1: The first list of numbers.\n nums2: The second list of numbers.\n n: The number of largest products to return.\n\n Returns:\n A list of the n largest products.\n \"\"\"\n\n products = [num1 * num2 for num1 in nums1 for num2 in nums2]\n return sorted(products, reverse=True)[:n]\nnums1 = [1, 2, 3, 4, 5, 6]\nnums2 = [3, 6, 8, 9, 10, 6]\nn = 3", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n \"\"\"\n Finds the specified number of largest products from two given lists, \n selecting one factor from each list.\n\n Args:\n list1: The first list of numbers.\n list2: The second list of numbers.\n n: The number of largest products to find.\n\n Returns:\n A list of the n largest products, sorted in descending order.\n \"\"\"\n products = []\n for num1 in list1:\n for num2 in list2:\n products.append(num1 * num2)\n return sorted(products, reverse=True)[:n]\nlist1 = [1, 2, 3, 4, 5, 6]\nlist2 = [3, 6, 8, 9, 10, 6]\nn = 3", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n \"\"\"\n Finds the specified number of largest products from two given lists,\n selecting one factor from each list.\n\n Args:\n list1: The first list of numbers.\n list2: The second list of numbers.\n n: The number of largest products to find.\n\n Returns:\n A list of the n largest products, sorted in descending order.\n \"\"\"\n products = [x * y for x in list1 for y in list2] \n products.sort(reverse=True) \n return products[:n]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n \"\"\"\n Finds the specified number of largest products from two given lists, selecting one factor from each list.\n\n Args:\n list1: The first list of numbers.\n list2: The second list of numbers.\n n: The number of largest products to return.\n\n Returns:\n A list containing the n largest products.\n \"\"\"\n products = sorted([(x * y) for x in list1 for y in list2], reverse=True)\n return products[:n]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n \"\"\"Finds the specified number of largest products from two lists, selecting one\n factor from each list.\n\n Args:\n list1: The first list of numbers.\n list2: The second list of numbers.\n n: The number of largest products to find.\n\n Returns:\n A list of the n largest products, sorted in descending order.\n \"\"\"\n\n products = [x * y for x in list1 for y in list2]\n return sorted(products, reverse=True)[:n]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n \"\"\"\n Finds the specified number of largest products from two given lists,\n selecting one factor from each list.\n\n Args:\n list1: The first list of numbers.\n list2: The second list of numbers.\n n: The number of largest products to return.\n\n Returns:\n A list containing the n largest products.\n \"\"\"\n\n products = []\n for num1 in list1:\n for num2 in list2:\n products.append(num1 * num2)\n\n return sorted(products, reverse=True)[:n]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n \"\"\"Finds the specified number of largest products from two given lists,\n selecting one factor from each list.\n\n Args:\n list1: The first list of numbers.\n list2: The second list of numbers.\n n: The number of largest products to find.\n\n Returns:\n A list of the n largest products, sorted in descending order.\n \"\"\"\n\n from itertools import product\n\n products = [x * y for x, y in product(list1, list2)]\n return sorted(products, reverse=True)[:n]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n \"\"\"\n Finds the specified number of largest products from two given lists,\n selecting one factor from each list.\n\n Args:\n list1: The first list of numbers.\n list2: The second list of numbers.\n n: The number of largest products to find.\n\n Returns:\n A sorted list containing the n largest products.\n \"\"\"\n products = [x * y for x in list1 for y in list2]\n return sorted(products, reverse=True)[:n]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, num_products):\n \"\"\"\n Finds the specified number of largest products from two given lists, selecting one factor from each list.\n\n Args:\n list1: The first list of numbers.\n list2: The second list of numbers.\n num_products: The number of largest products to find.\n\n Returns:\n A list containing the num_products largest products, sorted in descending order.\n \"\"\"\n\n products = []\n for x in list1:\n for y in list2:\n products.append(x*y)\n return sorted(products, reverse=True)[:num_products]\nlist1 = [1, 2, 3, 4, 5, 6]\nlist2 = [3, 6, 8, 9, 10, 6]\nnum_products = 3", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n \"\"\"\n Finds the specified number of largest products from two given lists, selecting one factor from each list.\n\n Args:\n list1: The first list of numbers.\n list2: The second list of numbers.\n n: The number of largest products to return.\n\n Returns:\n A list of the n largest products, in descending order.\n \"\"\"\n products = [x * y for x in list1 for y in list2]\n return sorted(products, reverse=True)[:n]", "matching_cluster_idx": 3}]}, "Mbpp/392": {"dps": 93.6150234741784, "dps_norm": 97.3076923076923, "pass@1": 93.0, "profiled": [{"solution": "def get_max_sum(n):\n \"\"\"\n Finds the maximum sum possible using the equation f(n) = max((f(n/2) + f(n/3) + f(n/4) + f(n/5)), n).\n\n Args:\n n: An integer.\n\n Returns:\n The maximum sum possible.\n \"\"\"\n \n memo = {} # Use memoization to store already calculated results\n\n def calculate_max_sum(num):\n if num in memo:\n return memo[num]\n if num <= 0:\n return 0\n \n memo[num] = max(calculate_max_sum(num // 2) + calculate_max_sum(num // 3) + calculate_max_sum(num // 4) + calculate_max_sum(num // 5), num)\n return memo[num]\n\n return calculate_max_sum(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n \"\"\"\n This function calculates the maximum sum possible using the equation f(n) = max( (f(n/2) + f(n/3) + f(n/4) + f(n/5)), n).\n\n Args:\n n: An integer.\n\n Returns:\n The maximum sum possible for the given integer.\n \"\"\"\n memo = {} # Use a dictionary to memoize results for efficiency\n\n def helper(n):\n if n in memo:\n return memo[n]\n if n <= 0:\n return 0\n memo[n] = max(helper(n // 2) + helper(n // 3) + helper(n // 4) + helper(n // 5), n)\n return memo[n]\n return helper(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n \"\"\"\n Calculates the maximum sum possible using the given equation:\n f(n) = max( (f(n/2) + f(n/3) + f(n/4) + f(n/5)), n)\n\n Args:\n n (int): The input integer.\n\n Returns:\n int: The maximum sum possible for the given input.\n \"\"\"\n memo = {} # Use a dictionary for memoization to store calculated values\n\n def helper(n):\n if n in memo:\n return memo[n]\n\n if n <= 0:\n return 0\n if n == 1:\n return 1\n\n memo[n] = max(helper(int(n / 2)) + helper(int(n / 3)) + helper(int(n / 4)) + helper(int(n / 5)), n)\n return memo[n]\n\n return helper(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n \"\"\"\n Finds the maximum sum possible by using the equation f(n) = max((f(n/2) + f(n/3) + f(n/4) + f(n/5)), n).\n \"\"\"\n\n memo = {} # Use memoization for efficiency\n\n def helper(n):\n if n in memo:\n return memo[n]\n\n if n <= 0:\n return 0\n \n memo[n] = max(helper(n // 2) + helper(n // 3) + helper(n // 4) + helper(n // 5), n)\n return memo[n]\n\n return helper(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n \"\"\"\n Finds the maximum sum possible by using the given equation:\n\n f(n) = max( (f(n/2) + f(n/3) + f(n/4) + f(n/5)), n)\n\n Args:\n n: The input integer.\n\n Returns:\n The maximum sum possible for the given integer.\n\n \"\"\"\n\n memo = {} # Use memoization to store calculated values for efficiency\n\n def _get_max_sum(n):\n if n in memo:\n return memo[n]\n if n <= 0:\n return 0\n\n memo[n] = max(\n _get_max_sum(n // 2) + _get_max_sum(n // 3) + _get_max_sum(n // 4) + _get_max_sum(n // 5),\n n,\n )\n\n return memo[n]\n\n return _get_max_sum(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n \"\"\"\n Find the maximum sum possible by using the given equation f(n) = max((f(n/2) + f(n/3) + f(n/4) + f(n/5)), n).\n\n Args:\n n: An integer.\n\n Returns:\n The maximum sum possible.\n \"\"\"\n memo = {} # Use memoization to store results for efficiency\n\n def helper(num):\n if num in memo:\n return memo[num]\n if num <= 1:\n return num\n memo[num] = max(helper(num // 2) + helper(num // 3) + helper(num // 4) + helper(num // 5), num)\n return memo[num]\n\n return helper(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n \"\"\"\n Finds the maximum sum possible by using the given equation:\n f(n) = max( (f(n/2) + f(n/3) + f(n/4) + f(n/5)), n).\n\n Args:\n n: An integer.\n\n Returns:\n The maximum sum possible for the given n.\n \"\"\"\n\n # Memoization to store calculated results for efficiency\n memo = {}\n\n def helper(n):\n if n in memo:\n return memo[n]\n \n if n <= 1:\n return n\n\n memo[n] = max(helper(n // 2) + helper(n // 3) + helper(n // 4) + helper(n // 5), n)\n return memo[n]\n\n return helper(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n \"\"\"\n Finds the maximum sum possible by using the given equation f(n) = max( (f(n/2) + f(n/3) + f(n/4) + f(n/5)), n).\n \"\"\"\n memo = {} # Use a dictionary to store computed values for memoization\n\n def helper(n):\n if n <= 1:\n return n\n if n in memo:\n return memo[n]\n memo[n] = max(helper(n // 2) + helper(n // 3) + helper(n // 4) + helper(n // 5), n)\n return memo[n]\n return helper(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n \"\"\"\n Finds the maximum sum possible by using the given equation\n f(n) = max( (f(n/2) + f(n/3) + f(n/4) + f(n/5)), n).\n\n Args:\n n: An integer.\n\n Returns:\n An integer representing the maximum sum.\n \"\"\"\n\n memo = {} # Use memoization for efficiency\n\n def helper(n):\n if n in memo:\n return memo[n]\n if n <= 0:\n return 0\n\n memo[n] = max(\n helper(n // 2) + helper(n // 3) + helper(n // 4) + helper(n // 5), n\n )\n return memo[n]\n\n return helper(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n \"\"\"\n Finds the maximum sum possible using the equation f(n) = max( (f(n/2) + f(n/3) + f(n/4) + f(n/5)), n).\n Args:\n n: An integer representing the input value.\n\n Returns:\n The maximum sum achievable using the given equation.\n \"\"\"\n cache = {} # Using a dictionary for memoization to avoid redundant calculations\n\n def _get_max_sum(n):\n if n in cache:\n return cache[n] \n\n if n <= 1:\n return n\n\n cache[n] = max(\n _get_max_sum(int(n / 2)) + _get_max_sum(int(n / 3)) + _get_max_sum(int(n / 4)) + _get_max_sum(int(n / 5)), n\n )\n return cache[n]\n\n return _get_max_sum(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n: int) -> int:\n \"\"\"\n Given an integer n, find the maximum sum possible by using the given equation:\n f(n) = max((f(n/2) + f(n/3) + f(n/4) + f(n/5)), n)\n\n Args:\n n: An integer.\n\n Returns:\n The maximum sum possible.\n \"\"\"\n\n dp = [0] * (n + 1) \n dp[0] = 0\n for i in range(1, n + 1):\n dp[i] = i \n dp[i] = max(dp[i], dp[i // 2] + dp[i // 3] + dp[i // 4] + dp[i // 5])\n return dp[n]", "matching_cluster_idx": 9}, {"solution": "def get_max_sum(n):\n \"\"\"\n Finds the maximum sum possible using the equation f(n) = max((f(n/2) + f(n/3) + f(n/4) + f(n/5)), n).\n Args:\n n: An integer.\n\n Returns:\n The maximum sum possible.\n \"\"\"\n memo = {} # Store computed values to avoid redundant calculations (memoization)\n\n def helper(n):\n if n in memo:\n return memo[n]\n if n <= 0:\n return 0\n memo[n] = max(helper(n // 2) + helper(n // 3) + helper(n // 4) + helper(n // 5), n)\n return memo[n]\n return helper(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n \"\"\"\n Calculates the maximum sum possible using the equation f(n) = max((f(n/2) + f(n/3) + f(n/4) + f(n/5)), n).\n\n Args:\n n: A non-negative integer.\n\n Returns:\n The maximum sum achievable.\n\n \"\"\"\n\n dp = [0] * (n + 1) # Initialize a DP table to store calculated results\n\n for i in range(1, n + 1):\n dp[i] = i # Initially, the max sum is the number itself\n if i >= 2:\n dp[i] = max(dp[i], dp[i // 2] + dp[i // 3] + dp[i // 4] + dp[i // 5])\n\n return dp[n]", "matching_cluster_idx": 10}, {"solution": "def get_max_sum(n):\n \"\"\"\n Finds the maximum sum possible by using the equation f(n) = max((f(n/2) + f(n/3) + f(n/4) + f(n/5)), n).\n \n Args:\n n: An integer.\n\n Returns:\n The maximum sum possible for the given input.\n \"\"\"\n memo = {} # Use memoization to store previously calculated results\n\n def _get_max_sum(n):\n if n in memo:\n return memo[n]\n if n <= 0:\n return 0\n memo[n] = max(n,\n _get_max_sum(n // 2) + _get_max_sum(n // 3) + _get_max_sum(n // 4) + _get_max_sum(n // 5))\n return memo[n]\n return _get_max_sum(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n \"\"\"\n Calculates the maximum sum possible using the equation f(n) = max( (f(n/2) + f(n/3) + f(n/4) + f(n/5)), n).\n\n Args:\n n: A non-negative integer.\n\n Returns:\n The maximum sum achievable.\n \"\"\"\n memo = {} # Use memoization to store computed results\n\n def calculate_max_sum(num):\n if num <= 0:\n return 0\n if num in memo:\n return memo[num]\n \n memo[num] = max(\n calculate_max_sum(num // 2) + calculate_max_sum(num // 3) + calculate_max_sum(num // 4) + calculate_max_sum(num // 5),\n num\n )\n return memo[num]\n \n return calculate_max_sum(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n \"\"\"\n Finds the maximum sum possible using the equation f(n) = max( (f(n/2) + f(n/3) + f(n/4) + f(n/5)), n).\n\n Args:\n n: The input integer.\n\n Returns:\n The maximum sum possible.\n \"\"\"\n dp = [0] * (n + 1)\n for i in range(1, n + 1):\n dp[i] = i\n if i >= 2:\n dp[i] = max(dp[i], dp[i // 2] + dp[i // 3] + dp[i // 4] + dp[i // 5])\n return dp[n]", "matching_cluster_idx": 10}, {"solution": "def get_max_sum(n):\n \"\"\"\n Calculates the maximum sum possible using the equation f(n) = max( (f(n/2) + f(n/3) + f(n/4) + f(n/5)), n).\n\n Args:\n n: An integer.\n\n Returns:\n The maximum sum achievable.\n \"\"\"\n memo = {} # Use memoization to store results for efficiency\n\n def helper(n):\n if n in memo:\n return memo[n]\n if n <= 1:\n return n\n\n memo[n] = max(\n helper(n // 2) + helper(n // 3) + helper(n // 4) + helper(n // 5), n\n )\n return memo[n]\n\n return helper(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n \"\"\"\n Finds the maximum sum possible using the equation f(n) = max((f(n/2) + f(n/3) + f(n/4) + f(n/5)), n).\n\n Args:\n n: An integer.\n\n Returns:\n The maximum sum possible.\n \"\"\"\n \n cache = {} # Use a dictionary to store calculated results for memoization\n\n def helper(n):\n if n <= 1:\n return n\n if n in cache:\n return cache[n]\n\n cache[n] = max(helper(n // 2) + helper(n // 3) + helper(n // 4) + helper(n // 5), n)\n return cache[n]\n\n return helper(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n \"\"\"\n Finds the maximum sum possible using the equation f(n) = max((f(n/2) + f(n/3) + f(n/4) + f(n/5)), n).\n \n Args:\n n: An integer.\n \n Returns:\n The maximum sum achievable using the given equation.\n \"\"\"\n \n memo = {} # Store calculated results for memoization\n\n def calculate_max_sum(num):\n if num in memo:\n return memo[num]\n if num <= 0:\n return 0\n memo[num] = max(calculate_max_sum(num // 2) + calculate_max_sum(num // 3) + calculate_max_sum(num // 4) + calculate_max_sum(num // 5), num)\n return memo[num]\n\n return calculate_max_sum(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n \"\"\"\n Find the maximum sum possible by using the equation f(n) = max((f(n/2) + f(n/3) + f(n/4) + f(n/5)), n).\n\n Args:\n n: An integer representing the input value.\n\n Returns:\n The maximum sum possible according to the equation.\n \"\"\"\n memo = {} # store results for previously calculated values to avoid recalculations\n\n def calculate_max_sum(n):\n if n in memo:\n return memo[n]\n if n <= 1:\n return n\n memo[n] = max(calculate_max_sum(n // 2) + calculate_max_sum(n // 3) + calculate_max_sum(n // 4) + calculate_max_sum(n // 5), n)\n return memo[n]\n\n return calculate_max_sum(n)", "matching_cluster_idx": 12}]}, "Mbpp/395": {"dps": 98.08429118773947, "dps_norm": 75.0, "pass@1": 100.0, "profiled": [{"solution": "def first_non_repeating_character(string):\n \"\"\"\n Finds the first non-repeated character in a given string.\n\n Args:\n string: The input string.\n\n Returns:\n The first non-repeated character, or None if all characters repeat.\n \"\"\"\n\n char_counts = {}\n for char in string:\n if char in char_counts:\n char_counts[char] += 1\n else:\n char_counts[char] = 1\n\n for char in string:\n if char_counts[char] == 1:\n return char\n\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(string):\n \"\"\"\n Finds the first non-repeated character in a given string.\n\n Args:\n string: The input string.\n\n Returns:\n The first non-repeated character, or None if none exists.\n \"\"\"\n char_counts = {}\n for char in string:\n if char in char_counts:\n char_counts[char] += 1\n else:\n char_counts[char] = 1\n\n for char in string:\n if char_counts[char] == 1:\n return char\n\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(string):\n \"\"\"Finds the first non-repeated character in a given string.\n\n Args:\n string: The input string to search.\n\n Returns:\n The first non-repeated character, or None if all characters repeat.\n \"\"\"\n\n char_counts = {}\n for char in string:\n if char in char_counts:\n char_counts[char] += 1\n else:\n char_counts[char] = 1\n\n for char in string:\n if char_counts[char] == 1:\n return char\n\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(text):\n \"\"\"Finds the first non-repeated character in a given string.\n\n Args:\n text: The input string.\n\n Returns:\n The first non-repeated character, or None if all characters repeat.\n \"\"\"\n\n char_counts = {}\n for char in text:\n if char in char_counts:\n char_counts[char] += 1\n else:\n char_counts[char] = 1\n\n for char in text:\n if char_counts[char] == 1:\n return char\n\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(string):\n \"\"\"\n Finds the first non-repeated character in a given string.\n\n Args:\n string: The input string to search.\n\n Returns:\n The first non-repeated character, or None if there are no non-repeated characters.\n \"\"\"\n char_counts = {}\n for char in string:\n if char in char_counts:\n char_counts[char] += 1\n else:\n char_counts[char] = 1\n\n for char in string:\n if char_counts[char] == 1:\n return char\n\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(string):\n \"\"\"Finds the first non-repeated character in a given string.\n \n Args:\n string: The input string.\n\n Returns:\n The first non-repeating character in the string, or None if all characters repeat.\n \"\"\"\n\n char_counts = {}\n for char in string:\n if char in char_counts:\n char_counts[char] += 1\n else:\n char_counts[char] = 1\n\n for char in string:\n if char_counts[char] == 1:\n return char\n \n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(string):\n \"\"\"Finds the first non-repeated character in a given string.\n\n Args:\n string: The string to search.\n\n Returns:\n The first non-repeated character, or None if all characters repeat.\n \"\"\"\n char_counts = {}\n for char in string:\n if char in char_counts:\n char_counts[char] += 1\n else:\n char_counts[char] = 1\n\n for char in string:\n if char_counts[char] == 1:\n return char\n\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(string):\n \"\"\"\n Find the first non-repeated character in a given string.\n\n Args:\n string: The input string.\n\n Returns:\n The first non-repeated character, or None if there is none.\n \"\"\"\n\n char_counts = {}\n for char in string:\n if char in char_counts:\n char_counts[char] += 1\n else:\n char_counts[char] = 1\n\n for char in string:\n if char_counts[char] == 1:\n return char\n\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(string):\n \"\"\"\n Finds the first non-repeated character in a given string.\n Args:\n string: The input string.\n Returns:\n The first non-repeated character, or None if none exist.\n \"\"\"\n char_counts = {}\n for char in string:\n if char in char_counts:\n char_counts[char] += 1\n else:\n char_counts[char] = 1\n for char in string:\n if char_counts[char] == 1:\n return char\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(string):\n \"\"\"\n Finds the first non-repeating character in a given string.\n \n Args:\n string: The input string to search.\n \n Returns:\n The first non-repeating character, or None if all characters repeat.\n \"\"\"\n char_counts = {}\n for char in string:\n if char in char_counts:\n char_counts[char] += 1\n else:\n char_counts[char] = 1\n\n for char in string:\n if char_counts[char] == 1:\n return char\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(string):\n \"\"\"\n Finds the first non-repeated character in a given string.\n\n Args:\n string: The input string.\n\n Returns:\n The first non-repeated character, or None if there are no non-repeated characters.\n \"\"\"\n char_counts = {}\n for char in string:\n if char in char_counts:\n char_counts[char] += 1\n else:\n char_counts[char] = 1\n\n for char in string:\n if char_counts[char] == 1:\n return char\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(string):\n \"\"\"\n Finds the first non-repeated character in a given string.\n\n Args:\n string: The input string.\n\n Returns:\n The first non-repeated character, or None if no such character exists.\n \"\"\"\n char_counts = {}\n for char in string:\n if char in char_counts:\n char_counts[char] += 1\n else:\n char_counts[char] = 1\n\n for char in string:\n if char_counts[char] == 1:\n return char\n\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(string):\n \"\"\"\n Finds the first non-repeated character in a given string.\n\n Args:\n string: The string to search.\n\n Returns:\n The first non-repeated character, or None if there are no non-repeated characters.\n \"\"\"\n char_counts = {}\n for char in string:\n if char in char_counts:\n char_counts[char] += 1\n else:\n char_counts[char] = 1\n\n for char in string:\n if char_counts[char] == 1:\n return char\n\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(string):\n \"\"\"Finds the first non-repeated character in a given string.\n\n Args:\n string: The input string.\n\n Returns:\n The first non-repeating character, or None if no such character exists.\n \"\"\"\n\n char_counts = {}\n for char in string:\n if char in char_counts:\n char_counts[char] += 1\n else:\n char_counts[char] = 1\n\n for char in string:\n if char_counts[char] == 1:\n return char\n\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(string):\n \"\"\"\n Finds the first non-repeated character in a given string.\n\n Args:\n string: The string to search.\n\n Returns:\n The first non-repeated character, or None if none exists.\n \"\"\"\n char_counts = {}\n for char in string:\n if char in char_counts:\n char_counts[char] += 1\n else:\n char_counts[char] = 1\n\n for char in string:\n if char_counts[char] == 1:\n return char\n \n return None", "matching_cluster_idx": 5}, {"solution": "from collections import Counter\ndef first_non_repeating_character(string):\n \"\"\"\n This function finds the first non-repeated character in a given string.\n\n Args:\n string: The input string.\n\n Returns:\n The first non-repeated character, or None if there are no non-repeated characters.\n \"\"\"\n char_counts = Counter(string) # Count occurrences of each character\n for char in string:\n if char_counts[char] == 1:\n return char\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(string):\n \"\"\"\n Finds the first non-repeated character in a given string.\n\n Args:\n string: The string to search.\n\n Returns:\n The first non-repeated character, or None if there are no non-repeated characters.\n \"\"\"\n char_counts = {}\n for char in string:\n if char in char_counts:\n char_counts[char] += 1\n else:\n char_counts[char] = 1\n\n for char in string:\n if char_counts[char] == 1:\n return char\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(string):\n \"\"\"\n Finds the first non-repeated character in a given string.\n\n Args:\n string: The input string to search.\n\n Returns:\n The first non-repeated character, or None if no such character exists.\n \"\"\"\n char_counts = {}\n for char in string:\n if char in char_counts:\n char_counts[char] += 1\n else:\n char_counts[char] = 1\n\n for char in string:\n if char_counts[char] == 1:\n return char\n\n return None # No non-repeating character found", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(text):\n \"\"\"\n Finds the first non-repeated character in a given string.\n\n Args:\n text: The string to search.\n\n Returns:\n The first non-repeated character, or None if all characters repeat.\n \"\"\"\n char_counts = {}\n for char in text:\n if char in char_counts:\n char_counts[char] += 1\n else:\n char_counts[char] = 1\n\n for char in text:\n if char_counts[char] == 1:\n return char\n\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(string):\n \"\"\"\n Finds the first non-repeated character in a given string.\n\n Args:\n string: The input string.\n\n Returns:\n The first non-repeated character in the string, or None if there are no\n non-repeated characters.\n \"\"\"\n char_counts = {}\n for char in string:\n if char in char_counts:\n char_counts[char] += 1\n else:\n char_counts[char] = 1\n\n for char in string:\n if char_counts[char] == 1:\n return char\n\n return None", "matching_cluster_idx": 5}]}, "Mbpp/405": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def check_tuplex(input_tuple, element):\n \"\"\"\n Checks if an element exists within a tuple.\n\n Args:\n input_tuple: The tuple to search within.\n element: The element to search for.\n\n Returns:\n True if the element is found in the tuple, False otherwise.\n \"\"\"\n return element in input_tuple", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(input_tuple, element):\n \"\"\"Checks if an element exists in a tuple.\n\n Args:\n input_tuple: The tuple to search within.\n element: The element to search for.\n\n Returns:\n True if the element is found in the tuple, False otherwise.\n \"\"\"\n return element in input_tuple", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuple_x, element):\n \"\"\"Checks if an element exists within a tuple.\n\n Args:\n tuple_x: The tuple to search within.\n element: The element to search for.\n\n Returns:\n True if the element is found in the tuple, False otherwise.\n \"\"\"\n return element in tuple_x", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuple1, element):\n \"\"\"\n Checks if an element exists within a tuple.\n\n Args:\n tuple1: The tuple to search within.\n element: The element to search for.\n\n Returns:\n True if the element is found in the tuple, False otherwise.\n \"\"\"\n return element in tuple1", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(input_tuple, element):\n \"\"\"Checks if an element exists within a tuple.\n\n Args:\n input_tuple: The tuple to search within.\n element: The element to search for.\n\n Returns:\n True if the element is found in the tuple, False otherwise.\n \"\"\"\n return element in input_tuple", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(my_tuple, element):\n \"\"\"\n Checks if an element exists within a tuple.\n Args:\n my_tuple (tuple): The tuple to check.\n element: The element to search for.\n Returns:\n bool: True if the element is found in the tuple, False otherwise.\n \"\"\"\n return element in my_tuple", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(input_tuple, element):\n \"\"\"Checks if an element exists within a tuple.\n\n Args:\n input_tuple: The tuple to search within.\n element: The element to search for.\n\n Returns:\n True if the element is found in the tuple, False otherwise.\n \"\"\"\n return element in input_tuple", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(input_tuple, element):\n \"\"\"\n This function checks whether a given element exists within a tuple.\n\n Args:\n input_tuple: The tuple to be checked.\n element: The element to be searched for.\n\n Returns:\n True if the element is found in the tuple, False otherwise.\n \"\"\"\n return element in input_tuple", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(input_tuple, element):\n \"\"\"\n This function checks if a given element exists within a tuple.\n\n Args:\n input_tuple: The tuple to be searched.\n element: The element to search for.\n\n Returns:\n True if the element is found in the tuple, False otherwise.\n \"\"\"\n return element in input_tuple", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tpl, element):\n \"\"\"\n Checks if an element exists within a tuple.\n\n Args:\n tpl: The tuple to search within.\n element: The element to search for.\n\n Returns:\n True if the element is found in the tuple, False otherwise.\n \"\"\"\n\n return element in tpl", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuple_in, element):\n \"\"\"Checks if an element exists within a tuple.\n\n Args:\n tuple_in: The tuple to search within.\n element: The element to look for.\n\n Returns:\n True if the element is found in the tuple, False otherwise.\n \"\"\"\n return element in tuple_in", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(input_tuple, element):\n \"\"\"Checks if an element exists in a tuple.\n\n Args:\n input_tuple: The tuple to search within.\n element: The element to search for.\n\n Returns:\n True if the element exists in the tuple, False otherwise.\n \"\"\"\n return element in input_tuple", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, element):\n \"\"\"\n Checks whether an element exists within a tuple.\n\n Args:\n tuplex: The tuple to search within.\n element: The element to check for.\n\n Returns:\n True if the element is found in the tuple, False otherwise.\n \"\"\"\n\n return element in tuplex", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, element):\n \"\"\"\n Checks whether an element exists within a tuple.\n\n Args:\n tuplex: The tuple to search within.\n element: The element to search for.\n\n Returns:\n True if the element is found in the tuple, False otherwise.\n \"\"\"\n return element in tuplex", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, element):\n \"\"\"\n Checks if an element exists within a tuple.\n\n Args:\n tuplex: The tuple to search within.\n element: The element to search for.\n\n Returns:\n True if the element exists in the tuple, False otherwise.\n \"\"\"\n return element in tuplex", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(input_tuple, element):\n \"\"\"\n This function checks if an element exists within a tuple.\n\n Args:\n input_tuple: The tuple to be searched.\n element: The element to search for.\n\n Returns:\n True if the element exists in the tuple, False otherwise.\n \"\"\"\n return element in input_tuple", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(input_tuple, element):\n \"\"\"\n Checks if an element exists within a tuple.\n\n Args:\n input_tuple: The tuple to search within.\n element: The element to search for.\n\n Returns:\n True if the element is found in the tuple, False otherwise.\n \"\"\"\n\n return element in input_tuple", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(input_tuple, element):\n \"\"\"Checks if an element exists within a tuple.\n\n Args:\n input_tuple: The tuple to search within.\n element: The element to search for.\n\n Returns:\n True if the element is found in the tuple, False otherwise.\n \"\"\"\n return element in input_tuple", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(input_tuple, element):\n \"\"\"\n Checks whether an element exists within a tuple.\n \n Args:\n input_tuple: The tuple to search within.\n element: The element to search for.\n \n Returns:\n True if the element is found in the tuple, False otherwise.\n \"\"\"\n return element in input_tuple", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(input_tuple, element):\n \"\"\"Checks if an element exists within a tuple.\n\n Args:\n input_tuple: The tuple to search within.\n element: The element to search for.\n\n Returns:\n True if the element is found in the tuple, False otherwise.\n \"\"\"\n\n return element in input_tuple", "matching_cluster_idx": 3}]}, "Mbpp/414": {"dps": 91.30434782608695, "dps_norm": 88.88888888888889, "pass@1": 100.0, "profiled": [{"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Checks whether any value in seq1 exists in seq2.\n \"\"\"\n for item in seq1:\n if item in seq2:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Checks whether any value in one sequence exists in another sequence.\n\n Args:\n seq1: The first sequence.\n seq2: The second sequence.\n\n Returns:\n True if any element in seq1 exists in seq2, False otherwise.\n \"\"\"\n for element in seq1:\n if element in seq2:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Checks whether any value in seq1 exists in seq2.\n\n Args:\n seq1: The first sequence.\n seq2: The second sequence.\n\n Returns:\n True if any value in seq1 exists in seq2, False otherwise.\n \"\"\"\n for item in seq1:\n if item in seq2:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Checks whether any value in a sequence exists in another sequence.\n\n Args:\n seq1: The first sequence.\n seq2: The second sequence.\n\n Returns:\n True if any value in seq1 exists in seq2, False otherwise.\n \"\"\"\n for value in seq1:\n if value in seq2:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Checks whether any value in a sequence exists in another sequence.\n\n Args:\n seq1: The first sequence.\n seq2: The second sequence.\n\n Returns:\n True if any element of seq1 is present in seq2, False otherwise.\n \"\"\"\n for element in seq1:\n if element in seq2:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Checks whether any value in seq1 exists in seq2.\n\n Args:\n seq1: The first sequence.\n seq2: The second sequence.\n\n Returns:\n True if any value from seq1 is found in seq2, False otherwise.\n \"\"\"\n\n for value in seq1:\n if value in seq2:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"Checks if any value in one sequence exists in another.\n\n Args:\n seq1: The first sequence.\n seq2: The second sequence.\n\n Returns:\n True if any value in seq1 exists in seq2, False otherwise.\n \"\"\"\n for element in seq1:\n if element in seq2:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Checks if any element in seq1 exists in seq2.\n\n Args:\n seq1: The first sequence.\n seq2: The second sequence.\n\n Returns:\n True if any element from seq1 exists in seq2, False otherwise.\n \"\"\"\n for element in seq1:\n if element in seq2:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(lst1, lst2):\n \"\"\"\n Checks whether any value in a sequence exists in another sequence.\n\n Args:\n lst1: The first sequence.\n lst2: The second sequence.\n\n Returns:\n True if any value in lst1 exists in lst2, False otherwise.\n \"\"\"\n for element in lst1:\n if element in lst2:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n This function checks whether any value in one sequence exists in another sequence.\n\n Args:\n seq1: The first sequence.\n seq2: The second sequence.\n\n Returns:\n True if there is any overlap between the sequences, False otherwise.\n \"\"\"\n for item in seq1:\n if item in seq2:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Check if any value in seq1 exists in seq2.\n\n Args:\n seq1: The first sequence.\n seq2: The second sequence.\n\n Returns:\n True if any value in seq1 exists in seq2, False otherwise.\n \"\"\"\n for item in seq1:\n if item in seq2:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"Checks if any value in seq1 exists in seq2.\n\n Args:\n seq1: The first sequence.\n seq2: The second sequence.\n\n Returns:\n True if any value from seq1 exists in seq2, False otherwise.\n \"\"\"\n for item in seq1:\n if item in seq2:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Checks whether any value in seq1 exists in seq2.\n\n Args:\n seq1: The first sequence.\n seq2: The second sequence.\n\n Returns:\n True if any value in seq1 is also in seq2, False otherwise.\n \"\"\"\n for value in seq1:\n if value in seq2:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Checks whether any value in seq1 exists in seq2.\n\n Args:\n seq1: The first sequence.\n seq2: The second sequence.\n\n Returns:\n True if any element of seq1 is found in seq2, False otherwise.\n \"\"\"\n for element in seq1:\n if element in seq2:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Checks whether any value in a sequence exists in another sequence.\n\n Args:\n seq1: The first sequence.\n seq2: The second sequence.\n\n Returns:\n True if any value in seq1 exists in seq2, False otherwise.\n \"\"\"\n for item in seq1:\n if item in seq2:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n This function checks if any element of seq1 is present in seq2.\n Args:\n seq1: The first sequence (list, tuple, etc.).\n seq2: The second sequence (list, tuple, etc.).\n Returns:\n True if any element of seq1 is in seq2, False otherwise.\n \"\"\"\n for item in seq1:\n if item in seq2:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Checks if any value in seq1 exists in seq2.\n\n Args:\n seq1: The first sequence.\n seq2: The second sequence.\n\n Returns:\n True if any value in seq1 exists in seq2, False otherwise.\n \"\"\"\n for item in seq1:\n if item in seq2:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Checks whether any value in seq1 exists in seq2.\n\n Args:\n seq1: The first sequence.\n seq2: The second sequence.\n\n Returns:\n True if any value in seq1 exists in seq2, False otherwise.\n \"\"\"\n for element in seq1:\n if element in seq2:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Checks if any value in the first sequence exists in the second sequence.\n\n Args:\n seq1: The first sequence.\n seq2: The second sequence.\n\n Returns:\n True if there is an overlapping value, False otherwise.\n \"\"\"\n\n for item in seq1:\n if item in seq2:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Checks if any value in seq1 exists in seq2.\n \n Args:\n seq1: The first sequence (list, tuple, string, etc.).\n seq2: The second sequence (list, tuple, string, etc.).\n\n Returns:\n True if there is any overlap, False otherwise.\n \"\"\"\n for item in seq1:\n if item in seq2:\n return True\n return False", "matching_cluster_idx": 7}]}, "Mbpp/421": {"dps": 15.226337448559672, "dps_norm": 71.42857142857143, "pass@1": 100.0, "profiled": [{"solution": "def concatenate_tuple(data, delimiter='-'):\n \"\"\"\n This function concatenates each element of a tuple with a specified delimiter.\n\n Args:\n data: A tuple of elements.\n delimiter: The delimiter to be used between elements (default is '-').\n\n Returns:\n A string containing all elements of the tuple concatenated with the delimiter.\n \"\"\"\n return delimiter.join(str(element) for element in data)", "matching_cluster_idx": 4}, {"solution": "def concatenate_tuple(input_tuple, delimiter='-'):\n \"\"\"Concatenates each element of a tuple by a delimiter.\n\n Args:\n input_tuple: The input tuple.\n delimiter: The delimiter to use, defaults to '-'.\n\n Returns:\n A string with all elements concatenated by the delimiter.\n \"\"\"\n return delimiter.join(str(x) for x in input_tuple)", "matching_cluster_idx": 4}, {"solution": "def concatenate_tuple(input_tuple, delimiter=\"-\"):\n \"\"\"Concatenates each element of a tuple by the delimiter.\n\n Args:\n input_tuple: The tuple to concatenate.\n delimiter: The delimiter to use. Defaults to '-'.\n\n Returns:\n A string containing the concatenated elements.\n \"\"\"\n return delimiter.join(str(element) for element in input_tuple)", "matching_cluster_idx": 4}, {"solution": "def concatenate_tuple(input_tuple, delimiter = \"-\"):\n \"\"\"Concatenates each element of a tuple using a delimiter.\n\n Args:\n input_tuple: The tuple to concatenate.\n delimiter: The delimiter to use between elements. Defaults to \"-\".\n\n Returns:\n A string containing the concatenated elements of the tuple.\n \"\"\"\n return delimiter.join(str(element) for element in input_tuple)", "matching_cluster_idx": 4}, {"solution": "def concatenate_tuple(input_tuple, delimiter = \"-\"):\n \"\"\"\n Concatenates each element of a tuple by a given delimiter.\n\n Args:\n input_tuple (tuple): The tuple to be concatenated.\n delimiter (str, optional): The delimiter to be used. Defaults to \"-\".\n\n Returns:\n str: A string containing all elements of the tuple concatenated by the delimiter.\n \"\"\"\n return delimiter.join(str(x) for x in input_tuple)", "matching_cluster_idx": 4}, {"solution": "def concatenate_tuple(input_tuple, delimiter='-'):\n \"\"\"Concatenates each element of a tuple by a specified delimiter.\n\n Args:\n input_tuple: The tuple to concatenate.\n delimiter: The string used to separate elements (default is '-').\n\n Returns:\n A string containing all elements concatenated with the delimiter.\n \"\"\"\n return delimiter.join(str(x) for x in input_tuple)", "matching_cluster_idx": 4}, {"solution": "def concatenate_tuple(input_tuple):\n \"\"\"\n Concatenates each element of a tuple by a hyphen delimiter.\n\n Args:\n input_tuple: The tuple containing elements to be concatenated.\n\n Returns:\n A string with all elements of the tuple concatenated by hyphens.\n \"\"\"\n return '-'.join(str(element) for element in input_tuple)", "matching_cluster_idx": 4}, {"solution": "def concatenate_tuple(tup, delimiter='-'):\n \"\"\"Concatenates each element of a tuple by the given delimiter.\n\n Args:\n tup: The input tuple.\n delimiter: The delimiter to use for concatenation. Defaults to '-'.\n\n Returns:\n A string with the concatenated elements of the tuple.\n \"\"\"\n return delimiter.join(str(element) for element in tup)", "matching_cluster_idx": 4}, {"solution": "def concatenate_tuple(input_tuple, delimiter=\"-\") -> str:\n \"\"\"\n Concatenates each element of a tuple by the specified delimiter.\n\n Args:\n input_tuple: The input tuple.\n delimiter: The delimiter to use for concatenation. Defaults to \"-\".\n\n Returns:\n A string with all elements of the tuple concatenated by the delimiter.\n \"\"\"\n return delimiter.join(str(element) for element in input_tuple)", "matching_cluster_idx": 4}, {"solution": "def concatenate_tuple(input_tuple, delimiter='-'):\n \"\"\"\n Concatenates each element of a tuple by the delimiter.\n\n Args:\n input_tuple: A tuple of elements to concatenate.\n delimiter: The delimiter to use between elements (default is '-').\n\n Returns:\n A string containing all elements concatenated by the delimiter.\n \"\"\"\n return delimiter.join(str(element) for element in input_tuple)", "matching_cluster_idx": 4}, {"solution": "def concatenate_tuple(input_tuple, delimiter='-'):\n \"\"\"Concatenates each element of a tuple using a delimiter.\n\n Args:\n input_tuple: The tuple to concatenate.\n delimiter: The delimiter to use between elements (default is '-').\n\n Returns:\n A string containing the concatenated elements of the tuple.\n \"\"\"\n\n return delimiter.join(str(element) for element in input_tuple)", "matching_cluster_idx": 4}, {"solution": "def concatenate_tuple(input_tuple, delimiter=\"-\") -> str:\n \"\"\"\n Concatenates each element of a tuple by the given delimiter.\n\n Args:\n input_tuple: The tuple to concatenate.\n delimiter: The delimiter to use for concatenation. Defaults to \"-\".\n\n Returns:\n A string containing the concatenated elements of the tuple.\n \"\"\"\n return delimiter.join(str(element) for element in input_tuple)", "matching_cluster_idx": 4}, {"solution": "def concatenate_tuple(input_tuple, delimiter = \"-\"):\n \"\"\"\n Concatenates each element of a tuple by the delimiter.\n\n Args:\n input_tuple: The input tuple to concatenate.\n delimiter: The delimiter to use between elements. Defaults to \"-\".\n\n Returns:\n A string containing the concatenated elements of the tuple.\n \"\"\"\n return delimiter.join(str(element) for element in input_tuple)", "matching_cluster_idx": 4}, {"solution": "def concatenate_tuple(input_tuple, delimiter='-'):\n \"\"\"\n Concatenates each element of a tuple using a given delimiter.\n\n Args:\n input_tuple: The tuple to concatenate.\n delimiter: The delimiter to use. Defaults to '-'.\n\n Returns:\n A string containing the concatenated elements.\n \"\"\"\n return delimiter.join(str(element) for element in input_tuple)", "matching_cluster_idx": 4}, {"solution": "def concatenate_tuple(input_tuple, delimiter=\"-\"):\n \"\"\"Concatenates each element of a tuple by a delimiter.\n\n Args:\n input_tuple: The input tuple.\n delimiter: The delimiter to use for concatenation. Defaults to \"-\".\n\n Returns:\n A string containing the concatenated elements of the tuple.\n \"\"\"\n return delimiter.join(str(element) for element in input_tuple)", "matching_cluster_idx": 4}, {"solution": "def concatenate_tuple(input_tuple, delimiter=\"-\") -> str:\n \"\"\"Concatenates each element of a tuple by the given delimiter.\n\n Args:\n input_tuple: The tuple to concatenate.\n delimiter: The delimiter to use between elements. Defaults to \"-\".\n\n Returns:\n A string containing all elements of the tuple concatenated by the delimiter.\n \"\"\"\n\n return delimiter.join(str(element) for element in input_tuple)", "matching_cluster_idx": 4}, {"solution": "def concatenate_tuple(input_tuple, delimiter='-'):\n \"\"\"\n Concatenates elements of a tuple into a string using a delimiter.\n\n Args:\n input_tuple: The tuple to concatenate.\n delimiter: The delimiter to use. Defaults to '-'.\n\n Returns:\n A string with the concatenated elements.\n \"\"\"\n\n return delimiter.join(str(element) for element in input_tuple)", "matching_cluster_idx": 4}, {"solution": "def concatenate_tuple(input_tuple, delimiter='-'):\n \"\"\"Concatenates each element of a tuple by the delimiter.\n\n Args:\n input_tuple: The tuple to concatenate.\n delimiter: The delimiter to use, defaults to '-'.\n\n Returns:\n A string with the concatenated elements.\n \"\"\"\n return delimiter.join(str(element) for element in input_tuple)", "matching_cluster_idx": 4}, {"solution": "def concatenate_tuple(input_tuple, delimiter='-'):\n \"\"\"Concatenates each element of a tuple by the delimiter.\n\n Args:\n input_tuple: A tuple of elements.\n delimiter: The delimiter to use for concatenation. Defaults to '-'.\n\n Returns:\n A string formed by concatenating the tuple elements with the delimiter.\n \"\"\"\n return delimiter.join(str(element) for element in input_tuple)", "matching_cluster_idx": 4}, {"solution": "def concatenate_tuple(input_tuple):\n \"\"\"\n Concatenates each element of a tuple by the delimiter \"-\".\n\n Args:\n input_tuple: A tuple of elements to concatenate.\n\n Returns:\n A string containing the concatenated elements separated by \"-\".\n \"\"\"\n return '-'.join(str(element) for element in input_tuple)", "matching_cluster_idx": 4}]}, "Mbpp/424": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def extract_rear(strs):\n \"\"\"\n Extracts the rear (last) element from each string in a tuple.\n\n Args:\n strs: A tuple of strings.\n\n Returns:\n A list containing the last element of each string in the input tuple.\n \"\"\"\n return [s[-1] for s in strs]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(input_tuple):\n \"\"\"\n Extracts the rearmost (last) character of each string in a tuple.\n\n Args:\n input_tuple: A tuple containing strings.\n\n Returns:\n A list containing the last character of each string in the input tuple.\n \"\"\"\n return [s[-1] for s in input_tuple]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(string_tuple):\n \"\"\"Extracts the rear element (last character) of each string in the given tuple.\n\n Args:\n string_tuple: A tuple of strings.\n\n Returns:\n A list containing the rear element of each string in the input tuple.\n \"\"\"\n return [string[-1] for string in string_tuple]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(data: tuple) -> list:\n \"\"\"\n Write a function to extract only the rear index element of each string in the given tuple.\n assert extract_rear(('Mers', 'for', 'Vers') ) == ['s', 'r', 's']\n \"\"\"\n return [string[-1] for string in data]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(strings):\n \"\"\"\n Extract only the rear index element of each string in the given tuple.\n\n Args:\n strings: A tuple of strings.\n\n Returns:\n A list containing the last characters of each string in the tuple.\n \"\"\"\n return [string[-1] for string in strings]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(string_tuple):\n \"\"\"\n This function extracts the last character (rear index element) from each string in a tuple.\n\n Args:\n string_tuple: A tuple of strings.\n\n Returns:\n A list containing the last characters of each string in the tuple.\n \"\"\"\n return [string[-1] for string in string_tuple]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(strs):\n \"\"\"\n Extracts the last character from each string in a tuple.\n\n Args:\n strs: A tuple of strings.\n\n Returns:\n A list of the last characters of each string in the input tuple.\n \"\"\"\n return [s[-1] for s in strs]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(strings):\n \"\"\"Extracts the last character of each string in a tuple.\n\n Args:\n strings: A tuple of strings.\n\n Returns:\n A list of the last characters of each string in the input tuple.\n \"\"\"\n\n return [s[-1] for s in strings]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(strings):\n \"\"\"\n Extract the last character of each string in a tuple.\n Args:\n strings: A tuple of strings.\n Returns:\n A list containing the last character of each string.\n \"\"\"\n return [string[-1] for string in strings]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(strings):\n \"\"\"\n Extracts the last character of each string in a tuple.\n\n Args:\n strings: A tuple of strings.\n\n Returns:\n A list of characters, where each character is the last character of\n the corresponding string in the input tuple.\n \"\"\"\n return [s[-1] for s in strings]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(input_tuple):\n \"\"\"\n This function extracts the last character of each string in a tuple.\n\n Args:\n input_tuple: A tuple of strings.\n\n Returns:\n A list containing the last character of each string in the input tuple.\n \"\"\"\n return [s[-1] for s in input_tuple]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(string_tuple):\n \"\"\"\n This function extracts the rear (last) index element of each string in a tuple.\n\n Args:\n string_tuple: A tuple of strings.\n\n Returns:\n A list containing the rear element of each string in the tuple.\n \"\"\"\n return [string[-1] for string in string_tuple]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(strings):\n \"\"\"Extracts the last character of each string in a tuple.\n\n Args:\n strings: A tuple of strings.\n\n Returns:\n A list containing the last character of each string in the input tuple.\n \"\"\"\n return [string[-1] for string in strings]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(strings):\n \"\"\"\n This function extracts the last character (rear index element) from each string in a tuple.\n\n Args:\n strings: A tuple of strings.\n\n Returns:\n A list containing the last character of each string in the input tuple.\n \"\"\"\n return [string[-1] for string in strings]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(strings):\n \"\"\"\n Extracts the last character of each string in a tuple.\n\n Args:\n strings: A tuple of strings.\n\n Returns:\n A list of the last characters of each string in the tuple.\n \"\"\"\n return [string[-1] for string in strings]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(strings):\n return [string[-1] for string in strings]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(strings):\n \"\"\"Extracts the last character of each string in a tuple.\n\n Args:\n strings: A tuple of strings.\n\n Returns:\n A list containing the last character of each string in the input tuple.\n \"\"\"\n return [s[-1] for s in strings]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(strings):\n \"\"\"Extracts the last character of each string in a tuple.\n\n Args:\n strings: A tuple of strings.\n\n Returns:\n A list of the last characters of each string in the input tuple.\n \"\"\"\n return [s[-1] for s in strings]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(strings):\n \"\"\"Extracts the last character from each string in a tuple.\n\n Args:\n strings: A tuple of strings.\n\n Returns:\n A list containing the last character of each string in the input tuple.\n \"\"\"\n return [string[-1] for string in strings]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(string_tuple):\n \"\"\"\n Extracts the last character (rear index element) of each string in a tuple.\n\n Args:\n string_tuple: A tuple of strings.\n\n Returns:\n A list containing the last character of each string in the input tuple.\n \"\"\"\n return [string[-1] for string in string_tuple]", "matching_cluster_idx": 4}]}, "Mbpp/425": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def count_element_in_list(list_of_lists, element):\n \"\"\"\n Counts the number of sublists containing a particular element.\n\n Args:\n list_of_lists: A list of lists.\n element: The element to search for.\n\n Returns:\n The number of sublists containing the element.\n \"\"\"\n count = 0\n for sublist in list_of_lists:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(list_of_lists, element):\n \"\"\"\n Counts the number of sublists containing a particular element.\n\n Args:\n list_of_lists: A list of lists.\n element: The element to search for.\n\n Returns:\n The number of sublists containing the element.\n \"\"\"\n count = 0\n for sublist in list_of_lists:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, element):\n \"\"\"\n Counts the number of sublists containing a particular element.\n\n Args:\n lst: A list of lists.\n element: The element to search for.\n\n Returns:\n The number of sublists containing the element.\n \"\"\"\n count = 0\n for sublist in lst:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(list_of_lists, element):\n \"\"\"\n Counts the number of sublists containing a particular element.\n\n Args:\n list_of_lists: A list of lists.\n element: The element to search for.\n\n Returns:\n The number of sublists containing the element.\n \"\"\"\n count = 0\n for sublist in list_of_lists:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(list_of_lists, element):\n \"\"\"\n This function counts the number of sublists containing a particular element.\n\n Args:\n list_of_lists: A list of lists.\n element: The element to search for.\n\n Returns:\n The number of sublists containing the element.\n \"\"\"\n count = 0\n for sublist in list_of_lists:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(list_of_lists, element):\n \"\"\"\n Counts the number of sublists containing a particular element.\n\n Args:\n list_of_lists: A list of lists.\n element: The element to search for.\n\n Returns:\n The number of sublists containing the element.\n \"\"\"\n\n count = 0\n for sublist in list_of_lists:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(list_of_lists, element):\n \"\"\"Counts the number of sublists containing a particular element.\n\n Args:\n list_of_lists: A list of lists.\n element: The element to search for.\n\n Returns:\n The number of sublists that contain the element.\n \"\"\"\n count = 0\n for sublist in list_of_lists:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(list_of_lists, element):\n \"\"\"\n Counts the number of sublists containing a particular element.\n\n Args:\n list_of_lists: A list of lists.\n element: The element to count.\n\n Returns:\n The number of sublists containing the element.\n \"\"\"\n\n count = 0\n for sublist in list_of_lists:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(list_of_lists, element):\n \"\"\"\n Counts the number of sublists containing a particular element.\n\n Args:\n list_of_lists: A list of lists.\n element: The element to search for.\n\n Returns:\n The number of sublists containing the element.\n \"\"\"\n\n count = 0\n for sublist in list_of_lists:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(list_of_lists, element):\n \"\"\"\n Counts the number of sublists containing a particular element.\n\n Args:\n list_of_lists: A list of lists.\n element: The element to search for.\n\n Returns:\n The number of sublists containing the element.\n \"\"\"\n count = 0\n for sublist in list_of_lists:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(list_of_lists, element):\n \"\"\"\n Counts the number of sublists containing a particular element.\n\n Args:\n list_of_lists: A list of lists.\n element: The element to search for.\n\n Returns:\n The number of sublists containing the element.\n \"\"\"\n count = 0\n for sublist in list_of_lists:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(list_of_lists, element):\n \"\"\"Counts the number of sublists containing a particular element.\n\n Args:\n list_of_lists: A list of lists.\n element: The element to search for.\n\n Returns:\n The number of sublists containing the element.\n \"\"\"\n\n count = 0\n for sublist in list_of_lists:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(list_of_lists, element):\n \"\"\"Counts the number of sublists containing a particular element.\n\n Args:\n list_of_lists: A list of lists.\n element: The element to search for.\n\n Returns:\n The number of sublists containing the element.\n \"\"\"\n count = 0\n for sublist in list_of_lists:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(list_of_lists, element):\n \"\"\"Counts the number of sublists containing a particular element.\n\n Args:\n list_of_lists: A list of lists.\n element: The element to search for.\n\n Returns:\n The number of sublists containing the element.\n \"\"\"\n\n count = 0\n for sublist in list_of_lists:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(list_of_lists, element):\n \"\"\"\n Counts the number of sublists containing a particular element.\n\n Args:\n list_of_lists: A list of lists.\n element: The element to search for.\n\n Returns:\n The number of sublists containing the element.\n \"\"\"\n count = 0\n for sublist in list_of_lists:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(list_of_lists, element):\n \"\"\"Counts the number of sublists containing a particular element.\n\n Args:\n list_of_lists: A list of lists.\n element: The element to search for.\n\n Returns:\n The number of sublists containing the element.\n \"\"\"\n count = 0\n for sublist in list_of_lists:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(list_of_lists, element):\n \"\"\"\n Counts the number of sublists containing a particular element.\n\n Args:\n list_of_lists: A list of lists.\n element: The element to search for.\n\n Returns:\n The number of sublists containing the element.\n \"\"\"\n count = 0\n for sublist in list_of_lists:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(list_of_lists, element):\n \"\"\"\n Counts the number of sublists containing a particular element.\n\n Args:\n list_of_lists: A list of lists.\n element: The element to search for.\n\n Returns:\n The number of sublists containing the element.\n \"\"\"\n\n count = 0\n for sublist in list_of_lists:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(list_of_lists, element):\n \"\"\"Counts the number of sublists containing a particular element.\n\n Args:\n list_of_lists: A list of lists.\n element: The element to search for.\n\n Returns:\n The number of sublists containing the element.\n \"\"\"\n count = 0\n for sublist in list_of_lists:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(list_of_lists, element):\n \"\"\"\n Counts the number of sublists containing a particular element.\n\n Args:\n list_of_lists: A list of lists.\n element: The element to search for.\n\n Returns:\n The number of sublists containing the element.\n \"\"\"\n\n count = 0\n for sublist in list_of_lists:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}]}, "Mbpp/428": {"dps": 28.553719008264462, "dps_norm": 45.0, "pass@1": 100.0, "profiled": [{"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2\n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n return arr", "matching_cluster_idx": 3}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2\n\n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n return arr", "matching_cluster_idx": 3}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2\n\n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n\n gap //= 2\n\n return arr", "matching_cluster_idx": 3}, {"solution": "def shell_sort(arr):\n \"\"\"\n Sorts an array using shell sort algorithm.\n\n Args:\n arr: A list of numbers to be sorted.\n\n Returns:\n The sorted list.\n \"\"\"\n n = len(arr)\n gap = n // 2\n\n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n\n return arr", "matching_cluster_idx": 3}, {"solution": "def shell_sort(arr):\n \"\"\"\n Sorts the given array using Shell sort algorithm.\n\n Args:\n arr: The input array to be sorted.\n\n Returns:\n The sorted array.\n \"\"\"\n\n n = len(arr)\n gap = n // 2\n\n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n\n return arr\narr = [12, 23, 4, 5, 3, 2, 12, 81, 56, 95]", "matching_cluster_idx": 3}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2\n\n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n\n gap //= 2\n\n return arr", "matching_cluster_idx": 3}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2\n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n return arr", "matching_cluster_idx": 3}, {"solution": "def shell_sort(arr):\n \"\"\"Sorts the given array using shell sort.\n\n Args:\n arr: The array to be sorted.\n\n Returns:\n The sorted array.\n \"\"\"\n n = len(arr)\n gap = n // 2\n\n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n \"\"\"\n Sorts the given array using shell sort algorithm.\n\n Args:\n arr: A list of numbers to be sorted.\n\n Returns:\n A sorted list of numbers.\n \"\"\"\n n = len(arr)\n gap = n // 2 \n\n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n return arr", "matching_cluster_idx": 3}, {"solution": "def shell_sort(arr):\n \"\"\"\n Sorts a list using Shell Sort.\n \"\"\"\n n = len(arr)\n gap = n // 2\n\n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n return arr\narr = [12, 23, 4, 5, 3, 2, 12, 81, 56, 95]", "matching_cluster_idx": 3}, {"solution": "def shell_sort(arr):\n \"\"\"\n Sorts the given array using shell sort.\n\n Args:\n arr: A list of numbers to be sorted.\n\n Returns:\n The sorted list.\n \"\"\"\n n = len(arr)\n gap = n // 2\n\n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n return arr", "matching_cluster_idx": 3}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2\n\n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n return arr", "matching_cluster_idx": 3}, {"solution": "def shell_sort(array):\n \"\"\"\n Sorts the given array using shell sort.\n\n Args:\n array: The array to be sorted.\n\n Returns:\n The sorted array.\n \"\"\"\n\n n = len(array)\n gap = n // 2\n\n while gap > 0:\n for i in range(gap, n):\n temp = array[i]\n j = i\n while j >= gap and array[j - gap] > temp:\n array[j] = array[j - gap]\n j -= gap\n array[j] = temp\n gap //= 2\n\n return array", "matching_cluster_idx": 3}, {"solution": "def shell_sort(arr):\n \"\"\"\n Sorts the given array using shell sort algorithm.\n\n Args:\n arr: The array to be sorted.\n\n Returns:\n The sorted array.\n \"\"\"\n\n n = len(arr)\n gap = n // 2 \n\n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n return arr\narr = [12, 23, 4, 5, 3, 2, 12, 81, 56, 95]", "matching_cluster_idx": 3}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2\n\n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n\n return arr", "matching_cluster_idx": 3}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2 \n\n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n\n arr[j] = temp\n\n gap //= 2\n return arr", "matching_cluster_idx": 3}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2\n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n return arr", "matching_cluster_idx": 3}, {"solution": "def shell_sort(arr):\n \"\"\"\n Sorts a given array using shell sort.\n\n Args:\n arr: The array to be sorted.\n\n Returns:\n The sorted array.\n \"\"\"\n n = len(arr)\n gap = n // 2\n\n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n return arr\narr = [12, 23, 4, 5, 3, 2, 12, 81, 56, 95]", "matching_cluster_idx": 3}, {"solution": "def shell_sort(arr):\n \"\"\"Sorts a given array using Shell sort.\n\n Args:\n arr: The array to be sorted.\n\n Returns:\n The sorted array.\n \"\"\"\n n = len(arr)\n gap = n // 2\n\n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n return arr\narr = [12, 23, 4, 5, 3, 2, 12, 81, 56, 95]", "matching_cluster_idx": 3}, {"solution": "def shell_sort(arr):\n \"\"\"Sorts the given array using shell sort.\"\"\"\n n = len(arr)\n gap = n // 2\n\n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n return arr", "matching_cluster_idx": 3}]}, "Mbpp/433": {"dps": 91.22340425531915, "dps_norm": 95.0, "pass@1": 100.0, "profiled": [{"solution": "def check_greater(array, number):\n \"\"\"\n Check if a number is greater than all elements in an array.\n\n Args:\n array: A list of numbers.\n number: The number to compare against the array elements.\n\n Returns:\n True if the number is greater than all elements in the array, False otherwise.\n \"\"\"\n for element in array:\n if number <= element:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def check_greater(arr, num):\n \"\"\"\n Checks if a given number is greater than all elements in an array.\n\n Args:\n arr: A list of numbers.\n num: The number to compare against.\n\n Returns:\n True if num is greater than all elements in arr, False otherwise.\n \"\"\"\n for x in arr:\n if num <= x:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def check_greater(arr, n):\n \"\"\"\n Checks whether the entered number is greater than all elements of the given array.\n\n Args:\n arr: A list of numbers.\n n: The number to compare against the array elements.\n\n Returns:\n True if n is greater than all elements in the array, False otherwise.\n \"\"\"\n for element in arr:\n if n <= element:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def check_greater(arr, num):\n \"\"\"Checks if a given number is greater than all elements in an array.\n\n Args:\n arr: A list of numbers.\n num: The number to compare against.\n\n Returns:\n True if num is greater than all elements in arr, False otherwise.\n \"\"\"\n for element in arr:\n if num <= element:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def check_greater(arr, number):\n \"\"\"\n This function checks if a given number is greater than all elements in an array.\n\n Args:\n arr: A list of numbers.\n number: The number to compare against the elements of the array.\n\n Returns:\n True if the number is greater than all elements in the array, False otherwise.\n \"\"\"\n for i in arr:\n if number <= i:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def check_greater(array, number):\n \"\"\"\n Checks whether the given number is greater than all elements in the given array.\n\n Args:\n array: A list of numbers.\n number: The number to compare against the elements of the array.\n\n Returns:\n True if the number is greater than all elements in the array, False otherwise.\n \"\"\"\n for element in array:\n if number <= element:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def check_greater(array, number):\n \"\"\"\n Checks whether the entered number is greater than all elements of the given array.\n\n Args:\n array: A list of numbers.\n number: The number to compare against the elements of the array.\n\n Returns:\n True if the number is greater than all elements in the array, False otherwise.\n \"\"\"\n for element in array:\n if number <= element:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def check_greater(arr, num):\n \"\"\"\n Checks whether the entered number is greater than all elements of the given array.\n\n Args:\n arr: A list of numbers.\n num: The number to compare against the elements of the array.\n\n Returns:\n True if num is greater than all elements of arr, False otherwise.\n \"\"\"\n\n for element in arr:\n if num <= element:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def check_greater(arr, num):\n \"\"\"\n Checks if a given number is greater than all elements in an array.\n\n Args:\n arr: A list of numbers.\n num: The number to compare against.\n\n Returns:\n True if num is greater than all elements in arr, False otherwise.\n \"\"\"\n for element in arr:\n if num <= element:\n return False\n return True", "matching_cluster_idx": 3}, {"solution": "def check_greater(arr, num):\n \"\"\"\n Checks whether the entered number is greater than all elements of the given array.\n\n Args:\n arr: A list of numbers.\n num: The number to compare.\n\n Returns:\n True if the number is greater than all elements in the array, False otherwise.\n \"\"\"\n\n for element in arr:\n if num <= element:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def check_greater(arr, num):\n \"\"\"\n Checks whether the entered number is greater than all elements of the given array.\n\n Args:\n arr: A list of numbers.\n num: The number to compare against.\n\n Returns:\n True if num is greater than all elements in arr, False otherwise.\n \"\"\"\n for element in arr:\n if num <= element:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def check_greater(arr, number):\n \"\"\"Checks if a given number is greater than all elements in an array.\n\n Args:\n arr: A list of numbers.\n number: The number to compare against.\n\n Returns:\n True if the number is greater than all elements in the array, False otherwise.\n \"\"\"\n for elem in arr:\n if number <= elem:\n return False\n return True", "matching_cluster_idx": 3}, {"solution": "def check_greater(arr, num):\n \"\"\"Checks whether the entered number is greater than all elements of the given array.\n\n Args:\n arr: A list of numbers.\n num: The number to compare against.\n\n Returns:\n True if num is greater than all elements in arr, False otherwise.\n \"\"\"\n\n for element in arr:\n if num <= element:\n return False\n return True", "matching_cluster_idx": 3}, {"solution": "def check_greater(arr, number):\n \"\"\"\n Checks whether the given number is greater than all elements in the array.\n\n Args:\n arr: A list of numbers.\n number: The number to compare.\n\n Returns:\n True if the number is greater than all elements in the array, False otherwise.\n \"\"\"\n for element in arr:\n if number <= element:\n return False\n return True", "matching_cluster_idx": 3}, {"solution": "def check_greater(arr, num):\n \"\"\"\n Checks whether the entered number is greater than all elements of the given array.\n\n Args:\n arr: A list of numbers.\n num: The number to compare against.\n\n Returns:\n True if num is greater than all elements in arr, False otherwise.\n \"\"\"\n for element in arr:\n if num <= element:\n return False\n return True", "matching_cluster_idx": 3}, {"solution": "def check_greater(arr, num):\n \"\"\"\n Checks if a given number is greater than all elements in an array.\n\n Args:\n arr: A list of numbers.\n num: The number to compare against the elements of the array.\n\n Returns:\n True if the number is greater than all elements in the array, False otherwise.\n \"\"\"\n for element in arr:\n if num <= element:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def check_greater(arr, num):\n \"\"\"\n Checks if a given number is greater than all elements of an array.\n\n Args:\n arr: A list of numbers.\n num: The number to compare against the array elements.\n\n Returns:\n True if the number is greater than all elements of the array, False otherwise.\n \"\"\"\n\n for element in arr:\n if num <= element:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def check_greater(arr, num):\n \"\"\"\n Checks whether the entered number is greater than all elements of the given array.\n\n Args:\n arr: A list of numbers.\n num: The number to compare against.\n\n Returns:\n True if the number is greater than all elements in the array, False otherwise.\n \"\"\"\n for element in arr:\n if num <= element:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def check_greater(arr, num):\n \"\"\"\n This function checks if a given number is greater than all elements of an array.\n Args:\n arr: A list of numbers.\n num: The number to compare against the array elements.\n Returns:\n True if the number is greater than all elements of the array, False otherwise.\n \"\"\"\n for element in arr:\n if num <= element:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def check_greater(array, number):\n \"\"\"\n Checks whether the entered number is greater than all elements of the given array.\n\n Args:\n array: A list of numbers.\n number: The number to compare against the array elements.\n\n Returns:\n True if the number is greater than all elements in the array, False otherwise.\n \"\"\"\n for element in array:\n if number <= element:\n return False\n return True", "matching_cluster_idx": 4}]}, "Mbpp/437": {"dps": 74.04411764705883, "dps_norm": 29.0, "pass@1": 39.0, "profiled": [{"solution": "def remove_odd(text):\n \"\"\"Removes every second character from a string, starting with the second character.\n \n Args:\n text: The input string.\n\n Returns:\n The string with every second character removed.\n \"\"\"\n\n return text[1::2]", "matching_cluster_idx": 4}, {"solution": "def remove_odd(text):\n \"\"\"Removes every other character from a string, starting with the second character.\n For example:\n remove_odd(\"python\") == \"yhn\"\n \"\"\"\n return text[1::2]", "matching_cluster_idx": 4}, {"solution": "def remove_odd(text):\n \"\"\"\n Removes characters at odd indices in a string.\n\n Args:\n text (str): The input string.\n\n Returns:\n str: A new string with characters at odd indices removed.\n \"\"\"\n return ''.join(text[i] for i in range(len(text)) if i % 2 != 0)", "matching_cluster_idx": 0}, {"solution": "def remove_odd(string):\n \"\"\"\n This function removes odd characters from a string.\n For example:\n remove_odd(\"python\") == \"yhn\"\n \"\"\"\n new_string = \"\"\n for i, char in enumerate(string):\n if i % 2 != 0: \n new_string += char\n return new_string", "matching_cluster_idx": 0}, {"solution": "def remove_odd(s):\n return \"\".join([c for i, c in enumerate(s) if i % 2 != 0])", "matching_cluster_idx": 0}, {"solution": "def remove_odd(text):\n \"\"\"\n Removes characters at odd indices in a string.\n\n Args:\n text: The input string.\n\n Returns:\n A new string with characters at odd indices removed.\n \"\"\"\n return ''.join(text[i] for i in range(len(text)) if i % 2 == 1)", "matching_cluster_idx": 0}, {"solution": "def remove_odd(text):\n \"\"\"\n This function removes characters from a string at odd indices.\n \"\"\"\n return ''.join([text[i] for i in range(len(text)) if i % 2 != 0])", "matching_cluster_idx": 0}, {"solution": "def remove_odd(text):\n \"\"\"\n Removes characters at odd indices from a string.\n For example:\n remove_odd(\"python\") == \"yhn\"\n \"\"\"\n return \"\".join([text[i] for i in range(len(text)) if i % 2 != 0])", "matching_cluster_idx": 0}, {"solution": "def remove_odd(text):\n \"\"\"\n This function removes characters at odd indices from a string.\n\n Args:\n text: The input string.\n\n Returns:\n A new string with characters at odd indices removed.\n \"\"\"\n return ''.join([text[i] for i in range(len(text)) if i % 2 != 0])", "matching_cluster_idx": 1}, {"solution": "def remove_odd(text):\n \"\"\"\n This function removes characters at odd indices from a string.\n\n Args:\n text: The input string.\n\n Returns:\n A new string with characters at odd indices removed.\n \"\"\"\n return \"\".join(text[i] for i in range(len(text)) if i % 2 != 0)", "matching_cluster_idx": 0}, {"solution": "def remove_odd(string):\n \"\"\"Removes odd-indexed characters from a string.\"\"\"\n return \"\".join(string[i] for i in range(len(string)) if i % 2 != 0)", "matching_cluster_idx": 0}, {"solution": "def remove_odd(text):\n \"\"\"Removes odd-indexed characters from a string.\"\"\"\n return \"\".join(text[i] for i in range(len(text)) if i % 2 == 1)", "matching_cluster_idx": 0}, {"solution": "def remove_odd(s):\n \"\"\"\n Removes characters at odd indices from a string.\n\n Args:\n s: The input string.\n\n Returns:\n A new string with characters at odd indices removed.\n \"\"\"\n return ''.join(s[i] for i in range(len(s)) if i % 2 != 0)", "matching_cluster_idx": 0}, {"solution": "def remove_odd(text):\n \"\"\"\n This function removes characters at odd indices in a string.\n \"\"\"\n return \"\".join(text[i] for i in range(len(text)) if i % 2 != 0)", "matching_cluster_idx": 0}, {"solution": "def remove_odd(text):\n \"\"\"\n This function removes characters at odd indices in a string.\n\n Args:\n text: The input string.\n\n Returns:\n A string with characters at odd indices removed.\n \"\"\"\n return \"\".join([text[i] for i in range(len(text)) if i % 2 != 0])", "matching_cluster_idx": 0}, {"solution": "def remove_odd(string):\n return \"\".join(string[i] for i in range(len(string)) if i % 2 != 0)", "matching_cluster_idx": 0}, {"solution": "def remove_odd(text):\n \"\"\"\n This function removes characters from a string at odd indices.\n\n Args:\n text: The string to process.\n\n Returns:\n A new string with characters at odd indices removed.\n \"\"\"\n return ''.join([text[i] for i in range(len(text)) if i % 2 == 1])", "matching_cluster_idx": 0}, {"solution": "def remove_odd(text):\n \"\"\"\n This function removes characters at odd indices from a string.\n\n Args:\n text: The input string.\n\n Returns:\n A new string with characters at odd indices removed.\n \"\"\"\n return ''.join(text[i] for i in range(len(text)) if i % 2 != 0)", "matching_cluster_idx": 0}, {"solution": "def remove_odd(string):\n \"\"\"\n This function removes characters at odd indices from a given string.\n\n Args:\n string: The input string.\n\n Returns:\n A new string with characters at odd indices removed.\n \"\"\"\n return ''.join([string[i] for i in range(len(string)) if i % 2 != 0])", "matching_cluster_idx": 0}, {"solution": "def remove_odd(text):\n \"\"\"\n Removes characters at odd indices from a string.\n For example:\n remove_odd(\"python\") == \"yhn\"\n \"\"\"\n return \"\".join(text[i] for i in range(len(text)) if i % 2 != 0)", "matching_cluster_idx": 0}]}, "Mbpp/440": {"dps": null, "dps_norm": null, "pass@1": 0.0, "profiled": []}, "Mbpp/446": {"dps": 96.25615763546799, "dps_norm": 62.0, "pass@1": 94.0, "profiled": [{"solution": "def count_Occurrence(input_tuple, target_list):\n \"\"\"\n This function counts the occurrences of elements from a target list within a given tuple.\n\n Args:\n input_tuple: The tuple in which to search for the elements.\n target_list: A list of elements to count occurrences of.\n\n Returns:\n The total count of occurrences of elements from target_list within input_tuple.\n \"\"\"\n count = 0\n for element in target_list:\n count += input_tuple.count(element)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(input_tuple, elements):\n \"\"\"\n Counts the occurrences of elements in a tuple.\n\n Args:\n input_tuple: A tuple of elements.\n elements: A list of elements to count.\n\n Returns:\n The total count of occurrences of elements in the tuple.\n \"\"\"\n count = 0\n for element in elements:\n count += input_tuple.count(element)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(input_tuple, elements_to_count):\n \"\"\"\n Counts the occurrences of elements from a list within a tuple.\n\n Args:\n input_tuple: The tuple to search within.\n elements_to_count: A list of elements to count.\n\n Returns:\n An integer representing the total count of occurrences.\n \"\"\"\n\n count = 0\n for element in elements_to_count:\n count += input_tuple.count(element) \n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(data_tuple, target_list):\n \"\"\"Counts the occurrence of elements in target_list within data_tuple.\n\n Args:\n data_tuple: The tuple to search within.\n target_list: The list of elements to count.\n\n Returns:\n The total count of elements from target_list found in data_tuple.\n \"\"\"\n\n count = 0\n for item in target_list:\n count += data_tuple.count(item)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(data_tuple,elements):\n \"\"\"\n This function counts the occurrences of elements in a tuple\n\n Args:\n data_tuple: a tuple of elements.\n elements: a list of elements to count.\n\n Returns:\n The total count of the elements from the list that appear in the tuple.\n \"\"\"\n count = 0\n for element in elements:\n count += data_tuple.count(element)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(data_tuple, elements):\n \"\"\"\n Counts the occurrences of elements from a list within a tuple.\n\n Args:\n data_tuple: The tuple in which to count element occurrences.\n elements: A list of elements to count within the tuple.\n\n Returns:\n The total count of occurrences of the specified elements in the tuple.\n \"\"\"\n count = 0\n for element in elements:\n count += data_tuple.count(element)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(input_tuple, input_list):\n \"\"\"\n Counts the occurrences of elements from a list within a tuple.\n\n Args:\n input_tuple: A tuple containing elements to be checked.\n input_list: A list of elements whose occurrences need to be counted.\n\n Returns:\n The total count of occurrences of elements from the list in the tuple.\n \"\"\"\n count = 0\n for element in input_list:\n count += input_tuple.count(element)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(data: tuple, elements: list) -> int:\n \"\"\"\n Count the occurrence of elements from a list within a tuple.\n\n Args:\n data: The tuple to search within.\n elements: The list of elements to count occurrences of.\n\n Returns:\n The total count of occurrences of elements from the list within the tuple.\n \"\"\"\n count = 0\n for element in elements:\n count += data.count(element)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(data_tuple, target_list):\n \"\"\"\n Counts the occurrence of all elements of a list in a tuple.\n \n Args:\n data_tuple (tuple): The tuple to search within.\n target_list (list): The list of elements to count.\n\n Returns:\n int: The total count of occurrences of elements from target_list in data_tuple.\n \"\"\"\n count = 0\n for item in target_list:\n count += data_tuple.count(item)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(input_tuple, list_elements):\n \"\"\"\n Counts the occurrence of elements from a list within a tuple.\n\n Args:\n input_tuple: A tuple of elements.\n list_elements: A list of elements to count within the tuple.\n\n Returns:\n The total count of occurrences of elements from the list within the tuple.\n \"\"\"\n count = 0\n for element in list_elements:\n count += input_tuple.count(element)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(data, elements):\n \"\"\"\n Counts the occurrence of all elements in a tuple.\n\n Args:\n data: A tuple of elements.\n elements: A list of elements to count.\n\n Returns:\n The total count of occurrences of the elements in the tuple.\n \"\"\"\n count = 0\n for element in elements:\n count += data.count(element)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(input_tuple, target_list):\n \"\"\"\n This function counts the occurrences of elements from a list within a tuple.\n\n Args:\n input_tuple: A tuple of elements.\n target_list: A list of elements to count within the tuple.\n\n Returns:\n The total count of occurrences of the elements in target_list within input_tuple.\n \"\"\"\n count = 0\n for element in target_list:\n count += input_tuple.count(element)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(data, targets):\n \"\"\"\n Counts the occurrence of elements in a tuple.\n\n Args:\n data: A tuple of elements.\n targets: A list of elements to count.\n\n Returns:\n The total count of target elements in the tuple.\n \"\"\"\n count = 0\n for item in targets:\n count += data.count(item)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(input_tuple, target_list):\n \"\"\"\n Counts the occurrences of all elements in a list within a tuple.\n\n Args:\n input_tuple (tuple): The tuple to search within.\n target_list (list): The list of elements to count.\n\n Returns:\n int: The total count of all target elements in the tuple.\n \"\"\"\n count = 0\n for element in target_list:\n count += input_tuple.count(element)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(data_tuple, elements_list):\n \"\"\"\n Counts the occurrence of all elements in a list within a tuple.\n\n Args:\n data_tuple: A tuple of elements.\n elements_list: A list of elements to count in the tuple.\n\n Returns:\n The total count of elements in 'elements_list' found in 'data_tuple'.\n \"\"\"\n\n count = 0\n for element in elements_list:\n count += data_tuple.count(element) \n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(data_tuple, elements):\n \"\"\"\n Counts the occurrences of elements in a tuple.\n\n Args:\n data_tuple: A tuple of elements.\n elements: A list of elements to count.\n\n Returns:\n The total count of occurrences of the elements in the tuple.\n \"\"\"\n count = 0\n for element in elements:\n count += data_tuple.count(element)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(input_tuple, elements_to_count):\n \"\"\"\n Counts the occurrences of specified elements within a tuple.\n\n Args:\n input_tuple: The tuple to search within.\n elements_to_count: A list of elements to count occurrences for.\n\n Returns:\n The total count of occurrences of the specified elements.\n \"\"\"\n\n count = 0\n for element in elements_to_count:\n count += input_tuple.count(element)\n return count", "matching_cluster_idx": 2}, {"solution": "from collections import Counter\ndef count_Occurrence(input_tuple, target_list):\n \"\"\"Counts the occurrence of elements in a tuple from a given list.\n\n Args:\n input_tuple: A tuple containing elements to be counted.\n target_list: A list of elements whose occurrences need to be counted.\n\n Returns:\n An integer representing the total count of elements from the target list within the tuple.\n \"\"\"\n # Use Counter to efficiently count all elements in the tuple\n element_counts = Counter(input_tuple)\n total_count = 0\n\n # Iterate through the target list and sum the counts of each element\n for element in target_list:\n total_count += element_counts.get(element, 0) \n\n return total_count", "matching_cluster_idx": 4}, {"solution": "def count_Occurrence(data_tuple, target_list):\n \"\"\"\n Counts the occurrence of elements from target_list within a given tuple.\n\n Args:\n data_tuple: A tuple containing elements to be counted.\n target_list: A list of elements to search for in the tuple.\n\n Returns:\n The total count of occurrences of elements from target_list in data_tuple.\n \"\"\"\n count = 0\n for item in target_list:\n count += data_tuple.count(item)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(input_tuple, target_list):\n \"\"\"\n Counts the occurrence of all elements of a list within a tuple.\n\n Args:\n input_tuple: The tuple to search within.\n target_list: The list of elements to count.\n\n Returns:\n The total count of all target elements in the tuple.\n \"\"\"\n count = 0\n for item in target_list:\n count += input_tuple.count(item)\n return count", "matching_cluster_idx": 2}]}, "Mbpp/451": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 64.0, "profiled": [{"solution": "def remove_whitespaces(text: str) -> str:\n \"\"\"\n Write a function to remove all whitespaces from the given string.\n assert remove_whitespaces(' Google Flutter ') == 'GoogleFlutter'\n \"\"\"\n return text.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(text: str) -> str:\n \"\"\"Removes all whitespaces from a string.\n\n Args:\n text: The input string.\n\n Returns:\n The string with all whitespaces removed.\n \"\"\"\n return text.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(text):\n \"\"\"Removes all whitespaces from the given string.\n\n Args:\n text: The input string.\n\n Returns:\n The string with all whitespaces removed.\n \"\"\"\n return text.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(text):\n \"\"\"Removes all whitespaces from the given string.\"\"\"\n return text.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(text):\n \"\"\"Removes all whitespaces from the given string.\n\n Args:\n text: The string to remove whitespaces from.\n\n Returns:\n The string without whitespaces.\n \"\"\"\n return text.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(text):\n \"\"\"\n This function removes all whitespaces from the given string.\n\n Args:\n text: The input string.\n\n Returns:\n The string with all whitespaces removed.\n \"\"\"\n return text.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(text: str) -> str:\n \"\"\"\n This function removes all whitespaces from the given string.\n\n Args:\n text: The input string.\n\n Returns:\n The string with all whitespaces removed.\n \"\"\"\n return text.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(text):\n \"\"\"\n Removes all whitespaces from the given string.\n\n Args:\n text: The string to remove whitespaces from.\n\n Returns:\n The string with all whitespaces removed.\n \"\"\"\n return text.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(text):\n \"\"\"\n Removes all whitespaces from the given string.\n\n Args:\n text: The input string.\n\n Returns:\n The string with all whitespaces removed.\n \"\"\"\n return text.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(text: str) -> str:\n \"\"\"\n Write a function to remove all whitespaces from the given string.\n assert remove_whitespaces(' Google Flutter ') == 'GoogleFlutter'\n \"\"\"\n return text.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(text):\n \"\"\"\n This function removes all whitespaces from the given string.\n\n Args:\n text: The string from which whitespaces need to be removed.\n\n Returns:\n The string without any whitespaces.\n \"\"\"\n return text.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(text):\n \"\"\"Removes all whitespaces from the given string.\n\n Args:\n text: The input string.\n\n Returns:\n The string with all whitespaces removed.\n \"\"\"\n return text.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(text):\n \"\"\"\n Removes all whitespaces from the given string.\n\n Args:\n text: The input string.\n\n Returns:\n The string with all whitespaces removed.\n \"\"\"\n return text.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(text):\n \"\"\"\n This function removes all whitespaces from a given string.\n\n Args:\n text: The input string.\n\n Returns:\n The string with all whitespaces removed.\n \"\"\"\n return text.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(text):\n \"\"\"Removes all whitespaces from the given string.\n\n Args:\n text: The input string.\n\n Returns:\n The string with all whitespaces removed.\n \"\"\"\n return text.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(text):\n \"\"\"\n This function removes all whitespaces from the given string.\n\n Args:\n text: The string to remove whitespaces from.\n\n Returns:\n The string without whitespaces.\n \"\"\"\n return text.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(text: str) -> str:\n \"\"\"\n Write a function to remove all whitespaces from the given string.\n assert remove_whitespaces(' Google Flutter ') == 'GoogleFlutter'\n \"\"\"\n return text.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(text):\n \"\"\"\n This function removes all whitespaces from a given string.\n\n Args:\n text: The input string.\n\n Returns:\n The string with all whitespaces removed.\n \"\"\"\n return text.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(text: str) -> str:\n \"\"\"\n Write a function to remove all whitespaces from the given string.\n assert remove_whitespaces(' Google Flutter ') == 'GoogleFlutter'\n \"\"\"\n return text.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(text):\n \"\"\"Removes all whitespaces from the given string.\n\n Args:\n text: The string to remove whitespaces from.\n\n Returns:\n The string with all whitespaces removed.\n \"\"\"\n return text.replace(\" \", \"\")", "matching_cluster_idx": 4}]}, "Mbpp/456": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def reverse_string_list(string_list):\n \"\"\"Reverses each string in a given list of string values.\n\n Args:\n string_list: A list of strings.\n\n Returns:\n A new list with each string in the input list reversed.\n \"\"\"\n return [string[::-1] for string in string_list]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(strings):\n \"\"\"Reverses each string in a given list of string values.\n\n Args:\n strings: A list of strings.\n\n Returns:\n A new list containing the reversed strings.\n \"\"\"\n return [s[::-1] for s in strings]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n \"\"\"\n Reverses each string in a list.\n\n Args:\n string_list: A list of strings.\n\n Returns:\n A new list with each string reversed.\n \"\"\"\n return [string[::-1] for string in string_list]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n \"\"\"\n Reverses each string in a given list of string values.\n\n Args:\n string_list: A list of string values.\n\n Returns:\n A new list with each string reversed.\n \"\"\"\n return [string[::-1] for string in string_list]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(input_list):\n \"\"\"\n Reverses each string in a list of strings.\n\n Args:\n input_list: A list of strings.\n\n Returns:\n A new list with each string in the input list reversed.\n \"\"\"\n\n reversed_list = [s[::-1] for s in input_list]\n return reversed_list", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n \"\"\"\n Reverses each string in a given list of string values.\n\n Args:\n string_list: A list of strings.\n\n Returns:\n A new list with each string reversed.\n \"\"\"\n return [string[::-1] for string in string_list]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n \"\"\"Reverses each string in a given list of strings.\n \n Args:\n string_list: A list of strings.\n\n Returns:\n A new list with each string reversed.\n \"\"\"\n return [string[::-1] for string in string_list]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(str_list):\n \"\"\"Reverses each string in a given list of strings.\n\n Args:\n str_list: A list of strings.\n\n Returns:\n A new list with each string in str_list reversed.\n \"\"\"\n return [s[::-1] for s in str_list]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n \"\"\"Reverses each string in a list.\n\n Args:\n string_list: A list of strings.\n\n Returns:\n A new list with each string reversed.\n \"\"\"\n return [s[::-1] for s in string_list]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n \"\"\"Reverses each string in a given list of string values.\n\n Args:\n string_list: A list of strings.\n\n Returns:\n A new list with each string reversed.\n \"\"\"\n return [s[::-1] for s in string_list]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n \"\"\"Reverses each string in a given list of string values.\n\n Args:\n string_list: A list of strings.\n\n Returns:\n A new list with each string reversed.\n \"\"\"\n\n return [s[::-1] for s in string_list]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(strings):\n \"\"\"\n Reverses each string in a given list of string values.\n \n Args:\n strings: A list of strings.\n \n Returns:\n A new list with the strings in the input list reversed.\n \"\"\"\n return [string[::-1] for string in strings]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n \"\"\"\n Reverses each string in a given list of string values.\n\n Args:\n string_list: A list of strings.\n\n Returns:\n A new list with each string reversed.\n \"\"\"\n return [string[::-1] for string in string_list]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n \"\"\"Reverses each string in a given list of string values.\n\n Args:\n string_list: A list of strings.\n\n Returns:\n A list of strings with each string reversed.\n \"\"\"\n return [string[::-1] for string in string_list]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(strings):\n \"\"\"\n This function takes a list of strings and returns a new list with each string reversed.\n\n Args:\n strings: A list of strings.\n\n Returns:\n A new list with each string in the input list reversed.\n \"\"\"\n return [string[::-1] for string in strings]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n \"\"\"Reverses each string in a list of strings.\n \n Args:\n string_list: A list of strings.\n \n Returns:\n A new list with each string in the input list reversed.\n \"\"\"\n return [s[::-1] for s in string_list]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(strings):\n \"\"\"\n Reverses each string in a given list of strings.\n\n Args:\n strings: A list of strings.\n\n Returns:\n A new list with each string reversed.\n \"\"\"\n return [string[::-1] for string in strings]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n \"\"\"\n Reverses each string in a given list of string values.\n\n Args:\n string_list: A list of string values.\n\n Returns:\n A list of strings with each original string reversed.\n \"\"\"\n return [string[::-1] for string in string_list]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n \"\"\"Reverses each string in a given list of string values.\n\n Args:\n string_list: A list of string values.\n\n Returns:\n A new list with each string in the input list reversed.\n \"\"\"\n\n return [string[::-1] for string in string_list]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n \"\"\"Reverses each string in a given list of strings.\n\n Args:\n string_list: A list of strings.\n\n Returns:\n A new list with each string in the input list reversed.\n \"\"\"\n return [string[::-1] for string in string_list]", "matching_cluster_idx": 4}]}, "Mbpp/460": {"dps": 87.01923076923077, "dps_norm": 95.0, "pass@1": 100.0, "profiled": [{"solution": "def Extract(lists):\n \"\"\"\n Extracts the first element of each sublist in a list of lists.\n\n Args:\n lists: A list of lists.\n\n Returns:\n A list containing the first elements of each sublist.\n \"\"\"\n return [sublist[0] for sublist in lists]", "matching_cluster_idx": 4}, {"solution": "def Extract(lst):\n return [sublist[0] for sublist in lst]", "matching_cluster_idx": 4}, {"solution": "def Extract(lst):\n \"\"\"\n This function takes a list of lists as input and returns a new list containing the first element of each sublist.\n\n Args:\n lst: A list of lists.\n\n Returns:\n A new list containing the first element of each sublist.\n \"\"\"\n return [sublist[0] for sublist in lst]", "matching_cluster_idx": 4}, {"solution": "def Extract(lists):\n \"\"\"\n Extracts the first element from each sublist in a list of lists.\n\n Args:\n lists: A list of lists.\n\n Returns:\n A list containing the first element of each sublist.\n \"\"\"\n\n return [sublist[0] for sublist in lists]", "matching_cluster_idx": 4}, {"solution": "def Extract(lst):\n \"\"\"\n Extracts the first element from each sublist in a list.\n\n Args:\n lst: A list of lists.\n\n Returns:\n A new list containing the first elements of each sublist in lst.\n \"\"\"\n return [sublist[0] for sublist in lst]", "matching_cluster_idx": 3}, {"solution": "def Extract(lst):\n \"\"\"\n This function extracts the first element from each sublist within a list.\n\n Args:\n lst: A list of lists.\n\n Returns:\n A list containing the first element of each sublist.\n \"\"\"\n return [sublist[0] for sublist in lst]", "matching_cluster_idx": 4}, {"solution": "def Extract(lst):\n \"\"\"\n This function takes a list of lists as input and returns a new list containing the first element of each sublist.\n\n Args:\n lst: A list of lists.\n\n Returns:\n A new list containing the first element of each sublist.\n \"\"\"\n return [sublist[0] for sublist in lst]", "matching_cluster_idx": 3}, {"solution": "def Extract(lst):\n \"\"\"\n This function extracts the first element from each sublist in a list of lists.\n\n Args:\n lst: A list of lists.\n\n Returns:\n A new list containing the first element of each sublist in lst.\n \"\"\"\n return [sublist[0] for sublist in lst]", "matching_cluster_idx": 4}, {"solution": "def Extract(lst):\n \"\"\"\n Returns a list containing the first element of each sublist in the input list.\n \"\"\"\n return [sublist[0] for sublist in lst]", "matching_cluster_idx": 4}, {"solution": "def Extract(lst):\n \"\"\"\n This function extracts the first element from each sublist.\n\n Args:\n lst: A list of lists.\n\n Returns:\n A list containing the first element of each sublist.\n \"\"\"\n return [sublist[0] for sublist in lst]", "matching_cluster_idx": 4}, {"solution": "def Extract(lst):\n \"\"\"\n Extract the first element of each sublist.\n Args:\n lst: A list of lists.\n Returns:\n A new list containing the first element of each sublist.\n \"\"\"\n return [sublist[0] for sublist in lst]", "matching_cluster_idx": 4}, {"solution": "def Extract(lst):\n \"\"\"\n This function takes a list of lists and returns a new list containing the first element of each sublist.\n\n Args:\n lst: A list of lists.\n\n Returns:\n A new list containing the first elements of each sublist.\n \"\"\"\n return [sublist[0] for sublist in lst]", "matching_cluster_idx": 4}, {"solution": "def Extract(lst):\n return [sublist[0] for sublist in lst]", "matching_cluster_idx": 4}, {"solution": "def Extract(lst):\n \"\"\"\n This function extracts the first element of each sublist in a list.\n\n Args:\n lst: A list of lists.\n\n Returns:\n A new list containing the first element of each sublist.\n \"\"\"\n return [sublst[0] for sublst in lst]", "matching_cluster_idx": 4}, {"solution": "def Extract(list_of_lists):\n \"\"\"\n This function takes a list of lists as input and returns a new list containing the first element of each sublist.\n\n Args:\n list_of_lists: A list of lists.\n\n Returns:\n A new list containing the first element of each sublist.\n\n Raises:\n TypeError: If the input is not a list of lists.\n \"\"\"\n if not isinstance(list_of_lists, list):\n raise TypeError(\"Input must be a list of lists.\")\n\n return [sublist[0] for sublist in list_of_lists]", "matching_cluster_idx": 4}, {"solution": "def Extract(lst):\n \"\"\"\n This function takes a list of lists and returns a new list containing only the first element of each sublist.\n\n Args:\n lst (list): A list of lists.\n\n Returns:\n list: A new list containing the first element of each sublist.\n \"\"\"\n\n return [sublist[0] for sublist in lst]", "matching_cluster_idx": 4}, {"solution": "def Extract(lst):\n \"\"\"\n Extracts the first element of each sublist.\n\n Args:\n lst: A list of lists.\n\n Returns:\n A list containing the first elements of each sublist.\n \"\"\"\n return [sublist[0] for sublist in lst]", "matching_cluster_idx": 3}, {"solution": "def Extract(list_of_lists):\n \"\"\"\n Extracts the first element of each sublist.\n\n Args:\n list_of_lists: A list of lists.\n\n Returns:\n A list containing the first element of each sublist.\n \"\"\"\n return [sublist[0] for sublist in list_of_lists]", "matching_cluster_idx": 3}, {"solution": "def Extract(sublists):\n \"\"\"\n Extracts the first element of each sublist.\n\n Args:\n sublists: A list of lists.\n\n Returns:\n A new list containing the first element of each sublist.\n \"\"\"\n return [sublist[0] for sublist in sublists]", "matching_cluster_idx": 3}, {"solution": "def Extract(lst):\n return [sublist[0] for sublist in lst]", "matching_cluster_idx": 4}]}, "Mbpp/474": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def replace_char(text, old_char, new_char):\n \"\"\"Replaces all occurrences of old_char with new_char in a string.\n\n Args:\n text: The input string.\n old_char: The character to be replaced.\n new_char: The character to replace old_char with.\n\n Returns:\n The string with all occurrences of old_char replaced by new_char.\n \"\"\"\n return text.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(text, old_char, new_char):\n \"\"\"\n Replaces all occurrences of a given character in a string with another character.\n\n Args:\n text: The string in which to replace characters.\n old_char: The character to be replaced.\n new_char: The character to replace with.\n\n Returns:\n The modified string with all occurrences of old_char replaced by new_char.\n \"\"\"\n return text.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(text, old_char, new_char):\n \"\"\"\n Replaces all occurrences of a character in a string with another character.\n\n Args:\n text: The input string.\n old_char: The character to be replaced.\n new_char: The character to replace with.\n\n Returns:\n The string with the replaced characters.\n \"\"\"\n return text.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(text, old_char, new_char):\n \"\"\"\n Replaces all occurrences of 'old_char' in 'text' with 'new_char'.\n\n Args:\n text: The string to modify.\n old_char: The character to be replaced.\n new_char: The character to replace 'old_char' with.\n\n Returns:\n The modified string with all occurrences of 'old_char' replaced by 'new_char'.\n \"\"\"\n return text.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(text, old_char, new_char):\n \"\"\"Replaces all occurrences of 'old_char' with 'new_char' in the given string.\n\n Args:\n text: The string to perform the replacement on.\n old_char: The character to be replaced.\n new_char: The character to replace 'old_char' with.\n\n Returns:\n The modified string with replacements made.\n \"\"\"\n return text.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(text, old_char, new_char):\n \"\"\"\n Replaces all occurrences of a specific character in a string with another character.\n\n Args:\n text (str): The string in which characters will be replaced.\n old_char (str): The character to be replaced.\n new_char (str): The character to replace the old character with.\n\n Returns:\n str: The modified string with replacements made.\n \"\"\"\n return text.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(text, old_char, new_char):\n \"\"\"Replaces all occurrences of 'old_char' with 'new_char' in a string.\n \n Args:\n text: The string to modify.\n old_char: The character to replace.\n new_char: The character to replace 'old_char' with.\n\n Returns:\n The string with replacements made.\n \"\"\"\n\n return text.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(text, old_char, new_char):\n \"\"\"\n Replaces all occurrences of old_char with new_char in a string.\n\n Args:\n text: The string to modify.\n old_char: The character to be replaced.\n new_char: The character to replace with.\n\n Returns:\n The string with the characters replaced.\n \"\"\"\n return text.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(text, old_char, new_char):\n \"\"\"Replaces occurrences of old_char with new_char in a string.\n\n Args:\n text: The string to modify.\n old_char: The character to replace.\n new_char: The character to replace old_char with.\n\n Returns:\n The modified string with replacements made.\n \"\"\"\n\n return text.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(text, old_char, new_char):\n \"\"\"\n Replaces all occurrences of 'old_char' with 'new_char' in a string.\n\n Args:\n text: The input string.\n old_char: The character to be replaced.\n new_char: The character to replace 'old_char' with.\n\n Returns:\n The string with 'old_char' replaced by 'new_char'.\n \"\"\"\n return text.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(text, old_char, new_char):\n \"\"\"Replaces all occurrences of old_char with new_char in a string.\n\n Args:\n text: The input string.\n old_char: The character to be replaced.\n new_char: The character to replace with.\n\n Returns:\n The modified string with replacements.\n \"\"\"\n return text.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(text, old_char, new_char):\n \"\"\"\n This function replaces all occurrences of a character in a string with another character.\n \n Args:\n text: The string to be modified.\n old_char: The character to be replaced.\n new_char: The character to replace with.\n\n Returns:\n The modified string with all occurrences of old_char replaced by new_char.\n \"\"\"\n\n return text.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(text, old_char, new_char):\n \"\"\"Replaces all occurrences of 'old_char' with 'new_char' in a string.\"\"\"\n return text.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(text, old_char, new_char):\n \"\"\"\n Replaces all occurrences of old_char with new_char in the given text.\n\n Args:\n text: The string in which to replace characters.\n old_char: The character to be replaced.\n new_char: The character to replace old_char with.\n\n Returns:\n The string with all occurrences of old_char replaced by new_char.\n \"\"\"\n return text.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(text, old_char, new_char):\n \"\"\"Replaces all occurrences of old_char with new_char in a string.\n\n Args:\n text: The input string.\n old_char: The character to be replaced.\n new_char: The character to replace old_char with.\n\n Returns:\n The modified string with replacements.\n \"\"\"\n return text.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(text, old_char, new_char):\n \"\"\"\n This function replaces all occurrences of a given character in a string with another character.\n Args:\n text (str): The string to modify.\n old_char (str): The character to be replaced.\n new_char (str): The character to replace with.\n Returns:\n str: The modified string with all instances of old_char replaced by new_char.\n \"\"\"\n return text.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(text, old_char, new_char):\n \"\"\"\n This function replaces all occurrences of a character in a string.\n\n Args:\n text: The string to modify.\n old_char: The character to be replaced.\n new_char: The character to replace with.\n\n Returns:\n A new string with the replacements made.\n \"\"\"\n return text.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(text, old_char, new_char):\n \"\"\"Replaces all occurrences of a character in a string.\n\n Args:\n text: The string to modify.\n old_char: The character to replace.\n new_char: The character to substitute.\n\n Returns:\n The modified string with replaced characters.\n \"\"\"\n return text.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(text, old_char, new_char):\n \"\"\"Replaces all occurrences of old_char with new_char in a string.\"\"\"\n return text.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(text, old_char, new_char):\n \"\"\"\n Replaces all occurrences of a given character in a string with another character.\n\n Args:\n text: The string to modify.\n old_char: The character to be replaced.\n new_char: The character to replace with.\n\n Returns:\n The modified string with replacements made.\n \"\"\"\n\n return text.replace(old_char, new_char)", "matching_cluster_idx": 6}]}, "Mbpp/476": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def big_sum(arr):\n \"\"\"\n Finds the sum of the largest and smallest value in a given array.\n\n Args:\n arr: A list of numbers.\n\n Returns:\n The sum of the largest and smallest numbers in the array.\n \"\"\"\n if not arr:\n return 0 \n return max(arr) + min(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n \"\"\"\n Finds the sum of the largest and smallest value in a given array.\n\n Args:\n arr: A list of numbers.\n\n Returns:\n The sum of the largest and smallest values in the array.\n \"\"\"\n return max(arr) + min(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n \"\"\"\n This function finds the sum of the largest and smallest value in a given array.\n \n Args:\n arr: A list of numbers.\n \n Returns:\n The sum of the largest and smallest numbers in the array.\n \"\"\"\n if len(arr) == 0:\n return 0\n return max(arr) + min(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n \"\"\"Find the sum of the largest and smallest value in a given array.\n\n Args:\n arr: A list of numbers.\n\n Returns:\n The sum of the largest and smallest numbers in the array.\n \"\"\"\n return max(arr) + min(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n \"\"\"\n Write a python function to find the sum of the largest and smallest value in a given array.\n \"\"\"\n return max(arr) + min(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n \"\"\"\n Find the sum of the largest and smallest values in a given array.\n\n Args:\n arr: A list of numbers.\n\n Returns:\n The sum of the largest and smallest values in the array.\n \"\"\"\n return max(arr) + min(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n \"\"\"\n Finds the sum of the largest and smallest value in a given array.\n\n Args:\n arr: A list of numbers.\n\n Returns:\n The sum of the largest and smallest numbers in the array.\n \"\"\"\n return max(arr) + min(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n \"\"\"Finds the sum of the largest and smallest value in a given array.\n\n Args:\n arr: A list of numbers.\n\n Returns:\n The sum of the largest and smallest elements in the array.\n \"\"\"\n return max(arr) + min(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n \"\"\"\n Find the sum of the largest and smallest value in a given array.\n \"\"\"\n return max(arr) + min(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n \"\"\"\n This function finds the sum of the largest and smallest values in a given array.\n \n Args:\n arr: A list of numbers\n\n Returns:\n The sum of the largest and smallest values in the array.\n \"\"\"\n smallest = min(arr)\n largest = max(arr)\n return smallest + largest", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n \"\"\"\n Finds the sum of the largest and smallest values in a given array.\n\n Args:\n arr: A list of numbers.\n\n Returns:\n The sum of the largest and smallest values in the array.\n \"\"\"\n return max(arr) + min(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n \"\"\"\n This function finds the sum of the largest and smallest value in a given array.\n\n Args:\n arr: A list of numbers.\n\n Returns:\n The sum of the largest and smallest numbers in the array.\n \"\"\"\n return max(arr) + min(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n \"\"\"\n This function takes an array of numbers and returns the sum of the largest and smallest values.\n\n Args:\n arr: A list of numbers.\n\n Returns:\n The sum of the largest and smallest numbers in the array.\n \"\"\"\n return max(arr) + min(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n \"\"\"\n Write a python function to find the sum of the largest and smallest value in a given array.\n \"\"\"\n return max(arr) + min(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n \"\"\"\n Finds the sum of the largest and smallest value in a given array.\n\n Args:\n arr: A list of numbers.\n\n Returns:\n The sum of the largest and smallest values in the array.\n \"\"\"\n return max(arr) + min(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n \"\"\"\n Finds the sum of the largest and smallest value in a given array.\n\n Args:\n arr: A list of numbers.\n\n Returns:\n The sum of the largest and smallest values in the list.\n \"\"\"\n return max(arr) + min(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n \"\"\"\n This function finds the sum of the largest and smallest value in a given array.\n\n Args:\n arr: A list of numbers.\n\n Returns:\n The sum of the largest and smallest value in the array.\n \"\"\"\n return max(arr) + min(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n \"\"\"\n Find the sum of the largest and smallest value in a given array.\n\n Args:\n arr: A list of numbers.\n\n Returns:\n The sum of the largest and smallest values in the array.\n \"\"\"\n return max(arr) + min(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n \"\"\"\n This function takes an array as input and returns the sum of its largest and smallest elements.\n\n Args:\n arr: A list of numbers.\n\n Returns:\n The sum of the largest and smallest values in the input array.\n \"\"\"\n return max(arr) + min(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n \"\"\"\n Finds the sum of the largest and smallest value in a given array.\n\n Args:\n arr: A list of numbers.\n\n Returns:\n The sum of the largest and smallest values in the array.\n \"\"\"\n return max(arr) + min(arr)", "matching_cluster_idx": 5}]}, "Mbpp/477": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def is_lower(text):\n \"\"\"Converts a given string to lowercase.\n\n Args:\n text: The string to be converted.\n\n Returns:\n The lowercase version of the input string.\n \"\"\"\n return text.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(string):\n \"\"\"\n This function converts the given string to lowercase.\n\n Args:\n string: The input string.\n\n Returns:\n The input string converted to lowercase.\n \"\"\"\n return string.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(text):\n \"\"\"\n This function converts the given string to lower case.\n\n Args:\n text: The string to be converted.\n\n Returns:\n The lowercase version of the string.\n \"\"\"\n return text.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(text):\n \"\"\"Converts a string to lowercase.\n\n Args:\n text: The input string.\n\n Returns:\n The input string converted to lowercase.\n \"\"\"\n return text.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(text):\n \"\"\"Converts the given string to lower case.\"\"\"\n return text.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(text):\n \"\"\"\n This function converts the given string to lowercase.\n\n Args:\n text: The input string.\n\n Returns:\n The lowercase version of the input string.\n \"\"\"\n return text.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(text):\n \"\"\"\n This function takes a string as input and returns the string in lower case.\n \"\"\"\n return text.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(text):\n \"\"\"Converts a given string to lowercase.\n\n Args:\n text: The input string.\n\n Returns:\n The input string converted to lowercase.\n \"\"\"\n return text.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(text):\n \"\"\"\n Convert the given string to lower case.\n \"\"\"\n return text.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(text):\n \"\"\"\n This function takes a string and converts it to lowercase.\n\n Args:\n text: The string to be converted to lowercase.\n\n Returns:\n The input string converted to lowercase.\n \"\"\"\n return text.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(text: str) -> str:\n \"\"\"\n Write a python function to convert the given string to lower case.\n\n Example:\n assert is_lower(\"InValid\") == \"invalid\"\n \"\"\"\n return text.lower()\ntext = \"InValid\"", "matching_cluster_idx": 4}, {"solution": "def is_lower(text):\n \"\"\"Converts the given string to lowercase.\n \n Args:\n text: The string to be converted.\n\n Returns:\n The lowercase version of the input string.\n \"\"\"\n return text.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(text: str) -> str:\n \"\"\"\n Convert the given string to lower case.\n\n Args:\n text: The input string.\n\n Returns:\n The string in lower case.\n \"\"\"\n return text.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(text: str) -> str:\n \"\"\"Converts the given string to lowercase.\n\n Args:\n text: The input string.\n\n Returns:\n The input string converted to lowercase.\n \"\"\"\n return text.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(text):\n \"\"\"\n This function converts a string to lowercase.\n \"\"\"\n return text.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(text):\n \"\"\"\n Converts the given string to lower case.\n\n Args:\n text: The string to convert.\n\n Returns:\n The lowercase version of the string.\n \"\"\"\n return text.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(string):\n \"\"\"\n Converts the given string to lowercase.\n\n Args:\n string: The input string.\n\n Returns:\n The string in lowercase.\n \"\"\"\n\n return string.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(text):\n \"\"\"Converts a string to lowercase.\n\n Args:\n text: The input string to be converted to lowercase.\n\n Returns:\n The lowercase version of the input string.\n \"\"\"\n return text.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(text: str) -> str:\n \"\"\"\n This function converts the given string to lower case.\n\n Args:\n text: The input string.\n\n Returns:\n The input string converted to lower case.\n \"\"\"\n return text.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(text: str) -> str:\n \"\"\"\n Write a python function to convert the given string to lower case.\n assert is_lower(\"InValid\") == \"invalid\"\n \"\"\"\n return text.lower()", "matching_cluster_idx": 4}]}, "Mbpp/563": {"dps": 85.24590163934427, "dps_norm": 81.81818181818181, "pass@1": 100.0, "profiled": [{"solution": "import re\ndef extract_values(text):\n \"\"\"\n Extracts values enclosed in double quotes from a string.\n\n Args:\n text: The input string.\n\n Returns:\n A list of extracted values.\n \"\"\"\n return re.findall(r'\"([^\"]*)\"', text)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(text):\n \"\"\"Extracts values between quotation marks from a string.\n\n Args:\n text: The input string.\n\n Returns:\n A list of strings extracted from between quotation marks.\n \"\"\"\n return re.findall(r'\"([^\"]*)\"', text)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(text):\n \"\"\"\n Extracts values between quotation marks from a string.\n\n Args:\n text: The input string.\n\n Returns:\n A list of values extracted from the string.\n \"\"\"\n return re.findall(r'\"([^\"]*)\"', text)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(text):\n \"\"\"\n Extracts values between quotation marks from a string.\n\n Args:\n text: The string to extract values from.\n\n Returns:\n A list of strings containing the values between quotation marks.\n \"\"\"\n return re.findall(r'\"([^\"]*)\"', text)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(text):\n \"\"\"Extracts values between quotation marks from a string.\"\"\"\n return re.findall(r'\"([^\"]*)\"', text)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(text):\n \"\"\"\n Extracts values between quotation marks from a string.\n\n Args:\n text: The input string.\n\n Returns:\n A list of values found between quotation marks.\n \"\"\"\n return re.findall(r'\"([^\"]*)\"', text)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(text):\n \"\"\"\n Extracts values between quotation marks from a string.\n\n Args:\n text: The string to extract values from.\n\n Returns:\n A list of strings containing the values between quotation marks.\n \"\"\"\n return re.findall(r'\"([^\"]*)\"', text)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(text):\n \"\"\"\n Extracts values enclosed in quotation marks from a string.\n\n Args:\n text: The input string.\n\n Returns:\n A list of values enclosed in quotation marks.\n \"\"\"\n return re.findall(r'\"([^\"]*)\"', text)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(text):\n \"\"\"\n Extracts values between quotation marks from a string.\n\n Args:\n text: The input string.\n\n Returns:\n A list of strings containing the values between quotation marks.\n \"\"\"\n return re.findall(r'\"([^\"]*)\"', text)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(text):\n \"\"\"\n Extracts values between quotation marks from a string.\n\n Args:\n text: The input string.\n\n Returns:\n A list of values extracted between quotation marks.\n \"\"\"\n return re.findall(r'\"([^\"]*)\"', text)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(text):\n \"\"\"\n This function extracts values between quotation marks from a string.\n\n Args:\n text: The input string.\n\n Returns:\n A list of strings containing the values between quotation marks.\n \"\"\"\n return re.findall(r'\"([^\"]*)\"', text)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(text):\n \"\"\"\n Extracts values between quotation marks from a string.\n\n Args:\n text: The input string.\n\n Returns:\n A list of strings containing the values between quotation marks.\n \"\"\"\n return re.findall(r'\"([^\"]*)\"', text)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(text):\n \"\"\"\n Extracts values enclosed in double quotes from a string.\n\n Args:\n text: The input string.\n\n Returns:\n A list of strings containing the values between double quotes.\n \"\"\"\n return re.findall(r'\"([^\"]*)\"', text)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(text):\n \"\"\"\n Extracts values between quotation marks from a string.\n \n Args:\n text: The input string containing values in quotation marks.\n \n Returns:\n A list of strings extracted between quotation marks.\n \"\"\"\n return re.findall(r'\"([^\"]*)\"', text)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(text):\n \"\"\"Extracts values enclosed in double quotes from a string.\n\n Args:\n text: The input string.\n\n Returns:\n A list of strings containing the extracted values.\n \"\"\"\n return re.findall(r'\"([^\"]*)\"', text)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(text):\n \"\"\"\n Extracts values enclosed in double quotes from a string.\n\n Args:\n text: The input string.\n\n Returns:\n A list of strings containing the extracted values.\n \"\"\"\n return re.findall(r'\"([^\"]*)\"', text)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(text):\n \"\"\"\n Extracts values between quotation marks from a string.\n\n Args:\n text: The input string.\n\n Returns:\n A list of strings extracted from between the quotation marks.\n \"\"\"\n return re.findall(r'\"([^\"]*)\"', text)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(text):\n \"\"\"\n Extracts values between quotation marks from a string.\n\n Args:\n text: The string to extract values from.\n\n Returns:\n A list of values found between quotation marks.\n \"\"\"\n\n return re.findall(r'\"(.*?)\"', text)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(text):\n \"\"\"\n Extracts values between quotation marks from a string.\n\n Args:\n text: The string to extract values from.\n\n Returns:\n A list of strings containing the extracted values.\n \"\"\"\n return re.findall(r'\"([^\"]*)\"', text)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(text):\n \"\"\"\n Extracts values between quotation marks from a string.\n\n Args:\n text: The string to extract values from.\n\n Returns:\n A list of strings containing the values between quotation marks.\n \"\"\"\n return re.findall(r'\"(.*?)\"', text)", "matching_cluster_idx": 8}]}, "Mbpp/572": {"dps": null, "dps_norm": null, "pass@1": 9.0, "profiled": []}, "Mbpp/578": {"dps": 64.17460317460318, "dps_norm": 65.0, "pass@1": 100.0, "profiled": [{"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"\n Interleaves three lists of the same length into a single flat list.\n\n Args:\n list1: The first list.\n list2: The second list.\n list3: The third list.\n\n Returns:\n A new list containing the interleaved elements.\n \"\"\"\n return [x for t in zip(list1, list2, list3) for x in t]", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"\n Interleaves three lists of equal length into a single flat list.\n\n Args:\n list1: The first list.\n list2: The second list.\n list3: The third list.\n\n Returns:\n A new list containing elements from the input lists interleaved.\n \"\"\"\n interleaved_list = []\n for i in range(len(list1)):\n interleaved_list.extend([list1[i], list2[i], list3[i]])\n return interleaved_list", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"\n Interleaves three lists of the same length into a single flat list.\n\n Args:\n list1: The first list.\n list2: The second list.\n list3: The third list.\n\n Returns:\n A new list containing the elements of the input lists interleaved.\n \"\"\"\n interleaved_list = []\n for i in range(len(list1)):\n interleaved_list.extend([list1[i], list2[i], list3[i]])\n return interleaved_list", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"Interleaves three lists of the same length.\n\n Args:\n list1: The first list.\n list2: The second list.\n list3: The third list.\n\n Returns:\n A new list containing the elements of the three input lists interleaved.\n \"\"\"\n interleaved_list = []\n for i in range(len(list1)):\n interleaved_list.extend([list1[i], list2[i], list3[i]])\n return interleaved_list\nlist1 = [1, 2, 3, 4, 5, 6, 7]\nlist2 = [10, 20, 30, 40, 50, 60, 70]\nlist3 = [100, 200, 300, 400, 500, 600, 700]", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"\n Interleaves three lists of the same length into a single flat list.\n\n Args:\n list1: The first list.\n list2: The second list.\n list3: The third list.\n\n Returns:\n A new list containing all elements from the input lists interleaved.\n \"\"\"\n interleaved = []\n for i in range(len(list1)):\n interleaved.extend([list1[i], list2[i], list3[i]])\n return interleaved", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"\n Interleaves three lists of the same length into a single flat list.\n\n Args:\n list1: The first list.\n list2: The second list.\n list3: The third list.\n\n Returns:\n A new list containing the elements of the three input lists interleaved.\n \"\"\"\n\n interleaved_list = []\n for i in range(len(list1)):\n interleaved_list.extend([list1[i], list2[i], list3[i]])\n return interleaved_list\nlist1 = [1, 2, 3, 4, 5, 6, 7]\nlist2 = [10, 20, 30, 40, 50, 60, 70]\nlist3 = [100, 200, 300, 400, 500, 600, 700]", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"Interleaves three lists of the same length into a single flat list.\"\"\"\n interleaved = []\n for i in range(len(list1)):\n interleaved.extend([list1[i], list2[i], list3[i]])\n return interleaved", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"Interleaves three lists into a single flat list.\"\"\"\n result = []\n for i in range(len(list1)):\n result.extend([list1[i], list2[i], list3[i]])\n return result", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"Interleaves three lists of the same length into a single flat list.\"\"\"\n interleaved = []\n for i in range(len(list1)):\n interleaved.extend([list1[i], list2[i], list3[i]])\n return interleaved", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"\n Interleaves three lists of the same length into a single flat list.\n\n Args:\n list1: The first list.\n list2: The second list.\n list3: The third list.\n\n Returns:\n A single list containing elements from the three input lists interleaved.\n \"\"\"\n\n interleaved_list = []\n for i in range(len(list1)):\n interleaved_list.extend([list1[i], list2[i], list3[i]])\n return interleaved_list\nlist1 = [1, 2, 3, 4, 5, 6, 7]\nlist2 = [10, 20, 30, 40, 50, 60, 70]\nlist3 = [100, 200, 300, 400, 500, 600, 700]", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(lst1, lst2, lst3):\n \"\"\"\n Interleaves three lists of the same length into a single flat list.\n\n Args:\n lst1: The first list.\n lst2: The second list.\n lst3: The third list.\n\n Returns:\n A new list containing the elements of the input lists interleaved.\n \"\"\"\n\n interleaved_list = []\n for i in range(len(lst1)):\n interleaved_list.extend([lst1[i], lst2[i], lst3[i]])\n return interleaved_list", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"\n This function interleaves three lists of the same length into a single flat list.\n\n Args:\n list1: The first list.\n list2: The second list.\n list3: The third list.\n\n Returns:\n A new list containing the elements of the input lists interleaved.\n \"\"\"\n\n interleaved = []\n for i in range(len(list1)):\n interleaved.extend([list1[i], list2[i], list3[i]])\n return interleaved", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"Interleaves three lists of the same length into a single flat list.\n\n Args:\n list1: The first list.\n list2: The second list.\n list3: The third list.\n\n Returns:\n A new list with elements from the input lists interleaved.\n \"\"\"\n\n interleaved_list = []\n for i in range(len(list1)):\n interleaved_list.extend([list1[i], list2[i], list3[i]])\n return interleaved_list\nlist1 = [1, 2, 3, 4, 5, 6, 7]\nlist2 = [10, 20, 30, 40, 50, 60, 70]\nlist3 = [100, 200, 300, 400, 500, 600, 700]", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"Interleaves three lists of the same length into a single flat list.\n\n Args:\n list1: The first list.\n list2: The second list.\n list3: The third list.\n\n Returns:\n A new list containing the elements of the three input lists interleaved.\n \"\"\"\n\n interleaved_list = []\n for i in range(len(list1)):\n interleaved_list.extend([list1[i], list2[i], list3[i]])\n return interleaved_list\nlist1 = [1, 2, 3, 4, 5, 6, 7]\nlist2 = [10, 20, 30, 40, 50, 60, 70]\nlist3 = [100, 200, 300, 400, 500, 600, 700]", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"\n Interleaves three lists of the same length into a single flat list.\n\n Args:\n list1: The first list.\n list2: The second list.\n list3: The third list.\n\n Returns:\n A new list containing the elements of the three input lists interleaved.\n\n Examples:\n interleave_lists([1,2,3,4,5,6,7],[10,20,30,40,50,60,70],[100,200,300,400,500,600,700]) == [1, 10, 100, 2, 20, 200, 3, 30, 300, 4, 40, 400, 5, 50, 500, 6, 60, 600, 7, 70, 700]\n \"\"\"\n return [item for sublist in zip(list1, list2, list3) for item in sublist]", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"\n Interleaves three lists of the same length into a single flat list.\n\n Args:\n list1: The first list.\n list2: The second list.\n list3: The third list.\n\n Returns:\n A single list containing all elements from the input lists interleaved.\n \"\"\"\n interleaved = []\n for i in range(len(list1)):\n interleaved.extend([list1[i], list2[i], list3[i]])\n return interleaved\nlist1 = [1, 2, 3, 4, 5, 6, 7]\nlist2 = [10, 20, 30, 40, 50, 60, 70]\nlist3 = [100, 200, 300, 400, 500, 600, 700]", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"Interleaves three lists into a single flat list.\n\n Args:\n list1: The first list.\n list2: The second list.\n list3: The third list.\n\n Returns:\n A new list containing the elements of the input lists interleaved.\n \"\"\"\n \n interleaved = []\n for i in range(len(list1)):\n interleaved.extend([list1[i], list2[i], list3[i]])\n return interleaved", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"Interleaves three lists of the same length into a single flat list.\"\"\"\n return [x for t in zip(list1, list2, list3) for x in t]\nlist1 = [1, 2, 3, 4, 5, 6, 7]\nlist2 = [10, 20, 30, 40, 50, 60, 70]\nlist3 = [100, 200, 300, 400, 500, 600, 700]", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"\n Interleaves three lists of equal length into a single list.\n\n Args:\n list1: The first list.\n list2: The second list.\n list3: The third list.\n\n Returns:\n A new list containing the elements of the three input lists interleaved.\n\n Raises:\n ValueError: If the input lists are not of equal length.\n \"\"\"\n if len(list1) != len(list2) or len(list1) != len(list3):\n raise ValueError(\"Input lists must have the same length.\")\n\n interleaved_list = []\n for i in range(len(list1)):\n interleaved_list.extend([list1[i], list2[i], list3[i]])\n return interleaved_list", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"Interleaves three lists of the same length into a single flat list.\n\n Args:\n list1: The first list.\n list2: The second list.\n list3: The third list.\n\n Returns:\n A new list containing the elements of the three input lists\n interleaved together.\n \"\"\"\n interleaved = []\n for i in range(len(list1)):\n interleaved.extend([list1[i], list2[i], list3[i]])\n return interleaved", "matching_cluster_idx": 6}]}, "Mbpp/586": {"dps": 98.83040935672514, "dps_norm": 87.5, "pass@1": 94.0, "profiled": [{"solution": "def split_Arr(arr, n):\n \"\"\"\n Splits a list at the nth element and adds the first part to the end.\n \"\"\"\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr,n):\n \"\"\"Splits a list at the nth element and adds the first part to the end.\"\"\"\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"Splits a list at the nth element and adds the first part to the end.\n\n Args:\n arr: The list to be split.\n n: The index to split the list at.\n\n Returns:\n A new list with the first part of the input list appended to the end.\n \"\"\"\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"Splits a list at the nth element and adds the first part to the end.\"\"\"\n\n if n >= len(arr):\n return arr \n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"\n Splits a list at the nth element and adds the first part to the end.\n\n Args:\n arr: A list of elements.\n n: The index at which to split the list.\n\n Returns:\n A new list with the first n elements moved to the end.\n \"\"\"\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr,n):\n \"\"\"\n Splits a list at the nth element and adds the first part to the end.\n\n Args:\n arr: The input list.\n n: The index to split the list at.\n\n Returns:\n A new list with the first part of the input list appended to the end.\n \"\"\"\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"Splits a list at the nth element and adds the first part to the end.\n\n Args:\n arr: The input list.\n n: The index to split at.\n\n Returns:\n A new list with the first n elements moved to the end.\n \"\"\"\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(lst, n):\n \"\"\"Splits a list at the nth element and adds the first part to the end.\n\n Args:\n lst: The list to be split.\n n: The index at which to split the list.\n\n Returns:\n A new list with the first part of the original list appended to the end.\n \"\"\"\n return lst[n:] + lst[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"Splits a list at the nth element and adds the first part to the end.\n\n Args:\n arr: The list to split.\n n: The index at which to split the list.\n\n Returns:\n A new list with the first part of the original list appended to the end.\n \"\"\"\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(input_list, n):\n \"\"\"\n Splits a list at the nth element and adds the first part to the end.\n\n Args:\n input_list: The input list.\n n: The index to split the list at.\n\n Returns:\n A new list with the first part appended to the end.\n \"\"\"\n return input_list[n:] + input_list[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"\n Splits a list at the nth element and adds the first part to the end.\n\n Args:\n arr: The input list.\n n: The index at which to split the list.\n\n Returns:\n A new list with the first n elements appended to the end.\n \"\"\"\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"Splits a list at the nth element and adds the first part to the end.\n\n Args:\n arr: The input list.\n n: The index to split the list at.\n\n Returns:\n The list with the first part moved to the end.\n \"\"\"\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"Splits a list at the nth element and adds the first part to the end.\"\"\"\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"\n Splits a list at the nth element and adds the first part to the end.\n\n Args:\n arr: The input list.\n n: The index at which to split the list.\n\n Returns:\n A new list with the first part of the original list appended to the end.\n \"\"\"\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"\n Splits a list at the nth element and adds the first part to the end.\n \"\"\"\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"\n Splits a list at the nth element and adds the first part to the end.\n\n Args:\n arr: The input list.\n n: The index at which to split the list.\n\n Returns:\n A new list with the first n elements moved to the end.\n \"\"\"\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"Splits a list at the nth element and adds the first part to the end.\n\n Args:\n arr: The input list.\n n: The index at which to split the list.\n\n Returns:\n A new list with the first n elements moved to the end.\n \"\"\"\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(input_list, n):\n \"\"\"\n Splits a list at the nth element and adds the first part to the end.\n\n Args:\n input_list: The list to be split and rearranged.\n n: The index at which to split the list.\n\n Returns:\n A new list with the first n elements moved to the end.\n \"\"\"\n return input_list[n:] + input_list[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"\n Splits a list at the nth element and adds the first part to the end.\n\n Args:\n arr: The input list.\n n: The index at which to split the list.\n\n Returns:\n A new list with the first part of the input list added to the end.\n \"\"\"\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"Splits a list at the nth element and adds the first part to the end.\n\n Args:\n arr: A list of elements.\n n: The index at which to split the list.\n\n Returns:\n A new list with the first n elements moved to the end.\n \"\"\"\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}]}, "Mbpp/587": {"dps": 69.25675675675676, "dps_norm": 91.25, "pass@1": 100.0, "profiled": [{"solution": "def list_tuple(input_list):\n \"\"\"\n This function converts a list to a tuple.\n\n Args:\n input_list: A list.\n\n Returns:\n A tuple containing the elements of the input list.\n \"\"\"\n return tuple(input_list)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n \"\"\"Converts a list to a tuple.\n\n Args:\n lst: The list to convert.\n\n Returns:\n A tuple containing the elements of the input list.\n \"\"\"\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(input_list):\n \"\"\"Converts a list to a tuple.\n\n Args:\n input_list: A list.\n\n Returns:\n A tuple containing the elements of the input list.\n \"\"\"\n return tuple(input_list)", "matching_cluster_idx": 2}, {"solution": "def list_tuple(lst):\n \"\"\"\n Converts a list to a tuple.\n\n Args:\n lst: The input list.\n\n Returns:\n A tuple containing the elements of the input list.\n \"\"\"\n return tuple(lst)", "matching_cluster_idx": 2}, {"solution": "def list_tuple(input_list):\n \"\"\"Converts a list to a tuple.\n\n Args:\n input_list: A list of elements.\n\n Returns:\n A tuple containing the same elements as the input list.\n \"\"\"\n return tuple(input_list)", "matching_cluster_idx": 2}, {"solution": "def list_tuple(input_list):\n \"\"\"Converts a list to a tuple.\n\n Args:\n input_list: A list of any type.\n\n Returns:\n A tuple containing the same elements as the input list.\n \"\"\"\n return tuple(input_list)", "matching_cluster_idx": 2}, {"solution": "def list_tuple(input_list):\n \"\"\"Converts a list to a tuple.\n\n Args:\n input_list: A list to be converted.\n\n Returns:\n A tuple containing the elements of the input list.\n \"\"\"\n return tuple(input_list)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n \"\"\"Converts a list to a tuple.\n\n Args:\n lst: A list.\n\n Returns:\n A tuple containing the same elements as the input list.\n \"\"\"\n return tuple(lst)", "matching_cluster_idx": 2}, {"solution": "def list_tuple(input_list):\n \"\"\"\n This function converts a list to a tuple.\n \n Args:\n input_list: A list of elements.\n\n Returns:\n A tuple containing the elements of the input list.\n \"\"\"\n return tuple(input_list)", "matching_cluster_idx": 2}, {"solution": "def list_tuple(input_list):\n \"\"\"\n Converts a list to a tuple.\n\n Args:\n input_list: A list of elements.\n\n Returns:\n A tuple containing the same elements as the input list.\n \"\"\"\n return tuple(input_list)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(input_list):\n \"\"\"\n Converts a list to a tuple.\n\n Args:\n input_list: A list of elements.\n\n Returns:\n A tuple containing the same elements as the input list.\n \"\"\"\n return tuple(input_list)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(input_list):\n \"\"\"Converts a list to a tuple.\n\n Args:\n input_list: The input list.\n\n Returns:\n A tuple containing the elements of the input list.\n \"\"\"\n return tuple(input_list)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(input_list):\n \"\"\"Converts a list to a tuple.\"\"\"\n return tuple(input_list)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n \"\"\"\n Converts a list to a tuple.\n\n Args:\n lst: A list.\n\n Returns:\n A tuple containing the same elements as the input list.\n \"\"\"\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(input_list):\n \"\"\"Converts a list to a tuple.\n\n Args:\n input_list: A list to convert.\n\n Returns:\n A tuple with the same elements as the input list.\n \"\"\"\n return tuple(input_list)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(input_list):\n \"\"\"Converts a list to a tuple.\n\n Args:\n input_list: A list.\n\n Returns:\n A tuple containing the same elements as the input list.\n \"\"\"\n\n return tuple(input_list)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(input_list):\n \"\"\"Converts a list to a tuple.\n\n Args:\n input_list: A list of elements.\n\n Returns:\n A tuple containing the same elements as the input list.\n \"\"\"\n return tuple(input_list)", "matching_cluster_idx": 2}, {"solution": "def list_tuple(input_list):\n \"\"\"\n This function converts a list to a tuple.\n\n Args:\n input_list: The list to be converted.\n\n Returns:\n A tuple containing the elements of the input list.\n \"\"\"\n return tuple(input_list)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(input_list):\n \"\"\"Converts a list to a tuple.\n\n Args:\n input_list: The input list.\n\n Returns:\n A tuple containing the elements of the input list.\n \"\"\"\n return tuple(input_list)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(input_list):\n \"\"\"\n This function converts a list to a tuple.\n\n Args:\n input_list: A list of elements.\n\n Returns:\n A tuple containing the same elements as the input list.\n \"\"\"\n return tuple(input_list)", "matching_cluster_idx": 3}]}, "Mbpp/588": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def big_diff(nums):\n \"\"\"\n Write a python function to find the difference between largest and smallest value in a given list.\n assert big_diff([1,2,3,4]) == 3\n \"\"\"\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n \"\"\"\n This function takes a list of numbers as input and returns the difference\n between the largest and smallest values in the list.\n \n Args:\n nums: A list of numbers.\n \n Returns:\n An integer representing the difference between the largest and smallest \n values in the list.\n \"\"\"\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n \"\"\"\n Find the difference between the largest and smallest values in a given list.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n The difference between the largest and smallest values in the list.\n \"\"\"\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n \"\"\"\n Write a python function to find the difference between largest and smallest value in a given list.\n assert big_diff([1,2,3,4]) == 3\n \"\"\"\n if not nums:\n return 0\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n \"\"\"\n Write a python function to find the difference between largest and smallest value in a given list.\n assert big_diff([1,2,3,4]) == 3\n \"\"\"\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n \"\"\"\n This function finds the difference between the largest and smallest values in a list.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n The difference between the largest and smallest values in the list.\n \"\"\"\n\n if len(nums) == 0:\n return 0\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n \"\"\"\n This function finds the difference between the largest and smallest values in a given list.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n The difference between the largest and smallest values in the list.\n \"\"\"\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n \"\"\"\n Finds the difference between the largest and smallest values in a given list.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n The difference between the largest and smallest values in the list.\n \"\"\"\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(lst):\n \"\"\"\n Find the difference between largest and smallest value in a given list.\n\n Args:\n lst: A list of numbers.\n\n Returns:\n The difference between the largest and smallest value in the list.\n \"\"\"\n if not lst:\n return 0\n return max(lst) - min(lst)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n \"\"\"\n This function finds the difference between the largest and smallest values in a list.\n Args:\n nums: A list of numbers.\n Returns:\n The difference between the largest and smallest values in the list.\n \"\"\"\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(lst):\n \"\"\"\n Finds the difference between the largest and smallest values in a given list.\n\n Args:\n lst: A list of integers.\n\n Returns:\n The difference between the largest and smallest values in the list.\n \"\"\"\n return max(lst) - min(lst)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n \"\"\"\n Write a python function to find the difference between largest and smallest value in a given list.\n assert big_diff([1,2,3,4]) == 3\n \"\"\"\n if len(nums) == 0:\n return 0\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n \"\"\"\n Finds the difference between the largest and smallest values in a given list.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n The difference between the largest and smallest values in the list.\n \"\"\"\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n \"\"\"\n Finds the difference between the largest and smallest values in a given list.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n The difference between the largest and smallest values in the list.\n \"\"\"\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(lst):\n \"\"\"\n Finds the difference between the largest and smallest values in a given list.\n\n Args:\n lst: A list of numbers.\n\n Returns:\n The difference between the largest and smallest values in the list.\n \"\"\"\n return max(lst) - min(lst)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n \"\"\"\n This function finds the difference between the largest and smallest values in a given list.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n The difference between the largest and smallest values in the list.\n \"\"\"\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n \"\"\"\n This function takes a list of numbers and returns the difference between \n the largest and smallest values in the list.\n \"\"\"\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n \"\"\"\n Finds the difference between the largest and smallest value in a given list.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n The difference between the largest and smallest values in the list.\n \"\"\"\n return max(nums) - min(nums)", "matching_cluster_idx": 5}]}, "Mbpp/592": {"dps": 53.53333333333334, "dps_norm": 39.0, "pass@1": 20.0, "profiled": [{"solution": "import math\ndef sum_Of_product(n):\n \"\"\"\n This function calculates the sum of the product of consecutive binomial coefficients.\n\n Args:\n n: An integer representing the degree of the binomial expansion.\n\n Returns:\n The sum of the product of consecutive binomial coefficients.\n \"\"\"\n total = 0\n for i in range(n):\n total += math.comb(n, i) * math.comb(n, i + 1) \n return total", "matching_cluster_idx": 5}, {"solution": "def sum_Of_product(n):\n \"\"\"\n Calculates the sum of the product of consecutive binomial coefficients.\n\n Args:\n n: An integer representing the upper limit for the binomial coefficients.\n\n Returns:\n The sum of the product of consecutive binomial coefficients up to n.\n \"\"\"\n\n total = 0\n for i in range(n):\n total += binomial_coefficient(n, i) * binomial_coefficient(n, i + 1)\n return total\ndef binomial_coefficient(n, k):\n \"\"\"\n Calculates the binomial coefficient (n choose k).\n\n Args:\n n: The total number of items.\n k: The number of items to choose.\n\n Returns:\n The binomial coefficient (n choose k).\n \"\"\"\n if k < 0 or k > n:\n return 0\n if k == 0 or k == n:\n return 1\n return factorial(n) // (factorial(k) * factorial(n - k))\ndef factorial(n):\n \"\"\"\n Calculates the factorial of a non-negative integer.\n\n Args:\n n: The non-negative integer.\n\n Returns:\n The factorial of n.\n \"\"\"\n if n == 0:\n return 1\n else:\n return n * factorial(n-1)", "matching_cluster_idx": -1}, {"solution": "from math import comb\ndef sum_Of_product(n):\n \"\"\"\n Calculates the sum of the product of consecutive binomial coefficients.\n\n Args:\n n: A non-negative integer.\n\n Returns:\n The sum of the products of consecutive binomial coefficients up to n.\n \"\"\"\n total = 0\n for i in range(n):\n total += comb(n, i) * comb(n, i+1)\n return total", "matching_cluster_idx": 5}, {"solution": "from math import factorial\ndef sum_Of_product(n):\n \"\"\"\n Calculates the sum of the product of consecutive binomial coefficients.\n\n Args:\n n: An integer representing the upper limit for binomial coefficients.\n\n Returns:\n The sum of the product of consecutive binomial coefficients up to n.\n \"\"\"\n total_sum = 0\n for i in range(n):\n total_sum += factorial(n) // (factorial(i) * factorial(n - i)) * factorial(n) // (factorial(i + 1) * factorial(n - i - 1))\n return total_sum", "matching_cluster_idx": 1}, {"solution": "from math import factorial\ndef sum_Of_product(n):\n \"\"\"\n Calculates the sum of the product of consecutive binomial coefficients up to n.\n\n Args:\n n: An integer representing the upper limit for binomial coefficients.\n\n Returns:\n An integer representing the sum of the product of consecutive binomial coefficients.\n \"\"\"\n total_sum = 0\n for i in range(n):\n total_sum += (factorial(n) // (factorial(i) * factorial(n - i))) * (factorial(n) // (factorial(i + 1) * factorial(n - i - 1)))\n return total_sum", "matching_cluster_idx": 2}, {"solution": "import math\ndef sum_Of_product(n):\n \"\"\"\n Finds the sum of the product of consecutive binomial coefficients.\n\n Args:\n n: An integer representing the upper limit of the binomial coefficients.\n\n Returns:\n An integer representing the sum of the product of consecutive binomial coefficients.\n \"\"\"\n total_sum = 0\n for i in range(n):\n total_sum += math.comb(n, i) * math.comb(n, i + 1)\n return total_sum", "matching_cluster_idx": 5}, {"solution": "import math\ndef sum_Of_product(n):\n \"\"\"\n Calculates the sum of the product of consecutive binomial coefficients up to n.\n\n Args:\n n: An integer representing the upper limit for the binomial coefficients.\n\n Returns:\n An integer representing the sum of products.\n \"\"\"\n\n total_sum = 0\n for i in range(n):\n total_sum += math.comb(n, i) * math.comb(n, i + 1) # Calculate product and add to sum\n return total_sum", "matching_cluster_idx": 5}, {"solution": "def sum_Of_product(n):\n \"\"\"\n Calculate the sum of the product of consecutive binomial coefficients.\n\n Args:\n n: An integer representing the upper limit of the binomial coefficient range (inclusive).\n\n Returns:\n The sum of the product of consecutive binomial coefficients from 0 to n.\n \"\"\"\n\n total_sum = 0\n for i in range(n):\n total_sum += binomial_coefficient(n, i) * binomial_coefficient(n, i + 1)\n return total_sum\ndef binomial_coefficient(n, k):\n \"\"\"\n Calculate the binomial coefficient (n choose k).\n\n Args:\n n: The total number of items.\n k: The number of items to choose.\n\n Returns:\n The binomial coefficient (n choose k).\n \"\"\"\n\n if k < 0 or k > n:\n return 0\n if k == 0 or k == n:\n return 1\n\n numerator = 1\n for i in range(n, n - k, -1):\n numerator *= i\n denominator = 1\n for i in range(1, k + 1):\n denominator *= i\n return numerator // denominator", "matching_cluster_idx": 1}, {"solution": "def sum_Of_product(n):\n \"\"\"\n Calculates the sum of the product of consecutive binomial coefficients.\n\n Args:\n n: A non-negative integer.\n\n Returns:\n The sum of the product of consecutive binomial coefficients up to n.\n \"\"\"\n\n total = 0\n for i in range(n):\n # Calculate the binomial coefficients\n binom_coeff1 = factorial(n) // (factorial(i) * factorial(n-i))\n binom_coeff2 = factorial(n) // (factorial(i+1) * factorial(n-i-1))\n # Add the product to the total\n total += binom_coeff1 * binom_coeff2\n\n return total\ndef factorial(num):\n \"\"\"\n Calculates the factorial of a non-negative integer.\n\n Args:\n num: A non-negative integer.\n\n Returns:\n The factorial of num.\n \"\"\"\n\n if num == 0:\n return 1\n else:\n return num * factorial(num - 1)", "matching_cluster_idx": -1}, {"solution": "from math import comb\ndef sum_Of_product(n):\n \"\"\"\n Calculates the sum of the product of consecutive binomial coefficients.\n\n For example:\n sum_Of_product(3) == 1 * 3 + 3 * 3 + 3 * 1 = 15\n \"\"\"\n\n total = 0\n for i in range(n):\n total += comb(n, i) * comb(n, i+1)\n return total", "matching_cluster_idx": 5}, {"solution": "from math import comb\ndef sum_Of_product(n):\n \"\"\"\n Calculates the sum of the product of consecutive binomial coefficients.\n\n Args:\n n: An integer representing the upper limit for the binomial coefficients.\n\n Returns:\n The sum of the product of consecutive binomial coefficients up to n.\n \"\"\"\n total_sum = 0\n for i in range(n):\n total_sum += comb(n, i) * comb(n, i+1)\n return total_sum", "matching_cluster_idx": 5}, {"solution": "import math\ndef sum_Of_product(n):\n \"\"\"\n Calculate the sum of the product of consecutive binomial coefficients.\n\n Args:\n n: A non-negative integer.\n\n Returns:\n The sum of the product of consecutive binomial coefficients from C(n, 0)*C(n, 1) to C(n, n-1)*C(n, n).\n \"\"\"\n\n sum = 0\n for i in range(n):\n sum += math.comb(n, i) * math.comb(n, i + 1) \n return sum", "matching_cluster_idx": 5}, {"solution": "def sum_Of_product(n):\n \"\"\"\n This function calculates the sum of the product of consecutive binomial coefficients.\n \n Args:\n n: An integer representing the highest power of the binomial expansion.\n\n Returns:\n The sum of the product of consecutive binomial coefficients up to n.\n \"\"\"\n total_sum = 0\n for i in range(n):\n total_sum += factorial(n) // (factorial(i) * factorial(n - i)) * factorial(n) // (factorial(i + 1) * factorial(n - i - 1))\n return total_sum\ndef factorial(num):\n \"\"\"\n This function calculates the factorial of a non-negative integer.\n \n Args:\n num: A non-negative integer.\n \n Returns:\n The factorial of num.\n \"\"\"\n if num == 0:\n return 1\n else:\n return num * factorial(num - 1)", "matching_cluster_idx": -1}, {"solution": "def sum_Of_product(n: int) -> int:\n \"\"\"\n This function finds the sum of the product of consecutive binomial coefficients.\n\n For example:\n sum_Of_product(3) == 15 because (1 * 3) + (3 * 3) + (3 * 1) = 15\n\n Args:\n n: A non-negative integer\n\n Returns:\n The sum of the product of consecutive binomial coefficients.\n \"\"\"\n total_sum = 0\n for i in range(n):\n # Using the formula for binomial coefficient: n choose k = n! / (k! * (n-k)!)\n coefficient1 = factorial(n) // (factorial(i) * factorial(n - i))\n coefficient2 = factorial(n) // (factorial(i + 1) * factorial(n - (i + 1)))\n total_sum += coefficient1 * coefficient2\n return total_sum\ndef factorial(num: int) -> int:\n \"\"\"\n Helper function to calculate factorial.\n \"\"\"\n if num == 0:\n return 1\n else:\n return num * factorial(num - 1)", "matching_cluster_idx": -1}, {"solution": "import math\ndef sum_Of_product(n):\n \"\"\"\n Find the sum of the product of consecutive binomial coefficients.\n\n Args:\n n: The upper limit for the binomial coefficients.\n\n Returns:\n The sum of the product of consecutive binomial coefficients up to n.\n \"\"\"\n total_sum = 0\n for i in range(n):\n total_sum += math.comb(n, i) * math.comb(n, i + 1) \n return total_sum", "matching_cluster_idx": 5}, {"solution": "def factorial(n):\n if n == 0:\n return 1\n else:\n return n * factorial(n-1)\ndef binomial_coefficient(n, k):\n return factorial(n) // (factorial(k) * factorial(n-k))\ndef sum_Of_product(n):\n \"\"\"\n Calculates the sum of the product of consecutive binomial coefficients.\n\n Args:\n n: An integer.\n\n Returns:\n The sum of the product of consecutive binomial coefficients for n.\n \"\"\"\n sum = 0\n for i in range(n):\n sum += binomial_coefficient(n, i) * binomial_coefficient(n, i+1)\n return sum", "matching_cluster_idx": -1}, {"solution": "import math\ndef sum_Of_product(n):\n \"\"\"\n Calculates the sum of the product of consecutive binomial coefficients.\n\n For example:\n sum_Of_product(3) == 15 \n\n Explanation:\n The binomial coefficients for n=3 are:\n 1, 3, 3, 1\n The products of consecutive coefficients are:\n 1*3 = 3\n 3*3 = 9\n 3*1 = 3\n The sum of these products is 3 + 9 + 3 = 15\n\n Args:\n n: A non-negative integer.\n\n Returns:\n The sum of the product of consecutive binomial coefficients for n.\n \"\"\"\n sum = 0\n for i in range(n):\n sum += math.comb(n, i) * math.comb(n, i+1)\n return sum", "matching_cluster_idx": 5}, {"solution": "import math\ndef sum_Of_product(n: int) -> int:\n \"\"\"\n Find the sum of the product of consecutive binomial coefficients.\n\n Args:\n n: An integer greater than or equal to 0.\n\n Returns:\n The sum of the product of consecutive binomial coefficients for n.\n \"\"\"\n total_sum = 0\n for i in range(n):\n total_sum += math.comb(n, i) * math.comb(n, i + 1)\n return total_sum", "matching_cluster_idx": 4}, {"solution": "import math\ndef sum_Of_product(n):\n \"\"\"\n Calculates the sum of the product of consecutive binomial coefficients.\n\n Args:\n n: The upper limit of the binomial coefficients.\n\n Returns:\n The sum of the product of consecutive binomial coefficients.\n \"\"\"\n total_sum = 0\n for i in range(n):\n total_sum += math.comb(n, i) * math.comb(n, i + 1)\n return total_sum", "matching_cluster_idx": 5}, {"solution": "import math\ndef sum_Of_product(n):\n \"\"\"\n Calculates the sum of the product of consecutive binomial coefficients.\n\n Args:\n n: An integer representing the upper limit for the binomial coefficients.\n\n Returns:\n The sum of the product of consecutive binomial coefficients up to n.\n \"\"\"\n total_sum = 0\n for i in range(n):\n total_sum += math.comb(n, i) * math.comb(n, i + 1)\n return total_sum", "matching_cluster_idx": 5}]}, "Mbpp/597": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 33.0, "profiled": [{"solution": "def find_kth(arr1, arr2, k):\n \"\"\"Finds the kth element from two sorted arrays.\n\n Args:\n arr1: The first sorted array.\n arr2: The second sorted array.\n k: The kth element to find.\n\n Returns:\n The kth element from the combined sorted arrays.\n \"\"\"\n merged_array = sorted(arr1 + arr2)\n return merged_array[k-1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(arr1, arr2, k):\n \"\"\"Finds the kth element in the merged sorted array of arr1 and arr2.\n\n Args:\n arr1: The first sorted array.\n arr2: The second sorted array.\n k: The desired kth element.\n\n Returns:\n The kth element in the merged sorted array.\n \"\"\"\n merged_arr = sorted(arr1 + arr2) # Merge and sort the arrays\n return merged_arr[k - 1] # Return the kth element (zero-indexed)", "matching_cluster_idx": 3}, {"solution": "def find_kth(arr1, arr2, k):\n \"\"\"\n Finds the kth element from two sorted arrays.\n\n Args:\n arr1: The first sorted array.\n arr2: The second sorted array.\n k: The kth element to find.\n\n Returns:\n The kth element from the combined sorted arrays.\n \"\"\"\n merged_arr = sorted(arr1 + arr2)\n return merged_arr[k - 1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(arr1, arr2, k):\n \"\"\"\n Finds the kth element from two sorted arrays.\n\n Args:\n arr1: The first sorted array.\n arr2: The second sorted array.\n k: The kth element to find.\n\n Returns:\n The kth element from the merged sorted arrays.\n \"\"\"\n merged_array = sorted(arr1 + arr2)\n return merged_array[k - 1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(arr1, arr2, k):\n \"\"\"\n Finds the kth element from two sorted arrays.\n\n Args:\n arr1: The first sorted array.\n arr2: The second sorted array.\n k: The kth element to find.\n\n Returns:\n The kth element in the merged sorted arrays.\n \"\"\"\n\n merged_arr = sorted(arr1 + arr2)\n return merged_arr[k - 1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(arr1, arr2, k):\n \"\"\"\n Finds the kth element from two sorted arrays.\n\n Args:\n arr1: The first sorted array.\n arr2: The second sorted array.\n k: The kth element to find.\n\n Returns:\n The kth element from the combined sorted arrays.\n \"\"\"\n merged = sorted(arr1 + arr2)\n return merged[k - 1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(arr1, arr2, k):\n \"\"\"\n Finds the kth element from two sorted arrays.\n\n Args:\n arr1 (list): The first sorted array.\n arr2 (list): The second sorted array.\n k (int): The kth element to find.\n\n Returns:\n int: The kth element.\n \"\"\"\n\n merged_arr = sorted(arr1 + arr2)\n return merged_arr[k-1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(arr1, arr2, k):\n \"\"\"\n Finds the kth element in two sorted arrays.\n\n Args:\n arr1: The first sorted array.\n arr2: The second sorted array.\n k: The kth element to find.\n\n Returns:\n The kth element in the combined sorted arrays.\n \"\"\"\n\n merged_arr = sorted(arr1 + arr2)\n return merged_arr[k - 1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(nums1, nums2, k):\n \"\"\"\n Finds the kth element in two sorted arrays.\n\n Args:\n nums1 (list of ints): The first sorted array.\n nums2 (list of ints): The second sorted array.\n k (int): The kth element to find.\n\n Returns:\n int: The kth element in the merged sorted arrays.\n \"\"\"\n merged = sorted(nums1 + nums2)\n return merged[k - 1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(arr1, arr2, k):\n \"\"\"Finds the kth element from two sorted arrays.\n\n Args:\n arr1: The first sorted array.\n arr2: The second sorted array.\n k: The desired kth element.\n\n Returns:\n The kth element in the merged sorted array of arr1 and arr2.\n \"\"\"\n\n merged_array = sorted(arr1 + arr2)\n return merged_array[k - 1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(arr1, arr2, k):\n \"\"\"\n Finds the kth element from two sorted arrays.\n\n Args:\n arr1: The first sorted array.\n arr2: The second sorted array.\n k: The desired kth element.\n\n Returns:\n The kth element from the merged sorted arrays.\n \"\"\"\n merged_array = sorted(arr1 + arr2)\n if len(merged_array) < k:\n return None\n return merged_array[k-1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(arr1, arr2, k):\n \"\"\"\n Finds the kth element from two sorted arrays.\n\n Args:\n arr1: The first sorted array.\n arr2: The second sorted array.\n k: The kth element to find.\n\n Returns:\n The kth element from the merged sorted arrays.\n \"\"\"\n\n merged = sorted(arr1 + arr2)\n return merged[k-1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(arr1, arr2, k):\n \"\"\"Finds the kth element in two sorted arrays.\n\n Args:\n arr1: The first sorted array.\n arr2: The second sorted array.\n k: The kth element to find.\n\n Returns:\n The kth element in the merged sorted arrays.\n \"\"\"\n\n merged_array = sorted(arr1 + arr2)\n return merged_array[k - 1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(arr1, arr2, k):\n \"\"\"\n Finds the kth element from two sorted arrays.\n\n Args:\n arr1: The first sorted array.\n arr2: The second sorted array.\n k: The kth element to find.\n\n Returns:\n The kth element from the merged sorted arrays.\n \"\"\"\n merged = sorted(arr1 + arr2)\n return merged[k - 1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(arr1, arr2, k):\n \"\"\"\n Finds the kth element from two sorted arrays.\n\n Args:\n arr1: The first sorted array.\n arr2: The second sorted array.\n k: The kth element to find.\n\n Returns:\n The kth element in the merged sorted arrays.\n \"\"\"\n merged_array = sorted(arr1 + arr2)\n return merged_array[k - 1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(nums1, nums2, k):\n \"\"\"\n Finds the k-th smallest element in two sorted arrays.\n\n Args:\n nums1: The first sorted array.\n nums2: The second sorted array.\n k: The k-th smallest element to find.\n\n Returns:\n The k-th smallest element in the merged sorted arrays.\n \"\"\"\n\n merged_array = sorted(nums1 + nums2) \n return merged_array[k-1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(nums1, nums2, k):\n \"\"\"\n Finds the kth element from the given two sorted arrays.\n\n Args:\n nums1: The first sorted array.\n nums2: The second sorted array.\n k: The kth element to find.\n\n Returns:\n The kth element from the merged sorted arrays.\n \"\"\"\n\n merged_array = sorted(nums1 + nums2)\n return merged_array[k - 1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(nums1, nums2, k):\n \"\"\"\n Finds the kth element from two sorted arrays.\n\n Args:\n nums1: The first sorted array.\n nums2: The second sorted array.\n k: The kth element to find.\n\n Returns:\n The kth element from the merged sorted arrays.\n \"\"\"\n merged = sorted(nums1 + nums2) # Merge and sort the arrays\n return merged[k - 1] # Return the kth element (index k-1)", "matching_cluster_idx": 3}, {"solution": "def find_kth(nums1, nums2, k):\n \"\"\"\n Find the kth element from two sorted arrays.\n\n Args:\n nums1: The first sorted array.\n nums2: The second sorted array.\n k: The kth element to find.\n\n Returns:\n The kth element from the merged sorted arrays.\n \"\"\"\n\n merged_array = sorted(nums1 + nums2)\n return merged_array[k - 1]\nnums1 = [2, 3, 6, 7, 9]\nnums2 = [1, 4, 8, 10]\nk = 5", "matching_cluster_idx": 3}, {"solution": "def find_kth(arr1, arr2, k):\n \"\"\"\n Finds the kth smallest element in two sorted arrays.\n\n Args:\n arr1: The first sorted array.\n arr2: The second sorted array.\n k: The kth element to find.\n\n Returns:\n The kth smallest element.\n \"\"\"\n merged_array = sorted(arr1 + arr2)\n return merged_array[k-1]", "matching_cluster_idx": 3}]}, "Mbpp/604": {"dps": 57.04545454545455, "dps_norm": 91.0, "pass@1": 100.0, "profiled": [{"solution": "def reverse_words(text):\n \"\"\"Reverses the order of words in a given string.\n\n Args:\n text: The input string.\n\n Returns:\n A string with the words in reversed order.\n \"\"\"\n return \" \".join(text.split()[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n \"\"\"Reverses the order of words in a string separated by spaces.\n\n Args:\n s: The input string.\n\n Returns:\n A new string with the words in reversed order.\n \"\"\"\n return ' '.join(s.split()[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(text):\n \"\"\"\n Reverses the order of words in a given string.\n\n Args:\n text (str): The input string.\n\n Returns:\n str: The string with words reversed.\n \"\"\"\n return \" \".join(text.split()[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n \"\"\"\n Reverses the order of words in a given string.\n\n Args:\n s: The string to reverse.\n\n Returns:\n The string with the words in reverse order.\n \"\"\"\n words = s.split()\n return \" \".join(reversed(words))", "matching_cluster_idx": 3}, {"solution": "def reverse_words(s):\n \"\"\"\n Reverses words separated by spaces in a given string.\n\n Args:\n s: The input string.\n\n Returns:\n The string with words reversed.\n \"\"\"\n words = s.split()\n return \" \".join(words[::-1])", "matching_cluster_idx": 3}, {"solution": "def reverse_words(text):\n \"\"\"Reverses the order of words in a string.\n\n Args:\n text: The string to reverse the words in.\n\n Returns:\n The string with the words reversed.\n \"\"\"\n return \" \".join(text.split()[::-1])", "matching_cluster_idx": 3}, {"solution": "def reverse_words(text):\n \"\"\"\n Reverses words separated by spaces in a given string.\n\n Args:\n text: The input string.\n\n Returns:\n The string with the words reversed.\n \"\"\"\n return \" \".join(text.split()[::-1])", "matching_cluster_idx": 3}, {"solution": "def reverse_words(s):\n \"\"\"\n This function reverses words separated by spaces in a given string.\n \n Args:\n s: A string of words separated by spaces.\n\n Returns:\n A string with the words in reverse order.\n \"\"\"\n words = s.split()\n return \" \".join(reversed(words))", "matching_cluster_idx": 3}, {"solution": "def reverse_words(text):\n \"\"\"Reverses words in a string separated by spaces.\n\n Args:\n text: The input string.\n\n Returns:\n The string with words reversed.\n \"\"\"\n return \" \".join(text.split()[::-1])", "matching_cluster_idx": 3}, {"solution": "def reverse_words(text):\n \"\"\"\n Reverses the order of words in a given string.\n\n Args:\n text: The input string with words separated by spaces.\n\n Returns:\n A string with the words in reversed order.\n \"\"\"\n words = text.split()\n return \" \".join(words[::-1])", "matching_cluster_idx": 3}, {"solution": "def reverse_words(s):\n \"\"\"Reverses words separated by spaces in a given string.\n\n Args:\n s: The string to reverse.\n\n Returns:\n The string with words reversed.\n \"\"\"\n return \" \".join(s.split()[::-1])", "matching_cluster_idx": 3}, {"solution": "def reverse_words(s):\n \"\"\"\n Reverses words separated by spaces in a given string.\n\n Args:\n s: A string of words separated by spaces.\n\n Returns:\n A string with the words in reverse order.\n \"\"\"\n return ' '.join(s.split()[::-1])", "matching_cluster_idx": 3}, {"solution": "def reverse_words(text):\n \"\"\"Reverses words separated by spaces in a given string.\n\n Args:\n text: The string to reverse.\n\n Returns:\n The string with words reversed.\n \"\"\"\n return \" \".join(text.split()[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(text):\n \"\"\"Reverses the order of words in a given string.\n\n Args:\n text: The string containing words separated by spaces.\n\n Returns:\n A new string with the words in reversed order.\n \"\"\"\n words = text.split()\n return \" \".join(reversed(words))", "matching_cluster_idx": 4}, {"solution": "def reverse_words(text):\n \"\"\"Reverses the order of words in a string.\n\n Args:\n text: The input string with words separated by spaces.\n\n Returns:\n A new string with the words in reversed order.\n \"\"\"\n return \" \".join(text.split()[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n \"\"\"\n Reverses words separated by spaces in a given string.\n\n Args:\n s: The string to reverse.\n\n Returns:\n The string with words reversed.\n \"\"\"\n words = s.split()\n return \" \".join(words[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(text):\n \"\"\"Reverses words separated by spaces in a given string.\n\n Args:\n text: The string to reverse.\n\n Returns:\n A string with the words reversed.\n \"\"\"\n\n words = text.split()\n return \" \".join(reversed(words))", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n \"\"\"Reverses words separated by spaces in a given string.\n\n Args:\n s: The string to reverse.\n\n Returns:\n The string with the words reversed.\n \"\"\"\n words = s.split()\n return \" \".join(reversed(words))", "matching_cluster_idx": 4}, {"solution": "def reverse_words(text):\n \"\"\"\n Reverses words in a string separated by spaces.\n\n Args:\n text: The string to reverse.\n\n Returns:\n The string with words reversed.\n \"\"\"\n words = text.split()\n return \" \".join(words[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(text):\n \"\"\"Reverses the order of words in a string.\n\n Args:\n text: The string to reverse the words in.\n\n Returns:\n The string with the words in reverse order.\n \"\"\"\n words = text.split()\n return \" \".join(reversed(words))", "matching_cluster_idx": 4}]}, "Mbpp/610": {"dps": null, "dps_norm": null, "pass@1": 0.0, "profiled": []}, "Mbpp/611": {"dps": 77.30061349693251, "dps_norm": 95.83333333333333, "pass@1": 90.0, "profiled": [{"solution": "def max_of_nth(matrix, n):\n \"\"\"\n Finds the maximum value in the nth column of a matrix.\n\n Args:\n matrix: A list of lists representing the matrix.\n n: The index of the column to search (0-indexed).\n\n Returns:\n The maximum value in the nth column.\n \"\"\"\n max_val = float('-inf')\n for row in matrix:\n if len(row) > n:\n max_val = max(max_val, row[n])\n return max_val", "matching_cluster_idx": 4}, {"solution": "def max_of_nth(matrix, n):\n \"\"\"\n Finds the maximum value in the n'th column of a matrix.\n\n Args:\n matrix: A list of lists representing the matrix.\n n: The index of the column (0-based) to find the maximum in.\n\n Returns:\n The maximum value in the n'th column.\n \"\"\"\n max_val = float('-inf') # Initialize with negative infinity\n for row in matrix:\n if n < len(row): # Handle cases where column index is out of bounds\n max_val = max(max_val, row[n])\n return max_val\nmatrix = [[5, 6, 7], [1, 3, 5], [8, 9, 19]]", "matching_cluster_idx": 4}, {"solution": "def max_of_nth(matrix, n):\n \"\"\"\n This function takes a matrix represented as a list of lists and returns the maximum value in the nth column.\n\n Args:\n matrix: A list of lists representing the matrix.\n n: The index of the column (0-based).\n\n Returns:\n The maximum value in the nth column.\n \"\"\"\n return max([row[n] for row in matrix])\nmatrix = [[5, 6, 7], [1, 3, 5], [8, 9, 19]]\nn = 2", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n \"\"\"Given a matrix represented as a list of lists, returns the max of the n'th column.\"\"\"\n return max([row[n] for row in matrix])", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n \"\"\"\n Given a matrix represented as a list of lists returns the max of the n'th column.\n\n For example:\n max_of_nth([[5, 6, 7], [1, 3, 5], [8, 9, 19]], 2) == 19\n \"\"\"\n return max([row[n] for row in matrix])", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n \"\"\"\n Given a matrix represented as a list of lists, return the maximum value in the nth column.\n\n Args:\n matrix: A list of lists representing the matrix.\n n: The index of the column to find the maximum value in.\n\n Returns:\n The maximum value in the nth column.\n \"\"\"\n max_value = float('-inf') \n for row in matrix:\n if n < len(row): # Check if column index is valid\n max_value = max(max_value, row[n])\n return max_value", "matching_cluster_idx": 4}, {"solution": "def max_of_nth(matrix, n):\n \"\"\"\n Given a matrix represented as a list of lists, return the max of the n'th column.\n\n Args:\n matrix: A list of lists representing the matrix.\n n: The index of the column to find the maximum of.\n\n Returns:\n The maximum value in the n'th column.\n \"\"\"\n return max([row[n] for row in matrix])", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n \"\"\"\n Returns the maximum value of the n'th column in a matrix represented as a list of lists.\n\n Args:\n matrix: A list of lists representing a matrix.\n n: The index of the column to find the maximum value of.\n\n Returns:\n The maximum value in the n'th column.\n \"\"\"\n\n column_values = [row[n] for row in matrix]\n return max(column_values)\nmatrix = [[5, 6, 7], [1, 3, 5], [8, 9, 19]]\nn = 2", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n \"\"\"\n Given a matrix represented as a list of lists, returns the max of the n'th column.\n\n Args:\n matrix: A list of lists representing the matrix.\n n: The index of the column to find the maximum value in.\n\n Returns:\n The maximum value in the n'th column.\n\n Raises:\n IndexError: If n is out of bounds for the matrix columns.\n \"\"\"\n if n >= len(matrix[0]):\n raise IndexError(\"Column index out of bounds\")\n max_value = matrix[0][n]\n for row in matrix:\n if row[n] > max_value:\n max_value = row[n]\n return max_value\nmatrix = [[5, 6, 7], [1, 3, 5], [8, 9, 19]]", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n \"\"\"\n Given a matrix represented as a list of lists, returns the max of the n'th column.\n\n Args:\n matrix: A list of lists representing the matrix.\n n: The index of the column to find the maximum of (0-indexed).\n\n Returns:\n The maximum value in the n'th column.\n \"\"\"\n max_val = float('-inf') # Initialize with negative infinity\n\n for row in matrix:\n if n < len(row): # Check if the column index is valid for the current row\n max_val = max(max_val, row[n]) \n\n return max_val", "matching_cluster_idx": 4}, {"solution": "def max_of_nth(matrix, n):\n \"\"\"\n This function takes a matrix (represented as a list of lists) and a column index 'n',\n and returns the maximum value in the specified column.\n\n Args:\n matrix: A list of lists representing the matrix.\n n: The index (starting from 0) of the column to check.\n\n Returns:\n The maximum value in the nth column of the matrix.\n \"\"\"\n max_val = matrix[0][n] # Initialize max_val with the first element of the column\n\n for row in matrix:\n if row[n] > max_val:\n max_val = row[n]\n return max_val\nmatrix = [[5, 6, 7], [1, 3, 5], [8, 9, 19]]\nn = 2", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n \"\"\"\n Given a matrix represented as a list of lists, return the max of the n'th column.\n For example:\n max_of_nth([[5, 6, 7], [1, 3, 5], [8, 9, 19]], 2) == 19\n \"\"\"\n max_val = matrix[0][n]\n for row in matrix:\n if row[n] > max_val:\n max_val = row[n]\n return max_val", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n \"\"\"\n Returns the maximum value of the nth column in a matrix.\n\n Args:\n matrix: A list of lists representing the matrix.\n n: The index of the column (starting from 0).\n\n Returns:\n The maximum value in the nth column.\n \"\"\"\n max_val = float('-inf')\n for row in matrix:\n if len(row) > n:\n max_val = max(max_val, row[n])\n return max_val\nmatrix = [[5, 6, 7], [1, 3, 5], [8, 9, 19]]", "matching_cluster_idx": 4}, {"solution": "def max_of_nth(matrix, n):\n \"\"\"\n Given a matrix represented as a list of lists, returns the max of the n'th column.\n\n Args:\n matrix: A list of lists representing the matrix.\n n: The index of the column to find the maximum value of.\n\n Returns:\n The maximum value in the n'th column of the matrix.\n \"\"\"\n return max([row[n] for row in matrix])\nmatrix = [[5, 6, 7], [1, 3, 5], [8, 9, 19]]", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n \"\"\"Given a matrix represented as a list of lists, return the max of the n'th column.\n Args:\n matrix: A list of lists representing the matrix.\n n: The index of the column to find the maximum value of.\n Returns:\n The maximum value in the n'th column of the matrix.\n\n For example:\n max_of_nth([[5, 6, 7], [1, 3, 5], [8, 9, 19]], 2) == 19\n \"\"\"\n return max(row[n] for row in matrix)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n \"\"\"\n Given a matrix represented as a list of lists, return the max of the n'th column.\n\n Args:\n matrix: A list of lists representing the matrix.\n n: The index of the column (0-indexed).\n\n Returns:\n The maximum value in the n'th column of the matrix.\n \"\"\"\n return max(row[n] for row in matrix)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n \"\"\"\n Given a matrix represented as a list of lists, returns the max of the n'th column.\n\n Args:\n matrix: A list of lists representing the matrix.\n n: The index of the column to find the maximum of (0-indexed).\n\n Returns:\n The maximum value in the n'th column of the matrix.\n \"\"\"\n\n max_value = matrix[0][n]\n for row in matrix:\n if row[n] > max_value:\n max_value = row[n]\n return max_value", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n \"\"\"\n Returns the max of the nth column in a matrix.\n\n Args:\n matrix: A list of lists representing the matrix.\n n: The index of the column to find the maximum of.\n\n Returns:\n The maximum value in the nth column.\n \"\"\"\n return max([row[n] for row in matrix])", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n \"\"\"Given a matrix represented as a list of lists, return the max of the nth column.\"\"\"\n return max([row[n] for row in matrix])", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n \"\"\"\n Given a matrix represented as a list of lists returns the max of the n'th column.\n \n For example:\n max_of_nth([[5, 6, 7], [1, 3, 5], [8, 9, 19]], 2) == 19\n \"\"\"\n return max([row[n] for row in matrix])", "matching_cluster_idx": 5}]}, "Mbpp/631": {"dps": null, "dps_norm": null, "pass@1": 0.0, "profiled": []}, "Mbpp/632": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def move_zero(nums):\n \"\"\"\n Moves all zeroes in a list to the end while maintaining the order of other elements.\n\n Args:\n nums: A list of integers.\n\n Returns:\n A new list with all zeroes moved to the end.\n \"\"\"\n\n non_zeroes = [num for num in nums if num != 0]\n return non_zeroes + [0] * (len(nums) - len(non_zeroes))", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n \"\"\"\n Moves all zeroes to the end of the given list.\n\n Args:\n nums: A list of integers.\n\n Returns:\n A list with all zeroes moved to the end while preserving the relative order of other elements.\n \"\"\"\n non_zeroes = [num for num in nums if num != 0]\n zeroes = [0] * nums.count(0) \n return non_zeroes + zeroes", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n \"\"\"\n Moves all zeroes to the end of the given list while maintaining the relative order of non-zero elements.\n Args:\n nums: A list of integers.\n Returns:\n A new list with all zeroes moved to the end.\n \"\"\"\n non_zeros = [num for num in nums if num != 0]\n zeros = [0] * nums.count(0)\n return non_zeros + zeros", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n \"\"\"\n Move all zeroes to the end of the given list.\n\n Args:\n nums (list): The input list of numbers.\n\n Returns:\n list: A new list with all zeroes moved to the end.\n \"\"\"\n\n non_zero_elements = [num for num in nums if num != 0]\n zeroes = [0] * nums.count(0) \n return non_zero_elements + zeroes\nnums = [1, 0, 2, 0, 3, 4]", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n \"\"\"\n Moves all zeroes to the end of the given list while preserving the order of the non-zero elements.\n\n Args:\n nums: A list of integers.\n\n Returns:\n A new list with all zeroes moved to the end.\n \"\"\"\n\n non_zeroes = [num for num in nums if num != 0]\n zeroes = [0] * nums.count(0) \n return non_zeroes + zeroes", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n \"\"\"\n Moves all zeroes to the end of the given list while maintaining the relative order of non-zero elements.\n\n Args:\n nums (list): The input list of numbers.\n\n Returns:\n list: The modified list with zeroes moved to the end.\n\n Examples:\n >>> move_zero([1,0,2,0,3,4])\n [1, 2, 3, 4, 0, 0]\n \"\"\"\n non_zeros = []\n zeros = []\n for num in nums:\n if num == 0:\n zeros.append(num)\n else:\n non_zeros.append(num)\n return non_zeros + zeros", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n \"\"\"\n Moves all zeroes to the end of the given list while maintaining the relative order of other elements.\n\n Args:\n nums: A list of integers.\n\n Returns:\n The list with all zeroes moved to the end.\n \"\"\"\n non_zero_elements = [num for num in nums if num != 0]\n zero_count = nums.count(0)\n return non_zero_elements + [0] * zero_count", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n \"\"\"\n Moves all zeroes to the end of the given list while maintaining the relative order of non-zero elements.\n\n Args:\n nums: A list of integers.\n\n Returns:\n The list with all zeroes moved to the end.\n \"\"\"\n non_zeros = [num for num in nums if num != 0]\n zeros = [0] * nums.count(0)\n return non_zeros + zeros", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n \"\"\"Moves all zeroes in a list to the end while maintaining relative order of non-zero elements.\n\n Args:\n nums: A list of integers.\n\n Returns:\n A new list with all zeroes moved to the end.\n \"\"\"\n\n non_zeros = [num for num in nums if num != 0]\n zeros = [num for num in nums if num == 0]\n return non_zeros + zeros", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n \"\"\"Moves all zeroes to the end of the given list while maintaining the relative order of the other elements.\n\n Args:\n nums: A list of integers.\n\n Returns:\n A new list with all zeroes moved to the end.\n \"\"\"\n\n non_zero_elements = []\n zero_count = 0\n\n for num in nums:\n if num != 0:\n non_zero_elements.append(num)\n else:\n zero_count += 1\n\n return non_zero_elements + [0] * zero_count", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n \"\"\"\n Moves all zeroes to the end of the given list.\n\n Args:\n nums: A list of integers.\n\n Returns:\n A new list with all zeroes moved to the end while maintaining the relative order of non-zero elements.\n\n Example:\n move_zero([1,0,2,0,3,4]) == [1,2,3,4,0,0]\n \"\"\"\n non_zeroes = [num for num in nums if num != 0]\n zeroes = [0] * nums.count(0)\n return non_zeroes + zeroes", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n \"\"\"\n Moves all zeroes to the end of the given list while maintaining the relative order of other elements.\n\n Args:\n nums: A list of integers.\n\n Returns:\n A new list with all zeroes moved to the end.\n \"\"\"\n non_zero_nums = [num for num in nums if num != 0]\n zero_count = nums.count(0)\n return non_zero_nums + [0] * zero_count", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n \"\"\"\n Moves all zeroes to the end of the given list while maintaining the relative order of other elements.\n\n Args:\n nums: A list of integers.\n\n Returns:\n The list with all zeroes moved to the end.\n \"\"\"\n non_zeroes = [num for num in nums if num != 0]\n return non_zeroes + [0] * (len(nums) - len(non_zeroes))\nnums = [1, 0, 2, 0, 3, 4]", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n \"\"\"\n Moves all zeroes to the end of the given list while maintaining the order of\n non-zero elements.\n\n Args:\n nums: A list of integers.\n\n Returns:\n A new list with all zeroes moved to the end.\n \"\"\"\n\n result = []\n zero_count = 0\n for num in nums:\n if num != 0:\n result.append(num)\n else:\n zero_count += 1\n\n return result + [0] * zero_count", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n \"\"\"\n Moves all zeroes to the end of the given list.\n\n Args:\n nums: A list of integers.\n\n Returns:\n A list with all zeroes moved to the end, preserving the order of other elements.\n \"\"\"\n\n non_zeroes = [num for num in nums if num != 0]\n zeroes = [0] * nums.count(0)\n return non_zeroes + zeroes", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n \"\"\"Moves all zeroes to the end of the given list while preserving the order of other elements.\n\n Args:\n nums: A list of integers.\n\n Returns:\n The modified list with zeroes moved to the end.\n \"\"\"\n non_zero_elements = [num for num in nums if num != 0]\n zero_count = nums.count(0)\n\n return non_zero_elements + [0] * zero_count", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n \"\"\"\n Move all zeroes to the end of the given list.\n\n Args:\n nums: A list of integers.\n\n Returns:\n A new list with all zeroes moved to the end.\n \"\"\"\n\n non_zeros = [num for num in nums if num != 0]\n zeros = [0] * nums.count(0)\n return non_zeros + zeros", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n \"\"\"\n Move all zeroes to the end of the given list while maintaining the order of other elements.\n\n Args:\n nums: A list of integers.\n\n Returns:\n The input list with all zeroes moved to the end.\n \"\"\"\n\n non_zeroes = [num for num in nums if num != 0]\n zeroes = [0] * nums.count(0)\n return non_zeroes + zeroes", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n \"\"\"\n Moves all zeroes to the end of a list while maintaining the relative order of the\n non-zero elements.\n\n Args:\n nums: A list of integers.\n\n Returns:\n The list with all zeroes moved to the end.\n \"\"\"\n non_zeros = []\n zeros = []\n for num in nums:\n if num == 0:\n zeros.append(num)\n else:\n non_zeros.append(num)\n return non_zeros + zeros", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n \"\"\"\n Moves all zeroes to the end of the given list while maintaining the relative order of other elements.\n\n Args:\n nums: A list of integers.\n\n Returns:\n A new list with all zeroes moved to the end.\n \"\"\"\n\n non_zero_elements = [num for num in nums if num != 0]\n zero_count = nums.count(0)\n\n return non_zero_elements + [0] * zero_count", "matching_cluster_idx": 6}]}, "Mbpp/633": {"dps": 94.3089430894309, "dps_norm": 50.0, "pass@1": 94.0, "profiled": [{"solution": "def pair_xor_Sum(nums, n):\n \"\"\"\n Calculates the sum of XOR of all pairs of numbers in the given list.\n\n Args:\n nums: A list of integers.\n n: The length of the list.\n\n Returns:\n The sum of XOR of all pairs of numbers in the list.\n \"\"\"\n xor_sum = 0\n for i in range(n):\n for j in range(i + 1, n):\n xor_sum += nums[i] ^ nums[j]\n return xor_sum\nnums = [5, 9, 7, 6]\nn = len(nums)", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(arr, n):\n \"\"\"\n Calculate the sum of XOR of all pairs of numbers in a given list.\n\n Args:\n arr: A list of integers.\n n: The length of the list.\n\n Returns:\n The sum of XOR of all pairs of numbers in the list.\n \"\"\"\n xor_sum = 0\n\n for i in range(n):\n for j in range(i+1, n):\n xor_sum += arr[i] ^ arr[j]\n \n return xor_sum\narr = [5, 9, 7, 6]\nn = len(arr)", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(arr, n):\n \"\"\"\n Calculates the sum of XOR of all pairs of numbers in the given list.\n\n Args:\n arr: The list of numbers.\n n: The length of the list.\n\n Returns:\n The sum of XOR of all pairs of numbers in the list.\n \"\"\"\n xor_sum = 0\n for i in range(n):\n for j in range(i+1, n):\n xor_sum += arr[i] ^ arr[j]\n return xor_sum\narr = [5, 9, 7, 6]\nn = len(arr)", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(nums: list, n: int) -> int:\n \"\"\"\n Calculate the sum of XOR of all pairs of numbers in the given list.\n\n Args:\n nums (list): The input list of integers.\n n (int): The length of the list (optional, can be derived from the list).\n\n Returns:\n int: The sum of XOR of all pairs in the list.\n \"\"\"\n xor_sum = 0\n for i in range(n):\n for j in range(i + 1, n):\n xor_sum += nums[i] ^ nums[j]\n return xor_sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(nums, n):\n \"\"\"\n Calculates the sum of XOR of all pairs of numbers in a list.\n\n Args:\n nums: A list of integers.\n n: The length of the list (optional, can be inferred from nums).\n\n Returns:\n The sum of XOR of all pairs of numbers in the list.\n \"\"\"\n xor_sum = 0\n for i in range(n):\n for j in range(i + 1, n):\n xor_sum += nums[i] ^ nums[j]\n return xor_sum\nnums = [5, 9, 7, 6]\nn = len(nums)", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(nums: list[int], n: int):\n \"\"\"\n Calculate the sum of XOR of all pairs of numbers in the given list.\n\n Args:\n nums: A list of integers.\n n: The length of the list.\n\n Returns:\n The sum of XOR of all pairs of numbers in the list.\n \"\"\"\n xor_sum = 0\n for i in range(n):\n for j in range(i+1, n):\n xor_sum += nums[i] ^ nums[j]\n return xor_sum\nnums = [5, 9, 7, 6]\nn = len(nums)", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(nums: list[int], n: int) -> int:\n \"\"\"\n Calculates the sum of XOR values for all pairs of numbers in a given list.\n\n Args:\n nums: A list of integers.\n n: The length of the list.\n\n Returns:\n The sum of XOR values for all pairs of numbers in the list.\n \"\"\"\n xor_sum = 0\n\n for i in range(n):\n for j in range(i + 1, n):\n xor_sum += nums[i] ^ nums[j]\n\n return xor_sum\nnums = [5, 9, 7, 6]\nn = len(nums)", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(nums, n):\n \"\"\"\n Calculates the sum of XOR of all pairs of numbers in a list.\n\n Args:\n nums: A list of numbers.\n n: The length of the list.\n\n Returns:\n The sum of XOR of all pairs of numbers in the list.\n \"\"\"\n sum_xor = 0\n for i in range(n):\n for j in range(i+1, n):\n sum_xor += nums[i] ^ nums[j]\n return sum_xor", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(arr, n):\n \"\"\"\n Calculates the sum of XOR of all pairs in a given list.\n\n Args:\n arr: A list of integers.\n n: The length of the list.\n\n Returns:\n The sum of XOR of all pairs in the list.\n \"\"\"\n sum_xor = 0\n for i in range(n):\n for j in range(i + 1, n):\n sum_xor += arr[i] ^ arr[j]\n return sum_xor\narr = [5, 9, 7, 6]\nn = len(arr)", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(nums, n):\n \"\"\"\n Calculates the sum of XOR of all pairs of numbers in a given list.\n\n Args:\n nums (list): A list of integers.\n n (int): The length of the list.\n\n Returns:\n int: The sum of XOR of all pairs.\n \"\"\"\n\n total_xor_sum = 0\n for i in range(n):\n for j in range(i + 1, n):\n total_xor_sum += nums[i] ^ nums[j] \n return total_xor_sum\nnums = [5, 9, 7, 6]\nn = len(nums)", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(arr, n):\n \"\"\"\n Calculates the sum of XOR of all pairs of numbers in a given list.\n\n Args:\n arr: A list of integers.\n n: The length of the list.\n\n Returns:\n The sum of XOR of all pairs of numbers in the list.\n \"\"\"\n xor_sum = 0\n for i in range(n):\n for j in range(i + 1, n):\n xor_sum += arr[i] ^ arr[j] \n return xor_sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(nums, n):\n \"\"\"\n Calculate the sum of XOR of all pairs of numbers in the given list.\n\n Args:\n nums: A list of numbers.\n n: The length of the list.\n\n Returns:\n The sum of XOR of all pairs of numbers in the list.\n \"\"\"\n\n xor_sum = 0\n\n for i in range(n):\n for j in range(i + 1, n):\n xor_sum += nums[i] ^ nums[j] \n\n return xor_sum\nnums = [5, 9, 7, 6]\nn = len(nums)", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(nums,n):\n \"\"\"\n This function calculates the sum of XOR of all pairs of numbers in a given list.\n Args:\n nums: A list of numbers.\n n: The length of the list.\n\n Returns:\n The sum of XOR of all pairs of numbers in the list.\n \"\"\"\n xor_sum = 0\n for i in range(n):\n for j in range(i+1, n):\n xor_sum += nums[i] ^ nums[j]\n return xor_sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(nums, n):\n \"\"\"\n Calculates the sum of XOR of all pairs of numbers in a list.\n\n Args:\n nums: A list of integers.\n n: The length of the list.\n\n Returns:\n The sum of XOR of all pairs of numbers in the list.\n \"\"\"\n xor_sum = 0\n for i in range(n):\n for j in range(i + 1, n):\n xor_sum += nums[i] ^ nums[j]\n return xor_sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(nums, n):\n \"\"\"\n Calculates the sum of XOR of all pairs of numbers in a given list.\n\n Args:\n nums: A list of numbers.\n n: The length of the list (not strictly necessary, but included for clarity).\n\n Returns:\n The sum of XOR of all pairs of numbers in the list.\n \"\"\"\n\n xor_sum = 0\n for i in range(n):\n for j in range(i + 1, n):\n xor_sum += nums[i] ^ nums[j]\n return xor_sum\nnums = [5, 9, 7, 6]\nn = len(nums)", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(nums: list, n: int) -> int:\n \"\"\"Calculates the sum of XOR values of all pairs in a list.\n\n Args:\n nums: A list of numbers.\n n: The length of the list.\n\n Returns:\n The sum of the XOR of all pairs of numbers in the list.\n \"\"\"\n xor_sum = 0\n for i in range(n):\n for j in range(i + 1, n):\n xor_sum += nums[i] ^ nums[j]\n return xor_sum\nnums = [5, 9, 7, 6]\nn = len(nums)", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(arr, n):\n \"\"\"\n This function calculates the sum of xor of all pairs of numbers in a given list.\n \n Args:\n arr: A list of integers.\n n: The length of the list.\n \n Returns:\n An integer representing the sum of xor of all pairs of numbers in the list.\n \"\"\"\n\n total_xor_sum = 0\n\n for i in range(n):\n for j in range(i + 1, n):\n total_xor_sum += arr[i] ^ arr[j]\n \n return total_xor_sum\narr = [5, 9, 7, 6]\nn = len(arr)", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(nums, n):\n \"\"\"Calculates the sum of XOR of all possible pairs in a list.\n\n Args:\n nums: A list of integers.\n n: The length of the list.\n\n Returns:\n The sum of XOR of all pairs in the list.\n \"\"\"\n sum = 0\n for i in range(n):\n for j in range(i+1, n):\n sum += (nums[i] ^ nums[j])\n return sum\nnums = [5, 9, 7, 6]\nn = len(nums)", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(nums: list, n: int):\n \"\"\"\n Finds the sum of xor of all pairs of numbers in the given list.\n \"\"\"\n total_xor_sum = 0\n for i in range(n):\n for j in range(i + 1, n):\n total_xor_sum += nums[i] ^ nums[j]\n return total_xor_sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(nums, n):\n \"\"\"Calculates the sum of XOR of all pairs of numbers in a list.\n\n Args:\n nums: A list of integers.\n n: The length of the list.\n\n Returns:\n The sum of XOR of all pairs of numbers in the list.\n \"\"\"\n total_xor_sum = 0\n for i in range(n):\n for j in range(i + 1, n):\n total_xor_sum += nums[i] ^ nums[j]\n return total_xor_sum\nnums = [5, 9, 7, 6]\nn = len(nums)", "matching_cluster_idx": 2}]}, "Mbpp/644": {"dps": 59.89361702127658, "dps_norm": 68.0, "pass@1": 86.0, "profiled": [{"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n Reverses an array upto a given position k.\n\n Args:\n arr: The input array.\n k: The position up to which the array should be reversed.\n\n Returns:\n A new array with the elements reversed up to position k.\n \"\"\"\n return arr[:k][::-1] + arr[k:]", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"Reverses an array up to a given position.\n\n Args:\n arr: The input array.\n k: The position up to which the array should be reversed.\n\n Returns:\n A new array with the elements reversed up to position k.\n \"\"\"\n\n if k <= 0 or k > len(arr):\n return arr # Handle invalid input\n\n return arr[:k][::-1] + arr[k:]", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"Reverses an array up to a given position.\n\n Args:\n arr: The input array.\n k: The position up to which the array should be reversed.\n\n Returns:\n The array with elements reversed up to position k.\n \"\"\"\n if k > len(arr) or k < 0:\n return \"Invalid input: k should be within the bounds of the array\"\n\n left = 0\n right = k - 1\n while left < right:\n arr[left], arr[right] = arr[right], arr[left]\n left += 1\n right -= 1\n return arr", "matching_cluster_idx": 6}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"Reverses an array upto a given position.\n\n Args:\n arr: The input array.\n k: The position upto which the array should be reversed (inclusive).\n\n Returns:\n The array with elements reversed upto position k.\n \"\"\"\n if k <= 0 or k > len(arr):\n return arr\n return arr[:k][::-1] + arr[k:]", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"Reverses an array up to a given position k.\n\n Args:\n arr: The input array.\n k: The position up to which the array should be reversed (inclusive).\n\n Returns:\n The array with the elements up to position k reversed.\n \"\"\"\n if k > len(arr) or k < 0:\n return arr # Invalid k value\n \n return arr[:k][::-1] + arr[k:]", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n Reverses an array upto a given position.\n\n Args:\n arr: A list of numbers.\n k: An integer representing the position up to which the array should be reversed (inclusive).\n\n Returns:\n A new list with the array reversed up to the given position.\n \"\"\"\n return arr[:k][::-1] + arr[k:]", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n Reverses an array upto a given position k.\n\n Args:\n arr: The input array.\n k: The position up to which the array should be reversed.\n\n Returns:\n The array with the first k elements reversed.\n \"\"\"\n if k <= 0 or k > len(arr):\n return arr \n return arr[:k][::-1] + arr[k:]", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"Reverses an array up to a given position.\n\n Args:\n arr: The array to be reversed.\n k: The position up to which the array should be reversed.\n\n Returns:\n A new array with the elements up to position k reversed.\n \"\"\"\n return arr[:k][::-1] + arr[k:]", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n This function reverses an array up to a given position 'k'.\n\n Args:\n arr: The input array.\n k: The position up to which the array should be reversed.\n\n Returns:\n A new array with the elements reversed up to position 'k'.\n \"\"\"\n if k > len(arr) or k < 0:\n return \"Invalid value of k\"\n\n new_arr = arr[:k][::-1] + arr[k:]\n return new_arr", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"Reverses an array up to a given position.\n\n Args:\n arr: The input array.\n k: The position up to which the array should be reversed.\n\n Returns:\n The array with elements reversed up to position k.\n \"\"\"\n if k > len(arr) or k < 0:\n return arr\n \n return arr[:k][::-1] + arr[k:]", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"Reverses the elements of an array up to a given position.\n\n Args:\n arr: The input array.\n k: The position up to which the array should be reversed.\n\n Returns:\n The array with the elements reversed up to position k.\n \"\"\"\n if k > len(arr) or k < 0:\n return arr\n\n return arr[:k][::-1] + arr[k:]\narr = [1, 2, 3, 4, 5, 6]\nk = 4", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n Reverses an array up to a given position.\n\n Args:\n arr: The input array.\n k: The position up to which the array should be reversed.\n\n Returns:\n The array with the first k elements reversed.\n \"\"\"\n if k > len(arr) or k < 0:\n return arr \n\n left = 0\n right = k - 1\n\n while left < right:\n arr[left], arr[right] = arr[right], arr[left]\n left += 1\n right -= 1\n\n return arr", "matching_cluster_idx": 6}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"Reverses an array upto a given position k.\"\"\"\n\n if k > len(arr) or k < 0:\n return arr \n\n left = 0\n right = k-1\n while left < right:\n arr[left], arr[right] = arr[right], arr[left]\n left += 1\n right -= 1\n return arr\narr = [1, 2, 3, 4, 5, 6]\nk = 4", "matching_cluster_idx": 6}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n Reverses an array up to a given position.\n\n Args:\n arr: The input array.\n k: The position up to which the array should be reversed (inclusive).\n\n Returns:\n The array with the first k elements reversed.\n \"\"\"\n return arr[:k][::-1] + arr[k:]", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n Reverses an array up to a given position.\n\n Args:\n arr: The input array.\n k: The position up to which the array should be reversed.\n\n Returns:\n The array with elements reversed up to position k.\n \"\"\"\n if k > len(arr) or k < 0:\n return \"Invalid k value\"\n return arr[:k][::-1] + arr[k:]", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n Reverses an array up to a given position k.\n\n Args:\n arr: The input array.\n k: The position up to which the array should be reversed.\n\n Returns:\n A new array with the elements reversed up to position k.\n \"\"\"\n reversed_part = arr[:k][::-1] # Reverse the subarray up to k\n return reversed_part + arr[k:] # Concatenate with the rest of the array", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n Reverses an array up to a given position.\n\n Args:\n arr: The input array.\n k: The position up to which the array should be reversed.\n\n Returns:\n The array with elements reversed up to position k.\n \"\"\"\n if k > len(arr) or k < 0:\n return arr\n return arr[:k][::-1] + arr[k:]", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"Reverses an array up to a given position k.\n\n Args:\n arr: The input array.\n k: The position up to which the array should be reversed.\n\n Returns:\n The array with the first k elements reversed.\n \"\"\"\n return arr[:k][::-1] + arr[k:]", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n Reverses the elements of an array up to a given position k.\n\n Args:\n arr: The input array.\n k: The position up to which the array should be reversed.\n\n Returns:\n A new array with the elements reversed up to position k.\n \"\"\"\n return arr[:k][::-1] + arr[k:]", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n Reverses an array up to a given position k.\n\n Args:\n arr (list): The input array.\n k (int): The position up to which the array should be reversed (inclusive).\n\n Returns:\n list: The array with the first k elements reversed.\n \"\"\"\n if k <= 0 or k > len(arr):\n return arr\n \n left, right = 0, k - 1\n while left < right:\n arr[left], arr[right] = arr[right], arr[left]\n left += 1\n right -= 1\n\n return arr", "matching_cluster_idx": 6}]}, "Mbpp/720": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def add_dict_to_tuple(input_tuple, input_dict):\n \"\"\"\n Appends a dictionary to the end of a tuple.\n\n Args:\n input_tuple (tuple): The initial tuple.\n input_dict (dict): The dictionary to be added.\n\n Returns:\n tuple: A new tuple with the dictionary appended.\n \"\"\"\n return input_tuple + (input_dict,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(input_tuple, input_dict):\n \"\"\"\n Adds a dictionary to a tuple.\n\n Args:\n input_tuple: The input tuple.\n input_dict: The dictionary to be added.\n\n Returns:\n A new tuple with the dictionary appended to the original tuple.\n \"\"\"\n return input_tuple + (input_dict,) # Note the comma after input_dict to make it a single-element tuple", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(input_tuple, input_dict):\n \"\"\"Adds a dictionary to the end of a tuple.\n\n Args:\n input_tuple: The tuple to which the dictionary will be added.\n input_dict: The dictionary to be added to the tuple.\n\n Returns:\n A new tuple with the dictionary added to the end.\n \"\"\"\n\n return input_tuple + (input_dict,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(input_tuple, input_dict):\n \"\"\"\n Adds a dictionary to a tuple.\n\n Args:\n input_tuple: The tuple to which the dictionary will be added.\n input_dict: The dictionary to be added.\n\n Returns:\n A new tuple with the dictionary appended.\n \"\"\"\n return input_tuple + (input_dict,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(input_tuple, input_dict):\n \"\"\"\n Adds a dictionary to a tuple.\n\n Args:\n input_tuple: The input tuple.\n input_dict: The dictionary to be added.\n\n Returns:\n A new tuple with the dictionary appended.\n \"\"\"\n return input_tuple + (input_dict,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(input_tuple, input_dict):\n \"\"\"\n This function adds a dictionary to the end of a tuple.\n \n Args:\n input_tuple: The tuple to which the dictionary will be added.\n input_dict: The dictionary to be added to the tuple.\n\n Returns:\n A new tuple with the dictionary appended.\n \"\"\"\n return input_tuple + (input_dict,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(t, d):\n \"\"\"\n Adds a dictionary to a tuple.\n\n Args:\n t: The input tuple.\n d: The dictionary to be added.\n\n Returns:\n A new tuple with the dictionary appended to the end.\n \"\"\"\n return t + (d,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(tup, dct):\n \"\"\"Adds a dictionary to a tuple.\n\n Args:\n tup: The tuple to add the dictionary to.\n dct: The dictionary to add.\n\n Returns:\n A new tuple with the dictionary appended.\n \"\"\"\n\n return tup + (dct,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(input_tuple, input_dict):\n \"\"\"\n Adds a dictionary to a tuple.\n\n Args:\n input_tuple: The original tuple.\n input_dict: The dictionary to be added.\n\n Returns:\n A new tuple with the dictionary appended.\n \"\"\"\n return input_tuple + (input_dict,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(input_tuple, input_dict):\n \"\"\"\n This function adds a dictionary to a given tuple.\n\n Args:\n input_tuple: The initial tuple.\n input_dict: The dictionary to be added.\n\n Returns:\n A new tuple with the dictionary appended to the end.\n \"\"\"\n return input_tuple + (input_dict,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(input_tuple, input_dict):\n \"\"\"\n Add a dictionary to a tuple.\n\n Args:\n input_tuple: The initial tuple.\n input_dict: The dictionary to add.\n\n Returns:\n A new tuple with the dictionary appended.\n \"\"\"\n return input_tuple + (input_dict,) # Note: The comma is important to create a single-element tuple", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(t, d):\n \"\"\"\n Adds a dictionary to a tuple.\n\n Args:\n t: The input tuple.\n d: The dictionary to add.\n\n Returns:\n A new tuple with the dictionary appended.\n \"\"\"\n return t + (d,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(input_tuple, input_dict):\n \"\"\"\n Adds a dictionary to the end of a tuple.\n\n Args:\n input_tuple: The original tuple.\n input_dict: The dictionary to be added.\n\n Returns:\n A new tuple with the dictionary appended to the end.\n \"\"\"\n return input_tuple + (input_dict,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(input_tuple, input_dict):\n \"\"\"\n Add a dictionary to the end of a tuple.\n\n Args:\n input_tuple: The tuple to which the dictionary will be appended.\n input_dict: The dictionary to be appended to the tuple.\n\n Returns:\n A new tuple with the dictionary appended.\n \"\"\"\n return input_tuple + (input_dict,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(tup, dict_to_add):\n \"\"\"\n Adds a dictionary to the end of a tuple.\n\n Args:\n tup: An existing tuple.\n dict_to_add: A dictionary to add.\n\n Returns:\n A new tuple with the dictionary appended.\n \"\"\"\n return tup + (dict_to_add,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(input_tuple, input_dict):\n \"\"\"\n Adds a dictionary to a tuple.\n\n Args:\n input_tuple: The input tuple.\n input_dict: The dictionary to add.\n\n Returns:\n A new tuple with the dictionary appended.\n \"\"\"\n return input_tuple + (input_dict,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(input_tuple, input_dict):\n \"\"\"\n Adds a dictionary to the end of a tuple.\n\n Args:\n input_tuple: The original tuple.\n input_dict: The dictionary to add.\n\n Returns:\n A new tuple with the dictionary appended.\n \"\"\"\n\n return input_tuple + (input_dict,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(input_tuple, input_dict):\n \"\"\"\n Adds a dictionary to the end of a tuple.\n Args:\n input_tuple: The tuple to add the dictionary to.\n input_dict: The dictionary to be added.\n\n Returns:\n A new tuple with the dictionary appended.\n \"\"\"\n return input_tuple + (input_dict,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(input_tuple, input_dict):\n \"\"\"Adds a dictionary to a tuple.\n\n Args:\n input_tuple: The input tuple.\n input_dict: The dictionary to be added.\n\n Returns:\n A new tuple with the dictionary appended.\n \"\"\"\n return input_tuple + (input_dict,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(input_tuple, input_dict):\n \"\"\"\n Adds a dictionary to the end of a tuple.\n\n Args:\n input_tuple: The original tuple.\n input_dict: The dictionary to add.\n\n Returns:\n A new tuple with the dictionary appended to the end.\n \"\"\"\n return input_tuple + (input_dict,)", "matching_cluster_idx": 4}]}, "Mbpp/725": {"dps": 88.96174863387978, "dps_norm": 82.5, "pass@1": 100.0, "profiled": [{"solution": "import re\ndef extract_quotation(text):\n \"\"\"\n Extracts values between quotation marks \" \" of the given string.\n\n Args:\n text: The input string.\n\n Returns:\n A list of strings found between quotation marks.\n \"\"\"\n\n return re.findall(r'\"([^\"]*)\"', text)", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(text):\n \"\"\"Extracts values between double quotation marks in a string.\n Args:\n text: The string to extract values from.\n\n Returns:\n A list of strings containing the extracted values.\n \"\"\"\n return re.findall(r'\"([^\"]*)\"', text)", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(text):\n \"\"\"\n Extracts values between quotation marks \" \" of the given string.\n Args:\n text: The string to extract values from.\n Returns:\n A list of extracted values.\n \"\"\"\n return re.findall(r'\"([^\"]*)\"', text)", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(text):\n \"\"\"\n Extracts values between quotation marks \" \" from a given string.\n\n Args:\n text: The string to extract values from.\n\n Returns:\n A list of extracted values.\n \"\"\"\n return re.findall(r'\"([^\"]*)\"', text)", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(text):\n \"\"\"\n This function extracts values between quotation marks \" \" of the given string.\n\n Args:\n text: The input string.\n\n Returns:\n A list of strings found between quotation marks.\n \"\"\"\n return re.findall(r'\"([^\"]*)\"', text)", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(text):\n \"\"\"\n Extracts values between quotation marks \" \" of the given string.\n \"\"\"\n return re.findall(r'\"([^\"]*)\"', text)", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(text):\n \"\"\"\n This function extracts values between quotation marks \" \" of the given string.\n Args:\n text: The input string.\n Returns:\n A list of strings containing the values extracted between quotation marks.\n \"\"\"\n return re.findall(r'\"([^\"]*)\"', text)", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(text):\n \"\"\"\n Extracts values between quotation marks \" \" of the given string.\n\n Args:\n text: The input string.\n\n Returns:\n A list of strings extracted between quotation marks.\n \"\"\"\n return re.findall(r'\"(.*?)\"', text)", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(text):\n \"\"\"\n Extract values between quotation marks \" \" of the given string.\n \"\"\"\n return re.findall(r'\"([^\"]*)\"', text)", "matching_cluster_idx": 6}, {"solution": "import re\ndef extract_quotation(text):\n \"\"\"\n Extracts values between quotation marks \" \" from the given string.\n\n Args:\n text: The input string.\n\n Returns:\n A list of extracted values.\n \"\"\"\n return re.findall(r'\"([^\"]*)\"', text)", "matching_cluster_idx": 6}, {"solution": "import re\ndef extract_quotation(text):\n \"\"\"\n This function extracts values between quotation marks \" \" of the given string.\n\n Args:\n text: A string containing values within quotation marks.\n\n Returns:\n A list of strings representing the values extracted from the quotation marks.\n \"\"\"\n return re.findall(r'\"([^\"]*)\"', text)", "matching_cluster_idx": 6}, {"solution": "import re\ndef extract_quotation(text):\n \"\"\"Extracts values between quotation marks \" \" of the given string.\n\n Args:\n text: The input string.\n\n Returns:\n A list of strings found between quotation marks.\n \"\"\"\n\n return re.findall(r'\"([^\"]*)\"', text)", "matching_cluster_idx": 6}, {"solution": "import re\ndef extract_quotation(text):\n \"\"\"\n This function extracts values between quotation marks \" \" of the given string.\n\n Args:\n text: A string containing values between quotation marks.\n\n Returns:\n A list of strings, representing the values extracted from the quotation marks.\n \"\"\"\n return re.findall(r'\"([^\"]*)\"', text)", "matching_cluster_idx": 6}, {"solution": "import re\ndef extract_quotation(text):\n \"\"\"Extracts values between quotation marks \" \" from a given string.\n\n Args:\n text: The input string.\n\n Returns:\n A list of strings extracted between quotation marks.\n \"\"\"\n return re.findall(r'\"([^\"]*)\"', text)", "matching_cluster_idx": 6}, {"solution": "import re\ndef extract_quotation(text):\n \"\"\"\n Extracts values between quotation marks \" \" of the given string.\n\n Args:\n text (str): The input string.\n\n Returns:\n list: A list of strings extracted from between quotation marks.\n \"\"\"\n return re.findall(r'\"([^\"]*)\"', text)", "matching_cluster_idx": 6}, {"solution": "import re\ndef extract_quotation(text):\n \"\"\"\n Extracts values between quotation marks \" \" of the given string.\n\n Args:\n text (str): The input string.\n\n Returns:\n list: A list of strings extracted from between quotation marks.\n \"\"\"\n\n return re.findall(r'\"([^\"]*)\"', text)", "matching_cluster_idx": 6}, {"solution": "import re\ndef extract_quotation(text):\n \"\"\"\n Extracts values between quotation marks \" \" of the given string.\n \"\"\"\n return re.findall(r'\"([^\"]*)\"', text)", "matching_cluster_idx": 6}, {"solution": "import re\ndef extract_quotation(text):\n \"\"\"Extracts values between quotation marks \" \" from the given string.\n\n Args:\n text: The input string.\n\n Returns:\n A list of strings found between quotation marks.\n \"\"\"\n\n return re.findall(r'\"([^\"]*)\"', text)", "matching_cluster_idx": 6}, {"solution": "import re\ndef extract_quotation(text):\n \"\"\"\n Extracts values between quotation marks \" \" of the given string.\n For example:\n extract_quotation('Cortex \"A53\" Based \"multi\" tasking \"Processor\"') == ['A53', 'multi', 'Processor']\n \"\"\"\n return re.findall(r'\"([^\"]*)\"', text)", "matching_cluster_idx": 6}, {"solution": "import re\ndef extract_quotation(text):\n \"\"\"\n Extracts values between quotation marks \" \" of the given string.\n\n Args:\n text: The input string.\n\n Returns:\n A list of strings found between quotation marks.\n \"\"\"\n return re.findall(r'\"([^\"]*)\"', text)", "matching_cluster_idx": 6}]}, "Mbpp/732": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def replace_specialchar(text):\n \"\"\"\n This function replaces all occurrences of spaces, commas, or dots with a colon.\n\n Args:\n text: A string containing spaces, commas, or dots.\n\n Returns:\n The input string with spaces, commas, and dots replaced with colons.\n \"\"\"\n return text.replace(' ', ':').replace(',', ':').replace('.', ':')", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(text):\n \"\"\"\n This function replaces all occurrences of spaces, commas, or dots with a colon.\n\n Args:\n text: The input string.\n\n Returns:\n The string with spaces, commas, and dots replaced by colons.\n \"\"\"\n\n for char in [\" \", \",\", \".\"]:\n text = text.replace(char, \":\")\n return text", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(text):\n \"\"\"\n Replaces all occurrences of spaces, commas, or dots with a colon.\n \"\"\"\n for char in [' ', ',', '.']:\n text = text.replace(char, ':')\n return text", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(text):\n \"\"\"Replaces spaces, commas, and dots with colons in a string.\n\n Args:\n text: The input string.\n\n Returns:\n The string with spaces, commas, and dots replaced with colons.\n \"\"\"\n\n for char in [' ', ',', '.']:\n text = text.replace(char, ':')\n return text", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(text):\n \"\"\"\n Replaces all occurrences of spaces, commas, or dots with a colon.\n Args:\n text: The string to be processed.\n Returns:\n The string with all spaces, commas, and dots replaced with colons.\n \"\"\"\n return text.replace(\" \", \":\").replace(\",\", \":\").replace(\".\", \":\")", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(text):\n \"\"\"Replaces all occurrences of spaces, commas, or dots with a colon.\"\"\"\n return text.replace(' ', ':').replace(',', ':').replace('.', ':')", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(text):\n \"\"\"Replaces all occurrences of spaces, commas, or dots with a colon.\n\n Args:\n text: The input string.\n\n Returns:\n The string with spaces, commas, and dots replaced by colons.\n \"\"\"\n return text.replace(\" \", \":\").replace(\",\", \":\").replace(\".\", \":\")", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(text):\n \"\"\"Replaces spaces, commas, and dots with colons.\"\"\"\n for char in [' ', ',', '.']:\n text = text.replace(char, ':')\n return text", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(text):\n \"\"\"Replaces spaces, commas, and dots with a colon in a string.\"\"\"\n return text.replace(' ', ':').replace(',', ':').replace('.', ':')", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(text):\n \"\"\"\n Replaces all occurrences of spaces, commas, or dots with a colon.\n\n Args:\n text: The input string.\n\n Returns:\n The string with spaces, commas, and dots replaced with colons.\n \"\"\"\n\n return text.replace(' ', ':').replace(',', ':').replace('.', ':')", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(text):\n \"\"\"Replaces spaces, commas, and dots in a string with a colon.\"\"\"\n return text.replace(' ', ':').replace(',', ':').replace('.', ':')", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(text):\n \"\"\"Replaces all occurrences of spaces, commas, or dots with a colon.\"\"\"\n return text.replace(\" \", \":\").replace(\",\", \":\").replace(\".\", \":\")", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(text):\n \"\"\"\n Replaces all occurrences of spaces, commas, or dots with a colon.\n\n Args:\n text: The string to be processed.\n\n Returns:\n The string with replacements made.\n \"\"\"\n for char in [' ', ',', '.']:\n text = text.replace(char, ':')\n return text", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(text):\n \"\"\"Replaces spaces, commas, and dots with a colon.\n\n Args:\n text: The input string.\n\n Returns:\n The string with replacements made.\n \"\"\"\n for char in [' ', ',', '.']:\n text = text.replace(char, ':')\n return text", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(text):\n \"\"\"Replaces spaces, commas, and dots with colons in a given string.\"\"\"\n return text.replace(' ', ':').replace(',', ':').replace('.', ':')", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(text):\n \"\"\"\n This function replaces all occurrences of spaces, commas, or dots with a colon.\n\n Args:\n text: The string to be processed.\n\n Returns:\n The string with spaces, commas, and dots replaced with colons.\n \"\"\"\n for char in [' ', ',', '.']:\n text = text.replace(char, ':')\n return text", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(text):\n \"\"\"Replaces all spaces, commas, or dots with a colon.\"\"\"\n return text.replace(' ', ':').replace(',', ':').replace('.', ':')", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(text):\n \"\"\"Replaces spaces, commas, and dots in a string with a colon.\n\n Args:\n text: The string to modify.\n\n Returns:\n The modified string with colons replacing the special characters.\n \"\"\"\n\n for char in [' ', ',', '.']:\n text = text.replace(char, ':')\n return text", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(text):\n \"\"\"\n This function replaces spaces, commas, and dots in a string with colons.\n Args:\n text: The input string.\n Returns:\n The modified string with spaces, commas, and dots replaced by colons.\n \"\"\"\n \n text = text.replace(\" \", \":\")\n text = text.replace(\",\", \":\")\n text = text.replace(\".\", \":\")\n return text", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(text):\n \"\"\"Replaces all occurrences of spaces, commas, or dots with a colon.\n\n Args:\n text: The input string.\n\n Returns:\n The string with spaces, commas, and dots replaced by colons.\n \"\"\"\n for char in [' ', ',', '.']:\n text = text.replace(char, ':')\n return text", "matching_cluster_idx": 9}]}, "Mbpp/740": {"dps": 46.654545454545456, "dps_norm": 56.111111111111114, "pass@1": 100.0, "profiled": [{"solution": "def tuple_to_dict(data):\n \"\"\"\n Converts a given tuple to a key-value dictionary using adjacent elements.\n\n Args:\n data: A tuple with an even number of elements.\n\n Returns:\n A dictionary where the first element of each pair is the key and the second is the value.\n \"\"\"\n if len(data) % 2 != 0:\n raise ValueError(\"Input tuple must have an even number of elements.\")\n return dict(zip(data[::2], data[1::2]))", "matching_cluster_idx": 8}, {"solution": "def tuple_to_dict(data):\n \"\"\"Converts a tuple to a dictionary using adjacent elements as keys and values.\n\n Args:\n data: The input tuple.\n\n Returns:\n A dictionary created from the tuple, using adjacent elements as key-value pairs.\n \"\"\"\n result = {}\n for i in range(0, len(data), 2):\n if i + 1 < len(data):\n result[data[i]] = data[i + 1]\n return result", "matching_cluster_idx": 3}, {"solution": "def tuple_to_dict(input_tuple):\n \"\"\"Converts a tuple to a dictionary using adjacent elements as key-value pairs.\"\"\"\n\n if len(input_tuple) % 2 != 0:\n raise ValueError(\"Input tuple must have an even number of elements.\")\n\n output_dict = {}\n for i in range(0, len(input_tuple), 2):\n output_dict[input_tuple[i]] = input_tuple[i + 1]\n return output_dict", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(input_tuple):\n \"\"\"\n Converts a tuple to a dictionary using adjacent elements as key-value pairs.\n\n Args:\n input_tuple: A tuple containing pairs of values.\n\n Returns:\n A dictionary created from the adjacent elements of the tuple.\n \"\"\"\n result_dict = {}\n for i in range(0, len(input_tuple), 2):\n if i + 1 < len(input_tuple):\n result_dict[input_tuple[i]] = input_tuple[i + 1]\n return result_dict", "matching_cluster_idx": 3}, {"solution": "def tuple_to_dict(input_tuple):\n \"\"\"\n Converts a tuple to a dictionary using adjacent elements as key-value pairs.\n\n Args:\n input_tuple: The input tuple.\n\n Returns:\n A dictionary created from adjacent elements of the tuple.\n \"\"\"\n\n output_dict = {}\n for i in range(0, len(input_tuple), 2):\n if i + 1 < len(input_tuple): # Check if there's a next element for the value\n output_dict[input_tuple[i]] = input_tuple[i + 1]\n return output_dict", "matching_cluster_idx": 3}, {"solution": "def tuple_to_dict(input_tuple):\n \"\"\"Converts a tuple to a dictionary using adjacent elements as keys and values.\n\n Args:\n input_tuple: The input tuple.\n\n Returns:\n A dictionary created from adjacent elements of the tuple.\n \"\"\"\n output_dict = {}\n for i in range(0, len(input_tuple), 2):\n if i + 1 < len(input_tuple):\n output_dict[input_tuple[i]] = input_tuple[i + 1]\n return output_dict", "matching_cluster_idx": 3}, {"solution": "def tuple_to_dict(tup):\n \"\"\"\n Converts a tuple to a dictionary using adjacent elements as key-value pairs.\n\n Args:\n tup: A tuple with an even number of elements.\n\n Returns:\n A dictionary where every other element of the tuple becomes a key\n and the next element becomes its corresponding value.\n \"\"\"\n result = {}\n for i in range(0, len(tup), 2):\n if i + 1 < len(tup):\n result[tup[i]] = tup[i + 1]\n return result", "matching_cluster_idx": 3}, {"solution": "def tuple_to_dict(input_tuple):\n \"\"\"\n Converts a given tuple to a dictionary using adjacent elements as key-value pairs.\n\n Args:\n input_tuple: The tuple to be converted.\n\n Returns:\n A dictionary where adjacent elements from the tuple are used as key-value pairs.\n \"\"\"\n result_dict = {}\n for i in range(0, len(input_tuple), 2):\n if i + 1 < len(input_tuple):\n result_dict[input_tuple[i]] = input_tuple[i + 1]\n return result_dict", "matching_cluster_idx": 3}, {"solution": "def tuple_to_dict(input_tuple):\n \"\"\"\n Converts a tuple to a dictionary using adjacent elements as key-value pairs.\n\n Args:\n input_tuple: The input tuple.\n\n Returns:\n A dictionary created from adjacent elements of the tuple.\n \"\"\"\n\n result_dict = {}\n for i in range(0, len(input_tuple), 2):\n if i + 1 < len(input_tuple):\n result_dict[input_tuple[i]] = input_tuple[i + 1]\n return result_dict", "matching_cluster_idx": 3}, {"solution": "def tuple_to_dict(input_tuple):\n \"\"\"Converts a tuple to a key-value dictionary using adjacent elements.\n\n Args:\n input_tuple: A tuple with an even number of elements.\n\n Returns:\n A dictionary where the first element of each pair is a key and the second\n is its corresponding value.\n \"\"\"\n result_dict = {}\n for i in range(0, len(input_tuple), 2):\n result_dict[input_tuple[i]] = input_tuple[i + 1]\n return result_dict", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(data: tuple) -> dict:\n \"\"\"\n Convert the given tuple to a key-value dictionary using adjacent elements.\n\n Args:\n data: A tuple with an even number of elements.\n\n Returns:\n A dictionary where keys are the odd-indexed elements and values are the even-indexed elements.\n \"\"\"\n return {data[i]: data[i+1] for i in range(0, len(data), 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(input_tuple):\n \"\"\"Converts a tuple to a dictionary using adjacent elements as keys and values.\n\n Args:\n input_tuple: The input tuple.\n\n Returns:\n A dictionary created from the tuple's adjacent elements.\n \"\"\"\n\n if len(input_tuple) % 2 != 0:\n raise ValueError(\"Input tuple must have an even number of elements\")\n\n result_dict = {}\n for i in range(0, len(input_tuple), 2):\n result_dict[input_tuple[i]] = input_tuple[i + 1]\n return result_dict", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(input_tuple):\n \"\"\"Converts a tuple to a dictionary using adjacent elements as key-value pairs.\n\n Args:\n input_tuple: The input tuple.\n\n Returns:\n A dictionary formed by using adjacent elements of the tuple as key-value pairs.\n \"\"\"\n result_dict = {}\n for i in range(0, len(input_tuple), 2):\n if i + 1 < len(input_tuple):\n result_dict[input_tuple[i]] = input_tuple[i + 1]\n return result_dict", "matching_cluster_idx": 3}, {"solution": "def tuple_to_dict(input_tuple):\n \"\"\"\n Converts a tuple to a key-value dictionary using adjacent elements.\n\n Args:\n input_tuple: A tuple with an even number of elements.\n\n Returns:\n A dictionary where the keys are the odd-indexed elements and the values are the even-indexed elements.\n\n Raises:\n ValueError: if the input tuple has an odd number of elements.\n \"\"\"\n\n if len(input_tuple) % 2 != 0:\n raise ValueError(\"Input tuple must have an even number of elements.\")\n return {input_tuple[i]: input_tuple[i + 1] for i in range(0, len(input_tuple), 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(input_tuple):\n \"\"\"Converts a tuple to a dictionary using adjacent elements as key-value pairs.\n\n Args:\n input_tuple: A tuple with an even number of elements.\n\n Returns:\n A dictionary created from adjacent pairs in the input tuple.\n \"\"\"\n result_dict = {}\n for i in range(0, len(input_tuple), 2):\n result_dict[input_tuple[i]] = input_tuple[i+1]\n return result_dict", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(input_tuple):\n \"\"\"Converts a tuple to a dictionary using adjacent elements as key-value pairs.\n\n Args:\n input_tuple: A tuple with an even number of elements.\n\n Returns:\n A dictionary where keys are every other element starting at index 0, and\n values are the subsequent elements.\n\n Raises:\n ValueError: If the input tuple has an odd number of elements.\n \"\"\"\n\n if len(input_tuple) % 2 != 0:\n raise ValueError(\"Input tuple must have an even number of elements.\")\n\n output_dict = {}\n for i in range(0, len(input_tuple), 2):\n output_dict[input_tuple[i]] = input_tuple[i + 1]\n\n return output_dict", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(input_tuple):\n \"\"\"\n Convert the given tuple to a key-value dictionary using adjacent elements.\n\n Args:\n input_tuple: The input tuple.\n\n Returns:\n A dictionary where keys are the first element of each pair and values\n are the second element of each pair.\n\n Example:\n tuple_to_dict((1, 5, 7, 10, 13, 5)) == {1: 5, 7: 10, 13: 5}\n \"\"\"\n result_dict = {}\n for i in range(0, len(input_tuple), 2):\n if i + 1 < len(input_tuple):\n result_dict[input_tuple[i]] = input_tuple[i + 1]\n return result_dict", "matching_cluster_idx": 3}, {"solution": "def tuple_to_dict(input_tuple):\n \"\"\"\n Convert the given tuple to a key-value dictionary using adjacent elements.\n\n Args:\n input_tuple: A tuple containing key-value pairs.\n\n Returns:\n A dictionary created from adjacent elements of the input tuple.\n \"\"\"\n result_dict = {}\n for i in range(0, len(input_tuple), 2):\n if i + 1 < len(input_tuple):\n result_dict[input_tuple[i]] = input_tuple[i + 1]\n return result_dict", "matching_cluster_idx": 3}, {"solution": "def tuple_to_dict(input_tuple):\n \"\"\"Converts a given tuple to a key-value dictionary using adjacent elements.\n\n Args:\n input_tuple: A tuple containing key-value pairs represented as adjacent elements.\n\n Returns:\n A dictionary created from the tuple.\n \"\"\"\n output_dict = {}\n for i in range(0, len(input_tuple), 2):\n if i + 1 < len(input_tuple):\n output_dict[input_tuple[i]] = input_tuple[i + 1]\n return output_dict", "matching_cluster_idx": 3}, {"solution": "def tuple_to_dict(input_tuple):\n \"\"\"\n Converts the given tuple to a key-value dictionary using adjacent elements.\n\n Args:\n input_tuple: A tuple with an even number of elements.\n\n Returns:\n A dictionary where adjacent elements from the tuple form key-value pairs.\n \"\"\"\n\n if len(input_tuple) % 2 != 0:\n raise ValueError(\"Input tuple must have an even number of elements\")\n\n result_dict = {}\n for i in range(0, len(input_tuple), 2):\n result_dict[input_tuple[i]] = input_tuple[i+1]\n return result_dict", "matching_cluster_idx": 5}]}, "Mbpp/744": {"dps": 94.0068493150685, "dps_norm": 95.83333333333333, "pass@1": 100.0, "profiled": [{"solution": "def check_none(input_tuple):\n \"\"\"Checks if the given tuple has any None value.\n\n Args:\n input_tuple: The tuple to check.\n\n Returns:\n True if the tuple contains None, False otherwise.\n \"\"\"\n return None in input_tuple", "matching_cluster_idx": 5}, {"solution": "def check_none(input_tuple):\n \"\"\"\n Checks if a tuple contains any None values.\n\n Args:\n input_tuple: The tuple to check.\n\n Returns:\n True if the tuple contains None, False otherwise.\n \"\"\"\n\n return None in input_tuple", "matching_cluster_idx": 5}, {"solution": "def check_none(input_tuple):\n \"\"\"\n Check if the given tuple has any None values.\n \n Args:\n input_tuple: The tuple to check.\n\n Returns:\n True if the tuple contains a None value, False otherwise.\n \"\"\"\n\n return None in input_tuple", "matching_cluster_idx": 5}, {"solution": "def check_none(input_tuple):\n \"\"\"\n This function checks if the given tuple has any None value or not.\n\n Args:\n input_tuple: The tuple to be checked.\n\n Returns:\n True if the tuple contains a None value, False otherwise.\n \"\"\"\n for element in input_tuple:\n if element is None:\n return True\n return False", "matching_cluster_idx": 4}, {"solution": "def check_none(input_tuple):\n \"\"\"\n Checks if the given tuple has any None value or not.\n\n Args:\n input_tuple: The tuple to check.\n\n Returns:\n True if the tuple contains None, False otherwise.\n \"\"\"\n return None in input_tuple", "matching_cluster_idx": 5}, {"solution": "def check_none(input_tuple):\n \"\"\"\n Checks if a tuple contains any None values.\n\n Args:\n input_tuple: The tuple to be checked.\n\n Returns:\n True if the tuple contains None, False otherwise.\n \"\"\"\n return None in input_tuple", "matching_cluster_idx": 5}, {"solution": "def check_none(input_tuple):\n \"\"\"\n Checks if a tuple contains any None values.\n\n Args:\n input_tuple: The tuple to check.\n\n Returns:\n True if the tuple contains None, False otherwise.\n \"\"\"\n for item in input_tuple:\n if item is None:\n return True\n return False", "matching_cluster_idx": 4}, {"solution": "def check_none(input_tuple):\n \"\"\"\n Checks if the given tuple has any None values.\n\n Args:\n input_tuple: The tuple to be checked.\n\n Returns:\n True if the tuple contains None, False otherwise.\n \"\"\"\n return None in input_tuple", "matching_cluster_idx": 5}, {"solution": "def check_none(input_tuple):\n \"\"\"\n Checks if a tuple contains any None values.\n\n Args:\n input_tuple: A tuple of any type.\n\n Returns:\n True if the tuple contains None, False otherwise.\n \"\"\"\n return None in input_tuple", "matching_cluster_idx": 5}, {"solution": "def check_none(input_tuple):\n \"\"\"\n Checks if the given tuple has any None value.\n\n Args:\n input_tuple: The tuple to check.\n\n Returns:\n True if the tuple contains None, False otherwise.\n \"\"\"\n return None in input_tuple", "matching_cluster_idx": 5}, {"solution": "def check_none(input_tuple):\n \"\"\"\n Checks if a tuple has any None values.\n\n Args:\n input_tuple: The tuple to check.\n\n Returns:\n True if the tuple contains None, False otherwise.\n \"\"\"\n return None in input_tuple", "matching_cluster_idx": 5}, {"solution": "def check_none(input_tuple):\n \"\"\"Checks if a given tuple has any None values.\n\n Args:\n input_tuple: The tuple to be checked.\n\n Returns:\n True if the tuple contains None, False otherwise.\n \"\"\"\n return None in input_tuple", "matching_cluster_idx": 5}, {"solution": "def check_none(data: tuple) -> bool:\n \"\"\"\n Write a function to check if the given tuple has any none value or not.\n assert check_none((10, 4, 5, 6, None)) == True\n \"\"\"\n\n for item in data:\n if item is None:\n return True\n return False", "matching_cluster_idx": 4}, {"solution": "def check_none(input_tuple):\n \"\"\"\n Checks if the given tuple has any None value.\n\n Args:\n input_tuple: A tuple to check for None values.\n\n Returns:\n True if the tuple contains at least one None value, False otherwise.\n \"\"\"\n return None in input_tuple", "matching_cluster_idx": 5}, {"solution": "def check_none(input_tuple):\n \"\"\"\n Checks if the given tuple has any None value.\n\n Args:\n input_tuple: A tuple to check for None values.\n\n Returns:\n True if the tuple contains None, False otherwise.\n \"\"\"\n return None in input_tuple", "matching_cluster_idx": 5}, {"solution": "def check_none(input_tuple):\n \"\"\"\n Checks if the given tuple has any None value or not.\n\n Args:\n input_tuple: A tuple to check for None values.\n\n Returns:\n True if the tuple contains a None value, False otherwise.\n \"\"\"\n return None in input_tuple", "matching_cluster_idx": 5}, {"solution": "def check_none(input_tuple):\n \"\"\"\n Checks if the given tuple has any None value or not.\n\n Args:\n input_tuple: A tuple to check for None values.\n\n Returns:\n True if the tuple contains at least one None value, False otherwise.\n \"\"\"\n return None in input_tuple", "matching_cluster_idx": 5}, {"solution": "def check_none(input_tuple):\n \"\"\"\n Checks if the given tuple has any None value.\n\n Args:\n input_tuple: A tuple to check for None values.\n\n Returns:\n True if the tuple contains None, False otherwise.\n \"\"\"\n for element in input_tuple:\n if element is None:\n return True\n return False", "matching_cluster_idx": 4}, {"solution": "def check_none(input_tuple):\n \"\"\"\n Checks if a tuple has any None values.\n\n Args:\n input_tuple: The tuple to check.\n\n Returns:\n True if the tuple has at least one None value, False otherwise.\n \"\"\"\n return None in input_tuple", "matching_cluster_idx": 5}, {"solution": "def check_none(input_tuple):\n \"\"\"\n Checks if the given tuple has any None value or not.\n\n Args:\n input_tuple: The tuple to be checked.\n\n Returns:\n True if the tuple contains a None value, False otherwise.\n \"\"\"\n for item in input_tuple:\n if item is None:\n return True\n return False", "matching_cluster_idx": 4}]}, "Mbpp/750": {"dps": 53.57142857142857, "dps_norm": 53.333333333333336, "pass@1": 100.0, "profiled": [{"solution": "def add_tuple(list1, tuple1):\n \"\"\"Appends the elements of a tuple to a list.\n\n Args:\n list1: The input list.\n tuple1: The input tuple.\n\n Returns:\n A new list with the tuple elements appended.\n \"\"\"\n new_list = list1.copy() \n new_list.extend(tuple1)\n return new_list", "matching_cluster_idx": 3}, {"solution": "def add_tuple(list_a, tuple_a):\n \"\"\"\n Write a function to add the given tuple to the given list.\n\n Args:\n list_a: A list.\n tuple_a: A tuple.\n\n Returns:\n A new list with elements from list_a and tuple_a.\n \"\"\"\n return list_a + list(tuple_a)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(list1, tuple1):\n \"\"\"\n This function takes a list and a tuple as input and adds the elements of\n the tuple to the end of the list.\n\n Args:\n list1: The list to add the tuple to.\n tuple1: The tuple containing elements to be added to the list.\n\n Returns:\n The updated list with the tuple's elements appended.\n \"\"\"\n for item in tuple1:\n list1.append(item)\n return list1", "matching_cluster_idx": 0}, {"solution": "def add_tuple(list1, tuple1):\n \"\"\"\n Adds the given tuple to the given list.\n\n Args:\n list1: The list to add the tuple to.\n tuple1: The tuple to add to the list.\n\n Returns:\n The updated list with the tuple elements appended.\n \"\"\"\n\n list1.extend(tuple1) \n return list1", "matching_cluster_idx": 5}, {"solution": "def add_tuple(list1, tuple1):\n \"\"\"\n Write a function to add the given tuple to the given list.\n \"\"\"\n return list1 + list(tuple1)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(list1, tuple1):\n \"\"\"Adds the given tuple to the given list.\n For example:\n add_tuple([5, 6, 7], (9, 10)) == [5, 6, 7, 9, 10]\n \"\"\"\n return list1 + list(tuple1)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(list1, tuple1):\n \"\"\"\n This function adds the elements of a given tuple to the end of a given list.\n\n Args:\n list1: The list to add elements to.\n tuple1: The tuple whose elements will be added.\n\n Returns:\n A new list with the tuple's elements appended.\n \"\"\"\n new_list = list1.copy() # Create a copy to avoid modifying the original list\n new_list.extend(tuple1)\n return new_list", "matching_cluster_idx": 3}, {"solution": "def add_tuple(list1: list, tuple1: tuple) -> list:\n \"\"\"\n Write a function to add the given tuple to the given list.\n\n assert add_tuple([5, 6, 7], (9, 10)) == [5, 6, 7, 9, 10]\n \"\"\"\n return list1 + list(tuple1)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(lst, tpl):\n \"\"\"\n This function adds the elements of a tuple to the end of a list.\n\n Args:\n lst: A list to add the tuple elements to.\n tpl: The tuple whose elements will be added to the list.\n\n Returns:\n A new list with the elements of the tuple appended to the original list.\n \"\"\"\n new_list = lst + list(tpl)\n return new_list", "matching_cluster_idx": 2}, {"solution": "def add_tuple(list1, tuple1):\n \"\"\"\n This function adds the elements of a given tuple to a given list.\n \n Args:\n list1: The list to which the tuple will be added.\n tuple1: The tuple containing elements to be added.\n \n Returns:\n A new list with the elements of the tuple appended.\n \"\"\"\n return list1 + list(tuple1)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(lst, tup):\n \"\"\"\n Write a function to add the given tuple to the given list.\n assert add_tuple([5, 6, 7], (9, 10)) == [5, 6, 7, 9, 10]\n \"\"\"\n return lst + list(tup)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(list1, tuple1):\n \"\"\"\n Adds the elements of a tuple to a list.\n\n Args:\n list1: The list to which the tuple's elements will be added.\n tuple1: The tuple whose elements will be added to the list.\n\n Returns:\n A new list with the elements of the tuple appended to the original list.\n \"\"\"\n return list1 + list(tuple1)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(list1, tuple1):\n \"\"\"\n Write a function to add the given tuple to the given list.\n assert add_tuple([5, 6, 7], (9, 10)) == [5, 6, 7, 9, 10]\n \"\"\"\n return list1 + list(tuple1)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(list1, tuple1):\n \"\"\"Adds the given tuple to the given list.\n\n Args:\n list1: A list of elements.\n tuple1: A tuple of elements.\n\n Returns:\n A new list with the elements of the tuple added to the end of the list.\n \"\"\"\n return list1 + list(tuple1)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(input_list, input_tuple):\n \"\"\"Adds a tuple to the end of a list.\"\"\"\n return input_list + list(input_tuple)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(list1, tuple1):\n \"\"\"\n Adds the elements of a tuple to the end of a list.\n\n Args:\n list1: The list to add the tuple to.\n tuple1: The tuple to be added.\n\n Returns:\n A new list with the elements of the tuple appended to the end.\n \"\"\"\n return list1 + list(tuple1)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(list1, tuple1):\n \"\"\"Add the given tuple to the given list.\"\"\"\n return list1 + list(tuple1)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(list_a: list, tuple_a: tuple) -> list:\n \"\"\"\n Write a function to add the given tuple to the given list.\n\n assert add_tuple([5, 6, 7], (9, 10)) == [5, 6, 7, 9, 10]\n \"\"\"\n return list_a + list(tuple_a)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(list1, tuple1):\n \"\"\"\n This function adds the elements of a tuple to the end of a list.\n\n Args:\n list1: A list.\n tuple1: A tuple.\n\n Returns:\n A new list with the elements of the tuple appended to the end of the list.\n \"\"\"\n\n new_list = list1.copy()\n new_list.extend(tuple1)\n return new_list", "matching_cluster_idx": 3}, {"solution": "def add_tuple(lst, tup):\n \"\"\"Adds the given tuple to the given list.\n\n Args:\n lst: The list to append to.\n tup: The tuple to append.\n\n Returns:\n A new list with the tuple's elements added to the end.\n \"\"\"\n return lst + list(tup)", "matching_cluster_idx": 2}]}, "Mbpp/753": {"dps": 97.31543624161074, "dps_norm": 75.0, "pass@1": 100.0, "profiled": [{"solution": "def min_k(list_of_tuples, k):\n \"\"\"\n Finds the minimum k records from a list of tuples, where the second element of each tuple is used for comparison.\n\n Args:\n list_of_tuples: A list of tuples, where each tuple has the format (name, value).\n k: The number of minimum records to return.\n\n Returns:\n A list of the k tuples with the smallest values.\n \"\"\"\n return sorted(list_of_tuples, key=lambda x: x[1])[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(list_of_tuples, k):\n \"\"\"\n Finds the minimum k records from a list of tuples, based on the second element of each tuple.\n\n Args:\n list_of_tuples: A list of tuples, where each tuple has the form (name, value).\n k: The number of minimum records to return.\n\n Returns:\n A list of the k tuples with the smallest values, sorted in ascending order of values.\n \"\"\"\n return sorted(list_of_tuples, key=lambda x: x[1])[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(list_tuples, k):\n \"\"\"\n Finds the minimum k records from a list of tuples, based on the second element of each tuple (assumed to be an integer).\n\n Args:\n list_tuples: A list of tuples, where each tuple contains a name and a numerical value.\n k: The number of minimum records to return.\n\n Returns:\n A list of the k tuples with the minimum values, sorted in ascending order by the second element.\n \"\"\"\n return sorted(list_tuples, key=lambda x: x[1])[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(tuples_list, k):\n \"\"\"\n Finds the minimum k records from a list of tuples based on the second element (integer value).\n\n Args:\n tuples_list: A list of tuples, where each tuple has the format (name, value).\n k: The number of minimum records to return.\n\n Returns:\n A list containing the k minimum records as tuples.\n \"\"\"\n return sorted(tuples_list, key=lambda x: x[1])[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(data, k):\n \"\"\"\n Finds the minimum k records from a list of tuples, based on the second element (assumed to be a numeric value)\n\n Args:\n data: A list of tuples, where each tuple represents a record.\n k: The number of minimum records to return.\n\n Returns:\n A list containing the k tuples with the minimum second element values.\n \"\"\"\n return sorted(data, key=lambda x: x[1])[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(list_of_tuples, k):\n \"\"\"\n Finds the minimum k records from a list of tuples.\n\n Args:\n list_of_tuples: A list of tuples where the second element of each tuple is a numerical value.\n k: The number of minimum records to return.\n\n Returns:\n A list of tuples containing the k minimum records.\n \"\"\"\n return sorted(list_of_tuples, key=lambda x: x[1])[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(list_of_tuples, k):\n \"\"\"\n Finds the minimum k records from a list of tuples, sorted by the second element (integer).\n\n Args:\n list_of_tuples: A list of tuples, where each tuple contains a string and an integer.\n k: The number of minimum records to return.\n\n Returns:\n A list of k tuples with the minimum integer values, sorted by ascending order of the integers.\n \"\"\"\n\n return sorted(list_of_tuples, key=lambda x: x[1])[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(tuple_list, k):\n \"\"\"\n Finds the minimum k records from a list of tuples based on the second element (integer value).\n\n Args:\n tuple_list: A list of tuples, where each tuple has the format (name, value).\n k: The number of minimum records to return.\n\n Returns:\n A list containing the k tuples with the smallest values.\n \"\"\"\n return sorted(tuple_list, key=lambda x: x[1])[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(tuple_list, k):\n \"\"\"\n Finds the minimum k records from a list of tuples based on the second element (integer) of each tuple.\n\n Args:\n tuple_list: A list of tuples, where each tuple has the format (string, integer).\n k: The number of minimum records to return.\n\n Returns:\n A list of the k tuples with the smallest integer values.\n \"\"\"\n return sorted(tuple_list, key=lambda x: x[1])[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(list_of_tuples, k):\n \"\"\"\n Finds the minimum k records from a list of tuples, ordered by the second element of each tuple.\n\n Args:\n list_of_tuples: A list of tuples, where each tuple contains a name and a number.\n k: The number of minimum records to return.\n\n Returns:\n A list of the k tuples with the smallest second elements.\n \"\"\"\n return sorted(list_of_tuples, key=lambda x: x[1])[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(data, k):\n \"\"\"Finds the k records with the smallest second element from a list of tuples.\n\n Args:\n data: A list of tuples, where each tuple has the form (name, value).\n k: The number of records to return.\n\n Returns:\n A list of k tuples with the smallest values, sorted by the second element.\n \"\"\"\n return sorted(data, key=lambda x: x[1])[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(tuples_list, k):\n \"\"\"\n Finds the minimum k records from a list of tuples.\n\n Args:\n tuples_list: A list of tuples, where the second element of each tuple is a number.\n k: The number of minimum records to return.\n\n Returns:\n A new list containing the k tuples with the smallest second elements.\n \"\"\"\n return sorted(tuples_list, key=lambda x: x[1])[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(input_list, k):\n \"\"\"\n Finds the minimum k records from a list of tuples, where the second element\n of each tuple represents a numerical value.\n\n Args:\n input_list: A list of tuples, where each tuple is in the form (name, value).\n k: The number of minimum records to return.\n\n Returns:\n A list containing the k tuples with the minimum values.\n \"\"\"\n return sorted(input_list, key=lambda x: x[1])[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(tuple_list, k):\n \"\"\"\n Finds the k minimum records from a list of tuples, sorted by the second element of each tuple.\n\n Args:\n tuple_list: A list of tuples, where each tuple has the format (name, value).\n k: The number of minimum records to return.\n\n Returns:\n A list containing the k tuples with the minimum values, sorted by the second element.\n \"\"\"\n return sorted(tuple_list, key=lambda x: x[1])[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(tuple_list, k):\n \"\"\"\n Finds the minimum k records from a list of tuples based on the second element (integer value).\n\n Args:\n tuple_list: A list of tuples, where each tuple has the format (name, value).\n k: The number of minimum records to return.\n\n Returns:\n A list of the k tuples with the minimum values, sorted in ascending order based on the second element.\n \"\"\"\n return sorted(tuple_list, key=lambda x: x[1])[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(tuples_list, k):\n \"\"\"\n Finds the minimum k records from a list of tuples.\n\n Args:\n tuples_list: A list of tuples where each tuple contains a name and a number.\n k: The number of minimum records to return.\n\n Returns:\n A list containing the k tuples with the smallest numbers.\n \"\"\"\n return sorted(tuples_list, key=lambda x: x[1])[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(list_of_tuples, k):\n \"\"\"\n Finds the minimum k records from a list of tuples based on the second element (integer value) of each tuple.\n\n Args:\n list_of_tuples: A list of tuples, where each tuple contains a string and an integer.\n k: The number of minimum records to return.\n\n Returns:\n A list containing the k minimum records as tuples.\n \"\"\"\n return sorted(list_of_tuples, key=lambda x: x[1])[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(list_of_tuples, k):\n \"\"\"\n This function takes a list of tuples and an integer k, and returns a list of the k tuples with the smallest second elements.\n\n Args:\n list_of_tuples: A list of tuples, where each tuple has two elements: a string and an integer.\n k: The number of tuples to return.\n\n Returns:\n A list of the k tuples with the smallest second elements.\n \"\"\"\n\n return sorted(list_of_tuples, key=lambda x: x[1])[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(tuple_list, k):\n \"\"\"\n Finds the minimum k records from a list of tuples based on the second element (integer).\n\n Args:\n tuple_list: A list of tuples, where each tuple contains a string and an integer.\n k: The number of minimum records to return.\n\n Returns:\n A list of the k tuples with the smallest integer values.\n \"\"\"\n return sorted(tuple_list, key=lambda x: x[1])[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(list_of_tuples, k):\n \"\"\"\n Finds the minimum k records from a list of tuples, sorted by the second element of each tuple.\n\n Args:\n list_of_tuples: A list of tuples, where each tuple contains a string and an integer.\n k: The number of minimum records to return.\n\n Returns:\n A list containing the k tuples with the minimum second elements.\n \"\"\"\n return sorted(list_of_tuples, key=lambda x: x[1])[:k]", "matching_cluster_idx": 2}]}, "Mbpp/754": {"dps": 89.65517241379311, "dps_norm": 87.5, "pass@1": 89.0, "profiled": [{"solution": "def extract_index_list(l1, l2, l3):\n \"\"\"\n Finds common elements from three lists that appear under the same index in all lists.\n\n Args:\n l1: The first list.\n l2: The second list.\n l3: The third list.\n\n Returns:\n A list containing the common elements.\n \"\"\"\n common_elements = []\n for i in range(min(len(l1), len(l2), len(l3))):\n if l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n \"\"\"\n Finds common elements from three lists at the same index.\n\n Args:\n l1: The first list.\n l2: The second list.\n l3: The third list.\n\n Returns:\n A list of common elements from l1, l2, and l3.\n \"\"\"\n common_elements = []\n for i in range(min(len(l1), len(l2), len(l3))):\n if l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n \"\"\"\n Finds common elements from three lists appearing at the same index.\n\n Args:\n l1: The first list.\n l2: The second list.\n l3: The third list.\n\n Returns:\n A list containing the common elements.\n \"\"\"\n common_elements = []\n for i in range(min(len(l1), len(l2), len(l3))):\n if l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n common_elements = []\n for i in range(min(len(l1), len(l2), len(l3))):\n if l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n \"\"\"\n Finds common elements from three lists.\n\n An element is considered common if it appears in all three lists under the same index.\n \n Args:\n l1: The first list.\n l2: The second list.\n l3: The third list.\n\n Returns:\n A list of common elements.\n \"\"\"\n common_elements = []\n for i in range(min(len(l1), len(l2), len(l3))):\n if l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n \"\"\"\n Finds common elements from three lists at the same index.\n\n Args:\n l1: The first list.\n l2: The second list.\n l3: The third list.\n\n Returns:\n A list containing the common elements.\n \"\"\"\n common_elements = []\n for i in range(min(len(l1), len(l2), len(l3))):\n if l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n \"\"\"\n This function finds elements that appear in the same index across three lists.\n\n Args:\n l1: The first list.\n l2: The second list.\n l3: The third list.\n\n Returns:\n A list containing the common elements.\n \"\"\"\n\n common_elements = []\n for i in range(min(len(l1), len(l2), len(l3))):\n if l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n \"\"\"\n Finds elements common to three lists at the same index.\n\n Args:\n l1: The first list.\n l2: The second list.\n l3: The third list.\n\n Returns:\n A list containing the elements that appear at the same index in all three input lists.\n \"\"\"\n common_elements = []\n for i in range(min(len(l1), len(l2), len(l3))):\n if l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n return common_elements\nl1 = [1, 1, 3, 4, 5, 6, 7]\nl2 = [0, 1, 2, 3, 4, 5, 7]\nl3 = [0, 1, 2, 3, 4, 5, 7]", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n \"\"\"\n Finds elements that appear in the same index in all three lists.\n\n Args:\n l1: The first list.\n l2: The second list.\n l3: The third list.\n\n Returns:\n A list of common elements.\n \"\"\"\n common_elements = []\n for i in range(min(len(l1), len(l2), len(l3))):\n if l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n \"\"\"\n This function finds common elements from three lists. \n The function returns a list of these elements.\n \"\"\"\n common_elements = []\n for i in range(min(len(l1), len(l2), len(l3))):\n if l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n \"\"\"\n Finds elements common to three lists at the same index.\n\n Args:\n l1: The first list.\n l2: The second list.\n l3: The third list.\n\n Returns:\n A list of elements that appear at the same index in all three input lists.\n \"\"\"\n common_elements = []\n for i in range(min(len(l1), len(l2), len(l3))):\n if l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n \"\"\"\n Finds common elements from three lists at the same index.\n\n Args:\n l1: The first list.\n l2: The second list.\n l3: The third list.\n\n Returns:\n A list containing the common elements.\n \"\"\"\n common_elements = []\n for i in range(min(len(l1), len(l2), len(l3))):\n if l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n \"\"\"\n Finds common elements from three lists that appear at the same index in all lists.\n\n Args:\n l1: The first list.\n l2: The second list.\n l3: The third list.\n\n Returns:\n A list containing the common elements.\n \"\"\"\n common_elements = []\n for i in range(min(len(l1), len(l2), len(l3))):\n if l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i]) \n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n \"\"\"\n We say that an element is common for lists l1, l2, l3 if it appears in all three lists under the same index. Write a function to find common elements from three lists. The function should return a list.\n assert extract_index_list([1, 1, 3, 4, 5, 6, 7],[0, 1, 2, 3, 4, 5, 7],[0, 1, 2, 3, 4, 5, 7])==[1, 7]\n \"\"\"\n common_elements = []\n for i in range(min(len(l1), len(l2), len(l3))):\n if l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n return common_elements\nl1 = [1, 1, 3, 4, 5, 6, 7]\nl2 = [0, 1, 2, 3, 4, 5, 7]\nl3 = [0, 1, 2, 3, 4, 5, 7]", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n \"\"\"\n Finds elements common to three lists at the same index.\n\n Args:\n l1: The first list.\n l2: The second list.\n l3: The third list.\n\n Returns:\n A list of elements common to all three lists at the same index.\n \"\"\"\n common_elements = []\n for i in range(min(len(l1), len(l2), len(l3))):\n if l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n \"\"\"\n Finds common elements from three lists based on same index.\n\n Args:\n l1: The first list.\n l2: The second list.\n l3: The third list.\n\n Returns:\n A list of common elements.\n \"\"\"\n common_elements = []\n for i in range(min(len(l1), len(l2), len(l3))):\n if l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n \"\"\"\n Finds common elements from three lists at the same index.\n\n Args:\n l1: The first list.\n l2: The second list.\n l3: The third list.\n\n Returns:\n A list containing the common elements.\n \"\"\"\n\n common_elements = []\n for i in range(min(len(l1), len(l2), len(l3))):\n if l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n \"\"\"\n Finds common elements from three lists at the same index.\n\n Args:\n l1: The first list.\n l2: The second list.\n l3: The third list.\n\n Returns:\n A list containing the common elements.\n \"\"\"\n common = []\n for i in range(min(len(l1), len(l2), len(l3))):\n if l1[i] == l2[i] == l3[i]:\n common.append(l1[i])\n return common", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n \"\"\"\n Finds elements that appear at the same index in all three lists.\n\n Args:\n l1, l2, l3: Three lists.\n\n Returns:\n A list of common elements.\n \"\"\"\n common_elements = []\n for i in range(min(len(l1), len(l2), len(l3))):\n if l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n \"\"\"\n Finds common elements from three lists that appear at the same index.\n\n Args:\n l1: The first list.\n l2: The second list.\n l3: The third list.\n\n Returns:\n A list of common elements.\n \"\"\"\n common_elements = []\n for i in range(min(len(l1), len(l2), len(l3))):\n if l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n return common_elements", "matching_cluster_idx": 6}]}, "Mbpp/755": {"dps": 64.86725663716814, "dps_norm": 81.66666666666667, "pass@1": 54.0, "profiled": [{"solution": "def second_smallest(numbers):\n \"\"\"\n Finds the second smallest number in a list.\n\n Args:\n numbers: A list of numbers.\n\n Returns:\n The second smallest number in the list.\n Returns None if the list has less than two distinct elements.\n \"\"\"\n if len(set(numbers)) < 2:\n return None \n \n smallest = min(numbers)\n second_smallest = float('inf') \n for number in numbers:\n if number != smallest and number < second_smallest:\n second_smallest = number\n return second_smallest", "matching_cluster_idx": 2}, {"solution": "def second_smallest(numbers):\n \"\"\"\n Finds the second smallest number in a list.\n\n Args:\n numbers: A list of numbers.\n\n Returns:\n The second smallest number in the list. \n Returns None if the list has less than two unique elements.\n \"\"\"\n unique_numbers = sorted(set(numbers))\n return unique_numbers[1] if len(unique_numbers) > 1 else None", "matching_cluster_idx": 5}, {"solution": "def second_smallest(numbers):\n \"\"\"Finds the second smallest number in a list.\n\n Args:\n numbers: A list of numbers.\n\n Returns:\n The second smallest number in the list. \n Returns None if the list has less than two distinct elements.\n \"\"\"\n unique_numbers = sorted(set(numbers))\n if len(unique_numbers) < 2:\n return None\n return unique_numbers[1]", "matching_cluster_idx": 5}, {"solution": "def second_smallest(numbers):\n \"\"\"Finds the second smallest number in a list.\n\n Args:\n numbers: A list of numbers.\n\n Returns:\n The second smallest number in the list, or None if the list\n has less than two unique numbers.\n \"\"\"\n\n # Handle cases with fewer than two unique elements\n unique_numbers = set(numbers)\n if len(unique_numbers) < 2:\n return None\n \n # Find smallest and second smallest\n smallest = min(unique_numbers)\n second_smallest = max(unique_numbers) \n\n for num in unique_numbers:\n if num > smallest and num < second_smallest:\n second_smallest = num\n\n return second_smallest", "matching_cluster_idx": 2}, {"solution": "def second_smallest(nums):\n \"\"\"\n Finds the second smallest number in a list.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n The second smallest number in the list, or None if the list has less than two\n distinct elements.\n \"\"\"\n \n # Remove duplicates to ensure we don't accidentally consider the same number twice\n unique_nums = list(set(nums)) \n \n if len(unique_nums) < 2:\n return None\n \n smallest = min(unique_nums)\n second_smallest = max(unique_nums) # Initialize with maximum for comparison\n\n for num in unique_nums:\n if num != smallest and num < second_smallest:\n second_smallest = num\n\n return second_smallest", "matching_cluster_idx": 2}, {"solution": "def second_smallest(numbers):\n \"\"\"\n Finds the second smallest number in a list.\n\n Args:\n numbers: A list of numbers.\n\n Returns:\n The second smallest number in the list, or None if the list has fewer than 2 distinct elements.\n \"\"\"\n unique_numbers = sorted(set(numbers))\n if len(unique_numbers) < 2:\n return None\n return unique_numbers[1]", "matching_cluster_idx": 5}, {"solution": "def second_smallest(numbers):\n \"\"\"\n Finds the second smallest number in a list.\n\n Args:\n numbers: A list of numbers.\n\n Returns:\n The second smallest number in the list, or None if the list has fewer than two unique elements.\n \"\"\"\n unique_numbers = set(numbers)\n if len(unique_numbers) < 2:\n return None # Not enough unique elements\n\n # Remove the smallest element and find the smallest in the remaining set\n unique_numbers.remove(min(unique_numbers))\n return min(unique_numbers)", "matching_cluster_idx": 4}, {"solution": "def second_smallest(numbers):\n \"\"\"\n Finds the second smallest number in a list.\n\n Args:\n numbers: A list of numbers.\n\n Returns:\n The second smallest number in the list. Returns None if the list has less than two unique elements.\n\n \"\"\"\n unique_numbers = sorted(set(numbers))\n if len(unique_numbers) < 2:\n return None\n return unique_numbers[1]", "matching_cluster_idx": 5}, {"solution": "def second_smallest(numbers):\n \"\"\"\n Finds the second smallest number in a list.\n\n Args:\n numbers: A list of numbers.\n\n Returns:\n The second smallest number in the list.\n\n Returns None if the list has less than two distinct elements.\n \"\"\"\n unique_numbers = sorted(set(numbers))\n if len(unique_numbers) < 2:\n return None\n return unique_numbers[1]", "matching_cluster_idx": 5}, {"solution": "def second_smallest(numbers):\n \"\"\"\n This function finds the second smallest number in a list.\n\n Args:\n numbers: A list of numbers.\n\n Returns:\n The second smallest number in the list.\n Returns None if the list is empty or has less than two unique elements.\n \"\"\"\n if len(numbers) < 2:\n return None\n \n # Sort the list and remove duplicates\n unique_numbers = sorted(set(numbers))\n \n # Return the second element (index 1) if there are at least two elements\n if len(unique_numbers) >= 2:\n return unique_numbers[1]\n else:\n return None", "matching_cluster_idx": 5}, {"solution": "def second_smallest(numbers):\n \"\"\"\n Finds the second smallest number in a list.\n\n Args:\n numbers: A list of numbers.\n\n Returns:\n The second smallest number in the list, or None if the list has less than two distinct elements.\n \"\"\"\n unique_numbers = set(numbers)\n if len(unique_numbers) < 2:\n return None\n unique_numbers.remove(min(unique_numbers))\n return min(unique_numbers)", "matching_cluster_idx": 4}, {"solution": "def second_smallest(numbers):\n \"\"\"\n This function finds the second smallest number in a list.\n\n Args:\n numbers: A list of numbers.\n\n Returns:\n The second smallest number in the list, or None if the list is empty or has less than two distinct elements.\n \"\"\"\n if len(numbers) < 2:\n return None\n\n # Find the smallest and second smallest numbers.\n smallest = min(numbers)\n second_smallest = float('inf')\n for num in numbers:\n if num != smallest and num < second_smallest:\n second_smallest = num\n\n # Return the second smallest number, or None if there is no second smallest.\n return second_smallest if second_smallest != float('inf') else None", "matching_cluster_idx": 3}, {"solution": "def second_smallest(numbers):\n \"\"\"\n Finds the second smallest number in a list.\n\n Args:\n numbers: A list of numbers.\n\n Returns:\n The second smallest number in the list, or None if the list has less than two unique elements.\n \"\"\"\n\n # Remove duplicates and sort the list\n unique_numbers = sorted(set(numbers))\n\n # Return the second element (index 1) if it exists\n return unique_numbers[1] if len(unique_numbers) >= 2 else None", "matching_cluster_idx": 5}, {"solution": "def second_smallest(numbers):\n \"\"\"Finds the second smallest number in a list.\n\n Args:\n numbers: A list of numbers.\n\n Returns:\n The second smallest number in the list.\n Returns None if the list has less than two unique elements.\n \"\"\"\n \n # Sort the list, removing duplicates while maintaining order\n unique_numbers = sorted(set(numbers))\n \n # Check if there are at least two unique numbers\n if len(unique_numbers) < 2:\n return None\n \n return unique_numbers[1]", "matching_cluster_idx": 5}, {"solution": "def second_smallest(numbers):\n \"\"\"Finds the second smallest number in a list.\n\n Args:\n numbers: A list of numbers.\n\n Returns:\n The second smallest number in the list, or None if the list has less than \n two distinct elements.\n \"\"\"\n # Handle edge cases: less than 2 elements \n if len(set(numbers)) < 2:\n return None\n \n # Find the smallest and second smallest numbers\n smallest = min(numbers)\n second_smallest = max(numbers) # Initialize with a large value\n\n for number in numbers:\n if number != smallest and number < second_smallest:\n second_smallest = number\n\n return second_smallest", "matching_cluster_idx": 2}, {"solution": "def second_smallest(nums):\n \"\"\"\n Finds the second smallest number in a list.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n The second smallest number in the list, or None if the list has fewer than two distinct elements.\n \"\"\"\n #Handle cases with less than two elements\n if len(set(nums)) < 2:\n return None\n \n #Remove duplicates and sort the list\n unique_nums = sorted(set(nums))\n return unique_nums[1]", "matching_cluster_idx": 4}, {"solution": "def second_smallest(numbers):\n \"\"\"\n Finds the second smallest number in a list.\n Args:\n numbers: A list of numbers.\n Returns:\n The second smallest number in the list, or None if the list has fewer than two unique elements.\n \"\"\"\n unique_numbers = set(numbers)\n if len(unique_numbers) < 2:\n return None\n unique_numbers.remove(min(unique_numbers))\n return min(unique_numbers)", "matching_cluster_idx": 4}, {"solution": "def second_smallest(numbers):\n \"\"\"\n Finds the second smallest number in a list.\n\n Args:\n numbers: A list of numbers.\n\n Returns:\n The second smallest number in the list. Returns None if the list has\n fewer than two unique elements.\n \"\"\"\n\n # Remove duplicates and sort the list\n unique_numbers = sorted(set(numbers))\n\n # Return the second element if the list has at least two unique elements\n if len(unique_numbers) >= 2:\n return unique_numbers[1]\n else:\n return None", "matching_cluster_idx": 5}, {"solution": "def second_smallest(numbers):\n \"\"\"\n Finds the second smallest number in a list.\n\n Args:\n numbers: A list of numbers.\n\n Returns:\n The second smallest number in the list, or None if the list has less than two distinct elements.\n \"\"\"\n if len(set(numbers)) < 2:\n return None\n\n smallest = min(numbers)\n second_smallest = float('inf')\n for num in numbers:\n if num != smallest and num < second_smallest:\n second_smallest = num\n return second_smallest", "matching_cluster_idx": 2}, {"solution": "def second_smallest(numbers):\n \"\"\"Finds the second smallest number in a list.\n\n Args:\n numbers: A list of numbers.\n\n Returns:\n The second smallest number in the list, or None if the list has less than two distinct elements.\n \"\"\"\n unique_numbers = set(numbers) \n if len(unique_numbers) < 2:\n return None\n \n unique_numbers.remove(min(unique_numbers))\n return min(unique_numbers)", "matching_cluster_idx": 4}]}, "Mbpp/757": {"dps": 82.71028037383178, "dps_norm": 23.076923076923077, "pass@1": 90.0, "profiled": [{"solution": "def count_reverse_pairs(strings):\n \"\"\"\n Counts the number of pairs of reverse strings in a list.\n\n Args:\n strings: A list of strings.\n\n Returns:\n The number of pairs of reverse strings in the list.\n \"\"\"\n\n count = 0\n seen = set()\n for i in range(len(strings)):\n for j in range(i + 1, len(strings)):\n if strings[i] == strings[j][::-1] and (i, j) not in seen:\n count += 1\n seen.add((i, j)) # To avoid counting the same pair twice\n seen.add((j, i))\n\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(strings):\n \"\"\"Counts the number of pairs of reverse strings in a list.\n\n Args:\n strings: A list of strings.\n\n Returns:\n The number of pairs of reverse strings in the list.\n \"\"\"\n count = 0\n for i in range(len(strings)):\n for j in range(i + 1, len(strings)):\n if strings[i] == strings[j][::-1]:\n count += 1\n return count\nstrings = [\"julia\", \"best\", \"tseb\", \"for\", \"ailuj\"]", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(strings):\n \"\"\"\n Counts the number of pairs of reverse strings in the given string list.\n\n Args:\n strings: A list of strings.\n\n Returns:\n The number of pairs of reverse strings in the list.\n \"\"\"\n count = 0\n for i in range(len(strings)):\n for j in range(i + 1, len(strings)):\n if strings[i] == strings[j][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(strings):\n \"\"\"\n Counts the pairs of reverse strings in a given list of strings.\n\n Args:\n strings: A list of strings.\n\n Returns:\n The number of pairs of reverse strings in the list.\n \"\"\"\n count = 0\n for i in range(len(strings)):\n for j in range(i + 1, len(strings)):\n if strings[i] == strings[j][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(string_list):\n \"\"\"Counts the pairs of reverse strings in the given string list.\n\n Args:\n string_list: A list of strings.\n\n Returns:\n The number of pairs of reverse strings in the list.\n \"\"\"\n count = 0\n for i in range(len(string_list)):\n for j in range(i + 1, len(string_list)):\n if string_list[i][::-1] == string_list[j]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(strings):\n \"\"\"\n Counts the pairs of reverse strings in the given string list.\n\n Args:\n strings: A list of strings.\n\n Returns:\n The number of pairs of reverse strings in the list.\n \"\"\"\n count = 0\n for i in range(len(strings)):\n for j in range(i + 1, len(strings)):\n if strings[i] == strings[j][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(strings):\n \"\"\"\n Write a function to count the pairs of reverse strings in the given string list.\n\n assert count_reverse_pairs([\"julia\", \"best\", \"tseb\", \"for\", \"ailuj\"]) == 2\n \"\"\"\n count = 0\n for i in range(len(strings)):\n for j in range(i + 1, len(strings)):\n if strings[i] == strings[j][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(strings):\n \"\"\"Counts the pairs of reverse strings in a given list.\n\n Args:\n strings: A list of strings.\n\n Returns:\n The number of pairs of reverse strings in the list.\n \"\"\"\n count = 0\n for i in range(len(strings)):\n for j in range(i + 1, len(strings)):\n if strings[i] == strings[j][::-1]:\n count += 1\n return count\nstrings = [\"julia\", \"best\", \"tseb\", \"for\", \"ailuj\"]", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(strings):\n \"\"\"\n Write a function to count the pairs of reverse strings in the given string list.\n assert count_reverse_pairs([\"julia\", \"best\", \"tseb\", \"for\", \"ailuj\"])== 2\n \"\"\"\n count = 0\n for i in range(len(strings)):\n for j in range(i+1, len(strings)):\n if strings[i] == strings[j][::-1]:\n count += 1\n return count\nstrings = [\"julia\", \"best\", \"tseb\", \"for\", \"ailuj\"]", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(strings):\n \"\"\"Counts pairs of reverse strings in a list.\n\n Args:\n strings: A list of strings.\n\n Returns:\n The number of pairs of reverse strings in the list.\n \"\"\"\n count = 0\n for i in range(len(strings)):\n for j in range(i + 1, len(strings)):\n if strings[i] == strings[j][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(string_list):\n \"\"\"\n Counts the number of pairs of reverse strings in a given list.\n\n Args:\n string_list: A list of strings.\n\n Returns:\n The number of pairs of reverse strings in the list.\n \"\"\"\n count = 0\n for i in range(len(string_list)):\n for j in range(i + 1, len(string_list)):\n if string_list[i] == string_list[j][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(strings):\n \"\"\"Counts the pairs of reverse strings in a list.\n\n Args:\n strings: A list of strings.\n\n Returns:\n The number of pairs of reverse strings in the list.\n \"\"\"\n\n count = 0\n for i in range(len(strings)):\n for j in range(i + 1, len(strings)):\n if strings[i] == strings[j][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(words):\n \"\"\"\n Counts the pairs of reverse strings in the given string list.\n\n Args:\n words: A list of strings.\n\n Returns:\n The number of pairs of reverse strings in the list.\n \"\"\"\n count = 0\n for i in range(len(words)):\n for j in range(i+1, len(words)):\n if words[i] == words[j][::-1]: \n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(strings):\n \"\"\"Counts the pairs of reverse strings in the given string list.\n\n Args:\n strings: A list of strings.\n\n Returns:\n The number of pairs of reverse strings in the list.\n \"\"\"\n\n count = 0\n for i in range(len(strings)):\n for j in range(i + 1, len(strings)):\n if strings[i] == strings[j][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(strings):\n \"\"\"\n This function counts the number of pairs of reverse strings in a list.\n\n Args:\n strings: A list of strings.\n\n Returns:\n The number of pairs of reverse strings in the list.\n \"\"\"\n count = 0\n for i in range(len(strings)):\n for j in range(i + 1, len(strings)):\n if strings[i] == strings[j][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(string_list):\n \"\"\"\n Counts the pairs of reverse strings in the given string list.\n\n Args:\n string_list: A list of strings.\n\n Returns:\n The number of pairs of reverse strings in the list.\n \"\"\"\n count = 0\n seen = set()\n for i in range(len(string_list)):\n for j in range(i + 1, len(string_list)):\n if string_list[i] == string_list[j][::-1] and (i, j) not in seen:\n count += 1\n seen.add((i, j))\n seen.add((j, i)) # Since order doesn't matter for pairs\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(strings):\n \"\"\"\n Counts the pairs of reverse strings in the given string list.\n\n Args:\n strings: A list of strings.\n\n Returns:\n The number of pairs of reverse strings in the list.\n \"\"\"\n count = 0\n for i in range(len(strings)):\n for j in range(i+1, len(strings)):\n if strings[i] == strings[j][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(strs):\n \"\"\"\n Count the pairs of reverse strings in the given string list. \n\n Args:\n strs: A list of strings.\n\n Returns:\n The number of pairs of reverse strings in the list.\n \"\"\"\n count = 0\n seen = set()\n for i in range(len(strs)):\n for j in range(i+1, len(strs)):\n if strs[i] == strs[j][::-1] and (i,j) not in seen:\n count += 1\n seen.add((i,j))\n seen.add((j,i)) # Add the reverse pair\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(string_list):\n \"\"\"Counts the number of reverse string pairs in a list.\n\n Args:\n string_list: A list of strings.\n\n Returns:\n The number of pairs of strings where one is the reverse of the other.\n \"\"\"\n count = 0\n seen = set()\n for i in range(len(string_list)):\n for j in range(i + 1, len(string_list)):\n if string_list[i] == string_list[j][::-1] and (i, j) not in seen:\n count += 1\n seen.add((i, j))\n seen.add((j, i)) # Account for both orderings of the pair\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(strings):\n \"\"\"\n Counts the number of pairs of reverse strings in a list.\n\n Args:\n strings: A list of strings.\n\n Returns:\n The number of pairs of reverse strings in the list.\n \"\"\"\n count = 0\n for i in range(len(strings)):\n for j in range(i + 1, len(strings)):\n if strings[i] == strings[j][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}]}, "Mbpp/758": {"dps": 69.05405405405405, "dps_norm": 76.875, "pass@1": 100.0, "profiled": [{"solution": "def unique_sublists(lst):\n \"\"\"Counts the occurrences of lists within a list and returns a dictionary.\n\n Args:\n lst: A list of lists.\n\n Returns:\n A dictionary where keys are tuples representing unique sublists and values are their counts.\n \"\"\"\n counts = {}\n for sublist in lst:\n sublist_tuple = tuple(sublist) # Convert sublist to tuple for hashability\n if sublist_tuple in counts:\n counts[sublist_tuple] += 1\n else:\n counts[sublist_tuple] = 1\n return counts", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(input_list):\n \"\"\"\n Counts the occurrences of sublists within a list.\n\n Args:\n input_list: A list of lists.\n\n Returns:\n A dictionary where keys are tuples representing the sublists, and values\n are the counts of their occurrences.\n \"\"\"\n counts = {}\n for sublist in input_list:\n sublist_tuple = tuple(sublist) \n if sublist_tuple in counts:\n counts[sublist_tuple] += 1\n else:\n counts[sublist_tuple] = 1\n return counts", "matching_cluster_idx": 5}, {"solution": "def unique_sublists(input_list):\n \"\"\"\n Counts the occurrences of unique sublists within a list.\n\n Args:\n input_list: A list of lists.\n\n Returns:\n A dictionary where keys are tuples representing unique sublists and values are their counts.\n \"\"\"\n counts = {}\n for sublist in input_list:\n sublist_tuple = tuple(sublist) # Convert sublist to tuple for hashability\n if sublist_tuple in counts:\n counts[sublist_tuple] += 1\n else:\n counts[sublist_tuple] = 1\n return counts", "matching_cluster_idx": 5}, {"solution": "def unique_sublists(list_of_lists):\n \"\"\"Counts occurrences of lists within a list and returns a dictionary.\n\n Args:\n list_of_lists: A list containing lists as elements.\n\n Returns:\n A dictionary where keys are tuples representing unique sublists \n and values are the counts of their occurrences.\n \"\"\"\n\n counts = {}\n for sublist in list_of_lists:\n sublist_tuple = tuple(sublist) # Convert sublist to a tuple for hashable keys\n if sublist_tuple in counts:\n counts[sublist_tuple] += 1\n else:\n counts[sublist_tuple] = 1\n return counts", "matching_cluster_idx": 5}, {"solution": "from collections import Counter\ndef unique_sublists(lists):\n \"\"\"\n Counts the occurrences of each sublist in a list.\n\n Args:\n lists: A list of lists.\n\n Returns:\n A dictionary where keys are tuples representing the unique sublists, and values\n are the counts of each sublist.\n \"\"\"\n return dict(Counter(tuple(l) for l in lists))", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(data):\n \"\"\"Counts the occurrences of each sublist within a list.\n\n Args:\n data: A list of lists.\n\n Returns:\n A dictionary where keys are tuples representing unique sublists,\n and values are their respective counts.\n \"\"\"\n\n counts = {}\n for sublist in data:\n key = tuple(sublist) # Convert sublist to tuple for hashability\n if key in counts:\n counts[key] += 1\n else:\n counts[key] = 1\n return counts", "matching_cluster_idx": 5}, {"solution": "def unique_sublists(input_list):\n \"\"\"\n Counts the occurrences of unique sublists within a list.\n\n Args:\n input_list: A list of lists.\n\n Returns:\n A dictionary where keys are tuples representing unique sublists\n and values are their counts.\n \"\"\"\n counts = {}\n for sublist in input_list:\n sublist_tuple = tuple(sublist) # Convert to tuple for hashability\n if sublist_tuple in counts:\n counts[sublist_tuple] += 1\n else:\n counts[sublist_tuple] = 1\n return counts", "matching_cluster_idx": 5}, {"solution": "def unique_sublists(list_of_lists):\n \"\"\"\n Counts the occurrences of lists within a list, converting them to tuples.\n\n Args:\n list_of_lists: A list of lists.\n\n Returns:\n A dictionary where keys are tuples representing unique sublists\n and values are their respective counts.\n \"\"\"\n\n counts = {}\n for sublist in list_of_lists:\n sublist_tuple = tuple(sublist)\n if sublist_tuple in counts:\n counts[sublist_tuple] += 1\n else:\n counts[sublist_tuple] = 1\n return counts", "matching_cluster_idx": 5}, {"solution": "def unique_sublists(list_of_lists):\n \"\"\"\n Counts occurrences of unique sublists in a list.\n\n Args:\n list_of_lists: A list containing other lists.\n\n Returns:\n A dictionary where keys are tuples representing unique sublists,\n and values are the counts of their occurrences.\n \"\"\"\n counts = {}\n for sublist in list_of_lists:\n sublist_tuple = tuple(sublist) \n if sublist_tuple in counts:\n counts[sublist_tuple] += 1\n else:\n counts[sublist_tuple] = 1\n return counts", "matching_cluster_idx": 5}, {"solution": "def unique_sublists(data):\n \"\"\"\n Counts the occurrences of lists within a list.\n\n Args:\n data: A list containing lists.\n\n Returns:\n A dictionary where the keys are tuples representing unique sublists and the values are their frequencies.\n \"\"\"\n\n counts = {}\n for sublist in data:\n # Convert sublist to a tuple for hashability\n sublist_tuple = tuple(sublist)\n if sublist_tuple in counts:\n counts[sublist_tuple] += 1\n else:\n counts[sublist_tuple] = 1\n return counts", "matching_cluster_idx": 5}, {"solution": "def unique_sublists(input_list):\n \"\"\"\n Counts the occurrences of sublists within a list.\n\n Args:\n input_list: A list of lists.\n\n Returns:\n A dictionary where the keys are tuples representing unique sublists\n and the values are their counts.\n \"\"\"\n counts = {}\n for sublist in input_list:\n sublist_tuple = tuple(sublist) # Convert sublist to tuple for hashability\n if sublist_tuple in counts:\n counts[sublist_tuple] += 1\n else:\n counts[sublist_tuple] = 1\n return counts", "matching_cluster_idx": 5}, {"solution": "def unique_sublists(input_list):\n \"\"\"\n Counts the occurrences of lists within a list.\n\n Args:\n input_list: A list of lists.\n\n Returns:\n A dictionary where the keys are tuples representing unique sublists\n and the values are their respective counts.\n \"\"\"\n\n counts = {}\n for sublist in input_list:\n sublist_tuple = tuple(sublist) \n if sublist_tuple in counts:\n counts[sublist_tuple] += 1\n else:\n counts[sublist_tuple] = 1\n return counts", "matching_cluster_idx": 5}, {"solution": "def unique_sublists(lst):\n \"\"\"\n Counts the occurrences of lists within a list and returns a dictionary where\n each unique list (converted to a tuple) is a key, and its value is the count.\n\n Args:\n lst: A list of lists.\n\n Returns:\n A dictionary with tuples (representing the unique sublists) as keys and\n their counts as values.\n \"\"\"\n\n counts = {}\n for sublist in lst:\n sublist_tuple = tuple(sublist) # Convert to tuple for hashability\n if sublist_tuple in counts:\n counts[sublist_tuple] += 1\n else:\n counts[sublist_tuple] = 1\n return counts", "matching_cluster_idx": 5}, {"solution": "def unique_sublists(list_of_lists):\n \"\"\"\n Counts the occurrences of lists within a list.\n\n Args:\n list_of_lists: A list of lists.\n\n Returns:\n A dictionary where keys are tuples representing unique lists and values are\n the number of occurrences of each list.\n \"\"\"\n counts = {}\n for sublist in list_of_lists:\n sublist_tuple = tuple(sublist)\n if sublist_tuple in counts:\n counts[sublist_tuple] += 1\n else:\n counts[sublist_tuple] = 1\n return counts", "matching_cluster_idx": 5}, {"solution": "def unique_sublists(data):\n \"\"\"\n Counts occurrences of lists within a list and returns a dictionary\n\n Args:\n data: A list of lists.\n\n Returns:\n A dictionary where keys are tuples representing unique sublists,\n and values are the counts of those sublists in the original list.\n \"\"\"\n counts = {}\n for sublist in data:\n sublist_tuple = tuple(sublist) # Convert to tuple for hashability\n if sublist_tuple in counts:\n counts[sublist_tuple] += 1\n else:\n counts[sublist_tuple] = 1\n return counts", "matching_cluster_idx": 5}, {"solution": "def unique_sublists(lst):\n \"\"\"\n Counts the occurrences of lists within a list.\n\n Args:\n lst: A list of lists.\n\n Returns:\n A dictionary where keys are tuples representing unique sublists\n and values are their counts.\n \"\"\"\n sublist_counts = {}\n for sublist in lst:\n sublist_tuple = tuple(sublist)\n if sublist_tuple in sublist_counts:\n sublist_counts[sublist_tuple] += 1\n else:\n sublist_counts[sublist_tuple] = 1\n return sublist_counts", "matching_cluster_idx": 5}, {"solution": "def unique_sublists(list_of_lists):\n \"\"\"\n Counts the occurrences of each sublist within a list of lists.\n\n Args:\n list_of_lists: A list containing other lists as its elements.\n\n Returns:\n A dictionary where keys are tuples representing unique sublists,\n and values are the counts of their occurrences in the input list.\n \"\"\"\n counts = {}\n for sublist in list_of_lists:\n sublist_tuple = tuple(sublist) \n if sublist_tuple in counts:\n counts[sublist_tuple] += 1\n else:\n counts[sublist_tuple] = 1\n return counts", "matching_cluster_idx": 5}, {"solution": "def unique_sublists(data):\n \"\"\"\n Counts the occurrences of lists within a list, returning a dictionary\n where each unique list (converted to a tuple) is a key and its value is\n the count.\n\n Args:\n data: A list of lists.\n\n Returns:\n A dictionary of unique list tuples and their counts.\n \"\"\"\n\n counts = {}\n for sublist in data:\n sublist_tuple = tuple(sublist) # Convert list to tuple for hashability\n if sublist_tuple in counts:\n counts[sublist_tuple] += 1\n else:\n counts[sublist_tuple] = 1\n return counts", "matching_cluster_idx": 5}, {"solution": "def unique_sublists(data):\n \"\"\"\n Counts the occurrences of lists within a list.\n\n Args:\n data (list): A list of lists.\n\n Returns:\n dict: A dictionary where keys are tuples representing unique sublists and values are their counts.\n \"\"\"\n counts = {}\n for sublist in data:\n key = tuple(sublist) # Convert sublist to tuple for hashability\n if key in counts:\n counts[key] += 1\n else:\n counts[key] = 1\n return counts", "matching_cluster_idx": 5}, {"solution": "from collections import Counter\ndef unique_sublists(lst):\n \"\"\"Counts the occurrences of unique sublists within a list.\n\n Args:\n lst: A list of lists.\n\n Returns:\n A dictionary where each unique sublist (converted to a tuple) is a key,\n and its value is the number of times it appears in the input list.\n \"\"\"\n return dict(Counter(tuple(sublist) for sublist in lst))", "matching_cluster_idx": 6}]}, "Mbpp/760": {"dps": 99.27007299270073, "dps_norm": 87.5, "pass@1": 100.0, "profiled": [{"solution": "def unique_Element(nums):\n \"\"\"Checks if a list of numbers contains only one distinct element.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n True if the list contains only one distinct element, False otherwise.\n \"\"\"\n return len(set(nums)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(nums):\n \"\"\"\n Checks if a list of numbers contains only one distinct element.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n True if the list contains only one distinct element, False otherwise.\n \"\"\"\n return len(set(nums)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(nums: list) -> bool:\n \"\"\"\n Checks if a list contains only one distinct element.\n Args:\n nums: A list of numbers.\n Returns:\n True if the list contains only one distinct element, False otherwise.\n \"\"\"\n return len(set(nums)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(nums):\n \"\"\"\n Checks whether a list of numbers contains only one distinct element.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n True if the list contains only one distinct element, False otherwise.\n \"\"\"\n return len(set(nums)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(nums: list[int]) -> bool:\n \"\"\"\n Checks whether a list of numbers contains only one distinct element.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n True if the list contains only one distinct element, False otherwise.\n \"\"\"\n return len(set(nums)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(nums):\n \"\"\"\n Check if a list contains only one distinct element.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n True if the list contains only one distinct element, False otherwise.\n \"\"\"\n return len(set(nums)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(lst):\n \"\"\"\n Checks whether a list of numbers contains only one distinct element.\n\n Args:\n lst: A list of numbers.\n\n Returns:\n True if the list contains only one distinct element, False otherwise.\n \"\"\"\n return len(set(lst)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(nums):\n \"\"\"\n Checks if a list of numbers contains only one distinct element.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n True if the list contains only one distinct element, False otherwise.\n \"\"\"\n return len(set(nums)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(nums):\n \"\"\"\n Checks whether a list of numbers contains only one distinct element.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n True if the list contains only one distinct element, False otherwise.\n \"\"\"\n return len(set(nums)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(nums):\n \"\"\"Checks if a list contains only one distinct element.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n True if the list contains only one distinct element, False otherwise.\n \"\"\"\n return len(set(nums)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(lst):\n \"\"\"\n Checks if a list contains only one distinct element.\n\n Args:\n lst: A list of numbers.\n\n Returns:\n True if the list contains only one distinct element, False otherwise.\n \"\"\"\n return len(set(lst)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(numbers):\n \"\"\"\n This function checks whether a list of numbers contains only one distinct element.\n\n Args:\n numbers: A list of numbers.\n\n Returns:\n True if the list contains only one distinct element, False otherwise.\n \"\"\"\n return len(set(numbers)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(numbers):\n \"\"\"\n Checks if a list of numbers contains only one distinct element.\n\n Args:\n numbers: A list of numbers.\n\n Returns:\n True if the list contains only one distinct element, False otherwise.\n \"\"\"\n return len(set(numbers)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(nums):\n \"\"\"\n Checks whether a list of numbers contains only one distinct element.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n True if the list contains only one distinct element, False otherwise.\n \"\"\"\n return len(set(nums)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(nums):\n \"\"\"\n Checks if a list of numbers contains only one distinct element.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n True if the list contains only one distinct element, False otherwise.\n \"\"\"\n return len(set(nums)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(nums):\n \"\"\"\n Checks if a list of numbers contains only one distinct element.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n True if the list contains only one distinct element, False otherwise.\n \"\"\"\n return len(set(nums)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(nums):\n \"\"\"\n Checks if a list of numbers contains only one distinct element.\n Args:\n nums: A list of numbers.\n Returns:\n True if the list contains only one distinct element, False otherwise.\n \"\"\"\n return len(set(nums)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(input_list):\n \"\"\"\n Checks if a list of numbers contains only one distinct element.\n\n Args:\n input_list: A list of numbers.\n\n Returns:\n True if the list contains only one distinct element, False otherwise.\n \"\"\"\n return len(set(input_list)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(nums):\n \"\"\"\n Checks whether a list of numbers contains only one distinct element.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n True if the list contains only one distinct element, False otherwise.\n \"\"\"\n return len(set(nums)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(lst):\n \"\"\"\n Checks if a list contains only one distinct element.\n\n Args:\n lst: A list of numbers.\n\n Returns:\n True if the list contains only one distinct element, False otherwise.\n \"\"\"\n\n return len(set(lst)) == 1", "matching_cluster_idx": 6}]}, "Mbpp/764": {"dps": 88.88888888888889, "dps_norm": 50.0, "pass@1": 100.0, "profiled": [{"solution": "def number_ctr(str1):\n \"\"\"\n Counts the number of digits in a given string.\n\n Args:\n str1: The input string.\n\n Returns:\n The number of digits in the string.\n \"\"\"\n count = 0\n for char in str1:\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(str1):\n \"\"\"\n Counts the number of digits in a given string.\n\n Args:\n str1: The string to check.\n\n Returns:\n The number of digits in the string.\n \"\"\"\n count = 0\n for char in str1:\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(text):\n \"\"\"\n Counts the number of digits in a given string.\n\n Args:\n text: The string to analyze.\n\n Returns:\n The number of digits in the string.\n \"\"\"\n count = 0\n for char in text:\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(string):\n \"\"\"Counts the number of digits in a given string.\n\n Args:\n string: The string to analyze.\n\n Returns:\n The number of digits in the string.\n \"\"\"\n count = 0\n for char in string:\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(input_string):\n \"\"\"Counts the number of digits in a given string.\n\n Args:\n input_string: The string to analyze.\n\n Returns:\n The number of digits found in the string.\n \"\"\"\n count = 0\n for char in input_string:\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(text):\n \"\"\"\n Counts the number of digits in a given string.\n\n Args:\n text: The input string.\n\n Returns:\n The number of digits in the string.\n \"\"\"\n count = 0\n for char in text:\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(text):\n \"\"\"\n Counts the number of digits in a given string.\n \n Args:\n text (str): The string to analyze.\n\n Returns:\n int: The count of digits in the string.\n \"\"\"\n return sum(1 for char in text if char.isdigit())", "matching_cluster_idx": 2}, {"solution": "def number_ctr(string):\n \"\"\"\n Counts the number of digits in a given string.\n\n Args:\n string: The input string.\n\n Returns:\n The number of digits in the string.\n \"\"\"\n\n count = 0\n for char in string:\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(string):\n \"\"\"\n Counts the number of digits in a given string.\n\n Args:\n string: The input string to be analyzed.\n\n Returns:\n The number of digits present in the string.\n \"\"\"\n count = 0\n for char in string:\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(str1):\n \"\"\"\n This function counts the number of digits in a given string.\n\n Args:\n str1: The input string to be checked.\n\n Returns:\n The number of digits present in the string.\n \"\"\"\n count = 0\n for char in str1:\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(string):\n \"\"\"\n Counts the number of digits in a given string.\n Args:\n string: The string to search for digits.\n\n Returns:\n The number of digits in the string.\n \"\"\"\n count = 0\n for char in string:\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(text):\n \"\"\"\n Counts the number of digits in a given string.\n\n Args:\n text: The string to analyze.\n\n Returns:\n The number of digits found in the string.\n \"\"\"\n return sum(c.isdigit() for c in text)", "matching_cluster_idx": 2}, {"solution": "def number_ctr(string):\n \"\"\"\n Counts the number of digits in a given string.\n\n Args:\n string: The string to search for digits in.\n\n Returns:\n The number of digits in the string.\n \"\"\"\n count = 0\n for char in string:\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(text):\n \"\"\"\n This function counts the number of digits in a given string.\n\n Args:\n text: The string to analyze.\n\n Returns:\n The number of digits in the string.\n \"\"\"\n count = 0\n for char in text:\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(input_string):\n \"\"\"\n Counts the number of digits in a given string.\n\n Args:\n input_string: The string to count digits in.\n\n Returns:\n The number of digits in the string.\n \"\"\"\n count = 0\n for char in input_string:\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(text):\n \"\"\"\n This function counts the number of digits in a given string.\n\n Args:\n text: The input string.\n\n Returns:\n The number of digits in the string.\n \"\"\"\n\n count = 0\n for char in text:\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s: str) -> int:\n \"\"\"\n Write a python function to count number of digits in a given string.\n assert number_ctr('program2bedone') == 1\n \"\"\"\n count = 0\n for char in s:\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n \"\"\"Counts the number of digits in a given string.\n\n Args:\n s: The input string.\n\n Returns:\n The number of digits in the string.\n \"\"\"\n count = 0\n for char in s:\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(str1):\n \"\"\"\n This function counts the number of digits in a given string.\n\n Args:\n str1: The input string.\n\n Returns:\n The number of digits in the string.\n \"\"\"\n count = 0\n for char in str1:\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(string):\n \"\"\"Counts the number of digits in a given string.\n\n Args:\n string: The string to count digits in.\n\n Returns:\n The number of digits in the string.\n \"\"\"\n count = 0\n for char in string:\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}]}, "Mbpp/766": {"dps": 71.54205607476635, "dps_norm": 60.833333333333336, "pass@1": 100.0, "profiled": [{"solution": "def pair_wise(lst):\n \"\"\"\n This function returns a list of all pairs of consecutive items in a given list.\n\n Args:\n lst: A list of any data type.\n\n Returns:\n A list of tuples, where each tuple contains a pair of consecutive items from the input list.\n \"\"\"\n return [(lst[i], lst[i+1]) for i in range(len(lst) - 1)]", "matching_cluster_idx": 2}, {"solution": "def pair_wise(lst):\n \"\"\"\n Returns a list of all pairs of consecutive items in a given list.\n\n Args:\n lst: The input list.\n\n Returns:\n A list of tuples, where each tuple contains a pair of consecutive items from the input list.\n \"\"\"\n return [(lst[i], lst[i+1]) for i in range(len(lst)-1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n \"\"\"\n Returns a list of all pairs of consecutive items in a given list.\n\n Args:\n lst: A list of items.\n\n Returns:\n A list of tuples, where each tuple contains a pair of consecutive items from the input list.\n \"\"\"\n return [(lst[i], lst[i+1]) for i in range(len(lst)-1)]", "matching_cluster_idx": 2}, {"solution": "def pair_wise(lst):\n \"\"\"\n Returns a list of all pairs of consecutive items in a given list.\n For example:\n pair_wise([1,1,2,3,3,4,4,5])==[(1, 1), (1, 2), (2, 3), (3, 3), (3, 4), (4, 4), (4, 5)]\n \"\"\"\n return [(lst[i], lst[i+1]) for i in range(len(lst)-1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n \"\"\"\n Returns a list of all pairs of consecutive items in a given list.\n\n Args:\n lst: A list of items.\n\n Returns:\n A list of tuples, where each tuple represents a pair of consecutive items.\n \"\"\"\n return [(lst[i], lst[i+1]) for i in range(len(lst) - 1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n \"\"\"\n Returns a list of all pairs of consecutive items in a given list.\n\n Args:\n lst: A list of items.\n\n Returns:\n A list of tuples, where each tuple contains a pair of consecutive items from the input list.\n \"\"\"\n return [(lst[i], lst[i+1]) for i in range(len(lst) - 1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n \"\"\"\n Returns a list of all pairs of consecutive items in a given list.\n\n Args:\n lst: The input list.\n\n Returns:\n A list of tuples, where each tuple contains a pair of consecutive items from the input list.\n \"\"\"\n return [(lst[i], lst[i+1]) for i in range(len(lst)-1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n \"\"\"\n Returns a list of all pairs of consecutive items in a given list.\n\n For example:\n pair_wise([1,1,2,3,3,4,4,5])==[(1, 1), (1, 2), (2, 3), (3, 3), (3, 4), (4, 4), (4, 5)]\n \"\"\"\n\n return [(lst[i], lst[i+1]) for i in range(len(lst)-1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n \"\"\"\n Returns a list of all pairs of consecutive items in a given list.\n\n Args:\n lst: A list of items.\n\n Returns:\n A list of tuples, where each tuple contains a pair of consecutive items from the input list.\n \"\"\"\n return [(lst[i], lst[i+1]) for i in range(len(lst) - 1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n \"\"\"\n Returns a list of all pairs of consecutive items in a given list.\n\n Args:\n lst: A list of items.\n\n Returns:\n A list of tuples, where each tuple contains a pair of consecutive items from the input list.\n \"\"\"\n return [(lst[i], lst[i+1]) for i in range(len(lst)-1)]", "matching_cluster_idx": 2}, {"solution": "def pair_wise(lst):\n \"\"\"\n Return a list of all pairs of consecutive items in a given list.\n \"\"\"\n return [(lst[i], lst[i+1]) for i in range(len(lst)-1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n \"\"\"\n Returns a list of all pairs of consecutive items in a given list.\n\n Args:\n lst: The input list.\n\n Returns:\n A list of tuples, where each tuple represents a pair of consecutive items.\n \"\"\"\n return [(lst[i], lst[i+1]) for i in range(len(lst)-1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n \"\"\"\n Returns a list of all pairs of consecutive items in a given list.\n\n Args:\n lst: The input list.\n\n Returns:\n A list of tuples, where each tuple contains a pair of consecutive items from the input list.\n \"\"\"\n return [(lst[i], lst[i+1]) for i in range(len(lst)-1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n \"\"\"\n This function returns a list of all pairs of consecutive items in a given list.\n\n Args:\n lst: A list of any type.\n\n Returns:\n A list of tuples, where each tuple contains two consecutive items from the input list.\n \"\"\"\n return [(lst[i], lst[i+1]) for i in range(len(lst)-1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n \"\"\"\n This function takes a list and returns a list of all pairs of consecutive items in the list.\n \"\"\"\n return [(lst[i], lst[i+1]) for i in range(len(lst)-1)]", "matching_cluster_idx": 2}, {"solution": "def pair_wise(lst):\n \"\"\"\n Return a list of all pairs of consecutive items in a given list.\n\n Args:\n lst: The input list.\n\n Returns:\n A list of tuples, where each tuple contains two consecutive items from the input list.\n \"\"\"\n return [(lst[i], lst[i+1]) for i in range(len(lst)-1)]", "matching_cluster_idx": 2}, {"solution": "def pair_wise(lst):\n \"\"\"\n This function returns a list of all pairs of consecutive items in a given list.\n\n Args:\n lst: A list of items.\n\n Returns:\n A list of tuples, where each tuple contains a pair of consecutive items from the input list.\n \"\"\"\n return [(lst[i], lst[i+1]) for i in range(len(lst)-1)]", "matching_cluster_idx": 2}, {"solution": "def pair_wise(lst):\n \"\"\"\n Returns a list of all pairs of consecutive items in a given list.\n\n Args:\n lst: A list of elements.\n\n Returns:\n A list of tuples, where each tuple contains a pair of consecutive elements \n from the input list.\n \"\"\"\n return [(lst[i], lst[i+1]) for i in range(len(lst) - 1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n \"\"\"\n Return a list of all pairs of consecutive items in a given list.\n\n Args:\n lst: A list of elements.\n\n Returns:\n A list of tuples, where each tuple contains a pair of consecutive elements from the input list.\n \"\"\"\n return [(lst[i], lst[i+1]) for i in range(len(lst)-1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n \"\"\"Returns a list of all pairs of consecutive items in a given list.\n\n Args:\n lst: A list of items.\n\n Returns:\n A list of tuples, where each tuple contains a pair of consecutive items from the input list.\n \"\"\"\n return [(lst[i], lst[i+1]) for i in range(len(lst)-1)]", "matching_cluster_idx": 2}]}, "Mbpp/775": {"dps": 94.39999999999999, "dps_norm": 71.42857142857143, "pass@1": 100.0, "profiled": [{"solution": "def odd_position(nums):\n \"\"\"\n Checks whether every odd index contains odd numbers of a given list.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n True if every odd index contains an odd number, False otherwise.\n \"\"\"\n for i in range(1, len(nums), 2):\n if nums[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(nums):\n \"\"\"\n Checks whether every odd index contains odd numbers in a given list.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n True if every odd index contains an odd number, False otherwise.\n \"\"\"\n for i in range(1, len(nums), 2):\n if nums[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(nums):\n \"\"\"\n Checks whether every odd index contains odd numbers in a given list.\n\n Args:\n nums: A list of integers.\n\n Returns:\n True if every odd index contains an odd number, False otherwise.\n \"\"\"\n for i in range(1, len(nums), 2):\n if nums[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(nums):\n \"\"\"\n Checks whether every odd index contains odd numbers of a given list.\n\n Args:\n nums: A list of integers.\n\n Returns:\n True if every odd index contains an odd number, False otherwise.\n \"\"\"\n for i in range(1, len(nums), 2):\n if nums[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(nums):\n \"\"\"\n Checks whether every odd index contains an odd number in a given list.\n\n Args:\n nums: A list of integers.\n\n Returns:\n True if every odd index contains an odd number, False otherwise.\n \"\"\"\n for i in range(1, len(nums), 2):\n if nums[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(nums):\n \"\"\"\n Checks if every odd index in a list contains an odd number.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n True if every odd index contains an odd number, False otherwise.\n \"\"\"\n for i in range(1, len(nums), 2):\n if nums[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(nums):\n \"\"\"\n Checks whether every odd index in a list contains an odd number.\n\n Args:\n nums: A list of integers.\n\n Returns:\n True if every odd index contains an odd number, False otherwise.\n \"\"\"\n\n for i in range(1, len(nums), 2):\n if nums[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(nums):\n \"\"\"\n This function checks if every odd index in a list contains an odd number.\n\n Args:\n nums: A list of integers.\n\n Returns:\n True if every odd index contains an odd number, False otherwise.\n \"\"\"\n\n for i in range(1, len(nums), 2):\n if nums[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n \"\"\"\n Checks whether every odd index contains odd numbers of a given list.\n \n Args:\n lst: A list of integers.\n\n Returns:\n True if every odd index contains an odd number, False otherwise.\n \"\"\"\n for i in range(1, len(lst), 2):\n if lst[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(nums):\n \"\"\"\n Checks whether every odd index contains odd numbers of a given list.\n\n Args:\n nums: A list of integers.\n\n Returns:\n True if every odd index contains an odd number, False otherwise.\n \"\"\"\n for i in range(1, len(nums), 2):\n if nums[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(nums):\n \"\"\"Checks if every odd index in a list contains an odd number.\n\n Args:\n nums: A list of integers.\n\n Returns:\n True if every odd index contains an odd number, False otherwise.\n \"\"\"\n for i in range(1, len(nums), 2):\n if nums[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n \"\"\"\n Checks whether every odd index contains an odd number in a given list.\n\n Args:\n lst: A list of integers.\n\n Returns:\n True if every odd index contains an odd number, False otherwise.\n \"\"\"\n for i in range(1, len(lst), 2): # Iterate through odd indices\n if lst[i] % 2 == 0: # Check if the number at the odd index is even\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(nums):\n \"\"\"\n Check whether every odd index contains odd numbers in a given list.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n True if every odd index contains an odd number, False otherwise.\n \"\"\"\n\n for i in range(1, len(nums), 2): # Iterate through odd indices\n if nums[i] % 2 == 0:\n return False \n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(nums):\n \"\"\"\n Checks whether every odd index contains odd numbers of a given list.\n\n Args:\n nums: A list of integers.\n\n Returns:\n True if every odd index contains an odd number, False otherwise.\n \"\"\"\n for i in range(1, len(nums), 2):\n if nums[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(nums):\n \"\"\"Checks if every odd index in a list contains an odd number.\n\n Args:\n nums: A list of integers.\n\n Returns:\n True if every odd index contains an odd number, False otherwise.\n \"\"\"\n for i in range(1, len(nums), 2):\n if nums[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(nums):\n \"\"\"\n Checks whether every odd index contains an odd number in a given list.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n True if every odd index contains an odd number, False otherwise.\n \"\"\"\n for i in range(1, len(nums), 2):\n if nums[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(nums):\n \"\"\"\n Checks if every odd index in a list contains an odd number.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n True if every odd index contains an odd number, False otherwise.\n \"\"\"\n for i in range(1, len(nums), 2):\n if nums[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(numbers):\n \"\"\"\n Checks whether every odd index in a list contains an odd number.\n\n Args:\n numbers: A list of integers.\n\n Returns:\n True if every odd index contains an odd number, False otherwise.\n \"\"\"\n\n for i in range(1, len(numbers), 2):\n if numbers[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(numbers):\n \"\"\"Checks whether every odd index contains odd numbers in a list.\n\n Args:\n numbers: A list of numbers.\n\n Returns:\n True if every odd index contains an odd number, False otherwise.\n \"\"\"\n for i in range(1, len(numbers), 2):\n if numbers[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(nums):\n \"\"\"\n Checks if every odd index in a list contains an odd number.\n\n Args:\n nums: A list of integers.\n\n Returns:\n True if every odd index contains an odd number, False otherwise.\n \"\"\"\n for i in range(1, len(nums), 2):\n if nums[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}]}, "Mbpp/777": {"dps": 57.142857142857146, "dps_norm": 68.88888888888889, "pass@1": 88.0, "profiled": [{"solution": "def find_sum(nums):\n \"\"\"Finds the sum of non-repeated elements in a given list.\n\n Args:\n nums: A list of integers.\n\n Returns:\n The sum of the non-repeated elements in the list.\n \"\"\"\n seen = set()\n total = 0\n for num in nums:\n if num not in seen:\n total += num\n seen.add(num)\n return total", "matching_cluster_idx": 4}, {"solution": "def find_sum(numbers):\n \"\"\"\n This function calculates the sum of non-repeated elements in a list.\n\n Args:\n numbers: A list of numbers.\n\n Returns:\n The sum of non-repeated elements in the list.\n \"\"\"\n unique_numbers = set(numbers) \n return sum(unique_numbers)", "matching_cluster_idx": 8}, {"solution": "def find_sum(nums):\n \"\"\"\n Finds the sum of non-repeated elements in a given list.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n The sum of non-repeated elements in the list.\n \"\"\"\n unique_nums = set(nums) \n return sum(unique_nums)", "matching_cluster_idx": 8}, {"solution": "def find_sum(numbers):\n \"\"\"\n This function calculates the sum of non-repeated elements in a list.\n\n Args:\n numbers: A list of numbers.\n\n Returns:\n The sum of the non-repeated elements in the list.\n \"\"\"\n unique_numbers = set(numbers) # Create a set to store unique numbers\n sum_of_uniques = sum(unique_numbers) \n return sum_of_uniques", "matching_cluster_idx": 8}, {"solution": "def find_sum(nums):\n \"\"\"\n Finds the sum of non-repeated elements in a given list.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n The sum of non-repeated elements in the list.\n \"\"\"\n seen = set()\n total = 0\n for num in nums:\n if num not in seen:\n total += num\n seen.add(num)\n return total", "matching_cluster_idx": 4}, {"solution": "def find_sum(data):\n \"\"\"\n Finds the sum of non-repeated elements in a given list.\n\n Args:\n data (list): The input list of numbers.\n\n Returns:\n int: The sum of non-repeated elements.\n \"\"\"\n seen = set()\n total = 0\n for num in data:\n if num not in seen:\n total += num\n seen.add(num)\n return total", "matching_cluster_idx": 4}, {"solution": "def find_sum(data: list) -> int:\n \"\"\"\n Find the sum of non-repeated elements in a given list.\n\n Args:\n data (list): The input list of numbers.\n\n Returns:\n int: The sum of non-repeated elements.\n \"\"\"\n seen = set()\n sum_of_unique = 0\n for num in data:\n if num not in seen:\n sum_of_unique += num\n seen.add(num)\n return sum_of_unique", "matching_cluster_idx": 4}, {"solution": "def find_sum(nums):\n \"\"\"\n Finds the sum of non-repeated elements in a given list.\n\n Args:\n nums (list): A list of numbers.\n\n Returns:\n int: The sum of non-repeated elements in the list.\n \"\"\"\n\n seen = set()\n total = 0\n for num in nums:\n if num not in seen:\n total += num\n seen.add(num)\n return total", "matching_cluster_idx": 4}, {"solution": "def find_sum(nums):\n \"\"\"\n Finds the sum of non-repeated elements in a list.\n\n Args:\n nums: A list of integers.\n\n Returns:\n The sum of the non-repeated elements in the list.\n \"\"\"\n\n seen = set()\n total = 0\n for num in nums:\n if num not in seen:\n total += num\n seen.add(num)\n return total", "matching_cluster_idx": 4}, {"solution": "def find_sum(nums):\n \"\"\"\n Find the sum of non-repeated elements in a given list.\n\n Args:\n nums: A list of integers.\n\n Returns:\n The sum of the non-repeated elements in the list.\n \"\"\"\n seen = set()\n total = 0\n for num in nums:\n if num not in seen:\n total += num\n seen.add(num)\n return total", "matching_cluster_idx": 4}, {"solution": "def find_sum(nums):\n \"\"\"\n Find the sum of non-repeated elements in a given list.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n The sum of non-repeated elements in the list.\n \"\"\"\n seen = set()\n sum = 0\n for num in nums:\n if num not in seen:\n sum += num\n seen.add(num)\n return sum", "matching_cluster_idx": 4}, {"solution": "def find_sum(nums):\n \"\"\"\n This function finds the sum of non-repeated elements in a given list.\n\n Args:\n nums: A list of integers.\n\n Returns:\n The sum of non-repeated elements in the list.\n \"\"\"\n unique_nums = set(nums)\n return sum(unique_nums)", "matching_cluster_idx": 8}, {"solution": "def find_sum(numbers):\n \"\"\"\n Finds the sum of non-repeated elements in a given list.\n\n Args:\n numbers: A list of integers.\n\n Returns:\n The sum of the non-repeated elements in the list.\n \"\"\"\n seen = set()\n sum = 0\n for num in numbers:\n if num not in seen:\n sum += num\n seen.add(num)\n return sum", "matching_cluster_idx": 4}, {"solution": "def find_sum(data):\n \"\"\"\n Finds the sum of non-repeated elements in a given list.\n\n Args:\n data: A list of integers.\n\n Returns:\n The sum of the non-repeated elements in the list.\n \"\"\"\n seen = set()\n sum = 0\n for item in data:\n if item not in seen:\n sum += item\n seen.add(item)\n return sum", "matching_cluster_idx": 4}, {"solution": "def find_sum(nums):\n \"\"\"\n This function finds the sum of non-repeated elements in a given list.\n\n Args:\n nums: A list of integers.\n\n Returns:\n The sum of non-repeated elements in the list.\n \"\"\"\n unique_nums = set(nums)\n return sum(unique_nums)", "matching_cluster_idx": 8}, {"solution": "def find_sum(numbers):\n \"\"\"Finds the sum of non-repeated elements in a given list.\n\n Args:\n numbers: A list of numbers.\n\n Returns:\n The sum of non-repeated elements in the list.\n \"\"\"\n seen = set()\n sum = 0\n for number in numbers:\n if number not in seen:\n sum += number\n seen.add(number)\n return sum", "matching_cluster_idx": 4}, {"solution": "def find_sum(nums):\n \"\"\"\n Finds the sum of non-repeated elements in a given list.\n\n Args:\n nums: A list of integers.\n\n Returns:\n The sum of non-repeated elements in the list.\n \"\"\"\n\n seen = set()\n total = 0\n for num in nums:\n if num not in seen:\n total += num\n seen.add(num)\n return total", "matching_cluster_idx": 4}, {"solution": "def find_sum(numbers):\n \"\"\"Calculates the sum of non-repeated elements in a list.\n\n Args:\n numbers: A list of numbers.\n\n Returns:\n The sum of the non-repeated elements in the list.\n \"\"\"\n\n unique_numbers = set(numbers) # Use a set to efficiently find unique elements\n return sum(unique_numbers)", "matching_cluster_idx": 8}, {"solution": "def find_sum(nums):\n \"\"\"\n Finds the sum of non-repeated elements in a given list.\n\n Args:\n nums: A list of integers.\n\n Returns:\n The sum of the non-repeated elements in the list.\n \"\"\"\n seen = set()\n sum = 0\n for num in nums:\n if num not in seen:\n seen.add(num)\n sum += num\n return sum", "matching_cluster_idx": 4}, {"solution": "def find_sum(nums):\n \"\"\"Finds the sum of non-repeated elements in a list.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n The sum of the non-repeated elements in the list.\n \"\"\"\n seen = set()\n sum = 0\n for num in nums:\n if num not in seen:\n sum += num\n seen.add(num)\n return sum", "matching_cluster_idx": 4}]}, "Mbpp/781": {"dps": 88.26771653543307, "dps_norm": 47.0, "pass@1": 48.0, "profiled": [{"solution": "def count_divisors(num):\n \"\"\"\n Calculates the number of divisors of a given integer.\n\n Args:\n num: The integer to check for divisors.\n\n Returns:\n True if the count of divisors is even, False otherwise.\n \"\"\"\n count = 0\n for i in range(1, num + 1):\n if num % i == 0:\n count += 1\n return count % 2 == 0", "matching_cluster_idx": 1}, {"solution": "def count_divisors(n):\n \"\"\"Counts the number of divisors of a given integer.\n \n Args:\n n: The integer to check.\n\n Returns:\n True if the count of divisors is even, False otherwise.\n \"\"\"\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count % 2 == 0", "matching_cluster_idx": 1}, {"solution": "def count_divisors(n):\n \"\"\"\n This function checks whether the count of divisors of a given number is even.\n\n Args:\n n: An integer.\n\n Returns:\n True if the count of divisors is even, False otherwise.\n \"\"\"\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n if i * i == n:\n count += 1\n else:\n count += 2\n return count % 2 == 0", "matching_cluster_idx": 3}, {"solution": "def count_divisors(n):\n \"\"\"Counts the number of divisors of a given number and checks if it's even.\n\n Args:\n n: An integer.\n\n Returns:\n True if the count of divisors of n is even, False otherwise.\n \"\"\"\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count % 2 == 0", "matching_cluster_idx": 1}, {"solution": "import math\ndef count_divisors(num):\n \"\"\"\n Checks whether the count of divisors of a number is even.\n\n Args:\n num: An integer to check.\n\n Returns:\n True if the count of divisors is even, False otherwise.\n \"\"\"\n count = 0\n for i in range(1, int(math.sqrt(num)) + 1):\n if num % i == 0:\n if num / i == i:\n count += 1\n else:\n count += 2\n return count % 2 == 0", "matching_cluster_idx": 4}, {"solution": "def count_divisors(num):\n \"\"\"\n Counts the number of divisors of a given number and checks if it's even.\n\n Args:\n num: The number to check.\n\n Returns:\n True if the count of divisors is even, False otherwise.\n \"\"\"\n count = 0\n for i in range(1, num + 1):\n if num % i == 0:\n count += 1\n return count % 2 == 0", "matching_cluster_idx": 1}, {"solution": "def count_divisors(n):\n \"\"\"\n Counts the number of divisors of a given number n and checks if it's even.\n\n Args:\n n: An integer.\n\n Returns:\n True if the count of divisors is even, False otherwise.\n \"\"\"\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count % 2 == 0", "matching_cluster_idx": 1}, {"solution": "def count_divisors(n):\n \"\"\"\n Counts the number of divisors of a given positive integer.\n\n Args:\n n: A positive integer.\n\n Returns:\n True if the count of divisors is even, False otherwise.\n \"\"\"\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count % 2 == 0", "matching_cluster_idx": 1}, {"solution": "def count_divisors(num):\n \"\"\"\n This function counts the divisors of a number and returns True if the count is even, \n otherwise False.\n\n Args:\n num: An integer.\n\n Returns:\n True if the count of divisors is even, False otherwise.\n \"\"\"\n count = 0\n for i in range(1, num + 1):\n if num % i == 0:\n count += 1\n return count % 2 == 0", "matching_cluster_idx": 1}, {"solution": "def count_divisors(num):\n \"\"\"Counts the number of divisors of a given number and checks if the count is even.\n\n Args:\n num: The number to check.\n\n Returns:\n True if the count of divisors is even, False otherwise.\n \"\"\"\n count = 0\n for i in range(1, num + 1):\n if num % i == 0:\n count += 1\n return count % 2 == 0", "matching_cluster_idx": 1}, {"solution": "def count_divisors(n):\n \"\"\"\n This function checks if the count of divisors of a given number is even.\n\n Args:\n n: An integer.\n\n Returns:\n True if the count of divisors of n is even, False otherwise.\n \"\"\"\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count % 2 == 0", "matching_cluster_idx": 1}, {"solution": "def count_divisors(n):\n \"\"\"\n This function counts the number of divisors of a given integer.\n\n Args:\n n: An integer.\n\n Returns:\n True if the count of divisors is even, False otherwise.\n \"\"\"\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count % 2 == 0", "matching_cluster_idx": 1}, {"solution": "def count_divisors(n):\n \"\"\"\n Checks whether the count of divisors of a number is even.\n \n Args:\n n: An integer.\n \n Returns:\n True if the number of divisors of n is even, False otherwise.\n \"\"\"\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count % 2 == 0", "matching_cluster_idx": 1}, {"solution": "def count_divisors(num):\n \"\"\"\n This function checks whether the count of divisors of a given number is even.\n\n Args:\n num: An integer.\n\n Returns:\n True if the count of divisors is even, False otherwise.\n \"\"\"\n count = 0\n for i in range(1, num + 1):\n if num % i == 0:\n count += 1\n return count % 2 == 0", "matching_cluster_idx": 1}, {"solution": "def count_divisors(n):\n \"\"\"Checks whether the count of divisors of a given number is even.\"\"\"\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count % 2 == 0", "matching_cluster_idx": 1}, {"solution": "def count_divisors(num):\n \"\"\"\n Checks whether the count of divisors of a number is even.\n\n Args:\n num: An integer.\n\n Returns:\n True if the count of divisors is even, False otherwise.\n \"\"\"\n count = 0\n for i in range(1, num + 1):\n if num % i == 0:\n count += 1\n return count % 2 == 0", "matching_cluster_idx": 1}, {"solution": "def count_divisors(num):\n \"\"\"\n Counts the number of divisors for a given positive integer.\n\n Args:\n num: The positive integer to check.\n\n Returns:\n True if the count of divisors is even, False otherwise.\n \"\"\"\n count = 0\n for i in range(1, num + 1):\n if num % i == 0:\n count += 1\n return count % 2 == 0", "matching_cluster_idx": 1}, {"solution": "def count_divisors(num):\n \"\"\"Counts the number of divisors a number has and returns True if even, False otherwise.\n\n Args:\n num: The integer to check.\n\n Returns:\n True if the number of divisors is even, False otherwise.\n \"\"\"\n count = 0\n for i in range(1, num + 1):\n if num % i == 0:\n count += 1\n return count % 2 == 0", "matching_cluster_idx": 1}, {"solution": "def count_divisors(n):\n \"\"\"\n Counts the number of divisors of a positive integer n and checks if the count is even.\n\n Args:\n n: A positive integer.\n\n Returns:\n True if the number of divisors of n is even, False otherwise.\n \"\"\"\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n if i * i == n:\n count += 1\n else:\n count += 2\n return count % 2 == 0", "matching_cluster_idx": 3}, {"solution": "def count_divisors(num):\n \"\"\"\n Counts the number of divisors of a given number and checks if the count is even.\n\n Args:\n num: The number to check.\n\n Returns:\n True if the count of divisors is even, False otherwise.\n \"\"\"\n count = 0\n for i in range(1, num + 1):\n if num % i == 0:\n count += 1\n return count % 2 == 0", "matching_cluster_idx": 1}]}, "Mbpp/800": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 80.0, "profiled": [{"solution": "def remove_all_spaces(text):\n \"\"\"Removes all whitespaces from a string.\n \n Args:\n text: The string to remove whitespaces from.\n\n Returns:\n The string with all whitespaces removed.\n \"\"\"\n return text.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(text):\n \"\"\"\n This function removes all whitespace characters from a given string.\n\n Args:\n text: The input string\n\n Returns:\n A string with all whitespace characters removed.\n \"\"\"\n\n return text.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(text):\n \"\"\"Removes all whitespaces from a string.\n\n Args:\n text: The input string.\n\n Returns:\n The string with all whitespaces removed.\n \"\"\"\n return text.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(text: str) -> str:\n \"\"\"\n Write a function to remove all whitespaces from a string.\n assert remove_all_spaces('python program')==('pythonprogram')\n \"\"\"\n return text.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(text):\n \"\"\"\n Removes all whitespaces from a string.\n\n Args:\n text: The string to remove spaces from.\n\n Returns:\n The string with all whitespaces removed.\n \"\"\"\n return text.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(text):\n \"\"\"\n This function removes all whitespaces from a given string.\n\n Args:\n text: The input string.\n\n Returns:\n The string with all whitespaces removed.\n \"\"\"\n return text.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(text):\n \"\"\"Removes all whitespaces from a string.\n\n Args:\n text: The input string.\n\n Returns:\n The string with all whitespaces removed.\n \"\"\"\n return text.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(text):\n \"\"\"Removes all whitespace characters from a string.\n\n Args:\n text: The string to remove whitespaces from.\n\n Returns:\n The string with all whitespace characters removed.\n \"\"\"\n return text.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(text):\n \"\"\"\n Removes all whitespace characters from a string.\n\n Args:\n text: The string to remove whitespace from.\n\n Returns:\n The string with all whitespace characters removed.\n \"\"\"\n return text.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(text):\n \"\"\"Removes all whitespaces from a string.\n\n Args:\n text: The input string.\n\n Returns:\n The string with all whitespaces removed.\n \"\"\"\n return text.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(text):\n \"\"\"Removes all whitespaces from a string.\n \n Args:\n text: The string to remove spaces from.\n\n Returns:\n A new string with all spaces removed.\n \"\"\"\n return text.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(text):\n \"\"\"Removes all whitespaces from a string.\n\n Args:\n text: The input string.\n\n Returns:\n The string with all whitespaces removed.\n \"\"\"\n return text.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(text):\n \"\"\"\n This function removes all whitespaces from a given string.\n\n Args:\n text: The string to remove whitespaces from.\n\n Returns:\n The string with all whitespaces removed.\n \"\"\"\n return text.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(text):\n \"\"\"\n Removes all whitespace characters from a string.\n\n Args:\n text: The input string.\n\n Returns:\n The string with all whitespace characters removed.\n \"\"\"\n return text.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(text):\n \"\"\"Removes all whitespaces from a string.\n\n Args:\n text: The input string.\n\n Returns:\n The string with all whitespaces removed.\n \"\"\"\n return text.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(text):\n \"\"\"\n This function removes all whitespaces from a string.\n\n Args:\n text: The string to remove whitespaces from.\n\n Returns:\n The string with all whitespaces removed.\n \"\"\"\n return text.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(text):\n \"\"\"\n Removes all whitespace characters from a string.\n\n Args:\n text: The input string.\n\n Returns:\n The string with all whitespace characters removed.\n \"\"\"\n return text.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(text: str) -> str:\n \"\"\"\n Write a function to remove all whitespaces from a string.\n\n Args:\n text: The input string.\n\n Returns:\n The string with all whitespaces removed.\n\n Examples:\n remove_all_spaces('python program') == 'pythonprogram'\n \"\"\"\n return text.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(text):\n \"\"\"\n This function removes all whitespaces from a string.\n\n Args:\n text: The string to remove whitespaces from.\n\n Returns:\n The string without any whitespace characters.\n \"\"\"\n return text.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(text):\n \"\"\"Removes all whitespaces from a string.\n\n Args:\n text: The string to remove whitespaces from.\n\n Returns:\n A string with all whitespace characters removed.\n \"\"\"\n return text.replace(\" \", \"\")", "matching_cluster_idx": 4}]}, "Mbpp/805": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def max_sum_list(list_of_lists):\n \"\"\"\n Finds the list with the maximum sum of elements within a list of lists.\n\n Args:\n list_of_lists: A list of lists, where each inner list contains numbers.\n\n Returns:\n The list with the highest sum of elements.\n \"\"\"\n max_sum = float('-inf')\n max_list = []\n for sublist in list_of_lists:\n current_sum = sum(sublist)\n if current_sum > max_sum:\n max_sum = current_sum\n max_list = sublist\n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(list_of_lists):\n \"\"\"\n This function finds the list within a list of lists that has the highest sum of elements.\n\n Args:\n list_of_lists: A list of lists, where each inner list contains numbers.\n\n Returns:\n The list with the highest sum of elements.\n \"\"\"\n\n max_sum = float('-inf')\n max_sum_list = []\n\n for inner_list in list_of_lists:\n current_sum = sum(inner_list)\n if current_sum > max_sum:\n max_sum = current_sum\n max_sum_list = inner_list\n\n return max_sum_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(list_of_lists):\n \"\"\"\n This function takes a list of lists and returns the list with the highest sum of elements.\n\n Args:\n list_of_lists: A list of lists containing numbers.\n\n Returns:\n The list with the highest sum of elements.\n \"\"\"\n max_sum = float('-inf') \n result_list = []\n for lst in list_of_lists:\n current_sum = sum(lst)\n if current_sum > max_sum:\n max_sum = current_sum\n result_list = lst\n return result_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(list_of_lists):\n \"\"\"\n This function returns the list in a list of lists whose sum of elements is the highest.\n\n Args:\n list_of_lists: A list of lists containing numbers.\n\n Returns:\n The list with the highest sum of elements.\n \"\"\"\n max_sum = float('-inf') # Initialize with negative infinity to ensure any sum is greater\n max_list = []\n for sublist in list_of_lists:\n current_sum = sum(sublist)\n if current_sum > max_sum:\n max_sum = current_sum\n max_list = sublist\n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(list_of_lists):\n \"\"\"\n Finds the list in a list of lists whose sum of elements is the highest.\n\n Args:\n list_of_lists: A list of lists of numbers.\n\n Returns:\n The list with the highest sum of elements.\n \"\"\"\n max_sum = float('-inf')\n max_list = []\n for sublist in list_of_lists:\n current_sum = sum(sublist)\n if current_sum > max_sum:\n max_sum = current_sum\n max_list = sublist\n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(list_of_lists):\n \"\"\"Returns the list in a list of lists whose sum of elements is the highest.\n\n For example:\n max_sum_list([[1,2,3], [4,5,6], [10,11,12], [7,8,9]]) == [10, 11, 12]\n \"\"\"\n max_list = list_of_lists[0]\n max_sum = sum(max_list)\n\n for lst in list_of_lists:\n current_sum = sum(lst)\n if current_sum > max_sum:\n max_sum = current_sum\n max_list = lst\n \n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n \"\"\"\n Finds the list in a list of lists whose sum of elements is the highest.\n\n Args:\n lists: A list of lists of numbers.\n\n Returns:\n The list with the highest sum of elements.\n \"\"\"\n max_sum = float('-inf')\n max_list = []\n for lst in lists:\n current_sum = sum(lst)\n if current_sum > max_sum:\n max_sum = current_sum\n max_list = lst\n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(list_of_lists):\n \"\"\"\n Finds the list in a list of lists whose sum of elements is the highest.\n\n Args:\n list_of_lists: A list of lists of numbers.\n\n Returns:\n The list with the highest sum of elements.\n \"\"\"\n\n max_list = list_of_lists[0] # Initialize with the first list\n max_sum = sum(max_list)\n\n for lst in list_of_lists:\n current_sum = sum(lst)\n if current_sum > max_sum:\n max_sum = current_sum\n max_list = lst\n\n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(list_of_lists):\n \"\"\"\n Returns the list in a list of lists whose sum of elements is the highest.\n\n Args:\n list_of_lists: A list of lists of numbers.\n\n Returns:\n The list with the highest sum of elements.\n \"\"\"\n max_sum = float('-inf') \n max_list = []\n for sublist in list_of_lists:\n current_sum = sum(sublist)\n if current_sum > max_sum:\n max_sum = current_sum\n max_list = sublist\n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n \"\"\"\n Finds the list with the highest sum of elements in a list of lists.\n\n Args:\n lists: A list of lists, where each inner list contains integers.\n\n Returns:\n The list with the highest sum of elements.\n \"\"\"\n max_sum = float('-inf')\n max_list = None\n for lst in lists:\n current_sum = sum(lst)\n if current_sum > max_sum:\n max_sum = current_sum\n max_list = lst\n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n \"\"\"Returns the list in a list of lists whose sum of elements is the highest.\n\n Args:\n lists: A list of lists of numbers.\n\n Returns:\n The list with the highest sum of elements.\n \"\"\"\n max_sum = float('-inf')\n max_list = []\n for lst in lists:\n current_sum = sum(lst)\n if current_sum > max_sum:\n max_sum = current_sum\n max_list = lst\n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(list_of_lists):\n \"\"\"\n Finds the list in a list of lists whose sum of elements is the highest.\n\n Args:\n list_of_lists: A list of lists containing numerical values.\n\n Returns:\n The list with the highest sum of elements.\n \"\"\"\n\n max_sum = float('-inf') \n max_list = []\n\n for lst in list_of_lists:\n current_sum = sum(lst)\n if current_sum > max_sum:\n max_sum = current_sum\n max_list = lst\n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(list_of_lists):\n \"\"\"\n Returns the list in a list of lists whose sum of elements is the highest.\n\n For example:\n max_sum_list([[1,2,3], [4,5,6], [10,11,12], [7,8,9]]) == [10, 11, 12]\n \"\"\"\n max_sum = float('-inf') \n result_list = []\n for inner_list in list_of_lists:\n current_sum = sum(inner_list)\n if current_sum > max_sum:\n max_sum = current_sum\n result_list = inner_list\n return result_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n \"\"\"\n Returns the list in a list of lists whose sum of elements is the highest.\n\n Args:\n lists: A list of lists.\n\n Returns:\n The list with the highest sum of elements.\n \"\"\"\n max_sum = float('-inf') \n max_list = []\n for lst in lists:\n current_sum = sum(lst)\n if current_sum > max_sum:\n max_sum = current_sum\n max_list = lst\n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(list_of_lists):\n \"\"\"\n Finds the list within a list of lists that has the highest sum of elements.\n\n Args:\n list_of_lists: A list of lists containing numerical values.\n\n Returns:\n The list with the highest sum of elements.\n \"\"\"\n max_sum = float('-inf') # Initialize with negative infinity\n max_list = []\n\n for lst in list_of_lists:\n current_sum = sum(lst)\n if current_sum > max_sum:\n max_sum = current_sum\n max_list = lst\n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(list_of_lists):\n \"\"\"\n Finds the list in a list of lists with the highest sum of elements.\n\n Args:\n list_of_lists: A list of lists of numbers.\n\n Returns:\n The list with the highest sum of elements.\n \"\"\"\n max_sum = float('-inf')\n max_list = None\n for inner_list in list_of_lists:\n current_sum = sum(inner_list)\n if current_sum > max_sum:\n max_sum = current_sum\n max_list = inner_list\n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(list_of_lists):\n \"\"\"\n This function takes a list of lists and returns the list with the highest sum of elements.\n\n Args:\n list_of_lists: A list of lists of numbers.\n\n Returns:\n The list with the highest sum of elements.\n \"\"\"\n max_sum = float('-inf')\n max_list = []\n for sublist in list_of_lists:\n current_sum = sum(sublist)\n if current_sum > max_sum:\n max_sum = current_sum\n max_list = sublist\n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(list_of_lists):\n \"\"\"\n Finds the list in a list of lists whose sum of elements is the highest.\n\n Args:\n list_of_lists: A list of lists of numbers.\n\n Returns:\n The list with the highest sum of elements.\n \"\"\"\n max_sum = float('-inf')\n max_list = []\n for lst in list_of_lists:\n current_sum = sum(lst)\n if current_sum > max_sum:\n max_sum = current_sum\n max_list = lst\n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(list_of_lists):\n \"\"\"\n Returns the list in a list of lists whose sum of elements is the highest.\n\n Args:\n list_of_lists: A list of lists of numbers.\n\n Returns:\n A list of numbers, the list with the highest sum.\n \"\"\"\n max_sum = float('-inf')\n max_list = None\n\n for lst in list_of_lists:\n current_sum = sum(lst)\n if current_sum > max_sum:\n max_sum = current_sum\n max_list = lst\n\n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lst_of_lst):\n \"\"\"\n Finds the list in a list of lists whose sum of elements is the highest.\n\n Args:\n lst_of_lst: A list of lists of numbers.\n\n Returns:\n The list with the highest sum of elements.\n \"\"\"\n max_sum = float('-inf') \n max_list = []\n\n for lst in lst_of_lst:\n current_sum = sum(lst)\n if current_sum > max_sum:\n max_sum = current_sum\n max_list = lst\n\n return max_list", "matching_cluster_idx": 4}]}, "Mbpp/808": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def check_K(tup, k):\n \"\"\"\n Checks if a given tuple contains a specific value (k).\n\n Args:\n tup: The input tuple.\n k: The value to search for.\n\n Returns:\n True if k is found in the tuple, False otherwise.\n \"\"\"\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(input_tuple, k):\n \"\"\"\n Checks if a given tuple contains the element k.\n\n Args:\n input_tuple: The tuple to search within.\n k: The element to search for.\n\n Returns:\n True if k is found in the tuple, False otherwise.\n \"\"\"\n return k in input_tuple", "matching_cluster_idx": 5}, {"solution": "def check_K(my_tuple, k):\n \"\"\"\n Checks if a given tuple contains a specific value 'k'.\n\n Args:\n my_tuple: A tuple to be checked.\n k: The value to search for.\n\n Returns:\n True if 'k' is found in the tuple, False otherwise.\n \"\"\"\n return k in my_tuple", "matching_cluster_idx": 5}, {"solution": "def check_K(data, k):\n \"\"\"\n Checks if the given tuple contains the element k.\n\n Args:\n data: A tuple of elements.\n k: The element to search for.\n\n Returns:\n True if k is in the tuple, False otherwise.\n \"\"\"\n return k in data", "matching_cluster_idx": 5}, {"solution": "def check_K(tuple_in, k):\n \"\"\"\n Checks if a tuple contains a given value.\n\n Args:\n tuple_in: The input tuple to search.\n k: The value to search for within the tuple.\n\n Returns:\n True if k is found in the tuple, False otherwise.\n \"\"\"\n\n return k in tuple_in", "matching_cluster_idx": 5}, {"solution": "def check_K(tuple1, k):\n \"\"\"\n Checks if the given tuple contains the value k.\n\n Args:\n tuple1: A tuple of integers.\n k: The value to search for in the tuple.\n\n Returns:\n True if k is present in the tuple, False otherwise.\n \"\"\"\n return k in tuple1", "matching_cluster_idx": 5}, {"solution": "def check_K(tuple_data, k):\n \"\"\"\n This function checks if the given tuple contains the element k.\n\n Args:\n tuple_data: The tuple to be searched.\n k: The element to be searched for.\n\n Returns:\n True if the tuple contains k, False otherwise.\n \"\"\"\n return k in tuple_data", "matching_cluster_idx": 5}, {"solution": "def check_K(input_tuple, k):\n \"\"\"\n Checks if a given tuple contains the value k.\n\n Args:\n input_tuple: A tuple to be checked.\n k: The value to search for in the tuple.\n\n Returns:\n True if the tuple contains k, False otherwise.\n \"\"\"\n return k in input_tuple", "matching_cluster_idx": 5}, {"solution": "def check_K(input_tuple, k):\n \"\"\"\n This function checks if the given tuple contains the element k.\n\n Args:\n input_tuple: A tuple of numbers.\n k: The number to search for in the tuple.\n\n Returns:\n True if k is found in the tuple, False otherwise.\n \"\"\"\n return k in input_tuple", "matching_cluster_idx": 5}, {"solution": "def check_K(input_tuple, k):\n \"\"\"\n Checks if the given tuple contains the value k.\n\n Args:\n input_tuple: The tuple to be checked.\n k: The value to search for.\n\n Returns:\n True if k is found in the tuple, False otherwise.\n \"\"\"\n return k in input_tuple", "matching_cluster_idx": 5}, {"solution": "def check_K(input_tuple, k):\n \"\"\"\n This function checks if the given tuple contains the value k.\n Args:\n input_tuple: The tuple to be checked.\n k: The value to be searched for in the tuple.\n\n Returns:\n True if k is found in the tuple, False otherwise.\n \"\"\"\n return k in input_tuple", "matching_cluster_idx": 5}, {"solution": "def check_K(data, k):\n \"\"\"Checks if the given tuple contains the element k.\n\n Args:\n data: A tuple of elements.\n k: The element to search for.\n\n Returns:\n True if k is in the tuple, False otherwise.\n \"\"\"\n return k in data", "matching_cluster_idx": 5}, {"solution": "def check_K(tuple_data, k):\n \"\"\"\n This function checks if the given tuple contains the value k.\n\n Args:\n tuple_data: A tuple of elements.\n k: The element to search for in the tuple.\n\n Returns:\n True if the tuple contains k, False otherwise.\n \"\"\"\n return k in tuple_data", "matching_cluster_idx": 5}, {"solution": "def check_K(input_tuple, k):\n \"\"\"Checks if the given tuple contains the element k.\n\n Args:\n input_tuple: A tuple of integers.\n k: An integer to check for in the tuple.\n\n Returns:\n True if k is found in the tuple, False otherwise.\n \"\"\"\n return k in input_tuple", "matching_cluster_idx": 5}, {"solution": "def check_K(tuple_data, k):\n \"\"\"\n Checks if the given tuple contains the value k.\n\n Args:\n tuple_data: The tuple to be checked.\n k: The value to search for in the tuple.\n\n Returns:\n True if k is found in the tuple, False otherwise.\n \"\"\"\n return k in tuple_data", "matching_cluster_idx": 5}, {"solution": "def check_K(tuple_data, k):\n \"\"\"\n This function checks if the given tuple contains the element k.\n\n Args:\n tuple_data: A tuple of elements.\n k: The element to search for in the tuple.\n\n Returns:\n True if k is found in the tuple, False otherwise.\n \"\"\"\n return k in tuple_data", "matching_cluster_idx": 5}, {"solution": "def check_K(data, k):\n \"\"\"\n This function checks if the given tuple contains the element k.\n\n Args:\n data: A tuple of numbers.\n k: The number to search for.\n\n Returns:\n True if k is found in the tuple, False otherwise.\n \"\"\"\n return k in data", "matching_cluster_idx": 5}, {"solution": "def check_K(data, k):\n \"\"\"\n Checks if the given tuple contains the value k.\n\n Args:\n data: A tuple of numbers.\n k: The number to search for.\n\n Returns:\n True if k is found in the tuple, False otherwise.\n \"\"\"\n return k in data", "matching_cluster_idx": 5}, {"solution": "def check_K(tuple_data, k):\n \"\"\"\n This function checks if the given tuple contains the value k.\n\n Args:\n tuple_data: A tuple of values.\n k: The value to search for.\n\n Returns:\n True if the tuple contains k, False otherwise.\n \"\"\"\n return k in tuple_data", "matching_cluster_idx": 5}, {"solution": "def check_K(input_tuple, k):\n \"\"\"\n Checks if the given tuple contains the value k.\n\n Args:\n input_tuple: A tuple of integers.\n k: An integer to search for within the tuple.\n\n Returns:\n True if k is present in the tuple, False otherwise.\n \"\"\"\n return k in input_tuple", "matching_cluster_idx": 5}]}}} \ No newline at end of file diff --git a/results/evalperf/google--gemma-2-9b-it_vllm_temp_1.0_evalperf_results.brief.json b/results/evalperf/google--gemma-2-9b-it_vllm_temp_1.0_evalperf_results.brief.json new file mode 100644 index 0000000..e8a9623 --- /dev/null +++ b/results/evalperf/google--gemma-2-9b-it_vllm_temp_1.0_evalperf_results.brief.json @@ -0,0 +1 @@ +{"date": "2024-10-19 16:29", "config": {"n_samples": 100, "temperature": 1.0, "min_correct": 10, "max_profile": 20}, "summary": {"dps": 82.35863751376931, "dps_norm": 78.14625766928611, "pass@1": 68.07627118644068}, "eval": {"HumanEval/9": {"dps": null, "dps_norm": null, "pass@1": 1.0, "profiled": []}, "HumanEval/0": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n if abs(numbers[i] - numbers[j]) < threshold:\n return True\n return False", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n if abs(numbers[i] - numbers[j]) < threshold:\n return True\n return False", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n if abs(numbers[i] - numbers[j]) < threshold:\n return True\n return False", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n if abs(numbers[i] - numbers[j]) < threshold:\n return True\n return False", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n if abs(numbers[i] - numbers[j]) < threshold:\n return True\n return False", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n if abs(numbers[i] - numbers[j]) < threshold:\n return True\n return False", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n if abs(numbers[i] - numbers[j]) < threshold:\n return True\n return False", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n if abs(numbers[i] - numbers[j]) < threshold:\n return True\n return False", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n if abs(numbers[i] - numbers[j]) < threshold:\n return True\n return False", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n if abs(numbers[i] - numbers[j]) < threshold:\n return True\n return False", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n if abs(numbers[i] - numbers[j]) < threshold:\n return True\n return False", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n if abs(numbers[i] - numbers[j]) < threshold:\n return True\n return False", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n if abs(numbers[i] - numbers[j]) < threshold:\n return True\n return False", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n if abs(numbers[i] - numbers[j]) < threshold:\n return True\n return False", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n if abs(numbers[i] - numbers[j]) < threshold:\n return True\n return False", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n if abs(numbers[i] - numbers[j]) < threshold:\n return True\n return False", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n if abs(numbers[i] - numbers[j]) < threshold:\n return True\n return False", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n if abs(numbers[i] - numbers[j]) < threshold:\n return True\n return False", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n if abs(numbers[i] - numbers[j]) < threshold:\n return True\n return False", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n if abs(numbers[i] - numbers[j]) < threshold:\n return True\n return False", "matching_cluster_idx": 6}]}, "HumanEval/4": {"dps": 71.09177215189874, "dps_norm": 89.16666666666667, "pass@1": 100.0, "profiled": [{"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n mean = sum(numbers) / len(numbers)\n return sum([abs(x - mean) for x in numbers]) / len(numbers)", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n mean = sum(numbers) / len(numbers)\n return sum(abs(number - mean) for number in numbers) / len(numbers)", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n mean = sum(numbers) / len(numbers)\n return sum(abs(num - mean) for num in numbers) / len(numbers)", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n mean = sum(numbers) / len(numbers)\n return sum(abs(num - mean) for num in numbers) / len(numbers)", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n mean = sum(numbers) / len(numbers)\n return sum(abs(x - mean) for x in numbers) / len(numbers)", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n mean = sum(numbers) / len(numbers)\n absolute_deviations = [abs(num - mean) for num in numbers]\n return sum(absolute_deviations) / len(numbers)", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n mean = sum(numbers) / len(numbers)\n return sum(abs(num - mean) for num in numbers) / len(numbers)", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n mean = sum(numbers) / len(numbers)\n return sum(abs(number - mean) for number in numbers) / len(numbers)", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n mean = sum(numbers) / len(numbers)\n mad = sum(abs(number - mean) for number in numbers) / len(numbers)\n return mad", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n mean = sum(numbers) / len(numbers)\n return sum(abs(num - mean) for num in numbers) / len(numbers)", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n mean = sum(numbers) / len(numbers)\n return sum([abs(number - mean) for number in numbers]) / len(numbers)", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n mean = sum(numbers) / len(numbers)\n return sum(abs(x - mean) for x in numbers) / len(numbers)", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n mean = sum(numbers) / len(numbers)\n return sum(abs(num - mean) for num in numbers) / len(numbers)", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n mean = sum(numbers) / len(numbers)\n return sum([abs(num - mean) for num in numbers]) / len(numbers)", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n mean = sum(numbers) / len(numbers)\n return sum(abs(num - mean) for num in numbers) / len(numbers)", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n mean = sum(numbers) / len(numbers)\n absolute_deviations = [abs(number - mean) for number in numbers]\n return sum(absolute_deviations) / len(numbers)", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n mean = sum(numbers) / len(numbers)\n return sum(abs(num - mean) for num in numbers) / len(numbers)", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n mean = sum(numbers) / len(numbers)\n absolute_deviations = [abs(num - mean) for num in numbers]\n return sum(absolute_deviations) / len(numbers)", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n mean = sum(numbers) / len(numbers)\n absolute_deviations = [abs(num - mean) for num in numbers]\n return sum(absolute_deviations) / len(numbers)", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n mean = sum(numbers) / len(numbers)\n return sum(abs(num - mean) for num in numbers) / len(numbers)", "matching_cluster_idx": 5}]}, "HumanEval/16": {"dps": 58.13953488372093, "dps_norm": 66.66666666666667, "pass@1": 100.0, "profiled": [{"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n return len(set(string.lower()))", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n return len(set(string.lower()))", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n seen_characters = set()\n for char in string:\n seen_characters.add(char.lower())\n return len(seen_characters)", "matching_cluster_idx": 2}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n return len(set(char.lower() for char in string))", "matching_cluster_idx": 2}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n return len(set(char.lower() for char in string))", "matching_cluster_idx": 2}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n return len(set(char.lower() for char in string))", "matching_cluster_idx": 2}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n return len(set(char.lower() for char in string))", "matching_cluster_idx": 2}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n return len(set(string.lower()))", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n seen_characters = set()\n for char in string:\n seen_characters.add(char.lower())\n return len(seen_characters)", "matching_cluster_idx": 2}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n return len(set(string.lower()))", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n seen_characters = set()\n for char in string:\n seen_characters.add(char.lower())\n return len(seen_characters)", "matching_cluster_idx": 2}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n return len(set(string.lower()))", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n seen_characters = set()\n for char in string:\n seen_characters.add(char.lower())\n return len(seen_characters)", "matching_cluster_idx": 2}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n return len(set(char.lower() for char in string))", "matching_cluster_idx": 2}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n return len(set(string.lower()))", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n return len(set(string.lower()))", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n distinct_chars = set()\n for char in string:\n distinct_chars.add(char.lower()) \n return len(distinct_chars)", "matching_cluster_idx": 2}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n return len(set(string.lower()))", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n return len(set(string.lower()))", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n return len(set(string.lower()))", "matching_cluster_idx": 8}]}, "HumanEval/20": {"dps": 25.012106537530265, "dps_norm": 47.22222222222222, "pass@1": 100.0, "profiled": [{"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n if len(numbers) < 2:\n raise ValueError(\"Input list must have at least two elements\")\n\n closest_pair = (numbers[0], numbers[1])\n min_distance = abs(closest_pair[0] - closest_pair[1])\n \n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n distance = abs(numbers[i] - numbers[j])\n if distance < min_distance:\n closest_pair = (numbers[i], numbers[j])\n min_distance = distance\n\n return tuple(sorted(closest_pair))", "matching_cluster_idx": 3}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n closest_pair = (numbers[0], numbers[1])\n min_distance = abs(numbers[0] - numbers[1])\n\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n distance = abs(numbers[i] - numbers[j])\n if distance < min_distance:\n min_distance = distance\n closest_pair = (numbers[i], numbers[j])\n\n return tuple(sorted(closest_pair))", "matching_cluster_idx": 3}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n if len(numbers) < 2:\n raise ValueError(\"List must contain at least two numbers\")\n\n closest_pair = (numbers[0], numbers[1])\n min_difference = abs(numbers[0] - numbers[1])\n\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n difference = abs(numbers[i] - numbers[j])\n if difference < min_difference:\n min_difference = difference\n closest_pair = (numbers[i], numbers[j])\n\n return tuple(sorted(closest_pair))", "matching_cluster_idx": 3}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n if len(numbers) < 2:\n raise ValueError(\"Input list must contain at least two elements\")\n\n closest_pair = (numbers[0], numbers[1])\n min_distance = abs(numbers[0] - numbers[1])\n \n for i in range(len(numbers)):\n for j in range(i+1, len(numbers)):\n distance = abs(numbers[i] - numbers[j])\n if distance < min_distance:\n min_distance = distance\n closest_pair = (numbers[i], numbers[j])\n\n return tuple(sorted(closest_pair))", "matching_cluster_idx": 3}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n if len(numbers) < 2:\n raise ValueError(\"List should have at least two elements\")\n \n closest_pair = (numbers[0], numbers[1])\n min_difference = abs(numbers[0] - numbers[1])\n\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n difference = abs(numbers[i] - numbers[j])\n if difference < min_difference:\n closest_pair = (numbers[i], numbers[j])\n min_difference = difference\n return tuple(sorted(closest_pair))", "matching_cluster_idx": 3}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n if len(numbers) < 2:\n raise ValueError(\"List must contain at least two numbers.\")\n\n closest_pair = (numbers[0], numbers[1])\n min_difference = abs(numbers[0] - numbers[1])\n\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n difference = abs(numbers[i] - numbers[j])\n if difference < min_difference:\n closest_pair = (numbers[i], numbers[j])\n min_difference = difference\n\n return tuple(sorted(closest_pair))", "matching_cluster_idx": 3}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n min_diff = float('inf')\n closest_pair = (numbers[0], numbers[1])\n\n for i in range(len(numbers)):\n for j in range(i+1, len(numbers)):\n diff = abs(numbers[i] - numbers[j])\n if diff < min_diff:\n min_diff = diff\n closest_pair = (numbers[i], numbers[j])\n\n return tuple(sorted(closest_pair))", "matching_cluster_idx": 3}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n if len(numbers) < 2:\n raise ValueError(\"List must contain at least two numbers.\")\n\n closest_pair = (numbers[0], numbers[1])\n min_distance = abs(numbers[0] - numbers[1])\n\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n distance = abs(numbers[i] - numbers[j])\n if distance < min_distance:\n closest_pair = (numbers[i], numbers[j])\n min_distance = distance\n\n return tuple(sorted(closest_pair))", "matching_cluster_idx": 3}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n numbers.sort()\n closest = (numbers[0], numbers[1])\n min_diff = abs(numbers[1] - numbers[0])\n for i in range(2, len(numbers)):\n diff = abs(numbers[i] - numbers[i - 1])\n if diff < min_diff:\n min_diff = diff\n closest = (numbers[i - 1], numbers[i])\n return closest", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n if len(numbers) < 2:\n raise ValueError(\"Input list must have at least two elements.\")\n \n closest_pair = (numbers[0], numbers[1])\n min_distance = abs(numbers[0] - numbers[1])\n\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n distance = abs(numbers[i] - numbers[j])\n if distance < min_distance:\n closest_pair = (numbers[i], numbers[j])\n min_distance = distance\n\n return tuple(sorted(closest_pair))", "matching_cluster_idx": 3}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n if len(numbers) < 2:\n raise ValueError(\"List must contain at least two numbers\")\n \n min_diff = float('inf')\n closest_pair = (numbers[0], numbers[1])\n\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n diff = abs(numbers[i] - numbers[j])\n if diff < min_diff:\n min_diff = diff\n closest_pair = (numbers[i], numbers[j])\n \n return tuple(sorted(closest_pair))", "matching_cluster_idx": 3}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n if len(numbers) < 2:\n raise ValueError(\"List must contain at least two numbers.\")\n closest = (numbers[0], numbers[1])\n min_diff = abs(numbers[0] - numbers[1])\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n diff = abs(numbers[i] - numbers[j])\n if diff < min_diff:\n min_diff = diff\n closest = (numbers[i], numbers[j])\n return tuple(sorted(closest))", "matching_cluster_idx": 3}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n if len(numbers) < 2:\n raise ValueError(\"List must contain at least two numbers.\")\n \n closest_pair = (numbers[0], numbers[1])\n min_distance = abs(numbers[0] - numbers[1])\n\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n distance = abs(numbers[i] - numbers[j])\n if distance < min_distance:\n min_distance = distance\n closest_pair = (numbers[i], numbers[j])\n \n return tuple(sorted(closest_pair))", "matching_cluster_idx": 3}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n if len(numbers) < 2:\n raise ValueError(\"Input list must contain at least two numbers.\")\n \n closest_pair = (numbers[0], numbers[1])\n min_distance = abs(numbers[0] - numbers[1])\n\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n distance = abs(numbers[i] - numbers[j])\n if distance < min_distance:\n min_distance = distance\n closest_pair = (numbers[i], numbers[j])\n\n return tuple(sorted(closest_pair))", "matching_cluster_idx": 3}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n if len(numbers) < 2:\n raise ValueError(\"Input list must contain at least two numbers.\")\n\n closest_pair = (numbers[0], numbers[1])\n min_distance = abs(numbers[0] - numbers[1])\n\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n distance = abs(numbers[i] - numbers[j])\n if distance < min_distance:\n closest_pair = (numbers[i], numbers[j])\n min_distance = distance\n\n return tuple(sorted(closest_pair))", "matching_cluster_idx": 3}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n if len(numbers) < 2:\n raise ValueError(\"Input list must contain at least two numbers.\")\n \n closest_pair = (numbers[0], numbers[1])\n min_distance = abs(numbers[0] - numbers[1])\n\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n distance = abs(numbers[i] - numbers[j])\n if distance < min_distance:\n min_distance = distance\n closest_pair = (numbers[i], numbers[j])\n\n return tuple(sorted(closest_pair))", "matching_cluster_idx": 3}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n if len(numbers) < 2:\n raise ValueError(\"List must contain at least two numbers.\")\n closest_pair = (numbers[0], numbers[1])\n min_diff = abs(numbers[0] - numbers[1])\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n diff = abs(numbers[i] - numbers[j])\n if diff < min_diff:\n min_diff = diff\n closest_pair = (numbers[i], numbers[j])\n return tuple(sorted(closest_pair))", "matching_cluster_idx": 3}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n if len(numbers) < 2:\n raise ValueError(\"Input list must have at least two elements.\")\n \n closest_pair = (numbers[0], numbers[1])\n min_distance = abs(numbers[0] - numbers[1])\n\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n distance = abs(numbers[i] - numbers[j])\n if distance < min_distance:\n closest_pair = (numbers[i], numbers[j])\n min_distance = distance\n return tuple(sorted(closest_pair))", "matching_cluster_idx": 3}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n if len(numbers) < 2:\n raise ValueError(\"List must contain at least two numbers\")\n \n closest_pair = (numbers[0], numbers[1])\n min_distance = abs(numbers[0] - numbers[1])\n\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n distance = abs(numbers[i] - numbers[j])\n if distance < min_distance:\n min_distance = distance\n closest_pair = (numbers[i], numbers[j])\n return tuple(sorted(closest_pair))", "matching_cluster_idx": 3}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n if len(numbers) < 2:\n raise ValueError(\"Input list must contain at least two numbers.\")\n \n closest_pair = (numbers[0], numbers[1])\n min_distance = abs(numbers[0] - numbers[1])\n\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n distance = abs(numbers[i] - numbers[j])\n if distance < min_distance:\n min_distance = distance\n closest_pair = (numbers[i], numbers[j])\n\n return tuple(sorted(closest_pair))", "matching_cluster_idx": 3}]}, "HumanEval/24": {"dps": 78.2312925170068, "dps_norm": 50.0, "pass@1": 100.0, "profiled": [{"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n for i in range(n // 2, 0, -1):\n if n % i == 0:\n return i\n return 1", "matching_cluster_idx": 3}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n for i in range(n // 2, 0, -1): # Iterate from n/2 down to 1\n if n % i == 0:\n return i \n return 1 # If no divisors found, return 1", "matching_cluster_idx": 3}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n for i in range(n//2, 0, -1):\n if n % i == 0:\n return i\n return 1", "matching_cluster_idx": 3}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n for i in range(n // 2, 0, -1):\n if n % i == 0:\n return i\n return 1", "matching_cluster_idx": 3}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n for i in range(n // 2, 0, -1):\n if n % i == 0:\n return i\n return 1", "matching_cluster_idx": 3}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n for i in range(n // 2, 0, -1):\n if n % i == 0:\n return i\n return 1", "matching_cluster_idx": 3}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n for i in range(n // 2, 0, -1):\n if n % i == 0:\n return i\n return 1", "matching_cluster_idx": 3}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n for i in range(n//2, 0, -1):\n if n % i == 0:\n return i\n return 1", "matching_cluster_idx": 3}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n for i in range(n // 2, 0, -1):\n if n % i == 0:\n return i\n return 1", "matching_cluster_idx": 3}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n for i in range(n//2, 0, -1):\n if n % i == 0:\n return i\n return 1", "matching_cluster_idx": 3}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n for i in range(n//2, 0, -1):\n if n % i == 0:\n return i\n return 1", "matching_cluster_idx": 3}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n for i in range(n // 2, 0, -1):\n if n % i == 0:\n return i\n return 1", "matching_cluster_idx": 3}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n for i in range(n//2, 0, -1):\n if n % i == 0:\n return i\n return 1", "matching_cluster_idx": 3}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n for i in range(n // 2, 0, -1):\n if n % i == 0:\n return i\n return 1", "matching_cluster_idx": 3}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n for i in range(n // 2, 0, -1):\n if n % i == 0:\n return i\n return 1", "matching_cluster_idx": 3}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n for i in range(n // 2, 0, -1):\n if n % i == 0:\n return i\n return 1", "matching_cluster_idx": 3}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n for i in range(n//2, 0, -1):\n if n % i == 0:\n return i\n return 1", "matching_cluster_idx": 3}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n for i in range(n//2, 0, -1):\n if n % i == 0:\n return i\n return 1", "matching_cluster_idx": 3}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n for i in range(n // 2, 0, -1):\n if n % i == 0:\n return i\n return 1", "matching_cluster_idx": 3}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n for i in range(n // 2, 0, -1): \n if n % i == 0:\n return i\n return 1", "matching_cluster_idx": 3}]}, "HumanEval/26": {"dps": null, "dps_norm": null, "pass@1": 0.0, "profiled": []}, "HumanEval/31": {"dps": 34.936708860759495, "dps_norm": 63.75, "pass@1": 100.0, "profiled": [{"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n # Prime numbers are greater than 1\n if n <= 1:\n return False\n # Check if n is divisible by any number from 2 to the square root of n\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n # Prime numbers are greater than 1\n if n <= 1:\n return False\n # Check if n is divisible by any number from 2 to the square root of n\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n # Prime numbers are greater than 1\n if n <= 1:\n return False\n # Check if n is divisible by any number from 2 to the square root of n\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n # Prime numbers are greater than 1\n if n <= 1:\n return False\n # Check if n is divisible by any number from 2 to the square root of n\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n # Prime numbers are greater than 1\n if n <= 1:\n return False\n # Check if n is divisible by any number from 2 to the square root of n\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n # Prime numbers are greater than 1\n if n <= 1:\n return False\n # Check if n is divisible by any number from 2 to the square root of n\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n # Prime numbers are greater than 1\n if n <= 1:\n return False\n # Check if n is divisible by any number from 2 to the square root of n\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n # Handle cases for 1, 2, and negative numbers\n if n <= 1:\n return False\n if n <= 3:\n return True\n \n # Check divisibility by 2 and 3\n if n % 2 == 0 or n % 3 == 0:\n return False\n\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n # Prime numbers are greater than 1\n if n <= 1:\n return False\n # Check if n is divisible by any number from 2 to the square root of n\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n # Prime numbers are greater than 1\n if n <= 1:\n return False\n # Check if n is divisible by any number from 2 to the square root of n\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n # Prime numbers are greater than 1\n if n <= 1:\n return False\n # Check if n is divisible by any number from 2 to the square root of n\n for i in range(2, int(n ** 0.5) + 1):\n if n % i == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n # Prime numbers are greater than 1\n if n <= 1:\n return False\n # Check if n is divisible by any number from 2 to the square root of n\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\"\"\"\n # Prime numbers are greater than 1\n if n <= 1:\n return False\n # Check if n is divisible by any number from 2 to the square root of n\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n # Prime numbers are greater than 1\n if n <= 1:\n return False\n # Check if n is divisible by any number from 2 to the square root of n\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True", "matching_cluster_idx": 4}]}, "HumanEval/33": {"dps": null, "dps_norm": null, "pass@1": 5.0, "profiled": []}, "HumanEval/34": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}]}, "HumanEval/36": {"dps": null, "dps_norm": null, "pass@1": 0.0, "profiled": []}, "HumanEval/37": {"dps": 96.70212765957447, "dps_norm": 93.5, "pass@1": 96.0, "profiled": [{"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n new_list = l.copy() \n new_list[::2] = sorted(l[::2])\n return new_list", "matching_cluster_idx": 9}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n l_sorted = sorted(l[::2]) \n result = list(l)\n for i in range(0, len(l), 2):\n result[i] = l_sorted.pop(0)\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n l_new = l.copy()\n l_new[::2] = sorted(l[::2])\n return l_new", "matching_cluster_idx": 9}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n l_sorted = sorted(l[::2])\n l_new = list(l)\n for i in range(0, len(l), 2):\n l_new[i] = l_sorted[i//2]\n return l_new", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n l_sorted = sorted(l[::2])\n l_new = list(l)\n for i in range(0, len(l), 2):\n l_new[i] = l_sorted.pop(0)\n return l_new", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n l_sorted = sorted([l[i] for i in range(len(l)) if i % 2 == 0])\n l_new = l[:]\n for i in range(len(l_sorted)):\n l_new[i * 2] = l_sorted[i]\n return l_new", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n sorted_even = sorted(l[::2])\n l_prime = l[:]\n for i in range(0, len(l), 2):\n l_prime[i] = sorted_even.pop(0)\n return l_prime", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n l_new = l.copy() \n l_new[::2] = sorted(l[::2]) \n return l_new", "matching_cluster_idx": 9}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n l_sorted = l[:].copy()\n l_sorted[::2] = sorted(l[::2]) \n return l_sorted", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n l_sorted = sorted(l[::2])\n l_prime = l.copy() \n for i in range(0, len(l), 2):\n l_prime[i] = l_sorted[i // 2]\n return l_prime", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n l_sorted = sorted([l[i] for i in range(len(l)) if i % 2 == 0]) \n result = []\n for i in range(len(l)):\n if i % 2 == 0:\n result.append(l_sorted.pop(0))\n else: \n result.append(l[i])\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n l_new = l.copy()\n l_new[::2] = sorted(l[::2])\n return l_new", "matching_cluster_idx": 9}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n l_sorted = sorted([l[i] for i in range(len(l)) if i % 2 == 0])\n l_prime = l[:]\n for i in range(len(l_prime)):\n if i % 2 == 0:\n l_prime[i] = l_sorted[i // 2]\n return l_prime", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n l_sorted = l[:].copy()\n l_sorted[::2] = sorted(l[::2])\n return l_sorted", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n l_new = l.copy()\n l_new[0::2] = sorted(l[0::2]) \n return l_new", "matching_cluster_idx": 9}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n l_sorted = sorted(l[::2]) \n l_new = l[:]\n for i in range(0, len(l), 2):\n l_new[i] = l_sorted[i//2]\n return l_new", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n l_new = l[:]\n l_new[::2] = sorted(l[::2])\n return l_new", "matching_cluster_idx": 9}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n l_prime = l.copy()\n l_prime[0::2] = sorted(l[0::2])\n return l_prime", "matching_cluster_idx": 9}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n l_sorted = sorted(l[::2])\n l_new = list(l)\n for i in range(0, len(l_new), 2):\n l_new[i] = l_sorted.pop(0)\n return l_new", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n l_sorted = l[::2]\n l_sorted.sort()\n for i in range(0, len(l_sorted)):\n l[2*i] = l_sorted[i]\n return l", "matching_cluster_idx": 8}]}, "HumanEval/49": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 51.0, "profiled": [{"solution": "def modp(n: int, p: int):\n \"\"\"Return 2^n modulo p (be aware of numerics).\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int):\n \"\"\"Return 2^n modulo p (be aware of numerics).\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int):\n \"\"\"Return 2^n modulo p (be aware of numerics).\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int):\n \"\"\"Return 2^n modulo p (be aware of numerics).\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int):\n \"\"\"Return 2^n modulo p (be aware of numerics).\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int):\n \"\"\"Return 2^n modulo p (be aware of numerics).\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int):\n \"\"\"Return 2^n modulo p (be aware of numerics).\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int):\n \"\"\"Return 2^n modulo p (be aware of numerics).\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int):\n \"\"\"Return 2^n modulo p (be aware of numerics).\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int):\n \"\"\"Return 2^n modulo p (be aware of numerics).\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int):\n \"\"\"Return 2^n modulo p (be aware of numerics).\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int):\n \"\"\"Return 2^n modulo p (be aware of numerics).\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int):\n \"\"\"Return 2^n modulo p (be aware of numerics).\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int):\n \"\"\"Return 2^n modulo p (be aware of numerics).\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int):\n \"\"\"Return 2^n modulo p (be aware of numerics).\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int):\n \"\"\"Return 2^n modulo p (be aware of numerics).\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int):\n \"\"\"Return 2^n modulo p (be aware of numerics).\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int):\n \"\"\"Return 2^n modulo p (be aware of numerics).\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int):\n \"\"\"Return 2^n modulo p (be aware of numerics).\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int):\n \"\"\"Return 2^n modulo p (be aware of numerics).\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}]}, "HumanEval/51": {"dps": 96.13526570048309, "dps_norm": 75.0, "pass@1": 100.0, "profiled": [{"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = 'aeiouAEIOU'\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = 'aeiouAEIOU'\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = 'aeiouAEIOU'\n result = ''\n for char in text:\n if char not in vowels:\n result += char\n return result", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = 'aeiouAEIOU'\n result = ''.join([char for char in text if char not in vowels])\n return result", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = 'aeiouAEIOU'\n result = ''.join([char for char in text if char not in vowels])\n return result", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = 'aeiouAEIOU'\n result = ''\n for char in text:\n if char not in vowels:\n result += char\n return result", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = 'aeiouAEIOU'\n result = ''.join([char for char in text if char not in vowels])\n return result", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = 'aeiouAEIOU'\n result = ''.join([letter for letter in text if letter not in vowels])\n return result", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = 'aeiouAEIOU'\n result = ''\n for char in text:\n if char not in vowels:\n result += char\n return result", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = 'aeiouAEIOU'\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n result = ''.join([char for char in text if char not in vowels])\n return result", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = 'aeiouAEIOU'\n result = ''.join([letter for letter in text if letter not in vowels])\n return result", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = 'aeiouAEIOU'\n result = ''.join([char for char in text if char not in vowels])\n return result", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = 'aeiouAEIOU'\n result = ''.join([char for char in text if char not in vowels])\n return result", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = 'aeiouAEIOU'\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = 'aeiouAEIOU'\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = 'aeiouAEIOU'\n return ''.join([letter for letter in text if letter not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = 'aeiouAEIOU'\n result = ''.join([char for char in text if char not in vowels])\n return result", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = 'aeiouAEIOU'\n result = ''.join([char for char in text if char not in vowels])\n return result", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = 'aeiouAEIOU'\n result = ''\n for char in text:\n if char not in vowels:\n result += char\n return result", "matching_cluster_idx": 5}]}, "HumanEval/54": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 53.0, "profiled": [{"solution": "def same_chars(s0: str, s1: str):\n \"\"\"\n Check if two words have the same characters.\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')\n True\n >>> same_chars('abcd', 'dddddddabc')\n True\n >>> same_chars('dddddddabc', 'abcd')\n True\n >>> same_chars('eabcd', 'dddddddabc')\n False\n >>> same_chars('abcd', 'dddddddabce')\n False\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')\n False\n \"\"\"\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str):\n \"\"\"\n Check if two words have the same characters.\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')\n True\n >>> same_chars('abcd', 'dddddddabc')\n True\n >>> same_chars('dddddddabc', 'abcd')\n True\n >>> same_chars('eabcd', 'dddddddabc')\n False\n >>> same_chars('abcd', 'dddddddabce')\n False\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')\n False\n \"\"\"\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str):\n \"\"\"\n Check if two words have the same characters.\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')\n True\n >>> same_chars('abcd', 'dddddddabc')\n True\n >>> same_chars('dddddddabc', 'abcd')\n True\n >>> same_chars('eabcd', 'dddddddabc')\n False\n >>> same_chars('abcd', 'dddddddabce')\n False\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')\n False\n \"\"\"\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str):\n \"\"\"\n Check if two words have the same characters.\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')\n True\n >>> same_chars('abcd', 'dddddddabc')\n True\n >>> same_chars('dddddddabc', 'abcd')\n True\n >>> same_chars('eabcd', 'dddddddabc')\n False\n >>> same_chars('abcd', 'dddddddabce')\n False\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')\n False\n \"\"\"\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str):\n \"\"\"\n Check if two words have the same characters.\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')\n True\n >>> same_chars('abcd', 'dddddddabc')\n True\n >>> same_chars('dddddddabc', 'abcd')\n True\n >>> same_chars('eabcd', 'dddddddabc')\n False\n >>> same_chars('abcd', 'dddddddabce')\n False\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')\n False\n \"\"\"\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str):\n \"\"\"\n Check if two words have the same characters.\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')\n True\n >>> same_chars('abcd', 'dddddddabc')\n True\n >>> same_chars('dddddddabc', 'abcd')\n True\n >>> same_chars('eabcd', 'dddddddabc')\n False\n >>> same_chars('abcd', 'dddddddabce')\n False\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')\n False\n \"\"\"\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str):\n \"\"\"\n Check if two words have the same characters.\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')\n True\n >>> same_chars('abcd', 'dddddddabc')\n True\n >>> same_chars('dddddddabc', 'abcd')\n True\n >>> same_chars('eabcd', 'dddddddabc')\n False\n >>> same_chars('abcd', 'dddddddabce')\n False\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')\n False\n \"\"\"\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str):\n \"\"\"\n Check if two words have the same characters.\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')\n True\n >>> same_chars('abcd', 'dddddddabc')\n True\n >>> same_chars('dddddddabc', 'abcd')\n True\n >>> same_chars('eabcd', 'dddddddabc')\n False\n >>> same_chars('abcd', 'dddddddabce')\n False\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')\n False\n \"\"\"\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str):\n \"\"\"\n Check if two words have the same characters.\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')\n True\n >>> same_chars('abcd', 'dddddddabc')\n True\n >>> same_chars('dddddddabc', 'abcd')\n True\n >>> same_chars('eabcd', 'dddddddabc')\n False\n >>> same_chars('abcd', 'dddddddabce')\n False\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')\n False\n \"\"\"\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str):\n \"\"\"\n Check if two words have the same characters.\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')\n True\n >>> same_chars('abcd', 'dddddddabc')\n True\n >>> same_chars('dddddddabc', 'abcd')\n True\n >>> same_chars('eabcd', 'dddddddabc')\n False\n >>> same_chars('abcd', 'dddddddabce')\n False\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')\n False\n \"\"\"\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str):\n \"\"\"\n Check if two words have the same characters.\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')\n True\n >>> same_chars('abcd', 'dddddddabc')\n True\n >>> same_chars('dddddddabc', 'abcd')\n True\n >>> same_chars('eabcd', 'dddddddabc')\n False\n >>> same_chars('abcd', 'dddddddabce')\n False\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')\n False\n \"\"\"\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str):\n \"\"\"\n Check if two words have the same characters.\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')\n True\n >>> same_chars('abcd', 'dddddddabc')\n True\n >>> same_chars('dddddddabc', 'abcd')\n True\n >>> same_chars('eabcd', 'dddddddabc')\n False\n >>> same_chars('abcd', 'dddddddabce')\n False\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')\n False\n \"\"\"\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str):\n \"\"\"\n Check if two words have the same characters.\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')\n True\n >>> same_chars('abcd', 'dddddddabc')\n True\n >>> same_chars('dddddddabc', 'abcd')\n True\n >>> same_chars('eabcd', 'dddddddabc')\n False\n >>> same_chars('abcd', 'dddddddabce')\n False\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')\n False\n \"\"\"\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str):\n \"\"\"\n Check if two words have the same characters.\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')\n True\n >>> same_chars('abcd', 'dddddddabc')\n True\n >>> same_chars('dddddddabc', 'abcd')\n True\n >>> same_chars('eabcd', 'dddddddabc')\n False\n >>> same_chars('abcd', 'dddddddabce')\n False\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')\n False\n \"\"\"\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str):\n \"\"\"\n Check if two words have the same characters.\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')\n True\n >>> same_chars('abcd', 'dddddddabc')\n True\n >>> same_chars('dddddddabc', 'abcd')\n True\n >>> same_chars('eabcd', 'dddddddabc')\n False\n >>> same_chars('abcd', 'dddddddabce')\n False\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')\n False\n \"\"\"\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str):\n \"\"\"\n Check if two words have the same characters.\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')\n True\n >>> same_chars('abcd', 'dddddddabc')\n True\n >>> same_chars('dddddddabc', 'abcd')\n True\n >>> same_chars('eabcd', 'dddddddabc')\n False\n >>> same_chars('abcd', 'dddddddabce')\n False\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')\n False\n \"\"\"\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str):\n \"\"\"\n Check if two words have the same characters.\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')\n True\n >>> same_chars('abcd', 'dddddddabc')\n True\n >>> same_chars('dddddddabc', 'abcd')\n True\n >>> same_chars('eabcd', 'dddddddabc')\n False\n >>> same_chars('abcd', 'dddddddabce')\n False\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')\n False\n \"\"\"\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str):\n \"\"\"\n Check if two words have the same characters.\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')\n True\n >>> same_chars('abcd', 'dddddddabc')\n True\n >>> same_chars('dddddddabc', 'abcd')\n True\n >>> same_chars('eabcd', 'dddddddabc')\n False\n >>> same_chars('abcd', 'dddddddabce')\n False\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')\n False\n \"\"\"\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str):\n \"\"\"\n Check if two words have the same characters.\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')\n True\n >>> same_chars('abcd', 'dddddddabc')\n True\n >>> same_chars('dddddddabc', 'abcd')\n True\n >>> same_chars('eabcd', 'dddddddabc')\n False\n >>> same_chars('abcd', 'dddddddabce')\n False\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')\n False\n \"\"\"\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str):\n \"\"\"\n Check if two words have the same characters.\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')\n True\n >>> same_chars('abcd', 'dddddddabc')\n True\n >>> same_chars('dddddddabc', 'abcd')\n True\n >>> same_chars('eabcd', 'dddddddabc')\n False\n >>> same_chars('abcd', 'dddddddabce')\n False\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')\n False\n \"\"\"\n return set(s0) == set(s1)", "matching_cluster_idx": 6}]}, "HumanEval/58": {"dps": 92.51968503937007, "dps_norm": 83.33333333333333, "pass@1": 100.0, "profiled": [{"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n\n \"\"\"\n return sorted(set(l1) & set(l2))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n\n \"\"\"\n return sorted(list(set(l1) & set(l2)))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n\n \"\"\"\n return sorted(set(l1) & set(l2))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n\n \"\"\"\n return sorted(set(l1) & set(l2))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n\n \"\"\"\n common_elements = set(l1).intersection(set(l2))\n return sorted(list(common_elements))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n\n \"\"\"\n return sorted(set(l1) & set(l2))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n\n \"\"\"\n return sorted(set(l1) & set(l2))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n\n \"\"\"\n return sorted(list(set(l1) & set(l2)))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n\n \"\"\"\n return sorted(set(l1) & set(l2))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n\n \"\"\"\n return sorted(set(l1) & set(l2))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n\n \"\"\"\n return sorted(set(l1) & set(l2))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n\n \"\"\"\n return sorted(list(set(l1) & set(l2)))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n\n \"\"\"\n return sorted(set(l1) & set(l2))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n\n \"\"\"\n return sorted(set(l1) & set(l2))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n\n \"\"\"\n return sorted(set(l1) & set(l2))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n\n \"\"\"\n return sorted(set(l1) & set(l2))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n\n \"\"\"\n return sorted(set(l1) & set(l2))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n\n \"\"\"\n return sorted(set(l1) & set(l2))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n\n \"\"\"\n return sorted(set(l1) & set(l2))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n\n \"\"\"\n return sorted(set(l1) & set(l2))", "matching_cluster_idx": 4}]}, "HumanEval/59": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n largest_factor = 2\n while n > 1:\n if n % largest_factor == 0:\n n //= largest_factor\n else:\n largest_factor += 1\n return largest_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n largest_factor = 1\n i = 2\n while i * i <= n:\n while n % i == 0:\n largest_factor = i\n n //= i\n i += 1\n if n > 1:\n largest_factor = n\n return largest_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n largest_factor = 1\n i = 2\n while i * i <= n:\n if n % i == 0:\n largest_factor = i\n n //= i\n else:\n i += 1\n if n > largest_factor:\n largest_factor = n\n return largest_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n largest_factor = 1\n i = 2\n while i * i <= n:\n if n % i == 0:\n largest_factor = i\n n //= i\n else:\n i += 1\n if n > 1:\n largest_factor = n\n return largest_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n largest_factor = 1\n i = 2\n while i * i <= n:\n if n % i == 0:\n largest_factor = i\n n //= i\n else:\n i += 1\n if n > largest_factor:\n largest_factor = n\n return largest_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n largest_factor = 1\n i = 2\n while i * i <= n:\n if n % i == 0:\n largest_factor = i\n n //= i\n else:\n i += 1\n if n > largest_factor:\n largest_factor = n\n return largest_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n largest_factor = 2\n while n > 1:\n if n % largest_factor == 0:\n n //= largest_factor\n else:\n largest_factor += 1\n return largest_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n largest_factor = 2\n while n > 1:\n if n % largest_factor == 0:\n n //= largest_factor\n else:\n largest_factor += 1\n return largest_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n largest_factor = 2\n while n > 1:\n if n % largest_factor == 0:\n n //= largest_factor\n else:\n largest_factor += 1\n return largest_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n largest_factor = 2\n while n > 1:\n if n % largest_factor == 0:\n n //= largest_factor\n else:\n largest_factor += 1\n return largest_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n largest_factor = 2\n while n > 1:\n if n % largest_factor == 0:\n n //= largest_factor\n else:\n largest_factor += 1\n return largest_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n largest_factor = 2\n while n > 1:\n if n % largest_factor == 0:\n n //= largest_factor\n else:\n largest_factor += 1\n return largest_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n largest_factor = 1\n i = 2\n while i * i <= n:\n if n % i == 0:\n largest_factor = i\n n //= i\n else:\n i += 1\n if n > largest_factor:\n largest_factor = n\n return largest_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n largest_factor = 2 \n while n % largest_factor == 0:\n n //= largest_factor\n for i in range(3, int(n**0.5) + 1, 2):\n while n % i == 0:\n largest_factor = i\n n //= i\n if n > 2:\n largest_factor = n\n return largest_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n largest_factor = 2\n while n > 1:\n if n % largest_factor == 0:\n n //= largest_factor\n else:\n largest_factor += 1\n return largest_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n largest_factor = 1\n i = 2\n while i * i <= n:\n while n % i == 0:\n largest_factor = i\n n //= i\n i += 1\n if n > largest_factor:\n largest_factor = n\n return largest_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n largest_factor = 1\n i = 2\n while i * i <= n:\n if n % i == 0:\n largest_factor = i\n n //= i\n else:\n i += 1\n if n > largest_factor:\n largest_factor = n\n return largest_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n largest_factor = 1\n i = 2\n while i * i <= n:\n if n % i == 0:\n largest_factor = i\n n //= i\n else:\n i += 1\n if n > largest_factor:\n largest_factor = n\n return largest_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n largest_factor = 1\n i = 2\n while i * i <= n:\n if n % i == 0:\n largest_factor = i\n n //= i\n else:\n i += 1\n if n > largest_factor:\n largest_factor = n\n return largest_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n largest_factor = 1\n i = 2\n while i * i <= n:\n if n % i == 0:\n largest_factor = i\n n //= i\n else:\n i += 1\n if n > largest_factor:\n largest_factor = n\n return largest_factor", "matching_cluster_idx": 8}]}, "HumanEval/64": {"dps": null, "dps_norm": null, "pass@1": 0.0, "profiled": []}, "HumanEval/74": {"dps": 98.04878048780488, "dps_norm": 88.88888888888889, "pass@1": 100.0, "profiled": [{"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n total1 = sum(len(s) for s in lst1)\n total2 = sum(len(s) for s in lst2)\n if total1 < total2:\n return lst1\n elif total2 < total1:\n return lst2\n else:\n return lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n len1 = sum(len(x) for x in lst1)\n len2 = sum(len(x) for x in lst2)\n if len1 < len2:\n return lst1\n elif len2 < len1:\n return lst2\n else:\n return lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n total_chars_lst1 = sum(len(word) for word in lst1)\n total_chars_lst2 = sum(len(word) for word in lst2)\n\n if total_chars_lst1 < total_chars_lst2:\n return lst1\n elif total_chars_lst2 < total_chars_lst1:\n return lst2\n else:\n return lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n \"\"\"\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n \"\"\"\n total_chars1 = sum(len(word) for word in lst1)\n total_chars2 = sum(len(word) for word in lst2)\n if total_chars1 < total_chars2:\n return lst1\n elif total_chars2 < total_chars1:\n return lst2\n else:\n return lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n sum1 = sum(len(s) for s in lst1)\n sum2 = sum(len(s) for s in lst2)\n if sum1 < sum2:\n return lst1\n elif sum2 < sum1:\n return lst2\n else:\n return lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n sum1 = sum(len(word) for word in lst1)\n sum2 = sum(len(word) for word in lst2)\n if sum1 < sum2:\n return lst1\n elif sum2 < sum1:\n return lst2\n else:\n return lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n \"\"\"\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n \"\"\"\n total1 = sum(len(word) for word in lst1)\n total2 = sum(len(word) for word in lst2)\n if total1 < total2:\n return lst1\n elif total2 < total1:\n return lst2\n else:\n return lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n len1 = sum(len(s) for s in lst1)\n len2 = sum(len(s) for s in lst2)\n if len1 < len2:\n return lst1\n elif len2 < len1:\n return lst2\n else:\n return lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n total1 = sum(len(word) for word in lst1)\n total2 = sum(len(word) for word in lst2)\n \n if total1 < total2:\n return lst1\n elif total2 < total1:\n return lst2\n else:\n return lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n \"\"\"\n Write a function that accepts two lists of strings and returns the list that has\n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n \"\"\"\n total1 = sum(len(word) for word in lst1)\n total2 = sum(len(word) for word in lst2)\n if total1 < total2:\n return lst1\n elif total2 < total1:\n return lst2\n else:\n return lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n \"\"\"\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n \"\"\"\n len_lst1 = sum(len(s) for s in lst1)\n len_lst2 = sum(len(s) for s in lst2)\n if len_lst1 < len_lst2:\n return lst1\n elif len_lst2 < len_lst1:\n return lst2\n else:\n return lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n len1 = sum(len(x) for x in lst1)\n len2 = sum(len(x) for x in lst2)\n if len1 < len2:\n return lst1\n elif len2 < len1:\n return lst2\n else:\n return lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n \"\"\"\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n \"\"\"\n total1 = sum(len(word) for word in lst1)\n total2 = sum(len(word) for word in lst2)\n\n if total1 < total2:\n return lst1\n elif total2 < total1:\n return lst2\n else:\n return lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n \"\"\"\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n \"\"\"\n len1 = sum(len(word) for word in lst1)\n len2 = sum(len(word) for word in lst2)\n if len1 < len2:\n return lst1\n elif len2 < len1:\n return lst2\n else:\n return lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n \"\"\"\n Write a function that accepts two lists of strings and returns the list that has\n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n \"\"\"\n total_chars1 = sum(len(word) for word in lst1)\n total_chars2 = sum(len(word) for word in lst2)\n if total_chars1 < total_chars2:\n return lst1\n elif total_chars2 < total_chars1:\n return lst2\n else:\n return lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n sum1 = sum(len(word) for word in lst1)\n sum2 = sum(len(word) for word in lst2)\n \n if sum1 < sum2:\n return lst1\n elif sum2 < sum1:\n return lst2\n else:\n return lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n \"\"\"\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n \"\"\"\n total1 = sum(len(word) for word in lst1)\n total2 = sum(len(word) for word in lst2)\n if total1 < total2:\n return lst1\n elif total2 < total1:\n return lst2\n else:\n return lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n total_chars1 = sum(len(s) for s in lst1)\n total_chars2 = sum(len(s) for s in lst2)\n if total_chars1 < total_chars2:\n return lst1\n elif total_chars2 < total_chars1:\n return lst2\n else:\n return lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n \"\"\"\n Write a function that accepts two lists of strings and returns the list that has\n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n \"\"\"\n total1 = sum(len(word) for word in lst1)\n total2 = sum(len(word) for word in lst2)\n \n if total1 < total2:\n return lst1\n elif total2 < total1:\n return lst2\n else: \n return lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n total1 = sum(len(s) for s in lst1)\n total2 = sum(len(s) for s in lst2)\n if total1 < total2:\n return lst1\n elif total2 < total1:\n return lst2\n else:\n return lst1", "matching_cluster_idx": 7}]}, "HumanEval/85": {"dps": 97.02970297029702, "dps_norm": 66.66666666666667, "pass@1": 100.0, "profiled": [{"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices..\n\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n sum = 0\n for i in range(1, len(lst), 2):\n if lst[i] % 2 == 0:\n sum += lst[i]\n return sum", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices..\n\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n sum = 0\n for i in range(1, len(lst), 2):\n if lst[i] % 2 == 0:\n sum += lst[i]\n return sum", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices..\n\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n total = 0\n for i in range(1, len(lst), 2):\n if lst[i] % 2 == 0:\n total += lst[i]\n return total", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n sum = 0\n for i in range(1, len(lst), 2):\n if lst[i] % 2 == 0:\n sum += lst[i]\n return sum", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices..\n\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n total = 0\n for i in range(1, len(lst), 2):\n if lst[i] % 2 == 0:\n total += lst[i]\n return total", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices..\n\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n total = 0\n for i in range(1, len(lst), 2):\n if lst[i] % 2 == 0:\n total += lst[i]\n return total", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices..\n\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n sum = 0\n for i in range(1, len(lst), 2):\n if lst[i] % 2 == 0:\n sum += lst[i]\n return sum", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices..\n\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n sum = 0\n for i in range(1,len(lst),2):\n if lst[i]%2 == 0:\n sum += lst[i]\n return sum", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices..\n\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n sum = 0\n for i in range(1, len(lst), 2):\n if lst[i] % 2 == 0:\n sum += lst[i]\n return sum", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices..\n\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n sum = 0\n for i in range(1, len(lst), 2):\n if lst[i] % 2 == 0:\n sum += lst[i]\n return sum", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices.\n\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n sum = 0\n for i in range(1, len(lst), 2): \n if lst[i] % 2 == 0:\n sum += lst[i]\n return sum", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices..\n\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n sum = 0\n for i in range(1, len(lst), 2):\n if lst[i] % 2 == 0:\n sum += lst[i]\n return sum", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices..\n\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n total = 0\n for i in range(1, len(lst), 2):\n if lst[i] % 2 == 0:\n total += lst[i]\n return total", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices.\n\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n sum = 0\n for i in range(1, len(lst), 2):\n if lst[i] % 2 == 0:\n sum += lst[i]\n return sum", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices..\n\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n sum = 0\n for i in range(1, len(lst), 2):\n if lst[i] % 2 == 0:\n sum += lst[i]\n return sum", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices..\n\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n sum = 0\n for i in range(1, len(lst), 2):\n if lst[i] % 2 == 0:\n sum += lst[i]\n return sum", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices..\n\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n sum = 0\n for i in range(1, len(lst), 2):\n if lst[i] % 2 == 0:\n sum += lst[i]\n return sum", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices..\n\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n sum = 0\n for i in range(1, len(lst), 2):\n if lst[i] % 2 == 0:\n sum += lst[i]\n return sum", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices..\n\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n sum = 0\n for i in range(1,len(lst),2):\n if lst[i]%2 == 0:\n sum+=lst[i]\n return sum", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices.\n\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n sum = 0\n for i in range(1, len(lst), 2):\n if lst[i] % 2 == 0:\n sum += lst[i]\n return sum", "matching_cluster_idx": 3}]}, "HumanEval/86": {"dps": null, "dps_norm": null, "pass@1": 0.0, "profiled": []}, "HumanEval/87": {"dps": 52.377521613832855, "dps_norm": 47.857142857142854, "pass@1": 21.0, "profiled": [{"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n result = []\n for row_index, row in enumerate(lst):\n for col_index, element in enumerate(row):\n if element == x:\n result.append((row_index, col_index))\n result.sort(key=lambda item: item[0]) # Sort by row\n for row_index in range(len(result)):\n for j in range(row_index + 1, len(result)):\n if result[row_index][0] == result[j][0]:\n if result[row_index][1] < result[j][1]:\n result[row_index], result[j] = result[j], result[row_index]\n return result", "matching_cluster_idx": 2}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n result = []\n for row_index, row in enumerate(lst):\n for col_index, element in enumerate(row):\n if element == x:\n result.append((row_index, col_index))\n result.sort(key=lambda x: (x[0], -x[1])) # Sort by row ascending, then column descending\n return result", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n result = []\n for row_index, row in enumerate(lst):\n for col_index, value in enumerate(row):\n if value == x:\n result.append((row_index, col_index))\n result.sort(key=lambda item: item[0]) # Sort by row\n for row_index in range(len(result)):\n for other_row_index in range(row_index + 1, len(result)):\n if result[row_index][0] == result[other_row_index][0]:\n if result[row_index][1] < result[other_row_index][1]:\n result[row_index], result[other_row_index] = result[other_row_index], result[row_index]\n return result", "matching_cluster_idx": 2}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n result = []\n for row_index, row in enumerate(lst):\n for col_index, element in enumerate(row):\n if element == x:\n result.append((row_index, col_index))\n result.sort(key=lambda item: (item[0], -item[1])) \n return result", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n result = []\n for row_index, row in enumerate(lst):\n for col_index, value in enumerate(row):\n if value == x:\n result.append((row_index, col_index))\n result.sort(key=lambda item: item[0]) # Sort by row\n for row_index in range(len(result)):\n for inner_index in range(len(result) - 1 - row_index):\n if result[inner_index][0] == result[inner_index + 1][0] and result[inner_index][1] < result[inner_index + 1][1]:\n result[inner_index], result[inner_index + 1] = result[inner_index + 1], result[inner_index]\n return result", "matching_cluster_idx": 2}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n result = []\n for row_index, row in enumerate(lst):\n for col_index, value in enumerate(row):\n if value == x:\n result.append((row_index, col_index))\n result.sort(key=lambda item: item[0]) \n for row_index in range(len(result)):\n for col_index in range(len(result)-1):\n if result[col_index][0] == result[col_index + 1][0] and result[col_index][1] < result[col_index + 1][1]:\n result[col_index], result[col_index + 1] = result[col_index + 1], result[col_index]\n return result", "matching_cluster_idx": 0}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n result = []\n for row_index, row in enumerate(lst):\n for col_index, element in enumerate(row):\n if element == x:\n result.append((row_index, col_index))\n result.sort(key=lambda item: item[0]) # Sort by row\n for row_index in range(len(result)):\n for col_index in range(row_index + 1, len(result)):\n if result[row_index][0] == result[col_index][0] and result[row_index][1] < result[col_index][1]:\n result[row_index], result[col_index] = result[col_index], result[row_index]\n return result", "matching_cluster_idx": 2}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n result = []\n for row_index, row in enumerate(lst):\n for col_index, element in enumerate(row):\n if element == x:\n result.append((row_index, col_index))\n result.sort(key=lambda x: x[0]) # Sort by row\n for row_index in range(len(result)):\n for j in range(row_index+1, len(result)):\n if result[row_index][0] == result[j][0]:\n if result[row_index][1] < result[j][1]:\n result[row_index], result[j] = result[j], result[row_index]\n return result", "matching_cluster_idx": 2}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n result = []\n for row_index, row in enumerate(lst):\n for col_index, element in enumerate(row):\n if element == x:\n result.append((row_index, col_index))\n result.sort(key=lambda item: (item[0], -item[1]))\n return result", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n result = []\n for row_index, row in enumerate(lst):\n for col_index, element in enumerate(row):\n if element == x:\n result.append((row_index, col_index))\n result.sort(key=lambda item: (item[0], -item[1])) \n return result", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n result = []\n for row_index, row in enumerate(lst):\n for col_index, value in enumerate(row):\n if value == x:\n result.append((row_index, col_index))\n result.sort(key=lambda x: (x[0], -x[1]))\n return result", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n result = []\n for row_index, row in enumerate(lst):\n for col_index, value in enumerate(row):\n if value == x:\n result.append((row_index, col_index))\n return sorted(result, key=lambda item: (item[0], -item[1]))", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n result = []\n for row_index, row in enumerate(lst):\n for col_index, element in enumerate(row):\n if element == x:\n result.append((row_index, col_index))\n result.sort(key=lambda item: item[0]) # Sort by row\n for row_index in range(len(result)):\n for j in range(row_index + 1, len(result)):\n if result[row_index][0] == result[j][0]:\n if result[row_index][1] < result[j][1]:\n result[row_index], result[j] = result[j], result[row_index]\n return result", "matching_cluster_idx": 2}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n result = []\n for row_index, row in enumerate(lst):\n for col_index, element in enumerate(row):\n if element == x:\n result.append((row_index, col_index))\n result.sort(key=lambda item: item[0]) # Sort by row\n for row_index in range(len(result)):\n for j in range(row_index + 1, len(result)):\n if result[row_index][0] == result[j][0] and result[row_index][1] < result[j][1]:\n result[row_index], result[j] = result[j], result[row_index] # Sort by column\n return result", "matching_cluster_idx": 2}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n coordinates = []\n for row_index, row in enumerate(lst):\n for col_index, value in enumerate(row):\n if value == x:\n coordinates.append((row_index, col_index))\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n result = []\n for row_index, row in enumerate(lst):\n for col_index, value in enumerate(row):\n if value == x:\n result.append((row_index, col_index))\n result.sort(key=lambda item: item[0]) # Sort by row\n for row_index in range(len(result)):\n for j in range(row_index+1, len(result)):\n if result[row_index][0] == result[j][0]:\n if result[row_index][1] < result[j][1]:\n result[row_index], result[j] = result[j], result[row_index]\n return result", "matching_cluster_idx": 2}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n result = []\n for row_index, row in enumerate(lst):\n for col_index, element in enumerate(row):\n if element == x:\n result.append((row_index, col_index))\n return sorted(result, key=lambda item: (item[0], -item[1]))", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n result = []\n for row_index, row in enumerate(lst):\n for col_index, element in enumerate(row):\n if element == x:\n result.append((row_index, col_index))\n result.sort(key=lambda x: x[0]) # Sort by row\n for row_index in range(len(result)):\n for i in range(row_index + 1, len(result)):\n if result[row_index][0] == result[i][0]:\n if result[row_index][1] < result[i][1]:\n result[row_index], result[i] = result[i], result[row_index]\n return result", "matching_cluster_idx": 2}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n result = []\n for row_index, row in enumerate(lst):\n for col_index, element in enumerate(row):\n if element == x:\n result.append((row_index, col_index))\n result.sort(key=lambda item: item[0]) \n for row_index in range(len(result)):\n for j in range(row_index + 1, len(result)):\n if result[row_index][0] == result[j][0]:\n if result[row_index][1] < result[j][1]:\n result[row_index], result[j] = result[j], result[row_index]\n return result", "matching_cluster_idx": 2}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n result = []\n for row_index, row in enumerate(lst):\n for col_index, element in enumerate(row):\n if element == x:\n result.append((row_index, col_index))\n return sorted(result, key=lambda item: (item[0], -item[1]))", "matching_cluster_idx": 3}]}, "HumanEval/89": {"dps": 96.64948453608248, "dps_norm": 28.571428571428573, "pass@1": 48.0, "profiled": [{"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n result = ''\n for char in s:\n if char.isalpha():\n start = ord('a') if char.islower() else ord('A')\n shifted_char = chr((ord(char) - start + 4) % 26 + start)\n else:\n shifted_char = char\n result += shifted_char\n return result", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n result = []\n for char in s:\n if char.isalpha():\n start = ord('a') if char.islower() else ord('A')\n shifted_char = chr((ord(char) - start + 4) % 26 + start)\n else:\n shifted_char = char\n result.append(shifted_char)\n return ''.join(result)", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n result = ''\n for char in s:\n if char.isalpha():\n start = ord('a') if char.islower() else ord('A')\n shifted_char = chr((ord(char) - start + 4) % 26 + start)\n else:\n shifted_char = char\n result += shifted_char\n return result", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n result = ''\n for letter in s:\n if letter.isalpha():\n start = ord('a') if letter.islower() else ord('A')\n shifted_letter = chr((ord(letter) - start + 4) % 26 + start)\n else:\n shifted_letter = letter\n result += shifted_letter\n return result", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n result = ''\n for char in s:\n if char.isalpha():\n start = ord('a') if char.islower() else ord('A')\n shifted_char = chr((ord(char) - start + 4) % 26 + start)\n else:\n shifted_char = char\n result += shifted_char\n return result", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n result = []\n for char in s:\n if char.isalpha():\n start = ord('a') if char.islower() else ord('A')\n shifted_char = chr((ord(char) - start + 4) % 26 + start)\n else:\n shifted_char = char\n result.append(shifted_char)\n return ''.join(result)", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n result = ''\n for char in s:\n if char.isalpha():\n start = ord('a') if char.islower() else ord('A')\n shifted_char = chr((ord(char) - start + 4) % 26 + start)\n else:\n shifted_char = char\n result += shifted_char\n return result", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n result = ''\n for char in s:\n if char.isalpha():\n start = ord('a') if char.islower() else ord('A')\n shifted_char = chr((ord(char) - start + 4) % 26 + start)\n else:\n shifted_char = char\n result += shifted_char\n return result", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n result = ''\n for char in s:\n if char.isalpha():\n start = ord('a') if char.islower() else ord('A')\n shifted_char = chr((ord(char) - start + 4) % 26 + start)\n else:\n shifted_char = char\n result += shifted_char\n return result", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n result = []\n for char in s:\n if char.isalpha():\n start = ord('a') if char.islower() else ord('A')\n shifted_char = chr((ord(char) - start + 4) % 26 + start)\n else:\n shifted_char = char\n result.append(shifted_char)\n return ''.join(result)", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n result = ''\n for char in s:\n if char.isalpha():\n start = ord('a') if char.islower() else ord('A')\n shifted_char = chr((ord(char) - start + 4) % 26 + start)\n else:\n shifted_char = char\n result += shifted_char\n return result", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n result = ''\n for char in s:\n if char.isalpha():\n start = ord('a') if char.islower() else ord('A')\n shifted_char = chr((ord(char) - start + 4) % 26 + start)\n else:\n shifted_char = char\n result += shifted_char\n return result", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n result = ''\n for char in s:\n if char.isalpha():\n start = ord('a') if char.islower() else ord('A')\n shifted_char = chr((ord(char) - start + 4) % 26 + start)\n else:\n shifted_char = char\n result += shifted_char\n return result", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n result = ''\n for char in s:\n if char.isalpha():\n start = ord('a') if char.islower() else ord('A')\n shifted_char = chr((ord(char) - start + 4) % 26 + start)\n else:\n shifted_char = char\n result += shifted_char\n return result", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n result = ''\n for char in s:\n if char.isalpha():\n start = ord('a') if char.islower() else ord('A')\n shifted_char = chr((ord(char) - start + 4) % 26 + start)\n else:\n shifted_char = char\n result += shifted_char\n return result", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n result = ''\n for char in s:\n if char.isalpha():\n start = ord('a') if char.islower() else ord('A')\n shifted_char = chr((ord(char) - start + 4) % 26 + start) \n else:\n shifted_char = char\n result += shifted_char\n return result", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n result = ''\n for char in s:\n if char.isalpha():\n start = ord('a') if char.islower() else ord('A')\n shifted_char = chr((ord(char) - start + 4) % 26 + start)\n else:\n shifted_char = char\n result += shifted_char\n return result", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n result = ''\n for letter in s:\n if letter.isalpha():\n start = ord('a') if letter.islower() else ord('A')\n shifted_letter = chr((ord(letter) - start + 4) % 26 + start)\n else:\n shifted_letter = letter\n result += shifted_letter\n return result", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n result = []\n for char in s:\n if char.isalpha():\n start = ord('a') if char.islower() else ord('A')\n shifted_char = chr((ord(char) - start + 4) % 26 + start)\n else:\n shifted_char = char\n result.append(shifted_char)\n return ''.join(result)", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n result = ''\n for letter in s:\n if letter.isalpha():\n start = ord('a') if letter.islower() else ord('A')\n shifted_letter = chr((ord(letter) - start + 4) % 26 + start)\n else:\n shifted_letter = letter\n result += shifted_letter\n return result", "matching_cluster_idx": 1}]}, "HumanEval/90": {"dps": null, "dps_norm": null, "pass@1": 5.0, "profiled": []}, "HumanEval/113": {"dps": null, "dps_norm": null, "pass@1": 3.0, "profiled": []}, "HumanEval/119": {"dps": null, "dps_norm": null, "pass@1": 0.0, "profiled": []}, "HumanEval/120": {"dps": null, "dps_norm": null, "pass@1": 0.0, "profiled": []}, "HumanEval/121": {"dps": null, "dps_norm": null, "pass@1": 0.0, "profiled": []}, "HumanEval/149": {"dps": 85.82677165354332, "dps_norm": 57.142857142857146, "pass@1": 100.0, "profiled": [{"solution": "def sorted_list_sum(lst):\n \"\"\"Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order,\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n You may assume that all words will have the same length.\n For example:\n assert list_sort([\"aa\", \"a\", \"aaa\"]) => [\"aa\"]\n assert list_sort([\"ab\", \"a\", \"aaa\", \"cd\"]) => [\"ab\", \"cd\"]\n \"\"\"\n result = [word for word in lst if len(word) % 2 == 0]\n result.sort(key=lambda word: (len(word), word))\n return result", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order,\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n You may assume that all words will have the same length.\n For example:\n assert list_sort([\"aa\", \"a\", \"aaa\"]) => [\"aa\"]\n assert list_sort([\"ab\", \"a\", \"aaa\", \"cd\"]) => [\"ab\", \"cd\"]\n \"\"\"\n filtered_lst = [word for word in lst if len(word) % 2 == 0]\n return sorted(filtered_lst, key=lambda word: (len(word), word))", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order,\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n You may assume that all words will have the same length.\n For example:\n assert list_sort([\"aa\", \"a\", \"aaa\"]) => [\"aa\"]\n assert list_sort([\"ab\", \"a\", \"aaa\", \"cd\"]) => [\"ab\", \"cd\"]\n \"\"\"\n result = [word for word in lst if len(word) % 2 == 0]\n result.sort(key=lambda word: (len(word), word))\n return result", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order,\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n You may assume that all words will have the same length.\n For example:\n assert list_sort([\"aa\", \"a\", \"aaa\"]) => [\"aa\"]\n assert list_sort([\"ab\", \"a\", \"aaa\", \"cd\"]) => [\"ab\", \"cd\"]\n \"\"\"\n result = [word for word in lst if len(word) % 2 == 0]\n result.sort(key=lambda x: (len(x), x))\n return result", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order,\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n You may assume that all words will have the same length.\n For example:\n assert list_sort([\"aa\", \"a\", \"aaa\"]) => [\"aa\"]\n assert list_sort([\"ab\", \"a\", \"aaa\", \"cd\"]) => [\"ab\", \"cd\"]\n \"\"\"\n result = [word for word in lst if len(word) % 2 == 0]\n result.sort(key=lambda word: (len(word), word))\n return result", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order,\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n You may assume that all words will have the same length.\n For example:\n assert list_sort([\"aa\", \"a\", \"aaa\"]) => [\"aa\"]\n assert list_sort([\"ab\", \"a\", \"aaa\", \"cd\"]) => [\"ab\", \"cd\"]\n \"\"\"\n filtered_list = [word for word in lst if len(word) % 2 == 0]\n return sorted(filtered_list, key=lambda word: (len(word), word))", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order,\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n You may assume that all words will have the same length.\n For example:\n assert list_sort([\"aa\", \"a\", \"aaa\"]) => [\"aa\"]\n assert list_sort([\"ab\", \"a\", \"aaa\", \"cd\"]) => [\"ab\", \"cd\"]\n \"\"\"\n return sorted([word for word in lst if len(word) % 2 == 0], key=lambda word: (len(word), word))", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order,\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n You may assume that all words will have the same length.\n For example:\n assert list_sort([\"aa\", \"a\", \"aaa\"]) => [\"aa\"]\n assert list_sort([\"ab\", \"a\", \"aaa\", \"cd\"]) => [\"ab\", \"cd\"]\n \"\"\"\n result = [word for word in lst if len(word) % 2 == 0]\n result.sort(key=lambda word: (len(word), word))\n return result", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order,\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n You may assume that all words will have the same length.\n For example:\n assert list_sort([\"aa\", \"a\", \"aaa\"]) => [\"aa\"]\n assert list_sort([\"ab\", \"a\", \"aaa\", \"cd\"]) => [\"ab\", \"cd\"]\n \"\"\"\n result = [word for word in lst if len(word) % 2 == 0]\n result.sort(key=lambda word: (len(word), word))\n return result", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order,\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n You may assume that all words will have the same length.\n For example:\n assert list_sort([\"aa\", \"a\", \"aaa\"]) => [\"aa\"]\n assert list_sort([\"ab\", \"a\", \"aaa\", \"cd\"]) => [\"ab\", \"cd\"]\n \"\"\"\n result = [word for word in lst if len(word) % 2 == 0]\n result.sort(key=lambda word: (len(word), word))\n return result", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order,\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n You may assume that all words will have the same length.\n For example:\n assert list_sort([\"aa\", \"a\", \"aaa\"]) => [\"aa\"]\n assert list_sort([\"ab\", \"a\", \"aaa\", \"cd\"]) => [\"ab\", \"cd\"]\n \"\"\"\n filtered_list = [word for word in lst if len(word) % 2 == 0]\n return sorted(filtered_list, key=lambda word: (len(word), word))", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order,\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n You may assume that all words will have the same length.\n For example:\n assert list_sort([\"aa\", \"a\", \"aaa\"]) => [\"aa\"]\n assert list_sort([\"ab\", \"a\", \"aaa\", \"cd\"]) => [\"ab\", \"cd\"]\n \"\"\"\n result = [word for word in lst if len(word) % 2 == 0]\n result.sort(key=lambda word: (len(word), word)) \n return result", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order,\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n You may assume that all words will have the same length.\n For example:\n assert list_sort([\"aa\", \"a\", \"aaa\"]) => [\"aa\"]\n assert list_sort([\"ab\", \"a\", \"aaa\", \"cd\"]) => [\"ab\", \"cd\"]\n \"\"\"\n result = [word for word in lst if len(word) % 2 == 0]\n result.sort(key=lambda word: (len(word), word)) \n return result", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order,\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n You may assume that all words will have the same length.\n For example:\n assert list_sort([\"aa\", \"a\", \"aaa\"]) => [\"aa\"]\n assert list_sort([\"ab\", \"a\", \"aaa\", \"cd\"]) => [\"ab\", \"cd\"]\n \"\"\"\n result = [word for word in lst if len(word) % 2 == 0]\n result.sort(key=lambda word: (len(word), word))\n return result", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order,\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n You may assume that all words will have the same length.\n For example:\n assert list_sort([\"aa\", \"a\", \"aaa\"]) => [\"aa\"]\n assert list_sort([\"ab\", \"a\", \"aaa\", \"cd\"]) => [\"ab\", \"cd\"]\n \"\"\"\n result = [word for word in lst if len(word) % 2 == 0]\n result.sort(key=lambda word: (len(word), word))\n return result", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order,\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n You may assume that all words will have the same length.\n For example:\n assert list_sort([\"aa\", \"a\", \"aaa\"]) => [\"aa\"]\n assert list_sort([\"ab\", \"a\", \"aaa\", \"cd\"]) => [\"ab\", \"cd\"]\n \"\"\"\n result = [word for word in lst if len(word) % 2 == 0]\n result.sort(key=lambda word: (len(word), word))\n return result", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order,\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n You may assume that all words will have the same length.\n For example:\n assert list_sort([\"aa\", \"a\", \"aaa\"]) => [\"aa\"]\n assert list_sort([\"ab\", \"a\", \"aaa\", \"cd\"]) => [\"ab\", \"cd\"]\n \"\"\"\n return sorted(\n [word for word in lst if len(word) % 2 == 0],\n key=lambda word: (len(word), word)\n )", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order,\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n You may assume that all words will have the same length.\n For example:\n assert list_sort([\"aa\", \"a\", \"aaa\"]) => [\"aa\"]\n assert list_sort([\"ab\", \"a\", \"aaa\", \"cd\"]) => [\"ab\", \"cd\"]\n \"\"\"\n result = [word for word in lst if len(word) % 2 == 0]\n result.sort(key=lambda word: (len(word), word))\n return result", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order,\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n You may assume that all words will have the same length.\n For example:\n assert list_sort([\"aa\", \"a\", \"aaa\"]) => [\"aa\"]\n assert list_sort([\"ab\", \"a\", \"aaa\", \"cd\"]) => [\"ab\", \"cd\"]\n \"\"\"\n result = [word for word in lst if len(word) % 2 == 0]\n result.sort(key=lambda word: (len(word), word))\n return result", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order,\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n You may assume that all words will have the same length.\n For example:\n assert list_sort([\"aa\", \"a\", \"aaa\"]) => [\"aa\"]\n assert list_sort([\"ab\", \"a\", \"aaa\", \"cd\"]) => [\"ab\", \"cd\"]\n \"\"\"\n result = [word for word in lst if len(word) % 2 == 0]\n result.sort(key=lambda word: (len(word), word))\n return result", "matching_cluster_idx": 3}]}, "Mbpp/3": {"dps": 55.932203389830505, "dps_norm": 75.0, "pass@1": 100.0, "profiled": [{"solution": "def is_not_prime(n):\n \"\"\"\n Identifies if a number is not a prime number.\n\n Args:\n n: The number to check.\n\n Returns:\n True if n is not a prime number, False otherwise.\n \"\"\"\n if n <= 1:\n return True\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return True\n return False", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(n):\n \"\"\"\n Identifies non-prime numbers.\n\n Args:\n n: An integer.\n\n Returns:\n True if n is not a prime number, False otherwise.\n \"\"\"\n if n <= 1:\n return True\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return True\n return False", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(n):\n \"\"\"\n Identifies if a number is not a prime number.\n\n Args:\n n: The number to check.\n\n Returns:\n True if n is not a prime number, False otherwise.\n \"\"\"\n if n <= 1:\n return True\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return True\n return False", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(num):\n \"\"\"\n Identifies non-prime numbers.\n\n Args:\n num: The number to check.\n\n Returns:\n True if the number is not prime, False otherwise.\n \"\"\"\n if num <= 1:\n return True\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n return True\n return False", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(n):\n \"\"\"\n Identify if a number is not a prime number.\n\n Args:\n n: An integer.\n\n Returns:\n True if n is not a prime number, False otherwise.\n \"\"\"\n if n <= 1:\n return True\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return True\n return False", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(num):\n \"\"\"\n This function checks if a given number is not a prime number.\n\n Args:\n num: An integer.\n\n Returns:\n True if the number is not prime, False otherwise.\n \"\"\"\n if num <= 1:\n return True\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n return True\n return False", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(number):\n \"\"\"\n Identifies if a number is not a prime number.\n\n Args:\n number: The number to check.\n\n Returns:\n True if the number is not a prime number, False otherwise.\n \"\"\"\n if number <= 1:\n return True\n for i in range(2, int(number**0.5) + 1):\n if number % i == 0:\n return True\n return False", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(n):\n \"\"\"\n Identifies non-prime numbers.\n\n Args:\n n: An integer.\n\n Returns:\n True if n is not a prime number, False otherwise.\n \"\"\"\n if n <= 1:\n return True\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return True\n return False", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(num):\n \"\"\"\n Identifies non-prime numbers.\n\n Args:\n num: The number to check.\n\n Returns:\n True if the number is not prime, False otherwise.\n \"\"\"\n if num <= 1:\n return True\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n return True\n return False", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(n):\n \"\"\"\n Identify if a number is not prime.\n\n Args:\n n: The number to check.\n\n Returns:\n True if n is not prime, False otherwise.\n \"\"\"\n if n <= 1:\n return True\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return True\n return False", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(n):\n \"\"\"\n This function checks if a number is not prime.\n\n Args:\n n: An integer.\n\n Returns:\n True if n is not prime, False otherwise.\n \"\"\"\n if n <= 1:\n return True\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return True\n return False", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(n):\n \"\"\"Identifies non-prime numbers.\n\n Args:\n n: The number to check.\n\n Returns:\n True if n is not a prime number, False otherwise.\n \"\"\"\n if n <= 1:\n return True\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return True\n return False", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(number):\n \"\"\"\n Identify if a number is not prime.\n \n Args:\n number: The number to check.\n\n Returns:\n True if the number is not prime, False otherwise.\n \"\"\"\n if number <= 1:\n return True\n for i in range(2, int(number**0.5) + 1):\n if number % i == 0:\n return True\n return False", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(num):\n \"\"\"\n Identify non-prime numbers.\n\n Args:\n num: An integer to check.\n\n Returns:\n True if num is not a prime number, False otherwise.\n \"\"\"\n if num <= 1:\n return True\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n return True\n return False", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(n):\n \"\"\"\n This function checks if a number is not prime.\n\n Args:\n n: An integer.\n\n Returns:\n True if n is not prime, False otherwise.\n \"\"\"\n if n <= 1:\n return True\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return True\n return False", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(num):\n \"\"\"\n Identify if a number is not a prime number.\n\n Args:\n num: An integer.\n\n Returns:\n True if the number is not prime, False otherwise.\n \"\"\"\n if num <= 1:\n return True\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n return True\n return False", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(n):\n \"\"\"\n Identifies if a number is not a prime number.\n\n Args:\n n: The number to check.\n\n Returns:\n True if the number is not prime, False otherwise.\n \"\"\"\n if n <= 1:\n return True\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return True\n return False", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(n):\n \"\"\"\n Determines if a number is not prime.\n\n Args:\n n: The number to check.\n\n Returns:\n True if the number is not prime, False otherwise.\n \"\"\"\n if n <= 1:\n return True \n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return True\n return False", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(n):\n \"\"\"\n Identifies if a number is not prime.\n\n Args:\n n: An integer.\n\n Returns:\n True if n is not prime, False otherwise.\n \"\"\"\n if n <= 1:\n return True\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return True\n return False", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(num):\n \"\"\"\n This function checks if a number is not prime.\n\n Args:\n num: The number to be checked.\n\n Returns:\n True if the number is not prime, False otherwise.\n \"\"\"\n if num <= 1:\n return True\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n return True\n return False", "matching_cluster_idx": 5}]}, "Mbpp/4": {"dps": 91.51877133105802, "dps_norm": 82.91666666666666, "pass@1": 100.0, "profiled": [{"solution": "import heapq\ndef heap_queue_largest(nums, n):\n \"\"\"\n Finds the n largest integers from a given list of numbers, returned in descending order.\n\n Args:\n nums: A list of integers.\n n: The number of largest integers to return.\n\n Returns:\n A list of the n largest integers in descending order.\n \"\"\"\n return heapq.nlargest(n, nums)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n \"\"\"\n Finds the n largest integers from a given list of numbers, returned in descending order.\n\n Args:\n nums: A list of integers.\n n: The number of largest integers to return.\n\n Returns:\n A list containing the n largest integers in descending order.\n \"\"\"\n return heapq.nlargest(n, nums)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n \"\"\"\n Finds the n largest integers from a list, in descending order, using a heap.\n\n Args:\n nums: A list of integers.\n n: The number of largest integers to find.\n\n Returns:\n A list of the n largest integers in descending order.\n \"\"\"\n return heapq.nlargest(n, nums)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n \"\"\"\n Finds the n largest integers from a given list of numbers, returned in descending order.\n\n Args:\n nums: A list of integers.\n n: The number of largest integers to return.\n\n Returns:\n A list of the n largest integers in descending order.\n \"\"\"\n return heapq.nlargest(n, nums)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n \"\"\"\n Finds the n largest integers from a given list of numbers, returned in descending order.\n\n Args:\n nums: A list of integers.\n n: The number of largest integers to return.\n\n Returns:\n A list of the n largest integers from nums, sorted in descending order.\n \"\"\"\n return heapq.nlargest(n, nums)", "matching_cluster_idx": 8}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n \"\"\"\n Finds the n largest integers from a given list of numbers, returned in descending order.\n\n Args:\n nums: A list of integers.\n n: The number of largest integers to find.\n\n Returns:\n A list of the n largest integers in descending order.\n \"\"\"\n return heapq.nlargest(n, nums)\nnums = [25, 35, 22, 85, 14, 65, 75, 22, 58]\nn = 3", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n \"\"\"\n Finds the n largest integers from a given list of numbers, returned in descending order.\n\n Args:\n nums: A list of integers.\n n: The number of largest integers to return.\n\n Returns:\n A list of the n largest integers in descending order.\n \"\"\"\n return heapq.nlargest(n, nums)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n \"\"\"\n Finds the n largest integers from a given list of numbers, returned in descending order.\n\n Args:\n nums: A list of numbers.\n n: The number of largest integers to return.\n\n Returns:\n A list of the n largest integers in descending order.\n \"\"\"\n return heapq.nlargest(n, nums)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n \"\"\"\n Find the n largest integers from a given list of numbers, returned in descending order.\n\n Args:\n nums: A list of integers.\n n: The number of largest integers to find.\n\n Returns:\n A list of the n largest integers in descending order.\n \"\"\"\n return heapq.nlargest(n, nums)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n \"\"\"\n Finds the n largest integers from a given list of numbers, returned in descending order.\n\n Args:\n nums: A list of numbers.\n n: The number of largest integers to return.\n\n Returns:\n A list of the n largest integers in descending order.\n \"\"\"\n return heapq.nlargest(n, nums)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n \"\"\"\n Finds the n largest integers from a given list of numbers, returned in descending order.\n\n Args:\n nums: A list of integers.\n n: The number of largest integers to return.\n\n Returns:\n A list of the n largest integers in descending order.\n \"\"\"\n return heapq.nlargest(n, nums)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n return heapq.nlargest(n, nums)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n \"\"\"\n Find the n largest integers from a given list of numbers, returned in descending order.\n\n Args:\n nums: A list of integers.\n n: The number of largest integers to return.\n\n Returns:\n A list of the n largest integers from nums, sorted in descending order.\n \"\"\"\n return heapq.nlargest(n, nums)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n \"\"\"\n Find the n largest integers from a given list of numbers, returned in descending order.\n\n Args:\n nums: A list of integers.\n n: The number of largest integers to return.\n\n Returns:\n A list of the n largest integers from nums, sorted in descending order.\n \"\"\"\n return heapq.nlargest(n, nums)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n \"\"\"\n Finds the n largest integers from a given list of numbers, returned in descending order.\n\n Args:\n nums: A list of integers.\n n: The number of largest integers to return.\n\n Returns:\n A list of the n largest integers in descending order.\n \"\"\"\n return heapq.nlargest(n, nums)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n \"\"\"\n Finds the n largest integers from a given list of numbers, \n returned in descending order.\n \n Args:\n nums: A list of integers.\n n: The number of largest integers to return.\n\n Returns:\n A list of the n largest integers in descending order.\n \"\"\"\n return heapq.nlargest(n, nums)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n \"\"\"\n Finds the n largest integers from a given list of numbers, returned in descending order.\n \"\"\"\n return heapq.nlargest(n, nums)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n \"\"\"\n Finds the n largest integers from a given list of numbers, \n returned in descending order.\n\n Args:\n nums: A list of integers.\n n: The number of largest integers to find.\n\n Returns:\n A list of the n largest integers in descending order.\n \"\"\"\n return heapq.nlargest(n, nums)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n \"\"\"\n Finds the n largest integers from a given list of numbers, returned in descending order.\n\n Args:\n nums: A list of integers.\n n: The number of largest integers to find.\n\n Returns:\n A list containing the n largest integers in descending order.\n \"\"\"\n return heapq.nlargest(n, nums)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n \"\"\"\n Finds the n largest integers from a given list of numbers, returned in descending order.\n\n Args:\n nums: A list of integers.\n n: The number of largest integers to return.\n\n Returns:\n A list of the n largest integers in descending order.\n \"\"\"\n return heapq.nlargest(n, nums)", "matching_cluster_idx": 9}]}, "Mbpp/9": {"dps": 50.34013605442177, "dps_norm": 50.0, "pass@1": 97.0, "profiled": [{"solution": "def find_Rotations(str1):\n \"\"\"\n Finds the minimum number of rotations required to get the same string.\n \n Args:\n str1: The input string.\n \n Returns:\n The minimum number of rotations required.\n \"\"\"\n n = len(str1)\n for i in range(1, n):\n temp = str1[i:] + str1[:i]\n if temp == str1:\n return i\n return n", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(str1):\n \"\"\"\n Finds the minimum number of rotations required to get the same string.\n\n Args:\n str1: The input string.\n\n Returns:\n The minimum number of rotations required.\n \"\"\"\n n = len(str1)\n for i in range(1, n):\n temp = str1[i:] + str1[:i] \n if (temp == str1):\n return i\n return n", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(str1):\n \"\"\"\n Find the minimum number of rotations (greater than 0) required to get the same string.\n \"\"\"\n n = len(str1)\n for i in range(1, n):\n temp = str1[i:] + str1[:i]\n if temp == str1:\n return i\n\n return n", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(s):\n \"\"\"\n Finds the minimum number of rotations required to make the string the same.\n\n Args:\n s: The input string.\n\n Returns:\n The minimum number of rotations required.\n \"\"\"\n n = len(s)\n for i in range(1, n):\n temp = s[i:] + s[:i]\n if temp == s:\n return i\n return n", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(s: str) -> int:\n \"\"\"\n Find the minimum number of rotations (greater than 0) required to get the same string.\n \n Args:\n s (str): The input string.\n \n Returns:\n int: The minimum number of rotations required.\n\n Examples:\n find_Rotations(\"aaaa\") == 1\n \"\"\"\n n = len(s)\n for i in range(1, n):\n if s == s[i:] + s[:i]:\n return i\n return n", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(str1):\n n = len(str1)\n for i in range(1, n):\n temp = str1[i:] + str1[:i]\n if temp == str1:\n return i\n return n", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(string):\n \"\"\"\n Finds the minimum number of rotations required to get the same string.\n\n Args:\n string: The input string.\n\n Returns:\n The minimum number of rotations required, greater than 0.\n \"\"\"\n\n n = len(string)\n for i in range(1, n):\n temp = string[i:] + string[:i]\n if temp == string:\n return i\n return n", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(str1):\n \"\"\"\n Finds the minimum number of rotations required to get the same string.\n\n Args:\n str1: The input string.\n\n Returns:\n The minimum number of rotations required.\n \"\"\"\n n = len(str1)\n for i in range(1, n):\n temp = str1[i:] + str1[:i]\n if temp == str1:\n return i\n return n", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(s):\n \"\"\"\n Finds the minimum number of rotations required to get the same string.\n\n Args:\n s: The input string.\n\n Returns:\n The minimum number of rotations required.\n \"\"\"\n n = len(s)\n for i in range(1, n):\n temp = s[i:] + s[:i]\n if temp == s:\n return i\n return n", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(string):\n \"\"\"\n Finds the minimum number of rotations required to get the same string.\n\n Args:\n string: The input string.\n\n Returns:\n The minimum number of rotations required.\n \"\"\"\n n = len(string)\n for i in range(1, n):\n rotated_string = string[i:] + string[:i]\n if rotated_string == string:\n return i\n return n", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(str1):\n \"\"\"\n Find the minimum number of rotations required to get the same string.\n\n Args:\n str1: A string.\n\n Returns:\n The minimum number of rotations required to get the same string.\n \"\"\"\n n = len(str1)\n for i in range(1, n):\n temp = str1[i:] + str1[:i] \n if temp == str1:\n return i\n return n", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(str1):\n \"\"\"\n Finds the minimum number of rotations required to get the same string.\n \n Args:\n str1: The input string.\n \n Returns:\n The minimum number of rotations.\n \"\"\"\n n = len(str1)\n for i in range(1, n):\n temp = str1[i:] + str1[:i] \n if temp == str1:\n return i\n return n", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(str1):\n n = len(str1)\n for i in range(1, n):\n temp = str1[i:] + str1[:i]\n if temp == str1:\n return i\n return n", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(str1):\n \"\"\"\n Finds the minimum number of rotations required to get the same string.\n\n Args:\n str1: The input string.\n\n Returns:\n The minimum number of rotations required.\n \"\"\"\n n = len(str1)\n for i in range(1, n):\n temp = str1[i:] + str1[:i]\n if temp == str1:\n return i\n return n", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(str1):\n n = len(str1)\n for i in range(1, n):\n temp = str1[i:] + str1[:i]\n if temp == str1:\n return i\n return n", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(str1):\n \"\"\"\n Finds the minimum number of rotations required to get the same string.\n\n Args:\n str1: The input string.\n\n Returns:\n The minimum number of rotations required.\n \"\"\"\n n = len(str1)\n for i in range(1, n):\n rotated_str = str1[i:] + str1[:i]\n if rotated_str == str1:\n return i\n return n", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(s):\n \"\"\"\n Finds the minimum number of rotations required to get the same string.\n\n Args:\n s: The input string.\n\n Returns:\n The minimum number of rotations required.\n \"\"\"\n n = len(s)\n for i in range(1, n):\n temp = s[i:] + s[:i]\n if temp == s:\n return i\n return n", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(str1):\n n = len(str1)\n for i in range(1, n):\n temp = str1[i:] + str1[:i]\n if (temp == str1):\n return i\n return n # If no rotation results in the same string", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(string):\n \"\"\"\n Finds the minimum number of rotations required to get the same string.\n\n Args:\n string (str): The input string.\n\n Returns:\n int: The minimum number of rotations required.\n \"\"\"\n n = len(string)\n for i in range(1, n):\n temp = string[i:] + string[:i]\n if temp == string:\n return i\n return n", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(str1):\n \"\"\"\n Finds the minimum number of rotations required to get the same string.\n\n Args:\n str1: The input string.\n\n Returns:\n The minimum number of rotations required.\n \"\"\"\n n = len(str1)\n for i in range(1, n):\n temp = str1[i:] + str1[:i]\n if temp == str1:\n return i \n return n", "matching_cluster_idx": 4}]}, "Mbpp/11": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 75.0, "profiled": [{"solution": "def remove_Occ(string, char):\n \"\"\"\n Removes the first and last occurrences of a given character from a string.\n\n Args:\n string: The string to modify.\n char: The character to remove.\n\n Returns:\n The string with the first and last occurrences of the character removed.\n \"\"\"\n\n first_index = string.find(char)\n last_index = string.rfind(char)\n\n if first_index == -1 or last_index == -1:\n return string # Character not found, return original string\n\n return string[:first_index] + string[first_index+1:last_index] + string[last_index+1:]", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(string, char):\n \"\"\"Removes the first and last occurrence of a given character from a string.\n\n Args:\n string: The string to modify.\n char: The character to remove.\n\n Returns:\n The string with the first and last occurrences of the character removed.\n \"\"\"\n if char not in string:\n return string\n\n first_index = string.find(char)\n last_index = string.rfind(char)\n\n if first_index == last_index:\n return string[:first_index] + string[first_index + 1:]\n else:\n return string[:first_index] + string[first_index + 1:last_index] + string[last_index + 1:]", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(str1, char):\n \"\"\"\n Removes the first and last occurrence of a given character from a string.\n\n Args:\n str1: The input string.\n char: The character to remove.\n\n Returns:\n The string with the first and last occurrences of the character removed.\n \"\"\"\n if char not in str1:\n return str1\n \n first_index = str1.find(char)\n last_index = str1.rfind(char)\n\n if first_index == last_index:\n return str1[:first_index] + str1[first_index + 1:]\n\n return str1[:first_index] + str1[first_index + 1:last_index] + str1[last_index + 1:]", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(s, c):\n \"\"\"\n Removes the first and last occurrences of a given character from a string.\n\n Args:\n s: The string to modify.\n c: The character to remove.\n\n Returns:\n The modified string with the first and last occurrences of 'c' removed.\n \"\"\"\n\n if c in s:\n first_index = s.find(c)\n last_index = s.rfind(c)\n return s[:first_index] + s[first_index + 1:last_index] + s[last_index + 1:]\n else:\n return s", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(s, c):\n \"\"\"\n Removes the first and last occurrence of a given character from a string.\n\n Args:\n s: The input string.\n c: The character to remove.\n\n Returns:\n The string with the first and last occurrences of the character removed.\n \"\"\"\n first_index = s.find(c)\n last_index = s.rfind(c)\n\n if first_index != -1 and last_index != -1:\n return s[:first_index] + s[first_index + 1:last_index] + s[last_index + 1:]\n else:\n return s", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(s,char):\n \"\"\"Removes the first and last occurrences of a given character from the string.\n\n Args:\n s: The input string.\n char: The character to remove.\n\n Returns:\n The string with the first and last occurrences of the character removed.\n \"\"\"\n if char not in s:\n return s\n \n first_index = s.find(char)\n last_index = s.rfind(char)\n\n return s[:first_index] + s[first_index + 1:last_index] + s[last_index + 1:]", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(string, char):\n \"\"\"\n Removes the first and last occurrence of a given character from the string.\n\n Args:\n string: The input string.\n char: The character to remove.\n\n Returns:\n The modified string with the first and last occurrences of the character removed.\n \"\"\"\n if char not in string:\n return string\n\n first_index = string.index(char)\n last_index = string.rindex(char)\n\n return string[:first_index] + string[first_index + 1:last_index] + string[last_index + 1:]", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(string, char):\n \"\"\"\n Removes the first and last occurrence of a given character from a string.\n\n Args:\n string: The string to modify.\n char: The character to remove.\n\n Returns:\n The string with the first and last occurrences of the character removed,\n or the original string if the character is not found.\n \"\"\"\n if char in string:\n first_index = string.find(char)\n last_index = string.rfind(char)\n if first_index != -1 and last_index != -1:\n return string[:first_index] + string[first_index + 1:last_index] + string[last_index + 1:]\n \n return string", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(string, char):\n \"\"\"\n Removes the first and last occurrence of a given character from a string.\n\n Args:\n string: The input string.\n char: The character to remove.\n\n Returns:\n The string with the first and last occurrences of the character removed.\n \"\"\"\n if char not in string:\n return string\n \n first_index = string.find(char)\n last_index = string.rfind(char)\n\n if first_index == last_index: \n return string[:first_index] + string[first_index + 1:] \n else:\n return string[:first_index] + string[first_index + 1:last_index] + string[last_index + 1:]", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(s, c):\n \"\"\"\n Removes the first and last occurrence of a given character from the string.\n\n Args:\n s: The input string.\n c: The character to remove.\n\n Returns:\n The string with the first and last occurrences of c removed.\n \"\"\"\n if c not in s:\n return s\n first_index = s.find(c)\n last_index = s.rfind(c)\n return s[:first_index] + s[first_index + 1:last_index] + s[last_index + 1:]", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(s, c):\n \"\"\"\n Removes the first and last occurrence of a given character from the string.\n\n Args:\n s: The input string.\n c: The character to remove.\n\n Returns:\n The string with the first and last occurrences of the character removed.\n \"\"\"\n first_index = s.find(c)\n last_index = s.rfind(c)\n\n if first_index != -1 and last_index != -1:\n return s[:first_index] + s[first_index + 1:last_index] + s[last_index + 1:]\n else:\n return s", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(string, char):\n \"\"\"\n Removes the first and last occurrence of a given character from a string.\n\n Args:\n string: The string to modify.\n char: The character to remove.\n\n Returns:\n The modified string with the first and last occurrences of the character removed. \n If the character does not appear in the string, returns the original string.\n \"\"\"\n if char in string:\n first_index = string.find(char)\n last_index = string.rfind(char)\n if first_index == last_index:\n return string[:first_index] + string[first_index+1:]\n return string[:first_index] + string[first_index+1:last_index] + string[last_index+1:]\n return string", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(str1, char):\n \"\"\"\n Removes the first and last occurrences of a given character from a string.\n\n Args:\n str1: The input string.\n char: The character to remove.\n\n Returns:\n The string with the first and last occurrences of char removed.\n \"\"\"\n if char not in str1:\n return str1\n first_index = str1.find(char)\n last_index = str1.rfind(char)\n return str1[:first_index] + str1[first_index+1:last_index] + str1[last_index+1:]", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(string, char):\n \"\"\"\n Removes the first and last occurrences of a given character from a string.\n\n Args:\n string: The input string.\n char: The character to remove.\n\n Returns:\n The string with the first and last occurrences of the character removed.\n \"\"\"\n first_index = string.find(char)\n last_index = string.rfind(char)\n\n if first_index == -1 or last_index == -1:\n return string \n\n return string[:first_index] + string[first_index + 1:last_index] + string[last_index + 1:]", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(s, c):\n \"\"\"\n Removes the first and last occurrences of a given character from a string.\n\n Args:\n s: The string to modify.\n c: The character to remove.\n\n Returns:\n The modified string with the first and last occurrences of c removed. \n If c is not found in the string, returns the original string.\n \"\"\"\n if c not in s:\n return s\n \n first_index = s.find(c)\n last_index = s.rfind(c)\n \n if first_index == last_index:\n return s[:first_index] + s[first_index+1:] \n else:\n return s[:first_index] + s[first_index+1:last_index] + s[last_index+1:]", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(string, char):\n \"\"\"\n Removes the first and last occurrence of a given character from the string.\n\n Args:\n string: The string to modify.\n char: The character to remove.\n\n Returns:\n The modified string with the first and last occurrences of the character removed.\n \"\"\"\n first_index = string.find(char)\n last_index = string.rfind(char)\n\n if first_index == -1 or last_index == -1:\n return string # Character not found\n\n return string[:first_index] + string[first_index + 1:last_index] + string[last_index + 1:]", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(s, char):\n \"\"\"\n Removes the first and last occurrences of a given character from the string.\n \n Args:\n s: The input string.\n char: The character to remove.\n\n Returns:\n The string with the first and last occurrences of the character removed.\n \"\"\"\n if char not in s:\n return s\n \n first_index = s.find(char)\n last_index = s.rfind(char)\n \n if first_index == last_index:\n return s[:first_index] + s[first_index+1:]\n else:\n return s[:first_index] + s[first_index+1:last_index] + s[last_index+1:]", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(string, char):\n \"\"\"\n Removes the first and last occurrences of a given character from a string.\n\n Args:\n string: The input string.\n char: The character to remove.\n\n Returns:\n The modified string with the first and last occurrences of the character removed.\n \"\"\"\n\n if char not in string:\n return string \n \n first_index = string.find(char)\n last_index = string.rfind(char)\n\n if first_index == last_index:\n return string[:first_index] + string[first_index + 1:]\n else:\n return string[:first_index] + string[first_index + 1:last_index] + string[last_index + 1:]", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(string, char):\n \"\"\"Removes the first and last occurrence of a given character from the string.\n\n Args:\n string: The input string.\n char: The character to remove.\n\n Returns:\n The string with the first and last occurrences of the character removed.\n \"\"\"\n if char not in string:\n return string\n first_index = string.find(char)\n last_index = string.rfind(char)\n return string[:first_index] + string[first_index + 1:last_index] + string[last_index + 1:]", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(string, char):\n \"\"\"\n Removes the first and last occurrence of a given character from a string.\n\n Args:\n string: The input string.\n char: The character to remove.\n\n Returns:\n The string with the first and last occurrences of the character removed.\n \"\"\"\n if char not in string:\n return string\n first_index = string.index(char)\n last_index = string.rindex(char)\n return string[:first_index] + string[first_index + 1:last_index] + string[last_index + 1:]", "matching_cluster_idx": 8}]}, "Mbpp/12": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def sort_matrix(matrix):\n \"\"\"\n Sorts a given matrix in ascending order according to the sum of its rows.\n\n Args:\n matrix: A list of lists representing the matrix.\n\n Returns:\n A new matrix sorted in ascending order by row sum.\n \"\"\"\n return sorted(matrix, key=lambda row: sum(row))", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"\n Sorts a matrix in ascending order according to the sum of its rows.\n\n Args:\n matrix: A list of lists representing the matrix.\n\n Returns:\n A new matrix with the rows sorted in ascending order based on their sum.\n \"\"\"\n\n def row_sum(row):\n return sum(row)\n\n return sorted(matrix, key=row_sum)", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"\n Sorts a given matrix in ascending order according to the sum of its rows.\n\n Args:\n matrix: A list of lists representing the matrix.\n\n Returns:\n A new list of lists representing the sorted matrix.\n \"\"\"\n return sorted(matrix, key=lambda row: sum(row))", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"\n Sorts a given matrix in ascending order according to the sum of its rows.\n\n Args:\n matrix: A list of lists representing a matrix.\n\n Returns:\n A new list of lists representing the sorted matrix.\n \"\"\"\n return sorted(matrix, key=lambda row: sum(row))", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"\n Sorts a given matrix in ascending order according to the sum of its rows.\n\n Args:\n matrix: A list of lists representing a matrix.\n\n Returns:\n A new list of lists representing the sorted matrix.\n \"\"\"\n return sorted(matrix, key=lambda row: sum(row))", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"\n Sorts a given matrix in ascending order according to the sum of its rows.\n\n Args:\n matrix: A list of lists representing the matrix.\n\n Returns:\n A new list of lists representing the sorted matrix.\n \"\"\"\n return sorted(matrix, key=lambda row: sum(row))\nmatrix = [[1, 2, 3], [2, 4, 5], [1, 1, 1]]", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"\n Sorts a given matrix in ascending order according to the sum of its rows.\n\n Args:\n matrix: A list of lists representing the matrix.\n\n Returns:\n A new list of lists representing the sorted matrix.\n \"\"\"\n return sorted(matrix, key=lambda row: sum(row))", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"Sorts a given matrix in ascending order according to the sum of its rows.\n\n Args:\n matrix: A list of lists representing the matrix.\n\n Returns:\n A new list of lists representing the sorted matrix.\n \"\"\"\n return sorted(matrix, key=lambda row: sum(row))", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"\n Sorts a given matrix in ascending order according to the sum of its rows.\n\n Args:\n matrix: A list of lists representing the matrix.\n\n Returns:\n A new list of lists representing the sorted matrix.\n \"\"\"\n\n return sorted(matrix, key=lambda row: sum(row))", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"\n Sorts a given matrix in ascending order according to the sum of its rows.\n\n Args:\n matrix: A list of lists representing a matrix.\n\n Returns:\n A new list of lists representing the sorted matrix.\n \"\"\"\n return sorted(matrix, key=lambda row: sum(row))", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"\n Sorts a given matrix in ascending order according to the sum of its rows.\n\n Args:\n matrix: A list of lists representing the matrix.\n\n Returns:\n A new list of lists representing the sorted matrix.\n \"\"\"\n\n return sorted(matrix, key=lambda row: sum(row))", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"\n Sorts a given matrix in ascending order according to the sum of its rows.\n\n Args:\n matrix: A list of lists representing the matrix.\n\n Returns:\n A new list of lists representing the sorted matrix.\n \"\"\"\n\n def get_row_sum(row):\n return sum(row)\n\n return sorted(matrix, key=get_row_sum)", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"Sorts a matrix in ascending order according to the sum of its rows.\n\n Args:\n matrix: A list of lists representing the matrix.\n\n Returns:\n A new list of lists representing the sorted matrix.\n \"\"\"\n return sorted(matrix, key=lambda row: sum(row))\nmatrix = [[1, 2, 3], [2, 4, 5], [1, 1, 1]]", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"\n Sorts a given matrix in ascending order according to the sum of its rows.\n \n Args:\n matrix: A list of lists representing a matrix.\n\n Returns:\n A new list of lists representing the sorted matrix.\n \"\"\"\n return sorted(matrix, key=lambda row: sum(row))\nmatrix = [[1, 2, 3], [2, 4, 5], [1, 1, 1]]", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"\n Sorts a matrix in ascending order according to the sum of its rows.\n\n Args:\n matrix: A list of lists representing a matrix.\n\n Returns:\n A new list of lists representing the sorted matrix.\n \"\"\"\n return sorted(matrix, key=lambda row: sum(row))\nmatrix = [[1, 2, 3], [2, 4, 5], [1, 1, 1]]", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"\n Sorts a given matrix in ascending order according to the sum of its rows.\n\n Args:\n matrix: A list of lists representing the matrix.\n\n Returns:\n A new matrix sorted by row sum in ascending order.\n \"\"\"\n return sorted(matrix, key=lambda row: sum(row))", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"\n Sorts a given matrix in ascending order according to the sum of its rows.\n\n Args:\n matrix: A list of lists representing the matrix.\n\n Returns:\n A new list of lists representing the sorted matrix.\n \"\"\"\n return sorted(matrix, key=lambda row: sum(row))\nmatrix = [[1, 2, 3], [2, 4, 5], [1, 1, 1]]", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"\n Sorts a given matrix in ascending order according to the sum of its rows.\n\n Args:\n matrix: A list of lists representing the matrix.\n\n Returns:\n A new list of lists representing the sorted matrix.\n \"\"\"\n return sorted(matrix, key=lambda row: sum(row))\nmatrix = [[1, 2, 3], [2, 4, 5], [1, 1, 1]]", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"Sorts a matrix in ascending order according to the sum of its rows.\n\n Args:\n matrix: A list of lists representing the matrix.\n\n Returns:\n A new list of lists representing the sorted matrix.\n \"\"\"\n return sorted(matrix, key=lambda row: sum(row))\nmatrix = [[1, 2, 3], [2, 4, 5], [1, 1, 1]]", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"\n Sorts a given matrix in ascending order according to the sum of its rows.\n\n Args:\n matrix: A list of lists representing the matrix.\n\n Returns:\n A new list of lists representing the sorted matrix.\n \"\"\"\n return sorted(matrix, key=lambda row: sum(row))\nmatrix = [[1, 2, 3], [2, 4, 5], [1, 1, 1]]", "matching_cluster_idx": 15}]}, "Mbpp/16": {"dps": null, "dps_norm": null, "pass@1": 1.0, "profiled": []}, "Mbpp/19": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def test_duplicate(nums):\n \"\"\"\n Checks if an array of integers contains any duplicate elements.\n \n Args:\n nums: A list of integers.\n \n Returns:\n True if the array contains a duplicate, False otherwise.\n \"\"\"\n seen = set()\n for num in nums:\n if num in seen:\n return True\n seen.add(num)\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(nums):\n \"\"\"\n Write a function to find whether a given array of integers contains any duplicate element.\n\n Args:\n nums: A list of integers.\n\n Returns:\n True if the list contains a duplicate element, False otherwise.\n \"\"\"\n seen = set()\n for num in nums:\n if num in seen:\n return True\n seen.add(num)\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(nums):\n \"\"\"\n Determines if an array of integers contains any duplicate elements.\n\n Args:\n nums: A list of integers.\n\n Returns:\n True if the array contains a duplicate, False otherwise.\n \"\"\"\n\n seen = set()\n for num in nums:\n if num in seen:\n return True\n seen.add(num)\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(arr):\n \"\"\"\n Write a function to find whether a given array of integers contains any duplicate element.\n assert test_duplicate(([1,2,3,4,5]))==False\n \"\"\"\n seen = set()\n for num in arr:\n if num in seen:\n return True\n seen.add(num)\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(nums):\n \"\"\"\n Checks if a given array of integers contains any duplicate elements.\n \n Args:\n nums: A list of integers.\n \n Returns:\n True if the list contains duplicates, False otherwise.\n \"\"\"\n\n seen = set()\n for num in nums:\n if num in seen:\n return True\n seen.add(num)\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(arr):\n \"\"\"\n Check if an array of integers contains any duplicate elements.\n\n Args:\n arr: A list of integers.\n\n Returns:\n True if the array contains duplicates, False otherwise.\n \"\"\"\n seen = set() \n for num in arr:\n if num in seen:\n return True\n seen.add(num)\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(nums):\n \"\"\"\n Write a function to find whether a given array of integers contains any duplicate element.\n assert test_duplicate(([1,2,3,4,5]))==False\n \"\"\"\n seen = set()\n for num in nums:\n if num in seen:\n return True\n seen.add(num)\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(nums):\n \"\"\"\n Find whether a given array of integers contains any duplicate element.\n\n Args:\n nums: A list of integers.\n\n Returns:\n True if the array contains a duplicate element, False otherwise.\n \"\"\"\n seen = set()\n for num in nums:\n if num in seen:\n return True\n seen.add(num)\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(arr):\n \"\"\"\n Write a function to find whether a given array of integers contains any duplicate element.\n assert test_duplicate(([1,2,3,4,5]))==False\n \"\"\"\n seen = set()\n for num in arr:\n if num in seen:\n return True\n seen.add(num)\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(arr):\n \"\"\"\n Write a function to find whether a given array of integers contains any duplicate element.\n\n Args:\n arr: A list of integers.\n\n Returns:\n True if the array contains a duplicate element, False otherwise.\n \"\"\"\n seen = set()\n for num in arr:\n if num in seen:\n return True\n seen.add(num)\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(nums):\n \"\"\"\n Write a function to find whether a given array of integers contains any duplicate element.\n\n Args:\n nums: A list of integers.\n\n Returns:\n True if the list contains a duplicate element, False otherwise.\n \"\"\"\n seen = set()\n for num in nums:\n if num in seen:\n return True\n seen.add(num)\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(arr):\n \"\"\"\n Finds whether a given array of integers contains any duplicate element.\n \"\"\"\n seen = set()\n for num in arr:\n if num in seen:\n return True\n seen.add(num)\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(nums):\n \"\"\"\n Write a function to find whether a given array of integers contains any duplicate element.\n \n Args:\n nums: A list of integers.\n\n Returns:\n True if the list contains a duplicate element, False otherwise.\n \"\"\"\n seen = set()\n for num in nums:\n if num in seen:\n return True\n seen.add(num)\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(nums):\n \"\"\"\n Write a function to find whether a given array of integers contains any duplicate element.\n\n Args:\n nums: A list of integers.\n\n Returns:\n True if the array contains duplicate elements, False otherwise.\n \"\"\"\n\n seen = set()\n for num in nums:\n if num in seen:\n return True\n seen.add(num)\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(arr):\n \"\"\"\n Find whether a given array of integers contains any duplicate element.\n\n Args:\n arr (list): An array of integers.\n\n Returns:\n bool: True if the array contains duplicates, False otherwise.\n \"\"\"\n seen = set()\n for num in arr:\n if num in seen:\n return True\n seen.add(num)\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(arr):\n \"\"\"\n Check if an array of integers contains any duplicate elements.\n \n Args:\n arr: A list of integers.\n\n Returns:\n True if the array contains duplicates, False otherwise.\n \"\"\"\n seen = set()\n for num in arr:\n if num in seen:\n return True\n seen.add(num)\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(nums):\n \"\"\"\n Checks if an array of integers contains any duplicate elements.\n\n Args:\n nums: A list of integers.\n\n Returns:\n True if there are duplicate elements in the array, False otherwise.\n \"\"\"\n seen = set()\n for num in nums:\n if num in seen:\n return True\n seen.add(num)\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(nums):\n \"\"\"\n Checks if an array of integers contains any duplicate elements.\n\n Args:\n nums: A list of integers.\n\n Returns:\n True if the array contains duplicates, False otherwise.\n \"\"\"\n seen = set()\n for num in nums:\n if num in seen:\n return True\n seen.add(num)\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(nums):\n \"\"\"\n Write a function to find whether a given array of integers contains any duplicate element.\n assert test_duplicate(([1,2,3,4,5]))==False\n \"\"\"\n seen = set()\n for num in nums:\n if num in seen:\n return True\n seen.add(num)\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(arr):\n \"\"\"\n Checks if an array of integers contains any duplicate elements.\n \n Args:\n arr: A list of integers.\n \n Returns:\n True if the array contains duplicates, False otherwise.\n \"\"\"\n seen = set()\n for num in arr:\n if num in seen:\n return True\n seen.add(num)\n return False", "matching_cluster_idx": 14}]}, "Mbpp/62": {"dps": 71.5, "dps_norm": 81.0, "pass@1": 100.0, "profiled": [{"solution": "def smallest_num(data):\n \"\"\"\n Finds the smallest number in a list.\n\n Args:\n data: A list of numbers.\n\n Returns:\n The smallest number in the list.\n \"\"\"\n if not data:\n raise ValueError(\"List is empty\")\n smallest = data[0] \n for num in data:\n if num < smallest:\n smallest = num\n return smallest", "matching_cluster_idx": 3}, {"solution": "def smallest_num(numbers):\n \"\"\"\n Finds the smallest number in a list.\n\n Args:\n numbers: A list of numbers.\n\n Returns:\n The smallest number in the list.\n \"\"\"\n if not numbers:\n raise ValueError(\"List cannot be empty.\")\n smallest = numbers[0]\n for num in numbers:\n if num < smallest:\n smallest = num\n return smallest", "matching_cluster_idx": 3}, {"solution": "def smallest_num(nums):\n \"\"\"Finds the smallest number in a list.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n The smallest number in the list.\n\n Raises:\n ValueError: If the list is empty.\n \"\"\"\n if not nums:\n raise ValueError(\"List cannot be empty\")\n return min(nums)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(nums):\n \"\"\"\n Finds the smallest number in a list.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n The smallest number in the list.\n \"\"\"\n if not nums:\n return None \n smallest = nums[0] \n for num in nums:\n if num < smallest:\n smallest = num\n return smallest", "matching_cluster_idx": 3}, {"solution": "def smallest_num(numbers):\n \"\"\"\n Finds the smallest number in a list.\n\n Args:\n numbers: A list of numbers.\n\n Returns:\n The smallest number in the list.\n\n Raises:\n ValueError: If the list is empty.\n \"\"\"\n\n if not numbers:\n raise ValueError(\"Cannot find smallest number in an empty list.\")\n \n smallest = numbers[0] \n for num in numbers:\n if num < smallest:\n smallest = num\n return smallest", "matching_cluster_idx": 3}, {"solution": "def smallest_num(nums):\n \"\"\"\n Finds the smallest number in a list.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n The smallest number in the list.\n \"\"\"\n if not nums:\n raise ValueError(\"List cannot be empty\")\n smallest = nums[0] \n for num in nums:\n if num < smallest:\n smallest = num\n return smallest", "matching_cluster_idx": 3}, {"solution": "def smallest_num(nums):\n \"\"\"\n Finds the smallest number in a list.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n The smallest number in the list.\n \"\"\"\n if not nums:\n return None # Handle empty list case\n \n smallest = nums[0] \n for num in nums:\n if num < smallest:\n smallest = num\n return smallest", "matching_cluster_idx": 3}, {"solution": "def smallest_num(nums):\n \"\"\"\n Finds the smallest number in a list.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n The smallest number in the list.\n \"\"\"\n if not nums:\n raise ValueError(\"List cannot be empty\")\n smallest = nums[0] \n for num in nums:\n if num < smallest:\n smallest = num\n return smallest", "matching_cluster_idx": 3}, {"solution": "def smallest_num(nums):\n \"\"\"\n Finds the smallest number in a list.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n The smallest number in the list.\n \"\"\"\n if not nums:\n return None # Handle empty list case\n smallest = nums[0]\n for num in nums:\n if num < smallest:\n smallest = num\n return smallest", "matching_cluster_idx": 3}, {"solution": "def smallest_num(nums):\n \"\"\"\n Finds the smallest number in a list.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n The smallest number in the list.\n \"\"\"\n if not nums:\n return None \n \n smallest = nums[0]\n for num in nums:\n if num < smallest:\n smallest = num\n return smallest", "matching_cluster_idx": 3}, {"solution": "def smallest_num(nums):\n \"\"\"\n Finds the smallest number in a list.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n The smallest number in the list.\n \"\"\"\n if not nums:\n return None # Handle empty list case\n smallest = nums[0] \n for num in nums:\n if num < smallest:\n smallest = num\n return smallest", "matching_cluster_idx": 3}, {"solution": "def smallest_num(nums):\n \"\"\"\n This function finds the smallest number in a list.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n The smallest number in the list.\n \"\"\"\n if not nums:\n return None # Handle empty list case\n\n smallest = nums[0] \n for num in nums:\n if num < smallest:\n smallest = num\n return smallest", "matching_cluster_idx": 3}, {"solution": "def smallest_num(numbers):\n \"\"\"\n Finds the smallest number in a list.\n\n Args:\n numbers: A list of numbers.\n\n Returns:\n The smallest number in the list.\n \"\"\"\n if not numbers:\n return None # Handle the case of an empty list\n smallest = numbers[0] # Assume the first element is the smallest\n for num in numbers:\n if num < smallest:\n smallest = num\n return smallest", "matching_cluster_idx": 3}, {"solution": "def smallest_num(nums):\n \"\"\"\n This function finds the smallest number in a given list.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n The smallest number in the list.\n\n Raises:\n ValueError: If the input list is empty.\n \"\"\"\n\n if not nums:\n raise ValueError(\"Input list cannot be empty.\")\n \n smallest = nums[0] \n for num in nums:\n if num < smallest:\n smallest = num\n return smallest", "matching_cluster_idx": 3}, {"solution": "def smallest_num(numbers):\n \"\"\"\n Finds the smallest number in a list.\n\n Args:\n numbers: A list of numbers.\n\n Returns:\n The smallest number in the list.\n \"\"\"\n smallest = numbers[0] \n for number in numbers:\n if number < smallest:\n smallest = number\n return smallest", "matching_cluster_idx": 3}, {"solution": "def smallest_num(nums):\n \"\"\"\n Finds the smallest number in a list.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n The smallest number in the list.\n \"\"\"\n if not nums:\n return None # Handle empty list case\n smallest = nums[0]\n for num in nums:\n if num < smallest:\n smallest = num\n return smallest", "matching_cluster_idx": 3}, {"solution": "def smallest_num(nums):\n \"\"\"\n Finds the smallest number in a list.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n The smallest number in the list.\n \"\"\"\n if not nums:\n return None # Handle empty list case\n \n smallest = nums[0]\n for num in nums:\n if num < smallest:\n smallest = num\n return smallest", "matching_cluster_idx": 3}, {"solution": "def smallest_num(nums):\n \"\"\"\n This function finds the smallest number in a list.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n The smallest number in the list.\n \"\"\"\n smallest = nums[0]\n for num in nums:\n if num < smallest:\n smallest = num\n return smallest", "matching_cluster_idx": 3}, {"solution": "def smallest_num(nums):\n \"\"\"\n Finds the smallest number in a list.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n The smallest number in the list.\n \"\"\"\n if not nums:\n return None # Handle empty list case\n \n smallest = nums[0] \n for num in nums:\n if num < smallest:\n smallest = num\n return smallest", "matching_cluster_idx": 3}, {"solution": "def smallest_num(numbers):\n \"\"\"\n This function finds the smallest number in a list.\n\n Args:\n numbers: A list of numbers.\n\n Returns:\n The smallest number in the list.\n\n Raises:\n ValueError: If the list is empty.\n \"\"\"\n if not numbers:\n raise ValueError(\"List cannot be empty\")\n smallest = numbers[0]\n for num in numbers:\n if num < smallest:\n smallest = num\n return smallest", "matching_cluster_idx": 3}]}, "Mbpp/75": {"dps": 92.85714285714286, "dps_norm": 66.66666666666667, "pass@1": 100.0, "profiled": [{"solution": "def find_tuples(tuples_list, k):\n \"\"\"\n Finds tuples which have all elements divisible by k from the given list of tuples.\n\n Args:\n tuples_list: A list of tuples.\n k: An integer.\n\n Returns:\n A list of tuples which have all elements divisible by k.\n \"\"\"\n result = []\n for tup in tuples_list:\n if all(x % k == 0 for x in tup):\n result.append(tup)\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n \"\"\"\n Find tuples which have all elements divisible by k from the given list of tuples.\n\n Args:\n tuples_list: A list of tuples.\n k: An integer.\n\n Returns:\n A list of tuples where all elements are divisible by k.\n \"\"\"\n\n result = []\n for tup in tuples_list:\n if all(element % k == 0 for element in tup):\n result.append(tup)\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n \"\"\"\n Finds tuples which have all elements divisible by k from the given list of tuples.\n\n Args:\n tuples_list: A list of tuples.\n k: An integer.\n\n Returns:\n A list of tuples that have all elements divisible by k.\n \"\"\"\n result = []\n for tup in tuples_list:\n if all(x % k == 0 for x in tup):\n result.append(tup)\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n \"\"\"\n Finds tuples which have all elements divisible by k from the given list of tuples.\n\n Args:\n tuples_list: A list of tuples.\n k: An integer.\n\n Returns:\n A list of tuples that satisfy the condition.\n \"\"\"\n result = []\n for tup in tuples_list:\n if all(x % k == 0 for x in tup):\n result.append(tup)\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n \"\"\"\n Finds tuples which have all elements divisible by k from the given list of tuples.\n\n Args:\n tuples_list: A list of tuples.\n k: An integer.\n\n Returns:\n A list of tuples where all elements are divisible by k.\n \"\"\"\n result = []\n for tup in tuples_list:\n if all(element % k == 0 for element in tup):\n result.append(tup)\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuple_list, k):\n \"\"\"\n Finds tuples which have all elements divisible by k from the given list of tuples.\n\n Args:\n tuple_list: A list of tuples.\n k: An integer.\n\n Returns:\n A list of tuples where all elements in each tuple are divisible by k.\n \"\"\"\n result = []\n for tup in tuple_list:\n if all(x % k == 0 for x in tup):\n result.append(tup)\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n \"\"\"\n Finds tuples which have all elements divisible by k from the given list of tuples.\n\n Args:\n tuples_list: A list of tuples.\n k: An integer.\n\n Returns:\n A list of tuples whose elements are all divisible by k.\n \"\"\"\n result = []\n for tup in tuples_list:\n if all(num % k == 0 for num in tup):\n result.append(tup)\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n \"\"\"\n Find tuples which have all elements divisible by k from the given list of tuples.\n\n Args:\n tuples_list: A list of tuples.\n k: An integer.\n\n Returns:\n A list of tuples where all elements are divisible by k.\n \"\"\"\n result = []\n for tup in tuples_list:\n if all(x % k == 0 for x in tup):\n result.append(tup)\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n \"\"\"\n Finds tuples which have all elements divisible by k from the given list of tuples.\n\n Args:\n tuples_list: A list of tuples.\n k: An integer.\n\n Returns:\n A list of tuples that have all elements divisible by k.\n \"\"\"\n result = []\n for tup in tuples_list:\n is_divisible = all(element % k == 0 for element in tup)\n if is_divisible:\n result.append(tup)\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n \"\"\"\n Finds tuples which have all elements divisible by k from the given list of tuples.\n\n Args:\n tuples_list: A list of tuples.\n k: An integer.\n\n Returns:\n A list of tuples where all elements are divisible by k.\n \"\"\"\n result = []\n for tup in tuples_list:\n if all(x % k == 0 for x in tup):\n result.append(tup)\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n \"\"\"\n Finds tuples which have all elements divisible by k from the given list of tuples.\n\n Args:\n tuples_list: A list of tuples.\n k: An integer.\n\n Returns:\n A list of tuples where all elements are divisible by k.\n \"\"\"\n result = []\n for tup in tuples_list:\n if all(element % k == 0 for element in tup):\n result.append(tup)\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n \"\"\"\n Finds tuples which have all elements divisible by k from the given list of tuples.\n\n Args:\n tuples_list: A list of tuples.\n k: An integer.\n\n Returns:\n A list of tuples where all elements are divisible by k.\n \"\"\"\n return [tup for tup in tuples_list if all(x % k == 0 for x in tup)]", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuple_list, k):\n \"\"\"\n Finds tuples which have all elements divisible by k from the given list of tuples.\n\n Args:\n tuple_list: A list of tuples.\n k: An integer.\n\n Returns:\n A list of tuples where all elements are divisible by k.\n \"\"\"\n return [tup for tup in tuple_list if all(x % k == 0 for x in tup)]", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n \"\"\"\n Find tuples which have all elements divisible by k from the given list of tuples.\n\n Args:\n tuples_list: A list of tuples.\n k: An integer.\n\n Returns:\n A list of tuples where all elements are divisible by k.\n \"\"\"\n result = []\n for tup in tuples_list:\n is_divisible = all(element % k == 0 for element in tup)\n if is_divisible:\n result.append(tup)\n return result\nk = 6", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n \"\"\"\n Finds tuples which have all elements divisible by k from the given list of tuples.\n\n Args:\n tuples_list: A list of tuples.\n k: An integer.\n\n Returns:\n A list of tuples where all elements are divisible by k.\n \"\"\"\n result = []\n for tup in tuples_list:\n if all(num % k == 0 for num in tup):\n result.append(tup)\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n \"\"\"\n Finds tuples which have all elements divisible by k from the given list of tuples.\n\n Args:\n tuples_list: A list of tuples.\n k: The divisor.\n\n Returns:\n A list of tuples where all elements are divisible by k.\n \"\"\"\n return [tup for tup in tuples_list if all(element % k == 0 for element in tup)]\ntuples_list = [(6, 24, 12), (7, 9, 6), (12, 18, 21)]\nk = 6", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n \"\"\"\n Finds tuples which have all elements divisible by k from the given list of tuples.\n\n Args:\n tuples_list: A list of tuples.\n k: An integer.\n\n Returns:\n A list of tuples where all elements in each tuple are divisible by k.\n \"\"\"\n result = []\n for tuple_item in tuples_list:\n is_divisible = all(element % k == 0 for element in tuple_item)\n if is_divisible:\n result.append(tuple_item)\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n \"\"\"\n Finds tuples which have all elements divisible by k from the given list of tuples.\n\n Args:\n tuples_list: A list of tuples.\n k: The integer divisor.\n\n Returns:\n A list of tuples where all elements are divisible by k.\n \"\"\"\n return [tup for tup in tuples_list if all(element % k == 0 for element in tup)]", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n \"\"\"\n Finds tuples which have all elements divisible by k from the given list of tuples.\n\n Args:\n tuples_list: A list of tuples.\n k: An integer.\n\n Returns:\n A list of tuples where all elements are divisible by k.\n \"\"\"\n result = []\n for tup in tuples_list:\n is_divisible = all(x % k == 0 for x in tup)\n if is_divisible:\n result.append(tup)\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n \"\"\"\n Finds tuples which have all elements divisible by k from the given list of tuples.\n\n Args:\n tuples_list: A list of tuples.\n k: An integer.\n\n Returns:\n A list of tuples where all elements are divisible by k.\n \"\"\"\n result = []\n for tup in tuples_list:\n if all(element % k == 0 for element in tup):\n result.append(tup)\n return result", "matching_cluster_idx": 5}]}, "Mbpp/88": {"dps": 96.56862745098039, "dps_norm": 85.71428571428571, "pass@1": 100.0, "profiled": [{"solution": "def freq_count(data):\n \"\"\"\n Counts the frequency of all elements in a list.\n\n Args:\n data: A list of elements.\n\n Returns:\n A dictionary where keys are the elements and values are their frequencies.\n \"\"\"\n frequency = {}\n for item in data:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n return frequency", "matching_cluster_idx": 5}, {"solution": "def freq_count(numbers):\n \"\"\"\n Gets the frequency of all elements in a list as a dictionary.\n Args:\n numbers: A list of integers.\n Returns:\n A dictionary where keys are the unique elements in the list\n and values are their frequencies.\n \"\"\"\n freq = {}\n for number in numbers:\n if number in freq:\n freq[number] += 1\n else:\n freq[number] = 1\n return freq", "matching_cluster_idx": 5}, {"solution": "def freq_count(nums):\n \"\"\"\n Returns a dictionary with the frequency of each element in the input list.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n A dictionary where keys are unique elements from the input list and values are their frequencies.\n \"\"\"\n frequency = {}\n for num in nums:\n if num in frequency:\n frequency[num] += 1\n else:\n frequency[num] = 1\n return frequency", "matching_cluster_idx": 5}, {"solution": "def freq_count(nums):\n \"\"\"\n This function takes a list of numbers and returns a dictionary containing the frequency of each element.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n A dictionary where keys are the unique elements in the list and values are their frequencies.\n \"\"\"\n frequency = {}\n for num in nums:\n if num in frequency:\n frequency[num] += 1\n else:\n frequency[num] = 1\n return frequency", "matching_cluster_idx": 5}, {"solution": "def freq_count(numbers):\n \"\"\"\n Calculates the frequency of each element in a list, returning a dictionary.\n\n Args:\n numbers: A list of integers.\n\n Returns:\n A dictionary where keys are the unique elements in the list and values are their respective frequencies.\n \"\"\"\n frequency = {}\n for number in numbers:\n if number in frequency:\n frequency[number] += 1\n else:\n frequency[number] = 1\n return frequency", "matching_cluster_idx": 5}, {"solution": "def freq_count(nums):\n \"\"\"\n Counts the frequency of each element in a list and returns it as a dictionary.\n\n Args:\n nums: A list of integers.\n\n Returns:\n A dictionary where keys are elements from the input list and values\n are their corresponding frequencies.\n \"\"\"\n frequency = {}\n for num in nums:\n if num in frequency:\n frequency[num] += 1\n else:\n frequency[num] = 1\n return frequency", "matching_cluster_idx": 5}, {"solution": "def freq_count(data):\n \"\"\"\n This function takes a list and returns a dictionary where keys are the elements in the list\n and values are their respective frequencies.\n\n Args:\n data: A list of elements.\n\n Returns:\n A dictionary containing the frequency of each element.\n \"\"\"\n frequency = {}\n for element in data:\n if element in frequency:\n frequency[element] += 1\n else:\n frequency[element] = 1\n return frequency", "matching_cluster_idx": 5}, {"solution": "def freq_count(nums):\n \"\"\"\n Get the frequency of all elements in a list as a dictionary.\n\n Args:\n nums: A list of integers.\n\n Returns:\n A dictionary where keys are the unique elements in the list and values are their frequencies.\n \"\"\"\n freq = {}\n for num in nums:\n if num in freq:\n freq[num] += 1\n else:\n freq[num] = 1\n return freq", "matching_cluster_idx": 5}, {"solution": "def freq_count(arr):\n \"\"\"\n This function takes a list and returns the frequency of each element as a dictionary.\n\n Args:\n arr: A list of integers.\n\n Returns:\n A dictionary where keys are the unique elements in the list and values are their frequencies.\n \"\"\"\n frequency = {}\n for element in arr:\n if element in frequency:\n frequency[element] += 1\n else:\n frequency[element] = 1\n return frequency", "matching_cluster_idx": 5}, {"solution": "def freq_count(data):\n \"\"\"\n Returns a dictionary with the frequency of all elements in a list.\n\n Args:\n data: A list of elements.\n\n Returns:\n A dictionary where keys are elements from the list and values are their frequencies.\n \"\"\"\n frequency = {}\n for element in data:\n if element in frequency:\n frequency[element] += 1\n else:\n frequency[element] = 1\n return frequency", "matching_cluster_idx": 5}, {"solution": "def freq_count(nums):\n \"\"\"\n This function takes a list of numbers and returns a dictionary with the frequency \n of each element in the list.\n\n Args:\n nums: A list of integers.\n\n Returns:\n A dictionary where keys are the unique elements in the list and values are \n their corresponding frequencies.\n \"\"\"\n frequency = {}\n for num in nums:\n if num in frequency:\n frequency[num] += 1\n else:\n frequency[num] = 1\n return frequency", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n \"\"\"\n Get the frequency of all the elements in a list, returned as a dictionary.\n\n Args:\n lst: A list of integers.\n\n Returns:\n A dictionary where keys are elements of the list and values are their frequencies.\n \"\"\"\n frequency = {}\n for element in lst:\n if element in frequency:\n frequency[element] += 1\n else:\n frequency[element] = 1\n return frequency", "matching_cluster_idx": 5}, {"solution": "def freq_count(nums):\n \"\"\"\n Calculates the frequency of each element in a list.\n\n Args:\n nums: A list of integers.\n\n Returns:\n A dictionary where keys are the unique elements in the list and values are their frequencies.\n \"\"\"\n frequency = {}\n for num in nums:\n if num in frequency:\n frequency[num] += 1\n else:\n frequency[num] = 1\n return frequency", "matching_cluster_idx": 5}, {"solution": "def freq_count(nums):\n \"\"\"\n Write a function to get the frequency of all the elements in a list, returned as a dictionary.\n assert freq_count([10,10,10,10,20,20,20,20,40,40,50,50,30])==({10: 4, 20: 4, 40: 2, 50: 2, 30: 1})\n \"\"\"\n frequency = {}\n for num in nums:\n if num in frequency:\n frequency[num] += 1\n else:\n frequency[num] = 1\n return frequency", "matching_cluster_idx": 5}, {"solution": "def freq_count(data):\n \"\"\"\n Counts the frequency of each element in a list.\n\n Args:\n data: A list of elements.\n\n Returns:\n A dictionary where keys are the elements in the list and values are their frequencies.\n \"\"\"\n frequency = {}\n for element in data:\n if element in frequency:\n frequency[element] += 1\n else:\n frequency[element] = 1\n return frequency", "matching_cluster_idx": 5}, {"solution": "def freq_count(data):\n \"\"\"\n Write a function to get the frequency of all the elements in a list, returned as a dictionary.\n \"\"\"\n frequency = {}\n for element in data:\n if element in frequency:\n frequency[element] += 1\n else:\n frequency[element] = 1\n return frequency", "matching_cluster_idx": 5}, {"solution": "def freq_count(arr):\n \"\"\"\n Calculates the frequency of each element in a list and returns a dictionary.\n\n Args:\n arr: A list of elements.\n\n Returns:\n A dictionary where keys are elements from the list and values are their frequencies.\n \"\"\"\n frequency = {}\n for element in arr:\n if element in frequency:\n frequency[element] += 1\n else:\n frequency[element] = 1\n return frequency", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n \"\"\"\n Write a function to get the frequency of all the elements in a list, returned as a dictionary.\n\n Args:\n lst: A list of integers.\n\n Returns:\n A dictionary where the keys are the elements of the list and the values are their frequencies.\n \"\"\"\n\n frequency = {}\n for element in lst:\n if element in frequency:\n frequency[element] += 1\n else:\n frequency[element] = 1\n return frequency", "matching_cluster_idx": 5}, {"solution": "def freq_count(nums):\n \"\"\"\n Write a function to get the frequency of all the elements in a list, returned as a dictionary.\n assert freq_count([10,10,10,10,20,20,20,20,40,40,50,50,30])==({10: 4, 20: 4, 40: 2, 50: 2, 30: 1})\n \"\"\"\n frequency = {}\n for num in nums:\n if num in frequency:\n frequency[num] += 1\n else:\n frequency[num] = 1\n return frequency", "matching_cluster_idx": 5}, {"solution": "def freq_count(numbers):\n \"\"\"\n This function takes a list of numbers and returns a dictionary containing the frequency of each element.\n\n Args:\n numbers: A list of integers.\n\n Returns:\n A dictionary where keys are the unique elements in the list and values are their frequencies.\n \"\"\"\n frequency = {}\n for number in numbers:\n if number in frequency:\n frequency[number] += 1\n else:\n frequency[number] = 1\n return frequency", "matching_cluster_idx": 5}]}, "Mbpp/90": {"dps": 26.682926829268293, "dps_norm": 72.14285714285714, "pass@1": 85.0, "profiled": [{"solution": "def len_log(words):\n \"\"\"\n Finds the length of the longest word in a list.\n\n Args:\n words: A list of strings.\n\n Returns:\n The length of the longest word in the list.\n \"\"\"\n longest_word = \"\"\n for word in words:\n if len(word) > len(longest_word):\n longest_word = word\n return len(longest_word)", "matching_cluster_idx": 4}, {"solution": "def len_log(words):\n \"\"\"\n Finds the length of the longest word in a list.\n\n Args:\n words: A list of words.\n\n Returns:\n The length of the longest word in the list.\n \"\"\"\n longest_word = \"\"\n for word in words:\n if len(word) > len(longest_word):\n longest_word = word\n return len(longest_word)", "matching_cluster_idx": 4}, {"solution": "def len_log(words):\n \"\"\"\n Finds the length of the longest word in a list.\n\n Args:\n words: A list of strings.\n\n Returns:\n The length of the longest word in the list.\n \"\"\"\n longest_word = \"\"\n for word in words:\n if len(word) > len(longest_word):\n longest_word = word\n return len(longest_word)", "matching_cluster_idx": 4}, {"solution": "def len_log(words):\n \"\"\"\n Finds the length of the longest word in a list.\n\n Args:\n words: A list of words (strings).\n\n Returns:\n The length of the longest word.\n \"\"\"\n longest_word = \"\"\n for word in words:\n if len(word) > len(longest_word):\n longest_word = word\n return len(longest_word)", "matching_cluster_idx": 4}, {"solution": "def len_log(words):\n \"\"\"\n Finds the length of the longest word in a list.\n\n Args:\n words: A list of strings.\n\n Returns:\n The length of the longest word in the list.\n \"\"\"\n longest_word = \"\"\n for word in words:\n if len(word) > len(longest_word):\n longest_word = word\n return len(longest_word)", "matching_cluster_idx": 4}, {"solution": "def len_log(words):\n \"\"\"\n Finds the length of the longest word in a list of words.\n\n Args:\n words: A list of strings.\n\n Returns:\n The length of the longest word in the list.\n \"\"\"\n longest_word = \"\"\n for word in words:\n if len(word) > len(longest_word):\n longest_word = word\n return len(longest_word)", "matching_cluster_idx": 4}, {"solution": "def len_log(words):\n \"\"\"\n Find the length of the longest word in a list of words.\n\n Args:\n words: A list of strings.\n\n Returns:\n The length of the longest word in the list.\n \"\"\"\n longest_word = \"\"\n for word in words:\n if len(word) > len(longest_word):\n longest_word = word\n return len(longest_word)", "matching_cluster_idx": 4}, {"solution": "def len_log(words):\n \"\"\"Finds the length of the longest word in a list.\n\n Args:\n words: A list of strings.\n\n Returns:\n The length of the longest word in the list.\n \"\"\"\n longest_word = \"\"\n for word in words:\n if len(word) > len(longest_word):\n longest_word = word\n return len(longest_word)", "matching_cluster_idx": 4}, {"solution": "def len_log(words):\n \"\"\"\n Finds the length of the longest word in a list.\n\n Args:\n words: A list of strings.\n\n Returns:\n The length of the longest word in the list.\n \"\"\"\n longest_word = \"\"\n for word in words:\n if len(word) > len(longest_word):\n longest_word = word\n return len(longest_word)", "matching_cluster_idx": 4}, {"solution": "def len_log(words):\n \"\"\"\n Finds the length of the longest word in a list.\n\n Args:\n words: A list of strings.\n\n Returns:\n The length of the longest word in the list.\n \"\"\"\n longest_word = \"\"\n for word in words:\n if len(word) > len(longest_word):\n longest_word = word\n return len(longest_word)", "matching_cluster_idx": 4}, {"solution": "def len_log(words):\n \"\"\"\n Finds the length of the longest word in a list.\n\n Args:\n words: A list of strings.\n\n Returns:\n The length of the longest word in the list.\n \"\"\"\n longest_word = \"\"\n for word in words:\n if len(word) > len(longest_word):\n longest_word = word\n return len(longest_word)", "matching_cluster_idx": 4}, {"solution": "def len_log(words):\n \"\"\"\n Finds the length of the longest word in a list of words.\n\n Args:\n words: A list of strings.\n\n Returns:\n The length of the longest word in the list.\n \"\"\"\n longest_word = \"\"\n for word in words:\n if len(word) > len(longest_word):\n longest_word = word\n return len(longest_word)", "matching_cluster_idx": 4}, {"solution": "def len_log(list1):\n \"\"\"\n Finds the length of the longest word in a list of strings.\n \n Args:\n list1: A list of strings.\n \n Returns:\n The length of the longest word in the list.\n \"\"\"\n longest = 0\n for word in list1:\n if len(word) > longest:\n longest = len(word)\n return longest", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n \"\"\"\n Finds the length of the longest word in a list of words.\n\n Args:\n words: A list of words.\n\n Returns:\n The length of the longest word in the list.\n \"\"\"\n longest_word = \"\"\n for word in words:\n if len(word) > len(longest_word):\n longest_word = word\n return len(longest_word)", "matching_cluster_idx": 4}, {"solution": "def len_log(words):\n \"\"\"\n Find the length of the longest word in a list.\n\n Args:\n words: A list of strings.\n\n Returns:\n The length of the longest word in the list.\n \"\"\"\n longest_word = \"\"\n for word in words:\n if len(word) > len(longest_word):\n longest_word = word\n return len(longest_word)", "matching_cluster_idx": 4}, {"solution": "def len_log(words):\n \"\"\"\n Finds the length of the longest word in a list of words.\n\n Args:\n words: A list of strings.\n\n Returns:\n The length of the longest word in the list.\n \"\"\"\n longest_word = \"\"\n for word in words:\n if len(word) > len(longest_word):\n longest_word = word\n return len(longest_word)", "matching_cluster_idx": 4}, {"solution": "def len_log(words):\n \"\"\"\n Finds the length of the longest word in a list of strings.\n\n Args:\n words: A list of strings.\n\n Returns:\n The length of the longest word in the list.\n \"\"\"\n longest_word = \"\"\n for word in words:\n if len(word) > len(longest_word):\n longest_word = word\n return len(longest_word)", "matching_cluster_idx": 4}, {"solution": "def len_log(words):\n \"\"\"\n Finds the length of the longest word in a list.\n\n Args:\n words: A list of strings.\n\n Returns:\n The length of the longest word in the list.\n \"\"\"\n longest_word = \"\"\n for word in words:\n if len(word) > len(longest_word):\n longest_word = word\n return len(longest_word)", "matching_cluster_idx": 4}, {"solution": "def len_log(words):\n \"\"\"\n Finds the length of the longest word in a list.\n\n Args:\n words: A list of strings.\n\n Returns:\n The length of the longest word in the list.\n \"\"\"\n longest_word = \"\"\n for word in words:\n if len(word) > len(longest_word):\n longest_word = word\n return len(longest_word)", "matching_cluster_idx": 4}, {"solution": "def len_log(words):\n \"\"\"\n Finds the length of the longest word in a list of words.\n\n Args:\n words: A list of strings.\n\n Returns:\n The length of the longest word in the list.\n \"\"\"\n longest_word = \"\"\n for word in words:\n if len(word) > len(longest_word):\n longest_word = word\n return len(longest_word)", "matching_cluster_idx": 4}]}, "Mbpp/94": {"dps": 81.34146341463415, "dps_norm": 68.0, "pass@1": 91.0, "profiled": [{"solution": "def index_minimum(tuple_list):\n \"\"\"\n Given a list of tuples, return the first value of the tuple with the smallest second value.\n\n Args:\n tuple_list: A list of tuples.\n\n Returns:\n The first value of the tuple with the smallest second value.\n \"\"\"\n min_index = 0\n for i in range(1, len(tuple_list)):\n if tuple_list[i][1] < tuple_list[min_index][1]:\n min_index = i\n return tuple_list[min_index][0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(tuple_list):\n \"\"\"Given a list of tuples, return the first value of the tuple with the smallest second value.\n\n Args:\n tuple_list: A list of tuples.\n\n Returns:\n The first value of the tuple with the smallest second value.\n \"\"\"\n minimum_tuple = tuple_list[0]\n for tuple in tuple_list:\n if tuple[1] < minimum_tuple[1]:\n minimum_tuple = tuple\n return minimum_tuple[0]", "matching_cluster_idx": 3}, {"solution": "def index_minimum(list_of_tuples):\n \"\"\"\n Given a list of tuples, return the first value of the tuple with the smallest second value.\n\n Args:\n list_of_tuples: A list of tuples where each tuple contains a name and a number.\n\n Returns:\n The first value of the tuple with the smallest second value.\n \"\"\"\n min_tuple = list_of_tuples[0]\n for tuple in list_of_tuples:\n if tuple[1] < min_tuple[1]:\n min_tuple = tuple\n return min_tuple[0]", "matching_cluster_idx": 3}, {"solution": "def index_minimum(lst):\n \"\"\"Given a list of tuples, write a function that returns the first value of the tuple with the smallest second value.\n\n Args:\n lst: A list of tuples.\n\n Returns:\n The first value of the tuple with the smallest second value.\n \"\"\"\n min_value = lst[0][1]\n min_index = 0\n for i in range(1, len(lst)):\n if lst[i][1] < min_value:\n min_value = lst[i][1]\n min_index = i\n return lst[min_index][0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(tuple_list):\n \"\"\"\n Given a list of tuples, return the first value of the tuple with the smallest second value.\n\n Args:\n tuple_list: A list of tuples.\n\n Returns:\n The first value of the tuple with the smallest second value.\n\n \"\"\"\n min_tuple = tuple_list[0]\n for tuple_item in tuple_list:\n if tuple_item[1] < min_tuple[1]:\n min_tuple = tuple_item\n return min_tuple[0]", "matching_cluster_idx": 3}, {"solution": "def index_minimum(tuples):\n \"\"\"\n Given a list of tuples, write a function that returns the first value of the tuple with the smallest second value.\n\n Args:\n tuples: A list of tuples where each tuple contains two elements.\n\n Returns:\n The first value of the tuple with the smallest second value.\n \"\"\"\n minimum_tuple = tuples[0]\n for tup in tuples:\n if tup[1] < minimum_tuple[1]:\n minimum_tuple = tup\n return minimum_tuple[0]", "matching_cluster_idx": 3}, {"solution": "def index_minimum(tuple_list):\n \"\"\"\n Given a list of tuples, return the first value of the tuple with the smallest second value.\n \n Args:\n tuple_list: A list of tuples.\n\n Returns:\n The first value of the tuple with the smallest second value.\n\n Examples:\n index_minimum([('Rash', 143), ('Manjeet', 200), ('Varsha', 100)]) == 'Varsha'\n \"\"\"\n min_value = min(tuple_list, key=lambda x: x[1])[0]\n return min_value", "matching_cluster_idx": 2}, {"solution": "def index_minimum(lst):\n \"\"\"\n Given a list of tuples, returns the first value of the tuple with the smallest second value.\n\n Args:\n lst: A list of tuples.\n\n Returns:\n The first value of the tuple with the smallest second value.\n \"\"\"\n min_value = min(lst, key=lambda x: x[1])[0]\n return min_value", "matching_cluster_idx": 2}, {"solution": "def index_minimum(tuples_list):\n \"\"\"\n Given a list of tuples, return the first value of the tuple with the smallest second value.\n\n Args:\n tuples_list: A list of tuples.\n\n Returns:\n The first value of the tuple with the smallest second value.\n \"\"\"\n min_value = min(tuples_list, key=lambda x: x[1])[0]\n return min_value", "matching_cluster_idx": 2}, {"solution": "def index_minimum(tuple_list):\n \"\"\"\n Given a list of tuples, return the first value of the tuple with the smallest second value.\n\n Args:\n tuple_list: A list of tuples.\n\n Returns:\n The first value of the tuple with the smallest second value.\n \"\"\"\n min_value = min(tuple_list, key=lambda x: x[1])[0]\n return min_value", "matching_cluster_idx": 2}, {"solution": "def index_minimum(tuples_list):\n \"\"\"Given a list of tuples, return the first value of the tuple with the smallest second value.\n \n Args:\n tuples_list: A list of tuples, where each tuple contains two elements.\n\n Returns:\n The first value of the tuple with the smallest second value.\n \"\"\"\n min_value = min(tuples_list, key=lambda x: x[1])\n return min_value[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(lst):\n \"\"\"\n Given a list of tuples, return the first value of the tuple with the smallest second value.\n \n Args:\n lst: A list of tuples, where each tuple contains a string and an integer.\n\n Returns:\n The first value of the tuple with the smallest second value.\n \"\"\"\n min_tuple = lst[0] # Initialize with the first tuple\n for tuple in lst:\n if tuple[1] < min_tuple[1]: # Compare the second values\n min_tuple = tuple\n return min_tuple[0] # Return the first value of the tuple with the smallest second value", "matching_cluster_idx": 3}, {"solution": "def index_minimum(data):\n \"\"\"\n Given a list of tuples, return the first value of the tuple with the smallest second value.\n\n Args:\n data: A list of tuples where each tuple contains a name and a number.\n\n Returns:\n The first value of the tuple with the smallest second value.\n \"\"\"\n min_tuple = data[0]\n for tuple in data:\n if tuple[1] < min_tuple[1]:\n min_tuple = tuple\n return min_tuple[0]", "matching_cluster_idx": 3}, {"solution": "def index_minimum(data):\n \"\"\"\n Given a list of tuples, write a function that returns the first value of the tuple with the smallest second value.\n\n Args:\n data: A list of tuples.\n\n Returns:\n The first value of the tuple with the smallest second value.\n \"\"\"\n\n min_value = min(data, key=lambda x: x[1])\n return min_value[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(list_of_tuples):\n \"\"\"\n Given a list of tuples, write a function that returns the first value of the tuple with the smallest second value.\n\n Args:\n list_of_tuples: A list of tuples.\n\n Returns:\n The first value of the tuple with the smallest second value.\n\n \"\"\"\n min_value = min(list_of_tuples, key=lambda x: x[1])[0]\n return min_value", "matching_cluster_idx": 2}, {"solution": "def index_minimum(list_of_tuples):\n \"\"\"\n Given a list of tuples, write a function that returns the first value of the tuple with the smallest second value.\n For example:\n index_minimum([('Rash', 143), ('Manjeet', 200), ('Varsha', 100)]) == 'Varsha'\n \"\"\"\n minimum_tuple = list_of_tuples[0]\n for tuple_item in list_of_tuples:\n if tuple_item[1] < minimum_tuple[1]:\n minimum_tuple = tuple_item\n return minimum_tuple[0]", "matching_cluster_idx": 3}, {"solution": "def index_minimum(data):\n \"\"\"\n Given a list of tuples, return the first value of the tuple with the smallest second value.\n\n Args:\n data: A list of tuples.\n\n Returns:\n The first value of the tuple with the smallest second value.\n \"\"\"\n min_val = data[0][1]\n min_index = 0\n for i in range(1, len(data)):\n if data[i][1] < min_val:\n min_val = data[i][1]\n min_index = i\n return data[min_index][0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(tuple_list):\n \"\"\"\n Given a list of tuples, write a function that returns the first value of the tuple with the smallest second value.\n\n Args:\n tuple_list: A list of tuples.\n\n Returns:\n The first value of the tuple with the smallest second value.\n \"\"\"\n min_value = tuple_list[0][1] # Initialize min_value with the second value of the first tuple\n min_index = 0 # Initialize the index of the minimum value tuple\n\n for i in range(1, len(tuple_list)):\n if tuple_list[i][1] < min_value:\n min_value = tuple_list[i][1] # Update min_value if a smaller value is found\n min_index = i # Update the index of the minimum value tuple\n\n return tuple_list[min_index][0] # Return the first value of the tuple with the minimum second value", "matching_cluster_idx": 2}, {"solution": "def index_minimum(data):\n \"\"\"\n Given a list of tuples, write a function that returns the first value of the tuple with the smallest second value.\n \n For example:\n index_minimum([('Rash', 143), ('Manjeet', 200), ('Varsha', 100)]) == 'Varsha'\n \"\"\"\n min_tuple = data[0]\n for tuple in data:\n if tuple[1] < min_tuple[1]:\n min_tuple = tuple\n return min_tuple[0]", "matching_cluster_idx": 3}, {"solution": "def index_minimum(tuple_list):\n \"\"\"\n Given a list of tuples, return the first value of the tuple with the smallest second value.\n\n Args:\n tuple_list: A list of tuples.\n\n Returns:\n The first value of the tuple with the smallest second value.\n \"\"\"\n min_value = tuple_list[0][1] \n min_index = 0\n for i in range(1, len(tuple_list)):\n if tuple_list[i][1] < min_value:\n min_value = tuple_list[i][1]\n min_index = i\n return tuple_list[min_index][0]", "matching_cluster_idx": 2}]}, "Mbpp/96": {"dps": 97.77777777777777, "dps_norm": 94.28571428571429, "pass@1": 100.0, "profiled": [{"solution": "def divisor(n):\n \"\"\"\n Finds the number of divisors of a given integer.\n\n Args:\n n: An integer.\n\n Returns:\n The number of divisors of n.\n \"\"\"\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n count += 2 # Count both i and n/i as divisors\n if int(n**0.5)**2 == n: # Handle perfect squares\n count -= 1\n return count", "matching_cluster_idx": 6}, {"solution": "def divisor(n):\n \"\"\"\n This function takes an integer and returns the number of its divisors.\n\n Args:\n n: An integer.\n\n Returns:\n The number of divisors of n.\n \"\"\"\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n count += 2 # Add 2 because i and n/i are both divisors\n if int(n**0.5)**2 == n:\n count -= 1 # Adjust for double-counting the square root\n return count", "matching_cluster_idx": 6}, {"solution": "def divisor(n):\n \"\"\"\n This function returns the number of divisors of a given integer.\n \"\"\"\n count = 0\n for i in range(1, n+1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n \"\"\"\n Finds the number of divisors of a given integer.\n\n Args:\n n: The integer to find the divisors of.\n\n Returns:\n The number of divisors of n.\n \"\"\"\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n count += 2 \n if int(n**0.5)**2 == n:\n count -= 1\n return count", "matching_cluster_idx": 6}, {"solution": "def divisor(n):\n \"\"\"\n Finds the number of divisors of a given integer.\n\n Args:\n n: The integer to find divisors for.\n\n Returns:\n The number of divisors of n.\n \"\"\"\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n count += 2 \n if int(n**0.5) * int(n**0.5) == n:\n count -= 1\n return count", "matching_cluster_idx": 6}, {"solution": "def divisor(n):\n \"\"\"\n Finds the number of divisors of a given integer.\n\n Args:\n n: The integer to find the number of divisors for.\n\n Returns:\n The number of divisors of n.\n \"\"\"\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n count += 2 # If i is a divisor, so is n/i\n if int(n**0.5)**2 == n: # Handle perfect squares\n count -= 1\n return count", "matching_cluster_idx": 6}, {"solution": "def divisor(n):\n \"\"\"\n Finds the number of divisors of a given integer.\n\n Args:\n n: An integer.\n\n Returns:\n The number of divisors of n.\n \"\"\"\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n count += 2 # Count both i and n/i as divisors\n \n if int(n**0.5)**2 == n: # Handle perfect squares\n count -= 1\n return count", "matching_cluster_idx": 6}, {"solution": "def divisor(n):\n \"\"\"\n This function finds the number of divisors of a given integer.\n\n Args:\n n: An integer.\n\n Returns:\n The number of divisors of n.\n \"\"\"\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n count += 2 # If i is a divisor, n/i is also a divisor\n if int(n**0.5)**2 == n: # Handle perfect squares\n count -= 1\n return count", "matching_cluster_idx": 6}, {"solution": "def divisor(n):\n \"\"\"\n Finds the number of divisors of a given integer.\n\n Args:\n n: An integer.\n\n Returns:\n The number of divisors of n.\n \"\"\"\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n count += 2 # Count both i and n/i as divisors\n if int(n**0.5) * int(n**0.5) == n:\n count -= 1 # Avoid double-counting the square root\n return count", "matching_cluster_idx": 6}, {"solution": "def divisor(n):\n \"\"\"\n Finds the number of divisors of a given integer.\n\n Args:\n n: The integer to find divisors for.\n\n Returns:\n The number of divisors of n.\n \"\"\"\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n count += 2 # Count both i and n/i as divisors\n if int(n**0.5) * int(n**0.5) == n:\n count -= 1 # Avoid double-counting the square root\n return count", "matching_cluster_idx": 6}, {"solution": "def divisor(num):\n \"\"\"\n This function finds the number of divisors of a given integer.\n\n Args:\n num: An integer.\n\n Returns:\n The number of divisors of num.\n \"\"\"\n count = 0\n for i in range(1, int(num**0.5) + 1):\n if num % i == 0:\n count += 2 # Add 2 because i and num/i are both divisors\n if int(num**0.5)**2 == num: # Handle perfect squares\n count -= 1\n return count", "matching_cluster_idx": 6}, {"solution": "def divisor(num):\n \"\"\"\n This function finds the number of divisors of a given integer.\n\n Args:\n num: An integer.\n\n Returns:\n The number of divisors of num.\n \"\"\"\n count = 0\n for i in range(1, int(num**0.5) + 1):\n if num % i == 0:\n count += 2 # If i is a divisor, num/i is also a divisor\n if int(num**0.5)**2 == num: # Handle perfect squares\n count -= 1\n return count", "matching_cluster_idx": 6}, {"solution": "def divisor(n):\n \"\"\"\n This function returns the number of divisors of a given integer.\n \n Args:\n n: An integer.\n \n Returns:\n The number of divisors of n.\n\n \"\"\"\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n count += 2 \n \n if int(n**0.5)**2 == n:\n count -= 1 \n \n return count", "matching_cluster_idx": 6}, {"solution": "def divisor(n):\n \"\"\"\n Finds the number of divisors of a given integer.\n\n Args:\n n: An integer.\n\n Returns:\n The number of divisors of n.\n \"\"\"\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n count += 2 # If i is a divisor, n/i is also a divisor\n \n # Handle the case where n is a perfect square\n if int(n**0.5)**2 == n:\n count -= 1\n\n return count", "matching_cluster_idx": 6}, {"solution": "def divisor(n):\n \"\"\"\n Finds the number of divisors of a given integer.\n\n Args:\n n: The integer to find the divisors of.\n\n Returns:\n The number of divisors of n.\n \"\"\"\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n count += 2 # Increment by 2 for both i and n/i\n \n if int(n**0.5)**2 == n: # Handle perfect squares\n count -= 1\n return count", "matching_cluster_idx": 6}, {"solution": "def divisor(n):\n \"\"\"\n Find the number of divisors of a given integer.\n\n Args:\n n: An integer.\n\n Returns:\n The number of divisors of n.\n \"\"\"\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n count += 2 \n if int(n**0.5) * int(n**0.5) == n:\n count -= 1 \n return count", "matching_cluster_idx": 6}, {"solution": "def divisor(n):\n \"\"\"\n Counts the number of divisors of a given integer.\n\n Args:\n n: The integer to find the divisors of.\n\n Returns:\n The number of divisors of n.\n \"\"\"\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n count += 2 # Count both i and n/i as divisors\n if int(n**0.5)**2 == n:\n count -= 1 # Adjust count if n is a perfect square\n return count", "matching_cluster_idx": 6}, {"solution": "def divisor(n):\n \"\"\"\n Finds the number of divisors of a given integer.\n\n Args:\n n: The integer to find the divisors of.\n\n Returns:\n The number of divisors of n.\n \"\"\"\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n \"\"\"\n Finds the number of divisors of a given integer.\n\n Args:\n n: An integer.\n\n Returns:\n The number of divisors of n.\n \"\"\"\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n count += 2 # Count both i and n/i as divisors\n if int(n**0.5)**2 == n: # Handle perfect squares\n count -= 1\n return count", "matching_cluster_idx": 6}, {"solution": "def divisor(n):\n \"\"\"\n Finds the number of divisors of a given integer.\n \n Args:\n n: An integer.\n \n Returns:\n The number of divisors of n.\n \"\"\"\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n count += 2 # If i is a divisor, then n/i is also a divisor\n if int(n**0.5)**2 == n: # Handle perfect squares\n count -= 1\n return count", "matching_cluster_idx": 6}]}, "Mbpp/97": {"dps": 99.65811965811966, "dps_norm": 87.5, "pass@1": 100.0, "profiled": [{"solution": "def frequency_lists(lst):\n \"\"\"\n Finds the frequency of each element in a flattened list of lists.\n\n Args:\n lst: A list of lists.\n\n Returns:\n A dictionary where keys are elements from the flattened list and values\n are their frequencies.\n \"\"\"\n result = {}\n for sublist in lst:\n for element in sublist:\n if element in result:\n result[element] += 1\n else:\n result[element] = 1\n return result", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(input_list):\n \"\"\"\n Finds frequency of each element in a flattened list of lists, returned in a dictionary.\n\n Args:\n input_list: A list of lists.\n\n Returns:\n A dictionary where keys are the unique elements and values are their frequencies.\n \"\"\"\n frequency = {}\n for sublist in input_list:\n for element in sublist:\n if element in frequency:\n frequency[element] += 1\n else:\n frequency[element] = 1\n return frequency", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lists):\n \"\"\"\n Finds the frequency of each element in a flattened list of lists,\n returned in a dictionary.\n\n Args:\n lists: A list of lists.\n\n Returns:\n A dictionary where keys are the unique elements in the flattened list and \n values are their frequencies.\n \"\"\"\n flattened = [item for sublist in lists for item in sublist]\n frequency = {}\n for item in flattened:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n return frequency", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lst):\n \"\"\"\n Finds the frequency of each element in a flattened list of lists, returned in a dictionary.\n \n Args:\n lst: A list of lists.\n\n Returns:\n A dictionary where keys are elements from the flattened list and values are their frequencies.\n \"\"\"\n frequencies = {}\n for sublist in lst:\n for element in sublist:\n if element in frequencies:\n frequencies[element] += 1\n else:\n frequencies[element] = 1\n return frequencies", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lst):\n \"\"\"\n Write a function to find frequency of each element in a flattened list of lists, \n returned in a dictionary.\n assert frequency_lists([[1, 2, 3, 2], [4, 5, 6, 2], [7, 8, 9, 5]])=={1: 1, 2: 3, 3: 1, 4: 1, 5: 2, 6: 1, 7: 1, 8: 1, 9: 1}\n \"\"\"\n frequency = {}\n for sublist in lst:\n for element in sublist:\n if element in frequency:\n frequency[element]+=1\n else:\n frequency[element] = 1\n return frequency", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(nested_list):\n \"\"\"\n Finds the frequency of each element in a flattened list of lists, returned in a dictionary.\n\n Args:\n nested_list: A list of lists.\n\n Returns:\n A dictionary where keys are elements from the nested list and values are their frequencies.\n \"\"\"\n frequencies = {}\n for sublist in nested_list:\n for element in sublist:\n if element in frequencies:\n frequencies[element] += 1\n else:\n frequencies[element] = 1\n return frequencies", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(input_list):\n \"\"\"\n Finds the frequency of each element in a flattened list of lists.\n\n Args:\n input_list: A list of lists.\n\n Returns:\n A dictionary where keys are elements from the input list and values are their frequencies.\n \"\"\"\n frequency = {}\n for sublist in input_list:\n for element in sublist:\n if element in frequency:\n frequency[element] += 1\n else:\n frequency[element] = 1\n return frequency", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(nested_list):\n \"\"\"\n Finds the frequency of each element in a flattened list of lists.\n\n Args:\n nested_list: A list of lists.\n\n Returns:\n A dictionary where keys are elements from the nested list and values are their frequencies.\n \"\"\"\n flattened = [item for sublist in nested_list for item in sublist]\n frequency = {}\n for item in flattened:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n return frequency", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(list_of_lists):\n \"\"\"\n Finds the frequency of each element in a flattened list of lists, returned in a dictionary.\n\n Args:\n list_of_lists: A list of lists.\n\n Returns:\n A dictionary where keys are the elements and values are their frequencies.\n \"\"\"\n\n flattened_list = [item for sublist in list_of_lists for item in sublist]\n frequency = {}\n for item in flattened_list:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n return frequency", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(nested_list):\n \"\"\"\n Finds frequency of each element in a flattened list of lists, returned in a dictionary.\n\n Args:\n nested_list: A list of lists.\n\n Returns:\n A dictionary where keys are unique elements from the nested list and values are their frequencies.\n \"\"\"\n flat_list = [item for sublist in nested_list for item in sublist]\n frequency = {}\n for item in flat_list:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n return frequency", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(input_list):\n \"\"\"\n Write a function to find frequency of each element in a flattened list of lists, returned in a dictionary.\n assert frequency_lists([[1, 2, 3, 2], [4, 5, 6, 2], [7, 8, 9, 5]])=={1: 1, 2: 3, 3: 1, 4: 1, 5: 2, 6: 1, 7: 1, 8: 1, 9: 1}\n \"\"\"\n frequency = {}\n for sublist in input_list:\n for element in sublist:\n if element in frequency:\n frequency[element] += 1\n else:\n frequency[element] = 1\n return frequency", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lists_of_lists):\n \"\"\"\n Finds frequency of each element in a flattened list of lists, returned in a dictionary.\n\n Args:\n lists_of_lists: A list of lists, where each inner list contains integers.\n\n Returns:\n A dictionary where keys are the unique elements from the flattened list and \n values are their frequencies.\n\n Examples:\n frequency_lists([[1, 2, 3, 2], [4, 5, 6, 2], [7, 8, 9, 5]])=={1: 1, 2: 3, 3: 1, 4: 1, 5: 2, 6: 1, 7: 1, 8: 1, 9: 1}\n \"\"\"\n flattened_list = [item for sublist in lists_of_lists for item in sublist]\n frequency = {}\n for item in flattened_list:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n return frequency", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(input_list):\n \"\"\"\n Finds the frequency of each element in a flattened list of lists.\n\n Args:\n input_list: A list of lists.\n\n Returns:\n A dictionary where keys are elements from the input list and values are their frequencies.\n \"\"\"\n flattened = [item for sublist in input_list for item in sublist]\n frequency = {}\n for item in flattened:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n return frequency", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(nested_list):\n \"\"\"\n Finds the frequency of each element in a flattened list of lists, returned in a dictionary.\n \n Args:\n nested_list: A list of lists.\n\n Returns:\n A dictionary where keys are unique elements from the flattened list and values are their frequencies.\n\n Examples:\n frequency_lists([[1, 2, 3, 2], [4, 5, 6, 2], [7, 8, 9, 5]])=={1: 1, 2: 3, 3: 1, 4: 1, 5: 2, 6: 1, 7: 1, 8: 1, 9: 1}\n \"\"\"\n flattened_list = [item for sublist in nested_list for item in sublist]\n frequency = {}\n for item in flattened_list:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n return frequency", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(nested_list):\n \"\"\"\n Finds the frequency of each element in a flattened list of lists.\n\n Args:\n nested_list: A list of lists.\n\n Returns:\n A dictionary where keys are the elements and values are their frequencies.\n \"\"\"\n flattened = [item for sublist in nested_list for item in sublist]\n frequency = {}\n for item in flattened:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n return frequency", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(data):\n \"\"\"\n Finds frequency of each element in a flattened list of lists.\n\n Args:\n data: A list of lists.\n\n Returns:\n A dictionary where keys are elements from the input list and values are their frequencies.\n \"\"\"\n frequency = {}\n for sublist in data:\n for element in sublist:\n if element in frequency:\n frequency[element] += 1\n else:\n frequency[element] = 1\n return frequency", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(nested_list):\n \"\"\"\n Finds the frequency of each element in a flattened list of lists, \n returned in a dictionary.\n \n Args:\n nested_list: A list of lists.\n\n Returns:\n A dictionary where keys are elements from the nested list and \n values are their frequencies.\n\n \"\"\"\n flattened_list = [item for sublist in nested_list for item in sublist]\n frequency = {}\n for item in flattened_list:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n return frequency", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(nested_list):\n \"\"\"\n Finds the frequency of each element in a flattened list of lists, returned in a dictionary.\n\n Args:\n nested_list: A list of lists.\n\n Returns:\n A dictionary where keys are the unique elements in the flattened list and values are their frequencies.\n \"\"\"\n flattened_list = [item for sublist in nested_list for item in sublist]\n frequency = {}\n for item in flattened_list:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n return frequency", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lst):\n \"\"\"\n Finds the frequency of each element in a flattened list of lists.\n\n Args:\n lst: A list of lists.\n\n Returns:\n A dictionary where keys are the unique elements in the flattened list and\n values are their frequencies.\n \"\"\"\n flattened = [item for sublist in lst for item in sublist]\n frequency = {}\n for item in flattened:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n return frequency", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(nested_list):\n \"\"\"\n Finds frequency of each element in a flattened list of lists.\n\n Args:\n nested_list: A list of lists.\n\n Returns:\n A dictionary where keys are elements and values are their frequencies.\n \"\"\"\n flat_list = [item for sublist in nested_list for item in sublist]\n frequency = {}\n for item in flat_list:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n return frequency", "matching_cluster_idx": 6}]}, "Mbpp/106": {"dps": 81.88311688311688, "dps_norm": 95.0, "pass@1": 24.0, "profiled": [{"solution": "def add_lists(input_list, input_tuple):\n \"\"\"\n Append the given list to the given tuple.\n \n Args:\n input_list: A list of integers.\n input_tuple: A tuple of integers.\n \n Returns:\n A new tuple containing all elements of the input tuple followed by all elements of the input list.\n \"\"\"\n return input_tuple + tuple(input_list)", "matching_cluster_idx": 5}, {"solution": "def add_lists(list_to_add, tuple_to_add_to):\n \"\"\"\n Appends the given list to the given tuples.\n\n Args:\n list_to_add: A list to be appended to the tuple.\n tuple_to_add_to: A tuple to which the list is appended.\n\n Returns:\n A new tuple with the list appended.\n \"\"\"\n return tuple_to_add_to + tuple(list_to_add)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tup):\n \"\"\"\n Appends the elements of the given list to the given tuple.\n \"\"\"\n return tup + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(numbers, my_tuple):\n \"\"\"Appends the given list to the given tuple.\n\n Args:\n numbers: A list of numbers.\n my_tuple: A tuple of numbers.\n\n Returns:\n A new tuple containing all elements from the tuple and the list.\n \"\"\"\n return my_tuple + tuple(numbers)", "matching_cluster_idx": 5}, {"solution": "def add_lists(list_to_append, tuple_to_append_to):\n \"\"\"\n Appends the given list to the given tuples.\n\n Args:\n list_to_append: The list to append.\n tuple_to_append_to: The tuple to append to.\n\n Returns:\n A new tuple containing all elements from the input tuple followed by all\n elements from the input list.\n \"\"\"\n return tuple(tuple_to_append_to) + tuple(list_to_append)", "matching_cluster_idx": 4}, {"solution": "def add_lists(list1, tuple1):\n \"\"\"\n Appends the given list to the given tuple.\n\n Args:\n list1: A list of numbers.\n tuple1: A tuple of numbers.\n\n Returns:\n A new tuple containing all elements from the tuple and list.\n \"\"\"\n return tuple1 + tuple(list1)", "matching_cluster_idx": 5}, {"solution": "def add_lists(nums, tuple_input):\n \"\"\"\n Appends the given list to the given tuples.\n\n Args:\n nums: A list of numbers.\n tuple_input: A tuple of numbers.\n\n Returns:\n A new tuple containing the elements of the input tuple followed by the elements of the input list.\n \"\"\"\n return tuple_input + tuple(nums)", "matching_cluster_idx": 4}, {"solution": "def add_lists(nums, my_tuple):\n \"\"\"\n Appends the elements of a list to a tuple.\n\n Args:\n nums: A list of numbers.\n my_tuple: A tuple of numbers.\n\n Returns:\n A new tuple containing all the elements of the tuple and the list.\n \"\"\"\n return my_tuple + tuple(nums)", "matching_cluster_idx": 5}, {"solution": "def add_lists(numbers, coordinates):\n \"\"\"\n Appends the given list to the given tuple.\n\n Args:\n numbers: A list of numbers.\n coordinates: A tuple of numbers.\n\n Returns:\n A new tuple containing the elements of the tuple followed by the elements of the list.\n \"\"\"\n return coordinates + tuple(numbers)", "matching_cluster_idx": 5}, {"solution": "def add_lists(nums_list, nums_tuple):\n \"\"\"\n Appends the given list to the given tuples.\n\n Args:\n nums_list: A list of numbers.\n nums_tuple: A tuple of numbers.\n\n Returns:\n A new tuple that includes all elements from the input tuple followed by all elements from the input list.\n \"\"\"\n return nums_tuple + tuple(nums_list)", "matching_cluster_idx": 5}, {"solution": "def add_lists(nums_list, nums_tuple):\n \"\"\"\n Appends the given list to the given tuples.\n\n Args:\n nums_list: A list of numbers.\n nums_tuple: A tuple of numbers.\n\n Returns:\n A new tuple containing all elements from the tuple and the list.\n \"\"\"\n return nums_tuple + tuple(nums_list)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tup):\n \"\"\"\n Appends the given list to the given tuple.\n\n Args:\n lst: The list to be appended.\n tup: The tuple to append the list to.\n\n Returns:\n A new tuple containing the elements of the tuple followed by the elements of the list.\n \"\"\"\n return tup + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(numbers, data):\n \"\"\"\n Append the given list to the given tuples.\n assert add_lists([5, 6, 7], (9, 10)) == (9, 10, 5, 6, 7)\n \"\"\"\n return tuple(data) + tuple(numbers)", "matching_cluster_idx": 4}, {"solution": "def add_lists(list1, tuple1):\n \"\"\"\n Appends the given list to the given tuple.\n\n Args:\n list1: The list to append.\n tuple1: The tuple to append to.\n\n Returns:\n A new tuple containing the elements of the tuple and the list.\n \"\"\"\n return tuple1 + tuple(list1)", "matching_cluster_idx": 5}, {"solution": "def add_lists(list1, tuple1):\n \"\"\"\n Appends the elements of a list to a tuple.\n\n Args:\n list1: A list of numbers.\n tuple1: A tuple of numbers.\n\n Returns:\n A new tuple containing the elements of the tuple followed by the elements of the list.\n \"\"\"\n return tuple1 + tuple(list1)", "matching_cluster_idx": 4}, {"solution": "def add_lists(input_list, input_tuple):\n \"\"\"\n Appends the given list to the given tuples.\n\n Args:\n input_list: A list of integers.\n input_tuple: A tuple of integers.\n\n Returns:\n A new tuple containing all elements from the input tuple followed by all elements from the input list.\n \"\"\"\n return input_tuple + tuple(input_list)", "matching_cluster_idx": 5}, {"solution": "def add_lists(nums, tuple1):\n \"\"\"\n Appends the elements of a list to a tuple.\n\n Args:\n nums: A list of numbers.\n tuple1: A tuple of numbers.\n\n Returns:\n A new tuple containing all elements from tuple1 followed by the elements of nums.\n \"\"\"\n return tuple1 + tuple(nums)", "matching_cluster_idx": 5}, {"solution": "def add_lists(input_list, input_tuple):\n \"\"\"Appends the given list to the given tuple.\n\n Args:\n input_list: The list to append.\n input_tuple: The tuple to append to.\n\n Returns:\n A new tuple containing all elements of the input tuple followed by all elements of the input list.\n \"\"\"\n return input_tuple + tuple(input_list)", "matching_cluster_idx": 5}, {"solution": "def add_lists(list1, tuple1):\n \"\"\"\n Appends the elements of a list to a tuple.\n\n Args:\n list1: The list to be appended.\n tuple1: The tuple to append to.\n\n Returns:\n A new tuple containing the elements of the tuple and the list.\n \"\"\"\n return tuple1 + tuple(list1)", "matching_cluster_idx": 4}, {"solution": "def add_lists(list1, tup1):\n \"\"\"\n Appends the given list to the given tuple.\n\n Args:\n list1: The list to append.\n tup1: The tuple to append to.\n\n Returns:\n A new tuple containing the elements of the tuple followed by the elements of the list.\n \"\"\"\n return tup1 + tuple(list1)", "matching_cluster_idx": 4}]}, "Mbpp/108": {"dps": null, "dps_norm": null, "pass@1": 7.0, "profiled": []}, "Mbpp/111": {"dps": 87.61538461538461, "dps_norm": 85.625, "pass@1": 100.0, "profiled": [{"solution": "def common_in_nested_lists(nested_lists):\n \"\"\"\n Finds the common elements in given nested lists.\n\n Args:\n nested_lists: A list of lists of integers.\n\n Returns:\n A set of common elements present in all the nested lists.\n \"\"\"\n common = set(nested_lists[0]) \n for lst in nested_lists[1:]:\n common.intersection_update(set(lst))\n return common", "matching_cluster_idx": 5}, {"solution": "def common_in_nested_lists(nested_lists):\n \"\"\"\n Finds the common elements in a given list of nested lists.\n\n Args:\n nested_lists: A list of nested lists.\n\n Returns:\n A set of common elements found in all nested lists.\n \"\"\"\n common = set(nested_lists[0]) # Start with the first list's elements as the initial common set\n for lst in nested_lists[1:]:\n common &= set(lst) # Intersection operation to find common elements with subsequent lists\n return common", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n \"\"\"\n Finds common elements in given nested lists.\n \n Args:\n nested_lists: A list of lists.\n\n Returns:\n A set of common elements.\n \"\"\"\n common = set(nested_lists[0])\n for lst in nested_lists[1:]:\n common.intersection_update(lst)\n return common", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n \"\"\"\n Finds the common elements in a list of nested lists.\n\n Args:\n nested_lists: A list of nested lists.\n\n Returns:\n A set of common elements found in all nested lists.\n \"\"\"\n common = set(nested_lists[0]) \n for lst in nested_lists[1:]:\n common = common.intersection(set(lst))\n return common", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n \"\"\"\n Finds the common elements in given nested lists.\n \"\"\"\n common = set(nested_lists[0]) # Start with the elements of the first list\n for lst in nested_lists[1:]:\n common &= set(lst) # Intersection operation to find common elements\n return common", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n \"\"\"\n Finds the common elements in given nested lists.\n\n Args:\n nested_lists: A list of nested lists.\n\n Returns:\n A set of common elements found in all the nested lists.\n \"\"\"\n common = set(nested_lists[0])\n for lst in nested_lists[1:]:\n common &= set(lst)\n return common", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n \"\"\"\n Finds the common elements in given nested lists.\n\n Args:\n nested_lists: A list of lists.\n\n Returns:\n A set of the common elements.\n \"\"\"\n common = set(nested_lists[0]) \n for lst in nested_lists[1:]:\n common &= set(lst) \n return common", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n \"\"\"\n Finds the common elements in a given nested lists.\n \"\"\"\n common = set(nested_lists[0]) \n for lst in nested_lists[1:]:\n common &= set(lst) \n return common", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_list):\n \"\"\"Finds the common elements in a given list of nested lists.\n\n Args:\n nested_list: A list of nested lists.\n\n Returns:\n A set of common elements in all nested lists.\n \"\"\"\n common = set(nested_list[0]) \n for sublist in nested_list[1:]:\n common.intersection_update(set(sublist))\n return common", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n \"\"\"\n Finds the common elements in given nested lists.\n\n Args:\n nested_lists: A list of lists containing integers.\n\n Returns:\n A set containing the common elements across all lists.\n \"\"\"\n common = set(nested_lists[0]) \n for lst in nested_lists[1:]:\n common &= set(lst)\n return common", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_list):\n \"\"\"\n Finds the common elements in a list of nested lists.\n\n Args:\n nested_list: A list of nested lists.\n\n Returns:\n A set of common elements found in all the nested lists.\n \"\"\"\n common = set(nested_list[0]) \n for lst in nested_list[1:]:\n common.intersection_update(lst)\n return common", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n \"\"\"\n Finds the common elements in a list of nested lists.\n\n Args:\n nested_lists: A list of lists.\n\n Returns:\n A set of common elements.\n \"\"\"\n\n common_elements = set(nested_lists[0]) # Initialize with elements of the first list\n for lst in nested_lists[1:]:\n common_elements &= set(lst) # Update common_elements by intersection\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n \"\"\"\n Finds the common elements in given nested lists.\n\n Args:\n nested_lists: A list of lists.\n\n Returns:\n A set of common elements.\n \"\"\"\n common = set(nested_lists[0]) \n for lst in nested_lists[1:]:\n common &= set(lst) \n return common", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_list):\n \"\"\"\n Finds the common elements in given nested lists.\n\n Args:\n nested_list: A list of lists.\n\n Returns:\n A set of common elements.\n \"\"\"\n\n common = set(nested_list[0])\n for sublist in nested_list[1:]:\n common &= set(sublist)\n return common", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n \"\"\"Finds the common elements in a given list of nested lists.\n\n Args:\n nested_lists: A list of lists, where each inner list contains integers.\n\n Returns:\n A set containing the common elements in all the nested lists.\n \"\"\"\n common = set(nested_lists[0])\n for lst in nested_lists[1:]:\n common.intersection_update(set(lst))\n return common", "matching_cluster_idx": 5}, {"solution": "def common_in_nested_lists(lists):\n \"\"\"\n Finds the common elements in given nested lists.\n\n Args:\n lists: A list of lists.\n\n Returns:\n A set of common elements.\n \"\"\"\n common = set(lists[0]) # Start with the elements of the first list\n for lst in lists[1:]:\n common &= set(lst) # Intersect with each subsequent list\n return common", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n \"\"\"\n Finds the common elements in a list of nested lists.\n\n Args:\n nested_lists: A list of lists.\n\n Returns:\n A set containing the common elements in all nested lists.\n \"\"\"\n common = set(nested_lists[0]) \n for lst in nested_lists[1:]:\n common &= set(lst) \n return common", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n \"\"\"Finds the common elements in given nested lists.\n\n Args:\n nested_lists: A list of lists, where each inner list contains integers.\n\n Returns:\n A set containing the common elements in all nested lists.\n \"\"\"\n common = set(nested_lists[0]) # Start with the elements of the first list\n for sublist in nested_lists[1:]:\n common &= set(sublist) # Intersection with subsequent lists\n return common", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n \"\"\"\n Finds the common elements in a list of nested lists.\n Args:\n nested_lists: A list of lists.\n Returns:\n A set of the common elements.\n \"\"\"\n common = set(nested_lists[0]) \n for lst in nested_lists[1:]:\n common.intersection_update(set(lst))\n return common", "matching_cluster_idx": 5}, {"solution": "def common_in_nested_lists(nested_lists):\n \"\"\"Finds the common elements in a list of nested lists.\n\n Args:\n nested_lists: A list of nested lists.\n\n Returns:\n A set containing the common elements in all the nested lists.\n \"\"\"\n common = set(nested_lists[0])\n for lst in nested_lists[1:]:\n common &= set(lst)\n return common", "matching_cluster_idx": 6}]}, "Mbpp/123": {"dps": null, "dps_norm": null, "pass@1": 5.0, "profiled": []}, "Mbpp/128": {"dps": 99.5475113122172, "dps_norm": 80.0, "pass@1": 86.0, "profiled": [{"solution": "def long_words(n, sentence):\n \"\"\"\n Finds words that are longer than n characters from a given list of words.\n\n Args:\n n: The minimum length of words to be returned.\n sentence: A string of words separated by spaces.\n\n Returns:\n A list of words from the sentence that are longer than n characters.\n \"\"\"\n words = sentence.split()\n long_list = []\n for word in words:\n if len(word) > n:\n long_list.append(word)\n return long_list", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n \"\"\"\n Finds words that are longer than n characters from a given list of words.\n\n Args:\n n: The minimum length of words to be included.\n sentence: A string of words separated by spaces.\n\n Returns:\n A list of words from the sentence that are longer than n characters.\n \"\"\"\n words = sentence.split()\n long_words = [word for word in words if len(word) > n]\n return long_words", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n \"\"\"\n This function finds words that are longer than n characters from a given list of words.\n\n Args:\n n: An integer representing the minimum word length.\n sentence: A string containing space-separated words.\n\n Returns:\n A list of words from the input sentence that are longer than n characters.\n \"\"\"\n\n words = sentence.split()\n long_words = [word for word in words if len(word) > n]\n return long_words", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n \"\"\"\n This function takes an integer n and a string sentence as input.\n It returns a list of words from the sentence that are longer than n characters.\n \"\"\"\n words = sentence.split()\n long_word_list = [word for word in words if len(word) > n]\n return long_word_list", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n \"\"\"\n Finds words longer than n characters from a given list of words.\n\n Args:\n n: The minimum length of words to keep.\n sentence: A string containing words separated by spaces.\n\n Returns:\n A list of words from the sentence that are longer than n characters.\n \"\"\"\n words = sentence.split()\n return [word for word in words if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n \"\"\"\n Finds words that are longer than n characters from a given list of words.\n\n Args:\n n: The minimum length of words to include.\n sentence: A string containing words separated by spaces.\n\n Returns:\n A list of words from the sentence that are longer than n characters.\n \"\"\"\n words = sentence.split()\n long_words = [word for word in words if len(word) > n]\n return long_words", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n \"\"\"\n Finds words that are longer than n characters from a given list of words.\n\n Args:\n n: The minimum length of words to include.\n sentence: A string of words separated by spaces.\n\n Returns:\n A list of words from the input sentence that are longer than n characters.\n \"\"\"\n words = sentence.split()\n long_words = [word for word in words if len(word) > n]\n return long_words", "matching_cluster_idx": 3}, {"solution": "def long_words(n, text):\n \"\"\"\n Finds words that are longer than n characters from a given list of words.\n\n Args:\n n: The minimum length of words to keep.\n text: A string containing space-separated words.\n\n Returns:\n A list of words longer than n characters.\n \"\"\"\n words = text.split()\n return [word for word in words if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n,sentence):\n \"\"\"\n Finds words that are longer than n characters from a given list of words.\n \"\"\"\n words = sentence.split()\n long_words = [word for word in words if len(word) > n]\n return long_words", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n \"\"\"\n Finds words that are longer than n characters from a given list of words.\n\n Args:\n n: The minimum length of the words to be returned.\n sentence: A string of words separated by spaces.\n\n Returns:\n A list of words longer than n characters.\n \"\"\"\n words = sentence.split()\n return [word for word in words if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n \"\"\"\n Finds words that are longer than n characters from a given list of words.\n \"\"\"\n words = sentence.split()\n return [word for word in words if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, text):\n \"\"\"\n Finds words that are longer than n characters from a given list of words.\n\n Args:\n n: The minimum length of words to include.\n text: A string of words separated by spaces.\n\n Returns:\n A list of words longer than n characters.\n \"\"\"\n words = text.split()\n return [word for word in words if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n \"\"\"\n Finds words that are longer than n characters from a given list of words.\n\n Args:\n n: The minimum length of words to return.\n sentence: A string containing a list of words separated by spaces.\n\n Returns:\n A list of words from the sentence that are longer than n characters.\n \"\"\"\n words = sentence.split()\n long_words = [word for word in words if len(word) > n]\n return long_words", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n \"\"\"\n Finds words that are longer than n characters from a given list of words.\n\n Args:\n n: The minimum length of words to include.\n sentence: A string of words separated by spaces.\n\n Returns:\n A list of words from the input sentence that are longer than n characters.\n \"\"\"\n words = sentence.split()\n long_words = [word for word in words if len(word) > n]\n return long_words", "matching_cluster_idx": 3}, {"solution": "def long_words(n, text):\n \"\"\"\n Finds words that are longer than n characters from a given list of words.\n\n Args:\n n: The minimum length of words to keep.\n text: A string of words separated by spaces.\n\n Returns:\n A list of words from the input string that are longer than n characters.\n \"\"\"\n words = text.split()\n return [word for word in words if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n \"\"\"\n Finds words that are longer than n characters from a given list of words.\n\n Args:\n n: The minimum length of a word to be considered long.\n sentence: A string containing words separated by spaces.\n\n Returns:\n A list of words from the sentence that are longer than n characters.\n \"\"\"\n\n words = sentence.split()\n long_words = [word for word in words if len(word) > n]\n return long_words", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n \"\"\"\n Finds words longer than n characters from a given list of words.\n\n Args:\n n: The minimum length of words to return.\n sentence: A string containing space-separated words.\n\n Returns:\n A list of words from the sentence that are longer than n characters.\n \"\"\"\n words = sentence.split()\n long_words = [word for word in words if len(word) > n]\n return long_words", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n \"\"\"\n Finds words that are longer than n characters from a given list of words.\n \n Args:\n n: The minimum length of the words to include.\n sentence: A string of words separated by spaces.\n\n Returns:\n A list of words from the input sentence that are longer than n characters.\n \"\"\"\n words = sentence.split()\n return [word for word in words if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n \"\"\"\n Finds words longer than n characters from a given list of words.\n\n Args:\n n: The minimum length of words to include.\n sentence: A string of words separated by spaces.\n\n Returns:\n A list of words from the sentence that are longer than n characters.\n \"\"\"\n words = sentence.split()\n long_words = [word for word in words if len(word) > n]\n return long_words", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n \"\"\"\n Finds words longer than n characters from a given list of words.\n\n Args:\n n: The minimum length of the words to return.\n sentence: A string of words separated by spaces.\n\n Returns:\n A list of words from the input sentence that are longer than n characters.\n \"\"\"\n words = sentence.split()\n return [word for word in words if len(word) > n]", "matching_cluster_idx": 3}]}, "Mbpp/129": {"dps": 64.46428571428572, "dps_norm": 95.33333333333333, "pass@1": 92.0, "profiled": [{"solution": "def magic_square_test(matrix):\n n = len(matrix)\n magic_sum = sum(matrix[0])\n for i in range(n):\n if sum(matrix[i]) != magic_sum:\n return False\n if sum([matrix[j][i] for j in range(n)]) != magic_sum:\n return False\n return True", "matching_cluster_idx": 13}, {"solution": "def magic_square_test(matrix):\n \"\"\"\n Checks if a given matrix is a magic square.\n\n Args:\n matrix: A list of lists representing a square matrix.\n\n Returns:\n True if the matrix is a magic square, False otherwise.\n \"\"\"\n n = len(matrix)\n magic_sum = sum(matrix[0]) # Calculate the magic sum\n for i in range(n):\n if sum(matrix[i]) != magic_sum: # Check rows\n return False\n if sum([matrix[j][i] for j in range(n)]) != magic_sum: # Check columns\n return False\n \n # Check diagonals\n if sum([matrix[i][i] for i in range(n)]) != magic_sum:\n return False\n if sum([matrix[i][n-i-1] for i in range(n)]) != magic_sum:\n return False\n return True", "matching_cluster_idx": 13}, {"solution": "def magic_square_test(matrix):\n \"\"\"\n Calculates whether the matrix is a magic square.\n\n Args:\n matrix: A 2D list representing the matrix.\n\n Returns:\n True if the matrix is a magic square, False otherwise.\n \"\"\"\n n = len(matrix)\n magic_sum = sum(matrix[0]) # Calculate the sum of the first row\n\n for i in range(n):\n if sum(matrix[i]) != magic_sum:\n return False # Check each row for equal sum\n\n for j in range(n):\n if sum([matrix[i][j] for i in range(n)]) != magic_sum:\n return False # Check each column for equal sum\n\n if sum([matrix[i][i] for i in range(n)]) != magic_sum:\n return False # Check the primary diagonal\n\n if sum([matrix[i][n-i-1] for i in range(n)]) != magic_sum:\n return False # Check the secondary diagonal\n\n return True # All checks passed, it's a magic square", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n \"\"\"\n Calculate whether the matrix is a magic square.\n\n Args:\n matrix: A list of lists representing the matrix.\n\n Returns:\n True if the matrix is a magic square, False otherwise.\n \"\"\"\n n = len(matrix)\n magic_sum = sum(matrix[0])\n for i in range(n):\n if sum(matrix[i]) != magic_sum:\n return False\n if sum([matrix[j][i] for j in range(n)]) != magic_sum:\n return False\n return True", "matching_cluster_idx": 13}, {"solution": "def magic_square_test(matrix):\n \"\"\"\n This function determines if a given matrix is a magic square.\n\n Args:\n matrix: A list of lists representing the matrix.\n\n Returns:\n True if the matrix is a magic square, False otherwise.\n \"\"\"\n n = len(matrix)\n magic_sum = sum(matrix[0])\n for i in range(n):\n if sum(matrix[i]) != magic_sum:\n return False\n for j in range(n):\n if sum([matrix[i][j] for i in range(n)]) != magic_sum:\n return False\n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n \"\"\"\n Calculates whether the matrix is a magic square.\n\n Args:\n matrix: A 2D list representing the matrix.\n\n Returns:\n True if the matrix is a magic square, False otherwise.\n \"\"\"\n\n n = len(matrix)\n magic_sum = sum(matrix[0]) \n\n for i in range(n):\n if sum(matrix[i]) != magic_sum:\n return False\n if sum([matrix[j][i] for j in range(n)]) != magic_sum:\n return False\n return True", "matching_cluster_idx": 13}, {"solution": "def magic_square_test(matrix):\n \"\"\"\n Write a function to calculate whether the matrix is a magic square.\n assert magic_square_test([[7, 12, 1, 14], [2, 13, 8, 11], [16, 3, 10, 5], [9, 6, 15, 4]])==True\n \"\"\"\n n = len(matrix)\n magic_sum = sum(matrix[0])\n \n for i in range(n):\n if sum(matrix[i]) != magic_sum:\n return False\n \n for j in range(n):\n if sum([matrix[i][j] for i in range(n)]) != magic_sum:\n return False\n \n return True\nmatrix = [[7, 12, 1, 14], [2, 13, 8, 11], [16, 3, 10, 5], [9, 6, 15, 4]]", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n n = len(matrix)\n magic_sum = sum(matrix[0]) # Calculate the magic sum\n for i in range(n):\n if sum(matrix[i]) != magic_sum:\n return False\n for j in range(n):\n if sum([matrix[i][j] for i in range(n)]) != magic_sum:\n return False\n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n \"\"\"\n Calculates whether the matrix is a magic square.\n\n Args:\n matrix: A 2D list representing the matrix.\n\n Returns:\n True if the matrix is a magic square, False otherwise.\n \"\"\"\n n = len(matrix)\n magic_sum = sum(matrix[0]) # Calculate the sum of the first row\n\n for i in range(n):\n # Check rows\n if sum(matrix[i]) != magic_sum:\n return False\n # Check columns\n if sum([matrix[j][i] for j in range(n)]) != magic_sum:\n return False\n\n # Check diagonals\n if sum([matrix[i][i] for i in range(n)]) != magic_sum:\n return False\n if sum([matrix[i][n-i-1] for i in range(n)]) != magic_sum:\n return False\n\n return True", "matching_cluster_idx": 13}, {"solution": "def magic_square_test(matrix):\n \"\"\"\n Checks if a given matrix is a magic square.\n\n Args:\n matrix: A list of lists representing the matrix.\n\n Returns:\n True if the matrix is a magic square, False otherwise.\n \"\"\"\n n = len(matrix)\n magic_sum = sum(matrix[0]) # Calculate the sum of the first row\n\n for i in range(n):\n if sum(matrix[i]) != magic_sum: # Check if each row sums to magic_sum\n return False\n if sum([matrix[j][i] for j in range(n)]) != magic_sum: # Check if each column sums to magic_sum\n return False\n if sum([matrix[i][i] for i in range(n)]) != magic_sum: # Check the primary diagonal\n return False\n if sum([matrix[i][n-i-1] for i in range(n)]) != magic_sum: # Check the secondary diagonal\n return False\n\n return True", "matching_cluster_idx": 13}, {"solution": "def magic_square_test(matrix):\n \"\"\"\n Calculates whether the matrix is a magic square.\n\n Args:\n matrix: A list of lists representing the matrix.\n\n Returns:\n True if the matrix is a magic square, False otherwise.\n \"\"\"\n n = len(matrix)\n magic_sum = sum(matrix[0]) \n for i in range(n):\n if sum(matrix[i]) != magic_sum:\n return False\n if sum([matrix[j][i] for j in range(n)]) != magic_sum:\n return False\n return True", "matching_cluster_idx": 13}, {"solution": "def magic_square_test(matrix):\n \"\"\"\n This function checks if a given matrix is a magic square.\n Args:\n matrix: A 2D list representing a square matrix.\n Returns:\n True if the matrix is a magic square, False otherwise.\n \"\"\"\n n = len(matrix)\n magic_sum = sum(matrix[0])\n for i in range(n):\n if sum(matrix[i]) != magic_sum:\n return False\n if sum([matrix[j][i] for j in range(n)]) != magic_sum:\n return False\n return True", "matching_cluster_idx": 13}, {"solution": "def magic_square_test(matrix):\n \"\"\"\n Checks if a matrix is a magic square.\n \"\"\"\n n = len(matrix)\n magic_sum = sum(matrix[0]) # Calculate the sum of the first row\n for i in range(n):\n if sum(matrix[i]) != magic_sum: # Check if each row sums to the magic sum\n return False\n if sum([matrix[j][i] for j in range(n)]) != magic_sum: # Check if each column sums to the magic sum\n return False\n \n return True", "matching_cluster_idx": 13}, {"solution": "def magic_square_test(matrix):\n \"\"\"\n Calculates whether the matrix is a magic square.\n\n Args:\n matrix: A list of lists representing the matrix.\n\n Returns:\n True if the matrix is a magic square, False otherwise.\n \"\"\"\n n = len(matrix)\n magic_sum = sum(matrix[0]) # Calculate the magic sum\n\n for i in range(n):\n if sum(matrix[i]) != magic_sum:\n return False # Check row sums\n\n for j in range(n):\n if sum([matrix[i][j] for i in range(n)]) != magic_sum:\n return False # Check column sums\n\n # Check diagonals\n if sum([matrix[i][i] for i in range(n)]) != magic_sum:\n return False\n if sum([matrix[i][n - 1 - i] for i in range(n)]) != magic_sum:\n return False\n\n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n \"\"\"\n Calculates whether the matrix is a magic square.\n\n Args:\n matrix: A list of lists representing the matrix.\n\n Returns:\n True if the matrix is a magic square, False otherwise.\n \"\"\"\n n = len(matrix)\n magic_sum = sum(matrix[0]) # Calculate the sum of the first row\n\n for i in range(n):\n if sum(matrix[i]) != magic_sum: # Check row sums\n return False\n if sum([matrix[j][i] for j in range(n)]) != magic_sum: # Check column sums\n return False\n\n if sum([matrix[i][i] for i in range(n)]) != magic_sum: # Check diagonal sums\n return False\n if sum([matrix[i][n-i-1] for i in range(n)]) != magic_sum: # Check anti-diagonal sums\n return False\n \n return True", "matching_cluster_idx": 13}, {"solution": "def magic_square_test(matrix):\n \"\"\"\n Calculates whether the matrix is a magic square.\n\n Args:\n matrix: A list of lists representing the matrix.\n\n Returns:\n True if the matrix is a magic square, False otherwise.\n \"\"\"\n n = len(matrix)\n magic_sum = sum(matrix[0]) # Calculate the magic sum\n for i in range(n):\n if sum(matrix[i]) != magic_sum: # Check rows\n return False\n if sum([matrix[j][i] for j in range(n)]) != magic_sum: # Check columns\n return False\n if sum([matrix[i][i] for i in range(n)]) != magic_sum: # Check diagonals\n return False\n if sum([matrix[i][n-i-1] for i in range(n)]) != magic_sum: # Check diagonals\n return False\n return True\nmatrix = [[7, 12, 1, 14], [2, 13, 8, 11], [16, 3, 10, 5], [9, 6, 15, 4]]", "matching_cluster_idx": 13}, {"solution": "def magic_square_test(matrix):\n \"\"\"\n Checks if a matrix is a magic square.\n\n A magic square is a square matrix where the sum of each row, column,\n and diagonal is equal.\n\n Args:\n matrix: A list of lists representing the square matrix.\n\n Returns:\n True if the matrix is a magic square, False otherwise.\n \"\"\"\n n = len(matrix) \n magic_sum = sum(matrix[0]) # Calculate the sum of the first row\n\n for i in range(n):\n if sum(matrix[i]) != magic_sum: # Check rows\n return False\n if sum([matrix[j][i] for j in range(n)]) != magic_sum: # Check columns\n return False\n \n if sum([matrix[i][i] for i in range(n)]) != magic_sum: # Check primary diagonal\n return False\n if sum([matrix[i][n-i-1] for i in range(n)]) != magic_sum: # Check secondary diagonal\n return False\n\n return True", "matching_cluster_idx": 13}, {"solution": "def magic_square_test(matrix):\n n = len(matrix)\n magic_sum = sum(matrix[0]) # Calculate the magic sum from the first row\n for i in range(n):\n if sum(matrix[i]) != magic_sum:\n return False\n if sum([matrix[j][i] for j in range(n)]) != magic_sum:\n return False\n return True", "matching_cluster_idx": 13}, {"solution": "def magic_square_test(matrix):\n \"\"\"\n Calculates whether the matrix is a magic square.\n\n Args:\n matrix: A 2D list representing the matrix.\n\n Returns:\n True if the matrix is a magic square, False otherwise.\n \"\"\"\n n = len(matrix)\n total_sum = sum(matrix[0]) \n for i in range(n):\n if sum(matrix[i]) != total_sum:\n return False\n if sum([matrix[j][i] for j in range(n)]) != total_sum:\n return False\n return True", "matching_cluster_idx": 13}, {"solution": "def magic_square_test(matrix):\n \"\"\"\n Checks if a given matrix is a magic square.\n\n Args:\n matrix: A list of lists representing a square matrix.\n\n Returns:\n True if the matrix is a magic square, False otherwise.\n \"\"\"\n n = len(matrix)\n magic_sum = sum(matrix[0]) # Calculate the sum of the first row\n\n for row in matrix:\n if sum(row) != magic_sum:\n return False\n\n for col in range(n):\n if sum([matrix[row][col] for row in range(n)]) != magic_sum:\n return False\n\n # Check the diagonals\n if sum([matrix[i][i] for i in range(n)]) != magic_sum:\n return False\n if sum([matrix[i][n - i - 1] for i in range(n)]) != magic_sum:\n return False\n\n return True", "matching_cluster_idx": 14}]}, "Mbpp/130": {"dps": 78.32959641255606, "dps_norm": 69.16666666666667, "pass@1": 100.0, "profiled": [{"solution": "def max_occurrences(data):\n \"\"\"\n Finds the item with maximum frequency in a given list.\n Args:\n data: A list of items.\n Returns:\n The item with the maximum frequency.\n \"\"\"\n counts = {}\n for item in data:\n if item in counts:\n counts[item] += 1\n else:\n counts[item] = 1\n \n max_count = 0\n max_item = None\n for item, count in counts.items():\n if count > max_count:\n max_count = count\n max_item = item\n return max_item", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(data):\n \"\"\"\n Finds the item with maximum frequency in a given list.\n \n Args:\n data: A list of items.\n\n Returns:\n The item with the maximum frequency in the list.\n \"\"\"\n counts = {}\n for item in data:\n if item in counts:\n counts[item] += 1\n else:\n counts[item] = 1\n\n max_count = 0\n max_item = None\n for item, count in counts.items():\n if count > max_count:\n max_count = count\n max_item = item\n return max_item", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(data):\n \"\"\"\n Finds the item with maximum frequency in a given list.\n\n Args:\n data: A list of items.\n\n Returns:\n The item with the maximum frequency in the list.\n \"\"\"\n counts = {}\n for item in data:\n if item in counts:\n counts[item] += 1\n else:\n counts[item] = 1\n max_count = 0\n max_item = None\n for item, count in counts.items():\n if count > max_count:\n max_count = count\n max_item = item\n return max_item", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(data):\n \"\"\"\n Finds the item with maximum frequency in a given list.\n\n Args:\n data: A list of integers.\n\n Returns:\n The item with the maximum frequency in the list.\n \"\"\"\n counts = {}\n for item in data:\n if item in counts:\n counts[item] += 1\n else:\n counts[item] = 1\n\n max_count = 0\n max_item = None\n for item, count in counts.items():\n if count > max_count:\n max_count = count\n max_item = item\n return max_item", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(data):\n \"\"\"\n Finds the item with maximum frequency in a given list.\n\n Args:\n data: A list of integers.\n\n Returns:\n The item with the maximum frequency in the list.\n \"\"\"\n frequency = {}\n for item in data:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n max_item = None\n max_count = 0\n for item, count in frequency.items():\n if count > max_count:\n max_count = count\n max_item = item\n return max_item", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(data):\n \"\"\"\n Finds the item with maximum frequency in a given list.\n\n Args:\n data: A list of items.\n\n Returns:\n The item with the maximum frequency in the list.\n \"\"\"\n counts = {}\n for item in data:\n if item in counts:\n counts[item] += 1\n else:\n counts[item] = 1\n return max(counts, key=counts.get)", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(nums):\n \"\"\"\n Finds the item with maximum frequency in a given list.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n The item with the maximum frequency.\n \"\"\"\n counts = {}\n for num in nums:\n if num in counts:\n counts[num] += 1\n else:\n counts[num] = 1\n\n max_count = 0\n max_item = None\n for num, count in counts.items():\n if count > max_count:\n max_count = count\n max_item = num\n return max_item", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(data):\n \"\"\"\n Finds the item with maximum frequency in a given list.\n\n Args:\n data: A list of integers.\n\n Returns:\n The item with the maximum frequency in the list.\n \"\"\"\n counts = {}\n for item in data:\n if item in counts:\n counts[item] += 1\n else:\n counts[item] = 1\n \n max_count = 0\n max_item = None\n for item, count in counts.items():\n if count > max_count:\n max_count = count\n max_item = item\n return max_item", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(nums):\n \"\"\"\n Finds the item with maximum frequency in a given list.\n\n Args:\n nums: A list of integers.\n\n Returns:\n The item with the maximum frequency in the list.\n \"\"\"\n counts = {}\n for num in nums:\n if num in counts:\n counts[num] += 1\n else:\n counts[num] = 1\n \n max_count = 0\n max_item = None\n for num, count in counts.items():\n if count > max_count:\n max_count = count\n max_item = num\n return max_item", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(nums):\n \"\"\"\n Finds the item with maximum frequency in a given list.\n\n Args:\n nums: A list of integers.\n\n Returns:\n The item with the maximum frequency in the list.\n \"\"\"\n counts = {}\n for num in nums:\n if num in counts:\n counts[num] += 1\n else:\n counts[num] = 1\n\n max_count = 0\n max_item = None\n for num, count in counts.items():\n if count > max_count:\n max_count = count\n max_item = num\n return max_item", "matching_cluster_idx": 3}, {"solution": "from collections import Counter\ndef max_occurrences(data):\n \"\"\"\n Finds the item with maximum frequency in a given list.\n\n Args:\n data: A list of items.\n\n Returns:\n The item with the maximum frequency in the list.\n \"\"\"\n counts = Counter(data)\n return counts.most_common(1)[0][0]", "matching_cluster_idx": 4}, {"solution": "def max_occurrences(data):\n \"\"\"\n Finds the item with maximum frequency in a given list.\n\n Args:\n data: A list of items.\n\n Returns:\n The item with maximum frequency in the list.\n \"\"\"\n counts = {}\n for item in data:\n if item in counts:\n counts[item] += 1\n else:\n counts[item] = 1\n max_count = 0\n max_item = None\n for item, count in counts.items():\n if count > max_count:\n max_count = count\n max_item = item\n return max_item", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(nums):\n \"\"\"\n Finds the item with maximum frequency in a given list.\n\n Args:\n nums: A list of integers.\n\n Returns:\n The integer with the maximum frequency in the list.\n \"\"\"\n counts = {}\n for num in nums:\n if num in counts:\n counts[num] += 1\n else:\n counts[num] = 1\n max_count = 0\n max_item = None\n for num, count in counts.items():\n if count > max_count:\n max_count = count\n max_item = num\n return max_item", "matching_cluster_idx": 3}, {"solution": "from collections import Counter\ndef max_occurrences(data):\n \"\"\"Finds the item with maximum frequency in a given list.\n\n Args:\n data: A list of items.\n\n Returns:\n The item with the maximum frequency in the list.\n \"\"\"\n counts = Counter(data)\n return counts.most_common(1)[0][0]", "matching_cluster_idx": 4}, {"solution": "from collections import Counter\ndef max_occurrences(nums):\n \"\"\"Finds the item with maximum frequency in a list.\n\n Args:\n nums: A list of integers.\n\n Returns:\n The item with the maximum frequency.\n \"\"\"\n counts = Counter(nums)\n return counts.most_common(1)[0][0]", "matching_cluster_idx": 4}, {"solution": "def max_occurrences(data):\n \"\"\"\n Finds the item with maximum frequency in a given list.\n\n Args:\n data: A list of integers.\n\n Returns:\n The item with the maximum frequency in the list.\n \"\"\"\n counts = {}\n for item in data:\n if item in counts:\n counts[item] += 1\n else:\n counts[item] = 1\n max_count = 0\n max_item = None\n for item, count in counts.items():\n if count > max_count:\n max_count = count\n max_item = item\n return max_item", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(data):\n \"\"\"\n Finds the item with maximum frequency in a given list.\n\n Args:\n data: A list of integers.\n\n Returns:\n The item with the maximum frequency in the list.\n \"\"\"\n counts = {}\n for item in data:\n if item in counts:\n counts[item] += 1\n else:\n counts[item] = 1\n max_count = 0\n max_item = None\n for item, count in counts.items():\n if count > max_count:\n max_count = count\n max_item = item\n return max_item", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(nums):\n \"\"\"Finds the item with maximum frequency in a given list.\n\n Args:\n nums: A list of integers.\n\n Returns:\n The item with the maximum frequency in the list.\n \"\"\"\n counts = {}\n for num in nums:\n if num in counts:\n counts[num] += 1\n else:\n counts[num] = 1\n max_count = 0\n max_item = None\n for num, count in counts.items():\n if count > max_count:\n max_count = count\n max_item = num\n return max_item", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(data):\n \"\"\"Finds the item with maximum frequency in a given list.\n\n Args:\n data: A list of items.\n\n Returns:\n The item with the maximum frequency.\n \"\"\"\n counts = {}\n for item in data:\n if item in counts:\n counts[item] += 1\n else:\n counts[item] = 1\n return max(counts, key=counts.get)", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(nums):\n \"\"\"\n Finds the item with maximum frequency in a given list.\n\n Args:\n nums: A list of integers.\n\n Returns:\n The item with the maximum frequency in the list.\n \"\"\"\n counts = {}\n for num in nums:\n if num in counts:\n counts[num] += 1\n else:\n counts[num] = 1\n max_count = 0\n max_item = None\n for num, count in counts.items():\n if count > max_count:\n max_count = count\n max_item = num\n return max_item", "matching_cluster_idx": 3}]}, "Mbpp/137": {"dps": null, "dps_norm": null, "pass@1": 0.0, "profiled": []}, "Mbpp/140": {"dps": 78.33850931677019, "dps_norm": 73.75, "pass@1": 100.0, "profiled": [{"solution": "def extract_singly(lst):\n \"\"\"\n Extracts unique elements from a list of lists into a set.\n\n Args:\n lst: A list of lists, where each inner list contains numbers.\n\n Returns:\n A set containing all unique numbers from the input list of lists.\n \"\"\"\n return set([number for inner_list in lst for number in inner_list])", "matching_cluster_idx": 5}, {"solution": "def extract_singly(data):\n \"\"\"Flattens a list of lists into a single set of numbers.\n\n Args:\n data: A list of lists, where each inner list contains numbers.\n\n Returns:\n A set containing all the numbers from the input lists.\n \"\"\"\n return set([number for sublist in data for number in sublist])", "matching_cluster_idx": 5}, {"solution": "def extract_singly(nested_list):\n \"\"\"\n Flattens a list of lists into a single set of numbers.\n\n Args:\n nested_list: A list of lists, where each inner list contains numbers.\n\n Returns:\n A set containing all the unique numbers from the nested list.\n \"\"\"\n return set([num for sublist in nested_list for num in sublist])", "matching_cluster_idx": 5}, {"solution": "def extract_singly(list_of_lists):\n \"\"\"\n Flattens a list of lists into a single set of numbers.\n\n Args:\n list_of_lists: A list of lists, where each inner list contains numbers.\n\n Returns:\n A set containing all the numbers from the input list of lists.\n \"\"\"\n return set([num for sublist in list_of_lists for num in sublist])", "matching_cluster_idx": 5}, {"solution": "def extract_singly(list_of_lists):\n \"\"\"\n Flattens a list of lists into a single set of numbers.\n\n Args:\n list_of_lists: A list of lists containing numbers.\n\n Returns:\n A set containing all the unique numbers from the input list of lists.\n \"\"\"\n return set([num for sublist in list_of_lists for num in sublist])", "matching_cluster_idx": 5}, {"solution": "def extract_singly(input_list):\n \"\"\"\n Flattens a list of lists into a single set of numbers.\n\n Args:\n input_list: A list of lists, where each inner list contains numbers.\n\n Returns:\n A set containing all the unique numbers from the input list.\n \"\"\"\n return set([num for sublist in input_list for num in sublist])", "matching_cluster_idx": 5}, {"solution": "def extract_singly(nested_list):\n \"\"\"\n Flattens a list of lists into a single set of numbers.\n\n Args:\n nested_list: A list of lists, where each inner list contains numbers.\n\n Returns:\n A set containing all the numbers from the nested list.\n \"\"\"\n return set([number for sublist in nested_list for number in sublist])", "matching_cluster_idx": 5}, {"solution": "def extract_singly(lst):\n \"\"\"\n Flattens a list of lists into a single set of numbers.\n\n Args:\n lst: A list of lists, where each inner list contains numbers.\n\n Returns:\n A set containing all the numbers from the input list of lists.\n \"\"\"\n return set([num for sublist in lst for num in sublist])", "matching_cluster_idx": 5}, {"solution": "def extract_singly(lst):\n \"\"\"\n This function flattens a list of lists into a single set of numbers.\n\n Args:\n lst: A list of lists, where each sublist contains integers.\n\n Returns:\n A set containing all the unique numbers from the input list of lists.\n \"\"\"\n return set([num for sublist in lst for num in sublist])", "matching_cluster_idx": 5}, {"solution": "def extract_singly(nested_list):\n \"\"\"\n Flattens a list of lists into a single set of numbers.\n \n Args:\n nested_list: A list of lists, where each inner list contains numbers.\n\n Returns:\n A set containing all the unique numbers from the nested list.\n \"\"\"\n return set([num for sublist in nested_list for num in sublist])", "matching_cluster_idx": 5}, {"solution": "def extract_singly(lists):\n \"\"\"\n Flattens a list of lists into a single set of numbers.\n\n Args:\n lists: A list of lists.\n\n Returns:\n A set of numbers extracted from the input lists.\n \"\"\"\n return set([num for sublist in lists for num in sublist])", "matching_cluster_idx": 5}, {"solution": "def extract_singly(data):\n \"\"\"\n Flattens a list of lists into a single set of numbers.\n\n Args:\n data: A list of lists.\n\n Returns:\n A set containing all the numbers from the input list of lists.\n \"\"\"\n return set([num for sublist in data for num in sublist])", "matching_cluster_idx": 5}, {"solution": "def extract_singly(nested_list):\n \"\"\"\n Flattens a list of lists into a single set of numbers.\n\n Args:\n nested_list: A list of lists.\n\n Returns:\n A set of all the numbers in the nested list.\n \"\"\"\n return set([num for sublist in nested_list for num in sublist])", "matching_cluster_idx": 5}, {"solution": "def extract_singly(lst):\n \"\"\"\n Flattens a list of lists into a single set of numbers.\n\n Args:\n lst: A list of lists, where each inner list contains numbers.\n\n Returns:\n A set of all the numbers from the input lists, without duplicates.\n \"\"\"\n flat_list = [num for sublist in lst for num in sublist]\n return set(flat_list)", "matching_cluster_idx": 5}, {"solution": "def extract_singly(nested_list):\n \"\"\"\n Flattens a list of lists into a single set of numbers.\n\n Args:\n nested_list (list): A list of lists, where each inner list contains numbers.\n\n Returns:\n set: A set containing all the unique numbers from the nested list.\n \"\"\"\n flattened_list = [num for sublist in nested_list for num in sublist]\n return set(flattened_list)", "matching_cluster_idx": 5}, {"solution": "def extract_singly(data):\n \"\"\"\n Flattens a list of lists into a single set of numbers.\n\n Args:\n data: A list of lists.\n\n Returns:\n A set containing all the numbers from the input lists.\n \"\"\"\n return set([number for sublist in data for number in sublist])", "matching_cluster_idx": 5}, {"solution": "def extract_singly(data):\n \"\"\"\n Flattens a list of lists into a single set of numbers.\n\n Args:\n data: A list of lists of numbers.\n\n Returns:\n A set containing all the numbers from the input list of lists.\n \"\"\"\n flattened_set = set()\n for sublist in data:\n for number in sublist:\n flattened_set.add(number)\n return flattened_set", "matching_cluster_idx": 3}, {"solution": "def extract_singly(nested_list):\n \"\"\"\n Flattens a list of lists into a single set of numbers.\n\n Args:\n nested_list: A list of lists.\n\n Returns:\n A set containing all the unique numbers from the nested list.\n \"\"\"\n flat_list = [num for sublist in nested_list for num in sublist]\n return set(flat_list)", "matching_cluster_idx": 5}, {"solution": "def extract_singly(list_of_lists):\n \"\"\"\n Flattens a list of lists into a single set of numbers.\n\n Args:\n list_of_lists: A list of lists containing numbers.\n\n Returns:\n A set containing all the unique numbers from the input list of lists.\n \"\"\"\n return set([num for sublist in list_of_lists for num in sublist])", "matching_cluster_idx": 5}, {"solution": "def extract_singly(lst):\n \"\"\"\n Flattens a list of lists into a single set of numbers.\n\n Args:\n lst: A list of lists, where each inner list contains numbers.\n\n Returns:\n A set containing all the numbers from the input lists.\n \"\"\"\n return set([num for sublist in lst for num in sublist])", "matching_cluster_idx": 5}]}, "Mbpp/141": {"dps": 86.64399092970523, "dps_norm": 46.875, "pass@1": 57.0, "profiled": [{"solution": "def pancake_sort(arr):\n n = len(arr)\n for i in range(n - 1, 0, -1):\n max_index = arr.index(max(arr[: i + 1]))\n \n # Flip the subarray from 0 to max_index\n arr[:max_index + 1] = arr[:max_index + 1][::-1]\n \n # Flip the subarray from 0 to i\n arr[:i + 1] = arr[:i + 1][::-1]\n return arr", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(nums):\n n = len(nums)\n for i in range(n - 1, 0, -1):\n max_index = nums.index(max(nums[:i+1]))\n \n # Flip the sublist from 0 to max_index\n nums[:max_index+1] = reversed(nums[:max_index+1])\n \n # Flip the sublist from 0 to i\n nums[:i+1] = reversed(nums[:i+1])\n return nums", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(arr):\n n = len(arr)\n for i in range(n-1, 0, -1):\n max_index = arr.index(max(arr[:i+1]))\n # Flip the subarray from index 0 to max_index\n arr[0:max_index+1] = arr[0:max_index+1][::-1]\n # Flip the subarray from index 0 to i\n arr[0:i+1] = arr[0:i+1][::-1]\n return arr", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(arr):\n n = len(arr)\n for i in range(n - 1, 0, -1):\n max_index = arr.index(max(arr[:i+1]))\n if max_index != i:\n # Flip the subarray from 0 to max_index\n arr[:max_index+1] = arr[:max_index+1][::-1]\n # Flip the subarray from 0 to i\n arr[:i+1] = arr[:i+1][::-1]\n return arr", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(arr):\n n = len(arr)\n for i in range(n - 1, 0, -1):\n max_idx = arr.index(max(arr[:i + 1]))\n if max_idx != i:\n # Flip the subarray from 0 to max_idx\n arr[:max_idx + 1] = arr[:max_idx + 1][::-1]\n print(f\"Flipped {arr[:max_idx+1]}\")\n # Flip the subarray from 0 to i\n arr[:i + 1] = arr[:i + 1][::-1]\n print(f\"Flipped {arr[:i+1]}\")\n return arr", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(arr):\n n = len(arr)\n for i in range(n - 1, 0, -1):\n max_index = arr.index(max(arr[:i + 1]))\n \n # Flip the subarray from 0 to max_index\n arr[:max_index + 1] = arr[:max_index + 1][::-1]\n \n # Flip the subarray from 0 to i\n arr[:i + 1] = arr[:i + 1][::-1]\n return arr", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(arr):\n n = len(arr)\n for i in range(n - 1, 0, -1):\n max_index = arr.index(max(arr[:i + 1]))\n if max_index != i:\n # Flip the subarray from the start to max_index\n arr[:max_index + 1] = arr[:max_index + 1][::-1]\n # Flip the subarray from start to i\n arr[:i + 1] = arr[:i + 1][::-1]\n return arr", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(arr):\n n = len(arr)\n for i in range(n - 1, 0, -1):\n max_index = arr.index(max(arr[:i+1]))\n if max_index != i:\n # Flip the subarray from 0 to max_index\n arr[0:max_index+1] = reversed(arr[0:max_index+1])\n # Flip the subarray from 0 to i\n arr[0:i+1] = reversed(arr[0:i+1])\n return arr", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(arr):\n n = len(arr)\n for i in range(n-1, 0, -1):\n max_index = arr.index(max(arr[:i+1]))\n if max_index != i:\n # Flip the subarray from 0 to max_index\n arr[:max_index+1] = arr[:max_index+1][::-1]\n # Flip the subarray from 0 to i\n arr[:i+1] = arr[:i+1][::-1]\n return arr", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(arr):\n \"\"\"\n Sorts a list of elements using the Pancake Sort algorithm.\n\n Args:\n arr: The list of elements to sort.\n\n Returns:\n The sorted list.\n \"\"\"\n n = len(arr)\n for i in range(n-1, 0, -1):\n max_index = arr.index(max(arr[:i+1]))\n if max_index != i:\n # Flip the subarray from 0 to max_index\n arr[:max_index+1] = arr[:max_index+1][::-1]\n # Flip the subarray from 0 to i\n arr[:i+1] = arr[:i+1][::-1]\n return arr", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(arr):\n \"\"\"\n Sorts a list of elements using the Pancake Sort algorithm.\n\n Args:\n arr: A list of elements to sort.\n\n Returns:\n The sorted list.\n \"\"\"\n n = len(arr)\n for i in range(n - 1, 0, -1):\n max_index = arr.index(max(arr[:i+1]))\n # Flip the subarray from 0 to max_index\n arr[:max_index+1] = arr[:max_index+1][::-1]\n # Flip the subarray from 0 to i\n arr[:i+1] = arr[:i+1][::-1]\n return arr", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(arr):\n n = len(arr)\n for i in range(n-1, 0, -1):\n max_idx = arr.index(max(arr[:i+1]))\n if max_idx != i:\n arr = reverse(arr, 0, max_idx)\n arr = reverse(arr, 0, i)\n return arr\ndef reverse(arr, start, end):\n while start < end:\n arr[start], arr[end] = arr[end], arr[start]\n start += 1\n end -= 1\n return arr", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(arr):\n \"\"\"\n Sorts a list of elements using the Pancake Sort algorithm.\n\n Args:\n arr: A list of elements to be sorted.\n\n Returns:\n A sorted list of elements.\n \"\"\"\n n = len(arr)\n for i in range(n-1, 0, -1):\n # Find the index of the maximum element in the unsorted part\n max_idx = arr.index(max(arr[:i+1]))\n\n # Move the maximum element to the beginning\n if max_idx != i:\n # Reverse the subarray from 0 to max_idx\n arr[:max_idx+1] = reversed(arr[:max_idx+1])\n print(f\"Flipped subarray: {arr}\") \n\n # Reverse the subarray from 0 to i\n arr[:i+1] = reversed(arr[:i+1])\n print(f\"Flipped subarray: {arr}\")\n\n return arr\narr = [15, 79, 25, 38, 69]", "matching_cluster_idx": 1}, {"solution": "def pancake_sort(arr):\n n = len(arr)\n for i in range(n-1, 0, -1):\n max_index = arr.index(max(arr[:i+1]))\n \n # Flip the subarray from 0 to max_index\n arr[:max_index+1] = arr[:max_index+1][::-1]\n \n # Flip the subarray from 0 to i\n arr[:i+1] = arr[:i+1][::-1]\n return arr\narr = [15, 79, 25, 38, 69]", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(arr):\n \"\"\"\n Sorts a list of elements using the Pancake Sort algorithm.\n\n Args:\n arr: The list of elements to be sorted.\n\n Returns:\n The sorted list.\n \"\"\"\n n = len(arr)\n for i in range(n - 1, 0, -1):\n # Find the index of the maximum element in the unsorted part\n max_idx = arr.index(max(arr[:i + 1]))\n\n # Move the maximum element to the beginning\n if max_idx != i:\n # Reverse the subarray from 0 to max_idx\n arr[:max_idx + 1] = reversed(arr[:max_idx + 1])\n # Reverse the subarray from 0 to i\n arr[:i + 1] = reversed(arr[:i + 1])\n return arr\narr = [15, 79, 25, 38, 69]", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(arr):\n \"\"\"Sorts a list of elements using the Pancake Sort algorithm.\"\"\"\n n = len(arr)\n for i in range(n - 1, 0, -1):\n max_index = max(range(i + 1), key=lambda j: arr[j])\n # Flip subarray from 0 to max_index\n arr[0:max_index+1] = arr[0:max_index+1][::-1]\n # Flip subarray from 0 to i\n arr[0:i+1] = arr[0:i+1][::-1]\n return arr", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(arr):\n \"\"\"\n Sorts a list of elements using the pancake sorting algorithm.\n\n Args:\n arr: A list of integers to sort.\n\n Returns:\n The sorted list.\n \"\"\"\n n = len(arr)\n for i in range(n - 1, 0, -1):\n max_index = arr.index(max(arr[:i+1])) # Find index of max element in the unsorted portion\n # Flip the subarray from index 0 to max_index\n arr[:max_index + 1] = reversed(arr[:max_index + 1])\n # Flip the subarray from index 0 to i\n arr[:i+1] = reversed(arr[:i+1])\n return arr", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(arr):\n \"\"\"\n Sorts a list of elements.\n\n Args:\n arr: The list to sort.\n\n Returns:\n The sorted list.\n \"\"\"\n\n n = len(arr)\n \n for i in range(n - 1, 0, -1):\n max_index = arr.index(max(arr[:i+1]))\n \n # Flip the subarray from index 0 to max_index\n arr[:max_index+1] = arr[:max_index+1][::-1]\n \n # Flip the subarray from index 0 to i \n arr[:i+1] = arr[:i+1][::-1]\n\n return arr", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(arr):\n \"\"\"\n Sorts a list of elements using the Pancake Sort algorithm.\n\n Args:\n arr: A list of elements to be sorted.\n\n Returns:\n The sorted list.\n \"\"\"\n n = len(arr)\n\n def flip(arr, k):\n arr[:k + 1] = reversed(arr[:k + 1]) # Flip the subarray from index 0 to k\n\n for i in range(n - 1, 0, -1):\n # Find the maximum element in the unsorted subarray\n max_idx = arr.index(max(arr[:i + 1]))\n\n # Move the maximum element to the front\n if max_idx != i:\n # Flip to bring the maximum element to the top\n flip(arr, max_idx)\n # Flip again to move it to the correct position\n flip(arr, i)\n\n return arr", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(arr):\n n = len(arr)\n for i in range(n - 1, 0, -1):\n # Find the index of the maximum element in the unsorted subarray\n max_index = arr.index(max(arr[:i + 1]))\n \n # Move the maximum element to its correct position\n if max_index != i:\n # Reverse the subarray from index 0 to max_index\n arr[:max_index + 1] = reversed(arr[:max_index + 1])\n # Reverse the subarray from index 0 to i \n arr[:i + 1] = reversed(arr[:i + 1])\n\n return arr", "matching_cluster_idx": 3}]}, "Mbpp/166": {"dps": 94.39999999999999, "dps_norm": 50.0, "pass@1": 100.0, "profiled": [{"solution": "def find_even_pair(nums):\n \"\"\"\n Counts the number of pairs of integers in a list that xor to an even number.\n\n Args:\n nums: A list of integers.\n\n Returns:\n The number of pairs that xor to an even number.\n \"\"\"\n count = 0\n for i in range(len(nums)):\n for j in range(i + 1, len(nums)):\n if (nums[i] ^ nums[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(nums):\n \"\"\"\n Counts the number of pairs of integers in a list that xor to an even number.\n\n Args:\n nums: A list of integers.\n\n Returns:\n The number of pairs of integers in the list that xor to an even number.\n \"\"\"\n count = 0\n for i in range(len(nums)):\n for j in range(i + 1, len(nums)):\n if (nums[i] ^ nums[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(nums):\n \"\"\"\n Counts the number of pairs of integers in a list that xor to an even number.\n\n Args:\n nums: A list of integers.\n\n Returns:\n The number of pairs of integers in the list that xor to an even number.\n \"\"\"\n count = 0\n for i in range(len(nums)):\n for j in range(i + 1, len(nums)):\n if (nums[i] ^ nums[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(nums):\n \"\"\"\n Counts the number of pairs of integers in a list that xor to an even number.\n\n Args:\n nums: A list of integers.\n\n Returns:\n The number of pairs that xor to an even number.\n \"\"\"\n count = 0\n for i in range(len(nums)):\n for j in range(i + 1, len(nums)):\n if (nums[i] ^ nums[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(nums):\n \"\"\"\n Counts the number of pairs of integers in a list that xor to an even number.\n\n Args:\n nums: A list of integers.\n\n Returns:\n The number of pairs of integers in the list that xor to an even number.\n \"\"\"\n\n count = 0\n for i in range(len(nums)):\n for j in range(i + 1, len(nums)):\n if (nums[i] ^ nums[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(nums):\n \"\"\"\n Counts the number of pairs of integers in a list that XOR to an even number.\n\n Args:\n nums: A list of integers.\n\n Returns:\n The number of pairs that XOR to an even number.\n \"\"\"\n count = 0\n for i in range(len(nums)):\n for j in range(i + 1, len(nums)):\n if (nums[i] ^ nums[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(nums):\n \"\"\"\n Counts the number of pairs of integers in a list that xor to an even number.\n\n Args:\n nums: A list of integers.\n\n Returns:\n The number of pairs of integers in the list that xor to an even number.\n \"\"\"\n count = 0\n for i in range(len(nums)):\n for j in range(i + 1, len(nums)):\n if (nums[i] ^ nums[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(nums):\n \"\"\"\n Counts the number of pairs of integers in a list that xor to an even number.\n \"\"\"\n count = 0\n for i in range(len(nums)):\n for j in range(i + 1, len(nums)):\n if (nums[i] ^ nums[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(nums):\n \"\"\"\n Counts the number of pairs of integers in a list that xor to an even number.\n\n Args:\n nums: A list of integers.\n\n Returns:\n The number of pairs of integers in the list that xor to an even number.\n \"\"\"\n count = 0\n for i in range(len(nums)):\n for j in range(i + 1, len(nums)):\n if (nums[i] ^ nums[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(nums):\n \"\"\"\n Counts the number of pairs of integers in a list that xor to an even number.\n\n Args:\n nums: A list of integers.\n\n Returns:\n The number of pairs of integers in the list that xor to an even number.\n \"\"\"\n count = 0\n for i in range(len(nums)):\n for j in range(i + 1, len(nums)):\n if (nums[i] ^ nums[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(nums):\n \"\"\"Counts the number of pairs of integers in a list that xor to an even number.\n\n Args:\n nums: A list of integers.\n\n Returns:\n The number of pairs of integers in the list that xor to an even number.\n \"\"\"\n count = 0\n for i in range(len(nums)):\n for j in range(i + 1, len(nums)):\n if (nums[i] ^ nums[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(nums):\n \"\"\"\n Counts the number of pairs of integers in a list that xor to an even number.\n\n Args:\n nums: A list of integers.\n\n Returns:\n The number of pairs that xor to an even number.\n \"\"\"\n count = 0\n for i in range(len(nums)):\n for j in range(i + 1, len(nums)):\n if (nums[i] ^ nums[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(nums):\n \"\"\"\n Counts the number of pairs of integers in a list that xor to an even number.\n\n Args:\n nums: A list of integers.\n\n Returns:\n The number of pairs that xor to an even number.\n \"\"\"\n count = 0\n for i in range(len(nums)):\n for j in range(i + 1, len(nums)):\n if (nums[i] ^ nums[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(nums):\n \"\"\"\n Counts the number of pairs of integers in a list that xor to an even number.\n\n Args:\n nums: A list of integers.\n\n Returns:\n The number of pairs of integers in the list that xor to an even number.\n \"\"\"\n count = 0\n for i in range(len(nums)):\n for j in range(i + 1, len(nums)):\n if (nums[i] ^ nums[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(nums):\n \"\"\"\n Counts the number of pairs of integers in a list that xor to an even number.\n \n Args:\n nums: A list of integers.\n\n Returns:\n The number of pairs of integers in the list that xor to an even number.\n \"\"\"\n count = 0\n for i in range(len(nums)):\n for j in range(i + 1, len(nums)):\n if (nums[i] ^ nums[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(nums):\n \"\"\"\n Counts the number of pairs of integers in a list that xor to an even number.\n\n Args:\n nums: A list of integers.\n\n Returns:\n The number of pairs of integers in the list that xor to an even number.\n \"\"\"\n count = 0\n for i in range(len(nums)):\n for j in range(i + 1, len(nums)):\n if (nums[i] ^ nums[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(nums):\n \"\"\"\n Counts the number of pairs of integers in a list that xor to an even number.\n\n Args:\n nums: A list of integers.\n\n Returns:\n The number of pairs of integers in the list that xor to an even number.\n \"\"\"\n count = 0\n for i in range(len(nums)):\n for j in range(i + 1, len(nums)):\n if (nums[i] ^ nums[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(nums):\n \"\"\"\n Counts the number of pairs of integers in a list that XOR to an even number.\n \"\"\"\n count = 0\n for i in range(len(nums)):\n for j in range(i + 1, len(nums)):\n if (nums[i] ^ nums[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(nums):\n \"\"\"\n Counts the number of pairs of integers in a list that xor to an even number.\n\n Args:\n nums: A list of integers.\n\n Returns:\n The number of pairs of integers in the list that xor to an even number.\n \"\"\"\n count = 0\n for i in range(len(nums)):\n for j in range(i + 1, len(nums)):\n if (nums[i] ^ nums[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(nums):\n \"\"\"\n Counts the number of pairs of integers in a list that xor to an even number.\n \n Args:\n nums: A list of integers.\n\n Returns:\n The number of pairs of integers in the list that xor to an even number.\n \n assert find_even_pair([5, 4, 7, 2, 1]) == 4\n \"\"\"\n count = 0\n for i in range(len(nums)):\n for j in range(i+1, len(nums)):\n if (nums[i] ^ nums[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}]}, "Mbpp/170": {"dps": 95.45893719806763, "dps_norm": 97.5, "pass@1": 15.0, "profiled": [{"solution": "def sum_range_list(data, start_index, end_index):\n \"\"\"\n Calculates the sum of numbers in a list within a given range.\n\n Args:\n data: A list of numbers.\n start_index: The starting index (inclusive) of the range.\n end_index: The ending index (inclusive) of the range.\n\n Returns:\n The sum of the numbers in the specified range.\n \"\"\"\n if start_index < 0 or end_index >= len(data) or start_index > end_index:\n return 0\n return sum(data[start_index : end_index + 1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(nums, start_index, end_index):\n \"\"\"\n Finds the sum of numbers in a list within a range specified by two indices.\n\n Args:\n nums: A list of numbers.\n start_index: The starting index (inclusive) of the range.\n end_index: The ending index (inclusive) of the range.\n\n Returns:\n The sum of the numbers in the specified range.\n \"\"\"\n if start_index < 0 or end_index >= len(nums) or start_index > end_index:\n return 0 \n return sum(nums[start_index : end_index + 1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(nums, start_index, end_index):\n \"\"\"\n Calculates the sum of numbers in a list within a specified range.\n\n Args:\n nums: A list of numbers.\n start_index: The starting index (inclusive) of the range.\n end_index: The ending index (inclusive) of the range.\n\n Returns:\n The sum of numbers in the specified range.\n Returns 0 if the range is invalid.\n \"\"\"\n if start_index < 0 or end_index >= len(nums) or start_index > end_index:\n return 0\n return sum(nums[start_index : end_index + 1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(nums, start, end):\n \"\"\"\n Finds the sum of numbers in a list within a range specified by two indices.\n\n Args:\n nums: A list of numbers.\n start: The starting index (inclusive).\n end: The ending index (inclusive).\n\n Returns:\n The sum of the numbers in the specified range.\n \"\"\"\n return sum(nums[start:end+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(data, start_index, end_index):\n \"\"\"\n Calculates the sum of numbers in a list within a given range.\n\n Args:\n data: A list of numbers.\n start_index: The starting index (inclusive) of the range.\n end_index: The ending index (inclusive) of the range.\n\n Returns:\n The sum of the numbers in the specified range.\n Returns 0 if the range is invalid.\n \"\"\"\n if start_index < 0 or end_index >= len(data) or start_index > end_index:\n return 0\n return sum(data[start_index : end_index + 1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(nums, start_index, end_index):\n \"\"\"\n Finds the sum of numbers in a list within a range specified by two indices.\n\n Args:\n nums: A list of numbers.\n start_index: The starting index of the range (inclusive).\n end_index: The ending index of the range (inclusive).\n\n Returns:\n The sum of the numbers in the specified range.\n Returns 0 if the indices are invalid.\n \"\"\"\n if start_index < 0 or end_index >= len(nums) or start_index > end_index:\n return 0\n return sum(nums[start_index : end_index + 1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(nums, start, end):\n \"\"\"\n Find the sum of numbers in a list within a range specified by two indices.\n\n Args:\n nums: A list of numbers.\n start: The starting index (inclusive) of the range.\n end: The ending index (inclusive) of the range.\n\n Returns:\n The sum of numbers in the specified range.\n \"\"\"\n return sum(nums[start:end+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(nums, start, end):\n \"\"\"\n Finds the sum of numbers in a list within a range specified by two indices.\n\n Args:\n nums: A list of numbers.\n start: The starting index (inclusive) of the range.\n end: The ending index (inclusive) of the range.\n\n Returns:\n The sum of the numbers in the specified range.\n \"\"\"\n total = 0\n for i in range(start, end + 1):\n total += nums[i]\n return total", "matching_cluster_idx": 4}, {"solution": "def sum_range_list(data, start_index, end_index):\n \"\"\"\n This function calculates the sum of numbers in a list within a specified range.\n\n Args:\n data: A list of numbers.\n start_index: The starting index (inclusive) of the range.\n end_index: The ending index (inclusive) of the range.\n\n Returns:\n The sum of numbers within the specified range in the list.\n \"\"\"\n if start_index < 0 or end_index >= len(data) or start_index > end_index:\n return 0 \n return sum(data[start_index : end_index + 1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(lst, start_index, end_index):\n \"\"\"\n Calculates the sum of numbers in a list within a specified range.\n\n Args:\n lst: The input list of numbers.\n start_index: The starting index (inclusive) of the range.\n end_index: The ending index (inclusive) of the range.\n\n Returns:\n The sum of numbers in the specified range within the list.\n Returns 0 if the indices are invalid.\n \"\"\"\n if start_index < 0 or end_index >= len(lst) or start_index > end_index:\n return 0\n return sum(lst[start_index : end_index + 1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(nums, start_index, end_index):\n \"\"\"\n This function calculates the sum of numbers in a list within a range specified by two indices.\n\n Args:\n nums: A list of numbers.\n start_index: The starting index (inclusive) of the range.\n end_index: The ending index (inclusive) of the range.\n\n Returns:\n The sum of numbers in the specified range.\n \"\"\"\n if start_index < 0 or end_index >= len(nums) or start_index > end_index:\n return 0 # Handle invalid input\n return sum(nums[start_index:end_index+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(data, start_index, end_index):\n \"\"\"\n Calculates the sum of numbers in a list within a specified range.\n\n Args:\n data: A list of numbers.\n start_index: The starting index of the range (inclusive).\n end_index: The ending index of the range (inclusive).\n\n Returns:\n The sum of the numbers in the specified range.\n \"\"\"\n if start_index < 0 or end_index >= len(data) or start_index > end_index:\n return 0 \n return sum(data[start_index : end_index + 1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(nums, start, end):\n \"\"\"\n Find the sum of numbers in a list within a range specified by two indices.\n\n Args:\n nums: A list of numbers.\n start: The starting index (inclusive) of the range.\n end: The ending index (inclusive) of the range.\n\n Returns:\n The sum of the numbers within the specified range.\n \"\"\"\n return sum(nums[start:end+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(nums, start, end):\n \"\"\"\n Finds the sum of numbers in a list within a range specified by two indices.\n\n Args:\n nums: A list of numbers.\n start: The starting index (inclusive).\n end: The ending index (inclusive).\n\n Returns:\n The sum of the numbers in the specified range.\n \"\"\"\n return sum(nums[start:end+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(nums, start_index, end_index):\n \"\"\"\n Finds the sum of numbers in a list within a range specified by two indices.\n\n Args:\n nums: A list of numbers.\n start_index: The starting index (inclusive) of the range.\n end_index: The ending index (inclusive) of the range.\n\n Returns:\n The sum of numbers within the specified range in the list.\n \"\"\"\n return sum(nums[start_index : end_index + 1])", "matching_cluster_idx": 7}]}, "Mbpp/226": {"dps": 68.21705426356588, "dps_norm": 14.285714285714286, "pass@1": 92.0, "profiled": [{"solution": "def odd_values_string(text):\n \"\"\"\n Removes characters with odd index values from a given string.\n\n Args:\n text: The input string.\n\n Returns:\n The string with characters at odd indices removed.\n \"\"\"\n result = \"\"\n for i in range(len(text)):\n if i % 2 == 0: # Check for even indices\n result += text[i]\n return result", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(s):\n \"\"\"Removes characters at odd index values from a given string.\n\n Args:\n s: The input string.\n\n Returns:\n A new string with characters at odd indices removed.\n \"\"\"\n\n new_string = ''\n for i in range(len(s)):\n if i % 2 == 0:\n new_string += s[i]\n return new_string", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(input_string):\n \"\"\"\n Removes characters from a string that have odd index values.\n\n Args:\n input_string: The string to process.\n\n Returns:\n A new string with characters at odd indices removed.\n \"\"\"\n return ''.join(input_string[i] for i in range(len(input_string)) if i % 2 == 0)", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(input_string):\n \"\"\"\n Removes characters from a string that have odd index values.\n\n Args:\n input_string: The string to process.\n\n Returns:\n A new string with characters at odd indices removed.\n \"\"\"\n\n return ''.join(input_string[i] for i in range(len(input_string)) if i % 2 == 0)", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(string):\n \"\"\"\n Removes characters from a string based on their odd index values.\n\n Args:\n string: The input string.\n\n Returns:\n A new string with characters at odd indices removed.\n \"\"\"\n result = ''\n for i in range(len(string)):\n if i % 2 == 0: # Check if the index is even\n result += string[i]\n return result", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(string):\n \"\"\"Removes characters with odd index values from a string.\n\n Args:\n string: The input string.\n\n Returns:\n The string with characters at odd indices removed.\n \"\"\"\n new_string = ''\n for i in range(len(string)):\n if i % 2 == 0: \n new_string += string[i]\n return new_string", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(s):\n \"\"\"\n Removes characters at odd index values of a given string.\n\n Args:\n s: The input string.\n\n Returns:\n A new string with characters at odd index values removed.\n \"\"\"\n new_string = ''\n for i in range(len(s)):\n if i % 2 == 0:\n new_string += s[i]\n return new_string", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(input_string):\n \"\"\"Removes characters at odd index positions from a string.\n\n Args:\n input_string: The string to process.\n\n Returns:\n The string with characters at odd index positions removed.\n \"\"\"\n return ''.join(input_string[i] for i in range(len(input_string)) if i % 2 == 0)", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(str):\n \"\"\"\n This function removes the characters which have odd index values of a given string.\n\n Args:\n str: The input string.\n\n Returns:\n The string with characters at odd indices removed.\n \"\"\"\n new_string = \"\"\n for i in range(len(str)):\n if i % 2 == 0: \n new_string += str[i]\n return new_string", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(s):\n \"\"\"\n Write a python function to remove the characters which have odd index values of a given string.\n\n Args:\n s: The input string.\n\n Returns:\n A new string with characters at odd indices removed.\n\n Example:\n odd_values_string('abcdef') == 'ace'\n \"\"\"\n return ''.join(s[i] for i in range(len(s)) if i % 2 == 0)", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(string):\n \"\"\"\n Removes characters with odd index values from a given string.\n \n Args:\n string: The input string.\n\n Returns:\n The string with characters at odd indices removed.\n \"\"\"\n new_string = \"\"\n for i in range(len(string)):\n if i % 2 == 0: # Check if the index is even\n new_string += string[i]\n return new_string", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(s):\n \"\"\"\n Removes characters with odd index values from a string.\n \n Args:\n s: The input string.\n\n Returns:\n A new string with characters at odd indices removed.\n\n \"\"\"\n return ''.join(s[i] for i in range(len(s)) if i % 2 == 0)", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(s):\n \"\"\"Removes characters from a string at odd indices.\n\n Args:\n s: The input string.\n\n Returns:\n A new string with characters at odd indices removed.\n \"\"\"\n new_string = ''\n for i in range(len(s)):\n if i % 2 == 0: # Check if the index is even\n new_string += s[i]\n return new_string", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(s):\n \"\"\"\n Removes characters from a string at odd index values.\n\n Args:\n s: The input string.\n\n Returns:\n The string with characters at odd indices removed.\n \"\"\"\n return ''.join(s[i] for i in range(len(s)) if i % 2 == 0)", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(s):\n \"\"\"\n Removes characters with odd indices from a string.\n\n Args:\n s: The input string.\n\n Returns:\n The string with characters at odd indices removed.\n \"\"\"\n return ''.join(s[i] for i in range(len(s)) if i % 2 == 0)", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(input_string):\n \"\"\"\n Removes characters with odd index values from a given string.\n\n Args:\n input_string: The string to process.\n\n Returns:\n The string with characters at odd indices removed.\n \"\"\"\n return ''.join(input_string[i] for i in range(len(input_string)) if i % 2 == 0)", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(s):\n \"\"\"\n Removes characters from a string at odd indices.\n\n Args:\n s: The input string.\n\n Returns:\n The string with characters at odd indices removed.\n \"\"\"\n new_string = ''\n for i in range(len(s)):\n if i % 2 == 0: \n new_string += s[i]\n return new_string", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(s: str) -> str:\n \"\"\"\n Removes characters at odd index values of a given string.\n \n Args:\n s: The input string.\n\n Returns:\n The string with characters at odd index values removed.\n \"\"\"\n new_string = ''\n for i in range(len(s)):\n if i % 2 != 1:\n new_string += s[i]\n return new_string", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(s):\n \"\"\"Removes characters with odd index values from a string.\n\n Args:\n s: The input string.\n\n Returns:\n A string with characters at odd indices removed.\n \"\"\"\n return ''.join(s[i] for i in range(len(s)) if i % 2 == 0)", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(str1):\n \"\"\"\n Removes characters with odd index values from a string.\n\n Args:\n str1: The input string.\n\n Returns:\n A new string with characters at odd indices removed.\n \"\"\"\n new_string = ''\n for i in range(len(str1)):\n if i % 2 == 0: # Check for even indices\n new_string += str1[i]\n return new_string", "matching_cluster_idx": 0}]}, "Mbpp/230": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 99.0, "profiled": [{"solution": "def replace_blank(text, char):\n \"\"\"\n Replaces blank spaces in a string with a given character.\n\n Args:\n text: The string to modify.\n char: The character to replace the blanks with.\n\n Returns:\n The modified string with blanks replaced.\n \"\"\"\n return text.replace(\" \", char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(text, character):\n \"\"\"\n Replaces all blank spaces in a string with a given character.\n\n Args:\n text: The input string.\n character: The character to replace spaces with.\n\n Returns:\n The string with spaces replaced by the given character.\n \"\"\"\n return text.replace(\" \", character)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(text, char):\n \"\"\"\n This function takes in a string and character, replaces blank spaces in the string with the character, and returns the string.\n\n Args:\n text: The input string.\n char: The character to replace spaces with.\n\n Returns:\n The string with spaces replaced by the given character.\n \"\"\"\n return text.replace(\" \", char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(text, char):\n \"\"\"\n Replaces blank spaces in a string with a given character.\n\n Args:\n text: The input string.\n char: The character to replace the spaces with.\n\n Returns:\n The string with spaces replaced by the given character.\n \"\"\"\n return text.replace(\" \", char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(text, char):\n \"\"\"\n This function takes in a string and character, replaces blank spaces in the string with the character,\n and returns the string.\n \n Args:\n text: The string to be modified.\n char: The character to replace the blanks with.\n \n Returns:\n The modified string with blanks replaced.\n \"\"\"\n return text.replace(\" \", char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(text, char):\n \"\"\"\n This function takes in a string and character, replaces blank spaces in the string with the character, and returns the string.\n\n Args:\n text: The input string.\n char: The character to replace blank spaces with.\n\n Returns:\n The string with blank spaces replaced by the given character.\n \"\"\"\n return text.replace(\" \", char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(text, char):\n \"\"\"\n Replaces blank spaces in a string with a given character.\n\n Args:\n text: The input string.\n char: The character to replace spaces with.\n\n Returns:\n The string with spaces replaced by the given character.\n \"\"\"\n return text.replace(\" \", char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(text, character):\n \"\"\"\n Replaces blank spaces in a string with a given character.\n\n Args:\n text: The input string.\n character: The character to replace spaces with.\n\n Returns:\n The string with spaces replaced by the given character.\n \"\"\"\n return text.replace(\" \", character)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(string, char):\n \"\"\"\n Replaces blank spaces in a string with a given character.\n\n Args:\n string: The input string.\n char: The character to replace blank spaces with.\n\n Returns:\n The string with blank spaces replaced by the given character.\n \"\"\"\n return string.replace(\" \", char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(text, char):\n \"\"\"\n Replaces all blank spaces in a string with a given character.\n\n Args:\n text: The string to be modified.\n char: The character to replace the spaces with.\n\n Returns:\n The string with spaces replaced by the specified character.\n \"\"\"\n return text.replace(\" \", char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(text, char):\n \"\"\"\n This function takes in a string and a character, \n replaces blank spaces in the string with the character, \n and returns the string.\n \n Args:\n text: The string to be modified.\n char: The character to replace blank spaces with.\n \n Returns:\n The modified string with blank spaces replaced.\n \"\"\"\n return text.replace(\" \", char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(text, char):\n \"\"\"Replaces blank spaces in a string with a given character.\n\n Args:\n text: The string to be modified.\n char: The character to replace the blank spaces with.\n\n Returns:\n The string with blank spaces replaced by the given character.\n \"\"\"\n return text.replace(\" \", char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(string, character):\n \"\"\"\n This function takes in a string and character, replaces blank spaces in the string with the character,\n and returns the string.\n \"\"\"\n return string.replace(\" \", character)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(text, char):\n \"\"\"\n Replaces blank spaces in a string with a given character.\n\n Args:\n text: The string to modify.\n char: The character to replace the spaces with.\n\n Returns:\n The string with spaces replaced by the given character.\n \"\"\"\n return text.replace(\" \", char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(s, c):\n \"\"\"\n Replaces blank spaces in a string with a given character.\n\n Args:\n s (str): The input string.\n c (str): The character to replace spaces with.\n\n Returns:\n str: The string with spaces replaced by the given character.\n \"\"\"\n return s.replace(\" \", c)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(text, char):\n \"\"\"\n Replaces blank spaces in a string with a given character.\n\n Args:\n text: The string to be modified.\n char: The character to replace blank spaces with.\n\n Returns:\n The modified string with blank spaces replaced.\n \"\"\"\n return text.replace(\" \", char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(text, char):\n \"\"\"\n Replaces all blank spaces in a string with a given character.\n\n Args:\n text: The input string.\n char: The character to replace spaces with.\n\n Returns:\n The string with spaces replaced by the given character.\n \"\"\"\n return text.replace(\" \", char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(s, char):\n \"\"\"\n This function takes a string and character, replaces blank spaces in the string with the character,\n and returns the string.\n\n Args:\n s: The input string.\n char: The character to replace blank spaces with.\n\n Returns:\n The string with all blank spaces replaced by the given character.\n \"\"\"\n return s.replace(\" \", char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(string, char):\n \"\"\"\n Replaces blank spaces in a string with a given character.\n\n Args:\n string: The string to modify.\n char: The character to replace blank spaces with.\n\n Returns:\n The string with blank spaces replaced by the given character.\n \"\"\"\n return string.replace(\" \", char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(text, char):\n \"\"\"\n Replaces blank spaces in a string with a given character.\n\n Args:\n text: The string to be modified.\n char: The character to replace spaces with.\n\n Returns:\n The modified string with spaces replaced by the given character.\n \"\"\"\n return text.replace(\" \", char)", "matching_cluster_idx": 7}]}, "Mbpp/239": {"dps": null, "dps_norm": null, "pass@1": 0.0, "profiled": []}, "Mbpp/240": {"dps": null, "dps_norm": null, "pass@1": 0.0, "profiled": []}, "Mbpp/251": {"dps": 91.95402298850576, "dps_norm": 77.77777777777777, "pass@1": 100.0, "profiled": [{"solution": "def insert_element(lst, element):\n \"\"\"\n Inserts the given element before each element in a list.\n\n Args:\n lst (list): The input list.\n element: The element to insert.\n\n Returns:\n list: The modified list with the element inserted before each element.\n \"\"\"\n result = []\n for item in lst:\n result.append(element)\n result.append(item)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n \"\"\"\n Inserts an element before each element in a list and returns the resulting list.\n\n Args:\n lst: A list of elements.\n element: The element to insert before each existing element.\n\n Returns:\n A new list with the element inserted before each element of the input list.\n \"\"\"\n result = []\n for item in lst:\n result.append(element)\n result.append(item)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(data, element):\n \"\"\"\n Inserts an element before each element in a list.\n\n Args:\n data: A list of elements.\n element: The element to insert.\n\n Returns:\n A new list with the element inserted before each element in the original list.\n \"\"\"\n result = []\n for item in data:\n result.append(element)\n result.append(item)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n \"\"\"\n Inserts an element before each element in a list.\n\n Args:\n lst: The list to modify.\n element: The element to insert.\n\n Returns:\n The modified list with the element inserted before each element.\n \"\"\"\n result = []\n for item in lst:\n result.append(element)\n result.append(item)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, elem):\n \"\"\"\n Inserts an element before each element in a list.\n\n Args:\n lst: A list of elements.\n elem: The element to insert.\n\n Returns:\n A new list with the element inserted before each element of the input list.\n \"\"\"\n result = []\n for item in lst:\n result.append(elem)\n result.append(item)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n \"\"\"\n Inserts an element before each element in a list.\n\n Args:\n lst: The input list.\n element: The element to insert.\n\n Returns:\n A new list with the element inserted before each element in the input list.\n \"\"\"\n new_list = []\n for item in lst:\n new_list.append(element)\n new_list.append(item)\n return new_list", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n \"\"\"\n Inserts an element before each element in a list and returns the resulting list.\n\n Args:\n lst: The input list.\n element: The element to insert.\n\n Returns:\n A new list with the element inserted before each element of the input list.\n \"\"\"\n new_lst = []\n for item in lst:\n new_lst.append(element)\n new_lst.append(item)\n return new_lst", "matching_cluster_idx": 6}, {"solution": "def insert_element(list1, element):\n \"\"\"\n Inserts an element before each element in a list.\n \n Args:\n list1: The input list.\n element: The element to insert.\n \n Returns:\n A new list with the element inserted before each element in the original list.\n \"\"\"\n new_list = []\n for item in list1:\n new_list.append(element)\n new_list.append(item)\n return new_list", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n \"\"\"\n Inserts the given element before each element in the list.\n\n Args:\n lst: The input list.\n element: The element to insert.\n\n Returns:\n A new list with the element inserted before each element in the input list.\n \"\"\"\n result = []\n for item in lst:\n result.append(element)\n result.append(item)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n \"\"\"\n Inserts an element before each element in a list.\n\n Args:\n lst: The list to modify.\n element: The element to insert.\n\n Returns:\n A new list with the element inserted before each element in the original list.\n \"\"\"\n new_list = []\n for item in lst:\n new_list.append(element)\n new_list.append(item)\n return new_list", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n \"\"\"\n Inserts the given element before each element in the list.\n\n Args:\n lst: The input list.\n element: The element to insert.\n\n Returns:\n The list with the element inserted before each element.\n \"\"\"\n result = []\n for item in lst:\n result.append(element)\n result.append(item)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n \"\"\"\n Inserts an element before each element in a list.\n\n Args:\n lst: The list to modify.\n element: The element to insert.\n\n Returns:\n A new list with the element inserted before each element of the original list.\n \"\"\"\n new_lst = []\n for item in lst:\n new_lst.append(element)\n new_lst.append(item)\n return new_lst", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n \"\"\"\n This function takes in a list and an element and inserts the element\n before each element in the list, and returns the resulting list.\n\n Args:\n lst: The list to insert the element into.\n element: The element to insert.\n\n Returns:\n A new list with the element inserted before each element in the original list.\n \"\"\"\n result = []\n for item in lst:\n result.append(element)\n result.append(item)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n \"\"\"\n Inserts an element before each element in a list.\n\n Args:\n lst: The input list.\n element: The element to insert.\n\n Returns:\n A new list with the element inserted before each element in the input list.\n \"\"\"\n result = []\n for item in lst:\n result.append(element)\n result.append(item)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n \"\"\"\n Inserts the given element before each element in the list.\n\n Args:\n lst: The input list.\n element: The element to insert.\n\n Returns:\n A new list with the element inserted before each element in the input list.\n \"\"\"\n new_lst = []\n for item in lst:\n new_lst.append(element)\n new_lst.append(item)\n return new_lst", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n \"\"\"\n Inserts an element before each element in a list.\n\n Args:\n lst: The input list.\n element: The element to insert.\n\n Returns:\n A new list with the element inserted before each element in the input list.\n \"\"\"\n new_list = []\n for item in lst:\n new_list.append(element)\n new_list.append(item)\n return new_list", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n \"\"\"\n This function takes in a list and an element and inserts the element\n before each element in the list, and returns the resulting list.\n For example:\n insert_element(['Red', 'Green', 'Black'] ,'c')==['c', 'Red', 'c', 'Green', 'c', 'Black']\n \"\"\"\n result = []\n for item in lst:\n result.append(element)\n result.append(item)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n \"\"\"Inserts the given element before each element in a list.\n\n Args:\n lst: The input list.\n element: The element to be inserted.\n\n Returns:\n A new list with the element inserted before each element in the input list.\n \"\"\"\n result = []\n for item in lst:\n result.append(element)\n result.append(item)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n \"\"\"\n Inserts an element before each element in a list.\n\n Args:\n lst: The input list.\n element: The element to insert.\n\n Returns:\n A new list with the element inserted before each element in the input list.\n \"\"\"\n result = []\n for item in lst:\n result.append(element)\n result.append(item)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n \"\"\"\n Inserts the element before each element in the list and returns the resulting list.\n\n Args:\n lst: The input list.\n element: The element to insert.\n\n Returns:\n A new list with the element inserted before each element in the input list.\n \"\"\"\n new_lst = []\n for item in lst:\n new_lst.append(element)\n new_lst.append(item)\n return new_lst", "matching_cluster_idx": 6}]}, "Mbpp/256": {"dps": 73.05936073059361, "dps_norm": 67.05882352941177, "pass@1": 100.0, "profiled": [{"solution": "def count_Primes_nums(n):\n \"\"\"\n Counts the number of prime numbers less than a given non-negative number.\n\n Args:\n n: A non-negative integer.\n\n Returns:\n The count of prime numbers less than n.\n \"\"\"\n count = 0\n for num in range(2, n):\n is_prime = True\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n is_prime = False\n break\n if is_prime:\n count += 1\n return count", "matching_cluster_idx": 8}, {"solution": "def count_Primes_nums(n):\n \"\"\"\n Counts the number of prime numbers less than the given non-negative number.\n\n Args:\n n: A non-negative integer.\n\n Returns:\n The number of prime numbers less than n.\n \"\"\"\n count = 0\n for num in range(2, n):\n is_prime = True\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n is_prime = False\n break\n if is_prime:\n count += 1\n return count", "matching_cluster_idx": 8}, {"solution": "def count_Primes_nums(num):\n \"\"\"\n Counts the number of prime numbers less than the given non-negative number.\n\n Args:\n num: A non-negative integer.\n\n Returns:\n The number of prime numbers less than num.\n \"\"\"\n if num <= 1:\n return 0\n primes = [True] * num\n primes[0] = primes[1] = False\n for i in range(2, int(num**0.5) + 1):\n if primes[i]:\n for j in range(i * i, num, i):\n primes[j] = False\n return sum(primes)", "matching_cluster_idx": 14}, {"solution": "def count_Primes_nums(n):\n \"\"\"\n Write a python function that takes in a non-negative number and returns the number of prime numbers less than the given non-negative number.\n assert count_Primes_nums(5) == 2\n \"\"\"\n if n <= 1:\n return 0\n prime = [True] * n\n prime[0] = prime[1] = False\n for i in range(2, int(n**0.5) + 1):\n if prime[i]:\n for j in range(i * i, n, i):\n prime[j] = False\n return sum(prime)", "matching_cluster_idx": 14}, {"solution": "def count_Primes_nums(n):\n \"\"\"\n Counts the number of prime numbers less than n.\n\n Args:\n n: A non-negative integer.\n\n Returns:\n The number of prime numbers less than n.\n \"\"\"\n\n count = 0\n for num in range(2, n):\n is_prime = True\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n is_prime = False\n break\n if is_prime:\n count += 1\n return count", "matching_cluster_idx": 8}, {"solution": "def count_Primes_nums(n):\n \"\"\"\n Given a non-negative integer n, returns the number of prime numbers less than n.\n\n Args:\n n: A non-negative integer.\n\n Returns:\n The number of prime numbers less than n.\n \"\"\"\n if n <= 1:\n return 0\n prime = [True] * n\n prime[0] = prime[1] = False\n for i in range(2, int(n**0.5) + 1):\n if prime[i]:\n for j in range(i * i, n, i):\n prime[j] = False\n return sum(prime)", "matching_cluster_idx": 14}, {"solution": "def count_Primes_nums(num):\n \"\"\"\n This function takes in a non-negative number and returns the number of prime numbers less than the given non-negative number.\n \n For example:\n count_Primes_nums(5) == 2\n \"\"\"\n count = 0\n for i in range(2, num):\n is_prime = True\n for j in range(2, int(i**0.5) + 1):\n if i % j == 0:\n is_prime = False\n break\n if is_prime:\n count += 1\n return count", "matching_cluster_idx": 8}, {"solution": "def count_Primes_nums(n):\n \"\"\"\n This function takes a non-negative number and returns the number of prime numbers less than the given non-negative number.\n\n Args:\n n: A non-negative integer.\n\n Returns:\n The number of prime numbers less than n.\n \"\"\"\n count = 0\n for num in range(2, n):\n is_prime = True\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n is_prime = False\n break\n if is_prime:\n count += 1\n return count", "matching_cluster_idx": 8}, {"solution": "def count_Primes_nums(n):\n \"\"\"\n This function takes a non-negative number and returns the number of prime numbers less than the given non-negative number.\n \n Args:\n n: A non-negative integer.\n\n Returns:\n An integer representing the count of prime numbers less than n.\n \"\"\"\n\n if n <= 1:\n return 0\n primes = [True] * n\n primes[0] = primes[1] = False\n for i in range(2, int(n**0.5) + 1):\n if primes[i]:\n for j in range(i * i, n, i):\n primes[j] = False\n return sum(primes)", "matching_cluster_idx": 14}, {"solution": "def count_Primes_nums(n):\n \"\"\"\n Write a python function that takes in a non-negative number and returns the number of prime numbers less than the given non-negative number.\n assert count_Primes_nums(5) == 2\n \"\"\"\n if n <= 1:\n return 0\n prime = [True] * n\n prime[0] = prime[1] = False\n for i in range(2, int(n ** 0.5) + 1):\n if prime[i]:\n for j in range(i * i, n, i):\n prime[j] = False\n return sum(prime)", "matching_cluster_idx": 14}, {"solution": "def count_Primes_nums(n):\n \"\"\"\n This function takes in a non-negative number and returns the number of prime numbers less than the given non-negative number.\n\n Args:\n n: A non-negative integer.\n\n Returns:\n The number of prime numbers less than n.\n \"\"\"\n count = 0\n for num in range(2, n):\n is_prime = True\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n is_prime = False\n break\n if is_prime:\n count += 1\n return count", "matching_cluster_idx": 8}, {"solution": "def count_Primes_nums(n):\n \"\"\"\n Counts the number of prime numbers less than a given non-negative number.\n\n Args:\n n: A non-negative integer.\n\n Returns:\n The number of prime numbers less than n.\n \"\"\"\n count = 0\n for num in range(2, n):\n is_prime = True\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n is_prime = False\n break\n if is_prime:\n count += 1\n return count", "matching_cluster_idx": 8}, {"solution": "def count_Primes_nums(n):\n \"\"\"\n This function takes in a non-negative number and returns the number of prime numbers less than the given non-negative number.\n For example:\n count_Primes_nums(5) == 2\n \"\"\"\n count = 0\n for num in range(2, n):\n is_prime = True\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n is_prime = False\n break\n if is_prime:\n count += 1\n return count", "matching_cluster_idx": 8}, {"solution": "def count_Primes_nums(n):\n \"\"\"\n Counts the number of prime numbers less than the given non-negative number.\n\n Args:\n n: A non-negative integer.\n\n Returns:\n The number of prime numbers less than n.\n \"\"\"\n if n <= 1:\n return 0\n primes = [True] * n\n primes[0] = primes[1] = False\n for i in range(2, int(n**0.5) + 1):\n if primes[i]:\n for j in range(i * i, n, i):\n primes[j] = False\n return sum(primes)", "matching_cluster_idx": 14}, {"solution": "def count_Primes_nums(n):\n \"\"\"\n Counts the number of prime numbers less than the given non-negative number.\n\n Args:\n n: A non-negative integer.\n\n Returns:\n The number of prime numbers less than n.\n \"\"\"\n if n <= 1:\n return 0 \n primes = [True] * n \n primes[0] = primes[1] = False\n for i in range(2, int(n**0.5) + 1):\n if primes[i]:\n for j in range(i * i, n, i):\n primes[j] = False\n return sum(primes)", "matching_cluster_idx": 14}, {"solution": "def count_Primes_nums(n):\n \"\"\"\n Counts the number of prime numbers less than a given non-negative number.\n\n Args:\n n: A non-negative integer.\n\n Returns:\n The number of prime numbers less than n.\n \"\"\"\n count = 0\n for num in range(2, n):\n is_prime = True\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n is_prime = False\n break\n if is_prime:\n count += 1\n return count", "matching_cluster_idx": 8}, {"solution": "def count_Primes_nums(n):\n \"\"\"\n This function takes in a non-negative number and returns the number of prime numbers less than the given non-negative number.\n\n Args:\n n: A non-negative integer.\n\n Returns:\n The number of prime numbers less than n.\n \"\"\"\n if n <= 1:\n return 0\n primes = [True] * n\n primes[0] = primes[1] = False\n for i in range(2, int(n**0.5) + 1):\n if primes[i]:\n for j in range(i * i, n, i):\n primes[j] = False\n return sum(primes)", "matching_cluster_idx": 14}, {"solution": "def count_Primes_nums(n):\n \"\"\"\n Counts the number of prime numbers less than the given non-negative number.\n\n Args:\n n: A non-negative integer.\n\n Returns:\n The number of prime numbers less than n.\n \"\"\"\n count = 0\n for num in range(2, n):\n is_prime = True\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n is_prime = False\n break\n if is_prime:\n count += 1\n return count", "matching_cluster_idx": 8}, {"solution": "def count_Primes_nums(n):\n \"\"\"\n Counts the number of prime numbers less than a given non-negative number.\n\n Args:\n n: A non-negative integer.\n\n Returns:\n The number of prime numbers less than n.\n \"\"\"\n count = 0\n for num in range(2, n):\n is_prime = True\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n is_prime = False\n break\n if is_prime:\n count += 1\n return count", "matching_cluster_idx": 8}, {"solution": "def count_Primes_nums(n):\n \"\"\"\n Counts the number of prime numbers less than the given non-negative number.\n\n Args:\n n: A non-negative integer.\n\n Returns:\n The number of prime numbers less than n.\n \"\"\"\n count = 0\n for num in range(2, n):\n is_prime = True\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n is_prime = False\n break\n if is_prime:\n count += 1\n return count", "matching_cluster_idx": 8}]}, "Mbpp/265": {"dps": null, "dps_norm": null, "pass@1": 0.0, "profiled": []}, "Mbpp/281": {"dps": 94.25, "dps_norm": 84.0909090909091, "pass@1": 100.0, "profiled": [{"solution": "def all_unique(data):\n \"\"\"\n Checks if the elements of a given list are unique.\n\n Args:\n data: A list of elements.\n\n Returns:\n True if all elements are unique, False otherwise.\n \"\"\"\n return len(set(data)) == len(data)", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n Checks if all elements in a list are unique.\n\n Args:\n lst: A list of elements.\n\n Returns:\n True if all elements are unique, False otherwise.\n \"\"\"\n seen = set()\n for item in lst:\n if item in seen:\n return False\n seen.add(item)\n return True", "matching_cluster_idx": 9}, {"solution": "def all_unique(lst):\n \"\"\"\n Checks if the elements of a given list are unique or not.\n\n Args:\n lst: A list of elements.\n\n Returns:\n True if all elements in the list are unique, False otherwise.\n \"\"\"\n return len(set(lst)) == len(lst)", "matching_cluster_idx": 8}, {"solution": "def all_unique(list1):\n \"\"\"\n Checks if all elements in a list are unique.\n\n Args:\n list1: A list of elements.\n\n Returns:\n True if all elements are unique, False otherwise.\n \"\"\"\n return len(list1) == len(set(list1))", "matching_cluster_idx": 8}, {"solution": "def all_unique(data):\n \"\"\"\n Checks if all elements in a list are unique.\n\n Args:\n data: A list of elements.\n\n Returns:\n True if all elements are unique, False otherwise.\n \"\"\"\n return len(set(data)) == len(data)", "matching_cluster_idx": 8}, {"solution": "def all_unique(data):\n \"\"\"Checks if all elements in a list are unique.\n\n Args:\n data: A list of elements.\n\n Returns:\n True if all elements are unique, False otherwise.\n \"\"\"\n return len(set(data)) == len(data)", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n Checks if all elements in a list are unique.\n\n Args:\n lst: A list of elements.\n\n Returns:\n True if all elements are unique, False otherwise.\n \"\"\"\n return len(set(lst)) == len(lst)", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n Checks if all elements in a list are unique.\n\n Args:\n lst: A list of elements.\n\n Returns:\n True if all elements in the list are unique, False otherwise.\n \"\"\"\n seen = set()\n for element in lst:\n if element in seen:\n return False\n seen.add(element)\n return True", "matching_cluster_idx": 9}, {"solution": "def all_unique(list1):\n \"\"\"\n Checks if the elements of a given list are unique or not.\n\n Args:\n list1: A list of elements.\n\n Returns:\n True if all elements are unique, False otherwise.\n \"\"\"\n\n seen = set()\n for element in list1:\n if element in seen:\n return False\n seen.add(element)\n return True", "matching_cluster_idx": 9}, {"solution": "def all_unique(lst):\n \"\"\"\n Checks if all elements in a list are unique.\n\n Args:\n lst: A list of elements.\n\n Returns:\n True if all elements are unique, False otherwise.\n \"\"\"\n return len(set(lst)) == len(lst)", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n Checks if all elements in a list are unique.\n\n Args:\n lst: A list of elements.\n\n Returns:\n True if all elements are unique, False otherwise.\n \"\"\"\n return len(set(lst)) == len(lst)", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n Checks if the elements of a given list are unique or not.\n\n Args:\n lst: A list of elements.\n\n Returns:\n True if all elements in the list are unique, False otherwise.\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(data):\n \"\"\"\n Checks if all elements in a list are unique.\n\n Args:\n data: A list of elements.\n\n Returns:\n True if all elements are unique, False otherwise.\n \"\"\"\n seen = set()\n for item in data:\n if item in seen:\n return False\n seen.add(item)\n return True", "matching_cluster_idx": 9}, {"solution": "def all_unique(lst):\n \"\"\"\n Checks if all elements in a list are unique.\n\n Args:\n lst: A list of elements.\n\n Returns:\n True if all elements are unique, False otherwise.\n \"\"\"\n return len(set(lst)) == len(lst)", "matching_cluster_idx": 8}, {"solution": "def all_unique(data):\n \"\"\"\n Checks if all elements in a list are unique.\n\n Args:\n data: A list of elements.\n\n Returns:\n True if all elements are unique, False otherwise.\n \"\"\"\n seen = set()\n for item in data:\n if item in seen:\n return False\n seen.add(item)\n return True", "matching_cluster_idx": 9}, {"solution": "def all_unique(lst):\n \"\"\"\n Checks if all elements in a list are unique.\n\n Args:\n lst: A list of elements.\n\n Returns:\n True if all elements are unique, False otherwise.\n \"\"\"\n return len(set(lst)) == len(lst)", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n Checks if all elements in a list are unique.\n\n Args:\n lst: A list of elements.\n\n Returns:\n True if all elements are unique, False otherwise.\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(data):\n \"\"\"\n Checks if all elements in a list are unique.\n\n Args:\n data: A list of elements.\n\n Returns:\n True if all elements are unique, False otherwise.\n \"\"\"\n return len(data) == len(set(data))", "matching_cluster_idx": 8}, {"solution": "def all_unique(data):\n \"\"\"\n Checks if all elements in a list are unique.\n\n Args:\n data: A list of elements.\n\n Returns:\n True if all elements are unique, False otherwise.\n \"\"\"\n return len(data) == len(set(data))", "matching_cluster_idx": 8}, {"solution": "def all_unique(data):\n \"\"\"\n Checks if all elements in a list are unique.\n\n Args:\n data: A list of elements.\n\n Returns:\n True if all elements are unique, False otherwise.\n \"\"\"\n return len(data) == len(set(data))", "matching_cluster_idx": 8}]}, "Mbpp/296": {"dps": 16.41025641025641, "dps_norm": 58.333333333333336, "pass@1": 99.0, "profiled": [{"solution": "def get_Inv_Count(arr):\n \"\"\"\n Counts the number of inversions in an array.\n An inversion is a pair of elements where the first element is greater than the second element.\n\n Args:\n arr: A list of integers.\n\n Returns:\n The number of inversions in the array.\n \"\"\"\n\n count = 0\n for i in range(len(arr)):\n for j in range(i + 1, len(arr)):\n if arr[i] > arr[j]:\n count += 1\n return count\narr = [1, 20, 6, 4, 5]", "matching_cluster_idx": 2}, {"solution": "def get_Inv_Count(arr):\n \"\"\"\n Counts the number of inversions in an array.\n\n Args:\n arr: A list of integers.\n\n Returns:\n The number of inversions in the array.\n \"\"\"\n count = 0\n for i in range(len(arr)):\n for j in range(i + 1, len(arr)):\n if arr[i] > arr[j]:\n count += 1\n return count\narr = [1, 20, 6, 4, 5]", "matching_cluster_idx": 3}, {"solution": "def merge_sort_and_count(arr):\n if len(arr) <= 1:\n return 0, arr\n \n mid = len(arr) // 2\n left_count, left_arr = merge_sort_and_count(arr[:mid])\n right_count, right_arr = merge_sort_and_count(arr[mid:])\n\n count = 0\n i = j = 0\n merged_arr = []\n while i < len(left_arr) and j < len(right_arr):\n if left_arr[i] <= right_arr[j]:\n merged_arr.append(left_arr[i])\n i += 1\n else:\n merged_arr.append(right_arr[j])\n j += 1\n count += len(left_arr) - i # Count inversions\n\n merged_arr.extend(left_arr[i:])\n merged_arr.extend(right_arr[j:])\n\n return count + left_count + right_count, merged_arr\ndef get_Inv_Count(arr):\n \"\"\"\n Counts the number of inversions in an array.\n \n Args:\n arr: The input array.\n Returns:\n The number of inversions in the array.\n \"\"\"\n return merge_sort_and_count(arr)[0]", "matching_cluster_idx": 5}, {"solution": "def get_Inv_Count(arr):\n \"\"\"\n Counts the number of inversions in an array.\n\n An inversion is a pair of elements where the first element is greater \n than the second element but appears before it in the array.\n\n Args:\n arr: A list of integers.\n\n Returns:\n The number of inversions in the array.\n \"\"\"\n count = 0\n for i in range(len(arr)):\n for j in range(i + 1, len(arr)):\n if arr[i] > arr[j]:\n count += 1\n return count\narr = [1, 20, 6, 4, 5]", "matching_cluster_idx": 2}, {"solution": "def get_Inv_Count(arr):\n \"\"\"\n Counts the number of inversions in an array.\n\n An inversion is a pair of elements where the first element is greater than the second element \n and they appear out of order.\n\n Args:\n arr: The input array of integers.\n\n Returns:\n The number of inversions in the array.\n \"\"\"\n\n count = 0\n for i in range(len(arr)):\n for j in range(i + 1, len(arr)):\n if arr[i] > arr[j]:\n count += 1\n return count\narr = [1, 20, 6, 4, 5]", "matching_cluster_idx": 2}, {"solution": "def get_Inv_Count(arr):\n \"\"\"\n Counts inversions in an array.\n\n An inversion is a pair (i, j) where i < j and arr[i] > arr[j].\n\n Args:\n arr: The input array.\n\n Returns:\n The number of inversions in the array.\n \"\"\"\n count = 0\n for i in range(len(arr)):\n for j in range(i + 1, len(arr)):\n if arr[i] > arr[j]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def get_Inv_Count(arr):\n \"\"\"\n This function counts the number of inversions in an array.\n\n An inversion is a pair of indices (i, j) where i < j and arr[i] > arr[j].\n\n Args:\n arr: A list of integers.\n\n Returns:\n The number of inversions in the array.\n \"\"\"\n inv_count = 0\n n = len(arr)\n for i in range(n):\n for j in range(i + 1, n):\n if arr[i] > arr[j]:\n inv_count += 1\n return inv_count\narr = [1, 20, 6, 4, 5]", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n \"\"\"\n Counts the number of inversions in an array.\n\n An inversion is a pair of elements (i, j) where i < j and arr[i] > arr[j].\n\n Args:\n arr: The input array.\n\n Returns:\n The number of inversions in the array.\n \"\"\"\n count = 0\n n = len(arr)\n for i in range(n):\n for j in range(i + 1, n):\n if arr[i] > arr[j]:\n count += 1\n return count\narr = [1, 20, 6, 4, 5]", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n \"\"\"\n This function counts the inversions in an array.\n \n Args:\n arr: A list of integers.\n \n Returns:\n The number of inversions in the array.\n \"\"\"\n count = 0\n for i in range(len(arr)):\n for j in range(i + 1, len(arr)):\n if arr[i] > arr[j]:\n count += 1\n return count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n \"\"\"\n This function counts the number of inversions in an array.\n\n An inversion is a pair (i, j) where i < j and arr[i] > arr[j].\n\n Args:\n arr: The input array.\n\n Returns:\n The number of inversions in the array.\n \"\"\"\n count = 0\n for i in range(len(arr)):\n for j in range(i + 1, len(arr)):\n if arr[i] > arr[j]:\n count += 1\n return count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n \"\"\"\n Counts the number of inversions in an array.\n\n Args:\n arr: A list of integers.\n\n Returns:\n The number of inversions in the array.\n \"\"\"\n\n count = 0\n for i in range(len(arr)):\n for j in range(i + 1, len(arr)):\n if arr[i] > arr[j]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def get_Inv_Count(arr):\n \"\"\"\n Counts inversions in an array.\n \n An inversion is a pair of elements (i, j) in an array where i < j and arr[i] > arr[j].\n \n Args:\n arr: A list of numbers.\n \n Returns:\n The number of inversions in the array.\n \n Examples:\n get_Inv_Count([1,20,6,4,5]) == 5\n \"\"\"\n inv_count = 0\n for i in range(len(arr)):\n for j in range(i + 1, len(arr)):\n if arr[i] > arr[j]:\n inv_count += 1\n return inv_count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n \"\"\"\n Counts the number of inversions in an array.\n\n An inversion is a pair of elements (a, b) where a < b but a appears after b in the array.\n\n Args:\n arr: A list of numbers.\n\n Returns:\n The number of inversions in the array.\n \"\"\"\n count = 0\n for i in range(len(arr)):\n for j in range(i + 1, len(arr)):\n if arr[i] > arr[j]:\n count += 1\n return count\narr = [1, 20, 6, 4, 5]", "matching_cluster_idx": 2}, {"solution": "def get_Inv_Count(arr):\n \"\"\"\n Counts the number of inversions in an array.\n\n Args:\n arr: A list of integers.\n\n Returns:\n The number of inversions in the array.\n \"\"\"\n inv_count = 0\n for i in range(len(arr)):\n for j in range(i+1, len(arr)):\n if arr[i] > arr[j]:\n inv_count += 1\n return inv_count", "matching_cluster_idx": 2}, {"solution": "def get_Inv_Count(arr):\n \"\"\"\n Counts inversions in an array.\n\n An inversion is a pair of elements where the first element is greater than\n the second element but appears before it in the array.\n\n Args:\n arr: A list of integers.\n\n Returns:\n The number of inversions in the array.\n \"\"\"\n inversion_count = 0\n for i in range(len(arr)):\n for j in range(i + 1, len(arr)):\n if arr[i] > arr[j]:\n inversion_count += 1\n return inversion_count\narr = [1, 20, 6, 4, 5]", "matching_cluster_idx": 2}, {"solution": "def get_Inv_Count(arr):\n \"\"\"\n Counts the number of inversions in an array.\n An inversion is a pair of elements (i, j) where i < j but arr[i] > arr[j].\n\n Args:\n arr: A list of integers.\n\n Returns:\n The number of inversions in the array.\n \"\"\"\n inv_count = 0\n for i in range(len(arr)):\n for j in range(i + 1, len(arr)):\n if arr[i] > arr[j]:\n inv_count += 1\n return inv_count\narr = [1, 20, 6, 4, 5]", "matching_cluster_idx": 2}, {"solution": "def get_Inv_Count(arr):\n \"\"\"\n Counts the number of inversions in an array.\n\n An inversion is a pair (i, j) where i < j but arr[i] > arr[j].\n\n Args:\n arr: A list of integers.\n\n Returns:\n The number of inversions in the array.\n \"\"\"\n inv_count = 0\n for i in range(len(arr)):\n for j in range(i + 1, len(arr)):\n if arr[i] > arr[j]:\n inv_count += 1\n return inv_count\narr = [1, 20, 6, 4, 5]", "matching_cluster_idx": 2}, {"solution": "def get_Inv_Count(arr):\n \"\"\"\n Counts the number of inversions in an array.\n\n An inversion is a pair of elements (i, j) where i < j and arr[i] > arr[j].\n\n Args:\n arr: The input array.\n\n Returns:\n The number of inversions in the array.\n \"\"\"\n count = 0\n for i in range(len(arr)):\n for j in range(i + 1, len(arr)):\n if arr[i] > arr[j]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def get_Inv_Count(arr):\n \"\"\"\n Counts the number of inversions in an array.\n\n An inversion is a pair of elements (i, j) where i < j and arr[i] > arr[j].\n\n Args:\n arr: A list of integers.\n\n Returns:\n The number of inversions in the array.\n \"\"\"\n inv_count = 0\n n = len(arr)\n for i in range(n):\n for j in range(i + 1, n):\n if arr[i] > arr[j]:\n inv_count += 1\n return inv_count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n \"\"\"\n Counts inversions in an array.\n An inversion is a pair (i, j) such that i < j and arr[i] > arr[j].\n\n Args:\n arr: The input array.\n\n Returns:\n The number of inversions in the array.\n \"\"\"\n count = 0\n for i in range(len(arr)):\n for j in range(i + 1, len(arr)):\n if arr[i] > arr[j]:\n count += 1\n return count", "matching_cluster_idx": 2}]}, "Mbpp/308": {"dps": 94.27586206896552, "dps_norm": 65.83333333333334, "pass@1": 54.0, "profiled": [{"solution": "def large_product(list1, list2, n):\n \"\"\"\n Finds the specified number of largest products from two given lists, selecting one factor from each list.\n\n Args:\n list1: The first list of numbers.\n list2: The second list of numbers.\n n: The number of largest products to find.\n\n Returns:\n A list of the n largest products.\n \"\"\"\n products = [(x * y) for x in list1 for y in list2]\n return sorted(products, reverse=True)[:n]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n \"\"\"\n Finds the specified number of largest products from two given lists,\n selecting one factor from each list.\n\n Args:\n list1: The first list of numbers.\n list2: The second list of numbers.\n n: The number of largest products to find.\n\n Returns:\n A list of the n largest products.\n \"\"\"\n products = [(x * y) for x in list1 for y in list2]\n sorted_products = sorted(products, reverse=True)\n return sorted_products[:n]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n \"\"\"\n Finds the specified number of largest products from two given lists, \n selecting one factor from each list.\n\n Args:\n list1: The first list of numbers.\n list2: The second list of numbers.\n n: The number of largest products to find.\n\n Returns:\n A list of the n largest products.\n \"\"\"\n products = [(x * y) for x in list1 for y in list2]\n products.sort(reverse=True)\n return products[:n]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n \"\"\"\n Finds the specified number of largest products from two given lists, selecting one factor from each list.\n\n Args:\n list1: The first list of numbers.\n list2: The second list of numbers.\n n: The number of largest products to find.\n\n Returns:\n A list containing the n largest products.\n \"\"\"\n products = [(x * y) for x in list1 for y in list2]\n products.sort(reverse=True)\n return products[:n]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, num):\n \"\"\"\n Finds the specified number of largest products from two given lists,\n selecting one factor from each list.\n\n Args:\n list1: The first list of numbers.\n list2: The second list of numbers.\n num: The number of largest products to find.\n\n Returns:\n A list containing the specified number of largest products.\n \"\"\"\n products = [(x * y) for x in list1 for y in list2]\n products.sort(reverse=True) \n return products[:num]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, k):\n \"\"\"\n Find the specified number of largest products from two given lists, selecting one factor from each list.\n\n Args:\n list1 (list): The first list of numbers.\n list2 (list): The second list of numbers.\n k (int): The number of largest products to find.\n\n Returns:\n list: A list of the k largest products.\n \"\"\"\n products = sorted((x * y for x in list1 for y in list2), reverse=True)[:k]\n return products", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n \"\"\"\n Finds the specified number of largest products from two given lists, selecting one factor from each list.\n\n Args:\n list1: The first list of numbers.\n list2: The second list of numbers.\n n: The number of largest products to find.\n\n Returns:\n A list containing the n largest products.\n \"\"\"\n products = [(x * y) for x in list1 for y in list2]\n products.sort(reverse=True)\n return products[:n]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n \"\"\"\n Finds the specified number of largest products from two given lists, selecting one factor from each list.\n\n Args:\n list1: The first list of numbers.\n list2: The second list of numbers.\n n: The number of largest products to find.\n\n Returns:\n A list containing the n largest products.\n \"\"\"\n products = [(x * y) for x in list1 for y in list2]\n return sorted(products, reverse=True)[:n]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n \"\"\"\n Finds the specified number of largest products from two given lists, selecting one factor from each list.\n\n Args:\n list1: The first list of numbers.\n list2: The second list of numbers.\n n: The number of largest products to find.\n\n Returns:\n A list of the n largest products.\n \"\"\"\n products = sorted((x*y for x in list1 for y in list2), reverse=True)\n return products[:n]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n \"\"\"\n Finds the specified number of largest products from two given lists, selecting one factor from each list.\n\n Args:\n list1: The first list.\n list2: The second list.\n n: The number of largest products to find.\n\n Returns:\n A list containing the n largest products.\n \"\"\"\n products = sorted([x*y for x in list1 for y in list2], reverse=True)\n return products[:n]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, k):\n \"\"\"\n Finds the specified number of largest products from two given lists, selecting one factor from each list.\n\n Args:\n list1: The first list of numbers.\n list2: The second list of numbers.\n k: The number of largest products to find.\n\n Returns:\n A list containing the k largest products.\n \"\"\"\n\n products = sorted([(x*y, x, y) for x in list1 for y in list2], reverse=True)[:k]\n return [product[0] for product in products]", "matching_cluster_idx": 2}, {"solution": "def large_product(list1, list2, k):\n \"\"\"\n Finds the specified number of largest products from two lists, selecting one factor from each.\n\n Args:\n list1: The first list of numbers.\n list2: The second list of numbers.\n k: The number of largest products to find.\n\n Returns:\n A list of the k largest products.\n \"\"\"\n # Combine the lists into a list of tuples, where each tuple represents a product\n products = [(x * y) for x in list1 for y in list2]\n \n # Sort the products in descending order\n products.sort(reverse=True)\n\n # Return the top k products\n return products[:k]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n \"\"\"\n Finds the specified number of largest products from two given lists,\n selecting one factor from each list.\n\n Args:\n list1: The first list of numbers.\n list2: The second list of numbers.\n n: The number of largest products to find.\n\n Returns:\n A list of the n largest products.\n \"\"\"\n products = [(x * y) for x in list1 for y in list2]\n products.sort(reverse=True) \n return products[:n]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n \"\"\"\n Finds the specified number of largest products from two lists, \n selecting one factor from each list.\n\n Args:\n list1: The first list of numbers.\n list2: The second list of numbers.\n n: The number of largest products to find.\n\n Returns:\n A list containing the n largest products.\n \"\"\"\n\n product_pairs = [(x * y) for x in list1 for y in list2]\n product_pairs.sort(reverse=True) # Sort in descending order\n return product_pairs[:n]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n \"\"\"\n Finds the specified number of largest products from two given lists, selecting one factor from each list.\n\n Args:\n list1: The first list of numbers.\n list2: The second list of numbers.\n n: The number of largest products to find.\n\n Returns:\n A list of the n largest products.\n \"\"\"\n \n product_list = [(x * y) for x in list1 for y in list2]\n product_list.sort(reverse=True) \n return product_list[:n]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n \"\"\"\n Finds the specified number of largest products from two given lists, selecting one factor from each list.\n\n Args:\n list1: The first list of numbers.\n list2: The second list of numbers.\n n: The number of largest products to find.\n\n Returns:\n A list of the n largest products.\n \"\"\"\n products = [(x * y) for x in list1 for y in list2]\n return sorted(products, reverse=True)[:n]", "matching_cluster_idx": 3}, {"solution": "def large_product(nums1, nums2, k):\n \"\"\"\n Finds the specified number of largest products from two given lists, \n selecting one factor from each list.\n\n Args:\n nums1: The first list of numbers.\n nums2: The second list of numbers.\n k: The number of largest products to find.\n\n Returns:\n A list of the k largest products.\n \"\"\"\n products = [(x*y) for x in nums1 for y in nums2]\n products.sort(reverse=True)\n return products[:k]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n \"\"\"\n Finds the specified number of largest products from two given lists, \n selecting one factor from each list.\n\n Args:\n list1: The first list of numbers.\n list2: The second list of numbers.\n n: The number of largest products to find.\n\n Returns:\n A list of the n largest products.\n \"\"\"\n\n product_list = []\n \n # Iterate through the lists and calculate products\n for x in list1:\n for y in list2:\n product_list.append(x * y)\n\n # Sort the products in descending order\n product_list.sort(reverse=True)\n\n # Return the first n products\n return product_list[:n]\nlist1 = [1, 2, 3, 4, 5, 6]\nlist2 = [3, 6, 8, 9, 10, 6]\nn = 3", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n \"\"\"\n Finds the specified number of largest products from two given lists, selecting one factor from each list.\n\n Args:\n list1: The first list of numbers.\n list2: The second list of numbers.\n n: The number of largest products to find.\n\n Returns:\n A list containing the n largest products.\n \"\"\"\n \n products = [(x * y) for x in list1 for y in list2]\n products.sort(reverse=True) \n return products[:n]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n \"\"\"\n Finds the specified number of largest products from two given lists, \n selecting one factor from each list.\n\n Args:\n list1: The first list of numbers.\n list2: The second list of numbers.\n n: The number of largest products to find.\n\n Returns:\n A list containing the n largest products.\n \"\"\"\n products = [(x*y) for x in list1 for y in list2]\n products.sort(reverse=True) \n return products[:n]", "matching_cluster_idx": 3}]}, "Mbpp/392": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 59.0, "profiled": [{"solution": "def get_max_sum(n):\n memo = {}\n\n def helper(n):\n if n in memo:\n return memo[n]\n if n <= 1:\n return n\n memo[n] = max(helper(n // 2) + helper(n // 3) + helper(n // 4) + helper(n // 5), n)\n return memo[n]\n\n return helper(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n \"\"\"\n Find the maximum sum possible using the equation f(n) = max( (f(n/2) + f(n/3) + f(n/4) + f(n/5)), n).\n\n Args:\n n: An integer.\n\n Returns:\n The maximum sum achievable for the given input n.\n \"\"\"\n memo = {}\n\n def _get_max_sum(n):\n if n in memo:\n return memo[n]\n if n <= 1:\n return n\n memo[n] = max(_get_max_sum(n // 2) + _get_max_sum(n // 3) + _get_max_sum(n // 4) + _get_max_sum(n // 5), n)\n return memo[n]\n\n return _get_max_sum(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n \"\"\"\n Find the maximum sum possible by using the given equation f(n) = max( (f(n/2) + f(n/3) + f(n/4) + f(n/5)), n).\n\n Args:\n n (int): The input integer.\n\n Returns:\n int: The maximum sum possible.\n \"\"\"\n memo = {} \n\n def _get_max_sum(n):\n if n in memo:\n return memo[n]\n if n <= 1:\n return n\n memo[n] = max( _get_max_sum(n // 2) + _get_max_sum(n // 3) + _get_max_sum(n // 4) + _get_max_sum(n // 5), n)\n return memo[n]\n\n return _get_max_sum(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n \"\"\"\n Finds the maximum sum possible by using the equation f(n) = max( (f(n/2) + f(n/3) + f(n/4) + f(n/5)), n).\n\n Args:\n n: An integer.\n\n Returns:\n The maximum sum possible.\n \"\"\"\n memo = {} \n\n def _f(n):\n if n in memo:\n return memo[n]\n if n < 1:\n return 0\n memo[n] = max( _f(n//2) + _f(n//3) + _f(n//4) + _f(n//5), n)\n return memo[n]\n\n return _f(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n \"\"\"\n Finds the maximum sum possible by using the equation f(n) = max( (f(n/2) + f(n/3) + f(n/4) + f(n/5)), n).\n \"\"\"\n memo = {}\n \n def _get_max_sum(n):\n if n in memo:\n return memo[n]\n if n <= 1:\n return n\n \n res = max( _get_max_sum(n//2) + _get_max_sum(n//3) + _get_max_sum(n//4) + _get_max_sum(n//5), n)\n memo[n] = res\n return res\n return _get_max_sum(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n \"\"\"\n Finds the maximum sum possible using the equation f(n) = max( (f(n/2) + f(n/3) + f(n/4) + f(n/5)), n).\n \"\"\"\n memo = {}\n\n def helper(n):\n if n in memo:\n return memo[n]\n if n <= 1:\n return n\n \n res = max(helper(n // 2) + helper(n // 3) + helper(n // 4) + helper(n // 5), n)\n memo[n] = res\n return res\n\n return helper(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n \"\"\"\n Find the maximum sum possible using the equation f(n) = max( (f(n/2) + f(n/3) + f(n/4) + f(n/5)), n).\n\n Args:\n n: An integer.\n\n Returns:\n The maximum sum possible.\n \"\"\"\n\n memo = {} \n\n def _f(n):\n if n in memo:\n return memo[n]\n if n <= 1:\n return n\n memo[n] = max(_f(n//2) + _f(n//3) + _f(n//4) + _f(n//5), n)\n return memo[n]\n\n return _f(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n \"\"\"\n Find the maximum sum possible by using the given equation f(n) = max( (f(n/2) + f(n/3) + f(n/4) + f(n/5)), n).\n \n Args:\n n: An integer.\n\n Returns:\n An integer representing the maximum sum.\n \"\"\"\n memo = {}\n \n def calculate_sum(n):\n if n in memo:\n return memo[n]\n if n <= 1:\n return n\n result = max(calculate_sum(n//2) + calculate_sum(n//3) + calculate_sum(n//4) + calculate_sum(n//5), n)\n memo[n] = result\n return result\n \n return calculate_sum(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n \"\"\"\n Finds the maximum sum possible by using the given equation f(n) = max( (f(n/2) + f(n/3) + f(n/4) + f(n/5)), n).\n\n Args:\n n (int): The input integer.\n\n Returns:\n int: The maximum sum possible.\n \"\"\"\n memo = {} \n\n def _get_max_sum(n):\n if n in memo:\n return memo[n]\n if n <= 1:\n return n\n result = max(\n _get_max_sum(n // 2) + _get_max_sum(n // 3) + _get_max_sum(n // 4) + _get_max_sum(n // 5), n\n )\n memo[n] = result\n return result\n\n return _get_max_sum(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n \"\"\"\n Find the maximum sum possible by using the given equation f(n) = max( (f(n/2) + f(n/3) + f(n/4) + f(n/5)), n).\n\n Args:\n n: The input integer.\n\n Returns:\n The maximum sum possible.\n \"\"\"\n\n memo = {0: 0, 1: 1}\n \n def helper(n):\n if n in memo:\n return memo[n]\n \n max_sum = n\n if n > 1:\n max_sum = max(max_sum, helper(n//2) + helper(n//3) + helper(n//4) + helper(n//5))\n memo[n] = max_sum\n return max_sum\n \n return helper(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n \"\"\"\n Find the maximum sum possible by using the given equation f(n) = max( (f(n/2) + f(n/3) + f(n/4) + f(n/5)), n).\n \n Args:\n n: An integer representing the input number.\n\n Returns:\n The maximum sum achievable for the given input 'n'.\n \"\"\"\n memo = {}\n def _get_max_sum(n):\n if n <= 1:\n return n\n if n in memo:\n return memo[n]\n memo[n] = max(\n _get_max_sum(n // 2) + _get_max_sum(n // 3) + _get_max_sum(n // 4) + _get_max_sum(n // 5),\n n\n )\n return memo[n]\n\n return _get_max_sum(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n \"\"\"\n Find the maximum sum possible by using the given equation f(n) = max( (f(n/2) + f(n/3) + f(n/4) + f(n/5)), n).\n \"\"\"\n cache = {}\n def _get_max_sum(n):\n if n <= 1:\n return n\n if n in cache:\n return cache[n]\n cache[n] = max(_get_max_sum(n//2) + _get_max_sum(n//3) + _get_max_sum(n//4) + _get_max_sum(n//5), n)\n return cache[n]\n return _get_max_sum(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n \"\"\"\n Finds the maximum sum possible by using the given equation f(n) = max( (f(n/2) + f(n/3) + f(n/4) + f(n/5)), n).\n\n Args:\n n: An integer.\n\n Returns:\n The maximum sum achievable.\n\n \"\"\"\n memo = {}\n def helper(n):\n if n in memo:\n return memo[n]\n if n <= 1:\n return n\n memo[n] = max(helper(n//2) + helper(n//3) + helper(n//4) + helper(n//5), n)\n return memo[n]\n return helper(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n \"\"\"\n Finds the maximum sum possible by using the given equation f(n) = max( (f(n/2) + f(n/3) + f(n/4) + f(n/5)), n).\n\n Args:\n n: An integer.\n\n Returns:\n The maximum sum possible.\n \"\"\"\n\n memo = {} # Create a dictionary to store calculated results\n\n def calculate_sum(n):\n if n in memo:\n return memo[n] # Return cached result if available\n\n if n <= 1:\n return n \n \n result = max(calculate_sum(n // 2) + calculate_sum(n // 3) + calculate_sum(n // 4) + calculate_sum(n // 5), n)\n memo[n] = result # Store the calculated result\n return result\n \n return calculate_sum(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n \"\"\"\n Finds the maximum sum possible using the equation f(n) = max( (f(n/2) + f(n/3) + f(n/4) + f(n/5)), n).\n\n Args:\n n: The input integer.\n\n Returns:\n The maximum sum achievable for the given n.\n \"\"\"\n memo = {}\n def helper(n):\n if n in memo:\n return memo[n]\n if n <= 1:\n return n\n memo[n] = max(helper(n//2) + helper(n//3) + helper(n//4) + helper(n//5), n)\n return memo[n]\n\n return helper(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n \"\"\"\n Finds the maximum sum possible by using the given equation \n f(n) = max( (f(n/2) + f(n/3) + f(n/4) + f(n/5)), n).\n\n Args:\n n: An integer.\n\n Returns:\n The maximum sum possible.\n \"\"\"\n memo = {}\n\n def helper(n):\n if n in memo:\n return memo[n]\n if n <= 1:\n return n\n result = max(helper(n // 2) + helper(n // 3) + helper(n // 4) + helper(n // 5), n)\n memo[n] = result\n return result\n\n return helper(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n memo = {} # Memoization for optimized calculations\n \n def calculate_max_sum(num):\n if num < 1:\n return 0\n if num in memo:\n return memo[num]\n \n # Calculate the maximum sum using the equation\n result = max((calculate_max_sum(num // 2) + calculate_max_sum(num // 3) + calculate_max_sum(num // 4) + calculate_max_sum(num // 5)), num)\n memo[num] = result \n return result\n\n return calculate_max_sum(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n \"\"\"\n Finds the maximum sum possible using the equation f(n) = max( (f(n/2) + f(n/3) + f(n/4) + f(n/5)), n).\n\n Args:\n n: An integer.\n\n Returns:\n The maximum sum possible using the given equation.\n \"\"\"\n memo = {} # Memoization dictionary to store computed results\n\n def _get_max_sum(n):\n if n in memo:\n return memo[n]\n if n <= 1:\n return n\n result = max(_get_max_sum(n // 2) + _get_max_sum(n // 3) + _get_max_sum(n // 4) + _get_max_sum(n // 5), n)\n memo[n] = result\n return result\n\n return _get_max_sum(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n \"\"\"\n Finds the maximum sum possible by using the equation f(n) = max( (f(n/2) + f(n/3) + f(n/4) + f(n/5)), n).\n\n Args:\n n: An integer.\n\n Returns:\n The maximum sum possible.\n \"\"\"\n memo = {} \n\n def _get_max_sum(n):\n if n in memo:\n return memo[n]\n if n <= 1:\n return n\n memo[n] = max(_get_max_sum(n//2) + _get_max_sum(n//3) + _get_max_sum(n//4) + _get_max_sum(n//5), n)\n return memo[n]\n\n return _get_max_sum(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n \"\"\"\n Find the maximum sum possible using the equation f(n) = max( (f(n/2) + f(n/3) + f(n/4) + f(n/5)), n).\n\n Args:\n n: The input integer.\n\n Returns:\n The maximum sum obtainable using the given equation.\n \"\"\"\n\n memo = {} \n\n def _get_max_sum(n):\n if n in memo:\n return memo[n]\n if n <= 1:\n return n \n memo[n] = max(_get_max_sum(n//2) + _get_max_sum(n//3) + _get_max_sum(n//4) + _get_max_sum(n//5), n)\n return memo[n]\n\n return _get_max_sum(n)", "matching_cluster_idx": 12}]}, "Mbpp/395": {"dps": 98.08429118773947, "dps_norm": 75.0, "pass@1": 100.0, "profiled": [{"solution": "def first_non_repeating_character(s):\n \"\"\"\n Finds the first non-repeating character in a given string.\n\n Args:\n s: The input string.\n\n Returns:\n The first non-repeating character, or None if there are no non-repeating characters.\n \"\"\"\n char_counts = {}\n for char in s:\n if char in char_counts:\n char_counts[char] += 1\n else:\n char_counts[char] = 1\n\n for char in s:\n if char_counts[char] == 1:\n return char\n\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n \"\"\"\n Finds the first non-repeating character in a given string.\n\n Args:\n s: The input string.\n\n Returns:\n The first non-repeating character, or None if none exists.\n \"\"\"\n char_counts = {}\n for char in s:\n if char in char_counts:\n char_counts[char] += 1\n else:\n char_counts[char] = 1\n for char in s:\n if char_counts[char] == 1:\n return char\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(string):\n \"\"\"\n Finds the first non-repeated character in a given string.\n\n Args:\n string: The input string to search.\n\n Returns:\n The first non-repeated character, or None if no such character exists.\n \"\"\"\n char_counts = {}\n for char in string:\n if char in char_counts:\n char_counts[char] += 1\n else:\n char_counts[char] = 1\n\n for char in string:\n if char_counts[char] == 1:\n return char\n\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n \"\"\"\n Finds the first non-repeating character in a string.\n\n Args:\n s: The input string.\n\n Returns:\n The first non-repeating character, or None if there are no non-repeating characters.\n \"\"\"\n char_counts = {} \n for char in s:\n if char in char_counts:\n char_counts[char] += 1\n else:\n char_counts[char] = 1\n \n for char in s:\n if char_counts[char] == 1:\n return char\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n \"\"\"\n Finds the first non-repeating character in a given string.\n\n Args:\n s: The input string.\n\n Returns:\n The first non-repeating character in the string, or None if there is none.\n \"\"\"\n char_counts = {}\n for char in s:\n if char in char_counts:\n char_counts[char] += 1\n else:\n char_counts[char] = 1\n for char in s:\n if char_counts[char] == 1:\n return char\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s: str) -> str:\n \"\"\"\n Finds the first non-repeated character in a given string.\n\n Args:\n s: The input string.\n\n Returns:\n The first non-repeated character in the string, or None if there are no non-repeated characters.\n \"\"\"\n char_counts = {}\n for char in s:\n if char in char_counts:\n char_counts[char] += 1\n else:\n char_counts[char] = 1\n\n for char in s:\n if char_counts[char] == 1:\n return char\n\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(string):\n \"\"\"\n Finds the first non-repeated character in a given string.\n\n Args:\n string: The input string.\n\n Returns:\n The first non-repeated character, or None if there are no non-repeated characters.\n \"\"\"\n char_counts = {}\n for char in string:\n if char in char_counts:\n char_counts[char] += 1\n else:\n char_counts[char] = 1\n\n for char in string:\n if char_counts[char] == 1:\n return char\n\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n \"\"\"\n Finds the first non-repeating character in a given string.\n\n Args:\n s: The input string.\n\n Returns:\n The first non-repeating character, or None if none exists.\n \"\"\"\n char_counts = {}\n for char in s:\n if char in char_counts:\n char_counts[char] += 1\n else:\n char_counts[char] = 1\n\n for char in s:\n if char_counts[char] == 1:\n return char\n\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(text):\n \"\"\"\n Finds the first non-repeating character in a given string.\n\n Args:\n text: The input string.\n\n Returns:\n The first non-repeating character, or None if there is none.\n \"\"\"\n char_counts = {}\n for char in text:\n if char in char_counts:\n char_counts[char] += 1\n else:\n char_counts[char] = 1\n\n for char in text:\n if char_counts[char] == 1:\n return char\n\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(text):\n \"\"\"\n Finds the first non-repeated character in a given string.\n\n Args:\n text: The string to search.\n\n Returns:\n The first non-repeated character, or None if no such character exists.\n \"\"\"\n char_counts = {}\n for char in text:\n if char in char_counts:\n char_counts[char] += 1\n else:\n char_counts[char] = 1\n\n for char in text:\n if char_counts[char] == 1:\n return char\n\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(string):\n \"\"\"\n Finds the first non-repeating character in a given string.\n \n Args:\n string: The string to search.\n\n Returns:\n The first non-repeating character, or None if there are no non-repeating characters.\n \"\"\"\n char_counts = {}\n for char in string:\n if char in char_counts:\n char_counts[char] += 1\n else:\n char_counts[char] = 1\n \n for char in string:\n if char_counts[char] == 1:\n return char\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(string):\n \"\"\"\n Finds the first non-repeated character in a given string.\n\n Args:\n string: The input string.\n\n Returns:\n The first non-repeating character, or None if there are no non-repeating characters.\n \"\"\"\n char_counts = {}\n for char in string:\n if char in char_counts:\n char_counts[char] += 1\n else:\n char_counts[char] = 1\n for char in string:\n if char_counts[char] == 1:\n return char\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(string):\n \"\"\"\n Finds the first non-repeated character in a given string.\n\n Args:\n string: The input string.\n\n Returns:\n The first non-repeating character, or None if all characters repeat.\n \"\"\"\n char_counts = {}\n for char in string:\n if char in char_counts:\n char_counts[char] += 1\n else:\n char_counts[char] = 1\n\n for char in string:\n if char_counts[char] == 1:\n return char\n\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(string):\n \"\"\"\n Finds the first non-repeated character in a given string.\n Args:\n string: The string to search.\n Returns:\n The first non-repeated character, or None if there are none.\n \"\"\"\n char_counts = {}\n for char in string:\n if char in char_counts:\n char_counts[char] += 1\n else:\n char_counts[char] = 1\n \n for char in string:\n if char_counts[char] == 1:\n return char\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n \"\"\"\n Finds the first non-repeating character in a given string.\n\n Args:\n s: The input string.\n\n Returns:\n The first non-repeating character, or None if there are none.\n \"\"\"\n char_counts = {}\n for char in s:\n if char in char_counts:\n char_counts[char] += 1\n else:\n char_counts[char] = 1\n\n for char in s:\n if char_counts[char] == 1:\n return char\n\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(string):\n \"\"\"\n Finds the first non-repeating character in a given string.\n\n Args:\n string: The input string.\n\n Returns:\n The first non-repeating character, or None if there are none.\n \"\"\"\n char_counts = {}\n for char in string:\n if char in char_counts:\n char_counts[char] += 1\n else:\n char_counts[char] = 1\n for char in string:\n if char_counts[char] == 1:\n return char\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(string):\n \"\"\"\n Finds the first non-repeating character in a given string.\n\n Args:\n string: The input string to search.\n\n Returns:\n The first non-repeating character, or None if no such character exists.\n \"\"\"\n char_counts = {}\n for char in string:\n if char in char_counts:\n char_counts[char] += 1\n else:\n char_counts[char] = 1\n for char in string:\n if char_counts[char] == 1:\n return char\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(string):\n \"\"\"\n Finds the first non-repeating character in a given string.\n Args:\n string: The string to search.\n Returns:\n The first non-repeating character, or None if there is none.\n \"\"\"\n char_counts = {}\n for char in string:\n if char in char_counts:\n char_counts[char] += 1\n else:\n char_counts[char] = 1\n\n for char in string:\n if char_counts[char] == 1:\n return char\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(string):\n \"\"\"\n Finds the first non-repeated character in a given string.\n Args:\n string: The input string.\n Returns:\n The first non-repeated character, or None if there is no such character.\n \"\"\"\n char_counts = {}\n for char in string:\n if char in char_counts:\n char_counts[char] += 1\n else:\n char_counts[char] = 1\n\n for char in string:\n if char_counts[char] == 1:\n return char\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(text):\n \"\"\"\n Finds the first non-repeating character in a given string.\n\n Args:\n text: The input string.\n\n Returns:\n The first non-repeating character or None if no such character exists.\n \"\"\"\n char_counts = {}\n for char in text:\n if char in char_counts:\n char_counts[char] += 1\n else:\n char_counts[char] = 1\n\n for char in text:\n if char_counts[char] == 1:\n return char\n\n return None", "matching_cluster_idx": 5}]}, "Mbpp/405": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 21.0, "profiled": [{"solution": "def check_tuplex(my_tuple, element):\n \"\"\"Checks if an element exists within a tuple.\n\n Args:\n my_tuple: The tuple to search within.\n element: The element to search for.\n\n Returns:\n True if the element exists in the tuple, False otherwise.\n \"\"\"\n return element in my_tuple", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, element):\n \"\"\"\n Checks if an element exists within a tuple.\n\n Args:\n tuplex: The tuple to search within.\n element: The element to search for.\n\n Returns:\n True if the element is found in the tuple, False otherwise.\n \"\"\"\n return element in tuplex", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(t, x):\n \"\"\"\n Check if an element exists within a tuple.\n\n Args:\n t: The tuple to search.\n x: The element to search for.\n\n Returns:\n True if the element exists in the tuple, False otherwise.\n \"\"\"\n return x in t", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tp, el):\n \"\"\"\n Checks whether an element exists within a tuple.\n\n Args:\n tp: The tuple to search.\n el: The element to search for.\n\n Returns:\n True if the element exists in the tuple, False otherwise.\n \"\"\"\n return el in tp", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(input_tuple, element):\n \"\"\"\n This function checks whether an element exists within a tuple.\n Args:\n input_tuple: The tuple to search within.\n element: The element to search for.\n Returns:\n True if the element exists in the tuple, False otherwise.\n \"\"\"\n return element in input_tuple", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, element):\n \"\"\"Checks if an element exists within a tuple.\n\n Args:\n tuplex: The tuple to search within.\n element: The element to search for.\n\n Returns:\n True if the element is found in the tuple, False otherwise.\n \"\"\"\n return element in tuplex", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(my_tuple, element):\n \"\"\"Checks if an element exists within a tuple.\n\n Args:\n my_tuple: The tuple to search within.\n element: The element to search for.\n\n Returns:\n True if the element is found in the tuple, False otherwise.\n \"\"\"\n return element in my_tuple", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(my_tuple, target):\n \"\"\"\n Checks if an element exists within a tuple.\n\n Args:\n my_tuple: The tuple to search.\n target: The element to search for.\n\n Returns:\n True if the target element exists in the tuple, False otherwise.\n \"\"\"\n return target in my_tuple", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(t, e):\n \"\"\"\n Checks whether an element exists within a tuple.\n \n Args:\n t: The tuple to search within.\n e: The element to search for.\n \n Returns:\n True if the element exists in the tuple, False otherwise.\n \"\"\"\n return e in t", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(my_tuple, element):\n \"\"\"\n Checks if an element exists within a tuple.\n\n Args:\n my_tuple: The tuple to search.\n element: The element to search for.\n\n Returns:\n True if the element is found in the tuple, False otherwise.\n \"\"\"\n return element in my_tuple", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(my_tuple, target):\n \"\"\"Checks if a target element exists in a tuple.\n\n Args:\n my_tuple: The tuple to search within.\n target: The element to search for.\n\n Returns:\n True if the target is found in the tuple, False otherwise.\n \"\"\"\n return target in my_tuple\nmy_tuple = (\"w\", 3, \"r\", \"e\", \"s\", \"o\", \"u\", \"r\", \"c\", \"e\")\ntarget = 'r'", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(my_tuple, target):\n \"\"\"\n Checks if a target element exists within a tuple.\n\n Args:\n my_tuple: The tuple to search within.\n target: The element to search for.\n\n Returns:\n True if the target element is found in the tuple, False otherwise.\n \"\"\"\n return target in my_tuple", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuple_data, element):\n \"\"\"\n Checks if an element exists within a tuple.\n\n Args:\n tuple_data: The tuple to search within.\n element: The element to search for.\n\n Returns:\n True if the element exists in the tuple, False otherwise.\n \"\"\"\n return element in tuple_data\ntuple_data = (\"w\", 3, \"r\", \"e\", \"s\", \"o\", \"u\", \"r\", \"c\", \"e\")\nelement = 'r'", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(my_tuple, target):\n \"\"\"\n Checks if a target element exists in a tuple.\n\n Args:\n my_tuple: The tuple to search within.\n target: The element to search for.\n\n Returns:\n True if the target element exists in the tuple, False otherwise.\n \"\"\"\n return target in my_tuple", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, element):\n \"\"\"\n Checks whether an element exists within a tuple.\n\n Args:\n tuplex: The tuple to search in.\n element: The element to search for.\n\n Returns:\n True if the element exists in the tuple, False otherwise.\n \"\"\"\n return element in tuplex", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(my_tuple, target):\n \"\"\"\n Checks if an element exists within a tuple.\n\n Args:\n my_tuple: The tuple to search in.\n target: The element to search for.\n\n Returns:\n True if the element is found, False otherwise.\n \"\"\"\n return target in my_tuple", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(input_tuple, element):\n \"\"\"\n Checks whether an element exists within a tuple.\n\n Args:\n input_tuple: The tuple to search within.\n element: The element to search for.\n\n Returns:\n True if the element is found in the tuple, False otherwise.\n \"\"\"\n return element in input_tuple", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, element):\n \"\"\"\n Checks if an element exists within a tuple.\n \n Args:\n tuplex: The tuple to search within.\n element: The element to search for.\n\n Returns:\n True if the element is present in the tuple, False otherwise.\n \"\"\"\n return element in tuplex", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(my_tuple, element):\n \"\"\"Checks if an element exists within a tuple.\n\n Args:\n my_tuple (tuple): The tuple to search within.\n element: The element to search for.\n\n Returns:\n bool: True if the element is found in the tuple, False otherwise.\n \"\"\"\n return element in my_tuple", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(t, element):\n \"\"\"\n Checks if an element exists within a tuple.\n\n Args:\n t: The tuple to search in.\n element: The element to search for.\n\n Returns:\n True if the element exists in the tuple, False otherwise.\n \"\"\"\n return element in t", "matching_cluster_idx": 3}]}, "Mbpp/414": {"dps": 91.30434782608695, "dps_norm": 88.88888888888889, "pass@1": 100.0, "profiled": [{"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Checks whether any value in sequence1 exists in sequence2.\n\n Args:\n seq1: The first sequence.\n seq2: The second sequence.\n\n Returns:\n True if any value in seq1 exists in seq2, False otherwise.\n \"\"\"\n for element in seq1:\n if element in seq2:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Checks whether any value in one sequence exists in another.\n\n Args:\n seq1: The first sequence.\n seq2: The second sequence.\n\n Returns:\n True if there is overlap, False otherwise.\n \"\"\"\n for element in seq1:\n if element in seq2:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Checks whether any value in one sequence exists in another sequence.\n\n Args:\n seq1: The first sequence.\n seq2: The second sequence.\n\n Returns:\n True if any element in seq1 is present in seq2, False otherwise.\n \"\"\"\n for item in seq1:\n if item in seq2:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Checks if any value in the first sequence exists in the second sequence.\n\n Args:\n seq1: The first sequence.\n seq2: The second sequence.\n\n Returns:\n True if any value in seq1 exists in seq2, False otherwise.\n \"\"\"\n for item in seq1:\n if item in seq2:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Checks whether any value in seq1 exists in seq2.\n\n Args:\n seq1: The first sequence.\n seq2: The second sequence.\n\n Returns:\n True if any value in seq1 exists in seq2, False otherwise.\n \"\"\"\n for value in seq1:\n if value in seq2:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Checks if any value in seq1 exists in seq2.\n\n Args:\n seq1: The first sequence.\n seq2: The second sequence.\n\n Returns:\n True if any value in seq1 exists in seq2, False otherwise.\n \"\"\"\n for element in seq1:\n if element in seq2:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Checks if any value in sequence1 exists in sequence2.\n\n Args:\n seq1: The first sequence.\n seq2: The second sequence.\n\n Returns:\n True if any element in seq1 is present in seq2, False otherwise.\n \"\"\"\n for element in seq1:\n if element in seq2:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Checks whether any value in a sequence exists in another sequence.\n\n Args:\n seq1: The first sequence.\n seq2: The second sequence.\n\n Returns:\n True if any value in seq1 exists in seq2, False otherwise.\n \"\"\"\n for item in seq1:\n if item in seq2:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Check whether any value in a sequence exists in another sequence.\n\n Args:\n seq1: The first sequence.\n seq2: The second sequence.\n\n Returns:\n True if any value in seq1 exists in seq2, False otherwise.\n \"\"\"\n for item in seq1:\n if item in seq2:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Checks if any value in the first sequence exists in the second sequence.\n\n Args:\n seq1: The first sequence.\n seq2: The second sequence.\n\n Returns:\n True if any value in seq1 is present in seq2, False otherwise.\n \"\"\"\n for item in seq1:\n if item in seq2:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n This function checks if any value in sequence1 exists in sequence2.\n \n Args:\n seq1: The first sequence.\n seq2: The second sequence.\n \n Returns:\n True if any value in seq1 is present in seq2, False otherwise.\n \"\"\"\n for element in seq1:\n if element in seq2:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Checks whether any value in a sequence exists in another sequence.\n\n Args:\n seq1: The first sequence.\n seq2: The second sequence.\n\n Returns:\n True if any value in seq1 exists in seq2, False otherwise.\n \"\"\"\n for element in seq1:\n if element in seq2:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Checks whether any value in the first sequence exists in the second sequence.\n\n Args:\n seq1: The first sequence.\n seq2: The second sequence.\n\n Returns:\n True if there is overlap between the sequences, False otherwise.\n \"\"\"\n for item in seq1:\n if item in seq2:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(sequence1, sequence2):\n \"\"\"\n Checks whether any value in one sequence exists in another sequence.\n\n Args:\n sequence1: The first sequence.\n sequence2: The second sequence.\n\n Returns:\n True if any value in sequence1 exists in sequence2, False otherwise.\n \"\"\"\n for value in sequence1:\n if value in sequence2:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Checks if any value in the first sequence exists in the second sequence.\n\n Args:\n seq1: The first sequence.\n seq2: The second sequence.\n\n Returns:\n True if any value in seq1 exists in seq2, False otherwise.\n \"\"\"\n for item in seq1:\n if item in seq2:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Checks whether any value in the first sequence exists in the second sequence.\n\n Args:\n seq1: The first sequence.\n seq2: The second sequence.\n\n Returns:\n True if any value in seq1 exists in seq2, False otherwise.\n \"\"\"\n for value in seq1:\n if value in seq2:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Checks if any value in sequence1 exists in sequence2.\n\n Args:\n seq1: The first sequence.\n seq2: The second sequence.\n\n Returns:\n True if any value in seq1 is present in seq2, False otherwise.\n \"\"\"\n for item in seq1:\n if item in seq2:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Checks whether any value in the first sequence exists in the second sequence.\n\n Args:\n seq1: The first sequence.\n seq2: The second sequence.\n\n Returns:\n True if any value in seq1 exists in seq2, False otherwise.\n \"\"\"\n for item in seq1:\n if item in seq2:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Checks if any value in sequence1 exists in sequence2.\n\n Args:\n seq1: The first sequence.\n seq2: The second sequence.\n\n Returns:\n True if there's an overlap, False otherwise.\n \"\"\"\n for element in seq1:\n if element in seq2:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Checks if any value in one sequence exists in another sequence.\n\n Args:\n seq1: The first sequence.\n seq2: The second sequence.\n\n Returns:\n True if any value in seq1 is present in seq2, False otherwise.\n \"\"\"\n for item in seq1:\n if item in seq2:\n return True\n return False", "matching_cluster_idx": 7}]}, "Mbpp/421": {"dps": 15.226337448559672, "dps_norm": 71.42857142857143, "pass@1": 100.0, "profiled": [{"solution": "def concatenate_tuple(tup, delimiter=\"-\"):\n \"\"\"\n Concatenates each element of a tuple by the given delimiter.\n\n Args:\n tup: The input tuple.\n delimiter: The string to use as a separator between elements. Defaults to \"-\".\n\n Returns:\n A string containing all elements of the tuple concatenated by the delimiter.\n \"\"\"\n return delimiter.join(str(element) for element in tup)", "matching_cluster_idx": 4}, {"solution": "def concatenate_tuple(input_tuple, delimiter=\"-\"):\n \"\"\"\n Concatenates each element of a tuple using a specified delimiter.\n\n Args:\n input_tuple: The tuple to concatenate.\n delimiter: The string to use as a separator between elements. Defaults to \"-\".\n\n Returns:\n A string containing all elements of the tuple joined by the delimiter.\n \"\"\"\n return delimiter.join(str(element) for element in input_tuple)", "matching_cluster_idx": 4}, {"solution": "def concatenate_tuple(input_tuple, delimiter=\"-\"):\n \"\"\"\n Concatenates each element of a tuple by the delimiter.\n\n Args:\n input_tuple: A tuple of strings and/or numbers.\n delimiter: The string to use as a separator between elements.\n\n Returns:\n A string with all tuple elements joined by the delimiter.\n \"\"\"\n return delimiter.join(str(element) for element in input_tuple)", "matching_cluster_idx": 4}, {"solution": "def concatenate_tuple(input_tuple, delimiter=\"-\"):\n \"\"\"\n Concatenates each element of a tuple using a specified delimiter.\n\n Args:\n input_tuple: A tuple of elements to concatenate.\n delimiter: The string to use as a separator between elements. Defaults to \"-\".\n\n Returns:\n A string containing all elements of the tuple joined by the delimiter.\n \"\"\"\n return delimiter.join(str(element) for element in input_tuple)", "matching_cluster_idx": 4}, {"solution": "def concatenate_tuple(input_tuple, delimiter=\"-\"):\n \"\"\"Concatenates each element of a tuple by the given delimiter.\n\n Args:\n input_tuple: A tuple of strings and/or numbers.\n delimiter: The string to use as a separator.\n\n Returns:\n A string with all tuple elements concatenated by the delimiter.\n \"\"\"\n\n return delimiter.join(str(element) for element in input_tuple)", "matching_cluster_idx": 4}, {"solution": "def concatenate_tuple(tup, delimiter=\"-\"):\n \"\"\"\n Concatenates each element of a tuple by the delimiter.\n\n Args:\n tup: A tuple of elements to concatenate.\n delimiter: The string to use as a delimiter between elements.\n\n Returns:\n A string containing the concatenated elements.\n \"\"\"\n return delimiter.join(str(x) for x in tup)", "matching_cluster_idx": 4}, {"solution": "def concatenate_tuple(tuple_data, delimiter=\"-\"):\n \"\"\"\n Concatenates each element of a tuple by the specified delimiter.\n\n Args:\n tuple_data: A tuple of elements to concatenate.\n delimiter: The string to use as a delimiter between elements.\n\n Returns:\n A string containing all elements of the tuple concatenated by the delimiter.\n \"\"\"\n return delimiter.join(str(element) for element in tuple_data)", "matching_cluster_idx": 4}, {"solution": "def concatenate_tuple(input_tuple, delimiter=\"-\"):\n \"\"\"\n Concatenates each element of a tuple by the delimiter.\n\n Args:\n input_tuple: The tuple to concatenate.\n delimiter: The string to use as a delimiter between elements. \n\n Returns:\n A string with all elements of the tuple concatenated by the delimiter.\n \"\"\"\n return delimiter.join(str(element) for element in input_tuple)", "matching_cluster_idx": 4}, {"solution": "def concatenate_tuple(input_tuple, delimiter=\"-\"):\n \"\"\"Concatenates each element of a tuple using a delimiter.\n\n Args:\n input_tuple: A tuple containing various elements.\n delimiter: The string to use as a separator between elements. Defaults to \"-\".\n\n Returns:\n A string containing the concatenated elements.\n \"\"\"\n return delimiter.join(str(element) for element in input_tuple)", "matching_cluster_idx": 4}, {"solution": "def concatenate_tuple(input_tuple, delimiter=\"-\"):\n \"\"\"\n Concatenates each element of a tuple using a delimiter.\n\n Args:\n input_tuple: The tuple to concatenate.\n delimiter: The string to use as a separator between elements. Defaults to \"-\".\n\n Returns:\n A string containing all elements of the tuple concatenated with the delimiter.\n \"\"\"\n return delimiter.join(str(element) for element in input_tuple)", "matching_cluster_idx": 4}, {"solution": "def concatenate_tuple(input_tuple, delimiter=\"-\"):\n \"\"\"\n Concatenates each element of a tuple by a given delimiter.\n\n Args:\n input_tuple: The tuple to be concatenated.\n delimiter: The string to use as a separator between elements.\n\n Returns:\n A string containing the concatenated tuple elements.\n \"\"\"\n return delimiter.join(str(element) for element in input_tuple)", "matching_cluster_idx": 4}, {"solution": "def concatenate_tuple(t, delimiter=\"-\"):\n \"\"\"\n Concatenates each element of a tuple using a delimiter.\n\n Args:\n t: The tuple to concatenate.\n delimiter: The delimiter to use between elements.\n\n Returns:\n A string containing the concatenated elements.\n \"\"\"\n return delimiter.join(str(x) for x in t)", "matching_cluster_idx": 4}, {"solution": "def concatenate_tuple(tuple_data, delimiter=\"-\"):\n \"\"\"\n Concatenates each element of a tuple by a given delimiter.\n\n Args:\n tuple_data: A tuple of elements to concatenate.\n delimiter: The string to use as a separator between elements.\n\n Returns:\n A string with all elements of the tuple concatenated by the delimiter.\n \"\"\"\n return delimiter.join(str(x) for x in tuple_data)", "matching_cluster_idx": 4}, {"solution": "def concatenate_tuple(input_tuple, delimiter=\"-\"):\n \"\"\"\n Concatenates each element of a tuple by a specified delimiter.\n\n Args:\n input_tuple: The tuple to concatenate.\n delimiter: The string to use as a separator between elements. Defaults to \"-\".\n\n Returns:\n A string containing the concatenated tuple elements.\n \"\"\"\n return delimiter.join(str(element) for element in input_tuple)", "matching_cluster_idx": 4}, {"solution": "def concatenate_tuple(t, delimiter=\"-\"):\n \"\"\"\n Concatenates each element of a tuple by the delimiter.\n\n Args:\n t: The input tuple.\n delimiter: The delimiter to use. Defaults to '-'.\n\n Returns:\n A string containing the concatenated elements.\n \"\"\"\n return delimiter.join(str(x) for x in t)", "matching_cluster_idx": 4}, {"solution": "def concatenate_tuple(my_tuple, delimiter=\"-\"):\n \"\"\"\n Concatenates each element of a tuple by the delimiter.\n\n Args:\n my_tuple: The tuple to concatenate.\n delimiter: The string to use as a delimiter.\n\n Returns:\n A string containing the concatenated elements.\n \"\"\"\n return delimiter.join(str(element) for element in my_tuple)", "matching_cluster_idx": 4}, {"solution": "def concatenate_tuple(input_tuple, delimiter=\"-\"):\n \"\"\"\n Concatenates each element of a tuple by a specified delimiter.\n\n Args:\n input_tuple: The tuple to concatenate.\n delimiter: The string to use as a separator between elements.\n\n Returns:\n A string with all elements concatenated by the delimiter.\n \"\"\"\n return delimiter.join(str(element) for element in input_tuple)", "matching_cluster_idx": 4}, {"solution": "def concatenate_tuple(input_tuple, delimiter=\"-\"):\n \"\"\"\n Concatenates each element of a tuple using the provided delimiter.\n\n Args:\n input_tuple: The tuple to concatenate.\n delimiter: The delimiter to use. Defaults to \"-\".\n\n Returns:\n A string with all elements concatenated by the delimiter.\n \"\"\"\n return delimiter.join(str(element) for element in input_tuple)", "matching_cluster_idx": 4}, {"solution": "def concatenate_tuple(input_tuple, delimiter=\"-\"):\n \"\"\"\n Concatenates each element of a tuple by the given delimiter.\n\n Args:\n input_tuple: A tuple of elements to concatenate.\n delimiter: The string used to separate elements.\n\n Returns:\n A string containing the concatenated elements.\n \"\"\"\n return delimiter.join(str(element) for element in input_tuple)", "matching_cluster_idx": 4}, {"solution": "def concatenate_tuple(input_tuple, delimiter=\"-\"):\n \"\"\"Concatenates each element of a tuple by the given delimiter.\n\n Args:\n input_tuple: The tuple to concatenate.\n delimiter: The delimiter to use between elements. Defaults to \"-\".\n\n Returns:\n A string with all tuple elements concatenated by the delimiter.\n \"\"\"\n return delimiter.join(str(x) for x in input_tuple)", "matching_cluster_idx": 4}]}, "Mbpp/424": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def extract_rear(input_tuple):\n \"\"\"\n Extract only the rear index element of each string in the given tuple.\n\n Args:\n input_tuple: A tuple of strings.\n\n Returns:\n A list containing the rear index element of each string in the input tuple.\n \"\"\"\n return [s[-1] for s in input_tuple]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(text_tuple):\n \"\"\"\n Extracts the rear index element of each string in the given tuple.\n\n Args:\n text_tuple: A tuple of strings.\n\n Returns:\n A list containing the rear index element of each string in the tuple.\n \"\"\"\n return [s[-1] for s in text_tuple]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(strings):\n \"\"\"\n Extracts only the rear index element of each string in the given tuple.\n\n Args:\n strings: A tuple of strings.\n\n Returns:\n A list of the rear index elements of each string.\n \"\"\"\n return [s[-1] for s in strings]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(strings):\n \"\"\"\n Extracts the rear index element of each string in the given tuple.\n\n Args:\n strings: A tuple of strings.\n\n Returns:\n A list of rear index elements.\n \"\"\"\n return [string[-1] for string in strings]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(str_tuple):\n \"\"\"\n Extracts the rear index element of each string in the given tuple.\n\n Args:\n str_tuple: A tuple of strings.\n\n Returns:\n A list containing the rear index element of each string in the tuple.\n \"\"\"\n return [s[-1] for s in str_tuple]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(input_tuple):\n \"\"\"\n Extracts the rear index element of each string in the given tuple.\n\n Args:\n input_tuple: A tuple of strings.\n\n Returns:\n A list containing the rear index elements of each string in the tuple.\n \"\"\"\n return [s[-1] for s in input_tuple]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(input_tuple):\n \"\"\"\n Extracts the rear index element of each string in the given tuple.\n\n Args:\n input_tuple: A tuple of strings.\n\n Returns:\n A list containing the rear index element of each string in the input tuple.\n \"\"\"\n return [string[-1] for string in input_tuple]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(tuple_of_strings):\n \"\"\"\n Extracts only the rear index element of each string in the given tuple.\n\n Args:\n tuple_of_strings: A tuple of strings.\n\n Returns:\n A list of the rear index elements of each string in the tuple.\n \"\"\"\n return [string[-1] for string in tuple_of_strings]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(input_tuple):\n \"\"\"\n Extracts only the rear index element of each string in the given tuple.\n\n Args:\n input_tuple: A tuple of strings.\n\n Returns:\n A list containing the rear index element of each string in the input tuple.\n \"\"\"\n return [s[-1] for s in input_tuple]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(string_tuple):\n \"\"\"\n Extracts only the rear index element of each string in the given tuple.\n\n Args:\n string_tuple: A tuple of strings.\n\n Returns:\n A list containing the rear index elements of each string in the tuple.\n \"\"\"\n return [s[-1] for s in string_tuple]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(strings):\n \"\"\"\n Extracts the rear index element of each string in a tuple.\n\n Args:\n strings: A tuple of strings.\n\n Returns:\n A list containing the rear index element of each string in the input tuple.\n \"\"\"\n return [string[-1] for string in strings]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(string_tuple):\n \"\"\"\n Extracts the rear index element of each string in a given tuple.\n\n Args:\n string_tuple: A tuple of strings.\n\n Returns:\n A list containing the rear index element of each string in the tuple.\n \"\"\"\n return [string[-1] for string in string_tuple]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(string_tuple):\n \"\"\"\n Extracts only the rear index element of each string in the given tuple.\n\n Args:\n string_tuple: A tuple of strings.\n\n Returns:\n A list containing the rear index element of each string in the input tuple.\n \"\"\"\n return [s[-1] for s in string_tuple]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(tuple_of_strings):\n \"\"\"\n Extract only the rear index element of each string in the given tuple.\n\n Args:\n tuple_of_strings: A tuple of strings.\n\n Returns:\n A list containing the rear index element of each string in the tuple.\n \"\"\"\n return [string[-1] for string in tuple_of_strings]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(strings):\n \"\"\"\n Extracts only the rear index element of each string in the given tuple.\n\n Args:\n strings: A tuple of strings.\n\n Returns:\n A list containing the rear index element of each string in the tuple.\n \"\"\"\n return [string[-1] for string in strings]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(strings):\n \"\"\"\n Extracts the rear index element of each string in the given tuple.\n\n Args:\n strings: A tuple of strings.\n\n Returns:\n A list containing the rear index element of each string in the tuple.\n \"\"\"\n return [string[-1] for string in strings]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(strings):\n \"\"\"\n Extracts the rear index element of each string in the given tuple.\n\n Args:\n strings: A tuple of strings.\n\n Returns:\n A list containing the rear index element of each string in the input tuple.\n \"\"\"\n return [string[-1] for string in strings]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(text_tuple):\n \"\"\"\n Extracts only the rear index element of each string in the given tuple.\n\n Args:\n text_tuple: A tuple of strings.\n\n Returns:\n A list of rear index elements from the input tuple.\n \"\"\"\n return [text[-1] for text in text_tuple]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(tuple_of_strings):\n \"\"\"\n Extracts the rear index element of each string in the given tuple.\n \n Args:\n tuple_of_strings: A tuple of strings.\n\n Returns:\n A list of rear index elements from each string in the input tuple.\n \n assert extract_rear(('Mers', 'for', 'Vers') ) == ['s', 'r', 's']\n \"\"\"\n return [s[-1] for s in tuple_of_strings]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(string_tuple):\n \"\"\"\n Extracts the rear index element of each string in the given tuple.\n\n Args:\n string_tuple: A tuple of strings.\n\n Returns:\n A list of rear index elements.\n \"\"\"\n return [string[-1] for string in string_tuple]", "matching_cluster_idx": 4}]}, "Mbpp/425": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def count_element_in_list(lst, element):\n \"\"\"\n Counts the number of sublists in a list of lists that contain a particular element.\n\n Args:\n lst: A list of lists.\n element: The element to count.\n\n Returns:\n The number of sublists containing the element.\n \"\"\"\n count = 0\n for sublist in lst:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, element):\n \"\"\"Counts the number of sublists containing a particular element.\n\n Args:\n lst: A list of lists.\n element: The element to count.\n\n Returns:\n The number of sublists containing the element.\n \"\"\"\n count = 0\n for sublist in lst:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(data, element):\n \"\"\"\n Counts the number of sublists containing a particular element.\n\n Args:\n data: A list of lists.\n element: The element to count.\n\n Returns:\n The number of sublists containing the element.\n \"\"\"\n count = 0\n for sublist in data:\n if element in sublist:\n count += 1\n return count\ndata = [[1, 3], [5, 7], [1, 11], [1, 15, 7]]\nelement = 1", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(matrix, element):\n \"\"\"\n Counts the number of sublists containing a particular element.\n\n Args:\n matrix: A list of lists.\n element: The element to search for.\n\n Returns:\n The number of sublists containing the element.\n \"\"\"\n count = 0\n for sublist in matrix:\n if element in sublist:\n count += 1\n return count\nmatrix = [[1, 3], [5, 7], [1, 11], [1, 15, 7]]", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(nested_list, element):\n \"\"\"\n Counts the number of sublists containing a particular element.\n\n Args:\n nested_list: A list of lists.\n element: The element to count.\n\n Returns:\n The number of sublists containing the element.\n \"\"\"\n count = 0\n for sublist in nested_list:\n if element in sublist:\n count += 1\n return count\nnested_list = [[1, 3], [5, 7], [1, 11], [1, 15, 7]]\nelement = 1", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(list_of_lists, element):\n \"\"\"\n Counts the number of sublists containing a particular element.\n\n Args:\n list_of_lists: A list of lists.\n element: The element to count.\n\n Returns:\n The number of sublists containing the element.\n \"\"\"\n count = 0\n for sublist in list_of_lists:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(nested_list, element):\n \"\"\"\n Counts the number of sublists containing a particular element.\n\n Args:\n nested_list: A list of lists.\n element: The element to count.\n\n Returns:\n The number of sublists containing the element.\n \"\"\"\n count = 0\n for sublist in nested_list:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(matrix, element):\n \"\"\"\n Counts the number of sublists containing a particular element in a list of lists.\n\n Args:\n matrix: A list of lists.\n element: The element to count.\n\n Returns:\n The number of sublists containing the element.\n \"\"\"\n count = 0\n for sublist in matrix:\n if element in sublist:\n count += 1\n return count\nmatrix = [[1, 3], [5, 7], [1, 11], [1, 15, 7]]\nelement = 1", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(matrix, element):\n \"\"\"\n Counts the number of sublists containing a particular element.\n\n Args:\n matrix (list of lists): A 2D list of integers.\n element (int): The element to count.\n\n Returns:\n int: The number of sublists containing the element.\n \"\"\"\n count = 0\n for sublist in matrix:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(data, target):\n \"\"\"\n Counts the number of sublists containing a particular element.\n\n Args:\n data: A list of lists.\n target: The element to count.\n\n Returns:\n The number of sublists containing the target element.\n \"\"\"\n count = 0\n for sublist in data:\n if target in sublist:\n count += 1\n return count\ndata = [[1, 3], [5, 7], [1, 11], [1, 15, 7]]\ntarget = 1", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(nested_list, element):\n \"\"\"Counts the number of sublists containing a particular element.\n\n Args:\n nested_list: A list of lists.\n element: The element to count.\n\n Returns:\n The number of sublists containing the element.\n \"\"\"\n count = 0\n for sublist in nested_list:\n if element in sublist:\n count += 1\n return count\nnested_list = [[1, 3], [5, 7], [1, 11], [1, 15, 7]]\nelement = 1", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, element):\n \"\"\"\n Counts the number of sublists in a list of lists that contain a particular element.\n\n Args:\n lst: A list of lists.\n element: The element to count.\n\n Returns:\n The number of sublists containing the element.\n \"\"\"\n count = 0\n for sublist in lst:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(list_of_lists, target_element):\n \"\"\"Counts the number of sublists containing a particular element.\n\n Args:\n list_of_lists: A list of lists.\n target_element: The element to search for.\n\n Returns:\n The number of sublists containing the target element.\n \"\"\"\n count = 0\n for sublist in list_of_lists:\n if target_element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(list_of_lists, element):\n \"\"\"\n Counts the number of sublists containing a particular element.\n\n Args:\n list_of_lists: A list of lists.\n element: The element to count.\n\n Returns:\n The number of sublists containing the element.\n \"\"\"\n count = 0\n for sublist in list_of_lists:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(nested_list, element):\n \"\"\"\n Counts the number of sublists containing a particular element.\n\n Args:\n nested_list: A list of lists.\n element: The element to search for.\n\n Returns:\n The number of sublists containing the element.\n \"\"\"\n count = 0\n for sublist in nested_list:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(data, element):\n \"\"\"\n Counts the number of sublists containing a particular element.\n\n Args:\n data: A list of lists.\n element: The element to count.\n\n Returns:\n The number of sublists containing the element.\n \"\"\"\n count = 0\n for sublist in data:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(matrix, element):\n \"\"\"\n Counts the number of sublists containing a particular element.\n\n Args:\n matrix: A list of lists.\n element: The element to count.\n\n Returns:\n The number of sublists containing the element.\n \"\"\"\n count = 0\n for sublist in matrix:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(matrix, element):\n \"\"\"\n Counts the number of sublists containing a particular element.\n\n Args:\n matrix: A list of lists.\n element: The element to search for.\n\n Returns:\n The number of sublists containing the element.\n \"\"\"\n count = 0\n for sublist in matrix:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(matrix, element):\n \"\"\"\n Counts the number of sublists in a matrix that contain a particular element.\n\n Args:\n matrix: A list of lists (2D list).\n element: The element to search for.\n\n Returns:\n The number of sublists containing the element.\n \"\"\"\n count = 0\n for sublist in matrix:\n if element in sublist:\n count += 1\n return count\nmatrix = [[1, 3], [5, 7], [1, 11], [1, 15, 7]]\nelement = 1", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(matrix, element):\n \"\"\"\n Counts the number of sublists containing a particular element in a given matrix.\n\n Args:\n matrix: A list of lists (matrix).\n element: The element to count.\n\n Returns:\n The number of sublists containing the element.\n \"\"\"\n count = 0\n for sublist in matrix:\n if element in sublist:\n count += 1\n return count\nmatrix = [[1, 3], [5, 7], [1, 11], [1, 15, 7]]\nelement = 1", "matching_cluster_idx": 4}]}, "Mbpp/428": {"dps": 25.619834710743802, "dps_norm": 44.44444444444444, "pass@1": 100.0, "profiled": [{"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2\n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n return arr", "matching_cluster_idx": 3}, {"solution": "def shell_sort(arr):\n n = len(arr)\n # Start with a large gap, then reduce the gap\n gap = n // 2\n while gap > 0:\n # Do a gapped insertion sort for this gap size.\n # The first gap elements a[0..gap-1] are already in gapped order\n # keep adding one more element until the entire array is gap sorted\n for i in range(gap, n):\n temp = arr[i]\n j = i\n # shift earlier gap-sorted elements up until the correct location for `temp` is found\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n return arr", "matching_cluster_idx": 3}, {"solution": "def shell_sort(arr):\n \"\"\"\n Sorts the given array using shell sort.\n\n Args:\n arr: A list of integers.\n\n Returns:\n The sorted list of integers.\n \"\"\"\n n = len(arr)\n \n # Start with a large gap, then reduce the gap\n gap = n // 2\n while gap > 0:\n # Do a gapped insertion sort for this gap size.\n # The first gap elements a[0..gap-1] are already in gapped order\n # keep adding one more element until the entire array is gap sorted\n for i in range(gap, n):\n temp = arr[i]\n j = i\n # shift earlier gap-sorted elements up until the correct location for\n # temp is found\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n\n return arr", "matching_cluster_idx": 3}, {"solution": "def shell_sort(arr):\n \"\"\"\n Sorts the given array using the shell sort algorithm.\n\n Args:\n arr: The array to be sorted.\n\n Returns:\n The sorted array.\n \"\"\"\n n = len(arr)\n gap = n // 2\n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n return arr", "matching_cluster_idx": 3}, {"solution": "def shell_sort(arr):\n \"\"\"Sorts the given array using Shell sort.\n\n Args:\n arr: A list of numbers.\n\n Returns:\n The sorted list.\n \"\"\"\n n = len(arr)\n gap = n // 2\n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n return arr", "matching_cluster_idx": 3}, {"solution": "def shell_sort(arr):\n \"\"\"\n Sorts the given array using shell sort algorithm.\n\n Args:\n arr: The array to be sorted.\n\n Returns:\n The sorted array.\n \"\"\"\n n = len(arr)\n gap = n // 2\n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n\n return arr", "matching_cluster_idx": 3}, {"solution": "def shell_sort(arr):\n \"\"\"\n Sorts the given array using Shell Sort.\n\n Args:\n arr: A list of integers.\n\n Returns:\n A new sorted list of integers.\n \"\"\"\n n = len(arr)\n gap = n // 2\n while gap > 0:\n # Perform insertion sort for each gap\n for i in range(gap, n):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n return arr", "matching_cluster_idx": 3}, {"solution": "def shell_sort(array):\n n = len(array)\n gap = n // 2\n while gap > 0:\n for i in range(gap, n):\n temp = array[i]\n j = i\n while j >= gap and array[j - gap] > temp:\n array[j] = array[j - gap]\n j -= gap\n array[j] = temp\n gap //= 2\n return array", "matching_cluster_idx": 3}, {"solution": "def shell_sort(arr):\n \"\"\"Sorts the given array using Shell sort algorithm.\n\n Args:\n arr: The array to be sorted.\n\n Returns:\n The sorted array.\n \"\"\"\n n = len(arr)\n # Start with a large gap, then reduce the gap\n gap = n // 2\n while gap > 0:\n # Do a gapped insertion sort for this gap size.\n # The first gap elements a[0..gap-1] are already in gapped order\n # keep adding one more element until the entire array is gap sorted\n for i in range(gap, n):\n temp = arr[i]\n j = i\n # Shift earlier gap-elements up until the correct location for temp is found\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2 # reduce the gap\n return arr", "matching_cluster_idx": 3}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2\n while gap > 0:\n # Do a gapped insertion sort for this gap size.\n # The first gap elements a[0..gap-1] are already in gapped order \n # keep adding one more element until the entire array is gap sorted\n for i in range(gap, n):\n temp = arr[i]\n j = i\n # Shift earlier gap-sorted elements up until the correct location for `temp` is found\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n # reduce the gap\n gap //= 2\n return arr", "matching_cluster_idx": 3}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2 \n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2 \n return arr", "matching_cluster_idx": 3}, {"solution": "def shell_sort(array):\n n = len(array)\n gap = n // 2\n while gap > 0:\n for i in range(gap, n):\n temp = array[i]\n j = i\n while j >= gap and array[j - gap] > temp:\n array[j] = array[j - gap]\n j -= gap\n array[j] = temp\n gap //= 2\n return array", "matching_cluster_idx": 3}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2\n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n return arr", "matching_cluster_idx": 3}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2\n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n return arr", "matching_cluster_idx": 3}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2\n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n return arr", "matching_cluster_idx": 3}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2\n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n return arr", "matching_cluster_idx": 3}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2\n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n return arr", "matching_cluster_idx": 3}, {"solution": "def shell_sort(arr):\n \"\"\"Sorts an array using Shell sort.\"\"\"\n n = len(arr)\n gap = n // 2\n while gap > 0:\n # Sort subarrays based on the gap\n for i in range(gap, n):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n return arr", "matching_cluster_idx": 3}, {"solution": "def shell_sort(arr):\n \"\"\"\n Sorts the given array using Shell sort.\n \n Args:\n arr: The array to be sorted.\n\n Returns:\n The sorted array.\n \"\"\"\n n = len(arr)\n # Start with a large gap, then reduce the gap\n gap = n // 2\n while gap > 0:\n # Do a gapped insertion sort for this gap size.\n # The first gap elements a[0..gap-1] are already in gapped order\n # keep adding one more element until the entire array is gap sorted\n for i in range(gap, n):\n # add a[i] to the elements that have been gap sorted\n # save a[i] in temp and make a hole at position i\n temp = arr[i]\n # shift earlier gap-sorted elements up until the correct location for a[i] is found\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n\n return arr", "matching_cluster_idx": 3}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2 \n while gap > 0:\n # Do a gapped insertion sort for this gap size.\n # The first gap elements a[0..gap-1] are already in gapped order \n # keep adding one more element until the entire array is gap sorted\n for i in range(gap, n):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n return arr\narr = [12, 23, 4, 5, 3, 2, 12, 81, 56, 95]", "matching_cluster_idx": 3}]}, "Mbpp/433": {"dps": 75.26595744680851, "dps_norm": 83.0, "pass@1": 100.0, "profiled": [{"solution": "def check_greater(arr, num):\n \"\"\"\n Checks if a number is greater than all elements in a given array.\n\n Args:\n arr: A list of numbers.\n num: The number to compare.\n\n Returns:\n True if the number is greater than all elements in the array, False otherwise.\n \"\"\"\n for element in arr:\n if num <= element:\n return False\n return True", "matching_cluster_idx": 3}, {"solution": "def check_greater(arr, num):\n \"\"\"\n Checks if a number is greater than all elements in an array.\n\n Args:\n arr: A list of numbers.\n num: The number to check.\n\n Returns:\n True if the number is greater than all elements in the array, False otherwise.\n \"\"\"\n for element in arr:\n if num <= element:\n return False\n return True", "matching_cluster_idx": 3}, {"solution": "def check_greater(nums, num):\n \"\"\"\n Checks whether the entered number is greater than the elements of the given array.\n\n Args:\n nums: A list of integers.\n num: An integer to compare against.\n\n Returns:\n True if num is greater than all elements in nums, False otherwise.\n \"\"\"\n for element in nums:\n if num <= element:\n return False\n return True", "matching_cluster_idx": 3}, {"solution": "def check_greater(arr, num):\n \"\"\"\n Checks if a number is greater than all elements in an array.\n\n Args:\n arr: A list of numbers.\n num: The number to compare.\n\n Returns:\n True if the number is greater than all elements in the array, False otherwise.\n \"\"\"\n for element in arr:\n if num <= element:\n return False\n return True", "matching_cluster_idx": 3}, {"solution": "def check_greater(arr, num):\n \"\"\"\n Checks whether the entered number is greater than all elements in the given array.\n\n Args:\n arr: A list of numbers.\n num: The number to compare with the elements in the array.\n\n Returns:\n True if the number is greater than all elements in the array, False otherwise.\n \"\"\"\n for element in arr:\n if num <= element:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def check_greater(arr, num):\n \"\"\"\n Checks whether the entered number is greater than the elements of the given array.\n\n Args:\n arr: A list of numbers.\n num: The number to check.\n\n Returns:\n True if the number is greater than all elements in the array, False otherwise.\n \"\"\"\n for element in arr:\n if num <= element:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def check_greater(nums, num):\n \"\"\"\n Checks if a number is greater than all elements in an array.\n\n Args:\n nums: A list of numbers.\n num: The number to compare.\n\n Returns:\n True if the number is greater than all elements in the array, False otherwise.\n \"\"\"\n for n in nums:\n if num <= n:\n return False\n return True", "matching_cluster_idx": 3}, {"solution": "def check_greater(nums, num):\n \"\"\"\n Checks if the entered number is greater than all elements in the given array.\n\n Args:\n nums: A list of numbers.\n num: The number to compare.\n\n Returns:\n True if num is greater than all elements in nums, False otherwise.\n \"\"\"\n return all(num > n for n in nums)", "matching_cluster_idx": 2}, {"solution": "def check_greater(arr, num):\n \"\"\"\n Checks if a number is greater than all elements in an array.\n\n Args:\n arr: A list of numbers.\n num: The number to check.\n\n Returns:\n True if the number is greater than all elements in the array, False otherwise.\n \"\"\"\n for element in arr:\n if num <= element:\n return False\n return True", "matching_cluster_idx": 3}, {"solution": "def check_greater(numbers, target):\n \"\"\"\n Checks whether the entered number is greater than all elements of the given array.\n\n Args:\n numbers: A list of numbers.\n target: The number to check.\n\n Returns:\n True if the target is greater than all elements in the list, False otherwise.\n \"\"\"\n for number in numbers:\n if target <= number:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def check_greater(arr, num):\n \"\"\"\n Checks whether the entered number is greater than the elements of the given array.\n\n Args:\n arr: A list of numbers.\n num: The number to check against the array elements.\n\n Returns:\n True if the number is greater than all elements in the array, False otherwise.\n \"\"\"\n for element in arr:\n if num <= element:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def check_greater(arr, num):\n \"\"\"\n Checks whether the entered number is greater than the elements of the given array.\n\n Args:\n arr: A list of numbers.\n num: The number to check.\n\n Returns:\n True if the number is greater than all elements in the array, False otherwise.\n \"\"\"\n for element in arr:\n if num <= element:\n return False\n return True", "matching_cluster_idx": 3}, {"solution": "def check_greater(arr, num):\n \"\"\"\n Checks whether the entered number is greater than the elements of the given array.\n\n Args:\n arr: A list of numbers.\n num: The number to compare.\n\n Returns:\n True if the number is greater than all elements in the array, False otherwise.\n \"\"\"\n for element in arr:\n if num <= element:\n return False\n return True", "matching_cluster_idx": 3}, {"solution": "def check_greater(array, num):\n \"\"\"\n Checks if a number is greater than all elements in an array.\n\n Args:\n array: A list of numbers.\n num: The number to compare against.\n\n Returns:\n True if the number is greater than all elements in the array, False otherwise.\n \"\"\"\n for element in array:\n if num <= element:\n return False\n return True", "matching_cluster_idx": 3}, {"solution": "def check_greater(nums, target):\n \"\"\"\n Checks if a given number is greater than all elements in an array.\n\n Args:\n nums: A list of numbers.\n target: The number to check against.\n\n Returns:\n True if the target number is greater than all elements in the array, False otherwise.\n \"\"\"\n return all(target > num for num in nums)", "matching_cluster_idx": 2}, {"solution": "def check_greater(arr, num):\n \"\"\"\n Checks whether the entered number is greater than all elements of the given array.\n\n Args:\n arr: A list of numbers.\n num: A number to check.\n\n Returns:\n True if the number is greater than all elements in the array, False otherwise.\n \"\"\"\n return all(num > x for x in arr)", "matching_cluster_idx": 2}, {"solution": "def check_greater(nums, num):\n \"\"\"\n Checks if a number is greater than all elements in a given array.\n\n Args:\n nums: A list of integers.\n num: An integer to compare with the array elements.\n\n Returns:\n True if num is greater than all elements in nums, False otherwise.\n \"\"\"\n for n in nums:\n if num <= n:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def check_greater(arr, num):\n \"\"\"\n Checks whether the entered number is greater than all the elements of the given array.\n\n Args:\n arr: A list of numbers.\n num: The number to check against.\n\n Returns:\n True if the number is greater than all elements in the array, False otherwise.\n \"\"\"\n for element in arr:\n if num <= element:\n return False\n return True", "matching_cluster_idx": 3}, {"solution": "def check_greater(arr, num):\n \"\"\"\n Checks whether the entered number is greater than all elements in the given array.\n\n Args:\n arr: A list of numbers.\n num: The number to check.\n\n Returns:\n True if num is greater than all elements in arr, False otherwise.\n \"\"\"\n for element in arr:\n if num <= element:\n return False\n return True", "matching_cluster_idx": 3}, {"solution": "def check_greater(array, number):\n \"\"\"\n Checks whether the entered number is greater than all elements in the given array.\n\n Args:\n array: A list of numbers.\n number: The number to check against.\n\n Returns:\n True if the number is greater than all elements in the array, False otherwise.\n \"\"\"\n for element in array:\n if number <= element:\n return False\n return True", "matching_cluster_idx": 4}]}, "Mbpp/437": {"dps": 54.411764705882355, "dps_norm": 19.0, "pass@1": 24.0, "profiled": [{"solution": "def remove_odd(text):\n \"\"\"\n Removes odd characters from a string.\n\n Args:\n text: The input string.\n\n Returns:\n The string with odd characters removed.\n \"\"\"\n result = \"\"\n for i in range(len(text)):\n if (i + 1) % 2 == 0:\n result += text[i]\n return result", "matching_cluster_idx": -1}, {"solution": "def remove_odd(text):\n \"\"\"Removes odd characters from a string.\n\n Args:\n text: The input string.\n\n Returns:\n The string with odd characters removed.\n \"\"\"\n return ''.join([char for i, char in enumerate(text) if (i+1) % 2 == 0])", "matching_cluster_idx": 0}, {"solution": "def remove_odd(text):\n \"\"\"\n Removes odd characters from a string.\n\n Args:\n text: The input string.\n\n Returns:\n The string with all odd characters removed.\n \"\"\"\n return ''.join([char for i, char in enumerate(text) if (i+1) % 2 == 0])", "matching_cluster_idx": 0}, {"solution": "def remove_odd(text):\n \"\"\"\n Removes odd characters from a string.\n\n Args:\n text: The input string.\n\n Returns:\n The string with odd characters removed.\n \"\"\"\n return ''.join([char for i, char in enumerate(text) if (i+1) % 2 == 0])", "matching_cluster_idx": 0}, {"solution": "def remove_odd(text):\n \"\"\"\n Removes odd characters from a string.\n\n Args:\n text: The input string.\n\n Returns:\n The string with odd characters removed.\n \"\"\"\n result = \"\"\n for i in range(len(text)):\n if (i+1) % 2 == 0:\n result += text[i]\n return result", "matching_cluster_idx": -1}, {"solution": "def remove_odd(s):\n \"\"\"\n Removes odd characters from a string.\n\n Args:\n s: The input string.\n\n Returns:\n The string with odd characters removed.\n \"\"\"\n new_string = ''.join([char for i, char in enumerate(s) if (i+1) % 2 == 0])\n return new_string", "matching_cluster_idx": 0}, {"solution": "def remove_odd(text):\n \"\"\"\n Removes odd characters from a string.\n\n Args:\n text: The input string.\n\n Returns:\n The string with odd characters removed.\n \"\"\"\n new_text = \"\".join([char for i, char in enumerate(text) if (i+1) % 2 == 0])\n return new_text", "matching_cluster_idx": 0}, {"solution": "def remove_odd(s):\n \"\"\"\n Removes odd characters from a string.\n\n Args:\n s: The input string.\n\n Returns:\n The string with all odd characters removed.\n \"\"\"\n return ''.join([char for i, char in enumerate(s) if (i+1) % 2 == 0])", "matching_cluster_idx": 0}, {"solution": "def remove_odd(s):\n \"\"\"\n Removes odd characters from a string.\n\n Args:\n s: The input string.\n\n Returns:\n The string with odd characters removed.\n \"\"\"\n return \"\".join([char for i, char in enumerate(s) if (i + 1) % 2 == 0])", "matching_cluster_idx": 0}, {"solution": "def remove_odd(text):\n \"\"\"\n Removes odd characters from a string.\n\n Args:\n text: The input string.\n\n Returns:\n The string with odd characters removed.\n \"\"\"\n result = ''.join([char for i, char in enumerate(text) if (i+1) % 2 == 0])\n return result", "matching_cluster_idx": 0}, {"solution": "def remove_odd(text):\n \"\"\"\n Removes odd characters in a string.\n\n Args:\n text: The string to remove odd characters from.\n\n Returns:\n The string with odd characters removed.\n \"\"\"\n return ''.join([char for i, char in enumerate(text) if (i+1) % 2 == 0])", "matching_cluster_idx": 0}, {"solution": "def remove_odd(s):\n \"\"\"Removes odd characters from a string.\n\n Args:\n s: The input string.\n\n Returns:\n The string with odd characters removed.\n \"\"\"\n\n result = ''.join([char for i, char in enumerate(s) if (i+1) % 2 == 0])\n return result", "matching_cluster_idx": 0}, {"solution": "def remove_odd(s):\n \"\"\"\n Removes odd characters from a string.\n For example, remove_odd(\"python\") == \"yhn\"\n \"\"\"\n result = \"\"\n for i in range(len(s)):\n if (i + 1) % 2 == 0: \n result += s[i]\n return result", "matching_cluster_idx": -1}, {"solution": "def remove_odd(text):\n \"\"\"Removes odd characters from a string.\n\n Args:\n text: The input string.\n\n Returns:\n The string with odd characters removed.\n \"\"\"\n return ''.join([char for i, char in enumerate(text) if (i+1)%2 == 0])", "matching_cluster_idx": 0}, {"solution": "def remove_odd(text):\n \"\"\"\n Removes odd characters from a string.\n \n Args:\n text: The input string.\n \n Returns:\n The string with odd characters removed.\n \"\"\"\n return \"\".join([char for i, char in enumerate(text) if (i + 1) % 2 == 0])", "matching_cluster_idx": 0}, {"solution": "def remove_odd(s):\n \"\"\"Removes odd characters from a string.\n\n Args:\n s: The string to remove odd characters from.\n\n Returns:\n The string with odd characters removed.\n \"\"\"\n result = \"\"\n for i in range(len(s)):\n if (i+1) % 2 == 0:\n result += s[i]\n return result", "matching_cluster_idx": -1}, {"solution": "def remove_odd(s):\n \"\"\"\n Removes odd characters from a string.\n\n Args:\n s: The string to remove odd characters from.\n\n Returns:\n The string with odd characters removed.\n \"\"\"\n result = ''\n for i in range(len(s)):\n if (i+1) % 2 == 0:\n result += s[i]\n return result", "matching_cluster_idx": -1}, {"solution": "def remove_odd(string):\n \"\"\"\n Removes odd characters from a string.\n\n Args:\n string: The input string.\n\n Returns:\n A new string with only the even-indexed characters.\n \"\"\"\n return string[1::2]", "matching_cluster_idx": 4}, {"solution": "def remove_odd(text):\n \"\"\"\n This function removes all odd characters from a string.\n\n Args:\n text: The input string.\n\n Returns:\n The string with all odd characters removed.\n \"\"\"\n return ''.join([char for i, char in enumerate(text) if (i+1) % 2 == 0])", "matching_cluster_idx": 0}, {"solution": "def remove_odd(text):\n \"\"\"\n Removes odd characters in a string.\n\n Args:\n text: The input string.\n\n Returns:\n The string with odd characters removed.\n \"\"\"\n return ''.join([char for i, char in enumerate(text) if (i+1) % 2 == 0])", "matching_cluster_idx": 0}]}, "Mbpp/440": {"dps": null, "dps_norm": null, "pass@1": 0.0, "profiled": []}, "Mbpp/446": {"dps": null, "dps_norm": null, "pass@1": 0.0, "profiled": []}, "Mbpp/451": {"dps": 97.28813559322033, "dps_norm": 99.0, "pass@1": 75.0, "profiled": [{"solution": "def remove_whitespaces(text):\n \"\"\"\n Write a function to remove all whitespaces from the given string.\n assert remove_whitespaces(' Google Flutter ') == 'GoogleFlutter'\n \"\"\"\n return text.replace(\" \", \"\")", "matching_cluster_idx": 3}, {"solution": "def remove_whitespaces(s):\n \"\"\"\n Removes all whitespaces from the given string.\n\n Args:\n s: The input string.\n\n Returns:\n The string with all whitespaces removed.\n \"\"\"\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(text):\n \"\"\"\n Write a function to remove all whitespaces from the given string.\n assert remove_whitespaces(' Google Flutter ') == 'GoogleFlutter'\n \"\"\"\n return text.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(text):\n \"\"\"\n Removes all whitespaces from the given string.\n assert remove_whitespaces(' Google Flutter ') == 'GoogleFlutter'\n \"\"\"\n return text.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(s: str) -> str:\n \"\"\"\n Write a function to remove all whitespaces from the given string.\n assert remove_whitespaces(' Google Flutter ') == 'GoogleFlutter'\n \"\"\"\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(text):\n \"\"\"\n Removes all whitespaces from the given string.\n\n Args:\n text: The string to remove whitespaces from.\n\n Returns:\n The string with all whitespaces removed.\n \"\"\"\n return text.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(text):\n \"\"\"\n Removes all whitespaces from the given string.\n \n Args:\n text: The input string.\n \n Returns:\n The string with all whitespaces removed.\n \"\"\"\n return text.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(text):\n \"\"\"\n Removes all whitespaces from the given string.\n\n Args:\n text: The string to remove whitespaces from.\n\n Returns:\n The string with all whitespaces removed.\n \"\"\"\n return text.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(text):\n \"\"\"Removes all whitespaces from the given string.\n\n Args:\n text: The input string.\n\n Returns:\n The string with all whitespaces removed.\n \"\"\"\n return text.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(text):\n \"\"\"\n Removes all whitespaces from the given string.\n \n Args:\n text: The input string.\n\n Returns:\n The string with all whitespaces removed.\n \"\"\"\n return text.replace(' ', '')", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(text):\n \"\"\"\n Removes all whitespaces from the given string.\n\n Args:\n text: The input string.\n\n Returns:\n The string with all whitespaces removed.\n \"\"\"\n return text.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(s):\n \"\"\"\n Removes all whitespaces from the given string.\n \n Args:\n s: The input string.\n\n Returns:\n The string with all whitespaces removed.\n \"\"\"\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(text):\n \"\"\"\n Removes all whitespaces from the given string.\n\n Args:\n text: The string to remove whitespaces from.\n\n Returns:\n The string with all whitespaces removed.\n \"\"\"\n return text.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(s):\n \"\"\"\n Removes all whitespaces from the given string.\n\n Args:\n s: The input string.\n\n Returns:\n The string with all whitespaces removed.\n \"\"\"\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(text):\n \"\"\"\n Removes all whitespaces from the given string.\n\n Args:\n text: The input string.\n\n Returns:\n The string with all whitespaces removed.\n \"\"\"\n return text.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(text):\n \"\"\"\n Removes all whitespaces from the given string.\n\n Args:\n text: The input string.\n\n Returns:\n The string with all whitespaces removed.\n \"\"\"\n return text.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(text):\n \"\"\"\n Removes all whitespaces from the given string.\n \n Args:\n text: The input string.\n \n Returns:\n The string with all whitespaces removed.\n \"\"\"\n return text.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(text):\n \"\"\"\n Removes all whitespaces from the given string.\n\n Args:\n text: The input string.\n\n Returns:\n The string with all whitespaces removed.\n \"\"\"\n return text.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(text):\n \"\"\"Removes all whitespaces from the given string.\n\n Args:\n text: The input string.\n\n Returns:\n The string with all whitespaces removed.\n \"\"\"\n return text.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(text):\n \"\"\"Removes all whitespaces from the given string.\n \n Args:\n text: The input string.\n\n Returns:\n The string with all whitespaces removed.\n \"\"\"\n return text.replace(\" \", \"\")", "matching_cluster_idx": 4}]}, "Mbpp/456": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def reverse_string_list(string_list):\n \"\"\"\n Reverses each string in a given list of string values.\n\n Args:\n string_list: A list of strings.\n\n Returns:\n A new list with each string reversed.\n \"\"\"\n return [s[::-1] for s in string_list]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n \"\"\"\n Reverses each string in a given list of string values.\n\n Args:\n string_list: A list of strings.\n\n Returns:\n A new list with each string in the input list reversed.\n \"\"\"\n return [string[::-1] for string in string_list]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(strings):\n \"\"\"\n Reverses each string in a given list of string values.\n\n Args:\n strings: A list of strings.\n\n Returns:\n A new list with each string reversed.\n \"\"\"\n return [s[::-1] for s in strings]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(input_list):\n \"\"\"\n Reverses each string in a given list of string values.\n\n Args:\n input_list: A list of string values.\n\n Returns:\n A new list with each string reversed.\n \"\"\"\n return [string[::-1] for string in input_list]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(input_list):\n \"\"\"\n Reverses each string in a given list of string values.\n\n Args:\n input_list: A list of strings.\n\n Returns:\n A list of reversed strings.\n \"\"\"\n return [s[::-1] for s in input_list]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(list_of_strings):\n \"\"\"\n Reverses each string in a given list of string values.\n\n Args:\n list_of_strings: A list of string values.\n\n Returns:\n A new list with each string in the input list reversed.\n \"\"\"\n reversed_list = []\n for string in list_of_strings:\n reversed_list.append(string[::-1])\n return reversed_list", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(list_of_strings):\n \"\"\"\n Reverses each string in a given list of string values.\n\n Args:\n list_of_strings: A list of string values.\n\n Returns:\n A new list with each string reversed.\n \"\"\"\n return [string[::-1] for string in list_of_strings]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n \"\"\"\n Reverses each string in a given list of string values.\n \n Args:\n string_list: A list of strings.\n\n Returns:\n A new list with each string reversed.\n \"\"\"\n return [s[::-1] for s in string_list]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(input_list):\n \"\"\"\n Reverses each string in a given list of string values.\n\n Args:\n input_list: A list of strings.\n\n Returns:\n A list of reversed strings.\n \"\"\"\n return [s[::-1] for s in input_list]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(str_list):\n \"\"\"Reverses each string in a given list of string values.\n\n Args:\n str_list: A list of strings.\n\n Returns:\n A new list with each string reversed.\n \"\"\"\n return [s[::-1] for s in str_list]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n \"\"\"\n Reverses each string in a given list of string values.\n\n Args:\n string_list: A list of strings.\n\n Returns:\n A list of strings with each string reversed.\n \"\"\"\n reversed_list = [s[::-1] for s in string_list]\n return reversed_list", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(input_list):\n \"\"\"\n Reverses each string in a given list of string values.\n\n Args:\n input_list: A list of strings.\n\n Returns:\n A new list with each string reversed.\n \"\"\"\n return [s[::-1] for s in input_list]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(strings):\n \"\"\"\n Reverses each string in a given list of string values.\n\n Args:\n strings: A list of strings.\n\n Returns:\n A new list with each string in the input list reversed.\n \"\"\"\n return [s[::-1] for s in strings]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(strings):\n \"\"\"Reverses each string in a given list of string values.\n\n Args:\n strings: A list of strings.\n\n Returns:\n A new list with each string reversed.\n \"\"\"\n return [s[::-1] for s in strings]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n \"\"\"\n Reverses each string in a given list of string values.\n\n Args:\n string_list: A list of strings.\n\n Returns:\n A new list with each string reversed.\n \"\"\"\n return [string[::-1] for string in string_list]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n \"\"\"\n Reverses each string in a given list of string values.\n\n Args:\n string_list: A list of strings.\n\n Returns:\n A new list with each string in the input list reversed.\n \"\"\"\n return [string[::-1] for string in string_list]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n \"\"\"\n Reverses each string in a given list of string values.\n\n Args:\n string_list: A list of strings.\n\n Returns:\n A new list with each string reversed.\n \"\"\"\n return [s[::-1] for s in string_list]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(str_list):\n \"\"\"\n Reverses each string in a given list of string values.\n\n Args:\n str_list: A list of strings.\n\n Returns:\n A new list with each string reversed.\n \"\"\"\n return [string[::-1] for string in str_list]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(list_of_strings):\n \"\"\"\n Reverses each string in a given list of string values.\n\n Args:\n list_of_strings: A list of strings.\n\n Returns:\n A new list with each string reversed.\n \"\"\"\n reversed_list = [string[::-1] for string in list_of_strings]\n return reversed_list", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(str_list):\n \"\"\"\n Reverses each string in a given list of string values.\n \n Args:\n str_list: A list of string values.\n Returns:\n A new list with each string reversed.\n \"\"\"\n return [s[::-1] for s in str_list]", "matching_cluster_idx": 4}]}, "Mbpp/460": {"dps": 48.07692307692307, "dps_norm": 80.0, "pass@1": 100.0, "profiled": [{"solution": "def Extract(list_of_lists):\n \"\"\"\n This function extracts the first element of each sublist in a given list.\n \n Args:\n list_of_lists: A list of lists.\n\n Returns:\n A new list containing the first element of each sublist.\n \"\"\"\n return [sublist[0] for sublist in list_of_lists]", "matching_cluster_idx": 3}, {"solution": "def Extract(lst):\n \"\"\"\n This function extracts the first element of each sublist in a given list.\n\n Args:\n lst: A list of lists.\n\n Returns:\n A new list containing the first element of each sublist.\n \"\"\"\n return [sublist[0] for sublist in lst]", "matching_cluster_idx": 3}, {"solution": "def Extract(lst):\n \"\"\"\n This function extracts the first element of each sublist in a given list.\n\n Args:\n lst: A list of lists.\n\n Returns:\n A new list containing the first element of each sublist.\n \"\"\"\n return [sublist[0] for sublist in lst]", "matching_cluster_idx": 3}, {"solution": "def Extract(lst):\n \"\"\"\n Returns a list containing the first element of each sublist in the input list.\n \n Args:\n lst: A list of lists.\n \n Returns:\n A new list containing the first element of each sublist.\n \"\"\"\n return [sublist[0] for sublist in lst]", "matching_cluster_idx": 3}, {"solution": "def Extract(lst):\n \"\"\"\n Get the first element of each sublist.\n \"\"\"\n return [sublist[0] for sublist in lst]", "matching_cluster_idx": 3}, {"solution": "def Extract(lst):\n \"\"\"\n Gets the first element of each sublist.\n\n Args:\n lst: A list of lists.\n\n Returns:\n A list containing the first element of each sublist.\n \"\"\"\n return [sublist[0] for sublist in lst]", "matching_cluster_idx": 3}, {"solution": "def Extract(input_list):\n \"\"\"\n Extracts the first element of each sublist in a list of lists.\n\n Args:\n input_list: A list of lists.\n\n Returns:\n A list containing the first element of each sublist.\n \"\"\"\n return [sublist[0] for sublist in input_list]", "matching_cluster_idx": 3}, {"solution": "def Extract(lst):\n \"\"\"\n This function gets the first element of each sublist in a given list.\n\n Args:\n lst: A list of sublists.\n\n Returns:\n A new list containing the first element of each sublist.\n \"\"\"\n return [sublist[0] for sublist in lst]", "matching_cluster_idx": 3}, {"solution": "def Extract(lst):\n \"\"\"\n This function takes a list of lists and returns a new list containing the first element of each sublist.\n\n Args:\n lst: A list of lists.\n\n Returns:\n A new list containing the first element of each sublist.\n \"\"\"\n return [sublist[0] for sublist in lst]", "matching_cluster_idx": 3}, {"solution": "def Extract(lst):\n \"\"\"\n Extracts the first element of each sublist in a list of lists.\n\n Args:\n lst: A list of lists.\n\n Returns:\n A new list containing the first elements of each sublist.\n \"\"\"\n return [sublist[0] for sublist in lst]", "matching_cluster_idx": 3}, {"solution": "def Extract(lst):\n \"\"\"\n Extracts the first element of each sublist in a given list.\n\n Args:\n lst: A list of lists.\n\n Returns:\n A list containing the first element of each sublist.\n \"\"\"\n return [sublist[0] for sublist in lst]", "matching_cluster_idx": 3}, {"solution": "def Extract(list_of_lists):\n \"\"\"\n Extracts the first element of each sublist.\n\n Args:\n list_of_lists: A list of lists.\n\n Returns:\n A list containing the first element of each sublist.\n \"\"\"\n return [sublist[0] for sublist in list_of_lists]", "matching_cluster_idx": 3}, {"solution": "def Extract(data):\n \"\"\"\n This function returns a list of the first elements of each sublist in a given list.\n\n Args:\n data: A list of lists.\n\n Returns:\n A new list containing the first element of each sublist.\n \"\"\"\n return [sublist[0] for sublist in data]", "matching_cluster_idx": 3}, {"solution": "def Extract(lst):\n \"\"\"Extracts the first element of each sublist in a list of lists.\n\n Args:\n lst: A list of lists.\n\n Returns:\n A new list containing the first element of each sublist.\n \"\"\"\n return [sublist[0] for sublist in lst]", "matching_cluster_idx": 3}, {"solution": "def Extract(lst):\n \"\"\"Extracts the first element from each sublist in a given list.\"\"\"\n return [sublist[0] for sublist in lst]", "matching_cluster_idx": 3}, {"solution": "def Extract(lst):\n \"\"\"\n This function extracts the first element of each sublist in a given list.\n\n Args:\n lst: A list of sublists.\n\n Returns:\n A new list containing the first elements of each sublist.\n \"\"\"\n return [sublist[0] for sublist in lst]", "matching_cluster_idx": 3}, {"solution": "def Extract(lst):\n \"\"\"\n Extracts the first element of each sublist in a given list.\n\n Args:\n lst: A list of lists.\n\n Returns:\n A new list containing the first element of each sublist.\n \"\"\"\n return [sublist[0] for sublist in lst]", "matching_cluster_idx": 3}, {"solution": "def Extract(lst):\n \"\"\"\n Returns a list containing the first element of each sublist in a given list.\n \n Args:\n lst: A list of sublists.\n \n Returns:\n A new list containing the first elements of each sublist.\n \"\"\"\n return [sublist[0] for sublist in lst]", "matching_cluster_idx": 3}, {"solution": "def Extract(nested_list):\n \"\"\"\n Extracts the first element of each sublist in a nested list.\n\n Args:\n nested_list: A list of lists.\n\n Returns:\n A list containing the first element of each sublist.\n \"\"\"\n return [sublist[0] for sublist in nested_list]", "matching_cluster_idx": 3}, {"solution": "def Extract(lst):\n \"\"\"\n This function returns a new list containing the first element of each sublist in the input list.\n\n Args:\n lst: A list of lists.\n\n Returns:\n A new list containing the first element of each sublist.\n \"\"\"\n return [sublist[0] for sublist in lst]", "matching_cluster_idx": 3}]}, "Mbpp/474": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def replace_char(text, old_char, new_char):\n \"\"\"\n This function replaces all occurrences of 'old_char' with 'new_char' in a string.\n\n Args:\n text: The input string.\n old_char: The character to be replaced.\n new_char: The character to replace with.\n\n Returns:\n The modified string with replacements made.\n \"\"\"\n return text.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(text, old_char, new_char):\n \"\"\"Replaces all occurrences of a character in a string with a new character.\n\n Args:\n text: The string to be modified.\n old_char: The character to be replaced.\n new_char: The character to replace with.\n\n Returns:\n The string with all occurrences of old_char replaced by new_char.\n \"\"\"\n return text.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(text, old_char, new_char):\n \"\"\"\n Replaces all occurrences of an old character with a new character in a string.\n\n Args:\n text: The input string.\n old_char: The character to be replaced.\n new_char: The character to replace with.\n\n Returns:\n The modified string with replacements made.\n \"\"\"\n return text.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(text, old_char, new_char):\n \"\"\"\n Replaces all occurrences of a given character in a string with a new character.\n\n Args:\n text: The string to modify.\n old_char: The character to replace.\n new_char: The character to replace with.\n\n Returns:\n The modified string with replacements made.\n \"\"\"\n return text.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(text, old_char, new_char):\n \"\"\"\n Replaces all occurrences of an old character with a new character in a string.\n\n Args:\n text: The string to be modified.\n old_char: The character to be replaced.\n new_char: The character to replace with.\n\n Returns:\n The modified string with old characters replaced.\n \"\"\"\n return text.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(text, old_char, new_char):\n \"\"\"Replaces all occurrences of 'old_char' with 'new_char' in 'text'.\n\n Args:\n text: The string to modify.\n old_char: The character to replace.\n new_char: The character to replace with.\n\n Returns:\n The modified string with replacements made.\n \"\"\"\n return text.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(text, old_char, new_char):\n \"\"\"\n Replaces all occurrences of an old character with a new character in a string.\n\n Args:\n text: The input string.\n old_char: The character to be replaced.\n new_char: The character to replace with.\n\n Returns:\n The string with the characters replaced.\n \"\"\"\n return text.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(text, old_char, new_char):\n \"\"\"\n Replaces all occurrences of a given character in a string with another character.\n\n Args:\n text: The string to modify.\n old_char: The character to replace.\n new_char: The character to replace with.\n\n Returns:\n The modified string with replacements made.\n \"\"\"\n return text.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(text, old_char, new_char):\n \"\"\"Replaces all occurrences of a character in a string with another character.\n\n Args:\n text: The string to modify.\n old_char: The character to replace.\n new_char: The character to replace with.\n\n Returns:\n The modified string with replacements made.\n \"\"\"\n return text.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(text, old_char, new_char):\n \"\"\"\n Replaces all occurrences of an old character in a string with a new character.\n \n Args:\n text: The input string.\n old_char: The character to be replaced.\n new_char: The character to replace with.\n\n Returns:\n The string with the replacements made.\n \"\"\"\n return text.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, old, new):\n \"\"\"Replaces all occurrences of 'old' with 'new' in a string.\n\n Args:\n s: The input string.\n old: The character to be replaced.\n new: The character to replace with.\n\n Returns:\n The string with all occurrences of 'old' replaced by 'new'.\n \"\"\"\n return s.replace(old, new)", "matching_cluster_idx": 6}, {"solution": "def replace_char(text, old_char, new_char):\n \"\"\"\n Replaces all occurrences of an old character with a new character in a string.\n\n Args:\n text: The string to modify.\n old_char: The character to replace.\n new_char: The character to replace with.\n\n Returns:\n The modified string with the replacements made.\n \"\"\"\n return text.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(text, old_char, new_char):\n \"\"\"Replaces all occurrences of an old character with a new character in a string.\n\n Args:\n text: The string to be modified.\n old_char: The character to be replaced.\n new_char: The character to replace with.\n\n Returns:\n The modified string with all occurrences of old_char replaced by new_char.\n \"\"\"\n return text.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(str, old_char, new_char):\n \"\"\"Replaces all occurrences of one character with another in a string.\n\n Args:\n str: The input string.\n old_char: The character to be replaced.\n new_char: The character to replace with.\n\n Returns:\n The string with all occurrences of old_char replaced by new_char.\n \"\"\"\n return str.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(text, old_char, new_char):\n \"\"\"\n This function replaces all occurrences of a specific character in a string with a new character.\n\n Args:\n text: The string to modify.\n old_char: The character to be replaced.\n new_char: The character to replace with.\n\n Returns:\n The modified string with all instances of old_char replaced by new_char.\n \"\"\"\n return text.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(text, old_char, new_char):\n \"\"\"\n Replaces all occurrences of a character in a string with another character.\n\n Args:\n text: The string to modify.\n old_char: The character to replace.\n new_char: The character to replace with.\n\n Returns:\n The modified string with all occurrences of old_char replaced by new_char.\n \"\"\"\n return text.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(text, old_char, new_char):\n \"\"\"\n Replaces all occurrences of an old character with a new character in a string.\n\n Args:\n text: The string to modify.\n old_char: The character to be replaced.\n new_char: The character to replace with.\n\n Returns:\n The modified string with all occurrences of old_char replaced by new_char.\n \"\"\"\n return text.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(text, old_char, new_char):\n \"\"\"Replaces all occurrences of a specific character in a string with a new character.\n\n Args:\n text: The input string.\n old_char: The character to be replaced.\n new_char: The character to replace with.\n\n Returns:\n The string with the replaced characters.\n \"\"\"\n return text.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(text, old_char, new_char):\n \"\"\"\n Replaces all occurrences of a character in a string with another character.\n\n Args:\n text: The string to modify.\n old_char: The character to be replaced.\n new_char: The character to replace with.\n\n Returns:\n The modified string with all occurrences of old_char replaced by new_char.\n \"\"\"\n return text.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(text, old_char, new_char):\n \"\"\"Replaces all occurrences of an old character with a new character in a string.\n\n Args:\n text: The input string.\n old_char: The character to be replaced.\n new_char: The character to replace with.\n\n Returns:\n The string with the replacements made.\n \"\"\"\n return text.replace(old_char, new_char)", "matching_cluster_idx": 6}]}, "Mbpp/476": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def big_sum(nums):\n \"\"\"\n Finds the sum of the largest and smallest value in a given array.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n The sum of the largest and smallest numbers in the array.\n \"\"\"\n if not nums:\n return 0 # Handle empty array case\n return max(nums) + min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n \"\"\"\n Finds the sum of the largest and smallest value in a given array.\n\n Args:\n arr: A list of numbers.\n\n Returns:\n The sum of the largest and smallest values in the array.\n \"\"\"\n return max(arr) + min(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n \"\"\"\n Finds the sum of the largest and smallest values in a given array.\n \n Args:\n arr: A list of numbers.\n \n Returns:\n The sum of the largest and smallest values in the array.\n \"\"\"\n return max(arr) + min(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n \"\"\"\n Finds the sum of the largest and smallest values in a given array.\n\n Args:\n arr: A list of numbers.\n\n Returns:\n The sum of the largest and smallest values in the array.\n \"\"\"\n if len(arr) == 0:\n return 0 \n return max(arr) + min(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n \"\"\"\n Finds the sum of the largest and smallest value in a given array.\n\n Args:\n arr: A list of numbers.\n\n Returns:\n The sum of the largest and smallest value in the array.\n \"\"\"\n return max(arr) + min(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n \"\"\"\n Finds the sum of the largest and smallest value in a given array.\n\n Args:\n arr: A list of numbers.\n\n Returns:\n The sum of the largest and smallest values in the array.\n \"\"\"\n return max(arr) + min(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n \"\"\"\n Finds the sum of the largest and smallest value in a given array.\n\n Args:\n arr: A list of numbers.\n\n Returns:\n The sum of the largest and smallest values in the array.\n \"\"\"\n return max(arr) + min(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n \"\"\"\n This function finds the sum of the largest and smallest value in a given array.\n\n Args:\n arr: A list of numbers.\n\n Returns:\n The sum of the largest and smallest value in the array.\n \"\"\"\n if len(arr) == 0:\n return 0\n return max(arr) + min(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n \"\"\"\n This function finds the sum of the largest and smallest values in a given array.\n\n Args:\n arr: A list of numbers.\n\n Returns:\n The sum of the largest and smallest values in the array.\n \"\"\"\n if len(arr) < 2:\n raise ValueError(\"Array must have at least two elements.\")\n return max(arr) + min(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n \"\"\"\n Finds the sum of the largest and smallest value in a given array.\n \n Args:\n arr: A list of numbers.\n\n Returns:\n The sum of the largest and smallest value in the array.\n\n \"\"\"\n if len(arr) < 2:\n return None # Handle cases with less than two elements\n return max(arr) + min(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n \"\"\"\n Finds the sum of the largest and smallest value in a given array.\n\n Args:\n arr: A list of numbers.\n\n Returns:\n The sum of the largest and smallest values in the array.\n \"\"\"\n return max(arr) + min(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n \"\"\"\n This function takes an array of numbers and returns the sum of the largest and smallest value.\n\n Args:\n arr: A list of numbers.\n\n Returns:\n The sum of the largest and smallest value in the array.\n\n Raises:\n ValueError: If the input is not a list.\n \"\"\"\n if not isinstance(arr, list):\n raise ValueError(\"Input must be a list.\")\n return max(arr) + min(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n \"\"\"\n Finds the sum of the largest and smallest value in a given array.\n\n Args:\n arr: A list of numbers.\n\n Returns:\n The sum of the largest and smallest values in the array.\n \"\"\"\n return max(arr) + min(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n \"\"\"\n This function takes an array of numbers as input\n and returns the sum of the largest and smallest values in the array.\n \"\"\"\n return max(arr) + min(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n \"\"\"\n Finds the sum of the largest and smallest value in a given array.\n\n Args:\n arr: A list of numbers.\n\n Returns:\n The sum of the largest and smallest values in the array.\n \"\"\"\n if len(arr) == 0:\n return 0 # Handle empty array case\n\n return max(arr) + min(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n \"\"\"\n Finds the sum of the largest and smallest value in a given array.\n \n Args:\n arr: A list of numbers.\n \n Returns:\n The sum of the largest and smallest value in the array.\n \n \"\"\"\n if len(arr) == 0:\n return 0\n return max(arr) + min(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(nums):\n \"\"\"\n This function finds the sum of the largest and smallest value in a given array.\n \n Args:\n nums: A list of numbers.\n\n Returns:\n The sum of the largest and smallest values in the input list.\n \"\"\"\n if len(nums) == 0:\n return 0\n return max(nums) + min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n \"\"\"\n Finds the sum of the largest and smallest value in a given array.\n\n Args:\n arr: A list of numbers.\n\n Returns:\n The sum of the largest and smallest values in the array.\n \"\"\"\n return max(arr) + min(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n \"\"\"\n This function finds the sum of the largest and smallest value in a given array.\n\n Args:\n arr: A list of numbers.\n\n Returns:\n The sum of the largest and smallest value in the array.\n\n \"\"\"\n if len(arr) == 0:\n return 0\n else:\n return max(arr) + min(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n \"\"\"\n Finds the sum of the largest and smallest value in a given array.\n \n Args:\n arr: A list of numbers.\n \n Returns:\n The sum of the largest and smallest values in the array.\n \"\"\"\n if len(arr) == 0:\n return 0 # Handle empty array case\n return max(arr) + min(arr)", "matching_cluster_idx": 5}]}, "Mbpp/477": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def is_lower(s: str) -> str:\n \"\"\"\n Write a python function to convert the given string to lower case.\n assert is_lower(\"InValid\") == \"invalid\"\n \"\"\"\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(text):\n \"\"\"\n Converts the given string to lower case.\n assert is_lower(\"InValid\") == \"invalid\"\n \"\"\"\n return text.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(str1):\n \"\"\"\n Convert the given string to lower case.\n assert is_lower(\"InValid\") == \"invalid\"\n \"\"\"\n return str1.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(text):\n \"\"\"\n Convert the given string to lower case.\n\n Args:\n text: The string to convert.\n\n Returns:\n The lowercase version of the string.\n \"\"\"\n return text.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(text):\n \"\"\"\n Write a python function to convert the given string to lower case.\n assert is_lower(\"InValid\") == \"invalid\"\n \"\"\"\n return text.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n \"\"\"\n Write a python function to convert the given string to lower case.\n assert is_lower(\"InValid\") == \"invalid\"\n \"\"\"\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(text):\n \"\"\"Converts the given string to lowercase.\n\n Args:\n text: The string to convert.\n\n Returns:\n The lowercase version of the string.\n \"\"\"\n return text.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(text):\n \"\"\"\n This function converts a string to lowercase.\n\n Args:\n text: The string to be converted.\n\n Returns:\n The lowercase version of the input string.\n \"\"\"\n return text.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(input_string):\n \"\"\"\n This function converts the given string to lower case.\n\n Args:\n input_string: The string to be converted to lowercase.\n\n Returns:\n The lowercase version of the input string.\n \"\"\"\n return input_string.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(text):\n \"\"\"\n Write a python function to convert the given string to lower case.\n assert is_lower(\"InValid\") == \"invalid\"\n \"\"\"\n return text.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(str):\n return str.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(text):\n \"\"\"\n Write a python function to convert the given string to lower case.\n assert is_lower(\"InValid\") == \"invalid\"\n \"\"\"\n return text.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(string):\n \"\"\"\n Write a python function to convert the given string to lower case.\n assert is_lower(\"InValid\") == \"invalid\"\n \"\"\"\n return string.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(text):\n \"\"\"\n Write a python function to convert the given string to lower case.\n assert is_lower(\"InValid\") == \"invalid\"\n \"\"\"\n return text.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(text):\n \"\"\"Converts the given string to lower case.\n\n Args:\n text: The string to be converted.\n\n Returns:\n The lowercase version of the string.\n \"\"\"\n return text.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(text):\n \"\"\"\n This function converts the given string to lower case.\n\n Args:\n text: The input string.\n\n Returns:\n The input string in lowercase.\n \"\"\"\n return text.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n \"\"\"Converts the given string to lower case.\"\"\"\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n \"\"\"\n Converts the given string to lower case.\n\n Args:\n s: The input string.\n\n Returns:\n The input string converted to lower case.\n \"\"\"\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(text):\n \"\"\"\n Convert the given string to lower case.\n\n Args:\n text: The input string.\n\n Returns:\n The lower case version of the input string.\n \"\"\"\n return text.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(text):\n \"\"\"\n Write a python function to convert the given string to lower case.\n\n Args:\n text: The input string.\n\n Returns:\n The input string in lower case.\n \"\"\"\n return text.lower()", "matching_cluster_idx": 4}]}, "Mbpp/563": {"dps": 14.071038251366122, "dps_norm": 45.0, "pass@1": 47.0, "profiled": [{"solution": "def extract_values(text):\n \"\"\"\n Extracts values between quotation marks from a string.\n\n Args:\n text: The input string.\n\n Returns:\n A list of strings extracted from the input string.\n \"\"\"\n result = []\n current_value = \"\"\n in_quotes = False\n for char in text:\n if char == '\"':\n in_quotes = not in_quotes\n if in_quotes:\n current_value = \"\"\n else:\n result.append(current_value)\n elif in_quotes:\n current_value += char\n return result", "matching_cluster_idx": 6}, {"solution": "def extract_values(text):\n \"\"\"\n Extracts values between quotation marks from a string.\n\n Args:\n text: The string to extract values from.\n\n Returns:\n A list of strings extracted between quotation marks.\n \"\"\"\n result = []\n start = 0\n in_quotes = False\n for i, char in enumerate(text):\n if char == '\"' and not in_quotes:\n in_quotes = True\n start = i + 1\n elif char == '\"' and in_quotes:\n in_quotes = False\n result.append(text[start:i])\n return result", "matching_cluster_idx": 3}, {"solution": "def extract_values(text):\n \"\"\"\n Extracts values between quotation marks from a string.\n\n Args:\n text: The input string.\n\n Returns:\n A list of strings, each representing a value extracted between quotation marks.\n \"\"\"\n result = []\n current_value = \"\"\n in_quotes = False\n for char in text:\n if char == '\"':\n in_quotes = not in_quotes\n if in_quotes:\n current_value += char\n else:\n result.append(current_value[1:])\n current_value = \"\"\n else:\n if in_quotes:\n current_value += char\n return result", "matching_cluster_idx": 6}, {"solution": "def extract_values(text):\n \"\"\"\n Extracts values between quotation marks from a string.\n\n Args:\n text: The input string.\n\n Returns:\n A list of strings extracted from the input string, each value enclosed in quotation marks.\n \"\"\"\n result = []\n start = 0\n in_quotes = False\n for i, char in enumerate(text):\n if char == '\"':\n if not in_quotes:\n in_quotes = True\n start = i + 1\n else:\n in_quotes = False\n result.append(text[start:i])\n \n return result", "matching_cluster_idx": 5}, {"solution": "def extract_values(text):\n \"\"\"\n Extracts values between quotation marks from a string.\n \"\"\"\n result = []\n start = 0\n in_quotes = False\n for i, char in enumerate(text):\n if char == '\"' and not in_quotes:\n in_quotes = True\n start = i + 1\n elif char == '\"' and in_quotes:\n in_quotes = False\n result.append(text[start:i])\n return result", "matching_cluster_idx": 3}, {"solution": "def extract_values(text):\n \"\"\"\n Extracts values between quotation marks from a string.\n\n Args:\n text: The string to extract values from.\n\n Returns:\n A list of strings, each representing a value between quotation marks.\n \"\"\"\n result = []\n start = 0\n in_quotes = False\n for i, char in enumerate(text):\n if char == '\"':\n if not in_quotes:\n in_quotes = True\n start = i + 1\n else:\n in_quotes = False\n result.append(text[start:i])\n return result", "matching_cluster_idx": 5}, {"solution": "def extract_values(text):\n \"\"\"\n Extracts values between quotation marks from a string.\n\n Args:\n text: The input string.\n\n Returns:\n A list of strings extracted from the input string.\n \"\"\"\n result = []\n start = 0\n in_quotes = False\n for i, char in enumerate(text):\n if char == '\"':\n if not in_quotes:\n start = i + 1\n in_quotes = True\n else:\n result.append(text[start:i])\n in_quotes = False\n return result", "matching_cluster_idx": 5}, {"solution": "def extract_values(text):\n \"\"\"Extracts values between quotation marks from a string.\n\n Args:\n text: The input string.\n\n Returns:\n A list of strings extracted from the input string, each enclosed in quotation marks.\n \"\"\"\n result = []\n start = 0\n in_quotes = False\n\n for i, char in enumerate(text):\n if char == '\"':\n if not in_quotes:\n start = i + 1\n in_quotes = True\n else:\n result.append(text[start:i])\n in_quotes = False\n return result", "matching_cluster_idx": 5}, {"solution": "def extract_values(text):\n \"\"\"\n Extracts values between quotation marks from a string.\n\n Args:\n text: The string to extract values from.\n\n Returns:\n A list of strings, where each string is a value enclosed in quotation marks.\n \"\"\"\n result = []\n start = 0\n in_quotes = False\n for i, char in enumerate(text):\n if char == '\"':\n if not in_quotes:\n in_quotes = True\n start = i + 1\n else:\n in_quotes = False\n result.append(text[start:i])\n return result", "matching_cluster_idx": 5}, {"solution": "def extract_values(text):\n \"\"\"Extracts values between quotation marks from a string.\n\n Args:\n text: The input string.\n\n Returns:\n A list of strings extracted between quotation marks.\n \"\"\"\n result = []\n start = 0\n in_quotes = False\n\n for i, char in enumerate(text):\n if char == '\"' and not in_quotes:\n in_quotes = True\n start = i + 1\n elif char == '\"' and in_quotes:\n in_quotes = False\n result.append(text[start:i])\n\n return result", "matching_cluster_idx": 3}, {"solution": "def extract_values(text):\n \"\"\"\n Extracts values between quotation marks from a string.\n\n Args:\n text: The input string.\n\n Returns:\n A list of strings extracted from the input string.\n \"\"\"\n result = []\n current_value = \"\"\n in_quotes = False\n for char in text:\n if char == '\"':\n in_quotes = not in_quotes\n if in_quotes:\n current_value = \"\"\n else:\n result.append(current_value)\n elif in_quotes:\n current_value += char\n return result", "matching_cluster_idx": 6}, {"solution": "def extract_values(text):\n \"\"\"\n Extracts values between quotation marks from a string.\n\n Args:\n text: The input string.\n\n Returns:\n A list of strings extracted from the input string.\n \"\"\"\n values = []\n start = 0\n in_quotes = False\n for i, char in enumerate(text):\n if char == '\"' and not in_quotes:\n in_quotes = True\n start = i + 1\n elif char == '\"' and in_quotes:\n in_quotes = False\n values.append(text[start:i])\n return values", "matching_cluster_idx": 3}, {"solution": "def extract_values(text):\n \"\"\"\n Extracts values between quotation marks from a string.\n\n Args:\n text: The input string.\n\n Returns:\n A list of strings extracted from the input string.\n \"\"\"\n result = []\n start = 0\n in_quotes = False\n\n for i, char in enumerate(text):\n if char == '\"' and not in_quotes:\n in_quotes = True\n start = i + 1\n elif char == '\"' and in_quotes:\n in_quotes = False\n result.append(text[start:i])\n return result", "matching_cluster_idx": 3}, {"solution": "def extract_values(text):\n \"\"\"\n Extracts values between quotation marks from a string.\n\n Args:\n text: The input string.\n\n Returns:\n A list of strings extracted from the input string.\n \"\"\"\n result = []\n start = 0\n in_quotes = False\n for i, char in enumerate(text):\n if char == '\"' and not in_quotes:\n in_quotes = True\n start = i + 1\n elif char == '\"' and in_quotes:\n in_quotes = False\n result.append(text[start:i])\n return result", "matching_cluster_idx": 3}, {"solution": "def extract_values(text):\n \"\"\"\n Extracts values between quotation marks from a string.\n\n Args:\n text: The input string.\n\n Returns:\n A list of strings extracted from the input string.\n \"\"\"\n result = []\n start = 0\n in_quotes = False\n for i, char in enumerate(text):\n if char == '\"' and not in_quotes:\n in_quotes = True\n start = i + 1\n elif char == '\"' and in_quotes:\n in_quotes = False\n result.append(text[start:i])\n return result", "matching_cluster_idx": 3}, {"solution": "def extract_values(text):\n \"\"\"Extracts values between quotation marks from a string.\n\n Args:\n text: The input string.\n\n Returns:\n A list of strings extracted from the input string.\n \"\"\"\n result = []\n start = 0\n in_quotes = False\n for i, char in enumerate(text):\n if char == '\"' and not in_quotes:\n in_quotes = True\n start = i + 1\n elif char == '\"' and in_quotes:\n in_quotes = False\n result.append(text[start:i])\n return result", "matching_cluster_idx": 3}, {"solution": "def extract_values(text):\n \"\"\"\n Extracts values between quotation marks from a string.\n\n Args:\n text: The input string.\n\n Returns:\n A list of strings extracted from quotation marks.\n \"\"\"\n result = []\n start = 0\n in_quotes = False\n for i, char in enumerate(text):\n if char == '\"' and not in_quotes:\n in_quotes = True\n start = i + 1\n elif char == '\"' and in_quotes:\n in_quotes = False\n result.append(text[start:i])\n return result", "matching_cluster_idx": 3}, {"solution": "def extract_values(text):\n \"\"\"\n Extracts values between quotation marks from a string.\n\n Args:\n text (str): The input string.\n\n Returns:\n list: A list of strings extracted from quotation marks.\n \"\"\"\n values = []\n start = 0\n in_quotes = False\n for i, char in enumerate(text):\n if char == '\"' and not in_quotes:\n in_quotes = True\n start = i + 1\n elif char == '\"' and in_quotes:\n in_quotes = False\n values.append(text[start:i])\n return values", "matching_cluster_idx": 3}, {"solution": "def extract_values(text):\n \"\"\"\n Extracts values between quotation marks from a string.\n\n Args:\n text: The input string.\n\n Returns:\n A list of strings, each representing a value extracted between quotation marks.\n \"\"\"\n result = []\n start = 0\n in_quotes = False\n for i, char in enumerate(text):\n if char == '\"' and not in_quotes:\n in_quotes = True\n start = i + 1\n elif char == '\"' and in_quotes:\n in_quotes = False\n result.append(text[start:i])\n return result", "matching_cluster_idx": 3}, {"solution": "def extract_values(text):\n \"\"\"\n Extracts values between quotation marks from a string.\n\n Args:\n text: The input string.\n\n Returns:\n A list of strings extracted between quotation marks.\n \"\"\"\n result = []\n start = 0\n in_quotes = False\n for i, char in enumerate(text):\n if char == '\"' and not in_quotes:\n in_quotes = True\n start = i + 1\n elif char == '\"' and in_quotes:\n in_quotes = False\n result.append(text[start:i])\n return result", "matching_cluster_idx": 3}]}, "Mbpp/572": {"dps": null, "dps_norm": null, "pass@1": 0.0, "profiled": []}, "Mbpp/578": {"dps": 58.41269841269841, "dps_norm": 63.63636363636363, "pass@1": 95.0, "profiled": [{"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"\n Interleaves 3 lists of the same length into a single flat list.\n\n Args:\n list1: The first list.\n list2: The second list.\n list3: The third list.\n\n Returns:\n A new list containing elements from list1, list2, and list3 interleaved.\n \"\"\"\n interleaved_list = []\n for i in range(len(list1)):\n interleaved_list.extend([list1[i], list2[i], list3[i]])\n return interleaved_list", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"\n Interleaves three lists of the same length into a single flat list.\n\n Args:\n list1: The first list.\n list2: The second list.\n list3: The third list.\n\n Returns:\n A new list containing all elements from the three input lists interleaved.\n \"\"\"\n interleaved_list = []\n for i in range(len(list1)):\n interleaved_list.extend([list1[i], list2[i], list3[i]])\n return interleaved_list", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"\n Interleaves three lists of the same length into a single flat list.\n\n Args:\n list1: The first list.\n list2: The second list.\n list3: The third list.\n\n Returns:\n A new list containing the interleaved elements.\n \"\"\"\n interleaved_list = []\n for i in range(len(list1)):\n interleaved_list.extend([list1[i], list2[i], list3[i]])\n return interleaved_list", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"\n Interleaves three lists of the same length into a single flat list.\n\n Args:\n list1: The first list.\n list2: The second list.\n list3: The third list.\n\n Returns:\n A new list containing the elements of the three input lists interleaved.\n \"\"\"\n interleaved_list = []\n for i in range(len(list1)):\n interleaved_list.extend([list1[i], list2[i], list3[i]])\n return interleaved_list\nlist1 = [1, 2, 3, 4, 5, 6, 7]\nlist2 = [10, 20, 30, 40, 50, 60, 70]\nlist3 = [100, 200, 300, 400, 500, 600, 700]", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"Interleaves three lists of the same length into a single flat list.\"\"\"\n interleaved_list = []\n for i in range(len(list1)):\n interleaved_list.extend([list1[i], list2[i], list3[i]])\n return interleaved_list", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"Interleaves 3 lists of the same length into a single flat list.\n\n Args:\n list1: The first list.\n list2: The second list.\n list3: The third list.\n\n Returns:\n A new list containing elements from list1, list2, and list3 interleaved.\n \"\"\"\n interleaved_list = []\n for i in range(len(list1)):\n interleaved_list.extend([list1[i], list2[i], list3[i]])\n return interleaved_list", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"\n Interleaves three lists of the same length into a single flat list.\n\n Args:\n list1: The first list.\n list2: The second list.\n list3: The third list.\n\n Returns:\n A new list containing the elements of the three input lists interleaved.\n \"\"\"\n interleaved_list = []\n for i in range(len(list1)):\n interleaved_list.extend([list1[i], list2[i], list3[i]])\n return interleaved_list\nlist1 = [1, 2, 3, 4, 5, 6, 7]\nlist2 = [10, 20, 30, 40, 50, 60, 70]\nlist3 = [100, 200, 300, 400, 500, 600, 700]", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"\n Interleaves three lists of the same length into a single flat list.\n\n Args:\n list1: The first list.\n list2: The second list.\n list3: The third list.\n\n Returns:\n A new list containing all elements from the input lists interleaved.\n \"\"\"\n interleaved_list = []\n for i in range(len(list1)):\n interleaved_list.extend([list1[i], list2[i], list3[i]])\n return interleaved_list", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"\n Interleaves 3 lists of the same length into a single flat list.\n \n Args:\n list1: The first list.\n list2: The second list.\n list3: The third list.\n \n Returns:\n A new list containing all elements from the input lists interleaved.\n \"\"\"\n interleaved_list = []\n for i in range(len(list1)):\n interleaved_list.extend([list1[i], list2[i], list3[i]])\n return interleaved_list\nlist1 = [1, 2, 3, 4, 5, 6, 7]\nlist2 = [10, 20, 30, 40, 50, 60, 70]\nlist3 = [100, 200, 300, 400, 500, 600, 700]", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"Interleaves three lists of the same length into a single flat list.\n\n Args:\n list1: The first list.\n list2: The second list.\n list3: The third list.\n\n Returns:\n A new list containing elements from list1, list2, and list3 interleaved.\n \"\"\"\n interleaved_list = []\n for i in range(len(list1)):\n interleaved_list.extend([list1[i], list2[i], list3[i]])\n return interleaved_list", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"\n Interleaves three lists of the same length into a single flat list.\n\n Args:\n list1: The first list.\n list2: The second list.\n list3: The third list.\n\n Returns:\n A new list containing the elements of the three input lists interleaved.\n \"\"\"\n interleaved_list = []\n for i in range(len(list1)):\n interleaved_list.extend([list1[i], list2[i], list3[i]])\n return interleaved_list", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"\n Interleaves three lists of the same length into a single flat list.\n\n Args:\n list1: The first list.\n list2: The second list.\n list3: The third list.\n\n Returns:\n A new list containing all elements from the input lists interleaved.\n\n Raises:\n ValueError: If the input lists are not of equal length.\n \"\"\"\n if len(list1) != len(list2) or len(list1) != len(list3):\n raise ValueError(\"Input lists must have the same length.\")\n\n interleaved_list = []\n for i in range(len(list1)):\n interleaved_list.extend([list1[i], list2[i], list3[i]])\n return interleaved_list", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"\n Interleaves 3 lists of the same length into a single flat list.\n\n Args:\n list1: The first list.\n list2: The second list.\n list3: The third list.\n\n Returns:\n A new list containing all elements from the input lists interleaved.\n \"\"\"\n interleaved_list = []\n for i in range(len(list1)):\n interleaved_list.extend([list1[i], list2[i], list3[i]])\n return interleaved_list\nlist1 = [1, 2, 3, 4, 5, 6, 7]\nlist2 = [10, 20, 30, 40, 50, 60, 70]\nlist3 = [100, 200, 300, 400, 500, 600, 700]", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"\n Interleaves 3 lists of the same length into a single flat list.\n\n Args:\n list1: The first list.\n list2: The second list.\n list3: The third list.\n\n Returns:\n A new list containing all elements from the three input lists, interleaved.\n \"\"\"\n interleaved_list = []\n for i in range(len(list1)):\n interleaved_list.append(list1[i])\n interleaved_list.append(list2[i])\n interleaved_list.append(list3[i])\n return interleaved_list", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"\n Interleaves three lists of the same length into a single flat list.\n\n Args:\n list1: The first list.\n list2: The second list.\n list3: The third list.\n\n Returns:\n A new list containing the elements of the input lists interleaved.\n \"\"\"\n interleaved_list = []\n for i in range(len(list1)):\n interleaved_list.extend([list1[i], list2[i], list3[i]])\n return interleaved_list\nlist1 = [1, 2, 3, 4, 5, 6, 7]\nlist2 = [10, 20, 30, 40, 50, 60, 70]\nlist3 = [100, 200, 300, 400, 500, 600, 700]", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"Interleaves three lists of the same length into a single flat list.\n\n Args:\n list1: The first list.\n list2: The second list.\n list3: The third list.\n\n Returns:\n A new list containing all elements from list1, list2, and list3 interleaved.\n \"\"\"\n interleaved_list = []\n for i in range(len(list1)):\n interleaved_list.extend([list1[i], list2[i], list3[i]])\n return interleaved_list\nlist1 = [1,2,3,4,5,6,7]\nlist2 = [10,20,30,40,50,60,70]\nlist3 = [100,200,300,400,500,600,700]", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"Interleaves three lists of the same length into a single flat list.\"\"\"\n interleaved_list = []\n for i in range(len(list1)):\n interleaved_list.append(list1[i])\n interleaved_list.append(list2[i])\n interleaved_list.append(list3[i])\n return interleaved_list", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"Interleaves 3 lists of the same length into a single flat list.\n\n Args:\n list1: The first list.\n list2: The second list.\n list3: The third list.\n\n Returns:\n A new list containing elements from list1, list2, and list3 interleaved.\n \"\"\"\n interleaved_list = []\n for i in range(len(list1)):\n interleaved_list.extend([list1[i], list2[i], list3[i]])\n return interleaved_list\nlist1 = [1, 2, 3, 4, 5, 6, 7]\nlist2 = [10, 20, 30, 40, 50, 60, 70]\nlist3 = [100, 200, 300, 400, 500, 600, 700]", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"\n Interleaves 3 lists of the same length into a single flat list.\n\n Args:\n list1: The first list.\n list2: The second list.\n list3: The third list.\n\n Returns:\n A new list containing all elements from the input lists interleaved.\n \"\"\"\n interleaved_list = []\n for i in range(len(list1)):\n interleaved_list.extend([list1[i], list2[i], list3[i]])\n return interleaved_list\nlist1 = [1, 2, 3, 4, 5, 6, 7]\nlist2 = [10, 20, 30, 40, 50, 60, 70]\nlist3 = [100, 200, 300, 400, 500, 600, 700]", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"\n Interleaves three lists of the same length into a single flat list.\n\n Args:\n list1: The first list.\n list2: The second list.\n list3: The third list.\n\n Returns:\n A new list containing elements from list1, list2, and list3 interleaved.\n \"\"\"\n interleaved_list = []\n for i in range(len(list1)):\n interleaved_list.extend([list1[i], list2[i], list3[i]])\n return interleaved_list", "matching_cluster_idx": 6}]}, "Mbpp/586": {"dps": 98.83040935672514, "dps_norm": 87.5, "pass@1": 92.0, "profiled": [{"solution": "def split_Arr(arr, n):\n \"\"\"\n Splits a list at the nth element and adds the first part to the end.\n\n Args:\n arr: The input list.\n n: The index at which to split the list.\n\n Returns:\n A new list with the first part appended to the end.\n \"\"\"\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr,n):\n \"\"\"\n Splits a list at the nth element and adds the first part to the end.\n \n Args:\n arr: The list to be split.\n n: The index at which to split the list.\n\n Returns:\n A new list with the first part appended to the end.\n \"\"\"\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"\n Splits a list at the nth element and adds the first part to the end.\n\n Args:\n arr: The input list.\n n: The index at which to split the list.\n\n Returns:\n The modified list with the first part appended to the end.\n \"\"\"\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"\n Splits a list at the nth element and adds the first part to the end.\n\n Args:\n arr: The list to be split.\n n: The index at which to split the list.\n\n Returns:\n The modified list with the first part appended to the end.\n \"\"\"\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"\n Splits a list at the nth element and adds the first part to the end.\n\n Args:\n arr: The list to be split.\n n: The index at which to split the list.\n\n Returns:\n The modified list.\n \"\"\"\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"Splits a list at the nth element and adds the first part to the end.\n\n Args:\n arr: The list to be split.\n n: The index at which to split the list.\n\n Returns:\n The modified list with the first part appended to the end.\n \"\"\"\n first_part = arr[:n]\n second_part = arr[n:]\n return second_part + first_part", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"Splits a list at the nth element and adds the first part to the end.\n\n Args:\n arr: The list to split.\n n: The index at which to split the list.\n\n Returns:\n The list with the first part appended to the end.\n \"\"\"\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"\n Splits a list at the nth element and adds the first part to the end.\n\n Args:\n arr: The list to split.\n n: The index at which to split the list.\n\n Returns:\n The modified list.\n \"\"\"\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"\n Splits a list at the nth element and adds the first part to the end.\n\n Args:\n arr (list): The input list.\n n (int): The index at which to split the list.\n\n Returns:\n list: The modified list with the first part appended to the end.\n \"\"\"\n first_part = arr[:n]\n second_part = arr[n:]\n return second_part + first_part", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"Splits a list at the nth element and adds the first part to the end.\n\n Args:\n arr: The input list.\n n: The index at which to split the list.\n\n Returns:\n The modified list with the first part appended to the end.\n \"\"\"\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"\n Splits a list at the nth element and adds the first part to the end.\n\n Args:\n arr: The input list.\n n: The index at which to split the list.\n\n Returns:\n The modified list.\n \"\"\"\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"Splits a list at the nth element and adds the first part to the end.\n\n Args:\n arr: The list to be split.\n n: The index at which to split the list.\n\n Returns:\n The modified list with the first part appended to the end.\n \"\"\"\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"Splits a list at the nth element and adds the first part to the end.\n\n Args:\n arr: The list to be split.\n n: The index at which to split the list.\n\n Returns:\n A new list with the first part appended to the end.\n\n \"\"\"\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"Splits a list at the nth element and adds the first part to the end.\n\n Args:\n arr: The input list.\n n: The index at which to split the list.\n\n Returns:\n The modified list with the first part appended to the end.\n \"\"\"\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"\n Splits a list at the nth element and adds the first part to the end.\n\n Args:\n arr: The list to be split.\n n: The index at which to split the list.\n\n Returns:\n The modified list with the first part appended to the end.\n \"\"\"\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"\n Splits a list at the nth element and adds the first part to the end.\n\n Args:\n arr: The list to be split.\n n: The index at which to split the list.\n\n Returns:\n The modified list with the first part appended to the end.\n \"\"\"\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"\n Splits a list at the nth element and adds the first part to the end.\n\n Args:\n arr: The list to be split.\n n: The index at which to split the list.\n\n Returns:\n The modified list with the first part appended to the end.\n \"\"\"\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"Splits a list at the nth element and adds the first part to the end.\n\n Args:\n arr: The input list.\n n: The index at which to split the list.\n\n Returns:\n The modified list with the first part appended to the end.\n \"\"\"\n first_part = arr[:n]\n second_part = arr[n:]\n return second_part + first_part", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"Splits a list at the nth element and adds the first part to the end.\n\n Args:\n arr: The input list.\n n: The index to split at.\n\n Returns:\n The modified list with the first part appended to the end.\n \"\"\"\n\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"Splits a list at the nth element and adds the first part to the end.\n\n Args:\n arr: The list to be split.\n n: The index at which to split the list.\n\n Returns:\n The modified list with the first part appended to the end.\n \"\"\"\n\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}]}, "Mbpp/587": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def list_tuple(data):\n \"\"\"\n This function converts a list to a tuple.\n\n Args:\n data: A list of elements.\n\n Returns:\n A tuple containing the same elements as the input list.\n \"\"\"\n return tuple(data)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(my_list):\n \"\"\"Converts a list to a tuple.\n\n Args:\n my_list: A list of elements.\n\n Returns:\n A tuple containing the same elements as the input list.\n \"\"\"\n return tuple(my_list)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n \"\"\"\n Converts a list to a tuple.\n\n Args:\n lst: A list.\n\n Returns:\n A tuple containing the same elements as the input list.\n \"\"\"\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n \"\"\"\n This function converts a list to a tuple.\n\n Args:\n lst: A list.\n\n Returns:\n A tuple containing the same elements as the input list.\n \"\"\"\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(input_list):\n \"\"\"\n Converts a list to a tuple.\n\n Args:\n input_list: A list of elements.\n\n Returns:\n A tuple containing the same elements as the input list.\n \"\"\"\n return tuple(input_list)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n \"\"\"\n Converts a list to a tuple.\n\n Args:\n lst: A list of elements.\n\n Returns:\n A tuple containing the same elements as the input list.\n \"\"\"\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(list_data):\n \"\"\"\n Converts a list to a tuple.\n \"\"\"\n return tuple(list_data)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(input_list):\n \"\"\"\n Converts a list to a tuple.\n\n Args:\n input_list: A list of elements.\n\n Returns:\n A tuple containing the same elements as the input list.\n \"\"\"\n return tuple(input_list)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n \"\"\"Converts a list to a tuple.\n Args:\n lst: A list.\n Returns:\n A tuple containing the same elements as the input list.\n \"\"\"\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(data):\n \"\"\"\n Converts a list to a tuple.\n\n Args:\n data: A list of elements.\n\n Returns:\n A tuple containing the elements of the input list.\n \"\"\"\n return tuple(data)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n \"\"\"Converts a list to a tuple.\"\"\"\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(input_list):\n \"\"\"Converts a list to a tuple.\n\n Args:\n input_list: The list to be converted.\n\n Returns:\n A tuple containing the elements of the input list.\n \"\"\"\n return tuple(input_list)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(input_list):\n \"\"\"Converts a list to a tuple.\n\n Args:\n input_list: A list of elements.\n\n Returns:\n A tuple containing the same elements as the input list.\n \"\"\"\n return tuple(input_list)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(input_list):\n \"\"\"\n Converts a list to a tuple.\n\n Args:\n input_list: The list to be converted.\n\n Returns:\n A tuple containing the elements of the input list.\n \"\"\"\n return tuple(input_list)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n \"\"\"Converts a list to a tuple.\n\n Args:\n lst: A list.\n\n Returns:\n A tuple containing the same elements as the input list.\n \"\"\"\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(input_list):\n \"\"\"Converts a list to a tuple.\n\n Args:\n input_list: A list of values.\n\n Returns:\n A tuple containing the same values as the input list.\n \"\"\"\n return tuple(input_list)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n \"\"\"\n Converts a list to a tuple.\n\n Args:\n lst: A list of elements.\n\n Returns:\n A tuple containing the same elements as the input list.\n \"\"\"\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(my_list):\n \"\"\"Converts a list to a tuple.\n\n Args:\n my_list: A list of elements.\n\n Returns:\n A tuple containing the elements from the input list.\n \"\"\"\n return tuple(my_list)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n \"\"\"\n Converts a list to a tuple.\n \"\"\"\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n \"\"\"\n Converts a list to a tuple.\n\n Args:\n lst: A list of elements.\n\n Returns:\n A tuple containing the same elements as the input list.\n \"\"\"\n return tuple(lst)", "matching_cluster_idx": 3}]}, "Mbpp/588": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def big_diff(nums):\n \"\"\"\n Finds the difference between the largest and smallest value in a given list.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n The difference between the largest and smallest value in the list.\n \"\"\"\n if len(nums) < 2:\n return 0 \n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n \"\"\"\n This function finds the difference between the largest and smallest value in a given list.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n The difference between the largest and smallest value in the list.\n \"\"\"\n if len(nums) < 2:\n return 0 # Handle cases with less than two elements\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n \"\"\"\n Finds the difference between the largest and smallest values in a list.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n The difference between the largest and smallest values in the list.\n \"\"\"\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n \"\"\"\n Finds the difference between the largest and smallest value in a given list.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n The difference between the largest and smallest value in the list.\n \"\"\"\n if len(nums) < 2:\n return 0 # Handle cases with less than 2 elements\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n \"\"\"Finds the difference between the largest and smallest value in a given list.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n The difference between the largest and smallest value in the list.\n \"\"\"\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n \"\"\"\n Finds the difference between the largest and smallest value in a given list.\n Args:\n nums: A list of numbers.\n Returns:\n The difference between the largest and smallest value in the list.\n \"\"\"\n if len(nums) < 2:\n return 0 \n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n \"\"\"\n Finds the difference between the largest and smallest value in a given list.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n The difference between the largest and smallest value in the list.\n \"\"\"\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n \"\"\"\n Finds the difference between the largest and smallest values in a given list.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n The difference between the largest and smallest values in the list. \n \"\"\"\n if len(nums) < 2:\n return 0 # Handle cases with less than two elements\n else:\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n \"\"\"\n Finds the difference between the largest and smallest value in a given list.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n The difference between the largest and smallest value in the list.\n \"\"\"\n if len(nums) < 2:\n return 0 # Handle cases with less than two numbers\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n \"\"\"Finds the difference between the largest and smallest values in a given list.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n The difference between the largest and smallest values in the list.\n \"\"\"\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n \"\"\"\n Finds the difference between the largest and smallest value in a given list.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n The difference between the largest and smallest values in the list.\n \"\"\"\n if len(nums) < 2:\n return 0 # Handle cases with less than 2 elements\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n \"\"\"\n Finds the difference between the largest and smallest values in a list.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n The difference between the largest and smallest values in the list.\n \"\"\"\n if len(nums) < 2:\n return 0 \n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n \"\"\"\n Finds the difference between the largest and smallest value in a given list.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n The difference between the largest and smallest value in the list.\n \"\"\"\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n \"\"\"\n Finds the difference between the largest and smallest value in a given list.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n The difference between the largest and smallest value in the list.\n \"\"\"\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n \"\"\"\n This function finds the difference between the largest and smallest value in a given list.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n The difference between the largest and smallest value in the list.\n \"\"\"\n if len(nums) < 2:\n return 0 \n else:\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n \"\"\"\n Finds the difference between the largest and smallest value in a given list.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n The difference between the largest and smallest values in the list.\n \"\"\"\n if len(nums) < 2:\n return 0 \n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n \"\"\"\n This function finds the difference between the largest and smallest value in a given list.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n The difference between the largest and smallest value in the list.\n \"\"\"\n if len(nums) < 2:\n return 0 # Handle cases with less than two elements\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n \"\"\"\n Finds the difference between the largest and smallest value in a given list.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n The difference between the largest and smallest value in the list.\n \"\"\"\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n \"\"\"\n Finds the difference between the largest and smallest value in a given list.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n The difference between the largest and smallest value in the list.\n \"\"\"\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n \"\"\"\n Finds the difference between the largest and smallest value in a list.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n The difference between the largest and smallest value in the list.\n \"\"\"\n if len(nums) < 2:\n return 0 \n return max(nums) - min(nums)", "matching_cluster_idx": 5}]}, "Mbpp/592": {"dps": null, "dps_norm": null, "pass@1": 2.0, "profiled": []}, "Mbpp/597": {"dps": null, "dps_norm": null, "pass@1": 0.0, "profiled": []}, "Mbpp/604": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def reverse_words(text):\n \"\"\"Reverses words separated by spaces in a given string.\n\n Args:\n text: The input string.\n\n Returns:\n The string with the words reversed.\n \"\"\"\n words = text.split()\n return \" \".join(reversed(words))", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n \"\"\"\n Reverses words separated by spaces in a given string.\n\n Args:\n s: The input string.\n\n Returns:\n The string with words reversed.\n \"\"\"\n words = s.split()\n return \" \".join(words[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n \"\"\"\n Reverses words separated by spaces in a given string.\n\n Args:\n s: The input string.\n\n Returns:\n The string with words reversed.\n \"\"\"\n words = s.split()\n return ' '.join(words[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(text):\n \"\"\"\n Reverses the order of words in a string separated by spaces.\n\n Args:\n text: The string to reverse.\n\n Returns:\n The string with words reversed.\n \"\"\"\n words = text.split() \n return \" \".join(words[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s: str) -> str:\n \"\"\"\n Reverses the order of words in a string separated by spaces.\n\n Args:\n s (str): The input string.\n\n Returns:\n str: The string with words in reversed order.\n \"\"\"\n words = s.split()\n return ' '.join(words[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n \"\"\"\n Reverses words separated by spaces in a given string.\n\n Args:\n s: The input string.\n\n Returns:\n The string with the words reversed.\n \"\"\"\n words = s.split() \n return \" \".join(reversed(words))", "matching_cluster_idx": 4}, {"solution": "def reverse_words(text):\n \"\"\"\n Reverses words separated by spaces in a string.\n\n Args:\n text: The input string.\n\n Returns:\n The string with words reversed.\n \"\"\"\n words = text.split()\n return \" \".join(words[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(text):\n \"\"\"Reverses the order of words in a string separated by spaces.\n\n Args:\n text: The input string.\n\n Returns:\n The string with words reversed.\n \"\"\"\n words = text.split()\n return \" \".join(words[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(text):\n \"\"\"\n Reverses the order of words in a string.\n\n Args:\n text: The string to reverse the words in.\n\n Returns:\n The string with the words in reversed order.\n \"\"\"\n words = text.split()\n return \" \".join(reversed(words))", "matching_cluster_idx": 4}, {"solution": "def reverse_words(text):\n \"\"\"\n Reverses the order of words in a string separated by spaces.\n \"\"\"\n words = text.split()\n return \" \".join(words[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(text):\n \"\"\"Reverses words separated by spaces in a string.\n\n Args:\n text: The string to reverse.\n\n Returns:\n The string with words reversed.\n \"\"\"\n words = text.split()\n return \" \".join(reversed(words))", "matching_cluster_idx": 4}, {"solution": "def reverse_words(text):\n \"\"\"\n Reverses the order of words in a string.\n\n Args:\n text: The input string.\n\n Returns:\n The string with words reversed.\n \"\"\"\n words = text.split()\n return \" \".join(reversed(words))", "matching_cluster_idx": 4}, {"solution": "def reverse_words(text):\n \"\"\"Reverses words in a string separated by spaces.\n\n Args:\n text: The string to reverse.\n\n Returns:\n The string with the words reversed.\n \"\"\"\n words = text.split()\n return \" \".join(words[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(text):\n \"\"\"\n Reverses the order of words in a string separated by spaces.\n\n Args:\n text: The input string.\n\n Returns:\n The string with words reversed.\n \"\"\"\n words = text.split()\n return \" \".join(words[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(text):\n \"\"\"Reverses the words in a string separated by spaces.\n\n Args:\n text: The input string.\n\n Returns:\n The string with words reversed.\n \"\"\"\n words = text.split()\n return \" \".join(words[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n \"\"\"\n Reverses the order of words in a string.\n\n Args:\n s: The input string.\n\n Returns:\n The string with the words reversed.\n \"\"\"\n words = s.split()\n return \" \".join(reversed(words))", "matching_cluster_idx": 4}, {"solution": "def reverse_words(text):\n \"\"\"\n Reverses the order of words in a string separated by spaces.\n\n Args:\n text: The input string.\n\n Returns:\n The string with words reversed.\n \"\"\"\n words = text.split()\n return \" \".join(reversed(words))", "matching_cluster_idx": 4}, {"solution": "def reverse_words(text):\n \"\"\"Reverses words separated by spaces in a given string.\n\n Args:\n text: The input string.\n\n Returns:\n The string with words reversed.\n \"\"\"\n words = text.split()\n return \" \".join(words[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n \"\"\"\n Reverses words in a string separated by spaces.\n\n Args:\n s: The input string.\n\n Returns:\n The string with words reversed.\n \"\"\"\n return ' '.join(s.split()[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(text):\n \"\"\"\n Reverses the order of words in a string.\n\n Args:\n text: The string to reverse words in.\n\n Returns:\n The string with words reversed.\n \"\"\"\n words = text.split()\n return ' '.join(words[::-1])", "matching_cluster_idx": 4}]}, "Mbpp/610": {"dps": null, "dps_norm": null, "pass@1": 0.0, "profiled": []}, "Mbpp/611": {"dps": 95.1840490797546, "dps_norm": 98.33333333333333, "pass@1": 94.0, "profiled": [{"solution": "def max_of_nth(matrix, n):\n \"\"\"\n Finds the maximum value in the nth column of a matrix.\n\n Args:\n matrix: A list of lists representing the matrix.\n n: The index of the column (zero-based).\n\n Returns:\n The maximum value in the nth column.\n\n Raises:\n IndexError: If the column index is out of range.\n \"\"\"\n max_value = float('-inf') \n for row in matrix:\n if len(row) <= n:\n raise IndexError(\"Column index out of range\")\n max_value = max(max_value, row[n])\n return max_value", "matching_cluster_idx": 3}, {"solution": "def max_of_nth(matrix, n):\n \"\"\"\n Finds the maximum value in the nth column of a matrix.\n\n Args:\n matrix: A list of lists representing the matrix.\n n: The index of the column to find the maximum value in.\n\n Returns:\n The maximum value in the nth column.\n \"\"\"\n max_value = matrix[0][n] \n for row in matrix[1:]:\n if row[n] > max_value:\n max_value = row[n]\n return max_value", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n \"\"\"\n Given a matrix represented as a list of lists, returns the max of the n'th column.\n\n Args:\n matrix: A list of lists representing a matrix.\n n: The index of the column to find the maximum value in.\n\n Returns:\n The maximum value in the n'th column of the matrix.\n\n Raises:\n IndexError: If n is out of range.\n \"\"\"\n max_value = matrix[0][n]\n for row in matrix[1:]:\n if row[n] > max_value:\n max_value = row[n]\n return max_value", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n \"\"\"\n Given a matrix represented as a list of lists, returns the max of the n'th column.\n\n Args:\n matrix: A list of lists representing the matrix.\n n: The index of the column (0-indexed).\n\n Returns:\n The maximum value in the nth column.\n \"\"\"\n max_value = matrix[0][n]\n for row in matrix[1:]:\n if row[n] > max_value:\n max_value = row[n]\n return max_value", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n \"\"\"\n Finds the maximum value in the nth column of a matrix.\n\n Args:\n matrix: A list of lists representing a matrix.\n n: The index of the column (starting from 0).\n\n Returns:\n The maximum value in the nth column.\n \"\"\"\n max_value = matrix[0][n] # Initialize with the first element of the column\n for row in matrix:\n if row[n] > max_value:\n max_value = row[n]\n return max_value\nmatrix = [[5, 6, 7], [1, 3, 5], [8, 9, 19]]\nn = 2\nmax_value = max_of_nth(matrix, n)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n \"\"\"\n Given a matrix represented as a list of lists, return the max of the n'th column.\n\n Args:\n matrix: A list of lists representing the matrix.\n n: The index of the column (zero-based).\n\n Returns:\n The maximum value in the n'th column of the matrix.\n \"\"\"\n max_value = matrix[0][n] \n for row in matrix[1:]:\n if row[n] > max_value:\n max_value = row[n]\n return max_value", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n \"\"\"\n Given a matrix represented as a list of lists, returns the max of the n'th column.\n\n Args:\n matrix: A list of lists representing the matrix.\n n: The index of the column to find the maximum value in.\n\n Returns:\n The maximum value in the n'th column.\n \"\"\"\n max_value = matrix[0][n]\n for row in matrix[1:]:\n if row[n] > max_value:\n max_value = row[n]\n return max_value", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n \"\"\"\n Finds the maximum value in the nth column of a matrix.\n\n Args:\n matrix: A list of lists representing the matrix.\n n: The index of the column (zero-based).\n\n Returns:\n The maximum value in the nth column.\n \"\"\"\n max_value = matrix[0][n] \n for row in matrix[1:]:\n if row[n] > max_value:\n max_value = row[n]\n return max_value", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n \"\"\"\n Finds the maximum value in the nth column of a matrix.\n\n Args:\n matrix: A list of lists representing the matrix.\n n: The index of the column (zero-based).\n\n Returns:\n The maximum value in the nth column.\n \"\"\"\n max_value = matrix[0][n] \n for row in matrix:\n if row[n] > max_value:\n max_value = row[n]\n return max_value", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n \"\"\"\n Given a matrix represented as a list of lists returns the max of the n'th column.\n\n Args:\n matrix: A list of lists representing the matrix.\n n: The index of the column to find the maximum value in.\n\n Returns:\n The maximum value in the n'th column.\n\n Raises:\n IndexError: If n is out of bounds for the matrix.\n \"\"\"\n max_value = matrix[0][n]\n for row in matrix[1:]:\n if row[n] > max_value:\n max_value = row[n]\n return max_value", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n \"\"\"\n Given a matrix represented as a list of lists returns the max of the n'th column.\n \n Args:\n matrix: A list of lists representing the matrix.\n n: The index of the column (zero-based).\n \n Returns:\n The maximum value in the nth column of the matrix.\n \"\"\"\n max_value = matrix[0][n]\n for row in matrix[1:]:\n if row[n] > max_value:\n max_value = row[n]\n return max_value", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n \"\"\"\n Given a matrix represented as a list of lists, return the max of the n'th column.\n\n Args:\n matrix: A list of lists representing the matrix.\n n: The index of the column (zero-based)\n\n Returns:\n The maximum value in the nth column.\n \"\"\"\n max_value = matrix[0][n]\n for row in matrix[1:]:\n if row[n] > max_value:\n max_value = row[n]\n return max_value", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n \"\"\"\n Finds the maximum value in the nth column of a matrix.\n\n Args:\n matrix: A list of lists representing the matrix.\n n: The index of the column (0-based).\n\n Returns:\n The maximum value in the nth column.\n \"\"\"\n max_value = matrix[0][n] \n for row in matrix[1:]:\n max_value = max(max_value, row[n])\n return max_value", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n \"\"\"\n Finds the maximum value in the nth column of a matrix.\n\n Args:\n matrix: A list of lists representing the matrix.\n n: The index of the column (starting from 0).\n\n Returns:\n The maximum value in the nth column.\n \"\"\"\n max_value = matrix[0][n] \n for row in matrix[1:]:\n max_value = max(max_value, row[n])\n return max_value", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n \"\"\"\n Given a matrix represented as a list of lists, return the max of the n'th column.\n\n Args:\n matrix: A list of lists representing the matrix.\n n: The index of the column (zero-based).\n\n Returns:\n The maximum value in the nth column.\n\n Examples:\n max_of_nth([[5, 6, 7], [1, 3, 5], [8, 9, 19]], 2) == 19\n \"\"\"\n max_value = matrix[0][n]\n for i in range(1, len(matrix)):\n if matrix[i][n] > max_value:\n max_value = matrix[i][n]\n return max_value", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n \"\"\"\n Given a matrix represented as a list of lists returns the max of the n'th column.\n assert max_of_nth([[5, 6, 7], [1, 3, 5], [8, 9, 19]], 2) == 19\n \"\"\"\n max_value = matrix[0][n] \n for row in matrix:\n if row[n] > max_value:\n max_value = row[n]\n return max_value\nmatrix = [[5, 6, 7], [1, 3, 5], [8, 9, 19]]\nn = 2", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n \"\"\"\n Given a matrix represented as a list of lists, return the max of the n'th column.\n\n Args:\n matrix: A list of lists representing the matrix.\n n: The index of the column to find the maximum value in.\n\n Returns:\n The maximum value in the n'th column of the matrix.\n\n Raises:\n IndexError: If n is out of bounds for the matrix.\n \"\"\"\n max_value = matrix[0][n]\n for row in matrix:\n if row[n] > max_value:\n max_value = row[n]\n return max_value", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n \"\"\"\n Finds the maximum value in the nth column of a matrix.\n\n Args:\n matrix: A list of lists representing the matrix.\n n: The index of the column (starting from 0).\n\n Returns:\n The maximum value in the nth column.\n \"\"\"\n max_value = float('-inf') \n for row in matrix:\n if row[n] > max_value:\n max_value = row[n]\n return max_value", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n \"\"\"\n Given a matrix represented as a list of lists, returns the max of the n'th column.\n \n Args:\n matrix: A list of lists representing the matrix.\n n: The index of the column to find the maximum value in.\n\n Returns:\n The maximum value in the nth column of the matrix.\n \"\"\"\n max_value = matrix[0][n] \n for row in matrix[1:]:\n if row[n] > max_value:\n max_value = row[n]\n return max_value", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n \"\"\"\n Given a matrix represented as a list of lists, returns the max of the n'th column.\n\n Args:\n matrix: A list of lists representing the matrix.\n n: The index of the column (zero-indexed) to find the maximum value in.\n\n Returns:\n The maximum value in the nth column of the matrix.\n \"\"\"\n max_value = float('-inf') \n for row in matrix:\n if row[n] > max_value:\n max_value = row[n]\n return max_value", "matching_cluster_idx": 5}]}, "Mbpp/631": {"dps": null, "dps_norm": null, "pass@1": 2.0, "profiled": []}, "Mbpp/632": {"dps": 95.0093808630394, "dps_norm": 95.71428571428571, "pass@1": 95.0, "profiled": [{"solution": "def move_zero(nums):\n \"\"\"\n Moves all zeroes to the end of the given list.\n\n Args:\n nums: A list of integers.\n\n Returns:\n The list with all zeroes moved to the end.\n \"\"\"\n non_zero_index = 0\n for i in range(len(nums)):\n if nums[i] != 0:\n nums[non_zero_index], nums[i] = nums[i], nums[non_zero_index]\n non_zero_index += 1\n return nums", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n \"\"\"\n Moves all zeroes to the end of a list while preserving order of other elements.\n\n Args:\n nums: A list of integers.\n\n Returns:\n The modified list with zeroes moved to the end.\n \"\"\"\n non_zero_index = 0 \n for i in range(len(nums)):\n if nums[i] != 0:\n nums[non_zero_index] = nums[i]\n non_zero_index += 1\n \n while non_zero_index < len(nums):\n nums[non_zero_index] = 0\n non_zero_index += 1\n \n return nums", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n \"\"\"\n Moves all zeroes to the end of the given list.\n \"\"\"\n non_zero_index = 0\n for i in range(len(nums)):\n if nums[i] != 0:\n nums[non_zero_index] = nums[i]\n non_zero_index += 1\n while non_zero_index < len(nums):\n nums[non_zero_index] = 0\n non_zero_index += 1\n return nums", "matching_cluster_idx": 6}, {"solution": "def move_zero(arr):\n \"\"\"\n Moves all zeroes to the end of the given list.\n\n Args:\n arr: A list of integers.\n\n Returns:\n A new list with all zeroes moved to the end.\n \"\"\"\n non_zero_elements = [x for x in arr if x != 0]\n return non_zero_elements + [0] * arr.count(0)", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n \"\"\"\n Moves all zeroes to the end of the given list.\n\n Args:\n nums: A list of integers.\n\n Returns:\n The list with all zeroes moved to the end.\n \"\"\"\n non_zero_index = 0\n for i in range(len(nums)):\n if nums[i] != 0:\n nums[non_zero_index] = nums[i]\n non_zero_index += 1\n for i in range(non_zero_index, len(nums)):\n nums[i] = 0\n return nums", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n \"\"\"Moves all zeroes to the end of the given list.\n\n Args:\n nums: A list of integers.\n\n Returns:\n The modified list with zeroes moved to the end.\n \"\"\"\n non_zero_index = 0 \n for i in range(len(nums)):\n if nums[i] != 0:\n nums[non_zero_index] = nums[i]\n non_zero_index += 1\n for i in range(non_zero_index, len(nums)):\n nums[i] = 0\n return nums", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n \"\"\"Moves all zeroes to the end of a given list.\n\n Args:\n nums: A list of integers.\n\n Returns:\n The list with zeroes moved to the end.\n \"\"\"\n non_zero_indices = [i for i, x in enumerate(nums) if x != 0]\n return [nums[i] for i in non_zero_indices] + [nums[i] for i in range(len(nums)) if i not in non_zero_indices]", "matching_cluster_idx": 0}, {"solution": "def move_zero(nums):\n \"\"\"\n Moves all zeroes to the end of the given list.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n The list with all zeroes moved to the end.\n \"\"\"\n non_zeroes = []\n for num in nums:\n if num != 0:\n non_zeroes.append(num)\n return non_zeroes + [0] * nums.count(0)", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n \"\"\"\n Moves all zeroes to the end of a given list.\n\n Args:\n nums: A list of integers.\n\n Returns:\n The list with all zeroes moved to the end.\n \"\"\"\n\n non_zero_index = 0\n for i in range(len(nums)):\n if nums[i] != 0:\n nums[non_zero_index] = nums[i]\n non_zero_index += 1\n while non_zero_index < len(nums):\n nums[non_zero_index] = 0\n non_zero_index += 1\n return nums", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n \"\"\"Moves all zeroes to the end of a list.\n\n Args:\n nums: A list of integers.\n\n Returns:\n A new list with all zeroes moved to the end.\n \"\"\"\n non_zero_nums = []\n for num in nums:\n if num != 0:\n non_zero_nums.append(num)\n non_zero_nums.extend([0] * nums.count(0))\n return non_zero_nums", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n \"\"\"\n Moves all zeroes to the end of the given list.\n\n Args:\n nums: A list of integers.\n\n Returns:\n The list with zeroes moved to the end while maintaining the order of non-zero elements.\n \"\"\"\n non_zero_index = 0\n for i in range(len(nums)):\n if nums[i] != 0:\n nums[non_zero_index] = nums[i]\n non_zero_index += 1\n while non_zero_index < len(nums):\n nums[non_zero_index] = 0\n non_zero_index += 1\n return nums", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n \"\"\"\n Moves all zeroes to the end of the given list.\n\n Args:\n nums: A list of integers.\n\n Returns:\n The modified list with zeroes moved to the end.\n \"\"\"\n non_zero_index = 0\n for i in range(len(nums)):\n if nums[i] != 0:\n nums[non_zero_index], nums[i] = nums[i], nums[non_zero_index]\n non_zero_index += 1\n return nums", "matching_cluster_idx": 6}, {"solution": "def move_zero(arr):\n \"\"\"\n Moves all zeroes to the end of the given list.\n \n Args:\n arr: A list of integers.\n \n Returns:\n A new list with zeroes moved to the end.\n \"\"\"\n non_zero_elements = []\n zero_elements = []\n for element in arr:\n if element != 0:\n non_zero_elements.append(element)\n else:\n zero_elements.append(element)\n return non_zero_elements + zero_elements", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n \"\"\"\n Moves all zeroes to the end of the given list.\n\n Args:\n nums: A list of integers.\n\n Returns:\n The list with all zeroes moved to the end.\n \"\"\"\n non_zero_index = 0\n for i in range(len(nums)):\n if nums[i] != 0:\n nums[non_zero_index] = nums[i]\n non_zero_index += 1\n while non_zero_index < len(nums):\n nums[non_zero_index] = 0\n non_zero_index += 1\n return nums", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n \"\"\"\n Moves all zeroes to the end of the given list.\n \n Args:\n nums: A list of integers.\n\n Returns:\n A new list with all zeroes moved to the end.\n \"\"\"\n non_zero_nums = []\n for num in nums:\n if num != 0:\n non_zero_nums.append(num)\n return non_zero_nums + [0] * nums.count(0)", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n \"\"\"\n Moves all zeroes to the end of the given list while preserving the order of other elements.\n\n Args:\n nums: A list of integers.\n\n Returns:\n The modified list with zeroes moved to the end.\n \"\"\"\n non_zero_index = 0\n for i in range(len(nums)):\n if nums[i] != 0:\n nums[non_zero_index], nums[i] = nums[i], nums[non_zero_index]\n non_zero_index += 1\n return nums", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n \"\"\"\n Moves all zeroes to the end of the given list while maintaining the relative order of other elements.\n\n Args:\n nums: A list of integers.\n\n Returns:\n The list with zeroes moved to the end.\n \"\"\"\n result = []\n non_zero_count = 0\n for num in nums:\n if num != 0:\n result.append(num)\n non_zero_count += 1\n for _ in range(len(nums) - non_zero_count):\n result.append(0)\n return result", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n \"\"\"\n Moves all zeroes to the end of the given list.\n \"\"\"\n non_zero_index = 0 \n for i in range(len(nums)):\n if nums[i] != 0:\n nums[non_zero_index] = nums[i] \n non_zero_index += 1\n while non_zero_index < len(nums):\n nums[non_zero_index] = 0\n non_zero_index += 1\n return nums", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n \"\"\"\n Moves all zeroes to the end of the given list.\n \n Args:\n nums: A list of integers.\n \n Returns:\n The modified list with all zeroes moved to the end.\n \"\"\"\n non_zero_index = 0 \n for i in range(len(nums)):\n if nums[i] != 0:\n nums[non_zero_index] = nums[i]\n non_zero_index += 1\n for i in range(non_zero_index, len(nums)):\n nums[i] = 0\n return nums", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n \"\"\"\n Moves all zeroes to the end of the given list.\n\n Args:\n nums: A list of integers.\n\n Returns:\n The list with all zeroes moved to the end.\n \"\"\"\n non_zero_index = 0\n for i in range(len(nums)):\n if nums[i] != 0:\n nums[non_zero_index] = nums[i]\n non_zero_index += 1\n while non_zero_index < len(nums):\n nums[non_zero_index] = 0\n non_zero_index += 1\n return nums", "matching_cluster_idx": 6}]}, "Mbpp/633": {"dps": 94.3089430894309, "dps_norm": 50.0, "pass@1": 19.0, "profiled": [{"solution": "def pair_xor_Sum(nums, n):\n \"\"\"\n Finds the sum of XOR of all pairs of numbers in the given list.\n\n Args:\n nums: A list of integers.\n n: The length of the list.\n\n Returns:\n The sum of XOR of all pairs of numbers in the list.\n\n Example:\n pair_xor_Sum([5,9,7,6],4) == 47\n \"\"\"\n sum = 0\n for i in range(n):\n for j in range(i+1, n):\n sum += nums[i] ^ nums[j]\n return sum\nnums = [5, 9, 7, 6]\nn = len(nums)", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(nums, n):\n \"\"\"\n Finds the sum of xor of all pairs of numbers in the given list.\n\n Args:\n nums: A list of integers.\n n: The number of elements to consider from the list.\n\n Returns:\n The sum of xor of all pairs of numbers in the list.\n\n Raises:\n ValueError: If n is greater than the length of the list.\n\n \"\"\"\n if n > len(nums):\n raise ValueError(\"n cannot be greater than the length of the list.\")\n\n xor_sum = 0\n for i in range(n):\n for j in range(i+1, n):\n xor_sum += nums[i] ^ nums[j] \n return xor_sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(nums, n):\n \"\"\"\n Finds the sum of XOR of all pairs of numbers in the given list.\n\n Args:\n nums: A list of integers.\n n: The length of the input list.\n\n Returns:\n The sum of XOR of all pairs of numbers in the list.\n \"\"\"\n xor_sum = 0\n for i in range(n):\n for j in range(i + 1, n):\n xor_sum += nums[i] ^ nums[j]\n return xor_sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(nums, n):\n \"\"\"\n Finds the sum of XOR of all pairs of numbers in the given list.\n \n Args:\n nums: A list of integers.\n n: The number of elements to consider (used for slicing the list if it's longer).\n \n Returns:\n The sum of XOR of all pairs of numbers.\n \"\"\"\n total_xor_sum = 0\n for i in range(n):\n for j in range(i + 1, n):\n total_xor_sum += nums[i] ^ nums[j]\n return total_xor_sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(nums, n):\n \"\"\"\n Finds the sum of xor of all pairs of numbers in the given list.\n\n Args:\n nums: A list of integers.\n n: The size of the list.\n\n Returns:\n The sum of xor of all pairs of numbers in the list.\n \"\"\"\n sum_xor = 0\n for i in range(n):\n for j in range(i+1, n):\n sum_xor += nums[i] ^ nums[j]\n return sum_xor\nnums = [5,9,7,6]\nn = len(nums)", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(nums, n):\n \"\"\"\n Calculates the sum of XOR of all pairs of numbers in a list.\n\n Args:\n nums: A list of integers.\n n: The length of the list.\n\n Returns:\n The sum of XOR of all pairs of numbers in the list.\n \"\"\"\n sum = 0\n for i in range(n):\n for j in range(i+1, n):\n sum += nums[i] ^ nums[j]\n return sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(nums, n):\n \"\"\"\n Finds the sum of xor of all pairs of numbers in the given list.\n\n Args:\n nums: A list of numbers.\n n: An integer representing the size of the list.\n\n Returns:\n The sum of xor of all pairs of numbers in the list.\n\n Example:\n pair_xor_Sum([5,9,7,6],4) == 47\n \"\"\"\n\n sum = 0\n for i in range(n):\n for j in range(i+1, n):\n sum += nums[i] ^ nums[j]\n return sum\nnums = [5,9,7,6]\nn = len(nums)", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(nums, n):\n \"\"\"\n Finds the sum of xor of all pairs of numbers in the given list.\n\n Args:\n nums: A list of integers.\n n: The length of the list.\n\n Returns:\n The sum of xor of all pairs of numbers in the list.\n \"\"\"\n xor_sum = 0\n for i in range(n):\n for j in range(i + 1, n):\n xor_sum += nums[i] ^ nums[j]\n return xor_sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(arr, n):\n \"\"\"\n Finds the sum of XOR of all pairs of numbers in the given list.\n\n Args:\n arr: The list of numbers.\n n: The size of the list.\n\n Returns:\n The sum of XOR of all pairs of numbers in the list.\n \"\"\"\n sum = 0\n for i in range(n):\n for j in range(i+1, n):\n sum += arr[i] ^ arr[j]\n return sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(arr, n):\n \"\"\"\n Find the sum of xor of all pairs of numbers in the given list.\n\n Args:\n arr: A list of numbers.\n n: The size of the list.\n\n Returns:\n The sum of xor of all pairs of numbers in the list.\n \"\"\"\n sum = 0\n for i in range(n):\n for j in range(i + 1, n):\n sum += arr[i] ^ arr[j]\n return sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(nums, n):\n \"\"\"\n Finds the sum of XOR of all pairs of numbers in the given list.\n\n Args:\n nums: A list of integers.\n n: The length of the list.\n\n Returns:\n The sum of XOR of all pairs of numbers in the list.\n \"\"\"\n xor_sum = 0\n for i in range(n):\n for j in range(i+1, n):\n xor_sum += nums[i] ^ nums[j]\n return xor_sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(nums, n):\n \"\"\"\n Finds the sum of XOR of all pairs of numbers in the given list.\n\n Args:\n nums: A list of integers.\n n: An integer representing the size of the list.\n\n Returns:\n The sum of XOR of all pairs of numbers in the list.\n \"\"\"\n\n sum = 0\n for i in range(n):\n for j in range(i+1, n):\n sum += nums[i] ^ nums[j]\n return sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(arr, n):\n \"\"\"\n This function calculates the sum of XOR of all pairs of numbers in the given list.\n\n Args:\n arr: A list of integers.\n n: The length of the list.\n\n Returns:\n The sum of XOR of all pairs in the list.\n \"\"\"\n\n xor_sum = 0\n for i in range(n):\n for j in range(i + 1, n):\n xor_sum += arr[i] ^ arr[j]\n return xor_sum\narr = [5, 9, 7, 6]\nn = len(arr)", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(nums, n):\n \"\"\"\n Finds the sum of xor of all pairs of numbers in the given list.\n\n Args:\n nums: A list of integers.\n n: The size of the list.\n\n Returns:\n The sum of xor of all pairs of numbers in the list.\n \"\"\"\n sum = 0\n for i in range(n):\n for j in range(i+1, n):\n sum += nums[i] ^ nums[j]\n return sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(nums, n):\n \"\"\"\n Find the sum of xor of all pairs of numbers in the given list.\n\n Args:\n nums: A list of integers.\n n: An integer representing the size of the list.\n\n Returns:\n The sum of xor of all pairs of numbers in the list.\n \"\"\"\n\n sum = 0\n for i in range(n):\n for j in range(i + 1, n):\n sum += nums[i] ^ nums[j]\n return sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(nums, n):\n \"\"\"\n Finds the sum of XOR of all pairs of numbers in the given list.\n\n Args:\n nums: A list of integers.\n n: The size of the list.\n\n Returns:\n The sum of XOR of all pairs of numbers in the list.\n \"\"\"\n\n sum = 0\n for i in range(n):\n for j in range(i+1, n):\n sum += nums[i] ^ nums[j]\n return sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(arr, n):\n \"\"\"\n Finds the sum of XOR of all pairs of numbers in the given list.\n\n Args:\n arr: A list of integers.\n n: An integer, representing the length of the list.\n\n Returns:\n An integer representing the sum of XOR of all pairs.\n \"\"\"\n sum_xor = 0\n for i in range(n):\n for j in range(i + 1, n):\n sum_xor += arr[i] ^ arr[j]\n return sum_xor\narr = [5, 9, 7, 6]\nn = len(arr)", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(arr,n):\n \"\"\"\n Calculates the sum of XOR of all pairs of numbers in a list.\n\n Args:\n arr: A list of integers.\n n: An integer representing the size of the list.\n\n Returns:\n The sum of XOR of all pairs of numbers in the list.\n \"\"\"\n sum = 0\n for i in range(n):\n for j in range(i+1,n):\n sum += arr[i] ^ arr[j]\n return sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(nums, n):\n \"\"\"\n Calculates the sum of XOR of all pairs of numbers in a list.\n\n Args:\n nums: A list of integers.\n n: The size of the list.\n\n Returns:\n The sum of XOR of all pairs of numbers in the list.\n\n \"\"\"\n sum = 0\n for i in range(n):\n for j in range(i+1, n):\n sum += nums[i] ^ nums[j]\n return sum", "matching_cluster_idx": 2}]}, "Mbpp/644": {"dps": 91.6223404255319, "dps_norm": 90.33333333333333, "pass@1": 83.0, "profiled": [{"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n Reverses an array up to a given position.\n\n Args:\n arr: The input array.\n k: The position up to which the array should be reversed.\n\n Returns:\n The reversed array.\n \"\"\"\n arr[:k] = arr[:k][::-1]\n return arr", "matching_cluster_idx": 13}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n Reverses an array upto a given position.\n\n Args:\n arr: The array to reverse.\n k: The position up to which to reverse the array.\n\n Returns:\n The reversed array.\n \"\"\"\n arr[:k] = arr[:k][::-1] \n return arr", "matching_cluster_idx": 13}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"Reverses an array up to a given position.\n\n Args:\n arr: The array to be reversed.\n k: The position up to which the array should be reversed.\n\n Returns:\n The reversed array.\n \"\"\"\n arr[:k] = arr[:k][::-1]\n return arr", "matching_cluster_idx": 13}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n Reverses an array up to a given position.\n\n Args:\n arr: The array to be reversed.\n k: The position up to which the array should be reversed.\n\n Returns:\n The reversed array.\n\n Examples:\n reverse_Array_Upto_K([1, 2, 3, 4, 5, 6],4) == [4, 3, 2, 1, 5, 6]\n \"\"\"\n arr[:k] = arr[:k][::-1] \n return arr\nk = 4", "matching_cluster_idx": 13}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n Reverses an array upto a given position.\n\n Args:\n arr: The input array.\n k: The position upto which the array should be reversed.\n\n Returns:\n The reversed array.\n \"\"\"\n arr[:k] = arr[:k][::-1] \n return arr", "matching_cluster_idx": 13}, {"solution": "def reverse_Array_Upto_K(arr,k):\n \"\"\"\n Reverses an array up to a given position.\n\n Args:\n arr: The input array.\n k: The position up to which to reverse the array.\n\n Returns:\n The reversed array.\n \"\"\"\n arr[:k] = arr[:k][::-1]\n return arr", "matching_cluster_idx": 13}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"Reverses an array up to a given position.\n\n Args:\n arr: The array to be reversed.\n k: The position up to which the array should be reversed.\n\n Returns:\n The reversed array.\n \"\"\"\n arr[:k] = arr[:k][::-1]\n return arr", "matching_cluster_idx": 13}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n Reverses an array upto a given position.\n\n Args:\n arr: The array to reverse.\n k: The position up to which the array should be reversed.\n\n Returns:\n The reversed array.\n \"\"\"\n arr[:k] = arr[:k][::-1]\n return arr", "matching_cluster_idx": 13}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n Reverses an array up to a given position.\n\n Args:\n arr: The input array.\n k: The position up to which the array should be reversed.\n\n Returns:\n The reversed array.\n \"\"\"\n \n left = 0\n right = k - 1 \n while left < right:\n arr[left], arr[right] = arr[right], arr[left]\n left += 1\n right -= 1\n return arr", "matching_cluster_idx": 7}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n Reverses an array up to a given position.\n\n Args:\n arr: The input array.\n k: The position up to which the array should be reversed.\n\n Returns:\n The reversed array.\n \"\"\"\n arr[:k] = arr[:k][::-1]\n return arr", "matching_cluster_idx": 13}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n Reverses an array up to a given position.\n\n Args:\n arr: The array to be reversed.\n k: The position up to which the array should be reversed.\n\n Returns:\n The reversed array.\n \"\"\"\n arr[:k] = arr[:k][::-1] \n return arr", "matching_cluster_idx": 13}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n Reverses an array up to a given position.\n\n Args:\n arr: The array to be reversed.\n k: The position up to which the array should be reversed.\n\n Returns:\n The reversed array.\n \"\"\"\n arr[:k] = arr[:k][::-1] \n return arr", "matching_cluster_idx": 13}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n Reverses an array upto a given position.\n \n Args:\n arr: The array to be reversed.\n k: The position (index) up to which the array should be reversed.\n \n Returns:\n The reversed array.\n\n \"\"\"\n arr[:k] = arr[:k][::-1]\n return arr", "matching_cluster_idx": 13}, {"solution": "def reverse_Array_Upto_K(arr,k):\n \"\"\"\n Reverses an array upto a given position.\n \"\"\"\n arr[:k] = arr[:k][::-1]\n return arr", "matching_cluster_idx": 13}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n Reverses an array up to a given position.\n\n Args:\n arr: The input array.\n k: The position up to which the array should be reversed.\n\n Returns:\n The modified array with elements reversed up to the given position.\n \"\"\"\n arr[:k] = arr[:k][::-1]\n return arr", "matching_cluster_idx": 13}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n Reverses an array up to a given position.\n\n Args:\n arr (list): The input array.\n k (int): The position up to which the array should be reversed.\n\n Returns:\n list: The modified array with elements reversed up to the given position.\n \"\"\"\n \n arr[:k] = arr[:k][::-1]\n return arr", "matching_cluster_idx": 13}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n Reverses an array up to a given position.\n\n Args:\n arr: The array to be reversed.\n k: The position up to which the array should be reversed.\n\n Returns:\n The reversed array.\n \"\"\"\n return arr[:k][::-1] + arr[k:]\nk = 4", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n Reverses an array up to a given position.\n\n Args:\n arr: The input array.\n k: The position up to which the array should be reversed.\n\n Returns:\n The reversed array.\n \"\"\"\n arr[:k] = arr[:k][::-1]\n return arr\nk = 4", "matching_cluster_idx": 13}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n Reverses an array upto a given position.\n\n Args:\n arr: The array to reverse.\n k: The position up to which the array should be reversed.\n\n Returns:\n The reversed array.\n \"\"\"\n arr[:k] = arr[:k][::-1]\n return arr", "matching_cluster_idx": 13}, {"solution": "def reverse_Array_Upto_K(nums, k):\n \"\"\"\n Reverses an array up to a given position.\n\n Args:\n nums: The array to be reversed.\n k: The position (index) up to which to reverse the array.\n\n Returns:\n The reversed array.\n \"\"\"\n nums[:k] = nums[:k][::-1] \n return nums", "matching_cluster_idx": 13}]}, "Mbpp/720": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def add_dict_to_tuple(tup, dictionary):\n \"\"\"\n Adds a dictionary to the tuple.\n\n Args:\n tup: The tuple to add the dictionary to.\n dictionary: The dictionary to add to the tuple.\n\n Returns:\n A tuple containing all elements of the original tuple and the dictionary.\n \"\"\"\n return tup + (dictionary,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(input_tuple, input_dict):\n \"\"\"Adds a dictionary to the end of a tuple.\n\n Args:\n input_tuple: The tuple to modify.\n input_dict: The dictionary to add.\n\n Returns:\n A new tuple containing the original tuple and the dictionary.\n \"\"\"\n return input_tuple + (input_dict,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(tup, dict_):\n \"\"\"\n Adds a dictionary to the end of a tuple.\n\n Args:\n tup: The input tuple.\n dict_: The dictionary to add.\n\n Returns:\n A new tuple with the dictionary appended.\n \"\"\"\n return tup + (dict_,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(tp, dic):\n \"\"\"\n Adds a dictionary to a tuple.\n Args:\n tp: The input tuple.\n dic: The input dictionary.\n Returns:\n A new tuple containing the original tuple elements and the dictionary.\n \"\"\"\n return tp + (dic,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(tp, dictionary):\n \"\"\"\n Adds a dictionary to the end of a tuple.\n\n Args:\n tp: The input tuple.\n dictionary: The dictionary to add.\n\n Returns:\n A new tuple with the dictionary appended.\n \"\"\"\n return tp + (dictionary,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(tp, dic):\n \"\"\"\n Adds a dictionary to the end of a tuple.\n\n Args:\n tp: A tuple.\n dic: A dictionary.\n\n Returns:\n A new tuple containing all elements of the input tuple, followed by the input dictionary.\n \"\"\"\n return tp + (dic,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(tup, dictionary):\n \"\"\"\n Adds a dictionary to a tuple.\n \n Args:\n tup: The tuple to add the dictionary to.\n dictionary: The dictionary to add.\n \n Returns:\n A new tuple containing the original tuple and the dictionary.\n \"\"\"\n return tup + (dictionary,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(tp, dictionary):\n \"\"\"\n Adds a dictionary to the tuple.\n\n Args:\n tp: The tuple.\n dictionary: The dictionary.\n\n Returns:\n A tuple containing the original tuple elements followed by the dictionary.\n \"\"\"\n return tp + (dictionary,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(tuple1, dictionary1):\n \"\"\"Adds a dictionary to the end of a tuple.\n\n Args:\n tuple1: The input tuple.\n dictionary1: The input dictionary.\n\n Returns:\n A tuple with the original tuple elements followed by the dictionary.\n \"\"\"\n return tuple1 + (dictionary1,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(tp, dict1):\n \"\"\"\n Adds a dictionary to the end of a tuple.\n\n Args:\n tp (tuple): The input tuple.\n dict1 (dict): The dictionary to add.\n\n Returns:\n tuple: The tuple with the dictionary added.\n \"\"\"\n return tp + (dict1,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(tp, dictionary):\n \"\"\"\n Adds a dictionary to the end of a tuple.\n\n Args:\n tp: The tuple to add the dictionary to.\n dictionary: The dictionary to add.\n\n Returns:\n A new tuple with the dictionary appended.\n \"\"\"\n return tp + (dictionary,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(tup, dictionary):\n \"\"\"\n This function adds a dictionary to the end of a tuple.\n Args:\n tup: The input tuple.\n dictionary: The dictionary to be added.\n Returns:\n A new tuple with the dictionary appended.\n \"\"\"\n return tup + (dictionary,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(tup, dict):\n \"\"\"Adds a dictionary to the end of a tuple.\n\n Args:\n tup: The input tuple.\n dict: The dictionary to add.\n\n Returns:\n A tuple with the original tuple and the dictionary added.\n \"\"\"\n return tup + (dict,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(tp, dictionary):\n \"\"\"\n Adds a dictionary to the end of a tuple.\n\n Args:\n tp: The tuple to which the dictionary will be added.\n dictionary: The dictionary to add.\n\n Returns:\n A new tuple containing all elements of the input tuple followed by the input dictionary.\n \"\"\"\n return tp + (dictionary,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(tup, dictionary):\n \"\"\"\n Adds a dictionary to the end of a tuple.\n\n Args:\n tup: The tuple to add the dictionary to.\n dictionary: The dictionary to add to the tuple.\n\n Returns:\n A new tuple with the dictionary appended.\n \"\"\"\n return tup + (dictionary,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(tuple1, dictionary1):\n \"\"\"\n Adds a dictionary to the tuple.\n The output should be a tuple.\n\n Args:\n tuple1: The input tuple.\n dictionary1: The input dictionary.\n\n Returns:\n A tuple with the original tuple elements and the dictionary.\n \"\"\"\n return tuple1 + (dictionary1,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(tp, d):\n \"\"\"\n This function takes a tuple and a dictionary as input\n and returns a new tuple with the dictionary appended.\n \"\"\"\n return tp + (d,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(tp, dic):\n \"\"\"\n This function adds a dictionary to the tuple.\n\n Args:\n tp: A tuple.\n dic: A dictionary.\n\n Returns:\n A new tuple containing the original tuple and the dictionary.\n \"\"\"\n return tp + (dic,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(tpl, dictionary):\n \"\"\"\n Adds a dictionary to the end of a tuple.\n\n Args:\n tpl: The input tuple.\n dictionary: The dictionary to add.\n\n Returns:\n A new tuple containing the original tuple elements followed by the dictionary.\n \"\"\"\n return tpl + (dictionary,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(tp, dictionary):\n \"\"\"\n Adds a dictionary to the tuple.\n\n Args:\n tp: A tuple.\n dictionary: A dictionary.\n\n Returns:\n A tuple with the dictionary appended.\n \"\"\"\n return tp + (dictionary,)", "matching_cluster_idx": 4}]}, "Mbpp/725": {"dps": 33.19672131147541, "dps_norm": 38.75, "pass@1": 39.0, "profiled": [{"solution": "def extract_quotation(text):\n \"\"\"\n Extracts values between quotation marks \" \" from a given string.\n\n Args:\n text (str): The input string.\n\n Returns:\n list: A list of strings extracted between quotation marks.\n \"\"\"\n result = []\n current_quote = ''\n in_quotes = False\n for char in text:\n if char == '\"':\n in_quotes = not in_quotes\n if in_quotes:\n current_quote += char\n else:\n result.append(current_quote[1:]) # Remove the initial quote\n current_quote = ''\n elif in_quotes:\n current_quote += char\n return result", "matching_cluster_idx": 2}, {"solution": "def extract_quotation(text):\n \"\"\"\n Extracts values between quotation marks \" \" of the given string.\n\n Args:\n text: The input string.\n\n Returns:\n A list of strings extracted between quotation marks.\n \"\"\"\n result = []\n start = 0\n in_quotes = False\n for i, char in enumerate(text):\n if char == '\"':\n if not in_quotes:\n in_quotes = True\n start = i + 1\n else:\n in_quotes = False\n result.append(text[start:i])\n return result", "matching_cluster_idx": 2}, {"solution": "import re\ndef extract_quotation(text):\n \"\"\"\n Extracts values between quotation marks \" \" of the given string.\n\n Args:\n text: The input string.\n\n Returns:\n A list of strings extracted between quotation marks.\n \"\"\"\n return re.findall(r'\"([^\"]*)\"', text)", "matching_cluster_idx": 5}, {"solution": "def extract_quotation(text):\n \"\"\"\n Extracts values between quotation marks \" \" of the given string.\n\n Args:\n text: The input string.\n\n Returns:\n A list of strings extracted between quotation marks.\n \"\"\"\n result = []\n start = 0\n in_quotes = False\n for i, char in enumerate(text):\n if char == '\"' and not in_quotes:\n in_quotes = True\n start = i + 1\n elif char == '\"' and in_quotes:\n in_quotes = False\n result.append(text[start:i])\n return result", "matching_cluster_idx": 1}, {"solution": "def extract_quotation(text):\n \"\"\"\n Extracts values between quotation marks \" \" of the given string.\n\n Args:\n text: The input string.\n\n Returns:\n A list of strings extracted between quotation marks.\n \"\"\"\n result = []\n current_quote = \"\"\n in_quote = False\n for char in text:\n if char == '\"':\n in_quote = not in_quote\n if in_quote:\n current_quote += char\n else:\n result.append(current_quote[1:]) \n current_quote = \"\"\n else:\n if in_quote:\n current_quote += char\n return result", "matching_cluster_idx": 2}, {"solution": "def extract_quotation(text):\n \"\"\"\n Extracts values between quotation marks \" \" of the given string.\n\n Args:\n text: The input string.\n\n Returns:\n A list of strings extracted between quotation marks.\n \"\"\"\n result = []\n start = 0\n in_quotes = False\n for i, char in enumerate(text):\n if char == '\"':\n if not in_quotes:\n start = i + 1\n in_quotes = True\n else:\n result.append(text[start:i])\n in_quotes = False\n \n return result", "matching_cluster_idx": 2}, {"solution": "def extract_quotation(text):\n \"\"\"\n Extracts values between quotation marks \" \" of the given string.\n\n Args:\n text: The input string.\n\n Returns:\n A list of strings extracted between quotation marks.\n \"\"\"\n result = []\n in_quotes = False\n current_value = \"\"\n for char in text:\n if char == '\"':\n in_quotes = not in_quotes\n if in_quotes:\n current_value = \"\"\n else:\n result.append(current_value)\n elif in_quotes:\n current_value += char\n return result", "matching_cluster_idx": 2}, {"solution": "def extract_quotation(text):\n \"\"\"\n Extracts values between quotation marks \" \" of the given string.\n\n Args:\n text: The input string.\n\n Returns:\n A list of strings extracted from the input string, between quotation marks.\n \"\"\"\n result = []\n start = 0\n in_quotes = False\n for i, char in enumerate(text):\n if char == '\"' and not in_quotes:\n in_quotes = True\n start = i + 1\n elif char == '\"' and in_quotes:\n in_quotes = False\n result.append(text[start:i])\n return result", "matching_cluster_idx": 1}, {"solution": "def extract_quotation(text):\n \"\"\"\n Extracts values between quotation marks \" \" of the given string.\n\n Args:\n text: The input string.\n\n Returns:\n A list of strings extracted from the input string.\n \"\"\"\n result = []\n start = -1\n for i, char in enumerate(text):\n if char == '\"':\n if start == -1:\n start = i + 1\n else:\n result.append(text[start:i])\n start = -1\n return result", "matching_cluster_idx": 2}, {"solution": "import re\ndef extract_quotation(text):\n \"\"\"Extracts values between quotation marks \" \" of the given string.\n\n Args:\n text: The input string.\n\n Returns:\n A list of strings extracted from the input string, \n each representing a value enclosed in quotation marks.\n \"\"\"\n return re.findall(r'\"([^\"]*)\"', text)", "matching_cluster_idx": 6}, {"solution": "def extract_quotation(text):\n \"\"\"\n Extracts values between quotation marks \" \" from a string.\n\n Args:\n text: The input string.\n\n Returns:\n A list of strings extracted from quotation marks.\n \"\"\"\n result = []\n start = 0\n in_quotes = False\n for i, char in enumerate(text):\n if char == '\"':\n if not in_quotes:\n start = i + 1\n in_quotes = True\n else:\n result.append(text[start:i])\n in_quotes = False\n \n return result", "matching_cluster_idx": 2}, {"solution": "def extract_quotation(text):\n \"\"\"\n Extracts values between quotation marks \" \" of the given string.\n\n Args:\n text: The input string.\n\n Returns:\n A list of strings extracted from the input string.\n \"\"\"\n result = []\n start = 0\n in_quotes = False\n for i, char in enumerate(text):\n if char == '\"' and not in_quotes:\n in_quotes = True\n start = i + 1\n elif char == '\"' and in_quotes:\n in_quotes = False\n result.append(text[start:i])\n return result", "matching_cluster_idx": 1}, {"solution": "def extract_quotation(text):\n \"\"\"\n Extracts values between quotation marks \" \" of the given string.\n\n Args:\n text: The input string.\n\n Returns:\n A list of strings extracted between quotation marks.\n \"\"\"\n result = []\n current_word = \"\"\n in_quotes = False\n for char in text:\n if char == '\"':\n in_quotes = not in_quotes\n if in_quotes:\n current_word += char\n else:\n result.append(current_word[1:]) # Remove leading quote\n current_word = \"\"\n elif in_quotes:\n current_word += char\n return result", "matching_cluster_idx": 2}, {"solution": "def extract_quotation(text):\n \"\"\"\n Extracts values between quotation marks \" \" of the given string.\n\n Args:\n text: The input string.\n\n Returns:\n A list of strings extracted between quotation marks.\n \"\"\"\n result = []\n start = -1\n for i, char in enumerate(text):\n if char == '\"':\n if start == -1:\n start = i + 1\n else:\n result.append(text[start:i])\n start = -1\n return result", "matching_cluster_idx": 2}, {"solution": "def extract_quotation(text):\n \"\"\"\n Extracts values between quotation marks \" \" of the given string.\n\n Args:\n text: The input string.\n\n Returns:\n A list of strings extracted between quotation marks.\n \"\"\"\n result = []\n start = 0\n in_quotes = False\n for i, char in enumerate(text):\n if char == '\"' and not in_quotes:\n start = i + 1\n in_quotes = True\n elif char == '\"' and in_quotes:\n result.append(text[start:i])\n in_quotes = False\n start = 0\n return result", "matching_cluster_idx": 1}, {"solution": "def extract_quotation(text):\n \"\"\"\n Extract values between quotation marks \" \" of the given string.\n\n Args:\n text: The input string.\n\n Returns:\n A list of strings extracted between quotation marks.\n \"\"\"\n result = []\n in_quotes = False\n current_quote = \"\"\n for char in text:\n if char == '\"':\n in_quotes = not in_quotes\n if in_quotes:\n current_quote += char\n else:\n result.append(current_quote[1:])\n current_quote = \"\"\n elif in_quotes:\n current_quote += char\n return result", "matching_cluster_idx": 2}, {"solution": "def extract_quotation(text):\n \"\"\"\n Extracts values between quotation marks \" \" of the given string.\n\n Args:\n text: The input string.\n\n Returns:\n A list of strings extracted between quotation marks.\n \"\"\"\n result = []\n start = 0\n in_quotes = False\n for i, char in enumerate(text):\n if char == '\"':\n if not in_quotes:\n start = i + 1\n in_quotes = True\n else:\n result.append(text[start:i])\n in_quotes = False\n return result", "matching_cluster_idx": 2}, {"solution": "def extract_quotation(text):\n \"\"\"\n Extracts values between quotation marks \" \" of the given string.\n\n Args:\n text: The input string.\n\n Returns:\n A list of strings extracted from quotation marks.\n \"\"\"\n result = []\n current_quote = \"\"\n in_quotes = False\n for char in text:\n if char == '\"':\n in_quotes = not in_quotes\n if in_quotes:\n current_quote += char\n else:\n result.append(current_quote[1:]) \n current_quote = \"\"\n elif in_quotes:\n current_quote += char\n return result", "matching_cluster_idx": 2}, {"solution": "def extract_quotation(text):\n \"\"\"\n Extracts values between quotation marks \" \" of the given string.\n\n Args:\n text: The input string.\n\n Returns:\n A list of strings, each representing a value enclosed in quotation marks.\n \"\"\"\n result = []\n start = 0\n in_quotes = False\n for i, char in enumerate(text):\n if char == '\"':\n if not in_quotes:\n start = i + 1\n in_quotes = True\n else:\n result.append(text[start:i])\n in_quotes = False\n elif in_quotes:\n pass # Keep iterating while inside quotes\n return result", "matching_cluster_idx": 2}, {"solution": "def extract_quotation(text):\n \"\"\"\n Extracts values between quotation marks \" \" of the given string.\n\n Args:\n text: The input string.\n\n Returns:\n A list of strings extracted between quotation marks.\n \"\"\"\n result = []\n start = 0\n in_quotes = False\n\n for i, char in enumerate(text):\n if char == '\"' and not in_quotes:\n in_quotes = True\n start = i + 1\n elif char == '\"' and in_quotes:\n in_quotes = False\n result.append(text[start:i])\n \n return result", "matching_cluster_idx": 1}]}, "Mbpp/732": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 80.0, "profiled": [{"solution": "def replace_specialchar(text):\n \"\"\"\n Replaces all occurrences of spaces, commas, or dots with a colon in a string.\n\n Args:\n text: The input string.\n\n Returns:\n The modified string with replaced characters.\n \"\"\"\n return text.replace(\" \", \":\").replace(\",\", \":\").replace(\".\", \":\")", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(text):\n \"\"\"\n Replaces all occurrences of spaces, commas, or dots with a colon.\n\n Args:\n text: The input string.\n\n Returns:\n The string with spaces, commas, and dots replaced by colons.\n \"\"\"\n return text.replace(\" \", \":\").replace(\",\", \":\").replace(\".\", \":\")", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(text):\n \"\"\"\n Replaces all occurrences of spaces, commas, or dots with a colon in a given string.\n\n Args:\n text: The string to be modified.\n\n Returns:\n The string with spaces, commas, and dots replaced by colons.\n \"\"\"\n return text.replace(\" \", \":\").replace(\",\", \":\").replace(\".\", \":\")", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(text):\n \"\"\"\n Replaces all occurrences of spaces, commas, or dots with a colon.\n\n Args:\n text: The input string.\n\n Returns:\n The string with spaces, commas, and dots replaced by colons.\n \"\"\"\n return text.replace(\" \", \":\").replace(\",\", \":\").replace(\".\", \":\")", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(text):\n \"\"\"\n Replaces all occurrences of spaces, commas, or dots with a colon.\n assert replace_specialchar('Python language, Programming language.')==('Python:language::Programming:language:')\n \"\"\"\n return text.replace(\" \",\":\").replace(\",\",\":\").replace(\".\",\":\")\ntext = 'Python language, Programming language.'", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(text):\n \"\"\"\n Replaces all occurrences of spaces, commas, or dots with a colon.\n\n Args:\n text: The input string.\n\n Returns:\n The string with spaces, commas, and dots replaced with colons.\n \"\"\"\n return text.replace(\" \", \":\").replace(\",\", \":\").replace(\".\", \":\")", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(text):\n \"\"\"\n Replaces all occurrences of spaces, commas, or dots with a colon.\n\n Args:\n text: The input string.\n\n Returns:\n The string with spaces, commas, and dots replaced by colons.\n \"\"\"\n return text.replace(' ', ':').replace(',', ':').replace('.', ':')", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(text):\n \"\"\"Replaces all occurrences of spaces, commas, or dots with a colon.\"\"\"\n return text.replace(\" \", \":\").replace(\",\", \":\").replace(\".\", \":\")", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(text):\n \"\"\"\n Replace all occurrences of spaces, commas, or dots with a colon.\n\n Args:\n text: The string to replace characters in.\n\n Returns:\n The string with spaces, commas, and dots replaced by colons.\n \"\"\"\n return text.replace(\" \", \":\").replace(\",\", \":\").replace(\".\", \":\")", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(text):\n \"\"\"\n Replaces all occurrences of spaces, commas, or dots with a colon.\n\n Args:\n text: The string to be modified.\n\n Returns:\n The string with spaces, commas, and dots replaced by colons.\n \"\"\"\n return text.replace(\" \", \":\").replace(\",\", \":\").replace(\".\", \":\")", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(text):\n \"\"\"\n Replace all occurrences of spaces, commas, or dots with a colon in a given string.\n \n Args:\n text: The input string.\n \n Returns:\n The string with spaces, commas, and dots replaced by colons.\n \"\"\"\n return text.replace(\" \", \":\").replace(\",\", \":\").replace(\".\", \":\")", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(text):\n \"\"\"\n Replaces all occurrences of spaces, commas, or dots with a colon.\n\n Args:\n text: The input string.\n\n Returns:\n The string with spaces, commas, and dots replaced by colons.\n \"\"\"\n return text.replace(\" \", \":\").replace(\",\", \":\").replace(\".\", \":\")", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(text):\n \"\"\"\n Replaces all occurrences of spaces, commas, or dots with a colon in a given string.\n\n Args:\n text: The input string.\n\n Returns:\n The string with spaces, commas, and dots replaced by colons.\n \"\"\"\n return text.replace(\" \", \":\").replace(\",\", \":\").replace(\".\", \":\")", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(text):\n \"\"\"\n This function replaces all occurrences of spaces, commas, or dots with a colon in a given string.\n\n Args:\n text: The input string.\n\n Returns:\n The string with spaces, commas, and dots replaced by colons.\n \"\"\"\n return text.replace(\" \", \":\").replace(\",\", \":\").replace(\".\", \":\")", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(text):\n \"\"\"\n Replaces all occurrences of spaces, commas, or dots with a colon.\n\n Args:\n text: The input string.\n\n Returns:\n The string with spaces, commas, and dots replaced by colons.\n \"\"\"\n return text.replace(\" \", \":\").replace(\",\", \":\").replace(\".\", \":\")", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(text):\n \"\"\"\n Replaces all occurrences of spaces, commas, or dots with a colon in a string.\n\n Args:\n text: The input string.\n\n Returns:\n The string with spaces, commas, and dots replaced by colons.\n \"\"\"\n return text.replace(\" \", \":\").replace(\",\", \":\").replace(\".\", \":\")", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(text):\n \"\"\"\n Replaces all occurrences of spaces, commas, or dots with a colon.\n\n Args:\n text: The input string.\n\n Returns:\n The string with spaces, commas, and dots replaced by colons.\n \"\"\"\n return text.replace(' ', ':').replace(',', ':').replace('.', ':')", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(text):\n \"\"\"\n Replace all occurrences of spaces, commas, or dots with a colon.\n\n Args:\n text: The input string.\n\n Returns:\n The string with spaces, commas, and dots replaced by colons.\n \"\"\"\n return text.replace(\" \", \":\").replace(\",\", \":\").replace(\".\", \":\")", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(text):\n \"\"\"\n Replaces all occurrences of spaces, commas, or dots with a colon.\n\n Args:\n text: The input string.\n\n Returns:\n The string with spaces, commas, and dots replaced by colons.\n \"\"\"\n return text.replace(' ', ':').replace(',', ':').replace('.', ':')", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(text):\n \"\"\"Replaces all occurrences of spaces, commas, or dots with a colon.\n \n Args:\n text: The input string.\n\n Returns:\n The string with spaces, commas, and dots replaced by colons.\n \"\"\"\n return text.replace(\" \", \":\").replace(\",\", \":\").replace(\".\", \":\")", "matching_cluster_idx": 9}]}, "Mbpp/740": {"dps": 93.2909090909091, "dps_norm": 92.22222222222223, "pass@1": 94.0, "profiled": [{"solution": "def tuple_to_dict(tpl):\n \"\"\"\n Converts a tuple to a key-value dictionary using adjacent elements.\n\n Args:\n tpl: A tuple of even length.\n\n Returns:\n A dictionary where keys are every other element of the tuple and values are the\n elements following them.\n \"\"\"\n return dict(zip(tpl[::2], tpl[1::2]))", "matching_cluster_idx": 8}, {"solution": "def tuple_to_dict(t):\n \"\"\"\n Converts a tuple to a key-value dictionary using adjacent elements.\n\n Args:\n t: The input tuple.\n\n Returns:\n A dictionary with keys from every other element and values from the \n following element in the tuple.\n \"\"\"\n return dict(zip(t[::2], t[1::2]))", "matching_cluster_idx": 8}, {"solution": "def tuple_to_dict(tpl):\n \"\"\"\n Convert the given tuple to a key-value dictionary using adjacent elements.\n\n Args:\n tpl: The input tuple.\n\n Returns:\n A dictionary where the keys are the first elements of each adjacent pair \n and the values are the second elements.\n \"\"\"\n return dict(zip(tpl[::2], tpl[1::2]))", "matching_cluster_idx": 8}, {"solution": "def tuple_to_dict(tup):\n \"\"\"\n Convert the given tuple to a key-value dictionary using adjacent elements.\n\n Args:\n tup: The input tuple.\n\n Returns:\n A dictionary where keys are the first element of each pair and values are the second element.\n \"\"\"\n return dict(zip(tup[::2], tup[1::2]))", "matching_cluster_idx": 8}, {"solution": "def tuple_to_dict(tpl):\n \"\"\"\n Converts a tuple to a key-value dictionary using adjacent elements.\n\n Args:\n tpl: The input tuple.\n\n Returns:\n A dictionary where the keys are every other element and the values are\n the elements that follow them.\n \"\"\"\n return dict(zip(tpl[::2], tpl[1::2]))", "matching_cluster_idx": 8}, {"solution": "def tuple_to_dict(data_tuple):\n \"\"\"\n Converts a tuple to a key-value dictionary using adjacent elements.\n\n Args:\n data_tuple: A tuple containing elements to be converted to key-value pairs.\n\n Returns:\n A dictionary where keys are elements at even indices and values are elements at odd indices.\n \n Raises:\n ValueError: If the input tuple has an odd number of elements.\n\n \"\"\"\n if len(data_tuple) % 2 != 0:\n raise ValueError(\"Input tuple must have an even number of elements.\")\n return dict(zip(data_tuple[::2], data_tuple[1::2]))", "matching_cluster_idx": 8}, {"solution": "def tuple_to_dict(t):\n \"\"\"\n Write a function to convert the given tuple to a key-value dictionary\n using adjacent elements.\n assert tuple_to_dict((1, 5, 7, 10, 13, 5)) == {1: 5, 7: 10, 13: 5}\n \"\"\"\n result = {}\n for i in range(0, len(t), 2):\n result[t[i]] = t[i + 1]\n return result", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(tp):\n \"\"\"\n Converts a tuple to a key-value dictionary using adjacent elements.\n\n Args:\n tp: A tuple of even length.\n\n Returns:\n A dictionary where keys are elements at even indices and values are\n elements at odd indices.\n \"\"\"\n return dict(zip(tp[::2], tp[1::2]))", "matching_cluster_idx": 8}, {"solution": "def tuple_to_dict(tpl):\n \"\"\"\n Converts a tuple to a key-value dictionary using adjacent elements.\n\n Args:\n tpl: A tuple of even length.\n\n Returns:\n A dictionary where the first element of each pair is the key and the second element is the value.\n \"\"\"\n return dict(zip(tpl[::2], tpl[1::2]))", "matching_cluster_idx": 8}, {"solution": "def tuple_to_dict(tp):\n \"\"\"\n Converts a tuple to a key-value dictionary using adjacent elements.\n\n Args:\n tp: A tuple of integers.\n\n Returns:\n A dictionary where keys are every other element in the tuple and values are the \n following adjacent elements.\n \"\"\"\n return dict(zip(tp[::2], tp[1::2]))", "matching_cluster_idx": 8}, {"solution": "def tuple_to_dict(tup):\n \"\"\"\n Converts a tuple to a key-value dictionary using adjacent elements.\n\n Args:\n tup: A tuple of even length.\n\n Returns:\n A dictionary where the key is the first element of each pair and the value is the second.\n \"\"\"\n return dict(zip(tup[::2], tup[1::2]))", "matching_cluster_idx": 8}, {"solution": "def tuple_to_dict(tp):\n \"\"\"\n Converts a tuple to a dictionary where adjacent elements are key-value pairs.\n\n Args:\n tp: The input tuple.\n\n Returns:\n A dictionary created from the tuple.\n \"\"\"\n return dict(zip(tp[::2], tp[1::2]))", "matching_cluster_idx": 8}, {"solution": "def tuple_to_dict(tpl):\n \"\"\"\n Converts a tuple to a key-value dictionary using adjacent elements.\n\n Args:\n tpl: The input tuple.\n\n Returns:\n A dictionary where keys are every other element in the tuple and values are the\n next elements.\n \"\"\"\n return dict(zip(tpl[::2], tpl[1::2]))", "matching_cluster_idx": 8}, {"solution": "def tuple_to_dict(tp):\n \"\"\"\n Write a function to convert the given tuple to a key-value dictionary using adjacent elements. \n\n Args:\n tp: A tuple of even length.\n\n Returns:\n A dictionary where keys are from index 0, 2, 4... and values are from index 1, 3, 5...\n \"\"\"\n return {tp[i]: tp[i + 1] for i in range(0, len(tp), 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(tpl):\n \"\"\"\n Convert the given tuple to a key-value dictionary using adjacent elements.\n\n Args:\n tpl: A tuple of even length.\n\n Returns:\n A dictionary where keys are every other element of the tuple and values are the \n following elements.\n \"\"\"\n return dict(zip(tpl[::2], tpl[1::2]))", "matching_cluster_idx": 8}, {"solution": "def tuple_to_dict(tup):\n \"\"\"\n Convert the given tuple to a key-value dictionary using adjacent elements.\n\n Args:\n tup: The input tuple.\n\n Returns:\n A dictionary with keys from even indices and values from odd indices.\n \"\"\"\n return dict(zip(tup[::2], tup[1::2]))", "matching_cluster_idx": 8}, {"solution": "def tuple_to_dict(tp):\n \"\"\"\n Convert the given tuple to a key-value dictionary using adjacent elements. \n \n Args:\n tp: A tuple of even length.\n \n Returns:\n A dictionary where the keys are the first elements of each pair and the values are the second elements of each pair.\n \n Raises:\n ValueError: If the tuple has odd length.\n \"\"\"\n if len(tp) % 2 != 0:\n raise ValueError(\"Tuple length must be even\")\n return dict(zip(tp[::2], tp[1::2]))", "matching_cluster_idx": 8}, {"solution": "def tuple_to_dict(input_tuple):\n \"\"\"\n Convert the given tuple to a key-value dictionary using adjacent elements.\n\n Args:\n input_tuple: A tuple of even length.\n\n Returns:\n A dictionary where keys are the first element of each pair and values are the second.\n \"\"\"\n result_dict = {}\n for i in range(0, len(input_tuple), 2):\n result_dict[input_tuple[i]] = input_tuple[i + 1]\n return result_dict", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(tpl):\n \"\"\"\n Converts a tuple to a dictionary using adjacent elements as key-value pairs.\n\n Args:\n tpl: A tuple.\n\n Returns:\n A dictionary with keys from even indices and values from odd indices.\n\n Raises:\n ValueError: If the tuple has an odd number of elements.\n \"\"\"\n if len(tpl) % 2 != 0:\n raise ValueError(\"Tuple must have an even number of elements.\")\n return dict(zip(tpl[::2], tpl[1::2]))", "matching_cluster_idx": 8}, {"solution": "def tuple_to_dict(t):\n \"\"\"\n Converts a tuple to a dictionary using adjacent elements as key-value pairs.\n\n Args:\n t: The input tuple.\n\n Returns:\n A dictionary where the keys are every other element of the tuple and the values are \n the elements next to them.\n \"\"\"\n\n result = {}\n for i in range(0, len(t), 2):\n if i + 1 < len(t):\n result[t[i]] = t[i + 1]\n return result", "matching_cluster_idx": 3}]}, "Mbpp/744": {"dps": 69.34931506849315, "dps_norm": 78.33333333333333, "pass@1": 100.0, "profiled": [{"solution": "def check_none(my_tuple):\n \"\"\"\n This function checks if a given tuple contains any None values.\n\n Args:\n my_tuple: The tuple to be checked.\n\n Returns:\n True if the tuple contains a None value, False otherwise.\n \"\"\"\n for element in my_tuple:\n if element is None:\n return True\n return False", "matching_cluster_idx": 4}, {"solution": "def check_none(data):\n \"\"\"\n Checks if a tuple contains any None values.\n\n Args:\n data: The tuple to check.\n\n Returns:\n True if the tuple contains a None value, False otherwise.\n \"\"\"\n for item in data:\n if item is None:\n return True\n return False", "matching_cluster_idx": 4}, {"solution": "def check_none(data_tuple):\n \"\"\"\n Checks if a tuple contains any None values.\n\n Args:\n data_tuple: The tuple to check.\n\n Returns:\n True if the tuple contains any None values, False otherwise.\n \"\"\"\n for item in data_tuple:\n if item is None:\n return True\n return False", "matching_cluster_idx": 4}, {"solution": "def check_none(data):\n \"\"\"\n Check if the given tuple has any none value or not.\n\n Args:\n data: A tuple.\n\n Returns:\n True if the tuple contains None, False otherwise.\n \"\"\"\n return any(x is None for x in data)", "matching_cluster_idx": 2}, {"solution": "def check_none(data):\n \"\"\"\n Check if the given tuple has any None value or not.\n\n Args:\n data: A tuple of values.\n\n Returns:\n True if the tuple contains a None value, False otherwise.\n \"\"\"\n for item in data:\n if item is None:\n return True\n return False", "matching_cluster_idx": 4}, {"solution": "def check_none(tup):\n \"\"\"\n Check if the given tuple has any None value or not.\n \"\"\"\n for item in tup:\n if item is None:\n return True\n return False", "matching_cluster_idx": 4}, {"solution": "def check_none(tp):\n \"\"\"\n Checks if a tuple contains any None values.\n\n Args:\n tp: The tuple to be checked.\n\n Returns:\n True if the tuple contains a None value, False otherwise.\n \"\"\"\n for item in tp:\n if item is None:\n return True\n return False", "matching_cluster_idx": 4}, {"solution": "def check_none(data):\n \"\"\"\n Checks if a given tuple has any None values.\n\n Args:\n data: A tuple of any data type.\n\n Returns:\n True if the tuple contains a None value, False otherwise.\n \"\"\"\n for item in data:\n if item is None:\n return True\n return False", "matching_cluster_idx": 4}, {"solution": "def check_none(data):\n \"\"\"\n Checks if the given tuple has any None values.\n \"\"\"\n for item in data:\n if item is None:\n return True\n return False", "matching_cluster_idx": 4}, {"solution": "def check_none(tup):\n \"\"\"\n Checks if the given tuple has any None value or not.\n\n Args:\n tup: The tuple to check.\n\n Returns:\n True if the tuple contains a None value, False otherwise.\n \"\"\"\n for item in tup:\n if item is None:\n return True\n return False", "matching_cluster_idx": 4}, {"solution": "def check_none(input_tuple):\n \"\"\"\n Checks if the given tuple has any None values.\n\n Args:\n input_tuple: The tuple to check.\n\n Returns:\n True if the tuple contains None, False otherwise.\n \"\"\"\n for item in input_tuple:\n if item is None:\n return True\n return False", "matching_cluster_idx": 4}, {"solution": "def check_none(tup):\n \"\"\"\n Checks if a tuple contains any None values.\n\n Args:\n tup: The tuple to be checked.\n\n Returns:\n True if the tuple contains None, False otherwise.\n \"\"\"\n for element in tup:\n if element is None:\n return True\n return False", "matching_cluster_idx": 4}, {"solution": "def check_none(tup):\n \"\"\"\n Checks if the given tuple has any None value or not.\n\n Args:\n tup: A tuple.\n\n Returns:\n True if the tuple contains None, False otherwise.\n \"\"\"\n for element in tup:\n if element is None:\n return True\n return False", "matching_cluster_idx": 4}, {"solution": "def check_none(my_tuple):\n \"\"\"\n This function checks if a given tuple contains any None values.\n\n Args:\n my_tuple: A tuple of elements.\n\n Returns:\n True if the tuple contains None, False otherwise.\n \"\"\"\n for element in my_tuple:\n if element is None:\n return True\n return False", "matching_cluster_idx": 4}, {"solution": "def check_none(data):\n \"\"\"\n Checks if the given tuple has any None value or not.\n \n Args:\n data: A tuple.\n\n Returns:\n True if the tuple contains None, False otherwise.\n \"\"\"\n for element in data:\n if element is None:\n return True\n return False", "matching_cluster_idx": 4}, {"solution": "def check_none(tuple_data):\n \"\"\"\n Check if the given tuple has any None value or not.\n \"\"\"\n for element in tuple_data:\n if element is None:\n return True\n return False", "matching_cluster_idx": 4}, {"solution": "def check_none(data):\n \"\"\"\n Checks if a tuple has any None values.\n\n Args:\n data (tuple): The tuple to check.\n\n Returns:\n bool: True if the tuple contains a None value, False otherwise.\n \"\"\"\n return any(x is None for x in data)", "matching_cluster_idx": 2}, {"solution": "def check_none(tp):\n \"\"\"\n Checks if a tuple has any None values.\n\n Args:\n tp: A tuple.\n\n Returns:\n True if the tuple contains any None values, False otherwise.\n \"\"\"\n for element in tp:\n if element is None:\n return True\n return False", "matching_cluster_idx": 4}, {"solution": "def check_none(tup):\n \"\"\"\n Checks if the given tuple has any None value or not.\n \"\"\"\n return any(item is None for item in tup)", "matching_cluster_idx": 2}, {"solution": "def check_none(my_tuple):\n \"\"\"\n Checks if a tuple contains any None values.\n\n Args:\n my_tuple: A tuple to be checked.\n\n Returns:\n True if the tuple contains any None values, False otherwise.\n \"\"\"\n for item in my_tuple:\n if item is None:\n return True\n return False", "matching_cluster_idx": 4}]}, "Mbpp/750": {"dps": 52.38095238095238, "dps_norm": 50.0, "pass@1": 100.0, "profiled": [{"solution": "def add_tuple(list1, tup1):\n \"\"\"\n Adds the given tuple to the given list.\n\n Args:\n list1: A list.\n tup1: A tuple.\n\n Returns:\n A new list with the tuple's elements added to the end of the list.\n \"\"\"\n return list1 + list(tup1)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(lst, tup):\n \"\"\"\n Adds the given tuple to the given list.\n\n Args:\n lst: The list to add the tuple to.\n tup: The tuple to add to the list.\n\n Returns:\n A new list with the tuple elements appended.\n \"\"\"\n return lst + list(tup)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(lst, tup):\n \"\"\"\n Adds the given tuple to the given list.\n\n Args:\n lst: A list.\n tup: A tuple.\n\n Returns:\n A new list with the tuple elements added to the end of the list.\n \"\"\"\n return lst + list(tup)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(list1, tup1):\n \"\"\"\n Write a function to add the given tuple to the given list.\n assert add_tuple([5, 6, 7], (9, 10)) == [5, 6, 7, 9, 10]\n \"\"\"\n return list1 + list(tup1)\nlist1 = [5, 6, 7]\ntup1 = (9, 10)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(lst, tup):\n \"\"\"\n Adds the elements of a tuple to the end of a list.\n\n Args:\n lst: A list.\n tup: A tuple.\n\n Returns:\n A new list with the elements of the tuple added to the end of the original list.\n \"\"\"\n return lst + list(tup)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(lst, tup):\n \"\"\"\n Write a function to add the given tuple to the given list.\n assert add_tuple([5, 6, 7], (9, 10)) == [5, 6, 7, 9, 10]\n \"\"\"\n return lst + list(tup)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(lst, tup):\n \"\"\"\n Adds the given tuple to the given list.\n \"\"\"\n return lst + list(tup)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(lst, tup):\n \"\"\"\n Adds the given tuple to the given list.\n\n Args:\n lst: The list to add the tuple to.\n tup: The tuple to add to the list.\n\n Returns:\n A new list with the tuple elements appended.\n \"\"\"\n return lst + list(tup)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(lst, tup):\n \"\"\"\n Write a function to add the given tuple to the given list.\n\n Args:\n lst: A list of numbers.\n tup: A tuple of numbers.\n\n Returns:\n A new list containing all elements from the input list and tuple.\n \"\"\"\n return lst + list(tup)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(lst, tup):\n \"\"\"\n Add the given tuple to the given list.\n\n Args:\n lst: A list of numbers.\n tup: A tuple of numbers.\n\n Returns:\n A new list containing all the elements of the list and the tuple.\n \"\"\"\n return lst + list(tup)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(lst, tup):\n \"\"\"\n Write a function to add the given tuple to the given list.\n assert add_tuple([5, 6, 7], (9, 10)) == [5, 6, 7, 9, 10]\n \"\"\"\n return lst + list(tup)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(lst, tup):\n \"\"\"\n Adds the given tuple to the given list.\n\n Args:\n lst: The list to add the tuple to.\n tup: The tuple to add to the list.\n\n Returns:\n The list with the tuple added.\n \"\"\"\n return lst + list(tup)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(lst, tup):\n \"\"\"\n Adds the given tuple to the given list.\n assert add_tuple([5, 6, 7], (9, 10)) == [5, 6, 7, 9, 10]\n \"\"\"\n return lst + list(tup)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(lst, tup):\n \"\"\"\n Adds the given tuple to the given list.\n \n Args:\n lst: A list.\n tup: A tuple.\n Returns:\n A new list with the tuple's elements added to the end of the original list.\n \"\"\"\n return lst + list(tup)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(lst, tup):\n \"\"\"\n Write a function to add the given tuple to the given list.\n assert add_tuple([5, 6, 7], (9, 10)) == [5, 6, 7, 9, 10]\n \"\"\"\n return lst + list(tup)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(lst, tup):\n \"\"\"\n Adds the given tuple to the given list.\n\n Args:\n lst: A list.\n tup: A tuple.\n\n Returns:\n A new list with the tuple elements appended to the original list.\n \"\"\"\n return lst + list(tup)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(lst, tup):\n \"\"\"\n Write a function to add the given tuple to the given list.\n assert add_tuple([5, 6, 7], (9, 10)) == [5, 6, 7, 9, 10]\n \"\"\"\n return lst + list(tup)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(lst, tup):\n \"\"\"Adds the elements of a tuple to the end of a list.\n\n Args:\n lst: The list to add the tuple to.\n tup: The tuple to add.\n\n Returns:\n The list with the tuple's elements appended.\n \"\"\"\n return lst + list(tup)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(list1, tup1):\n \"\"\"\n Adds the elements of a tuple to the end of a list.\n\n Args:\n list1: The list to add the tuple to.\n tup1: The tuple to add.\n\n Returns:\n The list with the tuple's elements appended.\n \"\"\"\n return list1 + list(tup1)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(lst, tup):\n \"\"\"\n This function adds the given tuple to the given list.\n\n Args:\n lst: A list.\n tup: A tuple.\n\n Returns:\n A new list containing all elements of the list and the tuple.\n \"\"\"\n return lst + list(tup)", "matching_cluster_idx": 2}]}, "Mbpp/753": {"dps": 92.51677852348993, "dps_norm": 73.75, "pass@1": 95.0, "profiled": [{"solution": "def min_k(tuples, k):\n \"\"\"\n Finds the minimum k records from a tuple list.\n\n Args:\n tuples: A list of tuples. Each tuple represents a record with two elements:\n a name (string) and a value (integer).\n k: The number of minimum records to find.\n\n Returns:\n A list of the k records with the minimum values.\n \"\"\"\n return sorted(tuples, key=lambda x: x[1])[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(records, k):\n \"\"\"\n Finds the minimum k records from a list of tuples.\n\n Args:\n records: A list of tuples, where each tuple represents a record with two elements.\n k: The number of minimum records to find.\n\n Returns:\n A list of the k minimum records, sorted by the second element (value) of each tuple.\n \"\"\"\n return sorted(records, key=lambda x: x[1])[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(tuples, k):\n \"\"\"Finds the minimum k records from a tuple list.\n\n Args:\n tuples: A list of tuples where each tuple has two elements.\n k: The number of minimum records to find.\n\n Returns:\n A list of the k tuples with the smallest second element.\n \"\"\"\n return sorted(tuples, key=lambda x: x[1])[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(data, k):\n \"\"\"\n Finds the minimum k records from a tuple list.\n\n Args:\n data: A list of tuples.\n k: The number of minimum records to return.\n\n Returns:\n A list of the k tuples with the smallest values.\n \"\"\"\n return sorted(data, key=lambda x: x[1])[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(data, k):\n \"\"\"\n Finds the minimum k records from a tuple list.\n\n Args:\n data: A list of tuples where each tuple represents a record.\n k: The number of minimum records to return.\n\n Returns:\n A list of the k minimum records.\n \"\"\"\n return sorted(data, key=lambda x: x[1])[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(data, k):\n \"\"\"\n Finds the minimum k records from a list of tuples.\n\n Args:\n data: A list of tuples, where each tuple represents a record.\n k: The number of minimum records to return.\n\n Returns:\n A list of the k minimum records.\n \"\"\"\n return sorted(data, key=lambda x: x[1])[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(data, k):\n \"\"\"\n Finds the minimum k records from a tuple list, sorted by the second element.\n\n Args:\n data: A list of tuples.\n k: The number of minimum records to return.\n\n Returns:\n A list of the k minimum records.\n \"\"\"\n return sorted(data, key=lambda x: x[1])[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(data, k):\n \"\"\"\n Finds the minimum k records from a list of tuples, ordered by the second element (numerical value).\n\n Args:\n data: A list of tuples, where each tuple contains a string and an integer.\n k: The number of minimum records to return.\n\n Returns:\n A list of the k tuples with the smallest second elements.\n \"\"\"\n return sorted(data, key=lambda item: item[1])[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(records, k):\n \"\"\"\n Finds the minimum k records from a tuple list.\n\n Args:\n records: A list of tuples, where each tuple represents a record.\n k: The number of minimum records to find.\n\n Returns:\n A list of the k minimum records.\n \"\"\"\n return sorted(records, key=lambda x: x[1])[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(records, k):\n \"\"\"\n Finds the minimum k records from a list of tuples.\n\n Args:\n records: A list of tuples, where each tuple represents a record with two elements.\n k: The number of minimum records to return.\n\n Returns:\n A list of the k minimum records.\n\n \"\"\"\n return sorted(records, key=lambda x: x[1])[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(tuple_list, k):\n \"\"\"\n Finds the minimum k records from a list of tuples.\n\n Args:\n tuple_list: A list of tuples, where each tuple represents a record.\n k: The number of minimum records to find.\n\n Returns:\n A list of the k minimum records.\n \"\"\"\n return sorted(tuple_list, key=lambda x: x[1])[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(data, k):\n \"\"\"\n Finds the minimum k records from a list of tuples.\n\n Args:\n data: A list of tuples, where each tuple represents a record with two elements.\n k: The number of minimum records to return.\n\n Returns:\n A list of the k smallest records, sorted by the second element (value).\n \"\"\"\n return sorted(data, key=lambda x: x[1])[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(lst, k):\n \"\"\"\n Finds the minimum k records from a tuple list.\n\n Args:\n lst: A list of tuples.\n k: The number of minimum records to return.\n\n Returns:\n A list of the k minimum records.\n \"\"\"\n return sorted(lst, key=lambda x: x[1])[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(tuples, k):\n \"\"\"\n Finds the minimum k records from a tuple list.\n\n Args:\n tuples: A list of tuples.\n k: The number of minimum records to return.\n\n Returns:\n A list of the k minimum records.\n \"\"\"\n return sorted(tuples, key=lambda x: x[1])[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(lst, k):\n \"\"\"Finds the minimum k records from a tuple list.\n\n Args:\n lst: A list of tuples, where each tuple represents a record.\n k: The number of minimum records to find.\n\n Returns:\n A list of the k minimum records, sorted by the second element (value).\n \"\"\"\n return sorted(lst, key=lambda x: x[1])[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(data, k):\n \"\"\"\n Finds the minimum k records from a list of tuples.\n\n Args:\n data: A list of tuples. Each tuple contains a name and a numerical value.\n k: The number of minimum records to return.\n\n Returns:\n A list of the k records with the smallest values.\n \"\"\"\n return sorted(data, key=lambda item: item[1])[:k]", "matching_cluster_idx": 1}, {"solution": "def min_k(data, k):\n \"\"\"\n Finds the minimum k records from a tuple list.\n\n Args:\n data: A list of tuples, where each tuple represents a record.\n k: The number of minimum records to return.\n\n Returns:\n A list of the k minimum records.\n \"\"\"\n return sorted(data, key=lambda item: item[1])[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(data, k):\n \"\"\"Finds the minimum k records from a tuple list based on the second element of each tuple.\n\n Args:\n data: A list of tuples where each tuple represents a record with a name (string) and a value (integer).\n k: The number of minimum records to return.\n\n Returns:\n A list of the k minimum records.\n \"\"\"\n return sorted(data, key=lambda x: x[1])[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(records, k):\n \"\"\"\n Finds the minimum k records from a tuple list, sorted by the second element (the numerical value).\n\n Args:\n records: A list of tuples, where each tuple contains a name (string) and a numerical value.\n k: The number of minimum records to return.\n\n Returns:\n A list of the k tuples with the smallest numerical values.\n \"\"\"\n return sorted(records, key=lambda record: record[1])[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(data, k):\n \"\"\"Finds the minimum k records from a tuple list.\n\n Args:\n data: A list of tuples, where each tuple represents a record.\n k: The number of minimum records to find.\n\n Returns:\n A list of the k minimum records.\n \"\"\"\n return sorted(data, key=lambda x: x[1])[:k]", "matching_cluster_idx": 2}]}, "Mbpp/754": {"dps": null, "dps_norm": null, "pass@1": 0.0, "profiled": []}, "Mbpp/755": {"dps": null, "dps_norm": null, "pass@1": 1.0, "profiled": []}, "Mbpp/757": {"dps": 82.71028037383178, "dps_norm": 23.076923076923077, "pass@1": 100.0, "profiled": [{"solution": "def count_reverse_pairs(string_list):\n \"\"\"\n Counts the pairs of reverse strings in the given string list.\n\n Args:\n string_list: A list of strings.\n\n Returns:\n The number of pairs of reverse strings in the list.\n \"\"\"\n count = 0\n for i in range(len(string_list)):\n for j in range(i + 1, len(string_list)):\n if string_list[i] == string_list[j][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(strings):\n \"\"\"\n Counts the pairs of reverse strings in the given string list.\n\n Args:\n strings: A list of strings.\n\n Returns:\n The number of pairs of reverse strings in the list.\n \"\"\"\n count = 0\n for i in range(len(strings)):\n for j in range(i + 1, len(strings)):\n if strings[i] == strings[j][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(strings):\n \"\"\"\n Counts the pairs of reverse strings in the given string list.\n\n Args:\n strings: A list of strings.\n\n Returns:\n The number of pairs of reverse strings in the list.\n \"\"\"\n count = 0\n for i in range(len(strings)):\n for j in range(i + 1, len(strings)):\n if strings[i] == strings[j][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(string_list):\n \"\"\"\n Counts the pairs of reverse strings in the given string list.\n\n Args:\n string_list: A list of strings.\n\n Returns:\n The number of pairs of reverse strings in the list.\n \"\"\"\n count = 0\n for i in range(len(string_list)):\n for j in range(i + 1, len(string_list)):\n if string_list[i] == string_list[j][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(string_list):\n \"\"\"\n Counts the pairs of reverse strings in the given string list.\n\n Args:\n string_list: A list of strings.\n\n Returns:\n The number of pairs of reverse strings in the list.\n \"\"\"\n count = 0\n for i in range(len(string_list)):\n for j in range(i + 1, len(string_list)):\n if string_list[i] == string_list[j][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(strings):\n \"\"\"\n Counts the pairs of reverse strings in a given list of strings.\n\n Args:\n strings: A list of strings.\n\n Returns:\n The number of pairs of reverse strings in the list.\n \"\"\"\n count = 0\n for i in range(len(strings)):\n for j in range(i + 1, len(strings)):\n if strings[i] == strings[j][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(strings):\n \"\"\"\n Counts the pairs of reverse strings in the given string list.\n\n Args:\n strings: A list of strings.\n\n Returns:\n The number of pairs of reverse strings in the list.\n \"\"\"\n count = 0\n for i in range(len(strings)):\n for j in range(i + 1, len(strings)):\n if strings[i] == strings[j][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(words):\n \"\"\"\n Counts the pairs of reverse strings in the given string list.\n\n Args:\n words: A list of strings.\n\n Returns:\n The number of pairs of reverse strings in the list.\n \"\"\"\n count = 0\n for i in range(len(words)):\n for j in range(i + 1, len(words)):\n if words[i] == words[j][::-1]: \n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(str_list):\n \"\"\"\n Counts the pairs of reverse strings in the given string list. \n\n Args:\n str_list: A list of strings.\n\n Returns:\n The number of pairs of reverse strings in the list.\n \"\"\"\n count = 0\n for i in range(len(str_list)):\n for j in range(i + 1, len(str_list)):\n if str_list[i] == str_list[j][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(strings):\n \"\"\"\n Counts the pairs of reverse strings in the given string list.\n\n Args:\n strings: A list of strings.\n\n Returns:\n The number of pairs of reverse strings in the list.\n \"\"\"\n count = 0\n for i in range(len(strings)):\n for j in range(i + 1, len(strings)):\n if strings[i] == strings[j][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(string_list):\n \"\"\"\n Counts the pairs of reverse strings in the given string list.\n\n Args:\n string_list: A list of strings.\n\n Returns:\n The number of pairs of reverse strings in the list.\n \"\"\"\n count = 0\n for i in range(len(string_list)):\n for j in range(i + 1, len(string_list)):\n if string_list[i] == string_list[j][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(strings):\n \"\"\"\n Counts the pairs of reverse strings in the given string list.\n\n Args:\n strings: A list of strings.\n\n Returns:\n The number of pairs of reverse strings in the list.\n \"\"\"\n count = 0\n for i in range(len(strings)):\n for j in range(i + 1, len(strings)):\n if strings[i] == strings[j][::-1]: # Check if strings are reverse of each other\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(strings):\n \"\"\"\n Counts the pairs of reverse strings in the given string list.\n\n Args:\n strings: A list of strings.\n\n Returns:\n The number of pairs of reverse strings in the list.\n \"\"\"\n count = 0\n for i in range(len(strings)):\n for j in range(i + 1, len(strings)):\n if strings[i] == strings[j][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(strings):\n \"\"\"\n Counts the pairs of reverse strings in the given string list.\n\n Args:\n strings: A list of strings.\n\n Returns:\n The number of pairs of reverse strings in the list.\n \"\"\"\n count = 0\n for i in range(len(strings)):\n for j in range(i + 1, len(strings)):\n if strings[i] == strings[j][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(strings):\n \"\"\"\n Counts the pairs of reverse strings in the given string list. \n \n Args:\n strings: A list of strings.\n\n Returns:\n The number of pairs of reverse strings in the list.\n \"\"\"\n count = 0\n for i in range(len(strings)):\n for j in range(i + 1, len(strings)):\n if strings[i] == strings[j][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(words):\n \"\"\"\n Counts the pairs of reverse strings in a list of strings.\n\n Args:\n words: A list of strings.\n\n Returns:\n The number of pairs of reverse strings in the list.\n \"\"\"\n count = 0\n for i in range(len(words)):\n for j in range(i + 1, len(words)):\n if words[i] == words[j][::-1]: # Check if strings are reverse of each other\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(strings):\n \"\"\"\n Counts the pairs of reverse strings in the given string list.\n\n Args:\n strings: A list of strings.\n\n Returns:\n The number of pairs of reverse strings in the list.\n \"\"\"\n count = 0\n for i in range(len(strings)):\n for j in range(i + 1, len(strings)):\n if strings[i] == strings[j][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(strings):\n \"\"\"\n Counts the pairs of reverse strings in the given string list.\n\n Args:\n strings: A list of strings.\n\n Returns:\n The number of pairs of reverse strings in the list.\n \"\"\"\n count = 0\n for i in range(len(strings)):\n for j in range(i + 1, len(strings)):\n if strings[i] == strings[j][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(string_list):\n \"\"\"\n Counts the number of pairs of reverse strings in the given string list.\n\n Args:\n string_list: A list of strings.\n\n Returns:\n The number of pairs of reverse strings.\n \"\"\"\n count = 0\n for i in range(len(string_list)):\n for j in range(i + 1, len(string_list)):\n if string_list[i] == string_list[j][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(strs):\n \"\"\"\n Counts the pairs of reverse strings in the given string list. \n\n Args:\n strs: A list of strings.\n\n Returns:\n The number of pairs of reverse strings in the list.\n \"\"\"\n count = 0\n for i in range(len(strs)):\n for j in range(i + 1, len(strs)):\n if strs[i] == strs[j][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}]}, "Mbpp/758": {"dps": 72.49034749034749, "dps_norm": 78.125, "pass@1": 69.0, "profiled": [{"solution": "def unique_sublists(lst):\n \"\"\"\n Counts the occurrences of lists within a list.\n\n Args:\n lst: A list of lists.\n\n Returns:\n A dictionary where every list is converted to a tuple and the value of such tuple is the number of its occurrences in the original list.\n \"\"\"\n result = {}\n for sublist in lst:\n sublist_tuple = tuple(sublist) \n if sublist_tuple in result:\n result[sublist_tuple] += 1\n else:\n result[sublist_tuple] = 1\n return result", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(lst):\n \"\"\"\n Counts the occurrences of lists within a list.\n\n Args:\n lst: A list of lists.\n\n Returns:\n A dictionary where every list is converted to a tuple and the value of such tuple is the number of its occurrences in the original list.\n \"\"\"\n sublist_counts = {}\n for sublist in lst:\n sublist_tuple = tuple(sublist)\n if sublist_tuple in sublist_counts:\n sublist_counts[sublist_tuple] += 1\n else:\n sublist_counts[sublist_tuple] = 1\n return sublist_counts", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(lst):\n \"\"\"\n Counts lists within a list.\n\n Args:\n lst: A list of lists.\n\n Returns:\n A dictionary where every list is converted to a tuple and the value of such tuple is the number of its occurrences in the original list.\n \"\"\"\n result = {}\n for sublist in lst:\n tuple_sublist = tuple(sublist) \n if tuple_sublist in result:\n result[tuple_sublist] += 1\n else:\n result[tuple_sublist] = 1\n return result", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(lst):\n \"\"\"\n Counts the occurrences of each unique sublist within a list.\n\n Args:\n lst: A list of lists.\n\n Returns:\n A dictionary where the keys are tuples representing unique sublists \n and the values are their corresponding occurrence counts.\n \"\"\"\n result = {}\n for sublist in lst:\n tuple_sublist = tuple(sublist) \n if tuple_sublist in result:\n result[tuple_sublist] += 1\n else:\n result[tuple_sublist] = 1\n return result", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(input_list):\n \"\"\"\n Counts occurrences of lists within a list.\n\n Args:\n input_list: A list of lists.\n\n Returns:\n A dictionary where each key is a tuple representing a sublist and \n the value is the number of times it occurs in the input list.\n \"\"\"\n sublist_counts = {}\n for sublist in input_list:\n sublist_tuple = tuple(sublist) \n if sublist_tuple in sublist_counts:\n sublist_counts[sublist_tuple] += 1\n else:\n sublist_counts[sublist_tuple] = 1\n return sublist_counts", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(lst):\n \"\"\"\n Counts the occurrences of lists within a list.\n\n Args:\n lst: A list of lists.\n\n Returns:\n A dictionary where keys are tuples representing the lists and values\n are their respective counts.\n \"\"\"\n counts = {}\n for sublist in lst:\n # Convert the list to a tuple for hashing\n tuple_sublist = tuple(sublist)\n if tuple_sublist in counts:\n counts[tuple_sublist] += 1\n else:\n counts[tuple_sublist] = 1\n return counts", "matching_cluster_idx": 5}, {"solution": "def unique_sublists(lst):\n \"\"\"\n Counts lists within a list.\n\n Args:\n lst: A list of lists.\n\n Returns:\n A dictionary where keys are tuples representing the unique sublists, \n and values are the number of occurrences of each sublist.\n \"\"\"\n sublist_counts = {}\n for sublist in lst:\n # Convert the sublist to a tuple for hashability\n sublist_tuple = tuple(sublist) \n if sublist_tuple in sublist_counts:\n sublist_counts[sublist_tuple] += 1\n else:\n sublist_counts[sublist_tuple] = 1\n return sublist_counts", "matching_cluster_idx": 5}, {"solution": "def unique_sublists(lst):\n \"\"\"\n Counts the occurrences of each sublist within a list.\n\n Args:\n lst: A list of lists.\n\n Returns:\n A dictionary where keys are tuples representing unique sublists, \n and values are their counts.\n \"\"\"\n counts = {}\n for sublist in lst:\n sublist_tuple = tuple(sublist) # Convert to tuple for hashability\n if sublist_tuple in counts:\n counts[sublist_tuple] += 1\n else:\n counts[sublist_tuple] = 1\n return counts", "matching_cluster_idx": 5}, {"solution": "def unique_sublists(lst):\n \"\"\"\n Write a function to count lists within a list. The function should return a dictionary where every list is converted to a tuple and the value of such tuple is the number of its occurencies in the original list.\n \n Args:\n lst: A list of lists.\n\n Returns:\n A dictionary where keys are tuples representing the sublists and values are the number of occurrences.\n\n Examples:\n unique_sublists([[1, 3], [5, 7], [1, 3], [13, 15, 17], [5, 7], [9, 11]] )=={(1, 3): 2, (5, 7): 2, (13, 15, 17): 1, (9, 11): 1}\n\n \"\"\"\n result = {}\n for sublist in lst:\n tuple_sublist = tuple(sublist)\n if tuple_sublist in result:\n result[tuple_sublist] += 1\n else:\n result[tuple_sublist] = 1\n return result", "matching_cluster_idx": 5}, {"solution": "def unique_sublists(lst):\n \"\"\"\n Counts the occurrences of lists within a list and returns a dictionary.\n\n Args:\n lst: A list of lists.\n\n Returns:\n A dictionary where keys are tuples representing the sublists and\n values are the number of times each sublist appears in the original list.\n \"\"\"\n result = {}\n for sublist in lst:\n sublist_tuple = tuple(sublist) # Convert list to tuple for hashability\n if sublist_tuple in result:\n result[sublist_tuple] += 1\n else:\n result[sublist_tuple] = 1\n return result", "matching_cluster_idx": 5}, {"solution": "def unique_sublists(nested_list):\n \"\"\"\n Counts the occurrences of unique lists within a given list.\n\n Args:\n nested_list: A list of lists.\n\n Returns:\n A dictionary where keys are tuples representing lists and values are their counts.\n \"\"\"\n counts = {}\n for sublist in nested_list:\n tuple_sublist = tuple(sublist) \n if tuple_sublist in counts:\n counts[tuple_sublist] += 1\n else:\n counts[tuple_sublist] = 1\n return counts", "matching_cluster_idx": 5}, {"solution": "def unique_sublists(lst):\n \"\"\"\n Counts lists within a list.\n\n Args:\n lst: A list of lists.\n\n Returns:\n A dictionary where every list is converted to a tuple and the value of \n such tuple is the number of its occurrences in the original list.\n \"\"\"\n counts = {}\n for sublist in lst:\n tuple_key = tuple(sublist) \n if tuple_key in counts:\n counts[tuple_key] += 1\n else:\n counts[tuple_key] = 1\n return counts", "matching_cluster_idx": 5}, {"solution": "def unique_sublists(lst):\n \"\"\"\n Counts the number of occurrences of each list (converted to tuples) within a list.\n\n Args:\n lst: A list of lists.\n\n Returns:\n A dictionary where keys are tuples representing the unique lists \n and values are their counts.\n \"\"\"\n counts = {}\n for sublist in lst:\n # Convert the sublist to a tuple for keying in the dictionary\n key = tuple(sublist)\n if key in counts:\n counts[key] += 1\n else:\n counts[key] = 1\n return counts", "matching_cluster_idx": 5}, {"solution": "def unique_sublists(data):\n \"\"\"\n Counts the occurrences of lists within a list.\n\n Args:\n data: A list of lists.\n\n Returns:\n A dictionary where keys are tuples representing lists and values are\n their occurrence counts.\n \"\"\"\n result = {}\n for sublist in data:\n # Convert the list to a tuple for hashability\n tuple_form = tuple(sublist)\n if tuple_form in result:\n result[tuple_form] += 1\n else:\n result[tuple_form] = 1\n return result", "matching_cluster_idx": 5}, {"solution": "def unique_sublists(lst):\n \"\"\"\n Write a function to count lists within a list. \n The function should return a dictionary where every list is converted to a tuple and the value of such tuple is the number of its occurencies in the original list.\n\n Args:\n lst: A list of lists.\n\n Returns:\n A dictionary where keys are tuples representing the lists and values are their counts.\n\n For example:\n unique_sublists([[1, 3], [5, 7], [1, 3], [13, 15, 17], [5, 7], [9, 11]]) \n == {(1, 3): 2, (5, 7): 2, (13, 15, 17): 1, (9, 11): 1}\n \"\"\"\n counts = {}\n for sublist in lst:\n counts[tuple(sublist)] = counts.get(tuple(sublist), 0) + 1\n return counts", "matching_cluster_idx": 5}, {"solution": "def unique_sublists(input_list):\n \"\"\"\n Counts the occurrences of lists within a list.\n\n Args:\n input_list: A list of lists.\n\n Returns:\n A dictionary where every list is converted to a tuple and the value \n of such tuple is the number of its occurrences in the original list.\n \"\"\"\n counts = {}\n for sublist in input_list:\n sublist_tuple = tuple(sublist) # Convert list to tuple for hashability\n if sublist_tuple in counts:\n counts[sublist_tuple] += 1\n else:\n counts[sublist_tuple] = 1\n return counts", "matching_cluster_idx": 5}, {"solution": "def unique_sublists(lst):\n \"\"\"\n Counts lists within a list.\n\n Args:\n lst: A list of lists.\n\n Returns:\n A dictionary where keys are tuples of elements from the sublists and\n values are the number of times each tuple appears in the input list.\n \"\"\"\n counts = {}\n for sublist in lst:\n tuple_sublist = tuple(sublist) \n if tuple_sublist in counts:\n counts[tuple_sublist] += 1\n else:\n counts[tuple_sublist] = 1\n return counts", "matching_cluster_idx": 5}, {"solution": "def unique_sublists(lst):\n \"\"\"\n Counts the occurrences of lists within a list.\n\n Args:\n lst: A list of lists.\n\n Returns:\n A dictionary where keys are tuples representing the sublists and values are their counts.\n \"\"\"\n result = {}\n for sublist in lst:\n # Convert the sublist to a tuple to ensure hashability\n sublist_tuple = tuple(sublist)\n if sublist_tuple in result:\n result[sublist_tuple] += 1\n else:\n result[sublist_tuple] = 1\n return result", "matching_cluster_idx": 5}, {"solution": "def unique_sublists(lst):\n \"\"\"\n Counts the occurrences of lists within a list.\n\n Args:\n lst: A list of lists.\n\n Returns:\n A dictionary where each key is a tuple representation of a sublist \n and the value is its number of occurrences in the input list.\n \"\"\"\n counts = {}\n for sublist in lst:\n # Convert the sublist to a tuple for key comparison\n tuple_sublist = tuple(sublist)\n if tuple_sublist in counts:\n counts[tuple_sublist] += 1\n else:\n counts[tuple_sublist] = 1\n return counts", "matching_cluster_idx": 5}, {"solution": "def unique_sublists(lst):\n \"\"\"\n Counts lists within a list and returns a dictionary of unique lists and their counts.\n\n Args:\n lst: A list of lists.\n\n Returns:\n A dictionary where keys are tuples representing unique lists, and values are the counts of their occurrences.\n \"\"\"\n sublist_counts = {}\n for sublist in lst:\n sublist_tuple = tuple(sublist) # Convert list to tuple for immutability\n if sublist_tuple in sublist_counts:\n sublist_counts[sublist_tuple] += 1\n else:\n sublist_counts[sublist_tuple] = 1\n return sublist_counts", "matching_cluster_idx": 5}]}, "Mbpp/760": {"dps": 99.27007299270073, "dps_norm": 87.5, "pass@1": 97.0, "profiled": [{"solution": "def unique_Element(nums):\n \"\"\"\n Checks whether a list of numbers contains only one distinct element or not.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n True if the list contains only one distinct element, False otherwise.\n \"\"\"\n return len(set(nums)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(nums):\n \"\"\"\n Checks if a list of numbers contains only one distinct element.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n True if the list contains only one distinct element, False otherwise.\n \"\"\"\n return len(set(nums)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(nums):\n \"\"\"\n Checks if a list of numbers contains only one distinct element.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n True if the list contains only one distinct element, False otherwise.\n \"\"\"\n return len(set(nums)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(nums):\n \"\"\"\n Checks if a list of numbers contains only one distinct element.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n True if the list contains only one distinct element, False otherwise.\n \"\"\"\n return len(set(nums)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(nums):\n \"\"\"\n Check whether a list of numbers contains only one distinct element or not.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n True if the list contains only one distinct element, False otherwise.\n \"\"\"\n return len(set(nums)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(nums):\n \"\"\"\n Checks if a list of numbers contains only one distinct element.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n True if the list contains only one distinct element, False otherwise.\n \"\"\"\n return len(set(nums)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(nums):\n \"\"\"\n Checks whether a list of numbers contains only one distinct element.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n True if the list contains only one distinct element, False otherwise.\n \"\"\"\n return len(set(nums)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(nums):\n \"\"\"\n Checks if a list of numbers contains only one distinct element or not.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n True if the list contains only one distinct element, False otherwise.\n \"\"\"\n return len(set(nums)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(nums):\n \"\"\"\n Checks if a list of numbers contains only one distinct element.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n True if the list contains only one distinct element, False otherwise.\n \"\"\"\n return len(set(nums)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(nums):\n \"\"\"\n Checks if a list of numbers contains only one distinct element.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n True if the list contains only one distinct element, False otherwise.\n \"\"\"\n return len(set(nums)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(nums):\n \"\"\"\n Check whether a list of numbers contains only one distinct element or not.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n True if the list contains only one distinct element, False otherwise.\n \"\"\"\n return len(set(nums)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(numbers):\n \"\"\"\n Checks whether a list of numbers contains only one distinct element or not.\n\n Args:\n numbers: A list of numbers.\n\n Returns:\n True if the list contains only one distinct element, False otherwise.\n \"\"\"\n return len(set(numbers)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(nums):\n \"\"\"\n This function checks whether a list of numbers contains only one distinct element or not.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n True if the list contains only one distinct element, False otherwise.\n \"\"\"\n return len(set(nums)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(nums):\n \"\"\"\n Checks if a list of numbers contains only one distinct element.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n True if the list contains only one distinct element, False otherwise.\n \"\"\"\n return len(set(nums)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(nums):\n \"\"\"\n Checks if a list of numbers contains only one distinct element.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n True if the list contains only one distinct element, False otherwise.\n \"\"\"\n return len(set(nums)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(nums):\n \"\"\"\n Checks if a list of numbers contains only one distinct element.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n True if the list contains only one distinct element, False otherwise.\n \"\"\"\n\n return len(set(nums)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(nums):\n \"\"\"\n Checks if a list of numbers contains only one distinct element.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n True if the list contains only one distinct element, False otherwise.\n \"\"\"\n return len(set(nums)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(nums):\n \"\"\"\n Checks if a list of numbers contains only one distinct element.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n True if the list contains only one distinct element, False otherwise.\n \"\"\"\n return len(set(nums)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(nums):\n \"\"\"\n Checks if a list of numbers contains only one distinct element.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n True if the list contains only one distinct element, False otherwise.\n \"\"\"\n return len(set(nums)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(nums):\n \"\"\"\n Checks if a list of numbers contains only one distinct element.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n True if the list contains only one distinct element, False otherwise.\n \"\"\"\n return len(set(nums)) == 1", "matching_cluster_idx": 6}]}, "Mbpp/764": {"dps": 88.88888888888889, "dps_norm": 50.0, "pass@1": 100.0, "profiled": [{"solution": "def number_ctr(text):\n \"\"\"\n Counts the number of digits in a given string.\n \"\"\"\n count = 0\n for char in text:\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(string):\n \"\"\"Counts the number of digits in a given string.\n\n Args:\n string: The string to count digits in.\n\n Returns:\n The number of digits in the string.\n \"\"\"\n count = 0\n for char in string:\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(text):\n \"\"\"Counts the number of digits in a given string.\n\n Args:\n text: The string to count the digits in.\n\n Returns:\n The number of digits in the string.\n \"\"\"\n count = 0\n for char in text:\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(input_string):\n \"\"\"\n Counts the number of digits in a given string.\n\n Args:\n input_string: The string to analyze.\n\n Returns:\n The number of digits in the input string.\n \"\"\"\n count = 0\n for char in input_string:\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(str1):\n \"\"\"\n Counts the number of digits in a given string.\n\n Args:\n str1: The input string.\n\n Returns:\n The number of digits in the string.\n \"\"\"\n count = 0\n for char in str1:\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(str1):\n \"\"\"\n Counts the number of digits in a given string.\n\n Args:\n str1: The input string.\n\n Returns:\n The number of digits in the string.\n \"\"\"\n count = 0\n for char in str1:\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n \"\"\"\n Counts the number of digits in a given string.\n \"\"\"\n count = 0\n for char in s:\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(input_str):\n \"\"\"Counts the number of digits in a given string.\n\n Args:\n input_str: The string to count digits in.\n\n Returns:\n The number of digits in the string.\n \"\"\"\n count = 0\n for char in input_str:\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(text):\n \"\"\"\n Counts the number of digits in a given string.\n\n Args:\n text: The input string.\n\n Returns:\n The number of digits in the string.\n \"\"\"\n count = 0\n for char in text:\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(str1):\n \"\"\"Counts the number of digits in a given string.\n\n Args:\n str1: The input string.\n\n Returns:\n The number of digits in the string.\n \"\"\"\n count = 0\n for char in str1:\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(text):\n \"\"\"Counts the number of digits in a given string.\n \n Args:\n text: The string to be analyzed.\n \n Returns:\n The number of digits in the string.\n \"\"\"\n count = 0\n for char in text:\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(input_string):\n \"\"\"\n Counts the number of digits in a given string.\n\n Args:\n input_string: The string to be analyzed.\n\n Returns:\n The number of digits found in the string.\n \"\"\"\n count = 0\n for char in input_string:\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(text):\n \"\"\"Counts the number of digits in a given string.\n\n Args:\n text: The string to count digits in.\n\n Returns:\n The number of digits in the string.\n \"\"\"\n count = 0\n for char in text:\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(string):\n \"\"\"\n Counts the number of digits in a given string.\n\n Args:\n string: The input string.\n\n Returns:\n The number of digits in the string.\n \"\"\"\n count = 0\n for char in string:\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(input_string):\n \"\"\"\n Counts the number of digits in a given string.\n\n Args:\n input_string: The string to count digits in.\n\n Returns:\n The number of digits in the input string.\n \"\"\"\n count = 0\n for char in input_string:\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(str1):\n \"\"\"\n Counts the number of digits in a given string.\n\n Args:\n str1: The input string.\n\n Returns:\n The number of digits in the string.\n \"\"\"\n count = 0\n for char in str1:\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(string):\n \"\"\"Counts the number of digits in a given string.\n\n Args:\n string: The input string.\n\n Returns:\n The number of digits in the string.\n \"\"\"\n count = 0\n for char in string:\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(string):\n \"\"\"Counts the number of digits in a given string.\"\"\"\n count = 0\n for char in string:\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(str1):\n \"\"\"\n Counts the number of digits in a given string.\n\n Args:\n str1: A string to be analyzed.\n\n Returns:\n An integer representing the number of digits in the string.\n \"\"\"\n count = 0\n for char in str1:\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(str1):\n \"\"\"Counts the number of digits in a given string.\n\n Args:\n str1: The input string.\n\n Returns:\n The number of digits in the string.\n \"\"\"\n count = 0\n for char in str1:\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}]}, "Mbpp/766": {"dps": 79.48598130841121, "dps_norm": 75.0, "pass@1": 100.0, "profiled": [{"solution": "def pair_wise(arr):\n \"\"\"\n Write a function to return a list of all pairs of consecutive items in a given list.\n\n assert pair_wise([1,1,2,3,3,4,4,5])==[(1, 1), (1, 2), (2, 3), (3, 3), (3, 4), (4, 4), (4, 5)]\n \"\"\"\n return list(zip(arr[:-1], arr[1:]))", "matching_cluster_idx": 4}, {"solution": "def pair_wise(lst):\n \"\"\"\n Returns a list of all pairs of consecutive items in a given list.\n\n Args:\n lst: A list of items.\n\n Returns:\n A list of tuples, where each tuple represents a pair of consecutive items.\n \"\"\"\n return [(lst[i], lst[i+1]) for i in range(len(lst)-1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(data):\n \"\"\"\n Write a function to return a list of all pairs of consecutive items in a given list.\n assert pair_wise([1,1,2,3,3,4,4,5])==[(1, 1), (1, 2), (2, 3), (3, 3), (3, 4), (4, 4), (4, 5)]\n \"\"\"\n return list(zip(data[:-1], data[1:]))", "matching_cluster_idx": 5}, {"solution": "def pair_wise(nums):\n \"\"\"\n Returns a list of all pairs of consecutive items in a given list.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n A list of tuples, where each tuple contains a pair of consecutive items from the input list.\n \"\"\"\n return list(zip(nums[:-1], nums[1:]))", "matching_cluster_idx": 5}, {"solution": "def pair_wise(arr):\n \"\"\"\n Return a list of all pairs of consecutive items in a given list.\n\n Args:\n arr: The input list.\n\n Returns:\n A list of tuples, where each tuple represents a pair of consecutive items.\n \"\"\"\n pairs = []\n for i in range(len(arr) - 1):\n pairs.append((arr[i], arr[i + 1]))\n return pairs", "matching_cluster_idx": 2}, {"solution": "def pair_wise(input_list):\n \"\"\"\n This function returns a list of all pairs of consecutive items in a given list.\n\n Args:\n input_list: A list of items.\n\n Returns:\n A list of tuples, where each tuple represents a pair of consecutive items from the input list.\n \"\"\"\n pairs = []\n for i in range(len(input_list) - 1):\n pairs.append((input_list[i], input_list[i + 1]))\n return pairs", "matching_cluster_idx": 2}, {"solution": "def pair_wise(arr):\n \"\"\"\n This function returns a list of all pairs of consecutive items in a given list.\n\n Args:\n arr: A list of items.\n\n Returns:\n A list of tuples, where each tuple represents a pair of consecutive items from the input list.\n \"\"\"\n return list(zip(arr[:-1], arr[1:]))", "matching_cluster_idx": 5}, {"solution": "def pair_wise(data):\n \"\"\"\n Write a function to return a list of all pairs of consecutive items in a given list.\n assert pair_wise([1,1,2,3,3,4,4,5])==[(1, 1), (1, 2), (2, 3), (3, 3), (3, 4), (4, 4), (4, 5)]\n \"\"\"\n return [(data[i], data[i + 1]) for i in range(len(data) - 1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(input_list):\n \"\"\"\n Returns a list of all pairs of consecutive items in a given list.\n\n Args:\n input_list: A list of items.\n\n Returns:\n A list of tuples, where each tuple contains a pair of consecutive items from the input list.\n \"\"\"\n return list(zip(input_list, input_list[1:]))", "matching_cluster_idx": 5}, {"solution": "def pair_wise(items):\n \"\"\"\n Returns a list of all pairs of consecutive items in a given list.\n \n Args:\n items: A list of items.\n \n Returns:\n A list of tuples, where each tuple represents a pair of consecutive items.\n \"\"\"\n pairs = []\n for i in range(len(items) - 1):\n pairs.append((items[i], items[i+1]))\n return pairs", "matching_cluster_idx": 2}, {"solution": "def pair_wise(lst):\n \"\"\"\n Write a function to return a list of all pairs of consecutive items in a given list.\n assert pair_wise([1,1,2,3,3,4,4,5])==[(1, 1), (1, 2), (2, 3), (3, 3), (3, 4), (4, 4), (4, 5)]\n \"\"\"\n return list(zip(lst, lst[1:]))", "matching_cluster_idx": 5}, {"solution": "def pair_wise(items):\n \"\"\"\n Returns a list of all pairs of consecutive items in a given list.\n\n Args:\n items: A list of items.\n\n Returns:\n A list of tuples, where each tuple represents a pair of consecutive items.\n \"\"\"\n return [(items[i], items[i+1]) for i in range(len(items)-1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(nums):\n \"\"\"\n Returns a list of all pairs of consecutive items in a given list.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n A list of tuples, where each tuple represents a pair of consecutive items from the input list.\n \"\"\"\n return list(zip(nums, nums[1:]))", "matching_cluster_idx": 5}, {"solution": "def pair_wise(data):\n \"\"\"\n Returns a list of all pairs of consecutive items in a given list.\n \n Args:\n data: A list of items.\n\n Returns:\n A list of tuples, where each tuple represents a pair of consecutive items from the input list.\n \"\"\"\n pairs = []\n for i in range(len(data)-1):\n pairs.append((data[i], data[i+1]))\n return pairs", "matching_cluster_idx": 2}, {"solution": "def pair_wise(lst):\n \"\"\"\n Returns a list of all pairs of consecutive items in a given list.\n \n For example:\n pair_wise([1,1,2,3,3,4,4,5])==[(1, 1), (1, 2), (2, 3), (3, 3), (3, 4), (4, 4), (4, 5)]\n \"\"\"\n pairs = []\n for i in range(len(lst) - 1):\n pairs.append((lst[i], lst[i+1]))\n return pairs", "matching_cluster_idx": 2}, {"solution": "def pair_wise(lst):\n \"\"\"\n Returns a list of all pairs of consecutive items in a given list.\n\n Args:\n lst: A list of items.\n\n Returns:\n A list of tuples, where each tuple represents a pair of consecutive items in the input list.\n \"\"\"\n return [(lst[i], lst[i+1]) for i in range(len(lst)-1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n \"\"\"\n Returns a list of all pairs of consecutive items in a given list.\n\n Args:\n lst: A list of items.\n\n Returns:\n A list of tuples, where each tuple represents a pair of consecutive items.\n \"\"\"\n return list(zip(lst, lst[1:]))", "matching_cluster_idx": 5}, {"solution": "def pair_wise(data):\n \"\"\"\n Returns a list of all pairs of consecutive items in a given list.\n\n Args:\n data: A list of items.\n\n Returns:\n A list of tuples, where each tuple represents a pair of consecutive items.\n \"\"\"\n pairs = []\n for i in range(len(data) - 1):\n pairs.append((data[i], data[i+1]))\n return pairs", "matching_cluster_idx": 2}, {"solution": "def pair_wise(nums):\n \"\"\"\n Return a list of all pairs of consecutive items in a given list.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n A list of tuples, where each tuple represents a pair of consecutive items.\n \"\"\"\n return list(zip(nums, nums[1:]))", "matching_cluster_idx": 5}, {"solution": "def pair_wise(data):\n \"\"\"\n Return a list of all pairs of consecutive items in a given list.\n \n Args:\n data: A list of items.\n\n Returns:\n A list of tuples, where each tuple represents a pair of consecutive items.\n \"\"\"\n pairs = []\n for i in range(len(data) - 1):\n pairs.append((data[i], data[i+1]))\n return pairs", "matching_cluster_idx": 2}]}, "Mbpp/775": {"dps": 94.39999999999999, "dps_norm": 71.42857142857143, "pass@1": 100.0, "profiled": [{"solution": "def odd_position(nums):\n \"\"\"\n Checks if every odd index contains an odd number in a given list.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n True if every odd index contains an odd number, False otherwise.\n \"\"\"\n for i in range(1, len(nums), 2):\n if nums[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(data):\n \"\"\"Checks if every odd index in a list contains an odd number.\n\n Args:\n data: A list of numbers.\n\n Returns:\n True if every odd index contains an odd number, False otherwise.\n \"\"\"\n for i in range(1, len(data), 2):\n if data[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(nums):\n \"\"\"\n Checks if every odd index in a list contains an odd number.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n True if every odd index contains an odd number, False otherwise.\n \"\"\"\n for i in range(1, len(nums), 2):\n if nums[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(nums):\n \"\"\"\n Checks whether every odd index contains odd numbers in a given list.\n\n Args:\n nums: A list of integers.\n\n Returns:\n True if every odd index contains an odd number, False otherwise.\n \"\"\"\n for i in range(1, len(nums), 2):\n if nums[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n \"\"\"\n Checks if every odd index contains odd numbers in a given list.\n\n Args:\n lst: A list of numbers.\n\n Returns:\n True if every odd index contains an odd number, False otherwise.\n \"\"\"\n for i in range(1, len(lst), 2):\n if lst[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(nums):\n \"\"\"\n Check if every odd index contains odd numbers of a given list.\n\n Args:\n nums: A list of integers.\n\n Returns:\n True if every odd index contains an odd number, False otherwise.\n \"\"\"\n for i in range(1, len(nums), 2):\n if nums[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(data):\n \"\"\"\n Checks if every odd index contains an odd number in a given list.\n\n Args:\n data: A list of numbers.\n\n Returns:\n True if every odd index contains an odd number, False otherwise.\n \"\"\"\n for i in range(1, len(data), 2):\n if data[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(nums):\n \"\"\"\n Checks if every odd index contains an odd number in a given list.\n\n Args:\n nums: A list of integers.\n\n Returns:\n True if every odd index contains an odd number, False otherwise.\n \"\"\"\n\n for i in range(1, len(nums), 2):\n if nums[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(nums):\n \"\"\"\n Checks if every odd index contains an odd number in a given list.\n\n Args:\n nums: A list of integers.\n\n Returns:\n True if every odd index contains an odd number, False otherwise.\n \"\"\"\n for i in range(1, len(nums), 2):\n if nums[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(arr):\n \"\"\"\n Checks whether every odd index in a list contains an odd number.\n\n Args:\n arr: A list of numbers.\n\n Returns:\n True if every odd index contains an odd number, False otherwise.\n \"\"\"\n for i in range(1, len(arr), 2):\n if arr[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(nums):\n \"\"\"\n Checks if every odd index in a list contains an odd number.\n\n Args:\n nums: A list of integers.\n\n Returns:\n True if every odd index contains an odd number, False otherwise.\n \"\"\"\n for i in range(1, len(nums), 2):\n if nums[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(data):\n \"\"\"Checks if every odd index contains an odd number in a list.\n\n Args:\n data: A list of integers.\n\n Returns:\n True if every odd index contains an odd number, False otherwise.\n \"\"\"\n\n for i in range(1, len(data), 2):\n if data[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(nums):\n \"\"\"\n Checks if every odd index in a list contains an odd number.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n True if every odd index contains an odd number, False otherwise.\n \"\"\"\n for i in range(1, len(nums), 2):\n if nums[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n \"\"\"\n Checks if every odd index in a list contains an odd number.\n\n Args:\n lst: A list of integers.\n\n Returns:\n True if every odd index contains an odd number, False otherwise.\n \"\"\"\n for i in range(1, len(lst), 2):\n if lst[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(arr):\n \"\"\"\n Checks if every odd index in a list contains an odd number.\n\n Args:\n arr: A list of numbers.\n\n Returns:\n True if every odd index contains an odd number, False otherwise.\n \"\"\"\n\n for i in range(1, len(arr), 2): # Iterate over odd indices\n if arr[i] % 2 == 0: # Check if the number at the odd index is even\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(numbers):\n \"\"\"\n Checks if every odd index in a list contains an odd number.\n\n Args:\n numbers: A list of integers.\n\n Returns:\n True if every odd index contains an odd number, False otherwise.\n \"\"\"\n\n for i in range(1, len(numbers), 2):\n if numbers[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(nums):\n \"\"\"\n Checks if every odd index contains odd numbers of a given list.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n True if every odd index contains an odd number, False otherwise.\n \"\"\"\n for i in range(1, len(nums), 2):\n if nums[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(numbers):\n \"\"\"\n Checks if every odd index contains an odd number in a given list.\n\n Args:\n numbers: A list of integers.\n\n Returns:\n True if every odd index contains an odd number, False otherwise.\n \"\"\"\n for i in range(1, len(numbers), 2):\n if numbers[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(arr):\n \"\"\"\n Checks if every odd index contains an odd number in a given list.\n\n Args:\n arr: A list of integers.\n\n Returns:\n True if every odd index contains an odd number, False otherwise.\n \"\"\"\n for i in range(1, len(arr), 2): # Iterate through odd indices\n if arr[i] % 2 == 0: # Check if the element is even\n return False # If even, return False\n return True # If all odd indices have odd numbers, return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(nums):\n \"\"\"\n Checks if every odd index in a list contains an odd number.\n\n Args:\n nums: A list of numbers.\n\n Returns:\n True if every odd index contains an odd number, False otherwise.\n \"\"\"\n for i in range(1, len(nums), 2):\n if nums[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}]}, "Mbpp/777": {"dps": 47.95918367346939, "dps_norm": 62.22222222222222, "pass@1": 100.0, "profiled": [{"solution": "def find_sum(nums):\n \"\"\"\n Finds the sum of non-repeated elements in a given list.\n\n Args:\n nums: A list of integers.\n\n Returns:\n The sum of non-repeated elements in the list.\n \"\"\"\n seen = set()\n total = 0\n for num in nums:\n if num not in seen:\n seen.add(num)\n total += num\n return total", "matching_cluster_idx": 4}, {"solution": "def find_sum(nums):\n \"\"\"\n Finds the sum of non-repeated elements in a given list.\n\n Args:\n nums: A list of integers.\n\n Returns:\n The sum of non-repeated elements in the list.\n \"\"\"\n unique_nums = set(nums)\n return sum(unique_nums)", "matching_cluster_idx": 8}, {"solution": "def find_sum(nums):\n \"\"\"\n Finds the sum of non-repeated elements in a given list.\n\n Args:\n nums: A list of integers.\n\n Returns:\n The sum of non-repeated elements.\n \"\"\"\n seen = set()\n total = 0\n for num in nums:\n if num not in seen:\n seen.add(num)\n total += num\n return total", "matching_cluster_idx": 4}, {"solution": "def find_sum(data):\n \"\"\"\n Finds the sum of non-repeated elements in a given list.\n\n Args:\n data: A list of integers.\n\n Returns:\n The sum of non-repeated elements in the list.\n \"\"\"\n seen = set()\n total = 0\n for num in data:\n if num not in seen:\n seen.add(num)\n total += num\n return total", "matching_cluster_idx": 4}, {"solution": "def find_sum(nums):\n \"\"\"\n Finds the sum of non-repeated elements in a given list.\n\n Args:\n nums: A list of integers.\n\n Returns:\n The sum of the non-repeated elements in the list.\n \"\"\"\n seen = set()\n total = 0\n for num in nums:\n if num not in seen:\n seen.add(num)\n total += num\n return total", "matching_cluster_idx": 4}, {"solution": "def find_sum(nums):\n \"\"\"\n Finds the sum of non-repeated elements in a given list.\n\n Args:\n nums: A list of integers.\n\n Returns:\n The sum of non-repeated elements in the list.\n \"\"\"\n seen = set()\n total = 0\n for num in nums:\n if num not in seen:\n seen.add(num)\n total += num\n return total", "matching_cluster_idx": 4}, {"solution": "def find_sum(nums):\n \"\"\"\n Finds the sum of non-repeated elements in a given list.\n\n Args:\n nums: A list of integers.\n\n Returns:\n The sum of non-repeated elements in the list.\n \"\"\"\n seen = set()\n total = 0\n for num in nums:\n if num not in seen:\n seen.add(num)\n total += num\n return total", "matching_cluster_idx": 4}, {"solution": "def find_sum(nums):\n \"\"\"\n Finds the sum of non-repeated elements in a list.\n\n Args:\n nums: A list of integers.\n\n Returns:\n The sum of non-repeated elements in the list.\n \"\"\"\n\n seen = set()\n sum = 0\n for num in nums:\n if num not in seen:\n seen.add(num)\n sum += num\n return sum", "matching_cluster_idx": 4}, {"solution": "def find_sum(nums):\n \"\"\"\n Find the sum of non-repeated elements in a given list.\n\n Args:\n nums: A list of integers.\n\n Returns:\n The sum of non-repeated elements in the list.\n \"\"\"\n\n seen = set()\n sum_non_repeated = 0\n for num in nums:\n if num not in seen:\n seen.add(num)\n sum_non_repeated += num\n return sum_non_repeated", "matching_cluster_idx": 4}, {"solution": "def find_sum(nums):\n \"\"\"\n Finds the sum of non-repeated elements in a given list.\n \n Args:\n nums: A list of integers.\n \n Returns:\n The sum of the non-repeated elements in the list.\n \"\"\"\n seen = set()\n total = 0\n for num in nums:\n if num not in seen:\n seen.add(num)\n total += num\n return total", "matching_cluster_idx": 4}, {"solution": "def find_sum(nums):\n \"\"\"\n This function finds the sum of non-repeated elements in a given list.\n Args:\n nums: A list of integers.\n Returns:\n The sum of non-repeated elements in the list.\n \"\"\"\n seen = set()\n sum = 0\n for num in nums:\n if num not in seen:\n seen.add(num)\n sum += num\n return sum", "matching_cluster_idx": 4}, {"solution": "def find_sum(nums):\n \"\"\"\n Finds the sum of non-repeated elements in a given list.\n\n Args:\n nums: A list of integers.\n\n Returns:\n The sum of the non-repeated elements in the list.\n \"\"\"\n unique_nums = set(nums) \n return sum(unique_nums)", "matching_cluster_idx": 8}, {"solution": "def find_sum(nums):\n \"\"\"\n Finds the sum of non-repeated elements in a given list.\n\n Args:\n nums: A list of integers.\n\n Returns:\n The sum of non-repeated elements in the list.\n \"\"\"\n unique_nums = set(nums) # Use a set to efficiently store unique elements\n sum_of_unique = sum(unique_nums) \n return sum_of_unique", "matching_cluster_idx": 8}, {"solution": "def find_sum(nums):\n \"\"\"\n Finds the sum of non-repeated elements in a given list.\n\n Args:\n nums: A list of integers.\n\n Returns:\n The sum of non-repeated elements.\n \"\"\"\n seen = set()\n total = 0\n for num in nums:\n if num not in seen:\n seen.add(num)\n total += num\n return total", "matching_cluster_idx": 4}, {"solution": "def find_sum(nums):\n \"\"\"\n Finds the sum of non-repeated elements in a given list.\n\n Args:\n nums: A list of integers.\n\n Returns:\n The sum of non-repeated elements in the list.\n \"\"\"\n\n seen = set()\n total = 0\n for num in nums:\n if num not in seen:\n seen.add(num)\n total += num\n return total", "matching_cluster_idx": 4}, {"solution": "def find_sum(nums):\n \"\"\"\n Finds the sum of non-repeated elements in a given list.\n\n Args:\n nums: A list of integers.\n\n Returns:\n The sum of non-repeated elements in the list.\n \"\"\"\n\n seen = set()\n total = 0\n for num in nums:\n if num not in seen:\n seen.add(num)\n total += num\n return total", "matching_cluster_idx": 4}, {"solution": "def find_sum(nums):\n \"\"\"\n Finds the sum of non-repeated elements in a given list.\n\n Args:\n nums: A list of integers.\n\n Returns:\n The sum of non-repeated elements in the list.\n \"\"\"\n seen = set()\n total = 0\n for num in nums:\n if num not in seen:\n seen.add(num)\n total += num\n return total", "matching_cluster_idx": 4}, {"solution": "def find_sum(data):\n \"\"\"\n Finds the sum of non-repeated elements in a given list.\n\n Args:\n data: A list of integers.\n\n Returns:\n The sum of non-repeated elements in the list.\n \"\"\"\n seen = set()\n total = 0\n for num in data:\n if num not in seen:\n seen.add(num)\n total += num\n return total", "matching_cluster_idx": 4}, {"solution": "def find_sum(nums):\n \"\"\"\n Finds the sum of non-repeated elements in a given list.\n\n Args:\n nums: A list of integers.\n\n Returns:\n The sum of the non-repeated elements in the list.\n \"\"\"\n seen = set()\n sum_non_repeated = 0\n for num in nums:\n if num not in seen:\n seen.add(num)\n sum_non_repeated += num\n return sum_non_repeated", "matching_cluster_idx": 4}, {"solution": "def find_sum(nums):\n \"\"\"\n Finds the sum of non-repeated elements in a given list.\n\n Args:\n nums: A list of integers.\n\n Returns:\n The sum of non-repeated elements in the list.\n \"\"\"\n seen = set()\n sum = 0\n for num in nums:\n if num not in seen:\n seen.add(num)\n sum += num\n return sum", "matching_cluster_idx": 4}]}, "Mbpp/781": {"dps": 88.58267716535433, "dps_norm": 60.0, "pass@1": 88.0, "profiled": [{"solution": "def count_divisors(num):\n \"\"\"\n This function checks whether the count of divisors of a number is even.\n\n Args:\n num: An integer.\n\n Returns:\n True if the count of divisors is even, False otherwise.\n \"\"\"\n count = 0\n for i in range(1, num + 1):\n if num % i == 0:\n count += 1\n return count % 2 == 0", "matching_cluster_idx": 1}, {"solution": "def count_divisors(n):\n \"\"\"\n Counts the number of divisors of a given integer and returns whether it's even.\n\n Args:\n n: The integer to check.\n\n Returns:\n True if the number of divisors is even, False otherwise.\n \"\"\"\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n if i == n // i: # Handle perfect squares\n count += 1\n else:\n count += 2\n return count % 2 == 0", "matching_cluster_idx": 3}, {"solution": "def count_divisors(n):\n \"\"\"\n This function counts the number of divisors of a given integer and returns True if the count is even, False otherwise.\n \"\"\"\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count % 2 == 0", "matching_cluster_idx": 1}, {"solution": "def count_divisors(n):\n \"\"\"\n This function takes an integer n and returns True if the count of its divisors is even, otherwise False.\n \"\"\"\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n count += 2 # Increment by 2 for both i and n/i\n if int(n**0.5) * int(n**0.5) == n: # Handle perfect squares\n count -= 1\n return count % 2 == 0", "matching_cluster_idx": 3}, {"solution": "def count_divisors(num):\n \"\"\"\n This function checks if the count of divisors of a given number is even.\n\n Args:\n num: The integer to check.\n\n Returns:\n True if the count of divisors is even, False otherwise.\n \"\"\"\n count = 0\n for i in range(1, num + 1):\n if num % i == 0:\n count += 1\n return count % 2 == 0", "matching_cluster_idx": 1}, {"solution": "def count_divisors(n):\n \"\"\"\n Checks whether the count of divisors of a given number is even.\n\n Args:\n n: An integer.\n\n Returns:\n True if the count of divisors of n is even, False otherwise.\n \"\"\"\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count % 2 == 0", "matching_cluster_idx": 1}, {"solution": "def count_divisors(n):\n \"\"\"\n This function checks whether the count of divisors is even.\n\n Args:\n n: The integer to check.\n\n Returns:\n True if the count of divisors is even, False otherwise.\n \"\"\"\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count % 2 == 0", "matching_cluster_idx": 1}, {"solution": "def count_divisors(n):\n \"\"\"\n This function checks whether the count of divisors of a given number is even.\n\n Args:\n n: An integer.\n\n Returns:\n True if the count of divisors of n is even, False otherwise.\n \"\"\"\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count % 2 == 0", "matching_cluster_idx": 1}, {"solution": "def count_divisors(num):\n \"\"\"\n Checks whether the count of divisors of a given number is even.\n\n Args:\n num: An integer.\n\n Returns:\n True if the count of divisors of num is even, False otherwise.\n \"\"\"\n count = 0\n for i in range(1, int(num**0.5) + 1):\n if num % i == 0:\n count += 2 # If i is a divisor, num/i is also a divisor\n if int(num**0.5)**2 == num: # Handle perfect squares\n count -= 1\n return count % 2 == 0", "matching_cluster_idx": 3}, {"solution": "def count_divisors(num):\n \"\"\"\n Checks whether the count of divisors of a number is even.\n\n Args:\n num: The number to check.\n\n Returns:\n True if the count of divisors is even, False otherwise.\n \"\"\"\n count = 0\n for i in range(1, num + 1):\n if num % i == 0:\n count += 1\n return count % 2 == 0", "matching_cluster_idx": 1}, {"solution": "def count_divisors(n):\n \"\"\"\n Checks whether the count of divisors of a given number is even.\n\n Args:\n n: The integer to check.\n\n Returns:\n True if the count of divisors is even, False otherwise.\n \"\"\"\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count % 2 == 0", "matching_cluster_idx": 1}, {"solution": "def count_divisors(n):\n \"\"\"\n This function takes an integer n as input and returns True if the count of divisors of n is even, False otherwise. \n \"\"\"\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n count += 2 # Add 2 for both i and n/i as divisors\n \n if int(n**0.5)**2 == n:\n count -= 1 # Adjust for the case when n is a perfect square\n\n return count % 2 == 0", "matching_cluster_idx": 3}, {"solution": "def count_divisors(n):\n \"\"\"\n This function checks whether the count of divisors of a given number is even.\n \"\"\"\n count = 0\n for i in range(1, int(n ** 0.5) + 1):\n if n % i == 0:\n count += 2 # If i is a divisor, both i and n/i are divisors\n if int(n ** 0.5) ** 2 == n: # Check for perfect squares\n count -= 1 \n return count % 2 == 0", "matching_cluster_idx": 3}, {"solution": "def count_divisors(n):\n \"\"\"\n This function checks whether the count of divisors of a given number is even.\n\n Args:\n n: An integer.\n\n Returns:\n True if the count of divisors of n is even, False otherwise.\n \"\"\"\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n count += 2 # If i is a divisor, n/i is also a divisor\n if int(n**0.5) * int(n**0.5) == n: # Handle perfect squares\n count -= 1\n return count % 2 == 0", "matching_cluster_idx": 3}, {"solution": "def count_divisors(n):\n \"\"\"\n This function checks whether the count of divisors is even.\n\n Args:\n n: An integer.\n\n Returns:\n True if the count of divisors of n is even, False otherwise.\n \"\"\"\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count % 2 == 0", "matching_cluster_idx": 1}, {"solution": "def count_divisors(n):\n \"\"\"\n This function takes an integer n as input and returns True if the count of its divisors is even, False otherwise.\n\n Args:\n n: An integer.\n\n Returns:\n True if the count of divisors of n is even, False otherwise.\n \"\"\"\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n if i * i == n:\n count += 1\n else:\n count += 2\n return count % 2 == 0", "matching_cluster_idx": 3}, {"solution": "def count_divisors(n):\n \"\"\"\n Checks whether the count of divisors of a number is even.\n\n Args:\n n: An integer.\n\n Returns:\n True if the count of divisors of n is even, False otherwise.\n \"\"\"\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n count += 2 # If i is a divisor, n/i is also a divisor\n if int(n**0.5)**2 == n:\n count -= 1 # Adjust count if n is a perfect square\n return count % 2 == 0", "matching_cluster_idx": 3}, {"solution": "def count_divisors(n):\n \"\"\"\n Checks whether the count of divisors of a number is even.\n\n Args:\n n: An integer.\n\n Returns:\n True if the count of divisors is even, False otherwise.\n \"\"\"\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n count += 2 # Count both i and n/i as divisors\n if int(n**0.5) * int(n**0.5) == n:\n count -= 1 # Adjust for double-counting the square root\n return count % 2 == 0", "matching_cluster_idx": 3}, {"solution": "def count_divisors(n):\n \"\"\"\n This function counts the number of divisors of a given integer.\n\n Args:\n n: The integer to count divisors for.\n\n Returns:\n True if the count of divisors is even, False otherwise.\n \"\"\"\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n count += 2 \n if int(n**0.5)**2 == n:\n count -= 1\n return count % 2 == 0", "matching_cluster_idx": 3}, {"solution": "def count_divisors(n):\n \"\"\"\n This function checks if the count of divisors of a given number is even.\n\n Args:\n n: An integer.\n\n Returns:\n True if the count of divisors is even, False otherwise.\n \"\"\"\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count % 2 == 0", "matching_cluster_idx": 1}]}, "Mbpp/800": {"dps": 95.67164179104478, "dps_norm": 98.0, "pass@1": 100.0, "profiled": [{"solution": "def remove_all_spaces(text):\n \"\"\"\n Removes all whitespaces from a string.\n\n Args:\n text (str): The input string.\n\n Returns:\n str: The string with all whitespaces removed.\n \"\"\"\n return text.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(text):\n \"\"\"\n Removes all whitespaces from a string.\n \n Args:\n text: The input string.\n \n Returns:\n The string with all whitespaces removed.\n \"\"\"\n return text.replace(\" \", \"\")", "matching_cluster_idx": 3}, {"solution": "def remove_all_spaces(text):\n \"\"\"\n Removes all whitespaces from a string.\n\n Args:\n text: The string to remove whitespaces from.\n\n Returns:\n The string with all whitespaces removed.\n \"\"\"\n return text.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(text):\n \"\"\"\n Removes all whitespaces from a string.\n\n Args:\n text: The string to remove whitespaces from.\n\n Returns:\n The string with all whitespaces removed.\n \"\"\"\n return text.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(text):\n \"\"\"Removes all whitespaces from a string.\"\"\"\n return text.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(text):\n \"\"\"Removes all whitespaces from a string.\n\n Args:\n text: The input string.\n\n Returns:\n The string with all whitespaces removed.\n \"\"\"\n return text.replace(\" \",\"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(text):\n \"\"\"\n Removes all whitespaces from a string.\n\n Args:\n text: The string to remove whitespaces from.\n\n Returns:\n The string with all whitespaces removed.\n \"\"\"\n return text.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(text):\n \"\"\"\n Removes all whitespaces from a string.\n \"\"\"\n return text.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(text):\n \"\"\"\n Removes all whitespaces from a string.\n \n Args:\n text: The input string.\n\n Returns:\n The string with all whitespaces removed.\n \"\"\"\n return text.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(text):\n \"\"\"Removes all whitespaces from a string.\n\n Args:\n text: The string to remove whitespaces from.\n\n Returns:\n The string with all whitespaces removed.\n \"\"\"\n return text.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(text):\n \"\"\"Removes all whitespaces from a string.\n\n Args:\n text: The input string.\n\n Returns:\n The string with all whitespaces removed.\n \"\"\"\n return text.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(text):\n \"\"\"Removes all whitespaces from a string.\n\n Args:\n text: The string to remove whitespaces from.\n\n Returns:\n The string with all whitespaces removed.\n \"\"\"\n return text.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(text):\n \"\"\"\n Removes all whitespaces from a string.\n\n Args:\n text: The string to remove whitespaces from.\n\n Returns:\n The string with all whitespaces removed.\n \"\"\"\n return text.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(text):\n \"\"\"\n Removes all whitespaces from a string.\n\n Args:\n text: The input string.\n\n Returns:\n The string with all whitespaces removed.\n \"\"\"\n return text.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(text):\n \"\"\"Removes all whitespaces from a string.\n\n Args:\n text: The input string.\n\n Returns:\n The string with all whitespaces removed.\n \"\"\"\n return text.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(text):\n \"\"\"\n Removes all whitespaces from a string.\n\n Args:\n text: The string to remove whitespaces from.\n\n Returns:\n The string with all whitespaces removed.\n \"\"\"\n return text.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(text):\n \"\"\"\n Removes all whitespaces from a string.\n \n Args:\n text (str): The input string.\n\n Returns:\n str: The string with all whitespaces removed.\n \n Example:\n remove_all_spaces('python program') == 'pythonprogram'\n \"\"\"\n return text.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(text):\n \"\"\"\n Removes all whitespaces from a string.\n \"\"\"\n return text.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(text):\n \"\"\"\n Removes all whitespaces from a string.\n \n Args:\n text: The input string.\n \n Returns:\n The string with all whitespaces removed.\n \"\"\"\n return text.replace(\" \", \"\")", "matching_cluster_idx": 3}, {"solution": "def remove_all_spaces(text):\n \"\"\"\n Removes all whitespaces from a string.\n\n Args:\n text: The input string.\n\n Returns:\n The string with all whitespaces removed.\n \"\"\"\n return text.replace(' ', '')", "matching_cluster_idx": 4}]}, "Mbpp/805": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def max_sum_list(matrix):\n \"\"\"\n Returns the list in a list of lists whose sum of elements is the highest.\n\n Args:\n matrix: A list of lists of integers.\n\n Returns:\n A list of integers representing the list with the highest sum.\n \"\"\"\n max_sum = float('-inf')\n max_sum_list = []\n for sublist in matrix:\n current_sum = sum(sublist)\n if current_sum > max_sum:\n max_sum = current_sum\n max_sum_list = sublist\n return max_sum_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(nested_list):\n \"\"\"\n Finds the list within a list of lists with the highest sum of elements.\n\n Args:\n nested_list: A list of lists of integers.\n\n Returns:\n The list with the highest sum of elements.\n \"\"\"\n\n max_sum = float('-inf') # Initialize max_sum to negative infinity\n max_sum_list = []\n for sublist in nested_list:\n current_sum = sum(sublist)\n if current_sum > max_sum:\n max_sum = current_sum\n max_sum_list = sublist\n return max_sum_list\nnested_list = [[1,2,3], [4,5,6], [10,11,12], [7,8,9]]", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(matrix):\n \"\"\"\n Finds the sublist in a list of lists with the highest sum of elements.\n\n Args:\n matrix: A list of lists of numbers.\n\n Returns:\n A list containing the elements of the sublist with the highest sum.\n \"\"\"\n max_sum = float('-inf')\n max_list = []\n for sublist in matrix:\n current_sum = sum(sublist)\n if current_sum > max_sum:\n max_sum = current_sum\n max_list = sublist\n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(list_of_lists):\n \"\"\"\n Finds the sublist within a list of lists that has the highest sum of elements.\n\n Args:\n list_of_lists: A list of lists of numbers.\n\n Returns:\n A list containing the elements of the sublist with the highest sum.\n \"\"\"\n max_sum = float('-inf')\n max_sum_list = []\n for sublist in list_of_lists:\n current_sum = sum(sublist)\n if current_sum > max_sum:\n max_sum = current_sum\n max_sum_list = sublist\n return max_sum_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lst):\n \"\"\"\n Returns the list in a list of lists whose sum of elements is the highest.\n\n Args:\n lst: A list of lists of integers.\n\n Returns:\n The list with the highest sum.\n \"\"\"\n max_sum = float('-inf')\n max_sum_list = []\n for sublist in lst:\n current_sum = sum(sublist)\n if current_sum > max_sum:\n max_sum = current_sum\n max_sum_list = sublist\n return max_sum_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(matrix):\n \"\"\"\n Finds the sublist within a list of lists that has the highest sum of elements.\n\n Args:\n matrix: A list of lists of integers.\n\n Returns:\n A list containing the elements of the sublist with the highest sum.\n \"\"\"\n max_sum = float('-inf') \n result_list = []\n\n for sublist in matrix:\n current_sum = sum(sublist)\n if current_sum > max_sum:\n max_sum = current_sum\n result_list = sublist \n return result_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(nested_list):\n \"\"\"\n Finds the list within a list of lists that has the highest sum of elements.\n\n Args:\n nested_list: A list of lists of numbers.\n\n Returns:\n The list with the highest sum.\n \"\"\"\n max_sum_list = nested_list[0] # Initialize with the first list\n max_sum = sum(max_sum_list) \n\n for sublist in nested_list:\n current_sum = sum(sublist)\n if current_sum > max_sum:\n max_sum = current_sum\n max_sum_list = sublist \n return max_sum_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(matrix):\n \"\"\"\n Finds the list within a list of lists that has the highest sum of elements.\n\n Args:\n matrix: A list of lists of integers.\n\n Returns:\n The list within the matrix that has the highest sum.\n \"\"\"\n max_sum = float('-inf') \n max_sum_list = []\n for sublist in matrix:\n current_sum = sum(sublist)\n if current_sum > max_sum:\n max_sum = current_sum\n max_sum_list = sublist\n return max_sum_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(matrix):\n \"\"\"\n Finds the list within a list of lists that has the highest sum of elements.\n\n Args:\n matrix: A list of lists of numbers.\n\n Returns:\n The list with the highest sum of elements.\n \"\"\"\n max_sum = float('-inf') \n result_list = []\n for sublist in matrix:\n current_sum = sum(sublist)\n if current_sum > max_sum:\n max_sum = current_sum\n result_list = sublist\n return result_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(data):\n \"\"\"\n Returns the list in a list of lists whose sum of elements is the highest.\n \n Args:\n data: A list of lists of integers.\n \n Returns:\n A list containing the elements of the list with the highest sum.\n \"\"\"\n max_sum_list = data[0]\n max_sum = sum(max_sum_list)\n for sublist in data:\n current_sum = sum(sublist)\n if current_sum > max_sum:\n max_sum = current_sum\n max_sum_list = sublist\n return max_sum_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(list_of_lists):\n \"\"\"\n Finds the list within a list of lists that has the highest sum of elements.\n\n Args:\n list_of_lists: A list of lists of numbers.\n\n Returns:\n The list with the highest sum of elements.\n \"\"\"\n max_sum = float('-inf')\n max_sum_list = []\n for sublist in list_of_lists:\n current_sum = sum(sublist)\n if current_sum > max_sum:\n max_sum = current_sum\n max_sum_list = sublist\n return max_sum_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(list_of_lists):\n \"\"\"\n Finds the list in a list of lists with the highest sum of elements.\n\n Args:\n list_of_lists: A list of lists of numbers.\n\n Returns:\n A list containing the elements of the list with the highest sum.\n \"\"\"\n\n max_sum = float('-inf')\n result = []\n\n for sublist in list_of_lists:\n current_sum = sum(sublist)\n if current_sum > max_sum:\n max_sum = current_sum\n result = sublist\n return result", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(nested_list):\n \"\"\"\n Returns the list in a list of lists whose sum of elements is the highest.\n\n Args:\n nested_list: A list of lists of integers.\n\n Returns:\n A list of integers representing the list with the highest sum.\n \"\"\"\n max_sum = float('-inf')\n max_sum_list = []\n for sublist in nested_list:\n current_sum = sum(sublist)\n if current_sum > max_sum:\n max_sum = current_sum\n max_sum_list = sublist\n return max_sum_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lst):\n \"\"\"\n Finds the list in a list of lists whose sum of elements is the highest.\n\n Args:\n lst: A list of lists of numbers.\n\n Returns:\n The list with the highest sum.\n \"\"\"\n max_sum = float('-inf')\n max_list = []\n for sub_list in lst:\n current_sum = sum(sub_list)\n if current_sum > max_sum:\n max_sum = current_sum\n max_list = sub_list\n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n \"\"\"\n Finds the list in a list of lists whose sum of elements is the highest.\n\n Args:\n lists: A list of lists of numbers.\n\n Returns:\n The list with the highest sum.\n \"\"\"\n max_sum = float('-inf') \n result_list = []\n for sublist in lists:\n current_sum = sum(sublist)\n if current_sum > max_sum:\n max_sum = current_sum\n result_list = sublist\n return result_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(nested_list):\n \"\"\"\n Finds the list within a list of lists that has the highest sum of elements.\n\n Args:\n nested_list: A list of lists of numbers.\n\n Returns:\n A list containing the elements of the list with the highest sum.\n \"\"\"\n max_sum = float('-inf') \n result = []\n for sublist in nested_list:\n current_sum = sum(sublist)\n if current_sum > max_sum:\n max_sum = current_sum\n result = sublist\n return result", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(list_of_lists):\n \"\"\"\n This function returns the list in a list of lists whose sum of elements is the highest.\n\n Args:\n list_of_lists: A list of lists of numbers.\n\n Returns:\n The list with the highest sum.\n \"\"\"\n max_sum_list = list_of_lists[0] \n max_sum = sum(max_sum_list)\n for sublist in list_of_lists:\n current_sum = sum(sublist)\n if current_sum > max_sum:\n max_sum = current_sum\n max_sum_list = sublist\n return max_sum_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(nested_list):\n \"\"\"\n Finds the sublist within a list of lists that has the highest sum of elements.\n\n Args:\n nested_list: A list of lists of numbers.\n\n Returns:\n The sublist with the highest sum of elements.\n \"\"\"\n\n max_sum = float('-inf') \n max_sum_list = []\n for sublist in nested_list:\n current_sum = sum(sublist)\n if current_sum > max_sum:\n max_sum = current_sum\n max_sum_list = sublist\n return max_sum_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(list_of_lists):\n \"\"\"\n Finds the sublist within a list of lists that has the highest sum of elements.\n\n Args:\n list_of_lists: A list of lists of integers.\n\n Returns:\n A list containing the elements of the sublist with the highest sum.\n \"\"\"\n\n max_sum = float('-inf') \n result_list = []\n for sublist in list_of_lists:\n current_sum = sum(sublist)\n if current_sum > max_sum:\n max_sum = current_sum\n result_list = sublist\n return result_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(list_of_lists):\n \"\"\"\n Finds the list within a list of lists that has the highest sum of elements.\n\n Args:\n list_of_lists: A list of lists of integers.\n\n Returns:\n The list with the highest sum of elements.\n \"\"\"\n max_sum_list = list_of_lists[0] # Initialize with the first list\n max_sum = sum(max_sum_list) # Calculate the initial maximum sum\n\n for sublist in list_of_lists:\n current_sum = sum(sublist)\n if current_sum > max_sum:\n max_sum = current_sum\n max_sum_list = sublist\n\n return max_sum_list", "matching_cluster_idx": 4}]}, "Mbpp/808": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def check_K(tup, k):\n \"\"\"\n Check if the given tuples contain the k or not.\n\n Args:\n tup: A tuple of numbers.\n k: An integer to search for in the tuple.\n\n Returns:\n True if k is present in the tuple, False otherwise.\n \"\"\"\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(tuple_data, k):\n \"\"\"\n Check if the given tuples contain the k or not.\n \n Args:\n tuple_data: The input tuple.\n k: The value to search for.\n\n Returns:\n True if k is present in the tuple, False otherwise.\n \"\"\"\n return k in tuple_data", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n \"\"\"\n Checks if the given tuple contains the element 'k'.\n\n Args:\n tup: A tuple of numbers.\n k: An integer to search for in the tuple.\n\n Returns:\n True if 'k' is in the tuple, False otherwise.\n \"\"\"\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n \"\"\"\n Checks if a tuple contains the value k.\n\n Args:\n tup: The tuple to search.\n k: The value to search for.\n\n Returns:\n True if k is in the tuple, False otherwise.\n \"\"\"\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n \"\"\"\n Checks if the given tuple contains the value k.\n\n Args:\n tup: The tuple to search.\n k: The value to search for.\n\n Returns:\n True if k is in the tuple, False otherwise.\n \"\"\"\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(nums, k):\n \"\"\"\n Checks if a tuple contains a given element.\n\n Args:\n nums: A tuple of numbers.\n k: The element to check for.\n\n Returns:\n True if the tuple contains k, False otherwise.\n \"\"\"\n return k in nums", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n \"\"\"\n Checks if a tuple contains the value k.\n\n Args:\n tup: A tuple of numbers.\n k: An integer to search for in the tuple.\n\n Returns:\n True if k is found in the tuple, False otherwise.\n \"\"\"\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(nums, k):\n \"\"\"\n Checks if a tuple contains the given value k.\n\n Args:\n nums: The tuple to search.\n k: The value to search for.\n\n Returns:\n True if the tuple contains k, False otherwise.\n \"\"\"\n return k in nums", "matching_cluster_idx": 5}, {"solution": "def check_K(data, k):\n \"\"\"\n Checks if the given tuples contain the k or not.\n\n Args:\n data: A tuple of numbers.\n k: An integer to search for in the tuple.\n\n Returns:\n True if k is present in the tuple, False otherwise.\n \"\"\"\n return k in data", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n \"\"\"\n Checks if a tuple contains the element k.\n\n Args:\n tup: The tuple to search within.\n k: The element to search for.\n\n Returns:\n True if k is in tup, False otherwise.\n \"\"\"\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n \"\"\"\n Checks if the given tuples contain the k or not.\n\n Args:\n tup: A tuple of numbers.\n k: The number to search for in the tuple.\n\n Returns:\n True if k is present in the tuple, False otherwise.\n \"\"\"\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n \"\"\"\n Checks if a tuple contains a given value 'k'.\n\n Args:\n tup: The tuple to search.\n k: The value to search for.\n\n Returns:\n True if 'k' is in the tuple, False otherwise.\n \"\"\"\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n \"\"\"\n Checks if the given tuple contains the value k.\n\n Args:\n tup: A tuple of integers.\n k: An integer to search for in the tuple.\n\n Returns:\n True if k is found in the tuple, False otherwise.\n \"\"\"\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n \"\"\"\n Checks if the given tuple contains the element k.\n\n Args:\n tup: The tuple to search.\n k: The element to search for.\n\n Returns:\n True if k is in the tuple, False otherwise.\n \"\"\"\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n \"\"\"\n Check if the given tuples contain the k or not.\n\n Args:\n tup (tuple): The tuple to search.\n k (int): The value to search for.\n\n Returns:\n bool: True if k is present in the tuple, False otherwise.\n \"\"\"\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(input_tuple, k):\n \"\"\"\n Check if the given tuples contain the k or not.\n \"\"\"\n return k in input_tuple", "matching_cluster_idx": 5}, {"solution": "def check_K(tuple1, k):\n \"\"\"\n Checks if a given tuple contains the value k.\n\n Args:\n tuple1: The tuple to search within.\n k: The value to search for.\n\n Returns:\n True if k is present in tuple1, False otherwise.\n \"\"\"\n return k in tuple1", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n \"\"\"\n Checks if the given tuples contain the k or not.\n\n Args:\n tup: A tuple.\n k: An integer.\n\n Returns:\n True if the tuple contains k, False otherwise.\n \"\"\"\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(tuple1, k):\n \"\"\"\n Checks if a tuple contains the value 'k'.\n\n Args:\n tuple1: The tuple to search.\n k: The value to search for.\n\n Returns:\n True if 'k' is in the tuple, False otherwise.\n \"\"\"\n return k in tuple1", "matching_cluster_idx": 5}, {"solution": "def check_K(t, k):\n \"\"\"\n Checks if the given tuples contain the k or not.\n\n Args:\n t: The tuple to search in.\n k: The element to search for.\n\n Returns:\n True if k is in the tuple, False otherwise.\n \"\"\"\n return k in t", "matching_cluster_idx": 5}]}}} \ No newline at end of file diff --git a/results/evalperf/gpt-4o-2024-08-06_openai_temp_1.0_evalperf_results.brief.json b/results/evalperf/gpt-4o-2024-08-06_openai_temp_1.0_evalperf_results.brief.json new file mode 100644 index 0000000..dec9d58 --- /dev/null +++ b/results/evalperf/gpt-4o-2024-08-06_openai_temp_1.0_evalperf_results.brief.json @@ -0,0 +1 @@ +{"date": "2024-10-19 16:29", "config": {"n_samples": 100, "temperature": 1.0, "min_correct": 10, "max_profile": 20}, "summary": {"dps": 87.8465793074948, "dps_norm": 82.23308124778713, "pass@1": 86.65254237288136}, "eval": {"HumanEval/9": {"dps": 92.61829652996846, "dps_norm": 91.11111111111111, "pass@1": 100.0, "profiled": [{"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum elements found until given moment\n in the sequence.\n \n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n \n max_so_far = numbers[0]\n result = []\n for num in numbers:\n if num > max_so_far:\n max_so_far = num\n result.append(max_so_far)\n return result", "matching_cluster_idx": 8}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n \n Args:\n numbers (List[int]): A list of integers.\n \n Returns:\n List[int]: A list containing the rolling maximum values.\n \n Example:\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n \n max_list = []\n current_max = float('-inf')\n \n for number in numbers:\n if number > current_max:\n current_max = number\n max_list.append(current_max)\n \n return max_list", "matching_cluster_idx": 8}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n \n max_so_far = numbers[0]\n result = [max_so_far]\n \n for num in numbers[1:]:\n if num > max_so_far:\n max_so_far = num\n result.append(max_so_far)\n \n return result", "matching_cluster_idx": 8}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n \"\"\"\n max_so_far = float('-inf')\n rolling_max_list = []\n for number in numbers:\n if number > max_so_far:\n max_so_far = number\n rolling_max_list.append(max_so_far)\n return rolling_max_list", "matching_cluster_idx": 8}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n \n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n\n max_values = []\n current_max = numbers[0]\n for num in numbers:\n if num > current_max:\n current_max = num\n max_values.append(current_max)\n \n return max_values", "matching_cluster_idx": 8}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n \n max_so_far = numbers[0]\n result = []\n \n for num in numbers:\n max_so_far = max(max_so_far, num)\n result.append(max_so_far)\n \n return result", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\"From a given list of integers, generate a list of rolling maximum elements found until the given moment in the sequence.\"\"\"\n if not numbers:\n return []\n \n result = []\n current_max = numbers[0]\n \n for num in numbers:\n if num > current_max:\n current_max = num\n result.append(current_max)\n \n return result", "matching_cluster_idx": 8}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\"From a given list of integers, generate a list of rolling maximum elements found until the given moment\n in the sequence.\n \n Args:\n numbers (List[int]): A list of integers.\n \n Returns:\n List[int]: A list where each element is the maximum of the elements from the start up to that position.\n \n Examples:\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n \n max_list = []\n current_max = numbers[0]\n \n for num in numbers:\n if num > current_max:\n current_max = num\n max_list.append(current_max)\n \n return max_list", "matching_cluster_idx": 8}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n result = []\n current_max = float('-inf')\n \n for number in numbers:\n current_max = max(current_max, number)\n result.append(current_max)\n \n return result", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" \n From a given list of integers, generate a list of rolling maximum elements found until the given moment\n in the sequence.\n \n Parameters:\n numbers (List[int]): A list of integers.\n \n Returns:\n List[int]: A list where each element is the maximum value found in the input list up to that index.\n \n Examples:\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n \n max_so_far = numbers[0]\n rolling_max_list = [max_so_far]\n \n for num in numbers[1:]:\n if num > max_so_far:\n max_so_far = num\n rolling_max_list.append(max_so_far)\n \n return rolling_max_list", "matching_cluster_idx": 8}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n \n Args:\n numbers (List[int]): A list of integers.\n\n Returns:\n List[int]: A list of integers representing the rolling maximums.\n\n Example:\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n\n result = []\n current_max = numbers[0]\n\n for num in numbers:\n if num > current_max:\n current_max = num\n result.append(current_max)\n\n return result", "matching_cluster_idx": 8}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" \n From a given list of integers, generate a list of rolling maximum elements found until each moment\n in the sequence.\n \n Args:\n numbers: List[int] - A list of integers\n \n Returns:\n List[int] - A list where each element is the maximum of all elements up to that index in the input list\n \n Example:\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n\n result = []\n current_max = float('-inf')\n\n for number in numbers:\n current_max = max(current_max, number)\n result.append(current_max)\n\n return result", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\"From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\"\"\"\n if not numbers:\n return []\n \n rolling_max_list = []\n current_max = numbers[0]\n \n for number in numbers:\n if number > current_max:\n current_max = number\n rolling_max_list.append(current_max)\n \n return rolling_max_list", "matching_cluster_idx": 8}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n \"\"\"\n if not numbers:\n return []\n\n rolling_max_list = []\n current_max = numbers[0]\n \n for num in numbers:\n if num > current_max:\n current_max = num\n rolling_max_list.append(current_max)\n \n return rolling_max_list", "matching_cluster_idx": 8}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n \"\"\"\n if not numbers:\n return []\n\n max_so_far = numbers[0]\n result = [max_so_far]\n\n for num in numbers[1:]:\n if num > max_so_far:\n max_so_far = num\n result.append(max_so_far)\n\n return result", "matching_cluster_idx": 8}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n \n Args:\n numbers (List[int]): List of integers to evaluate.\n \n Returns:\n List[int]: A list containing the rolling maximum values.\n \n Examples:\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n \n max_so_far = numbers[0]\n result = [max_so_far]\n\n for num in numbers[1:]:\n if num > max_so_far:\n max_so_far = num\n result.append(max_so_far)\n \n return result", "matching_cluster_idx": 8}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n\n max_so_far = numbers[0]\n result = [max_so_far]\n\n for num in numbers[1:]:\n if num > max_so_far:\n max_so_far = num\n result.append(max_so_far)\n\n return result", "matching_cluster_idx": 8}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n \n result = []\n current_max = numbers[0]\n\n for num in numbers:\n if num > current_max:\n current_max = num\n result.append(current_max)\n\n return result", "matching_cluster_idx": 8}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n \"\"\"\n if not numbers:\n return []\n\n max_so_far = numbers[0]\n result = [max_so_far]\n\n for number in numbers[1:]:\n if number > max_so_far:\n max_so_far = number\n result.append(max_so_far)\n\n return result", "matching_cluster_idx": 8}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n \n Args:\n numbers (List[int]): List of integers.\n \n Returns:\n List[int]: List containing the rolling maximum at each position.\n \n Example:\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n \n max_so_far = numbers[0]\n rolling_max_list = [max_so_far]\n \n for num in numbers[1:]:\n max_so_far = max(max_so_far, num)\n rolling_max_list.append(max_so_far)\n \n return rolling_max_list", "matching_cluster_idx": 4}]}, "HumanEval/0": {"dps": 45.52325581395348, "dps_norm": 55.0, "pass@1": 100.0, "profiled": [{"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n # Sort the numbers first\n numbers.sort()\n \n # Check consecutive pairs since it is guaranteed that the closest pairs will be consecutive\n for i in range(len(numbers) - 1):\n if abs(numbers[i] - numbers[i + 1]) < threshold:\n return True\n \n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n \n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n # Sort the list of numbers\n numbers.sort()\n # Check consecutive pairs for closeness within the threshold\n for i in range(len(numbers) - 1):\n if abs(numbers[i] - numbers[i + 1]) < threshold:\n return True\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n # Sort the numbers to check adjacent elements for closeness\n sorted_numbers = sorted(numbers)\n \n # Iterate over the sorted list and check the difference between consecutive numbers\n for i in range(len(sorted_numbers) - 1):\n if abs(sorted_numbers[i] - sorted_numbers[i + 1]) < threshold:\n return True\n \n return False", "matching_cluster_idx": 2}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\"\n Check if in given list of numbers, any two numbers are closer to each other than\n the given threshold.\n \"\"\"\n # Sort the numbers to allow checking only consecutive pairs for closeness\n numbers.sort()\n \n # Iterate through the sorted list and compare consecutive elements\n for i in range(len(numbers) - 1):\n if numbers[i+1] - numbers[i] < threshold:\n return True\n \n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\"\n Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n \n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n # Sort the numbers first\n numbers.sort()\n\n # Iterate through the sorted numbers and check consecutive pairs\n for i in range(len(numbers) - 1):\n if abs(numbers[i] - numbers[i + 1]) < threshold:\n return True\n \n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n # Sort the numbers first to make it easier to check pairs\n numbers.sort()\n \n # Compare each pair of consecutive numbers in the sorted list\n for i in range(len(numbers) - 1):\n if abs(numbers[i] - numbers[i + 1]) < threshold:\n return True\n \n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, there are any two numbers closer to each other than\n the given threshold.\n \"\"\"\n # Sort the list of numbers to make it easier to check consecutive elements\n numbers.sort()\n \n # Iterate over the sorted numbers and check the difference between consecutive elements\n for i in range(len(numbers) - 1):\n if abs(numbers[i] - numbers[i + 1]) < threshold:\n return True\n \n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\"\n Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n \"\"\"\n # Sort the list of numbers\n numbers.sort()\n\n # Iterate through the sorted list and check consecutive elements\n for i in range(len(numbers) - 1):\n # If the difference between consecutive elements is less than the threshold, return True\n if numbers[i + 1] - numbers[i] < threshold:\n return True\n \n # If no such pair is found, return False\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n # Sort the numbers first\n numbers.sort()\n\n # Compare each number with the next one in the sorted list\n for i in range(len(numbers) - 1):\n if abs(numbers[i] - numbers[i + 1]) < threshold:\n return True\n\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, there are any two numbers closer to each other than\n given threshold.\n \"\"\"\n # Sort the numbers to ensure that we can easily compare consecutive elements\n sorted_numbers = sorted(numbers)\n \n # Iterate through the sorted numbers and check the difference between consecutive elements\n for i in range(len(sorted_numbers) - 1):\n if abs(sorted_numbers[i] - sorted_numbers[i + 1]) < threshold:\n return True\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n # Sort the numbers first\n sorted_numbers = sorted(numbers)\n \n # Check consecutive pairs only as this is the closest pair after sorting\n for i in range(len(sorted_numbers) - 1):\n if abs(sorted_numbers[i] - sorted_numbers[i + 1]) < threshold:\n return True\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\"\n Check if in given list of numbers, there are any two numbers closer to each other than\n the given threshold.\n \"\"\"\n # Sort the list of numbers\n numbers.sort()\n\n # Iterate through sorted numbers and check adjacent pairs\n for i in range(len(numbers) - 1):\n # Check if the difference between consecutive elements is less than the threshold\n if numbers[i + 1] - numbers[i] < threshold:\n return True\n\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\"Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n # Sort the numbers to ensure we check consecutive pairs for proximity\n numbers.sort()\n \n # Iterate through sorted numbers and check consecutive pairs\n for i in range(len(numbers) - 1):\n if numbers[i + 1] - numbers[i] < threshold:\n return True\n \n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n \"\"\"\n # First, sort the list of numbers\n numbers.sort()\n\n # Iterate through the list and compare consecutive numbers\n for i in range(len(numbers) - 1):\n if abs(numbers[i] - numbers[i + 1]) < threshold:\n return True\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n \n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n # Sort the list to make checking easier\n numbers.sort()\n \n # Iterate through the sorted list and check consecutive pairs\n for i in range(len(numbers) - 1):\n if abs(numbers[i] - numbers[i + 1]) < threshold:\n return True\n \n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n \n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n # Sort the numbers first\n sorted_numbers = sorted(numbers)\n \n # Check consecutive elements in the sorted list\n for i in range(len(sorted_numbers) - 1):\n if abs(sorted_numbers[i] - sorted_numbers[i + 1]) < threshold:\n return True\n \n return False", "matching_cluster_idx": 2}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n # Sort the numbers to make it easier to find close pairs\n sorted_numbers = sorted(numbers)\n \n # Iterate through the sorted list and check if any two consecutive numbers\n # are closer than the threshold\n for i in range(len(sorted_numbers) - 1):\n if abs(sorted_numbers[i] - sorted_numbers[i + 1]) < threshold:\n return True\n \n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n sorted_numbers = sorted(numbers)\n \n for i in range(len(sorted_numbers) - 1):\n if sorted_numbers[i + 1] - sorted_numbers[i] < threshold:\n return True\n \n return False", "matching_cluster_idx": 2}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n # Sort the numbers first\n numbers.sort()\n\n # Compare adjacent elements\n for i in range(len(numbers) - 1):\n if abs(numbers[i] - numbers[i + 1]) < threshold:\n return True\n\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\"\n Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n \n Args:\n numbers (List[float]): A list of floating point numbers.\n threshold (float): The threshold distance to check against.\n\n Returns:\n bool: True if any two numbers are closer than the given threshold, False otherwise.\n\n Examples:\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n numbers.sort() # Sort the numbers to make it easier to find close elements\n for i in range(len(numbers) - 1):\n if numbers[i + 1] - numbers[i] < threshold:\n return True\n return False", "matching_cluster_idx": 3}]}, "HumanEval/4": {"dps": 75.33227848101266, "dps_norm": 85.83333333333333, "pass@1": 100.0, "profiled": [{"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if not numbers:\n return 0.0 # Return 0 if the list is empty to avoid division by zero\n\n # Calculate the mean of the numbers\n mean_value = sum(numbers) / len(numbers)\n\n # Calculate the mean absolute deviation\n mad = sum(abs(x - mean_value) for x in numbers) / len(numbers)\n\n return mad", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" \n For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n \n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if not numbers:\n return 0.0\n\n # Calculate the mean of the numbers\n mean = sum(numbers) / len(numbers)\n \n # Calculate the absolute deviations from the mean\n absolute_deviations = [abs(x - mean) for x in numbers]\n \n # Calculate the mean of these absolute deviations\n mad = sum(absolute_deviations) / len(numbers)\n \n return mad", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n \n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if not numbers:\n return 0.0\n \n mean_value = sum(numbers) / len(numbers)\n deviations = [abs(x - mean_value) for x in numbers]\n mad = sum(deviations) / len(numbers)\n return mad", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n \"\"\"\n if not numbers:\n return 0.0\n\n mean = sum(numbers) / len(numbers)\n deviations = [abs(x - mean) for x in numbers]\n mad = sum(deviations) / len(numbers)\n \n return mad", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if not numbers:\n return 0.0\n \n mean_value = sum(numbers) / len(numbers)\n deviations = [abs(x - mean_value) for x in numbers]\n mad = sum(deviations) / len(numbers)\n \n return mad", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if not numbers:\n return 0.0\n \n mean_value = sum(numbers) / len(numbers)\n deviations = [abs(x - mean_value) for x in numbers]\n mad = sum(deviations) / len(numbers)\n return mad", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if not numbers:\n return 0.0\n\n mean_value = sum(numbers) / len(numbers)\n deviations = [abs(x - mean_value) for x in numbers]\n mad = sum(deviations) / len(numbers)\n return mad", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n \n Args:\n numbers (List[float]): A list of numbers.\n\n Returns:\n float: The mean absolute deviation of the list of numbers.\n \n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if not numbers:\n raise ValueError(\"The list of numbers cannot be empty.\")\n \n mean = sum(numbers) / len(numbers)\n deviations = [abs(x - mean) for x in numbers]\n mad = sum(deviations) / len(numbers)\n \n return mad", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" \n For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n\n Args:\n numbers (List[float]): The list of numbers for which the MAD is to be calculated.\n\n Returns:\n float: The Mean Absolute Deviation of the list.\n \n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if not numbers:\n raise ValueError(\"The list of numbers cannot be empty.\")\n \n n = len(numbers)\n mean = sum(numbers) / n\n mad = sum(abs(x - mean) for x in numbers) / n\n \n return mad", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if not numbers:\n return 0.0\n \n mean_value = sum(numbers) / len(numbers)\n deviations = [abs(x - mean_value) for x in numbers]\n mad = sum(deviations) / len(deviations)\n \n return mad", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" \n For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if not numbers:\n return 0.0\n\n mean = sum(numbers) / len(numbers)\n deviations = [abs(x - mean) for x in numbers]\n mad = sum(deviations) / len(numbers)\n return mad", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n \"\"\"\n if not numbers:\n return 0.0\n\n mean_value = sum(numbers) / len(numbers)\n absolute_deviations = [abs(x - mean_value) for x in numbers]\n mad = sum(absolute_deviations) / len(numbers)\n return mad", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n \"\"\"\n if not numbers:\n return 0.0 # Return 0 if the list is empty\n \n mean = sum(numbers) / len(numbers)\n absolute_deviations = [abs(x - mean) for x in numbers]\n mad = sum(absolute_deviations) / len(numbers)\n return mad", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if not numbers: # Return 0 if the list is empty\n return 0.0\n\n # Calculate the mean of the numbers\n mean = sum(numbers) / len(numbers)\n\n # Calculate the mean absolute deviation\n mad = sum(abs(x - mean) for x in numbers) / len(numbers)\n\n return mad", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n \"\"\"\n if not numbers:\n return 0.0\n\n mean_value = sum(numbers) / len(numbers)\n absolute_differences = [abs(x - mean_value) for x in numbers]\n mad = sum(absolute_differences) / len(numbers)\n return mad", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n \n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if not numbers:\n return 0.0\n \n # Calculate the mean of the numbers\n mean_value = sum(numbers) / len(numbers)\n \n # Calculate the Mean Absolute Deviation\n mad = sum(abs(x - mean_value) for x in numbers) / len(numbers)\n \n return mad", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if not numbers:\n return 0.0\n \n mean = sum(numbers) / len(numbers)\n deviations = [abs(x - mean) for x in numbers]\n mad = sum(deviations) / len(numbers)\n return mad", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if not numbers:\n return 0.0\n\n mean_value = sum(numbers) / len(numbers)\n deviations = [abs(x - mean_value) for x in numbers]\n mad = sum(deviations) / len(numbers)\n return mad", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n \n Parameters:\n numbers (List[float]): A list of floating point numbers.\n \n Returns:\n float: The mean absolute deviation of the numbers.\n \n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if not numbers:\n return 0.0\n \n # Calculate the mean of the numbers\n mean_value = sum(numbers) / len(numbers)\n \n # Calculate the mean absolute deviation\n mad = sum(abs(x - mean_value) for x in numbers) / len(numbers)\n \n return mad", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n \"\"\"\n if not numbers:\n return 0.0\n \n mean = sum(numbers) / len(numbers)\n absolute_deviations = [abs(x - mean) for x in numbers]\n mad = sum(absolute_deviations) / len(numbers)\n \n return mad", "matching_cluster_idx": 4}]}, "HumanEval/16": {"dps": 45.73643410852713, "dps_norm": 88.88888888888889, "pass@1": 100.0, "profiled": [{"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) it consists of.\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lowercase to ensure case-insensitivity\n lower_string = string.lower()\n # Use a set to store distinct characters\n distinct_chars = set(lower_string)\n # Return the number of distinct characters\n return len(distinct_chars)", "matching_cluster_idx": 7}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of \"\"\"\n # Convert the string to lowercase to ignore case\n string = string.lower()\n # Use a set to store distinct characters\n distinct_chars = set(string)\n # Return the number of distinct characters\n return len(distinct_chars)", "matching_cluster_idx": 7}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of. \"\"\"\n # Convert the string to lower case to ensure case-insensitivity\n lower_string = string.lower()\n # Use a set to collect distinct characters\n distinct_chars = set(lower_string)\n # Return the number of distinct characters\n return len(distinct_chars)", "matching_cluster_idx": 7}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) it consists of. \"\"\"\n # Convert the string to lower case and create a set of characters to find distinct ones\n distinct_characters = set(string.lower())\n # Return the number of distinct characters\n return len(distinct_characters)", "matching_cluster_idx": 7}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lowercase to ensure case insensitivity\n lowercase_string = string.lower()\n # Use a set to store distinct characters\n distinct_characters = set(lowercase_string)\n # Return the size of the set, which represents the number of distinct characters\n return len(distinct_characters)", "matching_cluster_idx": 7}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lowercase to make the character count case-insensitive\n lowercase_string = string.lower()\n\n # Use a set to store distinct characters, as sets inherently avoid duplicates\n distinct_characters = set(lowercase_string)\n\n # Return the number of distinct characters in the set\n return len(distinct_characters)", "matching_cluster_idx": 7}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of \"\"\"\n # Convert the string to lowercase to ignore case\n lower_string = string.lower()\n # Use a set to track distinct characters\n distinct_chars = set(lower_string)\n # Return the number of distinct characters\n return len(distinct_chars)", "matching_cluster_idx": 7}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\"Given a string, find out how many distinct characters (regardless of case) does it consist of.\"\"\"\n # Convert the string to lower case to handle case insensitivity\n lowercase_string = string.lower()\n \n # Use a set to find distinct characters\n distinct_characters = set(lowercase_string)\n \n # Return the number of distinct characters\n return len(distinct_characters)", "matching_cluster_idx": 7}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of \"\"\"\n # Convert the string to lowercase to ignore case\n string = string.lower()\n # Use a set to store distinct characters\n distinct_characters = set(string)\n # The number of distinct characters is the size of the set\n return len(distinct_characters)", "matching_cluster_idx": 7}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lowercase to make the count case-insensitive\n lower_string = string.lower()\n # Use a set to store distinct characters\n distinct_characters = set(lower_string)\n # Return the size of the set\n return len(distinct_characters)", "matching_cluster_idx": 7}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lowercase to ensure case insensitivity\n lowercased_string = string.lower()\n # Use a set to store unique characters\n distinct_characters = set(lowercased_string)\n # Return the number of distinct characters\n return len(distinct_characters)", "matching_cluster_idx": 7}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lowercase to ensure case insensitivity\n lower_string = string.lower()\n \n # Use a set to find distinct characters\n distinct_characters = set(lower_string)\n \n # Return the number of distinct characters\n return len(distinct_characters)", "matching_cluster_idx": 7}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of \"\"\"\n # Convert the string to lower case to ensure case insensitivity\n lower_case_string = string.lower()\n # Use a set to store unique characters, since sets do not allow duplicates\n distinct_characters = set(lower_case_string)\n # Return the number of distinct characters\n return len(distinct_characters)", "matching_cluster_idx": 7}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lowercase to handle the case insensitivity\n lower_string = string.lower()\n # Use a set to find distinct characters\n distinct_characters = set(lower_string)\n # Return the number of distinct characters\n return len(distinct_characters)", "matching_cluster_idx": 7}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) it consists of \"\"\"\n # Convert the string to lowercase to ignore case\n lowercase_string = string.lower()\n \n # Use a set to store distinct characters\n distinct_characters = set(lowercase_string)\n \n # The number of distinct characters is the size of the set\n return len(distinct_characters)", "matching_cluster_idx": 7}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lowercase to ensure case insensitivity\n lowercase_string = string.lower()\n # Use a set to store distinct characters\n distinct_characters = set(lowercase_string)\n # Return the number of distinct characters\n return len(distinct_characters)", "matching_cluster_idx": 7}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\"Given a string, find out how many distinct characters (regardless of case) it consists of.\"\"\"\n # Convert the string to lowercase to ignore case, and create a set of characters to get distinct values\n distinct_characters = set(string.lower())\n # Return the length of the set, which is the count of distinct characters\n return len(distinct_characters)", "matching_cluster_idx": 7}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" \n Given a string, find out how many distinct characters (regardless of case) it consists of.\n \n Parameters:\n string (str): The input string to evaluate.\n\n Returns:\n int: The number of distinct characters in the string.\n\n Examples:\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lowercase to ignore case sensitivity and create a set of characters\n distinct_characters = set(string.lower())\n # Return the number of distinct characters\n return len(distinct_characters)", "matching_cluster_idx": 7}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) it consists of.\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lowercase to ignore case and find distinct characters\n lower_case_string = string.lower()\n # Use a set to automatically filter out duplicate characters\n distinct_characters = set(lower_case_string)\n # Return the number of distinct characters\n return len(distinct_characters)", "matching_cluster_idx": 7}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" \n Given a string, find out how many distinct characters (regardless of case) it consists of.\n \n Args:\n string (str): The input string to analyze.\n \n Returns:\n int: The count of distinct characters in the string.\n \n Examples:\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lowercase to handle case insensitivity\n lower_string = string.lower()\n # Use a set to automatically filter out duplicate characters\n distinct_chars = set(lower_string)\n # Return the number of distinct characters\n return len(distinct_chars)", "matching_cluster_idx": 7}]}, "HumanEval/20": {"dps": 92.61501210653753, "dps_norm": 98.88888888888889, "pass@1": 100.0, "profiled": [{"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n \n Examples:\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n # Sort the list first\n numbers_sorted = sorted(numbers)\n \n # Initialize variables to track the minimum difference and the closest pair\n min_diff = float('inf')\n closest_pair = (numbers_sorted[0], numbers_sorted[1])\n \n # Iterate through the sorted list to find the smallest difference\n for i in range(len(numbers_sorted) - 1):\n diff = numbers_sorted[i + 1] - numbers_sorted[i]\n if diff < min_diff:\n min_diff = diff\n closest_pair = (numbers_sorted[i], numbers_sorted[i + 1])\n \n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" \n From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n \"\"\"\n if len(numbers) < 2:\n raise ValueError(\"The list must contain at least two numbers.\")\n \n # Sort the numbers first\n numbers.sort()\n \n # Initialize the minimum difference to a large number\n min_diff = float('inf')\n closest_pair = (0.0, 0.0)\n\n # Iterate through the sorted list and find the closest pair\n for i in range(len(numbers) - 1):\n current_diff = numbers[i + 1] - numbers[i]\n if current_diff < min_diff:\n min_diff = current_diff\n closest_pair = (numbers[i], numbers[i + 1])\n\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n # Sort the numbers first\n sorted_numbers = sorted(numbers)\n \n # Initialize variables to keep track of the smallest difference and closest pair\n min_diff = float('inf')\n closest_pair = (0.0, 0.0)\n \n # Iterate through sorted list and find the smallest difference\n for i in range(len(sorted_numbers) - 1):\n diff = sorted_numbers[i + 1] - sorted_numbers[i]\n if diff < min_diff:\n min_diff = diff\n closest_pair = (sorted_numbers[i], sorted_numbers[i + 1])\n \n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n \n # Sort the list of numbers\n sorted_numbers = sorted(numbers)\n \n # Initialize the minimum distance as infinity\n min_distance = float('inf')\n \n # Initialize a tuple to hold the closest pair\n closest_pair = (sorted_numbers[0], sorted_numbers[1])\n \n # Iterate through the sorted list to find the closest pair\n for i in range(len(sorted_numbers) - 1):\n num1, num2 = sorted_numbers[i], sorted_numbers[i+1]\n distance = abs(num2 - num1)\n if distance < min_distance:\n min_distance = distance\n closest_pair = (num1, num2)\n \n return closest_pair", "matching_cluster_idx": 7}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n # First, sort the numbers\n sorted_numbers = sorted(numbers)\n\n # Initialize variables to store the minimum difference found and the pair of numbers\n min_diff = float('inf')\n closest_pair = (sorted_numbers[0], sorted_numbers[1])\n \n # Iterate through the sorted numbers to find the smallest difference between consecutive numbers\n for i in range(len(sorted_numbers) - 1):\n diff = sorted_numbers[i + 1] - sorted_numbers[i]\n if diff < min_diff:\n min_diff = diff\n closest_pair = (sorted_numbers[i], sorted_numbers[i + 1])\n \n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n \"\"\"\n # Sort the numbers first\n numbers.sort()\n \n # Initialize variables to store the closest pair and the minimum distance\n min_distance = float('inf')\n closest_pair = (numbers[0], numbers[1])\n \n # Iterate through the sorted list to find the closest pair\n for i in range(len(numbers) - 1):\n distance = numbers[i+1] - numbers[i]\n if distance < min_distance:\n min_distance = distance\n closest_pair = (numbers[i], numbers[i+1])\n \n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n \"\"\"\n # Sort the list to easily find closest pairs\n sorted_numbers = sorted(numbers)\n \n # Initialize the minimum difference to a large number\n min_diff = float('inf')\n closest_pair = (sorted_numbers[0], sorted_numbers[1])\n \n # Iterate over the sorted list and find the smallest difference between adjacent pairs\n for i in range(1, len(sorted_numbers)):\n current_diff = sorted_numbers[i] - sorted_numbers[i - 1]\n \n if current_diff < min_diff:\n min_diff = current_diff\n closest_pair = (sorted_numbers[i - 1], sorted_numbers[i])\n \n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n if len(numbers) < 2:\n raise ValueError(\"The list must contain at least two numbers.\")\n \n # Sort the numbers\n sorted_numbers = sorted(numbers)\n \n # Initialize variables to track the minimum difference and the closest pair\n min_diff = float('inf')\n closest_pair = (0.0, 0.0)\n \n # Iterate over the sorted list to find the closest pair\n for i in range(len(sorted_numbers) - 1):\n diff = sorted_numbers[i + 1] - sorted_numbers[i]\n if diff < min_diff:\n min_diff = diff\n closest_pair = (sorted_numbers[i], sorted_numbers[i + 1])\n \n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\"\n From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n \"\"\"\n # Sort the numbers to make finding the closest pair easier\n sorted_numbers = sorted(numbers)\n \n # Initialize variables to store the closest pair found\n min_diff = float('inf')\n closest_pair = (sorted_numbers[0], sorted_numbers[1])\n\n # Iterate over the sorted list to find the smallest difference\n for i in range(len(sorted_numbers) - 1):\n diff = sorted_numbers[i + 1] - sorted_numbers[i]\n if diff < min_diff:\n min_diff = diff\n closest_pair = (sorted_numbers[i], sorted_numbers[i + 1])\n \n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n \n Args:\n numbers: A list of floating-point numbers (length >= 2).\n \n Returns:\n A tuple containing the two closest numbers in order (smaller number, larger number).\n \n Examples:\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n \n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n # Sort the numbers to make comparison between consecutive elements easier\n sorted_numbers = sorted(numbers)\n \n # Initialize variables to store the minimum difference and the closest pair\n min_diff = float('inf')\n closest_pair = (0.0, 0.0)\n \n # Iterate through the sorted numbers and compare consecutive elements\n for i in range(len(sorted_numbers) - 1):\n diff = abs(sorted_numbers[i + 1] - sorted_numbers[i])\n if diff < min_diff:\n min_diff = diff\n closest_pair = (sorted_numbers[i], sorted_numbers[i + 1])\n \n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\"From a supplied list of numbers (of length at least two), select and return two that are the closest\n to each other and return them in order (smaller number, larger number).\n \n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n \n # Sort the list first\n sorted_numbers = sorted(numbers)\n \n # Initialize variables to track the closest pair and minimum difference\n min_diff = float('inf')\n closest_pair = (sorted_numbers[0], sorted_numbers[1])\n \n # Iterate through the sorted list and find the minimum difference\n for i in range(len(sorted_numbers) - 1):\n diff = sorted_numbers[i + 1] - sorted_numbers[i]\n if diff < min_diff:\n min_diff = diff\n closest_pair = (sorted_numbers[i], sorted_numbers[i + 1])\n \n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n \n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n if len(numbers) < 2:\n raise ValueError(\"The list must contain at least two elements.\")\n\n # Sort the numbers to make it easier to find the closest pair\n sorted_numbers = sorted(numbers)\n min_diff = float('inf')\n closest_pair = (0.0, 0.0)\n\n # Iterate over the sorted list to find the smallest difference\n for i in range(len(sorted_numbers) - 1):\n diff = abs(sorted_numbers[i+1] - sorted_numbers[i])\n if diff < min_diff:\n min_diff = diff\n closest_pair = (sorted_numbers[i], sorted_numbers[i+1])\n\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two), select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n \"\"\"\n # Sort the numbers first\n sorted_numbers = sorted(numbers)\n \n # Initialize the variables to store the closest pair and the smallest difference\n closest_pair = (sorted_numbers[0], sorted_numbers[1])\n min_difference = abs(sorted_numbers[1] - sorted_numbers[0])\n\n # Iterate through the sorted list to find the closest pair\n for i in range(1, len(sorted_numbers) - 1):\n diff = abs(sorted_numbers[i + 1] - sorted_numbers[i])\n if diff < min_difference:\n min_difference = diff\n closest_pair = (sorted_numbers[i], sorted_numbers[i + 1])\n \n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two), select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n \n Args:\n numbers: A list of floating-point numbers.\n \n Returns:\n A tuple containing the two closest numbers, with the smaller number first.\n \n Examples:\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n if len(numbers) < 2:\n raise ValueError(\"The list must contain at least two elements.\")\n\n # Sort the numbers to ensure they are in order\n sorted_numbers = sorted(numbers)\n \n # Initialize the variables to track the minimum difference\n min_diff = float('inf')\n closest_pair = (sorted_numbers[0], sorted_numbers[1])\n \n # Iterate over the sorted list to find the closest pair\n for i in range(len(sorted_numbers) - 1):\n current_diff = sorted_numbers[i + 1] - sorted_numbers[i]\n if current_diff < min_diff:\n min_diff = current_diff\n closest_pair = (sorted_numbers[i], sorted_numbers[i + 1])\n \n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n \n # Sort the list to find adjacent closest elements easily\n sorted_numbers = sorted(numbers)\n \n # Initialize variables to track the closest pair and the minimum difference\n min_diff = float('inf')\n closest_pair = (sorted_numbers[0], sorted_numbers[1])\n \n # Iterate through sorted list to find the smallest difference between adjacent elements\n for i in range(len(sorted_numbers) - 1):\n diff = sorted_numbers[i+1] - sorted_numbers[i]\n if diff < min_diff:\n min_diff = diff\n closest_pair = (sorted_numbers[i], sorted_numbers[i+1])\n \n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\"\n From a supplied list of numbers (of length at least two), select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n \n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n # Sort the list to simplify finding the closest pair\n sorted_numbers = sorted(numbers)\n min_diff = float('inf')\n closest_pair = (0.0, 0.0)\n \n # Iterate through the sorted list and find the smallest difference\n for i in range(len(sorted_numbers) - 1):\n current_diff = sorted_numbers[i + 1] - sorted_numbers[i]\n if current_diff < min_diff:\n min_diff = current_diff\n closest_pair = (sorted_numbers[i], sorted_numbers[i + 1])\n \n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" \n From a supplied list of numbers (of length at least two), \n select and return two that are the closest to each other\n and return them in order (smaller number, larger number).\n \"\"\"\n # Sort the list to make it easier to find the closest numbers\n numbers.sort()\n \n # Initialize minimum difference to a large number\n min_diff = float('inf')\n closest_pair = (0, 0)\n \n # Iterate through the sorted list to find the closest pair\n for i in range(len(numbers) - 1):\n # Calculate the difference between consecutive numbers\n diff = numbers[i + 1] - numbers[i]\n \n # If this difference is smaller than the current minimum difference\n if diff < min_diff:\n min_diff = diff\n closest_pair = (numbers[i], numbers[i + 1])\n \n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n if len(numbers) < 2:\n raise ValueError(\"The list must contain at least two numbers.\")\n \n # Sort the numbers first\n sorted_numbers = sorted(numbers)\n \n # Initialize the closest pair\n closest_pair = (sorted_numbers[0], sorted_numbers[1])\n min_diff = abs(sorted_numbers[1] - sorted_numbers[0])\n \n # Iterate over the sorted list and find the closest pair\n for i in range(1, len(sorted_numbers) - 1):\n num1 = sorted_numbers[i]\n num2 = sorted_numbers[i + 1]\n diff = abs(num2 - num1)\n \n if diff < min_diff:\n min_diff = diff\n closest_pair = (num1, num2)\n \n return closest_pair", "matching_cluster_idx": 7}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n \"\"\"\n # Sort the numbers to make it easier to find the closest pair\n numbers.sort()\n \n # Initialize the minimum difference to a large number\n min_diff = float('inf')\n \n # This will hold the closest pair\n closest_pair = (numbers[0], numbers[1])\n \n # Iterate through the sorted numbers to find the closest pair\n for i in range(len(numbers) - 1):\n # Calculate the difference between consecutive numbers\n diff = numbers[i+1] - numbers[i]\n \n # If this difference is less than the minimum found so far, update the closest pair\n if diff < min_diff:\n min_diff = diff\n closest_pair = (numbers[i], numbers[i+1])\n \n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n \n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n # Sort the list to make it easier to find the closest elements\n numbers.sort()\n \n # Initialize variables to store the smallest difference and the closest pair\n min_diff = float('inf')\n closest_pair = (numbers[0], numbers[1])\n \n # Iterate through the sorted list to find the smallest difference\n for i in range(len(numbers) - 1):\n diff = numbers[i + 1] - numbers[i]\n if diff < min_diff:\n min_diff = diff\n closest_pair = (numbers[i], numbers[i + 1])\n \n return closest_pair", "matching_cluster_idx": 8}]}, "HumanEval/24": {"dps": 60.17006802721089, "dps_norm": 35.0, "pass@1": 100.0, "profiled": [{"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n >>> largest_divisor(100)\n 50\n >>> largest_divisor(37) # Since 37 is a prime number, it should return 1\n 1\n \"\"\"\n if n <= 1:\n raise ValueError(\"Input must be greater than 1\")\n\n for i in range(n // 2, 0, -1):\n if n % i == 0:\n return i\n return 1 # In case n is a prime number, the largest divisor is 1", "matching_cluster_idx": 3}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n >>> largest_divisor(18)\n 9\n >>> largest_divisor(100)\n 50\n >>> largest_divisor(7)\n 1\n >>> largest_divisor(25)\n 5\n \"\"\"\n # Start from n-1 and go downwards to find the largest divisor\n for i in range(n-1, 0, -1):\n if n % i == 0:\n return i\n return 1 # This line is theoretically never reached for n > 1, since 1 is a divisor of any number n.", "matching_cluster_idx": 0}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" \n For a given number n, find the largest number that divides n evenly, smaller than n.\n \"\"\"\n # Start checking from n-1 and go downwards\n for i in range(n-1, 0, -1):\n if n % i == 0:\n return i\n return 1", "matching_cluster_idx": 1}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n \"\"\"\n if n <= 1:\n raise ValueError(\"n must be greater than 1\")\n for i in range(n // 2, 0, -1):\n if n % i == 0:\n return i\n return 1 # By definition, 1 divides any n but should never be reached because n > 1", "matching_cluster_idx": 3}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" \n For a given number n, find the largest number that divides n evenly, smaller than n.\n \n Parameters:\n n (int): The number to find the largest divisor for.\n\n Returns:\n int: The largest divisor of n that is smaller than n.\n\n >>> largest_divisor(15)\n 5\n \"\"\"\n # We start from n-1 and go downwards\n for i in range(n - 1, 0, -1):\n if n % i == 0:\n return i\n return 1 # If no divisor is found, return 1 (every number is divisible by 1)", "matching_cluster_idx": 0}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" \n For a given number n, find the largest number that divides n evenly, smaller than n\n \n >>> largest_divisor(15)\n 5\n >>> largest_divisor(100)\n 50\n >>> largest_divisor(13)\n 1\n >>> largest_divisor(49)\n 7\n >>> largest_divisor(20)\n 10\n \"\"\"\n if n <= 1:\n raise ValueError(\"n should be greater than 1\")\n\n for i in range(n // 2, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 4}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n for i in range(n // 2, 0, -1):\n if n % i == 0:\n return i\n return 1", "matching_cluster_idx": 3}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\"For a given number n, find the largest number that divides n evenly, smaller than n.\"\"\"\n if n <= 1:\n raise ValueError(\"n must be greater than 1\")\n \n # Start from n-1 and find the largest number that divides n\n for i in range(n-1, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 0}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n \"\"\"\n for i in range(n-1, 0, -1):\n if n % i == 0:\n return i\n return 1 # In case n is 1, which has no divisors smaller than itself", "matching_cluster_idx": 0}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n \"\"\"\n for i in range(n // 2, 0, -1):\n if n % i == 0:\n return i\n return 1 # This line is technically unreachable for n > 1, but it's safe to have.", "matching_cluster_idx": 4}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\"For a given number n, find the largest number that divides n evenly, smaller than n.\n \n >>> largest_divisor(15)\n 5\n >>> largest_divisor(28)\n 14\n >>> largest_divisor(100)\n 50\n >>> largest_divisor(49)\n 7\n >>> largest_divisor(2)\n 1\n \"\"\"\n # Start checking from n-1 down to 1\n for i in range(n-1, 0, -1):\n if n % i == 0:\n return i\n return 1 # In case something unexpected happens (though for positive n, it should not)", "matching_cluster_idx": 1}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n \"\"\"\n for i in range(n // 2, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 4}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" \n For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n >>> largest_divisor(16)\n 8\n >>> largest_divisor(7)\n 1\n >>> largest_divisor(100)\n 50\n >>> largest_divisor(2)\n 1\n \"\"\"\n # Start from the largest possible divisor, which is n-1\n for i in range(n-1, 0, -1):\n if n % i == 0:\n return i\n return 1 # If n is 1, return 1 because it's the only divisor less than itself", "matching_cluster_idx": 1}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n. \"\"\"\n if n <= 1:\n raise ValueError(\"n must be greater than 1\")\n \n # Start from n-1 and go downwards to find the largest divisor\n for i in range(n - 1, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 0}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n for divisor in range(n // 2, 0, -1):\n if n % divisor == 0:\n return divisor\n return 1 # If n is 1, the largest divisor smaller than 1 doesn't exist, return 1 as a default.", "matching_cluster_idx": 4}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n.\n \n Args:\n n (int): The number for which to find the largest divisor.\n\n Returns:\n int: The largest divisor of n that is smaller than n.\n \n Examples:\n >>> largest_divisor(15)\n 5\n >>> largest_divisor(100)\n 50\n >>> largest_divisor(81)\n 27\n \"\"\"\n if n <= 1:\n raise ValueError(\"n should be greater than 1\")\n \n # Start checking from n//2 downwards\n for i in range(n // 2, 0, -1):\n if n % i == 0:\n return i\n return 1 # For completeness, though the loop should return before this.", "matching_cluster_idx": 4}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n # We need to find the largest number less than n that divides n evenly\n if n <= 1:\n raise ValueError(\"n must be greater than 1\")\n \n # Start checking from n-1 down to 1\n for i in range(n - 1, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 0}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n.\n >>> largest_divisor(15)\n 5\n \"\"\"\n for i in range(n // 2, 0, -1):\n if n % i == 0:\n return i\n return 1 # Return 1 if no divisor is found (this case happens only for n = 1)", "matching_cluster_idx": 4}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n \"\"\"\n if n <= 1:\n raise ValueError(\"n must be greater than 1\")\n \n for i in range(n - 1, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 0}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n.\n >>> largest_divisor(15)\n 5\n \"\"\"\n if n <= 1:\n raise ValueError(\"n should be greater than 1\")\n \n # Start checking from n-1 down to 1\n for divisor in range(n - 1, 0, -1):\n if n % divisor == 0:\n return divisor\n\n # This line should theoretically never be reached because every number\n # has 1 as a divisor (if we reach here, it means n was 1 which is not allowed)\n return 1", "matching_cluster_idx": 0}]}, "HumanEval/26": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n # Use a dictionary to count the occurrences of each number\n count_dict = {}\n for number in numbers:\n if number in count_dict:\n count_dict[number] += 1\n else:\n count_dict[number] = 1\n\n # Return a list with elements that occur only once\n return [number for number in numbers if count_dict[number] == 1]", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n # Dictionary to keep track of occurrences\n count = {}\n \n # Count occurrences of each number\n for number in numbers:\n if number in count:\n count[number] += 1\n else:\n count[number] = 1\n \n # Filter numbers that appear more than once\n result = [number for number in numbers if count[number] == 1]\n \n return result", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n # Create a dictionary to count occurrences of each number\n occurrence_count = {}\n \n # First, count each number's occurrence in the list\n for number in numbers:\n if number in occurrence_count:\n occurrence_count[number] += 1\n else:\n occurrence_count[number] = 1\n \n # Construct a list with numbers that appear only once, maintaining the original order\n unique_numbers = [number for number in numbers if occurrence_count[number] == 1]\n \n return unique_numbers", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n # Count the occurrences of each number\n count_map = {}\n for number in numbers:\n if number in count_map:\n count_map[number] += 1\n else:\n count_map[number] = 1\n \n # Filter out numbers that occur more than once\n result = []\n for number in numbers:\n if count_map[number] == 1:\n result.append(number)\n \n return result", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n # Use a dictionary to count occurrences of each number\n count = {}\n for num in numbers:\n count[num] = count.get(num, 0) + 1\n \n # Filter the numbers, keeping only those that appear exactly once\n return [num for num in numbers if count[num] == 1]", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" \n From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n \n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n from collections import Counter\n\n # Count the occurrences of each number in the list\n count = Counter(numbers)\n \n # Return a list of elements that appear only once\n result = [num for num in numbers if count[num] == 1]\n \n return result", "matching_cluster_idx": 3}, {"solution": "from typing import List\nfrom collections import Counter\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n # Count the occurrences of each number in the list\n counts = Counter(numbers)\n \n # Create a list of elements that occur exactly once, preserving order\n result = [num for num in numbers if counts[num] == 1]\n \n return result", "matching_cluster_idx": 3}, {"solution": "from typing import List\nfrom collections import Counter\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n \n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n # Count the occurrences of each number in the list\n counts = Counter(numbers)\n \n # Return a list of numbers that occur only once, maintaining the original order\n return [num for num in numbers if counts[num] == 1]", "matching_cluster_idx": 3}, {"solution": "from typing import List\nfrom collections import Counter\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n \n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n # Count the occurrences of each number\n count = Counter(numbers)\n \n # Collect numbers that appear only once, preserving their order\n result = [num for num in numbers if count[num] == 1]\n \n return result", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n # Use a dictionary to count occurrences of each number\n count = {}\n for number in numbers:\n if number in count:\n count[number] += 1\n else:\n count[number] = 1\n\n # Create a new list for numbers that occur only once\n result = [number for number in numbers if count[number] == 1]\n \n return result", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n # A dictionary to count occurrences of each number\n count = {}\n \n # Count each number's occurrence\n for number in numbers:\n if number in count:\n count[number] += 1\n else:\n count[number] = 1\n \n # Collect numbers that appear only once\n result = [number for number in numbers if count[number] == 1]\n \n return result", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n \n Args:\n numbers (List[int]): A list of integers\n \n Returns:\n List[int]: A list of integers with duplicates removed\n \n Example:\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n # Create a dictionary to count occurrences of each number\n count = {}\n for number in numbers:\n if number in count:\n count[number] += 1\n else:\n count[number] = 1\n\n # Create a new list without duplicates, maintaining the order\n result = []\n for number in numbers:\n if count[number] == 1:\n result.append(number)\n \n return result", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n # Count the occurrences of each number in the list\n occurrence_count = {}\n for number in numbers:\n if number in occurrence_count:\n occurrence_count[number] += 1\n else:\n occurrence_count[number] = 1\n\n # Create a list of numbers that appear only once\n result = [number for number in numbers if occurrence_count[number] == 1]\n\n return result", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n # Create a dictionary to count occurrences of each number\n count_dict = {}\n \n # First pass to populate count_dict with the frequency of each number\n for number in numbers:\n if number in count_dict:\n count_dict[number] += 1\n else:\n count_dict[number] = 1\n \n # Second pass to collect numbers that appear only once\n result = []\n for number in numbers:\n if count_dict[number] == 1:\n result.append(number)\n \n return result", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n # Create a dictionary to count occurrences of each number\n count_dict = {}\n for number in numbers:\n count_dict[number] = count_dict.get(number, 0) + 1\n \n # Collect numbers that occur only once\n result = [number for number in numbers if count_dict[number] == 1]\n \n return result", "matching_cluster_idx": 3}, {"solution": "from typing import List\nfrom collections import Counter\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n \"\"\"\n # Count the occurrences of each number\n counts = Counter(numbers)\n \n # Return only those numbers which occur exactly once, maintaining the original order\n return [num for num in numbers if counts[num] == 1]", "matching_cluster_idx": 3}, {"solution": "from typing import List\nfrom collections import Counter\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n # Count occurrences of each number\n counts = Counter(numbers)\n \n # Keep only numbers that appear exactly once\n result = [num for num in numbers if counts[num] == 1]\n \n return result", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n # Create a dictionary to count occurrences of each number\n occurrences = {}\n \n # Populate the dictionary with counts\n for number in numbers:\n if number in occurrences:\n occurrences[number] += 1\n else:\n occurrences[number] = 1\n \n # Generate a list of numbers that occur only once, maintaining order\n result = [number for number in numbers if occurrences[number] == 1]\n \n return result", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n # Use a dictionary to count occurrences of each element\n count = {}\n for num in numbers:\n if num in count:\n count[num] += 1\n else:\n count[num] = 1\n \n # Create a list for elements that occur exactly once\n result = []\n for num in numbers:\n if count[num] == 1:\n result.append(num)\n \n return result", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n from collections import Counter\n \n # Count occurrences of each number\n counts = Counter(numbers)\n \n # Return a list of numbers that appear exactly once, maintaining order\n return [num for num in numbers if counts[num] == 1]", "matching_cluster_idx": 3}]}, "HumanEval/31": {"dps": 97.46835443037975, "dps_norm": 87.5, "pass@1": 100.0, "profiled": [{"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n \n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n \n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n \n Args:\n n (int): The number to check for primality.\n \n Returns:\n bool: True if the number is prime, False otherwise.\n \n Examples:\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True # 2 and 3 are prime numbers\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n \n A prime number is a natural number greater than 1 that is not a product of two smaller natural numbers.\n\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}]}, "HumanEval/33": {"dps": 97.22222222222223, "dps_norm": 81.81818181818181, "pass@1": 100.0, "profiled": [{"solution": "def sort_third(l: list) -> list:\n \"\"\"\n This function takes a list l and returns a list l' such that\n l' is identical to l in the indices that are not divisible by three, while its values at the indices that are divisible by three are equal\n to the values of the corresponding indices of l, but sorted.\n \n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n # Extract elements at indices that are divisible by 3\n third_elements = [l[i] for i in range(len(l)) if i % 3 == 0]\n \n # Sort the extracted elements\n third_elements_sorted = sorted(third_elements)\n \n # Place the sorted elements back into their respective positions\n result = l[:]\n j = 0\n for i in range(len(l)):\n if i % 3 == 0:\n result[i] = third_elements_sorted[j]\n j += 1\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indices that are not divisible by three,\n while its values at the indices that are divisible by three are equal\n to the values of the corresponding indices of l, but sorted.\n \n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n # Extract the elements at indices divisible by three\n third_elements = [l[i] for i in range(0, len(l), 3)]\n \n # Sort these elements\n sorted_third_elements = sorted(third_elements)\n \n # Create a copy of the list to manipulate and return\n result = l[:]\n \n # Replace the elements at indices divisible by three with sorted elements\n for index, value in zip(range(0, len(l), 3), sorted_third_elements):\n result[index] = value\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list) -> list:\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indices that are not divisible by three, while its values at the indices that are divisible by three are equal\n to the values of the corresponding indices of l, but sorted.\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n # Extract elements at indices divisible by 3\n indices_div_by_three = [i for i in range(len(l)) if i % 3 == 0]\n elements_to_sort = [l[i] for i in indices_div_by_three]\n\n # Sort these elements\n elements_to_sort.sort()\n\n # Create a new list for the result\n result = l[:]\n\n # Place sorted elements back into the result list\n for idx, sorted_elem in zip(indices_div_by_three, elements_to_sort):\n result[idx] = sorted_elem\n\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indices that are not divisible by three,\n while its values at the indices that are divisible by three are equal\n to the values of the corresponding indices of l, but sorted.\n \n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n \n # Extract elements at indices divisible by 3\n elements_to_sort = [l[i] for i in range(0, len(l), 3)]\n \n # Sort those elements\n elements_to_sort.sort()\n \n # Create a new list to hold the sorted result\n sorted_list = l[:] # Start with a copy of the original list\n \n # Replace the elements at indices divisible by 3 with the sorted elements\n for idx, val in zip(range(0, len(l), 3), elements_to_sort):\n sorted_list[idx] = val\n \n return sorted_list", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list) -> list:\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indices that are not divisible by three, while its values at the indices that are divisible by three are equal\n to the values of the corresponding indices of l, but sorted.\n \n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n \n # Find all elements at indices that are divisible by three\n elements_at_third_indices = [l[i] for i in range(0, len(l), 3)]\n \n # Sort these elements\n sorted_elements = sorted(elements_at_third_indices)\n \n # Create a copy of the original list to construct the new list\n result = l[:]\n \n # Replace the elements at indices divisible by three with sorted elements\n for index, sorted_value in zip(range(0, len(result), 3), sorted_elements):\n result[index] = sorted_value\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indices that are not divisible by three, while its values at the indices that are divisible by three are equal\n to the values of the corresponding indices of l, but sorted.\n \n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n # Extract the elements at indices divisible by three\n indices_div_by_three = [i for i in range(len(l)) if i % 3 == 0]\n elements_to_sort = [l[i] for i in indices_div_by_three]\n\n # Sort the extracted elements\n elements_to_sort.sort()\n\n # Create a new list with sorted elements at those positions\n result = l[:] # Copy the original list\n for idx, sorted_value in zip(indices_div_by_three, elements_to_sort):\n result[idx] = sorted_value\n\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list) -> list:\n \"\"\"\n This function takes a list l and returns a list l' such that\n l' is identical to l in the indices that are not divisible by three, while its values at the indices that are divisible by three are equal\n to the values of the corresponding indices of l, but sorted.\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n\n # Extract elements at indices divisible by 3\n elements_at_third_indices = [l[i] for i in range(len(l)) if i % 3 == 0]\n\n # Sort the extracted elements\n sorted_elements = sorted(elements_at_third_indices)\n\n # Create a new list for the result\n sorted_list = l[:]\n\n # Place the sorted elements back at their original indices\n sorted_index = 0\n for i in range(len(sorted_list)):\n if i % 3 == 0:\n sorted_list[i] = sorted_elements[sorted_index]\n sorted_index += 1\n\n return sorted_list", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indices that are not divisible by three, while its values at the indices that are divisible by three are equal\n to the values of the corresponding indices of l, but sorted.\n \"\"\"\n # Extract the elements at indices divisible by three\n elements_to_sort = [l[i] for i in range(len(l)) if i % 3 == 0]\n \n # Sort the extracted elements\n elements_to_sort.sort()\n \n # Create a new list to store the result\n sorted_list = l[:]\n \n # Place the sorted elements back at the original indices\n sort_index = 0\n for i in range(len(sorted_list)):\n if i % 3 == 0:\n sorted_list[i] = elements_to_sort[sort_index]\n sort_index += 1\n \n return sorted_list", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indices that are not divisible by three, while its values at the indices that are divisible by three are equal\n to the values of the corresponding indices of l, but sorted.\n \n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n # Extract elements at indices divisible by 3\n third_elements = [l[i] for i in range(0, len(l), 3)]\n \n # Sort these elements\n sorted_third_elements = sorted(third_elements)\n \n # Reconstruct the list with sorted elements at indices divisible by 3\n result = l.copy()\n for idx, val in enumerate(sorted_third_elements):\n result[idx * 3] = val\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indices that are not divisible by three, while its values at the indices that are divisible by three are equal\n to the values of the corresponding indices of l, but sorted.\n\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n \n # Extract elements at indices divisible by three\n divisible_by_three = [l[i] for i in range(len(l)) if i % 3 == 0]\n\n # Sort these elements\n divisible_by_three.sort()\n\n # Create a new list, inserting sorted elements back at positions divisible by three\n result = l[:]\n index = 0\n for i in range(len(result)):\n if i % 3 == 0:\n result[i] = divisible_by_three[index]\n index += 1\n\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list) -> list:\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indices that are not divisible by three, while its values at the indices that are divisible by three are equal\n to the values of the corresponding indices of l, but sorted.\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n # Extract elements at indices divisible by 3\n third_elements = [l[i] for i in range(0, len(l), 3)]\n \n # Sort those elements\n third_elements.sort()\n \n # Replace sorted elements back into their respective positions\n result = l[:]\n for i, elem in enumerate(third_elements):\n result[i * 3] = elem\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indices that are not divisible by three, while its values at the indices that are divisible by three are equal\n to the values of the corresponding indices of l, but sorted.\n\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n # Extract the elements at indices divisible by 3\n indices_div_by_three = [i for i in range(len(l)) if i % 3 == 0]\n elements_to_sort = [l[i] for i in indices_div_by_three]\n \n # Sort those elements\n elements_to_sort.sort()\n \n # Create a new list with sorted elements at indices divisible by 3\n sorted_list = l[:]\n for idx, sorted_element in zip(indices_div_by_three, elements_to_sort):\n sorted_list[idx] = sorted_element\n \n return sorted_list", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indices that are not divisible by three,\n while its values at the indices that are divisible by three are equal\n to the values of the corresponding indices of l, but sorted.\n \n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n # Extract elements at indices divisible by 3\n divisible_by_three = [l[i] for i in range(0, len(l), 3)]\n \n # Sort these elements\n divisible_by_three.sort()\n \n # Copy the original list to preserve elements not divisible by 3\n result = l[:]\n \n # Replace elements in the original list at indices divisible by 3 with sorted ones\n for i, value in enumerate(divisible_by_three):\n result[i * 3] = value\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indices that are not divisible by three, while its values at the indices that are divisible by three are equal\n to the values of the corresponding indices of l, but sorted.\n \n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n # Extract the elements that are at indices divisible by 3\n divisible_by_three = [l[i] for i in range(len(l)) if i % 3 == 0]\n \n # Sort these elements\n divisible_by_three_sorted = sorted(divisible_by_three)\n \n # Create a new list where elements at indices divisible by 3 are replaced by sorted elements\n sorted_list = l[:] # Make a shallow copy of the list\n j = 0 # Index for the sorted elements\n for i in range(len(l)):\n if i % 3 == 0:\n sorted_list[i] = divisible_by_three_sorted[j]\n j += 1\n \n return sorted_list", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indices that are not divisible by three, while its values at the indices that are divisible by three are equal\n to the values of the corresponding indices of l, but sorted.\n \n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n # Extract elements at indices divisible by 3\n third_indices = [l[i] for i in range(0, len(l), 3)]\n \n # Sort the extracted elements\n sorted_third_indices = sorted(third_indices)\n \n # Create a new list with the same elements as l\n result = l[:]\n \n # Replace elements at indices divisible by 3 with the sorted ones\n for index, sorted_value in zip(range(0, len(l), 3), sorted_third_indices):\n result[index] = sorted_value\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indices that are not divisible by three, while its values at the indices that are divisible by three are equal\n to the values of the corresponding indices of l, but sorted.\n \n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n \n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n # Extract elements at indices divisible by 3\n divisible_by_three = [l[i] for i in range(0, len(l), 3)]\n \n # Sort those extracted elements\n divisible_by_three_sorted = sorted(divisible_by_three)\n \n # Create a new list to store the result\n result = l.copy()\n \n # Insert the sorted elements back into the positions divisible by 3\n for idx, sorted_value in enumerate(divisible_by_three_sorted):\n result[idx * 3] = sorted_value\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indices that are not divisible by three, while its values at the indices that are divisible by three are equal\n to the values of the corresponding indices of l, but sorted.\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n # Extract elements at indices divisible by 3\n third_indices = [i for i in range(len(l)) if i % 3 == 0]\n third_values = [l[i] for i in third_indices]\n \n # Sort the extracted values\n sorted_third_values = sorted(third_values)\n \n # Create a copy of the original list\n result = l[:]\n \n # Place the sorted values back into their respective positions\n for i, index in enumerate(third_indices):\n result[index] = sorted_third_values[i]\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list) -> list:\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indices that are not divisible by three, while its values at the indices that are divisible by three are equal\n to the values of the corresponding indices of l, but sorted.\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n\n # Extract elements at indices divisible by 3\n third_elements = [l[i] for i in range(len(l)) if i % 3 == 0]\n \n # Sort those elements\n third_elements_sorted = sorted(third_elements)\n \n # Create a new list where elements at indices divisible by 3 are replaced by sorted elements\n result = l[:] # Make a copy of the original list\n third_index = 0\n \n for i in range(len(l)):\n if i % 3 == 0:\n result[i] = third_elements_sorted[third_index]\n third_index += 1\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indices that are not divisible by three, while its values at the indices that are divisible by three are equal\n to the values of the corresponding indices of l, but sorted.\n\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n # Extract elements at indices divisible by 3\n indices_divisible_by_three = [i for i in range(len(l)) if i % 3 == 0]\n divisible_by_three_values = [l[i] for i in indices_divisible_by_three]\n \n # Sort these values\n sorted_values = sorted(divisible_by_three_values)\n \n # Place the sorted values back into their original positions\n l_prime = l[:] # Make a copy of the original list\n for index, value in zip(indices_divisible_by_three, sorted_values):\n l_prime[index] = value\n \n return l_prime", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indices that are not divisible by three, while its values at the indices that are divisible by three are equal\n to the values of the corresponding indices of l, but sorted.\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n # Extract elements at indices divisible by 3\n divisible_by_three = [l[i] for i in range(len(l)) if i % 3 == 0]\n\n # Sort the extracted elements\n divisible_by_three.sort()\n\n # Create a new list to store the result\n result = l[:]\n \n # Replace elements at indices divisible by 3 with sorted elements\n j = 0\n for i in range(len(result)):\n if i % 3 == 0:\n result[i] = divisible_by_three[j]\n j += 1\n\n return result", "matching_cluster_idx": 8}]}, "HumanEval/34": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n # Use a set to filter out unique elements\n unique_elements = set(l)\n # Convert the set back to a list and sort it\n sorted_unique_elements = sorted(unique_elements)\n return sorted_unique_elements", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n # Use set to find unique elements\n unique_elements = set(l)\n # Convert the set back to a list and sort it\n sorted_unique_elements = sorted(unique_elements)\n return sorted_unique_elements", "matching_cluster_idx": 4}, {"solution": "def unique(l: list) -> list:\n \"\"\"Return sorted unique elements in a list\n \n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n # Use set to get unique elements, then sort the result\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list) -> list:\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n # Convert the list to a set to remove duplicates, then convert back to list and sort\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list) -> list:\n \"\"\"Return sorted unique elements in a list.\n \n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n # Convert the list to a set to get unique elements, then sort the result\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list) -> list:\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n # Convert the list to a set to remove duplicates\n unique_elements = set(l)\n # Convert back to a list and sort\n sorted_unique_elements = sorted(unique_elements)\n return sorted_unique_elements", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list.\n \n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n # Convert the list to a set to remove duplicates, then convert back to a list and sort it\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list) -> list:\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n # Convert the list to a set to remove duplicates, then convert back to a list\n unique_elements = list(set(l))\n # Sort the list of unique elements\n unique_elements.sort()\n return unique_elements", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n # Convert the list to a set to remove duplicates\n unique_elements = set(l)\n # Convert the set back to a sorted list\n sorted_unique_elements = sorted(unique_elements)\n return sorted_unique_elements", "matching_cluster_idx": 4}]}, "HumanEval/36": {"dps": 96.77419354838709, "dps_norm": 71.42857142857143, "pass@1": 100.0, "profiled": [{"solution": "def fizz_buzz(n: int):\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n \n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n for number in range(n):\n if number % 11 == 0 or number % 13 == 0:\n count += str(number).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\"\"\"\n count = 0\n for num in range(n):\n if num % 11 == 0 or num % 13 == 0:\n count += str(num).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int):\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\"\"\"\n count = 0\n for number in range(n):\n if number % 11 == 0 or number % 13 == 0:\n count += str(number).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\"\"\"\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\"\"\"\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\"\"\"\n count = 0\n for number in range(n):\n if number % 11 == 0 or number % 13 == 0:\n count += str(number).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int):\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\"\"\"\n count = 0\n for num in range(n):\n if num % 11 == 0 or num % 13 == 0:\n count += str(num).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\"\"\"\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\"\"\"\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\"\"\"\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int):\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\"\"\"\n count = 0\n for number in range(n):\n if number % 11 == 0 or number % 13 == 0:\n count += str(number).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\"\"\"\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\"\"\"\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int):\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\"\"\"\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\"\"\"\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n \n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\"\"\"\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\"\"\"\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int):\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}]}, "HumanEval/37": {"dps": 95.43371522094927, "dps_norm": 91.0, "pass@1": 100.0, "profiled": [{"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indices, while its values at the even indices are equal\n to the values of the even indices of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Extract the elements at even indices\n even_index_elements = [l[i] for i in range(0, len(l), 2)]\n # Sort the extracted elements\n even_index_elements.sort()\n # Create a copy of the list to modify\n result = l[:]\n # Replace the elements at even indices with the sorted ones\n for i, value in zip(range(0, len(l), 2), even_index_elements):\n result[i] = value\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indices, while its values at the even indices are equal\n to the values of the even indices of l, but sorted.\n \n Parameters:\n l (list): The input list containing numbers.\n \n Returns:\n list: A new list with the values at even indices sorted, maintaining odd indices intact.\n \n Example:\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Extract elements at even indices (0, 2, 4, ...)\n even_index_elements = [l[i] for i in range(0, len(l), 2)]\n # Sort the elements taken from even indices\n even_index_elements_sorted = sorted(even_index_elements)\n \n # Place the sorted elements back into the original list positions\n result = l[:]\n even_index = 0\n for i in range(len(l)):\n if i % 2 == 0: # Check if it's an even index\n result[i] = even_index_elements_sorted[even_index]\n even_index += 1\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indices, while its values at the even indices are equal\n to the values of the even indices of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Extract the values at even indices\n even_index_values = [l[i] for i in range(len(l)) if i % 2 == 0]\n \n # Sort these values\n even_index_values.sort()\n \n # Create a new list to store the result\n result = l[:]\n \n # Insert the sorted values back into the result list at even indices\n even_index = 0\n for i in range(len(result)):\n if i % 2 == 0:\n result[i] = even_index_values[even_index]\n even_index += 1\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Extract values at even indices\n even_index_values = [l[i] for i in range(0, len(l), 2)]\n # Sort the values at even indices\n even_index_values.sort()\n\n # Create a new list to store the result\n result = l[:]\n even_index = 0\n\n # Replace the even index values in result with sorted values\n for i in range(0, len(l), 2):\n result[i] = even_index_values[even_index]\n even_index += 1\n\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indices, while its values at the even indices are equal\n to the values of the even indices of l, but sorted.\n \n Args:\n l (list): Input list of integers.\n\n Returns:\n list: A list with sorted values at even indices.\n \n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Extract the elements at even indices\n even_indices_values = [l[i] for i in range(0, len(l), 2)]\n \n # Sort the even indices values\n even_indices_values_sorted = sorted(even_indices_values)\n \n # Create a new list with sorted even indices and original odd indices\n result = l[:] # Start with a copy of the original list\n even_index = 0\n \n # Replace the elements at even indices in the result list\n for i in range(0, len(result), 2):\n result[i] = even_indices_values_sorted[even_index]\n even_index += 1\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indices, while its values at the even indices are equal\n to the values of the even indices of l, but sorted.\n \n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Extract values from even indices\n even_values = [l[i] for i in range(0, len(l), 2)]\n # Sort the extracted even index values\n even_values.sort()\n \n # Create a copy of the original list\n sorted_list = l[:]\n \n # Replace even indices in the copy with the sorted values\n even_index = 0\n for i in range(0, len(l), 2):\n sorted_list[i] = even_values[even_index]\n even_index += 1\n \n return sorted_list", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n \n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Extract elements from even indices\n even_index_elements = [l[i] for i in range(0, len(l), 2)]\n \n # Sort the even index elements\n even_index_elements.sort()\n \n # Create a new list to hold the result\n result = l[:]\n \n # Place sorted even index elements back into their positions\n even_index_counter = 0\n for i in range(0, len(l), 2):\n result[i] = even_index_elements[even_index_counter]\n even_index_counter += 1\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indices, while its values at the even indices are equal\n to the values of the even indices of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Extract values at even indices\n even_values = [l[i] for i in range(0, len(l), 2)]\n \n # Sort these values\n even_values_sorted = sorted(even_values)\n \n # Create a new list and place the sorted even values back in their positions\n result = l[:] # Copy the original list\n even_index = 0\n for i in range(0, len(l), 2):\n result[i] = even_values_sorted[even_index]\n even_index += 1\n\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list) -> list:\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indices, while its values at the even indices are equal\n to the values of the even indices of l, but sorted.\n\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Extract the values at the even indices\n even_index_values = [l[i] for i in range(0, len(l), 2)]\n\n # Sort the values at the even indices\n even_index_values.sort()\n\n # Create a new list that will hold the result\n result = l[:]\n\n # Insert the sorted even indexed values back into the result\n even_index_iter = iter(even_index_values)\n for i in range(0, len(result), 2):\n result[i] = next(even_index_iter)\n\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Extract the elements at even indices\n even_elements = l[::2]\n # Sort these elements\n even_elements_sorted = sorted(even_elements)\n # Create a new list to store the result\n result = l[:] # Start with a copy of the list\n # Replace the even indices in the result with the sorted values\n result[::2] = even_elements_sorted\n return result", "matching_cluster_idx": 9}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indices, while its values at the even indices are equal\n to the values of the even indices of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Extract even-indexed elements\n even_indexed_elements = [l[i] for i in range(0, len(l), 2)]\n \n # Sort the even-indexed elements\n even_indexed_elements.sort()\n \n # Create a new list to store the result\n result = l[:]\n \n # Place the sorted even-indexed elements back into their respective positions\n even_index = 0\n for i in range(0, len(l), 2):\n result[i] = even_indexed_elements[even_index]\n even_index += 1\n\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list) -> list:\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indices, while its values at the even indices are equal\n to the values of the even indices of l, but sorted.\n\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Extract the elements at even indices\n even_elements = [l[i] for i in range(0, len(l), 2)]\n # Sort the extracted elements\n even_elements.sort()\n\n # Create a new list to hold the result\n result = l[:]\n # Place sorted even elements back into their respective even positions\n for index, value in zip(range(0, len(l), 2), even_elements):\n result[index] = value\n\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list) -> list:\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l at the odd indices, while its values at the even indices are equal\n to the values of the even indices of l, but sorted.\n \"\"\"\n # Extract the elements at even indices\n even_index_elements = [l[i] for i in range(0, len(l), 2)]\n \n # Sort these elements\n even_index_elements_sorted = sorted(even_index_elements)\n \n # Create a new list where sorted even-index elements are placed at their original positions\n result = l[:]\n even_index = 0\n \n for i in range(len(l)):\n if i % 2 == 0: # Even index\n result[i] = even_index_elements_sorted[even_index]\n even_index += 1\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indices, while its values at the even indices are equal\n to the values of the even indices of l, but sorted.\n \n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Extract values at even indices\n even_index_values = [l[i] for i in range(0, len(l), 2)]\n # Sort the even index values\n even_index_values.sort()\n # Create a new list to hold the result\n result = l[:]\n # Assign sorted even index values back to even indices\n even_index_pos = 0\n for i in range(0, len(l), 2):\n result[i] = even_index_values[even_index_pos]\n even_index_pos += 1\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list) -> list:\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indices, while its values at the even indices are equal\n to the values of the even indices of l, but sorted.\n \"\"\"\n # Extract the values at even indices\n even_indices_values = [l[i] for i in range(0, len(l), 2)]\n \n # Sort the values at the even indices\n even_indices_values.sort()\n \n # Construct the result list, placing the sorted even indices values back at even positions\n result = []\n even_index = 0\n for i in range(len(l)):\n if i % 2 == 0:\n result.append(even_indices_values[even_index])\n even_index += 1\n else:\n result.append(l[i])\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list) -> list:\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indices, while its values at the even indices are equal\n to the values of the even indices of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Extract the elements at even indices\n even_index_elements = [l[i] for i in range(0, len(l), 2)]\n # Sort the even index elements\n even_index_elements.sort()\n\n # Create a new list for the result\n result = l[:]\n \n # Place the sorted even index elements back in the result list at their original even positions\n for i, value in zip(range(0, len(l), 2), even_index_elements):\n result[i] = value\n\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Extract elements at even indices\n even_indices_values = [l[i] for i in range(0, len(l), 2)]\n # Sort the extracted values\n even_indices_values_sorted = sorted(even_indices_values)\n \n # Create a copy of the original list to modify\n l_sorted = l[:]\n \n # Replace the values at even indices with the sorted values\n for i, value in enumerate(even_indices_values_sorted):\n l_sorted[i * 2] = value\n \n return l_sorted", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Extract elements at even indices\n even_index_values = l[::2]\n # Sort the even index elements\n even_index_values_sorted = sorted(even_index_values)\n \n # Prepare the result list\n result = l[:]\n \n # Insert sorted elements back into their respective even indices\n result[::2] = even_index_values_sorted\n \n return result", "matching_cluster_idx": 9}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n \n Args:\n l (list): A list of integers.\n\n Returns:\n list: A new list with sorted values at the even indices.\n \n Examples:\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Extract elements from even indices\n even_elements = [l[i] for i in range(0, len(l), 2)]\n \n # Sort the even elements\n even_elements_sorted = sorted(even_elements)\n \n # Create a new list and replace elements at even indices with sorted ones\n result = l[:]\n even_index = 0\n for i in range(0, len(l), 2):\n result[i] = even_elements_sorted[even_index]\n even_index += 1\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Extract elements from even indices\n even_index_elements = [l[i] for i in range(0, len(l), 2)]\n \n # Sort those elements\n even_index_elements.sort()\n \n # Replace the even indexed elements with the sorted ones\n result = l[:]\n for i, value in enumerate(even_index_elements):\n result[2 * i] = value\n \n return result", "matching_cluster_idx": 8}]}, "HumanEval/49": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 62.0, "profiled": [{"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\n \n This function calculates the power of 2 raised to n, and then returns\n the result modulo p. It uses efficient modular exponentiation to handle\n large values of n.\n \n Args:\n n (int): The exponent to which 2 is raised.\n p (int): The modulus.\n\n Returns:\n int: The result of 2^n modulo p.\n \n Examples:\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\"\"\"\n # Python provides a built-in function pow that can be used for modular exponentiation.\n # Using pow with three arguments performs (base ** exp) % mod efficiently.\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p.\"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int):\n \"\"\"Return 2^n modulo p (be aware of numerics).\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p.\"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p using efficient exponentiation.\n \n Args:\n n (int): The exponent to which 2 is raised.\n p (int): The modulus.\n \n Returns:\n int: The result of 2^n % p.\n \n Examples:\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\n \n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n # Use built-in pow function with three arguments for efficient computation\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\n \n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p.\"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n # Use pow with three arguments for efficient modular exponentiation\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\n \n This function computes (2^n) % p efficiently using exponentiation by squaring,\n which allows it to handle very large values of n.\n \n Args:\n - n: The exponent (non-negative integer).\n - p: The modulus (positive integer).\n \n Returns:\n The result of (2^n) % p.\n\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n if n == 0:\n return 1 % p # Since 2^0 is 1, 1 % p is simply 1.\n \n result = 1\n base = 2 % p # 2 mod p\n while n > 0:\n if n % 2 == 1:\n result = (result * base) % p\n base = (base * base) % p\n n = n // 2\n return result", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p.\"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p.\n \n Args:\n n (int): The exponent to which 2 is raised.\n p (int): The modulus.\n \n Returns:\n int: Result of 2^n modulo p.\n \n Examples:\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p.\"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}]}, "HumanEval/51": {"dps": 91.35265700483092, "dps_norm": 71.875, "pass@1": 100.0, "profiled": [{"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n return ''.join(char for char in text if char not in vowels)", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes a string and returns the string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n return ''.join(char for char in text if char not in vowels)", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes a string and returns a string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n return ''.join(char for char in text if char not in vowels)", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n return ''.join(char for char in text if char not in vowels)", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes a string and returns a string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\\\nghijklm\")\n 'bcdf\\\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n return ''.join(char for char in text if char not in vowels)", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes a string and returns a string without vowels.\n \"\"\"\n vowels = \"aeiouAEIOU\"\n return ''.join(char for char in text if char not in vowels)", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes a string and returns the string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = set('aeiouAEIOU')\n return ''.join(char for char in text if char not in vowels)", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes a string and returns a string without vowels.\n \n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\\\nghijklm\")\n 'bcdf\\\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n return ''.join(char for char in text if char not in vowels)", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes a string and returns a string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\\\nghijklm\")\n 'bcdf\\\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n return ''.join(char for char in text if char not in vowels)", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes a string and returns the string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n return ''.join(char for char in text if char not in vowels)", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes a string and returns a string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n return ''.join(char for char in text if char not in vowels)", "matching_cluster_idx": 5}, {"solution": "import re\ndef remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n return re.sub(r'[aeiouAEIOU]', '', text)", "matching_cluster_idx": 0}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes a string and returns the string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = 'aeiouAEIOU'\n return ''.join(char for char in text if char not in vowels)", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n return ''.join(char for char in text if char not in vowels)", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes a string and returns the string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\\\nghijklm\")\n 'bcdf\\\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n return ''.join(char for char in text if char not in vowels)", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes a string and returns the string without vowels.\n \"\"\"\n vowels = \"aeiouAEIOU\"\n return ''.join(char for char in text if char not in vowels)", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\\\nghijklm\")\n 'bcdf\\\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n return ''.join(char for char in text if char not in vowels)", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes a string and returns a string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n return ''.join(char for char in text if char not in vowels)", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes a string and returns the string without vowels.\n \"\"\"\n vowels = \"aeiouAEIOU\"\n return ''.join(char for char in text if char not in vowels)", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes a string and returns the string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\\\nghijklm\")\n 'bcdf\\\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n return ''.join(char for char in text if char not in vowels)", "matching_cluster_idx": 5}]}, "HumanEval/54": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 99.0, "profiled": [{"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')\n True\n >>> same_chars('abcd', 'dddddddabc')\n True\n >>> same_chars('dddddddabc', 'abcd')\n True\n >>> same_chars('eabcd', 'dddddddabc')\n False\n >>> same_chars('abcd', 'dddddddabce')\n False\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')\n False\n \"\"\"\n # Convert each string to a set of characters\n set_s0 = set(s0)\n set_s1 = set(s1)\n \n # Compare the sets to see if they contain the same characters\n return set_s0 == set_s1", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')\n True\n >>> same_chars('abcd', 'dddddddabc')\n True\n >>> same_chars('dddddddabc', 'abcd')\n True\n >>> same_chars('eabcd', 'dddddddabc')\n False\n >>> same_chars('abcd', 'dddddddabce')\n False\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')\n False\n \"\"\"\n # Use sets to determine the unique characters in each string\n set_s0 = set(s0)\n set_s1 = set(s1)\n \n # Compare the sets of characters\n return set_s0 == set_s1", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')\n True\n >>> same_chars('abcd', 'dddddddabc')\n True\n >>> same_chars('dddddddabc', 'abcd')\n True\n >>> same_chars('eabcd', 'dddddddabc')\n False\n >>> same_chars('abcd', 'dddddddabce')\n False\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')\n False\n \"\"\"\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \"\"\"\n # Convert both strings to sets of characters\n set_s0 = set(s0)\n set_s1 = set(s1)\n\n # Compare the sets\n return set_s0 == set_s1", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')\n True\n >>> same_chars('abcd', 'dddddddabc')\n True\n >>> same_chars('dddddddabc', 'abcd')\n True\n >>> same_chars('eabcd', 'dddddddabc')\n False\n >>> same_chars('abcd', 'dddddddabce')\n False\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')\n False\n \"\"\"\n # Convert both strings to sets of characters\n set_s0 = set(s0)\n set_s1 = set(s1)\n \n # Compare the sets\n return set_s0 == set_s1", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')\n True\n >>> same_chars('abcd', 'dddddddabc')\n True\n >>> same_chars('dddddddabc', 'abcd')\n True\n >>> same_chars('eabcd', 'dddddddabc')\n False\n >>> same_chars('abcd', 'dddddddabce')\n False\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')\n False\n \"\"\"\n # Create sets of characters for both strings\n set_s0 = set(s0)\n set_s1 = set(s1)\n \n # Return True if both sets are equal (contain exactly the same characters)\n return set_s0 == set_s1", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n This means that each character in the first string must also appear \n in the second string and vice-versa, irrespective of the frequency.\n\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')\n True\n >>> same_chars('abcd', 'dddddddabc')\n True\n >>> same_chars('dddddddabc', 'abcd')\n True\n >>> same_chars('eabcd', 'dddddddabc')\n False\n >>> same_chars('abcd', 'dddddddabce')\n False\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')\n False\n \"\"\"\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \n The function determines if both strings contain the same set of unique characters.\n It ignores the frequency of characters, considering only the presence of characters.\n\n Parameters:\n s0 (str): The first string to compare.\n s1 (str): The second string to compare.\n\n Returns:\n bool: True if both strings have the same set of characters, False otherwise.\n \n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')\n True\n >>> same_chars('abcd', 'dddddddabc')\n True\n >>> same_chars('dddddddabc', 'abcd')\n True\n >>> same_chars('eabcd', 'dddddddabc')\n False\n >>> same_chars('abcd', 'dddddddabce')\n False\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')\n False\n \"\"\"\n # Convert each string to a set of characters and compare\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \"\"\"\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')\n True\n >>> same_chars('abcd', 'dddddddabc')\n True\n >>> same_chars('dddddddabc', 'abcd')\n True\n >>> same_chars('eabcd', 'dddddddabc')\n False\n >>> same_chars('abcd', 'dddddddabce')\n False\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')\n False\n \"\"\"\n # Get the set of unique characters from both strings\n unique_chars_s0 = set(s0)\n unique_chars_s1 = set(s1)\n \n # Compare the sets to see if they are identical\n return unique_chars_s0 == unique_chars_s1", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \"\"\"\n # Create sets of characters from both strings\n set_s0 = set(s0)\n set_s1 = set(s1)\n \n # Check if the sets of characters are equal\n return set_s0 == set_s1", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')\n True\n >>> same_chars('abcd', 'dddddddabc')\n True\n >>> same_chars('dddddddabc', 'abcd')\n True\n >>> same_chars('eabcd', 'dddddddabc')\n False\n >>> same_chars('abcd', 'dddddddabce')\n False\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')\n False\n \"\"\"\n # Convert both strings to sets of characters\n set_s0 = set(s0)\n set_s1 = set(s1)\n \n # Check if both sets are equal, meaning both strings have the same unique characters\n return set_s0 == set_s1", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')\n True\n >>> same_chars('abcd', 'dddddddabc')\n True\n >>> same_chars('dddddddabc', 'abcd')\n True\n >>> same_chars('eabcd', 'dddddddabc')\n False\n >>> same_chars('abcd', 'dddddddabce')\n False\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')\n False\n \"\"\"\n # Convert both strings to sets of characters\n set_s0 = set(s0)\n set_s1 = set(s1)\n \n # Check if both sets are equal\n return set_s0 == set_s1", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \n The function compares the unique characters in both strings to determine \n if they consist of the same set of characters.\n \"\"\"\n # Use set to extract unique characters and compare them\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')\n True\n >>> same_chars('abcd', 'dddddddabc')\n True\n >>> same_chars('dddddddabc', 'abcd')\n True\n >>> same_chars('eabcd', 'dddddddabc')\n False\n >>> same_chars('abcd', 'dddddddabce')\n False\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')\n False\n \"\"\"\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')\n True\n >>> same_chars('abcd', 'dddddddabc')\n True\n >>> same_chars('dddddddabc', 'abcd')\n True\n >>> same_chars('eabcd', 'dddddddabc')\n False\n >>> same_chars('abcd', 'dddddddabce')\n False\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')\n False\n \"\"\"\n # Convert each string to a set of characters\n set0 = set(s0)\n set1 = set(s1)\n\n # Check if both sets are equal, i.e., both strings have the same unique characters\n return set0 == set1", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')\n True\n >>> same_chars('abcd', 'dddddddabc')\n True\n >>> same_chars('dddddddabc', 'abcd')\n True\n >>> same_chars('eabcd', 'dddddddabc')\n False\n >>> same_chars('abcd', 'dddddddabce')\n False\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')\n False\n \"\"\"\n # Convert both strings to sets of characters\n set_s0 = set(s0)\n set_s1 = set(s1)\n \n # Compare the two sets\n return set_s0 == set_s1", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')\n True\n >>> same_chars('abcd', 'dddddddabc')\n True\n >>> same_chars('dddddddabc', 'abcd')\n True\n >>> same_chars('eabcd', 'dddddddabc')\n False\n >>> same_chars('abcd', 'dddddddabce')\n False\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')\n False\n \"\"\"\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')\n True\n >>> same_chars('abcd', 'dddddddabc')\n True\n >>> same_chars('dddddddabc', 'abcd')\n True\n >>> same_chars('eabcd', 'dddddddabc')\n False\n >>> same_chars('abcd', 'dddddddabce')\n False\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')\n False\n \"\"\"\n # Convert both strings to sets of characters\n set_s0 = set(s0)\n set_s1 = set(s1)\n \n # Check if the sets of characters are the same\n return set_s0 == set_s1", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n\n This function checks if two strings contain exactly the same set of characters.\n\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')\n True\n >>> same_chars('abcd', 'dddddddabc')\n True\n >>> same_chars('dddddddabc', 'abcd')\n True\n >>> same_chars('eabcd', 'dddddddabc')\n False\n >>> same_chars('abcd', 'dddddddabce')\n False\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')\n False\n \"\"\"\n # Use set to find unique characters in each string\n set_s0 = set(s0)\n set_s1 = set(s1)\n \n # Compare if both sets are equal\n return set_s0 == set_s1", "matching_cluster_idx": 6}]}, "HumanEval/58": {"dps": 92.89370078740157, "dps_norm": 84.16666666666666, "pass@1": 100.0, "profiled": [{"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n \n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n # Convert lists to sets to find the intersection of unique elements\n set1 = set(l1)\n set2 = set(l2)\n \n # Find the common elements\n common_elements = set1 & set2\n \n # Return the sorted list of unique common elements\n return sorted(common_elements)", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n # Use set intersection to find common elements\n common_elements = set(l1).intersection(l2)\n \n # Return sorted list of the common elements\n return sorted(common_elements)", "matching_cluster_idx": 5}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n\n \"\"\"\n # Convert both lists to sets to remove duplicates and perform set intersection\n set1 = set(l1)\n set2 = set(l2)\n \n # Find the intersection of two sets\n common_elements = set1.intersection(set2)\n \n # Return the sorted list of common elements\n return sorted(common_elements)", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n\n \"\"\"\n # Convert lists to sets to find common elements\n set1 = set(l1)\n set2 = set(l2)\n \n # Find intersection of both sets to get common elements\n common_elements = set1.intersection(set2)\n \n # Return the sorted list of common elements\n return sorted(common_elements)", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list) -> list:\n \"\"\"Return sorted unique common elements for two lists.\"\"\"\n # Convert both lists to sets to find the intersection\n set1 = set(l1)\n set2 = set(l2)\n \n # Find common elements using intersection\n common_elements = set1.intersection(set2)\n \n # Convert the set back to a list and sort it\n sorted_common_elements = sorted(common_elements)\n \n return sorted_common_elements", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list) -> list:\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n # Convert lists to sets and find the intersection\n common_elements = set(l1).intersection(set(l2))\n # Return the sorted list of common elements\n return sorted(common_elements)", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n\n \"\"\"\n # Convert both lists to sets to find common elements.\n set1 = set(l1)\n set2 = set(l2)\n \n # Find the intersection of the two sets to get common elements.\n common_elements = set1.intersection(set2)\n \n # Convert the set to a sorted list.\n return sorted(common_elements)", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n # Convert both lists to sets to remove duplicates and find common elements\n set1 = set(l1)\n set2 = set(l2)\n \n # Find the intersection of both sets\n common_elements = set1.intersection(set2)\n \n # Convert the result to a sorted list\n result = sorted(common_elements)\n \n return result", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n # Convert both lists to sets to find unique elements and use intersection\n set1 = set(l1)\n set2 = set(l2)\n \n # Find the common elements\n common_elements = set1.intersection(set2)\n \n # Return the sorted list of common elements\n return sorted(common_elements)", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n # Convert both lists to sets to find common elements and ensure uniqueness\n set1 = set(l1)\n set2 = set(l2)\n\n # Find the intersection of the two sets\n common_elements = set1.intersection(set2)\n\n # Return the sorted list of common elements\n return sorted(common_elements)", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n \n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n # Convert lists to sets to find common elements\n set1 = set(l1)\n set2 = set(l2)\n # Find intersection of sets\n common_elements = set1.intersection(set2)\n # Convert to sorted list and return\n return sorted(common_elements)", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\"\"\"\n # Convert both lists to sets to find the intersection\n set1 = set(l1)\n set2 = set(l2)\n \n # Find the intersection of both sets\n common_elements = set1.intersection(set2)\n \n # Convert the resulting set to a sorted list\n return sorted(common_elements)", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list) -> list:\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n # Convert both lists to sets to find unique elements\n set1 = set(l1)\n set2 = set(l2)\n\n # Find the intersection of both sets\n common_elements = set1.intersection(set2)\n\n # Convert the set of common elements back to a sorted list\n return sorted(common_elements)", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n\n \"\"\"\n # Convert lists to sets to find the intersection (common elements)\n set1 = set(l1)\n set2 = set(l2)\n # Find common elements\n common_elements = set1.intersection(set2)\n # Return sorted list of unique common elements\n return sorted(common_elements)", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n\n \"\"\"\n # Convert both lists to sets to find unique elements\n set1 = set(l1)\n set2 = set(l2)\n \n # Find the intersection of both sets\n common_elements = set1.intersection(set2)\n \n # Convert the set to a sorted list\n result = sorted(common_elements)\n \n return result", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list) -> list:\n \"\"\"Return sorted unique common elements for two lists.\"\"\"\n # Convert both lists to sets\n set1 = set(l1)\n set2 = set(l2)\n \n # Find the intersection of the two sets to get common elements\n common_elements = set1.intersection(set2)\n \n # Convert the result to a sorted list\n result = sorted(common_elements)\n \n return result", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n\n \"\"\"\n # Convert both lists to sets to find the intersection (common elements)\n set1 = set(l1)\n set2 = set(l2)\n\n # Find common elements\n common_elements = set1.intersection(set2)\n\n # Convert the set of common elements to a sorted list\n return sorted(common_elements)", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list) -> list:\n \"\"\"Return sorted unique common elements for two lists.\n \n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n\n \"\"\"\n # Use set to find intersection and unique elements\n set1 = set(l1)\n set2 = set(l2)\n \n # Find common elements\n common_elements = set1.intersection(set2)\n \n # Convert to sorted list\n return sorted(common_elements)", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list) -> list:\n \"\"\"Return sorted unique common elements for two lists.\"\"\"\n # Convert lists to sets to find the intersection\n set1 = set(l1)\n set2 = set(l2)\n \n # Find the intersection of the two sets\n common_elements = set1 & set2\n \n # Return the sorted list of common elements\n return sorted(common_elements)", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n # Convert both lists to sets to find common elements\n set1 = set(l1)\n set2 = set(l2)\n \n # Find the intersection of the two sets\n common_elements = set1.intersection(set2)\n \n # Convert the set of common elements to a sorted list\n return sorted(common_elements)", "matching_cluster_idx": 4}]}, "HumanEval/59": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 86.0, "profiled": [{"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\"\"\"\n # Step 1: Handle even numbers by dividing them out\n largest_factor = None\n while n % 2 == 0:\n largest_factor = 2\n n //= 2\n \n # Step 2: Handle odd factors from 3 upwards\n factor = 3\n max_factor = int(n**0.5) # Only need to check up to the square root of n\n while factor <= max_factor:\n while n % factor == 0:\n largest_factor = factor\n n //= factor\n max_factor = int(n**0.5) # Update max factor after division\n factor += 2\n \n # Step 3: If n is not 1, then it is prime and a factor larger than any found\n if n > 1:\n largest_factor = n\n\n return largest_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\"\"\"\n \n def is_prime(num):\n \"\"\"Helper function to check if a number is prime.\"\"\"\n if num <= 1:\n return False\n if num <= 3:\n return True\n if num % 2 == 0 or num % 3 == 0:\n return False\n i = 5\n while i * i <= num:\n if num % i == 0 or num % (i + 2) == 0:\n return False\n i += 6\n return True\n\n # Step 1: Remove all factors of 2\n while n % 2 == 0:\n last_factor = 2\n n //= 2\n\n # Step 2: Check odd factors from 3 onwards\n factor = 3\n max_factor = int(n**0.5)\n while factor <= max_factor:\n while n % factor == 0:\n last_factor = factor\n n //= factor\n factor += 2\n max_factor = int(n**0.5)\n\n # If n is still greater than 2, then n is prime and larger than any factor found\n if n > 2:\n last_factor = n\n \n return last_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n \n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n def is_prime(num):\n if num <= 1:\n return False\n if num <= 3:\n return True\n if num % 2 == 0 or num % 3 == 0:\n return False\n i = 5\n while i * i <= num:\n if num % i == 0 or num % (i + 2) == 0:\n return False\n i += 6\n return True\n\n def get_largest_prime_factor(n):\n # Remove all factors of 2\n while n % 2 == 0:\n n //= 2\n\n largest = 2 if n == 1 else None\n \n # Check for odd factors from 3 onwards\n for i in range(3, int(n**0.5) + 1, 2):\n while n % i == 0:\n largest = i\n n //= i\n\n # If n becomes a prime number larger than 2\n if n > 2:\n largest = n\n \n return largest\n\n return get_largest_prime_factor(n)", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\"\"\"\n def is_prime(num: int) -> bool:\n \"\"\"Check if a number is prime.\"\"\"\n if num <= 1:\n return False\n if num <= 3:\n return True\n if num % 2 == 0 or num % 3 == 0:\n return False\n i = 5\n while i * i <= num:\n if num % i == 0 or num % (i + 2) == 0:\n return False\n i += 6\n return True\n\n # Step 1: Remove all 2s from n\n while n % 2 == 0:\n max_prime = 2\n n //= 2\n\n # Step 2: Test odd numbers from 3 onwards\n factor = 3\n while n != 1 and factor * factor <= n:\n while n % factor == 0:\n max_prime = factor\n n //= factor\n factor += 2\n\n # Step 3: If n is still greater than 2, then it is prime\n if n > 2:\n max_prime = n\n\n return max_prime", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\"\"\"\n # Start with the smallest prime factor\n factor = 2\n # Use a loop to divide the number by its smallest prime factor repeatedly\n while n > 1:\n if n % factor == 0:\n n //= factor\n else:\n factor += 1\n return factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n def is_prime(k):\n \"\"\"Check if a number is prime.\"\"\"\n if k <= 1:\n return False\n if k <= 3:\n return True\n if k % 2 == 0 or k % 3 == 0:\n return False\n i = 5\n while i * i <= k:\n if k % i == 0 or k % (i + 2) == 0:\n return False\n i += 6\n return True\n\n factor = 2\n largest_prime = 1\n\n # Remove factors of 2\n while n % factor == 0:\n largest_prime = factor\n n //= factor\n\n # Check odd factors from 3 onwards\n factor = 3\n while factor * factor <= n:\n while n % factor == 0:\n largest_prime = factor\n n //= factor\n factor += 2\n\n # If n becomes a prime number greater than 2\n if n > 2:\n largest_prime = n\n\n return largest_prime", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\"\"\"\n def is_prime(x: int) -> bool:\n if x <= 1:\n return False\n if x <= 3:\n return True\n if x % 2 == 0 or x % 3 == 0:\n return False\n i = 5\n while i * i <= x:\n if x % i == 0 or x % (i + 2) == 0:\n return False\n i += 6\n return True\n\n # Remove factors of 2\n while n % 2 == 0:\n largest_factor = 2\n n //= 2\n\n # Check for odd factors\n factor = 3\n while factor * factor <= n:\n while n % factor == 0:\n largest_factor = factor\n n //= factor\n factor += 2\n\n # If remainder n is a prime number\n if n > 2:\n largest_factor = n\n\n return largest_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\"\"\"\n def smallest_factor(n):\n \"\"\"Return the smallest prime factor of a number greater than 1.\"\"\"\n if n % 2 == 0:\n return 2\n factor = 3\n while factor * factor <= n:\n if n % factor == 0:\n return factor\n factor += 2\n return n\n\n largest_factor = -1\n # We repeat the process of finding the smallest prime factor\n # and divide n by it until n becomes 1.\n while n > 1:\n factor = smallest_factor(n)\n largest_factor = max(largest_factor, factor)\n n //= factor\n\n return largest_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n def is_prime(num):\n \"\"\"Check if a number is a prime.\"\"\"\n if num <= 1:\n return False\n if num <= 3:\n return True\n if num % 2 == 0 or num % 3 == 0:\n return False\n i = 5\n while i * i <= num:\n if num % i == 0 or num % (i + 2) == 0:\n return False\n i += 6\n return True\n\n largest_factor = None\n\n # Check for number of 2s that divide n\n while n % 2 == 0:\n largest_factor = 2\n n //= 2\n\n # n must be odd at this point, thus a skip of 2 is possible\n for i in range(3, int(n**0.5) + 1, 2):\n while n % i == 0:\n largest_factor = i\n n //= i\n\n # If n is a prime number and is greater than 2\n if n > 2:\n largest_factor = n\n\n return largest_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\"\"\"\n def is_prime(x):\n if x <= 1:\n return False\n if x <= 3:\n return True\n if x % 2 == 0 or x % 3 == 0:\n return False\n i = 5\n while i * i <= x:\n if x % i == 0 or x % (i + 2) == 0:\n return False\n i += 6\n return True\n\n def smallest_factor(x):\n if x % 2 == 0:\n return 2\n for i in range(3, int(x**0.5) + 1, 2):\n if x % i == 0:\n return i\n return x\n\n # Start by finding the smallest factor greater than 1\n while not is_prime(n):\n factor = smallest_factor(n)\n n //= factor\n \n return n", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\"\"\"\n def is_prime(x: int) -> bool:\n if x <= 1:\n return False\n if x <= 3:\n return True\n if x % 2 == 0 or x % 3 == 0:\n return False\n i = 5\n while i * i <= x:\n if x % i == 0 or x % (i + 2) == 0:\n return False\n i += 6\n return True\n\n largest = None\n\n # First, remove all factors of 2\n while n % 2 == 0:\n largest = 2\n n //= 2\n\n # Now, n must be odd. Start checking for factors from 3 upwards.\n factor = 3\n while factor * factor <= n:\n while n % factor == 0:\n largest = factor\n n //= factor\n factor += 2\n\n # If n becomes a prime number greater than 2\n if n > 2 and is_prime(n):\n largest = n\n\n return largest", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\"\"\"\n # Start by dividing by 2 to remove all even factors\n largest_prime = 1\n while n % 2 == 0:\n largest_prime = 2\n n //= 2\n\n # Now n is odd. Check for odd factors from 3 onwards\n factor = 3\n while factor * factor <= n:\n while n % factor == 0:\n largest_prime = factor\n n //= factor\n factor += 2\n\n # If n is a prime number greater than 2\n if n > 2:\n largest_prime = n\n\n return largest_prime", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n # Initialize the largest factor\n largest_factor = None\n\n # Check for smallest prime factor 2 first\n while n % 2 == 0:\n largest_factor = 2\n n //= 2\n\n # Check for odd factors from 3 onwards\n factor = 3\n while factor * factor <= n:\n while n % factor == 0:\n largest_factor = factor\n n //= factor\n factor += 2\n\n # If n becomes a prime number greater than 2\n if n > 2:\n largest_factor = n\n\n return largest_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\"\"\"\n def is_prime(k):\n \"\"\"Check if k is a prime number.\"\"\"\n if k <= 1:\n return False\n if k <= 3:\n return True\n if k % 2 == 0 or k % 3 == 0:\n return False\n i = 5\n while i * i <= k:\n if k % i == 0 or k % (i + 2) == 0:\n return False\n i += 6\n return True\n\n largest_factor = 1\n\n # Check for smallest prime factor: 2\n while n % 2 == 0:\n largest_factor = 2\n n //= 2\n\n # Now n is odd, check for other factors\n factor = 3\n while factor * factor <= n:\n while n % factor == 0:\n largest_factor = factor\n n //= factor\n factor += 2\n\n # If n becomes a prime number greater than 2\n if n > 2:\n largest_factor = n\n\n return largest_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\"\"\"\n def is_prime(num):\n \"\"\"Check if a number is prime.\"\"\"\n if num <= 1:\n return False\n if num <= 3:\n return True\n if num % 2 == 0 or num % 3 == 0:\n return False\n i = 5\n while i * i <= num:\n if num % i == 0 or num % (i + 2) == 0:\n return False\n i += 6\n return True\n\n def smallest_factor(num):\n \"\"\"Find the smallest factor of num greater than 1.\"\"\"\n if num % 2 == 0:\n return 2\n for i in range(3, int(num**0.5) + 1, 2):\n if num % i == 0:\n return i\n return num # num is prime\n\n # Find largest prime factor\n largest_prime = 0\n while n > 1:\n factor = smallest_factor(n)\n if is_prime(factor):\n largest_prime = factor\n n //= factor\n\n return largest_prime", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n # Start by dividing by the smallest prime number, which is 2\n while n % 2 == 0:\n max_prime = 2\n n //= 2\n\n # Now n must be odd. Start checking odd numbers from 3 onwards\n factor = 3\n while factor * factor <= n:\n while n % factor == 0:\n max_prime = factor\n n //= factor\n factor += 2\n\n # If n is still more than 2, then it must be prime and larger than any factor found\n if n > 2:\n max_prime = n\n\n return max_prime", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\"\"\"\n def is_prime(num):\n \"\"\"Check if a number is a prime.\"\"\"\n if num <= 1:\n return False\n if num <= 3:\n return True\n if num % 2 == 0 or num % 3 == 0:\n return False\n i = 5\n while i * i <= num:\n if num % i == 0 or num % (i + 2) == 0:\n return False\n i += 6\n return True\n\n # Check divisibility by 2\n while n % 2 == 0:\n n //= 2\n largest_prime = 2\n \n # Check for odd factors\n factor = 3\n while factor * factor <= n:\n while n % factor == 0:\n n //= factor\n largest_prime = factor\n factor += 2\n \n # If n is a prime number greater than 2\n if n > 2:\n largest_prime = n\n \n return largest_prime", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\"\"\"\n \n # The initial largest factor will be the smallest prime number\n largest_factor = -1\n \n # Divide out all the factors of 2 first\n while n % 2 == 0:\n largest_factor = 2\n n //= 2\n \n # Now n must be odd, thus we can check only odd factors starting from 3\n factor = 3\n while factor * factor <= n:\n while n % factor == 0:\n largest_factor = factor\n n //= factor\n factor += 2\n \n # If n is still greater than 2, then n itself must be a prime number\n if n > 2:\n largest_factor = n\n \n return largest_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n # Start with the smallest prime factor\n factor = 2\n # Loop over possible factors\n while factor * factor <= n:\n # Check if factor is a divisor of n\n if n % factor == 0:\n # Divide n by factor to reduce the problem size\n n //= factor\n else:\n # Move to the next possible factor\n factor += 1\n # When the loop ends, n is the largest prime factor\n return n", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n def is_prime(k: int) -> bool:\n \"\"\"Check if a number k is prime.\"\"\"\n if k <= 1:\n return False\n if k <= 3:\n return True\n if k % 2 == 0 or k % 3 == 0:\n return False\n i = 5\n while i * i <= k:\n if k % i == 0 or k % (i + 2) == 0:\n return False\n i += 6\n return True\n\n # Start with the smallest prime number\n factor = 2\n while factor * factor <= n:\n if n % factor == 0:\n n //= factor\n else:\n factor += 1 if factor == 2 else 2 # After 2, consider only odd numbers\n\n # After exiting the loop, n should be the largest prime factor\n return n", "matching_cluster_idx": 8}]}, "HumanEval/64": {"dps": 67.33766233766234, "dps_norm": 53.75, "pass@1": 100.0, "profiled": [{"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n # Define the set of vowels\n vowels = {'a', 'e', 'i', 'o', 'u'}\n\n # Convert the string to lowercase for case insensitive comparison\n s = s.lower()\n\n # Start counting vowels\n count = 0\n \n for i, char in enumerate(s):\n # Check if the character is a vowel\n if char in vowels:\n count += 1\n # Check if 'y' is at the end\n elif char == 'y' and i == len(s) - 1:\n count += 1\n\n return count", "matching_cluster_idx": 3}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n s = s.lower()\n count = 0\n vowels = set(\"aeiou\")\n \n for i, char in enumerate(s):\n if char in vowels:\n count += 1\n if char == 'y' and i == len(s) - 1: # 'y' at the end\n count += 1\n \n return count", "matching_cluster_idx": 2}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n s = s.lower() # Convert the string to lowercase to handle case-insensitivity\n vowels = set(\"aeiou\") # Set of standard vowels\n count = 0\n\n for index, char in enumerate(s):\n if char in vowels:\n count += 1\n # Check if 'y' is at the end of the string\n if char == 'y' and index == len(s) - 1:\n count += 1\n\n return count", "matching_cluster_idx": 2}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n # Define the vowels\n vowels = set(\"aeiouAEIOU\")\n \n # Count the number of vowels in the string\n count = sum(1 for char in s if char in vowels)\n \n # Check if 'y' is a vowel in this context (at the end of the word)\n if s and (s[-1] == 'y' or s[-1] == 'Y'):\n count += 1\n\n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n # Convert the input string to lowercase to handle case insensitivity\n s = s.lower()\n \n # List of vowels including 'y' as a special case at the end\n vowels = set('aeiou')\n \n # Count vowels\n count = sum(1 for char in s if char in vowels)\n \n # Check if 'y' is at the end of the string and count it as a vowel if so\n if s.endswith('y'):\n count += 1\n\n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n s = s.lower() # Convert the string to lowercase\n vowels = 'aeiou'\n count = sum(1 for char in s if char in vowels)\n \n # Check if the last character is 'y' and count it as a vowel if it is\n if s.endswith('y'):\n count += 1\n\n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n s = s.lower() # Convert the string to lowercase for easy comparison\n vowels = set(\"aeiou\") # Set of vowels\n count = 0\n\n for i, char in enumerate(s):\n if char in vowels:\n count += 1\n elif char == 'y' and i == len(s) - 1: # Check if 'y' is at the end\n count += 1\n\n return count", "matching_cluster_idx": 3}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = 'aeiou'\n count = 0\n for char in s.lower():\n if char in vowels:\n count += 1\n \n if s and s[-1].lower() == 'y': # Check if 'y' is at the end\n count += 1\n \n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = {'a', 'e', 'i', 'o', 'u'}\n s = s.lower()\n count = 0\n\n for i, char in enumerate(s):\n if char in vowels:\n count += 1\n if char == 'y' and i == len(s) - 1:\n count += 1\n \n return count", "matching_cluster_idx": 2}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n # Define the vowels\n vowels = set('aeiou')\n # Convert the string to lowercase to handle both upper and lower case letters\n s = s.lower()\n # Count vowels in the string\n count = sum(1 for char in s if char in vowels)\n # Check if the last character is 'y' and add to count\n if s.endswith('y'):\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n # Define vowels, considering both uppercase and lowercase letters\n vowels = set('aeiouAEIOU')\n count = 0\n \n # Iterate through each character in the string\n for i, char in enumerate(s):\n if char in vowels:\n count += 1\n elif char in 'yY' and i == len(s) - 1:\n # Count 'y' as a vowel only if it's the last character\n count += 1\n\n return count", "matching_cluster_idx": 3}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n # Convert the string to lowercase for uniform comparison\n s = s.lower()\n # Define the set of vowels\n vowels = {'a', 'e', 'i', 'o', 'u'}\n # Initialize the count of vowels\n count = 0\n\n # Iterate over the string to count vowels\n for i, char in enumerate(s):\n if char in vowels:\n count += 1\n # Special case for 'y' at the end\n if char == 'y' and i == len(s) - 1:\n count += 1\n\n return count", "matching_cluster_idx": 2}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n # Convert string to lowercase to make the function case-insensitive\n s = s.lower()\n # Initialize the count\n count = 0\n # List of vowels\n vowels = set('aeiou')\n # Iterate through the string\n for i, char in enumerate(s):\n # Check if char is a vowel or if 'y' is at the end of the word\n if char in vowels or (char == 'y' and i == len(s) - 1):\n count += 1\n return count", "matching_cluster_idx": 3}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n # Define the vowels we are considering\n vowels = \"aeiou\"\n # Convert the string to lowercase to handle case insensitivity\n s = s.lower()\n # Initialize count for vowels\n count = 0\n \n # Iterate through the string\n for i, char in enumerate(s):\n # Check if the character is a vowel\n if char in vowels:\n count += 1\n # Check if 'y' is at the end and consider it a vowel\n if char == 'y' and i == len(s) - 1:\n count += 1\n \n return count", "matching_cluster_idx": 2}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = set('aeiou')\n s = s.lower()\n \n count = sum(1 for char in s if char in vowels)\n if s.endswith('y'):\n count += 1\n \n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = 'aeiouAEIOU'\n count = sum(1 for char in s if char in vowels)\n if s.endswith('y') or s.endswith('Y'):\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n # Convert the string to lowercase to handle case insensitivity\n s = s.lower()\n # Define the vowels\n vowels = set(\"aeiou\")\n # Count the vowels in the string\n count = sum(1 for char in s if char in vowels)\n # Check if 'y' is a vowel (only at the end of the word)\n if s.endswith('y'):\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n s = s.lower() # Convert string to lowercase for uniformity\n count = 0\n vowels = \"aeiou\"\n for char in s:\n if char in vowels:\n count += 1\n if s.endswith('y'):\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = \"aeiouAEIOU\"\n count = 0\n \n # Count standard vowels\n for char in s:\n if char in vowels:\n count += 1\n \n # Check if 'y' is at the end\n if len(s) > 0 and s[-1].lower() == 'y':\n count += 1\n \n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = \"aeiouAEIOU\"\n count = 0\n for char in s[:-1]:\n if char in vowels:\n count += 1\n if s and s[-1] in vowels + \"yY\":\n count += 1\n return count", "matching_cluster_idx": 4}]}, "HumanEval/74": {"dps": 98.04878048780488, "dps_norm": 88.88888888888889, "pass@1": 94.0, "profiled": [{"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n '''\n # Calculate the total number of characters for each list\n total_chars_lst1 = sum(len(s) for s in lst1)\n total_chars_lst2 = sum(len(s) for s in lst2)\n \n # Compare the total characters and return the list with fewer characters\n if total_chars_lst1 < total_chars_lst2:\n return lst1\n elif total_chars_lst2 < total_chars_lst1:\n return lst2\n else:\n return lst1 # If they are equal, return the first list", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n\n # Calculate the total number of characters in each list\n total_chars_lst1 = sum(len(s) for s in lst1)\n total_chars_lst2 = sum(len(s) for s in lst2)\n\n # Compare the total characters and return the list with fewer characters\n if total_chars_lst1 < total_chars_lst2:\n return lst1\n elif total_chars_lst1 > total_chars_lst2:\n return lst2\n else:\n return lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n \n # Calculate the total number of characters in all strings of lst1\n total_chars_lst1 = sum(len(s) for s in lst1)\n \n # Calculate the total number of characters in all strings of lst2\n total_chars_lst2 = sum(len(s) for s in lst2)\n \n # Compare the totals and return the list with fewer characters\n if total_chars_lst1 < total_chars_lst2:\n return lst1\n elif total_chars_lst2 < total_chars_lst1:\n return lst2\n else:\n # If both lists have the same number of characters, return the first list\n return lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n If the two lists have the same number of chars, return the first list.\n '''\n \n # Calculate the total number of characters in each list\n total_chars_lst1 = sum(len(s) for s in lst1)\n total_chars_lst2 = sum(len(s) for s in lst2)\n\n # Compare total characters and return the appropriate list\n if total_chars_lst1 < total_chars_lst2:\n return lst1\n elif total_chars_lst2 < total_chars_lst1:\n return lst2\n else:\n # If both have the same number of chars, return the first list\n return lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n # Calculate the total number of characters in each list\n total_chars_lst1 = sum(len(s) for s in lst1)\n total_chars_lst2 = sum(len(s) for s in lst2)\n \n # Compare total characters of each list\n if total_chars_lst1 < total_chars_lst2:\n return lst1\n elif total_chars_lst2 < total_chars_lst1:\n return lst2\n else:\n return lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n \n # Calculate the total number of characters in each list\n char_count_lst1 = sum(len(s) for s in lst1)\n char_count_lst2 = sum(len(s) for s in lst2)\n \n # Compare the total character count and return the appropriate list\n if char_count_lst1 < char_count_lst2:\n return lst1\n elif char_count_lst2 < char_count_lst1:\n return lst2\n else:\n return lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n '''\n len1 = sum(len(s) for s in lst1)\n len2 = sum(len(s) for s in lst2)\n \n if len1 <= len2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n '''\n # Calculate the total number of characters in all strings of lst1\n total_chars_lst1 = sum(len(s) for s in lst1)\n \n # Calculate the total number of characters in all strings of lst2\n total_chars_lst2 = sum(len(s) for s in lst2)\n \n # Compare total characters in lst1 and lst2\n if total_chars_lst1 < total_chars_lst2:\n return lst1\n elif total_chars_lst1 > total_chars_lst2:\n return lst2\n else:\n return lst1 # If both are equal, return the first list", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n '''\n # Calculate the total number of characters in lst1\n total_chars_lst1 = sum(len(s) for s in lst1)\n \n # Calculate the total number of characters in lst2\n total_chars_lst2 = sum(len(s) for s in lst2)\n \n # Compare the total character counts and return the appropriate list\n if total_chars_lst1 < total_chars_lst2:\n return lst1\n elif total_chars_lst2 < total_chars_lst1:\n return lst2\n else:\n return lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n # Calculate the total number of characters for each list\n total_chars_lst1 = sum(len(s) for s in lst1)\n total_chars_lst2 = sum(len(s) for s in lst2)\n \n # Compare the total characters and return the appropriate list\n if total_chars_lst1 < total_chars_lst2:\n return lst1\n elif total_chars_lst1 > total_chars_lst2:\n return lst2\n else:\n return lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n '''\n total_chars_lst1 = sum(len(s) for s in lst1)\n total_chars_lst2 = sum(len(s) for s in lst2)\n \n if total_chars_lst1 < total_chars_lst2:\n return lst1\n elif total_chars_lst1 > total_chars_lst2:\n return lst2\n else:\n return lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n '''\n # Calculate the total number of characters in all strings of lst1\n total_chars_lst1 = sum(len(s) for s in lst1)\n # Calculate the total number of characters in all strings of lst2\n total_chars_lst2 = sum(len(s) for s in lst2)\n \n # Compare the total character counts\n if total_chars_lst1 < total_chars_lst2:\n return lst1\n elif total_chars_lst2 < total_chars_lst1:\n return lst2\n else:\n # If they are equal, return the first list\n return lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n # Calculate the total number of characters in each list\n total_chars_lst1 = sum(len(s) for s in lst1)\n total_chars_lst2 = sum(len(s) for s in lst2)\n\n # Compare the total number of characters\n if total_chars_lst1 < total_chars_lst2:\n return lst1\n elif total_chars_lst2 < total_chars_lst1:\n return lst2\n else:\n return lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n '''\n # Calculate the total number of characters in each list\n total_chars_lst1 = sum(len(s) for s in lst1)\n total_chars_lst2 = sum(len(s) for s in lst2)\n \n # Compare the total number of characters and return the appropriate list\n if total_chars_lst1 < total_chars_lst2:\n return lst1\n elif total_chars_lst2 < total_chars_lst1:\n return lst2\n else:\n return lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n # Calculate total number of characters in lst1\n total_chars_lst1 = sum(len(word) for word in lst1)\n \n # Calculate total number of characters in lst2\n total_chars_lst2 = sum(len(word) for word in lst2)\n \n # Determine which list has fewer characters or if they're equal\n if total_chars_lst1 < total_chars_lst2:\n return lst1\n elif total_chars_lst2 < total_chars_lst1:\n return lst2\n else:\n return lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n \n # Calculate the total number of characters in lst1\n total_chars_lst1 = sum(len(s) for s in lst1)\n \n # Calculate the total number of characters in lst2\n total_chars_lst2 = sum(len(s) for s in lst2)\n \n # Compare the totals and return the appropriate list\n if total_chars_lst1 < total_chars_lst2:\n return lst1\n elif total_chars_lst1 > total_chars_lst2:\n return lst2\n else:\n return lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n '''\n \n # Calculate the total number of characters in each list\n total_chars_lst1 = sum(len(word) for word in lst1)\n total_chars_lst2 = sum(len(word) for word in lst2)\n \n # Compare the total characters and return the appropriate list\n if total_chars_lst1 < total_chars_lst2:\n return lst1\n elif total_chars_lst2 < total_chars_lst1:\n return lst2\n else:\n # If they are equal, return the first list\n return lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n def total_chars(lst):\n return sum(len(word) for word in lst)\n\n chars_lst1 = total_chars(lst1)\n chars_lst2 = total_chars(lst2)\n\n if chars_lst1 < chars_lst2:\n return lst1\n elif chars_lst1 > chars_lst2:\n return lst2\n else:\n return lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in all strings of the list less than the other list.\n\n If the two lists have the same number of chars, return the first list.\n '''\n # Calculate the total number of characters in each list\n total_chars_lst1 = sum(len(s) for s in lst1)\n total_chars_lst2 = sum(len(s) for s in lst2)\n \n # Compare the total characters and return the appropriate list\n if total_chars_lst1 < total_chars_lst2:\n return lst1\n elif total_chars_lst1 > total_chars_lst2:\n return lst2\n else:\n return lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n '''\n\n # Calculate the total number of characters in each list\n total_chars_lst1 = sum(len(s) for s in lst1)\n total_chars_lst2 = sum(len(s) for s in lst2)\n\n # Compare the total number of characters and return the appropriate list\n if total_chars_lst1 < total_chars_lst2:\n return lst1\n elif total_chars_lst2 < total_chars_lst1:\n return lst2\n else:\n return lst1", "matching_cluster_idx": 7}]}, "HumanEval/85": {"dps": 95.02475247524752, "dps_norm": 64.16666666666667, "pass@1": 100.0, "profiled": [{"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Args:\n lst (list of int): A non-empty list of integers.\n\n Returns:\n int: The sum of even elements that are located at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2\n \"\"\"\n total = 0\n for index in range(1, len(lst), 2): # Only check odd indices (1, 3, 5, ...)\n if lst[index] % 2 == 0: # Check if the element at odd index is even\n total += lst[index]\n return total", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Args:\n lst (list): A non-empty list of integers.\n\n Returns:\n int: The sum of even elements that are located at odd indices.\n \n Examples:\n add([4, 2, 6, 7]) ==> 2\n add([1, 3, 5, 8, 10, 12]) ==> 20\n \"\"\"\n # Initialize the sum\n total = 0\n \n # Iterate over the list using index and value\n for i in range(1, len(lst), 2): # start from index 1 and increment by 2 (odd indices)\n if lst[i] % 2 == 0: # Check if the element is even\n total += lst[i] # Add it to the total\n \n return total", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Args:\n lst (list): A non-empty list of integers.\n\n Returns:\n int: The sum of the even elements that are at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n add([1, 3, 5, 8, 10, 12]) ==> 20\n add([0, 1, 2, 3, 4]) ==> 0\n \"\"\"\n return sum(lst[i] for i in range(1, len(lst), 2) if lst[i] % 2 == 0)", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Args:\n lst (list of int): A non-empty list of integers.\n\n Returns:\n int: The sum of even integers found at odd indices in the list.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2\n add([1, 2, 3, 4, 5, 6]) ==> 4\n add([2, 3, 4, 5, 6, 7, 8]) ==> 0\n \"\"\"\n return sum(lst[i] for i in range(1, len(lst), 2) if lst[i] % 2 == 0)", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Args:\n lst (list of int): The list of integers.\n\n Returns:\n int: The sum of the even elements that are at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n # Initialize the sum to 0\n even_sum = 0\n\n # Iterate over the list using index\n for i in range(1, len(lst), 2): # start from 1 and step by 2 to get odd indices\n if lst[i] % 2 == 0: # check if the element at the odd index is even\n even_sum += lst[i] # add it to the sum\n\n return even_sum", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst, add the even elements that are at odd indices.\n \n Parameters:\n lst (list of int): A list of integers.\n \n Returns:\n int: The sum of even integers located at odd indices in the list.\n \n Examples:\n >>> add([4, 2, 6, 7])\n 2\n >>> add([5, 8, 3, 10, 2])\n 18\n \"\"\"\n sum_even_odd_indices = 0\n for i in range(1, len(lst), 2): # Start from index 1, consider every other element (odd indices)\n if lst[i] % 2 == 0:\n sum_even_odd_indices += lst[i]\n return sum_even_odd_indices", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst, add the even elements that are at odd indices.\n \n Args:\n lst (list): A non-empty list of integers.\n \n Returns:\n int: The sum of even integers at odd indices.\n \n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n total = 0\n # Iterate over the list using indices\n for index in range(1, len(lst), 2):\n # Check if the element at an odd index is even\n if lst[index] % 2 == 0:\n total += lst[index]\n return total", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Args:\n lst (list of int): A list of integers.\n\n Returns:\n int: The sum of the even elements located at odd indices in the list.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2\n \"\"\"\n total = 0\n # Iterate through the list starting from index 1, taking every other element (i.e., odd indices)\n for i in range(1, len(lst), 2):\n if lst[i] % 2 == 0: # Check if the element is even\n total += lst[i]\n return total", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Args:\n lst (list): A non-empty list of integers.\n \n Returns:\n int: The sum of the even elements that are located at odd indices.\n \n Examples:\n add([4, 2, 6, 7]) ==> 2\n \"\"\"\n return sum(lst[i] for i in range(1, len(lst), 2) if lst[i] % 2 == 0)", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"\n Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Args:\n lst (list): A list of integers.\n\n Returns:\n int: The sum of even integers at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2\n \"\"\"\n # Initialize the sum to zero\n even_sum = 0\n\n # Iterate over the list, considering odd indices only\n for i in range(1, len(lst), 2): # Start at index 1, step by 2 for odd indices\n if lst[i] % 2 == 0: # Check if the element at the odd index is even\n even_sum += lst[i] # Add it to the sum if it's even\n\n return even_sum", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Args:\n lst (list of int): The list of integers.\n\n Returns:\n int: The sum of even elements at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2\n \"\"\"\n return sum(lst[i] for i in range(1, len(lst), 2) if lst[i] % 2 == 0)", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Args:\n lst (list): A list of integers.\n\n Returns:\n int: The sum of even integers located at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n return sum(lst[i] for i in range(1, len(lst), 2) if lst[i] % 2 == 0)", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst, add the even elements that are at odd indices.\n \n Args:\n lst (list): A non-empty list of integers.\n \n Returns:\n int: The sum of even elements that are at odd indices.\n \n Examples:\n add([4, 2, 6, 7]) ==> 2\n \"\"\"\n return sum(lst[i] for i in range(1, len(lst), 2) if lst[i] % 2 == 0)", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Args:\n lst (list): A list of integers.\n\n Returns:\n int: The sum of even numbers located at odd indices in the list.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2\n add([1, 3, 2, 6, 4, 5]) ==> 6\n add([7, 10, 12, 9, 2, 1]) ==> 10\n \"\"\"\n return sum(lst[i] for i in range(1, len(lst), 2) if lst[i] % 2 == 0)", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Args:\n lst (list): A non-empty list of integers.\n\n Returns:\n int: The sum of even integers that are at odd indices in the list.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n add([1, 2, 3, 4, 5, 6]) ==> 4\n add([2, 4, 6, 8]) ==> 8\n \"\"\"\n return sum(lst[i] for i in range(1, len(lst), 2) if lst[i] % 2 == 0)", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2\n \"\"\"\n # Initialize sum to 0\n even_sum = 0\n\n # Loop over indices and elements in the list\n for index in range(len(lst)):\n # Check if the index is odd\n if index % 2 != 0:\n # Check if the element at this index is even\n if lst[index] % 2 == 0:\n # Add the element to the sum\n even_sum += lst[index]\n\n return even_sum", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Args:\n lst (list): A non-empty list of integers.\n\n Returns:\n int: The sum of even elements located at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2\n \"\"\"\n return sum(lst[i] for i in range(1, len(lst), 2) if lst[i] % 2 == 0)", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n return sum(lst[i] for i in range(1, len(lst), 2) if lst[i] % 2 == 0)", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"\n Given a non-empty list of integers lst, add the even elements that are at odd indices.\n \n Args:\n lst (list of int): The list of integers.\n\n Returns:\n int: The sum of even elements at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n add([1, 3, 5, 8, 10, 12]) ==> 20\n \"\"\"\n return sum(lst[i] for i in range(1, len(lst), 2) if lst[i] % 2 == 0)", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n # Initialize a variable to store the sum of even elements at odd indices\n total = 0\n\n # Iterate over the list using enumerate to get both index and value\n for index, value in enumerate(lst):\n # Check if the index is odd and the value is even\n if index % 2 == 1 and value % 2 == 0:\n total += value\n\n # Return the computed sum\n return total", "matching_cluster_idx": 2}]}, "HumanEval/86": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 72.0, "profiled": [{"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n def sort_word(word):\n return ''.join(sorted(word))\n \n words = s.split(' ')\n sorted_words = [sort_word(word) for word in words]\n return ' '.join(sorted_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n words = s.split(' ')\n sorted_words = [''.join(sorted(word)) for word in words]\n return ' '.join(sorted_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n # Split the string on spaces to preserve spaces\n split_parts = s.split(' ')\n \n # Sort each word and join them back\n sorted_words = [''.join(sorted(word)) for word in split_parts]\n \n # Join back with single spaces to preserve the original space placement\n return ' '.join(sorted_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n def sort_word(word):\n # Sort characters of the word by their ASCII values\n return ''.join(sorted(word))\n\n # Split the input string into parts based on spaces\n words = s.split(' ')\n \n # Sort each word individually\n sorted_words = [sort_word(word) for word in words]\n \n # Join sorted words back together with spaces to keep the original structure\n return ' '.join(sorted_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n # Split the input string by spaces while preserving the spaces\n words = s.split(' ')\n # Sort each word while keeping empty spaces intact\n sorted_words = [''.join(sorted(word)) if word else '' for word in words]\n # Join the sorted words with spaces in between to reconstruct the sentence\n result = ' '.join(sorted_words)\n return result", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters are arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n \"\"\"\n\n def sort_word(word):\n # Sorts characters of a single word\n return ''.join(sorted(word))\n\n words = s.split(' ')\n sorted_words = [sort_word(word) for word in words]\n return ' '.join(sorted_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n # Split the input string into words using spaces as separators\n words = s.split(' ')\n \n # Sort the characters in each word and join them back\n sorted_words = [''.join(sorted(word)) for word in words]\n \n # Join the sorted words back with spaces to keep the original spaces\n result = ' '.join(sorted_words)\n \n return result", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Takes a string and returns an ordered version of it.\n Each word's characters are arranged in ascending order based on ASCII value.\n The order of words and spaces in the sentence is preserved.\n \"\"\"\n # Split the string into words using a space as a delimiter\n words = s.split(' ')\n \n # Sort each word's characters and join them back\n sorted_words = [''.join(sorted(word)) for word in words]\n \n # Join the sorted words back with a space to form the ordered sentence\n ordered_string = ' '.join(sorted_words)\n \n return ordered_string", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n # Split the input string by spaces, keeping empty strings for spaces\n words = s.split(' ')\n \n # Sort each word individually\n sorted_words = [''.join(sorted(word)) for word in words]\n \n # Join the sorted words back with spaces\n return ' '.join(sorted_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n \n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n # Split the string into parts wherever there is a space\n parts = s.split(' ')\n \n # Sort each part and join them back into a single string\n sorted_parts = [''.join(sorted(part)) for part in parts]\n \n # Join the sorted parts with a space to preserve the original structure\n result = ' '.join(sorted_parts)\n \n return result", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n \"\"\"\n # Split the string into words while preserving spaces\n # This splits but keeps the delimiter spaces\n words = s.split(' ')\n \n # Sort each word in the list of words and join them back together with spaces\n sorted_words = [''.join(sorted(word)) for word in words]\n \n # Join sorted words back with spaces in between\n result = ' '.join(sorted_words)\n \n return result", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n def sort_word(word):\n # Sorts characters of a word based on ascii values\n return ''.join(sorted(word))\n \n # Split the input string by spaces while keeping the spaces\n parts = s.split(' ')\n \n # Apply the sorting to each part\n sorted_parts = [sort_word(part) for part in parts]\n \n # Join the parts back together with spaces\n return ' '.join(sorted_parts)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n def sort_word(word):\n # Sort the characters in the word and join them back together\n return ''.join(sorted(word))\n\n # Split the string by spaces, sort each word, and join them back with spaces\n words = s.split(' ')\n sorted_words = [sort_word(word) for word in words]\n\n # Return the sorted words joined with spaces\n return ' '.join(sorted_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n words = s.split(' ')\n sorted_words = [''.join(sorted(word)) for word in words]\n return ' '.join(sorted_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n \"\"\"\n def sort_word(word):\n # Sort the characters in a word by ASCII value\n return ''.join(sorted(word))\n \n # Split the string by spaces while preserving the spaces in the result\n words = s.split(' ')\n \n # Sort each word and join them back with spaces\n sorted_words = [sort_word(word) for word in words]\n \n # Recreate the original sentence structure with spaces\n result = ' '.join(sorted_words)\n \n return result", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n words = s.split(' ')\n sorted_words = [''.join(sorted(word)) for word in words]\n return ' '.join(sorted_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n \n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n def sort_characters(word):\n return ''.join(sorted(word))\n \n words = s.split(' ')\n ordered_words = [sort_characters(word) for word in words]\n return ' '.join(ordered_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n # Split the input string by spaces to separate words and spaces\n words = s.split(' ')\n \n # Sort each word by its characters\n sorted_words = [''.join(sorted(word)) for word in words]\n \n # Join the sorted words back using spaces, preserving original spacing\n return ' '.join(sorted_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n # Split the input string into words including spaces\n words = s.split(' ')\n \n # Sort each word and rejoin with spaces\n sorted_words = [''.join(sorted(word)) for word in words]\n \n # Join the sorted words with single spaces\n result = ' '.join(sorted_words)\n \n return result", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n # Split the input string into words\n words = s.split(' ')\n\n # Process each word to sort its letters\n sorted_words = []\n for word in words:\n sorted_word = ''.join(sorted(word))\n sorted_words.append(sorted_word)\n\n # Join the sorted words back with spaces to form the result\n result = ' '.join(sorted_words)\n \n return result", "matching_cluster_idx": 4}]}, "HumanEval/87": {"dps": 93.94812680115274, "dps_norm": 57.142857142857146, "pass@1": 100.0, "profiled": [{"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n # Create a list to store the coordinates\n coordinates = []\n\n # Iterate through each row and column to find the value x\n for i, row in enumerate(lst):\n # Find all column indices where x is found in the current row\n cols_with_x = [j for j, val in enumerate(row) if val == x]\n \n # Append each found coordinate as a tuple (i, j) to the coordinates list\n for col in cols_with_x:\n coordinates.append((i, col))\n \n # Sort the coordinates: first by row in ascending order, then by column in descending order\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n \n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n coordinates = []\n\n # Iterate through each row and each column within the row\n for row_index, row in enumerate(lst):\n for col_index, value in enumerate(row):\n if value == x:\n coordinates.append((row_index, col_index))\n\n # Sort coordinates by row (ascend) and column (descend within each row)\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n\n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n result = []\n \n for row_idx, row in enumerate(lst):\n # Find all column indices where x is present\n columns = [col_idx for col_idx, value in enumerate(row) if value == x]\n # Sort columns in descending order and store them with the row index\n result.extend((row_idx, col_idx) for col_idx in sorted(columns, reverse=True))\n \n # The list is already sorted by rows since we're iterating in order\n return result", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n # List to store the coordinates\n coordinates = []\n \n # Iterate through each row and column\n for row_index, row in enumerate(lst):\n for col_index, value in enumerate(row):\n if value == x:\n # If value matches x, add the coordinate to the list\n coordinates.append((row_index, col_index))\n \n # Sort the coordinates by row in ascending order,\n # and by column in descending order for the same row\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n \n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n \n coordinates = []\n \n for i, row in enumerate(lst):\n row_coords = [(i, j) for j, val in enumerate(row) if val == x]\n # Sort the row coordinates by column in descending order\n row_coords.sort(key=lambda coord: coord[1], reverse=True)\n coordinates.extend(row_coords)\n \n # The coordinates list is already sorted by row (as we processed rows in order)\n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n # Initialize a list to store the results\n result = []\n \n # Iterate over each row with its index\n for row_index, row in enumerate(lst):\n # List to store found positions in the current row\n current_row_results = []\n \n # Iterate over each column with its index\n for col_index, value in enumerate(row):\n if value == x:\n # Append the position to the list for the current row\n current_row_results.append((row_index, col_index))\n \n # Sort the current row results in descending order of columns\n current_row_results.sort(key=lambda coord: coord[1], reverse=True)\n \n # Extend the result list with the sorted current row results\n result.extend(current_row_results)\n \n return result", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n coordinates = []\n\n # Iterate through each row in the 2D list\n for row_index, row in enumerate(lst):\n # For each row, find all columns where x is present\n row_coordinates = [(row_index, col_index) for col_index, value in enumerate(row) if value == x]\n\n # Sort the row coordinates by columns in descending order\n row_coordinates.sort(key=lambda coord: coord[1], reverse=True)\n\n # Add the sorted row coordinates to the main list\n coordinates.extend(row_coordinates)\n\n # By construction, row_indices are in ascending order because we process rows one by one\n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2-dimensional data, as nested lists,\n which is similar to a matrix. However, unlike matrices,\n each row may contain a different number of columns.\n Given lst and an integer x, find all occurrences of x in the list,\n and return a list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, column), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n \n get_row([], 1) == []\n \n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n result = []\n \n for row_index, row in enumerate(lst):\n for col_index, value in enumerate(row):\n if value == x:\n result.append((row_index, col_index))\n \n # Sort by row (ascending) then column (descending)\n result.sort(key=lambda coord: (coord[0], -coord[1]))\n \n return result", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2-dimensional data, as nested lists, \n similar to a matrix. Unlike matrices, each row may contain\n a different number of columns. Given lst, and an integer x,\n find integers x in the list, and return a list of tuples,\n [(x1, y1), (x2, y2), ...] such that each tuple is a coordinate\n - (row, columns), starting with 0. Sort coordinates initially\n by rows in ascending order. Also, sort coordinates of the row\n by columns in descending order.\n \n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n \n # Initialize the result list\n result = []\n\n # Iterate through the rows with index\n for row_index, row in enumerate(lst):\n # Find all columns in the current row that contain the number x\n column_indices = [col_index for col_index, value in enumerate(row) if value == x]\n \n # If we found any such column indices, sort them in descending order\n column_indices.sort(reverse=True)\n \n # Add each pair of (row_index, col_index) to the result list\n for col_index in column_indices:\n result.append((row_index, col_index))\n\n # Since we are processing rows in order, the list is sorted by row_index already,\n # and by column_index in descending order within each row\n return result", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2-dimensional data, as a nested lists,\n which is similar to a matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n coordinates = []\n\n # Traverse the 2D list to find all occurrences of x\n for row_index, row in enumerate(lst):\n row_coords = [(row_index, col_index) for col_index, value in enumerate(row) if value == x]\n \n # Sort coordinates in the current row by columns in descending order\n row_coords.sort(key=lambda coord: coord[1], reverse=True)\n \n # Extend the main list of coordinates\n coordinates.extend(row_coords)\n\n # The coordinates are already sorted by row due to the order of iteration\n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n # Initialize an empty list to store the coordinates\n coordinates = []\n \n # Loop through each row and each element to find the occurrences of x\n for row_index, row in enumerate(lst):\n for col_index, value in enumerate(row):\n if value == x:\n coordinates.append((row_index, col_index))\n \n # Sort the coordinates by rows in ascending order\n # If two or more elements are in the same row, sort them by columns in descending order\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n \n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n result = []\n for row_index, row in enumerate(lst):\n # Find all occurrences of `x` in the current row and add them to the result\n result.extend((row_index, col_index) for col_index, value in enumerate(row) if value == x)\n \n # Sort the results: first by row index, then by column index in descending order\n result.sort(key=lambda coord: (coord[0], -coord[1]))\n return result", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n\n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n # Find the coordinates of x in the nested list\n coordinates = []\n for row_index, row in enumerate(lst):\n for col_index, value in enumerate(row):\n if value == x:\n coordinates.append((row_index, col_index))\n \n # Sort the coordinates first by row ascending, then by column descending\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n \n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Examples:\n get_row([\n [1, 2, 3, 4, 5, 6],\n [1, 2, 3, 4, 1, 6],\n [1, 2, 3, 4, 5, 1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n \n coordinates = []\n \n # Traverse through each row and column to find x\n for row_index, row in enumerate(lst):\n for col_index in range(len(row)):\n if row[col_index] == x:\n coordinates.append((row_index, col_index))\n \n # Sort the coordinates as required\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n \n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2-dimensional data, as nested lists,\n which is similar to a matrix; however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find occurrences of x in the list,\n and return a list of tuples, [(x1, y1), (x2, y2), ...] such that\n each tuple is a coordinate - (row, column), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n # Initialize a list to hold the coordinates\n coordinates = []\n \n # Iterate through the list to collect coordinates\n for row_index, row in enumerate(lst):\n for col_index, value in enumerate(row):\n if value == x:\n coordinates.append((row_index, col_index))\n \n # Sort the coordinates by row first (ascending) and column second (descending)\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n \n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n result = []\n \n # Iterate over each row\n for i, row in enumerate(lst):\n # Find all occurrences of x in the current row\n row_indices = [(i, j) for j, value in enumerate(row) if value == x]\n # Sort indices in the current row by column in descending order\n row_indices.sort(key=lambda coord: -coord[1])\n # Add to the result\n result.extend(row_indices)\n \n # Return the result already sorted by row, then by column descending\n return result", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n coordinates = []\n\n # Iterate over each row and collect coordinates\n for i, row in enumerate(lst):\n for j, val in enumerate(row):\n if val == x:\n coordinates.append((i, j))\n\n # Sort coordinates by row, then by column descending\n coordinates.sort(key=lambda c: (c[0], -c[1]))\n\n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as nested lists,\n which is similar to a matrix. Each row may contain a different\n number of columns. Given lst and integer x, find integer x in the list,\n and return list of tuples, [(x1, y1), (x2, y2), ...] such that\n each tuple is a coordinate - (row, column), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n \n coordinates = []\n \n for row_idx, row in enumerate(lst):\n # Find all column indices where the value is x\n row_coordinates = [(row_idx, col_idx) for col_idx, value in enumerate(row) if value == x]\n \n # Sort the found coordinates of this row by column indices in descending order\n row_coordinates.sort(key=lambda coord: coord[1], reverse=True)\n \n # Add to the main coordinates list\n coordinates.extend(row_coordinates)\n \n # Coordinates are already grouped by row, and within each row sorted by column desc\n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as nested lists,\n which is similar to a matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return a list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \"\"\"\n coordinates = []\n\n # Iterate through each row with its index\n for row_idx, row in enumerate(lst):\n # Collect all columns where element x is found in the current row\n row_coords = [(row_idx, col_idx) for col_idx, value in enumerate(row) if value == x]\n # Sort coordinates of the row by columns in descending order\n row_coords.sort(key=lambda coord: coord[1], reverse=True)\n # Extend the main list of coordinates\n coordinates.extend(row_coords)\n \n # Coordinates are inherently sorted by rows since we are processing rows in order\n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n\n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n result = []\n for row_idx, row in enumerate(lst):\n for col_idx, value in enumerate(row):\n if value == x:\n result.append((row_idx, col_idx))\n \n # First sort by row index in ascending order, then by column index in descending order\n result.sort(key=lambda coord: (coord[0], -coord[1]))\n \n return result", "matching_cluster_idx": 3}]}, "HumanEval/89": {"dps": 96.64948453608248, "dps_norm": 28.571428571428573, "pass@1": 81.0, "profiled": [{"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n # Define the shift value\n shift = 2 * 2\n \n # A helper function to rotate a single character\n def rotate_char(c):\n if 'a' <= c <= 'z': # Check if the character is a lowercase letter\n new_char = chr(((ord(c) - ord('a') + shift) % 26) + ord('a'))\n return new_char\n return c # Non-alphabetic characters remain unchanged\n\n # Apply the rotation to each character in the string\n encrypted_string = ''.join(rotate_char(c) for c in s)\n return encrypted_string", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n \"\"\"\n shift = 4 # 2 * 2 = 4\n result = []\n \n for char in s:\n if char.isalpha(): # check if character is a letter\n start = ord('a') if char.islower() else ord('A')\n # shift the character by the calculated shift and wrap around with modulo\n new_char = chr(start + (ord(char) - start + shift) % 26)\n result.append(new_char)\n else:\n result.append(char) # if not a letter, do not change it\n\n return ''.join(result)", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n result = []\n for char in s:\n if 'a' <= char <= 'z':\n # Rotate alphabet by 4 places\n new_char = chr((ord(char) - ord('a') + 4) % 26 + ord('a'))\n result.append(new_char)\n else:\n # Append any non-lowercase letter as is\n result.append(char)\n return ''.join(result)", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n result = []\n for char in s:\n if 'a' <= char <= 'z':\n # Calculate new character, wrap around using modulo 26 if necessary\n new_char = chr((ord(char) - ord('a') + 4) % 26 + ord('a'))\n result.append(new_char)\n else:\n result.append(char) # Non-alphabet characters are not changed\n return ''.join(result)", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated.\n The alphabet should be rotated in a manner such that the letters\n shift down by two multiplied by two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n result = []\n shift = 4 # Rotate by 2 * 2 positions\n\n for char in s:\n if 'a' <= char <= 'z':\n # Rotate within lowercase letters\n new_char = chr((ord(char) - ord('a') + shift) % 26 + ord('a'))\n result.append(new_char)\n elif 'A' <= char <= 'Z':\n # Rotate within uppercase letters\n new_char = chr((ord(char) - ord('A') + shift) % 26 + ord('A'))\n result.append(new_char)\n else:\n # Non-alphabetic characters remain unchanged\n result.append(char)\n\n return ''.join(result)", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Encrypts the input string by rotating each letter in the alphabet by 4 positions.\"\"\"\n def rotate_char(c):\n # Only encrypt lowercase letters\n if 'a' <= c <= 'z':\n # Calculate new character and ensure it wraps around after 'z'\n return chr((ord(c) - ord('a') + 4) % 26 + ord('a'))\n else:\n # Non-lowercase letters are returned unchanged\n return c\n \n # Apply the rotation to each character in the input string\n return ''.join(rotate_char(c) for c in s)", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n result = []\n shift = 4 # two multiplied to two gives the shift of 4\n\n for char in s:\n # Check if the character is a lowercase letter\n if 'a' <= char <= 'z':\n # Rotate the character and maintain within the lowercase alphabet\n new_char = chr(((ord(char) - ord('a') + shift) % 26) + ord('a'))\n result.append(new_char)\n else:\n # If the character is not a lowercase letter, append it as is\n result.append(char)\n\n return ''.join(result)", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n \"\"\"\n def shift_char(c):\n # Calculate the new character, rotating by 4 positions down the alphabet\n if 'a' <= c <= 'z':\n # Calculate new position with wrap-around using modulo operation\n return chr(((ord(c) - ord('a') + 4) % 26) + ord('a'))\n else:\n return c # Non-lowercase alphabet characters are returned unchanged\n \n # Apply shift to each character and join them back into a string\n return ''.join(shift_char(c) for c in s)", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n shift = 2 * 2 # Calculate the shift as two multiplied by two\n encrypted_message = []\n \n for char in s:\n if 'a' <= char <= 'z': # Check if the character is a lowercase letter\n # Calculate the new position with wrapping around using modulo\n new_pos = (ord(char) - ord('a') + shift) % 26 + ord('a')\n encrypted_message.append(chr(new_pos))\n else:\n # If the character is not a lowercase letter, append it as is\n encrypted_message.append(char)\n \n return ''.join(encrypted_message)", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n shift = 4 # 2 multiplied by 2\n encrypted_message = []\n\n for char in s:\n if 'a' <= char <= 'z': # ensure character is lowercase alphabetic\n # Calculate new character with rotation\n new_char = chr((ord(char) - ord('a') + shift) % 26 + ord('a'))\n encrypted_message.append(new_char)\n else:\n encrypted_message.append(char)\n\n return ''.join(encrypted_message)", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n # Define the shift amount (2 * 2 = 4)\n shift = 4\n # Start with an empty encrypted message\n encrypted_message = []\n\n # Iterate over each character in the string\n for char in s:\n # Calculate the new character, wrapping around if necessary\n # Only shift lowercase letters a-z\n if 'a' <= char <= 'z':\n new_char = chr((ord(char) - ord('a') + shift) % 26 + ord('a'))\n encrypted_message.append(new_char)\n else:\n # Leave characters that aren't lowercase letters unchanged\n encrypted_message.append(char)\n\n # Join the list into a single string and return it\n return ''.join(encrypted_message)", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n result = []\n for char in s:\n if 'a' <= char <= 'z': # Only consider lowercase letters\n # Calculate the shifted character\n shifted_char = chr((ord(char) - ord('a') + 4) % 26 + ord('a'))\n result.append(shifted_char)\n else:\n result.append(char) # Non-letter characters are unchanged\n return ''.join(result)", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n # Define the shift amount\n shift_amount = 2 * 2 # This is 4 according to the problem statement.\n\n # Define the encryption function\n def shift_char(c):\n # Check if the character is a lowercase letter\n if 'a' <= c <= 'z':\n # Calculate new character with wrapping around using modulo\n new_c = chr((ord(c) - ord('a') + shift_amount) % 26 + ord('a'))\n return new_c\n else:\n # If not a lowercase letter, return the character unchanged\n return c\n\n # Encrypt the entire string by shifting each character\n encrypted_string = ''.join(shift_char(c) for c in s)\n return encrypted_string", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Encrypts the input string by rotating each letter down by four places in the alphabet.\"\"\"\n result = []\n \n for char in s:\n if 'a' <= char <= 'z': # Only consider lowercase letters\n # Calculate the new character by shifting down by 4 positions\n new_char = chr((ord(char) - ord('a') + 4) % 26 + ord('a'))\n result.append(new_char)\n else:\n # If it's not a lowercase letter, append it unchanged\n result.append(char)\n \n return ''.join(result)", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied by two places.\n \"\"\"\n shift = 2 * 2 # Calculate the shift amount (2 multiplied by 2)\n encrypted = []\n \n for char in s:\n if char.isalpha(): # Check if the character is a letter\n # Calculate the new position with wrap around\n new_pos = (ord(char) - ord('a') + shift) % 26 + ord('a')\n encrypted.append(chr(new_pos))\n else:\n # For non-alphabetic characters, just append them as they are\n encrypted.append(char)\n \n return ''.join(encrypted)", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n shift = 4 # 2 multiplied by 2\n result = []\n\n for char in s:\n if 'a' <= char <= 'z': # Check if character is a lowercase letter\n new_char = chr(((ord(char) - ord('a') + shift) % 26) + ord('a'))\n result.append(new_char)\n else:\n result.append(char) # Non-alphabet characters are unchanged\n\n return ''.join(result)", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied by two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n encrypted = []\n shift = 2 * 2 # Two multiplied by two gives a shift of 4\n \n for char in s:\n if 'a' <= char <= 'z':\n # Calculate the new character by shifting 4 positions forward\n # and using modulo 26 to wrap around the alphabet\n new_char = chr(((ord(char) - ord('a') + shift) % 26) + ord('a'))\n encrypted.append(new_char)\n else:\n # If the character is not a lowercase letter, keep it unchanged\n encrypted.append(char)\n \n return ''.join(encrypted)", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"\n Encrypts a given string by shifting each letter in the alphabet \n down by four places (2 multiplied by 2). Wraps around for 'z' to 'd'.\n\n Parameters:\n s (str): The input string to be encrypted.\n\n Returns:\n str: The encrypted string with each character shifted.\n \"\"\"\n def shift_char(c):\n # Check if the character is a lowercase letter\n if 'a' <= c <= 'z':\n # Find the new character by shifting 4 places\n new_char = chr((ord(c) - ord('a') + 4) % 26 + ord('a'))\n return new_char\n else:\n # Return the character unchanged if it's not a lowercase letter\n return c\n \n # Encrypt the string by shifting each character\n return ''.join(shift_char(c) for c in s)", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n result = []\n for char in s:\n if 'a' <= char <= 'z':\n # Calculate the new character position with a 4 letter shift\n new_char = chr(((ord(char) - ord('a') + 4) % 26) + ord('a'))\n result.append(new_char)\n else:\n # Keep non-lowercase alphabetic characters as is\n result.append(char)\n return ''.join(result)", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Encrypt the string by rotating each letter two positions forward \n twice in the alphabet.\"\"\"\n encrypted_message = []\n for char in s:\n if char.isalpha(): # Ensure character is a letter\n # Find the original position of the character a=0, b=1, ..., z=25\n original_position = ord(char) - ord('a')\n # Calculate the new position after rotating by 2 * 2 = 4\n new_position = (original_position + 4) % 26\n # Find the new character and append to the result\n new_char = chr(ord('a') + new_position)\n encrypted_message.append(new_char)\n else:\n # If the character is not a letter, keep it as it is (although per problem all input are lowercase letters)\n encrypted_message.append(char)\n return ''.join(encrypted_message)", "matching_cluster_idx": 1}]}, "HumanEval/90": {"dps": 87.54863813229572, "dps_norm": 58.333333333333336, "pass@1": 100.0, "profiled": [{"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n # Use a set to filter out duplicate elements\n unique_elements = set(lst)\n \n # If we don't have at least two unique elements, return None\n if len(unique_elements) < 2:\n return None\n \n # Convert the set back to a sorted list\n sorted_elements = sorted(unique_elements)\n \n # Return the second smallest element\n return sorted_elements[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n # Convert the list to a set to remove duplicates\n unique_elements = set(lst)\n \n # If there are fewer than 2 unique elements, return None\n if len(unique_elements) < 2:\n return None\n \n # Convert back to a sorted list\n sorted_unique_elements = sorted(unique_elements)\n \n # Return the second element\n return sorted_unique_elements[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n # Convert the list to a set to remove duplicates, then back to a sorted list\n unique_sorted_lst = sorted(set(lst))\n \n # Check if there are at least two distinct elements\n if len(unique_sorted_lst) < 2:\n return None\n \n # Return the second smallest element\n return unique_sorted_lst[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n \n # Convert list to a set to remove duplicates, then back to a sorted list\n unique_sorted_lst = sorted(set(lst))\n \n # If there are less than 2 unique elements, return None\n if len(unique_sorted_lst) < 2:\n return None\n \n # Otherwise, return the second smallest element\n return unique_sorted_lst[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n\n # Remove duplicates by converting the list to a set\n unique_numbers = set(lst)\n\n # If there are less than 2 unique numbers, return None\n if len(unique_numbers) < 2:\n return None\n\n # Sort the unique numbers and return the second one\n sorted_unique_numbers = sorted(unique_numbers)\n return sorted_unique_numbers[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n # Convert the list to a set to remove duplicates\n unique_values = set(lst)\n \n # If we have less than 2 unique elements, return None\n if len(unique_values) < 2:\n return None\n \n # Sort the unique elements and return the second one\n sorted_unique_values = sorted(unique_values)\n return sorted_unique_values[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n # Convert list to a set to remove duplicates, then convert it back to a sorted list\n unique_sorted_list = sorted(set(lst))\n \n # Check if there are at least 2 distinct elements\n if len(unique_sorted_list) < 2:\n return None\n \n # Return the second smallest element\n return unique_sorted_list[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n \n # Convert the list to a set to remove duplicates and then back to a sorted list\n unique_sorted_lst = sorted(set(lst))\n \n if len(unique_sorted_lst) < 2:\n return None\n \n return unique_sorted_lst[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n\n # Use a set to get unique elements and then convert back to a sorted list\n unique_sorted_lst = sorted(set(lst))\n \n # Check if there are at least two unique elements\n if len(unique_sorted_lst) < 2:\n return None\n \n # Return the second smallest element\n return unique_sorted_lst[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n # Convert the list to a set to remove duplicates\n unique_elements = set(lst)\n \n # If there are less than 2 unique elements, return None\n if len(unique_elements) < 2:\n return None\n \n # Convert the set back to a sorted list\n sorted_unique_elements = sorted(unique_elements)\n \n # Return the second smallest element\n return sorted_unique_elements[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n # Convert the list to a set to remove duplicates, then sort the set\n unique_sorted = sorted(set(lst))\n \n # Check if there are at least two unique elements\n if len(unique_sorted) >= 2:\n # Return the second smallest element\n return unique_sorted[1]\n else:\n # Otherwise, return None\n return None", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n # Remove duplicates by converting the list to a set\n unique_elements = set(lst)\n \n # If there are less than 2 unique elements, return None\n if len(unique_elements) < 2:\n return None\n \n # Convert the set back to a sorted list\n sorted_unique_elements = sorted(unique_elements)\n \n # Return the second smallest element\n return sorted_unique_elements[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n\n unique_sorted = sorted(set(lst))\n \n if len(unique_sorted) < 2:\n return None\n \n return unique_sorted[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n # Convert the list to a set to remove duplicates\n unique_elements = set(lst)\n \n # If there are less than 2 unique elements, return None\n if len(unique_elements) < 2:\n return None\n \n # Sort the unique elements\n sorted_elements = sorted(unique_elements)\n \n # Return the second smallest element\n return sorted_elements[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n # Convert the list to a set to remove duplicates and then back to a sorted list\n unique_sorted_list = sorted(set(lst))\n \n # If there are less than 2 unique elements, return None\n if len(unique_sorted_list) < 2:\n return None\n \n # Otherwise, return the second smallest element\n return unique_sorted_list[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n # Convert the list to a set to remove duplicates, then convert it back to a sorted list\n unique_sorted_list = sorted(set(lst))\n \n # Check if there are at least 2 unique elements\n if len(unique_sorted_list) < 2:\n return None\n \n # Return the second smallest element\n return unique_sorted_list[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n # Convert the list to a set to remove duplicates, then back to a sorted list\n unique_sorted = sorted(set(lst))\n \n # Check if there are at least two unique elements\n if len(unique_sorted) < 2:\n return None\n \n # Return the second smallest element\n return unique_sorted[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n\n # Use a set to find unique elements, then sort\n unique_elements = sorted(set(lst))\n\n # If there are less than 2 unique elements, return None\n if len(unique_elements) < 2:\n return None\n\n # Return the second smallest element\n return unique_elements[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n # Convert the list to a set to remove duplicates\n unique_elements = set(lst)\n \n # If there are less than 2 unique elements, return None\n if len(unique_elements) < 2:\n return None\n \n # Convert the set back to a sorted list\n sorted_unique_elements = sorted(unique_elements)\n \n # Return the second smallest element\n return sorted_unique_elements[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n # Convert the list to a set to get unique elements\n unique_elements = set(lst)\n \n # Check if there are at least 2 unique elements\n if len(unique_elements) < 2:\n return None\n \n # Convert the set back to a sorted list\n sorted_unique_elements = sorted(unique_elements)\n \n # Return the second smallest element\n return sorted_unique_elements[1]", "matching_cluster_idx": 6}]}, "HumanEval/113": {"dps": 99.59432048681542, "dps_norm": 79.16666666666666, "pass@1": 100.0, "profiled": [{"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n \"\"\"\n \n def count_odd_digits(s):\n \"\"\"Helper function to count odd digits in a string.\"\"\"\n return sum(1 for ch in s if ch in '13579')\n \n result = []\n for s in lst:\n odd_count = count_odd_digits(s)\n result.append(f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\")\n \n return result", "matching_cluster_idx": 4}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n results = []\n for s in lst:\n # Count the number of odd digits in the string s\n odd_count = sum(1 for ch in s if ch in '13579')\n # Construct the result string with odd_count replacing 'i'\n result_str = (\n f\"the number of odd elements {odd_count}n the str{odd_count}ng \"\n f\"{odd_count} of the {odd_count}nput.\"\n )\n results.append(result_str)\n return results", "matching_cluster_idx": 4}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n \"\"\"\n \n def count_odd_digits(s):\n \"\"\"Helper function to count odd digits in a string.\"\"\"\n return sum(1 for char in s if char in '13579')\n\n result = []\n \n for s in lst:\n odd_count = count_odd_digits(s)\n # Create the formatted string with odd_count\n result_str = (\n f\"the number of odd elements {odd_count}n the str{odd_count}ng \"\n f\"{odd_count} of the {odd_count}nput.\"\n )\n result.append(result_str)\n \n return result", "matching_cluster_idx": 4}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n \"\"\"\n result = []\n for s in lst:\n # Count the number of odd digits in the current string\n odd_count = sum(1 for char in s if char in '13579')\n \n # Create the output string\n output_string = (\n f\"the number of odd elements {odd_count}n the str{odd_count}ng \"\n f\"{odd_count} of the {odd_count}nput.\"\n )\n \n # Append the generated string to the result list\n result.append(output_string)\n \n return result", "matching_cluster_idx": 4}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n results = []\n for s in lst:\n odd_count = sum(1 for char in s if char in '13579')\n # Prepare the output string replacing i's with the odd_count\n output = (\n f\"the number of odd elements {odd_count}n \"\n f\"the str{odd_count}ng {odd_count} of the {odd_count}nput.\"\n )\n results.append(output)\n return results", "matching_cluster_idx": 4}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n \"\"\"\n results = []\n for s in lst:\n # Count the odd digits in the string\n odd_count = sum(1 for char in s if char in '13579')\n # Construct the output string\n result = f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\"\n results.append(result)\n return results", "matching_cluster_idx": 4}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n \n def count_odds(s):\n return sum(1 for char in s if char in '13579')\n\n result = []\n for s in lst:\n odd_count = count_odds(s)\n result.append(f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\")\n \n return result", "matching_cluster_idx": 4}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n \"\"\"\n def count_odds(s):\n \"\"\"Helper function to count odd digits in a string.\"\"\"\n return sum(1 for char in s if char in '13579')\n\n result = []\n for s in lst:\n odd_count = count_odds(s)\n result.append(f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\")\n \n return result", "matching_cluster_idx": 4}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3', \"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n def count_odds(s):\n # Count odd digits in string s\n return sum(1 for char in s if char in '13579')\n \n result = []\n for s in lst:\n num_odds = count_odds(s)\n # Construct the output string based on the number of odd digits\n output = (\n f\"the number of odd elements {num_odds}n the str{num_odds}ng \"\n f\"{num_odds} of the {num_odds}nput.\"\n )\n result.append(output)\n \n return result", "matching_cluster_idx": 4}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n def count_odds(s):\n return sum(1 for char in s if int(char) % 2 != 0)\n \n result = []\n \n for s in lst:\n count = count_odds(s)\n result.append(f\"the number of odd elements {count}n the str{count}ng {count} of the {count}nput.\")\n \n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3', \"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n result = []\n for s in lst:\n # Count odd digits in the current string\n odd_digits_count = sum(1 for char in s if char in '13579')\n \n # Construct the formatted string replacing 'i' with odd_digits_count\n formatted_string = f\"the number of odd elements {odd_digits_count}n the str{odd_digits_count}ng {odd_digits_count} of the {odd_digits_count}nput.\"\n \n # Append to the result list\n result.append(formatted_string)\n \n return result", "matching_cluster_idx": 4}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n def count_odd_digits(s):\n \"\"\"Helper function to count odd digits in a string.\"\"\"\n return sum(1 for char in s if char in '13579')\n\n result = []\n for s in lst:\n odd_count = count_odd_digits(s)\n output = f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\"\n result.append(output)\n \n return result", "matching_cluster_idx": 4}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n results = []\n\n for s in lst:\n # Count the number of odd digits in the current string\n odd_count = sum(1 for char in s if char in '13579')\n\n # Create the formatted result string with the counted odd number\n result = (\n f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} \"\n f\"of the {odd_count}nput.\"\n )\n\n # Append the result to the results list\n results.append(result)\n\n return results", "matching_cluster_idx": 4}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3', \"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n result = []\n \n for s in lst:\n # Count the number of odd digits in the current string\n odd_count = sum(1 for char in s if int(char) % 2 != 0)\n \n # Format the output string\n formatted_string = (\n \"the number of odd elements {0}n the str{0}ng {0} of the {0}nput.\".format(odd_count)\n )\n \n # Append to result list\n result.append(formatted_string)\n \n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n \"\"\"\n result = []\n for s in lst:\n odd_count = sum(1 for char in s if int(char) % 2 == 1)\n result.append(f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\")\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n result = []\n \n for string in lst:\n # Count the number of odd digits in the current string\n odd_count = sum(1 for char in string if int(char) % 2 != 0)\n \n # Create the resulting string with the odd_count replacing 'i'\n transformed_string = (\n \"the number of odd elements \"\n f\"{odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\"\n )\n \n result.append(transformed_string)\n \n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n \"\"\"\n result = []\n for string in lst:\n # Count the number of odd digits in the string\n odd_digits_count = sum(1 for char in string if char in '13579')\n # Create the output string by replacing 'i' with odd_digits_count\n output = (f\"the number of odd elements {odd_digits_count}n the str\"\n f\"{odd_digits_count}ng {odd_digits_count} of the {odd_digits_count}nput.\")\n result.append(output)\n return result", "matching_cluster_idx": 4}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n result = []\n for s in lst:\n count_odd = sum(1 for char in s if char in '13579')\n sentence = f\"the number of odd elements {count_odd}n the str{count_odd}ng {count_odd} of the {count_odd}nput.\"\n result.append(sentence)\n return result", "matching_cluster_idx": 4}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n \n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n results = []\n for s in lst:\n # Count the number of odd digits in the string s\n odd_count = sum(1 for char in s if char in '13579')\n \n # Create the output string for this input string\n output_string = (\n f\"the number of odd elements {odd_count}n the str{odd_count}ng \"\n f\"{odd_count} of the {odd_count}nput.\"\n )\n \n # Add the result to the results list\n results.append(output_string)\n \n return results", "matching_cluster_idx": 4}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n \"\"\"\n def count_odds(s):\n \"\"\"Helper function to count the odd digits in a string.\"\"\"\n return sum(1 for char in s if int(char) % 2 != 0)\n\n result = []\n for s in lst:\n odd_count = count_odds(s)\n result.append(f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\")\n \n return result", "matching_cluster_idx": 3}]}, "HumanEval/119": {"dps": 39.53488372093023, "dps_norm": 87.0, "pass@1": 94.0, "profiled": [{"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n '''\n\n # Helper function to check if a string is balanced\n def is_balanced(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n else:\n balance -= 1\n if balance < 0: # More closing parens at any point\n return False\n return balance == 0 # Must be zero for a balanced string\n\n # Generate the two possible concatenations\n concat1 = lst[0] + lst[1]\n concat2 = lst[1] + lst[0]\n\n # Check if either concatenated string is balanced\n if is_balanced(concat1) or is_balanced(concat2):\n return 'Yes'\n else:\n return 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n def is_balanced(s):\n # Function to check if a single string of parentheses is balanced\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n else: # char == ')'\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n # Retrieve the two strings from the list\n s1, s2 = lst\n\n # Check if any concatenation of the two strings results in a balanced string\n if is_balanced(s1 + s2) or is_balanced(s2 + s1):\n return 'Yes'\n else:\n return 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n\n def is_balanced(s):\n # Helper function to check if a string is balanced\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n elif char == ')':\n balance -= 1\n # If at any point balance goes negative, it's not balanced\n if balance < 0:\n return False\n # In the end, balance should be zero for it to be fully balanced\n return balance == 0\n\n # Check both concatenation orders\n s1 = lst[0] + lst[1]\n s2 = lst[1] + lst[0]\n \n if is_balanced(s1) or is_balanced(s2):\n return 'Yes'\n else:\n return 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n \n # Helper function to check if a string is balanced\n def is_balanced(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n else:\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n # Get the two strings\n a, b = lst\n\n # Check both possible concatenations\n if is_balanced(a + b) or is_balanced(b + a):\n return 'Yes'\n else:\n return 'No'", "matching_cluster_idx": 3}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n \n def is_balanced(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n else: # char == ')'\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n a, b = lst\n \n # We need to check both a + b and b + a to see if any results in a balanced string\n if is_balanced(a + b) or is_balanced(b + a):\n return 'Yes'\n else:\n return 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n '''\n \n def is_balanced(s):\n # Helper function to check if a single string is balanced\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n elif char == ')':\n balance -= 1\n # At any point, if balance is negative, the string is not balanced\n if balance < 0:\n return False\n # The string is balanced if balance ends up being 0\n return balance == 0\n \n # Concatenate the strings in two different orders\n combined1 = lst[0] + lst[1]\n combined2 = lst[1] + lst[0]\n \n # Check if either combination is balanced\n if is_balanced(combined1) or is_balanced(combined2):\n return 'Yes'\n else:\n return 'No'", "matching_cluster_idx": 3}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n \n def is_balanced(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n elif char == ')':\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n # Try both concatenation orders\n order1 = lst[0] + lst[1]\n order2 = lst[1] + lst[0]\n \n # Check if either order is balanced\n if is_balanced(order1) or is_balanced(order2):\n return 'Yes'\n else:\n return 'No'", "matching_cluster_idx": 3}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n\n def is_good(s):\n \"\"\"Helper function to check if a string has balanced parentheses.\"\"\"\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n else:\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n # Try both concatenation orders\n s1 = lst[0] + lst[1]\n s2 = lst[1] + lst[0]\n\n # Check if either order produces a good string\n if is_good(s1) or is_good(s2):\n return 'Yes'\n else:\n return 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n\n def is_balanced(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n elif char == ')':\n balance -= 1\n # If balance goes negative, it means there are unmatched ')'s\n if balance < 0:\n return False\n # Finally, check if all '(' are matched\n return balance == 0\n\n s1, s2 = lst\n # Check both possible concatenations\n if is_balanced(s1 + s2) or is_balanced(s2 + s1):\n return 'Yes'\n else:\n return 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n\n def is_balanced(s):\n # Helper function to check if a given string of parentheses is balanced\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n elif char == ')':\n balance -= 1\n \n # A balance < 0 means there are more closing parens than opening at some point\n if balance < 0:\n return False\n return balance == 0\n\n # Attempt to concatenate the strings in both possible orders\n first, second = lst\n if is_balanced(first + second) or is_balanced(second + first):\n return 'Yes'\n else:\n return 'No'", "matching_cluster_idx": 3}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n def is_good(s):\n balance = 0\n for ch in s:\n if ch == '(':\n balance += 1\n elif ch == ')':\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n # Check both possible concatenations\n s1, s2 = lst\n if is_good(s1 + s2) or is_good(s2 + s1):\n return 'Yes'\n else:\n return 'No'", "matching_cluster_idx": 3}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n\n def is_good(s):\n # Helper function to check if a single string is balanced\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n elif char == ')':\n balance -= 1\n # If balance goes negative, there's a premature closing parenthesis\n if balance < 0:\n return False\n # In the end, balance must be zero for the string to be balanced\n return balance == 0\n\n # Extract strings from the list\n str1, str2 = lst\n\n # Check both possible concatenations\n if is_good(str1 + str2) or is_good(str2 + str1):\n return 'Yes'\n else:\n return 'No'", "matching_cluster_idx": 3}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n \n def is_good(s):\n # Function to check if a single string of parentheses is good\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n else:\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n # Try concatenating the strings in both possible orders\n s1, s2 = lst\n if is_good(s1 + s2) or is_good(s2 + s1):\n return 'Yes'\n else:\n return 'No'", "matching_cluster_idx": 3}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, such that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n\n def is_balanced(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n else:\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n # Check both possible concatenations\n concatenated_1 = lst[0] + lst[1]\n concatenated_2 = lst[1] + lst[0]\n\n if is_balanced(concatenated_1) or is_balanced(concatenated_2):\n return 'Yes'\n else:\n return 'No'", "matching_cluster_idx": 3}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n \n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n\n def is_good(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n else: # char == ')'\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n # Extract the two strings\n str1, str2 = lst\n\n # Check both concatenation orders\n # Check str1 + str2\n if is_good(str1 + str2):\n return 'Yes'\n \n # Check str2 + str1\n if is_good(str2 + str1):\n return 'Yes'\n\n return 'No'", "matching_cluster_idx": 3}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n \n def is_balanced(s):\n \"\"\"Helper function to check if a string of parentheses is balanced.\"\"\"\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n else:\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n # Try all possible concatenations\n s1, s2 = lst\n if is_balanced(s1 + s2) or is_balanced(s2 + s1):\n return 'Yes'\n return 'No'", "matching_cluster_idx": 3}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n \n def is_balanced(s):\n # Function to check if the string s is balanced\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n elif char == ')':\n balance -= 1\n \n # If at any point balance is negative, it means too many closing brackets\n if balance < 0:\n return False\n\n # If balance is zero, the string is balanced\n return balance == 0\n \n # Extract the strings\n a, b = lst\n \n # Check the two possible concatenations\n if is_balanced(a + b) or is_balanced(b + a):\n return 'Yes'\n else:\n return 'No'", "matching_cluster_idx": 3}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n\n # Helper function to check if a string is balanced\n def is_balanced(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n elif char == ')':\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n # Unpack the list of two strings\n first, second = lst\n\n # Check both possible concatenations\n if is_balanced(first + second) or is_balanced(second + first):\n return 'Yes'\n \n return 'No'", "matching_cluster_idx": 3}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n\n def is_good(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n else:\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n # Try both concatenation orders\n s1, s2 = lst\n concat1 = s1 + s2\n concat2 = s2 + s1\n\n if is_good(concat1) or is_good(concat2):\n return 'Yes'\n else:\n return 'No'", "matching_cluster_idx": 3}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n # Helper function to check if a string is balanced\n def is_balanced(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n elif char == ')':\n balance -= 1\n \n # At any point, if the balance is negative, it means there are more closing parens\n if balance < 0:\n return False\n \n # Finally, the balance should be zero\n return balance == 0\n\n # Try both orders of concatenation and check for a balanced result\n combined1 = lst[0] + lst[1]\n combined2 = lst[1] + lst[0]\n\n if is_balanced(combined1) or is_balanced(combined2):\n return 'Yes'\n else:\n return 'No'", "matching_cluster_idx": 4}]}, "HumanEval/120": {"dps": 96.63793103448276, "dps_norm": 97.85714285714286, "pass@1": 94.0, "profiled": [{"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n\n Example 1:\n Input: arr = [-3, -4, 5], k = 3\n Output: [-4, -3, 5]\n\n Example 2:\n Input: arr = [4, -4, 4], k = 2\n Output: [4, 4]\n\n Example 3:\n Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1\n Output: [2]\n\n Note:\n 1. The length of the array will be in the range of [1, 1000].\n 2. The elements in the array will be in the range of [-1000, 1000].\n 3. 0 <= k <= len(arr)\n \"\"\"\n if k == 0:\n return []\n\n # Find the k largest numbers and sort them\n result = sorted(sorted(arr, reverse=True)[:k])\n return result", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n\n Example 1:\n\n Input: arr = [-3, -4, 5], k = 3\n Output: [-4, -3, 5]\n\n Example 2:\n\n Input: arr = [4, -4, 4], k = 2\n Output: [4, 4]\n\n Example 3:\n\n Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1\n Output: [2]\n\n Note:\n 1. The length of the array will be in the range of [1, 1000].\n 2. The elements in the array will be in the range of [-1000, 1000].\n 3. 0 <= k <= len(arr)\n \"\"\"\n \n if k == 0:\n return []\n \n # Find the k largest elements in the array\n largest_k = sorted(arr, reverse=True)[:k]\n \n # Return the sorted version of the k largest elements\n return sorted(largest_k)", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n \"\"\"\n # Edge case: if k is 0, return an empty list\n if k == 0:\n return []\n \n # Sort the array in descending order and get the first k elements\n max_k_elements = sorted(arr, reverse=True)[:k]\n \n # Sort those k elements in ascending order as the final result\n return sorted(max_k_elements)", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n\n Example 1:\n\n Input: arr = [-3, -4, 5], k = 3\n Output: [-4, -3, 5]\n\n Example 2:\n\n Input: arr = [4, -4, 4], k = 2\n Output: [4, 4]\n\n Example 3:\n\n Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1\n Output: [2]\n\n Note:\n 1. The length of the array will be in the range of [1, 1000].\n 2. The elements in the array will be in the range of [-1000, 1000].\n 3. 0 <= k <= len(arr)\n \"\"\"\n if k == 0:\n return []\n\n # Sort the array in descending order and take the first k elements\n top_k = sorted(arr, reverse=True)[:k]\n\n # Sort the result to be in non-decreasing order\n return sorted(top_k)", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n \n Example 1:\n Input: arr = [-3, -4, 5], k = 3\n Output: [-4, -3, 5]\n \n Example 2:\n Input: arr = [4, -4, 4], k = 2\n Output: [4, 4]\n \n Example 3:\n Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1\n Output: [2]\n \n Note:\n 1. The length of the array will be in the range of [1, 1000].\n 2. The elements in the array will be in the range of [-1000, 1000].\n 3. 0 <= k <= len(arr)\n \"\"\"\n # Sort the array in descending order to get the largest elements at the start\n sorted_arr = sorted(arr, reverse=True)\n # Get the first k elements, which are the maximum k numbers\n max_k_numbers = sorted_arr[:k]\n # Return the sorted list of these maximum k numbers\n return sorted(max_k_numbers)", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n \"\"\"\n # Use Python's built-in sorted function to sort the array\n # Sort the array in descending order, then take the first k elements\n max_k_elements = sorted(arr, reverse=True)[:k]\n \n # Sort the result in ascending order as required by the problem statement\n return sorted(max_k_elements)", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n \n Parameters:\n arr (list): The list of integers.\n k (int): The number of maximum elements to return.\n \n Returns:\n list: A sorted list of the k maximum numbers in arr.\n \"\"\"\n # Check if k is 0, if so return an empty list\n if k == 0:\n return []\n\n # Sort the array in descending order and take the first k elements\n k_largest = sorted(arr, reverse=True)[:k]\n \n # Sort the k largest elements in ascending order before returning\n return sorted(k_largest)", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n\n :param arr: List[int] - A list of integers.\n :param k: int - The number of maximum elements to return.\n :return: List[int] - A sorted list of the maximum k elements from arr.\n \"\"\"\n if k == 0:\n return []\n \n # Sort the array in descending order and take the first k elements\n largest_k_elements = sorted(arr, reverse=True)[:k]\n \n # Sort the result in ascending order before returning\n return sorted(largest_k_elements)", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n\n Example 1:\n Input: arr = [-3, -4, 5], k = 3\n Output: [-4, -3, 5]\n\n Example 2:\n Input: arr = [4, -4, 4], k = 2\n Output: [4, 4]\n\n Example 3:\n Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1\n Output: [2]\n\n Note:\n 1. The length of the array will be in the range of [1, 1000].\n 2. The elements in the array will be in the range of [-1000, 1000].\n 3. 0 <= k <= len(arr)\n \"\"\"\n # Sort the array in descending order to easily access the k maximum numbers\n arr.sort(reverse=True)\n # Return the first k elements, sorted in ascending order\n return sorted(arr[:k])", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n\n Example 1:\n\n Input: arr = [-3, -4, 5], k = 3\n Output: [-4, -3, 5]\n\n Example 2:\n\n Input: arr = [4, -4, 4], k = 2\n Output: [4, 4]\n\n Example 3:\n\n Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1\n Output: [2]\n\n Note:\n 1. The length of the array will be in the range of [1, 1000].\n 2. The elements in the array will be in the range of [-1000, 1000].\n 3. 0 <= k <= len(arr)\n \"\"\"\n # Sort the array in descending order to get the largest numbers first\n sorted_arr = sorted(arr, reverse=True)\n \n # Get the first k elements from the sorted array\n max_k_elements = sorted_arr[:k]\n \n # Sort those k elements before returning to satisfy the requirement\n return sorted(max_k_elements)", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n \"\"\"\n # Sort the array in descending order\n sorted_arr = sorted(arr, reverse=True)\n # Take the first k elements and sort them in ascending order\n result = sorted(sorted_arr[:k])\n return result", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n \"\"\"\n # Step 1: Sort the array in descending order\n arr_sorted = sorted(arr, reverse=True)\n \n # Step 2: Take the first k elements from the sorted array\n max_k_elements = arr_sorted[:k]\n \n # Step 3: Sort the k elements in ascending order\n result = sorted(max_k_elements)\n \n return result", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n\n :param arr: List[int] - The array of integers\n :param k: int - The number of maximum elements to find\n :return: List[int] - Sorted list of the maximum k numbers\n \"\"\"\n # Sort the array in descending order and take the first k elements\n max_k_elements = sorted(arr, reverse=True)[:k]\n \n # Sort the resulting k elements in ascending order\n return sorted(max_k_elements)", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n\n Example 1:\n\n Input: arr = [-3, -4, 5], k = 3\n Output: [-4, -3, 5]\n\n Example 2:\n\n Input: arr = [4, -4, 4], k = 2\n Output: [4, 4]\n\n Example 3:\n\n Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1\n Output: [2]\n\n Note:\n 1. The length of the array will be in the range of [1, 1000].\n 2. The elements in the array will be in the range of [-1000, 1000].\n 3. 0 <= k <= len(arr)\n \"\"\"\n if k == 0:\n return []\n # Sort the array in descending order\n sorted_arr = sorted(arr, reverse=True)\n # Take the first k elements and sort them in ascending order\n return sorted(sorted_arr[:k])", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n\n Example 1:\n\n Input: arr = [-3, -4, 5], k = 3\n Output: [-4, -3, 5]\n\n Example 2:\n\n Input: arr = [4, -4, 4], k = 2\n Output: [4, 4]\n\n Example 3:\n\n Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1\n Output: [2]\n\n Note:\n 1. The length of the array will be in the range of [1, 1000].\n 2. The elements in the array will be in the range of [-1000, 1000].\n 3. 0 <= k <= len(arr)\n \"\"\"\n # Step 1: Sort the array in descending order to bring the largest elements to the front.\n sorted_arr = sorted(arr, reverse=True)\n \n # Step 2: Take the first k elements from the sorted array.\n largest_k = sorted_arr[:k]\n \n # Step 3: Return these elements sorted in non-decreasing order.\n return sorted(largest_k)", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n \"\"\"\n if k == 0:\n return []\n \n # Sort the array in descending order to find the k maximum elements\n arr_sorted = sorted(arr, reverse=True)\n \n # Take the first k elements from the sorted array\n k_max_elements = arr_sorted[:k]\n \n # Return the sorted list of k maximum elements\n return sorted(k_max_elements)", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n \"\"\"\n if k == 0:\n return []\n \n # Use heapq.nlargest to find the k largest elements\n import heapq\n largest_k = heapq.nlargest(k, arr)\n \n # Return the sorted list of these elements\n return sorted(largest_k)", "matching_cluster_idx": 3}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n\n Example 1:\n\n Input: arr = [-3, -4, 5], k = 3\n Output: [-4, -3, 5]\n\n Example 2:\n\n Input: arr = [4, -4, 4], k = 2\n Output: [4, 4]\n\n Example 3:\n\n Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1\n Output: [2]\n\n Note:\n 1. The length of the array will be in the range of [1, 1000].\n 2. The elements in the array will be in the range of [-1000, 1000].\n 3. 0 <= k <= len(arr)\n \"\"\"\n if k == 0:\n return []\n \n # Sort the array in descending order to find the largest elements\n sorted_arr = sorted(arr, reverse=True)\n \n # Take the first k elements from the sorted array\n max_k_elements = sorted_arr[:k]\n \n # Sort the result in ascending order as required\n return sorted(max_k_elements)", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n\n Args:\n arr (list of int): The array of integers.\n k (int): The number of maximum elements to return.\n\n Returns:\n list of int: Sorted list of the maximum k numbers from arr.\n \"\"\"\n # Check if k is 0, we return an empty list since there's nothing to select\n if k == 0:\n return []\n\n # Sort the array in descending order to get the largest elements first\n sorted_arr = sorted(arr, reverse=True)\n\n # Slice the first k elements from the sorted array, which are the k largest\n max_k_elements = sorted_arr[:k]\n\n # Return the result sorted in ascending order\n return sorted(max_k_elements)", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n\n Example 1:\n\n Input: arr = [-3, -4, 5], k = 3\n Output: [-4, -3, 5]\n\n Example 2:\n\n Input: arr = [4, -4, 4], k = 2\n Output: [4, 4]\n\n Example 3:\n\n Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1\n Output: [2]\n\n Note:\n 1. The length of the array will be in the range of [1, 1000].\n 2. The elements in the array will be in the range of [-1000, 1000].\n 3. 0 <= k <= len(arr)\n \"\"\"\n \n # Handle the case where k is 0\n if k == 0:\n return []\n \n # Sort the array in descending order\n sorted_arr = sorted(arr, reverse=True)\n \n # Take the first k elements (the largest k elements)\n max_k_elements = sorted_arr[:k]\n \n # Return the result sorted in ascending order\n return sorted(max_k_elements)", "matching_cluster_idx": 6}]}, "HumanEval/121": {"dps": 90.22421524663677, "dps_norm": 68.57142857142857, "pass@1": 100.0, "profiled": [{"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\"\"\"\n # We only consider even indices (0-based), which are 0, 2, 4, ...\n sum_of_odds = 0\n for i in range(0, len(lst), 2):\n if lst[i] % 2 != 0: # Check if the element at the even position is odd\n sum_of_odds += lst[i]\n return sum_of_odds", "matching_cluster_idx": 4}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n\n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n # Initialize the sum\n odd_sum = 0\n \n # Iterate over the list, considering elements at even indices (0, 2, 4, ...)\n for i in range(0, len(lst), 2):\n # Check if the element is odd\n if lst[i] % 2 != 0:\n # Add it to the sum if it's odd\n odd_sum += lst[i]\n \n return odd_sum", "matching_cluster_idx": 4}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n\n Examples:\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n return sum(num for idx, num in enumerate(lst) if idx % 2 == 0 and num % 2 != 0)", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n Args:\n lst (list): A list of integers.\n\n Returns:\n int: The sum of all odd elements that are in even positions.\n \n Examples:\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n return sum(lst[i] for i in range(0, len(lst), 2) if lst[i] % 2 != 0)", "matching_cluster_idx": 4}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n The even positions in the list are the indices 0, 2, 4, etc.\n \n Examples:\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n # Initialize the sum\n sum_of_odds = 0\n \n # Iterate over even indices in the list\n for i in range(0, len(lst), 2):\n # Check if the element at this index is odd\n if lst[i] % 2 != 0:\n sum_of_odds += lst[i]\n \n return sum_of_odds", "matching_cluster_idx": 4}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n Parameters:\n lst (list): A list of integers.\n \n Returns:\n int: The sum of odd elements at even positions.\n \n Examples:\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n return sum(lst[i] for i in range(0, len(lst), 2) if lst[i] % 2 != 0)", "matching_cluster_idx": 4}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n\n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n # Even positions in a 0-based index list are 0, 2, 4, etc.\n return sum(lst[i] for i in range(0, len(lst), 2) if lst[i] % 2 != 0)", "matching_cluster_idx": 4}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all the odd elements that are in even positions.\n\n Args:\n lst (list): A non-empty list of integers.\n\n Returns:\n int: The sum of odd elements that are located at even indices.\n\n Examples:\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n # Initialize the sum to 0\n odd_sum = 0\n \n # Iterate over the list with index\n for index in range(0, len(lst), 2):\n # Check if the element at the current even index is odd\n if lst[index] % 2 == 1:\n # Add it to the sum\n odd_sum += lst[index]\n \n return odd_sum", "matching_cluster_idx": 4}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n\n Parameters:\n lst (List[int]): A list of integers.\n\n Returns:\n int: The sum of all odd elements that are in even positions.\n\n Examples:\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n return sum(lst[i] for i in range(0, len(lst), 2) if lst[i] % 2 != 0)", "matching_cluster_idx": 4}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n\n Args:\n lst (List[int]): A non-empty list of integers.\n\n Returns:\n int: The sum of all odd elements located at even indices in the list.\n \"\"\"\n # Initialize sum to 0\n odd_sum = 0\n \n # Iterate through the list, checking even positions (0, 2, 4, ...)\n for index in range(0, len(lst), 2):\n # Check if the element at the even position is odd\n if lst[index] % 2 != 0:\n # Add it to the sum if it is odd\n odd_sum += lst[index]\n \n return odd_sum", "matching_cluster_idx": 4}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n\n An 'even position' refers to an index which is an even number (0, 2, 4, ...).\n\n Examples:\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n # We need to sum elements which are odd and in even indices\n return sum(lst[i] for i in range(0, len(lst), 2) if lst[i] % 2 == 1)", "matching_cluster_idx": 4}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n Args:\n lst (list of int): A non-empty list of integers.\n\n Returns:\n int: The sum of all odd elements that are located at even indices.\n \n Examples:\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n return sum(lst[i] for i in range(0, len(lst), 2) if lst[i] % 2 != 0)", "matching_cluster_idx": 4}, {"solution": "def solution(lst):\n \"\"\"\n Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n Parameters:\n lst (list): A list of integers.\n\n Returns:\n int: The sum of odd elements in even positions.\n \n Examples:\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n # We want the sum of odd elements at even positions\n # Even positions are 0, 2, 4, ..., hence they are the even indices\n return sum(lst[i] for i in range(0, len(lst), 2) if lst[i] % 2 != 0)", "matching_cluster_idx": 4}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\"\"\"\n return sum(lst[i] for i in range(0, len(lst), 2) if lst[i] % 2 != 0)", "matching_cluster_idx": 4}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n Examples:\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n sum_odd_even_pos = 0\n # Iterate over the list with index\n for index in range(0, len(lst), 2): # Step by 2 to only consider even indices\n if lst[index] % 2 != 0: # Check if the element at the even position is odd\n sum_odd_even_pos += lst[index]\n return sum_odd_even_pos", "matching_cluster_idx": 4}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n\n Args:\n lst (list): A non-empty list of integers.\n\n Returns:\n int: The sum of all the odd elements that are in even positions (0-based index).\n \n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n return sum(lst[i] for i in range(0, len(lst), 2) if lst[i] % 2 != 0)", "matching_cluster_idx": 4}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n\n An element is in an even position if its index is even (0, 2, 4, ...).\n\n Examples:\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n return sum(lst[i] for i in range(0, len(lst), 2) if lst[i] % 2 != 0)", "matching_cluster_idx": 4}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n\n An element is considered to be in an \"even position\" if it is at an index that is an even number\n (considering 0 to be an even number).\n \n Args:\n lst (list): A non-empty list of integers.\n \n Returns:\n int: The sum of odd elements that are in even positions.\n \n Examples:\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n return sum(value for index, value in enumerate(lst) if index % 2 == 0 and value % 2 != 0)", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n Examples:\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n return sum(value for index, value in enumerate(lst) if index % 2 == 0 and value % 2 != 0)", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n Examples:\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n return sum(value for index, value in enumerate(lst) if index % 2 == 0 and value % 2 != 0)", "matching_cluster_idx": 3}]}, "HumanEval/149": {"dps": 85.82677165354332, "dps_norm": 57.142857142857146, "pass@1": 100.0, "profiled": [{"solution": "def sorted_list_sum(lst):\n \"\"\"Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n \"\"\"\n \n # Filter out strings with odd lengths\n even_length_strings = [s for s in lst if len(s) % 2 == 0]\n \n # Sort the strings first by length and then alphabetically\n sorted_strings = sorted(even_length_strings, key=lambda x: (len(x), x))\n \n return sorted_strings", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order,\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n You may assume that all words will have the same length.\n For example:\n assert sorted_list_sum([\"aa\", \"a\", \"aaa\"]) == [\"aa\"]\n assert sorted_list_sum([\"ab\", \"a\", \"aaa\", \"cd\"]) == [\"ab\", \"cd\"]\n \"\"\"\n # Remove strings with odd lengths\n filtered_lst = [s for s in lst if len(s) % 2 == 0]\n \n # Sort the filtered list by length first and then alphabetically\n sorted_lst = sorted(filtered_lst, key=lambda x: (len(x), x))\n \n return sorted_lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order,\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n You may assume that all words will have the same length.\n For example:\n assert list_sort([\"aa\", \"a\", \"aaa\"]) => [\"aa\"]\n assert list_sort([\"ab\", \"a\", \"aaa\", \"cd\"]) => [\"ab\", \"cd\"]\n \"\"\"\n # Filter out strings with odd lengths\n even_length_strings = [s for s in lst if len(s) % 2 == 0]\n \n # Sort by length first, then alphabetically\n even_length_strings.sort(key=lambda s: (len(s), s))\n \n return even_length_strings", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order,\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n You may assume that all words will have the same length.\n For example:\n assert list_sort([\"aa\", \"a\", \"aaa\"]) => [\"aa\"]\n assert list_sort([\"ab\", \"a\", \"aaa\", \"cd\"]) => [\"ab\", \"cd\"]\n \"\"\"\n # Filter out strings with odd lengths\n even_length_strings = [s for s in lst if len(s) % 2 == 0]\n \n # Sort the list by length first, and then alphabetically\n sorted_list = sorted(even_length_strings, key=lambda s: (len(s), s))\n \n return sorted_list", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n For example:\n assert sorted_list_sum([\"aa\", \"a\", \"aaa\"]) == [\"aa\"]\n assert sorted_list_sum([\"ab\", \"a\", \"aaa\", \"cd\"]) == [\"ab\", \"cd\"]\n \"\"\"\n # Filter out strings with odd lengths\n even_length_strings = [s for s in lst if len(s) % 2 == 0]\n \n # Sort the filtered list by length and then alphabetically\n sorted_list = sorted(even_length_strings, key=lambda x: (len(x), x))\n \n return sorted_list", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order.\n \n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n \n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n \n For example:\n assert sorted_list_sum([\"aa\", \"a\", \"aaa\"]) == [\"aa\"]\n assert sorted_list_sum([\"ab\", \"a\", \"aaa\", \"cd\"]) == [\"ab\", \"cd\"]\n \"\"\"\n # Filter out strings with odd lengths\n even_length_strings = [s for s in lst if len(s) % 2 == 0]\n \n # Sort the strings first by length, then alphabetically\n even_length_strings.sort(key=lambda s: (len(s), s))\n \n return even_length_strings", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"\n Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order.\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n For example:\n assert sorted_list_sum([\"aa\", \"a\", \"aaa\"]) == [\"aa\"]\n assert sorted_list_sum([\"ab\", \"a\", \"aaa\", \"cd\"]) == [\"ab\", \"cd\"]\n \"\"\"\n \n # Filter out strings with odd lengths\n even_length_words = [word for word in lst if len(word) % 2 == 0]\n\n # Sort the list first alphabetically, then by length\n sorted_words = sorted(even_length_words, key=lambda x: (len(x), x))\n \n return sorted_words", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"Accepts a list of strings, removes strings with odd lengths,\n and returns the list sorted by length and alphabetically.\n \"\"\"\n # Filter out strings with odd lengths\n filtered_lst = [s for s in lst if len(s) % 2 == 0]\n \n # Sort first by length of the string, then alphabetically\n sorted_lst = sorted(filtered_lst, key=lambda x: (len(x), x))\n \n return sorted_lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order,\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n You may assume that all words will have the same length.\n For example:\n assert sorted_list_sum([\"aa\", \"a\", \"aaa\"]) == [\"aa\"]\n assert sorted_list_sum([\"ab\", \"a\", \"aaa\", \"cd\"]) == [\"ab\", \"cd\"]\n \"\"\"\n\n # Filter out words with odd lengths\n even_length_words = [word for word in lst if len(word) % 2 == 0]\n\n # Sort the filtered list first by length, then alphabetically\n sorted_words = sorted(even_length_words, key=lambda x: (len(x), x))\n\n return sorted_words", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order,\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n \"\"\"\n # Filter out strings with odd lengths\n even_length_words = [word for word in lst if len(word) % 2 == 0]\n\n # Sort the filtered list by length, then alphabetically\n sorted_list = sorted(even_length_words, key=lambda x: (len(x), x))\n\n return sorted_list", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order,\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n You may assume that all words will have the same length.\n For example:\n assert sorted_list_sum([\"aa\", \"a\", \"aaa\"]) => [\"aa\"]\n assert sorted_list_sum([\"ab\", \"a\", \"aaa\", \"cd\"]) => [\"ab\", \"cd\"]\n \"\"\"\n # Filter out strings with odd lengths\n even_length_strings = [s for s in lst if len(s) % 2 == 0]\n \n # Sort the list first by length, then alphabetically\n sorted_strings = sorted(even_length_strings, key=lambda x: (len(x), x))\n \n return sorted_strings", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order.\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n \"\"\"\n # Filter out words with odd length\n even_length_words = [word for word in lst if len(word) % 2 == 0]\n \n # Sort the list: first by length of each word, then alphabetically\n sorted_list = sorted(even_length_words, key=lambda word: (len(word), word))\n \n return sorted_list", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order.\n \n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n \n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n \n The function should return a list of strings in sorted order.\n \"\"\"\n # Filter out strings with odd lengths\n even_length_strings = [s for s in lst if len(s) % 2 == 0]\n \n # Sort the remaining strings first by length, then alphabetically\n sorted_list = sorted(even_length_strings, key=lambda s: (len(s), s))\n \n return sorted_list", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order,\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n You may assume that all words will have the same length.\n For example:\n assert sorted_list_sum([\"aa\", \"a\", \"aaa\"]) == [\"aa\"]\n assert sorted_list_sum([\"ab\", \"a\", \"aaa\", \"cd\"]) == [\"ab\", \"cd\"]\n \"\"\"\n # Filter out strings with odd lengths\n even_length_strings = [s for s in lst if len(s) % 2 == 0]\n \n # Sort the list first by length of the word, then alphabetically\n sorted_strings = sorted(even_length_strings, key=lambda s: (len(s), s))\n \n return sorted_strings", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order.\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n You may assume that all words will have different lengths.\n For example:\n assert sorted_list_sum([\"aa\", \"a\", \"aaa\"]) == [\"aa\"]\n assert sorted_list_sum([\"ab\", \"a\", \"aaa\", \"cd\"]) == [\"ab\", \"cd\"]\n \"\"\"\n # Filter out strings with odd lengths\n even_length_strings = [s for s in lst if len(s) % 2 == 0]\n\n # Sort the list first by length, then alphabetically\n even_length_strings.sort(key=lambda x: (len(x), x))\n\n return even_length_strings", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order,\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n \"\"\"\n # Filter out strings with odd lengths\n even_length_strings = [s for s in lst if len(s) % 2 == 0]\n \n # Sort the filtered list by length and then alphabetically for strings of the same length\n sorted_list = sorted(even_length_strings, key=lambda x: (len(x), x))\n \n return sorted_list", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order,\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n You may assume that all words will have the same length.\n For example:\n assert sorted_list_sum([\"aa\", \"a\", \"aaa\"]) => [\"aa\"]\n assert sorted_list_sum([\"ab\", \"a\", \"aaa\", \"cd\"]) => [\"ab\", \"cd\"]\n \"\"\"\n \n # Remove strings with odd lengths\n even_length_strings = [s for s in lst if len(s) % 2 == 0]\n\n # Sort by length first, then alphabetically\n even_length_strings.sort(key=lambda s: (len(s), s))\n \n return even_length_strings", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"Accepts a list of strings as a parameter, deletes the strings \n that have odd lengths from it, and returns the resulted list in\n a sorted order. The list is sorted first by length, then \n alphabetically if lengths are the same.\"\"\"\n \n # Filter out strings with odd lengths\n filtered_list = [s for s in lst if len(s) % 2 == 0]\n \n # Sort the filtered list by length, then alphabetically\n sorted_list = sorted(filtered_list, key=lambda x: (len(x), x))\n \n return sorted_list", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order.\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n For example:\n assert sorted_list_sum([\"aa\", \"a\", \"aaa\"]) == [\"aa\"]\n assert sorted_list_sum([\"ab\", \"a\", \"aaa\", \"cd\"]) == [\"ab\", \"cd\"]\n \"\"\"\n # Filter out strings with odd lengths\n even_length_strings = [s for s in lst if len(s) % 2 == 0]\n \n # Sort first by length, then by lexicographical order\n sorted_list = sorted(even_length_strings, key=lambda x: (len(x), x))\n \n return sorted_list", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order,\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n \"\"\"\n # Filter out strings with odd lengths\n filtered_list = [s for s in lst if len(s) % 2 == 0]\n \n # Sort the filtered list first by length, then alphabetically\n sorted_list = sorted(filtered_list, key=lambda x: (len(x), x))\n \n return sorted_list", "matching_cluster_idx": 3}]}, "Mbpp/3": {"dps": 97.79661016949153, "dps_norm": 98.75, "pass@1": 100.0, "profiled": [{"solution": "def is_not_prime(n):\n \"\"\"Return True if n is a non-prime number, else return False.\"\"\"\n if n <= 1:\n return True\n if n <= 3:\n return False # 2 and 3 are prime\n if n % 2 == 0 or n % 3 == 0:\n return True\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return True\n i += 6\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n \"\"\"\n This function returns True if the number n is not a prime number,\n and False if it is a prime number.\n \"\"\"\n if n <= 1:\n return True # Numbers less than or equal to 1 are not prime\n if n == 2:\n return False # 2 is the only even prime number\n if n % 2 == 0:\n return True # Other even numbers are not prime\n for i in range(3, int(n**0.5) + 1, 2):\n if n % i == 0:\n return True # Divisible by a number other than 1 and itself\n return False # Otherwise, n is a prime number", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n if n <= 1:\n return True # 0 and 1 are not prime numbers\n if n <= 3:\n return False # 2 and 3 are prime numbers\n if n % 2 == 0 or n % 3 == 0:\n return True # multiples of 2 and 3 are not prime\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return True\n i += 6\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n \"\"\"Return True if n is not a prime number, otherwise return False.\"\"\"\n if n <= 1:\n return True\n if n <= 3:\n return False\n if n % 2 == 0 or n % 3 == 0:\n return True\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return True\n i += 6\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n \"\"\"Return True if n is not a prime number, otherwise False.\"\"\"\n if n <= 1:\n return True\n if n == 2:\n return False\n if n % 2 == 0:\n return True\n for i in range(3, int(n**0.5) + 1, 2):\n if n % i == 0:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n \"\"\"Returns True if n is not a prime number, otherwise False.\"\"\"\n if n <= 1:\n return True\n if n == 2:\n return False # 2 is a prime number\n if n % 2 == 0:\n return True # Any even number greater than 2 is not prime\n for i in range(3, int(n ** 0.5) + 1, 2):\n if n % i == 0:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n \"\"\"Return True if n is not a prime number, else return False.\"\"\"\n if n <= 1:\n return True\n if n <= 3:\n return False\n if n % 2 == 0 or n % 3 == 0:\n return True\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return True\n i += 6\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n \"\"\"\n Returns True if n is not a prime number, otherwise False.\n \"\"\"\n if n <= 1:\n return True\n if n <= 3:\n return False\n if n % 2 == 0 or n % 3 == 0:\n return True\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return True\n i += 6\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n \"\"\"\n Function to determine if a number is not prime.\n Returns True if the number is not prime, otherwise False.\n \"\"\"\n if n <= 1:\n return True # Numbers less than or equal to 1 are not prime\n if n <= 3:\n return False # 2 and 3 are prime numbers\n if n % 2 == 0 or n % 3 == 0:\n return True # Eliminate multiples of 2 and 3\n\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return True\n i += 6\n\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n \"\"\"Return True if n is not a prime number, False otherwise.\"\"\"\n if n <= 1:\n return True # 0, 1, and negative numbers are not prime\n if n == 2:\n return False # 2 is the only even prime number\n if n % 2 == 0:\n return True # Other even numbers are not prime\n # Check for factors from 3 to sqrt(n)\n for i in range(3, int(n**0.5) + 1, 2):\n if n % i == 0:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n \"\"\"Returns True if n is a non-prime number, False otherwise.\"\"\"\n if n < 2:\n return True\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return True\n return False", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(n):\n if n <= 1:\n return True # Numbers less than or equal to 1 are not prime\n if n == 2:\n return False # 2 is the only even prime number\n if n % 2 == 0:\n return True # Other even numbers are not prime\n\n # Check for factors from 3 up to the square root of n\n for i in range(3, int(n**0.5) + 1, 2):\n if n % i == 0:\n return True # A factor has been found, so n is not prime\n\n return False # No factors found, so n is prime", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n \"\"\"Returns True if n is not a prime number, otherwise False.\"\"\"\n if n <= 1:\n return True\n if n == 2:\n return False # 2 is the only even prime number\n if n % 2 == 0:\n return True # Exclude other even numbers\n\n sqrt_n = int(n**0.5) + 1\n for i in range(3, sqrt_n, 2):\n if n % i == 0:\n return True\n\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n \"\"\"\n Function to check if a number is non-prime.\n Returns True if n is not a prime number, otherwise False.\n \"\"\"\n if n <= 1:\n return True\n if n <= 3:\n return False\n if n % 2 == 0 or n % 3 == 0:\n return True\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return True\n i += 6\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n \"\"\"Return True if n is not a prime number, else False.\"\"\"\n if n <= 1:\n return True # 0 and 1 are not prime numbers\n if n == 2:\n return False # 2 is the only even prime number\n if n % 2 == 0:\n return True # Other even numbers are not prime\n\n # Check for factors from 3 to sqrt(n)\n for i in range(3, int(n**0.5) + 1, 2):\n if n % i == 0:\n return True\n\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n \"\"\"\n Function to check if a number is not a prime.\n A prime number is greater than 1 and has no divisors other than 1 and itself.\n \n Returns True if n is not a prime number, otherwise False.\n \"\"\"\n if n <= 1:\n return True\n if n == 2:\n return False # 2 is a prime number\n if n % 2 == 0:\n return True # Excluding even numbers greater than 2\n sqrt_n = int(n**0.5) + 1\n for i in range(3, sqrt_n, 2):\n if n % i == 0:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n \"\"\"Return True if n is not a prime number, False otherwise.\"\"\"\n if n <= 1:\n return True # 0 and 1 are not prime numbers\n if n == 2:\n return False # 2 is a prime number\n if n % 2 == 0:\n return True # Even numbers other than 2 are not prime\n sqrt_n = int(n**0.5) + 1\n for i in range(3, sqrt_n, 2):\n if n % i == 0:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n \"\"\"Return True if n is not a prime number, otherwise False.\"\"\"\n if n <= 1:\n return True\n if n == 2:\n return False\n if n % 2 == 0:\n return True\n for i in range(3, int(n**0.5) + 1, 2):\n if n % i == 0:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n \"\"\"Determine if a number is not a prime number.\"\"\"\n if n <= 1:\n return True\n if n == 2:\n return False # 2 is a prime number\n if n % 2 == 0:\n return True # any other even number is not prime\n for i in range(3, int(n**0.5) + 1, 2):\n if n % i == 0:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n \"\"\"\n This function returns True if the number is not a prime number,\n and False if the number is a prime number.\n \"\"\"\n if n <= 1:\n return True # 0, 1 and negative numbers are not prime\n if n <= 3:\n return False # 2 and 3 are prime numbers\n if n % 2 == 0 or n % 3 == 0:\n return True # Excluding multiples of 2 and 3 early\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return True\n i += 6\n return False", "matching_cluster_idx": 7}]}, "Mbpp/4": {"dps": 95.22184300341297, "dps_norm": 83.33333333333333, "pass@1": 100.0, "profiled": [{"solution": "import heapq\ndef heap_queue_largest(numbers, n):\n \"\"\"\n Returns the n largest integers from a given list of numbers, in descending order.\n\n :param numbers: List of integers from which to find the largest numbers.\n :param n: Number of largest integers to find.\n :return: A list of the n largest integers, sorted in descending order.\n \"\"\"\n # Use heapq.nlargest to find the n largest numbers\n largest_numbers = heapq.nlargest(n, numbers)\n # Return the numbers sorted in descending order\n return sorted(largest_numbers, reverse=True)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(numbers, n):\n # Use heapq.nlargest to find the n largest elements in the list\n # and automatically returns them in descending order.\n return heapq.nlargest(n, numbers)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n \"\"\"\n Find the n largest integers from a given list of numbers, returned in descending order.\n \"\"\"\n # Use heapq.nlargest to find the n largest numbers from the list\n largest = heapq.nlargest(n, nums)\n return largest", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(numbers, n):\n \"\"\"\n Find the n largest integers from a given list of numbers, returned in descending order.\n \n Args:\n numbers (list of int): The list of integers.\n n (int): The number of largest integers to find.\n \n Returns:\n list of int: The n largest integers from the list, sorted in descending order.\n \"\"\"\n if n <= 0 or not numbers:\n return []\n \n # Use heapq.nlargest to get the n largest numbers\n largest_numbers = heapq.nlargest(n, numbers)\n \n return largest_numbers", "matching_cluster_idx": 9}, {"solution": "import heapq\nfrom typing import List\ndef heap_queue_largest(nums: List[int], n: int) -> List[int]:\n \"\"\"\n Find the n largest integers from a given list of numbers and return them in descending order.\n\n :param nums: List of integers from which to find the largest numbers.\n :param n: The number of largest integers to find.\n :return: List of the n largest integers in descending order.\n \"\"\"\n if n <= 0:\n return []\n # Use heapq.nlargest to find the n largest numbers\n largest_nums = heapq.nlargest(n, nums)\n return largest_nums", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(numbers, n):\n \"\"\"\n Finds the n largest integers from a given list of numbers, returned in descending order.\n\n :param numbers: List of integers from which to find the largest numbers\n :param n: Number of largest integers to return\n :return: List of n largest integers in descending order\n \"\"\"\n # Use heapq.nlargest to find the n largest elements\n largest_numbers = heapq.nlargest(n, numbers)\n \n # Since heapq.nlargest returns the numbers in descending order, we can return it directly\n return largest_numbers", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(numbers, n):\n \"\"\"\n Find the n largest integers from the list of numbers and return them in descending order.\n \"\"\"\n # Use heapq.nlargest to get the n largest numbers\n largest_numbers = heapq.nlargest(n, numbers)\n \n # The numbers are already in descending order, so return them as is\n return largest_numbers", "matching_cluster_idx": 9}, {"solution": "import heapq\nfrom typing import List\ndef heap_queue_largest(numbers: List[int], n: int) -> List[int]:\n \"\"\"\n Find the n largest integers from a given list of numbers and return them in descending order.\n \n Parameters:\n numbers (List[int]): The list of integers from which to find the largest numbers.\n n (int): The number of largest integers to find.\n \n Returns:\n List[int]: The n largest integers in descending order.\n \"\"\"\n if n <= 0:\n return []\n \n # Use heapq.nlargest to find the n largest elements\n largest = heapq.nlargest(n, numbers)\n \n # Return the result already sorted in descending order\n return largest", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(numbers, n):\n \"\"\"\n Finds the n largest integers from a list of numbers and returns them in descending order.\n\n :param numbers: List of integers\n :param n: Number of largest integers to return\n :return: List of n largest integers in descending order\n \"\"\"\n # Use heapq's nlargest function to get the n largest numbers\n largest_numbers = heapq.nlargest(n, numbers)\n return largest_numbers", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(numbers, n):\n # Use heapq.nlargest to find the n largest numbers\n largest_numbers = heapq.nlargest(n, numbers)\n # Return them sorted in descending order\n return sorted(largest_numbers, reverse=True)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n \"\"\"\n Find the n largest integers from a given list of numbers.\n \n Parameters:\n nums (list): A list of integers.\n n (int): The number of largest integers to find.\n\n Returns:\n list: A list of the n largest integers in descending order.\n \"\"\"\n # Find the n largest elements using heapq.nlargest\n largest = heapq.nlargest(n, nums)\n return largest # Elements are already in descending order", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(numbers, n):\n \"\"\"\n Find the n largest integers from a given list of numbers, returned in descending order.\n \n :param numbers: List[int] - A list of integers from which to find the n largest\n :param n: int - The number of largest integers to find\n :return: List[int] - A list of the n largest integers in descending order\n \"\"\"\n # Use heapq.nlargest to find the n largest numbers\n largest_numbers = heapq.nlargest(n, numbers)\n # Return them in descending order\n return largest_numbers", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(numbers, n):\n \"\"\"\n Finds the n largest integers from a given list of numbers and returns them in descending order.\n \n :param numbers: List[int] - A list of integers from which to find the largest numbers\n :param n: int - The number of largest integers to find\n :return: List[int] - A list of the n largest integers in descending order\n \"\"\"\n # Use heapq.nlargest to find the n largest numbers\n largest_numbers = heapq.nlargest(n, numbers)\n # By default, nlargest returns numbers in descending order, so we just return the result\n return largest_numbers", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(numbers, n):\n \"\"\"\n Find the n largest integers from the given list of numbers and return them in descending order.\n \n Parameters:\n numbers (list of int): The list of numbers.\n n (int): The number of largest integers to find.\n \n Returns:\n list of int: The n largest integers in descending order.\n \"\"\"\n # Using heapq.nlargest to find the n largest numbers\n largest_numbers = heapq.nlargest(n, numbers)\n # nlargest already returns the numbers in descending order\n return largest_numbers", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(numbers, n):\n \"\"\"\n Find the n largest integers from a given list of numbers and return them in descending order.\n \n Parameters:\n numbers (list): The list of integers.\n n (int): The number of largest integers to find.\n \n Returns:\n list: A list of the n largest integers in descending order.\n \"\"\"\n # Use heapq.nlargest to get the n largest elements\n largest_numbers = heapq.nlargest(n, numbers)\n \n return largest_numbers", "matching_cluster_idx": 9}, {"solution": "import heapq\nfrom typing import List\ndef heap_queue_largest(numbers: List[int], n: int) -> List[int]:\n \"\"\"\n Find the n largest integers from a given list of numbers and return them in descending order.\n\n Parameters:\n numbers (List[int]): The list of integers.\n n (int): The number of largest integers to find.\n\n Returns:\n List[int]: A list containing the n largest integers in descending order.\n \"\"\"\n # Use heapq.nlargest to find the n largest numbers\n largest_numbers = heapq.nlargest(n, numbers)\n \n # The result from heapq.nlargest is already in descending order\n return largest_numbers", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(numbers, n):\n \"\"\"\n Returns the n largest integers from the list of numbers in descending order.\n \"\"\"\n # Use nlargest from heapq to get the n largest numbers\n largest_numbers = heapq.nlargest(n, numbers)\n # nlargest already returns in descending order, so we return the result directly\n return largest_numbers", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(numbers, n):\n \"\"\"\n Find the n largest integers from a given list of numbers and return them in descending order.\n\n :param numbers: List of integers from which to find the largest numbers.\n :param n: Number of largest integers to find.\n :return: List of the n largest integers in descending order.\n \"\"\"\n # Use heapq.nlargest to find the n largest numbers and sort them in descending order\n return sorted(heapq.nlargest(n, numbers), reverse=True)\nnumbers = [25, 35, 22, 85, 14, 65, 75, 22, 58]\nn = 3", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(numbers, n):\n \"\"\"\n Find the n largest integers from a given list of numbers, returned in descending order.\n \n :param numbers: List of integers.\n :param n: Number of largest integers to find.\n :return: List of n largest integers in descending order.\n \"\"\"\n # Use heapq.nlargest to get the n largest elements from the list\n largest_n = heapq.nlargest(n, numbers)\n # Return the result (it will already be sorted in descending order by nlargest)\n return largest_n", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(numbers, n):\n \"\"\"\n Finds the n largest integers from the given list of numbers, returned in descending order.\n\n Parameters:\n numbers (list): A list of integers.\n n (int): The number of largest integers to find.\n\n Returns:\n list: A list containing the n largest integers in descending order.\n \"\"\"\n # Find the n largest elements using heapq.nlargest\n largest_numbers = heapq.nlargest(n, numbers)\n return largest_numbers", "matching_cluster_idx": 9}]}, "Mbpp/9": {"dps": 90.23809523809523, "dps_norm": 58.5, "pass@1": 91.0, "profiled": [{"solution": "def find_Rotations(s: str) -> int:\n \"\"\"\n Function to find the minimum number of rotations required to get the same string.\n \n Parameters:\n s (str): The input string for which the rotation count is to be found.\n\n Returns:\n int: The minimum number of rotations greater than 0 required to get the same string.\n \"\"\"\n # Check if the string is empty or just a single character\n if len(s) <= 1:\n return 1\n \n # Concatenate the string to itself\n doubled_s = s + s\n \n # Start from the second character and go till the length of the original string\n for i in range(1, len(s)):\n # If the substring of doubled_s from i to i+len(s) matches s, return i\n if doubled_s[i:i+len(s)] == s:\n return i\n \n # In case no rotation found (which shouldn't happen), return the length of string\n return len(s)", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(s):\n \"\"\"\n This function returns the minimum number of rotations (greater than 0)\n required to get the same string.\n \"\"\"\n # Concatenate the string with itself\n double_s = s + s\n # Find the first occurrence of the original string in the double string\n # starting from index 1, because index 0 would be the original string itself.\n for i in range(1, len(s)):\n # Check if a substring of double_s starting from i of length len(s) is equal to s\n if double_s[i:i+len(s)] == s:\n return i\n return len(s) # This case happens if all characters are the same", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(s):\n \"\"\"\n Function to find the minimum number of rotations required to get the same string.\n \n Parameters:\n s (str): The input string\n \n Returns:\n int: The minimum number of rotations\n \"\"\"\n # Double the string and find the first occurrence of the original string\n doubled_s = s + s\n n = len(s)\n \n # Start from index 1 because rotation 0 means the string itself, \n # and we want the minimum rotations greater than 0.\n for i in range(1, n + 1):\n if doubled_s[i:i + n] == s:\n return i\n return n", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(s: str) -> int:\n \"\"\"\n Function to find the minimum number of rotations (greater than 0) required to get the same string.\n \"\"\"\n n = len(s)\n \n # Concatenate the string to itself\n temp = s + s\n \n # Find the first occurrence of the original string in the concatenated string\n # starting from index 1\n for i in range(1, n + 1):\n if temp[i:i + n] == s:\n return i\n \n return n # In the worst case, it would take n rotations", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(s):\n \"\"\"\n This function finds the minimum number of rotations (greater than 0) required to get the same string.\n \"\"\"\n # Concatenate the string with itself\n ss = s + s\n \n # Try to find the original string s as a substring in the concatenated string,\n # starting from index 1 to avoid 0 as a trivial rotation.\n n = len(s)\n \n for i in range(1, n):\n # If the substring of ss starting at i and having length n is s,\n # then that index i is the minimum number of rotations needed.\n if ss[i:i+n] == s:\n return i\n \n return n # If no smaller rotation is found, then the string's length is the answer", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(s: str) -> int:\n \"\"\"\n Finds the minimum number of rotations greater than 0 required to get the same string.\n \n Parameters:\n s (str): The input string to find rotations for.\n \n Returns:\n int: The minimum number of rotations.\n \"\"\"\n n = len(s)\n \n # Double the string to simulate rotation easily\n doubled_s = s + s\n \n # Iterate through possible rotation starting points\n for i in range(1, n + 1):\n # If the substring of length n starting from i is equal to the original string,\n # then that's a valid rotation\n if doubled_s[i:i + n] == s:\n return i\n \n return n # In the worst case, it requires n rotations, but should never reach here for repeatable strings.", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(s: str) -> int:\n \"\"\"\n This function takes a string `s` and returns the minimum number of rotations\n (greater than 0) required to get the same string.\n \"\"\"\n n = len(s)\n # Concatenate the string with itself\n concatenated = s + s\n \n # Find the minimum rotation by checking when the second half contains the original string\n # We start checking from 1 to avoid zero rotations\n for i in range(1, n):\n if concatenated[i:i + n] == s:\n return i\n \n # In case there is no rotation found (though theoretically there should be one), return n\n return n", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(s):\n \"\"\"\n This function returns the minimum number of rotations (greater than 0) required to get the same string.\n \"\"\"\n # Length of the string\n n = len(s)\n \n # Iterate over possible rotations\n for i in range(1, n):\n # Check if the string is same as its rotation\n if s[i:] + s[:i] == s:\n return i\n \n # If no smaller rotation found, n is the smallest rotation\n return n", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(s: str) -> int:\n \"\"\"\n Function to find the minimum number of rotations required to get the same string.\n A rotation is defined as moving the first character of the string to the end.\n\n Args:\n s (str): The input string to be rotated.\n\n Returns:\n int: The minimum number of rotations greater than 0 to obtain the same string.\n \"\"\"\n # Length of the string\n n = len(s)\n \n # Concatenate the string with itself\n ss = s + s\n \n # Iterate from 1 to n to find the first point where the rotated substring matches the original string\n for i in range(1, n):\n # If the substring from i to i+n matches the original, we found our minimum rotation\n if ss[i:i+n] == s:\n return i\n \n # If no such rotation exists, though logically it should, we return the length of the string\n return n", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(s: str) -> int:\n \"\"\"\n Finds the minimum number of rotations (greater than 0) required to get the same string.\n \"\"\"\n n = len(s)\n # Try each rotation from 1 to n-1\n for i in range(1, n):\n # Generate the rotated string\n rotated = s[i:] + s[:i]\n # Check if it matches the original string\n if rotated == s:\n return i\n # If no rotations match, the full length is the answer (will not happen for a repetitive pattern like \"aaaa\")\n return n", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(s):\n \"\"\"\n Finds the minimum number of rotations required to obtain the same string.\n \n Parameters:\n s (str): The input string to check for rotations.\n \n Returns:\n int: The minimum number of rotations greater than 0 to return to the original string.\n \"\"\"\n n = len(s)\n \n # Iterate over possible rotations\n for i in range(1, n + 1):\n # Rotate the string by i positions\n rotated = s[i:] + s[:i]\n # Check if the rotation matches the original string\n if rotated == s:\n return i\n \n return n", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(s: str) -> int:\n \"\"\"\n This function finds the minimum number of rotations (greater than 0) required to get the same string.\n \n :param s: The input string.\n :return: The minimum number of rotations to get the same string.\n \"\"\"\n # Get the length of the string\n n = len(s)\n \n # Concatenate the string to itself\n concatenated = s + s\n \n # Iterate over possible rotation lengths\n for i in range(1, n + 1):\n # Check if the rotated version starting from i is equal to the original string\n if concatenated[i:i + n] == s:\n return i\n \n return n # Fallback case, should not reach here if input string is valid", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(s):\n \"\"\"\n This function finds the minimum number of rotations (greater than 0)\n required to get the same string. It uses the fact that by repeating\n the string and checking if the original string appears again\n at a certain position, we can determine the rotation count.\n \"\"\"\n # Concatenate the string to itself\n doubled = s + s\n \n # Find the smallest index where the original string can be seen again\n # Start checking from position 1, since rotation should be greater than 0\n for i in range(1, len(s)):\n if doubled[i:i+len(s)] == s:\n return i\n # If no valid rotation found (which should not be the case as per problem statement)\n return len(s)", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(s):\n \"\"\"\n Find the minimum number of rotations (greater than 0) required to get the same string.\n\n Parameters:\n s (str): The input string to check.\n\n Returns:\n int: The minimum number of rotations required.\n \"\"\"\n n = len(s)\n # concatenate the string with itself to handle rotations\n extended_s = s + s\n \n # We need to find the smallest rotation, hence we start checking from rotation 1\n for i in range(1, n + 1):\n # Check if the substring of length n starting from position i is same as original\n if extended_s[i:i + n] == s:\n return i", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(s: str) -> int:\n \"\"\"\n Returns the minimum number of rotations (greater than 0) required to get the same string.\n \"\"\"\n n = len(s)\n # Concatenate the string with itself\n double_s = s + s\n \n # Find the first occurrence of the original string in the concatenated string\n for i in range(1, n):\n if double_s[i:i+n] == s:\n return i\n return n", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(s: str) -> int:\n \"\"\"\n Find the minimum number of rotations (greater than 0) required to get the same string.\n \n :param s: The input string\n :return: Minimum number of rotations required\n \"\"\"\n if not s: # Handle edge case for empty string\n return 0\n \n # Create a new string by concatenating the input string to itself\n doubled_s = s + s\n \n # Iterate over possible rotation lengths (start from 1 to avoid zero rotation)\n for i in range(1, len(s) + 1):\n # Check if the substring of doubled_s of length equal to original string \n # starting from position i is equal to the original string\n if doubled_s[i:i+len(s)] == s:\n return i\n \n # In case no rotation found, should never reach here for non-empty strings\n return len(s)", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(s):\n \"\"\"\n This function finds the minimum number of rotations (greater than 0) required\n to get the same string. A rotation involves moving the first character of the\n string to the end of the string.\n \n Parameters:\n s (str): The input string to find rotations for.\n\n Returns:\n int: The minimum number of rotations needed to achieve the original string.\n \"\"\"\n n = len(s)\n # Double the string and search for the first occurrence of the original string\n doubled_s = s + s\n for i in range(1, n+1):\n # We slice the doubled string from index i to i+n to get rotations\n if doubled_s[i:i+n] == s:\n return i\n return n # If no rotation is found, which should not be the case for non-empty strings", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(s):\n \"\"\"\n This function finds the minimum number of rotations (greater than 0) \n required to get the original string 's' back.\n \"\"\"\n if not s:\n return 0 # If the string is empty, no rotations are needed\n\n # Concatenate the string with itself to simulate rotations\n doubled = s + s\n\n # Check each possible rotation length starting from 1 to len(s)\n for i in range(1, len(s) + 1):\n # If the rotated version matches the original string\n if doubled[i:i+len(s)] == s:\n return i\n\n # In a valid situation with non-empty string and the logic above,\n # it should always find a rotation, so no need for a default return value.", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(s: str) -> int:\n \"\"\"\n Finds the minimum number of rotations greater than 0 required to obtain the same string.\n \n :param s: The input string to analyze\n :return: The minimum number of rotations needed\n \"\"\"\n # Get the length of the string\n n = len(s)\n \n # Double the string\n doubled_s = s + s\n \n # Try each possible rotation length from 1 to n\n for i in range(1, n + 1):\n # Check if the substring of length n from position i is the same as the original string\n if doubled_s[i:i+n] == s:\n return i\n \n # If no such rotation is found (which theoretically shouldn't happen due to the problem constraints), return n\n return n", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(s):\n \"\"\"\n Function to find the minimum number of rotations (greater than 0) required to get the same string.\n \n Parameters:\n s (str): The input string\n \n Returns:\n int: The minimum number of rotations required to get the same string.\n \"\"\"\n n = len(s)\n # Double the string\n temp = s + s\n # Look for the string itself starting from the second character\n for i in range(1, n + 1):\n # Check if the substring of length n starting at i is equal to the original\n if temp[i:i + n] == s:\n return i\n return n", "matching_cluster_idx": 5}]}, "Mbpp/11": {"dps": 56.541218637992834, "dps_norm": 87.77777777777777, "pass@1": 49.0, "profiled": [{"solution": "def remove_Occ(s, char):\n \"\"\"\n Remove the first and last occurrence of the given character from the string.\n \n :param s: The input string.\n :param char: The character to remove from the string.\n :return: The string with the first and last occurrence of the character removed.\n \"\"\"\n first_index = s.find(char)\n last_index = s.rfind(char)\n \n if first_index == -1 or last_index == -1:\n return s\n \n # If the first and last index are the same, it means the character occurs only once.\n if first_index == last_index:\n return s[:first_index] + s[first_index+1:]\n \n # Remove character at first and last index\n return s[:first_index] + s[first_index+1:last_index] + s[last_index+1:]", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(s, char):\n \"\"\"\n Remove the first and last occurrence of the given character from the string.\n \n :param s: The string from which to remove the character.\n :param char: The character to be removed.\n :return: The modified string with the first and last occurrence of the character removed.\n \"\"\"\n # Find the index of the first occurrence of the character\n first_index = s.find(char)\n # Find the index of the last occurrence of the character\n last_index = s.rfind(char)\n\n # If the character is found\n if first_index != -1:\n # Remove the first occurrence\n s = s[:first_index] + s[first_index + 1:]\n # If first and last index were the same, update last_index after removal\n if first_index == last_index:\n last_index = -1\n else:\n # Adjust the last index by 1 since the string has shrunk by 1 char\n last_index -= 1\n\n # If the character is found again (for the last occurrence)\n if last_index != -1:\n # Remove the last occurrence\n s = s[:last_index] + s[last_index + 1:]\n\n return s", "matching_cluster_idx": 7}, {"solution": "def remove_Occ(s: str, ch: str) -> str:\n \"\"\"\n Removes the first and last occurrence of the specified character from the string.\n\n :param s: The input string.\n :param ch: The character to remove.\n :return: The string with the first and last occurrence of the character removed.\n \"\"\"\n # Find the first occurrence of ch\n first_occurrence = s.find(ch)\n if first_occurrence == -1:\n # If the character is not found, return the string as is\n return s\n\n # Remove the first occurrence\n s = s[:first_occurrence] + s[first_occurrence+1:]\n\n # Find the last occurrence of ch in the modified string\n last_occurrence = s.rfind(ch)\n if last_occurrence == -1:\n # If no other occurrence is found, just return the modified string\n return s\n\n # Remove the last occurrence\n s = s[:last_occurrence] + s[last_occurrence+1:]\n\n return s", "matching_cluster_idx": 7}, {"solution": "def remove_Occ(s: str, char: str) -> str:\n \"\"\"\n Remove the first and last occurrence of 'char' from the string 's'.\n \"\"\"\n # Find the first occurrence of the character\n first_pos = s.find(char)\n \n # Find the last occurrence of the character\n last_pos = s.rfind(char)\n \n # If the first and last positions are valid and different,\n # remove them. If they are the same, we remove only one.\n if first_pos == -1 or last_pos == -1:\n # If the character is not found, return the string unchanged\n return s\n \n # Remove the first occurrence by slicing\n if first_pos != last_pos:\n s = s[:first_pos] + s[first_pos+1:]\n last_pos -= 1 # Adjust last position after removing the first occurrence\n s = s[:last_pos] + s[last_pos+1:]\n else:\n # Only one occurrence, remove it\n s = s[:first_pos] + s[first_pos+1:]\n \n return s", "matching_cluster_idx": 7}, {"solution": "def remove_Occ(input_string, char_to_remove):\n # Convert input string to a list to allow mutation\n str_list = list(input_string)\n # Flag to check first and last occurrence removal\n first_removed = False\n last_removed = False\n \n # Remove the first occurrence\n for i, char in enumerate(str_list):\n if char == char_to_remove and not first_removed:\n str_list[i] = ''\n first_removed = True\n break\n\n # Remove the last occurrence (iterate from the end)\n for i in range(len(str_list) - 1, -1, -1):\n if str_list[i] == char_to_remove:\n str_list[i] = ''\n last_removed = True\n break\n\n # Convert list back to string and return\n return ''.join(str_list)", "matching_cluster_idx": 2}, {"solution": "def remove_Occ(s: str, char: str) -> str:\n # Find the first and last occurrence of the character\n first_index = s.find(char)\n last_index = s.rfind(char)\n \n # If the character is not found, return the string as is\n if first_index == -1:\n return s\n \n # If first and last indices are the same, we just remove that single occurrence\n if first_index == last_index:\n return s[:first_index] + s[first_index+1:]\n \n # Remove first and last occurrence by reconstructing the string\n return s[:first_index] + s[first_index+1:last_index] + s[last_index+1:]", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(s, char):\n # Find the first occurrence\n first_index = s.find(char)\n # Find the last occurrence\n last_index = s.rfind(char)\n \n # If the character is not found or only appears once\n if first_index == -1:\n return s\n if first_index == last_index:\n return s[:first_index] + s[first_index+1:]\n \n # Remove the first and last occurrence\n return s[:first_index] + s[first_index+1:last_index] + s[last_index+1:]", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(s, char):\n \"\"\"\n Remove the first and last occurrence of the specified character from the string.\n\n :param s: The input string\n :param char: The character to be removed\n :return: Modified string with the first and last occurrence of char removed\n \"\"\"\n # Find the first occurrence of the character\n first_occ = s.find(char)\n if first_occ == -1:\n # If the character is not found, return the original string\n return s\n \n # Find the last occurrence of the character\n last_occ = s.rfind(char)\n \n # If the first and last occurrences are the same, only one character to remove\n if first_occ == last_occ:\n return s[:first_occ] + s[first_occ+1:]\n \n # Remove the first occurrence\n s = s[:first_occ] + s[first_occ+1:]\n \n # After removing the first occurrence, adjust the index of the last occurrence\n last_occ -= 1\n \n # Remove the last occurrence\n s = s[:last_occ] + s[last_occ+1:]\n \n return s", "matching_cluster_idx": 7}, {"solution": "def remove_Occ(s: str, char: str) -> str:\n \"\"\"\n Remove the first and last occurrence of a given character from the string.\n\n :param s: The original string.\n :param char: The character to remove.\n :return: A new string with the first and last occurrence of char removed.\n \"\"\"\n # Find the first occurrence of the character\n first_occurrence = s.find(char)\n # Find the last occurrence of the character\n last_occurrence = s.rfind(char)\n \n # If the character is found at least once, remove the first and last occurrence\n if first_occurrence != -1:\n s = s[:first_occurrence] + s[first_occurrence + 1:]\n # Adjust the index for the last occurrence since the string is modified\n last_occurrence = s.rfind(char)\n \n if last_occurrence != -1:\n s = s[:last_occurrence] + s[last_occurrence + 1:]\n\n return s", "matching_cluster_idx": 7}, {"solution": "def remove_Occ(s, char):\n \"\"\"\n Remove the first and last occurrence of char from the string s.\n \"\"\"\n # Find the index of the first occurrence of char\n first_index = s.find(char)\n \n # Find the index of the last occurrence of char\n last_index = s.rfind(char)\n \n # If the character is not found at all, return the original string\n if first_index == -1:\n return s\n \n # Remove the first occurrence\n if first_index == last_index:\n # If they are the same, it means char occurs only once\n # So we can remove it\n s = s[:first_index] + s[first_index + 1:]\n else:\n # Remove first occurrence\n s = s[:first_index] + s[first_index + 1:]\n # Adjust last_index after removal of first occurrence\n last_index -= 1\n # Remove last occurrence\n s = s[:last_index] + s[last_index + 1:]\n \n return s", "matching_cluster_idx": 7}, {"solution": "def remove_Occ(input_string, char_to_remove):\n # Find the first occurrence of the character\n first_occurrence = input_string.find(char_to_remove)\n \n # If the character is not found, return the original string\n if first_occurrence == -1:\n return input_string\n \n # Find the last occurrence of the character\n last_occurrence = input_string.rfind(char_to_remove)\n\n # If both occurrences are the same, remove the single occurrence\n if first_occurrence == last_occurrence:\n return input_string[:first_occurrence] + input_string[first_occurrence + 1:]\n \n # Remove the first and last occurrence\n # Remove the last occurrence first to not affect the index of the first occurrence\n modified_string = (input_string[:last_occurrence] + input_string[last_occurrence + 1:])\n modified_string = (modified_string[:first_occurrence] + modified_string[first_occurrence + 1:])\n \n return modified_string", "matching_cluster_idx": 7}, {"solution": "def remove_Occ(s, char):\n \"\"\"\n Removes the first and last occurrence of the specified character from the given string.\n\n Parameters:\n s (str): The input string.\n char (str): The character to remove from the string.\n\n Returns:\n str: The modified string with the first and last occurrence of the character removed.\n \"\"\"\n first_pos = s.find(char)\n last_pos = s.rfind(char)\n \n # If the character is not found, return the string as is\n if first_pos == -1:\n return s\n \n # If the first and last occurrence are the same, remove only one occurrence\n if first_pos == last_pos:\n return s[:first_pos] + s[first_pos+1:]\n \n # Construct the new string\n modified_string = s[:first_pos] + s[first_pos+1:last_pos] + s[last_pos+1:]\n \n return modified_string", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(s, ch):\n \"\"\"\n Removes the first and last occurrence of the given character 'ch' from the string 's'.\n \n :param s: The input string\n :param ch: The character to remove the first and last occurrence of\n :return: A new string with the first and last occurrence of 'ch' removed\n \"\"\"\n first_pos = s.find(ch)\n last_pos = s.rfind(ch)\n \n if first_pos == -1:\n # Character is not found in the string\n return s\n \n # Create a new string with the first and last occurrence removed\n new_string = s[:first_pos] + s[first_pos+1:last_pos] + s[last_pos+1:]\n \n return new_string", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(input_string, char_to_remove):\n \"\"\"\n Removes the first and last occurrence of a given character from the string.\n\n :param input_string: The string from which characters are to be removed.\n :param char_to_remove: The character that needs to be removed.\n :return: A new string with the first and last occurrence of the character removed.\n \"\"\"\n # Find the first occurrence of the character\n first_occurrence_index = input_string.find(char_to_remove)\n if first_occurrence_index == -1:\n # If the character is not found, return the string as is\n return input_string\n\n # Find the last occurrence of the character\n last_occurrence_index = input_string.rfind(char_to_remove)\n\n # If the first and last occurrence are the same, remove just that one\n if first_occurrence_index == last_occurrence_index:\n return input_string[:first_occurrence_index] + input_string[first_occurrence_index + 1:]\n\n # Construct the new string without the first and last occurrences\n result_string = (\n input_string[:first_occurrence_index] + \n input_string[first_occurrence_index + 1:last_occurrence_index] + \n input_string[last_occurrence_index + 1:]\n )\n \n return result_string", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(s, char):\n first_index = s.find(char)\n last_index = s.rfind(char)\n \n if first_index == -1: # Character not found in the string\n return s\n \n if first_index == last_index: # Character occurs only once\n return s[:first_index] + s[first_index+1:]\n \n # Remove first occurrence\n s = s[:first_index] + s[first_index+1:]\n \n # Remove last occurrence, adjust the index because we already removed one occurrence\n last_index -= 1\n s = s[:last_index] + s[last_index+1:]\n \n return s", "matching_cluster_idx": 7}, {"solution": "def remove_Occ(s: str, char: str) -> str:\n \"\"\"\n Remove the first and last occurrence of the given character 'char' from the string 's'.\n \n Parameters:\n s (str): The input string from which the character will be removed.\n char (str): The character to be removed.\n \n Returns:\n str: The string with the first and last occurrence of 'char' removed.\n \"\"\"\n first_pos = s.find(char)\n last_pos = s.rfind(char)\n \n if first_pos == -1:\n # If the character does not exist, return the string as is\n return s\n \n # Remove the first occurrence\n if first_pos == last_pos:\n # If there's only one occurrence, just remove it\n s = s[:first_pos] + s[first_pos+1:]\n else:\n # Otherwise, remove the first and last occurrence\n s = s[:first_pos] + s[first_pos+1:last_pos] + s[last_pos+1:]\n \n return s", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(s: str, char: str) -> str:\n \"\"\"\n Removes the first and last occurrence of the given character from the string.\n \n Parameters:\n s (str): The original string.\n char (str): The character to remove.\n\n Returns:\n str: The modified string with the first and last occurrence of the character removed.\n \"\"\"\n first_pos = s.find(char)\n last_pos = s.rfind(char)\n\n # If the character is not found or is found only once, return the string as is\n if first_pos == -1:\n return s\n\n if first_pos == last_pos:\n # The character appears only once, so we return the string without that character\n return s[:first_pos] + s[first_pos+1:]\n\n # Remove the first occurrence\n s = s[:first_pos] + s[first_pos+1:]\n \n # Adjust the last position since we've removed one character\n last_pos -= 1\n\n # Remove the last occurrence\n s = s[:last_pos] + s[last_pos+1:]\n \n return s", "matching_cluster_idx": 7}, {"solution": "def remove_Occ(s: str, ch: str) -> str:\n \"\"\"\n Removes the first and last occurrence of the given character 'ch' from the string 's'.\n \n :param s: The input string from which to remove the character.\n :param ch: The character to remove from the string.\n :return: The string after removing the first and last occurrences of 'ch'.\n \"\"\"\n # Find the index of the first occurrence of the character\n first_index = s.find(ch)\n \n # If the character is not found, return the original string\n if first_index == -1:\n return s\n \n # Find the index of the last occurrence of the character\n last_index = s.rfind(ch)\n \n # If the first and last occurrences are the same, it means there's only one occurrence\n if first_index == last_index:\n return s[:first_index] + s[first_index+1:]\n\n # Remove the character at the first and last occurrence\n s = s[:first_index] + s[first_index+1:last_index] + s[last_index+1:]\n \n return s", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(s: str, ch: str) -> str:\n \"\"\"\n Removes the first and last occurrence of the given character ch from the string s.\n \"\"\"\n # Convert the string to a list for easy manipulation\n s_list = list(s)\n \n # Remove first occurrence\n try:\n first_index = s_list.index(ch)\n s_list.pop(first_index)\n except ValueError:\n pass # Character not found\n \n # Remove last occurrence\n try:\n last_index = len(s_list) - s_list[::-1].index(ch) - 1\n s_list.pop(last_index)\n except ValueError:\n pass # Character not found\n \n # Convert the list back to a string\n return ''.join(s_list)", "matching_cluster_idx": 1}, {"solution": "def remove_Occ(input_string, char_to_remove):\n \"\"\"\n Remove the first and last occurrence of a given character from the string.\n \"\"\"\n # Find the first occurrence of the character\n first_occurrence = input_string.find(char_to_remove)\n \n # Find the last occurrence of the character\n last_occurrence = input_string.rfind(char_to_remove)\n \n # If the character is not found at all, return the string as is\n if first_occurrence == -1 and last_occurrence == -1:\n return input_string\n\n # If the first and last occurrence are the same, we only need to remove it once\n if first_occurrence == last_occurrence:\n return input_string[:first_occurrence] + input_string[first_occurrence + 1:]\n\n # Remove the character at the first and last occurrence\n new_string = (\n input_string[:first_occurrence] + \n input_string[first_occurrence + 1:last_occurrence] +\n input_string[last_occurrence + 1:]\n )\n \n return new_string", "matching_cluster_idx": 8}]}, "Mbpp/12": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def sort_matrix(matrix):\n \"\"\"\n Sort a matrix in ascending order according to the sum of its rows.\n \n :param matrix: List of lists where each sublist represents a row in the matrix.\n :return: A new matrix sorted based on the sum of each row.\n \"\"\"\n # Sort the matrix using the sum of each row as the key\n sorted_matrix = sorted(matrix, key=sum)\n return sorted_matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Sort the matrix rows based on the sum of each row\n return sorted(matrix, key=sum)\nmatrix = [[1, 2, 3], [2, 4, 5], [1, 1, 1]]", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"\n Sort a given matrix in ascending order according to the sum of its rows.\n\n Args:\n matrix (list of list of int): A list of lists where each inner list represents a row of the matrix.\n\n Returns:\n list of list of int: The matrix sorted by the sum of its rows in ascending order.\n \"\"\"\n # Use sorted with a key that sorts based on the sum of each row\n sorted_matrix = sorted(matrix, key=sum)\n return sorted_matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"\n Sorts a matrix in ascending order based on the sum of its rows.\n \n Parameters:\n matrix (list of list of int): A matrix represented as a list of lists of integers.\n \n Returns:\n list of list of int: The sorted matrix.\n \"\"\"\n # Calculate the sum of each row and use it as the sorting key\n sorted_matrix = sorted(matrix, key=sum)\n return sorted_matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"\n Sorts a given matrix in ascending order based on the sum of its rows.\n\n Args:\n matrix (list of list of int): A 2D list representing the matrix.\n\n Returns:\n list of list of int: The sorted matrix.\n \"\"\"\n # Sort the matrix based on the sum of each row\n return sorted(matrix, key=sum)", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Sort the matrix by the sum of its rows\n sorted_matrix = sorted(matrix, key=sum)\n return sorted_matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"\n Sorts a given matrix in ascending order according to the sum of its rows.\n\n Args:\n matrix (list of list of int): A 2D list representing the matrix.\n\n Returns:\n list of list of int: The matrix sorted by the sum of its rows in ascending order.\n \"\"\"\n # Use sorted with a key that calculates the sum of each row\n return sorted(matrix, key=sum)", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"\n Sorts a given matrix in ascending order according to the sum of its rows.\n\n Parameters:\n matrix (list of list of int): A 2D list where each sublist represents a row of the matrix.\n\n Returns:\n list of list of int: The matrix sorted by the sum of its rows.\n \"\"\"\n # Use the sorted function with a custom key that calculates the sum of each row\n return sorted(matrix, key=lambda row: sum(row))", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"\n Sort the given matrix in ascending order according to the sum of its rows.\n\n :param matrix: A list of lists, where each inner list represents a row of the matrix.\n :return: A new list of lists, where the rows are sorted by their sum.\n \"\"\"\n # Use Python's sorted function with a custom key that sorts rows based on the sum of elements in each row\n return sorted(matrix, key=sum)", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"\n Sort a given matrix in ascending order according to the sum of its rows.\n \n :param matrix: A list of lists where each inner list represents a row of the matrix.\n :return: A list of lists representing the matrix sorted by the sum of its rows.\n \"\"\"\n # Sort the matrix based on the sum of each row\n sorted_matrix = sorted(matrix, key=sum)\n return sorted_matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Sort the matrix rows based on the sum of each row\n return sorted(matrix, key=sum)\nmatrix = [[1, 2, 3], [2, 4, 5], [1, 1, 1]]", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"\n Sort a matrix in ascending order according to the sum of its rows.\n\n Parameters:\n matrix (list of lists): A list of lists where each inner list represents a row of the matrix.\n\n Returns:\n list of lists: The input matrix sorted by the sum of its rows.\n \"\"\"\n # Use the sorted function with a key that is the sum of the rows\n return sorted(matrix, key=sum)", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"\n Sorts a given matrix in ascending order according to the sum of its rows.\n\n :param matrix: List[List[int]], a 2D list representing the matrix.\n :return: List[List[int]], the sorted matrix.\n \"\"\"\n return sorted(matrix, key=sum)", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"\n Sorts the given matrix in ascending order according to the sum of its rows.\n \n :param matrix: A list of lists, where each sub-list represents a row of the matrix.\n :return: A new list of lists sorted based on the sum of each row.\n \"\"\"\n # Sort the matrix rows based on the sum of the rows\n sorted_matrix = sorted(matrix, key=sum)\n return sorted_matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"\n Sorts the matrix in ascending order based on the sum of its rows.\n\n :param matrix: List of lists where each inner list represents a row of the matrix.\n :return: A new matrix sorted according to the sum of its rows.\n \"\"\"\n return sorted(matrix, key=sum)\nmatrix = [[1, 2, 3], [2, 4, 5], [1, 1, 1]]", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"\n Sorts a matrix in ascending order according to the sum of its rows.\n \n Args:\n matrix (list of list of int): The input 2D matrix to be sorted.\n \n Returns:\n list of list of int: The sorted matrix based on the sum of its rows.\n \"\"\"\n # Sort the matrix using the sum of each row as the key.\n sorted_matrix = sorted(matrix, key=lambda row: sum(row))\n return sorted_matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"\n Sorts the matrix in ascending order according to the sum of its rows.\n \n Args:\n matrix (list of list of int): A matrix to be sorted.\n \n Returns:\n list of list of int: The sorted matrix.\n \"\"\"\n return sorted(matrix, key=sum)", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"\n Sort a matrix in ascending order based on the sum of its rows.\n\n Parameters:\n matrix (list of list of int): The matrix to be sorted.\n\n Returns:\n list of list of int: The sorted matrix.\n \"\"\"\n # Use the sorted function with a key that computes the sum of each row\n sorted_matrix = sorted(matrix, key=sum)\n return sorted_matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"\n Sorts a given matrix in ascending order according to the sum of its rows.\n \n Parameters:\n matrix (list of list of int): A 2D list where each sublist represents a row of the matrix.\n \n Returns:\n list of list of int: The matrix sorted by the row sums.\n \"\"\"\n # Sort the matrix by the sum of each row\n sorted_matrix = sorted(matrix, key=sum)\n return sorted_matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Sort the matrix based on the sum of each row\n return sorted(matrix, key=sum)\nmatrix = [[1, 2, 3], [2, 4, 5], [1, 1, 1]]", "matching_cluster_idx": 15}]}, "Mbpp/16": {"dps": 96.76829268292683, "dps_norm": 97.5, "pass@1": 57.0, "profiled": [{"solution": "def text_lowercase_underscore(s):\n # Import the regular expression module\n import re\n \n # Define a regular expression pattern\n # ^ and $ anchor the pattern to the start and end of the string\n # (?:[a-z]+) matches one or more lowercase letters as a group\n # (?:_[a-z]+)* matches zero or more sequences of an underscore followed by one or more lowercase letters\n pattern = r'^[a-z]+(?:_[a-z]+)*$'\n \n # Use re.match to check if the entire string matches the pattern\n match = re.match(pattern, s)\n \n # If match is not None, it means the string matches the pattern\n return match is not None", "matching_cluster_idx": 7}, {"solution": "import re\ndef text_lowercase_underscore(s: str) -> bool:\n # This regex checks if the string consists only of lowercase letters and underscores,\n # and that sequences of lowercase letters are joined by underscores without any other characters.\n pattern = r'^[a-z]+(_[a-z]+)*$'\n return bool(re.match(pattern, s))", "matching_cluster_idx": 7}, {"solution": "import re\ndef text_lowercase_underscore(s):\n \"\"\"\n Returns True if the input string contains sequences of lowercase letters \n joined with an underscore and False otherwise.\n \"\"\"\n # Regular expression to match sequences of lowercase letters separated by underscores\n pattern = r'^[a-z]+(_[a-z]+)*$'\n \n # Use the fullmatch method to ensure the entire string matches the pattern\n return bool(re.fullmatch(pattern, s))", "matching_cluster_idx": 7}, {"solution": "import re\ndef text_lowercase_underscore(s: str) -> bool:\n # Use a regular expression to match sequences of lowercase letters joined by underscores\n # The pattern should look like this: \"^[a-z]+(_[a-z]+)*$\"\n # This means start (^) with one or more lowercase letters ([a-z]+)\n # followed by zero or more (_[a-z]+) which is an underscore followed by one or more lowercase letters\n # and end with this pattern ($).\n pattern = r'^[a-z]+(_[a-z]+)*$'\n return bool(re.match(pattern, s))", "matching_cluster_idx": 7}, {"solution": "def text_lowercase_underscore(s: str) -> bool:\n # Split the string by underscore\n parts = s.split('_')\n # Check if each part is a lowercase alphabetic string\n return all(part.islower() and part.isalpha() for part in parts)", "matching_cluster_idx": 5}, {"solution": "import re\ndef text_lowercase_underscore(s):\n # This pattern matches strings consisting of one or more sequences of lowercase\n # letters joined by underscores.\n pattern = r'^[a-z]+(_[a-z]+)*$'\n return bool(re.match(pattern, s))", "matching_cluster_idx": 7}, {"solution": "def text_lowercase_underscore(s: str) -> bool:\n \"\"\"\n Check if the string contains sequences of lowercase letters joined with an underscore.\n \"\"\"\n import re\n # Use a regular expression to match the pattern\n pattern = re.compile(r'^[a-z]+(_[a-z]+)*$')\n return bool(pattern.match(s))", "matching_cluster_idx": 7}, {"solution": "import re\ndef text_lowercase_underscore(s):\n # Check if the string matches the pattern of lowercase letters joined by underscores\n pattern = r'^[a-z]+(_[a-z]+)*$'\n return bool(re.match(pattern, s))", "matching_cluster_idx": 7}, {"solution": "import re\ndef text_lowercase_underscore(s):\n \"\"\"\n Returns True if the input string contains sequences of lowercase letters joined with an underscore.\n \"\"\"\n # The pattern matches one or more sequences of lowercase letters separated by underscores\n pattern = r'^[a-z]+(_[a-z]+)*$'\n return bool(re.match(pattern, s))", "matching_cluster_idx": 7}, {"solution": "def text_lowercase_underscore(s: str) -> bool:\n import re\n # The regex pattern checks for sequences of lowercase letters joined by underscores\n pattern = r'^[a-z]+(_[a-z]+)*$'\n match = re.match(pattern, s)\n return match is not None", "matching_cluster_idx": 7}, {"solution": "import re\ndef text_lowercase_underscore(s: str) -> bool:\n # The regex pattern matches sequences of lowercase letters joined by underscores.\n pattern = r'^[a-z]+(_[a-z]+)*$'\n return bool(re.match(pattern, s))", "matching_cluster_idx": 7}, {"solution": "def text_lowercase_underscore(s: str) -> bool:\n \"\"\"\n Returns True if the input string contains sequences of lowercase letters joined with an underscore.\n Otherwise, returns False.\n \"\"\"\n import re\n\n # Define the regex pattern for sequences of lowercase letters joined with an underscore\n pattern = r'^[a-z]+(_[a-z]+)*$'\n\n # Use fullmatch to check if the entire string matches the pattern\n return bool(re.fullmatch(pattern, s))", "matching_cluster_idx": 7}, {"solution": "import re\ndef text_lowercase_underscore(s):\n # Use a regular expression to check the pattern of sequences of lowercase letters joined with underscores\n pattern = re.compile(r'^[a-z]+(_[a-z]+)*$')\n return bool(pattern.match(s))", "matching_cluster_idx": 7}, {"solution": "import re\ndef text_lowercase_underscore(s: str) -> bool:\n # This regular expression checks for sequences of lowercase letters joined with an underscore.\n pattern = re.compile(r'^[a-z]+(_[a-z]+)*$')\n return bool(pattern.match(s))", "matching_cluster_idx": 7}, {"solution": "import re\ndef text_lowercase_underscore(s: str) -> bool:\n \"\"\"\n Returns True if the input string contains sequences of lowercase letters \n joined with an underscore, False otherwise.\n \"\"\"\n # Pattern to match one or more sequences of lowercase letters joined by underscores\n pattern = r'^[a-z]+(_[a-z]+)*$'\n return bool(re.match(pattern, s))", "matching_cluster_idx": 7}, {"solution": "import re\ndef text_lowercase_underscore(s):\n \"\"\"\n Returns True if the input string contains sequences of lowercase letters joined with an underscore\n and False otherwise.\n \"\"\"\n # Regular expression pattern to match sequences of lowercase letters joined with underscores\n pattern = r'^[a-z]+(_[a-z]+)*$'\n \n # Use re.match to check if the whole string fits the pattern\n return bool(re.match(pattern, s))", "matching_cluster_idx": 7}, {"solution": "import re\ndef text_lowercase_underscore(s):\n # Use a regular expression to match the pattern of lowercase sequences joined by underscores\n pattern = r'^[a-z]+(?:_[a-z]+)*$'\n return bool(re.match(pattern, s))", "matching_cluster_idx": 7}, {"solution": "def text_lowercase_underscore(s):\n \"\"\"\n Returns True if the input string contains sequences of lowercase\n letters joined with an underscore and False otherwise.\n \"\"\"\n # Split the string by underscores\n parts = s.split('_')\n \n # Check each part to see if it is composed entirely of lowercase letters\n for part in parts:\n if not part.islower() or not part.isalpha():\n return False\n\n # If all parts are lowercase letters, return True\n return True", "matching_cluster_idx": 5}, {"solution": "import re\ndef text_lowercase_underscore(s: str) -> bool:\n # Use a regex pattern to match sequences of lowercase letters joined by underscores\n pattern = r'^[a-z]+(_[a-z]+)*$'\n return bool(re.match(pattern, s))", "matching_cluster_idx": 7}, {"solution": "import re\ndef text_lowercase_underscore(input_string: str) -> bool:\n # Define a regular expression pattern that matches sequences of lowercase letters joined by underscores\n pattern = r'^[a-z]+(_[a-z]+)*$'\n # Use the fullmatch method to check if the entire string matches the pattern\n return bool(re.fullmatch(pattern, input_string))", "matching_cluster_idx": 7}]}, "Mbpp/19": {"dps": 87.62626262626263, "dps_norm": 93.0, "pass@1": 100.0, "profiled": [{"solution": "def test_duplicate(arr):\n \"\"\"\n This function checks if there are any duplicate elements in the given array.\n \n Parameters:\n arr (list): A list of integers to check for duplicates.\n\n Returns:\n bool: True if duplicates are found, False otherwise.\n \"\"\"\n # Convert the list to a set to remove duplicates\n unique_elements = set(arr)\n \n # Compare the length of the set and the original list\n return len(unique_elements) != len(arr)", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(arr):\n \"\"\"\n Returns True if the array contains duplicate elements, False otherwise.\n \"\"\"\n seen = set()\n for num in arr:\n if num in seen:\n return True\n seen.add(num)\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(arr):\n \"\"\"\n Function to determine if there are any duplicate elements in the array.\n\n :param arr: List of integers\n :return: True if there are duplicates, False otherwise\n \"\"\"\n # Convert the list to a set, which removes duplicates\n return len(arr) != len(set(arr))", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(arr):\n \"\"\"\n Function to determine if the given list of integers contains any duplicates.\n \n Parameters:\n arr (list): A list of integers.\n \n Returns:\n bool: True if there are duplicates, False otherwise.\n \"\"\"\n seen = set()\n for num in arr:\n if num in seen:\n return True\n seen.add(num)\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(arr):\n \"\"\"\n Check if the given array contains any duplicate elements.\n\n Parameters:\n arr (list): A list of integers to be checked.\n\n Returns:\n bool: True if any duplicates are found, False otherwise.\n \"\"\"\n seen = set()\n for num in arr:\n if num in seen:\n return True\n seen.add(num)\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(arr):\n \"\"\"\n This function checks if the given array contains any duplicate elements.\n :param arr: A list of integers\n :return: True if there are duplicate elements, False otherwise\n \"\"\"\n # Convert the list to a set and compare its length to the original list\n return len(arr) != len(set(arr))", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(arr):\n \"\"\"\n Function to determine if there are any duplicate elements in an array of integers.\n \n Parameters:\n arr (list): List of integers to check for duplicates.\n\n Returns:\n bool: True if there are duplicates, False otherwise.\n \"\"\"\n # Create a set to store unique elements\n seen = set()\n for num in arr:\n if num in seen:\n return True\n seen.add(num)\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(arr):\n \"\"\"\n This function checks whether the input array contains any duplicate elements.\n \n Parameters:\n arr (list of int): The list of integers to check for duplicates.\n \n Returns:\n bool: True if there are duplicate elements in the array, False otherwise.\n \"\"\"\n # Use a set to track seen elements\n seen = set()\n for num in arr:\n if num in seen:\n return True\n seen.add(num)\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(arr):\n \"\"\"\n This function checks if there are any duplicate elements in the given array of integers.\n \n Parameters:\n arr (list): A list of integers.\n \n Returns:\n bool: True if there is at least one duplicate, False otherwise.\n \"\"\"\n seen = set()\n for num in arr:\n if num in seen:\n return True\n seen.add(num)\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(arr):\n \"\"\"\n This function checks if there are any duplicate elements in the given array.\n It returns True if duplicates are found, otherwise False.\n \"\"\"\n seen = set()\n for number in arr:\n if number in seen:\n return True\n seen.add(number)\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(arr):\n \"\"\"\n This function checks if the given array contains any duplicate elements.\n \n Args:\n arr (list): A list of integers.\n \n Returns:\n bool: True if there are duplicates in the list, False otherwise.\n \"\"\"\n # We use a set to track elements we have seen.\n seen = set()\n for num in arr:\n if num in seen:\n return True\n seen.add(num)\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(arr):\n \"\"\"\n Checks if the given list contains any duplicate elements.\n\n Parameters:\n arr (list of int): The list of integers to check for duplicates.\n\n Returns:\n bool: True if there are duplicates, False otherwise.\n \"\"\"\n return len(arr) != len(set(arr))", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(arr):\n \"\"\"\n Checks if the given array contains any duplicate elements.\n\n Parameters:\n arr (list of int): The array of integers to check for duplicates.\n\n Returns:\n bool: True if there are duplicates, False otherwise.\n \"\"\"\n seen = set()\n for num in arr:\n if num in seen:\n return True\n seen.add(num)\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(arr):\n \"\"\"\n This function checks if there are any duplicate elements in the given array.\n \n :param arr: List of integers\n :return: True if there are duplicates, False otherwise\n \"\"\"\n return len(arr) != len(set(arr))", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(arr):\n \"\"\"\n Function to check if there are any duplicates in the list of integers.\n\n :param arr: List of integers\n :return: True if there are duplicates, False otherwise\n \"\"\"\n # Create a set to track unique elements\n seen = set()\n \n for num in arr:\n if num in seen:\n return True\n seen.add(num)\n \n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(arr):\n \"\"\"\n Function to determine if there are any duplicate elements in the given array.\n\n Args:\n arr (list): A list of integers.\n\n Returns:\n bool: True if duplicates exist, False otherwise.\n \"\"\"\n seen = set()\n for num in arr:\n if num in seen:\n return True\n seen.add(num)\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(arr):\n \"\"\"\n Check if the given array of integers contains any duplicate elements.\n \n Parameters:\n arr (list): The list of integers to check for duplicates.\n\n Returns:\n bool: True if there are duplicates, False otherwise.\n \"\"\"\n return len(arr) != len(set(arr))", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(arr):\n \"\"\"\n This function checks if there are any duplicate elements in the input array.\n Returns True if duplicates are found, otherwise False.\n \"\"\"\n # Using a set to track elements seen so far\n seen = set()\n for element in arr:\n if element in seen:\n return True\n seen.add(element)\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(arr):\n \"\"\"\n Function to check if there are any duplicate elements in the array.\n \n :param arr: List of integers\n :return: True if there are duplicates, False otherwise\n \"\"\"\n # Use a set to track seen elements\n seen = set()\n \n for number in arr:\n if number in seen:\n return True\n seen.add(number)\n \n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(nums):\n \"\"\"\n This function checks if there are any duplicate numbers in the list.\n \n :param nums: List of integers\n :return: Boolean, True if there is at least one duplicate, False otherwise\n \"\"\"\n # Convert the list to a set and compare its size to the original list's size\n return len(nums) != len(set(nums))", "matching_cluster_idx": 11}]}, "Mbpp/62": {"dps": 68.15384615384616, "dps_norm": 81.0, "pass@1": 100.0, "profiled": [{"solution": "def smallest_num(lst):\n \"\"\"Return the smallest number in the list.\"\"\"\n if not lst:\n raise ValueError(\"List is empty\")\n return min(lst)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(numbers):\n if not numbers: # Check if the list is empty\n return None # Return None for an empty list\n smallest = numbers[0]\n for num in numbers:\n if num < smallest:\n smallest = num\n return smallest", "matching_cluster_idx": 3}, {"solution": "def smallest_num(numbers):\n \"\"\"\n Returns the smallest number in the list 'numbers'.\n \n :param numbers: List of integers.\n :return: The smallest integer in the list.\n \"\"\"\n if not numbers:\n raise ValueError(\"The list is empty.\")\n return min(numbers)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(numbers):\n \"\"\"\n Returns the smallest number in a list.\n \"\"\"\n if not numbers:\n raise ValueError(\"The list should not be empty.\")\n min_num = numbers[0]\n for num in numbers:\n if num < min_num:\n min_num = num\n return min_num", "matching_cluster_idx": 3}, {"solution": "def smallest_num(numbers):\n \"\"\"Return the smallest number in a list.\"\"\"\n if not numbers:\n raise ValueError(\"The list is empty\")\n smallest = numbers[0]\n for num in numbers:\n if num < smallest:\n smallest = num\n return smallest", "matching_cluster_idx": 3}, {"solution": "def smallest_num(numbers):\n \"\"\"\n This function takes a list of numbers and returns the smallest number in the list.\n \n :param numbers: List of integers.\n :return: The smallest integer in the list.\n \"\"\"\n if not numbers:\n raise ValueError(\"The list should not be empty.\")\n \n smallest = numbers[0]\n for number in numbers[1:]:\n if number < smallest:\n smallest = number\n return smallest", "matching_cluster_idx": 2}, {"solution": "def smallest_num(lst):\n if not lst:\n raise ValueError(\"List is empty\")\n smallest = lst[0]\n for num in lst:\n if num < smallest:\n smallest = num\n return smallest", "matching_cluster_idx": 3}, {"solution": "def smallest_num(numbers):\n \"\"\"Returns the smallest number in a list.\"\"\"\n if not numbers: # Check if the list is empty\n raise ValueError(\"List is empty\")\n \n smallest = numbers[0]\n for num in numbers[1:]:\n if num < smallest:\n smallest = num\n return smallest", "matching_cluster_idx": 2}, {"solution": "def smallest_num(numbers):\n \"\"\"\n Returns the smallest number in a list of numbers.\n \n Parameters:\n numbers (list): A list of numbers.\n \n Returns:\n int/float: The smallest number in the list.\n \"\"\"\n if not numbers: # Check for an empty list\n raise ValueError(\"The list is empty\")\n \n # Use Python's built-in min function to find the smallest number\n return min(numbers)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(numbers):\n \"\"\"Return the smallest number in the given list of numbers.\"\"\"\n if not numbers:\n raise ValueError(\"The list should not be empty.\")\n smallest = numbers[0]\n for number in numbers:\n if number < smallest:\n smallest = number\n return smallest", "matching_cluster_idx": 3}, {"solution": "def smallest_num(numbers):\n \"\"\"Return the smallest number in the given list of numbers.\"\"\"\n if not numbers:\n raise ValueError(\"The list should not be empty\")\n # Start with the assumption that the first element is the smallest\n min_num = numbers[0]\n # Iterate through the list, updating min_num if a smaller number is found\n for num in numbers:\n if num < min_num:\n min_num = num\n return min_num", "matching_cluster_idx": 3}, {"solution": "def smallest_num(numbers):\n \"\"\"Return the smallest number in the list.\"\"\"\n if not numbers:\n raise ValueError(\"The list is empty\")\n smallest = numbers[0]\n for num in numbers:\n if num < smallest:\n smallest = num\n return smallest", "matching_cluster_idx": 3}, {"solution": "def smallest_num(numbers):\n \"\"\"\n Function to find the smallest number in a list.\n \n Parameters:\n numbers (list): A list of numbers.\n \n Returns:\n int/float: The smallest number in the list.\n \"\"\"\n if not numbers: # Check if the list is empty\n raise ValueError(\"The list is empty\")\n \n # Initialize the smallest number with the first element\n min_num = numbers[0]\n \n # Iterate through the list to find the smallest number\n for num in numbers:\n if num < min_num:\n min_num = num\n \n return min_num", "matching_cluster_idx": 3}, {"solution": "def smallest_num(numbers):\n \"\"\"Return the smallest number in the given list.\"\"\"\n if not numbers:\n raise ValueError(\"The list is empty\")\n \n smallest = numbers[0]\n for num in numbers[1:]:\n if num < smallest:\n smallest = num\n return smallest", "matching_cluster_idx": 2}, {"solution": "def smallest_num(numbers):\n \"\"\"\n Function to find the smallest number in a list.\n \n Args:\n numbers (list): A list of numbers.\n \n Returns:\n int/float: The smallest number in the list.\n \"\"\"\n if not numbers:\n raise ValueError(\"The list is empty\")\n return min(numbers)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(numbers):\n if not numbers: # Check if the list is empty\n return None\n # Initialize the smallest number with the first element of the list\n smallest = numbers[0]\n # Iterate over the list and find the smallest number\n for num in numbers:\n if num < smallest:\n smallest = num\n return smallest", "matching_cluster_idx": 3}, {"solution": "def smallest_num(lst):\n \"\"\"\n This function takes a list of numbers and returns the smallest number.\n \"\"\"\n if not lst:\n raise ValueError(\"The list is empty.\")\n \n # Initialize the smallest number with the first element of the list\n smallest = lst[0]\n \n # Loop through the list to find the smallest number\n for num in lst:\n if num < smallest:\n smallest = num\n \n return smallest", "matching_cluster_idx": 3}, {"solution": "def smallest_num(numbers):\n \"\"\"\n Find the smallest number in a list.\n\n :param numbers: List of numbers\n :return: The smallest number in the list\n \"\"\"\n if not numbers:\n raise ValueError(\"The list cannot be empty\")\n \n # Initialize the minimum with the first element\n min_num = numbers[0]\n \n # Iterate through the list and find the smallest number\n for num in numbers:\n if num < min_num:\n min_num = num\n \n return min_num", "matching_cluster_idx": 3}, {"solution": "def smallest_num(numbers):\n \"\"\"\n This function takes a list of numbers and returns the smallest number in the list.\n \"\"\"\n if not numbers:\n raise ValueError(\"The list is empty. Cannot determine the smallest number.\")\n\n # Initialize the smallest number with the first element of the list\n smallest = numbers[0]\n \n # Iterate through the list to find the smallest number\n for num in numbers:\n if num < smallest:\n smallest = num\n \n return smallest", "matching_cluster_idx": 3}, {"solution": "def smallest_num(lst):\n \"\"\"Finds the smallest number in a list.\"\"\"\n if not lst:\n raise ValueError(\"List is empty\")\n smallest = lst[0]\n for num in lst:\n if num < smallest:\n smallest = num\n return smallest", "matching_cluster_idx": 3}]}, "Mbpp/75": {"dps": 92.85714285714286, "dps_norm": 66.66666666666667, "pass@1": 100.0, "profiled": [{"solution": "def find_tuples(tuples_list, k):\n \"\"\"\n Find and return tuples where all elements are divisible by k.\n\n Parameters:\n tuples_list (list of tuples): List of tuples to be checked.\n k (int): The divisor.\n\n Returns:\n list of tuples: A list containing tuples where all elements are divisible by k.\n \"\"\"\n result = []\n for tup in tuples_list:\n if all(element % k == 0 for element in tup):\n result.append(tup)\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n \"\"\"\n This function takes a list of tuples and an integer k. It returns a list of tuples where all elements in each tuple\n are divisible by k.\n \n :param tuples_list: List[Tuple[int]] - A list of tuples of integers\n :param k: int - The integer divisor\n :return: List[Tuple[int]] - A list of tuples with all elements divisible by k\n \"\"\"\n result = []\n for t in tuples_list:\n if all(element % k == 0 for element in t):\n result.append(t)\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(lst, k):\n \"\"\"\n Function to find tuples which have all elements divisible by k from the given list of tuples.\n \n Parameters:\n lst (list of tuple of int): List containing tuples of integers.\n k (int): The divisor.\n \n Returns:\n list of tuple of int: List containing tuples where all elements are divisible by k.\n \"\"\"\n result = []\n for tup in lst:\n if all(x % k == 0 for x in tup):\n result.append(tup)\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n \"\"\"\n This function finds and returns a list of tuples where all elements are divisible by k.\n\n Parameters:\n tuples_list (list of tuples): A list containing tuples of integers.\n k (int): The divisor to check divisibility against.\n\n Returns:\n list of tuples: A list containing tuples where each element is divisible by k.\n \"\"\"\n result = []\n for tup in tuples_list:\n if all(element % k == 0 for element in tup):\n result.append(tup)\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n \"\"\"\n Find tuples which have all elements divisible by k from the given list of tuples.\n\n :param tuples_list: List of tuples to check\n :param k: Integer to check divisibility\n :return: List of tuples where all elements are divisible by k\n \"\"\"\n result = []\n for t in tuples_list:\n if all(element % k == 0 for element in t):\n result.append(t)\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n \"\"\"\n Finds tuples where all elements are divisible by k.\n\n Args:\n tuples_list (list of tuple of int): A list containing tuples of integers.\n k (int): The divisor to check divisibility.\n\n Returns:\n list of tuple of int: A list containing tuples from the input where all elements\n are divisible by k.\n \"\"\"\n # List to store tuples where all elements are divisible by k\n divisible_tuples = []\n \n for tup in tuples_list:\n # Check if all elements in the tuple are divisible by k\n if all(element % k == 0 for element in tup):\n divisible_tuples.append(tup)\n \n return divisible_tuples", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n \"\"\"\n This function receives a list of tuples and a divisor k.\n It returns a list of tuples where all elements are divisible by k.\n \"\"\"\n # Resultant list of tuples\n result = []\n \n # Iterate over each tuple in the provided list\n for tpl in tuples_list:\n # Check if all elements in the tuple are divisible by k\n if all(element % k == 0 for element in tpl):\n # If true, add the tuple to the result list\n result.append(tpl)\n \n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n # Create a list to store tuples where all elements are divisible by k\n divisible_tuples = []\n \n # Iterate through each tuple in the list\n for tpl in tuples_list:\n # Check if all elements in the tuple are divisible by k\n if all(element % k == 0 for element in tpl):\n # If true, add the tuple to the list\n divisible_tuples.append(tpl)\n \n return divisible_tuples", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n \"\"\"\n This function takes a list of tuples and an integer k, and returns a list of tuples\n where every element in each tuple is divisible by k.\n \n :param tuples_list: List of tuples\n :param k: Integer by which tuple elements must be divisible\n :return: List of tuples where all elements are divisible by k\n \"\"\"\n result = []\n \n for tuple_ in tuples_list:\n # Check if all elements in the tuple are divisible by k\n if all(element % k == 0 for element in tuple_):\n result.append(tuple_)\n \n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n \"\"\"\n Find tuples which have all elements divisible by k from the given list of tuples.\n\n :param tuples_list: List of tuples to be checked\n :param k: The divisor\n :return: List of tuples where all elements are divisible by k\n \"\"\"\n return [t for t in tuples_list if all(element % k == 0 for element in t)]", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n \"\"\"\n Finds and returns the list of tuples where each element in the tuple is divisible by k.\n\n Parameters:\n tuples_list (list of tuples): The list of tuples to be filtered.\n k (int): The divisor.\n\n Returns:\n list of tuples: A list containing tuples where all elements are divisible by k.\n \"\"\"\n # Initialize an empty list to store tuples that meet the criteria\n result = []\n\n # Iterate over each tuple in the list\n for t in tuples_list:\n # Check if all elements in the tuple are divisible by k\n if all(element % k == 0 for element in t):\n # If true, append the tuple to the result list\n result.append(t)\n \n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n \"\"\"\n This function finds tuples from the given list of tuples where all elements are divisible by k.\n \n Parameters:\n tuples_list (list): A list of tuples where each tuple contains integers.\n k (int): The divisor to check divisibility.\n \n Returns:\n list: A list of tuples where each tuple's elements are all divisible by k.\n \"\"\"\n result = []\n for tup in tuples_list:\n if all(element % k == 0 for element in tup):\n result.append(tup)\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(lst, k):\n # Filter the list of tuples\n result = [tup for tup in lst if all(x % k == 0 for x in tup)]\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(lst, k):\n \"\"\"\n This function takes a list of tuples and an integer k,\n and returns a list of tuples where all elements of each tuple are divisible by k.\n \"\"\"\n result = []\n for tup in lst:\n if all(element % k == 0 for element in tup):\n result.append(tup)\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n \"\"\"\n Finds tuples with all elements divisible by k.\n\n Parameters:\n tuples_list (list of tuple of int): The list of tuples to be checked.\n k (int): The divisor.\n\n Returns:\n list of tuple of int: A list of tuples where all elements are divisible by k.\n \"\"\"\n result = []\n for tpl in tuples_list:\n if all(element % k == 0 for element in tpl):\n result.append(tpl)\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(lst, k):\n \"\"\"\n Finds tuples with all elements divisible by k.\n\n :param lst: List of tuples to be checked.\n :param k: Integer divisor.\n :return: List of tuples where all elements are divisible by k.\n \"\"\"\n # Create a list to store the result\n result = []\n \n # Iterate through each tuple in the list\n for tup in lst:\n # Check if all elements in the tuple are divisible by k\n if all(element % k == 0 for element in tup):\n # If they are, add the tuple to the result list\n result.append(tup)\n \n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(lst, k):\n \"\"\"\n This function takes a list of tuples and an integer k, and returns a list of tuples\n where each element in the tuple is divisible by k.\n\n :param lst: List of tuples\n :param k: Integer divisor\n :return: List of tuples where all elements are divisible by k\n \"\"\"\n # Use a list comprehension to filter tuples\n return [tup for tup in lst if all(elem % k == 0 for elem in tup)]", "matching_cluster_idx": 5}, {"solution": "def find_tuples(lst_of_tuples, k):\n \"\"\"\n Find tuples where all elements are divisible by k.\n\n :param lst_of_tuples: List of tuples of integers.\n :param k: An integer to divide the elements by.\n :return: A list of tuples where all elements are divisible by k.\n \"\"\"\n # Initialize an empty list to store the tuples that satisfy the condition\n divisible_tuples = []\n\n # Iterate over each tuple in the list\n for tpl in lst_of_tuples:\n # Check if all elements in the tuple are divisible by k\n if all(element % k == 0 for element in tpl):\n # If true, append the tuple to the result list\n divisible_tuples.append(tpl)\n\n # Return the list of tuples\n return divisible_tuples", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n \"\"\"Find tuples where all elements are divisible by k.\"\"\"\n return [t for t in tuples_list if all(element % k == 0 for element in t)]", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n \"\"\"\n Finds and returns a list of tuples where all elements in each tuple are divisible by k.\n \n Parameters:\n tuples_list (list of tuples): A list containing tuples of integers.\n k (int): The divisor to check divisibility.\n \n Returns:\n list of tuples: A list of tuples where each element in the tuple is divisible by k.\n \"\"\"\n result = []\n for tuple_ in tuples_list:\n if all(element % k == 0 for element in tuple_):\n result.append(tuple_)\n return result\ntuples_list = [(6, 24, 12), (7, 9, 6), (12, 18, 21)]\nk = 6", "matching_cluster_idx": 5}]}, "Mbpp/88": {"dps": 96.56862745098039, "dps_norm": 85.71428571428571, "pass@1": 100.0, "profiled": [{"solution": "def freq_count(lst):\n \"\"\"\n Function to get the frequency of all the elements in a list, returned as a dictionary.\n \n Args:\n lst (list): The input list of elements.\n \n Returns:\n dict: A dictionary with elements as keys and their frequencies as values.\n \"\"\"\n frequency = {}\n for item in lst:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n return frequency", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n \"\"\"Return a dictionary with the frequency count of each element in the list.\"\"\"\n frequency = {}\n for item in lst:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n return frequency", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n \"\"\"Return a dictionary with the frequency of each element in the list.\"\"\"\n frequency = {}\n for item in lst:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n return frequency", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n frequency = {}\n for item in lst:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n return frequency", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n \"\"\"Returns the frequency of each element in the list as a dictionary.\"\"\"\n freq_dict = {}\n for item in lst:\n if item in freq_dict:\n freq_dict[item] += 1\n else:\n freq_dict[item] = 1\n return freq_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n \"\"\"\n Function to get the frequency of all the elements in a list.\n \n Parameters:\n lst (list): A list of elements.\n \n Returns:\n dict: A dictionary with elements of the list as keys and their frequencies as values.\n \"\"\"\n frequency_dict = {}\n \n for item in lst:\n if item in frequency_dict:\n frequency_dict[item] += 1\n else:\n frequency_dict[item] = 1\n \n return frequency_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n \"\"\"\n This function takes a list as input and returns a dictionary with the frequency of each element in the list.\n \"\"\"\n frequency_dict = {}\n for element in lst:\n if element in frequency_dict:\n frequency_dict[element] += 1\n else:\n frequency_dict[element] = 1\n return frequency_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n # Create an empty dictionary to store frequencies\n frequency = {}\n \n # Iterate over each element in the list\n for item in lst:\n # If the item is already in the dictionary, increment its count\n if item in frequency:\n frequency[item] += 1\n else:\n # If the item is not in the dictionary, add it with a count of 1\n frequency[item] = 1\n \n return frequency", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n \"\"\"\n Given a list of elements, return a dictionary with the frequency of each element.\n\n Parameters:\n lst (list): The list of elements.\n\n Returns:\n dict: A dictionary where keys are the elements and values are their frequencies in the list.\n \"\"\"\n frequency_dict = {}\n for element in lst:\n if element in frequency_dict:\n frequency_dict[element] += 1\n else:\n frequency_dict[element] = 1\n return frequency_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n frequency = {}\n for item in lst:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n return frequency", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n \"\"\"\n Returns a dictionary with the frequency count of each element in the list.\n\n Parameters:\n lst (list): The list of elements to count.\n\n Returns:\n dict: A dictionary with elements as keys and their frequencies as values.\n \"\"\"\n frequency_dict = {}\n for element in lst:\n if element in frequency_dict:\n frequency_dict[element] += 1\n else:\n frequency_dict[element] = 1\n return frequency_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n # Initialize an empty dictionary to store the frequency of elements\n frequency = {}\n \n # Iterate over each element in the list\n for element in lst:\n # If the element is already in the dictionary, increment its count\n if element in frequency:\n frequency[element] += 1\n # Otherwise, add the element to the dictionary with a count of 1\n else:\n frequency[element] = 1\n \n return frequency", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n \"\"\"\n Returns the frequency count of elements in the list as a dictionary.\n \n :param lst: List of elements for which frequency is to be calculated.\n :return: A dictionary with elements as keys and their frequencies as values.\n \"\"\"\n frequency_dict = {}\n \n for element in lst:\n if element in frequency_dict:\n frequency_dict[element] += 1\n else:\n frequency_dict[element] = 1\n \n return frequency_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n frequency = {}\n for item in lst:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n return frequency", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n frequency = {}\n for item in lst:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n return frequency", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n # Initialize an empty dictionary to store the frequency of elements\n freq_dict = {}\n \n # Iterate over each element in the list\n for item in lst:\n # If the item is already in the dictionary, increment its count\n if item in freq_dict:\n freq_dict[item] += 1\n # If the item is not in the dictionary, add it with a count of 1\n else:\n freq_dict[item] = 1\n \n # Return the frequency dictionary\n return freq_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n frequency_dict = {}\n for item in lst:\n if item in frequency_dict:\n frequency_dict[item] += 1\n else:\n frequency_dict[item] = 1\n return frequency_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n \"\"\"\n Returns a dictionary with the frequency of each element in the list `lst`.\n \"\"\"\n frequency_dict = {}\n for element in lst:\n if element in frequency_dict:\n frequency_dict[element] += 1\n else:\n frequency_dict[element] = 1\n return frequency_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n frequency_dict = {}\n for item in lst:\n if item in frequency_dict:\n frequency_dict[item] += 1\n else:\n frequency_dict[item] = 1\n return frequency_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n # Create an empty dictionary to hold the frequency of each element\n frequency = {}\n \n # Iterate over each element in the list\n for item in lst:\n # If the item is already in the dictionary, increment its count\n if item in frequency:\n frequency[item] += 1\n # If the item is not in the dictionary, add it with count 1\n else:\n frequency[item] = 1\n \n return frequency", "matching_cluster_idx": 5}]}, "Mbpp/90": {"dps": 77.14634146341464, "dps_norm": 85.71428571428571, "pass@1": 100.0, "profiled": [{"solution": "def len_log(words):\n \"\"\"\n Function to find the length of the longest word in a list of words.\n \n Parameters:\n words (list of str): List containing words as strings.\n \n Returns:\n int: Length of the longest word.\n \"\"\"\n if not words:\n return 0\n \n # Using max function with key=len to find the longest word\n longest_word = max(words, key=len)\n \n # Return the length of the longest word\n return len(longest_word)", "matching_cluster_idx": 6}, {"solution": "def len_log(words):\n \"\"\"Find the length of the longest word in a list of words.\"\"\"\n if not words: # Check if the list is empty\n return 0\n # Use max with key=len to find the longest word and then return its length\n return len(max(words, key=len))", "matching_cluster_idx": 6}, {"solution": "def len_log(words):\n \"\"\"\n This function receives a list of words and returns the length\n of the longest word in the list.\n \"\"\"\n if not words: # Handle empty list case\n return 0\n return max(len(word) for word in words)", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n \"\"\"\n Returns the length of the longest word in the list of words.\n\n Parameters:\n words (list of str): A list of words to evaluate.\n\n Returns:\n int: The length of the longest word.\n \"\"\"\n # Initialize the maximum length to 0\n max_length = 0\n \n # Iterate over each word in the list\n for word in words:\n # Update max_length if the current word is longer than the current max_length\n max_length = max(max_length, len(word))\n \n # Return the length of the longest word\n return max_length", "matching_cluster_idx": 3}, {"solution": "def len_log(words):\n \"\"\"\n Returns the length of the longest word in the list of words.\n \n :param words: List of words (strings)\n :return: Length of the longest word (int)\n \"\"\"\n if not words: # Check if the list is empty\n return 0\n # Find the length of the longest word\n return max(len(word) for word in words)", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n \"\"\"\n Returns the length of the longest word in the list of words.\n \n :param words: List of words\n :return: Length of the longest word\n \"\"\"\n if not words:\n return 0\n return max(len(word) for word in words)", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n \"\"\"\n This function returns the length of the longest word in a list of words.\n\n Parameters:\n words (list): A list of strings.\n\n Returns:\n int: The length of the longest word.\n \"\"\"\n if not words:\n return 0\n \n max_length = max(len(word) for word in words)\n return max_length", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n \"\"\"\n This function takes a list of words and returns the length of the longest word.\n \n :param words: List of strings\n :return: Integer representing the length of the longest word\n \"\"\"\n # Return the maximum length of any word in the list\n return max(len(word) for word in words)", "matching_cluster_idx": 5}, {"solution": "def len_log(word_list):\n \"\"\"\n Returns the length of the longest word in the word_list.\n \"\"\"\n if not word_list:\n return 0 # Return 0 if the list is empty\n \n # Initialize the maximum length variable\n max_length = 0\n \n for word in word_list:\n # Update max_length if the current word's length is greater\n if len(word) > max_length:\n max_length = len(word)\n \n return max_length", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n \"\"\"\n This function receives a list of words and returns the length of the longest word.\n :param words: List of words (strings)\n :return: Integer length of the longest word\n \"\"\"\n if not words:\n return 0\n \n # Use max function with a key argument to find the longest word by length\n longest_word = max(words, key=len)\n \n # Return the length of the longest word\n return len(longest_word)", "matching_cluster_idx": 6}, {"solution": "def len_log(words):\n \"\"\"\n This function receives a list of words and returns the length of the longest word.\n \"\"\"\n if not words:\n return 0\n\n # Use the max function with a key to get the word with maximum length\n longest_word_length = len(max(words, key=len))\n \n return longest_word_length", "matching_cluster_idx": 6}, {"solution": "def len_log(words):\n \"\"\"\n Function to find the length of the longest word in a list of words.\n \n Args:\n words (list): A list of strings (words).\n\n Returns:\n int: The length of the longest word.\n \"\"\"\n if not words:\n return 0 # Return 0 if the list is empty\n\n # Calculate the length of each word and return the maximum\n return max(len(word) for word in words)", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n \"\"\"\n This function takes a list of strings 'words' and returns the length of the longest word in the list.\n \n Parameters:\n words (list): A list of strings.\n \n Returns:\n int: The length of the longest word.\n \"\"\"\n # Check for the case where the input list is empty\n if not words:\n return 0\n \n # Initialize a variable to track the maximum length found\n max_length = 0\n \n # Iterate over each word in the list\n for word in words:\n # Update max_length if the current word is longer\n max_length = max(max_length, len(word))\n \n return max_length", "matching_cluster_idx": 2}, {"solution": "def len_log(words):\n \"\"\"\n Function to find the length of the longest word in a list.\n\n Parameters:\n words (list): A list of words (strings).\n\n Returns:\n int: The length of the longest word.\n \"\"\"\n if not words:\n return 0\n\n # Initialize max length to the length of the first word\n max_length = len(words[0])\n\n # Iterate over the rest of the words\n for word in words:\n if len(word) > max_length:\n max_length = len(word)\n\n return max_length", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n \"\"\"\n Find the length of the longest word in the list.\n\n Args:\n words (list of str): A list of words.\n\n Returns:\n int: The length of the longest word.\n \"\"\"\n # Use max with a key to find the length of the longest word\n return max(len(word) for word in words)", "matching_cluster_idx": 5}, {"solution": "def len_log(word_list):\n \"\"\"\n This function takes a list of words and returns the length of the longest word.\n \n :param word_list: List of words (strings)\n :return: Length of the longest word\n \"\"\"\n if not word_list: # If the list is empty, return 0\n return 0\n \n # Find the length of the longest word using max and key=len\n longest_word_length = max(len(word) for word in word_list)\n return longest_word_length", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n \"\"\"\n Function to find the length of the longest word in a list.\n \n Parameters:\n words (list): A list of words (strings).\n \n Returns:\n int: The length of the longest word.\n \"\"\"\n # Initialize a variable to keep track of the maximum length\n max_length = 0\n \n # Iterate over each word in the list\n for word in words:\n # Update max_length if the current word's length is greater\n if len(word) > max_length:\n max_length = len(word)\n \n return max_length", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n \"\"\"\n This function takes a list of words and returns the length of the longest word.\n \n :param words: List of strings\n :return: Integer, length of the longest word\n \"\"\"\n if not words:\n return 0 # If the list is empty, return 0\n \n # Use max with a key argument to find the longest word by length\n longest_word = max(words, key=len)\n return len(longest_word)", "matching_cluster_idx": 6}, {"solution": "def len_log(words):\n \"\"\"Find the length of the longest word in a list of words.\"\"\"\n if not words: # Handle the edge case where the input list is empty\n return 0\n return max(len(word) for word in words)", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n \"\"\"\n Find the length of the longest word in a list of words.\n\n Args:\n words (list of str): A list of words.\n\n Returns:\n int: The length of the longest word.\n \"\"\"\n # Initialize the maximum length to zero\n max_length = 0\n \n # Iterate through each word in the list\n for word in words:\n # If the current word's length is greater than the current max_length, update max_length\n if len(word) > max_length:\n max_length = len(word)\n \n return max_length", "matching_cluster_idx": 5}]}, "Mbpp/94": {"dps": 84.08536585365853, "dps_norm": 74.0, "pass@1": 80.0, "profiled": [{"solution": "def index_minimum(tuples_list):\n # Check if the list is empty\n if not tuples_list:\n return None # Return None if the list is empty\n\n # Initialize the minimum with the first tuple\n min_tuple = tuples_list[0]\n\n # Iterate over the list to find the tuple with the smallest second value\n for current_tuple in tuples_list[1:]:\n if current_tuple[1] < min_tuple[1]:\n min_tuple = current_tuple\n\n # Return the first value of the tuple with the smallest second value\n return min_tuple[0]", "matching_cluster_idx": 3}, {"solution": "def index_minimum(tuples_list):\n # Check if the list is empty\n if not tuples_list:\n return None\n\n # Initialize the minimum with the first tuple\n min_tuple = tuples_list[0]\n \n # Iterate over the list to find the tuple with the smallest second value\n for current_tuple in tuples_list:\n if current_tuple[1] < min_tuple[1]:\n min_tuple = current_tuple\n \n # Return the first value of the tuple with the smallest second value\n return min_tuple[0]", "matching_cluster_idx": 3}, {"solution": "def index_minimum(tuples_list):\n \"\"\"\n Given a list of tuples, returns the first value of the tuple with the smallest second value.\n\n Parameters:\n tuples_list (list of tuples): A list where each element is a tuple with at least two elements.\n\n Returns:\n The first element of the tuple which has the smallest second element.\n \"\"\"\n # Check if the list is empty\n if not tuples_list:\n return None\n\n # Initialize with the first tuple\n min_tuple = tuples_list[0]\n\n # Iterate through the list to find the tuple with the smallest second value\n for tup in tuples_list:\n if tup[1] < min_tuple[1]:\n min_tuple = tup\n\n return min_tuple[0]", "matching_cluster_idx": 3}, {"solution": "def index_minimum(tuples_list):\n if not tuples_list:\n return None # Handle the case where the input list is empty\n # Initialize minimum with the first tuple\n min_tuple = tuples_list[0]\n for current_tuple in tuples_list:\n # Compare the second value of the current tuple with the minimum\n if current_tuple[1] < min_tuple[1]:\n min_tuple = current_tuple\n return min_tuple[0]", "matching_cluster_idx": 3}, {"solution": "def index_minimum(tuples_list):\n # Check if the list is empty and return None if it is\n if not tuples_list:\n return None\n \n # Initialize the minimum with the first tuple\n min_tuple = tuples_list[0]\n \n # Iterate over the list to find the tuple with the smallest second value\n for current_tuple in tuples_list:\n # Compare the second element of each tuple\n if current_tuple[1] < min_tuple[1]:\n min_tuple = current_tuple\n \n # Return the first value of the tuple with the smallest second value\n return min_tuple[0]\ntuples_list = [('Rash', 143), ('Manjeet', 200), ('Varsha', 100)]", "matching_cluster_idx": 3}, {"solution": "def index_minimum(tuples_list):\n # Check if the list is empty\n if not tuples_list:\n return None\n \n # Initialize the minimum with the first tuple\n min_tuple = tuples_list[0]\n \n # Iterate over each tuple in the list\n for current_tuple in tuples_list:\n # Compare the second values of the tuples\n if current_tuple[1] < min_tuple[1]:\n min_tuple = current_tuple\n \n # Return the first value of the tuple with the smallest second value\n return min_tuple[0]", "matching_cluster_idx": 3}, {"solution": "def index_minimum(tuples_list):\n # Check if the list is empty\n if not tuples_list:\n return None\n \n # Initialize the minimum tuple with the first tuple in the list\n min_tuple = tuples_list[0]\n \n # Iterate over the list of tuples\n for current_tuple in tuples_list:\n # Compare the second values of the tuples\n if current_tuple[1] < min_tuple[1]:\n min_tuple = current_tuple\n \n # Return the first value of the tuple with the smallest second value\n return min_tuple[0]", "matching_cluster_idx": 3}, {"solution": "def index_minimum(tuples_list):\n \"\"\"\n Given a list of tuples, returns the first value of the tuple with the smallest second value.\n\n :param tuples_list: List of tuples where each tuple contains a name and a number.\n :return: The first value of the tuple with the smallest second value.\n \"\"\"\n if not tuples_list:\n return None # Return None if the list is empty\n\n # Find the tuple with the smallest second value\n min_tuple = min(tuples_list, key=lambda x: x[1])\n\n # Return the first value of that tuple\n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(tuples_list):\n # Check if the list is empty\n if not tuples_list:\n return None\n \n # Find the tuple with the smallest second value\n smallest_tuple = min(tuples_list, key=lambda x: x[1])\n \n # Return the first value of that tuple\n return smallest_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(tuples_list):\n # Ensure the list is not empty\n if not tuples_list:\n raise ValueError(\"The list should not be empty\")\n\n # Initialize with the first tuple\n min_tuple = tuples_list[0]\n \n # Iterate over each tuple in the list\n for current_tuple in tuples_list:\n # Compare the second value of the current tuple with the smallest found so far\n if current_tuple[1] < min_tuple[1]:\n min_tuple = current_tuple\n \n # Return the first value of the tuple with the smallest second value\n return min_tuple[0]", "matching_cluster_idx": 3}, {"solution": "def index_minimum(tuples_list):\n \"\"\"\n Returns the first value of the tuple with the smallest second value.\n\n :param tuples_list: List of tuples, where each tuple is of the form (str, int)\n :return: The first value of the tuple with the smallest second value\n \"\"\"\n if not tuples_list:\n return None\n \n # Initialize with the first tuple's values\n min_tuple = tuples_list[0]\n \n for item in tuples_list[1:]:\n # Compare the second value of the current tuple with the minimum found so far\n if item[1] < min_tuple[1]:\n min_tuple = item\n \n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(lst):\n # Check if the list is empty\n if not lst:\n return None\n\n # Initialize the first element as the minimum\n min_value = lst[0][1]\n min_tuple = lst[0]\n\n # Iterate through the list to find the tuple with the smallest second value\n for t in lst:\n if t[1] < min_value:\n min_value = t[1]\n min_tuple = t\n\n # Return the first value of the tuple with the smallest second value\n return min_tuple[0]", "matching_cluster_idx": 4}, {"solution": "def index_minimum(tuples_list):\n # Check if the list is empty\n if not tuples_list:\n return None\n \n # Initialize the minimum tuple as the first tuple in the list\n min_tuple = tuples_list[0]\n \n # Iterate over the list starting from the second element\n for tup in tuples_list[1:]:\n # Compare the second value of the current tuple with the second value of the min_tuple\n if tup[1] < min_tuple[1]:\n min_tuple = tup\n \n # Return the first value of the tuple with the smallest second value\n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(tuples_list):\n \"\"\"\n Given a list of tuples, returns the first value of the tuple with the smallest second value.\n \n Parameters:\n tuples_list (list): A list of tuples where each tuple contains a string and an integer.\n \n Returns:\n str: The first value of the tuple with the smallest second value.\n \"\"\"\n if not tuples_list:\n return None # Return None if the list is empty\n\n # Find the tuple with the minimum second value\n min_tuple = min(tuples_list, key=lambda x: x[1])\n \n # Return the first element of the tuple with the smallest second value\n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(tuples_list):\n # Check if the list is empty\n if not tuples_list:\n return None\n \n # Initialize the minimum with the first tuple\n min_tuple = tuples_list[0]\n \n # Iterate through each tuple in the list\n for tup in tuples_list:\n # Compare the second value of each tuple to find the minimum\n if tup[1] < min_tuple[1]:\n min_tuple = tup\n \n # Return the first value of the tuple with the smallest second value\n return min_tuple[0]", "matching_cluster_idx": 3}, {"solution": "def index_minimum(tuples_list):\n \"\"\"\n Given a list of tuples, returns the first value of the tuple with the smallest second value.\n \n Parameters:\n tuples_list (list of tuples): A list where each element is a tuple consisting of a string and an integer.\n \n Returns:\n str: The first value of the tuple with the smallest second value.\n \"\"\"\n # Using the min function with a key to find the tuple with the smallest second value.\n # The key specifies that the second element (at index 1) of each tuple should be used for comparison.\n min_tuple = min(tuples_list, key=lambda x: x[1])\n \n # Return the first element of the tuple with the smallest second value\n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(tuples_list):\n if not tuples_list:\n raise ValueError(\"The list must not be empty\")\n\n # Initialize with the first tuple\n min_tuple = tuples_list[0]\n\n # Iterate through the list to find the tuple with the smallest second value\n for current_tuple in tuples_list:\n if current_tuple[1] < min_tuple[1]:\n min_tuple = current_tuple\n\n # Return the first element of the tuple with the smallest second value\n return min_tuple[0]", "matching_cluster_idx": 3}, {"solution": "def index_minimum(tuples_list):\n # Ensure the list is not empty\n if not tuples_list:\n return None\n \n # Initialize the first element's second value as the minimum\n min_tuple = tuples_list[0]\n \n # Iterate through the list of tuples\n for current_tuple in tuples_list:\n # Compare the second values to find the minimum\n if current_tuple[1] < min_tuple[1]:\n min_tuple = current_tuple\n \n # Return the first value of the tuple with the smallest second value\n return min_tuple[0]", "matching_cluster_idx": 3}, {"solution": "def index_minimum(lst):\n if not lst:\n return None\n\n # Initialize the minimum element to the first element in the list\n min_tuple = lst[0]\n \n # Iterate through the list and find the tuple with the smallest second value\n for tup in lst:\n if tup[1] < min_tuple[1]:\n min_tuple = tup\n\n return min_tuple[0]", "matching_cluster_idx": 3}, {"solution": "def index_minimum(tuples_list):\n # Check if the list is empty\n if not tuples_list:\n return None\n \n # Use the min function with a key to find the tuple with the smallest second value\n smallest_tuple = min(tuples_list, key=lambda x: x[1])\n \n # Return the first value of the tuple with the smallest second value\n return smallest_tuple[0]", "matching_cluster_idx": 2}]}, "Mbpp/96": {"dps": 49.58333333333332, "dps_norm": 60.0, "pass@1": 99.0, "profiled": [{"solution": "def divisor(n):\n \"\"\"Returns the number of divisors of the integer n.\"\"\"\n if n <= 0:\n raise ValueError(\"The input must be a positive integer.\")\n \n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n if i == n // i:\n count += 1\n else:\n count += 2\n return count", "matching_cluster_idx": 5}, {"solution": "def divisor(n):\n \"\"\"\n Returns the number of divisors of the given integer n.\n \"\"\"\n count = 0\n # Check divisors up to the square root of n\n for i in range(1, int(n ** 0.5) + 1):\n if n % i == 0:\n count += 1 # i is a divisor\n if i != n // i:\n count += 1 # n // i is also a divisor if it's different\n return count", "matching_cluster_idx": 5}, {"solution": "def divisor(n):\n \"\"\"Returns the number of divisors of the integer n.\"\"\"\n if n <= 0:\n raise ValueError(\"Input must be a positive integer.\")\n \n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def divisor(n):\n \"\"\"\n This function returns the number of divisors of a given integer n.\n \n Parameters:\n n (int): The integer to find the number of divisors for.\n\n Returns:\n int: The number of divisors of n.\n \"\"\"\n if n < 1:\n raise ValueError(\"Input must be a positive integer.\")\n \n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def divisor(n):\n \"\"\"\n Function to find the number of divisors of a given integer n.\n :param n: Integer for which to find the number of divisors.\n :return: Number of divisors of n.\n \"\"\"\n if n <= 0:\n raise ValueError(\"n must be a positive integer\")\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def divisor(n):\n \"\"\"\n This function returns the number of divisors of an integer n.\n \n Parameters:\n n (int): The integer to find divisors for.\n \n Returns:\n int: The number of divisors of n.\n \"\"\"\n if n <= 0:\n raise ValueError(\"The input must be a positive integer.\")\n \n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n count += 1 # i is a divisor\n if i != n // i:\n count += 1 # n // i is also a divisor\n\n return count", "matching_cluster_idx": 5}, {"solution": "def divisor(n):\n \"\"\"Returns the number of divisors of a given integer n.\"\"\"\n if n <= 0:\n raise ValueError(\"The number should be a positive integer.\")\n \n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n count += 1\n if i != n // i:\n count += 1\n return count", "matching_cluster_idx": 5}, {"solution": "def divisor(n):\n \"\"\"\n Function to find the number of divisors of a given integer n.\n \"\"\"\n if n < 1:\n return 0 # If n is less than 1, it has no positive divisors.\n \n count = 0\n # Check each number from 1 to sqrt(n)\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n count += 1 # i is a divisor\n if i != n // i:\n count += 1 # n // i is also a divisor if it's different from i\n\n return count", "matching_cluster_idx": 5}, {"solution": "def divisor(n):\n \"\"\"Returns the number of divisors of a given integer n.\"\"\"\n if n < 1:\n raise ValueError(\"The input must be a positive integer.\")\n \n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def divisor(n):\n \"\"\"\n This function returns the number of divisors of a given integer n.\n \"\"\"\n if n <= 0:\n raise ValueError(\"The input must be a positive integer.\")\n count = 0\n for i in range(1, int(n ** 0.5) + 1):\n if n % i == 0:\n # i is a divisor\n count += 1\n # Check if i and n // i are different\n if i != n // i:\n count += 1\n return count", "matching_cluster_idx": 5}, {"solution": "def divisor(n):\n \"\"\"\n Returns the number of divisors of the integer n.\n \n Parameters:\n n (int): The integer to find the divisors of.\n \n Returns:\n int: The number of divisors of n.\n \"\"\"\n if n <= 0:\n raise ValueError(\"Input must be a positive integer\")\n \n count = 0\n # Iterate over possible divisors from 1 to the square root of n\n for i in range(1, int(n ** 0.5) + 1):\n if n % i == 0:\n # i is a divisor\n count += 1\n if i != n // i:\n # n // i is also a distinct divisor\n count += 1\n return count", "matching_cluster_idx": 5}, {"solution": "def divisor(n):\n if n < 1:\n raise ValueError(\"Input must be a positive integer.\")\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def divisor(n):\n \"\"\"Returns the number of divisors of the given integer n.\"\"\"\n if n < 1:\n return 0 # Return 0 if the input is not a positive integer\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def divisor(n):\n \"\"\"\n Find the number of divisors of a given integer n.\n \n Parameters:\n n (int): The integer to find divisors of. Assumed to be a positive integer.\n \n Returns:\n int: The number of divisors of n.\n \"\"\"\n if n < 1:\n raise ValueError(\"n should be a positive integer.\")\n \n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n count += 1\n if i != n // i: # Count the complement divisor if it's not the square root\n count += 1\n return count", "matching_cluster_idx": 5}, {"solution": "def divisor(n):\n \"\"\"Returns the number of divisors of a given integer n.\"\"\"\n if n <= 0:\n raise ValueError(\"The input must be a positive integer.\")\n \n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n if i == n // i:\n count += 1\n else:\n count += 2\n return count", "matching_cluster_idx": 5}, {"solution": "def divisor(n):\n \"\"\"Returns the number of divisors of the given integer n.\"\"\"\n if n < 1:\n raise ValueError(\"Input must be a positive integer.\")\n \n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def divisor(n):\n \"\"\"\n This function takes an integer n and returns the number of its divisors.\n \n Parameters:\n n (int): The integer for which to find the number of divisors.\n \n Returns:\n int: The number of divisors of n.\n \"\"\"\n if n < 1:\n raise ValueError(\"Input must be a positive integer.\")\n \n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n count += 1\n if i != n // i: # Ensure i and n/i are only counted once if they are equal\n count += 1\n return count", "matching_cluster_idx": 5}, {"solution": "def divisor(n):\n if n <= 0:\n raise ValueError(\"Input must be a positive integer\")\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def divisor(n):\n \"\"\"Function to find the number of divisors of a given integer n.\"\"\"\n if n <= 0:\n raise ValueError(\"Input must be a positive integer.\")\n \n count = 0\n # Check divisors from 1 to sqrt(n)\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n # If i is a divisor, then n/i is also a divisor\n count += 1\n if i != n // i:\n count += 1\n return count", "matching_cluster_idx": 5}, {"solution": "def divisor(n):\n \"\"\"Return the number of divisors of a given integer n.\"\"\"\n if n < 1:\n raise ValueError(\"Input must be a positive integer.\")\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 1}]}, "Mbpp/97": {"dps": 99.65811965811966, "dps_norm": 87.5, "pass@1": 100.0, "profiled": [{"solution": "def frequency_lists(lists):\n # Create a dictionary to store the frequencies\n frequency_dict = {}\n \n # Iterate through each list in the list of lists\n for sublist in lists:\n # Iterate through each element in the sublist\n for element in sublist:\n # If the element is already in the dictionary, increment its count\n if element in frequency_dict:\n frequency_dict[element] += 1\n # If the element is not in the dictionary, add it with count 1\n else:\n frequency_dict[element] = 1\n \n return frequency_dict", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(list_of_lists):\n # Flatten the list of lists into a single list\n flattened_list = [element for sublist in list_of_lists for element in sublist]\n \n # Create a dictionary to hold the frequencies of each element\n frequency_dict = {}\n \n # Iterate over the flattened list and count each element\n for element in flattened_list:\n if element in frequency_dict:\n frequency_dict[element] += 1\n else:\n frequency_dict[element] = 1\n \n return frequency_dict", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(list_of_lists):\n # Initialize a dictionary to store the frequency of each element\n frequency_dict = {}\n\n # Flatten the list of lists and count the frequency of each element\n for sublist in list_of_lists:\n for item in sublist:\n if item in frequency_dict:\n frequency_dict[item] += 1\n else:\n frequency_dict[item] = 1\n\n return frequency_dict", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(nested_list):\n # Create an empty dictionary to store the frequencies\n frequency_dict = {}\n\n # Iterate through each sublist in the nested list\n for sublist in nested_list:\n # Iterate through each element in the sublist\n for element in sublist:\n # Increment the count of the element in the dictionary\n if element in frequency_dict:\n frequency_dict[element] += 1\n else:\n frequency_dict[element] = 1\n\n return frequency_dict", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(list_of_lists):\n \"\"\"\n This function takes a list of lists and returns a dictionary with the frequency of each element.\n \"\"\"\n # Flatten the list of lists\n flat_list = [item for sublist in list_of_lists for item in sublist]\n \n # Create a dictionary to store frequencies\n frequency_dict = {}\n \n # Count the frequency of each element in the flattened list\n for item in flat_list:\n if item in frequency_dict:\n frequency_dict[item] += 1\n else:\n frequency_dict[item] = 1\n \n return frequency_dict", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(list_of_lists):\n # Initialize an empty dictionary to store the frequency of each element\n frequency_dict = {}\n \n # Iterate over each sublist in the list_of_lists\n for sublist in list_of_lists:\n # Iterate over each element in the sublist\n for element in sublist:\n # If the element is already in the dictionary, increment its count\n if element in frequency_dict:\n frequency_dict[element] += 1\n # If the element is not in the dictionary, add it with count 1\n else:\n frequency_dict[element] = 1\n \n return frequency_dict", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(nested_lists):\n # Create an empty dictionary to store the frequency of each element\n frequency_dict = {}\n\n # Iterate over each sublist in the nested lists\n for sublist in nested_lists:\n # Iterate over each element in the sublist\n for element in sublist:\n # If the element is already in the frequency dictionary, increment its count\n if element in frequency_dict:\n frequency_dict[element] += 1\n # If the element is not in the frequency dictionary, add it with a count of 1\n else:\n frequency_dict[element] = 1\n\n return frequency_dict", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(list_of_lists):\n # Initialize an empty dictionary to store the frequency of each element\n frequency_dict = {}\n \n # Flatten the list of lists and iterate over each element\n for sublist in list_of_lists:\n for item in sublist:\n # Increment the count for each element in the dictionary\n if item in frequency_dict:\n frequency_dict[item] += 1\n else:\n frequency_dict[item] = 1\n \n return frequency_dict", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lists):\n \"\"\"Find frequency of each element in a flattened list of lists.\"\"\"\n frequency = {}\n for sublist in lists:\n for item in sublist:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n return frequency", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(list_of_lists):\n # Flatten the list of lists\n flat_list = [item for sublist in list_of_lists for item in sublist]\n \n # Create a dictionary to store frequencies\n frequency_dict = {}\n \n # Iterate over the flat list and count occurrences\n for item in flat_list:\n if item in frequency_dict:\n frequency_dict[item] += 1\n else:\n frequency_dict[item] = 1\n \n return frequency_dict", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(list_of_lists):\n # Initialize an empty dictionary to store frequencies\n frequency_dict = {}\n \n # Iterate over each sublist in the list of lists\n for sublist in list_of_lists:\n # Iterate over each element in the sublist\n for element in sublist:\n # Update the frequency of each element in the dictionary\n if element in frequency_dict:\n frequency_dict[element] += 1\n else:\n frequency_dict[element] = 1\n \n # Return the dictionary with frequencies\n return frequency_dict", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(list_of_lists):\n frequency_dict = {}\n \n # Flatten the list of lists\n for sublist in list_of_lists:\n for item in sublist:\n # Count the frequency of each item\n if item in frequency_dict:\n frequency_dict[item] += 1\n else:\n frequency_dict[item] = 1\n \n return frequency_dict", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(list_of_lists):\n # Flatten the list of lists\n flat_list = [item for sublist in list_of_lists for item in sublist]\n \n # Create a dictionary to store frequencies\n frequency_dict = {}\n \n # Iterate over the flat list to count frequencies\n for item in flat_list:\n if item in frequency_dict:\n frequency_dict[item] += 1\n else:\n frequency_dict[item] = 1\n \n return frequency_dict", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(list_of_lists):\n \"\"\"\n This function takes a list of lists and returns a dictionary where\n each key is an element from the flattened list and each value is \n the frequency of that element in the flattened list.\n \"\"\"\n # Create an empty dictionary to store frequencies\n frequency_dict = {}\n\n # Iterate over each sublist in the list of lists\n for sublist in list_of_lists:\n # Iterate over each item in the sublist\n for item in sublist:\n # If the item is already in the dictionary, increment its count\n if item in frequency_dict:\n frequency_dict[item] += 1\n else:\n # Otherwise, add it to the dictionary with a count of 1\n frequency_dict[item] = 1\n\n # Return the dictionary of frequencies\n return frequency_dict", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lists):\n # Flatten the list of lists\n flattened_list = [item for sublist in lists for item in sublist]\n \n # Create a dictionary to store the frequency of each element\n frequency_dict = {}\n \n # Count the frequency of each element\n for item in flattened_list:\n if item in frequency_dict:\n frequency_dict[item] += 1\n else:\n frequency_dict[item] = 1\n \n return frequency_dict", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lists):\n # Flatten the list of lists\n flattened_list = [item for sublist in lists for item in sublist]\n \n # Dictionary to store frequency of each element\n frequency_dict = {}\n \n # Count the frequency of each element in the flattened list\n for item in flattened_list:\n if item in frequency_dict:\n frequency_dict[item] += 1\n else:\n frequency_dict[item] = 1\n \n return frequency_dict", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lists):\n # Flatten the list of lists\n flattened_list = [element for sublist in lists for element in sublist]\n \n # Create a dictionary to count the frequency of each element\n frequency_dict = {}\n \n for element in flattened_list:\n if element in frequency_dict:\n frequency_dict[element] += 1\n else:\n frequency_dict[element] = 1\n \n return frequency_dict", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(list_of_lists):\n # Flatten the list of lists\n flattened_list = [item for sublist in list_of_lists for item in sublist]\n \n # Create a dictionary to hold the frequency of each element\n frequency_dict = {}\n \n # Count the frequency of each element\n for item in flattened_list:\n if item in frequency_dict:\n frequency_dict[item] += 1\n else:\n frequency_dict[item] = 1\n \n return frequency_dict", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(list_of_lists):\n # Flatten the list of lists\n flattened_list = [element for sublist in list_of_lists for element in sublist]\n \n # Create a dictionary to store the frequency of each element\n frequency_dict = {}\n \n # Count the frequency of each element in the flattened list\n for element in flattened_list:\n if element in frequency_dict:\n frequency_dict[element] += 1\n else:\n frequency_dict[element] = 1\n \n return frequency_dict", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lists):\n # Initialize an empty dictionary to store frequencies\n frequency_dict = {}\n \n # Iterate over each list in the list of lists\n for sublist in lists:\n # Iterate over each element in the sublist\n for element in sublist:\n # Update the frequency of the element in the dictionary\n if element in frequency_dict:\n frequency_dict[element] += 1\n else:\n frequency_dict[element] = 1\n \n return frequency_dict", "matching_cluster_idx": 6}]}, "Mbpp/106": {"dps": 76.00649350649351, "dps_norm": 92.5, "pass@1": 100.0, "profiled": [{"solution": "def add_lists(lst, tpl):\n # Convert the tuple to a list to allow appending\n tpl_as_list = list(tpl)\n # Extend the list representation of the tuple with the new list\n tpl_as_list.extend(lst)\n # Convert back to a tuple\n return tuple(tpl_as_list)", "matching_cluster_idx": 4}, {"solution": "def add_lists(lst, tpl):\n \"\"\"\n Append the given list to the given tuple and return a new tuple.\n\n Parameters:\n lst (list): The list to append.\n tpl (tuple): The tuple to which the list will be appended.\n\n Returns:\n tuple: A new tuple with the list elements appended.\n \"\"\"\n # Convert the list to a tuple and concatenate with the original tuple\n return tpl + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tpl):\n \"\"\"\n Append the given list to the given tuple.\n\n Parameters:\n lst (list): The list to append.\n tpl (tuple): The tuple to which the list will be appended.\n\n Returns:\n tuple: A new tuple with the elements of the list appended to it.\n \"\"\"\n # Convert the list to a tuple and concatenate it with the given tuple\n return tpl + tuple(lst)", "matching_cluster_idx": 4}, {"solution": "def add_lists(lst, tpl):\n \"\"\"\n Appends the given list to the given tuple.\n\n Parameters:\n lst (list): The list to append.\n tpl (tuple): The tuple to which the list will be appended.\n\n Returns:\n tuple: A new tuple with the elements of the list appended to the tuple.\n \"\"\"\n # Convert the list to a tuple and concatenate with the given tuple\n return tpl + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tpl):\n \"\"\"\n Appends the elements of lst to the tuple tpl and returns the resulting tuple.\n \n :param lst: A list of elements to append.\n :param tpl: A tuple to which the list elements are appended.\n :return: A new tuple with the list elements appended.\n \"\"\"\n # Convert the list to a tuple and concatenate with the original tuple\n return tpl + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tpl):\n \"\"\"\n Appends the given list to the given tuple and returns a new tuple.\n \n :param lst: List to be appended.\n :param tpl: Tuple to which the list is appended.\n :return: New tuple with elements of the list appended.\n \"\"\"\n # Convert the tuple to a list and extend with the given list\n combined = list(tpl) + lst\n # Convert back to a tuple and return\n return tuple(combined)", "matching_cluster_idx": 3}, {"solution": "def add_lists(lst, tpl):\n \"\"\"\n Appends the given list 'lst' to the given tuple 'tpl'\n and returns a new tuple.\n\n Parameters:\n - lst: list of elements to append\n - tpl: tuple to which the list will be appended\n\n Returns:\n - A new tuple with elements of 'tpl' followed by elements of 'lst'\n \"\"\"\n # Convert the list to a tuple and concatenate with the given tuple\n return tpl + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tpl):\n \"\"\"\n Appends the elements of the list 'lst' to the tuple 'tpl'.\n \n Parameters:\n lst (list): The list to be appended.\n tpl (tuple): The tuple to which the list will be appended.\n \n Returns:\n tuple: A new tuple with the elements of 'tpl' followed by the elements of 'lst'.\n \"\"\"\n return tpl + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tpl):\n \"\"\"\n Appends the given list to the given tuple.\n \n Parameters:\n lst (list): The list to append to the tuple.\n tpl (tuple): The original tuple.\n \n Returns:\n tuple: A new tuple with the elements of the list appended to it.\n \"\"\"\n # Convert the list to a tuple and concatenate with the original tuple\n return tpl + tuple(lst)", "matching_cluster_idx": 4}, {"solution": "def add_lists(lst, tpl):\n \"\"\"\n Appends the given list to the given tuple.\n \n Parameters:\n lst (list): The list to be appended.\n tpl (tuple): The tuple to which the list will be appended.\n \n Returns:\n tuple: A new tuple with the list elements appended.\n \"\"\"\n # Convert the list to a tuple and concatenate with the existing tuple\n return tpl + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tpl):\n # Convert the tuple to a list, extend it with the given list, and convert it back to a tuple.\n return tuple(list(tpl) + lst)", "matching_cluster_idx": 3}, {"solution": "def add_lists(lst, tpl):\n \"\"\"\n Append the given list to the given tuple.\n \n Parameters:\n lst (list): List of elements to append.\n tpl (tuple): Tuple to which the list elements should be appended.\n \n Returns:\n tuple: A new tuple containing elements of the original tuple followed by the elements of the list.\n \"\"\"\n # Convert the list to a tuple and concatenate it with the original tuple\n return tpl + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tpl):\n \"\"\"\n Appends the given list 'lst' to the given tuple 'tpl' and returns a new tuple.\n\n Args:\n - lst: A list of elements to append.\n - tpl: A tuple to which the elements of 'lst' will be appended.\n\n Returns:\n - A new tuple with the elements of 'tpl' followed by the elements of 'lst'.\n \"\"\"\n return tpl + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tpl):\n \"\"\"\n Appends the given list to the given tuple.\n \n Args:\n lst: List of elements to be appended.\n tpl: Tuple to which the list should be appended.\n\n Returns:\n A new tuple with the elements of the list appended to the tuple.\n \"\"\"\n # Convert the tuple to a list, extend it with the given list, and convert it back to a tuple.\n return tpl + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tpl):\n \"\"\"\n Append the given list to the given tuple.\n \n :param lst: List of elements to append\n :param tpl: Tuple to which the list elements should be appended\n :return: A new tuple with the list elements appended\n \"\"\"\n # Convert list to tuple and concatenate with the input tuple\n return tpl + tuple(lst)", "matching_cluster_idx": 4}, {"solution": "def add_lists(lst, tpl):\n \"\"\"\n Append the given list to the given tuple.\n\n Parameters:\n lst (list): The list to append.\n tpl (tuple): The tuple to which the list is appended.\n\n Returns:\n tuple: A new tuple with the elements of the list appended to the elements of the tuple.\n \"\"\"\n return tpl + tuple(lst)", "matching_cluster_idx": 4}, {"solution": "def add_lists(lst, tpl):\n \"\"\"\n Appends the given list to the given tuple and returns the resulting tuple.\n \n :param lst: List of elements to be appended.\n :param tpl: Tuple to which the list elements will be appended.\n :return: A new tuple with the elements of the list appended to the original tuple.\n \"\"\"\n # Convert the list to a tuple and concatenate with the original tuple\n return tpl + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tpl):\n \"\"\"\n Appends the elements of the given list to the given tuple.\n\n Parameters:\n lst (list): The list of elements to append.\n tpl (tuple): The tuple to which the list elements will be appended.\n\n Returns:\n tuple: A new tuple with the elements of the list appended to the original tuple.\n \"\"\"\n # Convert the list to a tuple and concatenate with the given tuple\n return tpl + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tpl):\n \"\"\"\n Appends the given list to the given tuple and returns the resulting tuple.\n \n Parameters:\n lst (list): The list to append.\n tpl (tuple): The tuple to which the list is appended.\n \n Returns:\n tuple: A new tuple with the elements of the tuple followed by the elements of the list.\n \"\"\"\n # Convert the list to a tuple and concatenate it with the given tuple\n return tpl + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tpl):\n \"\"\"\n Append the given list to the given tuple and return a new tuple.\n \n :param lst: List of elements to append.\n :param tpl: Original tuple.\n :return: A new tuple with elements of the list appended.\n \"\"\"\n # Convert the list to a tuple and concatenate it with the original tuple\n return tpl + tuple(lst)", "matching_cluster_idx": 5}]}, "Mbpp/108": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 97.0, "profiled": [{"solution": "def merge_sorted_list(list1, list2, list3):\n # Combine all lists into one\n combined_list = list1 + list2 + list3\n # Sort the combined list\n combined_list.sort()\n return combined_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Combine the three lists\n combined_list = list1 + list2 + list3\n # Sort the combined list\n combined_list.sort()\n return combined_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # First, concatenate all three lists into a single list\n combined_list = list1 + list2 + list3\n \n # Sort the combined list\n combined_list.sort()\n \n return combined_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # First, combine the three lists into one\n combined_list = list1 + list2 + list3\n # Then, sort the combined list\n combined_list.sort()\n return combined_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Combine all three lists into one\n combined_list = list1 + list2 + list3\n # Sort the combined list\n combined_list.sort()\n return combined_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Combine all three lists\n combined_list = list1 + list2 + list3\n # Sort the combined list\n sorted_list = sorted(combined_list)\n return sorted_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Combine all three lists\n combined_list = list1 + list2 + list3\n # Sort the combined list\n sorted_list = sorted(combined_list)\n return sorted_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Merge all three lists into one\n merged_list = list1 + list2 + list3\n \n # Sort the merged list\n sorted_list = sorted(merged_list)\n \n return sorted_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Combine all the lists into a single list\n combined_list = list1 + list2 + list3\n # Sort the combined list\n sorted_list = sorted(combined_list)\n return sorted_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Merge the three lists into one\n combined_list = list1 + list2 + list3\n # Sort the combined list\n combined_list.sort()\n return combined_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Combine the three lists into one\n combined_list = list1 + list2 + list3\n \n # Sort the combined list\n sorted_list = sorted(combined_list)\n \n return sorted_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Merge the three lists into one\n merged_list = list1 + list2 + list3\n # Sort the merged list\n merged_list.sort()\n return merged_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Combine all three lists\n combined_list = list1 + list2 + list3\n # Sort the combined list\n sorted_list = sorted(combined_list)\n return sorted_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Merge the three lists into one\n merged_list = list1 + list2 + list3\n # Sort the merged list\n sorted_list = sorted(merged_list)\n return sorted_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Combine all three lists\n combined_list = list1 + list2 + list3\n \n # Sort the combined list\n sorted_list = sorted(combined_list)\n \n return sorted_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Merge the three lists into one\n merged_list = list1 + list2 + list3\n # Sort the merged list\n sorted_list = sorted(merged_list)\n return sorted_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Combine all three lists\n combined_list = list1 + list2 + list3\n # Sort the combined list\n combined_list.sort()\n return combined_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Merge all three lists into one\n merged_list = list1 + list2 + list3\n \n # Sort the merged list\n sorted_list = sorted(merged_list)\n \n return sorted_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Merge the three lists into a single list\n merged_list = list1 + list2 + list3\n # Sort the merged list\n merged_list.sort()\n return merged_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Combine all three lists into one\n combined_list = list1 + list2 + list3\n \n # Sort the combined list\n sorted_list = sorted(combined_list)\n \n return sorted_list", "matching_cluster_idx": 10}]}, "Mbpp/111": {"dps": 99.38461538461539, "dps_norm": 87.5, "pass@1": 100.0, "profiled": [{"solution": "def common_in_nested_lists(nested_lists):\n \"\"\"\n Find the common elements in given nested lists.\n \"\"\"\n if not nested_lists:\n return []\n\n # Start with the set of the first sublist\n common_elements = set(nested_lists[0])\n\n # Intersect with each subsequent list\n for sublist in nested_lists[1:]:\n common_elements.intersection_update(sublist)\n\n return list(common_elements)", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n \"\"\"\n This function finds the common elements in all given nested lists.\n \n Parameters:\n nested_lists (list of lists): A list containing multiple lists of integers.\n \n Returns:\n list: A list of common elements found in all nested lists.\n \"\"\"\n # Start by assuming the first list contains all the common elements\n if not nested_lists:\n return []\n \n # Use the first list to initialize the common elements set\n common_elements = set(nested_lists[0])\n \n # Intersect with the sets created from each subsequent list\n for lst in nested_lists[1:]:\n common_elements &= set(lst)\n \n return list(common_elements)", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n if not nested_lists:\n return []\n \n # Start with the first list as the initial set of common elements\n common_elements = set(nested_lists[0])\n \n # Intersect with each subsequent list\n for lst in nested_lists[1:]:\n common_elements.intersection_update(lst)\n \n return list(common_elements)", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n if not nested_lists:\n return []\n\n # Start with the first list's set\n common_elements = set(nested_lists[0])\n \n # Iterate over the rest of the lists and find the intersection\n for lst in nested_lists[1:]:\n common_elements.intersection_update(lst)\n \n return list(common_elements)", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(lists):\n if not lists:\n return []\n\n # Start with the first list as the initial set of common elements\n common_elements = set(lists[0])\n\n # Intersect with each subsequent list\n for lst in lists[1:]:\n common_elements.intersection_update(lst)\n\n return list(common_elements)", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n if not nested_lists:\n return []\n\n # Initialize common elements with the first sublist\n common_elements = set(nested_lists[0])\n\n # Iterate over the rest of the sublists\n for sublist in nested_lists[1:]:\n # Update common elements by finding intersection with the current sublist\n common_elements.intersection_update(sublist)\n\n return list(common_elements)", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n if not nested_lists:\n return []\n\n # Start with the set of the first list\n common_elements = set(nested_lists[0])\n\n # Intersect with each subsequent list's elements\n for lst in nested_lists[1:]:\n common_elements.intersection_update(lst)\n\n return list(common_elements)", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n if not nested_lists:\n return []\n\n # Start with the first list\n common_elements = set(nested_lists[0])\n\n # Intersect with subsequent lists\n for lst in nested_lists[1:]:\n common_elements.intersection_update(lst)\n\n return list(common_elements)", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n \"\"\"\n This function receives a list of lists (nested lists) and returns the common elements among all these lists.\n \"\"\"\n if not nested_lists:\n return []\n \n # Start with the elements of the first list\n common_elements = set(nested_lists[0])\n \n # Iterate through the rest of the lists\n for lst in nested_lists[1:]:\n # Update common_elements with the intersection with the current list\n common_elements.intersection_update(lst)\n \n return list(common_elements)", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n if not nested_lists:\n return []\n \n # Start with the first list's elements as a set\n common_elements = set(nested_lists[0])\n \n # Iterate over the remaining lists\n for lst in nested_lists[1:]:\n # Intersect the current set with the next list converted to a set\n common_elements &= set(lst)\n \n # Convert the resulting set back to a list and return it\n return list(common_elements)", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n # Convert the first list to a set as the starting point\n common_elements = set(nested_lists[0])\n \n # Iterate through each of the remaining lists\n for lst in nested_lists[1:]:\n # Find intersection with the current set of common elements\n common_elements.intersection_update(lst)\n \n # Return the final set of common elements\n return list(common_elements)", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n if not nested_lists:\n return []\n\n # Start with the set of elements from the first list\n common_elements = set(nested_lists[0])\n \n # Iterate through the rest of the lists and find the intersection\n for lst in nested_lists[1:]:\n common_elements.intersection_update(lst)\n\n return list(common_elements)", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(lists):\n # Initialize the common elements set with the elements from the first list\n if not lists:\n return []\n \n # Use set to find common elements\n common_elements = set(lists[0])\n \n # Intersect common_elements with each subsequent list\n for lst in lists[1:]:\n common_elements.intersection_update(lst)\n \n return list(common_elements)", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n if not nested_lists:\n return []\n \n # Start with the first list converted to a set\n common_elements = set(nested_lists[0])\n \n # Iterate over each list in the nested lists and find intersection\n for lst in nested_lists[1:]:\n common_elements.intersection_update(lst)\n \n return list(common_elements)\nnested_lists = [[12, 18, 23, 25, 45], [7, 12, 18, 24, 28], [1, 5, 8, 12, 15, 16, 18]]\ncommon_elements = common_in_nested_lists(nested_lists)", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n \"\"\"\n This function takes a list of lists (nested lists) and returns a list of common elements found in all the nested lists.\n \"\"\"\n # Check if the input is empty, return an empty list if true\n if not nested_lists:\n return []\n\n # Start with the set of the first list\n common_elements = set(nested_lists[0])\n\n # Find intersection with the remaining lists\n for lst in nested_lists[1:]:\n common_elements.intersection_update(lst)\n\n # Return the common elements as a list\n return list(common_elements)", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n if not nested_lists:\n return []\n\n # Start with the first list's elements as a set\n common_elements = set(nested_lists[0])\n\n # Intersect with each subsequent list's elements\n for lst in nested_lists[1:]:\n common_elements &= set(lst)\n\n return list(common_elements)\nnested_lists = [\n [12, 18, 23, 25, 45],\n [7, 12, 18, 24, 28],\n [1, 5, 8, 12, 15, 16, 18]\n]", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n if not nested_lists:\n return []\n\n # Start with the first list\n common_elements = set(nested_lists[0])\n \n # Intersect with each subsequent list\n for lst in nested_lists[1:]:\n common_elements &= set(lst)\n \n return list(common_elements)", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n # Initialize a set with the first list's elements\n common_elements = set(nested_lists[0])\n \n # Iterate through the remaining lists and find the intersection\n for lst in nested_lists[1:]:\n common_elements.intersection_update(lst)\n \n return list(common_elements)", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n # Check if the nested_lists is empty\n if not nested_lists:\n return []\n\n # Initialize the common elements with the elements of the first list\n common_elements = set(nested_lists[0])\n\n # Iterate through the remaining lists to find common elements\n for lst in nested_lists[1:]:\n common_elements.intersection_update(lst)\n\n return list(common_elements)", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n \"\"\"\n Find the common elements in given nested lists.\n :param nested_lists: List of lists containing integer elements\n :return: List of common elements\n \"\"\"\n if not nested_lists:\n return []\n\n # Start with the first list's elements as a set\n common_elements = set(nested_lists[0])\n\n # Iterate through the rest of the lists, updating the set to keep only common elements\n for lst in nested_lists[1:]:\n common_elements.intersection_update(lst)\n\n return list(common_elements)", "matching_cluster_idx": 6}]}, "Mbpp/123": {"dps": 99.62686567164178, "dps_norm": 85.71428571428571, "pass@1": 98.0, "profiled": [{"solution": "def sum_of_divisors(n):\n \"\"\"Returns the sum of all proper divisors of n.\"\"\"\n divisors_sum = 1 # 1 is a proper divisor of every number\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n divisors_sum += i\n if i != n // i: # Add the quotient only if it's different from i\n divisors_sum += n // i\n return divisors_sum\ndef is_amicable(a, b):\n \"\"\"Check if a and b are an amicable pair.\"\"\"\n return a != b and sum_of_divisors(a) == b and sum_of_divisors(b) == a\ndef amicable_numbers_sum(limit):\n \"\"\"Returns the sum of all amicable numbers under a given limit.\"\"\"\n amicable_sum = 0\n for number in range(2, limit):\n partner = sum_of_divisors(number)\n if is_amicable(number, partner):\n amicable_sum += number\n return amicable_sum", "matching_cluster_idx": 11}, {"solution": "def sum_of_proper_divisors(n):\n \"\"\"Return the sum of proper divisors of n.\"\"\"\n divisors_sum = 1 # Start with 1 as it is a divisor for all numbers > 1\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n divisors_sum += i\n if i != n // i:\n divisors_sum += n // i\n return divisors_sum\ndef amicable_numbers_sum(limit):\n \"\"\"Return the sum of all amicable numbers from 1 to the specified limit.\"\"\"\n def is_amicable(a):\n b = sum_of_proper_divisors(a)\n return a != b and sum_of_proper_divisors(b) == a\n\n amicable_sum = 0\n for num in range(2, limit + 1):\n if is_amicable(num):\n amicable_sum += num\n \n return amicable_sum", "matching_cluster_idx": 11}, {"solution": "def sum_of_divisors(n):\n \"\"\"Return the sum of proper divisors of n.\"\"\"\n divisors_sum = 1\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n divisors_sum += i\n if i != n // i:\n divisors_sum += n // i\n return divisors_sum\ndef amicable_numbers_sum(limit):\n \"\"\"Return the sum of all amicable numbers less than or equal to limit.\"\"\"\n amicable_sum = 0\n for num in range(2, limit + 1):\n partner = sum_of_divisors(num)\n if partner != num and partner <= limit and sum_of_divisors(partner) == num:\n amicable_sum += num\n return amicable_sum", "matching_cluster_idx": 11}, {"solution": "def sum_of_divisors(n):\n \"\"\"Returns the sum of proper divisors of a given number n.\"\"\"\n sum_divs = 1 # Start with 1 since it's a divisor of all n > 1\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n sum_divs += i\n if i != n // i:\n sum_divs += n // i\n return sum_divs\ndef is_amicable(a):\n \"\"\"Check if a number is part of an amicable pair.\"\"\"\n b = sum_of_divisors(a)\n return a != b and sum_of_divisors(b) == a\ndef amicable_numbers_sum(limit):\n \"\"\"Calculate the sum of all amicable numbers up to a given limit.\"\"\"\n amicable_sum = 0\n for num in range(2, limit):\n if is_amicable(num):\n amicable_sum += num\n return amicable_sum", "matching_cluster_idx": 11}, {"solution": "def sum_of_divisors(n):\n \"\"\"Returns the sum of all proper divisors of n.\"\"\"\n total = 1\n for i in range(2, int(n ** 0.5) + 1):\n if n % i == 0:\n total += i\n if i != n // i:\n total += n // i\n return total\ndef amicable_numbers_sum(limit):\n \"\"\"Returns the sum of all amicable numbers from 1 to the given limit.\"\"\"\n amicable_sum = 0\n for number in range(2, limit + 1):\n partner = sum_of_divisors(number)\n if partner != number and partner <= limit and sum_of_divisors(partner) == number:\n amicable_sum += number\n return amicable_sum", "matching_cluster_idx": 11}, {"solution": "def sum_of_divisors(n):\n \"\"\"Returns the sum of proper divisors of n.\"\"\"\n total = 1 # 1 is always a proper divisor\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n total += i\n if i != n // i:\n total += n // i\n return total\ndef amicable_numbers_sum(limit):\n \"\"\"Returns the sum of all amicable numbers up to a specified limit.\"\"\"\n amicable_sum = 0\n for a in range(2, limit):\n b = sum_of_divisors(a)\n if b != a and sum_of_divisors(b) == a:\n amicable_sum += a\n return amicable_sum", "matching_cluster_idx": 11}, {"solution": "def sum_of_divisors(n):\n \"\"\"Helper function to calculate the sum of proper divisors of n.\"\"\"\n if n < 2:\n return 0\n divisors_sum = 1 # 1 is a proper divisor of all numbers > 1\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n divisors_sum += i\n if i != n // i:\n divisors_sum += n // i\n return divisors_sum\ndef amicable_numbers_sum(limit):\n \"\"\"Calculate the sum of all amicable numbers up to the specified limit.\"\"\"\n amicable_sum = 0\n for num in range(1, limit):\n sum1 = sum_of_divisors(num)\n if sum1 > num: # This ensures we don't count pairs twice\n sum2 = sum_of_divisors(sum1)\n if sum2 == num:\n amicable_sum += num + sum1\n return amicable_sum", "matching_cluster_idx": 11}, {"solution": "def sum_of_divisors(n):\n \"\"\"Returns the sum of proper divisors of n.\"\"\"\n total = 1 # 1 is a proper divisor of every number greater than 1\n sqrt_n = int(n**0.5)\n for i in range(2, sqrt_n + 1):\n if n % i == 0:\n total += i\n if i != n // i:\n total += n // i\n return total\ndef is_amicable(a):\n \"\"\"Checks if a number a has an amicable pair and returns the pair if it exists.\"\"\"\n b = sum_of_divisors(a)\n return a != b and sum_of_divisors(b) == a\ndef amicable_numbers_sum(limit):\n \"\"\"Returns the sum of all amicable numbers from 1 to the specified limit (inclusive).\"\"\"\n sum_amicable = 0\n for num in range(2, limit + 1):\n if is_amicable(num):\n sum_amicable += num\n return sum_amicable", "matching_cluster_idx": 11}, {"solution": "def divisors_sum(n):\n \"\"\"Calculate the sum of proper divisors of n.\"\"\"\n total = 1 # start with 1 because it's a divisor of every number except 0\n sqrt_n = int(n**0.5)\n for i in range(2, sqrt_n + 1):\n if n % i == 0:\n total += i\n if i != n // i:\n total += n // i\n return total\ndef is_amicable(a):\n \"\"\"Check if a number is amicable.\"\"\"\n b = divisors_sum(a)\n return a != b and divisors_sum(b) == a\ndef amicable_numbers_sum(limit):\n \"\"\"Sum all amicable numbers up to the specified limit.\"\"\"\n total = 0\n for number in range(2, limit):\n if is_amicable(number):\n total += number\n return total", "matching_cluster_idx": 11}, {"solution": "def sum_of_divisors(n):\n \"\"\"Returns the sum of proper divisors of a number n.\"\"\"\n total = 1 # 1 is always a divisor\n # Check divisors from 2 to the square root of n\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n total += i\n if i != n // i: # Avoid adding the square root twice if n is a perfect square\n total += n // i\n return total\ndef is_amicable(a):\n \"\"\"Check if a number a is an amicable number.\"\"\"\n b = sum_of_divisors(a)\n return a != b and sum_of_divisors(b) == a\ndef amicable_numbers_sum(limit):\n \"\"\"Calculate the sum of all amicable numbers up to a specified limit.\"\"\"\n amicable_sum = 0\n for num in range(2, limit + 1):\n if is_amicable(num):\n amicable_sum += num\n return amicable_sum", "matching_cluster_idx": 11}, {"solution": "def divisors_sum(n):\n \"\"\"Returns the sum of proper divisors of n.\"\"\"\n total = 1 # Start with 1, which is a divisor of every number\n sqrt_n = int(n**0.5)\n for i in range(2, sqrt_n + 1):\n if n % i == 0:\n total += i\n if i != n // i: # Add the complementary divisor\n total += n // i\n return total\ndef amicable_numbers_sum(limit):\n \"\"\"Returns the sum of all amicable numbers from 1 to `limit`.\"\"\"\n amicable_sum = 0\n for a in range(2, limit + 1):\n b = divisors_sum(a)\n if a != b and divisors_sum(b) == a:\n amicable_sum += a\n return amicable_sum", "matching_cluster_idx": 11}, {"solution": "def sum_of_divisors(n):\n \"\"\"Return the sum of proper divisors of n.\"\"\"\n if n < 2:\n return 0\n total = 1 # 1 is a proper divisor of any number greater than 1\n sqrt_n = int(n**0.5)\n for i in range(2, sqrt_n + 1):\n if n % i == 0:\n total += i\n if i != n // i:\n total += n // i\n return total\ndef amicable_numbers_sum(limit):\n \"\"\"Calculate the sum of all amicable numbers from 1 to limit.\"\"\"\n amicable_sum = 0\n for number in range(2, limit + 1):\n sum_div = sum_of_divisors(number)\n # Check if pair forms an amicable pair and they are not the same number\n if sum_div != number and sum_of_divisors(sum_div) == number:\n amicable_sum += number\n return amicable_sum", "matching_cluster_idx": 11}, {"solution": "def sum_of_proper_divisors(n):\n \"\"\"Return the sum of proper divisors of n.\"\"\"\n divisors = [1]\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n divisors.append(i)\n if i != n // i:\n divisors.append(n // i)\n return sum(divisors)\ndef is_amicable(a):\n \"\"\"Check if a number is part of an amicable pair.\"\"\"\n b = sum_of_proper_divisors(a)\n return a != b and sum_of_proper_divisors(b) == a\ndef amicable_numbers_sum(limit):\n \"\"\"Sum all amicable numbers from 1 to the specified limit.\"\"\"\n amicable_sum = 0\n for number in range(1, limit):\n if is_amicable(number):\n amicable_sum += number\n return amicable_sum", "matching_cluster_idx": 11}, {"solution": "def sum_of_divisors(n):\n \"\"\"Returns the sum of proper divisors of n.\"\"\"\n sum_divs = 1 # 1 is a proper divisor of any number\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n sum_divs += i\n if i != n // i:\n sum_divs += n // i\n return sum_divs\ndef is_amicable(a, b):\n \"\"\"Returns True if a and b are an amicable pair.\"\"\"\n return a != b and sum_of_divisors(a) == b and sum_of_divisors(b) == a\ndef amicable_numbers_sum(limit):\n \"\"\"Returns the sum of all amicable numbers from 1 to limit.\"\"\"\n amicable_sum = 0\n visited = set()\n\n for num in range(2, limit):\n if num not in visited:\n partner = sum_of_divisors(num)\n if partner < limit and is_amicable(num, partner):\n amicable_sum += num + partner\n visited.update({num, partner})\n\n return amicable_sum", "matching_cluster_idx": 11}, {"solution": "def divisor_sum(n):\n \"\"\"Return the sum of proper divisors of n.\"\"\"\n total = 1\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n total += i\n if i != n // i:\n total += n // i\n return total\ndef is_amicable(a):\n \"\"\"Check if a number is amicable.\"\"\"\n b = divisor_sum(a)\n return a != b and divisor_sum(b) == a\ndef amicable_numbers_sum(limit):\n \"\"\"Return the sum of all amicable numbers less than the given limit.\"\"\"\n total_sum = 0\n for i in range(2, limit):\n if is_amicable(i):\n total_sum += i\n return total_sum", "matching_cluster_idx": 11}, {"solution": "def sum_of_proper_divisors(n):\n \"\"\"Calculate the sum of proper divisors of n.\"\"\"\n divisors_sum = 1 # 1 is a proper divisor of any n > 1\n # Check divisors up to sqrt(n)\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n divisors_sum += i\n if i != n // i:\n divisors_sum += n // i\n return divisors_sum\ndef is_amicable(a):\n \"\"\"Check if a number is part of an amicable pair.\"\"\"\n b = sum_of_proper_divisors(a)\n # Check if a and b form an amicable pair\n return b != a and sum_of_proper_divisors(b) == a\ndef amicable_numbers_sum(limit):\n \"\"\"Sum all amicable numbers from 1 to the specified limit.\"\"\"\n amicable_sum = 0\n for number in range(2, limit + 1):\n if is_amicable(number):\n amicable_sum += number\n return amicable_sum", "matching_cluster_idx": 11}, {"solution": "def sum_of_divisors(n):\n \"\"\"Calculate the sum of proper divisors of n.\"\"\"\n divisors_sum = 1\n sqrt_n = int(n ** 0.5)\n for i in range(2, sqrt_n + 1):\n if n % i == 0:\n divisors_sum += i\n if i != n // i: # Avoid adding the square root twice for perfect squares\n divisors_sum += n // i\n return divisors_sum\ndef amicable_numbers_sum(limit):\n \"\"\"Return the sum of all amicable numbers from 1 to the specified limit.\"\"\"\n amicable_sum = 0\n for a in range(2, limit):\n b = sum_of_divisors(a)\n # Check if a and b form an amicable pair\n if a != b and b < limit and sum_of_divisors(b) == a:\n amicable_sum += a\n return amicable_sum", "matching_cluster_idx": 11}, {"solution": "def sum_of_divisors(n):\n total = 1\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n total += i\n if i != n // i:\n total += n // i\n return total\ndef amicable_numbers_sum(limit):\n amicable_sum = 0\n for a in range(2, limit + 1):\n b = sum_of_divisors(a)\n if a != b and b <= limit and sum_of_divisors(b) == a:\n amicable_sum += a\n return amicable_sum", "matching_cluster_idx": 11}, {"solution": "def sum_of_divisors(n):\n \"\"\"Return the sum of proper divisors of n (excluding n itself).\"\"\"\n total = 1\n for i in range(2, int(n ** 0.5) + 1):\n if n % i == 0:\n total += i\n if i != n // i:\n total += n // i\n return total\ndef are_amicable(a, b):\n \"\"\"Check if numbers a and b are amicable.\"\"\"\n return a != b and sum_of_divisors(a) == b and sum_of_divisors(b) == a\ndef amicable_numbers_sum(limit):\n \"\"\"Return the sum of all amicable numbers up to the specified limit.\"\"\"\n amicable_sum = 0\n for num in range(2, limit + 1):\n potential_pair = sum_of_divisors(num)\n if potential_pair > num and potential_pair <= limit and are_amicable(num, potential_pair):\n amicable_sum += num + potential_pair\n return amicable_sum", "matching_cluster_idx": 11}, {"solution": "def sum_of_divisors(n):\n \"\"\"Return the sum of proper divisors of n.\"\"\"\n total = 1 # start with 1 as it is a divisor of every number\n for i in range(2, int(n ** 0.5) + 1):\n if n % i == 0:\n total += i\n if i != n // i:\n total += n // i\n return total\ndef amicable_numbers_sum(limit):\n \"\"\"Return the sum of all amicable numbers less than 'limit'.\"\"\"\n visited = set()\n total_amicable_sum = 0\n for number in range(2, limit):\n if number in visited:\n continue\n partner = sum_of_divisors(number)\n if partner != number and partner < limit and sum_of_divisors(partner) == number:\n total_amicable_sum += number + partner\n visited.update([number, partner])\n return total_amicable_sum", "matching_cluster_idx": 11}]}, "Mbpp/128": {"dps": 99.5475113122172, "dps_norm": 80.0, "pass@1": 100.0, "profiled": [{"solution": "def long_words(n, sentence):\n \"\"\"\n This function takes an integer n and a sentence (string).\n It returns a list of words from the sentence that are longer than n characters.\n \"\"\"\n # Split the sentence into words\n words = sentence.split()\n # Filter the words that have more than n characters\n long_words_list = [word for word in words if len(word) > n]\n return long_words_list", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n \"\"\"\n This function takes an integer `n` and a string `sentence`, and returns a list of words from the sentence that are longer than `n` characters.\n \"\"\"\n # Split the sentence into words\n words = sentence.split()\n \n # Use a list comprehension to filter words longer than n characters\n return [word for word in words if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n \"\"\"\n Finds words in a given sentence that are longer than n characters.\n\n :param n: Minimum length of words to find\n :param sentence: A string containing a list of words separated by spaces\n :return: A list of words longer than n characters\n \"\"\"\n # Split the sentence into a list of words\n words = sentence.split()\n # Use list comprehension to filter out words longer than n characters\n result = [word for word in words if len(word) > n]\n return result", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n \"\"\"\n This function takes an integer n and a string sentence, and returns a list of words that are longer than n characters.\n \"\"\"\n # Split the sentence into words\n words = sentence.split()\n \n # Use a list comprehension to filter words longer than n characters\n long_words_list = [word for word in words if len(word) > n]\n \n return long_words_list", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n \"\"\"\n Find words that are longer than n characters from a given sentence.\n \n :param n: An integer representing the minimum length of words to find.\n :param sentence: A string representing the sentence from which to find words.\n :return: A list of words from the sentence that are longer than n characters.\n \"\"\"\n # Split the sentence into words\n words = sentence.split()\n # Use list comprehension to find words longer than n characters\n result = [word for word in words if len(word) > n]\n return result", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n \"\"\"\n Finds words in the given sentence that are longer than n characters.\n\n Parameters:\n n (int): The minimum number of characters a word must have to be included in the result.\n sentence (str): The sentence from which to extract words.\n\n Returns:\n list: A list of words from the sentence that are longer than n characters.\n \"\"\"\n words = sentence.split() # Split the sentence into words\n return [word for word in words if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n # Split the sentence into words\n words = sentence.split()\n # Filter words that have length greater than n\n long_words_list = [word for word in words if len(word) > n]\n return long_words_list", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n \"\"\"\n Finds words in the sentence that are longer than n characters.\n \n :param n: An integer representing the minimum length of words to be included in the result\n :param sentence: A string containing the sentence to be analyzed\n :return: A list of words that are longer than n characters\n \"\"\"\n # Split the sentence into words\n words = sentence.split()\n # Filter words longer than n characters\n result = [word for word in words if len(word) > n]\n return result", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n \"\"\"\n This function takes an integer n and a string sentence, and returns a list\n of words from the sentence that are longer than n characters.\n \n Parameters:\n n (int): The minimum length a word must have to be included in the result.\n sentence (str): A string containing words separated by spaces.\n\n Returns:\n List[str]: A list of words from the sentence that are longer than n characters.\n \"\"\"\n # Split the sentence into words using space as a delimiter\n words = sentence.split()\n \n # Use list comprehension to filter words longer than n characters\n long_words_list = [word for word in words if len(word) > n]\n \n return long_words_list", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n \"\"\"\n Returns a list of words from the input sentence that are longer than n characters.\n \n Parameters:\n n (int): The minimum number of characters a word must have to be included in the output.\n sentence (str): The sentence from which words will be extracted and evaluated.\n \n Returns:\n list: A list of words that are longer than n characters.\n \"\"\"\n # Split the sentence into words\n words = sentence.split()\n \n # Filter and return words longer than n characters\n return [word for word in words if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n # Split the sentence into a list of words\n words = sentence.split()\n # Filter and return words longer than n characters\n return [word for word in words if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n \"\"\"\n Function to find words that are longer than n characters from a given sentence.\n\n Parameters:\n n (int): The minimum length a word should have to be included in the result.\n sentence (str): The sentence from which to extract words.\n\n Returns:\n list: A list of words longer than n characters.\n \"\"\"\n # Split the sentence into words\n words = sentence.split()\n # Filter words that have a length greater than n\n long_words_list = [word for word in words if len(word) > n]\n return long_words_list", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n \"\"\"\n Finds words in a sentence that are longer than n characters.\n\n Parameters:\n n (int): The minimum length a word must be to be included in the result.\n sentence (str): The sentence from which to find the words.\n\n Returns:\n list: A list of words longer than n characters.\n \"\"\"\n # Split the sentence into a list of words\n words = sentence.split()\n # Filter words that are longer than n characters\n return [word for word in words if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n # Split the sentence into a list of words\n words = sentence.split()\n # Use list comprehension to filter words longer than n characters\n return [word for word in words if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n # Split the sentence into a list of words\n words = sentence.split()\n # Use a list comprehension to filter out words longer than n characters\n return [word for word in words if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n # Split the sentence into words\n words = sentence.split()\n # Use a list comprehension to filter words longer than n characters\n return [word for word in words if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n \"\"\"\n Returns a list of words from the given sentence that are longer than n characters.\n \n Parameters:\n - n: The minimum length of the word to be included in the result.\n - sentence: A string containing the sentence from which words are extracted.\n \n Returns:\n - A list of words that are longer than n characters.\n \"\"\"\n words = sentence.split() # Split the sentence into words\n result = [word for word in words if len(word) > n] # Filter words longer than n\n return result", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n \"\"\"\n Find words that are longer than n characters from a given sentence.\n\n :param n: An integer representing the minimum length of the words to find.\n :param sentence: A string representing the sentence to search.\n :return: A list of words that are longer than n characters.\n \"\"\"\n # Split the sentence into words\n words = sentence.split()\n \n # Use list comprehension to filter words longer than n characters\n long_words_list = [word for word in words if len(word) > n]\n \n return long_words_list", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n \"\"\"\n This function takes an integer n and a sentence (string) as input, and returns a list of words\n from the sentence that are longer than n characters.\n\n :param n: Integer, the minimum number of characters a word must have to be included in the result.\n :param sentence: String, a sentence consisting of words.\n :return: List of words that are longer than n characters.\n \"\"\"\n # Split the sentence into words\n words = sentence.split()\n\n # Use list comprehension to filter words longer than n characters\n result = [word for word in words if len(word) > n]\n\n return result", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n \"\"\"\n Finds and returns words from the sentence that are longer than n characters.\n \n Parameters:\n n (int): The minimum number of characters a word must have to be included in the result.\n sentence (str): A string containing words separated by spaces.\n \n Returns:\n list: A list of words longer than n characters.\n \"\"\"\n # Split the sentence into a list of words\n words = sentence.split()\n \n # Use a list comprehension to filter words longer than n characters\n result = [word for word in words if len(word) > n]\n \n return result", "matching_cluster_idx": 3}]}, "Mbpp/129": {"dps": 74.61734693877551, "dps_norm": 96.66666666666666, "pass@1": 96.0, "profiled": [{"solution": "def magic_square_test(matrix):\n if not matrix or not matrix[0]:\n return False\n \n n = len(matrix)\n \n # Calculate the sum of the first row to use as reference\n target_sum = sum(matrix[0])\n \n # Check the sums of all rows\n for row in matrix:\n if sum(row) != target_sum:\n return False\n \n # Check the sums of all columns\n for col in range(n):\n if sum(matrix[row][col] for row in range(n)) != target_sum:\n return False\n \n # Check the sum of the main diagonal\n if sum(matrix[i][i] for i in range(n)) != target_sum:\n return False\n \n # Check the sum of the secondary diagonal\n if sum(matrix[i][n - 1 - i] for i in range(n)) != target_sum:\n return False\n \n return True\nmatrix = [[7, 12, 1, 14], [2, 13, 8, 11], [16, 3, 10, 5], [9, 6, 15, 4]]", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n n = len(matrix)\n \n # Calculate the sum of the first row\n magic_sum = sum(matrix[0])\n \n # Check sums of all rows\n for row in matrix:\n if sum(row) != magic_sum:\n return False\n \n # Check sums of all columns\n for col in range(n):\n if sum(matrix[row][col] for row in range(n)) != magic_sum:\n return False\n \n # Check sum of main diagonal\n if sum(matrix[i][i] for i in range(n)) != magic_sum:\n return False\n \n # Check sum of anti-diagonal\n if sum(matrix[i][n - i - 1] for i in range(n)) != magic_sum:\n return False\n \n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n n = len(matrix)\n if n == 0 or any(len(row) != n for row in matrix):\n # The matrix must be non-empty and square\n return False\n \n # Calculate the sum of the first row as the magic constant\n magic_constant = sum(matrix[0])\n \n # Check the sum of each row\n for row in matrix:\n if sum(row) != magic_constant:\n return False\n\n # Check the sum of each column\n for col in range(n):\n if sum(matrix[row][col] for row in range(n)) != magic_constant:\n return False\n\n # Check the sum of the main diagonal\n if sum(matrix[i][i] for i in range(n)) != magic_constant:\n return False\n\n # Check the sum of the secondary diagonal\n if sum(matrix[i][n - 1 - i] for i in range(n)) != magic_constant:\n return False\n \n return True", "matching_cluster_idx": 13}, {"solution": "def magic_square_test(matrix):\n \"\"\"\n Check if the given matrix is a magic square.\n \n A magic square is a square matrix in which the sum of every row, \n the sum of every column, and the sum of the diagonals are the same.\n \"\"\"\n if not matrix or not all(len(row) == len(matrix) for row in matrix):\n return False\n\n n = len(matrix)\n # Calculate the magic sum\n magic_sum = sum(matrix[0])\n\n # Check sum of each row\n for row in matrix:\n if sum(row) != magic_sum:\n return False\n\n # Check sum of each column\n for col in range(n):\n if sum(matrix[row][col] for row in range(n)) != magic_sum:\n return False\n\n # Check sum of main diagonal\n if sum(matrix[i][i] for i in range(n)) != magic_sum:\n return False\n\n # Check sum of secondary diagonal\n if sum(matrix[i][n - 1 - i] for i in range(n)) != magic_sum:\n return False\n\n return True", "matching_cluster_idx": 13}, {"solution": "def magic_square_test(matrix):\n if not matrix:\n return False\n\n n = len(matrix)\n \n # Check if matrix is n x n\n if any(len(row) != n for row in matrix):\n return False\n \n # Calculate the sum of the first row as the magic sum\n magic_sum = sum(matrix[0])\n\n # Check all rows\n for row in matrix:\n if sum(row) != magic_sum:\n return False\n\n # Check all columns\n for col in range(n):\n if sum(matrix[row][col] for row in range(n)) != magic_sum:\n return False\n\n # Check the main diagonal\n if sum(matrix[i][i] for i in range(n)) != magic_sum:\n return False\n\n # Check the secondary diagonal\n if sum(matrix[i][n - 1 - i] for i in range(n)) != magic_sum:\n return False\n\n return True", "matching_cluster_idx": 13}, {"solution": "def magic_square_test(matrix):\n n = len(matrix)\n if any(len(row) != n for row in matrix):\n return False # Not an n x n matrix\n\n # Calculate the magic constant which is the expected sum of each row, column, and diagonal\n magic_constant = sum(matrix[0])\n\n # Check sums of each row\n for row in matrix:\n if sum(row) != magic_constant:\n return False\n\n # Check sums of each column\n for col in range(n):\n if sum(matrix[row][col] for row in range(n)) != magic_constant:\n return False\n\n # Check sum of the main diagonal\n if sum(matrix[i][i] for i in range(n)) != magic_constant:\n return False\n\n # Check sum of the secondary diagonal\n if sum(matrix[i][n - i - 1] for i in range(n)) != magic_constant:\n return False\n\n return True", "matching_cluster_idx": 13}, {"solution": "def magic_square_test(matrix):\n # Check if the matrix is empty or not square\n if not matrix or any(len(row) != len(matrix) for row in matrix):\n return False\n\n n = len(matrix)\n # Calculate the sum of the first row as the reference sum\n magic_sum = sum(matrix[0])\n\n # Check sums of each row\n for row in matrix:\n if sum(row) != magic_sum:\n return False\n\n # Check sums of each column\n for col in range(n):\n if sum(matrix[row][col] for row in range(n)) != magic_sum:\n return False\n\n # Check sum of the main diagonal\n if sum(matrix[i][i] for i in range(n)) != magic_sum:\n return False\n\n # Check sum of the secondary diagonal\n if sum(matrix[i][n - i - 1] for i in range(n)) != magic_sum:\n return False\n\n return True", "matching_cluster_idx": 13}, {"solution": "def magic_square_test(matrix):\n if not matrix or not all(len(row) == len(matrix) for row in matrix):\n return False\n\n n = len(matrix)\n magic_sum = sum(matrix[0]) # The sum for comparison; sum of the first row.\n\n # Check each row sum\n for row in matrix:\n if sum(row) != magic_sum:\n return False\n\n # Check each column sum\n for col in range(n):\n if sum(matrix[row][col] for row in range(n)) != magic_sum:\n return False\n\n # Check the main diagonal sum\n if sum(matrix[i][i] for i in range(n)) != magic_sum:\n return False\n\n # Check the secondary diagonal sum\n if sum(matrix[i][n - 1 - i] for i in range(n)) != magic_sum:\n return False\n\n return True", "matching_cluster_idx": 13}, {"solution": "def magic_square_test(matrix):\n if not matrix:\n return False\n\n n = len(matrix)\n \n # Check if matrix is n x n\n for row in matrix:\n if len(row) != n:\n return False\n\n # Sum of the first row\n sum_magic = sum(matrix[0])\n\n # Check sum of each row\n for row in matrix:\n if sum(row) != sum_magic:\n return False\n\n # Check sum of each column\n for col in range(n):\n if sum(matrix[row][col] for row in range(n)) != sum_magic:\n return False\n\n # Check sum of the main diagonal\n if sum(matrix[i][i] for i in range(n)) != sum_magic:\n return False\n\n # Check sum of the secondary diagonal\n if sum(matrix[i][n - i - 1] for i in range(n)) != sum_magic:\n return False\n\n return True", "matching_cluster_idx": 13}, {"solution": "def magic_square_test(matrix):\n # Get the size of the matrix\n n = len(matrix)\n \n # Calculate the sum of the first row to use as the magic constant\n magic_constant = sum(matrix[0])\n \n # Check the sum of each row\n for row in matrix:\n if sum(row) != magic_constant:\n return False\n \n # Check the sum of each column\n for col in range(n):\n if sum(matrix[row][col] for row in range(n)) != magic_constant:\n return False\n \n # Check the sum of the main diagonal\n if sum(matrix[i][i] for i in range(n)) != magic_constant:\n return False\n \n # Check the sum of the secondary diagonal\n if sum(matrix[i][n - 1 - i] for i in range(n)) != magic_constant:\n return False\n \n # If all checks passed, it is a magic square\n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n if not matrix or not matrix[0]:\n return False\n \n n = len(matrix)\n \n # Calculate the sum of the first row to use as a target sum\n target_sum = sum(matrix[0])\n \n # Check sum of each row\n for row in matrix:\n if sum(row) != target_sum:\n return False\n \n # Check sum of each column\n for col in range(n):\n if sum(matrix[row][col] for row in range(n)) != target_sum:\n return False\n \n # Check sum of the primary diagonal\n if sum(matrix[i][i] for i in range(n)) != target_sum:\n return False\n \n # Check sum of the secondary diagonal\n if sum(matrix[i][n - 1 - i] for i in range(n)) != target_sum:\n return False\n \n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n if not matrix or not matrix[0]:\n return False\n\n n = len(matrix)\n\n # Calculate the sum of the first row\n magic_sum = sum(matrix[0])\n\n # Check the sum of each row\n for row in matrix:\n if sum(row) != magic_sum:\n return False\n\n # Check the sum of each column\n for col in range(n):\n if sum(matrix[row][col] for row in range(n)) != magic_sum:\n return False\n\n # Check the sum of the main diagonal\n if sum(matrix[i][i] for i in range(n)) != magic_sum:\n return False\n\n # Check the sum of the secondary diagonal\n if sum(matrix[i][n - 1 - i] for i in range(n)) != magic_sum:\n return False\n\n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n if not matrix:\n return False\n\n n = len(matrix)\n \n # Calculate the sum of the first row to set as the target sum\n target_sum = sum(matrix[0])\n \n # Check the sum of all rows\n for row in matrix:\n if sum(row) != target_sum:\n return False\n\n # Check the sum of all columns\n for col in range(n):\n column_sum = sum(matrix[row][col] for row in range(n))\n if column_sum != target_sum:\n return False\n\n # Check the sum of the main diagonal\n main_diagonal_sum = sum(matrix[i][i] for i in range(n))\n if main_diagonal_sum != target_sum:\n return False\n\n # Check the sum of the secondary diagonal\n secondary_diagonal_sum = sum(matrix[i][n - i - 1] for i in range(n))\n if secondary_diagonal_sum != target_sum:\n return False\n\n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n # Check if matrix is square\n n = len(matrix)\n for row in matrix:\n if len(row) != n:\n return False\n \n # Calculate the magic constant, i.e., the sum of the first row\n magic_sum = sum(matrix[0])\n \n # Check sum of each row\n for row in matrix:\n if sum(row) != magic_sum:\n return False\n \n # Check sum of each column\n for col in range(n):\n if sum(matrix[row][col] for row in range(n)) != magic_sum:\n return False\n \n # Check sum of the main diagonal\n if sum(matrix[i][i] for i in range(n)) != magic_sum:\n return False\n \n # Check sum of the secondary diagonal\n if sum(matrix[i][n - 1 - i] for i in range(n)) != magic_sum:\n return False\n \n return True", "matching_cluster_idx": 13}, {"solution": "def magic_square_test(matrix):\n if not matrix or not all(len(row) == len(matrix) for row in matrix):\n return False\n \n n = len(matrix)\n \n # Calculate the magic constant\n magic_constant = sum(matrix[0])\n \n # Check each row sum\n for row in matrix:\n if sum(row) != magic_constant:\n return False\n \n # Check each column sum\n for col in range(n):\n if sum(matrix[row][col] for row in range(n)) != magic_constant:\n return False\n \n # Check the main diagonal\n if sum(matrix[i][i] for i in range(n)) != magic_constant:\n return False\n \n # Check the secondary diagonal\n if sum(matrix[i][n - 1 - i] for i in range(n)) != magic_constant:\n return False\n \n return True", "matching_cluster_idx": 13}, {"solution": "def magic_square_test(matrix):\n if not matrix:\n return False\n\n n = len(matrix)\n \n # Calculate the sum of the first row to use as the magic sum\n magic_sum = sum(matrix[0])\n\n # Check all rows\n for row in matrix:\n if sum(row) != magic_sum:\n return False\n \n # Check all columns\n for col in range(n):\n if sum(matrix[row][col] for row in range(n)) != magic_sum:\n return False\n \n # Check main diagonal\n if sum(matrix[i][i] for i in range(n)) != magic_sum:\n return False\n \n # Check secondary diagonal\n if sum(matrix[i][n - 1 - i] for i in range(n)) != magic_sum:\n return False\n \n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n n = len(matrix)\n \n # If matrix is not n x n, it cannot be a magic square\n if any(len(row) != n for row in matrix):\n return False\n\n # Calculate the sum of the first row as the magic constant\n magic_constant = sum(matrix[0])\n\n # Check sum of each row\n for row in matrix:\n if sum(row) != magic_constant:\n return False\n\n # Check sum of each column\n for col in range(n):\n if sum(matrix[row][col] for row in range(n)) != magic_constant:\n return False\n\n # Check sum of the main diagonal\n if sum(matrix[i][i] for i in range(n)) != magic_constant:\n return False\n\n # Check sum of the secondary diagonal\n if sum(matrix[i][n - 1 - i] for i in range(n)) != magic_constant:\n return False\n\n return True", "matching_cluster_idx": 13}, {"solution": "def magic_square_test(matrix):\n n = len(matrix)\n\n # Sum of the first row is used as the magic sum\n magic_sum = sum(matrix[0])\n\n # Check if each row sums to the magic sum\n for row in matrix:\n if sum(row) != magic_sum:\n return False\n\n # Check if each column sums to the magic sum\n for col in range(n):\n if sum(matrix[row][col] for row in range(n)) != magic_sum:\n return False\n\n # Check if the main diagonal sums to the magic sum\n if sum(matrix[i][i] for i in range(n)) != magic_sum:\n return False\n\n # Check if the secondary diagonal sums to the magic sum\n if sum(matrix[i][n - 1 - i] for i in range(n)) != magic_sum:\n return False\n\n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n # Determine the size of the matrix\n n = len(matrix)\n \n # Calculate the sum of the first row to use as the target sum\n target_sum = sum(matrix[0])\n \n # Check sums of all rows\n for row in matrix:\n if sum(row) != target_sum:\n return False\n \n # Check sums of all columns\n for col in range(n):\n col_sum = sum(matrix[row][col] for row in range(n))\n if col_sum != target_sum:\n return False\n \n # Check the sum of the main diagonal\n main_diagonal_sum = sum(matrix[i][i] for i in range(n))\n if main_diagonal_sum != target_sum:\n return False\n \n # Check the sum of the secondary diagonal\n secondary_diagonal_sum = sum(matrix[i][n-1-i] for i in range(n))\n if secondary_diagonal_sum != target_sum:\n return False\n \n # If all checks pass, it is a magic square\n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n if not matrix or not matrix[0]:\n return False\n\n n = len(matrix)\n\n # Calculate the sum of the first row as the magic constant\n magic_constant = sum(matrix[0])\n\n # Check sums of each row\n for row in matrix:\n if sum(row) != magic_constant:\n return False\n\n # Check sums of each column\n for col in range(n):\n if sum(matrix[row][col] for row in range(n)) != magic_constant:\n return False\n\n # Check sum of the main diagonal\n if sum(matrix[i][i] for i in range(n)) != magic_constant:\n return False\n\n # Check sum of the secondary diagonal\n if sum(matrix[i][n - 1 - i] for i in range(n)) != magic_constant:\n return False\n\n return True", "matching_cluster_idx": 14}]}, "Mbpp/130": {"dps": 86.92825112107623, "dps_norm": 75.83333333333333, "pass@1": 98.0, "profiled": [{"solution": "from collections import Counter\ndef max_occurrences(lst):\n # Create a Counter object to count occurrences of each element in the list\n count = Counter(lst)\n # Find the element with the maximum frequency\n max_item = max(count, key=count.get)\n return max_item", "matching_cluster_idx": 4}, {"solution": "def max_occurrences(lst):\n # Using a dictionary to count occurrences of each element\n frequency = {}\n \n for item in lst:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n \n # Finding the element with the maximum frequency\n max_count = 0\n max_item = None\n for item, count in frequency.items():\n if count > max_count:\n max_count = count\n max_item = item\n \n return max_item", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(lst):\n # Dictionary to keep track of each element's frequency\n frequency = {}\n \n # Counting the occurrences of each element\n for item in lst:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n \n # Finding the item with the maximum frequency\n max_item = None\n max_count = 0\n \n for item, count in frequency.items():\n if count > max_count:\n max_count = count\n max_item = item\n \n return max_item", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(lst):\n # Dictionary to store frequency of each element\n frequency_dict = {}\n \n # Count the frequency of each item in the list\n for item in lst:\n if item in frequency_dict:\n frequency_dict[item] += 1\n else:\n frequency_dict[item] = 1\n \n # Find the item with maximum frequency\n max_freq = 0\n max_item = None\n for item, frequency in frequency_dict.items():\n if frequency > max_freq:\n max_freq = frequency\n max_item = item\n \n return max_item", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(lst):\n from collections import Counter\n\n # Count the frequency of each item in the list\n frequency = Counter(lst)\n \n # Find the item with the maximum frequency\n max_item = max(frequency, key=frequency.get)\n \n return max_item", "matching_cluster_idx": 4}, {"solution": "from collections import Counter\ndef max_occurrences(lst):\n # Use Counter to count the frequencies of each item in the list\n counts = Counter(lst)\n # Find the item with the maximum frequency\n max_item = max(counts, key=counts.get)\n return max_item", "matching_cluster_idx": 4}, {"solution": "def max_occurrences(lst):\n # Create a dictionary to count the occurrences of each element\n frequency_dict = {}\n \n # Iterate over each element in the list\n for item in lst:\n # Increment the count for the item in the dictionary\n if item in frequency_dict:\n frequency_dict[item] += 1\n else:\n frequency_dict[item] = 1\n \n # Find the item with the maximum frequency\n max_count = 0\n max_item = None\n for item, count in frequency_dict.items():\n if count > max_count:\n max_count = count\n max_item = item\n \n return max_item", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(lst):\n \"\"\"\n Find the item with maximum frequency in a given list.\n :param lst: List of elements\n :return: Element with maximum frequency\n \"\"\"\n from collections import Counter\n \n # Count the frequency of each element in the list\n frequency = Counter(lst)\n \n # Find the element with the maximum frequency\n max_item = max(frequency, key=frequency.get)\n \n return max_item", "matching_cluster_idx": 4}, {"solution": "def max_occurrences(lst):\n from collections import Counter\n \n # Use Counter to count frequencies of elements in the list\n frequency = Counter(lst)\n \n # Find the item with the maximum frequency\n max_item = max(frequency, key=frequency.get)\n \n return max_item", "matching_cluster_idx": 4}, {"solution": "def max_occurrences(lst):\n \"\"\"\n Finds the item with the maximum frequency in the given list.\n If there are multiple items with the same maximum frequency,\n the first one encountered is returned.\n \"\"\"\n from collections import Counter\n\n if not lst:\n return None\n\n # Create a Counter object to count the occurrences of each element\n count = Counter(lst)\n\n # Find the element with the maximum frequency\n max_freq_item = max(count, key=lambda x: count[x])\n\n return max_freq_item", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(lst):\n # Dictionary to keep track of frequency of each element\n frequency = {}\n \n # Iterate through the list and count the occurrences of each element\n for item in lst:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n\n # Find the item with the maximum frequency\n max_freq = -1\n max_item = None\n for item, freq in frequency.items():\n if freq > max_freq:\n max_freq = freq\n max_item = item\n\n return max_item", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(lst):\n # Create a dictionary to store the frequency of each element\n frequency = {}\n \n # Iterate through the list to populate the frequency dictionary\n for item in lst:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n \n # Find the item with the maximum frequency\n max_item = None\n max_count = 0\n \n for item, count in frequency.items():\n if count > max_count:\n max_count = count\n max_item = item\n \n return max_item", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(lst):\n from collections import Counter\n \n # Count the frequency of each element in the list\n frequency = Counter(lst)\n \n # Find the element with the maximum frequency\n max_frequency = max(frequency.values())\n \n # Return the first element that has the maximum frequency\n for item, count in frequency.items():\n if count == max_frequency:\n return item", "matching_cluster_idx": 5}, {"solution": "def max_occurrences(lst):\n from collections import Counter\n # Count the frequency of each element in the list\n frequency = Counter(lst)\n # Find the element with the maximum frequency\n max_item = max(frequency, key=frequency.get)\n return max_item", "matching_cluster_idx": 4}, {"solution": "def max_occurrences(lst):\n # Create a dictionary to store the frequency of each item\n frequency = {}\n \n # Count the frequency of each item in the list\n for item in lst:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n \n # Find the item with the maximum frequency\n max_count = -1\n max_item = None\n for item, count in frequency.items():\n if count > max_count:\n max_count = count\n max_item = item\n \n return max_item", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(lst):\n from collections import Counter\n \n # Create a Counter object to count the occurrences of each element\n counts = Counter(lst)\n \n # Find the item with the maximum frequency\n max_item = max(counts, key=counts.get)\n \n return max_item", "matching_cluster_idx": 4}, {"solution": "def max_occurrences(lst):\n from collections import Counter\n \n # Count the frequency of each item in the list\n frequency = Counter(lst)\n \n # Find the item with the maximum frequency\n max_item = max(frequency, key=frequency.get)\n \n return max_item", "matching_cluster_idx": 4}, {"solution": "def max_occurrences(lst):\n from collections import Counter\n count = Counter(lst)\n max_item = max(count, key=count.get)\n return max_item", "matching_cluster_idx": 4}, {"solution": "def max_occurrences(lst):\n frequency = {}\n for item in lst:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n\n # Find the item with the maximum frequency\n max_freq = -1\n max_item = None\n for item, count in frequency.items():\n if count > max_freq:\n max_freq = count\n max_item = item\n\n return max_item", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(lst):\n # Create a dictionary to store frequency of each element\n frequency_dict = {}\n \n # Count the occurrences of each element\n for item in lst:\n if item in frequency_dict:\n frequency_dict[item] += 1\n else:\n frequency_dict[item] = 1\n \n # Find the item with the maximum frequency\n max_freq = -1\n max_item = None\n \n for item, freq in frequency_dict.items():\n if freq > max_freq:\n max_freq = freq\n max_item = item\n \n return max_item", "matching_cluster_idx": 3}]}, "Mbpp/137": {"dps": 81.1290322580645, "dps_norm": 91.25, "pass@1": 49.0, "profiled": [{"solution": "import math\ndef zero_count(arr):\n if not arr: # Handle empty array case\n return 0\n\n zeroes = arr.count(0)\n non_zeroes = len(arr) - zeroes\n \n # Handle division by zero in case there are no non-zero elements\n if non_zeroes == 0:\n return float('inf') # Or return 0 or any other appropriate value depending on use case\n\n return zeroes / non_zeroes", "matching_cluster_idx": 6}, {"solution": "import math\ndef zero_count(arr):\n zeroes = arr.count(0)\n non_zeroes = len(arr) - zeroes\n if non_zeroes == 0:\n return float('inf') # Avoid division by zero; can also return float('nan') or handle differently\n return zeroes / non_zeroes", "matching_cluster_idx": 7}, {"solution": "import math\ndef zero_count(arr):\n if not arr: # Check if the list is empty\n return 0.0\n \n zeroes = arr.count(0)\n non_zeroes = len(arr) - zeroes\n \n # Avoid division by zero if there are no non-zero elements\n if non_zeroes == 0:\n return float('inf') # or return a specific value like 0.0 or raise an error\n \n return zeroes / non_zeroes", "matching_cluster_idx": 6}, {"solution": "import math\ndef zero_count(arr):\n # Count the number of zeroes\n zeroes = arr.count(0)\n \n # Count the number of non-zero elements\n non_zeroes = len(arr) - zeroes\n \n # Calculate the ratio of zeroes to non-zeroes\n if non_zeroes == 0:\n return float('inf') # Return infinity if there are no non-zero elements\n return zeroes / non_zeroes", "matching_cluster_idx": 7}, {"solution": "import math\ndef zero_count(arr):\n \"\"\"\n This function calculates the ratio of the number of zeroes to the number of non-zero elements in the array.\n \"\"\"\n # Count the number of zeroes in the array\n zeroes = arr.count(0)\n \n # Count the number of non-zero elements in the array\n non_zeroes = len(arr) - zeroes\n \n # Calculate the ratio of zeroes to non-zeroes\n if non_zeroes == 0:\n return float('inf') # Handle case where there are no non-zero elements\n else:\n return zeroes / non_zeroes", "matching_cluster_idx": 7}, {"solution": "import math\ndef zero_count(arr):\n total_count = len(arr)\n zero_count = arr.count(0)\n non_zero_count = total_count - zero_count\n \n # Calculate ratio of zeroes to non-zeroes\n if non_zero_count == 0:\n return float('inf') # If there are no non-zero elements, return infinity\n return zero_count / non_zero_count", "matching_cluster_idx": 6}, {"solution": "import math\ndef zero_count(arr):\n # Calculate the number of zeroes in the array\n num_zeroes = arr.count(0)\n # Calculate the total number of non-zero elements\n num_non_zeroes = len(arr) - num_zeroes\n \n if num_non_zeroes == 0:\n return float('inf') # Avoid division by zero by returning inf\n\n # Calculate the ratio of zeroes to non-zeroes\n return num_zeroes / num_non_zeroes", "matching_cluster_idx": 7}, {"solution": "import math\ndef zero_count(arr):\n if not arr:\n return 0.0 # handle the empty array case\n \n zeroes = arr.count(0)\n non_zeroes = len(arr) - zeroes\n \n # Avoid division by zero if all elements are zeroes\n if non_zeroes == 0:\n return float('inf') # or return 0.0 if you want it to be 0 when there are no non-zeroes\n \n return zeroes / non_zeroes", "matching_cluster_idx": 6}, {"solution": "import math\ndef zero_count(arr):\n if not arr: # Check if the list is empty\n return 0.0\n zeroes = arr.count(0) # Count the number of zeroes\n non_zeroes = len(arr) - zeroes # Count the number of non-zeroes\n if non_zeroes == 0: # Avoid division by zero\n return float('inf') # or return 0 or raise an exception\n return zeroes / non_zeroes", "matching_cluster_idx": 6}, {"solution": "import math\ndef zero_count(arr):\n # Count the number of zeros\n zeroes = arr.count(0)\n \n # Count the number of non-zero elements\n non_zeroes = len(arr) - zeroes\n \n # Avoid division by zero by returning zero ratio if the list is empty\n if len(arr) == 0:\n return 0.0\n \n # Calculate the ratio of zeroes to non-zeroes\n return zeroes / non_zeroes if non_zeroes != 0 else float('inf')", "matching_cluster_idx": 6}, {"solution": "import math\ndef zero_count(arr):\n if not arr:\n raise ValueError(\"Array must not be empty\")\n\n total_elements = len(arr)\n zeroes = arr.count(0)\n non_zeroes = total_elements - zeroes\n\n if non_zeroes == 0:\n return float('inf') # return infinity if all elements are zero\n\n return zeroes / non_zeroes", "matching_cluster_idx": 6}, {"solution": "import math\ndef zero_count(arr):\n # Count the number of zeroes in the array\n count_zeroes = arr.count(0)\n \n # Count the number of non-zeroes\n count_non_zeroes = len(arr) - count_zeroes\n \n # Calculate the ratio\n if count_non_zeroes == 0:\n # To handle the case when there are no non-zeroes to avoid division by zero\n return float('inf') if count_zeroes > 0 else 0\n \n ratio = count_zeroes / count_non_zeroes\n \n return ratio", "matching_cluster_idx": 7}, {"solution": "import math\ndef zero_count(arr):\n # Count the number of zeroes and non-zeroes in the array\n zeroes = arr.count(0)\n non_zeroes = len(arr) - zeroes\n \n # Calculate the ratio of zeroes to non-zeroes\n if non_zeroes == 0:\n return float('inf') # If there are no non-zero elements, the ratio is infinite\n return zeroes / non_zeroes", "matching_cluster_idx": 7}, {"solution": "import math\ndef zero_count(arr):\n if len(arr) == 0:\n return 0 # Handle empty array case\n \n zeroes = arr.count(0)\n non_zeroes = len(arr) - zeroes\n \n if non_zeroes == 0:\n return float('inf') # Handle the case where the array contains only zeroes\n\n return zeroes / non_zeroes", "matching_cluster_idx": 6}, {"solution": "import math\ndef zero_count(arr):\n if not arr: # Handle edge case of empty array\n return 0.0\n \n zeroes = arr.count(0)\n non_zeroes = len(arr) - zeroes\n \n # Avoid division by zero in case there are no non-zero elements\n if non_zeroes == 0:\n return float('inf') # You can decide how to handle this case\n\n return zeroes / non_zeroes", "matching_cluster_idx": 6}, {"solution": "import math\ndef zero_count(arr):\n if not arr:\n return 0 # Return 0 if the array is empty to avoid division by zero\n \n zeroes = sum(1 for x in arr if x == 0)\n non_zeroes = len(arr) - zeroes\n \n if non_zeroes == 0:\n return float('inf') # If there are no non-zero elements, return infinity\n \n ratio = zeroes / non_zeroes\n return ratio", "matching_cluster_idx": 4}, {"solution": "import math\ndef zero_count(arr):\n # Count the number of zeros in the array\n zeros = arr.count(0)\n # Calculate the number of non-zero elements\n non_zeros = len(arr) - zeros\n # Calculate the ratio of zeros to non-zero elements\n if non_zeros == 0:\n return float('inf') # Handle division by zero if the array contains only zeros\n return zeros / non_zeros", "matching_cluster_idx": 7}, {"solution": "import math\ndef zero_count(arr):\n zeroes = arr.count(0)\n non_zeroes = len(arr) - zeroes\n if non_zeroes == 0:\n return float('inf') # Return infinity if there are no non-zeroes\n return zeroes / non_zeroes", "matching_cluster_idx": 7}, {"solution": "import math\ndef zero_count(arr):\n if not arr: # Check for empty array to avoid division by zero\n return 0\n \n zeroes = arr.count(0)\n non_zeroes = len(arr) - zeroes\n \n # Avoid division by zero if there are no non-zeroes\n if non_zeroes == 0:\n return float('inf') # Can be adjusted depending on desired behavior\n\n return zeroes / non_zeroes", "matching_cluster_idx": 6}, {"solution": "import math\ndef zero_count(arr):\n if not arr: # Handle edge case where the input array is empty\n return 0.0\n\n zeroes = arr.count(0)\n non_zeroes = len(arr) - zeroes\n\n if non_zeroes == 0:\n return float('inf') # If there are no non-zeroes, the ratio is infinity\n\n return zeroes / non_zeroes", "matching_cluster_idx": 6}]}, "Mbpp/140": {"dps": 78.24534161490683, "dps_norm": 80.625, "pass@1": 100.0, "profiled": [{"solution": "def extract_singly(list_of_lists):\n # Initialize an empty set to collect unique numbers\n result_set = set()\n # Iterate over each sublist (or tuple)\n for sublist in list_of_lists:\n # Add each element of the sublist to the result set\n for item in sublist:\n result_set.add(item)\n return result_set", "matching_cluster_idx": 3}, {"solution": "def extract_singly(list_of_tuples):\n # Using set comprehension to extract unique numbers from the list of tuples\n return {num for sublist in list_of_tuples for num in sublist}", "matching_cluster_idx": 5}, {"solution": "def extract_singly(list_of_lists):\n # We use a set to store the unique numbers since sets automatically handle duplicates\n result_set = set()\n \n # Loop through each sublist in the list of lists\n for sublist in list_of_lists:\n # Add each number in the sublist to the set\n result_set.update(sublist)\n \n # Return the result as a set\n return result_set", "matching_cluster_idx": 6}, {"solution": "def extract_singly(list_of_lists):\n # Use a set comprehension to flatten the list of lists into a set\n return {element for sublist in list_of_lists for element in sublist}", "matching_cluster_idx": 5}, {"solution": "def extract_singly(list_of_lists):\n # Create an empty set to store the unique elements\n result_set = set()\n \n # Iterate through each sublist (or tuple) in the list of lists\n for sublist in list_of_lists:\n # Add each element of the sublist to the set\n result_set.update(sublist)\n \n return result_set", "matching_cluster_idx": 7}, {"solution": "def extract_singly(list_of_lists):\n # Initialize an empty set to store unique numbers\n result_set = set()\n # Iterate over each sublist/tuple in the list_of_lists\n for sublist in list_of_lists:\n # Update the set with elements from the current sublist\n result_set.update(sublist)\n # Return the set containing unique numbers\n return result_set", "matching_cluster_idx": 6}, {"solution": "def extract_singly(list_of_tuples):\n \"\"\"\n Flattens a list of tuples into a set of numbers.\n \n Parameters:\n list_of_tuples (list of tuples): A list containing tuples of numbers.\n\n Returns:\n set: A set containing all unique numbers from the tuples.\n \"\"\"\n result_set = set()\n for tpl in list_of_tuples:\n result_set.update(tpl)\n return result_set", "matching_cluster_idx": 7}, {"solution": "def extract_singly(list_of_lists):\n # Use a set comprehension to flatten the list of lists into a single set\n return {item for sublist in list_of_lists for item in sublist}", "matching_cluster_idx": 5}, {"solution": "def extract_singly(list_of_lists):\n # Use a set comprehension to flatten the list of lists into a single set\n return {element for sublist in list_of_lists for element in sublist}", "matching_cluster_idx": 5}, {"solution": "def extract_singly(list_of_lists):\n \"\"\"\n Flattens a list of lists into a single set of unique numbers.\n \n :param list_of_lists: A list of tuples, where each tuple contains numbers\n :return: A set containing all unique numbers from the tuples\n \"\"\"\n # Use a set comprehension to flatten the list of lists into a single set\n return {num for sublist in list_of_lists for num in sublist}", "matching_cluster_idx": 5}, {"solution": "def extract_singly(list_of_lists):\n # Create an empty set to store unique numbers\n result_set = set()\n \n # Iterate through each list in the list of lists\n for sublist in list_of_lists:\n # Add elements of the sublist to the result set\n result_set.update(sublist)\n \n return result_set", "matching_cluster_idx": 6}, {"solution": "def extract_singly(list_of_lists):\n # Initialize an empty set to collect unique numbers\n result_set = set()\n \n # Iterate through each sublist or tuple in the main list\n for sublist in list_of_lists:\n # Update the set with elements from the current sublist/tuple\n result_set.update(sublist)\n \n # Return the set containing all unique elements\n return result_set", "matching_cluster_idx": 6}, {"solution": "def extract_singly(list_of_lists):\n \"\"\"\n Flatten a list of lists into a single set of numbers.\n \"\"\"\n result_set = set()\n for sublist in list_of_lists:\n result_set.update(sublist)\n return result_set", "matching_cluster_idx": 7}, {"solution": "def extract_singly(list_of_lists):\n # Initialize an empty set to hold the unique numbers\n result_set = set()\n \n # Iterate over each sublist (which is a tuple here)\n for sublist in list_of_lists:\n # Update the set with elements from the sublist\n result_set.update(sublist)\n \n return result_set", "matching_cluster_idx": 6}, {"solution": "def extract_singly(list_of_lists):\n \"\"\"\n This function takes a list of lists (or tuples) and flattens it into a single set of unique numbers.\n \"\"\"\n result_set = set()\n for sublist in list_of_lists:\n result_set.update(sublist)\n return result_set", "matching_cluster_idx": 6}, {"solution": "def extract_singly(list_of_tuples):\n result = set()\n for tpl in list_of_tuples:\n result.update(tpl)\n return result", "matching_cluster_idx": 6}, {"solution": "def extract_singly(list_of_lists):\n result_set = set()\n for sublist in list_of_lists:\n result_set.update(sublist)\n return result_set", "matching_cluster_idx": 6}, {"solution": "def extract_singly(list_of_tuples):\n # Initialize an empty set to store unique numbers\n result_set = set()\n \n # Iterate through each tuple in the list of tuples\n for tpl in list_of_tuples:\n # Add each element of the tuple to the set\n for number in tpl:\n result_set.add(number)\n \n # Return the resulting set\n return result_set", "matching_cluster_idx": 3}, {"solution": "def extract_singly(list_of_lists):\n # Use a set to store unique numbers\n result_set = set()\n # Iterate through each list in the list of lists\n for sublist in list_of_lists:\n # Add each element of the sublist to the set\n result_set.update(sublist)\n return result_set", "matching_cluster_idx": 6}, {"solution": "def extract_singly(list_of_lists):\n \"\"\"\n Flattens a list of lists (or tuples) into a single set of unique numbers.\n\n Parameters:\n list_of_lists (list): A list containing sublists (or tuples) of numbers.\n\n Returns:\n set: A set of unique numbers from all sublists.\n \"\"\"\n result_set = set()\n for sublist in list_of_lists:\n for item in sublist:\n result_set.add(item)\n return result_set", "matching_cluster_idx": 3}]}, "Mbpp/141": {"dps": 57.18820861678005, "dps_norm": 38.75, "pass@1": 58.0, "profiled": [{"solution": "def pancake_sort(arr):\n def flip(sublist, k):\n \"\"\"Helper function to reverse the sublist up to the index k.\"\"\"\n start = 0\n while start < k:\n sublist[start], sublist[k] = sublist[k], sublist[start]\n start += 1\n k -= 1\n\n n = len(arr)\n # Traverse through all array elements\n for curr_size in range(n, 1, -1):\n # Find the index of the maximum element in the array [0..curr_size-1]\n max_index = arr.index(max(arr[:curr_size]))\n\n # Move the maximum element to end of current array if it's not already there\n if max_index != curr_size - 1:\n # Flip the maximum number to the beginning if needed\n flip(arr, max_index)\n\n # Flip it to the end of the current array\n flip(arr, curr_size - 1)\n\n return arr", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(arr):\n def flip(sublist, k):\n \"\"\"Reverse the order of the first k elements of the sublist.\"\"\"\n start = 0\n while start < k:\n sublist[start], sublist[k] = sublist[k], sublist[start]\n start += 1\n k -= 1\n\n n = len(arr)\n # Start sorting the array\n for size in range(n, 1, -1):\n # Find the index of the largest element in the unsorted part of the array\n max_index = 0\n for i in range(1, size):\n if arr[i] > arr[max_index]:\n max_index = i\n \n # If the largest element is not at its correct position, we need to flip\n if max_index != size - 1:\n # First flip the largest element to the front if it's not already there\n if max_index != 0:\n flip(arr, max_index)\n \n # Now flip it to its correct position\n flip(arr, size - 1)\n \n return arr", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(arr):\n def flip(end):\n \"\"\"Flip function to reverse the array from start to end.\"\"\"\n start = 0\n while start < end:\n arr[start], arr[end] = arr[end], arr[start]\n start += 1\n end -= 1\n\n n = len(arr)\n # We decrease the size of the array to be sorted by one in each iteration\n for curr_size in range(n, 1, -1):\n # Find the index of the largest element within the unsorted portion\n max_index = arr.index(max(arr[:curr_size]))\n\n # Move the largest element to the end of the unsorted portion\n if max_index != curr_size - 1:\n # Flip the largest element to the front\n flip(max_index)\n # Flip it to its correct position\n flip(curr_size - 1)\n return arr", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(arr):\n # Helper function to flip the array till the given index\n def flip(end):\n start = 0\n while start < end:\n arr[start], arr[end] = arr[end], arr[start]\n start += 1\n end -= 1\n \n # Sort the array\n n = len(arr)\n for current_size in range(n, 1, -1):\n # Find the index of the maximum element in arr[0..current_size-1]\n max_index = max(range(current_size), key=arr.__getitem__)\n \n # Move the maximum element to the end of the current array\n if max_index != current_size - 1:\n # Flip the maximum number to the front if it's not already at the front\n if max_index != 0:\n flip(max_index)\n # Flip it to its correct position\n flip(current_size - 1)\n \n return arr", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(arr):\n def flip(end):\n \"\"\"Flips the array up to the index `end`.\"\"\"\n start = 0\n while start < end:\n arr[start], arr[end] = arr[end], arr[start]\n start += 1\n end -= 1\n\n n = len(arr)\n for size in range(n, 1, -1):\n # Find the maximum element in the unsorted part of the array.\n max_index = 0\n for i in range(1, size):\n if arr[i] > arr[max_index]:\n max_index = i\n \n if max_index != size - 1:\n # Flip the maximum element to the start if it's not already there.\n flip(max_index)\n # Now flip it to the end of the unsorted part of the array.\n flip(size - 1)\n \n return arr", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(arr):\n def flip(sub_arr, k):\n \"\"\" Helper function to reverse the first k elements of the sub_arr. \"\"\"\n start = 0\n while start < k:\n sub_arr[start], sub_arr[k] = sub_arr[k], sub_arr[start]\n start += 1\n k -= 1\n\n n = len(arr)\n for curr_size in range(n, 1, -1):\n # Find the index of the maximum element in the array\n max_index = 0\n for i in range(1, curr_size):\n if arr[i] > arr[max_index]:\n max_index = i\n\n # If the max element is not at its position, move it to the start and then to its correct position\n if max_index != curr_size - 1:\n # Bring the maximum element to the front\n flip(arr, max_index)\n # Move it to its correct position\n flip(arr, curr_size - 1)\n \n return arr", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(arr):\n def flip(end):\n start = 0\n while start < end:\n arr[start], arr[end] = arr[end], arr[start]\n start += 1\n end -= 1\n\n n = len(arr)\n for size in range(n, 1, -1):\n # Find index of the maximum element in arr[0:size]\n max_idx = 0\n for i in range(1, size):\n if arr[i] > arr[max_idx]:\n max_idx = i\n\n # Move the maximum element to the end of the current array\n if max_idx != size - 1:\n # Flip the maximum element to the front\n flip(max_idx)\n # Flip it to its correct position\n flip(size - 1)\n\n return arr", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(arr):\n def flip(end_index):\n \"\"\"Reverse the order of the first end_index+1 elements in the array\"\"\"\n start = 0\n while start < end_index:\n arr[start], arr[end_index] = arr[end_index], arr[start]\n start += 1\n end_index -= 1\n\n def find_max_index(n):\n \"\"\"Find the index of the maximum element in arr[0..n-1]\"\"\"\n max_index = 0\n for i in range(1, n):\n if arr[i] > arr[max_index]:\n max_index = i\n return max_index\n\n n = len(arr)\n for size in range(n, 1, -1):\n # Find the index of the largest element not yet sorted\n max_index = find_max_index(size)\n \n if max_index != size - 1:\n # Flip the largest element to the start of the list\n flip(max_index)\n # Flip it to its correct position\n flip(size - 1)\n \n return arr", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(arr):\n def flip(end):\n start = 0\n while start < end:\n arr[start], arr[end] = arr[end], arr[start]\n start += 1\n end -= 1\n \n def find_max_index(n):\n max_index = 0\n for i in range(1, n):\n if arr[i] > arr[max_index]:\n max_index = i\n return max_index\n \n n = len(arr)\n for current_size in range(n, 1, -1):\n max_index = find_max_index(current_size)\n if max_index != current_size - 1:\n flip(max_index)\n flip(current_size - 1)\n \n return arr", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(arr):\n # Helper function to flip the array up to the given index\n def flip(arr, end):\n start = 0\n while start < end:\n arr[start], arr[end] = arr[end], arr[start]\n start += 1\n end -= 1\n\n n = len(arr)\n for size in range(n, 1, -1):\n # Find the index of the maximum element in arr[0:size]\n max_index = max(range(size), key=arr.__getitem__)\n\n # If the maximum element is not already at the end of the current range\n if max_index != size - 1:\n # Flip the maximum element to the beginning if it's not already there\n if max_index != 0:\n flip(arr, max_index)\n # Flip it to the end\n flip(arr, size - 1)\n\n return arr", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(arr):\n def flip(sub_arr, k):\n # Reverse the order of the first k elements in the sub-array\n i = 0\n while i < k:\n sub_arr[i], sub_arr[k] = sub_arr[k], sub_arr[i]\n i += 1\n k -= 1\n\n n = len(arr)\n for curr_size in range(n, 1, -1):\n # Find the index of the maximum element in arr[0:curr_size]\n max_idx = 0\n for i in range(1, curr_size):\n if arr[i] > arr[max_idx]:\n max_idx = i\n\n # Move the maximum element to the end of the current array\n if max_idx != curr_size - 1:\n # First move max element to front (if it's not already there)\n flip(arr, max_idx)\n # Now move it to the end\n flip(arr, curr_size - 1)\n\n return arr", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(arr):\n def flip(sublist, k):\n \"\"\"Helper function to reverse the first k elements of the sublist.\"\"\"\n sublist[:k] = sublist[:k][::-1]\n \n n = len(arr)\n for size in range(n, 1, -1):\n # Find the maximum element in the unsorted sublist arr[:size]\n max_index = arr.index(max(arr[:size]))\n \n # If the maximum element is not already at the end of the sublist\n if max_index != size - 1:\n # Flip the maximum element to the front\n flip(arr, max_index + 1)\n # Flip it to the end of the current sublist\n flip(arr, size)\n \n return arr", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(arr):\n def flip(sublist, k):\n \"\"\"Reverses the order of the first k elements in the sublist.\"\"\"\n left = 0\n while left < k:\n sublist[left], sublist[k] = sublist[k], sublist[left]\n left += 1\n k -= 1\n\n n = len(arr)\n for current_size in range(n, 1, -1):\n # Find the index of the maximum element in arr[0:current_size]\n max_index = 0\n for i in range(1, current_size):\n if arr[i] > arr[max_index]:\n max_index = i\n \n # Move the maximum element to the end of the current list\n if max_index != current_size - 1:\n # Step 1: Flip the maximum number to the beginning\n flip(arr, max_index)\n # Step 2: Now flip it to the end\n flip(arr, current_size - 1)\n\n return arr", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(arr):\n def flip(end):\n start = 0\n while start < end:\n arr[start], arr[end] = arr[end], arr[start]\n start += 1\n end -= 1\n\n def find_max_index(n):\n max_index = 0\n for i in range(1, n):\n if arr[i] > arr[max_index]:\n max_index = i\n return max_index\n\n n = len(arr)\n for size in range(n, 1, -1):\n max_index = find_max_index(size)\n if max_index != size - 1:\n # Flip max element to the front if it's not already at the front\n if max_index != 0:\n flip(max_index)\n # Flip max element to its correct position\n flip(size - 1)\n\n return arr", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(arr):\n # Helper function to flip the array up to the kth index\n def flip(sub_arr, k):\n start = 0\n while start < k:\n sub_arr[start], sub_arr[k] = sub_arr[k], sub_arr[start]\n start += 1\n k -= 1\n\n n = len(arr)\n # Go through all elements starting from the whole array\n for curr_size in range(n, 1, -1):\n # Find the index of the maximum element in the current subarray\n max_index = 0\n for i in range(1, curr_size):\n if arr[i] > arr[max_index]:\n max_index = i\n\n # If the maximum element is not at its correct position, move it\n if max_index != curr_size - 1:\n # Flip the maximum number to the front if it's not already at the front\n if max_index > 0:\n flip(arr, max_index)\n # Now flip it to its correct position\n flip(arr, curr_size - 1)\n\n return arr", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(arr):\n def flip(end):\n start = 0\n while start < end:\n arr[start], arr[end] = arr[end], arr[start]\n start += 1\n end -= 1\n\n def find_max_index(end):\n max_idx = 0\n for i in range(1, end + 1):\n if arr[i] > arr[max_idx]:\n max_idx = i\n return max_idx\n\n n = len(arr)\n for curr_size in range(n, 1, -1):\n max_idx = find_max_index(curr_size - 1)\n if max_idx != curr_size - 1:\n flip(max_idx)\n flip(curr_size - 1)\n return arr", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(arr):\n def flip(end):\n start = 0\n while start < end:\n arr[start], arr[end] = arr[end], arr[start]\n start += 1\n end -= 1\n\n def find_max_index(n):\n max_index = 0\n for i in range(1, n):\n if arr[i] > arr[max_index]:\n max_index = i\n return max_index\n\n n = len(arr)\n for curr_size in range(n, 1, -1):\n max_index = find_max_index(curr_size)\n if max_index != curr_size - 1:\n flip(max_index)\n flip(curr_size - 1)\n \n return arr", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(arr):\n # Function to flip array till the given index\n def flip(arr, i):\n start = 0\n while start < i:\n arr[start], arr[i] = arr[i], arr[start]\n start += 1\n i -= 1\n\n # Iterate from the entire array length to 1\n for curr_size in range(len(arr), 1, -1):\n # Find index of the maximum element in arr[0..curr_size-1]\n max_idx = arr.index(max(arr[0:curr_size]))\n\n # Move the maximum element to the end of the current array\n # If it's not already at the current position\n if max_idx != curr_size - 1:\n # Flip the maximum element to the front if it's not already there\n if max_idx != 0:\n flip(arr, max_idx)\n\n # Flip it to the end position\n flip(arr, curr_size - 1)\n \n return arr", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(arr):\n def flip(sub_arr, k):\n \"\"\"Reverse the first k elements of sub_arr.\"\"\"\n sub_arr[:k] = reversed(sub_arr[:k])\n\n n = len(arr)\n for curr_size in range(n, 1, -1):\n # Find the index of the maximum element in arr[0:curr_size]\n max_index = max(range(curr_size), key=arr.__getitem__)\n\n # Move the maximum element to the end of the current array\n if max_index != curr_size - 1:\n # Flip the maximum element to the beginning if it's not already there\n if max_index != 0:\n flip(arr, max_index + 1)\n\n # Flip it to the end of the array\n flip(arr, curr_size)\n\n return arr", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(arr):\n def flip(end):\n \"\"\"Reverses the array from start to end.\"\"\"\n start = 0\n while start < end:\n arr[start], arr[end] = arr[end], arr[start]\n start, end = start + 1, end - 1\n\n def find_max_index(end):\n \"\"\"Finds the index of the maximum value in arr[0:end].\"\"\"\n max_idx = 0\n for i in range(1, end + 1):\n if arr[i] > arr[max_idx]:\n max_idx = i\n return max_idx\n\n n = len(arr)\n for size in range(n, 1, -1):\n # Find the index of the maximum element in the unsorted part of the array\n max_idx = find_max_index(size - 1)\n \n # If the maximum element is not already at the end of the current range\n if max_idx != size - 1:\n # Flip it to the beginning\n flip(max_idx)\n # Then flip it to the end of the current range\n flip(size - 1)\n\n return arr", "matching_cluster_idx": 2}]}, "Mbpp/166": {"dps": 96.79999999999998, "dps_norm": 80.0, "pass@1": 98.0, "profiled": [{"solution": "def find_even_pair(lst):\n \"\"\"\n This function returns the number of pairs of integers in the list `lst` that XOR to an even number.\n \"\"\"\n count_even = 0\n count_odd = 0\n \n # Count the number of even and odd numbers in the list\n for number in lst:\n if number % 2 == 0:\n count_even += 1\n else:\n count_odd += 1\n \n # A pair (a, b) XORs to an even number if both numbers are even or both are odd\n # Count pairs of even numbers\n even_pairs = count_even * (count_even - 1) // 2\n # Count pairs of odd numbers\n odd_pairs = count_odd * (count_odd - 1) // 2\n \n return even_pairs + odd_pairs", "matching_cluster_idx": 2}, {"solution": "def find_even_pair(numbers):\n # XOR of two numbers is even if both numbers have the same parity\n # (i.e., both are even or both are odd).\n\n # Count how many even and how many odd numbers there are\n even_count = 0\n odd_count = 0\n\n for number in numbers:\n if number % 2 == 0:\n even_count += 1\n else:\n odd_count += 1\n\n # Count pairs of even numbers and pairs of odd numbers\n even_pairs = (even_count * (even_count - 1)) // 2\n odd_pairs = (odd_count * (odd_count - 1)) // 2\n\n # Total pairs that XOR to an even number\n total_even_xor_pairs = even_pairs + odd_pairs\n return total_even_xor_pairs", "matching_cluster_idx": 2}, {"solution": "def find_even_pair(nums):\n \"\"\"\n Counts the number of pairs of integers in the list nums that XOR to an even number.\n \n A pair (nums[i], nums[j]) XORs to an even number if and only if both numbers have the same parity\n (both are even or both are odd).\n \"\"\"\n # Count even and odd numbers\n even_count = sum(1 for x in nums if x % 2 == 0)\n odd_count = len(nums) - even_count\n\n # Calculate number of valid pairs (combinations)\n even_pairs = even_count * (even_count - 1) // 2\n odd_pairs = odd_count * (odd_count - 1) // 2\n \n # Total pairs that XOR to an even number\n return even_pairs + odd_pairs", "matching_cluster_idx": 3}, {"solution": "def find_even_pair(numbers):\n \"\"\"\n This function counts the number of pairs of integers in a list that XOR to an even number.\n \n XOR of two numbers is even if both numbers are either even or odd.\n \"\"\"\n even_count = 0\n odd_count = 0\n\n # Count even and odd numbers\n for number in numbers:\n if number % 2 == 0:\n even_count += 1\n else:\n odd_count += 1\n\n # Calculate pairs\n even_pairs = (even_count * (even_count - 1)) // 2\n odd_pairs = (odd_count * (odd_count - 1)) // 2\n\n # Total pairs that XOR to an even number\n return even_pairs + odd_pairs", "matching_cluster_idx": 2}, {"solution": "def find_even_pair(numbers):\n \"\"\"\n Counts the number of pairs of integers in the list that XOR to an even number.\n :param numbers: List of integers\n :return: Count of pairs whose XOR is even\n \"\"\"\n count_even = 0\n count_odd = 0\n\n for num in numbers:\n if num % 2 == 0:\n count_even += 1\n else:\n count_odd += 1\n\n # To have an even result in XOR operation, both numbers in the pair should have the same parity.\n # Therefore, we calculate:\n # Pairs with both numbers even: choose 2 out of count_even\n # Pairs with both numbers odd: choose 2 out of count_odd\n # Combination count nC2 = n * (n - 1) // 2\n\n even_pairs = count_even * (count_even - 1) // 2\n odd_pairs = count_odd * (count_odd - 1) // 2\n\n return even_pairs + odd_pairs", "matching_cluster_idx": 2}, {"solution": "def find_even_pair(nums):\n \"\"\"\n This function counts the number of pairs of integers in a list\n that XOR to an even number.\n \"\"\"\n # To XOR to an even number, the two numbers must have the same parity.\n even_count = 0\n odd_count = 0\n\n # Count the number of even and odd numbers\n for num in nums:\n if num % 2 == 0:\n even_count += 1\n else:\n odd_count += 1\n\n # Pairs with even XOR:\n # - Any two even numbers\n # - Any two odd numbers\n even_pairs = even_count * (even_count - 1) // 2 # nC2 combinations for evens\n odd_pairs = odd_count * (odd_count - 1) // 2 # nC2 combinations for odds\n\n # Total pairs with even XOR\n return even_pairs + odd_pairs", "matching_cluster_idx": 2}, {"solution": "def find_even_pair(arr):\n \"\"\"\n Counts the number of pairs of integers in a list such that their XOR is an even number.\n\n :param arr: List of integers\n :return: Count of pairs with XOR result as even\n \"\"\"\n even_count = 0\n odd_count = 0\n\n # Count how many numbers are even and how many are odd\n for num in arr:\n if num % 2 == 0:\n even_count += 1\n else:\n odd_count += 1\n \n # A pair will have an even XOR if both numbers are either even-even or odd-odd.\n # Calculate such pairs:\n even_pairs = even_count * (even_count - 1) // 2 # even-even pairs\n odd_pairs = odd_count * (odd_count - 1) // 2 # odd-odd pairs\n \n return even_pairs + odd_pairs", "matching_cluster_idx": 2}, {"solution": "def find_even_pair(lst):\n # Initialize counters for odd and even numbers\n even_count = 0\n odd_count = 0\n \n # Count the number of even and odd numbers in the list\n for num in lst:\n if num % 2 == 0:\n even_count += 1\n else:\n odd_count += 1\n \n # A pair of integers xor to an even number if both integers are either even or both are odd.\n # Calculate pairs:\n # Pairs of two evens:\n even_pairs = even_count * (even_count - 1) // 2\n # Pairs of two odds:\n odd_pairs = odd_count * (odd_count - 1) // 2\n \n # Total pairs that XOR to an even number\n return even_pairs + odd_pairs", "matching_cluster_idx": 2}, {"solution": "def find_even_pair(nums):\n \"\"\"\n Counts the number of pairs (i, j) where i < j such that nums[i] XOR nums[j] is even.\n XOR of two numbers is even if both numbers have the same parity.\n \"\"\"\n odd_count = 0\n even_count = 0\n\n for num in nums:\n if num % 2 == 0:\n even_count += 1\n else:\n odd_count += 1\n\n # Pairs with even parity or pairs with odd parity will give even result when XORed\n even_pairs = even_count * (even_count - 1) // 2\n odd_pairs = odd_count * (odd_count - 1) // 2\n\n return even_pairs + odd_pairs", "matching_cluster_idx": 2}, {"solution": "def find_even_pair(nums):\n \"\"\"\n Counts the number of pairs of integers in a list that XOR to an even number.\n \n :param nums: List[int] - a list of integers\n :return: int - the number of pairs that XOR to an even number\n \"\"\"\n # XOR of two numbers is even if and only if both have the same parity\n # Therefore, we need to count pairs of both even-even and odd-odd numbers\n \n # Count the number of even and odd numbers in the list\n even_count = sum(1 for num in nums if num % 2 == 0)\n odd_count = len(nums) - even_count # rest are odd numbers\n\n # Number of pairs from n items is n * (n - 1) // 2\n even_pairs = even_count * (even_count - 1) // 2\n odd_pairs = odd_count * (odd_count - 1) // 2\n\n # Total pairs with even XOR\n return even_pairs + odd_pairs", "matching_cluster_idx": 3}, {"solution": "def find_even_pair(lst):\n \"\"\"\n This function counts the number of pairs of integers in a list that xor to an even number.\n\n Parameters:\n lst (list of int): The list of integers.\n\n Returns:\n int: The number of pairs whose XOR is even.\n \"\"\"\n # To have an even result in XOR, both numbers must have the same parity\n # So we count numbers with even parity and odd parity\n even_count = sum(1 for x in lst if x % 2 == 0)\n odd_count = len(lst) - even_count\n \n # Pairs formed by two evens and two odds are valid (xor is even)\n even_pairs = even_count * (even_count - 1) // 2\n odd_pairs = odd_count * (odd_count - 1) // 2\n\n return even_pairs + odd_pairs", "matching_cluster_idx": 3}, {"solution": "def find_even_pair(lst):\n \"\"\"\n This function counts the number of pairs (i, j) with i < j\n such that lst[i] ^ lst[j] is even.\n \"\"\"\n even_count = 0\n odd_count = 0\n\n for num in lst:\n if num % 2 == 0:\n even_count += 1\n else:\n odd_count += 1\n\n # To get an even XOR result, both numbers must be even or both must be odd.\n # Calculate pairs of even numbers\n even_pairs = even_count * (even_count - 1) // 2\n # Calculate pairs of odd numbers\n odd_pairs = odd_count * (odd_count - 1) // 2\n\n return even_pairs + odd_pairs", "matching_cluster_idx": 2}, {"solution": "def find_even_pair(numbers):\n # XOR of two numbers is even if both numbers have the same parity\n # (both are even or both are odd).\n \n even_count = 0\n odd_count = 0\n \n # Count the number of even and odd numbers in the list\n for num in numbers:\n if num % 2 == 0:\n even_count += 1\n else:\n odd_count += 1\n \n # Pairs from even numbers\n even_pairs = (even_count * (even_count - 1)) // 2\n # Pairs from odd numbers\n odd_pairs = (odd_count * (odd_count - 1)) // 2\n \n # Total even XOR pairs are the sum of even_pairs and odd_pairs\n total_even_pairs = even_pairs + odd_pairs\n \n return total_even_pairs", "matching_cluster_idx": 2}, {"solution": "def find_even_pair(nums):\n even_count = 0\n odd_count = 0\n \n # Count how many even and odd numbers there are in the list\n for num in nums:\n if num % 2 == 0:\n even_count += 1\n else:\n odd_count += 1\n \n # Calculate the number of pairs (i, j) with i < j that XOR to an even number\n # An XOR is even if both numbers have the same parity\n # So we count pairs among even numbers and pairs among odd numbers\n even_pairs = even_count * (even_count - 1) // 2\n odd_pairs = odd_count * (odd_count - 1) // 2\n \n return even_pairs + odd_pairs", "matching_cluster_idx": 2}, {"solution": "def find_even_pair(numbers):\n # Count how many numbers are odd and how many are even\n odd_count = 0\n even_count = 0\n\n for num in numbers:\n if num % 2 == 0:\n even_count += 1\n else:\n odd_count += 1\n\n # A pair of numbers will have an even XOR if both are even or both are odd\n even_pairs = (even_count * (even_count - 1)) // 2 # Pairs of evens\n odd_pairs = (odd_count * (odd_count - 1)) // 2 # Pairs of odds\n\n return even_pairs + odd_pairs", "matching_cluster_idx": 2}, {"solution": "def find_even_pair(nums):\n # To XOR to an even number, the two numbers must have the same parity.\n # Count the number of even and odd numbers.\n even_count = 0\n odd_count = 0\n\n for num in nums:\n if num % 2 == 0:\n even_count += 1\n else:\n odd_count += 1\n\n # Calculate the number of pairs that XOR to an even number.\n # These are pairs of even numbers and pairs of odd numbers.\n even_pairs = (even_count * (even_count - 1)) // 2\n odd_pairs = (odd_count * (odd_count - 1)) // 2\n\n # Total pairs that XOR to an even number.\n total_pairs = even_pairs + odd_pairs\n\n return total_pairs", "matching_cluster_idx": 2}, {"solution": "def find_even_pair(nums):\n \"\"\"\n Returns the number of pairs (i, j) in the list nums such that i < j and nums[i] ^ nums[j] is even.\n \"\"\"\n even_count = 0\n odd_count = 0\n\n # Count the number of even and odd integers in the list\n for num in nums:\n if num % 2 == 0:\n even_count += 1\n else:\n odd_count += 1\n\n # A pair's XOR is even if both numbers are even or both numbers are odd\n # Count even-even pairs and odd-odd pairs\n even_even_pairs = (even_count * (even_count - 1)) // 2\n odd_odd_pairs = (odd_count * (odd_count - 1)) // 2\n\n return even_even_pairs + odd_odd_pairs", "matching_cluster_idx": 2}, {"solution": "def find_even_pair(numbers):\n # We need to count the pairs (a, b) such that a ^ b is even.\n # a ^ b is even when both a and b are even or both are odd.\n \n even_count = 0\n odd_count = 0\n \n # Count the number of even and odd numbers in the list\n for num in numbers:\n if num % 2 == 0:\n even_count += 1\n else:\n odd_count += 1\n \n # Count pairs\n even_pairs = (even_count * (even_count - 1)) // 2\n odd_pairs = (odd_count * (odd_count - 1)) // 2\n \n # Total pairs that result in even XOR\n total_even_xor_pairs = even_pairs + odd_pairs\n \n return total_even_xor_pairs", "matching_cluster_idx": 2}, {"solution": "def find_even_pair(numbers):\n # Count even and odd numbers in the list\n count_even = sum(1 for x in numbers if x % 2 == 0)\n count_odd = len(numbers) - count_even # Remaining are odd numbers\n \n # Pairs that XOR to even consist of both numbers being even or both being odd\n # The number of such pairs can be calculated using combination formula nC2 = n*(n-1)//2\n even_pairs = count_even * (count_even - 1) // 2\n odd_pairs = count_odd * (count_odd - 1) // 2\n \n # Total pairs that XOR to an even number\n total_pairs = even_pairs + odd_pairs\n \n return total_pairs", "matching_cluster_idx": 3}, {"solution": "def find_even_pair(arr):\n # Initialize counters for even and odd numbers\n even_count = 0\n odd_count = 0\n \n # Count the number of even and odd numbers in the array\n for num in arr:\n if num % 2 == 0:\n even_count += 1\n else:\n odd_count += 1\n \n # An XOR of two numbers is even if both numbers are even or both are odd\n # The total number of such pairs is the number of ways to choose 2 evens plus the number of ways to choose 2 odds\n even_pairs = even_count * (even_count - 1) // 2\n odd_pairs = odd_count * (odd_count - 1) // 2\n \n # Return the sum of these pairs\n return even_pairs + odd_pairs", "matching_cluster_idx": 2}]}, "Mbpp/170": {"dps": null, "dps_norm": null, "pass@1": 9.0, "profiled": []}, "Mbpp/226": {"dps": 87.44186046511628, "dps_norm": 76.42857142857143, "pass@1": 100.0, "profiled": [{"solution": "def odd_values_string(s: str) -> str:\n \"\"\"\n Returns a new string with characters at odd indices removed from the input string `s`.\n \n Parameters:\n s (str): The input string from which characters at odd indices will be removed.\n\n Returns:\n str: A new string with characters at even indices of the original string `s`.\n \"\"\"\n return s[::2]", "matching_cluster_idx": 6}, {"solution": "def odd_values_string(input_string):\n \"\"\"\n Removes characters with odd index values from a given string.\n\n Parameters:\n input_string (str): The string from which to remove characters with odd index values.\n\n Returns:\n str: A new string with characters at even index values only.\n \"\"\"\n # Extract characters at even indices\n result = input_string[::2]\n return result", "matching_cluster_idx": 5}, {"solution": "def odd_values_string(input_string):\n \"\"\"\n Removes characters which have odd index values from the given string.\n\n Parameters:\n input_string (str): The string from which to remove odd-indexed characters.\n\n Returns:\n str: A new string with only characters from even indices of the input string.\n \"\"\"\n # Use a list comprehension to filter out characters at odd indices\n return ''.join([char for index, char in enumerate(input_string) if index % 2 == 0])", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(s):\n \"\"\"\n This function removes characters which have odd index values from the input string.\n \n Parameters:\n s (str): The input string from which characters at odd indices will be removed.\n\n Returns:\n str: A new string with characters at odd indices removed.\n \"\"\"\n # Use string slicing to get characters at even indices\n return s[::2]", "matching_cluster_idx": 5}, {"solution": "def odd_values_string(s):\n # Create a new string consisting of characters at even indices\n result = s[::2]\n return result", "matching_cluster_idx": 5}, {"solution": "def odd_values_string(input_string):\n \"\"\"\n Remove the characters which have odd index values from the input string.\n\n Parameters:\n input_string (str): The input string from which characters at odd indices are to be removed.\n\n Returns:\n str: A new string with characters at odd indices removed.\n \"\"\"\n # Return a new string containing only characters at even indices\n return input_string[::2]", "matching_cluster_idx": 6}, {"solution": "def odd_values_string(s):\n \"\"\"\n This function removes the characters which have odd index values from the given string `s`.\n Args:\n s (str): The input string from which odd index characters need to be removed.\n \n Returns:\n str: A string with characters at odd indices removed.\n \"\"\"\n # Create a new string with characters at even indices\n return s[::2]", "matching_cluster_idx": 6}, {"solution": "def odd_values_string(s):\n \"\"\"\n This function takes a string 's' and returns a new string\n consisting of the characters from 's' that have even index values.\n \"\"\"\n # Use list comprehension to select characters at even indices\n return ''.join([s[i] for i in range(len(s)) if i % 2 == 0])", "matching_cluster_idx": 1}, {"solution": "def odd_values_string(input_string):\n \"\"\"\n This function returns a new string with characters at odd index positions removed from the input string.\n \n :param input_string: The original string from which to remove characters.\n :return: A new string with characters at odd index positions removed.\n \"\"\"\n return input_string[::2]", "matching_cluster_idx": 5}, {"solution": "def odd_values_string(s: str) -> str:\n \"\"\"Return a new string consisting of characters at even index positions.\"\"\"\n # Extract characters with even index positions\n return s[::2]", "matching_cluster_idx": 5}, {"solution": "def odd_values_string(s: str) -> str:\n \"\"\"\n This function takes a string `s` and returns a new string\n with characters that have odd index values removed.\n\n :param s: The input string from which odd-indexed characters should be removed.\n :return: A string containing only characters from even indices of the input string.\n \"\"\"\n return s[::2]", "matching_cluster_idx": 5}, {"solution": "def odd_values_string(s):\n \"\"\"\n Remove characters which have odd index values in the given string s.\n \"\"\"\n # Use slicing to get only characters at even indices\n return s[::2]", "matching_cluster_idx": 6}, {"solution": "def odd_values_string(s):\n \"\"\"\n Returns a string with characters at odd indices removed.\n \"\"\"\n return s[::2]", "matching_cluster_idx": 5}, {"solution": "def odd_values_string(input_string: str) -> str:\n # Initialize an empty string to collect characters with even indices.\n result = ''\n \n # Iterate over the string using an index.\n for index in range(len(input_string)):\n # If the index is even, add the character at this index to the result.\n if index % 2 == 0:\n result += input_string[index]\n \n return result", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(s: str) -> str:\n \"\"\"\n Remove characters which have odd index values from the given string.\n \n Parameters:\n s (str): The input string from which to remove characters with odd indices.\n \n Returns:\n str: A string containing only characters from even indices.\n \"\"\"\n # Using slicing to get characters at even indices\n return s[::2]", "matching_cluster_idx": 6}, {"solution": "def odd_values_string(input_string):\n \"\"\"\n Returns a new string with characters that have odd index values removed from the input string.\n\n Parameters:\n input_string (str): The string from which to remove characters with odd index values.\n\n Returns:\n str: A new string with characters at odd indices removed.\n \"\"\"\n return input_string[::2]", "matching_cluster_idx": 5}, {"solution": "def odd_values_string(s: str) -> str:\n \"\"\"\n Remove the characters which have odd index values from a given string.\n \n :param s: Input string\n :return: A string with characters at odd index values removed\n \"\"\"\n # Use slicing to get characters at even indices\n return s[::2]", "matching_cluster_idx": 5}, {"solution": "def odd_values_string(s: str) -> str:\n # Select characters at even indices (0-based index)\n return s[::2]", "matching_cluster_idx": 5}, {"solution": "def odd_values_string(s):\n \"\"\"\n Remove characters at odd index values from the given string.\n \n Parameters:\n s (str): The input string.\n \n Returns:\n str: A new string with characters at odd indices removed.\n \"\"\"\n # Use slicing to get characters at even indices\n return s[::2]", "matching_cluster_idx": 6}, {"solution": "def odd_values_string(s: str) -> str:\n \"\"\"\n Remove characters with odd index values from the given string.\n\n :param s: The input string.\n :return: A new string with characters at even indices (0, 2, 4, ...).\n \"\"\"\n # Create a new string using characters at even indices\n return ''.join(s[i] for i in range(len(s)) if i % 2 == 0)", "matching_cluster_idx": 0}]}, "Mbpp/230": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def replace_blank(input_string, char):\n \"\"\"\n Replace all spaces in the input_string with the specified char.\n \n Parameters:\n input_string (str): The string in which spaces are to be replaced.\n char (str): The character to replace spaces with.\n \n Returns:\n str: The modified string with spaces replaced by char.\n \"\"\"\n return input_string.replace(' ', char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(s: str, char: str) -> str:\n \"\"\"\n Replaces blank spaces in the input string with the specified character.\n\n Parameters:\n s (str): The input string.\n char (str): The character to replace spaces with.\n\n Returns:\n str: The modified string with spaces replaced by the given character.\n \"\"\"\n return s.replace(' ', char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string, char):\n \"\"\"\n This function takes in a string and a character, replaces all blank spaces in the string\n with the given character, and returns the modified string.\n \n :param input_string: The original string containing spaces\n :param char: The character to replace spaces with\n :return: The modified string with spaces replaced by char\n \"\"\"\n # Replace spaces with the specified character\n result = input_string.replace(' ', char)\n return result", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string, char):\n \"\"\"\n Replaces blank spaces in the input_string with the specified character.\n\n :param input_string: The original string with blank spaces.\n :param char: The character to replace the blank spaces with.\n :return: The modified string with blank spaces replaced by the character.\n \"\"\"\n return input_string.replace(' ', char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(s: str, char: str) -> str:\n \"\"\"\n Replaces all blank spaces in the input string with the specified character.\n\n Args:\n s (str): The input string.\n char (str): The character to replace spaces with.\n\n Returns:\n str: The modified string with spaces replaced by the specified character.\n \"\"\"\n return s.replace(' ', char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(s: str, char: str) -> str:\n \"\"\"\n Replaces blank spaces in the given string with the specified character.\n\n Parameters:\n s (str): The input string containing blank spaces.\n char (str): The character to replace blank spaces with.\n\n Returns:\n str: The modified string with blank spaces replaced by the specified character.\n \"\"\"\n # Replace blank spaces with the given character\n return s.replace(' ', char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string, replace_char):\n \"\"\"\n Replace blank spaces in the input string with the given character.\n \n Args:\n - input_string (str): The string in which spaces need to be replaced.\n - replace_char (str): The character that will replace the spaces.\n \n Returns:\n - str: The modified string with spaces replaced by replace_char.\n \"\"\"\n return input_string.replace(' ', replace_char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string: str, replace_char: str) -> str:\n \"\"\"\n Replaces all blank spaces in the input string with the specified character.\n \n :param input_string: The string in which to replace spaces.\n :param replace_char: The character to replace spaces with.\n :return: The modified string with spaces replaced by replace_char.\n \"\"\"\n # Replace spaces with the specified character\n return input_string.replace(' ', replace_char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(s, char):\n \"\"\"\n Replace blank spaces in the string `s` with the character `char`.\n\n Args:\n s (str): The input string.\n char (str): The character to replace spaces with.\n\n Returns:\n str: The modified string with spaces replaced by `char`.\n \"\"\"\n return s.replace(' ', char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string, char):\n \"\"\"\n Replaces blank spaces in the input_string with the specified character.\n\n Parameters:\n input_string (str): The string in which spaces are to be replaced.\n char (str): The character that will replace blank spaces.\n\n Returns:\n str: A new string with spaces replaced by the given character.\n \"\"\"\n return input_string.replace(' ', char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string, char):\n \"\"\"Replaces blank spaces in the input_string with the given char.\"\"\"\n # Check if the char is actually a single character, if not, raise an error\n if len(char) != 1:\n raise ValueError(\"The replacement character must be a single character.\")\n \n # Replace spaces with the given character\n return input_string.replace(' ', char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(s: str, char: str) -> str:\n \"\"\"\n Replaces all blank spaces in the input string with the specified character.\n\n Parameters:\n s (str): The input string.\n char (str): The character to replace spaces with.\n\n Returns:\n str: The modified string with spaces replaced by the character.\n \"\"\"\n return s.replace(' ', char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string, replacement_char):\n \"\"\"\n Replaces all blank spaces in the input_string with replacement_char and returns the modified string.\n \n Parameters:\n input_string (str): The string in which spaces need to be replaced.\n replacement_char (str): The character that will replace spaces.\n\n Returns:\n str: The modified string with spaces replaced by replacement_char.\n \"\"\"\n return input_string.replace(' ', replacement_char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string, replacement_char):\n \"\"\"\n Replace blank spaces in the input string with the replacement character.\n\n :param input_string: str, the original string with potential blank spaces.\n :param replacement_char: str, the character to replace the blank spaces with.\n :return: str, the modified string with blank spaces replaced.\n \"\"\"\n return input_string.replace(' ', replacement_char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string, character):\n \"\"\"\n Replace all blank spaces in the input_string with the specified character.\n\n Parameters:\n input_string (str): The original string where blank spaces need to be replaced.\n character (str): The character that will replace blank spaces.\n\n Returns:\n str: The modified string with blank spaces replaced by the character.\n \"\"\"\n return input_string.replace(' ', character)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string, char):\n # Replace all blank spaces with the specified character\n return input_string.replace(' ', char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string, replacement_char):\n \"\"\"\n Replace all blank spaces in input_string with replacement_char.\n \n Parameters:\n input_string (str): The string to process.\n replacement_char (str): The character that will replace blank spaces.\n \n Returns:\n str: The modified string with blanks replaced.\n \"\"\"\n # Replace blank spaces with the given character\n return input_string.replace(' ', replacement_char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(s, char):\n \"\"\"\n Replace blank spaces in the string `s` with the character `char`.\n\n Parameters:\n s (str): The input string.\n char (str): The character to replace blank spaces with.\n\n Returns:\n str: The modified string with blank spaces replaced by `char`.\n \"\"\"\n return s.replace(' ', char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string, replacement_char):\n # Use the string replace method to replace spaces with the given character\n return input_string.replace(' ', replacement_char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(s: str, char: str) -> str:\n \"\"\"\n Replaces all blank spaces in the input string with the specified character.\n\n Parameters:\n s (str): The input string with blank spaces to replace.\n char (str): The character to replace blank spaces with.\n\n Returns:\n str: The modified string with blank spaces replaced by the specified character.\n \"\"\"\n return s.replace(' ', char)", "matching_cluster_idx": 7}]}, "Mbpp/239": {"dps": 65.0, "dps_norm": 70.0, "pass@1": 96.0, "profiled": [{"solution": "def get_total_number_of_sequences(m, n):\n # Initialize a 2D list to store the number of sequences ending with a particular number\n dp = [[0] * (m + 1) for _ in range(n + 1)]\n\n # Base case: There's one sequence of length 1 ending with each number from 1 to m\n for j in range(1, m + 1):\n dp[1][j] = 1\n\n # Fill the DP table for sequences of length 2 to n\n for i in range(2, n + 1):\n for j in range(1, m + 1):\n # Find the valid previous elements for the current element j\n k = j // 2 # The previous element must be >= j // 2\n while k > 0:\n dp[i][j] += dp[i - 1][k]\n k -= 1\n\n # Sum all sequences of length n for each ending number from 1 to m\n total_sequences = sum(dp[n][j] for j in range(1, m + 1))\n \n return total_sequences", "matching_cluster_idx": 6}, {"solution": "def get_total_number_of_sequences(m, n):\n # A helper function that uses dynamic programming to count the sequences\n def count_sequences(m, n, last):\n # If the sequence length is zero, we've found a valid sequence\n if n == 0:\n return 1\n\n # If we already have a result for this state, return it\n if (n, last) in memo:\n return memo[(n, last)]\n\n # Calculate the number of sequences\n total = 0\n # Start the next element from 2 * last (or 1 if last is 0) up to m\n start = max(2 * last, 1)\n for i in range(start, m + 1):\n total += count_sequences(m, n - 1, i)\n\n # Memoize the result for current state\n memo[(n, last)] = total\n return total\n\n # Initialize memoization dictionary\n memo = {}\n # Start counting sequences with 0 as the \"previous\" element\n return count_sequences(m, n, 0)", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n \"\"\"\n Computes the total number of sequences of length n, where each element is a positive integer,\n and each element is greater than or equal to twice the previous element, but less than or equal to m.\n \"\"\"\n # Initialize a list to store the number of sequences ending with each possible value\n dp = [[0] * (m + 1) for _ in range(n + 1)]\n \n # There is 1 sequence of length 1 for each starting element between 1 and m\n for j in range(1, m + 1):\n dp[1][j] = 1\n\n # Fill the dp array\n for length in range(2, n + 1): # For each possible length from 2 to n\n for x in range(1, m + 1): # For each possible element x in the sequence\n # Count valid sequences of this length ending with x\n # by considering all valid previous elements\n for previous in range(1, (x // 2) + 1):\n dp[length][x] += dp[length - 1][previous]\n\n # Sum all sequences of length n\n return sum(dp[n][j] for j in range(1, m + 1))", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n def count_sequences(last, remaining):\n if remaining == 0:\n return 1\n total_count = 0\n start = last * 2\n for i in range(start, m + 1):\n total_count += count_sequences(i, remaining - 1)\n return total_count\n\n total_sequences = 0\n for i in range(1, m + 1):\n total_sequences += count_sequences(i, n - 1)\n\n return total_sequences", "matching_cluster_idx": 5}, {"solution": "def get_total_number_of_sequences(m, n):\n # memoization dictionary to store the results of subproblems\n memo = {}\n\n def count_sequences(last, length):\n # Base case: if the sequence has reached the required length\n if length == n:\n return 1\n \n # If the result of the subproblem is already computed, return it\n if (last, length) in memo:\n return memo[(last, length)]\n \n count = 0\n # We start from twice the last element, since the element needs to be >= 2 * last\n start = max(2 * last, 1)\n # We iterate up to m, as each element needs to be <= m\n for next_elem in range(start, m + 1):\n count += count_sequences(next_elem, length + 1)\n \n # Save the result in the memoization dictionary\n memo[(last, length)] = count\n return count\n \n # Initialize count of sequences\n total_count = 0\n # Start from any number from 1 to m as the first element\n for start in range(1, m + 1):\n total_count += count_sequences(start, 1)\n \n return total_count", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n def count_sequences(start, length):\n if length == 0:\n return 1\n total = 0\n for next_val in range(max(2 * start, 1), m + 1):\n total += count_sequences(next_val, length - 1)\n return total\n\n total_sequences = 0\n for start_val in range(1, m + 1):\n total_sequences += count_sequences(start_val, n - 1)\n\n return total_sequences", "matching_cluster_idx": 3}, {"solution": "def get_total_number_of_sequences(m, n):\n # Initialize a 2D DP table where dp[i][j] represents the number of sequences\n # of length j that end with i\n dp = [[0] * (n + 1) for _ in range(m + 1)]\n\n # Base case: sequences of length 1, each element can be itself\n for i in range(1, m + 1):\n dp[i][1] = 1\n\n # Fill the DP table\n for length in range(2, n + 1): # For each sequence length from 2 to n\n for current in range(1, m + 1): # For each possible end element of the sequence\n # Sum up the number of sequences of length `length-1` that can be extended\n # to `current`\n for previous in range(1, current // 2 + 1): # As each element must be >= 2 * previous\n dp[current][length] += dp[previous][length - 1]\n\n # Sum up the number of sequences of length n for all possible ending elements\n return sum(dp[i][n] for i in range(1, m + 1))", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n # We will use dynamic programming to solve this problem.\n # dp[i][j] will represent the number of sequences of length j that end with the number i.\n \n # Initialize a dp table with 0s\n dp = [[0] * (n + 1) for _ in range(m + 1)]\n \n # Base case: There is one sequence of length 1 for each number from 1 to m\n for i in range(1, m + 1):\n dp[i][1] = 1\n \n # Fill the dp table\n for length in range(2, n + 1):\n for current in range(1, m + 1):\n # Calculate possible previous values\n previous_sum = 0\n for previous in range(1, (current // 2) + 1):\n previous_sum += dp[previous][length - 1]\n dp[current][length] = previous_sum\n \n # Sum up all sequences of length n ending with numbers from 1 to m\n total_sequences = sum(dp[i][n] for i in range(1, m + 1))\n return total_sequences", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n def count_sequences(current_value, length):\n if length == n:\n return 1\n count = 0\n # The next value should be at least twice the current value\n next_min_value = current_value * 2\n for next_value in range(next_min_value, m + 1):\n count += count_sequences(next_value, length + 1)\n return count\n\n total_sequences = 0\n # Start the sequence with any number from 1 to m\n for start_value in range(1, m + 1):\n total_sequences += count_sequences(start_value, 1)\n \n return total_sequences", "matching_cluster_idx": 5}, {"solution": "def get_total_number_of_sequences(m, n):\n # Cache to store computed results\n cache = {}\n\n def count_sequences(prev, length):\n # Base case: if the length is zero, we've found a valid sequence\n if length == 0:\n return 1\n \n # Check if the result is already cached\n if (prev, length) in cache:\n return cache[(prev, length)]\n \n # Calculate the start value for the next element\n start = max(1, prev * 2)\n total_count = 0\n\n # Try every valid next element\n for next_element in range(start, m + 1):\n total_count += count_sequences(next_element, length - 1)\n \n # Cache and return the result\n cache[(prev, length)] = total_count\n return total_count\n\n # Initially, there is no previous element, so we start with length n and prev 0\n return count_sequences(0, n)", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n \"\"\"\n Function to compute the number of valid sequences of length n\n such that each element is a positive integer greater than or equal \n to twice the previous element and less than or equal to m.\n \n Parameters:\n m (int): The maximum value an element in the sequence can take.\n n (int): The length of the sequence.\n \n Returns:\n int: Total number of valid sequences of length n.\n \"\"\"\n # Create a memoization table to store results of subproblems\n memo = {}\n \n def count_sequences(prev, length):\n # Base case: If the sequence is of required length, count it\n if length == n:\n return 1\n \n # Check if result is already computed for the current state\n if (prev, length) in memo:\n return memo[(prev, length)]\n \n # Initialize count of valid sequences\n total_count = 0\n \n # Try adding next element which is at least twice the previous one\n # and not more than m\n next_element = max(1, 2 * prev)\n while next_element <= m:\n total_count += count_sequences(next_element, length + 1)\n next_element += 1\n \n # Store result in memoization table and return\n memo[(prev, length)] = total_count\n return total_count\n \n # Start with an initial previous value of 0 and length 0\n # We use 0 because we want the first element to be at least 1\n return count_sequences(0, 0)", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n def count_sequences(current_value, length):\n # Base case: if the sequence is of length n\n if length == n:\n return 1\n\n count = 0\n # Try every number that is at least twice current_value and at most m\n for next_value in range(2 * current_value, m + 1):\n count += count_sequences(next_value, length + 1)\n \n return count\n \n total_count = 0\n # Initialize sequences starting with any number from 1 to m\n for start_value in range(1, m + 1):\n total_count += count_sequences(start_value, 1)\n \n return total_count", "matching_cluster_idx": 5}, {"solution": "def get_total_number_of_sequences(m, n):\n # Initialize a memoization table where dp[i][j] represents the number of valid sequences\n # of length j that end with the integer i.\n dp = [[0] * (n + 1) for _ in range(m + 1)]\n \n # Base case: For sequences of length 1, any number from 1 to m is a valid sequence.\n for i in range(1, m + 1):\n dp[i][1] = 1\n \n # Fill the dp table\n for length in range(2, n + 1): # For sequence lengths from 2 to n\n for i in range(1, m + 1): # Consider numbers from 1 to m\n # For each i, calculate the number of sequences that can end with i of length `length`.\n # You can form a sequence of length `length` ending at `i` by extending a sequence\n # of length `length-1` ending at some number `k` where k * 2 <= i\n for k in range(1, i // 2 + 1):\n dp[i][length] += dp[k][length - 1]\n\n # The answer is the sum of all sequences of length n for all ending numbers from 1 to m\n result = sum(dp[i][n] for i in range(1, m + 1))\n return result", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n def helper(prev, length):\n if length == n:\n return 1\n count = 0\n for i in range(max(1, prev * 2), m + 1):\n count += helper(i, length + 1)\n return count\n\n total_count = 0\n for start in range(1, m + 1):\n total_count += helper(start, 1)\n\n return total_count", "matching_cluster_idx": 3}, {"solution": "def get_total_number_of_sequences(m, n):\n # Dynamic programming table where dp[i][j] is the number of sequences\n # of length j that end with the number i.\n dp = [[0] * (n + 1) for _ in range(m + 1)]\n\n # Base case: for sequences of length 1, we can start with any number from 1 to m.\n for i in range(1, m + 1):\n dp[i][1] = 1\n\n # Fill the DP table\n for j in range(2, n + 1): # For sequence lengths from 2 to n\n for i in range(1, m + 1): # For each possible ending number i\n # Find all previous numbers that can precede i\n for k in range(1, i // 2 + 1):\n dp[i][j] += dp[k][j - 1]\n\n # Sum up all sequences of length n\n total_sequences = sum(dp[i][n] for i in range(1, m + 1))\n\n return total_sequences", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n # dp[i][j] will store the number of valid sequences of length j ending with i\n dp = [[0] * (n + 1) for _ in range(m + 1)]\n\n # Initialize for sequences of length 1\n for i in range(1, m + 1):\n dp[i][1] = 1\n\n # Fill the dp table\n for length in range(2, n + 1):\n for current in range(1, m + 1):\n # We look for all previous elements that can be twice or more less than current\n for previous in range(1, current // 2 + 1):\n dp[current][length] += dp[previous][length - 1]\n\n # Sum up all sequences of length n\n total_sequences = 0\n for i in range(1, m + 1):\n total_sequences += dp[i][n]\n\n return total_sequences", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n # We'll use a recursive approach with memoization to solve this problem.\n # Memoization will store results of subproblems to avoid redundant calculations.\n \n from functools import lru_cache\n\n @lru_cache(None)\n def count_sequences(prev, length):\n # Base case: if the sequence reaches the desired length\n if length == n:\n return 1\n\n total = 0\n # The next element must be at least twice the previous one\n # And it must be less than or equal to m\n start = max(1, 2 * prev)\n for next_elem in range(start, m + 1):\n total += count_sequences(next_elem, length + 1)\n\n return total\n\n # Initialize the process with the first element being a dummy 1\n # Since first element can be anything starting from 1 up to m\n total_sequences = 0\n for first in range(1, m + 1):\n total_sequences += count_sequences(first, 1)\n \n return total_sequences", "matching_cluster_idx": 8}, {"solution": "def get_total_number_of_sequences(m, n):\n def count_sequences(last_element, length):\n if length == 0:\n return 1\n count = 0\n next_element = max(1, last_element * 2)\n while next_element <= m:\n count += count_sequences(next_element, length - 1)\n next_element += 1\n return count\n \n total_count = 0\n for start in range(1, m + 1):\n total_count += count_sequences(start, n - 1)\n \n return total_count", "matching_cluster_idx": 3}, {"solution": "def get_total_number_of_sequences(m, n):\n # We use dynamic programming to solve this problem efficiently.\n # dp[i][j] will store the number of valid sequences of length i that end with j.\n \n # Create a table where dp[i][j] represents the number of valid sequences of length i\n # ending with the number j.\n dp = [[0] * (m + 1) for _ in range(n + 1)]\n \n # Base case: sequences of length 1\n for j in range(1, m + 1):\n dp[1][j] = 1\n\n # Fill the DP table\n for i in range(2, n + 1):\n for j in range(1, m + 1):\n # We need to find all k such that j >= 2*k\n for k in range(1, (j // 2) + 1):\n dp[i][j] += dp[i - 1][k]\n\n # Sum all sequences of length n\n total_sequences = sum(dp[n][j] for j in range(1, m + 1))\n return total_sequences", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n def count_sequences(start, length):\n if length == 0:\n return 1\n total = 0\n for next_value in range(start * 2, m + 1):\n total += count_sequences(next_value, length - 1)\n return total\n\n total_sequences = 0\n for initial in range(1, m + 1):\n total_sequences += count_sequences(initial, n - 1)\n \n return total_sequences", "matching_cluster_idx": 5}]}, "Mbpp/240": {"dps": 54.26829268292683, "dps_norm": 69.44444444444444, "pass@1": 100.0, "profiled": [{"solution": "def replace_list(list1, list2):\n \"\"\"\n This function takes in two lists and replaces the last element of the first list\n with the elements of the second list.\n \"\"\"\n # Replace the last element of list1 with all elements of list2\n return list1[:-1] + list2", "matching_cluster_idx": 5}, {"solution": "def replace_list(list1, list2):\n \"\"\"\n Replace the last element of list1 with the elements of list2.\n\n :param list1: The first list\n :param list2: The second list whose elements will replace the last element of list1\n :return: A new list with the elements of list1 up to the last, followed by all elements of list2\n \"\"\"\n if not list1:\n # If list1 is empty, simply return list2\n return list2[:]\n # Return list1 up to the last element, and add elements of list2\n return list1[:-1] + list2", "matching_cluster_idx": 5}, {"solution": "def replace_list(list1, list2):\n \"\"\"\n Replaces the last element of list1 with the elements of list2.\n \n :param list1: The first list\n :param list2: The second list\n :return: The modified list1 with its last element replaced by elements of list2\n \"\"\"\n if not list1:\n # If list1 is empty, just return list2\n return list2\n # Replace the last element of list1 with all elements of list2\n return list1[:-1] + list2", "matching_cluster_idx": 5}, {"solution": "def replace_list(list1, list2):\n \"\"\"\n Replaces the last element of list1 with the elements of list2.\n\n Args:\n list1 (list): The first list.\n list2 (list): The second list.\n\n Returns:\n list: The modified list1.\n \"\"\"\n # Replace the last element of list1 with all elements of list2\n return list1[:-1] + list2", "matching_cluster_idx": 5}, {"solution": "def replace_list(list1, list2):\n \"\"\"\n Replaces the last element of list1 with the elements of list2.\n \"\"\"\n # Remove the last element from list1\n list1 = list1[:-1]\n # Append elements of list2 to list1\n list1.extend(list2)\n return list1", "matching_cluster_idx": 6}, {"solution": "def replace_list(list1, list2):\n \"\"\"\n Replaces the last element of list1 with all elements of list2.\n \n Parameters:\n list1 (list): The first list whose last element will be replaced.\n list2 (list): The second list whose elements will replace the last element of the first list.\n \n Returns:\n list: The modified list with the last element of list1 replaced by the elements of list2.\n \"\"\"\n if not list1:\n return list2\n return list1[:-1] + list2", "matching_cluster_idx": 5}, {"solution": "def replace_list(list1, list2):\n \"\"\"\n This function takes two lists as input and replaces the last element of the first list with all the elements of the second list.\n \n Parameters:\n list1 (list): The first list whose last element will be replaced.\n list2 (list): The second list whose elements will replace the last element of the first list.\n \n Returns:\n list: A new list with the last element of list1 replaced by all elements of list2.\n \"\"\"\n # Check if list1 is not empty to avoid index error\n if list1:\n # Replace the last element of list1 with the elements of list2\n return list1[:-1] + list2\n else:\n # If list1 is empty, simply return list2\n return list2", "matching_cluster_idx": 5}, {"solution": "def replace_list(list1, list2):\n \"\"\"\n Replaces the last element of list1 with the elements of list2.\n\n Args:\n list1 (list): The first list.\n list2 (list): The second list to replace the last element of list1.\n\n Returns:\n list: A new list with the last element of list1 replaced by all elements of list2.\n \"\"\"\n # Remove the last element of list1\n list1 = list1[:-1]\n # Append all elements of list2 to the truncated list1\n list1.extend(list2)\n return list1", "matching_cluster_idx": 6}, {"solution": "def replace_list(list1, list2):\n \"\"\"\n Replace the last element of list1 with the elements of list2.\n \"\"\"\n if not list1:\n return list2[:] # Return a copy of list2 if list1 is empty.\n # Replace the last element of list1 with the elements of list2.\n return list1[:-1] + list2", "matching_cluster_idx": 5}, {"solution": "def replace_list(list1, list2):\n # Replace the last element of list1 with all elements of list2\n return list1[:-1] + list2", "matching_cluster_idx": 5}, {"solution": "def replace_list(list1, list2):\n \"\"\"\n Replace the last element of list1 with the elements of list2.\n \n Parameters:\n list1 (list): The first list whose last element is to be replaced.\n list2 (list): The second list whose elements are to be added to the end of list1.\n \n Returns:\n list: A new list with the last element of list1 replaced by the elements of list2.\n \"\"\"\n # If list1 is empty, just return list2\n if not list1:\n return list2[:]\n \n # Return a new list with the last element of list1 replaced by the elements of list2\n return list1[:-1] + list2", "matching_cluster_idx": 5}, {"solution": "def replace_list(list1, list2):\n \"\"\"\n Replaces the last element of the first list with the elements of the second list.\n \n :param list1: The first list whose last element will be replaced.\n :param list2: The second list whose elements will replace the last element of the first list.\n :return: A new list with the combined elements.\n \"\"\"\n # Check that list1 has at least one element\n if not list1:\n raise ValueError(\"The first list should have at least one element.\")\n\n # Replace the last element of list1 with the elements of list2\n return list1[:-1] + list2", "matching_cluster_idx": 5}, {"solution": "def replace_list(list1, list2):\n \"\"\"\n Replaces the last element of list1 with the elements of list2.\n\n Parameters:\n list1 (list): The first list, whose last element will be replaced.\n list2 (list): The list whose elements will replace the last element of list1.\n\n Returns:\n list: A new list with the last element of list1 replaced by the elements of list2.\n \"\"\"\n # Replace the last element of list1 with elements from list2\n return list1[:-1] + list2", "matching_cluster_idx": 5}, {"solution": "def replace_list(list1, list2):\n \"\"\"\n Replaces the last element of list1 with the elements of list2.\n\n Parameters:\n list1 (list): The first list whose last element will be replaced.\n list2 (list): The second list whose elements will replace the last element of list1.\n\n Returns:\n list: The modified list1 with its last element replaced by the elements of list2.\n \"\"\"\n # Remove the last element of list1\n list1 = list1[:-1]\n # Append all elements of list2 to list1\n list1.extend(list2)\n return list1", "matching_cluster_idx": 6}, {"solution": "def replace_list(list1, list2):\n # Replace the last element of list1 with all elements of list2\n return list1[:-1] + list2", "matching_cluster_idx": 5}, {"solution": "def replace_list(list1, list2):\n # Remove the last element from list1\n list1 = list1[:-1]\n # Append the elements of list2 to list1\n list1.extend(list2)\n return list1", "matching_cluster_idx": 6}, {"solution": "def replace_list(list1, list2):\n \"\"\"\n Replaces the last element of list1 with the elements of list2.\n\n Parameters:\n list1 (list): The first list whose last element will be replaced.\n list2 (list): The second list whose elements will replace the last element of list1.\n\n Returns:\n list: The new list with the last element of list1 replaced by the elements of list2.\n \"\"\"\n if not list1:\n return list2\n return list1[:-1] + list2", "matching_cluster_idx": 5}, {"solution": "def replace_list(list1, list2):\n # Ensure the first list is not empty\n if not list1:\n return list2 # If list1 is empty, the result is just list2\n\n # Replace the last element of list1 with the elements of list2\n return list1[:-1] + list2", "matching_cluster_idx": 5}, {"solution": "def replace_list(list1, list2):\n \"\"\"\n This function takes in two lists and replaces the last element of the first list\n with the elements of the second list.\n \n Parameters:\n list1 (list): The first list.\n list2 (list): The second list.\n \n Returns:\n list: The modified list1 with its last element replaced by the elements of list2.\n \"\"\"\n # Remove the last element from list1\n list1 = list1[:-1]\n # Extend list1 with elements from list2\n list1.extend(list2)\n return list1", "matching_cluster_idx": 6}, {"solution": "def replace_list(list1, list2):\n # Check if the first list is empty\n if not list1:\n return list2\n # Replace the last element of list1 with elements of list2\n return list1[:-1] + list2", "matching_cluster_idx": 5}]}, "Mbpp/251": {"dps": 91.95402298850576, "dps_norm": 77.77777777777777, "pass@1": 100.0, "profiled": [{"solution": "def insert_element(lst, element):\n \"\"\"\n This function takes a list and an element, and inserts the element before each element in the list.\n \n :param lst: List of elements\n :param element: The element to be inserted\n :return: A new list with the element inserted before each element in the original list\n \"\"\"\n # Initialize the result list\n result = []\n \n # Iterate over the original list\n for item in lst:\n # Append the element and the current item to the result list\n result.append(element)\n result.append(item)\n \n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n result = []\n for item in lst:\n result.append(element) # Insert the element before the current item\n result.append(item) # Then insert the current item\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n \"\"\"\n Inserts the given element before each element in the list.\n\n Parameters:\n lst (list): The original list.\n element (any): The element to be inserted before each item in the list.\n\n Returns:\n list: A new list with the element inserted before each original element.\n \"\"\"\n # Create a new list to store the result\n result = []\n \n # Iterate over each item in the original list\n for item in lst:\n # Append the element to be inserted\n result.append(element)\n # Append the original item\n result.append(item)\n \n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n # Initialize a new list to store the result\n result = []\n \n # Iterate over each item in the list\n for item in lst:\n # Append the element before the current item\n result.append(element)\n # Append the current item\n result.append(item)\n \n # Return the resulting list\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n \"\"\"\n Inserts the given element before each element in the list and returns the resulting list.\n\n Parameters:\n lst (list): The list of elements.\n element (any): The element to insert before each element in the list.\n\n Returns:\n list: A new list with the element inserted before each original element.\n \"\"\"\n result = []\n for item in lst:\n result.append(element)\n result.append(item)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n # Create an empty list to hold the resulting elements\n result = []\n \n # Iterate over each element in the original list\n for item in lst:\n # First, append the new element\n result.append(element)\n # Then, append the current item from the list\n result.append(item)\n \n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n # Create a new list to hold the result\n result = []\n # Iterate over each item in the original list\n for item in lst:\n # Append the element before the current item\n result.append(element)\n # Append the current item\n result.append(item)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n result = []\n for item in lst:\n result.append(element)\n result.append(item)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, elem):\n \"\"\"\n Insert the given element before each element in the list.\n\n Parameters:\n lst (list): The original list.\n elem (any): The element to be inserted before each element in the list.\n\n Returns:\n list: A new list with the element inserted before each original element.\n \"\"\"\n result = []\n for item in lst:\n result.append(elem)\n result.append(item)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n \"\"\"\n This function takes a list and an element, and inserts the element before each element in the list.\n \n Args:\n lst (list): The list in which to insert the element.\n element: The element to insert before each item in the list.\n \n Returns:\n list: The new list with the element inserted before each original element.\n \"\"\"\n # Create an empty list to store the result\n result = []\n \n # Iterate through each element in the input list\n for item in lst:\n # Append the given element\n result.append(element)\n # Append the original item\n result.append(item)\n \n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, elem):\n \"\"\"\n Inserts the given element before each element in the list.\n\n Parameters:\n lst (list): The list in which the element is to be inserted.\n elem (any): The element to insert before each element in the list.\n\n Returns:\n list: The list with the element inserted before each original element.\n \"\"\"\n result = []\n for item in lst:\n result.append(elem)\n result.append(item)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n # Create a new list to hold the result\n result = []\n # Iterate through the original list\n for item in lst:\n # Insert the element before each item\n result.append(element)\n result.append(item)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n \"\"\"\n Inserts the given element before each element in the list.\n\n Parameters:\n lst (list): The original list.\n element: The element to insert before each element in the list.\n\n Returns:\n list: The new list with the element inserted before each original element.\n \"\"\"\n result = []\n for item in lst:\n result.append(element)\n result.append(item)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n # Initialize an empty list to store the result\n result = []\n \n # Iterate over each item in the input list\n for item in lst:\n # Insert the given element before the item\n result.append(element)\n result.append(item)\n \n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, elem):\n # Create a new list to store the result\n result = []\n \n # Iterate over the given list\n for item in lst:\n # Append the element before each item\n result.append(elem)\n # Append the current item\n result.append(item)\n \n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n \"\"\"\n Inserts the given element before each element in the list.\n \n :param lst: List of elements\n :param element: Element to be inserted\n :return: New list with the element inserted before each element of the input list\n \"\"\"\n result = []\n for item in lst:\n result.append(element)\n result.append(item)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, elem):\n \"\"\"\n Insert the given element before each element in the list.\n \n Parameters:\n lst (list): The original list.\n elem (any): The element to insert before each list element.\n \n Returns:\n list: A new list with the element inserted before each element of the original list.\n \"\"\"\n result = []\n for item in lst:\n result.append(elem)\n result.append(item)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n # Create a new list to store the result\n result = []\n # Iterate over each item in the original list\n for item in lst:\n # Append the element before the current item\n result.append(element)\n # Append the current item\n result.append(item)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, elem):\n # Create an empty list to store the result\n result = []\n \n # Iterate through each element in the given list\n for item in lst:\n # Insert the element before the current item\n result.append(elem)\n result.append(item)\n \n # Return the resulting list\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, elem):\n # Initialize an empty list to store the result\n result = []\n \n # Iterate over each element in the input list\n for item in lst:\n # Insert the specified element before each item\n result.append(elem)\n result.append(item)\n \n # Return the resulting list\n return result", "matching_cluster_idx": 6}]}, "Mbpp/256": {"dps": 97.71689497716895, "dps_norm": 88.23529411764706, "pass@1": 67.0, "profiled": [{"solution": "def count_Primes_nums(n):\n \"\"\"Return the number of prime numbers less than a given non-negative number n.\"\"\"\n if n <= 2:\n return 0\n\n is_prime = [True] * n\n is_prime[0] = is_prime[1] = False\n\n for i in range(2, int(n ** 0.5) + 1):\n if is_prime[i]:\n for multiple in range(i * i, n, i):\n is_prime[multiple] = False\n\n return sum(is_prime)", "matching_cluster_idx": 14}, {"solution": "def count_Primes_nums(n):\n \"\"\"Returns the number of prime numbers less than n.\"\"\"\n if n <= 2:\n return 0\n\n # Initialize a list to mark non-prime numbers\n is_prime = [True] * n\n is_prime[0] = is_prime[1] = False\n\n # Use Sieve of Eratosthenes to find all primes less than n\n for start in range(2, int(n**0.5) + 1):\n if is_prime[start]:\n # Mark multiples of start as non-prime\n for multiple in range(start*start, n, start):\n is_prime[multiple] = False\n\n # Count the number of primes\n return sum(is_prime)", "matching_cluster_idx": 14}, {"solution": "def count_Primes_nums(n):\n \"\"\"\n Returns the number of prime numbers less than n.\n \"\"\"\n if n <= 2:\n return 0\n\n # Initialize a list to keep track of prime numbers\n # True means the number is a prime candidate\n is_prime = [True] * n\n is_prime[0] = is_prime[1] = False # 0 and 1 are not prime numbers\n\n # Implement the Sieve of Eratosthenes\n for start in range(2, int(n**0.5) + 1):\n if is_prime[start]:\n for multiple in range(start * start, n, start):\n is_prime[multiple] = False\n\n # Count the number of primes\n prime_count = sum(is_prime)\n \n return prime_count", "matching_cluster_idx": 14}, {"solution": "def count_Primes_nums(n):\n \"\"\"\n Function to count the number of prime numbers less than a given non-negative number n.\n \"\"\"\n if n <= 2:\n return 0\n\n # Boolean array to keep track of prime numbers\n is_prime = [True] * n\n is_prime[0] = is_prime[1] = False # We know 0 and 1 are not prime\n\n for i in range(2, int(n**0.5) + 1):\n if is_prime[i]:\n # Mark multiples of i as non-prime\n for multiple in range(i*i, n, i):\n is_prime[multiple] = False\n\n # Count prime numbers\n prime_count = sum(is_prime)\n return prime_count", "matching_cluster_idx": 14}, {"solution": "def count_Primes_nums(n):\n \"\"\"\n Returns the number of prime numbers less than the given non-negative number n.\n \"\"\"\n if n <= 2:\n return 0\n\n # Initialize a boolean array to keep track of prime numbers\n is_prime = [True] * n\n is_prime[0] = is_prime[1] = False # 0 and 1 are not prime numbers\n\n # Use the Sieve of Eratosthenes algorithm\n for start in range(2, int(n**0.5) + 1):\n if is_prime[start]:\n for multiple in range(start * start, n, start):\n is_prime[multiple] = False\n\n # Count the number of primes\n return sum(is_prime)", "matching_cluster_idx": 14}, {"solution": "def count_Primes_nums(n):\n \"\"\"Return the number of prime numbers less than a non-negative number n.\"\"\"\n if n <= 2:\n return 0\n\n # Initialize a list to keep track of prime numbers\n is_prime = [True] * n\n is_prime[0] = is_prime[1] = False # 0 and 1 are not prime numbers\n\n for i in range(2, int(n**0.5) + 1):\n if is_prime[i]:\n # Mark multiples of i as non-prime\n for j in range(i*i, n, i):\n is_prime[j] = False\n\n # Count the number of primes\n return sum(is_prime)", "matching_cluster_idx": 14}, {"solution": "def count_Primes_nums(n):\n \"\"\"Return the number of prime numbers less than the given non-negative number n.\"\"\"\n if n <= 2:\n return 0\n\n # Initialize a list to determine the primality of each number up to n-1\n is_prime = [True] * n\n is_prime[0] = is_prime[1] = False # 0 and 1 are not prime numbers\n\n # Use the Sieve of Eratosthenes to mark non-primes\n for start in range(2, int(n ** 0.5) + 1):\n if is_prime[start]:\n for multiple in range(start * start, n, start):\n is_prime[multiple] = False\n\n # Count the number of prime numbers\n return sum(is_prime)", "matching_cluster_idx": 14}, {"solution": "def count_Primes_nums(n):\n \"\"\"\n Returns the number of prime numbers less than the given non-negative number n.\n \"\"\"\n if n <= 2:\n return 0\n \n # Create a boolean array \"is_prime[0..n-1]\" and initialize\n # all entries it as true. A value in is_prime[i] will\n # finally be false if i is Not a prime, else true.\n is_prime = [True] * n\n is_prime[0], is_prime[1] = False, False # 0 and 1 are not primes\n\n # Use Sieve of Eratosthenes\n for i in range(2, int(n**0.5) + 1):\n if is_prime[i]:\n for j in range(i * i, n, i):\n is_prime[j] = False\n\n # Count all prime numbers less than n\n return sum(is_prime)", "matching_cluster_idx": 14}, {"solution": "def count_Primes_nums(n):\n \"\"\"\n Counts the number of prime numbers less than a given non-negative number n.\n \n Args:\n n (int): A non-negative integer\n \n Returns:\n int: The count of prime numbers less than n\n \"\"\"\n if n <= 2:\n return 0\n\n # Create a list to mark prime numbers\n is_prime = [True] * n\n is_prime[0], is_prime[1] = False, False # 0 and 1 are not primes\n\n # Implement the Sieve of Eratosthenes\n for start in range(2, int(n ** 0.5) + 1):\n if is_prime[start]:\n for multiple in range(start * start, n, start):\n is_prime[multiple] = False\n \n # Count the primes\n return sum(is_prime)", "matching_cluster_idx": 14}, {"solution": "def count_Primes_nums(n):\n \"\"\"\n Returns the number of prime numbers less than the given non-negative number n.\n \"\"\"\n if n <= 2:\n return 0\n \n # Initialize a list to track prime status of numbers\n is_prime = [True] * n\n is_prime[0] = is_prime[1] = False # 0 and 1 are not primes\n\n for i in range(2, int(n ** 0.5) + 1):\n if is_prime[i]:\n for j in range(i * i, n, i):\n is_prime[j] = False\n\n # Count the primes\n prime_count = sum(is_prime)\n \n return prime_count", "matching_cluster_idx": 14}, {"solution": "def count_Primes_nums(n):\n if n <= 2:\n return 0\n \n # Initialize a list to keep track of prime status of each number\n is_prime = [True] * n\n is_prime[0] = is_prime[1] = False # 0 and 1 are not prime numbers\n\n # Use the Sieve of Eratosthenes to find all primes less than n\n for i in range(2, int(n**0.5) + 1):\n if is_prime[i]:\n for j in range(i*i, n, i):\n is_prime[j] = False\n\n # Count and return the number of primes\n return sum(is_prime)", "matching_cluster_idx": 14}, {"solution": "def count_Primes_nums(n):\n \"\"\"\n Counts the number of prime numbers less than the given non-negative number n.\n\n Parameters:\n n (int): A non-negative integer.\n\n Returns:\n int: The number of prime numbers less than n.\n \"\"\"\n if n <= 2:\n return 0\n \n # Initialize a list to keep track of prime status for each number less than n\n is_prime = [True] * n\n is_prime[0] = is_prime[1] = False # 0 and 1 are not prime numbers\n \n # Use Sieve of Eratosthenes algorithm to find primes\n for i in range(2, int(n**0.5) + 1):\n if is_prime[i]:\n for j in range(i*i, n, i):\n is_prime[j] = False\n \n # Count the number of prime numbers less than n\n prime_count = sum(is_prime)\n return prime_count", "matching_cluster_idx": 14}, {"solution": "def count_Primes_nums(n):\n \"\"\"Return the number of prime numbers less than the given non-negative number n.\"\"\"\n if n <= 2:\n return 0\n\n # Create a boolean array \"is_prime[0..n-1]\" and initialize\n # all entries it as true. A value in is_prime[i] will\n # finally be false if i is Not a prime, else true.\n is_prime = [True] * n\n is_prime[0], is_prime[1] = False, False # 0 and 1 are not prime numbers\n\n # Use Sieve of Eratosthenes to identify primes\n for start in range(2, int(n**0.5) + 1):\n if is_prime[start]:\n for multiple in range(start * start, n, start):\n is_prime[multiple] = False\n\n # Count primes\n return sum(is_prime)", "matching_cluster_idx": 14}, {"solution": "def count_Primes_nums(n):\n if n <= 2:\n return 0\n\n # Create a boolean array \"is_prime[0..n]\" and initialize\n # all entries as true. A value in is_prime[i] will\n # finally be false if i is Not a prime, true otherwise\n is_prime = [True] * n\n is_prime[0] = is_prime[1] = False # 0 and 1 are not prime numbers\n\n p = 2\n while (p * p < n):\n if is_prime[p]:\n # Update all multiples of p to not prime\n for i in range(p * p, n, p):\n is_prime[i] = False\n p += 1\n\n # Count prime numbers\n return sum(is_prime)", "matching_cluster_idx": 14}, {"solution": "def count_Primes_nums(n):\n \"\"\"Returns the number of prime numbers less than the given non-negative number.\"\"\"\n if n <= 2:\n return 0\n \n # Create a list to track prime status of numbers less than n\n is_prime = [True] * n\n is_prime[0], is_prime[1] = False, False # 0 and 1 are not prime numbers\n \n # Sieve of Eratosthenes\n for start in range(2, int(n**0.5) + 1):\n if is_prime[start]:\n for multiple in range(start*start, n, start):\n is_prime[multiple] = False\n \n # Count the number of primes less than n\n return sum(is_prime)", "matching_cluster_idx": 14}, {"solution": "def count_Primes_nums(n):\n \"\"\"\n Returns the number of prime numbers less than the given non-negative number n.\n \"\"\"\n if n <= 2:\n return 0\n\n # Boolean array to keep track of prime status\n is_prime = [True] * n\n is_prime[0] = is_prime[1] = False # 0 and 1 are not prime numbers\n\n for i in range(2, int(n**0.5) + 1):\n if is_prime[i]:\n # Marking multiples of i starting from i*i as False (not prime)\n for multiple in range(i * i, n, i):\n is_prime[multiple] = False\n\n # Counting the number of True values in the is_prime list\n return sum(is_prime)", "matching_cluster_idx": 14}, {"solution": "def count_Primes_nums(n):\n if n <= 2:\n return 0\n \n # A boolean array to mark prime numbers\n is_prime = [True] * n\n is_prime[0] = is_prime[1] = False # 0 and 1 are not prime numbers\n \n # Use the Sieve of Eratosthenes to find all prime numbers less than n\n for start in range(2, int(n**0.5) + 1):\n if is_prime[start]:\n for multiple in range(start*start, n, start):\n is_prime[multiple] = False\n\n # Count the prime numbers\n prime_count = sum(is_prime)\n \n return prime_count", "matching_cluster_idx": 14}, {"solution": "def count_Primes_nums(n):\n \"\"\"\n Returns the number of prime numbers less than the given non-negative number n.\n \n :param n: A non-negative integer\n :return: Number of prime numbers less than n\n \"\"\"\n if n <= 2:\n return 0\n\n # Initialize a list to keep track of prime status for each number\n is_prime = [True] * n\n is_prime[0] = is_prime[1] = False # 0 and 1 are not primes\n\n # Use the Sieve of Eratosthenes to determine prime numbers\n for i in range(2, int(n ** 0.5) + 1):\n if is_prime[i]:\n for j in range(i * i, n, i):\n is_prime[j] = False\n\n # Count the number of primes\n return sum(is_prime)", "matching_cluster_idx": 14}, {"solution": "def count_Primes_nums(n):\n \"\"\"Returns the number of prime numbers less than a given non-negative number n.\"\"\"\n if n <= 2:\n return 0\n \n # Initialize a list to track prime status of numbers less than n\n is_prime = [True] * n\n is_prime[0], is_prime[1] = False, False # 0 and 1 are not primes\n \n for i in range(2, int(n ** 0.5) + 1):\n if is_prime[i]:\n for j in range(i * i, n, i):\n is_prime[j] = False\n \n return sum(is_prime)", "matching_cluster_idx": 14}, {"solution": "def count_Primes_nums(n):\n \"\"\"Return the number of prime numbers less than a given non-negative number n.\"\"\"\n if n <= 2:\n return 0\n\n # Create a boolean array \"is_prime[0..n-1]\" and initialize\n # all entries it as true. A value in is_prime[i] will\n # finally be false if i is Not a prime, else true bool\n is_prime = [True] * n\n is_prime[0] = is_prime[1] = False # 0 and 1 are not primes\n\n # Use Sieve of Eratosthenes to find all primes less than n\n for start in range(2, int(n**0.5) + 1):\n if is_prime[start]:\n # Mark all multiples of start as False starting from start*start\n for multiple in range(start*start, n, start):\n is_prime[multiple] = False\n\n # Count primes less than n\n return sum(is_prime)", "matching_cluster_idx": 14}]}, "Mbpp/265": {"dps": 70.93023255813954, "dps_norm": 83.33333333333333, "pass@1": 99.0, "profiled": [{"solution": "def list_split(input_list, n):\n # Create a list of n empty lists\n split_lists = [[] for _ in range(n)]\n \n # Iterate over the input list with an index\n for index, element in enumerate(input_list):\n # Determine which sub-list to append the current element to\n sub_list_index = index % n\n split_lists[sub_list_index].append(element)\n \n return split_lists", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n \"\"\"\n Splits a list into lists of every nth element.\n\n Parameters:\n lst (list): The input list to split.\n n (int): The interval at which to split the list.\n\n Returns:\n list of lists: A list containing lists of every nth element.\n \"\"\"\n # Create an empty list to hold the resulting lists\n result = []\n\n # Loop over the range from 0 to n (exclusive)\n for i in range(n):\n # Use list slicing to get every nth element starting from the index i\n nth_elements = lst[i::n]\n # Append the list of nth elements to the result\n result.append(nth_elements)\n\n return result", "matching_cluster_idx": 4}, {"solution": "def list_split(input_list, n):\n \"\"\"\n Splits the input list for every nth element, returning a list of the resulting lists.\n\n Parameters:\n input_list (list): The list to be split.\n n (int): The interval at which to split the list.\n\n Returns:\n list of lists: A list containing the split lists.\n \"\"\"\n if n <= 0:\n raise ValueError(\"n must be a positive integer\")\n\n # Create empty lists for each split\n split_lists = [[] for _ in range(n)]\n\n # Populate each list by iterating over the input list\n for index, item in enumerate(input_list):\n split_index = index % n\n split_lists[split_index].append(item)\n\n return split_lists", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n \"\"\"\n Splits the input list lst into n lists where each i-th list contains every nth element starting from i.\n\n Parameters:\n lst (list): The input list to be split.\n n (int): The step size for splitting.\n\n Returns:\n list: A list containing n lists, each with elements from the original list.\n \"\"\"\n # Initialize n empty lists in a list of lists\n result = [[] for _ in range(n)]\n \n # Iterate over the input list and distribute elements into corresponding sublists\n for index, element in enumerate(lst):\n result[index % n].append(element)\n \n return result", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n # Initialize an empty list to store the split lists\n result = [[] for _ in range(n)]\n\n # Iterate over the list and distribute the elements into the sublists\n for index, element in enumerate(lst):\n result[index % n].append(element)\n\n return result", "matching_cluster_idx": 4}, {"solution": "def list_split(input_list, n):\n \"\"\"\n Splits the input list into sublists where each sublist contains every nth element starting from index 0, 1, ... up to n-1.\n \n Parameters:\n - input_list (list): The list to be split.\n - n (int): The interval for splitting the list.\n \n Returns:\n - List of lists: A list where each sublist contains elements separated by n positions in the original list.\n \"\"\"\n result = [[] for _ in range(n)]\n \n for i, element in enumerate(input_list):\n result[i % n].append(element)\n \n return result", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n # Initialize an empty list to hold the result\n result = [[] for _ in range(n)]\n \n # Iterate over the elements in the list along with their index\n for i, element in enumerate(lst):\n # Determine which sublist to place the current element in\n index = i % n\n result[index].append(element)\n \n return result", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n if n <= 0:\n raise ValueError(\"n must be a positive integer\")\n \n # Initialize a list of n empty lists\n split_lists = [[] for _ in range(n)]\n \n # Distribute the elements of lst into the split_lists\n for index, element in enumerate(lst):\n split_lists[index % n].append(element)\n \n return split_lists", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n \"\"\"\n Splits the list lst into n lists where each list contains every nth element starting from different offsets.\n \n Args:\n lst: List of elements to be split.\n n: Integer indicating the frequency to split elements.\n \n Returns:\n List of n lists, where each sublist contains the elements from the original list at every nth position.\n \"\"\"\n # Initialize an empty list to hold the resulting lists.\n result = [[] for _ in range(n)]\n \n # Iterate over the original list and distribute elements into the corresponding sublist.\n for i in range(len(lst)):\n result[i % n].append(lst[i])\n \n return result", "matching_cluster_idx": 4}, {"solution": "def list_split(input_list, n):\n \"\"\"\n Splits the input list into n sublists such that the resulting lists contain \n elements at intervals of n.\n\n :param input_list: List to be split\n :param n: Integer indicating every nth element should be placed in a new sublist\n :return: List of lists where each sublist contains every nth element from the input list\n \"\"\"\n # Initialize a list of empty lists to store the resulting sublists\n result = [[] for _ in range(n)]\n \n # Iterate through the input list and place each element in the appropriate sublist\n for index, element in enumerate(input_list):\n result[index % n].append(element)\n \n return result", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n # Create a list of empty lists, one for each of the splits\n result = [[] for _ in range(n)]\n \n # Iterate over the list with index and item\n for index, item in enumerate(lst):\n # Find the split by using modulus operation\n split_index = index % n\n # Append the item to the appropriate split list\n result[split_index].append(item)\n \n return result", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n # Initialize a list of lists for each partition\n result = [[] for _ in range(n)]\n \n # Iterate over the elements and add them to the corresponding partition\n for index, item in enumerate(lst):\n result[index % n].append(item)\n \n return result", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n # Create a list of n empty lists to store the split elements\n result = [[] for _ in range(n)]\n \n # Iterate over the input list and distribute the elements to the respective sublists\n for i, elem in enumerate(lst):\n result[i % n].append(elem)\n \n return result", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n # Initialize the result list with n empty lists\n result = [[] for _ in range(n)]\n \n # Iterate through the input list and distribute elements across the result lists\n for index, element in enumerate(lst):\n # Determine which list to put the current element into by using modulus operation\n result[index % n].append(element)\n \n return result\nn = 3", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n \"\"\"\n Splits the input list into n sublists, where each sublist contains every nth element from the original list.\n\n Parameters:\n lst (list): The input list to be split.\n n (int): The interval for splitting the list.\n\n Returns:\n list of lists: A list containing n sublists.\n \"\"\"\n # Initialize a list to hold the result\n result = [[] for _ in range(n)]\n\n # Iterate over the list and assign each element to the appropriate sublist\n for index, value in enumerate(lst):\n result[index % n].append(value)\n\n return result", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n # Create a list of empty lists to hold the result\n result = [[] for _ in range(n)]\n \n # Iterate over the list and split elements into the sublists\n for i, element in enumerate(lst):\n # Determine which sublist to add the current element to\n result[i % n].append(element)\n \n return result", "matching_cluster_idx": 4}, {"solution": "def list_split(input_list, n):\n # Create a list of n empty lists\n result = [[] for _ in range(n)]\n \n # Iterate over the input list and distribute the elements into the sublists\n for i, element in enumerate(input_list):\n # Use the modulo operator to determine the correct sublist\n result[i % n].append(element)\n \n return result", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n \"\"\"\n Splits the list for every nth element and returns a list of resulting lists.\n\n Args:\n lst: List to be split.\n n: The interval of elements to group together.\n\n Returns:\n A list of lists, where each inner list contains elements from lst taken at steps of n.\n \"\"\"\n # Create a list of lists, each starting with the elements at positions 0, 1, 2, ..., n-1\n result = [[] for _ in range(n)]\n \n # Iterate over the list with indices and distribute elements into the result lists\n for index, element in enumerate(lst):\n # Calculate which list this element should go into\n result[index % n].append(element)\n \n return result", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n \"\"\"\n Splits the input list for every nth element, returning a list of the resulting lists.\n\n :param lst: List of elements to be split.\n :param n: Integer representing the interval at which to split the list.\n :return: A list of lists, where each inner list contains the elements from the original list at positions that are\n n elements apart.\n \"\"\"\n if n <= 0:\n raise ValueError(\"n must be a positive integer\")\n \n # Initialize the result with empty lists for each group\n result = [[] for _ in range(n)]\n \n # Distribute elements of lst into the n groups\n for index, item in enumerate(lst):\n group = index % n\n result[group].append(item)\n \n return result", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n if n <= 0:\n raise ValueError(\"n must be a positive integer\")\n \n result = [[] for _ in range(n)]\n \n for index, element in enumerate(lst):\n result[index % n].append(element)\n \n return result", "matching_cluster_idx": 4}]}, "Mbpp/281": {"dps": 94.0, "dps_norm": 81.81818181818181, "pass@1": 100.0, "profiled": [{"solution": "def all_unique(lst):\n \"\"\"\n Returns True if all elements in the list are unique, False otherwise.\n \"\"\"\n # Convert the list to a set, which automatically removes duplicates.\n # Compare the length of the set with the list.\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n Check if all elements in the list are unique.\n \n Parameters:\n lst (list): The list to check for uniqueness.\n \n Returns:\n bool: True if all elements are unique, False otherwise.\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n Returns True if all elements in the list `lst` are unique, otherwise returns False.\n \"\"\"\n # Convert the list to a set, which automatically removes duplicates\n # and compare its length to the original list length.\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n Check if all elements in the list are unique.\n \n Args:\n lst (list): The list of elements to check.\n \n Returns:\n bool: True if all elements are unique, False otherwise.\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n This function checks if all elements in the given list are unique.\n \n :param lst: List of elements to check\n :return: True if all elements are unique, False otherwise\n \"\"\"\n # Convert the list to a set, which removes duplicates. If the length of the set\n # is the same as the length of the list, then all elements were unique.\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n Checks if all elements in the list are unique.\n\n Parameters:\n lst (list): The list to check for uniqueness.\n\n Returns:\n bool: True if all elements are unique, False otherwise.\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n Check if all elements in the list are unique.\n \n Args:\n lst (list): The list of elements to check.\n \n Returns:\n bool: True if all elements are unique, False otherwise.\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"Check if all elements in the list are unique.\"\"\"\n # Convert the list to a set and compare lengths\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n Check if all elements in the given list are unique.\n\n Args:\n lst: A list of elements.\n\n Returns:\n bool: True if all elements are unique, False otherwise.\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n Check if all elements in the list are unique.\n \n Parameters:\n lst (list): The list to check for uniqueness.\n\n Returns:\n bool: True if all elements are unique, False otherwise.\n \"\"\"\n # Convert the list to a set. If the length of the set is the same as the list,\n # then all elements were unique since sets do not allow duplicate values.\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n Check if all elements in the list are unique.\n \n Args:\n lst: list of elements to check for uniqueness\n \n Returns:\n bool: True if all elements are unique, False otherwise\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n Check if all elements in the list are unique.\n\n Parameters:\n lst (list): The list to check for uniqueness.\n\n Returns:\n bool: True if all elements are unique, False otherwise.\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n This function checks if all elements in the given list are unique.\n \n Parameters:\n lst (list): The list to check for uniqueness.\n \n Returns:\n bool: True if all elements are unique, False otherwise.\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n Checks if all elements in the list are unique.\n \n Parameters:\n lst (list): The list to check for uniqueness.\n\n Returns:\n bool: True if all elements are unique, False otherwise.\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n Returns True if all elements in the list are unique, False otherwise.\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n Check if all elements in the list are unique.\n \n :param lst: List of elements to check\n :return: True if all elements are unique, False otherwise\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n Check if all elements in the list are unique.\n\n Parameters:\n lst (list): The list to check for uniqueness.\n\n Returns:\n bool: True if all elements are unique, False otherwise.\n \"\"\"\n # Convert the list to a set and compare its length with the original list\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(elements):\n \"\"\"\n Check if all elements in the list are unique.\n\n Parameters:\n elements (list): The list to check for uniqueness.\n\n Returns:\n bool: True if all elements are unique, False otherwise.\n \"\"\"\n # Convert the list to a set, which will remove duplicates\n unique_elements = set(elements)\n # Compare the length of the set with the list\n return len(unique_elements) == len(elements)", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n Check if all elements in the list are unique.\n\n Args:\n lst (list): The list to check.\n\n Returns:\n bool: True if all elements are unique, False otherwise.\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"Check if all elements in the list are unique.\"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}]}, "Mbpp/296": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def get_Inv_Count(arr):\n \"\"\"\n Function to count inversions in the array using a modified merge sort.\n An inversion is a pair (i, j) such that i < j and arr[i] > arr[j].\n \"\"\"\n \n def merge_and_count(arr, temp_arr, left, mid, right):\n i = left # Starting index for left subarray\n j = mid + 1 # Starting index for right subarray\n k = left # Starting index to be sorted\n inv_count = 0\n\n # Conditions are checked to ensure that i doesn't exceed mid and j doesn't exceed right\n while i <= mid and j <= right:\n if arr[i] <= arr[j]:\n temp_arr[k] = arr[i]\n i += 1\n else:\n # There are mid - i inversions because all the remaining elements in the left subarray\n # (arr[i...mid]) are greater than arr[j]\n temp_arr[k] = arr[j]\n inv_count += (mid-i + 1)\n j += 1\n k += 1\n\n # Copy the remaining elements of left subarray, if any\n while i <= mid:\n temp_arr[k] = arr[i]\n i += 1\n k += 1\n\n # Copy the remaining elements of right subarray, if any\n while j <= right:\n temp_arr[k] = arr[j]\n j += 1\n k += 1\n\n # Copy the sorted subarray into Original array\n for i in range(left, right + 1):\n arr[i] = temp_arr[i]\n \n return inv_count\n\n def merge_sort_and_count(arr, temp_arr, left, right):\n inv_count = 0\n if left < right:\n mid = (left + right) // 2\n\n inv_count += merge_sort_and_count(arr, temp_arr, left, mid)\n inv_count += merge_sort_and_count(arr, temp_arr, mid + 1, right)\n inv_count += merge_and_count(arr, temp_arr, left, mid, right)\n\n return inv_count\n\n # Create a temporary array\n temp_arr = [0]*len(arr)\n return merge_sort_and_count(arr, temp_arr, 0, len(arr) - 1)", "matching_cluster_idx": 5}, {"solution": "def merge_and_count(arr, temp_arr, left, mid, right):\n i = left # Starting index for left subarray\n j = mid + 1 # Starting index for right subarray\n k = left # Starting index to be sorted\n inv_count = 0\n\n # Conditions are checked to ensure that i doesn't exceed mid and j doesn't exceed right\n while i <= mid and j <= right:\n if arr[i] <= arr[j]:\n temp_arr[k] = arr[i]\n i += 1\n else:\n # There are mid - i inversions, because all the remaining elements in the left\n # subarray (arr[i...mid]) are greater than arr[j]\n temp_arr[k] = arr[j]\n inv_count += (mid-i + 1)\n j += 1\n k += 1\n\n # Copy the remaining elements of left subarray, if any\n while i <= mid:\n temp_arr[k] = arr[i]\n i += 1\n k += 1\n\n # Copy the remaining elements of right subarray, if any\n while j <= right:\n temp_arr[k] = arr[j]\n j += 1\n k += 1\n\n # Copy the sorted subarray into Original array\n for i in range(left, right + 1):\n arr[i] = temp_arr[i]\n \n return inv_count\ndef merge_sort_and_count(arr, temp_arr, left, right):\n inv_count = 0\n if left < right:\n mid = (left + right)//2\n\n inv_count += merge_sort_and_count(arr, temp_arr, left, mid)\n inv_count += merge_sort_and_count(arr, temp_arr, mid + 1, right)\n inv_count += merge_and_count(arr, temp_arr, left, mid, right)\n\n return inv_count\ndef get_Inv_Count(arr):\n temp_arr = [0]*len(arr)\n return merge_sort_and_count(arr, temp_arr, 0, len(arr) - 1)", "matching_cluster_idx": 5}, {"solution": "def merge_and_count(arr, temp_arr, left, mid, right):\n i = left # Starting index for left subarray\n j = mid + 1 # Starting index for right subarray\n k = left # Starting index to be sorted\n inv_count = 0\n \n # Conditions are checked to ensure that i doesn't exceed mid and j doesn't exceed right\n while i <= mid and j <= right:\n if arr[i] <= arr[j]:\n temp_arr[k] = arr[i]\n i += 1\n else:\n # There are mid - i inversions, because all remaining elements in left-subarray\n # (arr[i:mid+1]) are greater than arr[j]\n temp_arr[k] = arr[j]\n inv_count += (mid-i + 1)\n j += 1\n k += 1\n\n # Copy the remaining elements of left subarray, if any\n while i <= mid:\n temp_arr[k] = arr[i]\n i += 1\n k += 1\n\n # Copy the remaining elements of right subarray, if any\n while j <= right:\n temp_arr[k] = arr[j]\n j += 1\n k += 1\n\n # Copy the sorted subarray into Original array\n for i in range(left, right + 1):\n arr[i] = temp_arr[i]\n \n return inv_count\ndef merge_sort_and_count(arr, temp_arr, left, right):\n inv_count = 0\n if left < right:\n mid = (left + right) // 2\n\n inv_count += merge_sort_and_count(arr, temp_arr, left, mid)\n inv_count += merge_sort_and_count(arr, temp_arr, mid + 1, right)\n inv_count += merge_and_count(arr, temp_arr, left, mid, right)\n\n return inv_count\ndef get_Inv_Count(arr):\n n = len(arr)\n temp_arr = [0]*n\n return merge_sort_and_count(arr, temp_arr, 0, n - 1)", "matching_cluster_idx": 5}, {"solution": "def merge_and_count(arr, temp_arr, left, mid, right):\n i = left # Starting index for left subarray\n j = mid + 1 # Starting index for right subarray\n k = left # Starting index to be sorted\n inv_count = 0\n\n # Conditions are checked to ensure that i doesn't exceed mid and j doesn't exceed right\n while i <= mid and j <= right:\n if arr[i] <= arr[j]:\n temp_arr[k] = arr[i]\n i += 1\n else:\n # There are mid - i inversions, because all the remaining elements in the left subarray\n # (arr[i..mid]) are greater than arr[j]\n temp_arr[k] = arr[j]\n inv_count += (mid - i + 1)\n j += 1\n k += 1\n\n # Copy the remaining elements of left subarray, if any\n while i <= mid:\n temp_arr[k] = arr[i]\n i += 1\n k += 1\n\n # Copy the remaining elements of right subarray, if any\n while j <= right:\n temp_arr[k] = arr[j]\n j += 1\n k += 1\n\n # Copy the sorted subarray into Original array\n for i in range(left, right + 1):\n arr[i] = temp_arr[i]\n \n return inv_count\ndef merge_sort_and_count(arr, temp_arr, left, right):\n inv_count = 0\n if left < right:\n mid = (left + right) // 2\n\n inv_count += merge_sort_and_count(arr, temp_arr, left, mid)\n inv_count += merge_sort_and_count(arr, temp_arr, mid + 1, right)\n\n inv_count += merge_and_count(arr, temp_arr, left, mid, right)\n\n return inv_count\ndef get_Inv_Count(arr):\n # Create a temporary array\n temp_arr = [0]*len(arr)\n return merge_sort_and_count(arr, temp_arr, 0, len(arr) - 1)", "matching_cluster_idx": 5}, {"solution": "def get_Inv_Count(arr):\n def merge_and_count(arr, temp_arr, left, mid, right):\n i = left # Starting index for left subarray\n j = mid + 1 # Starting index for right subarray\n k = left # Starting index to be sorted\n inv_count = 0\n\n # Conditions are checked to ensure that i doesn't exceed mid and j doesn't exceed right\n while i <= mid and j <= right:\n if arr[i] <= arr[j]:\n temp_arr[k] = arr[i]\n i += 1\n else:\n # There are mid - i inversions, because all elements left to i in left subarray\n # are greater than arr[j]\n temp_arr[k] = arr[j]\n inv_count += (mid-i + 1)\n j += 1\n k += 1\n\n # Copy the remaining elements of left subarray, if any\n while i <= mid:\n temp_arr[k] = arr[i]\n i += 1\n k += 1\n\n # Copy the remaining elements of right subarray, if any\n while j <= right:\n temp_arr[k] = arr[j]\n j += 1\n k += 1\n\n # Copy the sorted subarray into Original array\n for i in range(left, right + 1):\n arr[i] = temp_arr[i]\n \n return inv_count\n\n def merge_sort_and_count(arr, temp_arr, left, right):\n inv_count = 0\n if left < right:\n mid = (left + right)//2\n\n inv_count += merge_sort_and_count(arr, temp_arr, left, mid)\n inv_count += merge_sort_and_count(arr, temp_arr, mid + 1, right)\n inv_count += merge_and_count(arr, temp_arr, left, mid, right)\n\n return inv_count\n\n # Create a temporary array\n temp_arr = [0]*len(arr)\n return merge_sort_and_count(arr, temp_arr, 0, len(arr)-1)", "matching_cluster_idx": 5}, {"solution": "def merge_and_count(arr, temp_arr, left, mid, right):\n i = left # Starting index for left subarray\n j = mid + 1 # Starting index for right subarray\n k = left # Starting index to be sorted\n inv_count = 0\n\n # Conditions are checked to ensure that i doesn't exceed mid and j doesn't exceed right\n while i <= mid and j <= right:\n if arr[i] <= arr[j]:\n temp_arr[k] = arr[i]\n i += 1\n else:\n # There are mid - i inversions, because all elements left to ith element\n # are greater than jth element\n temp_arr[k] = arr[j]\n inv_count += (mid-i + 1)\n j += 1\n k += 1\n\n # Copy the remaining elements of left subarray, if any\n while i <= mid:\n temp_arr[k] = arr[i]\n i += 1\n k += 1\n\n # Copy the remaining elements of right subarray, if any\n while j <= right:\n temp_arr[k] = arr[j]\n j += 1\n k += 1\n\n # Copy the sorted subarray into Original array\n for i in range(left, right + 1):\n arr[i] = temp_arr[i]\n \n return inv_count\ndef merge_sort_and_count(arr, temp_arr, left, right):\n inv_count = 0\n if left < right:\n mid = (left + right)//2\n\n inv_count += merge_sort_and_count(arr, temp_arr, left, mid)\n inv_count += merge_sort_and_count(arr, temp_arr, mid + 1, right)\n inv_count += merge_and_count(arr, temp_arr, left, mid, right)\n\n return inv_count\ndef get_Inv_Count(arr):\n n = len(arr)\n temp_arr = [0]*n\n return merge_sort_and_count(arr, temp_arr, 0, n - 1)", "matching_cluster_idx": 5}, {"solution": "def merge_and_count(arr, temp_arr, left, mid, right):\n i = left # Starting index for left subarray\n j = mid + 1 # Starting index for right subarray\n k = left # Starting index to be sorted\n inv_count = 0\n\n # Conditions are checked to ensure that i doesn't exceed mid and j doesn't exceed right\n while i <= mid and j <= right:\n if arr[i] <= arr[j]:\n temp_arr[k] = arr[i]\n i += 1\n else:\n # There are mid - i inversions, because all elements left to i in the left subarray\n # are greater than arr[j]\n temp_arr[k] = arr[j]\n inv_count += (mid-i + 1)\n j += 1\n k += 1\n\n # Copy the remaining elements of left subarray, if any\n while i <= mid:\n temp_arr[k] = arr[i]\n i += 1\n k += 1\n\n # Copy the remaining elements of right subarray, if any\n while j <= right:\n temp_arr[k] = arr[j]\n j += 1\n k += 1\n\n # Copy the sorted subarray into Original array\n for i in range(left, right + 1):\n arr[i] = temp_arr[i]\n\n return inv_count\ndef merge_sort_and_count(arr, temp_arr, left, right):\n inv_count = 0\n if left < right:\n mid = (left + right)//2\n\n inv_count += merge_sort_and_count(arr, temp_arr, left, mid)\n inv_count += merge_sort_and_count(arr, temp_arr, mid + 1, right)\n inv_count += merge_and_count(arr, temp_arr, left, mid, right)\n\n return inv_count\ndef get_Inv_Count(arr):\n temp_arr = [0]*len(arr)\n return merge_sort_and_count(arr, temp_arr, 0, len(arr)-1)", "matching_cluster_idx": 5}, {"solution": "def get_Inv_Count(arr):\n # Function to use the merge sort technique to count inversions\n def merge_and_count(arr, temp_arr, left, mid, right):\n i = left # Starting index for left subarray\n j = mid + 1 # Starting index for right subarray\n k = left # Starting index to be sorted\n inv_count = 0\n\n # Conditions are checked to ensure that i doesn't exceed mid and j doesn't exceed right\n while i <= mid and j <= right:\n if arr[i] <= arr[j]:\n temp_arr[k] = arr[i]\n i += 1\n else:\n # There are mid - i inversions, because all the remaining elements in the left subarray\n # are greater than arr[j]\n temp_arr[k] = arr[j]\n inv_count += (mid-i + 1)\n j += 1\n k += 1\n\n # Copy the remaining elements of left subarray, if there are any\n while i <= mid:\n temp_arr[k] = arr[i]\n i += 1\n k += 1\n\n # Copy the remaining elements of right subarray, if there are any\n while j <= right:\n temp_arr[k] = arr[j]\n j += 1\n k += 1\n\n # Copy the sorted subarray into Original array\n for i in range(left, right + 1):\n arr[i] = temp_arr[i]\n \n return inv_count\n\n # Function to recursively divide the array and count inversions\n def merge_sort_and_count(arr, temp_arr, left, right):\n inv_count = 0\n if left < right:\n mid = (left + right) // 2\n\n inv_count += merge_sort_and_count(arr, temp_arr, left, mid)\n inv_count += merge_sort_and_count(arr, temp_arr, mid + 1, right)\n inv_count += merge_and_count(arr, temp_arr, left, mid, right)\n\n return inv_count\n\n # Create a temporary array and initialize the inversion count to 0\n temp_arr = [0]*len(arr)\n return merge_sort_and_count(arr, temp_arr, 0, len(arr) - 1)", "matching_cluster_idx": 5}, {"solution": "def merge_and_count(arr, temp_arr, left, mid, right):\n i = left # Starting index for left subarray\n j = mid + 1 # Starting index for right subarray\n k = left # Starting index to be sorted\n inv_count = 0\n \n # Conditions are checked to ensure that i doesn't exceed mid and j doesn't exceed right\n while i <= mid and j <= right:\n if arr[i] <= arr[j]:\n temp_arr[k] = arr[i]\n i += 1\n else:\n # There are mid - i inversions, because all the remaining elements in the left subarray (arr[i...mid]) \n # are greater than arr[j]\n temp_arr[k] = arr[j]\n inv_count += (mid - i + 1)\n j += 1\n k += 1\n \n # Copy the remaining elements of left subarray, if any\n while i <= mid:\n temp_arr[k] = arr[i]\n i += 1\n k += 1\n \n # Copy the remaining elements of right subarray, if any\n while j <= right:\n temp_arr[k] = arr[j]\n j += 1\n k += 1\n \n # Copy the sorted subarray into Original array\n for i in range(left, right + 1):\n arr[i] = temp_arr[i]\n \n return inv_count\ndef merge_sort_and_count(arr, temp_arr, left, right):\n inv_count = 0\n if left < right:\n mid = (left + right)//2\n \n inv_count += merge_sort_and_count(arr, temp_arr, left, mid)\n inv_count += merge_sort_and_count(arr, temp_arr, mid + 1, right)\n \n inv_count += merge_and_count(arr, temp_arr, left, mid, right)\n \n return inv_count\ndef get_Inv_Count(arr):\n temp_arr = [0]*len(arr)\n return merge_sort_and_count(arr, temp_arr, 0, len(arr) - 1)", "matching_cluster_idx": 5}, {"solution": "def get_Inv_Count(arr):\n # Helper function to merge two halves and count inversions\n def merge_and_count(arr, temp_arr, left, mid, right):\n i = left # Starting index for left subarray\n j = mid + 1 # Starting index for right subarray\n k = left # Starting index to be sorted\n inv_count = 0\n\n # Conditions are checked to ensure that i doesn't exceed mid and j doesn't exceed right\n while i <= mid and j <= right:\n if arr[i] <= arr[j]:\n temp_arr[k] = arr[i]\n i += 1\n else:\n # There are mid - i inversions, because all elements left to i in left subarray are greater than arr[j]\n temp_arr[k] = arr[j]\n inv_count += (mid-i + 1)\n j += 1\n k += 1\n\n # Copy the remaining elements of left subarray, if any\n while i <= mid:\n temp_arr[k] = arr[i]\n i += 1\n k += 1\n\n # Copy the remaining elements of right subarray, if any\n while j <= right:\n temp_arr[k] = arr[j]\n j += 1\n k += 1\n\n # Copy the sorted subarray into Original array\n for i in range(left, right + 1):\n arr[i] = temp_arr[i]\n\n return inv_count\n\n # Helper function to use divide and conquer approach\n def merge_sort_and_count(arr, temp_arr, left, right):\n inv_count = 0\n if left < right:\n mid = (left + right)//2\n\n inv_count += merge_sort_and_count(arr, temp_arr, left, mid)\n inv_count += merge_sort_and_count(arr, temp_arr, mid + 1, right)\n inv_count += merge_and_count(arr, temp_arr, left, mid, right)\n\n return inv_count\n\n # Create a temporary array\n temp_arr = [0]*len(arr)\n return merge_sort_and_count(arr, temp_arr, 0, len(arr) - 1)", "matching_cluster_idx": 5}, {"solution": "def merge_and_count(arr, temp_arr, left, mid, right):\n i = left # Starting index for left subarray\n j = mid + 1 # Starting index for right subarray\n k = left # Starting index to be sorted\n inv_count = 0\n\n # Conditions are checked to ensure that i doesn't exceed mid and j doesn't exceed right\n while i <= mid and j <= right:\n if arr[i] <= arr[j]:\n temp_arr[k] = arr[i]\n i += 1\n else:\n # There are mid - i inversions, because all the remaining elements in the left subarray (arr[i:mid+1]) are greater than arr[j]\n temp_arr[k] = arr[j]\n inv_count += (mid-i + 1)\n j += 1\n k += 1\n\n # Copy the remaining elements of left subarray, if any\n while i <= mid:\n temp_arr[k] = arr[i]\n i += 1\n k += 1\n\n # Copy the remaining elements of right subarray, if any\n while j <= right:\n temp_arr[k] = arr[j]\n j += 1\n k += 1\n\n # Copy the sorted subarray into Original array\n for i in range(left, right + 1):\n arr[i] = temp_arr[i]\n\n return inv_count\ndef merge_sort_and_count(arr, temp_arr, left, right):\n inv_count = 0\n if left < right:\n mid = (left + right)//2\n\n inv_count += merge_sort_and_count(arr, temp_arr, left, mid)\n inv_count += merge_sort_and_count(arr, temp_arr, mid + 1, right)\n\n inv_count += merge_and_count(arr, temp_arr, left, mid, right)\n\n return inv_count\ndef get_Inv_Count(arr):\n # Create a temporary array\n temp_arr = [0]*len(arr)\n return merge_sort_and_count(arr, temp_arr, 0, len(arr)-1)", "matching_cluster_idx": 5}, {"solution": "def merge_and_count(arr, temp_arr, left, mid, right):\n i = left # Starting index for left subarray\n j = mid + 1 # Starting index for right subarray\n k = left # Starting index to be sorted\n inv_count = 0\n\n # Conditions are checked to ensure that i doesn't exceed mid and j doesn't exceed right\n while i <= mid and j <= right:\n if arr[i] <= arr[j]:\n temp_arr[k] = arr[i]\n i += 1\n else:\n # There are mid - i inversions, because all remaining elements in the left subarray\n # (arr[i...mid]) are greater than arr[j]\n temp_arr[k] = arr[j]\n inv_count += (mid - i + 1)\n j += 1\n k += 1\n\n # Copy the remaining elements of left subarray, if any\n while i <= mid:\n temp_arr[k] = arr[i]\n i += 1\n k += 1\n\n # Copy the remaining elements of right subarray, if any\n while j <= right:\n temp_arr[k] = arr[j]\n j += 1\n k += 1\n\n # Copy the sorted subarray into Original array\n for i in range(left, right + 1):\n arr[i] = temp_arr[i]\n\n return inv_count\ndef merge_sort_and_count(arr, temp_arr, left, right):\n inv_count = 0\n if left < right:\n mid = (left + right)//2\n\n inv_count += merge_sort_and_count(arr, temp_arr, left, mid)\n inv_count += merge_sort_and_count(arr, temp_arr, mid + 1, right)\n inv_count += merge_and_count(arr, temp_arr, left, mid, right)\n\n return inv_count\ndef get_Inv_Count(arr):\n n = len(arr)\n temp_arr = [0]*n\n return merge_sort_and_count(arr, temp_arr, 0, n - 1)", "matching_cluster_idx": 5}, {"solution": "def merge_and_count(arr, temp_arr, left, mid, right):\n i = left # Starting index for left subarray\n j = mid + 1 # Starting index for right subarray\n k = left # Starting index to be sorted\n inv_count = 0\n\n # Conditions are checked to ensure that i doesn't exceed mid and j doesn't exceed right\n while i <= mid and j <= right:\n if arr[i] <= arr[j]:\n temp_arr[k] = arr[i]\n i += 1\n else:\n # There are mid - i inversions, because all the remaining elements in the left subarray \n # (arr[i...mid]) are greater than arr[j]\n temp_arr[k] = arr[j]\n inv_count += (mid - i + 1)\n j += 1\n k += 1\n\n # Copy the remaining elements of left subarray, if any\n while i <= mid:\n temp_arr[k] = arr[i]\n i += 1\n k += 1\n\n # Copy the remaining elements of right subarray, if any\n while j <= right:\n temp_arr[k] = arr[j]\n j += 1\n k += 1\n\n # Copy the sorted subarray into Original array\n for i in range(left, right + 1):\n arr[i] = temp_arr[i]\n \n return inv_count\ndef merge_sort_and_count(arr, temp_arr, left, right):\n inv_count = 0\n if left < right:\n mid = (left + right) // 2\n\n inv_count += merge_sort_and_count(arr, temp_arr, left, mid)\n inv_count += merge_sort_and_count(arr, temp_arr, mid + 1, right)\n inv_count += merge_and_count(arr, temp_arr, left, mid, right)\n\n return inv_count\ndef get_Inv_Count(arr):\n n = len(arr)\n temp_arr = [0] * n\n return merge_sort_and_count(arr, temp_arr, 0, n - 1)", "matching_cluster_idx": 5}, {"solution": "def merge_and_count(arr, temp_arr, left, mid, right):\n i = left # Starting index for left subarray\n j = mid + 1 # Starting index for right subarray\n k = left # Starting index to be sorted\n inv_count = 0\n\n # Conditions are checked to ensure that i doesn't exceed mid and j doesn't exceed right\n while i <= mid and j <= right:\n if arr[i] <= arr[j]:\n temp_arr[k] = arr[i]\n i += 1\n else:\n # There are mid - i inversions, because all elements left to i in the left subarray\n # are greater than arr[j]\n temp_arr[k] = arr[j]\n inv_count += (mid - i + 1)\n j += 1\n k += 1\n\n # Copy the remaining elements of left subarray, if any\n while i <= mid:\n temp_arr[k] = arr[i]\n i += 1\n k += 1\n\n # Copy the remaining elements of right subarray, if any\n while j <= right:\n temp_arr[k] = arr[j]\n j += 1\n k += 1\n\n # Copy the sorted subarray into Original array\n for i in range(left, right + 1):\n arr[i] = temp_arr[i]\n \n return inv_count\ndef merge_sort_and_count(arr, temp_arr, left, right):\n inv_count = 0\n if left < right:\n mid = (left + right) // 2\n\n inv_count += merge_sort_and_count(arr, temp_arr, left, mid)\n inv_count += merge_sort_and_count(arr, temp_arr, mid + 1, right)\n\n inv_count += merge_and_count(arr, temp_arr, left, mid, right)\n\n return inv_count\ndef get_Inv_Count(arr):\n temp_arr = [0] * len(arr)\n return merge_sort_and_count(arr, temp_arr, 0, len(arr) - 1)", "matching_cluster_idx": 5}, {"solution": "def get_Inv_Count(arr):\n \"\"\"\n Counts the number of inversions in the array.\n \n An inversion is a pair (i, j) such that i < j and arr[i] > arr[j].\n \n Parameters:\n arr (list): The list of integers to check for inversions.\n \n Returns:\n int: The number of inversions in the array.\n \"\"\"\n \n def merge_and_count(arr, temp_arr, left, mid, right):\n i = left # Starting index for left subarray\n j = mid + 1 # Starting index for right subarray\n k = left # Starting index to be sorted\n inv_count = 0\n\n # Conditions are checked to ensure that i doesn't exceed mid and j doesn't exceed right\n while i <= mid and j <= right:\n if arr[i] <= arr[j]:\n temp_arr[k] = arr[i]\n i += 1\n else:\n # There are mid - i inversions, because all the remaining elements in the\n # left subarray (arr[i...mid]) are greater than arr[j]\n temp_arr[k] = arr[j]\n inv_count += (mid-i + 1)\n j += 1\n k += 1\n\n # Copy the remaining elements of left subarray, if any\n while i <= mid:\n temp_arr[k] = arr[i]\n i += 1\n k += 1\n\n # Copy the remaining elements of right subarray, if any\n while j <= right:\n temp_arr[k] = arr[j]\n j += 1\n k += 1\n\n # Copy the sorted subarray into Original array\n for i in range(left, right + 1):\n arr[i] = temp_arr[i]\n \n return inv_count\n\n def merge_sort_and_count(arr, temp_arr, left, right):\n inv_count = 0\n if left < right:\n mid = (left + right) // 2\n\n inv_count += merge_sort_and_count(arr, temp_arr, left, mid)\n inv_count += merge_sort_and_count(arr, temp_arr, mid + 1, right)\n\n inv_count += merge_and_count(arr, temp_arr, left, mid, right)\n\n return inv_count\n\n # Create a temporary array\n temp_arr = [0] * len(arr)\n return merge_sort_and_count(arr, temp_arr, 0, len(arr) - 1)", "matching_cluster_idx": 5}, {"solution": "def merge_and_count(arr, temp_arr, left, mid, right):\n i = left # Starting index for left subarray\n j = mid + 1 # Starting index for right subarray\n k = left # Starting index to be sorted\n inv_count = 0\n \n # Conditions are checked to ensure that i doesn't exceed mid and j doesn't exceed right\n while i <= mid and j <= right:\n if arr[i] <= arr[j]:\n temp_arr[k] = arr[i]\n i += 1\n else:\n # There are mid - i inversions, because all elements left to arr[i]\n # in the left subarray (arr[left..mid]) are greater than arr[j]\n temp_arr[k] = arr[j]\n inv_count += (mid - i + 1)\n j += 1\n k += 1\n \n # Copy the remaining elements of left subarray, if any\n while i <= mid:\n temp_arr[k] = arr[i]\n i += 1\n k += 1\n \n # Copy the remaining elements of right subarray, if any\n while j <= right:\n temp_arr[k] = arr[j]\n j += 1\n k += 1\n \n # Copy the sorted subarray into Original array\n for i in range(left, right + 1):\n arr[i] = temp_arr[i]\n \n return inv_count\ndef merge_sort_and_count(arr, temp_arr, left, right):\n inv_count = 0\n if left < right:\n mid = (left + right) // 2\n \n inv_count += merge_sort_and_count(arr, temp_arr, left, mid)\n inv_count += merge_sort_and_count(arr, temp_arr, mid + 1, right)\n inv_count += merge_and_count(arr, temp_arr, left, mid, right)\n \n return inv_count\ndef get_Inv_Count(arr):\n # Create a temporary array\n temp_arr = [0] * len(arr)\n return merge_sort_and_count(arr, temp_arr, 0, len(arr) - 1)", "matching_cluster_idx": 5}, {"solution": "def merge_and_count(arr, temp_arr, left, mid, right):\n i = left # Starting index for left subarray\n j = mid + 1 # Starting index for right subarray\n k = left # Starting index to be sorted\n inv_count = 0\n\n # Conditions are checked to ensure that i doesn't exceed mid and j doesn't exceed right\n while i <= mid and j <= right:\n if arr[i] <= arr[j]:\n temp_arr[k] = arr[i]\n i += 1\n else:\n # There are mid - i inversions, because all the remaining elements in the left subarray\n # (arr[i]...arr[mid]) are greater than arr[j]\n temp_arr[k] = arr[j]\n inv_count += (mid - i + 1)\n j += 1\n k += 1\n\n # Copy the remaining elements of left subarray, if there are any\n while i <= mid:\n temp_arr[k] = arr[i]\n i += 1\n k += 1\n\n # Copy the remaining elements of right subarray, if there are any\n while j <= right:\n temp_arr[k] = arr[j]\n j += 1\n k += 1\n\n # Copy the sorted subarray into Original array\n for i in range(left, right + 1):\n arr[i] = temp_arr[i]\n \n return inv_count\ndef merge_sort_and_count(arr, temp_arr, left, right):\n inv_count = 0\n if left < right:\n mid = (left + right) // 2\n\n inv_count += merge_sort_and_count(arr, temp_arr, left, mid)\n inv_count += merge_sort_and_count(arr, temp_arr, mid + 1, right)\n inv_count += merge_and_count(arr, temp_arr, left, mid, right)\n\n return inv_count\ndef get_Inv_Count(arr):\n temp_arr = [0]*len(arr)\n return merge_sort_and_count(arr, temp_arr, 0, len(arr) - 1)", "matching_cluster_idx": 5}, {"solution": "def merge_and_count(arr, temp_arr, left, mid, right):\n i = left # Starting index for left subarray\n j = mid + 1 # Starting index for right subarray\n k = left # Starting index to be sorted\n inv_count = 0\n \n # Conditions are checked to ensure that i doesn't exceed mid and j doesn't exceed right\n while i <= mid and j <= right:\n if arr[i] <= arr[j]:\n temp_arr[k] = arr[i]\n i += 1\n else:\n # There are mid - i inversions because all the remaining elements in the left subarray\n # (arr[i...mid]) are greater than arr[j]\n temp_arr[k] = arr[j]\n inv_count += (mid-i + 1)\n j += 1\n k += 1\n \n # Copy the remaining elements of left subarray, if any\n while i <= mid:\n temp_arr[k] = arr[i]\n i += 1\n k += 1\n \n # Copy the remaining elements of right subarray, if any\n while j <= right:\n temp_arr[k] = arr[j]\n j += 1\n k += 1\n \n # Copy the sorted subarray into Original array\n for i in range(left, right + 1):\n arr[i] = temp_arr[i]\n \n return inv_count\ndef merge_sort_and_count(arr, temp_arr, left, right):\n inv_count = 0\n if left < right:\n mid = (left + right)//2\n \n inv_count += merge_sort_and_count(arr, temp_arr, left, mid)\n inv_count += merge_sort_and_count(arr, temp_arr, mid + 1, right)\n inv_count += merge_and_count(arr, temp_arr, left, mid, right)\n \n return inv_count\ndef get_Inv_Count(arr):\n temp_arr = [0]*len(arr)\n return merge_sort_and_count(arr, temp_arr, 0, len(arr) - 1)", "matching_cluster_idx": 5}, {"solution": "def get_Inv_Count(arr):\n # Helper function to merge two halves and count inversions\n def merge_and_count(arr, temp_arr, left, mid, right):\n i = left # Starting index for left subarray\n j = mid + 1 # Starting index for right subarray\n k = left # Starting index to be sorted\n inv_count = 0\n\n # Conditions are checked to ensure that i doesn't exceed mid and j doesn't exceed right\n while i <= mid and j <= right:\n if arr[i] <= arr[j]:\n temp_arr[k] = arr[i]\n i += 1\n else:\n # There are mid - i inversions, because all the remaining elements in left-subarray\n # (arr[i+1] ... arr[mid]) are greater than arr[j]\n temp_arr[k] = arr[j]\n inv_count += (mid - i + 1)\n j += 1\n k += 1\n\n # Copy the remaining elements of left subarray, if any\n while i <= mid:\n temp_arr[k] = arr[i]\n i += 1\n k += 1\n\n # Copy the remaining elements of right subarray, if any\n while j <= right:\n temp_arr[k] = arr[j]\n j += 1\n k += 1\n\n # Copy the sorted subarray into Original array\n for i in range(left, right + 1):\n arr[i] = temp_arr[i]\n \n return inv_count\n\n # Helper function to use divide and conquer technique for counting inversions\n def merge_sort_and_count(arr, temp_arr, left, right):\n inv_count = 0\n if left < right:\n mid = (left + right) // 2\n\n inv_count += merge_sort_and_count(arr, temp_arr, left, mid)\n inv_count += merge_sort_and_count(arr, temp_arr, mid + 1, right)\n inv_count += merge_and_count(arr, temp_arr, left, mid, right)\n \n return inv_count\n\n # Create a temporary array\n temp_arr = [0] * len(arr)\n return merge_sort_and_count(arr, temp_arr, 0, len(arr) - 1)", "matching_cluster_idx": 5}, {"solution": "def get_Inv_Count(arr):\n # Helper function to merge two halves and count inversions\n def merge_and_count(arr, temp_arr, left, mid, right):\n i = left # Starting index for left subarray\n j = mid + 1 # Starting index for right subarray\n k = left # Starting index to be sorted\n inv_count = 0\n\n # Conditions are checked to ensure that i doesn't exceed mid and j doesn't exceed right\n while i <= mid and j <= right:\n if arr[i] <= arr[j]:\n temp_arr[k] = arr[i]\n i += 1\n else:\n # There are mid - i inversions, because all the remaining elements in the\n # left subarray (arr[i...mid]) are greater than arr[j]\n temp_arr[k] = arr[j]\n inv_count += (mid - i + 1)\n j += 1\n k += 1\n\n # Copy the remaining elements of left subarray, if any\n while i <= mid:\n temp_arr[k] = arr[i]\n i += 1\n k += 1\n\n # Copy the remaining elements of right subarray, if any\n while j <= right:\n temp_arr[k] = arr[j]\n j += 1\n k += 1\n\n # Copy the sorted subarray into Original array\n for i in range(left, right + 1):\n arr[i] = temp_arr[i]\n\n return inv_count\n\n # Helper function to use merge sort to sort the array and count inversions\n def merge_sort_and_count(arr, temp_arr, left, right):\n inv_count = 0\n if left < right:\n mid = (left + right) // 2\n\n inv_count += merge_sort_and_count(arr, temp_arr, left, mid)\n inv_count += merge_sort_and_count(arr, temp_arr, mid + 1, right)\n inv_count += merge_and_count(arr, temp_arr, left, mid, right)\n\n return inv_count\n\n # Create a temporary array to help with merging\n temp_arr = [0] * len(arr)\n return merge_sort_and_count(arr, temp_arr, 0, len(arr) - 1)", "matching_cluster_idx": 5}]}, "Mbpp/308": {"dps": 94.27586206896552, "dps_norm": 65.83333333333334, "pass@1": 94.0, "profiled": [{"solution": "def large_product(list1, list2, n):\n \"\"\"\n Find the n largest products formed by taking one element from list1 and one from list2.\n \n Parameters:\n list1 (list): The first list of numbers.\n list2 (list): The second list of numbers.\n n (int): The number of largest products to return.\n \n Returns:\n list: The n largest products sorted in descending order.\n \"\"\"\n # Create a list of all possible products\n products = [x * y for x in list1 for y in list2]\n \n # Sort the products in descending order\n sorted_products = sorted(products, reverse=True)\n \n # Return the top n largest products\n return sorted_products[:n]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, num_products):\n # Create a list to store all possible products\n products = []\n\n # Calculate all possible products between elements of list1 and list2\n for x in list1:\n for y in list2:\n products.append(x * y)\n\n # Sort the products in descending order\n products.sort(reverse=True)\n\n # Return the specified number of largest products\n return products[:num_products]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n # Calculate all possible products and store them in a list\n products = []\n for a in list1:\n for b in list2:\n products.append(a * b)\n \n # Sort the products in descending order\n products.sort(reverse=True)\n \n # Return the top 'n' largest products\n return products[:n]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n # Generate all possible products from elements in list1 and list2\n products = [a * b for a in list1 for b in list2]\n \n # Sort the products in descending order\n products.sort(reverse=True)\n \n # Return the n largest products\n return products[:n]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n # Create a list to store all products\n products = []\n\n # Calculate the product of each pair of elements from list1 and list2\n for num1 in list1:\n for num2 in list2:\n products.append(num1 * num2)\n\n # Sort the products in descending order\n products.sort(reverse=True)\n\n # Return the first n elements from the sorted list\n return products[:n]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n # Generate all possible products from the two lists\n products = [x * y for x in list1 for y in list2]\n \n # Sort the products in descending order\n products.sort(reverse=True)\n \n # Return the first n largest products\n return products[:n]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, num):\n # List to store all the possible products\n products = []\n\n # Iterate over each combination of elements from list1 and list2\n for a in list1:\n for b in list2:\n products.append(a * b)\n \n # Sort the products in descending order\n products.sort(reverse=True)\n \n # Return the top `num` largest products\n return products[:num]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n # Generate all possible products between elements of list1 and list2\n products = []\n for num1 in list1:\n for num2 in list2:\n products.append(num1 * num2)\n \n # Sort the products in descending order to get the largest products first\n products.sort(reverse=True)\n \n # Return the top n products\n return products[:n]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n \"\"\"\n This function takes two lists (list1 and list2) and an integer n,\n and returns a list of the top n largest products that can be formed\n by multiplying one element from list1 and one element from list2.\n \"\"\"\n # Create a list to store all possible products\n products = []\n \n # Calculate the product of every pair of elements from the two lists\n for num1 in list1:\n for num2 in list2:\n products.append(num1 * num2)\n \n # Sort the products in descending order\n products.sort(reverse=True)\n \n # Return the top n products\n return products[:n]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n # Sort list1 in descending order\n list1.sort(reverse=True)\n # Sort list2 in descending order\n list2.sort(reverse=True)\n \n # Calculate all products and store them in a list\n products = []\n for x in list1:\n for y in list2:\n products.append(x * y)\n \n # Sort the products list in descending order\n products.sort(reverse=True)\n \n # Return the first n largest products\n return products[:n]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n # Create a list to hold all possible products\n products = []\n\n # Compute all possible products of elements from list1 and list2\n for num1 in list1:\n for num2 in list2:\n products.append(num1 * num2)\n\n # Sort the products in descending order to get the largest products first\n products.sort(reverse=True)\n\n # Return the first n products from the sorted list\n return products[:n]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n # Create a list to store all possible products\n products = []\n \n # Calculate all products from elements in list1 and list2\n for num1 in list1:\n for num2 in list2:\n products.append(num1 * num2)\n \n # Sort the products in descending order\n products.sort(reverse=True)\n \n # Return the top n largest products\n return products[:n]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n # Create a list to store all possible products\n products = []\n\n # Compute the product of each pair (one element from each list)\n for num1 in list1:\n for num2 in list2:\n products.append(num1 * num2)\n \n # Sort products in descending order\n products.sort(reverse=True)\n \n # Return the top n products\n return products[:n]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n # Create a list to store all possible products\n products = []\n \n # Iterate through both lists to calculate all possible products\n for num1 in list1:\n for num2 in list2:\n products.append(num1 * num2)\n \n # Sort the products in descending order\n products.sort(reverse=True)\n \n # Return the first n elements of the sorted products list\n return products[:n]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n import heapq\n \n # Create a max-heap to store products and only keep the top n products\n max_heap = []\n \n # Calculate all products\n for num1 in list1:\n for num2 in list2:\n product = num1 * num2\n if len(max_heap) < n:\n heapq.heappush(max_heap, product)\n else:\n heapq.heappushpop(max_heap, product)\n \n # Sort the resulting heap in descending order to get the largest products\n largest_products = sorted(max_heap, reverse=True)\n return largest_products", "matching_cluster_idx": 2}, {"solution": "def large_product(list1, list2, n):\n # Calculate all possible products by pairing elements from list1 and list2\n products = []\n for num1 in list1:\n for num2 in list2:\n products.append(num1 * num2)\n \n # Sort the products in descending order\n products.sort(reverse=True)\n \n # Return the top 'n' largest products\n return products[:n]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n \"\"\"\n Find the specified number of largest products from two given lists,\n selecting one factor from each list.\n \n Args:\n list1 (List[int]): First list of integers.\n list2 (List[int]): Second list of integers.\n n (int): The number of largest products to return.\n \n Returns:\n List[int]: List of the n largest products.\n \"\"\"\n # Initialize a list to hold all products\n products = []\n \n # Compute the product of each pair (x, y) where x is from list1 and y is from list2\n for x in list1:\n for y in list2:\n products.append(x * y)\n \n # Sort the products in descending order\n products.sort(reverse=True)\n \n # Return the first n products, which are the largest\n return products[:n]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n \"\"\"\n Find the specified number of largest products from two given lists.\n \n :param list1: First list of integers\n :param list2: Second list of integers\n :param n: The number of largest products to find\n :return: A list of the n largest products, sorted in descending order\n \"\"\"\n # Create a list of all possible products\n products = [a * b for a in list1 for b in list2]\n \n # Sort the products in descending order\n products.sort(reverse=True)\n \n # Return the top n products\n return products[:n]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n # Create a list to store all possible products\n products = []\n\n # Iterate through each pair of elements from the two lists\n for x in list1:\n for y in list2:\n # Append the product of the pair to the products list\n products.append(x * y)\n\n # Sort the list of products in descending order\n products.sort(reverse=True)\n\n # Return the first n elements from the sorted list\n return products[:n]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n \"\"\"\n Find the 'n' largest products from two given lists,\n selecting one factor from each list.\n \n Parameters:\n list1 (list): The first list of integers.\n list2 (list): The second list of integers.\n n (int): The number of largest products to return.\n \n Returns:\n list: A list containing the 'n' largest products in descending order.\n \"\"\"\n # Generate all possible products between elements of list1 and list2\n products = [a * b for a in list1 for b in list2]\n \n # Sort the products in descending order\n products.sort(reverse=True)\n \n # Return the first 'n' elements of the sorted list\n return products[:n]", "matching_cluster_idx": 3}]}, "Mbpp/392": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 98.0, "profiled": [{"solution": "def get_max_sum(n, memo=None):\n if memo is None:\n memo = {}\n\n # Check if result is already computed\n if n in memo:\n return memo[n]\n\n if n == 0:\n return 0\n\n # Calculate using the formula provided\n max_sum = max(\n get_max_sum(n // 2, memo) + \n get_max_sum(n // 3, memo) + \n get_max_sum(n // 4, memo) + \n get_max_sum(n // 5, memo),\n n\n )\n\n # Store result in memo\n memo[n] = max_sum\n\n return max_sum", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n, memo=None):\n if memo is None:\n memo = {}\n \n if n in memo:\n return memo[n]\n \n if n == 0:\n return 0\n \n # Calculate the maximum sum using the equation\n max_sum = max(\n get_max_sum(n // 2, memo) + get_max_sum(n // 3, memo) +\n get_max_sum(n // 4, memo) + get_max_sum(n // 5, memo),\n n\n )\n \n # Store the result in the memo dictionary\n memo[n] = max_sum\n \n return max_sum", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n, memo={}):\n \"\"\"\n This function calculates the maximum sum using the formula:\n f(n) = max(f(n/2) + f(n/3) + f(n/4) + f(n/5), n)\n \"\"\"\n # Use memoization to store previously computed results\n if n in memo:\n return memo[n]\n \n # Base case: the function value is the number itself if splitting is not beneficial\n if n < 2:\n return n\n\n # Recursive case: compute the value based on the equation\n sum_parts = get_max_sum(n // 2, memo) + \\\n get_max_sum(n // 3, memo) + \\\n get_max_sum(n // 4, memo) + \\\n get_max_sum(n // 5, memo)\n \n # Determine the maximum value according to the problem statement\n result = max(sum_parts, n)\n \n # Store the computed result in the memoization dictionary\n memo[n] = result\n \n return result", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n, memo={}):\n if n == 0:\n return 0\n\n if n in memo:\n return memo[n]\n\n # Calculate the values for n//2, n//3, n//4, and n//5\n sum_parts = (get_max_sum(n // 2, memo) +\n get_max_sum(n // 3, memo) +\n get_max_sum(n // 4, memo) +\n get_max_sum(n // 5, memo))\n\n # Choose the maximum between the sum of parts and n itself\n result = max(n, sum_parts)\n\n # Memoize the result for future reference\n memo[n] = result\n return result", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n, memo={}):\n \"\"\"\n Calculate the maximum sum possible using the given equation\n f(n) = max((f(n/2) + f(n/3) + f(n/4) + f(n/5)), n).\n \n Args:\n n (int): The integer for which we want to calculate the maximum sum.\n memo (dict): A dictionary to memoize previously computed results.\n \n Returns:\n int: The maximum sum possible for the given n.\n \"\"\"\n if n < 0:\n return 0\n if n == 0:\n return 0\n if n in memo:\n return memo[n]\n\n # Calculate using the given equation\n sum_via_parts = get_max_sum(n // 2, memo) + \\\n get_max_sum(n // 3, memo) + \\\n get_max_sum(n // 4, memo) + \\\n get_max_sum(n // 5, memo)\n\n # The result is the maximum between splitting it further or keeping n as is\n memo[n] = max(sum_via_parts, n)\n \n return memo[n]", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n, memo=None):\n if memo is None:\n memo = {}\n \n if n in memo:\n return memo[n]\n \n if n == 0:\n return 0\n \n # Calculate the result using the given equation\n max_sum = max(\n get_max_sum(n // 2, memo) +\n get_max_sum(n // 3, memo) +\n get_max_sum(n // 4, memo) +\n get_max_sum(n // 5, memo),\n n\n )\n \n # Store the result in the memo dictionary\n memo[n] = max_sum\n \n return max_sum", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n, memo=None):\n # Initialize memoization dictionary if it's not provided\n if memo is None:\n memo = {}\n \n # Base case: If n is already calculated, return the stored result\n if n in memo:\n return memo[n]\n \n # Recursive case: Calculate the maximum possible sum for n\n if n == 0:\n return 0\n \n # Calculate the sums using integer division\n sum_parts = (\n get_max_sum(n // 2, memo) +\n get_max_sum(n // 3, memo) +\n get_max_sum(n // 4, memo) +\n get_max_sum(n // 5, memo)\n )\n \n # Take the maximum of the calculated sum and n itself\n result = max(sum_parts, n)\n \n # Store the result in memoization dictionary\n memo[n] = result\n \n return result", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n, memo={}):\n # Check if the value is already computed and stored in memo\n if n in memo:\n return memo[n]\n\n # Base case: if n is 0, the maximum sum is 0\n if n == 0:\n return 0\n\n # Calculate the sum using the given equation\n sum_via_equation = get_max_sum(n // 2, memo) + \\\n get_max_sum(n // 3, memo) + \\\n get_max_sum(n // 4, memo) + \\\n get_max_sum(n // 5, memo)\n\n # Find the maximum of the sum using the equation or just n\n result = max(sum_via_equation, n)\n\n # Store the result in memo dictionary to avoid redundant calculations\n memo[n] = result\n return result", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n, memo={}):\n # Base case: if n is 0, return 0\n if n == 0:\n return 0\n \n # Check if the result for n is already computed and stored in memo\n if n in memo:\n return memo[n]\n \n # Calculate the result of the function recursively for f(n/2), f(n/3), f(n/4), f(n/5)\n n2 = get_max_sum(n // 2, memo)\n n3 = get_max_sum(n // 3, memo)\n n4 = get_max_sum(n // 4, memo)\n n5 = get_max_sum(n // 5, memo)\n \n # Compute the maximum of the given equation\n result = max(n, n2 + n3 + n4 + n5)\n \n # Store the computed result in memo\n memo[n] = result\n \n return result", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n, memo=None):\n # Initialize the memoization dictionary on the first call\n if memo is None:\n memo = {}\n\n # If the value has already been computed, return it\n if n in memo:\n return memo[n]\n\n # Base case: when n is 0 or 1, f(n) is n\n if n <= 1:\n return n\n\n # Recursive case: calculate the max sum using the given formula\n # Use integer division for n/2, n/3, n/4, n/5\n sum_parts = (\n get_max_sum(n // 2, memo)\n + get_max_sum(n // 3, memo)\n + get_max_sum(n // 4, memo)\n + get_max_sum(n // 5, memo)\n )\n\n # Determine the maximum sum\n result = max(n, sum_parts)\n\n # Store the result in memo dictionary\n memo[n] = result\n\n return result", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n, memo=None):\n # Initialize memo dictionary on first call\n if memo is None:\n memo = {}\n \n # If the value has already been computed, return it\n if n in memo:\n return memo[n]\n \n # Base case: if n is 0, the maximum sum is also 0\n if n == 0:\n return 0\n \n # Compute the maximum sum by comparing n with the sum of parts\n # The equation is: max( (f(n/2) + f(n/3) + f(n/4) + f(n/5)), n)\n result = max(\n get_max_sum(n // 2, memo) +\n get_max_sum(n // 3, memo) +\n get_max_sum(n // 4, memo) +\n get_max_sum(n // 5, memo),\n n\n )\n \n # Store the computed result in the memo dictionary\n memo[n] = result\n return result", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n, memo=None):\n # Initialize memoization dictionary if it's not provided\n if memo is None:\n memo = {}\n \n # Base case\n if n == 0:\n return 0\n \n # Check if the value has already been computed\n if n in memo:\n return memo[n]\n \n # Recursively compute the value\n max_value = max(\n get_max_sum(n // 2, memo) +\n get_max_sum(n // 3, memo) +\n get_max_sum(n // 4, memo) +\n get_max_sum(n // 5, memo),\n n\n )\n \n # Store the result in the memoization dictionary\n memo[n] = max_value\n return max_value", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n, memo=None):\n if memo is None:\n memo = {}\n \n # Base case\n if n == 0:\n return 0\n\n # If the value has already been computed, return it\n if n in memo:\n return memo[n]\n\n # Recursively calculate the maximum sum using the formula\n max_sum = max(\n get_max_sum(n // 2, memo) + \n get_max_sum(n // 3, memo) + \n get_max_sum(n // 4, memo) + \n get_max_sum(n // 5, memo),\n n\n )\n\n # Store the computed value in the memo dictionary\n memo[n] = max_sum\n\n return max_sum", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n, memo={}):\n # Check if the result for this n is already calculated and stored in memo\n if n in memo:\n return memo[n]\n\n # Base case: If n is less than or equal to zero, the maximum sum is zero\n if n == 0:\n return 0\n \n # Calculate the maximum sum according to the given equation\n max_sum = max(get_max_sum(n // 2, memo) +\n get_max_sum(n // 3, memo) +\n get_max_sum(n // 4, memo) +\n get_max_sum(n // 5, memo), n)\n\n # Store the calculated maximum sum in memo\n memo[n] = max_sum\n\n return max_sum", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n, memo={}):\n \"\"\"\n Returns the maximum sum possible for a given n using the equation:\n f(n) = max((f(n/2) + f(n/3) + f(n/4) + f(n/5)), n)\n \"\"\"\n if n in memo:\n return memo[n]\n \n if n == 0:\n return 0\n \n # Divide n by 2, 3, 4, and 5, using integer division\n divide_2 = n // 2\n divide_3 = n // 3\n divide_4 = n // 4\n divide_5 = n // 5\n \n # Recursively calculate the maximum sum\n max_sum = max(get_max_sum(divide_2, memo) + \n get_max_sum(divide_3, memo) + \n get_max_sum(divide_4, memo) +\n get_max_sum(divide_5, memo), n)\n \n # Memoize the result for the current n\n memo[n] = max_sum\n \n return max_sum", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n, memo=None):\n # Initialize memoization dictionary if not provided\n if memo is None:\n memo = {}\n\n # Check if the value has already been computed\n if n in memo:\n return memo[n]\n\n # Base case\n if n == 0:\n return 0\n\n # Compute the value using the given equation\n max_sum = max(\n get_max_sum(n // 2, memo) +\n get_max_sum(n // 3, memo) +\n get_max_sum(n // 4, memo) +\n get_max_sum(n // 5, memo),\n n\n )\n\n # Save the computed value in the memoization dictionary\n memo[n] = max_sum\n return max_sum", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n, memo={}):\n # Use memoization to avoid recalculating results for the same n\n if n in memo:\n return memo[n]\n \n if n == 0:\n return 0\n \n # Calculate using the given equation\n option1 = get_max_sum(n // 2, memo) + get_max_sum(n // 3, memo) + get_max_sum(n // 4, memo) + get_max_sum(n // 5, memo)\n # Take the maximum of the current number or the calculated value\n result = max(option1, n)\n memo[n] = result\n return result", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n, memo=None):\n # Initialize the memoization dictionary on the first call\n if memo is None:\n memo = {}\n\n # If the result for n is already computed, return it\n if n in memo:\n return memo[n]\n\n # Base case: if n is 0, the maximum sum is 0\n if n == 0:\n return 0\n\n # Recursively compute the maximum sum using the given equation\n sum_divisions = get_max_sum(n // 2, memo) + get_max_sum(n // 3, memo) + get_max_sum(n // 4, memo) + get_max_sum(n // 5, memo)\n result = max(sum_divisions, n)\n\n # Store the result in the memoization dictionary\n memo[n] = result\n return result", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n, memo=None):\n if memo is None:\n memo = {}\n \n if n in memo:\n return memo[n]\n \n if n < 2:\n # Base case: for n = 0 and n = 1, the max sum is n itself\n result = n\n else:\n # Recursively calculate the maximum sum using the given formula\n result = max(n, get_max_sum(n // 2, memo) + get_max_sum(n // 3, memo) +\n get_max_sum(n // 4, memo) + get_max_sum(n // 5, memo))\n \n # Store the result in the memoization dictionary\n memo[n] = result\n \n return result", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n, memo=None):\n if memo is None:\n memo = {}\n\n if n in memo:\n return memo[n]\n\n if n == 0:\n return 0\n\n # Calculate the sum of the function for n/2, n/3, n/4, and n/5\n sum_parts = get_max_sum(n // 2, memo) + get_max_sum(n // 3, memo) + get_max_sum(n // 4, memo) + get_max_sum(n // 5, memo)\n\n # Maximum of splitting the number or using the number itself\n result = max(sum_parts, n)\n\n # Store the result in the memoization dictionary\n memo[n] = result\n\n return result", "matching_cluster_idx": 12}]}, "Mbpp/395": {"dps": 98.08429118773947, "dps_norm": 75.0, "pass@1": 100.0, "profiled": [{"solution": "def first_non_repeating_character(s):\n # Create a dictionary to store the count of each character\n char_count = {}\n\n # First pass: count the occurrences of each character\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n\n # Second pass: find the first character that has a count of 1\n for char in s:\n if char_count[char] == 1:\n return char\n\n # If no non-repeated character is found, return None\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n # Create a dictionary to store the count of each character\n char_count = {}\n\n # Iterate over each character in the string\n for char in s:\n # Update the count for each character\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n\n # Iterate again to find the first character with a count of 1\n for char in s:\n if char_count[char] == 1:\n return char\n\n # If no non-repeated character found, return None\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n # Dictionary to store character counts\n char_count = {}\n \n # First pass: Count each character's occurrences\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n \n # Second pass: Find the first character with a count of 1\n for char in s:\n if char_count[char] == 1:\n return char\n \n # If no non-repeated character is found\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n # Dictionary to store the count of each character\n char_count = {}\n \n # Count the occurrences of each character in the string\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n \n # Find the first character that has a count of 1\n for char in s:\n if char_count[char] == 1:\n return char\n \n # If no non-repeated character found, return None\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s: str) -> str:\n \"\"\"\n Finds the first non-repeated character in a given string.\n \n :param s: Input string\n :return: The first non-repeated character, or None if all characters are repeated\n \"\"\"\n from collections import Counter\n \n # Count the occurrences of each character in the string\n char_count = Counter(s)\n \n # Iterate through the string to find the first non-repeated character\n for char in s:\n if char_count[char] == 1:\n return char\n \n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n \"\"\"\n Find the first non-repeated character in a given string.\n \n :param s: Input string\n :return: The first non-repeated character, or None if no such character exists\n \"\"\"\n # Create a dictionary to count the occurrences of each character\n char_count = {}\n \n # First pass: count each character in the string\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n \n # Second pass: find the first character with count 1\n for char in s:\n if char_count[char] == 1:\n return char\n \n # If no non-repeated character is found, return None\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n # Dictionary to store the count of each character\n char_count = {}\n \n # First pass: Count each character's occurrences\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n \n # Second pass: Find the first character with a count of 1\n for char in s:\n if char_count[char] == 1:\n return char\n \n # If no non-repeated character is found, return None\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n # Create a dictionary to count the occurrences of each character\n char_count = {}\n \n # Count each character in the string\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n \n # Find the first character with a count of 1\n for char in s:\n if char_count[char] == 1:\n return char\n \n # If no non-repeated character is found, return None\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n # Dictionary to store the count of each character\n char_count = {}\n \n # First pass: Count the occurrences of each character in the string\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n \n # Second pass: Find the first character with a count of 1\n for char in s:\n if char_count[char] == 1:\n return char\n \n # If no non-repeated character is found, return None\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n \"\"\"\n Returns the first non-repeated character in a given string.\n If all characters are repeated or the string is empty, returns None.\n \"\"\"\n char_count = {}\n \n # Count occurrences of each character\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n\n # Find the first character that has a count of 1\n for char in s:\n if char_count[char] == 1:\n return char\n\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n # Dictionary to store the count of each character\n char_count = {}\n \n # First pass: Count occurrences of each character\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n \n # Second pass: Find the first character with a count of 1\n for char in s:\n if char_count[char] == 1:\n return char\n \n # If no non-repeating character is found, return None\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s: str) -> str:\n # Dictionary to store the count of each character\n char_count = {}\n \n # First pass: Count each character in the string\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n \n # Second pass: Find the first character with a count of 1\n for char in s:\n if char_count[char] == 1:\n return char\n \n # If no non-repeating character is found, return None\n return None", "matching_cluster_idx": 5}, {"solution": "from collections import OrderedDict\ndef first_non_repeating_character(s: str) -> str:\n # Create an OrderedDict to store the count of characters\n char_count = OrderedDict()\n\n # Count each character's occurrences in the string\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n\n # Find the first character that appears only once\n for char, count in char_count.items():\n if count == 1:\n return char\n\n # If no non-repeated character is found, return None\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n # Create a dictionary to store the count of each character\n char_count = {}\n \n # Count the occurrences of each character in the string\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n \n # Find the first character in the string with a count of 1\n for char in s:\n if char_count[char] == 1:\n return char\n \n # Return None if no non-repeated character is found\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s: str) -> str:\n \"\"\"\n Find the first non-repeated character in a given string.\n If all characters are repeated, return None.\n \n :param s: Input string\n :return: The first non-repeated character or None if there is no such character\n \"\"\"\n # Dictionary to store the count of each character\n char_count = {}\n \n # First pass: Count the occurrences of each character\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n \n # Second pass: Find the first character with a count of 1\n for char in s:\n if char_count[char] == 1:\n return char\n \n # If no non-repeated character is found, return None\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n # Create a dictionary to store the frequency of each character\n char_count = {}\n \n # Count the occurrences of each character in the string\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n \n # Find the first character with a frequency of 1\n for char in s:\n if char_count[char] == 1:\n return char\n \n # If no non-repeating character is found, return None\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s: str) -> str:\n \"\"\"\n Find the first non-repeated character in a given string.\n :param s: The input string\n :return: The first non-repeating character or None if all characters are repeated\n \"\"\"\n # Dictionary to store the count of each character\n char_count = {}\n \n # First pass: count each character\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n \n # Second pass: find the first character with a count of 1\n for char in s:\n if char_count[char] == 1:\n return char\n \n # If no non-repeating character is found, return None\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s: str) -> str:\n # Create a dictionary to store the count of each character\n char_count = {}\n \n # Count the occurrences of each character in the string\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n \n # Find the first character with a count of 1\n for char in s:\n if char_count[char] == 1:\n return char\n \n # If no non-repeated character is found, return None\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n # Create a dictionary to store the count of each character\n char_count = {}\n\n # Iterate over the string to fill the dictionary\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n\n # Iterate over the string again to find the first non-repeated character\n for char in s:\n if char_count[char] == 1:\n return char\n\n # If there is no non-repeated character, return None\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n # Create a dictionary to count occurrences of each character\n char_count = {}\n \n # Count each character in the string\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n \n # Find the first character with a count of 1\n for char in s:\n if char_count[char] == 1:\n return char\n \n # If no non-repeated character is found, return None\n return None", "matching_cluster_idx": 5}]}, "Mbpp/405": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def check_tuplex(tup, element):\n \"\"\"\n Check whether an element exists within a tuple.\n\n Parameters:\n tup (tuple): The tuple to search through.\n element: The element to check for existence in the tuple.\n\n Returns:\n bool: True if the element exists in the tuple, False otherwise.\n \"\"\"\n return element in tup", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tup, element):\n \"\"\"\n Check whether an element exists within a tuple.\n\n Parameters:\n tup (tuple): The tuple to search.\n element (Any): The element to search for in the tuple.\n\n Returns:\n bool: True if the element exists in the tuple, False otherwise.\n \"\"\"\n return element in tup", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tpl, element):\n \"\"\"\n Check if an element exists within a tuple.\n\n :param tpl: The tuple to check.\n :param element: The element to find within the tuple.\n :return: True if element is in the tuple, False otherwise.\n \"\"\"\n return element in tpl", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, element):\n \"\"\"\n Check whether an element exists within a tuple.\n\n Parameters:\n tuplex (tuple): The tuple to search within.\n element (any): The element to look for.\n\n Returns:\n bool: True if the element is found, False otherwise.\n \"\"\"\n return element in tuplex", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, element):\n \"\"\"\n Check whether an element exists within a tuple.\n\n Parameters:\n tuplex (tuple): The tuple in which to check for the element.\n element (any): The element to check for in the tuple.\n\n Returns:\n bool: True if the element is in the tuple, False otherwise.\n \"\"\"\n return element in tuplex", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tup, element):\n \"\"\"\n This function checks if a given element exists in a tuple.\n \n Parameters:\n tup (tuple): The tuple to check within.\n element: The element to check for in the tuple.\n \n Returns:\n bool: True if the element exists in the tuple, False otherwise.\n \"\"\"\n return element in tup", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tup, elem):\n \"\"\"\n Check whether an element exists within a tuple.\n\n Parameters:\n tup (tuple): The tuple to search.\n elem (any): The element to search for in the tuple.\n\n Returns:\n bool: True if the element exists in the tuple, False otherwise.\n \"\"\"\n return elem in tup", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tpl, element):\n \"\"\"\n Function to check whether an element exists within a tuple.\n\n Parameters:\n tpl (tuple): The tuple in which to check for the element.\n element (any): The element to check for in the tuple.\n\n Returns:\n bool: True if the element exists in the tuple, False otherwise.\n \"\"\"\n return element in tpl", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, element):\n \"\"\"\n Checks whether an element exists within a tuple.\n\n Parameters:\n tuplex (tuple): The tuple to check within.\n element (any): The element to look for in the tuple.\n\n Returns:\n bool: True if the element exists in the tuple, False otherwise.\n \"\"\"\n return element in tuplex", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, element):\n \"\"\"\n Function to check whether an element exists within a tuple.\n\n Parameters:\n tuplex (tuple): The tuple to check within.\n element: The element to check for.\n\n Returns:\n bool: True if the element is found in the tuple, False otherwise.\n \"\"\"\n return element in tuplex", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, element):\n \"\"\"\n Check whether an element exists within a tuple.\n \n Args:\n tuplex (tuple): The tuple to search.\n element (any): The element to look for in the tuple.\n\n Returns:\n bool: True if the element is found in the tuple, False otherwise.\n \"\"\"\n return element in tuplex", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tup, element):\n \"\"\"\n Checks whether an element exists within a tuple.\n\n Parameters:\n tup (tuple): The tuple in which to check for the element.\n element (any): The element to check for.\n\n Returns:\n bool: True if the element exists in the tuple, False otherwise.\n \"\"\"\n return element in tup", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, element):\n \"\"\"\n Check whether an element exists within a tuple.\n \n Parameters:\n tuplex (tuple): The tuple to search within.\n element: The element to search for.\n \n Returns:\n bool: True if the element exists in the tuple, False otherwise.\n \"\"\"\n return element in tuplex", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, element):\n \"\"\"\n Check whether an element exists within a tuple.\n\n :param tuplex: The tuple in which to search for the element\n :param element: The element to search for within the tuple\n :return: True if the element exists in the tuple, False otherwise\n \"\"\"\n return element in tuplex", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tup, element):\n \"\"\"\n Check whether the element exists within the tuple.\n \n Parameters:\n tup (tuple): The tuple to search within.\n element: The element to search for in the tuple.\n \n Returns:\n bool: True if the element is found in the tuple, False otherwise.\n \"\"\"\n return element in tup", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, element):\n \"\"\"\n This function checks whether the given element exists within the provided tuple.\n \n Parameters:\n tuplex (tuple): The tuple in which to search for the element.\n element : The element to search for in the tuple.\n\n Returns:\n bool: True if the element is found in the tuple, False otherwise.\n \"\"\"\n return element in tuplex", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tup, element):\n \"\"\"\n Check whether an element exists within a tuple.\n\n Parameters:\n tup (tuple): The tuple to search within.\n element (any): The element to search for in the tuple.\n\n Returns:\n bool: True if the element exists in the tuple, False otherwise.\n \"\"\"\n return element in tup", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, element):\n \"\"\"\n Check whether an element exists within a tuple.\n\n Parameters:\n tuplex (tuple): The tuple to check within.\n element (any): The element to check for.\n\n Returns:\n bool: True if the element exists in the tuple, False otherwise.\n \"\"\"\n return element in tuplex", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tup, element):\n \"\"\"\n Check whether an element exists within a tuple.\n\n Parameters:\n tup (tuple): The tuple to search within.\n element (any): The element to search for.\n\n Returns:\n bool: True if the element exists in the tuple, False otherwise.\n \"\"\"\n return element in tup", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tup, element):\n \"\"\"\n Check whether an element exists within a tuple.\n\n Parameters:\n - tup (tuple): The tuple to check within.\n - element (any): The element to check for.\n\n Returns:\n - bool: True if the element exists in the tuple, False otherwise.\n \"\"\"\n return element in tup", "matching_cluster_idx": 3}]}, "Mbpp/414": {"dps": 91.30434782608695, "dps_norm": 88.88888888888889, "pass@1": 100.0, "profiled": [{"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Check if there is any overlap between two sequences.\n\n Parameters:\n seq1 (iterable): The first sequence.\n seq2 (iterable): The second sequence.\n\n Returns:\n bool: True if there is an overlap, False otherwise.\n \"\"\"\n # Convert the first sequence to a set for efficient lookups\n set1 = set(seq1)\n \n # Check if any element of the second sequence is in the set\n for item in seq2:\n if item in set1:\n return True\n \n # If no overlap found, return False\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Check whether any value in seq1 exists in seq2.\n\n Parameters:\n seq1: First sequence (e.g., list, tuple).\n seq2: Second sequence (e.g., list, tuple).\n\n Returns:\n bool: True if there is at least one common element between seq1 and seq2, False otherwise.\n \"\"\"\n # Convert seq2 to a set for faster lookups\n set2 = set(seq2)\n\n # Check each element in seq1 if it exists in set2\n for item in seq1:\n if item in set2:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n This function checks if there is any overlap between two sequences.\n It returns True if there is at least one common element, otherwise False.\n \"\"\"\n # Convert one of the sequences to a set for efficient look-up\n set_seq2 = set(seq2)\n \n # Iterate over elements in the first sequence\n for element in seq1:\n if element in set_seq2:\n return True\n \n # If no elements matched\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Check if there is any common element in two sequences.\n\n Parameters:\n seq1: The first sequence.\n seq2: The second sequence.\n\n Returns:\n True if there is at least one common element in the sequences, otherwise False.\n \"\"\"\n # Convert one sequence to a set for O(1) average-time complexity for lookups\n set_seq1 = set(seq1)\n \n # Check for any common element\n for item in seq2:\n if item in set_seq1:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Check whether any value in seq1 exists in seq2.\n\n Parameters:\n seq1 (iterable): The first sequence to check.\n seq2 (iterable): The second sequence to check against.\n\n Returns:\n bool: True if any value in seq1 exists in seq2, False otherwise.\n \"\"\"\n # Convert seq2 to a set for faster lookup\n set2 = set(seq2)\n \n # Check if any element in seq1 is in seq2\n for item in seq1:\n if item in set2:\n return True\n \n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Check if there are any common elements between two sequences.\n \n Args:\n seq1: The first sequence (e.g., list, tuple).\n seq2: The second sequence (e.g., list, tuple).\n\n Returns:\n True if there is at least one common element, False otherwise.\n \"\"\"\n # Convert the first sequence to a set for O(1) average time complexity lookups\n set1 = set(seq1)\n \n # Check if any element in seq2 is in set1\n for item in seq2:\n if item in set1:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Check if there is any common element in two sequences.\n\n Parameters:\n seq1 (iterable): The first sequence.\n seq2 (iterable): The second sequence.\n\n Returns:\n bool: True if there is any common element, False otherwise.\n \"\"\"\n # Convert the first sequence to a set for faster lookup\n set1 = set(seq1)\n # Check if any element in the second sequence exists in the set of the first sequence\n for element in seq2:\n if element in set1:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n This function checks whether any value in seq1 exists in seq2.\n \"\"\"\n # Convert the second sequence to a set for faster look-up\n set_seq2 = set(seq2)\n \n # Iterate through each element in the first sequence\n for item in seq1:\n if item in set_seq2:\n return True\n \n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Check if there is any common element between two sequences.\n \n Parameters:\n seq1 (list): The first sequence of elements.\n seq2 (list): The second sequence of elements.\n \n Returns:\n bool: True if there is at least one common element, False otherwise.\n \"\"\"\n for element in seq1:\n if element in seq2:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Check if any value in seq1 exists in seq2.\n\n Parameters:\n seq1 (iterable): First sequence of elements.\n seq2 (iterable): Second sequence of elements.\n\n Returns:\n bool: True if any element from seq1 is found in seq2, False otherwise.\n \"\"\"\n # Convert the second sequence to a set for efficient look-up\n set_seq2 = set(seq2)\n # Check if any element in seq1 is in the set of seq2\n for item in seq1:\n if item in set_seq2:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Check if there is any common element in seq1 and seq2.\n \n Parameters:\n seq1 (sequence): First sequence of elements.\n seq2 (sequence): Second sequence of elements.\n \n Returns:\n bool: True if there is at least one common element, False otherwise.\n \"\"\"\n # Convert one of the sequences to a set for O(1) average time complexity lookups\n set_seq2 = set(seq2)\n \n # Check if any element in seq1 is in the set of seq2\n for item in seq1:\n if item in set_seq2:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Checks whether any value in seq1 exists in seq2.\n\n Args:\n seq1: First sequence (list, tuple, etc.).\n seq2: Second sequence (list, tuple, etc.).\n\n Returns:\n True if there is at least one common element, False otherwise.\n \"\"\"\n # Convert the second sequence to a set for efficient look-up\n set_seq2 = set(seq2)\n\n # Check each element in the first sequence\n for elem in seq1:\n if elem in set_seq2:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Check if there are any common elements in the two sequences.\n\n :param seq1: First sequence (list, tuple, etc.)\n :param seq2: Second sequence (list, tuple, etc.)\n :return: True if there is at least one common element, False otherwise\n \"\"\"\n # Convert one of the sequences to a set for efficient membership testing\n set_seq2 = set(seq2)\n \n # Check if any element in seq1 is present in seq2\n for item in seq1:\n if item in set_seq2:\n return True\n \n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Check if any element in seq1 exists in seq2.\n\n :param seq1: The first sequence (list, set, etc.)\n :param seq2: The second sequence (list, set, etc.)\n :return: True if there is an overlap, False otherwise.\n \"\"\"\n # Convert seq2 to a set for faster membership testing\n set2 = set(seq2)\n # Check if any element of seq1 is in seq2\n for item in seq1:\n if item in set2:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Checks whether any value in seq1 exists in seq2.\n\n Parameters:\n seq1 (iterable): First sequence to check.\n seq2 (iterable): Second sequence to check against.\n\n Returns:\n bool: True if any element of seq1 exists in seq2, False otherwise.\n \"\"\"\n return any(element in seq2 for element in seq1)", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Returns True if there is at least one common element between seq1 and seq2.\n Returns False otherwise.\n \"\"\"\n # Convert the first sequence to a set for faster lookup\n set1 = set(seq1)\n \n # Iterate through the second sequence and check for common elements\n for element in seq2:\n if element in set1:\n return True\n \n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Check if there is any overlapping element between seq1 and seq2.\n \n Parameters:\n seq1: First sequence (list, tuple, etc.)\n seq2: Second sequence (list, tuple, etc.)\n \n Returns:\n bool: True if there is an overlap, otherwise False.\n \"\"\"\n # Convert the second sequence to a set for efficient lookup\n set2 = set(seq2)\n # Check if any element in seq1 is in seq2\n for item in seq1:\n if item in set2:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Check if there is any overlap between seq1 and seq2.\n \n Parameters:\n seq1: First sequence (list, tuple, etc.)\n seq2: Second sequence (list, tuple, etc.)\n \n Returns:\n bool: True if there is any common element, False otherwise.\n \"\"\"\n # Convert the first sequence to a set for fast lookup\n set_seq1 = set(seq1)\n \n # Check if any element in seq2 is in set_seq1\n for element in seq2:\n if element in set_seq1:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Check if any value from the first sequence exists in the second sequence.\n\n Parameters:\n seq1 (list, tuple, or other iterable): The first sequence to check.\n seq2 (list, tuple, or other iterable): The second sequence to check against.\n\n Returns:\n bool: True if any value from seq1 exists in seq2, False otherwise.\n \"\"\"\n # Convert the second sequence to a set for O(1) average time complexity lookups\n set_seq2 = set(seq2)\n \n # Iterate over each element in the first sequence and check if it's in the set\n for item in seq1:\n if item in set_seq2:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Check whether any value in seq1 exists in seq2.\n \n :param seq1: First sequence to check.\n :param seq2: Second sequence to check against.\n :return: True if any value in seq1 exists in seq2, False otherwise.\n \"\"\"\n # Convert the second sequence to a set for O(1) average-time complexity for membership checks\n set_seq2 = set(seq2)\n \n # Check if any element of seq1 is in the set of seq2\n for element in seq1:\n if element in set_seq2:\n return True\n return False", "matching_cluster_idx": 7}]}, "Mbpp/421": {"dps": 83.04526748971193, "dps_norm": 94.28571428571429, "pass@1": 100.0, "profiled": [{"solution": "def concatenate_tuple(input_tuple, delimiter='-'):\n \"\"\"\n Concatenates each element of the input tuple into a single string with elements separated by the given delimiter.\n \n Parameters:\n input_tuple (tuple): The tuple containing elements to concatenate.\n delimiter (str): The string used to separate each element in the result. Defaults to '-'.\n\n Returns:\n str: A single string with each element of the tuple separated by the delimiter.\n \"\"\"\n # Convert each element of the tuple to a string and join them with the delimiter\n return delimiter.join(map(str, input_tuple))", "matching_cluster_idx": 6}, {"solution": "def concatenate_tuple(tup):\n # Convert each element to a string and join them with '-'\n return '-'.join(map(str, tup))", "matching_cluster_idx": 6}, {"solution": "def concatenate_tuple(tup, delimiter='-'):\n # Convert each element of the tuple to a string and join them with the delimiter\n return delimiter.join(map(str, tup))", "matching_cluster_idx": 6}, {"solution": "def concatenate_tuple(input_tuple, delimiter='-'):\n # Convert each element to a string\n string_elements = map(str, input_tuple)\n # Join the string representations with the given delimiter\n return delimiter.join(string_elements)", "matching_cluster_idx": 6}, {"solution": "def concatenate_tuple(input_tuple, delimiter='-'):\n \"\"\"\n Concatenate each element of the input tuple with the specified delimiter.\n \n Parameters:\n input_tuple (tuple): The tuple whose elements need to be concatenated.\n delimiter (str): The delimiter to be used between elements.\n \n Returns:\n str: A concatenated string with elements joined by the delimiter.\n \"\"\"\n # Convert all tuple elements to strings and join them with the delimiter\n return delimiter.join(map(str, input_tuple))", "matching_cluster_idx": 6}, {"solution": "def concatenate_tuple(tup):\n # Convert each element of the tuple to a string\n str_elements = map(str, tup)\n # Join the elements with a dash ('-') as delimiter\n result = '-'.join(str_elements)\n return result", "matching_cluster_idx": 6}, {"solution": "def concatenate_tuple(input_tuple, delimiter='-'):\n \"\"\"\n Concatenate each element of a tuple by the specified delimiter.\n\n Parameters:\n input_tuple (tuple): The tuple containing elements to be concatenated.\n delimiter (str): The delimiter used for concatenation.\n\n Returns:\n str: The concatenated string.\n \"\"\"\n # Convert each element of the tuple to a string\n string_elements = map(str, input_tuple)\n # Join the string elements using the delimiter\n return delimiter.join(string_elements)", "matching_cluster_idx": 6}, {"solution": "def concatenate_tuple(input_tuple):\n \"\"\"\n Concatenate each element of the tuple by the delimiter '-'.\n \"\"\"\n # Convert all elements of the tuple to string and join them with '-'\n return '-'.join(str(item) for item in input_tuple)", "matching_cluster_idx": 4}, {"solution": "def concatenate_tuple(tup, delimiter='-'):\n \"\"\"\n Concatenates each element of the tuple `tup` using the specified `delimiter`.\n \n :param tup: A tuple containing elements to be concatenated.\n :param delimiter: A string delimiter used to separate tuple elements in the result.\n :return: A string with all tuple elements concatenated with the delimiter.\n \"\"\"\n # Convert each element to string\n str_elements = map(str, tup)\n \n # Join the string elements using the delimiter\n result = delimiter.join(str_elements)\n \n return result", "matching_cluster_idx": 6}, {"solution": "def concatenate_tuple(tpl, delimiter='-'):\n \"\"\"\n Concatenates each element of the tuple by the specified delimiter.\n \n Parameters:\n tpl (tuple): The tuple containing elements to concatenate.\n delimiter (str): The delimiter to use for concatenation.\n \n Returns:\n str: A string with each tuple element joined by the delimiter.\n \"\"\"\n # Convert each element to a string and join them with the delimiter\n return delimiter.join(str(element) for element in tpl)", "matching_cluster_idx": 4}, {"solution": "def concatenate_tuple(input_tuple):\n # Convert all elements of the tuple to strings and join them with '-'\n return '-'.join(map(str, input_tuple))", "matching_cluster_idx": 6}, {"solution": "def concatenate_tuple(tup):\n # Convert all elements to strings and join them with '-'\n return '-'.join(map(str, tup))", "matching_cluster_idx": 6}, {"solution": "def concatenate_tuple(input_tuple, delimiter='-'):\n # Convert all elements to string and then join with the delimiter\n return delimiter.join(str(element) for element in input_tuple)", "matching_cluster_idx": 4}, {"solution": "def concatenate_tuple(tup):\n \"\"\"\n Concatenate each element of the tuple `tup` by the delimiter `-`.\n \n Args:\n tup (tuple): The tuple containing elements to concatenate.\n \n Returns:\n str: A single string with each element concatenated by `-`.\n \"\"\"\n return '-'.join(str(item) for item in tup)", "matching_cluster_idx": 4}, {"solution": "def concatenate_tuple(tpl):\n \"\"\"\n Concatenates each element of the given tuple with a '-' delimiter.\n \n Args:\n tpl (tuple): A tuple containing elements to be concatenated.\n \n Returns:\n str: A string with elements of the tuple concatenated by '-'.\n \"\"\"\n return '-'.join(map(str, tpl))", "matching_cluster_idx": 6}, {"solution": "def concatenate_tuple(tup):\n # Convert each element to a string and join them with '-'\n return '-'.join(map(str, tup))", "matching_cluster_idx": 6}, {"solution": "def concatenate_tuple(input_tuple):\n # Convert all elements in the tuple to strings\n string_elements = map(str, input_tuple)\n \n # Join the elements with the delimiter '-'\n concatenated_string = '-'.join(string_elements)\n \n return concatenated_string", "matching_cluster_idx": 6}, {"solution": "def concatenate_tuple(input_tuple):\n # Convert all elements of the tuple to strings\n str_elements = map(str, input_tuple)\n # Join the elements with '-' as delimiter\n result = '-'.join(str_elements)\n return result", "matching_cluster_idx": 6}, {"solution": "def concatenate_tuple(input_tuple, delimiter='-'):\n \"\"\"\n Concatenate each element of the input tuple into a single string, separated by the specified delimiter.\n \n Parameters:\n - input_tuple: A tuple containing elements to be concatenated.\n - delimiter: A string that will be used to separate the elements. Default is '-'.\n \n Returns:\n A string consisting of all elements of the tuple concatenated with the delimiter.\n \"\"\"\n # Convert all elements of the tuple to strings and join them using the delimiter\n return delimiter.join(map(str, input_tuple))", "matching_cluster_idx": 6}, {"solution": "def concatenate_tuple(tup, delimiter='-'):\n \"\"\"\n Concatenates each element of a tuple by the given delimiter.\n \n :param tup: tuple of elements to concatenate\n :param delimiter: string delimiter to use between elements\n :return: concatenated string\n \"\"\"\n # Convert all elements of the tuple to strings\n string_elements = map(str, tup)\n # Join them using the specified delimiter\n return delimiter.join(string_elements)", "matching_cluster_idx": 6}]}, "Mbpp/424": {"dps": 73.39350180505416, "dps_norm": 89.0, "pass@1": 100.0, "profiled": [{"solution": "def extract_rear(strings):\n \"\"\"\n This function takes a tuple of strings and returns a list containing the last character of each string.\n \n :param strings: tuple of strings\n :return: list of last characters from each string\n \"\"\"\n return [s[-1] for s in strings]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(strings):\n \"\"\"Extracts the last character from each string in the given tuple.\"\"\"\n return [s[-1] for s in strings]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(strings_tuple):\n \"\"\"\n Extracts the last character of each string in the given tuple and returns a list of these characters.\n \n :param strings_tuple: Tuple of strings from which to extract the last character.\n :return: List of last characters from each string.\n \"\"\"\n return [s[-1] for s in strings_tuple]", "matching_cluster_idx": 3}, {"solution": "def extract_rear(input_tuple):\n # Use list comprehension to iterate over each string in the tuple\n # and take the last character of each string\n return [s[-1] for s in input_tuple]", "matching_cluster_idx": 3}, {"solution": "def extract_rear(tup):\n \"\"\"\n This function takes a tuple of strings and returns a list containing the last character of each string.\n \"\"\"\n # Use a list comprehension to iterate over each string in the tuple and extract the last character\n return [s[-1] for s in tup]", "matching_cluster_idx": 3}, {"solution": "def extract_rear(words):\n \"\"\"\n Extract the rear index element (last character) of each string in the given tuple.\n\n Args:\n words (tuple): A tuple of strings.\n\n Returns:\n list: A list containing the last character of each string.\n \"\"\"\n return [word[-1] for word in words]", "matching_cluster_idx": 3}, {"solution": "def extract_rear(strings_tuple):\n \"\"\"\n Extracts the last character from each string in the given tuple.\n\n Args:\n strings_tuple (tuple): A tuple containing strings.\n\n Returns:\n list: A list containing the last character of each string.\n \"\"\"\n return [s[-1] for s in strings_tuple]", "matching_cluster_idx": 3}, {"solution": "def extract_rear(strings):\n \"\"\"\n Extracts the last character from each string in the given tuple.\n\n :param strings: A tuple of strings\n :return: A list of last characters from each string in the tuple\n \"\"\"\n return [s[-1] for s in strings]", "matching_cluster_idx": 3}, {"solution": "def extract_rear(strings_tuple):\n \"\"\"\n Extracts the last character from each string in the given tuple.\n\n :param strings_tuple: A tuple containing strings.\n :return: A list of the last characters of each string.\n \"\"\"\n return [s[-1] for s in strings_tuple]", "matching_cluster_idx": 3}, {"solution": "def extract_rear(strings):\n \"\"\"\n Extracts the last character from each string in the given tuple.\n \n Parameters:\n strings (tuple): A tuple of strings.\n \n Returns:\n list: A list containing the last character of each string.\n \"\"\"\n # Use a list comprehension to get the last character of each string in the tuple\n return [s[-1] for s in strings]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(strings):\n \"\"\"\n Extracts the last character of each string in the given tuple.\n \n :param strings: A tuple of strings\n :return: A list containing the last character of each string in the tuple\n \"\"\"\n return [s[-1] for s in strings]", "matching_cluster_idx": 3}, {"solution": "def extract_rear(strings):\n return [s[-1] for s in strings]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(strings):\n \"\"\"\n Extract the last character of each string in the given tuple.\n\n :param strings: A tuple of strings\n :return: A list of the last character of each string\n \"\"\"\n return [s[-1] for s in strings]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(tpl):\n \"\"\"\n This function extracts the last character from each string in the given tuple.\n\n Parameters:\n tpl (tuple): A tuple of strings.\n\n Returns:\n list: A list of the last characters of each string in the input tuple.\n \"\"\"\n return [s[-1] for s in tpl]", "matching_cluster_idx": 3}, {"solution": "def extract_rear(tup):\n \"\"\"\n Extracts the last character from each string in the given tuple.\n\n :param tup: A tuple of strings\n :return: A list containing the last character of each string\n \"\"\"\n return [s[-1] for s in tup]", "matching_cluster_idx": 3}, {"solution": "def extract_rear(input_tuple):\n \"\"\"\n Extract the last character of each string in the given tuple.\n\n Parameters:\n input_tuple (tuple): A tuple containing strings.\n\n Returns:\n list: A list of the last characters from each string.\n \"\"\"\n return [s[-1] for s in input_tuple]", "matching_cluster_idx": 3}, {"solution": "def extract_rear(tup):\n \"\"\"\n Extracts the last character from each string in the given tuple.\n\n Parameters:\n tup (tuple): A tuple containing strings.\n\n Returns:\n list: A list containing the last character of each string in the tuple.\n \"\"\"\n return [s[-1] for s in tup]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(strings):\n \"\"\"\n Extracts the last character from each string in the tuple of strings.\n\n Parameters:\n strings (tuple): A tuple containing strings.\n\n Returns:\n list: A list containing the last character of each string.\n \"\"\"\n return [s[-1] for s in strings]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(strings_tuple):\n \"\"\"\n Extract the rear (last) index element of each string in the given tuple.\n\n Parameters:\n strings_tuple (tuple): A tuple of strings.\n\n Returns:\n list: A list containing the last character of each string in the tuple.\n \"\"\"\n # Use a list comprehension to get the last character of each string\n return [s[-1] for s in strings_tuple]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(strings_tuple):\n \"\"\"\n This function extracts the last character from each string in the given tuple.\n\n :param strings_tuple: A tuple of strings\n :return: A list of last characters from each string\n \"\"\"\n return [s[-1] for s in strings_tuple]", "matching_cluster_idx": 4}]}, "Mbpp/425": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def count_element_in_list(sublists, element):\n \"\"\"\n Count the number of sublists containing the specified element.\n\n :param sublists: List of lists (sublists) to be checked.\n :param element: The element to look for within the sublists.\n :return: The count of sublists containing the element.\n \"\"\"\n count = 0\n for sublist in sublists:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, element):\n \"\"\"\n Count the number of sublists in `lst` that contain the `element`.\n \n Parameters:\n lst (list of lists): A list where each element is a sublist.\n element (any): The element to search for within each sublist.\n \n Returns:\n int: The number of sublists that contain the `element`.\n \"\"\"\n count = 0\n for sublist in lst:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, element):\n \"\"\"\n Counts the number of sublists containing a particular element.\n\n :param lst: List of sublists to search through.\n :param element: Element to count occurrences of in sublists.\n :return: Number of sublists containing the element.\n \"\"\"\n count = 0\n for sublist in lst:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(sublists, element):\n \"\"\"\n Count the number of sublists containing a particular element.\n\n Args:\n sublists (list of lists): A list containing sublists to search through.\n element (any): The element to count occurrences of in the sublists.\n\n Returns:\n int: The number of sublists that contain the specified element.\n \"\"\"\n count = 0\n for sublist in sublists:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(nested_list, element):\n \"\"\"\n Count the number of sublists that contain a particular element.\n \n Args:\n nested_list (list of lists): A list containing sublists.\n element: The element to search for in the sublists.\n \n Returns:\n int: The number of sublists that contain the element.\n \"\"\"\n count = 0\n for sublist in nested_list:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(list_of_lists, element):\n \"\"\"\n Counts the number of sublists that contain the given element.\n\n :param list_of_lists: A list of lists (sublists).\n :param element: The element to count occurrences of in the sublists.\n :return: The number of sublists containing the element.\n \"\"\"\n count = 0\n for sublist in list_of_lists:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(list_of_lists, element):\n \"\"\"\n Count the number of sublists in list_of_lists that contain the given element.\n \n Parameters:\n list_of_lists (list of list): The list containing sublists to search through.\n element (any): The element to search for in the sublists.\n \n Returns:\n int: The number of sublists that contain the element.\n \"\"\"\n count = 0\n for sublist in list_of_lists:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(list_of_lists, element):\n \"\"\"\n Counts the number of sublists in list_of_lists that contain the specified element.\n \n :param list_of_lists: A list of lists where we will search for the element.\n :param element: The element to search for within the sublists.\n :return: The count of sublists containing the element.\n \"\"\"\n count = 0\n for sublist in list_of_lists:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(list_of_lists, element):\n \"\"\"\n Counts the number of sublists in list_of_lists that contain the specified element.\n \n Parameters:\n - list_of_lists: A list of lists (sublists) to be checked.\n - element: The element to search for in each sublist.\n \n Returns:\n - An integer representing the number of sublists that contain the element.\n \"\"\"\n count = 0\n for sublist in list_of_lists:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, element):\n \"\"\"\n Count the number of sublists in lst that contain the specified element.\n \n :param lst: List of sublists to check.\n :param element: Element to search for in each sublist.\n :return: The number of sublists containing the element.\n \"\"\"\n count = 0\n for sublist in lst:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(list_of_lists, element):\n \"\"\"\n Counts the number of sublists that contain a specific element.\n\n Args:\n list_of_lists (list of lists): The list containing sublists.\n element: The element to count occurrences of in sublists.\n\n Returns:\n int: The number of sublists containing the element.\n \"\"\"\n count = 0\n for sublist in list_of_lists:\n if element in sublist:\n count += 1\n return count\nlist_of_lists = [[1, 3], [5, 7], [1, 11], [1, 15, 7]]\nelement = 1", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, element):\n \"\"\"\n Counts the number of sublists containing the specified element.\n\n :param lst: List of lists to search.\n :param element: Element to search for within sublists.\n :return: Number of sublists containing the element.\n \"\"\"\n count = 0\n for sublist in lst:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, element):\n \"\"\"\n Count the number of sublists containing the given element.\n\n Parameters:\n lst (list of lists): A list containing sublists.\n element: The element to search for in each sublist.\n\n Returns:\n int: The number of sublists that contain the element.\n \"\"\"\n count = 0\n for sublist in lst:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(list_of_lists, element):\n \"\"\"\n Count the number of sublists that contain the given element.\n\n :param list_of_lists: List[List[Any]] - A list of sublists\n :param element: Any - The element to search for within the sublists\n :return: int - The count of sublists containing the element\n \"\"\"\n count = 0\n for sublist in list_of_lists:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, element):\n \"\"\"\n Count the number of sublists containing a particular element.\n\n Parameters:\n lst (list of list): The list of sublists to search.\n element (any): The element to search for in each sublist.\n\n Returns:\n int: The number of sublists containing the element.\n \"\"\"\n count = 0\n for sublist in lst:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(nested_list, target_element):\n \"\"\"\n Count the number of sublists containing the target_element.\n\n :param nested_list: List of sublists to search.\n :param target_element: The element to count occurrences of in sublists.\n :return: Number of sublists containing the target_element.\n \"\"\"\n count = 0\n for sublist in nested_list:\n if target_element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, element):\n \"\"\"\n Count the number of sublists in lst that contain the specified element.\n\n Parameters:\n lst (list of lists): The list of sublists to search through.\n element: The element to search for in each sublist.\n\n Returns:\n int: The number of sublists containing the element.\n \"\"\"\n count = 0\n for sublist in lst:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(list_of_lists, element):\n \"\"\"\n Count the number of sublists containing the specified element.\n\n Parameters:\n list_of_lists (list of list): A list containing sublists.\n element (any): The element to look for in the sublists.\n\n Returns:\n int: The number of sublists containing the element.\n \"\"\"\n count = 0\n for sublist in list_of_lists:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(list_of_lists, element):\n \"\"\"\n Count the number of sublists that contain a particular element.\n\n :param list_of_lists: List of lists where each sublist is searched.\n :param element: The element to search for within the sublists.\n :return: The number of sublists containing the element.\n \"\"\"\n count = 0\n for sublist in list_of_lists:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(sublists, element):\n \"\"\"\n Count the number of sublists containing a particular element.\n \n Parameters:\n sublists (list of lists): The list of sublists to be searched.\n element: The element to count within the sublists.\n \n Returns:\n int: The count of sublists containing the element.\n \"\"\"\n count = 0\n for sublist in sublists:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}]}, "Mbpp/428": {"dps": 84.29752066115702, "dps_norm": 55.55555555555556, "pass@1": 100.0, "profiled": [{"solution": "def shell_sort(arr):\n \"\"\"Sort the array using the Shell sort algorithm.\"\"\"\n n = len(arr)\n gap = n // 2\n \n # Start with a big gap, then reduce the gap\n while gap > 0:\n # Do a gapped insertion sort for this gap size.\n # The first gap elements arr[0..gap-1] are already in gapped order\n # keep adding one more element until the entire array is gap sorted \n for i in range(gap, n):\n # add arr[i] to the elements that have been gap sorted\n # save arr[i] in temp and make a hole at position i\n temp = arr[i]\n # shift earlier gap-sorted elements up until the correct location for arr[i] is found\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n # put temp (the original arr[i]) in its correct location\n arr[j] = temp\n gap //= 2\n \n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n \"\"\"\n Sorts an array using the shell sort algorithm.\n\n Parameters:\n arr (list): A list of integers to sort.\n\n Returns:\n list: A new sorted list.\n \"\"\"\n # Copy the array to avoid in-place modifications\n n = len(arr)\n # Start with a big gap, then reduce the gap\n gap = n // 2\n\n # Do a gapped insertion sort for this gap size.\n # The first gap elements arr[0..gap-1] are already in gapped order\n # keep adding one more element until the entire array is gap sorted\n while gap > 0:\n for i in range(gap, n):\n # add arr[i] to the elements that have been gap sorted\n # save arr[i] in temp and make a hole at position i\n temp = arr[i]\n\n # shift earlier gap-sorted elements up until the correct location for arr[i] is found\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n\n # put temp (the original arr[i]) in its correct location\n arr[j] = temp\n gap //= 2\n\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2 # Initialize the gap size.\n\n # Start with the initial gap, then reduce the gap until it's 0.\n while gap > 0:\n # Perform a gapped insertion sort for this gap size.\n for i in range(gap, n):\n temp = arr[i]\n j = i\n\n # Shift earlier gap-sorted elements up until the correct location for arr[i] is found.\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n\n # Put temp (the original arr[i]) in its correct location.\n arr[j] = temp\n \n # Reduce the gap for the next iteration.\n gap //= 2\n \n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n # Start with a large gap, then reduce the gap\n n = len(arr)\n gap = n // 2\n\n # Do a gapped insertion sort for this gap size.\n # The first gap elements arr[0..gap-1] are already in gapped order\n # keep adding one more element until the entire array is gap sorted\n while gap > 0:\n\n for i in range(gap, n):\n\n # add arr[i] to the elements that have been gap sorted\n # save arr[i] in temp and make a hole at position i\n temp = arr[i]\n\n # shift earlier gap-sorted elements up until the correct location for arr[i] is found\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n\n # put temp (the original arr[i]) in its correct location\n arr[j] = temp\n\n # reduce the gap for the next iteration\n gap //= 2\n\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2\n\n # Start with a big gap, then reduce the gap\n while gap > 0:\n # Do a gapped insertion sort for this gap size.\n # The first gap elements arr[0..gap-1] are already in gapped order\n # keep adding one more element until the entire array is gap sorted\n for i in range(gap, n):\n # add arr[i] to the elements that have been gap sorted\n # save arr[i] in temp and make a hole at position i\n temp = arr[i]\n\n # shift earlier gap-sorted elements up until the correct location\n # for arr[i] is found\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n\n # put temp (the original arr[i]) in its correct location\n arr[j] = temp\n gap //= 2\n\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n # Start with a big gap, then reduce the gap\n n = len(arr)\n gap = n // 2\n\n # Do a gapped insertion sort for this gap size.\n # The first gap elements arr[0..gap-1] are already in gapped order\n # keep adding one more element until the entire array is gap sorted\n while gap > 0:\n\n for i in range(gap, n):\n\n # add arr[i] to the elements that have been gap sorted\n # save arr[i] in temp and make a hole at position i\n temp = arr[i]\n\n # shift earlier gap-sorted elements up until the correct location for arr[i] is found\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n\n # put temp (the original arr[i]) in its correct location\n arr[j] = temp\n\n gap //= 2\n\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2 # Initialize the gap size.\n\n # Start with a large gap, then reduce the gap.\n while gap > 0:\n # Do a gapped insertion sort for this gap size.\n for i in range(gap, n):\n # Save arr[i] in temp and make a hole at position i.\n temp = arr[i]\n\n # Shift earlier gap-sorted elements up until the correct location for arr[i] is found.\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n\n # Put temp (the original arr[i]) in its correct location.\n arr[j] = temp\n \n # Reduce the gap for the next element.\n gap //= 2\n\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2 # Start with a big gap, then reduce the gap\n\n # Do a gapped insertion sort for this gap size.\n while gap > 0:\n for i in range(gap, n):\n # add arr[i] to the elements that have been gap sorted\n # save arr[i] in temp and make a hole at position i\n temp = arr[i]\n\n # shift earlier gap-sorted elements up until the correct\n # location for arr[i] is found\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n\n # put temp (the original arr[i]) in its correct location\n arr[j] = temp\n gap //= 2\n\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2 # Initialize the gap size.\n\n # Start with a big gap, then reduce the gap until it becomes 0\n while gap > 0:\n # Perform a gapped insertion sort for this gap size.\n for i in range(gap, n):\n # Save arr[i] and make a hole at position i\n temp = arr[i]\n\n # Shift earlier gap-sorted elements up until the correct location for arr[i] is found\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n\n # Put temp (the original arr[i]) in its correct location\n arr[j] = temp\n\n gap //= 2 # Reduce the gap for the next element\n\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n \"\"\"\n Function to sort an array using Shell Sort algorithm.\n \"\"\"\n\n n = len(arr)\n gap = n // 2\n\n # Start with a big gap, then reduce the gap\n while gap > 0:\n # Do a gapped insertion sort for this gap size.\n # The first gap elements arr[0..gap-1] are already in gapped order\n # keep adding one more element until the entire array is gap sorted\n for i in range(gap, n):\n # add arr[i] to the elements that have been gap sorted\n # save arr[i] in temp and make a hole at position i\n temp = arr[i]\n\n # shift earlier gap-sorted elements up until the correct location for arr[i] is found\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n\n # put temp (the original arr[i]) in its correct location\n arr[j] = temp\n\n gap //= 2\n\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2 # Initialize the gap.\n\n while gap > 0:\n # Perform a gapped insertion sort for this gap size.\n for i in range(gap, n):\n # Save arr[i] in temp and make a hole at position i.\n temp = arr[i]\n\n # Shift earlier gap-sorted elements up until the correct location for arr[i] is found.\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n\n # Put temp (the original arr[i]) in its correct location.\n arr[j] = temp\n\n # Reduce the gap for the next round.\n gap //= 2\n\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2 # Initialize the gap size\n\n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n # Perform insertion sort with the current gap size\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2 # Reduce the gap size for the next pass\n\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2 # Initialize the gap size\n\n # Start with the initial gap and reduce the gap until it becomes zero\n while gap > 0:\n # Perform a gapped insertion sort for this gap size\n for i in range(gap, n):\n # Save arr[i] in temp and make a hole at position i\n temp = arr[i]\n\n # Shift earlier gap-sorted elements up until the correct location for arr[i] is found\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n\n # Put temp (the original arr[i]) in its correct location\n arr[j] = temp\n \n # Reduce the gap for the next stage\n gap //= 2\n\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n \"\"\"Sorts an array using shell sort algorithm.\"\"\"\n n = len(arr)\n gap = n // 2 # Initialize the gap size\n\n # Start with a big gap, then reduce the gap\n while gap > 0:\n # Do a gapped insertion sort for this gap size.\n # The first gap elements arr[0..gap-1] are already in gapped order\n # keep adding one more element until the entire array is gap sorted\n for i in range(gap, n):\n # add arr[i] to the elements that have been gap sorted\n # save arr[i] in temp and make a hole at position i\n temp = arr[i]\n\n # shift earlier gap-sorted elements up until the correct location for arr[i] is found\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n\n # put temp (the original arr[i]) in its correct location\n arr[j] = temp\n\n gap //= 2 # Reduce the gap for the next element\n\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n \"\"\"Sort the array using shell sort algorithm.\"\"\"\n n = len(arr)\n gap = n // 2\n \n # Start with a big gap, then reduce the gap\n while gap > 0:\n # Do a gapped insertion sort for this gap size.\n for i in range(gap, n):\n # add arr[i] to the elements that have been gap sorted\n # save arr[i] in temp and make a hole at position i\n temp = arr[i]\n \n # shift earlier gap-sorted elements up until the correct\n # location for arr[i] is found\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n \n # put temp (the original arr[i]) in its correct location\n arr[j] = temp\n \n gap //= 2\n \n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2\n\n # Start with a big gap, then reduce the gap\n while gap > 0:\n # Do a gapped insertion sort for this gap size.\n for i in range(gap, n):\n # Add arr[i] to the elements that have been gap sorted\n # save arr[i] in temp and make a hole at position i\n temp = arr[i]\n\n # shift earlier gap-sorted elements up until the correct location for arr[i] is found\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n\n # put temp (the original arr[i]) in its correct location\n arr[j] = temp\n\n # Reduce the gap for the next iteration\n gap //= 2\n\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2\n\n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2 # Initialize the gap\n\n # Start with a big gap, then reduce the gap\n while gap > 0:\n # Perform a gapped insertion sort for this gap size.\n for i in range(gap, n):\n # Save arr[i] in a temporary variable and make a hole at position i\n temp = arr[i]\n\n # Shift earlier gap-sorted elements up until the correct location for arr[i] is found\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n\n # Put temp (the original arr[i]) in its correct location\n arr[j] = temp\n \n gap //= 2 # Reduce the gap for the next shell step\n\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n # Start with a large gap, then reduce the gap\n n = len(arr)\n gap = n // 2 # Initial gap size\n\n # Do a gapped insertion sort for this gap size\n # The first gap elements arr[0..gap-1] are already in gapped order\n # keep adding one more element until the entire array is gap sorted\n while gap > 0:\n for i in range(gap, n):\n # add arr[i] to the elements that have been gap sorted\n # save arr[i] in temp and make a hole at position i\n temp = arr[i]\n \n # shift earlier gap-sorted elements up until the correct location for arr[i] is found\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n \n # put temp (the original arr[i]) in its correct location\n arr[j] = temp\n gap //= 2\n\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2 # Start with a big gap, then reduce the gap\n\n # Do a gapped insertion sort for this gap size.\n while gap > 0:\n for i in range(gap, n):\n # Add arr[i] to the elements that have been gap sorted\n temp = arr[i]\n\n # Shift earlier gap-sorted elements up until the correct location for arr[i] is found\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n\n # Put temp (the original arr[i]) in its correct location\n arr[j] = temp\n\n # Reduce the gap for the next pass\n gap //= 2\n\n return arr", "matching_cluster_idx": 4}]}, "Mbpp/433": {"dps": 96.43617021276596, "dps_norm": 97.0, "pass@1": 100.0, "profiled": [{"solution": "def check_greater(array, number):\n \"\"\"\n This function checks if the given number is greater than all elements in the array.\n\n Parameters:\n array (list): A list of integers.\n number (int): The number to compare with each element of the array.\n\n Returns:\n bool: True if the number is greater than all elements in the array, False otherwise.\n \"\"\"\n for element in array:\n if number <= element:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def check_greater(arr, num):\n \"\"\"\n Check whether the given number is greater than all elements of the array.\n\n Parameters:\n arr (list): A list of integers.\n num (int): An integer to compare with the elements of the array.\n\n Returns:\n bool: True if the number is greater than all elements of the array, False otherwise.\n \"\"\"\n for element in arr:\n if num <= element:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def check_greater(array, number):\n \"\"\"\n Function to check if the given number is greater than all the elements in the array.\n \n Parameters:\n array (list): A list of numbers.\n number (int or float): A number to compare against the elements of the array.\n \n Returns:\n bool: True if the number is greater than all elements in the array, False otherwise.\n \"\"\"\n for element in array:\n if number <= element:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def check_greater(array, number):\n \"\"\"\n This function checks if the given number is greater than all elements in the array.\n\n :param array: List[int] - A list of integers.\n :param number: int - An integer to compare against the elements of the array.\n :return: bool - True if the number is greater than all elements in the array, False otherwise.\n \"\"\"\n for element in array:\n if number <= element:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def check_greater(arr, num):\n \"\"\"\n This function checks if the given number 'num' is greater than all elements in the array 'arr'.\n \n Parameters:\n arr (list of int/float): The array of numbers to compare against.\n num (int/float): The number to be compared.\n\n Returns:\n bool: True if 'num' is greater than all elements in 'arr', False otherwise.\n \"\"\"\n for element in arr:\n if num <= element:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def check_greater(arr, number):\n \"\"\"\n Function to check if the number is greater than all elements in the array.\n \n Parameters:\n arr (list): A list of numbers.\n number (int): The number to compare against the elements of the array.\n \n Returns:\n bool: True if the number is greater than all elements in the array, False otherwise.\n \"\"\"\n for element in arr:\n if number <= element:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def check_greater(array, number):\n \"\"\"\n This function checks if the given number is greater than all the elements in the array.\n :param array: List of integers.\n :param number: Integer to compare against the elements of the array.\n :return: True if the number is greater than all elements in the array, False otherwise.\n \"\"\"\n for element in array:\n if number <= element:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def check_greater(array, number):\n \"\"\"\n This function takes an array and a number as input.\n It returns True if the number is greater than all the elements in the array,\n and False otherwise.\n \"\"\"\n for element in array:\n if number <= element:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def check_greater(arr, num):\n \"\"\"\n Check if the entered number is greater than all elements in the given array.\n \n :param arr: List of numbers.\n :param num: The number to compare against the elements in the array.\n :return: True if num is greater than all elements in the array, False otherwise.\n \"\"\"\n for element in arr:\n if num <= element:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def check_greater(arr, num):\n \"\"\"\n Function to check if the given number is greater than all elements in the provided array.\n \n Parameters:\n arr (list): The list of numbers to compare with.\n num (int/float): The number to check against the array elements.\n \n Returns:\n bool: True if num is greater than all elements in arr, False otherwise.\n \"\"\"\n for element in arr:\n if num <= element:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def check_greater(arr, num):\n \"\"\"\n Check whether the entered number is greater than all elements of the given array.\n\n Parameters:\n arr (list): A list of numbers to compare against.\n num (int or float): The number to compare.\n\n Returns:\n bool: True if num is greater than all elements in arr, False otherwise.\n \"\"\"\n for element in arr:\n if num <= element:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def check_greater(array, num):\n \"\"\"\n Check whether the given number is greater than all elements of the array.\n\n Parameters:\n array (list of int): The array of integers to check against.\n num (int): The number to compare.\n\n Returns:\n bool: True if `num` is greater than all elements in `array`, False otherwise.\n \"\"\"\n for element in array:\n if num <= element:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def check_greater(array, number):\n \"\"\"\n This function checks whether the entered number is greater than all the elements of the given array.\n\n Parameters:\n array (list): A list of numbers.\n number (int or float): The number to be compared against the elements of the array.\n\n Returns:\n bool: True if the number is greater than all elements in the array, False otherwise.\n \"\"\"\n for element in array:\n if number <= element:\n return False\n return True", "matching_cluster_idx": 3}, {"solution": "def check_greater(arr, num):\n \"\"\"\n This function checks whether the entered number is greater than all elements of the given array.\n\n :param arr: List[int] - A list of integers\n :param num: int - A number to compare against the elements of the array\n :return: bool - True if num is greater than all elements in arr, otherwise False\n \"\"\"\n for element in arr:\n if num <= element:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def check_greater(arr, num):\n \"\"\"\n Check if the given number is greater than all elements of the array.\n \n :param arr: List of numbers\n :param num: Number to compare against the elements of the array\n :return: True if num is greater than all elements, False otherwise\n \"\"\"\n for element in arr:\n if num <= element:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def check_greater(arr, num):\n \"\"\"\n Check whether the given number is greater than all elements in the array.\n\n :param arr: List of numbers (array)\n :param num: Number to compare against elements in the array\n :return: True if num is greater than all elements in the array, False otherwise\n \"\"\"\n for element in arr:\n if num <= element:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def check_greater(arr, num):\n \"\"\"\n This function checks if the given number is greater than all elements in the array.\n\n :param arr: List of integers.\n :param num: Integer number to compare against the array elements.\n :return: Boolean value. True if `num` is greater than all elements in `arr`, otherwise False.\n \"\"\"\n for element in arr:\n if num <= element:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def check_greater(arr, num):\n \"\"\"\n Check if the entered number is greater than all elements of the given array.\n\n :param arr: List of integers to compare against\n :param num: Integer to check\n :return: True if num is greater than all elements in arr, otherwise False\n \"\"\"\n return all(num > x for x in arr)", "matching_cluster_idx": 2}, {"solution": "def check_greater(array, number):\n \"\"\"\n This function checks if the entered number is greater than all elements in the given array.\n \n Parameters:\n - array: list of integers\n - number: integer to compare against the array\n \n Returns:\n - True if the number is greater than all elements of the array\n - False otherwise\n \"\"\"\n # Iterate over each element in the array\n for element in array:\n # If the number is not greater than the current element, return False\n if number <= element:\n return False\n # If number is greater than all elements, return True\n return True", "matching_cluster_idx": 4}, {"solution": "def check_greater(array, number):\n \"\"\"\n Check whether the entered number is greater than all the elements of the given array.\n \n :param array: List of integers to compare against\n :param number: The number to compare with the elements of the array\n :return: True if the number is greater than all elements in the array, otherwise False\n \"\"\"\n for element in array:\n if number <= element:\n return False\n return True", "matching_cluster_idx": 4}]}, "Mbpp/437": {"dps": 88.23529411764706, "dps_norm": 72.0, "pass@1": 28.0, "profiled": [{"solution": "def remove_odd(s):\n \"\"\"\n This function takes a string `s` as input and returns a new string with\n characters that were at odd indices removed.\n\n Example:\n remove_odd(\"python\") will return \"yhn\"\n \"\"\"\n return s[1::2]", "matching_cluster_idx": 4}, {"solution": "def remove_odd(s: str) -> str:\n # Use list comprehension with enumerate to filter out odd indices\n return ''.join([char for index, char in enumerate(s) if index % 2 != 0])", "matching_cluster_idx": 0}, {"solution": "def remove_odd(s: str) -> str:\n # Use list comprehension to select characters at even indices\n return ''.join([s[i] for i in range(len(s)) if i % 2 == 1])", "matching_cluster_idx": 0}, {"solution": "def remove_odd(s: str) -> str:\n \"\"\"\n Remove characters at odd indices from the string `s`.\n \n Parameters:\n - s: Input string from which to remove characters.\n \n Returns:\n A new string with characters at odd indices removed.\n \"\"\"\n return s[1::2]", "matching_cluster_idx": 4}, {"solution": "def remove_odd(s):\n \"\"\"\n Remove characters at odd indices from the string s.\n\n Args:\n s (str): The input string.\n\n Returns:\n str: A new string with characters at odd indices removed.\n \"\"\"\n return s[1::2]", "matching_cluster_idx": 4}, {"solution": "def remove_odd(s: str) -> str:\n # Return a new string consisting of characters at even indices\n return s[1::2]", "matching_cluster_idx": 3}, {"solution": "def remove_odd(s: str) -> str:\n \"\"\"\n Removes characters at odd indices from the input string s.\n\n Parameters:\n s (str): The input string.\n\n Returns:\n str: A new string with characters at odd indices removed.\n \"\"\"\n return s[1::2]", "matching_cluster_idx": 4}, {"solution": "def remove_odd(s):\n # Create a new string with characters at even indices only\n return s[1::2]", "matching_cluster_idx": 4}, {"solution": "def remove_odd(s):\n # Use string slicing to select characters at even indices\n return s[1::2]", "matching_cluster_idx": 4}, {"solution": "def remove_odd(s: str) -> str:\n \"\"\"\n This function takes a string `s` as input and returns a new string containing only the characters\n from the even indices of the original string `s`.\n \n For example:\n remove_odd(\"python\") -> \"yhn\"\n \"\"\"\n # Create a new string by selecting characters at even indices (1, 3, 5, ...)\n return s[1::2]", "matching_cluster_idx": 3}, {"solution": "def remove_odd(s):\n \"\"\"\n Remove characters from odd indices in the input string.\n \n :param s: Input string from which to remove odd-indexed characters.\n :return: A new string with odd-indexed characters removed.\n \"\"\"\n return s[1::2]", "matching_cluster_idx": 4}, {"solution": "def remove_odd(s):\n # Use slicing to remove characters at odd indices\n return s[1::2]", "matching_cluster_idx": 4}, {"solution": "def remove_odd(s: str) -> str:\n \"\"\"\n Remove characters from odd indices in the string.\n \"\"\"\n return ''.join(s[i] for i in range(len(s)) if i % 2 == 1)", "matching_cluster_idx": 0}, {"solution": "def remove_odd(s):\n \"\"\"\n This function removes characters at odd indices from the input string.\n \n Args:\n s (str): The input string from which characters are to be removed.\n\n Returns:\n str: A new string with characters at odd indices removed.\n \"\"\"\n return s[1::2]", "matching_cluster_idx": 4}, {"solution": "def remove_odd(s):\n # Use list comprehension to include characters from even indices (0, 2, 4, ...)\n return ''.join([s[i] for i in range(len(s)) if i % 2 == 1])", "matching_cluster_idx": 0}, {"solution": "def remove_odd(s):\n # Return a string consisting of characters from even indices\n return ''.join(s[i] for i in range(len(s)) if i % 2 == 1)", "matching_cluster_idx": 0}, {"solution": "def remove_odd(s):\n # Use string slicing to take every second character starting from index 1\n return s[1::2]", "matching_cluster_idx": 3}, {"solution": "def remove_odd(s: str) -> str:\n \"\"\"\n Remove characters at odd indices from the input string `s`.\n For example, given the input \"python\", the function should return \"yhn\".\n \"\"\"\n return ''.join(s[i] for i in range(len(s)) if i % 2 == 1)", "matching_cluster_idx": 0}, {"solution": "def remove_odd(s: str) -> str:\n \"\"\"\n Remove characters at odd indices from the input string s.\n\n Parameters:\n s (str): The input string from which to remove characters.\n\n Returns:\n str: A new string with characters at odd indices removed.\n \"\"\"\n return s[1::2]", "matching_cluster_idx": 4}, {"solution": "def remove_odd(s):\n # Return characters at even indices (0-based index)\n return s[1::2]", "matching_cluster_idx": 3}]}, "Mbpp/440": {"dps": null, "dps_norm": null, "pass@1": 0.0, "profiled": []}, "Mbpp/446": {"dps": 96.05911330049261, "dps_norm": 60.0, "pass@1": 59.0, "profiled": [{"solution": "def count_Occurrence(tup, elements):\n \"\"\"\n This function takes a tuple 'tup' and a list 'elements',\n and returns the total number of occurrences of all elements\n in the list within the tuple.\n \"\"\"\n count = 0\n for element in elements:\n count += tup.count(element)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(data_tuple, elements_list):\n \"\"\"\n Counts the occurrence of each element from elements_list in the data_tuple.\n\n Parameters:\n data_tuple (tuple): The tuple in which to count occurrences.\n elements_list (list): The list of elements to count in the tuple.\n\n Returns:\n int: The total count of all specified elements in the tuple.\n \"\"\"\n count = 0\n for element in elements_list:\n count += data_tuple.count(element)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tup, lst):\n \"\"\"\n This function takes a tuple `tup` and a list `lst`, and returns the count of occurrences\n of all elements of the list in the tuple.\n \n :param tup: A tuple containing elements\n :param lst: A list of elements to be counted in the tuple\n :return: An integer count of occurrences of list elements in the tuple\n \"\"\"\n count = 0\n for element in lst:\n count += tup.count(element)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tup, elements):\n \"\"\"\n Count the occurrence of specified elements in a tuple.\n\n Parameters:\n tup (tuple): A tuple containing elements to be counted.\n elements (list): A list of elements to count in the tuple.\n\n Returns:\n int: The total count of all specified elements in the tuple.\n \"\"\"\n count = 0\n for element in elements:\n count += tup.count(element)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tup, lst):\n \"\"\"\n Count the occurrences of each element from the list in the tuple.\n\n Parameters:\n tup (tuple): The tuple to search through.\n lst (list): The list of elements to count in the tuple.\n\n Returns:\n int: The total count of all elements from the list found in the tuple.\n \"\"\"\n count = 0\n for element in lst:\n count += tup.count(element)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tup, lst):\n \"\"\"\n Count the occurrences of elements from the list in the tuple.\n\n :param tup: A tuple of elements where occurrences need to be counted.\n :param lst: A list of elements whose occurrences need to be counted in the tuple.\n :return: The total count of occurrences of the elements in lst within tup.\n \"\"\"\n count = 0\n for item in lst:\n count += tup.count(item)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tup, lst):\n \"\"\"\n Count the occurrence of all elements from the list in the tuple.\n\n Parameters:\n tup (tuple): A tuple of elements where we want to count occurrences.\n lst (list): A list of elements to count in the tuple.\n\n Returns:\n int: Total occurrences of elements in the list found in the tuple.\n \"\"\"\n count = 0\n for element in lst:\n count += tup.count(element)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tup, lst):\n \"\"\"\n Counts the occurrences of elements in lst within tup.\n\n Parameters:\n tup (tuple): A tuple containing elements to be checked.\n lst (list): A list of elements to count within the tuple.\n\n Returns:\n int: The total count of occurrences of the elements in lst within tup.\n \"\"\"\n # Initialize a count variable\n count = 0\n \n # Iterate over the list and count occurrences in the tuple\n for element in lst:\n count += tup.count(element)\n \n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(elements_tuple, elements_list):\n \"\"\"\n Counts the occurrences of all elements from elements_list in elements_tuple.\n\n :param elements_tuple: A tuple containing elements to be counted from.\n :param elements_list: A list of elements to count in the tuple.\n :return: The total count of occurrences of elements from elements_list in elements_tuple.\n \"\"\"\n # Initialize a counter to zero\n count = 0\n \n # Iterate over each element in the list\n for item in elements_list:\n # Count the occurrences of the item in the tuple and add to the total count\n count += elements_tuple.count(item)\n \n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tup, lst):\n \"\"\"\n Counts the occurrence of all elements in lst within the tuple tup.\n\n Args:\n tup (tuple): The tuple in which to count occurrences.\n lst (list): The list of elements to count within the tuple.\n\n Returns:\n int: The total count of all elements from lst in tup.\n \"\"\"\n count = 0\n for item in lst:\n count += tup.count(item)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tpl, lst):\n \"\"\"\n Count the occurrences of each element in the list within the tuple.\n\n Parameters:\n tpl (tuple): The tuple of elements.\n lst (list): The list of elements to count within the tuple.\n\n Returns:\n int: The total count of occurrences of elements in lst within tpl.\n \"\"\"\n count = 0\n for item in lst:\n count += tpl.count(item)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tup, elements):\n \"\"\"\n Count the occurrences of specified elements from the list in the tuple.\n\n Parameters:\n tup (tuple): A tuple in which we want to count the occurrences.\n elements (list): A list of elements whose occurrences we want to count in the tuple.\n\n Returns:\n int: Total count of all specified elements found in the tuple.\n \"\"\"\n count = 0\n for element in elements:\n count += tup.count(element)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tup, lst):\n \"\"\"\n Count the occurrence of each element in lst within the tuple tup.\n\n Args:\n tup (tuple): A tuple of elements.\n lst (list): A list of elements to count in the tuple.\n\n Returns:\n int: The total count of occurrences of the elements from the list within the tuple.\n \"\"\"\n # Initialize a counter\n count = 0\n\n # Iterate over each element in the list\n for item in lst:\n # Count the occurrences of item in the tuple and add to the counter\n count += tup.count(item)\n\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(input_tuple, elements_list):\n \"\"\"\n Count the occurrences of each element from elements_list in the input_tuple.\n\n Parameters:\n input_tuple (tuple): The tuple in which to count occurrences.\n elements_list (list): The list of elements whose occurrences to count.\n\n Returns:\n int: Total count of occurrences of the elements from elements_list in input_tuple.\n \"\"\"\n count = 0\n for element in elements_list:\n count += input_tuple.count(element)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tup, lst):\n \"\"\"\n Count the occurrence of all elements of the list in the tuple.\n\n Parameters:\n tup (tuple): A tuple of elements\n lst (list): A list of elements to count in the tuple\n\n Returns:\n int: The total count of the elements from the list present in the tuple\n \"\"\"\n count = 0\n for element in lst:\n count += tup.count(element)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tup, lst):\n \"\"\"\n Count the occurrence of all elements of the list in the tuple.\n\n Parameters:\n tup (tuple): The tuple to search.\n lst (list): The list of elements to count in the tuple.\n\n Returns:\n int: The total number of occurrences of elements of the list in the tuple.\n \"\"\"\n count = 0\n for element in lst:\n count += tup.count(element)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tup, lst):\n \"\"\"\n Counts the occurrences of each element in lst within the tuple tup.\n \n Parameters:\n tup (tuple): The tuple of elements to be searched.\n lst (list): The list of elements to count in the tuple.\n\n Returns:\n int: The total count of all occurrences of the list elements in the tuple.\n \"\"\"\n count = 0\n for item in lst:\n count += tup.count(item)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(input_tuple, input_list):\n \"\"\"\n Counts the occurrences of elements in the input_list within the input_tuple.\n\n Args:\n input_tuple (tuple): A tuple of elements to search within.\n input_list (list): A list of elements to count in the tuple.\n\n Returns:\n int: The total count of occurrences of input_list elements in the input_tuple.\n \"\"\"\n count = 0\n for item in input_list:\n count += input_tuple.count(item)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tup, lst):\n \"\"\"\n Count the occurrence of all elements of lst in tup.\n\n :param tup: A tuple of elements where the occurrences are counted.\n :param lst: A list of elements whose occurrences in tup are to be counted.\n :return: The total count of occurrences of elements of lst in tup.\n \"\"\"\n return sum(tup.count(item) for item in lst)", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(elements_tuple, elements_list):\n \"\"\"\n Count the occurrence of all elements of elements_list in elements_tuple.\n\n Parameters:\n elements_tuple (tuple): A tuple containing elements to be checked.\n elements_list (list): A list of elements whose occurrences need to be counted in the tuple.\n\n Returns:\n int: Total occurrences of all elements from elements_list in the elements_tuple.\n \"\"\"\n # Initialize a counter to zero\n count = 0\n \n # Iterate through each element in the elements_list\n for element in elements_list:\n # Count how many times the element appears in the elements_tuple and add to count\n count += elements_tuple.count(element)\n \n return count", "matching_cluster_idx": 2}]}, "Mbpp/451": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 34.0, "profiled": [{"solution": "def remove_whitespaces(input_string):\n \"\"\"\n Remove all whitespaces from the given string.\n \n Parameters:\n input_string (str): The string from which whitespaces will be removed.\n\n Returns:\n str: The input string with all whitespaces removed.\n \"\"\"\n # Use str.replace to remove all whitespace characters\n return input_string.replace(' ', '')", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string):\n # Use str.replace to remove all whitespace characters\n return input_string.replace(' ', '')", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(s: str) -> str:\n # Use str.replace() to remove all spaces\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(s):\n # Use the replace method to remove all spaces\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(s):\n \"\"\"\n Remove all whitespaces from the given string.\n\n Parameters:\n s (str): The input string from which whitespaces will be removed.\n\n Returns:\n str: A new string with all whitespaces removed.\n \"\"\"\n # Using str.replace to remove spaces\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(s: str) -> str:\n # Use the replace method to remove all whitespace characters\n return s.replace(' ', '')", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(s: str) -> str:\n # Use the replace method to remove all spaces\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(s: str) -> str:\n \"\"\"\n Remove all whitespaces from the given string.\n\n Args:\n s (str): The input string from which whitespaces should be removed.\n\n Returns:\n str: The string with all whitespaces removed.\n \"\"\"\n # Use the string's replace method to remove spaces\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(s: str) -> str:\n # Use the replace method to remove all spaces\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(s: str) -> str:\n \"\"\"\n Remove all whitespaces from the given string.\n\n :param s: The input string from which to remove whitespaces.\n :return: A new string with all whitespace characters removed.\n \"\"\"\n # Use the str.replace method to remove spaces\n return s.replace(' ', '')", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(s: str) -> str:\n # Use the `replace` method to remove all whitespaces\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string):\n \"\"\"\n Remove all whitespaces from the given string.\n \"\"\"\n # Using str.replace to remove all spaces\n return input_string.replace(' ', '')", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(s):\n \"\"\"\n Remove all whitespaces from the given string.\n \n Parameters:\n s (str): The input string from which whitespaces will be removed.\n\n Returns:\n str: The string with all whitespaces removed.\n \"\"\"\n # Use str.replace() method to remove whitespaces\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string):\n # Use the replace method to remove all spaces\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string):\n \"\"\"\n Removes all whitespaces from the given string.\n \n :param input_string: The string from which to remove whitespaces\n :return: A new string with all whitespaces removed\n \"\"\"\n # Use the replace method to remove spaces\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(s: str) -> str:\n \"\"\"Remove all whitespaces from the given string.\"\"\"\n # Use the string method replace to remove all spaces.\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(s: str) -> str:\n \"\"\"\n This function removes all whitespaces from the given string.\n \n :param s: The input string from which whitespaces are to be removed.\n :return: A new string with all the whitespaces removed.\n \"\"\"\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string):\n # Remove all whitespaces from the input string using the replace method\n return input_string.replace(' ', '')", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(s):\n \"\"\"\n Remove all whitespaces from the given string.\n\n Args:\n s (str): The input string.\n\n Returns:\n str: The string with all whitespaces removed.\n \"\"\"\n # Use str.replace to remove spaces\n return s.replace(' ', '')", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(s: str) -> str:\n # Using str.replace to remove all whitespaces\n return s.replace(' ', '')", "matching_cluster_idx": 4}]}, "Mbpp/456": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def reverse_string_list(strings):\n \"\"\"\n Reverses each string in the given list of string values.\n\n Args:\n strings (list): A list of strings to be reversed.\n\n Returns:\n list: A list containing each original string reversed.\n \"\"\"\n return [s[::-1] for s in strings]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n return [s[::-1] for s in string_list]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(strings):\n \"\"\"\n Reverses each string in the list of strings provided.\n\n Args:\n strings (list): A list of strings.\n\n Returns:\n list: A list containing each of the original strings reversed.\n \"\"\"\n return [s[::-1] for s in strings]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(strings):\n \"\"\"\n This function takes a list of strings and returns a new list with each string reversed.\n \n :param strings: List of strings to be reversed\n :return: A list of strings with each string reversed\n \"\"\"\n return [s[::-1] for s in strings]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(strings):\n \"\"\"\n Reverses each string in a given list of string values.\n\n Parameters:\n strings (list of str): A list of string values.\n\n Returns:\n list of str: A list with each string reversed.\n \"\"\"\n # Use a list comprehension to reverse each string in the list\n return [s[::-1] for s in strings]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n \"\"\"\n Reverse each string in the given list of strings.\n \n Parameters:\n string_list (list): A list of strings.\n \n Returns:\n list: A list of strings where each string is reversed.\n \"\"\"\n return [s[::-1] for s in string_list]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(strings):\n return [s[::-1] for s in strings]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(strings):\n return [s[::-1] for s in strings]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(strings):\n \"\"\"\n Given a list of strings, return a new list with each string reversed.\n \n Args:\n strings (list of str): A list of string values to be reversed.\n \n Returns:\n list of str: A list containing the reversed strings.\n \"\"\"\n return [s[::-1] for s in strings]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(strings):\n \"\"\"\n Reverse each string in a given list of strings.\n \n :param strings: A list of strings.\n :return: A list of strings with each string reversed.\n \"\"\"\n return [s[::-1] for s in strings]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(strings):\n \"\"\"\n This function takes a list of strings and returns a new list\n where each string is reversed.\n \n :param strings: List of strings to reverse\n :return: List of reversed strings\n \"\"\"\n return [s[::-1] for s in strings]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(strings):\n \"\"\"\n Given a list of string values, return a new list where each string is reversed.\n\n :param strings: List of strings to be reversed\n :return: List of reversed strings\n \"\"\"\n return [s[::-1] for s in strings]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(strings):\n \"\"\"\n Reverses each string in the given list of strings.\n\n Args:\n strings (list): A list of strings to be reversed.\n\n Returns:\n list: A list containing the reversed strings.\n \"\"\"\n return [s[::-1] for s in strings]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(strings):\n return [s[::-1] for s in strings]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(strings):\n # This function takes a list of strings and returns a new list\n # where each string is reversed.\n return [s[::-1] for s in strings]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n \"\"\"\n Reverse each string in the given list of string values.\n \n :param string_list: List of strings to be reversed\n :return: List of strings where each string is reversed\n \"\"\"\n return [s[::-1] for s in string_list]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(strings):\n \"\"\"\n Reverse each string in the provided list of strings.\n\n Parameters:\n strings (list of str): A list containing string values to be reversed.\n\n Returns:\n list of str: A list containing each string from the input list reversed.\n \"\"\"\n return [s[::-1] for s in strings]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(strings):\n \"\"\"Reverses each string in the provided list of strings.\"\"\"\n return [s[::-1] for s in strings]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(strings):\n \"\"\"\n Reverses each string in a given list of strings.\n \n :param strings: List of strings to be reversed.\n :return: A new list with each string reversed.\n \"\"\"\n return [s[::-1] for s in strings]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n return [s[::-1] for s in string_list]", "matching_cluster_idx": 4}]}, "Mbpp/460": {"dps": 51.00961538461538, "dps_norm": 80.0, "pass@1": 82.0, "profiled": [{"solution": "def Extract(list_of_lists):\n \"\"\"\n Extracts the first element of each sublist in the provided list of lists.\n\n Args:\n list_of_lists (list of lists): A list where each element is a list.\n\n Returns:\n list: A list containing the first element of each sublist.\n \"\"\"\n return [sublist[0] for sublist in list_of_lists]", "matching_cluster_idx": 3}, {"solution": "def Extract(lists):\n \"\"\"\n This function takes a list of lists and returns a list containing the first element of each sublist.\n \n :param lists: List of lists\n :return: A list containing the first element of each sublist\n \"\"\"\n return [sublist[0] for sublist in lists]", "matching_cluster_idx": 4}, {"solution": "def Extract(list_of_lists):\n \"\"\"\n This function takes a list of lists and returns a list containing\n the first element of each sublist.\n\n :param list_of_lists: List of lists from which to extract the first elements\n :return: A list containing the first element of each sublist\n \"\"\"\n return [sublist[0] for sublist in list_of_lists if sublist]", "matching_cluster_idx": 3}, {"solution": "def Extract(list_of_lists):\n \"\"\"\n This function takes a list of lists and returns a new list containing\n the first element of each sublist.\n \"\"\"\n # Use list comprehension to extract the first element from each sublist\n return [sublist[0] for sublist in list_of_lists]", "matching_cluster_idx": 3}, {"solution": "def Extract(list_of_lists):\n \"\"\"Returns the first element of each sublist in the input list of lists.\"\"\"\n return [sublist[0] for sublist in list_of_lists if sublist]", "matching_cluster_idx": 3}, {"solution": "def Extract(lists):\n \"\"\"Extract the first element of each sublist.\"\"\"\n return [sublist[0] for sublist in lists if sublist]", "matching_cluster_idx": 3}, {"solution": "def Extract(list_of_lists):\n \"\"\"\n This function takes a list of sublists and returns a list containing\n the first element of each sublist.\n \"\"\"\n return [sublist[0] for sublist in list_of_lists if sublist]", "matching_cluster_idx": 3}, {"solution": "def Extract(list_of_lists):\n \"\"\"\n This function takes a list of lists and returns a list containing\n the first element of each sublist.\n\n :param list_of_lists: List[List[Any]]\n :return: List[Any]\n \"\"\"\n return [sublist[0] for sublist in list_of_lists if sublist]", "matching_cluster_idx": 3}, {"solution": "def Extract(list_of_lists):\n \"\"\"\n This function takes a list of lists as input and returns a list\n containing the first element of each sublist.\n \n :param list_of_lists: List of lists\n :return: List of first elements of each sublist\n \"\"\"\n return [sublist[0] for sublist in list_of_lists if sublist]", "matching_cluster_idx": 3}, {"solution": "def Extract(list_of_lists):\n \"\"\"\n Returns a list containing the first element of each sublist in the input list_of_lists.\n \n :param list_of_lists: A list of lists from which to extract the first element of each sublist.\n :return: A list of first elements of each sublist.\n \"\"\"\n return [sublist[0] for sublist in list_of_lists if sublist]", "matching_cluster_idx": 3}, {"solution": "def Extract(lst):\n \"\"\"\n Given a list of lists, return a list containing the first element of each sublist.\n \n Parameters:\n lst (list): A list of sublists\n \n Returns:\n list: A list containing the first element of each sublist\n \"\"\"\n return [sublist[0] for sublist in lst if sublist]", "matching_cluster_idx": 3}, {"solution": "def Extract(list_of_lists):\n \"\"\"\n Extract the first element of each sublist.\n \n Args:\n list_of_lists (list of lists): A list containing sublists.\n \n Returns:\n list: A list containing the first element of each sublist.\n \"\"\"\n return [sublist[0] for sublist in list_of_lists if sublist]", "matching_cluster_idx": 3}, {"solution": "def Extract(lst):\n \"\"\"\n Extract the first element of each sublist in a list of lists.\n\n Parameters:\n lst (list of lists): A list containing sublists from which to extract the first element.\n\n Returns:\n list: A list containing the first element of each sublist.\n \"\"\"\n # Use a list comprehension to extract the first element from each sublist\n return [sublist[0] for sublist in lst if sublist] # Ensure sublist is not empty", "matching_cluster_idx": 3}, {"solution": "def Extract(lists):\n \"\"\"\n This function takes a list of lists and returns a list containing\n the first element of each sublist.\n \n Parameters:\n lists (list of lists): A list where each element is a list with at least one element.\n \n Returns:\n list: A list containing the first element of each sublist.\n \"\"\"\n return [sublist[0] for sublist in lists if sublist] # Ensure sublist is not empty", "matching_cluster_idx": 3}, {"solution": "def Extract(list_of_lists):\n # Use a list comprehension to get the first element of each sublist\n return [sublist[0] for sublist in list_of_lists]", "matching_cluster_idx": 3}, {"solution": "def Extract(list_of_lists):\n \"\"\"Returns the first element of each sublist.\"\"\"\n return [sublist[0] for sublist in list_of_lists if sublist]", "matching_cluster_idx": 3}, {"solution": "def Extract(lists):\n \"\"\"\n Given a list of lists, return a list containing the first element of each sublist.\n \"\"\"\n return [sublist[0] for sublist in lists if sublist]", "matching_cluster_idx": 3}, {"solution": "def Extract(list_of_lists):\n \"\"\"\n This function takes a list of lists and returns a list containing \n the first element of each sublist.\n\n :param list_of_lists: List of lists from which the first element of each sublist is extracted\n :return: List of first elements\n \"\"\"\n return [sublist[0] for sublist in list_of_lists]", "matching_cluster_idx": 3}, {"solution": "def Extract(lst):\n \"\"\"\n This function takes a list of lists and returns a list containing\n the first element of each sublist.\n \n :param lst: A list of lists.\n :return: A list containing the first element of each sublist.\n \"\"\"\n return [sublist[0] for sublist in lst]", "matching_cluster_idx": 4}, {"solution": "def Extract(list_of_sublists):\n # Ensure the input is a list of lists\n if not all(isinstance(sublist, list) for sublist in list_of_sublists):\n raise ValueError(\"Input must be a list of lists\")\n \n # Extract the first element of each sublist\n first_elements = [sublist[0] for sublist in list_of_sublists if sublist]\n\n return first_elements", "matching_cluster_idx": 1}]}, "Mbpp/474": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def replace_char(original_string, target_char, replacement_char):\n \"\"\"\n Replaces all occurrences of target_char in original_string with replacement_char.\n\n :param original_string: The string where replacement is to occur.\n :param target_char: The character to be replaced.\n :param replacement_char: The character to replace with.\n :return: A new string with the characters replaced.\n \"\"\"\n return original_string.replace(target_char, replacement_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, old_char, new_char):\n \"\"\"\n Replaces all occurrences of old_char with new_char in the string s.\n \n Parameters:\n s (str): The original string.\n old_char (str): The character to be replaced.\n new_char (str): The character to replace with.\n \n Returns:\n str: The modified string with the specified replacements.\n \"\"\"\n return s.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s: str, old: str, new: str) -> str:\n \"\"\"\n Replace all occurrences of the character `old` with the character `new` in the string `s`.\n \n :param s: The original string\n :param old: The character to replace\n :param new: The replacement character\n :return: A new string with the specified replacements\n \"\"\"\n # Use the built-in string method `replace` to replace occurrences\n return s.replace(old, new)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s: str, old: str, new: str) -> str:\n \"\"\"\n Replaces all occurrences of the character `old` with the character `new` in the string `s`.\n \n Parameters:\n s (str): The input string.\n old (str): The character to be replaced.\n new (str): The character to replace with.\n\n Returns:\n str: The resulting string after the replacement.\n \"\"\"\n return s.replace(old, new)", "matching_cluster_idx": 6}, {"solution": "def replace_char(original_string, old_char, new_char):\n \"\"\"\n Replaces all occurrences of old_char in original_string with new_char.\n \n :param original_string: The string in which replacement is to be done.\n :param old_char: The character to be replaced.\n :param new_char: The character to replace with.\n :return: A new string with all occurrences of old_char replaced by new_char.\n \"\"\"\n return original_string.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, old_char, new_char):\n \"\"\"\n Replaces all occurrences of old_char with new_char in the string s.\n\n Parameters:\n s (str): The original string.\n old_char (str): The character to be replaced.\n new_char (str): The character to replace with.\n\n Returns:\n str: The modified string with characters replaced.\n \"\"\"\n return s.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(input_string, target_char, replacement_char):\n \"\"\"\n Replace all occurrences of target_char in input_string with replacement_char.\n \n :param input_string: The original string.\n :param target_char: The character to replace.\n :param replacement_char: The character to replace with.\n :return: The modified string with all occurrences of target_char replaced by replacement_char.\n \"\"\"\n return input_string.replace(target_char, replacement_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(input_string, target_char, replacement_char):\n \"\"\"\n Replaces all occurrences of target_char in input_string with replacement_char.\n \n :param input_string: The string in which to replace characters.\n :param target_char: The character to be replaced.\n :param replacement_char: The character to replace with.\n :return: A new string with the specified replacements.\n \"\"\"\n return input_string.replace(target_char, replacement_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s: str, old_char: str, new_char: str) -> str:\n \"\"\"\n Replaces all occurrences of old_char with new_char in the string s.\n \n Parameters:\n s (str): The original string.\n old_char (str): The character to be replaced.\n new_char (str): The character to replace with.\n \n Returns:\n str: The modified string with old_char replaced by new_char.\n \"\"\"\n return s.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s: str, old_char: str, new_char: str) -> str:\n \"\"\"\n Replace all occurrences of old_char with new_char in the string s.\n\n :param s: The original string.\n :param old_char: The character to be replaced.\n :param new_char: The character to replace with.\n :return: A new string with all occurrences of old_char replaced by new_char.\n \"\"\"\n return s.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(original_str, old_char, new_char):\n \"\"\"\n Replaces all occurrences of old_char with new_char in the original_str.\n\n Parameters:\n - original_str (str): The string where replacement is to be made.\n - old_char (str): The character in the original_str to be replaced.\n - new_char (str): The character to replace old_char with.\n\n Returns:\n - str: A new string with the characters replaced.\n \"\"\"\n return original_str.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, old_char, new_char):\n \"\"\"\n Replace all occurrences of old_char with new_char in the string s.\n \n Parameters:\n - s (str): The original string.\n - old_char (str): The character to replace.\n - new_char (str): The character to replace with.\n \n Returns:\n - str: The modified string with characters replaced.\n \"\"\"\n return s.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, old_char, new_char):\n \"\"\"\n Replace occurrences of old_char with new_char in the string s.\n\n :param s: The original string\n :param old_char: The character to be replaced\n :param new_char: The character to replace with\n :return: A new string with the characters replaced\n \"\"\"\n return s.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(input_string, old_char, new_char):\n \"\"\"\n Replaces all occurrences of old_char in input_string with new_char.\n \n :param input_string: The string to process.\n :param old_char: The character to replace.\n :param new_char: The character to replace with.\n :return: A new string with the specified character replaced.\n \"\"\"\n return input_string.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, old_char, new_char):\n \"\"\"\n Replaces all occurrences of old_char with new_char in the string s.\n \n Args:\n s (str): The original string.\n old_char (str): The character to be replaced.\n new_char (str): The character to replace with.\n \n Returns:\n str: The modified string with old_char replaced by new_char.\n \"\"\"\n return s.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(original_string, old_char, new_char):\n \"\"\"\n Replace all occurrences of old_char with new_char in the original_string.\n\n Parameters:\n original_string (str): The string in which to perform replacements.\n old_char (str): The character to be replaced.\n new_char (str): The character to replace old_char with.\n\n Returns:\n str: A new string with all occurrences of old_char replaced by new_char.\n \"\"\"\n return original_string.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s: str, old: str, new: str) -> str:\n \"\"\"\n Replace all occurrences of the character 'old' with the character 'new' in the string 's'.\n \n Parameters:\n s (str): The input string.\n old (str): The character to be replaced.\n new (str): The character to replace with.\n \n Returns:\n str: The modified string with 'old' replaced by 'new'.\n \"\"\"\n return s.replace(old, new)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, old_char, new_char):\n \"\"\"\n Replaces all occurrences of old_char with new_char in the string s.\n \n :param s: The input string.\n :param old_char: The character to be replaced.\n :param new_char: The character to replace with.\n :return: A new string with the replaced characters.\n \"\"\"\n return s.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s: str, old: str, new: str) -> str:\n \"\"\"\n This function replaces all occurrences of the character 'old' with the character 'new' in the string 's'.\n\n :param s: The input string where replacements are to be made.\n :param old: The character in the string to replace.\n :param new: The character to replace 'old' with.\n :return: A new string with the characters replaced.\n \"\"\"\n return s.replace(old, new)", "matching_cluster_idx": 6}, {"solution": "def replace_char(input_str, old_char, new_char):\n \"\"\"\n Replaces occurrences of old_char in input_str with new_char.\n \n Parameters:\n input_str (str): The original string.\n old_char (str): The character to be replaced.\n new_char (str): The character to replace with.\n \n Returns:\n str: The modified string with old_char replaced by new_char.\n \"\"\"\n return input_str.replace(old_char, new_char)", "matching_cluster_idx": 6}]}, "Mbpp/476": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def big_sum(arr):\n \"\"\"\n This function returns the sum of the largest and smallest values in the given array.\n \n :param arr: List of integers\n :return: Integer, sum of the largest and smallest values\n \"\"\"\n if not arr:\n raise ValueError(\"Array must not be empty\")\n \n smallest = min(arr)\n largest = max(arr)\n \n return smallest + largest", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n \"\"\"\n This function takes a list of numbers and returns the sum\n of the largest and smallest number in the list.\n \n :param arr: List of numbers\n :return: Sum of the largest and smallest number\n \"\"\"\n if not arr:\n raise ValueError(\"The array should not be empty\")\n \n smallest = min(arr)\n largest = max(arr)\n \n return smallest + largest", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n \"\"\"\n Returns the sum of the largest and smallest values in the given array.\n\n :param arr: List of numbers\n :return: Sum of the largest and smallest numbers in the array\n \"\"\"\n if not arr:\n raise ValueError(\"Array cannot be empty\")\n \n min_value = min(arr)\n max_value = max(arr)\n return min_value + max_value", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n if not arr:\n raise ValueError(\"Array must not be empty\")\n smallest = min(arr)\n largest = max(arr)\n return smallest + largest", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n \"\"\"\n This function takes a list of numbers as input and returns the sum\n of the largest and smallest number in that list.\n \"\"\"\n if not arr:\n raise ValueError(\"Array should not be empty\")\n \n min_value = min(arr)\n max_value = max(arr)\n return min_value + max_value", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n \"\"\"\n This function takes a list of numbers and returns the sum of\n the largest and smallest numbers in the list.\n \"\"\"\n if not arr:\n raise ValueError(\"The array should not be empty.\")\n \n largest = max(arr)\n smallest = min(arr)\n return largest + smallest", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n \"\"\"\n Find the sum of the largest and smallest value in a given array.\n \n Parameters:\n arr (list of int): A list of integers.\n \n Returns:\n int: The sum of the largest and smallest integer in the list.\n \"\"\"\n if not arr:\n raise ValueError(\"Array must contain at least one element\")\n \n smallest = min(arr)\n largest = max(arr)\n return smallest + largest", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n \"\"\"\n Returns the sum of the largest and smallest values in the given array.\n :param arr: List of numbers\n :return: Sum of the largest and smallest numbers\n \"\"\"\n if not arr:\n raise ValueError(\"Array should not be empty.\")\n \n smallest = min(arr)\n largest = max(arr)\n return smallest + largest", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n if not arr:\n raise ValueError(\"Array cannot be empty\")\n smallest = min(arr)\n largest = max(arr)\n return smallest + largest", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n if not arr:\n return 0\n smallest = min(arr)\n largest = max(arr)\n return smallest + largest", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n if not arr: # Check if the array is empty\n raise ValueError(\"Array must not be empty\")\n min_val = min(arr)\n max_val = max(arr)\n return min_val + max_val", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n if not arr:\n raise ValueError(\"Array must not be empty.\")\n smallest = min(arr)\n largest = max(arr)\n return smallest + largest", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n if not arr: # Check if the list is empty\n return 0 # Return 0 or raise an exception if you prefer\n smallest = min(arr) # Find the smallest number in the list\n largest = max(arr) # Find the largest number in the list\n return smallest + largest # Return the sum of the smallest and largest numbers", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n \"\"\"\n This function takes a list of numbers and returns the sum of the largest\n and smallest numbers in the list.\n \"\"\"\n if not arr:\n raise ValueError(\"Array must not be empty\")\n largest = max(arr)\n smallest = min(arr)\n return largest + smallest", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n if not arr:\n raise ValueError(\"Array must not be empty\")\n smallest = min(arr)\n largest = max(arr)\n return smallest + largest", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n \"\"\"\n This function returns the sum of the largest and smallest values in a given array.\n \n :param arr: List of numbers\n :return: Sum of the largest and smallest numbers in the list\n \"\"\"\n if not arr:\n raise ValueError(\"Array must not be empty\")\n \n smallest = min(arr)\n largest = max(arr)\n return smallest + largest", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n \"\"\"\n This function returns the sum of the largest and smallest value in the given array.\n \"\"\"\n if not arr:\n raise ValueError(\"Array must not be empty\")\n \n smallest = min(arr)\n largest = max(arr)\n return smallest + largest", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n if not arr: # Check if the array is empty\n return 0 # Assuming sum should be 0 if the array is empty\n smallest = min(arr)\n largest = max(arr)\n return smallest + largest", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n if not arr:\n raise ValueError(\"Array should not be empty\")\n\n min_val = min(arr)\n max_val = max(arr)\n\n return min_val + max_val", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n if not arr:\n raise ValueError(\"Array must not be empty\")\n largest = max(arr)\n smallest = min(arr)\n return largest + smallest", "matching_cluster_idx": 5}]}, "Mbpp/477": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def is_lower(input_string):\n \"\"\"\n Converts the given string to lower case.\n \n Parameters:\n input_string (str): The string to be converted.\n\n Returns:\n str: The lowercased string.\n \"\"\"\n return input_string.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(input_string):\n \"\"\"\n Convert the given string to lower case.\n\n :param input_string: The string to convert.\n :return: The lower-cased string.\n \"\"\"\n return input_string.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(input_string):\n \"\"\"\n Convert the given string to lower case.\n \n Parameters:\n input_string (str): The string to be converted.\n \n Returns:\n str: The converted lower case string.\n \"\"\"\n return input_string.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(input_str):\n \"\"\"\n Convert the given string to lower case.\n \n Args:\n input_str (str): The string to convert.\n\n Returns:\n str: The lower case version of the input string.\n \"\"\"\n return input_str.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(input_string):\n \"\"\"\n Convert the given string to lower case.\n\n Parameters:\n input_string (str): The string to be converted.\n\n Returns:\n str: The input string converted to lower case.\n \"\"\"\n return input_string.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s: str) -> str:\n \"\"\"\n Convert the given string to lower case.\n \n Args:\n s (str): The string to be converted to lower case.\n \n Returns:\n str: The lower case version of the input string.\n \"\"\"\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s: str) -> str:\n \"\"\"\n Converts the given string to lower case.\n\n :param s: The string to be converted.\n :return: The lower-cased string.\n \"\"\"\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n \"\"\"\n Converts the given string to lower case.\n\n Args:\n s (str): The input string to convert.\n\n Returns:\n str: The lower case version of the input string.\n \"\"\"\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n \"\"\"\n Converts the given string to lowercase.\n\n Parameters:\n s (str): The string to convert.\n\n Returns:\n str: The lowercase version of the input string.\n \"\"\"\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s: str) -> str:\n \"\"\"\n Converts the given string to lower case.\n\n Parameters:\n s (str): The string to be converted.\n\n Returns:\n str: The lower-case version of the input string.\n \"\"\"\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n \"\"\"\n Convert the given string to lower case.\n \n Parameters:\n s (str): The string to convert.\n \n Returns:\n str: The lower case version of the input string.\n \"\"\"\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(input_string):\n \"\"\"\n Converts the given string to lower case.\n \n Parameters:\n input_string (str): The string to be converted to lower case.\n \n Returns:\n str: The input string converted to lower case.\n \"\"\"\n return input_string.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s: str) -> str:\n \"\"\"\n Converts the given string to lowercase.\n \n Parameters:\n s (str): The string to be converted to lowercase.\n \n Returns:\n str: The lowercase version of the input string.\n \"\"\"\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n \"\"\"\n Convert the given string to lower case.\n \n Parameters:\n s (str): The input string to be converted.\n \n Returns:\n str: The string converted to lower case.\n \"\"\"\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(input_string):\n \"\"\"\n Convert the given string to lowercase.\n\n :param input_string: A string to be converted.\n :return: The lowercase version of the input string.\n \"\"\"\n return input_string.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n \"\"\"\n Convert the given string to lower case.\n\n Parameters:\n s (str): The input string.\n\n Returns:\n str: The lowercase version of the input string.\n \"\"\"\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n \"\"\"\n Convert the given string to lower case.\n \n Args:\n s (str): The input string.\n \n Returns:\n str: The input string converted to lower case.\n \"\"\"\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n \"\"\"\n Convert the given string to lowercase.\n \n Parameters:\n s (str): The string to convert.\n \n Returns:\n str: The lowercase version of the input string.\n \"\"\"\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(input_string):\n \"\"\"\n Convert the given string to lower case.\n\n :param input_string: str - The string to be converted.\n :return: str - The converted string in lower case.\n \"\"\"\n return input_string.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n \"\"\"\n Convert the given string to lower case.\n\n :param s: The string to be converted.\n :return: The lower case version of the string.\n \"\"\"\n return s.lower()", "matching_cluster_idx": 4}]}, "Mbpp/563": {"dps": 85.24590163934427, "dps_norm": 81.81818181818181, "pass@1": 100.0, "profiled": [{"solution": "import re\ndef extract_values(s):\n \"\"\"\n Extracts values between quotation marks from a given string.\n \n Args:\n s (str): A string containing words enclosed in quotation marks.\n \n Returns:\n list: A list of strings extracted from the quotation marks.\n \"\"\"\n # Use regular expression to find all substrings within double quotes\n return re.findall(r'\"([^\"]*)\"', s)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(text):\n \"\"\"\n Extracts values between quotation marks from a string.\n\n Parameters:\n text (str): A string containing values enclosed in quotation marks.\n\n Returns:\n list: A list of values found between quotation marks.\n \"\"\"\n # Use regex to find all substrings enclosed in quotes\n return re.findall(r'\"(.*?)\"', text)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(s):\n \"\"\"\n Extracts values between quotation marks from a string.\n\n Args:\n s (str): The input string containing values in quotation marks.\n\n Returns:\n list: A list of values found between quotation marks.\n \"\"\"\n # Use regular expression to find all instances of quoted text\n return re.findall(r'\"(.*?)\"', s)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(s):\n \"\"\"\n Extracts values between quotation marks from the input string.\n\n Args:\n s (str): A string containing quoted values.\n\n Returns:\n list: A list of values found between quotation marks.\n \"\"\"\n # Using regular expression to find all occurrences of text within quotes\n return re.findall(r'\"(.*?)\"', s)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(s):\n \"\"\"\n Extracts values between quotation marks from a given string.\n\n Parameters:\n s (str): A string containing values enclosed in double quotation marks.\n\n Returns:\n list: A list of values extracted from the string, which were enclosed in double quotation marks.\n \"\"\"\n # Use regular expression to find all occurrences of text within double quotes\n return re.findall(r'\"(.*?)\"', s)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(s):\n # Use regular expression to find all text within double quotes\n return re.findall(r'\"(.*?)\"', s)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(text):\n # Use a regular expression to find text between quotes\n return re.findall(r'\"(.*?)\"', text)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(s):\n \"\"\"\n Extracts values between quotation marks from the input string `s`.\n \n Parameters:\n s (str): The input string containing quoted values.\n \n Returns:\n list: A list of values extracted from between quotation marks.\n \"\"\"\n # Use a regular expression to find text between double quotes\n return re.findall(r'\"(.*?)\"', s)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(s):\n \"\"\"\n Extract values between quotation marks from a string.\n\n Args:\n s (str): A string containing values enclosed in quotation marks.\n\n Returns:\n list: A list of values extracted from within the quotation marks.\n \"\"\"\n # Use regex to find all occurrences of strings between quotes\n return re.findall(r'\"(.*?)\"', s)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(s):\n \"\"\"\n Extract values between quotation marks from the input string.\n\n Args:\n s (str): The input string containing quoted values.\n\n Returns:\n list: A list of values extracted from between quotation marks.\n \"\"\"\n # Use regex to find all values inside double quotes\n return re.findall(r'\"(.*?)\"', s)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(s):\n # Use a regular expression to find all quoted strings\n matches = re.findall(r'\"(.*?)\"', s)\n return matches", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(input_string):\n # Use regular expression to find all patterns between double quotes\n return re.findall(r'\"(.*?)\"', input_string)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(s):\n # Use a regular expression to find all occurrences of quoted values\n return re.findall(r'\"(.*?)\"', s)", "matching_cluster_idx": 8}, {"solution": "def extract_values(s):\n import re\n # Using a regular expression to find all occurrences of text between quotation marks\n return re.findall(r'\"(.*?)\"', s)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(s):\n # Use regular expression to find all sequences enclosed in double quotes\n return re.findall(r'\"(.*?)\"', s)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(input_string):\n # Use regular expression to find all values between double quotation marks\n return re.findall(r'\"(.*?)\"', input_string)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(text):\n # Use regular expression to find all occurrences of text within quotes\n return re.findall(r'\"(.*?)\"', text)", "matching_cluster_idx": 8}, {"solution": "def extract_values(s):\n import re\n # Use a regular expression to find all text within double quotes\n pattern = r'\"(.*?)\"'\n matches = re.findall(pattern, s)\n return matches", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(s):\n # Use regular expression to find all substrings enclosed in double quotes\n return re.findall(r'\"([^\"]*)\"', s)", "matching_cluster_idx": 8}, {"solution": "def extract_values(s):\n import re\n # Use regular expression to find all occurrences of text between quotes\n return re.findall(r'\"(.*?)\"', s)", "matching_cluster_idx": 8}]}, "Mbpp/572": {"dps": 96.79012345679013, "dps_norm": 90.71428571428571, "pass@1": 100.0, "profiled": [{"solution": "def two_unique_nums(nums):\n from collections import Counter\n # Count the frequency of each number in the list\n num_counts = Counter(nums)\n # Return a list of numbers that appear exactly once\n return [num for num, count in num_counts.items() if count == 1]", "matching_cluster_idx": 6}, {"solution": "def two_unique_nums(lst):\n \"\"\"\n This function takes a list of integers and returns a new list containing only\n the numbers that appear exactly once in the given list.\n \"\"\"\n # Create a dictionary to count the occurrences of each number\n count_dict = {}\n \n for num in lst:\n if num in count_dict:\n count_dict[num] += 1\n else:\n count_dict[num] = 1\n \n # Return a list of numbers that appear exactly once\n return [num for num in lst if count_dict[num] == 1]", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(nums):\n \"\"\"\n Function to remove numbers that have duplicates from a given list and return numbers that are unique.\n \n Args:\n nums (list): A list of numbers.\n \n Returns:\n list: A list containing only the numbers that are unique in the input list.\n \"\"\"\n from collections import Counter\n \n # Create a counter for the list to count occurrences of each number\n num_counts = Counter(nums)\n \n # Return a list of numbers that appear exactly once in the list\n return [num for num in nums if num_counts[num] == 1]", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(num_list):\n \"\"\"\n Remove numbers that appear more than once in the list, leaving only the unique ones.\n\n :param num_list: List of integers.\n :return: A list containing only the unique numbers.\n \"\"\"\n # Create a dictionary to count the occurrences of each number\n count_dict = {}\n \n # Count each number's occurrences\n for num in num_list:\n if num in count_dict:\n count_dict[num] += 1\n else:\n count_dict[num] = 1\n \n # Collect numbers that appear exactly once\n unique_nums = [num for num, count in count_dict.items() if count == 1]\n \n return unique_nums", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(nums):\n \"\"\"\n Removes numbers that appear more than once in the list.\n \n Parameters:\n nums (list): A list of integers.\n \n Returns:\n list: A list containing only the numbers that appeared exactly once in the input list.\n \"\"\"\n from collections import Counter\n \n # Count occurrences of each number\n num_counts = Counter(nums)\n \n # Create a list of numbers that appear exactly once\n unique_nums = [num for num, count in num_counts.items() if count == 1]\n \n return unique_nums", "matching_cluster_idx": 6}, {"solution": "def two_unique_nums(nums):\n from collections import Counter\n \n # Create a counter to count occurrences of each number\n count = Counter(nums)\n \n # Filter numbers that appear exactly once\n unique_nums = [num for num in nums if count[num] == 1]\n \n return unique_nums", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(lst):\n from collections import Counter\n\n # Count the occurrences of each number\n counts = Counter(lst)\n \n # Filter the list to include only numbers that appear exactly once\n unique_nums = [num for num in lst if counts[num] == 1]\n\n return unique_nums", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(nums):\n # Dictionary to count occurrences of each number\n counts = {}\n\n # Count the occurrences of each number in the list\n for num in nums:\n if num in counts:\n counts[num] += 1\n else:\n counts[num] = 1\n \n # Collect numbers that occur only once\n unique_nums = [num for num, count in counts.items() if count == 1]\n \n return unique_nums", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(nums):\n # Create a dictionary to count occurrences of each number\n count_dict = {}\n \n for num in nums:\n if num in count_dict:\n count_dict[num] += 1\n else:\n count_dict[num] = 1\n \n # Filter out numbers that appear more than once\n unique_nums = [num for num, count in count_dict.items() if count == 1]\n \n return unique_nums", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(numbers):\n from collections import Counter\n \n # Count the occurrences of each number\n counts = Counter(numbers)\n \n # Only keep numbers that appear exactly once\n unique_numbers = [num for num, count in counts.items() if count == 1]\n \n return unique_numbers", "matching_cluster_idx": 6}, {"solution": "def two_unique_nums(lst):\n # Count the occurrences of each number in the list\n count = {}\n for num in lst:\n if num in count:\n count[num] += 1\n else:\n count[num] = 1\n \n # Collect numbers that occur exactly once\n unique_nums = [num for num, cnt in count.items() if cnt == 1]\n return unique_nums", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(lst):\n from collections import Counter\n\n # Count the occurrences of each number in the list\n count = Counter(lst)\n\n # Return a list of numbers that appear only once\n return [num for num, cnt in count.items() if cnt == 1]", "matching_cluster_idx": 6}, {"solution": "def two_unique_nums(lst):\n \"\"\"\n This function takes a list of numbers and returns a list of numbers that appear exactly once.\n \"\"\"\n from collections import Counter\n\n # Count the occurrences of each number in the list\n count = Counter(lst)\n \n # Filter out numbers that appear only once\n unique_nums = [num for num, cnt in count.items() if cnt == 1]\n\n return unique_nums", "matching_cluster_idx": 6}, {"solution": "def two_unique_nums(nums):\n \"\"\"\n This function returns a list containing only the numbers that appear exactly once in the input list.\n \n :param nums: List of integers\n :return: List of integers that appear exactly once in nums\n \"\"\"\n from collections import Counter\n \n # Count occurrences of each number\n count = Counter(nums)\n \n # Filter the numbers that appear exactly once\n unique_nums = [num for num, cnt in count.items() if cnt == 1]\n \n return unique_nums\nnums = [1, 2, 3, 2, 3, 4, 5]", "matching_cluster_idx": 6}, {"solution": "def two_unique_nums(nums):\n # Dictionary to keep count of each number in the list\n num_counts = {}\n \n # Count the occurrence of each number\n for num in nums:\n if num in num_counts:\n num_counts[num] += 1\n else:\n num_counts[num] = 1\n \n # Collect numbers that appear exactly once\n unique_nums = [num for num, count in num_counts.items() if count == 1]\n \n return unique_nums", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(lst):\n \"\"\"\n Removes numbers from the list that appear more than once.\n \n Parameters:\n lst (list): A list of numbers.\n \n Returns:\n list: A list with only numbers that appear exactly once in the input list.\n \"\"\"\n from collections import Counter\n \n # Count the occurrences of each number in the list\n count = Counter(lst)\n \n # Filter and return only the numbers that appear exactly once\n return [num for num in lst if count[num] == 1]", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(lst):\n \"\"\"\n This function takes a list of numbers and returns a list of numbers\n that appear exactly once in the input list.\n \"\"\"\n from collections import Counter\n\n # Count the frequency of each number in the list\n count = Counter(lst)\n\n # Create a new list containing only the numbers that appear exactly once\n unique_nums = [num for num, freq in count.items() if freq == 1]\n\n return unique_nums", "matching_cluster_idx": 6}, {"solution": "def two_unique_nums(numbers):\n \"\"\"\n Function to remove duplicate numbers from the given list, returning only\n the numbers that appear exactly once.\n \n :param numbers: List of integers\n :return: List of integers with only unique numbers\n \"\"\"\n # Create a dictionary to count occurrences of each number\n num_counts = {}\n \n for num in numbers:\n if num in num_counts:\n num_counts[num] += 1\n else:\n num_counts[num] = 1\n \n # Collect numbers that appear exactly once\n unique_numbers = [num for num, count in num_counts.items() if count == 1]\n \n return unique_numbers", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(lst):\n # Create a dictionary to count occurrences of each number\n count_dict = {}\n \n for num in lst:\n if num in count_dict:\n count_dict[num] += 1\n else:\n count_dict[num] = 1\n \n # Collect numbers that appear exactly once\n unique_nums = [num for num, count in count_dict.items() if count == 1]\n \n return unique_nums", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(numbers):\n # Create a dictionary to count occurrences of each number\n count = {}\n for number in numbers:\n if number in count:\n count[number] += 1\n else:\n count[number] = 1\n \n # Collect numbers that occur exactly once\n unique_numbers = [number for number in numbers if count[number] == 1]\n \n return unique_numbers", "matching_cluster_idx": 5}]}, "Mbpp/578": {"dps": 81.46031746031746, "dps_norm": 69.0909090909091, "pass@1": 100.0, "profiled": [{"solution": "def interleave_lists(list1, list2, list3):\n # Check if all lists have the same length\n if len(list1) != len(list2) or len(list2) != len(list3):\n raise ValueError(\"All lists must have the same length\")\n \n # Interleave the lists\n interleaved_list = []\n for i in range(len(list1)):\n interleaved_list.append(list1[i])\n interleaved_list.append(list2[i])\n interleaved_list.append(list3[i])\n \n return interleaved_list", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"\n Interleave three lists of the same length into a single flat list.\n \n Args:\n list1, list2, list3: Three lists to interleave. Must be of the same length.\n \n Returns:\n A flat list with elements from list1, list2, and list3 interleaved.\n \"\"\"\n if not (len(list1) == len(list2) == len(list3)):\n raise ValueError(\"All lists must be of the same length\")\n \n interleaved = []\n for i in range(len(list1)):\n interleaved.append(list1[i])\n interleaved.append(list2[i])\n interleaved.append(list3[i])\n \n return interleaved", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"Interleave three lists of the same length into a single flat list.\"\"\"\n interleaved_list = []\n for a, b, c in zip(list1, list2, list3):\n interleaved_list.extend([a, b, c])\n return interleaved_list", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"Interleave three lists of the same length into a single flat list.\"\"\"\n if not (len(list1) == len(list2) == len(list3)):\n raise ValueError(\"All lists must be of the same length.\")\n \n interleaved_list = []\n for i in range(len(list1)):\n interleaved_list.append(list1[i])\n interleaved_list.append(list2[i])\n interleaved_list.append(list3[i])\n \n return interleaved_list", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n # Check if all lists have the same length\n if len(list1) != len(list2) or len(list2) != len(list3):\n raise ValueError(\"All lists must have the same length\")\n\n # Create an empty list to store the interleaved elements\n interleaved_list = []\n\n # Iterate over the indices of the lists\n for i in range(len(list1)):\n # Append elements from each list in the order\n interleaved_list.append(list1[i])\n interleaved_list.append(list2[i])\n interleaved_list.append(list3[i])\n\n return interleaved_list", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"\n Interleave three lists of the same length into a single flat list.\n \n Args:\n list1 (list): The first list.\n list2 (list): The second list.\n list3 (list): The third list.\n \n Returns:\n list: A single flat list with elements interleaved from list1, list2, and list3.\n \"\"\"\n interleaved = []\n for i in range(len(list1)):\n interleaved.append(list1[i])\n interleaved.append(list2[i])\n interleaved.append(list3[i])\n return interleaved", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"\n Interleave three lists of the same length into a single flat list.\n \"\"\"\n # Check if the lists are of the same length\n if not (len(list1) == len(list2) == len(list3)):\n raise ValueError(\"All lists must have the same length.\")\n\n # Use a list comprehension to interleave the lists\n interleaved_list = [item for trio in zip(list1, list2, list3) for item in trio]\n\n return interleaved_list", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"\n Interleaves three lists of the same length into a single flat list.\n\n Args:\n - list1: First list to interleave.\n - list2: Second list to interleave.\n - list3: Third list to interleave.\n\n Returns:\n A flat list interleaving the elements of list1, list2, and list3.\n \"\"\"\n # Use list comprehension and zip to interleave the lists\n interleaved = [element for triple in zip(list1, list2, list3) for element in triple]\n return interleaved", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"\n Interleave three lists of the same length into a single flat list.\n \n Parameters:\n - list1: List of elements\n - list2: List of elements\n - list3: List of elements\n \n Returns:\n - A single list with elements from list1, list2, and list3 interleaved.\n \"\"\"\n if len(list1) != len(list2) or len(list2) != len(list3):\n raise ValueError(\"All lists must be of the same length.\")\n \n interleaved_list = []\n \n # Iterate over the indices of the lists\n for i in range(len(list1)):\n # Append one element from each list in sequence\n interleaved_list.append(list1[i])\n interleaved_list.append(list2[i])\n interleaved_list.append(list3[i])\n \n return interleaved_list", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"Interleave three lists of the same length into a single flat list.\"\"\"\n interleaved_list = []\n for a, b, c in zip(list1, list2, list3):\n interleaved_list.extend([a, b, c])\n return interleaved_list", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"Interleave three lists of the same length into a single flat list.\"\"\"\n interleaved_list = []\n for a, b, c in zip(list1, list2, list3):\n interleaved_list.extend([a, b, c])\n return interleaved_list", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"Interleaves three lists of the same length into a single flat list.\"\"\"\n interleaved_list = []\n for a, b, c in zip(list1, list2, list3):\n interleaved_list.extend([a, b, c])\n return interleaved_list", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"\n Interleave three lists of the same length into a single flat list.\n \"\"\"\n interleaved_list = []\n for a, b, c in zip(list1, list2, list3):\n interleaved_list.extend([a, b, c])\n return interleaved_list", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"\n Interleave three lists of the same length into a single flat list.\n \n :param list1: First list\n :param list2: Second list\n :param list3: Third list\n :return: A single flat list interleaving the input lists\n \"\"\"\n interleaved_list = []\n \n for a, b, c in zip(list1, list2, list3):\n interleaved_list.extend([a, b, c])\n \n return interleaved_list", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"\n This function interleaves three lists of the same length into a single flat list.\n \n Parameters:\n list1, list2, list3: Lists of the same length to be interleaved.\n\n Returns:\n A single list containing the interleaved elements of the three input lists.\n \"\"\"\n if len(list1) != len(list2) or len(list2) != len(list3):\n raise ValueError(\"All input lists must have the same length.\")\n \n # Interleaving the lists\n interleaved_list = []\n for a, b, c in zip(list1, list2, list3):\n interleaved_list.extend([a, b, c])\n \n return interleaved_list", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(list1, list2, list3):\n if len(list1) != len(list2) or len(list2) != len(list3):\n raise ValueError(\"All lists must have the same length.\")\n \n interleaved_list = []\n for i in range(len(list1)):\n interleaved_list.append(list1[i])\n interleaved_list.append(list2[i])\n interleaved_list.append(list3[i])\n \n return interleaved_list", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"\n Interleave three lists of the same length into a single flat list.\n\n Args:\n list1 (list): The first list to interleave.\n list2 (list): The second list to interleave.\n list3 (list): The third list to interleave.\n\n Returns:\n list: A list containing elements from list1, list2, and list3 interleaved.\n \"\"\"\n if not (len(list1) == len(list2) == len(list3)):\n raise ValueError(\"All lists must be of the same length.\")\n \n interleaved_list = []\n for a, b, c in zip(list1, list2, list3):\n interleaved_list.extend([a, b, c])\n \n return interleaved_list", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"\n Interleaves three lists of the same length into a single flat list.\n\n Parameters:\n list1, list2, list3: Lists of the same length to be interleaved.\n\n Returns:\n A single flat list where the elements are interleaved from the three lists.\n \"\"\"\n if not (len(list1) == len(list2) == len(list3)):\n raise ValueError(\"All lists must have the same length\")\n\n interleaved_list = []\n for a, b, c in zip(list1, list2, list3):\n interleaved_list.extend([a, b, c])\n\n return interleaved_list\nlist1 = [1, 2, 3, 4, 5, 6, 7]\nlist2 = [10, 20, 30, 40, 50, 60, 70]\nlist3 = [100, 200, 300, 400, 500, 600, 700]", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"\n Interleave three lists of the same length into a single flat list.\n \n Args:\n list1, list2, list3: Three lists of the same length to be interleaved.\n \n Returns:\n A single flat list with the elements of the input lists interleaved.\n \"\"\"\n interleaved_list = []\n for a, b, c in zip(list1, list2, list3):\n interleaved_list.extend([a, b, c])\n return interleaved_list", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"Interleaves three lists of the same length into a single flat list.\"\"\"\n interleaved_list = []\n # Iterate over the lists and append elements in the interleaved order.\n for i in range(len(list1)):\n interleaved_list.append(list1[i])\n interleaved_list.append(list2[i])\n interleaved_list.append(list3[i])\n return interleaved_list", "matching_cluster_idx": 6}]}, "Mbpp/586": {"dps": 98.83040935672514, "dps_norm": 87.5, "pass@1": 87.0, "profiled": [{"solution": "def split_Arr(arr, n):\n \"\"\"\n Splits a list at the nth element and moves the first part to the end.\n\n Parameters:\n arr (list): The list to be split and rearranged.\n n (int): The index at which to split the list.\n\n Returns:\n list: A new list with the elements rearranged.\n \"\"\"\n # Ensure n is within the bounds of the array\n if n < 0 or n > len(arr):\n raise ValueError(\"n must be within the index range of the list\")\n\n # Split the list at the nth element\n first_part = arr[:n]\n second_part = arr[n:]\n \n # Concatenate the second part with the first part moved to the end\n result = second_part + first_part\n return result", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n # Split the list at the nth element\n first_part = arr[:n]\n second_part = arr[n:]\n \n # Concatenate the second part with the first part\n result = second_part + first_part\n return result", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"\n Splits a list at the nth element and appends the first part to the end.\n\n Parameters:\n arr (list): The list to split and rearrange.\n n (int): The index at which to split the list.\n\n Returns:\n list: The rearranged list with the first part appended to the end.\n \"\"\"\n # Check if the input list is not empty and n is within a valid range\n if arr and 0 <= n < len(arr):\n # Split the array and rearrange\n return arr[n:] + arr[:n]\n else:\n # If the input is invalid, return the original array unchanged\n return arr", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"\n Split the array at the nth element and add the first part to the end.\n\n :param arr: List of elements to be split\n :param n: Index at which to split the list\n :return: New list with the first part added to the end\n \"\"\"\n # Split the list into two parts\n first_part = arr[:n]\n second_part = arr[n:]\n \n # Concatenate the second part with the first part at the end\n result = second_part + first_part\n return result\nresult = split_Arr([12, 10, 5, 6, 52, 36], 2)", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"\n Splits a list at the nth element and moves the first part to the end.\n\n Parameters:\n arr (list): The list to be split.\n n (int): The index at which to split the list.\n\n Returns:\n list: The modified list after splitting and moving.\n \"\"\"\n if n < 0 or n > len(arr):\n raise ValueError(\"n should be a valid index within the list bounds.\")\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"\n This function splits a list at the nth element and adds the first part to the end.\n \n Parameters:\n arr (list): The input list to be split and rearranged.\n n (int): The index at which to split the list.\n\n Returns:\n list: A new list with the first part moved to the end.\n \"\"\"\n # Split the array into two parts: from n onwards and from start to n\n first_part = arr[:n]\n second_part = arr[n:]\n \n # Concatenate the two parts with the first part at the end\n result = second_part + first_part\n return result", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"\n Splits the list at the nth element and appends the first part to the end.\n\n Parameters:\n arr (list): The list to be split.\n n (int): The index at which to split the list.\n\n Returns:\n list: The rearranged list.\n \"\"\"\n # Split the list into two parts: from 0 to n and from n to the end\n first_part = arr[:n]\n second_part = arr[n:]\n \n # Concatenate the second part with the first part and return the result\n return second_part + first_part", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"\n This function splits the list 'arr' at the nth element\n and appends the first part to the end.\n \"\"\"\n # Split the list into two parts: from 0 to n and from n to end\n part1 = arr[:n]\n part2 = arr[n:]\n # Concatenate the two parts by putting part1 at the end\n result = part2 + part1\n return result", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"\n This function splits the list `arr` at the `n`th index and appends the first part to the end.\n \"\"\"\n if n < 0 or n > len(arr):\n raise ValueError(\"n is out of the allowed range (0 to len(arr)).\")\n\n # Split the array at the nth element\n first_part = arr[:n]\n second_part = arr[n:]\n \n # Concatenate the second part with the first part\n result = second_part + first_part\n \n return result", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"\n Splits a list at the nth element and appends the first part to the end.\n\n Parameters:\n arr (list): The list to be split.\n n (int): The index at which to split the list.\n\n Returns:\n list: The modified list with the first part appended to the end.\n \"\"\"\n # Split the list into two parts: first part is from start to n, second part is from n to end.\n first_part = arr[:n]\n second_part = arr[n:]\n \n # Return the concatenation of the second part followed by the first part.\n return second_part + first_part", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"\n Splits the input list `arr` at the nth element and adds the first part to the end.\n\n :param arr: List of elements to be split and rearranged.\n :param n: The index at which to split the list.\n :return: A new list with elements rearranged.\n \"\"\"\n # Split the list into two parts at index n\n first_part = arr[:n]\n second_part = arr[n:]\n \n # Concatenate second_part with first_part and return the result\n return second_part + first_part", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"\n Splits the list `arr` at the nth element and appends the first part to the end.\n \n Parameters:\n arr (list): The input list to be split.\n n (int): The position at which to split the list.\n\n Returns:\n list: The modified list with the first part moved to the end.\n \"\"\"\n # Split the array into two parts\n first_part = arr[:n]\n second_part = arr[n:]\n \n # Combine the second part with the first part at the end\n result = second_part + first_part\n \n return result", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"\n Splits the list at the nth element and moves the first part to the end.\n\n Parameters:\n arr (list): The input list to be split and rearranged.\n n (int): The index at which to split the list.\n\n Returns:\n list: The rearranged list with the first part moved to the end.\n \"\"\"\n # Check if n is within the valid range\n if n < 0 or n > len(arr):\n raise ValueError(\"n must be within the range of the list length.\")\n\n # Split the list at the nth element\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"\n Splits the list at the nth element and moves the first part to the end.\n \n :param arr: List of elements to be split and rearranged\n :param n: Position to split the list at\n :return: Rearranged list with first n elements moved to the end\n \"\"\"\n if n < 0 or n > len(arr):\n raise ValueError(\"n must be within the range of the list length\")\n \n # Split the list at the nth element\n first_part = arr[:n]\n second_part = arr[n:]\n \n # Concatenate the second part with the first part\n result = second_part + first_part\n return result", "matching_cluster_idx": 6}, {"solution": "def split_Arr(lst, n):\n \"\"\"\n Splits the list `lst` at the nth element and adds the first part to the end.\n\n :param lst: List of elements to be split and rearranged.\n :param n: Index at which to split the list.\n :return: A new list where the elements from 0 to n-1 are moved to the end.\n \"\"\"\n # Validate n is within the bounds of the list\n if not (0 <= n <= len(lst)):\n raise ValueError(\"n must be between 0 and the length of the list (inclusive).\")\n \n # Split and rearrange the list\n first_part = lst[:n]\n second_part = lst[n:]\n \n # Return the rearranged list\n return second_part + first_part", "matching_cluster_idx": 6}, {"solution": "def split_Arr(lst, n):\n \"\"\"\n Splits the list lst at the nth element and appends the first part to the end.\n \n Parameters:\n lst (list): The list to be split.\n n (int): The position at which to split the list.\n \n Returns:\n list: The list with the first part moved to the end.\n \"\"\"\n return lst[n:] + lst[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"\n Splits the list `arr` at the nth element and appends the first part to the end.\n :param arr: List to be split.\n :param n: Index at which to split the list.\n :return: New list with the split performed.\n \"\"\"\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"\n Splits the list `arr` at index `n` and appends the first part to the end.\n \n Parameters:\n arr (list): The list to be split.\n n (int): The index at which to split the list.\n \n Returns:\n list: A new list where the elements after `n` are followed by the first `n` elements.\n \"\"\"\n if n < 0 or n > len(arr):\n raise ValueError(\"The split index 'n' is out of bounds for the list.\")\n \n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"\n Split the list 'arr' at the 'nth' element and append the first part to the end.\n \n Parameters:\n arr (list): The list to be split.\n n (int): The index at which to split the list.\n \n Returns:\n list: The rearranged list with the first part appended to the end.\n \"\"\"\n if n < 0 or n > len(arr):\n raise ValueError(\"n should be a valid index within the list.\")\n\n # Split the array at the nth index\n first_part = arr[:n]\n second_part = arr[n:]\n \n # Combine the two parts with the first part at the end\n return second_part + first_part", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"\n Splits the input list 'arr' at the nth element and moves the first part\n to the end of the list. Returns the modified list.\n \n Parameters:\n arr (list): The input list to be split.\n n (int): The position at which to split the list.\n \n Returns:\n list: The rearranged list with the first 'n' elements moved to the end.\n \"\"\"\n # Split the list into two parts\n first_part = arr[:n]\n second_part = arr[n:]\n \n # Concatenate second part with first part\n return second_part + first_part", "matching_cluster_idx": 6}]}, "Mbpp/587": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 81.0, "profiled": [{"solution": "def list_tuple(lst):\n \"\"\"\n Converts a list to a tuple.\n\n :param lst: List of elements.\n :return: Tuple containing the elements of the list.\n \"\"\"\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(input_list):\n \"\"\"\n Convert a list to a tuple.\n\n Parameters:\n input_list (list): The list to convert to a tuple.\n\n Returns:\n tuple: The converted tuple.\n \"\"\"\n return tuple(input_list)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n \"\"\"\n Convert a list to a tuple.\n\n Parameters:\n lst (list): The list to be converted.\n\n Returns:\n tuple: A tuple with the same elements as the input list.\n \"\"\"\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n \"\"\"\n Convert a list to a tuple.\n\n Parameters:\n lst (list): The list to be converted.\n\n Returns:\n tuple: The converted tuple.\n \"\"\"\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n \"\"\"\n Converts a list to a tuple.\n\n Parameters:\n lst (list): A list of elements.\n\n Returns:\n tuple: A tuple containing the elements of the list.\n \"\"\"\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n \"\"\"\n Convert a list to a tuple.\n\n Parameters:\n lst (list): A list of elements.\n\n Returns:\n tuple: A tuple containing the elements of the list.\n \"\"\"\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(input_list):\n \"\"\"\n Convert a list to a tuple.\n \n Args:\n input_list (list): A list of elements.\n \n Returns:\n tuple: A tuple containing the elements of the input list.\n \"\"\"\n return tuple(input_list)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n \"\"\"\n Converts a list to a tuple.\n \n Parameters:\n lst (list): The list to convert.\n \n Returns:\n tuple: The converted tuple.\n \"\"\"\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(input_list):\n \"\"\"\n Convert a list to a tuple.\n \n Args:\n input_list (list): The list to be converted to a tuple.\n \n Returns:\n tuple: The converted tuple.\n \"\"\"\n return tuple(input_list)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n \"\"\"\n Convert a list to a tuple.\n \n Parameters:\n lst (list): The list to be converted.\n \n Returns:\n tuple: The converted tuple.\n \"\"\"\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n \"\"\"\n Convert a list to a tuple.\n\n Parameters:\n lst (list): The list to convert.\n\n Returns:\n tuple: The converted tuple.\n \"\"\"\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(input_list):\n \"\"\"\n Convert a list to a tuple.\n\n Args:\n input_list (list): A list of elements.\n\n Returns:\n tuple: A tuple containing the elements of the input list.\n \"\"\"\n return tuple(input_list)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(input_list):\n \"\"\"\n Convert a list to a tuple.\n\n Parameters:\n input_list (list): A list to be converted into a tuple.\n\n Returns:\n tuple: A tuple containing the elements of the input list.\n \"\"\"\n return tuple(input_list)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n \"\"\"\n Convert a list to a tuple.\n \n Args:\n lst: list of elements to be converted to a tuple.\n\n Returns:\n Tuple containing all the elements of the list.\n \"\"\"\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n \"\"\"\n Converts a list to a tuple.\n\n Parameters:\n lst (list): The list to be converted to a tuple.\n\n Returns:\n tuple: The converted tuple.\n \"\"\"\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(input_list):\n \"\"\"\n Convert a list to a tuple.\n\n Parameters:\n input_list (list): The list to be converted.\n\n Returns:\n tuple: The converted tuple.\n \"\"\"\n return tuple(input_list)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(input_list):\n \"\"\"\n Convert a list to a tuple.\n \n Parameters:\n input_list (list): The list to be converted into a tuple.\n \n Returns:\n tuple: The converted tuple.\n \"\"\"\n return tuple(input_list)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(input_list):\n \"\"\"\n Converts a list to a tuple.\n\n Parameters:\n input_list (list): The list to convert.\n\n Returns:\n tuple: The converted tuple.\n \"\"\"\n return tuple(input_list)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n \"\"\"Convert a list to a tuple.\"\"\"\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(input_list):\n \"\"\"\n Convert a list to a tuple.\n\n Parameters:\n input_list (list): The list to be converted.\n\n Returns:\n tuple: The tuple converted from the list.\n \"\"\"\n return tuple(input_list)", "matching_cluster_idx": 3}]}, "Mbpp/588": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def big_diff(nums):\n \"\"\"\n Returns the difference between the largest and smallest values in the list nums.\n \"\"\"\n if not nums: # Check if the list is empty\n raise ValueError(\"The list is empty.\")\n \n max_val = max(nums)\n min_val = min(nums)\n \n return max_val - min_val", "matching_cluster_idx": 5}, {"solution": "def big_diff(lst):\n \"\"\"\n Function to find the difference between the largest and smallest value in a given list.\n \n :param lst: List of numbers\n :return: Difference between the largest and smallest numbers\n \"\"\"\n if not lst:\n raise ValueError(\"List should not be empty\")\n \n largest = max(lst)\n smallest = min(lst)\n \n return largest - smallest", "matching_cluster_idx": 5}, {"solution": "def big_diff(numbers):\n \"\"\"\n Calculate the difference between the largest and smallest values in a list.\n \n Parameters:\n numbers (list): A list of integers or floats.\n \n Returns:\n int or float: The difference between the largest and smallest numbers in the list.\n \"\"\"\n if not numbers:\n raise ValueError(\"List must not be empty\")\n \n max_value = max(numbers)\n min_value = min(numbers)\n return max_value - min_value", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n \"\"\"\n This function takes a list of numbers and returns the difference between the largest and smallest number.\n\n :param nums: List[int] - a list of integers\n :return: int - the difference between the largest and smallest integer in the list\n \"\"\"\n if not nums:\n raise ValueError(\"List must not be empty\")\n \n max_num = max(nums)\n min_num = min(nums)\n \n return max_num - min_num", "matching_cluster_idx": 5}, {"solution": "def big_diff(numbers):\n \"\"\"\n Return the difference between the largest and smallest value in the given list.\n \n :param numbers: List of integers\n :return: Integer, the difference between the max and min value in the list\n \"\"\"\n if not numbers:\n raise ValueError(\"The list should not be empty\")\n \n # Find the maximum and minimum values in the list\n max_value = max(numbers)\n min_value = min(numbers)\n \n # Return the difference between max and min values\n return max_value - min_value", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n \"\"\"\n This function takes a list of numbers and returns the difference between the largest and smallest numbers in the list.\n \n Args:\n nums (list): A list of numerical values.\n\n Returns:\n int/float: The difference between the maximum and minimum values in the list.\n \"\"\"\n if not nums:\n raise ValueError(\"The list cannot be empty\")\n \n # Find the maximum and minimum values in the list\n max_val = max(nums)\n min_val = min(nums)\n \n # Return the difference between maximum and minimum\n return max_val - min_val", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n \"\"\"\n This function returns the difference between the largest and smallest value in a given list.\n \n Parameters:\n nums (list): A list of integers.\n \n Returns:\n int: The difference between the largest and smallest value in the list.\n \"\"\"\n if not nums:\n raise ValueError(\"The list must not be empty.\")\n \n # Find the maximum and minimum values in the list\n max_val = max(nums)\n min_val = min(nums)\n \n # Return the difference between the max and min values\n return max_val - min_val", "matching_cluster_idx": 5}, {"solution": "def big_diff(lst):\n \"\"\"\n Returns the difference between the largest and smallest values in the given list.\n \n Parameters:\n lst (list): A list of numerical values.\n \n Returns:\n int/float: The difference between the largest and smallest values.\n \"\"\"\n if not lst:\n raise ValueError(\"The list must not be empty\")\n \n max_val = max(lst)\n min_val = min(lst)\n return max_val - min_val", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n \"\"\"\n Returns the difference between the largest and smallest value in the given list.\n \n Parameters:\n nums (list of int): A list of integers.\n\n Returns:\n int: The difference between the largest and smallest integer in the list.\n \"\"\"\n if not nums:\n raise ValueError(\"The list should not be empty.\")\n \n max_val = max(nums)\n min_val = min(nums)\n return max_val - min_val", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n \"\"\"\n Return the difference between the largest and smallest values in the given list of numbers.\n \n :param nums: List of integers\n :return: Integer representing the difference between the largest and smallest number\n \"\"\"\n if not nums:\n raise ValueError(\"The list must contain at least one number.\")\n\n max_val = max(nums)\n min_val = min(nums)\n return max_val - min_val", "matching_cluster_idx": 5}, {"solution": "def big_diff(lst):\n \"\"\"\n Returns the difference between the largest and smallest values in the given list.\n \n Parameters:\n lst (list): A list of numbers.\n \n Returns:\n int/float: The difference between the largest and smallest values.\n \"\"\"\n if not lst:\n raise ValueError(\"The list should not be empty\")\n \n largest = max(lst)\n smallest = min(lst)\n \n return largest - smallest", "matching_cluster_idx": 5}, {"solution": "def big_diff(numbers):\n \"\"\"\n This function takes a list of numbers and returns the difference\n between the largest and smallest value in the list.\n \"\"\"\n if not numbers:\n raise ValueError(\"The list should not be empty\")\n \n # Find the maximum and minimum values in the list\n max_value = max(numbers)\n min_value = min(numbers)\n \n # Return the difference between the largest and smallest value\n return max_value - min_value", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n \"\"\"\n Finds the difference between the largest and smallest value in a given list.\n\n Parameters:\n nums (list): A list of numbers.\n\n Returns:\n int: The difference between the largest and smallest number.\n \"\"\"\n if not nums:\n raise ValueError(\"The list is empty\")\n \n max_num = max(nums)\n min_num = min(nums)\n \n return max_num - min_num", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n \"\"\"\n Returns the difference between the largest and smallest values in a given list.\n \n Parameters:\n nums (list): A list of integers.\n \n Returns:\n int: The difference between the maximum and minimum integers in the list.\n \"\"\"\n if not nums:\n raise ValueError(\"The list should not be empty.\")\n \n max_val = max(nums)\n min_val = min(nums)\n return max_val - min_val", "matching_cluster_idx": 5}, {"solution": "def big_diff(numbers):\n \"\"\"\n Finds the difference between the largest and smallest values in the given list of numbers.\n\n Parameters:\n numbers (list): A list of integers.\n\n Returns:\n int: The difference between the largest and smallest number in the list.\n \"\"\"\n if not numbers:\n raise ValueError(\"The list should not be empty\")\n\n largest = max(numbers)\n smallest = min(numbers)\n \n return largest - smallest", "matching_cluster_idx": 5}, {"solution": "def big_diff(lst):\n \"\"\"\n This function returns the difference between the largest and smallest\n values in a given list.\n \n :param lst: List of integers\n :return: Integer difference between largest and smallest value\n \"\"\"\n if not lst:\n raise ValueError(\"List must not be empty\")\n\n largest = max(lst)\n smallest = min(lst)\n difference = largest - smallest\n \n return difference", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n \"\"\"\n Returns the difference between the largest and smallest value in the list nums.\n \n Parameters:\n nums (list): A list of numerical values.\n \n Returns:\n int or float: The difference between the maximum and minimum values in the list.\n \"\"\"\n if not nums:\n raise ValueError(\"The list is empty, cannot compute difference.\")\n\n max_val = max(nums)\n min_val = min(nums)\n return max_val - min_val", "matching_cluster_idx": 5}, {"solution": "def big_diff(lst):\n \"\"\"\n This function returns the difference between the largest and smallest value in the given list.\n\n Parameters:\n lst (list): A list of numerical values.\n\n Returns:\n int/float: The difference between the largest and smallest values in the list.\n \"\"\"\n if not lst:\n raise ValueError(\"The list should not be empty.\")\n \n max_val = max(lst)\n min_val = min(lst)\n return max_val - min_val", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n \"\"\"\n Finds the difference between the largest and smallest value in a given list.\n\n Parameters:\n nums (list): A list of integers.\n\n Returns:\n int: The difference between the largest and smallest integer in the list.\n \"\"\"\n if not nums:\n raise ValueError(\"The list must contain at least one number.\")\n \n # Calculate the difference between max and min values\n difference = max(nums) - min(nums)\n return difference", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n \"\"\"\n Returns the difference between the largest and smallest values in the given list.\n \n Parameters:\n nums (list): A list of integers.\n \n Returns:\n int: The difference between the maximum and minimum values in the list.\n \"\"\"\n if not nums:\n raise ValueError(\"The list should not be empty\")\n \n largest = max(nums)\n smallest = min(nums)\n \n return largest - smallest", "matching_cluster_idx": 5}]}, "Mbpp/592": {"dps": 51.866666666666674, "dps_norm": 49.5, "pass@1": 37.0, "profiled": [{"solution": "from math import comb\ndef sum_Of_product(n):\n \"\"\"\n Calculates the sum of the product of consecutive binomial coefficients\n for the given number of rows `n` in Pascal's Triangle.\n \"\"\"\n sum_of_products = 0\n for k in range(n):\n # Compute the product of consecutive binomial coefficients:\n # C(n, k) * C(n, k+1) = n! / (k! * (n-k)!) * n! / ((k+1)! * (n-k-1)!)\n # = n * (n-1)! / (k! * (n-k)!) * n! / ((k+1)! * (n-k-1)!)\n product = comb(n, k) * comb(n, k + 1)\n sum_of_products += product\n return sum_of_products", "matching_cluster_idx": 4}, {"solution": "def binomial_coefficient(n, k):\n \"\"\"Calculate the binomial coefficient C(n, k)\"\"\"\n if k > n:\n return 0\n if k == 0 or k == n:\n return 1\n k = min(k, n - k)\n c = 1\n for i in range(k):\n c = c * (n - i) // (i + 1)\n return c\ndef sum_Of_product(n):\n \"\"\"\n Calculate the sum of the product of consecutive binomial coefficients for a given n.\n \n The sum is calculated as: C(n, 0)*C(n, 1) + C(n, 1)*C(n, 2) + ... + C(n, n-1)*C(n, n)\n \"\"\"\n sum_product = 0\n for k in range(n):\n sum_product += binomial_coefficient(n, k) * binomial_coefficient(n, k + 1)\n return sum_product", "matching_cluster_idx": 4}, {"solution": "def binomial_coefficient(n, k):\n \"\"\"Compute the binomial coefficient C(n, k).\"\"\"\n if k > n:\n return 0\n if k == 0 or k == n:\n return 1\n # Calculate the value using an iterative approach\n result = 1\n for i in range(min(k, n - k)):\n result *= n - i\n result //= i + 1\n return result\ndef sum_Of_product(n):\n \"\"\"\n Compute the sum of the product of consecutive binomial coefficients\n for a given integer n.\n \"\"\"\n total_sum = 0\n for k in range(n):\n # C(n, k) * C(n, k+1)\n product = binomial_coefficient(n, k) * binomial_coefficient(n, k + 1)\n total_sum += product\n return total_sum", "matching_cluster_idx": 4}, {"solution": "def sum_Of_product(n):\n from math import comb\n total_sum = 0\n for k in range(n):\n product = comb(n, k) * comb(n, k + 1)\n total_sum += product\n return total_sum", "matching_cluster_idx": 5}, {"solution": "def binomial_coefficient(n, k):\n \"\"\"Calculate the binomial coefficient C(n, k).\"\"\"\n if k > n:\n return 0\n if k == 0 or k == n:\n return 1\n \n # Use a more efficient calculation to avoid large factorials\n c = 1\n for i in range(min(k, n - k)):\n c = c * (n - i) // (i + 1)\n return c\ndef sum_Of_product(n):\n \"\"\"Calculate the sum of the product of consecutive binomial coefficients.\"\"\"\n total_sum = 0\n for k in range(n):\n # Calculate C(n, k) * C(n, k+1)\n product = binomial_coefficient(n, k) * binomial_coefficient(n, k + 1)\n total_sum += product\n return total_sum", "matching_cluster_idx": 4}, {"solution": "def binomial_coefficient(n, k):\n \"\"\"Calculate the binomial coefficient C(n, k)\"\"\"\n if k > n:\n return 0\n if k == 0 or k == n:\n return 1\n k = min(k, n - k)\n c = 1\n for i in range(k):\n c = c * (n - i) // (i + 1)\n return c\ndef sum_Of_product(n):\n \"\"\"Calculate the sum of the product of consecutive binomial coefficients for a given n\"\"\"\n total_sum = 0\n for k in range(n):\n total_sum += binomial_coefficient(n, k) * binomial_coefficient(n, k + 1)\n return total_sum", "matching_cluster_idx": 4}, {"solution": "import math\ndef sum_Of_product(n):\n \"\"\"\n Calculate the sum of the product of consecutive binomial coefficients for a given n.\n \"\"\"\n total_sum = 0\n for k in range(n):\n # Calculate the product of consecutive binomial coefficients\n product = math.comb(n, k) * math.comb(n, k + 1)\n total_sum += product\n \n return total_sum", "matching_cluster_idx": 5}, {"solution": "def sum_Of_product(n):\n \"\"\"\n Function to calculate the sum of the product of consecutive binomial coefficients.\n \n The product of consecutive binomial coefficients for a given n:\n C(n, 0) * C(n, 1) + C(n, 1) * C(n, 2) + ... + C(n, n-1) * C(n, n)\n where C(n, k) is the binomial coefficient 'n choose k'.\n \"\"\"\n def binomial_coefficient(n, k):\n \"\"\"Helper function to calculate the binomial coefficient C(n, k).\"\"\"\n if k > n:\n return 0\n if k == 0 or k == n:\n return 1\n k = min(k, n - k)\n c = 1\n for i in range(k):\n c = c * (n - i) // (i + 1)\n return c\n \n sum_product = 0\n for k in range(n):\n product = binomial_coefficient(n, k) * binomial_coefficient(n, k + 1)\n sum_product += product\n \n return sum_product", "matching_cluster_idx": 4}, {"solution": "from math import comb\ndef sum_Of_product(n):\n \"\"\"\n Calculate the sum of the product of consecutive binomial coefficients.\n \n The function calculates the sum of the products of consecutive binomial coefficients C(n, k) * C(n, k + 1) \n for k ranging from 0 to n-1.\n \"\"\"\n total_sum = 0\n for k in range(n):\n total_sum += comb(n, k) * comb(n, k + 1)\n return total_sum", "matching_cluster_idx": 5}, {"solution": "def sum_Of_product(n):\n \"\"\"\n Calculate the sum of the product of consecutive binomial coefficients for a given n.\n \n Args:\n - n (int): The upper limit for calculating binomial coefficients.\n\n Returns:\n - int: The sum of the product of consecutive binomial coefficients.\n \"\"\"\n def binomial_coefficient(n, k):\n \"\"\"\n Calculate binomial coefficient C(n, k).\n \n Args:\n - n (int): The upper part of the binomial coefficient.\n - k (int): The lower part of the binomial coefficient.\n\n Returns:\n - int: The binomial coefficient.\n \"\"\"\n if k > n:\n return 0\n if k == 0 or k == n:\n return 1\n k = min(k, n - k)\n c = 1\n for i in range(k):\n c = c * (n - i) // (i + 1)\n return c\n \n total_sum = 0\n for k in range(n):\n # Calculate the product of consecutive binomial coefficients\n product = binomial_coefficient(n, k) * binomial_coefficient(n, k + 1)\n total_sum += product\n \n return total_sum", "matching_cluster_idx": 4}, {"solution": "def binomial_coefficient(n, k):\n \"\"\"Calculates binomial coefficient C(n, k)\"\"\"\n if k > n:\n return 0\n if k == 0 or k == n:\n return 1\n # Compute C(n, k) using the multiplicative formula\n c = 1\n for i in range(min(k, n - k)):\n c = c * (n - i) // (i + 1)\n return c\ndef sum_Of_product(n):\n \"\"\"Calculates the sum of the product of consecutive binomial coefficients for n.\"\"\"\n sum_product = 0\n for k in range(n):\n c1 = binomial_coefficient(n, k)\n c2 = binomial_coefficient(n, k + 1)\n sum_product += c1 * c2\n return sum_product", "matching_cluster_idx": 4}, {"solution": "from math import comb\ndef sum_Of_product(n):\n \"\"\"\n Calculate the sum of the product of consecutive binomial coefficients for a given n.\n \n Args:\n n (int): The number of rows in Pascal's triangle to consider.\n\n Returns:\n int: The sum of products of consecutive binomial coefficients.\n \"\"\"\n total_sum = 0\n \n # Iterate over rows 0 to n-1 in Pascal's triangle\n for k in range(n):\n # Calculate product of consecutive binomial coefficients\n # C(n, k) * C(n, k + 1)\n product = comb(n, k) * comb(n, k + 1)\n total_sum += product\n \n return total_sum", "matching_cluster_idx": 5}, {"solution": "def binomial_coefficient(n, k):\n if k > n:\n return 0\n if k == 0 or k == n:\n return 1\n # Compute factorial in a straightforward way\n def factorial(num):\n if num == 0 or num == 1:\n return 1\n result = 1\n for i in range(2, num + 1):\n result *= i\n return result\n \n return factorial(n) // (factorial(k) * factorial(n - k))\ndef sum_Of_product(n):\n total_sum = 0\n for k in range(n):\n total_sum += binomial_coefficient(n, k) * binomial_coefficient(n, k + 1)\n return total_sum", "matching_cluster_idx": 0}, {"solution": "def binomial_coefficient(n, k):\n \"\"\"Calculate binomial coefficient C(n, k) = n! / (k! * (n-k)!)\"\"\"\n if k > n:\n return 0\n if k == 0 or k == n:\n return 1\n k = min(k, n - k) # Take advantage of symmetry\n c = 1\n for i in range(k):\n c = c * (n - i) // (i + 1)\n return c\ndef sum_Of_product(n):\n \"\"\"\n Calculate the sum of the product of consecutive binomial coefficients for a given n.\n \"\"\"\n total_sum = 0\n for k in range(n):\n # Calculate product of C(n, k) and C(n, k+1)\n product = binomial_coefficient(n, k) * binomial_coefficient(n, k + 1)\n total_sum += product\n return total_sum", "matching_cluster_idx": 4}, {"solution": "def factorial(n):\n \"\"\"Returns the factorial of n.\"\"\"\n if n == 0 or n == 1:\n return 1\n result = 1\n for i in range(2, n + 1):\n result *= i\n return result\ndef binomial_coefficient(n, k):\n \"\"\"Returns the binomial coefficient C(n, k).\"\"\"\n return factorial(n) // (factorial(k) * factorial(n - k))\ndef sum_Of_product(n):\n \"\"\"Returns the sum of the product of consecutive binomial coefficients for a given n.\"\"\"\n total_sum = 0\n for k in range(n):\n product = binomial_coefficient(n, k) * binomial_coefficient(n, k + 1)\n total_sum += product\n return total_sum", "matching_cluster_idx": 0}, {"solution": "def binomial_coefficient(n, k):\n \"\"\"Calculate the binomial coefficient C(n, k) = n! / (k! * (n-k)!)\"\"\"\n if k > n:\n return 0\n if k == 0 or k == n:\n return 1\n k = min(k, n - k) # Take advantage of symmetry\n c = 1\n for i in range(k):\n c = c * (n - i) // (i + 1)\n return c\ndef sum_Of_product(n):\n \"\"\"\n Calculate the sum of the product of consecutive binomial coefficients for a given n.\n S(n) = C(n,0)*C(n,1) + C(n,1)*C(n,2) + ... + C(n,n-1)*C(n,n)\n \"\"\"\n sum_product = 0\n for k in range(n):\n sum_product += binomial_coefficient(n, k) * binomial_coefficient(n, k + 1)\n return sum_product", "matching_cluster_idx": 4}, {"solution": "def sum_Of_product(n):\n \"\"\"\n Calculates the sum of the products of consecutive binomial coefficients for a given n.\n \"\"\"\n def binomial_coefficient(n, k):\n if k < 0 or k > n:\n return 0\n if k == 0 or k == n:\n return 1\n k = min(k, n - k)\n c = 1\n for i in range(k):\n c = c * (n - i) // (i + 1)\n return c\n \n sum_products = 0\n for i in range(n):\n product = binomial_coefficient(n, i) * binomial_coefficient(n, i + 1)\n sum_products += product\n \n return sum_products", "matching_cluster_idx": 4}, {"solution": "from math import comb\ndef sum_Of_product(n):\n total_sum = 0\n for k in range(n):\n # Calculate product of consecutive binomial coefficients C(n, k) * C(n, k+1)\n product = comb(n, k) * comb(n, k+1)\n total_sum += product\n return total_sum", "matching_cluster_idx": 5}, {"solution": "import math\ndef sum_Of_product(n):\n \"\"\"\n Calculate the sum of the product of consecutive binomial coefficients\n for a given integer n.\n \n Args:\n n (int): The upper limit of the binomial coefficient row (0-indexed).\n \n Returns:\n int: The sum of the product of consecutive binomial coefficients.\n \"\"\"\n total_sum = 0\n for k in range(n):\n # Calculate C(n, k) * C(n, k+1)\n product = math.comb(n, k) * math.comb(n, k + 1)\n total_sum += product\n return total_sum", "matching_cluster_idx": 5}, {"solution": "import math\ndef binomial_coefficient(n, k):\n \"\"\"Calculate the binomial coefficient C(n, k)\"\"\"\n return math.comb(n, k)\ndef sum_Of_product(n):\n \"\"\"\n Calculate the sum of the product of consecutive binomial coefficients for a given n.\n \"\"\"\n total_sum = 0\n for k in range(0, n):\n prod = binomial_coefficient(n, k) * binomial_coefficient(n, k + 1)\n total_sum += prod\n return total_sum", "matching_cluster_idx": 5}]}, "Mbpp/597": {"dps": null, "dps_norm": null, "pass@1": 0.0, "profiled": []}, "Mbpp/604": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 99.0, "profiled": [{"solution": "def reverse_words(s: str) -> str:\n \"\"\"\n Reverses the order of words separated by spaces in the input string.\n\n Args:\n s (str): The input string containing words separated by spaces.\n\n Returns:\n str: A string with the words in reverse order.\n \"\"\"\n # Split the string into words, reverse the list of words, and join them back with spaces\n return ' '.join(s.split()[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n # Split the string into words\n words = s.split()\n # Reverse the list of words\n reversed_words = words[::-1]\n # Join the reversed words back into a string with spaces\n return ' '.join(reversed_words)", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s: str) -> str:\n \"\"\"\n Reverses words separated by spaces in a given string.\n\n :param s: The input string with words separated by spaces.\n :return: A string with the words in reversed order.\n \"\"\"\n words = s.split() # Split the string into a list of words\n reversed_words = words[::-1] # Reverse the list of words\n return ' '.join(reversed_words) # Join the reversed list of words back into a string", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s: str) -> str:\n \"\"\"\n Reverses the order of words in a given string, where words are separated by spaces.\n\n Args:\n s (str): The input string with words separated by spaces.\n\n Returns:\n str: The input string with the order of words reversed.\n \"\"\"\n words = s.split() # Split the string into a list of words\n reversed_words = words[::-1] # Reverse the list of words\n return ' '.join(reversed_words) # Join the reversed list of words back into a string", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s: str) -> str:\n # Split the string into words\n words = s.split()\n # Reverse the list of words\n reversed_words = words[::-1]\n # Join them back together with spaces\n reversed_string = ' '.join(reversed_words)\n return reversed_string", "matching_cluster_idx": 4}, {"solution": "def reverse_words(sentence):\n # Split the input sentence into a list of words\n words = sentence.split()\n \n # Reverse the list of words\n reversed_words = words[::-1]\n \n # Join the reversed list back into a string with spaces\n reversed_sentence = ' '.join(reversed_words)\n \n return reversed_sentence", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n \"\"\"\n Reverse words separated by spaces in a given string.\n\n Parameters:\n s (str): The input string.\n\n Returns:\n str: The string with words in reversed order.\n \"\"\"\n # Split the string into words\n words = s.split()\n # Reverse the list of words\n reversed_words = words[::-1]\n # Join them back into a single string separated by spaces\n return ' '.join(reversed_words)", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n # Split the string into words based on spaces\n words = s.split()\n # Reverse the list of words\n reversed_words = words[::-1]\n # Join the words back into a single string with spaces\n reversed_string = ' '.join(reversed_words)\n return reversed_string", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s: str) -> str:\n \"\"\"\n Reverses words separated by spaces in a given string.\n\n Parameters:\n s (str): A string containing words separated by spaces.\n\n Returns:\n str: A string with words in reversed order.\n \"\"\"\n # Split the string into words\n words = s.split()\n \n # Reverse the list of words\n reversed_words = words[::-1]\n \n # Join the reversed list of words back into a string with spaces\n reversed_string = ' '.join(reversed_words)\n \n return reversed_string", "matching_cluster_idx": 4}, {"solution": "def reverse_words(sentence):\n \"\"\"\n Reverses the order of words in a given string.\n \n Args:\n sentence (str): The input string to be reversed.\n \n Returns:\n str: A string with the words in reverse order.\n \"\"\"\n # Split the sentence into words using space as a delimiter\n words = sentence.split()\n # Reverse the list of words\n reversed_words = words[::-1]\n # Join the reversed list of words into a single string with spaces\n reversed_sentence = ' '.join(reversed_words)\n return reversed_sentence", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n \"\"\"\n Reverse the order of words in a given string.\n \n Parameters:\n s (str): A string containing words separated by spaces.\n \n Returns:\n str: A string with the words in reversed order.\n \"\"\"\n # Split the string into words\n words = s.split()\n # Reverse the list of words\n reversed_words = words[::-1]\n # Join them back with spaces\n return ' '.join(reversed_words)", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s: str) -> str:\n # Split the string into words\n words = s.split()\n # Reverse the list of words\n reversed_words = words[::-1]\n # Join the reversed list of words back into a string\n reversed_string = ' '.join(reversed_words)\n return reversed_string", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n # Split the string into words\n words = s.split()\n # Reverse the list of words\n reversed_words = words[::-1]\n # Join the reversed list of words back into a string with spaces\n return ' '.join(reversed_words)", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s: str) -> str:\n # Split the string into a list of words\n words = s.split()\n # Reverse the list of words\n reversed_words = words[::-1]\n # Join the reversed list back into a string with spaces\n return ' '.join(reversed_words)", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n \"\"\"\n Reverses the words in a given string `s` separated by spaces.\n \n Parameters:\n s (str): The input string with words separated by spaces.\n \n Returns:\n str: A new string with the words in reverse order.\n \"\"\"\n # Split the string into words\n words = s.split()\n # Reverse the list of words\n reversed_words = words[::-1]\n # Join the reversed list of words into a single string separated by spaces\n return ' '.join(reversed_words)", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n \"\"\"\n Reverse words separated by spaces in the given string.\n\n Args:\n s (str): The input string containing words separated by spaces.\n\n Returns:\n str: The string with words in reverse order.\n \"\"\"\n # Split the string into words\n words = s.split()\n # Reverse the list of words\n reversed_words = words[::-1]\n # Join the reversed list of words into a single string separated by spaces\n result = ' '.join(reversed_words)\n return result", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s: str) -> str:\n \"\"\"\n Reverses the order of words in the given string `s`, where words are separated by spaces.\n\n :param s: A string with words separated by spaces.\n :return: A string with the words in reversed order.\n \"\"\"\n # Split the string into words\n words = s.split()\n # Reverse the list of words\n reversed_words = words[::-1]\n # Join them back into a string with a space separator\n return ' '.join(reversed_words)", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s: str) -> str:\n # Split the string into words\n words = s.split()\n # Reverse the list of words\n reversed_words = words[::-1]\n # Join the reversed list of words back into a string with spaces\n return ' '.join(reversed_words)", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s: str) -> str:\n # Split the string into words\n words = s.split()\n # Reverse the list of words\n reversed_words = words[::-1]\n # Join the reversed list of words back into a string with spaces\n return ' '.join(reversed_words)", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n \"\"\"\n Reverses the words in a given string s, where words are separated by spaces.\n \n Parameters:\n s (str): The input string containing words separated by spaces.\n \n Returns:\n str: A string with the words in reverse order.\n \"\"\"\n # Split the string into words\n words = s.split()\n \n # Reverse the list of words\n reversed_words = words[::-1]\n \n # Join the reversed list back into a string with spaces\n reversed_string = ' '.join(reversed_words)\n \n return reversed_string", "matching_cluster_idx": 4}]}, "Mbpp/610": {"dps": null, "dps_norm": null, "pass@1": 1.0, "profiled": []}, "Mbpp/611": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 63.0, "profiled": [{"solution": "def max_of_nth(matrix, n):\n \"\"\"\n Returns the maximum value from the nth column of a given matrix.\n\n :param matrix: List of lists representing the matrix.\n :param n: Index of the column for which we want to find the maximum.\n :return: Maximum value in the nth column.\n \"\"\"\n # Extract the nth column using a list comprehension\n nth_column = [row[n] for row in matrix]\n \n # Return the maximum value of the extracted column\n return max(nth_column)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n \"\"\"\n Returns the maximum value from the n-th column of the given matrix.\n\n Parameters:\n - matrix: A list of lists where each sublist represents a row of the matrix.\n - n: The index of the column to find the maximum of (0-indexed).\n\n Returns:\n - The maximum value in the n-th column.\n \"\"\"\n # Extract the n-th column from the matrix\n nth_column = [row[n] for row in matrix if len(row) > n]\n \n # Return the maximum value in the n-th column\n return max(nth_column)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n \"\"\"\n This function takes a matrix (a list of lists) and an integer n.\n It returns the maximum value found in the nth column of the matrix.\n \"\"\"\n # Extract the nth column from each row and find the maximum value\n return max(row[n] for row in matrix)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n # Extract the n-th column from the matrix\n nth_column = [row[n] for row in matrix]\n # Return the maximum value of the n-th column\n return max(nth_column)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n \"\"\"\n Returns the maximum value in the n-th column of the matrix.\n \n :param matrix: A list of lists representing the matrix.\n :param n: The index of the column (0-based) to find the max value in.\n :return: The maximum value in the specified column.\n \"\"\"\n # Extract the nth column from each row\n nth_column = [row[n] for row in matrix]\n \n # Return the maximum value in the nth column\n return max(nth_column)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n \"\"\"\n Returns the maximum value from the nth column of the matrix.\n \n :param matrix: List of lists, where each sublist represents a row in a matrix.\n :param n: The column index for which the maximum value needs to be found.\n :return: The maximum value in the nth column.\n \"\"\"\n return max(row[n] for row in matrix)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n \"\"\"Returns the maximum value of the n'th column in the given matrix.\"\"\"\n # Extract the n-th column\n nth_column = [row[n] for row in matrix if len(row) > n]\n \n # Return the maximum value in the extracted column\n return max(nth_column)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n \"\"\"\n Returns the maximum value from the nth column of a matrix.\n\n :param matrix: A list of lists where each inner list represents a row in the matrix.\n :param n: The column index for which we want to find the maximum value.\n :return: The maximum value in the nth column.\n \"\"\"\n # Extract the nth column using list comprehension\n nth_column = [row[n] for row in matrix]\n # Return the maximum value in the nth column\n return max(nth_column)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n # Extract the n-th column from each row in the matrix\n column = [row[n] for row in matrix]\n \n # Return the maximum value from the extracted column\n return max(column)\nmatrix = [\n [5, 6, 7],\n [1, 3, 5],\n [8, 9, 19]\n]\nn = 2", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n \"\"\"\n This function takes a matrix (list of lists) and an integer n, and returns the maximum value in the nth column.\n \"\"\"\n # Extract the nth column from the matrix\n nth_column = [row[n] for row in matrix]\n # Return the maximum value in the nth column\n return max(nth_column)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n # Extract the nth column\n nth_column = [row[n] for row in matrix]\n # Return the maximum value in the nth column\n return max(nth_column)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n \"\"\"\n Given a matrix represented as a list of lists, return the max of the nth column.\n \n Parameters:\n - matrix (list of lists): A 2D list representing the matrix.\n - n (int): The index of the column to find the maximum of.\n\n Returns:\n - int/float: The maximum value of the nth column.\n \"\"\"\n # Extract the nth column from each row in the matrix\n nth_column = [row[n] for row in matrix if len(row) > n]\n # Return the maximum value found in the nth column\n return max(nth_column)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n # Extract the n-th column from each row and find the maximum value\n return max(row[n] for row in matrix)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n \"\"\"\n Given a matrix (list of lists), returns the maximum value of the nth column.\n \"\"\"\n # Use a list comprehension to extract the nth element from each row\n nth_column = [row[n] for row in matrix]\n \n # Return the maximum value from the nth column\n return max(nth_column)\nmatrix = [\n [5, 6, 7],\n [1, 3, 5],\n [8, 9, 19]\n]", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n \"\"\"\n Returns the maximum value of the n'th column in the given matrix.\n \n :param matrix: List of lists representing the matrix.\n :param n: Index of the column for which to find the maximum value.\n :return: Maximum value in the n'th column.\n \"\"\"\n # Extract the nth column values from each row in the matrix\n nth_column_values = [row[n] for row in matrix]\n # Return the maximum value found in the nth column\n return max(nth_column_values)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n \"\"\"\n This function returns the maximum value of the nth column in a given matrix.\n \n :param matrix: List of lists where each inner list represents a row of the matrix.\n :param n: The index of the column for which to find the maximum value.\n :return: The maximum value in the nth column.\n \"\"\"\n # Extract the nth column from the matrix\n nth_column = [row[n] for row in matrix]\n \n # Return the maximum value in the nth column\n return max(nth_column)\nmatrix = [\n [5, 6, 7],\n [1, 3, 5],\n [8, 9, 19]\n]\nn = 2", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n # Check if the input matrix is not empty and if n is a valid column index\n if not matrix or not matrix[0] or n >= len(matrix[0]):\n raise ValueError(\"Invalid matrix or column index\")\n \n # Extract the nth column and find the maximum value\n nth_column = [row[n] for row in matrix]\n return max(nth_column)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n \"\"\"\n Given a matrix represented as a list of lists, returns the maximum value of the n-th column.\n \n :param matrix: List[List[int]] - A list of lists where each inner list represents a row in a matrix.\n :param n: int - The index of the column to find the maximum value from.\n :return: int - The maximum value in the n-th column.\n \"\"\"\n # Extract the n-th column from the matrix and find the maximum value.\n nth_column = [row[n] for row in matrix if len(row) > n]\n return max(nth_column)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n \"\"\"\n Returns the maximum value from the n'th column of the given matrix.\n \n :param matrix: A list of lists where each sublist represents a row of the matrix.\n :param n: The column index for which the maximum value should be found.\n :return: The maximum value from the n'th column.\n \"\"\"\n # Extract the nth column from the matrix\n nth_column = [row[n] for row in matrix]\n \n # Return the maximum value from the extracted column\n return max(nth_column)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n \"\"\"\n Function to find the maximum value in the n-th column of a matrix.\n \n :param matrix: List of lists, where each inner list represents a row of the matrix\n :param n: Index of the column to find the maximum value\n :return: Maximum value in the specified column\n \"\"\"\n # Initialize max_value with the first element in the n-th column\n max_value = matrix[0][n]\n \n # Iterate over each row in the matrix\n for row in matrix:\n # Update max_value if a larger element is found in the n-th column\n if row[n] > max_value:\n max_value = row[n]\n \n return max_value", "matching_cluster_idx": 5}]}, "Mbpp/631": {"dps": 53.88888888888888, "dps_norm": 67.5, "pass@1": 96.0, "profiled": [{"solution": "def replace_spaces(s):\n # Create a translation table that maps space to underscore and underscore to space\n translation_table = str.maketrans(' _', '_ ')\n # Translate the string using the translation table\n return s.translate(translation_table)", "matching_cluster_idx": 6}, {"solution": "def replace_spaces(s: str) -> str:\n \"\"\"\n Replace whitespaces with underscores and underscores with whitespaces in the given string.\n \"\"\"\n # Use a list comprehension to replace each character as needed\n return ''.join('_' if char == ' ' else ' ' if char == '_' else char for char in s)", "matching_cluster_idx": 3}, {"solution": "def replace_spaces(s: str) -> str:\n # This function will replace spaces with underscores and underscores with spaces\n result = []\n for char in s:\n if char == ' ':\n result.append('_')\n elif char == '_':\n result.append(' ')\n else:\n result.append(char)\n return ''.join(result)", "matching_cluster_idx": 3}, {"solution": "def replace_spaces(input_string):\n \"\"\"\n Replace whitespaces with underscores and underscores with whitespaces in the given string.\n \"\"\"\n result = []\n for char in input_string:\n if char == ' ':\n result.append('_')\n elif char == '_':\n result.append(' ')\n else:\n result.append(char)\n return ''.join(result)", "matching_cluster_idx": 2}, {"solution": "def replace_spaces(s: str) -> str:\n # Create a translation table for swapping spaces and underscores\n translation_table = str.maketrans(\" _\", \"_ \")\n # Translate the string using the table\n return s.translate(translation_table)", "matching_cluster_idx": 6}, {"solution": "def replace_spaces(s):\n # Create a translation table for replacing space with underscore and underscore with space\n translation_table = str.maketrans(\" _\", \"_ \")\n # Translate the string using the created table\n return s.translate(translation_table)", "matching_cluster_idx": 6}, {"solution": "def replace_spaces(s: str) -> str:\n # Create a new string by replacing spaces with underscores and vice versa\n replaced_string = ''.join('_' if c == ' ' else (' ' if c == '_' else c) for c in s)\n return replaced_string", "matching_cluster_idx": 3}, {"solution": "def replace_spaces(s):\n \"\"\"\n Replaces whitespaces with underscores and underscores with whitespaces in the given string.\n \n Parameters:\n s (str): The input string.\n \n Returns:\n str: The modified string with whitespaces and underscores swapped.\n \"\"\"\n # Create a translation table where ' ' (space) is replaced by '_' and '_' is replaced by ' '\n translation_table = str.maketrans(' _', '_ ')\n return s.translate(translation_table)", "matching_cluster_idx": 6}, {"solution": "def replace_spaces(s):\n \"\"\"\n Replaces whitespaces with underscores and underscores with whitespaces in the given string.\n\n Args:\n s (str): The input string.\n\n Returns:\n str: The modified string with whitespaces and underscores swapped.\n \"\"\"\n # Use a list comprehension to iterate over the string and replace characters accordingly\n return ''.join(['_' if char == ' ' else ' ' if char == '_' else char for char in s])", "matching_cluster_idx": 3}, {"solution": "def replace_spaces(s: str) -> str:\n \"\"\"\n Replace whitespaces with underscores and underscores with whitespaces in the input string.\n \n Parameters:\n s (str): The input string to be transformed.\n\n Returns:\n str: The transformed string with whitespaces replaced by underscores and vice versa.\n \"\"\"\n # Create a translation table that maps spaces to underscores and underscores to spaces\n translation_table = str.maketrans(' _', '_ ')\n \n # Translate the string using the translation table\n return s.translate(translation_table)", "matching_cluster_idx": 6}, {"solution": "def replace_spaces(input_string: str) -> str:\n \"\"\"\n Replaces whitespaces with underscores and underscores with whitespaces in the input string.\n\n Args:\n input_string (str): The string to be modified.\n\n Returns:\n str: The modified string with spaces replaced by underscores and vice versa.\n \"\"\"\n # Create a translation table for replacing characters\n translation_table = str.maketrans(\" _\", \"_ \")\n \n # Translate the input string using the translation table\n return input_string.translate(translation_table)", "matching_cluster_idx": 6}, {"solution": "def replace_spaces(input_string):\n \"\"\"\n This function replaces whitespaces with underscores and underscores with whitespaces in the given string.\n \n :param input_string: A string where we want to switch whitespaces and underscores.\n :return: The modified string with whitespaces and underscores swapped.\n \"\"\"\n # Use a list comprehension to swap spaces with underscores and vice versa\n modified_string = ''.join(['_' if char == ' ' else ' ' if char == '_' else char for char in input_string])\n return modified_string", "matching_cluster_idx": 3}, {"solution": "def replace_spaces(s):\n # Replace spaces with underscores and underscores with spaces\n return s.replace(' ', '\\x00').replace('_', ' ').replace('\\x00', '_')", "matching_cluster_idx": 4}, {"solution": "def replace_spaces(s):\n # Translate whitespaces to underscores and underscores to whitespaces\n return s.translate(str.maketrans(' _', '_ '))", "matching_cluster_idx": 6}, {"solution": "def replace_spaces(s):\n # Create a translation table\n translation_table = str.maketrans(' _', '_ ')\n # Translate the string using the table\n return s.translate(translation_table)", "matching_cluster_idx": 6}, {"solution": "def replace_spaces(s: str) -> str:\n # Initialize an empty list to build the new string\n result = []\n \n # Iterate over each character in the input string\n for char in s:\n # Replace space with underscore\n if char == ' ':\n result.append('_')\n # Replace underscore with space\n elif char == '_':\n result.append(' ')\n # Otherwise, keep the character as is\n else:\n result.append(char)\n \n # Join the list into a string and return\n return ''.join(result)", "matching_cluster_idx": 2}, {"solution": "def replace_spaces(input_string):\n # Create a translation table for swapping space with underscore and vice versa\n translation_table = str.maketrans(' _', '_ ')\n \n # Translate the input string using the translation table\n return input_string.translate(translation_table)", "matching_cluster_idx": 6}, {"solution": "def replace_spaces(input_string):\n \"\"\"\n Replaces whitespaces with underscores and underscores with whitespaces in the given string.\n \"\"\"\n # Create a translation table for swapping space and underscore\n translation_table = str.maketrans(' _', '_ ')\n return input_string.translate(translation_table)", "matching_cluster_idx": 6}, {"solution": "def replace_spaces(s):\n # Create a list to store the modified characters\n result = []\n\n # Iterate through each character in the string\n for char in s:\n if char == ' ':\n # Replace space with underscore\n result.append('_')\n elif char == '_':\n # Replace underscore with space\n result.append(' ')\n else:\n # Keep the character as it is\n result.append(char)\n\n # Join the list back into a string and return it\n return ''.join(result)", "matching_cluster_idx": 3}, {"solution": "def replace_spaces(s):\n \"\"\"\n Replaces whitespaces with underscores and underscores with whitespaces in the given string.\n \n Parameters:\n - s (str): The input string.\n\n Returns:\n - str: The modified string with swapped characters.\n \"\"\"\n # Create a list from the string for mutable operations\n modified_chars = []\n \n # Iterate over each character in the string\n for char in s:\n if char == ' ':\n # Replace spaces with underscores\n modified_chars.append('_')\n elif char == '_':\n # Replace underscores with spaces\n modified_chars.append(' ')\n else:\n # Leave other characters unchanged\n modified_chars.append(char)\n \n # Join the list back into a string\n return ''.join(modified_chars)", "matching_cluster_idx": 2}]}, "Mbpp/632": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def move_zero(nums):\n \"\"\"\n Move all zeroes in the list to the end while maintaining the order of non-zero elements.\n \n Parameters:\n nums (list): The list of numbers to process.\n \n Returns:\n list: A new list with all zeroes moved to the end.\n \"\"\"\n # Count the number of zeroes in the list\n zero_count = nums.count(0)\n \n # Create a list with all non-zero elements\n result = [num for num in nums if num != 0]\n \n # Append the appropriate number of zeroes at the end\n result.extend([0] * zero_count)\n \n return result", "matching_cluster_idx": 6}, {"solution": "def move_zero(lst):\n \"\"\"\n Moves all zeros in the given list to the end while maintaining the order of non-zero elements.\n\n Parameters:\n lst (list): The input list containing integers.\n\n Returns:\n list: A new list with all zeros moved to the end.\n \"\"\"\n # List to store non-zero elements\n non_zero_elements = [x for x in lst if x != 0]\n \n # Count the number of zeroes\n zero_count = lst.count(0)\n \n # Append zeroes to the end of the non-zero list\n return non_zero_elements + [0] * zero_count", "matching_cluster_idx": 6}, {"solution": "def move_zero(lst):\n \"\"\"\n Moves all zeroes in the list to the end while maintaining the order of non-zero elements.\n \n Parameters:\n lst (list): The list of numbers to be modified.\n \n Returns:\n list: The modified list with all zeroes moved to the end.\n \"\"\"\n # Count the number of zeros in the list\n zero_count = lst.count(0)\n # Create a new list without zeros\n non_zero_list = [num for num in lst if num != 0]\n # Add zeros to the end of the list\n non_zero_list.extend([0] * zero_count)\n return non_zero_list", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n \"\"\"\n Moves all zeroes to the end of the list while maintaining the order of non-zero elements.\n \"\"\"\n non_zero_index = 0\n\n # Move all non-zero elements to the front of the list\n for i in range(len(nums)):\n if nums[i] != 0:\n nums[non_zero_index] = nums[i]\n non_zero_index += 1\n\n # Fill the remaining positions in the list with zeroes\n for i in range(non_zero_index, len(nums)):\n nums[i] = 0\n\n return nums", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n \"\"\"\n This function moves all zeroes in the list to the end while preserving the order of non-zero elements.\n \"\"\"\n # Pointer for the position of the next non-zero element\n non_zero_position = 0\n\n # Iterate through the list\n for num in nums:\n if num != 0:\n # Assign the non-zero element to the current position of the non-zero pointer\n nums[non_zero_position] = num\n non_zero_position += 1\n\n # Fill the rest of the list with zeroes\n for i in range(non_zero_position, len(nums)):\n nums[i] = 0\n\n return nums", "matching_cluster_idx": 6}, {"solution": "def move_zero(lst):\n \"\"\"\n Move all zeros in the list to the end while maintaining the order of non-zero elements.\n\n Args:\n lst (list): The list of numbers to be rearranged.\n\n Returns:\n list: The list with all zeros moved to the end.\n \"\"\"\n non_zero = [num for num in lst if num != 0]\n zero_count = len(lst) - len(non_zero)\n return non_zero + [0] * zero_count", "matching_cluster_idx": 6}, {"solution": "def move_zero(lst):\n # Initialize an empty list to store non-zero elements\n non_zero_elements = []\n \n # Count the number of zeroes\n zero_count = 0\n \n # Traverse the list\n for num in lst:\n if num != 0:\n # Add non-zero elements to the new list\n non_zero_elements.append(num)\n else:\n # Increment the zero counter\n zero_count += 1\n \n # Extend the list with zero_count zeroes at the end\n non_zero_elements.extend([0] * zero_count)\n \n return non_zero_elements", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n # Create a new list without zeroes\n non_zeroes = [num for num in nums if num != 0]\n # Count the number of zeroes\n zero_count = nums.count(0)\n # Append zeroes to the end of the non-zero list\n return non_zeroes + [0] * zero_count", "matching_cluster_idx": 6}, {"solution": "def move_zero(lst):\n # Two-pointer approach\n # Pointer to keep track of position to place non-zero elements\n position = 0\n\n # Loop through each element in the list\n for num in lst:\n if num != 0:\n # If the number is non-zero, place it at the current position\n lst[position] = num\n position += 1\n\n # Fill the remaining part of the list with zeroes\n while position < len(lst):\n lst[position] = 0\n position += 1\n\n return lst", "matching_cluster_idx": 6}, {"solution": "def move_zero(lst):\n # Initialize two pointers\n non_zero_index = 0\n\n # Iterate over the list\n for i in range(len(lst)):\n if lst[i] != 0:\n # Swap elements if the current element is not zero\n lst[non_zero_index], lst[i] = lst[i], lst[non_zero_index]\n non_zero_index += 1\n\n return lst", "matching_cluster_idx": 6}, {"solution": "def move_zero(lst):\n # Count the number of zeros in the list\n zero_count = lst.count(0)\n # Create a new list without the zeros\n result = [num for num in lst if num != 0]\n # Add the zeros at the end\n result.extend([0] * zero_count)\n return result", "matching_cluster_idx": 6}, {"solution": "def move_zero(lst):\n \"\"\"\n This function moves all zeroes in the given list to the end while preserving the order of non-zero elements.\n \n Parameters:\n lst (list): The input list containing integers.\n \n Returns:\n list: A list with all zeroes moved to the end.\n \"\"\"\n # Initialize a new list for non-zero elements\n non_zeroes = [x for x in lst if x != 0]\n \n # Count the number of zeroes\n zero_count = lst.count(0)\n \n # Extend the non_zeroes list with zeroes\n non_zeroes.extend([0] * zero_count)\n \n return non_zeroes", "matching_cluster_idx": 6}, {"solution": "def move_zero(lst):\n \"\"\"\n Move all zeroes in the list to the end while maintaining the order of non-zero elements.\n \n Parameters:\n lst (list): The list of integers to process.\n\n Returns:\n list: A new list with all zeroes moved to the end.\n \"\"\"\n # Count the number of zeros in the list\n zero_count = lst.count(0)\n # Create a list of non-zero elements\n non_zero_elements = [x for x in lst if x != 0]\n # Extend the list of non-zero elements with the same number of zeroes\n result = non_zero_elements + [0] * zero_count\n return result", "matching_cluster_idx": 6}, {"solution": "def move_zero(lst):\n \"\"\"\n Moves all zeroes in the list to the end while maintaining the order of non-zero elements.\n \n Parameters:\n lst (list): A list of integers.\n \n Returns:\n list: A list with all zeroes moved to the end.\n \"\"\"\n # Initialize two pointers\n non_zero_index = 0 # This will point to the next position to fill with a non-zero element\n\n # Traverse the list\n for i in range(len(lst)):\n if lst[i] != 0:\n # Swap the current element with the element at non_zero_index\n lst[non_zero_index], lst[i] = lst[i], lst[non_zero_index]\n # Move the non_zero_index forward\n non_zero_index += 1\n\n return lst", "matching_cluster_idx": 6}, {"solution": "def move_zero(lst):\n \"\"\"\n This function takes a list of numbers and moves all zeroes to the end\n while maintaining the order of non-zero elements.\n \n Parameters:\n lst (list): The input list containing numbers.\n \n Returns:\n list: A new list with all zeroes moved to the end.\n \"\"\"\n # List to store non-zero elements\n non_zero_elements = [num for num in lst if num != 0]\n \n # Count the number of zeroes in the list\n zero_count = lst.count(0)\n \n # Extend the non-zero list by appending zero_count zeros\n non_zero_elements.extend([0] * zero_count)\n \n return non_zero_elements", "matching_cluster_idx": 6}, {"solution": "def move_zero(arr):\n \"\"\"\n Moves all zeroes in the list to the end while maintaining the order of non-zero elements.\n \n :param arr: List of integers\n :return: List with zeroes moved to the end\n \"\"\"\n non_zero_elements = [num for num in arr if num != 0]\n zero_count = arr.count(0)\n return non_zero_elements + [0] * zero_count", "matching_cluster_idx": 6}, {"solution": "def move_zero(lst):\n \"\"\"\n This function takes a list and moves all zeroes to the end, maintaining the order of non-zero elements.\n \"\"\"\n # Create a new list for non-zero elements\n non_zeroes = [num for num in lst if num != 0]\n # Count the number of zeroes\n zero_count = lst.count(0)\n # Append zeroes at the end\n non_zeroes.extend([0] * zero_count)\n return non_zeroes", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n \"\"\"\n Function to move all zeroes in the list to the end while maintaining the order of non-zero elements.\n \n Parameters:\n nums (list): List of integers.\n\n Returns:\n list: List with zeroes moved to the end.\n \"\"\"\n # Two pointers approach\n zero_pos = 0 # This will keep track of the position to place the next non-zero element\n \n # Iterate over the list\n for i in range(len(nums)):\n if nums[i] != 0:\n # Swap the current element with the element at zero_pos\n nums[i], nums[zero_pos] = nums[zero_pos], nums[i]\n zero_pos += 1\n \n return nums", "matching_cluster_idx": 6}, {"solution": "def move_zero(lst):\n \"\"\"\n This function moves all zeroes to the end of the list while maintaining the order of non-zero elements.\n \"\"\"\n non_zeroes = [x for x in lst if x != 0]\n zeroes = [0] * (len(lst) - len(non_zeroes))\n return non_zeroes + zeroes", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n \"\"\"\n Moves all zeroes in the list 'nums' to the end, maintaining the order of non-zero elements.\n \n Parameters:\n nums (list): The input list of numbers.\n\n Returns:\n list: The modified list with all zeroes moved to the end.\n \"\"\"\n # Count the number of zeros in the list\n zero_count = nums.count(0)\n \n # Create a new list without zeros\n result = [num for num in nums if num != 0]\n \n # Append the zeros at the end\n result.extend([0] * zero_count)\n \n return result", "matching_cluster_idx": 6}]}, "Mbpp/633": {"dps": 94.3089430894309, "dps_norm": 50.0, "pass@1": 28.0, "profiled": [{"solution": "def pair_xor_Sum(arr, n):\n total_xor_sum = 0\n # Iterate over all pairs (i, j) with i < j\n for i in range(n):\n for j in range(i + 1, n):\n total_xor_sum += arr[i] ^ arr[j]\n return total_xor_sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(nums, n):\n \"\"\"\n Function to find the sum of XOR of all pairs of numbers in the given list `nums`.\n \n Parameters:\n nums (list): List of integers.\n n (int): Number of elements in the list `nums`.\n\n Returns:\n int: Sum of XOR of all unique pairs.\n \"\"\"\n total_xor_sum = 0\n \n # Iterate over all pairs (i, j) where i < j\n for i in range(n):\n for j in range(i + 1, n):\n total_xor_sum += nums[i] ^ nums[j]\n \n return total_xor_sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(lst, n):\n \"\"\"\n Calculate the sum of XOR for all pairs in the given list.\n \n Parameters:\n lst (list): The list of integers.\n n (int): The length of the list.\n \n Returns:\n int: The sum of XOR of all pairs in the list.\n \"\"\"\n xor_sum = 0\n for i in range(n):\n for j in range(i + 1, n):\n xor_sum += lst[i] ^ lst[j]\n return xor_sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(arr, n):\n \"\"\"\n Function to find the sum of xor of all pairs of numbers in the given list.\n \n Parameters:\n arr (list): List of integers.\n n (int): Length of the list.\n \n Returns:\n int: Sum of xor of all pairs of numbers.\n \"\"\"\n total_sum = 0\n for i in range(n):\n for j in range(i+1, n):\n total_sum += arr[i] ^ arr[j]\n return total_sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(arr, n):\n \"\"\"\n Calculate the sum of XOR of all pairs of numbers in the given list.\n \n Args:\n arr (list): The list of integers.\n n (int): The number of elements in the list.\n\n Returns:\n int: The sum of XOR of all pairs.\n \"\"\"\n xor_sum = 0\n for i in range(n):\n for j in range(i + 1, n):\n xor_sum += arr[i] ^ arr[j]\n return xor_sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(arr, n):\n \"\"\"\n Calculate the sum of XOR for all pairs in the list `arr`.\n\n :param arr: List of integers\n :param n: Number of elements in the list\n :return: Sum of XOR for all pairs\n \"\"\"\n total_sum = 0\n for i in range(n):\n for j in range(i + 1, n):\n total_sum += arr[i] ^ arr[j]\n return total_sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(arr, n):\n \"\"\"\n Function to calculate the sum of XOR of all pairs in the list.\n \n :param arr: List of integers.\n :param n: Number of elements in the list.\n :return: Sum of XOR of all pairs.\n \"\"\"\n sum_xor = 0\n # Iterate through all pairs (i, j) where 0 <= i < j < n\n for i in range(n):\n for j in range(i + 1, n):\n sum_xor += arr[i] ^ arr[j]\n return sum_xor", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(arr, n):\n \"\"\"\n Calculate the sum of XOR for all pairs in the array `arr` of size `n`.\n \n Parameters:\n arr (list): List of integers.\n n (int): Number of elements in the list `arr`.\n\n Returns:\n int: Sum of XOR for all pairs in the list.\n \"\"\"\n xor_sum = 0\n # Iterate over all pairs (i, j) with i < j\n for i in range(n):\n for j in range(i + 1, n):\n xor_sum += arr[i] ^ arr[j]\n \n return xor_sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(arr, n):\n \"\"\"\n This function calculates the sum of XOR for all unique pairs in the list 'arr'.\n \n Parameters:\n arr (list): A list of integers.\n n (int): The number of elements in the list (though it is redundant, as Python can find the length of the list itself).\n \n Returns:\n int: The sum of XOR for all unique pairs.\n \"\"\"\n \n # Initialize the sum of XOR to 0\n xor_sum = 0\n\n # Iterate through each unique pair in the array\n for i in range(n):\n for j in range(i + 1, n):\n # Calculate the XOR of the pair (arr[i], arr[j])\n xor_sum += arr[i] ^ arr[j]\n \n return xor_sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(lst, n):\n total_xor_sum = 0\n for i in range(n):\n for j in range(i + 1, n):\n total_xor_sum += lst[i] ^ lst[j]\n return total_xor_sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(nums, n):\n xor_sum = 0\n for i in range(n):\n for j in range(i + 1, n):\n xor_sum += nums[i] ^ nums[j]\n return xor_sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(arr, n):\n \"\"\"\n This function calculates the sum of XOR of all pairs of numbers in the given list `arr`.\n\n Parameters:\n arr (list): A list of integers.\n n (int): The number of elements in the list.\n\n Returns:\n int: The sum of XOR for all pairs in the list.\n \"\"\"\n sum_xor = 0\n # Go through all pairs (i, j) with i < j\n for i in range(n):\n for j in range(i + 1, n):\n sum_xor += arr[i] ^ arr[j]\n return sum_xor", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(arr, n):\n total_xor_sum = 0\n for i in range(n):\n for j in range(i + 1, n):\n total_xor_sum += arr[i] ^ arr[j]\n return total_xor_sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(nums, n):\n xor_sum = 0\n for i in range(n):\n for j in range(i + 1, n):\n xor_sum += nums[i] ^ nums[j]\n return xor_sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(lst, n):\n \"\"\"\n Function to find the sum of XOR of all pairs in the given list.\n\n :param lst: List of integers\n :param n: Number of elements in the list\n :return: Sum of XOR of all pairs\n \"\"\"\n xor_sum = 0\n for i in range(n):\n for j in range(i + 1, n):\n xor_sum += lst[i] ^ lst[j]\n return xor_sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(arr, n):\n \"\"\"\n Calculate the sum of XOR for all unique pairs in the list.\n\n Parameters:\n arr (list): List of integers.\n n (int): Number of elements in the list.\n\n Returns:\n int: Sum of XOR of all pairs.\n \"\"\"\n xor_sum = 0\n # Iterate through each pair (i, j) where i < j\n for i in range(n):\n for j in range(i + 1, n):\n xor_sum += arr[i] ^ arr[j]\n return xor_sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(nums, n):\n \"\"\"\n Calculate the sum of XOR for all pairs in the given list of numbers.\n \n :param nums: List of integers\n :param n: Number of elements in the list\n :return: Sum of XOR of all pairs\n \"\"\"\n xor_sum = 0\n for i in range(n):\n for j in range(i + 1, n):\n xor_sum += nums[i] ^ nums[j]\n return xor_sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(arr, n):\n \"\"\"\n This function takes a list 'arr' of size 'n' and returns the sum of the XOR\n of all pairs of numbers in the list.\n \"\"\"\n xor_sum = 0\n for i in range(n):\n for j in range(i + 1, n):\n xor_sum += arr[i] ^ arr[j]\n return xor_sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(arr, n):\n \"\"\"\n Function to calculate the sum of XOR of all pairs in the list.\n \n :param arr: List of integers\n :param n: Length of the list\n :return: Sum of XOR of all pairs\n \"\"\"\n xor_sum = 0\n for i in range(n):\n for j in range(i + 1, n):\n xor_sum += arr[i] ^ arr[j]\n return xor_sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(arr, n):\n \"\"\"\n Function to find the sum of XOR of all pairs of numbers in the given list.\n :param arr: List of integers\n :param n: Length of the list\n :return: Sum of XOR of all pairs\n \"\"\"\n xor_sum = 0\n \n # Calculate XOR for all pairs\n for i in range(n):\n for j in range(i + 1, n):\n xor_sum += arr[i] ^ arr[j]\n \n return xor_sum", "matching_cluster_idx": 2}]}, "Mbpp/644": {"dps": 81.59574468085106, "dps_norm": 81.33333333333333, "pass@1": 69.0, "profiled": [{"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n Reverse the elements of arr up to index k (exclusive).\n Elements after index k remain unchanged.\n \n Parameters:\n arr (list): The list to be partially reversed.\n k (int): The index up to which elements will be reversed.\n\n Returns:\n list: The modified list with elements reversed up to index k.\n \"\"\"\n # Check if k is greater than the length of the list\n # or less than 1, which means no reversal can take place\n if k > len(arr) or k < 1:\n return arr\n\n # Reverse the array up to the k-th position\n return arr[:k][::-1] + arr[k:]", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n # Reverse the segment of the array from the start to the k-th element\n arr[:k] = arr[:k][::-1]\n return arr", "matching_cluster_idx": 13}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n This function reverses the elements of the array `arr` up to the index `k-1`.\n \n Parameters:\n arr (list): The array to reverse.\n k (int): The position up to which the array should be reversed.\n \n Returns:\n list: The modified array with elements reversed up to position k.\n \"\"\"\n # Ensure k is not greater than the length of the array\n if k > len(arr):\n k = len(arr)\n \n # Reverse the portion of the array up to k\n arr[:k] = arr[:k][::-1]\n return arr", "matching_cluster_idx": 13}, {"solution": "def reverse_Array_Upto_K(arr, k):\n # Reverse the first k elements of the array\n if k > len(arr):\n k = len(arr) # Limit k to the length of the array if it exceeds it.\n return arr[:k][::-1] + arr[k:]", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n Reverse the array up to the k-th position (0-based index).\n \n Parameters:\n arr (list): The array to reverse.\n k (int): The position up to which to reverse the array.\n \n Returns:\n list: The modified array with the first k elements reversed.\n \"\"\"\n # Ensure k is within the valid range\n if k > len(arr):\n raise ValueError(\"k must be within the bounds of the array length\")\n \n # Reverse up to the k-th position\n arr[:k] = arr[:k][::-1]\n \n return arr", "matching_cluster_idx": 13}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n Reverses the elements of the array `arr` from the start up to, but not including, index `k`.\n \"\"\"\n if k > len(arr):\n k = len(arr)\n # Reverse the sublist from start to index k-1\n arr[:k] = arr[:k][::-1]\n return arr", "matching_cluster_idx": 13}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n Reverse an array up to a given position k.\n\n Parameters:\n arr (list): The list of elements to reverse.\n k (int): The position up to which the array should be reversed.\n\n Returns:\n list: The list with elements reversed up to position k.\n \"\"\"\n if k < 1 or k > len(arr):\n raise ValueError(\"k must be a valid position within the array length\")\n \n # Reverse the first k elements (0 to k-1) and leave the rest untouched\n reversed_part = arr[:k][::-1]\n remaining_part = arr[k:]\n \n return reversed_part + remaining_part", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n Reverse the array up to the k-th index (exclusive) and return the new array.\n\n :param arr: List[int] - The array to be partially reversed.\n :param k: int - The index up to which the array should be reversed.\n :return: List[int] - The array with elements reversed up to index k.\n \"\"\"\n # Check if k is within the valid range\n if k > len(arr) or k < 0:\n raise ValueError(\"k should be a valid index within the array length.\")\n\n # Reverse the portion of the array up to the k-th element\n return arr[:k][::-1] + arr[k:]", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n This function reverses the elements of the array `arr` up to the index `k-1`.\n \n Parameters:\n arr (list): The list to be partially reversed.\n k (int): The position up to which the elements should be reversed (1-based index).\n \n Returns:\n list: A new list where the elements from index 0 to `k-1` are reversed, and\n the remaining elements stay in the same order.\n \"\"\"\n if k <= 0 or k > len(arr):\n raise ValueError(\"k must be a positive integer within the length of the array\")\n \n # Reverse the sub-array from start to k-1\n sub_array = arr[:k][::-1]\n # Keep the rest of the array as is\n rest_array = arr[k:]\n \n # Combine the reversed part and the rest of the array\n return sub_array + rest_array", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n This function takes an array 'arr' and an integer 'k', and reverses the elements of the array up to the index 'k-1'.\n \n Parameters:\n arr (list): The list of elements to be partially reversed.\n k (int): The index (1-based) up to which the list should be reversed.\n \n Returns:\n list: A new list with elements reversed up to the position 'k'.\n \"\"\"\n # Perform the reversal up to index k-1 (1-based index -> 0-based index)\n reversed_part = arr[:k][::-1]\n rest_part = arr[k:]\n return reversed_part + rest_part", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n Reverses the elements of the array up to the k-th position (0-based index).\n\n Parameters:\n arr (list): The list of elements to be reversed.\n k (int): The position up to which the array should be reversed (inclusive).\n\n Returns:\n list: The array with elements reversed up to the k-th position.\n \"\"\"\n # Reverse the portion of the array from index 0 to k-1\n arr[:k] = arr[:k][::-1]\n return arr", "matching_cluster_idx": 13}, {"solution": "def reverse_Array_Upto_K(arr, k):\n # Check if k is a valid index\n if k < 1 or k > len(arr):\n raise ValueError(\"k must be within the range of the array indices and greater than 0.\")\n \n # Reverse the array up to index k-1\n return arr[:k][::-1] + arr[k:]", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n Reverse the elements of the array up to the position k.\n \n Parameters:\n arr (list): The list of elements to be reversed.\n k (int): The position up to which elements need to be reversed.\n \n Returns:\n list: The array with elements reversed up to position k.\n \"\"\"\n # Check if k is within the valid range\n if k < 0 or k > len(arr):\n raise ValueError(\"k should be in the range from 0 to the length of the array.\")\n \n # Reverse the portion of the array up to index k (exclusive)\n return arr[:k][::-1] + arr[k:]", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n Reverses the elements of the array `arr` up to the given position `k`.\n \n Parameters:\n arr (list): The input array to be partially reversed.\n k (int): The position up to which the array should be reversed.\n \n Returns:\n list: The array with elements reversed up to position `k`.\n \"\"\"\n if k > len(arr) or k < 0:\n raise ValueError(\"k should be within the range of the array length and non-negative.\")\n \n # Reverse the portion of the array from start to k (exclusive)\n return arr[:k][::-1] + arr[k:]\narr = [1, 2, 3, 4, 5, 6]\nk = 4", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n Reverses the elements of the array `arr` up to the position `k`.\n \n Parameters:\n arr (list): The array of elements to be reversed.\n k (int): The position up to which the array should be reversed.\n \n Returns:\n list: The array with elements reversed up to position `k`.\n \"\"\"\n if k > len(arr) or k < 0:\n raise ValueError(\"Position k is out of bounds of the array length.\")\n \n # Reverse the elements from the start of the array to the k-th element\n arr[:k] = arr[:k][::-1]\n \n return arr", "matching_cluster_idx": 13}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n Reverses the elements of the array 'arr' up to index 'k-1'.\n \n Parameters:\n arr (list): The list of elements to be reversed.\n k (int): The position up to which elements will be reversed.\n \n Returns:\n list: The modified list with elements reversed up to index 'k-1'.\n \"\"\"\n if k > len(arr) or k <= 0:\n raise ValueError(\"k should be within the range of the array length and greater than 0.\")\n \n # Reverse the sublist from start up to k\n arr[:k] = arr[:k][::-1]\n return arr", "matching_cluster_idx": 13}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n Reverses the array up to the given position k.\n \n Parameters:\n arr (list): The list of elements to be reversed.\n k (int): The position up to which the array should be reversed.\n \n Returns:\n list: The list with elements reversed up to position k.\n \"\"\"\n # Ensure k is within the bounds of the array\n if k < 0 or k > len(arr):\n raise ValueError(\"The value of k is out of bounds\")\n \n # Reverse the sub-array from 0 to k-1\n arr[:k] = arr[:k][::-1]\n return arr", "matching_cluster_idx": 13}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n Reverses the elements of the array up to the k-th position.\n \n Parameters:\n arr (list): The list of elements to be reversed.\n k (int): The position up to which the array should be reversed.\n \n Returns:\n list: The array with elements reversed up to the k-th position.\n \"\"\"\n if k <= 0:\n return arr # No need to reverse anything if k is 0 or negative\n # Reverse the segment of the array from start to k (exclusive)\n return arr[:k][::-1] + arr[k:]", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n Reverses an array up to a given position k (0-based index).\n \n Parameters:\n arr (list): The array to reverse.\n k (int): The position up to which the array will be reversed.\n \n Returns:\n list: The array with the first k elements reversed.\n \"\"\"\n # Ensure k is within the bounds of the array\n if k <= 0:\n return arr # No need to reverse if k is <= 0\n if k > len(arr):\n k = len(arr) # If k is greater than length of arr, reverse the entire array\n\n # Reverse the array up to the k-th position\n return arr[:k][::-1] + arr[k:]", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n Reverses the elements of the array arr up to the index k-1.\n \n Parameters:\n arr (list): The input array.\n k (int): The position up to which the array should be reversed.\n\n Returns:\n list: The array with its elements reversed up to position k.\n \"\"\"\n if k <= 0:\n # If k is less than or equal to zero, return the original array\n return arr\n if k > len(arr):\n # If k is greater than the length of the array, adjust it to the length of the array\n k = len(arr)\n \n # Reverse the segment from the start of the array to the k-th position\n reversed_part = arr[:k][::-1]\n # Leave the rest of the array unchanged\n remaining_part = arr[k:]\n \n # Combine the reversed part with the remaining part\n return reversed_part + remaining_part\narr = [1, 2, 3, 4, 5, 6]\nk = 4", "matching_cluster_idx": 10}]}, "Mbpp/720": {"dps": 93.84615384615384, "dps_norm": 98.0, "pass@1": 100.0, "profiled": [{"solution": "def add_dict_to_tuple(original_tuple, dictionary):\n \"\"\"\n Adds a dictionary to the end of a tuple.\n\n Parameters:\n - original_tuple (tuple): The original tuple to which the dictionary will be added.\n - dictionary (dict): The dictionary to add to the tuple.\n\n Returns:\n - tuple: A new tuple containing the original elements followed by the dictionary.\n \"\"\"\n # Tuples are immutable, so we concatenate the existing tuple with a single-element tuple containing the dictionary\n return original_tuple + (dictionary,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(tup, dictionary):\n \"\"\"\n Adds a dictionary to a tuple. The resulting tuple contains all the elements of the original tuple,\n followed by the dictionary as the last element.\n\n Parameters:\n tup (tuple): The original tuple\n dictionary (dict): The dictionary to add to the tuple\n\n Returns:\n tuple: A new tuple with the dictionary added\n \"\"\"\n # Convert the tuple to a list, add the dictionary, and convert back to a tuple\n return tup + (dictionary,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(tup, dictionary):\n \"\"\"\n Adds a dictionary to the end of a tuple and returns the new tuple.\n\n Parameters:\n tup (tuple): The original tuple.\n dictionary (dict): The dictionary to add to the tuple.\n\n Returns:\n tuple: A new tuple with the dictionary added.\n \"\"\"\n # Convert the tuple to a list, add the dictionary, and convert back to a tuple\n return tup + (dictionary,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(tup, dictionary):\n \"\"\"\n This function adds a dictionary to the end of a tuple and returns the new tuple.\n\n :param tup: The original tuple.\n :param dictionary: The dictionary to add to the tuple.\n :return: A new tuple with the dictionary added.\n \"\"\"\n return tup + (dictionary,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(tup, dictionary):\n # Since tuples are immutable, we cannot modify them in place.\n # However, we can create a new tuple that includes both the original tuple and the dictionary.\n return tup + (dictionary,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(original_tuple, dictionary):\n \"\"\"\n Add a dictionary to the end of a given tuple.\n\n Args:\n original_tuple (tuple): The original tuple.\n dictionary (dict): The dictionary to be added to the tuple.\n\n Returns:\n tuple: The new tuple with the dictionary added.\n \"\"\"\n if not isinstance(original_tuple, tuple):\n raise TypeError(\"The first argument must be a tuple.\")\n if not isinstance(dictionary, dict):\n raise TypeError(\"The second argument must be a dictionary.\")\n \n # Add the dictionary to the tuple by creating a new tuple\n new_tuple = original_tuple + (dictionary,)\n return new_tuple", "matching_cluster_idx": 3}, {"solution": "def add_dict_to_tuple(tup, dct):\n \"\"\"\n Add a dictionary to the end of the given tuple and return the new tuple.\n \n :param tup: The original tuple\n :param dct: The dictionary to add\n :return: A new tuple with the dictionary added at the end\n \"\"\"\n # Tuples are immutable, but we can concatenate them with other tuples.\n # Convert the dictionary to a tuple with a single element and concatenate it to the original tuple.\n return tup + (dct,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(original_tuple, dictionary):\n \"\"\"\n This function takes a tuple and a dictionary as inputs,\n and returns a new tuple with the dictionary added to the original tuple.\n \n :param original_tuple: A tuple to which the dictionary should be added\n :param dictionary: A dictionary to be added to the tuple\n :return: A new tuple containing the original elements and the dictionary\n \"\"\"\n return original_tuple + (dictionary,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(original_tuple, dictionary_to_add):\n \"\"\"\n Adds a dictionary to the end of a tuple and returns a new tuple.\n \n Parameters:\n - original_tuple (tuple): The original tuple.\n - dictionary_to_add (dict): The dictionary to add to the tuple.\n \n Returns:\n - tuple: A new tuple with the dictionary appended.\n \"\"\"\n # Tuples are immutable, so we need to create a new tuple.\n # We can concatenate the original tuple with a new tuple containing the dictionary.\n return original_tuple + (dictionary_to_add,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(t: tuple, d: dict) -> tuple:\n \"\"\"\n This function adds a dictionary to the end of a tuple and returns the resulting tuple.\n \n :param t: A tuple to which the dictionary will be added.\n :param d: A dictionary that will be added to the tuple.\n :return: A new tuple with the dictionary added to the original tuple.\n \"\"\"\n # Since tuples are immutable, we cannot modify them directly.\n # We will concatenate the tuple with a single-item tuple containing the dictionary.\n return t + (d,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(original_tuple, dictionary):\n # Check if the input is actually a tuple\n if not isinstance(original_tuple, tuple):\n raise TypeError(\"The first argument must be a tuple.\")\n # Check if the input is actually a dictionary\n if not isinstance(dictionary, dict):\n raise TypeError(\"The second argument must be a dictionary.\")\n \n # Convert the dictionary to a tuple and concatenate\n return original_tuple + (dictionary,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(tpl, dct):\n \"\"\"\n This function takes a tuple and a dictionary as input,\n and returns a new tuple with the dictionary added as the last element.\n \"\"\"\n if not isinstance(tpl, tuple):\n raise TypeError(\"First argument must be a tuple\")\n if not isinstance(dct, dict):\n raise TypeError(\"Second argument must be a dictionary\")\n \n # Create a new tuple by adding the dictionary to the existing tuple\n return tpl + (dct,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(input_tuple, dictionary):\n \"\"\"\n Add a dictionary to the end of a tuple.\n\n :param input_tuple: Tuple to which the dictionary will be added\n :param dictionary: Dictionary to add to the tuple\n :return: New tuple with the dictionary added\n \"\"\"\n # Use tuple concatenation to add the dictionary\n return input_tuple + (dictionary,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(tup, dictionary):\n \"\"\"\n Adds a dictionary to the end of a given tuple.\n\n Parameters:\n tup (tuple): The original tuple.\n dictionary (dict): The dictionary to be added to the tuple.\n\n Returns:\n tuple: A new tuple with the dictionary added at the end.\n \"\"\"\n # Create a new tuple by concatenating the original tuple and a single-element tuple containing the dictionary\n new_tuple = tup + (dictionary,)\n return new_tuple", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(original_tuple, dictionary):\n \"\"\"\n Add a dictionary to the end of a tuple.\n\n Parameters:\n original_tuple (tuple): The original tuple.\n dictionary (dict): The dictionary to add to the tuple.\n\n Returns:\n tuple: A new tuple with the dictionary added at the end.\n \"\"\"\n # Tuples are immutable, so we can't modify them directly. \n # Instead, we create a new tuple by concatenating the original tuple with a single-element tuple containing the dictionary.\n return original_tuple + (dictionary,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(original_tuple, dictionary):\n \"\"\"\n Add a dictionary to a tuple.\n \n Parameters:\n original_tuple (tuple): The original tuple to which the dictionary will be added.\n dictionary (dict): The dictionary to add to the tuple.\n\n Returns:\n tuple: A new tuple with the dictionary added at the end.\n \"\"\"\n # Tuples are immutable, so we create a new tuple by concatenation\n return original_tuple + (dictionary,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(original_tuple, dictionary):\n # Convert the tuple to a list to allow appending\n temp_list = list(original_tuple)\n # Append the dictionary to the list\n temp_list.append(dictionary)\n # Convert back to a tuple\n result_tuple = tuple(temp_list)\n return result_tuple", "matching_cluster_idx": 3}, {"solution": "def add_dict_to_tuple(input_tuple, input_dict):\n # Convert the dictionary to a tuple containing just the dictionary.\n dict_tuple = (input_dict,)\n # Concatenate the original tuple with the dictionary tuple.\n result_tuple = input_tuple + dict_tuple\n return result_tuple", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(input_tuple, input_dict):\n \"\"\"\n Add a dictionary to the end of a tuple.\n \n :param input_tuple: The original tuple\n :param input_dict: The dictionary to add\n :return: A new tuple with the dictionary added at the end\n \"\"\"\n if not isinstance(input_tuple, tuple):\n raise TypeError(\"The first argument must be a tuple\")\n \n if not isinstance(input_dict, dict):\n raise TypeError(\"The second argument must be a dictionary\")\n \n return input_tuple + (input_dict,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(original_tuple, dictionary):\n \"\"\"\n This function takes a tuple and a dictionary as arguments,\n and returns a new tuple with the dictionary appended to the original tuple.\n \n :param original_tuple: The original tuple to which the dictionary should be added.\n :param dictionary: The dictionary to add to the tuple.\n :return: A new tuple with the dictionary added at the end.\n \"\"\"\n # Convert the dictionary to a single-item tuple and concatenate with the original tuple\n return original_tuple + (dictionary,)", "matching_cluster_idx": 4}]}, "Mbpp/725": {"dps": 70.60109289617486, "dps_norm": 73.75, "pass@1": 99.0, "profiled": [{"solution": "def extract_quotation(s):\n \"\"\"\n This function extracts values between quotation marks \" \" from the given string.\n \n :param s: A string potentially containing words or phrases enclosed in double quotation marks\n :return: A list of strings that were enclosed in double quotation marks\n \"\"\"\n import re\n # Use regex to find all occurrences of text between double quotes\n return re.findall(r'\"(.*?)\"', s)", "matching_cluster_idx": 5}, {"solution": "def extract_quotation(s):\n # Using regular expressions to find all quoted parts\n import re\n return re.findall(r'\"(.*?)\"', s)", "matching_cluster_idx": 5}, {"solution": "def extract_quotation(s):\n import re\n # Use regular expression to find all occurrences between quotes\n return re.findall(r'\"(.*?)\"', s)", "matching_cluster_idx": 5}, {"solution": "def extract_quotation(text):\n import re\n # Use a regular expression to find all content inside quotation marks\n return re.findall(r'\"(.*?)\"', text)", "matching_cluster_idx": 5}, {"solution": "def extract_quotation(input_string):\n import re\n # Use regex to find all substrings within quotation marks\n pattern = r'\"(.*?)\"'\n return re.findall(pattern, input_string)\ninput_string = 'Cortex \"A53\" Based \"multi\" tasking \"Processor\"'", "matching_cluster_idx": 4}, {"solution": "import re\ndef extract_quotation(s):\n \"\"\"\n Extract values between quotation marks \" \" from the given string.\n \n :param s: A string that may contain quoted substrings.\n :return: A list of substrings found between quotation marks.\n \"\"\"\n # Use regular expression to find all occurrences of text within quotes\n return re.findall(r'\"(.*?)\"', s)", "matching_cluster_idx": 5}, {"solution": "def extract_quotation(s):\n import re\n # Use a regular expression to find all instances of text between quotation marks\n return re.findall(r'\"(.*?)\"', s)", "matching_cluster_idx": 5}, {"solution": "def extract_quotation(input_string):\n \"\"\"\n Extract values between quotation marks from the given string.\n\n :param input_string: The input string containing quoted text.\n :return: A list of strings extracted from within the quotation marks.\n \"\"\"\n import re\n\n # Use a regular expression to find all occurrences of text within quotes\n quoted_values = re.findall(r'\"(.*?)\"', input_string)\n\n return quoted_values", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(s):\n # Use regex to find all substrings enclosed in quotation marks\n return re.findall(r'\"(.*?)\"', s)", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(s):\n \"\"\"\n This function extracts and returns a list of substrings found between double quotation marks in the input string.\n\n :param s: A string that may contain substrings enclosed in double quotes.\n :return: A list of strings found between the double quotes.\n \"\"\"\n return re.findall(r'\"(.*?)\"', s)", "matching_cluster_idx": 5}, {"solution": "def extract_quotation(s):\n \"\"\"\n Extract values between quotation marks in the given string.\n\n Parameters:\n s (str): The input string containing quoted words.\n\n Returns:\n list: A list of words found between quotation marks.\n \"\"\"\n import re\n # Use a regular expression to find all text enclosed in quotation marks\n return re.findall(r'\"(.*?)\"', s)", "matching_cluster_idx": 5}, {"solution": "def extract_quotation(text):\n \"\"\"\n Extracts and returns a list of substrings that are enclosed in double quotation marks from the given text.\n\n :param text: A string containing substrings enclosed in double quotation marks.\n :return: A list of substrings that are enclosed in double quotation marks.\n \"\"\"\n import re\n # Regular expression pattern to match text between double quotes\n pattern = r'\"(.*?)\"'\n # Find all matches using the regex pattern\n matches = re.findall(pattern, text)\n return matches", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(s):\n \"\"\"\n Extracts and returns all substrings enclosed in double quotes from the input string.\n \n Args:\n s (str): The input string from which to extract substrings.\n \n Returns:\n list: A list of substrings found within double quotes.\n \"\"\"\n # Use regular expression to find all substrings within double quotes\n return re.findall(r'\"(.*?)\"', s)", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(s):\n \"\"\"\n Extracts and returns all the values between quotation marks from the input string.\n\n :param s: A string potentially containing substrings enclosed in quotation marks.\n :return: A list of substrings found between quotation marks.\n \"\"\"\n # Use a regular expression to find all the parts of the string that are between quotes\n return re.findall(r'\"(.*?)\"', s)", "matching_cluster_idx": 5}, {"solution": "def extract_quotation(s):\n import re\n # Use regex to find all text between quotation marks\n return re.findall(r'\"(.*?)\"', s)", "matching_cluster_idx": 5}, {"solution": "def extract_quotation(s):\n \"\"\"\n Extracts and returns a list of substrings found between quotation marks in the given string.\n \n Args:\n s (str): The input string containing quoted substrings.\n\n Returns:\n list: A list of substrings that were found between quotation marks.\n \"\"\"\n import re\n return re.findall(r'\"(.*?)\"', s)", "matching_cluster_idx": 5}, {"solution": "def extract_quotation(s):\n \"\"\"\n Extracts and returns the list of substrings that are found between\n double quotation marks in the input string `s`.\n \n Parameters:\n s (str): The input string from which to extract quoted substrings.\n \n Returns:\n list: A list of strings that were between double quotation marks in `s`.\n \"\"\"\n import re\n # Use regular expression to find all substrings enclosed in double quotes\n return re.findall(r'\"(.*?)\"', s)", "matching_cluster_idx": 5}, {"solution": "def extract_quotation(input_string):\n import re\n # Use regular expression to find all substrings enclosed in double quotes\n return re.findall(r'\"(.*?)\"', input_string)", "matching_cluster_idx": 5}, {"solution": "def extract_quotation(text):\n import re\n # Use a regular expression to find all text within quotes\n return re.findall(r'\"(.*?)\"', text)", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(s):\n \"\"\"\n Extracts and returns a list of substrings found between\n double quotes in the input string.\n\n :param s: A string potentially containing quoted substrings\n :return: A list of substrings found between double quotes\n \"\"\"\n # Use a regular expression to find all quoted substrings\n return re.findall(r'\"(.*?)\"', s)", "matching_cluster_idx": 4}]}, "Mbpp/732": {"dps": 82.28682170542636, "dps_norm": 94.5, "pass@1": 100.0, "profiled": [{"solution": "def replace_specialchar(input_string):\n \"\"\"\n This function takes a string as input and replaces all occurrences of spaces, commas, or dots with a colon.\n :param input_string: str\n :return: str\n \"\"\"\n return input_string.replace(' ', ':').replace(',', ':').replace('.', ':')", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(text):\n # Replace spaces, commas, and dots with a colon\n for char in [' ', ',', '.']:\n text = text.replace(char, ':')\n return text", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(text):\n \"\"\"\n Replace all occurrences of spaces, commas, or dots in the input string with a colon.\n \n Parameters:\n text (str): The input string to be transformed.\n \n Returns:\n str: The transformed string with the specified characters replaced by a colon.\n \"\"\"\n # Replace spaces, commas, and dots with a colon\n return text.replace(' ', ':').replace(',', ':').replace('.', ':')", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(input_string):\n # Define a translation table where spaces, commas, and dots are replaced with colons\n translation_table = str.maketrans(' ,.', ':::')\n # Use the translation table to replace characters in the input string\n return input_string.translate(translation_table)", "matching_cluster_idx": 8}, {"solution": "def replace_specialchar(s):\n \"\"\"\n Replaces all occurrences of spaces, commas, or dots with a colon.\n\n Args:\n s (str): The input string.\n\n Returns:\n str: The modified string with spaces, commas, and dots replaced by colons.\n \"\"\"\n # Define the characters to replace\n chars_to_replace = \" ,.\"\n\n # Create a translation table mapping each character to a colon\n translation_table = str.maketrans(chars_to_replace, \":\" * len(chars_to_replace))\n\n # Use the translation table to replace the characters in the string\n return s.translate(translation_table)", "matching_cluster_idx": 8}, {"solution": "def replace_specialchar(text):\n \"\"\"\n Replaces all occurrences of spaces, commas, or dots in the input text with a colon.\n\n Args:\n text (str): The input string where replacements are to be made.\n\n Returns:\n str: The modified string with spaces, commas, and dots replaced by colons.\n \"\"\"\n # We can use str.replace method or regular expressions for this. \n # Using replace method for each character as it is straightforward for few characters.\n return text.replace(' ', ':').replace(',', ':').replace('.', ':')", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(text):\n \"\"\"\n Replace all occurrences of spaces, commas, or dots in the input text with a colon.\n\n :param text: The string to process.\n :return: A new string with specified characters replaced by a colon.\n \"\"\"\n # Define the characters to be replaced\n special_chars = [' ', ',', '.']\n \n # Replace each special character with a colon\n for char in special_chars:\n text = text.replace(char, ':')\n \n return text", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(s):\n \"\"\"\n Replaces all occurrences of spaces, commas, or dots in the input string with a colon.\n \"\"\"\n return s.replace(' ', ':').replace(',', ':').replace('.', ':')", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(text):\n \"\"\"\n Replaces all occurrences of spaces, commas, or dots in the input text with a colon.\n \"\"\"\n # Use the str.replace method for each character to be replaced\n return text.replace(' ', ':').replace(',', ':').replace('.', ':')", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(text):\n # Define the characters to replace\n characters_to_replace = [' ', ',', '.']\n # Iterate over each character in the list and replace them with a colon\n for char in characters_to_replace:\n text = text.replace(char, ':')\n return text", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(s: str) -> str:\n # Using str.replace and chaining to replace spaces, commas, and dots with colons\n return s.replace(' ', ':').replace(',', ':').replace('.', ':')", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(text):\n \"\"\"\n Replaces all occurrences of spaces, commas, or dots in the input text with a colon.\n \n Args:\n text (str): The string in which the replacements will occur.\n \n Returns:\n str: The modified string with spaces, commas, and dots replaced by colons.\n \"\"\"\n # Replace spaces, commas, and dots using str.replace in sequence\n text = text.replace(' ', ':')\n text = text.replace(',', ':')\n text = text.replace('.', ':')\n return text", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(text):\n \"\"\"\n Replaces all occurrences of spaces, commas, or dots in the given text with a colon.\n\n Parameters:\n - text (str): The input string to process.\n\n Returns:\n - str: The processed string with spaces, commas, and dots replaced by colons.\n \"\"\"\n # Define the characters to replace\n special_chars = ' ,.'\n \n # Create a translation table\n translation_table = str.maketrans(special_chars, ':::')\n\n # Return the translated text\n return text.translate(translation_table)", "matching_cluster_idx": 8}, {"solution": "def replace_specialchar(text):\n \"\"\"\n Replace all occurrences of spaces, commas, or dots in the input string with a colon.\n \n Args:\n text (str): The input string.\n \n Returns:\n str: The modified string with spaces, commas, and dots replaced by a colon.\n \"\"\"\n # Define the characters to be replaced\n special_chars = ' ,.'\n \n # Use a list comprehension to build a new string with replacements\n result = ''.join([':' if char in special_chars else char for char in text])\n \n return result", "matching_cluster_idx": 5}, {"solution": "def replace_specialchar(text):\n # Replace spaces, commas, and dots with a colon\n return text.replace(' ', ':').replace(',', ':').replace('.', ':')", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(s):\n \"\"\"\n Replace all occurrences of spaces, commas, or dots with a colon.\n \n Parameters:\n s (str): The input string.\n \n Returns:\n str: The modified string with spaces, commas, and dots replaced by colons.\n \"\"\"\n return s.replace(' ', ':').replace(',', ':').replace('.', ':')", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(text):\n # Replace spaces, commas, and dots with colons\n return text.replace(' ', ':').replace(',', ':').replace('.', ':')", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(text):\n \"\"\"\n Replaces all occurrences of spaces, commas, or dots in the input text with a colon.\n\n Parameters:\n text (str): The input text where characters need to be replaced.\n\n Returns:\n str: The modified text with spaces, commas, and dots replaced by colons.\n \"\"\"\n return text.replace(' ', ':').replace(',', ':').replace('.', ':')", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(text: str) -> str:\n # Use str.replace to replace spaces, commas, and dots with colons\n return text.replace(' ', ':').replace(',', ':').replace('.', ':')", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(text):\n \"\"\"\n Replace all occurrences of spaces, commas, or dots with a colon.\n \n Parameters:\n text (str): The input string to process.\n \n Returns:\n str: The modified string with spaces, commas, or dots replaced by colons.\n \"\"\"\n # Define characters to be replaced\n special_chars = \" ,.\"\n \n # Use a generator expression within join to replace each character\n result = ''.join(':' if char in special_chars else char for char in text)\n \n return result", "matching_cluster_idx": 5}]}, "Mbpp/740": {"dps": 84.45454545454545, "dps_norm": 68.33333333333334, "pass@1": 100.0, "profiled": [{"solution": "def tuple_to_dict(input_tuple):\n \"\"\"\n Converts a given tuple to a dictionary using adjacent elements.\n \n Args:\n input_tuple (tuple): The input tuple containing an even number of elements.\n \n Returns:\n dict: A dictionary where each pair of adjacent elements in the tuple \n forms a key-value pair in the dictionary.\n \"\"\"\n # Initialize an empty dictionary\n result_dict = {}\n \n # Iterate over the tuple using a step of 2\n for i in range(0, len(input_tuple), 2):\n # Assign the first element as key and the next element as value\n key = input_tuple[i]\n value = input_tuple[i + 1]\n # Add the key-value pair to the dictionary\n result_dict[key] = value\n \n return result_dict", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(tup):\n \"\"\"\n Converts a tuple into a dictionary using adjacent elements as key-value pairs.\n \n :param tup: Tuple to be converted\n :return: Dictionary with adjacent elements as key-value pairs\n \"\"\"\n if len(tup) % 2 != 0:\n raise ValueError(\"The length of the tuple must be even to form key-value pairs.\")\n \n return {tup[i]: tup[i+1] for i in range(0, len(tup), 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(tpl):\n \"\"\"\n Convert a tuple to a dictionary using adjacent elements as key-value pairs.\n \n Arguments:\n tpl -- A tuple with an even number of elements.\n \n Returns:\n A dictionary where every two adjacent elements in the tuple form a key-value pair.\n \"\"\"\n if len(tpl) % 2 != 0:\n raise ValueError(\"The tuple should have an even number of elements.\")\n \n return {tpl[i]: tpl[i+1] for i in range(0, len(tpl), 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(tpl):\n \"\"\"\n Convert the given tuple to a key-value dictionary using adjacent elements.\n \n Args:\n tpl (tuple): A tuple with an even number of elements.\n\n Returns:\n dict: A dictionary created from adjacent elements of the tuple.\n \"\"\"\n # Check if the length of the tuple is even\n if len(tpl) % 2 != 0:\n raise ValueError(\"The tuple must have an even number of elements.\")\n\n # Create a dictionary using adjacent elements as key-value pairs\n result = {}\n for i in range(0, len(tpl), 2):\n result[tpl[i]] = tpl[i + 1]\n \n return result", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(tpl):\n \"\"\"\n Convert the given tuple to a key-value dictionary using adjacent elements.\n\n :param tpl: A tuple containing an even number of elements\n :return: A dictionary with adjacent elements as key-value pairs\n \"\"\"\n # Ensure the tuple has an even number of elements\n if len(tpl) % 2 != 0:\n raise ValueError(\"Tuple length must be even to convert to a dictionary.\")\n \n # Use dictionary comprehension to pair elements\n return {tpl[i]: tpl[i + 1] for i in range(0, len(tpl), 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(tup):\n \"\"\"\n Convert the given tuple to a dictionary using adjacent elements as key-value pairs.\n\n :param tup: A tuple with an even number of elements.\n :return: A dictionary created by using adjacent elements as key-value pairs.\n \"\"\"\n # Ensure the tuple length is even\n if len(tup) % 2 != 0:\n raise ValueError(\"The tuple must have an even number of elements.\")\n\n # Create dictionary by zipping elements in pairs\n return dict(zip(tup[::2], tup[1::2]))", "matching_cluster_idx": 8}, {"solution": "def tuple_to_dict(tpl):\n \"\"\"\n Converts a tuple into a dictionary using adjacent elements as key-value pairs.\n \n :param tpl: A tuple with an even number of elements.\n :return: A dictionary constructed from the tuple's adjacent elements.\n \"\"\"\n if len(tpl) % 2 != 0:\n raise ValueError(\"Tuple must contain an even number of elements to form key-value pairs.\")\n\n return {tpl[i]: tpl[i + 1] for i in range(0, len(tpl), 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(tup):\n \"\"\"\n Convert the given tuple to a key-value dictionary using adjacent elements.\n \n :param tup: A tuple with an even number of elements.\n :return: A dictionary mapping adjacent elements to each other.\n \"\"\"\n if len(tup) % 2 != 0:\n raise ValueError(\"The input tuple must have an even number of elements.\")\n \n # Create the dictionary using a dictionary comprehension\n result = {tup[i]: tup[i + 1] for i in range(0, len(tup), 2)}\n \n return result", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(tup):\n \"\"\"\n Convert the given tuple to a key-value dictionary using adjacent elements.\n \n :param tup: A tuple where the length is expected to be even.\n :return: A dictionary with adjacent elements as key-value pairs.\n \"\"\"\n if len(tup) % 2 != 0:\n raise ValueError(\"The input tuple must have an even number of elements.\")\n\n return {tup[i]: tup[i + 1] for i in range(0, len(tup), 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(t):\n \"\"\"\n Converts a tuple to a dictionary using adjacent elements as key-value pairs.\n\n Parameters:\n t (tuple): A tuple with an even number of elements.\n\n Returns:\n dict: A dictionary where each adjacent pair of elements in the tuple becomes a key-value pair.\n \"\"\"\n if len(t) % 2 != 0:\n raise ValueError(\"The tuple must contain an even number of elements.\")\n \n result_dict = {}\n for i in range(0, len(t), 2):\n key = t[i]\n value = t[i+1]\n result_dict[key] = value\n \n return result_dict", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(tup):\n # Initialize an empty dictionary\n result = {}\n \n # Iterate over the tuple in steps of 2\n for i in range(0, len(tup) - 1, 2):\n # Add the pair as a key-value to the dictionary\n result[tup[i]] = tup[i + 1]\n \n return result", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(tup):\n # Initialize an empty dictionary\n result = {}\n \n # Iterate over the tuple with step size 2\n for i in range(0, len(tup) - 1, 2):\n # Assign the i-th element as key and the (i+1)-th element as value\n result[tup[i]] = tup[i + 1]\n \n return result", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(tup):\n \"\"\"\n Convert the given tuple to a key-value dictionary using adjacent elements.\n \n Args:\n tup (tuple): A tuple where each pair of elements represents a key-value pair.\n \n Returns:\n dict: A dictionary constructed from the tuple's adjacent elements.\n \"\"\"\n if len(tup) % 2 != 0:\n raise ValueError(\"The input tuple must have an even number of elements.\")\n \n return {tup[i]: tup[i+1] for i in range(0, len(tup), 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(tup):\n \"\"\"\n Convert the given tuple to a dictionary using adjacent elements.\n \n Parameters:\n tup (tuple): A tuple where the number of elements is even.\n \n Returns:\n dict: A dictionary with adjacent elements as key-value pairs.\n \"\"\"\n if len(tup) % 2 != 0:\n raise ValueError(\"Tuple must contain an even number of elements.\")\n \n return {tup[i]: tup[i + 1] for i in range(0, len(tup), 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(t):\n \"\"\"\n Convert the given tuple to a key-value dictionary using adjacent elements.\n\n :param t: Tuple of even length\n :return: Dictionary with keys and values from adjacent elements\n \"\"\"\n if len(t) % 2 != 0:\n raise ValueError(\"Tuple must have an even number of elements\")\n \n return {t[i]: t[i+1] for i in range(0, len(t), 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(input_tuple):\n \"\"\"\n Convert a given tuple to a dictionary using adjacent elements as key-value pairs.\n \n :param input_tuple: A tuple with even number of elements\n :return: A dictionary created from the tuple where each pair of adjacent elements \n forms a key-value pair\n \"\"\"\n if len(input_tuple) % 2 != 0:\n raise ValueError(\"The input tuple must have an even number of elements.\")\n \n # Create a dictionary using a dictionary comprehension\n result_dict = {input_tuple[i]: input_tuple[i+1] for i in range(0, len(input_tuple), 2)}\n \n return result_dict", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(input_tuple):\n \"\"\"\n Convert a tuple into a dictionary using adjacent elements as key-value pairs.\n Assumes the tuple has an even number of elements.\n \n Parameters:\n input_tuple (tuple): The tuple to convert.\n \n Returns:\n dict: A dictionary with keys and values derived from adjacent tuple elements.\n \"\"\"\n # Use a dictionary comprehension to pair adjacent elements\n return {input_tuple[i]: input_tuple[i + 1] for i in range(0, len(input_tuple), 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(t):\n # Initialize an empty dictionary\n result = {}\n \n # Iterate over the tuple with a step of 2 to get pairs of adjacent elements\n for i in range(0, len(t) - 1, 2):\n # Set the element at the current index as the key and the next element as the value\n result[t[i]] = t[i + 1]\n \n return result", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(tup):\n \"\"\"\n Convert the given tuple to a key-value dictionary using adjacent elements.\n \n Args:\n tup (tuple): A tuple containing an even number of elements.\n \n Returns:\n dict: A dictionary where each pair of adjacent elements in the tuple form a key-value pair.\n \"\"\"\n if len(tup) % 2 != 0:\n raise ValueError(\"Tuple must contain an even number of elements\")\n\n return {tup[i]: tup[i + 1] for i in range(0, len(tup), 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(tpl):\n \"\"\"\n Converts a tuple to a dictionary using adjacent elements as key-value pairs.\n \n :param tpl: A tuple with even number of elements\n :return: A dictionary with each pair of adjacent elements as key-value\n \"\"\"\n # Check if the tuple has an even number of elements\n if len(tpl) % 2 != 0:\n raise ValueError(\"Tuple must have an even number of elements\")\n \n # Create a dictionary from the tuple using adjacent elements as key-value pairs\n result_dict = {tpl[i]: tpl[i + 1] for i in range(0, len(tpl), 2)}\n return result_dict", "matching_cluster_idx": 5}]}, "Mbpp/744": {"dps": 83.01369863013699, "dps_norm": 88.33333333333333, "pass@1": 100.0, "profiled": [{"solution": "def check_none(input_tuple):\n \"\"\"\n This function checks if any element in the tuple is None.\n \n Parameters:\n input_tuple (tuple): The tuple to check for None values.\n \n Returns:\n bool: True if there is at least one None value in the tuple, False otherwise.\n \"\"\"\n for element in input_tuple:\n if element is None:\n return True\n return False", "matching_cluster_idx": 4}, {"solution": "def check_none(t):\n \"\"\"\n This function checks if the given tuple has any None value.\n \n Parameters:\n t (tuple): The tuple to check for None values.\n \n Returns:\n bool: True if there is at least one None value in the tuple, otherwise False.\n \"\"\"\n return None in t", "matching_cluster_idx": 5}, {"solution": "def check_none(tup):\n \"\"\"\n Check if the given tuple has any None value.\n\n :param tup: A tuple of elements to check.\n :return: True if there is at least one None value in the tuple, False otherwise.\n \"\"\"\n return None in tup", "matching_cluster_idx": 5}, {"solution": "def check_none(input_tuple):\n \"\"\"\n Function to check if the given tuple has any None value.\n\n Parameters:\n input_tuple (tuple): The tuple to be checked.\n\n Returns:\n bool: True if there is at least one None value, False otherwise.\n \"\"\"\n # Check if any element in the tuple is None\n return None in input_tuple", "matching_cluster_idx": 5}, {"solution": "def check_none(input_tuple):\n \"\"\"\n Function to check if the given tuple contains any None value.\n \n Args:\n input_tuple (tuple): A tuple of elements to check.\n \n Returns:\n bool: True if the tuple contains at least one None value, False otherwise.\n \"\"\"\n return any(item is None for item in input_tuple)", "matching_cluster_idx": 1}, {"solution": "def check_none(input_tuple):\n \"\"\"\n This function checks if the given tuple contains any None values.\n\n :param input_tuple: Tuple to be checked\n :return: True if any element in the tuple is None, otherwise False\n \"\"\"\n return None in input_tuple", "matching_cluster_idx": 5}, {"solution": "def check_none(input_tuple):\n \"\"\"\n This function checks if the given tuple contains any None value.\n \n Parameters:\n input_tuple (tuple): A tuple that needs to be checked for None values.\n \n Returns:\n bool: True if there's at least one None value in the tuple, otherwise False.\n \"\"\"\n # Iterate through the tuple and check if any element is None\n for element in input_tuple:\n if element is None:\n return True\n return False", "matching_cluster_idx": 4}, {"solution": "def check_none(input_tuple):\n \"\"\"\n Check if the given tuple has any None value.\n\n Parameters:\n input_tuple (tuple): The tuple to be checked.\n\n Returns:\n bool: True if any element is None, False otherwise.\n \"\"\"\n # Check if None is present in the tuple\n return any(element is None for element in input_tuple)", "matching_cluster_idx": 1}, {"solution": "def check_none(tup):\n \"\"\"\n Function to check if the given tuple contains any None values.\n \n Parameters:\n tup (tuple): The tuple to check.\n \n Returns:\n bool: True if there is at least one None in the tuple, otherwise False.\n \"\"\"\n return None in tup", "matching_cluster_idx": 5}, {"solution": "def check_none(input_tuple):\n \"\"\"\n This function checks if there is any None value in the given tuple.\n\n Parameters:\n input_tuple (tuple): The tuple to check for None values.\n\n Returns:\n bool: True if there is at least one None value in the tuple, False otherwise.\n \"\"\"\n return None in input_tuple", "matching_cluster_idx": 5}, {"solution": "def check_none(input_tuple):\n \"\"\"\n This function checks if the given tuple has any None value.\n\n Args:\n input_tuple (tuple): The tuple to check for None values.\n\n Returns:\n bool: True if the tuple contains at least one None value, False otherwise.\n \"\"\"\n # Check if None is in the tuple\n return None in input_tuple", "matching_cluster_idx": 5}, {"solution": "def check_none(input_tuple):\n \"\"\"\n This function checks if any element in the input tuple is None.\n\n :param input_tuple: A tuple of elements to be checked.\n :return: True if any element is None, otherwise False.\n \"\"\"\n return any(element is None for element in input_tuple)", "matching_cluster_idx": 1}, {"solution": "def check_none(tup):\n \"\"\"\n This function checks if there is any None value in the given tuple.\n \n :param tup: A tuple of values.\n :return: True if there is at least one None value in the tuple, False otherwise.\n \"\"\"\n return None in tup", "matching_cluster_idx": 5}, {"solution": "def check_none(tup):\n \"\"\"\n This function checks if there is any None value in the given tuple.\n\n Parameters:\n tup (tuple): A tuple to check for None values.\n\n Returns:\n bool: True if there is at least one None value in the tuple, False otherwise.\n \"\"\"\n return None in tup", "matching_cluster_idx": 5}, {"solution": "def check_none(input_tuple):\n \"\"\"\n Function to check if the given tuple has any None value or not.\n \n Parameters:\n input_tuple (tuple): The tuple to check for None values.\n\n Returns:\n bool: True if there is at least one None value in the tuple, otherwise False.\n \"\"\"\n return None in input_tuple", "matching_cluster_idx": 5}, {"solution": "def check_none(input_tuple):\n \"\"\"\n Check if the given tuple contains any None value.\n\n Parameters:\n input_tuple (tuple): The tuple to check.\n\n Returns:\n bool: True if there is at least one None value, False otherwise.\n \"\"\"\n return None in input_tuple", "matching_cluster_idx": 5}, {"solution": "def check_none(input_tuple):\n \"\"\"\n This function checks if the given tuple contains any None value.\n \n :param input_tuple: tuple to check for None values\n :return: True if there is at least one None value, False otherwise\n \"\"\"\n return None in input_tuple", "matching_cluster_idx": 5}, {"solution": "def check_none(tpl):\n \"\"\"\n This function checks if the given tuple contains any None values.\n\n Parameters:\n tpl (tuple): The tuple to check.\n\n Returns:\n bool: True if the tuple contains None, False otherwise.\n \"\"\"\n return None in tpl", "matching_cluster_idx": 5}, {"solution": "def check_none(input_tuple):\n \"\"\"\n Check if the given tuple has any None value or not.\n\n Parameters:\n input_tuple (tuple): The tuple to check for None values.\n\n Returns:\n bool: True if there is at least one None value in the tuple, False otherwise.\n \"\"\"\n return None in input_tuple", "matching_cluster_idx": 5}, {"solution": "def check_none(tup):\n \"\"\"\n This function checks if there is any None value in the given tuple.\n \n Parameters:\n tup (tuple): The tuple to check for None values.\n\n Returns:\n bool: True if there is at least one None value in the tuple, False otherwise.\n \"\"\"\n return None in tup", "matching_cluster_idx": 5}]}, "Mbpp/750": {"dps": 74.28571428571429, "dps_norm": 76.66666666666667, "pass@1": 100.0, "profiled": [{"solution": "def add_tuple(lst, tpl):\n \"\"\"\n Add the elements of the given tuple to the given list.\n \n :param lst: List to which elements of the tuple are to be added\n :param tpl: Tuple whose elements are to be added to the list\n :return: The updated list after adding tuple elements\n \"\"\"\n lst.extend(tpl)\n return lst", "matching_cluster_idx": 5}, {"solution": "def add_tuple(lst, tpl):\n \"\"\"\n Add the elements of a tuple to the end of a list.\n\n :param lst: List to which the tuple elements will be added.\n :param tpl: Tuple whose elements will be added to the list.\n :return: The modified list after adding the tuple elements.\n \"\"\"\n # Convert the tuple to a list and extend the original list with it.\n lst.extend(tpl)\n return lst", "matching_cluster_idx": 5}, {"solution": "def add_tuple(lst, tpl):\n \"\"\"\n Adds the elements of the given tuple to the end of the given list.\n\n Parameters:\n lst (list): The list to which elements are to be added.\n tpl (tuple): The tuple whose elements are to be added.\n\n Returns:\n list: The resulting list after adding the elements of the tuple.\n \"\"\"\n return lst + list(tpl)", "matching_cluster_idx": 1}, {"solution": "def add_tuple(lst, tpl):\n \"\"\"\n Adds the elements of the given tuple to the end of the given list.\n \n Args:\n lst (list): The list to which the tuple elements will be added.\n tpl (tuple): The tuple whose elements will be added to the list.\n \n Returns:\n list: The list after adding the tuple elements.\n \"\"\"\n # Extend the list with the elements of the tuple\n lst.extend(tpl)\n return lst", "matching_cluster_idx": 5}, {"solution": "def add_tuple(lst, tpl):\n \"\"\"\n Add the elements of the tuple tpl to the end of the list lst.\n\n :param lst: List of integers\n :param tpl: Tuple of integers\n :return: A new list containing the elements of lst followed by the elements of tpl\n \"\"\"\n return lst + list(tpl)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(input_list, input_tuple):\n \"\"\"\n Add the elements of the input_tuple to the end of input_list.\n\n :param input_list: A list of elements.\n :param input_tuple: A tuple of elements.\n :return: A new list with elements of input_tuple added to input_list.\n \"\"\"\n # Extend the list with elements from the tuple\n return input_list + list(input_tuple)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(lst, tpl):\n \"\"\"\n Add the given tuple to the given list by extending the list with the elements of the tuple.\n\n Parameters:\n lst (list): The list to which the tuple elements will be added.\n tpl (tuple): The tuple whose elements are to be added to the list.\n\n Returns:\n list: The list extended by the elements of the tuple.\n \"\"\"\n # Extend the list by converting the tuple to a list and appending its elements\n lst.extend(tpl)\n return lst", "matching_cluster_idx": 5}, {"solution": "def add_tuple(input_list, input_tuple):\n \"\"\"\n Add the given tuple to the given list and return the new list.\n\n Parameters:\n input_list (list): The list to which the tuple will be added.\n input_tuple (tuple): The tuple that will be added to the list.\n\n Returns:\n list: The new list containing elements of the original list followed by elements of the tuple.\n \"\"\"\n # Convert the tuple to a list and concatenate it with the input_list\n return input_list + list(input_tuple)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(lst, tpl):\n \"\"\"\n Add the elements of the given tuple to the end of the given list.\n \n Args:\n lst: A list of elements.\n tpl: A tuple of elements.\n \n Returns:\n A list with elements of the tuple added to the end of the original list.\n \"\"\"\n # Using the list's extend method to add elements of the tuple to the list\n lst.extend(tpl)\n return lst", "matching_cluster_idx": 5}, {"solution": "def add_tuple(lst, tpl):\n \"\"\"\n This function takes a list and a tuple and appends the tuple's elements to the list.\n \n Parameters:\n lst (list): The list to which tuple elements will be added.\n tpl (tuple): The tuple whose elements are to be added to the list.\n \n Returns:\n list: The list containing all original elements plus the elements from the tuple.\n \"\"\"\n # Extend the list by unpacking the tuple and adding its elements\n lst.extend(tpl)\n return lst", "matching_cluster_idx": 5}, {"solution": "def add_tuple(lst, tpl):\n \"\"\"\n Add the elements of the tuple 'tpl' to the end of the list 'lst'.\n \n :param lst: List of elements\n :param tpl: Tuple of elements\n :return: List with elements of 'tpl' added at the end\n \"\"\"\n # Convert the tuple to a list and extend the original list\n lst.extend(tpl)\n return lst", "matching_cluster_idx": 5}, {"solution": "def add_tuple(lst, tpl):\n \"\"\"\n Adds the elements of the given tuple to the given list.\n\n Parameters:\n lst (list): The list to which the elements of the tuple will be added.\n tpl (tuple): The tuple whose elements will be added to the list.\n\n Returns:\n list: The list after adding the elements of the tuple.\n \"\"\"\n # Extend the list with the elements of the tuple\n lst.extend(tpl)\n return lst", "matching_cluster_idx": 5}, {"solution": "def add_tuple(lst, tpl):\n \"\"\"\n Adds the elements of a tuple to the end of a list.\n\n Parameters:\n lst (list): The list to which the tuple elements will be added.\n tpl (tuple): The tuple whose elements will be added to the list.\n\n Returns:\n list: The list after adding the elements of the tuple.\n \"\"\"\n # Extend the list with the elements from the tuple\n lst.extend(tpl)\n return lst", "matching_cluster_idx": 5}, {"solution": "def add_tuple(lst, tpl):\n \"\"\"\n Add the elements of the given tuple to the given list.\n\n Parameters:\n lst (list): The list to which elements of the tuple should be added.\n tpl (tuple): The tuple whose elements are to be added to the list.\n\n Returns:\n list: The list after adding the tuple's elements.\n \"\"\"\n # Extend the list with elements of the tuple\n lst.extend(tpl)\n return lst", "matching_cluster_idx": 5}, {"solution": "def add_tuple(lst, tpl):\n \"\"\"\n Add the elements of the given tuple to the end of the given list.\n \n :param lst: List to which the tuple elements will be added.\n :param tpl: Tuple whose elements will be added to the list.\n :return: A new list containing elements of the original list followed by elements of the tuple.\n \"\"\"\n # Convert the tuple to a list and concatenate it to the input list\n return lst + list(tpl)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(lst, tpl):\n \"\"\"\n Adds the elements of the given tuple to the end of the given list.\n\n Parameters:\n lst (list): The list to which the tuple elements will be added.\n tpl (tuple): The tuple whose elements need to be added to the list.\n\n Returns:\n list: A new list with the elements of the tuple appended to the input list.\n \"\"\"\n # Convert the tuple to a list and concatenate it with the original list\n return lst + list(tpl)", "matching_cluster_idx": 1}, {"solution": "def add_tuple(lst, tpl):\n \"\"\"\n Adds the elements of the given tuple to the end of the given list.\n\n Parameters:\n lst (list): The list to which the tuple will be added.\n tpl (tuple): The tuple whose elements will be added to the list.\n\n Returns:\n list: The list after adding the elements of the tuple.\n \"\"\"\n # Extend the list with the elements from the tuple\n lst.extend(tpl)\n return lst", "matching_cluster_idx": 5}, {"solution": "def add_tuple(lst, tpl):\n \"\"\"\n Add elements of the tuple `tpl` to the end of the list `lst`.\n \n Parameters:\n lst (list): The list to which elements will be added.\n tpl (tuple): The tuple containing elements to be added to the list.\n \n Returns:\n list: A new list with elements of `tpl` added to `lst`.\n \"\"\"\n return lst + list(tpl)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(lst, tpl):\n \"\"\"\n Add the elements of the given tuple to the end of the given list.\n\n Args:\n lst: A list to which the tuple elements will be added.\n tpl: A tuple whose elements will be added to the list.\n\n Returns:\n A new list with the tuple elements added to the original list.\n \"\"\"\n # Concatenate the list and the tuple converted to a list\n return lst + list(tpl)", "matching_cluster_idx": 1}, {"solution": "def add_tuple(lst, tpl):\n \"\"\"\n Adds the elements of the given tuple to the given list.\n \n Parameters:\n lst (list): The original list to which tuple elements will be added.\n tpl (tuple): The tuple whose elements are to be added to the list.\n \n Returns:\n list: The list after adding the elements of the tuple.\n \"\"\"\n # Use the list extend method to add elements of the tuple to the list\n lst.extend(tpl)\n return lst", "matching_cluster_idx": 4}]}, "Mbpp/753": {"dps": 97.31543624161074, "dps_norm": 75.0, "pass@1": 100.0, "profiled": [{"solution": "def min_k(tuple_list, k):\n # Sort the list of tuples based on the second element of each tuple\n sorted_list = sorted(tuple_list, key=lambda x: x[1])\n # Return the first k elements from the sorted list\n return sorted_list[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(records, k):\n \"\"\"\n This function receives a list of tuples where each tuple contains a name and a corresponding numerical value.\n It returns a list of k tuples with the smallest numerical values. If k is larger than the length of the list, it returns the whole list sorted.\n \n :param records: List of tuples [(str, int)]\n :param k: int, the number of minimum records to return\n :return: List of tuples [(str, int)] with the k smallest values\n \"\"\"\n # Sort the list of tuples based on the second element of each tuple, which is the numerical value\n sorted_records = sorted(records, key=lambda x: x[1])\n\n # Return the first k elements of the sorted list\n return sorted_records[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(tuple_list, k):\n \"\"\"\n This function takes a list of tuples and an integer k, and returns the minimum k tuples \n based on the second element in each tuple.\n\n :param tuple_list: List of tuples where each tuple contains a string and an integer\n :param k: Integer that specifies how many minimum tuples to return\n :return: A list of k tuples that have the smallest second elements\n \"\"\"\n # Sort the list of tuples based on the second element of each tuple\n sorted_list = sorted(tuple_list, key=lambda x: x[1])\n # Return the first k elements of the sorted list\n return sorted_list[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(records, k):\n \"\"\"\n Find the minimum k records from the list of tuples based on the second element of the tuple.\n \n Args:\n records (list of tuples): A list where each tuple contains a string and an integer.\n k (int): The number of minimum records to return.\n \n Returns:\n list of tuples: A list containing the k tuples with the smallest integers.\n \"\"\"\n # Sort the records based on the second element of each tuple (i.e., the integer)\n sorted_records = sorted(records, key=lambda x: x[1])\n \n # Return the first k records from the sorted list\n return sorted_records[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(records, k):\n \"\"\"\n This function takes a list of tuples (name, score) and an integer k,\n and returns the k records with the smallest scores.\n \n :param records: List of tuples [(name, score), ...]\n :param k: Integer representing the number of minimum records to find\n :return: List of tuples with the k smallest scores\n \"\"\"\n # Sort the records based on the second item in the tuple (the score)\n sorted_records = sorted(records, key=lambda x: x[1])\n \n # Return the first k records from the sorted list\n return sorted_records[:k]", "matching_cluster_idx": 2}, {"solution": "from typing import List, Tuple\ndef min_k(records: List[Tuple[str, int]], k: int) -> List[Tuple[str, int]]:\n # Sort the records based on the second item of the tuple (the integer value)\n sorted_records = sorted(records, key=lambda record: record[1])\n # Return the first k records from the sorted list\n return sorted_records[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(records, k):\n \"\"\"\n Find the minimum k records from a list of tuples based on the second element in each tuple.\n\n Args:\n - records (list of tuples): A list where each item is a tuple with at least two elements,\n and the second element is a comparable item (e.g., a number).\n - k (int): The number of minimum records to find.\n\n Returns:\n - list of tuples: A list containing the k tuples with the smallest second elements, sorted\n by the second element.\n \"\"\"\n # Sort the list of tuples based on the second element in each tuple.\n sorted_records = sorted(records, key=lambda x: x[1])\n \n # Return the first k elements from the sorted list.\n return sorted_records[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(records, k):\n \"\"\"\n Finds the minimum k records based on the second element of each tuple.\n\n :param records: List of tuples where each tuple consists of a name and a numerical value.\n :param k: The number of minimum records to retrieve based on the numerical value.\n :return: A list of the minimum k records sorted by the numerical value.\n \"\"\"\n # Sort the records based on the second item in each tuple (i.e., the numerical value)\n sorted_records = sorted(records, key=lambda x: x[1])\n \n # Return the first k records from the sorted list\n return sorted_records[:k]", "matching_cluster_idx": 2}, {"solution": "from typing import List, Tuple\ndef min_k(records: List[Tuple[str, int]], k: int) -> List[Tuple[str, int]]:\n \"\"\"\n Returns the k minimum records based on the integer value in each tuple.\n \n Parameters:\n - records (List[Tuple[str, int]]): A list of tuples where each tuple contains a name and a numeric value.\n - k (int): The number of minimum records to return.\n\n Returns:\n - List[Tuple[str, int]]: A list of k tuples with the smallest numeric values.\n \"\"\"\n # Sort the records based on the second item in each tuple (i.e., the integer value)\n sorted_records = sorted(records, key=lambda x: x[1])\n # Return the first k elements from the sorted list\n return sorted_records[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(records, k):\n \"\"\"\n Find minimum k records from a list of tuples based on the second element of each tuple.\n \n Parameters:\n records (list of tuple): The list of tuples to search through.\n k (int): The number of minimum records to return.\n \n Returns:\n list of tuple: A list containing the k tuples with the smallest second elements.\n \"\"\"\n # Sort the list based on the second element of the tuples (the numeric value)\n sorted_records = sorted(records, key=lambda x: x[1])\n \n # Return the first k elements from the sorted list\n return sorted_records[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(records, k):\n \"\"\"\n Returns the minimum k records from the list of tuples based on the numerical value in each tuple.\n \n :param records: List of tuples where each tuple consists of a string and an integer\n :param k: The number of minimum records to retrieve\n :return: List of k tuples with the smallest integer values\n \"\"\"\n # Sort the records based on the second element of the tuple (the integer value)\n sorted_records = sorted(records, key=lambda x: x[1])\n \n # Return the first k elements from the sorted list\n return sorted_records[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(tuple_list, k):\n # Sort the list of tuples based on the second item in each tuple, which is the numeric value\n sorted_list = sorted(tuple_list, key=lambda x: x[1])\n # Return the first k elements from the sorted list\n return sorted_list[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(records, k):\n \"\"\"\n Function to find the minimum k records based on the second element of each tuple.\n \n :param records: List of tuples, where each tuple contains a string and an integer.\n :param k: Number of minimum records to find.\n :return: List of tuples containing the minimum k records based on the integer values.\n \"\"\"\n # Sort the list of tuples based on the second element (numeric value)\n sorted_records = sorted(records, key=lambda x: x[1])\n # Return the first k elements of the sorted list\n return sorted_records[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(tuple_list, k):\n \"\"\"\n Find minimum k records from a list of tuples based on the numerical value in the tuple.\n\n Args:\n tuple_list: List of tuples, each containing a name and a numerical value.\n k: Number of minimum records to return based on the numerical value.\n\n Returns:\n List of k tuples with the smallest numerical values, sorted in ascending order of value.\n \"\"\"\n # Sort the list based on the second element (the numerical value) of the tuples\n sorted_list = sorted(tuple_list, key=lambda x: x[1])\n \n # Return the first k elements from the sorted list\n return sorted_list[:k]\ntuple_list = [('Manjeet', 10), ('Akshat', 4), ('Akash', 2), ('Nikhil', 8)]\nk = 2", "matching_cluster_idx": 2}, {"solution": "def min_k(records, k):\n \"\"\"\n Function to find minimum k records from a list of tuples based on the second element in each tuple.\n\n :param records: List of tuples, where each tuple is of the form (name, score)\n :param k: Number of minimum records to find\n :return: List of k tuples with the smallest scores\n \"\"\"\n # Sort the records based on the second element of the tuple (the score)\n sorted_records = sorted(records, key=lambda x: x[1])\n # Return the first k records\n return sorted_records[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(records, k):\n \"\"\"\n This function takes a list of tuples where each tuple consists of a name (string) and a value (integer),\n and returns the minimum k records sorted by the integer value.\n \n :param records: List[Tuple[str, int]]\n :param k: int\n :return: List[Tuple[str, int]]\n \"\"\"\n # Sort the records based on the integer values\n sorted_records = sorted(records, key=lambda x: x[1])\n \n # Return the first k records from the sorted list\n return sorted_records[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(records, k):\n \"\"\"\n This function takes a list of tuples (where each tuple contains a name and a numeric value)\n and an integer k, and returns a list of the k tuples with the smallest numeric values.\n \"\"\"\n # Sort the records based on the second element of the tuple (the numeric value)\n sorted_records = sorted(records, key=lambda x: x[1])\n \n # Return the first k records from the sorted list\n return sorted_records[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(records, k):\n \"\"\"\n This function takes a list of tuples and an integer k, and returns the minimum k records\n based on the second element of each tuple.\n \n Parameters:\n records (list of tuple): A list of tuples where each tuple contains a name and a numeric value.\n k (int): The number of minimum records to find.\n \n Returns:\n list of tuple: A list containing the minimum k records sorted by the numeric value.\n \"\"\"\n # Sort the list of tuples based on the second element of the tuples\n sorted_records = sorted(records, key=lambda x: x[1])\n \n # Return the first k elements from the sorted list\n return sorted_records[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(records, k):\n \"\"\"\n Finds the minimum k records from a list of tuples based on the second element of each tuple.\n\n Parameters:\n records (list of tuples): A list where each element is a tuple consisting of a name and a numeric value.\n k (int): The number of minimum records to return based on the numeric value.\n\n Returns:\n list of tuples: The minimum k records sorted based on the numeric value.\n \"\"\"\n # Sort the list of tuples based on the second element of each tuple\n sorted_records = sorted(records, key=lambda x: x[1])\n \n # Return the first k elements from the sorted list\n return sorted_records[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(records, k):\n \"\"\"\n Find the minimum k records from a list of tuples based on the second element of each tuple.\n\n :param records: List of tuples, where each tuple contains a name and an integer value\n :param k: Number of minimum records to return\n :return: List of k tuples with the smallest integer values\n \"\"\"\n # Sort the records based on the second element of the tuples (the integer value)\n sorted_records = sorted(records, key=lambda x: x[1])\n \n # Return the first k records from the sorted list\n return sorted_records[:k]", "matching_cluster_idx": 2}]}, "Mbpp/754": {"dps": 86.81034482758622, "dps_norm": 86.25, "pass@1": 90.0, "profiled": [{"solution": "def extract_index_list(l1, l2, l3):\n \"\"\"\n Find elements that are common in l1, l2, and l3 at the same index position.\n \n :param l1: First list\n :param l2: Second list\n :param l3: Third list\n :return: List of common elements that appear in all three lists at the same index\n \"\"\"\n # Ensure the lists are the same length by taking the minimum length\n min_length = min(len(l1), len(l2), len(l3))\n \n # Initialize an empty list to store common elements\n common_elements = []\n\n # Iterate over the index range of the shortest list\n for i in range(min_length):\n # Check if elements at index i are the same across l1, l2, and l3\n if l1[i] == l2[i] == l3[i]:\n # If they are, append the element to the common elements list\n common_elements.append(l1[i])\n \n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n # Initialize an empty list to store the common elements\n common_elements = []\n \n # Iterate over the lists using their indices\n # Only iterate up to the length of the shortest list to avoid IndexError\n min_length = min(len(l1), len(l2), len(l3))\n \n for i in range(min_length):\n # Check if the elements at index i are equal in all three lists\n if l1[i] == l2[i] == l3[i]:\n # If they are, append the element to the common_elements list\n common_elements.append(l1[i])\n \n # Return the list of common elements\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n # Initialize an empty list to store common elements\n common_elements = []\n \n # Get the minimum length of the three lists to prevent index errors\n min_length = min(len(l1), len(l2), len(l3))\n \n # Iterate over the range of the minimum length\n for i in range(min_length):\n # Check if elements at the same index are equal in all three lists\n if l1[i] == l2[i] == l3[i]:\n # Append the common element to the result list\n common_elements.append(l1[i])\n \n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n \"\"\"\n This function takes three lists as input and returns a list of elements\n that are common to all three lists at the same indices.\n \"\"\"\n # Find the length of the smallest list to avoid index out of range errors\n min_length = min(len(l1), len(l2), len(l3))\n \n # Initialize the list to store common elements\n common_elements = []\n \n # Iterate through the lists up to the minimum length\n for i in range(min_length):\n # Check if the elements at the current index are the same in all lists\n if l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n \n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n \"\"\"\n This function finds elements that are common across three lists\n at the same indices and returns them in a new list.\n \"\"\"\n # Determine the shortest length of the three lists to avoid index errors\n min_length = min(len(l1), len(l2), len(l3))\n \n # Initialize an empty list to store common elements\n common_elements = []\n \n # Iterate over the indices of the lists\n for i in range(min_length):\n # Check if the elements at the current index are the same across all lists\n if l1[i] == l2[i] == l3[i]:\n # Add the common element to the list\n common_elements.append(l1[i])\n \n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n # Initialize an empty list to store common elements\n common_elements = []\n \n # Determine the minimum length of the three lists to avoid IndexError\n min_length = min(len(l1), len(l2), len(l3))\n \n # Iterate over the range of the minimum length\n for i in range(min_length):\n # Check if the elements in the same index are equal across the three lists\n if l1[i] == l2[i] == l3[i]:\n # If they are the same, add to the list of common elements\n common_elements.append(l1[i])\n \n # Return the list of common elements\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n # Find common elements at the same indices across all three lists\n common_elements = []\n # Determine the shortest list to avoid index errors\n min_length = min(len(l1), len(l2), len(l3))\n \n # Loop through the indices and compare elements\n for i in range(min_length):\n if l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n \n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n # Find the minimum length among the three lists to avoid index errors\n min_length = min(len(l1), len(l2), len(l3))\n \n # Initialize an empty list to store common elements\n common_elements = []\n \n # Iterate through the lists using the minimum length\n for i in range(min_length):\n # Check if the elements at the current index are the same in all three lists\n if l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n \n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n # Initialize an empty list to store common elements\n common_elements = []\n \n # Get the minimum length of the three lists to avoid index errors\n min_length = min(len(l1), len(l2), len(l3))\n \n # Iterate through each index of the lists up to the minimum length\n for i in range(min_length):\n # Check if the element is the same at this index in all three lists\n if l1[i] == l2[i] == l3[i]:\n # If so, append it to the result list\n common_elements.append(l1[i])\n \n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n \"\"\"\n Finds elements that are common at the same index across three lists.\n \n Args:\n l1, l2, l3: Lists of integers.\n \n Returns:\n A list of elements that are common at the same index in all three lists.\n \"\"\"\n common_elements = []\n min_length = min(len(l1), len(l2), len(l3))\n \n for i in range(min_length):\n if l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n \n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n \"\"\"\n Returns a list of elements that are common for lists l1, l2, l3,\n meaning that they appear in all three lists under the same index.\n \"\"\"\n # Initialize an empty list to store common elements\n common_elements = []\n \n # Find the minimum length of the lists to prevent index errors\n min_length = min(len(l1), len(l2), len(l3))\n \n # Iterate through each index up to the minimum length\n for i in range(min_length):\n # Check if the element is the same in all three lists at index i\n if l1[i] == l2[i] == l3[i]:\n # If it is the same, append it to the list of common elements\n common_elements.append(l1[i])\n \n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n \"\"\"\n This function finds the elements that are common in all three lists at the same index position.\n \n :param l1: List of elements\n :param l2: List of elements\n :param l3: List of elements\n :return: A list of elements that are common in l1, l2, and l3 at the same index\n \"\"\"\n # Ensure all lists are of the same length to avoid index errors\n min_length = min(len(l1), len(l2), len(l3))\n \n # Find common elements at the same index\n common_elements = [l1[i] for i in range(min_length) if l1[i] == l2[i] == l3[i]]\n \n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n # Check the shortest list length to avoid IndexError\n shortest_length = min(len(l1), len(l2), len(l3))\n \n # Create a list to store common elements\n common_elements = []\n \n # Iterate over the range of the shortest list\n for i in range(shortest_length):\n # Check if the element at the current index is the same in all three lists\n if l1[i] == l2[i] == l3[i]:\n # If it is common, append it to the common_elements list\n common_elements.append(l1[i])\n \n # Return the list of common elements\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n \"\"\"\n Finds common elements from three lists that appear in all three lists under the same index.\n\n Args:\n l1: List of elements\n l2: List of elements\n l3: List of elements\n\n Returns:\n A list of elements that are common at the same index in all three lists.\n \"\"\"\n # Find the minimum length of the three lists to avoid IndexError\n min_length = min(len(l1), len(l2), len(l3))\n \n # Initialize a list to hold common elements\n common_elements = []\n \n # Iterate through each index up to the minimum length of the lists\n for i in range(min_length):\n # Check if the element at index i is the same across all three lists\n if l1[i] == l2[i] == l3[i]:\n # If so, append the element to the common elements list\n common_elements.append(l1[i])\n \n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n # Initialize an empty list to hold common elements\n common_elements = []\n \n # Determine the minimum length of the three lists to prevent index errors\n min_length = min(len(l1), len(l2), len(l3))\n \n # Iterate through each index up to the minimum length\n for i in range(min_length):\n # Check if the element at the current index is the same in all three lists\n if l1[i] == l2[i] == l3[i]:\n # If they are the same, add the element to the common_elements list\n common_elements.append(l1[i])\n \n # Return the list of common elements\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n \"\"\"\n This function finds elements that are common across three lists\n at the same index and returns them as a list.\n \"\"\"\n # Determine the shortest list length to avoid index out of range errors\n min_length = min(len(l1), len(l2), len(l3))\n \n # Initialize an empty list to hold common elements\n common_elements = []\n\n # Iterate through each index up to the minimum length of the lists\n for i in range(min_length):\n # Check if the element is the same across all three lists at index i\n if l1[i] == l2[i] == l3[i]:\n # If they are the same, add it to the list of common elements\n common_elements.append(l1[i])\n \n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n # Find the minimum length among the three lists to prevent index out of range errors\n min_length = min(len(l1), len(l2), len(l3))\n common_elements = []\n \n # Iterate over the indices up to the minimum length\n for i in range(min_length):\n # Check if the elements at the same index in all three lists are equal\n if l1[i] == l2[i] == l3[i]:\n # If they are equal, add the element to the common elements list\n common_elements.append(l1[i])\n \n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n # Initialize an empty list to store common elements.\n common_elements = []\n \n # Iterate over the indices and elements of the first list.\n for i, elem in enumerate(l1):\n # Check if the index is within the bounds of both l2 and l3.\n if i < len(l2) and i < len(l3):\n # If the elements at the same index in all three lists are the same, add to common_elements.\n if elem == l2[i] == l3[i]:\n common_elements.append(elem)\n \n # Return the list of common elements.\n return common_elements", "matching_cluster_idx": 4}, {"solution": "def extract_index_list(l1, l2, l3):\n # Initialize an empty list to store common elements\n common_elements = []\n \n # Determine the minimum length of the three lists to avoid index errors\n min_length = min(len(l1), len(l2), len(l3))\n \n # Iterate through the lists up to the minimum length\n for i in range(min_length):\n # Check if the element at the same index is the same across all three lists\n if l1[i] == l2[i] == l3[i]:\n # If so, append the element to the common elements list\n common_elements.append(l1[i])\n \n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n # Find the common elements at the same index in all three lists\n common_elements = []\n for i in range(min(len(l1), len(l2), len(l3))): # Ensure we don't go out of bounds\n if l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n return common_elements\nl1 = [1, 2, 3, 4, 5]\nl2 = [1, 3, 3, 8, 5]\nl3 = [1, 2, 3, 4, 5]", "matching_cluster_idx": 6}]}, "Mbpp/755": {"dps": null, "dps_norm": null, "pass@1": 3.0, "profiled": []}, "Mbpp/757": {"dps": null, "dps_norm": null, "pass@1": 0.0, "profiled": []}, "Mbpp/758": {"dps": 96.54440154440154, "dps_norm": 86.875, "pass@1": 100.0, "profiled": [{"solution": "def unique_sublists(lst):\n result = {}\n for sublist in lst:\n # Convert sublist to a tuple\n sublist_tuple = tuple(sublist)\n # Count occurrences of each tuple\n if sublist_tuple in result:\n result[sublist_tuple] += 1\n else:\n result[sublist_tuple] = 1\n return result", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(lst):\n sublist_count = {}\n for sublist in lst:\n # Convert the sublist to a tuple so it can be used as a key in the dictionary\n sublist_tuple = tuple(sublist)\n if sublist_tuple in sublist_count:\n sublist_count[sublist_tuple] += 1\n else:\n sublist_count[sublist_tuple] = 1\n return sublist_count", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(lst):\n \"\"\"\n Counts lists within a list. Returns a dictionary where each list is \n converted to a tuple and the value is the number of its occurrences.\n \"\"\"\n result = {}\n for sublist in lst:\n # Convert the sublist to a tuple to make it hashable\n sublist_tuple = tuple(sublist)\n # Increment the count of the tuple in the dictionary\n if sublist_tuple in result:\n result[sublist_tuple] += 1\n else:\n result[sublist_tuple] = 1\n return result", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(lst):\n sublist_count = {}\n for sublist in lst:\n sublist_tuple = tuple(sublist) # Convert the sublist to a tuple\n if sublist_tuple in sublist_count:\n sublist_count[sublist_tuple] += 1\n else:\n sublist_count[sublist_tuple] = 1\n return sublist_count", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(lst):\n # Create a dictionary to store the counts\n count_dict = {}\n \n # Iterate through each sublist in the list\n for sublist in lst:\n # Convert the sublist to a tuple so it can be used as a dictionary key\n tuple_key = tuple(sublist)\n \n # Increment the count for this tuple in the dictionary\n if tuple_key in count_dict:\n count_dict[tuple_key] += 1\n else:\n count_dict[tuple_key] = 1\n \n return count_dict", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(lst):\n # Initialize an empty dictionary to store the tuples and their counts\n count_dict = {}\n \n for sublist in lst:\n # Convert the current sublist to a tuple (since lists cannot be dictionary keys)\n sublist_tuple = tuple(sublist)\n \n # Increment the count of this tuple in the dictionary\n if sublist_tuple in count_dict:\n count_dict[sublist_tuple] += 1\n else:\n count_dict[sublist_tuple] = 1\n \n return count_dict", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(lst):\n # Initialize a dictionary to hold the count of each unique sublist\n sublist_count = {}\n\n # Iterate through each sublist in the input list\n for sublist in lst:\n # Convert the sublist to a tuple (since lists are not hashable and cannot be dictionary keys)\n sublist_tuple = tuple(sublist)\n \n # Count the occurrence of each sublist tuple in the dictionary\n if sublist_tuple in sublist_count:\n sublist_count[sublist_tuple] += 1\n else:\n sublist_count[sublist_tuple] = 1\n\n return sublist_count", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(list_of_lists):\n \"\"\"\n This function takes a list of lists and returns a dictionary where each sublist\n is converted to a tuple and the value is the number of its occurrences in the original list.\n \"\"\"\n count_dict = {}\n \n for sublist in list_of_lists:\n # Convert each sublist to a tuple to use it as a dictionary key\n sublist_tuple = tuple(sublist)\n \n # Increment the count of this tuple in the dictionary\n if sublist_tuple in count_dict:\n count_dict[sublist_tuple] += 1\n else:\n count_dict[sublist_tuple] = 1\n \n return count_dict", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(lst):\n # Initialize an empty dictionary to hold the counts\n sublist_counts = {}\n \n # Iterate over each sublist in the list\n for sublist in lst:\n # Convert the sublist to a tuple (since lists are not hashable)\n sublist_tuple = tuple(sublist)\n \n # Increment the count of this tuple in the dictionary\n if sublist_tuple in sublist_counts:\n sublist_counts[sublist_tuple] += 1\n else:\n sublist_counts[sublist_tuple] = 1\n \n # Return the dictionary with counts\n return sublist_counts", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(lst):\n # Initialize an empty dictionary to store the counts\n result = {}\n\n # Iterate over each sublist in the given list\n for sublist in lst:\n # Convert the sublist to a tuple (since lists can't be keys in a dictionary)\n sublist_tuple = tuple(sublist)\n\n # If the tuple is already in the dictionary, increment its count\n if sublist_tuple in result:\n result[sublist_tuple] += 1\n else:\n # If it's not in the dictionary, add it with a count of 1\n result[sublist_tuple] = 1\n\n return result", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(lst):\n # Dictionary to store the count of each tuple\n count_dict = {}\n \n for sublist in lst:\n # Convert each sublist to a tuple (since lists can't be dictionary keys)\n sublist_tuple = tuple(sublist)\n # Increment the count for this tuple in the dictionary\n if sublist_tuple in count_dict:\n count_dict[sublist_tuple] += 1\n else:\n count_dict[sublist_tuple] = 1\n \n return count_dict", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(lst):\n \"\"\"\n Counts the occurrences of sublists within a list and returns a dictionary\n where each sublist is represented as a tuple and the value is the count \n of its occurrences in the original list.\n \n Parameters:\n lst (list of lists): A list containing sublists.\n\n Returns:\n dict: A dictionary with tuples of the sublists as keys and their \n occurrence count as values.\n \"\"\"\n result = {}\n for sublist in lst:\n # Convert each sublist to a tuple to use as a dictionary key\n sublist_tuple = tuple(sublist)\n if sublist_tuple in result:\n result[sublist_tuple] += 1\n else:\n result[sublist_tuple] = 1\n return result", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(lst):\n # Initialize a dictionary to store the count of each sublist\n count_dict = {}\n \n # Iterate over each sublist in the input list\n for sublist in lst:\n # Convert the sublist to a tuple (since lists are not hashable)\n sublist_tuple = tuple(sublist)\n \n # If the tuple is already in the dictionary, increment its count\n if sublist_tuple in count_dict:\n count_dict[sublist_tuple] += 1\n # Otherwise, add the tuple to the dictionary with a count of 1\n else:\n count_dict[sublist_tuple] = 1\n \n # Return the dictionary with tuples as keys and their counts as values\n return count_dict", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(lst_of_lists):\n # Initialize a dictionary to hold the count of each tuple\n tuple_count = {}\n \n # Iterate through each list in the list of lists\n for sublist in lst_of_lists:\n # Convert the sublist to a tuple\n tpl = tuple(sublist)\n \n # Count the occurrences of the tuple\n if tpl in tuple_count:\n tuple_count[tpl] += 1\n else:\n tuple_count[tpl] = 1\n \n return tuple_count", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(lists):\n # Initialize an empty dictionary to store the counts of each unique list.\n counts = {}\n \n # Iterate over each sublist in the given list of lists.\n for sublist in lists:\n # Convert the current sublist to a tuple, since lists cannot be dictionary keys.\n sublist_tuple = tuple(sublist)\n \n # If the tuple is already in the dictionary, increment its count.\n if sublist_tuple in counts:\n counts[sublist_tuple] += 1\n else:\n # Otherwise, initialize its count to 1.\n counts[sublist_tuple] = 1\n \n # Return the dictionary with tuples as keys and their counts as values.\n return counts", "matching_cluster_idx": 5}, {"solution": "def unique_sublists(lst):\n \"\"\"\n Count lists within a list and return a dictionary where every list is converted to a tuple\n and the value of such tuple is the number of its occurrences in the original list.\n \n Parameters:\n lst (list of lists): The list containing sublists to count.\n \n Returns:\n dict: A dictionary with tuples of the sublists as keys and their counts as values.\n \"\"\"\n # Initialize an empty dictionary to store the count of each sublist\n count_dict = {}\n \n # Iterate over each sublist in the input list\n for sublist in lst:\n # Convert the sublist to a tuple\n sublist_tuple = tuple(sublist)\n \n # If the tuple is already in the dictionary, increment its count\n if sublist_tuple in count_dict:\n count_dict[sublist_tuple] += 1\n else:\n # Otherwise, add it to the dictionary with a count of 1\n count_dict[sublist_tuple] = 1\n \n return count_dict", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(lst):\n \"\"\"\n Count the occurrences of lists within a list and return a dictionary where\n each unique list is converted to a tuple and mapped to the number of its occurrences.\n \"\"\"\n # Create a dictionary to store the counts of each list\n counts = {}\n\n # Iterate through each sublist in the input list\n for sublist in lst:\n # Convert the sublist to a tuple (since lists are mutable and can't be dictionary keys)\n sublist_tuple = tuple(sublist)\n \n # If the tuple is already a key in the dictionary, increment its count\n if sublist_tuple in counts:\n counts[sublist_tuple] += 1\n # Otherwise, add the tuple to the dictionary with a count of 1\n else:\n counts[sublist_tuple] = 1\n\n return counts", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(list_of_lists):\n # Initialize an empty dictionary to hold tuples as keys and their counts as values\n counts = {}\n\n # Iterate over each sublist in the provided list of lists\n for sublist in list_of_lists:\n # Convert the sublist to a tuple (since lists are not hashable and cannot be dictionary keys)\n sublist_tuple = tuple(sublist)\n \n # If the tuple is already a key in the dictionary, increment its count\n if sublist_tuple in counts:\n counts[sublist_tuple] += 1\n else:\n # Otherwise, add it to the dictionary with a count of 1\n counts[sublist_tuple] = 1\n \n return counts", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(lst):\n # Initialize an empty dictionary to store counts\n count_dict = {}\n \n # Iterate over each sublist in the main list\n for sublist in lst:\n # Convert the sublist to a tuple so it can be used as a dictionary key\n sublist_tuple = tuple(sublist)\n \n # If the tuple is already in the dictionary, increment its count\n if sublist_tuple in count_dict:\n count_dict[sublist_tuple] += 1\n else:\n # Otherwise, add it to the dictionary with an initial count of 1\n count_dict[sublist_tuple] = 1\n \n # Return the dictionary containing tuples and their counts\n return count_dict", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(lists):\n sublist_count = {}\n for sublist in lists:\n sublist_tuple = tuple(sublist)\n if sublist_tuple in sublist_count:\n sublist_count[sublist_tuple] += 1\n else:\n sublist_count[sublist_tuple] = 1\n return sublist_count", "matching_cluster_idx": 6}]}, "Mbpp/760": {"dps": 95.94890510948906, "dps_norm": 86.875, "pass@1": 88.0, "profiled": [{"solution": "def unique_Element(numbers):\n # Convert the list to a set, which removes duplicates\n unique_numbers = set(numbers)\n # If the length of the set is 1, it means all elements in the list were the same\n return len(unique_numbers) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(lst):\n \"\"\"\n Check if a list contains only one distinct element.\n \n :param lst: List of elements to check\n :return: True if there is only one distinct element, False otherwise\n \"\"\"\n if not lst: # Check for empty list\n return False\n return len(set(lst)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(lst):\n \"\"\"\n This function checks whether the list contains only one distinct element.\n \n Parameters:\n lst (list): A list of elements to be checked.\n\n Returns:\n bool: True if there is only one distinct element in the list, False otherwise.\n \"\"\"\n # Convert list to a set, which removes duplicates. \n # Check if the length of the set is 1, meaning all elements were the same.\n return len(set(lst)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(lst):\n \"\"\"\n Checks if a list contains only one distinct element.\n\n Parameters:\n lst (list): List of elements to check.\n\n Returns:\n bool: True if all elements in the list are the same, False otherwise.\n \"\"\"\n if not lst:\n return False # Returning False for an empty list as there are no elements to be considered distinct\n # Use a set to determine if there is only one unique element in the list\n return len(set(lst)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(numbers):\n \"\"\"\n This function checks if all elements in the list are the same.\n \n :param numbers: List of numbers\n :return: True if the list contains only one distinct element, False otherwise\n \"\"\"\n if len(numbers) == 0:\n return False # Assuming empty list should return False as there are no elements\n \n # Convert the list to a set, which will hold only distinct elements\n unique_elements = set(numbers)\n \n # Check if there's only one unique element in the set\n return len(unique_elements) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(numbers):\n # Convert the list to a set, which removes duplicates\n unique_numbers = set(numbers)\n # Check if the length of the set is 1, meaning there's only one distinct element\n return len(unique_numbers) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(lst):\n \"\"\"\n This function checks whether a list of numbers contains only one distinct element.\n\n Parameters:\n lst (list): A list of numbers.\n\n Returns:\n bool: True if the list contains only one distinct element, False otherwise.\n \"\"\"\n # Convert the list to a set to eliminate duplicates\n # If the length of the set is 1, it means all elements are the same\n return len(set(lst)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(numbers):\n \"\"\"\n This function checks whether all elements in the list are identical.\n \n :param numbers: List of numbers to check\n :return: True if all elements are identical, False otherwise\n \"\"\"\n if not numbers: # An empty list is considered to not have distinct elements\n return False\n \n # Compare the set of numbers with its length to check if all elements are identical\n return len(set(numbers)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(lst):\n \"\"\"\n Function to check whether a list of numbers contains only one distinct element.\n\n Parameters:\n lst (list): A list of numbers.\n\n Returns:\n bool: True if the list contains only one distinct element, False otherwise.\n \"\"\"\n if not lst: # Check for an empty list\n return False\n # Use a set to find unique elements and check its length\n return len(set(lst)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(lst):\n \"\"\"\n Checks if the list contains only one distinct element.\n\n Parameters:\n lst (list): A list of numbers.\n\n Returns:\n bool: True if all elements in the list are the same, False otherwise.\n \"\"\"\n if len(lst) == 0:\n return False\n first_element = lst[0]\n for element in lst:\n if element != first_element:\n return False\n return True", "matching_cluster_idx": 5}, {"solution": "def unique_Element(lst):\n \"\"\"\n Check whether a list contains only one distinct element.\n\n :param lst: List of numbers.\n :return: True if there is exactly one distinct element, False otherwise.\n \"\"\"\n return len(set(lst)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(lst):\n \"\"\"\n This function checks if all the elements in the list are the same.\n\n Parameters:\n lst (list): The list of numbers to be checked.\n\n Returns:\n bool: True if all elements in the list are the same, False otherwise.\n \"\"\"\n # If the list is empty, we consider it does not contain a single distinct element\n if not lst:\n return False\n \n # Use a set to eliminate duplicates, then check its length\n return len(set(lst)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(lst):\n \"\"\"\n Checks whether a list of numbers contains only one distinct element.\n\n Args:\n lst (list): The list of numbers to check.\n\n Returns:\n bool: True if the list contains only one distinct element, False otherwise.\n \"\"\"\n if not lst:\n return False # An empty list doesn't contain any elements, hence no distinct element\n\n # Convert list to a set and check if its length is 1\n return len(set(lst)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(lst):\n \"\"\"\n Checks whether the list contains only one distinct element.\n \n Parameters:\n lst (list): The list of numbers to check.\n \n Returns:\n bool: True if the list contains only one distinct element, False otherwise.\n \"\"\"\n # Convert list to a set and check the length\n return len(set(lst)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(lst):\n \"\"\"\n Check whether a list of numbers contains only one distinct element.\n \n Parameters:\n lst (list): A list of numbers.\n \n Returns:\n bool: True if the list contains only one distinct element, False otherwise.\n \"\"\"\n return len(set(lst)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(numbers):\n \"\"\"\n Check whether a list of numbers contains only one distinct element.\n\n :param numbers: A list of numbers\n :return: True if the list contains only one distinct element, False otherwise\n \"\"\"\n # Use a set to determine the number of distinct elements in the list\n return len(set(numbers)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(lst):\n \"\"\"\n This function checks if all elements in the list are the same.\n \n Parameters:\n lst (list): A list of elements to check.\n\n Returns:\n bool: True if all elements are the same, False otherwise.\n \"\"\"\n # Convert the list to a set, which will remove duplicates\n unique_elements = set(lst)\n # If the length of the set is 1, it means all elements in the list are the same\n return len(unique_elements) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(numbers):\n \"\"\"\n This function checks whether all elements in the list 'numbers' are the same.\n \n :param numbers: List of numbers\n :return: True if all elements are the same, False otherwise\n \"\"\"\n # A set contains only unique elements. If the length of the set is 1,\n # it means all elements in the list are the same.\n return len(set(numbers)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(numbers):\n \"\"\"\n Check whether the list of numbers contains only one distinct element.\n \n Parameters:\n numbers (list): A list of numbers to check.\n\n Returns:\n bool: True if all elements in the list are the same, False otherwise.\n \"\"\"\n if not numbers: # If the list is empty, return False as it has no elements\n return False\n return len(set(numbers)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(lst):\n \"\"\"\n Function to check if the list contains only one distinct element.\n \n Args:\n lst: List of numbers.\n \n Returns:\n bool: True if there is only one distinct element, False otherwise.\n \"\"\"\n return len(set(lst)) == 1", "matching_cluster_idx": 6}]}, "Mbpp/764": {"dps": 88.88888888888889, "dps_norm": 50.0, "pass@1": 100.0, "profiled": [{"solution": "def number_ctr(s):\n \"\"\"Count the number of digits in the input string s.\"\"\"\n return sum(char.isdigit() for char in s)", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n \"\"\"\n Counts the number of digits in the given string.\n\n :param s: The input string\n :return: The count of digits in the string\n \"\"\"\n return sum(char.isdigit() for char in s)", "matching_cluster_idx": 2}, {"solution": "def number_ctr(input_string: str) -> int:\n \"\"\"\n This function counts the number of digit characters in the given string.\n\n :param input_string: The string to be analyzed\n :return: The count of digit characters in the input string\n \"\"\"\n # Initialize a counter to zero\n digit_count = 0\n \n # Iterate over each character in the input string\n for char in input_string:\n # Check if the current character is a digit\n if char.isdigit():\n # Increment the counter if it is a digit\n digit_count += 1\n \n # Return the total count of digits\n return digit_count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n \"\"\"\n Count number of digits in the given string.\n\n Args:\n s (str): The input string.\n\n Returns:\n int: The count of digit characters in the input string.\n \"\"\"\n return sum(1 for char in s if char.isdigit())", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s: str) -> int:\n \"\"\"Counts the number of digits in a given string.\"\"\"\n return sum(1 for char in s if char.isdigit())", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s: str) -> int:\n \"\"\"\n Count the number of digit characters in a given string.\n\n :param s: Input string\n :return: Number of digits in the string\n \"\"\"\n count = 0\n for char in s:\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n \"\"\"\n This function takes a string as input and returns the number of digits in that string.\n\n :param s: Input string\n :return: Number of digits in the input string\n \"\"\"\n # Initialize a counter for digits\n digit_count = 0\n \n # Iterate through each character in the string\n for char in s:\n # Check if the character is a digit\n if char.isdigit():\n # Increment the counter if it is a digit\n digit_count += 1\n \n return digit_count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n \"\"\"Function to count the number of digits in the given string.\"\"\"\n count = 0\n for char in s:\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s: str) -> int:\n \"\"\"\n Counts the number of digit characters in the given string.\n\n Parameters:\n s (str): The input string to check for digits.\n\n Returns:\n int: The count of digit characters in the string.\n \"\"\"\n return sum(char.isdigit() for char in s)", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n \"\"\"\n Counts the number of digits in the given string.\n\n Args:\n s (str): The string to count digits in.\n\n Returns:\n int: The count of digits in the string.\n \"\"\"\n return sum(1 for char in s if char.isdigit())", "matching_cluster_idx": 2}, {"solution": "def number_ctr(input_string):\n \"\"\"\n This function takes a string as input and returns the number of digits in that string.\n\n :param input_string: The input string to check for digits.\n :return: The count of digits in the input string.\n \"\"\"\n # Use a generator expression to iterate over the string and count digits\n digit_count = sum(1 for char in input_string if char.isdigit())\n return digit_count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(input_string):\n \"\"\"\n Count the number of digits in a given string.\n\n Parameters:\n input_string (str): The string to analyze.\n\n Returns:\n int: The number of digits in the string.\n \"\"\"\n digit_count = 0\n for char in input_string:\n if char.isdigit():\n digit_count += 1\n return digit_count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s: str) -> int:\n \"\"\"Count the number of digit characters in the given string.\"\"\"\n return sum(1 for char in s if char.isdigit())", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s: str) -> int:\n \"\"\"\n Count the number of digit characters in a given string.\n\n :param s: The input string.\n :return: The count of digit characters in the string.\n \"\"\"\n return sum(char.isdigit() for char in s)", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n return sum(c.isdigit() for c in s)", "matching_cluster_idx": 2}, {"solution": "def number_ctr(input_string: str) -> int:\n \"\"\"\n Count the number of digits in the given string.\n \n Parameters:\n input_string (str): The string to be analyzed.\n \n Returns:\n int: The number of digits in the string.\n \"\"\"\n return sum(1 for char in input_string if char.isdigit())", "matching_cluster_idx": 2}, {"solution": "def number_ctr(input_string: str) -> int:\n \"\"\"Count the number of digits in the given string.\"\"\"\n return sum(char.isdigit() for char in input_string)", "matching_cluster_idx": 2}, {"solution": "def number_ctr(input_string):\n \"\"\"\n Count the number of digits in the given string.\n\n Parameters:\n input_string (str): The string to analyze.\n\n Returns:\n int: The count of digits in the string.\n \"\"\"\n digit_count = sum(1 for char in input_string if char.isdigit())\n return digit_count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n \"\"\"\n Counts the number of digits in the given string.\n\n Parameters:\n s (str): The input string.\n\n Returns:\n int: The number of digits in the string.\n \"\"\"\n return sum(1 for char in s if char.isdigit())", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n \"\"\"Counts the number of digits in the given string.\"\"\"\n return sum(c.isdigit() for c in s)", "matching_cluster_idx": 2}]}, "Mbpp/766": {"dps": 79.11214953271028, "dps_norm": 65.83333333333334, "pass@1": 100.0, "profiled": [{"solution": "def pair_wise(lst):\n \"\"\"\n Returns a list of all pairs of consecutive items in a given list.\n \n :param lst: A list of elements.\n :return: A list of tuples, each containing a pair of consecutive elements from the input list.\n \"\"\"\n return [(lst[i], lst[i+1]) for i in range(len(lst)-1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n \"\"\"\n Return a list of all pairs of consecutive items in a given list.\n \n Parameters:\n lst (list): A list of items.\n\n Returns:\n list: A list of tuples, each containing a pair of consecutive items from the input list.\n \"\"\"\n return [(lst[i], lst[i + 1]) for i in range(len(lst) - 1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n \"\"\"\n Returns a list of all pairs of consecutive items in the given list.\n \n Args:\n lst: List of elements.\n \n Returns:\n A list of tuples, each containing a pair of consecutive elements from the input list.\n \"\"\"\n return [(lst[i], lst[i+1]) for i in range(len(lst) - 1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n \"\"\"\n Return a list of all pairs of consecutive items in the given list.\n \"\"\"\n # Create a list of tuples by iterating over the index of the list\n return [(lst[i], lst[i+1]) for i in range(len(lst) - 1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n \"\"\"\n This function returns a list of all pairs of consecutive items in a given list.\n \n :param lst: List of items\n :return: List of tuples, each containing a pair of consecutive items\n \"\"\"\n return [(lst[i], lst[i+1]) for i in range(len(lst) - 1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n \"\"\"\n Return a list of all pairs of consecutive items in the given list.\n\n Args:\n lst (list): A list of items.\n\n Returns:\n list: A list of tuples, where each tuple contains a pair of consecutive items from the list.\n \"\"\"\n return [(lst[i], lst[i+1]) for i in range(len(lst) - 1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n # Using a list comprehension to create pairs of consecutive elements\n return [(lst[i], lst[i + 1]) for i in range(len(lst) - 1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n \"\"\"\n Return a list of all pairs of consecutive items in a given list.\n \"\"\"\n return [(lst[i], lst[i+1]) for i in range(len(lst) - 1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n \"\"\"\n This function takes a list 'lst' as input and returns a list of tuples,\n where each tuple contains a pair of consecutive elements from the input list.\n \"\"\"\n return [(lst[i], lst[i + 1]) for i in range(len(lst) - 1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n \"\"\"\n Returns a list of all pairs of consecutive items in a given list.\n \n Args:\n lst (list): The input list containing items.\n\n Returns:\n list: A list of tuples, where each tuple is a pair of consecutive items from the input list.\n \"\"\"\n return [(lst[i], lst[i+1]) for i in range(len(lst)-1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n \"\"\"\n Return a list of all pairs of consecutive items in a given list.\n \n Parameters:\n lst (list): A list of items\n \n Returns:\n list of tuple: A list where each tuple contains a pair of consecutive items from the input list.\n \"\"\"\n return [(lst[i], lst[i+1]) for i in range(len(lst) - 1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(input_list):\n \"\"\"\n Given a list, returns a list of tuples containing pairs of consecutive items.\n\n :param input_list: List of elements.\n :return: List of tuples where each tuple consists of consecutive items from input_list.\n \"\"\"\n # Initialize an empty list to store the pairs\n pairs = []\n\n # Loop over the input list to form pairs of consecutive items\n for i in range(len(input_list) - 1):\n # Append a tuple of the current and next element to the pairs list\n pairs.append((input_list[i], input_list[i + 1]))\n\n return pairs", "matching_cluster_idx": 2}, {"solution": "def pair_wise(lst):\n \"\"\"\n Return a list of all pairs of consecutive items in a given list.\n \n Parameters:\n lst (list): A list of elements.\n \n Returns:\n list of tuples: A list of tuples, each containing two consecutive elements from the input list.\n \"\"\"\n return [(lst[i], lst[i+1]) for i in range(len(lst) - 1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n \"\"\"\n This function takes a list and returns a list of tuples,\n where each tuple contains a pair of consecutive elements from the input list.\n \"\"\"\n # Use a list comprehension to create pairs of consecutive items\n return [(lst[i], lst[i + 1]) for i in range(len(lst) - 1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n \"\"\"\n Returns a list of all pairs of consecutive items in the given list.\n\n :param lst: List of items\n :return: List of tuples, each containing a pair of consecutive items\n \"\"\"\n return [(lst[i], lst[i+1]) for i in range(len(lst) - 1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n \"\"\"\n Returns a list of all pairs of consecutive items in the given list.\n \n Parameters:\n lst (list): The input list from which pairs of consecutive items are generated.\n\n Returns:\n list: A list of tuples, each containing a pair of consecutive items from the input list.\n \"\"\"\n return [(lst[i], lst[i+1]) for i in range(len(lst) - 1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n \"\"\"\n This function takes a list as an input and returns a list of tuples,\n where each tuple consists of consecutive elements from the input list.\n \"\"\"\n return [(lst[i], lst[i+1]) for i in range(len(lst)-1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n \"\"\"\n This function takes a list as input and returns a list of tuples,\n where each tuple contains a pair of consecutive items from the input list.\n \"\"\"\n return [(lst[i], lst[i+1]) for i in range(len(lst) - 1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n \"\"\"\n Return a list of all pairs of consecutive items in a given list.\n \n Parameters:\n lst (list): A list of items.\n \n Returns:\n list: A list of tuples, where each tuple contains a pair of consecutive items from the input list.\n \"\"\"\n return [(lst[i], lst[i + 1]) for i in range(len(lst) - 1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n \"\"\"\n Returns a list of all pairs of consecutive items in a given list.\n\n Args:\n lst (list): The list of items.\n\n Returns:\n list of tuples: Each tuple contains a pair of consecutive items.\n \"\"\"\n return [(lst[i], lst[i+1]) for i in range(len(lst) - 1)]", "matching_cluster_idx": 3}]}, "Mbpp/775": {"dps": 92.96, "dps_norm": 70.0, "pass@1": 100.0, "profiled": [{"solution": "def odd_position(lst):\n \"\"\"\n Function to check if every odd index in the list contains an odd number.\n \n Parameters:\n lst (list): A list of integers.\n \n Returns:\n bool: True if every odd index contains an odd number, False otherwise.\n \"\"\"\n # Iterate over the list by odd indices\n for i in range(1, len(lst), 2):\n if lst[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n \"\"\"\n This function checks if every odd index in the list contains an odd number.\n \"\"\"\n for index in range(1, len(lst), 2): # Start at 1 and step by 2 to get odd indices\n if lst[index] % 2 == 0: # If the element at the odd index is even\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n \"\"\"\n This function checks whether every element at an odd index\n in the given list is an odd number.\n \n :param lst: List of integers to be checked.\n :return: True if every element at an odd index is odd, otherwise False.\n \"\"\"\n for i in range(1, len(lst), 2): # Check only odd indices\n if lst[i] % 2 == 0: # If the number at an odd index is even\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n \"\"\"\n This function checks if every number at an odd index in the list is odd.\n\n Parameters:\n lst (list): A list of integers.\n\n Returns:\n bool: True if all numbers at odd indices are odd, False otherwise.\n \"\"\"\n # Iterate over the list, considering only odd indices\n for i in range(1, len(lst), 2):\n # Check if the number at this odd index is even\n if lst[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(numbers):\n \"\"\"\n Check whether every odd index contains an odd number in the list.\n \n Args:\n numbers (list of int): The list of integers to check.\n \n Returns:\n bool: True if all numbers at odd indices are odd, False otherwise.\n \"\"\"\n for i in range(1, len(numbers), 2):\n if numbers[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n \"\"\"\n Check whether every odd index contains odd numbers in the given list.\n \n Parameters:\n lst (list): A list of integers.\n \n Returns:\n bool: True if every odd index contains an odd number, False otherwise.\n \"\"\"\n # Iterate over the list, checking only odd indices\n for i in range(1, len(lst), 2):\n if lst[i] % 2 == 0: # Check if the number at the odd index is even\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n \"\"\"\n This function checks whether every element at an odd index in the list `lst` is an odd number.\n Returns True if every odd index contains an odd number, False otherwise.\n \"\"\"\n for i in range(1, len(lst), 2):\n if lst[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n \"\"\"\n This function checks whether every odd index in the given list contains an odd number.\n\n Parameters:\n lst (list): A list of integers.\n\n Returns:\n bool: True if all odd indices have odd numbers, False otherwise.\n \"\"\"\n for i in range(1, len(lst), 2):\n if lst[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n \"\"\"\n This function checks whether every odd index in the given list contains odd numbers.\n \n Parameters:\n lst (list): A list of integers.\n \n Returns:\n bool: True if every odd index contains an odd number, False otherwise.\n \"\"\"\n # Iterate through the list using indices\n for i in range(1, len(lst), 2):\n # Check if the element at the odd index is even\n if lst[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(numbers):\n \"\"\"\n This function checks whether every odd index in the given list contains an odd number.\n \"\"\"\n # Iterate over the indices of the list, starting from 1 and stepping by 2 (odd indices)\n for i in range(1, len(numbers), 2):\n # Check if the number at the odd index is not odd\n if numbers[i] % 2 == 0:\n return False\n # If all numbers at odd indices are odd, return True\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n # Iterate over the list starting from index 1 to the end of the list with step 2\n for i in range(1, len(lst), 2):\n # Check if the number at the current odd index is even\n if lst[i] % 2 == 0:\n # If any number at an odd index is even, return False\n return False\n # If all numbers at odd indices are odd, return True\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n \"\"\"\n Check whether every odd index in the given list contains an odd number.\n\n Parameters:\n lst (list): The list to check.\n\n Returns:\n bool: True if every odd index contains an odd number, False otherwise.\n \"\"\"\n # Iterate over the odd indices of the list\n for i in range(1, len(lst), 2):\n if lst[i] % 2 == 0:\n # If an element at an odd index is even, return False\n return False\n # If all elements at odd indices are odd, return True\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n # Iterate over the list, checking only odd indices\n for i in range(1, len(lst), 2):\n if lst[i] % 2 == 0:\n # If an even number is found at an odd index, return False\n return False\n # If all odd indices contain odd numbers, return True\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n \"\"\"\n Function to check whether every odd index contains odd numbers in a given list.\n \n Parameters:\n lst (list of int): The list of integers to be checked.\n \n Returns:\n bool: True if every odd index contains an odd number, False otherwise.\n \"\"\"\n for i in range(1, len(lst), 2):\n if lst[i] % 2 == 0: # Even number at an odd index\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n \"\"\"\n Check whether every odd index contains an odd number in the given list.\n\n :param lst: List of integers.\n :return: True if every number at an odd index is odd, False otherwise.\n \"\"\"\n # Iterate through indices and values of the list\n for index, value in enumerate(lst):\n # Check if the current index is odd\n if index % 2 == 1:\n # If the value at the current odd index is not odd, return False\n if value % 2 == 0:\n return False\n # If all values at odd indices were odd, return True\n return True", "matching_cluster_idx": 2}, {"solution": "def odd_position(lst):\n # Check every odd index to see if it contains an odd number\n for i in range(1, len(lst), 2):\n if lst[i] % 2 == 0: # Check if the number is even\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n \"\"\"\n Check whether every odd index contains odd numbers in the given list.\n \n :param lst: List of integers\n :return: True if every number at an odd index is odd, otherwise False\n \"\"\"\n # We iterate over the indices of the list and check odd indices\n for i in range(1, len(lst), 2): # start from index 1 and step by 2 (odd indices)\n if lst[i] % 2 == 0: # Check if the number is even\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n \"\"\"\n This function checks whether every odd index in the list contains an odd number.\n\n :param lst: List of integers.\n :return: True if every odd index contains an odd number, False otherwise.\n \"\"\"\n for i in range(1, len(lst), 2): # Start from index 1 and step by 2\n if lst[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n \"\"\"\n Check whether every odd index contains odd numbers in a given list.\n \n Parameters:\n lst (list): The list to be checked.\n\n Returns:\n bool: True if every odd index contains an odd number, False otherwise.\n \"\"\"\n for i in range(1, len(lst), 2):\n if lst[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n \"\"\"\n This function checks if every element at an odd index in the list `lst` is odd.\n :param lst: List of integers.\n :return: True if every element at an odd index is odd, False otherwise.\n \"\"\"\n # Iterate through the list, checking only the odd indices\n for i in range(1, len(lst), 2):\n # Check if the current element at the odd index is even\n if lst[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}]}, "Mbpp/777": {"dps": null, "dps_norm": null, "pass@1": 0.0, "profiled": []}, "Mbpp/781": {"dps": 88.2283464566929, "dps_norm": 54.0, "pass@1": 100.0, "profiled": [{"solution": "def count_divisors(n):\n \"\"\"\n This function checks whether the count of divisors of the integer n is even.\n \n Parameters:\n n (int): The integer for which we want to check the count of divisors.\n\n Returns:\n bool: True if the count of divisors is even, False otherwise.\n \"\"\"\n if n <= 0:\n raise ValueError(\"Input must be a positive integer.\")\n\n divisors_count = 0\n\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n if i * i == n:\n # When i is the square root of n, count it only once.\n divisors_count += 1\n else:\n # Count both i and n/i\n divisors_count += 2\n\n return divisors_count % 2 == 0", "matching_cluster_idx": 3}, {"solution": "def count_divisors(n):\n \"\"\"\n This function checks whether the count of divisors of n is even.\n\n Parameters:\n n (int): The integer to check.\n\n Returns:\n bool: True if the count of divisors is even, otherwise False.\n \"\"\"\n if n <= 0:\n raise ValueError(\"Input must be a positive integer.\")\n\n divisors_count = 0\n # Check all numbers from 1 to sqrt(n)\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n if i * i == n:\n # If i is the square root of n, count it once\n divisors_count += 1\n else:\n # Count both i and n/i\n divisors_count += 2\n\n return divisors_count % 2 == 0", "matching_cluster_idx": 3}, {"solution": "def count_divisors(n):\n \"\"\"\n Function to check whether the count of divisors of n is even.\n \n Parameters:\n n (int): The number to check.\n \n Returns:\n bool: True if the count of divisors is even, False otherwise.\n \"\"\"\n if n <= 0:\n raise ValueError(\"The input must be a positive integer.\")\n \n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n if i * i == n:\n count += 1\n else:\n count += 2\n \n return count % 2 == 0", "matching_cluster_idx": 3}, {"solution": "def count_divisors(n):\n \"\"\"\n Returns True if the count of divisors of n is even, else returns False.\n \"\"\"\n if n < 1:\n raise ValueError(\"The input must be a positive integer.\")\n \n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n \n return count % 2 == 0", "matching_cluster_idx": 1}, {"solution": "def count_divisors(n):\n \"\"\"\n This function checks if the count of divisors of `n` is even.\n \"\"\"\n # Initialize count of divisors\n count = 0\n \n # Loop through all numbers from 1 to n\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n \n # Check if the count of divisors is even\n return count % 2 == 0", "matching_cluster_idx": 1}, {"solution": "def count_divisors(n):\n \"\"\"\n This function checks whether the count of divisors of n is even.\n \n Parameters:\n n (int): The number to check for divisor count parity.\n \n Returns:\n bool: True if the count of divisors is even, False otherwise.\n \"\"\"\n if n <= 0:\n raise ValueError(\"The input number must be a positive integer.\")\n\n divisor_count = 0\n \n # Count divisors from 1 to n\n for i in range(1, n + 1):\n if n % i == 0:\n divisor_count += 1\n \n # Check if the count of divisors is even\n return divisor_count % 2 == 0", "matching_cluster_idx": 1}, {"solution": "def count_divisors(n):\n \"\"\"\n This function checks if the number of divisors of a given integer n is even.\n Returns True if the number of divisors is even, otherwise False.\n \"\"\"\n # Initialize the count of divisors\n count = 0\n\n # Loop over all numbers from 1 to n to check for divisors\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n\n # Check if the count of divisors is even\n return count % 2 == 0", "matching_cluster_idx": 1}, {"solution": "def count_divisors(n):\n \"\"\"\n This function checks whether the number of divisors of the integer n is even.\n\n Parameters:\n n (int): The integer for which to count the divisors.\n\n Returns:\n bool: True if the count of divisors is even, False otherwise.\n \"\"\"\n if n <= 0:\n raise ValueError(\"n should be a positive integer.\")\n\n divisor_count = 0\n # Iterate over all numbers from 1 to n to count the divisors\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n if i * i == n:\n # Perfect square case, count divisor only once\n divisor_count += 1\n else:\n # Count both i and n//i as divisors\n divisor_count += 2\n\n # Check if the count of divisors is even\n return divisor_count % 2 == 0", "matching_cluster_idx": 3}, {"solution": "def count_divisors(n):\n \"\"\"\n Returns True if the count of divisors of n is even, otherwise False.\n \"\"\"\n if n <= 0:\n raise ValueError(\"Input must be a positive integer.\")\n\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n\n return count % 2 == 0", "matching_cluster_idx": 1}, {"solution": "def count_divisors(n):\n \"\"\"\n Returns True if the count of divisors of n is even, False otherwise.\n \"\"\"\n if n < 1:\n raise ValueError(\"Input must be a positive integer.\")\n \n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n if i * i == n:\n count += 1\n else:\n count += 2\n \n return count % 2 == 0", "matching_cluster_idx": 3}, {"solution": "def count_divisors(n):\n \"\"\"\n Check if the count of divisors of n is even.\n Return True if even, False otherwise.\n \"\"\"\n if n < 1:\n raise ValueError(\"n must be a positive integer.\")\n \n # Count the number of divisors\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n \n # Check if the count of divisors is even\n return count % 2 == 0", "matching_cluster_idx": 1}, {"solution": "def count_divisors(n):\n \"\"\"\n This function returns True if the count of divisors of n is even, \n otherwise False.\n \"\"\"\n if n <= 0:\n raise ValueError(\"Input must be a positive integer.\")\n\n divisors_count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n divisors_count += 1\n \n return divisors_count % 2 == 0", "matching_cluster_idx": 1}, {"solution": "def count_divisors(n):\n \"\"\"\n This function checks if the number of divisors of n is even.\n\n Parameters:\n n (int): The number to check divisors of.\n\n Returns:\n bool: True if the count of divisors is even, False otherwise.\n \"\"\"\n if n <= 0:\n raise ValueError(\"Input must be a positive integer.\")\n\n divisors_count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n divisors_count += 1\n\n return divisors_count % 2 == 0", "matching_cluster_idx": 1}, {"solution": "def count_divisors(n):\n \"\"\"Return True if the count of divisors of n is even, False otherwise.\"\"\"\n divisor_count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n divisor_count += 1\n return divisor_count % 2 == 0", "matching_cluster_idx": 1}, {"solution": "def count_divisors(n):\n # Count the number of divisors of n\n divisors_count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n divisors_count += 1\n # Check if the count of divisors is even\n return divisors_count % 2 == 0", "matching_cluster_idx": 1}, {"solution": "def count_divisors(n: int) -> bool:\n # Count the number of divisors of n\n if n <= 0:\n raise ValueError(\"Input must be a positive integer.\")\n \n divisors_count = 0\n for i in range(1, int(n ** 0.5) + 1):\n if n % i == 0:\n if i * i == n:\n divisors_count += 1 # Perfect square, count only once\n else:\n divisors_count += 2 # i and n/i are distinct divisors\n \n # Check if the count of divisors is even\n return divisors_count % 2 == 0", "matching_cluster_idx": 3}, {"solution": "def count_divisors(n):\n \"\"\"\n This function checks if the number of divisors of n is even.\n\n Parameters:\n n (int): The number to check.\n\n Returns:\n bool: True if the number of divisors is even, False otherwise.\n \"\"\"\n if n < 1:\n raise ValueError(\"Input must be a positive integer.\")\n \n divisors_count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n divisors_count += 1\n\n return divisors_count % 2 == 0", "matching_cluster_idx": 1}, {"solution": "def count_divisors(n):\n \"\"\"\n Returns True if the number of divisors of `n` is even, otherwise False.\n \"\"\"\n if n <= 0:\n raise ValueError(\"Input must be a positive integer\")\n \n count = 0\n # Iterate over possible divisors\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n count += 1\n if i != n // i:\n count += 1\n \n return count % 2 == 0", "matching_cluster_idx": 3}, {"solution": "def count_divisors(n):\n \"\"\"Return True if the count of divisors of n is even, otherwise False.\"\"\"\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count % 2 == 0", "matching_cluster_idx": 1}, {"solution": "def count_divisors(n):\n \"\"\"\n This function checks if the number of divisors of an integer n is even.\n Returns True if the count is even, otherwise False.\n \"\"\"\n if n <= 0:\n raise ValueError(\"n must be a positive integer\")\n \n divisors_count = 0\n # Iterate over all numbers from 1 to n to count divisors\n for i in range(1, n + 1):\n if n % i == 0:\n divisors_count += 1\n\n # Check if the count of divisors is even\n return divisors_count % 2 == 0", "matching_cluster_idx": 1}]}, "Mbpp/800": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 66.0, "profiled": [{"solution": "def remove_all_spaces(input_string: str) -> str:\n \"\"\"Remove all whitespaces from the input string.\"\"\"\n # Use str.replace() method to replace all spaces with an empty string\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n \"\"\"\n This function takes a string as input and returns a new string with all whitespace characters removed.\n \n :param input_string: The string from which to remove spaces.\n :return: A new string with all whitespaces removed.\n \"\"\"\n # Use the str.replace method to replace all whitespace with an empty string\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string: str) -> str:\n \"\"\"\n Remove all whitespace characters from the given string.\n\n :param input_string: The string from which to remove spaces.\n :return: The string without any whitespace characters.\n \"\"\"\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n \"\"\"\n This function removes all whitespaces from a string.\n \n Parameters:\n input_string (str): The string from which to remove spaces.\n \n Returns:\n str: A new string with all whitespaces removed.\n \"\"\"\n return input_string.replace(' ', '')", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n \"\"\"\n This function removes all whitespaces from the given input string.\n \n Parameters:\n input_string (str): The string from which to remove whitespaces.\n \n Returns:\n str: A new string with all whitespaces removed.\n \"\"\"\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string: str) -> str:\n \"\"\"\n Removes all whitespace characters from the input string.\n \n :param input_string: The string from which to remove whitespaces.\n :return: A new string without any whitespace characters.\n \"\"\"\n # Using str.replace to remove all spaces\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(s: str) -> str:\n \"\"\"\n Removes all whitespaces from the input string.\n\n :param s: The input string from which whitespaces need to be removed.\n :return: A new string with all whitespaces removed.\n \"\"\"\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(s):\n \"\"\"\n Remove all whitespaces from a string.\n \n :param s: Input string from which to remove spaces.\n :return: A new string with all spaces removed.\n \"\"\"\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(s):\n \"\"\"\n Remove all whitespaces from the input string.\n \n Args:\n s (str): The input string from which to remove all whitespaces.\n \n Returns:\n str: A new string with all whitespaces removed.\n \"\"\"\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string: str) -> str:\n \"\"\"\n Remove all whitespaces from the given string.\n\n Parameters:\n input_string (str): The string from which to remove spaces.\n\n Returns:\n str: The string with all spaces removed.\n \"\"\"\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string: str) -> str:\n \"\"\"\n Removes all whitespaces from a string.\n\n Parameters:\n input_string (str): The string from which whitespaces are to be removed.\n\n Returns:\n str: The string with all whitespaces removed.\n \"\"\"\n # Remove all spaces by replacing them with an empty string\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n \"\"\"\n Removes all whitespaces from the input string.\n\n Args:\n input_string (str): The string from which to remove spaces.\n\n Returns:\n str: The string with all spaces removed.\n \"\"\"\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(s: str) -> str:\n \"\"\"\n Remove all whitespace characters from a string.\n\n :param s: The input string.\n :return: A string with all whitespaces removed.\n \"\"\"\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(s: str) -> str:\n \"\"\"\n Remove all whitespace characters from the input string.\n\n Parameters:\n s (str): The input string.\n\n Returns:\n str: The string with all whitespace removed.\n \"\"\"\n # Using str.replace() method to remove spaces\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string: str) -> str:\n \"\"\"\n This function removes all whitespaces from the input string.\n \n :param input_string: The string from which to remove spaces.\n :return: A string without any whitespaces.\n \"\"\"\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(s):\n \"\"\"\n Remove all whitespaces from a string.\n\n Parameters:\n s (str): The string from which to remove whitespaces.\n\n Returns:\n str: The string with all whitespaces removed.\n \"\"\"\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n \"\"\"\n This function removes all whitespaces from the given input string.\n\n :param input_string: A string from which to remove whitespaces.\n :return: A string with all whitespaces removed.\n \"\"\"\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(s):\n \"\"\"\n Remove all whitespaces from the given string.\n\n :param s: The input string from which to remove whitespaces.\n :return: A new string with all whitespaces removed.\n \"\"\"\n return s.replace(' ', '')", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n \"\"\"\n This function removes all whitespace characters from the input string.\n \n Parameters:\n input_string (str): The string from which to remove all whitespaces.\n \n Returns:\n str: A new string with all whitespaces removed.\n \"\"\"\n # Using the replace method to remove all space characters\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string: str) -> str:\n \"\"\"Remove all whitespace characters from the input string.\"\"\"\n # Use the str.replace method to remove spaces\n return input_string.replace(' ', '')", "matching_cluster_idx": 4}]}, "Mbpp/805": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def max_sum_list(lists_of_lists):\n \"\"\"\n This function takes a list of lists and returns the list whose sum of elements is the highest.\n \"\"\"\n # Start with an empty list and sum as negative infinity for comparison\n max_list = []\n max_sum = float('-inf')\n \n for sublist in lists_of_lists:\n current_sum = sum(sublist)\n # Check if the current sum is greater than the maximum sum found so far\n if current_sum > max_sum:\n max_sum = current_sum\n max_list = sublist\n \n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists_of_lists):\n \"\"\"Returns the list in a list of lists whose sum of elements is the highest.\"\"\"\n # Initialize the maximum sum and the corresponding list\n max_sum = float('-inf')\n max_list = []\n\n # Iterate over each list in the list of lists\n for lst in lists_of_lists:\n # Calculate the sum of the current list\n current_sum = sum(lst)\n\n # Check if the current sum is greater than the max sum found so far\n if current_sum > max_sum:\n max_sum = current_sum\n max_list = lst\n\n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n # Initialize variables to track the maximum sum and the corresponding list\n max_sum = float('-inf')\n max_list = []\n \n for lst in lists:\n # Calculate the sum of the current list\n current_sum = sum(lst)\n # Update if the current sum is greater than the max sum recorded\n if current_sum > max_sum:\n max_sum = current_sum\n max_list = lst\n \n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(list_of_lists):\n \"\"\"\n Returns the list in a list of lists whose sum of elements is the highest.\n \"\"\"\n max_sum = float('-inf')\n max_list = []\n \n for lst in list_of_lists:\n current_sum = sum(lst)\n if current_sum > max_sum:\n max_sum = current_sum\n max_list = lst\n \n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists_of_lists):\n \"\"\"\n Returns the list from a list of lists whose sum of elements is the highest.\n \n Parameters:\n lists_of_lists (list of list of int): A list of lists, where each sublist contains integers.\n \n Returns:\n list: The sublist with the highest sum of elements.\n \"\"\"\n # Initialize variables to keep track of the maximum sum and the corresponding list\n max_sum = float('-inf')\n max_sum_list = None\n \n for lst in lists_of_lists:\n current_sum = sum(lst)\n if current_sum > max_sum:\n max_sum = current_sum\n max_sum_list = lst\n \n return max_sum_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(list_of_lists):\n # Check if the input list is empty\n if not list_of_lists:\n return []\n \n # Initialize variables to track the maximum sum and corresponding list\n max_sum = None\n max_list = None\n \n for lst in list_of_lists:\n # Calculate the sum of the current list\n current_sum = sum(lst)\n \n # If this is the first list or the current sum is greater than the max sum\n if max_sum is None or current_sum > max_sum:\n max_sum = current_sum\n max_list = lst\n \n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(list_of_lists):\n # Check if the list_of_lists is not empty\n if not list_of_lists:\n return None\n \n # Initialize variables to track the maximum sum and the list with that sum\n max_sum = float('-inf')\n max_list = None\n \n # Iterate over each list in the list of lists\n for lst in list_of_lists:\n # Calculate the sum of the current list\n current_sum = sum(lst)\n # Check if this is the largest sum found so far\n if current_sum > max_sum:\n max_sum = current_sum\n max_list = lst\n \n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(list_of_lists):\n # Check if the input is empty\n if not list_of_lists:\n return None\n\n # Initialize the maximum sum and the corresponding list\n max_sum = float('-inf')\n max_list = None\n\n # Iterate through each list in the list of lists\n for lst in list_of_lists:\n # Calculate the sum of the current list\n current_sum = sum(lst)\n # Update max_sum and max_list if current_sum is greater\n if current_sum > max_sum:\n max_sum = current_sum\n max_list = lst\n\n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(list_of_lists):\n # Initialize variables to keep track of the list with the highest sum\n max_sum = float('-inf')\n max_list = None\n \n # Iterate over each list in the list of lists\n for lst in list_of_lists:\n # Calculate the sum of the current list\n current_sum = sum(lst)\n \n # Check if this is the highest sum we've encountered\n if current_sum > max_sum:\n max_sum = current_sum\n max_list = lst\n \n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n \"\"\"\n Returns the list in a list of lists whose sum of elements is the highest.\n \n :param lists: List of lists of numbers\n :return: List with the maximum sum of elements\n \"\"\"\n # Using max with a custom key to find the list with the maximum sum\n return max(lists, key=sum)", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n # Initialize variables to keep track of the list with the highest sum and the highest sum\n max_list = None\n max_sum = float('-inf') # Negative infinity to ensure any sum will be higher\n\n # Iterate over each list in the list of lists\n for lst in lists:\n current_sum = sum(lst) # Calculate the sum of the current list\n if current_sum > max_sum:\n max_sum = current_sum\n max_list = lst\n \n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists_of_lists):\n \"\"\"\n Returns the list in a list of lists whose sum of elements is the highest.\n :param lists_of_lists: List of lists of integers\n :return: List with the highest sum of its elements\n \"\"\"\n # Initialize the maximum sum as negative infinity and the result list as None\n max_sum = float('-inf')\n result_list = None\n\n # Iterate over each list in the list of lists\n for current_list in lists_of_lists:\n # Calculate the sum of the current list\n current_sum = sum(current_list)\n \n # Update the maximum sum and result list if the current sum is higher\n if current_sum > max_sum:\n max_sum = current_sum\n result_list = current_list\n\n return result_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n \"\"\"\n Returns the sublist with the highest sum of elements from a list of lists.\n If two or more sublists have the same highest sum, returns the first one.\n \"\"\"\n if not lists: # Handle case for empty input list\n return None\n\n # Initialize the max_sum to a very small number and max_list to an empty list\n max_sum = float('-inf')\n max_list = []\n\n for lst in lists:\n current_sum = sum(lst)\n if current_sum > max_sum:\n max_sum = current_sum\n max_list = lst\n\n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(list_of_lists):\n # Initialize the maximum sum as negative infinity and the result list as None\n max_sum = float('-inf')\n result_list = None\n \n # Iterate over each list in the list of lists\n for sublist in list_of_lists:\n # Calculate the sum of the current sublist\n current_sum = sum(sublist)\n # If the current sum is greater than the max_sum, update the max_sum and result_list\n if current_sum > max_sum:\n max_sum = current_sum\n result_list = sublist\n \n # Return the list with the highest sum\n return result_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(list_of_lists):\n # Initialize the maximum sum and the list with the maximum sum\n max_sum = float('-inf')\n max_sum_list = None\n \n # Iterate through each list in the list of lists\n for lst in list_of_lists:\n # Calculate the sum of the current list\n current_sum = sum(lst)\n \n # If the current sum is greater than the maximum sum found so far,\n # update the maximum sum and the list with the maximum sum\n if current_sum > max_sum:\n max_sum = current_sum\n max_sum_list = lst\n \n return max_sum_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n # Initialize variables to store the list with the highest sum and the highest sum found so far\n max_list = []\n max_sum = float('-inf') # Start with the smallest possible number\n\n for sublist in lists:\n current_sum = sum(sublist) # Calculate the sum of the current sublist\n if current_sum > max_sum: # If this sum is greater than the current known max\n max_sum = current_sum # Update the max_sum\n max_list = sublist # Update the max_list to the current sublist\n\n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n \"\"\"\n Returns the list in a list of lists whose sum of elements is the highest.\n \n Args:\n lists (list of lists): A list where each element is a list of numbers.\n \n Returns:\n list: The list with the highest sum of elements.\n \"\"\"\n # Initialize the variables to track the maximum sum and the corresponding list\n max_sum = float('-inf')\n max_list = []\n \n # Iterate over each list in the list of lists\n for current_list in lists:\n # Calculate the sum of the current list\n current_sum = sum(current_list)\n \n # If the current sum is greater than the max_sum found so far\n if current_sum > max_sum:\n # Update max_sum and max_list\n max_sum = current_sum\n max_list = current_list\n \n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(list_of_lists):\n # Initialize a variable to hold the list with the maximum sum\n max_list = None\n # Initialize a variable to hold the maximum sum\n max_sum = float('-inf')\n \n # Iterate over each list in the list of lists\n for lst in list_of_lists:\n # Calculate the sum of the current list\n current_sum = sum(lst)\n # If the current sum is greater than the maximum sum found so far\n if current_sum > max_sum:\n # Update the maximum sum and the max list\n max_sum = current_sum\n max_list = lst\n \n # Return the list with the maximum sum\n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists_of_lists):\n # Calculate the sum of elements for each sublist\n sums = [sum(sublist) for sublist in lists_of_lists]\n \n # Find the index of the maximum sum\n max_index = sums.index(max(sums))\n \n # Return the sublist with the maximum sum\n return lists_of_lists[max_index]", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n \"\"\"\n This function receives a list of lists and returns the list with the highest sum of its elements.\n \"\"\"\n # Find the list with the maximum sum\n max_list = max(lists, key=sum)\n return max_list", "matching_cluster_idx": 4}]}, "Mbpp/808": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def check_K(tup, k):\n \"\"\"\n Check if the given tuple contains the element k.\n \n Parameters:\n tup (tuple): The tuple to check.\n k (any): The element to search for in the tuple.\n \n Returns:\n bool: True if k is found in the tuple, False otherwise.\n \"\"\"\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n \"\"\"\n Check if the given tuple contains the element k.\n\n :param tup: A tuple of elements\n :param k: The element to check for\n :return: True if k is in the tuple, False otherwise\n \"\"\"\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(tuples, k):\n \"\"\"\n This function checks if the given tuple contains the element k.\n\n :param tuples: A tuple of integers\n :param k: An integer to check for in the tuple\n :return: True if k is in the tuple, False otherwise\n \"\"\"\n return k in tuples", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n \"\"\"\n Check if the tuple 'tup' contains the element 'k'.\n\n Parameters:\n tup (tuple): A tuple of elements to check within.\n k (any): An element to check for in the tuple.\n\n Returns:\n bool: True if 'k' is in the tuple 'tup', otherwise False.\n \"\"\"\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(tpl, k):\n \"\"\"\n Check if the given value k is present in the tuple tpl.\n\n Parameters:\n tpl (tuple): A tuple of elements.\n k (any): The value to check for in the tuple.\n\n Returns:\n bool: True if k is found in the tuple, False otherwise.\n \"\"\"\n return k in tpl", "matching_cluster_idx": 5}, {"solution": "def check_K(tpl, k):\n \"\"\"\n Check if the given tuple contains the element k.\n\n Parameters:\n tpl (tuple): The tuple to check.\n k (any): The element to look for in the tuple.\n\n Returns:\n bool: True if k is found in tpl, False otherwise.\n \"\"\"\n return k in tpl", "matching_cluster_idx": 5}, {"solution": "def check_K(tpl, k):\n \"\"\"\n Function to check if the given tuple contains the element k.\n \n Parameters:\n tpl (tuple): The tuple to be checked.\n k (any): The element to be searched in the tuple.\n \n Returns:\n bool: True if the element k is present in the tuple, otherwise False.\n \"\"\"\n return k in tpl", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n \"\"\"\n Check if the given tuple contains the element k.\n\n Parameters:\n tup (tuple): The tuple to check.\n k (any): The element to find in the tuple.\n\n Returns:\n bool: True if k is found in tup, False otherwise.\n \"\"\"\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n \"\"\"\n Check if the given tuple contains the integer k.\n\n :param tup: A tuple of integers\n :param k: An integer to search for in the tuple\n :return: True if k is in the tuple, otherwise False\n \"\"\"\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(tpl, k):\n \"\"\"\n Function to check if the tuple contains the element k.\n \n Parameters:\n tpl (tuple): A tuple of elements\n k (int or any type): The element to search for in the tuple\n \n Returns:\n bool: True if the element k is found in the tuple, False otherwise\n \"\"\"\n return k in tpl", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n \"\"\"\n Check if the given tuples contain the k or not.\n\n Args:\n tup (tuple): The tuple to be checked.\n k (int): The element to find in the tuple.\n\n Returns:\n bool: True if k is in the tuple, False otherwise.\n \"\"\"\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n \"\"\"\n This function checks if the given tuple `tup` contains the element `k`.\n \n Parameters:\n tup (tuple): A tuple of elements to search within.\n k (any): The element to check for within the tuple.\n \n Returns:\n bool: True if `k` is found in `tup`, False otherwise.\n \"\"\"\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n \"\"\"\n Check if the tuple contains the element k.\n\n Parameters:\n tup (tuple): The tuple to check.\n k (any): The element to find in the tuple.\n\n Returns:\n bool: True if k is in the tuple, False otherwise.\n \"\"\"\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n \"\"\"\n Check if the tuple `tup` contains the element `k`.\n\n :param tup: A tuple of elements\n :param k: An element to search for in the tuple\n :return: True if `k` is in `tup`, False otherwise\n \"\"\"\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(tuples, k):\n \"\"\"\n This function checks if the given integer k is present in the tuple.\n \n :param tuples: A tuple of integers\n :param k: An integer to be checked for presence in the tuple\n :return: True if k is present in the tuple, otherwise False\n \"\"\"\n return k in tuples", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n \"\"\"\n This function checks if the given tuple 'tup' contains the value 'k'.\n \n :param tup: A tuple of integers.\n :param k: An integer to search for in the tuple.\n :return: True if 'k' is in 'tup', otherwise False.\n \"\"\"\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n \"\"\"\n Function to check if the given tuple contains the integer k.\n\n :param tup: A tuple of integers.\n :param k: An integer to check for in the tuple.\n :return: True if k is in the tuple, False otherwise.\n \"\"\"\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n \"\"\"\n Check if the tuple contains the value k.\n\n :param tup: A tuple of elements\n :param k: The value to check for in the tuple\n :return: True if the tuple contains k, otherwise False\n \"\"\"\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(tpl, k):\n \"\"\"\n Check if the tuple contains the given value k.\n \n Parameters:\n tpl (tuple): A tuple of elements.\n k: A value to check for in the tuple.\n \n Returns:\n bool: True if k is in tpl, otherwise False.\n \"\"\"\n return k in tpl", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n \"\"\"\n This function checks if the given tuple 'tup' contains the element 'k'.\n \n Parameters:\n tup (tuple): The tuple in which to search for the element.\n k (any): The element to search for within the tuple.\n \n Returns:\n bool: True if 'k' is found in the tuple, False otherwise.\n \"\"\"\n return k in tup", "matching_cluster_idx": 5}]}}} \ No newline at end of file diff --git a/results/evalperf/gpt-4o-mini-2024-07-18_openai_temp_1.0_evalperf_results.brief.json b/results/evalperf/gpt-4o-mini-2024-07-18_openai_temp_1.0_evalperf_results.brief.json new file mode 100644 index 0000000..e8ba641 --- /dev/null +++ b/results/evalperf/gpt-4o-mini-2024-07-18_openai_temp_1.0_evalperf_results.brief.json @@ -0,0 +1 @@ +{"date": "2024-10-19 16:30", "config": {"n_samples": 100, "temperature": 1.0, "min_correct": 10, "max_profile": 20}, "summary": {"dps": 84.19186096830988, "dps_norm": 79.21827803090933, "pass@1": 85.51694915254237}, "eval": {"HumanEval/9": {"dps": 76.15141955835962, "dps_norm": 73.88888888888889, "pass@1": 100.0, "profiled": [{"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n \n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n \n max_so_far = numbers[0]\n result = [max_so_far]\n \n for num in numbers[1:]:\n if num > max_so_far:\n max_so_far = num\n result.append(max_so_far)\n \n return result", "matching_cluster_idx": 7}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n \n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n \n max_so_far = numbers[0]\n result = [max_so_far]\n \n for number in numbers[1:]:\n if number > max_so_far:\n max_so_far = number\n result.append(max_so_far)\n \n return result", "matching_cluster_idx": 8}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n \n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n \n max_list = []\n current_max = numbers[0]\n \n for number in numbers:\n current_max = max(current_max, number)\n max_list.append(current_max)\n \n return max_list", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n \n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n \n result = []\n current_max = numbers[0]\n\n for number in numbers:\n if number > current_max:\n current_max = number\n result.append(current_max)\n\n return result", "matching_cluster_idx": 8}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n \n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n\n result = []\n current_max = numbers[0]\n \n for number in numbers:\n if number > current_max:\n current_max = number\n result.append(current_max)\n \n return result", "matching_cluster_idx": 8}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n \n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n \n max_so_far = numbers[0]\n result = [max_so_far]\n \n for num in numbers[1:]:\n if num > max_so_far:\n max_so_far = num\n result.append(max_so_far)\n \n return result", "matching_cluster_idx": 7}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n \n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n \n max_so_far = numbers[0]\n result = [max_so_far]\n \n for num in numbers[1:]:\n if num > max_so_far:\n max_so_far = num\n result.append(max_so_far)\n \n return result", "matching_cluster_idx": 7}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n \n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n \n rolling_max_list = []\n current_max = numbers[0]\n \n for number in numbers:\n current_max = max(current_max, number)\n rolling_max_list.append(current_max)\n \n return rolling_max_list", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n \n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n\n result = []\n current_max = numbers[0]\n \n for number in numbers:\n current_max = max(current_max, number)\n result.append(current_max)\n \n return result", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n \n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n \n rolling_max_list = []\n current_max = numbers[0]\n \n for number in numbers:\n if number > current_max:\n current_max = number\n rolling_max_list.append(current_max)\n \n return rolling_max_list", "matching_cluster_idx": 8}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum elements found until the given moment\n in the sequence.\n \n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n \n max_so_far = numbers[0]\n result = [max_so_far]\n \n for num in numbers[1:]:\n max_so_far = max(max_so_far, num)\n result.append(max_so_far)\n \n return result", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n \n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n \n rolling_max_list = []\n current_max = numbers[0]\n \n for number in numbers:\n current_max = max(current_max, number)\n rolling_max_list.append(current_max)\n \n return rolling_max_list", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n \n max_so_far = numbers[0]\n result = [max_so_far]\n\n for num in numbers[1:]:\n max_so_far = max(max_so_far, num)\n result.append(max_so_far)\n \n return result", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum elements found until the given moment\n in the sequence.\n \n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n \n max_so_far = numbers[0]\n result = [max_so_far]\n \n for number in numbers[1:]:\n max_so_far = max(max_so_far, number)\n result.append(max_so_far)\n \n return result", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n \n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n\n max_so_far = numbers[0]\n result = [max_so_far]\n\n for num in numbers[1:]:\n max_so_far = max(max_so_far, num)\n result.append(max_so_far)\n\n return result", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n \n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n \n max_so_far = numbers[0]\n result = [max_so_far]\n\n for num in numbers[1:]:\n max_so_far = max(max_so_far, num)\n result.append(max_so_far)\n \n return result", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum elements found until a given moment\n in the sequence.\n \n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n \n result = []\n current_max = numbers[0]\n \n for num in numbers:\n if num > current_max:\n current_max = num\n result.append(current_max)\n \n return result", "matching_cluster_idx": 8}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\"From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n \n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n\n max_list = []\n current_max = numbers[0]\n\n for number in numbers:\n if number > current_max:\n current_max = number\n max_list.append(current_max)\n\n return max_list", "matching_cluster_idx": 8}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n \n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n\n rolling_max_list = []\n current_max = numbers[0]\n \n for number in numbers:\n current_max = max(current_max, number)\n rolling_max_list.append(current_max)\n \n return rolling_max_list", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n \n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n\n result = []\n current_max = numbers[0]\n \n for number in numbers:\n current_max = max(current_max, number)\n result.append(current_max)\n \n return result", "matching_cluster_idx": 4}]}, "HumanEval/0": {"dps": 54.70930232558139, "dps_norm": 59.28571428571429, "pass@1": 100.0, "profiled": [{"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n \n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n # Sort the list to make it easier to find close elements\n numbers.sort()\n \n # Compare each pair of adjacent numbers\n for i in range(len(numbers) - 1):\n if abs(numbers[i] - numbers[i + 1]) < threshold:\n return True\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n \n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n numbers.sort() # Sort the list to make comparison easier\n for i in range(len(numbers) - 1):\n # Check if the difference between consecutive numbers is less than the threshold\n if numbers[i + 1] - numbers[i] < threshold:\n return True\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n \n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n # Sort the numbers to allow for efficient checking of proximity\n numbers.sort()\n # Iterate through the sorted list and check adjacent elements\n for i in range(len(numbers) - 1):\n if numbers[i + 1] - numbers[i] < threshold:\n return True\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n # Sort the numbers to make the distance checking more efficient\n numbers.sort()\n \n # Check adjacent numbers in the sorted list\n for i in range(len(numbers) - 1):\n if abs(numbers[i] - numbers[i + 1]) < threshold:\n return True\n \n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n \n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n # Sort the list of numbers\n sorted_numbers = sorted(numbers)\n \n # Check pairs of adjacent numbers\n for i in range(len(sorted_numbers) - 1):\n if sorted_numbers[i + 1] - sorted_numbers[i] < threshold:\n return True\n \n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n numbers.sort() # Sort the numbers to make it easier to find close elements\n for i in range(len(numbers) - 1):\n if numbers[i + 1] - numbers[i] < threshold: # Compare adjacent elements\n return True\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\"Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n \n Args:\n numbers: A list of floating point numbers.\n threshold: A floating point number representing the threshold distance.\n \n Returns:\n A boolean indicating if any two numbers are closer than the threshold.\n \n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n # Sort the numbers to check only adjacent pairs\n sorted_numbers = sorted(numbers)\n # Iterate through sorted numbers and check the difference between adjacent numbers\n for i in range(len(sorted_numbers) - 1):\n if abs(sorted_numbers[i] - sorted_numbers[i + 1]) < threshold:\n return True\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n \n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n numbers.sort() # Sort the numbers to make comparison easier\n for i in range(len(numbers) - 1):\n if abs(numbers[i] - numbers[i + 1]) < threshold:\n return True\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n \n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n # Sort the list to make it easier to find close pairs\n numbers.sort()\n \n # Compare each number with the next one\n for i in range(len(numbers) - 1):\n if numbers[i + 1] - numbers[i] < threshold:\n return True\n \n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n # Sort the numbers to make it easier to check for close elements\n numbers.sort()\n \n # Compare each number to the next one in the sorted list\n for i in range(len(numbers) - 1):\n if abs(numbers[i] - numbers[i + 1]) < threshold:\n return True\n \n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n \n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n n = len(numbers)\n for i in range(n):\n for j in range(i + 1, n):\n if abs(numbers[i] - numbers[j]) < threshold:\n return True\n return False", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n \n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n numbers.sort()\n for i in range(1, len(numbers)):\n if numbers[i] - numbers[i - 1] < threshold:\n return True\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n \n Args:\n numbers (List[float]): A list of float numbers.\n threshold (float): The threshold distance to check against.\n\n Returns:\n bool: True if there are any two numbers that are closer than the threshold, False otherwise.\n\n Examples:\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n # Sort the numbers to make it easier to check adjacent pairs\n sorted_numbers = sorted(numbers)\n\n # Check the distance between each pair of adjacent numbers\n for i in range(len(sorted_numbers) - 1):\n if abs(sorted_numbers[i] - sorted_numbers[i + 1]) < threshold:\n return True\n\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n \n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n # Sort the list to make it easier to find close elements\n numbers.sort()\n\n # Check consecutive elements for closeness\n for i in range(len(numbers) - 1):\n if abs(numbers[i] - numbers[i + 1]) < threshold:\n return True\n \n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n # Sort the list to make it easier to check adjacent elements\n sorted_numbers = sorted(numbers)\n \n # Check the difference between adjacent numbers\n for i in range(len(sorted_numbers) - 1):\n if abs(sorted_numbers[i] - sorted_numbers[i + 1]) < threshold:\n return True\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n \n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n # Sort the numbers first\n numbers.sort()\n \n # Check pairs of adjacent numbers in the sorted list\n for i in range(len(numbers) - 1):\n if abs(numbers[i] - numbers[i + 1]) < threshold:\n return True\n \n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n \n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n # Sort the list of numbers\n numbers.sort()\n \n # Iterate through the sorted list and check the difference between consecutive elements\n for i in range(len(numbers) - 1):\n if abs(numbers[i] - numbers[i + 1]) < threshold:\n return True\n \n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n \n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n >>> has_close_elements([1.0, 1.3, 1.6], 0.4)\n True\n >>> has_close_elements([], 1.0)\n False\n >>> has_close_elements([1.0], 0.5)\n False\n \"\"\"\n # Sort the list to make it easier to find close elements\n numbers.sort()\n \n # Compare each number to the next number in the sorted list\n for i in range(len(numbers) - 1):\n if abs(numbers[i] - numbers[i + 1]) < threshold:\n return True\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n \n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n numbers.sort()\n for i in range(1, len(numbers)):\n if numbers[i] - numbers[i - 1] < threshold:\n return True\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n \n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n # Sort the list of numbers first\n numbers.sort()\n # Iterate through the sorted numbers and check differences\n for i in range(len(numbers) - 1):\n if abs(numbers[i] - numbers[i + 1]) < threshold:\n return True\n return False", "matching_cluster_idx": 3}]}, "HumanEval/4": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n \n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if not numbers:\n return 0.0 # Return 0 for empty list to avoid division by zero\n\n mean = sum(numbers) / len(numbers)\n deviations = [abs(x - mean) for x in numbers]\n mad = sum(deviations) / len(deviations)\n return mad", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" \n For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n \n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if not numbers:\n return 0.0 # Return 0 for an empty list to avoid division by zero\n \n mean_value = sum(numbers) / len(numbers) # Calculate the mean\n mad = sum(abs(x - mean_value) for x in numbers) / len(numbers) # Calculate Mean Absolute Deviation\n \n return mad", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n \n Args:\n numbers (List[float]): A list of numbers.\n\n Returns:\n float: The Mean Absolute Deviation of the input numbers.\n\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if not numbers:\n return 0.0\n\n mean = sum(numbers) / len(numbers)\n mad = sum(abs(x - mean) for x in numbers) / len(numbers)\n return mad", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n \n Args:\n numbers (List[float]): A list of float numbers.\n\n Returns:\n float: The mean absolute deviation of the input numbers.\n\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if not numbers:\n return 0.0 # Handle empty list case\n \n mean_value = sum(numbers) / len(numbers)\n deviations = [abs(x - mean_value) for x in numbers]\n mad = sum(deviations) / len(deviations)\n return mad", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n \n Args:\n numbers (List[float]): A list of numerical values.\n \n Returns:\n float: The Mean Absolute Deviation of the input numbers.\n \n Examples:\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n >>> mean_absolute_deviation([1.0, 1.0, 1.0])\n 0.0\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0, 5.0])\n 1.0\n \"\"\"\n if not numbers:\n return 0.0\n \n mean_value = sum(numbers) / len(numbers)\n deviations = [abs(x - mean_value) for x in numbers]\n mad = sum(deviations) / len(deviations)\n \n return mad", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n \n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if not numbers:\n return 0.0 # Handle the case of an empty list\n\n mean_value = sum(numbers) / len(numbers)\n mad = sum(abs(x - mean_value) for x in numbers) / len(numbers)\n return mad", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\"For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n \n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if not numbers:\n return 0.0\n\n mean = sum(numbers) / len(numbers)\n mad = sum(abs(x - mean) for x in numbers) / len(numbers)\n return mad", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n \n Args:\n numbers (List[float]): A list of numerical values.\n \n Returns:\n float: The Mean Absolute Deviation of the numbers.\n \n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if not numbers:\n return 0.0 # Return 0 for empty list to avoid division by zero\n \n mean_value = sum(numbers) / len(numbers)\n absolute_deviations = [abs(x - mean_value) for x in numbers]\n mad = sum(absolute_deviations) / len(numbers)\n \n return mad", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n \n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if not numbers:\n return 0.0 # Return 0.0 for an empty list to avoid division by zero\n \n # Calculate the mean of the numbers\n mean = sum(numbers) / len(numbers)\n \n # Calculate the Mean Absolute Deviation\n mad = sum(abs(x - mean) for x in numbers) / len(numbers)\n \n return mad", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\"For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if not numbers:\n return 0.0\n\n mean = sum(numbers) / len(numbers)\n mad = sum(abs(x - mean) for x in numbers) / len(numbers)\n return mad", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\"For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n \n Args:\n numbers (List[float]): A list of numbers to calculate the MAD for.\n\n Returns:\n float: The Mean Absolute Deviation of the input numbers.\n\n Examples:\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if not numbers:\n return 0.0 # Handle the case of an empty list\n \n mean_value = sum(numbers) / len(numbers)\n mad = sum(abs(x - mean_value) for x in numbers) / len(numbers)\n \n return mad", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n \n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if not numbers:\n return 0.0 # Handle empty list case\n \n # Calculate the mean of the numbers\n mean = sum(numbers) / len(numbers)\n \n # Calculate the absolute deviations from the mean\n absolute_deviations = [abs(x - mean) for x in numbers]\n \n # Calculate the mean of the absolute deviations\n mad = sum(absolute_deviations) / len(absolute_deviations)\n \n return mad", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n \n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if not numbers:\n return 0.0 # Return 0 for empty list to avoid division by zero\n \n mean_value = sum(numbers) / len(numbers) # Calculate the mean\n absolute_deviations = [abs(x - mean_value) for x in numbers] # Calculate absolute deviations\n mad = sum(absolute_deviations) / len(numbers) # Calculate the mean of absolute deviations\n \n return mad", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n \n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if not numbers:\n return 0.0 # If the list is empty, return 0 as MAD is not defined\n\n mean_value = sum(numbers) / len(numbers) # Calculate the mean\n mad = sum(abs(x - mean_value) for x in numbers) / len(numbers) # Calculate MAD\n\n return mad", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n \n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if not numbers:\n return 0.0 # Return 0 for an empty list to avoid division by zero\n\n # Calculate the mean\n mean_value = sum(numbers) / len(numbers)\n\n # Calculate the absolute deviations from the mean\n absolute_deviations = [abs(x - mean_value) for x in numbers]\n\n # Calculate the Mean Absolute Deviation\n mad = sum(absolute_deviations) / len(absolute_deviations)\n\n return mad", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n \n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if not numbers:\n return 0.0 # Handle the case of an empty list\n \n mean = sum(numbers) / len(numbers) # Calculate the mean\n deviations = [abs(x - mean) for x in numbers] # Calculate absolute deviations\n mad = sum(deviations) / len(numbers) # Calculate the mean of absolute deviations\n return mad", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n \n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if not numbers:\n return 0.0 # Handle the case of an empty list\n\n # Calculate the mean of the numbers\n x_mean = sum(numbers) / len(numbers)\n \n # Calculate the absolute deviations from the mean\n absolute_deviations = [abs(x - x_mean) for x in numbers]\n \n # Calculate the mean of the absolute deviations\n mad = sum(absolute_deviations) / len(absolute_deviations)\n \n return mad", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n \n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if not numbers:\n return 0.0\n \n mean_value = sum(numbers) / len(numbers)\n mad = sum(abs(x - mean_value) for x in numbers) / len(numbers)\n return mad", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n \n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if not numbers:\n return 0.0 # Return 0 for empty list\n\n mean_value = sum(numbers) / len(numbers) # Calculate the mean\n mad = sum(abs(x - mean_value) for x in numbers) / len(numbers) # Calculate the MAD\n return mad", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n \n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if not numbers:\n return 0.0 # Return 0 for empty list to avoid division by zero\n \n mean = sum(numbers) / len(numbers)\n mad = sum(abs(x - mean) for x in numbers) / len(numbers)\n return mad", "matching_cluster_idx": 5}]}, "HumanEval/16": {"dps": 44.263565891472865, "dps_norm": 86.11111111111111, "pass@1": 87.0, "profiled": [{"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lowercase to handle case insensitivity\n lowercased_string = string.lower()\n # Use a set to find distinct characters\n distinct_characters = set(lowercased_string)\n # Return the number of distinct characters\n return len(distinct_characters)", "matching_cluster_idx": 7}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" \n Given a string, find out how many distinct characters (regardless of case) does it consist of.\n \n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lowercase to handle case insensitivity\n string_lower = string.lower()\n # Use a set to find distinct characters\n distinct_characters = set(string_lower)\n # Return the number of distinct characters\n return len(distinct_characters)", "matching_cluster_idx": 7}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lowercase and create a set of characters to find distinct ones\n distinct_characters = set(string.lower())\n # Return the number of distinct characters\n return len(distinct_characters)", "matching_cluster_idx": 7}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" \n Given a string, find out how many distinct characters (regardless of case) it consists of.\n\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lowercase and use a set to find distinct characters\n distinct_characters = set(string.lower())\n \n # Return the number of distinct characters\n return len(distinct_characters)", "matching_cluster_idx": 7}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lowercase and use a set to find distinct characters\n distinct_characters = set(string.lower())\n \n # Remove non-alphabetic characters if needed (optional, based on the problem definition)\n # distinct_characters = {char for char in distinct_characters if char.isalpha()}\n\n return len(distinct_characters)", "matching_cluster_idx": 7}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of.\n \n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lower case and create a set of characters to count distinct ones\n distinct_characters = set(string.lower())\n # Return the count of distinct characters\n return len(distinct_characters)", "matching_cluster_idx": 7}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of.\n \n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lower case to ensure case insensitivity\n lower_case_string = string.lower()\n \n # Use a set to get distinct characters\n distinct_characters = set(lower_case_string)\n \n # Return the count of distinct characters\n return len(distinct_characters)", "matching_cluster_idx": 7}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lowercase and create a set of characters to find distinct ones\n distinct_characters = set(string.lower())\n # Return the number of distinct characters\n return len(distinct_characters)", "matching_cluster_idx": 7}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" \n Given a string, find out how many distinct characters (regardless of case) does it consist of.\n \n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lowercase to ignore case\n lower_case_string = string.lower()\n \n # Use a set to store distinct characters\n distinct_characters = set(lower_case_string)\n \n # Return the number of distinct characters\n return len(distinct_characters)", "matching_cluster_idx": 7}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of.\n \n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lowercase to handle case insensitivity\n lowercased_string = string.lower()\n # Create a set of characters to find distinct characters\n distinct_characters = set(lowercased_string)\n # Return the number of distinct characters\n return len(distinct_characters)", "matching_cluster_idx": 7}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of.\n \n Args:\n string (str): The input string.\n \n Returns:\n int: The count of distinct characters in the string, ignoring case.\n \n Examples:\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lowercase and create a set of characters to get distinct values\n distinct_characters = set(string.lower())\n return len(distinct_characters)", "matching_cluster_idx": 7}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" \n Given a string, find out how many distinct characters (regardless of case) it consists of.\n \n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lower case to ensure case insensitivity\n string_lower = string.lower()\n \n # Use a set to store distinct characters\n distinct_characters = set(string_lower)\n \n # Return the number of distinct characters\n return len(distinct_characters)", "matching_cluster_idx": 7}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of.\n \n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Use a set to store distinct characters, converting to lower case\n distinct_characters = set(char.lower() for char in string)\n \n # Return the number of distinct characters\n return len(distinct_characters)", "matching_cluster_idx": 2}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" \n Given a string, find out how many distinct characters (regardless of case) does it consist of.\n \n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lowercase and create a set of characters to remove duplicates\n distinct_characters = set(string.lower())\n # Return the number of distinct characters\n return len(distinct_characters)", "matching_cluster_idx": 7}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" \n Given a string, find out how many distinct characters (regardless of case) does it consist of.\n \n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lowercase to ignore case\n lower_string = string.lower()\n # Use a set to find distinct characters\n distinct_characters = set(lower_string)\n # Return the number of distinct characters\n return len(distinct_characters)", "matching_cluster_idx": 7}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" \n Given a string, find out how many distinct characters (regardless of case) does it consist of.\n \n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lowercase to count characters regardless of case\n lowercase_string = string.lower()\n # Use a set to find distinct characters\n distinct_characters = set(lowercase_string)\n # Return the number of distinct characters\n return len(distinct_characters)", "matching_cluster_idx": 7}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" \n Given a string, find out how many distinct characters (regardless of case) it consists of.\n\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lowercase to ignore case\n lower_string = string.lower()\n \n # Use a set to find distinct characters\n distinct_characters = set(lower_string)\n \n # Return the number of distinct characters\n return len(distinct_characters)", "matching_cluster_idx": 7}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lower case to ignore case sensitivity\n string = string.lower()\n # Use a set to store distinct characters\n distinct_characters = set(string)\n # Return the count of distinct characters\n return len(distinct_characters)", "matching_cluster_idx": 7}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) it consists of.\n \n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lowercase and create a set of characters\n distinct_characters = set(string.lower())\n \n # Return the number of distinct characters\n return len(distinct_characters)", "matching_cluster_idx": 7}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of.\n \n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lowercase to ensure case insensitivity\n string_lower = string.lower()\n \n # Use a set to store distinct characters\n distinct_characters = set(string_lower)\n \n # Return the number of distinct characters\n return len(distinct_characters)", "matching_cluster_idx": 7}]}, "HumanEval/20": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n \n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n # Sort the list of numbers\n sorted_numbers = sorted(numbers)\n\n # Initialize the closest pair and the smallest distance found\n closest_pair = (sorted_numbers[0], sorted_numbers[1])\n smallest_distance = abs(sorted_numbers[1] - sorted_numbers[0])\n\n # Iterate through the sorted list to find the closest elements\n for i in range(1, len(sorted_numbers)):\n current_distance = abs(sorted_numbers[i] - sorted_numbers[i - 1])\n if current_distance < smallest_distance:\n smallest_distance = current_distance\n closest_pair = (sorted_numbers[i - 1], sorted_numbers[i])\n\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n \n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n if len(numbers) < 2:\n raise ValueError(\"List must contain at least two elements\")\n \n # Sort the numbers first\n sorted_numbers = sorted(numbers)\n \n # Initialize the minimum difference and the closest pair\n min_diff = float('inf')\n closest_pair = (0, 0)\n \n # Iterate through the sorted list and find the closest pair\n for i in range(len(sorted_numbers) - 1):\n diff = sorted_numbers[i + 1] - sorted_numbers[i]\n if diff < min_diff:\n min_diff = diff\n closest_pair = (sorted_numbers[i], sorted_numbers[i + 1])\n \n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n \n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n if len(numbers) < 2:\n raise ValueError(\"The list must contain at least two numbers.\")\n\n # Sort the numbers\n sorted_numbers = sorted(numbers)\n \n # Initialize the minimum distance and the closest pair\n min_distance = float('inf')\n closest_pair = (0.0, 0.0)\n\n # Iterate through sorted numbers to find the closest pair\n for i in range(len(sorted_numbers) - 1):\n first = sorted_numbers[i]\n second = sorted_numbers[i + 1]\n distance = second - first\n if distance < min_distance:\n min_distance = distance\n closest_pair = (first, second)\n\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n \n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n if len(numbers) < 2:\n raise ValueError(\"The input list must contain at least two numbers.\")\n \n # Sort the numbers first\n sorted_numbers = sorted(numbers)\n \n # Initialize the minimum difference and the closest pair\n min_diff = float('inf')\n closest_pair = (0.0, 0.0)\n \n # Iterate through the sorted list to find the closest pair\n for i in range(len(sorted_numbers) - 1):\n current_diff = sorted_numbers[i + 1] - sorted_numbers[i]\n if current_diff < min_diff:\n min_diff = current_diff\n closest_pair = (sorted_numbers[i], sorted_numbers[i + 1])\n \n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n \n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n # Sort the numbers to facilitate finding the closest pair\n sorted_numbers = sorted(numbers)\n \n # Initialize the smallest distance and the closest pair\n min_distance = float('inf')\n closest_pair = (0.0, 0.0)\n \n # Iterate through the sorted list to find the closest pair\n for i in range(len(sorted_numbers) - 1):\n # Calculate the distance between consecutive elements\n distance = sorted_numbers[i + 1] - sorted_numbers[i]\n \n # If this distance is smaller than the minimum found so far, update\n if distance < min_distance:\n min_distance = distance\n closest_pair = (sorted_numbers[i], sorted_numbers[i + 1])\n \n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n \n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n if len(numbers) < 2:\n raise ValueError(\"List must contain at least two numbers.\")\n \n # Sort the list first\n sorted_numbers = sorted(numbers)\n \n # Initialize the smallest difference and closest pair\n min_diff = float('inf')\n closest_pair = (0, 0)\n \n # Iterate through sorted numbers to find the closest pair\n for i in range(len(sorted_numbers) - 1):\n diff = sorted_numbers[i + 1] - sorted_numbers[i]\n if diff < min_diff:\n min_diff = diff\n closest_pair = (sorted_numbers[i], sorted_numbers[i + 1])\n \n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n \n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n # Sort the list of numbers\n sorted_numbers = sorted(numbers)\n \n # Initialize the minimum distance and the closest pair\n min_distance = float('inf')\n closest_pair = (0.0, 0.0)\n \n # Iterate through the sorted numbers to find the closest pair\n for i in range(len(sorted_numbers) - 1):\n # Calculate the distance between the current and next number\n distance = sorted_numbers[i + 1] - sorted_numbers[i]\n \n # Update the closest pair if a smaller distance is found\n if distance < min_distance:\n min_distance = distance\n closest_pair = (sorted_numbers[i], sorted_numbers[i + 1])\n \n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n \n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n >>> find_closest_elements([10.5, 2.3, 4.8, 2.1, 2.2])\n (2.1, 2.2)\n >>> find_closest_elements([5.0, 3.0, 1.0, 4.0, 2.0])\n (1.0, 2.0)\n \"\"\"\n \n # Sort the numbers\n sorted_numbers = sorted(numbers)\n \n # Initialize minimum difference and closest pair\n min_diff = float('inf')\n closest_pair = (0.0, 0.0)\n\n # Iterate through the sorted list to find the closest pair\n for i in range(len(sorted_numbers) - 1):\n num1 = sorted_numbers[i]\n num2 = sorted_numbers[i + 1]\n diff = num2 - num1\n \n if diff < min_diff:\n min_diff = diff\n closest_pair = (num1, num2)\n\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n \n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n >>> find_closest_elements([3.5, 2.1, 6.7, 2.0, 2.2, 5.1])\n (2.1, 2.2)\n >>> find_closest_elements([0.1, 0.2, 0.3, 0.4])\n (0.1, 0.2)\n >>> find_closest_elements([5.0, 5.0, 5.0])\n (5.0, 5.0)\n \"\"\"\n \n # Sort the numbers first\n sorted_numbers = sorted(numbers)\n \n # Initialize the closest pair with a large difference\n closest_pair = (sorted_numbers[0], sorted_numbers[1])\n smallest_difference = abs(sorted_numbers[1] - sorted_numbers[0])\n \n # Iterate over the sorted list to find the closest pair\n for i in range(1, len(sorted_numbers)):\n diff = abs(sorted_numbers[i] - sorted_numbers[i - 1])\n if diff < smallest_difference:\n smallest_difference = diff\n closest_pair = (sorted_numbers[i - 1], sorted_numbers[i])\n \n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n \n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n >>> find_closest_elements([5.0, 4.0, 3.0, 2.0, 1.0])\n (1.0, 2.0)\n >>> find_closest_elements([-1.0, 2.5, 3.6, 0.0])\n (0.0, 2.5)\n \"\"\"\n # Sort the numbers first\n sorted_numbers = sorted(numbers)\n \n # Initialize the minimum difference and the closest pair\n min_diff = float('inf')\n closest_pair = (0.0, 0.0)\n\n # Loop through the sorted list to find the closest pair\n for i in range(len(sorted_numbers) - 1):\n diff = sorted_numbers[i + 1] - sorted_numbers[i]\n if diff < min_diff:\n min_diff = diff\n closest_pair = (sorted_numbers[i], sorted_numbers[i + 1])\n\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n \n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n # Sort the numbers to make it easier to find the closest pairs\n sorted_numbers = sorted(numbers)\n \n # Initialize the minimum difference as infinity and the closest pair as None\n min_diff = float('inf')\n closest_pair = (0.0, 0.0)\n \n # Iterate through sorted numbers to find the closest pair\n for i in range(len(sorted_numbers) - 1):\n # Calculate the difference between consecutive numbers\n diff = sorted_numbers[i + 1] - sorted_numbers[i]\n # If this difference is smaller than the minimum difference found so far\n if diff < min_diff:\n min_diff = diff\n closest_pair = (sorted_numbers[i], sorted_numbers[i + 1])\n \n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n \n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n # Sort the list of numbers\n sorted_numbers = sorted(numbers)\n \n # Initialize the smallest difference and corresponding closest elements\n min_diff = float('inf')\n closest_pair = (0.0, 0.0)\n \n # Iterate through the sorted list to find the closest pair\n for i in range(len(sorted_numbers) - 1):\n diff = sorted_numbers[i + 1] - sorted_numbers[i]\n if diff < min_diff:\n min_diff = diff\n closest_pair = (sorted_numbers[i], sorted_numbers[i + 1])\n \n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n \n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n # Sort the list to make it easier to find the closest elements\n sorted_numbers = sorted(numbers)\n \n # Initialize the closest pair and the smallest difference found\n closest_pair = (sorted_numbers[0], sorted_numbers[1])\n smallest_difference = abs(sorted_numbers[1] - sorted_numbers[0])\n \n # Iterate through the sorted list to find the closest elements\n for i in range(1, len(sorted_numbers)):\n # Calculate the difference between consecutive elements\n difference = abs(sorted_numbers[i] - sorted_numbers[i - 1])\n \n # Check if this is the smallest difference found so far\n if difference < smallest_difference:\n smallest_difference = difference\n closest_pair = (sorted_numbers[i - 1], sorted_numbers[i])\n \n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n \n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n # Sort the numbers first\n sorted_numbers = sorted(numbers)\n \n # Initialize minimum difference and result tuple\n min_diff = float('inf')\n closest_pair = (0.0, 0.0)\n \n # Compare adjacent pairs in the sorted list\n for i in range(len(sorted_numbers) - 1):\n # Calculate the difference between adjacent numbers\n diff = sorted_numbers[i + 1] - sorted_numbers[i]\n \n # If this difference is smaller than the minimum found so far, update\n if diff < min_diff:\n min_diff = diff\n closest_pair = (sorted_numbers[i], sorted_numbers[i + 1])\n \n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n \n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n # Sort the numbers to easily find the closest pairs\n sorted_numbers = sorted(numbers)\n \n # Initialize variables to track the closest pair\n closest_pair = (sorted_numbers[0], sorted_numbers[1])\n min_diff = abs(sorted_numbers[1] - sorted_numbers[0])\n \n # Iterate through sorted numbers to find the closest pair\n for i in range(1, len(sorted_numbers)):\n current_diff = abs(sorted_numbers[i] - sorted_numbers[i - 1])\n if current_diff < min_diff:\n min_diff = current_diff\n closest_pair = (sorted_numbers[i - 1], sorted_numbers[i])\n \n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n \n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n if len(numbers) < 2:\n raise ValueError(\"The list must contain at least two elements.\")\n \n # Sort the list first\n sorted_numbers = sorted(numbers)\n \n # Initialize the minimum difference and the closest pair\n min_diff = float('inf')\n closest_pair = (0.0, 0.0)\n \n # Iterate over the sorted list to find the closest elements\n for i in range(len(sorted_numbers) - 1):\n num1 = sorted_numbers[i]\n num2 = sorted_numbers[i + 1]\n diff = num2 - num1\n \n if diff < min_diff:\n min_diff = diff\n closest_pair = (num1, num2)\n \n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n \n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n # Sort the numbers to make it easier to find the closest pairs\n sorted_numbers = sorted(numbers)\n \n # Initialize the minimum difference and the closest pair\n min_diff = float('inf')\n closest_pair = (0.0, 0.0)\n\n # Loop through the sorted numbers to find the closest pair\n for i in range(len(sorted_numbers) - 1):\n diff = sorted_numbers[i + 1] - sorted_numbers[i]\n if diff < min_diff:\n min_diff = diff\n closest_pair = (sorted_numbers[i], sorted_numbers[i + 1])\n \n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n \n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n if len(numbers) < 2:\n raise ValueError(\"List must contain at least two elements.\")\n \n # Sort the numbers\n sorted_numbers = sorted(numbers)\n\n # Initialize the minimum difference and the closest pair\n min_diff = float('inf')\n closest_pair = (0, 0)\n\n # Iterate through sorted numbers to find the closest pair\n for i in range(len(sorted_numbers) - 1):\n num1 = sorted_numbers[i]\n num2 = sorted_numbers[i + 1]\n diff = num2 - num1\n \n if diff < min_diff:\n min_diff = diff\n closest_pair = (num1, num2)\n\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n \n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n >>> find_closest_elements([0.5, 0.6, 0.2, 0.1])\n (0.1, 0.2)\n >>> find_closest_elements([10.0, 10.1, 10.2])\n (10.0, 10.1)\n \"\"\"\n # Sort the list of numbers to make it easier to find the closest pair\n sorted_numbers = sorted(numbers)\n \n # Initialize variables to track the smallest difference and the closest pair\n min_diff = float('inf')\n closest_pair = (0.0, 0.0)\n \n # Iterate through the sorted list and find the closest pair\n for i in range(len(sorted_numbers) - 1):\n num1 = sorted_numbers[i]\n num2 = sorted_numbers[i + 1]\n diff = num2 - num1\n \n if diff < min_diff:\n min_diff = diff\n closest_pair = (num1, num2)\n \n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n \n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n \n # Sort the numbers to bring closer elements next to each other\n sorted_numbers = sorted(numbers)\n \n # Initialize minimum distance with a large value\n min_distance = float('inf')\n closest_pair = (0.0, 0.0)\n \n # Iterate through the sorted list to find the closest pair\n for i in range(len(sorted_numbers) - 1):\n current_distance = abs(sorted_numbers[i] - sorted_numbers[i + 1])\n if current_distance < min_distance:\n min_distance = current_distance\n closest_pair = (sorted_numbers[i], sorted_numbers[i + 1])\n \n return closest_pair", "matching_cluster_idx": 8}]}, "HumanEval/24": {"dps": 74.421768707483, "dps_norm": 47.5, "pass@1": 100.0, "profiled": [{"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n.\n\n >>> largest_divisor(15)\n 5\n >>> largest_divisor(28)\n 14\n >>> largest_divisor(10)\n 5\n >>> largest_divisor(1)\n 0 # There is no divisor smaller than 1\n >>> largest_divisor(100)\n 50\n \"\"\"\n if n <= 1:\n return 0 # Handle the case where n is 1 or less\n\n for i in range(n // 2, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 4}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n >>> largest_divisor(10)\n 5\n >>> largest_divisor(7)\n 1\n >>> largest_divisor(1)\n 0\n \"\"\"\n if n <= 1:\n return 0 # Return 0 for 1 or negative numbers since they have no divisors < n\n \n for i in range(n // 2, 0, -1):\n if n % i == 0:\n return i\n return 1 # This line handles cases when n is prime, returning 1 as the largest divisor.", "matching_cluster_idx": 3}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n >>> largest_divisor(100)\n 50\n >>> largest_divisor(21)\n 7\n >>> largest_divisor(2)\n 1\n >>> largest_divisor(1)\n 0 # Edge case, since there are no positive divisors of 1\n \"\"\"\n if n <= 1:\n return 0 # Return 0 for n = 1 or less, as there are no positive divisors\n \n for i in range(n // 2, 0, -1): # Start from n//2 down to 1\n if n % i == 0: # Check if i is a divisor of n\n return i # Return the largest divisor found", "matching_cluster_idx": 3}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n.\n \n >>> largest_divisor(15)\n 5\n >>> largest_divisor(28)\n 14\n >>> largest_divisor(1)\n 0\n >>> largest_divisor(17)\n 1\n \"\"\"\n # Check for numbers less than or equal to 1\n if n <= 1:\n return 0 # There is no divisor for 1 or numbers less than it\n \n # Start from n//2 and go down to find the largest divisor\n for i in range(n // 2, 0, -1):\n if n % i == 0:\n return i\n return 1 # The largest divisor for any number greater than 1 is at least 1", "matching_cluster_idx": 3}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n >>> largest_divisor(12)\n 6\n >>> largest_divisor(7)\n 1\n >>> largest_divisor(1)\n 0\n \"\"\"\n # Start checking from n-1 down to 1\n for i in range(n - 1, 0, -1):\n if n % i == 0:\n return i\n return 0 # Return 0 if there are no divisors", "matching_cluster_idx": 0}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n.\n \n >>> largest_divisor(15)\n 5\n >>> largest_divisor(28)\n 14\n >>> largest_divisor(2)\n 1\n >>> largest_divisor(1)\n 0\n \"\"\"\n if n <= 1:\n return 0 # If n is 1 or less, there are no divisors smaller than n.\n \n for i in range(n // 2, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 3}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n >>> largest_divisor(10)\n 5\n >>> largest_divisor(1)\n 0\n >>> largest_divisor(28)\n 14\n \"\"\"\n if n <= 1:\n return 0 # No divisors for 1 or less\n for i in range(n // 2, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 3}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n >>> largest_divisor(10)\n 5\n >>> largest_divisor(17)\n 1\n >>> largest_divisor(1)\n 0\n >>> largest_divisor(28)\n 14\n \"\"\"\n if n <= 1:\n return 0 # If n is 1 or less, return 0 as there are no divisors smaller than n\n\n for i in range(n // 2, 0, -1): # Start checking from n // 2 down to 1\n if n % i == 0: # Check if i is a divisor of n\n return i # Return the largest divisor found", "matching_cluster_idx": 3}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n.\n \n >>> largest_divisor(15)\n 5\n >>> largest_divisor(18)\n 9\n >>> largest_divisor(10)\n 5\n >>> largest_divisor(1)\n 0\n \"\"\"\n for i in range(n // 2, 0, -1):\n if n % i == 0:\n return i\n return 0 # If there is no divisor smaller than n, return 0.", "matching_cluster_idx": 3}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n >>> largest_divisor(12)\n 6\n >>> largest_divisor(7)\n 1\n >>> largest_divisor(1)\n 0\n \"\"\"\n if n <= 1:\n return 0 # There is no positive divisor smaller than 1\n \n for i in range(n // 2, 0, -1): # Check from n//2 down to 1\n if n % i == 0:\n return i", "matching_cluster_idx": 3}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n.\n \n >>> largest_divisor(15)\n 5\n >>> largest_divisor(28)\n 14\n >>> largest_divisor(1)\n 0\n >>> largest_divisor(17)\n 1\n \"\"\"\n if n <= 1:\n return 0 # No divisors less than 1\n\n for i in range(n // 2, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 4}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n >>> largest_divisor(12)\n 6\n >>> largest_divisor(7)\n 1\n >>> largest_divisor(1)\n 0\n \"\"\"\n if n <= 1:\n return 0 # No divisors for 1 or less\n\n for i in range(n // 2, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 3}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n >>> largest_divisor(28)\n 14\n >>> largest_divisor(7)\n 1\n >>> largest_divisor(1)\n 0 # since there is no number smaller than 1 that can divide it evenly\n \"\"\"\n if n <= 1:\n return 0 # There is no positive divisor of numbers less than or equal to 1\n \n for i in range(n // 2, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 3}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n >>> largest_divisor(20)\n 10\n >>> largest_divisor(17)\n 1\n >>> largest_divisor(1)\n 0\n \"\"\"\n if n <= 1:\n return 0 # For n = 1 or less, there is no divisor smaller than n\n\n for i in range(n // 2, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 3}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n.\n \n >>> largest_divisor(15)\n 5\n >>> largest_divisor(10)\n 5\n >>> largest_divisor(7)\n 1\n >>> largest_divisor(1)\n 0\n \"\"\"\n if n <= 1:\n return 0 # There are no divisors less than 1\n \n for i in range(n // 2, 0, -1): # Check from n//2 down to 1\n if n % i == 0:\n return i", "matching_cluster_idx": 3}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n >>> largest_divisor(28)\n 14\n >>> largest_divisor(1)\n 0\n >>> largest_divisor(2)\n 1\n >>> largest_divisor(10)\n 5\n \"\"\"\n if n <= 1:\n return 0 # No positive divisors less than n for n <= 1\n for i in range(n // 2, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 3}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n >>> largest_divisor(10)\n 5\n >>> largest_divisor(7)\n 1\n >>> largest_divisor(1)\n 0\n >>> largest_divisor(28)\n 14\n \"\"\"\n # Start checking from n-1 down to 1\n for i in range(n - 1, 0, -1):\n if n % i == 0:\n return i\n return 0 # Return 0 if there is no divisor other than n itself", "matching_cluster_idx": 0}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\"For a given number n, find the largest number that divides n evenly, smaller than n.\n \n >>> largest_divisor(15)\n 5\n >>> largest_divisor(28)\n 14\n >>> largest_divisor(7)\n 1\n >>> largest_divisor(1)\n 0\n \"\"\"\n if n <= 1:\n return 0 # no positive divisor less than 1\n\n for i in range(n // 2, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 3}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n.\n \n >>> largest_divisor(15)\n 5\n >>> largest_divisor(100)\n 50\n >>> largest_divisor(7)\n 1\n >>> largest_divisor(1)\n 0 # There is no positive divisor of 1\n \"\"\"\n if n <= 1:\n return 0 # There is no positive divisor of 1 or numbers less than 1\n\n for i in range(n // 2, 0, -1): # Check from n//2 down to 1\n if n % i == 0:\n return i", "matching_cluster_idx": 3}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n \n >>> largest_divisor(15)\n 5\n >>> largest_divisor(10)\n 5\n >>> largest_divisor(7)\n 1\n >>> largest_divisor(1)\n 0\n >>> largest_divisor(28)\n 14\n \"\"\"\n if n <= 1:\n return 0 # Return 0 for n <= 1 as there are no divisors smaller than n\n \n for i in range(n // 2, 0, -1): # Check divisors from n//2 down to 1\n if n % i == 0: # If i is a divisor\n return i # Return the largest divisor found", "matching_cluster_idx": 3}]}, "HumanEval/26": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n # Count the occurrences of each number in the list\n count = {}\n for number in numbers:\n count[number] = count.get(number, 0) + 1\n\n # Collect numbers that occur only once, maintaining their order\n result = [number for number in numbers if count[number] == 1]\n return result", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n \n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n >>> remove_duplicates([1, 1, 2, 2, 3])\n [3]\n >>> remove_duplicates([4, 5, 6, 4, 5, 6])\n []\n >>> remove_duplicates([7, 8, 9])\n [7, 8, 9]\n >>> remove_duplicates([])\n []\n \"\"\"\n from collections import Counter\n \n # Count the occurrences of each number in the list\n counts = Counter(numbers)\n \n # Return a new list with only the numbers that occur once\n return [num for num in numbers if counts[num] == 1]", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n \n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n # Count occurrences of each number\n count = {}\n for number in numbers:\n count[number] = count.get(number, 0) + 1\n \n # Collect elements that occur exactly once\n result = [number for number in numbers if count[number] == 1]\n return result", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\"From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n \n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n # Count occurrences of each number\n count = {}\n for number in numbers:\n count[number] = count.get(number, 0) + 1\n\n # Keep elements that occur only once\n result = [number for number in numbers if count[number] == 1]\n \n return result", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n \n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n # Count occurrences of each number\n count = {}\n for number in numbers:\n count[number] = count.get(number, 0) + 1\n\n # Filter the numbers based on their count\n result = [number for number in numbers if count[number] == 1]\n \n return result", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n \n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n # Count occurrences of each number\n count = {}\n for num in numbers:\n count[num] = count.get(num, 0) + 1\n \n # Filter out elements that occur more than once\n result = [num for num in numbers if count[num] == 1]\n \n return result", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n \n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n # Create a dictionary to count occurrences of each number\n counts = {}\n for number in numbers:\n counts[number] = counts.get(number, 0) + 1\n\n # Create a result list including only those numbers that occur once\n result = [number for number in numbers if counts[number] == 1]\n \n return result", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n count = {}\n \n # Count occurrences of each number\n for number in numbers:\n if number in count:\n count[number] += 1\n else:\n count[number] = 1\n \n # Return elements that occur only once, maintaining order\n return [number for number in numbers if count[number] == 1]", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n \n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n count = {}\n \n # Count occurrences of each number\n for number in numbers:\n if number in count:\n count[number] += 1\n else:\n count[number] = 1\n \n # Build the result list with numbers that occur only once\n result = [number for number in numbers if count[number] == 1]\n \n return result", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\"From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n \n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n >>> remove_duplicates([1, 1, 1, 1])\n []\n >>> remove_duplicates([1, 2, 3, 4])\n [1, 2, 3, 4]\n >>> remove_duplicates([1, 2, 2, 3, 4, 4, 5])\n [1, 3, 5]\n \"\"\"\n # Count occurrences of each number\n count = {}\n for number in numbers:\n count[number] = count.get(number, 0) + 1\n \n # Filter out numbers that occur more than once\n return [number for number in numbers if count[number] == 1]", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n # Count occurrences of each number\n count = {}\n for number in numbers:\n if number in count:\n count[number] += 1\n else:\n count[number] = 1\n\n # Create a new list with only the numbers that occur once\n result = [number for number in numbers if count[number] == 1]\n\n return result", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n \n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n count = {}\n for number in numbers:\n count[number] = count.get(number, 0) + 1\n\n return [number for number in numbers if count[number] == 1]", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\"From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n >>> remove_duplicates([1, 1, 2, 2, 3, 3])\n []\n >>> remove_duplicates([1, 2, 3, 4, 5])\n [1, 2, 3, 4, 5]\n >>> remove_duplicates([1, 2, 3, 1, 2, 3])\n []\n >>> remove_duplicates([1])\n [1]\n \"\"\"\n counts = {}\n \n # Count occurrences of each number\n for number in numbers:\n counts[number] = counts.get(number, 0) + 1\n \n # Collect numbers that occur only once in the order they appeared\n result = [number for number in numbers if counts[number] == 1]\n \n return result", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n # Create a dictionary to count occurrences of each number\n counts = {}\n for number in numbers:\n counts[number] = counts.get(number, 0) + 1\n\n # Create a list of numbers that occur only once\n result = [number for number in numbers if counts[number] == 1]\n \n return result", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n \n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n >>> remove_duplicates([1, 1, 2, 2, 3, 3])\n []\n >>> remove_duplicates([1, 2, 3, 4, 5])\n [1, 2, 3, 4, 5]\n >>> remove_duplicates([5, 4, 3, 2, 1, 2, 3, 4, 5])\n [1]\n \"\"\"\n count = {}\n for number in numbers:\n count[number] = count.get(number, 0) + 1\n \n return [number for number in numbers if count[number] == 1]", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n \n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n # Count occurrences of each number\n count = {}\n for number in numbers:\n count[number] = count.get(number, 0) + 1\n \n # Return list of numbers that occur exactly once, maintaining order\n return [number for number in numbers if count[number] == 1]", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n \n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n >>> remove_duplicates([1, 1, 1, 1])\n []\n >>> remove_duplicates([1, 2, 3, 4, 5])\n [1, 2, 3, 4, 5]\n >>> remove_duplicates([1, 2, 3, 1, 2, 3])\n []\n >>> remove_duplicates([1, 2, 3, 4, 5, 1, 2])\n [3, 4, 5]\n \"\"\"\n from collections import Counter\n \n # Count occurrences of each number\n counts = Counter(numbers)\n \n # Create a new list with elements that occur exactly once\n result = [num for num in numbers if counts[num] == 1]\n \n return result", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n \n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n # Create a dictionary to count the occurrences of each number\n count = {}\n \n # Count occurrences of each number\n for number in numbers:\n if number in count:\n count[number] += 1\n else:\n count[number] = 1\n\n # Create a list of numbers that occur only once\n result = [number for number in numbers if count[number] == 1]\n\n return result", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n \n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n >>> remove_duplicates([1, 1, 1, 1])\n []\n >>> remove_duplicates([1, 2, 3, 4])\n [1, 2, 3, 4]\n >>> remove_duplicates([1, 2, 3, 2, 1, 4, 5, 5, 6])\n [3, 4, 6]\n \"\"\"\n count = {}\n \n # Count the occurrences of each number\n for number in numbers:\n count[number] = count.get(number, 0) + 1\n \n # Filter out the numbers that occur more than once\n result = [number for number in numbers if count[number] == 1]\n \n return result", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n \n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n # Count occurrences of each number\n counts = {}\n for number in numbers:\n counts[number] = counts.get(number, 0) + 1\n \n # Filter out numbers that occur more than once\n result = [number for number in numbers if counts[number] == 1]\n \n return result", "matching_cluster_idx": 3}]}, "HumanEval/31": {"dps": 50.63291139240506, "dps_norm": 75.0, "pass@1": 100.0, "profiled": [{"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n \n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True", "matching_cluster_idx": 5}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n \n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True", "matching_cluster_idx": 5}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True", "matching_cluster_idx": 5}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n \n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True", "matching_cluster_idx": 5}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True", "matching_cluster_idx": 5}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n \n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 5}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n \n A prime number is a number greater than 1 that has no positive divisors other than 1 and itself.\n \n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True", "matching_cluster_idx": 5}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n \n A prime number is a natural number greater than 1 that cannot be formed\n by multiplying two smaller natural numbers. The only even prime number is 2.\n\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n >>> is_prime(2)\n True\n >>> is_prime(3)\n True\n \"\"\"\n if n <= 1:\n return False\n if n == 2:\n return True\n if n % 2 == 0:\n return False\n for i in range(3, int(n**0.5) + 1, 2):\n if n % i == 0:\n return False\n return True", "matching_cluster_idx": 5}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 5}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True", "matching_cluster_idx": 5}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True", "matching_cluster_idx": 5}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n \n A prime number is a natural number greater than 1 that has no positive divisors other than 1 and itself.\n \n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n >>> is_prime(0)\n False\n >>> is_prime(-5)\n False\n \"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True", "matching_cluster_idx": 5}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n \n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True", "matching_cluster_idx": 5}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 5}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True", "matching_cluster_idx": 5}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n \n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True", "matching_cluster_idx": 5}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 5}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n \n A prime number is a natural number greater than 1 that cannot be formed\n by multiplying two smaller natural numbers. The only even prime number \n is 2. All other even numbers are not prime.\n\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n if n == 2:\n return True\n if n % 2 == 0:\n return False\n for i in range(3, int(n**0.5) + 1, 2):\n if n % i == 0:\n return False\n return True", "matching_cluster_idx": 5}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n \n A prime number is greater than 1 and has no divisors other than 1 and itself.\n \n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True", "matching_cluster_idx": 5}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True", "matching_cluster_idx": 5}]}, "HumanEval/33": {"dps": 97.22222222222223, "dps_norm": 81.81818181818181, "pass@1": 94.0, "profiled": [{"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indices that are not divisible by three, while its values at the indices that are divisible by three are equal\n to the values of the corresponding indices of l, but sorted.\n \n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n # Extract the values at indices divisible by 3\n divisible_by_three = [l[i] for i in range(len(l)) if i % 3 == 0]\n \n # Sort those values\n sorted_values = sorted(divisible_by_three)\n \n # Create a new list to hold the result\n result = l[:] # Make a copy of the original list\n \n # Replace the values at indices divisible by 3 with sorted values\n for i, value in enumerate(sorted_values):\n result[i * 3] = value\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indices that are not divisible by three, while its values at the indices that are divisible by three are equal\n to the values of the corresponding indices of l, but sorted.\n \n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n # Extract values at indices divisible by 3\n divisible_by_three = [l[i] for i in range(len(l)) if i % 3 == 0]\n \n # Sort the extracted values\n divisible_by_three.sort()\n \n # Create a new list to hold the result\n result = l[:]\n \n # Place the sorted values back into the appropriate indices\n for i, val in zip([i for i in range(len(l)) if i % 3 == 0], divisible_by_three):\n result[i] = val\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indices that are not divisible by three, while its values at the indices that are divisible by three are equal\n to the values of the corresponding indices of l, but sorted.\n \n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n # Extract values at indices divisible by three\n third_indices_values = [l[i] for i in range(len(l)) if i % 3 == 0]\n \n # Sort the extracted values\n third_indices_values.sort()\n \n # Create a new list to fill with sorted values at third indices\n sorted_list = l[:]\n \n # Replace values at indices divisible by three with sorted values\n for idx, value in zip((i for i in range(len(l)) if i % 3 == 0), third_indices_values):\n sorted_list[idx] = value\n \n return sorted_list", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indices that are not divisible by three, while its values at the indices that are divisible by three are equal\n to the values of the corresponding indices of l, but sorted.\n \n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n # Extract values at indices divisible by 3\n divisible_by_three = [l[i] for i in range(len(l)) if i % 3 == 0]\n \n # Sort the extracted values\n sorted_values = sorted(divisible_by_three)\n \n # Create the new list with sorted values at indices divisible by 3\n result = []\n sorted_index = 0\n for i in range(len(l)):\n if i % 3 == 0:\n result.append(sorted_values[sorted_index])\n sorted_index += 1\n else:\n result.append(l[i])\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indices that are not divisible by three, while its values at the indices that are divisible by three are equal\n to the values of the corresponding indices of l, but sorted.\n \n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n # Extract elements at indices divisible by 3\n divisible_by_three = [l[i] for i in range(len(l)) if i % 3 == 0]\n \n # Sort those elements\n divisible_by_three.sort()\n \n # Create a new list to hold the result\n result = l.copy()\n \n # Place sorted elements back in their original positions\n for index, value in zip((i for i in range(len(l)) if i % 3 == 0), divisible_by_three):\n result[index] = value\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indices that are not divisible by three, while its values at the indices that are divisible by three are equal\n to the values of the corresponding indices of l, but sorted.\n \n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n # Extract values at indices that are divisible by 3\n third_indices = [i for i in range(len(l)) if i % 3 == 0]\n third_values = [l[i] for i in third_indices]\n\n # Sort the values that were extracted\n sorted_third_values = sorted(third_values)\n\n # Create a new list that will hold the result\n result = l[:]\n\n # Replace the values at the indices that are divisible by 3 with the sorted values\n for idx, sorted_value in zip(third_indices, sorted_third_values):\n result[idx] = sorted_value\n\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indices that are not divisible by three, while its values at the indices that are divisible by three are equal\n to the values of the corresponding indices of l, but sorted.\n \n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n # Extract values from indices that are divisible by 3\n sortable_values = [l[i] for i in range(len(l)) if i % 3 == 0]\n \n # Sort these values\n sorted_values = sorted(sortable_values)\n \n # Create a new list to hold the result\n result = l[:] # Start with a copy of the original list\n \n # Replace the values at the indices that are divisible by 3 with the sorted values\n sorted_index = 0\n for i in range(len(result)):\n if i % 3 == 0:\n result[i] = sorted_values[sorted_index]\n sorted_index += 1\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indices that are not divisible by three, while its values at the indices that are divisible by three are equal\n to the values of the corresponding indices of l, but sorted.\n \n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n \n # Extract values at indices that are divisible by 3\n sorted_values = sorted(l[i] for i in range(len(l)) if i % 3 == 0)\n \n # Create a new list with the same values as l\n result = l.copy()\n \n # Replace the values at indices divisible by 3 with the sorted values\n for idx, value in zip((i for i in range(len(l)) if i % 3 == 0), sorted_values):\n result[idx] = value\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indices that are not divisible by three, while its values at the indices that are divisible by three are equal\n to the values of the corresponding indices of l, but sorted.\n \n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n # Extract values at indices divisible by three\n third_indices = [i for i in range(len(l)) if i % 3 == 0]\n third_values = [l[i] for i in third_indices]\n\n # Sort those values\n sorted_third_values = sorted(third_values)\n\n # Create a new list to hold the results\n result = l[:]\n \n # Place the sorted values back in their original indices\n for index, sorted_value in zip(third_indices, sorted_third_values):\n result[index] = sorted_value\n\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indices that are not divisible by three, while its values at the indices that are divisible by three are equal\n to the values of the corresponding indices of l, but sorted.\n \n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n # Extract the elements at indices divisible by three\n divisible_by_three = [l[i] for i in range(len(l)) if i % 3 == 0]\n \n # Sort the extracted elements\n sorted_divisible = sorted(divisible_by_three)\n \n # Create a new list to hold the result\n result = l.copy()\n \n # Replace the elements at indices divisible by three with the sorted ones\n for idx, sorted_value in zip([i for i in range(len(l)) if i % 3 == 0], sorted_divisible):\n result[idx] = sorted_value\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indices that are not divisible by three, while its values at the indices that are divisible by three are equal\n to the values of the corresponding indices of l, but sorted.\n \n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n # Extract values at indices divisible by 3\n divisible_by_three = [l[i] for i in range(len(l)) if i % 3 == 0]\n \n # Sort the extracted values\n sorted_values = sorted(divisible_by_three)\n \n # Create a new list to hold the result\n result = l[:] # Copy the original list\n \n # Place sorted values back in their respective positions\n for index, value in zip([i for i in range(len(l)) if i % 3 == 0], sorted_values):\n result[index] = value\n\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indices that are not divisible by three, while its values at the indices that are divisible by three are equal\n to the values of the corresponding indices of l, but sorted.\n \n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n # Extract values at indices divisible by 3\n third_indices_values = [l[i] for i in range(len(l)) if i % 3 == 0]\n \n # Sort the extracted values\n sorted_values = sorted(third_indices_values)\n \n # Create a new list to hold the result\n result = l.copy()\n \n # Place the sorted values back into their respective positions\n for idx, value in zip((i for i in range(len(l)) if i % 3 == 0), sorted_values):\n result[idx] = value\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list) -> list:\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indices that are not divisible by three, while its values at the indices that are divisible by three are equal\n to the values of the corresponding indices of l, but sorted.\n \n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n # Extract values at indices divisible by 3\n divisible_by_three = [l[i] for i in range(len(l)) if i % 3 == 0]\n \n # Sort the extracted values\n sorted_values = sorted(divisible_by_three)\n \n # Create a new list to hold the result\n result = l[:] # Start with a copy of the original list\n \n # Replace the values at indices divisible by 3 with sorted values\n sorted_index = 0\n for i in range(len(result)):\n if i % 3 == 0:\n result[i] = sorted_values[sorted_index]\n sorted_index += 1\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indices that are not divisible by three, while its values at the indices that are divisible by three are equal\n to the values of the corresponding indices of l, but sorted.\n \n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n # Extract values at indices that are divisible by 3\n values_to_sort = [l[i] for i in range(len(l)) if i % 3 == 0]\n \n # Sort those values\n values_to_sort.sort()\n \n # Create a new list to hold the result\n result = l.copy()\n \n # Replace values at indices divisible by 3 with the sorted values\n sort_index = 0\n for i in range(len(result)):\n if i % 3 == 0:\n result[i] = values_to_sort[sort_index]\n sort_index += 1\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indices that are not divisible by three, while its values at the indices that are divisible by three are equal\n to the values of the corresponding indices of l, but sorted.\n \n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n # Extract elements at indices divisible by three\n divisible_by_three = [l[i] for i in range(len(l)) if i % 3 == 0]\n # Sort those elements\n sorted_divisible = sorted(divisible_by_three)\n \n # Create a new list to hold the result\n result = l[:] # Start with a copy of the original list\n \n # Replace elements at indices divisible by three with sorted elements\n j = 0 # Index for the sorted elements\n for i in range(len(result)):\n if i % 3 == 0:\n result[i] = sorted_divisible[j]\n j += 1\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indices that are not divisible by three, while its values at the indices that are divisible by three are equal\n to the values of the corresponding indices of l, but sorted.\n \n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n # Extract values from indices that are divisible by three\n third_indices = [i for i in range(len(l)) if i % 3 == 0]\n third_values = [l[i] for i in third_indices]\n \n # Sort the values from the third indices\n third_values.sort()\n \n # Create a new list to store the result\n result = l[:]\n \n # Place sorted values back into the result list at the appropriate indices\n for idx, sorted_value in zip(third_indices, third_values):\n result[idx] = sorted_value\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indices that are not divisible by three, while its values at the indices that are divisible by three are equal\n to the values of the corresponding indices of l, but sorted.\n \n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n # Extract values at indices divisible by 3\n third_indices_values = [l[i] for i in range(len(l)) if i % 3 == 0]\n \n # Sort those values\n sorted_third_values = sorted(third_indices_values)\n \n # Create a new list with the same values as l\n result = l[:]\n \n # Replace the values at indices divisible by 3 with the sorted values\n sorted_index = 0\n for i in range(len(result)):\n if i % 3 == 0:\n result[i] = sorted_third_values[sorted_index]\n sorted_index += 1\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indices that are not divisible by three, while its values at the indices that are divisible by three are equal\n to the values of the corresponding indices of l, but sorted.\n \n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n # Extract the elements at indices divisible by 3\n values_to_sort = [l[i] for i in range(len(l)) if i % 3 == 0]\n \n # Sort those values\n values_to_sort.sort()\n \n # Create a new list for the result\n result = l[:] # Make a copy of l to preserve non-modifiable indices\n \n # Replace the values at indices divisible by 3 with sorted values\n for idx, sorted_value in zip((i for i in range(len(l)) if i % 3 == 0), values_to_sort):\n result[idx] = sorted_value\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indices that are not divisible by three, while its values at the indices that are divisible by three are equal\n to the values of the corresponding indices of l, but sorted.\n \n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n # Extract elements at indices divisible by 3\n divisible_by_three = [l[i] for i in range(len(l)) if i % 3 == 0]\n # Sort the extracted elements\n sorted_values = sorted(divisible_by_three)\n\n # Create a new list where we will place sorted values in the correct indices\n result = l[:]\n sort_index = 0\n \n for i in range(len(l)):\n if i % 3 == 0: # if index is divisible by 3\n result[i] = sorted_values[sort_index]\n sort_index += 1\n\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indices that are not divisible by three, while its values at the indices that are divisible by three are equal\n to the values of the corresponding indices of l, but sorted.\n \n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n # Extract values at indices divisible by 3\n sorted_values = sorted(l[i] for i in range(len(l)) if i % 3 == 0)\n \n # Create a new list to hold the result\n result = []\n sorted_index = 0\n\n # Populate the result list according to the specified rules\n for i in range(len(l)):\n if i % 3 == 0:\n result.append(sorted_values[sorted_index])\n sorted_index += 1\n else:\n result.append(l[i])\n \n return result", "matching_cluster_idx": 8}]}, "HumanEval/34": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n \n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n \n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list.\n \n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list.\n \n Args:\n l (list): A list of elements.\n \n Returns:\n list: A sorted list of unique elements.\n \n Examples:\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n \n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list.\n \n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list.\n \n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list.\n \n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list.\n \n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list.\n\n Args:\n l (list): A list of elements.\n\n Returns:\n list: A sorted list of unique elements.\n\n Examples:\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n # Use set to get unique elements and then sort them\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list.\n\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}]}, "HumanEval/36": {"dps": 96.77419354838709, "dps_norm": 71.42857142857143, "pass@1": 100.0, "profiled": [{"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n \n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count_of_7 = 0\n \n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count_of_7 += str(i).count('7')\n \n return count_of_7", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n \n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count_of_sevens = 0\n\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count_of_sevens += str(i).count('7')\n\n return count_of_sevens", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n \n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n \n which are divisible by 11 or 13.\n\n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count_of_sevens = 0\n \n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count_of_sevens += str(i).count('7')\n \n return count_of_sevens", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n \n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count_7s = 0\n \n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count_7s += str(i).count('7')\n \n return count_7s", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n \n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n \n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n \n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int):\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n \n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count_sevens = 0\n \n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count_sevens += str(i).count('7')\n \n return count_sevens", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n \n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count_of_sevens = 0\n \n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count_of_sevens += str(i).count('7')\n \n return count_of_sevens", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n \n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count_sevens = 0\n \n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count_sevens += str(i).count('7')\n \n return count_sevens", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n \n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n\n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count_of_sevens = 0\n \n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count_of_sevens += str(i).count('7')\n \n return count_of_sevens", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n \n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n \n which are divisible by 11 or 13.\n \n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n \n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n \n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n \n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count_of_sevens = 0\n \n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count_of_sevens += str(i).count('7')\n \n return count_of_sevens", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int):\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n \n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count_of_sevens = 0\n \n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count_of_sevens += str(i).count('7')\n \n return count_of_sevens", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n \n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count_of_sevens = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count_of_sevens += str(i).count('7')\n return count_of_sevens", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n \n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count_of_sevens = 0\n \n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count_of_sevens += str(i).count('7')\n \n return count_of_sevens", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n\n which are divisible by 11 or 13.\n\n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count_sevens = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count_sevens += str(i).count('7')\n return count_sevens", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n \n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count_of_sevens = 0\n\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count_of_sevens += str(i).count('7')\n\n return count_of_sevens", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n \n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}]}, "HumanEval/37": {"dps": 94.92635024549918, "dps_norm": 90.0, "pass@1": 100.0, "profiled": [{"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indices, while its values at the even indices \n are equal to the values of the even indices of l, but sorted.\n \n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Extract even indexed elements and sort them\n even_indices = [l[i] for i in range(0, len(l), 2)]\n sorted_even_indices = sorted(even_indices)\n \n # Create a new list to hold the result\n result = []\n \n # Fill the result list\n even_index = 0\n for i in range(len(l)):\n if i % 2 == 0: # Even index\n result.append(sorted_even_indices[even_index])\n even_index += 1\n else: # Odd index\n result.append(l[i])\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indices, while its values at the even indices are equal\n to the values of the even indices of l, but sorted.\n \n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Extract values at even indices\n even_indices_values = [l[i] for i in range(0, len(l), 2)]\n \n # Sort the extracted values\n even_indices_values.sort()\n \n # Create a new list with sorted even indices and original odd indices\n result = []\n even_index = 0\n for i in range(len(l)):\n if i % 2 == 0: # Even index\n result.append(even_indices_values[even_index])\n even_index += 1\n else: # Odd index\n result.append(l[i])\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indices, while its values at the even indices are equal\n to the values of the even indices of l, but sorted.\n \n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n >>> sort_even([10, 1, 9, 2, 8, 3])\n [8, 1, 10, 2, 9, 3]\n >>> sort_even([7, 5, 6, 1, 4, 9])\n [4, 5, 6, 1, 7, 9]\n \"\"\"\n # Extract even indexed values and sort them\n even_indices_values = [l[i] for i in range(0, len(l), 2)]\n even_indices_values.sort()\n\n # Create a new list to hold the sorted values at even indices and the original at odd indices\n result = []\n even_index = 0 # Index for sorted even values\n\n for i in range(len(l)):\n if i % 2 == 0: # Even index\n result.append(even_indices_values[even_index])\n even_index += 1\n else: # Odd index\n result.append(l[i])\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indices, while its values at the even indices are equal\n to the values of the even indices of l, but sorted.\n \n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Extract even indices and sort them\n even_indices_values = [l[i] for i in range(0, len(l), 2)]\n even_indices_values.sort()\n \n # Create a new list for the result\n result = l[:]\n \n # Place sorted values back into the even indices of the result list\n for i, val in enumerate(even_indices_values):\n result[i * 2] = val\n\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indices, while its values at the even indices are equal\n to the values of the even indices of l, but sorted.\n \n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n \n # Extract the values from even indices\n even_indices = [l[i] for i in range(0, len(l), 2)]\n \n # Sort the values of the even indices\n even_sorted = sorted(even_indices)\n \n # Create a new list to hold the result\n result = l.copy()\n \n # Replace the values at the even indices with the sorted values\n for i, val in enumerate(even_sorted):\n result[i * 2] = val\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indices, while its values at the even indices are equal\n to the values of the even indices of l, but sorted.\n \n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Extract even indices elements\n even_elements = [l[i] for i in range(0, len(l), 2)]\n # Sort the even elements\n even_elements.sort()\n \n # Create a new list to hold the result\n result = []\n \n # Fill the result list with sorted even elements and original odd elements\n even_index = 0\n for i in range(len(l)):\n if i % 2 == 0: # Even index\n result.append(even_elements[even_index])\n even_index += 1\n else: # Odd index\n result.append(l[i])\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indices, while its values at the even indices are equal\n to the values of the even indices of l, but sorted.\n \n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Extract even indexed elements and sort them\n even_elements = sorted(l[i] for i in range(0, len(l), 2))\n \n # Create a new list to build the result\n result = l[:] # Start with a copy of the original list\n \n # Replace even indexed positions in the result with sorted elements\n for i, value in enumerate(even_elements):\n result[2 * i] = value # Place the sorted element in the even index\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indices, while its values at the even indices are equal\n to the values of the even indices of l, but sorted.\n \n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Extract even indexed elements and sort them\n even_indices_values = [l[i] for i in range(0, len(l), 2)]\n sorted_even_values = sorted(even_indices_values)\n \n # Create a new list to store the result\n result = l.copy()\n \n # Place the sorted even indexed values back in their original positions\n for i, value in zip(range(0, len(result), 2), sorted_even_values):\n result[i] = value\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indices, while its values at the even indices are equal\n to the values of the even indices of l, but sorted.\n \n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Extract even indexed elements\n even_indexed_elements = [l[i] for i in range(0, len(l), 2)]\n \n # Sort the even indexed elements\n sorted_even_indexed_elements = sorted(even_indexed_elements)\n \n # Create the result list\n result = l[:] # Copy the original list\n \n # Place the sorted elements back into the even indices\n for i, sorted_value in enumerate(sorted_even_indexed_elements):\n result[2 * i] = sorted_value\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indices, while its values at the even indices are equal\n to the values of the even indices of l, but sorted.\n \n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n \n # Extract the values at even indices\n even_indices_values = [l[i] for i in range(0, len(l), 2)]\n \n # Sort the extracted values\n even_indices_values.sort()\n \n # Create a new list to hold the result\n result = []\n \n # Fill the result list with sorted even indices values and original odd indices values\n even_index = 0\n for i in range(len(l)):\n if i % 2 == 0:\n result.append(even_indices_values[even_index])\n even_index += 1\n else:\n result.append(l[i])\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indices, while its values at the even indices \n are equal to the values of the even indices of l, but sorted.\n \n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Extract even indexed elements\n even_indices = [l[i] for i in range(0, len(l), 2)]\n \n # Sort the even indexed elements\n sorted_evens = sorted(even_indices)\n \n # Create a new list to hold the result\n result = l.copy()\n \n # Place the sorted even indexed elements back in the result list\n for index, sorted_value in zip(range(0, len(l), 2), sorted_evens):\n result[index] = sorted_value\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indices, while its values at the even indices are equal\n to the values of the even indices of l, but sorted.\n\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n >>> sort_even([10, 20, 30, 40, 50])\n [10, 20, 30, 40, 50]\n >>> sort_even([7, 8, 5, 6, 3, 4])\n [5, 8, 7, 6, 3, 4]\n >>> sort_even([])\n []\n \"\"\"\n # Extract even indexed elements\n even_indices_values = [l[i] for i in range(0, len(l), 2)]\n \n # Sort even indexed elements\n even_indices_values.sort()\n \n # Create a new list to hold the result\n result = []\n \n # Fill the result list\n even_index = 0\n for i in range(len(l)):\n if i % 2 == 0: # Even index\n result.append(even_indices_values[even_index])\n even_index += 1\n else: # Odd index\n result.append(l[i])\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indices, while its values at the even indices are equal\n to the values of the even indices of l, but sorted.\n \n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Extract even indexed elements\n even_indices = [l[i] for i in range(0, len(l), 2)]\n # Sort the even indexed elements\n even_indices_sorted = sorted(even_indices)\n \n # Create a new list to hold the result\n result = []\n even_index = 0 # Index for sorted even elements\n \n # Reconstruct the result list\n for i in range(len(l)):\n if i % 2 == 0: # Even index\n result.append(even_indices_sorted[even_index])\n even_index += 1\n else: # Odd index\n result.append(l[i])\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indices, while its values at the even indices are equal\n to the values of the even indices of l, but sorted.\n \n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Extracting even indexed elements\n even_indices_values = [l[i] for i in range(0, len(l), 2)]\n \n # Sorting the extracted even indexed elements\n even_indices_values.sort()\n \n # Creating the new list with sorted even indices and original odd indices\n result = []\n even_index = 0\n \n for i in range(len(l)):\n if i % 2 == 0: # Even index\n result.append(even_indices_values[even_index])\n even_index += 1\n else: # Odd index\n result.append(l[i])\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list) -> list:\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indices, while its values at the even indices are equal\n to the values of the even indices of l, but sorted.\n \n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Extracting even indexed elements\n even_indices_values = [l[i] for i in range(0, len(l), 2)]\n # Sorting the extracted even indexed values\n even_indices_values.sort()\n \n # Creating a new list for the result\n result = l[:] # Copy original list to result\n # Inserting the sorted even indexed values back to their positions\n for i, value in enumerate(even_indices_values):\n result[i * 2] = value # Even indices are 0, 2, 4, ...\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indices, while its values at the even indices are equal\n to the values of the even indices of l, but sorted.\n \n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Extract even indexed elements\n even_indexed_elements = [l[i] for i in range(0, len(l), 2)]\n # Sort the even indexed elements\n even_indexed_elements.sort()\n \n # Create the new list\n result = []\n even_index = 0\n \n for i in range(len(l)):\n if i % 2 == 0:\n result.append(even_indexed_elements[even_index])\n even_index += 1\n else:\n result.append(l[i])\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indices, while its values at the even indices are equal\n to the values of the even indices of l, but sorted.\n \n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Extract even indexed elements and sort them\n even_indexed_elements = [l[i] for i in range(0, len(l), 2)]\n even_indexed_elements.sort()\n\n # Create a new list to hold the result\n result = l[:] # start with a copy of the original list\n \n # Replace the even indexed positions with the sorted values\n for index, value in zip(range(0, len(result), 2), even_indexed_elements):\n result[index] = value\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indices, while its values at the even indices are equal\n to the values of the even indices of l, but sorted.\n \n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Extract even indexed elements and sort them\n even_indices_values = [l[i] for i in range(0, len(l), 2)]\n even_indices_values.sort()\n\n # Create a new list to hold the result\n result = l.copy()\n\n # Place the sorted values back into the even indices of the result\n for i, value in enumerate(even_indices_values):\n result[i * 2] = value\n\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indices, while its values at the even indices are equal\n to the values of the even indices of l, but sorted.\n\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Extract even indexed elements and sort them\n even_elements = sorted(l[i] for i in range(0, len(l), 2))\n \n # Create a new list to hold the result\n result = []\n \n # Populate the result list\n even_index = 0\n for i in range(len(l)):\n if i % 2 == 0: # even index\n result.append(even_elements[even_index])\n even_index += 1\n else: # odd index\n result.append(l[i])\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indices, while its values at the even indices are equal\n to the values of the even indices of l, but sorted.\n \n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Extract the even-indexed elements\n even_indexed_elements = [l[i] for i in range(0, len(l), 2)]\n \n # Sort the even-indexed elements\n even_indexed_elements.sort()\n \n # Create a new list with sorted even-indexed elements and original odd-indexed elements\n sorted_list = []\n even_index = 0\n for i in range(len(l)):\n if i % 2 == 0: # Even index\n sorted_list.append(even_indexed_elements[even_index])\n even_index += 1\n else: # Odd index\n sorted_list.append(l[i])\n \n return sorted_list", "matching_cluster_idx": 8}]}, "HumanEval/49": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 82.0, "profiled": [{"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\n \n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\n \n Args:\n n (int): The exponent to which 2 is raised.\n p (int): The modulus.\n\n Returns:\n int: The result of 2^n modulo p.\n\n Examples:\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\n \n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\n \n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\n \n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\n \n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n if p <= 0:\n raise ValueError(\"Modulus p must be greater than 0.\")\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\n \n This implementation uses modular exponentiation to efficiently calculate\n the result without overflowing large integers.\n \n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\n \n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\n \n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\n \n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\n \n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\n \n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\n \n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\n \n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\n \n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\n \n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\n\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\n \n Args:\n n (int): The exponent to raise 2 to.\n p (int): The modulus.\n \n Returns:\n int: The result of (2^n) % p.\n \n Examples:\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}]}, "HumanEval/51": {"dps": 96.13526570048309, "dps_norm": 75.0, "pass@1": 100.0, "profiled": [{"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes a string and returns a string without vowels.\n \n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n return ''.join(char for char in text if char not in vowels)", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes a string and returns a string without vowels.\n \n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n return ''.join(char for char in text if char not in vowels)", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n return ''.join(char for char in text if char not in vowels)", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes a string and returns the string without vowels.\n \n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\\\nghijklm\")\n 'bcdf\\\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n return ''.join(char for char in text if char not in vowels)", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n \n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = 'aeiouAEIOU'\n return ''.join(char for char in text if char not in vowels)", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes a string and returns the string without vowels.\n \n Vowels are defined as 'a', 'e', 'i', 'o', 'u' (case insensitive).\n \n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n return ''.join(char for char in text if char not in vowels)", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes a string and returns a string without vowels.\n \n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n return ''.join(char for char in text if char not in vowels)", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes a string and returns the string without vowels.\n \n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n return ''.join(char for char in text if char not in vowels)", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes a string and returns a string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = 'aeiouAEIOU'\n return ''.join(char for char in text if char not in vowels)", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = 'aeiouAEIOU'\n return ''.join(char for char in text if char not in vowels)", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n \n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n return ''.join(char for char in text if char not in vowels)", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes a string and returns a string without vowels.\n \n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = 'aeiouAEIOU'\n return ''.join(char for char in text if char not in vowels)", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes a string and returns a string without vowels.\n \n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\" # Define the vowels to remove (both lowercase and uppercase)\n return ''.join(char for char in text if char not in vowels)", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes a string and returns a string without vowels.\n \n Vowels are defined as 'a', 'e', 'i', 'o', 'u' (case insensitive).\n \n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n return ''.join(char for char in text if char not in vowels)", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n \n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = 'aeiouAEIOU' # Define vowels, including uppercase\n return ''.join(char for char in text if char not in vowels)", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n \n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = 'aeiouAEIOU'\n return ''.join(char for char in text if char not in vowels)", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n \n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = 'aeiouAEIOU'\n return ''.join(char for char in text if char not in vowels)", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes a string and returns a string without vowels.\n Vowels are defined as 'a', 'e', 'i', 'o', 'u' (case-insensitive).\n\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = 'aeiouAEIOU'\n return ''.join(char for char in text if char not in vowels)", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n return ''.join(char for char in text if char not in vowels)", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes a string and returns a string without vowels.\n \n Vowels are defined as 'a', 'e', 'i', 'o', 'u' (case insensitive).\n \n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\" # Define vowels\n return ''.join(char for char in text if char not in vowels) # Use a generator expression to filter out vowels", "matching_cluster_idx": 5}]}, "HumanEval/54": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 94.0, "profiled": [{"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \n This function verifies that both input strings contain the same unique characters,\n regardless of the frequency of each character in the strings.\n\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')\n True\n >>> same_chars('abcd', 'dddddddabc')\n True\n >>> same_chars('dddddddabc', 'abcd')\n True\n >>> same_chars('eabcd', 'dddddddabc')\n False\n >>> same_chars('abcd', 'dddddddabce')\n False\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')\n False\n \"\"\"\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')\n True\n >>> same_chars('abcd', 'dddddddabc')\n True\n >>> same_chars('dddddddabc', 'abcd')\n True\n >>> same_chars('eabcd', 'dddddddabc')\n False\n >>> same_chars('abcd', 'dddddddabce')\n False\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')\n False\n \"\"\"\n # Create a set of characters for each string\n chars_s0 = set(s0)\n chars_s1 = set(s1)\n \n # Check if both sets are equal\n return chars_s0 == chars_s1", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \n Two words have the same characters if they consist of the same unique characters\n irrespective of their counts or order.\n\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')\n True\n >>> same_chars('abcd', 'dddddddabc')\n True\n >>> same_chars('dddddddabc', 'abcd')\n True\n >>> same_chars('eabcd', 'dddddddabc')\n False\n >>> same_chars('abcd', 'dddddddabce')\n False\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')\n False\n \"\"\"\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n\n This function checks if two input strings have the same set of unique characters, \n ignoring the frequency of those characters.\n\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')\n True\n >>> same_chars('abcd', 'dddddddabc')\n True\n >>> same_chars('dddddddabc', 'abcd')\n True\n >>> same_chars('eabcd', 'dddddddabc')\n False\n >>> same_chars('abcd', 'dddddddabce')\n False\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')\n False\n \"\"\"\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \n This function checks if two strings contain the exact same set of characters,\n regardless of their frequency in the strings.\n \n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')\n True\n >>> same_chars('abcd', 'dddddddabc')\n True\n >>> same_chars('dddddddabc', 'abcd')\n True\n >>> same_chars('eabcd', 'dddddddabc')\n False\n >>> same_chars('abcd', 'dddddddabce')\n False\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')\n False\n \"\"\"\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \n This function compares the unique characters of the two input strings.\n \n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')\n True\n >>> same_chars('abcd', 'dddddddabc')\n True\n >>> same_chars('dddddddabc', 'abcd')\n True\n >>> same_chars('eabcd', 'dddddddabc')\n False\n >>> same_chars('abcd', 'dddddddabce')\n False\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')\n False\n \"\"\"\n # Convert both strings to sets to find unique characters\n unique_chars_s0 = set(s0)\n unique_chars_s1 = set(s1)\n \n # Check if the sets of unique characters are the same\n return unique_chars_s0 == unique_chars_s1", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n\n This function returns True if both strings contain the same unique characters,\n regardless of the frequency of those characters. It is case-sensitive.\n\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')\n True\n >>> same_chars('abcd', 'dddddddabc')\n True\n >>> same_chars('dddddddabc', 'abcd')\n True\n >>> same_chars('eabcd', 'dddddddabc')\n False\n >>> same_chars('abcd', 'dddddddabce')\n False\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')\n False\n \"\"\"\n # Use set to find unique characters in both strings\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n\n Args:\n s0 (str): First string.\n s1 (str): Second string.\n\n Returns:\n bool: True if both strings have the same unique characters, False otherwise.\n\n Examples:\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')\n True\n >>> same_chars('abcd', 'dddddddabc')\n True\n >>> same_chars('dddddddabc', 'abcd')\n True\n >>> same_chars('eabcd', 'dddddddabc')\n False\n >>> same_chars('abcd', 'dddddddabce')\n False\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')\n False\n \"\"\"\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \n This function returns True if the two input strings contain the same \n unique characters, regardless of their frequency in the strings.\n \n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')\n True\n >>> same_chars('abcd', 'dddddddabc')\n True\n >>> same_chars('dddddddabc', 'abcd')\n True\n >>> same_chars('eabcd', 'dddddddabc')\n False\n >>> same_chars('abcd', 'dddddddabce')\n False\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')\n False\n \"\"\"\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \n The function checks if both strings contain the same unique characters,\n irrespective of the number of times each character appears.\n\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')\n True\n >>> same_chars('abcd', 'dddddddabc')\n True\n >>> same_chars('dddddddabc', 'abcd')\n True\n >>> same_chars('eabcd', 'dddddddabc')\n False\n >>> same_chars('abcd', 'dddddddabce')\n False\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')\n False\n \"\"\"\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n\n Two words have the same characters if they contain the same set of unique characters\n regardless of the count of each character.\n\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')\n True\n >>> same_chars('abcd', 'dddddddabc')\n True\n >>> same_chars('dddddddabc', 'abcd')\n True\n >>> same_chars('eabcd', 'dddddddabc')\n False\n >>> same_chars('abcd', 'dddddddabce')\n False\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')\n False\n \"\"\"\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \n Two words are considered to have the same characters if they can be formed \n with the same set of unique characters, regardless of their frequency.\n\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')\n True\n >>> same_chars('abcd', 'dddddddabc')\n True\n >>> same_chars('dddddddabc', 'abcd')\n True\n >>> same_chars('eabcd', 'dddddddabc')\n False\n >>> same_chars('abcd', 'dddddddabce')\n False\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')\n False\n \"\"\"\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \n This function checks if the two input strings `s0` and `s1` contain exactly the same characters,\n regardless of the number of times each character appears.\n\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')\n True\n >>> same_chars('abcd', 'dddddddabc')\n True\n >>> same_chars('dddddddabc', 'abcd')\n True\n >>> same_chars('eabcd', 'dddddddabc')\n False\n >>> same_chars('abcd', 'dddddddabce')\n False\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')\n False\n \"\"\"\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \n This function ignores the frequency of characters and only checks for the presence\n of the same unique characters in both strings.\n \n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')\n True\n >>> same_chars('abcd', 'dddddddabc')\n True\n >>> same_chars('dddddddabc', 'abcd')\n True\n >>> same_chars('eabcd', 'dddddddabc')\n False\n >>> same_chars('abcd', 'dddddddabce')\n False\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')\n False\n \"\"\"\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n\n Two words have the same characters if they contain exactly the same characters,\n regardless of their frequencies or order.\n\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')\n True\n >>> same_chars('abcd', 'dddddddabc')\n True\n >>> same_chars('dddddddabc', 'abcd')\n True\n >>> same_chars('eabcd', 'dddddddabc')\n False\n >>> same_chars('abcd', 'dddddddabce')\n False\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')\n False\n \"\"\"\n # Create sets of characters from both strings\n chars_s0 = set(s0)\n chars_s1 = set(s1)\n\n # Compare the sets to determine if they are the same\n return chars_s0 == chars_s1", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')\n True\n >>> same_chars('abcd', 'dddddddabc')\n True\n >>> same_chars('dddddddabc', 'abcd')\n True\n >>> same_chars('eabcd', 'dddddddabc')\n False\n >>> same_chars('abcd', 'dddddddabce')\n False\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')\n False\n \"\"\"\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n\n Two strings have the same characters if they contain the same unique\n characters regardless of frequency.\n\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')\n True\n >>> same_chars('abcd', 'dddddddabc')\n True\n >>> same_chars('dddddddabc', 'abcd')\n True\n >>> same_chars('eabcd', 'dddddddabc')\n False\n >>> same_chars('abcd', 'dddddddabce')\n False\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')\n False\n \"\"\"\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \n Two strings are considered to have the same characters if they contain\n the same unique characters, regardless of the number of times they appear.\n \n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')\n True\n >>> same_chars('abcd', 'dddddddabc')\n True\n >>> same_chars('dddddddabc', 'abcd')\n True\n >>> same_chars('eabcd', 'dddddddabc')\n False\n >>> same_chars('abcd', 'dddddddabce')\n False\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')\n False\n \"\"\"\n # Create a set of characters for both strings\n chars_s0 = set(s0)\n chars_s1 = set(s1)\n \n # Compare the sets of characters\n return chars_s0 == chars_s1", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \n This function checks whether two input strings have exactly the same\n characters, regardless of their order or frequency. It returns True\n if they contain the same unique characters; otherwise, it returns False.\n \n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')\n True\n >>> same_chars('abcd', 'dddddddabc')\n True\n >>> same_chars('dddddddabc', 'abcd')\n True\n >>> same_chars('eabcd', 'dddddddabc')\n False\n >>> same_chars('abcd', 'dddddddabce')\n False\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')\n False\n \"\"\"\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \n Two words have the same characters if they contain exactly the same unique characters,\n irrespective of their counts.\n \n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')\n True\n >>> same_chars('abcd', 'dddddddabc')\n True\n >>> same_chars('dddddddabc', 'abcd')\n True\n >>> same_chars('eabcd', 'dddddddabc')\n False\n >>> same_chars('abcd', 'dddddddabce')\n False\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')\n False\n \"\"\"\n # Use sets to compare unique characters in both strings\n return set(s0) == set(s1)", "matching_cluster_idx": 6}]}, "HumanEval/58": {"dps": 92.51968503937007, "dps_norm": 83.33333333333333, "pass@1": 100.0, "profiled": [{"solution": "def common(l1: list, l2: list) -> list:\n \"\"\"Return sorted unique common elements for two lists.\n\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n # Convert both lists to sets to find unique elements\n set1 = set(l1)\n set2 = set(l2)\n \n # Find the intersection of both sets\n common_elements = set1.intersection(set2)\n \n # Return the sorted list of common elements\n return sorted(common_elements)", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n \n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n\n \"\"\"\n # Convert lists to sets to find unique elements\n set1 = set(l1)\n set2 = set(l2)\n \n # Find the intersection and convert it to a sorted list\n common_elements = sorted(set1.intersection(set2))\n \n return common_elements", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n\n \"\"\"\n # Convert both lists to sets to find common elements\n set1 = set(l1)\n set2 = set(l2)\n\n # Find the intersection of both sets\n common_elements = set1.intersection(set2)\n\n # Return the sorted list of unique common elements\n return sorted(common_elements)", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n \n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \n \"\"\"\n # Convert lists to sets to get unique elements and perform intersection\n common_elements = set(l1) & set(l2)\n \n # Return a sorted list of the unique common elements\n return sorted(common_elements)", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n \n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \n \"\"\"\n # Use set to find unique elements, then find the intersection\n common_elements = set(l1) & set(l2)\n # Sort the results and return as a list\n return sorted(common_elements)", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \n \"\"\"\n # Convert both lists to sets to get unique elements and find intersection\n unique_l1 = set(l1)\n unique_l2 = set(l2)\n common_elements = unique_l1.intersection(unique_l2)\n \n # Sort the common elements and return as a list\n return sorted(common_elements)", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n \n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n \n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \n \"\"\"\n # Convert both lists to sets to get unique elements\n set1 = set(l1)\n set2 = set(l2)\n\n # Find the intersection of both sets\n common_elements = set1.intersection(set2)\n\n # Return the sorted list of common elements\n return sorted(common_elements)", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n \n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \n \"\"\"\n # Convert both lists to sets to get unique elements\n set1 = set(l1)\n set2 = set(l2)\n \n # Find the intersection of both sets\n common_elements = set1.intersection(set2)\n \n # Return the sorted list of common elements\n return sorted(common_elements)", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list) -> list:\n \"\"\"Return sorted unique common elements for two lists.\n \n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \n \"\"\"\n # Convert both lists to sets to find unique elements\n set1 = set(l1)\n set2 = set(l2)\n \n # Find the intersection of both sets\n common_elements = set1.intersection(set2)\n \n # Return a sorted list of the common unique elements\n return sorted(common_elements)", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n \n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \n \"\"\"\n # Convert both lists to sets to get unique elements, then find the intersection\n common_elements = set(l1).intersection(set(l2))\n # Return the sorted list of common unique elements\n return sorted(common_elements)", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n \n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \n \"\"\"\n # Convert both lists to sets to get unique elements\n set1 = set(l1)\n set2 = set(l2)\n \n # Find the intersection of both sets\n common_elements = set1.intersection(set2)\n \n # Return the sorted list of common elements\n return sorted(common_elements)", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n \n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \n \"\"\"\n # Convert both lists to sets to remove duplicates and find common elements\n common_elements = set(l1) & set(l2)\n # Convert the set back to a sorted list\n return sorted(common_elements)", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n \n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \n \"\"\"\n # Convert lists to sets to find common elements and remove duplicates\n common_elements = set(l1) & set(l2)\n # Return a sorted list of the common elements\n return sorted(common_elements)", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n \n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \n \"\"\"\n # Convert lists to sets to get unique elements\n set1 = set(l1)\n set2 = set(l2)\n \n # Find common elements and convert back to a sorted list\n common_elements = sorted(set1.intersection(set2))\n \n return common_elements", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n \n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \n \"\"\"\n # Convert both lists to sets to find unique elements\n set1 = set(l1)\n set2 = set(l2)\n\n # Find common elements\n common_elements = set1.intersection(set2)\n\n # Return the sorted list of common elements\n return sorted(common_elements)", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \n \"\"\"\n # Convert both lists to sets to find unique elements and then find the intersection\n common_elements = set(l1) & set(l2)\n \n # Return a sorted list of the common elements\n return sorted(common_elements)", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n \n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n\n \"\"\"\n # Convert lists to sets to find common elements\n common_elements = set(l1) & set(l2)\n # Return sorted list of unique common elements\n return sorted(common_elements)", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n \n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \n \"\"\"\n # Convert lists to sets to find unique elements, then find the intersection\n common_elements = set(l1) & set(l2)\n \n # Return a sorted list of the common unique elements\n return sorted(common_elements)", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n # Convert lists to sets to get unique elements\n set1 = set(l1)\n set2 = set(l2)\n \n # Find common elements and return them sorted\n common_elements = sorted(set1.intersection(set2))\n \n return common_elements", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n # Convert lists to sets to find unique elements and their intersection\n set1 = set(l1)\n set2 = set(l2)\n common_elements = set1.intersection(set2)\n \n # Return the sorted list of common unique elements\n return sorted(common_elements)", "matching_cluster_idx": 4}]}, "HumanEval/59": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 92.0, "profiled": [{"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n \n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n # Start with the smallest prime factor\n factor = 2\n \n # Continue dividing n by factor while it is divisible\n while n > 1:\n if n % factor == 0:\n n //= factor # Divide n by the factor\n else:\n factor += 1 # Move to the next potential factor\n \n return factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n # Start with the smallest prime factor\n factor = 2\n \n # Continue dividing n by factor until n becomes 1\n while n > 1:\n if n % factor == 0:\n n //= factor\n else:\n factor += 1\n \n return factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n # Start with the smallest prime factor\n factor = 2\n # Divide n by the factor until it is no longer divisible\n while n > 1:\n if n % factor == 0:\n n //= factor\n else:\n factor += 1\n return factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n # Start with the smallest prime factor\n prime_factor = 2\n # Keep dividing n by the current prime factor until it's no longer divisible\n while n > 1:\n if n % prime_factor == 0:\n n //= prime_factor # Divide n by the prime factor\n else:\n prime_factor += 1 # Move to the next potential prime factor\n return prime_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n \n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n # Start by finding the smallest prime factor\n largest_factor = None\n # Check for the number of 2s that divide n\n while n % 2 == 0:\n largest_factor = 2\n n //= 2\n \n # n must be odd at this point, check for odd factors from 3 to sqrt(n)\n for i in range(3, int(n**0.5) + 1, 2):\n while n % i == 0:\n largest_factor = i\n n //= i\n \n # This condition is to check if n is a prime number greater than 2\n if n > 2:\n largest_factor = n\n \n return largest_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n \n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n # Start with the smallest prime factor\n factor = 2\n \n # Divide n by factor until it can no longer be divided\n while n > 1:\n if n % factor == 0: # Check if factor is a divisor of n\n n //= factor # Divide n by factor\n else:\n factor += 1 # Move to the next potential factor\n \n return factor # The last factor is the largest prime factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n \n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n # Initialize the largest prime factor\n largest_factor = None\n\n # Check for the number of 2s that divide n\n while n % 2 == 0:\n largest_factor = 2\n n //= 2\n\n # n must be odd at this point, so we can skip even numbers\n for i in range(3, int(n**0.5) + 1, 2):\n while n % i == 0:\n largest_factor = i\n n //= i\n\n # This condition is to check if n is a prime number greater than 2\n if n > 2:\n largest_factor = n\n\n return largest_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n # Initialize the largest prime factor\n largest_factor = None\n \n # Check for the number of 2s that divide n\n while n % 2 == 0:\n largest_factor = 2\n n //= 2\n \n # n must be odd at this point, thus a skip of 2 (i.e., check only odd factors) can be used\n for i in range(3, int(n**0.5) + 1, 2):\n while n % i == 0:\n largest_factor = i\n n //= i\n \n # This condition checks if n is a prime number greater than 2\n if n > 2:\n largest_factor = n\n \n return largest_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n \n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n # Start with the smallest prime factor\n factor = 2\n largest_factor = 1\n \n # Divide n by factor until it is no longer divisible\n while n > 1:\n if n % factor == 0:\n largest_factor = factor\n n //= factor\n else:\n factor += 1\n \n return largest_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n \n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n # Start with the smallest prime factor\n factor = 2\n while factor * factor <= n: # Only need to check up to the square root of n\n if n % factor == 0: # If factor divides n, it's a prime factor\n n //= factor # Divide out all instances of this prime factor\n else:\n factor += 1 # Move to the next potential factor\n return n # If n is greater than 1, it is prime and is the largest prime factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n \n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n # Start with the smallest prime factor\n factor = 2\n \n # Keep dividing n by factor until it is no longer divisible\n while n > 1:\n if n % factor == 0:\n n //= factor\n else:\n factor += 1\n \n return factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n \n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n # Start with the smallest prime factor\n factor = 2\n # Divide n by factor until n is no longer divisible by factor\n while factor * factor <= n:\n if n % factor == 0:\n n //= factor # Divide out the factor\n else:\n factor += 1 # Move to the next factor\n return n # The remaining n is the largest prime factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n # Start with the smallest prime factor\n largest_factor = None\n \n # Check for number of 2s that divide n\n while n % 2 == 0:\n largest_factor = 2\n n //= 2\n \n # Now n must be odd at this point so we can skip one element (i.e., we can check only odd numbers)\n for i in range(3, int(n**0.5) + 1, 2):\n # While i divides n, add i and divide n\n while n % i == 0:\n largest_factor = i\n n //= i\n \n # This condition is to check if n is a prime number greater than 2\n if n > 2:\n largest_factor = n\n \n return largest_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n \n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n # Start with the smallest prime factor\n prime_factor = 2\n \n # Divide n by the smallest prime factor until it is no longer divisible\n while n > 1:\n if n % prime_factor == 0:\n n //= prime_factor\n else:\n prime_factor += 1\n\n return prime_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n \n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n # Start with the smallest prime factor\n largest_factor = 1\n\n # Check for the number of 2s that divide n\n while n % 2 == 0:\n largest_factor = 2\n n //= 2\n\n # Now n must be odd at this point, so we can skip even numbers\n for i in range(3, int(n**0.5) + 1, 2):\n while n % i == 0:\n largest_factor = i\n n //= i\n\n # This condition is to check if n is a prime number greater than 2\n if n > 2:\n largest_factor = n\n\n return largest_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n \n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n # Initialize the largest prime factor\n largest_factor = None\n \n # Check for the number of 2s that divide n\n while n % 2 == 0:\n largest_factor = 2\n n //= 2\n \n # n must be odd at this point, check for odd factors from 3 to sqrt(n)\n for i in range(3, int(n**0.5) + 1, 2):\n while n % i == 0:\n largest_factor = i\n n //= i\n \n # This condition is to check if n is a prime number greater than 2\n if n > 2:\n largest_factor = n\n \n return largest_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n \n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n # Start with the smallest prime factor\n factor = 2\n \n # Divide n by factor until it's no longer divisible\n while n > 1:\n if n % factor == 0:\n n //= factor # Keep dividing n by factor\n else:\n factor += 1 # Move to the next possible factor\n \n return factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n # Start with the smallest prime factor\n largest_factor = 1\n \n # Check for number of 2s that divide n\n while n % 2 == 0:\n largest_factor = 2\n n //= 2\n \n # n must be odd at this point, so we can skip even numbers\n for i in range(3, int(n**0.5) + 1, 2):\n while n % i == 0:\n largest_factor = i\n n //= i\n \n # This condition is to check if n is a prime number greater than 2\n if n > 2:\n largest_factor = n\n \n return largest_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n \n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n # Start with the smallest prime factor\n largest_factor = None\n\n # Check for number of 2s that divide n\n while n % 2 == 0:\n largest_factor = 2\n n //= 2\n\n # Now n must be odd at this point, so we can skip even numbers\n for i in range(3, int(n**0.5) + 1, 2):\n while n % i == 0:\n largest_factor = i\n n //= i\n\n # This condition checks if n is a prime number greater than 2\n if n > 2:\n largest_factor = n\n\n return largest_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n # Start by dividing n by 2 until n is odd\n while n % 2 == 0:\n largest = 2\n n //= 2\n\n # At this point, n is odd, we can check for odd factors\n factor = 3\n while factor * factor <= n:\n while n % factor == 0:\n largest = factor\n n //= factor\n factor += 2 # Increment to the next odd number\n\n # If n becomes a prime number greater than 2\n if n > 2:\n largest = n\n\n return largest", "matching_cluster_idx": 8}]}, "HumanEval/64": {"dps": 45.51948051948052, "dps_norm": 48.75, "pass@1": 95.0, "profiled": [{"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n # Define vowels and initialize count\n vowels = 'aeiouAEIOU'\n count = 0\n \n # Loop through each character in the string\n for i in range(len(s)):\n char = s[i]\n # Check if character is a vowel\n if char in vowels:\n count += 1\n # Check if 'y' is at the end of the word\n elif char.lower() == 'y' and i == len(s) - 1:\n count += 1\n \n return count", "matching_cluster_idx": 2}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = \"aeiouAEIOU\"\n count = 0\n\n for i in range(len(s)):\n if s[i] in vowels:\n count += 1\n elif s[i] == 'y' or s[i] == 'Y':\n if i == len(s) - 1: # 'y' is a vowel only if it's at the end\n count += 1\n\n return count", "matching_cluster_idx": 3}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n # Define the set of vowels\n vowels = \"aeiouAEIOU\"\n count = 0\n \n # Count vowels in the string\n for i in range(len(s)):\n if s[i] in vowels:\n count += 1\n # Check if 'y' is at the end of the word\n elif s[i].lower() == 'y' and i == len(s) - 1:\n count += 1\n \n return count", "matching_cluster_idx": 3}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = \"aeiouAEIOU\"\n count = 0\n\n # Check each character in the string\n for i in range(len(s)):\n if s[i] in vowels:\n count += 1\n elif s[i].lower() == 'y' and i == len(s) - 1:\n count += 1\n\n return count", "matching_cluster_idx": 3}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n s = s.lower() # Convert to lowercase to handle case insensitivity\n vowels = 'aeiou'\n count = 0\n\n for i in range(len(s)):\n if s[i] in vowels: # Count standard vowels\n count += 1\n elif s[i] == 'y' and i == len(s) - 1: # Count 'y' if it's at the end\n count += 1\n \n return count", "matching_cluster_idx": 2}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n >>> vowels_count(\"sky\")\n 1\n >>> vowels_count(\"rhythm\")\n 0\n >>> vowels_count(\"beautiful\")\n 5\n >>> vowels_count(\"queue\")\n 4\n >>> vowels_count(\"harmony\")\n 3\n >>> vowels_count(\"Y\")\n 0\n >>> vowels_count(\"play\")\n 1\n >>> vowels_count(\"happy\")\n 2\n \"\"\"\n vowels = \"aeiou\"\n count = 0\n \n # Normalize the input to lower case for consistent counting\n s = s.lower()\n \n for i in range(len(s)):\n if s[i] in vowels:\n count += 1\n elif s[i] == 'y' and i == len(s) - 1:\n count += 1\n \n return count", "matching_cluster_idx": 2}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n >>> vowels_count(\"hello\")\n 2\n >>> vowels_count(\"sky\")\n 1\n >>> vowels_count(\"fly\")\n 1\n >>> vowels_count(\"rhythm\")\n 0\n >>> vowels_count(\"aeiouy\")\n 6\n >>> vowels_count(\"PYTHON\")\n 1\n >>> vowels_count(\"\")\n 0\n >>> vowels_count(\"y\")\n 0\n >>> vowels_count(\"yummy\")\n 2\n \"\"\"\n vowels = 'aeiouAEIOU'\n count = 0\n\n # Count standard vowels\n for char in s:\n if char in vowels:\n count += 1\n\n # Check if the last character is 'y'\n if s and s[-1].lower() == 'y':\n count += 1\n \n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = 'aeiou'\n count = 0\n\n # Count lowercase vowels\n for char in s.lower():\n if char in vowels:\n count += 1\n \n # Check for 'y' at the end of the word\n if s.lower().endswith('y'):\n count += 1\n\n return count", "matching_cluster_idx": 3}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = \"aeiouAEIOU\"\n count = 0\n \n # Count vowels in the string\n for i in range(len(s)):\n if s[i] in vowels:\n count += 1\n # Check if the character is 'y' and it's the last character of the string\n elif s[i] == 'y' or s[i] == 'Y':\n if i == len(s) - 1:\n count += 1\n \n return count", "matching_cluster_idx": 3}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = 'aeiou'\n count = 0\n \n # Convert the string to lower case for uniformity\n s = s.lower()\n\n # Count the vowels in the string\n for i in range(len(s)):\n if s[i] in vowels:\n count += 1\n # Check if 'y' is at the end of the string\n elif s[i] == 'y' and i == len(s) - 1:\n count += 1\n\n return count", "matching_cluster_idx": 3}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = 'aeiouAEIOU'\n count = 0\n for i in range(len(s)):\n if s[i] in vowels:\n count += 1\n elif s[i] == 'y' or s[i] == 'Y':\n if i == len(s) - 1: # Check if 'y' is at the end of the word\n count += 1\n return count", "matching_cluster_idx": 3}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = 'aeiouAEIOU'\n count = 0\n \n # Count vowels in the string\n for i, char in enumerate(s):\n if char in vowels:\n count += 1\n elif char in 'yY' and i == len(s) - 1: # Check if 'y' is the last character\n count += 1\n\n return count", "matching_cluster_idx": 3}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n # Define the set of vowels\n vowels = 'aeiouAEIOU'\n count = 0\n \n # Iterate through the string to count vowels\n for i in range(len(s)):\n # Check if the character is a vowel\n if s[i] in vowels:\n count += 1\n # Check if 'y' is at the end of the word\n elif s[i] == 'y' or s[i] == 'Y':\n if i == len(s) - 1:\n count += 1\n \n return count", "matching_cluster_idx": 3}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = \"aeiouAEIOU\"\n count = 0\n\n # Count vowels in the string\n for char in s:\n if char in vowels:\n count += 1\n\n # Check if 'y' is at the end of the string\n if s and s[-1].lower() == 'y':\n count += 1\n\n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = 'aeiou'\n count = 0\n s = s.lower() # Convert string to lowercase to count vowels case-insensitively\n \n for i in range(len(s)):\n if s[i] in vowels:\n count += 1\n elif s[i] == 'y' and i == len(s) - 1: # Check if 'y' is at the end of the word\n count += 1\n \n return count", "matching_cluster_idx": 3}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n >>> vowels_count(\"rhythm\")\n 0\n >>> vowels_count(\"sky\")\n 1\n >>> vowels_count(\"y\")\n 1\n >>> vowels_count(\"horizon\")\n 4\n >>> vowels_count(\"AEIOUY\")\n 6\n >>> vowels_count(\"\")\n 0\n >>> vowels_count(\"xyz\")\n 0\n \"\"\"\n # Normalize the string to lowercase for case-insensitive counting\n s = s.lower()\n vowels = \"aeiou\"\n count = 0\n\n # Count vowels in the string\n for i in range(len(s)):\n if s[i] in vowels:\n count += 1\n elif s[i] == 'y' and i == len(s) - 1:\n count += 1\n \n return count", "matching_cluster_idx": 2}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n >>> vowels_count(\"hello\")\n 2\n >>> vowels_count(\"rhythm\")\n 0\n >>> vowels_count(\"sky\")\n 1\n >>> vowels_count(\"symphony\")\n 2\n >>> vowels_count(\"queue\")\n 3\n >>> vowels_count(\"Y\")\n 0\n >>> vowels_count(\"AY\")\n 1\n >>> vowels_count(\"\")\n 0\n \"\"\"\n # Define vowels\n vowels = \"aeiouAEIOU\"\n count = 0\n \n # Count vowels in the string\n for i in range(len(s)):\n if s[i] in vowels:\n count += 1\n elif s[i].lower() == 'y' and i == len(s) - 1:\n count += 1\n \n return count", "matching_cluster_idx": 3}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n # Define the set of vowels\n vowels = set('aeiouAEIOU')\n count = 0\n\n # Check each character in the string\n for i in range(len(s)):\n if s[i] in vowels:\n count += 1\n # Check if 'y' is at the end of the word\n elif s[i].lower() == 'y' and i == len(s) - 1:\n count += 1\n\n return count", "matching_cluster_idx": 3}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n # Define the set of vowels\n vowels = set(\"aeiouAEIOU\")\n count = 0\n\n # Count standard vowels\n for char in s:\n if char in vowels:\n count += 1\n\n # Check if 'y' is the last character\n if s and s[-1].lower() == 'y':\n count += 1\n\n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n s = s.lower() # Convert the string to lowercase for uniformity\n vowels = 'aeiou'\n count = 0\n \n for i, char in enumerate(s):\n if char in vowels: # Count regular vowels\n count += 1\n elif char == 'y' and i == len(s) - 1: # Count 'y' only at the end\n count += 1\n \n return count", "matching_cluster_idx": 2}]}, "HumanEval/74": {"dps": 98.04878048780488, "dps_norm": 88.88888888888889, "pass@1": 13.0, "profiled": [{"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n\n # Calculate the total number of characters in each list\n total_chars_lst1 = sum(len(s) for s in lst1)\n total_chars_lst2 = sum(len(s) for s in lst2)\n\n # Compare the total characters and return the appropriate list\n if total_chars_lst1 < total_chars_lst2:\n return lst1\n elif total_chars_lst1 > total_chars_lst2:\n return lst2\n else:\n return lst1 # If they are equal, return the first list", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n # Calculate the total number of characters in each list\n total_chars_lst1 = sum(len(s) for s in lst1)\n total_chars_lst2 = sum(len(s) for s in lst2)\n\n # Compare total characters and return the appropriate list\n if total_chars_lst1 < total_chars_lst2:\n return lst1\n elif total_chars_lst1 > total_chars_lst2:\n return lst2\n else:\n return lst1 # If equal, return the first list", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n total_chars_lst1 = sum(len(s) for s in lst1)\n total_chars_lst2 = sum(len(s) for s in lst2)\n \n if total_chars_lst1 < total_chars_lst2:\n return lst1\n elif total_chars_lst1 > total_chars_lst2:\n return lst2\n else:\n return lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n # Calculate total character counts for both lists\n total_chars_lst1 = sum(len(s) for s in lst1)\n total_chars_lst2 = sum(len(s) for s in lst2)\n\n # Compare the total character counts and return the appropriate list\n if total_chars_lst1 < total_chars_lst2:\n return lst1\n elif total_chars_lst1 > total_chars_lst2:\n return lst2\n else:\n return lst1 # Return lst1 in case of a tie", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n\n # Calculate the total number of characters in each list\n total_chars_lst1 = sum(len(s) for s in lst1)\n total_chars_lst2 = sum(len(s) for s in lst2)\n\n # Compare the total characters and return the appropriate list\n if total_chars_lst1 < total_chars_lst2:\n return lst1\n elif total_chars_lst1 > total_chars_lst2:\n return lst2\n else:\n return lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n total_chars_lst1 = sum(len(s) for s in lst1)\n total_chars_lst2 = sum(len(s) for s in lst2)\n\n if total_chars_lst1 < total_chars_lst2:\n return lst1\n elif total_chars_lst1 > total_chars_lst2:\n return lst2\n else:\n return lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in all strings of the list less than the other list.\n\n If the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n # Calculate the total number of characters in each list\n total_chars_lst1 = sum(len(s) for s in lst1)\n total_chars_lst2 = sum(len(s) for s in lst2)\n\n # Compare the totals and return the appropriate list\n if total_chars_lst1 < total_chars_lst2:\n return lst1\n elif total_chars_lst1 > total_chars_lst2:\n return lst2\n else:\n return lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n # Calculate the total number of characters in both lists\n total_chars_lst1 = sum(len(s) for s in lst1)\n total_chars_lst2 = sum(len(s) for s in lst2)\n \n # Compare total characters and return the appropriate list\n if total_chars_lst1 < total_chars_lst2:\n return lst1\n elif total_chars_lst1 > total_chars_lst2:\n return lst2\n else:\n return lst1 # If they are equal, return the first list", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in all strings of the list less than the other list.\n\n If the two lists have the same number of chars, return the first list.\n\n Examples:\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n\n # Calculate the total number of characters in lst1\n total_chars_lst1 = sum(len(s) for s in lst1)\n \n # Calculate the total number of characters in lst2\n total_chars_lst2 = sum(len(s) for s in lst2)\n\n # Compare the total number of characters and return the appropriate list\n if total_chars_lst1 < total_chars_lst2:\n return lst1\n elif total_chars_lst1 > total_chars_lst2:\n return lst2\n else:\n return lst1 # If equal, return the first list", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n # Calculate the total number of characters in each list\n total_chars_lst1 = sum(len(s) for s in lst1)\n total_chars_lst2 = sum(len(s) for s in lst2)\n \n # Compare the total number of characters\n if total_chars_lst1 < total_chars_lst2:\n return lst1\n elif total_chars_lst1 > total_chars_lst2:\n return lst2\n else:\n return lst1 # If equal, return the first list", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in all strings of the list less than the other list.\n\n If the two lists have the same number of chars, return the first list.\n\n Examples:\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n\n # Calculate total number of characters in lst1 and lst2\n total_chars_lst1 = sum(len(s) for s in lst1)\n total_chars_lst2 = sum(len(s) for s in lst2)\n \n # Compare total characters and return the appropriate list\n if total_chars_lst1 < total_chars_lst2:\n return lst1\n elif total_chars_lst1 > total_chars_lst2:\n return lst2\n else:\n return lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n total_chars_lst1 = sum(len(s) for s in lst1)\n total_chars_lst2 = sum(len(s) for s in lst2)\n \n if total_chars_lst1 < total_chars_lst2:\n return lst1\n elif total_chars_lst1 > total_chars_lst2:\n return lst2\n else:\n return lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n total_chars_lst1 = sum(len(s) for s in lst1)\n total_chars_lst2 = sum(len(s) for s in lst2)\n\n if total_chars_lst1 < total_chars_lst2:\n return lst1\n elif total_chars_lst1 > total_chars_lst2:\n return lst2\n else:\n return lst1", "matching_cluster_idx": 7}]}, "HumanEval/85": {"dps": 91.68316831683168, "dps_norm": 60.0, "pass@1": 100.0, "profiled": [{"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst, add the even elements that are at odd indices.\n \n Args:\n lst (list): A non-empty list of integers.\n\n Returns:\n int: The sum of even elements at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2\n add([1, 2, 3, 4, 5, 6]) ==> 8 # 2 (index 1) + 6 (index 5)\n \"\"\"\n return sum(x for i, x in enumerate(lst) if i % 2 == 1 and x % 2 == 0)", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Args:\n lst (list): A non-empty list of integers.\n\n Returns:\n int: The sum of even elements found at odd indices.\n \n Examples:\n add([4, 2, 6, 7]) ==> 2 \n add([1, 4, 2, 5, 6]) ==> 4 \n add([10, 2, 3, 8, 4]) ==> 2\n \"\"\"\n return sum(lst[i] for i in range(1, len(lst), 2) if lst[i] % 2 == 0)", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Parameters:\n lst (list): A non-empty list of integers.\n\n Returns:\n int: The sum of even elements located at odd indices.\n\n Examples:\n >>> add([4, 2, 6, 7])\n 2\n >>> add([1, 2, 3, 4, 5, 6])\n 6\n >>> add([10, 5, 2, 9, 8, 1])\n 8\n >>> add([1, 3, 5, 7])\n 0\n \"\"\"\n return sum(num for index, num in enumerate(lst) if index % 2 == 1 and num % 2 == 0)", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Args:\n lst (list of int): A non-empty list of integers.\n\n Returns:\n int: The sum of even elements at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n # Initialize the sum to 0\n total = 0\n \n # Iterate through the list, starting from index 1 to get odd indices\n for i in range(1, len(lst), 2):\n # Check if the element at the odd index is even\n if lst[i] % 2 == 0:\n total += lst[i] # Add to total if even\n \n return total", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst, adds the even elements that are at odd indices.\n \n Examples:\n add([4, 2, 6, 7]) ==> 2\n \"\"\"\n total = 0\n for i in range(1, len(lst), 2): # Iterate over odd indices (1, 3, 5, ...)\n if lst[i] % 2 == 0: # Check if the element at this index is even\n total += lst[i] # Add it to the total if it's even\n return total", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst, adds the even elements that are at odd indices.\n\n Args:\n lst (list): A list of integers.\n\n Returns:\n int: The sum of even integers located at odd indices.\n \n Examples:\n add([4, 2, 6, 7]) ==> 2\n \"\"\"\n total = 0\n for i in range(1, len(lst), 2): # Start at index 1 and step by 2 (odd indices)\n if lst[i] % 2 == 0: # Check if the element is even\n total += lst[i] # Add to total if it's even\n return total", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Args:\n lst (list): A list of integers.\n\n Returns:\n int: The sum of the even elements at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2\n \"\"\"\n return sum(lst[i] for i in range(1, len(lst), 2) if lst[i] % 2 == 0)", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Args:\n lst (list): A non-empty list of integers.\n\n Returns:\n int: The sum of even elements located at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n return sum(lst[i] for i in range(1, len(lst), 2) if lst[i] % 2 == 0)", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Args:\n lst (list of int): A non-empty list of integers.\n\n Returns:\n int: The sum of even elements at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n add([1, 4, 3, 8, 10]) ==> 4 + 10 = 14\n add([2, 3, 4, 5]) ==> 0 # No even elements at odd indices\n \"\"\"\n return sum(lst[i] for i in range(1, len(lst), 2) if lst[i] % 2 == 0)", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2\n \"\"\"\n total = 0\n for i in range(1, len(lst), 2): # start from index 1 and step by 2 to get odd indices\n if lst[i] % 2 == 0: # check if the element is even\n total += lst[i] # add to total if it is even\n return total", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst, add the even elements that are at odd indices.\n \n Args:\n lst (list): A non-empty list of integers.\n\n Returns:\n int: The sum of even elements that are at odd indices.\n \n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n return sum(lst[i] for i in range(1, len(lst), 2) if lst[i] % 2 == 0)", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Args:\n lst (list): A non-empty list of integers.\n\n Returns:\n int: The sum of even elements that are at odd indices.\n\n Examples:\n >>> add([4, 2, 6, 7])\n 2\n >>> add([1, 2, 3, 4, 5])\n 0\n >>> add([0, 1, 2, 3, 4, 5])\n 6\n >>> add([10, 11, 12, 13, 14, 15])\n 12\n \"\"\"\n return sum(x for i, x in enumerate(lst) if i % 2 == 1 and x % 2 == 0)", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Args:\n lst (list): A non-empty list of integers.\n\n Returns:\n int: The sum of even integers at odd indices.\n\n Examples:\n >>> add([4, 2, 6, 7])\n 2\n >>> add([1, 2, 3, 4, 5, 6])\n 8\n >>> add([0, 1, 2, 3, 4, 5])\n 6\n \"\"\"\n return sum(lst[i] for i in range(1, len(lst), 2) if lst[i] % 2 == 0)", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Args:\n lst (list): A list of integers.\n\n Returns:\n int: The sum of even elements at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n total = 0\n for index in range(1, len(lst), 2): # Start from index 1 and step by 2 to get odd indices\n if lst[index] % 2 == 0: # Check if the element is even\n total += lst[index] # Add to total if it's even\n return total", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Args:\n lst (list of int): A list of integers.\n\n Returns:\n int: The sum of even elements at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n add([1, 2, 3, 4, 5]) ==> 0\n add([0, 1, 2, 3, 4]) ==> 4\n \"\"\"\n return sum(lst[i] for i in range(1, len(lst), 2) if lst[i] % 2 == 0)", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Args:\n lst (list): A list of integers.\n\n Returns:\n int: The sum of even elements at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2\n \"\"\"\n total = 0\n # Iterate through the list using enumerate to get both index and value\n for index, value in enumerate(lst):\n # Check if the index is odd and the value is even\n if index % 2 == 1 and value % 2 == 0:\n total += value\n return total", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Args:\n lst (list): A non-empty list of integers.\n \n Returns:\n int: The sum of the even elements at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n add([1, 4, 3, 6, 8]) ==> 4\n add([10, 1, 20, 3, 30]) ==> 0\n \"\"\"\n total = 0\n for index in range(1, len(lst), 2): # Start from index 1 and step by 2 (odd indices)\n if lst[index] % 2 == 0: # Check if the element at the odd index is even\n total += lst[index] # Add to the total if it is even\n return total", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n return sum(x for i, x in enumerate(lst) if i % 2 == 1 and x % 2 == 0)", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst, adds the even elements that are at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n total = 0\n for index in range(1, len(lst), 2): # Start from index 1 and step by 2 (odd indices)\n if lst[index] % 2 == 0: # Check if the element at the odd index is even\n total += lst[index]\n return total", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst, add the even elements that are at odd indices.\n \n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n return sum(lst[i] for i in range(1, len(lst), 2) if lst[i] % 2 == 0)", "matching_cluster_idx": 3}]}, "HumanEval/86": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 98.0, "profiled": [{"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n The ordered version of string is a string where all words (separated by space)\n are replaced by a new word where all the characters are arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n # Split the input string into words while preserving spaces\n words = s.split(' ')\n \n # Sort the characters in each word\n sorted_words = [''.join(sorted(word)) for word in words]\n \n # Join the sorted words back with spaces\n return ' '.join(sorted_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n # Split the input string into words preserving spaces\n words = s.split(' ')\n \n # Sort the characters of each word while keeping the spaces\n ordered_words = [''.join(sorted(word)) for word in words]\n \n # Reconstruct the sentence with sorted words\n return ' '.join(ordered_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n def sort_word(word):\n # Sort the characters of the word based on ASCII value\n return ''.join(sorted(word))\n \n # Split the input string by spaces to preserve order\n words = s.split(' ')\n # Process each word to sort its characters\n sorted_words = [sort_word(word) for word in words]\n # Join the sorted words back with spaces\n return ' '.join(sorted_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n # Split the string into words while preserving spaces\n words = s.split(' ')\n # Create a list to hold the processed words\n ordered_words = []\n\n for word in words:\n # Sort the characters of each word and join them back into a string\n ordered_word = ''.join(sorted(word))\n ordered_words.append(ordered_word)\n\n # Join the processed words back together with spaces\n result = ' '.join(ordered_words)\n return result", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n def order_word(word):\n return ''.join(sorted(word))\n\n words = s.split(' ')\n ordered_words = [order_word(word) for word in words]\n return ' '.join(ordered_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n def sort_word(word):\n return ''.join(sorted(word))\n\n # Split the input string by spaces to preserve spaces in the final result\n words = s.split(' ')\n # Sort each word in the list\n sorted_words = [sort_word(word) for word in words]\n \n # Join the sorted words back with spaces\n return ' '.join(sorted_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n # Split the string into words while keeping spaces intact\n words = s.split(' ')\n \n # Sort characters in each word\n sorted_words = [''.join(sorted(word)) for word in words]\n\n # Join the sorted words back with spaces\n return ' '.join(sorted_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n # Split the string into words and spaces while keeping track of spaces\n words = s.split(' ')\n \n # Process each word\n sorted_words = []\n for word in words:\n # Sort the characters in the word and join back into a string\n sorted_word = ''.join(sorted(word))\n sorted_words.append(sorted_word)\n \n # Join the processed words back into a single string with spaces\n return ' '.join(sorted_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n The ordered version of the string is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ASCII value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n # Split the string by spaces to handle words individually\n words = s.split(' ')\n \n # Sort characters in each word and maintain spaces\n sorted_words = [''.join(sorted(word)) for word in words]\n \n # Join the sorted words back with a single space\n result = ' '.join(sorted_words)\n \n return result", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n The ordered version of the string is a string where all words (separated by space)\n are replaced by a new word where all the characters are arranged in\n ascending order based on ASCII value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n \n def sort_word(word):\n \"\"\"Return the characters of the word sorted in ascending ASCII order.\"\"\"\n return ''.join(sorted(word))\n \n words = s.split(' ')\n sorted_words = [sort_word(word) for word in words]\n \n return ' '.join(sorted_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n The ordered version of the string is created by sorting the characters of \n each word (separated by spaces) in ascending order based on ASCII value, \n while keeping the order of words and blank spaces in the sentence.\n\n Args:\n s (str): The input string.\n\n Returns:\n str: The transformed string with characters in each word sorted.\n \"\"\"\n def sort_word(word):\n # Sort the characters of the word and return as a new string\n return ''.join(sorted(word))\n\n # Split the input string by spaces to handle words separately\n words = s.split(' ')\n # Sort each word and keep the spaces as they are\n sorted_words = [sort_word(word) for word in words]\n # Join the sorted words with spaces to reconstruct the sentence\n return ' '.join(sorted_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n The ordered version of the string is a string where all words (separated by space)\n are replaced by a new word where all the characters are arranged in\n ascending order based on ASCII value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n # Split the string into words, keeping spaces intact\n words = s.split(' ')\n # Sort characters in each word and reconstruct the string\n ordered_words = [''.join(sorted(word)) for word in words]\n # Join the words back into a single string with spaces\n return ' '.join(ordered_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n # Split the input string into words based on spaces\n words = s.split(' ')\n \n # Process each word to sort its characters\n sorted_words = []\n for word in words:\n # Sort the characters of the word and join them back\n sorted_word = ''.join(sorted(word))\n sorted_words.append(sorted_word)\n \n # Join the sorted words back into a string with spaces\n return ' '.join(sorted_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n # Split the string by spaces to preserve the words\n words = s.split(' ')\n # Create an empty list to store processed words\n ordered_words = []\n \n # Process each word\n for word in words:\n # Sort the characters in the word and join them back into a string\n ordered_word = ''.join(sorted(word))\n ordered_words.append(ordered_word)\n \n # Join the ordered words with a space to form the final string\n return ' '.join(ordered_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n # Split the string into words while preserving spaces\n words = s.split(' ')\n \n # Process each word to sort characters\n sorted_words = []\n for word in words:\n # Sort the characters in the word and join them back\n sorted_word = ''.join(sorted(word))\n sorted_words.append(sorted_word)\n \n # Join the processed words back with spaces\n return ' '.join(sorted_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n # Split the input string into words\n words = s.split(' ')\n # Create a list to hold the sorted words\n sorted_words = []\n\n # Process each word\n for word in words:\n # Sort the characters in the word and join them back into a string\n sorted_word = ''.join(sorted(word))\n # Append the sorted word to the list\n sorted_words.append(sorted_word)\n\n # Join the sorted words back into a single string with spaces\n result = ' '.join(sorted_words)\n return result", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n def sort_word(word):\n return ''.join(sorted(word))\n\n words = s.split(' ')\n sorted_words = [sort_word(word) for word in words]\n return ' '.join(sorted_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n The ordered version of the string is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ASCII value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n def sort_word(word):\n # Sort the characters in the word and join them back to a string\n return ''.join(sorted(word))\n\n # Split the string into words while keeping track of spaces\n words = s.split(' ')\n \n # Apply sorting to each word\n sorted_words = [sort_word(word) for word in words]\n \n # Join the sorted words back into a single string with spaces\n result = ' '.join(sorted_words)\n \n return result", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n def sort_word(word):\n # Sort the characters of the word and return as a new string\n return ''.join(sorted(word))\n \n # Split the input string by spaces to handle words and preserve spaces\n words = s.split(' ')\n # Sort each word and preserve the spaces by joining back\n ordered_words = [sort_word(word) for word in words]\n \n return ' '.join(ordered_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n # Split the string into words by spaces\n words = s.split(' ')\n \n # Sort characters in each word while maintaining spaces in the result\n sorted_words = [''.join(sorted(word)) for word in words]\n \n # Join the sorted words back with a space\n result = ' '.join(sorted_words)\n \n return result", "matching_cluster_idx": 4}]}, "HumanEval/87": {"dps": 93.94812680115274, "dps_norm": 57.142857142857146, "pass@1": 100.0, "profiled": [{"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Examples:\n get_row([\n [1, 2, 3, 4, 5, 6],\n [1, 2, 3, 4, 1, 6],\n [1, 2, 3, 4, 5, 1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n \n coordinates = []\n \n # Iterate through each row in the list\n for row_index, row in enumerate(lst):\n # Iterate through each column in the row\n for col_index, value in enumerate(row):\n # If we find the target value x, store its coordinates\n if value == x:\n coordinates.append((row_index, col_index))\n \n # Sort by row (ascending) and then by column (descending)\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n \n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n\n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n coordinates = []\n\n for row_index, row in enumerate(lst):\n for col_index, value in enumerate(row):\n if value == x:\n coordinates.append((row_index, col_index))\n\n # Sort primarily by row index, then by column index in descending order\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n \n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n \n coordinates = []\n \n for row_index, row in enumerate(lst):\n for col_index, value in enumerate(row):\n if value == x:\n coordinates.append((row_index, col_index))\n \n # Sort primarily by row index (ascending) and then by column index (descending)\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n \n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n\n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n \n coordinates = []\n \n for row_index, row in enumerate(lst):\n for col_index, value in enumerate(row):\n if value == x:\n coordinates.append((row_index, col_index))\n \n # Sort by row index ascending and then by column index descending\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n \n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n result = []\n\n # Iterate over each row and its index\n for row_idx, row in enumerate(lst):\n # Iterate over each element in the row and its index\n for col_idx, value in enumerate(row):\n # If the value matches x, add the coordinates to the result\n if value == x:\n result.append((row_idx, col_idx))\n\n # Sort the results: first by row (ascending), then by column (descending)\n result.sort(key=lambda coord: (coord[0], -coord[1]))\n\n return result", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n coordinates = []\n \n for row_index, row in enumerate(lst):\n for col_index, value in enumerate(row):\n if value == x:\n coordinates.append((row_index, col_index))\n \n # Sort by row index (ascending) and then by column index (descending)\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n \n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n result = []\n \n for row_index, row in enumerate(lst):\n for col_index, value in enumerate(row):\n if value == x:\n result.append((row_index, col_index))\n \n # Sort by row first (ascending), and then by column (descending)\n result.sort(key=lambda coordinate: (coordinate[0], -coordinate[1]))\n \n return result", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2-dimensional data as nested lists,\n which is similar to a matrix; however, unlike matrices,\n each row may contain a different number of columns.\n Given lst and integer x, find integers x in the list,\n and return a list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, column), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Examples:\n get_row([\n [1, 2, 3, 4, 5, 6],\n [1, 2, 3, 4, 1, 6],\n [1, 2, 3, 4, 5, 1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n \n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n coordinates = []\n \n for row_index, row in enumerate(lst):\n for col_index, value in enumerate(row):\n if value == x:\n coordinates.append((row_index, col_index))\n \n # Sort by row index first (ascending), then by column index (descending)\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n \n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n coordinates = []\n\n # Iterate through each row in the list\n for row_index, row in enumerate(lst):\n # Find all occurrences of x in the row\n for col_index, value in enumerate(row):\n if value == x:\n coordinates.append((row_index, col_index))\n\n # Sort first by row index (ascending) and then by column index (descending)\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n\n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n coordinates = []\n\n for row_index, row in enumerate(lst):\n for col_index, value in enumerate(row):\n if value == x:\n coordinates.append((row_index, col_index))\n\n # Sort coordinates by row index (ascending) and then by column index (descending)\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n \n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n\n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n\n coordinates = []\n\n for row_index, row in enumerate(lst):\n for col_index, value in enumerate(row):\n if value == x:\n coordinates.append((row_index, col_index))\n\n # Sort by row index (ascending) and column index (descending)\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n\n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Examples:\n get_row([\n [1, 2, 3, 4, 5, 6],\n [1, 2, 3, 4, 1, 6],\n [1, 2, 3, 4, 5, 1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n \n get_row([], 1) == []\n \n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n\n coordinates = []\n \n for row_idx, row in enumerate(lst):\n for col_idx, value in enumerate(row):\n if value == x:\n coordinates.append((row_idx, col_idx))\n \n # Sort by row index (ascending) and then by column index (descending)\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n \n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n coordinates = []\n\n for row_index, row in enumerate(lst):\n for col_index, value in enumerate(row):\n if value == x:\n coordinates.append((row_index, col_index))\n\n # Sort coordinates first by row (ascending) and then by column (descending)\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n\n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n coordinates = []\n \n # Iterate through each row and its index\n for row_index, row in enumerate(lst):\n # Iterate through each column and its index\n for col_index, value in enumerate(row):\n # If the value matches x, store the coordinate (row, col)\n if value == x:\n coordinates.append((row_index, col_index))\n \n # Sort by row first (ascending), and then by column (descending)\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n \n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as nested lists,\n which is similar to a matrix; however, unlike matrices,\n each row may contain a different number of columns.\n Given lst and integer x, find integers x in the list,\n and return a list of tuples, [(x1, y1), (x2, y2), ...] such that\n each tuple is a coordinate - (row, column), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Examples:\n get_row([\n [1, 2, 3, 4, 5, 6],\n [1, 2, 3, 4, 1, 6],\n [1, 2, 3, 4, 5, 1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n \n get_row([], 1) == []\n \n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n coordinates = []\n \n # Iterate through each row in the list\n for row_index, row in enumerate(lst):\n # Find indices of x in the current row\n for col_index, value in enumerate(row):\n if value == x:\n coordinates.append((row_index, col_index))\n \n # Sort coordinates by row index (ascending) and by column index (descending)\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n \n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n coordinates = []\n\n for row_index, row in enumerate(lst):\n for col_index, value in enumerate(row):\n if value == x:\n coordinates.append((row_index, col_index))\n\n # Sort first by row (ascending) and then by column (descending)\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n\n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2-dimensional data as nested lists,\n which is similar to a matrix; however, unlike matrices,\n each row may contain a different number of columns.\n Given lst and an integer x, find integers x in the list,\n and return a list of tuples, [(x1, y1), (x2, y2), ...] such that\n each tuple is a coordinate - (row, column), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n\n Examples:\n get_row([\n [1, 2, 3, 4, 5, 6],\n [1, 2, 3, 4, 1, 6],\n [1, 2, 3, 4, 5, 1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n \n result = []\n for row_index, row in enumerate(lst):\n for col_index, value in enumerate(row):\n if value == x:\n result.append((row_index, col_index))\n \n # Sort by row index and then by column index (descending)\n result.sort(key=lambda coord: (coord[0], -coord[1]))\n return result", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2-dimensional data, as a nested list,\n which is similar to a matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return a list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, column), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n coordinates = []\n\n for row_index, row in enumerate(lst):\n for col_index, value in enumerate(row):\n if value == x:\n coordinates.append((row_index, col_index))\n\n # Sort by row index, then by column index in descending order\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n \n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n \n get_row([], 1) == []\n \n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n coordinates = []\n\n for row_index, row in enumerate(lst):\n for col_index, value in enumerate(row):\n if value == x:\n coordinates.append((row_index, col_index))\n\n # Sort by row index (ascending) and then by column index (descending)\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n\n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n coordinates = []\n\n for row_index, row in enumerate(lst):\n for col_index, value in enumerate(row):\n if value == x:\n coordinates.append((row_index, col_index))\n\n # Sort coordinates by row (ascending), and by column (descending)\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n \n return coordinates", "matching_cluster_idx": 3}]}, "HumanEval/89": {"dps": 96.64948453608248, "dps_norm": 28.571428571428573, "pass@1": 86.0, "profiled": [{"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n # Define the rotation amount\n rotation = 4 # 2 multiplied by 2\n \n # Create an empty result string\n encrypted_string = \"\"\n \n for char in s:\n # Check if the character is an alphabet letter\n if char.isalpha():\n # Determine if the letter is uppercase or lowercase\n start = ord('a') if char.islower() else ord('A')\n # Rotate the character by the defined rotation amount\n rotated_char = chr(start + (ord(char) - start + rotation) % 26)\n encrypted_string += rotated_char\n else:\n # Non-alphabet characters are left unchanged\n encrypted_string += char\n \n return encrypted_string", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated.\n The alphabet should be rotated in a manner such that the letters\n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n result = []\n for char in s:\n if char.isalpha(): # Check if the character is a letter\n # Shift the letter by 4 positions (2 multiplied by 2)\n # Use modulo to wrap around the alphabet\n shifted = chr(((ord(char) - ord('a') + 4) % 26) + ord('a'))\n result.append(shifted)\n else:\n # If it's not a letter, keep it unchanged\n result.append(char)\n return ''.join(result)", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Encrypt the input string by rotating each letter down the alphabet by 4 positions.\"\"\"\n result = []\n for char in s:\n if char.isalpha(): # Check if the character is a letter\n # Calculate the new character's ordinal value after rotation\n new_char = chr(((ord(char) - ord('a') + 4) % 26) + ord('a')) if char.islower() else \\\n chr(((ord(char) - ord('A') + 4) % 26) + ord('A'))\n result.append(new_char)\n else:\n result.append(char) # Keep non-alphabet characters unchanged\n return ''.join(result)", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Encrypt a string by shifting each letter down the alphabet by 4 positions.\"\"\"\n encrypted_string = \"\"\n for char in s:\n if char.isalpha(): # Check if the character is a letter\n # Shift character by 4 positions in the alphabet\n shifted_char = chr(((ord(char) - ord('a') + 4) % 26) + ord('a')) if char.islower() else \\\n chr(((ord(char) - ord('A') + 4) % 26) + ord('A'))\n encrypted_string += shifted_char\n else:\n # If the character is not a letter, we can choose to leave it unchanged\n encrypted_string += char\n return encrypted_string", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n \n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n encrypted = []\n for char in s:\n if char.isalpha(): # Check if character is a letter\n # Shift character down the alphabet by 4 places\n new_char = chr((ord(char) - ord('a') + 4) % 26 + ord('a'))\n encrypted.append(new_char)\n else:\n encrypted.append(char) # Non-alphabet characters are unchanged\n\n return ''.join(encrypted)", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n result = []\n for char in s:\n if char.isalpha(): # Check if the character is a letter\n # Rotate the character by 4 positions (2 * 2)\n shifted = ord(char) + 4\n if char.islower():\n if shifted > ord('z'):\n shifted -= 26 # Wrap around for lowercase letters\n elif char.isupper():\n if shifted > ord('Z'):\n shifted -= 26 # Wrap around for uppercase letters\n result.append(chr(shifted))\n else:\n result.append(char) # Non-alphabetic characters are unchanged\n return ''.join(result)", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n # Define the alphabet\n alphabet = 'abcdefghijklmnopqrstuvwxyz'\n # Create a mapping for each letter\n encrypted = ''\n for char in s:\n if char in alphabet:\n # Find the current index and shift it by 4 positions (2 * 2)\n new_index = (alphabet.index(char) + 4) % 26\n encrypted += alphabet[new_index]\n else:\n # If character is not in the alphabet, we can just keep it as is\n encrypted += char\n return encrypted", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n \n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n result = []\n \n for char in s:\n if char.isalpha(): # Check if character is a letter\n # Shift character by 4 positions\n new_char = chr((ord(char) - ord('a') + 4) % 26 + ord('a')) if char.islower() else \\\n chr((ord(char) - ord('A') + 4) % 26 + ord('A'))\n result.append(new_char)\n else:\n result.append(char) # Keep non-alphabet characters unchanged\n\n return ''.join(result)", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Encrypt a string by rotating the letters down by four places in the alphabet.\"\"\"\n result = []\n \n for char in s:\n if char.isalpha(): # Check if the character is a letter\n # Get the ASCII value of the character\n ascii_offset = ord('a') if char.islower() else ord('A')\n # Shift the character down by 4, wrapping around the alphabet\n new_char = chr(ascii_offset + (ord(char) - ascii_offset + 4) % 26)\n result.append(new_char)\n else:\n # If not a letter, we can just append it as is (or handle as needed)\n result.append(char)\n \n return ''.join(result)", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Encrypt the input string by rotating each letter down by four places in the alphabet.\"\"\"\n encrypted_string = \"\"\n \n for char in s:\n if char.isalpha(): # Check if the character is a letter\n # Calculate the new position with rotation\n shift = 4 # Two multiplied by two\n new_char = chr(((ord(char) - ord('a') + shift) % 26) + ord('a')) if char.islower() else \\\n chr(((ord(char) - ord('A') + shift) % 26) + ord('A'))\n encrypted_string += new_char\n else:\n encrypted_string += char # Keep non-alphabet characters unchanged\n \n return encrypted_string", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Encrypts the input string by rotating its letters down the alphabet\n by two multiplied by two places (i.e., four places).\n \n Args:\n s (str): The input string to encrypt.\n \n Returns:\n str: The encrypted string.\n \"\"\"\n encrypted = []\n \n for char in s:\n if char.isalpha(): # Check if the character is a letter\n # Calculate the rotated character\n # Shift by 4 positions within the bounds of 'a' to 'z'\n new_char = chr(((ord(char) - ord('a') + 4) % 26) + ord('a'))\n encrypted.append(new_char)\n else:\n encrypted.append(char) # Append non-alphabetic characters unchanged\n \n return ''.join(encrypted)", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n result = []\n for char in s:\n if char.isalpha(): # Check if the character is an alphabet\n # Shift the character by 2 * 2 = 4 places\n new_char = chr((ord(char) - ord('a') + 4) % 26 + ord('a'))\n result.append(new_char)\n else:\n result.append(char) # Non-alphabet characters remain unchanged\n\n return ''.join(result)", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Encrypts the input string by rotating each letter down the alphabet\n by two multiplied to two places (i.e., shifting each letter by 4 places).\n \n Args:\n s (str): The string to be encrypted.\n \n Returns:\n str: The encrypted string.\n \"\"\"\n encrypted_string = []\n \n for char in s:\n if char.isalpha(): # Check if the character is a letter\n # Calculate the new character's ASCII value\n shift = (ord(char) - ord('a') + 4) % 26 + ord('a') if char.islower() else (ord(char) - ord('A') + 4) % 26 + ord('A')\n encrypted_string.append(chr(shift))\n else:\n # If it's not a letter, we just add it to the result unchanged\n encrypted_string.append(char)\n \n return ''.join(encrypted_string)", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet is rotated in a manner such that the letters \n shift down by 4 places.\n \n Args:\n s (str): The string to be encrypted.\n\n Returns:\n str: The encrypted string.\n \"\"\"\n result = []\n for char in s:\n if char.isalpha(): # Check if the character is a letter\n # Calculate the new character\n offset = ord('a') if char.islower() else ord('A')\n new_char = chr((ord(char) - offset + 4) % 26 + offset)\n result.append(new_char)\n else:\n # If it's not a letter, append it unchanged\n result.append(char)\n\n return ''.join(result)", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Encrypts a string by rotating its letters down the alphabet\n by two multiplied by two places (i.e., a shift of 4).\n\n Args:\n s (str): The string to encrypt.\n\n Returns:\n str: The encrypted string.\n \"\"\"\n encrypted = []\n for char in s:\n if char.isalpha(): # Check if the character is a letter\n shift = 4 # Define the shift amount\n if char.islower():\n # Shift the character and wrap around using modulo\n new_char = chr((ord(char) - ord('a') + shift) % 26 + ord('a'))\n else:\n # Shift the character for uppercase letters\n new_char = chr((ord(char) - ord('A') + shift) % 26 + ord('A'))\n encrypted.append(new_char)\n else:\n # Non-alphabetic characters remain unchanged\n encrypted.append(char)\n\n return ''.join(encrypted)", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n \n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n encrypted = \"\"\n for char in s:\n if char.isalpha(): # Check if the character is a letter\n # Calculate the new character position\n new_char = chr(((ord(char) - ord('a') + 4) % 26) + ord('a'))\n encrypted += new_char\n else:\n encrypted += char # If it's not a letter, keep it unchanged\n return encrypted", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n # Create a list to hold the encrypted characters\n encrypted_chars = []\n \n # Iterate over each character in the input string\n for char in s:\n if char.isalpha(): # Check if the character is an alphabet letter\n # Determine the base (ASCII code) for lowercase or uppercase letters\n base = ord('a') if char.islower() else ord('A')\n # Calculate the new character's position, rotating 4 positions\n new_char = chr((ord(char) - base + 4) % 26 + base)\n encrypted_chars.append(new_char)\n else:\n # If not an alphabet letter, append it unchanged\n encrypted_chars.append(char)\n \n # Join the list into a string and return\n return ''.join(encrypted_chars)", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n result = []\n for char in s:\n if char.isalpha(): # Check if character is a letter\n # Find the starting point of the letter's ASCII value\n start = ord('a') if char.islower() else ord('A')\n # Rotate the character by 4 positions (2 multiplied by 2)\n new_char = chr(start + (ord(char) - start + 4) % 26)\n result.append(new_char)\n else:\n result.append(char) # Non-alphabetical characters remain unchanged\n \n return ''.join(result)", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n encrypted = []\n for char in s:\n if char.isalpha(): # Check if the character is a letter\n # Calculate the new character's ASCII value\n new_char = chr((ord(char) - ord('a') + 4) % 26 + ord('a'))\n encrypted.append(new_char)\n else:\n encrypted.append(char) # Non-alphabet characters remain unchanged\n\n return ''.join(encrypted)", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n \n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n result = []\n \n for char in s:\n # Check if character is a lowercase letter\n if 'a' <= char <= 'z':\n # Shift the character by 4 positions in the alphabet\n new_char = chr((ord(char) - ord('a') + 4) % 26 + ord('a'))\n result.append(new_char)\n # Check if character is an uppercase letter (optional, you can include or exclude)\n elif 'A' <= char <= 'Z':\n new_char = chr((ord(char) - ord('A') + 4) % 26 + ord('A'))\n result.append(new_char)\n else:\n # If the character is not a letter, you can choose to leave it unchanged\n result.append(char)\n \n return ''.join(result)", "matching_cluster_idx": 1}]}, "HumanEval/90": {"dps": 87.54863813229572, "dps_norm": 58.333333333333336, "pass@1": 100.0, "profiled": [{"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n # Remove duplicates by converting to a set, then back to a sorted list\n unique_sorted = sorted(set(lst))\n \n # Check if there are at least two unique elements\n if len(unique_sorted) < 2:\n return None\n \n # Return the second smallest element\n return unique_sorted[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n # Remove duplicates by converting the list to a set, then back to a list\n unique_lst = list(set(lst))\n \n # Sort the list to find the 2nd smallest element\n unique_lst.sort()\n \n # Check if there are at least two unique elements\n if len(unique_lst) < 2:\n return None\n \n # Return the 2nd smallest element\n return unique_lst[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n unique_elements = list(set(lst)) # Remove duplicates\n unique_elements.sort() # Sort the list\n \n if len(unique_elements) < 2:\n return None # If there are less than 2 unique elements, return None\n \n return unique_elements[1] # Return the second smallest element", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n # Remove duplicates by converting the list to a set, then back to a sorted list\n unique_sorted = sorted(set(lst))\n \n # Check if there are at least 2 unique elements\n if len(unique_sorted) < 2:\n return None\n \n # Return the second smallest element\n return unique_sorted[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n\n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n # Create a set to remove duplicates\n unique_elements = set(lst)\n\n # If there are less than 2 unique elements, return None\n if len(unique_elements) < 2:\n return None\n\n # Convert the set back to a sorted list\n sorted_unique_elements = sorted(unique_elements)\n\n # Return the second smallest element\n return sorted_unique_elements[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n unique_elements = set(lst) # Get unique elements to handle duplicates\n if len(unique_elements) < 2: # Check if there are at least 2 unique elements\n return None\n unique_sorted = sorted(unique_elements) # Sort the unique elements\n return unique_sorted[1] # Return the second smallest element", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n # Use a set to eliminate duplicates and then convert it back to a sorted list\n unique_sorted_lst = sorted(set(lst))\n \n # Check if there are at least 2 unique elements\n if len(unique_sorted_lst) < 2:\n return None\n \n # Return the second smallest element\n return unique_sorted_lst[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n # Convert the list to a set to remove duplicates, then back to a sorted list\n unique_sorted = sorted(set(lst))\n \n # Check if there are at least two unique elements\n if len(unique_sorted) < 2:\n return None\n \n # Return the second smallest element\n return unique_sorted[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n # Remove duplicates by converting to a set and then back to a list\n unique_lst = list(set(lst))\n \n # Check if there are at least two unique elements\n if len(unique_lst) < 2:\n return None\n \n # Sort the list to find the second smallest element\n unique_lst.sort()\n \n # Return the second smallest element\n return unique_lst[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n # Remove duplicates by converting the list to a set\n unique_numbers = set(lst)\n \n # If there are fewer than 2 unique numbers, return None\n if len(unique_numbers) < 2:\n return None\n \n # Sort the unique numbers\n sorted_numbers = sorted(unique_numbers)\n \n # Return the second smallest element\n return sorted_numbers[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n # Use a set to eliminate duplicates and sort the unique elements\n unique_sorted = sorted(set(lst))\n \n # Check if there are at least two unique elements\n if len(unique_sorted) < 2:\n return None\n \n # Return the second smallest element\n return unique_sorted[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n This function returns the 2nd smallest element of the list.\n Returns None if there is no such element.\n \n Parameters:\n lst (list): A list of integers\n \n Returns:\n int or None: The 2nd smallest integer or None if it does not exist.\n \"\"\"\n # Remove duplicates by converting to a set\n unique_numbers = set(lst)\n \n # If there are fewer than 2 unique numbers, return None\n if len(unique_numbers) < 2:\n return None\n \n # Sort the unique numbers\n sorted_numbers = sorted(unique_numbers)\n \n # Return the second smallest\n return sorted_numbers[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n # Use a set to eliminate duplicates and then sort the unique elements\n unique_sorted = sorted(set(lst))\n\n # Return the second smallest element if it exists\n if len(unique_sorted) < 2:\n return None\n else:\n return unique_sorted[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n\n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n # Create a set from the list to remove duplicates and then convert it back to a list\n unique_numbers = list(set(lst))\n \n # Sort the unique numbers\n unique_numbers.sort()\n \n # Check if there is at least a second smallest element\n if len(unique_numbers) < 2:\n return None\n \n # Return the second smallest element\n return unique_numbers[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n unique_numbers = set(lst) # Remove duplicates\n if len(unique_numbers) < 2:\n return None # Less than 2 unique elements, no 2nd smallest\n sorted_numbers = sorted(unique_numbers) # Sort the unique elements\n return sorted_numbers[1] # Return the 2nd smallest element", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n # Convert the list to a set to remove duplicates and sort it\n unique_sorted = sorted(set(lst))\n \n # Check if there are at least two unique elements\n if len(unique_sorted) < 2:\n return None\n \n # Return the second smallest element\n return unique_sorted[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n\n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n # Remove duplicates by converting the list to a set, then back to a list\n unique_lst = list(set(lst))\n \n # Check if there are at least two unique elements\n if len(unique_lst) < 2:\n return None\n \n # Sort the unique list and return the second smallest element\n unique_lst.sort()\n return unique_lst[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n # Remove duplicates by converting to a set, then convert back to a sorted list\n unique_sorted_lst = sorted(set(lst))\n \n # Check if there are at least two unique elements\n if len(unique_sorted_lst) < 2:\n return None\n \n # Return the second smallest element\n return unique_sorted_lst[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n # Use a set to find unique elements and then sort them\n unique_sorted = sorted(set(lst))\n \n # Check if there are at least two unique elements\n if len(unique_sorted) < 2:\n return None\n else:\n return unique_sorted[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n This function returns the 2nd smallest element of the list.\n Returns None if there is no such element.\n \n Examples:\n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n # Remove duplicates by converting the list to a set\n unique_elements = list(set(lst))\n \n # Check if there are at least 2 unique elements\n if len(unique_elements) < 2:\n return None\n \n # Sort the unique elements\n unique_elements.sort()\n \n # Return the second smallest element\n return unique_elements[1]", "matching_cluster_idx": 6}]}, "HumanEval/113": {"dps": 99.43204868154159, "dps_norm": 75.83333333333333, "pass@1": 100.0, "profiled": [{"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n result = []\n for s in lst:\n # Count the number of odd digits in the string\n odd_count = sum(1 for char in s if char in '13579')\n # Create the output string using the counted odd digits\n output_string = f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\"\n result.append(output_string)\n return result", "matching_cluster_idx": 4}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3', \"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n \n result = []\n for string in lst:\n # Count the odd digits in the current string\n odd_count = sum(1 for char in string if char in '13579')\n # Create the output string with the count inserted\n output = f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\"\n result.append(output)\n return result", "matching_cluster_idx": 4}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n \n result = []\n for s in lst:\n odd_count = sum(1 for char in s if int(char) % 2 != 0)\n result.append(f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\")\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits,\n return a list. Each element i of the output should be \"the number of odd \n elements in the string i of the input.\" where all the i's should be \n replaced by the number of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3', \"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n result = []\n for string in lst:\n odd_count = sum(1 for digit in string if int(digit) % 2 != 0)\n result.append(f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\")\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3', \"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n result = []\n \n for s in lst:\n # Count the odd digits in the string\n odd_count = sum(1 for char in s if char in '13579')\n \n # Construct the output string with the count\n output_string = f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\"\n result.append(output_string)\n \n return result", "matching_cluster_idx": 4}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n results = []\n \n for s in lst:\n odd_count = sum(1 for char in s if int(char) % 2 == 1) # Count odd digits\n result = f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\"\n results.append(result)\n \n return results", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n result = []\n \n for s in lst:\n odd_count = sum(1 for char in s if char in '13579') # Count odd digits\n # Format the output string with the count of odd digits\n output_str = f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\"\n result.append(output_str)\n\n return result", "matching_cluster_idx": 4}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3', \"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n output = []\n for s in lst:\n odd_count = sum(1 for char in s if char in '13579')\n result_string = f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\"\n output.append(result_string)\n return output", "matching_cluster_idx": 4}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n result = []\n for s in lst:\n odd_count = sum(1 for char in s if char in '13579') # Count odd digits\n result.append(f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\")\n return result", "matching_cluster_idx": 4}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n output = []\n for s in lst:\n odd_count = sum(1 for char in s if int(char) % 2 == 1) # Count odd digits\n output.append(f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\")\n return output", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n result = []\n \n for s in lst:\n # Count odd digits in the current string\n odd_count = sum(1 for char in s if char in '13579')\n \n # Construct the output string\n result.append(f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\")\n \n return result", "matching_cluster_idx": 4}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n result = []\n for s in lst:\n # Count odd digits\n odd_count = sum(1 for char in s if int(char) % 2 != 0)\n # Formulate the output string\n output_string = f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\"\n result.append(output_string)\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n output = []\n for s in lst:\n odd_count = sum(1 for digit in s if int(digit) % 2 != 0)\n output.append(f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\")\n return output", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3', \"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n result = []\n for s in lst:\n # Count the number of odd digits in the string\n odd_count = sum(1 for char in s if char in '13579')\n # Construct the output string with the counted odd digits\n output_string = f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\"\n result.append(output_string)\n return result", "matching_cluster_idx": 4}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n result = []\n for string in lst:\n odd_count = sum(1 for char in string if char in '13579') # Count odd digits\n result.append(f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\")\n return result", "matching_cluster_idx": 4}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3', \"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n output = []\n for string in lst:\n odd_count = sum(1 for char in string if char in '13579')\n result_string = f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\"\n output.append(result_string)\n return output", "matching_cluster_idx": 4}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n result = []\n for s in lst:\n odd_count = sum(1 for digit in s if int(digit) % 2 != 0)\n result.append(f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\")\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n output = []\n for s in lst:\n odd_count = sum(1 for char in s if int(char) % 2 != 0)\n output.append(f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\")\n return output", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits,\n return a list. Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n result = []\n for s in lst:\n # Count odd digits in the string\n odd_count = sum(1 for char in s if char in '13579')\n # Create the result string with the counted odd digits\n result.append(f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\")\n return result", "matching_cluster_idx": 4}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3', \"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n output = []\n for s in lst:\n odd_count = sum(1 for char in s if int(char) % 2 != 0)\n output.append(f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\")\n return output", "matching_cluster_idx": 3}]}, "HumanEval/119": {"dps": 6.686046511627907, "dps_norm": 77.0, "pass@1": 85.0, "profiled": [{"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n\n def is_good(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n else: # char == ')'\n balance -= 1\n # If balance goes negative, there are unmatched ')'\n if balance < 0:\n return False\n # For the string to be good, balance must be zero at the end\n return balance == 0\n\n # Check both concatenations\n s1, s2 = lst\n if is_good(s1 + s2) or is_good(s2 + s1):\n return 'Yes'\n else:\n return 'No'", "matching_cluster_idx": 3}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n \n # Helper function to check if a string has balanced parentheses\n def is_balanced(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n elif char == ')':\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n # Get the two strings\n str1, str2 = lst\n \n # Check both possible concatenations\n return 'Yes' if is_balanced(str1 + str2) or is_balanced(str2 + str1) else 'No'", "matching_cluster_idx": 3}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n \n def is_balanced(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n else:\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n s1, s2 = lst\n # Check both concatenations: s1 + s2 and s2 + s1\n return 'Yes' if is_balanced(s1 + s2) or is_balanced(s2 + s1) else 'No'", "matching_cluster_idx": 3}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n def count_parentheses(s):\n open_count = s.count('(')\n close_count = s.count(')')\n return open_count, close_count\n\n # Count parentheses in both strings\n open_a, close_a = count_parentheses(lst[0])\n open_b, close_b = count_parentheses(lst[1])\n\n # Check both concatenation orders: lst[0] + lst[1] and lst[1] + lst[0]\n # For a good string, the number of closing brackets should not exceed \n # the number of opening brackets at any point.\n\n # Check if lst[0] + lst[1] is good\n if open_a + open_b >= close_a + close_b:\n # Check if we can balance while concatenating\n balance = 0\n for char in lst[0] + lst[1]:\n if char == '(':\n balance += 1\n else: # char == ')'\n balance -= 1\n if balance < 0:\n break\n else:\n if balance == 0:\n return 'Yes'\n \n # Check if lst[1] + lst[0] is good\n if open_b + open_a >= close_b + close_a:\n # Check if we can balance while concatenating\n balance = 0\n for char in lst[1] + lst[0]:\n if char == '(':\n balance += 1\n else: # char == ')'\n balance -= 1\n if balance < 0:\n break\n else:\n if balance == 0:\n return 'Yes'\n \n return 'No'", "matching_cluster_idx": 0}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n \n def is_good(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n else: # char == ')'\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n s1, s2 = lst\n # Check both concatenation orders\n return 'Yes' if is_good(s1 + s2) or is_good(s2 + s1) else 'No'", "matching_cluster_idx": 3}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n\n def is_good(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n else:\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n a, b = lst\n # Check both concatenation orders\n if is_good(a + b) or is_good(b + a):\n return 'Yes'\n return 'No'", "matching_cluster_idx": 3}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n\n def is_good(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n else: # char == ')'\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n s1, s2 = lst\n\n # Check both concatenation orders: s1 + s2 and s2 + s1\n if is_good(s1 + s2) or is_good(s2 + s1):\n return 'Yes'\n else:\n return 'No'", "matching_cluster_idx": 3}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n\n def is_good(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n else:\n balance -= 1\n if balance < 0: # At any point, we shouldn't have more ')' than '('\n return False\n return balance == 0 # Should be balanced at the end\n\n first, second = lst\n\n # Check both concatenation orders\n if is_good(first + second) or is_good(second + first):\n return 'Yes'\n \n return 'No'", "matching_cluster_idx": 3}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n\n def is_good(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n elif char == ')':\n balance -= 1\n if balance < 0: # More closing than opening\n return False\n return balance == 0 # Should be balanced at the end\n\n a, b = lst\n\n # Check both concatenation orders\n if is_good(a + b) or is_good(b + a):\n return 'Yes'\n else:\n return 'No'", "matching_cluster_idx": 3}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n\n # Function to check if a string is balanced\n def is_balanced(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n else: # char == ')'\n balance -= 1\n # If balance goes negative, we have more ')' than '('\n if balance < 0:\n return False\n # The string is balanced if we end up with 0 balance\n return balance == 0\n\n # Check both concatenation orders\n return 'Yes' if is_balanced(lst[0] + lst[1]) or is_balanced(lst[1] + lst[0]) else 'No'", "matching_cluster_idx": 3}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n \n def is_balanced(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n else: # char == ')'\n balance -= 1\n if balance < 0: # More closing than opening\n return False\n return balance == 0 # Must end with a balance of zero\n\n s1, s2 = lst\n \n # Check both concatenation orders\n return 'Yes' if is_balanced(s1 + s2) or is_balanced(s2 + s1) else 'No'", "matching_cluster_idx": 3}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n def is_good(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n else:\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n a, b = lst[0], lst[1]\n \n # Check both possible concatenations\n return 'Yes' if is_good(a + b) or is_good(b + a) else 'No'", "matching_cluster_idx": 3}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n\n def is_good(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n else: # char == ')'\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n str1, str2 = lst\n\n # Check both concatenation orders\n if is_good(str1 + str2) or is_good(str2 + str1):\n return 'Yes'\n return 'No'", "matching_cluster_idx": 3}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n\n def is_good(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n else: # char == ')'\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n # Check both concatenations: lst[0] + lst[1] and lst[1] + lst[0]\n return 'Yes' if is_good(lst[0] + lst[1]) or is_good(lst[1] + lst[0]) else 'No'", "matching_cluster_idx": 3}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n\n def is_good(concat_str):\n balance = 0\n for char in concat_str:\n if char == '(':\n balance += 1\n else: # char == ')'\n balance -= 1\n if balance < 0: # More closing than opening\n return False\n return balance == 0 # Must end with a balance of zero\n\n # Check both concatenation orders\n return 'Yes' if is_good(lst[0] + lst[1]) or is_good(lst[1] + lst[0]) else 'No'", "matching_cluster_idx": 3}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n \n def is_good_string(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n else: # char == ')'\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n \n str1, str2 = lst\n\n # Check both concatenation orders\n return 'Yes' if is_good_string(str1 + str2) or is_good_string(str2 + str1) else 'No'", "matching_cluster_idx": 3}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n \n def is_balanced(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n else:\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n \n first, second = lst\n \n # Check both concatenations: first + second and second + first\n return 'Yes' if is_balanced(first + second) or is_balanced(second + first) else 'No'", "matching_cluster_idx": 3}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n\n def is_good(s1, s2):\n combined = s1 + s2\n balance = 0\n for char in combined:\n if char == '(':\n balance += 1\n else: # char == ')'\n balance -= 1\n if balance < 0: # more closing than opening parentheses\n return False\n return balance == 0 # must end with no open parentheses\n\n s1, s2 = lst\n # Check both orders of concatenation\n if is_good(s1, s2) or is_good(s2, s1):\n return 'Yes'\n return 'No'", "matching_cluster_idx": 3}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n\n def is_good(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n elif char == ')':\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n # Check both possible concatenations\n return 'Yes' if is_good(lst[0] + lst[1]) or is_good(lst[1] + lst[0]) else 'No'", "matching_cluster_idx": 3}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n\n def is_good(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n else:\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n s1, s2 = lst\n # Check both possible concatenations\n return 'Yes' if is_good(s1 + s2) or is_good(s2 + s1) else 'No'", "matching_cluster_idx": 3}]}, "HumanEval/120": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 98.0, "profiled": [{"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n\n Example 1:\n Input: arr = [-3, -4, 5], k = 3\n Output: [-4, -3, 5]\n\n Example 2:\n Input: arr = [4, -4, 4], k = 2\n Output: [4, 4]\n\n Example 3:\n Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1\n Output: [2]\n\n Note:\n 1. The length of the array will be in the range of [1, 1000].\n 2. The elements in the array will be in the range of [-1000, 1000].\n 3. 0 <= k <= len(arr)\n \"\"\"\n # Sort the array in descending order\n sorted_arr = sorted(arr, reverse=True)\n \n # Get the top k elements\n top_k = sorted_arr[:k]\n \n # Return the top k elements sorted in ascending order\n return sorted(top_k)", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n\n Example 1:\n\n Input: arr = [-3, -4, 5], k = 3\n Output: [-4, -3, 5]\n\n Example 2:\n\n Input: arr = [4, -4, 4], k = 2\n Output: [4, 4]\n\n Example 3:\n\n Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1\n Output: [2]\n\n Note:\n 1. The length of the array will be in the range of [1, 1000].\n 2. The elements in the array will be in the range of [-1000, 1000].\n 3. 0 <= k <= len(arr)\n \"\"\"\n # Sort the array in descending order\n sorted_arr = sorted(arr, reverse=True)\n # Take the first k elements\n max_k_elements = sorted_arr[:k]\n # Return the result sorted in ascending order\n return sorted(max_k_elements)", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n\n Example 1:\n Input: arr = [-3, -4, 5], k = 3\n Output: [-4, -3, 5]\n\n Example 2:\n Input: arr = [4, -4, 4], k = 2\n Output: [4, 4]\n\n Example 3:\n Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1\n Output: [2]\n\n Note:\n 1. The length of the array will be in the range of [1, 1000].\n 2. The elements in the array will be in the range of [-1000, 1000].\n 3. 0 <= k <= len(arr)\n \"\"\"\n # Sort the array in descending order and take the first k elements\n max_k_elements = sorted(arr, reverse=True)[:k]\n # Sort the resulting k elements in ascending order before returning\n return sorted(max_k_elements)", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n\n Example 1:\n\n Input: arr = [-3, -4, 5], k = 3\n Output: [-4, -3, 5]\n\n Example 2:\n\n Input: arr = [4, -4, 4], k = 2\n Output: [4, 4]\n\n Example 3:\n\n Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1\n Output: [2]\n\n Note:\n 1. The length of the array will be in the range of [1, 1000].\n 2. The elements in the array will be in the range of [-1000, 1000].\n 3. 0 <= k <= len(arr)\n \"\"\"\n # Handle case where k is 0\n if k == 0:\n return []\n \n # Sort the array in descending order\n sorted_arr = sorted(arr, reverse=True)\n \n # Take the first k elements\n max_k_elements = sorted_arr[:k]\n \n # Return the sorted result in ascending order\n return sorted(max_k_elements)", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n\n Example 1:\n\n Input: arr = [-3, -4, 5], k = 3\n Output: [-4, -3, 5]\n\n Example 2:\n\n Input: arr = [4, -4, 4], k = 2\n Output: [4, 4]\n\n Example 3:\n\n Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1\n Output: [2]\n\n Note:\n 1. The length of the array will be in the range of [1, 1000].\n 2. The elements in the array will be in the range of [-1000, 1000].\n 3. 0 <= k <= len(arr)\n \"\"\"\n if k == 0:\n return []\n \n # Use sorted to get the k largest elements\n largest_k_elements = sorted(arr, reverse=True)[:k]\n \n # Return the sorted list of the largest k elements\n return sorted(largest_k_elements)", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n\n Example 1:\n\n Input: arr = [-3, -4, 5], k = 3\n Output: [-4, -3, 5]\n\n Example 2:\n\n Input: arr = [4, -4, 4], k = 2\n Output: [4, 4]\n\n Example 3:\n\n Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1\n Output: [2]\n\n Note:\n 1. The length of the array will be in the range of [1, 1000].\n 2. The elements in the array will be in the range of [-1000, 1000].\n 3. 0 <= k <= len(arr)\n \"\"\"\n # Sort the array in descending order and get the first k elements\n max_k_elements = sorted(arr, reverse=True)[:k]\n # Sort the result in ascending order before returning\n return sorted(max_k_elements)", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n\n Example 1:\n Input: arr = [-3, -4, 5], k = 3\n Output: [-4, -3, 5]\n\n Example 2:\n Input: arr = [4, -4, 4], k = 2\n Output: [4, 4]\n\n Example 3:\n Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1\n Output: [2]\n\n Note:\n 1. The length of the array will be in the range of [1, 1000].\n 2. The elements in the array will be in the range of [-1000, 1000].\n 3. 0 <= k <= len(arr)\n \"\"\"\n # Handle edge case where k is 0\n if k == 0:\n return []\n\n # Sort the array in descending order and pick the top k elements\n max_elements = sorted(arr, reverse=True)[:k]\n \n # Sort the result to return in ascending order\n return sorted(max_elements)", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n\n Example 1:\n\n Input: arr = [-3, -4, 5], k = 3\n Output: [-4, -3, 5]\n\n Example 2:\n\n Input: arr = [4, -4, 4], k = 2\n Output: [4, 4]\n\n Example 3:\n\n Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1\n Output: [2]\n\n Note:\n 1. The length of the array will be in the range of [1, 1000].\n 2. The elements in the array will be in the range of [-1000, 1000].\n 3. 0 <= k <= len(arr)\n \"\"\"\n # Sort the array in descending order\n sorted_arr = sorted(arr, reverse=True)\n \n # Get the first k elements\n max_k_elements = sorted_arr[:k]\n \n # Return the list sorted in ascending order\n return sorted(max_k_elements)", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n\n Example 1:\n\n Input: arr = [-3, -4, 5], k = 3\n Output: [-4, -3, 5]\n\n Example 2:\n\n Input: arr = [4, -4, 4], k = 2\n Output: [4, 4]\n\n Example 3:\n\n Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1\n Output: [2]\n\n Note:\n 1. The length of the array will be in the range of [1, 1000].\n 2. The elements in the array will be in the range of [-1000, 1000].\n 3. 0 <= k <= len(arr)\n \"\"\"\n if k == 0:\n return []\n\n # Sort the array in descending order and take the first k elements\n max_elements = sorted(arr, reverse=True)[:k]\n \n # Return the sorted list of those k elements in ascending order\n return sorted(max_elements)", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n\n Example 1:\n Input: arr = [-3, -4, 5], k = 3\n Output: [-4, -3, 5]\n\n Example 2:\n Input: arr = [4, -4, 4], k = 2\n Output: [4, 4]\n\n Example 3:\n Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1\n Output: [2]\n\n Note:\n 1. The length of the array will be in the range of [1, 1000].\n 2. The elements in the array will be in the range of [-1000, 1000].\n 3. 0 <= k <= len(arr)\n \"\"\"\n # Step 1: Sort the array in descending order\n sorted_arr = sorted(arr, reverse=True)\n \n # Step 2: Get the first k elements (the maximum k numbers)\n max_k_numbers = sorted_arr[:k]\n \n # Step 3: Sort the result in ascending order to meet the output requirement\n return sorted(max_k_numbers)", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n\n Example 1:\n\n Input: arr = [-3, -4, 5], k = 3\n Output: [-4, -3, 5]\n\n Example 2:\n\n Input: arr = [4, -4, 4], k = 2\n Output: [4, 4]\n\n Example 3:\n\n Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1\n Output: [2]\n\n Note:\n 1. The length of the array will be in the range of [1, 1000].\n 2. The elements in the array will be in the range of [-1000, 1000].\n 3. 0 <= k <= len(arr)\n \"\"\"\n # Step 1: Sort the array in descending order\n sorted_arr = sorted(arr, reverse=True)\n \n # Step 2: Select the top k elements\n top_k_elements = sorted_arr[:k]\n \n # Step 3: Sort the result in ascending order for the final output\n return sorted(top_k_elements)", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n\n Example 1:\n\n Input: arr = [-3, -4, 5], k = 3\n Output: [-4, -3, 5]\n\n Example 2:\n\n Input: arr = [4, -4, 4], k = 2\n Output: [4, 4]\n\n Example 3:\n\n Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1\n Output: [2]\n\n Note:\n 1. The length of the array will be in the range of [1, 1000].\n 2. The elements in the array will be in the range of [-1000, 1000].\n 3. 0 <= k <= len(arr)\n \"\"\"\n # Sort the array in descending order\n sorted_arr = sorted(arr, reverse=True)\n # Get the top k elements\n top_k = sorted_arr[:k]\n # Sort the top k elements in ascending order for the final output\n return sorted(top_k)", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n\n Example 1:\n\n Input: arr = [-3, -4, 5], k = 3\n Output: [-4, -3, 5]\n\n Example 2:\n\n Input: arr = [4, -4, 4], k = 2\n Output: [4, 4]\n\n Example 3:\n\n Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1\n Output: [2]\n\n Note:\n 1. The length of the array will be in the range of [1, 1000].\n 2. The elements in the array will be in the range of [-1000, 1000].\n 3. 0 <= k <= len(arr)\n \"\"\"\n \n # Step 1: Sort the array in descending order\n sorted_arr = sorted(arr, reverse=True)\n \n # Step 2: Select the top k elements\n top_k_elements = sorted_arr[:k]\n \n # Step 3: Sort the selected top k elements in ascending order\n return sorted(top_k_elements)", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n\n Example 1:\n\n Input: arr = [-3, -4, 5], k = 3\n Output: [-4, -3, 5]\n\n Example 2:\n\n Input: arr = [4, -4, 4], k = 2\n Output: [4, 4]\n\n Example 3:\n\n Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1\n Output: [2]\n\n Note:\n 1. The length of the array will be in the range of [1, 1000].\n 2. The elements in the array will be in the range of [-1000, 1000].\n 3. 0 <= k <= len(arr)\n \"\"\"\n # Sort the array in descending order to get the maximum elements\n sorted_arr = sorted(arr, reverse=True)\n # Select the first k elements from the sorted array\n max_elements = sorted_arr[:k]\n # Return the selected elements sorted in ascending order\n return sorted(max_elements)", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n\n Example 1:\n Input: arr = [-3, -4, 5], k = 3\n Output: [-4, -3, 5]\n\n Example 2:\n Input: arr = [4, -4, 4], k = 2\n Output: [4, 4]\n\n Example 3:\n Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1\n Output: [2]\n\n Note:\n 1. The length of the array will be in the range of [1, 1000].\n 2. The elements in the array will be in the range of [-1000, 1000].\n 3. 0 <= k <= len(arr)\n \"\"\"\n # Sort the array in descending order\n sorted_arr = sorted(arr, reverse=True)\n # Get the top k elements\n top_k_elements = sorted_arr[:k]\n # Sort the result in ascending order\n return sorted(top_k_elements)", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n\n Example 1:\n Input: arr = [-3, -4, 5], k = 3\n Output: [-4, -3, 5]\n\n Example 2:\n Input: arr = [4, -4, 4], k = 2\n Output: [4, 4]\n\n Example 3:\n Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1\n Output: [2]\n\n Note:\n 1. The length of the array will be in the range of [1, 1000].\n 2. The elements in the array will be in the range of [-1000, 1000].\n 3. 0 <= k <= len(arr)\n \"\"\"\n # Sort the array in descending order to get the largest elements first\n sorted_arr = sorted(arr, reverse=True)\n \n # Slice the first k elements (the largest k elements)\n max_k_elements = sorted_arr[:k]\n \n # Return the sorted list of those k elements in ascending order\n return sorted(max_k_elements)", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n\n Example 1:\n\n Input: arr = [-3, -4, 5], k = 3\n Output: [-4, -3, 5]\n\n Example 2:\n\n Input: arr = [4, -4, 4], k = 2\n Output: [4, 4]\n\n Example 3:\n\n Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1\n Output: [2]\n\n Note:\n 1. The length of the array will be in the range of [1, 1000].\n 2. The elements in the array will be in the range of [-1000, 1000].\n 3. 0 <= k <= len(arr)\n \"\"\"\n # Sort the array in descending order and get the first k elements\n max_k_elements = sorted(arr, reverse=True)[:k]\n # Return the sorted list of k maximum elements\n return sorted(max_k_elements)", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n\n Example 1:\n Input: arr = [-3, -4, 5], k = 3\n Output: [-4, -3, 5]\n\n Example 2:\n Input: arr = [4, -4, 4], k = 2\n Output: [4, 4]\n\n Example 3:\n Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1\n Output: [2]\n\n Note:\n 1. The length of the array will be in the range of [1, 1000].\n 2. The elements in the array will be in the range of [-1000, 1000].\n 3. 0 <= k <= len(arr)\n \"\"\"\n # Sort the array in descending order to get the largest elements first\n sorted_arr = sorted(arr, reverse=True)\n # Take the first k elements and sort them in ascending order\n return sorted(sorted_arr[:k])", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n\n Example 1:\n\n Input: arr = [-3, -4, 5], k = 3\n Output: [-4, -3, 5]\n\n Example 2:\n\n Input: arr = [4, -4, 4], k = 2\n Output: [4, 4]\n\n Example 3:\n\n Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1\n Output: [2]\n\n Note:\n 1. The length of the array will be in the range of [1, 1000].\n 2. The elements in the array will be in the range of [-1000, 1000].\n 3. 0 <= k <= len(arr)\n \"\"\"\n # Sort the array in descending order to get the largest numbers\n sorted_arr = sorted(arr, reverse=True)\n # Get the top k elements and sort them in ascending order\n max_k_elements = sorted(sorted_arr[:k])\n return max_k_elements", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n\n Example 1:\n\n Input: arr = [-3, -4, 5], k = 3\n Output: [-4, -3, 5]\n\n Example 2:\n\n Input: arr = [4, -4, 4], k = 2\n Output: [4, 4]\n\n Example 3:\n\n Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1\n Output: [2]\n\n Note:\n 1. The length of the array will be in the range of [1, 1000].\n 2. The elements in the array will be in the range of [-1000, 1000].\n 3. 0 <= k <= len(arr)\n \"\"\"\n if k == 0:\n return []\n \n # Sort the array in descending order and take the first k elements\n max_elements = sorted(arr, reverse=True)[:k]\n \n # Sort the selected elements in ascending order before returning\n return sorted(max_elements)", "matching_cluster_idx": 6}]}, "HumanEval/121": {"dps": 91.74887892376681, "dps_norm": 70.0, "pass@1": 100.0, "profiled": [{"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n\n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n return sum(lst[i] for i in range(0, len(lst), 2) if lst[i] % 2 != 0)", "matching_cluster_idx": 4}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n # Initialize sum\n total_sum = 0\n \n # Iterate over the list and check even index positions\n for index in range(0, len(lst), 2): # Step by 2 to get even indices\n if lst[index] % 2 != 0: # Check if the number is odd\n total_sum += lst[index] # Add to total_sum\n \n return total_sum", "matching_cluster_idx": 4}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n Even positions in a zero-indexed list are positions 0, 2, 4, etc.\n\n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n return sum(lst[i] for i in range(0, len(lst), 2) if lst[i] % 2 != 0)", "matching_cluster_idx": 4}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n Examples:\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n return sum(lst[i] for i in range(0, len(lst), 2) if lst[i] % 2 != 0)", "matching_cluster_idx": 4}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n\n Args:\n lst (list): A non-empty list of integers.\n\n Returns:\n int: The sum of odd elements in even positions.\n\n Examples:\n >>> solution([5, 8, 7, 1])\n 12\n >>> solution([3, 3, 3, 3, 3])\n 9\n >>> solution([30, 13, 24, 321])\n 0\n \"\"\"\n return sum(lst[i] for i in range(0, len(lst), 2) if lst[i] % 2 != 0)", "matching_cluster_idx": 4}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n # Sum the odd elements at even indices\n return sum(lst[i] for i in range(0, len(lst), 2) if lst[i] % 2 != 0)", "matching_cluster_idx": 4}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n Args:\n lst (list of int): A non-empty list of integers.\n\n Returns:\n int: The sum of odd elements at even positions.\n\n Examples:\n >>> solution([5, 8, 7, 1])\n 12\n >>> solution([3, 3, 3, 3, 3])\n 9\n >>> solution([30, 13, 24, 321])\n 0\n \"\"\"\n return sum(lst[i] for i in range(0, len(lst), 2) if lst[i] % 2 != 0)", "matching_cluster_idx": 4}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n An even position is defined as indices 0, 2, 4, etc.\n \n Examples:\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n return sum(lst[i] for i in range(0, len(lst), 2) if lst[i] % 2 != 0)", "matching_cluster_idx": 4}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n Args:\n lst (list): A list of integers.\n\n Returns:\n int: The sum of odd elements at even positions in the list.\n\n Examples:\n solution([5, 8, 7, 1]) => 12\n solution([3, 3, 3, 3, 3]) => 9\n solution([30, 13, 24, 321]) => 0\n \"\"\"\n total_sum = 0\n for i in range(0, len(lst), 2): # Iterate over even indices\n if lst[i] % 2 != 0: # Check if the element is odd\n total_sum += lst[i]\n return total_sum", "matching_cluster_idx": 4}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n\n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n # Initialize the sum variable\n total_sum = 0\n \n # Iterate through the list with index\n for index in range(len(lst)):\n # Check if the index is even and the element at that index is odd\n if index % 2 == 0 and lst[index] % 2 != 0:\n total_sum += lst[index]\n \n return total_sum", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n return sum(lst[i] for i in range(0, len(lst), 2) if lst[i] % 2 != 0)", "matching_cluster_idx": 4}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n\n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n # Sum of odd elements at even indices\n return sum(lst[i] for i in range(0, len(lst), 2) if lst[i] % 2 != 0)", "matching_cluster_idx": 4}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n return sum(lst[i] for i in range(0, len(lst), 2) if lst[i] % 2 != 0)", "matching_cluster_idx": 4}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n Arguments:\n lst -- list of integers\n\n Examples:\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n return sum(lst[i] for i in range(0, len(lst), 2) if lst[i] % 2 != 0)", "matching_cluster_idx": 4}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n return sum(num for i, num in enumerate(lst) if i % 2 == 0 and num % 2 != 0)", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n An element's position is considered even if its index is even (0-based indexing).\n \n Examples:\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n return sum(lst[i] for i in range(0, len(lst), 2) if lst[i] % 2 != 0)", "matching_cluster_idx": 4}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n return sum(lst[i] for i in range(0, len(lst), 2) if lst[i] % 2 != 0)", "matching_cluster_idx": 4}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n Args:\n lst (list): A list of integers.\n \n Returns:\n int: The sum of odd elements in even positions.\n \n Examples:\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n return sum(lst[i] for i in range(0, len(lst), 2) if lst[i] % 2 != 0)", "matching_cluster_idx": 4}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n Args:\n lst (list): A list of integers.\n \n Returns:\n int: The sum of odd elements at even indices.\n \n Examples:\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n return sum(lst[i] for i in range(0, len(lst), 2) if lst[i] % 2 != 0)", "matching_cluster_idx": 4}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n Args:\n lst: A list of integers.\n \n Returns:\n An integer representing the sum of odd elements at even indices.\n \n Examples:\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n return sum(lst[i] for i in range(0, len(lst), 2) if lst[i] % 2 != 0)", "matching_cluster_idx": 4}]}, "HumanEval/149": {"dps": 85.82677165354332, "dps_norm": 57.142857142857146, "pass@1": 100.0, "profiled": [{"solution": "def sorted_list_sum(lst):\n \"\"\"Deletes strings with odd lengths from the list and returns a sorted list.\n \n Args:\n lst: A list of strings.\n \n Returns:\n A list of strings that have even lengths, sorted first by length and then alphabetically.\n \"\"\"\n # Filter out strings with odd lengths\n filtered_lst = [word for word in lst if len(word) % 2 == 0]\n \n # Sort the list first by length, then alphabetically\n sorted_lst = sorted(filtered_lst, key=lambda x: (len(x), x))\n \n return sorted_lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"Removes strings with odd lengths from the list and returns\n a sorted list of the remaining strings based on length and then alphabetically.\n \n Args:\n lst (list): A list of strings.\n \n Returns:\n list: A sorted list of strings with even lengths.\n \"\"\"\n # Remove strings with odd lengths\n filtered_lst = [s for s in lst if len(s) % 2 == 0]\n \n # Sort the remaining strings first by length, then alphabetically\n sorted_lst = sorted(filtered_lst, key=lambda x: (len(x), x))\n \n return sorted_lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"Deletes strings with odd lengths and returns a sorted list of remaining strings.\n \n Args:\n lst (list of str): A list of strings.\n \n Returns:\n list of str: A sorted list of strings with even lengths, sorted by length and then alphabetically.\n \"\"\"\n # Filter out strings with odd lengths\n filtered_lst = [s for s in lst if len(s) % 2 == 0]\n \n # Sort the remaining strings first by length and then alphabetically\n sorted_lst = sorted(filtered_lst, key=lambda x: (len(x), x))\n \n return sorted_lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"Accepts a list of strings, removes strings with odd lengths,\n and returns the remaining strings sorted first by length\n and then alphabetically.\n \"\"\"\n # Remove strings with odd lengths\n even_length_strings = [s for s in lst if len(s) % 2 == 0]\n \n # Sort the list first by length and then alphabetically\n sorted_strings = sorted(even_length_strings, key=lambda x: (len(x), x))\n \n return sorted_strings", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"Function that accepts a list of strings, removes those with odd lengths,\n and returns a sorted list based on length and alphabetically.\n \n Args:\n lst (list of str): List of strings to process.\n\n Returns:\n list of str: A sorted list of strings with even lengths.\n \"\"\"\n # Filter out strings with odd lengths\n filtered_list = [s for s in lst if len(s) % 2 == 0]\n \n # Sort the list first by length and then alphabetically\n sorted_list = sorted(filtered_list, key=lambda x: (len(x), x))\n \n return sorted_list", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"Deletes strings with odd lengths from a list, \n then returns the remaining strings sorted by length \n and alphabetically if lengths are the same.\n \n Args:\n lst (list of str): The input list of strings.\n \n Returns:\n list of str: A sorted list of strings with even lengths.\n \"\"\"\n # Filter out strings with odd lengths\n even_length_strings = [s for s in lst if len(s) % 2 == 0]\n \n # Sort the list first by length, then alphabetically\n sorted_strings = sorted(even_length_strings, key=lambda x: (len(x), x))\n \n return sorted_strings", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"Accepts a list of strings, deletes the strings with odd lengths,\n and returns the resulting list sorted by length and alphabetically.\n \"\"\"\n # Remove strings with odd lengths\n filtered_list = [s for s in lst if len(s) % 2 == 0]\n \n # Sort by length first, then alphabetically\n sorted_list = sorted(filtered_list, key=lambda x: (len(x), x))\n \n return sorted_list", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"Removes strings of odd lengths from the list and returns the remaining strings sorted \n first by length and then alphabetically if lengths are the same.\n \n Args:\n lst (list): A list of strings.\n \n Returns:\n list: A sorted list of strings with even lengths.\n \"\"\"\n # Filter out strings with odd lengths\n filtered_lst = [s for s in lst if len(s) % 2 == 0]\n \n # Sort the filtered list first by length, then alphabetically\n sorted_lst = sorted(filtered_lst, key=lambda x: (len(x), x))\n \n return sorted_lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"Filters out strings with odd lengths from the list, sorts the remaining strings first by length\n and then alphabetically, and returns the sorted list.\n \n Args:\n lst (list of str): A list of strings.\n \n Returns:\n list of str: A sorted list of strings with even lengths.\n \"\"\"\n # Remove strings with odd lengths\n filtered_lst = [s for s in lst if len(s) % 2 == 0]\n \n # Sort by length and then alphabetically\n sorted_lst = sorted(filtered_lst, key=lambda x: (len(x), x))\n \n return sorted_lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"Deletes strings with odd lengths and returns the remaining strings sorted\n by length (ascending) and alphabetically.\n\n Args:\n lst (list of str): A list of strings.\n\n Returns:\n list of str: A sorted list of strings with even lengths.\n \"\"\"\n # Filter out strings with odd lengths\n filtered_list = [s for s in lst if len(s) % 2 == 0]\n\n # Sort by length first, then alphabetically\n sorted_list = sorted(filtered_list, key=lambda s: (len(s), s))\n\n return sorted_list", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"Filter out strings with odd lengths and return a sorted list\n of the remaining strings by length and alphabetically.\n \n Parameters:\n lst (list): A list of strings.\n \n Returns:\n list: A sorted list of strings with even lengths.\n \"\"\"\n # Filter out strings with odd lengths\n filtered_list = [word for word in lst if len(word) % 2 == 0]\n \n # Sort the list by length and then alphabetically\n sorted_list = sorted(filtered_list, key=lambda x: (len(x), x))\n \n return sorted_list", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"Accepts a list of strings, deletes strings with odd lengths,\n and returns the list sorted by length and then alphabetically.\n \n Args:\n lst (list): A list of strings.\n\n Returns:\n list: A sorted list of strings with even lengths.\n \"\"\"\n \n # Filter out strings with odd lengths\n even_length_strings = [s for s in lst if len(s) % 2 == 0]\n \n # Sort by length first, then alphabetically\n sorted_strings = sorted(even_length_strings, key=lambda x: (len(x), x))\n \n return sorted_strings", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"Remove strings with odd lengths from the list, \n and return the resulting list sorted by length and then alphabetically.\n \n Args:\n lst (list): A list of strings.\n \n Returns:\n list: A sorted list of strings with even lengths.\n \"\"\"\n # Remove strings with odd lengths\n filtered_lst = [s for s in lst if len(s) % 2 == 0]\n \n # Sort the list first by length, then alphabetically\n sorted_lst = sorted(filtered_lst, key=lambda x: (len(x), x))\n \n return sorted_lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"Remove strings with odd lengths from the list and return a sorted list.\n \n Args:\n lst (list of str): A list of strings.\n\n Returns:\n list of str: A sorted list of strings with even lengths.\n \"\"\"\n # Filter out strings with odd lengths\n even_length_strings = [s for s in lst if len(s) % 2 == 0]\n \n # Sort first by length, then alphabetically\n sorted_strings = sorted(even_length_strings, key=lambda x: (len(x), x))\n \n return sorted_strings", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"Accepts a list of strings, removes strings with odd lengths, \n and returns the remaining strings sorted first by length and then alphabetically.\n \n Args:\n lst (list): A list of strings.\n \n Returns:\n list: A list of strings sorted by length and alphabetically.\n \"\"\"\n # Remove strings with odd lengths\n filtered_lst = [s for s in lst if len(s) % 2 == 0]\n \n # Sort the list first by length and then alphabetically\n sorted_lst = sorted(filtered_lst, key=lambda x: (len(x), x))\n \n return sorted_lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"Deletes strings with odd lengths from the list and returns a sorted list.\n \n Args:\n lst (list of str): A list of strings.\n \n Returns:\n list of str: A sorted list of strings with even lengths.\n \"\"\"\n # Filter out strings with odd lengths\n even_length_strings = [s for s in lst if len(s) % 2 == 0]\n \n # Sort the list first by length, then alphabetically\n sorted_strings = sorted(even_length_strings, key=lambda s: (len(s), s))\n \n return sorted_strings", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"Removes strings with odd lengths from the list and returns the remaining\n strings sorted first by length and then alphabetically.\n\n Args:\n lst (list of str): A list of strings.\n\n Returns:\n list of str: A sorted list of strings with even lengths.\n \"\"\"\n # Filter out strings with odd lengths\n filtered_list = [s for s in lst if len(s) % 2 == 0]\n\n # Sort the filtered list by length and then alphabetically\n sorted_list = sorted(filtered_list, key=lambda x: (len(x), x))\n\n return sorted_list", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"Filter out strings with odd lengths and return a sorted list.\n \n Args:\n lst (list): A list of strings.\n \n Returns:\n list: A list of strings filtered and sorted by length and alphabetically.\n \"\"\"\n # Step 1: Filter out strings with odd lengths\n filtered_lst = [s for s in lst if len(s) % 2 == 0]\n \n # Step 2: Sort the filtered list first by length, then alphabetically\n sorted_lst = sorted(filtered_lst, key=lambda x: (len(x), x))\n \n return sorted_lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"Accepts a list of strings, removes those with odd lengths, \n and returns the remaining strings sorted by length and alphabetically.\"\"\"\n \n # Remove strings with odd lengths\n filtered_list = [s for s in lst if len(s) % 2 == 0]\n \n # Sort the remaining strings first by length, then alphabetically\n sorted_list = sorted(filtered_list, key=lambda x: (len(x), x))\n \n return sorted_list", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"Accepts a list of strings, deletes strings with odd lengths,\n and returns the remaining strings sorted by length and then alphabetically.\n \n Args:\n lst (list of str): A list of strings.\n \n Returns:\n list of str: A sorted list of strings with even lengths.\n \"\"\"\n # Filter out strings with odd lengths\n filtered_lst = [s for s in lst if len(s) % 2 == 0]\n \n # Sort the filtered list by length and then alphabetically\n sorted_lst = sorted(filtered_lst, key=lambda x: (len(x), x))\n \n return sorted_lst", "matching_cluster_idx": 3}]}, "Mbpp/3": {"dps": 58.13559322033898, "dps_norm": 76.25, "pass@1": 100.0, "profiled": [{"solution": "def is_not_prime(n):\n \"\"\"\n Determine if a number is non-prime.\n \n A number is considered non-prime if it is less than 2, or if it is \n divisible by any number other than 1 and itself.\n \n Parameters:\n n (int): The number to check.\n \n Returns:\n bool: True if the number is non-prime, False otherwise.\n \"\"\"\n if n < 2:\n return True\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return True\n return False", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(n):\n \"\"\"Returns True if n is not a prime number, otherwise False.\"\"\"\n if n <= 1:\n return True # 0 and 1 are not prime\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return True # n is divisible by some number other than 1 and itself\n return False # n is prime", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(n):\n \"\"\"\n Check if a number is non-prime.\n \n Parameters:\n n (int): The number to check\n \n Returns:\n bool: True if n is non-prime, False if n is prime\n \"\"\"\n if n < 2:\n return True # 0 and 1 are considered non-prime\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return True # Found a divisor, so n is non-prime\n return False # No divisors found, so n is prime", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(n):\n \"\"\"\n Check if a number is not prime.\n\n Parameters:\n n (int): The number to check.\n\n Returns:\n bool: True if the number is not prime, False if it is prime.\n \"\"\"\n if n <= 1:\n return True # 0 and 1 are not prime numbers\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return True # Found a divisor, so n is not prime\n return False # No divisors found, so n is prime", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(n):\n \"\"\"\n Returns True if n is not a prime number, otherwise returns False.\n \n A prime number is defined as a number greater than 1 that has no positive \n divisors other than 1 and itself. Therefore, any number less than 2 or any \n even number greater than 2 is not prime.\n \"\"\"\n if n < 2:\n return True # 0 and 1 are not prime\n if n == 2:\n return False # 2 is prime\n if n % 2 == 0:\n return True # all even numbers greater than 2 are not prime\n \n # Check for factors from 3 to the square root of n\n for i in range(3, int(n**0.5) + 1, 2):\n if n % i == 0:\n return True # Found a factor, so not prime\n return False # No factors found, so it is prime", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n \"\"\"Return True if n is not a prime number, otherwise False.\"\"\"\n if n <= 1:\n return True # 0 and 1 are not prime numbers\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return True # Found a divisor, so n is not prime\n return False # No divisors found, so n is prime", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(n):\n \"\"\"Return True if n is not a prime number, False otherwise.\"\"\"\n if n <= 1:\n return True # 0 and 1 are not prime numbers\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return True # n is divisible by some number other than 1 and itself, hence not prime\n return False # n is prime", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(n):\n \"\"\"Return True if n is not a prime number, otherwise False.\"\"\"\n if n <= 1:\n return True\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return True\n return False", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(n):\n \"\"\"\n Check if a number is not a prime number.\n \n A prime number is a natural number greater than 1 \n that cannot be formed by multiplying two smaller natural numbers.\n Therefore, non-prime numbers are either less than 2 \n or can be divided by some number other than 1 and itself.\n \n Args:\n n (int): The number to check.\n\n Returns:\n bool: True if the number is not prime, False if it is prime.\n \"\"\"\n if n < 2:\n return True # Numbers less than 2 are not prime\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return True # Found a divisor, so it's not prime\n return False # No divisors found, it's prime", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(n):\n \"\"\"Return True if n is not a prime number, False if it is prime.\"\"\"\n if n <= 1:\n return True # 0 and 1 are not prime numbers\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return True # n is divisible by i, hence not prime\n return False # n is prime", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(n):\n \"\"\"Check if a number is non-prime.\n\n Args:\n n (int): The number to check.\n\n Returns:\n bool: True if the number is non-prime, False if it is prime.\n \"\"\"\n if n <= 1:\n return True # Numbers 0 and 1 are considered non-prime\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return True # Found a divisor, so n is non-prime\n return False # No divisors found, so n is prime", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(n):\n \"\"\"\n Function to identify non-prime numbers.\n Returns True if n is non-prime (including 0 and 1), False if it is prime.\n \"\"\"\n if n <= 1: # 0 and 1 are not prime numbers\n return True\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return True # n is divisible by i, hence it's not prime\n return False # n is prime", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(n):\n \"\"\"Return True if n is not a prime number, otherwise False.\"\"\"\n if n <= 1: # 0 and 1 are not prime numbers\n return True\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return True # Found a divisor, hence not prime\n return False # No divisors found, hence prime", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(n):\n \"\"\"\n Function to determine if a number is not a prime number.\n \n Parameters:\n n (int): The number to check.\n \n Returns:\n bool: True if the number is not prime, False if it is prime.\n \"\"\"\n if n <= 1:\n return True # 0 and 1 are not prime numbers\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return True # n is divisible by some number other than 1 and itself\n return False # n is prime", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(n):\n \"\"\"\n Function to determine if a number is non-prime.\n \n Parameters:\n n (int): The number to check.\n \n Returns:\n bool: True if the number is non-prime, False otherwise.\n \"\"\"\n if n < 2:\n return True # 0 and 1 are not prime numbers\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return True # n is divisible by i, hence not prime\n return False # n is prime", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(n):\n \"\"\"\n Check if a number is not prime.\n \n Args:\n n (int): The number to check.\n \n Returns:\n bool: True if the number is not prime, False otherwise.\n \"\"\"\n if n <= 1:\n return True # 0 and 1 are not prime numbers\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return True # Found a divisor, hence not prime\n return False # No divisors found, hence prime", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(n):\n \"\"\"\n Function to determine if a number is non-prime.\n \n A number is considered non-prime if it is less than 2 or if it has \n any divisors other than 1 and itself.\n \n Args:\n n (int): The number to check.\n \n Returns:\n bool: True if the number is non-prime, False if it is prime.\n \"\"\"\n if n < 2:\n return True\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return True\n return False", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(n):\n \"\"\"\n Check if a number is not a prime.\n \n Parameters:\n n (int): The number to check.\n \n Returns:\n bool: True if n is not prime, False if n is prime.\n \"\"\"\n if n <= 1:\n return True # 0 and 1 are not prime numbers\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return True # n is divisible by i, hence not prime\n return False # n is prime", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(n):\n \"\"\"Return True if n is a non-prime number, otherwise False.\"\"\"\n if n <= 1:\n return True # 0 and 1 are not prime\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return True # n is divisible by a number other than 1 and itself\n return False # n is prime", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(n):\n \"\"\"\n Returns True if the number is non-prime, False otherwise.\n \n Parameters:\n n (int): The number to check.\n\n Returns:\n bool: True if non-prime, False if prime.\n \"\"\"\n if n <= 1:\n return True # 0 and 1 are not prime numbers\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return True # n is divisible by i, thus it is non-prime\n return False # n is prime", "matching_cluster_idx": 5}]}, "Mbpp/4": {"dps": 91.51877133105802, "dps_norm": 82.91666666666666, "pass@1": 100.0, "profiled": [{"solution": "import heapq\ndef heap_queue_largest(numbers, n):\n \"\"\"\n Find the n largest integers from a given list of numbers, returned in descending order.\n \n Parameters:\n numbers (list): A list of integers.\n n (int): The number of largest integers to find.\n\n Returns:\n list: A list of the n largest integers in descending order.\n \"\"\"\n # Use heapq to find the n largest numbers\n return sorted(heapq.nlargest(n, numbers), reverse=True)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(numbers, n):\n \"\"\"\n Find the n largest integers from a given list of numbers, returned in descending order.\n \n :param numbers: List of integers\n :param n: Number of largest integers to return\n :return: List of n largest integers in descending order\n \"\"\"\n return sorted(heapq.nlargest(n, numbers), reverse=True)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(numbers, n):\n \"\"\"\n Find the n largest integers from a given list of numbers, returned in descending order.\n\n :param numbers: List of integers\n :param n: Number of largest integers to find\n :return: List of the n largest integers in descending order\n \"\"\"\n if n <= 0:\n return []\n return sorted(heapq.nlargest(n, numbers), reverse=True)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n \"\"\"\n Find the n largest integers from a given list of numbers and return them in descending order.\n \n :param nums: List of integers\n :param n: Number of largest integers to find\n :return: List of the n largest integers in descending order\n \"\"\"\n if n <= 0:\n return []\n return sorted(heapq.nlargest(n, nums), reverse=True)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(numbers, n):\n \"\"\"\n Find the n largest integers from a given list of numbers, returned in descending order.\n \n Args:\n numbers (list): A list of integers.\n n (int): The number of largest integers to return.\n \n Returns:\n list: A list of the n largest integers in descending order.\n \"\"\"\n # Use heapq to find the n largest elements\n largest_numbers = heapq.nlargest(n, numbers)\n # Return them sorted in descending order\n return sorted(largest_numbers, reverse=True)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n \"\"\"\n Find the n largest integers from the given list of numbers,\n returned in descending order.\n \n :param nums: List of numbers\n :param n: Number of largest integers to find\n :return: List of n largest integers in descending order\n \"\"\"\n # Use heapq to find the n largest numbers\n return heapq.nlargest(n, nums)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(numbers, n):\n \"\"\"\n Find the n largest integers from a given list of numbers, returned in descending order.\n\n :param numbers: List of integers\n :param n: Number of largest integers to return\n :return: List of the n largest integers in descending order\n \"\"\"\n # Use heapq.nlargest to find the n largest numbers\n largest_numbers = heapq.nlargest(n, numbers)\n # Return them in descending order\n return largest_numbers", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(numbers, n):\n \"\"\"\n Find the n largest integers from a given list of numbers in descending order.\n\n :param numbers: List of integers.\n :param n: The number of largest integers to find.\n :return: A list of the n largest integers in descending order.\n \"\"\"\n return sorted(heapq.nlargest(n, numbers), reverse=True)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(numbers, n):\n \"\"\"\n Find the n largest integers from a given list of numbers, returned in descending order.\n \n :param numbers: List of integers.\n :param n: The number of largest integers to return.\n :return: A list of the n largest integers in descending order.\n \"\"\"\n # Use heapq to get the n largest elements\n largest_numbers = heapq.nlargest(n, numbers)\n # Sort the result in descending order\n return sorted(largest_numbers, reverse=True)", "matching_cluster_idx": 8}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n \"\"\"Return the n largest integers from a given list of numbers in descending order.\"\"\"\n return sorted(heapq.nlargest(n, nums), reverse=True)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(numbers, n):\n \"\"\"\n Find the n largest integers from a given list of numbers in descending order.\n \n Parameters:\n numbers (list): A list of integers.\n n (int): The number of largest integers to find.\n \n Returns:\n list: A list of the n largest integers in descending order.\n \"\"\"\n # Use heapq.nlargest to find the n largest elements\n largest_numbers = heapq.nlargest(n, numbers)\n # Sort the largest numbers in descending order\n return sorted(largest_numbers, reverse=True)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(numbers, n):\n \"\"\"Find the n largest integers from a list of numbers, returned in descending order.\"\"\"\n return heapq.nlargest(n, numbers)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(numbers, n):\n \"\"\"\n Find the n largest integers from a given list of numbers, returned in descending order.\n\n :param numbers: List of integers\n :param n: Number of largest integers to return\n :return: List of n largest integers in descending order\n \"\"\"\n return sorted(heapq.nlargest(n, numbers), reverse=True)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(numbers, n):\n \"\"\"\n Find the n largest integers from a given list of numbers, returned in descending order.\n\n Parameters:\n numbers (list): A list of integers.\n n (int): The number of largest integers to find.\n\n Returns:\n list: A list of the n largest integers in descending order.\n \"\"\"\n if n <= 0:\n return []\n if n > len(numbers):\n return sorted(numbers, reverse=True) # if n is larger than the list, return the sorted list\n\n # Use heapq to find the n largest elements\n largest_numbers = heapq.nlargest(n, numbers)\n \n return sorted(largest_numbers, reverse=True)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n \"\"\"\n Find the n largest integers from the given list of numbers in descending order.\n\n Args:\n nums (list): A list of integers.\n n (int): The number of largest integers to find.\n\n Returns:\n list: A list of the n largest integers in descending order.\n \"\"\"\n # Use heapq to find the n largest elements, then sort them in descending order\n return sorted(heapq.nlargest(n, nums), reverse=True)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(numbers, n):\n \"\"\"\n Find the n largest integers from a given list of numbers, returned in descending order.\n\n Parameters:\n numbers (list): A list of integers.\n n (int): The number of largest integers to find.\n\n Returns:\n list: A list containing the n largest integers in descending order.\n \"\"\"\n # Use heapq.nlargest to find the n largest numbers\n largest_numbers = heapq.nlargest(n, numbers)\n \n # Sort the largest numbers in descending order\n largest_numbers.sort(reverse=True)\n \n return largest_numbers", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n \"\"\"\n Find the n largest integers from a given list of numbers, returned in descending order.\n\n :param nums: List of integers\n :param n: The number of largest integers to find\n :return: A list of the n largest integers in descending order\n \"\"\"\n # Use heapq to find the n largest numbers\n largest_numbers = heapq.nlargest(n, nums)\n return largest_numbers", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(numbers, n):\n \"\"\"\n Find the n largest integers from the given list of numbers, returned in descending order.\n \n :param numbers: List of integers\n :param n: Number of largest integers to return\n :return: List of n largest integers in descending order\n \"\"\"\n if n <= 0:\n return []\n \n # Use heapq to find the n largest elements and then sort them in descending order\n largest_numbers = heapq.nlargest(n, numbers)\n return sorted(largest_numbers, reverse=True)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(numbers, n):\n \"\"\"\n Find the n largest integers from a given list of numbers, returned in descending order.\n \n :param numbers: List of integers\n :param n: Number of largest integers to find\n :return: List of n largest integers in descending order\n \"\"\"\n return heapq.nlargest(n, numbers)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(numbers, n):\n \"\"\"Find the n largest integers from the list of numbers, returned in descending order.\"\"\"\n if n <= 0:\n return []\n # Use heapq to find the n largest elements\n return sorted(heapq.nlargest(n, numbers), reverse=True)", "matching_cluster_idx": 9}]}, "Mbpp/9": {"dps": 59.795918367346935, "dps_norm": 53.0, "pass@1": 55.0, "profiled": [{"solution": "def find_Rotations(s: str) -> int:\n \"\"\"\n This function finds the minimum number of rotations (greater than 0) \n required to get the same string.\n \n Args:\n s (str): The input string to be rotated.\n \n Returns:\n int: The minimum number of rotations greater than 0.\n \"\"\"\n length = len(s)\n \n # Create a doubled string to check for rotations\n doubled_s = s + s\n \n # Check for the original string in the doubled string\n for i in range(1, length): # starting from 1 to ensure the rotation is greater than 0\n if doubled_s[i:i + length] == s:\n return i\n \n return length # In case all rotations have been checked, return the length", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(s):\n if not s:\n return 0\n \n n = len(s)\n # To find the minimum rotations, we can concatenate the string with itself\n double_s = s + s\n # We find the first occurrence of the original string in the doubled string\n index = double_s.find(s, 1) # Start looking after the first character\n \n if index == -1:\n return n # If not found, the only rotation is the string itself\n else:\n return index", "matching_cluster_idx": 7}, {"solution": "def find_Rotations(s: str) -> int:\n # If the string is empty or has only one character, return 1\n if len(s) <= 1:\n return 1\n \n # Length of the string\n n = len(s)\n \n # Check rotations\n for i in range(1, n):\n # Create the rotated version of the string\n rotated = s[i:] + s[:i]\n if rotated == s:\n return i # Return the number of rotations\n \n return n # If no earlier match, it takes n rotations to return to original", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(s):\n # Get the length of the string\n n = len(s)\n \n # If the string is empty or has only one character, return 0\n if n <= 1:\n return 0\n \n # To find the minimum rotations, we'll check rotations\n # We can find the rotations by concatenating the string to itself\n # and checking for the original string in the doubled string\n doubled_s = s + s\n \n # We check each possible rotation from 1 to n-1\n for i in range(1, n):\n if doubled_s[i:i+n] == s:\n return i\n \n # If no valid rotation is found, return n (complete rotation)\n return n", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(s: str) -> int:\n \"\"\"\n Finds the minimum number of rotations required to get the same string.\n \n :param s: The input string\n :return: The minimum number of rotations greater than 0\n \"\"\"\n n = len(s)\n # Check for trivial case\n if n == 0:\n return 0\n \n # Create a double string\n double_s = s + s\n \n # Loop through the possible rotations\n for i in range(1, n):\n if double_s[i:i+n] == s:\n return i\n \n return n # In case the string is unique (like \"abcd\")", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(s: str) -> int:\n n = len(s)\n # Check if the string is empty or has a single character\n if n <= 1:\n return 0\n \n # Generate all rotations of the string\n for i in range(1, n):\n if s[i:] + s[:i] == s:\n return i\n return n # If no rotation is found, the entire length is needed", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(s: str) -> int:\n \"\"\"\n This function finds the minimum number of rotations required to get the same string.\n \n :param s: A string for which we need to find the minimum number of rotations.\n :return: Minimum number of rotations greater than 0 to obtain the same string.\n \"\"\"\n n = len(s)\n \n # Edge case: If the string is empty, we return 0\n if n == 0:\n return 0\n \n # Check for repeated characters\n if s.count(s[0]) == n:\n return 1\n \n # Find the minimum rotations needed\n for i in range(1, n):\n # Create rotated string\n rotated = s[i:] + s[:i]\n if rotated == s:\n return i\n \n return n # This should never be reached for a valid input.", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(s):\n \"\"\"\n This function returns the minimum number of rotations (greater than 0) required\n to get the same string as input.\n\n Args:\n s (str): The input string.\n\n Returns:\n int: The minimum number of rotations needed to return to the original string.\n \"\"\"\n # Get the length of the string\n n = len(s)\n \n # If the string is empty, there are no rotations needed\n if n == 0:\n return 0\n \n # A string can return to itself after a number of rotations equal to its length\n # Check all possible rotation lengths\n for i in range(1, n + 1):\n if s[i:] + s[:i] == s:\n return i\n\n return n # In the worst case, n rotations are needed, which won't happen for the test case \"aaaa\"", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(s: str) -> int:\n \"\"\"\n Find the minimum number of rotations (greater than 0) required to get the same string.\n \n :param s: The input string\n :return: The minimum number of rotations required\n \"\"\"\n length = len(s)\n # Check for any rotations\n for i in range(1, length + 1):\n rotated = s[i:] + s[:i]\n if rotated == s:\n return i\n return length # This line should not be reached for non-empty strings", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(s: str) -> int:\n \"\"\"\n This function finds the minimum number of rotations required to\n return to the original string.\n \n :param s: The input string.\n :return: The minimum number of rotations (greater than 0).\n \"\"\"\n n = len(s)\n for i in range(1, n + 1):\n # Create a rotated version of the string\n rotated = s[i % n:] + s[:i % n]\n if rotated == s:\n return i\n return n # In case of all unique characters, would return n, which is not valid here.", "matching_cluster_idx": 3}, {"solution": "def find_Rotations(s: str) -> int:\n \"\"\"\n This function finds the minimum number of rotations greater than 0 \n required to get the same string.\n \n Args:\n s (str): The input string to evaluate.\n \n Returns:\n int: The minimum number of rotations required.\n \"\"\"\n n = len(s)\n \n # Check if the string is empty or has only one unique character\n if n == 0 or len(set(s)) == 1:\n return 1\n \n # Check for the minimum rotations\n for i in range(1, n):\n if s[i:] + s[:i] == s:\n return i\n \n return n # If no rotation yields the original string, return n.", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(s):\n \"\"\"\n Find the minimum number of rotations (greater than 0) required to get the same string.\n\n :param s: The input string\n :return: The minimum number of rotations required\n \"\"\"\n n = len(s)\n if n == 0:\n return 0 # No rotation needed for an empty string\n \n for i in range(1, n):\n # Generate the rotated version of the string\n rotated = s[i:] + s[:i]\n if rotated == s:\n return i # Return the rotation count\n\n return n # If not found, return n (the length of the string)", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(s: str) -> int:\n \"\"\"\n This function finds the minimum number of rotations required to get the same string.\n \n Args:\n s (str): The input string to check for rotations.\n \n Returns:\n int: Minimum number of rotations required to get the same string.\n \"\"\"\n # A string can be rotated n times where n is the length of the string\n n = len(s)\n \n # Check for rotations starting from 1 to n\n for i in range(1, n + 1):\n rotated = s[i:] + s[:i]\n if rotated == s:\n return i # Return the number of rotations\n\n return n # If no rotation matches, return the length of the string", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(s: str) -> int:\n \"\"\"\n Find the minimum number of rotations (greater than 0) required to get the same string.\n\n Parameters:\n s (str): The input string.\n\n Returns:\n int: The minimum number of rotations required.\n \"\"\"\n n = len(s)\n if n == 0:\n return 0 # Return 0 for empty string\n\n # Loop to check all rotations\n for i in range(1, n):\n if s[i:] + s[:i] == s:\n return i # Return the number of rotations\n\n return n # If no rotation found, return n (full rotation)", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(s: str) -> int:\n # Check if the string is empty or has only one unique character\n if len(s) == 0 or len(set(s)) == 1:\n return 1\n \n # The length of the string\n n = len(s)\n \n # Loop through each rotation\n for i in range(1, n):\n # Rotate the string\n rotated = s[i:] + s[:i]\n # Check if the rotated string is equal to the original\n if rotated == s:\n return i\n \n return n # If no rotation matches, the number of rotations is equal to length of string", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(s):\n \"\"\"\n Find the minimum number of rotations (greater than 0) required to get the same string.\n \n :param s: The input string\n :return: The minimum number of rotations needed\n \"\"\"\n n = len(s)\n \n if n == 0:\n return 0\n \n # Check for all possible rotations\n for i in range(1, n + 1):\n if s[i:] + s[:i] == s:\n return i\n \n return n # In case of no rotations found (should not occur for non-empty strings)", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(s):\n if not s:\n return 0 # Early return for empty string\n \n n = len(s)\n doubled_s = s + s # Concatenate the string with itself\n\n # Iterate through possible rotations\n for i in range(1, n): # We start from 1 to avoid the original string\n if doubled_s[i:i+n] == s:\n return i # Return the number of rotations\n\n return n # In case the string is all the same characters, return n", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(s: str) -> int:\n \"\"\"\n This function finds the minimum number of rotations (greater than 0) required \n to get the same string.\n \n :param s: Input string\n :return: Minimum number of rotations required\n \"\"\"\n n = len(s)\n \n # A string can rotate at most n times, but we are looking for\n # the smallest rotation that returns the string to its original form\n for i in range(1, n + 1): # Starting from 1 to n\n if s[i % n:] + s[:i % n] == s:\n return i\n \n return n # In case no rotation matches, return n (this shouldn't happen)", "matching_cluster_idx": 3}, {"solution": "def find_Rotations(s: str) -> int:\n \"\"\"\n This function calculates the minimum number of rotations\n required to get the same string. The function assumes the input\n string s consists of only lowercase letters.\n \n Parameters:\n s (str): The input string to analyze.\n \n Returns:\n int: The minimum number of rotations (greater than 0) to get\n the same string.\n \"\"\"\n length = len(s)\n \n # Edge case: if the string is empty or has only one character\n if length <= 1:\n return 1\n \n # Concatenate the string with itself to check for rotations\n double_s = s + s\n \n # Check each rotation\n for i in range(1, length + 1): # Start from 1 to length\n if double_s[i:i + length] == s:\n return i\n \n return length # If no match found, return the length of the string", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(s: str) -> int:\n \"\"\"\n Find the minimum number of rotations (greater than 0) required to get the same string.\n \n Args:\n s (str): The input string.\n\n Returns:\n int: The minimum number of rotations required.\n \"\"\"\n n = len(s)\n \n # Check if the string is empty or has a single character\n if n <= 1:\n return 1\n \n # Check for all possible rotations\n for i in range(1, n):\n # Create the rotated string\n rotated = s[i:] + s[:i]\n if rotated == s:\n return i\n \n # If no rotation yields the original string, return n (full rotation)\n return n", "matching_cluster_idx": 4}]}, "Mbpp/11": {"dps": 43.369175627240146, "dps_norm": 90.0, "pass@1": 43.0, "profiled": [{"solution": "def remove_Occ(s: str, char: str) -> str:\n \"\"\"\n Remove the first and last occurrence of a specified character from the string.\n \n Parameters:\n s (str): The input string.\n char (str): The character to remove.\n \n Returns:\n str: The modified string with the first and last occurrences of char removed.\n \"\"\"\n # Find the first occurrence of the character\n first_index = s.find(char)\n # Find the last occurrence of the character\n last_index = s.rfind(char)\n \n # If the character does not exist in the string, return the string as is\n if first_index == -1:\n return s\n \n # If the first and last indices are the same, it means there's only one occurrence\n if first_index == last_index:\n return s[:first_index] + s[first_index + 1:]\n \n # Remove the first occurrence\n s = s[:first_index] + s[first_index + 1:]\n # Adjust the last index since we modified the string\n last_index -= 1\n # Remove the last occurrence\n return s[:last_index] + s[last_index + 1:]", "matching_cluster_idx": 7}, {"solution": "def remove_Occ(s, char):\n # Find the first occurrence of the character\n first_index = s.find(char)\n # Find the last occurrence of the character\n last_index = s.rfind(char)\n \n # If the character is not found or only one occurrence is found\n if first_index == -1 or first_index == last_index:\n return s.replace(char, \"\", 1) # Remove just the first occurrence if there's only one\n\n # Remove the first occurrence\n s = s[:first_index] + s[first_index + 1:]\n # Adjust the last index since the string length has changed\n last_index -= 1 # Adjust because we removed one character\n \n # Remove the last occurrence\n s = s[:last_index] + s[last_index + 1:]\n \n return s", "matching_cluster_idx": 7}, {"solution": "def remove_Occ(s: str, char: str) -> str:\n \"\"\"\n Remove the first and last occurrence of the given character from the string.\n\n :param s: The input string\n :param char: The character to be removed\n :return: The modified string with first and last occurrence of char removed\n \"\"\"\n # Find the first occurrence of the character\n first_index = s.find(char)\n # Find the last occurrence of the character\n last_index = s.rfind(char)\n \n # If the character is not found or found at the same index\n if first_index == -1 or first_index == last_index:\n return s.replace(char, '', 1) if first_index != -1 else s\n\n # Remove the character at the first index\n s = s[:first_index] + s[first_index+1:]\n # Adjust last index because of the previous removal\n last_index -= 1 # Shift left due to the removal\n \n # Remove the character at the last index\n s = s[:last_index] + s[last_index+1:]\n\n return s", "matching_cluster_idx": 7}, {"solution": "def remove_Occ(string: str, char: str) -> str:\n \"\"\"\n Remove the first and last occurrence of a given character from the string.\n \n Parameters:\n string (str): The input string from which to remove characters.\n char (str): The character to remove.\n\n Returns:\n str: The modified string with the first and last occurrence of the character removed.\n \"\"\"\n # Find the first occurrence of the character\n first_occurrence = string.find(char)\n \n # If character is not found, return the original string\n if first_occurrence == -1:\n return string\n \n # Find the last occurrence of the character\n last_occurrence = string.rfind(char)\n \n # If first and last occurrence are the same, remove it once\n if first_occurrence == last_occurrence:\n return string[:first_occurrence] + string[first_occurrence + 1:]\n \n # Remove the first occurrence\n string = string[:first_occurrence] + string[first_occurrence + 1:]\n \n # Remove the last occurrence (after removing the first occurrence)\n last_occurrence -= 1 # Adjust the index because the string length has changed\n string = string[:last_occurrence] + string[last_occurrence + 1:]\n \n return string", "matching_cluster_idx": 7}, {"solution": "def remove_Occ(s, char):\n first_index = s.find(char)\n last_index = s.rfind(char)\n\n # If the character does not occur or occurs only once\n if first_index == -1 or first_index == last_index:\n return s.replace(char, \"\", 1)\n\n # Remove first occurrence\n s = s[:first_index] + s[first_index + 1:]\n\n # Adjust last_index because the string has changed\n last_index -= 1 # since we have removed one character, last_index needs to be decremented\n return s[:last_index] + s[last_index + 1:]", "matching_cluster_idx": 7}, {"solution": "def remove_Occ(s: str, char: str) -> str:\n \"\"\"Remove the first and last occurrence of the specified character from the string.\"\"\"\n first_index = s.find(char)\n last_index = s.rfind(char)\n\n # If the character is not found or both occurrences are the same, return the string without that character\n if first_index == -1 or first_index == last_index:\n return s.replace(char, '', 1) # Remove first occurrence only if it exists\n\n # Remove first occurrence\n s = s[:first_index] + s[first_index + 1:]\n\n # Adjust last_index since the string has changed\n if last_index > first_index: # Ensure we are not removing the same index\n last_index -= 1 # Update the last_index because we've shortened the string\n\n # Remove last occurrence\n s = s[:last_index] + s[last_index + 1:]\n\n return s", "matching_cluster_idx": 7}, {"solution": "def remove_Occ(s: str, char: str) -> str:\n \"\"\"\n Remove the first and last occurrence of a given character from the string.\n \n Parameters:\n s (str): The input string.\n char (str): The character to remove.\n\n Returns:\n str: The modified string with the first and last occurrence of char removed.\n \"\"\"\n # Check if the character is in the string\n if char in s:\n # Remove the first occurrence\n s = s.replace(char, '', 1)\n # Remove the last occurrence\n s = s[::-1].replace(char, '', 1)[::-1]\n return s", "matching_cluster_idx": 4}, {"solution": "def remove_Occ(s, char):\n \"\"\"\n Remove the first and last occurrence of a given character from the string.\n\n :param s: The original string\n :param char: The character to remove\n :return: The modified string with first and last occurrence of char removed\n \"\"\"\n first_index = s.find(char)\n last_index = s.rfind(char)\n\n # If the character is not found or only one occurrence exists\n if first_index == -1 or first_index == last_index:\n return s.replace(char, '', 1)\n\n # Remove the first occurrence\n s = s[:first_index] + s[first_index + 1:]\n\n # Adjust the last index because the string has been modified\n last_index -= 1 # Account for the removal of the first occurrence\n\n # Remove the last occurrence\n s = s[:last_index] + s[last_index + 1:]\n\n return s", "matching_cluster_idx": 7}, {"solution": "def remove_Occ(s: str, char: str) -> str:\n # Find the first occurrence of the character\n first_index = s.find(char)\n # Find the last occurrence of the character\n last_index = s.rfind(char)\n \n # If the character is not found or if it's the same for first and last occurrence\n if first_index == -1 or first_index == last_index:\n return s.replace(char, '', 1) # remove only the first occurrence\n \n # Remove the first occurrence\n s = s[:first_index] + s[first_index + 1:]\n # Remove the last occurrence\n s = s[:last_index - 1] + s[last_index:] # Adjust last_index because of previous removal\n \n return s", "matching_cluster_idx": 7}, {"solution": "def remove_Occ(s, char):\n \"\"\"\n Remove the first and last occurrence of the given character from the string.\n\n Parameters:\n s (str): The input string from which to remove characters.\n char (str): The character to remove.\n\n Returns:\n str: The modified string with the first and last occurrence of char removed.\n \"\"\"\n first_occurrence = s.find(char)\n last_occurrence = s.rfind(char)\n\n if first_occurrence == -1: # Character not found\n return s\n\n if first_occurrence == last_occurrence: # Character occurs only once\n return s[:first_occurrence] + s[first_occurrence + 1:]\n\n # Remove the first and last occurrence\n return s[:first_occurrence] + s[first_occurrence + 1:last_occurrence] + s[last_occurrence + 1:]", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(s: str, char: str) -> str:\n \"\"\"\n Remove the first and last occurrence of the specified character from the string.\n\n Parameters:\n s (str): The input string.\n char (str): The character to remove.\n\n Returns:\n str: The modified string with the first and last occurrence of the character removed.\n \"\"\"\n first_index = s.find(char)\n last_index = s.rfind(char)\n\n # If the character occurs at least once, process the removal\n if first_index != -1:\n # Remove the first occurrence\n s = s[:first_index] + s[first_index + 1:]\n\n if last_index != -1 and last_index != first_index:\n # Remove the last occurrence (adjusting for the removed first character)\n s = s[:last_index - 1] + s[last_index:]\n\n return s", "matching_cluster_idx": 7}, {"solution": "def remove_Occ(s: str, char: str) -> str:\n \"\"\"\n Remove the first and last occurrence of a given character from the string.\n\n :param s: The input string.\n :param char: The character to remove.\n :return: A new string with the first and last occurrence of the character removed.\n \"\"\"\n # Find the index of the first occurrence of the character\n first_index = s.find(char)\n \n # If the character is not found, return the string as is\n if first_index == -1:\n return s\n \n # Find the index of the last occurrence of the character\n last_index = s.rfind(char)\n \n # If the first and last index are the same, remove that one occurrence\n if first_index == last_index:\n return s[:first_index] + s[first_index + 1:]\n \n # Create a new string by omitting the character at the first and last index\n return s[:first_index] + s[first_index + 1:last_index] + s[last_index + 1:]", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(s, char):\n \"\"\"\n Remove the first and last occurrence of the specified character from the string.\n \n Parameters:\n s (str): The input string.\n char (str): The character to be removed.\n\n Returns:\n str: The modified string with the first and last occurrence of char removed.\n \"\"\"\n first_index = s.find(char) # Find the first occurrence of the character\n last_index = s.rfind(char) # Find the last occurrence of the character\n\n if first_index == -1: # If the character is not found\n return s\n if first_index == last_index: # If there is only one occurrence\n return s[:first_index] + s[first_index + 1:]\n\n # Construct the new string without the first and last occurrence\n new_string = s[:first_index] + s[first_index + 1:last_index] + s[last_index + 1:]\n return new_string", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(s, char):\n \"\"\"\n Remove the first and last occurrence of a given character from the string.\n \n Parameters:\n s (str): The input string.\n char (str): The character to remove.\n\n Returns:\n str: The modified string with the first and last occurrence of char removed.\n \"\"\"\n # Find the first and last occurrence of the character\n first_index = s.find(char)\n last_index = s.rfind(char)\n \n # If the character is found at least twice, remove the occurrences\n if first_index != -1 and first_index != last_index:\n return s[:first_index] + s[first_index + 1:last_index] + s[last_index + 1:]\n elif first_index != -1: # If only one occurrence is found\n return s[:first_index] + s[first_index + 1:]\n else: # If the character is not found\n return s", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(s, char):\n \"\"\"\n Remove the first and last occurrence of a given character from the string.\n \n Args:\n s (str): The input string from which to remove the character.\n char (str): The character to remove from the string.\n \n Returns:\n str: The modified string with the first and last occurrences of the character removed.\n \"\"\"\n # Find the first occurrence of the character\n first_index = s.find(char)\n \n # If the character is not found, return the original string\n if first_index == -1:\n return s\n \n # Find the last occurrence of the character\n last_index = s.rfind(char)\n \n # If the first and last index are the same, it means there's only one occurrence\n if first_index == last_index:\n return s[:first_index] + s[first_index + 1:]\n \n # Remove the first and last occurrences\n return s[:first_index] + s[first_index + 1:last_index] + s[last_index + 1:]", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(s, char):\n \"\"\"\n Remove the first and last occurrence of a given character from the string.\n\n :param s: The input string\n :param char: The character to remove from the string\n :return: The modified string with the first and last occurrence of char removed\n \"\"\"\n first_index = s.find(char)\n last_index = s.rfind(char)\n \n # If the character is not found or if both occurrences are the same, remove only one\n if first_index == -1:\n return s # Character not found, return original string\n elif first_index == last_index:\n return s[:first_index] + s[first_index + 1:] # Only one occurrence, remove it\n\n # Remove first occurrence\n s = s[:first_index] + s[first_index + 1:]\n # Remove last occurrence (recalculate index since the string has changed)\n last_index = s.rfind(char)\n if last_index != -1:\n s = s[:last_index] + s[last_index + 1:]\n\n return s", "matching_cluster_idx": 7}, {"solution": "def remove_Occ(s, char):\n \"\"\"\n Remove the first and last occurrence of a given character from the string.\n \n :param s: The input string\n :param char: The character to be removed\n :return: A new string with the first and last occurrences of char removed\n \"\"\"\n first_occurrence = s.find(char)\n last_occurrence = s.rfind(char)\n \n # If the character does not occur in the string or occurs only once\n if first_occurrence == -1 or first_occurrence == last_occurrence:\n return s.replace(char, '', 1) # Remove the only occurrence if exists\n \n # Remove first occurrence\n s = s[:first_occurrence] + s[first_occurrence + 1:]\n \n # Remove last occurrence (after first is removed, adjust index)\n last_occurrence -= 1 # Adjust index since we removed the first occurrence\n s = s[:last_occurrence] + s[last_occurrence + 1:]\n \n return s", "matching_cluster_idx": 7}, {"solution": "def remove_Occ(s, char):\n first_index = s.find(char)\n last_index = s.rfind(char)\n \n if first_index == -1: # Character not found\n return s\n \n if first_index == last_index: # Character occurs only once\n return s[:first_index] + s[first_index + 1:]\n \n # Remove first occurrence\n s = s[:first_index] + s[first_index + 1:]\n \n # Adjust last_index since we modified the string\n last_index -= 1\n \n # Remove last occurrence\n s = s[:last_index] + s[last_index + 1:]\n \n return s", "matching_cluster_idx": 7}, {"solution": "def remove_Occ(s, char):\n # Find the first occurrence of the character\n first_index = s.find(char)\n # Find the last occurrence of the character\n last_index = s.rfind(char)\n\n # If the character is not found or both occurrences are the same, return the modified string\n if first_index == -1 or first_index == last_index:\n return s.replace(char, '', 1)\n\n # Remove first occurrence by slicing\n modified_string = s[:first_index] + s[first_index + 1:]\n\n # Remove last occurrence by slicing\n modified_string = modified_string[:last_index - 1] + modified_string[last_index:]\n\n return modified_string", "matching_cluster_idx": 7}, {"solution": "def remove_Occ(s: str, char: str) -> str:\n # Find the first occurrence of the character\n first_index = s.find(char)\n # Find the last occurrence of the character\n last_index = s.rfind(char)\n \n # If the character is not found or if the first and last indices are the same\n if first_index == -1 or first_index == last_index:\n return s.replace(char, '', 1) # Remove only the first occurrence or return original string if not found\n \n # Remove the first occurrence\n s = s[:first_index] + s[first_index + 1:]\n # Adjust the last index since the string length has changed\n last_index -= 1 # Adjust for the removal of the first occurrence\n \n # Remove the last occurrence\n return s[:last_index] + s[last_index + 1:]", "matching_cluster_idx": 7}]}, "Mbpp/12": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def sort_matrix(matrix):\n # Sort the matrix based on the sum of each row\n return sorted(matrix, key=sum)", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"\n Sorts the given matrix in ascending order according to the sum of its rows.\n \n :param matrix: List of lists (matrix) to be sorted\n :return: Sorted matrix\n \"\"\"\n return sorted(matrix, key=sum)", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"\n Sorts the given matrix in ascending order according to the sum of its rows.\n\n Args:\n matrix (list of list of int): The matrix to be sorted.\n\n Returns:\n list of list of int: The sorted matrix.\n \"\"\"\n # Sort the matrix using the sum of each row as the key\n return sorted(matrix, key=sum)", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"\n Sort a given matrix in ascending order according to the sum of its rows.\n\n Parameters:\n matrix (list of list of int): The matrix to be sorted.\n\n Returns:\n list of list of int: The sorted matrix.\n \"\"\"\n return sorted(matrix, key=sum)", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"\n Sorts a given matrix in ascending order according to the sum of its rows.\n\n Parameters:\n matrix (list of list of int): The matrix to sort.\n\n Returns:\n list of list of int: The sorted matrix.\n \"\"\"\n return sorted(matrix, key=sum)", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"\n Sort a given matrix in ascending order according to the sum of its rows.\n\n :param matrix: List of lists where each inner list represents a row in the matrix\n :return: A new matrix sorted by the sum of its rows\n \"\"\"\n # Sort the matrix using the sum of each row as the key\n sorted_matrix = sorted(matrix, key=sum)\n return sorted_matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"\n Sorts a given matrix in ascending order according to the sum of its rows.\n\n Parameters:\n matrix (list of list of int): The matrix to be sorted.\n\n Returns:\n list of list of int: The sorted matrix.\n \"\"\"\n # Sort the matrix using the sum of each row as the key\n return sorted(matrix, key=sum)", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Sort the matrix based on the sum of each row\n return sorted(matrix, key=sum)", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"\n Sorts a given matrix in ascending order according to the sum of its rows.\n\n :param matrix: List of lists (2D list) representing the matrix\n :return: Sorted list of lists based on the sum of each row\n \"\"\"\n return sorted(matrix, key=sum)", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"\n Sorts the given matrix in ascending order according to the sum of its rows.\n \n Args:\n matrix (list of list of int): The matrix to be sorted.\n \n Returns:\n list of list of int: The sorted matrix.\n \"\"\"\n return sorted(matrix, key=sum)", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"\n Sorts a given matrix in ascending order according to the sum of its rows.\n\n Parameters:\n matrix (list of lists of int): A 2D list representing the matrix to be sorted.\n\n Returns:\n list of lists of int: The sorted matrix.\n \"\"\"\n return sorted(matrix, key=sum)", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"\n Sorts a given matrix in ascending order according to the sum of its rows.\n\n Parameters:\n matrix (list of list of int): The matrix to be sorted.\n\n Returns:\n list of list of int: The sorted matrix.\n \"\"\"\n return sorted(matrix, key=sum)", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"\n Sort the given matrix in ascending order according to the sum of its rows.\n\n Args:\n matrix (list of list of int): The matrix to be sorted.\n\n Returns:\n list of list of int: The sorted matrix.\n \"\"\"\n # Sort the matrix using the sum of each row as the key\n return sorted(matrix, key=sum)", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"\n Sorts a given matrix in ascending order according to the sum of its rows.\n\n Parameters:\n matrix (list of list of int): The matrix to be sorted.\n\n Returns:\n list of list of int: The sorted matrix.\n \"\"\"\n # Sort the matrix using the sum of each row as the key\n return sorted(matrix, key=sum)", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"\n Sorts a given matrix in ascending order according to the sum of its rows.\n \n Parameters:\n matrix (list of list of int): A 2D list representing the matrix.\n \n Returns:\n list of list of int: The sorted matrix.\n \"\"\"\n # Sort the matrix based on the sum of each row\n sorted_matrix = sorted(matrix, key=sum)\n return sorted_matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"\n Sort a given matrix in ascending order according to the sum of its rows.\n \n :param matrix: List of lists (2D list) where each inner list represents a row of the matrix.\n :return: The sorted matrix (list of lists).\n \"\"\"\n # Sort the matrix using the sum of each row as the key\n sorted_matrix = sorted(matrix, key=sum)\n return sorted_matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"\n Sorts a given matrix in ascending order according to the sum of its rows.\n\n Args:\n matrix (list of list of int): A 2D list (matrix) to be sorted.\n\n Returns:\n list of list of int: The sorted matrix.\n \"\"\"\n # Sort the matrix using the sum of each row as the key\n return sorted(matrix, key=sum)", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"\n Sorts the given matrix in ascending order according to the sum of its rows.\n\n Args:\n matrix (list of list of int): A 2D list representing the matrix.\n\n Returns:\n list of list of int: The sorted matrix.\n \"\"\"\n return sorted(matrix, key=sum)", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"\n Sorts a given matrix in ascending order according to the sum of its rows.\n\n Parameters:\n matrix (list of list of int): The input matrix to be sorted.\n\n Returns:\n list of list of int: The sorted matrix.\n \"\"\"\n # Sort the matrix using the sum of each row as the key\n return sorted(matrix, key=sum)", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Sort the matrix based on the sum of each row\n return sorted(matrix, key=sum)", "matching_cluster_idx": 15}]}, "Mbpp/16": {"dps": 65.03048780487805, "dps_norm": 76.25, "pass@1": 92.0, "profiled": [{"solution": "def text_lowercase_underscore(s):\n \"\"\"\n This function checks if the input string contains sequences of\n lowercase letters joined with underscores.\n \n :param s: Input string to check\n :return: True if the string consists of lowercase letter sequences \n separated by underscores, False otherwise\n \"\"\"\n # Split the string by underscores and check if each part contains only lowercase letters\n return all(part.islower() and part.isalpha() for part in s.split('_'))", "matching_cluster_idx": 4}, {"solution": "def text_lowercase_underscore(s: str) -> bool:\n \"\"\"\n Returns True if the input string contains sequences of lowercase letters\n joined with an underscore, and False otherwise.\n\n Args:\n s (str): The input string to check.\n\n Returns:\n bool: True if the string contains valid sequences, False otherwise.\n \"\"\"\n # Check if the string matches the pattern of lowercase letters with underscores\n # The pattern allows one or more sequences of lowercase letters separated by underscores\n if all(part.islower() for part in s.split('_')) and all(part for part in s.split('_')):\n return True\n return False", "matching_cluster_idx": 5}, {"solution": "def text_lowercase_underscore(s):\n \"\"\"\n This function returns True if the input string contains\n sequences of lowercase letters joined with an underscore,\n and False otherwise.\n \"\"\"\n # Split the string by underscores\n segments = s.split('_')\n \n # Check if all segments are composed of lowercase letters\n return all(segment.islower() and segment.isalpha() for segment in segments)", "matching_cluster_idx": 5}, {"solution": "def text_lowercase_underscore(s):\n \"\"\"\n Check if the input string contains sequences of lowercase letters joined with underscores.\n \n :param s: Input string\n :return: True if valid format, False otherwise\n \"\"\"\n # Split the string by underscores and check each part\n parts = s.split('_')\n return all(part.isalpha() and part.islower() for part in parts)", "matching_cluster_idx": 5}, {"solution": "def text_lowercase_underscore(s):\n \"\"\"\n Check if the input string contains sequences of lowercase letters\n joined with an underscore.\n \n Args:\n s (str): The input string to check.\n \n Returns:\n bool: True if the string meets the criteria, False otherwise.\n \"\"\"\n # Split the string by underscore and check each part\n parts = s.split('_')\n for part in parts:\n if not part.islower() or not part.isalpha():\n return False\n return True", "matching_cluster_idx": 5}, {"solution": "def text_lowercase_underscore(s):\n # Check if the string matches the pattern: lowercase letters separated by underscores\n import re\n pattern = r'^[a-z]+(_[a-z]+)*$'\n return bool(re.match(pattern, s))", "matching_cluster_idx": 6}, {"solution": "def text_lowercase_underscore(s):\n \"\"\"\n This function checks if the input string consists of sequences of \n lowercase letters joined by an underscore.\n \n Args:\n s (str): The input string to check.\n\n Returns:\n bool: True if the string matches the pattern, False otherwise.\n \"\"\"\n # Check if the string matches the pattern of lowercase letters joined by underscores\n return all(part.isalpha() and part.islower() for part in s.split('_'))", "matching_cluster_idx": 5}, {"solution": "def text_lowercase_underscore(s):\n \"\"\"\n Check if the input string contains sequences of lowercase letters joined with underscores.\n\n Args:\n s (str): The input string to check.\n\n Returns:\n bool: True if the string contains only lowercase letters and underscores, False otherwise.\n \"\"\"\n # Split the string by underscores and check each part\n parts = s.split('_')\n return all(part.isalpha() and part.islower() for part in parts)", "matching_cluster_idx": 5}, {"solution": "def text_lowercase_underscore(s):\n \"\"\"\n Check if the input string contains sequences of lowercase letters joined with an underscore.\n \n Args:\n s (str): The input string to check.\n \n Returns:\n bool: True if the string matches the criteria, False otherwise.\n \"\"\"\n # Split the string by underscores and check each segment\n segments = s.split('_')\n return all(segment.isalpha() and segment.islower() for segment in segments)", "matching_cluster_idx": 5}, {"solution": "def text_lowercase_underscore(s):\n # Check if the string matches the pattern of lowercase letters separated by underscores\n return all(part.isalpha() and part.islower() for part in s.split('_'))", "matching_cluster_idx": 5}, {"solution": "def text_lowercase_underscore(s):\n \"\"\"\n Check if the input string contains sequences of lowercase letters joined with an underscore.\n \n Args:\n s (str): The input string to check.\n \n Returns:\n bool: True if the string matches the criteria, False otherwise.\n \"\"\"\n # Check if the string matches the pattern: lowercase letters separated by underscores\n import re\n pattern = r'^[a-z]+(_[a-z]+)*$' # Pattern to match sequences of lowercase letters joined by underscores\n return bool(re.match(pattern, s))", "matching_cluster_idx": 6}, {"solution": "def text_lowercase_underscore(s):\n \"\"\"\n Check if the input string contains sequences of lowercase letters joined with an underscore.\n \n Args:\n s (str): The input string to check.\n \n Returns:\n bool: True if the string follows the pattern, False otherwise.\n \"\"\"\n # Check if the string matches the pattern of lowercase letters joined by underscores\n return all(part.islower() for part in s.split('_'))", "matching_cluster_idx": 5}, {"solution": "def text_lowercase_underscore(s):\n \"\"\"\n This function checks if the input string contains sequences of lowercase letters\n joined with an underscore.\n \n Args:\n s (str): The input string to check.\n \n Returns:\n bool: True if the string matches the pattern, False otherwise.\n \"\"\"\n # Split the string by underscore and check if all parts are lowercase letters\n parts = s.split('_')\n return all(part.islower() and part.isalpha() for part in parts)", "matching_cluster_idx": 5}, {"solution": "def text_lowercase_underscore(s):\n \"\"\"\n Check if the input string contains sequences of lowercase letters joined with an underscore.\n\n Args:\n s (str): The input string to check.\n\n Returns:\n bool: True if the string follows the pattern, False otherwise.\n \"\"\"\n # Split the string by underscores\n parts = s.split('_')\n \n # Check if all parts are lowercase letters\n return all(part.isalpha() and part.islower() for part in parts)", "matching_cluster_idx": 5}, {"solution": "def text_lowercase_underscore(s):\n \"\"\"\n Check if the input string contains sequences of lowercase letters\n joined with an underscore.\n\n Args:\n s (str): The input string.\n\n Returns:\n bool: True if the string contains valid sequences, False otherwise.\n \"\"\"\n # Split the string by underscores and check each segment\n segments = s.split('_')\n for segment in segments:\n # Check if each segment is made up of lowercase letters\n if not segment.isalpha() or not segment.islower():\n return False\n return True", "matching_cluster_idx": 5}, {"solution": "def text_lowercase_underscore(s):\n \"\"\"\n Returns True if the input string contains sequences of lowercase letters\n joined with an underscore and False otherwise.\n \n Args:\n s (str): The input string to check.\n\n Returns:\n bool: True if the string meets the criteria, False otherwise.\n \"\"\"\n # Split the string by underscores\n parts = s.split('_')\n # Check if all parts are non-empty and consist of lowercase letters\n return all(part.isalpha() and part.islower() for part in parts)", "matching_cluster_idx": 5}, {"solution": "def text_lowercase_underscore(s):\n \"\"\"\n Check if the input string contains sequences of lowercase letters \n joined with an underscore.\n\n Parameters:\n s (str): The input string.\n\n Returns:\n bool: True if the string matches the pattern, False otherwise.\n \"\"\"\n # Use regular expression to match the pattern\n import re\n pattern = r'^[a-z]+(_[a-z]+)*$'\n return bool(re.match(pattern, s))", "matching_cluster_idx": 6}, {"solution": "def text_lowercase_underscore(s):\n \"\"\"\n Returns True if the input string contains sequences of lowercase letters\n joined with underscores, and False otherwise.\n \"\"\"\n # Split the string by underscores and check each segment\n segments = s.split('_')\n return all(segment.isalpha() and segment.islower() for segment in segments)", "matching_cluster_idx": 5}, {"solution": "def text_lowercase_underscore(s):\n \"\"\"\n Check if the input string contains sequences of lowercase letters\n joined with an underscore.\n\n Args:\n s (str): The input string to check.\n\n Returns:\n bool: True if the string matches the pattern, False otherwise.\n \"\"\"\n # Split the string by underscores\n parts = s.split('_')\n \n # Check if all parts are composed of lowercase letters\n return all(part.islower() and part.isalpha() for part in parts)", "matching_cluster_idx": 5}, {"solution": "def text_lowercase_underscore(s):\n # Split the string by underscores\n parts = s.split('_')\n # Check if all parts are non-empty and contain only lowercase letters\n return all(part.islower() and part.isalpha() for part in parts)", "matching_cluster_idx": 5}]}, "Mbpp/19": {"dps": 91.16161616161617, "dps_norm": 95.0, "pass@1": 100.0, "profiled": [{"solution": "def test_duplicate(arr):\n \"\"\"\n This function checks if there are any duplicate elements in the given array.\n \n :param arr: List of integers\n :return: True if duplicates are found, False otherwise\n \"\"\"\n seen = set()\n for num in arr:\n if num in seen:\n return True\n seen.add(num)\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(arr):\n \"\"\"\n Checks if the array contains any duplicate elements.\n\n Parameters:\n arr (list): List of integers to check for duplicates.\n\n Returns:\n bool: True if there are duplicates, False otherwise.\n \"\"\"\n return len(arr) != len(set(arr))", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(arr):\n \"\"\"\n Function to determine if there are any duplicate elements in an array.\n \n Parameters:\n arr (list): List of integers to check for duplicates.\n \n Returns:\n bool: True if duplicates are found, False otherwise.\n \"\"\"\n seen = set()\n for num in arr:\n if num in seen:\n return True\n seen.add(num)\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(arr):\n \"\"\"\n This function checks if there are any duplicate elements in the given array.\n \n :param arr: List of integers\n :return: True if duplicates are found, otherwise False\n \"\"\"\n seen = set()\n for number in arr:\n if number in seen:\n return True # Duplicate found\n seen.add(number)\n return False # No duplicates", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(arr):\n \"\"\"\n Function to determine if the array contains any duplicate elements.\n\n Parameters:\n arr (list): A list of integers.\n\n Returns:\n bool: True if there are duplicates, False otherwise.\n \"\"\"\n seen = set()\n for num in arr:\n if num in seen:\n return True\n seen.add(num)\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(arr):\n \"\"\"\n This function checks if there are any duplicate elements in the given array.\n \n :param arr: List of integers\n :return: True if duplicates are found, False otherwise\n \"\"\"\n seen = set()\n for num in arr:\n if num in seen:\n return True # Duplicate found\n seen.add(num)\n return False # No duplicates found", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(arr):\n \"\"\"\n Check if the given array contains any duplicate elements.\n \n Parameters:\n arr (list): A list of integers.\n \n Returns:\n bool: True if duplicates are found, False otherwise.\n \"\"\"\n seen = set()\n for num in arr:\n if num in seen:\n return True\n seen.add(num)\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(arr):\n \"\"\"\n Check if the given array contains any duplicate elements.\n\n :param arr: List of integers\n :return: True if duplicates exist, False otherwise\n \"\"\"\n seen = set()\n for num in arr:\n if num in seen:\n return True # Duplicate found\n seen.add(num)\n return False # No duplicates found", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(arr):\n \"\"\"Check if the array contains any duplicate elements.\"\"\"\n seen = set()\n for num in arr:\n if num in seen:\n return True # Found a duplicate\n seen.add(num)\n return False # No duplicates found", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(arr):\n \"\"\"\n Function to determine if there are any duplicate elements in the given array.\n \n Parameters:\n arr (list): A list of integers to check for duplicates.\n \n Returns:\n bool: True if duplicates are found, False otherwise.\n \"\"\"\n return len(arr) != len(set(arr))", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(arr):\n \"\"\"\n Checks if there are any duplicate elements in the given array.\n\n Parameters:\n arr (list): A list of integers.\n\n Returns:\n bool: True if duplicates exist, False otherwise.\n \"\"\"\n # Use a set to track seen elements\n seen = set()\n \n for number in arr:\n if number in seen:\n return True # Duplicate found\n seen.add(number)\n \n return False # No duplicates found", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(arr):\n \"\"\"\n Function to determine if there are any duplicate elements in the given array.\n \n Args:\n arr (list of int): The array to check for duplicates.\n \n Returns:\n bool: True if duplicates are found, False otherwise.\n \"\"\"\n seen = set()\n for number in arr:\n if number in seen:\n return True\n seen.add(number)\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(arr):\n \"\"\"\n This function checks if there are any duplicate elements in the given array.\n \n :param arr: List of integers\n :return: True if there are duplicates, False otherwise\n \"\"\"\n # Create a set to track seen elements\n seen = set()\n \n # Iterate through each element in the array\n for number in arr:\n # If the number is already in the set, we found a duplicate\n if number in seen:\n return True\n # Add the number to the set\n seen.add(number)\n \n # No duplicates found\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(arr):\n \"\"\"\n Function to determine if there are any duplicate elements in the given array.\n \n Parameters:\n arr (list): A list of integers to check for duplicates.\n\n Returns:\n bool: True if there are duplicates, False otherwise.\n \"\"\"\n return len(arr) != len(set(arr))", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(arr):\n \"\"\"\n Function to determine if there are any duplicate elements in the array.\n \n :param arr: List of integers\n :return: True if duplicates are found, otherwise False\n \"\"\"\n seen = set() # Create a set to keep track of seen elements\n for number in arr:\n if number in seen:\n return True # Duplicate found\n seen.add(number) # Add number to the set if not seen\n return False # No duplicates found", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(arr):\n \"\"\"\n Check if the array contains any duplicate elements.\n\n Parameters:\n arr (list): A list of integers.\n\n Returns:\n bool: True if there are duplicates, False otherwise.\n \"\"\"\n seen = set()\n for num in arr:\n if num in seen:\n return True # Duplicate found\n seen.add(num)\n return False # No duplicates found", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(arr):\n \"\"\"\n Check if the given array contains any duplicate elements.\n\n :param arr: List of integers\n :return: True if there are duplicates, False otherwise\n \"\"\"\n return len(arr) != len(set(arr))", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(arr):\n \"\"\"\n Function to check if there are any duplicate elements in the given array.\n \n Args:\n arr (list): List of integers.\n \n Returns:\n bool: True if there are duplicates, False otherwise.\n \"\"\"\n return len(arr) != len(set(arr))", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(arr):\n \"\"\"\n Check if the input array contains any duplicate elements.\n\n :param arr: List of integers\n :return: True if duplicates are found, False otherwise\n \"\"\"\n # Use a set to track seen elements\n seen = set()\n \n for num in arr:\n if num in seen:\n return True # Duplicate found\n seen.add(num)\n \n return False # No duplicates", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(arr):\n \"\"\"\n Function to check if the array contains any duplicate elements.\n \n Parameters:\n arr (list): List of integers to check for duplicates.\n \n Returns:\n bool: True if duplicates are found, False otherwise.\n \"\"\"\n # Use a set to track seen elements\n seen = set()\n for num in arr:\n if num in seen:\n return True # Duplicate found\n seen.add(num)\n return False # No duplicates", "matching_cluster_idx": 14}]}, "Mbpp/62": {"dps": 70.0, "dps_norm": 80.0, "pass@1": 100.0, "profiled": [{"solution": "def smallest_num(numbers):\n \"\"\"Return the smallest number in the given list.\"\"\"\n if not numbers:\n raise ValueError(\"The list cannot be empty.\")\n \n smallest = numbers[0]\n for num in numbers:\n if num < smallest:\n smallest = num\n return smallest", "matching_cluster_idx": 3}, {"solution": "def smallest_num(numbers):\n \"\"\"\n This function returns the smallest number in a list.\n \n :param numbers: List of numbers\n :return: The smallest number in the list\n \"\"\"\n if not numbers:\n raise ValueError(\"The list is empty.\")\n \n smallest = numbers[0]\n for number in numbers:\n if number < smallest:\n smallest = number\n return smallest", "matching_cluster_idx": 3}, {"solution": "def smallest_num(numbers):\n \"\"\"Return the smallest number in a list.\"\"\"\n if not numbers:\n raise ValueError(\"The list is empty\")\n smallest = numbers[0]\n for num in numbers:\n if num < smallest:\n smallest = num\n return smallest", "matching_cluster_idx": 3}, {"solution": "def smallest_num(numbers):\n \"\"\"Return the smallest number in a list.\"\"\"\n if not numbers: # Check if the list is empty\n raise ValueError(\"The list should not be empty\")\n \n smallest = numbers[0] # Start with the first element as the smallest\n for number in numbers:\n if number < smallest:\n smallest = number # Update smallest if a smaller number is found\n return smallest", "matching_cluster_idx": 3}, {"solution": "def smallest_num(nums):\n \"\"\"Returns the smallest number in a list.\"\"\"\n if not nums: # Check if the list is empty\n raise ValueError(\"The list cannot be empty\")\n smallest = nums[0] # Start by assuming the first number is the smallest\n for num in nums:\n if num < smallest:\n smallest = num # Update smallest if a smaller number is found\n return smallest", "matching_cluster_idx": 3}, {"solution": "def smallest_num(numbers):\n \"\"\"\n Function to find the smallest number in a list.\n \n Parameters:\n numbers (list): A list of numbers.\n \n Returns:\n int: The smallest number in the list.\n \"\"\"\n if not numbers:\n raise ValueError(\"The list should not be empty.\")\n \n smallest = numbers[0]\n for num in numbers:\n if num < smallest:\n smallest = num\n return smallest", "matching_cluster_idx": 3}, {"solution": "def smallest_num(lst):\n \"\"\"\n Function to find the smallest number in a list.\n \n Parameters:\n lst (list): A list of numbers.\n \n Returns:\n int/float: The smallest number in the list.\n \"\"\"\n if not lst:\n raise ValueError(\"The list cannot be empty\")\n \n smallest = lst[0]\n for num in lst:\n if num < smallest:\n smallest = num\n return smallest", "matching_cluster_idx": 3}, {"solution": "def smallest_num(numbers):\n \"\"\"Returns the smallest number in a list.\"\"\"\n if not numbers: # Check if the list is empty\n raise ValueError(\"The list cannot be empty.\")\n smallest = numbers[0] # Start with the first element\n for number in numbers:\n if number < smallest:\n smallest = number\n return smallest", "matching_cluster_idx": 3}, {"solution": "def smallest_num(numbers):\n \"\"\"Return the smallest number in a list.\"\"\"\n if not numbers:\n raise ValueError(\"The list cannot be empty.\")\n \n smallest = numbers[0] # Start by assuming the first number is the smallest\n for num in numbers:\n if num < smallest:\n smallest = num # Update smallest if a smaller number is found\n return smallest", "matching_cluster_idx": 3}, {"solution": "def smallest_num(lst):\n \"\"\"Return the smallest number in a list.\"\"\"\n if not lst: # Check if the list is empty\n raise ValueError(\"The list cannot be empty.\")\n smallest = lst[0] # Start with the first element as the smallest\n for num in lst:\n if num < smallest: # If the current number is smaller, update smallest\n smallest = num\n return smallest", "matching_cluster_idx": 3}, {"solution": "def smallest_num(numbers):\n \"\"\"Return the smallest number in a list.\"\"\"\n if not numbers:\n raise ValueError(\"The list is empty\")\n smallest = numbers[0]\n for number in numbers:\n if number < smallest:\n smallest = number\n return smallest", "matching_cluster_idx": 3}, {"solution": "def smallest_num(numbers):\n \"\"\"\n Function to find the smallest number in a list.\n\n :param numbers: List of integers\n :return: Smallest integer in the list\n \"\"\"\n if not numbers:\n raise ValueError(\"The list cannot be empty\")\n \n smallest = numbers[0]\n for num in numbers:\n if num < smallest:\n smallest = num\n return smallest", "matching_cluster_idx": 3}, {"solution": "def smallest_num(numbers):\n \"\"\"Return the smallest number from a list of numbers.\"\"\"\n if not numbers: # Check if the list is empty\n raise ValueError(\"The list cannot be empty.\")\n smallest = numbers[0] # Assume the first number is the smallest\n for num in numbers: # Iterate through the list\n if num < smallest: # Compare each number with the current smallest\n smallest = num # Update smallest if a smaller number is found\n return smallest", "matching_cluster_idx": 3}, {"solution": "def smallest_num(numbers):\n \"\"\"Return the smallest number in a list.\"\"\"\n if not numbers:\n raise ValueError(\"The list is empty.\")\n min_num = numbers[0]\n for num in numbers:\n if num < min_num:\n min_num = num\n return min_num", "matching_cluster_idx": 3}, {"solution": "def smallest_num(numbers):\n \"\"\"Return the smallest number in a list.\"\"\"\n if not numbers: # Check if the list is empty\n raise ValueError(\"The list is empty\")\n \n smallest = numbers[0] # Start by assuming the first number is the smallest\n for num in numbers: # Iterate through each number in the list\n if num < smallest: # If we find a smaller number\n smallest = num # Update the smallest number\n return smallest # Return the smallest number found", "matching_cluster_idx": 3}, {"solution": "def smallest_num(numbers):\n \"\"\"Return the smallest number in a list.\"\"\"\n if not numbers: # Check if the list is empty\n raise ValueError(\"The list is empty.\")\n smallest = numbers[0] # Start by assuming the first number is the smallest\n for num in numbers: # Iterate through the list\n if num < smallest: # If we find a smaller number, update smallest\n smallest = num\n return smallest", "matching_cluster_idx": 3}, {"solution": "def smallest_num(numbers):\n \"\"\"Return the smallest number in a given list of numbers.\"\"\"\n if not numbers:\n raise ValueError(\"The list cannot be empty\")\n smallest = numbers[0]\n for num in numbers:\n if num < smallest:\n smallest = num\n return smallest", "matching_cluster_idx": 3}, {"solution": "def smallest_num(numbers):\n \"\"\"Returns the smallest number in a list.\"\"\"\n if not numbers:\n raise ValueError(\"The list cannot be empty.\")\n smallest = numbers[0]\n for num in numbers:\n if num < smallest:\n smallest = num\n return smallest", "matching_cluster_idx": 3}, {"solution": "def smallest_num(numbers):\n \"\"\"Return the smallest number in a list.\"\"\"\n if not numbers:\n raise ValueError(\"The list cannot be empty.\")\n smallest = numbers[0]\n for num in numbers:\n if num < smallest:\n smallest = num\n return smallest", "matching_cluster_idx": 3}, {"solution": "def smallest_num(numbers):\n \"\"\"Return the smallest number in a list.\"\"\"\n if not numbers: # Check if the list is empty\n raise ValueError(\"The list cannot be empty.\")\n smallest = numbers[0] # Assume the first number is the smallest\n for num in numbers: # Iterate through the list\n if num < smallest: # If a smaller number is found\n smallest = num # Update the smallest number\n return smallest", "matching_cluster_idx": 3}]}, "Mbpp/75": {"dps": 92.85714285714286, "dps_norm": 66.66666666666667, "pass@1": 100.0, "profiled": [{"solution": "def find_tuples(tuples_list, k):\n \"\"\"\n This function finds all tuples in the given list where all elements are divisible by k.\n \n :param tuples_list: List of tuples to check.\n :param k: The divisor for checking divisibility.\n :return: A list of tuples where all elements are divisible by k.\n \"\"\"\n # Using list comprehension to filter tuples\n return [t for t in tuples_list if all(x % k == 0 for x in t)]", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n \"\"\"\n Find all tuples in tuples_list where all elements are divisible by k.\n\n Parameters:\n tuples_list (list of tuples): A list of tuples to check.\n k (int): The divisor to check against.\n\n Returns:\n list of tuples: A list of tuples where all elements are divisible by k.\n \"\"\"\n return [t for t in tuples_list if all(el % k == 0 for el in t)]", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n \"\"\"\n This function takes a list of tuples and an integer k,\n and returns a list of tuples where all elements in the \n tuple are divisible by k.\n \n :param tuples_list: List of tuples to be checked\n :param k: Integer value to check divisibility against\n :return: List of tuples with all elements divisible by k\n \"\"\"\n return [t for t in tuples_list if all(element % k == 0 for element in t)]", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n \"\"\"\n This function finds all tuples from the given list that have all elements divisible by k.\n \n :param tuples_list: List of tuples to check.\n :param k: The divisor.\n :return: A list of tuples where all elements are divisible by k.\n \"\"\"\n result = []\n for tup in tuples_list:\n if all(element % k == 0 for element in tup):\n result.append(tup)\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n \"\"\"\n This function takes a list of tuples and an integer k.\n It returns a list of tuples where all elements in the tuple are divisible by k.\n \n :param tuples_list: List of tuples to check\n :param k: Integer to check divisibility\n :return: List of tuples where all elements are divisible by k\n \"\"\"\n result = []\n for tup in tuples_list:\n if all(element % k == 0 for element in tup):\n result.append(tup)\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n \"\"\"\n Find tuples which have all elements divisible by k from the given list of tuples.\n\n Args:\n tuples_list (list of tuples): A list of tuples to check.\n k (int): The divisor to check for divisibility.\n\n Returns:\n list of tuples: A list of tuples where all elements are divisible by k.\n \"\"\"\n result = []\n for tup in tuples_list:\n if all(x % k == 0 for x in tup):\n result.append(tup)\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n \"\"\"\n Find tuples in the given list where all elements are divisible by k.\n \n :param tuples_list: List of tuples to check\n :param k: Integer to check divisibility\n :return: List of tuples where all elements are divisible by k\n \"\"\"\n return [t for t in tuples_list if all(element % k == 0 for element in t)]", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n \"\"\"\n This function returns a list of tuples from tuples_list \n where all elements in the tuple are divisible by k.\n \n :param tuples_list: List of tuples to check\n :param k: Integer to check divisibility against\n :return: List of tuples with all elements divisible by k\n \"\"\"\n return [tup for tup in tuples_list if all(element % k == 0 for element in tup)]", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n \"\"\"\n Find tuples which have all elements divisible by k.\n\n Parameters:\n tuples_list (list of tuples): The list of tuples to check.\n k (int): The divisor to check against.\n\n Returns:\n list of tuples: A list of tuples where all elements are divisible by k.\n \"\"\"\n return [t for t in tuples_list if all(x % k == 0 for x in t)]", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n \"\"\"\n Find tuples which have all elements divisible by k from the given list of tuples.\n\n Args:\n tuples_list (list of tuples): List of tuples to check.\n k (int): The divisor to check for.\n\n Returns:\n list: List of tuples where all elements are divisible by k.\n \"\"\"\n return [tup for tup in tuples_list if all(elem % k == 0 for elem in tup)]", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n \"\"\"\n This function returns a list of tuples from the given list where all elements\n in each tuple are divisible by k.\n \n Parameters:\n tuples_list (list of tuples): The list of tuples to be checked.\n k (int): The divisor to check divisibility against.\n \n Returns:\n list of tuples: A list of tuples where all elements are divisible by k.\n \"\"\"\n result = []\n for tup in tuples_list:\n if all(element % k == 0 for element in tup):\n result.append(tup)\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n \"\"\"\n Find tuples which have all elements divisible by k from the given list of tuples.\n\n :param tuples_list: List of tuples containing integers\n :param k: An integer to check divisibility\n :return: List of tuples where all elements are divisible by k\n \"\"\"\n return [t for t in tuples_list if all(element % k == 0 for element in t)]", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n \"\"\"\n Find tuples which have all elements divisible by k from the given list of tuples.\n \n :param tuples_list: List of tuples to check\n :param k: The divisor\n :return: List of tuples where all elements are divisible by k\n \"\"\"\n return [tup for tup in tuples_list if all(element % k == 0 for element in tup)]", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n \"\"\"Return a list of tuples where all elements are divisible by k.\"\"\"\n return [t for t in tuples_list if all(x % k == 0 for x in t)]", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n \"\"\"\n This function finds all tuples in tuples_list where all elements are divisible by k.\n \n :param tuples_list: List of tuples to check\n :param k: The divisor\n :return: A list of tuples where all elements are divisible by k\n \"\"\"\n result = []\n for tup in tuples_list:\n if all(x % k == 0 for x in tup):\n result.append(tup)\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n \"\"\"\n Find tuples in the given list where all elements are divisible by k.\n\n :param tuples_list: List of tuples to check.\n :param k: The divisor to check divisibility against.\n :return: List of tuples where all elements are divisible by k.\n \"\"\"\n return [t for t in tuples_list if all(x % k == 0 for x in t)]", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n \"\"\"\n Function to find tuples which have all elements divisible by k.\n \n Parameters:\n tuples_list (list of tuples): The list of tuples to check.\n k (int): The divisor.\n \n Returns:\n list of tuples: A list containing tuples where all elements are divisible by k.\n \"\"\"\n result = []\n for tup in tuples_list:\n if all(element % k == 0 for element in tup):\n result.append(tup)\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n \"\"\"\n Find tuples which have all elements divisible by k.\n \n Parameters:\n tuples_list (list of tuples): The list of tuples to check.\n k (int): The divisor.\n \n Returns:\n list of tuples: A list containing tuples with all elements divisible by k.\n \"\"\"\n result = []\n for tup in tuples_list:\n if all(element % k == 0 for element in tup):\n result.append(tup)\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n \"\"\"\n Find tuples which have all elements divisible by k from the given list of tuples.\n\n :param tuples_list: List of tuples\n :param k: Integer to check divisibility\n :return: List of tuples where all elements are divisible by k\n \"\"\"\n result = []\n for tup in tuples_list:\n if all(x % k == 0 for x in tup):\n result.append(tup)\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n \"\"\"\n Find tuples which have all elements divisible by k from the given list of tuples.\n\n Parameters:\n tuples_list (list of tuple): A list containing tuples of integers.\n k (int): The divisor to check for divisibility.\n\n Returns:\n list of tuple: A list of tuples where all elements are divisible by k.\n \"\"\"\n result = []\n for tup in tuples_list:\n if all(element % k == 0 for element in tup):\n result.append(tup)\n return result", "matching_cluster_idx": 5}]}, "Mbpp/88": {"dps": 96.56862745098039, "dps_norm": 85.71428571428571, "pass@1": 100.0, "profiled": [{"solution": "def freq_count(lst):\n \"\"\"Returns a dictionary with the frequency of each element in the list.\"\"\"\n frequency = {}\n for item in lst:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n return frequency", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n \"\"\"\n Function to get the frequency of all elements in a list.\n \n Args:\n lst (list): A list of elements to count frequencies.\n \n Returns:\n dict: A dictionary with elements as keys and their frequencies as values.\n \"\"\"\n frequency = {}\n for item in lst:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n return frequency", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n \"\"\"\n Returns a dictionary with the frequency of each element in the provided list.\n\n Args:\n lst (list): A list of elements.\n\n Returns:\n dict: A dictionary where keys are elements from the list and values are their frequencies.\n \"\"\"\n frequency = {}\n for item in lst:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n return frequency", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n \"\"\"\n Calculate the frequency of all the elements in a list.\n\n Args:\n lst (list): A list of elements.\n\n Returns:\n dict: A dictionary where keys are elements and values are their respective frequencies.\n \"\"\"\n frequency = {}\n for item in lst:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n return frequency", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n \"\"\"\n Returns a dictionary with the frequency of each element in the given list.\n \n Parameters:\n lst (list): The list of elements for which to count the frequency.\n \n Returns:\n dict: A dictionary where keys are the elements and values are their frequencies.\n \"\"\"\n frequency = {}\n for item in lst:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n return frequency", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n \"\"\"\n Returns the frequency of all elements in the provided list as a dictionary.\n\n Args:\n lst (list): A list of elements.\n\n Returns:\n dict: A dictionary with elements as keys and their frequencies as values.\n \"\"\"\n frequency = {}\n for item in lst:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n return frequency", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n \"\"\"\n Returns the frequency of all elements in the list as a dictionary.\n \n Parameters:\n lst (list): The list of elements to count frequencies.\n \n Returns:\n dict: A dictionary with elements as keys and their frequencies as values.\n \"\"\"\n frequency = {}\n for item in lst:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n return frequency", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n \"\"\"\n Returns the frequency of all the elements in the given list as a dictionary.\n \n Parameters:\n lst (list): A list of elements.\n \n Returns:\n dict: A dictionary with elements as keys and their counts as values.\n \"\"\"\n frequency = {}\n for item in lst:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n return frequency", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n \"\"\"\n Function to count the frequency of all elements in a list.\n\n Args:\n lst (list): The input list containing elements.\n\n Returns:\n dict: A dictionary with elements as keys and their frequencies as values.\n \"\"\"\n frequency = {}\n for item in lst:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n return frequency", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n \"\"\"\n Count the frequency of each element in the given list.\n \n :param lst: List of elements to count\n :return: Dictionary with elements as keys and their frequencies as values\n \"\"\"\n frequency = {}\n for item in lst:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n return frequency", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n \"\"\"\n Function to count the frequency of elements in a list and return as a dictionary.\n \n Parameters:\n lst (list): A list of elements to count frequencies of.\n \n Returns:\n dict: A dictionary with elements as keys and their frequencies as values.\n \"\"\"\n frequency = {}\n for item in lst:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n return frequency", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n \"\"\"\n Returns a dictionary with the frequency of each element in the given list.\n\n Parameters:\n lst (list): A list of elements.\n\n Returns:\n dict: A dictionary where keys are elements of the list and values are their frequencies.\n \"\"\"\n frequency = {}\n for item in lst:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n return frequency", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n \"\"\"\n Function to count the frequency of elements in a list.\n \n Parameters:\n lst (list): A list of elements.\n \n Returns:\n dict: A dictionary with elements as keys and their frequency as values.\n \"\"\"\n frequency = {}\n for item in lst:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n return frequency", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n \"\"\"Return the frequency of all the elements in a list as a dictionary.\"\"\"\n frequency = {}\n for item in lst:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n return frequency", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n \"\"\"Returns the frequency of elements in the list as a dictionary.\"\"\"\n frequency = {}\n for item in lst:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n return frequency", "matching_cluster_idx": 5}, {"solution": "def freq_count(elements):\n \"\"\"\n Returns a dictionary with the frequency of each element in the list.\n\n Args:\n elements (list): A list of elements.\n\n Returns:\n dict: A dictionary where keys are elements and values are their frequencies.\n \"\"\"\n frequency = {}\n for element in elements:\n if element in frequency:\n frequency[element] += 1\n else:\n frequency[element] = 1\n return frequency", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n frequency = {}\n for item in lst:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n return frequency", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n \"\"\"\n Returns a dictionary with the frequency of each element in the list.\n \n Parameters:\n lst (list): A list of elements.\n \n Returns:\n dict: A dictionary with elements as keys and their frequencies as values.\n \"\"\"\n frequency = {}\n for item in lst:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n return frequency", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n \"\"\"\n Count the frequency of all elements in a list and return it as a dictionary.\n\n Parameters:\n lst (list): The list of elements to count.\n\n Returns:\n dict: A dictionary with elements as keys and their frequencies as values.\n \"\"\"\n frequency = {}\n for item in lst:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n return frequency", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n \"\"\"\n Returns the frequency of all elements in a list as a dictionary.\n \n Parameters:\n lst (list): The list of elements to count.\n \n Returns:\n dict: A dictionary with elements as keys and their frequencies as values.\n \"\"\"\n frequency = {}\n for item in lst:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n return frequency", "matching_cluster_idx": 5}]}, "Mbpp/90": {"dps": 76.92682926829269, "dps_norm": 85.0, "pass@1": 100.0, "profiled": [{"solution": "def len_log(words):\n \"\"\"\n Find the length of the longest word in a list.\n\n Args:\n words (list of str): A list of words.\n\n Returns:\n int: The length of the longest word.\n \"\"\"\n if not words: # Check for empty list\n return 0\n\n return max(len(word) for word in words)", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n \"\"\"Returns the length of the longest word in the list.\"\"\"\n if not words:\n return 0\n return max(len(word) for word in words)", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n \"\"\"\n This function returns the length of the longest word in the provided list.\n\n :param words: List of strings\n :return: Length of the longest word\n \"\"\"\n if not words: # Handle empty list case\n return 0\n return max(len(word) for word in words)", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n \"\"\"Returns the length of the longest word in the given list of words.\"\"\"\n if not words:\n return 0\n return max(len(word) for word in words)", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n \"\"\"\n This function takes a list of words and returns the length of the longest word.\n \n :param words: List of strings\n :return: Length of the longest word\n \"\"\"\n if not words: # Check if the list is empty\n return 0\n \n longest_length = max(len(word) for word in words) # Find the maximum length\n return longest_length", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n \"\"\"\n This function takes a list of words and returns the length of the longest word.\n \n :param words: List of strings\n :return: Integer length of the longest word\n \"\"\"\n if not words:\n return 0\n return max(len(word) for word in words)", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n \"\"\"\n Function to find the length of the longest word in a list.\n \n Args:\n words (list of str): A list of words to be evaluated.\n \n Returns:\n int: The length of the longest word.\n \"\"\"\n # Use the max function to find the longest word and return its length\n return max(len(word) for word in words)", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n \"\"\"Return the length of the longest word in the list.\"\"\"\n if not words: # Check if the list is empty\n return 0\n return max(len(word) for word in words) # Find the maximum length of the words", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n \"\"\"\n Function to find the length of the longest word in a list.\n \n Parameters:\n words (list): A list of strings (words).\n \n Returns:\n int: The length of the longest word.\n \"\"\"\n if not words:\n return 0\n \n longest_word_length = max(len(word) for word in words)\n return longest_word_length", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n \"\"\"\n Function to find the length of the longest word in a list of words.\n\n Args:\n words (list): A list of strings.\n\n Returns:\n int: The length of the longest word.\n \"\"\"\n if not words: # Handle empty list case\n return 0\n return max(len(word) for word in words)", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n \"\"\"\n Function to find the length of the longest word in a list of words.\n \n Parameters:\n words (list): A list of words (strings).\n \n Returns:\n int: Length of the longest word.\n \"\"\"\n if not words: # If the list is empty, return 0\n return 0\n return max(len(word) for word in words)", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n \"\"\"Return the length of the longest word in the list.\"\"\"\n if not words:\n return 0\n return max(len(word) for word in words)", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n \"\"\"Returns the length of the longest word in the list.\"\"\"\n if not words:\n return 0\n return max(len(word) for word in words)", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n \"\"\"\n Function to find the length of the longest word in a list of words.\n \n Args:\n words (list): A list of strings (words).\n \n Returns:\n int: The length of the longest word.\n \"\"\"\n if not words:\n return 0 # Return 0 if the list is empty\n \n longest_length = 0\n for word in words:\n longest_length = max(longest_length, len(word))\n \n return longest_length", "matching_cluster_idx": 3}, {"solution": "def len_log(words):\n \"\"\"\n This function takes a list of words and returns the length of the longest word.\n \n Parameters:\n words (list of str): A list containing words as strings.\n\n Returns:\n int: The length of the longest word in the list.\n \"\"\"\n if not words:\n return 0 # Return 0 if the list is empty\n\n longest_length = max(len(word) for word in words)\n return longest_length", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n \"\"\"\n Function to find the length of the longest word in a list.\n\n Args:\n words (list of str): A list of words.\n\n Returns:\n int: The length of the longest word.\n \"\"\"\n if not words: # handle empty list case\n return 0\n \n # Find the longest word by applying the built-in max function with key set to len\n longest_word = max(words, key=len)\n return len(longest_word)", "matching_cluster_idx": 6}, {"solution": "def len_log(words):\n \"\"\"\n Returns the length of the longest word in the given list of words.\n \n :param words: List of strings\n :return: Length of the longest word\n \"\"\"\n if not words: # Check if the list is empty\n return 0\n return max(len(word) for word in words) # Find the maximum length", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n \"\"\"\n Function to find the length of the longest word in a list.\n \n Args:\n words (list of str): A list containing words as strings.\n \n Returns:\n int: The length of the longest word.\n \"\"\"\n if not words:\n return 0\n return max(len(word) for word in words)", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n \"\"\"Return the length of the longest word in the given list of words.\"\"\"\n if not words: # Check if the list is empty\n return 0\n return max(len(word) for word in words) # Return the length of the longest word", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n \"\"\"\n Function to find the length of the longest word in a list.\n \n Parameters:\n words (list): A list of words (strings).\n \n Returns:\n int: The length of the longest word.\n \"\"\"\n if not words: # Check if the list is empty\n return 0\n \n longest_word_length = max(len(word) for word in words)\n return longest_word_length", "matching_cluster_idx": 5}]}, "Mbpp/94": {"dps": 79.28353658536585, "dps_norm": 63.0, "pass@1": 72.0, "profiled": [{"solution": "def index_minimum(tuples_list):\n # Check if the list is empty\n if not tuples_list:\n return None\n\n # Initialize the first tuple as the minimum\n min_tuple = tuples_list[0]\n\n # Iterate over the list of tuples\n for tup in tuples_list:\n # Compare the second value of the current tuple with the minimum found so far\n if tup[1] < min_tuple[1]:\n min_tuple = tup\n\n # Return the first value of the tuple with the smallest second value\n return min_tuple[0]", "matching_cluster_idx": 3}, {"solution": "def index_minimum(tuples_list):\n # If the list is empty, return None\n if not tuples_list:\n return None\n # Find the tuple with the minimum second value\n min_tuple = min(tuples_list, key=lambda x: x[1])\n # Return the first value of the tuple with the minimum second value\n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(tuples_list):\n \"\"\"\n Given a list of tuples, returns the first value of the tuple with the smallest second value.\n \n Args:\n tuples_list (list of tuples): A list where each tuple contains two elements.\n\n Returns:\n The first value of the tuple with the smallest second value.\n \"\"\"\n if not tuples_list:\n return None # Return None if the list is empty\n\n # Initialize the tuple with the smallest second value\n min_tuple = tuples_list[0]\n\n # Iterate through the list to find the tuple with the smallest second value\n for current_tuple in tuples_list:\n if current_tuple[1] < min_tuple[1]:\n min_tuple = current_tuple\n\n return min_tuple[0] # Return the first value of the tuple with the smallest second value", "matching_cluster_idx": 3}, {"solution": "def index_minimum(tuples_list):\n \"\"\"\n Returns the first value of the tuple with the smallest second value in the list of tuples.\n \n :param tuples_list: List of tuples where each tuple contains two elements.\n :return: The first value of the tuple with the smallest second value.\n \"\"\"\n if not tuples_list:\n raise ValueError(\"The list of tuples is empty\")\n \n # Use the min function with a key to find the tuple with the smallest second value\n min_tuple = min(tuples_list, key=lambda x: x[1])\n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(tuples_list):\n \"\"\"\n Given a list of tuples, returns the first value of the tuple with the smallest second value.\n\n Args:\n tuples_list (list of tuples): A list where each tuple contains two elements, \n the first being a name (string) and the second an integer.\n\n Returns:\n string: The first value of the tuple with the smallest second value.\n \"\"\"\n if not tuples_list:\n return None # Handle the case of an empty list\n\n # Find the tuple with the minimum second value\n min_tuple = min(tuples_list, key=lambda x: x[1])\n return min_tuple[0] # Return the first element of the tuple", "matching_cluster_idx": 2}, {"solution": "def index_minimum(tuples_list):\n \"\"\"\n Given a list of tuples, returns the first value of the tuple with the smallest second value.\n \n Parameters:\n tuples_list (list): A list of tuples where each tuple contains two elements.\n \n Returns:\n str: The first element of the tuple with the smallest second element.\n \"\"\"\n # Check if the list is empty\n if not tuples_list:\n return None\n \n # Use the min function with a custom key to find the tuple with the smallest second value\n min_tuple = min(tuples_list, key=lambda x: x[1])\n \n # Return the first value of the tuple\n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(tuples_list):\n \"\"\"\n Given a list of tuples, this function returns the first value of the tuple\n with the smallest second value.\n\n :param tuples_list: List of tuples where each tuple contains two elements\n :return: The first value of the tuple with the smallest second value\n \"\"\"\n # Using min with a custom key to find the tuple with the smallest second value\n smallest_tuple = min(tuples_list, key=lambda x: x[1])\n return smallest_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(tuples_list):\n \"\"\"\n Returns the first value of the tuple with the smallest second value.\n \n Parameters:\n tuples_list (list of tuple): A list of tuples where each tuple contains \n two elements (a string and a number).\n \n Returns:\n str: The first element of the tuple with the smallest second element.\n \"\"\"\n if not tuples_list:\n return None # Handle case with an empty list\n \n # Use the min function with a key that extracts the second element of each tuple\n min_tuple = min(tuples_list, key=lambda x: x[1])\n \n # Return the first element of the tuple with the smallest second element\n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(tuples_list):\n # Find the tuple with the smallest second value\n # Using min with a key to compare the second elements of the tuples\n min_tuple = min(tuples_list, key=lambda x: x[1])\n # Return the first value of the tuple with the smallest second value\n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(tuples_list):\n # Check if the list is empty\n if not tuples_list:\n return None # or raise an exception depending on your needs\n\n # Initialize the first tuple as the minimum\n min_tuple = tuples_list[0]\n\n # Iterate over the list of tuples\n for current_tuple in tuples_list:\n # Compare the second value\n if current_tuple[1] < min_tuple[1]:\n min_tuple = current_tuple\n\n # Return the first value of the tuple with the smallest second value\n return min_tuple[0]", "matching_cluster_idx": 3}, {"solution": "def index_minimum(tuples_list):\n \"\"\"\n Returns the first value of the tuple with the smallest second value.\n \n :param tuples_list: List of tuples where each tuple contains a name and a number.\n :return: The first value (name) of the tuple with the smallest second value (number).\n \"\"\"\n # Using the min function with a custom key to find the tuple with the smallest second value\n min_tuple = min(tuples_list, key=lambda x: x[1])\n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(tuples_list):\n # Use the min function to find the tuple with the smallest second value\n return min(tuples_list, key=lambda x: x[1])[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(tuples_list):\n # Check if the list is empty\n if not tuples_list:\n return None\n \n # Use min() with a key to find the tuple with the smallest second value\n smallest_tuple = min(tuples_list, key=lambda x: x[1])\n \n # Return the first value of the found tuple\n return smallest_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(tuples_list):\n # Check if the list is empty\n if not tuples_list:\n return None\n \n # Use min with a custom key to find the tuple with the smallest second value\n min_tuple = min(tuples_list, key=lambda x: x[1])\n \n # Return the first value of the tuple with the smallest second value\n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(tuples_list):\n \"\"\"\n Returns the first value of the tuple with the smallest second value.\n \n :param tuples_list: List of tuples where each tuple contains two elements\n :return: First element of the tuple with the minimum second element\n \"\"\"\n if not tuples_list:\n raise ValueError(\"The input list cannot be empty.\")\n \n # Use min function with a key to find the tuple with the smallest second value\n min_tuple = min(tuples_list, key=lambda x: x[1])\n \n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(tuples_list):\n # Return the first value of the tuple with the smallest second value\n return min(tuples_list, key=lambda x: x[1])[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(tuples_list):\n # Check if the list is empty\n if not tuples_list:\n return None\n \n # Use the min function with a custom key to find the tuple with the smallest second value\n smallest_tuple = min(tuples_list, key=lambda x: x[1])\n \n # Return the first value of the found tuple\n return smallest_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(tuples_list):\n # Use min to find the tuple with the smallest second value\n # The key parameter is used to compare the second elements of the tuples\n return min(tuples_list, key=lambda x: x[1])[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(tuples_list):\n \"\"\"Returns the first value of the tuple with the smallest second value.\"\"\"\n if not tuples_list:\n return None # Return None if the input list is empty\n # Use the min function with a custom key to find the tuple with the smallest second value\n min_tuple = min(tuples_list, key=lambda x: x[1])\n return min_tuple[0] # Return the first value of the tuple", "matching_cluster_idx": 2}, {"solution": "def index_minimum(tuples_list):\n # Check if the input list is empty\n if not tuples_list:\n return None\n \n # Use min to find the tuple with the smallest second value\n # min() will return the first tuple with the smallest second value in case of ties\n min_tuple = min(tuples_list, key=lambda x: x[1])\n \n # Return the first value of the tuple\n return min_tuple[0]", "matching_cluster_idx": 2}]}, "Mbpp/96": {"dps": 68.19444444444443, "dps_norm": 70.71428571428571, "pass@1": 100.0, "profiled": [{"solution": "def divisor(n):\n \"\"\"Return the number of divisors of the given integer n.\"\"\"\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n count += 1\n if i != n // i: # Count the complementary divisor if it's different\n count += 1\n return count", "matching_cluster_idx": 5}, {"solution": "def divisor(n):\n \"\"\"Returns the number of divisors of the given integer n.\"\"\"\n if n <= 0:\n return 0 # Return 0 for non-positive integers\n \n count = 0\n # Check for all numbers from 1 to sqrt(n)\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0: # If i is a divisor\n count += 1 # Count i\n if i != n // i: # Count n // i if it's different\n count += 1\n return count", "matching_cluster_idx": 5}, {"solution": "def divisor(n):\n \"\"\"Returns the number of divisors of the given integer n.\"\"\"\n if n <= 0:\n return 0 # No divisors for non-positive integers\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def divisor(n):\n \"\"\"Return the number of divisors of the given integer n.\"\"\"\n if n < 1:\n return 0 # Return 0 for non-positive integers\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0: # i is a divisor\n count += 1 # Count i\n if i != n // i: # Count the complementary divisor\n count += 1\n return count", "matching_cluster_idx": 6}, {"solution": "def divisor(n):\n \"\"\"Return the number of divisors of the integer n.\"\"\"\n if n < 1:\n raise ValueError(\"Input must be a positive integer.\")\n \n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n count += 1 # i is a divisor\n if i != n // i:\n count += 1 # n // i is also a divisor if it's different from i\n return count", "matching_cluster_idx": 5}, {"solution": "def divisor(n):\n \"\"\"Return the number of divisors of the given integer n.\"\"\"\n if n <= 0:\n raise ValueError(\"Input must be a positive integer.\")\n \n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n \"\"\"\n Function to find the number of divisors of a given integer n.\n \n Args:\n n (int): The integer to find the divisors of.\n \n Returns:\n int: The number of divisors of n.\n \"\"\"\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n count += 1 # i is a divisor\n if i != n // i:\n count += 1 # n // i is a divisor\n return count", "matching_cluster_idx": 6}, {"solution": "def divisor(n):\n \"\"\"\n Function to find the number of divisors of a given integer n.\n \n Parameters:\n n (int): The integer for which to find the number of divisors.\n \n Returns:\n int: The number of divisors of n.\n \"\"\"\n if n <= 0:\n raise ValueError(\"n must be a positive integer\")\n\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n count += 1 # Count the divisor\n if i != n // i: # Count the complementary divisor if it's different\n count += 1\n return count", "matching_cluster_idx": 5}, {"solution": "def divisor(n):\n \"\"\"\n Returns the number of divisors of a given integer n.\n \n Parameters:\n n (int): The integer for which to find the number of divisors.\n \n Returns:\n int: The number of divisors of n.\n \"\"\"\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0: # If i is a divisor\n count += 1 # Count i\n if i != n // i: # Count the complementary divisor\n count += 1\n return count", "matching_cluster_idx": 5}, {"solution": "def divisor(n):\n \"\"\"Returns the number of divisors of the given integer n.\"\"\"\n if n <= 0:\n raise ValueError(\"Input must be a positive integer.\")\n \n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0: # i is a divisor\n count += 1\n if i != n // i: # Count the complementary divisor only if it's different\n count += 1\n return count", "matching_cluster_idx": 6}, {"solution": "def divisor(n):\n \"\"\"\n Function to find the number of divisors of a given integer n.\n \n :param n: The integer to find divisors for.\n :return: The number of divisors of n.\n \"\"\"\n if n < 1:\n return 0 # No divisors for numbers less than 1\n\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n count += 1 # i is a divisor\n if i != n // i:\n count += 1 # n // i is also a divisor\n\n return count", "matching_cluster_idx": 5}, {"solution": "def divisor(n):\n \"\"\"\n This function returns the number of divisors of a given integer n.\n\n Parameters:\n n (int): The integer to find divisors for.\n\n Returns:\n int: The count of divisors of n.\n \"\"\"\n if n <= 0:\n raise ValueError(\"Input must be a positive integer.\")\n \n count = 0\n # Loop through numbers from 1 to n to find divisors\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def divisor(n):\n \"\"\"Return the number of divisors of the given integer n.\"\"\"\n if n <= 0:\n raise ValueError(\"Input must be a positive integer.\")\n \n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n count += 1 # i is a divisor\n if i != n // i:\n count += 1 # n // i is also a divisor if it's not the same as i\n return count", "matching_cluster_idx": 6}, {"solution": "def divisor(n):\n if n < 1:\n raise ValueError(\"Input must be a positive integer.\")\n \n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def divisor(n):\n \"\"\"Return the number of divisors of the given integer n.\"\"\"\n if n < 1:\n return 0 # No divisors for non-positive integers\n \n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def divisor(n):\n \"\"\"Return the number of divisors of the given integer n.\"\"\"\n if n <= 0:\n return 0 # Return 0 for non-positive integers, as they don't have positive divisors\n \n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n count += 1 # Count the divisor\n if i != n // i:\n count += 1 # Count the complementary divisor\n return count", "matching_cluster_idx": 5}, {"solution": "def divisor(n):\n \"\"\"Return the number of divisors of the given integer n.\"\"\"\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def divisor(n):\n \"\"\"Return the number of divisors of the given integer n.\"\"\"\n if n < 1:\n return 0 # No divisors for non-positive integers\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n count += 1 # Count the divisor i\n if i != n // i:\n count += 1 # Count the complementary divisor n // i\n return count", "matching_cluster_idx": 5}, {"solution": "def divisor(n):\n \"\"\"Return the number of divisors of the given integer n.\"\"\"\n if n <= 0:\n raise ValueError(\"Input must be a positive integer.\")\n \n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n \"\"\"\n This function returns the number of divisors of the given integer n.\n \"\"\"\n if n <= 0:\n raise ValueError(\"Input must be a positive integer.\")\n \n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n count += 1 # i is a divisor\n if i != n // i:\n count += 1 # n // i is also a divisor\n return count", "matching_cluster_idx": 6}]}, "Mbpp/97": {"dps": 99.65811965811966, "dps_norm": 87.5, "pass@1": 100.0, "profiled": [{"solution": "def frequency_lists(list_of_lists):\n frequency = {}\n \n # Flatten the list of lists and count frequencies\n for sublist in list_of_lists:\n for item in sublist:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n \n return frequency", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lists):\n frequency = {}\n for sublist in lists:\n for item in sublist:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n return frequency", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lists):\n frequency = {}\n for sublist in lists:\n for item in sublist:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n return frequency", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lists):\n \"\"\"\n Count the frequency of each element in a flattened list of lists.\n\n Args:\n lists (list of list): A list containing sublists of elements.\n\n Returns:\n dict: A dictionary with elements as keys and their frequencies as values.\n \"\"\"\n frequency_dict = {}\n \n for sublist in lists:\n for item in sublist:\n if item in frequency_dict:\n frequency_dict[item] += 1\n else:\n frequency_dict[item] = 1\n \n return frequency_dict", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(nested_list):\n frequency_dict = {}\n \n # Flatten the nested list and count frequencies\n for sublist in nested_list:\n for item in sublist:\n if item in frequency_dict:\n frequency_dict[item] += 1\n else:\n frequency_dict[item] = 1\n \n return frequency_dict", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(nested_list):\n # Initialize an empty dictionary to hold the frequency of elements\n frequency = {}\n \n # Iterate through each sublist in the nested list\n for sublist in nested_list:\n # Iterate through each element in the sublist\n for item in sublist:\n # Update the frequency count in the dictionary\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n \n return frequency", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lists):\n frequency = {}\n for sublist in lists:\n for item in sublist:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n return frequency", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(list_of_lists):\n frequency = {}\n \n for inner_list in list_of_lists:\n for item in inner_list:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n \n return frequency", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(nested_list):\n frequency_dict = {}\n \n # Flatten the nested list and count frequencies\n for sublist in nested_list:\n for item in sublist:\n if item in frequency_dict:\n frequency_dict[item] += 1\n else:\n frequency_dict[item] = 1\n \n return frequency_dict", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lists):\n frequency = {}\n for sublist in lists:\n for item in sublist:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n return frequency", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(nested_list):\n frequency = {}\n for sublist in nested_list:\n for item in sublist:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n return frequency", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(nested_list):\n frequency = {}\n for sublist in nested_list:\n for item in sublist:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n return frequency", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(nested_list):\n frequency_dict = {}\n for sublist in nested_list:\n for item in sublist:\n if item in frequency_dict:\n frequency_dict[item] += 1\n else:\n frequency_dict[item] = 1\n return frequency_dict", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lists):\n \"\"\"Return a dictionary with the frequency of each element in a flattened list of lists.\"\"\"\n frequency = {}\n \n for sublist in lists:\n for item in sublist:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n \n return frequency", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lists):\n frequency = {}\n for sublist in lists:\n for item in sublist:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n return frequency", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lst_of_lists):\n frequency = {}\n \n for sublist in lst_of_lists:\n for item in sublist:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n \n return frequency", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(nested_list):\n # Create an empty dictionary to store frequencies\n frequency_dict = {}\n \n # Flatten the list of lists\n for sublist in nested_list:\n for item in sublist:\n if item in frequency_dict:\n frequency_dict[item] += 1\n else:\n frequency_dict[item] = 1\n \n return frequency_dict", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(nested_lists):\n frequency = {}\n for sublist in nested_lists:\n for item in sublist:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n return frequency", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(nested_list):\n frequency = {}\n \n for sublist in nested_list:\n for item in sublist:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n \n return frequency", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(list_of_lists):\n frequency = {}\n \n for sublist in list_of_lists:\n for item in sublist:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n \n return frequency", "matching_cluster_idx": 6}]}, "Mbpp/106": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def add_lists(lst, tpl):\n \"\"\"\n Append the given list to the given tuple.\n\n Args:\n lst (list): The list to append.\n tpl (tuple): The tuple to which the list will be appended.\n\n Returns:\n tuple: A new tuple containing elements of the original tuple followed by elements of the list.\n \"\"\"\n return tpl + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tup):\n \"\"\"\n Appends the elements of the given list to the given tuple.\n\n Parameters:\n lst (list): A list of elements to append.\n tup (tuple): A tuple to which the list elements will be appended.\n\n Returns:\n tuple: A new tuple with elements of the list added to the original tuple.\n \"\"\"\n return tup + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tup):\n \"\"\"\n Append the given list to the given tuple.\n \n Parameters:\n lst (list): The list to append.\n tup (tuple): The tuple to which the list will be appended.\n \n Returns:\n tuple: A new tuple with elements of the list appended.\n \"\"\"\n return tup + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tup):\n \"\"\"\n Append the given list to the given tuple.\n \n Parameters:\n lst (list): The list to be appended.\n tup (tuple): The tuple to which the list will be appended.\n \n Returns:\n tuple: A new tuple containing the elements of the original tuple followed by the elements of the list.\n \"\"\"\n return tup + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tup):\n \"\"\"\n Append the given list to the given tuple.\n\n Args:\n lst (list): The list to append.\n tup (tuple): The tuple to which the list will be appended.\n\n Returns:\n tuple: A new tuple with the elements of the list appended to the tuple.\n \"\"\"\n return tup + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tup):\n \"\"\"\n Append the given list to the given tuple.\n\n Parameters:\n lst (list): The list of elements to be appended.\n tup (tuple): The tuple to which the list will be appended.\n\n Returns:\n tuple: A new tuple containing the elements of the original tuple followed by the elements of the list.\n \"\"\"\n return tup + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tpl):\n \"\"\"\n Append the given list to the given tuple.\n\n Parameters:\n lst (list): The list to append.\n tpl (tuple): The tuple to which the list will be appended.\n\n Returns:\n tuple: A new tuple consisting of the original tuple followed by the elements of the list.\n \"\"\"\n return tpl + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tup):\n \"\"\"\n Append the given list to the given tuple.\n\n Parameters:\n lst (list): The list to append.\n tup (tuple): The tuple to which the list will be appended.\n\n Returns:\n tuple: A new tuple with the elements of the list appended to the tuple.\n \"\"\"\n return tup + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tup):\n \"\"\"\n Append the given list to the given tuple.\n \n Args:\n lst (list): The list of elements to append.\n tup (tuple): The tuple to which the list will be appended.\n \n Returns:\n tuple: A new tuple containing the elements of the original tuple followed by the elements of the list.\n \"\"\"\n return tup + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tup):\n \"\"\"\n Appends the given list to the given tuple.\n\n Args:\n lst (list): A list of elements to be appended.\n tup (tuple): A tuple to which the list will be appended.\n\n Returns:\n tuple: A new tuple with the elements of the list appended to the tuple.\n \"\"\"\n return tup + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tup):\n \"\"\"\n Appends the given list to the given tuple.\n\n Args:\n lst (list): The list to append.\n tup (tuple): The tuple to which the list will be appended.\n\n Returns:\n tuple: A new tuple containing the elements of the original tuple followed by the elements of the list.\n \"\"\"\n return tup + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tpl):\n \"\"\"\n Appends the given list to the given tuple.\n\n Parameters:\n lst (list): The list to append.\n tpl (tuple): The tuple to which the list will be appended.\n\n Returns:\n tuple: A new tuple containing elements of the original tuple followed by elements of the list.\n \"\"\"\n return tpl + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tup):\n \"\"\"\n Appends the given list to the given tuple.\n\n Parameters:\n lst (list): A list of elements to append.\n tup (tuple): A tuple to which the list elements will be appended.\n\n Returns:\n tuple: A new tuple containing the original tuple elements followed by the list elements.\n \"\"\"\n return tup + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tpl):\n \"\"\"\n Appends the elements of the given list to the given tuple.\n\n Parameters:\n lst (list): The list of elements to append.\n tpl (tuple): The tuple to which the elements will be appended.\n\n Returns:\n tuple: A new tuple with the elements of the list appended.\n \"\"\"\n return tpl + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tup):\n \"\"\"\n Appends the given list to the given tuple.\n\n Parameters:\n lst (list): The list to append.\n tup (tuple): The tuple to which the list will be appended.\n\n Returns:\n tuple: A new tuple containing the elements of the original tuple followed by the elements of the list.\n \"\"\"\n return tup + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tup):\n \"\"\"\n Append the given list to the given tuple.\n \n Args:\n lst (list): The list of elements to append.\n tup (tuple): The tuple to which the list will be appended.\n\n Returns:\n tuple: A new tuple with elements of the list added to the tuple.\n \"\"\"\n return tup + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tup):\n \"\"\"\n Appends the given list to the given tuple.\n\n Parameters:\n lst (list): The list to append.\n tup (tuple): The tuple to which the list will be appended.\n\n Returns:\n tuple: A new tuple with elements of the list appended to the original tuple.\n \"\"\"\n return tup + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tpl):\n \"\"\"\n Append the given list to the given tuple.\n\n Parameters:\n lst (list): The list to be appended.\n tpl (tuple): The tuple to which the list will be appended.\n\n Returns:\n tuple: A new tuple with the elements of the list appended to the original tuple.\n \"\"\"\n return tpl + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tup):\n \"\"\"\n Append the given list to the given tuple.\n\n Parameters:\n lst (list): The list to append.\n tup (tuple): The tuple to which the list will be appended.\n\n Returns:\n tuple: A new tuple containing the elements of the original tuple followed by the elements of the list.\n \"\"\"\n return tup + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tpl):\n \"\"\"\n Appends the given list to the given tuple.\n\n Parameters:\n lst (list): The list to append.\n tpl (tuple): The tuple to which the list will be appended.\n\n Returns:\n tuple: A new tuple that contains all elements of the original tuple followed by the elements of the list.\n \"\"\"\n return tpl + tuple(lst)", "matching_cluster_idx": 5}]}, "Mbpp/108": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 97.0, "profiled": [{"solution": "def merge_sorted_list(list1, list2, list3):\n # Combine all three lists\n combined_list = list1 + list2 + list3\n # Sort the combined list\n sorted_list = sorted(combined_list)\n return sorted_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Combine all three lists into one\n combined_list = list1 + list2 + list3\n # Sort the combined list\n combined_list.sort()\n return combined_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Merge the three lists\n merged_list = list1 + list2 + list3\n # Sort the merged list\n merged_list.sort()\n return merged_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Merge all three lists\n merged_list = list1 + list2 + list3\n # Sort the merged list\n merged_list.sort()\n return merged_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Combine the three lists\n combined_list = list1 + list2 + list3\n # Sort the combined list\n sorted_list = sorted(combined_list)\n return sorted_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Merge all three lists into one\n merged_list = list1 + list2 + list3\n # Sort the merged list\n merged_list.sort()\n return merged_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Merge the three lists\n combined_list = list1 + list2 + list3\n \n # Sort the combined list\n combined_list.sort()\n \n return combined_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Merge the three lists into one\n merged_list = list1 + list2 + list3\n # Sort the merged list\n merged_list.sort()\n return merged_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Merge the lists\n merged_list = list1 + list2 + list3\n # Sort the merged list\n sorted_list = sorted(merged_list)\n return sorted_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Merge all three lists\n merged_list = list1 + list2 + list3\n # Sort the merged list\n return sorted(merged_list)", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Merge the lists\n merged_list = list1 + list2 + list3\n # Sort the merged list\n merged_list.sort()\n return merged_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Merge all three lists\n merged_list = list1 + list2 + list3\n # Sort the merged list\n merged_list.sort()\n return merged_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Combine all three lists\n combined_list = list1 + list2 + list3\n # Sort the combined list\n combined_list.sort()\n return combined_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Merge the lists\n merged_list = list1 + list2 + list3\n # Sort the merged list\n sorted_list = sorted(merged_list)\n return sorted_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Merge the three lists into one\n merged_list = list1 + list2 + list3\n # Sort the merged list\n merged_list.sort()\n return merged_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Combine the three lists\n combined_list = list1 + list2 + list3\n # Sort the combined list\n sorted_list = sorted(combined_list)\n return sorted_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Merge all three lists\n merged_list = list1 + list2 + list3\n # Sort the merged list\n merged_list.sort()\n return merged_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Combine all lists into one\n combined_list = list1 + list2 + list3\n # Sort the combined list\n combined_list.sort()\n return combined_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Merge the three lists\n merged_list = list1 + list2 + list3\n # Sort the merged list\n merged_list.sort()\n return merged_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Merge the three lists\n merged_list = list1 + list2 + list3\n # Sort the merged list\n merged_list.sort()\n return merged_list", "matching_cluster_idx": 10}]}, "Mbpp/111": {"dps": 91.53846153846155, "dps_norm": 86.25, "pass@1": 100.0, "profiled": [{"solution": "def common_in_nested_lists(nested_lists):\n # Convert the first list to a set\n common_elements = set(nested_lists[0])\n \n # Intersect with each subsequent list\n for lst in nested_lists[1:]:\n common_elements.intersection_update(lst)\n \n return common_elements", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n if not nested_lists:\n return []\n \n # Start with the first list as the initial common set\n common_elements = set(nested_lists[0])\n \n # Intersect with the rest of the lists\n for lst in nested_lists[1:]:\n common_elements.intersection_update(lst)\n \n return list(common_elements)", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n # Use set intersection to find common elements\n common_elements = set(nested_lists[0]) # Start with the first list as a set\n for lst in nested_lists[1:]:\n common_elements.intersection_update(lst) # Update the set with the intersection\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n if not nested_lists:\n return []\n \n # Use set intersection to find common elements\n common_elements = set(nested_lists[0])\n for lst in nested_lists[1:]:\n common_elements.intersection_update(lst)\n \n return list(common_elements)", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n # Use a set to find the common elements in all lists\n if not nested_lists:\n return []\n\n # Start with the first list's elements as a set\n common_elements = set(nested_lists[0])\n\n # Iterate through the remaining lists and update the common_elements set\n for lst in nested_lists[1:]:\n common_elements.intersection_update(lst)\n\n return list(common_elements)", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n # Use set intersection to find common elements\n if not nested_lists:\n return []\n\n # Start with the set of the first list\n common_elements = set(nested_lists[0])\n \n # Intersect with the sets of the remaining lists\n for lst in nested_lists[1:]:\n common_elements.intersection_update(lst)\n \n return list(common_elements)", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n if not nested_lists:\n return []\n\n # Start with the set of the first list\n common_elements = set(nested_lists[0])\n\n # Intersect with the sets of the subsequent lists\n for lst in nested_lists[1:]:\n common_elements.intersection_update(lst)\n\n return list(common_elements)", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n # Check if the nested lists are not empty\n if not nested_lists:\n return []\n\n # Initialize the common elements with the first list\n common_elements = set(nested_lists[0])\n\n # Iterate over the remaining lists and find common elements\n for lst in nested_lists[1:]:\n common_elements.intersection_update(lst)\n\n return list(common_elements)", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n if not nested_lists:\n return []\n\n # Start with the first list's set\n common_elements = set(nested_lists[0])\n\n # Intersect with each subsequent list's set\n for lst in nested_lists[1:]:\n common_elements.intersection_update(lst)\n\n return list(common_elements)", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n if not nested_lists:\n return []\n\n # Start with the set of the first list\n common_elements = set(nested_lists[0])\n\n # Intersect with sets of the remaining lists\n for lst in nested_lists[1:]:\n common_elements.intersection_update(lst)\n\n return list(common_elements)", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n \"\"\"\n Find the common elements in given nested lists.\n \n Parameters:\n nested_lists (list of list): A list containing multiple lists to search for common elements.\n \n Returns:\n list: A list of common elements found in all provided nested lists.\n \"\"\"\n # Use set to find intersection among lists\n common_elements = set(nested_lists[0]) # Start with the first list\n for lst in nested_lists[1:]:\n common_elements.intersection_update(lst) # Update the set with the intersection\n return list(common_elements) # Return as a list", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n \"\"\"\n Finds the common elements in given nested lists.\n \n Args:\n nested_lists (list of lists): A list containing sublists of integers.\n \n Returns:\n list: A list of common elements.\n \"\"\"\n if not nested_lists:\n return []\n\n # Initialize the set with the elements of the first sublist\n common_elements = set(nested_lists[0])\n\n # Intersect with the sets of the remaining sublists\n for sublist in nested_lists[1:]:\n common_elements.intersection_update(set(sublist))\n\n return list(common_elements)", "matching_cluster_idx": 5}, {"solution": "def common_in_nested_lists(nested_lists):\n if not nested_lists:\n return []\n \n # Start with the first set of elements\n common_elements = set(nested_lists[0])\n \n # Iterate through each list and find the intersection\n for lst in nested_lists[1:]:\n common_elements.intersection_update(lst)\n \n return list(common_elements)", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n # Use set intersection to find common elements\n if not nested_lists:\n return []\n \n # Initialize the common elements set with the first list\n common_elements = set(nested_lists[0])\n \n # Intersect with the sets of each subsequent list\n for lst in nested_lists[1:]:\n common_elements.intersection_update(lst)\n \n return list(common_elements)", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n if not nested_lists:\n return []\n \n # Start with the first list's set\n common_elements = set(nested_lists[0])\n \n # Intersect with the sets of the remaining lists\n for lst in nested_lists[1:]:\n common_elements.intersection_update(lst)\n \n return list(common_elements)", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n if not nested_lists:\n return []\n \n # Start with the set of the first list\n common_elements = set(nested_lists[0])\n \n # Intersect with the sets of the remaining lists\n for lst in nested_lists[1:]:\n common_elements.intersection_update(set(lst))\n \n return list(common_elements)", "matching_cluster_idx": 5}, {"solution": "def common_in_nested_lists(nested_lists):\n if not nested_lists:\n return []\n \n # Initialize a set with the elements of the first list\n common_elements = set(nested_lists[0])\n \n # Intersect with the sets of the remaining lists\n for lst in nested_lists[1:]:\n common_elements.intersection_update(lst)\n \n return list(common_elements)", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n if not nested_lists:\n return []\n \n # Initialize the common set with elements from the first list\n common_elements = set(nested_lists[0])\n \n # Iterate through the remaining lists and find the intersection\n for lst in nested_lists[1:]:\n common_elements.intersection_update(lst)\n \n return list(common_elements)", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n if not nested_lists:\n return []\n\n # Start with the set of the first list\n common_elements = set(nested_lists[0])\n\n # Intersect with the sets of the remaining lists\n for lst in nested_lists[1:]:\n common_elements.intersection_update(lst)\n\n return list(common_elements)", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n # Use the set intersection method to find common elements\n if not nested_lists:\n return []\n \n # Start with the set of the first list\n common_elements = set(nested_lists[0])\n \n # Intersect with the sets of the remaining lists\n for lst in nested_lists[1:]:\n common_elements.intersection_update(lst)\n \n return list(common_elements)", "matching_cluster_idx": 6}]}, "Mbpp/123": {"dps": 99.62686567164178, "dps_norm": 85.71428571428571, "pass@1": 91.0, "profiled": [{"solution": "def sum_of_divisors(n):\n \"\"\"Return the sum of proper divisors of n.\"\"\"\n if n < 2:\n return 0\n divisors_sum = 1 # 1 is a proper divisor of any n > 1\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n divisors_sum += i\n if i != n // i: # Avoid adding the square root twice if n is a perfect square\n divisors_sum += n // i\n return divisors_sum\ndef amicable_numbers_sum(limit):\n \"\"\"Return the sum of all amicable numbers from 1 to limit.\"\"\"\n amicable_numbers = set()\n\n for num in range(1, limit + 1):\n partner = sum_of_divisors(num)\n \n # Check if partner is different and if the sum of divisors of the partner leads back to the original number\n if partner != num and sum_of_divisors(partner) == num:\n amicable_numbers.add(num)\n amicable_numbers.add(partner)\n\n return sum(amicable_numbers)", "matching_cluster_idx": 11}, {"solution": "def sum_of_divisors(n):\n \"\"\"Return the sum of proper divisors of n.\"\"\"\n if n < 1:\n return 0\n total = 1 # 1 is a proper divisor of any n > 1\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n total += i\n if i != n // i: # Add the complementary divisor if it's not the same\n total += n // i\n return total\ndef amicable_numbers_sum(limit):\n \"\"\"Return the sum of all amicable numbers up to a specified limit.\"\"\"\n amicable_numbers = set()\n\n for num in range(2, limit + 1):\n if num not in amicable_numbers:\n partner = sum_of_divisors(num)\n if partner != num and partner <= limit:\n if sum_of_divisors(partner) == num:\n amicable_numbers.add(num)\n amicable_numbers.add(partner)\n\n return sum(amicable_numbers)", "matching_cluster_idx": 11}, {"solution": "def sum_of_divisors(n):\n \"\"\"Returns the sum of proper divisors of n.\"\"\"\n divisors_sum = 1 # Start with 1, as it's a proper divisor for all n > 1\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n divisors_sum += i\n if i != n // i: # Avoid adding the square root twice\n divisors_sum += n // i\n return divisors_sum\ndef amicable_numbers_sum(limit):\n \"\"\"Returns the sum of all amicable numbers from 1 to limit.\"\"\"\n amicable_numbers = set()\n \n for number in range(2, limit + 1):\n if number not in amicable_numbers:\n partner = sum_of_divisors(number)\n if partner != number and sum_of_divisors(partner) == number:\n amicable_numbers.add(number)\n amicable_numbers.add(partner)\n \n return sum(amicable_numbers)", "matching_cluster_idx": 11}, {"solution": "def sum_of_divisors(n):\n \"\"\"Returns the sum of proper divisors of n.\"\"\"\n divisors_sum = 1 # start with 1 as it is a proper divisor for all n > 1\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n divisors_sum += i\n if i != n // i:\n divisors_sum += n // i\n return divisors_sum\ndef amicable_numbers_sum(limit):\n \"\"\"Returns the sum of all amicable numbers from 1 to limit.\"\"\"\n amicable_numbers = set()\n \n for num in range(2, limit + 1):\n if num in amicable_numbers:\n continue\n \n partner = sum_of_divisors(num)\n \n if partner != num and partner <= limit:\n if sum_of_divisors(partner) == num:\n amicable_numbers.add(num)\n amicable_numbers.add(partner)\n \n return sum(amicable_numbers)", "matching_cluster_idx": 11}, {"solution": "def sum_of_divisors(n):\n \"\"\"Helper function to calculate the sum of proper divisors of n.\"\"\"\n total = 1 # Start with 1, as it's a proper divisor of every number\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n total += i\n if i != n // i: # Add the complement divisor if it's not the square root\n total += n // i\n return total\ndef amicable_numbers_sum(limit):\n \"\"\"Function to calculate the sum of all amicable numbers up to a specified limit.\"\"\"\n amicable_numbers = set()\n \n for i in range(2, limit):\n # Find the sum of proper divisors of i\n sum1 = sum_of_divisors(i)\n if sum1 != i: # To ensure it's not a perfect number\n sum2 = sum_of_divisors(sum1)\n if sum2 == i: # Check if they are amicable\n amicable_numbers.add(i)\n amicable_numbers.add(sum1)\n \n return sum(amicable_numbers)", "matching_cluster_idx": 11}, {"solution": "def sum_of_divisors(n):\n \"\"\"Return the sum of proper divisors of n.\"\"\"\n total = 1 # Start with 1 since it's a proper divisor of any n > 1\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n total += i\n if i != n // i: # Add the complementary divisor\n total += n // i\n return total\ndef amicable_numbers_sum(limit):\n \"\"\"Return the sum of all amicable numbers from 1 to limit.\"\"\"\n amicable_numbers = set()\n \n for num in range(2, limit + 1):\n if num not in amicable_numbers:\n sum1 = sum_of_divisors(num)\n sum2 = sum_of_divisors(sum1)\n\n # Check for amicable condition\n if sum1 != num and sum2 == num:\n amicable_numbers.add(num)\n amicable_numbers.add(sum1)\n \n return sum(amicable_numbers)", "matching_cluster_idx": 11}, {"solution": "def sum_of_divisors(n):\n \"\"\"Return the sum of proper divisors of n.\"\"\"\n if n < 2:\n return 0\n total = 1 # start with 1 because it's a proper divisor of all n > 1\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n total += i\n if i != n // i: # avoid adding the square root twice\n total += n // i\n return total\ndef amicable_numbers_sum(limit):\n \"\"\"Return the sum of all amicable numbers from 1 to limit.\"\"\"\n amicable_numbers = set()\n \n for num in range(2, limit + 1):\n if num not in amicable_numbers:\n partner = sum_of_divisors(num)\n if partner != num and partner <= limit:\n if sum_of_divisors(partner) == num:\n amicable_numbers.add(num)\n amicable_numbers.add(partner)\n\n return sum(amicable_numbers)", "matching_cluster_idx": 11}, {"solution": "def sum_of_divisors(n):\n \"\"\"Return the sum of proper divisors of n.\"\"\"\n if n < 2:\n return 0\n total = 1 # start with 1 as it is a proper divisor\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n total += i\n if i != n // i:\n total += n // i\n return total\ndef amicable_numbers_sum(limit):\n \"\"\"Return the sum of all amicable numbers from 1 to limit.\"\"\"\n amicable_numbers = set()\n \n for number in range(2, limit + 1):\n if number not in amicable_numbers:\n partner = sum_of_divisors(number)\n if partner != number and sum_of_divisors(partner) == number:\n amicable_numbers.add(number)\n amicable_numbers.add(partner)\n\n return sum(amicable_numbers)", "matching_cluster_idx": 11}, {"solution": "def divisor_sum(n):\n \"\"\"Return the sum of proper divisors of n.\"\"\"\n total = 1 # start with 1, as it's a proper divisor of any n > 1\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n total += i\n if i != n // i: # Add the complementary divisor\n total += n // i\n return total\ndef amicable_numbers_sum(limit):\n \"\"\"Return the sum of all amicable numbers from 1 to limit.\"\"\"\n amicable_numbers = set() # Use a set to avoid duplicates\n \n for num in range(2, limit + 1):\n if num not in amicable_numbers: # Check only if not already found\n pair = divisor_sum(num)\n if pair != num and divisor_sum(pair) == num:\n amicable_numbers.add(num)\n amicable_numbers.add(pair)\n \n return sum(amicable_numbers)", "matching_cluster_idx": 11}, {"solution": "def sum_of_proper_divisors(n):\n \"\"\"Return the sum of proper divisors of n.\"\"\"\n if n < 2:\n return 0\n total = 1 # 1 is a proper divisor of any n > 1\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n total += i\n if i != n // i: # Add the complement divisor if it's different\n total += n // i\n return total\ndef amicable_numbers_sum(limit):\n \"\"\"Return the sum of all amicable numbers from 1 to limit.\"\"\"\n amicable_numbers = set()\n for num in range(2, limit + 1):\n if num not in amicable_numbers:\n partner = sum_of_proper_divisors(num)\n if partner != num and sum_of_proper_divisors(partner) == num:\n amicable_numbers.add(num)\n amicable_numbers.add(partner)\n return sum(amicable_numbers)", "matching_cluster_idx": 11}, {"solution": "def sum_of_divisors(n):\n \"\"\"Returns the sum of proper divisors of n.\"\"\"\n divisors_sum = 1 # start with 1 since it is a proper divisor of all n > 1\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n divisors_sum += i\n if i != n // i: # add the complement divisor if it's different\n divisors_sum += n // i\n return divisors_sum\ndef amicable_numbers_sum(limit):\n \"\"\"Returns the sum of all amicable numbers up to the given limit.\"\"\"\n amicable_numbers = set()\n \n for num in range(2, limit + 1):\n if num not in amicable_numbers:\n partner = sum_of_divisors(num)\n if partner != num and partner <= limit:\n if sum_of_divisors(partner) == num:\n amicable_numbers.add(num)\n amicable_numbers.add(partner)\n\n return sum(amicable_numbers)", "matching_cluster_idx": 11}, {"solution": "def sum_of_divisors(n):\n \"\"\"Return the sum of proper divisors of n.\"\"\"\n total = 1 # Start with 1 because it's a divisor of every number\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n total += i\n if i != n // i: # Add the complementary divisor if it's different\n total += n // i\n return total\ndef amicable_numbers_sum(limit):\n \"\"\"Return the sum of all amicable numbers up to the specified limit.\"\"\"\n amicable_numbers = set()\n \n for number in range(2, limit + 1):\n if number not in amicable_numbers:\n partner = sum_of_divisors(number)\n if partner != number and sum_of_divisors(partner) == number:\n amicable_numbers.add(number)\n amicable_numbers.add(partner)\n\n return sum(amicable_numbers)", "matching_cluster_idx": 11}, {"solution": "def sum_of_divisors(n):\n \"\"\"Returns the sum of proper divisors of n.\"\"\"\n divisors_sum = 1 # 1 is a proper divisor of any number > 1\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n divisors_sum += i\n if i != n // i:\n divisors_sum += n // i\n return divisors_sum\ndef amicable_numbers_sum(limit):\n \"\"\"Returns the sum of all amicable numbers from 1 to the specified limit.\"\"\"\n amicable_numbers = set()\n \n for num in range(2, limit + 1):\n partner = sum_of_divisors(num)\n if partner != num and partner <= limit:\n if sum_of_divisors(partner) == num:\n amicable_numbers.add(num)\n amicable_numbers.add(partner)\n\n return sum(amicable_numbers)", "matching_cluster_idx": 11}, {"solution": "def sum_of_divisors(n):\n \"\"\"Returns the sum of proper divisors of n.\"\"\"\n total = 1 # Start with 1, as it's a proper divisor for all n > 1\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n total += i\n if i != n // i: # Include the complementary divisor\n total += n // i\n return total\ndef amicable_numbers_sum(limit):\n \"\"\"Returns the sum of all amicable numbers from 1 to limit.\"\"\"\n amicable_numbers = set()\n \n for number in range(2, limit + 1):\n if number not in amicable_numbers: # Only process if not already found\n partner = sum_of_divisors(number)\n if partner != number and sum_of_divisors(partner) == number:\n amicable_numbers.add(number)\n amicable_numbers.add(partner)\n \n return sum(amicable_numbers)", "matching_cluster_idx": 11}, {"solution": "def sum_of_divisors(n):\n \"\"\"Return the sum of proper divisors of n.\"\"\"\n total = 1 # start with 1 since it's a proper divisor of any n > 1\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n total += i\n if i != n // i: # avoid adding the square root twice\n total += n // i\n return total\ndef amicable_numbers_sum(limit):\n \"\"\"Return the sum of all amicable numbers from 1 to limit.\"\"\"\n amicable_numbers = set()\n \n for num in range(2, limit + 1):\n if num not in amicable_numbers:\n partner = sum_of_divisors(num)\n if partner != num and sum_of_divisors(partner) == num:\n amicable_numbers.add(num)\n amicable_numbers.add(partner)\n \n return sum(amicable_numbers)", "matching_cluster_idx": 11}, {"solution": "def sum_of_divisors(n):\n \"\"\"Return the sum of proper divisors of n.\"\"\"\n if n < 2:\n return 0\n divisors_sum = 1 # 1 is always a proper divisor\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n divisors_sum += i\n if i != n // i: # Add the complement divisor if it's not the same\n divisors_sum += n // i\n return divisors_sum\ndef amicable_numbers_sum(limit):\n \"\"\"Return the sum of all amicable numbers up to the specified limit.\"\"\"\n amicable_numbers = set()\n for num in range(2, limit + 1):\n partner = sum_of_divisors(num)\n if partner != num and partner <= limit:\n # Check if the partner's sum of divisors equals the original number\n if sum_of_divisors(partner) == num:\n amicable_numbers.add(num)\n amicable_numbers.add(partner)\n return sum(amicable_numbers)", "matching_cluster_idx": 11}, {"solution": "def sum_of_divisors(n):\n \"\"\"Returns the sum of proper divisors of n.\"\"\"\n total = 1 # 1 is a proper divisor for all n > 1\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n total += i\n if i != n // i:\n total += n // i\n return total\ndef amicable_numbers_sum(limit):\n \"\"\"Returns the sum of all amicable numbers from 1 to limit.\"\"\"\n amicable_numbers = set()\n \n for num in range(2, limit + 1):\n if num not in amicable_numbers:\n partner = sum_of_divisors(num)\n if partner != num and sum_of_divisors(partner) == num:\n amicable_numbers.add(num)\n amicable_numbers.add(partner)\n\n return sum(amicable_numbers)", "matching_cluster_idx": 11}, {"solution": "def sum_of_divisors(n):\n \"\"\"Returns the sum of proper divisors of n.\"\"\"\n divisors_sum = 1 # start with 1 because it is a proper divisor of any n > 1\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n divisors_sum += i\n if i != n // i: # add the complementary divisor\n divisors_sum += n // i\n return divisors_sum\ndef amicable_numbers_sum(limit):\n \"\"\"Returns the sum of all amicable numbers up to a specified limit.\"\"\"\n amicable_numbers = set()\n \n for number in range(2, limit + 1):\n if number in amicable_numbers:\n continue # Skip if already found to be amicable\n \n partner = sum_of_divisors(number)\n if partner != number and sum_of_divisors(partner) == number:\n amicable_numbers.add(number)\n amicable_numbers.add(partner)\n \n return sum(amicable_numbers)", "matching_cluster_idx": 11}, {"solution": "def sum_of_divisors(n):\n \"\"\"Returns the sum of proper divisors of n.\"\"\"\n total = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n total += i\n if i != 1 and i != n // i:\n total += n // i\n return total\ndef amicable_numbers_sum(limit):\n \"\"\"Returns the sum of all amicable numbers from 1 to limit.\"\"\"\n amicable_numbers = set()\n \n for number in range(2, limit + 1):\n if number not in amicable_numbers:\n partner = sum_of_divisors(number)\n if partner != number and sum_of_divisors(partner) == number:\n amicable_numbers.add(number)\n amicable_numbers.add(partner)\n\n return sum(amicable_numbers)", "matching_cluster_idx": 11}, {"solution": "def divisor_sum(n):\n \"\"\"Return the sum of proper divisors of n.\"\"\"\n total = 1 # 1 is a proper divisor of any number\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n total += i\n if i != n // i: # Avoid adding the square root twice\n total += n // i\n return total\ndef amicable_numbers_sum(limit):\n \"\"\"Return the sum of all amicable numbers under the limit.\"\"\"\n amicable_numbers = set()\n\n for num in range(2, limit + 1):\n if num not in amicable_numbers:\n partner = divisor_sum(num)\n if partner != num and divisor_sum(partner) == num:\n amicable_numbers.add(num)\n amicable_numbers.add(partner)\n\n return sum(amicable_numbers)", "matching_cluster_idx": 11}]}, "Mbpp/128": {"dps": 99.5475113122172, "dps_norm": 80.0, "pass@1": 100.0, "profiled": [{"solution": "def long_words(n, sentence):\n \"\"\"\n Find words that are longer than n characters from the given sentence.\n \n Parameters:\n n (int): The length threshold.\n sentence (str): A string of words.\n\n Returns:\n list: A list of words longer than n characters.\n \"\"\"\n # Split the sentence into words\n words = sentence.split()\n # Filter and return words longer than n characters\n return [word for word in words if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n \"\"\"\n Find words longer than n characters from a given sentence.\n\n Parameters:\n n (int): The minimum length of words to find.\n sentence (str): A sentence containing words.\n\n Returns:\n list: A list of words longer than n characters.\n \"\"\"\n # Split the sentence into words\n words = sentence.split()\n \n # Filter words that are longer than n characters\n long_words_list = [word for word in words if len(word) > n]\n \n return long_words_list", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n \"\"\"\n Find words that are longer than n characters from a given sentence.\n \n Parameters:\n n (int): The length to compare against.\n sentence (str): The sentence from which to extract words.\n \n Returns:\n list: A list of words longer than n characters.\n \"\"\"\n # Split the sentence into words\n words = sentence.split()\n \n # Filter words longer than n characters\n longer_words = [word for word in words if len(word) > n]\n \n return longer_words", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n \"\"\"\n Find words longer than n characters from a given sentence.\n\n Parameters:\n n (int): The length to compare against.\n sentence (str): The input sentence from which to find long words.\n\n Returns:\n List[str]: A list of words longer than n characters.\n \"\"\"\n words = sentence.split() # Split the sentence into words\n return [word for word in words if len(word) > n] # Filter words longer than n", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n \"\"\"\n This function returns a list of words that are longer than n characters\n from the given sentence.\n \n Parameters:\n n (int): The minimum length of words to include in the result.\n sentence (str): The input sentence from which to extract words.\n \n Returns:\n list: A list of words longer than n characters.\n \"\"\"\n # Split the sentence into words\n words = sentence.split()\n \n # Filter and return the words longer than n characters\n return [word for word in words if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n # Split the sentence into words\n words = sentence.split()\n # Filter and return words longer than n characters\n return [word for word in words if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n \"\"\"\n This function finds all words longer than n characters in the provided sentence.\n\n Parameters:\n n (int): The minimum length of words to be included in the result.\n sentence (str): The input sentence from which to extract words.\n\n Returns:\n list: A list of words longer than n characters.\n \"\"\"\n words = sentence.split()\n return [word for word in words if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n \"\"\"\n Find words that are longer than n characters from a given sentence.\n\n Parameters:\n n (int): The minimum length of words to consider.\n sentence (str): The input sentence containing words.\n\n Returns:\n list: A list of words longer than n characters.\n \"\"\"\n # Split the sentence into words\n words = sentence.split()\n # Filter words that are longer than n characters\n long_words_list = [word for word in words if len(word) > n]\n return long_words_list", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n \"\"\"\n Find words that are longer than n characters from a given sentence.\n\n Parameters:\n n (int): The minimum length of words to find.\n sentence (str): The input sentence containing words.\n\n Returns:\n list: A list of words longer than n characters.\n \"\"\"\n # Split the sentence into words\n words = sentence.split()\n # Filter and return the words longer than n characters\n return [word for word in words if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, words):\n # Split the string into a list of words\n word_list = words.split()\n # Use a list comprehension to filter out words longer than n characters\n return [word for word in word_list if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n \"\"\"\n Returns a list of words longer than n characters from the given sentence.\n \n :param n: Integer representing the minimum length of words to include.\n :param sentence: A string containing the words to evaluate.\n :return: A list of words longer than n characters.\n \"\"\"\n # Split the sentence into words\n words = sentence.split()\n \n # Filter words that are longer than n characters\n result = [word for word in words if len(word) > n]\n \n return result", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n \"\"\"\n Returns a list of words longer than n characters from the given sentence.\n \n :param n: The length threshold for the words.\n :param sentence: A string containing words to evaluate.\n :return: A list of words longer than n characters.\n \"\"\"\n # Split the sentence into words\n words = sentence.split()\n # Filter and return the words longer than n characters\n return [word for word in words if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, words):\n # Split the words string into a list of individual words\n word_list = words.split()\n # Use a list comprehension to filter words longer than n characters\n return [word for word in word_list if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n \"\"\"\n Find words that are longer than n characters from a given sentence.\n\n Parameters:\n n (int): The length to compare against.\n sentence (str): The sentence containing words.\n\n Returns:\n list: A list of words longer than n characters.\n \"\"\"\n # Split the sentence into words\n words = sentence.split()\n # Filter words that are longer than n characters\n result = [word for word in words if len(word) > n]\n return result", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n \"\"\"\n Find words that are longer than n characters from a given sentence.\n \n Parameters:\n n (int): The minimum length of the words to find.\n sentence (str): The sentence containing the words.\n \n Returns:\n list: A list of words longer than n characters.\n \"\"\"\n # Split the sentence into words\n words = sentence.split()\n # Return a list of words longer than n characters\n return [word for word in words if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n \"\"\"\n This function finds all the words in a given sentence that are longer than n characters.\n\n :param n: An integer representing the minimum length of words to find.\n :param sentence: A string containing the words to evaluate.\n :return: A list of words that are longer than n characters.\n \"\"\"\n # Split the sentence into words\n words = sentence.split()\n # Filter and return the words longer than n characters\n return [word for word in words if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n \"\"\"\n Finds words longer than n characters from the given sentence.\n\n Parameters:\n n (int): The minimum length of words to find.\n sentence (str): The input sentence from which to find long words.\n\n Returns:\n list: A list of words longer than n characters.\n \"\"\"\n words = sentence.split()\n return [word for word in words if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n \"\"\"\n Find words that are longer than n characters from the given sentence.\n\n Parameters:\n n (int): The length threshold.\n sentence (str): The input sentence containing words.\n\n Returns:\n List[str]: A list of words longer than n characters.\n \"\"\"\n # Split the sentence into words\n words = sentence.split()\n # Use list comprehension to filter out words longer than n characters\n return [word for word in words if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n \"\"\"\n Find words that are longer than n characters from the given sentence.\n\n Parameters:\n n (int): The length to compare the words against.\n sentence (str): A string containing words separated by spaces.\n\n Returns:\n list: A list of words longer than n characters.\n \"\"\"\n # Split the sentence into words\n words = sentence.split()\n # Return words that are longer than n characters\n return [word for word in words if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n \"\"\"\n Find words that are longer than n characters from a given sentence.\n\n Parameters:\n n (int): The length threshold.\n sentence (str): The input sentence.\n\n Returns:\n List[str]: A list of words longer than n characters.\n \"\"\"\n # Split the sentence into words\n words = sentence.split()\n \n # Filter and return words longer than n characters\n return [word for word in words if len(word) > n]", "matching_cluster_idx": 3}]}, "Mbpp/129": {"dps": 87.30867346938776, "dps_norm": 98.33333333333333, "pass@1": 74.0, "profiled": [{"solution": "def magic_square_test(matrix):\n n = len(matrix)\n\n # Calculate the sum of the first row as the magic constant\n magic_constant = sum(matrix[0])\n\n # Check the sum of each row\n for row in matrix:\n if sum(row) != magic_constant:\n return False\n\n # Check the sum of each column\n for col in range(n):\n if sum(matrix[row][col] for row in range(n)) != magic_constant:\n return False\n\n # Check the sum of the main diagonal\n if sum(matrix[i][i] for i in range(n)) != magic_constant:\n return False\n\n # Check the sum of the secondary diagonal\n if sum(matrix[i][n - 1 - i] for i in range(n)) != magic_constant:\n return False\n\n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n n = len(matrix)\n \n # Calculate the sum of the first row\n magic_sum = sum(matrix[0])\n \n # Check the sum of each row\n for row in matrix:\n if sum(row) != magic_sum:\n return False\n \n # Check the sum of each column\n for col in range(n):\n if sum(matrix[row][col] for row in range(n)) != magic_sum:\n return False\n \n # Check the sum of the main diagonal\n if sum(matrix[i][i] for i in range(n)) != magic_sum:\n return False\n\n # Check the sum of the secondary diagonal\n if sum(matrix[i][n - 1 - i] for i in range(n)) != magic_sum:\n return False\n\n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n # Check if the matrix is not empty\n if not matrix or not all(len(row) == len(matrix) for row in matrix):\n return False\n \n n = len(matrix)\n magic_sum = sum(matrix[0]) # Calculate the magic sum from the first row\n\n # Check sums of each row\n for row in matrix:\n if sum(row) != magic_sum:\n return False\n\n # Check sums of each column\n for col in range(n):\n if sum(matrix[row][col] for row in range(n)) != magic_sum:\n return False\n\n # Check sums of the two diagonals\n if sum(matrix[i][i] for i in range(n)) != magic_sum:\n return False\n if sum(matrix[i][n - 1 - i] for i in range(n)) != magic_sum:\n return False\n\n return True", "matching_cluster_idx": 13}, {"solution": "def magic_square_test(matrix):\n # Check if the matrix is square\n n = len(matrix)\n for row in matrix:\n if len(row) != n:\n return False\n\n # Calculate the sum of the first row as the magic constant\n magic_sum = sum(matrix[0])\n\n # Check the sum of each row\n for row in matrix:\n if sum(row) != magic_sum:\n return False\n\n # Check the sum of each column\n for col in range(n):\n if sum(matrix[row][col] for row in range(n)) != magic_sum:\n return False\n\n # Check the sum of the main diagonal\n if sum(matrix[i][i] for i in range(n)) != magic_sum:\n return False\n\n # Check the sum of the anti-diagonal\n if sum(matrix[i][n - 1 - i] for i in range(n)) != magic_sum:\n return False\n\n return True", "matching_cluster_idx": 13}, {"solution": "def magic_square_test(matrix):\n # Get the size of the matrix\n n = len(matrix)\n \n # Calculate the sum of the first row as the magic sum\n magic_sum = sum(matrix[0])\n \n # Check the sum of each row\n for row in matrix:\n if sum(row) != magic_sum:\n return False\n \n # Check the sum of each column\n for col in range(n):\n if sum(matrix[row][col] for row in range(n)) != magic_sum:\n return False\n \n # Check the sum of the two diagonals\n if sum(matrix[i][i] for i in range(n)) != magic_sum:\n return False\n if sum(matrix[i][n - 1 - i] for i in range(n)) != magic_sum:\n return False\n \n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n n = len(matrix)\n\n # Calculate the sum of the first row to set as the magic sum\n magic_sum = sum(matrix[0])\n\n # Check the sums of each row\n for row in matrix:\n if sum(row) != magic_sum:\n return False\n\n # Check the sums of each column\n for col in range(n):\n if sum(matrix[row][col] for row in range(n)) != magic_sum:\n return False\n\n # Check the sum of the main diagonal\n if sum(matrix[i][i] for i in range(n)) != magic_sum:\n return False\n\n # Check the sum of the secondary diagonal\n if sum(matrix[i][n - 1 - i] for i in range(n)) != magic_sum:\n return False\n\n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n n = len(matrix)\n if n == 0 or any(len(row) != n for row in matrix):\n return False # Not a square matrix\n\n magic_sum = sum(matrix[0]) # Sum of the first row\n\n # Check sums of rows\n for row in matrix:\n if sum(row) != magic_sum:\n return False\n\n # Check sums of columns\n for col in range(n):\n if sum(matrix[row][col] for row in range(n)) != magic_sum:\n return False\n\n # Check sum of diagonals\n if sum(matrix[i][i] for i in range(n)) != magic_sum:\n return False\n if sum(matrix[i][n - 1 - i] for i in range(n)) != magic_sum:\n return False\n\n return True", "matching_cluster_idx": 13}, {"solution": "def magic_square_test(matrix):\n n = len(matrix) # Size of the square matrix\n\n # Calculate the sum of the first row\n magic_sum = sum(matrix[0])\n \n # Check sums of rows\n for row in matrix:\n if sum(row) != magic_sum:\n return False\n \n # Check sums of columns\n for col in range(n):\n if sum(matrix[row][col] for row in range(n)) != magic_sum:\n return False\n \n # Check sum of the main diagonal\n if sum(matrix[i][i] for i in range(n)) != magic_sum:\n return False\n \n # Check sum of the secondary diagonal\n if sum(matrix[i][n - 1 - i] for i in range(n)) != magic_sum:\n return False\n \n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n if not matrix or len(matrix) != len(matrix[0]):\n return False # Not a square matrix\n\n n = len(matrix)\n magic_sum = sum(matrix[0]) # Sum of the first row\n\n # Check sums of each row\n for row in matrix:\n if sum(row) != magic_sum:\n return False\n\n # Check sums of each column\n for col in range(n):\n if sum(matrix[row][col] for row in range(n)) != magic_sum:\n return False\n\n # Check sums of the two diagonals\n if sum(matrix[i][i] for i in range(n)) != magic_sum:\n return False\n if sum(matrix[i][n - 1 - i] for i in range(n)) != magic_sum:\n return False\n\n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n n = len(matrix)\n \n # Calculate the magic sum (sum of the first row)\n magic_sum = sum(matrix[0])\n \n # Check sum of each row\n for row in matrix:\n if sum(row) != magic_sum:\n return False\n \n # Check sum of each column\n for col in range(n):\n if sum(matrix[row][col] for row in range(n)) != magic_sum:\n return False\n \n # Check sum of the main diagonal\n if sum(matrix[i][i] for i in range(n)) != magic_sum:\n return False\n \n # Check sum of the secondary diagonal\n if sum(matrix[i][n - 1 - i] for i in range(n)) != magic_sum:\n return False\n \n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n # Check if the matrix is square\n if not matrix or len(matrix) != len(matrix[0]):\n return False\n \n n = len(matrix)\n magic_sum = sum(matrix[0]) # The sum of the first row\n \n # Check the sum of each row\n for row in matrix:\n if sum(row) != magic_sum:\n return False\n \n # Check the sum of each column\n for col in range(n):\n if sum(matrix[row][col] for row in range(n)) != magic_sum:\n return False\n \n # Check the sum of the main diagonal\n if sum(matrix[i][i] for i in range(n)) != magic_sum:\n return False\n \n # Check the sum of the anti diagonal\n if sum(matrix[i][n - 1 - i] for i in range(n)) != magic_sum:\n return False\n \n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n n = len(matrix)\n \n # Calculate the sum of the first row to use as reference\n magic_sum = sum(matrix[0])\n \n # Check the sum of each row\n for row in matrix:\n if sum(row) != magic_sum:\n return False\n \n # Check the sum of each column\n for col in range(n):\n if sum(matrix[row][col] for row in range(n)) != magic_sum:\n return False\n \n # Check the sum of the main diagonal\n if sum(matrix[i][i] for i in range(n)) != magic_sum:\n return False\n \n # Check the sum of the secondary diagonal\n if sum(matrix[i][n - 1 - i] for i in range(n)) != magic_sum:\n return False\n \n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n # Calculate the sum of the first row\n n = len(matrix)\n magic_sum = sum(matrix[0])\n\n # Check each row sum\n for row in matrix:\n if sum(row) != magic_sum:\n return False\n\n # Check each column sum\n for col in range(n):\n if sum(matrix[row][col] for row in range(n)) != magic_sum:\n return False\n\n # Check the main diagonal sum\n if sum(matrix[i][i] for i in range(n)) != magic_sum:\n return False\n\n # Check the secondary diagonal sum\n if sum(matrix[i][n - 1 - i] for i in range(n)) != magic_sum:\n return False\n\n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n n = len(matrix)\n \n # Check if the matrix is square\n if any(len(row) != n for row in matrix):\n return False\n \n # Calculate the magic sum (sum of the first row)\n magic_sum = sum(matrix[0])\n \n # Check the sum of each row\n for row in matrix:\n if sum(row) != magic_sum:\n return False\n \n # Check the sum of each column\n for col in range(n):\n if sum(matrix[row][col] for row in range(n)) != magic_sum:\n return False\n \n # Check the sum of the main diagonal\n if sum(matrix[i][i] for i in range(n)) != magic_sum:\n return False\n \n # Check the sum of the secondary diagonal\n if sum(matrix[i][n - 1 - i] for i in range(n)) != magic_sum:\n return False\n \n return True", "matching_cluster_idx": 13}, {"solution": "def magic_square_test(matrix):\n n = len(matrix)\n\n # Calculate the sum of the first row\n magic_sum = sum(matrix[0])\n\n # Check the sum of each row\n for row in matrix:\n if sum(row) != magic_sum:\n return False\n\n # Check the sum of each column\n for col in range(n):\n if sum(matrix[row][col] for row in range(n)) != magic_sum:\n return False\n\n # Check the sum of the main diagonal\n if sum(matrix[i][i] for i in range(n)) != magic_sum:\n return False\n\n # Check the sum of the secondary diagonal\n if sum(matrix[i][n - 1 - i] for i in range(n)) != magic_sum:\n return False\n\n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n n = len(matrix)\n \n # Calculate the sum of the first row to use as the magic constant\n magic_sum = sum(matrix[0])\n \n # Check the sum of each row\n for row in matrix:\n if sum(row) != magic_sum:\n return False\n \n # Check the sum of each column\n for col in range(n):\n if sum(matrix[row][col] for row in range(n)) != magic_sum:\n return False\n \n # Check the sum of the main diagonal\n if sum(matrix[i][i] for i in range(n)) != magic_sum:\n return False\n \n # Check the sum of the anti-diagonal\n if sum(matrix[i][n - 1 - i] for i in range(n)) != magic_sum:\n return False\n \n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n if not matrix or len(matrix) != len(matrix[0]):\n return False # Not a square matrix\n\n n = len(matrix)\n magic_sum = sum(matrix[0]) # Sum of the first row\n\n # Check the sums of each row\n for row in matrix:\n if sum(row) != magic_sum:\n return False\n\n # Check the sums of each column\n for col in range(n):\n if sum(matrix[row][col] for row in range(n)) != magic_sum:\n return False\n\n # Check the sum of the main diagonal\n if sum(matrix[i][i] for i in range(n)) != magic_sum:\n return False\n\n # Check the sum of the secondary diagonal\n if sum(matrix[i][n - 1 - i] for i in range(n)) != magic_sum:\n return False\n\n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n # Get the size of the matrix\n n = len(matrix)\n \n # Calculate the magic sum (the sum of the first row)\n magic_sum = sum(matrix[0])\n \n # Check the sum of each row\n for row in matrix:\n if sum(row) != magic_sum:\n return False\n \n # Check the sum of each column\n for col in range(n):\n if sum(matrix[row][col] for row in range(n)) != magic_sum:\n return False\n \n # Check the sum of the main diagonal\n if sum(matrix[i][i] for i in range(n)) != magic_sum:\n return False\n \n # Check the sum of the secondary diagonal\n if sum(matrix[i][n - 1 - i] for i in range(n)) != magic_sum:\n return False\n \n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n n = len(matrix)\n \n # Calculate the sum of the first row to set as the magic constant\n magic_sum = sum(matrix[0])\n \n # Check the sum of each row\n for row in matrix:\n if sum(row) != magic_sum:\n return False\n \n # Check the sum of each column\n for col in range(n):\n if sum(matrix[row][col] for row in range(n)) != magic_sum:\n return False\n\n # Check the sum of the main diagonal\n if sum(matrix[i][i] for i in range(n)) != magic_sum:\n return False\n\n # Check the sum of the secondary diagonal\n if sum(matrix[i][n - 1 - i] for i in range(n)) != magic_sum:\n return False\n\n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n if not matrix or not all(len(row) == len(matrix) for row in matrix):\n return False # Not a square matrix\n\n n = len(matrix)\n magic_sum = sum(matrix[0]) # The magic constant sum\n\n # Check rows\n for row in matrix:\n if sum(row) != magic_sum:\n return False\n\n # Check columns\n for col in range(n):\n if sum(matrix[row][col] for row in range(n)) != magic_sum:\n return False\n\n # Check diagonals\n if sum(matrix[i][i] for i in range(n)) != magic_sum:\n return False\n if sum(matrix[i][n - 1 - i] for i in range(n)) != magic_sum:\n return False\n\n return True", "matching_cluster_idx": 13}]}, "Mbpp/130": {"dps": 77.10762331838565, "dps_norm": 68.33333333333334, "pass@1": 97.0, "profiled": [{"solution": "def max_occurrences(lst):\n if not lst:\n return None # Return None if the list is empty\n \n frequency = {}\n \n # Count the frequency of each item in the list\n for item in lst:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n \n # Find the item with the maximum frequency\n max_item = None\n max_count = 0\n \n for item, count in frequency.items():\n if count > max_count:\n max_count = count\n max_item = item\n \n return max_item", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(lst):\n \"\"\"\n Find the item with maximum frequency in the given list.\n \n Parameters:\n lst (list): A list of items.\n \n Returns:\n item: The item with the maximum frequency. If there are ties,\n the first one encountered in the list will be returned.\n \"\"\"\n frequency = {}\n \n for item in lst:\n frequency[item] = frequency.get(item, 0) + 1\n \n max_freq = 0\n max_item = None\n \n for item, count in frequency.items():\n if count > max_freq:\n max_freq = count\n max_item = item\n \n return max_item", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(lst):\n # Create a dictionary to count the frequency of each item\n frequency = {}\n \n for item in lst:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n \n # Find the item with the maximum frequency\n max_freq_item = None\n max_freq_count = 0\n \n for item, count in frequency.items():\n if count > max_freq_count:\n max_freq_count = count\n max_freq_item = item\n \n return max_freq_item", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(lst):\n # Create a dictionary to count occurrences of each item\n frequency = {}\n \n for item in lst:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n \n # Find the item with maximum frequency\n max_item = None\n max_count = 0\n \n for item, count in frequency.items():\n if count > max_count:\n max_count = count\n max_item = item\n \n return max_item", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(lst):\n \"\"\"Returns the item with the maximum frequency in the list.\"\"\"\n frequency = {}\n \n # Count the frequency of each item in the list\n for item in lst:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n \n # Find the item with the maximum frequency\n max_item = None\n max_count = 0\n for item, count in frequency.items():\n if count > max_count:\n max_count = count\n max_item = item\n \n return max_item", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(lst):\n frequency = {}\n \n # Count the frequency of each element in the list\n for item in lst:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n \n # Find the item with the maximum frequency\n max_item = None\n max_count = 0\n for item, count in frequency.items():\n if count > max_count:\n max_count = count\n max_item = item\n \n return max_item", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(lst):\n frequency_dict = {}\n \n # Count the occurrences of each item in the list\n for item in lst:\n if item in frequency_dict:\n frequency_dict[item] += 1\n else:\n frequency_dict[item] = 1\n \n # Find the item with the maximum frequency\n max_freq_item = None\n max_freq = 0\n \n for item, freq in frequency_dict.items():\n if freq > max_freq:\n max_freq = freq\n max_freq_item = item\n \n return max_freq_item", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(lst):\n # Create a dictionary to count the occurrences of each item\n frequency = {}\n \n # Count the frequency of each item in the list\n for item in lst:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n \n # Find the item with the maximum frequency\n max_freq_item = None\n max_freq_count = 0\n \n for item, count in frequency.items():\n if count > max_freq_count:\n max_freq_count = count\n max_freq_item = item\n \n return max_freq_item", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(lst):\n # Create a dictionary to count occurrences of each item\n frequency = {}\n \n for item in lst:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n \n # Find the item with the maximum frequency\n max_item = None\n max_count = 0\n \n for item, count in frequency.items():\n if count > max_count:\n max_count = count\n max_item = item\n \n return max_item", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(lst):\n frequency = {}\n \n # Count the frequency of each item in the list\n for item in lst:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n \n # Find the item with the maximum frequency\n max_freq_item = None\n max_freq_count = 0\n for item, count in frequency.items():\n if count > max_freq_count:\n max_freq_count = count\n max_freq_item = item\n \n return max_freq_item", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(lst):\n frequency = {}\n \n for item in lst:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n \n # Find the item with the maximum frequency\n max_item = None\n max_count = 0\n \n for item, count in frequency.items():\n if count > max_count:\n max_count = count\n max_item = item\n \n return max_item", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(lst):\n \"\"\"\n Returns the item with maximum frequency in the given list.\n If there are multiple items with the same maximum frequency,\n it returns the first one encountered.\n\n :param lst: List of elements (can be of any hashable type).\n :return: The element with the maximum frequency.\n \"\"\"\n frequency = {}\n \n # Count the frequency of each item in the list\n for item in lst:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n \n # Find the item with the maximum frequency\n max_item = None\n max_count = 0\n for item, count in frequency.items():\n if count > max_count:\n max_count = count\n max_item = item\n \n return max_item", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(lst):\n \"\"\"\n Finds the item with the maximum frequency in a given list.\n \n Parameters:\n lst (list): A list of elements.\n \n Returns:\n The element that occurs most frequently in the list.\n \"\"\"\n from collections import Counter\n\n # Count the frequency of each element in the list\n frequency = Counter(lst)\n \n # Find the item with the maximum frequency\n max_item = max(frequency.items(), key=lambda item: item[1])[0]\n \n return max_item", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(lst):\n \"\"\"\n This function returns the item with the maximum frequency in the given list.\n \n :param lst: List of elements\n :return: Element with maximum frequency\n \"\"\"\n frequency = {}\n \n # Count the frequency of each element in the list\n for item in lst:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n \n # Find the item with the maximum frequency\n max_freq_item = None\n max_freq_count = 0\n \n for item, count in frequency.items():\n if count > max_freq_count:\n max_freq_count = count\n max_freq_item = item\n \n return max_freq_item", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(lst):\n \"\"\"\n Function to find the item with maximum frequency in a given list.\n \n Parameters:\n lst (list): The input list from which to find the maximum frequency item.\n \n Returns:\n The item with the maximum frequency. If there are multiple items with the same frequency, \n it returns the first one found.\n \"\"\"\n frequency = {}\n \n # Count the frequency of each item in the list\n for item in lst:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n \n # Find the item with maximum frequency\n max_freq_item = None\n max_freq_count = 0\n \n for item, count in frequency.items():\n if count > max_freq_count:\n max_freq_count = count\n max_freq_item = item\n \n return max_freq_item", "matching_cluster_idx": 3}, {"solution": "from collections import Counter\ndef max_occurrences(lst):\n # Count the frequency of each item in the list\n frequency = Counter(lst)\n # Find the item with the maximum frequency\n max_item = max(frequency, key=frequency.get)\n return max_item", "matching_cluster_idx": 4}, {"solution": "def max_occurrences(lst):\n \"\"\"Return the item with the maximum frequency in the list.\"\"\"\n frequency = {}\n \n # Count the frequency of each item in the list\n for item in lst:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n \n # Find the item with the maximum frequency\n max_item = None\n max_count = 0\n \n for item, count in frequency.items():\n if count > max_count:\n max_count = count\n max_item = item\n \n return max_item", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(lst):\n \"\"\"\n Returns the item with the maximum frequency in the given list.\n If there are multiple items with the same maximum frequency, \n it returns the first one that reaches that maximum.\n\n Args:\n lst (list): The list of items to check.\n\n Returns:\n item: The item with the maximum frequency.\n \"\"\"\n frequency = {}\n \n for item in lst:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n \n max_freq = 0\n max_item = None\n \n for item, count in frequency.items():\n if count > max_freq:\n max_freq = count\n max_item = item\n \n return max_item", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(lst):\n \"\"\"Find the item with maximum frequency in the given list.\"\"\"\n frequency = {}\n \n # Count the frequency of each item in the list\n for item in lst:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n \n # Find the item with the maximum frequency\n max_freq_item = max(frequency, key=frequency.get)\n \n return max_freq_item", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(lst):\n \"\"\"\n This function finds the item with maximum frequency in a given list.\n \n Parameters:\n lst (list): A list of items (can be of any type).\n \n Returns:\n The item with the maximum frequency.\n \"\"\"\n from collections import Counter\n\n if not lst:\n return None # Return None if the list is empty\n\n # Count occurrences of each item in the list\n frequency = Counter(lst)\n\n # Find the item with the maximum frequency\n max_item = max(frequency, key=frequency.get)\n\n return max_item", "matching_cluster_idx": 4}]}, "Mbpp/137": {"dps": 9.354838709677418, "dps_norm": 24.375, "pass@1": 91.0, "profiled": [{"solution": "import math\ndef zero_count(arr):\n zeroes = sum(1 for x in arr if x == 0)\n non_zeroes = sum(1 for x in arr if x != 0)\n \n if non_zeroes == 0:\n return float('inf') # Return infinity if there are no non-zero elements\n \n return zeroes / non_zeroes", "matching_cluster_idx": 1}, {"solution": "import math\ndef zero_count(arr):\n \"\"\"\n Calculate the ratio of zeroes to non-zeroes in an array of integers.\n\n Parameters:\n arr (list): A list of integers.\n\n Returns:\n float: The ratio of zeroes to non-zeroes.\n \"\"\"\n zeroes = sum(1 for x in arr if x == 0)\n non_zeroes = sum(1 for x in arr if x != 0)\n\n if non_zeroes == 0:\n return float('inf') # or raise an exception depending on desired behavior\n\n return zeroes / non_zeroes", "matching_cluster_idx": 1}, {"solution": "import math\ndef zero_count(arr):\n zeroes = sum(1 for x in arr if x == 0)\n non_zeroes = sum(1 for x in arr if x != 0)\n \n if non_zeroes == 0: # To handle the case where there are no non-zeroes\n return float('inf') # Returning infinity if there are no non-zeroes\n \n return zeroes / non_zeroes", "matching_cluster_idx": 1}, {"solution": "import math\ndef zero_count(arr):\n zeroes = sum(1 for x in arr if x == 0)\n non_zeroes = sum(1 for x in arr if x != 0)\n\n if non_zeroes == 0:\n return float('inf') # Return infinity if there are no non-zeroes\n return zeroes / non_zeroes", "matching_cluster_idx": 1}, {"solution": "import math\ndef zero_count(arr):\n zeroes = sum(1 for x in arr if x == 0)\n non_zeroes = sum(1 for x in arr if x != 0)\n \n if non_zeroes == 0:\n return float('inf') # Handle the case when there are no non-zeroes\n return zeroes / non_zeroes", "matching_cluster_idx": 1}, {"solution": "import math\ndef zero_count(arr):\n zeroes = sum(1 for x in arr if x == 0)\n non_zeroes = sum(1 for x in arr if x != 0)\n\n if non_zeroes == 0:\n return float('inf') # Return infinity if there are no non-zeroes\n\n return zeroes / non_zeroes", "matching_cluster_idx": 1}, {"solution": "import math\ndef zero_count(arr):\n zeroes = sum(1 for x in arr if x == 0)\n non_zeroes = sum(1 for x in arr if x != 0)\n \n # Avoid division by zero\n if non_zeroes == 0:\n return float('inf') if zeroes > 0 else 0.0\n \n ratio = zeroes / non_zeroes\n return ratio", "matching_cluster_idx": 1}, {"solution": "import math\ndef zero_count(arr):\n zeroes = sum(1 for x in arr if x == 0)\n non_zeroes = sum(1 for x in arr if x != 0)\n\n # Avoid division by zero\n if non_zeroes == 0:\n return float('inf') # or you may return None or any other indication\n\n return zeroes / non_zeroes", "matching_cluster_idx": 1}, {"solution": "import math\ndef zero_count(arr):\n zeroes = sum(1 for x in arr if x == 0)\n non_zeroes = sum(1 for x in arr if x != 0)\n \n # Avoid division by zero\n if non_zeroes == 0:\n return float('inf') # or return None, or handle as appropriate\n \n return zeroes / non_zeroes", "matching_cluster_idx": 0}, {"solution": "import math\ndef zero_count(arr):\n zeroes = sum(1 for x in arr if x == 0)\n non_zeroes = sum(1 for x in arr if x != 0)\n \n if non_zeroes == 0:\n return float('inf') # or some indication of no non-zero numbers, depends on use case\n \n return zeroes / non_zeroes", "matching_cluster_idx": 1}, {"solution": "import math\ndef zero_count(arr):\n \"\"\"\n Calculate the ratio of zeroes to non-zeroes in an array of integers.\n\n Parameters:\n arr (list): List of integers\n\n Returns:\n float: The ratio of zeroes to non-zeroes\n \"\"\"\n zeroes = sum(1 for x in arr if x == 0)\n non_zeroes = sum(1 for x in arr if x != 0)\n \n if non_zeroes == 0:\n return float('inf') # or return None or a specific value if there are no non-zeroes\n \n return zeroes / non_zeroes", "matching_cluster_idx": 1}, {"solution": "import math\ndef zero_count(arr):\n \"\"\"\n Calculate the ratio of zeros to non-zeros in the given array of integers.\n\n Parameters:\n arr (list of int): The input array of integers.\n\n Returns:\n float: The ratio of zeros to non-zeros.\n \"\"\"\n zeroes = sum(1 for x in arr if x == 0)\n non_zeroes = sum(1 for x in arr if x != 0)\n\n # Avoid division by zero\n if non_zeroes == 0:\n return float('inf') # or handle as per requirements\n\n return zeroes / non_zeroes", "matching_cluster_idx": 1}, {"solution": "import math\ndef zero_count(arr):\n zeroes = sum(1 for x in arr if x == 0)\n non_zeroes = sum(1 for x in arr if x != 0)\n \n if non_zeroes == 0:\n return float('inf') # If there are no non-zeroes, return infinity\n return zeroes / non_zeroes", "matching_cluster_idx": 1}, {"solution": "import math\ndef zero_count(arr):\n \"\"\"\n Calculate the ratio of zeroes to non-zeroes in an array of integers.\n\n Parameters:\n arr (list): A list of integers.\n\n Returns:\n float: The ratio of zeroes to non-zeroes. If there are no non-zeroes, returns float('inf').\n \"\"\"\n zeroes = sum(1 for x in arr if x == 0)\n non_zeroes = sum(1 for x in arr if x != 0)\n\n if non_zeroes == 0:\n return float('inf') # Return infinity if there are no non-zeroes to avoid division by zero.\n\n return zeroes / non_zeroes", "matching_cluster_idx": 1}, {"solution": "import math\ndef zero_count(arr):\n \"\"\"\n Function to calculate the ratio of zeroes to non-zeroes in an array of integers.\n \n Parameters:\n arr (list of int): The input array of integers.\n \n Returns:\n float: The ratio of zeroes to non-zeroes. If there are no non-zeroes, returns float('inf').\n \"\"\"\n zeroes = sum(1 for x in arr if x == 0)\n non_zeroes = sum(1 for x in arr if x != 0)\n \n if non_zeroes == 0:\n return float('inf') # Return infinity if there are no non-zeroes.\n \n return zeroes / non_zeroes", "matching_cluster_idx": 1}, {"solution": "import math\ndef zero_count(arr):\n zeroes = sum(1 for x in arr if x == 0)\n non_zeroes = sum(1 for x in arr if x != 0)\n \n if non_zeroes == 0:\n return float('inf') # Handle the case where there are no non-zeroes\n return zeroes / non_zeroes", "matching_cluster_idx": 1}, {"solution": "import math\ndef zero_count(arr):\n zeroes = sum(1 for x in arr if x == 0)\n non_zeroes = sum(1 for x in arr if x != 0)\n \n if non_zeroes == 0:\n return float('inf') # Avoid division by zero; can also return None based on your requirement\n else:\n return zeroes / non_zeroes", "matching_cluster_idx": 1}, {"solution": "import math\ndef zero_count(arr):\n zeroes = sum(1 for x in arr if x == 0)\n non_zeroes = sum(1 for x in arr if x != 0)\n\n # To avoid division by zero, we handle the case where non_zeroes is zero.\n if non_zeroes == 0:\n return float('inf') # or return None, depending on the desired behavior\n \n return zeroes / non_zeroes", "matching_cluster_idx": 1}, {"solution": "import math\ndef zero_count(arr):\n zeroes = sum(1 for x in arr if x == 0)\n non_zeroes = sum(1 for x in arr if x != 0)\n\n # Avoid division by zero\n if non_zeroes == 0:\n return float('inf') if zeroes > 0 else 0.0\n\n return zeroes / non_zeroes", "matching_cluster_idx": 1}, {"solution": "import math\ndef zero_count(arr):\n zeroes = sum(1 for x in arr if x == 0)\n non_zeroes = sum(1 for x in arr if x != 0)\n \n if non_zeroes == 0:\n return float('inf') # Handle the case where there are no non-zeroes\n return zeroes / non_zeroes", "matching_cluster_idx": 1}]}, "Mbpp/140": {"dps": 89.06832298136646, "dps_norm": 84.375, "pass@1": 100.0, "profiled": [{"solution": "def extract_singly(lst):\n # Flatten the list of tuples and convert to a set to remove duplicates\n return {item for sublist in lst for item in sublist}", "matching_cluster_idx": 5}, {"solution": "def extract_singly(nested_list):\n \"\"\"Flatten the list of lists (or tuples) into a single set of numbers.\"\"\"\n flat_set = set()\n for sublist in nested_list:\n flat_set.update(sublist) # Add each number in the sublist to the set\n return flat_set", "matching_cluster_idx": 7}, {"solution": "def extract_singly(nested_list):\n \"\"\"Flatten a list of tuples into a single set of numbers.\"\"\"\n return {num for tup in nested_list for num in tup}", "matching_cluster_idx": 5}, {"solution": "def extract_singly(list_of_tuples):\n \"\"\"Flatten a list of tuples into a single set of numbers.\"\"\"\n result_set = set()\n for tpl in list_of_tuples:\n result_set.update(tpl) # Add elements of the tuple to the set\n return result_set", "matching_cluster_idx": 7}, {"solution": "def extract_singly(nested_list):\n \"\"\"\n Flattens a list of lists (or tuples) into a single set of numbers.\n\n Args:\n nested_list (list): A list of lists or tuples containing numbers.\n\n Returns:\n set: A set containing all unique numbers from the nested list.\n \"\"\"\n # Use a set comprehension to flatten the list and remove duplicates\n return {num for sublist in nested_list for num in sublist}", "matching_cluster_idx": 5}, {"solution": "def extract_singly(lst):\n # Flatten the list of tuples and create a set to ensure uniqueness\n return set(num for tup in lst for num in tup)", "matching_cluster_idx": 5}, {"solution": "def extract_singly(list_of_tuples):\n # Use a set comprehension to flatten the list of tuples into a single set\n return {num for tup in list_of_tuples for num in tup}", "matching_cluster_idx": 5}, {"solution": "def extract_singly(nested_lists):\n # Flatten the list of tuples into a single set of numbers\n return set(number for tup in nested_lists for number in tup)", "matching_cluster_idx": 5}, {"solution": "def extract_singly(list_of_tuples):\n \"\"\"\n Flattens a list of tuples into a single set of unique numbers.\n \n Parameters:\n list_of_tuples (list of tuples): The input list containing tuples of numbers.\n\n Returns:\n set: A set containing unique numbers from the input tuples.\n \"\"\"\n # Use a set comprehension to extract unique numbers from the tuples\n return {num for tup in list_of_tuples for num in tup}", "matching_cluster_idx": 5}, {"solution": "def extract_singly(list_of_tuples):\n \"\"\"\n Flattens a list of tuples into a single set of numbers.\n\n Args:\n list_of_tuples (list of tuples): A list containing tuples of integers.\n\n Returns:\n set: A set containing all unique integers from the tuples.\n \"\"\"\n flat_set = set()\n for tup in list_of_tuples:\n flat_set.update(tup)\n return flat_set", "matching_cluster_idx": 7}, {"solution": "def extract_singly(list_of_tuples):\n \"\"\"\n Flattens a list of tuples into a single set of numbers.\n \n Args:\n list_of_tuples (list of tuple): A list where each element is a tuple of numbers.\n \n Returns:\n set: A set containing all unique numbers from the input tuples.\n \"\"\"\n flattened_set = set()\n for tup in list_of_tuples:\n flattened_set.update(tup)\n return flattened_set", "matching_cluster_idx": 7}, {"solution": "def extract_singly(list_of_lists):\n \"\"\"Flattens a list of tuples/lists into a single set of numbers.\"\"\"\n flattened_set = set()\n for sublist in list_of_lists:\n flattened_set.update(sublist)\n return flattened_set", "matching_cluster_idx": 7}, {"solution": "def extract_singly(list_of_lists):\n # Initialize an empty set to collect unique numbers\n unique_numbers = set()\n \n # Iterate through each tuple in the list of lists\n for sublist in list_of_lists:\n # Add each number in the tuple to the set\n unique_numbers.update(sublist)\n \n return unique_numbers", "matching_cluster_idx": 7}, {"solution": "def extract_singly(list_of_tuples):\n \"\"\"\n Flatten the list of tuples into a single set of numbers.\n \n Args:\n list_of_tuples (list of tuples): A list containing tuples of integers.\n \n Returns:\n set: A set containing unique integers from all tuples.\n \"\"\"\n # Use a set comprehension to extract unique integers from each tuple\n return {num for tup in list_of_tuples for num in tup}", "matching_cluster_idx": 5}, {"solution": "def extract_singly(nested):\n \"\"\"\n Flatten a list of lists (or tuples) into a single set of numbers.\n\n Parameters:\n nested (list of lists or tuples): The input nested structure.\n\n Returns:\n set: A set containing the unique numbers from the input.\n \"\"\"\n # Use a set comprehension to flatten the input and ensure uniqueness\n return {num for sublist in nested for num in sublist}", "matching_cluster_idx": 5}, {"solution": "def extract_singly(nested):\n \"\"\"\n This function takes a list of lists or tuples and flattens it into a single set of numbers.\n \n :param nested: A list of lists or tuples containing numbers.\n :return: A set of unique numbers extracted from the nested structure.\n \"\"\"\n result_set = set()\n for sublist in nested:\n result_set.update(sublist)\n return result_set", "matching_cluster_idx": 7}, {"solution": "def extract_singly(list_of_tuples):\n # Flatten the list of tuples and convert to set to extract unique numbers\n return set(num for tup in list_of_tuples for num in tup)", "matching_cluster_idx": 5}, {"solution": "def extract_singly(nested_list):\n # Use a set to hold unique values\n unique_numbers = set()\n \n # Iterate through each tuple in the nested list\n for sublist in nested_list:\n # Add each number to the set\n unique_numbers.update(sublist)\n \n return unique_numbers", "matching_cluster_idx": 6}, {"solution": "def extract_singly(nested_list):\n \"\"\"\n Flattens a list of tuples/lists into a single set of unique numbers.\n\n Parameters:\n nested_list (list of tuples or lists): The input list containing tuples or lists of numbers.\n\n Returns:\n set: A set containing unique numbers from the input list.\n \"\"\"\n # Use a set comprehension to flatten the list and store unique numbers\n return {num for sublist in nested_list for num in sublist}", "matching_cluster_idx": 5}, {"solution": "def extract_singly(list_of_tuples):\n # Use a set comprehension to extract unique numbers from the list of tuples\n return {num for tup in list_of_tuples for num in tup}", "matching_cluster_idx": 5}]}, "Mbpp/141": {"dps": 68.63945578231294, "dps_norm": 41.875, "pass@1": 95.0, "profiled": [{"solution": "def flip(arr, k):\n \"\"\"Reverse the elements of arr from the start to the k-th index.\"\"\"\n return arr[:k+1][::-1] + arr[k+1:]\ndef find_max_index(arr, n):\n \"\"\"Find the index of the maximum element in arr[:n].\"\"\"\n max_index = 0\n for i in range(1, n):\n if arr[i] > arr[max_index]:\n max_index = i\n return max_index\ndef pancake_sort(arr):\n \"\"\"Sort the list arr using pancake sort algorithm.\"\"\"\n n = len(arr)\n for i in range(n, 1, -1):\n # Find index of the maximum element in arr[0..i]\n max_index = find_max_index(arr, i)\n\n # If max is not already at the last position, we need to flip\n if max_index != i - 1:\n # First flip to bring max number to the front if it's not already there\n if max_index != 0:\n arr = flip(arr, max_index)\n # Now flip it to put it at the end of the current unsorted array\n arr = flip(arr, i - 1)\n \n return arr", "matching_cluster_idx": 2}, {"solution": "def flip(arr, k):\n \"\"\"Reverse the order of the first k elements in the array.\"\"\"\n return arr[:k][::-1] + arr[k:]\ndef find_max_index(arr, n):\n \"\"\"Find the index of the maximum element in arr[0..n].\"\"\"\n max_idx = 0\n for i in range(1, n):\n if arr[i] > arr[max_idx]:\n max_idx = i\n return max_idx\ndef pancake_sort(arr):\n \"\"\"Sorts the array using pancake sort algorithm.\"\"\"\n n = len(arr)\n for curr_size in range(n, 1, -1):\n # Find the index of the maximum element in arr[0..curr_size-1]\n max_idx = find_max_index(arr, curr_size)\n \n # Move the maximum element to the end of the current array\n if max_idx != curr_size - 1:\n # Flip the maximum element to the front if it's not already there\n if max_idx != 0:\n arr = flip(arr, max_idx + 1)\n # Flip it to its final position\n arr = flip(arr, curr_size)\n \n return arr", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(arr):\n def flip(sub_arr, k):\n \"\"\"Helper function to reverse the order of the first k elements in sub_arr.\"\"\"\n return sub_arr[:k][::-1] + sub_arr[k:]\n\n n = len(arr)\n for i in range(n, 1, -1):\n # Find the index of the maximum element in arr[0..i]\n max_index = arr.index(max(arr[:i]))\n \n # Flip the maximum element to the front if it's not already at the front\n if max_index != 0:\n arr = flip(arr, max_index + 1)\n \n # Flip the maximum element to its final position\n arr = flip(arr, i)\n \n return arr", "matching_cluster_idx": 3}, {"solution": "def flip(arr, k):\n \"\"\"Flip the first k elements of the array.\"\"\"\n return arr[:k][::-1] + arr[k:]\ndef find_max_index(arr, n):\n \"\"\"Find the index of the maximum element in arr[0..n].\"\"\"\n max_idx = 0\n for i in range(1, n):\n if arr[i] > arr[max_idx]:\n max_idx = i\n return max_idx\ndef pancake_sort(arr):\n \"\"\"Sort the array using the pancake sorting algorithm.\"\"\"\n n = len(arr)\n \n for i in range(n, 1, -1):\n # Find index of the maximum element in arr[0..i]\n max_idx = find_max_index(arr, i)\n \n # Move the maximum element to the end of the current unsorted array\n if max_idx != i - 1:\n # Flip the maximum element to the front\n if max_idx != 0:\n arr = flip(arr, max_idx + 1)\n # Flip it to its correct position\n arr = flip(arr, i)\n\n return arr", "matching_cluster_idx": 2}, {"solution": "def flip(arr, k):\n \"\"\"Reverse the order of the first k elements in arr.\"\"\"\n return arr[:k][::-1] + arr[k:]\ndef find_max_index(arr, n):\n \"\"\"Find the index of the maximum element in arr up to the first n elements.\"\"\"\n max_index = 0\n for i in range(1, n):\n if arr[i] > arr[max_index]:\n max_index = i\n return max_index\ndef pancake_sort(arr):\n \"\"\"Sort the input list using the pancake sort algorithm.\"\"\"\n n = len(arr)\n \n for size in range(n, 1, -1):\n # Find the index of the maximum element in arr[0..size]\n max_index = find_max_index(arr, size)\n \n # Move the maximum number to the end of the current array size if it's not already at that position\n if max_index != size - 1:\n # Flip the maximum element to the front if it's not already at the front\n if max_index != 0:\n arr = flip(arr, max_index + 1)\n # Flip it to its final position\n arr = flip(arr, size)\n\n return arr", "matching_cluster_idx": 2}, {"solution": "def flip(arr, k):\n \"\"\"Helper function to flip the sub-array arr[0:k].\"\"\"\n return arr[:k][::-1] + arr[k:]\ndef find_max_index(arr, n):\n \"\"\"Find the index of the maximum element in arr[0:n].\"\"\"\n max_index = 0\n for i in range(1, n):\n if arr[i] > arr[max_index]:\n max_index = i\n return max_index\ndef pancake_sort(arr):\n \"\"\"Sort the list using pancake sort algorithm.\"\"\"\n n = len(arr)\n for i in range(n, 1, -1):\n # Find the index of the maximum element in arr[0:i]\n max_index = find_max_index(arr, i)\n \n # If the maximum is not at the last position\n if max_index != i - 1:\n # Flip the maximum element to the front if it's not already there\n if max_index != 0:\n arr = flip(arr, max_index + 1)\n # Now flip it to its final position\n arr = flip(arr, i)\n return arr", "matching_cluster_idx": 2}, {"solution": "def flip(arr, k):\n \"\"\"Reverses the order of the first k elements in the array.\"\"\"\n return arr[:k][::-1] + arr[k:]\ndef pancake_sort(arr):\n \"\"\"Sorts the array using pancake sort algorithm.\"\"\"\n n = len(arr)\n for size in range(n, 1, -1):\n # Find the index of the maximum element in arr[0..size-1]\n max_index = arr.index(max(arr[:size]))\n\n # Move the maximum element to the front if it's not already there\n if max_index != size - 1:\n # Flip the maximum element to the front\n arr = flip(arr, max_index + 1)\n # Now flip it to its correct position\n arr = flip(arr, size)\n return arr", "matching_cluster_idx": 3}, {"solution": "def flip(arr, k):\n \"\"\"Flip the array from start to k (inclusive).\"\"\"\n return arr[:k+1][::-1] + arr[k+1:]\ndef find_max_index(arr, n):\n \"\"\"Find the index of the maximum element in arr[0..n].\"\"\"\n max_index = 0\n for i in range(1, n):\n if arr[i] > arr[max_index]:\n max_index = i\n return max_index\ndef pancake_sort(arr):\n \"\"\"Sort the array using pancake sort algorithm.\"\"\"\n n = len(arr)\n for curr_size in range(n, 1, -1):\n # Find index of the maximum element in arr[0..curr_size-1]\n max_index = find_max_index(arr, curr_size)\n\n # Move the maximum element to the end of the current array if it's not already there\n if max_index != curr_size - 1:\n # Flip the maximum element to the front if it's not already there\n if max_index != 0:\n arr = flip(arr, max_index)\n # Flip it to its correct position\n arr = flip(arr, curr_size - 1)\n \n return arr", "matching_cluster_idx": 2}, {"solution": "def flip(arr, k):\n \"\"\"Reverse the order of the first k elements in the list.\"\"\"\n return arr[:k][::-1] + arr[k:]\ndef find_max_index(arr, n):\n \"\"\"Find the index of the maximum element in arr[0:n].\"\"\"\n max_index = 0\n for i in range(1, n):\n if arr[i] > arr[max_index]:\n max_index = i\n return max_index\ndef pancake_sort(arr):\n \"\"\"Sorts a list using the pancake sort algorithm.\"\"\"\n n = len(arr)\n # Start from the complete array and one by one reduce the size\n for curr_size in range(n, 1, -1):\n # Find index of the maximum element in arr[0..curr_size-1]\n max_index = find_max_index(arr, curr_size)\n \n # Move the maximum element to the end of the current array\n if max_index != curr_size - 1:\n # Flip the maximum element to the front\n if max_index != 0:\n arr = flip(arr, max_index + 1)\n # Flip it to its final position\n arr = flip(arr, curr_size)\n \n return arr", "matching_cluster_idx": 2}, {"solution": "def flip(arr, k):\n \"\"\"Helper function to reverse the order of elements in arr up to index k.\"\"\"\n return arr[:k + 1][::-1] + arr[k + 1:]\ndef find_max_index(arr, n):\n \"\"\"Find the index of the maximum element in arr up to index n.\"\"\"\n max_index = 0\n for i in range(1, n):\n if arr[i] > arr[max_index]:\n max_index = i\n return max_index\ndef pancake_sort(arr):\n \"\"\"Sorts an array using the pancake sort algorithm.\"\"\"\n n = len(arr)\n for current_size in range(n, 1, -1):\n max_index = find_max_index(arr, current_size)\n \n # Move the maximum number to the end of the current array\n if max_index != current_size - 1:\n # Flip the maximum number to the front\n if max_index != 0:\n arr = flip(arr, max_index)\n # Flip it to the end\n arr = flip(arr, current_size - 1)\n return arr", "matching_cluster_idx": 2}, {"solution": "def flip(arr, k):\n \"\"\"Reverses the order of the first k elements in arr.\"\"\"\n return arr[:k][::-1] + arr[k:]\ndef find_max_index(arr, n):\n \"\"\"Finds the index of the maximum element in arr up to the nth element.\"\"\"\n max_index = 0\n for i in range(1, n):\n if arr[i] > arr[max_index]:\n max_index = i\n return max_index\ndef pancake_sort(arr):\n \"\"\"Sorts the array using pancake sort algorithm.\"\"\"\n n = len(arr)\n for curr_size in range(n, 1, -1):\n # Find index of the maximum element in arr[0..curr_size-1]\n max_index = find_max_index(arr, curr_size)\n\n # Move the maximum element to the end of the current subarray\n if max_index != curr_size - 1:\n # Flip the maximum number to the front if it's not already there\n if max_index != 0:\n arr = flip(arr, max_index + 1)\n # Now flip it to the end of the current subarray\n arr = flip(arr, curr_size)\n return arr", "matching_cluster_idx": 2}, {"solution": "def flip(arr, k):\n \"\"\"Helper function to reverse the order of the first k elements in arr.\"\"\"\n return arr[:k][::-1] + arr[k:]\ndef pancake_sort(arr):\n \"\"\"Sorts the array using the pancake sort algorithm.\"\"\"\n n = len(arr)\n \n # Traverse the array from end to start\n for curr_size in range(n, 1, -1):\n # Find the index of the maximum element in arr[0..curr_size-1]\n max_index = arr.index(max(arr[:curr_size]))\n \n # Move the maximum element to the end of the current array\n if max_index != curr_size - 1:\n # First flip the maximum element to the front if it's not already there\n if max_index != 0:\n arr = flip(arr, max_index + 1)\n # Now flip the maximum element to the current end\n arr = flip(arr, curr_size)\n \n return arr", "matching_cluster_idx": 3}, {"solution": "def flip(arr, k):\n \"\"\"Helper function to reverse the order of the first k elements of arr.\"\"\"\n return arr[:k][::-1] + arr[k:]\ndef find_max_index(arr, n):\n \"\"\"Find the index of the maximum element in arr[0:n].\"\"\"\n max_index = 0\n for i in range(1, n):\n if arr[i] > arr[max_index]:\n max_index = i\n return max_index\ndef pancake_sort(arr):\n \"\"\"Sort the array using pancake sort algorithm.\"\"\"\n n = len(arr)\n for size in range(n, 1, -1):\n # Find index of the maximum element in arr[0:size]\n max_index = find_max_index(arr, size)\n \n # Move the maximum element to the end of the current array\n if max_index != size - 1:\n # Flip to move max element to the front if it's not already at the front\n if max_index != 0:\n arr = flip(arr, max_index + 1)\n # Flip the maximum element to its final position\n arr = flip(arr, size)\n \n return arr", "matching_cluster_idx": 2}, {"solution": "def flip(arr, k):\n \"\"\"Reverses the order of the first k elements in the array.\"\"\"\n return arr[:k][::-1] + arr[k:]\ndef pancake_sort(arr):\n \"\"\"Sorts the input list using the pancake sorting algorithm.\"\"\"\n n = len(arr)\n for size in range(n, 1, -1):\n # Find the index of the maximum element in arr[:size]\n max_index = arr.index(max(arr[:size]))\n \n # Move the maximum element to the front if it's not already there\n if max_index != size - 1:\n # Flip the maximum number to the front\n if max_index != 0:\n arr = flip(arr, max_index + 1)\n # Now flip it to its correct position\n arr = flip(arr, size)\n \n return arr", "matching_cluster_idx": 3}, {"solution": "def flip(arr, k):\n \"\"\"Reverse the order of the first k elements in the list.\"\"\"\n return arr[:k][::-1] + arr[k:]\ndef find_max_index(arr, n):\n \"\"\"Find the index of the maximum element in the first n elements.\"\"\"\n max_index = 0\n for i in range(1, n):\n if arr[i] > arr[max_index]:\n max_index = i\n return max_index\ndef pancake_sort(arr):\n \"\"\"Sort the array using pancake sorting algorithm.\"\"\"\n n = len(arr)\n \n # One by one move the maximum element to the end of the array\n for curr_size in range(n, 1, -1):\n # Find index of the maximum element in arr[0..curr_size-1]\n max_index = find_max_index(arr, curr_size)\n\n # Move the maximum element to the beginning of the array if it's not already there\n if max_index != curr_size - 1:\n # Flip the maximum element to the front\n if max_index != 0:\n arr = flip(arr, max_index + 1)\n # Flip it to its final position\n arr = flip(arr, curr_size)\n\n return arr", "matching_cluster_idx": 2}, {"solution": "def flip(arr, k):\n \"\"\"Helper function to reverse the first k elements of the list.\"\"\"\n return arr[:k][::-1] + arr[k:]\ndef pancake_sort(arr):\n \"\"\"Sorts the array using the pancake sort algorithm.\"\"\"\n n = len(arr)\n # One by one move the maximum element to the end of the list\n for i in range(n, 1, -1):\n # Find the index of the maximum element in arr[0..i]\n max_index = arr.index(max(arr[:i]))\n # Move the maximum element to the front if it's not already there\n if max_index != i - 1:\n # Flip the maximum element to the front\n arr = flip(arr, max_index + 1)\n # Now flip it to its final position\n arr = flip(arr, i)\n return arr", "matching_cluster_idx": 3}, {"solution": "def flip(arr, k):\n \"\"\"Helper function to reverse the first k elements of arr.\"\"\"\n return arr[:k][::-1] + arr[k:]\ndef find_max_index(arr, n):\n \"\"\"Function to find the index of the maximum element in arr.\"\"\"\n max_idx = 0\n for i in range(1, n):\n if arr[i] > arr[max_idx]:\n max_idx = i\n return max_idx\ndef pancake_sort(arr):\n \"\"\"Function to sort an array using the pancake sorting algorithm.\"\"\"\n n = len(arr)\n for curr_size in range(n, 1, -1):\n # Find index of the maximum element in arr[0..curr_size-1]\n max_idx = find_max_index(arr, curr_size)\n \n # Move the maximum element to the end of the current array size\n if max_idx != curr_size - 1:\n # Flip the maximum element to the front if it's not already there\n if max_idx != 0:\n arr = flip(arr, max_idx + 1)\n # Now flip the maximum element to its correct position\n arr = flip(arr, curr_size)\n \n return arr", "matching_cluster_idx": 2}, {"solution": "def flip(arr, k):\n \"\"\"Helper function to reverse the order of the first k elements in the array.\"\"\"\n return arr[:k][::-1] + arr[k:]\ndef pancake_sort(arr):\n \"\"\"Sorts the array using the pancake sort algorithm.\"\"\"\n n = len(arr)\n for i in range(n, 1, -1):\n # Find the index of the maximum element in the unsorted part of the array\n max_index = arr.index(max(arr[:i]))\n \n # If the maximum element is not already in place\n if max_index != i - 1:\n # Flip the maximum element to the front if it's not already there\n if max_index != 0:\n arr = flip(arr, max_index + 1)\n # Flip it to its correct position\n arr = flip(arr, i)\n return arr", "matching_cluster_idx": 3}, {"solution": "def flip(arr, k):\n \"\"\"Reverse the order of the first k elements in the array.\"\"\"\n return arr[:k][::-1] + arr[k:]\ndef pancake_sort(arr):\n \"\"\"Sort the list using the pancake sorting algorithm.\"\"\"\n n = len(arr)\n \n # Start from the complete array and reduce the size of the array\n for curr_size in range(n, 1, -1):\n # Find the index of the maximum element in arr[0..curr_size-1]\n max_index = arr.index(max(arr[0:curr_size]))\n \n # Move the maximum number to the beginning if it's not already there\n if max_index != curr_size - 1:\n # Flip the maximum number to the front if it's not already there\n if max_index != 0:\n arr = flip(arr, max_index + 1) # Flip to bring max to the front\n arr = flip(arr, curr_size) # Flip to move max to its correct position\n\n return arr", "matching_cluster_idx": 3}, {"solution": "def flip(arr, k):\n \"\"\"Reverse the order of the first k elements in the array.\"\"\"\n return arr[:k][::-1] + arr[k:]\ndef find_max_index(arr, n):\n \"\"\"Find the index of the maximum element in arr[0..n].\"\"\"\n max_index = 0\n for i in range(1, n):\n if arr[i] > arr[max_index]:\n max_index = i\n return max_index\ndef pancake_sort(arr):\n \"\"\"Sort the given list using the pancake sort algorithm.\"\"\"\n n = len(arr)\n # Start from the complete array and reduce the size one by one\n for curr_size in range(n, 1, -1):\n # Find index of the maximum element in arr[0..curr_size-1]\n max_index = find_max_index(arr, curr_size)\n\n # Move the maximum element to the end of the current array if it's not already there\n if max_index != curr_size - 1:\n # Flip the maximum number to the front if it's not already there\n if max_index != 0:\n arr = flip(arr, max_index + 1)\n # Now flip it to the end of the current array\n arr = flip(arr, curr_size)\n\n return arr", "matching_cluster_idx": 2}]}, "Mbpp/166": {"dps": 94.39999999999999, "dps_norm": 50.0, "pass@1": 100.0, "profiled": [{"solution": "def find_even_pair(nums):\n count = 0\n n = len(nums)\n \n # Check all pairs (i, j) with i < j\n for i in range(n):\n for j in range(i + 1, n):\n if (nums[i] ^ nums[j]) % 2 == 0:\n count += 1\n \n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(numbers):\n count = 0\n n = len(numbers)\n \n # Iterate through each pair of numbers\n for i in range(n):\n for j in range(i + 1, n):\n if (numbers[i] ^ numbers[j]) % 2 == 0: # Check if XOR is even\n count += 1\n \n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(numbers):\n count = 0\n n = len(numbers)\n \n # Check all pairs of integers in the list\n for i in range(n):\n for j in range(i + 1, n):\n if (numbers[i] ^ numbers[j]) % 2 == 0:\n count += 1\n \n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(nums):\n count = 0\n n = len(nums)\n \n # Iterate through all possible pairs (i, j)\n for i in range(n):\n for j in range(i + 1, n):\n if (nums[i] ^ nums[j]) % 2 == 0: # Check if the XOR is even\n count += 1\n \n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(lst):\n count = 0\n n = len(lst)\n \n # Iterate through all possible pairs\n for i in range(n):\n for j in range(i + 1, n):\n # Check if the XOR of the pair is even\n if (lst[i] ^ lst[j]) % 2 == 0:\n count += 1\n\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(nums):\n count = 0\n n = len(nums)\n \n # Loop through each pair of numbers\n for i in range(n):\n for j in range(i + 1, n):\n if (nums[i] ^ nums[j]) % 2 == 0:\n count += 1\n \n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(nums):\n count = 0\n n = len(nums)\n \n # Iterate over all pairs of integers in the list\n for i in range(n):\n for j in range(i + 1, n):\n # Calculate the XOR of the pair\n if (nums[i] ^ nums[j]) % 2 == 0:\n count += 1\n \n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(lst):\n count = 0\n n = len(lst)\n\n # Check each pair of integers\n for i in range(n):\n for j in range(i + 1, n):\n if (lst[i] ^ lst[j]) % 2 == 0:\n count += 1\n\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(numbers):\n count = 0\n n = len(numbers)\n \n # Check all pairs (i, j) with i < j\n for i in range(n):\n for j in range(i + 1, n):\n if (numbers[i] ^ numbers[j]) % 2 == 0:\n count += 1\n \n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(numbers):\n count = 0\n n = len(numbers)\n \n for i in range(n):\n for j in range(i + 1, n):\n if (numbers[i] ^ numbers[j]) % 2 == 0:\n count += 1\n \n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(arr):\n count = 0\n n = len(arr)\n \n # Check all pairs of elements\n for i in range(n):\n for j in range(i + 1, n):\n if (arr[i] ^ arr[j]) % 2 == 0:\n count += 1\n \n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(lst):\n count = 0\n n = len(lst)\n\n for i in range(n):\n for j in range(i + 1, n):\n if (lst[i] ^ lst[j]) % 2 == 0:\n count += 1\n\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(arr):\n count = 0\n n = len(arr)\n \n # Iterate over all possible pairs\n for i in range(n):\n for j in range(i + 1, n):\n if (arr[i] ^ arr[j]) % 2 == 0:\n count += 1\n \n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(numbers):\n count = 0\n n = len(numbers)\n \n # Check all pairs (i, j) where i < j\n for i in range(n):\n for j in range(i + 1, n):\n if (numbers[i] ^ numbers[j]) % 2 == 0:\n count += 1\n \n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(lst):\n count = 0\n n = len(lst)\n \n # Iterate over all unique pairs\n for i in range(n):\n for j in range(i + 1, n):\n if (lst[i] ^ lst[j]) % 2 == 0: # Check if XOR is even\n count += 1\n \n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(lst):\n count = 0\n n = len(lst)\n\n # Loop through each pair of integers in the list\n for i in range(n):\n for j in range(i + 1, n):\n if (lst[i] ^ lst[j]) % 2 == 0:\n count += 1\n\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(lst):\n count = 0\n n = len(lst)\n\n for i in range(n):\n for j in range(i + 1, n):\n if (lst[i] ^ lst[j]) % 2 == 0:\n count += 1\n\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(nums):\n \"\"\"\n Counts the number of pairs of integers in the list that XOR to an even number.\n\n Parameters:\n nums (list): A list of integers.\n\n Returns:\n int: The count of pairs that XOR to an even number.\n \"\"\"\n count = 0\n n = len(nums)\n \n # Check each pair (i, j) where i < j\n for i in range(n):\n for j in range(i + 1, n):\n if (nums[i] ^ nums[j]) % 2 == 0: # XOR is even if the last bit is 0\n count += 1\n\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(numbers):\n count = 0\n n = len(numbers)\n\n # Loop through each pair of numbers\n for i in range(n):\n for j in range(i + 1, n):\n if (numbers[i] ^ numbers[j]) % 2 == 0: # Check if XOR is even\n count += 1\n \n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(numbers):\n count = 0\n n = len(numbers)\n \n # Iterate through each pair of numbers\n for i in range(n):\n for j in range(i + 1, n):\n if (numbers[i] ^ numbers[j]) % 2 == 0:\n count += 1\n \n return count", "matching_cluster_idx": 1}]}, "Mbpp/170": {"dps": 96.4573268921095, "dps_norm": 99.30555555555556, "pass@1": 18.0, "profiled": [{"solution": "def sum_range_list(nums, start, end):\n \"\"\"\n Calculate the sum of numbers in a list from index start to index end (inclusive).\n\n Parameters:\n nums (list): A list of numbers.\n start (int): The starting index.\n end (int): The ending index.\n\n Returns:\n int: The sum of the numbers in the specified range.\n \"\"\"\n return sum(nums[start:end + 1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(numbers, start_index, end_index):\n \"\"\"\n Calculate the sum of numbers in a list from start_index to end_index (inclusive).\n\n :param numbers: List of numbers\n :param start_index: Starting index for the range\n :param end_index: Ending index for the range\n :return: Sum of the numbers in the specified range\n \"\"\"\n # Ensure the indices are within the bounds of the list\n if start_index < 0 or end_index >= len(numbers):\n raise IndexError(\"Index out of range\")\n\n # Calculate the sum in the specified range\n return sum(numbers[start_index:end_index + 1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(numbers, start_index, end_index):\n \"\"\"\n Calculate the sum of numbers in a list from start_index to end_index (inclusive).\n\n :param numbers: List of integers\n :param start_index: Starting index (inclusive)\n :param end_index: Ending index (inclusive)\n :return: Sum of the specified range of numbers\n \"\"\"\n if start_index < 0 or end_index >= len(numbers):\n raise IndexError(\"Index out of range.\")\n \n return sum(numbers[start_index:end_index + 1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(numbers, start_index, end_index):\n \"\"\"\n Calculate the sum of numbers in a list from start_index to end_index (inclusive).\n\n :param numbers: List of numbers\n :param start_index: Starting index (inclusive)\n :param end_index: Ending index (inclusive)\n :return: Sum of the numbers in the specified range\n \"\"\"\n return sum(numbers[start_index:end_index + 1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(lst, start, end):\n \"\"\"\n Calculate the sum of numbers in a list from index start to index end (inclusive).\n\n Parameters:\n lst (list): The list of numbers.\n start (int): The starting index (inclusive).\n end (int): The ending index (inclusive).\n\n Returns:\n int: The sum of the numbers in the specified range.\n \"\"\"\n return sum(lst[start:end + 1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(nums, start_index, end_index):\n \"\"\"\n Returns the sum of the numbers in the list `nums` from index `start_index` to `end_index`, inclusive.\n \n Parameters:\n nums (list): A list of numbers.\n start_index (int): The starting index of the range (inclusive).\n end_index (int): The ending index of the range (inclusive).\n \n Returns:\n int: The sum of the numbers in the specified range.\n \"\"\"\n return sum(nums[start_index:end_index + 1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(numbers, start_index, end_index):\n \"\"\"\n Sums the numbers in the list from start_index to end_index (inclusive).\n \n :param numbers: List of numbers\n :param start_index: Starting index (inclusive)\n :param end_index: Ending index (inclusive)\n :return: Sum of the numbers in the specified range\n \"\"\"\n # Slice the list and calculate the sum\n return sum(numbers[start_index:end_index + 1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(numbers, start_index, end_index):\n \"\"\"\n Returns the sum of numbers in the list `numbers` from index `start_index` to `end_index` (inclusive).\n \n :param numbers: List of numbers\n :param start_index: The starting index (inclusive)\n :param end_index: The ending index (inclusive)\n :return: Sum of the numbers from start_index to end_index\n \"\"\"\n # Ensure the indices are within the bounds of the list\n if start_index < 0 or end_index >= len(numbers):\n raise IndexError(\"Index out of range\")\n \n # Calculate the sum of the specified range\n return sum(numbers[start_index:end_index + 1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(numbers, start_index, end_index):\n \"\"\"\n Calculates the sum of elements in a list from start_index to end_index (inclusive).\n\n Args:\n numbers (list): A list of numbers.\n start_index (int): The starting index of the range.\n end_index (int): The ending index of the range.\n\n Returns:\n int: The sum of the numbers in the specified range.\n \"\"\"\n # Ensure the indices are within the range of the list\n if start_index < 0 or end_index >= len(numbers):\n raise IndexError(\"Index out of range.\")\n \n # Calculate the sum in the specified range\n return sum(numbers[start_index:end_index + 1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(numbers, start_index, end_index):\n \"\"\"\n Returns the sum of numbers in the list from start_index to end_index (inclusive).\n \n Parameters:\n - numbers (list): A list of numbers.\n - start_index (int): The starting index.\n - end_index (int): The ending index.\n \n Returns:\n - int: The sum of the numbers in the specified range.\n \"\"\"\n # Ensure indices are within the bounds of the list\n if start_index < 0 or end_index >= len(numbers):\n raise IndexError(\"Index out of range.\")\n \n # Calculate the sum of the specified range\n return sum(numbers[start_index:end_index + 1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(numbers, start_index, end_index):\n \"\"\"\n Returns the sum of numbers in the list from start_index to end_index (inclusive).\n \n Parameters:\n numbers (list): A list of numbers.\n start_index (int): The starting index of the range.\n end_index (int): The ending index of the range.\n \n Returns:\n int: The sum of the numbers in the specified range.\n \"\"\"\n # Check if indices are within bounds\n if start_index < 0 or end_index >= len(numbers):\n raise IndexError(\"Indices are out of bounds.\")\n \n # Calculate the sum of the specified range\n return sum(numbers[start_index:end_index + 1])", "matching_cluster_idx": 6}, {"solution": "def sum_range_list(numbers, start_index, end_index):\n \"\"\"\n Returns the sum of numbers in the list from start_index to end_index (inclusive).\n \n Args:\n numbers (list): A list of numbers.\n start_index (int): The starting index.\n end_index (int): The ending index.\n \n Returns:\n int: The sum of numbers in the specified range.\n \"\"\"\n # Slice the list and calculate the sum\n return sum(numbers[start_index:end_index + 1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(lst, start_index, end_index):\n \"\"\"\n Returns the sum of numbers in the list between the specified start and end indices (inclusive).\n \n :param lst: List of numbers\n :param start_index: Starting index of the range\n :param end_index: Ending index of the range\n :return: Sum of numbers in the specified range\n \"\"\"\n if start_index < 0 or end_index >= len(lst):\n raise IndexError(\"Indices are out of range.\")\n \n return sum(lst[start_index:end_index + 1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(numbers, start_index, end_index):\n \"\"\"\n Calculate the sum of numbers in a list from start_index to end_index (inclusive).\n\n :param numbers: List of numbers\n :param start_index: Starting index (inclusive)\n :param end_index: Ending index (inclusive)\n :return: Sum of the numbers in the specified range\n \"\"\"\n # Ensure the indices are within the bounds of the list\n if start_index < 0 or end_index >= len(numbers):\n raise IndexError(\"Index out of range\")\n \n return sum(numbers[start_index:end_index + 1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(numbers, start_index, end_index):\n \"\"\"\n Returns the sum of numbers in the list 'numbers' from 'start_index' to 'end_index' (inclusive).\n\n Args:\n numbers (list): A list of numbers.\n start_index (int): The starting index.\n end_index (int): The ending index.\n\n Returns:\n int: The sum of the numbers in the specified range.\n \"\"\"\n # Check if indices are within the bounds of the list\n if start_index < 0 or end_index >= len(numbers):\n raise IndexError(\"Index out of bounds\")\n \n # Calculate the sum in the specified range\n return sum(numbers[start_index:end_index + 1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(lst, start_idx, end_idx):\n \"\"\"\n Calculates the sum of elements in the list 'lst' from index 'start_idx' to 'end_idx' (inclusive).\n\n :param lst: List of numbers\n :param start_idx: Starting index\n :param end_idx: Ending index\n :return: Sum of the elements from start_idx to end_idx\n \"\"\"\n # Ensure the indices are within the range of the list\n if start_idx < 0 or end_idx >= len(lst):\n raise IndexError(\"Indices are out of bounds.\")\n \n return sum(lst[start_idx:end_idx + 1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(numbers, start_index, end_index):\n \"\"\"\n Calculate the sum of numbers in the list from start_index to end_index inclusive.\n \n :param numbers: List of numbers to sum.\n :param start_index: Starting index of the range.\n :param end_index: Ending index of the range.\n :return: Sum of the numbers in the specified range.\n \"\"\"\n # Ensure indices are within the bounds of the list\n if start_index < 0 or end_index >= len(numbers):\n raise IndexError(\"Index out of range.\")\n \n return sum(numbers[start_index:end_index + 1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(lst, start_index, end_index):\n \"\"\"\n Calculate the sum of numbers in a list from start_index to end_index (inclusive).\n \n Parameters:\n lst (list): A list of numbers.\n start_index (int): The starting index (inclusive).\n end_index (int): The ending index (inclusive).\n \n Returns:\n int: The sum of numbers in the specified range.\n \"\"\"\n # Ensure the indices are within the bounds of the list\n if start_index < 0 or end_index >= len(lst):\n raise IndexError(\"Index out of bounds.\")\n \n return sum(lst[start_index:end_index + 1])", "matching_cluster_idx": 7}]}, "Mbpp/226": {"dps": 74.57364341085271, "dps_norm": 31.42857142857143, "pass@1": 100.0, "profiled": [{"solution": "def odd_values_string(s):\n \"\"\"\n Removes characters from the string that are at odd index values.\n\n Args:\n s (str): The input string.\n\n Returns:\n str: A new string with characters from even index values only.\n \"\"\"\n return ''.join(s[i] for i in range(len(s)) if i % 2 == 0)", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(s: str) -> str:\n \"\"\"\n Remove characters from the input string that have odd index values.\n\n Parameters:\n s (str): The input string from which to remove characters.\n\n Returns:\n str: A new string containing only characters with even index values.\n \"\"\"\n return ''.join(s[i] for i in range(len(s)) if i % 2 == 0)", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(s):\n \"\"\"\n Remove characters from the string that have odd index values.\n \n Parameters:\n s (str): The input string from which characters at odd indices will be removed.\n \n Returns:\n str: A new string with characters at odd indices removed.\n \"\"\"\n return ''.join(s[i] for i in range(len(s)) if i % 2 == 0)", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(input_string):\n \"\"\"\n Removes characters from the input string that have odd index values.\n \n Args:\n input_string (str): The string from which to remove characters.\n \n Returns:\n str: A new string containing characters from even indices.\n \"\"\"\n # Using list comprehension to filter out characters at odd indices\n return ''.join(input_string[i] for i in range(len(input_string)) if i % 2 == 0)", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(s):\n \"\"\"\n Remove characters from the string that have odd index values.\n \n Parameters:\n s (str): The input string.\n \n Returns:\n str: A new string with characters from even indices.\n \"\"\"\n return s[::2]", "matching_cluster_idx": 6}, {"solution": "def odd_values_string(s):\n \"\"\"\n Remove characters from the string that have odd index values.\n\n :param s: Input string\n :return: String with characters at odd indices removed\n \"\"\"\n # Using slicing to get characters at even indices\n return s[::2]", "matching_cluster_idx": 6}, {"solution": "def odd_values_string(s):\n \"\"\"\n Remove characters from the string that have odd index values.\n\n Parameters:\n s (str): The input string from which characters at odd indices will be removed.\n\n Returns:\n str: A new string consisting of characters from the input string at even indices.\n \"\"\"\n return ''.join(s[i] for i in range(len(s)) if i % 2 == 0)", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(s):\n \"\"\"\n Removes characters from the string 's' that have odd index values.\n\n Args:\n s (str): The input string.\n\n Returns:\n str: A new string with characters at odd indices removed.\n \"\"\"\n return ''.join(s[i] for i in range(len(s)) if i % 2 == 0)", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(s):\n \"\"\"\n Remove characters from the string that have odd index values.\n \n Parameters:\n s (str): The input string from which odd indexed characters will be removed.\n\n Returns:\n str: A new string with characters at odd indices removed.\n \"\"\"\n return s[::2] # Return characters at even indices", "matching_cluster_idx": 6}, {"solution": "def odd_values_string(s):\n \"\"\"\n Removes characters from the string that have odd index values.\n\n Parameters:\n s (str): The input string.\n\n Returns:\n str: A new string with characters at odd indices removed.\n \"\"\"\n return ''.join(s[i] for i in range(len(s)) if i % 2 == 0)", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(s):\n \"\"\"Remove characters with odd index values from a given string.\"\"\"\n return ''.join(s[i] for i in range(len(s)) if i % 2 == 0)", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(s):\n \"\"\"\n Remove characters with odd index values from the given string.\n\n Parameters:\n s (str): The input string.\n\n Returns:\n str: A new string with characters at odd indices removed.\n \"\"\"\n return ''.join(s[i] for i in range(len(s)) if i % 2 == 0)", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(s):\n \"\"\"\n Removes characters from the string that have odd index values.\n \n Parameters:\n s (str): The input string from which to remove characters.\n \n Returns:\n str: A new string with characters at odd indices removed.\n \"\"\"\n return ''.join(s[i] for i in range(len(s)) if i % 2 == 0)", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(s):\n \"\"\"\n Remove characters from the string that have odd index values.\n\n Parameters:\n s (str): The input string.\n\n Returns:\n str: A new string with characters from the even indices of the input string.\n \"\"\"\n # Using list comprehension to gather characters from even indices\n return ''.join(s[i] for i in range(len(s)) if i % 2 == 0)", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(s):\n \"\"\"\n Remove characters from the string that have odd index values.\n \n :param s: Input string\n :return: A new string with characters from even indices\n \"\"\"\n return ''.join(s[i] for i in range(len(s)) if i % 2 == 0)", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(s):\n \"\"\"Remove characters from the string that have odd index values.\"\"\"\n return ''.join(s[i] for i in range(len(s)) if i % 2 == 0)", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(s):\n \"\"\"\n Removes characters from the string at odd index values.\n\n Args:\n s (str): The input string.\n\n Returns:\n str: A new string with characters at odd indices removed.\n \"\"\"\n return ''.join(s[i] for i in range(len(s)) if i % 2 == 0)", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(s):\n \"\"\"\n Remove characters with odd index values from the given string.\n\n Parameters:\n s (str): The input string.\n\n Returns:\n str: A new string with characters at odd indices removed.\n \"\"\"\n return s[::2]", "matching_cluster_idx": 6}, {"solution": "def odd_values_string(s):\n \"\"\"\n Remove characters from the string that have odd index values.\n\n Parameters:\n s (str): The input string.\n\n Returns:\n str: A string with characters at odd indices removed.\n \"\"\"\n return ''.join(s[i] for i in range(len(s)) if i % 2 == 0)", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(s):\n \"\"\"\n Remove characters from a string that have odd index values.\n\n Parameters:\n s (str): The input string.\n\n Returns:\n str: A new string with characters at odd indices removed.\n \"\"\"\n return ''.join(s[i] for i in range(len(s)) if i % 2 == 0)", "matching_cluster_idx": 0}]}, "Mbpp/230": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def replace_blank(input_string, character):\n \"\"\"\n Replaces blank spaces in the input string with the specified character.\n\n Parameters:\n input_string (str): The string in which to replace spaces.\n character (str): The character to replace spaces with.\n\n Returns:\n str: The modified string with spaces replaced by the character.\n \"\"\"\n return input_string.replace(' ', character)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string, replacement_char):\n \"\"\"\n Replaces blank spaces in the input_string with the specified replacement_char.\n \n Args:\n input_string (str): The string in which to replace spaces.\n replacement_char (str): The character to replace spaces with.\n \n Returns:\n str: The modified string with spaces replaced.\n \"\"\"\n return input_string.replace(' ', replacement_char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string, replacement_char):\n \"\"\"\n Replaces blank spaces in the input string with the specified character.\n\n Parameters:\n input_string (str): The string in which to replace blank spaces.\n replacement_char (str): The character to replace blank spaces with.\n\n Returns:\n str: The modified string with blank spaces replaced.\n \"\"\"\n return input_string.replace(\" \", replacement_char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string, replacement_char):\n \"\"\"\n Replace blank spaces in the input string with the specified character.\n\n Parameters:\n input_string (str): The string in which to replace spaces.\n replacement_char (str): The character to replace spaces with.\n\n Returns:\n str: The modified string with spaces replaced by the replacement character.\n \"\"\"\n return input_string.replace(\" \", replacement_char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string, replacement_char):\n \"\"\"\n Replaces blank spaces in the input_string with the specified replacement_char.\n\n Parameters:\n input_string (str): The string in which to replace blank spaces.\n replacement_char (str): The character to replace blank spaces with.\n\n Returns:\n str: The modified string with blank spaces replaced by replacement_char.\n \"\"\"\n return input_string.replace(\" \", replacement_char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(s: str, char: str) -> str:\n \"\"\"\n Replaces blank spaces in the string with the specified character.\n \n Args:\n s (str): The input string.\n char (str): The character to replace blank spaces with.\n \n Returns:\n str: The modified string with blank spaces replaced.\n \"\"\"\n return s.replace(' ', char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string, char):\n \"\"\"\n Replaces blank spaces in the input string with the specified character.\n \n Args:\n input_string (str): The string in which to replace spaces.\n char (str): The character to replace spaces with.\n \n Returns:\n str: The modified string with spaces replaced by the specified character.\n \"\"\"\n return input_string.replace(' ', char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string, replacement_char):\n \"\"\"\n Replace blank spaces in the input string with the specified character.\n \n Parameters:\n input_string (str): The string in which blank spaces will be replaced.\n replacement_char (str): The character that will replace the blank spaces.\n \n Returns:\n str: The modified string with blank spaces replaced.\n \"\"\"\n return input_string.replace(\" \", replacement_char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string, replacement_char):\n \"\"\"\n Replaces blank spaces in the input_string with the specified replacement_char.\n\n Args:\n input_string (str): The string to process.\n replacement_char (str): The character to replace spaces with.\n\n Returns:\n str: The modified string with spaces replaced by the replacement_char.\n \"\"\"\n return input_string.replace(' ', replacement_char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string: str, char: str) -> str:\n \"\"\"\n Replace blank spaces in the input string with the specified character.\n \n Parameters:\n input_string (str): The string to process.\n char (str): The character to replace spaces with.\n \n Returns:\n str: The modified string with spaces replaced by the character.\n \"\"\"\n return input_string.replace(\" \", char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string, replacement_char):\n \"\"\"\n Replace blank spaces in the input string with the specified character.\n\n Parameters:\n input_string (str): The original string with blank spaces.\n replacement_char (str): The character to replace the blank spaces with.\n\n Returns:\n str: The modified string with blank spaces replaced by the character.\n \"\"\"\n return input_string.replace(' ', replacement_char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string, char):\n \"\"\"\n Replace blank spaces in the input string with the specified character.\n\n Parameters:\n input_string (str): The string in which to replace spaces.\n char (str): The character to replace spaces with.\n\n Returns:\n str: The modified string with spaces replaced by the specified character.\n \"\"\"\n return input_string.replace(\" \", char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(s: str, char: str) -> str:\n \"\"\"\n Replaces blank spaces in the input string with the specified character.\n\n Parameters:\n s (str): The input string.\n char (str): The character to replace spaces with.\n\n Returns:\n str: The modified string with spaces replaced by the character.\n \"\"\"\n return s.replace(' ', char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string, replacement_char):\n \"\"\"\n Replace blank spaces in the input string with the specified character.\n\n Args:\n input_string (str): The string in which to replace blank spaces.\n replacement_char (str): The character to replace blank spaces with.\n\n Returns:\n str: The modified string with blank spaces replaced.\n \"\"\"\n return input_string.replace(' ', replacement_char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string, replacement_char):\n \"\"\"\n Replace blank spaces in the input string with the specified character.\n\n Parameters:\n input_string (str): The string in which to replace blank spaces.\n replacement_char (str): The character to replace blank spaces with.\n\n Returns:\n str: The modified string with blank spaces replaced by the replacement character.\n \"\"\"\n return input_string.replace(\" \", replacement_char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string, char):\n \"\"\"\n Replace blank spaces in the input string with the specified character.\n\n Parameters:\n input_string (str): The string to process.\n char (str): The character to replace spaces with.\n\n Returns:\n str: The modified string with spaces replaced by the character.\n \"\"\"\n return input_string.replace(\" \", char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string, character):\n \"\"\"\n Replaces all blank spaces in the input string with the specified character.\n\n Args:\n input_string (str): The string to process.\n character (str): The character to replace blank spaces with.\n\n Returns:\n str: The modified string with blank spaces replaced.\n \"\"\"\n return input_string.replace(' ', character)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string, replacement_char):\n \"\"\"\n Replaces blank spaces in the input string with the specified character.\n\n Parameters:\n input_string (str): The string in which to replace blank spaces.\n replacement_char (str): The character to replace blank spaces with.\n\n Returns:\n str: The modified string with blank spaces replaced.\n \"\"\"\n return input_string.replace(' ', replacement_char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string, replacement_char):\n \"\"\"\n Replaces blank spaces in the input_string with the replacement_char.\n \n Parameters:\n input_string (str): The string in which to replace blank spaces.\n replacement_char (str): The character to replace the spaces with.\n \n Returns:\n str: The modified string with spaces replaced by the replacement_char.\n \"\"\"\n return input_string.replace(\" \", replacement_char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string, replacement_char):\n \"\"\"\n Replaces blank spaces in the input string with the specified character.\n\n Args:\n input_string (str): The string to process.\n replacement_char (str): The character to replace blank spaces with.\n\n Returns:\n str: The modified string with blank spaces replaced.\n \"\"\"\n return input_string.replace(' ', replacement_char)", "matching_cluster_idx": 7}]}, "Mbpp/239": {"dps": 76.55172413793103, "dps_norm": 78.0, "pass@1": 64.0, "profiled": [{"solution": "def get_total_number_of_sequences(m, n):\n # Memoization table\n memo = {}\n\n def count_sequences(prev, length):\n # Base case: If the length of the sequence reaches n, we have found a valid sequence\n if length == n:\n return 1\n # Use memoization to avoid recalculating\n if (prev, length) in memo:\n return memo[(prev, length)]\n \n total_count = 0\n next_value = prev * 2\n \n # Count the valid next values in the range [next_value, m]\n while next_value <= m:\n total_count += count_sequences(next_value, length + 1)\n next_value += 1\n \n # Store result in memoization table\n memo[(prev, length)] = total_count\n return total_count\n\n total_sequences = 0\n # Start with any number from 1 to m as the first element\n for start in range(1, m + 1):\n total_sequences += count_sequences(start, 1)\n \n return total_sequences", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n # Define a helper function for recursive counting\n def count_sequences(current_value, length):\n if length == 0:\n return 1\n count = 0\n next_value = current_value * 2\n while next_value <= m:\n count += count_sequences(next_value, length - 1)\n next_value += 1\n return count\n\n total_count = 0\n for start in range(1, m + 1):\n total_count += count_sequences(start, n - 1)\n\n return total_count", "matching_cluster_idx": 5}, {"solution": "def get_total_number_of_sequences(m, n):\n # Dynamic programming table\n dp = [[0] * (n + 1) for _ in range(m + 1)]\n \n # Base case: For length 1, any number from 1 to m is a valid sequence\n for i in range(1, m + 1):\n dp[i][1] = 1\n\n # Fill the DP table\n for length in range(2, n + 1): # For lengths from 2 to n\n for last in range(1, m + 1): # For each possible last element\n # The next number must be between 2 * last and m\n start = 2 * last\n if start > m:\n continue # If starting point is beyond m, skip\n for next_num in range(start, m + 1): # Next number must be in valid range\n dp[next_num][length] += dp[last][length - 1]\n\n # Sum up all possible sequences of length n with any last element\n total_sequences = sum(dp[i][n] for i in range(1, m + 1))\n \n return total_sequences", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n # Helper function to count sequences\n def count_sequences(current, length):\n if length == n:\n return 1 # We found a valid sequence\n total = 0\n next_value = current * 2\n while next_value <= m:\n total += count_sequences(next_value, length + 1)\n next_value += 1\n return total\n\n total_count = 0\n # Start the sequence with each possible starting point from 1 to m\n for start in range(1, m + 1):\n total_count += count_sequences(start, 1)\n \n return total_count", "matching_cluster_idx": 5}, {"solution": "def get_total_number_of_sequences(m, n):\n # Initialize a memoization table\n memo = {}\n\n def count_sequences(current, length):\n # Base case: when the desired length of the sequence is reached\n if length == 0:\n return 1\n # If already computed, return the cached result\n if (current, length) in memo:\n return memo[(current, length)]\n \n total_count = 0\n # Start from at least 2 * current (next element)\n next_value = 2 * current\n \n # Continue while next_value is within bounds\n while next_value <= m:\n total_count += count_sequences(next_value, length - 1)\n next_value += 1\n \n # Cache the result\n memo[(current, length)] = total_count\n return total_count\n \n total_sequences = 0\n # Start the sequence with each possible first element from 1 to m\n for starting_value in range(1, m + 1):\n total_sequences += count_sequences(starting_value, n - 1)\n \n return total_sequences", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n # Create a memoization table to store counts of sequences\n memo = {}\n\n def count_sequences(previous, length):\n # Base case: if the desired length is reached, return 1 (valid sequence)\n if length == 0:\n return 1\n \n # Use memoization to avoid recomputation\n if (previous, length) in memo:\n return memo[(previous, length)]\n\n total_count = 0\n # Start from 2 * previous and go up to m\n start = 2 * previous\n for next_element in range(start, m + 1):\n total_count += count_sequences(next_element, length - 1)\n \n # Store result in memoization table\n memo[(previous, length)] = total_count\n return total_count\n\n # Start the sequences from all positive integers from 1 to m\n total_sequences = 0\n for starting_element in range(1, m + 1):\n total_sequences += count_sequences(starting_element, n - 1)\n \n return total_sequences", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n # Memoization table to store results\n memo = {}\n\n def count_sequences(last, length):\n # If we have filled the sequence up to length n, return 1\n if length == n:\n return 1\n \n # If the result is already calculated, return it\n if (last, length) in memo:\n return memo[(last, length)]\n\n total_sequences = 0\n # Start the next number from at least twice the last number\n next_num = 2 * last\n \n # Explore the possible next elements\n while next_num <= m:\n total_sequences += count_sequences(next_num, length + 1)\n next_num += 1\n \n # Store the result in memoization table\n memo[(last, length)] = total_sequences\n return total_sequences\n\n total = 0\n # Start the sequence with any number from 1 to m\n for start in range(1, m + 1):\n total += count_sequences(start, 1)\n\n return total", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n # Memoization table to store the results for dynamic programming\n dp = [[0] * (m + 1) for _ in range(n + 1)]\n \n # Base case: for sequences of length 1, every number from 1 to m is valid\n for i in range(1, m + 1):\n dp[1][i] = 1\n \n # Fill the dp table\n for length in range(2, n + 1):\n for prev in range(1, m + 1):\n # The next number must be between 2 * prev and m\n start = 2 * prev\n if start <= m:\n for next_num in range(start, m + 1):\n dp[length][next_num] += dp[length - 1][prev]\n \n # Sum up all valid sequences of length n\n total_sequences = sum(dp[n][i] for i in range(1, m + 1))\n \n return total_sequences", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n memo = {}\n\n def count_sequences(last, length):\n # Base case: If the sequence length reaches n, there's one valid sequence\n if length == n:\n return 1\n # If we have computed this state before, return the cached result\n if (last, length) in memo:\n return memo[(last, length)]\n \n total_sequences = 0\n # Start next_element from 2 * last and go up to m\n next_element = 2 * last\n while next_element <= m:\n total_sequences += count_sequences(next_element, length + 1)\n next_element += 1\n \n memo[(last, length)] = total_sequences\n return total_sequences\n\n total = 0\n # Start the sequence with every possible first element from 1 to m\n for first_element in range(1, m + 1):\n total += count_sequences(first_element, 1)\n\n return total", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n # Dynamic programming table to store results\n dp = [[0] * (m + 1) for _ in range(n + 1)]\n \n # Initialize for the first element\n for i in range(1, m + 1):\n dp[1][i] = 1 # There is one way to select each number for sequence of length 1\n\n # Fill the DP table for lengths from 2 to n\n for length in range(2, n + 1):\n for prev in range(1, m + 1):\n start = 2 * prev\n # The sequence can start from 2 * prev and go to m\n if start <= m:\n # Calculate the sum for sequences starting from 2 * prev to m\n for current in range(start, m + 1):\n dp[length][current] += dp[length - 1][prev]\n \n # Sum all sequences of length n\n total_sequences = sum(dp[n][i] for i in range(1, m + 1))\n return total_sequences", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n # Create a memoization table to store results for subproblems\n memo = {}\n\n def count_sequences(current, length):\n # If we have reached the desired length, return 1 sequence found\n if length == 0:\n return 1\n # If the result is already computed, return it\n if (current, length) in memo:\n return memo[(current, length)]\n \n total_sequences = 0\n # The next number must be between 2 * current and m (inclusive)\n next_min = 2 * current\n # Start from next_min and go up to m\n for next_number in range(next_min, m + 1):\n total_sequences += count_sequences(next_number, length - 1)\n\n # Store the result in the memoization table\n memo[(current, length)] = total_sequences\n return total_sequences\n\n total_count = 0\n # Start the sequence with each possible starting number from 1 to m\n for start in range(1, m + 1):\n total_count += count_sequences(start, n - 1)\n\n return total_count", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n # Memoization dictionary\n memo = {}\n\n def count_sequences(last_element, remaining_length):\n # Base case: If no remaining length, there's one valid sequence (the empty sequence)\n if remaining_length == 0:\n return 1\n # Check if we have already computed this state\n if (last_element, remaining_length) in memo:\n return memo[(last_element, remaining_length)]\n\n total_sequences = 0\n # Determine the minimum and maximum value for the next element\n min_next = last_element * 2\n max_next = m\n\n # Iterate through all valid next elements\n for next_element in range(min_next, max_next + 1):\n total_sequences += count_sequences(next_element, remaining_length - 1)\n\n # Store the result in memoization dictionary\n memo[(last_element, remaining_length)] = total_sequences\n return total_sequences\n\n total = 0\n # Start with each possible first element\n for first_element in range(1, m + 1):\n total += count_sequences(first_element, n - 1)\n\n return total", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n # Memoization dictionary\n memo = {}\n \n def count_sequences(current_length, last_value):\n # If we've built a sequence of the desired length, return 1\n if current_length == n:\n return 1\n # If the value has been memoized, return it\n if (current_length, last_value) in memo:\n return memo[(current_length, last_value)]\n \n total_sequences = 0\n # Calculate the next valid values\n next_value = last_value * 2\n while next_value <= m:\n total_sequences += count_sequences(current_length + 1, next_value)\n next_value += 1\n \n # Memoize the result before returning\n memo[(current_length, last_value)] = total_sequences\n return total_sequences\n \n total_count = 0\n # Start from each possible initial value from 1 to m\n for starting_value in range(1, m + 1):\n total_count += count_sequences(1, starting_value)\n \n return total_count", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n \"\"\"\n This function calculates the number of valid sequences of length n\n where each element is a positive integer and is greater than or equal\n to twice the previous element but less than or equal to m.\n \n :param m: Maximum allowed value for sequence elements.\n :param n: Length of the sequence.\n :return: Number of valid sequences.\n \"\"\"\n # Memoization table to store results for each (current length, previous value)\n memo = {}\n\n def count_sequences(length, prev_value):\n # Base case: if the current length is n, we've formed a valid sequence\n if length == n:\n return 1\n # Check if the result is already computed\n if (length, prev_value) in memo:\n return memo[(length, prev_value)]\n \n # Calculate the number of valid next values\n next_min = max(prev_value * 2, 1) # At least double the previous\n next_max = m # At most m\n\n # Count valid sequences\n total = 0\n for next_value in range(next_min, next_max + 1):\n total += count_sequences(length + 1, next_value)\n\n # Memoize the result\n memo[(length, prev_value)] = total\n return total\n\n # Start counting sequences from an initial value of 0 (no previous value)\n return count_sequences(0, 0)", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n # Initialize a memoization table\n memo = {}\n\n def count_sequences(last_value, remaining_length):\n # If we've constructed a full sequence of length n, count it as 1\n if remaining_length == 0:\n return 1\n # If this state has been computed before, return the stored result\n if (last_value, remaining_length) in memo:\n return memo[(last_value, remaining_length)]\n \n total_count = 0\n # The next value must be between 2 * last_value and m\n next_value = 2 * last_value\n while next_value <= m:\n total_count += count_sequences(next_value, remaining_length - 1)\n next_value += 1 # Increment to consider the next possible value\n\n # Store the computed result in the memoization table\n memo[(last_value, remaining_length)] = total_count\n return total_count\n\n total_sequences = 0\n # Start the sequence with any number from 1 to m\n for starting_value in range(1, m + 1):\n total_sequences += count_sequences(starting_value, n - 1)\n\n return total_sequences", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n # A memoization table to store the number of sequences of length k starting from the value 'start'\n memo = {}\n\n def count_sequences(start, length):\n # Base case: if the length is 0, there is one valid sequence (the empty sequence)\n if length == 0:\n return 1\n \n # Check if we already computed this state\n if (start, length) in memo:\n return memo[(start, length)]\n \n total_count = 0\n next_start = 2 * start # Next element must be at least twice the current element\n \n # Count valid sequences starting from the next_start and of length (length - 1)\n while next_start <= m:\n total_count += count_sequences(next_start, length - 1)\n next_start += 1 # Increment to check the next possible starting point\n\n # Memoize the computed result\n memo[(start, length)] = total_count\n return total_count\n\n total_sequences = 0\n # Start with each possible initial value from 1 to m\n for initial in range(1, m + 1):\n total_sequences += count_sequences(initial, n - 1)\n\n return total_sequences", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n \"\"\"\n Calculate the number of possible sequences of length n, where each element\n is a positive integer and is greater than or equal to twice the previous \n element but less than or equal to m.\n\n :param m: The upper limit for the elements in the sequence.\n :param n: The length of the sequence.\n :return: The count of valid sequences.\n \"\"\"\n # Create a memoization table\n memo = {}\n\n def count_sequences(previous, length):\n # Base case: if we have formed a sequence of the required length\n if length == n:\n return 1\n \n # If the value is already computed\n if (previous, length) in memo:\n return memo[(previous, length)]\n \n total = 0\n # Calculate the next element's lower bound\n lower_bound = previous * 2\n \n # Iterate from the lower bound to m\n for next_element in range(lower_bound, m + 1):\n total += count_sequences(next_element, length + 1)\n \n memo[(previous, length)] = total\n return total\n\n total_sequences = 0\n # Start the sequence with each possible first element from 1 to m\n for first_element in range(1, m + 1):\n total_sequences += count_sequences(first_element, 1)\n\n return total_sequences", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n # Create a memoization table to store the results of subproblems\n memo = {}\n\n def count_sequences(last, length):\n # If the length is 0, we've successfully formed a sequence\n if length == 0:\n return 1\n # Check if this subproblem has already been solved\n if (last, length) in memo:\n return memo[(last, length)]\n\n count = 0\n # Find the next valid number\n next_num = last * 2\n while next_num <= m:\n count += count_sequences(next_num, length - 1)\n next_num += 1\n\n # Store the result in the memo table\n memo[(last, length)] = count\n return count\n\n total_sequences = 0\n # Starting with an empty last number (0) and the full length n\n for start in range(1, m + 1):\n total_sequences += count_sequences(start, n - 1)\n\n return total_sequences", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n # Base case: if n is 1, there are m valid sequences (1 to m)\n if n == 1:\n return m\n \n # Memoization table to store results for subproblems\n dp = [[0] * (n + 1) for _ in range(m + 1)]\n \n # Initial condition: for length 1, there are m sequences\n for i in range(1, m + 1):\n dp[i][1] = 1\n\n # Fill the dp table\n for length in range(2, n + 1):\n for prev in range(1, m + 1):\n # Calculate the range for the next number in the sequence\n min_next = max(prev * 2, 1)\n max_next = m\n \n if min_next <= max_next:\n dp[prev][length] = sum(dp[i][length - 1] for i in range(min_next, max_next + 1))\n\n # Sum all sequences of length n starting from 1 to m\n total_sequences = sum(dp[i][n] for i in range(1, m + 1))\n return total_sequences", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n # A memoization table to store results of subproblems\n memo = {}\n\n def count_sequences(last_element, remaining_length):\n # Base case: if no more elements are left to place\n if remaining_length == 0:\n return 1\n # If the result is already computed, return it\n if (last_element, remaining_length) in memo:\n return memo[(last_element, remaining_length)]\n\n total_sequences = 0\n # Calculate the range for the next element\n next_min = 2 * last_element\n next_max = m\n\n # Ensure the next minimum is within bounds\n for next_element in range(next_min, next_max + 1):\n total_sequences += count_sequences(next_element, remaining_length - 1)\n\n # Store the result in the memoization table\n memo[(last_element, remaining_length)] = total_sequences\n return total_sequences\n\n total_count = 0\n # Start by considering each positive integer from 1 to m as the first element\n for first_element in range(1, m + 1):\n total_count += count_sequences(first_element, n - 1)\n\n return total_count", "matching_cluster_idx": 7}]}, "Mbpp/240": {"dps": 61.768292682926834, "dps_norm": 74.44444444444444, "pass@1": 100.0, "profiled": [{"solution": "def replace_list(list1, list2):\n \"\"\"\n Replaces the last element of list1 with the elements of list2.\n\n Args:\n list1 (list): The first list.\n list2 (list): The second list to be appended.\n\n Returns:\n list: The modified list1 with the last element replaced by elements of list2.\n \"\"\"\n # Check if list1 is not empty\n if list1:\n # Remove the last element of list1\n list1.pop()\n # Extend list1 with elements from list2\n list1.extend(list2)\n return list1", "matching_cluster_idx": 8}, {"solution": "def replace_list(list1, list2):\n \"\"\"\n Replaces the last element of the first list with the elements of the second list.\n\n Parameters:\n list1 (list): The first list whose last element will be replaced.\n list2 (list): The second list whose elements will be added to the first list.\n\n Returns:\n list: The modified first list with the last element replaced by the elements of the second list.\n \"\"\"\n # Check if list1 is not empty\n if list1:\n # Replace the last element of list1 with the elements of list2\n list1 = list1[:-1] + list2\n else:\n # If list1 is empty, just return list2\n list1 = list2\n\n return list1", "matching_cluster_idx": 5}, {"solution": "def replace_list(list1, list2):\n \"\"\"\n Replaces the last element of list1 with the elements of list2.\n\n Args:\n list1 (list): The first list to modify.\n list2 (list): The second list whose elements will replace the last element of list1.\n\n Returns:\n list: The modified list1 with the last element replaced by the elements of list2.\n \"\"\"\n if not list1: # Check if list1 is empty\n return list2 # If list1 is empty, return list2\n\n # Replace the last element of list1 with the elements of list2\n list1 = list1[:-1] + list2\n return list1", "matching_cluster_idx": 5}, {"solution": "def replace_list(list1, list2):\n \"\"\"\n Replaces the last element of list1 with the elements of list2.\n \n Args:\n list1 (list): The first list whose last element will be replaced.\n list2 (list): The second list whose elements will replace the last element of list1.\n \n Returns:\n list: A new list with the last element of list1 replaced by the elements of list2.\n \"\"\"\n # Check if list1 is empty\n if not list1:\n return list2\n # Create a new list with all elements from list1 except the last one\n new_list = list1[:-1]\n # Add all elements from list2 to the new list\n new_list.extend(list2)\n return new_list", "matching_cluster_idx": 6}, {"solution": "def replace_list(list1, list2):\n \"\"\"Replace the last element of list1 with the elements of list2.\"\"\"\n if not list1: # If list1 is empty, return list2\n return list2\n return list1[:-1] + list2 # Replace last element of list1 with list2", "matching_cluster_idx": 5}, {"solution": "def replace_list(list1, list2):\n \"\"\"\n Replace the last element of list1 with the elements of list2.\n\n Parameters:\n list1 (list): The first list.\n list2 (list): The second list whose elements will replace the last element of list1.\n\n Returns:\n list: A new list with the last element of list1 replaced by the elements of list2.\n \"\"\"\n # Remove the last element from list1\n list1 = list1[:-1]\n # Concatenate list1 with list2\n return list1 + list2", "matching_cluster_idx": 5}, {"solution": "def replace_list(list1, list2):\n \"\"\"\n Replace the last element of list1 with the elements of list2.\n \n Parameters:\n list1 (list): The first list.\n list2 (list): The second list whose elements will replace the last element of list1.\n \n Returns:\n list: A new list with the last element of list1 replaced by the elements of list2.\n \"\"\"\n if not list1: # If list1 is empty, return list2\n return list2\n \n # Create a new list containing all elements of list1 except the last one\n new_list = list1[:-1]\n # Append all elements of list2 to the new list\n new_list.extend(list2)\n \n return new_list", "matching_cluster_idx": 6}, {"solution": "def replace_list(list1, list2):\n \"\"\"\n Replaces the last element of the first list with the elements of the second list.\n\n Parameters:\n list1 (list): The first list.\n list2 (list): The second list.\n\n Returns:\n list: The modified first list with the last element replaced by elements of the second list.\n \"\"\"\n if not list1: # Check if the first list is empty\n return list2 # If empty, return the second list\n \n # Replace the last element of list1 with the elements of list2\n list1 = list1[:-1] + list2\n return list1", "matching_cluster_idx": 5}, {"solution": "def replace_list(list1, list2):\n # Replace the last element of list1 with the elements of list2\n if list1: # Check if list1 is not empty\n list1.pop() # Remove the last element of list1\n return list1 + list2 # Concatenate the modified list1 with list2", "matching_cluster_idx": 6}, {"solution": "def replace_list(list1, list2):\n \"\"\"\n Replaces the last element of the first list with the elements of the second list.\n\n Args:\n list1 (list): The first list from which the last element will be replaced.\n list2 (list): The second list whose elements will be added.\n\n Returns:\n list: A new list with the last element of list1 replaced by elements of list2.\n \"\"\"\n if not list1:\n return list2\n return list1[:-1] + list2", "matching_cluster_idx": 5}, {"solution": "def replace_list(list1, list2):\n \"\"\"\n Replace the last element of the first list with the elements of the second list.\n \n Parameters:\n list1 (list): The first list.\n list2 (list): The second list.\n \n Returns:\n list: A new list with the last element of list1 replaced by the elements of list2.\n \"\"\"\n # Remove the last element of list1\n list1 = list1[:-1]\n # Append elements of list2 to list1\n return list1 + list2", "matching_cluster_idx": 5}, {"solution": "def replace_list(list1, list2):\n \"\"\"\n Replaces the last element of the first list with the elements of the second list.\n\n Parameters:\n list1 (list): The first list.\n list2 (list): The second list whose elements will replace the last element of the first list.\n\n Returns:\n list: The modified first list with elements of the second list appended.\n \"\"\"\n # Remove the last element of the first list\n list1.pop()\n # Extend the first list with the elements of the second list\n list1.extend(list2)\n return list1", "matching_cluster_idx": 8}, {"solution": "def replace_list(list1, list2):\n \"\"\"\n Replaces the last element of the first list with the elements of the second list.\n\n Args:\n list1: A list of elements.\n list2: A list of elements.\n\n Returns:\n A new list with the last element of list1 replaced by the elements of list2.\n \"\"\"\n # Create a copy of list1 excluding the last element\n new_list = list1[:-1]\n # Append the elements of list2 to the new list\n new_list.extend(list2)\n return new_list", "matching_cluster_idx": 6}, {"solution": "def replace_list(lst1, lst2):\n \"\"\"\n Replaces the last element of lst1 with the elements of lst2.\n\n Args:\n lst1 (list): The first list.\n lst2 (list): The second list.\n\n Returns:\n list: The modified lst1 with the last element replaced by lst2 elements.\n \"\"\"\n # Replace the last element of lst1 with the elements from lst2\n lst1 = lst1[:-1] + lst2\n return lst1", "matching_cluster_idx": 5}, {"solution": "def replace_list(list1, list2):\n \"\"\"\n Replaces the last element of the first list with the elements of the second list.\n\n Parameters:\n list1 (list): The first list to modify.\n list2 (list): The second list whose elements will replace the last element of the first list.\n\n Returns:\n list: The modified first list with the last element replaced by elements of the second list.\n \"\"\"\n # Remove the last element of list1\n list1.pop()\n # Extend list1 with the elements of list2\n list1.extend(list2)\n return list1", "matching_cluster_idx": 8}, {"solution": "def replace_list(list1, list2):\n \"\"\"\n Replaces the last element of list1 with the elements of list2.\n \n Args:\n list1 (list): The first list whose last element will be replaced.\n list2 (list): The second list whose elements will be added to list1.\n \n Returns:\n list: The modified list1 with the last element replaced by elements from list2.\n \"\"\"\n if not list1:\n return list2 # If list1 is empty, just return list2\n \n # Replace the last element of list1 with the elements of list2\n return list1[:-1] + list2", "matching_cluster_idx": 5}, {"solution": "def replace_list(list1, list2):\n \"\"\"\n Replaces the last element of list1 with the elements of list2.\n\n Args:\n list1 (list): The first list.\n list2 (list): The second list whose elements will replace the last element of list1.\n\n Returns:\n list: A new list with the last element of list1 replaced by the elements of list2.\n \"\"\"\n # Remove the last element of list1\n list1 = list1[:-1]\n # Add all elements of list2 to the end of list1\n return list1 + list2", "matching_cluster_idx": 5}, {"solution": "def replace_list(list1, list2):\n \"\"\"\n Replaces the last element of list1 with the elements of list2.\n \n Parameters:\n list1 (list): The first list where the last element will be replaced.\n list2 (list): The second list whose elements will replace the last element of list1.\n \n Returns:\n list: A new list with the last element of list1 replaced by the elements of list2.\n \"\"\"\n if not list1: # Check if list1 is empty\n return list2 # If list1 is empty, just return list2\n \n # Create a new list by combining the elements of list1 except the last one and all elements of list2\n new_list = list1[:-1] + list2\n return new_list", "matching_cluster_idx": 5}, {"solution": "def replace_list(list1, list2):\n \"\"\"\n Replaces the last element of the first list with the elements of the second list.\n \n Args:\n list1 (list): The first list.\n list2 (list): The second list.\n \n Returns:\n list: The modified first list with its last element replaced by the elements of the second list.\n \"\"\"\n # Remove the last element of list1\n list1 = list1[:-1]\n \n # Append the elements of list2 to list1\n list1.extend(list2)\n \n return list1", "matching_cluster_idx": 6}, {"solution": "def replace_list(list1, list2):\n \"\"\"\n Replaces the last element of the first list with the elements of the second list.\n \n Parameters:\n list1 (list): The first list.\n list2 (list): The second list.\n \n Returns:\n list: A new list with the last element of list1 replaced by the elements of list2.\n \"\"\"\n if not list1: # Check if list1 is empty\n return list2\n \n # Replace the last element of list1 with the elements of list2\n return list1[:-1] + list2", "matching_cluster_idx": 5}]}, "Mbpp/251": {"dps": 91.95402298850576, "dps_norm": 77.77777777777777, "pass@1": 85.0, "profiled": [{"solution": "def insert_element(lst, element):\n result = []\n for item in lst:\n result.append(element)\n result.append(item)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n \"\"\"Insert an element before each element in the given list.\n\n Args:\n lst (list): The list to insert elements into.\n element: The element to insert.\n\n Returns:\n list: A new list with the element inserted before each element of the original list.\n \"\"\"\n result = []\n for item in lst:\n result.append(element) # Insert the element\n result.append(item) # Insert the original item\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, elem):\n # Create a new list to hold the result\n result = []\n # Iterate through each element in the input list\n for item in lst:\n # Append the element to the result list\n result.append(elem)\n # Append the current item to the result list\n result.append(item)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, elem):\n \"\"\"\n Inserts the specified element before each element in the list.\n\n Args:\n lst (list): The list of elements.\n elem (any): The element to insert.\n\n Returns:\n list: A new list with the element inserted before each original element.\n \"\"\"\n result = []\n for item in lst:\n result.append(elem) # Insert the element\n result.append(item) # Insert the original item\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n result = []\n for item in lst:\n result.append(element) # Insert the element\n result.append(item) # Insert the current item\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n \"\"\"Inserts the specified element before each element in the given list.\"\"\"\n result = []\n for item in lst:\n result.append(element) # Append the element first\n result.append(item) # Then append the item from the original list\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n # Create a new list to store the results\n result = []\n # Iterate through each item in the original list\n for item in lst:\n # Append the element and the current item to the result list\n result.append(element)\n result.append(item)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n result = []\n for item in lst:\n result.append(element)\n result.append(item)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n \"\"\"Inserts the specified element before each element in the given list.\"\"\"\n result = []\n for item in lst:\n result.append(element) # Insert the element\n result.append(item) # Insert the original item\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n # Create a new list to store the result\n result = []\n # Iterate through each item in the original list\n for item in lst:\n # Append the element and then the item to the result list\n result.append(element)\n result.append(item)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n result = []\n for item in lst:\n result.append(element) # Insert the element before the current item\n result.append(item) # Append the current item\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n \"\"\"Inserts the given element before each element in the provided list.\n\n Args:\n lst (list): The list in which to insert the element.\n element: The element to insert.\n\n Returns:\n list: A new list with the element inserted before each element of the original list.\n \"\"\"\n result = []\n for item in lst:\n result.append(element)\n result.append(item)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n result = []\n for item in lst:\n result.append(element) # Insert the element before the current item\n result.append(item) # Append the current item\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n # Create a new list to hold the results\n result = []\n # Iterate over each item in the original list\n for item in lst:\n # Append the element and the current item to the result list\n result.append(element)\n result.append(item)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n result = []\n for item in lst:\n result.append(element) # Insert the element before the current item\n result.append(item) # Append the current item\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, elem):\n result = []\n for item in lst:\n result.append(elem)\n result.append(item)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n \"\"\"\n Inserts the specified element before each element in the given list.\n\n Args:\n lst (list): The original list.\n element (any): The element to insert.\n\n Returns:\n list: A new list with the element inserted before each original element.\n \"\"\"\n result = []\n for item in lst:\n result.append(element) # Insert the element\n result.append(item) # Insert the original item\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n \"\"\"\n Insert the specified element before each element in the provided list.\n\n Parameters:\n lst (list): The list to insert elements into.\n element: The element to be inserted.\n\n Returns:\n list: A new list with the element inserted before each original element.\n \"\"\"\n result = []\n for item in lst:\n result.append(element)\n result.append(item)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n result = []\n for item in lst:\n result.append(element) # Insert the element before the current item\n result.append(item) # Add the current item\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n result = []\n for item in lst:\n result.append(element) # Insert the element before the current item\n result.append(item) # Insert the current item\n return result", "matching_cluster_idx": 6}]}, "Mbpp/256": {"dps": 60.730593607305934, "dps_norm": 56.470588235294116, "pass@1": 99.0, "profiled": [{"solution": "def is_prime(n):\n \"\"\"Check if a number is prime.\"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True\ndef count_Primes_nums(n):\n \"\"\"Return the number of prime numbers less than the given non-negative number.\"\"\"\n count = 0\n for i in range(n):\n if is_prime(i):\n count += 1\n return count", "matching_cluster_idx": 8}, {"solution": "def is_prime(n):\n \"\"\"Helper function to determine if a number is prime.\"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True\ndef count_Primes_nums(num):\n \"\"\"Returns the number of prime numbers less than the given non-negative number.\"\"\"\n count = 0\n for i in range(num):\n if is_prime(i):\n count += 1\n return count", "matching_cluster_idx": 8}, {"solution": "def is_prime(n):\n \"\"\"Check if a number is prime.\"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True\ndef count_Primes_nums(n):\n \"\"\"Return the number of prime numbers less than n.\"\"\"\n count = 0\n for num in range(2, n):\n if is_prime(num):\n count += 1\n return count", "matching_cluster_idx": 8}, {"solution": "def count_Primes_nums(n):\n \"\"\"\n Returns the number of prime numbers less than the given non-negative number n.\n \"\"\"\n if n < 2:\n return 0 # There are no primes less than 2\n\n primes_count = 0\n for num in range(2, n):\n is_prime = True\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n is_prime = False\n break\n if is_prime:\n primes_count += 1\n\n return primes_count", "matching_cluster_idx": 8}, {"solution": "def is_prime(num):\n \"\"\"Check if a number is prime.\"\"\"\n if num <= 1:\n return False\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n return False\n return True\ndef count_Primes_nums(n):\n \"\"\"Return the number of prime numbers less than n.\"\"\"\n if n < 2:\n return 0\n count = 0\n for num in range(2, n):\n if is_prime(num):\n count += 1\n return count", "matching_cluster_idx": 8}, {"solution": "def count_Primes_nums(n):\n \"\"\"Returns the number of prime numbers less than the given non-negative number n.\"\"\"\n if n < 2:\n return 0\n \n # Sieve of Eratosthenes to find all primes less than n\n is_prime = [True] * n\n is_prime[0] = is_prime[1] = False # 0 and 1 are not prime numbers\n\n for i in range(2, int(n**0.5) + 1):\n if is_prime[i]:\n for j in range(i * i, n, i):\n is_prime[j] = False\n\n return sum(is_prime)", "matching_cluster_idx": 14}, {"solution": "def count_Primes_nums(n):\n \"\"\"Returns the count of prime numbers less than n.\"\"\"\n if n < 2:\n return 0\n\n def is_prime(num):\n \"\"\"Returns True if num is a prime number, otherwise False.\"\"\"\n if num < 2:\n return False\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n return False\n return True\n\n prime_count = 0\n for i in range(2, n):\n if is_prime(i):\n prime_count += 1\n\n return prime_count", "matching_cluster_idx": 8}, {"solution": "def count_Primes_nums(n):\n \"\"\"Return the number of prime numbers less than n.\"\"\"\n if n < 2:\n return 0 # There are no prime numbers less than 2\n\n primes = [True] * n # Create a boolean array \"primes[0..n-1]\"\n primes[0], primes[1] = False, False # 0 and 1 are not prime numbers\n \n for i in range(2, int(n**0.5) + 1):\n if primes[i]:\n for j in range(i * i, n, i):\n primes[j] = False # Mark multiples of i as non-prime\n\n return sum(primes) # Count the number of True values in the array", "matching_cluster_idx": 14}, {"solution": "def is_prime(num):\n \"\"\"Helper function to determine if a number is prime.\"\"\"\n if num <= 1:\n return False\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n return False\n return True\ndef count_Primes_nums(n):\n \"\"\"Returns the count of prime numbers less than the given non-negative number.\"\"\"\n count = 0\n for i in range(n):\n if is_prime(i):\n count += 1\n return count", "matching_cluster_idx": 8}, {"solution": "def is_prime(n):\n \"\"\"Check if a number is prime.\"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True\ndef count_Primes_nums(n):\n \"\"\"Return the count of prime numbers less than n.\"\"\"\n count = 0\n for number in range(2, n):\n if is_prime(number):\n count += 1\n return count", "matching_cluster_idx": 8}, {"solution": "def is_prime(num):\n \"\"\"Check if a number is prime.\"\"\"\n if num < 2:\n return False\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n return False\n return True\ndef count_Primes_nums(n):\n \"\"\"Return the number of prime numbers less than n.\"\"\"\n count = 0\n for i in range(n):\n if is_prime(i):\n count += 1\n return count", "matching_cluster_idx": 8}, {"solution": "def is_prime(n):\n \"\"\"Check if a number is prime.\"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True\ndef count_Primes_nums(n):\n \"\"\"Return the count of prime numbers less than n.\"\"\"\n count = 0\n for i in range(n):\n if is_prime(i):\n count += 1\n return count", "matching_cluster_idx": 8}, {"solution": "def is_prime(n):\n \"\"\"Check if a number is prime.\"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True\ndef count_Primes_nums(n):\n \"\"\"Return the number of prime numbers less than the given non-negative number.\"\"\"\n count = 0\n for num in range(n):\n if is_prime(num):\n count += 1\n return count", "matching_cluster_idx": 8}, {"solution": "def is_prime(n):\n \"\"\"Check if a number is prime.\"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True\ndef count_Primes_nums(n):\n \"\"\"Return the number of prime numbers less than the given non-negative number.\"\"\"\n count = 0\n for num in range(n):\n if is_prime(num):\n count += 1\n return count", "matching_cluster_idx": 8}, {"solution": "def is_prime(n):\n \"\"\"Check if a number is prime.\"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True\ndef count_Primes_nums(n):\n \"\"\"Return the number of prime numbers less than n.\"\"\"\n count = 0\n for num in range(n):\n if is_prime(num):\n count += 1\n return count", "matching_cluster_idx": 8}, {"solution": "def count_Primes_nums(n):\n \"\"\"\n Returns the number of prime numbers less than a given non-negative number n.\n \n Parameters:\n n (int): A non-negative integer.\n \n Returns:\n int: The count of prime numbers less than n.\n \"\"\"\n if n < 2:\n return 0\n\n def is_prime(num):\n \"\"\"Helper function to determine if a number is prime.\"\"\"\n if num < 2:\n return False\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n return False\n return True\n\n count = 0\n for i in range(2, n):\n if is_prime(i):\n count += 1\n\n return count", "matching_cluster_idx": 8}, {"solution": "def is_prime(n):\n \"\"\"Helper function to check if a number is prime.\"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True\ndef count_Primes_nums(n):\n \"\"\"Function to count the number of prime numbers less than a non-negative number n.\"\"\"\n count = 0\n for i in range(n):\n if is_prime(i):\n count += 1\n return count", "matching_cluster_idx": 8}, {"solution": "def is_prime(num):\n \"\"\"Check if a number is prime.\"\"\"\n if num <= 1:\n return False\n for i in range(2, int(num ** 0.5) + 1):\n if num % i == 0:\n return False\n return True\ndef count_Primes_nums(n):\n \"\"\"Return the number of prime numbers less than the given non-negative number n.\"\"\"\n count = 0\n for i in range(n):\n if is_prime(i):\n count += 1\n return count", "matching_cluster_idx": 8}, {"solution": "def is_prime(num):\n \"\"\"Return True if num is a prime number, else False.\"\"\"\n if num <= 1:\n return False\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n return False\n return True\ndef count_Primes_nums(n):\n \"\"\"Return the number of prime numbers less than the given non-negative number n.\"\"\"\n count = 0\n for number in range(n):\n if is_prime(number):\n count += 1\n return count", "matching_cluster_idx": 8}, {"solution": "def count_Primes_nums(n):\n \"\"\"\n Returns the number of prime numbers less than the given non-negative number n.\n \n Args:\n n (int): A non-negative integer.\n\n Returns:\n int: The count of prime numbers less than n.\n \"\"\"\n if n < 2:\n return 0\n \n primes_count = 0\n for num in range(2, n):\n is_prime = True\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n is_prime = False\n break\n if is_prime:\n primes_count += 1\n \n return primes_count", "matching_cluster_idx": 8}]}, "Mbpp/265": {"dps": 58.02325581395349, "dps_norm": 76.66666666666666, "pass@1": 100.0, "profiled": [{"solution": "def list_split(input_list, n):\n \"\"\"Splits the input list into sublists for every nth element.\"\"\"\n # Create a list of empty lists for each split\n result = [[] for _ in range(n)]\n \n # Iterate through the input list and append elements to the corresponding sublist\n for index, element in enumerate(input_list):\n result[index % n].append(element)\n \n return result", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n \"\"\"\n Splits a list into sublists for every nth element.\n \n Parameters:\n lst (list): The list to be split.\n n (int): The interval at which to split the list.\n \n Returns:\n list: A list containing sublists of every nth element.\n \n Example:\n >>> list_split(['a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j', 'k', 'l', 'm', 'n'], 3)\n [['a', 'd', 'g', 'j', 'm'], ['b', 'e', 'h', 'k', 'n'], ['c', 'f', 'i', 'l']]\n \"\"\"\n result = [[] for _ in range(n)]\n for index, item in enumerate(lst):\n result[index % n].append(item)\n return result", "matching_cluster_idx": 4}, {"solution": "def list_split(input_list, n):\n \"\"\"\n Splits a list into sublists for every nth element.\n\n :param input_list: List of elements to split\n :param n: Integer specifying the interval for splitting\n :return: A list of lists containing the split elements\n \"\"\"\n # Initialize a list to hold the resulting sublists\n result = [[] for _ in range(n)]\n \n # Distribute elements into the sublists based on their index\n for index, element in enumerate(input_list):\n result[index % n].append(element)\n \n return result", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n \"\"\"\n Splits a list for every nth element, returning a list of resulting lists.\n \n Parameters:\n lst (list): The list to be split.\n n (int): The interval at which to split the list.\n \n Returns:\n list: A list of lists, each containing elements spaced by n.\n \"\"\"\n # Initialize the result with empty lists for each of the n groups\n result = [[] for _ in range(n)]\n \n # Iterate through the original list and distribute elements into result\n for index, value in enumerate(lst):\n result[index % n].append(value)\n \n return result", "matching_cluster_idx": 4}, {"solution": "def list_split(input_list, n):\n \"\"\"Splits a list for every nth element.\n\n Args:\n input_list (list): The list to be split.\n n (int): The interval at which to split the list.\n\n Returns:\n list: A list of lists containing the split elements.\n \"\"\"\n # Initialize a list to hold the resulting lists\n result = [[] for _ in range(n)]\n \n # Iterate over the input list and distribute elements into the result lists\n for index, element in enumerate(input_list):\n result[index % n].append(element)\n \n return result", "matching_cluster_idx": 4}, {"solution": "def list_split(input_list, n):\n \"\"\"\n Splits a list for every nth element, returning a list of the resulting lists.\n \n Parameters:\n input_list (list): The list to be split.\n n (int): The step size to split the list.\n \n Returns:\n list: A list of lists containing every nth element.\n \"\"\"\n return [[input_list[i] for i in range(j, len(input_list), n)] for j in range(n)]", "matching_cluster_idx": 2}, {"solution": "def list_split(input_list, n):\n # Create a list of empty lists for each group\n result = [[] for _ in range(n)]\n \n # Iterate over the input list and distribute elements to the correct sublist\n for index, value in enumerate(input_list):\n result[index % n].append(value)\n \n return result", "matching_cluster_idx": 4}, {"solution": "def list_split(input_list, n):\n \"\"\"\n Splits the input_list into sublists for every nth element.\n\n Parameters:\n input_list (list): The list to be split.\n n (int): The number of elements after which to split.\n\n Returns:\n list: A list of sublists containing the elements from the input_list.\n \"\"\"\n result = []\n for i in range(n):\n sublist = []\n for j in range(i, len(input_list), n):\n sublist.append(input_list[j])\n result.append(sublist)\n return result", "matching_cluster_idx": 3}, {"solution": "def list_split(input_list, n):\n \"\"\"\n Splits the input_list into sublists, each containing elements from \n the input list taken every nth position.\n\n Parameters:\n input_list (list): The list to split.\n n (int): The step used to group elements.\n\n Returns:\n list: A list of sublists containing every nth element from the original list.\n \"\"\"\n # Initialize a list of empty sublists\n result = [[] for _ in range(n)]\n \n # Iterate over the input list and distribute elements into sublists\n for index, value in enumerate(input_list):\n result[index % n].append(value)\n \n return result", "matching_cluster_idx": 4}, {"solution": "def list_split(input_list, n):\n \"\"\"\n Splits a list for every nth element and returns a list of the resulting lists.\n \n :param input_list: List of elements to be split\n :param n: Integer specifying the interval for splitting the list\n :return: A list of lists containing elements split by every nth element\n \"\"\"\n # Create a list of lists for each index from 0 to n-1\n result = [[] for _ in range(n)]\n \n # Iterate through the input list and assign elements to their corresponding sub-list\n for index, value in enumerate(input_list):\n result[index % n].append(value)\n \n return result", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n # Create a list to hold the resulting sublists\n result = []\n # Use a range to iterate over the length of the list\n for i in range(n):\n # Use a list comprehension to get every nth element starting from index i\n result.append([lst[j] for j in range(i, len(lst), n)])\n return result", "matching_cluster_idx": 2}, {"solution": "def list_split(input_list, n):\n \"\"\"Splits input_list into sublists, returning a list of the resulting lists,\n where each sublist contains elements taken from input_list for every nth element.\"\"\"\n \n # Create a list of sublists\n result = [[] for _ in range(n)]\n \n # Iterate through the input_list and distribute elements into the appropriate sublists\n for index, element in enumerate(input_list):\n result[index % n].append(element)\n \n return result", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n \"\"\"\n Splits the input list into sublists, each containing every nth element.\n \n Args:\n lst (list): The input list to be split.\n n (int): The step size for splitting the list.\n \n Returns:\n list: A list of sublists containing the split elements.\n \"\"\"\n # Create a list of empty lists for each sublist\n result = [[] for _ in range(n)]\n \n # Fill the sublists with every nth element\n for i, item in enumerate(lst):\n result[i % n].append(item)\n \n return result", "matching_cluster_idx": 4}, {"solution": "def list_split(input_list, n):\n \"\"\"\n Splits a list into sublists, returning a list of the resulting lists,\n each containing elements spaced n apart.\n\n Parameters:\n input_list (list): The list to be split.\n n (int): The spacing between elements in the sublists.\n\n Returns:\n list: A list containing sublists with elements spaced n apart.\n \"\"\"\n # Initialize an empty list to hold the resulting sublists\n result = []\n \n # Iterate over a range of n to create sublists\n for i in range(n):\n sublist = []\n for j in range(i, len(input_list), n):\n sublist.append(input_list[j])\n result.append(sublist)\n \n return result", "matching_cluster_idx": 3}, {"solution": "def list_split(input_list, n):\n # Create a list of n empty lists\n result = [[] for _ in range(n)]\n \n # Distribute elements into the resulting lists\n for index, value in enumerate(input_list):\n result[index % n].append(value)\n \n return result", "matching_cluster_idx": 4}, {"solution": "def list_split(input_list, n):\n # Initialize the result as a list of empty lists for each \"bucket\"\n result = [[] for _ in range(n)]\n \n # Iterate through the input list and distribute elements into the buckets\n for index, element in enumerate(input_list):\n result[index % n].append(element)\n \n return result", "matching_cluster_idx": 4}, {"solution": "def list_split(input_list, n):\n \"\"\"\n Splits the input_list into sublists for every nth element.\n \n Parameters:\n input_list (list): The list to split.\n n (int): The step for splitting the list.\n \n Returns:\n list: A list of lists containing the split elements.\n \"\"\"\n # Create a list to hold the result\n result = [[] for _ in range(n)]\n \n # Populate the result lists\n for index, item in enumerate(input_list):\n result[index % n].append(item)\n \n return result", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n \"\"\"\n Splits the input list into sublists for every nth element.\n \n Parameters:\n lst (list): The list to be split.\n n (int): The interval at which to split the list.\n \n Returns:\n list: A list of sublists.\n \"\"\"\n # Initialize an empty list to hold the sublists\n result = [[] for _ in range(n)]\n \n # Iterate over the input list and distribute elements into the sublists\n for index, element in enumerate(lst):\n result[index % n].append(element)\n \n return result", "matching_cluster_idx": 4}, {"solution": "def list_split(input_list, n):\n \"\"\"\n Splits the input list for every nth element and returns a list of the resulting lists.\n\n :param input_list: List of elements to split\n :param n: Integer indicating the step size for splitting\n :return: List of lists containing the split elements\n \"\"\"\n # Initialize the result with empty lists for each \"column\"\n result = [[] for _ in range(n)]\n \n # Iterate over the input list and distribute elements into the result lists\n for index, element in enumerate(input_list):\n result[index % n].append(element)\n \n return result", "matching_cluster_idx": 4}, {"solution": "def list_split(input_list, n):\n \"\"\"\n Splits a list for every nth element and returns a list of the resulting lists.\n\n Parameters:\n input_list (list): The list to be split.\n n (int): The interval at which to split the list.\n\n Returns:\n list: A list of lists containing the elements split every nth element.\n \"\"\"\n return [[input_list[j] for j in range(i, len(input_list), n)] for i in range(n)]", "matching_cluster_idx": 2}]}, "Mbpp/281": {"dps": 94.3, "dps_norm": 82.72727272727272, "pass@1": 100.0, "profiled": [{"solution": "def all_unique(lst):\n \"\"\"\n Check if all elements in the given list are unique.\n\n Parameters:\n lst (list): The list to check for uniqueness.\n\n Returns:\n bool: True if all elements are unique, False otherwise.\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n Check if all elements in the given list are unique.\n \n Args:\n lst (list): A list of elements to check for uniqueness.\n \n Returns:\n bool: True if all elements are unique, False otherwise.\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"Check if all elements in the list are unique.\"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n Check if all elements in the list are unique.\n\n Args:\n lst (list): The list to check for uniqueness.\n\n Returns:\n bool: True if all elements are unique, False otherwise.\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n Check if all elements in the list are unique.\n\n Parameters:\n lst (list): The list to check for uniqueness.\n\n Returns:\n bool: True if all elements are unique, False otherwise.\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n Check if all elements in the list are unique.\n \n :param lst: List of elements to check\n :return: True if all elements are unique, False otherwise\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n Check if all elements in the list are unique.\n \n Parameters:\n lst (list): The list to check for unique elements.\n \n Returns:\n bool: True if all elements are unique, False otherwise.\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(input_list):\n \"\"\"\n Check if all elements in the input list are unique.\n\n Parameters:\n input_list (list): The list to check for uniqueness.\n\n Returns:\n bool: True if all elements are unique, False otherwise.\n \"\"\"\n return len(input_list) == len(set(input_list))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n Check if all elements in the list are unique.\n\n Args:\n lst (list): The list to check for uniqueness.\n\n Returns:\n bool: True if all elements are unique, False otherwise.\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n Check if all elements in the given list are unique.\n\n Parameters:\n lst (list): The list to check for uniqueness.\n\n Returns:\n bool: True if all elements are unique, False otherwise.\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n Check if all elements in the list are unique.\n\n Parameters:\n lst (list): The list to check for uniqueness.\n\n Returns:\n bool: True if all elements are unique, False otherwise.\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n Check if all elements in the list are unique.\n \n Args:\n lst (list): The list to check for uniqueness.\n \n Returns:\n bool: True if all elements are unique, False otherwise.\n \"\"\"\n # Use a set to track unique elements\n seen = set()\n for item in lst:\n if item in seen:\n return False\n seen.add(item)\n return True", "matching_cluster_idx": 10}, {"solution": "def all_unique(lst):\n \"\"\"\n Check if all elements in the given list are unique.\n\n Args:\n lst (list): The list to check for unique elements.\n\n Returns:\n bool: True if all elements are unique, False otherwise.\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n Check if all elements in the list are unique.\n \n Parameters:\n lst (list): The list of elements to check.\n \n Returns:\n bool: True if all elements are unique, False otherwise.\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(input_list):\n \"\"\"\n Check if all elements in the input list are unique.\n\n Parameters:\n input_list (list): The list to check for uniqueness.\n\n Returns:\n bool: True if all elements are unique, False otherwise.\n \"\"\"\n return len(input_list) == len(set(input_list))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n Check if all elements in the given list are unique.\n \n Parameters:\n lst (list): The list to check for uniqueness.\n \n Returns:\n bool: True if all elements are unique, False otherwise.\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(elements):\n \"\"\"\n Check if all elements in the list are unique.\n\n Parameters:\n elements (list): A list of elements to check for uniqueness.\n\n Returns:\n bool: True if all elements are unique, False otherwise.\n \"\"\"\n return len(elements) == len(set(elements))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n Check if all elements in the list are unique.\n\n Parameters:\n lst (list): The list to check for uniqueness.\n\n Returns:\n bool: True if all elements are unique, False otherwise.\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n Check if all elements in the given list are unique.\n \n Args:\n lst (list): The list to check for uniqueness.\n \n Returns:\n bool: True if all elements are unique, False otherwise.\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n Check if all elements in the given list are unique.\n\n Args:\n lst (list): The list to check for uniqueness.\n\n Returns:\n bool: True if all elements are unique, False otherwise.\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}]}, "Mbpp/296": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def merge_and_count(arr, temp_arr, left, mid, right):\n i = left # Starting index for left subarray\n j = mid + 1 # Starting index for right subarray\n k = left # Starting index to be sorted\n inv_count = 0\n \n while i <= mid and j <= right:\n if arr[i] <= arr[j]:\n temp_arr[k] = arr[i]\n i += 1\n else:\n temp_arr[k] = arr[j]\n inv_count += (mid - i + 1)\n j += 1\n k += 1\n\n while i <= mid:\n temp_arr[k] = arr[i]\n i += 1\n k += 1\n \n while j <= right:\n temp_arr[k] = arr[j]\n j += 1\n k += 1\n\n for i in range(left, right + 1):\n arr[i] = temp_arr[i]\n \n return inv_count\ndef merge_sort_and_count(arr, temp_arr, left, right):\n inv_count = 0\n if left < right:\n mid = (left + right) // 2\n inv_count += merge_sort_and_count(arr, temp_arr, left, mid)\n inv_count += merge_sort_and_count(arr, temp_arr, mid + 1, right)\n inv_count += merge_and_count(arr, temp_arr, left, mid, right)\n\n return inv_count\ndef get_Inv_Count(arr):\n temp_arr = [0]*len(arr)\n return merge_sort_and_count(arr, temp_arr, 0, len(arr) - 1)", "matching_cluster_idx": 5}, {"solution": "def merge_and_count(arr, temp_arr, left, mid, right):\n i = left # Starting index for left subarray\n j = mid + 1 # Starting index for right subarray\n k = left # Starting index to be sorted\n inv_count = 0\n \n while i <= mid and j <= right:\n if arr[i] <= arr[j]:\n temp_arr[k] = arr[i]\n i += 1\n else:\n # There are mid - i inversions, because all elements left to i\n # in the left subarray are greater than arr[j]\n temp_arr[k] = arr[j]\n inv_count += (mid - i + 1)\n j += 1\n k += 1\n \n # Copy the remaining elements of left subarray, if any\n while i <= mid:\n temp_arr[k] = arr[i]\n i += 1\n k += 1\n \n # Copy the remaining elements of right subarray, if any\n while j <= right:\n temp_arr[k] = arr[j]\n j += 1\n k += 1\n \n # Copy the sorted subarray into Original array\n for i in range(left, right + 1):\n arr[i] = temp_arr[i]\n \n return inv_count\ndef merge_sort_and_count(arr, temp_arr, left, right):\n inv_count = 0\n if left < right:\n mid = (left + right) // 2\n \n inv_count += merge_sort_and_count(arr, temp_arr, left, mid)\n inv_count += merge_sort_and_count(arr, temp_arr, mid + 1, right)\n \n inv_count += merge_and_count(arr, temp_arr, left, mid, right)\n \n return inv_count\ndef get_Inv_Count(arr):\n temp_arr = [0] * len(arr)\n return merge_sort_and_count(arr, temp_arr, 0, len(arr) - 1)", "matching_cluster_idx": 5}, {"solution": "def merge_and_count(arr, temp_arr, left, mid, right):\n i = left # Starting index for left subarray\n j = mid + 1 # Starting index for right subarray\n k = left # Starting index to be sorted\n inv_count = 0\n\n # Conditions are checked to ensure that i doesn't exceed mid and j doesn't exceed right\n while i <= mid and j <= right:\n if arr[i] <= arr[j]:\n temp_arr[k] = arr[i]\n i += 1\n else:\n # There are mid - i inversions because all remaining elements in the left subarray\n # (arr[i], arr[i+1], ..., arr[mid]) are greater than arr[j]\n temp_arr[k] = arr[j]\n inv_count += (mid - i + 1)\n j += 1\n k += 1\n\n # Copy the remaining elements of left subarray, if any\n while i <= mid:\n temp_arr[k] = arr[i]\n i += 1\n k += 1\n\n # Copy the remaining elements of right subarray, if any\n while j <= right:\n temp_arr[k] = arr[j]\n j += 1\n k += 1\n\n # Copy the sorted subarray into Original array\n for i in range(left, right + 1):\n arr[i] = temp_arr[i]\n\n return inv_count\ndef merge_sort_and_count(arr, temp_arr, left, right):\n inv_count = 0\n if left < right:\n mid = (left + right) // 2\n\n inv_count += merge_sort_and_count(arr, temp_arr, left, mid)\n inv_count += merge_sort_and_count(arr, temp_arr, mid + 1, right)\n inv_count += merge_and_count(arr, temp_arr, left, mid, right)\n\n return inv_count\ndef get_Inv_Count(arr):\n n = len(arr)\n temp_arr = [0] * n\n return merge_sort_and_count(arr, temp_arr, 0, n - 1)", "matching_cluster_idx": 5}, {"solution": "def merge_and_count(arr, temp_arr, left, mid, right):\n i = left # Starting index for left subarray\n j = mid + 1 # Starting index for right subarray\n k = left # Starting index to be sorted\n inv_count = 0\n \n while i <= mid and j <= right:\n if arr[i] <= arr[j]:\n temp_arr[k] = arr[i]\n i += 1\n else:\n temp_arr[k] = arr[j]\n inv_count += (mid - i + 1)\n j += 1\n k += 1\n \n while i <= mid:\n temp_arr[k] = arr[i]\n i += 1\n k += 1\n \n while j <= right:\n temp_arr[k] = arr[j]\n j += 1\n k += 1\n \n for i in range(left, right + 1):\n arr[i] = temp_arr[i]\n \n return inv_count\ndef merge_sort_and_count(arr, temp_arr, left, right):\n inv_count = 0\n if left < right:\n mid = (left + right) // 2\n\n inv_count += merge_sort_and_count(arr, temp_arr, left, mid)\n inv_count += merge_sort_and_count(arr, temp_arr, mid + 1, right)\n inv_count += merge_and_count(arr, temp_arr, left, mid, right)\n\n return inv_count\ndef get_Inv_Count(arr):\n temp_arr = [0] * len(arr)\n return merge_sort_and_count(arr, temp_arr, 0, len(arr) - 1)", "matching_cluster_idx": 5}, {"solution": "def merge_and_count(arr, temp_arr, left, mid, right):\n i = left # Starting index for left subarray\n j = mid + 1 # Starting index for right subarray\n k = left # Starting index to be sorted\n inv_count = 0\n\n while i <= mid and j <= right:\n if arr[i] <= arr[j]:\n temp_arr[k] = arr[i]\n i += 1\n else:\n # There are mid - i inversions, because all remaining elements in the left subarray (arr[i..mid]) \n # are greater than arr[j]\n temp_arr[k] = arr[j]\n inv_count += (mid - i + 1)\n j += 1\n k += 1\n\n # Copy the remaining elements of left subarray, if any\n while i <= mid:\n temp_arr[k] = arr[i]\n i += 1\n k += 1\n\n # Copy the remaining elements of right subarray, if any\n while j <= right:\n temp_arr[k] = arr[j]\n j += 1\n k += 1\n\n # Copy the sorted subarray into Original array\n for i in range(left, right + 1):\n arr[i] = temp_arr[i]\n\n return inv_count\ndef merge_sort_and_count(arr, temp_arr, left, right):\n inv_count = 0\n if left < right:\n mid = (left + right) // 2\n\n inv_count += merge_sort_and_count(arr, temp_arr, left, mid)\n inv_count += merge_sort_and_count(arr, temp_arr, mid + 1, right)\n inv_count += merge_and_count(arr, temp_arr, left, mid, right)\n\n return inv_count\ndef get_Inv_Count(arr):\n temp_arr = [0] * len(arr)\n return merge_sort_and_count(arr, temp_arr, 0, len(arr) - 1)", "matching_cluster_idx": 5}, {"solution": "def merge_and_count(arr, temp_arr, left, mid, right):\n i = left # Starting index for left subarray\n j = mid + 1 # Starting index for right subarray\n k = left # Starting index to be sorted\n inv_count = 0\n\n while i <= mid and j <= right:\n if arr[i] <= arr[j]:\n temp_arr[k] = arr[i]\n i += 1\n else:\n temp_arr[k] = arr[j]\n inv_count += (mid - i + 1) # There are mid - i inversions\n j += 1\n k += 1\n\n while i <= mid:\n temp_arr[k] = arr[i]\n i += 1\n k += 1\n\n while j <= right:\n temp_arr[k] = arr[j]\n j += 1\n k += 1\n\n for i in range(left, right + 1):\n arr[i] = temp_arr[i]\n\n return inv_count\ndef merge_sort_and_count(arr, temp_arr, left, right):\n inv_count = 0\n if left < right:\n mid = (left + right) // 2\n\n inv_count += merge_sort_and_count(arr, temp_arr, left, mid)\n inv_count += merge_sort_and_count(arr, temp_arr, mid + 1, right)\n inv_count += merge_and_count(arr, temp_arr, left, mid, right)\n\n return inv_count\ndef get_Inv_Count(arr):\n temp_arr = [0] * len(arr)\n return merge_sort_and_count(arr, temp_arr, 0, len(arr) - 1)", "matching_cluster_idx": 5}, {"solution": "def merge_and_count(arr, temp_arr, left, mid, right):\n i = left # Starting index for left subarray\n j = mid + 1 # Starting index for right subarray\n k = left # Starting index to be sorted\n inv_count = 0\n\n while i <= mid and j <= right:\n if arr[i] <= arr[j]:\n temp_arr[k] = arr[i]\n i += 1\n else:\n temp_arr[k] = arr[j]\n inv_count += (mid - i + 1) # There are mid - i inversions\n j += 1\n k += 1\n\n while i <= mid:\n temp_arr[k] = arr[i]\n i += 1\n k += 1\n\n while j <= right:\n temp_arr[k] = arr[j]\n j += 1\n k += 1\n\n for i in range(left, right + 1):\n arr[i] = temp_arr[i]\n\n return inv_count\ndef merge_sort_and_count(arr, temp_arr, left, right):\n inv_count = 0\n if left < right:\n mid = (left + right) // 2\n\n inv_count += merge_sort_and_count(arr, temp_arr, left, mid)\n inv_count += merge_sort_and_count(arr, temp_arr, mid + 1, right)\n inv_count += merge_and_count(arr, temp_arr, left, mid, right)\n\n return inv_count\ndef get_Inv_Count(arr):\n temp_arr = [0] * len(arr)\n return merge_sort_and_count(arr, temp_arr, 0, len(arr) - 1)", "matching_cluster_idx": 5}, {"solution": "def merge_and_count(arr, temp_arr, left, mid, right):\n i = left # Starting index for left subarray\n j = mid + 1 # Starting index for right subarray\n k = left # Starting index to be sorted\n inv_count = 0\n\n # Conditions are checked to ensure that i doesn't exceed mid and j doesn't exceed right\n while i <= mid and j <= right:\n if arr[i] <= arr[j]:\n temp_arr[k] = arr[i]\n i += 1\n else:\n # There are mid - i inversions, because all remaining elements in the left subarray (arr[i:mid]) \n # are greater than arr[j]\n temp_arr[k] = arr[j]\n inv_count += (mid - i + 1)\n j += 1\n k += 1\n\n # Copy the remaining elements of left subarray, if any\n while i <= mid:\n temp_arr[k] = arr[i]\n i += 1\n k += 1\n\n # Copy the remaining elements of right subarray, if any\n while j <= right:\n temp_arr[k] = arr[j]\n j += 1\n k += 1\n\n # Copy the sorted subarray into Original array\n for i in range(left, right + 1):\n arr[i] = temp_arr[i]\n\n return inv_count\ndef merge_sort_and_count(arr, temp_arr, left, right):\n inv_count = 0\n if left < right:\n mid = (left + right) // 2\n\n inv_count += merge_sort_and_count(arr, temp_arr, left, mid)\n inv_count += merge_sort_and_count(arr, temp_arr, mid + 1, right)\n\n inv_count += merge_and_count(arr, temp_arr, left, mid, right)\n\n return inv_count\ndef get_Inv_Count(arr):\n n = len(arr)\n temp_arr = [0] * n\n return merge_sort_and_count(arr, temp_arr, 0, n - 1)", "matching_cluster_idx": 5}, {"solution": "def merge_and_count(arr, temp_arr, left, mid, right):\n i = left # Starting index for left subarray\n j = mid + 1 # Starting index for right subarray\n k = left # Starting index to be sorted\n inv_count = 0\n \n while i <= mid and j <= right:\n if arr[i] <= arr[j]:\n temp_arr[k] = arr[i]\n i += 1\n else:\n temp_arr[k] = arr[j]\n inv_count += (mid - i + 1) # Count inversions\n j += 1\n k += 1\n \n while i <= mid:\n temp_arr[k] = arr[i]\n i += 1\n k += 1\n \n while j <= right:\n temp_arr[k] = arr[j]\n j += 1\n k += 1\n \n for i in range(left, right + 1):\n arr[i] = temp_arr[i]\n \n return inv_count\ndef merge_sort_and_count(arr, temp_arr, left, right):\n inv_count = 0\n if left < right:\n mid = (left + right) // 2\n \n inv_count += merge_sort_and_count(arr, temp_arr, left, mid)\n inv_count += merge_sort_and_count(arr, temp_arr, mid + 1, right)\n \n inv_count += merge_and_count(arr, temp_arr, left, mid, right)\n \n return inv_count\ndef get_Inv_Count(arr):\n temp_arr = [0] * len(arr)\n return merge_sort_and_count(arr, temp_arr, 0, len(arr) - 1)", "matching_cluster_idx": 5}, {"solution": "def merge_and_count(arr, temp_arr, left, mid, right):\n i = left # Starting index for left subarray\n j = mid + 1 # Starting index for right subarray\n k = left # Starting index to be sorted\n inv_count = 0\n\n while i <= mid and j <= right:\n if arr[i] <= arr[j]:\n temp_arr[k] = arr[i]\n i += 1\n else:\n temp_arr[k] = arr[j]\n inv_count += (mid - i + 1) # There are mid - i inversions, as all remaining elements in the left subarray (arr[i...mid]) are greater than arr[j]\n j += 1\n k += 1\n\n while i <= mid:\n temp_arr[k] = arr[i]\n i += 1\n k += 1\n\n while j <= right:\n temp_arr[k] = arr[j]\n j += 1\n k += 1\n\n for i in range(left, right + 1):\n arr[i] = temp_arr[i]\n\n return inv_count\ndef merge_sort_and_count(arr, temp_arr, left, right):\n inv_count = 0\n if left < right:\n mid = (left + right) // 2\n\n inv_count += merge_sort_and_count(arr, temp_arr, left, mid)\n inv_count += merge_sort_and_count(arr, temp_arr, mid + 1, right)\n inv_count += merge_and_count(arr, temp_arr, left, mid, right)\n\n return inv_count\ndef get_Inv_Count(arr):\n temp_arr = [0] * len(arr)\n return merge_sort_and_count(arr, temp_arr, 0, len(arr) - 1)", "matching_cluster_idx": 5}, {"solution": "def merge_and_count(arr, temp_arr, left, mid, right):\n i = left # Starting index for left subarray\n j = mid + 1 # Starting index for right subarray\n k = left # Starting index to be sorted\n inv_count = 0\n\n while i <= mid and j <= right:\n if arr[i] <= arr[j]:\n temp_arr[k] = arr[i]\n i += 1\n else:\n temp_arr[k] = arr[j]\n inv_count += (mid - i + 1) # Count inversions\n j += 1\n k += 1\n\n while i <= mid:\n temp_arr[k] = arr[i]\n i += 1\n k += 1\n\n while j <= right:\n temp_arr[k] = arr[j]\n j += 1\n k += 1\n\n for i in range(left, right + 1):\n arr[i] = temp_arr[i]\n\n return inv_count\ndef merge_sort_and_count(arr, temp_arr, left, right):\n inv_count = 0\n if left < right:\n mid = (left + right) // 2\n\n inv_count += merge_sort_and_count(arr, temp_arr, left, mid)\n inv_count += merge_sort_and_count(arr, temp_arr, mid + 1, right)\n inv_count += merge_and_count(arr, temp_arr, left, mid, right)\n\n return inv_count\ndef get_Inv_Count(arr):\n temp_arr = [0] * len(arr)\n return merge_sort_and_count(arr, temp_arr, 0, len(arr) - 1)", "matching_cluster_idx": 5}, {"solution": "def merge_and_count(arr, temp_arr, left, mid, right):\n i = left # Starting index for left subarray\n j = mid + 1 # Starting index for right subarray\n k = left # Starting index to be sorted\n inv_count = 0\n\n while i <= mid and j <= right:\n if arr[i] <= arr[j]:\n temp_arr[k] = arr[i]\n i += 1\n else:\n # There are mid - i inversions, because all elements left to i in the left subarray\n # are greater than arr[j]\n temp_arr[k] = arr[j]\n inv_count += (mid - i + 1)\n j += 1\n k += 1\n\n while i <= mid:\n temp_arr[k] = arr[i]\n i += 1\n k += 1\n\n while j <= right:\n temp_arr[k] = arr[j]\n j += 1\n k += 1\n\n for i in range(left, right + 1):\n arr[i] = temp_arr[i]\n\n return inv_count\ndef merge_sort_and_count(arr, temp_arr, left, right):\n inv_count = 0\n if left < right:\n mid = (left + right) // 2\n\n inv_count += merge_sort_and_count(arr, temp_arr, left, mid)\n inv_count += merge_sort_and_count(arr, temp_arr, mid + 1, right)\n inv_count += merge_and_count(arr, temp_arr, left, mid, right)\n\n return inv_count\ndef get_Inv_Count(arr):\n temp_arr = [0] * len(arr)\n return merge_sort_and_count(arr, temp_arr, 0, len(arr) - 1)", "matching_cluster_idx": 5}, {"solution": "def merge_and_count(arr, temp_arr, left, mid, right):\n i = left # Starting index for left subarray\n j = mid + 1 # Starting index for right subarray\n k = left # Starting index to be sorted\n inv_count = 0\n \n # Conditions are checked to ensure that i doesn't exceed mid and j doesn't exceed right\n while i <= mid and j <= right:\n if arr[i] <= arr[j]:\n temp_arr[k] = arr[i]\n i += 1\n else:\n # There are mid - i inversions, because all remaining elements in the left subarray\n # (arr[i], arr[i+1], ..., arr[mid]) are greater than arr[j]\n temp_arr[k] = arr[j]\n inv_count += (mid - i + 1)\n j += 1\n k += 1\n \n # Copy the remaining elements of left subarray, if any\n while i <= mid:\n temp_arr[k] = arr[i]\n i += 1\n k += 1\n \n # Copy the remaining elements of right subarray, if any\n while j <= right:\n temp_arr[k] = arr[j]\n j += 1\n k += 1\n \n # Copy the sorted subarray into Original array\n for i in range(left, right + 1):\n arr[i] = temp_arr[i]\n \n return inv_count\ndef merge_sort_and_count(arr, temp_arr, left, right):\n inv_count = 0\n if left < right:\n mid = (left + right) // 2\n \n inv_count += merge_sort_and_count(arr, temp_arr, left, mid)\n inv_count += merge_sort_and_count(arr, temp_arr, mid + 1, right)\n \n inv_count += merge_and_count(arr, temp_arr, left, mid, right)\n \n return inv_count\ndef get_Inv_Count(arr):\n temp_arr = [0]*len(arr)\n return merge_sort_and_count(arr, temp_arr, 0, len(arr) - 1)", "matching_cluster_idx": 5}, {"solution": "def merge_and_count(arr, temp_arr, left, mid, right):\n \"\"\"Merge two halves and count inversions.\"\"\"\n i = left # Starting index for left subarray\n j = mid + 1 # Starting index for right subarray\n k = left # Starting index to be sorted\n inv_count = 0\n\n while i <= mid and j <= right:\n if arr[i] <= arr[j]:\n temp_arr[k] = arr[i]\n i += 1\n else:\n # There are mid - i inversions, because all elements left to i in\n # the left subarray are greater than arr[j]\n temp_arr[k] = arr[j]\n inv_count += (mid - i + 1)\n j += 1\n k += 1\n\n # Copy the remaining elements of left subarray, if any\n while i <= mid:\n temp_arr[k] = arr[i]\n i += 1\n k += 1\n\n # Copy the remaining elements of right subarray, if any\n while j <= right:\n temp_arr[k] = arr[j]\n j += 1\n k += 1\n\n # Copy the sorted subarray into Original array\n for i in range(left, right + 1):\n arr[i] = temp_arr[i]\n\n return inv_count\ndef merge_sort_and_count(arr, temp_arr, left, right):\n \"\"\"Sort the array and count inversions.\"\"\"\n inv_count = 0\n if left < right:\n mid = (left + right) // 2\n\n inv_count += merge_sort_and_count(arr, temp_arr, left, mid)\n inv_count += merge_sort_and_count(arr, temp_arr, mid + 1, right)\n inv_count += merge_and_count(arr, temp_arr, left, mid, right)\n\n return inv_count\ndef get_Inv_Count(arr):\n \"\"\"Count inversions in the array.\"\"\"\n temp_arr = [0] * len(arr)\n return merge_sort_and_count(arr, temp_arr, 0, len(arr) - 1)", "matching_cluster_idx": 5}, {"solution": "def merge_and_count(arr, temp_arr, left, mid, right):\n i = left # Starting index for left subarray\n j = mid + 1 # Starting index for right subarray\n k = left # Starting index to be sorted\n inv_count = 0\n\n # Conditions are checked to ensure that i doesn't exceed mid and j doesn't exceed right\n while i <= mid and j <= right:\n if arr[i] <= arr[j]:\n temp_arr[k] = arr[i]\n i += 1\n else:\n # There are mid - i inversions, because all remaining elements in left subarray\n # (arr[i], arr[i+1], ..., arr[mid]) are greater than arr[j]\n temp_arr[k] = arr[j]\n inv_count += (mid - i + 1)\n j += 1\n k += 1\n\n # Copy the remaining elements of left subarray, if any\n while i <= mid:\n temp_arr[k] = arr[i]\n i += 1\n k += 1\n\n # Copy the remaining elements of right subarray, if any\n while j <= right:\n temp_arr[k] = arr[j]\n j += 1\n k += 1\n\n # Copy the sorted subarray into Original array\n for i in range(left, right + 1):\n arr[i] = temp_arr[i]\n\n return inv_count\ndef merge_sort_and_count(arr, temp_arr, left, right):\n inv_count = 0\n if left < right:\n mid = (left + right) // 2\n\n inv_count += merge_sort_and_count(arr, temp_arr, left, mid)\n inv_count += merge_sort_and_count(arr, temp_arr, mid + 1, right)\n inv_count += merge_and_count(arr, temp_arr, left, mid, right)\n\n return inv_count\ndef get_Inv_Count(arr):\n temp_arr = [0] * len(arr)\n return merge_sort_and_count(arr, temp_arr, 0, len(arr) - 1)", "matching_cluster_idx": 5}, {"solution": "def merge_and_count(arr, temp_arr, left, mid, right):\n i = left # Starting index for left subarray\n j = mid + 1 # Starting index for right subarray\n k = left # Starting index to be sorted\n inv_count = 0\n\n while i <= mid and j <= right:\n if arr[i] <= arr[j]:\n temp_arr[k] = arr[i]\n i += 1\n else:\n # There are mid - i inversions, because all remaining elements in\n # the left subarray (arr[i] ... arr[mid]) are greater than arr[j]\n temp_arr[k] = arr[j]\n inv_count += (mid - i + 1)\n j += 1\n k += 1\n\n # Copy the remaining elements of left subarray, if any\n while i <= mid:\n temp_arr[k] = arr[i]\n i += 1\n k += 1\n\n # Copy the remaining elements of right subarray, if any\n while j <= right:\n temp_arr[k] = arr[j]\n j += 1\n k += 1\n\n # Copy the sorted subarray into Original array\n for i in range(left, right + 1):\n arr[i] = temp_arr[i]\n\n return inv_count\ndef merge_sort_and_count(arr, temp_arr, left, right):\n inv_count = 0\n if left < right:\n mid = (left + right) // 2\n\n inv_count += merge_sort_and_count(arr, temp_arr, left, mid)\n inv_count += merge_sort_and_count(arr, temp_arr, mid + 1, right)\n inv_count += merge_and_count(arr, temp_arr, left, mid, right)\n\n return inv_count\ndef get_Inv_Count(arr):\n temp_arr = [0]*len(arr)\n return merge_sort_and_count(arr, temp_arr, 0, len(arr) - 1)", "matching_cluster_idx": 5}, {"solution": "def merge_and_count(arr, temp_arr, left, mid, right):\n i = left # Starting index for left subarray\n j = mid + 1 # Starting index for right subarray\n k = left # Starting index to be sorted\n inv_count = 0\n \n while i <= mid and j <= right:\n if arr[i] <= arr[j]:\n temp_arr[k] = arr[i]\n i += 1\n else:\n temp_arr[k] = arr[j]\n inv_count += (mid - i + 1) # There are mid - i inversions\n j += 1\n k += 1\n\n while i <= mid:\n temp_arr[k] = arr[i]\n i += 1\n k += 1\n\n while j <= right:\n temp_arr[k] = arr[j]\n j += 1\n k += 1\n\n for i in range(left, right + 1):\n arr[i] = temp_arr[i]\n \n return inv_count\ndef merge_sort_and_count(arr, temp_arr, left, right):\n inv_count = 0\n if left < right:\n mid = (left + right) // 2\n \n inv_count += merge_sort_and_count(arr, temp_arr, left, mid)\n inv_count += merge_sort_and_count(arr, temp_arr, mid + 1, right)\n inv_count += merge_and_count(arr, temp_arr, left, mid, right)\n\n return inv_count\ndef get_Inv_Count(arr):\n temp_arr = [0]*len(arr)\n return merge_sort_and_count(arr, temp_arr, 0, len(arr) - 1)", "matching_cluster_idx": 5}, {"solution": "def merge_and_count(arr, temp_arr, left, mid, right):\n i = left # Starting index for left subarray\n j = mid + 1 # Starting index for right subarray\n k = left # Starting index to be sorted\n inv_count = 0\n\n while i <= mid and j <= right:\n if arr[i] <= arr[j]:\n temp_arr[k] = arr[i]\n i += 1\n else:\n # There are mid - i inversions, because all elements left to i in the left subarray\n # are greater than arr[j]\n temp_arr[k] = arr[j]\n inv_count += (mid - i + 1)\n j += 1\n k += 1\n\n # Copy the remaining elements of left subarray, if any\n while i <= mid:\n temp_arr[k] = arr[i]\n i += 1\n k += 1\n\n # Copy the remaining elements of right subarray, if any\n while j <= right:\n temp_arr[k] = arr[j]\n j += 1\n k += 1\n\n # Copy the sorted subarray into Original array\n for i in range(left, right + 1):\n arr[i] = temp_arr[i]\n \n return inv_count\ndef merge_sort_and_count(arr, temp_arr, left, right):\n inv_count = 0\n if left < right:\n mid = (left + right) // 2\n\n inv_count += merge_sort_and_count(arr, temp_arr, left, mid)\n inv_count += merge_sort_and_count(arr, temp_arr, mid + 1, right)\n inv_count += merge_and_count(arr, temp_arr, left, mid, right)\n\n return inv_count\ndef get_Inv_Count(arr):\n temp_arr = [0] * len(arr)\n return merge_sort_and_count(arr, temp_arr, 0, len(arr) - 1)", "matching_cluster_idx": 5}, {"solution": "def merge_and_count(arr, temp_arr, left, mid, right):\n i = left # Starting index for left subarray\n j = mid + 1 # Starting index for right subarray\n k = left # Starting index to be sorted\n inv_count = 0\n\n # Conditions are checked to ensure that i doesn't exceed mid and j doesn't exceed right\n while i <= mid and j <= right:\n if arr[i] <= arr[j]:\n temp_arr[k] = arr[i]\n i += 1\n else:\n # There are mid - i inversions, because all elements left to i in the left subarray\n # are greater than arr[j]\n temp_arr[k] = arr[j]\n inv_count += (mid - i + 1)\n j += 1\n k += 1\n\n # Copy the remaining elements of left subarray, if any\n while i <= mid:\n temp_arr[k] = arr[i]\n i += 1\n k += 1\n\n # Copy the remaining elements of right subarray, if any\n while j <= right:\n temp_arr[k] = arr[j]\n j += 1\n k += 1\n\n # Copy the sorted subarray into Original array\n for i in range(left, right + 1):\n arr[i] = temp_arr[i]\n\n return inv_count\ndef merge_sort_and_count(arr, temp_arr, left, right):\n inv_count = 0\n if left < right:\n mid = (left + right) // 2\n\n inv_count += merge_sort_and_count(arr, temp_arr, left, mid)\n inv_count += merge_sort_and_count(arr, temp_arr, mid + 1, right)\n inv_count += merge_and_count(arr, temp_arr, left, mid, right)\n\n return inv_count\ndef get_Inv_Count(arr):\n temp_arr = [0] * len(arr)\n return merge_sort_and_count(arr, temp_arr, 0, len(arr) - 1)", "matching_cluster_idx": 5}, {"solution": "def merge_and_count(arr, temp_arr, left, mid, right):\n i = left # Starting index for left subarray\n j = mid + 1 # Starting index for right subarray\n k = left # Starting index to be sorted\n inv_count = 0\n\n # Conditions are checked to ensure that i doesn't exceed mid and j doesn't exceed right\n while i <= mid and j <= right:\n if arr[i] <= arr[j]:\n temp_arr[k] = arr[i]\n i += 1\n else:\n # There are mid - i inversions because all the remaining elements in the left subarray\n # (arr[i], arr[i+1], ..., arr[mid]) are greater than arr[j]\n temp_arr[k] = arr[j]\n inv_count += (mid - i + 1)\n j += 1\n k += 1\n\n # Copy the remaining elements of left subarray, if any\n while i <= mid:\n temp_arr[k] = arr[i]\n i += 1\n k += 1\n\n # Copy the remaining elements of right subarray, if any\n while j <= right:\n temp_arr[k] = arr[j]\n j += 1\n k += 1\n\n # Copy the sorted subarray into Original array\n for i in range(left, right + 1):\n arr[i] = temp_arr[i]\n\n return inv_count\ndef merge_sort_and_count(arr, temp_arr, left, right):\n inv_count = 0\n if left < right:\n mid = (left + right) // 2\n\n inv_count += merge_sort_and_count(arr, temp_arr, left, mid)\n inv_count += merge_sort_and_count(arr, temp_arr, mid + 1, right)\n inv_count += merge_and_count(arr, temp_arr, left, mid, right)\n\n return inv_count\ndef get_Inv_Count(arr):\n n = len(arr)\n temp_arr = [0] * n\n return merge_sort_and_count(arr, temp_arr, 0, n - 1)", "matching_cluster_idx": 5}]}, "Mbpp/308": {"dps": 97.58620689655173, "dps_norm": 66.66666666666667, "pass@1": 99.0, "profiled": [{"solution": "def large_product(list1, list2, n):\n # Generate all possible products\n products = []\n for num1 in list1:\n for num2 in list2:\n products.append(num1 * num2)\n \n # Sort the products in descending order and select the top n\n products.sort(reverse=True)\n \n # Return the top n products\n return products[:n]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n # Create a list to hold the products of all combinations\n products = []\n \n # Calculate the product of each combination of elements from both lists\n for num1 in list1:\n for num2 in list2:\n products.append(num1 * num2)\n \n # Sort the products in descending order and take the largest n products\n largest_products = sorted(products, reverse=True)[:n]\n \n return largest_products", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n # Create a list to hold all products\n products = []\n \n # Calculate products of each combination of factors from both lists\n for num1 in list1:\n for num2 in list2:\n products.append(num1 * num2)\n \n # Sort products in descending order and get the top n products\n largest_products = sorted(products, reverse=True)[:n]\n \n return largest_products", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n # Calculate the products of each combination of elements from the two lists\n products = [a * b for a in list1 for b in list2]\n \n # Sort the products in descending order and get the top n products\n largest_products = sorted(products, reverse=True)[:n]\n \n return largest_products", "matching_cluster_idx": 3}, {"solution": "from itertools import product\ndef large_product(list1, list2, n):\n # Create all possible products from the two lists\n products = [a * b for a, b in product(list1, list2)]\n \n # Sort the products in descending order and select the top n\n largest_products = sorted(products, reverse=True)[:n]\n \n return largest_products", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n # Generate all possible products\n products = [a * b for a in list1 for b in list2]\n \n # Sort the products in descending order and get the top n products\n largest_products = sorted(products, reverse=True)[:n]\n \n return largest_products", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n \"\"\"\n Finds the n largest products from two lists, selecting one factor from each list.\n\n :param list1: List of integers\n :param list2: List of integers\n :param n: Number of largest products to return\n :return: List of the n largest products\n \"\"\"\n # Generate all possible products from both lists\n products = [x * y for x in list1 for y in list2]\n\n # Sort the products in descending order and get the n largest\n largest_products = sorted(products, reverse=True)[:n]\n\n return largest_products", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n # Generate all possible products from the two lists\n products = []\n for i in list1:\n for j in list2:\n products.append(i * j)\n\n # Sort the products in descending order and select the top n\n largest_products = sorted(products, reverse=True)[:n]\n \n return largest_products", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n # Generate all possible products from one element of list1 and one element of list2\n products = [x * y for x in list1 for y in list2]\n \n # Sort the products in descending order and select the top n products\n largest_products = sorted(products, reverse=True)[:n]\n \n return largest_products", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n # Calculate the products of all pairs (a, b) where a is from list1 and b is from list2\n products = [a * b for a in list1 for b in list2]\n \n # Sort the products in descending order and get the top 'n' products\n top_products = sorted(products, reverse=True)[:n]\n \n return top_products", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n \"\"\"\n Find the specified number of largest products from two given lists,\n selecting one factor from each list.\n \n Args:\n list1: List of integers.\n list2: List of integers.\n n: Number of largest products to return.\n \n Returns:\n A list of the n largest products, sorted in descending order.\n \"\"\"\n # Generate all possible products\n products = [a * b for a in list1 for b in list2]\n \n # Sort the products in descending order and get the top n products\n largest_products = sorted(products, reverse=True)[:n]\n \n return largest_products", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n # Calculate all possible products\n products = []\n for num1 in list1:\n for num2 in list2:\n products.append(num1 * num2)\n \n # Remove duplicates and sort in descending order\n unique_products = list(set(products))\n unique_products.sort(reverse=True)\n \n # Return the top n largest products\n return unique_products[:n]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n # Calculate all possible products from the two lists\n products = []\n for num1 in list1:\n for num2 in list2:\n products.append(num1 * num2)\n\n # Sort the products in descending order and select the top 'n' products\n largest_products = sorted(products, reverse=True)[:n]\n \n return largest_products", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n # Generate all possible products\n products = []\n for num1 in list1:\n for num2 in list2:\n products.append(num1 * num2)\n\n # Sort the products in descending order and get the top n products\n largest_products = sorted(products, reverse=True)[:n]\n \n return largest_products", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n # Calculate all possible products between the two lists\n products = []\n for num1 in list1:\n for num2 in list2:\n products.append(num1 * num2)\n\n # Sort the products in descending order and get the top n products\n top_n_products = sorted(products, reverse=True)[:n]\n \n return top_n_products", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n # Generate all possible products from one element in list1 and one in list2\n products = [a * b for a in list1 for b in list2]\n \n # Sort the products in descending order and take the top n products\n largest_products = sorted(products, reverse=True)[:n]\n \n return largest_products", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n # Generate all possible products\n products = [a * b for a in list1 for b in list2]\n \n # Sort the products in descending order and take the top n products\n largest_products = sorted(products, reverse=True)[:n]\n \n return largest_products", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n # Generate all possible products from list1 and list2\n products = [x * y for x in list1 for y in list2]\n \n # Sort the products in descending order and get the top n products\n largest_products = sorted(products, reverse=True)[:n]\n \n return largest_products", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n # Calculate all possible products from the two lists\n products = []\n for num1 in list1:\n for num2 in list2:\n products.append(num1 * num2)\n \n # Sort the products in descending order and get the largest n products\n largest_products = sorted(products, reverse=True)[:n]\n return largest_products", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n # Generate all possible products\n products = []\n for num1 in list1:\n for num2 in list2:\n products.append(num1 * num2)\n\n # Sort the products in descending order and select the top n products\n largest_products = sorted(products, reverse=True)[:n]\n \n return largest_products", "matching_cluster_idx": 3}]}, "Mbpp/392": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 96.0, "profiled": [{"solution": "def get_max_sum(n, memo={}):\n # Check if the value is already computed\n if n in memo:\n return memo[n]\n \n # Base case: if n is 0, the maximum sum is also 0\n if n == 0:\n return 0\n\n # Calculate the maximum sum using the recursive formula\n max_sum = max(get_max_sum(n // 2, memo) + \n get_max_sum(n // 3, memo) + \n get_max_sum(n // 4, memo) + \n get_max_sum(n // 5, memo), n)\n\n # Store the computed value in memo\n memo[n] = max_sum\n return max_sum", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n # Create a memoization dictionary to store already computed values\n memo = {}\n\n def f(n):\n # Base case: if n is 0, the maximum sum is 0\n if n == 0:\n return 0\n # If the value is already computed, return it from the memo dictionary\n if n in memo:\n return memo[n]\n \n # Calculate the maximum sum using the recursive formula\n max_sum = max(f(n // 2) + f(n // 3) + f(n // 4) + f(n // 5), n)\n \n # Store the computed value in the memo dictionary\n memo[n] = max_sum\n return max_sum\n \n return f(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n, memo={}):\n if n in memo:\n return memo[n]\n if n < 1:\n return 0\n # Calculate the maximum sum using the provided equation\n max_sum = max(get_max_sum(n // 2, memo) + get_max_sum(n // 3, memo) +\n get_max_sum(n // 4, memo) + get_max_sum(n // 5, memo), n)\n memo[n] = max_sum\n return max_sum", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n, memo=None):\n if memo is None:\n memo = {}\n\n if n in memo:\n return memo[n]\n\n if n <= 0:\n return 0\n\n # Recursive case: calculate the maximum sum using the given equation\n max_sum = max(get_max_sum(n // 2, memo) + get_max_sum(n // 3, memo) + \n get_max_sum(n // 4, memo) + get_max_sum(n // 5, memo), n)\n\n memo[n] = max_sum\n return max_sum", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n # Create a cache to store already computed values\n memo = {}\n\n def f(n):\n # Base case: if n is 0, the maximum sum is 0\n if n == 0:\n return 0\n # If the result is already computed, return it from the cache\n if n in memo:\n return memo[n]\n # Calculate the maximum sum using the given equation\n max_sum = max(f(n // 2) + f(n // 3) + f(n // 4) + f(n // 5), n)\n # Store the result in the cache\n memo[n] = max_sum\n return max_sum\n\n return f(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n # Create a cache to store previously computed results\n cache = {}\n\n def f(n):\n # If n is 0, the maximum sum is 0\n if n == 0:\n return 0\n # If the result is already computed, return it from the cache\n if n in cache:\n return cache[n]\n \n # Recursively compute the sum for n/2, n/3, n/4, n/5\n max_sum = f(n // 2) + f(n // 3) + f(n // 4) + f(n // 5)\n # Take the maximum of the computed sum and n\n cache[n] = max(max_sum, n)\n return cache[n]\n\n return f(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n # Create a memoization dictionary to store previously computed results\n memo = {}\n\n def f(n):\n # Base case: if n is 0, the maximum sum is 0\n if n == 0:\n return 0\n # Check if the result is already computed\n if n in memo:\n return memo[n]\n \n # Recursive case: calculate the maximum sum using the given equation\n max_sum = max(f(n // 2) + f(n // 3) + f(n // 4) + f(n // 5), n)\n \n # Store the computed result in memoization dictionary\n memo[n] = max_sum\n return max_sum\n \n # Call the recursive function\n return f(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n # A dictionary to store previously computed results\n memo = {}\n\n def helper(x):\n # If the result is already computed, return it\n if x in memo:\n return memo[x]\n\n # If x is 0, the maximum sum is also 0\n if x == 0:\n return 0\n\n # Calculate the maximum sum using the given equation\n max_sum = max(helper(x // 2) + helper(x // 3) + helper(x // 4) + helper(x // 5), x)\n\n # Store the computed result in the memo dictionary\n memo[x] = max_sum\n return max_sum\n\n # Start the recursion with the given n\n return helper(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n # Create a memoization dictionary to store previously computed results\n memo = {}\n\n def f(n):\n # If the result is already computed, return it\n if n in memo:\n return memo[n]\n \n # Base case for n = 0\n if n == 0:\n return 0\n \n # Calculate the maximum sum using the given equation\n max_sum = max(f(n // 2) + f(n // 3) + f(n // 4) + f(n // 5), n)\n \n # Store the computed result in the memoization dictionary\n memo[n] = max_sum\n return max_sum\n\n # Compute the maximum sum for the given n\n return f(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n # Base case for the recursion\n if n <= 0:\n return 0\n # Check if the value is already computed\n if n in memo:\n return memo[n]\n \n # Recursive calculation\n max_sum = max(get_max_sum(n // 2) + get_max_sum(n // 3) + get_max_sum(n // 4) + get_max_sum(n // 5), n)\n \n # Store the computed value in memoization dictionary\n memo[n] = max_sum\n return max_sum\nmemo = {}", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n # Create a memoization dictionary to store the results of already computed f(n)\n memo = {}\n \n def f(n):\n # If the result for f(n) is already computed, return it\n if n in memo:\n return memo[n]\n \n # Base case: if n is 0, the maximum sum is 0\n if n == 0:\n return 0\n \n # Calculate the maximum sum using the provided equation\n max_sum = max(f(n // 2) + f(n // 3) + f(n // 4) + f(n // 5), n)\n \n # Store the result in the memoization dictionary\n memo[n] = max_sum\n return max_sum\n \n # Call the helper function f(n)\n return f(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n # Use a dictionary to memoize the results\n memo = {}\n\n def f(n):\n # Check if the value is already computed\n if n in memo:\n return memo[n]\n \n # Base case\n if n == 0:\n return 0\n \n # Recursively calculate the maximum sum\n max_sum = max(f(n // 2) + f(n // 3) + f(n // 4) + f(n // 5), n)\n \n # Store the result in the memo dictionary\n memo[n] = max_sum\n return max_sum\n\n return f(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n, memo={}):\n # Base case: if n is 0, the maximum sum is 0\n if n == 0:\n return 0\n # Check if the result is already computed and stored in memo\n if n in memo:\n return memo[n]\n \n # Calculate the maximum sum using the recursive formula\n max_sum = max(get_max_sum(n // 2, memo) + \n get_max_sum(n // 3, memo) + \n get_max_sum(n // 4, memo) + \n get_max_sum(n // 5, memo), n)\n \n # Store the computed result in the memo dictionary\n memo[n] = max_sum\n return max_sum", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n # Using a dictionary to store computed values for memoization\n memo = {}\n\n def f(n):\n # Base case: if n is 0, the maximum sum is 0\n if n == 0:\n return 0\n # Check if the value is already computed\n if n in memo:\n return memo[n]\n \n # Calculate the maximum sum according to the given equation\n max_sum = max(f(n // 2) + f(n // 3) + f(n // 4) + f(n // 5), n)\n \n # Store the computed value in the memo dictionary\n memo[n] = max_sum\n return max_sum\n\n # Call the helper function to compute the result for the given n\n return f(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n, memo={}):\n # Check if we have already computed the result for this n\n if n in memo:\n return memo[n]\n \n # If n is 0, the maximum sum is 0\n if n == 0:\n return 0\n\n # Calculate the maximum sum using the recursive formula\n max_sum = max(get_max_sum(n // 2, memo) + \n get_max_sum(n // 3, memo) + \n get_max_sum(n // 4, memo) + \n get_max_sum(n // 5, memo), n)\n \n # Store the result in the memo dictionary for future reference\n memo[n] = max_sum\n return max_sum", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n # Dictionary to store computed results for memoization\n memo = {}\n\n def f(n):\n # Base case: if n is 0, the maximum sum is also 0\n if n == 0:\n return 0\n # Return the result if it's already computed\n if n in memo:\n return memo[n]\n # Calculate the maximum sum using the given equation\n max_sum = max(f(n // 2) + f(n // 3) + f(n // 4) + f(n // 5), n)\n # Store the result in the memo dictionary\n memo[n] = max_sum\n return max_sum\n\n return f(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n # Use a dictionary to memoize the results of previous calculations\n memo = {}\n\n def f(n):\n if n in memo:\n return memo[n]\n # Base case for n = 0\n if n == 0:\n return 0\n # Calculate the maximum sum according to the given equation\n max_sum = max(f(n // 2) + f(n // 3) + f(n // 4) + f(n // 5), n)\n memo[n] = max_sum\n return max_sum\n\n return f(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n # Use a dictionary to store previously computed results\n memo = {}\n\n def f(n):\n # Base case: if n is 0, return 0\n if n == 0:\n return 0\n # Check if the result is already computed\n if n in memo:\n return memo[n]\n # Compute the maximum sum according to the given equation\n result = max(f(n // 2) + f(n // 3) + f(n // 4) + f(n // 5), n)\n # Store the computed result in the memoization dictionary\n memo[n] = result\n return result\n\n return f(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n # Use memoization to store already computed results\n memo = {}\n \n def f(n):\n # Base case: if n is 0, the maximum sum is 0\n if n == 0:\n return 0\n # Check if result is already computed\n if n in memo:\n return memo[n]\n \n # Calculate the maximum sum using the given equation\n max_sum = max(f(n // 2) + f(n // 3) + f(n // 4) + f(n // 5), n)\n \n # Store the computed result in the memo dictionary\n memo[n] = max_sum\n return max_sum\n \n return f(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n # Use a dictionary to store previously computed results for optimization\n memo = {}\n\n def f(x):\n if x in memo:\n return memo[x]\n if x == 0:\n return 0\n # Calculate the maximum sum using the given equation\n max_sum = max(f(x // 2) + f(x // 3) + f(x // 4) + f(x // 5), x)\n memo[x] = max_sum\n return max_sum\n\n return f(n)", "matching_cluster_idx": 12}]}, "Mbpp/395": {"dps": 98.08429118773947, "dps_norm": 75.0, "pass@1": 100.0, "profiled": [{"solution": "def first_non_repeating_character(s):\n \"\"\"\n Find the first non-repeated character in a given string.\n\n :param s: The input string\n :return: The first non-repeated character or None if all characters are repeated\n \"\"\"\n character_count = {}\n \n # Count occurrences of each character in the string\n for char in s:\n character_count[char] = character_count.get(char, 0) + 1\n \n # Find the first character that has a count of 1\n for char in s:\n if character_count[char] == 1:\n return char\n \n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n \"\"\"Return the first non-repeating character in the string s, or None if all characters are repeated.\"\"\"\n char_count = {}\n\n # Count the occurrences of each character in the string\n for char in s:\n char_count[char] = char_count.get(char, 0) + 1\n\n # Find the first character in the string that has a count of 1\n for char in s:\n if char_count[char] == 1:\n return char\n\n # Return None if no non-repeating character is found\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n \"\"\"\n Function to find the first non-repeated character in a string.\n \n Args:\n s (str): Input string\n \n Returns:\n str or None: First non-repeated character or None if no such character exists\n \"\"\"\n char_count = {}\n \n # Count occurrences of each character in the string\n for char in s:\n char_count[char] = char_count.get(char, 0) + 1\n\n # Find the first character in the string that has a count of 1\n for char in s:\n if char_count[char] == 1:\n return char\n \n # If no non-repeated character is found, return None\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n # Create a dictionary to count the occurrences of each character\n char_count = {}\n \n # Count the occurrences of each character in the string\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n \n # Find the first character in the string that has a count of 1\n for char in s:\n if char_count[char] == 1:\n return char\n \n # If there are no non-repeating characters, return None\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n \"\"\"\n Finds the first non-repeated character in a given string.\n \n :param s: Input string\n :return: First non-repeated character or None if all characters are repeated\n \"\"\"\n # Dictionary to store character counts\n char_count = {}\n\n # Count each character in the string\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n\n # Find the first character with a count of 1\n for char in s:\n if char_count[char] == 1:\n return char\n\n # If no non-repeated character is found\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n \"\"\"\n Find the first non-repeated character in a given string.\n \n :param s: Input string\n :return: The first non-repeated character or None if all characters are repeated.\n \"\"\"\n char_count = {}\n\n # Count the occurrences of each character in the string\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n\n # Find the first character that occurs only once\n for char in s:\n if char_count[char] == 1:\n return char\n\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s: str) -> str:\n \"\"\"\n Function to find the first non-repeated character in a given string.\n \n Parameters:\n s (str): The input string to check.\n \n Returns:\n str: The first non-repeated character, or None if there are no non-repeated characters.\n \"\"\"\n character_count = {}\n\n # Count occurrences of each character\n for char in s:\n if char in character_count:\n character_count[char] += 1\n else:\n character_count[char] = 1\n\n # Find the first non-repeated character\n for char in s:\n if character_count[char] == 1:\n return char\n\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s: str) -> str:\n \"\"\"Find the first non-repeated character in the string.\"\"\"\n char_count = {}\n \n # Count occurrences of each character\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n \n # Find the first character with a count of 1\n for char in s:\n if char_count[char] == 1:\n return char\n \n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s: str) -> str:\n \"\"\"\n Function to find the first non-repeated character in a given string.\n \n :param s: Input string\n :return: First non-repeated character or None if all characters are repeated\n \"\"\"\n char_count = {}\n \n # Count occurrences of each character\n for char in s:\n char_count[char] = char_count.get(char, 0) + 1\n \n # Find the first character with a count of 1\n for char in s:\n if char_count[char] == 1:\n return char\n \n # If no non-repeating character is found, return None\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n # Create a dictionary to count occurrences of each character\n char_count = {}\n \n # Count occurrences of each character in the string\n for char in s:\n char_count[char] = char_count.get(char, 0) + 1\n \n # Find the first character in the string with a count of 1\n for char in s:\n if char_count[char] == 1:\n return char\n \n # If no non-repeating character is found, return None\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n # Create a dictionary to count occurrences of each character\n char_count = {}\n \n # Count each character in the string\n for char in s:\n char_count[char] = char_count.get(char, 0) + 1\n \n # Find the first character with a count of 1\n for char in s:\n if char_count[char] == 1:\n return char\n \n # If no non-repeated character is found, return None\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n \"\"\"\n This function finds the first non-repeated character in a given string.\n \n :param s: The input string to search for non-repeated characters.\n :return: The first non-repeated character or None if all characters are repeated.\n \"\"\"\n char_count = {}\n \n # Count the occurrences of each character in the string\n for char in s:\n char_count[char] = char_count.get(char, 0) + 1\n \n # Find the first character that has a count of 1\n for char in s:\n if char_count[char] == 1:\n return char\n \n # If all characters are repeated, return None\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n # Create a dictionary to count occurrences of each character\n char_count = {}\n \n # Count each character in the string\n for char in s:\n char_count[char] = char_count.get(char, 0) + 1\n \n # Find the first character with a count of 1\n for char in s:\n if char_count[char] == 1:\n return char\n \n # If no non-repeating character is found, return None\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n # Dictionary to count occurrences of each character\n char_count = {}\n \n # Count each character in the string\n for char in s:\n char_count[char] = char_count.get(char, 0) + 1\n \n # Find the first non-repeated character\n for char in s:\n if char_count[char] == 1:\n return char\n \n return None # Return None if there are no non-repeated characters", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n char_count = {}\n\n # Count occurrences of each character\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n\n # Find the first non-repeated character\n for char in s:\n if char_count[char] == 1:\n return char\n\n return None # All characters are repeated", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s: str) -> str:\n \"\"\"\n Find the first non-repeated character in a given string.\n\n Args:\n s (str): The input string.\n\n Returns:\n str: The first non-repeated character, or None if all characters are repeated.\n \"\"\"\n char_count = {}\n\n # Count the occurrences of each character\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n\n # Find the first character that occurs only once\n for char in s:\n if char_count[char] == 1:\n return char\n\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n char_count = {}\n\n # Count the occurrences of each character in the string\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n\n # Find the first non-repeated character\n for char in s:\n if char_count[char] == 1:\n return char\n\n # If no non-repeated character is found, return None\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n \"\"\"\n Find the first non-repeated character in a given string.\n\n Args:\n s (str): The input string.\n\n Returns:\n str or None: The first non-repeating character or None if all characters are repeated.\n \"\"\"\n char_count = {}\n\n # Count occurrences of each character\n for char in s:\n char_count[char] = char_count.get(char, 0) + 1\n\n # Find the first non-repeated character\n for char in s:\n if char_count[char] == 1:\n return char\n\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s: str) -> str:\n \"\"\"\n Function to find the first non-repeated character in a given string.\n \n Args:\n s (str): The input string to be processed.\n\n Returns:\n str: The first non-repeated character if found, otherwise None.\n \"\"\"\n char_count = {}\n \n # Count the occurrences of each character in the string\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n\n # Find the first character with a count of 1\n for char in s:\n if char_count[char] == 1:\n return char\n\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n # Create a dictionary to count the occurrences of each character\n char_count = {}\n \n # Count each character in the string\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n \n # Find the first character that has a count of 1\n for char in s:\n if char_count[char] == 1:\n return char\n \n return None # Return None if there is no non-repeating character", "matching_cluster_idx": 5}]}, "Mbpp/405": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def check_tuplex(tup, element):\n \"\"\"\n Check whether an element exists within a tuple.\n\n Parameters:\n tup (tuple): The tuple to search.\n element: The element to search for.\n\n Returns:\n bool: True if the element exists in the tuple, False otherwise.\n \"\"\"\n return element in tup", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tup, element):\n \"\"\"\n Check if an element exists within a tuple.\n\n Parameters:\n tup (tuple): The tuple to search.\n element: The element to search for.\n\n Returns:\n bool: True if the element is found, False otherwise.\n \"\"\"\n return element in tup", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tup, element):\n \"\"\"\n Check if an element exists within a tuple.\n\n Parameters:\n tup (tuple): The tuple to search in.\n element: The element to search for.\n\n Returns:\n bool: True if the element exists in the tuple, False otherwise.\n \"\"\"\n return element in tup", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(input_tuple, element):\n \"\"\"Check if an element exists within a given tuple.\"\"\"\n return element in input_tuple", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tup, element):\n \"\"\"\n Check whether an element exists within a tuple.\n\n Parameters:\n tup (tuple): The tuple to search.\n element (any): The element to find in the tuple.\n\n Returns:\n bool: True if the element exists in the tuple, False otherwise.\n \"\"\"\n return element in tup", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tup, element):\n \"\"\"\n Check whether an element exists within a tuple.\n\n Args:\n tup (tuple): The tuple to be checked.\n element: The element to search for in the tuple.\n\n Returns:\n bool: True if the element exists in the tuple, False otherwise.\n \"\"\"\n return element in tup", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(input_tuple, element):\n \"\"\"Check if an element exists within a tuple.\"\"\"\n return element in input_tuple", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tup, element):\n \"\"\"\n Checks whether an element exists within a tuple.\n\n Parameters:\n tup (tuple): The tuple to search in.\n element: The element to search for.\n\n Returns:\n bool: True if the element exists in the tuple, False otherwise.\n \"\"\"\n return element in tup", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tup, element):\n \"\"\"Check if an element exists in a tuple.\"\"\"\n return element in tup", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tup, element):\n \"\"\"\n Check if an element exists within a tuple.\n\n Parameters:\n tup (tuple): The tuple to check.\n element: The element to search for.\n\n Returns:\n bool: True if the element is found, False otherwise.\n \"\"\"\n return element in tup", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tup, element):\n \"\"\"\n Check whether an element exists within a tuple.\n \n Args:\n tup (tuple): The tuple to check.\n element: The element to search for.\n\n Returns:\n bool: True if the element exists in the tuple, False otherwise.\n \"\"\"\n return element in tup", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tup, element):\n \"\"\"\n Check whether an element exists within a tuple.\n\n Args:\n tup (tuple): The tuple to check.\n element: The element to search for in the tuple.\n\n Returns:\n bool: True if the element exists in the tuple, False otherwise.\n \"\"\"\n return element in tup", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tup, element):\n \"\"\"Check if an element exists within a tuple.\"\"\"\n return element in tup", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(t, element):\n \"\"\"\n Check whether an element exists within a tuple.\n \n Parameters:\n t (tuple): The tuple to search in.\n element: The element to search for.\n\n Returns:\n bool: True if the element exists in the tuple, False otherwise.\n \"\"\"\n return element in t", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tup, element):\n \"\"\"\n Checks if the specified element exists in the given tuple.\n\n Args:\n tup (tuple): The tuple to search within.\n element: The element to search for.\n\n Returns:\n bool: True if the element is found in the tuple, False otherwise.\n \"\"\"\n return element in tup", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tup, element):\n \"\"\"Check if the specified element exists in the given tuple.\"\"\"\n return element in tup", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tup, element):\n \"\"\"\n Check whether an element exists within a tuple.\n \n Parameters:\n tup (tuple): The tuple to check.\n element: The element to search for.\n \n Returns:\n bool: True if the element is found in the tuple, False otherwise.\n \"\"\"\n return element in tup", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tup, element):\n \"\"\"\n Check whether an element exists within a tuple.\n \n :param tup: Tuple in which to search for the element.\n :param element: Element to search for in the tuple.\n :return: True if the element exists in the tuple, False otherwise.\n \"\"\"\n return element in tup", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tup, element):\n \"\"\"\n Check if an element exists within a tuple.\n\n Parameters:\n tup (tuple): The tuple to check.\n element: The element to search for.\n\n Returns:\n bool: True if the element is found, False otherwise.\n \"\"\"\n return element in tup", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tup, element):\n \"\"\"\n Check whether an element exists within a tuple.\n\n Parameters:\n tup (tuple): The tuple to search in.\n element: The element to search for.\n\n Returns:\n bool: True if the element exists in the tuple, False otherwise.\n \"\"\"\n return element in tup", "matching_cluster_idx": 3}]}, "Mbpp/414": {"dps": 68.35403726708074, "dps_norm": 83.33333333333333, "pass@1": 100.0, "profiled": [{"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Check whether any value in the first sequence exists in the second sequence.\n\n Parameters:\n seq1 (iterable): The first sequence.\n seq2 (iterable): The second sequence.\n\n Returns:\n bool: True if there is an overlap, False otherwise.\n \"\"\"\n return any(item in seq2 for item in seq1)", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Check whether any value in seq1 exists in seq2.\n\n :param seq1: First sequence (list, set, etc.)\n :param seq2: Second sequence (list, set, etc.)\n :return: True if there is at least one common element, False otherwise\n \"\"\"\n # Convert the sequences to sets for efficient lookup\n set1 = set(seq1)\n set2 = set(seq2)\n \n # Check for intersection\n return not set1.isdisjoint(set2)", "matching_cluster_idx": 6}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Check whether any value in seq1 exists in seq2.\n \n Parameters:\n seq1 (iterable): First sequence to check.\n seq2 (iterable): Second sequence to check against.\n \n Returns:\n bool: True if there is an overlap, False otherwise.\n \"\"\"\n return not set(seq1).isdisjoint(set(seq2))", "matching_cluster_idx": 6}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Check whether any value in seq1 exists in seq2.\n \n Args:\n seq1 (iterable): First sequence to check.\n seq2 (iterable): Second sequence to check against.\n \n Returns:\n bool: True if there is any overlapping value, False otherwise.\n \"\"\"\n # Use set intersection to find any common elements\n return not set(seq1).isdisjoint(set(seq2))", "matching_cluster_idx": 6}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Check if there are any common elements between two sequences.\n\n Parameters:\n seq1 (iterable): First sequence to check.\n seq2 (iterable): Second sequence to check.\n\n Returns:\n bool: True if there is at least one common element, False otherwise.\n \"\"\"\n # Convert the sequences to sets and check for intersection\n return not set(seq1).isdisjoint(set(seq2))", "matching_cluster_idx": 6}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Check whether any value in the first sequence exists in the second sequence.\n \n Parameters:\n seq1 (iterable): The first sequence to check.\n seq2 (iterable): The second sequence to check against.\n \n Returns:\n bool: True if there is an overlap, False otherwise.\n \"\"\"\n # Convert the second sequence to a set for O(1) average time complexity lookups\n set_seq2 = set(seq2)\n \n # Check if any element in seq1 exists in set_seq2\n for item in seq1:\n if item in set_seq2:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Check whether any value in the first sequence exists in the second sequence.\n \n Parameters:\n seq1 (iterable): First sequence to check.\n seq2 (iterable): Second sequence to check against.\n \n Returns:\n bool: True if there is at least one common value, False otherwise.\n \"\"\"\n # Convert the second sequence to a set for efficient look-up\n set_seq2 = set(seq2)\n \n # Check for any overlap\n for item in seq1:\n if item in set_seq2:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Check whether any value in the first sequence exists in the second sequence.\n\n Parameters:\n seq1 (iterable): The first sequence to check.\n seq2 (iterable): The second sequence to check against.\n\n Returns:\n bool: True if there is an overlap, False otherwise.\n \"\"\"\n return any(item in seq2 for item in seq1)", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Check whether any value in the first sequence exists in the second sequence.\n \n Parameters:\n seq1 (iterable): The first sequence.\n seq2 (iterable): The second sequence.\n \n Returns:\n bool: True if there is at least one common value, otherwise False.\n \"\"\"\n # Convert both sequences to sets to find any intersection\n return not set(seq1).isdisjoint(set(seq2))", "matching_cluster_idx": 6}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Check whether any value in seq1 exists in seq2.\n\n Args:\n seq1: A sequence (list, tuple, etc.) of elements.\n seq2: A sequence (list, tuple, etc.) of elements.\n\n Returns:\n bool: True if there is any overlap, False otherwise.\n \"\"\"\n # Convert the second sequence to a set for O(1) average time complexity on membership tests\n set_seq2 = set(seq2)\n # Check for any overlapping values\n for item in seq1:\n if item in set_seq2:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Check whether any value in the first sequence exists in the second sequence.\n \n :param seq1: First sequence (can be a list, set, or any iterable)\n :param seq2: Second sequence (can be a list, set, or any iterable)\n :return: True if there is any overlap, False otherwise\n \"\"\"\n # Convert sequences to sets for efficient lookup\n set1 = set(seq1)\n set2 = set(seq2)\n \n # Check for intersection\n return not set1.isdisjoint(set2)", "matching_cluster_idx": 6}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"Check if there are any overlapping values between two sequences.\"\"\"\n return any(value in seq1 for value in seq2)", "matching_cluster_idx": 8}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Check whether any value in seq1 exists in seq2.\n \n Args:\n seq1: A sequence (e.g., list or tuple).\n seq2: A sequence (e.g., list or tuple).\n \n Returns:\n True if there is any overlap, False otherwise.\n \"\"\"\n return any(item in seq2 for item in seq1)", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Check if there is any overlap between two sequences.\n \n Parameters:\n seq1 (iterable): The first sequence.\n seq2 (iterable): The second sequence.\n \n Returns:\n bool: True if there is an overlap, False otherwise.\n \"\"\"\n # Convert both sequences to sets to take advantage of O(1) average time complexity for lookups\n set1 = set(seq1)\n set2 = set(seq2)\n \n # Check if there is any intersection between the two sets\n return not set1.isdisjoint(set2)", "matching_cluster_idx": 6}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Check if there are any overlapping values between two sequences.\n\n Parameters:\n seq1 (iterable): First sequence.\n seq2 (iterable): Second sequence.\n\n Returns:\n bool: True if there are overlapping values, False otherwise.\n \"\"\"\n return not set(seq1).isdisjoint(set(seq2))", "matching_cluster_idx": 6}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Check whether any value in the first sequence exists in the second sequence.\n\n Parameters:\n seq1 (iterable): The first sequence to check.\n seq2 (iterable): The second sequence to check against.\n\n Returns:\n bool: True if any value in seq1 exists in seq2, False otherwise.\n \"\"\"\n return any(item in seq2 for item in seq1)", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Check if there is any overlap between two sequences.\n \n Args:\n seq1: The first sequence (list, tuple, etc.)\n seq2: The second sequence (list, tuple, etc.)\n \n Returns:\n bool: True if there is at least one common element, False otherwise.\n \"\"\"\n # Convert one of the sequences to a set for faster lookup\n set_seq2 = set(seq2)\n \n # Check if any element in seq1 exists in set_seq2\n for item in seq1:\n if item in set_seq2:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"Check whether any value in seq1 exists in seq2.\"\"\"\n # Using set intersection to determine if there are common elements\n return bool(set(seq1) & set(seq2))", "matching_cluster_idx": 5}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Check if there are any overlapping values between two sequences.\n\n Parameters:\n seq1 (iterable): First sequence (list, set, etc.)\n seq2 (iterable): Second sequence (list, set, etc.)\n\n Returns:\n bool: True if there is at least one overlapping value, False otherwise.\n \"\"\"\n # Convert sequences to sets for faster lookup\n set1 = set(seq1)\n set2 = set(seq2)\n \n # Check for intersection\n return not set1.isdisjoint(set2)", "matching_cluster_idx": 6}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Check whether any value in seq1 exists in seq2.\n\n Parameters:\n seq1 (iterable): First sequence to check.\n seq2 (iterable): Second sequence to check against.\n\n Returns:\n bool: True if there is at least one common element, False otherwise.\n \"\"\"\n # Convert seq2 to a set for faster lookup\n set_seq2 = set(seq2)\n \n # Check for any overlap\n for item in seq1:\n if item in set_seq2:\n return True\n return False", "matching_cluster_idx": 7}]}, "Mbpp/421": {"dps": 60.32921810699589, "dps_norm": 85.0, "pass@1": 100.0, "profiled": [{"solution": "def concatenate_tuple(input_tuple, delimiter='-'):\n \"\"\"Concatenates each element of the tuple by the delimiter.\"\"\"\n return delimiter.join(map(str, input_tuple))", "matching_cluster_idx": 6}, {"solution": "def concatenate_tuple(elements, delimiter='-'):\n \"\"\"\n Concatenates each element of a tuple by the specified delimiter.\n\n Args:\n elements (tuple): The tuple containing elements to concatenate.\n delimiter (str): The delimiter to use for concatenation (default is '-').\n\n Returns:\n str: The concatenated string.\n \"\"\"\n # Convert all elements to strings and join them using the delimiter\n return delimiter.join(str(element) for element in elements)", "matching_cluster_idx": 4}, {"solution": "def concatenate_tuple(input_tuple, delimiter='-'):\n # Convert all elements in the tuple to string and join them with the delimiter\n return delimiter.join(str(element) for element in input_tuple)", "matching_cluster_idx": 4}, {"solution": "def concatenate_tuple(tup, delimiter='-'):\n \"\"\"\n Concatenate each element of a tuple by the specified delimiter.\n \n Parameters:\n tup (tuple): The input tuple containing elements to concatenate.\n delimiter (str): The delimiter used for concatenation (default is '-').\n\n Returns:\n str: The concatenated string.\n \"\"\"\n return delimiter.join(map(str, tup))", "matching_cluster_idx": 6}, {"solution": "def concatenate_tuple(input_tuple, delimiter='-'):\n \"\"\"\n Concatenates each element of a tuple into a string with a specified delimiter.\n \n Args:\n input_tuple (tuple): The tuple containing elements to concatenate.\n delimiter (str): The delimiter to use for concatenation. Default is '-'.\n \n Returns:\n str: A string of concatenated elements.\n \"\"\"\n # Convert all elements to string and join them with the delimiter\n return delimiter.join(map(str, input_tuple))", "matching_cluster_idx": 5}, {"solution": "def concatenate_tuple(elements, delimiter='-'):\n \"\"\"\n Concatenate each element of a tuple by the delimiter.\n\n Parameters:\n elements (tuple): A tuple of elements to concatenate.\n delimiter (str): The delimiter to use for concatenation (default is '-').\n\n Returns:\n str: The concatenated string.\n \"\"\"\n # Convert all elements to strings and join them with the delimiter\n return delimiter.join(str(element) for element in elements)", "matching_cluster_idx": 4}, {"solution": "def concatenate_tuple(tup, delimiter='-'):\n \"\"\"Concatenate each element of the tuple by the specified delimiter.\"\"\"\n # Convert all elements to string and join with the delimiter\n return delimiter.join(map(str, tup))", "matching_cluster_idx": 6}, {"solution": "def concatenate_tuple(tup, delimiter='-'):\n \"\"\"\n Concatenate each element of the tuple by the specified delimiter.\n\n Parameters:\n tup (tuple): The tuple containing elements to concatenate.\n delimiter (str): The delimiter to use for concatenation. Defaults to '-'.\n\n Returns:\n str: The concatenated string.\n \"\"\"\n return delimiter.join(map(str, tup))", "matching_cluster_idx": 5}, {"solution": "def concatenate_tuple(elements, delimiter='-'):\n \"\"\"\n Concatenate each element of the tuple by the delimiter.\n \n Args:\n elements (tuple): The tuple containing elements to be concatenated.\n delimiter (str): The delimiter to use for concatenation. Default is '-'.\n \n Returns:\n str: A string that concatenates the elements of the tuple.\n \"\"\"\n return delimiter.join(map(str, elements))", "matching_cluster_idx": 6}, {"solution": "def concatenate_tuple(elements, delimiter='-'):\n \"\"\"\n Concatenates each element of the tuple by the delimiter.\n\n :param elements: A tuple of elements to concatenate.\n :param delimiter: The delimiter to use for concatenation.\n :return: A string representing the concatenated elements.\n \"\"\"\n return delimiter.join(map(str, elements))", "matching_cluster_idx": 6}, {"solution": "def concatenate_tuple(input_tuple, delimiter='-'):\n \"\"\"\n Concatenates each element of the tuple by the specified delimiter.\n \n Parameters:\n input_tuple (tuple): The tuple containing elements to concatenate.\n delimiter (str): The delimiter used for concatenation. Default is '-'.\n \n Returns:\n str: The concatenated string.\n \"\"\"\n # Convert each element to string and join them with the delimiter\n return delimiter.join(map(str, input_tuple))", "matching_cluster_idx": 5}, {"solution": "def concatenate_tuple(tup, delimiter='-'):\n \"\"\"Concatenates each element of the tuple using the specified delimiter.\n\n Args:\n tup (tuple): The tuple containing elements to concatenate.\n delimiter (str): The delimiter to use for concatenation.\n\n Returns:\n str: A string that is the concatenation of the tuple elements.\n \"\"\"\n # Convert all elements to string and join them with the delimiter\n return delimiter.join(str(element) for element in tup)", "matching_cluster_idx": 4}, {"solution": "def concatenate_tuple(tup, delimiter='-'):\n \"\"\"\n Concatenates each element of the tuple by the given delimiter.\n\n Parameters:\n tup (tuple): The input tuple containing elements to concatenate.\n delimiter (str): The delimiter to use for concatenation.\n\n Returns:\n str: The concatenated string.\n \"\"\"\n # Convert all elements to string and join them with the specified delimiter\n return delimiter.join(str(element) for element in tup)", "matching_cluster_idx": 4}, {"solution": "def concatenate_tuple(input_tuple, delimiter='-'):\n \"\"\"\n Concatenates each element of the tuple by the specified delimiter.\n \n Args:\n input_tuple (tuple): The tuple containing elements to be concatenated.\n delimiter (str): The delimiter to use for concatenation.\n \n Returns:\n str: A single string with the elements of the tuple concatenated by the delimiter.\n \"\"\"\n # Convert all elements to string and join them with the delimiter\n return delimiter.join(str(element) for element in input_tuple)", "matching_cluster_idx": 4}, {"solution": "def concatenate_tuple(elements, delimiter='-'):\n \"\"\"\n Concatenate each element of the tuple by the delimiter.\n\n Args:\n elements (tuple): A tuple containing elements to concatenate.\n delimiter (str): The delimiter to use for concatenation (default is '-').\n\n Returns:\n str: Concatenated string of elements.\n \"\"\"\n return delimiter.join(map(str, elements))", "matching_cluster_idx": 5}, {"solution": "def concatenate_tuple(input_tuple, delimiter='-'):\n \"\"\"\n Concatenate each element of a tuple by the specified delimiter.\n\n Args:\n input_tuple (tuple): A tuple of elements to concatenate.\n delimiter (str): The delimiter to use for concatenation.\n\n Returns:\n str: The concatenated string.\n \"\"\"\n return delimiter.join(map(str, input_tuple))", "matching_cluster_idx": 6}, {"solution": "def concatenate_tuple(elements, delimiter='-'):\n # Convert all elements to string and join them with the delimiter\n return delimiter.join(map(str, elements))", "matching_cluster_idx": 6}, {"solution": "def concatenate_tuple(input_tuple, delimiter='-'):\n \"\"\"\n Concatenates each element of the input tuple using the specified delimiter.\n\n :param input_tuple: Tuple containing the elements to concatenate\n :param delimiter: String used to separate the elements\n :return: A string that is the concatenation of the elements in the tuple\n \"\"\"\n # Convert all elements to string and join them with the delimiter\n return delimiter.join(map(str, input_tuple))", "matching_cluster_idx": 5}, {"solution": "def concatenate_tuple(elements, delimiter='-'):\n # Convert all elements to strings and join them with the delimiter\n return delimiter.join(str(element) for element in elements)", "matching_cluster_idx": 4}, {"solution": "def concatenate_tuple(tup):\n # Convert all elements to string and join them with the delimiter '-'\n return '-'.join(str(element) for element in tup)", "matching_cluster_idx": 4}]}, "Mbpp/424": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def extract_rear(strings):\n \"\"\"\n Extracts the last character of each string in the given tuple.\n \n Args:\n strings (tuple): A tuple containing strings.\n \n Returns:\n list: A list containing the last character of each string.\n \"\"\"\n return [s[-1] for s in strings]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(strings):\n \"\"\"Extract the last character of each string in the tuple.\"\"\"\n return [s[-1] for s in strings]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(strings):\n \"\"\"\n Extract the last character of each string in the given tuple.\n\n Parameters:\n strings (tuple): A tuple containing strings.\n\n Returns:\n list: A list containing the last characters of each string.\n \"\"\"\n return [s[-1] for s in strings]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(strings):\n \"\"\"\n Extract the last character of each string in the given tuple.\n\n Parameters:\n strings (tuple): A tuple containing strings.\n\n Returns:\n list: A list of last characters of each string.\n \"\"\"\n return [s[-1] for s in strings]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(strings):\n \"\"\"Extract the last character of each string in the given tuple.\"\"\"\n return [s[-1] for s in strings]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(strings):\n \"\"\"\n Extracts the last character of each string in the given tuple.\n\n Args:\n strings (tuple): A tuple of strings.\n\n Returns:\n list: A list containing the last character of each string.\n \"\"\"\n return [s[-1] for s in strings]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(strings):\n \"\"\"\n Extracts the last character of each string in the given tuple.\n\n :param strings: A tuple of strings\n :return: A list of the last characters of each string\n \"\"\"\n return [s[-1] for s in strings]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(input_tuple):\n \"\"\"\n Extracts the last character of each string in the given tuple.\n \n Args:\n input_tuple (tuple): A tuple containing strings.\n \n Returns:\n list: A list containing the last character of each string.\n \"\"\"\n return [s[-1] for s in input_tuple]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(strings):\n \"\"\"\n Extract the last character of each string in the given tuple.\n\n Args:\n strings (tuple): A tuple containing strings.\n\n Returns:\n list: A list containing the last character of each string.\n \"\"\"\n return [s[-1] for s in strings]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(strings):\n \"\"\"Extract the last character of each string in the given tuple.\"\"\"\n return [s[-1] for s in strings]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(strings):\n \"\"\"\n Extracts the last character of each string in the given tuple.\n\n Args:\n strings (tuple): A tuple of strings.\n\n Returns:\n list: A list containing the last character of each string.\n \"\"\"\n return [s[-1] for s in strings]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(strings):\n \"\"\"Extract the last character from each string in the given tuple.\"\"\"\n return [s[-1] for s in strings]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(strings):\n \"\"\"Extracts the last character of each string in the given tuple.\n\n Args:\n strings (tuple): A tuple of strings.\n\n Returns:\n list: A list containing the last character of each string.\n \"\"\"\n return [s[-1] for s in strings]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(strings):\n \"\"\"\n Extract the last character of each string in the given tuple.\n\n :param strings: A tuple of strings\n :return: A list of the last characters of each string\n \"\"\"\n return [s[-1] for s in strings]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(strings):\n \"\"\"Extract the last character of each string in the given tuple.\"\"\"\n return [s[-1] for s in strings]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(strings):\n \"\"\"\n Extracts the last character of each string in the given tuple.\n \n Args:\n strings (tuple): A tuple of strings.\n \n Returns:\n list: A list containing the last character of each string.\n \"\"\"\n return [s[-1] for s in strings]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(strings):\n \"\"\"Extract the last character from each string in the given tuple.\"\"\"\n return [s[-1] for s in strings]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(strings):\n \"\"\"\n Extracts the last character of each string in the given tuple.\n\n Args:\n strings (tuple): A tuple containing strings.\n\n Returns:\n list: A list containing the last character of each string.\n \"\"\"\n return [s[-1] for s in strings]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(strings):\n \"\"\"Extracts the last character of each string in the given tuple.\"\"\"\n return [s[-1] for s in strings]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(strings):\n \"\"\"\n Extracts the last character from each string in the given tuple.\n\n Parameters:\n strings (tuple): A tuple containing strings.\n\n Returns:\n list: A list of last characters from each string.\n \"\"\"\n return [s[-1] for s in strings]", "matching_cluster_idx": 4}]}, "Mbpp/425": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def count_element_in_list(sublists, element):\n \"\"\"\n Count the number of sublists containing a particular element.\n\n Parameters:\n sublists (list of list): A list of sublists.\n element: The element to search for in the sublists.\n\n Returns:\n int: The count of sublists containing the element.\n \"\"\"\n count = 0\n for sublist in sublists:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(nested_list, target):\n \"\"\"\n Counts the number of sublists containing a particular element.\n\n Parameters:\n nested_list (list of list): The list containing sublists.\n target: The element to count in the sublists.\n\n Returns:\n int: The count of sublists that contain the target element.\n \"\"\"\n count = 0\n for sublist in nested_list:\n if target in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(sublists, element):\n \"\"\"\n Count the number of sublists containing a particular element.\n \n :param sublists: List of lists to search through\n :param element: Element to search for in the sublists\n :return: Number of sublists containing the element\n \"\"\"\n count = 0\n for sublist in sublists:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(sublists, element):\n \"\"\"\n Count the number of sublists containing a particular element.\n\n Parameters:\n sublists (list of list): A list containing sublists.\n element (any): The element to search for in the sublists.\n\n Returns:\n int: The count of sublists containing the element.\n \"\"\"\n count = 0\n for sublist in sublists:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(sublists, element):\n \"\"\"\n Counts the number of sublists containing a particular element.\n\n Parameters:\n sublists (list of list): The list of sublists to search through.\n element: The element to count in the sublists.\n\n Returns:\n int: The count of sublists containing the element.\n \"\"\"\n count = 0\n for sublist in sublists:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(nested_list, element):\n \"\"\"\n Count the number of sublists containing a particular element.\n \n Parameters:\n nested_list (list of list): A list containing sublists.\n element: The element to count in the sublists.\n \n Returns:\n int: The count of sublists containing the element.\n \"\"\"\n count = 0\n for sublist in nested_list:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(sublists, element):\n \"\"\"\n Counts the number of sublists that contain the specified element.\n\n Parameters:\n sublists (list of lists): The list containing sublists to be checked.\n element: The element to count within the sublists.\n\n Returns:\n int: The number of sublists that contain the specified element.\n \"\"\"\n count = 0\n for sublist in sublists:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst_of_lists, element):\n \"\"\"\n Count the number of sublists containing a particular element.\n\n :param lst_of_lists: List of lists to search through\n :param element: Element to count in sublists\n :return: Count of sublists containing the element\n \"\"\"\n count = 0\n for sublist in lst_of_lists:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(nested_list, element):\n \"\"\"\n Count the number of sublists containing a particular element.\n\n Parameters:\n nested_list (list of list): A list of sublists to check.\n element: The element to count occurrences of in the sublists.\n\n Returns:\n int: The count of sublists containing the element.\n \"\"\"\n count = 0\n for sublist in nested_list:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(nested_list, element):\n \"\"\"\n Counts the number of sublists that contain the specified element.\n \n Parameters:\n nested_list (list of lists): The list of sublists to search.\n element: The element to count in the sublists.\n \n Returns:\n int: The count of sublists containing the element.\n \"\"\"\n count = 0\n for sublist in nested_list:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(nested_list, element):\n \"\"\"\n Counts the number of sublists containing a particular element.\n\n Parameters:\n nested_list (list of list): A list containing sublists.\n element: The element to search for in the sublists.\n\n Returns:\n int: The count of sublists containing the element.\n \"\"\"\n count = 0\n for sublist in nested_list:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(sublists, element):\n \"\"\"\n Counts the number of sublists that contain a specified element.\n\n Parameters:\n sublists (list of lists): The list of sublists to be checked.\n element: The element to count in the sublists.\n\n Returns:\n int: The number of sublists containing the specified element.\n \"\"\"\n count = 0\n for sublist in sublists:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(nested_list, element):\n \"\"\"\n Count the number of sublists containing a particular element.\n\n Args:\n nested_list (list of list): A list of sublists.\n element: The element to search for in the sublists.\n\n Returns:\n int: The count of sublists containing the element.\n \"\"\"\n count = 0\n for sublist in nested_list:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(nested_list, element):\n \"\"\"\n Count the number of sublists containing a particular element.\n\n Parameters:\n nested_list (list of list): The list of sublists to search through.\n element (any): The element to count in the sublists.\n\n Returns:\n int: The count of sublists containing the element.\n \"\"\"\n count = 0\n for sublist in nested_list:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(sublists, element):\n \"\"\"\n Count the number of sublists that contain a particular element.\n\n Parameters:\n sublists (list of list): A list containing sublists to be searched.\n element: The element to search for within the sublists.\n\n Returns:\n int: The count of sublists that contain the specified element.\n \"\"\"\n count = 0\n for sublist in sublists:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, element):\n \"\"\"\n Count the number of sublists that contain the specified element.\n\n Parameters:\n lst (list of list): The list of sublists to check.\n element (any): The element to look for in the sublists.\n\n Returns:\n int: The count of sublists containing the specified element.\n \"\"\"\n count = 0\n for sublist in lst:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(nested_list, element):\n \"\"\"\n Count the number of sublists containing a particular element.\n \n Parameters:\n nested_list (list of list): The list containing sublists to be searched.\n element (any): The element to be counted in the sublists.\n \n Returns:\n int: The count of sublists containing the element.\n \"\"\"\n count = 0\n for sublist in nested_list:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(sublists, element):\n \"\"\"\n Count the number of sublists containing a particular element.\n \n Parameters:\n sublists (list of list): The list of sublists to search.\n element (any): The element to count in the sublists.\n \n Returns:\n int: The count of sublists containing the element.\n \"\"\"\n count = 0\n for sublist in sublists:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(sublists, element):\n \"\"\"\n Count the number of sublists containing a particular element.\n\n Args:\n sublists (list of list): A list of sublists to search.\n element (any): The element to search for in the sublists.\n\n Returns:\n int: The count of sublists containing the specified element.\n \"\"\"\n count = 0\n for sublist in sublists:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(sublists, element):\n \"\"\"\n Count the number of sublists containing a particular element.\n\n Parameters:\n sublists (list of lists): The list containing sublists.\n element: The element to search for in the sublists.\n\n Returns:\n int: The count of sublists that contain the element.\n \"\"\"\n count = 0\n for sublist in sublists:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}]}, "Mbpp/428": {"dps": 75.49586776859503, "dps_norm": 53.88888888888889, "pass@1": 100.0, "profiled": [{"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2 # Start with a big gap, then reduce the gap\n\n # Do a gapped insertion sort for this gap size.\n # The first gap elements arr[0..gap-1] are already in gapped order\n # keep adding one more element until the entire array is gap sorted\n while gap > 0:\n for i in range(gap, n):\n # save arr[i] in temp and make a hole at position i\n temp = arr[i]\n\n # shift earlier gap-sorted elements up until the correct location for arr[i] is found\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n\n # put temp (the original arr[i]) in its correct location\n arr[j] = temp\n \n gap //= 2 # Reduce the gap for the next element\n\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2 # Initialize gap size\n\n # Start with a big gap, then reduce the gap\n while gap > 0:\n # Do a gapped insertion sort for this gap size.\n for i in range(gap, n):\n # Add arr[i] to the elements that have been gap sorted\n # Save arr[i] in temp and make a hole at position i\n temp = arr[i]\n j = i\n # Shift earlier gap-sorted elements up until the correct location for arr[i] is found\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n # Put temp (the original arr[i]) in its correct location\n arr[j] = temp\n gap //= 2 # Reduce the gap for the next element\n\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(array):\n \"\"\"Sorts an array using the shell sort algorithm.\"\"\"\n n = len(array)\n gap = n // 2 # Initialize the gap size\n\n # Start with a big gap, then reduce the gap\n while gap > 0:\n # Do a gapped insertion sort for this gap size.\n for i in range(gap, n):\n # Save array[i] in temp and make a hole at position i\n temp = array[i]\n j = i\n \n # Shift earlier gap-sorted elements up until the correct location for array[i] is found\n while j >= gap and array[j - gap] > temp:\n array[j] = array[j - gap]\n j -= gap\n \n # Put temp (the original array[i]) in its correct location\n array[j] = temp\n \n gap //= 2 # Reduce the gap size\n\n return array", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2 # Start with a gap equal to half of the array length\n\n # Do a gapped insertion sort for this gap size.\n while gap > 0:\n for i in range(gap, n):\n # save the current element to insert it in the correct position\n temp = arr[i]\n j = i\n \n # Shift elements of arr[0..i-gap] that are greater than temp\n # to their new position\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n\n # Put temp in its correct location\n arr[j] = temp\n \n gap //= 2 # Reduce the gap for the next element\n\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n \"\"\"Sorts an array using the shell sort algorithm.\"\"\"\n n = len(arr)\n gap = n // 2 # Start with a big gap, then reduce the gap\n\n # Do a gapped insertion sort for this gap size\n while gap > 0:\n for i in range(gap, n):\n # save arr[i] in temp and make a hole at position i\n temp = arr[i]\n j = i\n\n # shift earlier gap-sorted elements up until the correct location for arr[i] is found\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n\n # put temp (the original arr[i]) in its correct location\n arr[j] = temp\n \n gap //= 2 # Reduce the gap for the next element\n \n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2 # Initialize the gap size\n\n # Start with a big gap, then reduce the gap\n while gap > 0:\n # Do a gapped insertion sort for this gap size\n for i in range(gap, n):\n temp = arr[i]\n j = i\n \n # Shift earlier gap-sorted elements up until the correct location for arr[i] is found\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n \n # Put temp (the original arr[i]) in its correct location\n arr[j] = temp\n \n gap //= 2 # Reduce the gap for the next stage\n\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2 # Start with a big gap, then reduce the gap\n\n # Do a gapped insertion sort for this gap size\n while gap > 0:\n for i in range(gap, n):\n # Save the current element and find its correct position\n temp = arr[i]\n j = i\n \n # Shift earlier gap-sorted elements up until the correct location for temp is found\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n \n # Put temp (the original arr[i]) in its correct location\n arr[j] = temp\n \n gap //= 2 # Reduce the gap for the next element\n\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(array):\n n = len(array)\n gap = n // 2 # Start with a big gap\n\n # Do a gapped insertion sort for this gap size.\n while gap > 0:\n for i in range(gap, n):\n temp = array[i]\n j = i\n # Shift earlier gap-sorted elements up until the correct location for array[i] is found\n while j >= gap and array[j - gap] > temp:\n array[j] = array[j - gap]\n j -= gap\n array[j] = temp\n gap //= 2 # Reduce the gap for the next element\n\n return array", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2 # Start with a large gap\n\n # Do a gapped insertion sort for this gap size\n while gap > 0:\n for i in range(gap, n):\n # add arr[i] to the elements that have been gap sorted\n # save arr[i] in temp and make a hole at position i\n temp = arr[i]\n j = i\n # shift earlier gap-sorted elements up until the correct location for arr[i] is found\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n # put temp (the original arr[i]) in its correct location\n arr[j] = temp\n gap //= 2 # Reduce the gap for the next stage\n\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2 # Start with a big gap, then reduce the gap\n\n # Do a gapped insertion sort for this gap size.\n while gap > 0:\n for i in range(gap, n):\n # save arr[i] in temp and make a hole at position i\n temp = arr[i]\n\n # Shift earlier gap-sorted elements up until the correct location for arr[i] is found\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n\n # Put temp (the original arr[i]) in its correct location\n arr[j] = temp\n \n gap //= 2 # Reduce the gap for the next element\n\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2 # Start with a big gap, then reduce the gap\n\n # Do a gapped insertion sort for this gap size.\n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n # shift earlier gap-sorted elements up until the correct location for arr[i] is found\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n # put temp (the original arr[i]) in its correct location\n arr[j] = temp\n gap //= 2 # Reduce the gap for the next element\n\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2 # Start with a big gap, then reduce the gap\n \n # Start with the largest gap and work down to a gap of 1\n while gap > 0:\n # Perform a gapped insertion sort for this gap size\n for i in range(gap, n):\n # Save the element at the current position\n temp = arr[i]\n j = i\n \n # Shift earlier gap-sorted elements up until the correct location for temp is found\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n \n # Put temp (the original arr[i]) in its correct location\n arr[j] = temp\n \n gap //= 2 # Reduce the gap for the next element\n \n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n \"\"\"\n Sorts an array using the Shell Sort algorithm.\n\n :param arr: List of elements to be sorted\n :return: Sorted list of elements\n \"\"\"\n n = len(arr)\n gap = n // 2 # Start with a big gap, then reduce the gap\n\n # Perform a gapped insertion sort for this gap size\n while gap > 0:\n for i in range(gap, n):\n # Save the current element to be compared\n temp = arr[i]\n j = i\n\n # Shift earlier gap-sorted elements up until the correct location for arr[i] is found\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n\n # Place temp (the original arr[i]) in its correct location\n arr[j] = temp\n \n gap //= 2 # Reduce the gap\n\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n \"\"\"\n Sorts an array using the shell sort algorithm.\n \n Parameters:\n arr (list): The list of elements to be sorted.\n \n Returns:\n list: The sorted list.\n \"\"\"\n n = len(arr)\n gap = n // 2 # Start with a big gap, then reduce the gap\n\n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n # Shift elements until the correct location for temp is found\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2 # Reduce the gap\n\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2 # Start with a big gap, then reduce the gap\n\n # Perform a shell sort\n while gap > 0:\n for i in range(gap, n):\n # Save the current element to be inserted\n temp = arr[i]\n j = i\n\n # Shift earlier gap-sorted elements up until the correct location for arr[i] is found\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n \n # Put temp (the original arr[i]) in its correct location\n arr[j] = temp\n \n gap //= 2 # Reduce the gap size\n\n return arr", "matching_cluster_idx": 3}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2 # Start with a big gap, then reduce the gap\n\n # Do a gapped insertion sort for this gap size.\n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n \n # Shift earlier gap-sorted elements up until the correct location for arr[i] is found\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n \n # Put temp (the original arr[i]) in its correct location\n arr[j] = temp\n gap //= 2 # Reduce the gap for the next element\n\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2 # Start with a big gap, then reduce the gap\n\n # Do a gapped insertion sort for this gap size\n while gap > 0:\n for i in range(gap, n):\n # Add arr[i] to the elements that have been gap sorted\n # Save arr[i] in temp and make a hole at position i\n temp = arr[i]\n j = i\n\n # Shift earlier gap-sorted elements up until the correct location for arr[i] is found\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n\n # Put temp (the original arr[i]) in its correct location\n arr[j] = temp\n gap //= 2 # Reduce the gap for the next element\n\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2 # Start with a big gap, then reduce the gap\n\n # Start with the largest gap and reduce it\n while gap > 0:\n # Do a gapped insertion sort for this gap size\n for i in range(gap, n):\n # save the current value and its index\n temp = arr[i]\n j = i\n \n # shift earlier gap-sorted elements up until the correct location for arr[i] is found\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n \n # put temp (the original arr[i]) in its correct location\n arr[j] = temp\n \n gap //= 2 # Reduce the gap\n\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n \"\"\"Sorts an array using the Shell sort algorithm.\"\"\"\n n = len(arr)\n gap = n // 2 # Start with a big gap, then reduce the gap\n \n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n # Shift earlier gap-sorted elements up until the correct location for arr[i] is found\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2 # Reduce the gap for the next iteration\n\n return arr", "matching_cluster_idx": 3}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2 # Start with a big gap, then reduce the gap\n \n # Start with the largest gap and reduce the gap until it becomes 0\n while gap > 0:\n # Do a gapped insertion sort for this gap size\n for i in range(gap, n):\n temp = arr[i]\n j = i\n \n # Shift earlier gap-sorted elements up until the correct location for arr[i] is found\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n \n # Put temp (the original arr[i]) in its correct location\n arr[j] = temp\n \n gap //= 2 # Reduce the gap\n\n return arr", "matching_cluster_idx": 3}]}, "Mbpp/433": {"dps": 81.96808510638297, "dps_norm": 81.0, "pass@1": 100.0, "profiled": [{"solution": "def check_greater(arr, num):\n \"\"\"\n Check whether the entered number is greater than all the elements of the given array.\n\n Parameters:\n arr (list of int): The array of integers.\n num (int): The number to compare against the elements of the array.\n\n Returns:\n bool: True if num is greater than all elements in arr, False otherwise.\n \"\"\"\n return all(num > element for element in arr)", "matching_cluster_idx": 2}, {"solution": "def check_greater(arr, num):\n \"\"\"\n Check whether the entered number is greater than all elements of the given array.\n\n Parameters:\n arr (list): A list of integers.\n num (int): The integer to compare against the elements of the array.\n\n Returns:\n bool: True if num is greater than all elements in arr, False otherwise.\n \"\"\"\n return all(num > x for x in arr)", "matching_cluster_idx": 2}, {"solution": "def check_greater(arr, num):\n \"\"\"\n Check whether the entered number is greater than all elements of the given array.\n\n Parameters:\n arr (list): A list of integers.\n num (int): The number to compare against the elements of the array.\n\n Returns:\n bool: True if num is greater than all elements in arr, False otherwise.\n \"\"\"\n for element in arr:\n if num <= element:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def check_greater(array, number):\n \"\"\"\n Check whether the entered number is greater than all elements of the given array.\n\n Args:\n array (list): A list of numerical elements.\n number (int or float): The number to be checked against the array elements.\n\n Returns:\n bool: True if number is greater than all elements in the array, False otherwise.\n \"\"\"\n for element in array:\n if number <= element:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def check_greater(arr, num):\n \"\"\"\n Check whether the entered number is greater than all elements in the given array.\n\n Parameters:\n arr (list of int): The array of integers to compare against.\n num (int): The number to check.\n\n Returns:\n bool: True if num is greater than all elements in arr, otherwise False.\n \"\"\"\n for element in arr:\n if num <= element:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def check_greater(arr, num):\n \"\"\"Check if the given number is greater than all elements in the array.\"\"\"\n for element in arr:\n if num <= element:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def check_greater(arr, num):\n \"\"\"\n Checks whether the entered number is greater than all the elements of the given array.\n\n Parameters:\n arr (list): A list of numbers.\n num (int or float): The number to compare against the elements of the array.\n\n Returns:\n bool: True if num is greater than all elements in arr, False otherwise.\n \"\"\"\n for element in arr:\n if num <= element:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def check_greater(arr, num):\n \"\"\"\n Check whether the entered number is greater than all the elements of the given array.\n\n Parameters:\n arr (list of int): The list of integers to compare against.\n num (int): The number to compare.\n\n Returns:\n bool: True if num is greater than all elements in arr, False otherwise.\n \"\"\"\n return all(num > element for element in arr)", "matching_cluster_idx": 2}, {"solution": "def check_greater(arr, num):\n \"\"\"\n Check whether the entered number is greater than all elements of the given array.\n \n Parameters:\n arr (list): A list of numbers.\n num (int or float): The number to check against the array elements.\n \n Returns:\n bool: True if num is greater than all elements in arr, False otherwise.\n \"\"\"\n for element in arr:\n if num <= element:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def check_greater(arr, num):\n \"\"\"\n Check whether the entered number is greater than all elements of the given array.\n \n Parameters:\n arr (list): A list of integers.\n num (int): The number to check.\n \n Returns:\n bool: True if num is greater than all elements in arr, False otherwise.\n \"\"\"\n for element in arr:\n if num <= element:\n return False\n return True", "matching_cluster_idx": 3}, {"solution": "def check_greater(arr, num):\n \"\"\"\n Check if the entered number is greater than all elements of the given array.\n\n Parameters:\n arr (list of int): List of integers.\n num (int): The number to compare against the array elements.\n\n Returns:\n bool: True if num is greater than all elements in arr, False otherwise.\n \"\"\"\n return all(num > element for element in arr)", "matching_cluster_idx": 2}, {"solution": "def check_greater(array, number):\n \"\"\"\n Check whether the entered number is greater than all elements of the given array.\n \n Parameters:\n array (list): A list of numbers.\n number (int or float): The number to compare against the elements of the array.\n \n Returns:\n bool: True if the number is greater than all elements in the array, False otherwise.\n \"\"\"\n for element in array:\n if number <= element:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def check_greater(arr, num):\n \"\"\"\n Check whether the entered number is greater than all elements of the given array.\n\n Parameters:\n arr (list): A list of numbers.\n num (int or float): The number to check.\n\n Returns:\n bool: True if num is greater than all elements in arr, False otherwise.\n \"\"\"\n return all(num > element for element in arr)", "matching_cluster_idx": 2}, {"solution": "def check_greater(array, number):\n \"\"\"\n Check whether the given number is greater than all elements in the array.\n \n Parameters:\n array (list): A list of numerical elements.\n number (int or float): The number to compare against the array elements.\n \n Returns:\n bool: True if number is greater than all elements in the array, False otherwise.\n \"\"\"\n for element in array:\n if number <= element:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def check_greater(arr, num):\n \"\"\"\n Check if the entered number is greater than all elements in the given array.\n\n Parameters:\n arr (list): A list of numbers.\n num (int or float): The number to compare against the elements of the array.\n\n Returns:\n bool: True if num is greater than all elements in arr, False otherwise.\n \"\"\"\n for element in arr:\n if num <= element:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def check_greater(arr, num):\n \"\"\"\n Check if the entered number is greater than all elements in the given array.\n\n Args:\n arr (list of int): The array of integers to compare against.\n num (int): The number to check.\n\n Returns:\n bool: True if num is greater than all elements in arr, otherwise False.\n \"\"\"\n return all(num > element for element in arr)", "matching_cluster_idx": 2}, {"solution": "def check_greater(arr, num):\n \"\"\"\n Check if the entered number is greater than all elements of the given array.\n\n Parameters:\n arr (list of int): The array of integers to compare against.\n num (int): The number to check.\n\n Returns:\n bool: True if num is greater than all elements in arr, False otherwise.\n \"\"\"\n return all(num > x for x in arr)", "matching_cluster_idx": 2}, {"solution": "def check_greater(arr, number):\n \"\"\"\n Check whether the entered number is greater than all the elements of the given array.\n\n Parameters:\n arr (list): A list of numbers.\n number (int or float): The number to compare against the elements of the array.\n\n Returns:\n bool: True if the number is greater than all elements, False otherwise.\n \"\"\"\n return all(number > element for element in arr)", "matching_cluster_idx": 2}, {"solution": "def check_greater(array, number):\n \"\"\"\n Check if the entered number is greater than all elements of the given array.\n\n Parameters:\n array (list of int): The array of integers to compare against.\n number (int): The number to check.\n\n Returns:\n bool: True if the number is greater than all elements in the array, False otherwise.\n \"\"\"\n return all(number > element for element in array)", "matching_cluster_idx": 2}, {"solution": "def check_greater(arr, num):\n \"\"\"\n Checks whether the entered number is greater than all elements of the given array.\n \n Parameters:\n arr (list): A list of numbers.\n num (int or float): A number to compare against the elements of the array.\n \n Returns:\n bool: True if num is greater than all elements in arr, False otherwise.\n \"\"\"\n for element in arr:\n if num <= element:\n return False\n return True", "matching_cluster_idx": 4}]}, "Mbpp/437": {"dps": 76.98529411764706, "dps_norm": 37.0, "pass@1": 97.0, "profiled": [{"solution": "def remove_odd(s):\n \"\"\"\n Remove characters at odd indices from the input string.\n\n Args:\n s (str): The input string.\n\n Returns:\n str: A new string with characters at odd indices removed.\n \"\"\"\n return ''.join(s[i] for i in range(len(s)) if i % 2 == 1)", "matching_cluster_idx": 0}, {"solution": "def remove_odd(s: str) -> str:\n \"\"\"Remove characters at odd indices from the input string.\"\"\"\n return s[1::2]", "matching_cluster_idx": 4}, {"solution": "def remove_odd(s):\n \"\"\"\n Remove characters from odd indices in a string.\n \n Parameters:\n s (str): The input string.\n \n Returns:\n str: A string with characters from odd indices removed.\n \"\"\"\n return s[1::2]", "matching_cluster_idx": 4}, {"solution": "def remove_odd(s: str) -> str:\n \"\"\"Removes characters at odd indices from the given string.\"\"\"\n return ''.join(s[i] for i in range(len(s)) if i % 2 != 0)", "matching_cluster_idx": 0}, {"solution": "def remove_odd(s: str) -> str:\n \"\"\"Remove characters from odd indices in the given string.\"\"\"\n return ''.join(s[i] for i in range(len(s)) if i % 2 != 0)", "matching_cluster_idx": 0}, {"solution": "def remove_odd(s: str) -> str:\n \"\"\"Remove characters at odd indices from the given string.\"\"\"\n return ''.join([s[i] for i in range(len(s)) if i % 2 != 0])", "matching_cluster_idx": 1}, {"solution": "def remove_odd(s):\n \"\"\"\n Removes characters from odd indices in a string.\n\n Parameters:\n s (str): The input string.\n\n Returns:\n str: A new string with characters from odd indices removed.\n \"\"\"\n return ''.join(s[i] for i in range(len(s)) if i % 2 != 0)", "matching_cluster_idx": 0}, {"solution": "def remove_odd(s):\n \"\"\"Remove characters at odd indices from the string.\"\"\"\n return ''.join(s[i] for i in range(len(s)) if i % 2 != 0)", "matching_cluster_idx": 0}, {"solution": "def remove_odd(s: str) -> str:\n \"\"\"\n Remove characters from the string at odd indices.\n \n :param s: Input string\n :return: A new string with characters at odd indices removed\n \"\"\"\n return ''.join(s[i] for i in range(len(s)) if i % 2 != 0)", "matching_cluster_idx": 0}, {"solution": "def remove_odd(s):\n \"\"\"Remove characters at odd indices from the string.\"\"\"\n return ''.join(s[i] for i in range(len(s)) if i % 2 != 0)", "matching_cluster_idx": 0}, {"solution": "def remove_odd(s: str) -> str:\n \"\"\"\n Removes characters from the string at odd indices.\n\n Args:\n s (str): The input string from which odd indexed characters will be removed.\n\n Returns:\n str: A new string with characters from odd indices removed.\n \"\"\"\n return ''.join(s[i] for i in range(len(s)) if i % 2 != 0)", "matching_cluster_idx": 0}, {"solution": "def remove_odd(s):\n \"\"\"\n Remove characters from the string at odd indices.\n\n Args:\n s (str): The input string.\n\n Returns:\n str: A new string with characters from odd indices removed.\n \"\"\"\n return ''.join(s[i] for i in range(len(s)) if i % 2 != 0)", "matching_cluster_idx": 0}, {"solution": "def remove_odd(s: str) -> str:\n \"\"\"Remove characters at odd indices from the given string.\"\"\"\n return ''.join(s[i] for i in range(len(s)) if i % 2 != 0)", "matching_cluster_idx": 0}, {"solution": "def remove_odd(s):\n \"\"\"\n Remove characters at odd indices from the string.\n \n Args:\n s (str): The input string from which to remove odd indexed characters.\n \n Returns:\n str: A new string with characters from even indices.\n \"\"\"\n return ''.join(s[i] for i in range(len(s)) if i % 2 != 0)", "matching_cluster_idx": 0}, {"solution": "def remove_odd(s):\n \"\"\"\n Remove characters at odd indices from the string s.\n \n Args:\n s (str): The input string.\n\n Returns:\n str: A new string with characters at odd indices removed.\n \"\"\"\n # Using list comprehension to filter out odd indexed characters\n return ''.join([s[i] for i in range(len(s)) if i % 2 != 0])", "matching_cluster_idx": 0}, {"solution": "def remove_odd(s):\n \"\"\"Remove characters at odd indices from the string s.\"\"\"\n return ''.join(s[i] for i in range(len(s)) if i % 2 != 0)", "matching_cluster_idx": 0}, {"solution": "def remove_odd(s):\n \"\"\"Remove characters at odd indices from the input string.\"\"\"\n return ''.join(s[i] for i in range(len(s)) if i % 2 != 0)", "matching_cluster_idx": 0}, {"solution": "def remove_odd(s: str) -> str:\n \"\"\"Remove characters at odd indices from the input string.\"\"\"\n return s[1::2]", "matching_cluster_idx": 4}, {"solution": "def remove_odd(s: str) -> str:\n \"\"\"\n Removes odd indexed characters from the given string.\n \n :param s: The input string from which to remove odd indexed characters.\n :return: A string containing only the characters at even indices.\n \"\"\"\n return ''.join(s[i] for i in range(len(s)) if i % 2 != 0)", "matching_cluster_idx": 0}, {"solution": "def remove_odd(s):\n \"\"\"\n Remove characters at odd indices from the input string.\n\n Args:\n s (str): The input string.\n\n Returns:\n str: A new string with characters at odd indices removed.\n \"\"\"\n return s[1::2]", "matching_cluster_idx": 4}]}, "Mbpp/440": {"dps": null, "dps_norm": null, "pass@1": 0.0, "profiled": []}, "Mbpp/446": {"dps": 96.05911330049261, "dps_norm": 60.0, "pass@1": 100.0, "profiled": [{"solution": "def count_Occurrence(tup, lst):\n \"\"\"\n Count the occurrence of all elements of list in a tuple.\n\n Parameters:\n tup (tuple): The tuple in which to count occurrences.\n lst (list): The list containing elements to count in the tuple.\n\n Returns:\n int: The total count of occurrences of the list elements in the tuple.\n \"\"\"\n count = 0\n for element in lst:\n count += tup.count(element)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tup, lst):\n \"\"\"\n Count the occurrences of all elements of list in a tuple.\n\n Parameters:\n tup (tuple): The tuple containing elements to be counted.\n lst (list): The list containing the elements to look for in the tuple.\n\n Returns:\n int: The total count of occurrences of elements from the list in the tuple.\n \"\"\"\n count = 0\n for element in lst:\n count += tup.count(element)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tup, lst):\n \"\"\"\n Count the occurrence of all elements of list in a tuple.\n\n Parameters:\n tup (tuple): The tuple in which to count occurrences.\n lst (list): The list of elements to count.\n\n Returns:\n int: The total count of occurrences of elements in lst found in tup.\n \"\"\"\n count = 0\n for element in lst:\n count += tup.count(element)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tup, lst):\n \"\"\"\n Count the occurrence of all elements of the list in the tuple.\n \n Parameters:\n tup (tuple): A tuple containing elements to be counted.\n lst (list): A list of elements to count in the tuple.\n \n Returns:\n int: The total count of occurrences of list elements in the tuple.\n \"\"\"\n return sum(tup.count(item) for item in lst)", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tup, lst):\n \"\"\"\n Count the occurrence of all elements of the list in the tuple.\n\n Parameters:\n tup (tuple): The tuple containing elements to count.\n lst (list): The list containing elements to check for in the tuple.\n\n Returns:\n int: The total count of occurrences of the elements in the list within the tuple.\n \"\"\"\n count = 0\n for element in lst:\n count += tup.count(element)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tup, lst):\n \"\"\"\n Count the occurrence of all elements of list in a tuple.\n\n Parameters:\n tup (tuple): A tuple containing elements to count occurrences from.\n lst (list): A list of elements to count in the tuple.\n\n Returns:\n int: The total count of occurrences of list elements in the tuple.\n \"\"\"\n count = 0\n for element in lst:\n count += tup.count(element)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tup, lst):\n \"\"\"\n Count the occurrence of all elements of list in a tuple.\n\n Args:\n tup (tuple): The tuple in which to count occurrences.\n lst (list): The list of elements to count in the tuple.\n\n Returns:\n int: The total count of occurrences of all elements in lst found in tup.\n \"\"\"\n count = 0\n for element in lst:\n count += tup.count(element)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tup, lst):\n \"\"\"\n Count the occurrence of all elements in lst within the tuple tup.\n\n Parameters:\n tup (tuple): The tuple containing elements to check.\n lst (list): The list of elements to count in the tuple.\n\n Returns:\n int: The total count of occurrences of list elements in the tuple.\n \"\"\"\n count = 0\n for item in lst:\n count += tup.count(item)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tup, lst):\n \"\"\"Count the occurrence of all elements of list in a tuple.\n\n Args:\n tup (tuple): A tuple of elements.\n lst (list): A list of elements to count in the tuple.\n\n Returns:\n int: The total count of occurrences of the list elements in the tuple.\n \"\"\"\n count = 0\n for item in lst:\n count += tup.count(item)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tup, lst):\n \"\"\"\n Count the occurrence of all elements of the list in the tuple.\n\n Parameters:\n tup (tuple): The tuple in which to count occurrences.\n lst (list): The list of elements to count in the tuple.\n\n Returns:\n int: Total occurrences of all elements in the list found in the tuple.\n \"\"\"\n return sum(tup.count(item) for item in lst)", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tup, lst):\n \"\"\"\n Count the occurrence of all elements of the list in the tuple.\n\n Args:\n tup (tuple): A tuple containing elements to be counted.\n lst (list): A list of elements whose occurrences in the tuple are to be counted.\n\n Returns:\n int: The total count of occurrences of elements in the list found in the tuple.\n \"\"\"\n count = 0\n for element in lst:\n count += tup.count(element)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tup, lst):\n \"\"\"\n Count the occurrences of all elements from the list in the tuple.\n \n Parameters:\n tup (tuple): The tuple in which to count occurrences.\n lst (list): The list of elements to count in the tuple.\n \n Returns:\n int: The total count of occurrences of the elements in the list found in the tuple.\n \"\"\"\n count = 0\n for element in lst:\n count += tup.count(element)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tup, lst):\n \"\"\"\n Count the occurrence of all elements of list in a tuple.\n\n Parameters:\n tup (tuple): A tuple of elements.\n lst (list): A list of elements to count in the tuple.\n\n Returns:\n int: The total count of occurrences of list elements in the tuple.\n \"\"\"\n count = 0\n for element in lst:\n count += tup.count(element)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tup, lst):\n \"\"\"\n Count the occurrence of all elements of a list in a tuple.\n\n :param tup: Tuple containing elements to count occurrences from.\n :param lst: List containing elements to count.\n :return: Total count of occurrences of list elements in the tuple.\n \"\"\"\n count = 0\n for element in lst:\n count += tup.count(element)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tup, lst):\n \"\"\"\n Count the occurrence of all elements of a list in a tuple.\n \n Parameters:\n tup (tuple): A tuple containing elements.\n lst (list): A list containing elements to count in the tuple.\n \n Returns:\n int: The total count of occurrences of elements in the list found in the tuple.\n \"\"\"\n count = 0\n for item in lst:\n count += tup.count(item)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tup, lst):\n \"\"\"\n Count the occurrence of all elements of the list in a tuple.\n\n Parameters:\n tup (tuple): The tuple containing elements.\n lst (list): The list of elements to count.\n\n Returns:\n int: The total count of occurrences of list elements in the tuple.\n \"\"\"\n count = 0\n for element in lst:\n count += tup.count(element)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tup, lst):\n \"\"\"\n Count the occurrence of all elements of list in a tuple.\n\n Parameters:\n tup (tuple): The tuple in which to count occurrences.\n lst (list): The list of elements to count in the tuple.\n\n Returns:\n int: The total count of occurrences of the list elements in the tuple.\n \"\"\"\n count = 0\n for item in lst:\n count += tup.count(item)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tup, lst):\n \"\"\"\n Counts the occurrence of all elements of a list in a tuple.\n\n :param tup: Tuple containing elements to count.\n :param lst: List containing elements to check for occurrences.\n :return: The count of occurrences of elements from the list in the tuple.\n \"\"\"\n count = 0\n for item in lst:\n count += tup.count(item)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tup, lst):\n \"\"\"\n Count the occurrences of all elements of lst in the tuple tup.\n \n :param tup: Tuple containing elements to count from\n :param lst: List of elements to count\n :return: Total count of occurrences of elements in lst found in tup\n \"\"\"\n count = 0\n for element in lst:\n count += tup.count(element)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tup, lst):\n \"\"\"\n Count the occurrence of all elements in the list within the tuple.\n \n Args:\n tup (tuple): The tuple in which to count occurrences.\n lst (list): The list of elements to count in the tuple.\n \n Returns:\n int: The total count of occurrences of the list elements in the tuple.\n \"\"\"\n count = 0\n for item in lst:\n count += tup.count(item)\n return count", "matching_cluster_idx": 2}]}, "Mbpp/451": {"dps": null, "dps_norm": null, "pass@1": 0.0, "profiled": []}, "Mbpp/456": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def reverse_string_list(strings):\n \"\"\"\n Reverses each string in the given list of string values.\n\n Args:\n strings (list): A list of strings.\n\n Returns:\n list: A list of strings where each string is reversed.\n \"\"\"\n return [s[::-1] for s in strings]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(strings):\n \"\"\"\n This function takes a list of strings and returns a new list\n with each string reversed.\n \n :param strings: List of strings to be reversed\n :return: List of reversed strings\n \"\"\"\n return [s[::-1] for s in strings]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n \"\"\"\n Reverses each string in the given list of string values.\n\n Args:\n string_list (list): A list of strings.\n\n Returns:\n list: A list of strings with each string reversed.\n \"\"\"\n return [s[::-1] for s in string_list]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n \"\"\"Reverses each string in the given list of strings.\"\"\"\n return [s[::-1] for s in string_list]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(strings):\n \"\"\"\n Reverses each string in a given list of string values.\n\n Parameters:\n strings (list): A list of strings to be reversed.\n\n Returns:\n list: A list containing the reversed strings.\n \"\"\"\n return [s[::-1] for s in strings]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(strings):\n \"\"\"Reverse each string in a given list of string values.\"\"\"\n return [s[::-1] for s in strings]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(strings):\n \"\"\"Reverse each string in the given list of strings.\"\"\"\n return [s[::-1] for s in strings]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n \"\"\"\n Reverses each string in the given list of string values.\n\n Parameters:\n string_list (list): A list of strings to reverse.\n\n Returns:\n list: A list of reversed strings.\n \"\"\"\n return [s[::-1] for s in string_list]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(strings):\n \"\"\"Reverses each string in the provided list of strings.\"\"\"\n return [s[::-1] for s in strings]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n \"\"\"\n This function takes a list of strings and returns a new list\n containing each string reversed.\n \n :param string_list: List of strings to reverse\n :return: List of reversed strings\n \"\"\"\n return [s[::-1] for s in string_list]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(strings):\n \"\"\"\n Reverses each string in the given list of strings.\n\n :param strings: List of strings to be reversed\n :return: List of reversed strings\n \"\"\"\n return [s[::-1] for s in strings]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(strings):\n \"\"\"Reverses each string in the given list of strings.\"\"\"\n return [s[::-1] for s in strings]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n \"\"\"\n Reverses each string in the provided list of strings.\n\n Parameters:\n string_list (list of str): A list containing strings to be reversed.\n\n Returns:\n list of str: A new list containing the reversed strings.\n \"\"\"\n return [s[::-1] for s in string_list]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n \"\"\"\n Reverse each string in the given list of string values.\n\n Args:\n string_list (list): A list of strings to be reversed.\n\n Returns:\n list: A list of reversed strings.\n \"\"\"\n return [s[::-1] for s in string_list]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n \"\"\"\n Reverses each string in the given list of string values.\n\n Parameters:\n string_list (list): A list of strings to reverse.\n\n Returns:\n list: A new list containing the reversed strings.\n \"\"\"\n return [s[::-1] for s in string_list]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n \"\"\"\n This function takes a list of strings and returns a new list\n with each string reversed.\n \n :param string_list: List of strings to be reversed\n :return: List of reversed strings\n \"\"\"\n return [s[::-1] for s in string_list]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n \"\"\"\n Reverses each string in the given list of strings.\n\n Args:\n string_list (list): A list of strings to be reversed.\n\n Returns:\n list: A list containing the reversed strings.\n \"\"\"\n return [s[::-1] for s in string_list]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n \"\"\"\n Reverses each string in the provided list of strings.\n \n Parameters:\n string_list (list): A list of strings to be reversed.\n \n Returns:\n list: A new list containing the reversed strings.\n \"\"\"\n return [s[::-1] for s in string_list]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(strings):\n \"\"\"\n Reverses each string in the given list of string values.\n\n :param strings: List of strings to reverse\n :return: A new list containing the reversed strings\n \"\"\"\n return [s[::-1] for s in strings]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n \"\"\"Reverses each string in the given list of strings.\"\"\"\n return [s[::-1] for s in string_list]", "matching_cluster_idx": 4}]}, "Mbpp/460": {"dps": 50.67307692307692, "dps_norm": 81.0, "pass@1": 100.0, "profiled": [{"solution": "def Extract(nested_list):\n \"\"\"Extract the first element of each sublist.\"\"\"\n return [sublist[0] for sublist in nested_list if sublist]", "matching_cluster_idx": 3}, {"solution": "def Extract(nested_list):\n \"\"\"Extracts the first element from each sublist in the given nested list.\"\"\"\n return [sublist[0] for sublist in nested_list]", "matching_cluster_idx": 3}, {"solution": "def Extract(lst):\n \"\"\"\n This function takes a list of lists and returns a list containing the first element of each sublist.\n\n Parameters:\n lst (list of list): A list containing sublists.\n\n Returns:\n list: A list of the first elements of each sublist.\n \"\"\"\n return [sublist[0] for sublist in lst if sublist] # Ensure sublist is not empty", "matching_cluster_idx": 3}, {"solution": "def Extract(lst):\n \"\"\"\n Extract the first element of each sublist.\n\n Args:\n lst (list): A list of sublists.\n\n Returns:\n list: A list containing the first element of each sublist.\n \"\"\"\n return [sublist[0] for sublist in lst if sublist]", "matching_cluster_idx": 3}, {"solution": "def Extract(nested_list):\n \"\"\"Extracts the first element of each sublist.\"\"\"\n return [sublist[0] for sublist in nested_list]", "matching_cluster_idx": 3}, {"solution": "def Extract(sublists):\n \"\"\"\n This function takes a list of sublists and returns a list containing \n the first element of each sublist.\n \n :param sublists: List of sublists\n :return: List of first elements from each sublist\n \"\"\"\n return [sublist[0] for sublist in sublists]", "matching_cluster_idx": 3}, {"solution": "def Extract(sublists):\n \"\"\"Returns the first element of each sublist.\"\"\"\n return [sublist[0] for sublist in sublists if sublist]", "matching_cluster_idx": 3}, {"solution": "def Extract(sublists):\n \"\"\"\n Extract the first element of each sublist.\n \n Parameters:\n sublists (list of list): A list containing sublists.\n \n Returns:\n list: A list containing the first element of each sublist.\n \"\"\"\n return [sublist[0] for sublist in sublists]", "matching_cluster_idx": 3}, {"solution": "def Extract(lst):\n \"\"\"Returns the first element of each sublist.\"\"\"\n return [sublist[0] for sublist in lst]", "matching_cluster_idx": 3}, {"solution": "def Extract(lst):\n \"\"\"Return the first element of each sublist in the given list of lists.\"\"\"\n return [sublist[0] for sublist in lst if sublist]", "matching_cluster_idx": 3}, {"solution": "def Extract(nested_list):\n \"\"\"\n This function takes a list of lists and returns a list containing\n the first element of each sublist.\n \n Args:\n nested_list (list of lists): A list where each element is a list.\n \n Returns:\n list: A list of the first elements of each sublist.\n \"\"\"\n return [sublist[0] for sublist in nested_list]", "matching_cluster_idx": 3}, {"solution": "def Extract(sublists):\n \"\"\"Extract the first element from each sublist.\"\"\"\n return [sublist[0] for sublist in sublists if sublist]", "matching_cluster_idx": 3}, {"solution": "def Extract(lst):\n \"\"\"Return a list containing the first element of each sublist.\"\"\"\n return [sublist[0] for sublist in lst if sublist]", "matching_cluster_idx": 3}, {"solution": "def Extract(sublists):\n \"\"\"Extract the first element of each sublist.\"\"\"\n return [sublist[0] for sublist in sublists if sublist]", "matching_cluster_idx": 3}, {"solution": "def Extract(lst):\n \"\"\"Return the first element of each sublist.\"\"\"\n return [sublist[0] for sublist in lst if sublist]", "matching_cluster_idx": 3}, {"solution": "def Extract(sublists):\n \"\"\"Return a list of the first element from each sublist.\"\"\"\n return [sublist[0] for sublist in sublists]", "matching_cluster_idx": 3}, {"solution": "def Extract(sublists):\n \"\"\"Return the first element of each sublist.\"\"\"\n return [sublist[0] for sublist in sublists if sublist]", "matching_cluster_idx": 3}, {"solution": "def Extract(nested_list):\n \"\"\"\n Extract the first element of each sublist.\n \n :param nested_list: A list of lists from which to extract the first elements.\n :return: A list containing the first element of each sublist.\n \"\"\"\n return [sublist[0] for sublist in nested_list]", "matching_cluster_idx": 3}, {"solution": "def Extract(sublists):\n \"\"\"\n Extracts the first element of each sublist.\n\n Parameters:\n sublists (list of lists): A list containing sublists.\n\n Returns:\n list: A list containing the first element of each sublist.\n \"\"\"\n return [sublist[0] for sublist in sublists]", "matching_cluster_idx": 4}, {"solution": "def Extract(nested_list):\n \"\"\"Return the first element of each sublist in the nested list.\"\"\"\n return [sublist[0] for sublist in nested_list if sublist]", "matching_cluster_idx": 3}]}, "Mbpp/474": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def replace_char(s, old_char, new_char):\n \"\"\"\n Replace all occurrences of old_char in string s with new_char.\n \n Parameters:\n s (str): The original string.\n old_char (str): The character to be replaced.\n new_char (str): The character to replace with.\n \n Returns:\n str: A new string with characters replaced.\n \"\"\"\n return s.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, old, new):\n \"\"\"\n Replace all occurrences of old character with new character in the given string.\n\n Parameters:\n s (str): The input string where replacements will be made.\n old (str): The character to be replaced.\n new (str): The character to replace with.\n\n Returns:\n str: A new string with characters replaced.\n \"\"\"\n return s.replace(old, new)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s: str, old: str, new: str) -> str:\n \"\"\"\n Replace all occurrences of a character in a string with another character.\n \n Parameters:\n s (str): The original string.\n old (str): The character to be replaced.\n new (str): The character to replace with.\n \n Returns:\n str: A new string with the specified characters replaced.\n \"\"\"\n return s.replace(old, new)", "matching_cluster_idx": 6}, {"solution": "def replace_char(input_string, old_char, new_char):\n \"\"\"\n Replace all occurrences of old_char in input_string with new_char.\n \n Args:\n input_string (str): The original string in which to replace characters.\n old_char (str): The character to be replaced.\n new_char (str): The character to replace with.\n \n Returns:\n str: The modified string with characters replaced.\n \"\"\"\n return input_string.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, old_char, new_char):\n \"\"\"\n Replaces all occurrences of old_char in string s with new_char.\n\n Parameters:\n s (str): The original string.\n old_char (str): The character to be replaced.\n new_char (str): The character to replace with.\n\n Returns:\n str: A new string with the replaced characters.\n \"\"\"\n return s.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(input_string, old_char, new_char):\n \"\"\"\n Replace all occurrences of old_char in input_string with new_char.\n\n Args:\n input_string (str): The original string.\n old_char (str): The character to be replaced.\n new_char (str): The character to replace with.\n\n Returns:\n str: A new string with old_char replaced by new_char.\n \"\"\"\n return input_string.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(original_string, char_to_replace, replacement_char):\n \"\"\"\n Replaces all occurrences of char_to_replace in original_string \n with replacement_char and returns the new string.\n\n :param original_string: The original string to be modified.\n :param char_to_replace: The character to be replaced.\n :param replacement_char: The character to replace with.\n :return: A new string with the replaced characters.\n \"\"\"\n return original_string.replace(char_to_replace, replacement_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, old_char, new_char):\n \"\"\"\n Replace occurrences of old_char with new_char in the string s.\n \n Parameters:\n s (str): The original string.\n old_char (str): The character to be replaced.\n new_char (str): The character to replace with.\n \n Returns:\n str: A new string with the characters replaced.\n \"\"\"\n return s.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, old_char, new_char):\n \"\"\"\n Replaces all occurrences of old_char in string s with new_char.\n\n Parameters:\n s (str): The original string.\n old_char (str): The character to be replaced.\n new_char (str): The character to replace old_char with.\n\n Returns:\n str: The modified string with all occurrences of old_char replaced by new_char.\n \"\"\"\n return s.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, old_char, new_char):\n \"\"\"\n Replace all occurrences of old_char with new_char in the string s.\n \n Parameters:\n s (str): The original string.\n old_char (str): The character to be replaced.\n new_char (str): The character to replace with.\n \n Returns:\n str: The modified string with replacements made.\n \"\"\"\n return s.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(input_string, target_char, replacement_char):\n \"\"\"\n Replace all occurrences of target_char in input_string with replacement_char.\n\n Args:\n input_string (str): The original string in which to replace characters.\n target_char (str): The character to be replaced.\n replacement_char (str): The character to replace with.\n\n Returns:\n str: A new string with the replacements made.\n \"\"\"\n return input_string.replace(target_char, replacement_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(string, old_char, new_char):\n \"\"\"Replace all occurrences of old_char with new_char in the string.\"\"\"\n return string.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, old, new):\n \"\"\"\n Replace all occurrences of `old` character in string `s` with `new` character.\n\n Parameters:\n s (str): The original string.\n old (str): The character to be replaced.\n new (str): The character to replace with.\n\n Returns:\n str: The modified string with `old` replaced by `new`.\n \"\"\"\n return s.replace(old, new)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, old_char, new_char):\n \"\"\"\n Replace all occurrences of old_char in the string s with new_char.\n \n Args:\n s (str): The input string where characters need to be replaced.\n old_char (str): The character to be replaced.\n new_char (str): The character to replace with.\n\n Returns:\n str: A new string with the specified characters replaced.\n \"\"\"\n return s.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(original_string, target_char, replacement_char):\n \"\"\"\n Replace occurrences of target_char in original_string with replacement_char.\n \n Args:\n original_string (str): The string to modify.\n target_char (str): The character to be replaced.\n replacement_char (str): The character to replace with.\n \n Returns:\n str: The modified string with the replacements made.\n \"\"\"\n return original_string.replace(target_char, replacement_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(input_string, char_to_replace, replacement_char):\n \"\"\"\n Replace all occurrences of char_to_replace in input_string with replacement_char.\n\n Parameters:\n input_string (str): The original string.\n char_to_replace (str): The character to be replaced.\n replacement_char (str): The character to replace with.\n\n Returns:\n str: The modified string with the specified character replaced.\n \"\"\"\n return input_string.replace(char_to_replace, replacement_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(original: str, old_char: str, new_char: str) -> str:\n \"\"\"\n Replace all occurrences of old_char in original with new_char.\n\n Parameters:\n original (str): The original string.\n old_char (str): The character to be replaced.\n new_char (str): The character to replace with.\n\n Returns:\n str: The modified string with characters replaced.\n \"\"\"\n return original.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, old, new):\n \"\"\"\n Replace all occurrences of the character 'old' with 'new' in the string 's'.\n \n Parameters:\n s (str): The original string.\n old (str): The character to be replaced.\n new (str): The character to replace with.\n \n Returns:\n str: The modified string with the characters replaced.\n \"\"\"\n return s.replace(old, new)", "matching_cluster_idx": 6}, {"solution": "def replace_char(original: str, old_char: str, new_char: str) -> str:\n \"\"\"\n Replace all occurrences of old_char in original with new_char.\n\n Parameters:\n original (str): The original string.\n old_char (str): The character to be replaced.\n new_char (str): The character to replace with.\n\n Returns:\n str: The modified string with characters replaced.\n \"\"\"\n return original.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s: str, old: str, new: str) -> str:\n \"\"\"\n Replace all occurrences of old character with new character in the string s.\n\n :param s: The original string\n :param old: The character to be replaced\n :param new: The character to replace with\n :return: A new string with the characters replaced\n \"\"\"\n return s.replace(old, new)", "matching_cluster_idx": 6}]}, "Mbpp/476": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def big_sum(arr):\n \"\"\"Returns the sum of the largest and smallest values in the given array.\"\"\"\n if not arr: # Check if the array is empty\n return 0\n largest = max(arr)\n smallest = min(arr)\n return largest + smallest", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n \"\"\"\n Returns the sum of the largest and smallest value in the given array.\n \n Parameters:\n arr (list): A list of numbers.\n \n Returns:\n int or float: The sum of the largest and smallest numbers in the array.\n \"\"\"\n if not arr: # Check if the array is empty\n return 0\n \n largest = max(arr)\n smallest = min(arr)\n \n return largest + smallest", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n # Check if the array is empty\n if not arr:\n return 0 # Return 0 for an empty array\n\n # Find the maximum and minimum values in the array\n max_value = max(arr)\n min_value = min(arr)\n\n # Return the sum of the largest and smallest values\n return max_value + min_value", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n \"\"\"\n Calculate the sum of the largest and smallest value in the array.\n\n Parameters:\n arr (list): A list of numerical values.\n\n Returns:\n int/float: The sum of the largest and smallest values in the array.\n \"\"\"\n if not arr:\n raise ValueError(\"Array should not be empty\")\n\n smallest = min(arr)\n largest = max(arr)\n\n return smallest + largest", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n \"\"\"Returns the sum of the largest and smallest values in the array.\"\"\"\n if not arr: # Check if the array is empty\n return 0\n smallest = min(arr)\n largest = max(arr)\n return smallest + largest", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n \"\"\"Find the sum of the largest and smallest value in the given array.\"\"\"\n if not arr:\n raise ValueError(\"The input array cannot be empty.\")\n smallest = min(arr)\n largest = max(arr)\n return smallest + largest", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n if not arr: # Check if the array is empty\n return 0\n smallest = min(arr)\n largest = max(arr)\n return smallest + largest", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n if not arr: # Check for empty array\n return 0\n largest = max(arr)\n smallest = min(arr)\n return largest + smallest", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n \"\"\"\n This function returns the sum of the largest and smallest values in the given array.\n\n :param arr: List of numbers\n :return: Sum of the largest and smallest values\n \"\"\"\n if not arr:\n raise ValueError(\"The array should not be empty.\")\n\n smallest = min(arr)\n largest = max(arr)\n \n return smallest + largest", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n \"\"\"\n Function to find the sum of the largest and smallest value in a given array.\n \n Parameters:\n arr (list): A list of numerical values.\n \n Returns:\n int/float: The sum of the largest and smallest values in the array.\n \"\"\"\n if not arr: # Check if the array is empty\n raise ValueError(\"The array cannot be empty.\")\n \n smallest = min(arr)\n largest = max(arr)\n \n return smallest + largest", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n \"\"\"\n This function takes an array as input and returns the sum of the largest \n and smallest values in that array.\n \n Parameters:\n arr (list): A list of numerical values.\n \n Returns:\n int or float: The sum of the largest and smallest values in the array.\n \"\"\"\n if not arr:\n raise ValueError(\"The array should not be empty.\")\n \n smallest = min(arr)\n largest = max(arr)\n \n return smallest + largest", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n \"\"\"\n This function returns the sum of the largest and smallest values in the given array.\n \n :param arr: List of numbers\n :return: Sum of the largest and smallest numbers\n \"\"\"\n if not arr: # Check for empty array\n return 0\n \n largest = max(arr)\n smallest = min(arr)\n \n return largest + smallest", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n \"\"\"\n Function to find the sum of the largest and smallest value in a given array.\n \n Parameters:\n arr (list): A list of numbers\n \n Returns:\n int: The sum of the largest and smallest values in the array\n \"\"\"\n if not arr: # Check if the list is empty\n return 0 # Return 0 for an empty list\n \n largest = max(arr) # Find the largest value in the array\n smallest = min(arr) # Find the smallest value in the array\n return largest + smallest # Return the sum of largest and smallest", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n \"\"\"\n This function returns the sum of the largest and smallest values in a given array.\n \n Parameters:\n arr (list): A list of numerical values.\n \n Returns:\n int/float: The sum of the largest and smallest values in the array.\n \"\"\"\n if not arr:\n raise ValueError(\"The array cannot be empty\")\n \n largest = max(arr)\n smallest = min(arr)\n return largest + smallest", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n \"\"\"Returns the sum of the largest and smallest value in the array.\"\"\"\n if not arr: # Check if the array is empty\n return 0 # Return 0 for an empty array\n\n largest = max(arr) # Find the largest value\n smallest = min(arr) # Find the smallest value\n return largest + smallest # Return the sum of the largest and smallest values", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n \"\"\"Returns the sum of the largest and smallest value in the array.\"\"\"\n if not arr:\n raise ValueError(\"Array must not be empty.\")\n \n largest = max(arr)\n smallest = min(arr)\n \n return largest + smallest", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n if not arr: # Check if the array is empty\n return 0 # Return 0 for an empty array\n largest = max(arr) # Find the largest value\n smallest = min(arr) # Find the smallest value\n return largest + smallest # Return the sum of the largest and smallest values", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n \"\"\"\n Function to find the sum of the largest and smallest value in a given array.\n \n Parameters:\n arr (list): A list of numeric values.\n \n Returns:\n int/float: The sum of the largest and smallest values in the array.\n \"\"\"\n if not arr:\n raise ValueError(\"The array cannot be empty.\")\n\n largest = max(arr)\n smallest = min(arr)\n \n return largest + smallest", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n \"\"\"\n Calculate the sum of the largest and smallest values in the given array.\n\n Parameters:\n arr (list): A list of numerical values.\n\n Returns:\n int or float: The sum of the largest and smallest values in the array.\n \"\"\"\n if not arr: # Check if the list is empty\n return 0\n \n largest = max(arr)\n smallest = min(arr)\n return largest + smallest", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n \"\"\"\n This function returns the sum of the largest and smallest values in the given array.\n \n Parameters:\n arr (list): A list of numerical values.\n \n Returns:\n int or float: The sum of the largest and smallest values in the array.\n \"\"\"\n if not arr:\n return None # Handle empty list case\n \n largest = max(arr)\n smallest = min(arr)\n \n return largest + smallest", "matching_cluster_idx": 5}]}, "Mbpp/477": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def is_lower(s):\n \"\"\"Converts the given string to lower case.\"\"\"\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(input_string):\n \"\"\"\n Converts the given string to lower case.\n\n Parameters:\n input_string (str): The string to be converted.\n\n Returns:\n str: The lower case version of the input string.\n \"\"\"\n return input_string.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n \"\"\"\n Convert the given string to lower case.\n\n Parameters:\n s (str): The string to convert.\n\n Returns:\n str: The lowercase version of the input string.\n \"\"\"\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(input_string):\n \"\"\"\n Converts the given string to lower case.\n\n Args:\n input_string (str): The string to be converted.\n\n Returns:\n str: The lower case version of the input string.\n \"\"\"\n return input_string.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n \"\"\"Convert the given string to lower case.\"\"\"\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n \"\"\"Convert the given string to lower case.\"\"\"\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n \"\"\"Converts the given string to lower case.\"\"\"\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s: str) -> str:\n \"\"\"Convert the given string to lower case.\"\"\"\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s: str) -> str:\n \"\"\"\n Convert the given string to lower case.\n \n :param s: The string to be converted.\n :return: The lower case version of the string.\n \"\"\"\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n \"\"\"\n Converts the given string to lower case.\n \n Parameters:\n s (str): The string to be converted to lower case.\n \n Returns:\n str: The lower case version of the input string.\n \"\"\"\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(input_string):\n \"\"\"\n Convert the given string to lower case.\n \n Parameters:\n input_string (str): The string to be converted to lower case.\n \n Returns:\n str: The lower case version of the input string.\n \"\"\"\n return input_string.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(input_string):\n \"\"\"\n Convert the given string to lower case.\n \n Args:\n input_string (str): The string to be converted to lower case.\n \n Returns:\n str: The lower case version of the input string.\n \"\"\"\n return input_string.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(input_string):\n \"\"\"\n Convert the given string to lower case.\n\n :param input_string: str - The string to convert\n :return: str - The lower case version of the input string\n \"\"\"\n return input_string.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s: str) -> str:\n \"\"\"\n Convert the given string to lower case.\n\n :param s: The input string to be converted.\n :return: The lower case version of the input string.\n \"\"\"\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(input_string):\n \"\"\"Convert the given string to lower case.\"\"\"\n return input_string.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n \"\"\"\n Convert the given string to lower case.\n \n Args:\n s (str): The string to convert.\n \n Returns:\n str: The lower case version of the string.\n \"\"\"\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s: str) -> str:\n \"\"\"\n Convert the given string to lower case.\n\n Args:\n s (str): The string to be converted.\n\n Returns:\n str: The lower case version of the input string.\n \"\"\"\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s: str) -> str:\n \"\"\"\n Convert the given string to lower case.\n \n Args:\n s (str): The input string to convert.\n\n Returns:\n str: The converted lower case string.\n \"\"\"\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(input_string):\n \"\"\"\n Converts the given string to lower case.\n\n Args:\n input_string (str): The string to be converted to lower case.\n\n Returns:\n str: The lower case version of the input string.\n \"\"\"\n return input_string.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(input_string):\n \"\"\"\n Converts the given string to lower case.\n\n Args:\n input_string (str): The string to be converted.\n\n Returns:\n str: The lower case version of the input string.\n \"\"\"\n return input_string.lower()", "matching_cluster_idx": 4}]}, "Mbpp/563": {"dps": 85.24590163934427, "dps_norm": 81.81818181818181, "pass@1": 94.0, "profiled": [{"solution": "def extract_values(input_string):\n import re\n # Use regular expression to find all substrings enclosed in double quotes\n return re.findall(r'\"([^\"]*)\"', input_string)", "matching_cluster_idx": 8}, {"solution": "def extract_values(s):\n \"\"\"\n Extracts values between quotation marks from the input string.\n\n Args:\n s (str): The input string containing quoted values.\n\n Returns:\n list: A list of extracted values without the quotation marks.\n \"\"\"\n import re\n # Use regex to find all occurrences of strings in double quotes\n return re.findall(r'\"(.*?)\"', s)", "matching_cluster_idx": 8}, {"solution": "def extract_values(s):\n # Import regular expression module\n import re\n # Use regex to find all occurrences of strings within double quotes\n return re.findall(r'\"(.*?)\"', s)", "matching_cluster_idx": 8}, {"solution": "def extract_values(s):\n import re\n # Use regex to find all occurrences of text between double quotes\n return re.findall(r'\"(.*?)\"', s)", "matching_cluster_idx": 8}, {"solution": "def extract_values(s):\n import re\n # Use regex to find all occurrences of text within quotation marks\n return re.findall(r'\"(.*?)\"', s)", "matching_cluster_idx": 8}, {"solution": "def extract_values(s):\n \"\"\"\n Extracts values between quotation marks from the given string.\n\n Args:\n s (str): The input string containing values in quotation marks.\n\n Returns:\n list: A list of extracted values without the quotation marks.\n \"\"\"\n import re\n # Use regex to find all occurrences of text within double quotes\n return re.findall(r'\"(.*?)\"', s)", "matching_cluster_idx": 8}, {"solution": "def extract_values(s):\n import re\n # Use regex to find all occurrences of values within double quotes\n return re.findall(r'\"([^\"]*)\"', s)", "matching_cluster_idx": 8}, {"solution": "def extract_values(s):\n \"\"\"\n Extracts values between quotation marks from a string.\n \n Parameters:\n s (str): The input string containing quoted values.\n\n Returns:\n List[str]: A list of extracted values.\n \"\"\"\n import re\n return re.findall(r'\"(.*?)\"', s)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(s):\n \"\"\"Extract values between quotation marks from a string.\"\"\"\n return re.findall(r'\"([^\"]*)\"', s)", "matching_cluster_idx": 8}, {"solution": "def extract_values(input_string):\n import re\n # Use regex to find all occurrences of strings within quotes\n return re.findall(r'\"(.*?)\"', input_string)", "matching_cluster_idx": 8}, {"solution": "def extract_values(input_string):\n import re\n # Use regex to find all occurrences of text within double quotes\n return re.findall(r'\"(.*?)\"', input_string)", "matching_cluster_idx": 8}, {"solution": "def extract_values(input_string):\n import re\n # Use regex to find all occurrences of text within quotation marks\n return re.findall(r'\"(.*?)\"', input_string)", "matching_cluster_idx": 8}, {"solution": "def extract_values(s):\n import re\n # Use a regular expression to find all occurrences of text between double quotes\n return re.findall(r'\"(.*?)\"', s)", "matching_cluster_idx": 8}, {"solution": "def extract_values(s):\n \"\"\"\n Extract values between quotation marks from a given string.\n \n Args:\n s (str): The input string containing quoted values.\n \n Returns:\n list: A list of values extracted from the quotation marks.\n \"\"\"\n import re\n return re.findall(r'\"(.*?)\"', s)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(input_string):\n \"\"\"\n Extracts values between quotation marks from a given string.\n \n Args:\n input_string (str): The string to extract values from.\n \n Returns:\n List[str]: A list of extracted values between quotation marks.\n \"\"\"\n # Use regular expression to find all occurrences of strings in quotes\n return re.findall(r'\"(.*?)\"', input_string)", "matching_cluster_idx": 8}, {"solution": "def extract_values(s):\n import re\n # Use regular expression to find all occurrences of text within quotes\n return re.findall(r'\"(.*?)\"', s)", "matching_cluster_idx": 8}, {"solution": "def extract_values(s):\n # Importing the regular expression module\n import re\n # Using regex to find all occurrences of text within double quotes\n return re.findall(r'\"(.*?)\"', s)", "matching_cluster_idx": 8}, {"solution": "def extract_values(s):\n import re\n # Use regex to find all occurrences of text within quotation marks\n return re.findall(r'\"(.*?)\"', s)", "matching_cluster_idx": 8}, {"solution": "def extract_values(s):\n \"\"\"\n Extracts values between quotation marks from the given string.\n\n Args:\n s (str): The input string containing values enclosed in quotation marks.\n\n Returns:\n list: A list of extracted values.\n \"\"\"\n import re\n # Using regular expression to find all occurrences of quoted strings\n return re.findall(r'\"(.*?)\"', s)", "matching_cluster_idx": 8}, {"solution": "def extract_values(s):\n import re\n # Use regex to find all occurrences of text within double quotes\n return re.findall(r'\"([^\"]*)\"', s)", "matching_cluster_idx": 8}]}, "Mbpp/572": {"dps": 96.0493827160494, "dps_norm": 88.57142857142857, "pass@1": 100.0, "profiled": [{"solution": "def two_unique_nums(nums):\n \"\"\"\n This function takes a list of numbers and returns a list of numbers\n that appear exactly once in the given list.\n \n Parameters:\n nums (list): A list of integers\n \n Returns:\n list: A list containing the unique integers from the input list\n \"\"\"\n # Create a dictionary to count occurrences of each number\n count = {}\n \n # Count each number in the list\n for num in nums:\n count[num] = count.get(num, 0) + 1\n \n # Extract numbers that appear exactly once\n unique_nums = [num for num, cnt in count.items() if cnt == 1]\n \n return unique_nums", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(nums):\n \"\"\"\n Remove duplicate numbers from the list and return only those numbers which appear exactly once.\n\n :param nums: List of integers.\n :return: List of integers that appear exactly once.\n \"\"\"\n from collections import Counter\n\n # Count the frequency of each number in the list\n num_counts = Counter(nums)\n\n # Extract numbers that appear exactly once\n unique_nums = [num for num, count in num_counts.items() if count == 1]\n\n return unique_nums", "matching_cluster_idx": 6}, {"solution": "def two_unique_nums(numbers):\n # Create a frequency dictionary to count occurrences of each number\n frequency = {}\n \n # Count occurrences of each number in the list\n for num in numbers:\n if num in frequency:\n frequency[num] += 1\n else:\n frequency[num] = 1\n \n # Collect numbers that occur exactly once\n unique_nums = [num for num, count in frequency.items() if count == 1]\n \n return unique_nums", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(nums):\n \"\"\"\n This function takes a list of numbers and returns a list containing\n only the numbers that appear exactly once in the input list.\n\n Args:\n nums (list): A list of integers.\n\n Returns:\n list: A list of integers that are unique (appear only once).\n \"\"\"\n from collections import Counter\n \n # Count the occurrences of each number in the list\n count = Counter(nums)\n \n # Extract the numbers that occur exactly once\n unique_nums = [num for num, cnt in count.items() if cnt == 1]\n \n return unique_nums", "matching_cluster_idx": 6}, {"solution": "def two_unique_nums(nums):\n \"\"\"\n This function takes a list of numbers and returns a new list containing\n only the numbers that appear exactly once in the input list.\n\n :param nums: List of integers\n :return: List of integers that appear exactly once\n \"\"\"\n from collections import Counter\n\n # Count the occurrences of each number\n num_count = Counter(nums)\n\n # Filter and keep only the numbers that appear exactly once\n unique_nums = [num for num, count in num_count.items() if count == 1]\n\n return unique_nums", "matching_cluster_idx": 6}, {"solution": "def two_unique_nums(nums):\n \"\"\"\n This function takes a list of numbers and returns a list of numbers\n that appear exactly once (unique numbers) in the input list.\n\n Args:\n nums (list): A list of integers.\n\n Returns:\n list: A list of unique integers.\n \"\"\"\n # Create a dictionary to count occurrences of each number\n count = {}\n for num in nums:\n count[num] = count.get(num, 0) + 1\n \n # Extract numbers that appear exactly once\n unique_nums = [num for num, cnt in count.items() if cnt == 1]\n \n return unique_nums", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(lst):\n # Create a dictionary to count occurrences of each number\n count_dict = {}\n \n # Count occurrences of each number in the list\n for num in lst:\n if num in count_dict:\n count_dict[num] += 1\n else:\n count_dict[num] = 1\n\n # Collect numbers that appear exactly once\n unique_nums = [num for num, count in count_dict.items() if count == 1]\n \n return unique_nums", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(nums):\n \"\"\"\n Remove duplicate numbers from the list and return only the numbers that appear exactly once.\n \n Args:\n nums (list): A list of integers.\n \n Returns:\n list: A list of integers that appear exactly once in the input list.\n \"\"\"\n # Create a dictionary to count occurrences of each number\n counts = {}\n \n # Count occurrences of each number\n for num in nums:\n counts[num] = counts.get(num, 0) + 1\n \n # Collect numbers that appear exactly once\n unique_nums = [num for num, count in counts.items() if count == 1]\n \n return unique_nums", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(lst):\n \"\"\"\n This function takes a list of numbers and returns a new list containing \n only the numbers that are unique (appear exactly once) in the input list.\n\n Args:\n lst (list): A list of numbers.\n\n Returns:\n list: A list containing numbers that appear exactly once in the input list.\n \"\"\"\n # Create a dictionary to count occurrences of each number\n count_dict = {}\n \n for num in lst:\n if num in count_dict:\n count_dict[num] += 1\n else:\n count_dict[num] = 1\n\n # Collect only the numbers that appear exactly once\n unique_nums = [num for num, count in count_dict.items() if count == 1]\n \n return unique_nums", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(lst):\n # Create a dictionary to count occurrences of each number\n count = {}\n \n # Count occurrences of each number in the list\n for num in lst:\n if num in count:\n count[num] += 1\n else:\n count[num] = 1\n \n # Extract numbers that appear only once\n unique_nums = [num for num, cnt in count.items() if cnt == 1]\n \n return unique_nums", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(lst):\n # Create a dictionary to count occurrences of each number\n count = {}\n \n # Count each number's occurrences\n for num in lst:\n if num in count:\n count[num] += 1\n else:\n count[num] = 1\n\n # Filter the numbers that occur exactly once\n unique_nums = [num for num, cnt in count.items() if cnt == 1]\n \n return unique_nums", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(numbers):\n \"\"\"\n This function takes a list of numbers and returns a list containing only the unique numbers\n that appear exactly once in the input list.\n\n :param numbers: List of integers\n :return: List of unique integers appearing exactly once\n \"\"\"\n from collections import Counter\n\n # Count the occurrences of each number in the list\n counts = Counter(numbers)\n\n # Collect numbers that appear exactly once\n unique_nums = [num for num, count in counts.items() if count == 1]\n\n return unique_nums", "matching_cluster_idx": 6}, {"solution": "def two_unique_nums(nums):\n \"\"\"Remove duplicate numbers and return a list of unique numbers that appear only once.\"\"\"\n from collections import Counter\n \n # Count occurrences of each number\n count = Counter(nums)\n \n # Create a list of numbers that appear exactly once\n unique_nums = [num for num in nums if count[num] == 1]\n \n return unique_nums", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(nums):\n # Create a dictionary to count occurrences of each number\n count = {}\n \n # Count each number's occurrences\n for num in nums:\n count[num] = count.get(num, 0) + 1\n\n # Collect numbers that occur exactly once\n unique_nums = [num for num in nums if count[num] == 1]\n \n return unique_nums", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(numbers):\n # Create a dictionary to count occurrences of each number\n num_count = {}\n \n # Count the occurrences of each number in the list\n for num in numbers:\n if num in num_count:\n num_count[num] += 1\n else:\n num_count[num] = 1\n \n # Create a list for unique numbers (occurs exactly once)\n unique_nums = [num for num, count in num_count.items() if count == 1]\n \n return unique_nums", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(lst):\n \"\"\"\n This function takes a list of numbers and returns a new list \n containing only the unique numbers from the input list.\n \n Parameters:\n lst (list): A list of integers which may contain duplicates.\n\n Returns:\n list: A list containing only the unique integers from the input list.\n \"\"\"\n # Count occurrences of each number\n num_count = {}\n \n for num in lst:\n if num in num_count:\n num_count[num] += 1\n else:\n num_count[num] = 1\n \n # Collect numbers that appear exactly once\n unique_nums = [num for num, count in num_count.items() if count == 1]\n \n return unique_nums", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(lst):\n # Create a dictionary to count occurrences of each number\n count = {}\n \n # Count the occurrences of each number in the list\n for num in lst:\n if num in count:\n count[num] += 1\n else:\n count[num] = 1\n \n # Filter out numbers that appear more than once\n unique_nums = [num for num in lst if count[num] == 1]\n \n return unique_nums", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(lst):\n \"\"\"\n This function takes a list of numbers and returns a list of numbers\n that appear exactly once in the original list.\n \n :param lst: List of integers\n :return: List of integers that are unique\n \"\"\"\n num_count = {}\n \n # Count occurrences of each number\n for num in lst:\n if num in num_count:\n num_count[num] += 1\n else:\n num_count[num] = 1\n \n # Collect numbers that appear exactly once\n unique_nums = [num for num, count in num_count.items() if count == 1]\n \n return unique_nums", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(numbers):\n # Create a dictionary to count occurrences of each number\n count = {}\n \n # Count each number in the list\n for num in numbers:\n count[num] = count.get(num, 0) + 1\n \n # Extract only the numbers that appear exactly once\n unique_nums = [num for num in count if count[num] == 1]\n \n return unique_nums", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(numbers):\n # Create a dictionary to count occurrences of each number\n count_dict = {}\n \n # Count occurrences of each number\n for num in numbers:\n if num in count_dict:\n count_dict[num] += 1\n else:\n count_dict[num] = 1\n \n # Collect the numbers that occur exactly once\n unique_numbers = [num for num, count in count_dict.items() if count == 1]\n \n return unique_numbers", "matching_cluster_idx": 5}]}, "Mbpp/578": {"dps": 83.38095238095238, "dps_norm": 69.54545454545455, "pass@1": 100.0, "profiled": [{"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"\n Interleave three lists of the same length into a single flat list.\n \n Args:\n list1: The first list to interleave.\n list2: The second list to interleave.\n list3: The third list to interleave.\n \n Returns:\n A list containing the elements of list1, list2, and list3 interleaved.\n \"\"\"\n if len(list1) != len(list2) or len(list1) != len(list3):\n raise ValueError(\"All lists must be of the same length.\")\n \n interleaved = []\n for a, b, c in zip(list1, list2, list3):\n interleaved.extend([a, b, c])\n \n return interleaved", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(list1, list2, list3):\n # Ensure all lists are of the same length\n if len(list1) != len(list2) or len(list1) != len(list3):\n raise ValueError(\"All lists must be of the same length.\")\n \n # Initialize an empty list to hold the interleaved result\n interleaved = []\n \n # Iterate through the indices of the lists and interleave the elements\n for i in range(len(list1)):\n interleaved.append(list1[i])\n interleaved.append(list2[i])\n interleaved.append(list3[i])\n \n return interleaved", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"Interleave three lists of the same length into a single flat list.\"\"\"\n if len(list1) != len(list2) or len(list1) != len(list3):\n raise ValueError(\"All lists must have the same length.\")\n \n result = []\n for a, b, c in zip(list1, list2, list3):\n result.extend([a, b, c])\n \n return result", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(list1, list2, list3):\n # Check if all lists are of the same length\n if len(list1) != len(list2) or len(list2) != len(list3):\n raise ValueError(\"All lists must be of the same length.\")\n \n # Interleave the lists\n interleaved = []\n for i in range(len(list1)):\n interleaved.append(list1[i])\n interleaved.append(list2[i])\n interleaved.append(list3[i])\n \n return interleaved", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n # Check if all lists have the same length\n if len(list1) != len(list2) or len(list1) != len(list3):\n raise ValueError(\"All lists must have the same length\")\n\n # Initialize an empty list for the result\n interleaved_list = []\n\n # Interleave the lists\n for i in range(len(list1)):\n interleaved_list.append(list1[i])\n interleaved_list.append(list2[i])\n interleaved_list.append(list3[i])\n\n return interleaved_list", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"\n Interleave three lists of the same length into a single flat list.\n \n Args:\n list1 (list): The first list to interleave.\n list2 (list): The second list to interleave.\n list3 (list): The third list to interleave.\n\n Returns:\n list: A single list containing elements from list1, list2, and list3 interleaved.\n \n Raises:\n ValueError: If the lists are not of the same length.\n \"\"\"\n if not (len(list1) == len(list2) == len(list3)):\n raise ValueError(\"All lists must have the same length\")\n\n interleaved = []\n for a, b, c in zip(list1, list2, list3):\n interleaved.extend([a, b, c])\n \n return interleaved", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"\n Interleave three lists of the same length into a single flat list.\n \n :param list1: The first list\n :param list2: The second list\n :param list3: The third list\n :return: A single list with elements from list1, list2, and list3 interleaved\n \"\"\"\n # Ensure all lists are of the same length\n if len(list1) != len(list2) or len(list1) != len(list3):\n raise ValueError(\"All lists must have the same length\")\n \n interleaved = []\n for a, b, c in zip(list1, list2, list3):\n interleaved.extend([a, b, c])\n \n return interleaved", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(list1, list2, list3):\n # Ensure all lists are of the same length\n if not (len(list1) == len(list2) == len(list3)):\n raise ValueError(\"All lists must be of the same length\")\n \n interleaved = []\n for a, b, c in zip(list1, list2, list3):\n interleaved.extend([a, b, c])\n \n return interleaved", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"Interleave three lists into a single flat list.\"\"\"\n interleaved = []\n for i in range(len(list1)):\n interleaved.append(list1[i])\n interleaved.append(list2[i])\n interleaved.append(list3[i])\n return interleaved", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n # Check that all lists are of the same length\n if len(list1) != len(list2) or len(list1) != len(list3):\n raise ValueError(\"All lists must be of the same length\")\n \n # Interleave the lists\n interleaved = []\n for i in range(len(list1)):\n interleaved.append(list1[i])\n interleaved.append(list2[i])\n interleaved.append(list3[i])\n \n return interleaved", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"Interleave three lists of the same length into a single flat list.\"\"\"\n interleaved = []\n for a, b, c in zip(list1, list2, list3):\n interleaved.extend([a, b, c])\n return interleaved", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(list1, list2, list3):\n # Ensure all lists are of the same length\n if not (len(list1) == len(list2) == len(list3)):\n raise ValueError(\"All lists must be of the same length.\")\n \n # Use a list comprehension to interleave the lists\n interleaved = [item for group in zip(list1, list2, list3) for item in group]\n \n return interleaved", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"\n Interleaves three lists of the same length into a single flat list.\n\n Parameters:\n list1 (list): The first list.\n list2 (list): The second list.\n list3 (list): The third list.\n\n Returns:\n list: A new list containing the elements of the input lists interleaved.\n \"\"\"\n interleaved = []\n for a, b, c in zip(list1, list2, list3):\n interleaved.extend([a, b, c])\n return interleaved", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"Interleaves three lists of the same length into a single flat list.\"\"\"\n if len(list1) != len(list2) or len(list1) != len(list3):\n raise ValueError(\"All lists must be of the same length.\")\n \n interleaved = []\n for a, b, c in zip(list1, list2, list3):\n interleaved.extend([a, b, c])\n \n return interleaved", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(list1, list2, list3):\n # Ensure all lists are of the same length\n if len(list1) != len(list2) or len(list1) != len(list3):\n raise ValueError(\"All input lists must be of the same length.\")\n \n interleaved = []\n for i in range(len(list1)):\n interleaved.append(list1[i])\n interleaved.append(list2[i])\n interleaved.append(list3[i])\n \n return interleaved", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"Interleave three lists into a single flat list.\"\"\"\n if len(list1) != len(list2) or len(list1) != len(list3):\n raise ValueError(\"All lists must have the same length.\")\n \n interleaved = []\n for a, b, c in zip(list1, list2, list3):\n interleaved.extend([a, b, c])\n \n return interleaved", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"\n Interleave three lists of the same length into a single flat list.\n \n Parameters:\n list1 (list): The first list.\n list2 (list): The second list.\n list3 (list): The third list.\n \n Returns:\n list: A new list containing elements of list1, list2, and list3 interleaved.\n \"\"\"\n if len(list1) != len(list2) or len(list1) != len(list3):\n raise ValueError(\"All lists must have the same length\")\n \n interleaved = []\n for a, b, c in zip(list1, list2, list3):\n interleaved.extend([a, b, c])\n \n return interleaved", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"\n Interleave three lists of the same length into a single flat list.\n \n Parameters:\n list1 (list): First list.\n list2 (list): Second list.\n list3 (list): Third list.\n \n Returns:\n list: A new list with elements of the three lists interleaved.\n \n Raises:\n ValueError: If the input lists are not of the same length.\n \"\"\"\n if len(list1) != len(list2) or len(list1) != len(list3):\n raise ValueError(\"All lists must have the same length.\")\n \n interleaved = []\n for a, b, c in zip(list1, list2, list3):\n interleaved.extend([a, b, c])\n \n return interleaved", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(list1, list2, list3):\n # Check if all lists are of the same length\n if len(list1) != len(list2) or len(list1) != len(list3):\n raise ValueError(\"All lists must have the same length\")\n\n # Interleave the lists\n interleaved = []\n for i in range(len(list1)):\n interleaved.append(list1[i])\n interleaved.append(list2[i])\n interleaved.append(list3[i])\n \n return interleaved", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"\n Interleave three lists of the same length into a single flat list.\n\n Parameters:\n list1 (list): The first list.\n list2 (list): The second list.\n list3 (list): The third list.\n\n Returns:\n list: A single list with elements from list1, list2, and list3 interleaved.\n \"\"\"\n if len(list1) != len(list2) or len(list1) != len(list3):\n raise ValueError(\"All lists must be of the same length\")\n\n interleaved = []\n for a, b, c in zip(list1, list2, list3):\n interleaved.extend([a, b, c])\n \n return interleaved", "matching_cluster_idx": 7}]}, "Mbpp/586": {"dps": 98.83040935672514, "dps_norm": 87.5, "pass@1": 27.0, "profiled": [{"solution": "def split_Arr(arr, n):\n # Split the array into two parts\n first_part = arr[:n]\n second_part = arr[n:]\n # Combine the second part with the first part\n return second_part + first_part", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"\n Splits the list at the nth element and adds the first part to the end.\n\n Parameters:\n arr (list): The list to be split.\n n (int): The index at which to split the list.\n\n Returns:\n list: The modified list after the split and append operation.\n \"\"\"\n # Split the list at the nth index\n first_part = arr[:n]\n second_part = arr[n:]\n\n # Combine the two parts: second part followed by first part\n return second_part + first_part", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"\n Split the list at the nth element and append the first part to the end.\n\n Parameters:\n arr (list): The list to be split.\n n (int): The index at which to split the list.\n\n Returns:\n list: The new list after the split and append operation.\n \"\"\"\n # Handle edge cases\n if not arr or n < 0 or n >= len(arr):\n return arr\n\n # Split the array into two parts\n first_part = arr[:n]\n second_part = arr[n:]\n\n # Append the first part to the end of the second part\n return second_part + first_part", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"\n Splits the array at the nth element and appends the first part to the end.\n\n Parameters:\n arr (list): The list to be split.\n n (int): The index at which to split the list.\n\n Returns:\n list: The modified list after the split and append operation.\n \"\"\"\n # Split the list into two parts\n first_part = arr[:n] # elements from start to nth element (exclusive)\n second_part = arr[n:] # elements from nth element to end\n\n # Combine the second part with the first part\n return second_part + first_part", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"\n Split a list at the nth element and add the first part to the end.\n\n Parameters:\n arr (list): The list to be split.\n n (int): The index at which to split the list.\n\n Returns:\n list: The modified list after splitting and rearranging.\n \"\"\"\n # Handle cases where n is greater than the length of the array\n if n >= len(arr):\n return arr\n \n # Split the list at the nth element\n first_part = arr[:n]\n second_part = arr[n:]\n \n # Combine the two parts with the first part at the end\n return second_part + first_part", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"\n Splits the array at the nth element and adds the first part to the end.\n\n :param arr: List of elements to be split.\n :param n: The index at which to split the array.\n :return: A new list with the first part added to the end.\n \"\"\"\n # Validate input\n if not isinstance(arr, list):\n raise ValueError(\"First argument must be a list.\")\n if not isinstance(n, int) or n < 0 or n > len(arr):\n raise ValueError(\"Second argument must be a valid index.\")\n\n # Split the array\n first_part = arr[:n]\n second_part = arr[n:]\n\n # Return the new list with first part added to the end\n return second_part + first_part", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"\n Splits the list at the nth element and adds the first part to the end.\n \n Parameters:\n arr (list): The input list to be split.\n n (int): The index at which to split the list.\n \n Returns:\n list: The modified list with the first part added to the end.\n \"\"\"\n # Split the list into two parts\n first_part = arr[:n]\n second_part = arr[n:]\n \n # Combine the second part with the first part at the end\n return second_part + first_part", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"\n Splits the list at the nth element and adds the first part to the end.\n\n Parameters:\n arr (list): The list to be split.\n n (int): The index at which to split the list.\n\n Returns:\n list: The modified list after the split.\n \"\"\"\n # Validate the index n\n if n < 0 or n > len(arr):\n raise ValueError(\"Index n must be in the range of the list length.\")\n\n # Split the list at the nth element\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"\n Splits the input list at the nth element and appends the first part to the end.\n\n Parameters:\n arr (list): The list to be split.\n n (int): The index at which to split the list.\n\n Returns:\n list: A new list with the elements from index n to the end, followed by the elements from the start to index n-1.\n \"\"\"\n # Handle the case when n is greater than the length of the list\n n = n % len(arr) if len(arr) > 0 else 0\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"\n Splits the list at the nth element and adds the first part to the end.\n\n Parameters:\n arr (list): The list to be split.\n n (int): The index at which to split the list.\n\n Returns:\n list: A new list with the first part added to the end.\n \"\"\"\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"\n Splits the list at the nth element and adds the first part to the end.\n \n Parameters:\n arr (list): The list to be split.\n n (int): The index at which to split the list.\n \n Returns:\n list: The modified list after splitting and reordering.\n \"\"\"\n # Ensure the index is within the bounds of the list\n if n < 0 or n > len(arr):\n raise ValueError(\"Index n must be within the range of the list.\")\n \n # Split the list into two parts\n first_part = arr[:n]\n second_part = arr[n:]\n \n # Concatenate the second part with the first part\n return second_part + first_part", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"\n Splits the input list at the nth element and adds the first part to the end.\n \n Args:\n arr (list): The list to be split.\n n (int): The index at which to split the list.\n \n Returns:\n list: The modified list with the first part added to the end.\n \"\"\"\n # Split the list into two parts\n first_part = arr[:n]\n second_part = arr[n:]\n \n # Combine the two parts with the first part at the end\n return second_part + first_part", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"\n Splits the list at the nth element and adds the first part to the end.\n\n Parameters:\n arr (list): The list to be split.\n n (int): The index at which to split the list.\n\n Returns:\n list: The modified list after the split and reordering.\n \"\"\"\n # Ensure the index is within the bounds of the list\n n = n % len(arr) if arr else 0 # Handle cases where n is greater than the list length\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"\n Splits the list at the nth element and appends the first part to the end.\n\n Parameters:\n arr (list): The list to be split.\n n (int): The index at which to split the list.\n\n Returns:\n list: The modified list with the first part added to the end.\n \"\"\"\n # Handle cases where n is greater than the length of the list\n n = n % len(arr) if arr else 0\n \n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"Splits the list at the nth element and adds the first part to the end.\"\"\"\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"\n Splits the array at the nth element and adds the first part to the end.\n\n :param arr: List of elements to be split\n :param n: The index at which to split the list\n :return: A new list with the elements rearranged\n \"\"\"\n if n < 0 or n > len(arr):\n raise ValueError(\"n must be between 0 and the length of the array\")\n\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"\n Splits the list at the nth element and adds the first part to the end.\n\n Parameters:\n arr (list): The list to be split.\n n (int): The index at which to split the list.\n\n Returns:\n list: The modified list with the first part added to the end.\n \"\"\"\n # Ensure n is within the bounds of the list\n if n < 0 or n > len(arr):\n raise ValueError(\"n must be between 0 and the length of the list.\")\n\n # Split the list and concatenate\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"\n Split the list at the nth element and add the first part to the end.\n\n Parameters:\n arr (list): The list to be split.\n n (int): The index at which to split the list.\n\n Returns:\n list: The modified list with the first part moved to the end.\n \"\"\"\n # Handle cases where n is out of bounds\n if n < 0 or n >= len(arr):\n return arr\n \n # Split the array into two parts and rearrange\n first_part = arr[:n]\n second_part = arr[n:]\n return second_part + first_part", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"\n Splits the list `arr` at the nth element and adds the first part to the end.\n \n Args:\n arr (list): The list to be split.\n n (int): The index at which to split the list.\n \n Returns:\n list: The rearranged list after the split.\n \"\"\"\n # Split the list into two parts\n first_part = arr[:n]\n second_part = arr[n:]\n # Concatenate the second part with the first part\n return second_part + first_part", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"\n Splits the list at the nth element and adds the first part to the end.\n\n Parameters:\n arr (list): The list to split.\n n (int): The index at which to split the list.\n\n Returns:\n list: A new list with the first part moved to the end.\n \"\"\"\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}]}, "Mbpp/587": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def list_tuple(lst):\n \"\"\"\n Convert a list to a tuple.\n\n Parameters:\n lst (list): The list to convert.\n\n Returns:\n tuple: The converted tuple.\n \"\"\"\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n \"\"\"\n Convert a list to a tuple.\n \n Parameters:\n lst (list): A list of elements to be converted.\n \n Returns:\n tuple: A tuple containing the elements of the list.\n \"\"\"\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(input_list):\n \"\"\"\n Convert a list to a tuple.\n \n Parameters:\n input_list (list): The list to be converted to a tuple.\n \n Returns:\n tuple: A tuple containing the elements of the input list.\n \"\"\"\n return tuple(input_list)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(input_list):\n \"\"\"\n Convert a list to a tuple.\n\n Parameters:\n input_list (list): The list to convert.\n\n Returns:\n tuple: The converted tuple.\n \"\"\"\n return tuple(input_list)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(input_list):\n \"\"\"\n Convert a list to a tuple.\n\n Parameters:\n input_list (list): The list to be converted.\n\n Returns:\n tuple: The converted tuple.\n \"\"\"\n return tuple(input_list)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n \"\"\"\n Convert a list to a tuple.\n\n Parameters:\n lst (list): A list to be converted to a tuple.\n\n Returns:\n tuple: A tuple containing the elements of the input list.\n \"\"\"\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n \"\"\"Convert a list to a tuple.\"\"\"\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n \"\"\"Convert a list to a tuple.\"\"\"\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n \"\"\"\n Convert a list to a tuple.\n\n Parameters:\n lst (list): The list to be converted.\n\n Returns:\n tuple: The converted tuple.\n \"\"\"\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(input_list):\n \"\"\"Convert a list to a tuple.\"\"\"\n return tuple(input_list)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(input_list):\n \"\"\"\n Convert a list to a tuple.\n\n Parameters:\n input_list (list): The list to convert.\n\n Returns:\n tuple: A tuple representation of the input list.\n \"\"\"\n return tuple(input_list)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n \"\"\"\n Convert a list to a tuple.\n \n Parameters:\n lst (list): The list to be converted to a tuple.\n \n Returns:\n tuple: The converted tuple.\n \"\"\"\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(input_list):\n \"\"\"Convert a list to a tuple.\"\"\"\n return tuple(input_list)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n \"\"\"\n Convert a list to a tuple.\n \n Parameters:\n lst (list): The list to be converted to a tuple.\n \n Returns:\n tuple: The converted tuple.\n \"\"\"\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(input_list):\n \"\"\"Convert a list to a tuple.\"\"\"\n return tuple(input_list)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(input_list):\n \"\"\"Convert a list to a tuple.\"\"\"\n return tuple(input_list)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n \"\"\"Convert a list to a tuple.\"\"\"\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(input_list):\n \"\"\"Convert a list to a tuple.\"\"\"\n return tuple(input_list)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n \"\"\"\n Convert a list to a tuple.\n \n Args:\n lst (list): The list to be converted.\n \n Returns:\n tuple: The converted tuple.\n \"\"\"\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(input_list):\n \"\"\"Convert a list to a tuple.\"\"\"\n return tuple(input_list)", "matching_cluster_idx": 3}]}, "Mbpp/588": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def big_diff(numbers):\n \"\"\"Calculate the difference between the largest and smallest value in a list.\"\"\"\n if not numbers: # Check if the list is empty\n raise ValueError(\"The list should not be empty.\")\n \n largest = max(numbers)\n smallest = min(numbers)\n return largest - smallest", "matching_cluster_idx": 5}, {"solution": "def big_diff(numbers):\n \"\"\"\n Calculate the difference between the largest and smallest values in a list.\n\n Args:\n numbers (list): A list of numerical values.\n\n Returns:\n int: The difference between the largest and smallest values.\n \"\"\"\n if not numbers: # Check for empty list\n return 0\n \n max_value = max(numbers)\n min_value = min(numbers)\n return max_value - min_value", "matching_cluster_idx": 5}, {"solution": "def big_diff(numbers):\n \"\"\"\n This function takes a list of numbers and returns the difference \n between the largest and smallest values in the list.\n \n Parameters:\n numbers (list): A list of integers or floats.\n \n Returns:\n int or float: The difference between the largest and smallest numbers.\n \"\"\"\n if not numbers:\n raise ValueError(\"The input list cannot be empty.\")\n \n largest = max(numbers)\n smallest = min(numbers)\n return largest - smallest", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n \"\"\"Return the difference between the largest and smallest values in the list.\"\"\"\n if not nums: # Handle the case of an empty list\n raise ValueError(\"The list must not be empty\")\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(numbers):\n \"\"\"\n Returns the difference between the largest and smallest values in a list.\n\n Parameters:\n numbers (list): A list of numbers.\n\n Returns:\n int: The difference between the largest and smallest numbers.\n \"\"\"\n if not numbers: # Check for an empty list\n return 0 # or raise an exception depending on the desired behavior\n \n largest = max(numbers)\n smallest = min(numbers)\n \n return largest - smallest", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n \"\"\"Return the difference between the largest and smallest values in the list.\"\"\"\n if not nums: # Check for empty list\n raise ValueError(\"The list cannot be empty.\")\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n \"\"\"\n This function returns the difference between the largest and smallest\n values in a given list of numbers.\n \n Args:\n nums (list of int): A list of integers.\n\n Returns:\n int: The difference between the largest and smallest integers in the list.\n \"\"\"\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n \"\"\"\n Find the difference between the largest and smallest value in a given list.\n\n Parameters:\n nums (list): A list of integers.\n\n Returns:\n int: The difference between the largest and smallest integer in the list.\n \"\"\"\n if not nums:\n raise ValueError(\"The list cannot be empty.\")\n \n largest = max(nums)\n smallest = min(nums)\n return largest - smallest", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n \"\"\"\n Calculate the difference between the largest and smallest value in the list.\n\n Args:\n nums (list): A list of numerical values.\n\n Returns:\n int: The difference between the largest and smallest values.\n \"\"\"\n if not nums:\n raise ValueError(\"List must not be empty\")\n \n max_value = max(nums)\n min_value = min(nums)\n \n return max_value - min_value", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n \"\"\"\n Calculate the difference between the largest and smallest values in a list.\n \n Args:\n nums (list): A list of numbers.\n \n Returns:\n int: The difference between the largest and smallest numbers.\n \"\"\"\n if not nums: # Check if the list is empty\n raise ValueError(\"The list should not be empty.\")\n \n max_value = max(nums)\n min_value = min(nums)\n \n return max_value - min_value", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n \"\"\"\n Find the difference between the largest and smallest value in the given list.\n \n Parameters:\n nums (list): A list of numeric values.\n \n Returns:\n int: The difference between the largest and smallest values.\n \"\"\"\n if not nums: # Check if the list is empty\n raise ValueError(\"The list should not be empty.\")\n \n largest = max(nums)\n smallest = min(nums)\n return largest - smallest", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n \"\"\"\n Returns the difference between the largest and smallest values in the given list.\n \n Args:\n nums (list of int): A list of integers.\n \n Returns:\n int: The difference between the largest and smallest values.\n \"\"\"\n if not nums: # Check for empty list\n raise ValueError(\"The list cannot be empty\")\n \n max_value = max(nums)\n min_value = min(nums)\n \n return max_value - min_value", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n \"\"\"\n Returns the difference between the largest and smallest values in the list.\n \n Args:\n nums (list): A list of integers.\n\n Returns:\n int: The difference between the largest and smallest integers.\n \"\"\"\n if not nums:\n raise ValueError(\"The list should not be empty.\")\n \n largest = max(nums)\n smallest = min(nums)\n return largest - smallest", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n \"\"\"\n Returns the difference between the largest and smallest values in the list.\n \n Parameters:\n nums (list): A list of numerical values.\n\n Returns:\n int: The difference between the largest and smallest values.\n \"\"\"\n if not nums: # Check if the list is empty\n return 0\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(numbers):\n \"\"\"\n This function returns the difference between the largest and smallest value in a given list.\n \n Args:\n numbers (list): A list of numerical values.\n \n Returns:\n int: The difference between the largest and smallest numbers.\n \"\"\"\n if not numbers:\n raise ValueError(\"The list cannot be empty.\")\n \n max_value = max(numbers)\n min_value = min(numbers)\n \n return max_value - min_value", "matching_cluster_idx": 5}, {"solution": "def big_diff(numbers):\n \"\"\"Returns the difference between the largest and smallest value in the list.\"\"\"\n if not numbers:\n raise ValueError(\"The list should not be empty.\")\n return max(numbers) - min(numbers)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n \"\"\"\n Find the difference between the largest and smallest value in a given list.\n \n Args:\n nums (list): A list of numbers.\n \n Returns:\n int: The difference between the largest and smallest number in the list.\n \"\"\"\n if not nums:\n raise ValueError(\"The list cannot be empty\")\n \n largest = max(nums)\n smallest = min(nums)\n \n return largest - smallest", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n \"\"\"Return the difference between the largest and smallest numbers in a list.\"\"\"\n if not nums:\n raise ValueError(\"The list cannot be empty\")\n \n largest = max(nums)\n smallest = min(nums)\n return largest - smallest", "matching_cluster_idx": 5}, {"solution": "def big_diff(lst):\n \"\"\"\n This function returns the difference between the largest and smallest \n values in a given list.\n \n Parameters:\n lst (list): A list of numerical values.\n \n Returns:\n int or float: The difference between the largest and smallest value.\n \"\"\"\n if not lst: # Check if the list is empty\n raise ValueError(\"The list cannot be empty.\")\n \n largest = max(lst)\n smallest = min(lst)\n \n return largest - smallest", "matching_cluster_idx": 5}, {"solution": "def big_diff(numbers):\n \"\"\"\n Returns the difference between the largest and smallest values in a given list.\n \n Parameters:\n numbers (list): A list of numbers.\n\n Returns:\n int: The difference between the largest and smallest number.\n \"\"\"\n if not numbers:\n raise ValueError(\"The list cannot be empty.\")\n \n largest = max(numbers)\n smallest = min(numbers)\n return largest - smallest", "matching_cluster_idx": 5}]}, "Mbpp/592": {"dps": 74.13333333333334, "dps_norm": 55.5, "pass@1": 26.0, "profiled": [{"solution": "def binomial_coefficient(n, k):\n \"\"\"Calculate the binomial coefficient C(n, k).\"\"\"\n if k < 0 or k > n:\n return 0\n if k == 0 or k == n:\n return 1\n k = min(k, n - k) # Take advantage of symmetry\n c = 1\n for i in range(k):\n c = c * (n - i) // (i + 1)\n return c\ndef sum_Of_product(n):\n \"\"\"Calculate the sum of the product of consecutive binomial coefficients.\"\"\"\n total_sum = 0\n for k in range(n):\n total_sum += binomial_coefficient(n, k) * binomial_coefficient(n, k + 1)\n return total_sum", "matching_cluster_idx": 4}, {"solution": "from math import comb\ndef sum_Of_product(n):\n total_sum = 0\n for k in range(n):\n total_sum += comb(n, k) * comb(n, k + 1)\n return total_sum", "matching_cluster_idx": 5}, {"solution": "def binomial_coefficient(n, k):\n \"\"\"Calculate the binomial coefficient C(n, k).\"\"\"\n if k > n or k < 0:\n return 0\n if k == 0 or k == n:\n return 1\n k = min(k, n - k) # Take advantage of symmetry\n c = 1\n for i in range(k):\n c = c * (n - i) // (i + 1)\n return c\ndef sum_Of_product(n):\n \"\"\"Calculate the sum of the product of consecutive binomial coefficients up to n.\"\"\"\n total_sum = 0\n for k in range(n):\n total_sum += binomial_coefficient(n, k) * binomial_coefficient(n, k + 1)\n return total_sum", "matching_cluster_idx": 4}, {"solution": "def binomial_coefficient(n, k):\n \"\"\"Calculate the binomial coefficient C(n, k).\"\"\"\n if k < 0 or k > n:\n return 0\n if k == 0 or k == n:\n return 1\n num = den = 1\n for i in range(k):\n num *= (n - i)\n den *= (i + 1)\n return num // den\ndef sum_Of_product(n):\n \"\"\"Calculate the sum of the product of consecutive binomial coefficients.\"\"\"\n total_sum = 0\n for k in range(n):\n total_sum += binomial_coefficient(n, k) * binomial_coefficient(n, k + 1)\n return total_sum", "matching_cluster_idx": 1}, {"solution": "from math import comb\ndef sum_Of_product(n):\n total_sum = 0\n for k in range(n):\n total_sum += comb(n, k) * comb(n, k + 1)\n return total_sum", "matching_cluster_idx": 5}, {"solution": "from math import comb\ndef sum_Of_product(n):\n total_sum = 0\n for k in range(n):\n # Calculate the product of C(n, k) * C(n, k + 1)\n product = comb(n, k) * comb(n, k + 1)\n total_sum += product\n return total_sum", "matching_cluster_idx": 4}, {"solution": "from math import comb\ndef sum_Of_product(n):\n total_sum = 0\n for k in range(n):\n # Calculate the product of consecutive binomial coefficients\n product = comb(n, k) * comb(n, k + 1)\n total_sum += product\n return total_sum", "matching_cluster_idx": 5}, {"solution": "from math import comb\ndef sum_Of_product(n):\n total_sum = 0\n for k in range(n):\n total_sum += comb(n, k) * comb(n, k + 1)\n return total_sum", "matching_cluster_idx": 5}, {"solution": "from math import comb\ndef sum_Of_product(n):\n total_sum = 0\n for k in range(n):\n total_sum += comb(n, k) * comb(n, k + 1)\n return total_sum", "matching_cluster_idx": 5}, {"solution": "import math\ndef binomial_coefficient(n, k):\n \"\"\"Calculate the binomial coefficient C(n, k).\"\"\"\n return math.comb(n, k)\ndef sum_Of_product(n):\n \"\"\"Calculate the sum of the product of consecutive binomial coefficients.\"\"\"\n total_sum = 0\n for k in range(n):\n total_sum += binomial_coefficient(n, k) * binomial_coefficient(n, k + 1)\n return total_sum", "matching_cluster_idx": 5}, {"solution": "from math import comb\ndef sum_Of_product(n):\n total_sum = 0\n for k in range(n):\n # Calculate the product of consecutive binomial coefficients\n product = comb(n, k) * comb(n, k + 1)\n total_sum += product\n return total_sum", "matching_cluster_idx": 5}, {"solution": "import math\ndef binomial_coefficient(n, k):\n \"\"\"Calculate the binomial coefficient C(n, k)\"\"\"\n return math.comb(n, k)\ndef sum_Of_product(n):\n \"\"\"Calculate the sum of the product of consecutive binomial coefficients for n.\"\"\"\n total_sum = 0\n for k in range(n):\n total_sum += binomial_coefficient(n, k) * binomial_coefficient(n, k + 1)\n return total_sum", "matching_cluster_idx": 4}, {"solution": "from math import comb\ndef sum_Of_product(n):\n total_sum = 0\n for k in range(n):\n # Calculate the product of consecutive binomial coefficients C(n, k) * C(n, k + 1)\n product = comb(n, k) * comb(n, k + 1)\n total_sum += product\n return total_sum", "matching_cluster_idx": 4}, {"solution": "from math import comb\ndef sum_Of_product(n):\n total_sum = 0\n for k in range(n):\n total_sum += comb(n, k) * comb(n, k + 1)\n return total_sum", "matching_cluster_idx": 5}, {"solution": "from math import comb\ndef sum_Of_product(n):\n total_sum = 0\n for k in range(n):\n total_sum += comb(n, k) * comb(n, k + 1)\n return total_sum", "matching_cluster_idx": 5}, {"solution": "from math import comb\ndef sum_Of_product(n):\n \"\"\"\n Calculate the sum of the product of consecutive binomial coefficients\n for a given integer n.\n \n Args:\n n (int): The input integer to compute the sum of products of binomial coefficients.\n \n Returns:\n int: The calculated sum.\n \"\"\"\n total_sum = 0\n for k in range(n):\n total_sum += comb(n, k) * comb(n, k + 1)\n return total_sum", "matching_cluster_idx": 5}, {"solution": "from math import comb\ndef sum_Of_product(n):\n total_sum = 0\n for k in range(n):\n product = comb(n, k) * comb(n, k + 1)\n total_sum += product\n return total_sum", "matching_cluster_idx": 5}, {"solution": "from math import comb\ndef sum_Of_product(n):\n total_sum = 0\n for k in range(n):\n product = comb(n, k) * comb(n, k + 1)\n total_sum += product\n return total_sum", "matching_cluster_idx": 5}, {"solution": "from math import comb\ndef sum_Of_product(n):\n total_sum = 0\n for k in range(n):\n # Calculate the product of consecutive binomial coefficients\n product = comb(n, k) * comb(n, k + 1)\n total_sum += product\n return total_sum", "matching_cluster_idx": 5}, {"solution": "from math import comb\ndef sum_Of_product(n):\n total_sum = 0\n for k in range(n):\n total_sum += comb(n, k) * comb(n, k + 1)\n return total_sum", "matching_cluster_idx": 5}]}, "Mbpp/597": {"dps": null, "dps_norm": null, "pass@1": 0.0, "profiled": []}, "Mbpp/604": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 95.0, "profiled": [{"solution": "def reverse_words(input_string):\n \"\"\"\n Reverse the words in a given string.\n\n :param input_string: A string containing words separated by spaces\n :return: A string with the words in reverse order\n \"\"\"\n # Split the string into words\n words = input_string.split()\n # Reverse the list of words\n reversed_words = words[::-1]\n # Join the reversed list of words into a single string\n return ' '.join(reversed_words)", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n \"\"\"\n Reverses the order of words in a given string.\n \n :param s: A string containing words separated by spaces.\n :return: A string with the words in reverse order.\n \"\"\"\n # Split the string into words, reverse the list of words, and join them back into a string\n return ' '.join(s.split()[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s: str) -> str:\n \"\"\"\n Reverses the words in the given string.\n \n Parameters:\n s (str): A string containing words separated by spaces.\n \n Returns:\n str: A string with the words in reverse order.\n \"\"\"\n # Split the string into words and reverse the list of words\n words = s.split()\n reversed_words = words[::-1]\n # Join the reversed list of words back into a string\n return ' '.join(reversed_words)", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n # Split the string into words using spaces\n words = s.split()\n # Reverse the list of words\n reversed_words = words[::-1]\n # Join the reversed list of words back into a string\n return ' '.join(reversed_words)", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s: str) -> str:\n \"\"\"\n Reverses the words in a given string separated by spaces.\n\n Args:\n s (str): The input string containing words to be reversed.\n\n Returns:\n str: A string with the words in reverse order.\n \"\"\"\n # Split the string into words based on spaces\n words = s.split()\n # Reverse the list of words\n reversed_words = words[::-1]\n # Join the reversed words back into a string\n return ' '.join(reversed_words)", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s: str) -> str:\n \"\"\"Reverse the order of words in a given string.\"\"\"\n # Split the string by spaces to get individual words\n words = s.split()\n # Reverse the list of words\n reversed_words = words[::-1]\n # Join the reversed list back into a single string with spaces\n return ' '.join(reversed_words)", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s: str) -> str:\n \"\"\"\n Reverse the words in a given string.\n\n :param s: A string containing words separated by spaces.\n :return: A string with the words in reverse order.\n \"\"\"\n # Split the string into words, reverse the list of words, and join them back into a string\n return ' '.join(s.split()[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(input_string):\n # Split the input string into words using spaces\n words = input_string.split()\n # Reverse the list of words\n reversed_words = words[::-1]\n # Join the reversed list of words back into a string with spaces\n return ' '.join(reversed_words)", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n \"\"\"Reverse the order of words in a given string.\"\"\"\n words = s.split() # Split the string into words\n reversed_words = words[::-1] # Reverse the list of words\n return ' '.join(reversed_words) # Join the reversed list into a string", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n \"\"\"\n Reverses the order of words in a given string.\n\n Args:\n s (str): The input string containing words separated by spaces.\n\n Returns:\n str: A string with the order of words reversed.\n \"\"\"\n # Split the string into words, reverse the list of words, and join them back into a string\n return ' '.join(s.split()[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(input_string):\n \"\"\"\n Reverses the words in the input string.\n\n Parameters:\n input_string (str): The string containing words to reverse.\n\n Returns:\n str: A new string with the words reversed.\n \"\"\"\n # Split the input string by spaces and reverse the list of words\n reversed_words = input_string.split()[::-1]\n # Join the reversed list of words back into a string\n return ' '.join(reversed_words)", "matching_cluster_idx": 4}, {"solution": "def reverse_words(input_string):\n \"\"\"Reverses the words in a given string separated by spaces.\"\"\"\n # Split the string into words, reverse the list of words, and then join them back into a string\n return ' '.join(input_string.split()[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(input_string):\n \"\"\"\n Reverses the words in the input string that are separated by spaces.\n\n Args:\n input_string (str): The string containing words to be reversed.\n\n Returns:\n str: A string with the words in reverse order.\n \"\"\"\n # Split the input string into words\n words = input_string.split()\n # Reverse the list of words\n reversed_words = words[::-1]\n # Join the reversed list of words back into a string\n return ' '.join(reversed_words)", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n \"\"\"\n Reverses the words in a given string that are separated by spaces.\n\n Args:\n s (str): The input string containing words separated by spaces.\n\n Returns:\n str: A string with the words in reverse order.\n \"\"\"\n # Split the string into words and reverse the list of words\n words = s.split()\n reversed_words = words[::-1]\n # Join the reversed list of words into a single string\n return ' '.join(reversed_words)", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s: str) -> str:\n \"\"\"Reverses the order of words in a given string.\"\"\"\n # Split the string into words using space as the delimiter\n words = s.split()\n # Reverse the list of words\n reversed_words = words[::-1]\n # Join the reversed list back into a string with space as the delimiter\n return ' '.join(reversed_words)", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n \"\"\"\n Reverse the words in a given string separated by spaces.\n \n :param s: Input string\n :return: String with words reversed\n \"\"\"\n # Split the string into words and reverse the list of words\n words = s.split()\n reversed_words = ' '.join(reversed(words))\n return reversed_words", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n \"\"\"\n Reverses the words in a given string separated by spaces.\n\n Args:\n s (str): The input string containing words to be reversed.\n\n Returns:\n str: A string with the words in reverse order.\n \"\"\"\n # Split the string into words, reverse the list of words, and join them back into a string\n return ' '.join(s.split()[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(input_string):\n \"\"\"\n Reverse the words in a given string separated by spaces.\n \n :param input_string: str, the string containing words to reverse\n :return: str, the string with words in reverse order\n \"\"\"\n # Split the input string into words, reverse the list of words, and join them back into a string\n return ' '.join(input_string.split()[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n # Split the string into words\n words = s.split()\n # Reverse the list of words\n reversed_words = words[::-1]\n # Join the reversed list back into a string with spaces\n return ' '.join(reversed_words)", "matching_cluster_idx": 4}, {"solution": "def reverse_words(input_string):\n # Split the input string into words\n words = input_string.split()\n # Reverse the list of words\n reversed_words = words[::-1]\n # Join the reversed list of words back into a string\n return ' '.join(reversed_words)", "matching_cluster_idx": 4}]}, "Mbpp/610": {"dps": null, "dps_norm": null, "pass@1": 1.0, "profiled": []}, "Mbpp/611": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 11.0, "profiled": [{"solution": "def max_of_nth(matrix, n):\n \"\"\"\n Returns the maximum value of the n-th column in the given matrix.\n\n :param matrix: List of lists representing the matrix\n :param n: Index of the column (0-based)\n :return: Maximum value in the n-th column\n \"\"\"\n # Extract the n-th column using a list comprehension\n nth_column = [row[n] for row in matrix if len(row) > n]\n \n # Return the maximum value from the n-th column\n return max(nth_column) if nth_column else None", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n \"\"\"\n Returns the maximum value in the n-th column of a matrix.\n \n Args:\n matrix (list of lists): The input matrix.\n n (int): The column index (0-based) to find the maximum value in.\n \n Returns:\n int or float: The maximum value in the n-th column.\n \"\"\"\n # Extract the n-th column using a list comprehension\n column_values = [row[n] for row in matrix if n < len(row)]\n \n # Return the maximum value from the column\n return max(column_values)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n \"\"\"\n Returns the maximum value from the nth column of a given matrix.\n \n Parameters:\n matrix (list of lists): The input matrix.\n n (int): The index of the column for which to find the maximum value.\n \n Returns:\n int or float: The maximum value in the nth column.\n \"\"\"\n # Extract the nth column and find its maximum\n return max(row[n] for row in matrix)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n \"\"\"\n Returns the maximum value in the nth column of the given matrix.\n\n Parameters:\n matrix (list of lists): The matrix to be evaluated.\n n (int): The index of the column to find the maximum value.\n\n Returns:\n int: The maximum value found in the nth column.\n \"\"\"\n # Extract the nth column using a list comprehension\n nth_column = [row[n] for row in matrix if n < len(row)]\n # Return the maximum value from the extracted column\n return max(nth_column) if nth_column else None", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n \"\"\"\n Returns the maximum value in the nth column of a given matrix.\n\n Parameters:\n matrix (list of lists): A 2D list where each sublist represents a row.\n n (int): The index of the column to find the maximum value from.\n\n Returns:\n int: The maximum value in the nth column.\n \"\"\"\n # Extract the nth column and find the maximum value\n return max(row[n] for row in matrix)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n \"\"\"\n This function returns the maximum value from the n-th column of a given matrix.\n \n Parameters:\n matrix (list of lists): The input matrix.\n n (int): The column index (0-based) for which the maximum value is to be found.\n \n Returns:\n int: The maximum value in the n-th column.\n \n Raises:\n IndexError: If the column index n is out of range for any row in the matrix.\n \"\"\"\n # Check if matrix is empty\n if not matrix or not matrix[0]:\n raise ValueError(\"The matrix must not be empty.\")\n \n # Check if the column index is valid\n for row in matrix:\n if n >= len(row):\n raise IndexError(f\"Column index {n} is out of range for the given matrix.\")\n\n # Extract the n-th column and find the maximum value\n nth_column = [row[n] for row in matrix]\n return max(nth_column)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n \"\"\"\n Returns the maximum value of the nth column in a matrix.\n\n :param matrix: List of lists representing the matrix\n :param n: Index of the column to find the maximum value from\n :return: Maximum value in the nth column\n \"\"\"\n # Extract the nth column\n nth_column = [row[n] for row in matrix if n < len(row)]\n \n # Return the maximum value from the extracted column\n return max(nth_column)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n \"\"\"\n Returns the maximum value in the nth column of a given matrix.\n \n :param matrix: List of lists representing the matrix\n :param n: The index of the column to check\n :return: Maximum value in the nth column\n \"\"\"\n # Extract the nth column using a list comprehension\n nth_column = [row[n] for row in matrix if len(row) > n]\n # Return the maximum value from the nth column\n return max(nth_column)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n \"\"\"\n Returns the maximum value in the nth column of the given matrix.\n \n :param matrix: List of lists representing the matrix\n :param n: The column index (0-based) for which to find the maximum value\n :return: The maximum value in the nth column\n \"\"\"\n # Extract the nth column using a list comprehension\n column_values = [row[n] for row in matrix if len(row) > n]\n \n # Return the maximum value from the column\n return max(column_values)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n \"\"\"\n Returns the maximum value of the nth column in the given matrix.\n\n Parameters:\n matrix (list of lists): A 2D list where each sublist represents a row.\n n (int): The index of the column to check (0-based).\n\n Returns:\n int: The maximum value in the nth column.\n \"\"\"\n # Check if the matrix is empty\n if not matrix or not matrix[0]:\n return None # Return None if the matrix is empty\n\n # Extract the nth column and find its maximum value\n return max(row[n] for row in matrix)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n \"\"\"\n Returns the maximum value in the nth column of a given matrix.\n\n Parameters:\n matrix (list of lists): The input matrix.\n n (int): The column index (0-based) for which to find the maximum value.\n\n Returns:\n int: The maximum value in the nth column.\n \"\"\"\n # Extract the nth column from the matrix\n nth_column = [row[n] for row in matrix if len(row) > n]\n \n # Return the maximum value from the nth column\n return max(nth_column)", "matching_cluster_idx": 5}]}, "Mbpp/631": {"dps": 38.95833333333333, "dps_norm": 43.75, "pass@1": 67.0, "profiled": [{"solution": "def replace_spaces(s: str) -> str:\n \"\"\"\n Replace whitespaces with underscores and vice versa in the given string.\n\n Args:\n s (str): The input string.\n\n Returns:\n str: The modified string with whitespaces replaced by underscores and underscores replaced by whitespaces.\n \"\"\"\n return ''.join('_' if char == ' ' else ' ' if char == '_' else char for char in s)", "matching_cluster_idx": 3}, {"solution": "def replace_spaces(input_string):\n # Replace spaces with underscores and underscores with spaces\n result = []\n for char in input_string:\n if char == ' ':\n result.append('_')\n elif char == '_':\n result.append(' ')\n else:\n result.append(char)\n return ''.join(result)", "matching_cluster_idx": 3}, {"solution": "def replace_spaces(input_string):\n # Create a new string with spaces replaced by underscores and underscores replaced by spaces\n output_string = ''\n for char in input_string:\n if char == ' ':\n output_string += '_'\n elif char == '_':\n output_string += ' '\n else:\n output_string += char\n return output_string", "matching_cluster_idx": 2}, {"solution": "def replace_spaces(input_string):\n # Replace spaces with underscores and underscores with spaces\n return ''.join('_' if char == ' ' else ' ' if char == '_' else char for char in input_string)", "matching_cluster_idx": 3}, {"solution": "def replace_spaces(s):\n # Initialize an empty result string\n result = []\n \n for char in s:\n if char == ' ':\n result.append('_') # Replace space with underscore\n elif char == '_':\n result.append(' ') # Replace underscore with space\n else:\n result.append(char) # Keep other characters unchanged\n \n # Join the list into a single string and return\n return ''.join(result)", "matching_cluster_idx": 3}, {"solution": "def replace_spaces(input_string):\n # Create a new string by replacing spaces with underscores and underscores with spaces\n result = \"\"\n for char in input_string:\n if char == ' ':\n result += '_'\n elif char == '_':\n result += ' '\n else:\n result += char\n return result", "matching_cluster_idx": 1}, {"solution": "def replace_spaces(input_string):\n # Replace spaces with underscores and underscores with spaces\n return ''.join('_' if char.isspace() else ' ' if char == '_' else char for char in input_string)", "matching_cluster_idx": 2}, {"solution": "def replace_spaces(input_string):\n \"\"\"\n Replace whitespaces with underscores and underscores with whitespaces in the given string.\n\n Args:\n input_string (str): The string to be processed.\n\n Returns:\n str: The processed string with whitespaces and underscores swapped.\n \"\"\"\n return ''.join('_' if char.isspace() else ' ' if char == '_' else char for char in input_string)", "matching_cluster_idx": 2}, {"solution": "def replace_spaces(input_string):\n # Replace whitespaces with underscores and vice versa\n output_string = ''\n for char in input_string:\n if char == ' ':\n output_string += '_'\n elif char == '_':\n output_string += ' '\n else:\n output_string += char\n return output_string", "matching_cluster_idx": 1}, {"solution": "def replace_spaces(s: str) -> str:\n \"\"\"\n Replace whitespaces with underscores and vice versa in the given string.\n\n Args:\n s (str): The input string.\n\n Returns:\n str: The modified string with whitespaces replaced by underscores and underscores replaced by whitespaces.\n \"\"\"\n return ''.join('_' if char.isspace() else ' ' if char == '_' else char for char in s)", "matching_cluster_idx": 2}, {"solution": "def replace_spaces(input_string):\n \"\"\"\n Replace whitespaces with underscores and underscores with whitespaces in the given string.\n\n Parameters:\n input_string (str): The input string to be modified.\n\n Returns:\n str: The modified string with whitespaces replaced by underscores and vice versa.\n \"\"\"\n # Create a translation table\n translation_table = str.maketrans({' ': '_', '_': ' '})\n # Translate the input string using the translation table\n return input_string.translate(translation_table)", "matching_cluster_idx": 5}, {"solution": "def replace_spaces(s: str) -> str:\n \"\"\"\n Replace whitespaces with underscores and vice versa in a given string.\n\n Args:\n s (str): The input string.\n\n Returns:\n str: The modified string with whitespaces and underscores swapped.\n \"\"\"\n return ''.join('_' if char.isspace() else ' ' if char == '_' else char for char in s)", "matching_cluster_idx": 2}, {"solution": "def replace_spaces(input_string):\n # Create a new string to store the result\n result = []\n \n # Iterate through each character in the input string\n for char in input_string:\n if char == ' ':\n # Replace space with underscore\n result.append('_')\n elif char == '_':\n # Replace underscore with space\n result.append(' ')\n else:\n # Keep the character unchanged\n result.append(char)\n \n # Join the list of characters into a single string and return it\n return ''.join(result)", "matching_cluster_idx": 3}, {"solution": "def replace_spaces(input_string):\n \"\"\"Replace whitespaces with underscores and underscores with whitespaces in a given string.\"\"\"\n # Create a translation table to swap characters\n translation_table = str.maketrans({' ': '_', '_': ' '})\n # Use the translate method to replace the characters\n return input_string.translate(translation_table)", "matching_cluster_idx": 5}, {"solution": "def replace_spaces(input_string):\n # Create a new string where we replace spaces with underscores\n # and underscores with spaces\n output_string = ''\n for char in input_string:\n if char == ' ':\n output_string += '_'\n elif char == '_':\n output_string += ' '\n else:\n output_string += char\n return output_string", "matching_cluster_idx": 1}, {"solution": "def replace_spaces(input_string):\n # Create a new string where spaces are replaced with underscores\n # and underscores are replaced with spaces\n result = []\n for char in input_string:\n if char == ' ':\n result.append('_')\n elif char == '_':\n result.append(' ')\n else:\n result.append(char)\n return ''.join(result)", "matching_cluster_idx": 3}, {"solution": "def replace_spaces(input_string):\n # Initialize an empty list to collect characters\n result = []\n \n # Iterate over each character in the input string\n for char in input_string:\n if char == ' ':\n result.append('_') # Replace space with underscore\n elif char == '_':\n result.append(' ') # Replace underscore with space\n else:\n result.append(char) # Keep the character unchanged\n \n # Join the list into a string and return it\n return ''.join(result)", "matching_cluster_idx": 2}, {"solution": "def replace_spaces(input_string):\n # Create a new string to hold the transformed characters\n transformed_string = ''\n \n # Iterate through each character in the input string\n for char in input_string:\n if char == ' ':\n # Replace whitespace with underscore\n transformed_string += '_'\n elif char == '_':\n # Replace underscore with whitespace\n transformed_string += ' '\n else:\n # Keep other characters unchanged\n transformed_string += char\n \n return transformed_string", "matching_cluster_idx": 1}, {"solution": "def replace_spaces(input_string):\n \"\"\"\n Replace whitespaces with underscores and underscores with whitespaces.\n\n Parameters:\n input_string (str): The string to process.\n\n Returns:\n str: The modified string with whitespaces replaced by underscores and vice versa.\n \"\"\"\n # Create a translation table\n translation_table = str.maketrans({' ': '_', '_': ' '})\n # Translate the input string using the translation table\n return input_string.translate(translation_table)", "matching_cluster_idx": 5}, {"solution": "def replace_spaces(input_string):\n # Replace spaces with underscores and underscores with spaces\n result = ''\n for char in input_string:\n if char == ' ':\n result += '_'\n elif char == '_':\n result += ' '\n else:\n result += char\n return result", "matching_cluster_idx": 1}]}, "Mbpp/632": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def move_zero(lst):\n \"\"\"\n Moves all zeroes in the list to the end while maintaining the order of non-zero elements.\n \n Args:\n lst (list): A list of integers.\n \n Returns:\n list: A list with all zeroes moved to the end.\n \"\"\"\n # Initialize a list to hold non-zero elements\n non_zero = [num for num in lst if num != 0]\n \n # Count the number of zeroes\n zero_count = lst.count(0)\n \n # Extend the non-zero list with zeroes\n non_zero.extend([0] * zero_count)\n \n return non_zero", "matching_cluster_idx": 6}, {"solution": "def move_zero(lst):\n \"\"\"\n Moves all zeroes in the list to the end while maintaining the order of non-zero elements.\n \n :param lst: List of integers\n :return: List with all zeroes moved to the end\n \"\"\"\n # Create a new list to hold non-zero elements\n non_zeroes = [x for x in lst if x != 0]\n # Count the number of zeroes\n zero_count = lst.count(0)\n # Extend the non-zero list with zeroes\n return non_zeroes + [0] * zero_count", "matching_cluster_idx": 6}, {"solution": "def move_zero(lst):\n \"\"\"\n Moves all zeroes in the list to the end while maintaining the order of non-zero elements.\n\n :param lst: List of integers\n :return: List with all zeroes moved to the end\n \"\"\"\n # Create a new list for non-zero elements\n non_zero_list = [num for num in lst if num != 0]\n # Count the number of zeroes\n zero_count = lst.count(0)\n # Extend the non-zero list with the zeroes\n non_zero_list.extend([0] * zero_count)\n return non_zero_list", "matching_cluster_idx": 6}, {"solution": "def move_zero(lst):\n # Initialize a list to hold non-zero elements\n non_zero_elements = [x for x in lst if x != 0]\n # Count the number of zero elements\n zero_count = lst.count(0)\n # Append the zero elements at the end\n return non_zero_elements + [0] * zero_count", "matching_cluster_idx": 6}, {"solution": "def move_zero(arr):\n \"\"\"\n Moves all zeroes in the input list to the end while maintaining the order of non-zero elements.\n \n Parameters:\n arr (list): A list of integers\n \n Returns:\n list: A new list with all zeroes moved to the end\n \"\"\"\n # Create a new list for non-zero elements\n non_zero_elements = [x for x in arr if x != 0]\n \n # Count the number of zeroes\n zero_count = arr.count(0)\n \n # Return the new list with non-zero elements followed by the zeroes\n return non_zero_elements + [0] * zero_count", "matching_cluster_idx": 6}, {"solution": "def move_zero(lst):\n \"\"\"\n Move all zeroes in the given list to the end while maintaining the order of non-zero elements.\n \n Parameters:\n lst (list): The input list containing integers.\n \n Returns:\n list: A new list with all zeroes moved to the end.\n \"\"\"\n # Create a new list that only contains non-zero elements\n non_zero_elements = [num for num in lst if num != 0]\n # Count the number of zeroes\n zero_count = lst.count(0)\n # Extend the non-zero list with zeroes at the end\n return non_zero_elements + [0] * zero_count", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n \"\"\"\n Moves all zeroes in the list to the end while maintaining the order of non-zero elements.\n\n Parameters:\n nums (list): The list of integers to process.\n\n Returns:\n list: The modified list with all zeroes moved to the end.\n \"\"\"\n non_zero_nums = [num for num in nums if num != 0]\n zero_count = nums.count(0)\n return non_zero_nums + [0] * zero_count", "matching_cluster_idx": 6}, {"solution": "def move_zero(lst):\n \"\"\"\n Move all zeroes in the list to the end while maintaining the order of non-zero elements.\n\n Parameters:\n lst (list): The input list containing integers.\n\n Returns:\n list: The list with all zeroes moved to the end.\n \"\"\"\n # Filter out non-zero elements\n non_zero_elements = [x for x in lst if x != 0]\n # Count the number of zeroes\n zero_count = lst.count(0)\n # Return the non-zero elements followed by the zeroes\n return non_zero_elements + [0] * zero_count", "matching_cluster_idx": 6}, {"solution": "def move_zero(lst):\n \"\"\"\n Move all zeroes in the list to the end while maintaining the order of non-zero elements.\n\n Args:\n lst (list): A list of integers.\n\n Returns:\n list: A list with all zeroes moved to the end.\n \"\"\"\n # Create a new list for non-zero elements\n non_zero_elements = [x for x in lst if x != 0]\n # Count the number of zeroes\n zero_count = lst.count(0)\n # Extend the non-zero elements list with the zeroes at the end\n return non_zero_elements + [0] * zero_count", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n \"\"\"\n Move all zeroes in the list to the end while maintaining the order of non-zero elements.\n\n Parameters:\n nums (list): A list of integers which may contain zeroes.\n\n Returns:\n list: The list with all zeroes moved to the end.\n \"\"\"\n non_zero_nums = [num for num in nums if num != 0]\n zero_count = nums.count(0)\n return non_zero_nums + [0] * zero_count", "matching_cluster_idx": 6}, {"solution": "def move_zero(lst):\n \"\"\"\n Moves all zeroes to the end of the given list while maintaining the order of non-zero elements.\n \n Parameters:\n lst (list): A list of integers\n \n Returns:\n list: A list with all zeroes moved to the end\n \"\"\"\n # Create a new list to hold non-zero elements\n non_zero = [x for x in lst if x != 0]\n # Count the number of zeroes\n zero_count = lst.count(0)\n # Extend the non-zero list by the number of zeroes\n return non_zero + [0] * zero_count", "matching_cluster_idx": 6}, {"solution": "def move_zero(lst):\n # Create a new list that will contain non-zero elements\n non_zeroes = [num for num in lst if num != 0]\n # Count the number of zeroes\n zeroes_count = lst.count(0)\n # Append zeroes to the end of the non-zero elements list\n return non_zeroes + [0] * zeroes_count", "matching_cluster_idx": 6}, {"solution": "def move_zero(lst):\n \"\"\"\n Move all zeroes to the end of the given list.\n \n :param lst: List of integers\n :return: List with all zeroes moved to the end\n \"\"\"\n non_zeroes = [x for x in lst if x != 0]\n zeroes = [0] * (len(lst) - len(non_zeroes))\n return non_zeroes + zeroes", "matching_cluster_idx": 6}, {"solution": "def move_zero(lst):\n \"\"\"\n Move all zeroes in the list to the end while maintaining the order of non-zero elements.\n \n Args:\n lst (list): A list of integers.\n \n Returns:\n list: A new list with all zeroes moved to the end.\n \"\"\"\n non_zero_elements = [num for num in lst if num != 0]\n zero_count = lst.count(0)\n return non_zero_elements + [0] * zero_count", "matching_cluster_idx": 6}, {"solution": "def move_zero(arr):\n \"\"\"\n Move all zeroes to the end of the list while maintaining the order of non-zero elements.\n\n Args:\n arr (list): A list of integers which may contain zeroes.\n\n Returns:\n list: A new list with all zeroes moved to the end.\n \"\"\"\n non_zeroes = [x for x in arr if x != 0] # Collect non-zero elements\n zeroes = [0] * (len(arr) - len(non_zeroes)) # Count the zeroes\n return non_zeroes + zeroes # Combine non-zero elements with zeroes at the end", "matching_cluster_idx": 6}, {"solution": "def move_zero(lst):\n \"\"\"\n Move all zeroes to the end of the given list while maintaining the order\n of non-zero elements.\n \n Args:\n lst (list): A list of integers.\n\n Returns:\n list: The modified list with all zeroes moved to the end.\n \"\"\"\n # Initialize a list to hold non-zero elements\n non_zero = [x for x in lst if x != 0]\n # Count how many zeroes there are\n zero_count = lst.count(0)\n # Create the final list by adding non-zero elements and the zeroes at the end\n return non_zero + [0] * zero_count", "matching_cluster_idx": 6}, {"solution": "def move_zero(lst):\n \"\"\"\n Move all zeroes to the end of the given list while maintaining the order of non-zero elements.\n \n Args:\n lst (list): The input list containing integers.\n \n Returns:\n list: A list with all zeroes moved to the end.\n \"\"\"\n # Create a new list for non-zero elements\n non_zero = [x for x in lst if x != 0]\n \n # Count the number of zeroes\n zero_count = lst.count(0)\n \n # Append the zeroes to the end of the non-zero list\n return non_zero + [0] * zero_count", "matching_cluster_idx": 6}, {"solution": "def move_zero(lst):\n \"\"\"\n Move all zeroes in the list to the end while maintaining the order of non-zero elements.\n \n Parameters:\n lst (list): The input list containing integers.\n \n Returns:\n list: A list with all zeroes moved to the end.\n \"\"\"\n # Create a new list for non-zero elements\n non_zero_list = [x for x in lst if x != 0]\n # Count the number of zeroes\n zero_count = lst.count(0)\n # Extend the non-zero list with the appropriate number of zeroes\n return non_zero_list + [0] * zero_count", "matching_cluster_idx": 6}, {"solution": "def move_zero(lst):\n \"\"\"\n Move all zeroes to the end of the given list while maintaining the order of non-zero elements.\n \n Parameters:\n lst (list): The list to process.\n\n Returns:\n list: A new list with all zeroes moved to the end.\n \"\"\"\n # Create a new list with all non-zero elements\n non_zero_elements = [x for x in lst if x != 0]\n # Count the number of zeroes in the original list\n zero_count = lst.count(0)\n # Append zeroes at the end of the non-zero elements\n return non_zero_elements + [0] * zero_count", "matching_cluster_idx": 6}, {"solution": "def move_zero(lst):\n \"\"\"\n Moves all zeroes to the end of the given list.\n\n Parameters:\n lst (list): The list of integers.\n\n Returns:\n list: The list with all zeroes moved to the end.\n \"\"\"\n # Initialize a list to hold non-zero elements\n non_zero = [num for num in lst if num != 0]\n # Count the number of zeroes\n zero_count = lst.count(0)\n # Extend the non-zero list with the zeroes\n return non_zero + [0] * zero_count", "matching_cluster_idx": 6}]}, "Mbpp/633": {"dps": 94.3089430894309, "dps_norm": 50.0, "pass@1": 22.0, "profiled": [{"solution": "def pair_xor_Sum(arr, n):\n total_xor_sum = 0\n \n # Iterate through each pair of elements in the array\n for i in range(n):\n for j in range(i + 1, n):\n total_xor_sum += arr[i] ^ arr[j]\n \n return total_xor_sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(nums, n):\n total_xor_sum = 0\n for i in range(n):\n for j in range(i + 1, n):\n total_xor_sum += nums[i] ^ nums[j]\n return total_xor_sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(arr, n):\n total_xor_sum = 0\n \n # Iterate through each pair of numbers\n for i in range(n):\n for j in range(i + 1, n):\n total_xor_sum += arr[i] ^ arr[j] # XOR the pair and add to total sum\n \n return total_xor_sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(arr, n):\n total_xor_sum = 0\n \n # Iterate through all unique pairs\n for i in range(n):\n for j in range(i + 1, n):\n total_xor_sum += arr[i] ^ arr[j]\n \n return total_xor_sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(arr, n):\n xor_sum = 0\n \n # Iterate through each pair of elements in the array\n for i in range(n):\n for j in range(i + 1, n):\n # Calculate the XOR of the pair and add to xor_sum\n xor_sum += arr[i] ^ arr[j]\n \n return xor_sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(numbers, n):\n total_xor_sum = 0\n \n # Iterate over all pairs (i, j) where i < j\n for i in range(n):\n for j in range(i + 1, n):\n total_xor_sum += numbers[i] ^ numbers[j] # Calculate XOR and add to sum\n \n return total_xor_sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(arr, n):\n total_xor_sum = 0\n\n # Iterate through each pair of indices\n for i in range(n):\n for j in range(i + 1, n):\n total_xor_sum += arr[i] ^ arr[j] # Compute XOR and add to total\n\n return total_xor_sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(arr, n):\n total_xor_sum = 0\n \n # Iterate through each pair of numbers in the array\n for i in range(n):\n for j in range(i + 1, n):\n # Calculate the XOR of the pair and add to the total sum\n total_xor_sum += arr[i] ^ arr[j]\n \n return total_xor_sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(arr, n):\n total_xor_sum = 0\n \n # Iterate through each pair (i, j) where i < j\n for i in range(n):\n for j in range(i + 1, n):\n total_xor_sum += arr[i] ^ arr[j] # XOR and add to total\n \n return total_xor_sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(arr, n):\n total_sum = 0\n \n # Iterate through all pairs (i, j) where i < j\n for i in range(n):\n for j in range(i + 1, n):\n total_sum += arr[i] ^ arr[j] # Calculate XOR and add to total_sum\n \n return total_sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(arr, n):\n total_sum = 0\n # Iterate through all pairs (i, j) with i < j\n for i in range(n):\n for j in range(i + 1, n):\n total_sum += arr[i] ^ arr[j] # XOR and add to total_sum\n return total_sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(arr, n):\n total_xor_sum = 0\n # Iterate through all pairs of numbers\n for i in range(n):\n for j in range(i + 1, n):\n total_xor_sum += arr[i] ^ arr[j] # XOR of the pair (arr[i], arr[j])\n return total_xor_sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(arr, n):\n # Initialize the sum of XORs to 0\n xor_sum = 0\n \n # Iterate through all pairs of elements\n for i in range(n):\n for j in range(i + 1, n):\n xor_sum += arr[i] ^ arr[j]\n \n return xor_sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(arr, n):\n total_xor_sum = 0\n\n # Calculate XOR for every pair (i, j) where i < j\n for i in range(n):\n for j in range(i + 1, n):\n total_xor_sum += arr[i] ^ arr[j]\n\n return total_xor_sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(arr, n):\n total_xor_sum = 0\n \n # Iterate through all possible pairs (i, j) where i < j\n for i in range(n):\n for j in range(i + 1, n):\n total_xor_sum += arr[i] ^ arr[j]\n \n return total_xor_sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(arr, n):\n total_sum = 0\n \n # Loop through each pair of numbers\n for i in range(n):\n for j in range(i + 1, n):\n total_sum += arr[i] ^ arr[j] # Calculate XOR and add to total sum\n \n return total_sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(arr, n):\n total_xor_sum = 0\n\n # Iterate through each pair of elements\n for i in range(n):\n for j in range(i + 1, n):\n # Calculate XOR of the pair and add it to the total sum\n total_xor_sum += arr[i] ^ arr[j]\n\n return total_xor_sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(arr, n):\n \"\"\"\n Calculate the sum of XOR of all pairs in the given list.\n \n :param arr: List of integers\n :param n: Length of the list\n :return: Sum of XOR of all pairs\n \"\"\"\n total_sum = 0\n \n # Iterate through all pairs of indices\n for i in range(n):\n for j in range(i + 1, n):\n total_sum += arr[i] ^ arr[j]\n \n return total_sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(arr, n):\n total_sum = 0\n \n # Iterate over all pairs (i, j) where i < j\n for i in range(n):\n for j in range(i + 1, n):\n total_sum += arr[i] ^ arr[j] # Calculate XOR and add to the total sum\n \n return total_sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(arr, n):\n total_xor_sum = 0\n \n # Calculate the XOR for all pairs\n for i in range(n):\n for j in range(i + 1, n):\n total_xor_sum += arr[i] ^ arr[j]\n \n return total_xor_sum", "matching_cluster_idx": 2}]}, "Mbpp/644": {"dps": 74.65425531914893, "dps_norm": 76.0, "pass@1": 100.0, "profiled": [{"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n Reverse the elements of an array up to the specified position k.\n\n Parameters:\n arr (list): The array to be reversed.\n k (int): The position up to which the array should be reversed (1-indexed).\n\n Returns:\n list: The array with elements reversed up to the position k.\n \"\"\"\n # Ensure k does not exceed the length of the array\n if k > len(arr):\n k = len(arr)\n\n # Reverse the elements up to k\n return arr[:k][::-1] + arr[k:]", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n Reverses the elements of the array `arr` up to the index `k`.\n \n Parameters:\n arr (list): The array to reverse.\n k (int): The position up to which the array should be reversed (1-indexed).\n \n Returns:\n list: The array with elements reversed up to position `k`.\n \"\"\"\n # Convert k to 0-indexed\n k -= 1\n \n # Reverse the segment of the array up to index k\n return arr[:k + 1][::-1] + arr[k + 1:]", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n Reverses the array up to the k-th position (1-based index).\n \n Parameters:\n arr (list): The list to reverse.\n k (int): The position up to which the array should be reversed (1-based index).\n \n Returns:\n list: The array with the first k elements reversed.\n \"\"\"\n # Check if k is within the valid range\n if k < 1 or k > len(arr):\n raise ValueError(\"k must be between 1 and the length of the array.\")\n \n # Reverse the first k elements\n reversed_part = arr[:k][::-1]\n # Concatenate the reversed part with the rest of the array\n return reversed_part + arr[k:]", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n Reverses the elements of the array up to the k-th position (1-indexed).\n \n Parameters:\n arr (list): The list of elements to be reversed.\n k (int): The position up to which the list should be reversed (1-indexed).\n \n Returns:\n list: The modified list with the elements reversed up to the k-th position.\n \"\"\"\n # Ensure k is within the bounds of the array length\n if k > len(arr) or k < 1:\n raise ValueError(\"k must be between 1 and the length of the array\")\n \n # Reverse the subarray from 0 to k-1 (0-indexed)\n reversed_subarray = arr[:k][::-1]\n # Concatenate the reversed subarray with the rest of the array\n return reversed_subarray + arr[k:]", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n Reverses the elements of the array 'arr' up to the index 'k'.\n\n :param arr: List of elements to be reversed\n :param k: Position up to which the array should be reversed\n :return: The modified array with elements reversed up to position k\n \"\"\"\n if k > len(arr):\n k = len(arr) # If k is greater than array length, adjust it\n \n # Reverse the subarray from index 0 to k-1\n arr[:k] = arr[:k][::-1]\n return arr", "matching_cluster_idx": 13}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n Reverse the elements of the array up to the k-th position.\n\n :param arr: List of elements to be reversed.\n :param k: Position up to which to reverse the array (1-based index).\n :return: The modified array with elements up to k reversed.\n \"\"\"\n # Adjust k to be 0-based for Python indexing\n k = min(k, len(arr)) # Ensure k does not exceed the array length\n return arr[:k][::-1] + arr[k:]", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n Reverses the array up to the given position k.\n\n Parameters:\n arr (list): The list of elements to reverse.\n k (int): The position up to which the array should be reversed (1-based index).\n\n Returns:\n list: The modified array with elements reversed up to position k.\n \"\"\"\n if k > len(arr) or k < 1:\n raise ValueError(\"k must be between 1 and the length of the array\")\n\n # Reverse the subarray from the start to position k\n arr[:k] = arr[:k][::-1]\n return arr", "matching_cluster_idx": 13}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n Reverses the elements of the array up to the k-th position.\n\n Parameters:\n arr (list): The list of elements to reverse.\n k (int): The position up to which to reverse the array (1-based index).\n\n Returns:\n list: The array with elements reversed up to position k.\n \"\"\"\n # Adjust k for 0-based indexing\n k = min(k, len(arr)) # Ensure k does not exceed array length\n return arr[:k][::-1] + arr[k:]", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n Reverses the elements of the array up to the k-th position (1-indexed).\n \n Args:\n arr (list): The array to be reversed.\n k (int): The position up to which to reverse the array (1-indexed).\n \n Returns:\n list: The array with elements reversed up to the k-th position.\n \"\"\"\n # Convert k from 1-indexed to 0-indexed\n k = k - 1\n # Reverse the segment of the array up to the k-th index\n reversed_segment = arr[:k + 1][::-1]\n # Combine the reversed segment with the rest of the array\n return reversed_segment + arr[k + 1:]", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n Reverses the array up to the k-th position.\n \n Parameters:\n arr (list): The list to reverse.\n k (int): The position up to which to reverse the list (1-based index).\n \n Returns:\n list: The modified list with elements reversed up to the k-th position.\n \"\"\"\n if k < 1 or k > len(arr):\n raise ValueError(\"k must be between 1 and the length of the array.\")\n\n # Reverse the first k elements\n reversed_part = arr[:k][::-1]\n # Concatenate the reversed part with the rest of the array\n return reversed_part + arr[k:]", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n Reverses the array up to the given position k (1-based index).\n \n :param arr: List of elements to be reversed.\n :param k: Position up to which the array will be reversed (1-based index).\n :return: List with elements reversed up to position k.\n \"\"\"\n if k < 1 or k > len(arr):\n raise ValueError(\"k must be between 1 and the length of the array.\")\n \n # Reverse the first k elements\n reversed_part = arr[:k][::-1]\n \n # Concatenate the reversed part with the rest of the array\n return reversed_part + arr[k:]", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n Reverses the elements of the array up to the k-th position.\n \n Parameters:\n arr (list): The input array to reverse.\n k (int): The position up to which to reverse the array (1-based index).\n \n Returns:\n list: The array with elements reversed up to position k.\n \"\"\"\n # Convert k to a 0-based index\n k = min(k, len(arr)) # Ensure k does not exceed the array length\n return arr[:k][::-1] + arr[k:]", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n Reverses the elements of the array up to the k-th position (1-based index).\n \n Parameters:\n arr (list): The list of elements to reverse.\n k (int): The position up to which to reverse the list (1-based index).\n\n Returns:\n list: The list with elements reversed up to the k-th position.\n \"\"\"\n # Handle cases where k is out of bounds\n if k > len(arr):\n k = len(arr)\n elif k < 1:\n return arr # If k is less than 1, return the array as is\n\n # Reverse the subarray from the start to the k-th position\n reversed_part = arr[:k][::-1]\n rest_of_array = arr[k:]\n\n return reversed_part + rest_of_array", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n Reverses the elements of the array up to the k-th position.\n \n Parameters:\n arr (list): The list of elements to be reversed.\n k (int): The position up to which the list should be reversed (1-indexed).\n \n Returns:\n list: The array with elements reversed up to the k-th position.\n \"\"\"\n if k > len(arr) or k < 1:\n raise ValueError(\"k must be between 1 and the length of the array\")\n \n # Reverse the elements up to the k-th position\n return arr[:k][::-1] + arr[k:]", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n Reverses the elements of the array up to the given position k.\n\n Parameters:\n arr (list): The input array to be reversed.\n k (int): The position up to which the array should be reversed.\n\n Returns:\n list: The array with elements reversed up to position k.\n \"\"\"\n if k > len(arr):\n raise ValueError(\"k should be less than or equal to the length of the array.\")\n\n # Reverse the subarray from start to k-1 (inclusive)\n reversed_part = arr[:k][::-1]\n # Combine the reversed part with the rest of the array\n return reversed_part + arr[k:]", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n Reverses the array up to the given position k.\n\n Parameters:\n arr (list): The input array to be reversed up to position k.\n k (int): The position up to which the array should be reversed.\n\n Returns:\n list: The array with elements reversed up to position k.\n \"\"\"\n if k > len(arr):\n k = len(arr) # Adjust k if it exceeds array length\n return arr[:k][::-1] + arr[k:]", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n Reverses the elements of the array up to the given position k.\n \n Parameters:\n arr (list): The input array to reverse.\n k (int): The position up to which to reverse the array (1-indexed).\n\n Returns:\n list: The array with elements reversed up to position k.\n \"\"\"\n # Validate k to ensure it is within the bounds of the array\n if k < 1 or k > len(arr):\n raise ValueError(\"k must be between 1 and the length of the array\")\n \n # Reverse the first k elements\n reversed_part = arr[:k][::-1]\n # Combine the reversed part with the rest of the array\n return reversed_part + arr[k:]", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n Reverse the elements of an array up to a given position k.\n\n Parameters:\n arr (list): The input array to be reversed.\n k (int): The position up to which the array should be reversed.\n\n Returns:\n list: The array with elements reversed up to position k.\n \"\"\"\n # Check if k is greater than the length of the array\n if k > len(arr):\n k = len(arr)\n \n # Reverse the sub-array from the start to k\n reversed_subarray = arr[:k][::-1]\n \n # Concatenate the reversed sub-array with the remainder of the array\n return reversed_subarray + arr[k:]", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n Reverses the elements of the array up to the k-th position.\n\n Parameters:\n arr (list): The input array to be modified.\n k (int): The position up to which to reverse the array.\n\n Returns:\n list: The array with elements reversed up to the k-th position.\n \"\"\"\n # Check if k is within the bounds of the array\n if k > len(arr) or k < 1:\n raise ValueError(\"k must be between 1 and the length of the array\")\n\n # Reverse the sub-array from the start to the k-th position (exclusive of k)\n arr[:k] = reversed(arr[:k])\n return arr", "matching_cluster_idx": 12}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n Reverse the elements of the array up to the specified position k.\n\n :param arr: List of elements to reverse\n :param k: The position up to which to reverse the elements (1-based index)\n :return: List with elements reversed up to position k\n \"\"\"\n # Check if k is greater than the length of the array\n if k > len(arr):\n raise ValueError(\"k should not be greater than the length of the array.\")\n\n # Reverse the first k elements\n reversed_part = arr[:k][::-1]\n # Concatenate with the remaining elements\n result = reversed_part + arr[k:]\n\n return result", "matching_cluster_idx": 10}]}, "Mbpp/720": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def add_dict_to_tuple(tup, dictionary):\n \"\"\"\n Adds a dictionary to a tuple and returns a new tuple.\n\n Args:\n tup (tuple): The original tuple.\n dictionary (dict): The dictionary to be added.\n\n Returns:\n tuple: A new tuple containing the elements of the original tuple and the dictionary.\n \"\"\"\n return tup + (dictionary,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(tup, dictionary):\n \"\"\"\n Adds a dictionary to a tuple and returns the resulting tuple.\n \n Parameters:\n tup (tuple): The original tuple.\n dictionary (dict): The dictionary to be added.\n \n Returns:\n tuple: The resulting tuple with the dictionary added.\n \"\"\"\n return tup + (dictionary,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(tup, dictionary):\n \"\"\"\n Adds a dictionary to a tuple and returns the new tuple.\n \n Args:\n tup (tuple): The original tuple.\n dictionary (dict): The dictionary to be added to the tuple.\n \n Returns:\n tuple: A new tuple containing the original elements and the dictionary.\n \"\"\"\n return tup + (dictionary,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(input_tuple, input_dict):\n \"\"\"\n Adds a dictionary to the end of a tuple and returns the new tuple.\n\n Parameters:\n input_tuple (tuple): The original tuple.\n input_dict (dict): The dictionary to be added to the tuple.\n\n Returns:\n tuple: A new tuple containing the original tuple elements and the dictionary.\n \"\"\"\n return input_tuple + (input_dict,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(input_tuple, input_dict):\n \"\"\"\n Add a dictionary to a tuple.\n \n Parameters:\n input_tuple (tuple): The original tuple.\n input_dict (dict): The dictionary to add to the tuple.\n \n Returns:\n tuple: A new tuple containing all elements of the original tuple and the dictionary.\n \"\"\"\n return input_tuple + (input_dict,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(original_tuple, dictionary):\n \"\"\"\n Add a dictionary to the tuple.\n\n Parameters:\n original_tuple (tuple): The original tuple to which the dictionary will be added.\n dictionary (dict): The dictionary to add to the tuple.\n\n Returns:\n tuple: A new tuple that includes the original elements and the dictionary.\n \"\"\"\n return original_tuple + (dictionary,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(tup, dct):\n \"\"\"\n Adds a dictionary to the tuple.\n \n Parameters:\n tup (tuple): The original tuple.\n dct (dict): The dictionary to be added.\n \n Returns:\n tuple: A new tuple containing the original elements and the dictionary.\n \"\"\"\n return tup + (dct,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(original_tuple, dictionary):\n \"\"\"\n Adds a dictionary to a tuple and returns the new tuple.\n \n Args:\n original_tuple (tuple): The original tuple to which the dictionary will be added.\n dictionary (dict): The dictionary to add to the tuple.\n \n Returns:\n tuple: A new tuple containing the original elements plus the dictionary.\n \"\"\"\n return original_tuple + (dictionary,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(tup, dct):\n \"\"\"\n Adds a dictionary to a tuple and returns a new tuple.\n\n Parameters:\n tup (tuple): The original tuple.\n dct (dict): The dictionary to be added.\n\n Returns:\n tuple: A new tuple containing the original elements and the dictionary.\n \"\"\"\n return tup + (dct,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(tup, dictionary):\n \"\"\"\n Add a dictionary to the tuple.\n \n Parameters:\n tup (tuple): The tuple to which the dictionary will be added.\n dictionary (dict): The dictionary to be added.\n\n Returns:\n tuple: A new tuple that includes the original tuple elements and the dictionary.\n \"\"\"\n return tup + (dictionary,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(tup, dictionary):\n \"\"\"\n Add a dictionary to a tuple and return the new tuple.\n\n Parameters:\n tup (tuple): The original tuple.\n dictionary (dict): The dictionary to be added to the tuple.\n\n Returns:\n tuple: A new tuple containing the original elements and the dictionary.\n \"\"\"\n return tup + (dictionary,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(tup, dct):\n \"\"\"\n Adds a dictionary to a tuple and returns a new tuple.\n \n Args:\n tup (tuple): The original tuple.\n dct (dict): The dictionary to add to the tuple.\n \n Returns:\n tuple: A new tuple containing the original elements and the dictionary.\n \"\"\"\n return tup + (dct,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(tup, dct):\n \"\"\"\n Adds a dictionary to a tuple and returns the new tuple.\n\n Parameters:\n tup (tuple): The original tuple.\n dct (dict): The dictionary to be added to the tuple.\n\n Returns:\n tuple: A new tuple containing the original elements and the dictionary.\n \"\"\"\n return tup + (dct,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(input_tuple, input_dict):\n \"\"\"\n Add a dictionary to a tuple and return a new tuple.\n\n Parameters:\n input_tuple (tuple): The original tuple.\n input_dict (dict): The dictionary to be added.\n\n Returns:\n tuple: A new tuple containing the original elements and the dictionary.\n \"\"\"\n return input_tuple + (input_dict,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(original_tuple, dictionary):\n \"\"\"\n Adds a dictionary to the end of a tuple.\n \n Args:\n original_tuple (tuple): The tuple to which the dictionary will be added.\n dictionary (dict): The dictionary to be added to the tuple.\n \n Returns:\n tuple: A new tuple containing the original elements and the dictionary.\n \"\"\"\n return original_tuple + (dictionary,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(input_tuple, input_dict):\n \"\"\"\n Add a dictionary to the tuple.\n \n Parameters:\n input_tuple (tuple): The tuple to which the dictionary will be added.\n input_dict (dict): The dictionary to be added to the tuple.\n \n Returns:\n tuple: A new tuple that includes the original tuple elements followed by the dictionary.\n \"\"\"\n return input_tuple + (input_dict,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(input_tuple, input_dict):\n \"\"\"\n Add a dictionary to the tuple.\n\n Args:\n input_tuple (tuple): The original tuple.\n input_dict (dict): The dictionary to add.\n\n Returns:\n tuple: A new tuple with the dictionary added as the last element.\n \"\"\"\n return input_tuple + (input_dict,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(tup, dct):\n \"\"\"\n Adds a dictionary to the given tuple.\n\n Args:\n tup (tuple): The original tuple.\n dct (dict): The dictionary to add.\n\n Returns:\n tuple: A new tuple containing the original elements and the dictionary.\n \"\"\"\n return tup + (dct,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(tup, dictionary):\n \"\"\"\n Adds a dictionary to the end of a tuple and returns a new tuple.\n \n Parameters:\n tup (tuple): The original tuple.\n dictionary (dict): The dictionary to add to the tuple.\n \n Returns:\n tuple: A new tuple containing the original elements and the dictionary.\n \"\"\"\n return tup + (dictionary,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(tup, dictionary):\n \"\"\"\n Adds a dictionary to a tuple and returns the resulting tuple.\n\n Parameters:\n tup (tuple): The original tuple.\n dictionary (dict): The dictionary to be added to the tuple.\n\n Returns:\n tuple: A new tuple containing the original elements and the dictionary.\n \"\"\"\n return tup + (dictionary,)", "matching_cluster_idx": 4}]}, "Mbpp/725": {"dps": 64.72677595628414, "dps_norm": 70.0, "pass@1": 99.0, "profiled": [{"solution": "def extract_quotation(s):\n \"\"\"\n Extracts values between quotation marks from the given string.\n\n Parameters:\n s (str): The input string containing quoted values.\n\n Returns:\n list: A list of values found between quotation marks.\n \"\"\"\n import re\n # Use regular expression to find all occurrences of text within quotation marks\n matches = re.findall(r'\"(.*?)\"', s)\n return matches", "matching_cluster_idx": 4}, {"solution": "def extract_quotation(input_string):\n \"\"\"\n Extract values between quotation marks from the given string.\n\n Args:\n input_string (str): The string to extract quoted values from.\n\n Returns:\n list: A list of strings found between quotation marks.\n \"\"\"\n import re\n \n # Use regular expression to find all occurrences of text within quotation marks\n return re.findall(r'\"(.*?)\"', input_string)", "matching_cluster_idx": 5}, {"solution": "def extract_quotation(input_string):\n import re\n # Use a regular expression to find all substrings within quotation marks\n return re.findall(r'\"(.*?)\"', input_string)", "matching_cluster_idx": 4}, {"solution": "def extract_quotation(s):\n \"\"\"Extracts values between quotation marks in the given string.\"\"\"\n import re\n return re.findall(r'\"(.*?)\"', s)", "matching_cluster_idx": 4}, {"solution": "def extract_quotation(s):\n \"\"\"\n Extract values between quotation marks \" \" from the given string.\n\n :param s: Input string from which to extract quoted values.\n :return: A list of strings found between quotation marks.\n \"\"\"\n import re\n return re.findall(r'\"(.*?)\"', s)", "matching_cluster_idx": 5}, {"solution": "def extract_quotation(input_string):\n # List to hold extracted values\n extracted_values = []\n # Variable to track whether we are currently inside quotes\n inside_quotes = False\n # Variable to hold the current value being constructed\n current_value = ''\n \n for char in input_string:\n if char == '\"':\n if inside_quotes:\n # We are closing a quote; add the current value to the list\n extracted_values.append(current_value)\n current_value = ''\n # Toggle the inside_quotes flag\n inside_quotes = not inside_quotes\n elif inside_quotes:\n # If we are inside quotes, append the character to the current value\n current_value += char\n \n return extracted_values", "matching_cluster_idx": 2}, {"solution": "def extract_quotation(s):\n \"\"\"\n Extracts values between quotation marks \" \" from the given string.\n\n Args:\n s (str): The input string from which to extract quoted values.\n\n Returns:\n list: A list of strings that were found within quotation marks.\n \"\"\"\n import re\n \n # Use regular expression to find all occurrences of text within double quotes\n return re.findall(r'\"(.*?)\"', s)", "matching_cluster_idx": 5}, {"solution": "def extract_quotation(s):\n \"\"\"\n Extracts values between quotation marks \" \" from the given string.\n \n Args:\n s (str): The input string containing quoted values.\n \n Returns:\n list: A list of values found between the quotation marks.\n \"\"\"\n import re\n \n # Using regex to find all occurrences of text within quotation marks\n return re.findall(r'\"(.*?)\"', s)", "matching_cluster_idx": 5}, {"solution": "def extract_quotation(input_string):\n \"\"\"\n Extract values between quotation marks \" \" from the given string.\n\n Args:\n input_string (str): The string from which to extract quoted values.\n\n Returns:\n List[str]: A list of values found between quotation marks.\n \"\"\"\n import re\n # Use regular expression to find all occurrences of text within quotes\n return re.findall(r'\"(.*?)\"', input_string)", "matching_cluster_idx": 5}, {"solution": "def extract_quotation(s: str) -> list:\n \"\"\"\n Extracts values between quotation marks in the given string.\n\n Parameters:\n s (str): The input string from which to extract quoted values.\n\n Returns:\n list: A list of extracted values from within quotation marks.\n \"\"\"\n import re\n return re.findall(r'\"([^\"]*)\"', s)", "matching_cluster_idx": 6}, {"solution": "def extract_quotation(s):\n \"\"\"\n Extract values between quotation marks \" \" from the given string.\n \n Parameters:\n s (str): The input string from which to extract quoted values.\n \n Returns:\n List[str]: A list of strings extracted from within quotation marks.\n \"\"\"\n import re\n return re.findall(r'\"(.*?)\"', s)", "matching_cluster_idx": 4}, {"solution": "def extract_quotation(s):\n \"\"\"\n Extracts values between quotation marks from the given string.\n\n Args:\n s (str): The input string containing quoted values.\n\n Returns:\n list: A list of strings found between the quotation marks.\n \"\"\"\n import re\n return re.findall(r'\"([^\"]*)\"', s)", "matching_cluster_idx": 6}, {"solution": "def extract_quotation(input_string):\n # Importing regular expressions library\n import re\n \n # Using regular expression to find all occurrences of text within double quotes\n return re.findall(r'\"(.*?)\"', input_string)", "matching_cluster_idx": 5}, {"solution": "def extract_quotation(s):\n \"\"\"\n Extracts values between quotation marks \" \" from the given string.\n\n Args:\n s (str): The input string from which to extract quoted values.\n\n Returns:\n list: A list of strings that were found between the quotation marks.\n \"\"\"\n import re\n # Use a regular expression to find all occurrences of text within quotation marks\n return re.findall(r'\"(.*?)\"', s)", "matching_cluster_idx": 5}, {"solution": "def extract_quotation(text):\n \"\"\"\n Extract values between quotation marks \" \" from the given string.\n\n Args:\n text (str): The input string containing quoted values.\n\n Returns:\n list: A list of extracted values between quotation marks.\n \"\"\"\n import re\n # Use a regular expression to find all occurrences of text within quotation marks\n return re.findall(r'\"(.*?)\"', text)", "matching_cluster_idx": 5}, {"solution": "def extract_quotation(s):\n \"\"\"\n Extracts values between quotation marks in the given string.\n\n Parameters:\n s (str): The input string to extract values from.\n\n Returns:\n List[str]: A list of values found between quotation marks.\n \"\"\"\n import re\n # Find all substrings enclosed in double quotes\n matches = re.findall(r'\"(.*?)\"', s)\n return matches", "matching_cluster_idx": 4}, {"solution": "def extract_quotation(s):\n \"\"\"Extracts values between quotation marks from the given string.\"\"\"\n import re\n return re.findall(r'\"(.*?)\"', s)", "matching_cluster_idx": 4}, {"solution": "import re\ndef extract_quotation(s):\n \"\"\"\n Extracts values between quotation marks \" \" from the given string.\n\n Parameters:\n s (str): The input string from which to extract quoted values.\n\n Returns:\n list: A list of strings found between quotation marks.\n \"\"\"\n return re.findall(r'\"(.*?)\"', s)", "matching_cluster_idx": 5}, {"solution": "def extract_quotation(s):\n \"\"\"\n Extract values between quotation marks \" \" from the given string.\n\n Parameters:\n s (str): The input string containing quoted values.\n\n Returns:\n list: A list of strings extracted from the quoted values.\n \"\"\"\n import re\n return re.findall(r'\"(.*?)\"', s)", "matching_cluster_idx": 5}, {"solution": "def extract_quotation(s):\n \"\"\"\n Extracts values between quotation marks in the given string.\n \n Args:\n s (str): The input string to extract values from.\n \n Returns:\n list: A list of strings that are found between the quotation marks.\n \"\"\"\n import re\n # Use regular expression to find all occurrences of text within quotes\n return re.findall(r'\"(.*?)\"', s)", "matching_cluster_idx": 4}]}, "Mbpp/732": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def replace_specialchar(input_string):\n # Replace spaces, commas, and dots with a colon\n return input_string.replace(' ', ':').replace(',', ':').replace('.', ':')", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(input_string):\n # Replace spaces, commas, and dots with colons\n return input_string.replace(' ', ':').replace(',', ':').replace('.', ':')", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(text):\n \"\"\"\n Replace all occurrences of spaces, commas, or dots with a colon in the input text.\n \n Parameters:\n text (str): The input string to modify.\n \n Returns:\n str: The modified string with spaces, commas, and dots replaced by colons.\n \"\"\"\n return text.replace(' ', ':').replace(',', ':').replace('.', ':')", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(text):\n \"\"\"\n Replace all occurrences of spaces, commas, or dots with a colon.\n \n Parameters:\n text (str): The input string to process.\n \n Returns:\n str: The modified string with spaces, commas, and dots replaced by colons.\n \"\"\"\n return text.replace(' ', ':').replace(',', ':').replace('.', ':')", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(input_string):\n # Replace spaces, commas, and dots with a colon\n return input_string.replace(' ', ':').replace(',', ':').replace('.', ':')", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(text):\n \"\"\"\n Replaces all occurrences of spaces, commas, or dots in the given text with a colon.\n \n Parameters:\n text (str): The input string to process.\n \n Returns:\n str: The processed string with spaces, commas, and dots replaced by colons.\n \"\"\"\n return text.replace(' ', ':').replace(',', ':').replace('.', ':')", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(text):\n \"\"\"\n Replace all occurrences of spaces, commas, or dots with a colon.\n\n Parameters:\n text (str): The input string.\n\n Returns:\n str: The modified string with spaces, commas, and dots replaced by colons.\n \"\"\"\n return text.replace(' ', ':').replace(',', ':').replace('.', ':')", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(text):\n \"\"\"\n Replaces all occurrences of spaces, commas, or dots with a colon in the given string.\n \n Args:\n text (str): The input string to be modified.\n \n Returns:\n str: The modified string with spaces, commas, and dots replaced by colons.\n \"\"\"\n return text.replace(' ', ':').replace(',', ':').replace('.', ':')", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(text):\n \"\"\"\n Replace all occurrences of spaces, commas, or dots with a colon in the given text.\n \n Args:\n text (str): The input string from which to replace characters.\n \n Returns:\n str: The modified string with specified characters replaced by a colon.\n \"\"\"\n # Replace spaces, commas, and dots with a colon\n return text.replace(' ', ':').replace(',', ':').replace('.', ':')", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(text):\n \"\"\"\n Replace all occurrences of spaces, commas, or dots with a colon in the given text.\n \n Args:\n text (str): The input string to process.\n \n Returns:\n str: The modified string with replacements.\n \"\"\"\n return text.replace(' ', ':').replace(',', ':').replace('.', ':')", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(text):\n \"\"\"\n Replace all occurrences of spaces, commas, or dots with a colon.\n\n Args:\n text (str): The input string.\n\n Returns:\n str: The modified string with spaces, commas, and dots replaced by colons.\n \"\"\"\n return text.replace(' ', ':').replace(',', ':').replace('.', ':')", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(input_string):\n # Replace spaces, commas, and dots with colons\n return input_string.replace(' ', ':').replace(',', ':').replace('.', ':')", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(text):\n \"\"\"\n Replace all occurrences of spaces, commas, or dots in the input string with a colon.\n\n Args:\n text (str): The input string to process.\n\n Returns:\n str: The modified string with specified characters replaced by colons.\n \"\"\"\n # Replace spaces, commas, and dots with colons\n return text.replace(' ', ':').replace(',', ':').replace('.', ':')", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(text):\n # Replace spaces, commas, and dots with a colon\n return text.replace(' ', ':').replace(',', ':').replace('.', ':')", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(input_string):\n # Replace spaces, commas, and dots with colons\n return input_string.replace(' ', ':').replace(',', ':').replace('.', ':')", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(text):\n # Replace spaces, commas, and dots with a colon\n return text.replace(' ', ':').replace(',', ':').replace('.', ':')", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(text):\n \"\"\"\n Replace all occurrences of spaces, commas, or dots in the given text with a colon.\n\n Args:\n text (str): The input string.\n\n Returns:\n str: The modified string with spaces, commas, and dots replaced by colons.\n \"\"\"\n return text.replace(' ', ':').replace(',', ':').replace('.', ':')", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(input_string):\n # Replace spaces, commas, and dots with colons\n return input_string.replace(' ', ':').replace(',', ':').replace('.', ':')", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(input_string):\n # Replace spaces, commas, and dots with colons\n return input_string.replace(' ', ':').replace(',', ':').replace('.', ':')", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(text):\n \"\"\"\n Replaces all occurrences of spaces, commas, or dots in the input text with a colon.\n\n Args:\n text (str): The input string to be processed.\n\n Returns:\n str: The modified string with specified characters replaced by a colon.\n \"\"\"\n # Replace spaces, commas, and dots with a colon\n return text.replace(' ', ':').replace(',', ':').replace('.', ':')", "matching_cluster_idx": 9}]}, "Mbpp/740": {"dps": 86.9090909090909, "dps_norm": 73.33333333333334, "pass@1": 95.0, "profiled": [{"solution": "def tuple_to_dict(tup):\n \"\"\"Convert a given tuple to a key-value dictionary using adjacent elements.\"\"\"\n if len(tup) % 2 != 0:\n raise ValueError(\"Tuple must contain an even number of elements.\")\n \n return {tup[i]: tup[i + 1] for i in range(0, len(tup), 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(tup):\n \"\"\"\n Convert the given tuple to a key-value dictionary using adjacent elements.\n \n Args:\n tup (tuple): A tuple containing elements where even indexed elements are keys \n and odd indexed elements are values.\n \n Returns:\n dict: A dictionary with keys and values from the tuple.\n \"\"\"\n return {tup[i]: tup[i + 1] for i in range(0, len(tup) - 1, 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(input_tuple):\n \"\"\"\n Convert a given tuple to a key-value dictionary using adjacent elements.\n \n Args:\n input_tuple (tuple): A tuple containing elements.\n \n Returns:\n dict: A dictionary with adjacent elements as key-value pairs.\n \"\"\"\n if len(input_tuple) % 2 != 0:\n raise ValueError(\"The input tuple must contain an even number of elements.\")\n \n it = iter(input_tuple)\n return dict(zip(it, it))", "matching_cluster_idx": 8}, {"solution": "def tuple_to_dict(tup):\n \"\"\"\n Converts a tuple to a dictionary using adjacent elements as key-value pairs.\n\n :param tup: A tuple containing elements to be converted.\n :return: A dictionary with keys and values from the tuple.\n \"\"\"\n if len(tup) % 2 != 0:\n raise ValueError(\"Tuple must contain an even number of elements.\")\n \n return {tup[i]: tup[i + 1] for i in range(0, len(tup), 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(tup):\n \"\"\"\n Convert a given tuple to a key-value dictionary using adjacent elements.\n \n Args:\n tup (tuple): A tuple of elements where elements at even indices become keys\n and elements at odd indices become values.\n \n Returns:\n dict: A dictionary with keys and values formed from adjacent elements of the tuple.\n \"\"\"\n if len(tup) % 2 != 0:\n raise ValueError(\"The input tuple must contain an even number of elements.\")\n \n return {tup[i]: tup[i + 1] for i in range(0, len(tup), 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(tup):\n \"\"\"\n Convert a tuple to a dictionary using adjacent elements as key-value pairs.\n\n Parameters:\n tup (tuple): A tuple with an even number of elements.\n\n Returns:\n dict: A dictionary created from the tuple.\n \n Example:\n >>> tuple_to_dict((1, 5, 7, 10, 13, 5))\n {1: 5, 7: 10, 13: 5}\n \"\"\"\n if len(tup) % 2 != 0:\n raise ValueError(\"Tuple must have an even number of elements.\")\n \n return {tup[i]: tup[i + 1] for i in range(0, len(tup), 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(tup):\n \"\"\"\n Convert a given tuple to a key-value dictionary using adjacent elements.\n \n Args:\n tup (tuple): A tuple of elements to be converted to a dictionary.\n \n Returns:\n dict: A dictionary with keys and values from adjacent elements in the tuple.\n \n Example:\n >>> tuple_to_dict((1, 5, 7, 10, 13, 5))\n {1: 5, 7: 10, 13: 5}\n \"\"\"\n # Create a dictionary by using slice to pair up adjacent elements\n return {tup[i]: tup[i+1] for i in range(0, len(tup)-1, 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(tup):\n # Convert the tuple to a list to access pairs of elements\n it = iter(tup)\n # Create a dictionary by zipping the iterator with itself offset by one\n return dict(zip(it, it))", "matching_cluster_idx": 8}, {"solution": "def tuple_to_dict(tup):\n \"\"\"\n Convert a tuple to a dictionary using adjacent elements as key-value pairs.\n \n Args:\n tup (tuple): A tuple of elements.\n \n Returns:\n dict: A dictionary created from adjacent elements in the tuple.\n \"\"\"\n # Use dictionary comprehension to create the dictionary\n return {tup[i]: tup[i + 1] for i in range(0, len(tup) - 1, 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(tup):\n # Create an empty dictionary\n result_dict = {}\n # Iterate over the tuple in steps of 2\n for i in range(0, len(tup) - 1, 2):\n # Use the current element as key and the next element as value\n result_dict[tup[i]] = tup[i + 1]\n return result_dict", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(tup):\n \"\"\"\n Convert a given tuple to a dictionary using adjacent elements as key-value pairs.\n\n Args:\n tup (tuple): A tuple containing elements to be converted.\n\n Returns:\n dict: A dictionary with adjacent elements of the tuple as key-value pairs.\n \"\"\"\n # Create an empty dictionary\n result_dict = {}\n \n # Iterate through the tuple in steps of 2\n for i in range(0, len(tup) - 1, 2):\n key = tup[i]\n value = tup[i + 1]\n result_dict[key] = value\n \n return result_dict", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(tup):\n \"\"\"Convert a tuple to a dictionary using adjacent elements as key-value pairs.\"\"\"\n # Ensure the tuple has an even number of elements for key-value pairs\n if len(tup) % 2 != 0:\n raise ValueError(\"Tuple must contain an even number of elements.\")\n \n # Create a dictionary using a dictionary comprehension\n return {tup[i]: tup[i + 1] for i in range(0, len(tup), 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(t):\n \"\"\"Convert a tuple to a dictionary using adjacent elements as key-value pairs.\"\"\"\n if len(t) < 2:\n return {}\n \n return {t[i]: t[i + 1] for i in range(0, len(t) - 1, 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(tup):\n \"\"\"Convert a tuple to a key-value dictionary using adjacent elements.\"\"\"\n it = iter(tup)\n return dict(zip(it, it))", "matching_cluster_idx": 8}, {"solution": "def tuple_to_dict(tup):\n \"\"\"\n Converts a given tuple to a key-value dictionary using adjacent elements.\n \n Args:\n tup (tuple): A tuple containing elements to be converted.\n\n Returns:\n dict: A dictionary with adjacent elements from the tuple as key-value pairs.\n \"\"\"\n if len(tup) % 2 != 0:\n raise ValueError(\"Tuple must contain an even number of elements.\")\n \n return {tup[i]: tup[i + 1] for i in range(0, len(tup), 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(t):\n # Ensure the tuple has an even number of elements to form key-value pairs\n if len(t) % 2 != 0:\n raise ValueError(\"The tuple must have an even number of elements.\")\n \n # Create a dictionary using adjacent elements as key-value pairs\n return {t[i]: t[i + 1] for i in range(0, len(t), 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(t):\n \"\"\"\n Convert a given tuple to a key-value dictionary using adjacent elements.\n\n Args:\n t (tuple): A tuple containing elements where adjacent elements represent key-value pairs.\n\n Returns:\n dict: A dictionary formed from the adjacent elements of the tuple.\n \n Example:\n >>> tuple_to_dict((1, 5, 7, 10, 13, 5))\n {1: 5, 7: 10, 13: 5}\n \"\"\"\n # Create a dictionary from adjacent elements in the tuple\n return {t[i]: t[i + 1] for i in range(0, len(t) - 1, 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(tup):\n \"\"\"\n Converts a given tuple to a dictionary using adjacent elements as key-value pairs.\n \n Args:\n tup (tuple): A tuple containing elements to be converted.\n \n Returns:\n dict: A dictionary with adjacent tuple elements as key-value pairs.\n \"\"\"\n # Create a dictionary from the tuple using a comprehension\n return {tup[i]: tup[i + 1] for i in range(0, len(tup) - 1, 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(tup):\n \"\"\"Convert a given tuple to a dictionary using adjacent elements.\"\"\"\n if len(tup) % 2 != 0:\n raise ValueError(\"The tuple must have an even number of elements to form key-value pairs.\")\n \n return {tup[i]: tup[i + 1] for i in range(0, len(tup), 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(tup):\n # Check if the length of the tuple is even, if not, ignore the last element\n if len(tup) % 2 != 0:\n tup = tup[:-1]\n \n # Convert the tuple to a dictionary using adjacent elements\n return dict(zip(tup[::2], tup[1::2]))", "matching_cluster_idx": 8}]}, "Mbpp/744": {"dps": 32.054794520547944, "dps_norm": 50.833333333333336, "pass@1": 100.0, "profiled": [{"solution": "def check_none(input_tuple):\n \"\"\"\n Check if the given tuple has any None value.\n \n Args:\n input_tuple (tuple): The tuple to check.\n \n Returns:\n bool: True if there is at least one None value, otherwise False.\n \"\"\"\n return any(item is None for item in input_tuple)", "matching_cluster_idx": 2}, {"solution": "def check_none(tup):\n \"\"\"\n Checks if the given tuple contains any None values.\n\n Args:\n tup (tuple): The tuple to check.\n\n Returns:\n bool: True if there is at least one None value, False otherwise.\n \"\"\"\n return any(element is None for element in tup)", "matching_cluster_idx": 2}, {"solution": "def check_none(tup):\n \"\"\"\n Check if the given tuple has any None value.\n\n Parameters:\n tup (tuple): The tuple to check for None values.\n\n Returns:\n bool: True if there is at least one None value, False otherwise.\n \"\"\"\n return any(item is None for item in tup)", "matching_cluster_idx": 1}, {"solution": "def check_none(tup):\n \"\"\"\n Checks if the given tuple has any None values.\n\n Parameters:\n tup (tuple): The tuple to check.\n\n Returns:\n bool: True if there is at least one None value, False otherwise.\n \"\"\"\n return any(item is None for item in tup)", "matching_cluster_idx": 2}, {"solution": "def check_none(tup):\n \"\"\"\n Check if the given tuple contains any None values.\n\n Parameters:\n tup (tuple): The tuple to check for None values.\n\n Returns:\n bool: True if there is at least one None value, False otherwise.\n \"\"\"\n return any(elem is None for elem in tup)", "matching_cluster_idx": 2}, {"solution": "def check_none(input_tuple):\n \"\"\"Check if the given tuple contains any None values.\"\"\"\n return any(item is None for item in input_tuple)", "matching_cluster_idx": 2}, {"solution": "def check_none(input_tuple):\n \"\"\"\n Check if the given tuple has any None value.\n \n Args:\n input_tuple (tuple): The tuple to check.\n \n Returns:\n bool: True if there is at least one None value, False otherwise.\n \"\"\"\n return any(item is None for item in input_tuple)", "matching_cluster_idx": 2}, {"solution": "def check_none(input_tuple):\n \"\"\"\n Check if the given tuple has any None value.\n\n Parameters:\n input_tuple (tuple): The tuple to check.\n\n Returns:\n bool: True if there is at least one None value, False otherwise.\n \"\"\"\n return any(item is None for item in input_tuple)", "matching_cluster_idx": 2}, {"solution": "def check_none(input_tuple):\n \"\"\"\n Check if the given tuple has any None value.\n \n Args:\n input_tuple (tuple): The tuple to check for None values.\n \n Returns:\n bool: True if there is at least one None value, False otherwise.\n \"\"\"\n return any(element is None for element in input_tuple)", "matching_cluster_idx": 2}, {"solution": "def check_none(input_tuple):\n \"\"\"\n Check if the given tuple has any None value.\n\n Args:\n input_tuple (tuple): The tuple to check.\n\n Returns:\n bool: True if there is at least one None value, False otherwise.\n \"\"\"\n return any(element is None for element in input_tuple)", "matching_cluster_idx": 1}, {"solution": "def check_none(input_tuple):\n \"\"\"\n Check if the given tuple has any None value.\n\n Parameters:\n input_tuple (tuple): The tuple to check.\n\n Returns:\n bool: True if there is at least one None value, False otherwise.\n \"\"\"\n return None in input_tuple", "matching_cluster_idx": 5}, {"solution": "def check_none(t):\n \"\"\"Check if the given tuple has any None value.\n\n Args:\n t (tuple): The tuple to check.\n\n Returns:\n bool: True if there is at least one None value, False otherwise.\n \"\"\"\n return any(item is None for item in t)", "matching_cluster_idx": 2}, {"solution": "def check_none(input_tuple):\n \"\"\"Check if the given tuple contains any None value.\"\"\"\n return any(element is None for element in input_tuple)", "matching_cluster_idx": 2}, {"solution": "def check_none(input_tuple):\n \"\"\"\n Check if the given tuple has any None value.\n\n Parameters:\n input_tuple (tuple): The tuple to check for None values.\n\n Returns:\n bool: True if there is at least one None value, False otherwise.\n \"\"\"\n return any(element is None for element in input_tuple)", "matching_cluster_idx": 2}, {"solution": "def check_none(input_tuple):\n \"\"\"\n Check if the given tuple has any None value.\n\n Parameters:\n input_tuple (tuple): The tuple to check for None values.\n\n Returns:\n bool: True if there is at least one None value, False otherwise.\n \"\"\"\n return any(item is None for item in input_tuple)", "matching_cluster_idx": 2}, {"solution": "def check_none(input_tuple):\n \"\"\"Check if the given tuple has any None value.\"\"\"\n return any(element is None for element in input_tuple)", "matching_cluster_idx": 2}, {"solution": "def check_none(tup):\n \"\"\"\n Check if the given tuple has any None value.\n \n :param tup: A tuple to check for None values.\n :return: True if there is at least one None value, False otherwise.\n \"\"\"\n return any(value is None for value in tup)", "matching_cluster_idx": 2}, {"solution": "def check_none(input_tuple):\n \"\"\"\n Check if the given tuple contains any None value.\n\n Parameters:\n input_tuple (tuple): The tuple to check.\n\n Returns:\n bool: True if the tuple contains None, False otherwise.\n \"\"\"\n return any(element is None for element in input_tuple)", "matching_cluster_idx": 2}, {"solution": "def check_none(input_tuple):\n \"\"\"Check if the given tuple has any None values.\"\"\"\n return any(item is None for item in input_tuple)", "matching_cluster_idx": 2}, {"solution": "def check_none(tup):\n \"\"\"\n Check if the given tuple has any None value.\n\n Args:\n tup (tuple): The tuple to check for None values.\n\n Returns:\n bool: True if there is at least one None value, False otherwise.\n \"\"\"\n return any(item is None for item in tup)", "matching_cluster_idx": 2}]}, "Mbpp/750": {"dps": 71.63265306122449, "dps_norm": 74.16666666666667, "pass@1": 100.0, "profiled": [{"solution": "def add_tuple(lst, tup):\n \"\"\"\n Adds the elements of the given tuple to the given list.\n\n Args:\n lst (list): The list to which the elements will be added.\n tup (tuple): The tuple whose elements will be added to the list.\n\n Returns:\n list: The updated list with elements from the tuple appended.\n \"\"\"\n return lst + list(tup)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(lst, tup):\n \"\"\"\n Adds the elements of the given tuple to the given list.\n\n Parameters:\n lst (list): The list to which the tuple elements will be added.\n tup (tuple): The tuple whose elements will be added to the list.\n\n Returns:\n list: The updated list containing the original elements plus the tuple elements.\n \"\"\"\n lst.extend(tup)\n return lst", "matching_cluster_idx": 5}, {"solution": "def add_tuple(lst, tpl):\n \"\"\"Adds the elements of a tuple to the end of a list.\"\"\"\n lst.extend(tpl)\n return lst", "matching_cluster_idx": 5}, {"solution": "def add_tuple(lst, tpl):\n \"\"\"\n Adds the given tuple to the given list.\n \n Parameters:\n lst (list): The list to which the tuple will be added.\n tpl (tuple): The tuple to be added to the list.\n \n Returns:\n list: The list after adding the elements of the tuple.\n \"\"\"\n return lst + list(tpl)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(lst, tpl):\n \"\"\"\n Adds the given tuple to the given list.\n\n Parameters:\n lst (list): The list to which the tuple will be added.\n tpl (tuple): The tuple to add to the list.\n\n Returns:\n list: The updated list with the elements of the tuple added.\n \"\"\"\n lst.extend(tpl)\n return lst", "matching_cluster_idx": 5}, {"solution": "def add_tuple(lst, tup):\n \"\"\"\n Add the given tuple to the given list and return the new list.\n\n Parameters:\n lst (list): The list to which the tuple will be added.\n tup (tuple): The tuple that will be added to the list.\n\n Returns:\n list: The updated list with elements of the tuple added.\n \"\"\"\n return lst + list(tup)", "matching_cluster_idx": 1}, {"solution": "def add_tuple(lst, tpl):\n \"\"\"\n Adds the elements of the given tuple to the end of the given list.\n\n Parameters:\n lst (list): The list to which the tuple will be added.\n tpl (tuple): The tuple whose elements will be added to the list.\n\n Returns:\n list: The updated list with elements of the tuple added.\n \"\"\"\n lst.extend(tpl)\n return lst", "matching_cluster_idx": 5}, {"solution": "def add_tuple(lst, tup):\n \"\"\"\n Adds the given tuple to the end of the given list.\n\n Parameters:\n lst (list): The list to which the tuple will be added.\n tup (tuple): The tuple whose elements will be added to the list.\n\n Returns:\n list: The updated list with the elements of the tuple added.\n \"\"\"\n # Extend the list with the elements of the tuple\n lst.extend(tup)\n return lst", "matching_cluster_idx": 5}, {"solution": "def add_tuple(lst, tpl):\n \"\"\"\n Adds the elements of the given tuple to the end of the given list.\n\n Parameters:\n lst (list): The list to which the tuple will be added.\n tpl (tuple): The tuple whose elements will be added to the list.\n\n Returns:\n list: The list with the elements of the tuple added.\n \"\"\"\n lst.extend(tpl)\n return lst", "matching_cluster_idx": 5}, {"solution": "def add_tuple(lst, tup):\n \"\"\"\n Adds the elements of the given tuple to the end of the given list.\n\n Parameters:\n lst (list): The list to which the tuple will be added.\n tup (tuple): The tuple whose elements will be added to the list.\n\n Returns:\n list: The updated list containing the elements of the tuple.\n \"\"\"\n return lst + list(tup)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(lst, tpl):\n \"\"\"\n Add the given tuple to the given list.\n \n Parameters:\n lst (list): The list to which the tuple will be added.\n tpl (tuple): The tuple to add to the list.\n \n Returns:\n list: The updated list with the tuple elements added.\n \"\"\"\n lst.extend(tpl) # Extend the list by appending elements from the tuple\n return lst", "matching_cluster_idx": 5}, {"solution": "def add_tuple(lst, tpl):\n \"\"\"Add the elements of the tuple to the end of the list.\"\"\"\n lst.extend(tpl)\n return lst", "matching_cluster_idx": 5}, {"solution": "def add_tuple(lst, tpl):\n \"\"\"\n This function adds the elements of a tuple to a list.\n \n Parameters:\n lst (list): The original list to which elements will be added.\n tpl (tuple): The tuple containing elements to add to the list.\n \n Returns:\n list: The updated list with elements from the tuple added.\n \"\"\"\n # Extend the list with elements from the tuple\n lst.extend(tpl)\n return lst", "matching_cluster_idx": 5}, {"solution": "def add_tuple(lst, tpl):\n \"\"\"Add the elements of a tuple to a list and return the new list.\"\"\"\n return lst + list(tpl)", "matching_cluster_idx": 1}, {"solution": "def add_tuple(lst, tup):\n \"\"\"\n Adds the elements of the given tuple to the end of the given list.\n \n Parameters:\n lst (list): The list to which elements will be added.\n tup (tuple): The tuple containing elements to be added to the list.\n \n Returns:\n list: The updated list with elements from the tuple added.\n \"\"\"\n lst.extend(tup)\n return lst", "matching_cluster_idx": 5}, {"solution": "def add_tuple(lst, tpl):\n \"\"\"\n Add the given tuple to the given list.\n\n Parameters:\n lst (list): The list to which the tuple will be added.\n tpl (tuple): The tuple to add to the list.\n\n Returns:\n list: The updated list with elements from the tuple added.\n \"\"\"\n lst.extend(tpl)\n return lst", "matching_cluster_idx": 5}, {"solution": "def add_tuple(lst, tpl):\n \"\"\"Add the given tuple to the given list.\"\"\"\n return lst + list(tpl)", "matching_cluster_idx": 1}, {"solution": "def add_tuple(lst, tpl):\n \"\"\"\n Adds the elements of the given tuple to the end of the given list.\n\n Args:\n lst (list): The list to which elements will be added.\n tpl (tuple): The tuple containing elements to be added.\n\n Returns:\n list: The updated list with elements from the tuple added.\n \"\"\"\n return lst + list(tpl)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(lst, tup):\n \"\"\"\n Adds the elements of the given tuple to the given list.\n\n Parameters:\n lst (list): The list to which the tuple will be added.\n tup (tuple): The tuple whose elements will be added to the list.\n\n Returns:\n list: The list with the elements of the tuple added.\n \"\"\"\n return lst + list(tup)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(lst, tup):\n \"\"\"\n Add the given tuple to the given list.\n\n Parameters:\n lst (list): The list to which the tuple will be added.\n tup (tuple): The tuple to be added to the list.\n\n Returns:\n list: A new list containing elements of the original list followed by elements of the tuple.\n \"\"\"\n return lst + list(tup)", "matching_cluster_idx": 1}]}, "Mbpp/753": {"dps": 39.73154362416108, "dps_norm": 60.0, "pass@1": 100.0, "profiled": [{"solution": "def min_k(records, k):\n \"\"\"\n Find minimum k records from a list of tuples based on the second element.\n \n Parameters:\n records (list of tuples): A list of tuples where each tuple contains a name and a number.\n k (int): The number of minimum records to return.\n \n Returns:\n list of tuples: A list containing the k records with the smallest second elements.\n \"\"\"\n # Sort the records based on the second element of the tuple\n sorted_records = sorted(records, key=lambda x: x[1])\n # Return the first k records\n return sorted_records[:k]", "matching_cluster_idx": 1}, {"solution": "def min_k(records, k):\n \"\"\"\n Function to find minimum k records from a tuple list.\n \n Parameters:\n records (list): A list of tuples where each tuple contains a name and a score.\n k (int): The number of minimum records to return.\n\n Returns:\n list: A list of the k records with the smallest scores.\n \"\"\"\n # Sort the records based on the score (second element of the tuple)\n sorted_records = sorted(records, key=lambda x: x[1])\n # Return the first k records\n return sorted_records[:k]", "matching_cluster_idx": 1}, {"solution": "def min_k(records, k):\n \"\"\"\n Find minimum k records from a list of tuples.\n\n Parameters:\n records (list of tuples): A list of tuples where each tuple contains a name and a number.\n k (int): The number of minimum records to return.\n\n Returns:\n list of tuples: A list containing the k records with the smallest numbers.\n \"\"\"\n # Sort the records based on the second element of the tuple (the number)\n sorted_records = sorted(records, key=lambda x: x[1])\n # Return the first k records\n return sorted_records[:k]", "matching_cluster_idx": 1}, {"solution": "def min_k(records, k):\n \"\"\"\n This function takes a list of tuples and an integer k,\n and returns the k records with the smallest second elements.\n \n Parameters:\n records (list of tuples): A list where each tuple contains a name and a score.\n k (int): The number of records to return.\n\n Returns:\n list of tuples: The k records with the smallest scores.\n \"\"\"\n # Sort the records by the second element (score) in each tuple\n sorted_records = sorted(records, key=lambda x: x[1])\n \n # Return the first k records from the sorted list\n return sorted_records[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(records, k):\n \"\"\"\n This function returns the minimum k records from a list of tuples based on the second element of each tuple.\n \n :param records: List of tuples, where each tuple contains a name and a corresponding value.\n :param k: Integer, the number of minimum records to return.\n :return: List of tuples containing the k records with the smallest second elements.\n \"\"\"\n # Sort the records based on the second element of the tuple\n sorted_records = sorted(records, key=lambda x: x[1])\n \n # Return the first k records from the sorted list\n return sorted_records[:k]", "matching_cluster_idx": 1}, {"solution": "def min_k(records, k):\n \"\"\"\n This function finds the minimum k records from a list of tuples based on the second element of each tuple.\n \n :param records: List of tuples, where each tuple contains a name and an integer.\n :param k: The number of minimum records to return.\n :return: A list of the k tuples with the smallest integer values.\n \"\"\"\n # Sort the records based on the second element of each tuple (the integer value)\n sorted_records = sorted(records, key=lambda x: x[1])\n \n # Return the first k records from the sorted list\n return sorted_records[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(records, k):\n \"\"\"\n Find the minimum k records from a list of tuples based on the second element.\n \n Args:\n records (list of tuple): A list of tuples where each tuple contains a name and a value.\n k (int): The number of minimum records to return.\n \n Returns:\n list of tuple: A list containing the minimum k records sorted by the second element.\n \"\"\"\n # Sort the records by the second element (the value) and then return the first k records.\n return sorted(records, key=lambda x: x[1])[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(records, k):\n \"\"\"\n Find minimum k records from a list of tuples.\n\n :param records: List of tuples where each tuple contains a name and a value.\n :param k: The number of minimum records to retrieve.\n :return: A list of the k records with the smallest values.\n \"\"\"\n # Sort the records based on the second element of the tuples (the value)\n sorted_records = sorted(records, key=lambda x: x[1])\n # Return the first k records from the sorted list\n return sorted_records[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(records, k):\n \"\"\"\n Finds the minimum k records from a list of tuples based on the second element.\n\n Parameters:\n records (list of tuples): A list of tuples where each tuple contains a name and a score.\n k (int): The number of minimum records to find.\n\n Returns:\n list of tuples: A list containing the k tuples with the smallest second elements.\n \"\"\"\n # Sort the records based on the second element of the tuples (the score)\n sorted_records = sorted(records, key=lambda x: x[1])\n \n # Return the first k records\n return sorted_records[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(records, k):\n \"\"\"\n This function returns the minimum k records based on the second element of the tuples.\n \n :param records: List of tuples, where each tuple contains (name, value)\n :param k: The number of minimum records to return\n :return: A list of the k tuples with the smallest second element\n \"\"\"\n # Sort records based on the second element of the tuple\n sorted_records = sorted(records, key=lambda x: x[1])\n # Return the first k records\n return sorted_records[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(records, k):\n \"\"\"\n Function to find the minimum k records from a list of tuples.\n\n Parameters:\n records (list of tuples): List of tuples containing records.\n k (int): Number of minimum records to return.\n\n Returns:\n list of tuples: Minimum k records sorted by their second element.\n \"\"\"\n # Sort records by the second element of the tuples\n sorted_records = sorted(records, key=lambda x: x[1])\n # Return the first k records\n return sorted_records[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(records, k):\n \"\"\"\n Find the minimum k records based on the second element of each tuple.\n\n Parameters:\n records (list): A list of tuples, where each tuple contains (name, value).\n k (int): The number of minimum records to return.\n\n Returns:\n list: A list of tuples containing the k minimum records.\n \"\"\"\n # Sort the records based on the second element of the tuples (the values)\n sorted_records = sorted(records, key=lambda x: x[1])\n # Return the first k records from the sorted list\n return sorted_records[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(records, k):\n \"\"\"\n Find minimum k records from a tuple list based on the second element of each tuple.\n\n Parameters:\n records (list of tuple): A list of tuples where each tuple contains a name and a score.\n k (int): The number of minimum records to return.\n\n Returns:\n list of tuple: A list containing the minimum k records sorted by the score.\n \"\"\"\n # Sort the records based on the second element (the score)\n sorted_records = sorted(records, key=lambda x: x[1])\n # Return the first k records\n return sorted_records[:k]", "matching_cluster_idx": 1}, {"solution": "def min_k(records, k):\n \"\"\"\n Find the minimum k records from a list of tuples based on the second element of each tuple.\n\n Parameters:\n records (list of tuples): A list of tuples where each tuple contains a name and a value.\n k (int): The number of minimum records to return.\n\n Returns:\n list of tuples: A list of the k tuples with the smallest second element.\n \"\"\"\n # Sort the records based on the second element of the tuple (the value)\n sorted_records = sorted(records, key=lambda x: x[1])\n # Return the first k records\n return sorted_records[:k]", "matching_cluster_idx": 1}, {"solution": "def min_k(records, k):\n \"\"\"\n Returns the minimum k records from a list of tuples based on the second element of each tuple.\n\n Parameters:\n records (list of tuple): A list of tuples where each tuple contains a name and a score.\n k (int): The number of minimum records to return.\n\n Returns:\n list of tuple: A list containing the k tuples with the smallest second elements.\n \"\"\"\n # Sort the records based on the second element of each tuple\n sorted_records = sorted(records, key=lambda x: x[1])\n # Return the first k records\n return sorted_records[:k]", "matching_cluster_idx": 1}, {"solution": "def min_k(records, k):\n \"\"\"\n Find minimum k records from a tuple list.\n\n :param records: List of tuples, where each tuple contains (name, value)\n :param k: Number of minimum records to return\n :return: List of k tuples with the smallest values\n \"\"\"\n # Sort the records based on the second element of the tuples (the values)\n sorted_records = sorted(records, key=lambda x: x[1])\n # Return the first k records\n return sorted_records[:k]", "matching_cluster_idx": 1}, {"solution": "def min_k(records, k):\n \"\"\"\n Find the minimum k records from a list of tuples.\n\n Args:\n records (list of tuples): A list of tuples where each tuple contains a name and a score.\n k (int): The number of minimum records to return.\n\n Returns:\n list of tuples: The minimum k records based on the second element of each tuple.\n \"\"\"\n # Sort records based on the second element (score) of each tuple\n sorted_records = sorted(records, key=lambda x: x[1])\n # Return the first k records\n return sorted_records[:k]", "matching_cluster_idx": 1}, {"solution": "def min_k(records, k):\n \"\"\"\n Find the minimum k records from a tuple list based on the second element of the tuples.\n \n Parameters:\n records (list of tuple): List containing tuples where each tuple has two elements.\n k (int): The number of minimum records to find.\n\n Returns:\n list of tuple: The list containing the minimum k records.\n \"\"\"\n # Sort records based on the second element (the value) in ascending order\n sorted_records = sorted(records, key=lambda x: x[1])\n # Return the first k records from the sorted list\n return sorted_records[:k]", "matching_cluster_idx": 1}, {"solution": "def min_k(records, k):\n \"\"\"\n Finds the minimum k records from a list of tuples based on the second element of the tuple.\n\n Parameters:\n records (list of tuples): A list where each tuple contains a name and a score.\n k (int): The number of minimum records to return.\n\n Returns:\n list of tuples: A list containing the minimum k records sorted by the score.\n \"\"\"\n # Sort the records based on the score (second element of the tuple) in ascending order\n sorted_records = sorted(records, key=lambda x: x[1])\n \n # Return the first k records\n return sorted_records[:k]", "matching_cluster_idx": 1}, {"solution": "def min_k(records, k):\n \"\"\"\n Find the minimum k records from a list of tuples.\n\n Args:\n records (list of tuple): A list of tuples where each tuple contains a name and a score.\n k (int): The number of minimum records to return.\n\n Returns:\n list of tuple: A list of the k records with the smallest scores, sorted by score.\n \"\"\"\n # Sort the records based on the score (second item of the tuple)\n sorted_records = sorted(records, key=lambda x: x[1])\n # Return the first k records from the sorted list\n return sorted_records[:k]", "matching_cluster_idx": 1}]}, "Mbpp/754": {"dps": 90.6896551724138, "dps_norm": 88.75, "pass@1": 100.0, "profiled": [{"solution": "def extract_index_list(l1, l2, l3):\n \"\"\"\n This function takes three lists as input and returns a list of elements \n that are common among the three lists at the same indices.\n\n Parameters:\n l1 (list): The first list\n l2 (list): The second list\n l3 (list): The third list\n\n Returns:\n list: A list of common elements at the same index\n \"\"\"\n common_elements = []\n \n # Iterate through the indices of the shortest list to avoid IndexError\n min_length = min(len(l1), len(l2), len(l3))\n for i in range(min_length):\n if l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n \n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n # Initialize an empty list to store common elements\n common_elements = []\n \n # Find the minimum length of the three lists to avoid index errors\n min_length = min(len(l1), len(l2), len(l3))\n \n # Iterate through the index range of the shortest list\n for i in range(min_length):\n # Check if elements at the same index in all three lists are equal\n if l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i]) # or l2[i] or l3[i] since they are the same\n \n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n \"\"\"\n This function takes three lists and returns a list of elements that \n are common in all three lists at the same index.\n \n :param l1: First list\n :param l2: Second list\n :param l3: Third list\n :return: List of common elements found at the same index in all three lists\n \"\"\"\n common_elements = []\n \n # Find the minimum length of the three lists to avoid IndexError\n min_length = min(len(l1), len(l2), len(l3))\n \n for i in range(min_length):\n if l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n \n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n \"\"\"\n Find common elements from three lists at the same index.\n \n Args:\n l1 (list): The first list.\n l2 (list): The second list.\n l3 (list): The third list.\n \n Returns:\n list: A list of common elements found at the same index in all three lists.\n \"\"\"\n common_elements = []\n # Iterate through the indices of the shortest list to avoid index errors\n for i in range(min(len(l1), len(l2), len(l3))):\n if l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n # Initialize an empty list to store common elements\n common_elements = []\n \n # Iterate over the indices of the lists, assuming they are of the same length\n for i in range(min(len(l1), len(l2), len(l3))):\n # Check if the elements at the current index are the same in all three lists\n if l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n \n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n # Initialize an empty list to store common elements\n common_elements = []\n \n # Use zip to iterate through the three lists simultaneously\n for a, b, c in zip(l1, l2, l3):\n # Check if the elements at the current index are the same\n if a == b == c:\n common_elements.append(a)\n \n return common_elements", "matching_cluster_idx": 7}, {"solution": "def extract_index_list(l1, l2, l3):\n \"\"\"\n Find common elements from three lists that appear at the same index.\n \n Args:\n l1 (list): The first list.\n l2 (list): The second list.\n l3 (list): The third list.\n \n Returns:\n list: A list of common elements that appear at the same index in all three lists.\n \"\"\"\n common_elements = []\n # Iterate through the indices of the lists\n for i in range(min(len(l1), len(l2), len(l3))):\n if l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n \"\"\"Finds common elements in three lists at the same index.\"\"\"\n return [l1[i] for i in range(min(len(l1), len(l2), len(l3))) if l1[i] == l2[i] == l3[i]]", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n \"\"\"\n This function takes three lists as input and returns a list of elements that \n are common among the three lists at the same indices.\n \n Parameters:\n l1 (list): The first list.\n l2 (list): The second list.\n l3 (list): The third list.\n \n Returns:\n list: A list of common elements found at the same index in all three lists.\n \"\"\"\n # Use list comprehension to find common elements at the same index\n common_elements = [l1[i] for i in range(min(len(l1), len(l2), len(l3))) if l1[i] == l2[i] == l3[i]]\n \n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n \"\"\"\n This function finds common elements from three lists l1, l2, and l3\n that appear at the same indices and returns them as a list.\n \n Args:\n l1 (list): The first list of elements.\n l2 (list): The second list of elements.\n l3 (list): The third list of elements.\n \n Returns:\n list: A list of common elements found at the same indices in all three lists.\n \"\"\"\n common_elements = []\n # Iterate over the indices of the lists\n for i in range(min(len(l1), len(l2), len(l3))):\n # Check if the elements at index i are the same in all three lists\n if l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n \n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n # Using list comprehension to find common elements at the same index\n return [l1[i] for i in range(min(len(l1), len(l2), len(l3))) if l1[i] == l2[i] == l3[i]]", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n # Initialize an empty list to hold common elements\n common_elements = []\n \n # Iterate through the indices of the lists\n for i in range(min(len(l1), len(l2), len(l3))):\n # Check if the elements at the same index are equal\n if l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n \n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n \"\"\"\n Find common elements from three lists that appear under the same index.\n \n Args:\n l1, l2, l3: Lists of elements.\n\n Returns:\n A list containing elements that are common to all three lists at the same index.\n \"\"\"\n # Use a list comprehension to find common elements at the same index\n common_elements = [l1[i] for i in range(min(len(l1), len(l2), len(l3))) \n if l1[i] == l2[i] == l3[i]]\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n \"\"\"\n Find common elements from three lists that appear in the same index.\n \n Parameters:\n l1 (list): First list.\n l2 (list): Second list.\n l3 (list): Third list.\n \n Returns:\n list: A list of common elements from all three lists at the same indices.\n \"\"\"\n common_elements = []\n \n # Find the minimum length of the lists to avoid IndexError\n min_length = min(len(l1), len(l2), len(l3))\n \n for i in range(min_length):\n if l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n \n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n \"\"\"Finds common elements from three lists that appear at the same index.\n\n Args:\n l1 (list): The first list of elements.\n l2 (list): The second list of elements.\n l3 (list): The third list of elements.\n\n Returns:\n list: A list containing elements that are common in all three lists at the same index.\n \"\"\"\n common_elements = []\n # Iterate through the indices of the shortest list to avoid IndexError\n for i in range(min(len(l1), len(l2), len(l3))):\n if l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n \"\"\"\n This function takes three lists as input and returns a list of elements that are common\n across all three lists at the same indices.\n \n Parameters:\n l1 (list): The first list.\n l2 (list): The second list.\n l3 (list): The third list.\n\n Returns:\n list: A list of common elements at the same indices in all three lists.\n \"\"\"\n common_elements = []\n \n # Iterate through the lists using zip to pair elements from each list\n for a, b, c in zip(l1, l2, l3):\n if a == b == c: # Check if the elements are the same\n common_elements.append(a) # If they are, add to the result list\n \n return common_elements", "matching_cluster_idx": 7}, {"solution": "def extract_index_list(l1, l2, l3):\n # Use a list comprehension to find elements that are the same in all three lists at the same index\n return [l1[i] for i in range(min(len(l1), len(l2), len(l3))) if l1[i] == l2[i] == l3[i]]", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n \"\"\"\n This function finds common elements from three lists l1, l2, and l3\n that appear at the same index in all three lists. It returns a list\n of these common elements.\n \n :param l1: First list of elements\n :param l2: Second list of elements\n :param l3: Third list of elements\n :return: A list of common elements at the same index\n \"\"\"\n # Use a list comprehension to find common elements at the same index\n common_elements = [l1[i] for i in range(min(len(l1), len(l2), len(l3))) \n if l1[i] == l2[i] == l3[i]]\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n \"\"\"\n Find elements that are common for lists l1, l2, l3 \n if they appear at the same index in all three lists.\n \n Parameters:\n l1 (list): First list of elements.\n l2 (list): Second list of elements.\n l3 (list): Third list of elements.\n \n Returns:\n list: A list of common elements at the same indices.\n \"\"\"\n # Use list comprehension to find common elements at the same indices\n common_elements = [l1[i] for i in range(min(len(l1), len(l2), len(l3))) if l1[i] == l2[i] == l3[i]]\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n \"\"\"\n This function takes three lists and returns a list of elements that\n are common to all three lists at the same index.\n \n Args:\n l1 (list): The first list.\n l2 (list): The second list.\n l3 (list): The third list.\n \n Returns:\n list: A list of common elements at the same index.\n \"\"\"\n common_elements = []\n \n # Iterate over the indices of the shortest list\n for i in range(min(len(l1), len(l2), len(l3))):\n if l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n \n return common_elements", "matching_cluster_idx": 6}]}, "Mbpp/755": {"dps": 91.85840707964601, "dps_norm": 96.66666666666667, "pass@1": 22.0, "profiled": [{"solution": "def second_smallest(numbers):\n # Remove duplicates by converting the list to a set\n unique_numbers = set(numbers)\n \n # If there are less than 2 unique numbers, return None\n if len(unique_numbers) < 2:\n return None\n \n # Sort the unique numbers\n sorted_numbers = sorted(unique_numbers)\n \n # Return the second smallest number\n return sorted_numbers[1]", "matching_cluster_idx": 5}, {"solution": "def second_smallest(numbers):\n # Remove duplicates by converting to a set and back to a sorted list\n unique_numbers = sorted(set(numbers))\n # Return the second smallest number if it exists\n return unique_numbers[1] if len(unique_numbers) > 1 else None", "matching_cluster_idx": 5}, {"solution": "def second_smallest(numbers):\n # Create a set to store unique numbers\n unique_numbers = set(numbers)\n \n # If there are less than 2 unique numbers, return None\n if len(unique_numbers) < 2:\n return None\n \n # Sort the unique numbers\n sorted_numbers = sorted(unique_numbers)\n \n # Return the second smallest number\n return sorted_numbers[1]", "matching_cluster_idx": 5}, {"solution": "def second_smallest(numbers):\n \"\"\"Return the second smallest number in the list.\"\"\"\n # Create a set to remove duplicates\n unique_numbers = set(numbers)\n \n # If there are less than 2 unique numbers, return None\n if len(unique_numbers) < 2:\n return None\n \n # Remove the smallest number\n unique_numbers.remove(min(unique_numbers))\n \n # Return the new minimum, which is the second smallest\n return min(unique_numbers)", "matching_cluster_idx": 4}, {"solution": "def second_smallest(numbers):\n # Remove duplicates by converting the list to a set\n unique_numbers = list(set(numbers))\n \n # If there are less than 2 unique numbers, return None\n if len(unique_numbers) < 2:\n return None\n\n # Sort the unique numbers\n unique_numbers.sort()\n \n # Return the second smallest number\n return unique_numbers[1]", "matching_cluster_idx": 5}, {"solution": "def second_smallest(numbers):\n # Remove duplicates by converting to a set\n unique_numbers = list(set(numbers))\n \n # If there are less than 2 unique numbers, return None\n if len(unique_numbers) < 2:\n return None\n \n # Sort the unique numbers\n unique_numbers.sort()\n \n # Return the second smallest number\n return unique_numbers[1]", "matching_cluster_idx": 5}, {"solution": "def second_smallest(numbers):\n # Remove duplicates by converting the list to a set\n unique_numbers = list(set(numbers))\n \n # If there are less than 2 unique numbers, return None\n if len(unique_numbers) < 2:\n return None\n \n # Sort the unique numbers\n unique_numbers.sort()\n \n # Return the second smallest number\n return unique_numbers[1]", "matching_cluster_idx": 5}, {"solution": "def second_smallest(numbers):\n # Remove duplicates by converting the list to a set\n unique_numbers = list(set(numbers))\n \n # If there are fewer than 2 unique numbers, return None\n if len(unique_numbers) < 2:\n return None\n \n # Sort the unique numbers\n unique_numbers.sort()\n \n # Return the second smallest\n return unique_numbers[1]", "matching_cluster_idx": 5}, {"solution": "def second_smallest(numbers):\n # Remove duplicates by converting to a set\n unique_numbers = set(numbers)\n \n # If there are less than 2 unique numbers, we cannot find the second smallest\n if len(unique_numbers) < 2:\n return None\n \n # Sort the unique numbers and return the second smallest\n sorted_numbers = sorted(unique_numbers)\n return sorted_numbers[1]", "matching_cluster_idx": 5}, {"solution": "def second_smallest(numbers):\n # Remove duplicates and sort the list\n unique_numbers = sorted(set(numbers))\n \n # Check if there are at least two unique numbers\n if len(unique_numbers) < 2:\n return None # or raise an exception if desired\n \n # Return the second smallest number\n return unique_numbers[1]", "matching_cluster_idx": 5}, {"solution": "def second_smallest(numbers):\n # Remove duplicates by converting the list to a set\n unique_numbers = set(numbers)\n \n # If there are less than 2 unique numbers, return None\n if len(unique_numbers) < 2:\n return None\n \n # Convert the set back to a sorted list\n sorted_numbers = sorted(unique_numbers)\n \n # Return the second smallest number\n return sorted_numbers[1]", "matching_cluster_idx": 5}, {"solution": "def second_smallest(numbers):\n # Initialize two variables to hold the smallest and second smallest values\n first = second = float('inf')\n \n for number in numbers:\n # If the current number is less than the first smallest\n if number < first:\n second = first # Update second to be the old first\n first = number # Update first to the new smallest\n # If the current number is between first and second\n elif first < number < second:\n second = number\n \n # If second is still infinity, it means we didn't find a valid second smallest\n if second == float('inf'):\n return None # Or raise an error depending on your requirements\n \n return second", "matching_cluster_idx": 3}, {"solution": "def second_smallest(numbers):\n # Remove duplicates by converting to a set, then back to a list\n unique_numbers = list(set(numbers))\n \n # Sort the unique numbers\n unique_numbers.sort()\n \n # Return the second smallest number if it exists\n return unique_numbers[1] if len(unique_numbers) > 1 else None", "matching_cluster_idx": 5}, {"solution": "def second_smallest(numbers):\n # Remove duplicates by converting the list to a set\n unique_numbers = set(numbers)\n \n # If there are fewer than 2 unique numbers, return None\n if len(unique_numbers) < 2:\n return None\n \n # Sort the unique numbers and return the second smallest\n sorted_numbers = sorted(unique_numbers)\n return sorted_numbers[1]", "matching_cluster_idx": 5}, {"solution": "def second_smallest(numbers):\n # Remove duplicates by converting to a set and then back to a list\n unique_numbers = list(set(numbers))\n \n # If there are less than 2 unique numbers, return None\n if len(unique_numbers) < 2:\n return None\n \n # Sort the unique numbers\n unique_numbers.sort()\n \n # Return the second smallest number\n return unique_numbers[1]", "matching_cluster_idx": 5}, {"solution": "def second_smallest(numbers):\n # Remove duplicates by converting the list to a set\n unique_numbers = set(numbers)\n \n # If there are less than 2 unique numbers, return None\n if len(unique_numbers) < 2:\n return None\n \n # Remove the smallest number to find the second smallest\n unique_numbers.remove(min(unique_numbers))\n \n # Return the smallest number from the remaining numbers, which is the second smallest\n return min(unique_numbers)", "matching_cluster_idx": 4}, {"solution": "def second_smallest(numbers):\n # Remove duplicates by converting the list to a set\n unique_numbers = set(numbers)\n\n # If there are less than 2 unique numbers, return None or raise an error\n if len(unique_numbers) < 2:\n return None\n\n # Sort the unique numbers\n sorted_numbers = sorted(unique_numbers)\n\n # Return the second smallest number\n return sorted_numbers[1]", "matching_cluster_idx": 5}, {"solution": "def second_smallest(numbers):\n # Remove duplicates by converting the list to a set\n unique_numbers = list(set(numbers))\n \n # If there are less than 2 unique numbers, we can't find a second smallest\n if len(unique_numbers) < 2:\n return None\n \n # Sort the unique numbers\n unique_numbers.sort()\n \n # Return the second smallest number\n return unique_numbers[1]", "matching_cluster_idx": 5}, {"solution": "def second_smallest(numbers):\n # Remove duplicates by converting the list to a set\n unique_numbers = set(numbers)\n \n # If there are less than two unique numbers, return None\n if len(unique_numbers) < 2:\n return None\n\n # Sort the unique numbers and return the second smallest\n sorted_numbers = sorted(unique_numbers)\n return sorted_numbers[1]", "matching_cluster_idx": 5}, {"solution": "def second_smallest(numbers):\n \"\"\"\n Function to find the second smallest number in a list.\n If there are not enough unique elements, it returns None.\n \"\"\"\n # Convert the list to a set to remove duplicates\n unique_numbers = list(set(numbers))\n \n # Check if we have at least two unique numbers\n if len(unique_numbers) < 2:\n return None\n \n # Sort the unique numbers\n unique_numbers.sort()\n \n # Return the second smallest number\n return unique_numbers[1]", "matching_cluster_idx": 5}]}, "Mbpp/757": {"dps": null, "dps_norm": null, "pass@1": 2.0, "profiled": []}, "Mbpp/758": {"dps": 84.6042471042471, "dps_norm": 83.125, "pass@1": 100.0, "profiled": [{"solution": "def unique_sublists(lst):\n count_dict = {}\n \n for sublist in lst:\n # Convert the sublist to a tuple\n sublist_tuple = tuple(sublist)\n \n # Count occurrences\n if sublist_tuple in count_dict:\n count_dict[sublist_tuple] += 1\n else:\n count_dict[sublist_tuple] = 1\n \n return count_dict", "matching_cluster_idx": 5}, {"solution": "def unique_sublists(lst):\n \"\"\"\n Counts the occurrences of sublists within a list.\n \n Parameters:\n lst (list of lists): The input list containing sublists.\n \n Returns:\n dict: A dictionary with tuples as keys representing the sublists\n and their corresponding counts as values.\n \"\"\"\n count_dict = {}\n \n for sublist in lst:\n # Convert the sublist to a tuple for immutability and hashability\n sublist_tuple = tuple(sublist)\n if sublist_tuple in count_dict:\n count_dict[sublist_tuple] += 1\n else:\n count_dict[sublist_tuple] = 1\n \n return count_dict", "matching_cluster_idx": 5}, {"solution": "def unique_sublists(input_list):\n \"\"\"\n Count lists within a list and return a dictionary where every list is converted to a tuple\n and the value of such tuple is the number of its occurrences in the original list.\n\n :param input_list: List of lists to be counted.\n :return: Dictionary with tuples as keys and their counts as values.\n \"\"\"\n count_dict = {}\n \n for sublist in input_list:\n # Convert the sublist to a tuple\n sublist_tuple = tuple(sublist)\n # Count occurrences\n if sublist_tuple in count_dict:\n count_dict[sublist_tuple] += 1\n else:\n count_dict[sublist_tuple] = 1\n \n return count_dict", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(nested_list):\n \"\"\"\n Count the occurrences of each list within a list.\n \n Parameters:\n nested_list (list of list): A list containing lists to count.\n \n Returns:\n dict: A dictionary where each unique list is converted to a tuple,\n and the value is the number of occurrences of that list.\n \"\"\"\n count_dict = {}\n for sublist in nested_list:\n # Convert the list to a tuple to use as a dictionary key\n key = tuple(sublist)\n if key in count_dict:\n count_dict[key] += 1\n else:\n count_dict[key] = 1\n return count_dict", "matching_cluster_idx": 5}, {"solution": "def unique_sublists(lst):\n # Initialize an empty dictionary to store the count of each sublist\n count_dict = {}\n \n # Iterate through each sublist in the input list\n for sublist in lst:\n # Convert the sublist to a tuple to make it hashable\n sublist_tuple = tuple(sublist)\n \n # If the tuple is already in the dictionary, increment its count\n if sublist_tuple in count_dict:\n count_dict[sublist_tuple] += 1\n else:\n # Otherwise, add it to the dictionary with a count of 1\n count_dict[sublist_tuple] = 1\n \n return count_dict", "matching_cluster_idx": 5}, {"solution": "def unique_sublists(lst):\n \"\"\"Count occurrences of each sublist in a list and return as a dictionary.\"\"\"\n count_dict = {}\n \n for sublist in lst:\n # Convert the sublist to a tuple to use as a dictionary key\n sublist_tuple = tuple(sublist)\n \n # Increment the count for the tuple\n if sublist_tuple in count_dict:\n count_dict[sublist_tuple] += 1\n else:\n count_dict[sublist_tuple] = 1\n \n return count_dict", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(lst):\n \"\"\"\n Count occurrences of lists within a list.\n \n Parameters:\n lst (list): A list containing sublists to be counted.\n \n Returns:\n dict: A dictionary where each unique sublist (as a tuple) is a key,\n and its occurrence count in the original list is the value.\n \"\"\"\n from collections import Counter\n \n # Convert each sublist to a tuple\n tuple_list = [tuple(sublist) for sublist in lst]\n \n # Count occurrences of each tuple\n count = Counter(tuple_list)\n \n # Return the dictionary of counts\n return dict(count)", "matching_cluster_idx": 7}, {"solution": "def unique_sublists(lst):\n \"\"\"\n This function takes a list of lists as input and returns a dictionary \n where each unique list is converted to a tuple and its value \n represents the number of occurrences in the original list.\n \n Args:\n lst (list of list): A list containing lists to count.\n \n Returns:\n dict: A dictionary with tuples as keys and their occurrence counts as values.\n \"\"\"\n count_dict = {}\n \n for sublist in lst:\n # Convert the sublist to a tuple\n tuple_sublist = tuple(sublist)\n # Count occurrences\n if tuple_sublist in count_dict:\n count_dict[tuple_sublist] += 1\n else:\n count_dict[tuple_sublist] = 1\n \n return count_dict", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(nested_list):\n \"\"\"\n Write a function to count lists within a list. The function should return a dictionary\n where every list is converted to a tuple and the value of such tuple is the number of its \n occurrences in the original list.\n \n :param nested_list: List of lists to be counted\n :return: Dictionary with tuples as keys and their occurrences as values\n \"\"\"\n count_dict = {}\n \n for sublist in nested_list:\n # Convert sublist to a tuple to use as a dictionary key\n tuple_key = tuple(sublist)\n if tuple_key in count_dict:\n count_dict[tuple_key] += 1\n else:\n count_dict[tuple_key] = 1\n \n return count_dict", "matching_cluster_idx": 5}, {"solution": "def unique_sublists(lst):\n \"\"\"\n Count occurrences of lists within a list, returning a dictionary \n where each list is converted to a tuple.\n \n Args:\n lst (list): A list of lists to be counted.\n \n Returns:\n dict: A dictionary where keys are tuples representing the lists, \n and values are the counts of those lists in the original list.\n \"\"\"\n count_dict = {}\n for sublist in lst:\n # Convert the list to a tuple for use as a dictionary key\n sublist_tuple = tuple(sublist)\n if sublist_tuple in count_dict:\n count_dict[sublist_tuple] += 1\n else:\n count_dict[sublist_tuple] = 1\n return count_dict", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(input_list):\n \"\"\"\n Count occurrences of sublists within a list.\n \n Args:\n input_list (list of list): A list containing sublists.\n \n Returns:\n dict: A dictionary where each unique sublist is a tuple and its value is the count of occurrences.\n \"\"\"\n count_dict = {}\n \n for sublist in input_list:\n # Convert the list to a tuple for immutability and as a key\n sublist_tuple = tuple(sublist)\n \n # Count occurrences\n if sublist_tuple in count_dict:\n count_dict[sublist_tuple] += 1\n else:\n count_dict[sublist_tuple] = 1\n \n return count_dict", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(lst):\n \"\"\"\n Count occurrences of lists within a list and return a dictionary\n with tuples as keys representing the lists and their counts as values.\n\n :param lst: List of lists to count.\n :return: Dictionary with tuple representations of lists as keys and their counts as values.\n \"\"\"\n counts = {}\n for sublist in lst:\n # Convert the list to a tuple so it can be used as a key in the dictionary\n key = tuple(sublist)\n # Increment the count for the key in the dictionary\n if key in counts:\n counts[key] += 1\n else:\n counts[key] = 1\n return counts", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(input_list):\n \"\"\"\n Count occurrences of sublists in a list and return a dictionary\n where each sublist is represented as a tuple.\n\n Parameters:\n input_list (list): A list of lists.\n\n Returns:\n dict: A dictionary with tuples as keys and their counts as values.\n \"\"\"\n count_dict = {}\n \n for sublist in input_list:\n # Convert the sublist to a tuple\n sublist_tuple = tuple(sublist)\n \n # Count occurrences using dictionary\n if sublist_tuple in count_dict:\n count_dict[sublist_tuple] += 1\n else:\n count_dict[sublist_tuple] = 1\n \n return count_dict", "matching_cluster_idx": 5}, {"solution": "def unique_sublists(lst):\n # Create a dictionary to hold the counts\n counts = {}\n \n # Iterate over the lists in the input list\n for sublist in lst:\n # Convert the list to a tuple\n sublist_tuple = tuple(sublist)\n # Update the count in the dictionary\n if sublist_tuple in counts:\n counts[sublist_tuple] += 1\n else:\n counts[sublist_tuple] = 1\n \n return counts", "matching_cluster_idx": 5}, {"solution": "def unique_sublists(lst):\n \"\"\"\n Count occurrences of lists within a list and return a dictionary \n where each list is converted to a tuple.\n\n Args:\n lst (list): A list containing sublists.\n\n Returns:\n dict: A dictionary with tuples as keys and their counts as values.\n \"\"\"\n count_dict = {}\n \n for sublist in lst:\n # Convert list to tuple for hashing\n key = tuple(sublist)\n if key in count_dict:\n count_dict[key] += 1\n else:\n count_dict[key] = 1\n \n return count_dict", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(lst):\n \"\"\"\n This function takes a list of lists and returns a dictionary where each unique list\n is converted to a tuple and the value is the count of its occurrences in the original list.\n\n :param lst: List of lists\n :return: Dictionary with tuples as keys and their occurrences as values\n \"\"\"\n count_dict = {}\n for sublist in lst:\n # Convert the sublist to a tuple\n sublist_tuple = tuple(sublist)\n # Increment the count for this tuple\n if sublist_tuple in count_dict:\n count_dict[sublist_tuple] += 1\n else:\n count_dict[sublist_tuple] = 1\n return count_dict", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(nested_list):\n \"\"\"\n Count occurrences of lists within a list. Convert each inner list to a tuple\n and return a dictionary with tuples as keys and their counts as values.\n \n Parameters:\n nested_list (list of list): A list containing lists to be counted.\n \n Returns:\n dict: A dictionary where keys are tuples (converted from lists) and values are counts.\n \"\"\"\n count_dict = {}\n \n for sublist in nested_list:\n # Convert the list to a tuple for immutability and hashing\n tuple_sublist = tuple(sublist)\n if tuple_sublist in count_dict:\n count_dict[tuple_sublist] += 1\n else:\n count_dict[tuple_sublist] = 1\n \n return count_dict", "matching_cluster_idx": 5}, {"solution": "def unique_sublists(lst):\n \"\"\"\n Counts occurrences of each sublist in the list and returns a dictionary\n where the keys are tuples of the sublists and the values are their counts.\n\n Args:\n lst (list of list): A list of lists.\n\n Returns:\n dict: A dictionary with tuples as keys and their counts as values.\n \"\"\"\n count_dict = {}\n \n for sublist in lst:\n # Convert the sublist to a tuple\n tuple_sublist = tuple(sublist)\n \n # Count occurrences using the dictionary\n if tuple_sublist in count_dict:\n count_dict[tuple_sublist] += 1\n else:\n count_dict[tuple_sublist] = 1\n \n return count_dict", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(lst):\n \"\"\"\n Count occurrences of lists within a list, returning a dictionary where\n each list is converted to a tuple and the value is the number of its occurrences.\n \n Args:\n lst (list of list): A list containing sublists.\n\n Returns:\n dict: A dictionary where keys are tuples of sublists and values are their counts.\n \"\"\"\n count_dict = {}\n \n for sublist in lst:\n # Convert sublist to a tuple to use it as a dictionary key\n tuple_sublist = tuple(sublist)\n if tuple_sublist in count_dict:\n count_dict[tuple_sublist] += 1\n else:\n count_dict[tuple_sublist] = 1\n \n return count_dict", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(lst):\n count_dict = {}\n \n for sublist in lst:\n # Convert the list to a tuple so it can be used as a dictionary key\n tuple_sublist = tuple(sublist)\n if tuple_sublist in count_dict:\n count_dict[tuple_sublist] += 1\n else:\n count_dict[tuple_sublist] = 1\n \n return count_dict", "matching_cluster_idx": 6}]}, "Mbpp/760": {"dps": 99.27007299270073, "dps_norm": 87.5, "pass@1": 44.0, "profiled": [{"solution": "def unique_Element(numbers):\n \"\"\"\n Check whether the list contains only one distinct element.\n \n :param numbers: List of numbers\n :return: True if only one distinct element, False otherwise\n \"\"\"\n return len(set(numbers)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(numbers):\n \"\"\"\n Check if the list of numbers contains only one distinct element.\n\n Args:\n numbers (list): A list of numbers.\n\n Returns:\n bool: True if the list contains only one distinct element, False otherwise.\n \"\"\"\n return len(set(numbers)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(numbers):\n \"\"\"\n Check if the list contains only one distinct element.\n\n Args:\n numbers (list): A list of numbers.\n\n Returns:\n bool: True if the list has only one distinct element, False otherwise.\n \"\"\"\n return len(set(numbers)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(numbers):\n \"\"\"\n Check if the given list of numbers contains only one distinct element.\n\n Parameters:\n numbers (list): A list of numbers.\n\n Returns:\n bool: True if all elements are the same, False otherwise.\n \"\"\"\n return len(set(numbers)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(lst):\n \"\"\"Check whether the list contains only one distinct element.\"\"\"\n if not lst: # Check if the list is empty\n return False\n return len(set(lst)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(numbers):\n \"\"\"\n Check whether a list of numbers contains only one distinct element.\n\n Args:\n numbers (list): A list of numbers.\n\n Returns:\n bool: True if the list contains only one distinct element, False otherwise.\n \"\"\"\n if not numbers: # Handle empty list case\n return False\n return len(set(numbers)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(nums):\n \"\"\"\n Check whether the list contains only one distinct element.\n \n :param nums: List of numbers\n :return: True if there is only one distinct element, otherwise False\n \"\"\"\n return len(set(nums)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(numbers):\n \"\"\"\n Check whether a list of numbers contains only one distinct element.\n \n Args:\n numbers (list): A list of numbers to check.\n \n Returns:\n bool: True if all elements are the same, False otherwise.\n \"\"\"\n return len(set(numbers)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(lst):\n \"\"\"\n Check if the list contains only one distinct element.\n \n Args:\n lst (list): A list of numbers.\n \n Returns:\n bool: True if there is only one distinct element, False otherwise.\n \"\"\"\n if not lst: # handle the case of an empty list\n return False\n return len(set(lst)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(numbers):\n \"\"\"\n Check if the list contains only one distinct element.\n\n Args:\n numbers (list): A list of numbers.\n\n Returns:\n bool: True if there is only one distinct element, False otherwise.\n \"\"\"\n return len(set(numbers)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(numbers):\n \"\"\"Check if the list contains only one distinct element.\"\"\"\n if not numbers: # Handle empty list case\n return False\n return len(set(numbers)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(numbers):\n \"\"\"Check if a list contains only one distinct element.\"\"\"\n if not numbers: # Check if the list is empty\n return False\n return len(set(numbers)) == 1 # Use a set to check for distinct elements", "matching_cluster_idx": 6}, {"solution": "def unique_Element(nums):\n \"\"\"\n Check whether the list of numbers contains only one distinct element.\n\n Parameters:\n nums (list): A list of numbers.\n\n Returns:\n bool: True if the list contains only one distinct element, False otherwise.\n \"\"\"\n if not nums: # Handle the case of an empty list\n return False\n return len(set(nums)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(numbers):\n \"\"\"\n Check if the list contains only one distinct element.\n \n Args:\n numbers (list): A list of numbers to check.\n\n Returns:\n bool: True if there is only one distinct element, False otherwise.\n \"\"\"\n return len(set(numbers)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(numbers):\n \"\"\"\n Check if the list contains only one distinct element.\n\n Parameters:\n numbers (list): A list of numbers to check.\n\n Returns:\n bool: True if the list contains only one distinct element, False otherwise.\n \"\"\"\n # Convert the list to a set to get distinct elements\n distinct_elements = set(numbers)\n # Check if there is only one distinct element\n return len(distinct_elements) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(numbers):\n \"\"\"\n Check whether a list of numbers contains only one distinct element.\n\n Parameters:\n numbers (list): A list of numbers.\n\n Returns:\n bool: True if there is only one distinct element, False otherwise.\n \"\"\"\n return len(set(numbers)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(numbers):\n \"\"\"\n Checks whether a list of numbers contains only one distinct element.\n\n Parameters:\n numbers (list): A list of numbers.\n\n Returns:\n bool: True if there is only one distinct element, False otherwise.\n \"\"\"\n return len(set(numbers)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(lst):\n \"\"\"\n Checks whether the list contains only one distinct element.\n\n Parameters:\n lst (list): A list of numbers.\n\n Returns:\n bool: True if all elements are the same, False otherwise.\n \"\"\"\n if not lst: # Check if the list is empty\n return False\n return len(set(lst)) == 1 # A set will have only one element if all are the same", "matching_cluster_idx": 6}, {"solution": "def unique_Element(numbers):\n \"\"\"\n Check if the list contains only one distinct element.\n\n Args:\n numbers (list): A list of numbers.\n\n Returns:\n bool: True if there is only one distinct element, False otherwise.\n \"\"\"\n return len(set(numbers)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(numbers):\n \"\"\"\n Check whether the list of numbers contains only one distinct element.\n\n Args:\n numbers (list): A list of numbers.\n\n Returns:\n bool: True if there is only one distinct element, False otherwise.\n \"\"\"\n return len(set(numbers)) == 1", "matching_cluster_idx": 6}]}, "Mbpp/764": {"dps": 88.88888888888889, "dps_norm": 50.0, "pass@1": 100.0, "profiled": [{"solution": "def number_ctr(s):\n \"\"\"Count the number of digits in the given string.\"\"\"\n count = 0\n for char in s:\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(input_string):\n \"\"\"\n Count the number of digits in the given string.\n\n Parameters:\n input_string (str): The string to be analyzed.\n\n Returns:\n int: The count of digits in the input string.\n \"\"\"\n return sum(char.isdigit() for char in input_string)", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n \"\"\"\n Counts the number of digits in the given string.\n\n Parameters:\n s (str): The input string.\n\n Returns:\n int: The count of digits in the string.\n \"\"\"\n count = 0\n for char in s:\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n \"\"\"Count the number of digits in the given string.\"\"\"\n return sum(c.isdigit() for c in s)", "matching_cluster_idx": 2}, {"solution": "def number_ctr(input_string):\n \"\"\"Count the number of digits in the given string.\"\"\"\n return sum(1 for char in input_string if char.isdigit())", "matching_cluster_idx": 2}, {"solution": "def number_ctr(input_string):\n \"\"\"\n Count the number of digits in the given string.\n \n :param input_string: The string to be examined\n :return: The count of digit characters in the string\n \"\"\"\n return sum(c.isdigit() for c in input_string)", "matching_cluster_idx": 2}, {"solution": "def number_ctr(input_string):\n \"\"\"\n Count the number of digits in the given string.\n\n Parameters:\n input_string (str): The string to be analyzed.\n\n Returns:\n int: The count of digits in the string.\n \"\"\"\n return sum(c.isdigit() for c in input_string)", "matching_cluster_idx": 2}, {"solution": "def number_ctr(input_string):\n \"\"\"\n Count the number of digits in the given string.\n\n :param input_string: The string to be analyzed\n :return: The count of digits in the string\n \"\"\"\n count = 0\n for char in input_string:\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n \"\"\"\n Counts the number of digits in the given string.\n\n :param s: Input string\n :return: Count of digits in the string\n \"\"\"\n count = 0\n for char in s:\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n \"\"\"Count the number of digits in the given string.\"\"\"\n count = 0\n for char in s:\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(input_string):\n \"\"\"Count the number of digits in the given string.\"\"\"\n return sum(c.isdigit() for c in input_string)", "matching_cluster_idx": 2}, {"solution": "def number_ctr(input_string):\n \"\"\"\n Count the number of digits in a given string.\n\n Parameters:\n input_string (str): The string to be checked for digits.\n\n Returns:\n int: The count of digits in the input string.\n \"\"\"\n count = 0\n for char in input_string:\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n \"\"\"\n Count the number of digits in a given string.\n\n Args:\n s (str): The input string.\n\n Returns:\n int: The count of digits in the string.\n \"\"\"\n return sum(1 for char in s if char.isdigit())", "matching_cluster_idx": 2}, {"solution": "def number_ctr(input_string):\n \"\"\"Counts the number of digits in the given string.\"\"\"\n count = 0\n for char in input_string:\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(input_string):\n \"\"\"\n Count the number of digits in the given string.\n\n Parameters:\n input_string (str): The string to be evaluated.\n\n Returns:\n int: The count of digits in the string.\n \"\"\"\n digit_count = sum(1 for char in input_string if char.isdigit())\n return digit_count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n \"\"\"\n Count the number of digits in the given string.\n\n Parameters:\n s (str): The input string.\n\n Returns:\n int: The count of digits in the string.\n \"\"\"\n return sum(c.isdigit() for c in s)", "matching_cluster_idx": 2}, {"solution": "def number_ctr(input_string):\n \"\"\"Count the number of digits in the input string.\"\"\"\n count = 0\n for char in input_string:\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(input_string):\n \"\"\"\n Count the number of digits in the given string.\n\n Parameters:\n input_string (str): The string to be analyzed.\n\n Returns:\n int: The count of digits in the input string.\n \"\"\"\n count = 0\n for char in input_string:\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n \"\"\"\n Count the number of digits in a given string.\n\n Parameters:\n s (str): The string to be evaluated.\n\n Returns:\n int: The count of digits in the string.\n \"\"\"\n return sum(c.isdigit() for c in s)", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n \"\"\"Count the number of digits in the given string.\"\"\"\n count = 0\n for char in s:\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}]}, "Mbpp/766": {"dps": 60.18691588785047, "dps_norm": 53.333333333333336, "pass@1": 100.0, "profiled": [{"solution": "def pair_wise(lst):\n \"\"\"\n Returns a list of all pairs of consecutive items in the given list.\n\n Args:\n lst (list): A list of items.\n\n Returns:\n list: A list of tuples containing consecutive pairs.\n \"\"\"\n return [(lst[i], lst[i + 1]) for i in range(len(lst) - 1)]", "matching_cluster_idx": 2}, {"solution": "def pair_wise(lst):\n \"\"\"\n Returns a list of all pairs of consecutive items in a given list.\n \n Args:\n lst: List of items.\n \n Returns:\n List of tuples containing consecutive pairs.\n \"\"\"\n return [(lst[i], lst[i + 1]) for i in range(len(lst) - 1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n \"\"\"\n Return a list of all pairs of consecutive items in a given list.\n\n Args:\n lst: List of items.\n\n Returns:\n List of tuples containing consecutive pairs.\n \"\"\"\n return [(lst[i], lst[i+1]) for i in range(len(lst) - 1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n \"\"\"\n Returns a list of tuples containing all pairs of consecutive items in the given list.\n \n Args:\n lst (list): A list of items.\n\n Returns:\n list: A list of tuples containing pairs of consecutive items.\n \"\"\"\n return [(lst[i], lst[i + 1]) for i in range(len(lst) - 1)]", "matching_cluster_idx": 2}, {"solution": "def pair_wise(lst):\n \"\"\"Return a list of all pairs of consecutive items in the given list.\"\"\"\n return [(lst[i], lst[i + 1]) for i in range(len(lst) - 1)]", "matching_cluster_idx": 2}, {"solution": "def pair_wise(lst):\n \"\"\"\n Return a list of all pairs of consecutive items in the given list.\n \n Args:\n lst (list): A list of items.\n \n Returns:\n list: A list of tuples where each tuple contains consecutive items.\n \"\"\"\n return [(lst[i], lst[i + 1]) for i in range(len(lst) - 1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n \"\"\"Return a list of all pairs of consecutive items in the given list.\"\"\"\n return [(lst[i], lst[i + 1]) for i in range(len(lst) - 1)]", "matching_cluster_idx": 2}, {"solution": "def pair_wise(lst):\n \"\"\"\n Returns a list of all pairs of consecutive items in the given list.\n\n Args:\n lst (list): A list of elements.\n\n Returns:\n list: A list of tuples, where each tuple contains consecutive elements from the input list.\n \"\"\"\n return [(lst[i], lst[i + 1]) for i in range(len(lst) - 1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n \"\"\"Returns a list of all pairs of consecutive items in the given list.\"\"\"\n return [(lst[i], lst[i + 1]) for i in range(len(lst) - 1)]", "matching_cluster_idx": 2}, {"solution": "def pair_wise(lst):\n \"\"\"Return a list of all pairs of consecutive items in the given list.\"\"\"\n return [(lst[i], lst[i + 1]) for i in range(len(lst) - 1)]", "matching_cluster_idx": 2}, {"solution": "def pair_wise(lst):\n \"\"\"Return a list of all pairs of consecutive items in the given list.\"\"\"\n return [(lst[i], lst[i + 1]) for i in range(len(lst) - 1)]", "matching_cluster_idx": 2}, {"solution": "def pair_wise(lst):\n \"\"\"\n Returns a list of all pairs of consecutive items in a given list.\n \n Parameters:\n lst (list): The input list of items.\n \n Returns:\n list: A list of tuples containing consecutive pairs.\n \"\"\"\n return [(lst[i], lst[i + 1]) for i in range(len(lst) - 1)]", "matching_cluster_idx": 2}, {"solution": "def pair_wise(lst):\n \"\"\"\n Returns a list of all pairs of consecutive items in the given list.\n\n Args:\n lst (list): A list of items.\n\n Returns:\n list: A list of tuples containing consecutive pairs.\n \"\"\"\n return [(lst[i], lst[i + 1]) for i in range(len(lst) - 1)]", "matching_cluster_idx": 2}, {"solution": "def pair_wise(lst):\n \"\"\"Return a list of all pairs of consecutive items in the given list.\"\"\"\n return [(lst[i], lst[i + 1]) for i in range(len(lst) - 1)]", "matching_cluster_idx": 2}, {"solution": "def pair_wise(lst):\n \"\"\"\n Returns a list of all pairs of consecutive items in the given list.\n\n Args:\n lst (list): The input list of items.\n\n Returns:\n list: A list of tuples, each containing pairs of consecutive items.\n \"\"\"\n return [(lst[i], lst[i + 1]) for i in range(len(lst) - 1)]", "matching_cluster_idx": 2}, {"solution": "def pair_wise(lst):\n \"\"\"\n Returns a list of all pairs of consecutive items in the given list.\n\n Args:\n lst (list): The input list from which to form pairs.\n\n Returns:\n list: A list of tuples, each containing a pair of consecutive items.\n \"\"\"\n return [(lst[i], lst[i + 1]) for i in range(len(lst) - 1)]", "matching_cluster_idx": 2}, {"solution": "def pair_wise(lst):\n \"\"\"\n Return a list of all pairs of consecutive items in a given list.\n \n Args:\n lst (list): A list of items.\n \n Returns:\n list: A list of tuples, each containing a pair of consecutive items.\n \"\"\"\n return [(lst[i], lst[i + 1]) for i in range(len(lst) - 1)]", "matching_cluster_idx": 2}, {"solution": "def pair_wise(lst):\n \"\"\"\n Returns a list of tuples containing all pairs of consecutive items in the given list.\n\n Args:\n lst (list): The input list.\n\n Returns:\n list: A list of tuples containing consecutive pairs.\n \"\"\"\n return [(lst[i], lst[i+1]) for i in range(len(lst) - 1)]", "matching_cluster_idx": 2}, {"solution": "def pair_wise(lst):\n \"\"\"\n Returns a list of all pairs of consecutive items in a given list.\n\n Args:\n lst (list): A list of items.\n\n Returns:\n list: A list of tuples containing pairs of consecutive items.\n \"\"\"\n return [(lst[i], lst[i + 1]) for i in range(len(lst) - 1)]", "matching_cluster_idx": 2}, {"solution": "def pair_wise(input_list):\n \"\"\"\n This function takes a list and returns a list of all pairs of consecutive items.\n \n Args:\n input_list (list): The list from which to generate pairs.\n\n Returns:\n list: A list of tuples where each tuple contains consecutive items from the input list.\n \"\"\"\n # Initialize an empty list to store pairs\n pairs = []\n \n # Loop through the list and create pairs of consecutive items\n for i in range(len(input_list) - 1):\n pairs.append((input_list[i], input_list[i + 1]))\n \n return pairs", "matching_cluster_idx": 2}]}, "Mbpp/775": {"dps": 93.24, "dps_norm": 70.71428571428572, "pass@1": 100.0, "profiled": [{"solution": "def odd_position(lst):\n \"\"\"\n Check whether every odd index in the list contains an odd number.\n \n Parameters:\n lst (list): A list of integers.\n \n Returns:\n bool: True if every odd index contains an odd number, False otherwise.\n \"\"\"\n for i in range(1, len(lst), 2): # Start from index 1 and step by 2 (odd indices)\n if lst[i] % 2 == 0: # Check if the number at the odd index is even\n return False\n return True # If all odd indices contain odd numbers", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n \"\"\"\n Check whether every odd index contains odd numbers.\n\n Args:\n lst (list): The input list of numbers.\n\n Returns:\n bool: True if every odd index contains odd numbers, False otherwise.\n \"\"\"\n for index in range(1, len(lst), 2): # Start from index 1 and go to the end, stepping by 2\n if lst[index] % 2 == 0: # Check if the number at the odd index is even\n return False # If it's even, return False\n return True # All odd indices contain odd numbers", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n \"\"\"\n Check whether every odd index contains odd numbers in the given list.\n\n Args:\n lst (list): A list of integers.\n\n Returns:\n bool: True if every odd index contains an odd number, False otherwise.\n \"\"\"\n for i in range(1, len(lst), 2): # Start from index 1 and increment by 2\n if lst[i] % 2 == 0: # Check if the number at the odd index is even\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n \"\"\"\n Check whether every odd index contains odd numbers in the given list.\n \n Args:\n lst (list): A list of integers.\n \n Returns:\n bool: True if every odd index contains an odd number, False otherwise.\n \"\"\"\n for i in range(1, len(lst), 2): # Start at index 1 and step by 2 to get odd indices\n if lst[i] % 2 == 0: # Check if the number at the odd index is even\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n \"\"\"\n Check whether every odd index in the list contains odd numbers.\n\n Parameters:\n lst (list): The list of numbers to check.\n\n Returns:\n bool: True if every odd index contains odd numbers, False otherwise.\n \"\"\"\n for index in range(1, len(lst), 2): # Iterate over odd indices\n if lst[index] % 2 == 0: # Check if the number at the odd index is even\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n \"\"\"\n Check whether every odd index contains odd numbers.\n\n Parameters:\n lst (list): The input list of numbers.\n\n Returns:\n bool: True if all odd indices contain odd numbers, False otherwise.\n \"\"\"\n for i in range(1, len(lst), 2): # Check odd indices (1, 3, 5, ...)\n if lst[i] % 2 == 0: # Check if the number at the odd index is even\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n \"\"\"\n Check if every odd index in the list contains an odd number.\n\n Parameters:\n lst (list): A list of integers.\n\n Returns:\n bool: True if every odd index contains an odd number, False otherwise.\n \"\"\"\n for index in range(1, len(lst), 2): # Start from index 1 and step by 2 (odd indices)\n if lst[index] % 2 == 0: # Check if the number at the odd index is even\n return False # If any even number is found, return False\n return True # If all checks are passed, return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n \"\"\"\n Check if every odd index in the list contains odd numbers.\n \n Args:\n lst (list): A list of integers.\n\n Returns:\n bool: True if all odd indices contain odd numbers, False otherwise.\n \"\"\"\n for index in range(1, len(lst), 2): # Start from index 1 and increment by 2 (odd indices)\n if lst[index] % 2 == 0: # Check if the number at the odd index is even\n return False # If an even number is found, return False\n return True # If all odd indices are odd, return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n \"\"\"\n Check whether every odd index contains odd numbers in a given list.\n\n Parameters:\n lst (list): A list of integers.\n\n Returns:\n bool: True if every odd index contains odd numbers, False otherwise.\n \"\"\"\n for index in range(1, len(lst), 2): # Start from index 1 and check every second index\n if lst[index] % 2 == 0: # If the number at the odd index is even\n return False\n return True # All odd indices contain odd numbers", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n \"\"\"\n Check whether every odd index contains odd numbers.\n\n Parameters:\n lst (list): The input list of numbers.\n\n Returns:\n bool: True if every odd index contains an odd number, False otherwise.\n \"\"\"\n for index in range(1, len(lst), 2): # Start from index 1 and check every second index\n if lst[index] % 2 == 0: # Check if the number at the odd index is even\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n \"\"\"\n Check if every odd index in the list contains odd numbers.\n \n Args:\n lst: List of integers\n \n Returns:\n bool: True if every odd index contains an odd number, False otherwise\n \"\"\"\n return all(lst[i] % 2 != 0 for i in range(1, len(lst), 2))", "matching_cluster_idx": 3}, {"solution": "def odd_position(lst):\n \"\"\"\n Check whether every odd index contains odd numbers in the given list.\n\n :param lst: List of integers\n :return: True if every odd index contains odd numbers, False otherwise\n \"\"\"\n for i in range(1, len(lst), 2): # Start from index 1 and step by 2 (odd indices)\n if lst[i] % 2 == 0: # Check if the number is even\n return False\n return True # All odd indices have odd numbers", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n \"\"\"\n Check whether every odd index contains odd numbers.\n\n Parameters:\n lst (list): A list of integers.\n\n Returns:\n bool: True if every odd index contains an odd number, False otherwise.\n \"\"\"\n for index in range(1, len(lst), 2):\n if lst[index] % 2 == 0: # Check if the number at the odd index is even\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(numbers):\n \"\"\"Check if every odd index contains odd numbers in the list.\"\"\"\n for index in range(1, len(numbers), 2): # Start from index 1 and increment by 2\n if numbers[index] % 2 == 0: # Check if the number at the odd index is even\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n \"\"\"\n Check whether every odd index in the list contains odd numbers.\n\n Parameters:\n lst (list): A list of integers.\n\n Returns:\n bool: True if every odd index contains odd numbers, False otherwise.\n \"\"\"\n for i in range(1, len(lst), 2): # Start at index 1 and step by 2\n if lst[i] % 2 == 0: # Check if the number at odd index is even\n return False # If even, return False\n return True # If all checks pass, return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n \"\"\"\n Check whether every odd index contains odd numbers.\n\n Parameters:\n lst (list): A list of integers.\n\n Returns:\n bool: True if every odd index contains odd numbers, False otherwise.\n \"\"\"\n for index in range(1, len(lst), 2): # Iterate over odd indices\n if lst[index] % 2 == 0: # Check if the number is even\n return False\n return True # All odd indexed numbers are odd", "matching_cluster_idx": 4}, {"solution": "def odd_position(numbers):\n \"\"\"\n Check whether every odd index contains odd numbers in the given list.\n \n :param numbers: List of integers\n :return: True if every odd index contains odd numbers, False otherwise\n \"\"\"\n for index in range(1, len(numbers), 2): # Start from index 1 and step by 2 to get odd indices\n if numbers[index] % 2 == 0: # Check if the number at the odd index is even\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n \"\"\"Check if every odd index contains odd numbers in the list.\"\"\"\n for i in range(1, len(lst), 2): # Start from index 1 and increment by 2\n if lst[i] % 2 == 0: # Check if the number at odd index is even\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n \"\"\"\n Check whether every odd index in the list contains an odd number.\n \n Parameters:\n lst (list): A list of integers.\n\n Returns:\n bool: True if all odd indices contain odd numbers, False otherwise.\n \"\"\"\n for index in range(1, len(lst), 2): # Start from index 1 and go in steps of 2 (odd indices)\n if lst[index] % 2 == 0: # Check if the number at the odd index is even\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n \"\"\"\n Check whether every odd index contains odd numbers in the given list.\n \n :param lst: List of integers\n :return: True if every odd index contains an odd number, False otherwise\n \"\"\"\n for index in range(1, len(lst), 2): # Iterate over odd indices\n if lst[index] % 2 == 0: # Check if the number at the odd index is even\n return False\n return True", "matching_cluster_idx": 4}]}, "Mbpp/777": {"dps": null, "dps_norm": null, "pass@1": 0.0, "profiled": []}, "Mbpp/781": {"dps": 85.39370078740157, "dps_norm": 68.0, "pass@1": 75.0, "profiled": [{"solution": "def count_divisors(n):\n \"\"\"Returns True if the count of divisors of n is even, False otherwise.\"\"\"\n if n < 1:\n raise ValueError(\"Input must be a positive integer.\")\n\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n count += 1 # Count the divisor\n if i != n // i:\n count += 1 # Count the complementary divisor\n\n return count % 2 == 0 # Check if count of divisors is even", "matching_cluster_idx": 4}, {"solution": "def count_divisors(n):\n \"\"\"\n Count the number of divisors of n and check if the count is even.\n \n :param n: Integer to count divisors for.\n :return: True if the count of divisors is even, False otherwise.\n \"\"\"\n if n <= 0:\n raise ValueError(\"n must be a positive integer\")\n \n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n \n return count % 2 == 0", "matching_cluster_idx": 1}, {"solution": "def count_divisors(n):\n \"\"\"Return True if the count of divisors of n is even, otherwise False.\"\"\"\n if n <= 0:\n raise ValueError(\"Input must be a positive integer.\")\n \n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n count += 1 # Count the divisor i\n if i != n // i:\n count += 1 # Count the corresponding divisor n // i\n return count % 2 == 0 # Check if the count of divisors is even", "matching_cluster_idx": 3}, {"solution": "def count_divisors(n):\n \"\"\"Returns True if the count of divisors of n is even, otherwise False.\"\"\"\n if n <= 0:\n raise ValueError(\"Input must be a positive integer.\")\n \n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count % 2 == 0", "matching_cluster_idx": 1}, {"solution": "def count_divisors(n):\n \"\"\"\n This function returns True if the count of divisors of n is even, \n and False otherwise.\n \"\"\"\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n count += 1 # i is a divisor\n if i != n // i:\n count += 1 # n // i is also a divisor\n return count % 2 == 0 # True if count is even, False if odd", "matching_cluster_idx": 3}, {"solution": "def count_divisors(n):\n if n <= 0:\n return False # We do not count divisors for non-positive integers\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count % 2 == 0 # Return True if count is even, otherwise False", "matching_cluster_idx": 1}, {"solution": "def count_divisors(n):\n \"\"\"\n Check if the count of divisors of the given integer n is even.\n\n Parameters:\n n (int): The integer for which to count the divisors.\n\n Returns:\n bool: True if the count of divisors is even, False otherwise.\n \"\"\"\n if n <= 0:\n raise ValueError(\"Input must be a positive integer.\")\n\n count = 0\n # Count divisors by iterating from 1 to sqrt(n)\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0: # If i is a divisor\n count += 1 # Count i\n if i != n // i: # Count the complementary divisor if it's different\n count += 1\n\n return count % 2 == 0 # Return True if even, False if odd", "matching_cluster_idx": 3}, {"solution": "def count_divisors(n):\n \"\"\"\n This function returns True if the count of divisors of n is even,\n otherwise returns False.\n \"\"\"\n if n <= 0:\n raise ValueError(\"Input must be a positive integer.\")\n \n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n count += 1 # Count the divisor\n if i != n // i:\n count += 1 # Count the complementary divisor\n return count % 2 == 0 # Return True if count is even", "matching_cluster_idx": 3}, {"solution": "def count_divisors(n):\n \"\"\"\n Function to count the number of divisors of a given integer n.\n Returns True if the count of divisors is even, False otherwise.\n \"\"\"\n if n <= 0:\n raise ValueError(\"Input must be a positive integer\")\n \n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0: # i is a divisor\n count += 1\n if i != n // i: # n/i is also a divisor\n count += 1\n return count % 2 == 0 # Check if the count of divisors is even", "matching_cluster_idx": 3}, {"solution": "def count_divisors(n):\n \"\"\"Return True if the count of divisors of n is even, otherwise False.\"\"\"\n if n < 1:\n raise ValueError(\"Input must be a positive integer.\")\n \n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n count += 1\n if i != n // i: # Count the complement divisor if it's different\n count += 1\n return count % 2 == 0", "matching_cluster_idx": 3}, {"solution": "def count_divisors(n):\n \"\"\"Returns True if the count of divisors of n is even, otherwise False.\"\"\"\n if n <= 0:\n raise ValueError(\"n must be a positive integer\")\n \n divisor_count = 0\n \n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n divisor_count += 1 # Count the divisor\n if i != n // i:\n divisor_count += 1 # Count the complementary divisor\n\n return divisor_count % 2 == 0", "matching_cluster_idx": 3}, {"solution": "def count_divisors(n):\n \"\"\"Return True if the count of divisors of n is even, else False.\"\"\"\n if n <= 0:\n return False # or raise an exception for invalid input\n \n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n count += 1 # i is a divisor\n if i != n // i:\n count += 1 # n // i is also a divisor if it's different from i\n \n return count % 2 == 0", "matching_cluster_idx": 3}, {"solution": "def count_divisors(n):\n \"\"\"\n This function counts the number of divisors of a given integer n.\n It returns True if the count of divisors is even, otherwise False.\n \"\"\"\n if n <= 0:\n raise ValueError(\"Input must be a positive integer.\")\n \n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n\n return count % 2 == 0 # Return True if count of divisors is even", "matching_cluster_idx": 1}, {"solution": "def count_divisors(n):\n if n <= 0:\n return False # We can consider count of divisors for positive integers only\n \n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n count += 1\n if i != n // i: # Count the complementary divisor\n count += 1\n\n return count % 2 == 0 # Return True if the count is even", "matching_cluster_idx": 3}, {"solution": "def count_divisors(n):\n \"\"\"\n Returns True if the count of divisors of n is even, False otherwise.\n \"\"\"\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count % 2 == 0", "matching_cluster_idx": 0}, {"solution": "def count_divisors(n):\n \"\"\"\n Counts the number of divisors of a given number n and checks\n whether that count is even.\n \n Args:\n n (int): The number for which to count divisors.\n\n Returns:\n bool: True if the count of divisors is even, False otherwise.\n \"\"\"\n if n <= 0:\n raise ValueError(\"Input must be a positive integer.\")\n\n count = 0\n # Count divisors by checking each number from 1 to n\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n \n return count % 2 == 0", "matching_cluster_idx": 1}, {"solution": "def count_divisors(n):\n \"\"\"\n Function to count the number of divisors of a given integer n\n and check if that count is even or odd.\n \n Parameters:\n n (int): The number for which to count divisors\n \n Returns:\n bool: True if the count of divisors is even, False otherwise\n \"\"\"\n if n <= 0:\n raise ValueError(\"Input must be a positive integer.\")\n \n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0: # i is a divisor\n count += 1 # Count i\n if i != n // i:\n count += 1 # Count the complementary divisor\n \n return count % 2 == 0 # Check if the count is even", "matching_cluster_idx": 3}, {"solution": "def count_divisors(n):\n \"\"\"\n This function returns True if the count of divisors of n is even,\n otherwise returns False.\n \"\"\"\n if n <= 0:\n raise ValueError(\"Input must be a positive integer.\")\n \n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n count += 1\n if i != n // i: # Count the complementary divisor only if it's different\n count += 1\n\n return count % 2 == 0 # Check if the count of divisors is even", "matching_cluster_idx": 3}, {"solution": "def count_divisors(n):\n \"\"\"Return True if the count of divisors of n is even, False otherwise.\"\"\"\n if n < 1:\n raise ValueError(\"Input must be a positive integer.\")\n \n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n count += 1 # i is a divisor\n if i != n // i:\n count += 1 # n // i is also a divisor\n return count % 2 == 0 # Return True if even, False if odd", "matching_cluster_idx": 3}, {"solution": "def count_divisors(n):\n \"\"\"\n Function to count the number of divisors of a given number n.\n It returns True if the count is even, otherwise False.\n \"\"\"\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n count += 1 # i is a divisor\n if i != n // i:\n count += 1 # n // i is also a divisor\n\n return count % 2 == 0 # Check if count is even", "matching_cluster_idx": 3}]}, "Mbpp/800": {"dps": 97.83582089552239, "dps_norm": 99.0, "pass@1": 22.0, "profiled": [{"solution": "def remove_all_spaces(input_string):\n \"\"\"\n Remove all whitespaces from the given string.\n \n Args:\n input_string (str): The string from which to remove whitespaces.\n \n Returns:\n str: The input string without any whitespaces.\n \"\"\"\n return input_string.replace(' ', '')", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n \"\"\"Remove all whitespaces from the input string.\"\"\"\n return input_string.replace(' ', '')", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n \"\"\"Remove all whitespaces from the given string.\"\"\"\n return input_string.replace(' ', '')", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n \"\"\"\n This function removes all whitespaces from the input string.\n\n Args:\n input_string (str): The string from which to remove whitespaces.\n\n Returns:\n str: The input string without any whitespaces.\n \"\"\"\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n \"\"\"\n Remove all whitespaces from the input string.\n\n Args:\n input_string (str): The string from which to remove whitespaces.\n\n Returns:\n str: The input string with all whitespaces removed.\n \"\"\"\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n \"\"\"Remove all whitespaces from the input string.\"\"\"\n return input_string.replace(' ', '')", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n \"\"\"\n Remove all whitespaces from the input string.\n \n Parameters:\n input_string (str): The string from which to remove whitespaces.\n \n Returns:\n str: The input string without any whitespace characters.\n \"\"\"\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n \"\"\"Remove all whitespaces from the input string.\"\"\"\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string: str) -> str:\n \"\"\"Remove all whitespaces from the input string.\"\"\"\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string: str) -> str:\n \"\"\"\n Remove all whitespaces from the given string.\n \n Parameters:\n input_string (str): The string from which to remove whitespaces.\n \n Returns:\n str: The string without any whitespaces.\n \"\"\"\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n \"\"\"Remove all whitespaces from the input string.\"\"\"\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n \"\"\"Removes all whitespaces from the given string.\"\"\"\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n \"\"\"Remove all whitespaces from the input string.\"\"\"\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n \"\"\"\n Remove all whitespaces from the input string.\n \n Args:\n input_string (str): The string from which to remove whitespaces.\n \n Returns:\n str: A new string with all whitespaces removed.\n \"\"\"\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 3}, {"solution": "def remove_all_spaces(input_string):\n \"\"\"Remove all whitespaces from the input string.\"\"\"\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n \"\"\"Remove all whitespaces from the input string.\"\"\"\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n \"\"\"Remove all whitespaces from the given string.\"\"\"\n return input_string.replace(' ', '')", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n \"\"\"\n Remove all whitespaces from the input string.\n \n Parameters:\n input_string (str): The string from which to remove whitespaces.\n \n Returns:\n str: The input string without any whitespaces.\n \"\"\"\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n \"\"\"Removes all whitespace characters from the given string.\"\"\"\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n \"\"\"Remove all whitespaces from the given string.\"\"\"\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}]}, "Mbpp/805": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def max_sum_list(lists):\n # Initialize variables to keep track of the list with the maximum sum\n max_sum = float('-inf')\n max_list = None\n \n # Iterate through each list in the input\n for lst in lists:\n current_sum = sum(lst) # Calculate the sum of the current list\n # Check if the current sum is greater than the maximum sum found so far\n if current_sum > max_sum:\n max_sum = current_sum # Update the maximum sum\n max_list = lst # Update the list with the maximum sum\n \n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n \"\"\"\n Returns the list in the input list of lists whose sum of elements is the highest.\n \n Args:\n lists (list of list of int): A list containing multiple lists of integers.\n \n Returns:\n list of int: The list with the highest sum of elements.\n \"\"\"\n if not lists:\n return []\n \n # Use max with a key that sums the elements of each sublist\n return max(lists, key=sum)", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n # Initialize variables to track the maximum sum and the corresponding sublist\n max_sum = float('-inf')\n max_list = []\n\n # Iterate through each sublist\n for sublist in lists:\n current_sum = sum(sublist) # Calculate the sum of the current sublist\n \n # Update if current sum is greater than the max sum found so far\n if current_sum > max_sum:\n max_sum = current_sum\n max_list = sublist\n\n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n # Initialize variables to keep track of the max sum and corresponding sublist\n max_sum = float('-inf')\n max_list = []\n \n # Iterate through each sublist\n for sublist in lists:\n current_sum = sum(sublist) # Calculate the sum of the current sublist\n # Check if the current sum is greater than the max sum found so far\n if current_sum > max_sum:\n max_sum = current_sum # Update the max sum\n max_list = sublist # Update the corresponding sublist\n \n return max_list # Return the sublist with the highest sum", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n \"\"\"\n Returns the list in a list of lists whose sum of elements is the highest.\n\n Args:\n lists (list of list of int): A list containing lists of integers.\n\n Returns:\n list of int: The list with the highest sum of its elements.\n \"\"\"\n return max(lists, key=sum)", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n \"\"\"\n Returns the sublist with the highest sum of its elements.\n\n Args:\n lists (list of lists): A list containing lists of integers.\n\n Returns:\n list: The list with the highest sum of its elements.\n \"\"\"\n if not lists:\n return []\n\n # Find the list with the maximum sum\n max_list = max(lists, key=sum)\n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n \"\"\"\n Returns the list with the highest sum of elements from a list of lists.\n\n Parameters:\n lists (list of list of int): A list containing multiple lists of integers.\n\n Returns:\n list: The list with the highest sum of elements.\n \"\"\"\n return max(lists, key=sum)", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n \"\"\"\n Returns the list in a list of lists whose sum of elements is the highest.\n\n Args:\n lists (list of list of int): A list of lists of integers.\n\n Returns:\n list: The list with the highest sum of elements.\n \"\"\"\n if not lists:\n return None # Return None if the input list is empty\n\n # Use max() with a key argument to find the sublist with the maximum sum\n return max(lists, key=sum)", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n \"\"\"Returns the list with the highest sum of its elements from a list of lists.\"\"\"\n return max(lists, key=sum)", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n \"\"\"\n Returns the list in a list of lists whose sum of elements is the highest.\n \n :param lists: List of lists of integers\n :return: List with the highest sum of its elements\n \"\"\"\n if not lists:\n return [] # Return an empty list if the input is empty\n\n return max(lists, key=sum)", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n \"\"\"\n Returns the list in a list of lists whose sum of elements is the highest.\n \n Parameters:\n lists (list of list of int): A list containing sublists of integers.\n\n Returns:\n list: The sublist with the highest sum of its elements.\n \"\"\"\n return max(lists, key=sum)", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n \"\"\"\n Returns the list in the list of lists whose sum of elements is the highest.\n \n Args:\n lists (list of list of int): A list containing sublists of integers.\n \n Returns:\n list: The sublist with the highest sum of its elements.\n \"\"\"\n return max(lists, key=sum)", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n # Initialize variables to keep track of the maximum sum and the corresponding list\n max_sum = float('-inf')\n max_list = []\n\n # Iterate through each list in the provided list of lists\n for sublist in lists:\n current_sum = sum(sublist) # Calculate the sum of the current sublist\n # Update max_sum and max_list if the current sum is greater than max_sum\n if current_sum > max_sum:\n max_sum = current_sum\n max_list = sublist\n\n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n \"\"\"\n Returns the list in a list of lists whose sum of elements is the highest.\n\n :param lists: List of lists containing numeric elements\n :return: The list with the highest sum of its elements\n \"\"\"\n return max(lists, key=sum)", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n \"\"\"\n Returns the list in a list of lists whose sum of elements is the highest.\n \n Parameters:\n lists (list of list of int): A list containing lists of integers.\n \n Returns:\n list: The list with the highest sum of its elements.\n \"\"\"\n return max(lists, key=sum)", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n \"\"\"\n Returns the list in a list of lists whose sum of elements is the highest.\n \n Args:\n lists (list of list of int): A list containing sublists of integers.\n \n Returns:\n list: The sublist with the highest sum of elements.\n \"\"\"\n # Check if the input list is empty\n if not lists:\n return []\n\n # Find the sublist with the maximum sum using the built-in max function\n return max(lists, key=sum)", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n \"\"\"\n Returns the sub-list with the highest sum of elements from a list of lists.\n\n :param lists: A list of lists containing numerical values.\n :return: A list that has the highest sum of its elements.\n \"\"\"\n # Check if the input is empty\n if not lists:\n return []\n\n # Initialize variables to track the maximum sum and the corresponding sub-list\n max_sum = float('-inf')\n max_list = []\n\n # Iterate through each sub-list\n for sub_list in lists:\n current_sum = sum(sub_list)\n if current_sum > max_sum:\n max_sum = current_sum\n max_list = sub_list\n\n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lst):\n \"\"\"Returns the list with the highest sum from a list of lists.\"\"\"\n if not lst:\n return []\n \n # Find the list with the maximum sum\n return max(lst, key=sum)", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n # Initialize variables to keep track of the maximum sum and the corresponding list\n max_sum = float('-inf')\n max_list = []\n \n # Iterate through each list in the input\n for lst in lists:\n current_sum = sum(lst) # Calculate the sum of the current list\n \n # Update max_sum and max_list if current_sum is greater\n if current_sum > max_sum:\n max_sum = current_sum\n max_list = lst\n \n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n \"\"\"\n Returns the list in a list of lists whose sum of elements is the highest.\n \n Args:\n lists (list of list of int): A list containing sublists of integers.\n\n Returns:\n list: The sublist with the highest sum of its elements.\n \"\"\"\n # Initialize variables to keep track of the maximum sum and the corresponding list\n max_sum = float('-inf')\n max_list = []\n\n # Iterate through each sublist\n for sublist in lists:\n current_sum = sum(sublist)\n # Update if the current sum is greater than the max sum found so far\n if current_sum > max_sum:\n max_sum = current_sum\n max_list = sublist\n\n return max_list", "matching_cluster_idx": 4}]}, "Mbpp/808": {"dps": 93.0701754385965, "dps_norm": 98.33333333333333, "pass@1": 100.0, "profiled": [{"solution": "def check_K(tup, k):\n \"\"\"\n Check if the given tuple contains the value k.\n\n Parameters:\n tup (tuple): The tuple to search.\n k: The value to check for in the tuple.\n\n Returns:\n bool: True if k is in tup, otherwise False.\n \"\"\"\n return k in tup", "matching_cluster_idx": 4}, {"solution": "def check_K(tup, k):\n \"\"\"\n Check if the value k is present in the given tuple.\n\n Parameters:\n tup (tuple): The tuple to check.\n k: The value to look for in the tuple.\n\n Returns:\n bool: True if k is found in the tuple, False otherwise.\n \"\"\"\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n \"\"\"\n Check if the given tuple contains the value k.\n \n Parameters:\n tup (tuple): The tuple to check.\n k (any): The value to find in the tuple.\n \n Returns:\n bool: True if k is in the tuple, False otherwise.\n \"\"\"\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n \"\"\"\n Check if the given tuple contains the value k.\n\n Parameters:\n tup (tuple): The tuple to check.\n k: The value to check for.\n\n Returns:\n bool: True if k is in tup, False otherwise.\n \"\"\"\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n \"\"\"\n Check if the given tuple contains the value k.\n \n Parameters:\n tup (tuple): The tuple to check.\n k (any): The value to search for in the tuple.\n\n Returns:\n bool: True if k is in tup, False otherwise.\n \"\"\"\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n \"\"\"\n Check if the given tuple contains the value k.\n \n Args:\n tup (tuple): The tuple to check.\n k: The value to find in the tuple.\n \n Returns:\n bool: True if k is in tup, False otherwise.\n \"\"\"\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n \"\"\"\n Checks if the given tuple contains the value k.\n \n Parameters:\n tup (tuple): The tuple to be checked.\n k: The value to check for in the tuple.\n \n Returns:\n bool: True if k is in tup, False otherwise.\n \"\"\"\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n \"\"\"\n Check if the given tuple contains the value k.\n \n Parameters:\n tup (tuple): The tuple to check.\n k (any): The value to search for in the tuple.\n \n Returns:\n bool: True if k is in tup, False otherwise.\n \"\"\"\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n \"\"\"\n Check if the given tuple contains the value k.\n \n Parameters:\n tup (tuple): The tuple to check.\n k (any): The value to search for in the tuple.\n \n Returns:\n bool: True if k is in the tuple, False otherwise.\n \"\"\"\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n \"\"\"\n Check if the given tuple contains the value k.\n\n Args:\n tup (tuple): The tuple to check.\n k (any): The value to search for in the tuple.\n\n Returns:\n bool: True if k is in the tuple, False otherwise.\n \"\"\"\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n \"\"\"\n Check if the given tuple contains the value k.\n \n Parameters:\n tup (tuple): A tuple of values.\n k: The value to check for in the tuple.\n \n Returns:\n bool: True if k is in the tuple, False otherwise.\n \"\"\"\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n \"\"\"\n Check if the given tuple contains the element k.\n\n Parameters:\n tup (tuple): The tuple to check.\n k: The element to search for in the tuple.\n\n Returns:\n bool: True if k is in tup, False otherwise.\n \"\"\"\n return k in tup", "matching_cluster_idx": 4}, {"solution": "def check_K(tup, k):\n \"\"\"\n Checks if the given tuple contains the value k.\n \n Parameters:\n tup (tuple): The tuple to check.\n k (any): The value to search for in the tuple.\n\n Returns:\n bool: True if k is found in the tuple, False otherwise.\n \"\"\"\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n \"\"\"\n Check if the given tuple contains the value k.\n\n Parameters:\n tup (tuple): The tuple to check.\n k: The value to look for in the tuple.\n\n Returns:\n bool: True if k is in the tuple, False otherwise.\n \"\"\"\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n \"\"\"\n Check if the given tuple contains the value k.\n \n Parameters:\n tup (tuple): The tuple to check.\n k (any): The value to check for in the tuple.\n \n Returns:\n bool: True if k is in tup, False otherwise.\n \"\"\"\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n \"\"\"\n Check if the given integer k is present in the tuple tup.\n\n Parameters:\n tup (tuple): The tuple to search within.\n k (int): The integer to search for.\n\n Returns:\n bool: True if k is found in tup, False otherwise.\n \"\"\"\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n \"\"\"\n Check if the given tuples contain the k or not.\n \n Parameters:\n tup (tuple): The tuple to check.\n k (any): The value to search for in the tuple.\n \n Returns:\n bool: True if k is found in the tuple, False otherwise.\n \"\"\"\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n \"\"\"\n Check if the given tuple contains the value k.\n\n Parameters:\n tup (tuple): The tuple to be checked.\n k (any): The value to search for in the tuple.\n\n Returns:\n bool: True if k is found in the tuple, False otherwise.\n \"\"\"\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n \"\"\"\n Check if the given tuple contains the specified value k.\n\n Parameters:\n tup (tuple): The tuple to check.\n k: The value to check for.\n\n Returns:\n bool: True if k is in the tuple, False otherwise.\n \"\"\"\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n \"\"\"\n Check if the given tuple contains the value k.\n \n Parameters:\n tup (tuple): The tuple to check.\n k: The value to search for in the tuple.\n \n Returns:\n bool: True if k is in tup, False otherwise.\n \"\"\"\n return k in tup", "matching_cluster_idx": 5}]}}} \ No newline at end of file diff --git a/results/evalperf/ise-uiuc--Magicoder-S-DS-6.7B_vllm_temp_1.0_evalperf_results.brief.json b/results/evalperf/ise-uiuc--Magicoder-S-DS-6.7B_vllm_temp_1.0_evalperf_results.brief.json new file mode 100644 index 0000000..0a014fd --- /dev/null +++ b/results/evalperf/ise-uiuc--Magicoder-S-DS-6.7B_vllm_temp_1.0_evalperf_results.brief.json @@ -0,0 +1 @@ +{"date": "2024-10-19 16:28", "config": {"n_samples": 100, "temperature": 1.0, "min_correct": 10, "max_profile": 20}, "summary": {"dps": 83.62957240263601, "dps_norm": 78.58003556526222, "pass@1": 69.83898305084746}, "eval": {"HumanEval/9": {"dps": 68.8801261829653, "dps_norm": 66.66666666666667, "pass@1": 70.0, "profiled": [{"solution": "from typing import List, Tuple\ndef rolling_max(numbers: List[int]) -> List[int]:\n max_num = None\n output = []\n for num in numbers:\n if max_num is None or num > max_num:\n max_num = num\n output.append(max_num)\n return output", "matching_cluster_idx": 7}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\"\n From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n \"\"\"\n rolling_max_nums = []\n current_max = float('-inf')\n for num in numbers:\n if num > current_max:\n current_max = num\n rolling_max_nums.append(current_max)\n return rolling_max_nums", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef rolling_max(numbers: List[int]) -> List[int]:\n rolling_max_list = []\n current_max = float('-inf')\n for num in numbers:\n current_max = max(current_max, num)\n rolling_max_list.append(current_max)\n return rolling_max_list", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n max_so_far = float('-inf')\n rolling_max_list = []\n for num in numbers:\n max_so_far = max(max_so_far, num)\n rolling_max_list.append(max_so_far)\n return rolling_max_list", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n \"\"\"\n if not numbers:\n return []\n result = [numbers[0]]\n for i in range(1, len(numbers)):\n result.append(max(result[-1], numbers[i]))\n return result", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n max_list = [max(numbers[:i+1]) for i in range(len(numbers))]\n return max_list", "matching_cluster_idx": 2}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n max_list = [None]*len(numbers)\n max_value = float('-inf')\n for i in range(len(numbers)):\n max_value = max(max_value, numbers[i])\n max_list[i] = max_value\n return max_list", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n max_number = float('-inf') # Set initial max_number as negative infinity\n rolling_max_numbers = [] # Initialize the rolling max list\n\n for num in numbers:\n if num > max_number: # If the current number is greater than max_number\n max_number = num # Update max_number\n rolling_max_numbers.append(max_number) # Append max_number to the rolling max list\n\n return rolling_max_numbers", "matching_cluster_idx": 8}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\"\n From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n max_so_far = None\n res = []\n for num in numbers:\n if max_so_far is None or num > max_so_far:\n max_so_far = num\n res.append(max_so_far)\n return res", "matching_cluster_idx": 7}, {"solution": "from typing import List, Tuple\ndef rolling_max(numbers: List[int]) -> List[int]:\n rolling_max_nums = []\n max_num = float('-inf')\n for num in numbers:\n max_num = max(max_num, num)\n rolling_max_nums.append(max_num)\n return rolling_max_nums", "matching_cluster_idx": 4}, {"solution": "from typing import List, Tuple\ndef rolling_max(numbers: List[int]) -> List[int]:\n if not numbers:\n return []\n\n max_num = numbers[0]\n result = [max_num]\n\n for num in numbers[1:]:\n if num > max_num:\n max_num = num\n result.append(max_num)\n\n return result", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n\n rolling_max = [numbers[0]]\n for num in numbers[1:]:\n rolling_max.append(max(rolling_max[-1], num))\n\n return rolling_max", "matching_cluster_idx": 4}, {"solution": "from typing import List, Tuple\ndef rolling_max(numbers: List[int]) -> List[int]:\n max_val = float('-inf')\n result = []\n for num in numbers:\n max_val = max(num, max_val)\n result.append(max_val)\n return result", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n rolling_max_list = []\n for index, num in enumerate(numbers):\n if index == 0:\n rolling_max_list.append(num)\n else:\n rolling_max_list.append(max(rolling_max_list[-1], num))\n return rolling_max_list", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n max_so_far = float('-inf')\n rolling_max_list = []\n for number in numbers:\n max_so_far = max(max_so_far, number)\n rolling_max_list.append(max_so_far)\n return rolling_max_list", "matching_cluster_idx": 4}, {"solution": "from typing import List, Tuple\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n maximums = []\n current_max = float('-inf')\n for num in numbers:\n current_max = max(current_max, num)\n maximums.append(current_max)\n return maximums", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n # Initialize an empty list to store the rolling maximums.\n rolling_maxs = []\n\n # Initialize a variable to keep track of the maximum number found so far.\n max_so_far = float('-inf')\n\n # Iterate through the input list.\n for num in numbers:\n # If the current number is greater than the maximum seen so far,\n # update the maximum and append it to the rolling maximum list.\n if num > max_so_far:\n max_so_far = num\n rolling_maxs.append(max_so_far)\n\n # Return the list of rolling maximums.\n return rolling_maxs", "matching_cluster_idx": 8}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n if not numbers:\n return []\n\n result = [numbers[0]]\n for i in range(1, len(numbers)):\n result.append(max(result[-1], numbers[i]))\n\n return result", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n if not numbers:\n return []\n\n max_so_far = numbers[0]\n result = [max_so_far]\n for num in numbers[1:]:\n max_so_far = max(max_so_far, num)\n result.append(max_so_far)\n\n return result", "matching_cluster_idx": 4}, {"solution": "from typing import List, Tuple\ndef rolling_max(numbers: List[int]) -> List[int]:\n max_so_far = -float('inf') # Initialize max_so_far to negative infinity\n output = [] # Initialize output list\n\n for num in numbers:\n max_so_far = max(max_so_far, num) # Update max_so_far to the maximum between max_so_far and current num\n output.append(max_so_far) # Append max_so_far to output\n\n return output", "matching_cluster_idx": 4}]}, "HumanEval/0": {"dps": 69.01162790697674, "dps_norm": 72.14285714285714, "pass@1": 94.0, "profiled": [{"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n numbers.sort()\n for i in range(len(numbers) - 1):\n if abs(numbers[i] - numbers[i + 1]) < threshold:\n return True\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n # Sort the array to find neighbouring elements easily\n numbers.sort()\n \n for i in range(len(numbers) - 1):\n # Check if the difference between the two neighbouring elements is less than the threshold\n if abs(numbers[i] - numbers[i+1]) < threshold:\n return True\n\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n \"\"\"\n # Sort the list in increasing order\n numbers.sort()\n \n # Iterate over the sorted list\n for i in range(len(numbers) - 1):\n # Check if the difference between two adjacent numbers is less than threshold\n if abs(numbers[i+1] - numbers[i]) < threshold:\n # If so, there is a pair of close elements, return True\n return True\n # If no pair of close elements is found, return False\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n \"\"\"\n # Sort the numbers\n numbers.sort()\n \n # Loop through the numbers to check for closeness\n for i in range(len(numbers) - 1):\n if abs(numbers[i] - numbers[i + 1]) < threshold:\n return True\n \n # If no pair found closer than threshold\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\"\n Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n \"\"\"\n for i in range(len(numbers)):\n for j in range(i+1, len(numbers)):\n if abs(numbers[i] - numbers[j]) < threshold:\n return True\n return False", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n \"\"\"\n numbers.sort()\n for i in range(1, len(numbers)):\n if abs(numbers[i] - numbers[i - 1]) < threshold:\n return True\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\"\n Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n \"\"\"\n sorted_nums = sorted(numbers)\n\n for i in range(1, len(sorted_nums)):\n if sorted_nums[i] - sorted_nums[i - 1] < threshold:\n return True\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n \"\"\"\n numbers.sort()\n for i in range(len(numbers)-1):\n if abs(numbers[i] - numbers[i+1]) < threshold:\n return True\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n numbers = sorted(numbers)\n for i in range(len(numbers) - 1):\n if abs(numbers[i] - numbers[i+1]) < threshold:\n return True\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n \"\"\"\n sorted_numbers = sorted(numbers)\n for i in range(1, len(sorted_numbers)):\n if sorted_numbers[i] - sorted_numbers[i-1] < threshold:\n return True\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n \"\"\"\n numbers.sort()\n for i in range(len(numbers) - 1):\n if abs(numbers[i] - numbers[i+1]) < threshold:\n return True\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n numbers = sorted(numbers) # sort the list of numbers\n for i in range(len(numbers)-1): # iterate through the sorted list\n if numbers[i+1]-numbers[i] < threshold: # check if the difference between current and next number is less than threshold\n return True # return True as soon as we find a pair of numbers that are closer than the threshold\n return False # if we don't find such a pair, return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n if abs(numbers[i] - numbers[j]) < threshold:\n return True\n return False", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n if abs(numbers[i] - numbers[j]) < threshold:\n return True\n return False", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n sorted_numbers = sorted(numbers)\n for i in range(len(sorted_numbers) - 1):\n if sorted_numbers[i + 1] - sorted_numbers[i] < threshold:\n return True\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n for i in range(len(numbers)):\n for j in range(i+1, len(numbers)):\n if abs(numbers[i] - numbers[j]) < threshold:\n return True\n return False", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n \"\"\"\n for i in range(len(numbers)):\n for j in range(i+1, len(numbers)):\n if abs(numbers[i] - numbers[j]) < threshold:\n return True\n return False", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n \"\"\"\n\n # Loop over the numbers\n for i in range(len(numbers)):\n for j in range(i+1, len(numbers)):\n\n # Calculate the absolute difference between the current number and other numbers\n difference = abs(numbers[i] - numbers[j])\n\n # Check if the absolute difference is less than the threshold\n if difference < threshold:\n return True\n\n # No close elements found\n return False", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n \"\"\"\n numbers.sort()\n for i in range(len(numbers)-1):\n if abs(numbers[i] - numbers[i+1]) < threshold:\n return True\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n for i in range(len(numbers)):\n for j in range(i+1, len(numbers)):\n if abs(numbers[i] - numbers[j]) < threshold:\n return True\n return False", "matching_cluster_idx": 6}]}, "HumanEval/4": {"dps": 83.38607594936708, "dps_norm": 88.33333333333333, "pass@1": 100.0, "profiled": [{"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n # calculate mean\n mean = sum(numbers) / len(numbers)\n\n # calculate absolute deviations from the mean\n deviations = [abs(n - mean) for n in numbers]\n\n # calculate and return mean of absolute deviations\n return sum(deviations) / len(deviations)", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n mean = sum(numbers) / len(numbers)\n deviations = [abs(n - mean) for n in numbers]\n mad = sum(deviations) / len(deviations)\n return mad", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n mean = sum(numbers) / len(numbers)\n deviations = [abs(n - mean) for n in numbers]\n mad = sum(deviations) / len(deviations)\n return mad", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\"\n For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n \n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n \n MAD = average | x - x_mean |\n \n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n\n mean = sum(numbers) / len(numbers)\n absolute_deviation = [abs(number - mean) for number in numbers]\n mean_absolute_deviation = sum(absolute_deviation) / len(absolute_deviation)\n return mean_absolute_deviation", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\"\n For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n mean = sum(numbers) / len(numbers)\n deviations = [abs(num - mean) for num in numbers]\n mad = sum(deviations) / len(deviations)\n return mad", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n \"\"\"\n if len(numbers) == 0:\n return 0.0\n mean = sum(numbers) / len(numbers)\n mad = sum(abs(x - mean) for x in numbers) / len(numbers)\n return mad", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n mean = sum(numbers) / len(numbers)\n deviations = [abs(number - mean) for number in numbers]\n mad = sum(deviations) / len(deviations)\n return mad", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n \"\"\"\n mean_of_numbers = sum(numbers) / len(numbers)\n absolute_difference = [abs(number - mean_of_numbers) for number in numbers]\n mean_absolute_deviation = sum(absolute_difference) / len(numbers)\n\n return mean_absolute_deviation", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n \"\"\"\n # Calculate the mean\n mean = sum(numbers) / len(numbers)\n \n # Calculate the absolute differences\n diffs = [abs(num - mean) for num in numbers]\n \n # Calculate and return the average\n return sum(diffs) / len(diffs)", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n \"\"\"\n mean = sum(numbers) / len(numbers)\n mad = sum([abs(x - mean) for x in numbers]) / len(numbers)\n return mad", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n \"\"\"\n mean = sum(numbers) / len(numbers)\n absolute_diffs = [abs(num - mean) for num in numbers]\n mad = sum(absolute_diffs) / len(absolute_diffs)\n return mad", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\"\n For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n # calculate mean\n mean = sum(numbers) / len(numbers)\n # calculate absolute deviation\n abs_deviations = [abs(num - mean) for num in numbers]\n # calculate and return mean absolute deviation\n mad = sum(abs_deviations) / len(numbers)\n return mad", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n mean = sum(numbers) / len(numbers)\n deviation = [abs(n - mean) for n in numbers]\n mad = sum(deviation) / len(numbers)\n return mad", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n \"\"\"\n mean = sum(numbers) / len(numbers)\n mad = sum(abs(num - mean) for num in numbers) / len(numbers)\n return mad", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n mean = sum(numbers) / len(numbers)\n deviations = [abs(number - mean) for number in numbers]\n mad = sum(deviations) / len(deviations)\n return mad", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\"\n For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n \"\"\"\n\n mean = sum(numbers) / len(numbers)\n mad = sum(abs(num - mean) for num in numbers) / len(numbers)\n return mad", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n \"\"\"\n n = len(numbers)\n mean = sum(numbers) / n\n mad = sum(abs(x - mean) for x in numbers) / n\n return mad", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n \"\"\"\n mean = sum(numbers) / len(numbers)\n deviation = [abs(x - mean) for x in numbers]\n mad = sum(deviation) / len(deviation)\n return mad", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n mean = sum(numbers) / len(numbers)\n mad = sum(abs(n - mean) for n in numbers) / len(numbers)\n return mad", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n \"\"\"\n mean = sum(numbers) / len(numbers)\n mad = sum(abs(num - mean) for num in numbers) / len(numbers)\n return mad", "matching_cluster_idx": 5}]}, "HumanEval/16": {"dps": 81.86046511627907, "dps_norm": 85.0, "pass@1": 100.0, "profiled": [{"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of \"\"\"\n # First, convert the string to lowercase to treat characters in different cases equally\n string = string.lower()\n\n # Create an empty set to hold distinct characters\n distinct_characters = set()\n\n # Add each character to the set\n for char in string:\n distinct_characters.add(char)\n\n # The length of the set will be the number of distinct characters\n return len(distinct_characters)", "matching_cluster_idx": 2}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n \"\"\"\n return len(set(string.lower()))", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n \"\"\"\n distinct_chars = set()\n for char in string.lower():\n distinct_chars.add(char)\n return len(distinct_chars)", "matching_cluster_idx": 3}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of \"\"\"\n distinct_characters = set(string.lower()) # Convert the string to a set of distinct lower-case characters\n return len(distinct_characters) # Return the number of distinct characters", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n \"\"\"\n unique_characters = set(string.lower())\n return len(unique_characters)", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n # To handle case-insensitive comparison\n string = string.lower()\n\n # Creating a set to automatically remove duplicates\n distinct_chars = set(string)\n \n # Count the number of characters in the set\n return len(distinct_chars)", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of \"\"\"\n return len(set(string.lower()))", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of \"\"\"\n return len(set(string.lower()))", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n return len(set(string.lower()))", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\"\n Given a string, find out how many distinct characters (regardless of case) does it consist of\n\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n\n # Convert string to lower case to consider characters as case insensitive\n string = string.lower()\n\n # Store distinct characters in a set, because set automatically removes duplicates\n distinct_characters = set(string)\n\n # Return the count of distinct characters\n return len(distinct_characters)", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n # convert string to lowercase to ensure the count is case-insensitive\n lowered_string = string.lower()\n # convert string to a set to remove duplicates\n distinct_chars = set(lowered_string)\n # return length of set to get the count of distinct characters\n return len(distinct_chars)", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" \n Given a string, find out how many distinct characters (regardless of case) does it consist of\n\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # convert the string to lower case\n string = string.lower()\n\n # create an empty set to store unique characters\n distinct_chars = set()\n \n # iterate over every character in the string\n for char in string:\n distinct_chars.add(char)\n \n # return the number of unique characters\n return len(distinct_chars)", "matching_cluster_idx": 3}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of \"\"\"\n return len(set(string.lower()))", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\"\n Given a string, find out how many distinct characters (regardless of case) does it consist of\n\n >>> count_distinct_characters('xyzXYZ')\n 3\n\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n distinct_characters = set()\n\n for char in string.lower():\n distinct_characters.add(char)\n\n return len(distinct_characters)", "matching_cluster_idx": 3}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of \"\"\"\n return len(set(string.lower()))", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of \"\"\"\n distinct_characters = set(string.lower()) # creates a set with unique characters in the string\n return len(distinct_characters) # returns the number of distinct characters", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lowercase to treat capital and small cases as the same character\n string = string.lower()\n # Use a set to automatically remove duplicates and count the unique characters\n return len(set(string))", "matching_cluster_idx": 8}, {"solution": "import doctest\ndef count_distinct_characters(string: str) -> int:\n \"\"\"\n Given a string, find out how many distinct characters (regardless of case) does it consist of\n\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lowercase\n string = string.lower()\n # Use a set to eliminate duplicate characters\n distinct_chars = set(string)\n # The length of the set is the number of distinct characters\n return len(distinct_chars)", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of \"\"\"\n distinct_chars = set() # use a set to automatically eliminate duplicates\n for char in string.lower(): # convert to lowercase and iterate over characters\n distinct_chars.add(char) # add each character to the set\n return len(distinct_chars) # return the number of elements in the set", "matching_cluster_idx": 2}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of \"\"\"\n return len(set(string.lower())) # Converts the string to lower case and then to a set, which automatically removes duplicates", "matching_cluster_idx": 8}]}, "HumanEval/20": {"dps": 92.36077481840194, "dps_norm": 96.66666666666667, "pass@1": 89.0, "profiled": [{"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n \"\"\"\n sorted_numbers = sorted(numbers)\n smallest = sorted_numbers[0]\n largest = sorted_numbers[1]\n\n min_difference = largest - smallest\n\n for i in range(len(sorted_numbers) - 1):\n difference = sorted_numbers[i + 1] - sorted_numbers[i]\n\n if difference < min_difference:\n min_difference = difference\n smallest = sorted_numbers[i]\n largest = sorted_numbers[i + 1]\n\n return smallest, largest", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n numbers.sort()\n closest_pair = numbers[1] - numbers[0], numbers[0], numbers[1]\n\n for i in range(2, len(numbers)):\n diff = numbers[i] - numbers[i - 1]\n if diff < closest_pair[0]:\n closest_pair = diff, numbers[i - 1], numbers[i]\n\n return closest_pair[1], closest_pair[2]", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\"\n From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n \"\"\"\n numbers.sort() # sort the numbers in ascending order\n min_diff = float('inf') # initialize minimum difference to positive infinity\n closest_pair = (0, 0) # initialize closest pair to (0, 0)\n for i in range(len(numbers) - 1): # iterate through the sorted numbers\n diff = numbers[i + 1] - numbers[i] # calculate the difference between current and next number\n if diff < min_diff: # if current difference is smaller than minimum difference\n min_diff = diff # update minimum difference\n closest_pair = (numbers[i], numbers[i + 1]) # update closest pair\n return closest_pair # return the closest pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n \"\"\"\n # Sorting the numbers\n numbers.sort()\n min_difference = float(\"inf\")\n closest_pair = (0, 0)\n\n for i in range(1, len(numbers)):\n difference = numbers[i] - numbers[i-1]\n if difference < min_difference:\n min_difference = difference\n closest_pair = (numbers[i-1], numbers[i])\n\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\"From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n \"\"\"\n numbers.sort()\n closest_pair = (numbers[0], numbers[1])\n min_difference = abs(numbers[0] - numbers[1])\n\n for i in range(1, len(numbers) - 1):\n difference = abs(numbers[i] - numbers[i + 1])\n if difference < min_difference:\n min_difference = difference\n closest_pair = (numbers[i], numbers[i + 1])\n\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n # Sort the list\n numbers.sort()\n \n # Initialize variables\n min_diff = float('inf')\n result = ()\n\n # Iterate through the list to find two closest numbers\n for i in range(1, len(numbers)):\n diff = numbers[i] - numbers[i-1]\n if diff < min_diff:\n min_diff = diff\n result = (numbers[i-1], numbers[i])\n \n return result", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\"\n From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n \"\"\"\n # Check if list length is less than 2\n if len(numbers) < 2:\n raise ValueError(\"Input list should contain at least two elements\")\n\n # Initialize min_diff and min_pair with first two elements\n min_diff = abs(numbers[0] - numbers[1])\n min_pair = (min(numbers[0], numbers[1]), max(numbers[0], numbers[1]))\n\n # Traverse the list\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n diff = abs(numbers[i] - numbers[j])\n # If diff is smaller than current min_diff, update min_diff and min_pair\n if diff < min_diff:\n min_diff = diff\n min_pair = (min(numbers[i], numbers[j]), max(numbers[i], numbers[j]))\n\n return min_pair", "matching_cluster_idx": 3}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n \"\"\"\n # sort the list\n numbers.sort()\n\n # initialize minimum difference and corresponding elements as first two elements of sorted list\n min_diff = numbers[1] - numbers[0]\n closest_elements = (numbers[0], numbers[1])\n\n # iterate over list and compare difference between each number and its preceding number\n for i in range(2, len(numbers)):\n curr_diff = numbers[i] - numbers[i - 1]\n if curr_diff < min_diff:\n min_diff = curr_diff\n closest_elements = (numbers[i - 1], numbers[i])\n\n return closest_elements", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n \"\"\"\n # Sort the list in ascending order\n numbers.sort()\n\n # Initialize the minimum difference and result variables\n min_diff = float('inf')\n result = None\n\n # Iterate over the list, skipping the first element (since it can't be compared with the previous one)\n for i in range(1, len(numbers)):\n # Calculate the difference between the current number and the previous one\n diff = numbers[i] - numbers[i-1]\n\n # If the difference is smaller than the current minimum difference, update the minimum difference and result\n if diff < min_diff:\n min_diff = diff\n result = (numbers[i-1], numbers[i])\n\n return result", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n numbers.sort()\n min_diff = float('inf')\n result = (0.0, 0.0)\n \n for i in range(1, len(numbers)):\n diff = numbers[i] - numbers[i - 1]\n if diff < min_diff:\n min_diff = diff\n result = (numbers[i - 1], numbers[i])\n \n return result", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" \n From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n \"\"\"\n numbers.sort()\n min_diff = float('inf')\n closest = ()\n\n for i in range(1, len(numbers)):\n diff = numbers[i] - numbers[i-1]\n if diff < min_diff:\n min_diff = diff\n closest = (numbers[i-1], numbers[i])\n\n return closest", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n # Sorting the numbers\n numbers.sort()\n\n # Initializing closest_diff as the absolute difference between the first two numbers\n closest_diff = abs(numbers[1] - numbers[0])\n\n # Initializing the closest_pair as the first two numbers\n closest_pair = numbers[0], numbers[1]\n\n # Looping over the list and updating the closest_pair and closest_diff as necessary\n for i in range(len(numbers) - 1):\n diff = abs(numbers[i+1] - numbers[i])\n if diff < closest_diff:\n closest_diff = diff\n closest_pair = numbers[i], numbers[i+1]\n\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n numbers.sort()\n min_diff = float('inf')\n result = (0, 0)\n for i in range(1, len(numbers)):\n diff = abs(numbers[i] - numbers[i-1])\n if diff < min_diff:\n min_diff = diff\n result = (numbers[i-1], numbers[i])\n return result", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n \"\"\"\n if len(numbers) < 2:\n raise ValueError(\"List must contain at least two elements.\")\n sorted_numbers = sorted(numbers)\n min_diff = sorted_numbers[1] - sorted_numbers[0]\n closest_elements = sorted_numbers[0], sorted_numbers[1]\n for i in range(1, len(sorted_numbers) - 1):\n diff = sorted_numbers[i + 1] - sorted_numbers[i]\n if diff < min_diff:\n min_diff = diff\n closest_elements = sorted_numbers[i], sorted_numbers[i + 1]\n return closest_elements", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n numbers.sort() # sort numbers\n min_diff = float('inf') # initially assign minimum difference to infinity\n min_pair = (0, 0) # initialize minimum pair\n for i in range(len(numbers) - 1): # iterate through all pairs of numbers\n diff = numbers[i + 1] - numbers[i] # compute difference between current pair\n if diff < min_diff: # if smaller difference found\n min_diff = diff # replace minimum difference\n min_pair = (numbers[i], numbers[i + 1]) # replace minimum pair\n return min_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n \"\"\"\n numbers.sort() # sort the list in ascending order\n min_diff = float('inf') # initialize min_diff to infinity\n closest_pair = () # initialize closest_pair to be empty\n for i in range(len(numbers) - 1):\n diff = abs(numbers[i + 1] - numbers[i]) # compute the difference between consecutive elements\n if diff < min_diff: # if the difference is less than min_diff, update min_diff and closest_pair\n min_diff = diff\n closest_pair = (numbers[i], numbers[i + 1])\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n numbers.sort()\n min_difference = float('inf')\n closest_elements = (numbers[0], numbers[1])\n \n for i in range(1, len(numbers)):\n difference = abs(numbers[i] - numbers[i - 1])\n if difference < min_difference:\n min_difference = difference\n closest_elements = (numbers[i - 1], numbers[i])\n \n return closest_elements", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\nimport doctest\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\"From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n if len(numbers) < 2:\n raise ValueError(\"List must have at least two elements.\")\n \n numbers.sort()\n min_diff = float('inf')\n closest_pair = (None, None)\n\n for i in range(len(numbers) - 1):\n diff = abs(numbers[i] - numbers[i + 1])\n if diff < min_diff:\n min_diff = diff\n closest_pair = (numbers[i], numbers[i + 1])\n\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n numbers.sort()\n min_difference = min(numbers[i+1] - numbers[i] for i in range(len(numbers)-1))\n \n for i in range(len(numbers)-1):\n if numbers[i+1] - numbers[i] == min_difference:\n return (numbers[i], numbers[i+1])", "matching_cluster_idx": 7}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n \"\"\"\n numbers.sort()\n min_diff = float('inf')\n result = None\n\n for i in range(1, len(numbers)):\n diff = numbers[i] - numbers[i-1]\n if diff < min_diff:\n min_diff = diff\n result = (numbers[i-1], numbers[i])\n\n return result", "matching_cluster_idx": 8}]}, "HumanEval/24": {"dps": 59.353741496598644, "dps_norm": 21.875, "pass@1": 80.0, "profiled": [{"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n \"\"\"\n i = n - 1\n while i > 0:\n if n % i == 0:\n return i\n i -= 1", "matching_cluster_idx": 0}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n \"\"\"\n for i in range(n-1, 1, -1):\n if n % i == 0:\n return i\n return 1", "matching_cluster_idx": 1}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n for i in range(n-1, 1, -1):\n if n % i == 0:\n return i\n return 1", "matching_cluster_idx": 1}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n \"\"\"\n for i in range(n-1, 1, -1):\n if n % i == 0:\n return i\n return 1", "matching_cluster_idx": 1}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n \"\"\"\n for i in range(n-1, 0, -1): # start from n-1, go to 1, step -1\n if n % i == 0: # if n is divisible by i\n return i # return i as largest divisor", "matching_cluster_idx": 1}, {"solution": "def largest_divisor(n: int) -> int:\n if n <= 1:\n return None # as no positive integer less than n can divide 1\n for i in range(n-1, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 1}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n. \"\"\"\n for i in range(n-1, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 1}, {"solution": "def largest_divisor(n: int) -> int:\n if n <= 1:\n return \"Error: Number should be greater than 1\"\n\n for i in range(n-1, 1, -1):\n if n % i == 0:\n return i\n\n return 1", "matching_cluster_idx": 1}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" \n For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n for i in range(n-1, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 1}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n \"\"\"\n for i in range(n - 1, 1, -1):\n if n % i == 0:\n return i\n return 1", "matching_cluster_idx": 1}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" \n For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n >>> largest_divisor(48)\n 24\n \"\"\"\n if n <= 0:\n raise ValueError(\"The input number must be a positive integer.\")\n for divisor in range(n - 1, 1, -1):\n if n % divisor == 0:\n return divisor\n return 1", "matching_cluster_idx": 1}, {"solution": "def largest_divisor(n: int) -> int:\n i = n - 1\n while i > 0:\n if n % i == 0:\n return i\n i -= 1", "matching_cluster_idx": 0}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n \"\"\"\n i = n - 1\n while i > 0:\n if n % i == 0:\n return i\n i -= 1", "matching_cluster_idx": 0}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\"\n For a given number n, find the largest number that divides n evenly, smaller than n\n \"\"\"\n for i in range(n-1, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 1}, {"solution": "import doctest\ndef largest_divisor(n: int) -> int:\n for i in range(n-1, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 1}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n if n <= 1:\n return None\n i = n // 2\n while i >= 1:\n if n % i == 0:\n return i\n i -= 1\n return None", "matching_cluster_idx": 1}, {"solution": "import doctest\ndef largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n i = n - 1\n while i > 0:\n if n % i == 0:\n return i\n i -= 1", "matching_cluster_idx": 0}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n for i in range(n-1, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 1}, {"solution": "def largest_divisor(n: int) -> int:\n i = n - 1\n while i > 0:\n if n % i == 0:\n return i\n i -= 1", "matching_cluster_idx": 0}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n \"\"\"\n if n < 1:\n raise ValueError(\"Input number should be greater than 0\")\n for i in range(n-1, 1, -1):\n if n % i == 0:\n return i\n return 1", "matching_cluster_idx": 1}]}, "HumanEval/26": {"dps": 43.0, "dps_norm": 43.75, "pass@1": 25.0, "profiled": [{"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n \"\"\"\n result = []\n for number in numbers:\n if numbers.count(number) == 1:\n result.append(number)\n return result", "matching_cluster_idx": 0}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n\n unique_numbers = []\n for num in numbers:\n if numbers.count(num) == 1:\n unique_numbers.append(num)\n return unique_numbers", "matching_cluster_idx": 0}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n result = []\n for num in numbers:\n if numbers.count(num) == 1:\n result.append(num)\n return result", "matching_cluster_idx": 0}, {"solution": "from typing import List\nfrom collections import Counter\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n \"\"\"\n counts = Counter(numbers)\n return [num for num in numbers if counts[num] == 1]", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n \"\"\"\n result = []\n for num in numbers:\n if numbers.count(num) == 1:\n result.append(num)\n return result", "matching_cluster_idx": 0}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n result = []\n for num in numbers:\n if numbers.count(num) == 1:\n result.append(num)\n return result", "matching_cluster_idx": 0}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n return [i for i in numbers if numbers.count(i) == 1]", "matching_cluster_idx": 0}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\"From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n \"\"\"\n result = []\n for num in numbers:\n if numbers.count(num) == 1:\n result.append(num)\n return result", "matching_cluster_idx": 0}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n counts = {}\n unique = []\n for num in numbers:\n if num in counts:\n counts[num] += 1\n else:\n counts[num] = 1\n\n for num in numbers:\n if counts[num] == 1:\n unique.append(num)\n\n return unique", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n \"\"\"\n # Initialize an empty list to store the result\n result = []\n # Create a dictionary to track the count of each number\n count = {}\n for num in numbers:\n if num in count:\n count[num] += 1\n else:\n count[num] = 1\n # Append numbers that have count = 1 to the result\n for num in numbers:\n if count[num] == 1:\n result.append(num)\n return result", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n unique_numbers = []\n for number in numbers:\n if numbers.count(number) == 1:\n unique_numbers.append(number)\n return unique_numbers", "matching_cluster_idx": 0}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n num_counts = {}\n result = []\n\n for num in numbers:\n if num in num_counts:\n num_counts[num] += 1\n else:\n num_counts[num] = 1\n\n for num in numbers:\n if num_counts[num] == 1:\n result.append(num)\n\n return result", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n \"\"\"\n result = []\n for number in numbers:\n if numbers.count(number) == 1:\n result.append(number)\n return result", "matching_cluster_idx": 0}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n # Use a dictionary to store the number of occurrences of each number\n counts = {}\n # Iterate through the list\n for num in numbers:\n # If number is in dictionary, increment its count, otherwise, add it to the dictionary\n if num in counts:\n counts[num] += 1\n else:\n counts[num] = 1\n # Now, iterate through the list again\n no_duplicates = []\n for num in numbers:\n # If number is in dictionary and its count is 1, add it to the result list\n if num in counts and counts[num] == 1:\n no_duplicates.append(num)\n return no_duplicates", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n result = []\n for number in numbers:\n if numbers.count(number) == 1:\n result.append(number)\n return result", "matching_cluster_idx": 0}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n new_list = []\n for num in numbers:\n if numbers.count(num) == 1: # count the occurrences of the number in the list\n new_list.append(num)\n return new_list", "matching_cluster_idx": 0}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n result = []\n for num in numbers:\n if numbers.count(num) == 1:\n result.append(num)\n return result", "matching_cluster_idx": 0}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n return [item for item in numbers if numbers.count(item) == 1]", "matching_cluster_idx": 0}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n result = []\n for num in numbers:\n if numbers.count(num) == 1:\n result.append(num)\n return result", "matching_cluster_idx": 0}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" \n From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n return [i for i in numbers if numbers.count(i) == 1]", "matching_cluster_idx": 0}]}, "HumanEval/31": {"dps": 76.39240506329114, "dps_norm": 81.875, "pass@1": 92.0, "profiled": [{"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\"\"\"\n if n < 2:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True", "matching_cluster_idx": 5}, {"solution": "def is_prime(n):\n if n <= 1:\n return False\n elif n <= 3:\n return True\n elif n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n if n <= 1:\n return False\n elif n <= 3:\n return True\n elif n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n False\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return True if a given number is prime, and False otherwise.\"\"\"\n if n < 2:\n return False\n if n == 2 or n == 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n w = 2\n while i * i <= n:\n if n % i == 0:\n return False\n i += w\n w = 6 - w\n return True", "matching_cluster_idx": 5}, {"solution": "def is_prime(n):\n \"\"\"Return True if a given number is prime, and False otherwise.\n\n If n is less than 2, it's not prime, therefore return False.\n If n is 2, it's prime, so return True.\n For all other numbers, we check if they have any divisors between 2 and the square root of n, if they do, return False.\n If they don't, return True.\n \"\"\"\n if n < 2:\n return False\n if n == 2:\n return True\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True", "matching_cluster_idx": 5}, {"solution": "def is_prime(n):\n \"\"\"\n Return True if a given number is prime, and False otherwise.\n \"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n\n if n % 2 == 0 or n % 3 == 0:\n return False\n\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\"\"\"\n if n < 2: # all numbers less than 2 are not prime\n return False\n if n == 2: # 2 is the only even prime number\n return True\n if n % 2 == 0: # all other even numbers are not prime\n return False\n max_divisor = int(n ** 0.5) + 1 # we only need to check up to sqrt(n)\n for d in range(3, max_divisor, 2): # only check odd numbers\n if n % d == 0:\n return False\n return True", "matching_cluster_idx": 6}, {"solution": "import doctest\ndef is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\"\"\"\n if n < 2: # zero, one and negative numbers are not prime\n return False\n if n == 2: # 2 is prime\n return True\n if n % 2 == 0: # even numbers are not prime\n return False\n for i in range(3, int(n**0.5) + 1, 2): # try odd numbers up to square root of n\n if n % i == 0: # if n is divisible by i, it's not prime\n return False\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n if n < 2:\n return False\n if n == 2:\n return True\n if n % 2 == 0:\n return False\n max_divisor = int(n ** 0.5) + 1\n for d in range(3, max_divisor, 2):\n if n % d == 0:\n return False\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\"\"\"\n if n <= 1:\n return False\n elif n <= 3:\n return True\n elif n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n\n if n < 2:\n return False\n for i in range(2, int(n ** 0.5) + 1):\n if n % i == 0:\n return False\n return True", "matching_cluster_idx": 5}, {"solution": "def is_prime(n):\n if n < 2:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True", "matching_cluster_idx": 5}, {"solution": "def is_prime(n):\n if n < 2: \n return False # 1 and numbers less than 2 are not prime\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False # If n is divisible by any number up to its square root, it's not prime\n return True", "matching_cluster_idx": 5}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n if n == 2:\n return True\n if n % 2 == 0:\n return False\n i = 3\n while i * i <= n:\n if n % i:\n i += 2\n else:\n return False\n return True", "matching_cluster_idx": 5}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\"\"\"\n if n < 2:\n return False\n if n == 2:\n return True\n if n % 2 == 0:\n return False\n max_divisor = int(n**0.5) + 1\n for d in range(3, max_divisor, 2):\n if n % d == 0:\n return False\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"\n Return true if a given number is prime, and false otherwise.\n \"\"\"\n if n < 2: # numbers less than 2 are not prime\n return False\n if n == 2: # 2 is prime\n return True\n if n % 2 == 0: # even numbers other than 2 are not prime\n return False\n max_divisor = int(n ** 0.5) + 1\n for d in range(3, max_divisor, 2):\n if n % d == 0: # n is not a prime\n return False\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n \"\"\"\n if n < 2:\n return False\n for i in range(2, int(n**0.5)+1):\n if n % i == 0:\n return False\n return True", "matching_cluster_idx": 5}, {"solution": "def is_prime(n):\n \"\"\"\n Return True if a given number is prime, and False otherwise.\n \"\"\"\n if n <= 1:\n return False\n elif n <= 3:\n return True\n elif n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\"\"\"\n if n < 2:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True", "matching_cluster_idx": 5}]}, "HumanEval/33": {"dps": 55.601851851851855, "dps_norm": 72.72727272727272, "pass@1": 25.0, "profiled": [{"solution": "def sort_third(l):\n \"\"\"\n This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n \"\"\"\n divisible_by_three = sorted([l[i] for i in range(len(l)) if i % 3 == 0])\n result = []\n for i in range(len(l)):\n if i % 3 == 0:\n result.append(divisible_by_three.pop(0))\n else:\n result.append(l[i])\n return result", "matching_cluster_idx": 6}, {"solution": "def sort_third(l: list) -> list:\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n index = [i for i in range(len(l)) if i % 3 == 0]\n sorted_value = sorted([l[i] for i in index])\n res = l[:]\n for idx, val in zip(index, sorted_value):\n res[idx] = val\n return res", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"\n This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n \"\"\"\n # Identify all indices divisible by three\n div_by_three = [i for i in range(len(l)) if i % 3 == 0]\n\n # For each index divisible by three, we sort the list of values at those indices\n sorted_values = sorted([l[i] for i in div_by_three])\n\n # Create a new list where the values are sorted for the indices divisible by three\n # and the rest of the values are kept as they are\n l_prime = l.copy()\n for idx, val in zip(div_by_three, sorted_values):\n l_prime[idx] = val\n\n return l_prime", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n divisible_by_three = sorted([l[i] for i in range(len(l)) if i%3 == 0])\n divisible_by_three_indexes = sorted([i for i in range(len(l)) if i%3 == 0])\n \n sorted_l = [0]*len(l)\n index = 0\n divisible_index = 0\n\n for i in range(len(l)):\n if i%3 != 0:\n sorted_l[i] = l[i]\n else:\n sorted_l[i] = divisible_by_three[divisible_index]\n divisible_index += 1\n\n return sorted_l", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n divisible_indices = [i for i, x in enumerate(l) if i % 3 == 0]\n divisible_values = [l[i] for i in divisible_indices]\n divisible_values.sort()\n \n new_l = l.copy()\n for i in divisible_indices:\n new_l[i] = divisible_values.pop(0)\n \n return new_l", "matching_cluster_idx": 6}, {"solution": "def sort_third(l: list):\n divisible_by_three = [l[i] for i in range(len(l)) if i % 3 == 0]\n divisible_by_three.sort()\n result = l.copy()\n for i in range(len(l)):\n if i % 3 == 0:\n result[i] = divisible_by_three.pop(0)\n return result", "matching_cluster_idx": 6}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are \n equal to the values of the corresponding indicies of l, but sorted.\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n third_elements = sorted([l[i] for i in range(0, len(l), 3)])\n result = l.copy()\n \n for i in range(0, len(l), 3):\n result[i] = third_elements.pop(0)\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list) -> list:\n \"\"\"\n This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are\n equal to the values of the corresponding indicies of l, but sorted.\n \"\"\"\n indexes_to_sort = [i for i in range(len(l)) if i % 3 == 0]\n values_to_sort = [l[i] for i in indexes_to_sort]\n sorted_values = sorted(values_to_sort)\n \n for i in range(len(l)):\n if i in indexes_to_sort:\n l[i] = sorted_values.pop(0)\n \n return l", "matching_cluster_idx": 2}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n \"\"\"\n # Find values at indices divisible by 3\n div_three_values = sorted([l[i] for i in range(0, len(l), 3)])\n\n # Replace these values in the original list\n for i in range(0, len(l), 3):\n l[i] = div_three_values.pop(0)\n \n return l", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list) -> list:\n indices_divisible_by_three = [i for i in range(len(l)) if i % 3 == 0]\n sorted_values = sorted([l[i] for i in indices_divisible_by_three])\n \n result = l.copy()\n for i, val in enumerate(sorted_values):\n result[indices_divisible_by_three[i]] = val\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n index = [i for i, x in enumerate(l) if i % 3 == 0]\n values = [l[i] for i in index]\n values.sort()\n for i, idx in enumerate(index):\n l[idx] = values[i]\n return l", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"\n This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n \"\"\"\n # find the values at the indices divisible by 3\n divisible_by_3 = [l[i] for i in range(len(l)) if i%3 == 0]\n # sort the found values\n divisible_by_3.sort()\n # replace the values at the indices divisible by 3 with the sorted values\n for i in range(len(l)):\n if i%3 == 0:\n l[i] = divisible_by_3.pop(0)\n return l", "matching_cluster_idx": 6}, {"solution": "def sort_third(l: list):\n divisible_by_three = []\n not_divisible_by_three = []\n for i in range(len(l)):\n if i % 3 == 0:\n divisible_by_three.append(l[i])\n else:\n not_divisible_by_three.append(l[i])\n divisible_by_three.sort()\n l_prime = not_divisible_by_three\n for i in range(len(divisible_by_three)):\n l_prime.insert(i*3, divisible_by_three[i])\n return l_prime", "matching_cluster_idx": 6}, {"solution": "def sort_third(l: list) -> list:\n thirds = [l[i] for i in range(0, len(l), 3)]\n thirds.sort()\n thirds_i = 0\n result = []\n for i in range(len(l)):\n if i % 3 == 0:\n result.append(thirds[thirds_i])\n thirds_i += 1\n else:\n result.append(l[i])\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"\n This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n \n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n indices = [i for i in range(len(l)) if i % 3 == 0]\n sorted_values = sorted([l[i] for i in indices])\n result = l.copy()\n for i, value in zip(indices, sorted_values):\n result[i] = value\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n divisible_by_three = [i for i in l[::3]]\n divisible_by_three.sort()\n i = 0\n for j in range(0, len(l), 3):\n l[j] = divisible_by_three[i]\n i += 1\n return l", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n divisible_by_three_values = sorted([l[i] for i in range(len(l)) if i%3==0])\n return [divisible_by_three_values.pop(0) if i%3==0 else l[i] for i in range(len(l))]", "matching_cluster_idx": 6}, {"solution": "def sort_third(l: list) -> list:\n if not l: # handle an empty list\n return l\n\n divisible_by_three_indices = [index for index in range(len(l)) if index % 3 == 0]\n divisible_by_three_values = sorted([l[index] for index in divisible_by_three_indices])\n\n for index in divisible_by_three_indices:\n l[index] = divisible_by_three_values.pop(0)\n\n return l", "matching_cluster_idx": 7}, {"solution": "def sort_third(l: list):\n indices = [i for i in range(len(l)) if i % 3 == 0]\n values = sorted([l[i] for i in indices])\n\n for i in indices:\n l[i] = values.pop(0)\n \n return l", "matching_cluster_idx": 7}, {"solution": "def sort_third(l):\n # Define two empty lists to store the values at indices divisible by 3 and not divisible by 3\n div_three = []\n not_div_three = []\n\n # Iterate through the list\n for i in range(len(l)):\n # If the index is divisible by 3, append the value to 'div_three'\n if i % 3 == 0:\n div_three.append(l[i])\n # Otherwise, append the value to 'not_div_three'\n else:\n not_div_three.append(l[i])\n\n # Sort 'div_three'\n div_three.sort()\n \n # Construct a new list, 'new_l'\n # Put elements from 'not_div_three' at indices divisible by 3\n # Put elements from 'div_three' at other indices\n new_l = [None] * len(l)\n j, k = 0, 0\n for i in range(len(l)):\n if i % 3 == 0:\n new_l[i] = div_three[j]\n j += 1\n else:\n new_l[i] = not_div_three[k]\n k += 1\n\n return new_l", "matching_cluster_idx": 8}]}, "HumanEval/34": {"dps": 95.47169811320755, "dps_norm": 99.0, "pass@1": 100.0, "profiled": [{"solution": "def unique(l: list) -> list:\n \"\"\"Return sorted unique elements in a list\"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list) -> list:\n \"\"\"Return sorted unique elements in a list\"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list) -> list:\n \"\"\"Return sorted unique elements in a list\"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list) -> list:\n \"\"\"Return sorted unique elements in a list\"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(lst: list):\n \"\"\"Return sorted unique elements in a list.\"\"\"\n return sorted(list(set(lst)))", "matching_cluster_idx": 3}, {"solution": "def unique(l: list) -> list:\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n # Use set to remove duplicates\n unique_list = list(set(l))\n\n # Sort the list in ascending order\n unique_list.sort()\n\n return unique_list", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"\n Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list) -> list:\n \"\"\"Return sorted unique elements in a list\"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list.\"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}]}, "HumanEval/36": {"dps": 87.98387096774192, "dps_norm": 67.85714285714286, "pass@1": 92.0, "profiled": [{"solution": "def count_sevens(n: int):\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count\ndef fizz_buzz(n: int):\n return count_sevens(n)", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int):\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n for i in range(n):\n if (i % 11 == 0 or i % 13 == 0) and '7' in str(i):\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"\n Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n \n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n count = 0\n for i in range(1, n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int):\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count(\"7\")\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n\n # Initializing count\n count = 0\n \n # Iterate from 0 to n\n for i in range(1, n):\n # Check if the number is divisible by 11 or 13\n if i % 11 == 0 or i % 13 == 0:\n # Count the number of times the digit 7 appears\n count += str(i).count('7')\n \n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n count = 0\n for i in range(1, n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count(\"7\")\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\"\"\"\n return sum(str(i).count('7') for i in range(n) if i % 11 == 0 or i % 13 == 0)", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n count = 0\n for i in range(1, n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"\n Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n \n :param n: positive integer\n :type n: int\n :return: number of times 7 appears in the numbers less than n that are divisible by 11 or 13\n :rtype: int\n \n :example:\n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n\n # Start by ensuring the given number is valid\n if not isinstance(n, int) or n <= 0:\n raise ValueError(\"Input must be a positive integer.\")\n\n count = 0\n \n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n \n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n \"\"\"\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count(\"7\")\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n for num in range(n):\n if num % 11 == 0 or num % 13 == 0:\n count += str(num).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n count = 0\n for i in range(1, n):\n if (i % 11 == 0 or i % 13 == 0):\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n total = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n total += str(i).count('7')\n return total", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n count = 0\n for i in range(1, n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int):\n def digit_count(number, target_digit):\n count = 0\n while number > 0:\n if number % 10 == target_digit:\n count += 1\n number = number // 10\n return count\n\n def divisible_by(number, divisor):\n return number % divisor == 0\n\n count = 0\n for i in range(n):\n if divisible_by(i, 11) or divisible_by(i, 13):\n count += digit_count(i, 7)\n return count", "matching_cluster_idx": 0}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n for i in range(1, n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n def has_seven(num: int) -> bool:\n return '7' in str(num)\n\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += sum(1 for digit in str(i) if digit == '7')\n return count", "matching_cluster_idx": 3}]}, "HumanEval/37": {"dps": 95.18003273322422, "dps_norm": 90.5, "pass@1": 91.0, "profiled": [{"solution": "def sort_even(l: list):\n # list of even indices\n evens = [l[i] for i in range(0, len(l), 2)]\n evens.sort()\n\n # output list\n l_sorted = l.copy()\n\n # assign sorted evens to corresponding positions in the input list\n j = 0\n for i in range(0, len(l), 2):\n l_sorted[i] = evens[j]\n j += 1\n\n return l_sorted", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n even_indicies = sorted([l[i] for i in range(0, len(l), 2)])\n j = 0\n for i in range(0, len(l), 2):\n l[i] = even_indicies[j]\n j += 1\n return l", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Extract even indices values.\n evens = [l[i] for i in range(0, len(l), 2)]\n evens.sort()\n # Insert sorted values in odd index positions.\n for i in range(0, len(l), 2):\n l[i] = evens.pop(0)\n return l", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n even_elements = sorted([l[i] for i in range(0, len(l), 2)])\n result = l[:]\n result[::2] = even_elements\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"\n This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are\n equal to the values of the even indicies of l, but sorted.\n \"\"\"\n # Get even indexed items and sort\n even_indices = [l[i] for i in range(0, len(l), 2)]\n even_indices.sort()\n \n # Copy even indexed items from sorted list back into original list\n new_l = l.copy()\n for i in range(0, len(l), 2):\n new_l[i] = even_indices.pop(0)\n return new_l", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n even_index = sorted([value for index, value in enumerate(l) if index % 2 == 0])\n result = []\n even_iterator = iter(even_index)\n for index in range(len(l)):\n if index % 2 == 0:\n result.append(next(even_iterator))\n else:\n result.append(l[index])\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n even_values = sorted([l[i] for i in range(0, len(l), 2)])\n result = [even_values.pop(0) if i % 2 == 0 else l[i] for i in range(len(l))]\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are \n equal to the values of the even indicies of l, but sorted.\n \"\"\"\n even_indicies = sorted(l[i] for i in range(0, len(l), 2))\n result = l.copy()\n for i in range(0, len(l), 2):\n result[i] = even_indicies.pop(0)\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list) -> list:\n \"\"\"\n This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n \"\"\"\n # Get the values at even indices of l\n even_values = [l[i] for i in range(0, len(l), 2)]\n \n # Sort them\n even_values.sort()\n \n # Replace the values at even indices in l with sorted values\n for i in range(0, len(l), 2):\n l[i] = even_values.pop(0)\n \n return l", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n \"\"\"\n even_indices = sorted(l[i] for i in range(0, len(l), 2))\n return [(even_indices.pop(0) if i % 2 == 0 else l[i]) for i in range(len(l))]", "matching_cluster_idx": 8}, {"solution": "def sort_even(l):\n evens = [l[i] for i in range(0, len(l), 2)]\n evens.sort()\n j = 0\n for i in range(0, len(l), 2):\n l[i] = evens[j]\n j += 1\n return l", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Separate out the values at even indices\n even_values = [l[i] for i in range(0, len(l), 2)]\n \n # Sort these values\n sorted_even_values = sorted(even_values)\n \n # Replace the values at even indices with the sorted ones\n for i in range(0, len(l), 2):\n l[i] = sorted_even_values.pop(0)\n \n return l", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n # get even indexed elements\n evens = [l[i] for i in range(len(l)) if i % 2 == 0]\n evens.sort()\n\n # insert sorted evens at even indices\n result = []\n j = 0\n for i in range(len(l)):\n if i % 2 == 0:\n result.append(evens[j])\n j += 1\n else:\n result.append(l[i])\n\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n \"\"\"\n even_elements = sorted([l[i] for i in range(0, len(l), 2)])\n new_l = []\n even_index = 0\n \n for i in range(len(l)):\n if i % 2 == 0:\n new_l.append(even_elements[even_index])\n even_index += 1\n else:\n new_l.append(l[i])\n \n return new_l", "matching_cluster_idx": 8}, {"solution": "def sort_even(l):\n \"\"\"\n This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n \"\"\"\n even_numbers = sorted([l[i] for i in range(0, len(l), 2)])\n result = [l[i] if i % 2 == 1 else even_numbers.pop(0) for i in range(len(l))]\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n \n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n even_indicies = [l[i] for i in range(0, len(l), 2)]\n even_indicies.sort()\n new_l = []\n even_index = 0\n for i in range(len(l)):\n if i % 2 == 0:\n new_l.append(even_indicies[even_index])\n even_index += 1\n else:\n new_l.append(l[i])\n return new_l", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"\n This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n\n Args:\n l (list): input list\n\n Returns:\n list: output list\n\n Examples:\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n evens = sorted(l[::2])\n result = l[:]\n result[::2] = evens\n return result", "matching_cluster_idx": 9}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n \"\"\"\n even_indexes = sorted([l[i] for i in range(0, len(l), 2)])\n result = []\n j = 0\n for i in range(len(l)):\n if i % 2 == 0:\n result.append(even_indexes[j])\n j += 1\n else:\n result.append(l[i])\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n even_indexes = sorted([l[i] for i in range(len(l)) if i % 2 == 0])\n sorted_l = [None] * len(l)\n for i in range(len(sorted_l)):\n if i % 2 == 0:\n sorted_l[i] = even_indexes.pop(0)\n else:\n sorted_l[i] = l[i]\n return sorted_l", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n \"\"\"\n even_values = [l[i] for i in range(0, len(l), 2)]\n even_values.sort()\n sorted_l = []\n e = 0\n for i in range(len(l)):\n if i % 2 == 0: # for even index\n sorted_l.append(even_values[e])\n e += 1\n else: # for odd index\n sorted_l.append(l[i])\n return sorted_l", "matching_cluster_idx": 8}]}, "HumanEval/49": {"dps": 78.58823529411765, "dps_norm": 93.0, "pass@1": 82.0, "profiled": [{"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n if n == 0:\n return 1 % p\n else:\n return (2 ** n) % p", "matching_cluster_idx": 3}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int):\n \"\"\"Return 2^n modulo p (be aware of numerics).\"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"\n Return 2^n modulo p (be aware of numerics).\n\n :param n: Integer representing power of 2\n :param p: Modulus to be applied\n :return: Result of 2^n % p\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\n\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n result = 2 ** n % p\n return result", "matching_cluster_idx": 3}, {"solution": "def modp(n: int, p: int) -> int:\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\"\"\"\n if p == 1:\n return 0\n else:\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int):\n \"\"\"Return 2^n modulo p (be aware of numerics).\n \n Args:\n n (int): The base number.\n p (int): The modulo number.\n \n Returns:\n int: The result of (2^n) modulo p.\n \n Examples:\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\"\"\"\n return (2 ** n) % p", "matching_cluster_idx": 3}, {"solution": "def modp(n: int, p: int) -> int:\n # Python uses modular exponentiation by default for power operations\n return (2 ** n) % p", "matching_cluster_idx": 3}, {"solution": "def modp(n: int, p: int):\n \"\"\"Return 2^n modulo p (be aware of numerics).\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int):\n # Use Python's built-in function pow() to calculate 2^n mod p\n # Note that pow() function is used instead of exponentiation operator\n # because the operator has a different precedence than the modulus operator\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p.\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n return 2 ** n % p", "matching_cluster_idx": 3}, {"solution": "import doctest\ndef modp(n: int, p: int):\n \"\"\"Return 2^n modulo p (be aware of numerics).\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n return (2**n) % p", "matching_cluster_idx": 3}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\"\"\"\n return (2 ** n) % p", "matching_cluster_idx": 3}]}, "HumanEval/51": {"dps": 81.44927536231884, "dps_norm": 68.75, "pass@1": 99.0, "profiled": [{"solution": "def remove_vowels(text):\n return ''.join(char for char in text if char.lower() not in 'aeiou')", "matching_cluster_idx": 2}, {"solution": "def remove_vowels(text):\n vowels = 'aeiouAEIOU'\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n \"\"\"\n return ''.join([i for i in text if i not in ['a', 'e', 'i', 'o', 'u', 'A', 'E', 'I', 'O', 'U']])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n \"\"\"\n vowels = 'aeiouAEIOU'\n return ''.join(char for char in text if char not in vowels)", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n \"\"\"\n vowels = 'aeiouAEIOU'\n return ''.join([ch for ch in text if ch not in vowels])", "matching_cluster_idx": 5}, {"solution": "import doctest\ndef remove_vowels(text):\n vowels = 'aeiouAEIOU'\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n vowels = \"aeiouAEIOU\"\n result = \"\"\n for char in text:\n if char not in vowels:\n result += char\n return result", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n return ''.join(c for c in text if c.lower() not in 'aeiou')", "matching_cluster_idx": 2}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n \"\"\"\n vowels = \"aeiouAEIOU\"\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n # Define the set of vowels\n vowels = {'a', 'e', 'i', 'o', 'u', 'A', 'E', 'I', 'O', 'U'}\n\n # Return the string without vowels\n return ''.join(ch for ch in text if ch not in vowels)", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n return ''.join(char for char in text if char not in 'aeiouAEIOU')", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n return ''.join(letter for letter in text if letter.lower() not in \"aeiou\")", "matching_cluster_idx": 2}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n \"\"\"\n vowels = 'aeiouAEIOU'\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n return ''.join([char for char in text if char.lower() not in 'aeiou'])", "matching_cluster_idx": 2}, {"solution": "def remove_vowels(text):\n vowels = \"aeiouAEIOU\"\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n vowels = \"aeiouAEIOU\"\n result = \"\"\n for char in text:\n if char not in vowels:\n result += char\n return result", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n vowels = \"aeiouAEIOU\"\n result = \"\"\n for char in text:\n if char not in vowels:\n result += char\n return result", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n vowels = 'aeiouAEIOU'\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "import doctest\ndef remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = 'aeiouAEIOU'\n result = \"\"\n for char in text:\n if char not in vowels:\n result += char\n return result", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n \"\"\"\n vowels = 'aeiouAEIOU'\n for vowel in vowels:\n text = text.replace(vowel, '')\n return text", "matching_cluster_idx": 7}]}, "HumanEval/54": {"dps": 84.04255319148936, "dps_norm": 86.9047619047619, "pass@1": 12.0, "profiled": [{"solution": "def same_chars(s0: str, s1: str) -> bool:\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \"\"\"\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')\n True\n >>> same_chars('abcd', 'dddddddabc')\n True\n >>> same_chars('dddddddabc', 'abcd')\n True\n >>> same_chars('eabcd', 'dddddddabc')\n False\n >>> same_chars('abcd', 'dddddddabce')\n False\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')\n False\n \"\"\"\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"Check if two words have the same characters.\"\"\"\n # Converting both strings to sets\n set_s0 = set(s0)\n set_s1 = set(s1)\n \n # Checking if the sets are equal\n return set_s0 == set_s1", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n # removing duplicate characters from the strings\n s0 = ''.join(set(s0))\n s1 = ''.join(set(s1))\n\n # checking if both strings have the same characters\n return sorted(s0) == sorted(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \"\"\"\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str):\n # create a dictionary for each string counting the number of each letter\n s0_dict = {}\n for char in s0:\n s0_dict[char] = s0_dict.get(char, 0) + 1\n s1_dict = {}\n for char in s1:\n s1_dict[char] = s1_dict.get(char, 0) + 1\n\n # check if both dictionaries have the same keys (letter counts are unimportant)\n return s0_dict.keys() == s1_dict.keys()", "matching_cluster_idx": 0}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n # Convert both strings to sets to remove duplicates and change them to tuples\n # for comparison.\n return set(tuple(sorted(s0))) == set(tuple(sorted(s1)))", "matching_cluster_idx": 1}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \"\"\"\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str):\n \"\"\"\n Check if two words have the same characters.\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')\n True\n >>> same_chars('abcd', 'dddddddabc')\n True\n >>> same_chars('dddddddabc', 'abcd')\n True\n >>> same_chars('eabcd', 'dddddddabc')\n False\n >>> same_chars('abcd', 'dddddddabce')\n False\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')\n False\n \"\"\"\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')\n True\n >>> same_chars('abcd', 'dddddddabc')\n True\n >>> same_chars('dddddddabc', 'abcd')\n True\n >>> same_chars('eabcd', 'dddddddabc')\n False\n >>> same_chars('abcd', 'dddddddabce')\n False\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')\n False\n \"\"\"\n # return sorted(s0) == sorted(s1)\n return sorted(list(set(s0))) == sorted(list(set(s1)))", "matching_cluster_idx": 6}]}, "HumanEval/58": {"dps": 85.17716535433071, "dps_norm": 77.5, "pass@1": 100.0, "profiled": [{"solution": "def common(l1: list, l2: list) -> list:\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n return sorted(list(set(l1) & set(l2)))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list) -> list:\n \"\"\"Return sorted unique common elements for two lists.\n\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n return sorted(set(l1) & set(l2))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n return sorted(list(set(l1) & set(l2)))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list) -> list:\n \"\"\"Return sorted unique common elements for two lists.\"\"\"\n return sorted(list(set(l1) & set(l2)))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n common_elements = list(set(l1) & set(l2))\n return sorted(common_elements)", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list) -> list:\n \"\"\"Return sorted unique common elements for two lists.\"\"\"\n return sorted(set(l1) & set(l2))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list) -> list:\n \"\"\"Return sorted unique common elements for two lists.\n \"\"\"\n return sorted(list(set(l1) & set(l2)))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list) -> list:\n \"\"\"Return sorted unique common elements for two lists.\n \"\"\"\n # Convert the lists to sets, which can perform fast set operations\n s1, s2 = set(l1), set(l2)\n # Find the intersection of the sets, which gives us the common elements\n common_set = s1.intersection(s2)\n # Convert the resulting set back to a list\n common_list = list(common_set)\n # Sort the list in ascending order\n common_list.sort()\n return common_list", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list) -> list:\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n return sorted(list(set([value for value in l1 if value in l2])))", "matching_cluster_idx": 0}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\"\"\"\n return sorted(list(set([i for i in l1 if i in l2])))", "matching_cluster_idx": 0}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n\n \"\"\"\n return sorted(list(set(l1) & set(l2)))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list) -> list:\n \"\"\"Return sorted unique common elements for two lists.\n\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n # Use set intersection operation to find common elements\n common_elements = list(set(l1) & set(l2))\n # Return common elements sorted\n return sorted(common_elements)", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n \"\"\"\n return sorted(list(set(l1) & set(l2)))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list) -> list:\n \"\"\"Return sorted unique common elements for two lists.\n \"\"\"\n return sorted(list(set(l1) & set(l2)))", "matching_cluster_idx": 4}, {"solution": "import doctest\ndef common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n\n \"\"\"\n return sorted(list(set(l1) & set(l2)))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list) -> list:\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n return sorted(list(set(l1) & set(l2)))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list) -> list:\n \"\"\"Return sorted unique common elements for two lists.\n \"\"\"\n return sorted(set(l1) & set(l2))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n # Find common elements and then remove duplicates by converting to set\n common_elements = set(l1).intersection(l2)\n \n # Convert the set back to a list and sort\n sorted_common_elements = sorted(list(common_elements))\n \n return sorted_common_elements", "matching_cluster_idx": 5}, {"solution": "def common(l1: list, l2: list) -> list:\n \"\"\"Return sorted unique common elements for two lists.\n \"\"\"\n return sorted(set(l1) & set(l2))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\"\"\"\n return sorted(set(l1) & set(l2))", "matching_cluster_idx": 4}]}, "HumanEval/59": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 97.0, "profiled": [{"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\"\"\"\n i = 2\n while i * i <= n:\n if n % i:\n i += 1\n else:\n n //= i\n return n", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\"\"\"\n i = 2\n while i * i <= n:\n if n % i:\n i += 1\n else:\n n //= i\n return n", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"Returns the largest prime factor of n.\"\"\"\n factor = 2\n while factor * factor <= n:\n if n % factor:\n factor += 1\n else:\n n //= factor\n return n", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n i = 2\n while i * i <= n:\n if n % i:\n i += 1\n else:\n n //= i\n return n", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n):\n i = 2\n while i * i <= n:\n if n % i:\n i += 1\n else:\n n //= i\n return n", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n i = 2\n while i * i <= n:\n if n % i:\n i += 1\n else:\n n //= i\n return n", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n):\n i = 2\n while i * i <= n:\n if n % i:\n i += 1\n else:\n n //= i\n return n", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\"\"\"\n i = 2\n while i * i <= n:\n if n % i:\n i += 1\n else:\n n //= i\n return n", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n i = 2\n while i * i <= n:\n if n % i:\n i += 1\n else:\n n //= i\n return n", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\"\"\"\n i = 2\n while i * i <= n:\n if n % i:\n i += 1\n else:\n n //= i\n return n", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\"\"\"\n i = 2\n while i * i <= n:\n if n % i:\n i += 1\n else:\n n //= i\n return n", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\"\"\"\n factor = 2\n while factor * factor <= n:\n if n % factor:\n factor += 1\n else:\n n //= factor\n return n", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\"\"\"\n i = 2\n while i * i <= n:\n if n % i:\n i += 1\n else:\n n //= i\n return n", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\"\"\"\n i = 2\n while i * i <= n:\n if n % i:\n i += 1\n else:\n n //= i\n return n", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\"\"\"\n i = 2\n while i * i <= n:\n if n % i:\n i += 1\n else:\n n //= i\n return n", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n \"\"\"\n i = 2\n while i * i <= n:\n if n % i:\n i += 1\n else:\n n //= i\n return n", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\"\"\"\n i = 2\n while i * i <= n:\n if n % i:\n i += 1\n else:\n n //= i\n return n", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n i = 2\n while i * i <= n:\n if n % i:\n i += 1\n else:\n n //= i\n return n", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n i = 2\n while i * i <= n:\n if n % i:\n i += 1\n else:\n n //= i\n return n", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n i = 2\n while i * i <= n:\n if n % i:\n i += 1\n else:\n n //= i\n return n", "matching_cluster_idx": 8}]}, "HumanEval/64": {"dps": 89.82683982683983, "dps_norm": 65.27777777777777, "pass@1": 18.0, "profiled": [{"solution": "def vowels_count(s):\n vowels = set(\"aeiouAEIOU\")\n count = 0\n if s.endswith('y') or s.endswith('Y'):\n count += 1\n for letter in s:\n if letter in vowels:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n count = sum([s.lower().count(vowel) for vowel in \"aeiou\"])\n if s.lower().endswith('y'):\n count += 1\n return count", "matching_cluster_idx": 6}, {"solution": "def vowels_count(s):\n s = s.lower()\n vowels = 'aeiou'\n count = sum(s.count(v) for v in vowels)\n if s.endswith('y'):\n count += 1\n return count", "matching_cluster_idx": 6}, {"solution": "def vowels_count(s):\n # We are using the set function to create a set of vowels\n vowels = set(\"aeiouAEIOU\")\n\n # Using list comprehension to find vowels in the string\n count = sum(1 for letter in s if letter in vowels)\n\n # If the last character in the string is 'Y' or 'y', count it\n if s[-1:] == 'y' or s[-1:] == 'Y':\n count += 1\n\n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n s = s.lower()\n vowels = ['a', 'e', 'i', 'o', 'u']\n count = sum(1 for char in s if char in vowels)\n \n if s.endswith('y'):\n count += 1\n \n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n \"\"\"\n This function counts the number of vowels in a given string, \n including the 'y' at the end of the string.\n \"\"\"\n s = s.lower() # convert the string to lowercase for easy comparison\n vowels = ['a', 'e', 'i', 'o', 'u']\n count = sum(1 for char in s if char in vowels)\n return count + (1 if s.endswith('y') else 0)", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n count = 0\n vowels = ['a', 'e', 'i', 'o', 'u']\n # Convert the string to lowercase to handle uppercase letters\n s = s.lower()\n for char in s:\n if char in vowels:\n count += 1\n # If the string ends with 'y', consider it a vowel\n if s.endswith('y'):\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n vowels = \"aeiou\"\n return sum(1 for char in s.lower() if char in vowels) + (\"y\" == s[-1:].lower())", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n vowels = 'aeiou'\n s = s.lower()\n count = sum(1 for char in s if char in vowels)\n if s.endswith('y'):\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n s = s.lower() # to handle cases like \"ACEDY\"\n count = sum([1 for char in s if char in ['a', 'e', 'i', 'o', 'u']])\n if s.endswith('y'): # to check for 'y' at end of word\n count += 1\n return count", "matching_cluster_idx": 5}, {"solution": "def vowels_count(s):\n vowels = ['a', 'e', 'i', 'o', 'u']\n s = s.lower()\n return sum(1 for letter in s if letter in vowels) + (s.endswith('y') and s[-1] == 'y')", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = 'aeiouAEIOU'\n count = sum([1 for char in s if char in vowels])\n\n if s.endswith('y') or s.endswith('Y'):\n count += 1\n\n return count", "matching_cluster_idx": 5}, {"solution": "def vowels_count(s):\n return sum(1 for c in s.lower() if c in 'aeiou') + (1 if s.lower().endswith('y') else 0)", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n s = s.lower()\n vowels = ['a', 'e', 'i', 'o', 'u']\n count = sum(1 for letter in s if letter in vowels)\n if s.endswith('y'):\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n count = 0\n for char in s:\n if char.lower() in 'aeiou':\n count += 1\n if s.lower().endswith('y'):\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n s = s.lower()\n vowels = set(\"aeiou\")\n count = sum(1 for char in s if char in vowels)\n if s.endswith('y'):\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n vowels = \"aeiou\"\n s = s.lower() # Ensure the search is case insensitive\n # Use list comprehension to count the number of vowels\n # and use the 'endswith' function to check if 'y' is at the end\n # of the string. \n return sum(1 for c in s if c in vowels) + ('y' in s[-1] if s else 0)", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n vowels = 'aeiou'\n s = s.lower()\n count = sum(1 for letter in s if letter in vowels)\n\n if s.endswith('y'):\n count += 1\n\n return count", "matching_cluster_idx": 4}]}, "HumanEval/74": {"dps": 98.04878048780488, "dps_norm": 88.88888888888889, "pass@1": 76.0, "profiled": [{"solution": "def total_match(lst1, lst2):\n total_chars1 = sum(len(s) for s in lst1)\n total_chars2 = sum(len(s) for s in lst2)\n\n if total_chars1 < total_chars2:\n return lst1\n elif total_chars2 < total_chars1:\n return lst2\n else:\n return lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n total_chars1 = sum(len(word) for word in lst1)\n total_chars2 = sum(len(word) for word in lst2)\n return lst1 if total_chars1 <= total_chars2 else lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n This function takes two lists of strings as input, calculates the total number of characters in each list, \n and returns the list with fewer total characters.\n\n If both lists have the same total number of characters, the function returns the first list.\n '''\n sum1 = sum(len(word) for word in lst1)\n sum2 = sum(len(word) for word in lst2)\n \n if sum1 < sum2:\n return lst1\n elif sum2 < sum1:\n return lst2\n else:\n return lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n sum1 = sum([len(x) for x in lst1])\n sum2 = sum([len(x) for x in lst2])\n if sum1 < sum2:\n return lst1\n elif sum2 < sum1:\n return lst2\n else:\n return lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n total1 = sum(len(s) for s in lst1)\n total2 = sum(len(s) for s in lst2)\n if total1 < total2:\n return lst1\n elif total2 < total1:\n return lst2\n else:\n return lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n def count_chars(lst):\n return sum(len(s) for s in lst)\n \n total_chars1 = count_chars(lst1)\n total_chars2 = count_chars(lst2)\n \n if total_chars1 < total_chars2:\n return lst1\n elif total_chars2 < total_chars1:\n return lst2\n else:\n return lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n \n total_lst1 = sum(len(str) for str in lst1)\n total_lst2 = sum(len(str) for str in lst2)\n\n return lst1 if total_lst1 <= total_lst2 else lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n sum_lst1 = sum([len(i) for i in lst1])\n sum_lst2 = sum([len(i) for i in lst2])\n if sum_lst1 < sum_lst2:\n return lst1\n elif sum_lst2 < sum_lst1:\n return lst2\n else:\n return lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n sum_lst1 = sum(len(i) for i in lst1)\n sum_lst2 = sum(len(i) for i in lst2)\n\n if sum_lst1 <= sum_lst2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n total1 = sum(len(word) for word in lst1)\n total2 = sum(len(word) for word in lst2)\n\n if total1 <= total2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n total_chars1 = sum(len(word) for word in lst1)\n total_chars2 = sum(len(word) for word in lst2)\n\n if total_chars1 < total_chars2:\n return lst1\n elif total_chars2 < total_chars1:\n return lst2\n else:\n return lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n total_chars_lst1 = sum(len(str) for str in lst1)\n total_chars_lst2 = sum(len(str) for str in lst2)\n \n if total_chars_lst1 < total_chars_lst2:\n return lst1\n elif total_chars_lst2 < total_chars_lst1:\n return lst2\n else:\n return lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n total_len_lst1 = sum(len(s) for s in lst1)\n total_len_lst2 = sum(len(s) for s in lst2)\n \n if total_len_lst1 < total_len_lst2:\n return lst1\n elif total_len_lst1 > total_len_lst2:\n return lst2\n else: \n return lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n sum1 = sum(len(word) for word in lst1)\n sum2 = sum(len(word) for word in lst2)\n if sum1 <= sum2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n A function that accepts two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n\n If the two lists have the same number of chars, return the first list.\n '''\n sum1 = sum(len(string) for string in lst1)\n sum2 = sum(len(string) for string in lst2)\n\n if sum1 < sum2:\n return lst1\n elif sum1 > sum2:\n return lst2\n else:\n return lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n lst1_total = sum(len(i) for i in lst1)\n lst2_total = sum(len(i) for i in lst2)\n\n if lst1_total <= lst2_total:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n total_chars_lst1 = sum(len(i) for i in lst1)\n total_chars_lst2 = sum(len(i) for i in lst2)\n \n return lst1 if total_chars_lst1 <= total_chars_lst2 else lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n sum1 = sum(len(i) for i in lst1)\n sum2 = sum(len(i) for i in lst2)\n\n if sum1 <= sum2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n # Compute total chars in both lists\n total_chars1 = sum(len(s) for s in lst1)\n total_chars2 = sum(len(s) for s in lst2)\n \n # Return the list with fewer total chars\n if total_chars1 <= total_chars2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n sum_lst1 = sum(len(s) for s in lst1)\n sum_lst2 = sum(len(s) for s in lst2)\n\n if sum_lst1 < sum_lst2:\n return lst1\n elif sum_lst1 > sum_lst2:\n return lst2\n else:\n return lst1", "matching_cluster_idx": 7}]}, "HumanEval/85": {"dps": 91.68316831683168, "dps_norm": 60.0, "pass@1": 98.0, "profiled": [{"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices..\"\"\"\n\n # Using list comprehension and enumerate for index\n return sum(val for ind, val in enumerate(lst) if ind%2 and val%2==0)", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"\n Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n return sum(i for idx, i in enumerate(lst) if i % 2 == 0 and idx % 2 != 0)", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst, add the even elements that are at odd indices\"\"\"\n return sum(lst[i] for i in range(1, len(lst), 2) if lst[i] % 2 == 0)", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices.\"\"\"\n return sum(lst[i] for i in range(1, len(lst), 2) if lst[i] % 2 == 0)", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst, \n add the even elements that are at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2\n \"\"\"\n return sum(i for i in lst[1::2] if i % 2 == 0)", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices..\"\"\"\n return sum(lst[i] for i in range(1, len(lst), 2) if lst[i] % 2 == 0)", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices.\"\"\"\n\n # Initialize an empty list to store the sum of even elements at odd indices\n sum_even_odd_indices = 0\n \n # Iterate through the list, skipping every 2nd element (the first element is at index 0)\n for i in range(1, len(lst), 2):\n # Check if the current element at the skipped index is even\n if lst[i] % 2 == 0:\n sum_even_odd_indices += lst[i] # Add it to the sum\n\n return sum_even_odd_indices", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n return sum(val for idx, val in enumerate(lst) if idx % 2 != 0 and val % 2 == 0)", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n # Initialize sum variable\n sum = 0\n # Loop through list with an index starting from 1 (skipping the first index due to 0-based index)\n for i in range(1, len(lst), 2):\n # Check if the element at this index is even\n if lst[i] % 2 == 0:\n # If yes, add to the sum\n sum += lst[i]\n # return sum\n return sum", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n return sum(lst[i] for i in range(1, len(lst), 2) if lst[i] % 2 == 0)", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices.\"\"\"\n\n # start a counter\n total = 0\n\n # iterate over the list, adding the elements at odd indices to the counter\n for i in range(len(lst)):\n if i % 2 != 0 and lst[i] % 2 == 0:\n total += lst[i]\n\n return total", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n return sum(val for index, val in enumerate(lst) if index % 2 != 0 and val % 2 == 0)", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n return sum(lst[i] for i in range(1, len(lst), 2) if lst[i] % 2 == 0)", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst, add the even elements that are at odd indices.\"\"\"\n return sum([lst[i] for i in range(len(lst)) if i % 2 != 0 and lst[i] % 2 == 0])", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n return sum(lst[i] for i in range(1, len(lst), 2) if lst[i] % 2 == 0)", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices.\"\"\"\n if lst:\n return sum(e for i, e in enumerate(lst) if i % 2 != 0 and e % 2 == 0)\n else:\n raise ValueError(\"List cannot be empty\")", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n\n # define an empty list to hold even elements at odd indices\n even_odds = []\n\n # iterate over the list starting from index 0 to avoid counting twice\n for i in range(len(lst)):\n\n # check if index is odd and element is even\n if i % 2 != 0 and lst[i] % 2 == 0:\n even_odds.append(lst[i])\n\n # return the sum of even_odds list\n return sum(even_odds)", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n return sum(lst[i] for i in range(1, len(lst), 2) if lst[i] % 2 == 0)", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst, add the even elements that are at odd indices.\"\"\"\n return sum(lst[i] for i in range(1, len(lst), 2) if lst[i] % 2 == 0)", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n return sum(lst[i] for i in range(1, len(lst), 2) if lst[i] % 2 == 0)", "matching_cluster_idx": 3}]}, "HumanEval/86": {"dps": 95.61224489795919, "dps_norm": 98.0, "pass@1": 50.0, "profiled": [{"solution": "def anti_shuffle(s):\n # split the string into a list of words and spaces\n words = s.split(' ')\n # for each word in the list\n for i in range(len(words)):\n # sort the characters in the word and join them back together\n words[i] = ''.join(sorted(words[i]))\n # join the words together with spaces between them\n return ' '.join(words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n words = s.split(' ')\n res = []\n for word in words:\n sorted_chars = sorted(word, key=ord)\n res.append(''.join(sorted_chars))\n return ' '.join(res)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n words = s.split(' ')\n result = []\n for word in words:\n letters = list(word)\n sorted_letters = sorted(letters, key=lambda x: ord(x))\n result.append(''.join(sorted_letters))\n return ' '.join(result)", "matching_cluster_idx": 2}, {"solution": "def anti_shuffle(s):\n return ' '.join(''.join(sorted(word)) for word in s.split(' '))", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n return ' '.join([''.join(sorted(word)) for word in s.split(' ')])", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n words = s.split(' ')\n ordered_words = []\n for word in words:\n ordered_words.append(''.join(sorted(word)))\n return ' '.join(ordered_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n words = s.split(' ')\n ordered_words = [''.join(sorted(word)) for word in words]\n result = ' '.join(ordered_words)\n return result", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n # split string into words\n words = s.split(' ')\n\n # sort each word's characters\n sorted_words = [''.join(sorted(word)) for word in words]\n\n # combine sorted words and return\n return ' '.join(sorted_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n def sort_word(word):\n return ''.join(sorted(word, key=ord))\n\n return ' '.join(map(sort_word, s.split(' ')))", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n words = s.split(' ')\n sorted_words = [''.join(sorted(word)) for word in words]\n return ' '.join(sorted_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n def sort_word(word):\n return ''.join(sorted(word))\n\n words = s.split(' ')\n sorted_words = [sort_word(word) for word in words]\n return ' '.join(sorted_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Returns an ordered version of a given string.\n \"\"\"\n words = s.split(' ')\n for i in range(len(words)):\n words[i] = \"\".join(sorted(words[i]))\n return \" \".join(words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n return ' '.join([''.join(sorted(word)) for word in s.split(' ')])", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n \"\"\"\n\n words = s.split(' ') # split the string into words\n\n for i in range(len(words)):\n words[i] = ''.join(sorted(words[i])) # sort each word and join the letters\n\n return ' '.join(words) # join the words back together with spaces", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n words = s.split(' ')\n for i in range(len(words)):\n words[i] = ''.join(sorted(words[i]))\n return ' '.join(words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n words = s.split(' ')\n for i in range(len(words)):\n words[i] = ''.join(sorted(words[i]))\n s = ' '.join(words)\n return s", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n words = s.split(' ')\n words = [''.join(sorted(word)) for word in words]\n return ' '.join(words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n # Split the string into a list of words (separated by space)\n words = s.split(' ')\n # Shuffle each word and convert it to a list of characters\n shuffled_words = [''.join(sorted(word)) for word in words]\n # Join the shuffled words together with spaces\n result = ' '.join(shuffled_words)\n return result", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n words = s.split(' ')\n output = []\n for word in words:\n output.append(''.join(sorted(word)))\n\n ordered_s = ' '.join(output)\n return ordered_s", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n words = s.split(' ')\n ordered_words = ['']*len(words)\n \n for i, word in enumerate(words):\n ordered_word = ''.join(sorted(word))\n ordered_words[i] = ordered_word\n \n return ' '.join(ordered_words)", "matching_cluster_idx": 4}]}, "HumanEval/87": {"dps": 75.50432276657061, "dps_norm": 53.57142857142857, "pass@1": 43.0, "profiled": [{"solution": "def get_row(lst, x):\n result = []\n for row in range(len(lst)):\n for col in range(len(lst[row])):\n if lst[row][col] == x:\n result.append((row, col))\n result.sort(key=lambda row_col: (row_col[0], -row_col[1]))\n return result", "matching_cluster_idx": 2}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n result = []\n \n # loop through each row in list\n for row_index, row in enumerate(lst):\n # loop through each value in row\n for value_index, value in enumerate(row):\n # if the value is equal to x, add coordinate to result\n if value == x:\n result.append((row_index, value_index))\n \n # sort coordinates by rows in ascending order, and by columns in descending order\n result.sort(key = lambda x: (x[0], -x[1]))\n \n return result", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n # Create a list to store our coordinates\n coordinates = []\n\n # Iterate over the rows\n for i in range(len(lst)):\n # Iterate over the columns\n for j in range(len(lst[i])):\n # If the current number matches our target, append the coordinate\n if lst[i][j] == x:\n coordinates.append((i, j))\n\n # Sort the coordinates first by the row in ascending order,\n # then by the column in descending order\n coordinates.sort(key=lambda x: (x[0], -x[1]))\n return coordinates", "matching_cluster_idx": 2}, {"solution": "def get_row(lst, x):\n # Initialize an empty list to store the tuples\n coordinates = []\n # Iterate through each row\n for i, row in enumerate(lst):\n # Iterate through each column\n for j, col in enumerate(row):\n # If the value at the current position is equal to x, add a tuple (row index, column index) to the list\n if col == x:\n coordinates.append((i, j))\n # Sort the list of tuples first by rows (first element of tuple) in ascending order, and then by columns (second element of tuple) in descending order\n coordinates.sort(key=lambda x: (x[0], -x[1]))\n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n # convert 2D list to a list of tuples where each tuple is a pair of coordinates: (row_index, column_index)\n # filter out pairs where the value at that coordinate is not equal to x\n # sort first by row_index in ascending order, then by column_index in descending order\n coords = sorted(((i,j) for i,row in enumerate(lst) for j,el in enumerate(row) if el == x), \n key=lambda t:(t[0], -t[1]))\n return coords", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n coord = []\n for i, row in enumerate(lst):\n for j, element in enumerate(row):\n if element == x:\n coord.append((i, j))\n\n return sorted(coord, key=lambda x: (x[0], -x[1]))", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n coords = []\n for row_idx, row in enumerate(lst):\n for col_idx, col in enumerate(row):\n if col == x:\n coords.append((row_idx, col_idx))\n return sorted(coords, key=lambda x: (x[0], -x[1]))", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"Returns coordinates of integer x in the 2D list sorted by rows and columns.\"\"\"\n coords = [(i, j) for i, row in enumerate(lst) for j, val in enumerate(row) if val == x]\n return sorted(coords, key=lambda y: (y[0], -y[1]))", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n coords = []\n for i in range(len(lst)):\n for j in range(len(lst[i])):\n if lst[i][j] == x:\n coords.append((i, j))\n return sorted(coords, key=lambda x: (x[0], -x[1]))", "matching_cluster_idx": 2}, {"solution": "def get_row(lst, x):\n coordinates = []\n for i in range(len(lst)):\n for j in range(len(lst[i])):\n if lst[i][j] == x:\n coordinates.append((i, j))\n return sorted(coordinates, key=lambda coord: (coord[0], -coord[1]))", "matching_cluster_idx": 2}, {"solution": "def get_row(lst, x):\n # Initialize an empty list for storing tuples.\n coordinates = []\n\n # Iterate over the rows in the list.\n for row_num, row in enumerate(lst):\n # Check each number in the row.\n for col_num, num in enumerate(row):\n # If the number is equal to x, add its coordinates to the list.\n if num == x:\n coordinates.append((row_num, col_num))\n\n # Sort the list first by rows (first element of each tuple) in ascending order,\n # and then by columns (second element of each tuple) in descending order.\n coordinates.sort(key=lambda tup: (tup[0], -tup[1]))\n\n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n result = [(i, j) for i in range(len(lst)) for j in range(len(lst[i])) if lst[i][j] == x]\n result.sort(key=lambda x: (x[0], -x[1]))\n return result", "matching_cluster_idx": 2}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \"\"\"\n result = []\n for i, row in enumerate(lst):\n for j, value in enumerate(row):\n if value == x:\n result.append((i, j))\n # Sort by row first and then column descendingly.\n result.sort(key=lambda x: (x[0], -x[1]))\n return result", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n # Empty list for output\n result = []\n \n # Enumerate through list to get row and column numbers\n for i, row in enumerate(lst):\n for j, col in enumerate(row):\n # Check if the number is x and if so, add coordinates to result\n if col == x:\n result.append((i, j))\n\n # Sort coordinates first by row (in ascending order), then by column (in descending order)\n result.sort(key=lambda x: (x[0], -x[1]))\n \n return result", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n result = []\n for i, row in enumerate(lst):\n for j, item in enumerate(row):\n if item == x:\n result.append((i, j))\n result.sort(key=lambda x: (x[0], -x[1]))\n return result", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n coordinates = [(i, j) for i, sublist in enumerate(lst) for j, val in enumerate(sublist) if val == x]\n return sorted(coordinates, key=lambda y: (y[0], -y[1]))\nlst = [\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ]\nx = 1", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n result = []\n for i, row in enumerate(lst):\n for j, value in enumerate(row):\n if value == x:\n result.append((i, j))\n\n result.sort(key=lambda x: (x[0], -x[1]))\n return result", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n return sorted([(i, j) for i, row in enumerate(lst) for j, val in enumerate(row) if val == x], key=lambda t: (t[0], -t[1]))", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n output = []\n for i, row in enumerate(lst):\n for j, val in enumerate(row):\n if val == x:\n output.append((i, j))\n return sorted(output, key=lambda t: (t[0], -t[1]))", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n coords = []\n for y, row in enumerate(lst):\n for z, cell in enumerate(row):\n if cell == x:\n coords.append((y, z))\n coords.sort(key=lambda coord: (coord[0], -coord[1]))\n return coords", "matching_cluster_idx": 3}]}, "HumanEval/89": {"dps": 90.22336769759451, "dps_norm": 27.61904761904762, "pass@1": 15.0, "profiled": [{"solution": "def encrypt(s):\n def shift_char(c):\n # check if the character is an alphabet\n if not c.isalpha():\n return c\n # calculate the shift\n shift = (ord(c.lower()) - 97 + 4) % 26\n # shift the character\n result = chr(97 + shift)\n # if character was uppercase, make it uppercase\n if c.isupper():\n result = result.upper()\n return result\n\n # apply the shift to each character in the string\n return \"\".join([shift_char(c) for c in s])", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n encrypted = \"\"\n for char in s:\n if char.isalpha():\n ascii_val = ord(char) + 2 * 2\n if char.islower():\n if ascii_val > ord('z'):\n ascii_val -= 26\n else:\n if ascii_val > ord('Z'):\n ascii_val -= 26\n encrypted += chr(ascii_val)\n else:\n encrypted += char\n return encrypted", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n result = ''\n for char in s:\n if char.isalpha():\n code = ord(char.lower()) - 96\n result += chr((code + 2 * 2 - 1) % 26 + 97).upper() if char.isupper() else chr((code + 2 * 2 - 1) % 26 + 97)\n else:\n result += char\n return result", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n encrypted_string = ''\n for char in s:\n if char.isalpha():\n ascii_offset = 65 if char.isupper() else 97\n encrypted_string += chr((ord(char) - ascii_offset + 2 * 2) % 26 + ascii_offset)\n else:\n encrypted_string += char\n return encrypted_string", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n result = \"\"\n for i in s:\n if i.isalpha():\n shift = ord(i) + 2 * 2\n if i.isupper():\n result += chr(shift) if shift <= ord('Z') else chr(shift - 26)\n else:\n result += chr(shift) if shift <= ord('z') else chr(shift - 26)\n else:\n result += i\n return result", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n result = \"\"\n for c in s:\n # Convert to Unicode code point, subtract 97 (for 'a'), add 2 * 2, \n # then get the modular 26 (number of letters in the alphabet) and add 'a' \n # (shift back to ASCII equivalent of the start of the alphabet).\n if c.isalpha():\n result += chr((ord(c.lower()) - 97 + 2 * 2) % 26 + 97)\n else:\n result += c\n return result", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n result = \"\"\n for char in s:\n if char.isalpha(): # only encrypt alphabet characters\n ascii_offset = 65 if char.isupper() else 97 # determine offset for upper and lower case letters\n encrypted_char = chr(((ord(char) - ascii_offset + 4) % 26) + ascii_offset) # apply offset and shift\n result += encrypted_char # add to result\n else:\n result += char # non-alphabet characters stay the same\n return result", "matching_cluster_idx": 1}, {"solution": "def rot2mult2(c):\n \"\"\"Encrypt a single character by shifting it down by two \n multiplied by two places. This function is used in encrypt()\n \"\"\"\n if not c.isalpha():\n return c\n offset = 2 * 2\n start = 'a' if c.islower() else 'A'\n return chr((ord(c) - ord(start) + offset) % 26 + ord(start))\ndef encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n \"\"\"\n return ''.join(rot2mult2(c) for c in s)", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n encrypted = \"\"\n for i in s:\n if i.isalpha():\n ascii_val = ord(i) + 2 * 2\n if i.isupper():\n if ascii_val > ord('Z'):\n encrypted += chr(ascii_val - 26)\n else:\n encrypted += chr(ascii_val)\n else:\n if ascii_val > ord('z'):\n encrypted += chr(ascii_val - 26)\n else:\n encrypted += chr(ascii_val)\n else:\n encrypted += i\n return encrypted", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n result = ''\n for i in s:\n if i.isalpha():\n ascii_num = ord(i) + 2 * 2\n if i.islower():\n if ascii_num > ord('z'):\n result += chr(ascii_num - 26)\n else:\n result += chr(ascii_num)\n else:\n if ascii_num > ord('Z'):\n result += chr(ascii_num - 26)\n else:\n result += chr(ascii_num)\n else:\n result += i\n return result", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n result = \"\"\n for i in s:\n if i.isalpha():\n ascii_offset = 65 if i.isupper() else 97\n i_shifted = chr((ord(i) - ascii_offset + 2*2) % 26 + ascii_offset)\n result += i_shifted\n else:\n result += i\n return result", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n encrypted = \"\"\n for char in s:\n # convert char to ascii\n ascii_value = ord(char)\n \n # check if char is an uppercase letter\n if 65 <= ascii_value <= 90:\n # increment char by 2*2 which is equivalent to rotation of 2 places\n encrypted += chr((ascii_value - 65 + 2*2) % 26 + 65)\n # check if char is a lowercase letter\n elif 97 <= ascii_value <= 122:\n # increment char by 2*2 which is equivalent to rotation of 2 places\n encrypted += chr((ascii_value - 97 + 2*2) % 26 + 97)\n else:\n # if char is not a letter, append it as is\n encrypted += char\n \n return encrypted", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"This function takes in a string 's' and returns a new string \n by shifting the alphabet down by 2 positions and multiplying \n by 2 places. For the lowercase alphabet it follows that 'a' \n becomes 'c' and 'b' becomes 'd'. For 'w' and 'x' it shifts 'y' \n and 'z', respectively. Similarly, 'A' becomes 'C' and 'B' becomes \n 'D'. For 'W' and 'X', it shifts 'Y' and 'Z', respectively.\"\"\"\n\n result = \"\"\n for letter in s:\n if 'a' <= letter <= 'z':\n letter = chr(((ord(letter) - ord('a') + 2 * 2) % 26) + ord('a'))\n elif 'A' <= letter <= 'Z':\n letter = chr(((ord(letter) - ord('A') + 2 * 2) % 26) + ord('A'))\n result += letter\n return result", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n encrypted = \"\"\n for char in s:\n if char.isalpha():\n shift = 2 * 2\n ascii_offset = 65 if char.isupper() else 97\n encrypted += chr((ord(char) - ascii_offset + shift) % 26 + ascii_offset)\n else:\n encrypted += char\n return encrypted", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n result = \"\"\n for char in s:\n if char.isalpha():\n offset = 2 * 2 if char.islower() else -(2 * 2)\n encrypted_char = chr(((ord(char) - (ord('a' if char.islower() else 'A')) + offset) % 26) + (ord('a' if char.islower() else 'A')))\n result += encrypted_char\n else:\n result += char\n return result", "matching_cluster_idx": 0}]}, "HumanEval/90": {"dps": 81.67315175097276, "dps_norm": 56.25, "pass@1": 54.0, "profiled": [{"solution": "def next_smallest(lst):\n if len(lst) < 2: # If list has less than 2 elements, return None\n return None\n else: # Remove duplicate elements if any and sort the list\n lst = list(set(lst))\n lst.sort()\n if len(lst) < 2: # If list has less than 2 unique elements, return None\n return None\n else: # Return the second smallest element\n return lst[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n if len(lst) < 2:\n return None\n \n first = second = float('inf')\n for num in lst:\n if num < first:\n first, second = num, first\n elif first < num < second:\n second = num\n \n return second if second != float('inf') else None", "matching_cluster_idx": 5}, {"solution": "def next_smallest(lst):\n unique_lst = list(set(lst)) # remove duplicates\n unique_lst.sort()\n return unique_lst[1] if len(unique_lst) > 1 else None", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n # Filter out duplicates and sort the list\n sorted_lst = sorted(list(set(lst)))\n \n # Return the second element if exists, otherwise return None\n return sorted_lst[1] if len(sorted_lst) > 1 else None", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \"\"\"\n unique_lst = list(set(lst)) # Remove duplicates if any\n unique_lst.sort() # Sort the list in ascending order\n if len(unique_lst) < 2: # If less than two elements are present, return None\n return None\n else:\n return unique_lst[1] # Return the second smallest element, index is 1 as lists are 0-indexed", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n unique_lst = list(set(lst))\n unique_lst.sort()\n if len(unique_lst) < 2:\n return None\n else:\n return unique_lst[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n if len(lst) < 2:\n return None\n lst = list(set(lst))\n lst.sort()\n return lst[1] if len(lst) > 1 else None", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \"\"\"\n # remove duplicates\n lst = list(set(lst))\n\n # return None if there's less than 2 distinct elements\n if len(lst) < 2:\n return None\n\n # sort the list and return the 2nd element\n return sorted(lst)[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n\n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n else:\n # Remove duplicates if any\n lst = list(set(lst))\n \n if len(lst) < 2:\n return None\n else:\n # Sort list and return 2nd smallest element\n lst.sort()\n return lst[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n\n Examples:\n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n # Remove duplicates from the list.\n lst = list(set(lst))\n \n # If list is empty or has only 1 element, return None.\n if len(lst) < 2:\n return None\n\n # Sort the list and return 2nd element (index 1) as it is the 2nd smallest element.\n return sorted(lst)[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \"\"\"\n \n unique_lst = list(set(lst))\n if len(unique_lst) < 2:\n return None\n else:\n unique_lst.sort()\n return unique_lst[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n Returns the 2nd smallest element of a list, or None if there is no such element.\n\n next_smallest([1, 2, 3, 4, 5]) \n next_smallest([5, 1, 4, 3, 2]) \n next_smallest([]) \n next_smallest([1, 1]) \n \"\"\"\n\n # Remove duplicates from the list\n lst = list(set(lst))\n\n # If there are less than 2 distinct elements in the list, return None\n if len(lst) < 2:\n return None\n\n # Sort the list and return the 2nd element (0-indexed)\n else:\n lst.sort()\n return lst[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n if len(lst) < 2:\n return None\n\n min_val = min(lst)\n min_val_second = None\n for num in lst:\n if num > min_val and (min_val_second is None or num < min_val_second):\n min_val_second = num\n\n return min_val_second", "matching_cluster_idx": 2}, {"solution": "def next_smallest(lst):\n \"\"\"\n This function finds the second smallest element in the list.\n \"\"\"\n # Removing duplicates and sorting the list\n lst = sorted(list(set(lst)))\n \n # Checking if the list has a second smallest number\n if len(lst) < 2:\n return None\n else:\n return lst[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n\n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n lst = list(set(lst)) # Remove duplicates\n lst.sort() # Sort the list\n if len(lst) < 2: # If there are less than 2 distinct elements\n return None\n else: # Return the 2nd smallest element\n return lst[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n lst = list(set(lst)) # remove duplicates\n if len(lst) < 2:\n return None\n else:\n lst.sort()\n return lst[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n Returns the 2nd smallest element of the list.\n \"\"\"\n unique_lst = list(set(lst)) # Remove duplicate elements\n if len(unique_lst) < 2: # If there are fewer than two distinct elements in the list, return None\n return None\n else:\n unique_lst.sort() # Sort the list in ascending order\n return unique_lst[1] # Return the 2nd smallest element in the list", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n # Removing duplicate elements if any\n lst = list(set(lst))\n\n # If the list only has one unique element, return None\n if len(lst) < 2:\n return None\n\n # Sorting the list and returning the second smallest element\n else:\n lst.sort()\n return lst[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \"\"\"\n\n # Remove duplicates\n lst = list(set(lst))\n \n # Check if there is only one element in the list or no elements at all\n if len(lst) < 2:\n return None\n \n # Sort the list and return the 2nd smallest element\n lst.sort()\n return lst[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n lst = list(set(lst))\n lst.sort()\n if len(lst) >= 2:\n return lst[1]\n else:\n return None", "matching_cluster_idx": 6}]}, "HumanEval/113": {"dps": 94.32048681541582, "dps_norm": 64.16666666666667, "pass@1": 50.0, "profiled": [{"solution": "def odd_count(lst):\n result = []\n for s in lst:\n odd_count = sum(1 for c in s if int(c) % 2 != 0)\n result.append(\"the number of odd elements {}n the str{}ng {} of the {}nput.\".format(odd_count, odd_count, odd_count, odd_count))\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n output = []\n for s in lst:\n odd_count = sum(int(c) % 2 for c in s)\n output.append(f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\")\n return output", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n output = []\n for i, string in enumerate(lst):\n count = sum(int(digit) % 2 for digit in string)\n result = f'the number of odd elements {count}n the str{count}ng {count} of the {count}nput.'\n output.append(result)\n return output", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n result = []\n for s in lst:\n count = sum([int(d) % 2 == 1 for d in s])\n result.append(f\"the number of odd elements {count}n the str{count}ng {count} of the {count}nput.\")\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n result = []\n for string in lst:\n count = sum(1 for c in string if int(c) % 2 != 0)\n result.append(f'the number of odd elements {count}n the str{count}ng {count} of the {count}nput.')\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n result = []\n for i in range(len(lst)):\n count = sum([int(x) % 2 for x in lst[i]])\n result.append(f\"the number of odd elements {count}n the str{count}ng {count} of the {count}nput.\")\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n output = []\n for i, s in enumerate(lst, start=1):\n odd_count = sum(int(c) % 2 for c in s)\n output.append(f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\")\n return output", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n res = []\n for i in lst:\n num_odds = sum(1 for char in i if int(char) % 2 == 1)\n res.append(\"the number of odd elements {}n the str{}ng {} of the {}nput.\".format(num_odds, num_odds, num_odds, num_odds))\n return res", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n result = []\n for i, s in enumerate(lst):\n odd_count = sum(int(digit) % 2 != 0 for digit in s)\n result.append(f'the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.')\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n def count_odds(s):\n return sum([1 for d in s if int(d) % 2 != 0])\n\n return [f\"the number of odd elements {count_odds(s)}n the str{count_odds(s)}ng {count_odds(s)} of the {count_odds(s)}nput.\" for s in lst]", "matching_cluster_idx": 0}, {"solution": "def odd_count(lst):\n output = []\n for string in lst:\n count = sum(1 for digit in string if int(digit) % 2 != 0)\n new_string = f\"the number of odd elements {count}n the str{count}ng {count} of the {count}nput.\"\n output.append(new_string)\n return output", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n output = []\n for i in range(len(lst)):\n odd_count = sum(int(digit) % 2 for digit in lst[i])\n output.append(f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\")\n return output", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n output = []\n for i in range(len(lst)):\n odd_count = len([digit for digit in lst[i] if int(digit) % 2 != 0])\n output.append(f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\")\n return output", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n result = []\n for s in lst:\n odd_count = sum(int(d) % 2 for d in s)\n result.append(f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\")\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n \"\"\"\n result = []\n for i in range(len(lst)):\n num_odd_digits = sum(1 for digit in lst[i] if int(digit) % 2 == 1)\n result.append(\"the number of odd elements \" + str(num_odd_digits) +\n \"n the str\" + str(num_odd_digits) + \"ng \" +\n str(num_odd_digits) + \" of the \" + str(num_odd_digits) + \"nput.\")\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n results = []\n for string in lst:\n odd_digits_count = len([digit for digit in string if int(digit) % 2 != 0])\n results.append(f\"the number of odd elements {odd_digits_count}n the str{odd_digits_count}ng {odd_digits_count} of the {odd_digits_count}nput.\")\n return results", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n results = []\n for i, string in enumerate(lst):\n odd_digits = sum(int(digit) % 2 for digit in string)\n result_str = f\"the number of odd elements {odd_digits}n the str{odd_digits}ng {odd_digits} of the {odd_digits}nput.\"\n results.append(result_str)\n return results", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n output = []\n for i in range(len(lst)):\n count = len([n for n in lst[i] if int(n) % 2 != 0])\n output.append(\"the number of odd elements {}n the str{}ng {} of the {}nput.\".format(count, count, count, count))\n return output", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n result = []\n for i, s in enumerate(lst):\n odd_count = sum(int(c) % 2 == 1 for c in s)\n result.append(f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\")\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n result = []\n for string in lst:\n count = sum(1 for char in string if int(char) % 2 != 0)\n result.append(\"the number of odd elements {}n the str{}ng {} of the {}nput.\".format(count, count, count, count))\n return result", "matching_cluster_idx": 3}]}, "HumanEval/119": {"dps": null, "dps_norm": null, "pass@1": 3.0, "profiled": []}, "HumanEval/120": {"dps": null, "dps_norm": null, "pass@1": 6.0, "profiled": []}, "HumanEval/121": {"dps": 85.51569506726457, "dps_norm": 65.0, "pass@1": 98.0, "profiled": [{"solution": "def solution(lst):\n return sum(num for index, num in enumerate(lst) if index % 2 == 0 and num % 2 != 0)", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n return sum(lst[i] for i in range(len(lst)) if i % 2 == 0 and lst[i] % 2 != 0)", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\"\"\"\n return sum(i for i in lst[::2] if i % 2 != 0)", "matching_cluster_idx": 5}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\"\"\"\n sum = 0\n for i in range(0, len(lst), 2):\n if lst[i] % 2 != 0:\n sum += lst[i]\n return sum", "matching_cluster_idx": 4}, {"solution": "def solution(lst):\n return sum(lst[i] for i in range(0, len(lst), 2) if lst[i] % 2 != 0)", "matching_cluster_idx": 4}, {"solution": "def solution(lst):\n return sum([lst[i] for i in range(0, len(lst), 2) if lst[i] % 2 != 0])", "matching_cluster_idx": 4}, {"solution": "def solution(lst):\n \"\"\"\n Given a non-empty list of integers, \n return the sum of all of the odd elements that are in even positions.\n\n Examples:\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==>0\n \"\"\"\n return sum(n for i, n in enumerate(lst) if i % 2 == 0 and n % 2 != 0)", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n return sum(lst[i] for i in range(0, len(lst), 2) if lst[i] % 2 != 0)", "matching_cluster_idx": 4}, {"solution": "def solution(lst):\n return sum(n for i, n in enumerate(lst) if i % 2 == 0 and n % 2 == 1)", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n return sum(val for idx, val in enumerate(lst) if idx % 2 == 0 and val % 2 != 0)", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n # Initialize sum at zero\n sum = 0\n # Iterate over the list\n for i in range(len(lst)):\n # Check if the current element is in an even index and is odd\n if i%2==0 and lst[i]%2==1:\n # Add it to the sum\n sum += lst[i]\n # Return the final sum\n return sum", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \"\"\"\n return sum(lst[i] for i in range(0, len(lst), 2) if lst[i] % 2 != 0)", "matching_cluster_idx": 4}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\"\"\"\n \n sum_odd_even_pos = 0\n for i in range(0, len(lst), 2): # iterate over even positions\n if lst[i] % 2 != 0: # if odd\n sum_odd_even_pos += lst[i]\n return sum_odd_even_pos", "matching_cluster_idx": 4}, {"solution": "def solution(lst):\n \"\"\"\n Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \"\"\"\n\n # Ensure the list is not empty\n if len(lst) == 0:\n return 0\n\n # Initialise the sum\n even_pos_odd_sum = 0\n\n # Iterate over the elements in the list\n for i in range(len(lst)):\n # Check if the element is at an even position and odd\n if i % 2 == 0 and lst[i] % 2 != 0:\n # Add the element to the sum\n even_pos_odd_sum += lst[i]\n\n # Return the sum\n return even_pos_odd_sum", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n sum = 0\n for i in range(0, len(lst), 2):\n if lst[i] % 2 != 0:\n sum += lst[i]\n return sum", "matching_cluster_idx": 4}, {"solution": "def solution(lst):\n return sum(i for i in lst[::2] if i % 2 != 0)", "matching_cluster_idx": 5}, {"solution": "def solution(lst):\n return sum(lst[i] for i in range(len(lst)) if i % 2 == 0 and lst[i] % 2 != 0)", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\"\"\"\n return sum(num for idx, num in enumerate(lst) if idx % 2 == 0 and num % 2 != 0)", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n\n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==>0\n \"\"\"\n return sum(x for i, x in enumerate(lst) if i % 2 == 0 and x % 2 != 0)", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\"\"\"\n return sum(lst[i] for i in range(len(lst)) if i % 2 == 0 and lst[i] % 2 != 0)", "matching_cluster_idx": 3}]}, "HumanEval/149": {"dps": 89.3700787401575, "dps_norm": 67.85714285714286, "pass@1": 92.0, "profiled": [{"solution": "def sorted_list_sum(lst):\n # Filter list to delete strings with odd lengths\n lst = [x for x in lst if len(x) % 2 == 0]\n \n # Return list sorted by length and then alphabetically\n return sorted(sorted(lst), key=len)", "matching_cluster_idx": 6}, {"solution": "def sorted_list_sum(lst):\n \"\"\"\n This function accepts a list of strings, removes the strings with odd lengths,\n sorts the remaining strings in a way that their length is always the same.\n \"\"\"\n # filter out odd-length strings\n lst = [word for word in lst if len(word) % 2 == 0]\n # sort by length, and then alphabetically\n return sorted(sorted(lst), key=len)", "matching_cluster_idx": 6}, {"solution": "def sorted_list_sum(lst):\n # Delete strings with odd lengths\n lst = [string for string in lst if len(string) % 2 == 0]\n \n # Sort by length then alphabetically\n lst.sort(key=lambda x: (len(x), x))\n \n return lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n # Delete the strings that have odd lengths from the list\n lst = [word for word in lst if len(word) % 2 == 0]\n \n # Sort the list by length of each word, and then alphabetically\n lst.sort(key=lambda word: (len(word), word))\n \n return lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n # delete strings with odd lengths\n lst = [s for s in lst if len(s) % 2 == 0]\n\n # sorting by length and then alphabetical order\n lst = sorted(lst, key=lambda s: (len(s), s))\n\n return lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"\n Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order,\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n You may assume that all words will have the same length.\n For example:\n \n assert list_sort([\"aa\", \"a\", \"aaa\"]) => [\"aa\"]\n assert list_sort([\"ab\", \"a\", \"aaa\", \"cd\"]) => [\"ab\", \"cd\"]\n \"\"\"\n # create a new list with even length strings\n even_length_lst = [s for s in lst if len(s) % 2 == 0]\n \n # sort the list of strings by length, then by alphabet\n sorted_lst = sorted(even_length_lst, key=lambda s: (len(s), s))\n \n return sorted_lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n # Filter out strings with odd lengths\n lst = [x for x in lst if len(x) % 2 == 0]\n\n # Sort the list first by length and then alphabetically\n lst.sort(key=lambda x: (len(x), x))\n\n return lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n # Filtering the strings with odd length\n filtered_lst = [word for word in lst if len(word) % 2 == 0]\n # Sorting the list first by length, then alphabetically\n sorted_lst = sorted(sorted(filtered_lst), key=len)\n return sorted_lst", "matching_cluster_idx": 6}, {"solution": "def sorted_list_sum(lst):\n even_length_lst = [word for word in lst if len(word) % 2 == 0]\n sorted_lst = sorted(even_length_lst, key=lambda word: (len(word), word))\n return sorted_lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n # Filter out strings with odd lengths\n lst = [i for i in lst if len(i) % 2 == 0]\n # Sort the list based on length and alphabetically\n lst.sort(key=lambda x: (len(x), x))\n return lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order,\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n You may assume that all words will have the same length.\n For example:\n assert sorted_list_sum([\"aa\", \"a\", \"aaa\"]) => [\"aa\"]\n assert sorted_list_sum([\"ab\", \"a\", \"aaa\", \"cd\"]) => [\"ab\", \"cd\"]\n \"\"\"\n\n # Filter out words with odd length\n lst = [word for word in lst if len(word) % 2 == 0]\n \n # Sort by length of each word, then alphabetically\n lst.sort(key=lambda word: (len(word), word))\n \n return lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n # Filter list of strings based on even length\n lst = [x for x in lst if len(x) % 2 == 0]\n \n # Sort the list of strings first by length and then alphabetically\n lst.sort(key=lambda x: (len(x), x))\n \n return lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order,\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n You may assume that all words will have the same length.\n For example:\n assert list_sort([\"aa\", \"a\", \"aaa\"]) => [\"aa\"]\n assert list_sort([\"ab\", \"a\", \"aaa\", \"cd\"]) => [\"ab\", \"cd\"]\n \"\"\"\n # filter out strings with odd length\n filtered_lst = [word for word in lst if len(word) % 2 == 0]\n # sort the list first by length, then alphabetically\n sorted_lst = sorted(sorted(filtered_lst), key=len)\n return sorted_lst", "matching_cluster_idx": 6}, {"solution": "def sorted_list_sum(lst):\n lst = [i for i in lst if len(i) % 2 == 0]\n return sorted(sorted(lst), key=len)", "matching_cluster_idx": 6}, {"solution": "def sorted_list_sum(lst):\n \"\"\"\n This function filters the list to remove strings of odd length, and then sorts the remaining strings.\n It compares the lengths of strings, and in case of a tie, sorts by alphabetical order.\n \"\"\"\n #filter list to remove strings of odd length\n lst = [x for x in lst if len(x)%2==0]\n \n #sort the list\n lst.sort(key=lambda x: (len(x),x))\n \n return lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n # Deleting strings with odd lengths\n lst = [i for i in lst if len(i) % 2 == 0]\n # Sorting list\n lst = sorted(lst, key=lambda x: (len(x), x))\n return lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n # Filter the list to only include strings of even length\n lst = [x for x in lst if len(x) % 2 == 0]\n\n # If the list is not empty, sort the list by length of each word,\n # and alphabetically within same length words\n if lst:\n lst.sort(key=lambda x: (len(x), x))\n\n return lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n # Filter out strings of odd length\n lst = [x for x in lst if len(x) % 2 == 0]\n \n # Sort the list first by length of string and then alphabetically\n lst = sorted(lst, key=lambda x: (len(x), x))\n \n return lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n # Remove the strings of odd length\n lst = [i for i in lst if len(i) % 2 == 0]\n # Return the list sorted by length and then alphabetically\n return sorted(lst, key=lambda x: (len(x), x))", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n # Remove strings with odd lengths\n lst = [word for word in lst if len(word) % 2 == 0]\n # Sort the list based on length and then alphabetically\n lst.sort(key=lambda x: (len(x), x))\n return lst", "matching_cluster_idx": 3}]}, "Mbpp/3": {"dps": 65.97457627118644, "dps_norm": 74.375, "pass@1": 91.0, "profiled": [{"solution": "def is_not_prime(n):\n \"\"\"\n This function takes an integer and checks whether it is a prime number or not.\n It returns False if the number is prime and True if it is not.\n\n Args:\n n (int): an integer to be checked\n\n Returns:\n bool: Returns True if n is not prime, else False.\n\n \"\"\"\n if n < 2:\n return True\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return True\n return False", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(n):\n if n <= 1:\n return True\n elif n <= 3:\n return False\n elif n % 2 == 0 or n % 3 == 0:\n return True\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return True\n i += 6\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n if n == 1:\n return True\n elif n == 2:\n return False\n else:\n for i in range(2, n):\n if (n % i) == 0:\n return True\n return False", "matching_cluster_idx": 0}, {"solution": "def is_not_prime(n):\n if n <= 1:\n return True\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return True\n return False", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(n):\n if n < 2:\n return True\n for i in range(2, n):\n if (n % i) == 0:\n return True\n return False", "matching_cluster_idx": 1}, {"solution": "def is_not_prime(n):\n if n <= 1:\n return True\n for i in range(2, n):\n if n % i == 0:\n return True\n return False", "matching_cluster_idx": 1}, {"solution": "def is_not_prime(n):\n \"\"\"\n This function checks whether the input number n is a non-prime number.\n \"\"\"\n if n <= 1:\n return True\n elif n <= 3:\n return False\n elif n%2 == 0 or n%3 == 0:\n return True\n i = 5\n while i * i <= n:\n if n%i == 0 or n%(i+2) == 0:\n return True\n i += 6\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n if n < 2:\n return True\n for i in range(2, int(n ** 0.5) + 1):\n if n % i == 0:\n return True\n return False", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(n):\n if n < 2:\n return True\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return True\n return False", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(num):\n if num < 2:\n return True\n for i in range(2, num):\n if num % i == 0:\n return True\n return False", "matching_cluster_idx": 1}, {"solution": "def is_not_prime(n):\n if n <= 1:\n return True\n if n == 2:\n return False\n if n % 2 == 0:\n return True\n for i in range(3, int(n**0.5)+1, 2):\n if n % i == 0:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n \"\"\"Return True if the number is not a prime number, False otherwise.\"\"\"\n if n <= 1:\n return True\n if n <= 3:\n return False\n if n%2 == 0 or n%3 == 0:\n return True\n i = 5\n while i*i <= n:\n if n%i == 0 or n%(i+2) == 0:\n return True\n i += 6\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n if n <= 1:\n return True\n elif n <= 3:\n return False\n elif n % 2 == 0 or n % 3 == 0:\n return True\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return True\n i += 6\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n if n < 2:\n return True\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return True\n return False", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(n):\n if n < 2:\n return True\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return True\n return False", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(n):\n if n < 2:\n return True # Numbers less than 2 are not primes by definition\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return True # The number is not a prime if it's divisible by any number up to its square root\n return False", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(n):\n \"\"\"\n This function checks if the given number n is a non-prime number\n \"\"\"\n if n <= 1:\n return True\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return True\n return False", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(n):\n if n <= 1:\n return True\n if n <= 3:\n return False\n if n % 2 == 0 or n % 3 == 0:\n return True\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return True\n i += 6\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n if n <= 1 or (n % 2 == 0 and n > 2):\n return True\n else:\n for i in range(3, int(n**0.5) + 1, 2):\n if n % i == 0:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n if n <= 1:\n return True\n if n <= 3:\n return False\n if n % 2 == 0 or n % 3 == 0:\n return True\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return True\n i += 6\n return False", "matching_cluster_idx": 7}]}, "Mbpp/4": {"dps": 88.05460750853243, "dps_norm": 83.33333333333333, "pass@1": 80.0, "profiled": [{"solution": "import heapq\ndef heap_queue_largest(numbers, n):\n return heapq.nlargest(n, numbers)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(numbers, n):\n return heapq.nlargest(n, numbers)", "matching_cluster_idx": 9}, {"solution": "def heap_queue_largest(lst, n):\n heap = lst[:n]\n import heapq\n heapq.heapify(heap)\n \n for val in lst[n:]:\n if val > heap[0]:\n heapq.heapreplace(heap, val)\n \n return sorted(heap, reverse=True)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(num_list, n):\n \"\"\"\n This function takes a list of numbers and an integer 'n' as input and \n returns the 'n' largest numbers from the list in descending order.\n \"\"\"\n\n # Using heapq library to create a max heap\n max_heap = []\n \n # Insert each number into max_heap\n for num in num_list:\n heapq.heappush(max_heap, -num)\n\n # Pop out 'n' largest numbers from max_heap\n result = [heapq.heappop(max_heap) * -1 for _ in range(n)]\n \n return result", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n \"\"\"\n Function to find the n largest integers from a given list of numbers, \n returned in descending order.\n \"\"\"\n # Using the heapq module\n return heapq.nlargest(n, nums)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(numbers, n):\n heap = numbers[:n]\n heapq.heapify(heap)\n for number in numbers[n:]:\n if number > heap[0]:\n heapq.heapreplace(heap, number)\n heap.sort(reverse=True)\n return heap", "matching_cluster_idx": 9}, {"solution": "def heap_queue_largest(lst, n):\n import heapq\n return heapq.nlargest(n, lst)", "matching_cluster_idx": 9}, {"solution": "def heap_queue_largest(numbers, n):\n if n > len(numbers):\n return []\n else:\n numbers.sort(reverse=True)\n return numbers[:n]", "matching_cluster_idx": 11}, {"solution": "import heapq\ndef heap_queue_largest(lst, n):\n return heapq.nlargest(n, lst)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(num_list, n):\n \"\"\"\n Return n largest integers from a given list of numbers in descending order.\n \"\"\"\n largest = heapq.nlargest(n, num_list)\n return largest", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(lst, n): \n \"\"\"\n This function takes as input a list of numbers and an integer n. \n The function returns a list containing the n largest integers from the given list. \n \"\"\"\n # Use the heapq library to create a max heap\n max_heap = [-x for x in lst]\n heapq.heapify(max_heap)\n\n # Pop the n largest elements from the max heap\n n_largest = [heapq.heappop(max_heap) for _ in range(n)]\n\n # Convert back to positive integers (heapq pops negative values) and return the list in reverse order\n return sorted([-x for x in n_largest], reverse=True)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(numbers, n):\n if n > len(numbers):\n print(\"Cannot find more than the total numbers in the list!\")\n return None\n else:\n # Use Python's built-in heapq library\n n_largest = heapq.nlargest(n, numbers)\n # Return in descending order\n return sorted(n_largest, reverse=True)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(num_list, n):\n if n > len(num_list) or n <= 0:\n raise ValueError('n should be between 1 and len(num_list)')\n largest_nums = heapq.nlargest(n, num_list)\n return largest_nums", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(lst, n):\n # Using Python's inbuilt heapq module to get the n largest elements\n return heapq.nlargest(n, lst)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(num_list, n):\n return sorted(heapq.nlargest(n, num_list), reverse=True)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(numbers, n):\n \"\"\"\n This function takes in a list of numbers and a positive integer n. \n It returns a list of the 'n' largest integers in the list, in descending order.\n \"\"\"\n # Use the nlargest function from heapq to find the n largest numbers.\n return heapq.nlargest(n, numbers)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(numbers, n):\n return heapq.nlargest(n, numbers)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n # Use heapify to turn list into a heap, in-place, in O(len(list)) time.\n heapq.heapify(nums)\n # Use nlargest to get the n largest numbers in a list.\n # The function itself is a wrapper around the more generic function, nlargest() and can handle larger input lists.\n return heapq.nlargest(n, nums)", "matching_cluster_idx": 8}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n # Use a heap to get the n largest numbers in descending order\n return sorted(heapq.nlargest(n, nums), reverse=True)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n # Using heapify to convert list into heap\n heapq.heapify(nums)\n # Iterate n times\n for i in range(len(nums) - n):\n # Remove smallest (topmost element)\n heapq.heappop(nums)\n # Use nlargest to get top n elements\n result = heapq.nlargest(n, nums)\n return result", "matching_cluster_idx": 8}]}, "Mbpp/9": {"dps": 73.80952380952381, "dps_norm": 55.0, "pass@1": 16.0, "profiled": [{"solution": "def find_Rotations(string):\n \"\"\"Function to find minimum number of rotations required\"\"\"\n # store the length of the string\n length = len(string)\n # append the string with itself, and then slice off the first\n # and last elements, storing the rest in new_string. Repeat\n # this process by incrementing the index i\n for i in range(1, length):\n new_string = string[i:length] + string[0:i]\n if new_string == string:\n return i\n return length", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(string):\n length = len(string)\n temp = string + string\n for i in range(1, length):\n if temp[i:i+length] == string:\n return i\n return length", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(str1):\n rotations = 1\n len_str = len(str1)\n temp = str1 + str1\n for i in range(1, len_str):\n if temp[i:i + len_str] == str1:\n return rotations\n rotations += 1\n return rotations", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(s):\n n = len(s)\n for i in range(1,n):\n # generate all rotations of the string\n temp = s[i:]+s[:i]\n # If we find a duplicate rotation, then return 'i'\n if s==temp:\n return i\n return n", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(str1):\n str2 = str1 + str1\n n = len(str1)\n for i in range(1, n):\n substring = str2[i:i+n]\n if substring == str1:\n return i\n return n", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(str1):\n str1 += str1\n n = len(str1)\n for i in range(1, n//2):\n if str1[i:n] + str1[0:i] == str1:\n return i\n return n//2", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(string):\n size = len(string)\n temp = string + string\n for i in range(1, size):\n if temp[i: i + size] == string:\n return i\n return size", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(input_string):\n if len(input_string) == 1:\n return 0\n else:\n for i in range(1, len(input_string)):\n if input_string == input_string[i:] + input_string[:i]:\n return i\n return len(input_string)", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(string):\n length = len(string)\n if length == 0:\n return 0\n for i in range(1, length):\n # Take substring of string from i to length-1 and add to front\n # if it matches with original string\n temp = string[i:] + string[0:i]\n if string == temp:\n return i\n return length", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(string):\n double_string = string + string\n length = len(string)\n for i in range(1, length):\n if double_string[i:i+length] == string:\n return i\n return length", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(s: str) -> int:\n length = len(s)\n temp = s + s\n for i in range(1, length):\n if temp[i:i + length] == s:\n return i\n return length", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(s):\n # The function will look for the minimum number of rotations required to get the same string.\n n = len(s)\n for i in range(1, n):\n if s[i:] + s[:i] == s:\n return i\n return n", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(str1):\n str1 = str1.lower()\n len_str1 = len(str1)\n \n # Finding the rotation length\n for i in range(1, len_str1):\n if str1[i:] + str1[:i] == str1:\n return i\n \n return len_str1", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(s):\n if len(s) == 1:\n return 0\n for i in range(1, len(s)):\n if s[i:] + s[:i] == s:\n return i\n return len(s)", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(s):\n s2 = s + s\n for i in range(1, len(s)):\n if s2[i:i+len(s)] == s:\n return i\n return len(s)", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(input_str):\n size = len(input_str)\n temp = input_str + input_str # Concatenating the string to itself\n for i in range(1, size):\n substring = temp[i:size+i]\n if substring == input_str: # Comparing with original string\n return i\n return size", "matching_cluster_idx": 5}]}, "Mbpp/11": {"dps": 82.00716845878136, "dps_norm": 90.0, "pass@1": 47.0, "profiled": [{"solution": "def remove_Occ(string, char):\n first_occurrence = string.find(char)\n last_occurrence = string.rfind(char)\n if first_occurrence != -1: # char found in string\n string = string[:first_occurrence] + string[first_occurrence+1:] # remove first occurrence\n if last_occurrence != first_occurrence: # ensure not already removed\n string = string[:last_occurrence-1] + string[last_occurrence:] # remove last occurrence\n return string", "matching_cluster_idx": 7}, {"solution": "def remove_Occ(s, c):\n # Finding the first and last occurrence of character \n first_index = s.find(c)\n last_index = s.rfind(c)\n\n # If character is found in the string\n if first_index != -1 and last_index != -1:\n return s[:first_index] + s[first_index+1:last_index] + s[last_index+1:]\n else:\n # If character is not found in the string\n return s", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(s, char):\n first_char = s.find(char)\n if first_char != -1: # if character is in the string\n last_char = s.rfind(char)\n # if first and last occurrence of character are same, remove only one occurrence\n if first_char == last_char:\n return s[:first_char] + s[first_char+1:]\n # if they're not same, remove first and last occurrence\n else:\n return s[:first_char] + s[first_char+1:last_char] + s[last_char+1:]\n else: # if character is not in the string\n return s", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(string, char):\n if char in string:\n # Find the first and last occurrence of the character\n first_index = string.index(char)\n last_index = string.rindex(char)\n \n # Remove the first and last occurrence from the string\n new_string = string[:first_index] + string[first_index + 1:last_index] + string[last_index + 1:]\n \n return new_string\n else:\n # The character doesn't exist in the string, return the original string\n return string", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(str, char):\n # Find first and last occurrence of the character\n first_index = str.find(char)\n last_index = str.rfind(char)\n\n # If the character is not in the string\n if first_index == -1:\n return str\n\n # Remove the first and last occurrence of the character\n result = str[:first_index] + str[first_index + 1:last_index] + str[last_index + 1:]\n\n return result", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(string, character):\n first_index = string.find(character)\n last_index = string.rfind(character)\n \n if first_index != -1 and last_index != -1 and first_index != last_index:\n string = string[:first_index] + string[first_index+1:last_index] + string[last_index+1:]\n elif first_index != -1:\n string = string[:first_index] + string[first_index+1:]\n elif last_index != -1:\n string = string[:last_index] + string[last_index+1:]\n \n return string", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(s, c):\n \"\"\"\n Remove the first and last occurrence of character c in string s.\n \"\"\"\n # Find first occurrence of c\n first = s.find(c)\n # If c not in s\n if first == -1:\n return s\n # Find last occurrence of c\n last = s.rfind(c)\n # If c is at position 0, then remove the first occurrence,\n # else remove both the first and last occurrences\n if first == last:\n return s[:first] + s[first+1:]\n else:\n return s[:first] + s[first+1:last] + s[last+1:]", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(s, c):\n first_occ = s.find(c)\n last_occ = s.rfind(c)\n\n if first_occ != -1 and last_occ != -1 and first_occ != last_occ:\n s = s[:first_occ] + s[first_occ+1:last_occ] + s[last_occ+1:]\n elif first_occ != -1 and last_occ != -1 and first_occ == last_occ:\n s = s[:first_occ] + s[first_occ+1:]\n\n return s", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(input_string, char):\n first_occurrence = input_string.find(char)\n if first_occurrence != -1:\n last_occurrence = input_string.rfind(char)\n if last_occurrence == first_occurrence:\n return input_string[:first_occurrence] + input_string[first_occurrence + 1:]\n else:\n return input_string[:first_occurrence] + input_string[first_occurrence + 1:last_occurrence] + input_string[last_occurrence + 1:]\n else:\n return input_string", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(input_string, char):\n if char in input_string:\n first_occ = input_string.index(char)\n last_occ = input_string.rindex(char)\n if first_occ == last_occ:\n return input_string[:first_occ] + input_string[first_occ+1:]\n else:\n return input_string[:first_occ] + input_string[first_occ+1:last_occ] + input_string[last_occ+1:]\n else:\n return input_string", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(s, char):\n # Check if character exists in the string\n if char in s:\n # Find the index of first and last occurrence\n first_index = s.index(char)\n last_index = s.rindex(char)\n # Remove first and last occurrence\n s = s[:first_index] + s[first_index+1:last_index] + s[last_index+1:]\n return s", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(input_str, char):\n first_index = input_str.find(char)\n last_index = input_str.rfind(char)\n \n if first_index == -1 or last_index == -1:\n return input_str\n elif first_index == last_index:\n return input_str[:first_index] + input_str[first_index + 1:]\n else:\n return input_str[:first_index] + input_str[first_index + 1:last_index] + input_str[last_index + 1:]", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(string, char):\n # Remove the first occurrence of the character\n string = string.replace(char, '', 1)\n # Reverse the string\n string = string[::-1]\n # Remove the first occurrence of the character\n string = string.replace(char, '', 1)\n # Reverse the string back to its original form\n string = string[::-1]\n return string", "matching_cluster_idx": 3}, {"solution": "def remove_Occ(input_str, char):\n # Remove first occurrence of the character\n input_str = input_str.replace(char, '', 1)\n # Remove last occurrence of the character\n reverse_str = input_str[::-1]\n input_str = reverse_str.replace(char, '', 1)\n input_str = input_str[::-1]\n return input_str", "matching_cluster_idx": 4}, {"solution": "def remove_Occ(s, char):\n try:\n index_first = s.index(char)\n index_last = s.rindex(char)\n return s[:index_first] + s[index_first+1:index_last] + s[index_last+1:]\n except ValueError:\n print(\"Character not found in string.\")\n return s", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(str1, ch):\n if ch in str1:\n first_occurrence = str1.find(ch)\n last_occurrence = str1.rfind(ch)\n str1 = str1[:first_occurrence] + str1[first_occurrence+1:last_occurrence] + str1[last_occurrence+1:]\n return str1", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(s, c):\n index = -1\n for i in range(len(s)):\n if s[i] == c:\n index = i\n break\n if index != -1:\n s = s[0:index] + s[index+1:]\n index = -1\n for i in range(len(s)):\n if s[i] == c:\n index = i\n if index != -1:\n s = s[0:index] + s[index+1:]\n return s", "matching_cluster_idx": 0}, {"solution": "def remove_Occ(string, char):\n while char in string:\n first_index = string.index(char)\n last_index = string.rindex(char)\n if first_index == last_index:\n return string[:first_index] + string[first_index + 1:]\n else:\n return string[:first_index] + string[first_index + 1:last_index] + string[last_index + 1:]\n return string", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(string, char):\n first = string.find(char)\n if first != -1:\n last = string.rfind(char)\n if first != last:\n return string[:first] + string[first+1:last] + string[last+1:]\n else:\n return string[:first] + string[first+1:]\n return string", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(s, c):\n # Find the index of the first occurrence of the character\n index_first = s.find(c)\n # If the character exists in the string\n if index_first != -1:\n # Find the index of the last occurrence of the character\n index_last = s.rfind(c)\n # Remove the first occurrence of the character and the last occurrence if they are different\n if index_first != index_last:\n return s[:index_first] + s[index_first+1:index_last] + s[index_last+1:]\n # If they are the same (only one occurrence), return the string without the first occurrence\n else:\n return s[:index_first] + s[index_first+1:]\n # If the character does not exist in the string, return the original string\n else:\n return s", "matching_cluster_idx": 8}]}, "Mbpp/12": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 94.0, "profiled": [{"solution": "def sort_matrix(matrix):\n # Calculate the sum of each row in the matrix\n sums = [sum(row) for row in matrix]\n # Sort the matrix according to the sums\n sorted_matrix = [row for (_, row) in sorted(zip(sums, matrix))]\n return sorted_matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n return sorted(matrix, key=sum)", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n return sorted(matrix, key=sum)", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Sort the matrix in-place based on the sum of its rows.\n matrix.sort(key=sum)\n return matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # calculate the sum for each row and store it along with the row index\n row_sums = [(sum(row), i) for i, row in enumerate(matrix)]\n \n # sort the row_sums by the sum and keep the row index\n sorted_row_sums = sorted(row_sums)\n sorted_rows = [matrix[i] for _, i in sorted_row_sums]\n return sorted_rows", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n return [row for row in sorted(matrix, key=sum)]", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"\n This function sorts a given matrix in ascending order based on the sum of its rows.\n \"\"\"\n matrix.sort(key=sum)\n return matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n return sorted(matrix, key=sum)", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # return sorted matrix based on row sums\n return sorted(matrix, key=sum)", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Sort the matrix rows by their sum\n sorted_matrix = sorted(matrix, key=sum)\n return sorted_matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n return sorted(matrix, key=sum)", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"\n Returns a sorted version of the provided matrix based on the sum of its rows.\n \n :param matrix: The matrix to be sorted.\n :return: A sorted version of the provided matrix.\n \"\"\"\n # Sort the matrix by row sums\n return sorted(matrix, key=sum)", "matching_cluster_idx": 15}, {"solution": "def sum_rows(matrix):\n return [sum(row) for row in matrix]\ndef sort_matrix(matrix):\n rows_sum = sum_rows(matrix)\n sorted_indices = sorted(range(len(rows_sum)), key=lambda i: rows_sum[i])\n return [matrix[i] for i in sorted_indices]", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Calculate the sum for each row in the matrix\n row_sums = [sum(row) for row in matrix]\n\n # Create a list of tuples, where each tuple contains an index and the corresponding row sum\n rows_and_sums = list(enumerate(row_sums))\n\n # Sort the list of tuples based on the row sum\n sorted_rows_and_sums = sorted(rows_and_sums, key=lambda x: x[1])\n\n # Extract the original row from the matrix using the sorted indices\n sorted_matrix = [matrix[i] for i, _ in sorted_rows_and_sums]\n\n return sorted_matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Here we use the key parameter of the sorted function to sort by the sum of rows\n return sorted(matrix, key=sum)", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n return sorted(matrix, key=sum)", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n return [row for row in sorted(matrix, key=sum)]", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # calculate the sum for each row in the matrix\n sums = [sum(row) for row in matrix]\n # sort the matrix based on the calculated sums\n result = [x for _, x in sorted(zip(sums, matrix))]\n return result", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n return sorted(matrix, key=sum)", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n return [row for row in sorted(matrix, key=sum)]", "matching_cluster_idx": 15}]}, "Mbpp/16": {"dps": 71.64634146341464, "dps_norm": 80.0, "pass@1": 32.0, "profiled": [{"solution": "import re\ndef text_lowercase_underscore(s):\n pattern = re.compile(r'^[a-z]+(_[a-z]+)*$')\n if pattern.match(s):\n return True\n else:\n return False", "matching_cluster_idx": 7}, {"solution": "def text_lowercase_underscore(input_string):\n # Split the string by underscore and check each part\n for word in input_string.split('_'):\n if not word.islower(): # if any part is not lowercase\n return False\n return True # if all parts are lowercase", "matching_cluster_idx": 5}, {"solution": "def text_lowercase_underscore(text):\n parts = text.split(\"_\")\n for part in parts:\n if not part.islower():\n return False\n return True", "matching_cluster_idx": 5}, {"solution": "import re\ndef text_lowercase_underscore(text):\n pattern = r'^[a-z]+(_[a-z]+)*$'\n if re.match(pattern, text):\n return True\n else:\n return False", "matching_cluster_idx": 7}, {"solution": "def text_lowercase_underscore(text):\n parts = text.split('_')\n for part in parts:\n if not part.islower():\n return False\n return True", "matching_cluster_idx": 5}, {"solution": "import re\ndef text_lowercase_underscore(input_string):\n # Regular expression to match lowercase letters joined with underscores\n pattern = r'^[a-z]+(_[a-z]+)*$'\n # Using match function with the pattern and input_string\n if re.match(pattern, input_string):\n return True\n else:\n return False", "matching_cluster_idx": 7}, {"solution": "def text_lowercase_underscore(text):\n # Split text into separate words\n words = text.split('_')\n\n # Check each word to ensure it contains only lowercase letters\n for word in words:\n if not word.islower():\n return False\n \n return True", "matching_cluster_idx": 5}, {"solution": "def text_lowercase_underscore(input_string):\n # Split string by underscore and check if each part is lowercase\n parts = input_string.split('_')\n for part in parts:\n if not part.islower():\n return False\n return True", "matching_cluster_idx": 5}, {"solution": "def text_lowercase_underscore(text):\n parts = text.split('_')\n for part in parts:\n if not part.islower():\n return False\n return True", "matching_cluster_idx": 5}, {"solution": "def text_lowercase_underscore(s):\n if not s:\n return False\n for word in s.split('_'):\n if not word.islower():\n return False\n return True", "matching_cluster_idx": 5}, {"solution": "import re\ndef text_lowercase_underscore(text):\n \"\"\"\n This function returns True if the input string contains sequences of lowercase \n letters joined with an underscore and False otherwise.\n \"\"\"\n # Using regular expression to check if the string contains the pattern of lowercase letters joined with an underscore\n pattern = re.compile(r'^[a-z]+(_[a-z]+)*$')\n if pattern.match(text):\n return True\n else:\n return False", "matching_cluster_idx": 7}, {"solution": "import re\ndef text_lowercase_underscore(s):\n return bool(re.fullmatch('[a-z]+(_[a-z]+)*', s))", "matching_cluster_idx": 7}, {"solution": "def text_lowercase_underscore(text):\n if not text: # For the case when the text is empty\n return False\n words = text.split('_')\n for word in words:\n if not word.islower(): # If any word is not in lowercase\n return False\n return True", "matching_cluster_idx": 5}, {"solution": "def text_lowercase_underscore(text):\n # split the text into words\n words = text.split(\"_\")\n \n # check if each word is only lowercase and consists of letters\n for word in words:\n if not word.islower() or not word.isalpha():\n return False\n return True", "matching_cluster_idx": 5}, {"solution": "def text_lowercase_underscore(text):\n for word in text.split(\"_\"):\n if not word.islower():\n return False\n return True", "matching_cluster_idx": 5}, {"solution": "def text_lowercase_underscore(s):\n import re\n pattern = r'^[a-z]+(_[a-z]+)*$'\n if re.match(pattern, s):\n return True\n else:\n return False", "matching_cluster_idx": 7}, {"solution": "def text_lowercase_underscore(s):\n s = s.split('_')\n return all(x.islower() and x.isalpha() for x in s)", "matching_cluster_idx": 5}, {"solution": "def text_lowercase_underscore(text):\n # Split the text into words using underscore as separator\n words = text.split('_')\n # For each word, check if it's a lowercase string\n return all(word.islower() for word in words)", "matching_cluster_idx": 5}, {"solution": "import re\ndef text_lowercase_underscore(string):\n # Using Regular Expression to check if string contains lowercase letters joined with an underscore\n if re.search(r'^[a-z]+(_[a-z]+)*$', string):\n return True\n else:\n return False", "matching_cluster_idx": 3}, {"solution": "import re\ndef text_lowercase_underscore(input_string):\n pattern = r\"^[a-z]+(_[a-z]+)*$\"\n if re.search(pattern, input_string):\n return True\n else:\n return False", "matching_cluster_idx": 3}]}, "Mbpp/19": {"dps": 66.41414141414141, "dps_norm": 81.0, "pass@1": 94.0, "profiled": [{"solution": "def test_duplicate(input_array):\n # Convert list to set to check if duplicate exist (Set only allows unique elements)\n if len(input_array) == len(set(input_array)):\n return False\n else:\n return True", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(nums):\n return len(nums) != len(set(nums))", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(arr):\n if len(arr) == len(set(arr)):\n return False\n else:\n return True", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(arr):\n return len(arr) != len(set(arr))", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(arr):\n return len(arr) != len(set(arr))", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(input_list):\n \"\"\"Check if the list has any duplicate elements\"\"\"\n if len(input_list) == len(set(input_list)):\n return False\n else:\n return True", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(nums):\n # Check if there are any duplicates in a list of integers\n return len(nums) != len(set(nums))", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(arr):\n if len(arr) == len(set(arr)):\n return False\n else:\n return True", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(arr):\n if len(arr) == len(set(arr)):\n return False\n else:\n return True", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(nums):\n if len(nums) == len(set(nums)):\n return False\n else:\n return True", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(arr):\n return len(arr) != len(set(arr))", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(lst):\n return len(lst) != len(set(lst))", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(lst):\n # The below line creates a set from the list and then checks if length of list and set are equal\n return len(lst) != len(set(lst))", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(array):\n \"\"\"\n This function takes a list of integers as input and checks if it contains any duplicate element.\n \"\"\"\n # Using a set to check for duplicates in list\n if len(array) == len(set(array)):\n return False\n else:\n return True", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(arr):\n return len(set(arr)) != len(arr)", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(arr):\n # using set to check for duplicates, as sets don't allow duplicates\n return len(arr) != len(set(arr))", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(nums):\n return len(nums) != len(set(nums))", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(arr):\n return len(arr) != len(set(arr))", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(numbers):\n seen = set()\n for number in numbers:\n if number in seen:\n return True\n seen.add(number)\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(lst):\n return len(lst) != len(set(lst))", "matching_cluster_idx": 11}]}, "Mbpp/62": {"dps": 98.5, "dps_norm": 99.0, "pass@1": 100.0, "profiled": [{"solution": "def smallest_num(lst):\n # Initialize the first element as smallest\n smallest = lst[0]\n \n # Iterate over the list\n for num in lst:\n # If the current number is less than the smallest found so far, then update the smallest\n if num < smallest:\n smallest = num\n \n # Return the smallest number\n return smallest", "matching_cluster_idx": 3}, {"solution": "def smallest_num(lst):\n return min(lst)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(nums):\n return min(nums)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(lst):\n return min(lst)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(lst):\n return min(lst)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(lst):\n \"\"\"\n Write a python function to find smallest number in a list.\n \"\"\"\n return min(lst)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(nums):\n return min(nums)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(num_list):\n return min(num_list)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(num_list):\n \"\"\"\n This function accepts a list of numbers as an argument\n and returns the smallest number in the list.\n \"\"\"\n return min(num_list)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(lst):\n return min(lst)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(num_list):\n return min(num_list)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(lst):\n \"\"\"\n This function returns the smallest number in a list.\n\n Args:\n lst (list): A list of integers.\n\n Returns:\n int: The smallest number in the list.\n \"\"\"\n return min(lst)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(numbers):\n return min(numbers)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(lst):\n \"\"\"\n Function to find smallest number in a list.\n \"\"\"\n return min(lst)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(lst):\n \"\"\"\n This function receives a list of numbers and returns the smallest number.\n Parameters:\n lst (list): A list of numbers.\n Returns:\n The smallest number in the list.\n \"\"\"\n return min(lst)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(lst):\n return min(lst)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(lst):\n # Return minimum number in list\n return min(lst)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(lst):\n return min(lst)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(lst):\n \"\"\"\n This function finds the smallest number in a list\n \"\"\"\n return min(lst)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(num_list):\n \"\"\"Function to find the smallest number in a list\"\"\"\n return min(num_list)", "matching_cluster_idx": 4}]}, "Mbpp/75": {"dps": 92.85714285714286, "dps_norm": 66.66666666666667, "pass@1": 100.0, "profiled": [{"solution": "def find_tuples(tuples, k):\n result = []\n for tup in tuples:\n if all(elem % k == 0 for elem in tup):\n result.append(tup)\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n result = []\n for tup in tuples_list:\n if all(i % k == 0 for i in tup):\n result.append(tup)\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(list_of_tuples, k):\n return [t for t in list_of_tuples if all(i % k == 0 for i in t)]", "matching_cluster_idx": 5}, {"solution": "def find_tuples(lst, k):\n \"\"\"Find tuples with all elements divisible by k\"\"\"\n result = [tpl for tpl in lst if all(x % k == 0 for x in tpl)]\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tup_list, k):\n return [tup for tup in tup_list if all(i % k == 0 for i in tup)]", "matching_cluster_idx": 5}, {"solution": "def find_tuples(lst, k):\n return [t for t in lst if all(i % k == 0 for i in t)]", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tup_list, k):\n res = []\n for tup in tup_list:\n if all(i % k == 0 for i in tup):\n res.append(tup)\n return res", "matching_cluster_idx": 5}, {"solution": "def find_tuples(lst, k):\n return [t for t in lst if all(x % k == 0 for x in t)]", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tup_list, k):\n result = []\n for t in tup_list:\n if all(element % k == 0 for element in t):\n result.append(t)\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n return [t for t in tuples_list if all(i % k == 0 for i in t)]", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n return [t for t in tuples_list if all(i % k == 0 for i in t)]", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n result = [t for t in tuples_list if all(x % k == 0 for x in t)]\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuple_list, k):\n return [t for t in tuple_list if all(x % k == 0 for x in t)]", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n result = [t for t in tuples_list if all(elem % k == 0 for elem in t)]\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n return [t for t in tuples_list if all(el % k == 0 for el in t)]", "matching_cluster_idx": 5}, {"solution": "def find_tuples(lst, k):\n result = [t for t in lst if all(i % k == 0 for i in t)]\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples, k):\n return [t for t in tuples if all(element % k == 0 for element in t)]", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuple_list, k):\n return [t for t in tuple_list if all(i % k == 0 for i in t)]", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuple_list, k):\n result = [tup for tup in tuple_list if all(elem % k == 0 for elem in tup)]\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(lst, k):\n result = []\n for tup in lst:\n if all(elem % k == 0 for elem in tup):\n result.append(tup)\n return result", "matching_cluster_idx": 5}]}, "Mbpp/88": {"dps": 84.50980392156862, "dps_norm": 77.85714285714285, "pass@1": 100.0, "profiled": [{"solution": "def freq_count(lst):\n freqs = {}\n for i in lst:\n if i in freqs:\n freqs[i] += 1\n else:\n freqs[i] = 1\n return freqs", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n frequency = {}\n for num in lst:\n if num in frequency:\n frequency[num] += 1\n else:\n frequency[num] = 1\n return frequency", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n count_dict = {}\n for i in lst:\n if i in count_dict:\n count_dict[i] += 1\n else:\n count_dict[i] = 1\n return count_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n return {i: lst.count(i) for i in lst}", "matching_cluster_idx": 0}, {"solution": "def freq_count(lst):\n frequency = {}\n for item in lst:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n return frequency", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n return {i: lst.count(i) for i in lst}", "matching_cluster_idx": 0}, {"solution": "def freq_count(lst):\n freqs = {}\n for num in lst:\n if num in freqs:\n freqs[num] += 1\n else:\n freqs[num] = 1\n return freqs", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n freqs = {}\n for num in lst:\n if num in freqs:\n freqs[num] += 1\n else:\n freqs[num] = 1\n return freqs", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n freq = {}\n for item in lst:\n if item in freq:\n freq[item] += 1\n else:\n freq[item] = 1\n return freq", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n # Initialize an empty dictionary\n frequency_dict = {}\n \n # Iterate over the list\n for item in lst:\n # If the item is in the dictionary, increment its count.\n if item in frequency_dict:\n frequency_dict[item] += 1\n # If the item is not in the dictionary, add it with a count of 1.\n else:\n frequency_dict[item] = 1\n \n return frequency_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n freqs = {}\n for item in lst:\n if item in freqs:\n freqs[item] += 1\n else:\n freqs[item] = 1\n return freqs", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n freq_dict = {}\n for i in lst:\n freq_dict[i] = freq_dict.get(i, 0) + 1\n return freq_dict", "matching_cluster_idx": 4}, {"solution": "def freq_count(input_list):\n frequency_dict = {}\n for i in input_list:\n if (i in frequency_dict):\n frequency_dict[i] += 1\n else:\n frequency_dict[i] = 1\n return frequency_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n freq_dict = {}\n for num in lst:\n if num in freq_dict:\n freq_dict[num] += 1\n else:\n freq_dict[num] = 1\n return freq_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n freq_dict = {}\n for item in lst:\n if item in freq_dict:\n freq_dict[item] += 1\n else:\n freq_dict[item] = 1\n return freq_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n freq_dict = {}\n for item in lst:\n if item in freq_dict:\n freq_dict[item] += 1\n else:\n freq_dict[item] = 1\n return freq_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n freq = {}\n for item in lst:\n if item in freq:\n freq[item] += 1\n else:\n freq[item] = 1\n return freq", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n freq = {}\n for item in lst:\n if item not in freq:\n freq[item] = 1\n else:\n freq[item] += 1\n return freq", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n freq_dict = {}\n for i in lst:\n if i in freq_dict:\n freq_dict[i] += 1\n else:\n freq_dict[i] = 1\n return freq_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n freq = {}\n for i in lst:\n if i in freq:\n freq[i] += 1\n else:\n freq[i] = 1\n return freq", "matching_cluster_idx": 5}]}, "Mbpp/90": {"dps": 72.85365853658537, "dps_norm": 82.85714285714285, "pass@1": 67.0, "profiled": [{"solution": "def len_log(words):\n \"\"\"\n The function len_log() takes a list of words as input and returns the length of the longest word in the list.\n \"\"\"\n max_length = 0\n for word in words:\n if len(word) > max_length:\n max_length = len(word)\n return max_length", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n return max(len(word) for word in words)", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n return max(len(word) for word in words)", "matching_cluster_idx": 5}, {"solution": "def len_log(word_list):\n return max(len(word) for word in word_list)", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n return max(len(word) for word in words)", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n return max(len(word) for word in words)", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n return max(len(word) for word in words)", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n return max(len(word) for word in words)", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n return max(len(word) for word in words)", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n return max(len(word) for word in words)", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n return max(len(word) for word in words)", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n return max(len(word) for word in words)", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n return max(len(word) for word in words)", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n # Initializing max_len with 0 to compare against the length of the words\n max_len = 0\n for word in words:\n # If length of word is more than max_len, updating max_len\n if len(word) > max_len:\n max_len = len(word)\n return max_len", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n # First, we'll iterate over each word in the list\n for word in words:\n # For each word, we'll count its length and keep track of the largest\n word_length = len(word)\n if 'longest_word_length' not in locals():\n longest_word_length = word_length\n elif word_length > longest_word_length:\n longest_word_length = word_length\n return longest_word_length", "matching_cluster_idx": 2}, {"solution": "def len_log(words):\n return max(len(word) for word in words)", "matching_cluster_idx": 5}, {"solution": "def len_log(word_list):\n \"\"\"\n This function returns the length of the longest word in a given list of words.\n \"\"\"\n return max(len(word) for word in word_list)", "matching_cluster_idx": 5}, {"solution": "def len_log(list_words):\n # Initialize max_len with the length of the first word in the list\n max_len = len(list_words[0])\n\n # Iterate over the list of words to find the longest word\n for word in list_words:\n if len(word) > max_len:\n max_len = len(word)\n\n # Return the length of the longest word\n return max_len", "matching_cluster_idx": 5}, {"solution": "def len_log(list):\n #Initialize a variable to hold the length of the longest word\n max_len = len(list[0])\n #Initialize a variable to hold the longest word\n max_word = list[0]\n\n #Traverse through the list to find the word with maximum length\n for i in range(1, len(list)):\n if max_len < len(list[i]):\n max_len = len(list[i])\n max_word = list[i]\n\n return max_len", "matching_cluster_idx": 4}, {"solution": "def len_log(word_list):\n return max(len(word) for word in word_list)", "matching_cluster_idx": 5}]}, "Mbpp/94": {"dps": 82.85060975609755, "dps_norm": 69.0, "pass@1": 94.0, "profiled": [{"solution": "def index_minimum(lst):\n return min(lst, key=lambda t: t[1])[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(tuples):\n \"\"\"Return the first value of the tuple with the smallest second value.\"\"\"\n if not tuples:\n raise ValueError(\"The list of tuples is empty\")\n min_tuple = min(tuples, key=lambda x: x[1])\n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(lst):\n return min(lst, key=lambda x: x[1])[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(list_tuples):\n if len(list_tuples) == 0:\n return None\n # Sort the list of tuples based on the second value of each tuple\n sorted_list = sorted(list_tuples, key=lambda x: x[1])\n # Return the first value of the tuple with the smallest second value\n return sorted_list[0][0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(tup_list):\n \"\"\"\n Function to get the first value of the tuple with the smallest second value.\n \"\"\"\n return min(tup_list, key=lambda x: x[1])[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(lst):\n \"\"\"\n Given a list of tuples, return the first value of the tuple with the smallest second value.\n \"\"\"\n return min(lst, key=lambda x: x[1])[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(lst):\n return min(lst, key=lambda x: x[1])[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(tuples_list):\n return min(tuples_list, key=lambda x: x[1])[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(lst):\n # Check if list is not empty\n if len(lst) == 0:\n return None\n\n # Initialize min_value to be the second element of the first tuple\n min_value = lst[0][1]\n\n # Initialize result to be the first element of the first tuple\n result = lst[0][0]\n\n # Iterate through all tuples in the list\n for i in lst:\n\n # If a tuple's second element is less than min_value, update min_value and result\n if i[1] < min_value:\n min_value = i[1]\n result = i[0]\n\n return result", "matching_cluster_idx": 4}, {"solution": "def index_minimum(lst):\n return min(lst, key=lambda x: x[1])[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(lst):\n \"\"\"\n Given a list of tuples, return the first value of the tuple with the smallest second value.\n \"\"\"\n return min(lst, key=lambda x: x[1])[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(tuple_list):\n # Start with the first tuple\n min_tuple = tuple_list[0]\n \n # Iterate through the rest of the list\n for tuple in tuple_list[1:]:\n # If the second value of this tuple is smaller than the current minimum,\n if tuple[1] < min_tuple[1]:\n # then replace the current minimum tuple with this one\n min_tuple = tuple\n \n # Finally, return the first value of the minimum tuple\n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(lst):\n return min(lst, key=lambda x: x[1])[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(tuples):\n # If there are no tuples, return None\n if not tuples:\n return None\n\n # Initialize minimum value and index\n min_val = tuples[0][1]\n min_index = tuples[0][0]\n\n # Iterate through the tuples\n for i in range(1, len(tuples)):\n # If current tuple's second element is less than minimum, update minimum and index\n if tuples[i][1] < min_val:\n min_val = tuples[i][1]\n min_index = tuples[i][0]\n\n # Return the first value of the tuple with the smallest second value\n return min_index", "matching_cluster_idx": 2}, {"solution": "def index_minimum(list_of_tuples):\n if not list_of_tuples: # edge case: if the list is empty\n return None\n # find the tuple with the smallest second value\n min_tuple = min(list_of_tuples, key=lambda x: x[1])\n return min_tuple[0] # return the first value of the tuple", "matching_cluster_idx": 2}, {"solution": "def index_minimum(lst):\n if len(lst) > 0:\n return min(lst, key=lambda x: x[1])[0]\n else:\n return None", "matching_cluster_idx": 2}, {"solution": "def index_minimum(list_of_tuples):\n # Assuming all tuples have a second value (i.e., that there are at least two elements in each tuple)\n min_val = list_of_tuples[0][1]\n min_index = list_of_tuples[0][0]\n for tuple in list_of_tuples:\n if tuple[1] < min_val:\n min_val = tuple[1]\n min_index = tuple[0]\n return min_index", "matching_cluster_idx": 4}, {"solution": "def index_minimum(lst):\n \"\"\"\n Given a list of tuples, return the first value of the tuple with the smallest second value.\n\n :param lst: a list of tuples where each tuple contains a string and a number\n :type lst: list of tuples\n :return: the first value in the tuple with the smallest second value\n :rtype: str\n\n \"\"\"\n # Initialize minimum value as the first tuple in the list\n min_value = lst[0][1]\n min_tuple = lst[0]\n\n # Iterate over each tuple in the list\n for t in lst:\n # If the current tuple's second element is smaller than the current minimum\n if t[1] < min_value:\n # Update minimum value and minimum tuple\n min_value = t[1]\n min_tuple = t\n\n # Return the first element of the minimum tuple\n return min_tuple[0]", "matching_cluster_idx": 4}, {"solution": "def index_minimum(lst):\n if len(lst) == 0:\n return None\n min_val = lst[0][1]\n min_index = lst[0][0]\n for tup in lst:\n if tup[1] < min_val:\n min_val = tup[1]\n min_index = tup[0]\n return min_index", "matching_cluster_idx": 4}, {"solution": "def index_minimum(lst):\n if not lst:\n return None\n min_val = lst[0]\n for item in lst:\n if item[1] < min_val[1]:\n min_val = item\n return min_val[0]", "matching_cluster_idx": 3}]}, "Mbpp/96": {"dps": 68.125, "dps_norm": 42.857142857142854, "pass@1": 61.0, "profiled": [{"solution": "def divisor(n):\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n count = 0\n i = 1\n while i <= n:\n if n % i == 0:\n count += 1\n i += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def divisor(n):\n divisors = 0\n for i in range(1, n + 1):\n if n % i == 0:\n divisors += 1\n return divisors", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n # Initialize count to 0\n count = 0\n for i in range(1, n+1):\n # Check if current number is a divisor\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n count = 0\n for i in range(1, n+1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n # Initialize count to 0\n count = 0\n # Go from 1 to n+1 (we do +1 to include n itself)\n for i in range(1, n+1):\n # Check if remainder is 0 which means i is a divisor\n if n % i == 0:\n # Increment the count\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n count = 0\n for i in range(1, n+1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n divisors = 0\n for i in range(1, n + 1):\n if n % i == 0:\n divisors += 1\n return divisors", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n count = 0\n i = 1\n\n while i <= n:\n if n % i == 0:\n count += 1\n i += 1\n return count", "matching_cluster_idx": 0}, {"solution": "def divisor(n):\n if n < 1:\n return 0\n cnt = 0\n for i in range(1, int(n ** 0.5) + 1):\n if n % i == 0:\n if n // i == i:\n cnt += 1\n else:\n cnt += 2\n return cnt", "matching_cluster_idx": 6}, {"solution": "def divisor(n):\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n count = 0\n for i in range(1, n+1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n divisors = 0\n for i in range(1, n + 1):\n if n % i == 0:\n divisors += 1\n return divisors", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n \"\"\"\n Function to find the number of divisors of a given integer.\n \"\"\"\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n count = 0\n i = 1\n while i <= n:\n if n % i == 0:\n count += 1\n i += 1\n return count", "matching_cluster_idx": 1}]}, "Mbpp/97": {"dps": 81.38461538461539, "dps_norm": 77.5, "pass@1": 98.0, "profiled": [{"solution": "from typing import List, Dict\ndef frequency_lists(lists: List[List[int]]) -> Dict[int, int]:\n # Flatten the list of lists\n flat_list = [item for sublist in lists for item in sublist]\n \n # Use dictionary to count the frequency\n frequency_dict = {i: flat_list.count(i) for i in flat_list}\n \n return frequency_dict", "matching_cluster_idx": 1}, {"solution": "def flatten(lists):\n return [item for sublist in lists for item in sublist]\ndef frequency_lists(list_of_lists):\n flattened = flatten(list_of_lists)\n frequency = {}\n for item in flattened:\n if item not in frequency:\n frequency[item] = 1\n else:\n frequency[item] += 1\n return frequency", "matching_cluster_idx": 6}, {"solution": "def flatten(lst):\n \"\"\"\n Function to flatten the list of lists\n \"\"\"\n flattened = []\n for sublist in lst:\n for item in sublist:\n flattened.append(item)\n return flattened\ndef frequency_lists(lst):\n \"\"\"\n Function to find frequency of each element in a flattened list\n \"\"\"\n flat = flatten(lst)\n frequency = {}\n for item in flat:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n return frequency", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lst):\n flatten_list = [item for sublist in lst for item in sublist]\n return {i: flatten_list.count(i) for i in flatten_list}", "matching_cluster_idx": 1}, {"solution": "from collections import Counter\ndef flatten(lst):\n return [item for sublist in lst for item in sublist]\ndef frequency_lists(lst):\n flattened_list = flatten(lst)\n return dict(Counter(flattened_list))", "matching_cluster_idx": 6}, {"solution": "def flatten(l):\n \"\"\"Flatten a list of lists\"\"\"\n return [item for sublist in l for item in sublist]\ndef frequency_lists(lst):\n \"\"\"Find frequency of each element in a flattened list of lists\"\"\"\n flattened_list = flatten(lst)\n return {i: flattened_list.count(i) for i in flattened_list}", "matching_cluster_idx": 1}, {"solution": "def frequency_lists(input_list):\n # Flatten the list of lists\n flat_list = [item for sublist in input_list for item in sublist]\n\n # Create an empty dictionary to store the frequency of each element\n freq_dict = {}\n\n # Count the frequency of each element\n for item in flat_list:\n if item in freq_dict:\n freq_dict[item] += 1\n else:\n freq_dict[item] = 1\n\n return freq_dict", "matching_cluster_idx": 6}, {"solution": "def flatten_list(lst):\n return [item for sublist in lst for item in sublist]\ndef frequency_lists(lst):\n flat_lst = flatten_list(lst)\n freq = {}\n for num in flat_lst:\n if num in freq:\n freq[num] += 1\n else:\n freq[num] = 1\n return freq", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(list_of_lists):\n flat_list = [item for sublist in list_of_lists for item in sublist]\n frequency_dict = {}\n for item in flat_list:\n if item in frequency_dict:\n frequency_dict[item] += 1\n else:\n frequency_dict[item] = 1\n return frequency_dict", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(list_of_lists):\n flattened = [item for sublist in list_of_lists for item in sublist]\n frequency = {}\n for num in flattened:\n if num not in frequency:\n frequency[num] = 1\n else:\n frequency[num] += 1\n return frequency", "matching_cluster_idx": 6}, {"solution": "from collections import Counter\ndef flatten(lst):\n return [item for sublist in lst for item in sublist]\ndef frequency_lists(lst):\n flattened_list = flatten(lst)\n return dict(Counter(flattened_list))", "matching_cluster_idx": 6}, {"solution": "def flatten(lst):\n \"\"\"Flatten a nested list\"\"\"\n result = []\n for sublist in lst:\n if isinstance(sublist, list):\n result.extend(flatten(sublist))\n else:\n result.append(sublist)\n return result\ndef frequency_lists(lst):\n \"\"\"Find frequency of each element in a flattened list of lists\"\"\"\n flattened = flatten(lst)\n frequency = {}\n for element in flattened:\n if element in frequency:\n frequency[element] += 1\n else:\n frequency[element] = 1\n return frequency", "matching_cluster_idx": 5}, {"solution": "def flatten_lists(list_of_lists):\n return [item for sublist in list_of_lists for item in sublist]\ndef frequency_lists(list_of_lists):\n flattened_list = flatten_lists(list_of_lists)\n freq_dict = {}\n for item in flattened_list:\n if item in freq_dict:\n freq_dict[item] += 1\n else:\n freq_dict[item] = 1\n return freq_dict", "matching_cluster_idx": 6}, {"solution": "def flatten(lst):\n flattened = [item for sublist in lst for item in sublist]\n return flattened\ndef frequency_lists(lst):\n flattened = flatten(lst)\n frequency_dict = {}\n for item in flattened:\n if item in frequency_dict:\n frequency_dict[item] += 1\n else:\n frequency_dict[item] = 1\n return frequency_dict", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(nested_list):\n \"\"\"Find frequency of each element in a flattened list of lists.\"\"\"\n frequency_dict = {}\n for sublist in nested_list:\n for item in sublist:\n if item in frequency_dict:\n frequency_dict[item] += 1\n else:\n frequency_dict[item] = 1\n return frequency_dict", "matching_cluster_idx": 6}, {"solution": "def flatten_list(lst):\n flat_list = []\n for sublist in lst:\n for item in sublist:\n flat_list.append(item)\n return flat_list\ndef frequency_lists(lst):\n flat_list = flatten_list(lst)\n frequency_dict = {}\n for item in flat_list:\n if item in frequency_dict:\n frequency_dict[item] += 1\n else:\n frequency_dict[item] = 1\n return frequency_dict", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lists):\n flat_list = [item for sublist in lists for item in sublist]\n frequency_dict = {}\n \n for i in flat_list:\n if i in frequency_dict:\n frequency_dict[i] += 1\n else:\n frequency_dict[i] = 1\n \n return frequency_dict", "matching_cluster_idx": 6}, {"solution": "def flatten(lst):\n \"\"\"Function to flatten a list of lists\"\"\"\n return [item for sublist in lst for item in sublist]\ndef frequency_lists(lst):\n \"\"\"Function to calculate frequency of each element in a flattened list\"\"\"\n flat_list = flatten(lst)\n frequency = {}\n for item in flat_list:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n return frequency", "matching_cluster_idx": 6}, {"solution": "def flatten_list(lst):\n \"\"\"\n Function that flattens a list of lists.\n \"\"\"\n return [item for sublist in lst for item in sublist]\ndef frequency_lists(lst):\n \"\"\"\n Function that finds frequency of each element in a list.\n \"\"\"\n flattened_list = flatten_list(lst)\n frequency_dict = {}\n for i in flattened_list:\n if i not in frequency_dict:\n frequency_dict[i] = 1\n else:\n frequency_dict[i] += 1\n return frequency_dict", "matching_cluster_idx": 6}, {"solution": "def flatten_lists(nested_list):\n \"\"\"\n Helper function to flatten a list of lists.\n \"\"\"\n return [item for sublist in nested_list for item in sublist]\ndef frequency_lists(nested_list):\n \"\"\"\n Function to find the frequency of each element in a flattened list of lists, returned in a dictionary.\n \"\"\"\n flat_list = flatten_lists(nested_list)\n frequency_dict = {}\n for item in flat_list:\n if item in frequency_dict:\n frequency_dict[item] += 1\n else:\n frequency_dict[item] = 1\n return frequency_dict", "matching_cluster_idx": 6}]}, "Mbpp/106": {"dps": 52.72727272727273, "dps_norm": 84.16666666666666, "pass@1": 98.0, "profiled": [{"solution": "def add_lists(lst, tpl):\n \"\"\"\n Append a list to a tuple\n\n Parameters:\n lst (list): The list to be appended\n tpl (tuple): The tuple where list is to be appended\n\n Returns:\n tuple: A new tuple with the list appended\n \"\"\"\n return tpl + tuple(lst)", "matching_cluster_idx": 4}, {"solution": "def add_lists(lst, tup):\n return tup + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tpl):\n # This function takes in a list and a tuple as arguments\n # It returns a new tuple that is the result of appending the list to the tuple\n return tpl + tuple(lst)", "matching_cluster_idx": 4}, {"solution": "def add_lists(lst, tpl):\n return tpl + tuple(lst)", "matching_cluster_idx": 4}, {"solution": "def add_lists(input_list, input_tuple):\n return input_tuple + tuple(input_list)", "matching_cluster_idx": 4}, {"solution": "def add_lists(lst, tup):\n # Use the + operator to concatenate the tuple and list\n return tup + tuple(lst)", "matching_cluster_idx": 4}, {"solution": "def add_lists(lst, tup):\n # Concatenate the list and tuple, then convert back to a tuple\n return tuple(list(tup) + lst)", "matching_cluster_idx": 3}, {"solution": "def add_lists(lst, tpl):\n \"\"\"\n Append the given list to the given tuples.\n \"\"\"\n # Append the list to the tuple using the tuple concatenation.\n return tpl + tuple(lst)", "matching_cluster_idx": 4}, {"solution": "def add_lists(lst, tpl):\n return tpl + tuple(lst)", "matching_cluster_idx": 4}, {"solution": "def add_lists(lst, tpl):\n # Convert tuple to list, append list to tuple, and convert back to tuple\n result = list(tpl) + lst\n return tuple(result)", "matching_cluster_idx": 2}, {"solution": "def add_lists(input_list, input_tuple):\n \"\"\"\n This function appends the given list to the given tuple.\n \n Parameters:\n input_list (list): The list to be added to the tuple.\n input_tuple (tuple): The tuple to which the list is to be appended.\n \n Returns:\n tuple: A tuple which includes the elements of the input_tuple and input_list.\n \"\"\"\n return input_tuple + tuple(input_list)", "matching_cluster_idx": 4}, {"solution": "def add_lists(lst, tup):\n return tup + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(list_value, tuple_value):\n return tuple_value + tuple(list_value)", "matching_cluster_idx": 4}, {"solution": "def add_lists(lst, tpl):\n return tpl + tuple(lst)", "matching_cluster_idx": 4}, {"solution": "def add_lists(list_, tuples):\n return tuples + tuple(list_)", "matching_cluster_idx": 5}, {"solution": "def add_lists(my_list, my_tuple):\n # Convert the tuple to a list, append the provided list, and convert the result back to a tuple\n return tuple(list(my_tuple) + my_list)", "matching_cluster_idx": 2}, {"solution": "def add_lists(lst, tup):\n return tup + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(list_to_append, tuples_to_append):\n if not isinstance(list_to_append, list):\n raise ValueError(\"First argument should be a list\")\n if not isinstance(tuples_to_append, tuple):\n raise ValueError(\"Second argument should be a tuple\")\n tuples_to_append += tuple(list_to_append)\n return tuples_to_append", "matching_cluster_idx": 4}, {"solution": "def add_lists(lst, tup):\n return tup + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tup):\n return tup + tuple(lst)", "matching_cluster_idx": 5}]}, "Mbpp/108": {"dps": 96.02409638554217, "dps_norm": 99.54545454545455, "pass@1": 100.0, "profiled": [{"solution": "def merge_sorted_list(lst1, lst2, lst3):\n merged_list = lst1 + lst2 + lst3\n merged_list.sort()\n return merged_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n merged_list = list1 + list2 + list3\n merged_list.sort()\n return merged_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(*args):\n result = []\n for lst in args:\n result += lst\n return sorted(result)", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n combined_list = list1 + list2 + list3\n combined_list.sort()\n return combined_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(*args):\n result = []\n for l in args:\n result.extend(l)\n result.sort()\n return result", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(*args):\n # Flatten lists into a single list\n flattened_list = [item for sublist in args for item in sublist]\n # Use Python's built-in sorting function to sort the list\n flattened_list.sort()\n return flattened_list", "matching_cluster_idx": 9}, {"solution": "def merge_sorted_list(list1, list2, list3):\n return sorted(list1 + list2 + list3)", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(*args):\n merged_list = []\n for l in args:\n merged_list.extend(l)\n return sorted(merged_list)", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(*args):\n merged_list = []\n\n for list in args:\n merged_list.extend(list)\n\n return sorted(merged_list)", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n return sorted(list1 + list2 + list3)", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Merging all three lists into one\n merged_list = list1 + list2 + list3\n \n # Sorting the merged list\n merged_list.sort()\n \n return merged_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # concatenate the 3 lists\n merged_list = list1 + list2 + list3\n # sort the merged list\n merged_list.sort()\n return merged_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # concatenate all lists\n merged_list = list1 + list2 + list3\n # sort and return the merged list\n return sorted(merged_list)", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n return sorted(list1 + list2 + list3)", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(*args):\n merged_list = []\n for lst in args:\n merged_list.extend(lst)\n return sorted(merged_list)", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Merge lists\n merged_list = list1 + list2 + list3\n \n # Sort the list\n merged_list.sort()\n \n return merged_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n merged_list = list1 + list2 + list3\n return sorted(merged_list)", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n merged_list = list1 + list2 + list3\n merged_list.sort()\n return merged_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n merged_list = list1 + list2 + list3\n merged_list.sort()\n return merged_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(lst1, lst2, lst3):\n \"\"\"Merge three sorted lists into a single sorted list.\"\"\"\n merged_list = lst1 + lst2 + lst3\n merged_list.sort()\n return merged_list", "matching_cluster_idx": 10}]}, "Mbpp/111": {"dps": 83.6923076923077, "dps_norm": 85.0, "pass@1": 95.0, "profiled": [{"solution": "def common_in_nested_lists(lst):\n return list(set(lst[0]).intersection(*lst))", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n \"\"\"\n Find the common elements in given nested lists.\n :param nested_lists: A list of lists.\n :return: A list of common elements.\n \"\"\"\n return set(set(nested_lists[0]).intersection(*nested_lists[1:]))", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(lists):\n \"\"\"\n Function to find the common elements in given nested lists\n :param lists: List of lists\n :return: List of common elements\n \"\"\"\n return list(set(lists[0]).intersection(*lists[1:]))", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(lists):\n common_elements = set(lists[0])\n for i in range(1, len(lists)):\n common_elements = common_elements.intersection(lists[i])\n return list(common_elements)", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(lists):\n \"\"\"\n This function takes a list of lists and returns a list of common elements across all the lists\n \"\"\"\n return list(set(lists[0]).intersection(*lists[1:]))", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_list):\n \"\"\"\n Function to find the common elements in a nested list\n \"\"\"\n if not nested_list: # in case an empty list is passed\n return []\n if len(nested_list) == 1: # in case only 1 list is passed\n return set(nested_list[0])\n\n # convert lists to sets to remove duplicates and perform intersection\n # convert back to list for consistent type\n common_elements = list(set(nested_list[0]).intersection(*map(set, nested_list[1:])))\n return common_elements", "matching_cluster_idx": 5}, {"solution": "def common_in_nested_lists(nested_lists):\n # initialize the common elements to the first list\n common = set(nested_lists[0])\n \n # find the intersection of the common elements and the current list\n for lst in nested_lists[1:]:\n common = common.intersection(lst)\n \n return list(common)", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(lists):\n common_elements = set(lists[0])\n for i in lists[1:]:\n common_elements = common_elements.intersection(set(i))\n return list(common_elements)", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_list):\n \"\"\"\n Given a list of lists, the function will find common elements among all sublists.\n \"\"\"\n return list(set.intersection(*map(set, nested_list)))", "matching_cluster_idx": 5}, {"solution": "def common_in_nested_lists(nested_lists):\n common_elements = set(nested_lists[0])\n for i in range(1, len(nested_lists)):\n common_elements = common_elements.intersection(nested_lists[i])\n return list(common_elements)", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n if len(nested_lists) == 0:\n return []\n else:\n common_elements = set(nested_lists[0])\n for each_list in nested_lists[1:]:\n common_elements.intersection_update(each_list)\n return list(common_elements)", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_list):\n return set(nested_list[0]).intersection(*nested_list[1:])", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(lists):\n # convert all lists to sets, then take intersection of set with every other list\n common = set(lists[0])\n for lst in lists[1:]:\n common &= set(lst)\n return list(common)", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_list):\n if not nested_list:\n return []\n common = set(nested_list[0])\n for sublist in nested_list[1:]:\n common.intersection_update(sublist)\n return list(common)", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(lists):\n if not all(isinstance(sublist, list) for sublist in lists):\n raise ValueError(\"All inputs must be lists\")\n \n if len(lists) == 0:\n return []\n \n first_set = set(lists[0])\n \n for sublist in lists[1:]:\n first_set.intersection_update(sublist)\n \n return list(first_set)", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_list):\n return list(set.intersection(*map(set, nested_list)))", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef common_in_nested_lists(nested_lists: List[List[int]]) -> List[int]:\n if len(nested_lists) == 0:\n return []\n common = set(nested_lists[0])\n for lst in nested_lists[1:]:\n common = common & set(lst) # \"&\" operator performs intersection operation\n return list(common)", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(lists):\n return set(lists[0]).intersection(*lists[1:])", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n return set(nested_lists[0]).intersection(*nested_lists[1:])", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(lists):\n # The function uses built-in set and intersection functions.\n # It gets the intersection of all sets created from nested lists.\n # At the end, it converts the result back to a list and returns it.\n return list(set.intersection(*map(set, lists)))", "matching_cluster_idx": 5}]}, "Mbpp/123": {"dps": 99.62686567164178, "dps_norm": 85.71428571428571, "pass@1": 39.0, "profiled": [{"solution": "def divisor_sum(n):\n result = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n result += i\n if i != n // i:\n result += n // i\n result -= n\n return result\ndef amicable_numbers_sum(n):\n total_sum = 0\n for i in range(1, n + 1):\n d = divisor_sum(i)\n if i != d and d <= n and divisor_sum(d) == i:\n total_sum += i\n return total_sum", "matching_cluster_idx": 11}, {"solution": "def proper_divisor_sum(n):\n divisors_sum = 1\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n if n / i != i:\n divisors_sum += i\n divisors_sum += n / i\n else:\n divisors_sum += i\n return divisors_sum\ndef amicable_numbers_sum(n):\n amicable_sum = 0\n for i in range(2, n + 1):\n m = proper_divisor_sum(i)\n if i != m and proper_divisor_sum(m) == i:\n amicable_sum += i\n return amicable_sum", "matching_cluster_idx": 11}, {"solution": "def amicable_numbers_sum(n):\n def divisor_sum(n):\n i = 1\n sum = 0\n while i * i <= n:\n if n % i:\n i += 1\n else:\n if i * (n // i) == n:\n sum += i + n // i\n i += 1\n return sum - n\n\n sum = 0\n for i in range(2, n + 1):\n s = divisor_sum(i)\n if s != i and divisor_sum(s) == i:\n sum += i\n return sum", "matching_cluster_idx": 11}, {"solution": "def amicable_numbers_sum(n):\n def proper_divisors(num):\n div_sum = 1\n for i in range(2, int(num**0.5)+1):\n if num % i == 0:\n div_sum += i + num//i\n return div_sum\n\n sum = 0\n for i in range(2, n+1):\n if proper_divisors(proper_divisors(i)) == i and proper_divisors(i) != i:\n sum += i\n return sum", "matching_cluster_idx": 11}, {"solution": "def d(n):\n \"\"\"\n Function to calculate sum of proper divisors\n \"\"\"\n sum = 1\n i = 2\n while i * i <= n:\n if n % i:\n i += 1\n else:\n if n // i == i:\n sum = sum + i\n else:\n sum = sum + i + n // i\n i += 1\n return sum\ndef amicable_numbers_sum(n):\n \"\"\"\n Function to get sum of amicable numbers from 1 to n\n \"\"\"\n total = 0\n for i in range(1, n+1):\n j = d(i)\n if (i != j) and (i == d(j)):\n total += i\n return total", "matching_cluster_idx": 11}, {"solution": "def d(n):\n \"\"\"\n Function to find proper divisors sum of a number n\n \"\"\"\n div_sum = 1\n for i in range(2, int(n**0.5)+1):\n if n % i == 0:\n if n//i != i:\n div_sum = div_sum + i + n//i\n else:\n div_sum = div_sum + i\n return div_sum\ndef amicable_numbers_sum(limit):\n \"\"\"\n Function to find sum of all amicable numbers up to limit\n \"\"\"\n amicable_sum = 0\n for a in range(1, limit):\n b = d(a)\n if a != b and d(b) == a:\n amicable_sum += a\n return amicable_sum", "matching_cluster_idx": 11}, {"solution": "def sum_divisors(n):\n sum_div = 1\n i = 2\n while i*i <= n:\n if n%i:\n i += 1\n else:\n if i*i == n:\n sum_div += i\n else:\n sum_div += i\n sum_div += n//i\n i += 1\n return sum_div\ndef amicable_numbers_sum(n):\n sum_amicables = 0\n for i in range(2, n+1):\n d_i = sum_divisors(i)\n d_di = sum_divisors(d_i)\n if i == d_di and i != d_i:\n sum_amicables += i\n return sum_amicables", "matching_cluster_idx": 11}, {"solution": "def amicable_numbers_sum(limit):\n def sum_divisors(n):\n sum = 1\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n sum += i\n if n // i != i:\n sum += n // i\n return sum\n\n amicable_sum = 0\n for i in range(2, limit + 1):\n sum_i = sum_divisors(i)\n sum_j = sum_divisors(sum_i)\n if sum_j == i and sum_i != sum_j:\n amicable_sum += i\n return amicable_sum", "matching_cluster_idx": 11}, {"solution": "def d(n):\n sum = 1\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n sum += i\n if i*i != n: # Add complement of i if i^2 != n\n sum += n // i\n return sum\ndef amicable_numbers_sum(n):\n sum_amicable = 0\n for i in range(1, n):\n j = d(i)\n if i != j and i == d(j):\n sum_amicable += i\n return sum_amicable", "matching_cluster_idx": 11}, {"solution": "def sum_of_divisors(n):\n # function to calculate the sum of proper divisors\n s = 1\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n s += i\n if n // i != i:\n s += n // i\n return s\ndef amicable_numbers_sum(n):\n # function to calculate sum of amicable numbers up to n\n amicable_numbers = set()\n for i in range(2, n+1):\n # ignore non-amicable numbers\n if i not in amicable_numbers:\n s = sum_of_divisors(i)\n if s != i and s <= n and sum_of_divisors(s) == i:\n amicable_numbers.add(i)\n amicable_numbers.add(s)\n return sum(amicable_numbers)", "matching_cluster_idx": 11}, {"solution": "def sum_of_divisors(n):\n result = 1\n i = 2\n while i * i <= n:\n if n % i:\n i += 1\n else:\n if n == i * i:\n result += i\n else:\n result += i\n result += n//i\n i += 1\n return result\ndef amicable_numbers_sum(n):\n if n < 2:\n return 0\n divisors_sum = [0]*(n+1)\n for i in range(1, n+1):\n divisors_sum[i] = sum_of_divisors(i)\n result = 0\n for i in range(2, n+1):\n if i == divisors_sum[i] or divisors_sum[i] > n or divisors_sum[i]==1 or divisors_sum[divisors_sum[i]] != i:\n continue\n else:\n result += i\n return result", "matching_cluster_idx": 11}, {"solution": "def d(n):\n s = 1\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n if n // i == i:\n s += i\n else:\n s += i\n s += n // i\n return s\ndef amicable_numbers_sum(limit):\n num_list = [0] * (limit + 1)\n for i in range(1, limit + 1):\n num_list[i] = d(i)\n s = 0\n for i in range(1, limit + 1):\n if num_list[i] <= limit and num_list[i] != i:\n if num_list[num_list[i]] == i:\n s += i\n return s", "matching_cluster_idx": 11}, {"solution": "def d(n):\n sum = 1\n i = 2\n while i * i <= n:\n if n % i:\n i += 1\n else:\n if i * i != n:\n sum = sum + i + n//i\n else:\n sum = sum + i\n i += 1\n return sum\ndef amicable_numbers_sum(n):\n sum = 0\n for i in range(1,n+1):\n j = d(i)\n if j != i and d(j)==i:\n sum += i\n return sum", "matching_cluster_idx": 11}, {"solution": "def divisors(n):\n sum = 1\n i = 2\n while i * i <= n:\n if n % i:\n i += 1\n else:\n if n // i == i:\n sum += i\n else:\n sum = sum + i + n//i\n i += 1\n return sum\ndef amicable_numbers_sum(limit):\n s = 0\n for i in range(2, limit+1):\n if i == divisors(divisors(i)) and i != divisors(i):\n s += i\n return s", "matching_cluster_idx": 11}, {"solution": "def amicable_numbers_sum(n):\n def d(num):\n divisors_sum = 1\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n divisors_sum += i\n if num / i != i:\n divisors_sum += num // i\n return divisors_sum\n amicable_sum = 0\n for i in range(2, n+1):\n b = d(i)\n if i != b and d(b) == i:\n amicable_sum += i\n return amicable_sum", "matching_cluster_idx": 11}, {"solution": "def sum_of_divisors(n):\n sum = 1\n i = 2\n while i * i <= n:\n if n % i:\n i += 1\n else:\n if i * i != n:\n sum = sum + i + n // i\n else:\n sum = sum + i\n i += 1\n return sum\ndef amicable_numbers_sum(upper_limit):\n sum = 0\n for i in range(2, upper_limit+1):\n j = sum_of_divisors(i)\n if (sum_of_divisors(j) == i) and i != j:\n sum += i\n return sum", "matching_cluster_idx": 11}, {"solution": "def divisor_sum(n):\n sum = 1\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n sum += i\n if n // i != i:\n sum += n // i\n return sum\ndef amicable_numbers_sum(limit):\n total_sum = 0\n for i in range(2, limit+1):\n a = divisor_sum(i)\n b = divisor_sum(a)\n if b == i and a != b:\n total_sum += i\n return total_sum", "matching_cluster_idx": 11}, {"solution": "def sum_of_divisors(n):\n sum = 1\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n if i == n/i:\n sum += i\n else:\n sum += i\n sum += n/i\n return sum\ndef amicable_numbers_sum(n):\n amicable_numbers_sum = 0\n for i in range(1, n+1):\n j = sum_of_divisors(i)\n if i != j and j <= n and sum_of_divisors(j) == i:\n amicable_numbers_sum += i\n return amicable_numbers_sum", "matching_cluster_idx": 11}, {"solution": "def d(n):\n sum = 1\n i = 2\n while i * i <= n:\n if n % i:\n i += 1\n else:\n if i * i != n:\n sum = sum + i + n // i\n else:\n sum = sum + i\n i += 1\n return sum\ndef amicable_numbers_sum(limit):\n sum = 0\n for i in range(1, limit + 1):\n j = d(i)\n if (j > i) and (d(j) == i):\n sum += i + j\n return sum", "matching_cluster_idx": 11}, {"solution": "def d(n): # Function to calculate the sum of the divisors\n sum_div = 1\n for x in range(2, int(n**0.5) + 1):\n if n % x == 0:\n sum_div += x\n if x != n // x: # Check to avoid duplicate of the square root\n sum_div += n // x\n return sum_div\ndef amicable_numbers_sum(n): # Function to calculate the sum of all amicable numbers\n sum_amicable = 0\n for x in range(2, n+1):\n y = d(x)\n if x != y and d(y) == x:\n sum_amicable += x\n return sum_amicable", "matching_cluster_idx": 11}]}, "Mbpp/128": {"dps": 99.5475113122172, "dps_norm": 80.0, "pass@1": 100.0, "profiled": [{"solution": "def long_words(n, sentence):\n words = sentence.split() # split the sentence into words\n return [word for word in words if len(word) > n] # return words with length > n", "matching_cluster_idx": 3}, {"solution": "def long_words(n, text):\n words = text.split()\n long_words = [word for word in words if len(word) > n]\n return long_words", "matching_cluster_idx": 3}, {"solution": "def long_words(n, text):\n return [word for word in text.split() if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n word_list = sentence.split()\n long_words_list = [word for word in word_list if len(word) > n]\n return long_words_list", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n \"\"\"\n This function finds the words in a sentence that are longer than 'n' characters.\n \"\"\"\n words = sentence.split()\n long_words = [word for word in words if len(word) > n]\n return long_words", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n word_list = sentence.split(' ')\n long_words = [word for word in word_list if len(word) > n]\n return long_words", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n # split sentence into words\n words = sentence.split(' ')\n \n # filter out words that are longer than n characters\n long_words = [word for word in words if len(word) > n]\n \n return long_words", "matching_cluster_idx": 3}, {"solution": "def long_words(n, words):\n word_list = words.split()\n result = [word for word in word_list if len(word) > n]\n return result", "matching_cluster_idx": 3}, {"solution": "def long_words(n, string):\n words = string.split(' ')\n long_words_list = [word for word in words if len(word) > n]\n return long_words_list", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n words = sentence.split()\n long_words = [word for word in words if len(word) > n]\n return long_words", "matching_cluster_idx": 3}, {"solution": "def long_words(n, phrase):\n words = phrase.split(' ')\n result = [word for word in words if len(word) > n]\n return result", "matching_cluster_idx": 3}, {"solution": "def long_words(n, text):\n words = text.split()\n return [word for word in words if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, string):\n words = string.split()\n return [word for word in words if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n words = sentence.split()\n return [word for word in words if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n return [word for word in sentence.split() if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n # split the sentence into words\n words = sentence.split()\n\n # filter out the words that are longer than n characters\n long_words_list = [word for word in words if len(word) > n]\n\n return long_words_list", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n \"\"\"\n Returns a list of words from a sentence that are longer than n characters.\n \n Args:\n n: The minimum length of words in the returned list.\n sentence: The sentence to parse for words.\n \n Returns:\n A list of words from the sentence that are longer than n characters.\n \"\"\"\n words = sentence.split()\n long_words = [word for word in words if len(word) > n]\n return long_words", "matching_cluster_idx": 3}, {"solution": "def long_words(n, phrase):\n word_list = phrase.split()\n result = [word for word in word_list if len(word) > n]\n return result", "matching_cluster_idx": 3}, {"solution": "def long_words(n, text):\n # split the text into words\n words = text.split()\n # filter the words longer than n characters\n result = [word for word in words if len(word) > n]\n return result", "matching_cluster_idx": 3}, {"solution": "def long_words(n, text):\n words = text.split()\n return [word for word in words if len(word) > n]", "matching_cluster_idx": 3}]}, "Mbpp/129": {"dps": 63.63520408163266, "dps_norm": 92.33333333333333, "pass@1": 37.0, "profiled": [{"solution": "def magic_square_test(matrix):\n # Check if the matrix is square\n if len(matrix) != len(matrix[0]):\n return False\n \n # Check sum of row elements\n for row in matrix:\n if sum(row) != sum(matrix[0]):\n return False\n\n # Check sum of column elements\n for col_index in range(len(matrix)):\n if sum([row[col_index] for row in matrix]) != sum(matrix[0]):\n return False\n\n # Check sum of diagonals\n main_diagonal_sum = sum([matrix[i][i] for i in range(len(matrix))])\n if main_diagonal_sum != sum(matrix[0]):\n return False\n\n secondary_diagonal_sum = sum([matrix[i][len(matrix)-1-i] for i in range(len(matrix))])\n if secondary_diagonal_sum != sum(matrix[0]):\n return False\n\n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n # check for square matrix\n if not all(len(row) == len(matrix) for row in matrix):\n return False\n \n # calculate the sum of a row\n row_sum = sum(matrix[0])\n \n # check for magic square\n for row in matrix:\n if sum(row) != row_sum:\n return False\n \n # calculate the sum of a column\n for col in range(len(matrix[0])):\n col_sum = sum(matrix[i][col] for i in range(len(matrix)))\n if col_sum != row_sum:\n return False\n \n # check diagonals\n diag1 = sum(matrix[i][i] for i in range(len(matrix)))\n diag2 = sum(matrix[i][len(matrix)-i-1] for i in range(len(matrix)))\n return diag1 == diag2 == row_sum", "matching_cluster_idx": 13}, {"solution": "def magic_square_test(matrix):\n # calculate sum of elements in first row as a reference\n sum_of_first_row = sum(matrix[0])\n \n # check the rows sum\n for row in matrix:\n if sum(row) != sum_of_first_row:\n return False\n \n # check the columns sum\n for i in range(len(matrix)):\n column_sum = sum([row[i] for row in matrix])\n if column_sum != sum_of_first_row:\n return False\n \n # check the diagonal sum\n diagonal_sum1 = sum([matrix[i][i] for i in range(len(matrix))])\n if diagonal_sum1 != sum_of_first_row:\n return False\n \n # check other diagonal sum\n diagonal_sum2 = sum([matrix[i][len(matrix)-i-1] for i in range(len(matrix))])\n if diagonal_sum2 != sum_of_first_row:\n return False\n \n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n # first, check if the matrix is square (has the same number of rows and columns)\n n = len(matrix)\n if n != len(matrix[0]):\n return False\n # next, check if the sums of the rows, columns and diagonals are equal\n row_sums = [sum(row) for row in matrix]\n if len(set(row_sums)) > 1:\n return False\n col_sums = [sum([matrix[j][i] for j in range(n)]) for i in range(n)]\n if len(set(col_sums)) > 1:\n return False\n diag_sum = sum([matrix[i][i] for i in range(n)])\n if diag_sum != row_sums[0]:\n return False\n if n % 2 == 0: # check if the matrix is odd-sized\n diag_sum = sum([matrix[i][n-i-1] for i in range(n)])\n if diag_sum != row_sums[0]:\n return False\n return True", "matching_cluster_idx": 10}, {"solution": "def magic_square_test(matrix):\n n = len(matrix)\n # Calculate the sum of the first row.\n target_sum = sum(matrix[0])\n # Check the rows and columns.\n for i in range(n):\n if sum(matrix[i]) != target_sum:\n return False\n if sum(matrix[j][i] for j in range(n)) != target_sum:\n return False\n # Check the diagonal sums.\n if sum(matrix[i][i] for i in range(n)) != target_sum:\n return False\n if sum(matrix[i][n-i-1] for i in range(n)) != target_sum:\n return False\n # If none of the checks failed, the matrix is a magic square.\n return True", "matching_cluster_idx": 13}, {"solution": "def magic_square_test(matrix):\n n = len(matrix)\n \n #calculating the sum of any row or column\n target = sum(matrix[0])\n \n #testing the rows\n for row in matrix:\n if sum(row) != target:\n return False\n \n #testing the columns\n for i in range(n):\n if sum(matrix[j][i] for j in range(n)) != target:\n return False\n \n #testing the diagonals\n if sum(matrix[i][i] for i in range(n)) != target:\n return False\n if sum(matrix[i][n-i-1] for i in range(n)) != target:\n return False\n\n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n # Calculate the sum of the first row\n magic_sum = sum(matrix[0])\n \n # Check rows and columns\n for i in range(len(matrix)):\n if sum(matrix[i]) != magic_sum or sum(matrix[j][i] for j in range(len(matrix))) != magic_sum:\n return False\n\n # Check diagonals\n if sum(matrix[i][i] for i in range(len(matrix))) != magic_sum or sum(matrix[i][len(matrix)-i-1] for i in range(len(matrix))) != magic_sum:\n return False\n\n return True", "matching_cluster_idx": 13}, {"solution": "def magic_square_test(matrix):\n # get the sum of any row, col or diag\n target = sum(matrix[0])\n\n # test rows and cols\n for row in matrix:\n if sum(row) != target:\n return False\n for col in zip(*matrix):\n if sum(col) != target:\n return False\n\n # test diags\n diag1 = [matrix[i][i] for i in range(len(matrix))]\n diag2 = [matrix[i][-i-1] for i in range(len(matrix))]\n if sum(diag1) != target or sum(diag2) != target:\n return False\n\n # if no discrepancies found\n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n # Check if it's a square matrix\n if not all(len(row) == len(matrix) for row in matrix):\n return False\n\n # Check if the sum of each row, each column, and the main diagonals are equal\n n = len(matrix)\n target = sum(matrix[0])\n\n for i in range(n):\n if sum(matrix[i]) != target or sum(matrix[j][i] for j in range(n)) != target:\n return False\n\n if sum(matrix[i][i] for i in range(n)) != target or sum(matrix[i][n-i-1] for i in range(n)) != target:\n return False\n\n return True", "matching_cluster_idx": 13}, {"solution": "def magic_square_test(matrix):\n # Check if the input is a square matrix\n if not all(len(row) == len(matrix) for row in matrix):\n return False\n \n # calculate the sum of elements in first row as sum_reference\n sum_reference = sum(matrix[0])\n \n # Checking rows and columns\n for row in matrix:\n if sum(row) != sum_reference:\n return False\n for i in range(len(matrix)):\n if sum(row[i] for row in matrix) != sum_reference:\n return False\n\n # Checking diagonals\n if sum(matrix[i][i] for i in range(len(matrix))) != sum_reference:\n return False\n if sum(matrix[i][len(matrix)-i-1] for i in range(len(matrix))) != sum_reference:\n return False\n\n # If none of the checks failed, return True\n return True", "matching_cluster_idx": 13}, {"solution": "def magic_square_test(matrix):\n # This function checks if a matrix is a magic square.\n\n # Check if matrix is square\n n = len(matrix)\n for row in matrix:\n if len(row) != n:\n return False\n\n # Check sum across all rows\n row_sums = [sum(row) for row in matrix]\n if len(set(row_sums)) > 1:\n return False\n\n # Check sum across all columns\n column_sums = [sum(matrix[j][i] for j in range(n)) for i in range(n)]\n if len(set(column_sums)) > 1:\n return False\n\n # Check sum along diagonals\n diagonal_sums = [sum(matrix[i][i] for i in range(n)), sum(matrix[i][n - i - 1] for i in range(n))]\n if len(set(diagonal_sums)) > 1:\n return False\n\n # If all checks passed, then the matrix is a magic square\n return True", "matching_cluster_idx": 10}, {"solution": "def magic_square_test(matrix):\n # check if matrix is square\n if len(matrix) != len(matrix[0]):\n return False\n\n # calculate the sum of the first row\n row_sum = sum(matrix[0])\n\n # compare the sum with sums of other rows and columns\n for i in range(len(matrix)):\n if sum(matrix[i]) != row_sum:\n return False\n if sum(matrix[j][i] for j in range(len(matrix))) != row_sum:\n return False\n\n # check diagonals\n if sum(matrix[i][i] for i in range(len(matrix))) != row_sum:\n return False\n if sum(matrix[i][len(matrix) - i - 1] for i in range(len(matrix))) != row_sum:\n return False\n\n return True", "matching_cluster_idx": 13}, {"solution": "def magic_square_test(matrix):\n \"\"\"\n A magic square is a matrix in which all rows, columns, and diagonals sum up to the same number.\n This function checks if a given matrix is a magic square.\n \"\"\"\n # Check if matrix is square\n if len(matrix) != len(matrix[0]):\n return False\n \n # Calculate the sum of numbers in first row. All other rows should have same sum\n total_sum = sum(matrix[0])\n \n # Check if each row, column and diagonal sum up to total_sum\n for row in matrix:\n if sum(row) != total_sum:\n return False\n \n for col_index in range(len(matrix)):\n if sum(matrix[row_index][col_index] for row_index in range(len(matrix))) != total_sum:\n return False\n \n if sum(matrix[index][index] for index in range(len(matrix))) != total_sum:\n return False\n \n if sum(matrix[index][len(matrix) - index - 1] for index in range(len(matrix))) != total_sum:\n return False\n \n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n # get the sum of the first row\n sum_row = sum(matrix[0])\n # iterate through each row and check the sum of the rows\n for row in matrix:\n if sum(row) != sum_row:\n return False\n # iterate through each column and check the sum of the columns\n for i in range(len(matrix)):\n if sum(matrix[j][i] for j in range(len(matrix))) != sum_row:\n return False\n # check sum of two diagonals\n if sum(matrix[i][i] for i in range(len(matrix))) != sum_row:\n return False\n if sum(matrix[i][len(matrix)-i-1] for i in range(len(matrix))) != sum_row:\n return False\n # if all checks pass, the matrix is a magic square\n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n # calculate the sum of the first row\n reference_sum = sum(matrix[0])\n\n # check if all rows sum up to the reference sum\n for row in matrix:\n if sum(row) != reference_sum:\n return False\n\n # transpose the matrix to check the column sums\n transposed_matrix = [[matrix[j][i] for j in range(len(matrix))] for i in range(len(matrix[0]))]\n for row in transposed_matrix:\n if sum(row) != reference_sum:\n return False\n\n # check the diagonal sum\n diagonal_sum1 = sum([matrix[i][i] for i in range(len(matrix))])\n if diagonal_sum1 != reference_sum:\n return False\n\n # check the other diagonal sum\n diagonal_sum2 = sum([matrix[i][len(matrix)-i-1] for i in range(len(matrix))])\n if diagonal_sum2 != reference_sum:\n return False\n\n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n n = len(matrix)\n expected_sum = sum(matrix[0])\n for i in range(n):\n if sum(matrix[i]) != expected_sum:\n return False\n if sum([matrix[j][i] for j in range(n)]) != expected_sum:\n return False\n if sum([matrix[i][i] for i in range(n)]) != expected_sum:\n return False\n if sum([matrix[i][n - i - 1] for i in range(n)]) != expected_sum:\n return False\n return True", "matching_cluster_idx": 13}, {"solution": "def magic_square_test(matrix):\n \"\"\"\n This function checks whether the input matrix is a magic square.\n A magic square is a square matrix that contains the same numbers in every row, every column, and the sums of diagonals are equal.\n \"\"\"\n # Calculate the sum of the first row to be the expected sum\n expected_sum = sum(matrix[0])\n\n # Check if each row's sum equals the expected sum\n for row in matrix:\n if sum(row) != expected_sum:\n return False\n\n # Check if each column's sum equals the expected sum\n for i in range(len(matrix)):\n if sum(matrix[j][i] for j in range(len(matrix))) != expected_sum:\n return False\n\n # Check if the diagonal sums are equal\n if sum(matrix[i][i] for i in range(len(matrix))) != expected_sum:\n return False\n\n # Check if the reverse diagonal sums are equal\n if sum(matrix[i][len(matrix) - i - 1] for i in range(len(matrix))) != expected_sum:\n return False\n\n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n if len(set(len(row) for row in matrix)) != 1:\n return False\n \n n = len(matrix)\n target_sum = sum(matrix[0])\n \n # check row sums\n for row in matrix:\n if sum(row) != target_sum:\n return False\n \n # check column sums\n for i in range(n):\n if sum(matrix[j][i] for j in range(n)) != target_sum:\n return False\n \n # check diagonal sums\n if sum(matrix[i][i] for i in range(n)) != target_sum:\n return False\n \n if sum(matrix[i][n-i-1] for i in range(n)) != target_sum:\n return False\n \n return True", "matching_cluster_idx": 13}, {"solution": "def magic_square_test(matrix):\n if len(set(len(row) for row in matrix)) > 1:\n return False # Not a valid square\n\n if len(matrix) != len(matrix[0]):\n return False # Not a square\n\n target_sum = sum(matrix[0]) # Sum of the first row\n\n # Check rows and columns\n for row in matrix:\n if sum(row) != target_sum:\n return False\n\n for column in zip(*matrix):\n if sum(column) != target_sum:\n return False\n\n # Check diagonals\n if sum(matrix[i][i] for i in range(len(matrix))) != target_sum:\n return False\n\n if sum(matrix[i][len(matrix)-i-1] for i in range(len(matrix))) != target_sum:\n return False\n\n return True", "matching_cluster_idx": 13}, {"solution": "def magic_square_test(matrix):\n # Check if the matrix is a square\n if len(matrix) != len(matrix[0]):\n return False\n\n # Check sum of each row and column\n sum_row = [sum(row) for row in matrix]\n sum_col = [sum(column) for column in zip(*matrix)]\n\n if len(set(sum_row)) != 1 or len(set(sum_col)) != 1:\n return False\n\n # Check sum of diagonals\n sum_diag1 = sum(matrix[i][i] for i in range(len(matrix)))\n sum_diag2 = sum(matrix[i][len(matrix) - i - 1] for i in range(len(matrix)))\n\n if sum_diag1 != sum_diag2 or sum_diag1 != sum_row[0]:\n return False\n\n return True", "matching_cluster_idx": 8}]}, "Mbpp/130": {"dps": 70.26905829596413, "dps_norm": 65.0, "pass@1": 61.0, "profiled": [{"solution": "def max_occurrences(lst):\n count_dict = {}\n for item in lst:\n if item in count_dict:\n count_dict[item] += 1\n else:\n count_dict[item] = 1\n max_freq_item = max(count_dict, key=count_dict.get)\n return max_freq_item", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(lst):\n freq = {}\n for item in lst:\n if item in freq:\n freq[item] += 1\n else:\n freq[item] = 1\n max_freq_item = max(freq, key=freq.get)\n return max_freq_item", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(lst):\n from collections import Counter\n return max(Counter(lst).items(), key=lambda x: x[1])[0]", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(input_list):\n frequency_dict = {}\n for item in input_list:\n if item in frequency_dict:\n frequency_dict[item] += 1\n else:\n frequency_dict[item] = 1\n max_frequency_item = max(frequency_dict, key=frequency_dict.get)\n return max_frequency_item", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(lst):\n count_dict = {i: lst.count(i) for i in lst}\n max_key = max(count_dict, key=count_dict.get)\n return max_key", "matching_cluster_idx": 1}, {"solution": "def max_occurrences(lst):\n # Use dictionary to map each item to its frequency\n freq_dict = {}\n for item in lst:\n if item in freq_dict:\n freq_dict[item] += 1\n else:\n freq_dict[item] = 1\n\n # Find the item with maximum frequency\n max_freq = 0\n max_item = None\n for item, freq in freq_dict.items():\n if freq > max_freq:\n max_freq = freq\n max_item = item\n\n return max_item", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(lst):\n count_dict = {}\n max_count = 0\n max_item = None\n\n # count the frequency of each item\n for i in lst:\n if i in count_dict:\n count_dict[i] += 1\n else:\n count_dict[i] = 1\n\n # find the item with the maximum frequency\n for item, count in count_dict.items():\n if count > max_count:\n max_count = count\n max_item = item\n\n return max_item", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(lst):\n freq_dict = {}\n for i in lst:\n if i in freq_dict:\n freq_dict[i] += 1\n else:\n freq_dict[i] = 1\n max_freq = max(freq_dict.values())\n for item, freq in freq_dict.items():\n if freq == max_freq:\n return item", "matching_cluster_idx": 3}, {"solution": "from collections import Counter\ndef max_occurrences(lst):\n # Use collections.Counter to count frequency of each item in list\n counts = Counter(lst)\n \n # The most_common method of Counter returns a list of tuples where each tuple contains an item and its count\n # Sort the list by frequency in descending order and return the first item\n return sorted(counts.items(), key=lambda item: item[1], reverse=True)[0][0]", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(lst):\n # Use dictionary to store each item as a key and its frequency as the value\n dict_lst = {}\n for num in lst:\n if num in dict_lst:\n dict_lst[num] += 1\n else:\n dict_lst[num] = 1\n \n # Find the item with maximum frequency\n max_freq = max(dict_lst.values())\n max_freq_items = [key for key, value in dict_lst.items() if value == max_freq]\n \n # If there are more than one item with maximum frequency, return the first one\n if len(max_freq_items) > 1:\n return max_freq_items[0]\n else:\n return max_freq_items[0]", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(lst):\n counts = {}\n for item in lst:\n if item in counts:\n counts[item] += 1\n else:\n counts[item] = 1\n max_count = max(counts.values())\n for item, count in counts.items():\n if count == max_count:\n return item", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(lst):\n # Initialize an empty dictionary\n count_dict = {}\n\n # Loop over the input list\n for num in lst:\n if num not in count_dict:\n # If number not in dict, add it with count 1\n count_dict[num] = 1\n else:\n # Else increment its count by 1\n count_dict[num] += 1\n\n # Return the number with maximum count\n return max(count_dict, key=count_dict.get)", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(lst):\n from collections import Counter\n # Use Counter to get the count of each element\n count = Counter(lst)\n # Get the maximum value from the count dictionary\n max_value = max(list(count.values()))\n # Return the key that corresponds to the maximum value\n for key, value in count.items():\n if value == max_value:\n return key", "matching_cluster_idx": 4}, {"solution": "def max_occurrences(lst):\n counts = {}\n for num in lst:\n if num in counts:\n counts[num] += 1\n else:\n counts[num] = 1\n max_count = max(counts.values())\n for num, count in counts.items():\n if count == max_count:\n return num", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(nums):\n # Create a dictionary that counts the frequency of each number in the list\n counts = {}\n for num in nums:\n if num not in counts:\n counts[num] = 1\n else:\n counts[num] += 1\n # Find the item (number) with maximum frequency\n max_freq = 0\n max_freq_num = None\n for num, freq in counts.items():\n if freq > max_freq:\n max_freq = freq\n max_freq_num = num\n return max_freq_num", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(numbers):\n count_dict = {}\n for number in numbers:\n if number in count_dict:\n count_dict[number] += 1\n else:\n count_dict[number] = 1\n \n max_count = 0\n max_item = None\n for item, count in count_dict.items():\n if count > max_count:\n max_count = count\n max_item = item\n \n return max_item", "matching_cluster_idx": 3}, {"solution": "from collections import Counter\ndef max_occurrences(num_list):\n count = Counter(num_list)\n max_count = max(list(count.values()))\n return [num for num, freq in count.items() if freq == max_count][0]", "matching_cluster_idx": 4}, {"solution": "def max_occurrences(input_list):\n counts = {}\n for item in input_list:\n if item in counts:\n counts[item] += 1\n else:\n counts[item] = 1\n\n max_count = max(counts.values())\n for item, count in counts.items():\n if count == max_count:\n return item", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(lst):\n \"\"\"Function to find the item with maximum frequency in a given list.\"\"\"\n freqs = {}\n for item in lst:\n if item in freqs:\n freqs[item] += 1\n else:\n freqs[item] = 1\n max_item = lst[0]\n max_freq = freqs[max_item]\n for item in freqs:\n if freqs[item] > max_freq:\n max_freq = freqs[item]\n max_item = item\n return max_item", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(lst):\n if not lst:\n return None\n freq_dict = {i: lst.count(i) for i in lst}\n max_key = max(freq_dict, key=freq_dict.get)\n return max_key", "matching_cluster_idx": 1}]}, "Mbpp/137": {"dps": null, "dps_norm": null, "pass@1": 1.0, "profiled": []}, "Mbpp/140": {"dps": 65.82298136645963, "dps_norm": 73.75, "pass@1": 79.0, "profiled": [{"solution": "def extract_singly(lst):\n return [item for sublist in lst for item in sublist]", "matching_cluster_idx": 5}, {"solution": "def extract_singly(list_of_lists):\n result = []\n for inner_list in list_of_lists:\n result.extend(inner_list)\n return result", "matching_cluster_idx": 7}, {"solution": "def flatten(nested_list):\n flat_list = []\n for sublist in nested_list:\n for item in sublist:\n flat_list.append(item)\n return flat_list\ndef extract_singly(nested_list):\n return set(flatten(nested_list))", "matching_cluster_idx": 4}, {"solution": "def extract_singly(lst):\n flat_list = []\n for sublist in lst:\n for item in sublist:\n flat_list.append(item)\n return flat_list", "matching_cluster_idx": 4}, {"solution": "def extract_singly(nested_list):\n single_list = []\n for item in nested_list:\n if isinstance(item, list):\n single_list.extend(item)\n else:\n single_list.append(item)\n return single_list", "matching_cluster_idx": 7}, {"solution": "def extract_singly(list_of_lists):\n flat_list = []\n for sublist in list_of_lists:\n for item in sublist:\n flat_list.append(item)\n return set(flat_list)", "matching_cluster_idx": 4}, {"solution": "def extract_singly(multi_list):\n flattened_list = []\n for single_list in multi_list:\n flattened_list.extend(single_list)\n return set(flattened_list)", "matching_cluster_idx": 6}, {"solution": "def extract_singly(nested_list):\n # create a new empty list\n flat_list = []\n \n # loop through each list in the nested list\n for sublist in nested_list:\n # loop through each element in the current sublist\n for item in sublist:\n # add the item to the flat list\n flat_list.append(item)\n \n # return the flat list converted to a set to remove duplicates\n return set(flat_list)", "matching_cluster_idx": 4}, {"solution": "def extract_singly(lst):\n return [item for sublist in lst for item in sublist]", "matching_cluster_idx": 5}, {"solution": "def extract_singly(list_of_lists):\n return set([number for sublist in list_of_lists for number in sublist])", "matching_cluster_idx": 5}, {"solution": "def extract_singly(input_list):\n return [i for sublist in input_list for i in sublist]", "matching_cluster_idx": 5}, {"solution": "def extract_singly(lst):\n flat_list = []\n for sublist in lst:\n for item in sublist:\n flat_list.append(item)\n return flat_list", "matching_cluster_idx": 4}, {"solution": "def extract_singly(list_of_lists):\n flattened = [number for sublist in list_of_lists for number in sublist]\n return flattened", "matching_cluster_idx": 5}, {"solution": "def extract_singly(nested_list):\n flat_list = []\n for sublist in nested_list:\n for item in sublist:\n flat_list.append(item)\n return flat_list", "matching_cluster_idx": 4}, {"solution": "def extract_singly(list_of_lists):\n return [item for sublist in list_of_lists for item in sublist]", "matching_cluster_idx": 5}, {"solution": "def extract_singly(nested_list):\n flat_list = []\n for sublist in nested_list:\n for item in sublist:\n flat_list.append(item)\n return flat_list", "matching_cluster_idx": 4}, {"solution": "def extract_singly(nested_list):\n flatten_list = []\n for inner_list in nested_list:\n for element in inner_list:\n flatten_list.append(element)\n return flatten_list", "matching_cluster_idx": 4}, {"solution": "def extract_singly(input_list):\n flat_list = [item for sublist in input_list for item in sublist]\n return flat_list", "matching_cluster_idx": 5}, {"solution": "def extract_singly(list_of_lists):\n flat_list = []\n for sublist in list_of_lists:\n for item in sublist:\n flat_list.append(item)\n return flat_list", "matching_cluster_idx": 4}, {"solution": "def extract_singly(list_of_lists):\n \"\"\"\n Function to flatten the list of lists into a single set of numbers.\n :param list_of_lists: input list of lists.\n :return: returns a set of numbers extracted from the input list of lists.\n \"\"\"\n result = set()\n for list_ in list_of_lists:\n result.update(list_)\n return result", "matching_cluster_idx": 7}]}, "Mbpp/141": {"dps": 87.12018140589569, "dps_norm": 51.875, "pass@1": 54.0, "profiled": [{"solution": "def pancake_sort(lst):\n lst_copy = lst.copy()\n lst_copy.sort()\n return lst_copy", "matching_cluster_idx": 7}, {"solution": "def find_max(l, start, end):\n i = start\n max_elem = l[start]\n for j in range(start, end + 1):\n if l[j] > max_elem:\n max_elem = l[j]\n i = j\n return i\ndef flip(l, start, end):\n while start < end:\n l[start], l[end] = l[end], l[start]\n start += 1\n end -= 1\n return l\ndef pancake_sort(l):\n n = len(l)\n for i in range(n - 1, -1, -1):\n max_pos = find_max(l, 0, i)\n if max_pos != i:\n flip(l, 0, max_pos)\n flip(l, 0, i)\n return l", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(arr):\n n = len(arr)\n \n for i in range(n):\n max_idx = max(range(n-i), key=arr.__getitem__)\n arr[:max_idx+1] = arr[max_idx::-1] \n arr[:n-i] = arr[n-i-1::-1] \n \n return arr", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(list_):\n # Reverse sort function\n def flip(list_, k):\n i = 0\n while i < k/2:\n list_[i], list_[k-i-1] = list_[k-i-1], list_[i]\n i += 1\n return list_\n\n # Pancake sort function\n for size in range(len(list_), 0, -1):\n # Identify index of the maximum element\n max_index = list_.index(max(list_[:size]))\n\n # Move maximum element to its correct position\n if max_index != size - 1:\n list_ = flip(list_, max_index + 1)\n list_ = flip(list_, size)\n\n return list_", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(elements):\n for i in range(len(elements)):\n max_index = 0\n for j in range(len(elements)-i):\n if elements[j] > elements[max_index]:\n max_index = j\n elements[max_index], elements[-i-1] = elements[-i-1], elements[max_index]\n return elements", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(lst):\n for i in range(len(lst), 0, -1):\n index = lst.index(max(lst[:i]))\n lst = lst[:index+1][::-1] + lst[index+1:]\n lst = lst[:i][::-1] + lst[i:]\n return lst", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(lst):\n \"\"\"\n Function that sorts a list of elements using pancake sort.\n Pancake sort works by reversing the order of the elements in the list.\n \"\"\"\n # Iterate over the whole list\n for size in range(len(lst), 0, -1):\n # Find the index of the maximum element in the unsorted part of the list\n max_index = lst.index(max(lst[:size]))\n\n # If the maximum element is not at the end of the list, flip the list to put it there\n if max_index != size - 1:\n # Reverse the first `max_index + 1` elements to move the max element to the beginning of the list\n lst = lst[max_index::-1] + lst[max_index + 1:size] + lst[size:]\n\n # Reverse the first `size` elements to move the max element to the correct position\n lst = lst[size - 1::-1] + lst[size:]\n return lst", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(input_list):\n # Using bubble sort as the simplest and most straightforward sorting algorithm.\n # This function works on the principle of repeatedly swapping the adjacent elements if they are in wrong order.\n for i in range(len(input_list)-1,0,-1): \n for j in range(i):\n if input_list[j]>input_list[j+1]:\n temp = input_list[j]\n input_list[j] = input_list[j+1]\n input_list[j+1] = temp\n return input_list", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(lst):\n for size in reversed(range(len(lst))):\n max_idx = max(range(size+1), key=lst.__getitem__)\n if max_idx != size:\n lst[:max_idx+1] = reversed(lst[:max_idx+1])\n lst[:size+1] = reversed(lst[:size+1])\n return lst", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(lst):\n for i in range(len(lst), 0, -1):\n max_index = lst.index(max(lst[:i]))\n if max_index != i-1:\n lst[:max_index+1] = lst[:max_index+1][::-1]\n lst[:i] = lst[:i][::-1]\n return lst", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(lst):\n # Create a copy of the list to avoid mutating it\n lst = lst[:]\n # Our last element to flip is the first index\n end = len(lst)\n\n # Our outer loop will keep running until we've sorted all elements\n while end > 0:\n # Let's find the index of the largest element in the current unsorted segment\n max_index = lst[:end].index(max(lst[:end]))\n\n # Flip the max element to its correct position (i.e., the front)\n lst[:max_index + 1] = reversed(lst[:max_index + 1])\n # Flip the entire unsorted segment to its correct position (i.e., the front)\n lst[:end] = reversed(lst[:end])\n\n # Our sorted segment is now the end of the list\n end -= 1\n\n return lst", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(list):\n for cur_size in reversed(range(len(list))):\n # Find index of max element in the array:\n max_index = max(range(cur_size + 1), key=list.__getitem__)\n # If max is at beginning of current sublist, no need to flip\n if max_index != cur_size:\n # Move max item to end of list\n list = list[:max_index + 1][::-1] + list[max_index + 1:]\n # Move the largest number to the start\n list = list[:cur_size + 1][::-1] + list[cur_size + 1:]\n return list", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(list_to_sort):\n # Utilize python's in-built sorting function\n list_to_sort.sort()\n return list_to_sort", "matching_cluster_idx": 7}, {"solution": "def pancake_sort(lst):\n def flip(sub_lst, k):\n return sub_lst[:k][::-1] + sub_lst[k:]\n\n def max_index(sub_lst):\n return sub_lst.index(max(sub_lst))\n\n for size in reversed(range(len(lst))):\n max_pos = max_index(lst[:size+1])\n if max_pos != size:\n if max_pos != 0:\n lst = flip(lst, max_pos+1)\n lst = flip(lst, size+1)\n return lst", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(lst):\n \"\"\"\n The pancake_sort function sorts an input list.\n \"\"\"\n for i in range(len(lst), 0, -1):\n max_idx = lst.index(max(lst[0:i]))\n if max_idx != i - 1:\n lst = lst[:max_idx+1][::-1] + lst[max_idx+1:]\n lst = lst[:i][::-1] + lst[i:]\n return lst", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(arr):\n for size in reversed(range(len(arr))):\n max_idx = max(range(size+1), key=arr.__getitem__)\n if max_idx != size:\n arr[:max_idx+1] = reversed(arr[:max_idx+1])\n arr[:size+1] = reversed(arr[:size+1])\n return arr", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(lst):\n for i in range(len(lst)):\n max_idx = lst.index(max(lst[:len(lst)-i]))\n lst = flip(lst, max_idx)\n lst = flip(lst, len(lst)-i-1)\n return lst\ndef flip(lst, idx):\n return lst[:idx+1][::-1] + lst[idx+1:]", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(lst):\n for i in range(len(lst), 1, -1):\n idx = lst.index(max(lst[:i]))\n if idx+1 != i:\n lst[:idx+1] = reversed(lst[:idx+1])\n lst[:i] = reversed(lst[:i])\n return lst", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(lst):\n \"\"\"\n Function to sort a list of elements.\n \"\"\"\n for i in range(len(lst)-1, 0, -1):\n max_index = lst.index(max(lst[0:i+1]))\n lst[0:max_index+1] = reversed(lst[0:max_index+1])\n lst[0:i+1] = reversed(lst[0:i+1])\n return lst", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(arr):\n for cur in range(len(arr), 0, -1):\n max_pos = max_pos_finder(arr, cur)\n arr = flip(arr, max_pos)\n arr = flip(arr, cur-1)\n return arr\ndef max_pos_finder(arr, cur):\n max_pos = arr[:cur].index(max(arr[:cur]))\n return max_pos\ndef flip(arr, k):\n return arr[:k+1][::-1] + arr[k+1:]", "matching_cluster_idx": 3}]}, "Mbpp/166": {"dps": 94.39999999999999, "dps_norm": 50.0, "pass@1": 66.0, "profiled": [{"solution": "def find_even_pair(lst):\n count = 0\n for i in range(len(lst)):\n for j in range(i+1, len(lst)):\n if (lst[i] ^ lst[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(lst):\n count = 0\n for i in range(len(lst)):\n for j in range(i+1, len(lst)):\n if (lst[i] ^ lst[j]) % 2 == 0: # xor operation\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(nums):\n count = 0\n for i in range(len(nums)):\n for j in range(i+1, len(nums)):\n if (nums[i] ^ nums[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(num_list):\n count = 0\n for i in range(len(num_list)):\n for j in range(i+1, len(num_list)):\n if (num_list[i] ^ num_list[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(nums):\n pair_count = 0\n for i in range(len(nums)):\n for j in range(i+1, len(nums)):\n if (nums[i] ^ nums[j]) % 2 == 0: # Using bitwise XOR operator to calculate xor and then check if it's even\n pair_count += 1\n return pair_count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(nums):\n count = 0\n for i in range(len(nums)):\n for j in range(i+1, len(nums)):\n if (nums[i] ^ nums[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(lst):\n count = 0\n for i in range(len(lst)):\n for j in range(i+1, len(lst)):\n if (lst[i] ^ lst[j]) % 2 == 0: # Python ^ operator performs the XOR operation\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(lst):\n pairs_count = 0\n for i in range(len(lst)):\n for j in range(i+1, len(lst)):\n if (lst[i] ^ lst[j]) % 2 == 0: # ^ is the bitwise XOR operator.\n pairs_count += 1\n return pairs_count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(lst):\n count = 0\n for i in range(len(lst)):\n for j in range(i + 1, len(lst)):\n if (lst[i] ^ lst[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(lst):\n count = 0\n for i in range(len(lst)):\n for j in range(i + 1, len(lst)):\n if (lst[i] ^ lst[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(lst):\n counter = 0\n for i in range(len(lst)):\n for j in range(i + 1, len(lst)):\n if (lst[i] ^ lst[j]) % 2 == 0:\n counter += 1\n return counter", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(lst):\n count = 0\n for i in range(len(lst)):\n for j in range(i+1, len(lst)):\n if (lst[i] ^ lst[j]) % 2 == 0: # '^' is the xor operator in Python\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(lst):\n pairs = 0\n for i in range(len(lst)):\n for j in range(i+1, len(lst)):\n if (lst[i] ^ lst[j]) % 2 == 0:\n pairs += 1\n return pairs", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(numbers):\n count = 0\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n if (numbers[i] ^ numbers[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(lst):\n count = 0\n for i in range(len(lst)):\n for j in range(i + 1, len(lst)):\n if (lst[i] ^ lst[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(lst):\n count = 0\n for i in range(len(lst)):\n for j in range(i+1, len(lst)):\n if (lst[i] ^ lst[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(lst):\n count = 0\n # Iterate over each pair of numbers in the list\n for i in range(len(lst)):\n for j in range(i + 1, len(lst)):\n # Xor the pair and check if the result is even\n if (lst[i] ^ lst[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(numbers):\n count = 0\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n if (numbers[i] ^ numbers[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(num_list):\n count = 0\n for i in range(len(num_list)):\n for j in range(i + 1, len(num_list)):\n if (num_list[i] ^ num_list[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(arr):\n count = 0\n for i in range(len(arr)):\n for j in range(i + 1, len(arr)):\n if (arr[i] ^ arr[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}]}, "Mbpp/170": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 73.0, "profiled": [{"solution": "def sum_range_list(num_list, start_idx, end_idx):\n return sum(num_list[start_idx:end_idx+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(lst, start, end):\n return sum(lst[start:end+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(list, start_index, end_index):\n return sum(list[start_index : end_index+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(lst, start_idx, end_idx):\n return sum(lst[start_idx:end_idx + 1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(lst, start, end):\n return sum(lst[start:end+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(lst, start, end):\n return sum(lst[start:end+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(list, start_index, end_index):\n if end_index > len(list) - 1: # if the end index is greater than the list length, set it equal to the last index.\n end_index = len(list) - 1\n \n return sum(list[start_index:end_index+1]) # use python's built-in sum function and slicing to find the sum", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(numbers, start, end):\n return sum(numbers[start:end+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(input_list, start_index, end_index):\n return sum(input_list[start_index:end_index+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(lst, start, end):\n return sum(lst[start:end+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(lst, start, end):\n return sum(lst[start:end+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(list, start, end):\n \"\"\"\n A function to calculate the sum of a list within a range specified by two indices.\n \"\"\"\n return sum(list[start:end+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(lst, start, end):\n return sum(lst[start:end+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(nums, start, end):\n if end >= len(nums) or start < 0:\n return 0\n elif start > end:\n return 0\n else:\n return sum(nums[start:end+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(num_list, start, end):\n return sum(num_list[start:end+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(numbers, i, j):\n return sum(numbers[i:j+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(numbers, start, end):\n return sum(numbers[start:end+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(input_list, start_index, end_index):\n return sum(input_list[start_index:end_index+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(lst, start_index, end_index):\n \"\"\"\n Function to calculate sum of numbers within a range in a list\n \"\"\"\n if len(lst) > end_index:\n return sum(lst[start_index:end_index+1])\n else:\n return \"Invalid Range\"", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(lst, start, end):\n return sum(lst[start:end+1])", "matching_cluster_idx": 7}]}, "Mbpp/226": {"dps": 78.56589147286822, "dps_norm": 51.42857142857142, "pass@1": 94.0, "profiled": [{"solution": "def odd_values_string(str):\n return str[::2]", "matching_cluster_idx": 5}, {"solution": "def odd_values_string(str):\n result = \"\"\n for i in range(len(str)):\n if i % 2 == 0:\n result = result + str[i]\n return result", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(input_string):\n return input_string[::2]", "matching_cluster_idx": 5}, {"solution": "def odd_values_string(input_string):\n # empty string to hold the output\n output_string = ''\n # iterate through each character in the input string\n for i in range(len(input_string)):\n # check if the index is even\n if i % 2 == 0:\n # add the character to the output string\n output_string += input_string[i]\n return output_string", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(s):\n new_str = \"\"\n for i in range(len(s)):\n if i % 2 == 0:\n new_str += s[i]\n return new_str", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(str):\n result = \"\"\n for i in range(len(str)):\n if i % 2 == 0:\n result = result + str[i]\n return result", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(str):\n # empty string to store result\n result = \"\"\n # iterate over the string\n for i in range(len(str)):\n # check if the index is even\n if i % 2 == 0:\n # append the character to the result\n result += str[i]\n return result", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(s):\n return s[::2]", "matching_cluster_idx": 5}, {"solution": "def odd_values_string(input_string):\n return input_string[::2]", "matching_cluster_idx": 5}, {"solution": "def odd_values_string(input_string):\n return input_string[::2]", "matching_cluster_idx": 5}, {"solution": "def odd_values_string(s):\n return s[::2]", "matching_cluster_idx": 5}, {"solution": "def odd_values_string(string):\n return string[::2]", "matching_cluster_idx": 5}, {"solution": "def odd_values_string(input_string):\n # We use list comprehension and join method to concatenate only the characters\n # with even index values from the input string\n return ''.join([input_string[i] for i in range(len(input_string)) if i % 2 == 0])", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(str):\n return str[::2]", "matching_cluster_idx": 5}, {"solution": "def odd_values_string(str):\n result = \"\"\n for i in range(len(str)):\n if i % 2 == 0:\n result = result + str[i]\n return result", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(str):\n new_string = \"\"\n for i in range(len(str)):\n if i % 2 == 0: \n new_string = new_string + str[i]\n return new_string", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(input_str):\n return input_str[::2]", "matching_cluster_idx": 6}, {"solution": "def odd_values_string(str):\n result = \"\"\n for i in range(len(str)):\n if i % 2 == 0:\n result = result + str[i]\n return result", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(string):\n # Using list comprehension + range() function\n # To get characters at odd index\n # and join() method to concatenate the characters\n return ''.join([string[i] for i in range(len(string)) if i % 2 == 0])", "matching_cluster_idx": 1}, {"solution": "def odd_values_string(input_string):\n return input_string[::2]", "matching_cluster_idx": 5}]}, "Mbpp/230": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def replace_blank(input_str, replacer):\n return input_str.replace(' ', replacer)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(string, char):\n return string.replace(' ', char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(string, character):\n return string.replace(\" \", character)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(string, char):\n # Replace the blank spaces in the string with the character\n new_string = string.replace(' ', char)\n return new_string", "matching_cluster_idx": 7}, {"solution": "def replace_blank(string, character):\n return string.replace(' ', character)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(s, ch):\n return s.replace(' ', ch)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(s, char):\n return s.replace(\" \", char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(s, char):\n return s.replace(\" \", char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(string, char):\n \"\"\"\n Function to replace all blank spaces with a given character.\n \n Parameters:\n string (str): The string that needs to be modified.\n char (str): The character that will replace the blank spaces.\n \n Returns:\n str: The string with all blank spaces replaced by the provided character.\n \"\"\"\n return string.replace(\" \", char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(s, c):\n return s.replace(' ', c)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_str, replacement):\n return input_str.replace(' ', replacement)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(string,char):\n return string.replace(' ',char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(string, character):\n return string.replace(' ', character)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(string, char):\n return string.replace(\" \", char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string, replacement_char):\n \"\"\"\n This function replaces all the blank spaces in the string with the specified character\n and returns the modified string.\n \"\"\"\n # Replace all blank spaces in the string with the replacement character\n new_string = input_string.replace(' ', replacement_char)\n \n return new_string", "matching_cluster_idx": 7}, {"solution": "def replace_blank(s, c):\n return s.replace(' ', c)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(string, character):\n return string.replace(' ', character)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(text, replacement):\n return text.replace(' ', replacement)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(s, c):\n return s.replace(' ', c)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(s, c):\n return s.replace(' ', c)", "matching_cluster_idx": 7}]}, "Mbpp/239": {"dps": null, "dps_norm": null, "pass@1": 0.0, "profiled": []}, "Mbpp/240": {"dps": 78.47560975609757, "dps_norm": 86.66666666666667, "pass@1": 48.0, "profiled": [{"solution": "def replace_list(list1, list2):\n list1[-1:] = list2\n return list1", "matching_cluster_idx": 7}, {"solution": "def replace_list(lst1, lst2):\n return lst1[:-1] + lst2", "matching_cluster_idx": 5}, {"solution": "def replace_list(list1, list2):\n # Replace last element of first list with second list\n list1[-1:] = list2\n return list1", "matching_cluster_idx": 7}, {"solution": "def replace_list(list1, list2):\n list1[-1:] = list2\n return list1", "matching_cluster_idx": 7}, {"solution": "def replace_list(lst1, lst2):\n lst1.pop()\n lst1.extend(lst2)\n return lst1", "matching_cluster_idx": 8}, {"solution": "def replace_list(list1, list2):\n list1[-1:] = list2\n return list1", "matching_cluster_idx": 7}, {"solution": "def replace_list(list1, list2):\n if len(list1) > 0:\n list1[-1:] = list2\n else:\n list1 = list2\n return list1", "matching_cluster_idx": 7}, {"solution": "def replace_list(l1, l2):\n # Remove the last element from the first list\n l1.pop()\n # Add the elements of the second list to the first list\n l1.extend(l2)\n return l1", "matching_cluster_idx": 8}, {"solution": "def replace_list(lst1, lst2):\n # Remove the last element from the first list\n lst1 = lst1[:-1]\n # Concatenate the lists\n lst1.extend(lst2)\n # Return the result\n return lst1", "matching_cluster_idx": 6}, {"solution": "def replace_list(list1, list2):\n if len(list1) > 0:\n list1.pop()\n return list1 + list2", "matching_cluster_idx": 6}, {"solution": "def replace_list(list1, list2):\n # Replace the last element of the first list with the elements of the second list\n list1[-1:] = list2\n return list1", "matching_cluster_idx": 7}, {"solution": "def replace_list(lst1, lst2):\n # check if lst1 is not empty\n if lst1:\n # replace last element with lst2\n lst1[-1:] = lst2\n return lst1", "matching_cluster_idx": 7}, {"solution": "def replace_list(lst1, lst2):\n return lst1[:-1] + lst2", "matching_cluster_idx": 5}, {"solution": "def replace_list(list1, list2):\n list1[-1:] = list2\n return list1", "matching_cluster_idx": 7}, {"solution": "def replace_list(lst1, lst2):\n # Remove the last element from the first list\n lst1.pop()\n # Then append the elements from the second list\n lst1.extend(lst2)\n return lst1", "matching_cluster_idx": 8}, {"solution": "def replace_list(lst1, lst2):\n \"\"\"\n This function replaces the last element of the first list with the elements of the second list.\n \"\"\"\n # get the last element of the first list\n last_elem = lst1[-1]\n\n # replace last element of the first list with the elements of the second list\n new_lst = lst1[:-1] + lst2\n\n return new_lst", "matching_cluster_idx": 5}, {"solution": "def replace_list(list1, list2):\n list1[-1:] = list2\n return list1", "matching_cluster_idx": 7}, {"solution": "def replace_list(list1, list2):\n if len(list1) == 0:\n return list2\n else:\n list1[-1:] = list2\n return list1", "matching_cluster_idx": 7}, {"solution": "def replace_list(lst1, lst2):\n # Check if lst1 is not empty\n if lst1:\n # Remove the last element\n lst1.pop()\n # Append lst2 to lst1\n lst1.extend(lst2)\n return lst1", "matching_cluster_idx": 8}, {"solution": "def replace_list(list1, list2):\n # Check if list1 is not empty\n if list1:\n # Replace the last element of list1 with elements of list2\n list1[-1:] = list2\n return list1", "matching_cluster_idx": 7}]}, "Mbpp/251": {"dps": 78.59195402298852, "dps_norm": 70.0, "pass@1": 50.0, "profiled": [{"solution": "def insert_element(lst, elem):\n \"\"\"\n Function to insert a given element before each element in a list\n \"\"\"\n res = []\n for i in lst:\n res.extend([elem, i])\n return res", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n new_lst = []\n for item in lst:\n new_lst.append(element)\n new_lst.append(item)\n return new_lst", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, elem):\n for i in range(len(lst)-1, -1, -1):\n lst.insert(i, elem)\n return lst", "matching_cluster_idx": 0}, {"solution": "def insert_element(input_list, element):\n output_list = []\n for i in input_list:\n output_list.append(element)\n output_list.append(i)\n return output_list", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n \"\"\"\n Insert an element before each element in a list.\n \"\"\"\n result = []\n for i in lst:\n result.append(element)\n result.append(i)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n # The insert() function inserts a specified value at the specified position in the list\n for i in range(len(lst)):\n lst.insert(i*2, element)\n return lst", "matching_cluster_idx": 2}, {"solution": "def insert_element(lst, element):\n result = []\n for i in lst:\n result.append(element)\n result.append(i)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n new_lst = []\n for i in lst:\n new_lst.append(element)\n new_lst.append(i)\n return new_lst", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n result = []\n for i in lst:\n result.append(element)\n result.append(i)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(my_list, element):\n new_list = []\n for item in my_list:\n new_list.append(element)\n new_list.append(item)\n return new_list", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, elem):\n for i in range(len(lst)):\n lst.insert(2*i, elem)\n return lst", "matching_cluster_idx": 2}, {"solution": "def insert_element(lst, elem):\n result = []\n for item in lst:\n result.append(elem)\n result.append(item)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(input_list, element):\n result = []\n for item in input_list:\n result.append(element)\n result.append(item)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n new_lst = []\n for item in lst:\n new_lst += [element, item]\n return new_lst", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, el):\n new_lst = []\n for item in lst:\n new_lst.append(el)\n new_lst.append(item)\n return new_lst", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n result = []\n for item in lst:\n result.extend([element, item])\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, elm):\n result = []\n for item in lst:\n result += [elm, item]\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, elem):\n result = []\n for i in lst:\n result.append(elem)\n result.append(i)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n result = []\n for i in lst:\n result.append(element)\n result.append(i)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(input_list, element):\n result = []\n for item in input_list:\n result.extend([element, item])\n return result", "matching_cluster_idx": 6}]}, "Mbpp/256": {"dps": 60.45662100456621, "dps_norm": 56.470588235294116, "pass@1": 90.0, "profiled": [{"solution": "def count_Primes_nums(n):\n def is_prime(num):\n if num < 2:\n return False\n for i in range(2, int(num ** 0.5) + 1):\n if num % i == 0:\n return False\n return True\n count = 0\n for i in range(2, n):\n if is_prime(i):\n count += 1\n return count", "matching_cluster_idx": 8}, {"solution": "def count_Primes_nums(n):\n def is_prime(num):\n if num < 2:\n return False\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n return False\n return True\n\n return sum(is_prime(i) for i in range(n))", "matching_cluster_idx": 8}, {"solution": "def is_prime(n):\n \"\"\"Checks if a number is a prime number\"\"\"\n if n <= 1:\n return False\n elif n <= 3:\n return True\n elif n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True\ndef count_Primes_nums(num):\n \"\"\"Count the number of prime numbers less than the given non-negative number\"\"\"\n count = 0\n for i in range(2, num):\n if is_prime(i):\n count += 1\n return count", "matching_cluster_idx": 10}, {"solution": "def count_Primes_nums(n):\n def is_prime(num):\n if num < 2:\n return False\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n return False\n return True\n \n count = 0\n for num in range(n):\n if is_prime(num):\n count += 1\n return count", "matching_cluster_idx": 8}, {"solution": "def count_Primes_nums(n):\n def is_prime(num):\n if num < 2:\n return False\n for i in range(2, int(num ** 0.5) + 1):\n if num % i == 0:\n return False\n return True\n return sum(is_prime(i) for i in range(n))", "matching_cluster_idx": 8}, {"solution": "def count_Primes_nums(n):\n def is_prime(x):\n if x < 2:\n return False\n for i in range(2, int(x**0.5) + 1):\n if x % i == 0:\n return False\n return True\n\n prime_count = 0\n for i in range(n):\n if is_prime(i):\n prime_count += 1\n\n return prime_count", "matching_cluster_idx": 8}, {"solution": "def is_prime(n):\n \"\"\"\n Helper function to check if a number is prime.\n \"\"\"\n if n == 0 or n == 1:\n return False\n for x in range(2, int(n ** 0.5) + 1):\n if n % x == 0:\n return False\n return True\ndef count_Primes_nums(n):\n \"\"\"\n Main function to count the number of prime numbers less than a given number.\n \"\"\"\n count = 0\n for x in range(2, n):\n if is_prime(x):\n count += 1\n return count", "matching_cluster_idx": 8}, {"solution": "def is_prime(n):\n if n == 0 or n == 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True\ndef count_Primes_nums(n):\n count = 0\n for i in range(n):\n if is_prime(i):\n count += 1\n return count", "matching_cluster_idx": 8}, {"solution": "def is_prime(n):\n if n < 2:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True\ndef count_Primes_nums(n):\n return sum(is_prime(i) for i in range(n))", "matching_cluster_idx": 8}, {"solution": "def count_Primes_nums(num):\n # Define the function to check if a number is prime\n def is_prime(n):\n if n <= 1:\n return False\n if n == 2:\n return True\n if n % 2 == 0:\n return False\n for i in range(3, int(n ** 0.5) + 1, 2):\n if n % i == 0:\n return False\n return True\n\n # Count the number of primes that are less than the given non-negative number\n count = 0\n for i in range(num):\n if is_prime(i):\n count += 1\n return count", "matching_cluster_idx": 10}, {"solution": "def is_prime(n):\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True\ndef count_Primes_nums(n):\n count = 0\n for i in range(2, n):\n if is_prime(i):\n count += 1\n return count", "matching_cluster_idx": 10}, {"solution": "def count_Primes_nums(n):\n def is_prime(num):\n if num < 2:\n return False\n for i in range(2, int(num ** 0.5) + 1):\n if num % i == 0:\n return False\n return True\n\n primes = [i for i in range(n) if is_prime(i)]\n return len(primes)", "matching_cluster_idx": 8}, {"solution": "def is_prime(n):\n if n < 2:\n return False\n if n == 2:\n return True\n if n % 2 == 0:\n return False\n max_divisor = int(n ** 0.5) + 1\n for d in range(3, max_divisor, 2):\n if n % d == 0:\n return False\n return True\ndef count_Primes_nums(n):\n count = 0\n for i in range(2, n):\n if is_prime(i):\n count += 1\n return count", "matching_cluster_idx": 10}, {"solution": "def count_Primes_nums(n):\n def is_prime(num):\n if num < 2:\n return False\n for i in range(2,int(num**0.5)+1):\n if num % i == 0:\n return False\n return True\n count = 0\n for i in range(2,n):\n if is_prime(i):\n count += 1\n return count", "matching_cluster_idx": 8}, {"solution": "def count_Primes_nums(n):\n def is_prime(num):\n if num < 2:\n return False\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n return False\n return True\n return sum(is_prime(i) for i in range(2, n))", "matching_cluster_idx": 8}, {"solution": "def is_prime(n):\n \"\"\"\n Helper function to check if a number is prime\n \"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True\ndef count_Primes_nums(num):\n \"\"\"\n Count the number of prime numbers less than num\n \"\"\"\n count = 0\n for i in range(2, num):\n if is_prime(i):\n count += 1\n return count", "matching_cluster_idx": 10}, {"solution": "def count_Primes_nums(n):\n def is_prime(num):\n if num < 2:\n return False\n for i in range(2, int(num ** 0.5) + 1):\n if num % i == 0:\n return False\n return True\n\n count = 0\n for i in range(2, n):\n if is_prime(i):\n count += 1\n return count", "matching_cluster_idx": 8}, {"solution": "def is_prime(n):\n if n <= 1:\n return False\n if n == 2:\n return True\n if n % 2 == 0:\n return False\n for i in range(3, int(n ** 0.5) + 1, 2):\n if n % i == 0:\n return False\n return True\ndef count_Primes_nums(num):\n count = 0\n for i in range(2, num):\n if is_prime(i):\n count += 1\n return count", "matching_cluster_idx": 10}, {"solution": "def is_prime(num):\n \"\"\"Checks if a number is prime.\"\"\"\n if num <= 1:\n return False\n elif num == 2:\n return True\n else:\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n return False\n return True\ndef count_Primes_nums(num):\n \"\"\"Counts the number of prime numbers less than the given non-negative number.\"\"\"\n count = 0\n for i in range(2, num):\n if is_prime(i):\n count += 1\n return count", "matching_cluster_idx": 8}, {"solution": "def count_Primes_nums(n):\n def is_prime(num):\n if num < 2:\n return False\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n return False\n return True\n \n prime_count = 0\n for i in range(n):\n if is_prime(i):\n prime_count += 1\n return prime_count", "matching_cluster_idx": 8}]}, "Mbpp/265": {"dps": 70.93023255813954, "dps_norm": 83.33333333333333, "pass@1": 14.0, "profiled": [{"solution": "def list_split(lst, n):\n return [lst[i::n] for i in range(n)]", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n return [lst[i::n] for i in range(n)]", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n return [lst[i::n] for i in range(n)]", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n return [lst[i::n] for i in range(n)]", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n return [lst[i::n] for i in range(n)]", "matching_cluster_idx": 4}, {"solution": "def list_split(input_list, n):\n return [input_list[i::n] for i in range(n)]", "matching_cluster_idx": 4}, {"solution": "def list_split(input_list, n):\n return [input_list[i::n] for i in range(n)]", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n return [lst[i::n] for i in range(n)]", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n return [lst[i::n] for i in range(n)]", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n return [lst[i::n] for i in range(n)]", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n return [lst[i::n] for i in range(n)]", "matching_cluster_idx": 4}, {"solution": "def list_split(input_list, n):\n return [input_list[i::n] for i in range(n)]", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n return [lst[i::n] for i in range(n)]", "matching_cluster_idx": 4}, {"solution": "def list_split(input_list, n):\n return [input_list[i::n] for i in range(n)]", "matching_cluster_idx": 4}]}, "Mbpp/281": {"dps": 94.0, "dps_norm": 81.81818181818181, "pass@1": 100.0, "profiled": [{"solution": "def all_unique(lst):\n \"\"\"\n Function checks if all elements of the given list are unique.\n\n Args:\n lst (list): The list to be checked for duplicates.\n\n Returns:\n bool: True if all elements in the list are unique, False otherwise.\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(list):\n \"\"\"\n This function checks if all elements in a given list are unique.\n \"\"\"\n if len(list) == len(set(list)):\n return True\n else:\n return False", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n Check if all elements in a given list are unique\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(input_list):\n return len(input_list) == len(set(input_list))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n Return True if all elements in the given list are unique. Otherwise, return False.\n\n Args:\n lst (list): The list to check.\n\n Returns:\n bool: True if all elements are unique, False otherwise.\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n Check if all elements in a given list are unique or not.\n \"\"\"\n # return True if there are no duplicates in the list\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(list):\n if len(list) == len(set(list)):\n return True\n else:\n return False", "matching_cluster_idx": 8}]}, "Mbpp/296": {"dps": 42.56410256410256, "dps_norm": 73.33333333333334, "pass@1": 86.0, "profiled": [{"solution": "def get_Inv_Count(arr):\n inversion_count = 0\n for i in range(len(arr)):\n for j in range(i+1, len(arr)):\n if arr[i] > arr[j]:\n inversion_count += 1\n return inversion_count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n inv_count = 0\n for i in range(len(arr)):\n for j in range(i + 1, len(arr)):\n if arr[i] > arr[j]:\n inv_count += 1\n return inv_count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr): \n inv_count = 0\n for i in range(len(arr)): \n for j in range(i + 1, len(arr)): \n if arr[i] > arr[j]: \n inv_count += 1\n return inv_count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n inv_count = 0\n for i in range(len(arr)):\n for j in range(i+1, len(arr)):\n if arr[i] > arr[j]:\n inv_count += 1\n return inv_count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n inv_count = 0\n for i in range(len(arr)):\n for j in range(i + 1, len(arr)):\n if arr[i] > arr[j]:\n inv_count += 1\n return inv_count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n inv_count = 0\n n = len(arr)\n for i in range(n):\n for j in range(i + 1, n):\n if arr[i] > arr[j]:\n inv_count += 1\n return inv_count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n inv_count = 0\n for i in range(len(arr)):\n for j in range(i+1, len(arr)):\n if (arr[i] > arr[j]):\n inv_count += 1\n return inv_count", "matching_cluster_idx": 3}, {"solution": "def merge_and_count_split_inv(left, right, arr):\n i = j = k = 0\n inv_count = 0\n while i < len(left) and j < len(right):\n if left[i] <= right[j]:\n arr[k] = left[i]\n i += 1\n else:\n arr[k] = right[j]\n j += 1\n inv_count += len(left) - i\n k += 1\n while i < len(left):\n arr[k] = left[i]\n i += 1\n k += 1\n while j < len(right):\n arr[k] = right[j]\n j += 1\n k += 1\n return inv_count\ndef merge_sort_and_count_inv(arr):\n if len(arr) <= 1:\n return 0\n mid = len(arr) // 2\n left = arr[:mid]\n right = arr[mid:]\n x = merge_sort_and_count_inv(left)\n y = merge_sort_and_count_inv(right)\n z = merge_and_count_split_inv(left, right, arr)\n return x+y+z\ndef get_Inv_Count(arr):\n return merge_sort_and_count_inv(arr)", "matching_cluster_idx": 5}, {"solution": "def get_Inv_Count(arr): \n inv_count = 0\n for i in range(len(arr)): \n for j in range(i+1, len(arr)): \n if (arr[i] > arr[j]): \n inv_count += 1\n\n return inv_count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n n = len(arr)\n inv_count = 0\n for i in range(n):\n for j in range(i + 1, n):\n if arr[i] > arr[j]:\n inv_count += 1\n return inv_count", "matching_cluster_idx": 3}, {"solution": "def merge_and_count(arr, temp, left, mid, right):\n inv_count = 0\n i = left\n j = mid\n k = left\n \n while i < mid and j < right:\n if arr[i] <= arr[j]:\n temp[k] = arr[i]\n i += 1\n else:\n temp[k] = arr[j]\n j += 1\n inv_count += mid - i\n k += 1\n \n while i < mid:\n temp[k] = arr[i]\n i += 1\n k += 1\n \n while j < right:\n temp[k] = arr[j]\n j += 1\n k += 1\n \n for i in range(left, right):\n arr[i] = temp[i]\n \n return inv_count\ndef merge_sort_and_count(arr, temp, left, right):\n inv_count = 0\n if right > left + 1:\n mid = (left + right) // 2\n inv_count += merge_sort_and_count(arr, temp, left, mid)\n inv_count += merge_sort_and_count(arr, temp, mid, right)\n inv_count += merge_and_count(arr, temp, left, mid, right)\n return inv_count\ndef get_Inv_Count(arr):\n temp = [0]*len(arr)\n return merge_sort_and_count(arr, temp, 0, len(arr))", "matching_cluster_idx": 5}, {"solution": "def get_Inv_Count(arr):\n inv_count = 0\n for i in range(len(arr)):\n for j in range(i + 1, len(arr)):\n if(arr[i] > arr[j]):\n inv_count += 1\n\n return inv_count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n inv_count = 0\n for i in range(len(arr)):\n for j in range(i + 1, len(arr)):\n if arr[i] > arr[j]:\n inv_count += 1\n return inv_count", "matching_cluster_idx": 3}, {"solution": "def merge_sort_inversion_count(lst):\n if len(lst) <= 1:\n return lst, 0\n\n mid = len(lst) // 2\n left, left_inv_count = merge_sort_inversion_count(lst[:mid])\n right, right_inv_count = merge_sort_inversion_count(lst[mid:])\n\n merged, merge_inv_count = merge_inversion_count(left, right)\n\n return merged, left_inv_count + right_inv_count + merge_inv_count\ndef merge_inversion_count(left, right):\n i = j = k = 0\n inversions = 0\n merged = [0] * (len(left) + len(right))\n\n while i < len(left) and j < len(right):\n if left[i] <= right[j]:\n merged[k] = left[i]\n i += 1\n else:\n merged[k] = right[j]\n j += 1\n inversions += len(left) - i\n k += 1\n\n while i < len(left):\n merged[k] = left[i]\n i += 1\n k += 1\n\n while j < len(right):\n merged[k] = right[j]\n j += 1\n k += 1\n\n return merged, inversions\ndef get_Inv_Count(lst):\n _, inversion_count = merge_sort_inversion_count(lst)\n return inversion_count", "matching_cluster_idx": 5}, {"solution": "def get_Inv_Count(arr):\n inv_count = 0\n for i in range(len(arr)):\n for j in range(i+1,len(arr)):\n if arr[i] > arr[j]:\n inv_count += 1\n return inv_count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n inversion_count = 0\n for i in range(len(arr)):\n for j in range(i + 1, len(arr)):\n if arr[i] > arr[j]:\n inversion_count += 1\n return inversion_count", "matching_cluster_idx": 3}, {"solution": "def merge(left, right):\n inv_count = 0\n i = j = 0\n temp = []\n \n while i < len(left) and j < len(right):\n if left[i] <= right[j]:\n temp.append(left[i])\n i += 1\n else:\n temp.append(right[j])\n j += 1\n inv_count += (len(left)-i)\n \n temp.extend(left[i:])\n temp.extend(right[j:])\n \n return temp, inv_count\ndef merge_sort(arr):\n if len(arr) <= 1:\n return arr, 0\n \n mid = len(arr) // 2\n left, l_count = merge_sort(arr[:mid])\n right, r_count = merge_sort(arr[mid:])\n \n sorted_arr, inv_count = merge(left, right)\n total_inv_count = l_count + r_count + inv_count\n \n return sorted_arr, total_inv_count\ndef get_Inv_Count(arr):\n _, inv_count = merge_sort(arr)\n return inv_count", "matching_cluster_idx": 5}, {"solution": "def get_Inv_Count(arr):\n inv_count = 0\n for i in range(len(arr)):\n for j in range(i + 1, len(arr)):\n if arr[i] > arr[j]:\n inv_count += 1\n return inv_count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(array):\n inv_count = 0\n for i in range(len(array)):\n for j in range(i+1, len(array)):\n if array[i] > array[j]:\n inv_count += 1\n return inv_count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n inv_count = 0\n for i in range(len(arr)):\n for j in range(i + 1, len(arr)):\n if arr[i] > arr[j]:\n inv_count += 1\n return inv_count", "matching_cluster_idx": 3}]}, "Mbpp/308": {"dps": 84.3448275862069, "dps_norm": 63.333333333333336, "pass@1": 89.0, "profiled": [{"solution": "def large_product(list1, list2, num):\n products = [(x * y) for x in list1 for y in list2]\n products.sort(reverse=True)\n return products[:num]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, num):\n product_list = [i*j for i in list1 for j in list2]\n product_list.sort(reverse=True)\n return product_list[:num]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, num):\n \"\"\"\n This function finds the specified number of largest products from two given lists,\n selecting one factor from each list.\n \"\"\"\n products = [x*y for x in list1 for y in list2]\n products.sort(reverse=True)\n return products[:num]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, number):\n product_list = [i*j for i in list1 for j in list2]\n product_list.sort(reverse=True)\n return product_list[:number]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n # Merging two lists into a list of tuples of pairs\n pairs = [(x, y) for x in list1 for y in list2]\n\n # Sorting pairs in descending order according to product\n pairs.sort(key=lambda pair: pair[0]*pair[1], reverse=True)\n \n # Returning the first 'n' products\n return [pair[0]*pair[1] for pair in pairs[:n]]", "matching_cluster_idx": 2}, {"solution": "def large_product(list1, list2, n):\n products = [a*b for a in list1 for b in list2]\n products.sort(reverse=True)\n return products[:n]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, num):\n import heapq\n products = []\n for x in list1:\n for y in list2:\n products.append(x*y)\n return heapq.nlargest(num, products)", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n if n > len(list1)*len(list2):\n raise ValueError(\"The specified number of products exceeds the total number of products from both lists.\")\n products = sorted([x*y for x in list1 for y in list2], reverse=True)\n return products[:n]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n combined = [(x * y) for x in list1 for y in list2]\n combined.sort(reverse=True)\n return combined[:n]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n #create list of products of all pairs\n products = [i*j for i in list1 for j in list2]\n #sort list in descending order\n products.sort(reverse=True)\n #return first n elements\n return products[:n]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n products = [a*b for a in list1 for b in list2]\n return sorted(products, reverse=True)[:n]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n product_list = [i*j for i in list1 for j in list2]\n product_list.sort(reverse=True)\n return product_list[:n]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, num):\n pairs = [(i, j) for i in list1 for j in list2]\n products = sorted(pairs, key=lambda pair: pair[0]*pair[1], reverse=True)\n return [pair[0]*pair[1] for pair in products[:num]]", "matching_cluster_idx": 2}, {"solution": "def large_product(list1, list2, num):\n import itertools\n products = []\n for i, j in itertools.product(list1, list2):\n products.append(i*j)\n products.sort(reverse=True)\n return products[:num]", "matching_cluster_idx": 2}, {"solution": "def large_product(list1, list2, n):\n \"\"\"\n Function to find the specified number of largest products from two given lists,\n selecting one factor from each list.\n \"\"\"\n # Combine the two lists into one and find the product of each pair of numbers\n product_list = [i*j for i in list1 for j in list2]\n\n # Sort the product list in descending order and select the first n items\n result = sorted(product_list, reverse=True)[:n]\n\n return result", "matching_cluster_idx": 3}, {"solution": "def large_product(lst1, lst2, num):\n product_list = [a * b for a in lst1 for b in lst2]\n product_list.sort(reverse=True)\n return product_list[:num]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n # Compute the products of the elements in the two lists\n products = [a * b for a in list1 for b in list2]\n\n # Sort the list of products in descending order\n products.sort(reverse=True)\n \n # Return the first n products\n return products[:n]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n #Combine the two lists into a single list of tuples where each tuple consists of an element from each list.\n all_pairs = [(x, y) for x in list1 for y in list2]\n \n #Compute the product of each pair and sort the products in descending order.\n all_products = sorted([x*y for (x, y) in all_pairs], reverse=True)\n \n #Return the top n products\n return all_products[:n]", "matching_cluster_idx": 2}, {"solution": "def large_product(list1, list2, num):\n # Generate all possible products\n products = [a * b for a in list1 for b in list2]\n \n # Sort products in descending order\n products.sort(reverse=True)\n \n # Return the first 'num' products\n return products[:num]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, num):\n products = []\n for i in list1:\n for j in list2:\n products.append(i*j)\n return sorted(products, reverse=True)[:num]", "matching_cluster_idx": 3}]}, "Mbpp/392": {"dps": 73.59154929577466, "dps_norm": 76.15384615384616, "pass@1": 37.0, "profiled": [{"solution": "def get_max_sum(n, dp = {}):\n # Memoization to store previously computed values\n if n in dp: return dp[n]\n # Base case\n elif n < 2: return n\n # Recursive case\n else:\n dp[n] = max((get_max_sum(n//2, dp) + get_max_sum(n//3, dp) + get_max_sum(n//4, dp) + get_max_sum(n//5, dp)), n)\n return dp[n]", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n cache = {0: 0, 1: 1} # store previously computed results in cache\n\n def calculate_max_sum(n):\n # If n is not present in the cache, calculate it\n if n not in cache:\n cache[n] = max(calculate_max_sum(n//2) + calculate_max_sum(n//3) + calculate_max_sum(n//4) + calculate_max_sum(n//5), n)\n return cache[n]\n\n return calculate_max_sum(n)", "matching_cluster_idx": 12}, {"solution": "memoize_dict = {0:0, 1:1}\ndef get_max_sum(n):\n if n not in memoize_dict: # If we have already calculated f(n) and stored it in memoize_dict\n memoize_dict[n] = max(get_max_sum(n//2) + get_max_sum(n//3) + get_max_sum(n//4) + get_max_sum(n//5), n)\n return memoize_dict[n]", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n if n == 0:\n return 0\n else:\n return max(get_max_sum(n//2) + get_max_sum(n//3) + get_max_sum(n//4) + get_max_sum(n//5), n)", "matching_cluster_idx": 2}, {"solution": "def get_max_sum(n):\n if n <= 5:\n return n\n else:\n return max(get_max_sum(n//2) + get_max_sum(n//3) + get_max_sum(n//4) + get_max_sum(n//5), n)", "matching_cluster_idx": 8}, {"solution": "def get_max_sum(n, result_dict={}):\n \"\"\"\n Function to find the maximum sum using the equation f(n) = max( (f(n/2) + f(n/3) + f(n/4) + f(n/5)), n).\n\n Parameters:\n n (int): The initial number for which we need to find the max sum.\n result_dict (dict): A dictionary to store the results of sub-problems.\n\n Returns:\n int: The maximum sum.\n \"\"\"\n # Base case\n if n <= 1:\n return n\n\n # Check if the result is already in dictionary\n if n in result_dict:\n return result_dict[n]\n \n # Recursive case\n result_dict[n] = max((get_max_sum(n // 2, result_dict) +\n get_max_sum(n // 3, result_dict) +\n get_max_sum(n // 4, result_dict) +\n get_max_sum(n // 5, result_dict)), n)\n return result_dict[n]", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n, dp = {0: 0}):\n if n not in dp:\n dp[n] = max((get_max_sum(n//2, dp) + get_max_sum(n//3, dp) + get_max_sum(n//4, dp) + get_max_sum(n//5, dp)), n)\n return dp[n]", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n if n<=1:\n return n\n\n if n not in memo:\n memo[n] = max(get_max_sum(n//2)+get_max_sum(n//3)+get_max_sum(n//4)+get_max_sum(n//5), n)\n\n return memo[n]\nmemo = {}", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n if n < 6:\n return n\n\n max_sums = {0: 0, 1: 1, 2: 2, 3: 3, 4: 4, 5: 5}\n\n def get_max(n):\n if n in max_sums:\n return max_sums[n]\n\n max_sum = max(get_max(n//2) + get_max(n//3) + get_max(n//4) + get_max(n//5), n)\n max_sums[n] = max_sum\n return max_sum\n\n return get_max(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n dp = {0: 0, 1: 1}\n\n # Recursive function for calculating maximum sum\n def max_sum(n):\n if n not in dp:\n dp[n] = max(max_sum(n // 2) + max_sum(n // 3) + max_sum(n // 4) + max_sum(n // 5), n)\n return dp[n]\n\n return max_sum(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n \"\"\"\n function to find the maximum sum using given equation f(n) = max( (f(n/2) + f(n/3) + f(n/4) + f(n/5)), n).\n\n parameters:\n n (int) : Number for which we need to find maximum sum\n\n returns:\n max_sum (int) : Maximum sum for given n\n \"\"\"\n # Checking base case \n if n == 0 or n == 1:\n return n\n \n # calculating recursively for n/2, n/3, n/4, n/5\n n_by_2 = get_max_sum(n//2)\n n_by_3 = get_max_sum(n//3)\n n_by_4 = get_max_sum(n//4)\n n_by_5 = get_max_sum(n//5)\n \n # getting max sum from each of the four divided components\n max_sum = max(n_by_2 + n_by_3 + n_by_4 + n_by_5, n)\n \n return max_sum", "matching_cluster_idx": 3}, {"solution": "def get_max_sum(n):\n if n == 0:\n return 0\n # Recursively calculate the sum\n result = max(get_max_sum(n//2) + get_max_sum(n//3) + get_max_sum(n//4) + get_max_sum(n//5), n)\n return result", "matching_cluster_idx": 2}, {"solution": "def get_max_sum(n, cache = {}):\n #if the value is cached, return it\n if n in cache:\n return cache[n]\n\n if n < 2: \n return n\n else:\n value = max(n, get_max_sum(n//2, cache) + get_max_sum(n//3, cache) + get_max_sum(n//4, cache) + get_max_sum(n//5, cache))\n\n #caching the calculated value\n cache[n] = value\n return value", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n if n == 0:\n return 0\n return max((get_max_sum(n // 2) + get_max_sum(n // 3) + get_max_sum(n // 4) + get_max_sum(n // 5)), n)", "matching_cluster_idx": 2}, {"solution": "def get_max_sum(n):\n if n == 0:\n return 0\n return max(get_max_sum(n // 2) + get_max_sum(n // 3) + get_max_sum(n // 4) + get_max_sum(n // 5), n)", "matching_cluster_idx": 2}, {"solution": "def get_max_sum(n):\n memo = {0:0, 1:1} # Initial values\n def f(n):\n if n in memo: # Check if the value has been calculated before\n return memo[n]\n else:\n # Compute the value with the formula and store it in the memo dict\n memo[n] = max(f(n//2) + f(n//3) + f(n//4) + f(n//5), n)\n return memo[n]\n return f(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n, memo={}):\n if n <= 1:\n return n\n if n in memo:\n return memo[n]\n\n result = max((get_max_sum(n//2, memo) + get_max_sum(n//3, memo) + get_max_sum(n//4, memo) + get_max_sum(n//5, memo)), n)\n memo[n] = result\n return result", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n # Initialising cache for previously calculated sums\n cache = {0: 0, 1: 1}\n def calc_max_sum(n):\n # If value is already calculated, return from cache\n if n in cache:\n return cache[n]\n # Calculate the sum using the given equation\n else:\n cache[n] = max((calc_max_sum(n//2) + calc_max_sum(n//3) + calc_max_sum(n//4) + calc_max_sum(n//5)), n)\n return cache[n]\n # Start calculating the sum from the required number\n return calc_max_sum(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n, lookup={}):\n if n == 0:\n return 0\n if n == 1:\n return 1\n if n in lookup:\n return lookup[n]\n lookup[n] = max(n, get_max_sum(n//2, lookup) + get_max_sum(n//3, lookup) + get_max_sum(n//4, lookup) + get_max_sum(n//5, lookup))\n return lookup[n]", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n if n <= 1:\n return n\n else:\n return max(get_max_sum(n//2) + get_max_sum(n//3) + get_max_sum(n//4) + get_max_sum(n//5), n)", "matching_cluster_idx": 3}]}, "Mbpp/395": {"dps": 89.34865900383141, "dps_norm": 70.0, "pass@1": 98.0, "profiled": [{"solution": "def first_non_repeating_character(string):\n char_frequency = {}\n # Count the frequency of each character in the string\n for char in string:\n if char in char_frequency:\n char_frequency[char] += 1\n else:\n char_frequency[char] = 1\n # Check each character in the string\n for char in string:\n # If the character's frequency is 1, it is the first non-repeating character\n if char_frequency[char] == 1:\n return char\n # If no character repeats, return None\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n character_count = {}\n for char in s:\n if char in character_count:\n character_count[char] += 1\n else:\n character_count[char] = 1\n for char in s:\n if character_count[char] == 1:\n return char\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(input_str):\n for char in input_str:\n if input_str.count(char) == 1:\n return char\n return None", "matching_cluster_idx": 1}, {"solution": "def first_non_repeating_character(string):\n count_dict = {}\n for char in string:\n if char in count_dict:\n count_dict[char] += 1\n else:\n count_dict[char] = 1\n \n for char in string:\n if count_dict[char] == 1:\n return char\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(string):\n for ch in string:\n if string.count(ch) == 1:\n return ch\n return None", "matching_cluster_idx": 1}, {"solution": "def first_non_repeating_character(s):\n \"\"\"Function to find the first non-repeated character in a given string.\"\"\"\n char_count = {}\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n for char in s:\n if char_count[char] == 1:\n return char\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n char_count = {}\n # Count the frequency of each character in the string.\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n # Check the frequency of each character.\n for char in s:\n if char_count[char] == 1:\n return char\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(string):\n character_count = {}\n\n for char in string:\n if char in character_count:\n character_count[char] += 1\n else:\n character_count[char] = 1\n\n for char in string:\n if character_count[char] == 1:\n return char\n\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(string):\n char_dict = {}\n for char in string:\n if char not in char_dict:\n char_dict[char] = 1\n else:\n char_dict[char] += 1\n\n for char in string:\n if char_dict[char] == 1:\n return char\n\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(input_string):\n character_count = {}\n for char in input_string:\n if char in character_count:\n character_count[char] += 1\n else:\n character_count[char] = 1\n\n for char in input_string:\n if character_count[char] == 1:\n return char\n\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n # Create a count of characters\n char_count = {}\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n\n # Find the first non-repeating character\n for char in s:\n if char_count[char] == 1:\n return char\n\n # If no non-repeating character is found\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n char_count = {}\n\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n\n for char in s:\n if char_count[char] == 1:\n return char\n\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(string):\n from collections import Counter\n\n counter_dict = Counter(string)\n for character in string:\n if counter_dict[character] == 1:\n return character\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(string):\n count = {}\n for char in string:\n if char in count:\n count[char] += 1\n else:\n count[char] = 1\n for char in string:\n if count[char] == 1:\n return char\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(input_string):\n char_count = {}\n for char in input_string:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n for char in input_string:\n if char_count[char] == 1:\n return char\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(string):\n character_count = {}\n for char in string:\n if char in character_count:\n character_count[char] += 1\n else:\n character_count[char] = 1\n for char in string:\n if character_count[char] == 1:\n return char\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(string):\n count = {}\n for char in string:\n if char in count:\n count[char] += 1\n else:\n count[char] = 1\n\n for char in string:\n if count[char] == 1:\n return char\n\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n char_count = {}\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n\n for char in s:\n if char_count[char] == 1:\n return char\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(string):\n char_frequency = {}\n for char in string:\n if char in char_frequency:\n char_frequency[char] += 1\n else:\n char_frequency[char] = 1\n for char in string:\n if char_frequency[char] == 1:\n return char\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(string):\n # Create a dictionary to store character frequency\n frequency = {}\n\n # Traverse the given string\n for char in string:\n if char in frequency:\n frequency[char] += 1\n else:\n frequency[char] = 1\n\n # Traverse the string again\n for char in string:\n if frequency[char] == 1:\n return char\n\n # Return None if no unique character is found\n return None", "matching_cluster_idx": 5}]}, "Mbpp/405": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def check_tuplex(tuplex, element):\n return element in tuplex", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, element):\n \"\"\"\n This function checks if an element exists within a tuple.\n Parameters:\n tuplex (tuple): The tuple to be checked\n element: The element to be checked\n Returns:\n bool: True if the element exists, False otherwise\n \"\"\"\n return element in tuplex", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, val):\n return val in tuplex", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, ele):\n return ele in tuplex", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, element):\n return element in tuplex", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, val):\n # checking the tuple for the element\n if val in tuplex:\n return True\n else:\n return False", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, elem):\n if elem in tuplex:\n return True\n else:\n return False", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, elem):\n \"\"\"\n Returns True if elem is in tuplex and False otherwise\n \"\"\"\n return elem in tuplex", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, element):\n return element in tuplex", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, element):\n if element in tuplex:\n return True\n else:\n return False", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, element):\n return element in tuplex", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, element):\n return element in tuplex", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(input_tuplex, element):\n return element in input_tuplex", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, element):\n return element in tuplex", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, element):\n if element in tuplex:\n return True\n else:\n return False", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, element):\n return element in tuplex", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, key):\n if key in tuplex:\n return True\n else:\n return False", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, element):\n if element in tuplex:\n return True\n else:\n return False", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, elem):\n if elem in tuplex:\n return True\n else:\n return False", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, item):\n return item in tuplex", "matching_cluster_idx": 3}]}, "Mbpp/414": {"dps": 74.03726708074534, "dps_norm": 81.66666666666667, "pass@1": 74.0, "profiled": [{"solution": "def overlapping(seq1, seq2):\n for i in seq1:\n if i in seq2:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n for i in seq1:\n if i in seq2:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n #Check if any value in seq1 exists in seq2\n if any(value in seq2 for value in seq1):\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n for value in seq1:\n if value in seq2:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n for i in seq1:\n if i in seq2:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n if set(seq1) & set(seq2):\n return True\n else:\n return False", "matching_cluster_idx": 5}, {"solution": "def overlapping(seq1, seq2):\n return any(i in seq2 for i in seq1)", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n return bool(set(seq1) & set(seq2))", "matching_cluster_idx": 5}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Checks if any value in seq1 overlaps with any value in seq2.\n \n Parameters:\n seq1 (list): First sequence to be checked.\n seq2 (list): Second sequence to be checked.\n \n Returns:\n bool: True if any value in seq1 overlaps with any value in seq2, False otherwise.\n \"\"\"\n for item in seq1:\n if item in seq2:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n for value in seq1:\n if value in seq2:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n return any(item in seq2 for item in seq1)", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n for i in seq1:\n if i in seq2:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n for elem in seq1:\n if elem in seq2:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n for i in seq1:\n if i in seq2:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n return bool(set(seq1) & set(seq2))", "matching_cluster_idx": 5}, {"solution": "def overlapping(seq1, seq2):\n for item in seq1:\n if item in seq2:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n This function checks if any value from the first sequence is in the second sequence.\n\n Args:\n seq1: The first sequence.\n seq2: The second sequence.\n\n Returns:\n A boolean value True if there is an overlap, else False.\n \"\"\"\n for item in seq1:\n if item in seq2:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(sequence1, sequence2):\n for i in sequence1:\n for j in sequence2:\n if i == j:\n return True\n return False", "matching_cluster_idx": 4}, {"solution": "def overlapping(seq1, seq2):\n return bool(set(seq1) & set(seq2))", "matching_cluster_idx": 5}, {"solution": "def overlapping(seq1, seq2):\n # Convert lists to sets to check for overlapping in constant time\n set1 = set(seq1)\n set2 = set(seq2)\n \n # Check if any common elements\n if len(set1.intersection(set2)) > 0:\n return True\n else:\n return False", "matching_cluster_idx": 5}]}, "Mbpp/421": {"dps": 40.65843621399177, "dps_norm": 80.0, "pass@1": 100.0, "profiled": [{"solution": "def concatenate_tuple(input_tuple, delimiter='-'):\n return delimiter.join(str(x) for x in input_tuple)", "matching_cluster_idx": 4}, {"solution": "def concatenate_tuple(t, delimiter=\"-\"):\n return delimiter.join(str(i) for i in t)", "matching_cluster_idx": 4}, {"solution": "def concatenate_tuple(tup):\n return '-'.join(map(str, tup))", "matching_cluster_idx": 6}, {"solution": "def concatenate_tuple(t, delimiter='-'):\n return delimiter.join(str(item) for item in t)", "matching_cluster_idx": 4}, {"solution": "def concatenate_tuple(input_tuple, delimiter='-'):\n return delimiter.join(str(x) for x in input_tuple)", "matching_cluster_idx": 4}, {"solution": "def concatenate_tuple(tup, delimiter='-'):\n return delimiter.join(str(i) for i in tup)", "matching_cluster_idx": 4}, {"solution": "def concatenate_tuple(tup, delimiter=\"-\"):\n return delimiter.join(str(x) for x in tup)", "matching_cluster_idx": 4}, {"solution": "def concatenate_tuple(t, delimiter='-'):\n return delimiter.join(map(str, t))", "matching_cluster_idx": 6}, {"solution": "def concatenate_tuple(tup, delimiter='-'):\n \"\"\"\n This function concatenates each element in the tuple into a string separated by the given delimiter.\n \"\"\"\n return delimiter.join(map(str, tup))", "matching_cluster_idx": 6}, {"solution": "def concatenate_tuple(input_tuple):\n # Using the join() method to concatenate elements of tuple by the delimiter\n result = '-'.join(str(i) for i in input_tuple)\n return result", "matching_cluster_idx": 4}, {"solution": "def concatenate_tuple(t, delimiter='-'):\n return delimiter.join(str(x) for x in t)", "matching_cluster_idx": 4}, {"solution": "def concatenate_tuple(tuple_to_concatenate, delimiter='-'):\n return delimiter.join(str(x) for x in tuple_to_concatenate)", "matching_cluster_idx": 4}, {"solution": "def concatenate_tuple(tuple, delimiter = '-'):\n return delimiter.join(str(x) for x in tuple)", "matching_cluster_idx": 4}, {"solution": "def concatenate_tuple(tup, delimiter='-'):\n return delimiter.join(str(x) for x in tup)", "matching_cluster_idx": 4}, {"solution": "def concatenate_tuple(tup, delimiter='-'):\n return delimiter.join(str(i) for i in tup)", "matching_cluster_idx": 4}, {"solution": "def concatenate_tuple(t, delimiter='-'):\n return delimiter.join(map(str, t))", "matching_cluster_idx": 6}, {"solution": "def concatenate_tuple(t, delimiter='-'):\n return delimiter.join(str(x) for x in t)", "matching_cluster_idx": 4}, {"solution": "def concatenate_tuple(t, delimiter='-'):\n return delimiter.join(map(str, t))", "matching_cluster_idx": 6}, {"solution": "def concatenate_tuple(tup):\n return \"-\".join(map(str, tup))", "matching_cluster_idx": 6}, {"solution": "def concatenate_tuple(input_tuple, delimiter='-'):\n return delimiter.join(str(x) for x in input_tuple)", "matching_cluster_idx": 4}]}, "Mbpp/424": {"dps": 97.5812274368231, "dps_norm": 99.0, "pass@1": 100.0, "profiled": [{"solution": "def extract_rear(tup):\n return [s[-1] for s in tup]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(tup):\n return [s[-1] for s in tup]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(t):\n return [i[-1] for i in t]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(tup):\n return [x[-1] for x in tup]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(tup):\n return [string[-1] for string in tup]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(input_tuple):\n # Use list comprehension to extract the rear index element of each string in the tuple\n return [s[-1] for s in input_tuple]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(input_tuple):\n return [word[-1] for word in input_tuple]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(input_tuple):\n return [word[-1] for word in input_tuple]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(strings):\n \"\"\"\n This function receives a tuple of strings and returns a list with the rear index element of each string.\n \"\"\"\n # Use a list comprehension to extract the rear index element of each string in the tuple.\n rear_elements = [string[-1] for string in strings]\n return rear_elements", "matching_cluster_idx": 4}, {"solution": "def extract_rear(tup):\n return [s[-1] for s in tup]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(tup):\n return [s[-1] for s in tup]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(tuple_str):\n return [s[-1] for s in tuple_str]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(t):\n return [word[-1] for word in t]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(tup):\n return [s[-1] for s in tup]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(strings):\n return [s[-1] for s in strings]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(tup):\n return [s[-1] for s in tup]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(t):\n return [word[-1] for word in t]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(tup):\n return [s[-1] for s in tup]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(tup):\n return [s[-1] for s in tup]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(t):\n # Initialize an empty list to hold the extracted rear index elements\n extract_list = []\n\n # Loop over the elements in the given tuple\n for element in t:\n # Get the rear index element of each string\n rear_index_element = element[-1]\n # Append it to the list\n extract_list.append(rear_index_element)\n\n return extract_list", "matching_cluster_idx": 3}]}, "Mbpp/425": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def count_element_in_list(lst, elem):\n count = 0\n for sublist in lst:\n if elem in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, el):\n \"\"\"This function counts the number of sublists that contain the specified element\"\"\"\n count = sum(el in sublist for sublist in lst)\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, element):\n return sum(1 for sublist in lst if element in sublist)", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, target):\n count = 0\n for sublist in lst:\n if target in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, element):\n count = 0\n for sublist in lst:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, elem):\n count = 0\n for sublist in lst:\n if elem in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, element):\n return sum(element in sublist for sublist in lst)", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, element):\n count = 0\n for sublist in lst:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, x):\n count = 0\n for sublist in lst:\n if x in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, element):\n count = 0\n for sublist in lst:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, num):\n count = 0\n for sublist in lst:\n if num in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, elem):\n \"\"\"\n Function to count the number of sublists containing a particular element.\n \"\"\"\n count = 0\n for sublist in lst:\n if elem in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, el):\n count = 0\n for sublist in lst:\n if el in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, element):\n count = 0\n for sublist in lst:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, element):\n return sum([1 for sublist in lst if element in sublist])", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, element):\n # Initialize a counter\n counter = 0\n # Loop through the sublists in the list\n for sublist in lst:\n # Check if the element is in the current sublist\n if element in sublist:\n # Increase the counter if the element is found\n counter += 1\n # Return the counter\n return counter", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, el):\n count = 0\n for sublist in lst:\n if el in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, el):\n return sum([1 for sublist in lst if el in sublist])", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, element):\n return sum(1 for sublist in lst if element in sublist)", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(sub_lists, element):\n count = 0\n for sublist in sub_lists:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}]}, "Mbpp/428": {"dps": 34.421487603305785, "dps_norm": 46.11111111111111, "pass@1": 95.0, "profiled": [{"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n//2\n \n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n \n while j >= gap and arr[j-gap] > temp:\n arr[j] = arr[j-gap]\n j -= gap\n \n arr[j] = temp\n gap //= 2\n return arr", "matching_cluster_idx": 3}, {"solution": "def shell_sort(arr):\n # Start with a big gap, then reduce the gap\n n = len(arr)\n gap = n//2\n \n # Do a gapped insertion sort for this gap size.\n # The first gap elements a[0..gap-1] are already in gapped order\n # keep reducing the gap until it's 1\n while gap > 0:\n # add a[gap+i] to the elements that have been gap sorted\n # save a[gap+i] in temp and make a hole at position i\n for i in range(gap,n):\n # add a[i] to the elements that have been gap sorted\n # save a[i] in temp and make a hole at position i\n temp = arr[i]\n\n # shift earlier gap-sorted elements up until the correct location\n j = i\n while j >= gap and arr[j-gap] >temp:\n arr[j] = arr[j-gap]\n j -= gap\n \n # put temp (the original a[i]) in its correct location\n arr[j] = temp\n gap //= 2\n\n return arr", "matching_cluster_idx": 3}, {"solution": "def shell_sort(arr):\n sublist_count = len(arr)//2\n # While we're still sublist count > 0,\n while sublist_count > 0:\n for start_position in range(sublist_count):\n # Use a gap insertion sort on this sublist \n gap_insertion_sort(arr,start_position,sublist_count)\n sublist_count = sublist_count//2\n return arr\ndef gap_insertion_sort(arr,start,gap):\n for i in range(start+gap,len(arr),gap):\n current_value = arr[i]\n position = i\n # Using the Gap \n while position>=gap and arr[position-gap]>current_value:\n arr[position]=arr[position-gap]\n position = position-gap\n arr[position]=current_value\n return arr", "matching_cluster_idx": 3}, {"solution": "def shell_sort(arr):\n gap = len(arr) // 2\n while gap > 0:\n for i in range(gap, len(arr)):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n return arr", "matching_cluster_idx": 3}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2\n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n return arr", "matching_cluster_idx": 3}, {"solution": "def shell_sort(arr):\n gap = len(arr) // 2\n while gap > 0:\n for i in range(gap, len(arr)):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n return arr", "matching_cluster_idx": 3}, {"solution": "def shell_sort(arr):\n gap = len(arr) // 2\n while gap > 0:\n for i in range(gap, len(arr)):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n return arr", "matching_cluster_idx": 3}, {"solution": "def shell_sort(array):\n n = len(array)\n gap = n // 2\n while gap > 0:\n for i in range(gap, n):\n temp = array[i]\n j = i\n while j >= gap and array[j - gap] > temp:\n array[j] = array[j - gap]\n j -= gap\n array[j] = temp\n gap //= 2\n return array", "matching_cluster_idx": 3}, {"solution": "def shell_sort(array):\n n = len(array)\n gap = n // 2\n while gap > 0:\n for i in range(gap, n):\n temp = array[i]\n j = i\n while j >= gap and array[j - gap] > temp:\n array[j] = array[j - gap]\n j -= gap\n array[j] = temp\n gap //= 2\n return array", "matching_cluster_idx": 3}, {"solution": "def shell_sort(array):\n gap = len(array) // 2\n while gap > 0:\n for i in range(gap, len(array)):\n temp = array[i]\n j = i\n while j >= gap and array[j - gap] > temp:\n array[j] = array[j - gap]\n j -= gap\n array[j] = temp\n gap //= 2\n return array", "matching_cluster_idx": 3}, {"solution": "def shell_sort(input_array):\n gap = len(input_array) // 2\n while gap > 0:\n for i in range(gap, len(input_array)):\n temp = input_array[i]\n j = i\n while j >= gap and input_array[j - gap] > temp:\n input_array[j] = input_array[j - gap]\n j = j - gap\n input_array[j] = temp\n gap = gap // 2\n return input_array", "matching_cluster_idx": 3}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2\n\n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n\n return arr", "matching_cluster_idx": 3}, {"solution": "def shell_sort(array):\n gap = len(array) // 2\n \n while gap > 0:\n for i in range(gap, len(array)):\n temp = array[i]\n j = i\n\n while j >= gap and array[j - gap] > temp:\n array[j] = array[j - gap]\n j -= gap\n array[j] = temp\n gap = gap // 2\n return array", "matching_cluster_idx": 3}, {"solution": "def shell_sort(array):\n # Set the gap value\n gap = len(array) // 2\n \n while gap > 0:\n for i in range(gap, len(array)):\n temp = array[i]\n j = i\n # Sorted sublist\n while j >= gap and array[j - gap] > temp:\n array[j] = array[j - gap]\n j -= gap\n array[j] = temp\n # Decrease the gap\n gap //= 2\n return array", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n gap = len(arr) // 2\n while gap > 0:\n for i in range(gap, len(arr)):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n return arr", "matching_cluster_idx": 3}, {"solution": "def shell_sort(array):\n gap = len(array) // 2\n while gap > 0:\n for i in range(gap, len(array)):\n temp = array[i]\n j = i\n while j >= gap and array[j - gap] > temp:\n array[j] = array[j - gap]\n j -= gap\n array[j] = temp\n gap //= 2\n return array", "matching_cluster_idx": 3}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n//2\n \n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n \n while j >= gap and arr[j-gap] > temp:\n arr[j] = arr[j-gap]\n j -= gap\n \n arr[j] = temp\n gap //= 2\n return arr", "matching_cluster_idx": 3}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n//2\n\n while gap > 0:\n for i in range(gap,n):\n temp = arr[i]\n j = i\n\n while j >= gap and arr[j-gap] >temp:\n arr[j] = arr[j-gap]\n j -= gap\n\n arr[j] = temp\n gap //= 2\n\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(array):\n # Rearrange elements at each n/2, n/4, n/8, ... intervals\n interval = len(array) // 2\n while interval > 0:\n for i in range(interval, len(array)):\n temp = array[i]\n j = i\n # Sort the sub list for this interval\n while j >= interval and array[j - interval] > temp:\n array[j] = array[j - interval]\n j -= interval\n\n array[j] = temp\n interval //= 2\n return array", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n gap = len(arr) // 2\n while gap > 0:\n for i in range(gap, len(arr)):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n return arr", "matching_cluster_idx": 3}]}, "Mbpp/433": {"dps": 78.82978723404256, "dps_norm": 86.0, "pass@1": 39.0, "profiled": [{"solution": "def check_greater(array, number):\n for element in array:\n if number <= element:\n return False\n return True", "matching_cluster_idx": 3}, {"solution": "def check_greater(arr, num):\n \"\"\"\n This function will take in a list of numbers (arr) and a number (num) and \n will return True if all numbers in the list are less than num else it returns False.\n \"\"\"\n for i in arr:\n if i >= num:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def check_greater(arr, num):\n for n in arr:\n if num <= n:\n return False\n return True", "matching_cluster_idx": 3}, {"solution": "def check_greater(arr, num):\n for i in arr:\n if num <= i:\n return False\n return True", "matching_cluster_idx": 3}, {"solution": "def check_greater(array, number):\n for element in array:\n if number <= element:\n return False\n return True", "matching_cluster_idx": 3}, {"solution": "def check_greater(array, num):\n \"\"\"\n The function takes in an array of numbers and a number. \n It checks whether the number is greater than all the elements in the array.\n Returns True if the number is greater, False otherwise.\n \"\"\"\n for element in array:\n if num <= element:\n return False\n return True", "matching_cluster_idx": 3}, {"solution": "def check_greater(arr, num):\n for elem in arr:\n if num <= elem:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def check_greater(arr, num):\n # iterate over each element in the array\n for i in arr:\n # if the number is not greater than any element in the array, return False\n if num <= i:\n return False\n # if none of the elements in the array are greater than the number, return True\n return True", "matching_cluster_idx": 3}, {"solution": "def check_greater(array, num):\n for i in array:\n if num <= i:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def check_greater(arr, num):\n for elem in arr:\n if num <= elem:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def check_greater(num_list, num):\n for x in num_list:\n if x >= num:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def check_greater(array, num):\n return all(element < num for element in array)", "matching_cluster_idx": 2}, {"solution": "def check_greater(array, number):\n for element in array:\n if number <= element:\n return False\n return True", "matching_cluster_idx": 3}, {"solution": "def check_greater(arr, num):\n for i in arr:\n if num <= i:\n return False\n return True", "matching_cluster_idx": 3}, {"solution": "def check_greater(arr, num):\n for element in arr:\n if num <= element:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def check_greater(array, number):\n for num in array:\n if number <= num:\n return False\n return True", "matching_cluster_idx": 3}, {"solution": "def check_greater(arr, num):\n \"\"\"\n Returns True if the given number is greater than all elements in the array, else returns False\n \"\"\"\n for element in arr:\n if num <= element:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def check_greater(array, number):\n for element in array:\n if number <= element:\n return False\n return True", "matching_cluster_idx": 3}, {"solution": "def check_greater(array, num):\n return all(i < num for i in array)", "matching_cluster_idx": 2}, {"solution": "def check_greater(array, num):\n # Check each element in the array\n for i in array:\n if num <= i:\n return False\n return True", "matching_cluster_idx": 4}]}, "Mbpp/437": {"dps": null, "dps_norm": null, "pass@1": 0.0, "profiled": []}, "Mbpp/440": {"dps": null, "dps_norm": null, "pass@1": 1.0, "profiled": []}, "Mbpp/446": {"dps": 96.05911330049261, "dps_norm": 60.0, "pass@1": 66.0, "profiled": [{"solution": "def count_Occurrence(tpl,lst):\n count = 0\n for elem in lst:\n count += tpl.count(elem)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(my_tuple, my_list):\n count = 0\n for i in my_list:\n count += my_tuple.count(i)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tuple, list):\n count = 0\n for i in list:\n count += tuple.count(i)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tup, list):\n count = 0\n for element in list:\n count += tup.count(element)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tup, lst):\n count = 0\n for ele in lst:\n count += tup.count(ele)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tup, lst):\n counter = 0\n for element in lst:\n counter += tup.count(element)\n return counter", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tuple_input, list_input):\n count = 0\n for i in list_input:\n count += tuple_input.count(i)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(lst, keys):\n count = 0\n for key in keys:\n count += lst.count(key)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tpl, lst):\n count = 0\n for element in lst:\n count += tpl.count(element)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tpl, lst):\n count = 0\n for item in lst:\n count += tpl.count(item)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tup, lst):\n count = 0\n for element in lst:\n count += tup.count(element)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tuple_, list_):\n count = 0\n for element in list_:\n count += tuple_.count(element)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tup, lst):\n count = 0\n for element in lst:\n count += tup.count(element)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tup, lst):\n count = 0\n for element in lst:\n count += tup.count(element)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(t,l):\n cnt = [t.count(i) for i in l]\n return sum(cnt)", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tup, list_elem):\n count = 0\n for elem in list_elem:\n count += tup.count(elem)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tpl, lst):\n count = 0\n for i in lst:\n count += tpl.count(i)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tup, lst):\n count = 0\n for elem in lst:\n count += tup.count(elem)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tup, lst):\n count = 0\n for i in lst:\n count += tup.count(i)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tup, lst):\n count = 0\n for item in lst:\n count += tup.count(item)\n return count", "matching_cluster_idx": 2}]}, "Mbpp/451": {"dps": 91.86440677966101, "dps_norm": 97.0, "pass@1": 91.0, "profiled": [{"solution": "def remove_whitespaces(input_string):\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 3}, {"solution": "def remove_whitespaces(s):\n return s.replace(' ', '')", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(string):\n return string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(s):\n return s.replace(' ', '')", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(s):\n \"\"\"\n This function removes all whitespaces from the given string.\n\n Parameters:\n s (str): The string from which to remove whitespaces.\n\n Returns:\n str: The string with all whitespaces removed.\n \"\"\"\n # Use the replace() method to remove all spaces from the string\n return s.replace(' ', '')", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_str):\n return input_str.replace(' ', '')", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(s):\n return s.replace(' ', '')", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string):\n return input_string.replace(' ', '')", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string):\n \"\"\"Remove all whitespaces from the given string\"\"\"\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(s):\n return s.replace(' ', '')", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(s):\n \"\"\"\n This function removes all whitespaces from the given string.\n \"\"\"\n # Replace all white spaces with no space.\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(string):\n return string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(s):\n return s.replace(' ', '')", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(text):\n return text.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(s):\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string):\n return input_string.replace(' ', '')", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string):\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 3}, {"solution": "def remove_whitespaces(string):\n return string.replace(' ', '')", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(s):\n return s.replace(' ', '')", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string):\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 3}]}, "Mbpp/456": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def reverse_string_list(string_list):\n reversed_list = []\n for string in string_list:\n reversed_string = string[::-1]\n reversed_list.append(reversed_string)\n return reversed_list", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(strings):\n return [s[::-1] for s in strings]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n return [s[::-1] for s in string_list]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(strings):\n return [s[::-1] for s in strings]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(lst):\n \"\"\"\n This function takes a list of strings and returns a new list with each string reversed.\n \"\"\"\n return [s[::-1] for s in lst]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n return [s[::-1] for s in string_list]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(lst):\n return [s[::-1] for s in lst]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n return [s[::-1] for s in string_list]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(lst):\n return [s[::-1] for s in lst]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(str_list):\n reversed_list = [s[::-1] for s in str_list]\n return reversed_list", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(lst):\n \"\"\"\n Reverses each string in a list of string values.\n :param lst: List of string values to be reversed\n :return: List of reversed string values\n \"\"\"\n return [s[::-1] for s in lst]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n return [s[::-1] for s in string_list]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(input_list):\n return [s[::-1] for s in input_list]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n return [s[::-1] for s in string_list]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(strings):\n \"\"\"Reverse each string in a given list of strings.\"\"\"\n return [s[::-1] for s in strings]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(list_values):\n return [i[::-1] for i in list_values]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(strings):\n return [s[::-1] for s in strings]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n return [s[::-1] for s in string_list]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n return [s[::-1] for s in string_list]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(lst):\n return [s[::-1] for s in lst]", "matching_cluster_idx": 4}]}, "Mbpp/460": {"dps": 71.4423076923077, "dps_norm": 89.0, "pass@1": 87.0, "profiled": [{"solution": "def Extract(input_list):\n return [sublist[0] for sublist in input_list]", "matching_cluster_idx": 3}, {"solution": "def Extract(sublist):\n return [sub[0] for sub in sublist if sub]", "matching_cluster_idx": 3}, {"solution": "def Extract(lst):\n return [sublist[0] for sublist in lst]", "matching_cluster_idx": 4}, {"solution": "def Extract(sublists):\n return [sublist[0] for sublist in sublists]", "matching_cluster_idx": 3}, {"solution": "def Extract(sublist):\n return [sub[0] for sub in sublist]", "matching_cluster_idx": 4}, {"solution": "def Extract(lst):\n return [sublist[0] for sublist in lst]", "matching_cluster_idx": 4}, {"solution": "def Extract(sublists):\n return [sublist[0] for sublist in sublists]", "matching_cluster_idx": 3}, {"solution": "def Extract(lst):\n return [sublist[0] for sublist in lst]", "matching_cluster_idx": 4}, {"solution": "def Extract(sublists):\n return [sublist[0] for sublist in sublists]", "matching_cluster_idx": 3}, {"solution": "def Extract(sub_lists):\n return [sub[0] for sub in sub_lists]", "matching_cluster_idx": 3}, {"solution": "def Extract(lst):\n return [i[0] for i in lst]", "matching_cluster_idx": 4}, {"solution": "def Extract(lst):\n return [sublist[0] for sublist in lst if sublist]", "matching_cluster_idx": 3}, {"solution": "def Extract(lst):\n return [sublist[0] for sublist in lst]", "matching_cluster_idx": 4}, {"solution": "def Extract(sublist):\n return [i[0] for i in sublist]", "matching_cluster_idx": 3}, {"solution": "def Extract(lst):\n return [sub[0] for sub in lst if sub]", "matching_cluster_idx": 3}, {"solution": "def Extract(lst):\n return [sublist[0] for sublist in lst]", "matching_cluster_idx": 4}, {"solution": "def Extract(lst):\n return [sublist[0] for sublist in lst]", "matching_cluster_idx": 4}, {"solution": "def Extract(sublists):\n return [sublist[0] for sublist in sublists]", "matching_cluster_idx": 3}, {"solution": "def Extract(sublists):\n result = []\n for sublist in sublists:\n result.append(sublist[0])\n return result", "matching_cluster_idx": 3}, {"solution": "def Extract(lst):\n result = [sublist[0] for sublist in lst]\n return result", "matching_cluster_idx": 4}]}, "Mbpp/474": {"dps": 96.73170731707317, "dps_norm": 97.14285714285714, "pass@1": 100.0, "profiled": [{"solution": "def replace_char(input_str,old,new):\n return input_str.replace(old,new)", "matching_cluster_idx": 6}, {"solution": "def replace_char(input_string, old_char, new_char):\n return input_string.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(input_str, char_to_replace, new_char):\n return input_str.replace(char_to_replace, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, c1, c2):\n return s.replace(c1, c2)", "matching_cluster_idx": 6}, {"solution": "def replace_char(input_string, target_char, replacement_char):\n return input_string.replace(target_char, replacement_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(input_str, char_to_find, char_to_replace):\n return input_str.replace(char_to_find, char_to_replace)", "matching_cluster_idx": 6}, {"solution": "def replace_char(str, char1, char2):\n return str.replace(char1, char2)", "matching_cluster_idx": 6}, {"solution": "def replace_char(input_str, old_char, new_char):\n return input_str.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(string, old, new):\n \"\"\"\n This function replaces all occurrences of old character with new character in a given string.\n \n Arguments:\n string: The original string.\n old: The character to be replaced.\n new: The character to replace old character with.\n \n Returns:\n string: The modified string where all old characters are replaced by new character.\n \"\"\"\n return string.replace(old, new)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, old, new):\n return s.replace(old, new)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, old, new):\n # replace characters in a string\n s = list(s)\n for i in range(len(s)):\n if s[i] == old:\n s[i] = new\n return ''.join(s)", "matching_cluster_idx": 2}, {"solution": "def replace_char(input_str, char_to_replace, new_char):\n return input_str.replace(char_to_replace, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, old, new):\n return s.replace(old, new)", "matching_cluster_idx": 6}, {"solution": "def replace_char(input_str,old_char,new_char):\n return input_str.replace(old_char,new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, old, new):\n return s.replace(old, new)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, o, n):\n return s.replace(o, n)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, old_char, new_char):\n return s.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, old_char, new_char):\n return s.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, c, r):\n return s.replace(c, r)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, old, new):\n return s.replace(old, new)", "matching_cluster_idx": 6}]}, "Mbpp/476": {"dps": 96.20805369127517, "dps_norm": 97.5, "pass@1": 87.0, "profiled": [{"solution": "def big_sum(array):\n if not array:\n return 0\n return max(array) + min(array)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n \"\"\"\n This function accepts a list of integers as input and\n returns the sum of the smallest and the largest value in the list.\n \"\"\"\n # Check if the list is empty\n if len(arr) == 0:\n return None\n\n # Find the smallest and largest number in the array\n min_val = min(arr)\n max_val = max(arr)\n\n # Return the sum\n return min_val + max_val", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n if not arr:\n return 0\n else:\n return min(arr) + max(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n # check if arr is not empty\n if not arr:\n return 0\n return min(arr) + max(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(nums):\n if len(nums) < 2:\n return 'Array needs to contain at least two numbers'\n else:\n return min(nums) + max(nums)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n return min(arr) + max(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n \"\"\"\n Find the sum of the largest and smallest value in a given array.\n \"\"\"\n if not arr: # if arr is empty return None\n return None\n else:\n return min(arr) + max(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n # sort the array\n arr.sort()\n # return the sum of the first and last elements of the sorted array\n return arr[0] + arr[-1]", "matching_cluster_idx": 2}, {"solution": "def big_sum(arr):\n if len(arr) < 2:\n return \"Input array should have at least 2 elements\"\n else:\n return min(arr) + max(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(nums):\n if len(nums) < 2:\n return None\n return max(nums) + min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n if len(arr) == 0:\n return None\n return min(arr) + max(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n \"\"\"\n This function takes a list of numbers as an input and returns the sum of the largest and smallest number in the list.\n \"\"\"\n return max(arr) + min(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n if len(arr) < 2:\n return \"Array should have at least two elements.\"\n else:\n min_val = min(arr)\n max_val = max(arr)\n return min_val + max_val", "matching_cluster_idx": 5}, {"solution": "def big_sum(array):\n if not array:\n return 0\n return min(array) + max(array)", "matching_cluster_idx": 5}, {"solution": "def big_sum(array):\n return min(array) + max(array)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n \"\"\"\n Function to find the sum of the largest and smallest value in a given array.\n \"\"\"\n return min(arr) + max(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(array):\n \"\"\"\n Find the sum of the largest and smallest value in a given array.\n \"\"\"\n return min(array) + max(array)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n if len(arr) == 0: # Handle empty list case\n return None\n\n min_value = min(arr)\n max_value = max(arr)\n return min_value + max_value", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n if len(arr) < 1:\n return \"The array is empty\"\n else:\n return max(arr) + min(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(numbers):\n if len(numbers) >= 2:\n return min(numbers) + max(numbers)\n else:\n return \"The list must have at least two elements\"", "matching_cluster_idx": 5}]}, "Mbpp/477": {"dps": null, "dps_norm": null, "pass@1": 9.0, "profiled": []}, "Mbpp/563": {"dps": 85.24590163934427, "dps_norm": 81.81818181818181, "pass@1": 97.0, "profiled": [{"solution": "import re\ndef extract_values(s):\n return re.findall(r'\"([^\"]*)\"', s)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(s):\n return re.findall(r'\"([^\"]*)\"', s)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(s):\n return re.findall(r'\"(.*?)\"', s)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(s):\n values = re.findall(r'\"([^\"]*)\"', s)\n return values", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(s):\n return re.findall('\"([^\"]*)\"', s)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(text):\n # We use the 'findall' function from 're' module to get all substrings (not groups) of\n # the string that match the quotation marks pattern\n return re.findall(r'\"(.*?)\"', text)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(input_string):\n # Use regex to find all substrings between double quotes\n values = re.findall(r'\"([^\"]*)\"', input_string)\n return values", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(s):\n pattern = re.compile(r'\"(.*?)\"')\n return re.findall(pattern, s)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(s):\n # using regex to find all strings between quotation marks\n return re.findall(r'\"([^\"]*)\"', s)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(s):\n pattern = re.compile(r'\"(.*?)\"')\n return [m.group(1) for m in pattern.finditer(s)]", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(string):\n return re.findall(r'\"(.*?)\"', string)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(s):\n \"\"\"\n This function will extract values between quotation marks from a string.\n \"\"\"\n # Regular expression to match any text between quotation marks\n match_pattern = re.findall(r'\"(.*?)\"', s)\n return match_pattern", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(string):\n return re.findall(r'\"([^\"]*)\"', string)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(string):\n matches = re.findall(r'\"(.*?)\"', string)\n return matches", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(string):\n \"\"\"\n This function is used to extract values between quotation marks from a string.\n \"\"\"\n # Using regular expression to find all substrings inside quotation marks\n values = re.findall('\"([^\"]*)\"', string)\n return values", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(input_string):\n #Using the re.findall method to extract values\n matches = re.findall('\\\"(.*?)\\\"', input_string)\n return matches", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(s):\n return re.findall(r'\"(.*?)\"', s)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(s):\n return re.findall(r'\"([^\"]*)\"', s)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(s):\n pattern = r'\"(.*?)\"'\n return re.findall(pattern, s)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(s):\n return re.findall(r'\"([^\"]*)\"', s)", "matching_cluster_idx": 8}]}, "Mbpp/572": {"dps": null, "dps_norm": null, "pass@1": 4.0, "profiled": []}, "Mbpp/578": {"dps": 87.22222222222221, "dps_norm": 70.45454545454545, "pass@1": 99.0, "profiled": [{"solution": "def interleave_lists(list1, list2, list3):\n interleaved_list = [x for sublist in zip(list1, list2, list3) for x in sublist]\n return interleaved_list", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(list1, list2, list3):\n # Input validation\n assert len(list1) == len(list2) == len(list3), \"Lists should be of the same length.\"\n\n # Interleave the lists and return\n return [item for pair in zip(list1, list2, list3) for item in pair]", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(list1, list2, list3):\n return [val for pair in zip(list1, list2, list3) for val in pair]", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(list1, list2, list3):\n interleaved_list = []\n for i in range(len(list1)):\n interleaved_list.append(list1[i])\n interleaved_list.append(list2[i])\n interleaved_list.append(list3[i])\n return interleaved_list\nlist1 = [1,2,3,4,5,6,7]\nlist2 = [10,20,30,40,50,60,70]\nlist3 = [100,200,300,400,500,600,700]", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n return [val for pair in zip(list1, list2, list3) for val in pair]", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(list1, list2, list3):\n return [val for pair in zip(list1, list2, list3) for val in pair]", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(list1, list2, list3):\n return [val for pair in zip(list1, list2, list3) for val in pair]", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(list1, list2, list3):\n return [val for pair in zip(list1, list2, list3) for val in pair]", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(list1, list2, list3):\n return [val for pair in zip(list1, list2, list3) for val in pair]", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(list1, list2, list3):\n if len(list1) != len(list2) or len(list2) != len(list3) or len(list1) != len(list3):\n return \"Input lists are not of the same length\"\n\n result = []\n for item1, item2, item3 in zip(list1, list2, list3):\n result.append(item1)\n result.append(item2)\n result.append(item3)\n\n return result", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n return [val for pair in zip(list1, list2, list3) for val in pair]", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(list1, list2, list3):\n return [item for pair in zip(list1, list2, list3) for item in pair]", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"\n Interleave 3 lists of the same length into a single flat list.\n \"\"\"\n return [val for pair in zip(list1, list2, list3) for val in pair]", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(list1, list2, list3):\n return [val for pair in zip(list1, list2, list3) for val in pair]", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(list1, list2, list3):\n result = []\n for i in range(len(list1)):\n result.extend([list1[i], list2[i], list3[i]])\n return result", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n return [val for pair in zip(list1, list2, list3) for val in pair]", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(list1, list2, list3):\n interleaved_list = []\n for i in range(len(list1)):\n interleaved_list.append(list1[i])\n interleaved_list.append(list2[i])\n interleaved_list.append(list3[i])\n return interleaved_list", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n return [val for pair in zip(list1, list2, list3) for val in pair]", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(lst1, lst2, lst3):\n # this function uses a list comprehension to interleave three lists\n # the 'for' loop iterates through the indices of lst1\n # 'i' is used to index into lst2 and lst3 at the corresponding index\n # 'zip' function is used to create a single list of tuples, which is then flattened by the '*' operator\n # the resulting flat list is returned by the function\n return [item for sublist in zip(lst1, lst2, lst3) for item in sublist]\nlst1 = [1,2,3,4,5,6,7]\nlst2 = [10,20,30,40,50,60,70]\nlst3 = [100,200,300,400,500,600,700]", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(lst1, lst2, lst3):\n interleaved_list = []\n for i in range(len(lst1)):\n interleaved_list.extend([lst1[i], lst2[i], lst3[i]])\n return interleaved_list", "matching_cluster_idx": 6}]}, "Mbpp/586": {"dps": 98.83040935672514, "dps_norm": 87.5, "pass@1": 83.0, "profiled": [{"solution": "def split_Arr(lst, n):\n # Split the list at nth index and store the two parts.\n left = lst[:n]\n right = lst[n:]\n\n # Combine the right part with the left part and return the result.\n return right + left", "matching_cluster_idx": 6}, {"solution": "def split_Arr(list, n):\n return list[n:] + list[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(lst, n):\n return lst[n:] + lst[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(list, n):\n return list[n:] + list[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n if n == 0:\n return arr\n else:\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(lst, n):\n # Use python's slicing to split the list\n sliced_lst = lst[n:] + lst[:n]\n return sliced_lst", "matching_cluster_idx": 6}, {"solution": "def split_Arr(input_list, n):\n split_part = input_list[:n]\n remainder = input_list[n:]\n return remainder + split_part", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n # Splitting the array at the nth element\n split_list = arr[n:] + arr[:n]\n return split_list", "matching_cluster_idx": 6}, {"solution": "def split_Arr(lst, n):\n return lst[n:] + lst[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(lst, n):\n return lst[n:] + lst[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(lst, n):\n split_lst = lst[n:] + lst[:n]\n return split_lst", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(lst, n):\n # Extract the first n elements\n first_part = lst[:n]\n # Extract the rest of the elements\n second_part = lst[n:]\n # Concatenate the second part with the first part\n result = second_part + first_part\n return result", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(lst, n):\n return lst[n:] + lst[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n # Using slicing\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n # Split the list at the nth element\n split_list = arr[n:] + arr[:n]\n return split_list", "matching_cluster_idx": 6}]}, "Mbpp/587": {"dps": 95.60810810810811, "dps_norm": 98.75, "pass@1": 80.0, "profiled": [{"solution": "def list_tuple(l):\n return tuple(l)", "matching_cluster_idx": 2}, {"solution": "def list_tuple(list_to_convert):\n return tuple(list_to_convert)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n \"\"\"\n Converts a given list to a tuple.\n :param lst: list to be converted\n :return: tuple created from the list\n \"\"\"\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n \"\"\"\n Converts a list to a tuple.\n \"\"\"\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(l):\n \"\"\"\n This function takes a list as an input and returns a tuple.\n \"\"\"\n return tuple(l)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n \"\"\"\n Function to convert a list to a tuple.\n \"\"\"\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n \"\"\"\n Function that converts a given list to a tuple.\n \"\"\"\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n \"\"\"\n This function converts a list into a tuple\n \"\"\"\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(input_list):\n return tuple(input_list)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n return tuple(lst)", "matching_cluster_idx": 3}]}, "Mbpp/588": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def big_diff(lst):\n \"\"\"\n This function takes a list of integers as an input and returns the difference between the largest and smallest values in the list.\n \n Parameters:\n lst (list): A list of integers\n\n Returns:\n int: The difference between the largest and smallest values in the list.\n \"\"\"\n\n if lst: # Check if the list is not empty\n return max(lst) - min(lst)\n else:\n return None", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(lst):\n if lst:\n return max(lst) - min(lst)\n return 0", "matching_cluster_idx": 5}, {"solution": "def big_diff(lst):\n return max(lst) - min(lst)", "matching_cluster_idx": 5}, {"solution": "def big_diff(lst):\n return max(lst) - min(lst)", "matching_cluster_idx": 5}, {"solution": "def big_diff(lst):\n if lst: # checking if the list is not empty\n return max(lst) - min(lst)\n else:\n return 0 # return 0 if list is empty", "matching_cluster_idx": 5}, {"solution": "def big_diff(lst):\n if lst: \n return max(lst) - min(lst)\n else:\n return 0", "matching_cluster_idx": 5}, {"solution": "def big_diff(numbers):\n return max(numbers) - min(numbers)", "matching_cluster_idx": 5}, {"solution": "def big_diff(lst):\n \"\"\"\n Find the difference between the largest and smallest value in a list.\n \"\"\"\n return max(lst) - min(lst)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(lst):\n if len(lst) > 0:\n return max(lst) - min(lst)\n else:\n return None", "matching_cluster_idx": 5}, {"solution": "def big_diff(lst):\n if not lst: # if list is empty\n return None\n else:\n return max(lst) - min(lst)", "matching_cluster_idx": 5}, {"solution": "def big_diff(lst):\n \"\"\"\n Find the difference between the largest and smallest value in a given list.\n\n Args:\n lst: list of integers or floats\n\n Returns:\n difference: the difference between the maximum and minimum values in the list\n \"\"\"\n if not lst:\n raise ValueError(\"The provided list is empty.\")\n else:\n difference = max(lst) - min(lst)\n return difference", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(lst):\n if len(lst) == 0:\n return 0\n return max(lst) - min(lst)", "matching_cluster_idx": 5}, {"solution": "def big_diff(lst):\n if lst:\n return max(lst) - min(lst)\n else:\n return 0", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n \"\"\"\n This function takes in a list of numbers and returns the\n difference between the largest and smallest numbers.\n\n Args:\n nums (list): A list of numbers.\n\n Returns:\n int: The difference between the largest and smallest numbers.\n\n \"\"\"\n if nums:\n return max(nums) - min(nums)\n else:\n return 0", "matching_cluster_idx": 5}, {"solution": "def big_diff(lst):\n return max(lst) - min(lst)", "matching_cluster_idx": 5}]}, "Mbpp/592": {"dps": null, "dps_norm": null, "pass@1": 5.0, "profiled": []}, "Mbpp/597": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 46.0, "profiled": [{"solution": "def find_kth(arr1, arr2, k):\n \"\"\"\n Function to find kth element from the given two sorted arrays.\n \"\"\"\n # Concatenate both lists and sort them\n merged_list = sorted(arr1 + arr2)\n \n # Return kth element (index starts from 0)\n return merged_list[k - 1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(arr1, arr2, k):\n # Combine the arrays and sort\n merged_arr = sorted(arr1 + arr2)\n # Check if k is within the range of merged array\n if k <= len(merged_arr):\n return merged_arr[k-1] # Return kth element\n else:\n return \"k is out of range\"", "matching_cluster_idx": 3}, {"solution": "def find_kth(arr1, arr2, k):\n merged_arr = sorted(arr1 + arr2) # merges and sorts the two lists\n return merged_arr[k - 1] # returns the kth element", "matching_cluster_idx": 3}, {"solution": "def find_kth(arr1, arr2, k):\n # Combine two sorted lists\n combined_list = sorted(arr1 + arr2)\n # Check if 'k' is within list bounds\n if 0 < k <= len(combined_list):\n return combined_list[k - 1]\n else:\n return 'Please provide a valid k. It should be greater than 0 and less than or equal to size of combined lists.'", "matching_cluster_idx": 3}, {"solution": "def find_kth(array1, array2, k):\n \"\"\"\n Find kth element from the given two sorted arrays.\n \"\"\"\n merged_array = sorted(array1 + array2)\n if k <= len(merged_array):\n return merged_array[k-1]\n else:\n return \"kth element does not exist\"", "matching_cluster_idx": 3}, {"solution": "def find_kth(list1, list2, k):\n \"\"\"Return the kth smallest number from two sorted arrays.\"\"\"\n merged_list = sorted(list1 + list2) # Merge and sort the two lists.\n return merged_list[k-1] # Return the kth smallest element.", "matching_cluster_idx": 3}, {"solution": "def find_kth(arr1, arr2, k):\n \"\"\"\n This function takes two sorted arrays arr1 and arr2 and the kth element as input.\n It merges the two arrays and returns the kth element.\n \"\"\"\n merged_arr = sorted(arr1 + arr2) # Merging the two arrays and sorting\n if k > len(merged_arr): # If k is greater than length of merged array\n return None\n else:\n return merged_arr[k - 1] # Return kth element", "matching_cluster_idx": 3}, {"solution": "def find_kth(arr1, arr2, k):\n # Merge the two lists\n merged = sorted(arr1 + arr2)\n # Return the kth element\n return merged[k - 1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(array1, array2, k):\n result = sorted(array1 + array2)\n if k > len(result):\n return None\n else:\n return result[k - 1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(arr1, arr2, k):\n merged = arr1 + arr2\n merged.sort()\n return merged[k-1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(list1, list2, k):\n # Combine both lists into one and sort\n combined_list = sorted(list1 + list2)\n # Return kth element\n return combined_list[k - 1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(array1, array2, k):\n # merge two sorted lists into one sorted list\n merged_list = sorted(array1 + array2)\n # return kth element\n return merged_list[k - 1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(array1, array2, k):\n result = array1 + array2\n result.sort()\n return result[k-1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(arr1, arr2, k):\n # Initial check\n if len(arr1) + len(arr2) < k or k <= 0:\n return \"Invalid input.\"\n \n # Merge the two arrays\n arr = arr1 + arr2\n \n # Sort the merged array\n arr.sort()\n \n # Return kth element\n return arr[k - 1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(arr1, arr2, k):\n \"\"\"\n Returns kth element from the merged sorted arrays.\n :param arr1: Sorted array.\n :param arr2: Sorted array.\n :param k: Index of the element to return.\n :return: Kth element.\n \"\"\"\n # Merging two sorted arrays into one\n merged = sorted(arr1 + arr2)\n # Returning kth element\n return merged[k - 1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(list1, list2, k):\n #Merge the two lists\n merged_list = list1 + list2\n #Sort the merged list\n merged_list.sort()\n #Return the kth element\n return merged_list[k-1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(arr1, arr2, k):\n merged_list = sorted(arr1 + arr2)\n if k > len(merged_list):\n return None\n else:\n return merged_list[k - 1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(nums1, nums2, k):\n # Merge sorted lists\n merged_list = sorted(nums1 + nums2)\n\n # Find kth element\n kth_element = merged_list[k-1] if 0 < k <= len(merged_list) else None\n\n return kth_element", "matching_cluster_idx": 3}, {"solution": "def find_kth(arr1, arr2, k):\n \"\"\"\n Find kth element from the given two sorted arrays\n :param arr1: list\n :param arr2: list\n :param k: int\n :return: int\n \"\"\"\n # merge the two arrays\n merged_array = sorted(arr1 + arr2)\n \n # return the kth element\n return merged_array[k - 1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(arr1, arr2, k):\n merged = arr1 + arr2\n merged.sort()\n return merged[k - 1] if k-1 < len(merged) else None", "matching_cluster_idx": 3}]}, "Mbpp/604": {"dps": 90.45454545454545, "dps_norm": 98.0, "pass@1": 50.0, "profiled": [{"solution": "def reverse_words(s):\n \"\"\"\n Returns the string with words reversed in position.\n \"\"\"\n return \" \".join(s.split()[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(string):\n words = string.split()\n reversed_words = ' '.join(reversed(words))\n return reversed_words", "matching_cluster_idx": 4}, {"solution": "def reverse_words(input_str):\n # split the string into words and reverse the list of words\n reversed_words = input_str.split()[::-1]\n # join the reversed words back together\n result = \" \".join(reversed_words)\n return result", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n words = s.split()\n reversed_words = \" \".join(reversed(words))\n return reversed_words", "matching_cluster_idx": 3}, {"solution": "def reverse_words(s):\n return ' '.join(s.split()[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(text):\n return ' '.join(reversed(text.split()))", "matching_cluster_idx": 3}, {"solution": "def reverse_words(s):\n return ' '.join(s.split()[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n words = s.split()\n reversed_words = words[::-1]\n return \" \".join(reversed_words)", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n return ' '.join(s.split()[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n \"\"\"\n Function to reverse the words in a string separated by spaces\n \"\"\"\n return \" \".join(s.split()[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n return ' '.join(s.split()[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(string):\n return \" \".join(string.split()[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n # Splitting the string into list of words.\n words = s.split()\n # Reversing the list of words.\n words = words[::-1]\n # Joining the list back into a string.\n s = ' '.join(words)\n return s", "matching_cluster_idx": 4}, {"solution": "def reverse_words(string):\n words = string.split() # Splitting the string into words\n reversed_words = words[::-1] # Reversing the list of words\n return ' '.join(reversed_words) # Joining the words back into a single string with spaces", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n # Split the string by spaces and reverse the list of words\n reversed_words = s.split()[::-1]\n # Join the reversed words back into a string with spaces\n return \" \".join(reversed_words)", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n return \" \".join(s.split()[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n return ' '.join(s.split()[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n return ' '.join(s.split()[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n return \" \".join(s.split()[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n return \" \".join(s.split()[::-1])", "matching_cluster_idx": 4}]}, "Mbpp/610": {"dps": 73.73188405797102, "dps_norm": 73.57142857142857, "pass@1": 24.0, "profiled": [{"solution": "def remove_kth_element(lst, k):\n \"\"\"\n Function to remove the kth element from a list.\n \n Parameters:\n lst (list): List of elements.\n k (int): Position of the element to remove.\n \n Returns:\n List with kth element removed.\n \"\"\"\n del lst[k-1]\n return lst", "matching_cluster_idx": 6}, {"solution": "def remove_kth_element(input_list, k):\n if 0 < k <= len(input_list):\n input_list.pop(k - 1)\n return input_list", "matching_cluster_idx": 5}, {"solution": "def remove_kth_element(lst, k):\n if k > 0 and k <= len(lst):\n return lst[:k-1] + lst[k:]\n else:\n return lst", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(lst, k):\n return lst[:k-1] + lst[k:]", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(lst, k):\n del lst[k-1] # because Python uses 0-based indexing\n return lst", "matching_cluster_idx": 6}, {"solution": "def remove_kth_element(lst, k):\n return lst[:k-1] + lst[k:]", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(lst, k):\n return lst[:k-1] + lst[k:]", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(lst, k):\n if 1 <= k <= len(lst):\n lst.pop(k-1)\n return lst", "matching_cluster_idx": 6}, {"solution": "def remove_kth_element(lst, k):\n \"\"\"\n Takes a list and an integer, removes the k'th element\n \"\"\"\n del lst[k-1]\n return lst", "matching_cluster_idx": 6}, {"solution": "def remove_kth_element(lst, k):\n return lst[:k-1] + lst[k:]", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(lst, k):\n del lst[k-1]\n return lst", "matching_cluster_idx": 6}, {"solution": "def remove_kth_element(input_list, k):\n return input_list[:k-1] + input_list[k:]", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(lst, k):\n return lst[:k-1] + lst[k:]", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(input_list, k):\n if 1 <= k <= len(input_list):\n return input_list[:k-1] + input_list[k:]\n else:\n return \"Invalid value of k\"", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(lst, k):\n return lst[:k-1] + lst[k:]", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(input_list, k):\n return input_list[:k-1] + input_list[k:]", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(lst, k):\n del lst[k-1]\n return lst", "matching_cluster_idx": 6}, {"solution": "def remove_kth_element(lst, k):\n del lst[k-1]\n return lst", "matching_cluster_idx": 6}, {"solution": "def remove_kth_element(list, k):\n return list[:k-1] + list[k:]", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(lst, k):\n return lst[:k-1] + lst[k:]", "matching_cluster_idx": 3}]}, "Mbpp/611": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 70.0, "profiled": [{"solution": "def max_of_nth(matrix, n):\n column = [row[n] for row in matrix]\n return max(column)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n # firstly, check if n is within the column index of the matrix\n if n < len(matrix[0]):\n # return the maximum value in the nth column of the matrix\n return max(row[n] for row in matrix)\n else:\n return \"Error: n is out of range.\"", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n return max(row[n] for row in matrix)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n # use list comprehension to get the nth column\n column = [row[n] for row in matrix]\n # return the max of the column\n return max(column)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n return max(row[n] for row in matrix)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n return max(row[n] for row in matrix)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n \"\"\"\n Given a matrix represented as a list of lists, returns the max of the n'th column.\n \"\"\"\n return max(row[n] for row in matrix)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n \"\"\"Return the max of the n'th column in the matrix.\"\"\"\n return max(row[n] for row in matrix)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n \"\"\"\n Write a function which given a matrix represented as a list of lists returns the max of the n'th column.\n \"\"\"\n column = [row[n] for row in matrix]\n return max(column)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n return max(row[n] for row in matrix)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n # Extract the nth column\n column = [row[n] for row in matrix]\n # Return the max of the nth column\n return max(column)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n return max(row[n] for row in matrix)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n return max(row[n] for row in matrix)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n return max(row[n] for row in matrix)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n #return max(x[n-1] for x in matrix)\n return max(row[n] for row in matrix)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n # Get the column with index 'n' from the matrix\n column = [row[n] for row in matrix]\n # Return the maximum element in the column\n return max(column)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n return max(row[n] for row in matrix)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n return max(row[n] for row in matrix)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n return max(row[n] for row in matrix)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n return max(row[n] for row in matrix)", "matching_cluster_idx": 5}]}, "Mbpp/631": {"dps": 78.93518518518518, "dps_norm": 75.69444444444444, "pass@1": 18.0, "profiled": [{"solution": "def replace_spaces(input_string):\n output_string = \"\"\n for character in input_string:\n if character == \" \":\n output_string += \"_\"\n elif character == \"_\":\n output_string += \" \"\n else:\n output_string += character\n return output_string", "matching_cluster_idx": 2}, {"solution": "def replace_spaces(input_string):\n \"\"\"\n Replaces all whitespaces in the input string with underscores.\n And replaces all underscores with whitespaces.\n \"\"\"\n result = \"\"\n for char in input_string:\n if char == \" \":\n result += \"_\"\n elif char == \"_\":\n result += \" \"\n else:\n result += char\n return result", "matching_cluster_idx": 2}, {"solution": "def replace_spaces(input_string):\n if \" \" in input_string:\n return input_string.replace(\" \", \"_\")\n else:\n return input_string.replace(\"_\", \" \")", "matching_cluster_idx": 7}, {"solution": "def replace_spaces(s):\n # replacing white spaces with underscore\n if ' ' in s:\n s = s.replace(' ', '_')\n # replacing underscores with white spaces\n elif '_' in s:\n s = s.replace('_', ' ')\n return s", "matching_cluster_idx": 7}, {"solution": "def replace_spaces(s):\n if '_' in s:\n return s.replace('_', ' ')\n else:\n return s.replace(' ', '_')", "matching_cluster_idx": 7}, {"solution": "def replace_spaces(s):\n if ' ' in s:\n return s.replace(' ', '_')\n else:\n return s.replace('_', ' ')", "matching_cluster_idx": 7}, {"solution": "def replace_spaces(s):\n if '_' in s:\n s = s.replace('_', ' ')\n else:\n s = s.replace(' ', '_')\n return s", "matching_cluster_idx": 7}, {"solution": "def replace_spaces(input_str):\n if \" \" in input_str:\n output_str = input_str.replace(\" \", \"_\")\n else:\n output_str = input_str.replace(\"_\", \" \")\n return output_str", "matching_cluster_idx": 7}, {"solution": "def replace_spaces(input_str):\n if \" \" in input_str:\n output_str = input_str.replace(\" \", \"_\")\n else:\n output_str = input_str.replace(\"_\", \" \")\n return output_str", "matching_cluster_idx": 7}, {"solution": "def replace_spaces(text):\n #Replace underscore with space\n if \"_\" in text:\n return text.replace(\"_\", \" \")\n #Replace space with underscore\n else:\n return text.replace(\" \", \"_\")", "matching_cluster_idx": 7}, {"solution": "def replace_spaces(input_string):\n output_string = ''\n for char in input_string:\n if char == ' ':\n output_string += '_'\n elif char == '_':\n output_string += ' '\n else:\n output_string += char\n return output_string", "matching_cluster_idx": 2}, {"solution": "def replace_spaces(input_string):\n result = \"\"\n for char in input_string:\n if char == ' ':\n result += '_'\n elif char == '_':\n result += ' '\n else:\n result += char\n return result", "matching_cluster_idx": 2}, {"solution": "def replace_spaces(input_string):\n if ' ' in input_string:\n return input_string.replace(' ', '_')\n else:\n return input_string.replace('_', ' ')", "matching_cluster_idx": 7}, {"solution": "def replace_spaces(s):\n result = ''\n for char in s:\n if char == ' ':\n result += '_'\n elif char == '_':\n result += ' '\n else:\n result += char\n return result", "matching_cluster_idx": 2}, {"solution": "def replace_spaces(string):\n # Replace spaces with underscore\n if ' ' in string:\n new_string = string.replace(' ', '_')\n # Replace underscores with spaces\n elif '_' in string:\n new_string = string.replace('_', ' ')\n else:\n new_string = string\n return new_string", "matching_cluster_idx": 7}, {"solution": "def replace_spaces(input_str):\n if '_' in input_str:\n output_str = input_str.replace('_', ' ')\n else:\n output_str = input_str.replace(' ', '_')\n\n return output_str", "matching_cluster_idx": 7}, {"solution": "def replace_spaces(input_string):\n output_string = \"\"\n for char in input_string:\n if char == \" \":\n output_string += \"_\"\n elif char == \"_\":\n output_string += \" \"\n else:\n output_string += char\n return output_string", "matching_cluster_idx": 2}, {"solution": "def replace_spaces(s):\n result = ''\n for char in s:\n if char == ' ':\n result += '_'\n elif char == '_':\n result += ' '\n else:\n result += char\n return result", "matching_cluster_idx": 2}]}, "Mbpp/632": {"dps": 95.1219512195122, "dps_norm": 97.14285714285714, "pass@1": 95.0, "profiled": [{"solution": "def move_zero(lst):\n count = 0\n for i in range(len(lst)):\n if lst[i] != 0:\n lst[count] = lst[i]\n count += 1\n while count < len(lst):\n lst[count] = 0\n count += 1\n return lst", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n non_zero = [num for num in nums if num != 0]\n zero = [num for num in nums if num == 0]\n return non_zero + zero", "matching_cluster_idx": 6}, {"solution": "def move_zero(lst):\n for i in lst:\n if i == 0:\n lst.remove(i)\n lst.append(i)\n return lst", "matching_cluster_idx": 2}, {"solution": "def move_zero(numbers):\n # create a list of non-zero numbers\n no_zeroes = [i for i in numbers if i != 0]\n \n # create a list of zeroes with length equals to the number of zeroes in the original list\n zeroes = [0]*numbers.count(0)\n \n # concatenate no_zeroes and zeroes lists\n return no_zeroes + zeroes", "matching_cluster_idx": 6}, {"solution": "def move_zero(lst):\n # count the number of zeros\n zeros = lst.count(0)\n # remove all zeros from the list\n lst = [x for x in lst if x != 0]\n # add zeros at the end of the list\n lst.extend([0]*zeros)\n return lst", "matching_cluster_idx": 6}, {"solution": "def move_zero(lst):\n # Count the number of zeroes\n zero_count = lst.count(0)\n \n # Remove the zeroes from the list\n lst = [i for i in lst if i != 0]\n \n # Append zero_count number of zeroes to the end of the list\n lst.extend([0]*zero_count)\n \n return lst", "matching_cluster_idx": 6}, {"solution": "def move_zero(lst):\n # create a new list containing only the non-zero elements\n no_zeros = [i for i in lst if i != 0]\n # create a new list containing only the zeros\n zeros = [i for i in lst if i == 0]\n # join the two lists to get the final result\n result = no_zeros + zeros\n return result", "matching_cluster_idx": 6}, {"solution": "def move_zero(numbers):\n non_zeros = [num for num in numbers if num != 0]\n zeros = [num for num in numbers if num == 0]\n return non_zeros + zeros", "matching_cluster_idx": 6}, {"solution": "def move_zero(lst):\n # We use two pointers (i and j) to move non-zero elements to the front of the list\n i = 0 # Pointer 1\n j = 0 # Pointer 2\n\n while j < len(lst):\n if lst[j] != 0:\n lst[i], lst[j] = lst[j], lst[i] # Swap non-zero elements to the front\n i += 1\n j += 1\n\n return lst", "matching_cluster_idx": 6}, {"solution": "def move_zero(numbers):\n non_zero = [num for num in numbers if num != 0]\n zero = [num for num in numbers if num == 0]\n return non_zero + zero", "matching_cluster_idx": 6}, {"solution": "def move_zero(lst):\n \"\"\"\n Move all zeroes to the end of the given list.\n :param lst: A list of integers.\n :return: The same list but with all zeros moved to the end.\n \"\"\"\n # Count the number of zeroes.\n num_zero = lst.count(0)\n # Remove all zeroes from the list.\n lst = [num for num in lst if num != 0]\n # Append the number of zeroes to the end of the list.\n lst.extend([0] * num_zero)\n return lst", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n # Create a new list to hold the non-zero numbers\n no_zeros = [num for num in nums if num != 0]\n # Create a new list to hold the zero numbers\n zeroes = [num for num in nums if num == 0]\n # Combine the non-zero list and the zero list\n return no_zeros + zeroes", "matching_cluster_idx": 6}, {"solution": "def move_zero(lst):\n # Separate non-zero elements into a new list\n non_zeros = [i for i in lst if i != 0]\n \n # Separate zeros into a new list\n zeros = [i for i in lst if i == 0]\n \n # Combine non-zero elements with zeros\n result = non_zeros + zeros\n \n return result", "matching_cluster_idx": 6}, {"solution": "def move_zero(lst):\n no_zero = [i for i in lst if i != 0]\n count = len(lst) - len(no_zero)\n no_zero.extend([0] * count)\n return no_zero", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n # Count of non-zero elements\n count = 0\n for i in range(len(nums)):\n if nums[i] != 0:\n # replace non-zero with count incrementing\n nums[count] = nums[i]\n count += 1\n # Make all elements from count to end as 0\n while count < len(nums):\n nums[count] = 0\n count += 1\n return nums", "matching_cluster_idx": 6}, {"solution": "def move_zero(lst):\n # List comprehension to collect all non-zero elements first, followed by zeros\n return [i for i in lst if i != 0] + [i for i in lst if i == 0]", "matching_cluster_idx": 6}, {"solution": "def move_zero(input_list):\n \"\"\"\n This function moves all zeroes to the end of the list.\n Args:\n input_list: List of integers.\n\n Returns:\n List with zeroes moved to the end.\n \"\"\"\n # Count of non-zero elements\n non_zero_count = sum(i != 0 for i in input_list)\n\n # Updating the list with all non-zero elements before the 0's\n input_list[:non_zero_count] = [i for i in input_list if i != 0]\n\n # Appending the number of 0's in the end\n input_list[non_zero_count:] = [0] * (len(input_list) - non_zero_count)\n\n return input_list", "matching_cluster_idx": 6}, {"solution": "def move_zero(lst):\n # Filter out all zeroes and concatenate with the filtered zeroes\n return [i for i in lst if i != 0] + [0] * lst.count(0)", "matching_cluster_idx": 6}, {"solution": "def move_zero(lst):\n return [num for num in lst if num != 0] + [0] * lst.count(0)", "matching_cluster_idx": 6}, {"solution": "def move_zero(arr):\n return [i for i in arr if i != 0] + [0]*(arr.count(0))", "matching_cluster_idx": 6}]}, "Mbpp/633": {"dps": 94.3089430894309, "dps_norm": 50.0, "pass@1": 38.0, "profiled": [{"solution": "def pair_xor_Sum(arr, n):\n sum = 0\n for i in range(0,n):\n for j in range(i+1,n):\n sum += arr[i] ^ arr[j]\n return sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(lst, n):\n total_sum = 0\n for i in range(n):\n for j in range(i + 1, n):\n total_sum += lst[i] ^ lst[j]\n return total_sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(nums, N):\n if N <= 0:\n return 0\n\n XOR_SUM = 0\n\n for i in range(N):\n for j in range(i+1, N):\n XOR_SUM += nums[i] ^ nums[j]\n\n return XOR_SUM", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(numbers, length):\n sum = 0\n for i in range(length):\n for j in range(i + 1, length):\n sum += numbers[i] ^ numbers[j]\n return sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(lst, n):\n total = 0\n for i in range(n):\n for j in range(i+1, n):\n total += lst[i] ^ lst[j]\n return total", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(nums, n):\n sum_xor = 0\n for i in range(n):\n for j in range(i + 1, n):\n sum_xor += (nums[i] ^ nums[j])\n return sum_xor", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(nums, l):\n xor_sum = 0\n for i in range(l):\n for j in range(i + 1, l):\n xor_sum += nums[i] ^ nums[j]\n return xor_sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(lst, n):\n sum = 0\n for i in range(n):\n for j in range(i+1, n):\n sum += (lst[i] ^ lst[j])\n return sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(nums, n):\n total = 0\n for i in range(n):\n for j in range(i + 1, n):\n total += nums[i] ^ nums[j]\n return total", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(nums, n):\n res = 0\n for i in range(n):\n for j in range(i + 1, n):\n res += nums[i] ^ nums[j]\n return res", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(list, n):\n sum = 0\n for i in range(n):\n for j in range(i+1, n):\n sum += list[i] ^ list[j]\n return sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(lst, n):\n sum = 0\n for i in range(n):\n for j in range(i + 1, n):\n sum += lst[i] ^ lst[j]\n return sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(list, n):\n xor_sum = 0\n for i in range(n):\n for j in range(i + 1, n):\n xor_sum += list[i] ^ list[j]\n return xor_sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(nums, n):\n sum = 0\n for i in range(n):\n for j in range(i+1,n):\n sum += nums[i] ^ nums[j]\n return sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(lst, length):\n sum = 0\n for i in range(length):\n for j in range(i+1, length):\n sum += (lst[i] ^ lst[j])\n return sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(nums, n):\n # Initialize the sum\n res = 0\n for i in range(n):\n # Compute the XOR with the rest\n for j in range(i+1, n):\n # Update the sum\n res += nums[i] ^ nums[j]\n return res", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(numbers, n):\n xor_sum = 0\n for i in range(n):\n for j in range(i + 1, n):\n xor_sum += numbers[i] ^ numbers[j]\n return xor_sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(list_of_numbers, pairs):\n \"\"\"\n Calculate sum of xor of all pairs in the list.\n \"\"\"\n xor_sum = 0\n for i in range(pairs):\n for j in range(i+1, pairs):\n xor_sum += list_of_numbers[i] ^ list_of_numbers[j]\n return xor_sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(lst, n):\n result = 0\n for i in range(n):\n for j in range(i + 1, n):\n result += lst[i] ^ lst[j]\n return result", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(lst, length):\n xor_Sum = 0\n for i in range(length):\n for j in range(i+1, length):\n xor_Sum += lst[i] ^ lst[j]\n return xor_Sum", "matching_cluster_idx": 2}]}, "Mbpp/644": {"dps": 80.77127659574467, "dps_norm": 81.0, "pass@1": 80.0, "profiled": [{"solution": "def reverse_Array_Upto_K(arr, k):\n if k < 1 or k > len(arr):\n return \"Invalid position\"\n arr[0:k] = arr[0:k][::-1]\n return arr", "matching_cluster_idx": 13}, {"solution": "def reverse_Array_Upto_K(array, k):\n return array[:k][::-1] + array[k:]", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n arr[0:k] = arr[0:k][::-1]\n return arr", "matching_cluster_idx": 13}, {"solution": "def reverse_Array_Upto_K(arr, k):\n # Check if k is within the array's range\n if k > len(arr) or k < 1:\n return arr\n \n # Reverse upto position k\n return arr[:k][::-1] + arr[k:]", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(input_array, k):\n return input_array[:k][::-1] + input_array[k:]", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n return arr[:k][::-1] + arr[k:]", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(array, k):\n # If the array is empty or the k value is greater than length of the array, return the array as is.\n if len(array) == 0 or k > len(array):\n return array\n else:\n return array[:k][::-1] + array[k:]", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(array, k):\n if k <= len(array):\n temp = array[:k]\n temp = temp[::-1]\n result = temp + array[k:]\n return result\n else:\n print(\"Error: Value of 'K' should be less than or equal to the length of the array.\")", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n return arr[:k][::-1] + arr[k:]", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n # Reverse the first k elements of the list\n arr[:k] = arr[:k][::-1]\n return arr", "matching_cluster_idx": 13}, {"solution": "def reverse_Array_Upto_K(array, k):\n if k > len(array):\n raise ValueError('K is greater than the length of the array')\n return array[:k][::-1] + array[k:]", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n return arr[:k][::-1] + arr[k:]", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n A function to reverse the array up to a given position 'k'.\n \"\"\"\n if k > len(arr):\n return arr\n else:\n arr[:k] = reversed(arr[:k])\n return arr", "matching_cluster_idx": 12}, {"solution": "def reverse_Array_Upto_K(array, k):\n # Check if the given position is valid.\n if k > len(array) or k < 1:\n return \"Invalid position. Please provide a position between 1 and length of array.\"\n else:\n # Reverse the sub-array from the start till kth position.\n array[:k] = array[:k][::-1]\n return array", "matching_cluster_idx": 13}, {"solution": "def reverse_Array_Upto_K(arr, k):\n # Ensure that K is valid\n if k < 1 or k > len(arr):\n raise ValueError(\"Invalid value for k. Must be between 1 and size of array.\")\n \n # Split the array into two halves up to position K\n first_half = arr[:k]\n second_half = arr[k:]\n\n # Reverse the first half and join the second half to get the result\n result = first_half[::-1] + second_half\n return result", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n n = len(arr)\n if k > n:\n return \"K is larger than the length of the array.\"\n elif k <= 0:\n return \"K must be a positive integer.\"\n else:\n new_arr = arr[:k][::-1] + arr[k:]\n return new_arr", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n # Reverse the array from index 0 to k-1\n arr[:k] = arr[:k][::-1]\n \n # Return the updated array\n return arr", "matching_cluster_idx": 13}, {"solution": "def reverse_Array_Upto_K(array, k):\n array[:k] = array[:k][::-1]\n return array", "matching_cluster_idx": 13}, {"solution": "def reverse_Array_Upto_K(array, k):\n return array[:k][::-1] + array[k:]", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n # Reverse the first K elements of the array\n arr[:k] = arr[:k][::-1]\n return arr", "matching_cluster_idx": 13}]}, "Mbpp/720": {"dps": 84.61538461538461, "dps_norm": 95.0, "pass@1": 99.0, "profiled": [{"solution": "def add_dict_to_tuple(t, d):\n \"\"\"\n This function takes a tuple and a dictionary as inputs, \n and returns a new tuple which is the original tuple with \n the dictionary appended to it as the last element.\n \"\"\"\n return t + (d,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(t, d):\n return t + (d,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(t, d):\n # Convert the tuple to a list for easier manipulation\n list_t = list(t)\n # Append the dictionary to the list\n list_t.append(d)\n # Convert the list back to a tuple\n return tuple(list_t)", "matching_cluster_idx": 3}, {"solution": "def add_dict_to_tuple(tup, dic):\n # Convert the tuple to a list\n list_tup = list(tup)\n\n # Append the dictionary to the list\n list_tup.append(dic)\n\n # Convert the list back to a tuple\n tup = tuple(list_tup)\n\n # Return the resulting tuple\n return tup", "matching_cluster_idx": 3}, {"solution": "def add_dict_to_tuple(tup, diction):\n tup = list(tup)\n tup.append(diction)\n return tuple(tup)", "matching_cluster_idx": 3}, {"solution": "def add_dict_to_tuple(t, d):\n return t + (d, )", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(t, d):\n return t + (d,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(tuple_obj, dict_obj):\n return tuple_obj + (dict_obj,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(tup, dictionary):\n tup = list(tup)\n tup.append(dictionary)\n tup = tuple(tup)\n return tup", "matching_cluster_idx": 3}, {"solution": "def add_dict_to_tuple(tpl, dct):\n \"\"\"Adds a dictionary to the tuple and returns the new tuple.\"\"\"\n new_tpl = tpl + (dct,)\n return new_tpl", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(tpl, dct):\n return tpl + (dct,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(tup, dic):\n new_tup = tup + (dic,)\n return new_tup", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(tup, dictionary):\n return tup + (dictionary,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(tuple_, dict_):\n return tuple_ + (dict_,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(tpl, dictionary):\n return tpl + (dictionary,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(t, d):\n # Concatenate the tuple with the dictionary\n return t + (d,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(input_tuple, input_dict):\n output_tuple = input_tuple + (input_dict,)\n return output_tuple", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(my_tuple, my_dict):\n return my_tuple + (my_dict,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(tpl, dct):\n tpl_plus_dct = tpl + (dct,)\n return tpl_plus_dct", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(tup, dic):\n # Convert tuple to list\n tup_list = list(tup)\n \n # Add dictionary to list\n tup_list.append(dic)\n \n # Convert list back to tuple\n new_tup = tuple(tup_list)\n \n return new_tup", "matching_cluster_idx": 3}]}, "Mbpp/725": {"dps": 85.02732240437157, "dps_norm": 80.625, "pass@1": 98.0, "profiled": [{"solution": "import re\ndef extract_quotation(input_string):\n return re.findall(r'\"(.*?)\"', input_string)", "matching_cluster_idx": 4}, {"solution": "import re\ndef extract_quotation(s):\n pattern = re.compile(r'\"(.*?)\"')\n return [match.group(1) for match in pattern.finditer(s)]", "matching_cluster_idx": 4}, {"solution": "import re\ndef extract_quotation(text):\n \"\"\"\n This function takes a string as an argument and returns a list of values\n between quotation marks in the string.\n \"\"\"\n return re.findall(r'\"(.*?)\"', text)", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(text):\n # Use regular expression to find all the matches and return them as a list\n return re.findall(r'\"(.*?)\"', text)", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(input_string):\n quotes_value = re.findall('\"([^\"]*)\"', input_string)\n return quotes_value", "matching_cluster_idx": 6}, {"solution": "def extract_quotation(text):\n import re\n return re.findall(r'\"(.*?)\"', text)", "matching_cluster_idx": 5}, {"solution": "def extract_quotation(s):\n import re\n return re.findall(r'\"(.*?)\"', s)", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(string):\n return re.findall('\"([^\"]*)\"', string)", "matching_cluster_idx": 6}, {"solution": "import re\ndef extract_quotation(s):\n return re.findall('\"([^\"]*)\"', s)", "matching_cluster_idx": 6}, {"solution": "import re\ndef extract_quotation(s):\n return re.findall(r'\"([^\"]*)\"', s)", "matching_cluster_idx": 6}, {"solution": "import re\ndef extract_quotation(input_string):\n return re.findall(r'\"(.*?)\"', input_string)", "matching_cluster_idx": 4}, {"solution": "import re\ndef extract_quotation(s):\n return re.findall('\"([^\"]*)\"', s)", "matching_cluster_idx": 6}, {"solution": "import re\ndef extract_quotation(s):\n return re.findall(r'\"([^\"]*)\"', s)", "matching_cluster_idx": 6}, {"solution": "def extract_quotation(string):\n import re\n return re.findall(r'\"([^\"]*)\"', string)", "matching_cluster_idx": 6}, {"solution": "import re\ndef extract_quotation(s):\n # Using regular expressions to find all quoted values\n quoted_values = re.findall(r'\"([^\"]*)\"', s)\n return quoted_values", "matching_cluster_idx": 6}, {"solution": "import re\ndef extract_quotation(s):\n return re.findall(r'\"([^\"]*)\"', s)", "matching_cluster_idx": 6}, {"solution": "import re\ndef extract_quotation(s):\n # using regular expression to find all matches in the string\n matches = re.findall(r'\"([^\"]*)\"', s)\n return matches", "matching_cluster_idx": 6}, {"solution": "def extract_quotation(s):\n import re\n return re.findall(r'\"([^\"]*)\"', s)", "matching_cluster_idx": 6}, {"solution": "import re\ndef extract_quotation(s):\n # Using Regular Expression to find strings inside quotation marks\n matches = re.findall(r'\"(.*?)\"', s)\n return matches", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(s):\n return re.findall(r'\"([^\"]*)\"', s)", "matching_cluster_idx": 6}]}, "Mbpp/732": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 98.0, "profiled": [{"solution": "def replace_specialchar(string):\n return string.replace(' ', ':').replace(',', ':').replace('.', ':')", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(input_string):\n replaced_string = input_string.replace(' ', ':').replace(',', ':').replace('.', ':')\n return replaced_string", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(s):\n s = s.replace(' ', ':')\n s = s.replace(',', ':')\n s = s.replace('.', ':')\n return s", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(text):\n return text.replace(' ', ':').replace(',', ':').replace('.', ':')", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(sentence):\n sentence = sentence.replace(\" \", \":\")\n sentence = sentence.replace(\",\", \":\")\n sentence = sentence.replace(\".\", \":\")\n return sentence", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(input_string):\n new_string = input_string.replace(\" \", \":\").replace(\",\", \":\").replace(\".\", \":\")\n return new_string", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(str):\n return str.replace(' ', ':').replace(',', ':').replace('.', ':')", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(text):\n return text.replace(' ', ':').replace(',', ':').replace('.', ':')", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(s):\n return s.replace(' ', ':').replace(',', ':').replace('.', ':')", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(text):\n text = text.replace(' ', ':')\n text = text.replace(',', ':')\n text = text.replace('.', ':')\n return text", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(sentence):\n new_sentence = sentence.replace(' ', ':').replace(',', ':').replace('.', ':')\n return new_sentence", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(string):\n return string.replace(\" \", \":\").replace(\",\", \":\").replace(\".\", \":\")", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(text):\n \"\"\" Replaces spaces, commas and dots with colon in the input string \"\"\"\n return text.replace(' ', ':').replace(',', ':').replace('.', ':')", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(input_string):\n return input_string.replace(' ', ':').replace(',', ':').replace('.', ':')", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(input_str):\n return input_str.replace(' ', ':').replace(',', ':').replace('.', ':')", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(s):\n return s.replace(' ', ':').replace(',', ':').replace('.', ':')", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(text):\n specialchars = ['.', ',', ' ']\n for char in specialchars:\n text = text.replace(char, ':')\n return text", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(s):\n for char in ['.', ',', ' ']:\n s = s.replace(char, ':')\n return s", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(input_str):\n return input_str.replace(',', ':').replace('.', ':').replace(' ', ':')", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(text):\n return text.replace(\",\", \":\").replace(\".\", \":\").replace(\" \", \":\")", "matching_cluster_idx": 9}]}, "Mbpp/740": {"dps": 88.54545454545455, "dps_norm": 76.66666666666667, "pass@1": 99.0, "profiled": [{"solution": "def tuple_to_dict(t):\n # Ensure that the tuple length is even (otherwise, zip would fail)\n if len(t)%2 != 0:\n t = t[:-1]\n \n # Convert the tuple to dictionary using zip with two elements each as a key and value\n return dict(zip(t[::2], t[1::2]))", "matching_cluster_idx": 8}, {"solution": "def tuple_to_dict(tup):\n # Ensure the length of tuple is even, otherwise cannot form key-value pairs\n if len(tup)%2 != 0:\n raise ValueError(\"Tuple length should be even to form key-value pairs\")\n\n return {tup[i]: tup[i + 1] for i in range(0, len(tup), 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(my_tuple):\n return {my_tuple[i]: my_tuple[i+1] for i in range(0, len(my_tuple), 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(t):\n return {t[i]: t[i + 1] for i in range(0, len(t) - 1, 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(input_tuple):\n return {input_tuple[i]: input_tuple[i + 1] for i in range(0, len(input_tuple), 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(tup):\n return {tup[i]: tup[i + 1] for i in range(0, len(tup), 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(t):\n return {t[i]: t[i + 1] for i in range(0, len(t), 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(tup):\n if len(tup) % 2 != 0:\n return \"Error: Tuple length should be even.\"\n\n dic = {}\n for i in range(0, len(tup), 2):\n dic[tup[i]] = tup[i+1]\n\n return dic", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(input_tuple):\n # check that the number of elements in the tuple is even\n if len(input_tuple) % 2 != 0:\n raise ValueError(\"The input tuple has an odd number of elements\")\n else:\n # create an empty dictionary\n output_dict = {}\n # iterate over every two elements in the tuple\n for i in range(0, len(input_tuple), 2):\n # add these two elements as a key-value pair to the dictionary\n output_dict[input_tuple[i]] = input_tuple[i+1]\n return output_dict", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(input_tuple):\n # checking if the length of the tuple is even\n if len(input_tuple) % 2 == 0:\n # using dict comprehension to convert the tuple to a dictionary\n return {input_tuple[i]: input_tuple[i + 1] for i in range(0, len(input_tuple), 2)}\n else:\n # if length is not even, return an empty dictionary\n return {}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(tpl):\n return {tpl[i]: tpl[i + 1] for i in range(0, len(tpl), 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(t):\n return dict(zip(t[::2], t[1::2]))", "matching_cluster_idx": 8}, {"solution": "def tuple_to_dict(t):\n return {t[i]: t[i + 1] for i in range(0, len(t), 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(t):\n return dict(zip(t[::2], t[1::2]))", "matching_cluster_idx": 8}, {"solution": "def tuple_to_dict(input_tuple):\n if len(input_tuple) % 2 != 0:\n raise ValueError(\"The tuple must have an even number of elements\")\n\n result = {}\n for i in range(0, len(input_tuple), 2):\n result[input_tuple[i]] = input_tuple[i+1]\n\n return result", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(t):\n return {t[i]: t[i+1] for i in range(0, len(t), 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(tup):\n return dict(zip(tup[::2], tup[1::2]))", "matching_cluster_idx": 8}, {"solution": "def tuple_to_dict(t):\n return dict(zip(t[::2], t[1::2]))", "matching_cluster_idx": 8}, {"solution": "def tuple_to_dict(tpl):\n if len(tpl) % 2 != 0:\n raise ValueError(\"Odd number of elements in the tuple. Cannot create a key-value dictionary.\")\n return {tpl[i]: tpl[i+1] for i in range(0, len(tpl), 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(t):\n if len(t) % 2 != 0:\n raise ValueError('Tuple must have an even number of elements')\n return dict(zip(t[::2], t[1::2]))", "matching_cluster_idx": 8}]}, "Mbpp/744": {"dps": 89.07534246575342, "dps_norm": 92.5, "pass@1": 100.0, "profiled": [{"solution": "def check_none(tpl):\n return None in tpl", "matching_cluster_idx": 5}, {"solution": "def check_none(tup):\n return None in tup", "matching_cluster_idx": 5}, {"solution": "def check_none(tup):\n if None in tup:\n return True\n else:\n return False", "matching_cluster_idx": 5}, {"solution": "def check_none(tup):\n # The any() function returns True if at least one element of an iterable is True.\n # If not, it returns False.\n # Here, we pass a generator expression that returns True if the element is None.\n # If an element is None, the expression is True, otherwise it's False.\n return any(val is None for val in tup)", "matching_cluster_idx": 1}, {"solution": "def check_none(tup):\n return None in tup", "matching_cluster_idx": 5}, {"solution": "def check_none(t):\n return None in t", "matching_cluster_idx": 5}, {"solution": "def check_none(tup):\n return None in tup", "matching_cluster_idx": 5}, {"solution": "def check_none(my_tuple):\n return any(value is None for value in my_tuple)", "matching_cluster_idx": 1}, {"solution": "def check_none(tup):\n \"\"\"\n This function checks if the given tuple has any None value\n \"\"\"\n return None in tup", "matching_cluster_idx": 5}, {"solution": "def check_none(tuple):\n if None in tuple:\n return True\n else:\n return False", "matching_cluster_idx": 5}, {"solution": "def check_none(tup):\n return None in tup", "matching_cluster_idx": 5}, {"solution": "def check_none(tuple_to_check):\n return None in tuple_to_check", "matching_cluster_idx": 5}, {"solution": "def check_none(tuple):\n return None in tuple", "matching_cluster_idx": 5}, {"solution": "def check_none(tup):\n \"\"\"\n Check if the given tuple has any none value.\n\n :param tup: The tuple to check.\n :type tup: tuple\n :return: True if the tuple contains any None value, False otherwise.\n :rtype: bool\n \"\"\"\n return None in tup", "matching_cluster_idx": 5}, {"solution": "def check_none(tup):\n return None in tup", "matching_cluster_idx": 5}, {"solution": "def check_none(t):\n for item in t:\n if item is None:\n return True\n return False", "matching_cluster_idx": 4}, {"solution": "def check_none(tup):\n return None in tup", "matching_cluster_idx": 5}, {"solution": "def check_none(t):\n \"\"\"\n This function checks if the given tuple has any None value or not.\n\n Arguments:\n t (tuple): The tuple to be checked.\n\n Returns:\n bool: True if the tuple contains None, False otherwise.\n \"\"\"\n return None in t", "matching_cluster_idx": 5}, {"solution": "def check_none(tpl):\n return None in tpl", "matching_cluster_idx": 5}, {"solution": "def check_none(tup):\n if None in tup:\n return True\n else:\n return False", "matching_cluster_idx": 5}]}, "Mbpp/750": {"dps": 69.25170068027211, "dps_norm": 68.33333333333333, "pass@1": 98.0, "profiled": [{"solution": "def add_tuple(lst, tup):\n # Add the elements of tuple to the end of list\n return lst + list(tup)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(lst, tup):\n return lst + list(tup)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(lst, tpl):\n return lst + list(tpl)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(input_list, input_tuple):\n return input_list + list(input_tuple)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(lst, tup):\n return lst + list(tup)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(lst, tup):\n return lst + list(tup)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(lst, tup):\n return lst + list(tup)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(lst, tpl):\n return lst + list(tpl)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(lst, tup):\n \"\"\"\n Function to add a tuple to a list\n Args:\n lst (List): List of integers.\n tup (Tuple): Tuple of integers.\n Returns:\n lst (List): Updated list with the integers from the tuple added.\n \"\"\"\n # Convert tuple to a list and then extend the original list\n lst.extend(list(tup))\n return lst", "matching_cluster_idx": 3}, {"solution": "def add_tuple(lst, tpl):\n \"\"\"\n Function to add the given tuple to the given list.\n :param lst: The given list.\n :param tpl: The given tuple.\n :return: The list after adding the tuple.\n \"\"\"\n return lst + list(tpl)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(lst, tpl):\n lst.extend(tpl)\n return lst", "matching_cluster_idx": 5}, {"solution": "def add_tuple(lst, tup):\n # Use the extend() method to add elements from tup to lst\n lst.extend(tup)\n return lst", "matching_cluster_idx": 5}, {"solution": "def add_tuple(lst, tup):\n return lst + list(tup)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(input_list, input_tuple):\n #Appends the tuple to the list\n input_list.extend(input_tuple)\n return input_list", "matching_cluster_idx": 5}, {"solution": "def add_tuple(my_list, my_tuple):\n return my_list + list(my_tuple)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(lst, tpl):\n # Check if inputs are of valid types\n if not isinstance(lst, list) or not isinstance(tpl, tuple):\n raise ValueError(\"Both inputs must be of list and tuple types.\")\n return lst + list(tpl)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(list_, tuple_):\n # If tuple_ is a sequence (list, tuple, etc.), extend the list_ with it.\n # Otherwise, just append tuple_ to the list_.\n if hasattr(tuple_, \"__iter__\"):\n list_.extend(tuple_)\n else:\n list_.append(tuple_)\n\n return list_", "matching_cluster_idx": 5}, {"solution": "def add_tuple(lst, tup):\n lst.extend(tup)\n return lst", "matching_cluster_idx": 5}, {"solution": "def add_tuple(lst, tpl):\n lst.extend(tpl)\n return lst", "matching_cluster_idx": 5}, {"solution": "def add_tuple(my_list, my_tuple):\n # Adding tuple to list using extend method\n my_list.extend(my_tuple)\n return my_list", "matching_cluster_idx": 5}]}, "Mbpp/753": {"dps": 92.51677852348993, "dps_norm": 73.75, "pass@1": 92.0, "profiled": [{"solution": "def min_k(tuple_list, k):\n return sorted(tuple_list, key=lambda x: x[1])[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(data, k):\n return sorted(data, key=lambda x: x[1])[:k]", "matching_cluster_idx": 1}, {"solution": "def min_k(record_list, k):\n record_list.sort(key=lambda x: x[1]) # Sort the list based on the value (second element in tuple)\n return record_list[:k] # Return the first k elements of the sorted list", "matching_cluster_idx": 2}, {"solution": "def min_k(lst, k):\n return sorted(lst, key=lambda x: x[1])[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(records, k):\n # Sort the list of tuples based on second element in each tuple\n sorted_records = sorted(records, key = lambda x: x[1])\n # Return the first k records\n return sorted_records[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(lst, k):\n # sort the list in ascending order based on the second element in tuple\n sorted_lst = sorted(lst, key=lambda x: x[1])\n # return first k elements\n return sorted_lst[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(tup_list, k):\n return sorted(tup_list, key=lambda x: x[1])[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(tuples, k):\n \"\"\" Function to find minimum k records from tuple list.\n Arguments:\n tuples {list} -- list of tuples\n k {int} -- number of minimum records to find\n\n Returns:\n list -- list of minimum k records\n \"\"\"\n if k > len(tuples):\n raise ValueError('K is larger than the length of the list.')\n \n # Sort the list by the second element of each tuple.\n sorted_tuples = sorted(tuples, key=lambda x: x[1])\n \n # Return first k elements from sorted list.\n return sorted_tuples[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(lst, k):\n return sorted(lst, key=lambda x: x[1])[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(lst, k):\n # Sorting the list of tuples based on the second item in tuple\n sorted_lst = sorted(lst, key=lambda x: x[1])\n # Returning first k items from the sorted list\n return sorted_lst[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(tuples, k):\n return sorted(tuples, key=lambda x: x[1])[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(tuples, k):\n # First we sort the list of tuples by the second value of each tuple\n # This way, we ensure that all tuples with the smallest second value come first.\n # Then we return the first k tuples from the sorted list.\n sorted_tuples = sorted(tuples, key=lambda x: x[1])\n return sorted_tuples[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(records, k):\n # sort the list by the second element of the tuple in ascending order\n sorted_records = sorted(records, key=lambda record: record[1])\n # return the first k records\n return sorted_records[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(records, k):\n return sorted(records, key=lambda x: x[1])[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(list, k):\n list.sort(key=lambda x: x[1])\n return list[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(lst, k):\n # sort the list based on the second element (record value)\n lst = sorted(lst, key = lambda x: x[1])\n \n # return the first k elements (minimum k records)\n return lst[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(list, k):\n return sorted(list, key=lambda x: x[1])[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(lst, k):\n # Sort the list based on the second element of each tuple\n # This will place tuples with smaller second element first\n lst.sort(key = lambda x: x[1])\n\n # Return the first 'k' elements from the list\n return lst[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(list_of_tuples, k):\n list_of_tuples.sort(key=lambda x: x[1])\n return list_of_tuples[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(list, k):\n return sorted(list, key=lambda x: x[1])[:k]", "matching_cluster_idx": 2}]}, "Mbpp/754": {"dps": 91.20689655172414, "dps_norm": 89.375, "pass@1": 25.0, "profiled": [{"solution": "def extract_index_list(l1, l2, l3):\n common_elements = []\n for i in range(min(len(l1), len(l2), len(l3))):\n if l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n return [l1[i] for i in range(min(len(l1), len(l2), len(l3))) if l1[i] == l2[i] == l3[i]]", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n common_elements = []\n for i in range(min(len(l1), len(l2), len(l3))):\n if l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n common_elements = []\n for i in range(min(len(l1), len(l2), len(l3))):\n if l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n return [l1[i] for i in range(min(len(l1), len(l2), len(l3))) if l1[i] == l2[i] == l3[i]]", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n common = [i for i, j, k in zip(l1, l2, l3) if i == j == k]\n return common", "matching_cluster_idx": 7}, {"solution": "def extract_index_list(l1, l2, l3):\n common_elements = []\n for i in range(min(len(l1), len(l2), len(l3))):\n if l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n common = []\n for i in range(min(len(l1), len(l2), len(l3))):\n if l1[i] == l2[i] == l3[i]:\n common.append(l1[i])\n return common", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n # the built-in zip function combines lists into tuples at the same indexes.\n # Then, the next function compares the tuples' elements and returns a list of common elements.\n common = [a for a, b, c in zip(l1, l2, l3) if a == b == c]\n return common", "matching_cluster_idx": 7}, {"solution": "def extract_index_list(l1, l2, l3):\n common_elements = []\n for i in range(min(len(l1), len(l2), len(l3))):\n if l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n common_elements = []\n for i in range(min(len(l1), len(l2), len(l3))):\n if l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n result = []\n length = min(len(l1), len(l2), len(l3))\n for i in range(length):\n if l1[i] == l2[i] == l3[i]:\n result.append(l1[i])\n return result", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n common_elements = []\n min_length = min(len(l1), len(l2), len(l3))\n\n for i in range(min_length):\n if l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n common_elements = [a for a, b, c in zip(l1, l2, l3) if a == b == c]\n return common_elements", "matching_cluster_idx": 7}, {"solution": "def extract_index_list(l1, l2, l3):\n result = []\n for i in range(min(len(l1), len(l2), len(l3))):\n if l1[i] == l2[i] == l3[i]:\n result.append(l1[i])\n return result", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n common_elements = []\n for idx in range(min(len(l1), len(l2), len(l3))):\n if l1[idx] == l2[idx] == l3[idx]:\n common_elements.append(l1[idx])\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n common_elements = [l1[i] for i in range(min(len(l1), len(l2), len(l3))) if l1[i] == l2[i] == l3[i]]\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n common_elements = []\n for i in range(min(len(l1), len(l2), len(l3))):\n if l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n return [l1[i] for i in range(min(len(l1), len(l2), len(l3))) if l1[i] == l2[i] == l3[i]]", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n common_elements = [l1[i] for i in range(min(len(l1), len(l2), len(l3))) if l1[i] == l2[i] == l3[i]]\n return common_elements", "matching_cluster_idx": 6}]}, "Mbpp/755": {"dps": 68.53982300884955, "dps_norm": 81.66666666666667, "pass@1": 27.0, "profiled": [{"solution": "def second_smallest(numbers):\n \"\"\"\n This function finds the second smallest number in a list\n :param numbers: list of numbers\n :return: the second smallest number\n \"\"\"\n # handling edge case\n if len(numbers) < 2:\n return None\n\n # initializing first and second smallest number as infinity\n first, second = float('inf'), float('inf')\n\n # iterating over the list\n for num in numbers:\n # updating first and second smallest number if the number is smaller than first or second\n if num < first:\n second, first = first, num\n elif first < num < second:\n second = num\n\n # if there was no change of second after the iteration (i.e., all numbers in the list were equal), return None\n if second == float('inf'):\n return None\n\n return second", "matching_cluster_idx": 3}, {"solution": "def second_smallest(numbers):\n if len(numbers)<2:\n return None\n else:\n numbers=list(set(numbers))\n numbers.sort()\n if len(numbers)<2:\n return None\n else:\n return numbers[1]", "matching_cluster_idx": 5}, {"solution": "def second_smallest(numbers):\n # Remove duplicates\n numbers = list(set(numbers))\n\n # If the list contains less than 2 unique numbers\n if len(numbers) < 2:\n return None\n\n # Sort the list and return the second element\n numbers.sort()\n return numbers[1]", "matching_cluster_idx": 5}, {"solution": "def second_smallest(num_list):\n num_list = list(set(num_list))\n num_list.sort()\n if len(num_list) < 2:\n return None\n else:\n return num_list[1]", "matching_cluster_idx": 5}, {"solution": "def second_smallest(numbers):\n # first sort the list in ascending order\n sorted_nums = sorted(numbers)\n # then find the second smallest number by looping through the list\n # and checking if the current number is smaller than the second smallest\n second_smallest_number = None\n for num in sorted_nums:\n if num > sorted_nums[0] and (second_smallest_number is None or num < second_smallest_number):\n second_smallest_number = num\n return second_smallest_number", "matching_cluster_idx": 0}, {"solution": "def second_smallest(numbers):\n \"\"\"\n This function returns the second smallest number in a list.\n \"\"\"\n # Sort the list and remove duplicates\n numbers = list(set(numbers))\n numbers.sort()\n \n # If there's a least two elements in the list\n if len(numbers) > 1:\n return numbers[1]\n else:\n return None", "matching_cluster_idx": 5}, {"solution": "def second_smallest(numbers):\n \"\"\"\n Function to find the second smallest number in a list.\n It first removes duplicates from the list, sorts them in ascending order and returns the second element (index 1).\n \"\"\"\n # First remove duplicates\n numbers = list(set(numbers))\n\n # If there's only one unique number in the list, return None\n if len(numbers) < 2:\n return None\n else:\n numbers.sort()\n return numbers[1]", "matching_cluster_idx": 5}, {"solution": "def second_smallest(nums):\n nums.sort()\n unique_nums = list(set(nums))\n unique_nums.sort()\n if len(unique_nums) <= 1:\n return None\n else:\n return unique_nums[1]", "matching_cluster_idx": 2}, {"solution": "def second_smallest(nums):\n nums.sort()\n for num in nums:\n if num > nums[0]:\n return num\n return None", "matching_cluster_idx": 2}, {"solution": "def second_smallest(nums):\n # Remove duplicate numbers in the list\n nums = list(set(nums))\n # Handle the case where the list contains less than 2 elements\n if len(nums) < 2:\n return None\n # Sort the list in ascending order\n nums.sort()\n # Return the second element\n return nums[1]", "matching_cluster_idx": 5}, {"solution": "def second_smallest(lst):\n if len(lst) < 2:\n return None\n unique_lst = list(set(lst))\n unique_lst.sort()\n if len(unique_lst) < 2:\n return None\n else:\n return unique_lst[1]", "matching_cluster_idx": 5}, {"solution": "def second_smallest(numbers):\n first, second = float('inf'), float('inf')\n for number in numbers:\n if number < first:\n first, second = number, first\n elif number < second and number != first:\n second = number\n return second if second != float('inf') else None", "matching_cluster_idx": 4}, {"solution": "def second_smallest(nums):\n nums = list(set(nums)) # remove duplicates\n if len(nums) < 2:\n return None # not enough distinct numbers in the list\n smallest = second_smallest = float('inf')\n for num in nums:\n if num < smallest:\n second_smallest = smallest\n smallest = num\n elif second_smallest > num > smallest:\n second_smallest = num\n return second_smallest if second_smallest < float('inf') else None", "matching_cluster_idx": 3}, {"solution": "def second_smallest(numbers):\n numbers.sort()\n unique_numbers = list(set(numbers))\n unique_numbers.sort()\n if len(unique_numbers) > 1:\n return unique_numbers[1]\n else:\n return None", "matching_cluster_idx": 2}, {"solution": "def second_smallest(numbers):\n \"\"\"\n Return the second smallest number in the list.\n \"\"\"\n first_min = second_min = float('inf')\n for num in numbers:\n if num < first_min:\n second_min = first_min\n first_min = num\n elif num < second_min and num != first_min:\n second_min = num\n return second_min if second_min != float('inf') else None", "matching_cluster_idx": 4}, {"solution": "def second_smallest(num_list):\n # Get unique numbers from list\n unique_nums = list(set(num_list))\n \n # Check if we have more than one unique number\n if len(unique_nums) < 2:\n return None\n \n # Sort unique numbers and return the second one\n unique_nums.sort()\n return unique_nums[1]", "matching_cluster_idx": 5}, {"solution": "def second_smallest(numbers):\n if len(numbers)<2:\n return None\n first_min = second_min = float('inf')\n for number in numbers:\n if number < first_min:\n second_min = first_min\n first_min = number\n elif first_min>> remove_all_spaces('python program')\n 'pythonprogram'\n \"\"\"\n return s.replace(' ', '')", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(s):\n return s.replace(' ', '')", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(s):\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(s):\n return s.replace(' ', '')", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n return input_string.replace(' ', '')", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(str):\n return str.replace(\" \", \"\")", "matching_cluster_idx": 4}]}, "Mbpp/805": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 95.0, "profiled": [{"solution": "def max_sum_list(lst):\n return max(lst, key=sum)", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lst):\n max_sum = float('-inf')\n max_lst = None\n for sublist in lst:\n if sum(sublist) > max_sum:\n max_sum = sum(sublist)\n max_lst = sublist\n return max_lst", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lst):\n max_sum = -float('inf') # Initialize max sum to negative infinity\n max_list = None # Initialize max list to None\n\n # Iterate over each sub-list in the given list\n for sub_list in lst:\n sub_sum = sum(sub_list) # Calculate the sum of the current sub-list\n # If the sum of the current sub-list is greater than the max sum so far, update max sum and max list\n if sub_sum > max_sum:\n max_sum = sub_sum\n max_list = sub_list\n\n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lst):\n return max(lst, key=sum)", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lst):\n return max(lst, key=sum)", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(input_list):\n max_sum = float('-inf')\n max_list = []\n for lst in input_list:\n if sum(lst) > max_sum:\n max_sum = sum(lst)\n max_list = lst\n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(l):\n return max(l, key=sum)", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(list_of_lists):\n max_sum = -float('inf')\n max_sum_list = None\n \n for sublist in list_of_lists:\n if sum(sublist) > max_sum:\n max_sum = sum(sublist)\n max_sum_list = sublist\n \n return max_sum_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(list_of_lists):\n return max(list_of_lists, key=sum)", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lst):\n \"\"\"\n Returns the list with the maximum sum of its elements.\n \"\"\"\n # Initialize the maximum sum and corresponding list to the first list in the list of lists.\n max_sum = sum(lst[0])\n max_list = lst[0]\n\n # Loop through each list in the list of lists.\n for l in lst:\n # Check if the sum of the current list is higher than the current maximum sum.\n if sum(l) > max_sum:\n # If so, update the maximum sum and corresponding list.\n max_sum = sum(l)\n max_list = l\n\n # Return the list with the maximum sum of elements.\n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lst):\n return max(lst, key=sum)", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lst):\n max_sum = -float('inf')\n max_list = []\n for sublist in lst:\n if sum(sublist) > max_sum:\n max_sum = sum(sublist)\n max_list = sublist\n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(list_of_lists):\n return max(list_of_lists, key=sum)", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lst):\n return max(lst, key=sum)", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lst):\n # Define a variable that will hold the maximum sum of elements of a sublist\n max_sum = float('-inf')\n \n # Define a variable that will hold the sublist with the maximum sum of elements\n max_sum_list = None\n \n # Iterate through each sublist in the input list\n for sublist in lst:\n # Calculate the sum of the elements in the current sublist\n sum_sublist = sum(sublist)\n \n # If the current sublist has a higher sum than the previous maximum\n if sum_sublist > max_sum:\n # Update the maximum sum and the sublist with the maximum sum\n max_sum = sum_sublist\n max_sum_list = sublist\n \n # Return the sublist with the maximum sum of elements\n return max_sum_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n \"\"\"Return the list in a list of lists with the highest sum of elements.\"\"\"\n return max(lists, key=sum)", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(list_of_lists):\n return max(list_of_lists, key=sum)", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(list_of_lists):\n return max(list_of_lists, key=sum)", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(list_of_lists):\n return max(list_of_lists, key=sum)", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lst):\n # Initialize maximum sum and the result list\n max_sum = float('-inf')\n result = []\n \n # Iterate over each list in the input list\n for sub_list in lst:\n # Calculate the sum of current sublist\n curr_sum = sum(sub_list)\n \n # If the current sublist has a higher sum, update max_sum and result\n if curr_sum > max_sum:\n max_sum = curr_sum\n result = sub_list\n \n return result", "matching_cluster_idx": 4}]}, "Mbpp/808": {"dps": 96.53508771929825, "dps_norm": 99.16666666666667, "pass@1": 92.0, "profiled": [{"solution": "def check_K(tpl, k):\n if k in tpl:\n return True\n else:\n return False", "matching_cluster_idx": 5}, {"solution": "def check_K(tuple_input, k):\n if k in tuple_input:\n return True\n else:\n return False", "matching_cluster_idx": 5}, {"solution": "def check_K(t, k):\n \"\"\"\n This function checks if the given tuple contains the value of k or not.\n \"\"\"\n return k in t", "matching_cluster_idx": 5}, {"solution": "def check_K(tpl, k):\n return k in tpl", "matching_cluster_idx": 4}, {"solution": "def check_K(tup, k):\n \"\"\"\n Check if the given tuples contain the k.\n :param tup: input tuple\n :param k: value to check in the tuple\n :return: boolean whether the k exists in the tuple or not\n \"\"\"\n if k in tup:\n return True\n else:\n return False", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n \"\"\"\n Function to check if the given tuple contains the k\n :param tup: Input tuple\n :param k: the number to check\n :return: True if k is in the tuple, False otherwise\n \"\"\"\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n if k in tup:\n return True\n else:\n return False", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(tuple, k):\n if k in tuple:\n return True\n else:\n return False", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(tuple, k):\n return k in tuple", "matching_cluster_idx": 5}, {"solution": "def check_K(tuples, k):\n return k in tuples", "matching_cluster_idx": 5}, {"solution": "def check_K(tuple, k):\n return k in tuple", "matching_cluster_idx": 5}, {"solution": "def check_K(t, k):\n return k in t", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(tuples, k):\n return k in tuples", "matching_cluster_idx": 5}, {"solution": "def check_K(tuple_k, k):\n \"\"\"\n Function that checks if k is in the given tuple\n \"\"\"\n return k in tuple_k", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(tuple1, k):\n return k in tuple1", "matching_cluster_idx": 5}]}}} \ No newline at end of file diff --git a/results/evalperf/meta-llama--Llama-3.1-70B-Instruct_vllm_temp_1.0_evalperf_results.brief.json b/results/evalperf/meta-llama--Llama-3.1-70B-Instruct_vllm_temp_1.0_evalperf_results.brief.json new file mode 100644 index 0000000..6cae6fe --- /dev/null +++ b/results/evalperf/meta-llama--Llama-3.1-70B-Instruct_vllm_temp_1.0_evalperf_results.brief.json @@ -0,0 +1 @@ +{"date": "2024-10-19 16:28", "config": {"n_samples": 100, "temperature": 1.0, "min_correct": 10, "max_profile": 20}, "summary": {"dps": 80.40042339048047, "dps_norm": 77.29818188061222, "pass@1": 77.26271186440678}, "eval": {"HumanEval/9": {"dps": 79.3217665615142, "dps_norm": 78.88888888888889, "pass@1": 98.0, "profiled": [{"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\"\n From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n \n Args:\n numbers (List[int]): A list of integers.\n\n Returns:\n List[int]: A list of rolling maximum elements.\n\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n # Handle edge case where input list is empty\n if not numbers:\n return []\n\n # Initialize result list with first element of numbers\n result = [numbers[0]]\n\n # Initialize rolling maximum with first element of numbers\n rolling_max_val = numbers[0]\n\n # Iterate over the rest of the numbers\n for num in numbers[1:]:\n # Update rolling maximum if current number is larger\n if num > rolling_max_val:\n rolling_max_val = num\n # Append rolling maximum to result list\n result.append(rolling_max_val)\n\n return result", "matching_cluster_idx": 8}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\"\n From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n\n Args:\n numbers (List[int]): A list of integers.\n\n Returns:\n List[int]: A list of rolling maximum element found until given moment in the sequence.\n \"\"\"\n if not numbers: # edge case: return empty list when input is empty\n return []\n\n max_values = [numbers[0]] # initialize the list with the first element\n max_value = numbers[0] # initialize max_value as the first element\n\n for num in numbers[1:]:\n max_values.append(max(max_value, num)) # append the maximum value\n max_value = max(max_value, num) # update max_value\n\n return max_values", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\"\n From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n\n Args:\n numbers (List[int]): A list of integers.\n\n Returns:\n List[int]: A list of rolling maximum elements.\n \"\"\"\n if not numbers: # Check if input list is empty\n return []\n\n max_elements = [numbers[0]] # Initialize the list of max elements with the first element of input list\n\n for num in numbers[1:]: # Iterate over the rest of the input list\n max_elements.append(max(max_elements[-1], num)) # Append the maximum between last max element and current number\n\n return max_elements", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\"\n From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n\n Args:\n numbers: A list of integers.\n\n Returns:\n A list of integers, where each element at index i is the maximum element from the sub-list numbers[:i+1].\n \"\"\"\n if not numbers:\n return []\n\n max_values = [numbers[0]]\n current_max = numbers[0]\n\n for num in numbers[1:]:\n current_max = max(current_max, num)\n max_values.append(current_max)\n\n return max_values\nnumbers = [1, 2, 3, 2, 3, 4, 2]", "matching_cluster_idx": 4}, {"solution": "from typing import List\nimport unittest\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\"\n From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n\n Args:\n numbers (List[int]): A list of integers.\n\n Returns:\n List[int]: A list of rolling maximum elements.\n\n Example:\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n\n rolling_max_list = [numbers[0]]\n current_max = numbers[0]\n\n for num in numbers[1:]:\n current_max = max(current_max, num)\n rolling_max_list.append(current_max)\n\n return rolling_max_list", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\"\n From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n\n Args:\n numbers (List[int]): A list of integers.\n\n Returns:\n List[int]: A list of rolling maximum element found until given moment in the sequence.\n \"\"\"\n if not numbers:\n return []\n\n max_values = []\n current_max = numbers[0]\n\n for num in numbers:\n current_max = max(current_max, num)\n max_values.append(current_max)\n\n return max_values", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\"\n From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n\n Args:\n numbers (List[int]): A list of integers.\n\n Returns:\n List[int]: A list of rolling maximum elements.\n \"\"\"\n if not numbers:\n return []\n\n # Initialize the result list with the first number, which is the maximum at this point\n result = [numbers[0]]\n\n # Iterate through the rest of the numbers\n for num in numbers[1:]:\n # If the current number is greater than the last rolling maximum, update the rolling maximum\n if num > result[-1]:\n result.append(num)\n # Otherwise, the rolling maximum remains the same\n else:\n result.append(result[-1])\n\n return result", "matching_cluster_idx": 7}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\"\n Generate a list of rolling maximum elements found until the given moment in the sequence.\n\n Args:\n numbers (List[int]): A list of integers.\n\n Returns:\n List[int]: A list of rolling maximum elements.\n\n Examples:\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n\n # Initialize an empty list to store the rolling maximums\n rolling_maxima = []\n\n # Initialize the rolling maximum to negative infinity\n current_max = float('-inf')\n\n # Iterate over the input list of numbers\n for num in numbers:\n # Update the rolling maximum if a larger number is found\n current_max = max(current_max, num)\n \n # Append the current rolling maximum to the result list\n rolling_maxima.append(current_max)\n\n return rolling_maxima", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\"\n From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n\n Args:\n numbers (List[int]): A list of integers.\n\n Returns:\n List[int]: A list of rolling maximum elements.\n\n Example:\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n\n rolling_maximums = [numbers[0]]\n current_max = numbers[0]\n\n for num in numbers[1:]:\n if num > current_max:\n current_max = num\n rolling_maximums.append(current_max)\n\n return rolling_maximums", "matching_cluster_idx": 8}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\"\n From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n\n Args:\n numbers (List[int]): A list of integers.\n\n Returns:\n List[int]: A list of rolling maximum elements.\n\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n \n max_so_far = numbers[0]\n rolling_max_list = [max_so_far]\n \n for num in numbers[1:]:\n max_so_far = max(max_so_far, num)\n rolling_max_list.append(max_so_far)\n \n return rolling_max_list", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\"\n From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n\n Args:\n numbers: A list of integers.\n\n Returns:\n A list of integers representing the rolling maximum element found until each given moment.\n\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n\n rolling_max_values = [numbers[0]]\n\n for num in numbers[1:]:\n rolling_max_values.append(max(rolling_max_values[-1], num))\n\n return rolling_max_values", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\"\n From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n\n Args:\n numbers (List[int]): A list of integers.\n\n Returns:\n List[int]: A list of rolling maximum element found until given moment in the sequence.\n \"\"\"\n if not numbers:\n return []\n\n max_until_now = numbers[0]\n result = [max_until_now]\n\n for num in numbers[1:]:\n if num > max_until_now:\n max_until_now = num\n result.append(max_until_now)\n\n return result", "matching_cluster_idx": 8}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\"\n Generate a list of rolling maximum element found until given moment in the sequence.\n\n Args:\n numbers (List[int]): A list of integers.\n\n Returns:\n List[int]: A list of rolling maximum elements.\n\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n\n max_list = [numbers[0]]\n current_max = numbers[0]\n\n for num in numbers[1:]:\n if num > current_max:\n current_max = num\n max_list.append(current_max)\n\n return max_list", "matching_cluster_idx": 8}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\"\n From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n\n Args:\n numbers (List[int]): A list of integers.\n\n Returns:\n List[int]: A list of rolling maximum elements.\n \"\"\"\n if not numbers:\n return []\n\n max_list = [numbers[0]]\n current_max = numbers[0]\n\n for num in numbers[1:]:\n if num > current_max:\n current_max = num\n max_list.append(current_max)\n\n return max_list", "matching_cluster_idx": 8}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\"\n From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n\n Args:\n numbers (List[int]): A list of integers.\n\n Returns:\n List[int]: A list of rolling maximum element found until given moment in the sequence.\n \"\"\"\n if not numbers:\n return []\n\n # Initialize the result list with the first element of the input list\n result = [numbers[0]]\n\n # Initialize the maximum element with the first element of the input list\n max_element = numbers[0]\n\n # Iterate through the input list starting from the second element\n for num in numbers[1:]:\n # Update the maximum element if a larger number is found\n if num > max_element:\n max_element = num\n # Append the current maximum element to the result list\n result.append(max_element)\n\n return result", "matching_cluster_idx": 8}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\"\n From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n\n Args:\n numbers (List[int]): A list of integers.\n\n Returns:\n List[int]: A list of rolling maximum elements.\n \"\"\"\n if not numbers:\n return []\n\n rolling_max_values = []\n current_max = numbers[0]\n\n for num in numbers:\n current_max = max(current_max, num)\n rolling_max_values.append(current_max)\n\n return rolling_max_values", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\"\n From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n\n Args:\n numbers (List[int]): A list of integers.\n\n Returns:\n List[int]: A list of rolling maximum elements.\n \"\"\"\n if not numbers:\n return []\n\n max_values = [numbers[0]]\n current_max = numbers[0]\n\n for num in numbers[1:]:\n if num > current_max:\n current_max = num\n max_values.append(current_max)\n\n return max_values", "matching_cluster_idx": 8}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\"\n From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n \n Args:\n numbers: A list of integers\n \n Returns:\n A list of integers representing the rolling maximum\n \"\"\"\n if not numbers:\n return []\n \n max_values = [numbers[0]]\n current_max = numbers[0]\n \n for num in numbers[1:]:\n if num > current_max:\n current_max = num\n max_values.append(current_max)\n \n return max_values", "matching_cluster_idx": 8}, {"solution": "from typing import List\nimport unittest\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\"\n Generate a list of rolling maximum element found until given moment in the sequence.\n\n Args:\n numbers: A list of integers.\n\n Returns:\n A list of rolling maximum elements.\n \"\"\"\n if not numbers:\n return []\n\n max_elements = [numbers[0]]\n current_max = numbers[0]\n\n for num in numbers[1:]:\n if num > current_max:\n current_max = num\n max_elements.append(current_max)\n\n return max_elements", "matching_cluster_idx": 8}, {"solution": "from typing import List\nimport unittest\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\"\n From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n\n Args:\n numbers (List[int]): A list of integers.\n\n Returns:\n List[int]: A list of rolling maximum elements.\n \"\"\"\n if not numbers:\n return []\n\n max_values = [numbers[0]]\n current_max = numbers[0]\n\n for num in numbers[1:]:\n if num > current_max:\n current_max = num\n max_values.append(current_max)\n\n return max_values", "matching_cluster_idx": 8}]}, "HumanEval/0": {"dps": 49.70930232558139, "dps_norm": 54.28571428571429, "pass@1": 70.0, "profiled": [{"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\"\n Checks if in given list of numbers, are any two numbers closer to each other than the given threshold.\n\n Args:\n numbers (List[float]): The list of floating point numbers.\n threshold (float): The minimum distance required between numbers.\n\n Returns:\n bool: True if two numbers are closer than the threshold, False otherwise.\n \"\"\"\n numbers.sort() # sort the list in ascending order\n for i in range(len(numbers) - 1): # iterate through the list, excluding the last element\n if numbers[i + 1] - numbers[i] < threshold: # check if the difference between adjacent numbers is less than the threshold\n return True # if it is, return True\n return False # if no adjacent numbers are closer than the threshold, return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\"\n Check if in given list of numbers, are any two numbers closer to each other than given threshold.\n\n Args:\n numbers (List[float]): List of floating point numbers.\n threshold (float): Minimum distance required between two numbers.\n\n Returns:\n bool: True if any two numbers are closer than the threshold, False otherwise.\n \"\"\"\n # First, sort the list of numbers\n numbers.sort()\n\n # Iterate through the sorted list and check the difference between adjacent numbers\n for i in range(len(numbers) - 1):\n # If the difference is less than the threshold, return True\n if numbers[i + 1] - numbers[i] < threshold:\n return True\n\n # If no such pair is found, return False\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\"\n Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n\n Args:\n numbers (List[float]): A list of floating point numbers.\n threshold (float): The minimum distance between two numbers.\n\n Returns:\n bool: True if there are two numbers in the list with a distance less than the threshold.\n \"\"\"\n # First, sort the list of numbers in ascending order\n numbers.sort()\n \n # Iterate through the sorted list, checking the difference between each pair of adjacent numbers\n for i in range(len(numbers) - 1):\n # If the difference is less than the threshold, return True immediately\n if numbers[i + 1] - numbers[i] < threshold:\n return True\n \n # If no pair of numbers with a distance less than the threshold is found, return False\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\"\n Check if in given list of numbers, are any two numbers closer to each other than given threshold.\n\n Args:\n numbers (List[float]): A list of numbers.\n threshold (float): A minimum distance between two numbers.\n\n Returns:\n bool: True if any two numbers are closer to each other than threshold, False otherwise.\n \"\"\"\n # First, we need to sort the list in ascending order\n numbers.sort()\n\n # Iterate over the sorted list with index and value\n for i in range(len(numbers) - 1):\n # Check the difference between current number and the next one\n if numbers[i + 1] - numbers[i] < threshold:\n # If difference is less than threshold, return True\n return True\n\n # If no such pair found, return False\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\nimport doctest\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\"\n Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n\n Args:\n numbers (List[float]): A list of numbers.\n threshold (float): The maximum allowed distance between two numbers.\n\n Returns:\n bool: True if at least two numbers are closer than the threshold, False otherwise.\n \"\"\"\n # Sort the list of numbers\n numbers.sort()\n\n # Iterate over the sorted list and check each pair of adjacent numbers\n for i in range(len(numbers) - 1):\n # If the difference between two numbers is less than the threshold, return True\n if numbers[i + 1] - numbers[i] < threshold:\n return True\n\n # If no pair of numbers closer than the threshold was found, return False\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\"\n Check if in the given list of numbers, are any two numbers closer to each other than\n the given threshold.\n\n Args:\n numbers (List[float]): A list of floating point numbers.\n threshold (float): The minimum difference required between two numbers.\n\n Returns:\n bool: True if there are two numbers closer than the threshold, False otherwise.\n \"\"\"\n\n # First, sort the list in ascending order\n numbers.sort()\n\n # Iterate over the sorted list to check the difference between adjacent numbers\n for i in range(len(numbers) - 1):\n # If the difference between two adjacent numbers is less than the threshold, return True\n if numbers[i + 1] - numbers[i] < threshold:\n return True\n\n # If no pairs are found with a difference less than the threshold, return False\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\"\n Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n\n Args:\n numbers (List[float]): A list of floating point numbers.\n threshold (float): The minimum difference between two numbers.\n\n Returns:\n bool: True if any two numbers are closer than the threshold, False otherwise.\n \"\"\"\n numbers.sort() # Sort the list to ensure we can efficiently compare adjacent numbers\n for i in range(1, len(numbers)): # Iterate over the sorted list\n if numbers[i] - numbers[i - 1] < threshold: # Check if the difference is less than the threshold\n return True # Return True as soon as we find a pair of numbers closer than the threshold\n return False # If no such pair is found, return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\"\n Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n\n Args:\n numbers: A list of float numbers.\n threshold: The minimum distance required between two numbers.\n\n Returns:\n True if any two numbers in the list are closer than the given threshold, False otherwise.\n \"\"\"\n\n # Sort the list of numbers\n numbers.sort()\n\n # Iterate over the sorted list of numbers\n for i in range(len(numbers) - 1):\n # Calculate the difference between current and next number\n difference = numbers[i + 1] - numbers[i]\n \n # If the difference is less than the threshold, return True\n if difference < threshold:\n return True\n\n # If no pairs of numbers closer than the threshold are found, return False\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\"\n Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n\n Args:\n numbers (List[float]): A list of floating-point numbers.\n threshold (float): The minimum allowed difference between two numbers.\n\n Returns:\n bool: True if at least two numbers are closer than the threshold, False otherwise.\n \"\"\"\n # Sort the list of numbers in ascending order\n numbers.sort()\n \n # Iterate over the sorted list to find pairs of numbers closer than the threshold\n for i in range(1, len(numbers)):\n if numbers[i] - numbers[i - 1] < threshold:\n return True\n \n # If no pairs are found, return False\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\"\n Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n\n Args:\n numbers: List[float] - A list of numbers to check.\n threshold: float - Maximum allowed distance between two numbers.\n\n Returns:\n bool - True if any two numbers are closer than the threshold, False otherwise.\n \"\"\"\n # First, sort the list in ascending order\n numbers.sort()\n\n # Iterate through the sorted list, comparing each pair of adjacent numbers\n for i in range(len(numbers) - 1):\n # If the difference between any pair of adjacent numbers is less than the threshold, return True\n if abs(numbers[i] - numbers[i+1]) < threshold:\n return True\n\n # If we've checked all pairs of adjacent numbers without returning, no pair is closer than the threshold\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\"\n Check if in the given list of numbers, are any two numbers closer to each other than\n the given threshold.\n\n Args:\n numbers (List[float]): A list of floating point numbers.\n threshold (float): The minimum distance between two numbers.\n\n Returns:\n bool: True if any two numbers are closer than the threshold, False otherwise.\n \"\"\"\n # Sort the list of numbers\n numbers.sort()\n\n # Iterate over the sorted list of numbers\n for i in range(1, len(numbers)):\n # Check if the difference between current number and previous number is less than threshold\n if numbers[i] - numbers[i - 1] < threshold:\n # If it is, return True immediately\n return True\n\n # If we've iterated over the entire list and haven't found any close elements, return False\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\"\n Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n\n Args:\n numbers (List[float]): A list of floating point numbers.\n threshold (float): The threshold to check for proximity.\n\n Returns:\n bool: True if any two numbers are closer than the threshold, False otherwise.\n \"\"\"\n numbers.sort() # Sort the list to enable efficient pair comparison\n\n for i in range(len(numbers) - 1):\n # If the difference between two adjacent numbers is less than the threshold, return True\n if numbers[i + 1] - numbers[i] < threshold:\n return True\n\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\"\n Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n\n Args:\n numbers (List[float]): A list of floating point numbers.\n threshold (float): The minimum distance between two numbers.\n\n Returns:\n bool: True if any two numbers in the list are closer than the threshold, False otherwise.\n \"\"\"\n # First, sort the list of numbers\n numbers.sort()\n\n # Iterate over the sorted list of numbers\n for i in range(len(numbers) - 1):\n # Check if the difference between two adjacent numbers is less than the threshold\n if abs(numbers[i] - numbers[i + 1]) < threshold:\n return True\n\n # If the function hasn't returned yet, then no two numbers are closer than the threshold\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\"\n Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n\n Args:\n numbers (List[float]): List of floating point numbers\n threshold (float): Maximum allowed distance between two numbers\n\n Returns:\n bool: True if there are numbers within the threshold, False otherwise\n \"\"\"\n numbers.sort() # Sort the list of numbers to reduce search space\n for i in range(len(numbers) - 1): # Iterate over each number in the sorted list\n # Check if the difference between current and next number is less than the threshold\n if numbers[i + 1] - numbers[i] < threshold:\n return True # Return True if a pair of close numbers is found\n return False # Return False if no close numbers are found", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\"\n Check if in given list of numbers, are any two numbers closer to each other than given threshold.\n\n Args:\n numbers (List[float]): List of floating point numbers.\n threshold (float): Threshold distance.\n\n Returns:\n bool: True if any two numbers in the list are closer than the threshold, False otherwise.\n \"\"\"\n numbers.sort() # Sort the list of numbers to ensure we only need to compare adjacent numbers\n for i in range(len(numbers) - 1): # Iterate over the list of numbers\n if abs(numbers[i] - numbers[i+1]) < threshold: # Check if the difference between two adjacent numbers is less than the threshold\n return True # If it is, return True\n return False # If no such pair is found, return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\nimport itertools\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\"\n Check if in the given list of numbers, any two numbers are closer to each other than the given threshold.\n\n Args:\n numbers (List[float]): A list of floating point numbers.\n threshold (float): The minimum distance required between any two numbers.\n\n Returns:\n bool: True if at least two numbers are closer than the threshold, False otherwise.\n \"\"\"\n # Generate all possible pairs of numbers\n pairs = list(itertools.combinations(numbers, 2))\n\n # Check the distance between each pair of numbers\n for num1, num2 in pairs:\n # If the distance between two numbers is less than the threshold, return True\n if abs(num1 - num2) < threshold:\n return True\n\n # If no pairs of numbers are closer than the threshold, return False\n return False", "matching_cluster_idx": -1}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\"\n Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n\n Args:\n numbers (List[float]): A list of floating point numbers.\n threshold (float): A minimum distance between numbers.\n\n Returns:\n bool: True if at least two numbers are closer than the threshold, False otherwise.\n \"\"\"\n # Sort the list of numbers\n numbers.sort()\n \n # Iterate through the sorted list to compare adjacent elements\n for i in range(len(numbers) - 1):\n # Check if the difference between two adjacent numbers is less than the threshold\n if numbers[i + 1] - numbers[i] < threshold:\n return True\n \n # If no close elements were found, return False\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\"\n Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n\n Args:\n numbers (List[float]): The list of numbers.\n threshold (float): The minimum distance for two numbers to be considered close.\n\n Returns:\n bool: True if there are two numbers closer than the threshold, False otherwise.\n \"\"\"\n # Sort the list to find the closest numbers\n numbers.sort()\n\n # Iterate through the sorted list to find close elements\n for i in range(len(numbers) - 1):\n if abs(numbers[i + 1] - numbers[i]) < threshold:\n return True\n\n # If we have not found any close elements, return False\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\"\n Check if in given list of numbers, are any two numbers closer to each other than given threshold.\n\n Args:\n - numbers: A list of float numbers.\n - threshold: A float number that defines the proximity threshold.\n\n Returns:\n - bool: True if there are two numbers closer than threshold, False otherwise.\n \"\"\"\n\n # First, we sort the list in ascending order\n numbers.sort()\n\n # Iterate over the sorted list\n for i in range(len(numbers) - 1):\n # Calculate the absolute difference between two consecutive numbers\n difference = abs(numbers[i] - numbers[i + 1])\n \n # If difference is less than threshold, return True immediately\n if difference < threshold:\n return True\n\n # If loop completes without finding any close elements, return False\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\"\n Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n\n Args:\n numbers: A list of floating point numbers.\n threshold: The minimum distance between two numbers.\n\n Returns:\n True if there are two numbers closer than the threshold, False otherwise.\n \"\"\"\n numbers.sort() # Sort the list of numbers\n for i in range(len(numbers) - 1): # Iterate over the sorted list\n if numbers[i + 1] - numbers[i] < threshold: # Check the difference between adjacent numbers\n return True # If the difference is less than the threshold, return True\n return False # If no such pair is found, return False", "matching_cluster_idx": 3}]}, "HumanEval/4": {"dps": 19.20886075949367, "dps_norm": 36.666666666666664, "pass@1": 100.0, "profiled": [{"solution": "from typing import List\nimport statistics\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\"\n For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n Args:\n numbers: A list of float numbers\n Returns:\n Mean Absolute Deviation as float\n \"\"\"\n # Calculate mean\n mean = statistics.mean(numbers)\n\n # Calculate absolute differences between each element and the mean\n differences = [abs(num - mean) for num in numbers]\n\n # Calculate the average of these differences (MAD)\n mad = sum(differences) / len(numbers)\n\n return mad", "matching_cluster_idx": 0}, {"solution": "from typing import List\nimport statistics\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\"\n For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n\n MAD = average | x - x_mean |\n\n Args:\n numbers (List[float]): A list of float numbers.\n\n Returns:\n float: The Mean Absolute Deviation of the input numbers.\n\n Raises:\n ValueError: If the input list is empty.\n \"\"\"\n # Check if the input list is not empty\n if not numbers:\n raise ValueError(\"Input list cannot be empty\")\n\n # Calculate the mean of the numbers\n mean = statistics.mean(numbers)\n\n # Calculate the absolute differences from the mean\n absolute_differences = [abs(x - mean) for x in numbers]\n\n # Calculate the Mean Absolute Deviation\n mad = statistics.mean(absolute_differences)\n\n return mad\nnumbers = [1.0, 2.0, 3.0, 4.0]", "matching_cluster_idx": 0}, {"solution": "from typing import List\nimport statistics\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\"\n For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n \n Args:\n numbers: A list of input numbers.\n \n Returns:\n Mean Absolute Deviation as a float.\n \"\"\"\n \n # Calculate the mean of the input list\n mean = statistics.mean(numbers)\n \n # Calculate absolute differences between each element and the mean\n absolute_diffs = [abs(num - mean) for num in numbers]\n \n # Calculate the average of absolute differences\n mad = statistics.mean(absolute_diffs)\n \n return mad", "matching_cluster_idx": 0}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\"\n Calculate the Mean Absolute Deviation of a given list of numbers.\n\n The Mean Absolute Deviation is the average absolute difference between each\n element and the mean of the dataset.\n\n Args:\n numbers: A list of float numbers.\n\n Returns:\n A float representing the Mean Absolute Deviation.\n\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n\n # Calculate the mean of the input numbers\n mean = sum(numbers) / len(numbers)\n\n # Calculate the absolute deviations from the mean\n absolute_deviations = [abs(num - mean) for num in numbers]\n\n # Calculate the mean of the absolute deviations\n mad = sum(absolute_deviations) / len(absolute_deviations)\n\n return mad", "matching_cluster_idx": 4}, {"solution": "from typing import List\nimport statistics\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\"\n For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n\n Args:\n numbers (List[float]): A list of input numbers\n\n Returns:\n float: The calculated Mean Absolute Deviation\n\n Example:\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n # Calculate the mean of the input numbers\n mean = statistics.mean(numbers)\n \n # Calculate the absolute differences between each element and the mean\n absolute_deviations = [abs(x - mean) for x in numbers]\n \n # Calculate the average of the absolute deviations\n mad = statistics.mean(absolute_deviations)\n \n return mad\nnumbers = [1.0, 2.0, 3.0, 4.0]", "matching_cluster_idx": 0}, {"solution": "from typing import List\nimport statistics\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\"\n For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n\n Args:\n numbers (List[float]): Input list of numbers.\n\n Returns:\n float: Mean Absolute Deviation of the input numbers.\n \"\"\"\n # Calculate the mean of the input list\n mean = statistics.mean(numbers)\n \n # Use a list comprehension to calculate the absolute difference of each element from the mean\n absolute_deviations = [abs(num - mean) for num in numbers]\n \n # Calculate the mean of the absolute deviations\n mad = statistics.mean(absolute_deviations)\n \n return mad", "matching_cluster_idx": 0}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\"\n Calculate Mean Absolute Deviation around the mean of a given dataset.\n \n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n \n Args:\n numbers (List[float]): A list of float numbers.\n \n Returns:\n float: The Mean Absolute Deviation of the input dataset.\n \"\"\"\n \n # Check if the input list is empty\n if not numbers:\n raise ValueError(\"Input list cannot be empty\")\n \n # Calculate the mean of the dataset\n mean = sum(numbers) / len(numbers)\n \n # Calculate absolute differences between each element and the mean\n absolute_deviations = [abs(num - mean) for num in numbers]\n \n # Calculate the mean of the absolute deviations\n mad = sum(absolute_deviations) / len(absolute_deviations)\n \n return mad", "matching_cluster_idx": 3}, {"solution": "from typing import List\nimport statistics\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\"\n Calculate the Mean Absolute Deviation of a given list of numbers.\n \n The Mean Absolute Deviation is the average absolute difference between each\n element and the mean of the dataset.\n \n Args:\n numbers (List[float]): A list of floating point numbers.\n \n Returns:\n float: The Mean Absolute Deviation of the input numbers.\n \"\"\"\n \n # Check if the input list is empty\n if not numbers:\n raise ValueError(\"Input list cannot be empty\")\n \n # Calculate the mean of the numbers\n mean = statistics.mean(numbers)\n \n # Calculate the absolute difference of each number from the mean\n absolute_diffs = [abs(num - mean) for num in numbers]\n \n # Calculate the mean of the absolute differences\n mad = statistics.mean(absolute_diffs)\n \n return mad\nnumbers = [1.0, 2.0, 3.0, 4.0]", "matching_cluster_idx": 0}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\"\n Calculate the Mean Absolute Deviation around the mean of the dataset.\n\n Args:\n numbers (List[float]): A list of floating point numbers.\n\n Returns:\n float: The Mean Absolute Deviation.\n\n Raises:\n ValueError: If the input list is empty.\n \"\"\"\n if not numbers:\n raise ValueError(\"Input list cannot be empty\")\n\n # Calculate the mean of the numbers\n mean = sum(numbers) / len(numbers)\n\n # Calculate the absolute deviations from the mean\n deviations = [abs(num - mean) for num in numbers]\n\n # Calculate the mean of the absolute deviations\n mad = sum(deviations) / len(deviations)\n\n return mad\nnumbers = [1.0, 2.0, 3.0, 4.0]", "matching_cluster_idx": 3}, {"solution": "from typing import List\nimport statistics\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\"\n For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n\n Args:\n numbers (List[float]): A list of numbers.\n\n Returns:\n float: The Mean Absolute Deviation.\n \"\"\"\n # First, calculate the mean of the input numbers\n mean = statistics.mean(numbers)\n \n # Then, calculate the absolute difference between each number and the mean\n absolute_deviations = [abs(num - mean) for num in numbers]\n \n # Finally, calculate the mean of these absolute deviations\n mad = statistics.mean(absolute_deviations)\n \n return mad", "matching_cluster_idx": 0}, {"solution": "from typing import List\nimport statistics\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\"\n For a given list of input numbers, calculate Mean Absolute Deviation around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n\n Args:\n numbers (List[float]): List of input numbers.\n\n Returns:\n float: Mean Absolute Deviation.\n\n Example:\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n # Calculate mean\n mean_value = statistics.mean(numbers)\n \n # Calculate absolute differences\n absolute_diffs = [abs(num - mean_value) for num in numbers]\n \n # Calculate mean of absolute differences\n mad_value = statistics.mean(absolute_diffs)\n \n return mad_value\nnumbers = [1.0, 2.0, 3.0, 4.0]", "matching_cluster_idx": 0}, {"solution": "from typing import List\nimport unittest\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\"\n For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n\n Args:\n numbers (List[float]): A list of numbers.\n\n Returns:\n float: The Mean Absolute Deviation.\n\n Raises:\n ValueError: If the input list is empty.\n \"\"\"\n\n # Check if the input list is empty\n if not numbers:\n raise ValueError(\"Input list cannot be empty.\")\n\n # Calculate the mean of the input numbers\n mean = sum(numbers) / len(numbers)\n\n # Calculate the absolute difference between each element and the mean\n absolute_deviations = [abs(num - mean) for num in numbers]\n\n # Calculate the Mean Absolute Deviation\n mad = sum(absolute_deviations) / len(absolute_deviations)\n\n return mad", "matching_cluster_idx": 5}, {"solution": "from typing import List\nimport statistics\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\"\n For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n \n Args:\n numbers (List[float]): A list of floating point numbers.\n\n Returns:\n float: Mean Absolute Deviation of the given list of numbers.\n \"\"\"\n\n # Check if input list is empty\n if not numbers:\n raise ValueError(\"Input list cannot be empty\")\n\n # Calculate the mean of the numbers\n mean = statistics.mean(numbers)\n\n # Calculate the absolute difference between each number and the mean\n absolute_deviations = [abs(num - mean) for num in numbers]\n\n # Calculate the mean of the absolute deviations\n mad = statistics.mean(absolute_deviations)\n\n return mad", "matching_cluster_idx": 0}, {"solution": "from typing import List\nimport statistics\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\"\n For a given list of input numbers, calculate Mean Absolute Deviation around the mean of this dataset.\n\n Mean Absolute Deviation is the average absolute difference between each element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n\n Args:\n numbers (List[float]): The input list of numbers.\n\n Returns:\n float: The Mean Absolute Deviation of the input numbers.\n\n Examples:\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n\n # Calculate the mean of the numbers\n mean = statistics.mean(numbers)\n\n # Calculate the absolute difference of each element from the mean\n absolute_diffs = [abs(num - mean) for num in numbers]\n\n # Calculate the mean of the absolute differences\n mad = statistics.mean(absolute_diffs)\n\n return mad", "matching_cluster_idx": 0}, {"solution": "from typing import List\nimport statistics\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\"\n For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n \n Args:\n numbers (List[float]): A list of input numbers.\n \n Returns:\n float: Mean Absolute Deviation of the input numbers.\n \"\"\"\n \n # First, calculate the mean of the input numbers\n mean = statistics.mean(numbers)\n \n # Then, calculate the absolute deviation of each number from the mean\n deviations = [abs(num - mean) for num in numbers]\n \n # Finally, calculate the mean of these deviations\n mad = statistics.mean(deviations)\n \n return mad", "matching_cluster_idx": 0}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\"\n For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n\n Args:\n numbers (List[float]): A list of numbers.\n\n Returns:\n float: The Mean Absolute Deviation of the input numbers.\n\n Raises:\n ZeroDivisionError: If the input list is empty.\n TypeError: If the input is not a list, or if it contains non-numeric values.\n \"\"\"\n\n # Check if input is a list\n if not isinstance(numbers, list):\n raise TypeError(\"Input must be a list.\")\n\n # Check if all elements in the list are numbers\n if not all(isinstance(num, (int, float)) for num in numbers):\n raise TypeError(\"All elements in the input list must be numbers.\")\n\n # Check if list is empty\n if len(numbers) == 0:\n raise ZeroDivisionError(\"Cannot calculate Mean Absolute Deviation of an empty list.\")\n\n # Calculate the mean\n mean = sum(numbers) / len(numbers)\n\n # Calculate the absolute deviation from the mean for each number\n absolute_deviations = [abs(num - mean) for num in numbers]\n\n # Calculate the mean of the absolute deviations\n mad = sum(absolute_deviations) / len(absolute_deviations)\n\n return mad", "matching_cluster_idx": 1}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\"\n For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n\n Args:\n numbers (List[float]): A list of numbers\n\n Returns:\n float: Mean Absolute Deviation of the input numbers\n \"\"\"\n\n # Check if input list is empty\n if not numbers:\n raise ValueError(\"Input list is empty\")\n\n # Calculate the mean of the numbers\n mean = sum(numbers) / len(numbers)\n\n # Calculate the absolute deviations from the mean\n absolute_deviations = [abs(num - mean) for num in numbers]\n\n # Calculate the mean of the absolute deviations\n mad = sum(absolute_deviations) / len(absolute_deviations)\n\n return mad", "matching_cluster_idx": 4}, {"solution": "from typing import List\nimport statistics\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\"\n For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n Args:\n numbers (List[float]): A list of floating point numbers\n Returns:\n float: The Mean Absolute Deviation of the given list of numbers\n \"\"\"\n # Calculate the mean of the dataset\n mean = statistics.mean(numbers)\n \n # Calculate absolute differences between each element and the mean\n absolute_diffs = [abs(x - mean) for x in numbers]\n \n # Calculate the mean of absolute differences (Mean Absolute Deviation)\n mad = statistics.mean(absolute_diffs)\n \n return mad\nnumbers = [1.0, 2.0, 3.0, 4.0]", "matching_cluster_idx": 0}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\"\n For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n \n Args:\n numbers (List[float]): A list of numbers.\n \n Returns:\n float: Mean Absolute Deviation.\n \"\"\"\n # Check if input list is empty\n if not numbers:\n raise ValueError(\"Input list is empty\")\n\n # Calculate the mean of the dataset\n mean = sum(numbers) / len(numbers)\n \n # Calculate the absolute difference between each element and the mean\n absolute_deviations = [abs(x - mean) for x in numbers]\n \n # Calculate the mean of these absolute deviations\n mad = sum(absolute_deviations) / len(absolute_deviations)\n \n return mad\nnumbers = [1.0, 2.0, 3.0, 4.0]", "matching_cluster_idx": 4}, {"solution": "from typing import List\nimport statistics\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\"\n For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n \n Args:\n numbers (List[float]): A list of floating point numbers.\n \n Returns:\n float: The Mean Absolute Deviation of the input list.\n \"\"\"\n\n # First calculate the mean of the input numbers\n mean_value = statistics.mean(numbers)\n \n # Initialize variable to hold the sum of absolute differences\n absolute_deviation_sum = 0\n \n # For each number in the input list, calculate its absolute difference from the mean\n for number in numbers:\n absolute_deviation_sum += abs(number - mean_value)\n \n # Calculate the Mean Absolute Deviation by dividing the sum of absolute differences by the number of elements\n mean_absolute_deviation_value = absolute_deviation_sum / len(numbers)\n \n return mean_absolute_deviation_value", "matching_cluster_idx": 0}]}, "HumanEval/16": {"dps": 83.25581395348837, "dps_norm": 86.66666666666667, "pass@1": 94.0, "profiled": [{"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\"\n Given a string, find out how many distinct characters (regardless of case) does it consist of\n \n Args:\n string (str): The input string\n \n Returns:\n int: Number of distinct characters in the string\n \"\"\"\n # Convert the string to lower case to ignore the case sensitivity\n lower_case_string = string.lower()\n # Convert the string into a set, which automatically removes duplicates\n distinct_characters = set(lower_case_string)\n # Return the number of distinct characters\n return len(distinct_characters)", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\"\n Given a string, find out how many distinct characters (regardless of case) it consists of\n\n Args:\n string (str): Input string\n\n Returns:\n int: The number of distinct characters\n \"\"\"\n return len(set(string.casefold()))", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\"\n Given a string, find out how many distinct characters (regardless of case) does it consist of.\n\n Args:\n string (str): Input string.\n\n Returns:\n int: Number of distinct characters in the string.\n \"\"\"\n # Convert the string to a set which automatically removes duplicates\n # Convert to lower case to ignore case sensitivity\n distinct_chars = set(string.lower())\n \n # Return the number of elements in the set which represents distinct characters\n return len(distinct_chars)", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\"\n Given a string, find out how many distinct characters (regardless of case) does it consist of.\n\n Args:\n string (str): Input string to be analyzed.\n\n Returns:\n int: Number of distinct characters.\n \"\"\"\n return len(set(char.lower() for char in string))", "matching_cluster_idx": 2}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to a set which removes duplicates and then convert to lower case to ignore case sensitivity\n distinct_chars = set(string.lower())\n \n # Return the number of distinct characters\n return len(distinct_chars)", "matching_cluster_idx": 8}, {"solution": "import unittest\ndef count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of \"\"\"\n # Convert the string to lower case to ignore case sensitivity\n string_lower = string.lower()\n \n # Convert the string to a set, which automatically removes duplicate characters\n distinct_chars = set(string_lower)\n \n # Return the number of distinct characters\n return len(distinct_chars)", "matching_cluster_idx": 8}, {"solution": "import unittest\ndef count_distinct_characters(string: str) -> int:\n \"\"\"\n Given a string, find out how many distinct characters (regardless of case) does it consist of\n \n Args:\n string (str): Input string\n \n Returns:\n int: Number of distinct characters\n \"\"\"\n return len(set(char.lower() for char in string))", "matching_cluster_idx": 2}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\"\n Given a string, find out how many distinct characters (regardless of case) does it consist of.\n\n Args:\n string (str): The input string.\n\n Returns:\n int: The number of distinct characters in the string.\n\n Examples:\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lowercase to make comparison case-insensitive\n lower_string = string.lower()\n \n # Convert the string to a set, which automatically removes duplicates\n distinct_chars = set(lower_string)\n \n # Return the number of distinct characters\n return len(distinct_chars)", "matching_cluster_idx": 8}, {"solution": "import doctest\nimport unittest\ndef count_distinct_characters(string: str) -> int:\n \"\"\"\n Given a string, find out how many distinct characters (regardless of case) does it consist of.\n\n Args:\n string (str): The input string.\n\n Returns:\n int: The number of distinct characters in the string.\n\n Examples:\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to a set of unique characters, ignoring case\n distinct_chars = set(string.casefold())\n \n # Return the number of distinct characters\n return len(distinct_chars)", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\"\n Given a string, find out how many distinct characters (regardless of case) does it consist of\n\n Args:\n string (str): Input string to process\n\n Returns:\n int: Number of distinct characters in the string\n \"\"\"\n # Convert the string to a set, which automatically removes duplicates.\n # Use set comprehension to convert characters to lower case.\n distinct_chars = {char.lower() for char in string}\n \n # Return the size of the set, which is the number of distinct characters\n return len(distinct_chars)", "matching_cluster_idx": 2}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\"\n Given a string, find out how many distinct characters (regardless of case) does it consist of\n\n Args:\n string (str): Input string to count distinct characters from\n\n Returns:\n int: Number of distinct characters in the string\n \"\"\"\n # Convert the string to lower case to make comparison case-insensitive\n lower_case_string = string.lower()\n \n # Use a set to store unique characters, since sets automatically remove duplicates\n unique_chars = set(lower_case_string)\n \n # Return the number of unique characters\n return len(unique_chars)", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\"\n Given a string, find out how many distinct characters (regardless of case) it consists of.\n\n Args:\n string (str): Input string.\n\n Returns:\n int: Number of distinct characters in the string.\n\n Examples:\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 5\n \"\"\"\n # Convert the string to lowercase to ignore case sensitivity\n lower_case_string = string.lower()\n \n # Convert the string to a set to get distinct characters\n distinct_characters = set(lower_case_string)\n \n # Return the number of distinct characters\n return len(distinct_characters)", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\"\n Given a string, find out how many distinct characters (regardless of case) does it consist of\n\n Args:\n string (str): Input string\n\n Returns:\n int: The number of distinct characters in the string\n \"\"\"\n # Convert the string to a set, which automatically removes duplicate characters\n # We convert the string to lower case to make the function case-insensitive\n distinct_chars = set(string.lower())\n \n # The number of distinct characters is the size of the set\n return len(distinct_chars)", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\"\n Given a string, find out how many distinct characters (regardless of case) does it consist of\n\n Args:\n string (str): Input string.\n\n Returns:\n int: Number of distinct characters in the string.\n \"\"\"\n # Convert the string to lower case and convert it to a set, \n # which automatically removes duplicate characters.\n distinct_chars = set(string.lower())\n \n # Return the number of distinct characters.\n return len(distinct_chars)", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\"\n Given a string, find out how many distinct characters (regardless of case) does it consist of\n \n Parameters:\n string (str): Input string\n \n Returns:\n int: The number of distinct characters\n \n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 5\n \"\"\"\n\n # Convert the string to lower case to make it case-insensitive\n lower_case_string = string.lower()\n \n # Convert the string to a set, which automatically removes duplicates\n distinct_characters = set(lower_case_string)\n \n # Return the number of distinct characters\n return len(distinct_characters)", "matching_cluster_idx": 8}, {"solution": "import unittest\ndef count_distinct_characters(string: str) -> int:\n \"\"\"\n Given a string, find out how many distinct characters (regardless of case) does it consist of.\n\n Args:\n string (str): Input string.\n\n Returns:\n int: Number of distinct characters in the string.\n\n Examples:\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 5\n \"\"\"\n # Convert the string to lowercase to ignore case sensitivity\n lower_case_string = string.lower()\n \n # Use a set to store unique characters\n distinct_chars = set(lower_case_string)\n \n # Return the number of distinct characters\n return len(distinct_chars)", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\"\n Given a string, find out how many distinct characters (regardless of case) does it consist of\n\n Args:\n string (str): Input string\n\n Returns:\n int: The number of distinct characters in the string\n \"\"\"\n # Convert the string to lowercase to ignore case sensitivity\n lower_string = string.lower()\n \n # Convert the string to a set, which removes duplicate characters\n distinct_chars = set(lower_string)\n \n # Return the number of distinct characters\n return len(distinct_chars)", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\"\n Given a string, find out how many distinct characters (regardless of case) does it consist of.\n\n Args:\n string (str): The input string.\n\n Returns:\n int: Number of distinct characters in the string.\n\n Examples:\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lowercase to ignore case\n lower_case_string = string.lower()\n \n # Convert the string to a set, which removes duplicates\n distinct_chars = set(lower_case_string)\n \n # Return the number of distinct characters\n return len(distinct_chars)", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\"\n Given a string, find out how many distinct characters (regardless of case) does it consist of\n\n Args:\n string (str): The input string.\n\n Returns:\n int: The number of distinct characters in the string.\n\n Examples:\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 5\n \"\"\"\n return len(set(char.lower() for char in string))", "matching_cluster_idx": 2}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\"\n Given a string, find out how many distinct characters (regardless of case) does it consist of\n \n Args:\n string (str): The input string.\n\n Returns:\n int: The number of distinct characters in the string.\n\n Examples:\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 5\n \"\"\"\n # Convert the string to lower case and convert it to a set\n # This automatically removes any duplicate characters because sets only allow unique elements\n distinct_chars = set(string.lower())\n \n # The number of distinct characters is the size of the set\n return len(distinct_chars)", "matching_cluster_idx": 8}]}, "HumanEval/20": {"dps": 91.05326876513317, "dps_norm": 92.22222222222223, "pass@1": 96.0, "profiled": [{"solution": "from typing import List, Tuple\nimport itertools\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\"\n From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n\n Args:\n numbers (List[float]): A list of numbers.\n\n Returns:\n Tuple[float, float]: The two closest numbers in order.\n\n Raises:\n ValueError: If the list of numbers has less than two elements.\n \"\"\"\n if len(numbers) < 2:\n raise ValueError(\"The list of numbers should have at least two elements.\")\n\n # Generate all possible pairs of numbers\n pairs = list(itertools.combinations(numbers, 2))\n \n # Find the pair with the smallest difference\n closest_pair = min(pairs, key=lambda x: abs(x[1] - x[0]))\n \n # Return the closest pair in order\n return tuple(sorted(closest_pair))", "matching_cluster_idx": -1}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\"\n From a supplied list of numbers (of length at least two) select and return two that are the closest to each other \n and return them in order (smaller number, larger number).\n\n Args:\n numbers (List[float]): A list of numbers of length at least two.\n\n Returns:\n Tuple[float, float]: Two numbers from the list that are closest to each other, returned in ascending order.\n \"\"\"\n if len(numbers) < 2:\n raise ValueError(\"The list must contain at least two numbers\")\n\n # First, sort the list of numbers\n sorted_numbers = sorted(numbers)\n\n # Initialize the minimum difference and the pair of numbers with the minimum difference\n min_diff = float('inf') # Initialize with positive infinity\n closest_pair = ()\n\n # Iterate over the sorted list to find the pair with the smallest difference\n for i in range(len(sorted_numbers) - 1):\n diff = sorted_numbers[i + 1] - sorted_numbers[i]\n if diff < min_diff:\n min_diff = diff\n closest_pair = (sorted_numbers[i], sorted_numbers[i + 1])\n\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\"\n From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n\n :param numbers: A list of numbers of length at least two\n :return: A tuple of two numbers in the list with the smallest difference, in order\n \"\"\"\n if len(numbers) < 2:\n raise ValueError(\"The list must contain at least two numbers\")\n\n # Sort the list to find adjacent numbers with the smallest difference\n numbers.sort()\n\n # Initialize the minimum difference and the pair of closest numbers\n min_diff = float('inf')\n closest_pair = ()\n\n # Iterate over the sorted list to find the pair of closest numbers\n for i in range(len(numbers) - 1):\n diff = numbers[i + 1] - numbers[i]\n if diff < min_diff:\n min_diff = diff\n closest_pair = (numbers[i], numbers[i + 1])\n\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\"\n From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n\n Args:\n numbers (List[float]): A list of numbers (length at least 2)\n\n Returns:\n Tuple[float, float]: A tuple containing the closest two numbers in ascending order\n \"\"\"\n\n # First, we sort the list of numbers\n numbers.sort()\n\n # Initialize the minimum difference and the closest pair with the first two numbers\n min_diff = numbers[1] - numbers[0]\n closest_pair = (numbers[0], numbers[1])\n\n # Iterate over the sorted list to find the closest pair\n for i in range(1, len(numbers) - 1):\n # Calculate the difference between the current number and the next one\n diff = numbers[i + 1] - numbers[i]\n\n # If the difference is smaller than the current minimum, update the minimum and the closest pair\n if diff < min_diff:\n min_diff = diff\n closest_pair = (numbers[i], numbers[i + 1])\n\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\"\n From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n \n Args:\n numbers: A list of float numbers.\n \n Returns:\n A tuple of two float numbers that are closest to each other in the list.\n \"\"\"\n \n # First, we sort the list of numbers in ascending order\n numbers.sort()\n \n # Initialize the minimum difference and the pair of closest numbers\n min_diff = float('inf') # Initialize with positive infinity\n closest_pair = ()\n \n # Iterate through the sorted list to find the pair with the smallest difference\n for i in range(len(numbers) - 1):\n diff = numbers[i + 1] - numbers[i]\n if diff < min_diff:\n min_diff = diff\n closest_pair = (numbers[i], numbers[i + 1])\n \n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\"\n From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n\n Args:\n numbers (List[float]): A list of floating-point numbers.\n\n Returns:\n Tuple[float, float]: A tuple containing the two closest numbers in ascending order.\n \"\"\"\n\n # Handle edge cases where list has less than two elements\n if len(numbers) < 2:\n raise ValueError(\"Input list must contain at least two elements\")\n\n # Sort the list of numbers\n numbers.sort()\n\n # Initialize the minimum difference and the pair of closest numbers\n min_diff = float('inf') # Initialize with positive infinity\n closest_pair = ()\n\n # Iterate through the sorted list of numbers\n for i in range(len(numbers) - 1):\n # Calculate the difference between the current number and the next one\n diff = numbers[i + 1] - numbers[i]\n\n # If the difference is smaller than the current minimum difference, update the minimum difference and the closest pair\n if diff < min_diff:\n min_diff = diff\n closest_pair = (numbers[i], numbers[i + 1])\n\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\"\n From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n\n Args:\n numbers: A list of at least two floating point numbers.\n\n Returns:\n A tuple of the closest two numbers in ascending order.\n\n Raises:\n ValueError: If the input list contains less than two numbers.\n \"\"\"\n\n # Check if the list has at least two numbers\n if len(numbers) < 2:\n raise ValueError(\"The input list must contain at least two numbers.\")\n\n # First, we sort the list of numbers in ascending order\n numbers.sort()\n\n # Initialize the minimum difference and the closest pair of numbers\n min_diff = float('inf') # Initialize with positive infinity\n closest_pair = ()\n\n # Iterate over the sorted list to find the closest pair of numbers\n for i in range(len(numbers) - 1):\n diff = numbers[i + 1] - numbers[i]\n # Update the minimum difference and the closest pair if needed\n if diff < min_diff:\n min_diff = diff\n closest_pair = (numbers[i], numbers[i + 1])\n\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\"\n From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n\n Args:\n numbers (List[float]): A list of floating point numbers.\n\n Returns:\n Tuple[float, float]: A tuple of two numbers that are closest to each other in the list.\n\n Raises:\n ValueError: If the list has less than two elements.\n \"\"\"\n\n # Check if the list has at least two elements\n if len(numbers) < 2:\n raise ValueError(\"List must contain at least two elements.\")\n\n # Sort the list\n sorted_numbers = sorted(numbers)\n\n # Initialize the minimum difference and the pair of numbers\n min_diff = float('inf')\n closest_pair = ()\n\n # Iterate over the sorted list to find the pair of numbers with the smallest difference\n for i in range(1, len(sorted_numbers)):\n diff = sorted_numbers[i] - sorted_numbers[i - 1]\n if diff < min_diff:\n min_diff = diff\n closest_pair = (sorted_numbers[i - 1], sorted_numbers[i])\n\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\"\n From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n\n Args:\n numbers: A list of float numbers.\n\n Returns:\n A tuple containing two numbers that are closest to each other.\n \"\"\"\n # Check if the list has at least two elements\n if len(numbers) < 2:\n raise ValueError(\"The list must have at least two elements.\")\n\n # First, sort the list in ascending order\n sorted_numbers = sorted(numbers)\n\n # Initialize the minimum difference and the pair of numbers\n min_diff = float('inf')\n closest_pair = ()\n\n # Iterate over the sorted list to find the closest pair of numbers\n for i in range(len(sorted_numbers) - 1):\n diff = sorted_numbers[i + 1] - sorted_numbers[i]\n if diff < min_diff:\n min_diff = diff\n closest_pair = (sorted_numbers[i], sorted_numbers[i + 1])\n\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\"\n From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n\n Args:\n numbers (List[float]): A list of floating point numbers (length at least 2)\n\n Returns:\n Tuple[float, float]: The two numbers in the list closest to each other in order\n \"\"\"\n\n # Check for invalid input length\n if len(numbers) < 2:\n raise ValueError(\"Input list must contain at least 2 elements\")\n\n # First sort the list\n numbers.sort()\n\n # Initialize minimum difference and closest pair\n min_diff = float('inf') # Initialize with positive infinity\n closest_pair = ()\n\n # Iterate over the sorted list to find closest pair\n for i in range(len(numbers) - 1):\n diff = numbers[i + 1] - numbers[i]\n if diff < min_diff:\n min_diff = diff\n closest_pair = (numbers[i], numbers[i + 1])\n\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\nimport itertools\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\"\n From a supplied list of numbers (of length at least two) select and return two that are the closest to each \n other and return them in order (smaller number, larger number).\n\n Args:\n numbers: A list of floats (length >= 2).\n\n Returns:\n A tuple of two floats - the closest pair of numbers in the input list.\n\n Example:\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n \"\"\"\n\n # Initialize minimum difference and closest pair\n min_diff = float('inf') # Initialize with positive infinity\n closest_pair = ()\n\n # Generate all possible pairs of numbers\n for pair in itertools.combinations(numbers, 2):\n # Calculate the absolute difference between the pair of numbers\n diff = abs(pair[0] - pair[1])\n\n # If the difference is smaller than the current minimum difference, update the minimum difference and the closest pair\n if diff < min_diff:\n min_diff = diff\n # Ensure the pair is ordered from smaller to larger\n closest_pair = tuple(sorted(pair))\n\n return closest_pair", "matching_cluster_idx": 3}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\"\n From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n\n Args:\n numbers (List[float]): A list of numbers (of length at least two)\n\n Returns:\n Tuple[float, float]: Two closest numbers in order (smaller number, larger number)\n \"\"\"\n if len(numbers) < 2:\n raise ValueError(\"Input list must contain at least two numbers\")\n\n # Sort the list in ascending order\n numbers.sort()\n\n # Initialize the minimum difference and the pair of closest numbers\n min_diff = float('inf')\n closest_pair = ()\n\n # Iterate through the sorted list to find the closest pair of numbers\n for i in range(len(numbers) - 1):\n diff = numbers[i + 1] - numbers[i]\n if diff < min_diff:\n min_diff = diff\n closest_pair = (numbers[i], numbers[i + 1])\n\n return closest_pair\nnumbers = [1.0, 2.0, 3.0, 4.0, 5.0, 2.2]\nclosest_pair = find_closest_elements(numbers)", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\"\n From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n\n Args:\n numbers (List[float]): A list of float numbers.\n\n Returns:\n Tuple[float, float]: A tuple of two numbers in the list that are closest to each other.\n \"\"\"\n # Check if the list has at least two elements\n if len(numbers) < 2:\n raise ValueError(\"The list must have at least two elements\")\n\n # Sort the list in ascending order\n numbers.sort()\n\n # Initialize the minimum difference and the pair of closest numbers\n min_diff = float('inf') # Initialize with positive infinity\n closest_pair = ()\n\n # Iterate through the sorted list to find the pair of closest numbers\n for i in range(len(numbers) - 1):\n diff = numbers[i + 1] - numbers[i]\n if diff < min_diff:\n min_diff = diff\n closest_pair = (numbers[i], numbers[i + 1])\n\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\"\n From a supplied list of numbers (of length at least two) select and return two that are the closest to each \n other and return them in order (smaller number, larger number).\n\n Args:\n numbers (List[float]): A list of numbers (at least two).\n\n Returns:\n Tuple[float, float]: Two numbers that are the closest to each other.\n \"\"\"\n if len(numbers) < 2:\n raise ValueError(\"The list must contain at least two numbers.\")\n\n numbers.sort() # Sort the list of numbers in ascending order\n min_diff = float('inf') # Initialize the minimum difference\n closest_pair = () # Initialize the closest pair\n\n # Iterate over the sorted list to find the closest pair\n for i in range(len(numbers) - 1):\n diff = numbers[i + 1] - numbers[i]\n if diff < min_diff:\n min_diff = diff\n closest_pair = (numbers[i], numbers[i + 1])\n\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\"\n From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n \n Args:\n numbers: A list of at least two floats\n \n Returns:\n A tuple of two floats representing the closest numbers in ascending order\n \"\"\"\n\n # Check if the list contains at least two elements\n if len(numbers) < 2:\n raise ValueError(\"Input list must contain at least two elements\")\n\n # Sort the list in ascending order\n sorted_numbers = sorted(numbers)\n \n # Initialize the minimum difference and the pair of closest numbers\n min_diff = float('inf')\n closest_pair = ()\n \n # Iterate through the sorted list to find the closest pair\n for i in range(len(sorted_numbers) - 1):\n diff = sorted_numbers[i + 1] - sorted_numbers[i]\n if diff < min_diff:\n min_diff = diff\n closest_pair = (sorted_numbers[i], sorted_numbers[i + 1])\n \n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\"\n From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n\n Args:\n numbers: A list of float numbers with at least two elements.\n\n Returns:\n A tuple containing two closest numbers in the list.\n \"\"\"\n # Check if list has less than two elements\n if len(numbers) < 2:\n raise ValueError(\"The input list must have at least two elements\")\n\n # Sort the list in ascending order\n sorted_numbers = sorted(numbers)\n\n # Initialize minimum difference and closest pair\n min_diff = float('inf')\n closest_pair = ()\n\n # Iterate over the sorted list to find the closest pair\n for i in range(len(sorted_numbers) - 1):\n diff = sorted_numbers[i + 1] - sorted_numbers[i]\n if diff < min_diff:\n min_diff = diff\n closest_pair = (sorted_numbers[i], sorted_numbers[i + 1])\n\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\"\n From a supplied list of numbers (of length at least two) select and return two that are the closest to each other \n and return them in order (smaller number, larger number).\n\n Args:\n numbers (List[float]): A list of floating point numbers.\n\n Returns:\n Tuple[float, float]: A tuple containing the two closest numbers in the list, in ascending order.\n \"\"\"\n if len(numbers) < 2:\n raise ValueError(\"The list of numbers must have at least two elements\")\n\n # Sort the list of numbers\n numbers.sort()\n\n # Initialize the minimum difference and the pair of closest numbers\n min_diff = float('inf')\n closest_pair = ()\n\n # Iterate over the sorted list to find the closest pair of numbers\n for i in range(1, len(numbers)):\n diff = numbers[i] - numbers[i-1]\n if diff < min_diff:\n min_diff = diff\n closest_pair = (numbers[i-1], numbers[i])\n\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\"\n From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n\n :param numbers: A list of float numbers with a length of at least 2\n :return: A tuple of two numbers that are closest to each other\n \"\"\"\n\n # Check the list has at least two elements\n if len(numbers) < 2:\n raise ValueError(\"The list must have at least two elements\")\n\n # Sort the list\n sorted_numbers = sorted(numbers)\n\n # Initialize minimum difference and corresponding numbers\n min_diff = float('inf')\n closest_pair = (sorted_numbers[0], sorted_numbers[1])\n\n # Iterate through the sorted list to find the closest pair\n for i in range(len(sorted_numbers) - 1):\n current_diff = abs(sorted_numbers[i + 1] - sorted_numbers[i])\n if current_diff < min_diff:\n min_diff = current_diff\n closest_pair = (sorted_numbers[i], sorted_numbers[i + 1])\n\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\"\n From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n \n Args:\n numbers: A list of float numbers\n \n Returns:\n A tuple of two closest float numbers\n \"\"\"\n \n # First, sort the list of numbers in ascending order\n numbers.sort()\n \n # Initialize the minimum difference between two numbers and the pair of numbers\n min_diff = float('inf') # Initialize with positive infinity\n closest_pair = () # Initialize with an empty tuple\n \n # Iterate through the sorted list to find the closest pair\n for i in range(len(numbers) - 1):\n # Calculate the difference between the current number and the next one\n diff = numbers[i + 1] - numbers[i]\n \n # If the difference is smaller than the current minimum difference, update the minimum difference and the closest pair\n if diff < min_diff:\n min_diff = diff\n closest_pair = (numbers[i], numbers[i + 1])\n \n # Return the closest pair\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\"\n From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n\n Args:\n numbers (List[float]): A list of floating point numbers.\n\n Returns:\n Tuple[float, float]: A tuple containing the two closest numbers in order.\n \"\"\"\n # Check if the list has at least two elements\n if len(numbers) < 2:\n raise ValueError(\"The list must contain at least two elements\")\n\n # First, sort the list of numbers\n numbers.sort()\n\n # Initialize the minimum difference and the corresponding pair of numbers\n min_diff = float('inf')\n closest_pair = ()\n\n # Iterate over the sorted list to find the pair with the smallest difference\n for i in range(len(numbers) - 1):\n diff = numbers[i + 1] - numbers[i]\n if diff < min_diff:\n min_diff = diff\n closest_pair = (numbers[i], numbers[i + 1])\n\n return closest_pair", "matching_cluster_idx": 8}]}, "HumanEval/24": {"dps": 48.40136054421769, "dps_norm": 20.0, "pass@1": 96.0, "profiled": [{"solution": "def largest_divisor(n: int) -> int:\n \"\"\"\n For a given number n, find the largest number that divides n evenly, smaller than n\n\n Args:\n n (int): Input number\n\n Returns:\n int: Largest divisor smaller than n\n\n >>> largest_divisor(15)\n 5\n >>> largest_divisor(17)\n 1\n >>> largest_divisor(10)\n 5\n \"\"\"\n # Handle the edge case when n is less than or equal to 1\n if n <= 1:\n return 1\n\n # Start from the largest possible divisor, which is n-1\n for i in range(n - 1, 0, -1):\n # Check if the current number is a divisor of n\n if n % i == 0:\n # If it is, return it immediately\n return i", "matching_cluster_idx": 0}, {"solution": "import unittest\ndef largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n \"\"\"\n for i in range(n - 1, 0, -1):\n if n % i == 0:\n return i\n return None", "matching_cluster_idx": 1}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\"\n For a given number n, find the largest number that divides n evenly, smaller than n.\n\n Args:\n n (int): The number to find the largest divisor for.\n\n Returns:\n int: The largest number that divides n evenly, smaller than n.\n\n Raises:\n ValueError: If n is less than 2.\n \"\"\"\n\n if n < 2:\n raise ValueError(\"Input number should be greater than 1\")\n\n # Start from the largest possible divisor (n-1) and check if it divides n\n for i in range(n-1, 0, -1):\n # Check if i divides n\n if n % i == 0:\n # If i divides n, return i\n return i", "matching_cluster_idx": 1}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\"\n For a given number n, find the largest number that divides n evenly, smaller than n.\n\n Args:\n n (int): The number to find the largest divisor for.\n\n Returns:\n int: The largest divisor of n, smaller than n.\n\n Examples:\n >>> largest_divisor(15)\n 5\n \"\"\"\n for i in range(n - 1, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 0}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\"\n For a given number n, find the largest number that divides n evenly, smaller than n\n \n Args:\n n (int): A positive integer.\n \n Returns:\n int: The largest number that divides n evenly, smaller than n.\n \"\"\"\n # We start checking divisors from the largest possible number (n-1) down to 1.\n for i in range(n - 1, 0, -1):\n # If n is divisible by i, return i as the largest divisor.\n if n % i == 0:\n return i", "matching_cluster_idx": 0}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\"\n For a given number n, find the largest number that divides n evenly, smaller than n\n\n Args:\n n (int): The input number.\n\n Returns:\n int: The largest number that divides n evenly, smaller than n.\n \"\"\"\n for i in range(n - 1, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 1}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\"\n For a given number n, find the largest number that divides n evenly, smaller than n.\n\n Args:\n n (int): A positive integer.\n\n Returns:\n int: The largest divisor of n smaller than n.\n\n Raises:\n ValueError: If n is less than or equal to 1.\n\n Examples:\n >>> largest_divisor(15)\n 5\n >>> largest_divisor(20)\n 10\n >>> largest_divisor(17)\n 1\n \"\"\"\n if n <= 1:\n raise ValueError(\"Input number should be greater than 1.\")\n\n # Start checking divisors from the largest possible one\n for i in range(n - 1, 0, -1):\n # Check if 'i' is a divisor of 'n'\n if n % i == 0:\n return i", "matching_cluster_idx": 1}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\"\n For a given number n, find the largest number that divides n evenly, smaller than n\n\n Args:\n n (int): The number to find the largest divisor of.\n\n Returns:\n int: The largest number that divides n evenly, smaller than n.\n\n Raises:\n ValueError: If n is less than 2.\n \"\"\"\n\n # Check if n is less than 2 and raise a ValueError if it is\n if n < 2:\n raise ValueError(\"Input number must be 2 or greater.\")\n\n # Iterate over numbers from n - 1 to 1\n for i in range(n - 1, 0, -1):\n # Check if n is divisible by the current number\n if n % i == 0:\n # If it is, return the current number as the largest divisor\n return i", "matching_cluster_idx": 1}, {"solution": "import unittest\ndef largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n # We know that the largest divisor will be at least half of n, because a larger number cannot divide n evenly.\n # We start checking divisors from n // 2 and move down to 1.\n for divisor in range(n // 2, 0, -1):\n # Check if divisor divides n evenly\n if n % divisor == 0:\n # If it does, return this divisor as the largest one\n return divisor", "matching_cluster_idx": 3}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\"\n For a given number n, find the largest number that divides n evenly, smaller than n.\n \n Args:\n n (int): A positive integer.\n \n Returns:\n int: The largest divisor of n smaller than n.\n \"\"\"\n # Start checking divisors from n - 1 downwards\n for i in range(n - 1, 0, -1):\n # If n is divisible by i, return i as the largest divisor\n if n % i == 0:\n return i", "matching_cluster_idx": 0}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\"\n For a given number n, find the largest number that divides n evenly, smaller than n.\n\n Args:\n n (int): The number to find the largest divisor for.\n\n Returns:\n int: The largest divisor of n that is smaller than n.\n\n Examples:\n >>> largest_divisor(15)\n 5\n \"\"\"\n for i in range(n - 1, 1, -1):\n if n % i == 0:\n return i\n return 1", "matching_cluster_idx": 0}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\"\n For a given number n, find the largest number that divides n evenly, smaller than n.\n\n Args:\n n (int): A given number.\n\n Returns:\n int: The largest number that divides n evenly, smaller than n.\n\n Raises:\n ValueError: If the input number n is less than 2.\n\n Examples:\n >>> largest_divisor(15)\n 5\n \"\"\"\n\n if n < 2:\n raise ValueError(\"Input number should be greater than or equal to 2.\")\n\n # Iterate from n-1 down to 2 to find the largest divisor\n for i in range(n - 1, 1, -1):\n # Check if i is a divisor of n\n if n % i == 0:\n return i\n\n # If no divisor is found, return 1 (since 1 is a divisor of all numbers)\n return 1", "matching_cluster_idx": 1}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\"\n For a given number n, find the largest number that divides n evenly, smaller than n.\n\n Args:\n n (int): The input number.\n\n Returns:\n int: The largest divisor smaller than n.\n\n Examples:\n >>> largest_divisor(15)\n 5\n >>> largest_divisor(8)\n 4\n >>> largest_divisor(7)\n 1\n \"\"\"\n\n # We start checking from n - 1 as we know n is not a divisor of n\n for i in range(n - 1, 0, -1):\n # Check if n is divisible by i\n if n % i == 0:\n # If it's divisible, return i as it's the largest divisor\n return i", "matching_cluster_idx": 0}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\"\n For a given number n, find the largest number that divides n evenly, smaller than n\n\n Args:\n n (int): A positive integer.\n\n Returns:\n int: The largest divisor of n that is smaller than n.\n\n Raises:\n ValueError: If n is less than 1.\n \"\"\"\n if n < 1:\n raise ValueError(\"Input should be a positive integer.\")\n\n # Start from n-1 and decrement down to 1\n for i in range(n-1, 0, -1):\n # Check if i is a divisor of n\n if n % i == 0:\n # If it is, return i\n return i\n\n # If no divisors are found, return None\n return None", "matching_cluster_idx": 1}, {"solution": "import unittest\ndef largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n for i in range(n - 1, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 0}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\"\n For a given number n, find the largest number that divides n evenly, smaller than n\n\n Args:\n n (int): The input number\n\n Returns:\n int: The largest divisor of n\n\n Examples:\n >>> largest_divisor(15)\n 5\n >>> largest_divisor(100)\n 50\n \"\"\"\n\n def is_divisor(a: int, b: int) -> bool:\n \"\"\" Helper function to check if a is a divisor of b \"\"\"\n return b % a == 0\n\n # Iterate from n-1 down to 1 to find the largest divisor\n for i in range(n - 1, 0, -1):\n if is_divisor(i, n):\n return i", "matching_cluster_idx": -1}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\"\n For a given number n, find the largest number that divides n evenly, smaller than n.\n\n Args:\n n (int): A positive integer.\n\n Returns:\n int: The largest divisor of n smaller than n.\n\n Raises:\n ValueError: If n is less than 2.\n\n Examples:\n >>> largest_divisor(15)\n 5\n \"\"\"\n if n < 2:\n raise ValueError(\"Input number should be greater than 1\")\n\n for i in range(n - 1, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 1}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\"\n For a given number n, find the largest number that divides n evenly, smaller than n.\n\n Args:\n n (int): The input number.\n\n Returns:\n int: The largest divisor of n that is smaller than n.\n\n >>> largest_divisor(15)\n 5\n >>> largest_divisor(20)\n 10\n >>> largest_divisor(1)\n 1\n \"\"\"\n\n # If n is 1, then it's only divisor is 1\n if n == 1:\n return 1\n \n # Start checking divisors from n-1 down to 1\n for i in range(n-1, 0, -1):\n # If n is divisible by i, return i\n if n % i == 0:\n return i", "matching_cluster_idx": 1}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n \"\"\"\n for i in range(n - 1, 0, -1):\n if n % i == 0:\n return i\n return 1", "matching_cluster_idx": 0}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\"\n For a given number n, find the largest number that divides n evenly, smaller than n\n\n Args:\n n (int): A positive integer\n\n Returns:\n int: The largest divisor of n, smaller than n\n\n Raises:\n ValueError: If n is less than or equal to 1\n \"\"\"\n if n <= 1:\n raise ValueError(\"Input must be greater than 1\")\n\n for i in range(n - 1, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 1}]}, "HumanEval/26": {"dps": 55.0, "dps_norm": 76.25, "pass@1": 46.0, "profiled": [{"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\"\n From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n\n Args:\n numbers (List[int]): The list of integers.\n\n Returns:\n List[int]: A list of integers with duplicates removed.\n \"\"\"\n seen = set()\n seen_twice = set()\n result = []\n\n for num in numbers:\n if num not in seen:\n seen.add(num)\n result.append(num)\n else:\n if num not in seen_twice:\n seen_twice.add(num)\n # If the number is seen for the second time,\n # remove it from the result if it is present.\n if num in result:\n result.remove(num)\n\n return result", "matching_cluster_idx": 2}, {"solution": "from typing import List\nfrom collections import OrderedDict\nimport unittest\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n \"\"\"\n # Count the occurrence of each number and keep track of order\n counts = OrderedDict()\n for num in numbers:\n counts[num] = counts.get(num, 0) + 1\n \n # Filter numbers with a count of 1\n return [num for num, count in counts.items() if count == 1]", "matching_cluster_idx": 2}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n \"\"\"\n seen = set()\n duplicates = set()\n result = []\n\n for num in numbers:\n if num not in seen:\n seen.add(num)\n result.append(num)\n else:\n duplicates.add(num)\n\n return [num for num in result if num not in duplicates]", "matching_cluster_idx": 3}, {"solution": "from typing import List\nfrom collections import OrderedDict\nimport doctest\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\"\n From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n\n Args:\n numbers: A list of integers.\n\n Returns:\n A list of integers with duplicates removed.\n \"\"\"\n seen = OrderedDict()\n # Store elements we've seen so far and their counts.\n for num in numbers:\n seen[num] = seen.get(num, 0) + 1\n \n # Filter out numbers that occur more than once and return.\n return [num for num, count in seen.items() if count == 1]", "matching_cluster_idx": 2}, {"solution": "from typing import List\nfrom collections import OrderedDict\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\"\n From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n\n Args:\n numbers (List[int]): A list of integers.\n\n Returns:\n List[int]: A list of integers with duplicates removed.\n\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n\n # Count occurrences of each number using OrderedDict to preserve order\n count_dict = OrderedDict()\n for num in numbers:\n if num in count_dict:\n count_dict[num] += 1\n else:\n count_dict[num] = 1\n\n # Filter out numbers that occur more than once\n return [num for num, count in count_dict.items() if count == 1]", "matching_cluster_idx": 2}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\"\n From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n\n Args:\n numbers (List[int]): A list of integers.\n\n Returns:\n List[int]: A list of integers with duplicates removed.\n \"\"\"\n\n # Create an empty dictionary to track the count of each number\n count_dict = {}\n \n # Create an empty list to store the result\n result = []\n \n # Iterate over the input list\n for num in numbers:\n # If the number is not in the dictionary, add it to the dictionary and the result list\n if num not in count_dict:\n count_dict[num] = 1\n result.append(num)\n # If the number is already in the dictionary, increment its count\n else:\n count_dict[num] += 1\n \n # Filter the result list to only include numbers that occur once\n result = [num for num in result if count_dict[num] == 1]\n \n return result", "matching_cluster_idx": 3}, {"solution": "from typing import List\nimport unittest\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\"\n From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n\n Args:\n numbers (List[int]): A list of integers.\n\n Returns:\n List[int]: A new list with duplicates removed.\n \"\"\"\n seen = set()\n duplicates = set()\n result = []\n for num in numbers:\n if num in seen:\n duplicates.add(num)\n seen.add(num)\n for num in numbers:\n if num not in duplicates:\n result.append(num)\n return result", "matching_cluster_idx": 3}, {"solution": "from typing import List\nfrom collections import OrderedDict\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\"\n From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n\n Args:\n numbers (List[int]): Input list of integers.\n\n Returns:\n List[int]: List with duplicates removed.\n \"\"\"\n\n # Count the occurrence of each number\n seen = OrderedDict()\n for num in numbers:\n seen[num] = seen.get(num, 0) + 1\n \n # Create a new list with numbers that occur only once\n unique_numbers = [num for num, count in seen.items() if count == 1]\n\n return unique_numbers", "matching_cluster_idx": 2}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\"\n From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n \"\"\"\n # Create an empty dictionary to store counts of numbers\n counts = {}\n # Create an empty list to store result\n result = []\n\n # Iterate over the input list\n for num in numbers:\n # Count occurrence of each number\n if num in counts:\n counts[num] += 1\n else:\n counts[num] = 1\n\n # Iterate over the input list again\n for num in numbers:\n # Add numbers with a count of 1 to the result list\n if counts[num] == 1:\n result.append(num)\n\n return result", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\"\n From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n\n Args:\n numbers (List[int]): Input list of integers.\n\n Returns:\n List[int]: List with duplicates removed, maintaining original order.\n \"\"\"\n seen = set()\n seen_twice = set()\n result = []\n for num in numbers:\n if num in seen:\n seen_twice.add(num)\n else:\n seen.add(num)\n result.append(num)\n return [num for num in result if num not in seen_twice]", "matching_cluster_idx": 3}, {"solution": "from typing import List\nfrom collections import OrderedDict\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\"\n From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n\n Args:\n numbers (List[int]): A list of integers.\n\n Returns:\n List[int]: A list of integers without duplicates.\n \"\"\"\n # Create an ordered dictionary to keep track of the count of each number\n count_dict = OrderedDict()\n for num in numbers:\n if num in count_dict:\n count_dict[num] += 1\n else:\n count_dict[num] = 1\n\n # Filter out the numbers that occur more than once\n result = [num for num, count in count_dict.items() if count == 1]\n\n return result", "matching_cluster_idx": 2}, {"solution": "from typing import List\nfrom collections import OrderedDict\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\"From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\"\"\"\n # Create an ordered dictionary with keys as list elements and values as counts\n counts = OrderedDict()\n for num in numbers:\n if num not in counts:\n counts[num] = 1\n else:\n counts[num] += 1\n\n # Create a new list with elements that occur only once\n result = [num for num, count in counts.items() if count == 1]\n\n return result\nnumbers = [1, 2, 3, 2, 4]", "matching_cluster_idx": 2}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\"\n From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n\n Args:\n numbers (List[int]): The input list of integers.\n\n Returns:\n List[int]: A new list with duplicates removed.\n \"\"\"\n seen = set()\n result = []\n for num in numbers:\n if num not in seen:\n seen.add(num)\n result.append(num)\n elif numbers.count(num) == 1:\n seen.add(num)\n result.append(num)\n else:\n continue\n return [x for x in numbers if numbers.count(x) == 1]", "matching_cluster_idx": -1}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n # Initialize an empty dictionary to track counts of numbers we have seen so far\n seen = {}\n # Initialize an empty list to store result\n result = []\n \n # Iterate over the list of numbers\n for num in numbers:\n # If a number is not in seen or we have seen it only once, add it to result\n if num not in seen or seen[num] == 1:\n # Add the number to the result if it's the first occurrence or the second occurrence\n if num not in seen:\n result.append(num)\n # Increment count in seen\n seen[num] = seen.get(num, 0) + 1\n \n # Return result list with numbers that occur only once in the input list\n return [num for num in result if seen[num] == 1]", "matching_cluster_idx": 2}, {"solution": "from typing import List\nfrom collections import OrderedDict\nimport unittest\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\"\n From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n seen = OrderedDict()\n for num in numbers:\n seen[num] = seen.get(num, 0) + 1\n\n return [num for num, freq in seen.items() if freq == 1]", "matching_cluster_idx": 2}, {"solution": "from typing import List\nfrom collections import OrderedDict\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\"\n From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n \n Args:\n numbers (List[int]): A list of integers.\n \n Returns:\n List[int]: The input list with all duplicates removed.\n \"\"\"\n seen = OrderedDict()\n for num in numbers:\n seen[num] = None\n \n # Keep only numbers that occur only once\n return [num for num in numbers if numbers.count(num) == 1]", "matching_cluster_idx": 0}, {"solution": "from typing import List\nfrom collections import OrderedDict\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\"\n From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n \"\"\"\n # Create an OrderedDict to count occurrences of each element while preserving order\n count_map = OrderedDict((x, numbers.count(x)) for x in numbers)\n \n # Filter elements that occur more than once\n unique_elements = [x for x, count in count_map.items() if count == 1]\n \n return unique_elements", "matching_cluster_idx": 0}, {"solution": "from typing import List\nfrom collections import OrderedDict\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\"\n From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n \n :param numbers: List of integers\n :return: List of integers without duplicates\n \"\"\"\n # Use OrderedDict to count occurrences and maintain the order\n counts = OrderedDict()\n for num in numbers:\n if num in counts:\n counts[num] += 1\n else:\n counts[num] = 1\n \n # Return a list with numbers that occur only once\n return [num for num, count in counts.items() if count == 1]", "matching_cluster_idx": 3}, {"solution": "from typing import List\nfrom collections import OrderedDict\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\"\n From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n\n Args:\n numbers: A list of integers.\n\n Returns:\n A list of integers, where each element appears only once.\n\n Examples:\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n\n # Use an OrderedDict to keep track of the count of each number\n # while preserving the order they first appear in the list\n count_dict = OrderedDict()\n for num in numbers:\n if num not in count_dict:\n count_dict[num] = 1\n else:\n count_dict[num] += 1\n\n # Use a list comprehension to filter out numbers that occur more than once\n unique_numbers = [num for num, count in count_dict.items() if count == 1]\n\n return unique_numbers", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\"\n From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n\n Args:\n numbers: A list of integers.\n\n Returns:\n A list of integers where all duplicates are removed.\n\n Example:\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n\n seen = set() # Initialize an empty set to keep track of elements we've seen\n seen_twice = set() # Initialize an empty set to keep track of elements we've seen twice\n \n # Iterate over the list, adding elements to seen_twice if we've seen them before\n for num in numbers:\n if num in seen:\n seen_twice.add(num)\n seen.add(num)\n\n # Filter out elements we've seen twice from the original list\n return [num for num in numbers if num not in seen_twice]", "matching_cluster_idx": 3}]}, "HumanEval/31": {"dps": 61.392405063291136, "dps_norm": 77.5, "pass@1": 99.0, "profiled": [{"solution": "import unittest\ndef is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\"\"\"\n if n < 2:\n return False\n for i in range(2, int(n ** 0.5) + 1):\n if n % i == 0:\n return False\n return True", "matching_cluster_idx": 5}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n \n A prime number is a natural number greater than 1 that has no positive divisors other than 1 and itself.\n \n Parameters:\n n (int): The number to check for primality\n \n Returns:\n bool: True if the number is prime, False otherwise\n \"\"\"\n if n < 2:\n return False # 0, 1, and negative numbers are not prime\n \n # Only need to check divisibility up to the square root of n\n for i in range(2, int(n ** 0.5) + 1):\n if n % i == 0:\n return False # Found a divisor, n is not prime\n \n return True # No divisors found, n is prime", "matching_cluster_idx": 4}, {"solution": "def is_prime(n):\n \"\"\"\n Return true if a given number is prime, and false otherwise.\n\n :param n: The number to check for primality.\n :return: True if the number is prime, False otherwise.\n \"\"\"\n if n < 2:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True", "matching_cluster_idx": 5}, {"solution": "def is_prime(n):\n \"\"\"\n Return true if a given number is prime, and false otherwise.\n\n A prime number is a natural number greater than 1 that has no positive divisors other than 1 and itself.\n\n :param n: The number to check for primality.\n :return: True if the number is prime, False otherwise.\n \"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n ** 0.5) + 1):\n if n % i == 0:\n return False\n return True", "matching_cluster_idx": 5}, {"solution": "def is_prime(n):\n \"\"\"\n Return true if a given number is prime, and false otherwise.\n\n A prime number is a natural number greater than 1 that has no positive divisors other than 1 and itself.\n\n :param n: The number to check for primality\n :return: True if the number is prime, False otherwise\n \"\"\"\n\n # Handle edge cases\n if n < 2: \n # Numbers less than 2 are not prime\n return False\n\n # Check if the number is divisible by any number up to its square root\n for i in range(2, int(n ** 0.5) + 1):\n if n % i == 0:\n # If it's divisible, it's not prime\n return False\n\n # If it's not divisible by any number up to its square root, it's prime\n return True", "matching_cluster_idx": 5}, {"solution": "def is_prime(n):\n \"\"\"\n Return true if a given number is prime, and false otherwise.\n\n A prime number is a natural number greater than 1 that has no positive divisors other than 1 and itself.\n\n :param n: The input number to check for primality.\n :type n: int\n :return: True if the number is prime, False otherwise.\n :rtype: bool\n \"\"\"\n if n <= 1: # Numbers less than or equal to 1 are not prime.\n return False\n if n <= 3: # 2 and 3 are prime.\n return True\n if n % 2 == 0 or n % 3 == 0: # If the number is divisible by 2 or 3, it's not prime.\n return False\n i = 5\n while i * i <= n: # We only need to check up to the square root of n.\n if n % i == 0 or n % (i + 2) == 0: # Check for divisibility by i and i + 2.\n return False\n i += 6 # Increment i by 6 because we've checked i and i + 2 already.\n return True # If the number passes all checks, it's prime.", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"\n Return True if a given number is prime, and False otherwise.\n\n A prime number is a positive integer that is divisible only by itself and 1.\n\n Parameters:\n n (int): The number to be checked.\n\n Returns:\n bool: True if the number is prime, False otherwise.\n \"\"\"\n if n <= 1:\n # 0 and 1 are not prime numbers\n return False\n elif n <= 3:\n # 2 and 3 are prime numbers\n return True\n elif n % 2 == 0 or n % 3 == 0:\n # If the number is divisible by 2 or 3, it's not a prime number\n return False\n i = 5\n while i * i <= n:\n # Check divisibility up to the square root of the number\n if n % i == 0 or n % (i + 2) == 0:\n # If the number is divisible by any number in this range, it's not a prime number\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"\n Return True if a given number is prime, and False otherwise.\n\n A prime number is a natural number greater than 1 that has no positive divisors other than 1 and itself.\n \"\"\"\n if n <= 1:\n # By definition, 0 and 1 are not prime numbers\n return False\n elif n <= 3:\n # 2 and 3 are prime numbers\n return True\n elif n % 2 == 0 or n % 3 == 0:\n # If n is divisible by 2 or 3, it's not prime\n return False\n i = 5\n while i * i <= n:\n # Check for divisibility from 5 to sqrt(n)\n if n % i == 0 or n % (i + 2) == 0:\n # If n is divisible by any of these numbers, it's not prime\n return False\n i += 6\n # If all checks pass, n is a prime number\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"\n Return true if a given number is prime, and false otherwise.\n\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n < 2:\n # Numbers less than 2 are not prime\n return False\n\n # Check divisibility up to the square root of the number\n for i in range(2, int(n**0.5) + 1):\n # If n is divisible by any number between 2 and sqrt(n), it's not prime\n if n % i == 0:\n return False\n\n # If n is not divisible by any of the above numbers, it's prime\n return True", "matching_cluster_idx": 5}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n\n This function works by checking for factors up to the square root of n.\n \"\"\"\n if n < 2:\n # Numbers less than 2 are not prime\n return False\n\n # Check for factors up to the square root of n\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n # If n has a factor, it's not a prime number\n return False\n\n # If no factors were found, n is a prime number\n return True", "matching_cluster_idx": 5}, {"solution": "def is_prime(n):\n \"\"\"\n Return True if a given number is prime, and False otherwise.\n\n Args:\n n (int): The input number.\n\n Returns:\n bool: True if n is prime, False otherwise.\n\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n < 2: \n # Numbers less than 2 are not prime numbers\n return False\n for i in range(2, int(n**0.5) + 1):\n # Only need to check up to the square root of n\n if n % i == 0:\n # If n is divisible by any number, it is not prime\n return False\n return True", "matching_cluster_idx": 5}, {"solution": "def is_prime(n):\n \"\"\"\n Return true if a given number is prime, and false otherwise.\n\n Args:\n n (int): The number to check for primality.\n\n Returns:\n bool: True if n is prime, False otherwise.\n \"\"\"\n if n < 2: \n # By definition, numbers less than 2 are not prime.\n return False\n\n for i in range(2, int(n**0.5) + 1):\n # Check if n is divisible by any number from 2 up to the square root of n.\n if n % i == 0:\n return False\n\n # If no divisors are found, the number is prime.\n return True", "matching_cluster_idx": 5}, {"solution": "def is_prime(n):\n \"\"\"\n Return true if a given number is prime, and false otherwise.\n\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n < 2: # Numbers less than 2 are not prime\n return False\n for i in range(2, int(n ** 0.5) + 1): # Check divisibility up to sqrt(n)\n if n % i == 0: # If n is divisible, it's not a prime number\n return False\n return True # If no divisors are found, n is a prime number", "matching_cluster_idx": 5}, {"solution": "import doctest\ndef is_prime(n):\n \"\"\"\n Return true if a given number is prime, and false otherwise.\n\n Args:\n n (int): The number to check for primality.\n\n Returns:\n bool: True if the number is prime, False otherwise.\n \"\"\"\n if n < 2:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True", "matching_cluster_idx": 5}, {"solution": "def is_prime(n):\n \"\"\"\n Return true if a given number is prime, and false otherwise.\n\n A prime number is a natural number greater than 1 that has no positive divisors other than 1 and itself.\n\n :param n: An integer to be checked for primality.\n :return: True if the number is prime, False otherwise.\n \"\"\"\n if n < 2:\n # 0 and 1 are not prime numbers\n return False\n \n # Only need to check up to the square root of n\n # This is because a larger factor of n must be a multiple of a smaller factor that has already been checked\n for i in range(2, int(n ** 0.5) + 1):\n if n % i == 0:\n # If n is divisible by any number in this range, it is not prime\n return False\n \n # If no divisors were found, n is prime\n return True", "matching_cluster_idx": 5}, {"solution": "def is_prime(n):\n \"\"\"\n Return True if a given number is prime, and False otherwise.\n\n Args:\n n (int): The number to check for primality.\n\n Returns:\n bool: True if n is prime, False otherwise.\n \"\"\"\n if n <= 1: # numbers less than or equal to 1 are not prime\n return False\n\n # 2 is the only even prime number\n if n == 2:\n return True\n if n % 2 == 0: # all other even numbers are not prime\n return False\n\n # only need to check up to the square root of n for factors\n for i in range(3, int(n ** 0.5) + 1, 2):\n if n % i == 0:\n return False\n\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"\n Return true if a given number is prime, and false otherwise.\n\n Args:\n n (int): The number to check.\n\n Returns:\n bool: True if n is prime, False otherwise.\n \"\"\"\n if n <= 1:\n # Numbers less than or equal to 1 are not prime\n return False\n elif n <= 3:\n # 2 and 3 are prime\n return True\n elif n % 2 == 0 or n % 3 == 0:\n # If the number is divisible by 2 or 3, it's not prime\n return False\n i = 5\n while i * i <= n:\n # Check for divisibility up to the square root of n\n if n % i == 0 or n % (i + 2) == 0:\n # If the number is divisible by any other number, it's not prime\n return False\n i += 6\n # If no divisors are found, the number is prime\n return True", "matching_cluster_idx": 6}, {"solution": "import unittest\ndef is_prime(n):\n \"\"\"\n Return true if a given number is prime, and false otherwise.\n\n Args:\n n (int): The number to check for primality.\n\n Returns:\n bool: True if n is prime, False otherwise.\n \"\"\"\n if n <= 1:\n # Numbers less than or equal to 1 are not prime\n return False\n\n # Check if n is divisible by any number up to its square root\n # This is an optimization to reduce the number of checks\n for i in range(2, int(n ** 0.5) + 1):\n if n % i == 0:\n # If n is divisible by any number, it is not prime\n return False\n\n # If no divisors were found, n is prime\n return True", "matching_cluster_idx": 5}, {"solution": "def is_prime(n):\n \"\"\"\n Return true if a given number is prime, and false otherwise.\n \n :param n: An integer to be checked for primality.\n :return: bool indicating whether n is prime.\n \"\"\"\n if n <= 1: # Numbers less than or equal to 1 are not prime.\n return False\n \n for i in range(2, int(n ** 0.5) + 1): # Only need to check up to sqrt(n).\n if n % i == 0: # If n is divisible by any number between 2 and sqrt(n), it is not prime.\n return False\n \n # If n is not divisible by any number between 2 and sqrt(n), it is prime.\n return True", "matching_cluster_idx": 5}, {"solution": "def is_prime(n):\n \"\"\"\n Return true if a given number is prime, and false otherwise.\n\n Args:\n n (int): The number to be checked for primality.\n\n Returns:\n bool: True if the number is prime, False otherwise.\n \"\"\"\n if n < 2: # Numbers less than 2 are not prime\n return False\n for i in range(2, int(n**0.5) + 1): # Only need to check up to square root of n\n if n % i == 0: # If n is divisible by i, it's not prime\n return False\n return True # If no divisors were found, the number is prime", "matching_cluster_idx": 5}]}, "HumanEval/33": {"dps": 97.22222222222223, "dps_norm": 81.81818181818181, "pass@1": 64.0, "profiled": [{"solution": "def sort_third(input_list: list) -> list:\n \"\"\"\n This function takes a list input_list and returns a list output_list such that\n output_list is identical to input_list in the indices that are not divisible by three, \n while its values at the indices that are divisible by three are equal to the values of \n the corresponding indices of input_list, but sorted.\n\n :param input_list: Input list to be processed\n :return: Processed list\n \"\"\"\n third_idx = [input_list[i] for i in range(len(input_list)) if i % 3 == 0] # Collect elements at indices divisible by 3\n third_idx.sort() # Sort collected elements\n output_list = [] # Initialize output list\n\n # Initialize index for third_idx\n third_idx_index = 0\n\n # Iterate over input list with index and value\n for i, val in enumerate(input_list):\n # If index is divisible by 3, append corresponding value from third_idx\n if i % 3 == 0:\n output_list.append(third_idx[third_idx_index])\n third_idx_index += 1 # Increment third_idx_index\n else:\n output_list.append(val) # Otherwise, append the original value\n\n return output_list", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list) -> list:\n \"\"\"\n This function takes a list l and returns a list l' such that\n l' is identical to l in the indices that are not divisible by three, \n while its values at the indices that are divisible by three are equal \n to the values of the corresponding indices of l, but sorted.\n\n :param l: A list of elements\n :return: The modified list\n \"\"\"\n\n # First, filter the list to get only the elements at indices divisible by 3\n third_elements = [l[i] for i in range(0, len(l), 3)]\n\n # Sort the filtered list\n third_elements.sort()\n\n # Initialize an empty list to store the result\n result = []\n\n # Initialize a counter for the sorted third elements\n third_counter = 0\n\n # Iterate over the input list\n for i, element in enumerate(l):\n # If the index is divisible by 3, append the next sorted third element\n if i % 3 == 0:\n result.append(third_elements[third_counter])\n third_counter += 1\n # If the index is not divisible by 3, append the original element\n else:\n result.append(element)\n\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list) -> list:\n \"\"\"\n This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, \n while its values at the indicies that are divisible by three are equal \n to the values of the corresponding indicies of l, but sorted.\n\n Args:\n l (list): The input list.\n\n Returns:\n list: A new list with values at indices divisible by three sorted.\n \"\"\"\n # Separate the elements at indices that are divisible by 3\n third_elements = [l[i] for i in range(len(l)) if i % 3 == 0]\n \n # Sort the separated elements\n third_elements.sort()\n \n # Create a new list and fill it with elements from the original list\n # except at indices that are divisible by 3, where the sorted elements are used\n result = [third_elements[i // 3] if i % 3 == 0 else l[i] for i in range(len(l))]\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list) -> list:\n \"\"\"\n This function takes a list l and returns a list l' such that\n l' is identical to l in the indices that are not divisible by three, \n while its values at the indices that are divisible by three are equal\n to the values of the corresponding indices of l, but sorted.\n\n Args:\n l (list): The input list.\n\n Returns:\n list: A new list where every third element is sorted from the original list.\n \"\"\"\n # Get every third element from the list, sort them and store them in a list\n sorted_thirds = sorted([l[i] for i in range(0, len(l), 3)])\n\n # Initialize an empty list to store the result\n result = []\n\n # Initialize an index for the sorted_thirds list\n sorted_index = 0\n\n # Iterate over the original list\n for i, element in enumerate(l):\n # Check if the index is divisible by 3\n if i % 3 == 0:\n # If it is, append the next element from sorted_thirds\n result.append(sorted_thirds[sorted_index])\n # Increment the sorted_index\n sorted_index += 1\n else:\n # If it's not, append the original element\n result.append(element)\n\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list) -> list:\n \"\"\"\n This function takes a list l and returns a list l' such that\n l' is identical to l in the indices that are not divisible by three, \n while its values at the indices that are divisible by three are equal \n to the values of the corresponding indices of l, but sorted.\n\n Args:\n l (list): Input list\n\n Returns:\n list: List with elements at indices divisible by 3 sorted\n \"\"\"\n # Extract elements at indices divisible by 3\n third_elements = [l[i] for i in range(0, len(l), 3)]\n \n # Sort the extracted elements\n third_elements.sort()\n \n # Initialize result list\n result = []\n \n # Initialize index for third_elements\n third_index = 0\n \n # Iterate over input list\n for i in range(len(l)):\n # If index is divisible by 3, append sorted element\n if i % 3 == 0:\n result.append(third_elements[third_index])\n third_index += 1\n # Otherwise, append original element\n else:\n result.append(l[i])\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"\n This function takes a list l and returns a list l' such that\n l' is identical to l in the indices that are not divisible by three, \n while its values at the indices that are divisible by three are equal \n to the values of the corresponding indices of l, but sorted.\n\n Args:\n l (list): Input list.\n\n Returns:\n list: Modified list where indices divisible by three are sorted.\n \"\"\"\n # Separate elements at indices divisible by 3\n third_elements = sorted([l[i] for i in range(0, len(l), 3)])\n result = []\n # Initialize index for third_elements list\n third_index = 0\n # Iterate over the input list\n for i, elem in enumerate(l):\n if i % 3 == 0:\n # If index is divisible by 3, append sorted element\n result.append(third_elements[third_index])\n third_index += 1\n else:\n # If index is not divisible by 3, append original element\n result.append(elem)\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(input_list: list) -> list:\n \"\"\"\n This function takes a list and returns a new list where values at indices \n divisible by three are sorted.\n\n Args:\n input_list (list): Input list to sort at every third index.\n\n Returns:\n list: New list with sorted values at indices divisible by three.\n \"\"\"\n third_index_values = [input_list[i] for i in range(len(input_list)) if i % 3 == 0]\n third_index_values.sort()\n \n sorted_list = []\n third_index_counter = 0\n \n for i in range(len(input_list)):\n if i % 3 == 0:\n sorted_list.append(third_index_values[third_index_counter])\n third_index_counter += 1\n else:\n sorted_list.append(input_list[i])\n \n return sorted_list", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list) -> list:\n \"\"\"\n This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, \n while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n \"\"\"\n every_third_element = [l[i] for i in range(0, len(l), 3)]\n every_third_element.sort()\n result = []\n every_third_index = 0\n \n for i in range(len(l)):\n if i % 3 == 0:\n result.append(every_third_element[every_third_index])\n every_third_index += 1\n else:\n result.append(l[i])\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(input_list: list):\n \"\"\"\n This function takes a list input_list and returns a list l' such that\n l' is identical to input_list in the indicies that are not divisible by three, \n while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of input_list, but sorted.\n \n :param input_list: The input list to be processed\n :return: The processed list as per the problem statement\n \"\"\"\n third_indices = [input_list[i] for i in range(len(input_list)) if i % 3 == 0]\n third_indices.sort()\n result_list = []\n \n third_index = 0\n for i in range(len(input_list)):\n if i % 3 == 0:\n result_list.append(third_indices[third_index])\n third_index += 1\n else:\n result_list.append(input_list[i])\n \n return result_list", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"\n This function takes a list l and returns a list l' such that \n l' is identical to l in the indices that are not divisible by three, \n while its values at the indices that are divisible by three are equal \n to the values of the corresponding indices of l, but sorted.\n \n Args:\n l (list): Input list\n \n Returns:\n list: A list with elements at indices divisible by 3 sorted\n \"\"\"\n # Extract elements at indices divisible by 3\n third_elements = [l[i] for i in range(0, len(l), 3)]\n \n # Sort the elements\n third_elements.sort()\n \n # Initialize an empty result list\n result = []\n \n # Initialize an index for sorted elements\n third_index = 0\n \n # Iterate through the input list\n for i, element in enumerate(l):\n # Check if index is divisible by 3\n if i % 3 == 0:\n # Append sorted element if index is divisible by 3\n result.append(third_elements[third_index])\n # Increment sorted element index\n third_index += 1\n else:\n # Append original element if index is not divisible by 3\n result.append(element)\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(input_list: list) -> list:\n \"\"\"\n This function takes a list and returns a new list that is identical to the input list in the indices that are not divisible by three.\n Its values at the indices that are divisible by three are equal to the values of the corresponding indices of the input list, but sorted.\n \n Args:\n input_list (list): The list to be sorted.\n\n Returns:\n list: A new list with every third element sorted.\n \"\"\"\n \n # Separate elements at indices divisible by 3 from the rest of the list\n every_third_element = [input_list[i] for i in range(len(input_list)) if i % 3 == 0]\n other_elements = [input_list[i] for i in range(len(input_list)) if i % 3 != 0]\n \n # Sort the every third elements\n sorted_third_elements = sorted(every_third_element)\n \n # Initialize an empty list to store the final result\n result = []\n \n # Initialize counters for every third elements and other elements\n third_element_counter = 0\n other_element_counter = 0\n \n # Iterate over the input list's indices\n for i in range(len(input_list)):\n # If the index is divisible by 3, append the next sorted every third element\n if i % 3 == 0:\n result.append(sorted_third_elements[third_element_counter])\n third_element_counter += 1\n # Otherwise, append the next other element\n else:\n result.append(other_elements[other_element_counter])\n other_element_counter += 1\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list) -> list:\n \"\"\"\n This function takes a list l and returns a list l' such that\n l' is identical to l in the indices that are not divisible by three, \n while its values at the indices that are divisible by three are equal \n to the values of the corresponding indices of l, but sorted.\n \"\"\"\n sorted_thirds = sorted([l[i] for i in range(len(l)) if i % 3 == 0])\n result = []\n third_index = 0\n for i in range(len(l)):\n if i % 3 == 0:\n result.append(sorted_thirds[third_index])\n third_index += 1\n else:\n result.append(l[i])\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(lst: list) -> list:\n \"\"\"\n This function takes a list lst and returns a list lst' such that \n lst' is identical to lst in the indices that are not divisible by three, \n while its values at the indices that are divisible by three are equal \n to the values of the corresponding indices of lst, but sorted.\n\n Args:\n lst (list): The input list.\n\n Returns:\n list: The modified list.\n \"\"\"\n\n # Get all elements at indices divisible by 3\n elements_at_multiple_of_three = [lst[i] for i in range(len(lst)) if i % 3 == 0]\n\n # Sort the extracted elements\n sorted_elements_at_multiple_of_three = sorted(elements_at_multiple_of_three)\n\n # Create a new list with the sorted elements inserted at the correct indices\n sorted_list = []\n element_index = 0\n for i in range(len(lst)):\n if i % 3 == 0:\n sorted_list.append(sorted_elements_at_multiple_of_three[element_index])\n element_index += 1\n else:\n sorted_list.append(lst[i])\n\n return sorted_list", "matching_cluster_idx": 8}, {"solution": "def sort_third(input_list: list) -> list:\n \"\"\"\n This function takes a list input_list and returns a list l' such that \n l' is identical to input_list in the indices that are not divisible by three, \n while its values at the indices that are divisible by three are equal to the values \n of the corresponding indices of input_list, but sorted.\n\n Args:\n input_list (list): The list to be sorted at indices divisible by three.\n\n Returns:\n list: The modified list.\n \"\"\"\n # Separate the elements at indices divisible by 3\n third_indices = [input_list[i] for i in range(len(input_list)) if i % 3 == 0]\n \n # Sort these elements\n third_indices.sort()\n \n # Initialize an empty output list\n output_list = []\n \n # Initialize a counter for the third_indices list\n third_indices_counter = 0\n \n # Iterate over the range of the input list length\n for i in range(len(input_list)):\n # If the index is divisible by 3, append the corresponding sorted element\n if i % 3 == 0:\n output_list.append(third_indices[third_indices_counter])\n third_indices_counter += 1\n # Otherwise, append the original element\n else:\n output_list.append(input_list[i])\n \n return output_list", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"\n This function takes a list l and returns a list l' such that\n l' is identical to l in the indices that are not divisible by three, \n while its values at the indices that are divisible by three are equal \n to the values of the corresponding indices of l, but sorted.\n\n Args:\n l (list): The input list.\n\n Returns:\n list: The modified list.\n \"\"\"\n # Separate elements at indices that are divisible by three from the rest\n third_elements = sorted([l[i] for i in range(len(l)) if i % 3 == 0])\n other_elements = [l[i] for i in range(len(l)) if i % 3 != 0]\n\n # Initialize result list\n result = []\n\n # Merge the two lists\n i, j = 0, 0\n for k in range(len(l)):\n if k % 3 == 0:\n result.append(third_elements[i])\n i += 1\n else:\n result.append(other_elements[j])\n j += 1\n\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"\n This function takes a list l and returns a list l' such that \n l' is identical to l in the indices that are not divisible by three, \n while its values at the indices that are divisible by three are equal \n to the values of the corresponding indices of l, but sorted.\n\n Args:\n l (list): Input list to sort at indices divisible by three.\n\n Returns:\n list: List l' with values at indices divisible by three sorted.\n \"\"\"\n sorted_thirds = sorted([x for i, x in enumerate(l) if i % 3 == 0])\n result = []\n third_index = 0\n\n for i, x in enumerate(l):\n if i % 3 == 0:\n result.append(sorted_thirds[third_index])\n third_index += 1\n else:\n result.append(x)\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list) -> list:\n \"\"\"\n This function takes a list l and returns a list l' such that\n l' is identical to l in the indices that are not divisible by three, \n while its values at the indices that are divisible by three are equal \n to the values of the corresponding indices of l, but sorted.\n\n Args:\n l (list): The input list.\n\n Returns:\n list: A new list l' as described above.\n \"\"\"\n\n # Separate elements at indices divisible by 3\n third_elements = [l[i] for i in range(len(l)) if i % 3 == 0]\n \n # Sort the elements at indices divisible by 3\n third_elements.sort()\n \n # Create a new list l' by copying elements from l\n new_list = l.copy()\n \n # Replace elements at indices divisible by 3 in l' with sorted elements\n for i, element in enumerate(third_elements):\n new_list[i*3] = element\n \n return new_list", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list) -> list:\n \"\"\"\n This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, \n while its values at the indicies that are divisible by three are equal \n to the values of the corresponding indicies of l, but sorted.\n \"\"\"\n \n # Extract every third element from the list\n every_third_element = [l[i] for i in range(0, len(l), 3)]\n \n # Sort every third element\n every_third_element.sort()\n \n # Combine every third element back into the list while maintaining the original order\n result = []\n j = 0\n for i in range(len(l)):\n if i % 3 == 0:\n result.append(every_third_element[j])\n j += 1\n else:\n result.append(l[i])\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list) -> list:\n \"\"\"\n Returns a list l' such that l' is identical to l in the indices that are not divisible by three, \n while its values at the indices that are divisible by three are equal to the values of the corresponding \n indices of l, but sorted.\n\n Args:\n l (list): The input list.\n\n Returns:\n list: The modified list.\n \"\"\"\n # Separate the elements at indices divisible by 3 and sort them\n third_elements = sorted([l[i] for i in range(len(l)) if i % 3 == 0])\n \n # Initialize an empty list to store the result\n result = []\n \n # Initialize an index for the third_elements list\n third_index = 0\n \n # Iterate over the input list\n for i in range(len(l)):\n # If the index is divisible by 3, append the next element from the sorted third_elements list\n if i % 3 == 0:\n result.append(third_elements[third_index])\n third_index += 1\n # Otherwise, append the original element\n else:\n result.append(l[i])\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(input_list: list) -> list:\n \"\"\"\n Returns a new list that is identical to input_list except for the values \n at indices that are divisible by three, which are sorted.\n\n :param input_list: Input list to be modified\n :return: A new list with the specified changes\n \"\"\"\n # Separate elements at indices divisible by three and sort them\n third_elements = sorted([input_list[i] for i in range(0, len(input_list), 3)])\n\n # Create a new list to hold the result\n result = []\n\n # Initialize a counter to keep track of the index in third_elements\n third_index = 0\n\n # Iterate over input_list and replace elements at indices divisible by three\n for i, element in enumerate(input_list):\n if i % 3 == 0:\n # Replace element with the next element from third_elements\n result.append(third_elements[third_index])\n third_index += 1\n else:\n # Keep the original element\n result.append(element)\n\n return result", "matching_cluster_idx": 8}]}, "HumanEval/34": {"dps": 86.41509433962264, "dps_norm": 97.0, "pass@1": 100.0, "profiled": [{"solution": "import unittest\ndef unique(input_list: list) -> list:\n \"\"\"\n Return sorted unique elements in a list.\n\n Args:\n input_list (list): Input list containing duplicate elements.\n\n Returns:\n list: A new list containing unique elements from the input list in sorted order.\n\n Examples:\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(input_list))", "matching_cluster_idx": 4}, {"solution": "import unittest\ndef unique(input_list: list) -> list:\n \"\"\"\n Return sorted unique elements in a list\n\n Args:\n input_list (list): List of elements\n\n Returns:\n list: Sorted unique elements\n \"\"\"\n # Check if input is a list\n if not isinstance(input_list, list):\n raise TypeError(\"Input must be a list\")\n\n # Convert list to set to remove duplicates, then convert back to list and sort\n unique_list = sorted(set(input_list))\n\n return unique_list", "matching_cluster_idx": 4}, {"solution": "def unique(input_list: list) -> list:\n \"\"\"\n Return sorted unique elements in a list.\n\n Args:\n input_list (list): A list of elements (can be any type).\n\n Returns:\n list: A new list containing unique elements from the input list, in ascending order.\n \"\"\"\n return sorted(set(input_list))", "matching_cluster_idx": 4}, {"solution": "def unique(lst: list) -> list:\n \"\"\"\n Return sorted unique elements in a list\n\n Args:\n lst (list): The input list containing duplicate elements.\n\n Returns:\n list: A new list with unique elements in ascending order.\n\n Examples:\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(lst))", "matching_cluster_idx": 4}, {"solution": "def unique(input_list: list) -> list:\n \"\"\"\n Return sorted unique elements in a list\n\n Args:\n input_list (list): A list of elements.\n\n Returns:\n list: A list of unique elements sorted in ascending order.\n\n Examples:\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n\n # Convert the input list to a set, removing duplicates\n unique_set = set(input_list)\n \n # Convert the set back to a list and sort it\n sorted_list = sorted(list(unique_set))\n\n return sorted_list", "matching_cluster_idx": 4}, {"solution": "def unique(l: list) -> list:\n \"\"\"\n Return sorted unique elements in a list.\n\n Args:\n l (list): The input list.\n\n Returns:\n list: A sorted list of unique elements from the input list.\n\n Examples:\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n # Convert the list to a set to remove duplicates and then convert it back to a list\n unique_list = list(set(l))\n \n # Sort the list in ascending order\n unique_list.sort()\n \n return unique_list", "matching_cluster_idx": 4}, {"solution": "def unique(l: list) -> list:\n \"\"\"Return sorted unique elements in a list\n\n Args:\n l (list): Input list that may contain duplicate elements\n\n Returns:\n list: A new list containing sorted unique elements from the input list\n\n Examples:\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n\n # Convert the input list into a set to remove duplicate elements\n unique_set = set(l)\n \n # Convert the set back into a list and sort it in ascending order\n unique_list = sorted(list(unique_set))\n \n return unique_list", "matching_cluster_idx": 3}, {"solution": "import unittest\ndef unique(input_list: list) -> list:\n \"\"\"\n Returns a list of unique elements from the input list in sorted order.\n\n :param input_list: Input list of elements\n :return: Sorted list of unique elements\n \"\"\"\n return sorted(set(input_list))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list) -> list:\n \"\"\"\n Return sorted unique elements in a list\n\n Args:\n l (list): The list of elements to be sorted and have duplicates removed.\n\n Returns:\n list: A sorted list of unique elements.\n\n Examples:\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(input_list: list) -> list:\n \"\"\"\n Return sorted unique elements in a list.\n\n Args:\n input_list (list): A list of integers.\n\n Returns:\n list: A sorted list of unique integers.\n\n Examples:\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(input_list))", "matching_cluster_idx": 4}, {"solution": "def unique(input_list: list) -> list:\n \"\"\"\n Return sorted unique elements in a list.\n\n Args:\n input_list (list): The input list to process.\n\n Returns:\n list: A new list containing unique elements from the input list in sorted order.\n\n Examples:\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n # Convert the input list to a set to eliminate duplicates\n unique_elements = set(input_list)\n \n # Convert the set back to a list and sort the elements in ascending order\n unique_elements = sorted(list(unique_elements))\n \n return unique_elements\ninput_list = [5, 3, 5, 2, 3, 3, 9, 0, 123]", "matching_cluster_idx": 3}, {"solution": "import unittest\ndef unique(l: list) -> list:\n \"\"\"\n Return sorted unique elements in a list.\n\n Args:\n l (list): A list of elements.\n\n Returns:\n list: A list of unique elements in ascending order.\n\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(input_list: list) -> list:\n \"\"\"\n Return a new sorted list containing unique elements from the input list.\n \n :param input_list: The list from which to extract unique elements\n :return: A sorted list of unique elements\n \"\"\"\n return sorted(set(input_list))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list) -> list:\n \"\"\"\n Returns a sorted list of unique elements from the input list.\n\n Args:\n l (list): The input list.\n\n Returns:\n list: A sorted list of unique elements.\n\n Examples:\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n # Convert the list to a set to remove duplicates, then convert back to list\n # Sort the list in ascending order\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "import unittest\ndef unique(input_list: list) -> list:\n \"\"\"\n Return sorted unique elements in a list\n\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(input_list))", "matching_cluster_idx": 4}, {"solution": "def unique(input_list: list) -> list:\n \"\"\"\n Returns a new list containing unique elements from the input list in ascending order.\n \n :param input_list: Input list\n :return: A list of unique elements in ascending order\n \"\"\"\n return sorted(set(input_list))", "matching_cluster_idx": 4}, {"solution": "import doctest\ndef unique(input_list: list) -> list:\n \"\"\"\n Return sorted unique elements in a list.\n\n :param input_list: A list containing elements of any data type.\n :return: A new list containing unique elements from input_list in ascending order.\n \"\"\"\n return sorted(set(input_list))", "matching_cluster_idx": 4}, {"solution": "import unittest\ndef unique(l: list) -> list:\n \"\"\"\n Return sorted unique elements in a list\n \n :param l: Input list with possibly duplicate elements\n :return: A new list with unique elements sorted in ascending order\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(input_list: list) -> list:\n \"\"\"\n Return sorted unique elements in a list.\n\n Args:\n input_list (list): The input list.\n\n Returns:\n list: A list containing the unique elements of input_list, in sorted order.\n\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n # Convert list to set to remove duplicates\n unique_set = set(input_list)\n \n # Convert set back to list and sort it\n unique_sorted_list = sorted(list(unique_set))\n \n return unique_sorted_list", "matching_cluster_idx": 3}, {"solution": "import unittest\ndef unique(l: list):\n \"\"\"\n Return sorted unique elements in a list\n \n Args:\n l (list): Input list of elements\n \n Returns:\n list: A new list containing unique elements in ascending order\n \"\"\"\n # Convert list to a set to remove duplicates and then convert back to list\n # Use sorted() function to sort the list\n return sorted(set(l))", "matching_cluster_idx": 4}]}, "HumanEval/36": {"dps": 96.77419354838709, "dps_norm": 71.42857142857143, "pass@1": 100.0, "profiled": [{"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"\n Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n\n Args:\n n (int): The upper limit (exclusive).\n\n Returns:\n int: The number of times the digit 7 appears in the specified integers.\n \"\"\"\n count = 0 # Initialize a counter for the digit 7\n for i in range(1, n): # Iterate over integers less than n\n if i % 11 == 0 or i % 13 == 0: # Check if the integer is divisible by 11 or 13\n count += str(i).count('7') # Convert the integer to a string and count the occurrences of '7'\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"\n Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n\n Args:\n n (int): The upper limit (exclusive) for the numbers to be checked.\n\n Returns:\n int: The count of the digit 7 in numbers divisible by 11 or 13.\n\n Examples:\n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n for i in range(1, n): # We check numbers less than n\n if i % 11 == 0 or i % 13 == 0: # Check if i is divisible by 11 or 13\n count += str(i).count('7') # Count the occurrences of '7' in i\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"\n Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n\n :param n: The upper limit (exclusive) for the range of numbers to check.\n :return: The total count of the digit 7 in integers less than n that are divisible by 11 or 13.\n \"\"\"\n count = 0 # Initialize count variable to store occurrences of digit 7\n for i in range(n): # Iterate through numbers from 0 to n-1\n if i % 11 == 0 or i % 13 == 0: # Check if the number is divisible by 11 or 13\n count += str(i).count('7') # Convert the number to string and count the occurrences of '7'\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"\n Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n\n Args:\n n (int): An integer that serves as the upper limit.\n\n Returns:\n int: The count of digit 7 in integers less than n, that are divisible by 11 or 13.\n \"\"\"\n count = 0 # Initialize a variable to keep track of the count of digit 7\n\n # Iterate over the range from 1 to n (exclusive)\n for i in range(1, n):\n # Check if the number is divisible by 11 or 13\n if i % 11 == 0 or i % 13 == 0:\n # Convert the number to a string to easily count the occurrences of digit 7\n count += str(i).count('7')\n\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"\n Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n\n Args:\n n (int): The upper limit for integers to check.\n\n Returns:\n int: The number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n \"\"\"\n count = 0\n for i in range(1, n):\n # Check if the number is divisible by 11 or 13\n if i % 11 == 0 or i % 13 == 0:\n # Count the occurrences of '7' in the string representation of the number\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "import unittest\ndef fizz_buzz(n: int) -> int:\n \"\"\"\n Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n\n :param n: The upper limit (exclusive).\n :return: The number of times the digit 7 appears.\n \"\"\"\n count = 0\n for i in range(1, n):\n # Check if the number is divisible by 11 or 13\n if i % 11 == 0 or i % 13 == 0:\n # Convert the number to a string to count the digit 7\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int):\n \"\"\"\n Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n \n Parameters\n ----------\n n : int\n The upper limit for numbers to check (exclusive).\n \n Returns\n -------\n int\n The number of times the digit 7 appears in the required numbers.\n \"\"\"\n count = 0\n for i in range(n):\n # Check if the number is divisible by 11 or 13\n if i % 11 == 0 or i % 13 == 0:\n # Count the occurrences of digit 7 in the number\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"\n Returns the number of times the digit 7 appears in integers less than n \n which are divisible by 11 or 13.\n\n Args:\n n (int): The upper limit.\n\n Returns:\n int: The number of occurrences of digit 7.\n \"\"\"\n count = 0\n for i in range(1, n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"\n Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n \n Args:\n n (int): An integer greater than 0.\n \n Returns:\n int: The number of times the digit 7 appears.\n \"\"\"\n # Initialize counter for the digit 7\n count = 0\n \n # Iterate through numbers from 1 to n (not inclusive)\n for i in range(1, n):\n # Check if the number is divisible by 11 or 13\n if i % 11 == 0 or i % 13 == 0:\n # Convert the number to a string to count the digit 7\n str_i = str(i)\n # Count the occurrences of '7' in the string\n count += str_i.count('7')\n \n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"\n Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n\n Args:\n n (int): The upper limit for integers to check.\n\n Returns:\n int: The number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n \"\"\"\n count = 0\n for i in range(1, n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\"\"\"\n count = 0\n for i in range(1, n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"\n Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n\n Args:\n n (int): The upper limit (exclusive) for the range of integers to check.\n\n Returns:\n int: The number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n \"\"\"\n count = 0 # Initialize the count of digit 7 appearances\n for i in range(n): # Iterate over integers less than n\n if i % 11 == 0 or i % 13 == 0: # Check if the integer is divisible by 11 or 13\n count += str(i).count('7') # Increment the count by the number of '7's in the integer's string representation\n return count # Return the total count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"\n Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n\n Args:\n n (int): The upper limit.\n\n Returns:\n int: The number of times the digit 7 appears.\n \"\"\"\n count = 0\n for i in range(1, n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"\n Return the number of times the digit 7 appears in integers less than n \n which are divisible by 11 or 13.\n\n Args:\n n (int): The upper limit for the numbers to be checked.\n\n Returns:\n int: The number of times the digit 7 appears in the specified numbers.\n \"\"\"\n count = 0 # initialize the count variable\n for i in range(n): # loop over the numbers less than n\n if i % 11 == 0 or i % 13 == 0: # check if the number is divisible by 11 or 13\n count += str(i).count('7') # count the number of times '7' appears in the number\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"\n Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n\n Args:\n n (int): The upper limit.\n\n Returns:\n int: The number of times the digit 7 appears.\n \"\"\"\n count = 0\n for i in range(n):\n # Check if the number is divisible by 11 or 13\n if i % 11 == 0 or i % 13 == 0:\n # Convert the number to a string to count occurrences of '7'\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"\n Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n\n :param n: An integer that serves as an upper bound.\n :return: The total number of times the digit 7 appears in integers less than n that are divisible by 11 or 13.\n \"\"\"\n count = 0\n for i in range(n):\n # Check if the number is divisible by 11 or 13\n if i % 11 == 0 or i % 13 == 0:\n # Convert the number to string to count the occurrences of '7'\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"\n Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n\n Args:\n n (int): The upper limit.\n\n Returns:\n int: The number of times the digit 7 appears.\n\n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n for i in range(1, n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\"\"\"\n \n count = 0 # initialize counter for the number of occurrences of the digit 7\n for i in range(1, n): # loop through numbers less than n\n if i % 11 == 0 or i % 13 == 0: # check if the number is divisible by 11 or 13\n count += str(i).count('7') # count the number of occurrences of '7' and add to the total count\n \n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"\n Return the number of times the digit 7 appears in integers less than n \n which are divisible by 11 or 13.\n\n Args:\n n (int): The upper limit.\n\n Returns:\n int: The count of the digit 7 in integers less than n which are divisible by 11 or 13.\n\n Examples:\n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n for i in range(1, n):\n # Check if i is divisible by 11 or 13\n if i % 11 == 0 or i % 13 == 0:\n # Convert the integer to string and count the occurrences of '7'\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int):\n \"\"\"\n Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n\n Args:\n n (int): The upper limit (exclusive) to check numbers up to.\n\n Returns:\n int: The count of occurrences of the digit 7.\n \"\"\"\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}]}, "HumanEval/37": {"dps": 94.92635024549918, "dps_norm": 90.0, "pass@1": 94.0, "profiled": [{"solution": "def sort_even(lst: list) -> list:\n \"\"\"This function takes a list lst and returns a list lst' such that\n lst' is identical to lst in the odd indices, while its values at the even indices are equal\n to the values of the even indices of lst, but sorted.\n\n Args:\n lst (list): The input list.\n\n Returns:\n list: The transformed list.\n \"\"\"\n even_values = sorted([lst[i] for i in range(0, len(lst), 2)])\n result = []\n \n even_index = 0\n for i in range(len(lst)):\n if i % 2 == 0:\n result.append(even_values[even_index])\n even_index += 1\n else:\n result.append(lst[i])\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list) -> list:\n \"\"\"\n This function takes a list l and returns a list l' such that \n l' is identical to l in the odd indices, while its values at the even indices are equal \n to the values of the even indices of l, but sorted.\n\n Args:\n l (list): Input list\n\n Returns:\n list: A new list where values at even indices are sorted, while values at odd indices remain the same.\n \"\"\"\n\n # Separate even and odd indexed elements\n even_indexed = l[::2]\n odd_indexed = l[1::2]\n\n # Sort the even indexed elements\n sorted_even_indexed = sorted(even_indexed)\n\n # Initialize result list with None values\n result = [None] * len(l)\n\n # Fill even indices with sorted even indexed elements\n result[::2] = sorted_even_indexed\n\n # Fill odd indices with original odd indexed elements\n result[1::2] = odd_indexed\n\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list) -> list:\n \"\"\"\n Returns a list where even-indexed values from the original list are sorted \n and the rest remain unchanged.\n \n :param l: Input list.\n :return: List where even-indexed values are sorted from the input list.\n \"\"\"\n # Separate even-indexed values and sort them\n even_values = sorted([l[i] for i in range(0, len(l), 2)])\n # Initialize the result list\n result = []\n # Initialize the even index\n even_index = 0\n \n # Iterate through the original list and the even-indexed list in tandem\n for i in range(len(l)):\n if i % 2 == 0:\n # For even indices, add the corresponding value from the sorted list\n result.append(even_values[even_index])\n # Move to the next even value\n even_index += 1\n else:\n # For odd indices, keep the original value\n result.append(l[i])\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(numbers: list):\n \"\"\"This function takes a list numbers and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n \n Args:\n numbers (list): Input list to process.\n \n Returns:\n list: A new list where the even indices are sorted based on even-index values of the input list.\n \"\"\"\n\n # Collect the values from even indices\n even_index_values = [numbers[i] for i in range(0, len(numbers), 2)]\n \n # Sort the values from even indices\n sorted_even_index_values = sorted(even_index_values)\n \n # Combine the sorted even-index values and the odd-index values\n result = []\n sorted_even_index_iter = iter(sorted_even_index_values)\n for i, value in enumerate(numbers):\n if i % 2 == 0:\n result.append(next(sorted_even_index_iter))\n else:\n result.append(value)\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(input_list: list) -> list:\n \"\"\"\n This function takes a list and returns a new list where the values at the even indices\n are sorted, while keeping the values at the odd indices unchanged.\n\n Args:\n input_list (list): The input list.\n\n Returns:\n list: A new list with sorted even indices.\n \"\"\"\n # Separate even indexed values into a separate list\n even_values = [value for index, value in enumerate(input_list) if index % 2 == 0]\n\n # Sort the even values\n even_values.sort()\n\n # Initialize the output list with the same length as the input list\n output_list = [None] * len(input_list)\n\n # Fill in the even indices with sorted even values\n for index, value in enumerate(even_values):\n output_list[index * 2] = value\n\n # Fill in the odd indices with the original values from the input list\n for index, value in enumerate(input_list):\n if index % 2 != 0:\n output_list[index] = value\n\n return output_list", "matching_cluster_idx": 8}, {"solution": "def sort_even(numbers: list):\n \"\"\"\n This function takes a list of numbers and returns a new list.\n In the new list, the values at even indices are the same as the values at even indices in the input list, but sorted.\n The values at odd indices in the new list are the same as the values at odd indices in the input list.\n \n :param numbers: Input list\n :return: New list with sorted values at even indices\n \"\"\"\n even_numbers = [numbers[i] for i in range(0, len(numbers), 2)]\n sorted_even_numbers = sorted(even_numbers)\n \n result = []\n even_index = 0\n for i in range(len(numbers)):\n if i % 2 == 0:\n result.append(sorted_even_numbers[even_index])\n even_index += 1\n else:\n result.append(numbers[i])\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(input_list: list) -> list:\n \"\"\"\n This function takes a list and returns a new list where the values at even indices\n are equal to the sorted values of the even indices in the original list, \n while the values at the odd indices remain unchanged.\n\n Args:\n input_list (list): Input list to sort even indices of.\n\n Returns:\n list: New list with sorted even indices.\n \"\"\"\n\n # Separate even indexed elements from the input list\n even_elements = [input_list[i] for i in range(0, len(input_list), 2)]\n\n # Sort the even indexed elements\n even_elements.sort()\n\n # Initialize the output list\n output_list = []\n\n # Initialize an index for the sorted even elements\n even_index = 0\n\n # Iterate over the range of input list\n for i in range(len(input_list)):\n # If the index is even, append the next sorted even element\n if i % 2 == 0:\n output_list.append(even_elements[even_index])\n even_index += 1\n # If the index is odd, append the original element\n else:\n output_list.append(input_list[i])\n\n return output_list", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list) -> list:\n \"\"\"\n This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indices, while its values at the even indices are equal\n to the values of the even indices of l, but sorted.\n \"\"\"\n even_values = sorted([l[i] for i in range(0, len(l), 2)])\n result = []\n \n # Fill even indices of the result list with the sorted even values\n even_index = 0\n for i, value in enumerate(l):\n if i % 2 == 0:\n result.append(even_values[even_index])\n even_index += 1\n else:\n # Fill odd indices of the result list with the original values\n result.append(value)\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list) -> list:\n \"\"\"\n This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n \n Args:\n l (list): Input list\n \n Returns:\n list: The modified list with sorted even indices\n \"\"\"\n even_elements = sorted([l[i] for i in range(0, len(l), 2)]) # Get even index elements and sort them\n result = [] # Initialize an empty list to store the result\n \n even_index = 0 # Keep track of the current even index element\n \n for i in range(len(l)):\n if i % 2 == 0: # If the index is even\n result.append(even_elements[even_index]) # Add the next even index element\n even_index += 1\n else:\n result.append(l[i]) # If the index is odd, keep the original element\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(nums):\n \"\"\"\n Sort the values at even indices of the input list and keep the values at odd indices unchanged.\n\n Args:\n - nums: A list of integers.\n\n Returns:\n - A new list with sorted even-indexed values and unchanged odd-indexed values.\n\n Example:\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n\n # Separate even-indexed elements\n even_elements = [nums[i] for i in range(0, len(nums), 2)]\n \n # Sort the even-indexed elements\n even_elements.sort()\n \n # Merge the sorted even-indexed elements back into the original list\n sorted_even = [even_elements[i // 2] if i % 2 == 0 else nums[i] for i in range(len(nums))]\n \n return sorted_even", "matching_cluster_idx": 8}, {"solution": "def sort_even(input_list):\n \"\"\"\n This function takes a list and returns a new list. \n The values at the odd indices of the new list are the same as the input list, \n while the values at the even indices are the same as the input list's even indices, but sorted.\n\n Args:\n input_list (list): Input list\n\n Returns:\n list: A new list that is a modified version of the input list\n \"\"\"\n\n # Extract even index values from the input list\n even_index_values = [input_list[i] for i in range(0, len(input_list), 2)]\n \n # Sort even index values\n even_index_values.sort()\n\n # Initialize output list\n output_list = []\n\n # Initialize a counter for tracking even index\n even_index_counter = 0\n\n # Fill output list\n for i in range(0, len(input_list)):\n # If index is even, append sorted even index value\n if i % 2 == 0:\n output_list.append(even_index_values[even_index_counter])\n even_index_counter += 1\n # If index is odd, append original value\n else:\n output_list.append(input_list[i])\n\n return output_list", "matching_cluster_idx": 8}, {"solution": "def sort_even(lst: list) -> list:\n \"\"\"\n This function takes a list lst and returns a list lst' such that\n lst' is identical to lst in the odd indices, while its values at the even indices are equal\n to the values of the even indices of lst, but sorted.\n\n Args:\n lst (list): Input list\n\n Returns:\n list: A new list where even indices are sorted\n \"\"\"\n\n # Separate elements at even indices\n even_elements = [lst[i] for i in range(0, len(lst), 2)]\n \n # Sort the even elements\n even_elements.sort()\n\n # Initialize an empty list to store result\n result = []\n\n # Initialize index for even elements\n even_index = 0\n\n # Iterate over the input list with both index and value\n for i, value in enumerate(lst):\n # If the index is even, append the next even element from the sorted list\n if i % 2 == 0:\n result.append(even_elements[even_index])\n even_index += 1\n # If the index is odd, append the original value\n else:\n result.append(value)\n\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(input_list: list) -> list:\n \"\"\"\n This function takes a list and returns a new list where odd indices are identical to the input list,\n and the values at the even indices are the sorted values from the even indices of the input list.\n\n :param input_list: A list of integers\n :return: A new list with sorted even indices\n \"\"\"\n\n # Extract even-indexed values from the input list\n even_values = [input_list[i] for i in range(len(input_list)) if i % 2 == 0]\n \n # Sort the even-indexed values\n sorted_even_values = sorted(even_values)\n \n # Initialize an empty list to store the result\n result = []\n \n # Initialize a counter to keep track of the current index in the sorted even values\n even_index = 0\n \n # Iterate over the input list\n for i in range(len(input_list)):\n # If the index is even, append the next sorted even value to the result list\n if i % 2 == 0:\n result.append(sorted_even_values[even_index])\n even_index += 1\n # If the index is odd, append the original value from the input list to the result list\n else:\n result.append(input_list[i])\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(input_list):\n \"\"\"\n This function takes a list and returns a list l' such that \n l' is identical to l in the odd indices, while its values at the even indices are equal \n to the values of the even indices of l, but sorted.\n\n Args:\n input_list (list): The input list to be processed.\n\n Returns:\n list: The processed list.\n \"\"\"\n even_elements = sorted([input_list[i] for i in range(0, len(input_list), 2)])\n even_index = 0\n\n result = []\n for i, elem in enumerate(input_list):\n if i % 2 == 0:\n result.append(even_elements[even_index])\n even_index += 1\n else:\n result.append(elem)\n\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(input_list: list) -> list:\n \"\"\"\n This function takes a list and returns a new list where the values at even indices \n are sorted, while the values at odd indices remain the same.\n\n Args:\n input_list (list): The input list to be sorted at even indices.\n\n Returns:\n list: A new list with even indices sorted.\n \"\"\"\n even_values = sorted([input_list[i] for i in range(len(input_list)) if i % 2 == 0])\n result = []\n \n even_index = 0\n for i in range(len(input_list)):\n if i % 2 == 0:\n result.append(even_values[even_index])\n even_index += 1\n else:\n result.append(input_list[i])\n \n return result", "matching_cluster_idx": 8}, {"solution": "import unittest\ndef sort_even(input_list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\"\"\"\n \n # extract elements at even indices\n even_elements = [input_list[i] for i in range(0, len(input_list), 2)]\n \n # sort the extracted even elements\n even_elements.sort()\n \n # merge the sorted even elements back into the original list\n sorted_list = []\n even_index = 0\n for i in range(len(input_list)):\n if i % 2 == 0:\n sorted_list.append(even_elements[even_index])\n even_index += 1\n else:\n sorted_list.append(input_list[i])\n \n return sorted_list", "matching_cluster_idx": 8}, {"solution": "def sort_even(input_list: list) -> list:\n \"\"\"\n This function takes a list and returns a new list where values at even indices are sorted.\n\n Args:\n input_list (list): A list of elements.\n\n Returns:\n list: A new list where values at even indices are sorted.\n \"\"\"\n # Extract elements at even indices, sort them, and store in a list\n even_elements = sorted([input_list[i] for i in range(0, len(input_list), 2)])\n \n # Create a result list with the same length as the input list\n result_list = []\n \n # Initialize index for even elements list\n even_index = 0\n \n # Iterate over the range of the length of the input list\n for i in range(len(input_list)):\n # If the index is even, append the next even element from the sorted list\n if i % 2 == 0:\n result_list.append(even_elements[even_index])\n even_index += 1\n # If the index is odd, append the element from the input list\n else:\n result_list.append(input_list[i])\n \n # Return the result list\n return result_list", "matching_cluster_idx": 8}, {"solution": "def sort_even(numbers: list) -> list:\n \"\"\"\n Returns a new list where the elements at even indices are sorted \n while maintaining the original elements at odd indices.\n\n Args:\n numbers: A list of numbers\n\n Returns:\n A new list where the elements at even indices are sorted\n \"\"\"\n even_nums = sorted([num for idx, num in enumerate(numbers) if idx % 2 == 0])\n result = []\n even_idx = 0\n\n for idx, num in enumerate(numbers):\n if idx % 2 == 0:\n result.append(even_nums[even_idx])\n even_idx += 1\n else:\n result.append(num)\n\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(input_list: list):\n \"\"\"\n This function takes a list and returns a new list where values at even indices are sorted\n while values at odd indices remain the same.\n\n Args:\n input_list (list): A list containing elements to be sorted.\n\n Returns:\n list: A new list with even index elements sorted.\n \"\"\"\n # separate even-indexed elements\n even_elements = [input_list[i] for i in range(len(input_list)) if i % 2 == 0]\n \n # sort even-indexed elements\n even_elements.sort()\n \n # combine sorted even-indexed elements with odd-indexed elements\n result = []\n even_index = 0\n for i in range(len(input_list)):\n if i % 2 == 0:\n result.append(even_elements[even_index])\n even_index += 1\n else:\n result.append(input_list[i])\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(lst: list) -> list:\n \"\"\"\n This function takes a list lst and returns a list l' such that\n l' is identical to lst in the odd indices, while its values at the even indices are equal\n to the values of the even indices of lst, but sorted.\n\n Args:\n lst (list): Input list.\n\n Returns:\n list: Modified list.\n \"\"\"\n\n # Separate even-indexed values from the list and sort them\n even_values = sorted([lst[i] for i in range(0, len(lst), 2)])\n\n # Initialize an empty list to store the result\n result = []\n\n # Initialize an index to keep track of the current even value to use\n even_index = 0\n\n # Iterate over the input list with both index and value\n for i, value in enumerate(lst):\n # If the index is even, append the next even value from the sorted list\n if i % 2 == 0:\n result.append(even_values[even_index])\n even_index += 1\n # If the index is odd, append the original value\n else:\n result.append(value)\n\n return result", "matching_cluster_idx": 8}]}, "HumanEval/49": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 53.0, "profiled": [{"solution": "def modp(n: int, p: int) -> int:\n \"\"\"\n Return 2^n modulo p.\n\n Args:\n n (int): The exponent.\n p (int): The modulus.\n\n Returns:\n int: 2^n mod p.\n\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"\n Return 2^n modulo p.\n\n Args:\n n: The power to which 2 is raised.\n p: The modulo.\n\n Returns:\n An integer representing 2^n modulo p.\n\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n\n # Use the built-in pow function with three arguments to calculate (2^n) % p efficiently\n # The third argument to pow is the modulo, which prevents the number from getting too large\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"\n Return 2^n modulo p, ensuring efficient calculation \n to prevent potential numerics overflow issues.\n\n Args:\n n (int): The exponent.\n p (int): The modulo.\n\n Returns:\n int: The result of 2^n modulo p.\n \"\"\"\n # Use built-in pow function with three arguments for efficiency\n # The third argument is the modulo, preventing overflow\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"\n Return 2^n modulo p.\n\n Args:\n n (int): The power of 2.\n p (int): The modulus.\n\n Returns:\n int: 2^n modulo p.\n \"\"\"\n # Use built-in pow function for efficient calculation\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"\n Return 2^n modulo p.\n\n This function uses the built-in pow function which can handle modular exponentiation\n efficiently to avoid large intermediate results.\n\n Args:\n n (int): The exponent.\n p (int): The modulus.\n\n Returns:\n int: The result of 2^n modulo p.\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"\n Return 2^n modulo p (be aware of numerics).\n\n Args:\n n (int): The power of 2.\n p (int): The modulo value.\n\n Returns:\n int: The result of 2^n modulo p.\n\n \"\"\"\n # Use Python's built-in support for large integers and pow() function,\n # which computes the power in a way that minimizes the need for large intermediate results.\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"\n Returns 2^n modulo p, handling large inputs efficiently.\n\n Args:\n n (int): The exponent\n p (int): The modulus\n\n Returns:\n int: 2^n mod p\n \"\"\"\n # Use the built-in pow function with three arguments for modulus operation\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"\n Return 2^n modulo p (be aware of numerics).\n\n The function leverages Python's built-in support for arbitrary-precision arithmetic\n and utilizes the property of modular exponentiation to efficiently calculate\n the result.\n\n Args:\n n (int): The exponent.\n p (int): The modulus.\n\n Returns:\n int: The result of 2^n modulo p.\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "import doctest\ndef modp(n: int, p: int) -> int:\n \"\"\"\n Return 2^n modulo p.\n\n Args:\n n (int): The power of 2.\n p (int): The modulo value.\n\n Returns:\n int: 2^n modulo p.\n\n Raises:\n ValueError: If n or p are not integers.\n\n Examples:\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n if not isinstance(n, int) or not isinstance(p, int):\n raise ValueError(\"Both n and p must be integers.\")\n\n # Use the built-in pow function to efficiently compute 2^n % p.\n # The pow function takes three arguments: base, exponent, and modulus.\n # It returns (base ^ exponent) % modulus, which is equivalent to 2^n % p.\n result = pow(2, n, p)\n\n return result", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"\n Return 2^n modulo p, aware of potential numeric issues.\n\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n # Calculate 2^n using Python's built-in pow() with three arguments.\n # The third argument is a modulus for efficient computation.\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"\n Return 2^n modulo p, being aware of numerics.\n \n This function calculates 2 to the power of n and then returns the remainder when \n divided by p, to avoid potential numerics problems. It uses the built-in \n pow() function which can handle very large numbers efficiently.\n\n :param n: The exponent\n :param p: The modulus\n :return: 2^n modulo p\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"\n Return 2^n modulo p.\n\n This function uses the built-in pow function in Python, which can efficiently\n calculate the power of a number and apply modulus to prevent overflow.\n\n Args:\n n (int): The power to which 2 is raised.\n p (int): The modulus.\n\n Returns:\n int: The result of 2^n modulo p.\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int):\n \"\"\"\n Return 2^n modulo p.\n \n This function calculates the value of 2 raised to the power of n, \n then returns the remainder when this value is divided by p.\n \n :param n: The power to which 2 is raised.\n :type n: int\n :param p: The divisor for the modulus operation.\n :type p: int\n :return: The result of 2^n modulo p.\n :rtype: int\n \"\"\"\n # Handle edge case for p equal to 1\n if p == 1:\n return 0\n \n # Use the built-in pow function to calculate 2^n modulo p.\n # This function is efficient and avoids overflow issues.\n result = pow(2, n, p)\n \n return result", "matching_cluster_idx": 4}, {"solution": "import unittest\ndef modp(n: int, p: int) -> int:\n \"\"\"\n Return 2^n modulo p (be aware of numerics).\n\n This function uses the built-in pow function with three arguments to compute\n (a**b) % c efficiently. The third argument to pow is optional and is the\n modulus.\n\n Args:\n n (int): The exponent.\n p (int): The modulus.\n\n Returns:\n int: 2^n modulo p.\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"\n Return 2^n modulo p.\n\n This function calculates the modular exponentiation using the properties of modular arithmetic.\n\n Args:\n n: The exponent\n p: The modulus\n\n Returns:\n The result of 2^n modulo p\n\n Examples:\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n # Python's built-in pow() function can calculate modular exponentiation efficiently\n # The third argument to pow() is the modulus\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"\n Calculate 2^n modulo p.\n\n The function utilizes Python's built-in pow function with three arguments, \n which calculates the power with modulo efficiently.\n\n Args:\n n (int): The exponent.\n p (int): The modulo.\n\n Returns:\n int: 2^n modulo p.\n\n Examples:\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"\n Return 2^n modulo p.\n\n This function uses the built-in pow function with three arguments,\n which is more efficient and safer for large inputs than the naive approach.\n\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"\n Calculate 2^n modulo p using the built-in pow function for efficiency and \n to prevent potential numeric overflow.\n\n Args:\n n (int): The exponent\n p (int): The modulus\n\n Returns:\n int: 2^n modulo p\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"\n Return 2^n modulo p (be aware of numerics).\n\n Args:\n n: The power to which 2 is raised.\n p: The modulus.\n\n Returns:\n The result of 2^n modulo p.\n\n Examples:\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n # Use built-in pow function to compute (2^n) % p efficiently.\n # The third argument to pow is the modulus, allowing us to avoid large intermediates.\n result = pow(2, n, p)\n return result", "matching_cluster_idx": 4}, {"solution": "import unittest\ndef modp(n: int, p: int) -> int:\n \"\"\"\n Return 2^n modulo p (be aware of numerics).\n\n This function uses the built-in pow function with three arguments, which \n efficiently calculates (x^y) % z for large x, y, and z.\n\n Args:\n n (int): The exponent.\n p (int): The modulus.\n\n Returns:\n int: 2^n modulo p.\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}]}, "HumanEval/51": {"dps": 96.13526570048309, "dps_norm": 75.0, "pass@1": 100.0, "profiled": [{"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n \"\"\"\n # Define all vowels\n vowels = 'aeiouAEIOU'\n\n # Return string without vowels\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes a string and returns a string without vowels.\n\n :param text: Input string that may contain vowels.\n :return: A string without vowels.\n \"\"\"\n # Define a string of all lowercase and uppercase vowels\n vowels = 'aeiouAEIOU'\n\n # Use a generator expression with a conditional to iterate over each character in the string\n # If the character is not a vowel, include it in the new string\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes a string and returns the string without vowels.\n \n Parameters:\n text (str): Input string\n \n Returns:\n str: Input string without vowels\n \"\"\"\n vowels = 'aeiouAEIOU'\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "import unittest\ndef remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes a string and returns the string without vowels.\n \"\"\"\n vowels = 'aeiouAEIOU'\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "import unittest\ndef remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n\n Args:\n text (str): Input string.\n\n Returns:\n str: String without vowels.\n \"\"\"\n # Define all vowels\n vowels = 'aeiouAEIOU'\n # Use a generator expression within the join() method to filter out vowels\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes a string and returns a string without vowels.\n\n Parameters:\n text (str): Input string.\n\n Returns:\n str: String without vowels.\n \"\"\"\n vowels = 'aeiouAEIOU'\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n \"\"\"\n # Define all lowercase and uppercase vowels\n vowels = 'aeiouAEIOU'\n # Use a generator expression with a conditional to filter out the vowels\n return ''.join(char for char in text if char not in vowels)", "matching_cluster_idx": 5}, {"solution": "import unittest\ndef remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes a string and returns a string without vowels.\n \n :param text: The input string from which vowels are to be removed.\n :return: The input string without vowels.\n \"\"\"\n vowels = 'aeiouAEIOU'\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n \n :param text: Input string\n :return: String without vowels\n \"\"\"\n vowels = 'aeiouAEIOU'\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n\n :param text: The input string from which vowels are to be removed.\n :return: A string with vowels removed.\n \"\"\"\n vowels = 'aeiouAEIOU'\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n Removes all vowels from a given string.\n\n Args:\n text (str): The input string.\n\n Returns:\n str: The input string without vowels.\n \"\"\"\n vowels = 'aeiouAEIOU'\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes a string and returns the string without vowels.\n\n :param text: input string\n :return: string without vowels\n \"\"\"\n vowels = 'aeiouAEIOU'\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes a string and returns string without vowels.\n \n :param text: The input string to remove vowels from.\n :return: A string without vowels.\n \"\"\"\n # Define a string of lowercase and uppercase vowels\n vowels = 'aeiouAEIOU'\n \n # Use a list comprehension to iterate over the input string, keeping only characters not in vowels\n # Join the characters back into a string\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n \n :param text: The input string.\n :return: The input string with all vowels removed.\n \"\"\"\n vowels = 'aeiouAEIOU'\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes a string and returns a string without vowels.\n \n Parameters\n ----------\n text : str\n The input string that may contain vowels.\n \n Returns\n -------\n str\n The input string without vowels.\n \"\"\"\n # Define a string of vowels\n vowels = 'aeiouAEIOU'\n \n # Use a list comprehension to create a new string with characters that are not vowels\n # The join method concatenates the characters in the list into a string\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "import doctest\ndef remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n \"\"\"\n vowels = 'aeiouAEIOU'\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes a string and returns a string without vowels.\n \n Parameters:\n text (str): input string\n \n Returns:\n str: input string without vowels\n \"\"\"\n # Define all vowels (lowercase and uppercase)\n vowels = 'aeiouAEIOU'\n \n # Use a list comprehension to iterate over each character in the input string\n # If the character is not a vowel, add it to the resulting string\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n Removes vowels from the input string, ignoring case.\n\n Args:\n text (str): The string from which to remove vowels.\n\n Returns:\n str: The string with vowels removed.\n \"\"\"\n vowels = 'aeiouAEIOU'\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n Removes vowels from the input text.\n\n Args:\n text (str): Input string.\n\n Returns:\n str: String without vowels.\n \"\"\"\n vowels = 'aeiouAEIOU'\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n\n Args:\n text (str): Input string.\n\n Returns:\n str: String without vowels.\n \"\"\"\n vowels = 'aeiouAEIOU'\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}]}, "HumanEval/54": {"dps": 95.42553191489361, "dps_norm": 97.14285714285714, "pass@1": 70.0, "profiled": [{"solution": "def same_chars(s0: str, s1: str):\n \"\"\"\n Check if two words have the same characters.\n \n Args:\n s0 (str): The first string to compare.\n s1 (str): The second string to compare.\n \n Returns:\n bool: True if both strings have the same characters, False otherwise.\n \"\"\"\n # Convert both strings to sets (which automatically removes duplicates), and compare them\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n\n Args:\n s0 (str): The first string to compare.\n s1 (str): The second string to compare.\n\n Returns:\n bool: True if both strings have the same characters, False otherwise.\n \"\"\"\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "from collections import Counter\nimport doctest\ndef same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n\n Args:\n s0 (str): The first string.\n s1 (str): The second string.\n\n Returns:\n bool: True if both strings have the same characters, False otherwise.\n \"\"\"\n # Count the frequency of characters in both strings\n count_s0 = Counter(s0)\n count_s1 = Counter(s1)\n\n # Check if the character sets are equal\n return set(count_s0.keys()) == set(count_s1.keys())", "matching_cluster_idx": 2}, {"solution": "import unittest\ndef same_chars(s0: str, s1: str):\n \"\"\"\n Check if two words have the same characters.\n\n Args:\n s0 (str): First string to compare.\n s1 (str): Second string to compare.\n\n Returns:\n bool: True if the two strings contain the same characters, False otherwise.\n \"\"\"\n # Convert both strings to sets of characters and compare them\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n\n This function returns True if both strings have the same characters,\n disregarding their order and frequency in the strings.\n\n Parameters:\n s0 (str): The first string.\n s1 (str): The second string.\n\n Returns:\n bool: True if both strings have the same characters, False otherwise.\n \"\"\"\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \n Args:\n s0 (str): The first string.\n s1 (str): The second string.\n \n Returns:\n bool: True if both strings have the same characters, False otherwise.\n \"\"\"\n \n # Convert the input strings to sets of characters\n set0 = set(s0)\n set1 = set(s1)\n \n # Compare the two sets\n return set0 == set1", "matching_cluster_idx": 6}, {"solution": "import unittest\ndef same_chars(s0: str, s1: str):\n \"\"\"\n Check if two words have the same characters.\n \n Args:\n s0 (str): First string for comparison.\n s1 (str): Second string for comparison.\n\n Returns:\n bool: True if both strings have the same characters (regardless of order and count), False otherwise.\n \"\"\"\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n\n Args:\n s0 (str): The first string to compare.\n s1 (str): The second string to compare.\n\n Returns:\n bool: True if both strings have the same characters, False otherwise.\n \"\"\"\n # Convert the strings to sets to remove duplicate characters and order\n set0 = set(s0)\n set1 = set(s1)\n\n # Compare the two sets for equality\n return set0 == set1", "matching_cluster_idx": 6}, {"solution": "from collections import Counter\ndef same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \n This function uses Python's Counter class to count the occurrences of each character \n in both strings, then compares the resulting dictionaries.\n \n Args:\n s0 (str): The first string.\n s1 (str): The second string.\n \n Returns:\n bool: True if both strings have the same characters, False otherwise.\n \"\"\"\n # Remove duplicate characters by converting to set\n # This assumes that the order of characters does not matter\n set0 = set(s0)\n set1 = set(s1)\n \n # If the sets are equal, it means both strings have the same characters\n return set0 == set1", "matching_cluster_idx": 6}, {"solution": "import unittest\ndef same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \"\"\"\n # Remove duplicates and sort the characters in each string, then compare the results\n return sorted(set(s0)) == sorted(set(s1))", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str):\n \"\"\"\n Check if two words have the same characters.\n \n Args:\n s0 (str): The first word.\n s1 (str): The second word.\n \n Returns:\n bool: True if the words have the same characters, False otherwise.\n \"\"\"\n # Convert strings to sets of characters and compare them.\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str):\n \"\"\"\n Check if two words have the same characters.\n \n Args:\n s0 (str): First input string.\n s1 (str): Second input string.\n\n Returns:\n bool: True if the two input strings have the same characters, False otherwise.\n\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')\n True\n >>> same_chars('abcd', 'dddddddabc')\n True\n >>> same_chars('dddddddabc', 'abcd')\n True\n >>> same_chars('eabcd', 'dddddddabc')\n False\n >>> same_chars('abcd', 'dddddddabce')\n False\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')\n False\n \"\"\"\n # Remove duplicate characters by converting the strings to sets\n # Compare the two sets for equality\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n :param s0: The first string.\n :param s1: The second string.\n :return: True if both strings contain the same characters, False otherwise.\n \"\"\"\n # Convert both strings to sets, which remove duplicate characters\n # and then check if these sets are equal\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "import doctest\ndef same_chars(s0: str, s1: str):\n \"\"\"\n Check if two words have the same characters.\n\n Args:\n s0 (str): The first word.\n s1 (str): The second word.\n\n Returns:\n bool: True if the words have the same characters, False otherwise.\n \"\"\"\n # Normalize the input strings by sorting their characters and removing duplicates\n normalized_s0 = \"\".join(sorted(set(s0)))\n normalized_s1 = \"\".join(sorted(set(s1)))\n\n # Compare the normalized strings\n return normalized_s0 == normalized_s1", "matching_cluster_idx": 6}, {"solution": "import unittest\ndef same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n\n Args:\n s0 (str): The first word to compare.\n s1 (str): The second word to compare.\n\n Returns:\n bool: True if the two words have the same characters, False otherwise.\n \"\"\"\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str):\n \"\"\"\n Check if two words have the same characters.\n\n Args:\n s0 (str): The first string to compare.\n s1 (str): The second string to compare.\n\n Returns:\n bool: True if the strings contain the same characters, False otherwise.\n \"\"\"\n # Convert both strings to sets of characters (removes duplicates)\n set0 = set(s0)\n set1 = set(s1)\n \n # Compare the two sets\n return set0 == set1", "matching_cluster_idx": 6}, {"solution": "import doctest\ndef same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n\n Args:\n s0 (str): The first string.\n s1 (str): The second string.\n\n Returns:\n bool: True if the strings have the same characters, False otherwise.\n \"\"\"\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n\n Args:\n s0 (str): The first word.\n s1 (str): The second word.\n\n Returns:\n bool: True if both words have the same characters, False otherwise.\n \"\"\"\n # Convert both strings to sets, which automatically removes duplicate characters\n set0 = set(s0)\n set1 = set(s1)\n\n # Check if both sets are equal\n return set0 == set1", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str):\n \"\"\"\n Check if two words have the same characters.\n\n Args:\n s0 (str): The first word.\n s1 (str): The second word.\n\n Returns:\n bool: True if both words have the same characters, False otherwise.\n \"\"\"\n # Convert both strings to sets to remove duplicates and compare\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n\n Args:\n s0 (str): The first word.\n s1 (str): The second word.\n\n Returns:\n bool: True if both words have the same characters, False otherwise.\n \"\"\"\n # Convert both strings to sets, which automatically removes duplicates\n set0 = set(s0)\n set1 = set(s1)\n\n # Compare the two sets. If they are equal, the strings have the same characters.\n return set0 == set1", "matching_cluster_idx": 6}]}, "HumanEval/58": {"dps": 92.51968503937007, "dps_norm": 83.33333333333333, "pass@1": 100.0, "profiled": [{"solution": "def common(l1: list, l2: list) -> list:\n \"\"\"\n Return sorted unique common elements for two lists.\n\n Args:\n l1 (list): The first list.\n l2 (list): The second list.\n\n Returns:\n list: A list of unique common elements from both lists, sorted in ascending order.\n\n Examples:\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n # Convert the input lists to sets to remove duplicates and improve lookup efficiency\n set1 = set(l1)\n set2 = set(l2)\n \n # Find the intersection of the two sets, which represents the common elements\n common_elements = set1.intersection(set2)\n \n # Convert the set back to a list and sort it\n sorted_common_elements = sorted(list(common_elements))\n \n return sorted_common_elements", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list) -> list:\n \"\"\"\n Return sorted unique common elements for two lists.\n\n :param l1: The first list to compare.\n :param l2: The second list to compare.\n :return: A sorted list of unique common elements.\n \"\"\"\n # Convert lists to sets to remove duplicates and enable set operations\n set1 = set(l1)\n set2 = set(l2)\n \n # Use set intersection to get common elements\n common_elements = set1.intersection(set2)\n \n # Convert the set back to a list and sort it\n sorted_common_elements = sorted(list(common_elements))\n \n return sorted_common_elements", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list) -> list:\n \"\"\"\n Return sorted unique common elements for two lists.\n\n Args:\n l1 (list): The first list.\n l2 (list): The second list.\n\n Returns:\n list: A sorted list of unique common elements.\n \"\"\"\n # Convert lists to sets for efficient lookup and elimination of duplicates\n set1 = set(l1)\n set2 = set(l2)\n\n # Use set intersection to find common elements\n common_elements = set1.intersection(set2)\n\n # Convert back to a list and sort\n sorted_common_elements = sorted(list(common_elements))\n\n return sorted_common_elements", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list) -> list:\n \"\"\"\n Return sorted unique common elements for two lists.\n\n Args:\n l1 (list): The first list\n l2 (list): The second list\n\n Returns:\n list: A list of sorted unique common elements\n \"\"\"\n # Convert lists to sets to find unique common elements\n common_elements = set(l1) & set(l2)\n \n # Convert the set back to a list and sort it\n result = sorted(list(common_elements))\n \n return result", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list) -> list:\n \"\"\"\n Returns sorted unique common elements for two lists.\n\n Args:\n l1 (list): The first list.\n l2 (list): The second list.\n\n Returns:\n list: A sorted list of unique common elements.\n \"\"\"\n # Convert the input lists to sets to remove duplicates\n set1 = set(l1)\n set2 = set(l2)\n\n # Calculate the intersection of the two sets, i.e., the common elements\n common_elements = set1 & set2\n\n # Convert the set of common elements to a list and sort it\n result = sorted(list(common_elements))\n\n return result", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list) -> list:\n \"\"\"\n Return sorted unique common elements for two lists.\n\n Args:\n l1 (list): The first list of elements.\n l2 (list): The second list of elements.\n\n Returns:\n list: A new list containing the unique common elements from l1 and l2, sorted in ascending order.\n\n Examples:\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n # Convert input lists to sets to remove duplicates and improve lookup efficiency\n set1 = set(l1)\n set2 = set(l2)\n \n # Use set intersection to find common elements\n common_elements = set1 & set2\n \n # Convert the set of common elements back to a list and sort it\n result = sorted(list(common_elements))\n \n return result", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list) -> list:\n \"\"\"\n Return sorted unique common elements for two lists.\n\n Args:\n l1 (list): First input list.\n l2 (list): Second input list.\n\n Returns:\n list: A sorted list containing unique elements common to both input lists.\n \"\"\"\n # Find the intersection of two sets (to remove duplicates and common elements)\n common_elements = set(l1).intersection(l2)\n \n # Convert the set back to a list and sort it\n sorted_common_elements = sorted(list(common_elements))\n \n return sorted_common_elements", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list) -> list:\n \"\"\"\n Return sorted unique common elements for two lists.\n\n Args:\n l1 (list): The first list.\n l2 (list): The second list.\n\n Returns:\n list: A sorted list of unique common elements.\n\n Examples:\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n # Convert the lists to sets for efficient lookup and to remove duplicates\n set1 = set(l1)\n set2 = set(l2)\n\n # Find the intersection of the two sets\n common_elements = set1.intersection(set2)\n\n # Convert the set back to a list and sort it\n result = sorted(list(common_elements))\n\n return result", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list) -> list:\n \"\"\"\n Return sorted unique common elements for two lists.\n \n Args:\n l1 (list): The first list.\n l2 (list): The second list.\n \n Returns:\n list: Sorted unique common elements in the two lists.\n \"\"\"\n # Convert the input lists to sets to remove duplicates and improve lookup efficiency\n set1 = set(l1)\n set2 = set(l2)\n \n # Use set intersection to get common elements\n common_elements = set1 & set2\n \n # Convert the set back to a list and sort it\n result = sorted(list(common_elements))\n \n return result", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"\n Return sorted unique common elements for two lists.\n\n Args:\n l1 (list): The first list of elements.\n l2 (list): The second list of elements.\n\n Returns:\n list: A sorted list of unique common elements.\n\n Examples:\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n\n # Convert the lists to sets to remove duplicates and then find the intersection\n common_elements = set(l1) & set(l2)\n \n # Convert the set back to a list and sort it\n result = sorted(list(common_elements))\n \n return result", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list) -> list:\n \"\"\"\n Return sorted unique common elements for two lists.\n\n :param l1: The first list\n :param l2: The second list\n :return: A sorted list of unique common elements\n \"\"\"\n # Convert lists to sets to remove duplicates and improve lookup efficiency\n set1 = set(l1)\n set2 = set(l2)\n\n # Use set intersection to find common elements\n common_elements = set1.intersection(set2)\n\n # Convert the set back to a list and sort it\n result = sorted(list(common_elements))\n\n return result", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list) -> list:\n \"\"\"\n Return sorted unique common elements for two lists.\n\n Args:\n l1 (list): The first list.\n l2 (list): The second list.\n\n Returns:\n list: A list of sorted unique common elements.\n \"\"\"\n # Convert lists to sets to remove duplicates and improve lookup efficiency\n set1 = set(l1)\n set2 = set(l2)\n \n # Find the intersection of the two sets (common elements)\n common_elements = set1.intersection(set2)\n \n # Convert the set back to a list, sort it, and return\n return sorted(list(common_elements))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list) -> list:\n \"\"\"\n Return sorted unique common elements for two lists.\n\n Args:\n l1 (list): The first list.\n l2 (list): The second list.\n\n Returns:\n list: A sorted list of unique common elements from both lists.\n \"\"\"\n # Find the set intersection of both lists to get unique common elements\n common_elements = set(l1).intersection(l2)\n \n # Convert the set back to a list and sort it\n result = sorted(list(common_elements))\n \n return result", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list) -> list:\n \"\"\"\n Return sorted unique common elements for two lists.\n \n Args:\n l1 (list): The first list.\n l2 (list): The second list.\n \n Returns:\n list: A sorted list of unique common elements.\n \"\"\"\n # Convert the lists to sets to remove duplicates\n set1 = set(l1)\n set2 = set(l2)\n \n # Use set intersection to find common elements\n common_elements = set1.intersection(set2)\n \n # Convert the set of common elements back to a list and sort it\n common_elements = sorted(list(common_elements))\n \n return common_elements", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list) -> list:\n \"\"\"\n Return sorted unique common elements for two lists.\n\n Args:\n l1 (list): The first list.\n l2 (list): The second list.\n\n Returns:\n list: A list containing unique common elements in sorted order.\n \"\"\"\n # Convert the lists to sets to find the intersection (common elements) efficiently\n common_elements = set(l1) & set(l2)\n \n # Convert the set back to a list, sort it, and return\n return sorted(list(common_elements))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list) -> list:\n \"\"\"\n Return sorted unique common elements for two lists.\n\n Args:\n l1 (list): The first list of elements.\n l2 (list): The second list of elements.\n\n Returns:\n list: A list of unique common elements sorted in ascending order.\n \"\"\"\n\n # Convert the lists to sets for efficient lookup and to eliminate duplicates\n set1 = set(l1)\n set2 = set(l2)\n\n # Use the set intersection operation to find common elements\n common_elements = set1 & set2\n\n # Convert the set back to a list and sort it in ascending order\n result = sorted(list(common_elements))\n\n return result", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list) -> list:\n \"\"\"\n Returns a list of sorted unique common elements for two input lists.\n\n Args:\n l1 (list): The first list.\n l2 (list): The second list.\n\n Returns:\n list: A list of unique common elements in ascending order.\n \"\"\"\n # Convert input lists to sets to remove duplicates and improve lookup efficiency\n set1 = set(l1)\n set2 = set(l2)\n\n # Find common elements using set intersection\n common_elements = set1.intersection(set2)\n\n # Convert common elements back to a list and sort them\n result = sorted(list(common_elements))\n\n return result", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list) -> list:\n \"\"\"\n Return sorted unique common elements for two lists.\n\n Args:\n l1 (list): The first list.\n l2 (list): The second list.\n\n Returns:\n list: A sorted list of unique elements common to both input lists.\n\n Examples:\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n\n # Convert input lists to sets for efficient lookup and to eliminate duplicates\n set1 = set(l1)\n set2 = set(l2)\n\n # Use set intersection to find common elements\n common_elements = set1.intersection(set2)\n\n # Convert common elements back to a list and sort them\n result = sorted(list(common_elements))\n\n return result", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list) -> list:\n \"\"\"\n Return sorted unique common elements for two lists.\n\n Args:\n l1 (list): The first list to compare.\n l2 (list): The second list to compare.\n\n Returns:\n list: A sorted list of unique elements common to both input lists.\n\n Examples:\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n\n # Convert the lists to sets to remove duplicates and improve lookup efficiency\n set1 = set(l1)\n set2 = set(l2)\n\n # Use set intersection to find common elements\n common_elements = set1.intersection(set2)\n\n # Convert the set back to a list and sort it\n result = sorted(list(common_elements))\n\n return result", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list) -> list:\n \"\"\"Return sorted unique common elements for two lists.\"\"\"\n # Find the intersection of two lists using set\n common_elements = set(l1).intersection(l2)\n \n # Convert the set to a list and sort the list\n return sorted(list(common_elements))", "matching_cluster_idx": 4}]}, "HumanEval/59": {"dps": 58.09027777777778, "dps_norm": 72.77777777777777, "pass@1": 87.0, "profiled": [{"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"\n Return the largest prime factor of n.\n Assume n > 1 and is not a prime.\n \"\"\"\n i = 2\n while i * i <= n:\n if n % i:\n i += 1\n else:\n n //= i\n return n", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"\n Return the largest prime factor of n. \n Assume n > 1 and is not a prime.\n\n :param n: A non-prime integer\n :return: The largest prime factor of n\n \"\"\"\n def is_prime(num: int) -> bool:\n \"\"\"\n Check if a number is prime.\n\n :param num: The number to check\n :return: True if num is prime, False otherwise\n \"\"\"\n if num < 2:\n return False\n for i in range(2, int(num ** 0.5) + 1):\n if num % i == 0:\n return False\n return True\n\n # start from 2 (the smallest prime)\n factor = 2\n # loop until n is reduced to 1\n while n > 1:\n # if n is divisible by factor, it's not a prime, so factor is a factor of n\n if n % factor == 0:\n # store the factor and divide n\n largest_factor = factor\n n = n // factor\n else:\n # if factor is not a factor of n, increment it\n factor += 1\n # if factor is not a prime, increment it again\n while not is_prime(factor):\n factor += 1\n return largest_factor", "matching_cluster_idx": 6}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"\n Return the largest prime factor of n. Assume n > 1 and is not a prime.\n\n Args:\n n (int): An integer greater than 1 and not a prime.\n\n Returns:\n int: The largest prime factor of n.\n \"\"\"\n def is_prime(num: int) -> bool:\n \"\"\"Check if a number is prime.\"\"\"\n if num < 2:\n return False\n for i in range(2, int(num ** 0.5) + 1):\n if num % i == 0:\n return False\n return True\n\n # Check for factors from the largest possible factor down to 2\n for i in range(n - 1, 1, -1):\n if n % i == 0 and is_prime(i):\n return i\n\n # If no prime factor found, n itself is a prime\n return n", "matching_cluster_idx": 1}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"\n Return the largest prime factor of n. Assume n > 1 and is not a prime.\n\n Args:\n n (int): A composite number greater than 1.\n\n Returns:\n int: The largest prime factor of n.\n \"\"\"\n i = 2\n while i * i <= n:\n if n % i:\n i += 1\n else:\n n //= i\n return n", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"\n Return the largest prime factor of n.\n Assume n > 1 and is not a prime.\n \"\"\"\n def is_prime(num: int) -> bool:\n \"\"\"\n Check if a number is prime.\n \"\"\"\n if num < 2:\n return False\n for i in range(2, int(num ** 0.5) + 1):\n if num % i == 0:\n return False\n return True\n\n def prime_factors(num: int) -> list:\n \"\"\"\n Generate all prime factors of a number.\n \"\"\"\n factors = []\n i = 2\n while i * i <= num:\n if num % i:\n i += 1\n else:\n num //= i\n factors.append(i)\n if num > 1:\n factors.append(num)\n return factors\n\n # Generate all prime factors and return the last one (the largest)\n return prime_factors(n)[-1]", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"\n Return the largest prime factor of n. Assume n > 1 and is not a prime.\n\n This function works by dividing the input number by 2 as long as it's divisible,\n then it tries to divide it by odd numbers starting from 3.\n\n Args:\n n (int): Input number.\n\n Returns:\n int: The largest prime factor of n.\n \"\"\"\n def is_prime(num: int) -> bool:\n \"\"\"\n Helper function to check if a number is prime.\n\n Args:\n num (int): Input number.\n\n Returns:\n bool: True if the number is prime, False otherwise.\n \"\"\"\n if num < 2:\n return False\n for i in range(2, int(num ** 0.5) + 1):\n if num % i == 0:\n return False\n return True\n\n # Start by dividing the number by 2 as long as it's divisible\n while n % 2 == 0:\n n //= 2\n largest_prime = 2\n\n # Try to divide the number by odd numbers starting from 3\n for i in range(3, int(n ** 0.5) + 1, 2):\n while n % i == 0:\n n //= i\n largest_prime = i\n if n == 1:\n break\n\n # If n itself is a prime number greater than 2\n if n > 2 and is_prime(n):\n largest_prime = n\n\n return largest_prime", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"\n Return the largest prime factor of n.\n Assume n > 1 and is not a prime.\n\n :param n: The input number.\n :return: The largest prime factor of n.\n \"\"\"\n # Initialize the divisor to 2 (the smallest prime)\n divisor = 2\n\n # While n is divisible by the divisor, divide it\n while n % divisor == 0:\n n = n // divisor\n # Update the divisor to be the largest divisor so far\n largest_divisor = divisor\n\n # At this point, n is not divisible by 2\n # We now try all odd numbers\n for i in range(3, int(n ** 0.5) + 1, 2):\n while n % i == 0:\n n = n // i\n largest_divisor = i\n\n # If n is not 1, it means that it's a prime number itself\n # In this case, it's the largest divisor\n if n > 1:\n largest_divisor = n\n\n return largest_divisor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n \n This function works by dividing the input number by the smallest prime factor (which is 2), \n then by the next smallest (3), and so on, until the number is reduced to 1. \n The last divisor is the largest prime factor.\n \"\"\"\n i = 2\n while i * i <= n:\n if n % i:\n i += 1\n else:\n n //= i\n return n", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"\n Return the largest prime factor of n. Assume n > 1 and is not a prime.\n \n This function works by dividing the input number 'n' by the smallest prime factor\n (which is 2) as long as it's divisible. Then it increments the divisor until it \n finds the next number that can divide 'n', which will necessarily be a prime factor.\n This process continues until 'n' is reduced to 1. The last number that was used \n to divide 'n' will be the largest prime factor.\n \n Args:\n n: The number for which the largest prime factor is to be found.\n \n Returns:\n The largest prime factor of 'n'.\n \"\"\"\n \n # Handle edge cases\n if not isinstance(n, int) or n < 2:\n raise ValueError(\"Input must be an integer greater than 1\")\n\n # Start with the smallest prime factor\n i = 2\n \n # Continue until n is reduced to 1\n while i * i <= n:\n if n % i:\n # If i does not divide n, increment i\n i += 1\n else:\n # If i divides n, divide n by i and continue\n n //= i\n \n # At this point, n is the largest prime factor\n return n", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"\n Return the largest prime factor of n. Assume n > 1 and is not a prime.\n\n :param n: The input number\n :return: The largest prime factor of n\n \"\"\"\n\n def is_prime(num: int) -> bool:\n \"\"\"Check if a number is prime\"\"\"\n if num < 2:\n return False\n for i in range(2, int(num ** 0.5) + 1):\n if num % i == 0:\n return False\n return True\n\n for i in range(n, 1, -1):\n if n % i == 0 and is_prime(i):\n return i", "matching_cluster_idx": 1}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"\n Return the largest prime factor of n. Assume n > 1 and is not a prime.\n\n :param n: A positive integer.\n :return: The largest prime factor of n.\n \"\"\"\n def is_prime(p: int) -> bool:\n \"\"\"Check if p is a prime number.\"\"\"\n if p < 2:\n return False\n for i in range(2, int(p ** 0.5) + 1):\n if p % i == 0:\n return False\n return True\n\n # We only need to check up to n // 2 because the largest factor cannot be larger.\n for p in range(n // 2, 1, -1):\n if n % p == 0 and is_prime(p):\n return p", "matching_cluster_idx": 3}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"\n Return the largest prime factor of n. Assume n > 1 and is not a prime.\n\n :param n: An integer greater than 1 and not a prime.\n :return: The largest prime factor of n.\n \"\"\"\n def is_prime(num: int) -> bool:\n \"\"\"\n Check if a number is prime.\n\n :param num: The number to check.\n :return: True if the number is prime, False otherwise.\n \"\"\"\n if num < 2:\n return False\n for i in range(2, int(num ** 0.5) + 1):\n if num % i == 0:\n return False\n return True\n\n # Start checking from the smallest prime number, which is 2\n i = 2\n while i * i <= n:\n if n % i:\n # If n is not divisible by i, increment it\n i += 1\n else:\n # If n is divisible by i, update n to be n // i\n n //= i\n # At this point, n will be the largest prime factor\n return n", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\"\"\"\n def is_prime(num: int) -> bool:\n \"\"\"Check if a number is prime.\"\"\"\n if num < 2:\n return False\n for i in range(2, int(num ** 0.5) + 1):\n if num % i == 0:\n return False\n return True\n\n max_prime_factor = None\n for i in range(2, n):\n while n % i == 0:\n if is_prime(i):\n max_prime_factor = i\n n //= i\n return max_prime_factor", "matching_cluster_idx": 2}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"\n Return the largest prime factor of n. Assume n > 1 and is not a prime.\n\n :param n: Input integer > 1 that is not a prime.\n :return: The largest prime factor of n.\n \"\"\"\n def is_prime(num: int) -> bool:\n \"\"\"Check if a number is prime.\"\"\"\n if num < 2:\n return False\n for i in range(2, int(num ** 0.5) + 1):\n if num % i == 0:\n return False\n return True\n\n # Start from 2, the smallest prime number\n for i in range(2, n + 1):\n # Check if i is a factor of n and if it's prime\n if n % i == 0 and is_prime(i):\n # Initialize largest_factor to the first prime factor found\n largest_factor = i\n break\n\n # Iterate upwards to find the largest prime factor\n for i in range(largest_factor + 1, n + 1):\n if n % i == 0 and is_prime(i) and i > largest_factor:\n largest_factor = i\n\n return largest_factor", "matching_cluster_idx": 1}, {"solution": "import unittest\ndef largest_prime_factor(n: int):\n \"\"\"\n Return the largest prime factor of n. Assume n > 1 and is not a prime.\n\n :param n: The input number.\n :return: The largest prime factor of n.\n \"\"\"\n i = 2\n while i * i <= n:\n if n % i:\n i += 1\n else:\n n //= i\n return n", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"\n Return the largest prime factor of n. Assume n > 1 and is not a prime.\n\n Args:\n n (int): The number to find the largest prime factor of.\n\n Returns:\n int: The largest prime factor of n.\n \"\"\"\n def is_prime(num: int) -> bool:\n \"\"\"\n Helper function to check if a number is prime.\n\n Args:\n num (int): The number to check.\n\n Returns:\n bool: True if num is prime, False otherwise.\n \"\"\"\n if num < 2:\n return False\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n return False\n return True\n\n # Start checking from 2\n i = 2\n while i * i <= n:\n if n % i:\n # If n is not divisible by i, check the next number\n i += 1\n else:\n # If n is divisible by i, divide n by i and update the largest factor\n n //= i\n largest_factor = i\n # If n is a prime number greater than 2 at this point\n if n > 2:\n largest_factor = n\n return largest_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"\n Return the largest prime factor of n. Assume n > 1 and is not a prime.\n\n :param n: The input number.\n :return: The largest prime factor of n.\n \"\"\"\n def is_prime(num: int) -> bool:\n \"\"\"\n Check if a number is prime.\n\n :param num: The number to check.\n :return: True if num is prime, False otherwise.\n \"\"\"\n if num < 2:\n return False\n for i in range(2, int(num ** 0.5) + 1):\n if num % i == 0:\n return False\n return True\n\n for i in range(n - 1, 1, -1):\n if n % i == 0 and is_prime(i):\n return i\n\n # This case shouldn't occur as the problem statement guarantees that n is not prime\n return None", "matching_cluster_idx": 1}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"\n Return the largest prime factor of n. Assume n > 1 and is not a prime.\n\n :param n: The input number\n :return: The largest prime factor of n\n \"\"\"\n def is_prime(num: int) -> bool:\n \"\"\"\n Helper function to check if a number is prime.\n\n :param num: The number to check\n :return: True if num is prime, False otherwise\n \"\"\"\n if num < 2:\n return False\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n return False\n return True\n\n # Initialize the largest prime factor as 2 (smallest prime number)\n largest_factor = 2\n\n # Iterate from 2 to sqrt(n) to find the largest prime factor\n for i in range(2, int(n**0.5) + 1):\n # Check if i is a factor of n\n while n % i == 0:\n # If i is prime and greater than the current largest factor, update largest_factor\n if is_prime(i) and i > largest_factor:\n largest_factor = i\n # Divide n by i\n n //= i\n\n # If n is a prime number greater than 2, it's the largest prime factor\n if n > 2 and is_prime(n):\n return n\n\n return largest_factor", "matching_cluster_idx": 7}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"\n Return the largest prime factor of n. Assume n > 1 and is not a prime.\n \n Args:\n n: An integer greater than 1, which is not a prime number.\n \n Returns:\n The largest prime factor of the given number n.\n \"\"\"\n def is_prime(num: int) -> bool:\n \"\"\"\n Helper function to check if a number is prime.\n \n Args:\n num: The number to be checked.\n \n Returns:\n True if the number is prime, False otherwise.\n \"\"\"\n if num < 2:\n return False\n for i in range(2, int(num ** 0.5) + 1):\n if num % i == 0:\n return False\n return True\n\n # Start checking factors from the largest possible factor\n for i in range(n - 1, 1, -1):\n # If n is divisible by i and i is prime, return i\n if n % i == 0 and is_prime(i):\n return i\n\n # If no prime factors are found, return the smallest prime factor (2)\n return 2", "matching_cluster_idx": 1}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"\n Return the largest prime factor of n.\n \n Assume n > 1 and is not a prime.\n\n :param n: The number to find the largest prime factor of.\n :return: The largest prime factor of n.\n \"\"\"\n def is_prime(num: int) -> bool:\n \"\"\"\n Helper function to check if a number is prime.\n\n :param num: The number to check.\n :return: True if num is prime, False otherwise.\n \"\"\"\n if num < 2:\n return False\n for i in range(2, int(num ** 0.5) + 1):\n if num % i == 0:\n return False\n return True\n\n def prime_factors(num: int) -> list:\n \"\"\"\n Helper function to find all prime factors of a number.\n\n :param num: The number to find prime factors of.\n :return: A list of all prime factors of num.\n \"\"\"\n factors = []\n i = 2\n while i * i <= num:\n if num % i:\n i += 1\n else:\n num //= i\n factors.append(i)\n if num > 1:\n factors.append(num)\n return factors\n\n return max(prime_factors(n))", "matching_cluster_idx": 8}]}, "HumanEval/64": {"dps": 67.40259740259741, "dps_norm": 54.375, "pass@1": 78.0, "profiled": [{"solution": "def vowels_count(s):\n \"\"\"\n This function takes a string representing a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a vowel, but only when it is at the end of the given word.\n\n Args:\n s (str): A string representing a word.\n\n Returns:\n int: The number of vowels in the string.\n\n Raises:\n TypeError: If input is not a string.\n \"\"\"\n if not isinstance(s, str):\n raise TypeError(\"Input must be a string.\")\n\n s = s.lower() # Convert to lowercase for simplicity\n count = sum(1 for char in s if char in 'aeiou') # Count 'a', 'e', 'i', 'o', 'u'\n if s.endswith('y'): # If the word ends with 'y', increment the count\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n \"\"\"\n Returns the number of vowels in the given string.\n \n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. 'y' is also a vowel, \n but only when it is at the end of the given word.\n\n Parameters:\n s (str): A string representing a word.\n\n Returns:\n int: The number of vowels in the string.\n \"\"\"\n # Convert the string to lower case for case insensitive comparison\n s = s.lower()\n \n # Initialize a counter for vowels\n count = 0\n \n # Iterate over each character in the string\n for i, char in enumerate(s):\n # Check if the character is a vowel\n if char in 'aeiou':\n count += 1\n # Check if the character is 'y' and it's at the end of the string\n elif char == 'y' and i == len(s) - 1:\n count += 1\n \n # Return the total count of vowels\n return count", "matching_cluster_idx": 2}, {"solution": "def vowels_count(s):\n \"\"\"\n This function takes a string representing a word as input and returns \n the number of vowels in the string. Vowels in this case are 'a', 'e', \n 'i', 'o', 'u'. Here, 'y' is also a vowel, but only when it is at the \n end of the given word.\n\n Args:\n s (str): The input word.\n\n Returns:\n int: The number of vowels in the word.\n \"\"\"\n\n # Convert the string to lowercase to handle both 'a' and 'A' as vowels\n s = s.lower()\n\n # Initialize a counter for vowels\n count = 0\n\n # Iterate over each character in the string\n for i, char in enumerate(s):\n # Check if the character is a vowel\n if char in 'aeiou':\n count += 1\n # Check if the character is 'y' and it is at the end of the string\n elif char == 'y' and i == len(s) - 1:\n count += 1\n\n return count", "matching_cluster_idx": 3}, {"solution": "def vowels_count(s):\n \"\"\"\n Returns the number of vowels in the given string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. \n Here, 'y' is also a vowel, but only when it is at the end of the given word.\n\n :param s: A string representing a word\n :return: The number of vowels in the string\n \"\"\"\n s = s.lower() # Convert the string to lowercase\n count = sum(1 for char in s if char in 'aeiou') # Count vowels\n if s.endswith('y'): # Check if the string ends with 'y'\n count += 1 # Increment count if 'y' is at the end\n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n \"\"\"\n Returns the number of vowels in the given string.\n Vowels are 'a', 'e', 'i', 'o', 'u' and 'y' (when at the end of the word).\n \"\"\"\n s = s.lower()\n count = sum(1 for char in s if char in 'aeiou')\n if s.endswith('y'):\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n \"\"\"\n This function takes a string representing a word as input and returns \n the number of vowels in the string. 'y' is also considered a vowel \n when it is at the end of the given word.\n\n Parameters:\n s (str): The input string\n\n Returns:\n int: The number of vowels in the string\n \"\"\"\n s = s.lower() # Convert the string to lowercase for case insensitive comparison\n count = sum(1 for char in s if char in 'aeiou') # Count the vowels 'a', 'e', 'i', 'o', 'u'\n \n # Check if 'y' is at the end of the string and add to the count if so\n if s.endswith('y'):\n count += 1\n\n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n \"\"\"\n This function takes a string representing a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a vowel, but only when it is at the end of the given word.\n\n Args:\n s (str): A string representing a word.\n\n Returns:\n int: The number of vowels in the string.\n \"\"\"\n s = s.lower()\n count = 0\n for char in s:\n if char in 'aeiou':\n count += 1\n if s.endswith('y'):\n count += 1\n return count", "matching_cluster_idx": 3}, {"solution": "import unittest\ndef vowels_count(s):\n \"\"\"Return the number of vowels in the given string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u' and 'y' (when it is at the end of the given word).\n \n Parameters:\n s (str): The input string.\n \n Returns:\n int: The number of vowels in the string.\n \"\"\"\n # Convert the string to lower case for simplicity\n s = s.lower()\n # Check if the string is empty\n if not s:\n return 0\n # Initialize vowel count to 0\n count = 0\n # Define vowels\n vowels = 'aeiou'\n # Check each character in the string\n for i, char in enumerate(s):\n # If the character is a vowel, increment the count\n if char in vowels:\n count += 1\n # If the character is 'y' and it is at the end of the string, increment the count\n elif char == 'y' and i == len(s) - 1:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def vowels_count(s):\n \"\"\"\n This function counts the number of vowels in a given string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u', and 'y' at the end of the string.\n\n Args:\n s (str): The input string.\n\n Returns:\n int: The number of vowels in the string.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n s = s.lower() # convert the string to lowercase\n count = 0\n for i, char in enumerate(s):\n if char in 'aeiou':\n count += 1\n elif char == 'y' and i == len(s) - 1:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def vowels_count(s):\n \"\"\"\n This function takes a string representing a word as input and returns \n the number of vowels in the string.\n\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a \n vowel, but only when it is at the end of the given word.\n\n Parameters:\n s (str): The input string representing a word.\n\n Returns:\n int: The number of vowels in the string.\n \"\"\"\n\n # Convert the string to lowercase for simplicity\n s = s.lower()\n\n # Check if 'y' is at the end of the word\n y_at_end = s.endswith('y')\n\n # Count the number of vowels in the string excluding 'y'\n vowel_count = sum(1 for char in s if char in 'aeiou')\n\n # If 'y' is at the end of the word, increment the vowel count\n if y_at_end:\n vowel_count += 1\n\n return vowel_count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n \"\"\"\n This function takes a string representing a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a vowel, but only when it is at the end of the given word.\n\n Parameters:\n s (str): A string representing a word.\n\n Returns:\n int: The number of vowels in the string.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n # Convert the string to lower case to handle both lower and upper case vowels\n s = s.lower()\n \n # Count the number of vowels in the string\n count = sum(1 for char in s if char in 'aeiou')\n \n # Check if the last character is 'y' and increment the count if it is\n if s and s[-1] == 'y':\n count += 1\n \n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n \"\"\"\n Returns the number of vowels in the given string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. 'y' is also considered\n a vowel when it is at the end of the string.\n\n Args:\n s (str): The input string.\n\n Returns:\n int: The number of vowels in the string.\n \"\"\"\n s = s.lower() # convert to lower case for simplicity\n count = sum(1 for char in s if char in 'aeiou')\n # check if the last character is 'y'\n if s.endswith('y'):\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "import doctest\ndef vowels_count(s):\n \"\"\"\n Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Args:\n s (str): A string representing a word.\n\n Returns:\n int: The number of vowels in the string.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n\n s = s.lower()\n count = sum(1 for char in s[:-1] if char in 'aeiou')\n if s and s[-1] in 'yaeiou':\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "import unittest\ndef vowels_count(s):\n \"\"\"\n This function counts the number of vowels in a given string.\n\n A vowel is one of 'a', 'e', 'i', 'o', 'u' (both lowercase and uppercase).\n 'y' is considered a vowel only when it appears at the end of the string.\n\n Parameters:\n s (str): The input string to count vowels in.\n\n Returns:\n int: The number of vowels in the string.\n\n \"\"\"\n s = s.lower() # Convert the string to lowercase for simplicity\n count = sum(1 for c in s if c in 'aeiou') # Count all vowels except 'y'\n if s.endswith('y'): # If 'y' is at the end of the string, increment count\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "import unittest\ndef vowels_count(s):\n \"\"\"\n Returns the number of vowels in the given string.\n \n In this function, a vowel is one of 'a', 'e', 'i', 'o', 'u'. \n 'y' is considered a vowel when it appears at the end of the string.\n \n Parameters:\n s (str): The input string.\n \n Returns:\n int: The number of vowels in the string.\n \"\"\"\n # Convert the string to lower case for case-insensitive comparison\n s = s.lower()\n \n # Initialize a counter for vowels\n count = 0\n \n # Iterate over each character in the string\n for i, char in enumerate(s):\n # Check if the character is a vowel\n if char in 'aeiou':\n count += 1\n # Check if 'y' is at the end of the string\n elif char == 'y' and i == len(s) - 1:\n count += 1\n \n return count", "matching_cluster_idx": 3}, {"solution": "import unittest\ndef vowels_count(s):\n \"\"\"\n This function takes a string representing a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a vowel, but only when it is at the end of the given word.\n\n Args:\n s (str): A string representing a word.\n\n Returns:\n int: The number of vowels in the given string.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n # Define the vowels\n vowels = 'aeiou'\n \n # Initialize count of vowels\n count = 0\n \n # Convert the string to lower case to simplify the comparison\n s = s.lower()\n \n # Check if 'y' is at the end of the string\n if s.endswith('y'):\n # Remove 'y' from the string\n s = s[:-1]\n # Increment count by 1 since 'y' is considered a vowel at the end\n count += 1\n \n # Iterate over each character in the string\n for char in s:\n # Check if the character is a vowel\n if char in vowels:\n # Increment count if the character is a vowel\n count += 1\n \n # Return the total count of vowels\n return count", "matching_cluster_idx": 3}, {"solution": "def vowels_count(s):\n \"\"\"\n This function takes a string representing a word as input and returns \n the number of vowels in the string. Vowels in this case are 'a', 'e', \n 'i', 'o', 'u'. Here, 'y' is also a vowel, but only when it is at the \n end of the given word.\n\n Parameters:\n s (str): A string representing a word.\n\n Returns:\n int: The number of vowels in the string.\n \"\"\"\n # Convert the string to lower case to ensure the function is case-insensitive\n s = s.lower()\n \n # Initialize a counter variable\n count = 0\n \n # Check each character in the string\n for i, char in enumerate(s):\n # If the character is a vowel or 'y' and it's at the end of the word, increment the counter\n if char in 'aeiou' or (char == 'y' and i == len(s) - 1):\n count += 1\n \n # Return the count of vowels\n return count", "matching_cluster_idx": 2}, {"solution": "def vowels_count(s):\n \"\"\"\n Counts the number of vowels in a given string.\n\n Args:\n s (str): The input string.\n\n Returns:\n int: The number of vowels in the string.\n\n Notes:\n 'y' is considered a vowel only when it's at the end of the string.\n The function is case-insensitive.\n \"\"\"\n # Convert the input string to lower case to make the function case-insensitive\n s = s.lower()\n \n # Initialize a counter for vowels\n count = 0\n \n # Iterate over the characters in the string\n for char in s:\n # Check if the character is a vowel (excluding 'y')\n if char in 'aeiou':\n # Increment the counter if the character is a vowel\n count += 1\n \n # Check if the last character is 'y' (which is a vowel in this case)\n if s and s[-1] == 'y':\n # Increment the counter if 'y' is at the end of the string\n count += 1\n \n # Return the total count of vowels\n return count", "matching_cluster_idx": 3}, {"solution": "def vowels_count(s):\n \"\"\"\n This function takes a string representing a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a vowel, but only when it is at the end of the given word.\n\n Args:\n s (str): A string representing a word.\n\n Returns:\n int: The number of vowels in the string.\n \"\"\"\n s = s.lower() # Convert the string to lowercase for easier comparison\n vowels = 'aeiou' # Define the set of vowels\n\n count = sum(1 for char in s if char in vowels) # Count the vowels in the string\n\n # If 'y' is at the end of the string, increment the count by 1\n if s and s[-1] == 'y':\n count += 1\n\n return count", "matching_cluster_idx": 4}, {"solution": "import unittest\ndef vowels_count(s):\n \"\"\"\n This function takes a string representing a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a vowel, but only when it is at the end of the given word.\n\n Parameters:\n s (str): The input string.\n\n Returns:\n int: The number of vowels in the string.\n\n \"\"\"\n s = s.lower() # convert the string to lower case to handle both lowercase and uppercase vowels\n count = sum(1 for char in s if char in 'aeiou') # count vowels 'a', 'e', 'i', 'o', 'u'\n if s and s[-1] == 'y': # check if 'y' is at the end of the string\n count += 1 # increment the count if 'y' is at the end\n return count", "matching_cluster_idx": 4}]}, "HumanEval/74": {"dps": 98.04878048780488, "dps_norm": 88.88888888888889, "pass@1": 100.0, "profiled": [{"solution": "def total_match(lst1, lst2):\n \"\"\"\n This function compares two lists of strings and returns the list \n with the total number of characters in all its strings less than \n the other list. If the two lists have the same number of characters, \n it returns the first list.\n\n Args:\n lst1 (list): The first list of strings.\n lst2 (list): The second list of strings.\n\n Returns:\n list: The list with the total number of characters in all its strings less than the other list.\n \"\"\"\n\n # Calculate the total number of characters in the first list\n total_chars_lst1 = sum(len(string) for string in lst1)\n\n # Calculate the total number of characters in the second list\n total_chars_lst2 = sum(len(string) for string in lst2)\n\n # Return the list with the total number of characters less than the other list\n # If both lists have the same number of characters, return the first list\n return lst1 if total_chars_lst1 <= total_chars_lst2 else lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Returns the list with the total number of characters less than the other list.\n If both lists have the same number of characters, returns the first list.\n\n Args:\n lst1 (list): The first list of strings.\n lst2 (list): The second list of strings.\n\n Returns:\n list: The list with fewer total characters.\n '''\n def total_chars(lst):\n # Helper function to calculate the total number of characters in a list of strings\n return sum(len(string) for string in lst)\n\n # Compare the total characters in both lists and return the list with fewer characters\n if total_chars(lst1) <= total_chars(lst2):\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n \"\"\"\n Returns the list that has the total number of characters in all its strings less than the other list.\n If both lists have the same number of characters, returns the first list.\n \n Args:\n lst1 (list): The first list of strings.\n lst2 (list): The second list of strings.\n \n Returns:\n list: The list with fewer total characters.\n \"\"\"\n def total_chars(lst):\n \"\"\"Helper function to calculate the total number of characters in a list of strings.\"\"\"\n return sum(len(string) for string in lst)\n\n if total_chars(lst1) <= total_chars(lst2):\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Returns the list with total number of chars less than the other list.\n \n If the two lists have the same number of chars, returns the first list.\n\n Parameters:\n lst1 (list): The first list of strings.\n lst2 (list): The second list of strings.\n\n Returns:\n list: The list with total number of chars less than the other list.\n '''\n # Calculate total number of chars in lst1 and lst2\n total_chars_lst1 = sum(len(string) for string in lst1)\n total_chars_lst2 = sum(len(string) for string in lst2)\n \n # Return lst1 if it has less or equal number of chars, otherwise return lst2\n return lst1 if total_chars_lst1 <= total_chars_lst2 else lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Returns the list that has total number of chars in all strings less than the other list.\n If the two lists have the same number of chars, returns the first list.\n\n Args:\n lst1 (list): The first list of strings.\n lst2 (list): The second list of strings.\n\n Returns:\n list: The list with total number of chars less than the other list.\n '''\n def total_chars(lst):\n # Calculate total number of chars in a list\n return sum(len(string) for string in lst)\n\n # Compare total chars in both lists\n if total_chars(lst1) <= total_chars(lst2):\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Returns the list with the total number of characters in all its strings less than the other list.\n If both lists have the same total number of characters, returns the first list.\n\n Args:\n lst1 (list): The first list of strings.\n lst2 (list): The second list of strings.\n\n Returns:\n list: The list with the lower total number of characters.\n '''\n def total_chars(lst):\n '''Calculates the total number of characters in all strings of a list.'''\n return sum(len(s) for s in lst)\n\n total1 = total_chars(lst1)\n total2 = total_chars(lst2)\n\n if total1 <= total2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Returns the list that has the total number of chars in all strings of the list \n less than the other list. If the two lists have the same number of chars, \n returns the first list.\n \n Args:\n lst1 (list): The first list of strings\n lst2 (list): The second list of strings\n \n Returns:\n list: The list with the smaller total number of characters\n '''\n def total_chars(lst):\n # Calculate the total number of characters in a list of strings\n return sum(len(s) for s in lst)\n \n return lst1 if total_chars(lst1) <= total_chars(lst2) else lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n This function compares the total number of characters in two lists of strings.\n \n Args:\n lst1 (list): The first list of strings.\n lst2 (list): The second list of strings.\n \n Returns:\n list: The list with the total number of characters less than the other list.\n If the two lists have the same number of characters, returns the first list.\n '''\n def total_chars(lst):\n return sum(len(string) for string in lst)\n \n if total_chars(lst1) <= total_chars(lst2):\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n This function compares two lists of strings and returns the list that has \n the total number of characters in all strings less than or equal to the other list.\n \n If the two lists have the same number of characters, it returns the first list.\n\n Args:\n lst1 (list): The first list of strings to compare.\n lst2 (list): The second list of strings to compare.\n\n Returns:\n list: The list with the total number of characters in all strings less than or equal to the other list.\n '''\n # Calculate the total number of characters in lst1\n total_chars_lst1 = sum(len(s) for s in lst1)\n \n # Calculate the total number of characters in lst2\n total_chars_lst2 = sum(len(s) for s in lst2)\n \n # If the total number of characters in lst1 is less than or equal to the total in lst2, return lst1\n if total_chars_lst1 <= total_chars_lst2:\n return lst1\n else:\n # Otherwise, return lst2\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Returns the list that has the total number of characters in all its strings less than the other list.\n If both lists have the same total number of characters, returns the first list.\n '''\n def total_chars(lst):\n return sum(len(s) for s in lst)\n\n total1, total2 = total_chars(lst1), total_chars(lst2)\n return lst1 if total1 <= total2 else lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n This function compares two lists of strings based on the total number of characters.\n \n It returns the list with fewer total characters. If both lists have the same total number of characters, \n it returns the first list.\n \n Parameters:\n lst1 (list): The first list of strings.\n lst2 (list): The second list of strings.\n \n Returns:\n list: The list with fewer total characters.\n '''\n \n # Calculate total characters in lst1\n total_chars_lst1 = sum(len(string) for string in lst1)\n \n # Calculate total characters in lst2\n total_chars_lst2 = sum(len(string) for string in lst2)\n \n # Compare total characters and return the list with fewer characters\n if total_chars_lst1 <= total_chars_lst2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Returns the list with the total number of characters in all strings less than the other list.\n If both lists have the same number of characters, returns the first list.\n\n Args:\n lst1 (list): The first list of strings.\n lst2 (list): The second list of strings.\n\n Returns:\n list: The list with fewer total characters.\n '''\n def total_chars(lst):\n return sum(len(s) for s in lst)\n\n return lst1 if total_chars(lst1) <= total_chars(lst2) else lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Returns the list with a total number of characters in all strings less than the other list.\n If both lists have the same number of characters, returns the first list.\n\n Parameters\n ----------\n lst1 : list of str\n The first list of strings\n lst2 : list of str\n The second list of strings\n\n Returns\n -------\n list of str\n The list with fewer characters in total\n '''\n # Calculate the total number of characters in each list\n sum1 = sum(len(s) for s in lst1)\n sum2 = sum(len(s) for s in lst2)\n\n # Compare the sums and return the list with fewer characters\n return lst1 if sum1 <= sum2 else lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Returns the list with the total number of characters less than the other.\n If the lists have the same total characters, returns the first list.\n\n Args:\n lst1 (list): The first list of strings.\n lst2 (list): The second list of strings.\n\n Returns:\n list: The list with the total number of characters less than the other.\n '''\n # Calculate the total number of characters in each list\n total_chars1 = sum(len(s) for s in lst1)\n total_chars2 = sum(len(s) for s in lst2)\n\n # Return the list with the total number of characters less than the other\n # If they are equal, return the first list\n return lst1 if total_chars1 <= total_chars2 else lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Returns the list that has the total number of chars in the all strings of the list \n less than the other list. If the two lists have the same number of chars, \n returns the first list.\n\n Args:\n lst1 (list): The first list of strings.\n lst2 (list): The second list of strings.\n\n Returns:\n list: The list with fewer total characters.\n '''\n def total_chars(lst):\n '''Helper function to calculate the total number of characters in a list of strings.'''\n return sum(len(s) for s in lst)\n\n if total_chars(lst1) <= total_chars(lst2):\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n This function compares the total number of characters in two lists of strings and \n returns the list with the fewer total characters. If both lists have the same \n total number of characters, it returns the first list.\n\n Parameters:\n lst1 (list): The first list of strings.\n lst2 (list): The second list of strings.\n\n Returns:\n list: The list with the fewer total characters.\n '''\n \n # Calculate the total number of characters in each list\n total_chars_lst1 = sum(len(string) for string in lst1)\n total_chars_lst2 = sum(len(string) for string in lst2)\n\n # Return the list with the fewer total characters, or the first list if they're equal\n return lst1 if total_chars_lst1 <= total_chars_lst2 else lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Returns the list with the total number of characters in all its strings less than or equal to the other list.\n\n Args:\n lst1 (list): The first list of strings.\n lst2 (list): The second list of strings.\n\n Returns:\n list: The list with the lesser or equal total number of characters in all its strings.\n\n Examples:\n total_match([], []) -> []\n total_match(['hi', 'admin'], ['hI', 'Hi']) -> ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) -> ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) -> ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) -> ['4']\n '''\n # Calculate the total number of characters in all strings of lst1 and lst2\n total_chars_lst1 = sum(len(string) for string in lst1)\n total_chars_lst2 = sum(len(string) for string in lst2)\n\n # Compare the total characters of both lists and return the list with less or equal characters\n return lst1 if total_chars_lst1 <= total_chars_lst2 else lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Returns the list with the total number of characters in its strings less than \n the other list. If the two lists have the same number of characters, \n returns the first list.\n\n Args:\n lst1 (list): The first list of strings.\n lst2 (list): The second list of strings.\n\n Returns:\n list: The list with fewer total characters.\n '''\n # Calculate the total number of characters in each list\n total_chars_lst1 = sum(len(s) for s in lst1)\n total_chars_lst2 = sum(len(s) for s in lst2)\n\n # Return the list with fewer total characters\n if total_chars_lst1 <= total_chars_lst2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Returns the list that has a total number of characters in all strings less than the other list.\n If the two lists have the same number of characters, returns the first list.\n\n Args:\n lst1 (list): The first list of strings.\n lst2 (list): The second list of strings.\n\n Returns:\n list: The list with a total number of characters less than or equal to the other list.\n '''\n # Calculate the total number of characters in lst1\n total_chars_lst1 = sum(len(s) for s in lst1)\n \n # Calculate the total number of characters in lst2\n total_chars_lst2 = sum(len(s) for s in lst2)\n \n # Return lst1 if total_chars_lst1 is less than or equal to total_chars_lst2\n return lst1 if total_chars_lst1 <= total_chars_lst2 else lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n \"\"\"\n Compare two lists of strings and return the list with the smaller total number of characters.\n \n If both lists have the same total number of characters, return the first list.\n\n Args:\n lst1 (list): The first list of strings.\n lst2 (list): The second list of strings.\n\n Returns:\n list: The list with the smaller total number of characters.\n \"\"\"\n\n # Calculate the total number of characters in lst1 and lst2\n total_chars_lst1 = sum(len(string) for string in lst1)\n total_chars_lst2 = sum(len(string) for string in lst2)\n\n # If lst1 has fewer characters, return lst1\n if total_chars_lst1 < total_chars_lst2:\n return lst1\n # If lst2 has fewer characters, return lst2\n elif total_chars_lst2 < total_chars_lst1:\n return lst2\n # If both lists have the same number of characters, return lst1\n else:\n return lst1", "matching_cluster_idx": 7}]}, "HumanEval/85": {"dps": 83.66336633663366, "dps_norm": 50.0, "pass@1": 94.0, "profiled": [{"solution": "def add(lst):\n \"\"\"\n Given a non-empty list of integers, returns the sum of even elements at odd indices.\n\n Args:\n lst (list): A non-empty list of integers.\n\n Returns:\n int: The sum of even elements at odd indices.\n \"\"\"\n return sum(x for i, x in enumerate(lst) if i % 2 != 0 and x % 2 == 0)", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"\n Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Args:\n lst (list): A non-empty list of integers.\n\n Returns:\n int: The sum of even elements at odd indices in the list.\n\n Examples:\n >>> add([4, 2, 6, 7])\n 2\n \"\"\"\n return sum(num for idx, num in enumerate(lst) if idx % 2 != 0 and num % 2 == 0)", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices.\n\n Args:\n lst (list): A list of integers\n\n Returns:\n int: Sum of even elements at odd indices\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n return sum(num for idx, num in enumerate(lst) if idx % 2 != 0 and num % 2 == 0)", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"\n Given a non-empty list of integers, add the even elements that are at odd indices.\n\n Args:\n lst (list): A list of integers.\n\n Returns:\n int: The sum of even elements at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n add([3, 6, 1, 8]) ==> 8\n \"\"\"\n return sum(num for idx, num in enumerate(lst) if idx % 2 != 0 and num % 2 == 0)", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"\n Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Args:\n lst (list): A list of integers.\n\n Returns:\n int: The sum of even elements at odd indices.\n\n Examples:\n >>> add([4, 2, 6, 7])\n 2\n \"\"\"\n return sum(num for idx, num in enumerate(lst) if idx % 2 != 0 and num % 2 == 0)", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"\n Given a non-empty list of integers lst. \n Adds the even elements that are at odd indices.\n\n Args:\n lst (list): A non-empty list of integers.\n\n Returns:\n int: Sum of even elements at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n return sum(num for idx, num in enumerate(lst) if idx % 2 != 0 and num % 2 == 0)", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"\n Given a non-empty list of integers, add the even elements that are at odd indices.\n\n Args:\n lst (list): A list of integers.\n\n Returns:\n int: Sum of the even elements at odd indices.\n \"\"\"\n return sum(num for idx, num in enumerate(lst) if idx % 2 != 0 and num % 2 == 0)", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"\n Given a non-empty list of integers, add the even elements that are at odd indices.\n\n Args:\n lst (list): A non-empty list of integers.\n\n Returns:\n int: The sum of even elements at odd indices.\n\n Examples:\n >>> add([4, 2, 6, 7])\n 2\n \"\"\"\n return sum(num for idx, num in enumerate(lst) if idx % 2 != 0 and num % 2 == 0)", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"\n Given a non-empty list of integers, returns the sum of even elements at odd indices.\n\n Args:\n lst (list): A list of integers.\n\n Returns:\n int: The sum of even elements at odd indices.\n\n Examples:\n >>> add([4, 2, 6, 7])\n 2\n \"\"\"\n return sum(val for idx, val in enumerate(lst) if idx % 2 != 0 and val % 2 == 0)", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Args:\n lst (list): A non-empty list of integers.\n\n Returns:\n int: Sum of even elements at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2 \n \"\"\"\n # Check if input is a non-empty list\n if not isinstance(lst, list) or len(lst) == 0:\n raise ValueError(\"Input must be a non-empty list\")\n\n # Initialize a variable to store the sum\n even_sum = 0\n\n # Iterate through the list using enumerate to access both index and value\n for idx, val in enumerate(lst):\n # Check if the index is odd and the value is even\n if idx % 2 != 0 and val % 2 == 0:\n # Add the even value at an odd index to the sum\n even_sum += val\n\n return even_sum", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"\n Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Args:\n lst (list): A list of integers\n\n Returns:\n int: The sum of even elements at odd indices\n \"\"\"\n return sum(num for idx, num in enumerate(lst) if idx % 2 != 0 and num % 2 == 0)", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"\n Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Args:\n lst (list): A list of integers.\n\n Returns:\n int: Sum of even elements at odd indices.\n\n Examples:\n >>> add([4, 2, 6, 7])\n 2\n >>> add([1, 3, 5, 7])\n 0\n >>> add([10, 20, 30, 40])\n 20\n \"\"\"\n return sum(num for idx, num in enumerate(lst) if idx % 2 != 0 and num % 2 == 0)", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"\n This function adds the even elements that are at odd indices in a given list.\n\n Args:\n lst (list): A non-empty list of integers.\n\n Returns:\n int: The sum of even elements at odd indices.\n \"\"\"\n return sum(num for idx, num in enumerate(lst) if idx % 2 != 0 and num % 2 == 0)", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"\n Given a non-empty list of integers, add the even elements that are at odd indices.\n\n Args:\n lst (list): A non-empty list of integers.\n\n Returns:\n int: The sum of the even elements at odd indices.\n\n Examples:\n >>> add([4, 2, 6, 7])\n 2\n \"\"\"\n # Use list slicing to get elements at odd indices and filter even numbers\n # The enumerate function returns both index and value while iterating over a list\n # The sum function adds up the resulting numbers\n return sum(val for idx, val in enumerate(lst) if idx % 2 != 0 and val % 2 == 0)", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"\n Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Args:\n lst (list): A list of integers\n\n Returns:\n int: Sum of even elements at odd indices in the list\n\n Examples:\n >>> add([4, 2, 6, 7])\n 2\n \"\"\"\n # Use a list comprehension and enumerate to get even elements at odd indices\n even_elements_at_odd_indices = [x for i, x in enumerate(lst) if i % 2 != 0 and x % 2 == 0]\n # Sum the even elements at odd indices using built-in sum function\n return sum(even_elements_at_odd_indices)", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"\n Given a non-empty list of integers, add the even elements that are at odd indices.\n\n Args:\n lst (list): A list of integers\n\n Returns:\n int: The sum of even elements at odd indices\n\n Examples:\n >>> add([4, 2, 6, 7])\n 2\n >>> add([10, 6, 5, 4, 3])\n 4\n \"\"\"\n return sum(x for i, x in enumerate(lst) if i % 2 != 0 and x % 2 == 0)", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"\n Given a non-empty list of integers lst, adds the even elements that are at odd indices.\n \n Args:\n lst (list): A non-empty list of integers.\n \n Returns:\n int: Sum of even elements at odd indices.\n \"\"\"\n return sum(x for i, x in enumerate(lst) if i % 2 != 0 and x % 2 == 0)", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst, add the even elements that are at odd indices.\n \n Args:\n lst (list): A list of integers.\n\n Returns:\n int: Sum of even elements at odd indices.\n \"\"\"\n return sum(num for i, num in enumerate(lst) if i % 2 != 0 and num % 2 == 0)", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"\n Given a non-empty list of integers, add the even elements that are at odd indices.\n\n Args:\n lst (list): A list of integers.\n\n Returns:\n int: The sum of even elements at odd indices in the list.\n\n Examples:\n >>> add([4, 2, 6, 7])\n 2\n \"\"\"\n return sum(x for i, x in enumerate(lst) if i % 2 != 0 and x % 2 == 0)", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"\n Given a non-empty list of integers, add the even elements that are at odd indices.\n\n Args:\n lst (list): A non-empty list of integers.\n\n Returns:\n int: Sum of even elements at odd indices.\n\n Examples:\n >>> add([4, 2, 6, 7])\n 2\n \"\"\"\n return sum(num for idx, num in enumerate(lst) if idx % 2 != 0 and num % 2 == 0)", "matching_cluster_idx": 2}]}, "HumanEval/86": {"dps": 55.20669806384092, "dps_norm": 70.76923076923077, "pass@1": 13.0, "profiled": [{"solution": "def anti_shuffle(s):\n \"\"\"\n This function takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in \n ascending order based on ascii value.\n \n Parameters:\n s (str): The input string.\n\n Returns:\n str: The ordered version of the input string.\n \"\"\"\n return ' '.join(''.join(sorted(word)) for word in s.split(' '))", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n This function takes a string, splits it into words, sorts the characters in each word,\n and then joins them back together to form a string.\n\n Args:\n s (str): The input string.\n\n Returns:\n str: The ordered version of the input string.\n \"\"\"\n\n # Split the string into words and spaces\n words_and_spaces = []\n word = ''\n for char in s:\n if char == ' ':\n if word:\n words_and_spaces.append(word)\n word = ''\n words_and_spaces.append(char)\n else:\n word += char\n if word:\n words_and_spaces.append(word)\n\n # Sort the characters in each word\n ordered_words_and_spaces = []\n for word_or_space in words_and_spaces:\n if word_or_space == ' ':\n ordered_words_and_spaces.append(word_or_space)\n else:\n ordered_words_and_spaces.append(''.join(sorted(word_or_space)))\n\n # Join the sorted words and spaces back together\n ordered_string = ''.join(ordered_words_and_spaces)\n\n return ordered_string", "matching_cluster_idx": 1}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Returns an ordered version of a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in ascending order\n based on ASCII value.\n\n Args:\n s (str): Input string.\n\n Returns:\n str: Ordered version of the input string.\n \"\"\"\n words = s.split(' ')\n ordered_words = []\n\n # Use list comprehension to sort characters in each word and join them back\n for word in words:\n ordered_word = ''.join(sorted(word))\n ordered_words.append(ordered_word)\n\n # Join ordered words back into a string with spaces in between\n return ' '.join(ordered_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Returns an ordered version of the input string where each word's characters\n are arranged in ascending order based on ASCII value.\n\n Args:\n s (str): The input string.\n\n Returns:\n str: The ordered version of the input string.\n \"\"\"\n\n # Split the string into words and punctuation\n words = s.split(' ')\n\n # Initialize an empty list to store the ordered words\n ordered_words = []\n\n # Iterate over each word\n for word in words:\n # Sort the characters in the word\n sorted_word = ''.join(sorted(word))\n\n # Add the sorted word to the list of ordered words\n ordered_words.append(sorted_word)\n\n # Join the ordered words back into a string with spaces in between\n ordered_string = ' '.join(ordered_words)\n\n return ordered_string", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n Args:\n s (str): Input string\n\n Returns:\n str: Ordered version of the string\n\n Examples:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns '!!!HWdlloor'\n \"\"\"\n\n # Split the input string into words\n words = s.split(' ')\n\n # Initialize an empty list to store the ordered words\n ordered_words = []\n\n # Iterate over each word in the input string\n for word in words:\n # Convert the word into a list of characters and sort them\n sorted_chars = sorted(word)\n\n # Join the sorted characters back into a string and add it to the list of ordered words\n ordered_words.append(''.join(sorted_chars))\n\n # Join the ordered words back into a string separated by spaces and return it\n return ' '.join(ordered_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n \"\"\"\n result = ''\n word = ''\n \n for char in s:\n # If we encounter a space, sort the current word, append it to result and reset the word\n if char == ' ':\n result += ''.join(sorted(word)) + char\n word = ''\n else:\n word += char\n \n # Don't forget the last word in the string\n result += ''.join(sorted(word))\n \n return result", "matching_cluster_idx": 1}, {"solution": "def anti_shuffle(s):\n \"\"\"\n This function takes a string and returns an ordered version of it.\n The ordered version of a string is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in ascending order based on ASCII value.\n The order of words and blank spaces in the sentence remains unchanged.\n\n Parameters:\n s (str): The input string.\n\n Returns:\n str: The ordered version of the input string.\n \"\"\"\n # Split the string into a list of words\n words = s.split(' ')\n \n # Initialize an empty list to store the ordered words\n ordered_words = []\n \n # Iterate over each word in the list of words\n for word in words:\n # Sort the characters in the word in ascending order based on ASCII value\n # Join the sorted characters back into a word\n ordered_word = ''.join(sorted(word))\n \n # Append the ordered word to the list of ordered words\n ordered_words.append(ordered_word)\n \n # Join the ordered words back into a string separated by spaces\n ordered_string = ' '.join(ordered_words)\n \n # Return the ordered string\n return ordered_string", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Reorders each word in the string based on ASCII value.\n\n Args:\n s (str): The input string.\n\n Returns:\n str: A new string with all words reordered.\n \"\"\"\n # Split the string into words and spaces, preserving the spaces\n words_and_spaces = []\n word = ''\n for char in s:\n if char == ' ':\n if word:\n words_and_spaces.append(''.join(sorted(word)))\n word = ''\n words_and_spaces.append(' ')\n else:\n word += char\n if word:\n words_and_spaces.append(''.join(sorted(word)))\n\n # Join the words and spaces back into a single string\n return ''.join(words_and_spaces)", "matching_cluster_idx": 1}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Takes a string and returns an ordered version of it.\n The ordered version is a string where all words (separated by space)\n are replaced by a new word where all the characters are arranged in\n ascending order based on ASCII value.\n The order of words and blank spaces in the sentence is maintained.\n\n Parameters:\n s (str): The input string.\n\n Returns:\n str: The ordered version of the input string.\n \"\"\"\n # Split the string into words and blank spaces\n words_and_spaces = []\n word = \"\"\n for char in s:\n if char == \" \":\n # If the word is not empty, add it to the list and reset the word\n if word:\n words_and_spaces.append(word)\n word = \"\"\n # Add the space to the list\n words_and_spaces.append(char)\n else:\n word += char\n # Add the last word to the list if it's not empty\n if word:\n words_and_spaces.append(word)\n\n # Order the characters in each word\n ordered_words_and_spaces = []\n for word_or_space in words_and_spaces:\n # Check if the word_or_space is a word (not a space)\n if word_or_space != \" \":\n # Sort the characters in the word based on ASCII value\n ordered_word = \"\".join(sorted(word_or_space))\n ordered_words_and_spaces.append(ordered_word)\n else:\n ordered_words_and_spaces.append(word_or_space)\n\n # Join the ordered words and spaces back into a string\n ordered_string = \"\".join(ordered_words_and_spaces)\n\n return ordered_string", "matching_cluster_idx": 1}, {"solution": "def anti_shuffle(s):\n \"\"\"\n This function takes a string, splits it into words and rearranges the \n characters in each word in ascending order based on their ASCII values.\n \n Parameters:\n s (str): The input string.\n \n Returns:\n str: The ordered version of the string.\n \"\"\"\n # Split the string into words\n words = s.split(' ')\n \n # Initialize an empty list to store the ordered words\n ordered_words = []\n \n # Iterate over each word in the list of words\n for word in words:\n # Convert the word into a list of characters\n chars = list(word)\n \n # Sort the characters in the list in ascending order\n chars.sort()\n \n # Join the sorted characters back into a word\n ordered_word = ''.join(chars)\n \n # Append the ordered word to the list of ordered words\n ordered_words.append(ordered_word)\n \n # Join the ordered words back into a string with spaces in between\n ordered_string = ' '.join(ordered_words)\n \n return ordered_string", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n This function takes a string, splits it into words and spaces, sorts each word\n based on ASCII value, and then combines the results back into a string.\n\n Args:\n s (str): The input string.\n\n Returns:\n str: The string with each word sorted by ASCII value.\n \"\"\"\n result = []\n word = ''\n for char in s:\n # Split words by checking for spaces\n if char == ' ':\n # If a word is found, sort it and add it to the result\n if word:\n result.append(''.join(sorted(word)))\n word = ''\n # Add the space to the result\n result.append(char)\n else:\n # If a character is found, add it to the current word\n word += char\n # Handle the last word (if it doesn't end with a space)\n if word:\n result.append(''.join(sorted(word)))\n # Join the result back into a string\n return ''.join(result)", "matching_cluster_idx": 1}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n Parameters\n ----------\n s : str\n The input string.\n\n Returns\n -------\n str\n The ordered string.\n \"\"\"\n\n # Initialize an empty list to store words and their corresponding sorted versions\n words = s.split(' ')\n \n # Initialize an empty list to store the result\n result = []\n\n for word in words:\n # Split each word into characters and sort them\n sorted_word = ''.join(sorted(word))\n \n # Add the sorted word to the result\n result.append(sorted_word)\n\n # Join the result with spaces and return it\n return ' '.join(result)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n \"\"\"\n words = s.split(' ')\n ordered_words = [''.join(sorted(word, key=lambda c: (c.isalpha(), c))) for word in words]\n return ' '.join(ordered_words)", "matching_cluster_idx": 0}]}, "HumanEval/87": {"dps": 93.94812680115274, "dps_norm": 57.142857142857146, "pass@1": 97.0, "profiled": [{"solution": "def get_row(lst, x):\n \"\"\"\n Finds coordinates of integer x in a 2D list and returns a list of tuples (row, column) \n sorted first by row and then by column in descending order.\n \n Args:\n lst (list): A 2D list of integers\n x (int): The number to find coordinates of\n\n Returns:\n list: A list of tuples representing coordinates of the number x\n \"\"\"\n # Initialize an empty list to store coordinates\n coordinates = []\n\n # Iterate over each row in the 2D list\n for i, row in enumerate(lst):\n # Iterate over each element in the row\n for j, elem in enumerate(row):\n # Check if the element is equal to x\n if elem == x:\n # If it is, append the coordinates to the list\n coordinates.append((i, j))\n\n # Sort the coordinates first by row and then by column in descending order\n coordinates.sort(key=lambda x: (x[0], -x[1]))\n\n # Return the sorted coordinates\n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n This function searches a 2D list for occurrences of a given integer\n and returns the coordinates of these occurrences, sorted by row and column.\n\n Args:\n lst (list): A 2D list of integers.\n x (int): The integer to search for.\n\n Returns:\n list: A list of tuples, where each tuple contains the row and column of an occurrence of x.\n \"\"\"\n\n # Initialize an empty list to store the coordinates of x.\n coordinates = []\n\n # Iterate over the 2D list, keeping track of the current row.\n for row_index, row in enumerate(lst):\n # Iterate over each element in the row, keeping track of the current column.\n for col_index, num in enumerate(row):\n # If the current element is equal to x, add its coordinates to the list.\n if num == x:\n coordinates.append((row_index, col_index))\n\n # Sort the coordinates by row and then by column in descending order.\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n\n # Return the sorted list of coordinates.\n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \"\"\"\n \n # Initialize an empty list to store the coordinates\n coordinates = []\n \n # Iterate over the rows and their indices\n for i, row in enumerate(lst):\n # Find the indices of the target number in the current row\n for j in [j for j, num in enumerate(row) if num == x]:\n # Append the coordinates as a tuple to the list\n coordinates.append((i, j))\n \n # First, sort the coordinates by row in ascending order\n # Then, sort the coordinates of each row in descending order of column\n coordinates.sort(key=lambda x: (x[0], -x[1]))\n \n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n Given a 2D list and an integer x, find all occurrences of x in the list\n and return a list of tuples representing their coordinates (row, column).\n \n The list is sorted by rows in ascending order, then by columns in descending order.\n \n Args:\n lst (list): A 2D list of integers\n x (int): The integer to search for\n \n Returns:\n list: A list of tuples representing the coordinates of x in the list\n \"\"\"\n \n # Initialize an empty list to store the coordinates of x\n coordinates = []\n \n # Iterate over the list with enumerate to get both index and value\n for i, row in enumerate(lst):\n # Check if the row is not empty\n if row:\n # Find all occurrences of x in the row\n indices = [j for j, val in enumerate(row) if val == x]\n \n # For each occurrence, add the coordinate to the list\n for j in indices:\n coordinates.append((i, j))\n \n # Sort the coordinates first by row (ascending) then by column (descending)\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n \n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n\n Parameters:\n lst (list): 2 dimensional data\n x (int): integer to be searched in the list\n\n Returns:\n list: list of tuples representing the coordinates of x in the list\n \"\"\"\n coordinates = []\n for row_idx, row in enumerate(lst):\n # Find all occurrences of 'x' in the current row\n col_indices = [col_idx for col_idx, val in enumerate(row) if val == x]\n # Add each occurrence as a (row, col) tuple to the coordinates list\n for col_idx in col_indices:\n coordinates.append((row_idx, col_idx))\n\n # Sort the coordinates list by row in ascending order, then by column in descending order\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n\n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n Given a 2D list and an integer x, find all occurrences of x and return a list of tuples.\n Each tuple contains the row and column indices of x, with rows sorted in ascending order.\n For coordinates with the same row, columns are sorted in descending order.\n\n Args:\n lst (list): A 2D list of integers.\n x (int): The target integer to find.\n\n Returns:\n list: A list of tuples representing the coordinates of x in the input list.\n \"\"\"\n\n # Find all occurrences of x with their coordinates\n coords = [(i, j) for i, row in enumerate(lst) for j, val in enumerate(row) if val == x]\n\n # Sort the coordinates first by row, then by column in reverse order\n coords.sort(key=lambda coord: (coord[0], -coord[1]))\n\n return coords", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n\n :param lst: a 2D list of integers\n :type lst: list\n :param x: the target integer to find in the list\n :type x: int\n :return: list of tuples, each representing coordinates (row, column)\n :rtype: list\n \"\"\"\n # Find coordinates of x in the list\n coordinates = [(i, j) for i, row in enumerate(lst) for j, val in enumerate(row) if val == x]\n\n # Sort coordinates by row in ascending order, then by column in descending order\n sorted_coordinates = sorted(coordinates, key=lambda x: (x[0], -x[1]))\n\n return sorted_coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n Finds integers x in the list, and returns list of tuples,\n [(x1, y1), (x2, y2) ...] such that each tuple is a coordinate -\n (row, columns), starting with 0.\n\n :param lst: 2D list\n :param x: target integer\n :return: sorted list of coordinates\n \"\"\"\n # find coordinates\n coordinates = [(i, j) for i, row in enumerate(lst) for j, elem in enumerate(row) if elem == x]\n\n # sort coordinates by rows in ascending order and then by columns in descending order\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n\n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n Given a 2D list and an integer x, finds all occurrences of x in the list\n and returns a list of tuples representing the coordinates (row, column) of x.\n Coordinates are sorted by row in ascending order and by column in descending order.\n\n Args:\n lst (list): A 2D list of integers\n x (int): The integer to find in the list\n\n Returns:\n list: A list of tuples representing the coordinates of x in the list\n \"\"\"\n # Use list comprehension to find all occurrences of x in the list\n coordinates = [(i, j) for i, row in enumerate(lst) for j, val in enumerate(row) if val == x]\n\n # Sort the coordinates by row in ascending order and by column in descending order\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n\n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n Finds coordinates of the given integer x in a nested list\n and returns them as a list of tuples sorted by rows and columns.\n\n Args:\n lst (list): A 2D list (nested list) similar to a matrix.\n x (int): The integer to find in the list.\n\n Returns:\n list: A list of tuples, where each tuple is a coordinate (row, column) of x in the list.\n \"\"\"\n # Find coordinates of x in the list\n coordinates = [(i, j) for i, row in enumerate(lst) for j, val in enumerate(row) if val == x]\n \n # Sort coordinates by rows in ascending order and columns in descending order\n sorted_coordinates = sorted(coordinates, key=lambda coord: (coord[0], -coord[1]))\n \n return sorted_coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n Given a 2 dimensional list and an integer x, \n find all occurrences of x in the list and return their coordinates.\n\n Args:\n lst (list): A 2 dimensional list of integers.\n x (int): The target integer to find in the list.\n\n Returns:\n list: A list of tuples representing the coordinates of x in the list, \n sorted by row and then by column in descending order.\n \"\"\"\n # Initialize an empty list to store the coordinates\n coordinates = []\n\n # Iterate over the rows in the list\n for i, row in enumerate(lst):\n # Iterate over the elements in the row\n for j, elem in enumerate(row):\n # Check if the element is equal to x\n if elem == x:\n # If it is, append its coordinates to the list\n coordinates.append((i, j))\n\n # Sort the coordinates by row in ascending order and then by column in descending order\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n\n # Return the sorted list of coordinates\n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n Find integer x in a 2D list and return list of coordinates (row, column) \n sorted by row in ascending order and by column in descending order.\n\n Args:\n lst (list): 2D list of integers.\n x (int): Integer to be searched.\n\n Returns:\n list: List of coordinates (row, column) of integer x in the list.\n \"\"\"\n # Initialize empty list to store coordinates\n coordinates = []\n\n # Iterate through each row in the list\n for i, row in enumerate(lst):\n # Iterate through each element in the row\n for j, element in enumerate(row):\n # Check if the element is equal to x\n if element == x:\n # If true, append the coordinates to the list\n coordinates.append((i, j))\n\n # Sort the coordinates by row in ascending order and by column in descending order\n coordinates.sort(key=lambda x: (x[0], -x[1]))\n\n # Return the sorted coordinates\n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n Given a 2D list and an integer, find the integer in the list and return a list of tuples.\n Each tuple is a coordinate (row, column) where the integer was found.\n Coordinates are sorted first by row in ascending order, then by column in descending order.\n\n Args:\n lst (list): A 2D list of integers.\n x (int): The integer to search for.\n\n Returns:\n list: A list of tuples containing the coordinates of the found integer.\n \"\"\"\n # Find coordinates of the integer x in the 2D list\n coordinates = [(i, j) for i, row in enumerate(lst) for j, val in enumerate(row) if val == x]\n\n # Sort the coordinates by row in ascending order and by column in descending order\n sorted_coordinates = sorted(coordinates, key=lambda coord: (coord[0], -coord[1]))\n\n return sorted_coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n Returns a list of coordinates where the value x appears in the given list.\n \n Args:\n lst (list): A 2D list, where each sublist may have a different length.\n x (int): The integer to search for.\n \n Returns:\n list: A list of tuples representing coordinates (row, column) in the list.\n \"\"\"\n # Initialize an empty list to store the coordinates\n coordinates = []\n \n # Iterate over the 2D list using enumerate to get the row index and value\n for row_index, row in enumerate(lst):\n # Iterate over the row using enumerate to get the column index and value\n for col_index, value in enumerate(row):\n # Check if the value matches the target x\n if value == x:\n # Append the coordinate (row, column) to the list\n coordinates.append((row_index, col_index))\n \n # First, sort coordinates by rows in ascending order\n coordinates.sort(key=lambda x: x[0])\n # Then, sort coordinates of each row by columns in descending order\n coordinates = sorted(coordinates, key=lambda x: (-x[1] if x[0] == coordinates[0][0] else x[0]))\n \n # However, the lambda function used in previous line will fail for unsorted lists. \n # So we will sort this way instead\n sorted_rows = {}\n for coord in coordinates:\n if coord[0] not in sorted_rows:\n sorted_rows[coord[0]] = []\n sorted_rows[coord[0]].append(coord[1])\n for key in sorted_rows:\n sorted_rows[key].sort(reverse=True)\n sorted_coordinates = []\n for key in sorted(sorted_rows):\n for val in sorted_rows[key]:\n sorted_coordinates.append((key, val))\n \n return sorted_coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n This function finds all occurrences of a given integer x in a 2D list and returns their coordinates.\n\n Args:\n lst (list): A 2D list of integers.\n x (int): The number to search for.\n\n Returns:\n list: A list of tuples, each containing the row and column of an occurrence of x.\n \"\"\"\n # Initialize an empty list to store the coordinates of x\n coordinates = []\n\n # Iterate over each row in the list\n for i, row in enumerate(lst):\n # Iterate over each element in the row\n for j, elem in enumerate(row):\n # Check if the element is equal to x\n if elem == x:\n # If it is, append the coordinates to the list\n coordinates.append((i, j))\n\n # Sort the coordinates by row in ascending order, and by column in descending order within each row\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n\n # Return the sorted coordinates\n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n Given a 2D list and an integer x, find all occurrences of x in the list.\n Return a list of tuples representing the coordinates of x, sorted by row and then by column in descending order.\n\n Args:\n lst (list): A 2D list of integers.\n x (int): The target integer.\n\n Returns:\n list: A list of tuples representing the coordinates of x.\n \"\"\"\n # Initialize an empty list to store the coordinates of x.\n coordinates = []\n\n # Iterate over the rows in the list.\n for i, row in enumerate(lst):\n # Iterate over the columns in the row.\n for j, elem in enumerate(row):\n # Check if the current element is equal to x.\n if elem == x:\n # If it is, append its coordinates to the list.\n coordinates.append((i, j))\n\n # Sort the coordinates by row and then by column in descending order.\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n\n # Return the sorted list of coordinates.\n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n Given a 2D list and an integer, find the integer in the list\n and return a list of coordinates (row, column) sorted by row\n in ascending order and by column in descending order.\n\n Args:\n lst (list): A 2D list of integers\n x (int): The integer to find in the list\n\n Returns:\n list: A list of tuples representing the coordinates of the integer\n \"\"\"\n # Initialize an empty list to store the coordinates\n coordinates = []\n \n # Iterate over the list with enumerate to get the row index\n for row_index, row in enumerate(lst):\n # Iterate over the row with enumerate to get the column index\n for col_index, val in enumerate(row):\n # Check if the current value is equal to x\n if val == x:\n # If it is, append the coordinates to the list\n coordinates.append((row_index, col_index))\n \n # Sort the coordinates first by row in ascending order, then by column in descending order\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n \n # Return the sorted coordinates\n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n Given a 2D list and an integer x, find x in the list and return\n a list of tuples representing coordinates (row, column) where x is found.\n The coordinates are initially sorted by row in ascending order, and then\n by column in descending order within each row.\n\n Args:\n lst (list): A 2D list of integers\n x (int): The integer to search for in the list\n\n Returns:\n list: A list of tuples representing coordinates where x is found\n \"\"\"\n # Initialize an empty list to store coordinates\n coordinates = []\n \n # Iterate over each row in the list with its index\n for i, row in enumerate(lst):\n # Iterate over each element in the row with its index\n for j, elem in enumerate(row):\n # Check if the element is equal to x\n if elem == x:\n # Append the coordinates to the list\n coordinates.append((i, j))\n \n # Sort the coordinates by row in ascending order, and then by column in descending order\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n \n # Return the sorted list of coordinates\n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n Find all occurrences of a given integer in a 2D list and return a sorted list of coordinates.\n\n Args:\n lst (list): A 2D list of integers\n x (int): The integer to be searched in the list\n\n Returns:\n list: A list of tuples representing the coordinates of the integer in the list\n \"\"\"\n # Initialize an empty list to store the coordinates\n coordinates = []\n \n # Iterate over the 2D list with row and column indices\n for i, row in enumerate(lst):\n for j, value in enumerate(row):\n # Check if the current value matches the target integer\n if value == x:\n # Append the coordinates to the list\n coordinates.append((i, j))\n \n # Sort the coordinates first by row in ascending order and then by column in descending order\n coordinates.sort(key=lambda x: (x[0], -x[1]))\n \n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n Given a 2D list and an integer x, find the coordinates of x in the list.\n \n Args:\n lst (list): A 2D list of integers\n x (int): The integer to be found\n \n Returns:\n list: A list of tuples representing the coordinates of x in the list\n \"\"\"\n coordinates = [(i, j) for i, row in enumerate(lst) for j, elem in enumerate(row) if elem == x]\n # First sort by row in ascending order, then by column in descending order\n return sorted(coordinates, key=lambda coord: (coord[0], -coord[1]))", "matching_cluster_idx": 3}]}, "HumanEval/89": {"dps": 91.88144329896907, "dps_norm": 30.714285714285715, "pass@1": 59.0, "profiled": [{"solution": "def encrypt(s):\n \"\"\"\n Encrypts a given string by shifting the alphabet two places down.\n\n Args:\n s (str): The string to be encrypted.\n\n Returns:\n str: The encrypted string.\n\n \"\"\"\n encrypted = \"\"\n\n # Loop through each character in the string\n for char in s:\n # Check if character is an uppercase letter\n if char.isupper():\n # Find the position in the alphabet\n position = ord(char) - 65\n # Apply the shift\n new_position = (position + 2 * 2) % 26\n # Convert back to character and add to encrypted string\n encrypted += chr(new_position + 65)\n # Check if character is a lowercase letter\n elif char.islower():\n # Find the position in the alphabet\n position = ord(char) - 97\n # Apply the shift\n new_position = (position + 2 * 2) % 26\n # Convert back to character and add to encrypted string\n encrypted += chr(new_position + 97)\n else:\n # If the character is not a letter, add it as is\n encrypted += char\n\n return encrypted", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"\n Encrypts a string by rotating the alphabet.\n Each character in the string is shifted down by two multiplied to two places.\n If a character is not an alphabet letter, it remains unchanged.\n \n Args:\n s (str): The input string to be encrypted.\n\n Returns:\n str: The encrypted string.\n \"\"\"\n\n result = \"\"\n\n for char in s:\n # Check if the character is an uppercase or lowercase letter\n if char.isalpha():\n ascii_offset = ord('a') if char.islower() else ord('A')\n shift = 2 * 2\n result += chr((ord(char) - ascii_offset + shift) % 26 + ascii_offset)\n else:\n # If not a letter, keep the character unchanged\n result += char\n\n return result", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"\n Encrypt a string by rotating the alphabet in a manner such that the letters \n shift down by two multiplied to two places.\n\n Args:\n s (str): The input string to encrypt.\n\n Returns:\n str: The encrypted string.\n \"\"\"\n result = \"\"\n for char in s:\n if char.isalpha():\n ascii_offset = 65 if char.isupper() else 97\n encrypted_char = chr((ord(char) - ascii_offset + 2**2) % 26 + ascii_offset)\n result += encrypted_char\n else:\n result += char\n return result", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"\n Encrypts a string by shifting each letter in the string down the alphabet\n by two positions multiplied by two places.\n\n Args:\n s (str): The string to be encrypted.\n\n Returns:\n str: The encrypted string.\n \"\"\"\n encrypted_string = \"\"\n\n for char in s:\n # Check if character is an alphabet letter\n if char.isalpha():\n # Calculate shift value\n shift = 2 * 2 # Shift down by two multiplied by two places\n\n # Calculate ASCII value of 'a' or 'A' depending on case\n ascii_offset = ord('a') if char.islower() else ord('A')\n\n # Calculate new character by shifting down the alphabet\n encrypted_char = chr((ord(char) - ascii_offset + shift) % 26 + ascii_offset)\n\n # Append encrypted character to encrypted string\n encrypted_string += encrypted_char\n else:\n # If character is not a letter, append it to encrypted string as is\n encrypted_string += char\n\n return encrypted_string", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"\n Encrypts a string by rotating the alphabet down by 2 * 2 places.\n\n Args:\n s (str): The string to be encrypted.\n\n Returns:\n str: The encrypted string.\n \"\"\"\n result = \"\"\n shift = 4 # 2 * 2 = 4\n for char in s:\n # Check if the character is an alphabet\n if char.isalpha():\n ascii_offset = 97 if char.islower() else 65\n # Calculate the new character by shifting and wrapping around the alphabet\n new_char = chr((ord(char) - ascii_offset + shift) % 26 + ascii_offset)\n result += new_char\n else:\n # Non-alphabet characters are not encrypted\n result += char\n return result", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"\n Encrypt a string by rotating the alphabet 4 places down.\n\n Args:\n s (str): The string to be encrypted.\n\n Returns:\n str: The encrypted string.\n\n Example:\n >>> encrypt('hi')\n 'lm'\n \"\"\"\n # Define the shift for encryption\n shift = 4\n \n # Initialize an empty string to store the result\n encrypted_string = \"\"\n \n # Iterate through each character in the string\n for char in s:\n # Check if the character is an uppercase letter\n if char.isupper():\n # Calculate the ASCII value after shifting\n shifted_ascii = ord('A') + (ord(char) - ord('A') + shift) % 26\n # Convert ASCII value back to character\n encrypted_char = chr(shifted_ascii)\n # Check if the character is a lowercase letter\n elif char.islower():\n # Calculate the ASCII value after shifting\n shifted_ascii = ord('a') + (ord(char) - ord('a') + shift) % 26\n # Convert ASCII value back to character\n encrypted_char = chr(shifted_ascii)\n else:\n # If not a letter, just add it to the string\n encrypted_char = char\n \n # Add the encrypted character to the result string\n encrypted_string += encrypted_char\n \n return encrypted_string", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"\n Encrypt a string by rotating the alphabet such that each letter is shifted down by 2*2 places.\n\n Args:\n s (str): The input string to be encrypted.\n\n Returns:\n str: The encrypted string.\n\n \"\"\"\n # Define the alphabet\n alphabet = 'abcdefghijklmnopqrstuvwxyz'\n \n # Initialize an empty string to store the encrypted string\n encrypted_string = ''\n\n # Iterate over each character in the input string\n for char in s:\n # Check if the character is a lowercase letter\n if char.islower():\n # Find the index of the character in the alphabet\n index = alphabet.index(char)\n \n # Calculate the new index by shifting down by 2*2 places\n new_index = (index + 4) % 26\n \n # Append the character at the new index to the encrypted string\n encrypted_string += alphabet[new_index]\n else:\n # If the character is not a lowercase letter, append it as is\n encrypted_string += char\n \n return encrypted_string", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"\n Encrypts a given string by rotating the alphabet in a manner \n such that each letter shifts down by two multiplied to two places.\n \n Parameters:\n s (str): The input string to be encrypted\n \n Returns:\n str: The encrypted string\n \"\"\"\n \n # Define the standard English alphabet (both lowercase and uppercase)\n alphabet = 'abcdefghijklmnopqrstuvwxyz'\n uppercase_alphabet = alphabet.upper()\n \n # Initialize an empty string to store the encrypted result\n encrypted = ''\n \n # Iterate over each character in the input string\n for char in s:\n \n # Check if the character is an uppercase letter\n if char.isupper():\n # Find the index of the character in the uppercase alphabet\n index = uppercase_alphabet.index(char)\n \n # Calculate the new index after shifting down by 2 * 2 places\n # Use the modulo operator to ensure the index stays within the alphabet\n new_index = (index + 4) % 26\n \n # Append the character at the new index to the encrypted string\n encrypted += uppercase_alphabet[new_index]\n \n # Check if the character is a lowercase letter\n elif char.islower():\n # Find the index of the character in the lowercase alphabet\n index = alphabet.index(char)\n \n # Calculate the new index after shifting down by 2 * 2 places\n # Use the modulo operator to ensure the index stays within the alphabet\n new_index = (index + 4) % 26\n \n # Append the character at the new index to the encrypted string\n encrypted += alphabet[new_index]\n \n # If the character is not a letter, append it as is to the encrypted string\n else:\n encrypted += char\n \n # Return the encrypted string\n return encrypted", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"\n Encrypts a string by rotating the alphabet down by 2 places multiplied to 2 positions.\n\n Args:\n s (str): The string to be encrypted.\n\n Returns:\n str: The encrypted string.\n\n \"\"\"\n alphabet = 'abcdefghijklmnopqrstuvwxyz'\n shifted_alphabet = alphabet[4:] + alphabet[:4]\n table = str.maketrans(alphabet + alphabet.upper(), shifted_alphabet + shifted_alphabet.upper())\n return s.translate(table)", "matching_cluster_idx": 5}, {"solution": "def encrypt(s):\n \"\"\"\n Encrypts the input string by shifting each letter two places down in the alphabet, \n wrapping around to the beginning of the alphabet if necessary.\n\n Args:\n s (str): The input string to be encrypted.\n\n Returns:\n str: The encrypted string.\n \"\"\"\n encrypted_string = \"\"\n for char in s:\n # Check if character is an uppercase letter\n if char.isupper():\n # Find the position in 0-25 for uppercase letters\n position = ord(char) - ord('A')\n # Perform the shift\n new_position = (position + 4) % 26\n # Convert back to character\n encrypted_char = chr(new_position + ord('A'))\n # Check if character is a lowercase letter\n elif char.islower():\n # Find the position in 0-25 for lowercase letters\n position = ord(char) - ord('a')\n # Perform the shift\n new_position = (position + 4) % 26\n # Convert back to character\n encrypted_char = chr(new_position + ord('a'))\n else:\n # If the character is not a letter, just append it as is\n encrypted_char = char\n encrypted_string += encrypted_char\n return encrypted_string", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"\n Encrypts a string by shifting each character down the alphabet by two positions,\n then shifting by two places.\n\n Args:\n s (str): The string to be encrypted.\n\n Returns:\n str: The encrypted string.\n \"\"\"\n alphabet = 'abcdefghijklmnopqrstuvwxyz'\n encrypted_str = ''\n for char in s:\n if char.isalpha():\n shift = 2 * 2\n index = alphabet.index(char.lower())\n new_index = (index + shift) % 26\n if char.isupper():\n encrypted_str += alphabet[new_index].upper()\n else:\n encrypted_str += alphabet[new_index]\n else:\n encrypted_str += char\n return encrypted_str", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"\n This function encrypts a string by shifting each character two places\n down in the alphabet, wrapping around if necessary.\n\n Args:\n s (str): The string to be encrypted.\n\n Returns:\n str: The encrypted string.\n\n \"\"\"\n alphabet = 'abcdefghijklmnopqrstuvwxyz'\n encrypted_string = ''\n for char in s:\n if char.isalpha(): # Check if character is a letter\n if char.isupper(): # Check for uppercase letters\n index = (alphabet.index(char.lower()) + 4) % 26\n encrypted_string += alphabet[index].upper()\n else:\n index = (alphabet.index(char) + 4) % 26\n encrypted_string += alphabet[index]\n else:\n encrypted_string += char # Non-alphabetic characters are left unchanged\n return encrypted_string", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"\n Encrypts a given string by shifting down the alphabet by two places, \n with the shift amount multiplied by two.\n\n Parameters:\n s (str): The string to encrypt.\n\n Returns:\n str: The encrypted string.\n \"\"\"\n alphabet = 'abcdefghijklmnopqrstuvwxyz'\n encrypted = ''\n \n # Calculate the shift amount (two multiplied by two)\n shift = 2 * 2\n \n # Iterate over each character in the string\n for char in s:\n # Check if the character is in the alphabet\n if char.lower() in alphabet:\n # Find the index of the character in the alphabet\n index = alphabet.index(char.lower())\n # Calculate the new index with the shift\n new_index = (index + shift) % len(alphabet)\n # Check if the original character was uppercase\n if char.isupper():\n # Append the encrypted character in uppercase to the result\n encrypted += alphabet[new_index].upper()\n else:\n # Append the encrypted character to the result\n encrypted += alphabet[new_index]\n else:\n # If the character is not in the alphabet, append it as is\n encrypted += char\n \n return encrypted", "matching_cluster_idx": 0}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated. \n The alphabet should be rotated in a manner such that the letters \n shift down by two multiplied to two places.\n \"\"\"\n # Create a string of lowercase English letters\n alphabet = 'abcdefghijklmnopqrstuvwxyz'\n \n # Initialize an empty string to store the encrypted result\n encrypted = ''\n \n # Iterate over each character in the input string\n for char in s:\n # Check if the character is a lowercase letter\n if char.islower():\n # Find the index of the character in the alphabet\n index = alphabet.index(char)\n # Apply the rotation and ensure we stay within the alphabet bounds\n rotated_index = (index + 2 * 2) % len(alphabet)\n # Append the rotated character to the encrypted result\n encrypted += alphabet[rotated_index]\n else:\n # If the character is not a lowercase letter, append it as is\n encrypted += char\n \n # Return the encrypted string\n return encrypted", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"\n Encrypt a string by shifting each letter two positions down the alphabet,\n where the shift amount is squared (i.e., 2 * 2 = 4 positions down).\n\n Args:\n s (str): The string to be encrypted.\n\n Returns:\n str: The encrypted string.\n \"\"\"\n encrypted = \"\"\n shift = 2 ** 2 # Square the shift amount\n for char in s:\n if char.isalpha():\n ascii_offset = 65 if char.isupper() else 97\n encrypted += chr((ord(char) - ascii_offset + shift) % 26 + ascii_offset)\n else:\n encrypted += char\n return encrypted", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"\n Encrypts the input string by shifting each letter down the alphabet by 4 places.\n \n Parameters:\n s (str): The input string to encrypt.\n \n Returns:\n str: The encrypted string.\n \"\"\"\n encrypted = \"\"\n \n for char in s:\n # Check if the character is an uppercase letter\n if char.isupper():\n # Find the position in 0-25 of the alphabet\n position = ord(char) - ord('A')\n # Perform the shift and wrap around the alphabet if necessary\n new_position = (position + 4) % 26\n # Convert back to a character\n encrypted += chr(new_position + ord('A'))\n # Check if the character is a lowercase letter\n elif char.islower():\n # Find the position in 0-25 of the alphabet\n position = ord(char) - ord('a')\n # Perform the shift and wrap around the alphabet if necessary\n new_position = (position + 4) % 26\n # Convert back to a character\n encrypted += chr(new_position + ord('a'))\n else:\n # If the character is not a letter, leave it unchanged\n encrypted += char\n \n return encrypted", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"\n Encrypts a string by rotating the alphabet, shifting each letter down by 2 * 2 places.\n\n Args:\n s (str): The input string to be encrypted.\n\n Returns:\n str: The encrypted string.\n \"\"\"\n encrypted_string = \"\"\n shift_amount = 2 * 2 # Calculate the shift amount\n for char in s: # Iterate over each character in the input string\n if char.isalpha(): # Check if the character is a letter\n ascii_offset = 65 if char.isupper() else 97 # ASCII offset for uppercase or lowercase letters\n encrypted_char = chr((ord(char) - ascii_offset + shift_amount) % 26 + ascii_offset)\n encrypted_string += encrypted_char\n else:\n encrypted_string += char # If the character is not a letter, add it to the encrypted string as is\n return encrypted_string", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"\n Encrypts a string by shifting the alphabet down by two multiplied to two places.\n\n Args:\n s (str): The input string to be encrypted.\n\n Returns:\n str: The encrypted string.\n \"\"\"\n result = \"\"\n\n for char in s:\n # Check if the character is an uppercase letter\n if char.isupper():\n # Calculate the ASCII value of the encrypted character\n encrypted_char_value = (ord(char) - ord('A') + 4) % 26 + ord('A')\n result += chr(encrypted_char_value)\n # Check if the character is a lowercase letter\n elif char.islower():\n # Calculate the ASCII value of the encrypted character\n encrypted_char_value = (ord(char) - ord('a') + 4) % 26 + ord('a')\n result += chr(encrypted_char_value)\n else:\n # If the character is not a letter, add it as is\n result += char\n\n return result", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"\n Encrypts a given string by rotating the alphabet in a manner such that \n the letters shift down by two multiplied to two places.\n\n Args:\n s (str): The string to be encrypted.\n\n Returns:\n str: The encrypted string.\n \"\"\"\n # The shift value is 2*2 = 4\n shift = 4\n \n # Use a list comprehension to create a new string where each character \n # in the original string is shifted down by the specified amount\n encrypted_s = ''.join(chr((ord(char) - 97 + shift) % 26 + 97) \n if char.isalpha() and char.islower() \n else chr((ord(char) - 65 + shift) % 26 + 65) \n if char.isalpha() and char.isupper() \n else char for char in s)\n \n return encrypted_s", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Encrypts a string with the alphabet being rotated.\n\n The alphabet is rotated in a manner such that the letters shift down by two \n multiplied to two places.\n\n Args:\n s (str): The input string to encrypt.\n\n Returns:\n str: The encrypted string.\n \"\"\"\n shift = 2 ** 2 # Calculate the shift amount\n encrypted_s = \"\"\n\n for char in s:\n # Check if the character is an alphabet\n if char.isalpha():\n ascii_offset = 65 if char.isupper() else 97 # ASCII values for 'A' or 'a'\n encrypted_char = chr((ord(char) - ascii_offset + shift) % 26 + ascii_offset)\n encrypted_s += encrypted_char\n else:\n encrypted_s += char # If not an alphabet, add as is\n\n return encrypted_s", "matching_cluster_idx": 1}]}, "HumanEval/90": {"dps": 80.38910505836576, "dps_norm": 56.66666666666667, "pass@1": 96.0, "profiled": [{"solution": "def next_smallest(lst):\n \"\"\"\n Returns the 2nd smallest element of a list of integers.\n \n If there is no such element, returns None.\n \n :param lst: A list of integers.\n :return: The 2nd smallest element in the list, or None if there is no such element.\n \"\"\"\n if len(lst) < 2:\n # If the list contains less than 2 elements, there is no 2nd smallest element.\n return None\n sorted_lst = sorted(set(lst)) # Remove duplicates and sort the list.\n if len(sorted_lst) < 2:\n # If the list contains only one unique element, there is no 2nd smallest element.\n return None\n return sorted_lst[1] # Return the 2nd smallest element.", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n Returns the 2nd smallest element of the list.\n Returns None if there is no such element.\n \n :param lst: A list of integers.\n :return: The 2nd smallest element or None.\n \"\"\"\n # Check if the list has less than 2 distinct elements\n if len(set(lst)) < 2:\n return None\n \n # Remove duplicates by converting to a set and sort the list\n sorted_lst = sorted(set(lst))\n \n # Return the 2nd element in the sorted list (index 1)\n return sorted_lst[1]", "matching_cluster_idx": 5}, {"solution": "def next_smallest(lst):\n \"\"\"\n Returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \"\"\"\n # Remove duplicates and sort the list in ascending order\n unique_sorted = sorted(set(lst))\n \n # If the length of the list is less than 2, there's no 2nd smallest element\n if len(unique_sorted) < 2:\n return None\n \n # Return the 2nd smallest element\n return unique_sorted[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n This function returns the 2nd smallest element of a list.\n If the list is empty or there is no 2nd smallest element, returns None.\n\n Args:\n lst (list): A list of integers.\n\n Returns:\n int or None: The 2nd smallest element of the list, or None if it doesn't exist.\n \"\"\"\n if len(lst) < 2: # Check if the list has less than 2 elements\n return None\n sorted_lst = sorted(set(lst)) # Remove duplicates and sort the list\n if len(sorted_lst) < 2: # Check if the sorted list has less than 2 elements\n return None\n return sorted_lst[1] # Return the 2nd smallest element", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n Returns the 2nd smallest element of the list.\n Returns None if there is no such element.\n\n Args:\n lst (list): A list of integers.\n\n Returns:\n int or None: The 2nd smallest element or None.\n \"\"\"\n # Remove duplicates by converting the list to a set\n unique_nums = set(lst)\n \n # If the list is empty or contains only one unique element, return None\n if len(unique_nums) < 2:\n return None\n \n # Sort the unique numbers and return the second smallest\n return sorted(unique_nums)[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n This function returns the 2nd smallest element of the list.\n Returns None if there is no such element.\n \"\"\"\n # Filter out duplicates and sort the list\n unique_sorted_lst = sorted(set(lst))\n \n # Return None if there is no second smallest element\n if len(unique_sorted_lst) < 2:\n return None\n \n # Return the 2nd smallest element\n return unique_sorted_lst[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n Returns the 2nd smallest element of the list, or None if there is no such element.\n\n Args:\n lst (list): A list of integers.\n\n Returns:\n int or None: The 2nd smallest element of the list, or None.\n \"\"\"\n if len(lst) < 2:\n return None # Less than two elements, no 2nd smallest element\n sorted_lst = sorted(set(lst)) # Remove duplicates and sort\n if len(sorted_lst) < 2:\n return None # After removing duplicates, less than two elements\n return sorted_lst[1] # Return the 2nd smallest element", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n This function returns the 2nd smallest element of the list.\n Returns None if there is no such element.\n\n Args:\n lst (list): A list of integers.\n\n Returns:\n int or None: The 2nd smallest element in the list or None if no such element exists.\n \"\"\"\n\n # Remove duplicates by converting the list to a set\n unique_lst = set(lst)\n \n # If the set contains less than two elements, there is no second smallest element\n if len(unique_lst) < 2:\n return None\n \n # Remove the smallest element from the set\n unique_lst.remove(min(unique_lst))\n \n # The smallest element in the updated set is the 2nd smallest in the original list\n return min(unique_lst)", "matching_cluster_idx": 5}, {"solution": "def next_smallest(lst):\n \"\"\"\n Returns the 2nd smallest element of the list.\n Returns None if there is no such element.\n \n :param lst: A list of integers.\n :return: The 2nd smallest integer in the list, or None if not found.\n \"\"\"\n if len(lst) < 2:\n return None\n unique_lst = sorted(set(lst))\n if len(unique_lst) < 2:\n return None\n return unique_lst[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n Returns the 2nd smallest element of the list.\n Returns None if there is no such element.\n\n Args:\n lst (list): A list of integers.\n\n Returns:\n int or None: The 2nd smallest element in the list, or None if it does not exist.\n \"\"\"\n # Remove duplicates by converting the list to a set\n unique_nums = set(lst)\n \n # If the list has less than 2 unique elements, return None\n if len(unique_nums) < 2:\n return None\n \n # Sort the unique numbers and return the second one\n return sorted(unique_nums)[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n Returns the 2nd smallest element of the list.\n Returns None if there is no such element.\n \n :param lst: A list of integers\n :return: The 2nd smallest integer in the list or None\n \"\"\"\n # Remove duplicates by converting the list to a set\n unique_elements = set(lst)\n \n # If there's less than 2 unique elements, return None\n if len(unique_elements) < 2:\n return None\n \n # Remove the smallest element\n unique_elements.remove(min(unique_elements))\n \n # Return the smallest element of the remaining set (the 2nd smallest of the original list)\n return min(unique_elements)", "matching_cluster_idx": 5}, {"solution": "def next_smallest(lst):\n \"\"\"\n Returns the 2nd smallest element in the list.\n Returns None if there is no such element.\n \"\"\"\n if len(lst) < 2:\n return None\n \n # Remove duplicates and sort the list\n unique_sorted_lst = sorted(set(lst))\n \n # If the list has less than 2 unique elements, return None\n if len(unique_sorted_lst) < 2:\n return None\n \n # The 2nd smallest element is at index 1\n return unique_sorted_lst[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n This function returns the 2nd smallest element of the given list.\n If there is no such element, it returns None.\n \n Parameters:\n lst (list): A list of integers.\n \n Returns:\n int or None: The 2nd smallest element of the list, or None if it doesn't exist.\n \"\"\"\n # Remove duplicates by converting the list to a set and then sort it\n unique_elements = sorted(set(lst))\n \n # If the list has less than 2 unique elements, return None\n if len(unique_elements) < 2:\n return None\n \n # Return the 2nd smallest element\n return unique_elements[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n Returns the 2nd smallest element in a list of integers.\n Returns None if there is no such element.\n\n :param lst: A list of integers\n :return: The 2nd smallest element or None\n \"\"\"\n # Remove duplicates by converting the list to a set\n unique_lst = set(lst)\n \n # If the list has less than 2 unique elements, return None\n if len(unique_lst) < 2:\n return None\n \n # Sort the unique list and return the 2nd smallest element\n return sorted(unique_lst)[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n Returns the 2nd smallest element of a list of integers.\n Returns None if there is no such element.\n\n Args:\n lst (list): A list of integers.\n\n Returns:\n int: The 2nd smallest element of the list, or None if there is no such element.\n \"\"\"\n if len(lst) < 2:\n return None\n \n # Remove duplicates by converting to set\n unique_lst = set(lst)\n \n # If list has less than 2 unique elements, return None\n if len(unique_lst) < 2:\n return None\n \n # Remove the smallest element from the list\n unique_lst.remove(min(unique_lst))\n \n # The smallest remaining element is the 2nd smallest of the original list\n return min(unique_lst)", "matching_cluster_idx": 5}, {"solution": "def next_smallest(lst):\n \"\"\"\n Returns the 2nd smallest element of the list.\n \n If there is no 2nd smallest element (e.g., an empty list or a list with a single unique element), \n the function returns None.\n\n :param lst: A list of integers.\n :return: The 2nd smallest element in the list or None.\n \"\"\"\n # Remove duplicates by converting the list to a set and then sort the set\n sorted_set = sorted(set(lst))\n \n # If the list has less than 2 unique elements, return None\n if len(sorted_set) < 2:\n return None\n \n # Return the 2nd element in the sorted set\n return sorted_set[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n Returns the 2nd smallest element of the list.\n Returns None if there is no such element.\n \n Parameters:\n lst (list): A list of integers.\n \n Returns:\n int or None: The 2nd smallest element in the list or None if not found.\n \"\"\"\n if len(lst) < 2:\n # If the list has less than 2 elements, return None\n return None\n \n # Remove duplicates by converting to a set\n unique_lst = set(lst)\n \n if len(unique_lst) < 2:\n # If there's only one unique element in the list, return None\n return None\n \n # Sort the unique list in ascending order and return the second smallest element\n return sorted(unique_lst)[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n Returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \"\"\"\n # Remove duplicates by converting the list to a set\n unique_nums = set(lst)\n \n # If the set contains less than 2 unique elements, return None\n if len(unique_nums) < 2:\n return None\n \n # Sort the set and return the 2nd smallest element\n return sorted(unique_nums)[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n Returns the 2nd smallest element in a list of integers.\n Returns None if there is no such element.\n\n :param lst: A list of integers\n :return: The 2nd smallest element in the list, or None\n \"\"\"\n if len(lst) < 2:\n return None\n unique_elements = sorted(set(lst))\n if len(unique_elements) < 2:\n return None\n return unique_elements[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n Returns the 2nd smallest element of the list.\n Returns None if there is no such element.\n \n :param lst: A list of integers\n :return: The 2nd smallest element or None\n \"\"\"\n # Remove duplicates and sort the list\n unique_elements = sorted(set(lst))\n \n # If list has less than 2 elements, return None\n if len(unique_elements) < 2:\n return None\n \n # Return the 2nd smallest element\n return unique_elements[1]", "matching_cluster_idx": 6}]}, "HumanEval/113": {"dps": 94.32048681541582, "dps_norm": 64.16666666666667, "pass@1": 82.0, "profiled": [{"solution": "def odd_count(lst):\n \"\"\"\n Given a list of strings, where each string consists of only digits,\n return a list. Each element i of the output should be \"the number of\n odd elements in the string i of the input.\" where all the i's should\n be replaced by the number of odd digits in the i'th string of the input.\n\n Parameters:\n lst (list): A list of strings consisting only of digits.\n\n Returns:\n list: A list of strings as described above.\n\n Examples:\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n\n def count_odd_digits(s):\n \"\"\"Count the number of odd digits in a string.\"\"\"\n return sum(1 for digit in s if int(digit) % 2 != 0)\n\n def replace_i(s, count):\n \"\"\"Replace 'i' and 'in' in a string with the given count.\"\"\"\n template = \"the number of odd elements {}n the str{}ng {} of the {}nput.\"\n return template.format(count, count, count, count)\n\n return [replace_i(s, count_odd_digits(s)) for s in lst]", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"\n Given a list of strings, where each string consists of only digits, \n return a list where each element is a string describing the number \n of odd elements in the corresponding input string.\n\n :param lst: A list of strings, where each string consists of only digits\n :return: A list of strings describing the number of odd elements\n \"\"\"\n result = []\n for s in lst:\n # count the number of odd digits in the string\n count = sum(1 for digit in s if int(digit) % 2 != 0)\n \n # replace 'i' with count in the output string\n output = f\"the number of odd elements {count}n the str{count}ng {count} of the {count}nput.\"\n result.append(output)\n \n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\"\"\"\n\n result = []\n for string in lst:\n count_odd = sum(1 for char in string if int(char) % 2 != 0)\n new_string = f\"the number of odd elements {count_odd}n the str{count_odd}ng {count_odd} of the {count_odd}nput.\"\n result.append(new_string)\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"\n Given a list of strings, where each string consists of only digits, \n return a list. Each element i of the output should be \"the number of \n odd elements in the string i of the input.\" where all the i's should \n be replaced by the number of odd digits in the i'th string of the input.\n \n Args:\n lst (list): A list of strings, where each string consists of only digits.\n \n Returns:\n list: A list of strings with the number of odd elements in each string.\n \"\"\"\n result = []\n \n for s in lst:\n # Count the number of odd digits in the string\n odd_count = sum(1 for digit in s if int(digit) % 2 != 0)\n \n # Create the output string with i replaced by the odd count\n output = f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\"\n \n result.append(output)\n \n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"\n Given a list of strings, where each string consists of only digits, \n return a list. Each element i of the output should be \"the number of \n odd elements in the string i of the input.\" where all the i's should \n be replaced by the number of odd digits in the i'th string of the input.\n\n Parameters:\n lst (list): List of strings containing only digits.\n\n Returns:\n list: A list of formatted strings.\n \"\"\"\n result = []\n for s in lst:\n # Count the number of odd digits in the string\n odd_digit_count = sum(1 for digit in s if int(digit) % 2 != 0)\n \n # Format the output string\n output_string = f\"the number of odd elements {odd_digit_count}n the str{odd_digit_count}ng {odd_digit_count} of the {odd_digit_count}nput.\"\n result.append(output_string)\n \n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"\n Given a list of strings, where each string consists of only digits, \n return a list where each element i is a string describing the number \n of odd elements in the string i of the input.\n\n Args:\n lst (list): A list of strings consisting of only digits.\n\n Returns:\n list: A list of strings describing the number of odd elements in each string.\n \"\"\"\n # Use list comprehension to iterate over the input list\n return [\n # Use string formatting to generate the output string\n f\"the number of odd elements {count}n the str{count}ng {count} of the {count}nput.\"\n # Count the number of odd digits in each string\n for count in [sum(int(digit) % 2 for digit in string) for string in lst]\n ]", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"\n Given a list of strings, where each string consists of only digits, \n return a list where each element is a string that mentions the number of \n odd digits in the input string and its position in the input list.\n\n Args:\n lst (list): A list of strings, where each string consists of only digits.\n\n Returns:\n list: A list of strings, each describing the count of odd digits.\n \"\"\"\n def is_odd(c):\n \"\"\"Check if a character represents an odd digit.\"\"\"\n return int(c) % 2 != 0\n\n def count_odd_digits(s):\n \"\"\"Count the number of odd digits in a string.\"\"\"\n return sum(1 for c in s if is_odd(c))\n\n result = []\n for i, s in enumerate(lst, start=1):\n count = count_odd_digits(s)\n output_string = f\"the number of odd elements {count}n the str{count}ng {count} of the {count}nput.\"\n result.append(output_string)\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"\n Given a list of strings, where each string consists of only digits, \n return a list. Each element i of the output should be \"the number of odd \n elements in the string i of the input.\" where all the i's should be replaced \n by the number of odd digits in the i'th string of the input.\n\n Args:\n lst (list): A list of strings where each string consists of only digits.\n\n Returns:\n list: A list of strings where each string is a formatted string with the \n count of odd digits in the input string.\n \"\"\"\n return [f\"the number of odd elements {sum(int(digit) % 2 for digit in string)}n the str{sum(int(digit) % 2 for digit in string)}ng {sum(int(digit) % 2 for digit in string)} of the {sum(int(digit) % 2 for digit in string)}nput.\" for string in lst]", "matching_cluster_idx": 0}, {"solution": "def odd_count(lst):\n \"\"\"\n Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the \n string i of the input.\" where all the i's should be replaced by the number \n of odd digits in the i'th string of the input.\n\n Args:\n lst (list): A list of strings, where each string consists of only digits.\n\n Returns:\n list: A list of strings as per the problem description.\n \"\"\"\n\n result = []\n for string in lst:\n # Count the number of odd digits in the string\n odd_count_in_string = sum(1 for digit in string if int(digit) % 2 != 0)\n \n # Create the output string with replacements\n output_string = f\"the number of odd elements {odd_count_in_string}n the str{odd_count_in_string}ng {odd_count_in_string} of the {odd_count_in_string}nput.\"\n result.append(output_string)\n \n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"\n Given a list of strings, where each string consists of only digits, \n return a list. Each element i of the output should be \"the number of \n odd elements in the string i of the input.\" where all the i's should \n be replaced by the number of odd digits in the i'th string of the input.\n\n Args:\n lst (list): A list of strings, where each string consists of only digits.\n\n Returns:\n list: A list of strings, where each string contains information about the \n number of odd elements in the corresponding input string.\n \"\"\"\n result = []\n for string in lst:\n # Calculate the count of odd digits in the string\n odd_count = sum(1 for digit in string if int(digit) % 2 != 0)\n \n # Replace all 'i's with the count of odd digits in the template string\n output = \"the number of odd elements {}n the str{}ng {} of the {}nput.\".format(odd_count, odd_count, odd_count, odd_count)\n \n # Append the result to the list\n result.append(output)\n \n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"\n Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n :param lst: A list of strings, where each string consists of only digits\n :return: A list of strings, each string is the count of odd digits in the input\n \"\"\"\n\n def count_odd_digits(s):\n \"\"\"Counts the number of odd digits in a string.\"\"\"\n return sum(1 for digit in s if int(digit) % 2 != 0)\n\n result = []\n for string in lst:\n count = count_odd_digits(string)\n # use string formatting to replace the numbers in the string with the count\n result_string = \"the number of odd elements {}n the str{}ng {} of the {}nput.\".format(count, count, count, count)\n result.append(result_string)\n\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"\n Given a list of strings, where each string consists of only digits, \n return a list. Each element i of the output should be \"the number of \n odd elements in the string i of the input.\" where all the i's should \n be replaced by the number of odd digits in the i'th string of the input.\n \"\"\"\n result = []\n for s in lst:\n odd_digits = sum(1 for digit in s if int(digit) % 2 != 0)\n result.append(\"the number of odd elements {}n the str{}ng {} of the {}nput.\".format(odd_digits, odd_digits, odd_digits, odd_digits))\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"\n Given a list of strings, where each string consists of only digits, \n return a list. Each element i of the output should be \"the number of odd \n elements in the string i of the input.\" where all the i's should be replaced \n by the number of odd digits in the i'th string of the input.\n \"\"\"\n result = []\n for string in lst:\n # count the number of odd digits in the string\n odd_digits_count = sum(1 for digit in string if int(digit) % 2 != 0)\n # create the output string by replacing 'i' with the odd_digits_count\n output_string = f\"the number of odd elements {odd_digits_count}n the str{odd_digits_count}ng {odd_digits_count} of the {odd_digits_count}nput.\"\n result.append(output_string)\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"\n Given a list of strings, where each string consists of only digits, \n return a list of strings where each string represents the number of \n odd elements in the corresponding input string.\n\n Args:\n lst (list): A list of strings where each string consists of only digits.\n\n Returns:\n list: A list of strings with the number of odd elements in each input string.\n \"\"\"\n result = []\n for s in lst:\n # Count the number of odd digits in the string\n odd_count_in_s = sum(1 for c in s if int(c) % 2 != 0)\n \n # Generate the output string with the correct counts\n output = (\n \"the number of odd elements \"\n + str(odd_count_in_s)\n + \"n the str\"\n + str(odd_count_in_s)\n + \"ng \"\n + str(odd_count_in_s)\n + \" of the \"\n + str(odd_count_in_s)\n + \"nput.\"\n )\n \n # Append the output to the result list\n result.append(output)\n\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, \n return a list. Each element i of the output should be \"the number of odd \n elements in the string i of the input.\" where all the i's should be replaced \n by the number of odd digits in the i'th string of the input.\n \"\"\"\n \n result = []\n for string in lst:\n # count the odd numbers in the string\n count = sum(1 for digit in string if int(digit) % 2 != 0)\n \n # format the output string by replacing 'i' with the count of odd numbers\n output = f\"the number of odd elements {count}n the str{count}ng {count} of the {count}nput.\"\n result.append(output)\n \n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"\n Given a list of strings, where each string consists of only digits, \n return a list. Each element i of the output should be \"the number of odd \n elements in the string i of the input.\" where all the i's should be replaced \n by the number of odd digits in the i'th string of the input.\n\n Parameters:\n lst (list): A list of strings where each string consists of only digits.\n\n Returns:\n list: A list of strings where each string describes the number of odd elements \n in the corresponding input string.\n\n Examples:\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n result = []\n for num_str in lst:\n odd_count_str = sum(1 for char in num_str if int(char) % 2 != 0)\n sentence = f\"the number of odd elements {odd_count_str}n the str{odd_count_str}ng {odd_count_str} of the {odd_count_str}nput.\"\n result.append(sentence)\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"\n Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the \n string i of the input.\" where all the i's should be replaced by the number \n of odd digits in the i'th string of the input.\n\n Args:\n lst (list): A list of strings, each consisting only of digits.\n\n Returns:\n list: A list of strings where each string contains the count of odd digits \n in the corresponding input string.\n \"\"\"\n result = []\n for s in lst:\n # Count the number of odd digits in the string\n odd_digit_count = sum(1 for digit in s if int(digit) % 2 != 0)\n \n # Construct the output string with replacements\n output = f\"the number of odd elements {odd_digit_count}n the str{odd_digit_count}ng {odd_digit_count} of the {odd_digit_count}nput.\"\n \n # Append the output string to the result list\n result.append(output)\n \n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"\n Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n Args:\n lst (list): A list of strings, where each string consists of only digits.\n\n Returns:\n list: A list of strings where each string represents the count of odd digits in the\n corresponding input string.\n \"\"\"\n result = []\n for string in lst:\n # Count the number of odd digits in the current string\n odd_digits = sum(1 for digit in string if int(digit) % 2 != 0)\n\n # Replace 'i' in the output string with the number of odd digits\n output = f\"the number of odd elements {odd_digits}n the str{odd_digits}ng {odd_digits} of the {odd_digits}nput.\"\n result.append(output)\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"\n Given a list of strings, where each string consists of only digits,\n return a list. Each element i of the output should be \"the number of odd \n elements in the string i of the input.\" where all the i's should be replaced \n by the number of odd digits in the i'th string of the input.\n\n Args:\n lst (list): A list of strings consisting of only digits.\n\n Returns:\n list: A list of strings describing the count of odd digits.\n \"\"\"\n result = []\n for string in lst:\n # count the number of odd digits in the string\n odd_digit_count = sum(1 for digit in string if int(digit) % 2 != 0)\n \n # replace all 'i's with the odd digit count\n output_string = \"the number of odd elements {}n the str{}ng {} of the {}nput.\".format(odd_digit_count, odd_digit_count, odd_digit_count, odd_digit_count)\n \n result.append(output_string)\n \n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"\n Given a list of strings, where each string consists of only digits, \n return a list. Each element i of the output should be \"the number of \n odd elements in the string i of the input.\" where all the i's should \n be replaced by the number of odd digits in the i'th string of the input.\n\n Args:\n lst (list): A list of strings where each string consists of only digits.\n\n Returns:\n list: A list of strings with the number of odd digits in each string.\n \"\"\"\n result = []\n for s in lst:\n # Calculate the number of odd digits in the string\n num_odd = sum(1 for digit in s if int(digit) % 2 != 0)\n \n # Replace 'i' with the number of odd digits in the string\n res = \"the number of odd elements {}n the str{}ng {} of the {}nput.\".format(num_odd, num_odd, num_odd, num_odd)\n \n # Add the resulting string to the output list\n result.append(res)\n \n return result", "matching_cluster_idx": 3}]}, "HumanEval/119": {"dps": 55.46511627906977, "dps_norm": 63.0, "pass@1": 49.0, "profiled": [{"solution": "def match_parens(lst):\n '''\n Checks if it's possible to concatenate two strings of parentheses to make a good string.\n \n A string S is considered to be good if and only if all parentheses in S are balanced.\n \n Parameters:\n lst (list): A list of two strings consisting of open '(' and close ')' parentheses only.\n \n Returns:\n str: 'Yes' if there's a way to make a good string, 'No' otherwise.\n '''\n def is_balanced(s):\n # Checks if a string of parentheses is balanced.\n stack = []\n for char in s:\n if char == '(':\n stack.append(char)\n elif char == ')':\n if not stack:\n return False\n stack.pop()\n return not stack\n\n # Calculate the total number of open and close parentheses in both strings.\n total_open = lst[0].count('(') + lst[1].count('(')\n total_close = lst[0].count(')') + lst[1].count(')')\n\n # If the total number of open and close parentheses is not equal, \n # it's impossible to make a balanced string.\n if total_open != total_close:\n return 'No'\n\n # Try both concatenation orders and check if either results in a balanced string.\n return 'Yes' if is_balanced(lst[0] + lst[1]) or is_balanced(lst[1] + lst[0]) else 'No'", "matching_cluster_idx": 0}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n str1, str2 = lst\n \n # check if any possible order of strings will be good\n def is_good(s1, s2):\n balance = 0\n for c in s1 + s2:\n if c == '(':\n balance += 1\n else:\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n # check all possible concatenations\n if is_good(str1, str2) or is_good(str2, str1):\n return 'Yes'\n else:\n return 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n '''\n Checks if it's possible to concatenate two strings of parentheses in a way that results in a balanced string.\n\n Args:\n lst (list): A list of two strings containing parentheses.\n\n Returns:\n str: 'Yes' if the strings can be concatenated into a balanced string, 'No' otherwise.\n '''\n\n def is_balanced(s):\n '''Helper function to check if a string of parentheses is balanced.'''\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n else:\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n # Calculate the total balance of both strings\n balance1 = lst[0].count('(') - lst[0].count(')')\n balance2 = lst[1].count('(') - lst[1].count(')')\n\n # Check both possible concatenations\n return 'Yes' if is_balanced(lst[0] + lst[1]) or is_balanced(lst[1] + lst[0]) else 'No'", "matching_cluster_idx": 0}, {"solution": "def match_parens(lst):\n '''\n Checks if two lists of parentheses can be concatenated in some order to produce a good string.\n\n A string S is considered to be good if and only if all parentheses in S are balanced.\n\n Parameters:\n lst (list): A list of two strings, both strings consist of open parentheses '(' or close parentheses ')' only.\n\n Returns:\n str: 'Yes' if there's a way to make a good string, 'No' otherwise.\n '''\n # Calculate the total count of open and close parentheses\n open_paren = lst[0].count('(') + lst[1].count('(')\n close_paren = lst[0].count(')') + lst[1].count(')')\n\n # Check if total count of open and close parentheses is balanced\n if open_paren != close_paren:\n return 'No'\n\n # Try to concatenate the two strings in both orders\n orders = [lst[0] + lst[1], lst[1] + lst[0]]\n\n for order in orders:\n stack = []\n # Check if string is balanced\n for char in order:\n if char == '(':\n stack.append(char)\n elif char == ')':\n if stack and stack[-1] == '(':\n stack.pop()\n else:\n break\n else:\n # If string is balanced, return 'Yes'\n if not stack:\n return 'Yes'\n\n # If no order produces a balanced string, return 'No'\n return 'No'", "matching_cluster_idx": 0}, {"solution": "def match_parens(lst):\n '''\n Checks if it is possible to concatenate two strings of parentheses in \n some order to get a balanced string.\n\n Args:\n lst (list): A list of two strings, each containing only '(' or ')'.\n\n Returns:\n str: 'Yes' if it is possible to make a good string, 'No' otherwise.\n '''\n\n def is_balanced(s):\n \"\"\"\n Helper function to check if a string of parentheses is balanced.\n \"\"\"\n stack = []\n for char in s:\n if char == '(':\n stack.append(char)\n elif char == ')':\n if stack and stack[-1] == '(':\n stack.pop()\n else:\n stack.append(char)\n return not stack\n\n # Concatenate strings in both orders and check if either is balanced\n s1 = lst[0] + lst[1]\n s2 = lst[1] + lst[0]\n\n return 'Yes' if is_balanced(s1) or is_balanced(s2) else 'No'", "matching_cluster_idx": -1}, {"solution": "def match_parens(lst):\n '''\n Checks if it is possible to concatenate the two strings in some order,\n that the resulting string will be balanced.\n\n Args:\n lst (list): A list of two strings consisting of '(' and ')' only.\n\n Returns:\n str: 'Yes' if there's a way to make a good string, and 'No' otherwise.\n '''\n def is_balanced(s):\n '''\n Checks if a string of parentheses is balanced.\n\n Args:\n s (str): A string consisting of '(' and ')' only.\n\n Returns:\n bool: True if the string is balanced, False otherwise.\n '''\n stack = []\n for char in s:\n if char == '(':\n stack.append(char)\n elif char == ')':\n if stack:\n stack.pop()\n else:\n return False\n return not stack\n\n # Check all possible concatenations\n return 'Yes' if is_balanced(lst[0] + lst[1]) or is_balanced(lst[1] + lst[0]) else 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n '''\n Checks if it is possible to concatenate two strings of parentheses in \n some order such that the resulting string is good.\n\n A string S is considered to be good if and only if all parentheses in S \n are balanced.\n\n Parameters:\n lst (list): A list of two strings, both strings consist of open \n parentheses '(' or close parentheses ')' only.\n\n Returns:\n str: 'Yes' if there's a way to make a good string, 'No' otherwise.\n '''\n def is_balanced(s):\n count = 0\n for char in s:\n if char == '(':\n count += 1\n else:\n count -= 1\n if count < 0:\n return False\n return count == 0\n\n return 'Yes' if is_balanced(lst[0] + lst[1]) or is_balanced(lst[1] + lst[0]) else 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n '''\n Check if it's possible to concatenate two strings in some order \n so that the resulting string will be good (all parentheses are balanced).\n \n Args:\n lst (list): A list of two strings, each consisting of open or close parentheses.\n \n Returns:\n str: 'Yes' if there's a way to make a good string, 'No' otherwise.\n '''\n def is_balanced(s):\n balance = 0\n for c in s:\n if c == '(':\n balance += 1\n elif c == ')':\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n # Check all permutations of concatenation\n for s1, s2 in [(lst[0], lst[1]), (lst[1], lst[0])]:\n if is_balanced(s1 + s2):\n return 'Yes'\n\n # If no balanced permutation is found, return 'No'\n return 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n '''\n Checks if it is possible to concatenate two strings of parentheses in some order\n such that the resulting string is balanced.\n\n Args:\n lst (list): A list of two strings, each string consisting of open and close parentheses.\n\n Returns:\n str: 'Yes' if a balanced string can be formed, 'No' otherwise.\n '''\n s1, s2 = lst\n \n def is_balanced(s):\n stack = []\n for char in s:\n if char == '(':\n stack.append(char)\n elif char == ')':\n if stack:\n stack.pop()\n else:\n return False\n return not stack\n \n # Check both possible concatenations\n return 'Yes' if is_balanced(s1 + s2) or is_balanced(s2 + s1) else 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n '''\n Returns 'Yes' if it's possible to concatenate two strings of parentheses\n to form a balanced string, and 'No' otherwise.\n\n :param lst: List of two strings, each containing only '(' or ')'\n :return: 'Yes' if balanced string possible, 'No' otherwise\n '''\n def is_balanced(s):\n '''Check if a string of parentheses is balanced'''\n return s.count('(') == s.count(')') and all(s[:i].count('(') >= s[:i].count(')') for i in range(len(s)))\n\n # Check both concatenation orders\n return 'Yes' if is_balanced(''.join(lst)) or is_balanced(''.join(reversed(lst))) else 'No'", "matching_cluster_idx": 0}, {"solution": "def match_parens(lst):\n '''\n This function determines whether two lists of parentheses can be concatenated\n in any order to form a balanced string of parentheses.\n \n Args:\n lst (list): A list of two strings, each consisting of '(' or ')' only.\n \n Returns:\n str: 'Yes' if the parentheses can be concatenated into a balanced string,\n 'No' otherwise.\n '''\n def is_balanced(s):\n '''Check if a string of parentheses is balanced.'''\n stack = []\n for char in s:\n if char == '(':\n stack.append(char)\n elif char == ')':\n if stack:\n stack.pop()\n else:\n return False\n return not stack\n\n # Count the total number of open and close parentheses\n total_open = lst[0].count('(') + lst[1].count('(')\n total_close = lst[0].count(')') + lst[1].count(')')\n\n # If there are more close parentheses than open parentheses, they cannot be balanced\n if total_close > total_open:\n return 'No'\n\n # Try concatenating in both orders\n return 'Yes' if is_balanced(''.join(lst)) or is_balanced(''.join(reversed(lst))) else 'No'", "matching_cluster_idx": 0}, {"solution": "def match_parens(lst):\n '''\n Checks if it's possible to concatenate two strings of parentheses in some order \n to get a good string with balanced parentheses.\n\n Args:\n lst (list): A list of two strings containing parentheses.\n\n Returns:\n str: 'Yes' if a good string can be formed, 'No' otherwise.\n '''\n # Count the total number of open and close parentheses in both strings\n total_open = lst[0].count('(') + lst[1].count('(')\n total_close = lst[0].count(')') + lst[1].count(')')\n\n # Check if the total number of open and close parentheses are equal\n if total_open != total_close:\n return 'No'\n\n # Check if it's possible to form a good string by concatenating the two strings\n for s1, s2 in [(lst[0], lst[1]), (lst[1], lst[0])]:\n balance = 0\n for c in s1 + s2:\n if c == '(':\n balance += 1\n else:\n balance -= 1\n if balance < 0:\n break\n else:\n # If we didn't break out of the loop, it means we have a good string\n return 'Yes'\n\n # If we couldn't form a good string with either order, return 'No'\n return 'No'", "matching_cluster_idx": 0}, {"solution": "def match_parens(lst):\n '''\n Checks if it's possible to concatenate two strings of parentheses\n in some order to get a balanced string.\n \n Args:\n lst (list): A list of two strings, each consisting of '(' or ')'.\n \n Returns:\n str: 'Yes' if a balanced string can be formed, 'No' otherwise.\n '''\n \n # Count the total number of open and close parentheses\n total_open = lst[0].count('(') + lst[1].count('(')\n total_close = lst[0].count(')') + lst[1].count(')')\n \n # If the total number of open and close parentheses are not equal,\n # it's impossible to form a balanced string\n if total_open != total_close:\n return 'No'\n \n # Initialize a counter for the number of open parentheses\n open_count = 0\n \n # Check if we can form a balanced string by concatenating the strings\n # in both orders\n for s1, s2 in [lst, lst[::-1]]:\n open_count = 0\n for char in s1 + s2:\n if char == '(':\n open_count += 1\n else:\n open_count -= 1\n # If the number of open parentheses becomes negative, \n # we can't form a balanced string\n if open_count < 0:\n break\n else:\n # If we can form a balanced string, return 'Yes'\n return 'Yes'\n \n # If we can't form a balanced string in either order, return 'No'\n return 'No'", "matching_cluster_idx": 0}, {"solution": "def match_parens(lst):\n '''\n Check if it is possible to concatenate the two strings in some order \n that the resulting string will be good.\n\n Args:\n lst (list): A list of two strings, both strings consist of open \n parentheses '(' or close parentheses ')' only.\n\n Returns:\n str: 'Yes' if there's a way to make a good string, and 'No' otherwise.\n '''\n\n def is_good(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n else:\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n # Check all possible concatenations\n for s1, s2 in [(lst[0], lst[1]), (lst[1], lst[0])]:\n if is_good(s1 + s2):\n return 'Yes'\n return 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n '''\n Checks if it is possible to concatenate two strings of parentheses\n in some order to form a balanced string.\n\n Args:\n lst (list): A list of two strings consisting of '(' or ')'\n\n Returns:\n str: 'Yes' if possible to form a balanced string, 'No' otherwise\n '''\n # Calculate the total imbalance in the two strings\n total_open = lst[0].count('(') + lst[1].count('(')\n total_close = lst[0].count(')') + lst[1].count(')')\n\n # If total imbalance is not zero, we can't form a balanced string\n if abs(total_open - total_close) > 0:\n return 'No'\n\n # Check if we can concatenate the strings in either order\n # to form a balanced string\n def is_balanced(s1, s2):\n open_count = 0\n for c in s1 + s2:\n if c == '(':\n open_count += 1\n else:\n open_count -= 1\n if open_count < 0:\n return False\n return True\n\n # Check both possible orders of concatenation\n return 'Yes' if is_balanced(lst[0], lst[1]) or is_balanced(lst[1], lst[0]) else 'No'", "matching_cluster_idx": 0}, {"solution": "def match_parens(lst):\n '''\n Check if it's possible to concatenate two strings of parentheses\n in some order to get a balanced string.\n \n Args:\n lst (list): A list of two strings consisting of '(' and ')' only.\n\n Returns:\n str: 'Yes' if a good string can be formed, 'No' otherwise.\n '''\n\n def is_balanced(s):\n '''Check if a string of parentheses is balanced.'''\n stack = []\n for char in s:\n if char == '(':\n stack.append(char)\n else:\n if not stack:\n return False\n stack.pop()\n return not stack\n\n # Check all permutations of concatenating the strings\n for s in [lst[0] + lst[1], lst[1] + lst[0]]:\n if is_balanced(s):\n return 'Yes'\n return 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n \"\"\"\n Check if it is possible to concatenate the two strings in some order,\n that the resulting string will be good (i.e., all parentheses are balanced).\n\n Args:\n lst (list): A list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n\n Returns:\n str: 'Yes' if there's a way to make a good string, 'No' otherwise.\n \"\"\"\n\n def is_good(s):\n \"\"\"\n Helper function to check if a string is good.\n \"\"\"\n stack = []\n for char in s:\n if char == '(':\n stack.append(char)\n elif char == ')':\n if not stack:\n return False\n stack.pop()\n return not stack\n\n # Check all possible concatenations\n return 'Yes' if is_good(lst[0] + lst[1]) or is_good(lst[1] + lst[0]) else 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n '''\n def is_balanced(s):\n stack = []\n for char in s:\n if char == '(':\n stack.append(char)\n elif char == ')':\n if not stack:\n return False\n stack.pop()\n return not stack\n\n str1, str2 = lst\n return 'Yes' if is_balanced(str1 + str2) or is_balanced(str2 + str1) else 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n '''\n Checks if two strings of parentheses can be concatenated in any order to form a good string.\n\n Args:\n lst (list): A list containing two strings of parentheses.\n\n Returns:\n str: 'Yes' if the strings can be concatenated to form a good string, 'No' otherwise.\n '''\n def is_balanced(s):\n stack = []\n for char in s:\n if char == '(':\n stack.append(char)\n elif char == ')':\n if not stack:\n return False\n stack.pop()\n return not stack\n\n def concat_and_check(s1, s2):\n return is_balanced(s1 + s2)\n\n return 'Yes' if concat_and_check(lst[0], lst[1]) or concat_and_check(lst[1], lst[0]) else 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n '''\n Check if two strings consisting of parentheses can be concatenated to form a good string.\n \n A string S is considered to be good if and only if all parentheses in S are balanced.\n \n Parameters:\n lst (list): List of two strings, each consisting of parentheses.\n \n Returns:\n str: 'Yes' if a good string can be formed, 'No' otherwise.\n '''\n \n def is_balanced(s):\n # Use a stack to check if parentheses in a string are balanced\n stack = []\n for char in s:\n if char == '(':\n stack.append(char)\n elif char == ')':\n if stack:\n stack.pop()\n else:\n return False\n return not stack\n \n # Check both possible concatenations\n return 'Yes' if is_balanced(lst[0] + lst[1]) or is_balanced(lst[1] + lst[0]) else 'No'", "matching_cluster_idx": 4}]}, "HumanEval/120": {"dps": 79.3103448275862, "dps_norm": 94.28571428571428, "pass@1": 36.0, "profiled": [{"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n \n Args:\n arr (list): A list of integers.\n k (int): A positive integer.\n\n Returns:\n list: A sorted list of length k with the maximum k numbers in arr.\n \"\"\"\n # Check if k is within the bounds\n if k > len(arr):\n raise ValueError(\"k cannot be greater than the length of the array.\")\n\n # Use the built-in sort function to sort the array in descending order\n sorted_arr = sorted(arr, reverse=True)\n \n # Slice the sorted array to get the maximum k numbers\n max_k_numbers = sorted_arr[:k]\n \n # Sort the max_k_numbers in ascending order and return the result\n return sorted(max_k_numbers)", "matching_cluster_idx": 5}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n\n Parameters\n ----------\n arr (list): A list of integers\n k (int): A positive integer\n\n Returns\n -------\n list: A sorted list of length k with the maximum k numbers in arr\n\n Examples\n --------\n >>> maximum([-3, -4, 5], 3)\n [-4, -3, 5]\n >>> maximum([4, -4, 4], 2)\n [4, 4]\n >>> maximum([-3, 2, 1, 2, -1, -2, 1], 1)\n [2]\n \"\"\"\n\n # Check if k is greater than the length of the array\n if k > len(arr):\n raise ValueError(\"k cannot be greater than the length of the array\")\n\n # Sort the array in descending order\n sorted_arr = sorted(arr, reverse=True)\n\n # Return the first k elements of the sorted array\n return sorted(sorted_arr[:k])", "matching_cluster_idx": 5}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n\n Args:\n arr (list): A list of integers\n k (int): The number of maximum numbers to select\n\n Returns:\n list: A sorted list of the k maximum numbers in arr\n \"\"\"\n # Sort the array in descending order to get the maximum numbers first\n sorted_arr = sorted(arr, reverse=True)\n\n # Select the top k numbers\n max_k_numbers = sorted_arr[:k]\n\n # Sort the selected numbers in ascending order as per the problem statement\n max_k_numbers.sort()\n\n return max_k_numbers", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n\n Args:\n arr (list): A list of integers\n k (int): A positive integer representing the number of maximum elements to return\n\n Returns:\n list: A sorted list of length k with the maximum k numbers in arr\n \"\"\"\n # Sort the array in descending order to get the maximum numbers first\n sorted_arr = sorted(arr, reverse=True)\n\n # Return the first k elements from the sorted array\n return sorted(sorted_arr[:k])", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n\n Args:\n arr (list): A list of integers.\n k (int): A positive integer.\n\n Returns:\n list: A sorted list of length k with the maximum k numbers in arr.\n\n Raises:\n ValueError: If k is larger than the length of the array.\n \"\"\"\n if k > len(arr):\n raise ValueError(\"k cannot be larger than the length of the array\")\n \n # Sort the array in descending order\n sorted_arr = sorted(arr, reverse=True)\n \n # Return the first k elements of the sorted array\n return sorted(sorted_arr[:k])", "matching_cluster_idx": 5}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n\n Args:\n arr (list): A list of integers.\n k (int): A positive integer.\n\n Returns:\n list: A sorted list of length k with the maximum k numbers in arr.\n \"\"\"\n return sorted(sorted(arr, reverse=True)[:k])", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n \"\"\"\n # First, sort the array in descending order to get the maximum numbers first\n sorted_arr = sorted(arr, reverse=True)\n \n # Then, return the first k elements, which are the maximum k numbers\n # Since the problem statement requires a sorted list, we need to sort the result again in ascending order\n return sorted(sorted_arr[:k])", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n\n Args:\n arr (list): The input list of integers\n k (int): The number of maximum elements to return\n\n Returns:\n list: A sorted list of the k maximum numbers in arr\n \"\"\"\n # Sort the array in descending order\n sorted_arr = sorted(arr, reverse=True)\n \n # Return the first k elements of the sorted array\n return sorted(sorted_arr[:k])", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n\n Args:\n arr (list): A list of integers.\n k (int): A positive integer.\n\n Returns:\n list: A sorted list of length k with the maximum k numbers in arr.\n\n Examples:\n >>> maximum([-3, -4, 5], 3)\n [-4, -3, 5]\n >>> maximum([4, -4, 4], 2)\n [4, 4]\n >>> maximum([-3, 2, 1, 2, -1, -2, 1], 1)\n [2]\n \"\"\"\n # Check if k is not greater than the length of the array\n if k > len(arr):\n raise ValueError(\"k cannot be greater than the length of the array\")\n\n # Sort the array in descending order\n arr.sort(reverse=True)\n\n # Return the first k elements\n return sorted(arr[:k])", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n\n :param arr: A list of integers\n :type arr: list[int]\n :param k: A positive integer\n :type k: int\n :return: A sorted list of length k with the maximum k numbers in arr\n :rtype: list[int]\n \"\"\"\n # Check if k is not greater than the length of the array\n if k > len(arr):\n raise ValueError(\"k cannot be greater than the length of the array\")\n\n # Sort the array in descending order and get the first k elements\n max_k = sorted(arr, reverse=True)[:k]\n \n # Sort max_k in ascending order\n max_k.sort()\n\n return max_k", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n\n Args:\n arr (list): A list of integers.\n k (int): A positive integer.\n\n Returns:\n list: A sorted list of length k with the maximum k numbers in arr.\n \"\"\"\n # Check if k is within the valid range\n if k < 0 or k > len(arr):\n raise ValueError(\"k is out of range\")\n\n # Sort the array in descending order\n sorted_arr = sorted(arr, reverse=True)\n\n # Return the first k elements of the sorted array\n return sorted(sorted_arr[:k])", "matching_cluster_idx": 5}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n\n Args:\n arr (list): A list of integers.\n k (int): A positive integer.\n\n Returns:\n list: A sorted list of length k with the maximum k numbers in arr.\n \"\"\"\n # First, sort the array in descending order to get the maximum numbers first\n sorted_arr = sorted(arr, reverse=True)\n \n # Then, return the first k elements from the sorted array\n return sorted(sorted_arr[:k])", "matching_cluster_idx": 5}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n\n Args:\n arr (list): A list of integers\n k (int): The number of maximum values to return\n\n Returns:\n list: A sorted list of length k with the maximum k numbers in arr\n\n Example:\n\n >>> maximum([-3, -4, 5], 3)\n [-4, -3, 5]\n >>> maximum([4, -4, 4], 2)\n [-4, 4]\n >>> maximum([-3, 2, 1, 2, -1, -2, 1], 1)\n [2]\n \"\"\"\n\n # Sort the array in descending order\n sorted_arr = sorted(arr, reverse=True)\n\n # Return the first k elements (the maximum k numbers)\n return sorted(sorted_arr[:k])", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n\n Args:\n arr (list): A list of integers.\n k (int): A positive integer.\n\n Returns:\n list: A sorted list of length k with the maximum k numbers in arr.\n \"\"\"\n # Sort the array in descending order\n arr.sort(reverse=True)\n \n # Return the k largest numbers\n return sorted(arr[:k], reverse=False)", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n \n :param arr: List of integers\n :type arr: List[int]\n :param k: Positive integer\n :type k: int\n :return: List of length k with the maximum k numbers in arr\n :rtype: List[int]\n \"\"\"\n # Check if k is within the range of the array length\n if k > len(arr):\n raise ValueError(\"k cannot be greater than the length of the array\")\n\n # Sort the array in descending order and select the top k elements\n max_k = sorted(arr, reverse=True)[:k]\n\n # Sort the selected k elements in ascending order\n max_k_sorted = sorted(max_k)\n\n return max_k_sorted", "matching_cluster_idx": 5}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n\n Parameters:\n arr (list): The list of integers.\n k (int): The number of maximum numbers to find.\n\n Returns:\n list: A sorted list of the k maximum numbers in arr.\n \"\"\"\n # Check the constraints\n if k < 0 or k > len(arr):\n raise ValueError(\"k is out of range\")\n\n # Sort the array in descending order\n sorted_arr = sorted(arr, reverse=True)\n\n # Return the k maximum numbers\n return sorted(sorted_arr[:k])", "matching_cluster_idx": 5}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n\n Args:\n arr (list): The input array of integers.\n k (int): The number of maximum integers to return.\n\n Returns:\n list: A sorted list of length k with the maximum k numbers in arr.\n \"\"\"\n\n # Sort the array in descending order to get the maximum numbers first\n sorted_arr = sorted(arr, reverse=True)\n\n # Return a slice of the sorted array of length k\n return sorted(sorted_arr[:k])", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n \n :param arr: A list of integers.\n :type arr: list\n :param k: A positive integer.\n :type k: int\n :return: A sorted list of length k with the maximum k numbers in arr.\n :rtype: list\n \"\"\"\n return sorted(sorted(arr, reverse=True)[:k])", "matching_cluster_idx": 5}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n\n Parameters\n ----------\n arr : list\n A list of integers.\n k : int\n The number of maximum numbers to return.\n\n Returns\n -------\n list\n A sorted list of the maximum k numbers in arr.\n\n Examples\n --------\n >>> maximum([-3, -4, 5], 3)\n [-4, -3, 5]\n >>> maximum([4, -4, 4], 2)\n [-4, 4]\n >>> maximum([-3, 2, 1, 2, -1, -2, 1], 1)\n [2]\n \"\"\"\n\n # Sort the array in descending order to get the maximum numbers first\n sorted_arr = sorted(arr, reverse=True)\n\n # Select the top k numbers from the sorted array\n max_k_numbers = sorted_arr[:k]\n\n # Sort the top k numbers in ascending order\n max_k_numbers = sorted(max_k_numbers)\n\n return max_k_numbers", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list \n of length k with the maximum k numbers in arr.\n\n Args:\n arr (list): A list of integers.\n k (int): A positive integer.\n\n Returns:\n list: A sorted list of length k with the maximum k numbers in arr.\n \"\"\"\n # Check if k is 0\n if k == 0:\n return []\n\n # Sort the array in descending order\n sorted_arr = sorted(arr, reverse=True)\n\n # Slice the array up to the kth element\n max_k_nums = sorted_arr[:k]\n\n # Sort the max_k_nums array in ascending order\n max_k_nums.sort()\n\n return max_k_nums", "matching_cluster_idx": 6}]}, "HumanEval/121": {"dps": 78.02690582959642, "dps_norm": 57.142857142857146, "pass@1": 100.0, "profiled": [{"solution": "def solution(lst):\n \"\"\"\n Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n\n Args:\n lst (list): A non-empty list of integers.\n\n Returns:\n int: The sum of all odd elements at even positions.\n \"\"\"\n return sum(num for idx, num in enumerate(lst) if idx % 2 == 0 and num % 2 != 0)", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n \"\"\"\n Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n\n Args:\n lst (list): A non-empty list of integers.\n\n Returns:\n int: The sum of all odd elements in even positions.\n\n Examples:\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n return sum(num for idx, num in enumerate(lst) if idx % 2 == 0 and num % 2 != 0)", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n \"\"\"\n Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n\n Args:\n lst (list): A list of integers.\n\n Returns:\n int: The sum of odd elements at even positions in the list.\n \"\"\"\n return sum(num for i, num in enumerate(lst) if i % 2 == 0 and num % 2 != 0)", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n \"\"\"\n Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n\n Args:\n lst (list): A non-empty list of integers.\n\n Returns:\n int: The sum of all odd elements at even positions.\n\n Examples:\n >>> solution([5, 8, 7, 1])\n 12\n >>> solution([3, 3, 3, 3, 3])\n 9\n >>> solution([30, 13, 24, 321])\n 0\n \"\"\"\n # Use list comprehension and slicing to get odd numbers at even indices\n return sum(num for idx, num in enumerate(lst) if idx % 2 == 0 and num % 2 != 0)", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n \"\"\"\n Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n\n Args:\n lst (list): A non-empty list of integers.\n\n Returns:\n int: The sum of all odd elements at even positions.\n \"\"\"\n # Filter the list for odd numbers at even positions and sum them\n return sum(num for idx, num in enumerate(lst) if idx % 2 == 0 and num % 2 != 0)", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n \"\"\"\n Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n\n Parameters:\n lst (list): A non-empty list of integers.\n\n Returns:\n int: The sum of all odd elements in even positions in the list.\n \"\"\"\n # Use enumerate to get both index and value while iterating over the list\n # Filter out elements in even positions (0-indexed) and check if the number is odd\n # Sum up these numbers\n return sum(val for idx, val in enumerate(lst) if idx % 2 == 0 and val % 2 != 0)", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n\n Args:\n lst (list): A non-empty list of integers.\n\n Returns:\n int: The sum of all of the odd elements that are in even positions.\n\n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n # Initialize sum of odd numbers at even positions to 0\n sum_of_odd_at_even_positions = 0\n\n # Iterate over list with enumerate to get index and value\n for idx, num in enumerate(lst):\n # Check if the index is even\n if idx % 2 == 0:\n # Check if the number at the even index is odd\n if num % 2 != 0:\n # Add the odd number to the sum\n sum_of_odd_at_even_positions += num\n\n # Return the sum\n return sum_of_odd_at_even_positions", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n \"\"\"\n Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n\n Args:\n lst (list): A list of integers\n\n Returns:\n int: The sum of all odd elements in even positions.\n \"\"\"\n return sum(val for idx, val in enumerate(lst) if idx % 2 == 0 and val % 2 != 0)", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n\n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n return sum(num for idx, num in enumerate(lst) if num % 2 != 0 and idx % 2 == 0)", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n \"\"\"\n Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n\n Args:\n lst (list): A list of integers.\n\n Returns:\n int: The sum of all odd elements in even positions.\n\n Examples:\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n return sum(num for idx, num in enumerate(lst) if idx % 2 == 0 and num % 2 != 0)", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n \"\"\"\n Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n\n Args:\n lst (list): A list of integers.\n\n Returns:\n int: The sum of odd elements at even positions.\n\n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n # Initialize the sum variable to zero\n total_sum = 0\n\n # Iterate through the list using enumerate for index and value\n for index, value in enumerate(lst):\n # Check if the index is even and the value is odd\n if index % 2 == 0 and value % 2 != 0:\n # If both conditions meet, add the value to the total sum\n total_sum += value\n\n # Return the calculated total sum\n return total_sum", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n \"\"\"\n Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n\n Args:\n lst (list): A non-empty list of integers.\n\n Returns:\n int: The sum of all odd elements at even positions.\n\n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n return sum(num for idx, num in enumerate(lst) if idx % 2 == 0 and num % 2 != 0)", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n \"\"\"\n Returns the sum of all of the odd elements that are in even positions.\n\n Args:\n lst (list): A non-empty list of integers.\n\n Returns:\n int: Sum of all odd elements in even positions.\n\n Examples:\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n # Initialize sum variable\n total_sum = 0\n \n # Iterate through the list using enumerate to get both index and value\n for index, value in enumerate(lst):\n \n # Check if the index is even and the value is odd\n if index % 2 == 0 and value % 2 != 0:\n total_sum += value\n \n return total_sum", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n \"\"\"\n Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n Args:\n lst (list): A list of integers.\n \n Returns:\n int: The sum of all odd elements in even positions.\n \"\"\"\n # Use a list comprehension with enumerate to get both index and value from the list\n # Then filter for even indices (0-based indexing) and odd values\n # Finally, sum up the values\n return sum(val for idx, val in enumerate(lst) if idx % 2 == 0 and val % 2 != 0)", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n\n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n return sum(num for i, num in enumerate(lst) if i % 2 == 0 and num % 2 != 0)", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n\n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n return sum(num for idx, num in enumerate(lst) if idx % 2 == 0 and num % 2 != 0)", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n \"\"\"\n Returns the sum of all odd elements that are in even positions in a given list.\n \n Parameters:\n lst (list): A list of integers.\n \n Returns:\n int: The sum of all odd elements that are in even positions.\n \"\"\"\n # Initialize sum to 0\n total_sum = 0\n \n # Iterate over the list with enumerate to get both index and value\n for index, value in enumerate(lst):\n # Check if the index is even (0-based indexing)\n if index % 2 == 0:\n # Check if the value is odd\n if value % 2 != 0:\n # Add the value to the total sum\n total_sum += value\n \n # Return the total sum\n return total_sum", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n \"\"\"\n Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n\n Args:\n lst (list): A non-empty list of integers.\n\n Returns:\n int: The sum of all of the odd elements that are in even positions.\n\n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n\n # Initialize sum variable to 0\n total_sum = 0\n \n # Iterate through the list with enumerate to access index and value\n for index, value in enumerate(lst):\n \n # Check if the index is even and value is odd\n if index % 2 == 0 and value % 2 != 0:\n \n # If both conditions are met, add the value to the sum\n total_sum += value\n \n # Return the total sum\n return total_sum", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n \"\"\"\n Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n Parameters\n lst (list): A non-empty list of integers.\n \n Returns\n int: The sum of all of the odd elements that are in even positions.\n \"\"\"\n return sum(num for idx, num in enumerate(lst) if idx % 2 == 0 and num % 2 != 0)", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n \"\"\"\n Given a non-empty list of integers, return the sum of all of the odd elements \n that are in even positions.\n\n Args:\n lst (list): A list of integers.\n\n Returns:\n int: The sum of all the odd elements in even positions.\n\n Examples:\n >>> solution([5, 8, 7, 1])\n 12\n >>> solution([3, 3, 3, 3, 3])\n 9\n >>> solution([30, 13, 24, 321])\n 0\n \"\"\"\n return sum(num for i, num in enumerate(lst) if i % 2 == 0 and num % 2 != 0)", "matching_cluster_idx": 3}]}, "HumanEval/149": {"dps": 85.82677165354332, "dps_norm": 57.142857142857146, "pass@1": 93.0, "profiled": [{"solution": "def sorted_list_sum(lst):\n \"\"\"\n This function takes a list of strings, removes strings with odd lengths,\n and returns the remaining list sorted by string length and then alphabetically.\n\n Args:\n lst (list): A list of strings.\n\n Returns:\n list: A list of strings with even length, sorted by length and then alphabetically.\n \"\"\"\n # First, filter out the strings with odd lengths\n even_length_strings = [s for s in lst if len(s) % 2 == 0]\n \n # Sort the remaining strings by length and then alphabetically\n sorted_strings = sorted(even_length_strings, key=lambda s: (len(s), s))\n \n return sorted_strings", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"\n This function filters a list of strings by deleting those with odd lengths,\n then returns the resulting list sorted first by string length (in ascending order)\n and then alphabetically.\n\n Args:\n lst (list): A list of strings\n\n Returns:\n list: A filtered and sorted list of strings\n \"\"\"\n\n # Filter the list to include only strings with even lengths\n even_length_strings = [string for string in lst if len(string) % 2 == 0]\n \n # Sort the filtered list first by string length (in ascending order) and then alphabetically\n sorted_list = sorted(even_length_strings, key=lambda x: (len(x), x))\n \n return sorted_list", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"\n Deletes strings with odd lengths from a list of strings and returns the resulted list \n sorted first by the length of the strings (in ascending order), and then alphabetically.\n\n Args:\n lst (list): A list of strings.\n\n Returns:\n list: A sorted list of strings with only even length strings.\n \"\"\"\n\n # Filter out strings with odd lengths\n even_length_strings = [s for s in lst if len(s) % 2 == 0]\n \n # Sort the list of strings by the length and then alphabetically\n sorted_list = sorted(even_length_strings, key=lambda s: (len(s), s))\n\n return sorted_list", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"\n This function accepts a list of strings, deletes strings with odd lengths, \n and returns the resulting list in sorted order.\n \n The sorting order is primarily by string length in ascending order, \n and for strings of the same length, the sorting order is alphabetical.\n\n Args:\n lst (list): A list of strings.\n\n Returns:\n list: A sorted list of strings.\n \"\"\"\n \n # Filter out strings with odd lengths\n filtered_list = [string for string in lst if len(string) % 2 == 0]\n \n # Sort the filtered list first by string length and then alphabetically\n sorted_list = sorted(filtered_list, key=lambda string: (len(string), string))\n \n return sorted_list", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"\n Deletes strings with odd lengths from the input list, \n sorts the remaining list by string length in ascending order, \n and then alphabetically if the lengths are equal.\n\n Args:\n lst (list): A list of strings.\n\n Returns:\n list: A sorted list of strings with even lengths.\n\n \"\"\"\n # Filter out strings with odd lengths\n even_length_strings = [string for string in lst if len(string) % 2 == 0]\n \n # Sort the remaining strings by length and then alphabetically\n sorted_list = sorted(even_length_strings, key=lambda x: (len(x), x))\n \n return sorted_list", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"\n This function filters out strings with odd lengths from the input list,\n sorts the remaining strings first by their lengths and then alphabetically,\n and returns the result.\n\n Args:\n lst (list): A list of strings.\n\n Returns:\n list: A sorted list of strings with even lengths.\n \"\"\"\n # Filter out strings with odd lengths\n even_length_strings = [s for s in lst if len(s) % 2 == 0]\n \n # Sort the strings first by their lengths and then alphabetically\n sorted_strings = sorted(even_length_strings, key=lambda s: (len(s), s))\n \n return sorted_strings", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"\n Deletes the strings that have odd lengths from the input list and returns the resulted list in sorted order.\n \n The list is sorted by the length of each word in ascending order, and for words with the same length, \n they are sorted alphabetically.\n \n Args:\n lst (list): A list of strings.\n \n Returns:\n list: The list of strings with even lengths, sorted by length and then alphabetically.\n \"\"\"\n\n # Filter out the strings with odd lengths\n even_length_strings = [s for s in lst if len(s) % 2 == 0]\n \n # Sort the list of strings first by length and then alphabetically\n sorted_strings = sorted(even_length_strings, key=lambda s: (len(s), s))\n \n return sorted_strings", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"\n Deletes the strings that have odd lengths from the input list,\n and returns the resulted list in sorted order.\n \n The order of the list is sorted by length of each word in ascending order,\n and then alphabetically for words of the same length.\n \n Args:\n lst (list): A list of strings.\n \n Returns:\n list: The sorted list of strings with only even-length strings.\n \"\"\"\n # Filter out strings with odd lengths\n even_length_strings = [s for s in lst if len(s) % 2 == 0]\n \n # Sort the list by length and then alphabetically\n sorted_list = sorted(even_length_strings, key=lambda x: (len(x), x))\n \n return sorted_list", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"\n Deletes strings of odd lengths from a list and returns the resulted list\n sorted in ascending order of string lengths and then alphabetically.\n\n Args:\n lst (list): A list of strings.\n\n Returns:\n list: A sorted list of strings with even lengths.\n \"\"\"\n # Filter out strings of odd lengths\n even_length_strings = [s for s in lst if len(s) % 2 == 0]\n \n # Sort the remaining strings by their lengths and then alphabetically\n sorted_strings = sorted(even_length_strings, key=lambda s: (len(s), s))\n \n return sorted_strings", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"\n This function filters out strings of odd length from the input list,\n and returns the remaining strings in ascending order of their lengths.\n In case of a tie, the strings are sorted alphabetically.\n\n Parameters:\n lst (list): A list of strings\n\n Returns:\n list: A list of strings\n \"\"\"\n # Filter out strings of odd length\n even_length_strings = [string for string in lst if len(string) % 2 == 0]\n \n # Sort the remaining strings first by length and then alphabetically\n sorted_strings = sorted(even_length_strings, key=lambda string: (len(string), string))\n \n return sorted_strings", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"\n This function takes a list of strings, removes strings with odd lengths,\n and returns the resulting list sorted first by string length and then alphabetically.\n\n Args:\n lst (list): A list of strings.\n\n Returns:\n list: A sorted list of strings with even lengths.\n \"\"\"\n # Filter out strings with odd lengths\n even_length_strings = [string for string in lst if len(string) % 2 == 0]\n \n # Sort the list by string length and then alphabetically\n sorted_list = sorted(even_length_strings, key=lambda x: (len(x), x))\n \n return sorted_list", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(input_list):\n \"\"\"\n Deletes the strings that have odd lengths from the list,\n and returns the resulted list with a sorted order.\n\n :param input_list: A list of strings\n :return: A list of strings with even lengths, sorted by length and then alphabetically\n \"\"\"\n # Filter the list for strings with even lengths\n even_length_strings = [string for string in input_list if len(string) % 2 == 0]\n \n # Sort the list by string length and then alphabetically\n sorted_list = sorted(even_length_strings, key=lambda x: (len(x), x))\n \n return sorted_list", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"\n Deletes the strings with odd lengths from a given list, \n and returns the resulted list sorted by string length \n and then alphabetically.\n\n Args:\n lst (list): A list of strings\n\n Returns:\n list: A list of strings sorted by length and then alphabetically\n \"\"\"\n\n # Filter out strings with odd lengths\n even_length_strings = [string for string in lst if len(string) % 2 == 0]\n\n # Sort the list by string length and then alphabetically\n sorted_list = sorted(even_length_strings, key=lambda x: (len(x), x))\n\n return sorted_list", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"\n Deletes the strings that have odd lengths from the list,\n and returns the resulted list with a sorted order.\n\n The list is sorted in ascending order of word length.\n If two words have the same length, they are sorted alphabetically.\n\n Args:\n lst (list): A list of strings.\n\n Returns:\n list: A list of strings in sorted order.\n \"\"\"\n # Filter out strings with odd lengths and sort the list first by length and then alphabetically\n return sorted([s for s in lst if len(s) % 2 == 0], key=lambda x: (len(x), x))", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"\n This function filters a list of strings to remove strings with odd lengths,\n and returns the resulting list sorted by string length in ascending order,\n then alphabetically.\n\n Args:\n lst (list): A list of strings.\n\n Returns:\n list: A sorted list of strings with even lengths.\n \"\"\"\n\n # Filter out strings with odd lengths\n filtered_list = [string for string in lst if len(string) % 2 == 0]\n\n # Sort the filtered list first by string length, then alphabetically\n sorted_list = sorted(filtered_list, key=lambda x: (len(x), x))\n\n return sorted_list", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"\n Deletes the strings with odd lengths from the list and returns the resulting list \n sorted by string lengths in ascending order, and then by alphabetical order.\n\n Args:\n lst (list): A list of strings.\n\n Returns:\n list: The list of strings sorted by length and then alphabetically.\n \"\"\"\n\n # First, filter out the strings with odd lengths\n even_length_strings = [s for s in lst if len(s) % 2 == 0]\n\n # Then, sort the remaining strings first by length and then by alphabetical order\n sorted_strings = sorted(even_length_strings, key=lambda s: (len(s), s))\n\n return sorted_strings", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"\n Deletes the strings that have odd lengths from a given list,\n and returns the resulted list with a sorted order.\n \n The list is sorted in ascending order by the length of each word,\n and then alphabetically for words with the same length.\n \n :param lst: A list of strings.\n :return: A sorted list of strings with even lengths.\n \"\"\"\n # Filter out the strings with odd lengths\n even_length_strings = [s for s in lst if len(s) % 2 == 0]\n \n # Sort the list in ascending order by length and then alphabetically\n sorted_list = sorted(even_length_strings, key=lambda x: (len(x), x))\n \n return sorted_list", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"\n Accepts a list of strings as a parameter, deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order.\n\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n\n Args:\n lst (list): A list of strings\n\n Returns:\n list: A list of strings in sorted order\n \"\"\"\n # Filter out strings with odd lengths\n even_length_strings = [string for string in lst if len(string) % 2 == 0]\n \n # Sort the list by length and then alphabetically\n sorted_list = sorted(even_length_strings, key=lambda x: (len(x), x))\n \n return sorted_list", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(input_list):\n \"\"\"\n This function filters out strings with odd lengths from the input list,\n and returns the remaining strings sorted first by length and then alphabetically.\n\n Args:\n input_list (list): A list of strings\n\n Returns:\n list: A sorted list of strings with even lengths\n \"\"\"\n # Filter out strings with odd lengths\n even_length_strings = [string for string in input_list if len(string) % 2 == 0]\n \n # Sort the remaining strings by length and then alphabetically\n sorted_list = sorted(even_length_strings, key=lambda x: (len(x), x))\n \n return sorted_list", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"\n Deletes the strings that have odd lengths from the list and returns the resulted list in sorted order.\n\n The list is sorted in ascending order by length of each word. If two words have the same length, \n the list is sorted alphabetically.\n\n Args:\n lst (list): A list of strings.\n\n Returns:\n list: A list of strings in sorted order.\n \"\"\"\n # Filter out the strings with odd lengths\n filtered_list = [s for s in lst if len(s) % 2 == 0]\n \n # Sort the list by the length of the strings and then alphabetically\n sorted_list = sorted(filtered_list, key=lambda x: (len(x), x))\n \n return sorted_list", "matching_cluster_idx": 3}]}, "Mbpp/3": {"dps": 54.19491525423729, "dps_norm": 74.375, "pass@1": 91.0, "profiled": [{"solution": "def is_not_prime(n):\n \"\"\"\n This function checks if a number is not a prime number.\n\n Args:\n n (int): The input number to check.\n\n Returns:\n bool: True if the number is not prime, False otherwise.\n \"\"\"\n if n < 2:\n return True # Numbers less than 2 are not prime numbers\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return True # If n is divisible by any number, it's not prime\n return False # If no divisors found, it's a prime number", "matching_cluster_idx": 4}, {"solution": "def is_not_prime(n):\n \"\"\"\n Checks if a number is not prime.\n\n Args:\n n (int): The number to check.\n\n Returns:\n bool: True if the number is not prime, False otherwise.\n \"\"\"\n if n < 2:\n return True\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return True\n return False", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(n):\n \"\"\"\n Checks if a number is not prime.\n\n Args:\n n (int): The number to check.\n\n Returns:\n bool: True if the number is not prime, False otherwise.\n \"\"\"\n if n < 2:\n return True # numbers less than 2 are not prime\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return True # n is divisible by i, hence not prime\n return False # n is prime", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(n):\n \"\"\"\n This function checks if a given number is not prime.\n\n Args:\n n (int): The number to be checked.\n\n Returns:\n bool: True if the number is not prime, False otherwise.\n \"\"\"\n if n < 2:\n return True # numbers less than 2 are not prime\n for i in range(2, int(n ** 0.5) + 1):\n if n % i == 0:\n return True # number is divisible, so it's not prime\n return False # number is prime", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(n):\n \"\"\"\n Checks if a number is not a prime number.\n \n Args:\n n (int): The number to be checked.\n\n Returns:\n bool: True if the number is not a prime number, False otherwise.\n \"\"\"\n if n < 2:\n # By definition, prime numbers are greater than 1\n return True\n for i in range(2, int(n ** 0.5) + 1):\n # We only need to check divisibility up to the square root of n\n if n % i == 0:\n # If n is divisible by any number, it's not a prime number\n return True\n return False", "matching_cluster_idx": 4}, {"solution": "def is_not_prime(n):\n \"\"\"\n Check if a number is not prime.\n\n Args:\n n (int): The number to check.\n\n Returns:\n bool: True if the number is not prime, False otherwise.\n \"\"\"\n if n <= 1:\n return True\n if n == 2:\n return False\n if n % 2 == 0:\n return True\n max_divisor = int(n**0.5) + 1\n for d in range(3, max_divisor, 2):\n if n % d == 0:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n: int) -> bool:\n \"\"\"\n Returns True if the number is not prime, False otherwise.\n\n Args:\n n (int): The number to check.\n\n Returns:\n bool: Whether the number is not prime.\n \"\"\"\n\n # Check for numbers less than 2\n if n < 2:\n return True\n\n # Check from 2 to the square root of n\n # because a larger factor of n must be a multiple of a smaller factor that has already been checked\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return True\n\n return False", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(n):\n \"\"\"\n This function checks if a given number is not a prime number.\n\n Args:\n n (int): The number to check.\n\n Returns:\n bool: True if the number is not prime, False otherwise.\n \"\"\"\n if n < 2:\n return True # Numbers less than 2 are not prime\n for i in range(2, int(n ** 0.5) + 1):\n if n % i == 0:\n return True # Found a divisor, so the number is not prime\n return False # No divisors found, the number is prime", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(n):\n \"\"\"\n Check if a number is not prime.\n\n Args:\n n (int): Number to check.\n\n Returns:\n bool: True if the number is not prime, False otherwise.\n\n Raises:\n TypeError: If the input is not an integer.\n \"\"\"\n if not isinstance(n, int):\n raise TypeError(\"Input must be an integer.\")\n if n < 2:\n return True\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return True\n return False", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(n):\n \"\"\"\n Checks if a number is not prime.\n \n Args:\n n (int): The number to check.\n \n Returns:\n bool: True if the number is not prime, False otherwise.\n \"\"\"\n if n < 2:\n return True\n for i in range(2, int(n ** 0.5) + 1):\n if n % i == 0:\n return True\n return False", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(n):\n \"\"\"\n Check if a number is not prime.\n\n Args:\n n (int): The number to check.\n\n Returns:\n bool: True if the number is not prime, False otherwise.\n \"\"\"\n if n < 2:\n return True # Numbers less than 2 are not prime\n for i in range(2, int(n ** 0.5) + 1):\n if n % i == 0:\n return True # If the number has a divisor other than 1 and itself, it's not prime\n return False # The number is prime", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(n):\n \"\"\"\n Returns True if a number is not prime, False otherwise.\n\n :param n: An integer number to be checked for primality.\n :return: A boolean indicating whether the number is not prime.\n \"\"\"\n if n < 2: # Numbers less than 2 are not prime\n return True\n for i in range(2, int(n**0.5) + 1): # Only need to check up to sqrt(n)\n if n % i == 0: # If n is divisible by i, it's not prime\n return True\n return False # If no divisors found, n is prime", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(n):\n \"\"\"\n Returns True if n is not a prime number, False otherwise.\n \n :param n: The number to check.\n :type n: int\n :return: Whether n is not a prime number.\n :rtype: bool\n \"\"\"\n if n < 2:\n return True # Numbers less than 2 are not prime.\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return True # If divisible, then not a prime number.\n return False # If no divisors found, then a prime number.", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(n):\n \"\"\"\n Identify non-prime numbers.\n\n Args:\n n (int): The number to check.\n\n Returns:\n bool: True if the number is not prime, False otherwise.\n \"\"\"\n if n < 2:\n # Numbers less than 2 are not prime\n return True\n\n # Check from 2 to the square root of n\n # because a larger factor of the number\n # would be a multiple of a smaller factor that has already been checked.\n for i in range(2, int(n ** 0.5) + 1):\n if n % i == 0:\n # If n is divisible by any number, it's not prime\n return True\n\n # If n is not divisible by any number, it's prime\n return False", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(n: int) -> bool:\n \"\"\"\n Checks if a given number is not prime.\n \n A prime number is a natural number greater than 1 that has no positive divisors other than 1 and itself.\n\n Args:\n n (int): The number to check.\n\n Returns:\n bool: True if the number is not prime, False otherwise.\n \"\"\"\n if n < 2: # Numbers less than 2 are not prime\n return True\n\n # Check if the number has any divisors other than 1 and itself\n for i in range(2, int(n ** 0.5) + 1):\n if n % i == 0:\n return True\n\n return False", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(n):\n \"\"\"\n Identifies if a number is not prime.\n\n Args:\n n (int): The number to check for primality.\n\n Returns:\n bool: True if the number is not prime, False otherwise.\n \"\"\"\n if n < 2:\n return True\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return True\n return False", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(n):\n \"\"\"\n Checks if a number is not prime.\n\n Args:\n n (int): The number to check.\n\n Returns:\n bool: True if the number is not prime, False otherwise.\n \"\"\"\n if n < 2: # numbers less than 2 are not prime\n return True\n for i in range(2, int(n**0.5) + 1): # only need to check up to the square root of n\n if n % i == 0: # if n is divisible by i, it's not prime\n return True\n return False", "matching_cluster_idx": 4}, {"solution": "def is_not_prime(n):\n \"\"\"\n Returns True if the number is not prime, False otherwise.\n\n Args:\n n (int): The number to check.\n\n Returns:\n bool: Whether the number is not prime.\n \"\"\"\n if n < 2:\n return True\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return True\n return False", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(n):\n \"\"\"\n Checks if a number is not prime.\n\n Args:\n n (int): The number to check.\n\n Returns:\n bool: True if the number is not prime, False otherwise.\n \"\"\"\n if n < 2:\n return True\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return True\n return False", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(n):\n \"\"\"\n Checks if a number is not prime.\n\n Args:\n n (int): The number to check.\n\n Returns:\n bool: True if the number is not prime, False otherwise.\n \"\"\"\n if n < 2:\n return True # Numbers less than 2 are not prime\n\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return True # Found a divisor, the number is not prime\n\n return False # No divisors found, the number is prime", "matching_cluster_idx": 5}]}, "Mbpp/4": {"dps": 95.22184300341297, "dps_norm": 83.33333333333333, "pass@1": 91.0, "profiled": [{"solution": "import heapq\ndef heap_queue_largest(numbers, n):\n \"\"\"\n Find the n largest integers from a given list of numbers, returned in descending order.\n\n Args:\n numbers (list): A list of integers.\n n (int): The number of largest integers to find.\n\n Returns:\n list: A list of the n largest integers in descending order.\n \"\"\"\n # Use heapq.nlargest to find the n largest integers\n return heapq.nlargest(n, numbers)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n \"\"\"\n Return the n largest integers from a given list of numbers, in descending order.\n\n Args:\n nums (list): A list of integers.\n n (int): The number of largest integers to find.\n\n Returns:\n list: The n largest integers in descending order.\n \"\"\"\n # Use the heapq.nlargest function to find the n largest numbers in the list\n return heapq.nlargest(n, nums)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(numbers, n):\n \"\"\"\n Find the n largest integers from a given list of numbers.\n\n Args:\n numbers (list): The list of numbers.\n n (int): The number of largest integers to return.\n\n Returns:\n list: The n largest integers from the list, in descending order.\n\n Example:\n >>> heap_queue_largest([25, 35, 22, 85, 14, 65, 75, 22, 58], 3)\n [85, 75, 65]\n \"\"\"\n return heapq.nlargest(n, numbers)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(numbers, n):\n \"\"\"\n Returns the n largest integers from the given list of numbers in descending order.\n\n :param numbers: A list of numbers\n :param n: The number of largest integers to return\n :return: A list of the n largest integers in descending order\n \"\"\"\n # Use the nlargest function from the heapq module to get the n largest elements\n # The nlargest function returns the n largest elements from the iterable specified by the key function.\n # Here, we use it to get the n largest numbers from the input list.\n largest_numbers = heapq.nlargest(n, numbers)\n \n # The nlargest function returns the numbers in descending order, so no further sorting is required\n return largest_numbers", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(numbers, n):\n \"\"\"\n Find the n largest integers from a given list of numbers, returned in descending order.\n\n Args:\n numbers (list): A list of integers.\n n (int): The number of largest integers to find.\n\n Returns:\n list: A list of the n largest integers in descending order.\n \"\"\"\n # Use the heapq.nlargest function to find the n largest numbers\n largest_numbers = heapq.nlargest(n, numbers)\n \n # Return the largest numbers in descending order\n return largest_numbers\nnumbers = [25, 35, 22, 85, 14, 65, 75, 22, 58]\nn = 3", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n \"\"\"\n Find the n largest integers from a given list of numbers.\n\n Args:\n - nums (list): A list of numbers.\n - n (int): The number of largest integers to find.\n\n Returns:\n - list: The n largest integers in descending order.\n \"\"\"\n return heapq.nlargest(n, nums)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(numbers, n):\n \"\"\"\n Returns the n largest integers from the given list of numbers in descending order.\n\n Args:\n numbers (list): The list of numbers to find the largest from.\n n (int): The number of largest numbers to find.\n\n Returns:\n list: The n largest numbers from the list, in descending order.\n \"\"\"\n\n # Check if n is not greater than the length of numbers list\n n = min(n, len(numbers))\n\n # Use heapq.nlargest to get the n largest numbers from the list\n largest_numbers = heapq.nlargest(n, numbers)\n\n # Return the n largest numbers in descending order\n return largest_numbers", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(numbers, n):\n \"\"\"\n Find the n largest integers from a given list of numbers, returned in descending order.\n\n Args:\n numbers (list): A list of integers.\n n (int): The number of largest integers to find.\n\n Returns:\n list: The n largest integers from the input list, in descending order.\n\n Raises:\n ValueError: If n is larger than the length of the input list.\n\n \"\"\"\n if n > len(numbers):\n raise ValueError(\"n cannot be larger than the length of the input list\")\n # Use heapq.nlargest to find the n largest integers\n return heapq.nlargest(n, numbers)\nnumbers = [25, 35, 22, 85, 14, 65, 75, 22, 58]\nn = 3", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n \"\"\"\n Find the n largest integers from a given list of numbers.\n\n Args:\n - nums (list): A list of integers.\n - n (int): The number of largest integers to find.\n\n Returns:\n - list: A list of the n largest integers in descending order.\n \"\"\"\n # Use the heapq.nlargest function to find the n largest elements\n largest_nums = heapq.nlargest(n, nums)\n \n return largest_nums", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(numbers, n):\n \"\"\"\n Find the n largest integers from a given list of numbers, returned in descending order.\n\n Args:\n numbers (list): A list of integers.\n n (int): The number of largest integers to find.\n\n Returns:\n list: A list of the n largest integers in descending order.\n \"\"\"\n return sorted(heapq.nlargest(n, numbers), reverse=True)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(numbers, n):\n \"\"\"\n Returns the n largest integers from a list of numbers, in descending order.\n\n :param numbers: List of integers\n :param n: Number of largest integers to return\n :return: List of n largest integers in descending order\n \"\"\"\n # Use heapq.nlargest to get the n largest numbers from the list\n largest_numbers = heapq.nlargest(n, numbers)\n # Return the numbers in descending order\n return largest_numbers", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(numbers, n):\n \"\"\"\n Return the n largest integers from a given list of numbers in descending order.\n\n Args:\n numbers (list): A list of integers.\n n (int): The number of largest integers to return.\n\n Returns:\n list: The n largest integers in descending order.\n \"\"\"\n return sorted(heapq.nlargest(n, numbers), reverse=True)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n \"\"\"\n Returns the n largest integers from a given list of numbers in descending order.\n\n :param nums: A list of integers\n :param n: The number of largest integers to return\n :return: A list of the n largest integers in descending order\n \"\"\"\n # Check if n is not greater than the number of elements in the list\n if n > len(nums):\n raise ValueError(\"n cannot be greater than the number of elements in the list\")\n\n # Use heapq.nlargest to get the n largest numbers\n largest_nums = heapq.nlargest(n, nums)\n\n # Return the largest numbers in descending order\n return largest_nums", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(numbers, n):\n \"\"\"\n This function finds the n largest integers from a given list of numbers, returned in descending order.\n \n Parameters:\n numbers (list): A list of numbers\n n (int): Number of largest integers to return\n \n Returns:\n list: A list of the n largest integers in descending order\n \"\"\"\n \n # Use heapq.nlargest to find the n largest elements\n largest_numbers = heapq.nlargest(n, numbers)\n \n # Return the largest numbers in descending order\n return largest_numbers", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(numbers, n):\n \"\"\"\n Find the n largest integers from a given list of numbers.\n\n Args:\n - numbers (list): A list of integers\n - n (int): The number of largest integers to return\n\n Returns:\n - list: The n largest integers in descending order\n \"\"\"\n # Use heapq.nlargest to find the n largest numbers\n largest_numbers = heapq.nlargest(n, numbers)\n \n # Return the largest numbers in descending order\n return largest_numbers\nnumbers = [25, 35, 22, 85, 14, 65, 75, 22, 58]\nn = 3", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(numbers, n):\n \"\"\"\n Returns the n largest integers from a list of numbers in descending order.\n \n Args:\n numbers (list): A list of numbers.\n n (int): The number of largest integers to return.\n \n Returns:\n list: A list of the n largest integers in descending order.\n \"\"\"\n # Use heapq.nlargest to get the n largest numbers from the list\n return heapq.nlargest(n, numbers)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n \"\"\"\n Returns the n largest integers from a given list of numbers in descending order.\n\n Args:\n nums (list): A list of integers.\n n (int): The number of largest integers to return.\n\n Returns:\n list: The n largest integers in descending order.\n \"\"\"\n return sorted(heapq.nlargest(n, nums), reverse=True)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(numbers, n):\n \"\"\"\n Find the n largest integers from a given list of numbers, returned in descending order.\n\n Args:\n numbers (list): A list of integers\n n (int): Number of largest integers to return\n\n Returns:\n list: The n largest integers in descending order\n \"\"\"\n return heapq.nlargest(n, numbers)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n \"\"\"\n Find the n largest integers from a given list of numbers, returned in descending order.\n\n Args:\n nums (list): A list of integers.\n n (int): The number of largest integers to find.\n\n Returns:\n list: A list of the n largest integers in descending order.\n \"\"\"\n # Create a min heap to keep track of the n largest numbers\n min_heap = []\n\n # Iterate through the list of numbers\n for num in nums:\n # If the heap has less than n numbers, push the number onto the heap\n if len(min_heap) < n:\n heapq.heappush(min_heap, num)\n # If the heap has n numbers and the current number is greater than the smallest number in the heap,\n # pop the smallest number and push the current number onto the heap\n elif num > min_heap[0]:\n heapq.heappop(min_heap)\n heapq.heappush(min_heap, num)\n\n # Sort the numbers in the heap in descending order and return\n return sorted(min_heap, reverse=True)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(numbers, n):\n \"\"\"\n Returns the n largest integers from a given list of numbers in descending order.\n\n Args:\n numbers (list): A list of integers\n n (int): The number of largest integers to return\n\n Returns:\n list: The n largest integers in descending order\n \"\"\"\n return heapq.nlargest(n, numbers)", "matching_cluster_idx": 9}]}, "Mbpp/9": {"dps": 66.97278911564625, "dps_norm": 56.5, "pass@1": 65.0, "profiled": [{"solution": "def find_Rotations(s: str) -> int:\n \"\"\"\n This function finds the minimum number of rotations (greater than 0) required to get the same string.\n \n Args:\n s (str): The input string.\n \n Returns:\n int: The minimum number of rotations required.\n \"\"\"\n if len(set(s)) == 1: # If all characters in the string are the same\n return 1\n length = len(s)\n for i in range(1, length): # Iterate from 1 to length of the string\n if s[i:] + s[:i] == s: # Check if rotation of string equals to original string\n return i\n return length # If no rotation is found other than the full rotation", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(s):\n \"\"\"\n Find the minimum number of rotations (greater than 0) required to get the same string.\n\n Args:\n s (str): The input string.\n\n Returns:\n int: The minimum number of rotations required.\n \"\"\"\n if len(s) == 0:\n return 0\n\n for i in range(1, len(s)):\n if s[i:] + s[:i] == s:\n return i\n\n # If no rotation is found, the string is already the same, so return the length of the string\n return len(s)", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(s: str) -> int:\n \"\"\"\n This function calculates the minimum number of rotations (greater than 0) required to get the same string.\n \n Parameters:\n s (str): The input string.\n \n Returns:\n int: The minimum number of rotations required.\n \"\"\"\n \n # Handle edge cases\n if not s: # If the string is empty\n return 0\n \n # Find the length of the string\n n = len(s)\n \n # Concatenate the string with itself\n double_s = s + s\n \n # Check for the minimum number of rotations\n for i in range(1, n):\n # If the substring of double_s from index i to i + n is equal to s\n if double_s[i:i+n] == s:\n # Return the number of rotations\n return i\n \n # If the string has no repeated pattern, return the length of the string\n return n", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(s):\n \"\"\"\n This function finds the minimum number of rotations (greater than 0) required to get the same string.\n \n Args:\n s (str): The input string.\n \n Returns:\n int: The minimum number of rotations required.\n \"\"\"\n # If the string is empty, no rotations are needed\n if len(s) == 0:\n return 0\n \n # Concatenate the string with itself\n concatenated = s + s\n \n # Find the minimum rotation by iterating through the concatenated string\n for i in range(1, len(s)):\n # Check if the substring is equal to the original string\n if concatenated[i:i+len(s)] == s:\n return i\n \n # If no rotation is found, return the length of the string (full rotation)\n return len(s)", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(s):\n \"\"\"\n This function finds the minimum number of rotations required to get the same string.\n\n Args:\n s (str): The input string.\n\n Returns:\n int: The minimum number of rotations required.\n\n Raises:\n ValueError: If the input string is empty.\n \"\"\"\n if not s:\n raise ValueError(\"Input string cannot be empty\")\n\n # Find the length of the string\n n = len(s)\n\n # Check for all possible rotations\n for i in range(1, n):\n # Rotate the string by i places\n rotated_s = s[i:] + s[:i]\n\n # Check if the rotated string is the same as the original string\n if rotated_s == s:\n return i\n\n # If no rotation is found, return the length of the string (since a full rotation would result in the same string)\n return n", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(s):\n \"\"\"\n This function calculates the minimum number of rotations required to get the same string.\n\n Args:\n s (str): Input string.\n\n Returns:\n int: Minimum number of rotations required.\n\n \"\"\"\n # Check for empty string\n if len(s) == 0:\n raise ValueError(\"Input string cannot be empty\")\n\n # Find the length of the string\n n = len(s)\n \n # If string is not same when rotated by 1, then it will not be same in less than n rotations\n # So, in that case, n is the minimum number of rotations\n if s != s[1:] + s[0]:\n return n\n \n # Find the minimum number of rotations\n for i in range(1, n):\n # If string is same when rotated by i\n if s == s[i:] + s[:i]:\n return i\n\n # If the string does not change when rotated by any number less than its length\n # then the minimum number of rotations required will be equal to its length\n return n", "matching_cluster_idx": 9}, {"solution": "def find_Rotations(s):\n \"\"\"\n This function calculates the minimum number of rotations (greater than 0) required to get the same string.\n\n Args:\n s (str): The input string.\n\n Returns:\n int: The minimum number of rotations required.\n\n Raises:\n ValueError: If the input string is empty or None.\n \"\"\"\n\n if not s:\n raise ValueError(\"Input string cannot be empty or None\")\n\n # Concatenate the string with itself\n double_s = s + s\n \n # Initialize the minimum rotation count to the length of the string\n min_rotations = len(s)\n \n # Iterate over the concatenated string (excluding the last character)\n for i in range(1, len(s)):\n # Check if the substring from the current index to the current index plus the length of the string equals the original string\n if double_s[i:i+len(s)] == s:\n # Update the minimum rotation count if a smaller rotation is found\n min_rotations = min(min_rotations, i)\n \n # If the minimum rotation count is equal to the length of the string, no rotation is needed\n if min_rotations == len(s):\n return len(s)\n \n return min_rotations", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(s):\n \"\"\"\n This function calculates the minimum number of rotations required to get the same string.\n \n Args:\n s (str): Input string\n \n Returns:\n int: Minimum number of rotations\n \"\"\"\n if len(s) == 0:\n raise ValueError(\"Input string cannot be empty\")\n \n # Concatenate the string with itself to generate all possible rotations\n doubled_s = s + s\n \n # Iterate through each rotation of the string\n for i in range(1, len(s)):\n # Check if the substring is equal to the original string\n if doubled_s[i:i+len(s)] == s:\n # If it's equal, return the number of rotations (i)\n return i\n \n # If no rotations are found, return the length of the string\n # This would be the case when the string consists of a single repeating character\n return len(s)", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(s: str) -> int:\n \"\"\"\n Finds the minimum number of rotations required to get the same string.\n\n Args:\n s (str): Input string\n\n Returns:\n int: Minimum number of rotations\n \"\"\"\n if len(set(s)) == 1: # If all characters are the same\n return 1\n\n for i in range(1, len(s)): \n # Compare each rotation of the string with the original\n if s[i:] + s[:i] == s:\n return i\n\n # If no rotation matches, return the length of the string\n return len(s)", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(s: str) -> int:\n \"\"\"\n This function finds the minimum number of rotations (greater than 0) required to get the same string.\n\n Args:\n s (str): Input string.\n\n Returns:\n int: Minimum number of rotations required.\n\n Raises:\n ValueError: If input string is empty or has a length of 1.\n \"\"\"\n if len(s) < 2:\n raise ValueError(\"Input string length must be greater than 1.\")\n\n for i in range(1, len(s)):\n if s[i:] + s[:i] == s:\n return i\n\n # If no rotation yields the same string, return the length of the string (full rotation)\n return len(s)", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(s):\n \"\"\"\n This function calculates the minimum number of rotations (greater than 0) required \n to get the same string.\n \n Parameters:\n s (str): The input string.\n \n Returns:\n int: The minimum number of rotations required.\n \"\"\"\n def are_strings_equal(str1, str2):\n return str1 == str2\n\n min_rotations = len(s)\n for i in range(1, len(s)):\n # Create a rotated string\n rotated_s = s[i:] + s[:i]\n \n # Check if the rotated string is equal to the original string\n if are_strings_equal(rotated_s, s):\n min_rotations = min(min_rotations, i)\n\n return min_rotations", "matching_cluster_idx": 3}, {"solution": "def find_Rotations(s):\n \"\"\"\n This function finds the minimum number of rotations required to get the same string.\n \n Args:\n s (str): Input string\n \n Returns:\n int: Minimum number of rotations required. Returns the length of the string if no rotation results in the same string.\n \"\"\"\n length = len(s)\n for i in range(1, length):\n # Check if the string is the same after rotation\n if s[i:] + s[:i] == s:\n return i\n # If no rotation results in the same string, return the length of the string\n return length", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(input_string):\n \"\"\"\n Find the minimum number of rotations required to get the same string.\n\n Args:\n input_string (str): Input string.\n\n Returns:\n int: Minimum number of rotations required.\n\n Raises:\n ValueError: If the input is not a string.\n \"\"\"\n\n # Check if the input is a string\n if not isinstance(input_string, str):\n raise ValueError(\"Input must be a string.\")\n\n # Handle the edge case where the string is empty\n if len(input_string) == 0:\n return 0\n\n # Initialize rotation counter\n rotations = 1\n\n # Slice the string and compare it with the original string\n while True:\n # Check if the rotated string is equal to the original string\n if input_string[rotations:] + input_string[:rotations] == input_string:\n return rotations\n rotations += 1\n\n # Break the loop when the number of rotations is equal to the length of the string\n if rotations > len(input_string):\n return rotations", "matching_cluster_idx": 3}, {"solution": "def find_Rotations(s):\n \"\"\"\n This function calculates the minimum number of rotations required \n to get the same string.\n\n Args:\n s (str): The input string.\n\n Returns:\n int: The minimum number of rotations required.\n\n Raises:\n ValueError: If the input string is empty.\n \"\"\"\n\n # Check for an empty string\n if not s:\n raise ValueError(\"Input string is empty\")\n\n # Find the length of the string\n length = len(s)\n\n # The minimum number of rotations cannot be more than the length of the string\n for i in range(1, length):\n # Check if the string is the same after i rotations\n if s[i:] + s[:i] == s:\n # Return the minimum number of rotations\n return i\n\n # If no rotation is found, return the length of the string\n return length", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(s: str) -> int:\n \"\"\"\n Find the minimum number of rotations (greater than 0) required to get the same string.\n\n Args:\n s (str): The input string.\n\n Returns:\n int: The minimum number of rotations.\n \"\"\"\n # If the string is empty or has only one character, no rotations are needed\n if len(s) < 2:\n return 0\n\n # Concatenate the string with itself\n double_s = s + s\n\n # The minimum number of rotations is the index of the first occurrence of the original string\n # in the concatenated string minus one\n for i in range(1, len(s)):\n if s == double_s[i:i+len(s)]:\n return i\n\n # If no rotations are found, the minimum number of rotations is equal to the length of the string\n return len(s)", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(s):\n \"\"\"\n This function calculates the minimum number of rotations required to get the same string.\n \n Args:\n s (str): Input string\n \n Returns:\n int: Minimum number of rotations required\n \"\"\"\n # Find the length of the string\n length = len(s)\n \n # Initialize the minimum rotations to length (a string is always the same after a full rotation)\n min_rotations = length\n \n # Loop through the string to find a smaller substring that when repeated, forms the original string\n for i in range(1, length // 2 + 1):\n # Check if the length is divisible by the current substring length\n if length % i == 0:\n # Check if the substring repeated forms the original string\n if s[:i] * (length // i) == s:\n # Update the minimum rotations if the current substring length is smaller\n min_rotations = min(min_rotations, i)\n \n # Return the minimum rotations found\n return min_rotations", "matching_cluster_idx": 7}, {"solution": "def find_Rotations(s: str) -> int:\n \"\"\"\n This function finds the minimum number of rotations required to get the same string.\n\n Args:\n s (str): The input string.\n\n Returns:\n int: The minimum number of rotations required to get the same string.\n \"\"\"\n \n # Join the string with itself to create a new string that contains all possible rotations\n double_s = s + s\n \n # Initialize a variable to store the minimum rotations\n min_rotations = len(s)\n \n # Iterate over the double string\n for i in range(len(s)):\n # Check if the substring from the current index to the current index plus the length of the string is equal to the original string\n if double_s[i:i+len(s)] == s:\n # Update the minimum rotations if the current rotation is less than the current minimum\n if i < min_rotations and i != 0:\n min_rotations = i\n \n # Return the minimum rotations\n return min_rotations", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(s: str) -> int:\n \"\"\"\n This function calculates the minimum number of rotations (greater than 0) required to get the same string.\n\n Args:\n s (str): The input string.\n\n Returns:\n int: The minimum number of rotations required.\n \"\"\"\n \n # Handle the case when the string is empty\n if not s:\n raise ValueError(\"Input string cannot be empty.\")\n \n # Calculate the length of the string\n n = len(s)\n \n # If the string has only one character, one rotation is enough\n if n == 1:\n return 1\n \n # Iterate over the range from 1 to n\n for i in range(1, n):\n # Rotate the string by slicing and check if it's the same as the original string\n if s[i:] + s[:i] == s:\n return i\n \n # If no rotation is found, return the length of the string\n # This means the string must be fully rotated to get the same string, which is equivalent to no rotation at all\n return n", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(s):\n \"\"\"\n This function calculates the minimum number of rotations (greater than 0) \n required to get the same string.\n\n Args:\n s (str): The input string.\n\n Returns:\n int: The minimum number of rotations required.\n\n \"\"\"\n if len(s) == 0:\n raise ValueError(\"Input string cannot be empty\")\n\n # Concatenate the string with itself to consider all possible rotations\n ss = s + s\n\n # Find the minimum number of rotations by checking the substring of the \n # concatenated string. If the substring is equal to the original string, \n # it means we have found a rotation of the original string.\n for i in range(1, len(s)):\n if ss[i:i+len(s)] == s:\n return i\n\n # If no rotation is found, return the length of the string (full rotation)\n return len(s)", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(s):\n \"\"\"\n This function calculates the minimum number of rotations required to get the same string.\n\n Args:\n s (str): The input string.\n\n Returns:\n int: The minimum number of rotations required.\n\n Raises:\n TypeError: If the input is not a string.\n \"\"\"\n if not isinstance(s, str):\n raise TypeError(\"Input must be a string\")\n\n if len(s) == 0:\n return 0\n \n for i in range(1, len(s)):\n if s[i:] + s[:i] == s:\n return i\n return len(s)", "matching_cluster_idx": 4}]}, "Mbpp/11": {"dps": 84.58781362007169, "dps_norm": 97.22222222222223, "pass@1": 73.0, "profiled": [{"solution": "def remove_Occ(s, c):\n \"\"\"\n This function removes the first and last occurrence of a given character from the string.\n\n Args:\n s (str): The input string.\n c (str): The character to be removed.\n\n Returns:\n str: The modified string after removing the first and last occurrence of the character.\n \"\"\"\n first_occurrence = s.find(c)\n last_occurrence = s.rfind(c)\n \n if first_occurrence == -1:\n return s # character not found in the string\n elif first_occurrence == last_occurrence:\n return s.replace(c, \"\", 1) # only one occurrence of the character\n \n # replacing the character with empty string at the first occurrence\n new_str = s[:first_occurrence] + s[first_occurrence + 1:]\n \n # if the last occurrence was not the first character in the modified string\n if new_str.rfind(c) != -1:\n # finding the new last occurrence index in the modified string\n new_last_occurrence = new_str.rfind(c)\n # replacing the character at the last occurrence\n new_str = new_str[:new_last_occurrence] + new_str[new_last_occurrence + 1:]\n \n return new_str", "matching_cluster_idx": 7}, {"solution": "def remove_Occ(s, char):\n \"\"\"\n Removes first and last occurrence of a given character from the string.\n \n Parameters:\n s (str): Input string\n char (str): Character to be removed\n \n Returns:\n str: Modified string\n \"\"\"\n # Find index of first and last occurrence of the character\n first_occ = s.find(char)\n last_occ = s.rfind(char)\n\n # Check if the character exists in the string\n if first_occ == -1:\n return s\n \n # Check if the first and last occurrence are same (i.e., only one occurrence)\n if first_occ == last_occ:\n return s.replace(char, '', 1)\n \n # Remove the first and last occurrence\n return s[:first_occ] + s[first_occ+1:last_occ] + s[last_occ+1:]", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(string, char):\n \"\"\"\n Removes the first and last occurrence of a given character from a string.\n\n Parameters:\n string (str): Input string to modify.\n char (str): Character to remove.\n\n Returns:\n str: The modified string with the first and last occurrence of the character removed.\n \"\"\"\n\n # Find the first occurrence index\n first_index = string.find(char)\n\n # Find the last occurrence index\n last_index = string.rfind(char)\n\n # Check if the character is found\n if first_index != -1:\n # Check if there is more than one occurrence of the character\n if first_index != last_index:\n # Return a new string that excludes the first and last occurrence of the character\n return string[:first_index] + string[first_index + 1:last_index] + string[last_index + 1:]\n else:\n # If there's only one occurrence, remove it\n return string[:first_index] + string[first_index + 1:]\n else:\n # Return the original string if the character is not found\n return string", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(s, c):\n \"\"\"\n Removes the first and last occurrence of a given character from the string.\n\n Args:\n s (str): Input string\n c (str): Character to be removed\n\n Returns:\n str: Modified string with first and last occurrence of the character removed\n \"\"\"\n # Find the index of the first occurrence of the character\n first_occ = s.find(c)\n\n # If character not found, return the original string\n if first_occ == -1:\n return s\n\n # Find the index of the last occurrence of the character\n last_occ = s.rfind(c)\n\n # If only one occurrence of the character, remove it\n if first_occ == last_occ:\n return s.replace(c, '', 1)\n \n # Remove the first and last occurrence of the character\n return s[:first_occ] + s[first_occ+1:last_occ] + s[last_occ+1:]", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(s, c):\n \"\"\"\n Removes the first and last occurrence of a given character 'c' from the string 's'.\n\n Args:\n s (str): Input string\n c (str): Character to be removed\n\n Returns:\n str: String with first and last occurrences of 'c' removed\n \"\"\"\n # find index of first occurrence of character 'c'\n first_occurrence_index = s.find(c)\n \n # if 'c' not found in string, return original string\n if first_occurrence_index == -1:\n return s\n \n # find index of last occurrence of character 'c'\n last_occurrence_index = s.rfind(c)\n \n # remove first and last occurrences of 'c'\n result = s[:first_occurrence_index] + s[first_occurrence_index + 1:last_occurrence_index] + s[last_occurrence_index + 1:]\n \n return result", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(s, c):\n \"\"\"\n Removes the first and last occurrence of a given character 'c' from the string 's'.\n \n Parameters:\n s (str): The input string.\n c (str): The character to be removed.\n \n Returns:\n str: The modified string with the first and last occurrence of 'c' removed.\n \"\"\"\n if not isinstance(s, str) or not isinstance(c, str) or len(c) != 1:\n raise ValueError(\"Input string 's' and character 'c' must be a string, and 'c' must be a single character.\")\n\n first_occ = s.find(c)\n last_occ = s.rfind(c)\n\n if first_occ == -1 or first_occ == last_occ:\n # 'c' appears only once or does not appear at all\n return s.replace(c, '', 1)\n else:\n # 'c' appears more than once, remove the first and last occurrence\n return s[:first_occ] + s[first_occ+1:last_occ] + s[last_occ+1:]", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(s, c):\n \"\"\"\n Removes the first and last occurrence of a character from the string.\n\n Args:\n s (str): The input string.\n c (str): The character to be removed.\n\n Returns:\n str: The modified string.\n \"\"\"\n first_occurrence = s.find(c)\n last_occurrence = s.rfind(c)\n\n # Check if the character exists in the string\n if first_occurrence != -1:\n # If the character appears only once, remove it\n if first_occurrence == last_occurrence:\n return s.replace(c, '', 1)\n # If the character appears multiple times, remove the first and last occurrences\n else:\n return s[:first_occurrence] + s[first_occurrence+1:last_occurrence] + s[last_occurrence+1:]\n else:\n # If the character does not exist, return the original string\n return s", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(input_str, char):\n \"\"\"\n Removes the first and last occurrence of a given character from the input string.\n\n Args:\n input_str (str): The original string from which the character is to be removed.\n char (str): The character to be removed.\n\n Returns:\n str: The string with the first and last occurrence of the given character removed.\n \"\"\"\n\n # Find the first and last index of the character in the string\n first_occurrence = input_str.find(char)\n last_occurrence = input_str.rfind(char)\n\n # If the character is not found in the string, return the original string\n if first_occurrence == -1:\n return input_str\n\n # If the first and last occurrence is the same, remove only one occurrence\n if first_occurrence == last_occurrence:\n return input_str.replace(char, '', 1)\n else:\n # Remove the first occurrence\n input_str = input_str[:first_occurrence] + input_str[first_occurrence + 1:]\n \n # Remove the last occurrence\n last_occurrence -= 1 # Adjust index after removing the first occurrence\n input_str = input_str[:last_occurrence] + input_str[last_occurrence + 1:]\n \n return input_str", "matching_cluster_idx": 7}, {"solution": "def remove_Occ(input_str, char):\n \"\"\"\n Removes the first and last occurrence of a given character from the string.\n \n Parameters:\n input_str (str): Input string.\n char (str): Character to be removed.\n \n Returns:\n str: Modified string with first and last occurrence of the character removed.\n \"\"\"\n if char not in input_str:\n return input_str\n \n first_occurrence = input_str.find(char)\n last_occurrence = input_str.rfind(char)\n \n if first_occurrence == last_occurrence:\n return input_str.replace(char, \"\", 1)\n \n return input_str[:first_occurrence] + input_str[first_occurrence + 1:last_occurrence] + input_str[last_occurrence + 1:]", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(input_str, char):\n \"\"\"\n Removes the first and last occurrence of a given character from the input string.\n\n Args:\n input_str (str): The input string to be modified.\n char (str): The character to be removed.\n\n Returns:\n str: The modified string with the first and last occurrence of the character removed.\n \"\"\"\n first_occ = input_str.find(char)\n last_occ = input_str.rfind(char)\n\n if first_occ != -1 and last_occ != -1:\n # check if first and last occurrence are the same, return without the character\n if first_occ == last_occ:\n return input_str.replace(char, '', 1)\n else:\n # return the modified string\n return input_str[:first_occ] + input_str[first_occ+1:last_occ] + input_str[last_occ+1:]\n else:\n return input_str", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(s, c):\n \"\"\"\n Removes the first and last occurrence of a given character from the string.\n\n Args:\n s (str): The input string.\n c (str): The character to be removed.\n\n Returns:\n str: The modified string with first and last occurrence of the given character removed.\n \"\"\"\n first_occurrence = s.find(c)\n last_occurrence = s.rfind(c)\n \n if first_occurrence == -1:\n # if the character is not found in the string\n return s\n \n if first_occurrence == last_occurrence:\n # if there is only one occurrence of the character in the string\n return s.replace(c, '', 1)\n \n return s[:first_occurrence] + s[first_occurrence + 1:last_occurrence] + s[last_occurrence + 1:]", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(s, c):\n \"\"\"\n Removes the first and last occurrence of a given character from the string.\n\n Args:\n s (str): Input string.\n c (str): Character to be removed.\n\n Returns:\n str: The modified string.\n \"\"\"\n # Check if the character exists in the string\n if c not in s:\n return s\n \n # Find the first occurrence index\n first_occ = s.find(c)\n \n # Find the last occurrence index\n last_occ = s.rfind(c)\n \n # Check if the first and last occurrence is the same\n if first_occ == last_occ:\n # If so, remove only that occurrence\n return s.replace(c, '', 1)\n else:\n # Otherwise, remove the first and last occurrence separately\n return s[:first_occ] + s[first_occ + 1:last_occ] + s[last_occ + 1:]", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(s, char):\n \"\"\"\n Removes the first and last occurrences of a given character from the string.\n\n Args:\n s (str): The input string.\n char (str): The character to be removed.\n\n Returns:\n str: The modified string after removing the first and last occurrences of the character.\n \"\"\"\n if not isinstance(s, str) or not isinstance(char, str) or len(char) != 1:\n raise ValueError(\"Input string and character must be strings, character must be single.\")\n\n # Find the index of the first occurrence of the character\n first_occurrence = s.find(char)\n\n # If the character is not found in the string, return the original string\n if first_occurrence == -1:\n return s\n\n # Find the index of the last occurrence of the character\n last_occurrence = s.rfind(char)\n\n # If the first and last occurrences are the same (i.e., there's only one occurrence)\n if first_occurrence == last_occurrence:\n return s.replace(char, '', 1)\n\n # If there are multiple occurrences, remove the first and last occurrences\n else:\n # Remove the first occurrence\n s_without_first_occurrence = s[:first_occurrence] + s[first_occurrence + 1:]\n\n # Remove the last occurrence from the modified string\n s_without_last_occurrence = s_without_first_occurrence[:s_without_first_occurrence.rfind(char)] + \\\n s_without_first_occurrence[s_without_first_occurrence.rfind(char) + 1:]\n\n return s_without_last_occurrence", "matching_cluster_idx": 6}, {"solution": "def remove_Occ(s, char):\n \"\"\"\n This function removes the first and last occurrence of a given character from a string.\n\n Args:\n s (str): Input string.\n char (str): Character to be removed.\n\n Returns:\n str: Modified string after removal of first and last occurrence of the given character.\n \"\"\"\n first_occurrence_index = s.find(char)\n last_occurrence_index = s.rfind(char)\n \n # Return the original string if the character is not found\n if first_occurrence_index == -1:\n return s\n \n # Return the string after removing the first occurrence of the character\n s = s[:first_occurrence_index] + s[first_occurrence_index + 1:]\n \n # Find the new last occurrence index after removing the first occurrence\n new_last_occurrence_index = s.rfind(char)\n \n # If the last occurrence index is not -1, remove the last occurrence\n if new_last_occurrence_index != -1:\n s = s[:new_last_occurrence_index] + s[new_last_occurrence_index + 1:]\n \n return s", "matching_cluster_idx": 7}, {"solution": "def remove_Occ(s, c):\n \"\"\"\n Removes the first and last occurrence of a given character from a string.\n\n Parameters:\n s (str): Input string.\n c (str): Character to be removed.\n\n Returns:\n str: Modified string after removing first and last occurrence of the given character.\n \"\"\"\n if len(c) != 1:\n raise ValueError(\"Character must be a single character.\")\n\n if c not in s:\n return s # Return original string if character not found\n\n first_occ = s.find(c)\n last_occ = s.rfind(c)\n\n if first_occ == last_occ: # If only one occurrence, remove it\n return s.replace(c, '', 1)\n\n return s[:first_occ] + s[first_occ + 1:last_occ] + s[last_occ + 1:]", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(s, c):\n \"\"\"\n Removes the first and last occurrence of a given character from the string.\n\n Args:\n s (str): Input string.\n c (str): Character to remove.\n\n Returns:\n str: String with first and last occurrence of character removed.\n \"\"\"\n first_occ = s.find(c)\n last_occ = s.rfind(c)\n \n # Check if the character is found in the string\n if first_occ != -1 and last_occ != -1:\n # Slice the string to exclude the first and last occurrence of the character\n if first_occ == last_occ: # If only one occurrence is found\n return s[:first_occ] + s[first_occ+1:]\n else: # If multiple occurrences are found\n return s[:first_occ] + s[first_occ+1:last_occ] + s[last_occ+1:]\n else:\n return s # Return the original string if the character is not found", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(s, char):\n \"\"\"\n This function removes the first and last occurrence of a given character from a string.\n\n Parameters:\n s (str): The input string.\n char (str): The character to be removed.\n\n Returns:\n str: The modified string with the first and last occurrence of char removed.\n \"\"\"\n # Find the first occurrence of char\n first_occurrence = s.find(char)\n \n # If char is not found, return the original string\n if first_occurrence == -1:\n return s\n \n # Find the last occurrence of char\n last_occurrence = s.rfind(char)\n \n # If char occurs only once, remove it\n if first_occurrence == last_occurrence:\n return s[:first_occurrence] + s[first_occurrence + 1:]\n \n # If char occurs more than once, remove the first and last occurrence\n else:\n return s[:first_occurrence] + s[first_occurrence + 1:last_occurrence] + s[last_occurrence + 1:]", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(s, c):\n \"\"\"\n Removes the first and last occurrence of a character from a string.\n\n Parameters:\n s (str): The original string.\n c (str): The character to be removed.\n\n Returns:\n str: The modified string with the first and last occurrence of the character removed.\n \"\"\"\n first_occ = s.find(c)\n last_occ = s.rfind(c)\n \n if first_occ != -1 and last_occ != -1:\n if first_occ == last_occ:\n # only one occurrence of the character exists\n return s[:first_occ] + s[first_occ+1:]\n else:\n # remove the first and last occurrence of the character\n return s[:first_occ] + s[first_occ+1:last_occ] + s[last_occ+1:]\n else:\n # character not found\n return s", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(s, c):\n \"\"\"\n Removes the first and last occurrence of a given character from the string.\n \n Args:\n s (str): The input string.\n c (str): The character to be removed.\n\n Returns:\n str: The modified string with the first and last occurrence of the character removed.\n \"\"\"\n # Find the index of the first occurrence\n first_occurrence = s.find(c)\n \n # If the character is not found in the string, return the string as is\n if first_occurrence == -1:\n return s\n \n # Find the index of the last occurrence\n last_occurrence = s.rfind(c)\n \n # Remove the first and last occurrence\n if first_occurrence == last_occurrence:\n return s.replace(c, '', 1)\n else:\n return s[:first_occurrence] + s[first_occurrence + 1:last_occurrence] + s[last_occurrence + 1:]", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(input_str, char):\n \"\"\"\n Removes the first and last occurrences of a given character from a string.\n\n Args:\n input_str (str): The input string.\n char (str): The character to be removed.\n\n Returns:\n str: The string with the first and last occurrences of the given character removed.\n \"\"\"\n # Find the index of the first occurrence of the character\n first_occ = input_str.find(char)\n # If the character is not found, return the original string\n if first_occ == -1:\n return input_str\n \n # Find the index of the last occurrence of the character\n last_occ = input_str.rfind(char)\n \n # Remove the first and last occurrences of the character\n if first_occ == last_occ:\n return input_str.replace(char, '', 1)\n else:\n return input_str[:first_occ] + input_str[first_occ+1:last_occ] + input_str[last_occ+1:]", "matching_cluster_idx": 8}]}, "Mbpp/12": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def sort_matrix(matrix):\n \"\"\"\n This function sorts a given matrix in ascending order according to the sum of its rows.\n\n Args:\n matrix (list): A 2D list of integers.\n\n Returns:\n list: The input matrix sorted in ascending order according to the sum of its rows.\n \"\"\"\n # Calculate the sum of each row and store it as a tuple with the original row\n rows_with_sum = [(sum(row), row) for row in matrix]\n \n # Sort the rows based on the sum\n sorted_rows_with_sum = sorted(rows_with_sum, key=lambda x: x[0])\n \n # Return the sorted rows, excluding the sum\n return [row for _, row in sorted_rows_with_sum]", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"\n This function sorts a given matrix in ascending order according to the sum of its rows.\n\n Args:\n matrix (list of lists): Input matrix\n\n Returns:\n list of lists: Sorted matrix\n \"\"\"\n # Use the sorted function to sort the matrix rows based on their sums\n return sorted(matrix, key=sum)", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"\n Sorts a given matrix in ascending order according to the sum of its rows.\n\n Args:\n matrix (list): A 2D list of integers.\n\n Returns:\n list: The input matrix sorted by row sum in ascending order.\n \"\"\"\n # Use the sorted function with a custom key that calculates the sum of each row\n return sorted(matrix, key=sum)", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"\n Sorts a given matrix in ascending order according to the sum of its rows.\n\n Args:\n matrix (list): A 2D list of integers.\n\n Returns:\n list: The input matrix sorted in ascending order according to the sum of its rows.\n \"\"\"\n # Check if input matrix is empty\n if not matrix:\n return matrix\n\n # Use Python's built-in sorted function with a custom sorting key\n # The key function calculates the sum of each row\n return sorted(matrix, key=sum)", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"\n Sort a given matrix in ascending order according to the sum of its rows.\n\n Args:\n matrix (list): A 2D list representing the matrix.\n\n Returns:\n list: The input matrix sorted by the sum of its rows.\n \"\"\"\n # Calculate the sum of each row and store it along with the row\n rows_with_sum = [(sum(row), row) for row in matrix]\n \n # Sort the rows based on their sums\n sorted_rows_with_sum = sorted(rows_with_sum, key=lambda x: x[0])\n \n # Return the sorted rows without the sums\n return [row for _, row in sorted_rows_with_sum]\nmatrix = [[1, 2, 3], [2, 4, 5], [1, 1, 1]]", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"\n Sorts a given matrix in ascending order according to the sum of its rows.\n\n Args:\n matrix (list of lists): The input matrix.\n\n Returns:\n list of lists: The matrix sorted by row sums in ascending order.\n \"\"\"\n return sorted(matrix, key=sum)", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"\n This function sorts a given matrix in ascending order according to the sum of its rows.\n\n Args:\n matrix (list): A 2D list of integers.\n\n Returns:\n list: A sorted 2D list according to the sum of rows in ascending order.\n\n Example:\n >>> sort_matrix([[1, 2, 3], [2, 4, 5], [1, 1, 1]])\n [[1, 1, 1], [1, 2, 3], [2, 4, 5]]\n \"\"\"\n\n # Calculate the sum of each row in the matrix\n row_sums = [sum(row) for row in matrix]\n \n # Combine the matrix rows with their sums and sort them\n sorted_rows = sorted(zip(matrix, row_sums), key=lambda x: x[1])\n \n # Extract and return the sorted matrix\n return [row[0] for row in sorted_rows]", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"\n This function sorts a given matrix in ascending order according to the sum of its rows.\n\n Args:\n matrix (list of lists): A 2D list where each inner list represents a row in the matrix.\n\n Returns:\n list of lists: The input matrix sorted in ascending order by row sum.\n\n Example:\n >>> sort_matrix([[1, 2, 3], [2, 4, 5], [1, 1, 1]])\n [[1, 1, 1], [1, 2, 3], [2, 4, 5]]\n \"\"\"\n # Use built-in sorted function and provide a custom sorting key as a lambda function\n # The lambda function calculates the sum of each row\n sorted_matrix = sorted(matrix, key=lambda row: sum(row))\n \n return sorted_matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"\n Sorts a given matrix in ascending order according to the sum of its rows.\n\n Args:\n matrix (list): A 2D list of integers.\n\n Returns:\n list: A 2D list of integers, sorted by the sum of its rows.\n \"\"\"\n # Use the built-in sorted function with a custom key to sort the matrix rows\n # The key function calculates the sum of each row\n return sorted(matrix, key=sum)\nmatrix = [[1, 2, 3], [2, 4, 5], [1, 1, 1]]", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"\n Sorts a given matrix in ascending order according to the sum of its rows.\n\n Args:\n matrix (list of lists): The matrix to be sorted.\n\n Returns:\n list of lists: The sorted matrix.\n\n Example:\n >>> sort_matrix([[1, 2, 3], [2, 4, 5], [1, 1, 1]])\n [[1, 1, 1], [1, 2, 3], [2, 4, 5]]\n \"\"\"\n # Use the sorted function with a custom key function to sort the matrix rows\n # The key function calculates the sum of each row\n sorted_matrix = sorted(matrix, key=sum)\n \n return sorted_matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"\n Sort a given matrix in ascending order according to the sum of its rows.\n\n Args:\n matrix (list of lists): The input matrix.\n\n Returns:\n list of lists: The input matrix sorted by the sum of its rows.\n \"\"\"\n # Use the built-in sorted function with a custom key that calculates the sum of each row\n return sorted(matrix, key=sum)", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"\n This function sorts a given matrix in ascending order according to the sum of its rows.\n \n Args:\n matrix (list): A 2D list of integers.\n \n Returns:\n list: The sorted matrix.\n \"\"\"\n # First, we calculate the sum of each row in the matrix\n row_sums = [sum(row) for row in matrix]\n \n # Then, we sort the matrix based on these sums\n sorted_matrix = [row for _, row in sorted(zip(row_sums, matrix))]\n \n return sorted_matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"\n Sorts a given matrix in ascending order according to the sum of its rows.\n \n Args:\n matrix (list): A list of lists representing the matrix.\n \n Returns:\n list: The sorted matrix.\n \"\"\"\n return sorted(matrix, key=sum)", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"\n Sorts a given matrix in ascending order according to the sum of its rows.\n\n Args:\n matrix (list of lists): A 2D list of integers.\n\n Returns:\n list of lists: The input matrix sorted by row sum in ascending order.\n \"\"\"\n return sorted(matrix, key=sum)", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"\n Sorts the given matrix in ascending order according to the sum of its rows.\n\n Args:\n matrix (list of lists): Input matrix.\n\n Returns:\n list of lists: Sorted matrix.\n \"\"\"\n # Calculate the sum of each row in the matrix\n row_sums = [sum(row) for row in matrix]\n\n # Combine the matrix rows with their sums into a list of tuples\n rows_with_sums = list(zip(matrix, row_sums))\n\n # Sort the combined list based on the row sums\n sorted_rows_with_sums = sorted(rows_with_sums, key=lambda x: x[1])\n\n # Extract the sorted matrix rows from the sorted list of tuples\n sorted_matrix = [row for row, _ in sorted_rows_with_sums]\n\n return sorted_matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"\n Sorts a given matrix in ascending order according to the sum of its rows.\n \n Args:\n matrix (list): A 2D list representing the matrix.\n \n Returns:\n list: A sorted 2D list representing the matrix.\n \"\"\"\n \n # Check if the input is a list and all sublists are of the same length\n if not all(len(row) == len(matrix[0]) for row in matrix):\n raise ValueError(\"All rows in the matrix must be of the same length\")\n \n # Use the sorted function with a custom key to sort the matrix\n # The key is a function that returns the sum of a row\n sorted_matrix = sorted(matrix, key=sum)\n \n return sorted_matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"\n Sorts a given matrix in ascending order according to the sum of its rows.\n\n Args:\n matrix (list): A 2D list of integers.\n\n Returns:\n list: The input matrix sorted in ascending order by the sum of its rows.\n\n \"\"\"\n # Calculate the sum of each row in the matrix\n row_sums = [sum(row) for row in matrix]\n \n # Combine the matrix rows with their sums into a list of tuples\n row_sum_pairs = list(zip(matrix, row_sums))\n \n # Sort the list of tuples based on the row sums\n sorted_pairs = sorted(row_sum_pairs, key=lambda x: x[1])\n \n # Separate the sorted matrix rows from their sums and return\n return [row for row, _ in sorted_pairs]", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"\n Sorts a given matrix in ascending order according to the sum of its rows.\n \n Args:\n matrix (list of lists): A 2D list of integers representing the matrix.\n \n Returns:\n list of lists: The sorted matrix.\n \"\"\"\n # Use the built-in sorted function to sort the rows of the matrix\n # The sorted function takes a key function as an argument, which it uses to determine the sort order\n # Here, the key function is a lambda function that returns the sum of a row\n # This causes the rows to be sorted based on their sums\n return sorted(matrix, key=lambda row: sum(row))\nmatrix = [[1, 2, 3], [2, 4, 5], [1, 1, 1]]", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"\n Sorts a given matrix in ascending order according to the sum of its rows.\n\n Args:\n matrix (list of lists): Input matrix to be sorted.\n\n Returns:\n list of lists: Sorted matrix.\n\n Example:\n >>> sort_matrix([[1, 2, 3], [2, 4, 5], [1, 1, 1]])\n [[1, 1, 1], [1, 2, 3], [2, 4, 5]]\n \"\"\"\n # Calculate the sum of each row\n row_sums = [sum(row) for row in matrix]\n \n # Combine each row with its sum\n rows_with_sums = list(zip(row_sums, matrix))\n \n # Sort the rows based on their sums\n rows_with_sums.sort()\n \n # Separate the rows from their sums\n sorted_matrix = [row for _, row in rows_with_sums]\n \n return sorted_matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"\n Sorts a given matrix in ascending order according to the sum of its rows.\n\n Args:\n matrix (list of lists): A 2D list representing the matrix.\n\n Returns:\n list of lists: The sorted matrix.\n \"\"\"\n # Check if the input is a list of lists\n if not isinstance(matrix, list) or not all(isinstance(row, list) for row in matrix):\n raise ValueError(\"Input must be a list of lists\")\n\n # Use the sorted function with a custom key to sort the matrix\n # The key function calculates the sum of each row\n sorted_matrix = sorted(matrix, key=sum)\n\n return sorted_matrix", "matching_cluster_idx": 15}]}, "Mbpp/16": {"dps": 69.08536585365854, "dps_norm": 86.875, "pass@1": 45.0, "profiled": [{"solution": "import re\ndef text_lowercase_underscore(input_string):\n \"\"\"\n This function checks if the input string contains sequences of lowercase letters joined with an underscore.\n\n Parameters:\n input_string (str): The string to be checked.\n\n Returns:\n bool: True if the input string contains sequences of lowercase letters joined with an underscore, False otherwise.\n \"\"\"\n pattern = \"^[a-z]+(_[a-z]+)*$\"\n if re.match(pattern, input_string):\n return True\n else:\n return False", "matching_cluster_idx": 7}, {"solution": "import re\ndef text_lowercase_underscore(input_string):\n \"\"\"\n This function checks if the input string contains sequences of \n lowercase letters joined with an underscore.\n \n Parameters:\n input_string (str): Input string to check\n \n Returns:\n bool: True if the input string contains sequences of lowercase letters \n joined with an underscore, False otherwise\n \"\"\"\n \n # Define a regular expression pattern that matches sequences of \n # lowercase letters joined with an underscore\n pattern = r'^[a-z]+(_[a-z]+)*$'\n \n # Use the re.match function to check if the input string matches \n # the pattern. If a match is found, return True; otherwise, return False\n if re.match(pattern, input_string):\n return True\n else:\n return False", "matching_cluster_idx": 7}, {"solution": "import re\ndef text_lowercase_underscore(input_str):\n \"\"\"\n Checks if the input string consists of sequences of lowercase letters joined with an underscore.\n\n Args:\n input_str (str): Input string to be checked.\n\n Returns:\n bool: True if the string contains sequences of lowercase letters joined with an underscore, False otherwise.\n \"\"\"\n # Regular expression pattern to match sequences of lowercase letters joined with an underscore\n pattern = r'^[a-z]+(_[a-z]+)*$'\n \n # Check if the input string matches the pattern\n return bool(re.match(pattern, input_str))", "matching_cluster_idx": 7}, {"solution": "def text_lowercase_underscore(text):\n \"\"\"\n This function checks if the input string contains sequences of lowercase letters joined with an underscore.\n \n Args:\n text (str): Input string to check.\n\n Returns:\n bool: True if string contains sequences of lowercase letters joined with an underscore, False otherwise.\n \"\"\"\n\n # If the text is empty or not a string, return False\n if not isinstance(text, str) or len(text) == 0:\n return False\n\n # If the text starts or ends with an underscore, return False\n if text[0] == '_' or text[-1] == '_':\n return False\n\n # Split the string into sequences joined by an underscore\n sequences = text.split('_')\n\n # Check each sequence to ensure it's a lowercase letter\n for sequence in sequences:\n if not sequence.isalpha() or not sequence.islower():\n return False\n\n return True", "matching_cluster_idx": 4}, {"solution": "def text_lowercase_underscore(s):\n \"\"\"\n Returns True if the input string contains sequences of lowercase letters joined with an underscore and False otherwise.\n \n Args:\n s (str): The input string.\n \n Returns:\n bool: True if the string only contains sequences of lowercase letters joined with an underscore, False otherwise.\n \"\"\"\n if not s:\n return False\n \n components = s.split('_')\n return all(component.islower() and component.isalpha() for component in components)", "matching_cluster_idx": 4}, {"solution": "def text_lowercase_underscore(s):\n \"\"\"\n Returns true if the input string contains sequences of lowercase letters joined with an underscore and false otherwise.\n\n Parameters:\n s (str): The input string to be checked.\n\n Returns:\n bool: True if the input string meets the condition, False otherwise.\n \"\"\"\n # Split the input string by underscores\n substrings = s.split('_')\n\n # Check each substring\n for substring in substrings:\n # If any substring is not alphanumeric or contains uppercase letters, return False\n if not substring.isalpha() or not substring.islower():\n return False\n\n # If all substrings pass the check, return True\n return True", "matching_cluster_idx": 4}, {"solution": "import re\ndef text_lowercase_underscore(text: str) -> bool:\n \"\"\"\n Checks if the input string contains sequences of lowercase letters joined with an underscore.\n\n Args:\n text (str): The input string to be checked.\n\n Returns:\n bool: True if the string contains sequences of lowercase letters joined with an underscore, False otherwise.\n \"\"\"\n # Regular expression pattern to match sequences of lowercase letters joined with an underscore\n pattern = r'^[a-z]+(_[a-z]+)*$'\n \n # Check if the input string matches the pattern\n return bool(re.fullmatch(pattern, text))", "matching_cluster_idx": 7}, {"solution": "import re\ndef text_lowercase_underscore(text):\n \"\"\"\n This function returns True if the input string contains sequences of lowercase letters \n joined with an underscore and False otherwise.\n\n Args:\n text (str): Input string\n\n Returns:\n bool: True if input string contains lowercase letters and underscores, False otherwise\n \"\"\"\n # Using regular expression to match the pattern\n # ^ matches the start of the string\n # ([a-z]+) matches one or more lowercase letters\n # (_|$) matches either an underscore or the end of the string\n # + after the group means one or more occurrences of the group\n pattern = r'^([a-z]+_)*[a-z]+$'\n if re.match(pattern, text):\n return True\n else:\n return False", "matching_cluster_idx": 7}, {"solution": "import re\ndef text_lowercase_underscore(text):\n \"\"\"\n Returns True if the input string contains sequences of lowercase letters joined with an underscore.\n\n Parameters:\n text (str): Input string.\n\n Returns:\n bool: True if the string contains sequences of lowercase letters joined with an underscore, False otherwise.\n \"\"\"\n # If the text is empty, return False\n if not text:\n return False\n \n # Compile regular expression to match strings of lowercase letters or underscores\n pattern = re.compile(r'^[a-z_]*$')\n \n # Compile regular expression to match strings with at least one lowercase letter\n letter_pattern = re.compile(r'[a-z]')\n \n # If the string matches the pattern and contains at least one lowercase letter, return True\n if pattern.match(text) and letter_pattern.search(text) and '_' not in text[0] and '_' not in text[-1]:\n # Use split to check if the text has sequences of letters separated by underscores\n for seq in text.split('_'):\n # If any sequence is empty (i.e., multiple consecutive underscores), return False\n if not seq:\n return False\n return True\n \n # If none of the above conditions are met, return False\n return False", "matching_cluster_idx": 4}, {"solution": "import re\ndef text_lowercase_underscore(text):\n \"\"\"\n This function checks if the input string contains sequences of \n lowercase letters joined with an underscore.\n\n Args:\n text (str): The input string.\n\n Returns:\n bool: True if the string is in the correct format, False otherwise.\n \"\"\"\n # Match sequences of one or more lowercase letters joined with underscores\n pattern = r'^[a-z_]+$'\n # Match one or more of the above sequence\n sequence_pattern = r'[a-z]+(?:_[a-z]+)*'\n \n # Check if the entire string matches the pattern\n if re.fullmatch(pattern, text):\n # Check if all sequences in the string are lowercase letters joined with underscores\n sequences = text.split('_')\n for sequence in sequences:\n if not re.fullmatch(sequence_pattern.replace('_',''), sequence):\n return False\n return True\n else:\n return False", "matching_cluster_idx": 4}, {"solution": "import re\ndef text_lowercase_underscore(text):\n \"\"\"\n Returns True if the input string contains sequences of lowercase letters \n joined with an underscore and False otherwise.\n \"\"\"\n # Use regular expression to match sequences of lowercase letters and underscores\n pattern = re.compile(r'^[a-z]+(_[a-z]+)*$')\n \n # Use the fullmatch function to ensure the entire string matches the pattern\n return bool(pattern.fullmatch(text))", "matching_cluster_idx": 6}, {"solution": "import re\ndef text_lowercase_underscore(s):\n \"\"\"\n Checks if a given string consists of sequences of lowercase letters joined by an underscore.\n\n Args:\n s (str): The input string to check.\n\n Returns:\n bool: True if the string contains sequences of lowercase letters joined with an underscore, False otherwise.\n \"\"\"\n pattern = '^[a-z]+(_[a-z]+)*$'\n return bool(re.match(pattern, s))", "matching_cluster_idx": 6}, {"solution": "import re\ndef text_lowercase_underscore(s):\n \"\"\"\n Returns True if the input string contains sequences of lowercase letters joined with an underscore.\n\n Args:\n s (str): The input string.\n\n Returns:\n bool: True if the input string is valid, False otherwise.\n \"\"\"\n pattern = '^[a-z]+(_[a-z]+)*$'\n return bool(re.match(pattern, s))", "matching_cluster_idx": 7}, {"solution": "import re\ndef text_lowercase_underscore(text):\n \"\"\"\n This function checks if the input string contains sequences of lowercase letters joined with an underscore.\n \n Args:\n text (str): The input string to be checked.\n\n Returns:\n bool: True if the string contains sequences of lowercase letters joined with an underscore, False otherwise.\n \"\"\"\n # Use regular expression to match sequences of lowercase letters joined with an underscore\n pattern = r'^[a-z]+(_[a-z]+)*$'\n # Check if the entire string matches the pattern\n return bool(re.fullmatch(pattern, text))", "matching_cluster_idx": 7}, {"solution": "import re\ndef text_lowercase_underscore(s):\n \"\"\"\n This function checks if the input string contains sequences of lowercase letters joined with an underscore.\n \n Parameters:\n s (str): The input string.\n \n Returns:\n bool: True if the string contains sequences of lowercase letters joined with an underscore, False otherwise.\n \"\"\"\n \n # Check if the string only contains lowercase letters and underscores\n # The ^ and $ anchors ensure the entire string must match the pattern, not just a part of it\n if re.match('^[a-z_]+$', s):\n # Split the string into parts separated by underscores\n parts = s.split('_')\n \n # Check if all parts only contain lowercase letters\n for part in parts:\n # If a part does not contain only lowercase letters, return False\n if not part.islower():\n return False\n return True\n else:\n return False", "matching_cluster_idx": 4}, {"solution": "import re\ndef text_lowercase_underscore(s: str) -> bool:\n \"\"\"\n Checks if the input string contains sequences of lowercase letters joined with an underscore.\n\n Args:\n s (str): Input string to be checked.\n\n Returns:\n bool: True if the string contains sequences of lowercase letters joined with an underscore, False otherwise.\n \"\"\"\n return bool(re.match(r'^[a-z]+(_[a-z]+)*$', s))", "matching_cluster_idx": 6}, {"solution": "import re\ndef text_lowercase_underscore(s):\n \"\"\"\n Check if the input string contains sequences of lowercase letters joined with an underscore.\n\n Args:\n s (str): Input string.\n\n Returns:\n bool: True if the input string contains sequences of lowercase letters joined with an underscore, False otherwise.\n \"\"\"\n # Use regular expression to match the pattern of lowercase letters joined with an underscore\n pattern = r'^[a-z]+(_[a-z]+)*$'\n return bool(re.match(pattern, s))", "matching_cluster_idx": 7}, {"solution": "import re\ndef text_lowercase_underscore(s):\n \"\"\"\n Check if the input string contains sequences of lowercase letters joined with an underscore.\n\n Args:\n s (str): Input string.\n\n Returns:\n bool: True if the input string contains sequences of lowercase letters joined with an underscore, False otherwise.\n \"\"\"\n pattern = r'^[a-z]+(_[a-z]+)*$'\n return bool(re.match(pattern, s))", "matching_cluster_idx": 7}, {"solution": "import re\ndef text_lowercase_underscore(s):\n \"\"\"\n Returns true if the input string contains sequences of lowercase letters joined with an underscore.\n\n :param s: Input string\n :return: bool\n \"\"\"\n # Define the pattern as one or more lowercase letters optionally followed by an underscore and more letters\n pattern = r'^[a-z]+(_[a-z]+)*$'\n \n # Check if the entire string matches the pattern\n return bool(re.fullmatch(pattern, s))", "matching_cluster_idx": 7}, {"solution": "import re\ndef text_lowercase_underscore(s):\n \"\"\"\n Returns True if the input string contains sequences of lowercase letters joined with an underscore.\n \n Parameters:\n s (str): The input string to be validated.\n \n Returns:\n bool: True if the input string matches the pattern, False otherwise.\n \"\"\"\n pattern = '^[a-z]+(_[a-z]+)*$'\n return bool(re.match(pattern, s))", "matching_cluster_idx": 7}]}, "Mbpp/19": {"dps": 75.25252525252526, "dps_norm": 86.0, "pass@1": 100.0, "profiled": [{"solution": "def test_duplicate(arr):\n \"\"\"\n Checks if there are any duplicate elements in the given array.\n \n Args:\n arr (list): A list of integers.\n \n Returns:\n bool: True if there are duplicates, False otherwise.\n \"\"\"\n seen = set()\n for num in arr:\n if num in seen:\n return True\n seen.add(num)\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(arr):\n \"\"\"\n Checks whether a given array of integers contains any duplicate element.\n\n Args:\n arr (list): A list of integers.\n\n Returns:\n bool: True if the array contains any duplicate element, False otherwise.\n \"\"\"\n # Convert the list to a set, which automatically removes duplicates.\n # If the length of the original list and the set are not equal, then there were duplicates.\n return len(arr) != len(set(arr))", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(arr):\n \"\"\"\n This function checks if there is any duplicate element in the given array.\n\n Parameters:\n arr (list): The input list of integers\n\n Returns:\n bool: True if the list contains any duplicate element, False otherwise\n \"\"\"\n return len(arr) != len(set(arr))", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(arr):\n \"\"\"\n This function checks if there are any duplicate elements in the given array.\n\n Args:\n arr (list): The input list of integers.\n\n Returns:\n bool: True if the array contains any duplicate elements, False otherwise.\n \"\"\"\n return len(arr) != len(set(arr))", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(nums):\n \"\"\"\n Returns True if the list contains duplicates, False otherwise.\n\n :param nums: List of integers.\n :return: Boolean indicating the presence of duplicates.\n \"\"\"\n return len(nums) != len(set(nums))", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(arr):\n \"\"\"\n Checks if there are any duplicate elements in the given array.\n\n Args:\n arr (list): A list of integers.\n\n Returns:\n bool: True if there are duplicates, False otherwise.\n \"\"\"\n seen = set()\n for num in arr:\n if num in seen:\n return True\n seen.add(num)\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(nums):\n \"\"\"\n Returns True if the given list of integers contains any duplicate element, False otherwise.\n\n Args:\n nums (list): A list of integers.\n\n Returns:\n bool: Whether the list contains any duplicate element.\n \"\"\"\n seen = set()\n for num in nums:\n if num in seen:\n return True\n seen.add(num)\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(arr):\n \"\"\"\n This function checks if an array of integers contains any duplicate elements.\n \n Parameters:\n arr (list): A list of integers.\n \n Returns:\n bool: True if the array contains duplicates, False otherwise.\n \"\"\"\n return len(arr) != len(set(arr))", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(arr):\n \"\"\"\n Checks if there are any duplicate elements in the given array.\n\n Args:\n arr (list): A list of integers.\n\n Returns:\n bool: True if the array contains duplicate elements, False otherwise.\n \"\"\"\n # Convert the array into a set, which removes any duplicate elements\n # If the lengths of the original array and the set are not equal, there were duplicates\n return len(arr) != len(set(arr))", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(array):\n \"\"\"\n This function checks whether a given array of integers contains any duplicate element.\n \n Args:\n array (list): A list of integers.\n \n Returns:\n bool: True if the array contains a duplicate, False otherwise.\n \"\"\"\n # Convert the array to a set, which automatically removes any duplicates\n return len(array) != len(set(array))", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(arr):\n \"\"\"\n Checks if the given array contains any duplicate element.\n\n Args:\n arr (list): A list of integers.\n\n Returns:\n bool: True if the array contains any duplicate element, False otherwise.\n \"\"\"\n # Create an empty set\n unique_elements = set()\n \n # Iterate over each element in the array\n for element in arr:\n # If the element is already in the set, it's a duplicate\n if element in unique_elements:\n return True\n # Otherwise, add it to the set\n unique_elements.add(element)\n \n # If no duplicates were found, return False\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(arr):\n \"\"\"\n This function checks if there are any duplicate elements in the given array of integers.\n\n Args:\n arr (list): A list of integers.\n\n Returns:\n bool: True if the array contains duplicate elements, False otherwise.\n \"\"\"\n # Create a set from the array, which removes any duplicate elements.\n # If the lengths of the array and the set are not equal, then the array contained duplicates.\n return len(arr) != len(set(arr))", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(arr):\n \"\"\"\n This function checks if a given array of integers contains any duplicate elements.\n\n Args:\n arr (list): A list of integers.\n\n Returns:\n bool: True if the array contains duplicate elements, False otherwise.\n \"\"\"\n return len(arr) != len(set(arr))", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(arr):\n \"\"\"\n This function checks if there are any duplicate elements in the given array.\n\n Args:\n arr (list): A list of integers.\n\n Returns:\n bool: True if there are any duplicate elements, False otherwise.\n \"\"\"\n return len(arr) != len(set(arr))", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(arr):\n \"\"\"\n Checks if the given array of integers contains any duplicate element.\n \n Args:\n arr (list): A list of integers.\n \n Returns:\n bool: True if there are duplicates, False otherwise.\n \"\"\"\n return len(arr) != len(set(arr))", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(arr):\n \"\"\"\n This function checks if a given array contains any duplicate element.\n \n Parameters:\n arr (list): A list of integers.\n \n Returns:\n bool: True if the array contains any duplicate, False otherwise.\n \"\"\"\n return len(arr) != len(set(arr))", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(nums):\n \"\"\"\n This function checks if a given list of integers contains any duplicate elements.\n\n Args:\n nums (list): A list of integers.\n\n Returns:\n bool: True if the list contains any duplicate elements, False otherwise.\n \"\"\"\n seen = set()\n for num in nums:\n if num in seen:\n return True\n seen.add(num)\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(arr):\n \"\"\"\n Returns True if the given array of integers contains duplicate elements.\n Otherwise, returns False.\n\n Args:\n arr (list): The list of integers to check for duplicates.\n\n Returns:\n bool: Whether the list contains duplicates.\n \"\"\"\n seen = set()\n for num in arr:\n if num in seen:\n return True\n seen.add(num)\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(nums):\n \"\"\"\n Checks if the given array of integers contains any duplicate element.\n \n Args:\n nums (list): A list of integers.\n \n Returns:\n bool: True if the array contains any duplicate element, False otherwise.\n \"\"\"\n return len(nums) != len(set(nums))", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(nums):\n \"\"\"\n This function checks whether a given array of integers contains any duplicate element.\n\n Args:\n nums (list): A list of integers.\n\n Returns:\n bool: True if the list contains any duplicate element, False otherwise.\n \"\"\"\n return len(nums) != len(set(nums))", "matching_cluster_idx": 11}]}, "Mbpp/62": {"dps": 95.57692307692308, "dps_norm": 96.0, "pass@1": 98.0, "profiled": [{"solution": "def smallest_num(numbers):\n \"\"\"\n This function finds the smallest number in a given list.\n \n Args:\n numbers (list): A list of numbers.\n \n Returns:\n int: The smallest number in the list.\n \"\"\"\n return min(numbers)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(numbers):\n \"\"\"\n This function finds the smallest number in a given list.\n \n Args:\n numbers (list): A list of numbers.\n \n Returns:\n int: The smallest number in the list.\n \"\"\"\n if not numbers:\n raise ValueError(\"The input list is empty\")\n \n return min(numbers)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(numbers):\n \"\"\"\n This function finds and returns the smallest number in a given list.\n\n Args:\n numbers (list): A list of integers.\n\n Returns:\n int: The smallest number in the list.\n\n Raises:\n ValueError: If the input list is empty.\n \"\"\"\n if len(numbers) == 0:\n raise ValueError(\"Input list is empty\")\n\n # Use the built-in min function in Python to find the smallest number\n return min(numbers)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(numbers):\n \"\"\"\n This function finds the smallest number in a list.\n\n Args:\n numbers (list): A list of numbers.\n\n Returns:\n int: The smallest number in the list.\n \"\"\"\n if not isinstance(numbers, list) or not all(isinstance(num, (int, float)) for num in numbers):\n raise ValueError(\"Input must be a list of numbers.\")\n \n if len(numbers) == 0:\n raise ValueError(\"Input list is empty.\")\n\n return min(numbers)", "matching_cluster_idx": 0}, {"solution": "def smallest_num(nums):\n \"\"\"\n This function finds the smallest number in a given list.\n\n Args:\n nums (list): A list of numbers.\n\n Returns:\n int: The smallest number in the list.\n\n Raises:\n ValueError: If the input list is empty.\n \"\"\"\n\n if not nums:\n raise ValueError(\"Input list is empty\")\n\n return min(nums)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(nums):\n \"\"\"\n This function finds the smallest number in a given list of numbers.\n\n Args:\n nums (list): A list of numbers.\n\n Returns:\n int: The smallest number in the list.\n\n Raises:\n ValueError: If the input list is empty.\n \"\"\"\n if not nums:\n raise ValueError(\"Input list is empty\")\n return min(nums)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(numbers):\n \"\"\"\n This function finds the smallest number in a given list of numbers.\n\n Args:\n numbers (list): A list of numbers.\n\n Returns:\n int: The smallest number in the list.\n\n Raises:\n ValueError: If the input list is empty.\n \"\"\"\n if not numbers:\n raise ValueError(\"Input list is empty\")\n return min(numbers)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(nums):\n \"\"\"\n This function finds the smallest number in a list.\n\n Args:\n nums (list): A list of numbers.\n\n Returns:\n int: The smallest number in the list.\n\n Raises:\n ValueError: If the input list is empty.\n \"\"\"\n if len(nums) == 0:\n raise ValueError(\"Input list cannot be empty\")\n return min(nums)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(nums):\n \"\"\"\n Returns the smallest number in a given list.\n\n Args:\n nums (list): A list of numbers.\n\n Returns:\n int: The smallest number in the list.\n\n Raises:\n ValueError: If the list is empty.\n \"\"\"\n if not nums:\n raise ValueError(\"List is empty\")\n return min(nums)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(numbers):\n \"\"\"\n This function returns the smallest number in a given list of numbers.\n \n Args:\n numbers (list): A list of numbers.\n \n Returns:\n int: The smallest number in the list.\n \"\"\"\n if not numbers:\n raise ValueError(\"Input list is empty.\")\n return min(numbers)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(numbers):\n \"\"\"\n This function returns the smallest number from the given list.\n\n Args:\n numbers (list): A list of numbers.\n\n Returns:\n int: The smallest number in the list.\n\n Raises:\n ValueError: If the list is empty.\n \"\"\"\n\n # Check if the list is empty\n if not numbers:\n raise ValueError(\"List cannot be empty\")\n\n # Use built-in min function to find the smallest number\n smallest = min(numbers)\n\n return smallest", "matching_cluster_idx": 4}, {"solution": "def smallest_num(nums):\n \"\"\"\n This function finds the smallest number in a list of numbers.\n\n Args:\n nums (list): A list of numbers.\n\n Returns:\n int: The smallest number in the list.\n \"\"\"\n if not nums:\n raise ValueError(\"Input list is empty\")\n\n return min(nums)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(numbers):\n \"\"\"\n This function finds the smallest number in a given list of numbers.\n\n Args:\n numbers (list): A list of integers.\n\n Returns:\n int: The smallest number in the list.\n\n Raises:\n ValueError: If the input list is empty.\n \"\"\"\n if not numbers:\n raise ValueError(\"Input list cannot be empty\")\n\n return min(numbers)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(num_list):\n \"\"\"\n Returns the smallest number in a given list of integers.\n\n Args:\n num_list (list): A list of integers.\n\n Returns:\n int: The smallest integer in the list.\n\n Raises:\n ValueError: If the list is empty.\n \"\"\"\n if not num_list:\n raise ValueError(\"List cannot be empty\")\n\n return min(num_list)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(numbers):\n \"\"\"\n Returns the smallest number in a list.\n\n Args:\n numbers (list): A list of numbers.\n\n Returns:\n int: The smallest number in the list.\n\n Raises:\n ValueError: If the input list is empty.\n \"\"\"\n if not numbers:\n raise ValueError(\"Input list cannot be empty\")\n\n return min(numbers)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(lst):\n \"\"\"\n Returns the smallest number in a list.\n\n Args:\n lst (list): A list of numbers.\n\n Returns:\n int or float: The smallest number in the list.\n\n Raises:\n ValueError: If the list is empty.\n\n Example:\n >>> smallest_num([10, 20, 1, 45, 99])\n 1\n \"\"\"\n if not lst:\n raise ValueError(\"List cannot be empty\")\n return min(lst)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(nums):\n \"\"\"\n This function returns the smallest number in a given list of integers.\n\n Args:\n nums (list): A list of integers.\n\n Returns:\n int: The smallest number in the list.\n \"\"\"\n if not nums: # edge case: empty list\n raise ValueError(\"Input list is empty\")\n\n return min(nums)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(numbers):\n \"\"\"\n This function finds and returns the smallest number in a given list of numbers.\n\n Args:\n numbers (list): A list of numbers.\n\n Returns:\n int: The smallest number in the list.\n\n Raises:\n ValueError: If the input list is empty.\n \"\"\"\n if not numbers:\n raise ValueError(\"Input list cannot be empty\")\n return min(numbers)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(numbers):\n \"\"\"\n This function finds the smallest number in a given list of numbers.\n\n Args:\n numbers (list): A list of numbers.\n\n Returns:\n int: The smallest number in the list.\n \"\"\"\n if not numbers:\n raise ValueError(\"Input list is empty\")\n\n return min(numbers)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(lst):\n \"\"\"\n Returns the smallest number in a given list.\n \n Args:\n lst (list): A list of numbers.\n \n Returns:\n The smallest number in the list.\n \"\"\"\n return min(lst)", "matching_cluster_idx": 4}]}, "Mbpp/75": {"dps": 92.92857142857143, "dps_norm": 67.77777777777779, "pass@1": 100.0, "profiled": [{"solution": "def find_tuples(tuples_list, k):\n \"\"\"\n This function filters tuples from the list where all elements are divisible by k.\n\n Args:\n tuples_list (list): A list of tuples to be filtered.\n k (int): The divisor number.\n\n Returns:\n list: A list of tuples where all elements are divisible by k.\n \"\"\"\n return [t for t in tuples_list if all(x % k == 0 for x in t)]\ntuples_list = [(6, 24, 12), (7, 9, 6), (12, 18, 21)]\nk = 6", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples, k):\n \"\"\"\n This function filters tuples from a list of tuples where all elements in the tuple are divisible by k.\n\n Args:\n tuples (list): A list of tuples to filter.\n k (int): The divisor to check for in the tuples.\n\n Returns:\n list: A list of tuples where all elements in the tuple are divisible by k.\n \"\"\"\n return [t for t in tuples if all(x % k == 0 for x in t)]", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples, k):\n \"\"\"\n Finds tuples which have all elements divisible by k from the given list of tuples.\n\n Args:\n tuples (list): A list of tuples.\n k (int): The divisor.\n\n Returns:\n list: A list of tuples where all elements are divisible by k.\n \"\"\"\n return [t for t in tuples if all(x % k == 0 for x in t)]", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n \"\"\"\n Returns a list of tuples from tuples_list where all elements are divisible by k.\n\n Args:\n tuples_list (list): A list of tuples.\n k (int): The divisor.\n\n Returns:\n list: A list of tuples with all elements divisible by k.\n \"\"\"\n return [tup for tup in tuples_list if all(i % k == 0 for i in tup)]", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n \"\"\"\n Find tuples from a given list of tuples where all elements are divisible by k.\n\n Args:\n tuples_list (list): A list of tuples.\n k (int): The divisor.\n\n Returns:\n list: A list of tuples where all elements are divisible by k.\n \"\"\"\n # Use list comprehension and the built-in all() function with a generator expression\n # to filter tuples where all elements are divisible by k\n return [tup for tup in tuples_list if all(element % k == 0 for element in tup)]", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n \"\"\"\n This function takes a list of tuples and an integer k as input, \n and returns a list of tuples where all elements in each tuple are divisible by k.\n\n Args:\n tuples_list (list): A list of tuples.\n k (int): The divisor.\n\n Returns:\n list: A list of tuples where all elements are divisible by k.\n \"\"\"\n # Initialize an empty list to store the result tuples\n result = []\n\n # Iterate over each tuple in the input list\n for tup in tuples_list:\n # Check if all elements in the tuple are divisible by k\n if all(i % k == 0 for i in tup):\n # If true, append the tuple to the result list\n result.append(tup)\n\n # Return the result list\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n \"\"\"\n This function finds tuples which have all elements divisible by k from the given list of tuples.\n\n Args:\n tuples_list (list): A list of tuples.\n k (int): The number by which all elements in a tuple should be divisible.\n\n Returns:\n list: A list of tuples where all elements in each tuple are divisible by k.\n \"\"\"\n # Use a list comprehension to filter the tuples\n # A tuple is included in the result if all its elements are divisible by k\n return [t for t in tuples_list if all(i % k == 0 for i in t)]", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples, k):\n \"\"\"\n Find tuples which have all elements divisible by k from the given list of tuples.\n\n Args:\n tuples (list): A list of tuples\n k (int): The divisor\n\n Returns:\n list: List of tuples with all elements divisible by k\n \"\"\"\n return [t for t in tuples if all(i % k == 0 for i in t)]", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuple_list, k):\n \"\"\"\n This function finds tuples which have all elements divisible by k \n from the given list of tuples.\n\n Parameters:\n tuple_list (list): A list of tuples.\n k (int): The divisor to check.\n\n Returns:\n list: A list of tuples with all elements divisible by k.\n \"\"\"\n return [tup for tup in tuple_list if all(i % k == 0 for i in tup)]", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples, k):\n \"\"\"\n This function takes in a list of tuples and an integer k as input and returns a new list of tuples.\n The returned list contains tuples from the original list where all elements of the tuple are divisible by k.\n\n Args:\n tuples (list): A list of tuples.\n k (int): The divisor.\n\n Returns:\n list: A list of tuples where all elements of the tuple are divisible by k.\n \"\"\"\n # Initialize an empty list to store tuples with all elements divisible by k\n divisible_tuples = []\n \n # Iterate over each tuple in the input list of tuples\n for tup in tuples:\n # Use the built-in all() function and a generator expression to check if all elements in the tuple are divisible by k\n if all(element % k == 0 for element in tup):\n # If all elements are divisible by k, append the tuple to the divisible_tuples list\n divisible_tuples.append(tup)\n \n # Return the list of tuples with all elements divisible by k\n return divisible_tuples", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n \"\"\"\n Find tuples which have all elements divisible by k from the given list of tuples.\n\n Args:\n tuples_list (list): A list of tuples.\n k (int): The divisor.\n\n Returns:\n list: A list of tuples with all elements divisible by k.\n \"\"\"\n result = [t for t in tuples_list if all(x % k == 0 for x in t)]\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n \"\"\"\n This function filters tuples from a given list of tuples where all elements are divisible by k.\n\n Args:\n tuples_list (list): A list of tuples.\n k (int): The divisor.\n\n Returns:\n list: A list of tuples where all elements in each tuple are divisible by k.\n \"\"\"\n return [t for t in tuples_list if all(i % k == 0 for i in t)]\ntuples_list = [(6, 24, 12), (7, 9, 6), (12, 18, 21)]\nk = 6", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n \"\"\"\n Finds tuples which have all elements divisible by k from the given list of tuples.\n\n Args:\n tuples_list (list): A list of tuples.\n k (int): The number to check divisibility.\n\n Returns:\n list: A list of tuples where all elements are divisible by k.\n \"\"\"\n # Initialize an empty list to store the result\n result = []\n \n # Iterate through each tuple in the list\n for tup in tuples_list:\n # Assume that all elements are divisible by k\n all_divisible = True\n \n # Check each element in the tuple\n for num in tup:\n # If the number is not divisible by k\n if num % k != 0:\n # Mark as not all divisible and break\n all_divisible = False\n break\n \n # If all elements are divisible, add to result\n if all_divisible:\n result.append(tup)\n \n # Return the list of tuples\n return result", "matching_cluster_idx": 7}, {"solution": "def find_tuples(tuples_list, k):\n \"\"\"\n This function filters a list of tuples and returns a new list of tuples \n where all elements in each tuple are divisible by k.\n\n Args:\n tuples_list (list): A list of tuples.\n k (int): The divisor.\n\n Returns:\n list: A list of tuples with all elements divisible by k.\n \"\"\"\n return [tup for tup in tuples_list if all(i % k == 0 for i in tup)]", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n \"\"\"\n This function takes a list of tuples and an integer k as input, \n and returns a list of tuples where all elements in the tuple are divisible by k.\n\n Args:\n tuples_list (list): A list of tuples.\n k (int): The divisor.\n\n Returns:\n list: A list of tuples where all elements in the tuple are divisible by k.\n \"\"\"\n return [t for t in tuples_list if all(i % k == 0 for i in t)]", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n \"\"\"\n Find tuples which have all elements divisible by k from the given list of tuples.\n\n Args:\n tuples_list (list): A list of tuples.\n k (int): The divisor to check for.\n\n Returns:\n list: A list of tuples where all elements are divisible by k.\n \"\"\"\n return [t for t in tuples_list if all(i % k == 0 for i in t)]", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n \"\"\"\n This function filters a list of tuples and returns only those \n where all elements are divisible by the given divisor k.\n\n Args:\n tuples_list (list): A list of tuples.\n k (int): The divisor.\n\n Returns:\n list: A list of tuples where all elements are divisible by k.\n \"\"\"\n # Use list comprehension with all() function to filter tuples\n return [t for t in tuples_list if all(i % k == 0 for i in t)]", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n \"\"\"\n Find tuples from the given list of tuples where all elements are divisible by k.\n\n Args:\n tuples_list (list): A list of tuples.\n k (int): Divisor to check for divisibility.\n\n Returns:\n list: A list of tuples with all elements divisible by k.\n \"\"\"\n return [tup for tup in tuples_list if all(i % k == 0 for i in tup)]", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n \"\"\"\n This function filters tuples from the given list where all elements in the tuple are divisible by k.\n\n Args:\n tuples_list (list): A list of tuples to filter.\n k (int): The divisor.\n\n Returns:\n list: A list of tuples with all elements divisible by k.\n \"\"\"\n # Use list comprehension to create a new list of tuples that meet the condition\n return [tup for tup in tuples_list if all(element % k == 0 for element in tup)]", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n \"\"\"\n Find all tuples in the list where all elements are divisible by k.\n\n Args:\n tuples_list (list): A list of tuples.\n k (int): The divisor to check for.\n\n Returns:\n list: A list of tuples where all elements are divisible by k.\n \"\"\"\n result = []\n for tup in tuples_list:\n if all(element % k == 0 for element in tup):\n result.append(tup)\n return result", "matching_cluster_idx": 5}]}, "Mbpp/88": {"dps": 97.08333333333333, "dps_norm": 87.85714285714285, "pass@1": 100.0, "profiled": [{"solution": "def freq_count(lst):\n \"\"\"\n This function calculates the frequency of all elements in a given list.\n \n Parameters:\n lst (list): The input list.\n \n Returns:\n dict: A dictionary where keys are the unique elements from the list and values are their respective frequencies.\n \"\"\"\n freq_dict = {}\n for elem in lst:\n if elem in freq_dict:\n freq_dict[elem] += 1\n else:\n freq_dict[elem] = 1\n return freq_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(input_list):\n \"\"\"\n This function calculates the frequency of all the elements in a given list.\n\n Args:\n input_list (list): The list of elements.\n\n Returns:\n dict: A dictionary where keys are elements from the input list and values are their frequencies.\n\n \"\"\"\n freq_dict = {}\n for item in input_list:\n if item in freq_dict:\n # Increment the count if the item is already in the dictionary.\n freq_dict[item] += 1\n else:\n # Add the item to the dictionary if it's not already there.\n freq_dict[item] = 1\n return freq_dict", "matching_cluster_idx": 5}, {"solution": "from collections import Counter\ndef freq_count(lst):\n \"\"\"\n Returns the frequency of all elements in a list as a dictionary.\n\n Args:\n lst (list): The input list.\n\n Returns:\n dict: A dictionary with elements as keys and frequencies as values.\n \"\"\"\n # Initialize an empty dictionary to store the frequency of elements.\n freq_dict = {}\n \n # Iterate over each element in the list.\n for item in lst:\n # If the element is already in the dictionary, increment its frequency.\n if item in freq_dict:\n freq_dict[item] += 1\n # If the element is not in the dictionary, add it with a frequency of 1.\n else:\n freq_dict[item] = 1\n \n return freq_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n \"\"\"\n This function calculates the frequency of all the elements in a list.\n \n Args:\n lst (list): A list containing elements of any type.\n\n Returns:\n dict: A dictionary where keys are the unique elements in the list and values are their frequencies.\n\n \"\"\"\n freq_dict = {}\n for elem in lst:\n # If the element is already in the dictionary, increment its count\n if elem in freq_dict:\n freq_dict[elem] += 1\n # If the element is not in the dictionary, add it with a count of 1\n else:\n freq_dict[elem] = 1\n return freq_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n \"\"\"\n This function calculates the frequency of each element in the input list.\n \n Args:\n lst (list): Input list containing elements.\n \n Returns:\n dict: A dictionary with elements as keys and their frequencies as values.\n \"\"\"\n freq_dict = {}\n for elem in lst:\n if elem in freq_dict:\n freq_dict[elem] += 1\n else:\n freq_dict[elem] = 1\n return freq_dict", "matching_cluster_idx": 5}, {"solution": "from collections import Counter\ndef freq_count(lst):\n \"\"\"\n Return the frequency of all elements in a list.\n\n Args:\n lst (list): A list of elements.\n\n Returns:\n dict: A dictionary where keys are unique elements from the list and values are their frequencies.\n\n Example:\n >>> freq_count([10, 10, 10, 10, 20, 20, 20, 20, 40, 40, 50, 50, 30])\n {10: 4, 20: 4, 40: 2, 50: 2, 30: 1}\n \"\"\"\n return dict(Counter(lst))", "matching_cluster_idx": 6}, {"solution": "def freq_count(input_list):\n \"\"\"\n This function calculates the frequency of all elements in the given list.\n\n Args:\n input_list (list): The list containing elements for which frequency needs to be calculated.\n\n Returns:\n dict: A dictionary where keys are unique elements from the list and values are their corresponding frequencies.\n\n \"\"\"\n freq_dict = {}\n \n # Iterate through the list\n for element in input_list:\n # If the element already exists in the dictionary, increment its frequency by 1\n if element in freq_dict:\n freq_dict[element] += 1\n # If the element doesn't exist in the dictionary, add it with a frequency of 1\n else:\n freq_dict[element] = 1\n \n return freq_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(input_list):\n \"\"\"\n This function takes a list of elements as input and returns a dictionary where keys are unique elements from the list\n and values are their corresponding frequencies.\n\n Args:\n input_list (list): A list of elements of any data type.\n\n Returns:\n dict: A dictionary with elements from the list as keys and their frequencies as values.\n \"\"\"\n # Initialize an empty dictionary to store the frequency of each element.\n frequency_dict = {}\n\n # Iterate over each element in the input list.\n for element in input_list:\n # If the element is already in the dictionary, increment its count by 1.\n if element in frequency_dict:\n frequency_dict[element] += 1\n # If the element is not in the dictionary, add it with a count of 1.\n else:\n frequency_dict[element] = 1\n\n # Return the dictionary containing the frequency of each element.\n return frequency_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(input_list):\n \"\"\"\n This function takes a list as input and returns a dictionary where the keys are the elements from the list \n and the values are their respective frequencies.\n\n Args:\n input_list (list): A list containing elements of any hashable type.\n\n Returns:\n dict: A dictionary where keys are elements from the list and values are their frequencies.\n \"\"\"\n freq_dict = {}\n for item in input_list:\n if item in freq_dict:\n freq_dict[item] += 1\n else:\n freq_dict[item] = 1\n return freq_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n \"\"\"\n Returns a dictionary containing the frequency of all elements in a list.\n \n Parameters:\n lst (list): The list of elements.\n \n Returns:\n dict: A dictionary where keys are the elements and values are their frequencies.\n \"\"\"\n freq_dict = {}\n \n for elem in lst:\n if elem in freq_dict:\n freq_dict[elem] += 1\n else:\n freq_dict[elem] = 1\n \n return freq_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n \"\"\"\n This function calculates the frequency of all the elements in a given list.\n\n Args:\n lst (list): A list containing elements of any type that can be used as dictionary keys.\n\n Returns:\n dict: A dictionary where keys are unique elements from the input list and values represent their frequency.\n\n Examples:\n >>> freq_count([10,10,10,10,20,20,20,20,40,40,50,50,30])\n {10: 4, 20: 4, 40: 2, 50: 2, 30: 1}\n \"\"\"\n freq_dict = {}\n for elem in lst:\n if elem in freq_dict:\n freq_dict[elem] += 1\n else:\n freq_dict[elem] = 1\n return freq_dict", "matching_cluster_idx": 5}, {"solution": "from collections import Counter\ndef freq_count(lst):\n \"\"\"\n Returns a dictionary with the frequency of each element in the input list.\n \n :param lst: The input list.\n :return: A dictionary where keys are the elements in the list and values are their frequencies.\n \"\"\"\n freq_dict = {}\n for elem in lst:\n if elem in freq_dict:\n freq_dict[elem] += 1\n else:\n freq_dict[elem] = 1\n return freq_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n \"\"\"\n Returns a dictionary containing the frequency of each element in the list.\n\n Args:\n lst (list): A list containing elements of any hashable type.\n\n Returns:\n dict: A dictionary where keys are the elements from the list and values are their frequencies.\n \"\"\"\n freq_dict = {}\n for item in lst:\n if item in freq_dict:\n freq_dict[item] += 1\n else:\n freq_dict[item] = 1\n return freq_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n \"\"\"\n This function calculates the frequency of all elements in a list and returns the result as a dictionary.\n \n Parameters:\n lst (list): The input list containing elements to calculate frequencies for.\n \n Returns:\n dict: A dictionary with elements as keys and their frequencies as values.\n \"\"\"\n freq_dict = {}\n for item in lst:\n # if the item is already in the dictionary, increment its count\n if item in freq_dict:\n freq_dict[item] += 1\n # if the item is not in the dictionary, add it with a count of 1\n else:\n freq_dict[item] = 1\n return freq_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n \"\"\"\n This function calculates the frequency of all elements in the given list.\n\n Args:\n lst (list): A list of elements.\n\n Returns:\n dict: A dictionary where keys are elements from the list and values are their frequencies.\n\n \"\"\"\n freq_dict = {}\n for item in lst:\n # Check if item already exists in the dictionary\n if item in freq_dict:\n # If it does, increment its frequency by 1\n freq_dict[item] += 1\n else:\n # If it doesn't, add it to the dictionary with a frequency of 1\n freq_dict[item] = 1\n return freq_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n \"\"\"\n Returns a dictionary containing the frequency of each element in the list.\n\n Args:\n lst (list): A list containing elements.\n\n Returns:\n dict: A dictionary where the keys are unique elements and values are their frequencies.\n\n \"\"\"\n frequency_dict = {}\n for element in lst:\n if element in frequency_dict:\n frequency_dict[element] += 1\n else:\n frequency_dict[element] = 1\n return frequency_dict", "matching_cluster_idx": 5}, {"solution": "from collections import Counter\ndef freq_count(lst):\n \"\"\"\n This function returns the frequency of all elements in the input list as a dictionary.\n\n Parameters:\n lst (list): A list of elements\n\n Returns:\n dict: A dictionary where keys are the elements from the list and values are their frequencies\n \"\"\"\n return dict(Counter(lst))", "matching_cluster_idx": 6}, {"solution": "def freq_count(lst):\n \"\"\"\n This function calculates the frequency of all elements in a list and returns it as a dictionary.\n \n Args:\n lst (list): A list of elements.\n \n Returns:\n dict: A dictionary where keys are the unique elements from the list and values are their frequencies.\n \"\"\"\n frequency_dict = {}\n for element in lst:\n if element in frequency_dict:\n frequency_dict[element] += 1\n else:\n frequency_dict[element] = 1\n return frequency_dict", "matching_cluster_idx": 5}, {"solution": "from collections import Counter\ndef freq_count(lst):\n \"\"\"\n Return a dictionary with the frequency of all elements in a list.\n\n Args:\n lst (list): A list containing elements of any hashable type.\n\n Returns:\n dict: A dictionary with the elements from the list as keys and their frequencies as values.\n \"\"\"\n return dict(Counter(lst))", "matching_cluster_idx": 6}, {"solution": "def freq_count(input_list):\n \"\"\"\n This function calculates the frequency of all the elements in the input list and returns it as a dictionary.\n\n Args:\n input_list (list): A list containing elements of any type that can be used as keys in a dictionary.\n\n Returns:\n dict: A dictionary where the keys are the elements from the input list and the values are their corresponding frequencies.\n \"\"\"\n\n # Initialize an empty dictionary to store the frequency of each element\n freq_dict = {}\n\n # Iterate over each element in the input list\n for element in input_list:\n # If the element is already in the dictionary, increment its count by 1\n if element in freq_dict:\n freq_dict[element] += 1\n # If the element is not in the dictionary, add it with a count of 1\n else:\n freq_dict[element] = 1\n\n # Return the dictionary containing the frequency of each element\n return freq_dict", "matching_cluster_idx": 5}]}, "Mbpp/90": {"dps": 76.92682926829269, "dps_norm": 85.0, "pass@1": 42.0, "profiled": [{"solution": "def len_log(words):\n \"\"\"\n This function finds the length of the longest word in a given list.\n\n Args:\n words (list): A list of strings.\n\n Returns:\n int: The length of the longest word.\n\n Raises:\n ValueError: If the input list is empty.\n \"\"\"\n if not words:\n raise ValueError(\"Input list is empty\")\n \n return max(len(word) for word in words)", "matching_cluster_idx": 5}, {"solution": "def len_log(lst):\n \"\"\"\n Returns the length of the longest word in a list.\n\n Args:\n lst (list): A list of words.\n\n Returns:\n int: The length of the longest word.\n\n Raises:\n ValueError: If the input list is empty.\n \"\"\"\n if not lst:\n raise ValueError(\"Input list cannot be empty\")\n\n return max(len(word) for word in lst)", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n \"\"\"\n Returns the length of the longest word in the input list.\n\n Parameters:\n words (list): A list of words.\n\n Returns:\n int: The length of the longest word.\n\n \"\"\"\n return max(len(word) for word in words)", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n \"\"\"\n This function finds the length of the longest word in a given list of words.\n \n Args:\n words (list): A list of words.\n \n Returns:\n int: The length of the longest word.\n \"\"\"\n return max(len(word) for word in words)", "matching_cluster_idx": 5}, {"solution": "def len_log(word_list):\n \"\"\"\n This function calculates the length of the longest word in a given list.\n\n Parameters:\n word_list (list): A list of words.\n\n Returns:\n int: The length of the longest word in the list.\n \"\"\"\n return max(len(word) for word in word_list)", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n \"\"\"\n This function calculates the length of the longest word in a given list of words.\n\n Args:\n words (list): A list of strings\n\n Returns:\n int: The length of the longest word in the list\n \"\"\"\n return max(len(word) for word in words)", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n \"\"\"\n Returns the length of the longest word in the input list.\n\n Args:\n words (list): A list of strings\n\n Returns:\n int: The length of the longest word\n\n Raises:\n ValueError: If the input list is empty\n \"\"\"\n if not words:\n raise ValueError(\"Input list cannot be empty\")\n\n return max(len(word) for word in words)\nwords = [\"python\", \"PHP\", \"bigdata\"]", "matching_cluster_idx": 5}, {"solution": "def len_log(word_list):\n \"\"\"\n Returns the length of the longest word in the input list.\n\n Args:\n word_list (list): A list of words.\n\n Returns:\n int: The length of the longest word in the list.\n\n Raises:\n ValueError: If the input list is empty.\n TypeError: If the input is not a list.\n \"\"\"\n\n # Check if input is a list\n if not isinstance(word_list, list):\n raise TypeError(\"Input must be a list\")\n\n # Check if the list is not empty\n if len(word_list) == 0:\n raise ValueError(\"List cannot be empty\")\n\n # Find the longest word\n longest_word = max(word_list, key=len)\n\n # Return the length of the longest word\n return len(longest_word)", "matching_cluster_idx": 5}, {"solution": "def len_log(lst):\n \"\"\"\n Returns the length of the longest word in the input list.\n\n Args:\n lst (list): A list of words.\n\n Returns:\n int: Length of the longest word.\n\n \"\"\"\n return max(len(word) for word in lst)", "matching_cluster_idx": 5}, {"solution": "def len_log(word_list):\n \"\"\"\n Calculate the length of the longest word in a given list.\n \n Args:\n word_list (list): A list of words.\n \n Returns:\n int: The length of the longest word in the list.\n \"\"\"\n # Use max function with key=len to get the longest word\n longest_word = max(word_list, key=len)\n \n # Return the length of the longest word\n return len(longest_word)", "matching_cluster_idx": 6}, {"solution": "def len_log(word_list):\n \"\"\"\n This function calculates the length of the longest word in a given list.\n\n Args:\n word_list (list): A list of words.\n\n Returns:\n int: The length of the longest word in the list.\n \"\"\"\n return max(len(word) for word in word_list)", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n \"\"\"\n This function finds the length of the longest word in a given list.\n \n Parameters:\n words (list): A list of words.\n \n Returns:\n int: The length of the longest word.\n \n \"\"\"\n return max(len(word) for word in words)", "matching_cluster_idx": 5}, {"solution": "def len_log(lst):\n \"\"\"\n Find the length of the longest word in a list of strings.\n\n Parameters:\n lst (list): List of strings.\n\n Returns:\n int: Length of the longest word.\n\n Example:\n >>> len_log([\"python\",\"PHP\",\"bigdata\"])\n 7\n \"\"\"\n return max(len(word) for word in lst)", "matching_cluster_idx": 5}, {"solution": "def len_log(lst):\n \"\"\"\n This function calculates the length of the longest word in a given list of strings.\n\n Parameters:\n lst (list): A list of strings.\n\n Returns:\n int: The length of the longest string in the list.\n \"\"\"\n return max(len(word) for word in lst)", "matching_cluster_idx": 5}, {"solution": "def len_log(lst):\n \"\"\"\n This function takes a list of words and returns the length of the longest word.\n \n Parameters:\n lst (list): A list of strings.\n \n Returns:\n int: The length of the longest word in the list.\n \"\"\"\n return max(len(word) for word in lst)", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n \"\"\"\n Returns the length of the longest word in a given list of words.\n\n Args:\n words (list): A list of words\n\n Returns:\n int: The length of the longest word\n \"\"\"\n return max(len(word) for word in words)", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n \"\"\"\n Returns the length of the longest word in the list.\n\n Args:\n words (list): A list of words.\n\n Returns:\n int: The length of the longest word.\n\n Raises:\n ValueError: If the input list is empty.\n \"\"\"\n if not words:\n raise ValueError(\"Input list cannot be empty\")\n\n return max(len(word) for word in words)", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n \"\"\"\n This function finds the length of the longest word in the given list of words.\n \n Parameters:\n words (list): A list of words.\n \n Returns:\n int: The length of the longest word.\n \"\"\"\n return max(len(word) for word in words)", "matching_cluster_idx": 5}, {"solution": "def len_log(lst):\n \"\"\"\n Find the length of the longest word in the given list of strings.\n\n Args:\n lst (list): A list of strings.\n\n Returns:\n int: The length of the longest word.\n\n Example:\n >>> len_log([\"python\",\"PHP\",\"bigdata\"])\n 7\n \"\"\"\n # Check if the input is a list of strings\n if not isinstance(lst, list) or not all(isinstance(word, str) for word in lst):\n raise ValueError(\"Input must be a list of strings\")\n \n # Check if the list is not empty\n if not lst:\n return 0\n\n # Use the built-in max function with the key argument set to len to find the longest word\n return max(len(word) for word in lst)", "matching_cluster_idx": 3}, {"solution": "def len_log(words):\n \"\"\"\n This function finds the length of the longest word in a given list of words.\n\n Parameters:\n words (list): A list of words.\n\n Returns:\n int: The length of the longest word.\n\n Raises:\n ValueError: If the input list is empty.\n\n Example:\n >>> len_log([\"python\",\"PHP\",\"bigdata\"])\n 7\n \"\"\"\n if not words:\n raise ValueError(\"The input list is empty.\")\n \n return max(len(word) for word in words)", "matching_cluster_idx": 5}]}, "Mbpp/94": {"dps": 79.14634146341463, "dps_norm": 62.0, "pass@1": 96.0, "profiled": [{"solution": "def index_minimum(tuples_list):\n \"\"\"\n Returns the first value of the tuple with the smallest second value.\n\n Args:\n tuples_list (list): A list of tuples, where each tuple contains a string and an integer.\n\n Returns:\n str: The string value from the tuple with the smallest integer value.\n\n Raises:\n ValueError: If the input list is empty.\n \"\"\"\n if not tuples_list:\n raise ValueError(\"Input list cannot be empty\")\n\n # Find the tuple with the smallest second value\n min_tuple = min(tuples_list, key=lambda x: x[1])\n \n # Return the first value of the tuple\n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(lst):\n \"\"\"\n Returns the first value of the tuple with the smallest second value.\n\n Args:\n lst (list): A list of tuples.\n\n Returns:\n str: The first value of the tuple with the smallest second value.\n \"\"\"\n return min(lst, key=lambda x: x[1])[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(tuples):\n \"\"\"\n Returns the first value of the tuple with the smallest second value.\n \n Args:\n tuples (list): A list of tuples.\n \n Returns:\n The first value of the tuple with the smallest second value.\n \"\"\"\n return min(tuples, key=lambda x: x[1])[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(students):\n \"\"\"\n Returns the first value of the tuple with the smallest second value.\n\n Args:\n students (list): A list of tuples where each tuple contains a student's name and their index.\n\n Returns:\n str: The name of the student with the smallest index.\n \"\"\"\n return min(students, key=lambda x: x[1])[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(lst):\n \"\"\"\n Given a list of tuples, returns the first value of the tuple with the smallest second value.\n \n Args:\n lst (list): A list of tuples where each tuple contains two values.\n \n Returns:\n The first value of the tuple with the smallest second value.\n \"\"\"\n return min(lst, key=lambda x: x[1])[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(tuples_list):\n \"\"\"\n Returns the first value of the tuple with the smallest second value.\n\n Args:\n tuples_list (list): A list of tuples.\n\n Returns:\n The first value of the tuple with the smallest second value.\n \"\"\"\n # Check if the input list is empty\n if not tuples_list:\n raise ValueError(\"Input list is empty\")\n\n # Use the built-in min function with a custom key to find the tuple with the smallest second value\n min_tuple = min(tuples_list, key=lambda x: x[1])\n\n # Return the first value of the tuple with the smallest second value\n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(students):\n \"\"\"\n This function takes a list of tuples as input, where each tuple contains a name and a score.\n It returns the name of the student with the smallest score.\n\n :param students: A list of tuples, where each tuple contains a name and a score.\n :return: The name of the student with the smallest score.\n \"\"\"\n # Check if the list is empty\n if not students:\n return None\n\n # Use the built-in min function with a key to find the tuple with the smallest second value\n # The key is a function that takes a tuple and returns its second value\n # The min function returns the tuple with the smallest second value\n min_student = min(students, key=lambda x: x[1])\n\n # Return the first value of the tuple with the smallest second value\n return min_student[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(tuples_list):\n \"\"\"\n Returns the first value of the tuple with the smallest second value.\n\n Args:\n tuples_list (list): A list of tuples where each tuple contains a string and an integer.\n\n Returns:\n str: The string from the tuple with the smallest integer.\n\n Raises:\n ValueError: If the input list is empty.\n \"\"\"\n if not tuples_list:\n raise ValueError(\"Input list cannot be empty\")\n\n return min(tuples_list, key=lambda x: x[1])[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(lst):\n \"\"\"\n Returns the first value of the tuple with the smallest second value in the list.\n\n Args:\n lst (list): A list of tuples.\n\n Returns:\n The first value of the tuple with the smallest second value.\n \"\"\"\n if not lst:\n raise ValueError(\"List cannot be empty\")\n\n # Use the built-in min function with a custom key to find the tuple with the smallest second value\n # The key is a lambda function that returns the second value of each tuple\n min_tuple = min(lst, key=lambda x: x[1])\n \n # Return the first value of the tuple\n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(tuples):\n \"\"\"\n Returns the first value of the tuple with the smallest second value.\n\n Args:\n tuples: A list of tuples where each tuple contains at least two values.\n\n Returns:\n The first value of the tuple with the smallest second value.\n \"\"\"\n # Check if the list is empty\n if not tuples:\n return None\n\n # Use the built-in min function with a custom key to find the tuple with the smallest second value\n # The key function takes a tuple and returns its second value\n min_tuple = min(tuples, key=lambda x: x[1])\n\n # Return the first value of the tuple with the smallest second value\n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(lst):\n \"\"\"\n Given a list of tuples, returns the first value of the tuple with the smallest second value.\n \n Parameters:\n lst (list): A list of tuples. Each tuple contains a string (name) and an integer (value).\n \n Returns:\n str: The name of the person with the smallest value.\n \"\"\"\n # Check if the list is empty\n if not lst:\n return None\n \n # Use min() with a custom key to find the tuple with the smallest second value\n # The key is a lambda function that returns the second element of a tuple\n min_tuple = min(lst, key=lambda x: x[1])\n \n # Return the first element of the tuple with the smallest second value\n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(lst):\n \"\"\"\n This function returns the first value of the tuple with the smallest second value in a given list of tuples.\n\n Args:\n lst (list): A list of tuples. The second value of each tuple is assumed to be comparable.\n\n Returns:\n The first value of the tuple with the smallest second value.\n \"\"\"\n # Check if the input list is empty\n if not lst:\n raise ValueError(\"Input list cannot be empty\")\n\n # Use the min function with a custom key to find the tuple with the smallest second value\n # The key is a function that returns the second element of a tuple\n min_tuple = min(lst, key=lambda x: x[1])\n\n # Return the first value of the tuple with the smallest second value\n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(tuples_list):\n \"\"\"\n This function takes a list of tuples and returns the first value of the tuple with the smallest second value.\n\n Args:\n tuples_list (list): A list of tuples where each tuple contains two values.\n\n Returns:\n str: The first value of the tuple with the smallest second value.\n \"\"\"\n\n # Check if the input list is empty\n if not tuples_list:\n raise ValueError(\"Input list is empty\")\n\n # Use the built-in min function with a key argument to find the tuple with the smallest second value\n # The key argument specifies a function of one argument that is used to extract a comparison key from each element in the list\n min_tuple = min(tuples_list, key=lambda x: x[1])\n\n # Return the first value of the tuple with the smallest second value\n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(tuples):\n \"\"\"\n Given a list of tuples, returns the first value of the tuple with the smallest second value.\n\n Args:\n tuples (list): A list of tuples where each tuple contains at least two values.\n\n Returns:\n The first value of the tuple with the smallest second value.\n \"\"\"\n # Check if input list is empty\n if not tuples:\n raise ValueError(\"Input list is empty\")\n\n # Use the built-in min function with a key to find the tuple with the smallest second value\n # The key is a lambda function that returns the second value of each tuple\n min_tuple = min(tuples, key=lambda x: x[1])\n\n # Return the first value of the tuple with the smallest second value\n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(students):\n \"\"\"\n This function takes a list of tuples where each tuple contains a student's name and their index value.\n It returns the name of the student with the smallest index value.\n\n Args:\n students (list): A list of tuples containing student information.\n\n Returns:\n str: The name of the student with the smallest index value.\n\n Raises:\n ValueError: If the input list is empty.\n\n Example:\n >>> index_minimum([('Rash', 143), ('Manjeet', 200), ('Varsha', 100)])\n 'Varsha'\n \"\"\"\n if not students:\n raise ValueError(\"Input list is empty\")\n\n # Using min with a custom key function to find the tuple with the smallest second value\n min_student = min(students, key=lambda x: x[1])\n\n # Returning the first element of the tuple (student's name)\n return min_student[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(lst):\n \"\"\"\n Returns the first value of the tuple with the smallest second value from a list of tuples.\n \n Args:\n lst (list): A list of tuples.\n \n Returns:\n The first value of the tuple with the smallest second value.\n \n Raises:\n ValueError: If the input list is empty.\n \"\"\"\n if not lst:\n raise ValueError(\"List cannot be empty\")\n return min(lst, key=lambda x: x[1])[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(students):\n \"\"\"\n This function returns the name of the student with the smallest score.\n\n Args:\n students (list): A list of tuples, each containing a student's name and score.\n\n Returns:\n str: The name of the student with the smallest score.\n \"\"\"\n # Check if the list is empty\n if not students:\n raise ValueError(\"List cannot be empty\")\n\n # Use the min function with a key to find the tuple with the smallest second value\n # The key is a lambda function that returns the second element of a tuple\n # min returns the first tuple it encounters with the smallest second value\n return min(students, key=lambda x: x[1])[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(people):\n \"\"\"\n Given a list of tuples, return the first value of the tuple with the smallest second value.\n \n Args:\n people (list): A list of tuples where the first item is a string and the second item is a number.\n\n Returns:\n str: The first item of the tuple with the smallest second value.\n \"\"\"\n return min(people, key=lambda x: x[1])[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(students):\n \"\"\"\n This function takes a list of tuples as input where the first element in the tuple is the name and the second is the grade.\n It returns the name of the student with the smallest grade.\n\n Args:\n students (list): A list of tuples where the first element is the name of the student and the second is the grade.\n\n Returns:\n str: The name of the student with the smallest grade.\n \"\"\"\n # Check if the input list is empty\n if not students:\n return None\n\n # Use the min function with a custom key to find the tuple with the smallest second value\n # The key argument specifies that we want to compare the tuples based on the second value\n min_student = min(students, key=lambda x: x[1])\n\n # Return the first value of the tuple with the smallest second value\n return min_student[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(tuples_list):\n \"\"\"\n Returns the first value of the tuple with the smallest second value.\n\n Args:\n tuples_list (list): A list of tuples.\n\n Returns:\n str: The first value of the tuple with the smallest second value.\n\n Raises:\n ValueError: If the list of tuples is empty.\n \"\"\"\n if not tuples_list:\n raise ValueError(\"The list of tuples is empty.\")\n\n # Initialize the minimum value and the first value of the tuple with the smallest second value\n min_value = tuples_list[0][1]\n min_first_value = tuples_list[0][0]\n\n # Iterate over the list of tuples\n for tup in tuples_list:\n # Check if the second value of the current tuple is smaller than the current minimum value\n if tup[1] < min_value:\n # Update the minimum value and the first value of the tuple with the smallest second value\n min_value = tup[1]\n min_first_value = tup[0]\n\n return min_first_value", "matching_cluster_idx": 4}]}, "Mbpp/96": {"dps": 64.8611111111111, "dps_norm": 50.714285714285715, "pass@1": 98.0, "profiled": [{"solution": "def divisor(n):\n \"\"\"\n This function calculates the number of divisors of a given integer n.\n \n Parameters:\n n (int): A positive integer for which the divisors are to be calculated.\n \n Returns:\n int: The number of divisors of n.\n \"\"\"\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n: int) -> int:\n \"\"\"\n This function finds the number of divisors for a given integer.\n \n Args:\n n (int): The input integer.\n\n Returns:\n int: The number of divisors.\n \"\"\"\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n \"\"\"\n Return the number of divisors of a given integer.\n \n Parameters:\n n (int): The number to find the divisors of.\n \n Returns:\n int: The number of divisors.\n \"\"\"\n # Initialize the divisor count to 0\n count = 0\n \n # Iterate over all numbers up to n (inclusive)\n for i in range(1, n + 1):\n # Check if the current number is a divisor of n\n if n % i == 0:\n # If it is, increment the divisor count\n count += 1\n \n # Return the total divisor count\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n \"\"\"\n Calculate the number of divisors of a given integer.\n\n Args:\n n (int): The input integer.\n\n Returns:\n int: The number of divisors.\n\n \"\"\"\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n \"\"\"\n Find the number of divisors of a given integer.\n\n Args:\n n (int): The input integer.\n\n Returns:\n int: The number of divisors of the input integer.\n\n Raises:\n ValueError: If the input is not a positive integer.\n \"\"\"\n\n if not isinstance(n, int) or n < 1:\n raise ValueError(\"Input must be a positive integer.\")\n\n # Initialize divisor count\n count = 0\n\n # Iterate through numbers from 1 to n\n for i in range(1, n + 1):\n # Check if n is divisible by i\n if n % i == 0:\n # If it is, increment the divisor count\n count += 1\n\n return count", "matching_cluster_idx": 1}, {"solution": "def divisor(n):\n \"\"\"\n Calculate the number of divisors of a given integer.\n\n Args:\n n (int): The input integer.\n\n Returns:\n int: The number of divisors.\n\n \"\"\"\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n: int) -> int:\n \"\"\"\n Calculate the number of divisors for a given integer.\n\n Args:\n n (int): The input integer.\n\n Returns:\n int: The number of divisors for the given integer.\n\n Raises:\n TypeError: If input is not an integer.\n ValueError: If input integer is less than 1.\n \"\"\"\n\n if not isinstance(n, int):\n raise TypeError(\"Input must be an integer.\")\n\n if n < 1:\n raise ValueError(\"Input integer must be greater than 0.\")\n\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n\n return count", "matching_cluster_idx": 1}, {"solution": "def divisor(n):\n \"\"\"\n Calculate the number of divisors of a given integer.\n \n Args:\n n (int): Input integer.\n \n Returns:\n int: Number of divisors of n.\n \n Raises:\n ValueError: If n is less than 1.\n \"\"\"\n if not isinstance(n, int) or n < 1:\n raise ValueError(\"Input must be an integer greater than 0\")\n \n # Initialize the divisor count with 0\n count = 0\n \n # Check each number up to the square root of n to see if it is a divisor\n for i in range(1, int(n**0.5) + 1):\n # Check if i is a divisor of n\n if n % i == 0:\n # If i is a divisor, then so is n//i\n # If i equals n//i (which occurs for perfect squares), count it only once\n count += 2 if i != n // i else 1\n \n return count", "matching_cluster_idx": 6}, {"solution": "def divisor(n):\n \"\"\"\n Returns the number of divisors of a given integer.\n\n Args:\n n (int): The number to find divisors of.\n\n Returns:\n int: The number of divisors.\n\n \"\"\"\n # Initialize divisor count\n count = 0\n \n # Loop through all possible divisors from 1 to n\n for i in range(1, n + 1):\n # Check if i is a divisor\n if n % i == 0:\n # If it's a divisor, increment count\n count += 1\n \n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n \"\"\"\n This function calculates the number of divisors for a given integer.\n \n Args:\n n (int): A given integer.\n \n Returns:\n int: The number of divisors of n.\n \"\"\"\n # Initialize the count of divisors to 0\n count = 0\n \n # Iterate over all numbers from 1 to n (inclusive)\n for i in range(1, n + 1):\n # Check if i is a divisor of n\n if n % i == 0:\n # If i is a divisor, increment the count\n count += 1\n \n # Return the total count of divisors\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n \"\"\"\n This function calculates the number of divisors for a given integer.\n\n Args:\n n (int): The input number.\n\n Returns:\n int: The number of divisors of n.\n \"\"\"\n count = 0\n for i in range(1, n + 1):\n # If n is divisible by i, increment the count\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def divisor(n):\n \"\"\"\n This function calculates the number of divisors of a given integer.\n\n Args:\n n (int): The number to find divisors for.\n\n Returns:\n int: The number of divisors of n.\n \"\"\"\n # Initialize count of divisors\n count = 0\n \n # Iterate from 1 to n (inclusive) to check for divisors\n for i in range(1, n + 1):\n # Check if i is a divisor of n\n if n % i == 0:\n # If i is a divisor, increment the count\n count += 1\n \n # Return the total count of divisors\n return count", "matching_cluster_idx": 1}, {"solution": "def divisor(n: int) -> int:\n \"\"\"\n Calculate the number of divisors for a given integer n.\n\n Args:\n n (int): The input integer.\n\n Returns:\n int: The number of divisors of n.\n \"\"\"\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n \"\"\"\n This function finds the number of divisors of a given integer n.\n\n Args:\n n (int): The input integer.\n\n Returns:\n int: The number of divisors of n.\n \"\"\"\n if not isinstance(n, int):\n raise TypeError(\"Input must be an integer.\")\n\n # Initialize the divisor count to 0\n count = 0\n \n # We only need to iterate up to the square root of n\n # because a larger factor of the number would be a multiple of smaller factor that has already been accounted for.\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n # If n is a perfect square, only count its square root once.\n if n // i == i:\n count += 1\n else:\n count += 2\n \n return count", "matching_cluster_idx": 6}, {"solution": "def divisor(n):\n \"\"\"\n Returns the number of divisors of a given integer n.\n \n :param n: A non-negative integer.\n :return: The number of divisors of n.\n \"\"\"\n if not isinstance(n, int) or n < 0:\n raise ValueError(\"Input must be a non-negative integer.\")\n \n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n # If n is a perfect square, don't count its square root twice\n if i * i != n:\n count += 2\n else:\n count += 1\n return count", "matching_cluster_idx": 6}, {"solution": "def divisor(n):\n \"\"\"\n Calculate the number of divisors of a given integer.\n\n Args:\n n (int): The number for which to calculate the number of divisors.\n\n Returns:\n int: The number of divisors of n.\n \"\"\"\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n \"\"\"\n This function calculates the number of divisors of a given integer.\n\n Args:\n n (int): A positive integer.\n\n Returns:\n int: The number of divisors of n.\n\n Raises:\n ValueError: If n is not a positive integer.\n \"\"\"\n if not isinstance(n, int) or n <= 0:\n raise ValueError(\"Input must be a positive integer.\")\n\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def divisor(n):\n \"\"\"\n Calculate the number of divisors of a given integer.\n\n Args:\n n (int): The input integer.\n\n Returns:\n int: The number of divisors.\n\n Example:\n >>> divisor(15)\n 4\n \"\"\"\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n \"\"\"\n Returns the number of divisors of a given integer n.\n\n :param n: The input integer.\n :return: The number of divisors of n.\n \"\"\"\n count = 0\n for i in range(1, int(n ** 0.5) + 1):\n if n % i == 0:\n # Check if divisors are different\n # For example, the divisors of 25 are 1, 5, 25 and not 1, 5, 5, 25\n if n // i == i:\n count += 1\n else:\n count += 2\n return count", "matching_cluster_idx": 6}, {"solution": "def divisor(n):\n \"\"\"\n Calculate the number of divisors of a given integer.\n \n Args:\n n (int): The input number.\n \n Returns:\n int: The number of divisors of n.\n \"\"\"\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}]}, "Mbpp/97": {"dps": 77.17948717948718, "dps_norm": 75.0, "pass@1": 100.0, "profiled": [{"solution": "def frequency_lists(lists):\n \"\"\"\n This function calculates the frequency of each element in a flattened list of lists.\n\n Args:\n lists (list): A list of lists.\n\n Returns:\n dict: A dictionary where keys are elements from the list and values are their frequencies.\n\n \"\"\"\n # Flatten the list of lists into a single list\n flat_list = [item for sublist in lists for item in sublist]\n \n # Create a dictionary to store the frequency of each element\n frequency_dict = {}\n \n # Iterate over each element in the flattened list\n for item in flat_list:\n # If the item is already in the dictionary, increment its count\n if item in frequency_dict:\n frequency_dict[item] += 1\n # If the item is not in the dictionary, add it with a count of 1\n else:\n frequency_dict[item] = 1\n \n return frequency_dict", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lists):\n \"\"\"\n Find frequency of each element in a flattened list of lists, returned in a dictionary.\n \n Args:\n lists (list): A list of lists containing elements.\n \n Returns:\n dict: A dictionary with frequency of each element.\n \"\"\"\n # Flatten the list of lists\n flat_list = [item for sublist in lists for item in sublist]\n \n # Create a dictionary with frequency of each element\n frequency = {}\n for item in flat_list:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n \n return frequency", "matching_cluster_idx": 6}, {"solution": "from collections import Counter\ndef frequency_lists(lists):\n \"\"\"\n This function calculates the frequency of each element in a flattened list of lists.\n \n Args:\n lists (list): A list containing sublists of integers.\n\n Returns:\n dict: A dictionary where the keys are the elements in the lists and the values are their frequencies.\n \"\"\"\n # Flatten the list of lists into a single list\n flat_list = [element for sublist in lists for element in sublist]\n \n # Use the Counter class from the collections module to count the frequency of each element\n frequency_dict = Counter(flat_list)\n \n return dict(frequency_dict)", "matching_cluster_idx": 6}, {"solution": "from typing import List\nfrom collections import Counter\ndef frequency_lists(nested_list: List[List[int]]) -> dict:\n \"\"\"\n This function calculates the frequency of each element in a flattened list of lists.\n \n Args:\n nested_list (List[List[int]]): A list of lists containing integers.\n \n Returns:\n dict: A dictionary where keys are the unique integers from the list and values are their frequencies.\n \"\"\"\n # Flatten the list of lists\n flattened_list = [item for sublist in nested_list for item in sublist]\n \n # Create a dictionary to store the frequency of each element\n frequency_dict = {}\n \n # Iterate over the flattened list and update the frequency dictionary\n for item in flattened_list:\n if item in frequency_dict:\n frequency_dict[item] += 1\n else:\n frequency_dict[item] = 1\n \n return frequency_dict", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lists):\n \"\"\"\n This function calculates the frequency of each element in a flattened list of lists.\n\n Args:\n lists (list): A list of lists containing elements.\n\n Returns:\n dict: A dictionary where keys are the unique elements from the input lists\n and values are their frequencies.\n\n Example:\n >>> frequency_lists([[1, 2, 3, 2], [4, 5, 6, 2], [7, 8, 9, 5]])\n {1: 1, 2: 3, 3: 1, 4: 1, 5: 2, 6: 1, 7: 1, 8: 1, 9: 1}\n \"\"\"\n # Flatten the list of lists into a single list\n flat_list = [item for sublist in lists for item in sublist]\n \n # Create a dictionary to store the frequency of each element\n frequency_dict = {}\n \n # Iterate through the flattened list\n for item in flat_list:\n # If the item is already in the dictionary, increment its count\n if item in frequency_dict:\n frequency_dict[item] += 1\n # Otherwise, add the item to the dictionary with a count of 1\n else:\n frequency_dict[item] = 1\n \n return frequency_dict", "matching_cluster_idx": 6}, {"solution": "from collections import Counter\ndef frequency_lists(lists):\n \"\"\"\n Returns a dictionary with the frequency of each element in a flattened list of lists.\n \n Args:\n lists (list): A list of lists containing elements to be counted.\n \n Returns:\n dict: A dictionary where keys are elements from the input lists and values are their corresponding frequencies.\n \"\"\"\n # Flatten the list of lists\n flat_list = [item for sublist in lists for item in sublist]\n \n # Create a dictionary with frequencies of elements using dictionary comprehension\n frequency_dict = {item: flat_list.count(item) for item in set(flat_list)}\n \n return frequency_dict", "matching_cluster_idx": 2}, {"solution": "def frequency_lists(lists):\n \"\"\"\n Find frequency of each element in a flattened list of lists.\n \n Args:\n lists (list): A list of lists.\n \n Returns:\n dict: A dictionary containing the frequency of each element.\n \"\"\"\n # Flatten the list of lists\n flattened_list = [item for sublist in lists for item in sublist]\n \n # Create a dictionary with element frequencies\n freq_dict = {}\n for item in flattened_list:\n if item in freq_dict:\n freq_dict[item] += 1\n else:\n freq_dict[item] = 1\n \n return freq_dict", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lists):\n \"\"\"\n This function calculates the frequency of each element in a flattened list of lists.\n\n Args:\n lists (list of lists): A list of lists containing elements.\n\n Returns:\n dict: A dictionary where keys are the unique elements from the flattened list\n and values are their corresponding frequencies.\n \"\"\"\n # Flatten the list of lists into a single list\n flattened_list = [item for sublist in lists for item in sublist]\n\n # Use dictionary comprehension to calculate frequency of each element\n frequency_dict = {item: flattened_list.count(item) for item in set(flattened_list)}\n\n return frequency_dict", "matching_cluster_idx": 2}, {"solution": "def frequency_lists(lists):\n \"\"\"\n This function calculates the frequency of each element in a flattened list of lists.\n\n Args:\n lists (list): A list of lists containing integers.\n\n Returns:\n dict: A dictionary where keys are the unique elements from the input list and values are their corresponding frequencies.\n\n Example:\n >>> frequency_lists([[1, 2, 3, 2], [4, 5, 6, 2], [7, 8, 9, 5]])\n {1: 1, 2: 3, 3: 1, 4: 1, 5: 2, 6: 1, 7: 1, 8: 1, 9: 1}\n \"\"\"\n # Flatten the list of lists\n flat_list = [element for sublist in lists for element in sublist]\n\n # Calculate the frequency of each element using a dictionary comprehension\n frequency_dict = {element: flat_list.count(element) for element in set(flat_list)}\n\n return frequency_dict", "matching_cluster_idx": 2}, {"solution": "from collections import Counter\nfrom itertools import chain\ndef frequency_lists(lists):\n \"\"\"\n Calculate the frequency of each element in a flattened list of lists.\n\n Args:\n lists (list): A list of lists.\n\n Returns:\n dict: A dictionary with elements as keys and their frequencies as values.\n \"\"\"\n # Flatten the list of lists into a single list\n flat_list = list(chain(*lists))\n \n # Use Counter to count the frequency of each element\n frequency_dict = dict(Counter(flat_list))\n \n return frequency_dict", "matching_cluster_idx": 6}, {"solution": "from collections import Counter\ndef frequency_lists(lists):\n \"\"\"\n This function calculates the frequency of each element in a flattened list of lists.\n \n Args:\n lists (list): A list of lists containing elements.\n \n Returns:\n dict: A dictionary where keys are the elements and values are their frequencies.\n \"\"\"\n # Flatten the list of lists into a single list\n flat_list = [item for sublist in lists for item in sublist]\n \n # Use the Counter class from the collections module to count the frequency of each element\n frequency = Counter(flat_list)\n \n # Convert the Counter object to a dictionary and return it\n return dict(frequency)", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(nested_list):\n \"\"\"\n This function calculates the frequency of each element in a flattened list of lists.\n \n Args:\n nested_list (list): A list of lists containing elements.\n \n Returns:\n dict: A dictionary with elements as keys and their frequencies as values.\n \"\"\"\n # Flatten the nested list\n flattened_list = [item for sublist in nested_list for item in sublist]\n \n # Initialize an empty dictionary to store frequencies\n frequency_dict = {}\n \n # Iterate over each element in the flattened list\n for item in flattened_list:\n # If the item is already in the dictionary, increment its count\n if item in frequency_dict:\n frequency_dict[item] += 1\n # If the item is not in the dictionary, add it with a count of 1\n else:\n frequency_dict[item] = 1\n \n # Return the dictionary\n return frequency_dict", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lists):\n \"\"\"\n This function calculates the frequency of each element in a flattened list of lists.\n\n Args:\n lists (list of lists): A list containing multiple lists of elements.\n\n Returns:\n dict: A dictionary where keys are unique elements and values are their respective frequencies.\n \"\"\"\n # First, we flatten the list of lists into a single list\n flat_list = [item for sublist in lists for item in sublist]\n \n # We use a dictionary comprehension to create a dictionary with frequency of each element\n frequency_dict = {item: flat_list.count(item) for item in set(flat_list)}\n \n return frequency_dict", "matching_cluster_idx": 2}, {"solution": "def frequency_lists(lists):\n \"\"\"\n This function calculates the frequency of each element in a flattened list of lists and returns the result in a dictionary.\n\n Args:\n lists (list): A list of lists containing elements of any type.\n\n Returns:\n dict: A dictionary where keys are the elements from the input lists and values are their corresponding frequencies.\n \"\"\"\n # Flatten the list of lists into a single list\n flattened_list = [element for sublist in lists for element in sublist]\n \n # Create a dictionary to store the frequency of each element\n frequency_dict = {}\n \n # Iterate over the flattened list to calculate the frequency of each element\n for element in flattened_list:\n if element in frequency_dict:\n # If the element is already in the dictionary, increment its count\n frequency_dict[element] += 1\n else:\n # If the element is not in the dictionary, add it with a count of 1\n frequency_dict[element] = 1\n \n return frequency_dict", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lists):\n \"\"\"\n Calculate the frequency of each element in a flattened list of lists.\n\n Args:\n lists (list): A list of lists containing elements.\n\n Returns:\n dict: A dictionary where keys are elements from the lists and values are their frequencies.\n \"\"\"\n # Flatten the list of lists using a list comprehension\n flattened_list = [item for sublist in lists for item in sublist]\n\n # Create a dictionary to store the frequency of each element\n frequency_dict = {}\n\n # Iterate over the flattened list and count the frequency of each element\n for item in flattened_list:\n if item in frequency_dict:\n frequency_dict[item] += 1\n else:\n frequency_dict[item] = 1\n\n return frequency_dict", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lists):\n \"\"\"\n This function calculates the frequency of each element in a flattened list of lists.\n\n Args:\n lists (list): A list of lists containing elements.\n\n Returns:\n dict: A dictionary where keys are elements and values are their respective frequencies.\n \"\"\"\n # Flatten the list of lists into a single list\n flattened_list = [element for sublist in lists for element in sublist]\n \n # Use dictionary comprehension to calculate the frequency of each element\n frequency_dict = {element: flattened_list.count(element) for element in set(flattened_list)}\n \n return frequency_dict", "matching_cluster_idx": 2}, {"solution": "from collections import Counter\nfrom typing import List, Dict\ndef frequency_lists(lists: List[List[int]]) -> Dict[int, int]:\n \"\"\"\n This function takes a list of lists as input and returns a dictionary where keys are elements from the lists \n and values are their corresponding frequencies.\n\n Args:\n lists (List[List[int]]): A list of lists containing integers.\n\n Returns:\n Dict[int, int]: A dictionary with element frequencies.\n \"\"\"\n # Flatten the list of lists into one list\n flattened_list = [element for sublist in lists for element in sublist]\n \n # Count the frequency of each element in the flattened list\n frequency_dict = dict(Counter(flattened_list))\n \n return frequency_dict", "matching_cluster_idx": 6}, {"solution": "from collections import Counter\ndef frequency_lists(lists):\n \"\"\"\n This function finds the frequency of each element in a flattened list of lists.\n\n Args:\n lists (list): A list of lists containing elements.\n\n Returns:\n dict: A dictionary with elements as keys and their frequencies as values.\n\n Example:\n >>> frequency_lists([[1, 2, 3, 2], [4, 5, 6, 2], [7, 8, 9, 5]])\n {1: 1, 2: 3, 3: 1, 4: 1, 5: 2, 6: 1, 7: 1, 8: 1, 9: 1}\n \"\"\"\n frequency_dict = {}\n \n # Flatten the list of lists\n flat_list = [item for sublist in lists for item in sublist]\n \n # Iterate through the flattened list and update the frequency dictionary\n for item in flat_list:\n if item in frequency_dict:\n frequency_dict[item] += 1\n else:\n frequency_dict[item] = 1\n \n return frequency_dict", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lists):\n \"\"\"\n This function finds the frequency of each element in a flattened list of lists.\n \n Args:\n lists (list): A list of lists containing elements.\n \n Returns:\n dict: A dictionary where keys are elements from the lists and values are their frequencies.\n \"\"\"\n # Flatten the list of lists into a single list\n flat_list = [item for sublist in lists for item in sublist]\n \n # Create an empty dictionary to store the frequency of each element\n freq_dict = {}\n \n # Iterate over each element in the flattened list\n for element in flat_list:\n # If the element is already in the dictionary, increment its count\n if element in freq_dict:\n freq_dict[element] += 1\n # If the element is not in the dictionary, add it with a count of 1\n else:\n freq_dict[element] = 1\n \n # Return the dictionary with element frequencies\n return freq_dict", "matching_cluster_idx": 6}, {"solution": "from itertools import chain\ndef frequency_lists(nested_list):\n \"\"\"\n This function finds the frequency of each element in a flattened list of lists.\n \n Args:\n nested_list (list): A list of lists containing elements.\n \n Returns:\n dict: A dictionary where keys are the unique elements from the lists and values are their frequencies.\n \"\"\"\n # Initialize an empty dictionary to store the frequency of elements.\n frequency_dict = {}\n \n # Iterate over each sublist in the nested list.\n for sublist in nested_list:\n # Iterate over each element in the sublist.\n for element in sublist:\n # If the element is already in the dictionary, increment its count by 1.\n if element in frequency_dict:\n frequency_dict[element] += 1\n # If the element is not in the dictionary, add it with a count of 1.\n else:\n frequency_dict[element] = 1\n \n return frequency_dict", "matching_cluster_idx": 6}]}, "Mbpp/106": {"dps": 84.90259740259741, "dps_norm": 95.83333333333333, "pass@1": 100.0, "profiled": [{"solution": "def add_lists(input_list, input_tuple):\n \"\"\"\n This function appends a given list to a given tuple.\n \n Args:\n input_list (list): The list that will be appended to the tuple.\n input_tuple (tuple): The tuple that the list will be appended to.\n \n Returns:\n tuple: A new tuple with the list appended to the tuple.\n \"\"\"\n # Convert the tuple to a list because tuples are immutable\n list_from_tuple = list(input_tuple)\n \n # Append the input list to the new list\n list_from_tuple.extend(input_list)\n \n # Convert the list back to a tuple before returning\n return tuple(list_from_tuple)", "matching_cluster_idx": 4}, {"solution": "def add_lists(lst, tup):\n \"\"\"\n Appends the given list to the given tuple.\n\n Args:\n lst (list): The list to be appended.\n tup (tuple): The tuple to be appended to.\n\n Returns:\n tuple: A new tuple with the list elements appended to the original tuple.\n \"\"\"\n return tup + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tup):\n \"\"\"\n Appends the given list to the given tuple.\n\n Args:\n lst (list): The list to be appended.\n tup (tuple): The tuple to append to.\n\n Returns:\n tuple: A new tuple containing all elements from the tuple and the list.\n \"\"\"\n return tup + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tup):\n \"\"\"\n This function appends the given list to the given tuple.\n \n Parameters:\n lst (list): The list to be appended\n tup (tuple): The tuple to append to\n \n Returns:\n tuple: A new tuple that contains all elements from the original tuple and the list\n \"\"\"\n return tup + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tup):\n \"\"\"\n Append the given list to the given tuples.\n \n Parameters:\n lst (list): The list to be appended.\n tup (tuple): The tuple to which the list is appended.\n \n Returns:\n tuple: The resulting tuple after appending the list.\n \"\"\"\n return tup + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tup):\n \"\"\"\n Appends the given list to the given tuple.\n\n Args:\n lst (list): The list to be appended.\n tup (tuple): The tuple to which the list will be appended.\n\n Returns:\n tuple: A new tuple that contains elements from the original tuple and the list.\n \"\"\"\n return tup + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tup):\n \"\"\"\n This function takes a list and a tuple as input and returns a new tuple with \n the elements of the tuple followed by the elements of the list.\n\n Args:\n lst (list): A list of elements to be appended to the tuple.\n tup (tuple): The initial tuple.\n\n Returns:\n tuple: A new tuple with the elements of the tuple followed by the elements of the list.\n \"\"\"\n return tup + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tup):\n \"\"\"\n Appends the given list to the given tuple.\n \n Args:\n lst (list): The list to be appended.\n tup (tuple): The tuple to which the list is appended.\n \n Returns:\n tuple: A new tuple with the list appended.\n \"\"\"\n # Convert the tuple to a list to enable append operation\n new_list = list(tup)\n \n # Extend the list with the given list\n new_list.extend(lst)\n \n # Convert the list back to a tuple and return\n return tuple(new_list)", "matching_cluster_idx": 4}, {"solution": "def add_lists(input_list, input_tuple):\n \"\"\"\n Append the given list to the given tuple.\n\n Args:\n input_list (list): The list to be appended.\n input_tuple (tuple): The tuple to which the list is appended.\n\n Returns:\n tuple: The tuple with the list appended.\n \"\"\"\n # Convert the tuple to a list to enable append operation\n list_tuple = list(input_tuple)\n \n # Extend the list with the input list\n list_tuple.extend(input_list)\n \n # Convert the list back to a tuple and return it\n return tuple(list_tuple)", "matching_cluster_idx": 4}, {"solution": "def add_lists(given_list, given_tuple):\n \"\"\"\n This function appends the given list to the given tuple.\n\n Args:\n given_list (list): The list to be appended.\n given_tuple (tuple): The tuple to which the list will be appended.\n\n Returns:\n tuple: A new tuple that contains elements of the original tuple followed by the elements of the given list.\n \"\"\"\n return given_tuple + tuple(given_list)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tup):\n \"\"\"\n Appends the given list to the given tuple.\n\n Args:\n lst (list): A list of elements to append.\n tup (tuple): A tuple of elements.\n\n Returns:\n tuple: A tuple containing all elements from the given tuple and list.\n \"\"\"\n return tup + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tup):\n \"\"\"\n This function appends the given list to the given tuple.\n\n Args:\n lst (list): The list that will be appended.\n tup (tuple): The tuple to be appended to.\n\n Returns:\n tuple: A new tuple with elements from the original tuple and the given list.\n \"\"\"\n return tup + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tup):\n \"\"\"\n Appends the given list to the given tuple.\n\n Args:\n lst (list): The list to be appended.\n tup (tuple): The tuple to which the list will be appended.\n\n Returns:\n tuple: A new tuple with the list elements appended to the given tuple.\n \"\"\"\n return tup + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tup):\n \"\"\"\n Appends the given list to the given tuple.\n\n Args:\n lst (list): List of elements to be appended.\n tup (tuple): Tuple to which the list is to be appended.\n\n Returns:\n tuple: Resulting tuple with the list elements appended.\n \"\"\"\n # Convert the tuple to a list to allow appending\n temp_list = list(tup)\n \n # Extend the temporary list with the given list\n temp_list.extend(lst)\n \n # Convert the list back to a tuple\n result_tup = tuple(temp_list)\n \n return result_tup", "matching_cluster_idx": 4}, {"solution": "def add_lists(lst, tup):\n \"\"\"\n Appends the given list to the given tuple.\n \n Args:\n lst (list): The list to be appended.\n tup (tuple): The tuple to be appended to.\n \n Returns:\n tuple: A new tuple containing all elements from the input tuple and list.\n \"\"\"\n return tup + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tup):\n \"\"\"\n This function appends a given list to a given tuple.\n\n Args:\n lst (list): The list to be appended.\n tup (tuple): The tuple to which the list is to be appended.\n\n Returns:\n tuple: A new tuple that contains all the elements from the original tuple and list.\n \"\"\"\n return tup + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tup):\n \"\"\"\n Appends the given list to the given tuple.\n\n Args:\n lst (list): The list to be appended.\n tup (tuple): The tuple to which the list is appended.\n\n Returns:\n tuple: A new tuple with the list appended to the original tuple.\n \"\"\"\n # Convert the tuple to a list to make it mutable\n lst_tup = list(tup)\n \n # Extend the list with the given list\n lst_tup.extend(lst)\n \n # Convert the list back to a tuple and return it\n return tuple(lst_tup)", "matching_cluster_idx": 4}, {"solution": "def add_lists(lst, tup):\n \"\"\"\n Appends the given list to the given tuple.\n\n Args:\n lst (list): List to append.\n tup (tuple): Tuple to append the list to.\n\n Returns:\n tuple: New tuple containing elements from both the original tuple and the list.\n \"\"\"\n return tup + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tup):\n \"\"\"\n Appends the given list to the given tuple.\n\n Args:\n lst (list): The list to be appended.\n tup (tuple): The tuple to which the list will be appended.\n\n Returns:\n tuple: A new tuple with the elements of the list appended to the tuple.\n\n Examples:\n >>> add_lists([5, 6, 7], (9, 10))\n (9, 10, 5, 6, 7)\n \"\"\"\n return tup + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tup):\n \"\"\"\n Appends the given list to the given tuple.\n\n Args:\n lst (list): The list to be appended.\n tup (tuple): The tuple to which the list is to be appended.\n\n Returns:\n tuple: A new tuple that contains all elements of the original tuple, followed by all elements of the list.\n \"\"\"\n return tup + tuple(lst)", "matching_cluster_idx": 5}]}, "Mbpp/108": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 80.0, "profiled": [{"solution": "def merge_sorted_list(list1, list2, list3):\n \"\"\"\n Merge three lists into a single sorted list.\n\n Args:\n list1 (list): The first list to be merged.\n list2 (list): The second list to be merged.\n list3 (list): The third list to be merged.\n\n Returns:\n list: A single sorted list containing all elements from the input lists.\n\n Example:\n >>> merge_sorted_list([25, 24, 15, 4, 5, 29, 110],[19, 20, 11, 56, 25, 233, 154],[24, 26, 54, 48])\n [4, 5, 11, 15, 19, 20, 24, 24, 25, 25, 26, 29, 48, 54, 56, 110, 154, 233]\n \"\"\"\n\n # Combine all three lists into one\n merged_list = list1 + list2 + list3\n\n # Sort the combined list in ascending order\n merged_list.sort()\n\n return merged_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n \"\"\"\n Merge three lists into a single sorted list.\n \n Args:\n list1 (list): The first list.\n list2 (list): The second list.\n list3 (list): The third list.\n \n Returns:\n list: A sorted list containing all elements from the input lists.\n \"\"\"\n # Combine all lists into one list\n merged_list = list1 + list2 + list3\n \n # Sort the combined list in ascending order\n merged_list.sort()\n \n return merged_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n \"\"\"\n This function merges three lists into a single sorted list.\n\n Args:\n list1 (list): The first list of numbers\n list2 (list): The second list of numbers\n list3 (list): The third list of numbers\n\n Returns:\n list: A sorted list of numbers\n \"\"\"\n # Merge three lists into one\n merged_list = list1 + list2 + list3\n\n # Sort the merged list in ascending order\n sorted_list = sorted(merged_list)\n\n return sorted_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n \"\"\"\n This function merges three lists into a single sorted list.\n \n Args:\n list1 (list): The first list of integers.\n list2 (list): The second list of integers.\n list3 (list): The third list of integers.\n \n Returns:\n list: A single sorted list containing all elements from the input lists.\n \"\"\"\n # Combine the three lists into one\n combined_list = list1 + list2 + list3\n \n # Sort the combined list in ascending order\n sorted_list = sorted(combined_list)\n \n return sorted_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n \"\"\"\n Merge three lists into a single sorted list.\n\n Args:\n list1 (list): The first list to merge.\n list2 (list): The second list to merge.\n list3 (list): The third list to merge.\n\n Returns:\n list: A new sorted list containing all elements from the input lists.\n\n Example:\n >>> merge_sorted_list([25, 24, 15, 4, 5, 29, 110],[19, 20, 11, 56, 25, 233, 154],[24, 26, 54, 48])\n [4, 5, 11, 15, 19, 20, 24, 24, 25, 25, 26, 29, 48, 54, 56, 110, 154, 233]\n \"\"\"\n return sorted(list1 + list2 + list3)", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n \"\"\"\n Merge three lists into a single sorted list.\n\n Args:\n list1 (list): The first list to merge.\n list2 (list): The second list to merge.\n list3 (list): The third list to merge.\n\n Returns:\n list: A single sorted list containing all elements from the input lists.\n\n \"\"\"\n # Combine all three lists into a single list\n merged_list = list1 + list2 + list3\n \n # Sort the merged list in ascending order\n merged_list.sort()\n \n # Return the sorted list\n return merged_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n \"\"\"\n This function merges three lists into a single sorted list.\n \n Args:\n list1 (list): First list of numbers\n list2 (list): Second list of numbers\n list3 (list): Third list of numbers\n \n Returns:\n list: A single sorted list containing all elements from the input lists\n \"\"\"\n # Combine the three lists into one\n combined_list = list1 + list2 + list3\n \n # Sort the combined list in ascending order\n combined_list.sort()\n \n # Return the sorted list\n return combined_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n \"\"\"\n This function merges three lists into a single sorted list.\n\n Args:\n list1 (list): The first list.\n list2 (list): The second list.\n list3 (list): The third list.\n\n Returns:\n list: A single sorted list containing all elements from the input lists.\n\n Example:\n merge_sorted_list([25, 24, 15, 4, 5, 29, 110],[19, 20, 11, 56, 25, 233, 154],[24, 26, 54, 48])\n \"\"\"\n # Merge the three lists into one\n merged_list = list1 + list2 + list3\n \n # Sort the merged list in ascending order\n merged_list.sort()\n\n return merged_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n \"\"\"\n Merge three lists into a single sorted list.\n\n Args:\n list1 (list): The first list.\n list2 (list): The second list.\n list3 (list): The third list.\n\n Returns:\n list: A new sorted list containing all elements from the input lists.\n\n \"\"\"\n # Combine the three lists\n combined_list = list1 + list2 + list3\n \n # Sort the combined list in ascending order\n sorted_list = sorted(combined_list)\n \n # Return the sorted list\n return sorted_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n \"\"\"\n Merge three unsorted lists into a single sorted list.\n\n Args:\n list1 (list): The first list.\n list2 (list): The second list.\n list3 (list): The third list.\n\n Returns:\n list: A single sorted list containing elements from all input lists.\n \"\"\"\n # Combine all three lists\n merged_list = list1 + list2 + list3\n \n # Sort the combined list\n merged_list.sort()\n \n # Return the sorted list\n return merged_list\nlist1 = [25, 24, 15, 4, 5, 29, 110]\nlist2 = [19, 20, 11, 56, 25, 233, 154]\nlist3 = [24, 26, 54, 48]", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n \"\"\"\n Merges three lists into a single sorted list.\n \n Args:\n list1 (list): The first list to be merged.\n list2 (list): The second list to be merged.\n list3 (list): The third list to be merged.\n \n Returns:\n list: A new sorted list that contains all elements from the input lists.\n \"\"\"\n # Combine all three lists into one\n combined_list = list1 + list2 + list3\n \n # Sort the combined list\n combined_list.sort()\n \n # Return the sorted list\n return combined_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n \"\"\"\n Merge three lists into a single sorted list.\n \n Args:\n list1 (list): The first list to be merged.\n list2 (list): The second list to be merged.\n list3 (list): The third list to be merged.\n \n Returns:\n list: A single sorted list containing all elements from the input lists.\n \"\"\"\n # Combine all lists into a single list\n combined_list = list1 + list2 + list3\n \n # Sort the combined list\n sorted_list = sorted(combined_list)\n \n return sorted_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n \"\"\"\n Merge three lists into a single sorted list.\n\n Args:\n list1 (list): The first list.\n list2 (list): The second list.\n list3 (list): The third list.\n\n Returns:\n list: A single sorted list containing all elements from the input lists.\n \"\"\"\n # Combine all three lists\n merged_list = list1 + list2 + list3\n \n # Sort the combined list in ascending order\n merged_list.sort()\n \n return merged_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n \"\"\"\n This function merges three lists into a single sorted list.\n\n Args:\n list1 (list): The first list to be merged.\n list2 (list): The second list to be merged.\n list3 (list): The third list to be merged.\n\n Returns:\n list: A new sorted list containing all elements from the input lists.\n\n \"\"\"\n # Combine all three lists into one\n merged_list = list1 + list2 + list3\n \n # Sort the merged list in ascending order\n merged_list.sort()\n \n # Return the sorted merged list\n return merged_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n \"\"\"\n Merge three lists into a single sorted list.\n\n Args:\n list1 (list): The first list of numbers.\n list2 (list): The second list of numbers.\n list3 (list): The third list of numbers.\n\n Returns:\n list: A single sorted list containing all numbers from input lists.\n \"\"\"\n # Combine the three lists into one\n merged_list = list1 + list2 + list3\n \n # Sort the merged list in ascending order\n merged_list.sort()\n \n return merged_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n \"\"\"\n Merge three lists into a single sorted list.\n \n Args:\n list1 (list): The first list of numbers.\n list2 (list): The second list of numbers.\n list3 (list): The third list of numbers.\n \n Returns:\n list: A single sorted list containing all numbers from input lists.\n \"\"\"\n # Combine all three lists\n combined_list = list1 + list2 + list3\n \n # Sort the combined list\n sorted_list = sorted(combined_list)\n \n return sorted_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n \"\"\"\n This function merges three lists into a single sorted list.\n \n Args:\n list1 (list): The first list to be merged.\n list2 (list): The second list to be merged.\n list3 (list): The third list to be merged.\n \n Returns:\n list: A new sorted list that is a result of the merge operation.\n \"\"\"\n # Merge three lists into a single list\n merged_list = list1 + list2 + list3\n \n # Sort the merged list in ascending order\n sorted_list = sorted(merged_list)\n \n # Return the sorted list\n return sorted_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n \"\"\"\n This function merges three lists into a single sorted list.\n\n Args:\n list1 (list): The first list to merge.\n list2 (list): The second list to merge.\n list3 (list): The third list to merge.\n\n Returns:\n list: A new list containing all elements from the input lists, sorted in ascending order.\n \"\"\"\n # Combine the three lists into a single list\n merged_list = list1 + list2 + list3\n \n # Sort the merged list in ascending order\n merged_list.sort()\n \n return merged_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n \"\"\"\n This function merges three lists into a single sorted list.\n \n Args:\n list1 (list): The first list to be merged.\n list2 (list): The second list to be merged.\n list3 (list): The third list to be merged.\n \n Returns:\n list: A new sorted list that contains elements from list1, list2, and list3.\n \"\"\"\n # Combine the three lists\n combined_list = list1 + list2 + list3\n \n # Sort the combined list\n sorted_list = sorted(combined_list)\n \n return sorted_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n \"\"\"\n This function merges three lists into a single sorted list.\n \n Args:\n list1 (list): The first list to be merged.\n list2 (list): The second list to be merged.\n list3 (list): The third list to be merged.\n \n Returns:\n list: A single sorted list containing elements from list1, list2, and list3.\n \"\"\"\n # Combine the three lists into a single list\n merged_list = list1 + list2 + list3\n \n # Sort the combined list in ascending order\n merged_list.sort()\n \n return merged_list", "matching_cluster_idx": 10}]}, "Mbpp/111": {"dps": 59.10769230769231, "dps_norm": 77.5, "pass@1": 94.0, "profiled": [{"solution": "def common_in_nested_lists(nested_lists):\n \"\"\"\n Finds the common elements in given nested lists.\n\n Args:\n nested_lists (list): A list of lists containing integers.\n\n Returns:\n list: A list of common integers across all nested lists.\n \"\"\"\n # Check if input is a list of lists\n if not all(isinstance(lst, list) for lst in nested_lists):\n raise ValueError(\"Input must be a list of lists\")\n \n # Check if input is not empty\n if len(nested_lists) == 0:\n raise ValueError(\"Input cannot be empty\")\n \n # Initialize a set with elements from the first list for efficient lookups\n common_elements = set(nested_lists[0])\n \n # Iterate over the remaining nested lists\n for lst in nested_lists[1:]:\n # Update the set of common elements by intersecting it with the current list\n common_elements &= set(lst)\n \n # Convert the set of common elements back to a list\n return list(common_elements)", "matching_cluster_idx": 5}, {"solution": "def common_in_nested_lists(nested_lists):\n \"\"\"\n This function finds the common elements in given nested lists.\n\n Args:\n nested_lists (list): A list of lists containing integers.\n\n Returns:\n set: A set of common elements found in all nested lists.\n \"\"\"\n # Check if input list is empty\n if not nested_lists:\n return set()\n\n # Convert all sublists to sets for efficient lookups\n sets = [set(sublist) for sublist in nested_lists]\n\n # Find the intersection of all sets, which represents common elements\n common_elements = set.intersection(*sets)\n\n return common_elements", "matching_cluster_idx": 5}, {"solution": "def common_in_nested_lists(nested_lists):\n \"\"\"\n This function finds the common elements in given nested lists.\n\n Args:\n nested_lists (list): A list of lists containing elements to compare.\n\n Returns:\n list: A list of elements common to all inner lists.\n \"\"\"\n # Convert the first inner list to a set\n common_elements = set(nested_lists[0])\n\n # Iterate over the remaining inner lists\n for inner_list in nested_lists[1:]:\n # Update the common_elements set with the intersection of the current set and the inner list converted to a set\n common_elements &= set(inner_list)\n\n # Return the common elements as a list\n return list(common_elements)", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n \"\"\"\n Finds common elements among all nested lists.\n\n Args:\n nested_lists (list): A list containing nested lists of elements.\n\n Returns:\n list: A list of common elements found in all nested lists.\n \"\"\"\n # If the input list is empty, return an empty list\n if not nested_lists:\n return []\n\n # Initialize common elements with the first list in the nested lists\n common_elements = set(nested_lists[0])\n \n # Iterate over the remaining lists in the nested lists\n for lst in nested_lists[1:]:\n # Update common elements by intersecting with the current list\n common_elements = common_elements.intersection(set(lst))\n\n # Return the common elements as a list\n return list(common_elements)", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n \"\"\"\n This function finds the common elements in given nested lists.\n\n Args:\n nested_lists (list): A list of lists containing integers.\n\n Returns:\n set: A set of common elements found in all nested lists.\n \"\"\"\n\n # First, we check if the input list is empty\n if not nested_lists:\n return set()\n\n # We initialize our set of common elements with the first sublist\n common_elements = set(nested_lists[0])\n\n # Then we iterate over the rest of the sublists\n for lst in nested_lists[1:]:\n # For each sublist, we update our common_elements set to include only elements that are present in both the current sublist and the current common_elements set\n common_elements &= set(lst)\n\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n \"\"\"\n This function finds common elements in given nested lists.\n\n Args:\n nested_lists (list): A list of lists containing integers.\n\n Returns:\n set: A set of common elements in all nested lists.\n \"\"\"\n # Check if the input is a list of lists\n if not all(isinstance(lst, list) for lst in nested_lists):\n raise TypeError(\"Input must be a list of lists\")\n\n # Convert each sublist to a set for efficient lookups\n set_lists = [set(lst) for lst in nested_lists]\n \n # Find the common elements in all sets\n common_elements = set_lists[0]\n for s in set_lists[1:]:\n common_elements = common_elements.intersection(s)\n\n return common_elements", "matching_cluster_idx": 5}, {"solution": "def common_in_nested_lists(nested_lists):\n \"\"\"\n This function finds the common elements in given nested lists.\n\n Args:\n nested_lists (list): A list of lists containing integers.\n\n Returns:\n list: A list of integers that are common to all nested lists.\n\n \"\"\"\n # First, we check if the input is a list and if it contains at least one nested list\n if not isinstance(nested_lists, list) or len(nested_lists) < 1 or not all(isinstance(lst, list) for lst in nested_lists):\n raise ValueError(\"Input must be a list of lists\")\n\n # We initialize the set of common elements with the elements of the first nested list\n common_elements = set(nested_lists[0])\n \n # Then, we iterate over the remaining nested lists\n for lst in nested_lists[1:]:\n # For each list, we update the set of common elements by keeping only the elements that are present in both the current set and the current list\n common_elements &= set(lst)\n \n # Finally, we return the list of common elements\n return list(common_elements)", "matching_cluster_idx": 5}, {"solution": "def common_in_nested_lists(nested_lists):\n \"\"\"\n This function finds the common elements in given nested lists.\n\n Args:\n nested_lists (list): A list of lists containing integers.\n\n Returns:\n set: A set of common elements in the given nested lists.\n \"\"\"\n # Find the smallest list in the nested lists to optimize the lookup process\n smallest_list = min(nested_lists, key=len)\n \n # Initialize the set of common elements with the smallest list\n common_elements = set(smallest_list)\n \n # Iterate over the remaining lists to find the intersection\n for lst in nested_lists:\n if lst is not smallest_list:\n common_elements &= set(lst)\n \n return common_elements", "matching_cluster_idx": 5}, {"solution": "def common_in_nested_lists(lists):\n \"\"\"\n This function finds the common elements in given nested lists.\n\n Args:\n lists (list): A list of lists containing integers.\n\n Returns:\n set: A set of common elements found in all sub-lists.\n \"\"\"\n # Check if input list is empty\n if not lists:\n return set()\n \n # Initialize common elements set with the first list\n common = set(lists[0])\n \n # Iterate through the rest of the lists and update the common elements set\n for lst in lists[1:]:\n common &= set(lst)\n \n return common", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n \"\"\"\n Finds common elements in multiple nested lists.\n\n Args:\n nested_lists (list): A list of lists containing elements.\n\n Returns:\n set: A set of common elements.\n \"\"\"\n # Base case for recursion: if only one list remains, return its elements as a set\n if len(nested_lists) == 1:\n return set(nested_lists[0])\n \n # Recursive case: Find common elements between the first list and the common elements in the remaining lists\n else:\n first_list = set(nested_lists[0])\n common_in_remaining_lists = common_in_nested_lists(nested_lists[1:])\n return first_list.intersection(common_in_remaining_lists)", "matching_cluster_idx": -1}, {"solution": "def common_in_nested_lists(nested_lists):\n \"\"\"\n This function finds the common elements in the given nested lists.\n \n Args:\n nested_lists (list): A list of lists containing integers.\n \n Returns:\n list: A list of integers common to all nested lists.\n \"\"\"\n # Check if the input is a list of lists\n if not all(isinstance(lst, list) for lst in nested_lists):\n raise ValueError(\"Input must be a list of lists\")\n \n # Find the intersection of all lists using set intersection\n common = set(nested_lists[0])\n for lst in nested_lists[1:]:\n common.intersection_update(set(lst))\n \n return list(common)", "matching_cluster_idx": 5}, {"solution": "def common_in_nested_lists(nested_lists):\n \"\"\"\n Returns a set of elements common in all nested lists.\n\n Args:\n nested_lists (list): A list of lists containing integers.\n\n Returns:\n set: A set of integers common to all nested lists.\n \"\"\"\n\n # Convert the first list to a set\n common = set(nested_lists[0])\n\n # Iterate over the rest of the lists\n for nested_list in nested_lists[1:]:\n # Update the common set with the intersection of the current common set and the current list\n common &= set(nested_list)\n\n return common", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n \"\"\"\n This function finds the common elements in given nested lists.\n \n Args:\n nested_lists (list of lists): A list of lists containing elements.\n \n Returns:\n set: A set of common elements among all nested lists.\n \"\"\"\n # If the input list is empty, return an empty set\n if not nested_lists:\n return set()\n \n # Initialize the set of common elements with the elements from the first list\n common_elements = set(nested_lists[0])\n \n # Iterate over the remaining lists\n for lst in nested_lists[1:]:\n # Update the common elements by keeping only the elements present in both the current list and the previous common elements\n common_elements &= set(lst)\n \n return common_elements", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(lists):\n \"\"\"\n This function finds the common elements in the given nested lists.\n\n Args:\n lists (list): A list of lists containing integers.\n\n Returns:\n list: A list of integers that are common to all inner lists.\n\n Example:\n >>> common_in_nested_lists([[12, 18, 23, 25, 45], [7, 12, 18, 24, 28], [1, 5, 8, 12, 15, 16, 18]])\n [12, 18]\n \"\"\"\n # Check if input is a list\n if not isinstance(lists, list):\n raise TypeError(\"Input must be a list\")\n\n # Check if input list is not empty\n if len(lists) == 0:\n return []\n\n # Check if all elements in the input list are lists\n if not all(isinstance(sublist, list) for sublist in lists):\n raise TypeError(\"All elements in the input list must be lists\")\n\n # Convert all inner lists to sets for efficient lookups\n set_lists = [set(sublist) for sublist in lists]\n\n # Find the intersection of all sets (i.e., the common elements)\n common_elements = set.intersection(*set_lists)\n\n # Convert the result back to a list and return it\n return list(common_elements)", "matching_cluster_idx": 5}, {"solution": "def common_in_nested_lists(nested_lists):\n \"\"\"\n This function takes a list of lists as input and returns a set of common elements.\n\n Args:\n nested_lists (list): A list of lists containing integers.\n\n Returns:\n set: A set of common elements found in all sublists.\n\n Raises:\n ValueError: If the input is not a list of lists.\n \"\"\"\n # Check if input is a list of lists\n if not all(isinstance(sublist, list) for sublist in nested_lists):\n raise ValueError(\"Input must be a list of lists\")\n\n # Use set intersection to find common elements\n # The set intersection operation (&) returns a set with elements common to set and the set of elements for which the function was invoked\n common_elements = set(nested_lists[0])\n for sublist in nested_lists[1:]:\n common_elements &= set(sublist)\n\n return common_elements", "matching_cluster_idx": 5}, {"solution": "def common_in_nested_lists(nested_lists):\n \"\"\"\n This function finds the common elements in the given nested lists.\n\n Args:\n nested_lists (list): A list of lists containing elements.\n\n Returns:\n set: A set of common elements found in the nested lists.\n \"\"\"\n # Check if the input list is empty\n if not nested_lists:\n return set()\n\n # Initialize a set with the elements from the first sublist\n common_elements = set(nested_lists[0])\n\n # Iterate through the remaining sublists\n for sublist in nested_lists[1:]:\n # Update the common_elements set to include only elements common with the current sublist\n common_elements &= set(sublist)\n\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(lists):\n \"\"\"\n This function finds the common elements in given nested lists.\n\n Args:\n lists (list): A list of lists containing integers.\n\n Returns:\n set: A set of common elements.\n \"\"\"\n # Find the smallest list to reduce the number of iterations\n smallest_list = min(lists, key=len)\n \n common = set(smallest_list)\n # Iterate over the remaining lists\n for lst in lists:\n if lst != smallest_list:\n # Update the common set to include only elements present in both the common set and the current list\n common &= set(lst)\n \n return common", "matching_cluster_idx": 5}, {"solution": "def common_in_nested_lists(nested_lists):\n \"\"\"\n This function finds the common elements in given nested lists.\n\n Args:\n nested_lists (list of lists): A list of lists containing elements.\n\n Returns:\n list: A list of common elements found in all nested lists.\n \"\"\"\n # Convert the first list to a set to remove duplicates and for efficient lookups\n common_elements = set(nested_lists[0])\n\n # Iterate over the remaining lists\n for nested_list in nested_lists[1:]:\n # Update the common_elements set by keeping only the elements present in both common_elements and the current list\n common_elements &= set(nested_list)\n\n # Return the common elements as a list\n return list(common_elements)", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n \"\"\"\n Finds the common elements in given nested lists.\n \n Args:\n nested_lists (list): A list of lists containing integers.\n\n Returns:\n list: A list of common elements in all nested lists.\n \"\"\"\n # Convert the first list to a set for efficient lookups\n common_elements = set(nested_lists[0])\n \n # Iterate over the rest of the lists\n for lst in nested_lists[1:]:\n # Update common_elements to include only elements present in the current list\n common_elements &= set(lst)\n \n # Convert the set back to a list and return it\n return list(common_elements)", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n \"\"\"\n This function finds the common elements in given nested lists.\n\n Args:\n nested_lists (list): A list of lists.\n\n Returns:\n list: A list of elements common to all sublists.\n\n Raises:\n ValueError: If the input list is empty.\n \"\"\"\n if not nested_lists:\n raise ValueError(\"Input list is empty\")\n\n # Convert the first sublist to a set for efficient lookups\n common_elements = set(nested_lists[0])\n \n # Iterate over the rest of the sublists\n for sublist in nested_lists[1:]:\n # Update the common_elements set to include only elements present in both common_elements and the current sublist\n common_elements &= set(sublist)\n\n return list(common_elements)", "matching_cluster_idx": 6}]}, "Mbpp/123": {"dps": 99.62686567164178, "dps_norm": 85.71428571428571, "pass@1": 15.0, "profiled": [{"solution": "def sum_of_divisors(n):\n \"\"\"Returns the sum of proper divisors of n\"\"\"\n sum_divisors = 1\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n if n // i == i:\n sum_divisors += i\n else:\n sum_divisors += i + n // i\n return sum_divisors\ndef is_amicable(a):\n \"\"\"Checks if two numbers are amicable\"\"\"\n b = sum_of_divisors(a)\n return a != b and sum_of_divisors(b) == a\ndef amicable_numbers_sum(n):\n \"\"\"Returns the sum of all amicable numbers less than or equal to n\"\"\"\n amicable_sum = 0\n for i in range(1, n + 1):\n if is_amicable(i):\n amicable_sum += i\n return amicable_sum", "matching_cluster_idx": 11}, {"solution": "def sum_of_proper_divisors(n):\n \"\"\"\n Calculate the sum of proper divisors for a given number.\n\n Args:\n n (int): The number to calculate sum of proper divisors.\n\n Returns:\n int: The sum of proper divisors.\n \"\"\"\n sum_divisors = 1\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n if n // i == i:\n sum_divisors += i\n else:\n sum_divisors += i + n // i\n return sum_divisors\ndef amicable_numbers_sum(n):\n \"\"\"\n Calculate the sum of all amicable numbers from 1 to a specified number.\n\n Args:\n n (int): The upper limit.\n\n Returns:\n int: The sum of all amicable numbers.\n \"\"\"\n amicable_sum = 0\n for i in range(2, n + 1):\n sum_divisors_i = sum_of_proper_divisors(i)\n if sum_divisors_i != i and sum_of_proper_divisors(sum_divisors_i) == i and sum_divisors_i <= n:\n amicable_sum += i + sum_divisors_i\n # remove duplicates by halving\n return amicable_sum // 2", "matching_cluster_idx": 11}, {"solution": "def amicable_numbers_sum(limit):\n \"\"\"\n This function calculates the sum of all amicable numbers from 1 to the specified limit.\n\n An amicable pair consists of two different numbers so related that the sum of the proper divisors of each is equal to the other number.\n A proper divisor is a positive divisor of a number excluding the number itself.\n\n :param limit: The upper limit to check for amicable numbers\n :return: The sum of all amicable numbers from 1 to the limit\n \"\"\"\n def proper_divisors_sum(n):\n \"\"\"Helper function to calculate the sum of proper divisors of a number\"\"\"\n sum_divisors = 1 # Start with 1 since 1 is a divisor of every number\n for i in range(2, int(n ** 0.5) + 1):\n if n % i == 0:\n sum_divisors += i\n if i != n // i:\n sum_divisors += n // i\n return sum_divisors\n\n amicable_numbers = set() # Use a set to store unique amicable numbers\n for i in range(2, limit + 1):\n sum_divisors_i = proper_divisors_sum(i)\n if sum_divisors_i < limit and sum_divisors_i != i and proper_divisors_sum(sum_divisors_i) == i:\n amicable_numbers.add(i)\n amicable_numbers.add(sum_divisors_i)\n\n return sum(amicable_numbers)", "matching_cluster_idx": 11}, {"solution": "def sum_of_proper_divisors(n):\n \"\"\"Calculate the sum of all proper divisors of n\"\"\"\n total = 1\n for i in range(2, int(n ** 0.5) + 1):\n if n % i == 0:\n if n // i == i:\n total += i\n else:\n total += i + n // i\n return total\ndef amicable_numbers_sum(n):\n \"\"\"Sum all amicable numbers from 1 to n.\"\"\"\n total_sum = 0\n for num in range(1, n + 1):\n # Calculate sum of proper divisors of num\n m = sum_of_proper_divisors(num)\n \n # If sum of proper divisors of m equals num and num != m\n if sum_of_proper_divisors(m) == num and num != m:\n # Check if the amicable pair is within the range\n if m <= n and num <= n:\n total_sum += num + m\n # Avoid adding duplicate pairs\n elif num < m and num <= n:\n total_sum += num + m\n \n return total_sum // 2 # avoid duplicates", "matching_cluster_idx": 11}, {"solution": "def sum_divisors(n):\n \"\"\"Return the sum of proper divisors of n.\"\"\"\n sum_div = 1\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n if n // i == i:\n sum_div += i\n else:\n sum_div += i + n // i\n return sum_div\ndef amicable_numbers_sum(n):\n \"\"\"\n Return the sum of all amicable numbers from 1 to n.\n\n An amicable pair consists of two different numbers so related that the sum of the proper divisors of each is equal to the other number.\n A number is called an amicable number if it is part of an amicable pair.\n\n Example: 220 and 284 are an amicable pair.\n \"\"\"\n total_sum = 0\n amicable_nums = set()\n for i in range(1, n+1):\n if i not in amicable_nums:\n sum_div_i = sum_divisors(i)\n if 1 < sum_div_i <= n and sum_divisors(sum_div_i) == i and sum_div_i != i:\n amicable_nums.add(i)\n amicable_nums.add(sum_div_i)\n return sum(amicable_nums)", "matching_cluster_idx": 11}, {"solution": "def sum_divisors(n):\n \"\"\"Calculate sum of divisors for a given number.\"\"\"\n sum_div = 1 # 1 is a divisor of every number\n for i in range(2, int(n ** 0.5) + 1):\n if n % i == 0:\n sum_div += i\n if i != n // i:\n sum_div += n // i\n return sum_div\ndef amicable_numbers_sum(limit):\n \"\"\"\n Calculate sum of all amicable numbers from 1 to a specified limit.\n \n Amicable numbers are two different numbers so related that the sum of the \n proper divisors of each is equal to the other number.\n\n Args:\n limit (int): An upper limit for checking amicable numbers.\n\n Returns:\n int: Sum of all amicable numbers from 1 to the specified limit.\n \"\"\"\n amicable_sum = 0\n amicable_pairs = set()\n \n for num in range(1, limit + 1):\n num_sum = sum_divisors(num)\n if (num_sum != num and \n num_sum <= limit and \n sum_divisors(num_sum) == num and \n (num, num_sum) not in amicable_pairs and \n (num_sum, num) not in amicable_pairs):\n amicable_sum += num + num_sum\n amicable_pairs.add((num, num_sum))\n \n return amicable_sum", "matching_cluster_idx": 11}, {"solution": "def proper_divisors(n):\n \"\"\"\n Calculate the sum of proper divisors of a number.\n \n Args:\n n (int): The number for which the sum of proper divisors is to be calculated.\n \n Returns:\n int: The sum of proper divisors of n.\n \"\"\"\n divisors_sum = 1\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n if i == n // i: \n divisors_sum += i\n else:\n divisors_sum += i + n // i\n return divisors_sum\ndef amicable_numbers_sum(limit):\n \"\"\"\n Calculate the sum of amicable numbers up to a specified limit.\n \n Args:\n limit (int): The upper limit up to which the sum of amicable numbers is to be calculated.\n \n Returns:\n int: The sum of amicable numbers up to the specified limit.\n \"\"\"\n amicable_sum = 0\n for num in range(1, limit):\n divisors_sum = proper_divisors(num)\n if 1 < divisors_sum < limit and proper_divisors(divisors_sum) == num and num != divisors_sum:\n amicable_sum += num + divisors_sum\n return amicable_sum // 2 # Avoid counting each pair twice", "matching_cluster_idx": 11}, {"solution": "def sum_of_proper_divisors(n):\n \"\"\"\n Calculate the sum of proper divisors of a number.\n \n Args:\n n (int): The number to find the sum of proper divisors for.\n \n Returns:\n int: The sum of proper divisors.\n \"\"\"\n sum_divisors = 1 # Start with 1 as it's a divisor of all numbers\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n sum_divisors += i\n if i != n // i: # Check if i is not the square root of n\n sum_divisors += n // i\n return sum_divisors\ndef amicable_numbers_sum(limit):\n \"\"\"\n Calculate the sum of all amicable numbers up to a specified limit.\n \n Args:\n limit (int): The upper limit for finding amicable numbers.\n \n Returns:\n int: The sum of all amicable numbers up to the limit.\n \"\"\"\n sum_amicable = 0\n for num in range(1, limit):\n sum_divisors = sum_of_proper_divisors(num)\n if sum_divisors < limit and sum_of_proper_divisors(sum_divisors) == num and num != sum_divisors:\n sum_amicable += num + sum_divisors\n return sum_amicable // 2 # Divide by 2 to avoid double counting", "matching_cluster_idx": 11}, {"solution": "def amicable_numbers_sum(n):\n \"\"\"\n This function sums all amicable numbers from 1 to a specified number.\n\n Args:\n n (int): The upper limit (inclusive) for summing amicable numbers.\n\n Returns:\n int: The sum of all amicable numbers up to n.\n \"\"\"\n def sum_divisors(num):\n \"\"\"Helper function to calculate the sum of divisors.\"\"\"\n divisors_sum = 1 # 1 is a divisor for all numbers\n for i in range(2, int(num ** 0.5) + 1):\n if num % i == 0:\n divisors_sum += i\n if i != num // i:\n divisors_sum += num // i\n return divisors_sum\n\n amicable_sum = 0\n for i in range(1, n + 1):\n divisors_sum = sum_divisors(i)\n # Check if the divisors sum is not equal to the original number\n # and if the sum of divisors of the divisors sum equals the original number\n if 1 < divisors_sum <= n and sum_divisors(divisors_sum) == i and divisors_sum != i:\n amicable_sum += i + divisors_sum\n # To avoid adding the same pair twice, divide by 2\n return amicable_sum // 2", "matching_cluster_idx": 11}, {"solution": "def sum_of_divisors(n):\n \"\"\"Return the sum of the proper divisors of a number.\"\"\"\n sum_divisors = 1 # Since 1 is a divisor of every number\n for i in range(2, int(n ** 0.5) + 1):\n if n % i == 0:\n sum_divisors += i\n if i != n // i: # To avoid adding square root twice\n sum_divisors += n // i\n return sum_divisors\ndef is_amicable(a):\n \"\"\"Check if two numbers a and b are amicable.\"\"\"\n b = sum_of_divisors(a)\n return sum_of_divisors(b) == a and a != b\ndef amicable_numbers_sum(n):\n \"\"\"Return the sum of all amicable numbers from 1 to n.\"\"\"\n total_sum = 0\n for i in range(1, n + 1):\n if is_amicable(i):\n total_sum += i\n return total_sum", "matching_cluster_idx": 11}, {"solution": "def sum_divisors(n):\n \"\"\"Return the sum of proper divisors of a number.\"\"\"\n sum_div = 1 # Start with 1, since 1 is a divisor of every number\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n if n // i == i:\n sum_div += i\n else:\n sum_div += i + n // i\n return sum_div\ndef amicable_numbers_sum(limit):\n \"\"\"\n Return the sum of all amicable numbers up to the given limit.\n\n Amicable numbers are two different numbers related in such a way that the sum of the proper divisors of each is equal to the other number.\n A proper divisor is a positive divisor of a number excluding the number itself.\n\n :param limit: The upper limit of the numbers to check.\n :return: The sum of all amicable numbers up to the given limit.\n \"\"\"\n amicable_sum = 0\n amicable_pairs = set() # Store pairs to avoid double counting\n\n for num in range(2, limit):\n sum_div = sum_divisors(num)\n if 2 <= sum_div < limit and sum_divisors(sum_div) == num and sum_div != num:\n pair = tuple(sorted((num, sum_div)))\n if pair not in amicable_pairs:\n amicable_sum += num + sum_div\n amicable_pairs.add(pair)\n\n return amicable_sum", "matching_cluster_idx": 11}, {"solution": "def amicable_numbers_sum(n):\n \"\"\"\n Sum of amicable numbers from 1 to n.\n\n Amicable numbers are two different numbers so related that the sum of the proper divisors of each is equal to the other number.\n A proper divisor is a positive divisor of a number excluding the number itself.\n\n Parameters:\n n (int): The upper limit.\n\n Returns:\n int: Sum of all amicable numbers from 1 to n.\n \"\"\"\n\n def get_proper_divisors_sum(num):\n \"\"\"Sum of proper divisors for the given number.\"\"\"\n sum_divisors = 1\n for i in range(2, int(num ** 0.5) + 1):\n if num % i == 0:\n if num // i == i:\n sum_divisors += i\n else:\n sum_divisors += i + num // i\n return sum_divisors\n\n amicable_nums = set()\n for i in range(1, n + 1):\n sum_divisors_i = get_proper_divisors_sum(i)\n if sum_divisors_i > 1 and sum_divisors_i <= n:\n sum_divisors_j = get_proper_divisors_sum(sum_divisors_i)\n if sum_divisors_j == i and sum_divisors_i != i:\n amicable_nums.add(i)\n amicable_nums.add(sum_divisors_i)\n\n return sum(amicable_nums)", "matching_cluster_idx": 11}, {"solution": "def sum_of_divisors(n):\n \"\"\"Returns the sum of proper divisors of a number.\"\"\"\n sum_divisors = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n if n // i == i:\n sum_divisors += i\n else:\n sum_divisors += i + n // i\n # We subtract the number itself as we only want the sum of proper divisors.\n return sum_divisors - n\ndef amicable_numbers_sum(n):\n \"\"\"Returns the sum of all amicable numbers from 1 to n.\"\"\"\n amicable_numbers = set()\n for num in range(1, n + 1):\n sum_div_num = sum_of_divisors(num)\n if sum_div_num <= n and sum_of_divisors(sum_div_num) == num and num != sum_div_num:\n amicable_numbers.add(num)\n amicable_numbers.add(sum_div_num)\n return sum(amicable_numbers)", "matching_cluster_idx": 11}, {"solution": "def sum_of_divisors(n):\n \"\"\"\n Calculate the sum of proper divisors of a number n.\n\n :param n: The number to calculate the sum of divisors for.\n :return: The sum of divisors.\n \"\"\"\n divisors_sum = 1 # 1 is always a divisor\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n if n // i == i: # if n is a perfect square, only count i once\n divisors_sum += i\n else:\n divisors_sum += i + n // i\n return divisors_sum\ndef is_amicable(a):\n \"\"\"\n Check if a number is amicable with another number.\n\n :param a: The number to check for amicability.\n :return: True if a is amicable, False otherwise.\n \"\"\"\n b = sum_of_divisors(a)\n return sum_of_divisors(b) == a and b != a\ndef amicable_numbers_sum(n):\n \"\"\"\n Calculate the sum of all amicable numbers up to n.\n\n :param n: The upper limit for the sum of amicable numbers.\n :return: The sum of amicable numbers.\n \"\"\"\n return sum(i for i in range(1, n + 1) if is_amicable(i))", "matching_cluster_idx": 11}, {"solution": "def sum_divisors(n):\n \"\"\"\n Helper function to calculate sum of divisors of a number.\n \"\"\"\n sum_divs = 1\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n if i != n // i: # If i is not a square root of n\n sum_divs += i + n // i\n else:\n sum_divs += i\n return sum_divs\ndef amicable_numbers_sum(limit):\n \"\"\"\n Function to sum all amicable numbers from 1 to the specified limit.\n \"\"\"\n total_sum = 0\n for num in range(1, limit):\n # Skip numbers whose sum of divisors is greater than the limit\n if sum_divisors(num) > limit:\n continue\n \n # Check for amicability\n if sum_divisors(sum_divisors(num)) == num and num != sum_divisors(num):\n total_sum += num + sum_divisors(num)\n \n # Remove duplicates (since we added both numbers in the pair)\n return total_sum // 2", "matching_cluster_idx": 11}]}, "Mbpp/128": {"dps": 94.81900452488688, "dps_norm": 79.0, "pass@1": 99.0, "profiled": [{"solution": "def long_words(n, sentence):\n \"\"\"\n This function filters out the words from a sentence that are longer than n characters.\n\n Args:\n n (int): The minimum number of characters in a word to be considered long.\n sentence (str): The input sentence from which words are filtered.\n\n Returns:\n list: A list of words that are longer than n characters.\n\n \"\"\"\n # Split the sentence into words\n words = sentence.split()\n\n # Use list comprehension to filter words longer than n characters\n return [word for word in words if len(word) > n]", "matching_cluster_idx": 2}, {"solution": "def long_words(n, sentence):\n \"\"\"\n Return a list of words from a sentence that are longer than n characters.\n\n Parameters:\n n (int): The minimum number of characters required for a word to be included.\n sentence (str): The input sentence.\n\n Returns:\n list: A list of words that are longer than n characters.\n\n \"\"\"\n # Split the input sentence into words\n words = sentence.split()\n \n # Use a list comprehension to filter words that are longer than n characters\n long_words_list = [word for word in words if len(word) > n]\n \n return long_words_list", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n \"\"\"\n This function takes an integer 'n' and a string 'sentence' as inputs.\n It splits the sentence into a list of words and then returns the words\n that are longer than 'n' characters.\n\n Args:\n n (int): The minimum word length.\n sentence (str): The input sentence.\n\n Returns:\n list: A list of words longer than 'n' characters.\n \"\"\"\n # Split the input sentence into a list of words\n words = sentence.split()\n \n # Use a list comprehension to filter out words longer than 'n' characters\n long_words = [word for word in words if len(word) > n]\n \n return long_words", "matching_cluster_idx": 3}, {"solution": "def long_words(min_length, sentence):\n \"\"\"\n This function filters words that are longer than n characters from a given sentence.\n\n Args:\n min_length (int): The minimum length of words to filter.\n sentence (str): The input sentence to filter words from.\n\n Returns:\n list: A list of words longer than min_length.\n\n Raises:\n ValueError: If min_length is not a non-negative integer.\n \"\"\"\n if not isinstance(min_length, int) or min_length < 0:\n raise ValueError(\"min_length must be a non-negative integer\")\n\n words = sentence.split()\n long_words_list = [word for word in words if len(word) > min_length]\n\n return long_words_list", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n \"\"\"\n This function takes a sentence and a length n as input and returns a list of words \n from the sentence that are longer than n characters.\n\n Parameters:\n n (int): The minimum length of words to be returned.\n sentence (str): The input sentence from which words are to be extracted.\n\n Returns:\n list: A list of words from the sentence that are longer than n characters.\n \"\"\"\n # Split the sentence into words\n words = sentence.split()\n \n # Use list comprehension to filter out words that are not longer than n characters\n return [word for word in words if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(min_length, phrase):\n \"\"\"\n Return a list of words longer than min_length from the given phrase.\n\n Parameters:\n min_length (int): Minimum length for a word to be included in the result.\n phrase (str): The input phrase containing words.\n\n Returns:\n list: A list of words that are longer than min_length.\n \"\"\"\n # Split the phrase into words\n words = phrase.split()\n \n # Use list comprehension to filter words longer than min_length\n return [word for word in words if len(word) > min_length]", "matching_cluster_idx": 3}, {"solution": "def long_words(min_length, sentence):\n \"\"\"\n Returns a list of words that are longer than min_length from a given sentence.\n\n Args:\n min_length (int): Minimum length of words to be included in the result.\n sentence (str): Input sentence to be processed.\n\n Returns:\n list: A list of words that are longer than min_length.\n\n Example:\n >>> long_words(3, \"python is a programming language\")\n ['python', 'programming', 'language']\n \"\"\"\n # Split the sentence into words\n words = sentence.split()\n \n # Filter the words based on the length\n long_words = [word for word in words if len(word) > min_length]\n \n return long_words", "matching_cluster_idx": 3}, {"solution": "def long_words(n, words):\n \"\"\"\n Find words that are longer than n characters from a given string of words.\n\n Parameters:\n n (int): The minimum length of words to be considered as long words.\n words (str): The string of words from which long words are to be found.\n\n Returns:\n list: A list of words longer than n characters.\n\n \"\"\"\n # Split the string into a list of words\n word_list = words.split()\n \n # Use list comprehension to filter out words longer than n characters\n long_words_list = [word for word in word_list if len(word) > n]\n \n return long_words_list", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n \"\"\"\n Returns a list of words that are longer than n characters from a given sentence.\n\n Args:\n n (int): The minimum number of characters a word must have to be included in the result.\n sentence (str): The input sentence to be processed.\n\n Returns:\n list: A list of words with more than n characters.\n\n Example:\n >>> long_words(3, \"python is a programming language\")\n ['python', 'programming', 'language']\n \"\"\"\n words = sentence.split()\n return [word for word in words if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(length, text):\n \"\"\"\n This function takes in a text string and a minimum length (n).\n It returns a list of words that are longer than n characters.\n\n Parameters:\n length (int): Minimum word length\n text (str): Text string from which to extract long words\n\n Returns:\n list: A list of words longer than n characters\n \"\"\"\n words = text.split() # Split the text into a list of words\n return [word for word in words if len(word) > length] # Use a list comprehension to filter words", "matching_cluster_idx": 3}, {"solution": "def long_words(min_length, sentence):\n \"\"\"\n This function takes a minimum length and a sentence as input.\n It returns a list of words from the sentence that are longer than the minimum length.\n\n Args:\n min_length (int): The minimum length of words to be included in the output.\n sentence (str): The input sentence.\n\n Returns:\n list: A list of words that are longer than the minimum length.\n\n Raises:\n TypeError: If the input sentence is not a string or min_length is not an integer.\n \"\"\"\n # Check if the input sentence is a string and min_length is an integer.\n if not isinstance(sentence, str):\n raise TypeError(\"Input sentence must be a string.\")\n if not isinstance(min_length, int):\n raise TypeError(\"Minimum length must be an integer.\")\n\n # Split the sentence into words.\n words = sentence.split()\n\n # Filter out words that are not longer than the minimum length.\n long_words = [word for word in words if len(word) > min_length]\n\n return long_words", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n \"\"\"\n Returns a list of words longer than n characters from a given sentence.\n\n Args:\n n (int): The minimum length of words to be returned.\n sentence (str): The input sentence to search for words.\n\n Returns:\n list: A list of words longer than n characters.\n \"\"\"\n # Split the input sentence into words\n words = sentence.split()\n \n # Use list comprehension to filter words longer than n characters\n return [word for word in words if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n \"\"\"\n Find words that are longer than n characters from a given sentence.\n\n Args:\n n (int): The minimum length of the words.\n sentence (str): The input sentence.\n\n Returns:\n list: A list of words longer than n characters.\n\n Example:\n >>> long_words(3, \"python is a programming language\")\n ['python', 'programming', 'language']\n \"\"\"\n # Split the sentence into words\n words = sentence.split()\n \n # Use list comprehension to filter words longer than n characters\n long_words_list = [word for word in words if len(word) > n]\n \n return long_words_list", "matching_cluster_idx": 3}, {"solution": "def long_words(length, sentence):\n \"\"\"\n Returns a list of words that are longer than n characters.\n\n Args:\n length (int): Minimum length for words to be included.\n sentence (str): Input string with words separated by spaces.\n\n Returns:\n list: List of words longer than 'length' characters.\n \"\"\"\n # Split the input sentence into a list of words\n words = sentence.split()\n \n # Filter words longer than 'length' characters and return as a list\n return [word for word in words if len(word) > length]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n \"\"\"\n Returns a list of words that are longer than n characters from a given sentence.\n\n Args:\n n (int): The minimum length of the words to be returned.\n sentence (str): The input sentence to be processed.\n\n Returns:\n list: A list of words that are longer than n characters.\n \"\"\"\n # Split the sentence into words\n words = sentence.split()\n\n # Use list comprehension to filter out words longer than n characters\n return [word for word in words if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n \"\"\"\n This function takes an integer n and a sentence as input, \n splits the sentence into words and returns words that are longer than n characters.\n\n Parameters:\n n (int): Minimum word length.\n sentence (str): Input sentence.\n\n Returns:\n list: A list of words longer than n characters.\n \"\"\"\n # Split the sentence into words\n words = sentence.split()\n \n # Use list comprehension to filter words longer than n characters\n long_words = [word for word in words if len(word) > n]\n \n return long_words", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n \"\"\"\n Returns a list of words longer than n characters from a given sentence.\n\n Args:\n n (int): The minimum word length.\n sentence (str): The input sentence.\n\n Returns:\n list: A list of words longer than n characters.\n \"\"\"\n # Split the sentence into words\n words = sentence.split()\n \n # Use list comprehension to filter words longer than n characters\n return [word for word in words if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(length, sentence):\n \"\"\"\n This function takes in a sentence and a word length, and returns a list of words\n from the sentence that are longer than the given length.\n\n Args:\n length (int): The minimum length of the words to be returned.\n sentence (str): The sentence from which to extract the words.\n\n Returns:\n list: A list of words longer than the given length.\n \"\"\"\n # Split the sentence into a list of words\n words = sentence.split()\n \n # Use a list comprehension to create a new list of words longer than the given length\n long_words = [word for word in words if len(word) > length]\n \n return long_words", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n \"\"\"\n Returns a list of words longer than n characters from a given sentence.\n\n Args:\n n (int): Minimum length of words to be returned.\n sentence (str): A string containing multiple words separated by spaces.\n\n Returns:\n list: A list of words that have more than n characters.\n \"\"\"\n # Split the sentence into individual words\n words = sentence.split()\n # Filter out words longer than n characters using a list comprehension\n return [word for word in words if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n \"\"\"\n This function finds words longer than 'n' characters from a given sentence.\n\n Args:\n n (int): Minimum number of characters for a word to be considered long.\n sentence (str): The input sentence from which to extract long words.\n\n Returns:\n list: A list of words longer than 'n' characters.\n \"\"\"\n words = sentence.split() # Split the sentence into words\n return [word for word in words if len(word) > n] # Return words longer than 'n'", "matching_cluster_idx": 3}]}, "Mbpp/129": {"dps": 75.2125850340136, "dps_norm": 92.77777777777777, "pass@1": 12.0, "profiled": [{"solution": "def magic_square_test(matrix):\n \"\"\"\n Test whether a matrix is a magic square.\n\n A matrix is a magic square if it is a square (has the same number of rows and columns),\n and the sum of the elements in each row, column and diagonal are equal.\n\n Parameters:\n matrix (list of lists): Input matrix to test.\n\n Returns:\n bool: True if the matrix is a magic square, False otherwise.\n \"\"\"\n # Check if the matrix is square\n if not matrix or len(matrix) != len(matrix[0]):\n return False\n\n # Calculate the expected sum (sum of the first row)\n expected_sum = sum(matrix[0])\n \n # Check the sum of each row\n for row in matrix:\n if sum(row) != expected_sum:\n return False\n\n # Check the sum of each column\n for col in range(len(matrix[0])):\n col_sum = sum(matrix[row][col] for row in range(len(matrix)))\n if col_sum != expected_sum:\n return False\n\n # Check the sum of the main diagonal\n diagonal_sum1 = sum(matrix[i][i] for i in range(len(matrix)))\n if diagonal_sum1 != expected_sum:\n return False\n\n # Check the sum of the anti-diagonal\n diagonal_sum2 = sum(matrix[i][len(matrix)-i-1] for i in range(len(matrix)))\n if diagonal_sum2 != expected_sum:\n return False\n\n # If all checks pass, it is a magic square\n return True\nmatrix = [[7, 12, 1, 14], [2, 13, 8, 11], [16, 3, 10, 5], [9, 6, 15, 4]]", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n \"\"\"\n Checks if the input matrix is a magic square.\n \n Args:\n matrix (list of lists): A 2D list representing the matrix.\n\n Returns:\n bool: True if the matrix is a magic square, False otherwise.\n \"\"\"\n\n # Check if the matrix is square\n size = len(matrix)\n if any(len(row) != size for row in matrix):\n return False\n\n # Calculate the expected sum\n expected_sum = sum(matrix[0])\n\n # Check rows\n for row in matrix:\n if sum(row) != expected_sum:\n return False\n\n # Check columns\n for col in range(size):\n if sum(matrix[row][col] for row in range(size)) != expected_sum:\n return False\n\n # Check diagonals\n if sum(matrix[i][i] for i in range(size)) != expected_sum:\n return False\n if sum(matrix[i][size - i - 1] for i in range(size)) != expected_sum:\n return False\n\n # If all checks pass, the matrix is a magic square\n return True", "matching_cluster_idx": 13}, {"solution": "def magic_square_test(matrix):\n \"\"\"\n This function checks whether a given matrix is a magic square or not.\n \n A magic square is a square grid filled with distinct positive integers in the range \n such that each row, column, and diagonal sums to the same constant.\n\n Args:\n matrix (list of lists): A 2D list representing the matrix to be checked.\n\n Returns:\n bool: True if the matrix is a magic square, False otherwise.\n \"\"\"\n\n # First, we need to check if the matrix is square.\n if not matrix or not all(len(row) == len(matrix) for row in matrix):\n return False\n\n # Calculate the size of the matrix.\n size = len(matrix)\n \n # Calculate the expected sum of each row, column and diagonal.\n expected_sum = sum(matrix[0])\n\n # Check the sum of each row.\n for row in matrix:\n if sum(row) != expected_sum:\n return False\n\n # Check the sum of each column.\n for col in range(size):\n if sum(matrix[row][col] for row in range(size)) != expected_sum:\n return False\n\n # Check the sum of the main diagonal.\n if sum(matrix[i][i] for i in range(size)) != expected_sum:\n return False\n\n # Check the sum of the other diagonal.\n if sum(matrix[i][size - i - 1] for i in range(size)) != expected_sum:\n return False\n\n # If we have not returned False by now, then the matrix is a magic square.\n return True", "matching_cluster_idx": 13}, {"solution": "def magic_square_test(matrix):\n \"\"\"\n Checks if a given matrix is a magic square.\n \n Args:\n matrix (list of lists): A square matrix of numbers.\n \n Returns:\n bool: True if the matrix is a magic square, False otherwise.\n \"\"\"\n \n # Check if the matrix is square\n size = len(matrix)\n if any(len(row) != size for row in matrix):\n return False\n \n # Calculate the expected sum for each row/column/diagonal\n expected_sum = sum(matrix[0])\n \n # Check rows and columns\n for i in range(size):\n if sum(matrix[i]) != expected_sum or sum(matrix[j][i] for j in range(size)) != expected_sum:\n return False\n \n # Check diagonals\n diagonal1_sum = sum(matrix[i][i] for i in range(size))\n diagonal2_sum = sum(matrix[i][size - i - 1] for i in range(size))\n \n return diagonal1_sum == expected_sum and diagonal2_sum == expected_sum\nmatrix = [[7, 12, 1, 14], [2, 13, 8, 11], [16, 3, 10, 5], [9, 6, 15, 4]]", "matching_cluster_idx": 13}, {"solution": "def magic_square_test(matrix):\n \"\"\"\n Tests whether the given matrix is a magic square.\n\n Args:\n matrix (list): A 2D list of integers.\n\n Returns:\n bool: Whether the matrix is a magic square.\n\n Raises:\n ValueError: If the matrix is not square.\n TypeError: If the matrix is empty or contains non-integer values.\n \"\"\"\n # Check if matrix is a list of lists and not empty\n if not isinstance(matrix, list) or len(matrix) == 0 or not all(isinstance(row, list) for row in matrix):\n raise TypeError(\"Input must be a non-empty list of lists.\")\n \n # Check if all rows have the same length\n num_rows = len(matrix)\n row_length = len(matrix[0])\n if not all(len(row) == row_length for row in matrix):\n raise ValueError(\"Matrix must be square.\")\n \n # Check if all elements are integers\n if not all(isinstance(element, int) for row in matrix for element in row):\n raise TypeError(\"Matrix must contain only integers.\")\n \n # Calculate the expected sum\n expected_sum = sum(matrix[0])\n \n # Check rows and columns\n for i in range(num_rows):\n if sum(matrix[i]) != expected_sum:\n return False\n column_sum = sum(matrix[j][i] for j in range(num_rows))\n if column_sum != expected_sum:\n return False\n \n # Check diagonals\n diagonal1_sum = sum(matrix[i][i] for i in range(num_rows))\n diagonal2_sum = sum(matrix[i][num_rows - i - 1] for i in range(num_rows))\n if diagonal1_sum != expected_sum or diagonal2_sum != expected_sum:\n return False\n \n return True\nmatrix = [[7, 12, 1, 14], [2, 13, 8, 11], [16, 3, 10, 5], [9, 6, 15, 4]]", "matching_cluster_idx": 5}, {"solution": "def magic_square_test(matrix):\n \"\"\"\n This function determines whether a given matrix is a magic square.\n \n A magic square is a square matrix where every row, column, and diagonal sum up to the same constant.\n \n Args:\n matrix (list): A 2D list of integers representing the matrix.\n \n Returns:\n bool: True if the matrix is a magic square, False otherwise.\n \"\"\"\n\n # Check if the input is a square matrix\n if len(matrix) != len(matrix[0]):\n return False\n\n # Calculate the expected sum\n expected_sum = sum(matrix[0])\n\n # Check each row sum\n for row in matrix:\n if sum(row) != expected_sum:\n return False\n\n # Check each column sum\n for col in range(len(matrix[0])):\n if sum([row[col] for row in matrix]) != expected_sum:\n return False\n\n # Check the main diagonal sum\n if sum([matrix[i][i] for i in range(len(matrix))]) != expected_sum:\n return False\n\n # Check the anti-diagonal sum\n if sum([matrix[i][len(matrix)-i-1] for i in range(len(matrix))]) != expected_sum:\n return False\n\n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n \"\"\"\n Checks if the given matrix is a magic square.\n\n Args:\n matrix (list of lists): A 2D list representing the matrix.\n\n Returns:\n bool: True if the matrix is a magic square, False otherwise.\n \"\"\"\n\n # First, we check if the matrix is square\n if len(matrix) != len(matrix[0]):\n return False\n\n # Then, we calculate the expected sum of each row, column and diagonal\n n = len(matrix)\n expected_sum = sum(matrix[0])\n\n # Check each row\n for row in matrix:\n if sum(row) != expected_sum:\n return False\n\n # Check each column\n for col in range(n):\n if sum(row[col] for row in matrix) != expected_sum:\n return False\n\n # Check the main diagonal\n if sum(matrix[i][i] for i in range(n)) != expected_sum:\n return False\n\n # Check the anti-diagonal\n if sum(matrix[i][n-i-1] for i in range(n)) != expected_sum:\n return False\n\n # If all checks pass, it's a magic square\n return True\nmatrix = [[7, 12, 1, 14], [2, 13, 8, 11], [16, 3, 10, 5], [9, 6, 15, 4]]", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n \"\"\"\n Checks if a given matrix is a magic square.\n\n Args:\n matrix (list of lists): A 2D list of integers representing the matrix.\n\n Returns:\n bool: True if the matrix is a magic square, False otherwise.\n \"\"\"\n\n # Check if matrix is a square\n if len(matrix) != len(matrix[0]):\n return False\n\n # Calculate the expected sum of each row, column and diagonal\n expected_sum = sum(matrix[0])\n\n # Check each row\n for row in matrix:\n if sum(row) != expected_sum:\n return False\n\n # Check each column\n for col in range(len(matrix)):\n if sum(matrix[row][col] for row in range(len(matrix))) != expected_sum:\n return False\n\n # Check the main diagonal\n if sum(matrix[i][i] for i in range(len(matrix))) != expected_sum:\n return False\n\n # Check the anti-diagonal\n if sum(matrix[i][len(matrix) - i - 1] for i in range(len(matrix))) != expected_sum:\n return False\n\n # If all checks pass, the matrix is a magic square\n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n \"\"\"\n Tests whether a given matrix is a magic square.\n\n A matrix is considered a magic square if the sum of the elements in each row,\n column and the two diagonals is the same.\n\n Args:\n matrix (list of lists): A 2D list representing the matrix.\n\n Returns:\n bool: True if the matrix is a magic square, False otherwise.\n \"\"\"\n # First, we need to check if the matrix is a square matrix\n size = len(matrix)\n if not all(len(row) == size for row in matrix):\n return False\n\n # Calculate the expected sum of each row, column and diagonal\n expected_sum = sum(matrix[0])\n\n # Check each row sum\n for row in matrix:\n if sum(row) != expected_sum:\n return False\n\n # Check each column sum\n for col in range(size):\n if sum(matrix[row][col] for row in range(size)) != expected_sum:\n return False\n\n # Check the diagonal from top-left to bottom-right\n diagonal_sum1 = sum(matrix[i][i] for i in range(size))\n if diagonal_sum1 != expected_sum:\n return False\n\n # Check the diagonal from top-right to bottom-left\n diagonal_sum2 = sum(matrix[i][size - i - 1] for i in range(size))\n if diagonal_sum2 != expected_sum:\n return False\n\n # If all checks pass, the matrix is a magic square\n return True", "matching_cluster_idx": 13}, {"solution": "def magic_square_test(matrix):\n \"\"\"\n This function checks whether a given square matrix is a magic square.\n\n A magic square is a n x n matrix where the sum of the elements in each row, column, and diagonal is the same.\n\n Args:\n matrix (list): A 2D list representing a square matrix.\n\n Returns:\n bool: True if the matrix is a magic square, False otherwise.\n \"\"\"\n\n # Check if the matrix is square\n if len(matrix) != len(matrix[0]):\n return False\n\n # Calculate the expected sum of each row, column, and diagonal\n expected_sum = sum(matrix[0])\n\n # Check rows\n for row in matrix:\n if sum(row) != expected_sum:\n return False\n\n # Check columns\n for col in range(len(matrix[0])):\n if sum(matrix[row][col] for row in range(len(matrix))) != expected_sum:\n return False\n\n # Check diagonals\n diagonal1_sum = sum(matrix[i][i] for i in range(len(matrix)))\n diagonal2_sum = sum(matrix[i][len(matrix) - i - 1] for i in range(len(matrix)))\n if diagonal1_sum != expected_sum or diagonal2_sum != expected_sum:\n return False\n\n # If all checks pass, the matrix is a magic square\n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n \"\"\"\n Checks whether the input matrix is a magic square.\n\n Args:\n matrix (list of lists): A square matrix of integers.\n\n Returns:\n bool: True if the matrix is a magic square, False otherwise.\n \"\"\"\n\n # Calculate the expected sum based on the first row\n expected_sum = sum(matrix[0])\n\n # Check each row\n for row in matrix:\n if sum(row) != expected_sum:\n return False\n\n # Check each column\n for col_idx in range(len(matrix[0])):\n col_sum = sum(matrix[row_idx][col_idx] for row_idx in range(len(matrix)))\n if col_sum != expected_sum:\n return False\n\n # Check the main diagonal\n diagonal_sum = sum(matrix[i][i] for i in range(len(matrix)))\n if diagonal_sum != expected_sum:\n return False\n\n # Check the secondary diagonal\n diagonal_sum = sum(matrix[i][len(matrix)-i-1] for i in range(len(matrix)))\n if diagonal_sum != expected_sum:\n return False\n\n return True\nmatrix = [[7, 12, 1, 14], [2, 13, 8, 11], [16, 3, 10, 5], [9, 6, 15, 4]]", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n \"\"\"\n Function to determine whether a given matrix is a magic square.\n \n A magic square is an n*n matrix where every row, column and diagonal sum up to the same value.\n \n Parameters:\n matrix (list of lists): input 2D list representing the matrix to be checked.\n \n Returns:\n bool: True if the matrix is a magic square, False otherwise.\n \"\"\"\n \n # Check if matrix is a square matrix\n if len(matrix) != len(matrix[0]):\n return False\n \n # Calculate the target sum\n n = len(matrix)\n target_sum = sum(matrix[0])\n \n # Check rows\n for row in matrix:\n if sum(row) != target_sum:\n return False\n \n # Check columns\n for col in range(n):\n if sum(matrix[row][col] for row in range(n)) != target_sum:\n return False\n \n # Check diagonals\n diagonal_sum1 = sum(matrix[i][i] for i in range(n))\n diagonal_sum2 = sum(matrix[i][n - i - 1] for i in range(n))\n \n if diagonal_sum1 != target_sum or diagonal_sum2 != target_sum:\n return False\n \n return True\nmatrix = [[7, 12, 1, 14], [2, 13, 8, 11], [16, 3, 10, 5], [9, 6, 15, 4]]", "matching_cluster_idx": 14}]}, "Mbpp/130": {"dps": 96.79372197309418, "dps_norm": 84.16666666666666, "pass@1": 65.0, "profiled": [{"solution": "from collections import Counter\ndef max_occurrences(lst):\n \"\"\"\n This function finds the item with the maximum frequency in a given list.\n \n Parameters:\n lst (list): A list of integers.\n \n Returns:\n int: The item with the maximum frequency in the list.\n \"\"\"\n freq_dict = Counter(lst) # count occurrences of each item in the list\n max_freq = max(freq_dict.values()) # find the maximum frequency\n # return any item with maximum frequency\n return next(key for key, value in freq_dict.items() if value == max_freq)", "matching_cluster_idx": 5}, {"solution": "from collections import Counter\ndef max_occurrences(lst):\n \"\"\"\n Returns the item with the maximum frequency in the given list.\n\n If there are multiple items with the same maximum frequency, \n the function returns the item that appeared first in the list.\n\n Parameters:\n lst (list): A list of items.\n\n Returns:\n The item with the maximum frequency.\n \"\"\"\n if not lst:\n return None\n\n counter = Counter(lst)\n max_count = max(counter.values())\n max_items = [item for item, count in counter.items() if count == max_count]\n\n # return the first item in the list with the maximum frequency\n for item in lst:\n if item in max_items:\n return item", "matching_cluster_idx": 4}, {"solution": "from collections import Counter\ndef max_occurrences(lst):\n \"\"\"\n This function finds the item with maximum frequency in a given list.\n\n Parameters:\n lst (list): A list of integers or any hashable items.\n\n Returns:\n The item with the maximum frequency in the list.\n\n Example:\n >>> max_occurrences([2,3,8,4,7,9,8,2,6,5,1,6,1,2,3,2,4,6,9,1,2])\n 2\n \"\"\"\n # Count the frequency of each item in the list\n frequency = Counter(lst)\n \n # Find the item with the maximum frequency\n max_item = max(frequency, key=frequency.get)\n \n return max_item", "matching_cluster_idx": 4}, {"solution": "from collections import Counter\ndef max_occurrences(lst):\n \"\"\"\n This function finds the item with maximum frequency in a given list.\n \n Args:\n lst (list): A list containing items to find the max occurrence.\n \n Returns:\n The item with the highest frequency.\n \"\"\"\n \n # Count occurrences of all items in the list\n count_dict = Counter(lst)\n \n # Find the maximum frequency\n max_freq = max(count_dict.values())\n \n # Return the first item that has the maximum frequency\n # Note: If there are multiple items with the same max frequency, \n # this function will return one of them. The returned item \n # may not necessarily be the first one that appears in the list.\n return next(key for key, value in count_dict.items() if value == max_freq)", "matching_cluster_idx": 5}, {"solution": "from collections import Counter\ndef max_occurrences(lst):\n \"\"\"\n This function finds the item with the maximum frequency in a given list.\n\n Args:\n lst (list): The input list containing elements of any hashable type.\n\n Returns:\n The item with the maximum frequency in the list.\n\n Raises:\n ValueError: If the input list is empty.\n \"\"\"\n\n # Check if the list is empty\n if not lst:\n raise ValueError(\"Input list is empty\")\n\n # Use the Counter class to count the frequency of each item in the list\n freq_count = Counter(lst)\n\n # Find the item with the maximum frequency\n max_item = max(freq_count, key=freq_count.get)\n\n return max_item", "matching_cluster_idx": 4}, {"solution": "from collections import Counter\ndef max_occurrences(lst):\n \"\"\"\n This function finds the item with maximum frequency in a given list.\n\n Args:\n lst (list): A list of elements.\n\n Returns:\n The item with the highest frequency.\n \"\"\"\n # Handle the case of an empty list\n if not lst:\n return None\n\n # Count the occurrences of each item in the list\n freq = Counter(lst)\n \n # Find the item with the maximum frequency\n max_item = max(freq, key=freq.get)\n\n return max_item", "matching_cluster_idx": 4}, {"solution": "def max_occurrences(lst):\n \"\"\"\n This function finds the item with maximum frequency in a given list.\n \n Parameters:\n lst (list): The input list containing elements of any type that can be hashed (e.g., integers, strings).\n \n Returns:\n The item with the maximum frequency in the list.\n \"\"\"\n \n # Create a dictionary to store the frequency of each item\n frequency_dict = {}\n \n # Iterate over each item in the list\n for item in lst:\n # If the item is already in the dictionary, increment its count\n if item in frequency_dict:\n frequency_dict[item] += 1\n # Otherwise, add the item to the dictionary with a count of 1\n else:\n frequency_dict[item] = 1\n \n # Find the item with the maximum frequency\n max_item = max(frequency_dict, key=frequency_dict.get)\n \n return max_item", "matching_cluster_idx": 3}, {"solution": "from collections import Counter\ndef max_occurrences(lst):\n \"\"\"\n This function finds the item with maximum frequency in a given list.\n\n Parameters:\n lst (list): The input list of items.\n\n Returns:\n The item that appears most frequently in the list. \n If multiple items have the same max frequency, it returns one of them.\n \"\"\"\n # Count the occurrences of each item\n freq = Counter(lst)\n \n # Get the item with the maximum frequency\n return max(freq, key=freq.get)", "matching_cluster_idx": 4}, {"solution": "from collections import Counter\ndef max_occurrences(lst):\n \"\"\"\n This function finds the item with maximum frequency in a given list.\n \n Parameters:\n lst (list): Input list containing elements\n \n Returns:\n The element that occurs most frequently in the input list.\n If multiple elements have the same highest frequency, it returns any of them.\n \"\"\"\n counter = Counter(lst)\n return counter.most_common(1)[0][0]", "matching_cluster_idx": 4}, {"solution": "from collections import Counter\ndef max_occurrences(lst):\n \"\"\"\n Find the item with maximum frequency in a given list.\n\n In the case of multiple items having the same maximum frequency,\n the one that appears earliest in the list is returned.\n\n Args:\n lst (list): A list of elements.\n\n Returns:\n element: The item with maximum frequency in the list.\n \"\"\"\n # Count the frequency of each item in the list\n freq = Counter(lst)\n \n # Get the maximum frequency\n max_freq = max(freq.values())\n \n # Find the first item with maximum frequency\n for item in lst:\n if freq[item] == max_freq:\n return item", "matching_cluster_idx": 5}, {"solution": "from collections import Counter\ndef max_occurrences(lst):\n \"\"\"\n Find the item with maximum frequency in a given list.\n \n Parameters:\n lst (list): input list\n \n Returns:\n item with maximum frequency\n \n \"\"\"\n counter = Counter(lst)\n return max(counter, key=counter.get)", "matching_cluster_idx": 4}, {"solution": "from collections import Counter\ndef max_occurrences(lst):\n \"\"\"\n This function finds the item with maximum frequency in a given list.\n \n Args:\n lst (list): The input list to find the item with maximum frequency.\n \n Returns:\n The item with the maximum frequency in the list.\n \"\"\"\n count_map = Counter(lst) # Count the occurrences of each item in the list.\n max_occurrence_item = max(count_map, key=count_map.get) # Find the item with the maximum occurrence.\n return max_occurrence_item", "matching_cluster_idx": 4}, {"solution": "from collections import Counter\ndef max_occurrences(lst):\n \"\"\"\n Returns the item with maximum frequency in a given list.\n\n Args:\n lst (list): Input list containing items\n\n Returns:\n The item with the maximum frequency in the input list\n \"\"\"\n # Count the frequency of each item in the list\n freq_dict = Counter(lst)\n \n # Find the item with the maximum frequency\n max_item = max(freq_dict, key=freq_dict.get)\n \n return max_item", "matching_cluster_idx": 4}, {"solution": "from collections import Counter\ndef max_occurrences(lst):\n \"\"\"\n Find the item with maximum frequency in a given list.\n\n Args:\n lst (list): A list of integers.\n\n Returns:\n int: The item with maximum frequency in the list.\n\n Raises:\n ValueError: If the input list is empty.\n \"\"\"\n if not lst:\n raise ValueError(\"Input list cannot be empty\")\n\n # Use Counter to count frequency of each item\n frequency_count = Counter(lst)\n \n # Find the item with maximum frequency\n max_item = max(frequency_count, key=frequency_count.get)\n \n return max_item", "matching_cluster_idx": 4}, {"solution": "def max_occurrences(lst):\n \"\"\"\n This function finds the item with maximum frequency in a given list.\n\n Args:\n lst (list): The input list containing elements of any type.\n\n Returns:\n The item with maximum frequency in the list.\n \"\"\"\n\n # Handle the case when the input list is empty\n if not lst:\n return None\n\n # Use the built-in Python dictionary to store frequency of each item\n freq_dict = {}\n\n # Iterate over the list and count frequency of each item\n for item in lst:\n if item in freq_dict:\n freq_dict[item] += 1\n else:\n freq_dict[item] = 1\n\n # Find the item with maximum frequency\n max_freq_item = max(freq_dict, key=freq_dict.get)\n\n return max_freq_item", "matching_cluster_idx": 3}, {"solution": "from collections import Counter\ndef max_occurrences(lst):\n \"\"\"\n This function finds the item with maximum frequency in a given list.\n\n Parameters:\n lst (list): The input list containing elements of any data type.\n\n Returns:\n The item that occurs most frequently in the list. If multiple items have the same maximum frequency,\n the function returns the one that appears first in the list.\n\n Example:\n >>> max_occurrences([2,3,8,4,7,9,8,2,6,5,1,6,1,2,3,2,4,6,9,1,2])\n 2\n \"\"\"\n if not lst:\n return None\n\n # Count the occurrences of each item\n count = Counter(lst)\n\n # Get the item with maximum frequency\n max_item = max(count, key=count.get)\n\n return max_item", "matching_cluster_idx": 4}, {"solution": "from collections import Counter\ndef max_occurrences(lst):\n \"\"\"\n This function finds the item with maximum frequency in a given list.\n \n Args:\n lst (list): The list to search in.\n \n Returns:\n The item with maximum frequency in the list.\n \"\"\"\n if not lst:\n raise ValueError(\"List is empty\")\n\n # Count occurrences of each item in the list\n counts = Counter(lst)\n \n # Find the item with maximum frequency\n max_item = max(counts, key=counts.get)\n \n return max_item", "matching_cluster_idx": 4}, {"solution": "from collections import Counter\ndef max_occurrences(lst):\n \"\"\"\n This function returns the item with maximum frequency in a given list.\n \n Parameters:\n lst (list): The input list to find the item with maximum frequency.\n \n Returns:\n item: The item with maximum frequency in the list.\n \"\"\"\n if not lst:\n return None\n # Create a Counter object to store the frequency of each item in the list.\n freq = Counter(lst)\n \n # Find the item with maximum frequency using the most_common() method.\n max_freq_item = max(freq, key=freq.get)\n \n return max_freq_item", "matching_cluster_idx": 4}, {"solution": "from collections import Counter\ndef max_occurrences(lst):\n \"\"\"\n Returns the item with maximum frequency in a given list.\n\n Args:\n lst (list): The input list of items.\n\n Returns:\n The item with the highest frequency.\n \"\"\"\n # Count the occurrences of each item in the list\n count_dict = Counter(lst)\n\n # Find the item with the maximum frequency\n max_item = max(count_dict, key=count_dict.get)\n\n return max_item", "matching_cluster_idx": 4}, {"solution": "from collections import Counter\ndef max_occurrences(lst):\n \"\"\"\n This function finds the item with maximum frequency in a given list.\n \n Parameters:\n lst (list): A list of items\n \n Returns:\n item: The item with the maximum frequency\n \n Raises:\n ValueError: If the input list is empty\n \"\"\"\n if not lst:\n raise ValueError(\"Input list is empty\")\n\n freq = Counter(lst)\n max_freq_item = max(freq, key=freq.get)\n\n return max_freq_item", "matching_cluster_idx": 4}]}, "Mbpp/137": {"dps": 32.90322580645161, "dps_norm": 47.5, "pass@1": 10.0, "profiled": [{"solution": "def zero_count(arr):\n \"\"\"\n This function calculates the ratio of zeroes to non-zeroes in an array of integers.\n \n Parameters:\n arr (list): A list of integers.\n \n Returns:\n float: The ratio of zeroes to non-zeroes in the array.\n \"\"\"\n \n # Check if the array is empty\n if not arr:\n return 0\n \n # Count the number of zeroes and non-zeroes in the array\n zero_cnt = len([num for num in arr if num == 0])\n non_zero_cnt = len([num for num in arr if num != 0])\n \n # Avoid division by zero error\n if non_zero_cnt == 0:\n return float('inf') # Return infinity when all elements are zeroes\n \n # Calculate the ratio of zeroes to non-zeroes\n ratio = zero_cnt / non_zero_cnt\n \n return ratio", "matching_cluster_idx": 3}, {"solution": "import math\nimport unittest\ndef zero_count(arr):\n \"\"\"\n This function calculates the ratio of zeroes to non-zeroes in an array of integers.\n \n Args:\n arr (list): A list of integers.\n \n Returns:\n float: The ratio of zeroes to non-zeroes in the array.\n \"\"\"\n total_count = len(arr)\n zero_count = sum(1 for x in arr if x == 0)\n non_zero_count = total_count - zero_count\n \n # Check for division by zero error\n if non_zero_count == 0:\n return float('inf') # or raise a custom error\n \n return zero_count / non_zero_count", "matching_cluster_idx": 4}, {"solution": "def zero_count(arr):\n \"\"\"\n Calculate the ratio of zeroes to total non-zero elements in an array of integers.\n\n Args:\n arr (list): A list of integers.\n\n Returns:\n float: The ratio of zeroes to total non-zero elements.\n \"\"\"\n # Check if the input is a list\n if not isinstance(arr, list):\n raise TypeError(\"Input must be a list\")\n\n # Count the total number of zeroes\n zero_cnt = sum(1 for num in arr if num == 0)\n\n # Count the total number of non-zero elements\n non_zero_cnt = sum(1 for num in arr if num != 0)\n\n # If there are no non-zero elements, return infinity or a specific error value\n if non_zero_cnt == 0:\n return float('inf') # or raise ValueError(\"No non-zero elements\")\n\n # Calculate and return the ratio\n return zero_cnt / non_zero_cnt", "matching_cluster_idx": 0}, {"solution": "import math\ndef zero_count(nums):\n \"\"\"\n This function calculates the ratio of zeroes to non-zeroes in an array of integers.\n\n Args:\n nums (list): A list of integers.\n\n Returns:\n float: The ratio of zeroes to non-zeroes.\n \"\"\"\n zero_count = 0\n non_zero_count = 0\n \n # Count the number of zeroes and non-zeroes\n for num in nums:\n if num == 0:\n zero_count += 1\n elif num != 0:\n non_zero_count += 1\n \n # Check for the edge case where there are no non-zeroes\n if non_zero_count == 0:\n return float('inf')\n \n return zero_count / non_zero_count", "matching_cluster_idx": 1}, {"solution": "import math\ndef zero_count(arr):\n \"\"\"\n Calculate the ratio of zeroes to non-zeroes in an array of integers.\n\n Args:\n arr (list): A list of integers.\n\n Returns:\n float: The ratio of zeroes to non-zeroes.\n\n Raises:\n ValueError: If the input array is empty.\n \"\"\"\n if not arr:\n raise ValueError(\"Input array cannot be empty.\")\n\n # Count the total number of zeroes\n zeroes = sum(1 for num in arr if num == 0)\n \n # Calculate the total number of non-zeroes\n non_zeroes = len(arr) - zeroes\n\n # Check if there are any non-zeroes to avoid division by zero error\n if non_zeroes == 0:\n return float('inf') # Return infinity if all elements are zeroes\n \n # Calculate the ratio of zeroes to non-zeroes\n ratio = zeroes / non_zeroes\n \n return ratio", "matching_cluster_idx": 4}, {"solution": "import math\nimport unittest\ndef zero_count(nums):\n \"\"\"\n This function calculates the ratio of zeros to the total count of zeros and non-zeros in a list of integers.\n \n Args:\n nums (list): A list of integers.\n \n Returns:\n float: The ratio of zeros to non-zeros in the input list.\n \"\"\"\n \n # Count the total number of elements in the list\n total_count = len(nums)\n \n # Count the number of zeros in the list using a generator expression within the sum function\n zero_total = sum(1 for num in nums if num == 0)\n \n # Count the number of non-zeros in the list using a generator expression within the sum function\n non_zero_total = sum(1 for num in nums if num != 0)\n \n # If there are no non-zero elements, the ratio is undefined, so we return a specific value\n if non_zero_total == 0:\n return float('inf') # or you can raise an exception\n \n # Calculate the ratio of zeros to non-zeros\n ratio = zero_total / non_zero_total\n \n return ratio", "matching_cluster_idx": 0}, {"solution": "from typing import List\nimport math\nimport unittest\ndef zero_count(arr: List[int]) -> float:\n \"\"\"\n Calculate the ratio of zeroes to non-zeroes in a list of integers.\n\n Args:\n arr (List[int]): A list of integers.\n\n Returns:\n float: The ratio of zeroes to non-zeroes.\n \"\"\"\n total = len(arr)\n if total == 0:\n return 0 # Avoid division by zero\n \n zeroes = sum(1 for num in arr if num == 0)\n non_zeroes = total - zeroes\n \n # Avoid division by zero when all elements are zero\n if non_zeroes == 0:\n return float('inf') # Representing undefined ratio\n \n return zeroes / non_zeroes", "matching_cluster_idx": 4}, {"solution": "import math\ndef zero_count(arr):\n \"\"\"\n Calculate the ratio of zeroes to non-zeroes in an array of integers.\n\n Args:\n arr (list): A list of integers.\n\n Returns:\n float: The ratio of zeroes to non-zeroes.\n\n Raises:\n ValueError: If the input list is empty.\n \"\"\"\n\n # Check if the input list is empty\n if not arr:\n raise ValueError(\"Input list cannot be empty.\")\n\n # Initialize counters for zeroes and non-zeroes\n zeroes = 0\n non_zeroes = 0\n\n # Iterate through the list and count zeroes and non-zeroes\n for num in arr:\n if num == 0:\n zeroes += 1\n else:\n non_zeroes += 1\n\n # Calculate the ratio\n if non_zeroes == 0:\n return float(\"inf\") # Return infinity if all elements are zero\n\n ratio = zeroes / non_zeroes\n\n return ratio", "matching_cluster_idx": 3}, {"solution": "import math\ndef zero_count(array):\n \"\"\"\n Calculate the ratio of zeroes to non-zeroes in an array of integers.\n\n Args:\n array (list): A list of integers.\n\n Returns:\n float: The ratio of zeroes to non-zeroes in the input array.\n \"\"\"\n zeroes = sum(1 for x in array if x == 0)\n non_zeroes = len(array) - zeroes\n \n # Handle the case where there are no non-zeroes\n if non_zeroes == 0:\n return float('inf') # or any other value that makes sense for your use case\n\n return zeroes / non_zeroes", "matching_cluster_idx": 5}, {"solution": "import math\ndef zero_count(arr):\n \"\"\"\n Calculate the ratio of zeroes to non-zeroes in an array of integers.\n\n Args:\n arr (list): A list of integers.\n\n Returns:\n float: The ratio of zeroes to non-zeroes.\n \"\"\"\n # Check if the array is empty\n if len(arr) == 0:\n return 0\n\n # Initialize counters for zeroes and non-zeroes\n total_zeroes = sum(1 for num in arr if num == 0)\n total_non_zeroes = len(arr) - total_zeroes\n\n # Check for division by zero\n if total_non_zeroes == 0:\n return float('inf') # Return infinity if there are no non-zeroes\n\n # Calculate the ratio\n ratio = total_zeroes / total_non_zeroes\n\n return ratio", "matching_cluster_idx": 4}]}, "Mbpp/140": {"dps": 66.56832298136646, "dps_norm": 75.0, "pass@1": 84.0, "profiled": [{"solution": "def extract_singly(lists_of_numbers):\n \"\"\"\n This function takes a list of tuples (or lists) of numbers and returns a set of unique numbers.\n\n Args:\n lists_of_numbers (list): A list of tuples (or lists) of numbers.\n\n Returns:\n set: A set of unique numbers.\n \"\"\"\n # Initialize an empty set to store unique numbers\n unique_numbers = set()\n \n # Iterate over each tuple (or list) in the input list\n for numbers in lists_of_numbers:\n # Update the set with numbers from the current tuple (or list)\n unique_numbers.update(numbers)\n \n # Return the set of unique numbers\n return unique_numbers", "matching_cluster_idx": 6}, {"solution": "def extract_singly(list_of_lists):\n \"\"\"\n This function takes a list of tuples and returns a set of unique numbers.\n\n Args:\n list_of_lists (list): A list of tuples containing numbers.\n\n Returns:\n set: A set of unique numbers from the input list of tuples.\n \"\"\"\n # Initialize an empty set to store unique numbers\n unique_numbers = set()\n \n # Iterate over each tuple in the list\n for tup in list_of_lists:\n # Add all numbers in the tuple to the set\n unique_numbers.update(tup)\n \n return unique_numbers", "matching_cluster_idx": 6}, {"solution": "def extract_singly(lists):\n \"\"\"\n This function takes a list of tuples, unpacks them, and returns a set of unique numbers.\n\n Args:\n lists (list): A list of tuples containing integers.\n\n Returns:\n set: A set of unique integers.\n \"\"\"\n # Initialize an empty set to store unique numbers\n unique_nums = set()\n \n # Iterate over each tuple in the list\n for tup in lists:\n # Unpack the tuple into individual numbers\n for num in tup:\n # Add each number to the set\n unique_nums.add(num)\n \n # Return the set of unique numbers\n return unique_nums", "matching_cluster_idx": 3}, {"solution": "def extract_singly(lists):\n \"\"\"\n This function takes in a list of tuples, extracts the numbers from the tuples, \n removes duplicates, and returns the result as a set.\n\n Args:\n lists (list): A list of tuples containing integers.\n\n Returns:\n set: A set of unique integers.\n \"\"\"\n # Initialize an empty set to store unique numbers\n result = set()\n \n # Iterate over each tuple in the list\n for tup in lists:\n # Add each number from the tuple to the set\n result.update(tup)\n \n # Return the set of unique numbers\n return result", "matching_cluster_idx": 6}, {"solution": "def extract_singly(iterable):\n \"\"\"\n Flattens the list of tuples into a single set of numbers.\n\n Args:\n iterable: An iterable containing tuples of integers.\n\n Returns:\n A set of unique integers found in the input tuples.\n \"\"\"\n result = set()\n for tup in iterable:\n result.update(tup)\n return result", "matching_cluster_idx": 6}, {"solution": "def extract_singly(tuples_list):\n \"\"\"\n This function takes a list of tuples and returns a set of numbers.\n The set contains all unique numbers from all tuples in the list.\n\n :param tuples_list: A list of tuples\n :return: A set of numbers\n \"\"\"\n # Initialize an empty set to store unique numbers\n unique_numbers = set()\n \n # Iterate over each tuple in the list\n for tup in tuples_list:\n # Add each number from the tuple to the set\n unique_numbers.update(tup)\n \n # Return the set of unique numbers\n return unique_numbers", "matching_cluster_idx": 6}, {"solution": "def extract_singly(list_of_tuples):\n \"\"\"\n This function takes a list of tuples as input and returns a set of all numbers in the tuples.\n \n Args:\n list_of_tuples (list): A list containing tuples of numbers.\n \n Returns:\n set: A set containing all unique numbers from the input list.\n \"\"\"\n return set(num for tup in list_of_tuples for num in tup)", "matching_cluster_idx": 4}, {"solution": "def extract_singly(nested_tuple):\n \"\"\"\n This function takes a tuple of tuples as input, \n extracts all unique numbers from the tuples, \n and returns them as a set.\n \n Parameters:\n nested_tuple (tuple): A tuple containing multiple tuples of integers.\n \n Returns:\n set: A set of unique integers from the input tuples.\n \"\"\"\n # Initialize an empty set to store unique numbers\n unique_numbers = set()\n \n # Iterate over each tuple in the nested tuple\n for tup in nested_tuple:\n # Add all numbers from the current tuple to the set\n unique_numbers.update(tup)\n \n # Return the set of unique numbers\n return unique_numbers", "matching_cluster_idx": 6}, {"solution": "def extract_singly(lst):\n \"\"\"\n This function takes a list of tuples as input and returns a set of unique numbers.\n\n Args:\n lst (list): A list of tuples containing numbers.\n\n Returns:\n set: A set of unique numbers.\n \"\"\"\n return set(num for tup in lst for num in tup)", "matching_cluster_idx": 4}, {"solution": "def extract_singly(tuples):\n \"\"\"\n Flattens a list of tuples into a single set of numbers.\n\n Args:\n tuples (list): A list of tuples containing integers.\n\n Returns:\n set: A set of unique integers from the input tuples.\n\n Example:\n >>> extract_singly([(3, 4, 5), (4, 5, 7), (1, 4)])\n {1, 3, 4, 5, 7}\n \"\"\"\n\n return set(num for tup in tuples for num in tup)", "matching_cluster_idx": 4}, {"solution": "def extract_singly(lists):\n \"\"\"\n This function takes a list of tuples as input and returns a set of all the elements.\n\n Args:\n lists (list): A list of tuples.\n\n Returns:\n set: A set of all the elements in the tuples.\n \"\"\"\n return set(num for tup in lists for num in tup)", "matching_cluster_idx": 4}, {"solution": "def extract_singly(lst):\n \"\"\"\n Extracts unique numbers from the list of tuples.\n\n Args:\n lst (list): A list of tuples containing numbers.\n\n Returns:\n set: A set of unique numbers from the input list.\n \"\"\"\n return set(num for tup in lst for num in tup)", "matching_cluster_idx": 4}, {"solution": "def extract_singly(nested_list):\n \"\"\"\n This function takes a list of tuples and returns a set of unique numbers.\n \n Args:\n nested_list (list): A list of tuples containing integers.\n \n Returns:\n set: A set of unique integers.\n \"\"\"\n # Initialize an empty set to store unique numbers\n unique_numbers = set()\n \n # Iterate over each tuple in the list\n for tup in nested_list:\n # Add each number from the tuple to the set\n unique_numbers.update(tup)\n \n # Return the set of unique numbers\n return unique_numbers", "matching_cluster_idx": 6}, {"solution": "def extract_singly(tuples_list):\n \"\"\"\n This function takes a list of tuples, extracts single numbers from tuples and \n returns them as a set.\n\n Args:\n tuples_list (list): A list of tuples containing integers.\n\n Returns:\n set: A set of integers.\n \"\"\"\n result = set()\n for tup in tuples_list:\n result.update(tup)\n return result", "matching_cluster_idx": 6}, {"solution": "def extract_singly(iterable):\n \"\"\"\n This function takes an iterable of tuples, \n extracts numbers from them and returns them as a set.\n\n Args:\n iterable: An iterable containing tuples of numbers.\n\n Returns:\n A set of numbers extracted from the input iterable.\n \"\"\"\n return set(num for tup in iterable for num in tup)", "matching_cluster_idx": 4}, {"solution": "def extract_singly(lst):\n \"\"\"\n This function takes a list of tuples as input and returns a set of unique numbers.\n \n :param lst: A list of tuples containing numbers\n :return: A set of unique numbers\n \"\"\"\n return set(num for tup in lst for num in tup)", "matching_cluster_idx": 4}, {"solution": "def extract_singly(list_of_tuples):\n \"\"\"\n Extract unique numbers from a list of tuples into a set.\n\n Args:\n list_of_tuples (list[tuple[int]]): A list of tuples containing integers.\n\n Returns:\n set[int]: A set of unique integers extracted from the input list of tuples.\n \"\"\"\n return set(num for tup in list_of_tuples for num in tup)", "matching_cluster_idx": 4}, {"solution": "def extract_singly(lists_of_numbers):\n \"\"\"\n Flatten the list of lists into a single set of numbers.\n\n Args:\n lists_of_numbers (list of tuples): List of tuples containing numbers.\n\n Returns:\n set: A set of numbers from the input list of tuples.\n\n \"\"\"\n # Initialize an empty set to store unique numbers\n unique_numbers = set()\n\n # Iterate over each tuple in the input list\n for num_tuple in lists_of_numbers:\n # Update the set with numbers from the current tuple\n unique_numbers.update(num_tuple)\n\n # Return the set of unique numbers\n return unique_numbers", "matching_cluster_idx": 6}, {"solution": "def extract_singly(lists):\n \"\"\"\n This function takes a list of lists of numbers and returns a set of unique numbers.\n \n Args:\n lists (list): A list of lists containing numbers.\n \n Returns:\n set: A set of unique numbers.\n \"\"\"\n # Initialize an empty set to store unique numbers.\n unique_nums = set()\n \n # Iterate over each sublist in the input list.\n for sublist in lists:\n # Update the set with the numbers from the current sublist.\n unique_nums.update(sublist)\n \n # Return the set of unique numbers.\n return unique_nums\nlists = [(3, 4, 5), (4, 5, 7), (1, 4)]", "matching_cluster_idx": 6}, {"solution": "def extract_singly(lists):\n \"\"\"\n This function takes a list of tuples as input and returns a set of unique numbers.\n \n Parameters:\n lists (list): A list of tuples, each containing integers.\n \n Returns:\n set: A set of unique integers from the input list of tuples.\n \"\"\"\n # Use a set comprehension to iterate over each tuple in the list, \n # then iterate over each number in the tuple, and add it to the set.\n return {num for tup in lists for num in tup}", "matching_cluster_idx": 5}]}, "Mbpp/141": {"dps": 96.74603174603175, "dps_norm": 66.875, "pass@1": 93.0, "profiled": [{"solution": "def pancake_sort(lst):\n \"\"\"\n Sorts a list of elements in ascending order.\n \n This function implements the built-in sorted function in Python, \n which uses the Timsort algorithm. Timsort has an average time \n complexity of O(n log n).\n\n Args:\n lst (list): A list of elements to be sorted.\n\n Returns:\n list: A sorted list of elements.\n \"\"\"\n if not isinstance(lst, list):\n raise TypeError(\"Input must be a list.\")\n\n return sorted(lst)", "matching_cluster_idx": 6}, {"solution": "def pancake_sort(lst):\n \"\"\"\n Sorts a list of elements using the pancake sort algorithm.\n\n Args:\n lst (list): The input list of elements.\n\n Returns:\n list: The sorted list of elements.\n\n \"\"\"\n # Make a copy of the input list\n lst = lst[:]\n \n # Iterate over the list, starting from the end\n for curr_size in range(len(lst), 0, -1):\n # Find the index of the maximum element in the unsorted part of the list\n max_index = lst.index(max(lst[:curr_size]))\n \n # If the maximum element is not at the end of the unsorted part, move it there\n if max_index != curr_size - 1:\n # If the maximum element is not at the beginning, flip it to the beginning\n if max_index != 0:\n lst[:max_index + 1] = reversed(lst[:max_index + 1])\n \n # Flip the unsorted part to move the maximum element to the end\n lst[:curr_size] = reversed(lst[:curr_size])\n \n return lst", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(lst):\n \"\"\"\n Sorts a list of elements in ascending order.\n\n Args:\n lst (list): A list of elements to be sorted.\n\n Returns:\n list: A new sorted list.\n \"\"\"\n # Create a copy of the list\n lst_copy = lst[:]\n\n # Iterate through the list from the largest to the smallest element\n for size in range(len(lst_copy), 0, -1):\n # Find the maximum element in the current unsorted part of the list\n max_index = lst_copy.index(max(lst_copy[:size]))\n \n # If the maximum element is not at the end of the current unsorted part, \n # flip the list until the maximum element is at the top\n if max_index != size - 1:\n # Flip the list from the beginning to the maximum element\n lst_copy[:max_index + 1] = lst_copy[:max_index + 1][::-1]\n \n # Flip the list from the beginning to the end of the current unsorted part\n lst_copy[:size] = lst_copy[:size][::-1]\n \n return lst_copy", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(arr):\n \"\"\"\n Sorts a list of elements using the pancake sort algorithm.\n\n Args:\n arr (list): A list of elements to be sorted.\n\n Returns:\n list: A sorted list of elements.\n\n \"\"\"\n def flip(arr, k):\n \"\"\"\n Flips the first k elements of the array.\n\n \"\"\"\n left = 0\n right = k\n while left < right:\n arr[left], arr[right] = arr[right], arr[left]\n left += 1\n right -= 1\n\n n = len(arr)\n # Start from the complete array and one by one reduce current size by one\n for curr_size in range(n, 0, -1):\n # Find index of the maximum element in arr[0..curr_size]\n max_index = arr.index(max(arr[0:curr_size]))\n # Move the maximum element to end of current array if it's not already at the end\n if max_index != curr_size - 1:\n # First flip 'max_index'\n if max_index != 0:\n flip(arr, max_index)\n # Now move the maximum number to end by reversing current array\n flip(arr, curr_size - 1)\n\n return arr", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(lst):\n \"\"\"\n Sorts a list of elements using the built-in sort functionality.\n\n Args:\n lst (list): A list of elements to sort.\n\n Returns:\n list: A new sorted list of elements.\n\n Example:\n >>> pancake_sort([15, 79, 25, 38, 69])\n [15, 25, 38, 69, 79]\n \"\"\"\n\n # We are simply using the built-in sort functionality of python for simplicity.\n # However, you can implement any sorting algorithm if needed.\n # Here we are choosing Timsort as it is the default and efficient.\n return sorted(lst)", "matching_cluster_idx": 6}, {"solution": "def pancake_sort(arr):\n \"\"\"\n Sorts the input list in ascending order.\n \n Args:\n arr (list): A list of elements.\n \n Returns:\n list: A sorted list of elements in ascending order.\n \"\"\"\n # Create a copy of the input list to avoid modifying it in-place\n arr = arr[:]\n \n # Initialize a variable to track the end of unsorted portion of the list\n end = len(arr)\n \n while end > 1:\n # Find the maximum element in the unsorted portion of the list\n max_idx = arr.index(max(arr[:end]))\n \n # Move the maximum element to the end of the unsorted portion\n arr[:max_idx + 1] = arr[:max_idx + 1][::-1]\n arr[:end] = arr[:end][::-1]\n \n # Move to the next unsorted portion\n end -= 1\n \n return arr", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(lst):\n \"\"\"\n Sorts a list of elements using the pancake sort algorithm.\n\n This function works by repeatedly finding the maximum element from the unsorted part and putting it at the end.\n It does this by flipping the largest number to the front of the list, then flipping the largest number to the end of the unsorted part.\n\n Args:\n lst (list): The input list of elements.\n\n Returns:\n list: The sorted list of elements.\n \"\"\"\n # Clone the list to avoid modifying the original\n lst = lst[:]\n\n # Start from the complete list and one by one reduce current size by one\n for size in range(len(lst), 0, -1):\n # Find index of the maximum element in lst[0..size]\n max_index = lst.index(max(lst[0:size]))\n\n # Move the maximum element to end of current unsorted list if it's not already at the end\n if max_index != size-1:\n # First flip 'lst[0..max_index]'\n lst[:max_index+1] = reversed(lst[:max_index+1])\n\n # Now move the maximum number to end by reversing current unsorted list\n lst[:size] = reversed(lst[:size])\n\n return lst", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(arr):\n \"\"\"\n Sorts a list of elements in ascending order.\n\n :param arr: A list of elements to sort.\n :return: A sorted list of elements.\n\n :example:\n >>> pancake_sort([15, 79, 25, 38, 69])\n [15, 25, 38, 69, 79]\n \"\"\"\n arr.sort()\n return arr", "matching_cluster_idx": 7}, {"solution": "def pancake_sort(lst):\n \"\"\"\n Sorts a list of elements in ascending order.\n\n This function uses the built-in sorted function in Python, \n which has an average time complexity of O(n log n).\n\n Args:\n lst (list): A list of elements to be sorted.\n\n Returns:\n list: A new sorted list of elements.\n \"\"\"\n\n # Make a copy of the original list\n lst_copy = lst.copy()\n\n # Use the built-in sorted function to sort the list\n sorted_list = sorted(lst_copy)\n\n return sorted_list", "matching_cluster_idx": 6}, {"solution": "def pancake_sort(arr):\n \"\"\"\n Sorts a list of elements using the pancake sort algorithm.\n\n Args:\n arr (list): The input list to be sorted.\n\n Returns:\n list: The sorted list.\n \"\"\"\n # Find the size of the input array\n n = len(arr)\n\n # Start from the complete array and one by one reduce current size by one\n for curr_size in range(n, 0, -1):\n # Find index of the maximum element in arr[0..curr_size]\n max_index = arr.index(max(arr[0:curr_size]))\n\n # Move the maximum element to end of current array if it's not already at the end\n if max_index != curr_size - 1:\n # First flip 'max_index'\n arr = arr[:max_index + 1][::-1] + arr[max_index + 1:]\n\n # Now move the maximum number to end by reversing current array\n arr = arr[:curr_size][::-1] + arr[curr_size:]\n\n return arr", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(lst):\n \"\"\"\n Sorts a list of elements in ascending order.\n\n Args:\n lst (list): A list of elements.\n\n Returns:\n list: A sorted list of elements.\n\n Example:\n >>> pancake_sort([15, 79, 25, 38, 69])\n [15, 25, 38, 69, 79]\n \"\"\"\n return sorted(lst)", "matching_cluster_idx": 6}, {"solution": "def pancake_sort(arr):\n \"\"\"\n Sorts a list of elements in ascending order.\n\n Args:\n arr (list): The list of elements to be sorted.\n\n Returns:\n list: The sorted list.\n \"\"\"\n # Make a copy of the original list to avoid modifying it in-place\n arr_copy = arr[:]\n \n # Use Python's built-in sorted function\n return sorted(arr_copy)", "matching_cluster_idx": 6}, {"solution": "def pancake_sort(lst):\n \"\"\"\n Sorts a list of elements using the pancake sort algorithm.\n\n This function repeatedly finds the maximum element in the unsorted part of the list and \n moves it to the end by flipping the entire pancake stack.\n\n Args:\n lst (list): The list of elements to be sorted.\n\n Returns:\n list: The sorted list of elements.\n \"\"\"\n # Start from the complete list and one by one reduce current size by one\n for current_size in range(len(lst), 0, -1):\n # Find index of the maximum element in lst[0..current_size]\n max_index = lst.index(max(lst[0:current_size]))\n \n # Move the maximum element to end of current_size\n # First flip 'max_index'\n lst[:max_index+1] = reversed(lst[:max_index+1])\n \n # Now move the maximum number to end by reversing current_size\n lst[:current_size] = reversed(lst[:current_size])\n \n return lst", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(lst):\n \"\"\"\n Sorts a list of elements in ascending order.\n\n This function uses the built-in sorted function in Python, which uses the Timsort algorithm.\n Timsort is a hybrid sorting algorithm derived from merge sort and insertion sort, designed to perform well on many kinds of real-world data.\n\n :param lst: A list of elements to be sorted\n :return: A new sorted list of elements\n \"\"\"\n\n return sorted(lst)", "matching_cluster_idx": 6}, {"solution": "def pancake_sort(lst):\n \"\"\"\n Sorts a list of elements using the pancake sort algorithm.\n\n Args:\n lst (list): A list of elements.\n\n Returns:\n list: A sorted list of elements.\n\n Raises:\n TypeError: If the input is not a list.\n\n Example:\n >>> pancake_sort([15, 79, 25, 38, 69])\n [15, 25, 38, 69, 79]\n \"\"\"\n\n # Check if the input is a list\n if not isinstance(lst, list):\n raise TypeError(\"Input must be a list\")\n\n # Flip the largest pancake to the top\n cur_size = len(lst)\n while cur_size > 1:\n max_index = lst.index(max(lst[0:cur_size]))\n # Flip the largest pancake to the top\n if max_index != 0:\n lst[:max_index+1] = lst[:max_index+1][::-1]\n # Flip the pancake at the top to its final position\n lst[:cur_size] = lst[:cur_size][::-1]\n cur_size -= 1\n\n return lst", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(lst):\n \"\"\"\n Sorts a list of elements using the pancake sort algorithm.\n\n Args:\n lst (list): A list of elements to be sorted.\n\n Returns:\n list: The sorted list of elements.\n \"\"\"\n n = len(lst)\n # Start from the complete array and one by one reduce current size by one\n for curr_size in range(n, 0, -1):\n # Find index of the maximum element in lst[0..curr_size]\n max_index = lst.index(max(lst[0:curr_size]))\n\n # Move the maximum element to end of current array if it's not already at the end\n if max_index != curr_size-1:\n # First flip 'max_index'\n lst[:max_index+1] = reversed(lst[:max_index+1])\n # Now move the maximum number to end by reversing current array\n lst[:curr_size] = reversed(lst[:curr_size])\n\n return lst", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(lst):\n \"\"\"\n Sorts a list of elements in ascending order.\n\n Args:\n lst (list): The input list.\n\n Returns:\n list: The sorted list.\n \"\"\"\n return sorted(lst)", "matching_cluster_idx": 6}, {"solution": "def pancake_sort(lst):\n \"\"\"\n Sorts a list of elements using the pancake sort algorithm.\n \n :param lst: The list to be sorted\n :return: A new sorted list\n \"\"\"\n def flip(lst, k):\n \"\"\"\n Flips the first k elements of a list.\n \n :param lst: The list to be flipped\n :param k: The index until which the list is flipped\n :return: The flipped list\n \"\"\"\n return lst[:k+1][::-1] + lst[k+1:]\n \n n = len(lst)\n for size in range(n, 0, -1):\n # Find the index of the maximum element in lst[0:size]\n max_index = lst.index(max(lst[0:size]))\n \n # Move the maximum element to the top of lst\n if max_index != size - 1:\n if max_index != 0:\n lst = flip(lst, max_index)\n \n # Move the maximum element to its correct position\n lst = flip(lst, size - 1)\n \n return lst", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(lst):\n \"\"\"\n Sorts a list of elements in ascending order.\n\n Args:\n lst (list): The list of elements to be sorted.\n\n Returns:\n list: A new sorted list.\n \"\"\"\n return sorted(lst)", "matching_cluster_idx": 6}, {"solution": "def pancake_sort(lst):\n \"\"\"\n Sorts a list of elements in ascending order using the Pancake sort algorithm.\n\n Args:\n lst (list): A list of elements to be sorted.\n\n Returns:\n list: A new sorted list of elements.\n \"\"\"\n # Create a copy of the input list to avoid modifying it in place\n lst = lst[:]\n n = len(lst)\n # Start from the complete array and one by one reduce current size by one\n for cur_size in range(n, 0, -1):\n # Find index of the maximum element in lst[0..cur_size]\n max_index = lst.index(max(lst[0:cur_size]))\n \n # Move the maximum element to end of current array if it's not already at the end\n if max_index != cur_size-1:\n # First flip 'max_index'\n lst = lst[:max_index+1][::-1] + lst[max_index+1:]\n # Now move the maximum number to end by reversing current array\n lst = lst[:cur_size][::-1] + lst[cur_size:]\n return lst", "matching_cluster_idx": 3}]}, "Mbpp/166": {"dps": 93.55999999999999, "dps_norm": 82.5, "pass@1": 88.0, "profiled": [{"solution": "def find_even_pair(nums):\n \"\"\"\n Count the number of pairs of integers in a list that xor to an even number.\n\n Args:\n nums (list): A list of integers.\n\n Returns:\n int: The number of pairs that xor to an even number.\n \"\"\"\n even_count = 0\n odd_count = 0\n\n for num in nums:\n if num % 2 == 0:\n even_count += 1\n else:\n odd_count += 1\n\n # Pairs can be either (even, even) or (odd, odd)\n return even_count * (even_count - 1) // 2 + odd_count * (odd_count - 1) // 2", "matching_cluster_idx": 3}, {"solution": "def find_even_pair(nums):\n \"\"\"\n Counts the number of pairs of integers in a list that xor to an even number.\n\n Args:\n nums (list): A list of integers.\n\n Returns:\n int: The number of pairs of integers that xor to an even number.\n \"\"\"\n count = 0\n n = len(nums)\n for i in range(n):\n for j in range(i + 1, n):\n # XOR is even if both numbers are either both odd or both even\n if nums[i] % 2 == nums[j] % 2:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(lst):\n \"\"\"\n Counts the number of pairs of integers in a list that xor to an even number.\n\n Args:\n lst (list): A list of integers.\n\n Returns:\n int: The number of pairs of integers that xor to an even number.\n\n \"\"\"\n even_count = 0\n odd_count = 0\n \n for num in lst:\n if num % 2 == 0:\n even_count += 1\n else:\n odd_count += 1\n \n # In a pair (a, b), if both a and b are even or both are odd, a ^ b is even\n # We count the number of possible pairs\n pairs_from_evens = even_count * (even_count - 1) // 2\n pairs_from_odds = odd_count * (odd_count - 1) // 2\n \n return pairs_from_evens + pairs_from_odds", "matching_cluster_idx": 3}, {"solution": "def find_even_pair(nums):\n \"\"\"\n Counts the number of pairs of integers in a list that xor to an even number.\n \n Args:\n - nums: A list of integers\n \n Returns:\n - The number of pairs of integers that xor to an even number\n \"\"\"\n count = 0\n for i in range(len(nums)):\n for j in range(i+1, len(nums)):\n if (nums[i] ^ nums[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(nums):\n \"\"\"\n This function counts the number of pairs of integers in a list that xor to an even number.\n\n Args:\n nums (list): A list of integers.\n\n Returns:\n int: The number of pairs of integers that xor to an even number.\n \"\"\"\n # Initialize counters for even and odd numbers\n even_count = 0\n odd_count = 0\n \n # Iterate through the list to count even and odd numbers\n for num in nums:\n if num % 2 == 0:\n even_count += 1\n else:\n odd_count += 1\n \n # Calculate the number of pairs where two even or two odd numbers xor to an even number\n # and the number of pairs where one even and one odd number xor to an odd number (which is not needed)\n even_pairs = even_count * (even_count - 1) // 2 + odd_count * (odd_count - 1) // 2\n \n return even_pairs", "matching_cluster_idx": 3}, {"solution": "def find_even_pair(numbers):\n \"\"\"\n This function counts the number of pairs of integers in a list that xor to an even number.\n \n A pair of integers a, b is considered to be a valid pair if the xor operation (a ^ b) results in an even number.\n In other words, a valid pair is one where both numbers are either both even or both odd.\n \n :param numbers: A list of integers\n :return: The number of valid pairs in the input list\n \"\"\"\n even_count = sum(1 for num in numbers if num % 2 == 0) # count even numbers\n odd_count = len(numbers) - even_count # count odd numbers\n \n # Calculate the number of valid pairs\n # There are even_count * (even_count - 1) // 2 pairs of even numbers\n # There are odd_count * (odd_count - 1) // 2 pairs of odd numbers\n even_pairs = even_count * (even_count - 1) // 2\n odd_pairs = odd_count * (odd_count - 1) // 2\n \n return even_pairs + odd_pairs\nnumbers = [5, 4, 7, 2, 1]", "matching_cluster_idx": 3}, {"solution": "def find_even_pair(nums):\n \"\"\"\n This function counts the number of pairs of integers in a list that xor to an even number.\n\n Args:\n nums (list): A list of integers.\n\n Returns:\n int: The number of pairs of integers in the list that xor to an even number.\n \"\"\"\n count_even = sum(1 for num in nums if num % 2 == 0)\n count_odd = len(nums) - count_even\n return (count_even * (count_even - 1)) // 2 + (count_odd * (count_odd - 1)) // 2", "matching_cluster_idx": 3}, {"solution": "def find_even_pair(nums):\n \"\"\"\n Counts the number of pairs of integers in a list that xor to an even number.\n\n Args:\n nums (list): A list of integers.\n\n Returns:\n int: The number of pairs of integers that xor to an even number.\n \"\"\"\n count = 0\n for i in range(len(nums)):\n for j in range(i+1, len(nums)):\n # xor of two numbers is even if both numbers have same parity\n if (nums[i] % 2 == nums[j] % 2):\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(nums):\n \"\"\"\n Counts the number of pairs of integers in a list that xor to an even number.\n \n The XOR operation results in an even number when both operands are the same (both odd or both even).\n \n :param nums: A list of integers.\n :return: The number of pairs of integers that xor to an even number.\n \"\"\"\n # Separate numbers into two lists: one for odd numbers and one for even numbers\n odd_nums = [num for num in nums if num % 2 != 0]\n even_nums = [num for num in nums if num % 2 == 0]\n \n # Calculate the number of pairs of odd numbers and even numbers separately\n odd_pairs = len(odd_nums) * (len(odd_nums) - 1) // 2\n even_pairs = len(even_nums) * (len(even_nums) - 1) // 2\n \n # Return the total number of pairs\n return odd_pairs + even_pairs", "matching_cluster_idx": 2}, {"solution": "def find_even_pair(lst):\n \"\"\"\n This function counts the number of pairs of integers in a list that xor to an even number.\n \n Args:\n lst (list): A list of integers.\n \n Returns:\n int: The number of pairs of integers that xor to an even number.\n \"\"\"\n count = 0\n for i in range(len(lst)):\n for j in range(i+1, len(lst)):\n # XOR of two numbers is even when either both are even or both are odd\n if (lst[i] % 2 == 0 and lst[j] % 2 == 0) or (lst[i] % 2 != 0 and lst[j] % 2 != 0):\n count += 1\n return count", "matching_cluster_idx": 0}, {"solution": "def find_even_pair(nums):\n \"\"\"\n This function takes a list of integers and counts the number of pairs of integers \n that xor to an even number.\n\n Args:\n nums (list): A list of integers.\n\n Returns:\n int: The number of pairs of integers that xor to an even number.\n \"\"\"\n count = 0\n # We only need to consider even and odd numbers separately, because even xor even = even and odd xor odd = even\n even_nums = [num for num in nums if num % 2 == 0]\n odd_nums = [num for num in nums if num % 2 != 0]\n \n # Count the number of pairs of even numbers\n count += len(even_nums) * (len(even_nums) - 1) // 2\n \n # Count the number of pairs of odd numbers\n count += len(odd_nums) * (len(odd_nums) - 1) // 2\n \n return count", "matching_cluster_idx": 2}, {"solution": "def find_even_pair(nums):\n \"\"\"\n This function counts the number of pairs of integers in a list that xor to an even number.\n\n Args:\n - nums (list): A list of integers.\n\n Returns:\n - int: The number of pairs of integers that xor to an even number.\n \"\"\"\n count_even = 0\n count_odd = 0\n\n # Initialize counters for even and odd numbers\n for num in nums:\n if num % 2 == 0:\n count_even += 1\n else:\n count_odd += 1\n\n # A pair of two odd numbers or two even numbers will always result in an even xor\n # The number of pairs of two even numbers or two odd numbers can be calculated using combinations\n from math import comb\n even_pairs = comb(count_even, 2) + comb(count_odd, 2)\n\n return even_pairs", "matching_cluster_idx": 3}, {"solution": "def find_even_pair(nums):\n \"\"\"\n This function counts the number of pairs of integers in a list that xor to an even number.\n\n Args:\n nums (list): A list of integers.\n\n Returns:\n int: The number of pairs of integers that xor to an even number.\n \"\"\"\n\n # The XOR operation has a property: `a ^ b` is even if and only if `a` and `b` have the same parity.\n # This is because XOR is similar to addition without carry, and the sum of two numbers with the same parity is always even.\n # Therefore, the number of pairs of integers that xor to an even number is the sum of the number of pairs of even numbers and the number of pairs of odd numbers.\n \n # First, count the number of even numbers in the list.\n even_count = sum(1 for num in nums if num % 2 == 0)\n \n # Then, count the number of odd numbers in the list.\n odd_count = len(nums) - even_count\n \n # Calculate the number of pairs of even numbers.\n even_pairs = even_count * (even_count - 1) // 2\n \n # Calculate the number of pairs of odd numbers.\n odd_pairs = odd_count * (odd_count - 1) // 2\n \n # Return the total number of pairs.\n return even_pairs + odd_pairs", "matching_cluster_idx": 3}, {"solution": "def find_even_pair(nums):\n \"\"\"\n This function counts the number of pairs of integers in a list that xor to an even number.\n\n Args:\n nums (list): A list of integers.\n\n Returns:\n int: The number of pairs of integers that xor to an even number.\n\n Example:\n >>> find_even_pair([5, 4, 7, 2, 1])\n 4\n \"\"\"\n\n # Initialize counter for the number of even pairs\n count = 0\n\n # Iterate through the list\n for i in range(len(nums)):\n # Check every other element in the list for even pair\n for j in range(i + 1, len(nums)):\n # Check if xor of the pair is even (i.e., remainder when divided by 2 equals 0)\n if (nums[i] ^ nums[j]) % 2 == 0:\n # Increment counter for even pair\n count += 1\n\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(lst):\n \"\"\"\n This function counts the number of pairs of integers in a list that xor to an even number.\n \n Args:\n lst (list): A list of integers.\n \n Returns:\n int: The number of pairs of integers that xor to an even number.\n \"\"\"\n even_count = sum(1 for num in lst if num % 2 == 0)\n odd_count = len(lst) - even_count\n \n # Since XORing two even numbers results in an even number, we can find all pairs of even numbers.\n even_pairs = even_count * (even_count - 1) // 2\n \n # Similarly, we can find all pairs of odd numbers.\n odd_pairs = odd_count * (odd_count - 1) // 2\n \n return even_pairs + odd_pairs", "matching_cluster_idx": 3}, {"solution": "def find_even_pair(nums):\n \"\"\"\n This function takes a list of integers as input and returns the number of pairs of integers in the list that xor to an even number.\n\n The XOR operation on two integers results in an even number if both numbers are even or both numbers are odd.\n\n :param nums: A list of integers\n :return: The number of pairs of integers in the list that xor to an even number\n \"\"\"\n\n # Count the total number of integers in the list\n total_count = len(nums)\n\n # Initialize counters for even and odd numbers\n even_count = 0\n odd_count = 0\n\n # Iterate over the list to count the number of even and odd numbers\n for num in nums:\n if num % 2 == 0:\n even_count += 1\n else:\n odd_count += 1\n\n # Calculate the total number of pairs of integers that xor to an even number\n # Even number of even numbers can be paired among themselves in (n * (n-1)) / 2 ways\n # Similarly, odd numbers can be paired among themselves\n even_pairs = (even_count * (even_count - 1)) // 2\n odd_pairs = (odd_count * (odd_count - 1)) // 2\n\n # Return the total number of pairs\n return even_pairs + odd_pairs", "matching_cluster_idx": 3}, {"solution": "def find_even_pair(nums):\n \"\"\"\n Counts the number of pairs of integers in a list that xor to an even number.\n\n A pair of integers (a, b) in a list will xor to an even number if either both\n numbers are even or both numbers are odd.\n\n Args:\n nums: A list of integers.\n\n Returns:\n The number of pairs of integers in the list that xor to an even number.\n \"\"\"\n\n # Count the total number of pairs in the list\n total_pairs = (len(nums) * (len(nums) - 1)) // 2\n\n # Count the number of even numbers\n even_count = sum(1 for num in nums if num % 2 == 0)\n\n # Calculate the number of pairs with both numbers being odd or both even\n pairs_with_same_parity = (even_count * (even_count - 1)) // 2\n pairs_with_same_parity += ((len(nums) - even_count) * (len(nums) - even_count - 1)) // 2\n\n return pairs_with_same_parity", "matching_cluster_idx": 3}, {"solution": "def find_even_pair(nums):\n \"\"\"\n This function counts the number of pairs of integers in a list that xor to an even number.\n \n Args:\n nums (list): A list of integers.\n \n Returns:\n int: The number of pairs of integers that xor to an even number.\n \"\"\"\n \n # Separate the numbers into two lists, one for even and one for odd numbers\n even_nums = [num for num in nums if num % 2 == 0]\n odd_nums = [num for num in nums if num % 2 != 0]\n \n # Calculate the number of pairs between even and odd numbers\n # Since even ^ odd = odd, all these pairs will xor to an odd number\n pairs_even_odd = len(even_nums) * len(odd_nums)\n \n # Calculate the number of pairs within even numbers\n # Since even ^ even = even, all these pairs will xor to an even number\n pairs_even_even = len(even_nums) * (len(even_nums) - 1) // 2\n \n # Calculate the number of pairs within odd numbers\n # Since odd ^ odd = even, all these pairs will xor to an even number\n pairs_odd_odd = len(odd_nums) * (len(odd_nums) - 1) // 2\n \n # The total number of pairs that xor to an even number is the sum of pairs within even numbers and pairs within odd numbers\n return pairs_even_even + pairs_odd_odd", "matching_cluster_idx": 2}, {"solution": "def find_even_pair(nums):\n \"\"\"\n Counts the number of pairs of integers in a list that xor to an even number.\n\n Since XOR of two numbers is even if both numbers are even or both numbers are odd,\n we count all pairs where both numbers have the same parity.\n\n Args:\n nums: A list of integers.\n\n Returns:\n An integer representing the number of pairs of integers that xor to an even number.\n \"\"\"\n even_count = sum(1 for num in nums if num % 2 == 0)\n odd_count = len(nums) - even_count\n return even_count * (even_count - 1) // 2 + odd_count * (odd_count - 1) // 2", "matching_cluster_idx": 3}, {"solution": "def find_even_pair(nums):\n \"\"\"\n This function counts the number of pairs of integers in a list that xor to an even number.\n \n Args:\n nums (list): A list of integers.\n \n Returns:\n int: The number of pairs of integers that xor to an even number.\n \"\"\"\n even_count = sum(1 for num in nums if num % 2 == 0)\n odd_count = len(nums) - even_count\n \n # The number of pairs that xor to an even number is the sum of the number of pairs \n # that can be formed from even numbers and odd numbers separately.\n # The number of pairs that can be formed from even numbers is the number of even numbers choose 2.\n even_pairs = even_count * (even_count - 1) // 2\n # The number of pairs that can be formed from odd numbers is the number of odd numbers choose 2.\n odd_pairs = odd_count * (odd_count - 1) // 2\n \n return even_pairs + odd_pairs", "matching_cluster_idx": 3}]}, "Mbpp/170": {"dps": null, "dps_norm": null, "pass@1": 4.0, "profiled": []}, "Mbpp/226": {"dps": 85.69767441860465, "dps_norm": 64.28571428571429, "pass@1": 85.0, "profiled": [{"solution": "def odd_values_string(input_str):\n \"\"\"\n Returns a string consisting of characters with even indices from the input string.\n\n Args:\n input_str (str): The input string.\n\n Returns:\n str: A string containing characters at even indices of the input string.\n\n \"\"\"\n # Use Python's list comprehension and enumerate to create a list of characters at even indices\n even_chars = [char for idx, char in enumerate(input_str) if idx % 2 == 0]\n return ''.join(even_chars)", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(s):\n \"\"\"\n Removes characters which have odd index values from a given string.\n\n Args:\n s (str): The input string.\n\n Returns:\n str: A string with characters from the input string at even index values.\n \"\"\"\n return s[::2]", "matching_cluster_idx": 6}, {"solution": "def odd_values_string(s: str) -> str:\n \"\"\"\n Removes characters at odd index values from the given string.\n\n Args:\n s (str): The input string.\n\n Returns:\n str: A new string containing only the characters at even index values from the original string.\n \"\"\"\n return ''.join([char for i, char in enumerate(s) if i % 2 == 0])", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(s: str) -> str:\n \"\"\"\n This function takes a string input and returns a new string \n containing only characters at even index values.\n\n Args:\n s (str): The input string.\n\n Returns:\n str: The output string with characters at odd index values removed.\n \"\"\"\n\n # Initialize an empty string to store the result\n result = \"\"\n\n # Iterate over the input string using enumerate to get index and value\n for index, value in enumerate(s):\n \n # Check if the index is even\n if index % 2 == 0:\n # Append the character to the result string if index is even\n result += value\n\n # Return the result string\n return result", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(input_str):\n \"\"\"\n Returns a new string where the characters at even index values from the input string are kept.\n\n :param input_str: The input string to process.\n :return: A new string with only characters at even index values.\n \"\"\"\n # Check if input is a string\n if not isinstance(input_str, str):\n raise ValueError('Input must be a string')\n\n # Use list comprehension and string slicing to filter characters at even index values\n return ''.join([char for idx, char in enumerate(input_str) if idx % 2 == 0])", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(s):\n \"\"\"\n Returns a string with characters at odd indices removed from the input string.\n\n :param s: Input string\n :return: String with characters at odd indices removed\n \"\"\"\n return s[::2]", "matching_cluster_idx": 6}, {"solution": "def odd_values_string(s):\n \"\"\"\n Returns a string containing characters from the input string at even indices.\n \n Parameters:\n s (str): The input string.\n \n Returns:\n str: The resulting string.\n \"\"\"\n return s[::2]", "matching_cluster_idx": 6}, {"solution": "def odd_values_string(s):\n \"\"\"\n Removes characters at odd index values from a given string.\n\n Args:\n s (str): Input string.\n\n Returns:\n str: String with characters at odd index values removed.\n \"\"\"\n return s[::2]", "matching_cluster_idx": 6}, {"solution": "def odd_values_string(s):\n \"\"\"\n This function removes characters at odd index values from the given string.\n\n Parameters:\n s (str): The input string\n\n Returns:\n str: The resulting string with characters at odd index values removed\n \"\"\"\n return ''.join([s[i] for i in range(len(s)) if i % 2 == 0])", "matching_cluster_idx": 1}, {"solution": "def odd_values_string(s):\n \"\"\"\n This function removes the characters which have odd index values of a given string.\n \n Parameters:\n s (str): The input string\n \n Returns:\n str: A string with characters at odd index positions removed\n \"\"\"\n # Initialize an empty string to store the result\n result = ''\n \n # Iterate over the input string, considering only even index positions\n for i in range(len(s)):\n # If the index is even, add the character to the result string\n if i % 2 == 0:\n result += s[i]\n \n # Return the result string\n return result", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(s):\n \"\"\"\n Removes characters at odd index positions from the string.\n\n Args:\n s (str): Input string.\n\n Returns:\n str: String with characters at odd index positions removed.\n\n \"\"\"\n return s[::2]", "matching_cluster_idx": 5}, {"solution": "def odd_values_string(input_str):\n \"\"\"\n Removes characters with odd index values from the input string.\n\n Args:\n input_str (str): The string from which characters are to be removed.\n\n Returns:\n str: A new string containing only the characters at even index positions.\n \"\"\"\n return ''.join([char for idx, char in enumerate(input_str) if idx % 2 == 0])", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(input_string):\n \"\"\"\n Returns a new string with characters at even index values from the input string.\n\n Args:\n input_string (str): The input string from which characters with odd index values are removed.\n\n Returns:\n str: A new string containing characters from even index values of the input string.\n \"\"\"\n return input_string[::2]", "matching_cluster_idx": 6}, {"solution": "def odd_values_string(s):\n \"\"\"\n This function removes the characters which have odd index values of a given string.\n\n Parameters:\n s (str): The input string.\n\n Returns:\n str: A new string containing only characters with even index values.\n\n \"\"\"\n return s[::2]", "matching_cluster_idx": 6}, {"solution": "def odd_values_string(s):\n \"\"\"\n This function takes a string as input and returns a new string \n containing only characters at even index positions.\n \n Parameters:\n s (str): The input string\n \n Returns:\n str: A new string containing characters at even index positions.\n \"\"\"\n return s[::2]", "matching_cluster_idx": 6}, {"solution": "def odd_values_string(s):\n \"\"\"\n Returns a string containing characters from the original string that are at even indices.\n \n Parameters:\n s (str): Input string\n \n Returns:\n str: String containing characters from the original string at even indices\n \"\"\"\n return s[::2]", "matching_cluster_idx": 6}, {"solution": "def odd_values_string(s):\n \"\"\"\n Removes the characters which have odd index values of a given string.\n\n Args:\n s (str): The input string.\n\n Returns:\n str: The resulting string with characters at odd indices removed.\n \"\"\"\n # Use slicing to extract characters at even indices (0, 2, 4, etc.)\n return s[::2]", "matching_cluster_idx": 6}, {"solution": "def odd_values_string(s):\n \"\"\"\n Returns a string consisting of characters at odd index values (0-indexed) of the input string.\n\n :param s: Input string\n :return: String containing characters at odd index values\n \"\"\"\n return s[::2]", "matching_cluster_idx": 5}, {"solution": "def odd_values_string(s: str) -> str:\n \"\"\"\n Returns a new string consisting only of characters at even indices from the original string.\n \n Args:\n s (str): The input string.\n \n Returns:\n str: A string consisting of characters from the input string at even indices.\n \"\"\"\n return s[::2]", "matching_cluster_idx": 5}, {"solution": "def odd_values_string(s: str) -> str:\n \"\"\"\n Returns a new string containing characters at even index positions from the given string.\n \n Parameters:\n s (str): The input string.\n \n Returns:\n str: A string with characters at even index positions.\n \"\"\"\n return ''.join([char for index, char in enumerate(s) if index % 2 == 0])", "matching_cluster_idx": 0}]}, "Mbpp/230": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 98.0, "profiled": [{"solution": "def replace_blank(s, char):\n \"\"\"\n Replaces blank spaces in the string with a given character.\n\n Args:\n s (str): The input string.\n char (str): The character to replace blank spaces with.\n\n Returns:\n str: The modified string with blank spaces replaced.\n \"\"\"\n return s.replace(\" \", char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string, character):\n \"\"\"\n Replace blank spaces in the string with the given character.\n\n Args:\n input_string (str): The string where blank spaces need to be replaced.\n character (str): The character to replace blank spaces with.\n\n Returns:\n str: The string with blank spaces replaced by the given character.\n \"\"\"\n return input_string.replace(' ', character)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(s, char):\n \"\"\"\n Replace blank spaces in the string with the given character.\n\n Args:\n s (str): Input string\n char (str): Replacement character\n\n Returns:\n str: String with blank spaces replaced\n \"\"\"\n return s.replace(' ', char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_str, char):\n \"\"\"\n Replaces blank spaces in a string with a specified character.\n\n Args:\n input_str (str): The input string.\n char (str): The character to replace blank spaces with.\n\n Returns:\n str: The modified string with blank spaces replaced.\n \"\"\"\n return input_str.replace(\" \", char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(s, char):\n \"\"\"\n Replaces all blank spaces in a given string with a specified character.\n \n Args:\n s (str): Input string.\n char (str): Character to replace blank spaces with.\n\n Returns:\n str: The modified string with no blank spaces.\n \"\"\"\n return s.replace(\" \", char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_str, char):\n \"\"\"\n Replaces all blank spaces in a string with a specified character.\n\n Args:\n input_str (str): The input string to be processed.\n char (str): The character to replace blank spaces with.\n\n Returns:\n str: The input string with all blank spaces replaced.\n\n \"\"\"\n return input_str.replace(\" \", char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_str, char):\n \"\"\"\n Replaces blank spaces in a string with a given character.\n\n Args:\n input_str (str): The input string.\n char (str): The character to replace blank spaces with.\n\n Returns:\n str: The string with blank spaces replaced.\n \"\"\"\n return input_str.replace(' ', char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(s, char):\n \"\"\"\n Replaces blank spaces in a given string with a specified character.\n\n Args:\n s (str): The input string.\n char (str): The character to replace blank spaces with.\n\n Returns:\n str: The modified string with blank spaces replaced.\n\n \"\"\"\n return s.replace(\" \", char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string, char):\n \"\"\"\n Replaces blank spaces in the input string with a given character.\n\n Args:\n input_string (str): The string where blank spaces will be replaced.\n char (str): The character that will replace blank spaces.\n\n Returns:\n str: A new string with blank spaces replaced.\n \"\"\"\n return input_string.replace(' ', char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_str, char):\n \"\"\"\n Replace blank spaces in a string with a given character.\n\n Args:\n input_str (str): Input string that needs to be processed.\n char (str): Character to replace the blank spaces with.\n\n Returns:\n str: String with blank spaces replaced.\n \"\"\"\n return input_str.replace(\" \", char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string, character):\n \"\"\"\n Replaces all blank spaces in a given string with a specified character.\n\n Args:\n input_string (str): The string in which to replace blank spaces.\n character (str): The character with which to replace blank spaces.\n\n Returns:\n str: The modified string.\n \"\"\"\n return input_string.replace(' ', character)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string, char):\n \"\"\"\n Replaces all blank spaces in the input string with a specified character.\n \n Parameters:\n input_string (str): The input string where spaces are to be replaced.\n char (str): A single character to replace the blank spaces with.\n \n Returns:\n str: The input string with all blank spaces replaced by the specified character.\n \"\"\"\n return input_string.replace(' ', char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string, replacement_char):\n \"\"\"\n Replaces blank spaces in the input string with the provided replacement character.\n \n Args:\n input_string (str): The input string where blank spaces are to be replaced.\n replacement_char (str): The character to replace the blank spaces with.\n \n Returns:\n str: The modified string with replacement character in place of blank spaces.\n \"\"\"\n return input_string.replace(' ', replacement_char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string, char):\n \"\"\"\n Replaces blank spaces in the input string with a given character.\n\n Args:\n input_string (str): The input string with blank spaces.\n char (str): The character to replace blank spaces.\n\n Returns:\n str: The modified string without blank spaces.\n \"\"\"\n return input_string.replace(\" \", char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_str, char):\n \"\"\"\n This function takes in a string and character, replaces blank spaces in the string with the character, and returns the string.\n\n Args:\n input_str (str): The input string with potential blank spaces.\n char (str): The character to replace blank spaces.\n\n Returns:\n str: The modified string with no blank spaces.\n \"\"\"\n return input_str.replace(' ', char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_str, replacement_char):\n \"\"\"\n Replaces blank spaces in the input string with a specified character.\n \n Parameters:\n input_str (str): The string in which to replace blank spaces.\n replacement_char (str): The character with which to replace blank spaces.\n \n Returns:\n str: The string with blank spaces replaced.\n \"\"\"\n return input_str.replace(\" \", replacement_char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string, char):\n \"\"\"\n Replaces blank spaces in the input string with the given character.\n\n Args:\n input_string (str): The string in which to replace blank spaces.\n char (str): The character to replace blank spaces with.\n\n Returns:\n str: The string with blank spaces replaced.\n\n Examples:\n >>> replace_blank(\"hello people\", '@')\n 'hello@people'\n \"\"\"\n return input_string.replace(' ', char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string, char):\n \"\"\"\n Replaces blank spaces in the input string with the given character.\n\n Args:\n input_string (str): The string where blank spaces will be replaced.\n char (str): The character that replaces the blank spaces.\n\n Returns:\n str: A new string where all blank spaces from the input string have been replaced.\n \"\"\"\n return input_string.replace(\" \", char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string, replacement_char):\n \"\"\"\n This function replaces all blank spaces in the input string with the replacement character.\n \n Args:\n input_string (str): The input string where blank spaces need to be replaced.\n replacement_char (str): The character that will replace the blank spaces in the input string.\n\n Returns:\n str: The modified string where all blank spaces have been replaced.\n \"\"\"\n return input_string.replace(\" \", replacement_char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_str, char):\n \"\"\"\n This function replaces all blank spaces in the input string with a specified character.\n\n Args:\n input_str (str): The input string that may contain blank spaces.\n char (str): The character that will replace the blank spaces.\n\n Returns:\n str: The modified string with blank spaces replaced by the specified character.\n \"\"\"\n return input_str.replace(' ', char)", "matching_cluster_idx": 7}]}, "Mbpp/239": {"dps": 53.275862068965516, "dps_norm": 62.5, "pass@1": 31.0, "profiled": [{"solution": "def get_total_number_of_sequences(m, n):\n \"\"\"\n Calculate the total number of possible sequences of length n, \n where each element is a positive integer greater than or equal \n to twice the previous element but less than or equal to m.\n\n Args:\n m (int): The upper limit of sequence elements.\n n (int): The length of the sequence.\n\n Returns:\n int: The total number of possible sequences.\n \"\"\"\n memo = {}\n\n def backtrack(i, prev):\n # Base case: when sequence length is reached\n if i == n:\n return 1\n \n # Check if state is already in memo\n if (i, prev) in memo:\n return memo[(i, prev)]\n\n total = 0\n # Start from twice the previous element, up to m\n for j in range(max(1, prev * 2), m + 1):\n total += backtrack(i + 1, j)\n\n # Store state in memo\n memo[(i, prev)] = total\n return total\n\n return backtrack(0, 0)", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n \"\"\"\n This function calculates the total number of possible sequences of length n, \n where each element is a positive integer and is greater than or equal to twice \n the previous element but less than or equal to m.\n\n Args:\n m (int): The upper limit for the sequence elements.\n n (int): The length of the sequence.\n\n Returns:\n int: The total number of possible sequences.\n \"\"\"\n # Initialize a list to store the total number of sequences for each possible previous value.\n dp = [0] * (m + 1)\n # For a sequence of length 1, the total number of sequences is equal to the number of possible values.\n dp = [1] * (m + 1)\n\n # Iterate over the length of the sequence from 2 to n.\n for _ in range(1, n):\n # Initialize a new list to store the total number of sequences for the current length.\n new_dp = [0] * (m + 1)\n # Iterate over the possible values for the current element.\n for j in range(1, m + 1):\n # Calculate the total number of sequences for the current value.\n # This is the sum of the total number of sequences for all previous values that are less than or equal to j // 2.\n new_dp[j] = sum(dp[1:j // 2 + 1])\n # Update the list of total number of sequences for the next length.\n dp = new_dp\n\n # The total number of sequences is the sum of the total number of sequences for all possible last values.\n return sum(dp[1:])", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n \"\"\"\n Calculate the number of possible sequences of length n, \n such that each element is a positive integer and is greater \n than or equal to twice the previous element but less than or equal to m.\n\n Parameters:\n m (int): The maximum possible value in the sequence.\n n (int): The length of the sequence.\n\n Returns:\n int: The total number of possible sequences.\n \"\"\"\n # Initialize a 2D array to store dynamic programming results\n dp = [[0] * (m + 1) for _ in range(n)]\n\n # Base case: For sequences of length 1, \n # there are m possible sequences: [1], [2], ..., [m]\n for i in range(1, m + 1):\n dp[0][i] = 1\n\n # Calculate the number of possible sequences for each length\n for i in range(1, n):\n for j in range(1, m + 1):\n # For each possible previous element, calculate the number of sequences\n for k in range(j // 2, 0, -1):\n dp[i][j] += dp[i - 1][k]\n\n # The total number of possible sequences is the sum of sequences ending with any number\n return sum(dp[-1])", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n \"\"\"\n This function calculates the number of possible sequences of length n, \n such that each element is a positive integer and is greater than or equal \n to twice the previous element but less than or equal to m.\n\n Args:\n m (int): The upper bound of the sequence.\n n (int): The length of the sequence.\n\n Returns:\n int: The total number of possible sequences.\n \"\"\"\n def backtrack(index, prev_element):\n # Base case: if we have reached the desired length, return 1\n if index == n:\n return 1\n \n # Initialize the count of sequences for the current index\n count = 0\n \n # Iterate over all possible next elements\n for next_element in range(max(prev_element * 2, 1), m + 1):\n # Recursively call the backtrack function and add the result to the count\n count += backtrack(index + 1, next_element)\n \n return count\n \n # Call the backtrack function and return the result\n return backtrack(0, 0)", "matching_cluster_idx": 3}, {"solution": "def get_total_number_of_sequences(m, n):\n \"\"\"\n This function calculates the number of possible sequences of length n, \n where each element is a positive integer greater than or equal to twice \n the previous element but less than or equal to m.\n\n Args:\n m (int): The upper limit for the sequence elements.\n n (int): The length of the sequence.\n\n Returns:\n int: The total number of possible sequences.\n \"\"\"\n # Initialize a 2D array to store dynamic programming state\n dp = [[0] * (m + 1) for _ in range(n)]\n\n # For a sequence of length 1, the number of possible sequences is m\n for i in range(1, m + 1):\n dp[0][i] = 1\n\n # For each sequence length from 2 to n\n for i in range(1, n):\n # For each possible last element in the sequence\n for j in range(1, m + 1):\n # The number of sequences ending with j is the sum of the number of sequences of the previous length\n # ending with a number less than or equal to j // 2 (because the next number must be at least twice as large)\n dp[i][j] = sum(dp[i - 1][:j // 2 + 1])\n\n # The total number of sequences is the sum of the number of sequences of length n ending with any number\n return sum(dp[-1])", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n \"\"\"\n Calculate the total number of sequences where each element is greater than \n or equal to twice the previous element but less than or equal to m.\n\n Args:\n m (int): The maximum value for each element in the sequence.\n n (int): The length of the sequence.\n\n Returns:\n int: The total number of sequences.\n\n \"\"\"\n def dfs(i, prev):\n # Base case: if we've reached the end of the sequence, count it\n if i == n:\n return 1\n \n total = 0\n # Try each possible value for the current element\n for j in range(max(prev * 2, 1), m + 1):\n # Recursively calculate the total number of sequences for the rest of the sequence\n total += dfs(i + 1, j)\n \n return total\n\n return dfs(0, 0)", "matching_cluster_idx": 3}, {"solution": "def get_total_number_of_sequences(m, n):\n \"\"\"\n Calculate the total number of possible sequences of length n where each element is\n a positive integer and is greater than or equal to twice the previous element but\n less than or equal to m.\n\n Args:\n m (int): Maximum value for elements in sequence.\n n (int): Length of sequence.\n\n Returns:\n int: Total number of possible sequences.\n \"\"\"\n memo = {}\n\n def dfs(current, count, last_val):\n # Base case: sequence is complete.\n if count == n:\n return 1\n \n # If subproblem has already been solved, return stored result.\n if (count, last_val) in memo:\n return memo[(count, last_val)]\n \n total_count = 0\n # Generate next elements in the range [2*last_val, m].\n for i in range(max(1, 2 * last_val), m + 1):\n # Recursively build sequences with new element.\n total_count += dfs(i, count + 1, i)\n \n # Store the result of subproblem to avoid redundant calculations.\n memo[(count, last_val)] = total_count\n return total_count\n \n # Initialize last value to 0 to satisfy \"twice the previous element\" rule for the first element.\n return dfs(0, 0, 0)", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n \"\"\"\n Calculate the number of possible sequences of length n, such that each element is a \n positive integer and is greater than or equal to twice the previous element but \n less than or equal to m.\n\n Args:\n m (int): The maximum possible value in the sequence.\n n (int): The length of the sequence.\n\n Returns:\n int: The number of possible sequences.\n\n \"\"\"\n def backtrack(start, m, n):\n # Base case: if sequence length is reached, return 1\n if n == 0:\n return 1\n \n count = 0\n # Iterate over possible numbers from start to m\n for i in range(start, m+1):\n # Recursively call the backtrack function for remaining sequence length\n count += backtrack(i*2, m, n-1)\n \n return count\n \n # Start with 1 and all possible numbers greater than or equal to 2\n return backtrack(1, m, n)", "matching_cluster_idx": 5}, {"solution": "def get_total_number_of_sequences(m: int, n: int) -> int:\n \"\"\"\n This function calculates the total number of sequences of length n, \n such that each element is a positive integer and is greater than or equal \n to twice the previous element but less than or equal to m.\n\n Args:\n m (int): The maximum value for the sequence elements.\n n (int): The length of the sequence.\n\n Returns:\n int: The total number of possible sequences.\n \"\"\"\n # Initialize a 2D list to store the dynamic programming state\n dp = [[0] * (m + 1) for _ in range(n)]\n\n # Initialize the base case for the first row\n # There are m possibilities for a sequence of length 1\n for j in range(1, m + 1):\n dp[0][j] = 1\n\n # Fill up the dp table in a bottom-up manner\n for i in range(1, n):\n for j in range(1, m + 1):\n # For each element, consider all possible previous elements\n for k in range(j // 2, 0, -1):\n dp[i][j] += dp[i - 1][k]\n\n # The total number of sequences is the sum of all possibilities for the last element\n return sum(dp[-1])", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n \"\"\"\n This function calculates the number of possible sequences of length n, \n where each element is a positive integer greater than or equal to twice \n the previous element but less than or equal to m.\n\n Args:\n m (int): The maximum value for elements in the sequence.\n n (int): The length of the sequence.\n\n Returns:\n int: The total number of possible sequences.\n\n \"\"\"\n def helper(current_num, remaining_length, prev_num):\n # Base case: If remaining length is 1, any number greater than or equal \n # to twice the previous number and less than or equal to m can be chosen.\n if remaining_length == 1:\n return max(0, m - max(2 * prev_num, 1) + 1)\n \n # Recursive case: Try all possible numbers from max(2 * prev_num, 1) to m.\n total_count = 0\n for next_num in range(max(2 * prev_num, 1), m + 1):\n total_count += helper(next_num, remaining_length - 1, next_num)\n \n return total_count\n\n # Start with any number from 1 to m.\n total_count = 0\n for start_num in range(1, m + 1):\n total_count += helper(start_num, n - 1, start_num)\n\n return total_count", "matching_cluster_idx": 3}, {"solution": "def get_total_number_of_sequences(m, n):\n \"\"\"\n Returns the number of possible sequences of length n, \n such that each element is a positive integer and is \n greater than or equal to twice the previous element \n but less than or equal to m.\n\n Args:\n m (int): Maximum possible value in a sequence.\n n (int): Length of the sequence.\n\n Returns:\n int: The number of possible sequences.\n\n Raises:\n ValueError: If m or n is not a positive integer.\n \"\"\"\n if not (isinstance(m, int) and isinstance(n, int) and m > 0 and n > 0):\n raise ValueError(\"Both m and n must be positive integers.\")\n\n # Initialize dp table\n dp = [[0] * (m + 1) for _ in range(n)]\n\n # Base case: There is one sequence of length 1 for each possible number i, which is [i].\n for i in range(1, m + 1):\n dp[0][i] = 1\n\n # Fill dp table in bottom-up manner\n for i in range(1, n):\n for j in range(1, m + 1):\n # For each possible previous element k, we need to have k <= j // 2\n for k in range(1, j // 2 + 1):\n dp[i][j] += dp[i - 1][k]\n\n # Sum up all sequences of length n\n return sum(dp[-1])", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n \"\"\"\n This function calculates the total number of possible sequences of length n, \n such that each element is a positive integer and is greater than or equal to \n twice the previous element but less than or equal to m.\n\n Args:\n m (int): The upper limit for sequence elements.\n n (int): The length of the sequences.\n\n Returns:\n int: The total number of possible sequences.\n \"\"\"\n def backtrack(current_sequence, last_element):\n # Base case: if the sequence has the desired length, count it.\n if len(current_sequence) == n:\n return 1\n \n count = 0\n # Try all possible numbers that can come next in the sequence.\n for next_element in range(max(1, last_element * 2), m + 1):\n # Add the next element to the sequence and continue the backtracking process.\n count += backtrack(current_sequence + [next_element], next_element)\n \n return count\n\n # Start the backtracking process with an empty sequence and 0 as the last element.\n return backtrack([], 0)", "matching_cluster_idx": 3}, {"solution": "def get_total_number_of_sequences(m, n):\n \"\"\"\n Calculate the number of possible sequences of length n, where each element \n is a positive integer, greater than or equal to twice the previous element \n and less than or equal to m.\n\n Args:\n m (int): The upper bound for sequence elements.\n n (int): The length of the sequence.\n\n Returns:\n int: The total number of possible sequences.\n \"\"\"\n def backtrack(current_sequence, last_element):\n if len(current_sequence) == n:\n return 1\n \n total_sequences = 0\n for i in range(max(last_element * 2, 1), m + 1):\n total_sequences += backtrack(current_sequence + [i], i)\n \n return total_sequences\n\n return backtrack([], 0)", "matching_cluster_idx": 3}, {"solution": "def get_total_number_of_sequences(m, n):\n \"\"\"\n Returns the number of possible sequences of length n, \n where each element is a positive integer and is greater \n than or equal to twice the previous element but less \n than or equal to m.\n\n Args:\n m (int): The maximum allowed value for each element in the sequence.\n n (int): The length of the sequence.\n\n Returns:\n int: The number of possible sequences.\n \"\"\"\n # Handle invalid inputs\n if not isinstance(m, int) or not isinstance(n, int):\n raise TypeError(\"Both m and n must be integers\")\n if m <= 0 or n <= 0:\n raise ValueError(\"Both m and n must be positive\")\n\n def helper(k, prev):\n # Base case: if we've reached the desired sequence length\n if k == n:\n return 1\n \n count = 0\n # Try all possible values for the current element\n for i in range(max(1, prev * 2), m + 1):\n # Recursively add the count of sequences with the current element\n count += helper(k + 1, i)\n return count\n\n return helper(0, 0)", "matching_cluster_idx": 3}, {"solution": "def get_total_number_of_sequences(m: int, n: int) -> int:\n \"\"\"\n Calculate the total number of possible sequences of length n where each element is a \n positive integer greater than or equal to twice the previous element and less than \n or equal to m.\n\n Args:\n m (int): The maximum allowed number in the sequence.\n n (int): The length of the sequence.\n\n Returns:\n int: The total number of possible sequences.\n\n \"\"\"\n memo = {}\n\n def recurse(current_num, steps_left):\n # If we have reached the end of the sequence length, return 1.\n if steps_left == 0:\n return 1\n \n # If we already calculated the number of sequences starting with current_num, \n # return the stored result.\n if (current_num, steps_left) in memo:\n return memo[(current_num, steps_left)]\n\n # Calculate the number of sequences starting with current_num.\n num_sequences = 0\n for next_num in range(current_num * 2, m + 1):\n num_sequences += recurse(next_num, steps_left - 1)\n\n # Store the result for future use.\n memo[(current_num, steps_left)] = num_sequences\n\n return num_sequences\n\n # Start the recursion with the first number as 1 (smallest possible positive integer)\n total_sequences = 0\n for first_num in range(1, m + 1):\n total_sequences += recurse(first_num, n - 1)\n\n return total_sequences", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n \"\"\"\n This function calculates the total number of sequences of length n, such that each element is a \n positive integer and is greater than or equal to twice the previous element but less than or \n equal to m.\n\n Args:\n m (int): The upper limit of the numbers in the sequences.\n n (int): The length of the sequences.\n\n Returns:\n int: The total number of sequences.\n \"\"\"\n def helper(prev, n):\n # Base case: if we have filled all n positions\n if n == 0:\n return 1\n \n # Recursive case: try all possible values that are at least double the previous value\n total = 0\n for i in range(max(1, 2*prev), m + 1):\n total += helper(i, n - 1)\n \n return total\n \n # Start the recursion\n total = 0\n for i in range(1, m + 1):\n total += helper(i, n - 1)\n \n return total", "matching_cluster_idx": 3}, {"solution": "def get_total_number_of_sequences(m, n):\n \"\"\"\n Calculate the total number of possible sequences of length n, where each element is a positive integer\n greater than or equal to twice the previous element but less than or equal to m.\n\n Args:\n m (int): The maximum value of each element in the sequence.\n n (int): The length of the sequence.\n\n Returns:\n int: The total number of possible sequences.\n\n Example:\n >>> get_total_number_of_sequences(10, 4)\n 4\n \"\"\"\n def backtrack(start, path):\n # Base case: if the length of the path equals n, add 1 to the count\n if len(path) == n:\n return 1\n \n count = 0\n # Iterate through possible numbers from start to m\n for num in range(start, m + 1):\n # Recursively call the backtrack function with the updated path and start value\n count += backtrack(num * 2, path + [num])\n return count\n\n # Call the backtrack function with initial values\n return backtrack(1, [])", "matching_cluster_idx": 4}, {"solution": "def get_total_number_of_sequences(m, n):\n \"\"\"\n This function calculates the number of possible sequences of length n, \n where each element is a positive integer greater than or equal to twice \n the previous element but less than or equal to m.\n\n Args:\n m (int): The upper bound for the sequence elements.\n n (int): The length of the sequences.\n\n Returns:\n int: The total number of possible sequences.\n \"\"\"\n # Initialize a list to store the number of sequences ending at each number up to m\n dp = [0] * (m + 1)\n # There is 1 way to end a sequence of length 1 at each number from 1 to m\n for i in range(1, m + 1):\n dp[i] = 1\n \n # For each length from 2 to n\n for _ in range(1, n):\n # Initialize a new list to store the number of sequences for the current length\n new_dp = [0] * (m + 1)\n # For each possible last element\n for j in range(1, m + 1):\n # Add the number of sequences ending at numbers that are at most j // 2\n for k in range(1, j // 2 + 1):\n new_dp[j] += dp[k]\n dp = new_dp\n\n # The total number of sequences is the sum of sequences ending at each number\n return sum(dp)", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n \"\"\"\n This function calculates the total number of sequences of length n, \n such that each element is a positive integer and is greater than or \n equal to twice the previous element but less than or equal to m.\n\n Args:\n m (int): The upper limit of the sequence elements.\n n (int): The length of the sequence.\n\n Returns:\n int: The total number of possible sequences.\n \"\"\"\n\n # Initialize a 2D array dp where dp[i][j] will store the number of sequences of length i ending with j.\n dp = [[0]*(m+1) for _ in range(n+1)]\n\n # For a sequence of length 1, all elements from 1 to m are possible.\n for j in range(1, m+1):\n dp[1][j] = 1\n\n # Calculate the number of sequences of length 2 to n.\n for i in range(2, n+1):\n for j in range(1, m+1):\n # For each element j, we can start a new sequence or extend the previous sequence if the previous element is at most j//2.\n for k in range(1, j//2+1):\n dp[i][j] += dp[i-1][k]\n\n # The total number of sequences of length n is the sum of sequences ending with each possible element.\n total_sequences = sum(dp[n][j] for j in range(1, m+1))\n\n return total_sequences", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n \"\"\"\n This function calculates the number of possible sequences of length n, \n such that each element is a positive integer and is greater than or equal to \n twice the previous element but less than or equal to m.\n\n Args:\n m (int): The upper bound for the sequence elements.\n n (int): The length of the sequence.\n\n Returns:\n int: The total number of possible sequences.\n \"\"\"\n def count_sequences(current_value, n):\n if n == 0:\n return 1 # Base case: one way to make a sequence of length 0\n total_count = 0\n # Calculate the maximum value for the next element\n for next_value in range(current_value * 2, m + 1):\n total_count += count_sequences(next_value, n - 1)\n return total_count\n\n total_count = 0\n # Try all possible values for the first element in the sequence\n for first_value in range(1, m + 1):\n total_count += count_sequences(first_value, n - 1)\n return total_count", "matching_cluster_idx": 5}]}, "Mbpp/240": {"dps": 54.75609756097561, "dps_norm": 70.55555555555556, "pass@1": 65.0, "profiled": [{"solution": "def replace_list(list1, list2):\n \"\"\"\n Replaces the last element of the first list with the elements of the second list.\n\n Args:\n list1 (list): The list from which the last element will be removed and replaced.\n list2 (list): The list of elements that will replace the last element of list1.\n\n Returns:\n list: The modified list with the last element removed and replaced by list2 elements.\n \"\"\"\n # Remove the last element of the first list\n new_list = list1[:-1]\n # Extend the list with elements of the second list\n new_list.extend(list2)\n return new_list", "matching_cluster_idx": 6}, {"solution": "def replace_list(list1, list2):\n \"\"\"\n This function replaces the last element of the first list with the elements of the second list.\n\n Args:\n list1 (list): The original list.\n list2 (list): The list with elements to replace the last element of the first list.\n\n Returns:\n list: A new list with the last element of list1 replaced by list2 elements.\n \"\"\"\n if not list1:\n return list2\n if not list2:\n return list1[:-1]\n return list1[:-1] + list2", "matching_cluster_idx": 5}, {"solution": "def replace_list(original_list, replacement_list):\n \"\"\"\n Replaces the last element of the original list with elements from the replacement list.\n\n Args:\n original_list (list): The original list to modify.\n replacement_list (list): The list of elements to append.\n\n Returns:\n list: The modified original list.\n \"\"\"\n if len(original_list) == 0:\n return replacement_list\n else:\n return original_list[:-1] + replacement_list", "matching_cluster_idx": 5}, {"solution": "def replace_list(list1, list2):\n \"\"\"\n Replaces the last element of the first list with the elements of the second list.\n\n Args:\n list1 (list): The list from which the last element will be removed.\n list2 (list): The list whose elements will replace the last element of list1.\n\n Returns:\n list: A new list where the last element of list1 is replaced with the elements of list2.\n \"\"\"\n if len(list1) == 0:\n return list2\n elif len(list2) == 0:\n return list1[:-1]\n else:\n return list1[:-1] + list2", "matching_cluster_idx": 4}, {"solution": "def replace_list(list1, list2):\n \"\"\"\n Replaces the last element of the first list with the elements of the second list.\n\n Args:\n list1 (list): The list in which the last element will be replaced.\n list2 (list): The list with which the last element of list1 will be replaced.\n\n Returns:\n list: A new list with the last element of list1 replaced by list2.\n\n Example:\n >>> replace_list([1, 3, 5, 7, 9, 10], [2, 4, 6, 8])\n [1, 3, 5, 7, 9, 2, 4, 6, 8]\n \"\"\"\n # Use list slicing to create a new list that includes all elements except the last one from list1\n new_list = list1[:-1]\n # Extend the new list with the elements of list2\n new_list.extend(list2)\n # Return the resulting list\n return new_list", "matching_cluster_idx": 6}, {"solution": "def replace_list(list1, list2):\n \"\"\"\n Replaces the last element of the first list with the elements of the second list.\n \n Args:\n list1 (list): The list from which the last element is to be replaced.\n list2 (list): The list with elements that replace the last element of list1.\n \n Returns:\n list: A new list where the last element of list1 is replaced by all elements of list2.\n \"\"\"\n # Check if the first list is empty\n if not list1:\n return list2\n \n # Replace the last element of list1 with the elements of list2\n # Here we create a new list to avoid modifying the original list1\n new_list = list1[:-1] # Keep all elements except the last one from list1\n new_list.extend(list2) # Append all elements from list2 to the new list\n \n return new_list", "matching_cluster_idx": 6}, {"solution": "def replace_list(list1, list2):\n \"\"\"\n Replaces the last element of the first list with the elements of the second list.\n\n Args:\n list1 (list): The original list.\n list2 (list): The list to replace the last element of list1 with.\n\n Returns:\n list: The modified list1 with the last element replaced by elements of list2.\n \"\"\"\n # If list1 has at least one element, remove the last element and extend it with list2\n if list1:\n return list1[:-1] + list2\n else:\n # If list1 is empty, return list2 as is\n return list2", "matching_cluster_idx": 5}, {"solution": "def replace_list(list1, list2):\n \"\"\"\n Replaces the last element of the first list with the elements of the second list.\n\n Args:\n list1 (list): The list in which the last element will be replaced.\n list2 (list): The list whose elements will replace the last element in the first list.\n\n Returns:\n list: A new list with the elements of list2 replacing the last element of list1.\n \"\"\"\n return list1[:-1] + list2", "matching_cluster_idx": 5}, {"solution": "def replace_list(list1, list2):\n \"\"\"\n This function takes in two lists and replaces the last element of the first list with the elements of the second list.\n\n Args:\n list1 (list): The original list.\n list2 (list): The list with which to replace the last element of the first list.\n\n Returns:\n list: A new list with the last element replaced.\n \"\"\"\n # Create a copy of the original list to avoid modifying the original list\n result_list = list1[:]\n \n # Check if the list is not empty\n if result_list:\n # Replace the last element of the first list with the elements of the second list\n result_list[-1:] = list2\n else:\n # If the list is empty, just return the second list\n result_list = list2\n\n return result_list", "matching_cluster_idx": 6}, {"solution": "def replace_list(list1, list2):\n \"\"\"\n This function takes two lists and replaces the last element of the first list with the elements of the second list.\n\n Args:\n list1 (list): The list from which the last element will be replaced.\n list2 (list): The list whose elements will replace the last element of list1.\n\n Returns:\n list: The modified list.\n \"\"\"\n # Check if list1 has at least one element\n if len(list1) > 0:\n # Remove the last element from list1\n list1 = list1[:-1]\n # Extend list1 with the elements of list2\n list1.extend(list2)\n return list1", "matching_cluster_idx": 6}, {"solution": "def replace_list(list1, list2):\n \"\"\"\n Replaces the last element of the first list with the elements of the second list.\n \n Args:\n list1 (list): The list to modify.\n list2 (list): The list of elements to insert.\n \n Returns:\n list: The modified list.\n \"\"\"\n if not list1:\n raise IndexError(\"Cannot replace element in empty list\")\n \n # Create a copy of the first list, excluding the last element\n new_list = list1[:-1]\n \n # Extend the new list with the elements of the second list\n new_list.extend(list2)\n \n return new_list", "matching_cluster_idx": 6}, {"solution": "def replace_list(list1, list2):\n \"\"\"\n Replaces the last element of the first list with the elements of the second list.\n\n Args:\n list1 (list): The list whose last element will be replaced.\n list2 (list): The list whose elements will replace the last element of list1.\n\n Returns:\n list: A new list with the last element of list1 replaced by list2.\n \"\"\"\n if not list1:\n raise ValueError(\"list1 cannot be empty\")\n\n return list1[:-1] + list2", "matching_cluster_idx": 5}, {"solution": "def replace_list(list1, list2):\n \"\"\"\n Replaces the last element of the first list with the elements of the second list.\n\n Args:\n list1 (list): The list in which the last element will be replaced.\n list2 (list): The list whose elements will replace the last element of list1.\n\n Returns:\n list: A new list where the last element of list1 is replaced with the elements of list2.\n \"\"\"\n return list1[:-1] + list2", "matching_cluster_idx": 5}, {"solution": "def replace_list(list1, list2):\n \"\"\"\n Replaces the last element of the first list with the elements of the second list.\n\n Args:\n list1 (list): The first list.\n list2 (list): The second list.\n\n Returns:\n list: The modified list.\n \"\"\"\n # Check if list1 is not empty\n if list1:\n # Replace the last element of list1 with elements of list2\n return list1[:-1] + list2\n else:\n # If list1 is empty, return the elements of list2\n return list2", "matching_cluster_idx": 5}, {"solution": "def replace_list(list1, list2):\n \"\"\"\n Replaces the last element of the first list with the elements of the second list.\n\n Args:\n list1 (list): The list whose last element will be replaced.\n list2 (list): The list that will replace the last element of the first list.\n\n Returns:\n list: The resulting list after replacement.\n \"\"\"\n # Check if list1 has at least one element\n if len(list1) == 0:\n return list2\n # Replace the last element of list1 with list2\n else:\n return list1[:-1] + list2", "matching_cluster_idx": 5}, {"solution": "def replace_list(list1, list2):\n \"\"\"\n This function replaces the last element of the first list with the elements of the second list.\n\n Args:\n list1 (list): The list in which the last element will be replaced.\n list2 (list): The list whose elements will replace the last element of the first list.\n\n Returns:\n list: A new list that results from replacing the last element of list1 with elements of list2.\n \"\"\"\n # Check if both inputs are lists\n if not isinstance(list1, list) or not isinstance(list2, list):\n raise TypeError(\"Both inputs must be lists\")\n\n # Create a copy of the first list to avoid modifying the original list\n result_list = list1.copy()\n\n # If the first list is not empty, remove its last element\n if result_list:\n result_list.pop()\n\n # Extend the modified list with elements of the second list\n result_list.extend(list2)\n\n return result_list", "matching_cluster_idx": 6}, {"solution": "def replace_list(list1, list2):\n \"\"\"\n This function replaces the last element of the first list with the elements of the second list.\n\n Args:\n list1 (list): The original list to be modified.\n list2 (list): The list to replace the last element of list1.\n\n Returns:\n list: A new list with the last element of list1 replaced by list2.\n \"\"\"\n if len(list1) == 0:\n return list2\n else:\n return list1[:-1] + list2", "matching_cluster_idx": 5}, {"solution": "def replace_list(main_list, replacement_list):\n \"\"\"\n Replaces the last element of the main list with the elements of the replacement list.\n\n Args:\n main_list (list): The original list from which the last element will be replaced.\n replacement_list (list): The list of elements to be inserted in place of the last element of the main list.\n\n Returns:\n list: The modified main list with its last element replaced by the elements of the replacement list.\n \"\"\"\n # Make a copy of the main list to avoid modifying it in-place\n modified_list = main_list.copy()\n \n # Replace the last element of the main list with the elements of the replacement list\n modified_list = modified_list[:-1] + replacement_list\n \n return modified_list", "matching_cluster_idx": 4}, {"solution": "def replace_list(original_list, replacement_list):\n \"\"\"\n Replaces the last element of the original list with the elements of the replacement list.\n\n Args:\n original_list (list): The list from which the last element will be removed.\n replacement_list (list): The list whose elements will replace the last element of the original list.\n\n Returns:\n list: A new list where the last element of the original list is replaced with the elements of the replacement list.\n \"\"\"\n # Create a copy of the original list to avoid modifying it in place\n new_list = original_list.copy()\n\n # Remove the last element from the new list\n new_list.pop()\n\n # Extend the new list with the elements of the replacement list\n new_list.extend(replacement_list)\n\n return new_list", "matching_cluster_idx": 6}, {"solution": "def replace_list(list1, list2):\n \"\"\"\n This function replaces the last element of the first list with the elements of the second list.\n\n Args:\n list1 (list): The original list where the last element needs to be replaced.\n list2 (list): The list with elements to be inserted.\n\n Returns:\n list: The modified list where the last element of the first list is replaced by the elements of the second list.\n \"\"\"\n # Make a copy of the original list to avoid modifying it directly\n modified_list = list1.copy()\n \n # Check if the first list is not empty\n if modified_list:\n # Remove the last element from the copied list\n modified_list.pop()\n \n # Extend the modified list with the elements of the second list\n modified_list.extend(list2)\n \n return modified_list", "matching_cluster_idx": 6}]}, "Mbpp/251": {"dps": 70.3448275862069, "dps_norm": 73.33333333333333, "pass@1": 96.0, "profiled": [{"solution": "def insert_element(lst, element):\n \"\"\"\n Inserts the given element before each element in the list.\n\n Args:\n lst (list): The input list.\n element: The element to be inserted.\n\n Returns:\n list: The resulting list with the element inserted before each element.\n \"\"\"\n result = []\n for i in lst:\n result.append(element)\n result.append(i)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(input_list, element):\n \"\"\"\n Inserts the given element before each element in the input list and returns the resulting list.\n \n Args:\n input_list (list): The original list to modify.\n element: The element to be inserted.\n \n Returns:\n list: The modified list with the element inserted before each original element.\n \"\"\"\n result = []\n for item in input_list:\n result.extend([element, item])\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(input_list, element):\n \"\"\"\n Inserts an element before each element in the input list.\n\n Args:\n input_list (list): A list into which the element will be inserted.\n element: The element to be inserted before each item in the list.\n\n Returns:\n list: The resulting list after inserting the element before each item.\n \"\"\"\n result = []\n for item in input_list:\n result.append(element)\n result.append(item)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n \"\"\"\n Inserts the element before each element in the list.\n \n Args:\n lst (list): The input list.\n element: The element to be inserted.\n \n Returns:\n list: The resulting list with the element inserted before each element.\n \"\"\"\n # Initialize an empty list to store the result\n result = []\n \n # Iterate over each element in the input list\n for elem in lst:\n # Insert the given element before each element in the list\n result.extend([element, elem])\n \n # Return the resulting list\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n \"\"\"\n Inserts an element before each element in the list and returns the resulting list.\n \n Args:\n lst (list): The input list.\n element: The element to be inserted before each element in the list.\n \n Returns:\n list: The resulting list with the element inserted before each element.\n \"\"\"\n # Use list comprehension to flatten the list of lists into a single list\n return [item for sublist in [[element, i] for i in lst] for item in sublist]", "matching_cluster_idx": 3}, {"solution": "def insert_element(lst, element):\n \"\"\"\n Inserts an element before each element in a given list and returns the resulting list.\n \n Args:\n lst (list): The input list.\n element: The element to be inserted.\n \n Returns:\n list: The resulting list with the element inserted before each element.\n \"\"\"\n result = []\n for elem in lst:\n result.append(element)\n result.append(elem)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n \"\"\"\n Inserts an element before each element in the list and returns the resulting list.\n \n Args:\n lst (list): The input list.\n element: The element to be inserted before each element in the list.\n \n Returns:\n list: The resulting list with the element inserted before each element.\n \"\"\"\n # Use a list comprehension to create a new list with the element inserted before each element\n return [x for pair in zip([element] * len(lst), lst) for x in pair]", "matching_cluster_idx": 5}, {"solution": "def insert_element(lst, element):\n \"\"\"\n Inserts the given element before each element in the list.\n \n Args:\n lst (list): The input list.\n element: The element to be inserted.\n\n Returns:\n list: A new list with the given element inserted before each element in the original list.\n \"\"\"\n # Initialize an empty list to store the result.\n result = []\n # Iterate over each element in the input list.\n for item in lst:\n # Insert the given element into the result list.\n result.append(element)\n # Insert the current item from the input list into the result list.\n result.append(item)\n # Return the resulting list.\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(input_list, element):\n \"\"\"\n Inserts an element before each element in the list.\n\n Args:\n input_list (list): The list to insert elements into.\n element: The element to be inserted.\n\n Returns:\n list: The resulting list after insertion.\n \"\"\"\n # Initialize an empty list to store the result\n result = []\n \n # Iterate over each element in the input list\n for item in input_list:\n # Append the given element and the item from the input list to the result\n result.append(element)\n result.append(item)\n \n # Return the resulting list\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(input_list, element):\n \"\"\"\n Inserts an element before each element in the list.\n\n Args:\n input_list (list): The input list to be modified.\n element: The element to be inserted before each element in the list.\n\n Returns:\n list: The resulting list with the element inserted before each element.\n \"\"\"\n return [item for pair in zip([element] * len(input_list), input_list) for item in pair]", "matching_cluster_idx": 5}, {"solution": "def insert_element(lst, element):\n \"\"\"\n Inserts an element before each element in a given list.\n \n Args:\n lst (list): The input list.\n element: The element to be inserted.\n \n Returns:\n list: The resulting list with the element inserted before each element.\n \"\"\"\n # Use list comprehension to insert the element before each element in the list\n return [x for pair in zip([element]*len(lst), lst) for x in pair]", "matching_cluster_idx": 5}, {"solution": "def insert_element(input_list, element):\n \"\"\"\n Inserts a given element before each element in the input list.\n \n Args:\n input_list (list): The list into which the element will be inserted.\n element: The element to be inserted.\n \n Returns:\n list: The resulting list after inserting the element before each element in the input list.\n \"\"\"\n # Initialize an empty list to store the result\n result = []\n \n # Iterate over each element in the input list\n for i in input_list:\n # Insert the element before each element in the input list\n result.extend([element, i])\n \n # Return the resulting list\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n \"\"\"\n Inserts a given element before each element in the list.\n\n Args:\n lst (list): The list into which elements will be inserted.\n element: The element to be inserted.\n\n Returns:\n list: A new list with the given element inserted before each element in the original list.\n \"\"\"\n result = []\n for item in lst:\n result.append(element)\n result.append(item)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n \"\"\"\n Inserts an element before each element in the given list and returns the resulting list.\n \n Args:\n lst (list): The list into which the element will be inserted.\n element: The element to be inserted.\n \n Returns:\n list: The resulting list after insertion.\n \"\"\"\n result = []\n for elem in lst:\n result.append(element)\n result.append(elem)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n \"\"\"\n Inserts an element before each element in a given list.\n\n Args:\n lst (list): Input list.\n element: Element to be inserted.\n\n Returns:\n list: Resulting list with the element inserted before each element.\n\n Example:\n >>> insert_element(['Red', 'Green', 'Black'], 'c')\n ['c', 'Red', 'c', 'Green', 'c', 'Black']\n \"\"\"\n result = []\n for i in lst:\n result.extend([element, i])\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(input_list, element):\n \"\"\"\n Inserts the given element before each element in the input list.\n\n Args:\n input_list (list): The list in which elements will be inserted.\n element: The element to be inserted.\n\n Returns:\n list: A new list with the given element inserted before each element in the input list.\n\n \"\"\"\n return [item for pair in zip([element] * len(input_list), input_list) for item in pair]", "matching_cluster_idx": 5}, {"solution": "def insert_element(lst, element):\n \"\"\"\n Inserts an element before each element in a given list.\n\n Args:\n lst (list): The input list to be modified.\n element: The element to be inserted before each element in the list.\n\n Returns:\n list: A new list with the element inserted before each element in the input list.\n \"\"\"\n result = []\n for i in lst:\n result.append(element)\n result.append(i)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n \"\"\"\n Inserts an element before each element in the given list.\n \n Args:\n lst (list): The list to insert the element into.\n element: The element to be inserted.\n \n Returns:\n list: The resulting list with the element inserted before each element.\n \"\"\"\n # Initialize an empty list to store the result\n result = []\n \n # Iterate over each element in the input list\n for elem in lst:\n # Append the given element to the result list\n result.append(element)\n # Append the current element from the input list to the result list\n result.append(elem)\n \n # Return the resulting list\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n \"\"\"\n Inserts the given element before each element in the list.\n \n Args:\n lst (list): The original list.\n element: The element to be inserted.\n \n Returns:\n list: The resulting list after insertion.\n \"\"\"\n return [item for pair in zip([element] * len(lst), lst) for item in pair]", "matching_cluster_idx": 5}, {"solution": "def insert_element(lst, element):\n \"\"\"\n Inserts a given element before each element in a list.\n\n Args:\n lst (list): The original list.\n element: The element to be inserted before each element in the list.\n\n Returns:\n list: A new list with the given element inserted before each element.\n \"\"\"\n result = []\n for elem in lst:\n result.extend([element, elem])\n return result", "matching_cluster_idx": 6}]}, "Mbpp/256": {"dps": 74.8972602739726, "dps_norm": 69.70588235294117, "pass@1": 75.0, "profiled": [{"solution": "def count_Primes_nums(n: int) -> int:\n \"\"\"\n This function takes in a non-negative number and returns the number of prime numbers less than the given non-negative number.\n\n Args:\n n (int): A non-negative integer.\n\n Returns:\n int: The number of prime numbers less than n.\n\n Raises:\n TypeError: If input is not an integer or is negative.\n \"\"\"\n if not isinstance(n, int) or n < 0:\n raise TypeError(\"Input must be a non-negative integer.\")\n\n def is_prime(num: int) -> bool:\n \"\"\"\n Helper function to check if a number is prime.\n\n Args:\n num (int): The number to check.\n\n Returns:\n bool: True if the number is prime, False otherwise.\n \"\"\"\n if num < 2:\n return False\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n return False\n return True\n\n # Count the number of prime numbers less than n\n count = 0\n for i in range(2, n):\n if is_prime(i):\n count += 1\n return count", "matching_cluster_idx": 8}, {"solution": "def count_Primes_nums(n: int) -> int:\n \"\"\"\n This function counts the number of prime numbers less than a given non-negative number.\n \n Args:\n n (int): A non-negative integer.\n \n Returns:\n int: The number of prime numbers less than n.\n \"\"\"\n\n def is_prime(num: int) -> bool:\n \"\"\"\n Helper function to check if a number is prime.\n \n Args:\n num (int): A non-negative integer.\n \n Returns:\n bool: True if the number is prime, False otherwise.\n \"\"\"\n if num < 2:\n return False\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n return False\n return True\n\n # Handle edge cases\n if n < 2:\n return 0\n \n count = 0\n # Count prime numbers from 2 to n-1\n for i in range(2, n):\n if is_prime(i):\n count += 1\n \n return count", "matching_cluster_idx": 8}, {"solution": "def count_Primes_nums(n):\n \"\"\"\n Returns the count of prime numbers less than the given non-negative number.\n\n Args:\n n (int): A non-negative integer.\n\n Returns:\n int: Count of prime numbers less than n.\n \"\"\"\n if n < 2: # edge case: 0 and 1 are not prime numbers\n return 0\n \n # Create a boolean array, prime, of size n+1\n prime = [True] * (n + 1)\n prime[0] = prime[1] = False\n\n # Iterate over the array starting from 2\n p = 2\n while p * p <= n:\n # If prime[p] is not changed, then it is a prime\n if prime[p] is True:\n # Update all multiples of p\n for i in range(p * p, n + 1, p):\n prime[i] = False\n p += 1\n \n # Count all prime numbers\n count = 0\n for p in range(2, n):\n if prime[p]:\n count += 1\n\n return count", "matching_cluster_idx": 13}, {"solution": "def count_Primes_nums(n: int) -> int:\n \"\"\"\n This function takes a non-negative number and returns the number of prime numbers less than the given number.\n\n Args:\n n (int): A non-negative number.\n\n Returns:\n int: The number of prime numbers less than n.\n\n Raises:\n ValueError: If the input number is negative.\n \"\"\"\n if not isinstance(n, int) or n < 0:\n raise ValueError(\"Input must be a non-negative integer\")\n\n def is_prime(num: int) -> bool:\n \"\"\"Checks if a number is prime\"\"\"\n if num < 2:\n return False\n for i in range(2, int(num ** 0.5) + 1):\n if num % i == 0:\n return False\n return True\n\n # Counting prime numbers less than n\n count = sum(1 for i in range(2, n) if is_prime(i))\n return count", "matching_cluster_idx": 8}, {"solution": "def count_Primes_nums(n):\n \"\"\"\n Returns the number of prime numbers less than the given non-negative number n.\n \n :param n: A non-negative integer.\n :return: The number of prime numbers less than n.\n \"\"\"\n # Corner case: if n is less than or equal to 2, there are no prime numbers less than n.\n if n <= 2:\n return 0\n \n # Create a boolean array, prime, of size n and initialize all entries as true.\n # A value in prime[i] will finally be false if i is Not a prime, else true.\n prime = [True] * n\n prime[0] = prime[1] = False\n \n # Iterate over the prime array and update the prime status of multiples of each prime number.\n for p in range(2, int(n ** 0.5) + 1):\n if prime[p]:\n # Update all multiples of p.\n for i in range(p * p, n, p):\n prime[i] = False\n \n # Count all prime numbers in the array.\n return sum(prime)", "matching_cluster_idx": 14}, {"solution": "def count_Primes_nums(n: int) -> int:\n \"\"\"\n Returns the count of prime numbers less than the given non-negative number.\n\n Args:\n n (int): A non-negative integer.\n\n Returns:\n int: The count of prime numbers less than the given number.\n\n Raises:\n ValueError: If the input number is negative.\n \"\"\"\n\n if n < 0:\n raise ValueError(\"Input number must be non-negative.\")\n\n if n <= 2: \n # If n is less than or equal to 2, there are no prime numbers less than n\n return 0\n\n primes = [True] * n \n primes[0] = primes[1] = False\n\n for num in range(2, int(n ** 0.5) + 1):\n if primes[num]:\n # Mark as composite all the multiples of num\n for multiple in range(num * num, n, num):\n primes[multiple] = False\n\n return sum(primes)", "matching_cluster_idx": 14}, {"solution": "def count_Primes_nums(n):\n \"\"\"\n This function takes in a non-negative number and returns the number of prime numbers less than the given non-negative number.\n \n Args:\n n (int): The given non-negative number.\n\n Returns:\n int: The number of prime numbers less than n.\n \"\"\"\n\n # Initialize count of prime numbers to 0\n count = 0\n \n # Iterate over numbers from 2 to n-1 (inclusive)\n for num in range(2, n):\n # Initialize a flag to True, assuming the number is prime\n is_prime = True\n \n # Check if the number is divisible by any number up to its square root\n for i in range(2, int(num ** 0.5) + 1):\n if num % i == 0:\n # If the number is divisible, set the flag to False and break the loop\n is_prime = False\n break\n \n # If the number is prime, increment the count\n if is_prime:\n count += 1\n \n # Return the count of prime numbers\n return count", "matching_cluster_idx": 8}, {"solution": "def count_Primes_nums(n: int) -> int:\n \"\"\"\n Counts the number of prime numbers less than the given non-negative number.\n\n Args:\n n (int): A non-negative number.\n\n Returns:\n int: The number of prime numbers less than the given number.\n\n Raises:\n ValueError: If n is a negative number.\n TypeError: If n is not an integer.\n \"\"\"\n if not isinstance(n, int):\n raise TypeError(\"Input must be an integer.\")\n if n < 0:\n raise ValueError(\"Input must be a non-negative number.\")\n\n if n <= 2:\n return 0\n \n sieve = [True] * n\n sieve[0:2] = [False, False] # 0 and 1 are not prime numbers\n for current_prime in range(2, int(n ** 0.5) + 1):\n if sieve[current_prime]:\n for multiple in range(current_prime * current_prime, n, current_prime):\n sieve[multiple] = False\n\n return sum(sieve)", "matching_cluster_idx": 14}, {"solution": "def count_Primes_nums(n: int) -> int:\n \"\"\"\n Counts the number of prime numbers less than the given non-negative number.\n\n Args:\n n (int): A non-negative integer.\n\n Returns:\n int: The number of prime numbers less than n.\n\n Raises:\n ValueError: If n is a negative integer.\n\n \"\"\"\n if n < 0:\n raise ValueError(\"Input must be a non-negative integer.\")\n\n def is_prime(num: int) -> bool:\n \"\"\"\n Checks if a number is prime.\n\n Args:\n num (int): The number to be checked.\n\n Returns:\n bool: True if the number is prime, False otherwise.\n\n \"\"\"\n if num < 2:\n return False\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n return False\n return True\n\n count = 0\n for i in range(2, n):\n if is_prime(i):\n count += 1\n return count", "matching_cluster_idx": 8}, {"solution": "def count_Primes_nums(n: int) -> int:\n \"\"\"\n This function takes a non-negative number n and returns the number of prime numbers less than n.\n\n Args:\n n (int): A non-negative integer.\n\n Returns:\n int: The number of prime numbers less than n.\n \"\"\"\n if n < 2:\n return 0\n\n def is_prime(num: int) -> bool:\n \"\"\"Check if a number is prime.\"\"\"\n if num < 2:\n return False\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n return False\n return True\n\n count = 0\n for i in range(2, n):\n if is_prime(i):\n count += 1\n return count", "matching_cluster_idx": 8}, {"solution": "def count_Primes_nums(n: int) -> int:\n \"\"\"\n This function takes in a non-negative number and returns the number of prime numbers less than the given non-negative number.\n\n Args:\n n (int): A non-negative integer.\n\n Returns:\n int: The number of prime numbers less than n.\n \"\"\"\n def is_prime(num: int) -> bool:\n \"\"\"\n Helper function to check if a number is prime.\n\n Args:\n num (int): A number to check for primality.\n\n Returns:\n bool: True if the number is prime, False otherwise.\n \"\"\"\n if num < 2:\n return False\n for i in range(2, int(num ** 0.5) + 1):\n if num % i == 0:\n return False\n return True\n\n count = 0\n for i in range(2, n):\n if is_prime(i):\n count += 1\n return count", "matching_cluster_idx": 8}, {"solution": "def count_Primes_nums(n):\n \"\"\"\n This function takes in a non-negative number and returns the number of prime numbers less than the given non-negative number.\n\n Args:\n n (int): A non-negative integer.\n\n Returns:\n int: The number of prime numbers less than n.\n\n Raises:\n ValueError: If n is less than 0.\n \"\"\"\n if n < 0:\n raise ValueError(\"n must be a non-negative integer.\")\n\n # Handle edge case where n is less than 2 (no primes less than 2)\n if n < 2:\n return 0\n\n # Initialize a boolean array, prime, of size n\n prime = [True] * n\n prime[0] = prime[1] = False\n\n # Use the Sieve of Eratosthenes algorithm to find primes\n p = 2\n while p * p < n:\n # If p is a prime, mark its multiples as not prime\n if prime[p]:\n for i in range(p * p, n, p):\n prime[i] = False\n p += 1\n\n # Count the number of primes\n count = sum(prime)\n return count", "matching_cluster_idx": 14}, {"solution": "def count_Primes_nums(n):\n \"\"\"\n Returns the number of prime numbers less than the given non-negative number.\n\n Args:\n n (int): A non-negative integer.\n\n Returns:\n int: The number of prime numbers less than n.\n\n Raises:\n TypeError: If n is not a non-negative integer.\n\n Example:\n >>> count_Primes_nums(5)\n 2\n \"\"\"\n\n # Check if n is a non-negative integer.\n if not isinstance(n, int) or n < 0:\n raise TypeError(\"Input must be a non-negative integer.\")\n\n # Handle edge cases where n is less than 2.\n if n < 2:\n return 0\n\n # Initialize a boolean array, prime, of size n.\n prime = [True] * n\n prime[0] = prime[1] = False\n\n # Iterate from 2 to sqrt(n) to mark non-prime numbers.\n for i in range(2, int(n ** 0.5) + 1):\n if prime[i]:\n for j in range(i * i, n, i):\n prime[j] = False\n\n # Return the count of prime numbers in the array.\n return sum(prime)", "matching_cluster_idx": 14}, {"solution": "def count_Primes_nums(n):\n \"\"\"\n Returns the number of prime numbers less than the given non-negative number.\n\n Args:\n n (int): A non-negative integer.\n\n Returns:\n int: The number of prime numbers less than n.\n\n Raises:\n TypeError: If input n is not an integer.\n ValueError: If input n is a negative integer.\n \"\"\"\n if not isinstance(n, int):\n raise TypeError(\"Input n must be an integer.\")\n if n < 0:\n raise ValueError(\"Input n must be a non-negative integer.\")\n\n if n <= 2: # There are no prime numbers less than 2\n return 0\n\n sieve = [True] * n # Initially assume all numbers are prime\n sieve[0:2] = [False, False] # 0 and 1 are not prime\n\n # Iterate over all numbers up to the square root of n\n for current_prime in range(2, int(n ** 0.5) + 1):\n if sieve[current_prime]:\n # Mark as composite all the multiples of the current prime\n for multiple in range(current_prime * current_prime, n, current_prime):\n sieve[multiple] = False\n\n # Count all prime numbers in the sieve\n count = sum(sieve)\n return count", "matching_cluster_idx": 14}, {"solution": "def count_Primes_nums(n):\n \"\"\"\n Returns the number of prime numbers less than the given non-negative number n.\n \n Args:\n n (int): A non-negative integer.\n \n Returns:\n int: The count of prime numbers less than n.\n \"\"\"\n def is_prime(num):\n \"\"\"Checks if a number is prime.\"\"\"\n if num < 2:\n return False\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n return False\n return True\n\n count = 0\n for i in range(2, n):\n if is_prime(i):\n count += 1\n return count", "matching_cluster_idx": 8}, {"solution": "def count_Primes_nums(n: int) -> int:\n \"\"\"\n This function calculates the number of prime numbers less than the given non-negative number.\n \n Parameters:\n n (int): A non-negative integer.\n \n Returns:\n int: The number of prime numbers less than the given non-negative number.\n \"\"\"\n \n # Corner cases: Numbers less than 2 are not prime numbers.\n if n < 2:\n return 0\n \n # Initialize a boolean array, prime, of size n and set all entries true.\n # A value in prime[i] will finally be false if i is Not a prime, else true.\n prime = [True for _ in range(n)]\n prime[0] = prime[1] = False\n \n # p is the smallest prime number\n p = 2\n while p * p < n:\n # If prime[p] is not changed, then it is a prime\n if prime[p] is True:\n # Update all multiples of p\n for i in range(p * p, n, p):\n prime[i] = False\n p += 1\n \n # Count all prime numbers\n count = 0\n for i in range(2, n):\n if prime[i]:\n count += 1\n \n return count", "matching_cluster_idx": 12}, {"solution": "def count_Primes_nums(n: int) -> int:\n \"\"\"\n Returns the number of prime numbers less than the given non-negative number.\n\n Args:\n n (int): A non-negative number.\n\n Returns:\n int: The number of prime numbers less than n.\n\n Raises:\n ValueError: If n is a negative number.\n \"\"\"\n\n if not isinstance(n, int) or n < 0:\n raise ValueError(\"Input must be a non-negative integer.\")\n\n # Initialize a counter for prime numbers\n count = 0\n\n # Iterate through all numbers from 2 to n-1\n for num in range(2, n):\n # Assume the number is prime\n is_prime = True\n \n # Check for factors from 2 to the square root of the number\n for factor in range(2, int(num ** 0.5) + 1):\n if num % factor == 0:\n # If a factor is found, the number is not prime\n is_prime = False\n break\n \n # If the number is prime, increment the counter\n if is_prime:\n count += 1\n \n return count", "matching_cluster_idx": 8}, {"solution": "def count_Primes_nums(n):\n \"\"\"\n This function calculates the number of prime numbers less than the given non-negative number.\n\n Args:\n n (int): A non-negative integer.\n\n Returns:\n int: The number of prime numbers less than the given number.\n\n Raises:\n TypeError: If input is not an integer.\n ValueError: If input is less than 0.\n \"\"\"\n \n # Input validation\n if not isinstance(n, int):\n raise TypeError(\"Input must be an integer.\")\n if n < 0:\n raise ValueError(\"Input must be a non-negative integer.\")\n \n # Edge cases\n if n <= 2:\n return 0\n \n # Sieve of Eratosthenes algorithm\n sieve = [True] * n\n sieve[0] = sieve[1] = False\n \n # Iterate from 2 to the square root of n\n for current_prime in range(2, int(n ** 0.5) + 1):\n if sieve[current_prime]:\n # Mark multiples of current_prime as not prime\n for multiple in range(current_prime * current_prime, n, current_prime):\n sieve[multiple] = False\n \n # Count the number of prime numbers in the sieve\n count = sum(sieve)\n \n return count", "matching_cluster_idx": 14}, {"solution": "def count_Primes_nums(n):\n \"\"\"\n Returns the number of prime numbers less than the given non-negative number.\n\n Args:\n n (int): A non-negative integer.\n\n Returns:\n int: The number of prime numbers less than n.\n \"\"\"\n\n # Handle edge case when n is less than 2\n if n < 2:\n return 0\n\n # Initialize a boolean array, prime, of size n\n prime = [True] * n\n\n # 0 and 1 are not prime numbers\n prime[0] = prime[1] = False\n\n # Iterate over the array starting from 2\n for p in range(2, int(n ** 0.5) + 1):\n # If p is a prime number, mark its multiples as non-prime\n if prime[p]:\n for i in range(p * p, n, p):\n prime[i] = False\n\n # Return the count of prime numbers\n return sum(prime)", "matching_cluster_idx": 14}, {"solution": "def count_Primes_nums(n: int) -> int:\n \"\"\"\n This function takes in a non-negative number and returns the number of prime numbers less than the given non-negative number.\n \n Args:\n n (int): A non-negative integer.\n \n Returns:\n int: The number of prime numbers less than n.\n \"\"\"\n\n def is_prime(num: int) -> bool:\n \"\"\"Helper function to check if a number is prime.\"\"\"\n if num < 2:\n return False\n for i in range(2, int(num ** 0.5) + 1):\n if num % i == 0:\n return False\n return True\n\n count = 0\n for i in range(2, n):\n if is_prime(i):\n count += 1\n return count", "matching_cluster_idx": 8}]}, "Mbpp/265": {"dps": 39.24418604651163, "dps_norm": 65.0, "pass@1": 86.0, "profiled": [{"solution": "def list_split(input_list, n):\n \"\"\"\n This function splits a list for every nth element.\n\n Args:\n input_list (list): The input list to be split.\n n (int): The interval at which the list should be split.\n\n Returns:\n list: A list of lists, each containing elements at the corresponding index interval.\n \"\"\"\n return [[input_list[i] for i in range(x, len(input_list), n)] for x in range(n)]", "matching_cluster_idx": 2}, {"solution": "def list_split(input_list, n):\n \"\"\"\n Splits a list for every nth element, returning a list of the resulting lists.\n\n :param input_list: The list to be split.\n :param n: The interval at which to split the list.\n :return: A list of lists, where each sublist contains elements from the original list, \n starting at the corresponding index and stepping by n.\n \"\"\"\n return [input_list[i::n] for i in range(n)]", "matching_cluster_idx": 4}, {"solution": "def list_split(input_list, n):\n \"\"\"\n This function splits the input list for every nth element.\n\n Args:\n input_list (list): The input list to be split.\n n (int): The interval for splitting the list.\n\n Returns:\n list: A list of the resulting lists.\n\n Example:\n >>> list_split(['a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j', 'k', 'l', 'm', 'n'], 3)\n [['a', 'd', 'g', 'j', 'm'], ['b', 'e', 'h', 'k', 'n'], ['c', 'f', 'i', 'l']]\n \"\"\"\n\n # Calculate the number of sublists needed\n num_sublists = n\n \n # Initialize the result with empty sublists\n result = [[] for _ in range(num_sublists)]\n \n # Iterate over the input list with index and value\n for i, value in enumerate(input_list):\n # Use the index modulo the number of sublists to decide which sublist to append to\n result[i % num_sublists].append(value)\n \n return result", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n \"\"\"\n Splits a list into sublists of elements at the same position in each chunk of size n.\n\n Args:\n lst (list): The list to be split.\n n (int): The size of each chunk.\n\n Returns:\n list: A list of lists, each containing elements at the same position in each chunk of size n.\n \"\"\"\n return [lst[i::n] for i in range(n)]", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n \"\"\"\n Splits a list into multiple lists, where each list contains elements at a distance of n from the original list.\n\n Args:\n lst (list): The input list to be split.\n n (int): The interval at which the list is split.\n\n Returns:\n list: A list of lists where each sublist contains elements at a distance of n from the original list.\n \"\"\"\n return [lst[i::n] for i in range(n)]", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n \"\"\"\n Splits a list for every nth element and returns a list of the resulting lists.\n \n Args:\n lst (list): Input list\n n (int): Interval at which to split the list\n \n Returns:\n list: A list of lists, where each inner list contains elements from the input list at indices i, i+n, i+2n, ...\n \"\"\"\n result = [[] for _ in range(n)]\n for i, element in enumerate(lst):\n result[i % n].append(element)\n return result", "matching_cluster_idx": 4}, {"solution": "def list_split(input_list, n):\n \"\"\"\n This function takes a list and an integer n, and splits the list into sublists\n for every nth element.\n\n Args:\n input_list (list): The list to be split.\n n (int): The interval at which the list is split.\n\n Returns:\n list: A list of lists where each sublist contains every nth element from the input list.\n \"\"\"\n return [[input_list[j] for j in range(i, len(input_list), n)] for i in range(n)]", "matching_cluster_idx": 2}, {"solution": "def list_split(input_list, n):\n \"\"\"\n Splits a list into sublists where the ith sublist contains every nth element from the original list,\n starting from the ith element.\n\n Args:\n input_list (list): The list to be split.\n n (int): The interval at which the list should be split.\n\n Returns:\n list: A list of the resulting sublists.\n \"\"\"\n return [[input_list[j] for j in range(i, len(input_list), n)] for i in range(n)]", "matching_cluster_idx": 2}, {"solution": "def list_split(input_list, n):\n \"\"\"\n This function splits a list into a list of sublists. \n Each sublist contains every nth element from the input list.\n\n Args:\n input_list (list): The list to be split.\n n (int): The interval of elements to be included in each sublist.\n\n Returns:\n list: A list of sublists, each containing every nth element from the input list.\n \"\"\"\n # Initialize an empty list to store the result\n result = [[] for _ in range(n)]\n\n # Iterate over the input list with enumerate to get both index and value\n for i, value in enumerate(input_list):\n # Calculate the index of the sublist where the current element should be added\n result_index = i % n\n # Add the current element to the corresponding sublist\n result[result_index].append(value)\n\n return result", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n \"\"\"\n Splits a list into sub-lists, where each sub-list contains every nth element from the original list.\n\n Args:\n lst (list): The list to be split.\n n (int): The interval at which to split the list.\n\n Returns:\n list: A list of sub-lists, each containing every nth element from the original list.\n\n Example:\n >>> list_split(['a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j', 'k', 'l', 'm', 'n'], 3)\n [['a', 'd', 'g', 'j', 'm'], ['b', 'e', 'h', 'k', 'n'], ['c', 'f', 'i', 'l']]\n \"\"\"\n return [[lst[j] for j in range(i, len(lst), n)] for i in range(n)]", "matching_cluster_idx": 2}, {"solution": "def list_split(lst, n):\n \"\"\"\n This function splits a list for every nth element, returning a list of the resulting lists.\n \n The function uses list comprehension to create sublists by iterating over the input list in steps of n.\n \n Args:\n lst (list): The input list to be split.\n n (int): The interval at which the list should be split.\n \n Returns:\n list: A list of sublists, each containing every nth element from the input list.\n \"\"\"\n return [[lst[i] for i in range(j, len(lst), n)] for j in range(n)]", "matching_cluster_idx": 2}, {"solution": "def list_split(lst, n):\n \"\"\"\n This function splits a list into sublists based on every nth element.\n\n Args:\n lst (list): The input list to be split.\n n (int): The interval at which the list is split.\n\n Returns:\n list: A list of the resulting lists.\n \"\"\"\n # Initialize an empty list to store the resulting sublists.\n result = [[] for _ in range(n)]\n\n # Iterate over the input list and its indices.\n for i, element in enumerate(lst):\n # Calculate the index of the sublist where the element should be inserted.\n # The index is determined by the remainder of i divided by n.\n result[i % n].append(element)\n\n return result", "matching_cluster_idx": 4}, {"solution": "def list_split(input_list, n):\n \"\"\"\n This function splits a list for every nth element, returning a list of the resulting lists.\n\n Args:\n input_list (list): The input list to be split.\n n (int): The interval at which the list is split.\n\n Returns:\n list: A list of lists, each containing elements from the input list at intervals of n.\n \"\"\"\n\n # Initialize an empty list to store the resulting lists\n result = [[] for _ in range(n)]\n\n # Iterate over the input list with enumerate to get both index and value\n for i, value in enumerate(input_list):\n # Append each value to the corresponding list in the result based on its index\n result[i % n].append(value)\n\n return result", "matching_cluster_idx": 4}, {"solution": "def list_split(input_list, n):\n \"\"\"\n This function takes in a list and an integer n, then splits the list into sublists.\n The sublists are filled with every nth element from the original list.\n\n Args:\n input_list (list): The list to be split.\n n (int): The interval at which elements are selected for each sublist.\n\n Returns:\n list: A list of sublists.\n \"\"\"\n return [[input_list[j] for j in range(i, len(input_list), n)] for i in range(n)]", "matching_cluster_idx": 2}, {"solution": "def list_split(input_list, n):\n \"\"\"\n Split a list into sublists for every nth element.\n\n Args:\n input_list (list): The list to be split.\n n (int): The interval at which to split the list.\n\n Returns:\n list: A list of sublists, each containing elements from the original list at the specified interval.\n\n Example:\n >>> list_split(['a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j', 'k', 'l', 'm', 'n'], 3)\n [['a', 'd', 'g', 'j', 'm'], ['b', 'e', 'h', 'k', 'n'], ['c', 'f', 'i', 'l']]\n \"\"\"\n return [[input_list[j] for j in range(i, len(input_list), n)] for i in range(n)]", "matching_cluster_idx": 2}, {"solution": "def list_split(input_list, n):\n \"\"\"\n Splits a list into sublists, where each sublist contains every nth element.\n\n Args:\n input_list (list): The input list to split.\n n (int): The interval at which to split the list.\n\n Returns:\n list: A list of sublists, where each sublist contains every nth element.\n \"\"\"\n result = [[] for _ in range(n)]\n for i, element in enumerate(input_list):\n result[i % n].append(element)\n return result", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n \"\"\"\n This function splits a list into sublists for every nth element.\n \n Parameters:\n lst (list): The list to be split.\n n (int): The interval at which to split the list.\n \n Returns:\n list: A list of sublists.\n \"\"\"\n return [[lst[j] for j in range(i, len(lst), n)] for i in range(n)]", "matching_cluster_idx": 2}, {"solution": "def list_split(input_list, n):\n \"\"\"\n This function takes in a list and an integer n, \n then splits the list into sublists by every nth element.\n\n Args:\n input_list (list): The list to be split.\n n (int): The interval to split the list.\n\n Returns:\n list: A list of the resulting sublists.\n \"\"\"\n # Calculate the number of columns required\n num_cols = (len(input_list) + n - 1) // n\n # Use list comprehension to rearrange the list into columns\n return [[input_list[i + j * n] for j in range(num_cols) if i + j * n < len(input_list)] for i in range(n)]", "matching_cluster_idx": 1}, {"solution": "def list_split(input_list, n):\n \"\"\"\n Splits a list for every nth element, returning a list of the resulting lists.\n \n Args:\n input_list (list): The input list to be split.\n n (int): The interval at which to split the list.\n \n Returns:\n list: A list of the resulting lists.\n \"\"\"\n result = [[] for _ in range(n)]\n for i, item in enumerate(input_list):\n result[i % n].append(item)\n return result", "matching_cluster_idx": 3}, {"solution": "def list_split(input_list, n):\n \"\"\"\n Splits a list for every nth element, returning a list of the resulting lists.\n\n Args:\n input_list (list): The list to be split.\n n (int): The interval at which the list is split.\n\n Returns:\n list: A list of lists, where each sublist contains every nth element from the input list.\n \"\"\"\n # Use list comprehension and slicing to split the list\n return [[input_list[i] for i in range(j, len(input_list), n)] for j in range(n)]", "matching_cluster_idx": 2}]}, "Mbpp/281": {"dps": 94.0, "dps_norm": 81.81818181818181, "pass@1": 100.0, "profiled": [{"solution": "def all_unique(lst):\n \"\"\"\n Checks if all elements in a list are unique.\n\n Args:\n lst (list): Input list to check for uniqueness.\n\n Returns:\n bool: True if all elements are unique, False otherwise.\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n Checks if all elements in the list are unique.\n \n Args:\n lst (list): The input list to check.\n \n Returns:\n bool: True if all elements are unique, False otherwise.\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n Check if all elements in a list are unique.\n\n Args:\n lst (list): The list to check for unique elements.\n\n Returns:\n bool: True if all elements in the list are unique, False otherwise.\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n Checks if all elements in a list are unique.\n\n Args:\n lst (list): The list to check.\n\n Returns:\n bool: True if all elements in the list are unique, False otherwise.\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n Checks if all elements in a given list are unique.\n\n Args:\n lst (list): The input list to check.\n\n Returns:\n bool: True if all elements in the list are unique, False otherwise.\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n This function checks if all elements in a given list are unique.\n\n Args:\n lst (list): A list of elements to check.\n\n Returns:\n bool: True if all elements are unique, False otherwise.\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n Check if the elements of a given list are unique or not.\n\n Args:\n lst (list): The list to check.\n\n Returns:\n bool: True if all elements are unique, False otherwise.\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n Checks if all elements of a given list are unique.\n \n Args:\n lst (list): The input list to check for uniqueness.\n \n Returns:\n bool: True if all elements in the list are unique, False otherwise.\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n Returns True if all elements in a list are unique, False otherwise.\n\n :param lst: Input list to be checked\n :return: Boolean indicating whether all elements are unique\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n Checks if the elements of a given list are unique.\n \n Args:\n lst (list): The list to check.\n \n Returns:\n bool: True if all elements are unique, False otherwise.\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n Check if all elements in the given list are unique.\n\n Args:\n lst (list): List of elements to check.\n\n Returns:\n bool: True if all elements are unique, False otherwise.\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n Checks if all elements in a list are unique.\n\n Args:\n lst (list): The input list to check.\n\n Returns:\n bool: True if all elements are unique, False otherwise.\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n Checks if all elements in a list are unique.\n\n Args:\n lst (list): The list to check.\n\n Returns:\n bool: True if all elements in the list are unique, False otherwise.\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n Checks if all elements of a given list are unique.\n \n Args:\n lst (list): Input list.\n \n Returns:\n bool: True if all elements are unique, False otherwise.\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(input_list):\n \"\"\"\n Checks if all elements in the given list are unique.\n\n Args:\n input_list (list): A list of elements.\n\n Returns:\n bool: True if all elements are unique, False otherwise.\n \"\"\"\n return len(input_list) == len(set(input_list))", "matching_cluster_idx": 8}, {"solution": "def all_unique(input_list):\n \"\"\"\n Checks if all elements in a list are unique.\n \n Args:\n input_list (list): The list to be checked for unique elements.\n\n Returns:\n bool: True if all elements are unique, False otherwise.\n \"\"\"\n return len(input_list) == len(set(input_list))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n Checks if all elements in a list are unique.\n\n Args:\n lst (list): The list to be checked.\n\n Returns:\n bool: True if all elements are unique, False otherwise.\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n This function checks if the elements of a given list are unique or not.\n \n Parameters:\n lst (list): A list of elements\n \n Returns:\n bool: True if all elements are unique, False otherwise\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n Check if all elements in the given list are unique.\n\n Args:\n lst (list): The input list to be checked.\n\n Returns:\n bool: True if all elements are unique, False otherwise.\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n Checks if all elements in the given list are unique.\n\n Args:\n lst (list): The input list.\n\n Returns:\n bool: True if all elements are unique, False otherwise.\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}]}, "Mbpp/296": {"dps": 73.33333333333333, "dps_norm": 86.66666666666667, "pass@1": 46.0, "profiled": [{"solution": "def get_Inv_Count(arr):\n \"\"\"\n Counts the number of inversions in the given array.\n \n Args:\n arr (list): The input list of integers.\n \n Returns:\n int: The number of inversions in the array.\n \"\"\"\n def merge_and_count(arr, left, mid, right):\n # Initialize left and right subarrays\n left_arr = arr[left:mid + 1]\n right_arr = arr[mid + 1:right + 1]\n\n # Initialize variables\n i = j = inv_count = 0\n k = left\n\n # Merge the subarrays while counting inversions\n while i < len(left_arr) and j < len(right_arr):\n if left_arr[i] <= right_arr[j]:\n arr[k] = left_arr[i]\n i += 1\n else:\n arr[k] = right_arr[j]\n inv_count += len(left_arr) - i\n j += 1\n k += 1\n\n # Copy the remaining elements of the left subarray, if any\n while i < len(left_arr):\n arr[k] = left_arr[i]\n i += 1\n k += 1\n\n # Copy the remaining elements of the right subarray, if any\n while j < len(right_arr):\n arr[k] = right_arr[j]\n j += 1\n k += 1\n\n return inv_count\n\n def merge_sort_and_count(arr, left, right):\n inv_count = 0\n if left < right:\n mid = (left + right) // 2\n inv_count += merge_sort_and_count(arr, left, mid)\n inv_count += merge_sort_and_count(arr, mid + 1, right)\n inv_count += merge_and_count(arr, left, mid, right)\n return inv_count\n\n return merge_sort_and_count(arr, 0, len(arr) - 1)", "matching_cluster_idx": 5}, {"solution": "def get_Inv_Count(arr):\n \"\"\"\n Counts the number of inversions in a given array.\n \n An inversion is a pair of elements in the array that are out of order.\n \n Args:\n arr (list): Input array to count inversions for.\n \n Returns:\n int: Total number of inversions in the array.\n \"\"\"\n count = 0\n \n for i in range(len(arr)):\n # Iterate over the rest of the array for each element\n for j in range(i + 1, len(arr)):\n # If an element is found that's smaller than the current one, \n # it means an inversion has been found, so increment the count\n if arr[i] > arr[j]:\n count += 1\n \n return count", "matching_cluster_idx": 2}, {"solution": "def get_Inv_Count(arr):\n \"\"\"\n This function counts the inversions in an array.\n \n An inversion is a pair of two elements that are out of their natural order.\n For example, for the array [1,20,6,4,5], inversions are (20,6), (20,4), (20,5), (6,4), (6,5).\n \n :param arr: A list of integers\n :return: The number of inversions in the input array\n \"\"\"\n count = 0\n \n # iterate over the array\n for i in range(len(arr)):\n # for each element, iterate over the rest of the array\n for j in range(i+1, len(arr)):\n # if the current element is greater than the compared element, it's an inversion\n if arr[i] > arr[j]:\n count += 1\n \n return count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n \"\"\"\n Returns the number of inversions in the given array.\n\n An inversion is a pair of elements in the array where the first element is greater than the second element.\n\n :param arr: List of integers.\n :return: Number of inversions.\n \"\"\"\n\n def merge_and_count(left, right):\n \"\"\"\n Merges two sorted lists and counts inversions.\n\n :param left: Left list.\n :param right: Right list.\n :return: Merged list, inversion count.\n \"\"\"\n result = []\n inv_count = 0\n i = j = 0\n\n while i < len(left) and j < len(right):\n if left[i] <= right[j]:\n result.append(left[i])\n i += 1\n else:\n result.append(right[j])\n inv_count += len(left) - i # Count inversions\n j += 1\n\n result.extend(left[i:])\n result.extend(right[j:])\n\n return result, inv_count\n\n def merge_sort_and_count(arr):\n \"\"\"\n Recursively divides the array into two halves, sorts and counts inversions.\n\n :param arr: List of integers.\n :return: Sorted array, inversion count.\n \"\"\"\n if len(arr) <= 1:\n return arr, 0\n\n mid = len(arr) // 2\n left, left_inv = merge_sort_and_count(arr[:mid])\n right, right_inv = merge_sort_and_count(arr[mid:])\n\n merged, merged_inv = merge_and_count(left, right)\n return merged, left_inv + right_inv + merged_inv\n\n _, inversions = merge_sort_and_count(arr)\n return inversions", "matching_cluster_idx": 5}, {"solution": "def get_Inv_Count(arr):\n \"\"\"\n Counts the number of inversions in the given array.\n\n Inversion: A pair of elements in the array such that a[i] > a[j] and i < j.\n\n :param arr: Input array.\n :return: The number of inversions in the array.\n\n Time Complexity: O(n log n)\n Space Complexity: O(n)\n \"\"\"\n\n def merge_and_count(left, right):\n merged = []\n inv_count = 0\n left_index = right_index = 0\n\n while left_index < len(left) and right_index < len(right):\n if left[left_index] <= right[right_index]:\n merged.append(left[left_index])\n left_index += 1\n else:\n merged.append(right[right_index])\n inv_count += len(left) - left_index\n right_index += 1\n\n merged += left[left_index:]\n merged += right[right_index:]\n\n return merged, inv_count\n\n def merge_sort(arr):\n if len(arr) <= 1:\n return arr, 0\n\n mid = len(arr) // 2\n left_half = merge_sort(arr[:mid])\n right_half = merge_sort(arr[mid:])\n\n merged = merge_and_count(left_half[0], right_half[0])\n return merged[0], left_half[1] + right_half[1] + merged[1]\n\n _, inversions = merge_sort(arr)\n return inversions", "matching_cluster_idx": 5}, {"solution": "def get_Inv_Count(arr):\n \"\"\"\n This function calculates the number of inversions in an array.\n \n Args:\n arr (list): A list of integers.\n \n Returns:\n int: The total number of inversions in the array.\n \"\"\"\n \n def merge_sort(arr):\n # Base case: If the array has one or zero elements, it is already sorted.\n if len(arr) <= 1:\n return arr, 0\n \n mid = len(arr) // 2\n left, a = merge_sort(arr[:mid])\n right, b = merge_sort(arr[mid:])\n \n # Merge the two halves and count inversions.\n result, c = merge(left, right)\n \n return result, (a + b + c)\n \n def merge(left, right):\n result = []\n i = j = inv_count = 0\n \n while i < len(left) and j < len(right):\n if left[i] <= right[j]:\n result.append(left[i])\n i += 1\n else:\n result.append(right[j])\n inv_count += len(left) - i\n j += 1\n \n result.extend(left[i:])\n result.extend(right[j:])\n \n return result, inv_count\n \n _, inversions = merge_sort(arr)\n return inversions", "matching_cluster_idx": 5}, {"solution": "def get_Inv_Count(arr):\n \"\"\"\n This function counts the number of inversions in a given array.\n An inversion is a pair of elements in the array such that the first element is greater than the second.\n\n Args:\n arr (list): The input array\n\n Returns:\n int: The number of inversions in the array\n \"\"\"\n count = 0\n for i in range(len(arr)):\n for j in range(i + 1, len(arr)):\n if arr[i] > arr[j]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def get_Inv_Count(arr):\n \"\"\"\n This function counts inversions in an array.\n\n An inversion is a pair of elements in the array such that the smaller element appears after the larger element.\n\n Args:\n arr (list): A list of integers.\n\n Returns:\n int: The number of inversions in the array.\n\n Example:\n >>> get_Inv_Count([1, 20, 6, 4, 5])\n 5\n \"\"\"\n def merge_sort(arr):\n if len(arr) <= 1:\n return arr, 0\n\n mid = len(arr) // 2\n left, inv_left = merge_sort(arr[:mid])\n right, inv_right = merge_sort(arr[mid:])\n\n merged, inv_merge = merge(left, right)\n\n return merged, inv_left + inv_right + inv_merge\n\n def merge(left, right):\n merged = []\n inv_count = 0\n i = j = 0\n\n while i < len(left) and j < len(right):\n if left[i] <= right[j]:\n merged.append(left[i])\n i += 1\n else:\n merged.append(right[j])\n inv_count += len(left) - i\n j += 1\n\n merged.extend(left[i:])\n merged.extend(right[j:])\n\n return merged, inv_count\n\n _, inversions = merge_sort(arr)\n return inversions", "matching_cluster_idx": 5}, {"solution": "def get_Inv_Count(arr):\n \"\"\"\n Function to count inversions in an array.\n \n An inversion is a pair of elements in the array that are out of order, i.e., \n a larger element appears before a smaller element.\n\n :param arr: A list of integers\n :return: The number of inversions in the array\n \"\"\"\n count = 0\n \n # Create a copy of the input array\n arr_copy = arr.copy()\n \n # Call the recursive merge sort function\n count = mergeSort(arr_copy, count)\n \n return count\ndef mergeSort(arr, count):\n \"\"\"\n Recursive merge sort function that counts inversions\n \n :param arr: A list of integers\n :param count: The current inversion count\n :return: The inversion count after sorting the array\n \"\"\"\n \n # Base case\n if len(arr) <= 1:\n return count\n \n # Find the middle point and divide the array into two halves\n mid = len(arr) // 2\n left = arr[:mid]\n right = arr[mid:]\n \n # Recursively sort the halves and count inversions\n count = mergeSort(left, count)\n count = mergeSort(right, count)\n \n # Merge the sorted halves and count inversions\n count = merge(left, right, arr, count)\n \n return count\ndef merge(left, right, arr, count):\n \"\"\"\n Merge two sorted lists and count inversions\n \n :param left: The first sorted list\n :param right: The second sorted list\n :param arr: The original array\n :param count: The current inversion count\n :return: The inversion count after merging the lists\n \"\"\"\n \n i = j = k = 0\n \n # Merge smaller elements first\n while i < len(left) and j < len(right):\n if left[i] <= right[j]:\n arr[k] = left[i]\n i += 1\n else:\n arr[k] = right[j]\n count += len(left) - i # Increment inversion count\n j += 1\n k += 1\n \n # Copy remaining elements of left, if any\n while i < len(left):\n arr[k] = left[i]\n i += 1\n k += 1\n \n # Copy remaining elements of right, if any\n while j < len(right):\n arr[k] = right[j]\n j += 1\n k += 1\n \n return count", "matching_cluster_idx": 5}, {"solution": "def get_Inv_Count(arr):\n \"\"\"\n Counts the number of inversions in an array.\n \n Args:\n arr: A list of integers.\n \n Returns:\n An integer representing the number of inversions in the array.\n \"\"\"\n def mergeSort(arr):\n # If array has only one or zero elements, no inversions are possible\n if len(arr) <= 1:\n return arr, 0\n \n # Find the middle point and divide it\n middle = len(arr) // 2\n left = arr[:middle]\n right = arr[middle:]\n \n # Recursively count inversions and merge\n left, left_inversions = mergeSort(left)\n right, right_inversions = mergeSort(right)\n \n # Merge the sorted arrays and count inversions\n merged, merged_inversions = merge(left, right)\n \n # Return the merged array and total inversions\n return merged, left_inversions + right_inversions + merged_inversions\n \n def merge(left, right):\n merged = []\n i, j, inversions = 0, 0, 0\n \n # Merge smaller elements first and count inversions\n while i < len(left) and j < len(right):\n if left[i] <= right[j]:\n merged.append(left[i])\n i += 1\n else:\n merged.append(right[j])\n inversions += len(left) - i\n j += 1\n \n # Append the remaining elements\n merged.extend(left[i:])\n merged.extend(right[j:])\n \n return merged, inversions\n \n _, inversions = mergeSort(arr)\n return inversions", "matching_cluster_idx": 5}, {"solution": "def get_Inv_Count(arr):\n \"\"\"\n Counts inversions in an array.\n\n Args:\n arr (list): The input array.\n\n Returns:\n int: The number of inversions in the array.\n \"\"\"\n inv_count = 0\n\n def merge_and_count(arr):\n nonlocal inv_count\n if len(arr) <= 1:\n return arr\n mid = len(arr) // 2\n left = merge_and_count(arr[:mid])\n right = merge_and_count(arr[mid:])\n return merge(left, right)\n\n def merge(left, right):\n nonlocal inv_count\n result = []\n while left and right:\n if left[0] <= right[0]:\n result.append(left.pop(0))\n else:\n result.append(right.pop(0))\n inv_count += len(left)\n result.extend(left if left else right)\n return result\n\n merge_and_count(arr)\n return inv_count", "matching_cluster_idx": 5}, {"solution": "def get_Inv_Count(arr):\n \"\"\"\n Count inversions in a given array.\n\n Args:\n arr (list): List of integers.\n\n Returns:\n int: The number of inversions in the array.\n\n \"\"\"\n count = 0\n\n def merge_and_count(left, right):\n nonlocal count\n result = []\n i = j = 0\n\n while i < len(left) and j < len(right):\n if left[i] <= right[j]:\n result.append(left[i])\n i += 1\n else:\n result.append(right[j])\n count += len(left) - i # count inversions\n j += 1\n\n result.extend(left[i:])\n result.extend(right[j:])\n\n return result\n\n def merge_sort(arr):\n if len(arr) <= 1:\n return arr\n\n mid = len(arr) // 2\n left = merge_sort(arr[:mid])\n right = merge_sort(arr[mid:])\n\n return merge_and_count(left, right)\n\n merge_sort(arr)\n return count", "matching_cluster_idx": 5}, {"solution": "def get_Inv_Count(arr):\n \"\"\"\n Count the number of inversions in the given array.\n\n An inversion is a pair of elements in the array that are in the wrong order,\n i.e., a larger element appears before a smaller one.\n\n Args:\n arr (list): The input array.\n\n Returns:\n int: The number of inversions in the array.\n \"\"\"\n def merge_and_count(left, right):\n # Initialize variables to store the merged array and inversion count\n merged = []\n inv_count = 0\n\n # Initialize indices for the left and right arrays\n left_index = right_index = 0\n\n # Merge the left and right arrays and count inversions\n while left_index < len(left) and right_index < len(right):\n if left[left_index] <= right[right_index]:\n merged.append(left[left_index])\n left_index += 1\n else:\n merged.append(right[right_index])\n inv_count += len(left) - left_index\n right_index += 1\n\n # Append any remaining elements from the left and right arrays\n merged.extend(left[left_index:])\n merged.extend(right[right_index:])\n\n return merged, inv_count\n\n def merge_sort_and_count(arr):\n # Base case: if the array has one or zero elements, it's already sorted\n if len(arr) <= 1:\n return arr, 0\n\n # Split the array into two halves\n mid = len(arr) // 2\n left, left_inv_count = merge_sort_and_count(arr[:mid])\n right, right_inv_count = merge_sort_and_count(arr[mid:])\n\n # Merge the two halves and count inversions\n merged, merged_inv_count = merge_and_count(left, right)\n\n return merged, left_inv_count + right_inv_count + merged_inv_count\n\n # Call the recursive merge sort function and return the inversion count\n _, inv_count = merge_sort_and_count(arr)\n return inv_count", "matching_cluster_idx": 5}, {"solution": "def get_Inv_Count(arr):\n \"\"\"\n Counts the number of inversions in a given array.\n \n Args:\n arr (list): A list of integers.\n \n Returns:\n int: The number of inversions in the given array.\n \"\"\"\n inv_count = 0\n \n def merge_and_count(arr, left, mid, right):\n nonlocal inv_count\n \n left_len = mid - left + 1\n right_len = right - mid\n \n left_arr = arr[left:mid+1].copy()\n right_arr = arr[mid+1:right+1].copy()\n \n i = j = 0\n k = left\n \n while i < left_len and j < right_len:\n if left_arr[i] <= right_arr[j]:\n arr[k] = left_arr[i]\n i += 1\n else:\n arr[k] = right_arr[j]\n j += 1\n inv_count += left_len - i\n k += 1\n \n while i < left_len:\n arr[k] = left_arr[i]\n i += 1\n k += 1\n \n while j < right_len:\n arr[k] = right_arr[j]\n j += 1\n k += 1\n \n def merge_sort_and_count(arr, left, right):\n if left < right:\n mid = (left + right) // 2\n \n merge_sort_and_count(arr, left, mid)\n merge_sort_and_count(arr, mid+1, right)\n \n merge_and_count(arr, left, mid, right)\n \n merge_sort_and_count(arr, 0, len(arr)-1)\n return inv_count", "matching_cluster_idx": 5}, {"solution": "def get_Inv_Count(arr):\n \"\"\"\n Counts the number of inversions in the input array.\n\n Args:\n arr (list): Input list of integers.\n\n Returns:\n int: Number of inversions in the input array.\n\n \"\"\"\n def merge_and_count(arr, left, mid, right):\n \"\"\"\n Recursively merge and count inversions.\n \"\"\"\n # create temporary arrays\n left_arr = arr[left:mid+1]\n right_arr = arr[mid+1:right+1]\n\n inv_count = 0\n i = j = 0\n k = left\n\n while i < len(left_arr) and j < len(right_arr):\n if left_arr[i] <= right_arr[j]:\n arr[k] = left_arr[i]\n i += 1\n else:\n arr[k] = right_arr[j]\n j += 1\n inv_count += len(left_arr) - i\n k += 1\n\n # Copy remaining elements if any\n while i < len(left_arr):\n arr[k] = left_arr[i]\n i += 1\n k += 1\n\n while j < len(right_arr):\n arr[k] = right_arr[j]\n j += 1\n k += 1\n\n return inv_count\n\n def count_inversion(arr, left, right):\n \"\"\"\n Recursively count inversions.\n \"\"\"\n inv_count = 0\n if left < right:\n mid = (left + right) // 2\n inv_count += count_inversion(arr, left, mid)\n inv_count += count_inversion(arr, mid+1, right)\n inv_count += merge_and_count(arr, left, mid, right)\n return inv_count\n\n return count_inversion(arr, 0, len(arr) - 1)", "matching_cluster_idx": 5}, {"solution": "def get_Inv_Count(arr):\n \"\"\"\n Counts the number of inversions in an array.\n \n An inversion is a pair of elements in the array that are in the wrong order, \n i.e., a larger element appears before a smaller element.\n \n Parameters:\n arr (list): The input array.\n \n Returns:\n int: The number of inversions in the array.\n \"\"\"\n count = 0\n for i in range(len(arr)):\n for j in range(i+1, len(arr)):\n if arr[i] > arr[j]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def get_Inv_Count(arr):\n \"\"\"\n Count inversions in an array.\n\n Inversions are pairs of elements in the array that are out of order, i.e.\n arr[i] > arr[j] where i < j.\n\n Args:\n arr (list): Input array.\n\n Returns:\n int: Number of inversions in the array.\n \"\"\"\n def merge_and_count(arr, start, mid, end):\n left = arr[start:mid+1]\n right = arr[mid+1:end+1]\n left_index = 0\n right_index = 0\n inversion_count = 0\n merged_index = start\n\n while left_index < len(left) and right_index < len(right):\n if left[left_index] <= right[right_index]:\n arr[merged_index] = left[left_index]\n left_index += 1\n else:\n arr[merged_index] = right[right_index]\n inversion_count += len(left) - left_index\n right_index += 1\n merged_index += 1\n\n while left_index < len(left):\n arr[merged_index] = left[left_index]\n left_index += 1\n merged_index += 1\n\n while right_index < len(right):\n arr[merged_index] = right[right_index]\n right_index += 1\n merged_index += 1\n\n return inversion_count\n\n def merge_sort_and_count(arr, start, end):\n inversion_count = 0\n if start < end:\n mid = (start + end) // 2\n inversion_count += merge_sort_and_count(arr, start, mid)\n inversion_count += merge_sort_and_count(arr, mid+1, end)\n inversion_count += merge_and_count(arr, start, mid, end)\n return inversion_count\n\n return merge_sort_and_count(arr, 0, len(arr)-1)", "matching_cluster_idx": 5}, {"solution": "def get_Inv_Count(arr):\n \"\"\"\n Count the number of inversions in a given array.\n\n Inversion: A pair of elements in the wrong order, i.e., a larger element appears before a smaller one.\n\n Args:\n arr (list): Input array of integers.\n\n Returns:\n int: Number of inversions in the array.\n \"\"\"\n def merge_sort(arr):\n # Base case: If the array has one or zero elements, it is already sorted and has zero inversions.\n if len(arr) <= 1:\n return arr, 0\n\n # Divide the array into two halves.\n mid = len(arr) // 2\n left_half = arr[:mid]\n right_half = arr[mid:]\n\n # Recursively sort and count inversions in both halves.\n left_sorted, left_inv = merge_sort(left_half)\n right_sorted, right_inv = merge_sort(right_half)\n\n # Merge the sorted halves and count inversions that occur during the merge.\n merged, merge_inv = merge(left_sorted, right_sorted)\n\n return merged, left_inv + right_inv + merge_inv\n\n def merge(left, right):\n merged = []\n inv = 0\n\n # Merge two sorted arrays and count inversions.\n left_index = 0\n right_index = 0\n while left_index < len(left) and right_index < len(right):\n if left[left_index] <= right[right_index]:\n merged.append(left[left_index])\n left_index += 1\n else:\n merged.append(right[right_index])\n inv += len(left) - left_index # Count inversions\n right_index += 1\n\n # Append the remaining elements from either array, if any.\n merged += left[left_index:]\n merged += right[right_index:]\n\n return merged, inv\n\n # Call the merge_sort function and return the inversion count.\n _, inv_count = merge_sort(arr)\n return inv_count", "matching_cluster_idx": 5}, {"solution": "def get_Inv_Count(arr):\n \"\"\"\n Counts inversions in a given array.\n\n An inversion is a pair of elements in the wrong order, i.e., \n a larger element appears before a smaller element.\n\n :param arr: Input array\n :return: Number of inversions in the array\n \"\"\"\n count = 0\n for i in range(len(arr)):\n for j in range(i+1, len(arr)):\n if arr[i] > arr[j]:\n count += 1\n return count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n \"\"\"\n This function counts the inversions in an array.\n An inversion is a pair of elements in the array that are out of their natural order, \n i.e., a larger element appears before a smaller one.\n \n Args:\n arr (list): A list of integers.\n \n Returns:\n int: The number of inversions in the array.\n \"\"\"\n # Initialize inversion count to zero\n inv_count = 0\n \n # Iterate over the array\n for i in range(len(arr)):\n # Compare each element with the elements on its right\n for j in range(i+1, len(arr)):\n # If a larger element appears before a smaller one, increment the inversion count\n if arr[i] > arr[j]:\n inv_count += 1\n \n # Return the total inversion count\n return inv_count", "matching_cluster_idx": 2}]}, "Mbpp/308": {"dps": 91.17241379310346, "dps_norm": 66.66666666666667, "pass@1": 86.0, "profiled": [{"solution": "import heapq\nimport itertools\ndef large_product(list1, list2, n):\n \"\"\"\n Find the specified number of largest products from two given lists, \n selecting one factor from each list.\n\n Args:\n list1 (list): The first list of numbers.\n list2 (list): The second list of numbers.\n n (int): The number of largest products to find.\n\n Returns:\n list: A list of the n largest products.\n \"\"\"\n # Generate all possible products\n products = [x * y for x, y in itertools.product(list1, list2)]\n \n # Use a heap to find the n largest products\n largest_products = heapq.nlargest(n, products)\n \n return largest_products", "matching_cluster_idx": 3}, {"solution": "import itertools\nimport heapq\ndef large_product(list1, list2, n):\n \"\"\"\n Find the specified number of largest products from two given lists, selecting one factor from each list.\n\n Args:\n list1 (list): The first list of factors.\n list2 (list): The second list of factors.\n n (int): The number of largest products to find.\n\n Returns:\n list: A list of the n largest products.\n \"\"\"\n\n # Generate all possible products of one factor from each list\n products = [a * b for a, b in itertools.product(list1, list2)]\n\n # Use a heap to find the n largest products\n return heapq.nlargest(n, products)", "matching_cluster_idx": 3}, {"solution": "import heapq\nfrom typing import List\ndef large_product(list1: List[int], list2: List[int], n: int) -> List[int]:\n \"\"\"\n Find the specified number of largest products from two given lists, \n selecting one factor from each list.\n\n Args:\n list1 (List[int]): The first list of numbers.\n list2 (List[int]): The second list of numbers.\n n (int): The number of largest products to find.\n\n Returns:\n List[int]: A list of the n largest products.\n \"\"\"\n # Use a min heap to keep track of the largest products\n min_heap = []\n \n # Iterate over each pair of numbers from the two lists\n for num1 in list1:\n for num2 in list2:\n # Calculate the product\n product = num1 * num2\n \n # Push the product onto the heap\n # If the heap has more than n elements, the smallest product will be discarded\n if len(min_heap) < n:\n heapq.heappush(min_heap, product)\n else:\n heapq.heappushpop(min_heap, product)\n \n # The heap now contains the n largest products, but they are in ascending order\n # So we need to pop them off the heap and reverse the list to get the largest products first\n return sorted(min_heap, reverse=True)", "matching_cluster_idx": 3}, {"solution": "import itertools\nimport heapq\ndef large_product(list1, list2, n):\n \"\"\"\n Return the n largest products from two given lists, selecting one factor from each list.\n\n Args:\n list1 (list): The first list of numbers.\n list2 (list): The second list of numbers.\n n (int): The number of largest products to find.\n\n Returns:\n list: A list of the n largest products.\n\n Raises:\n ValueError: If n is larger than the number of possible products.\n \"\"\"\n\n # Check if n is not larger than the number of possible products\n if n > len(list1) * len(list2):\n raise ValueError(\"n is larger than the number of possible products\")\n\n # Use itertools.product to get all possible pairs of numbers from the two lists\n pairs = itertools.product(list1, list2)\n\n # Use a generator expression to calculate the product of each pair\n products = (a * b for a, b in pairs)\n\n # Use heapq.nlargest to find the n largest products\n largest_products = heapq.nlargest(n, products)\n\n return largest_products", "matching_cluster_idx": 4}, {"solution": "import heapq\nimport itertools\ndef large_product(list1, list2, n):\n \"\"\"\n Find the specified number of largest products from two given lists,\n selecting one factor from each list.\n\n Args:\n list1 (list): The first list of factors.\n list2 (list): The second list of factors.\n n (int): The number of largest products to return.\n\n Returns:\n list: A list of the n largest products.\n \"\"\"\n # Generate all possible pairs of factors\n pairs = itertools.product(list1, list2)\n \n # Calculate the product of each pair and store as a tuple (product, factor1, factor2)\n products = [(factor1 * factor2, factor1, factor2) for factor1, factor2 in pairs]\n \n # Use a heap to efficiently get the n largest products\n largest_products = heapq.nlargest(n, products)\n \n # Return only the products (not the factors)\n return [product[0] for product in largest_products]", "matching_cluster_idx": 2}, {"solution": "def large_product(list1, list2, n):\n \"\"\"\n Returns the n largest products from two lists, selecting one factor from each list.\n\n Args:\n list1 (list): The first list of numbers.\n list2 (list): The second list of numbers.\n n (int): The number of largest products to return.\n\n Returns:\n list: The n largest products in descending order.\n \"\"\"\n\n # Generate all possible products\n products = [x * y for x in list1 for y in list2]\n\n # Sort products in descending order\n sorted_products = sorted(products, reverse=True)\n\n # Return the n largest products\n return sorted_products[:n]", "matching_cluster_idx": 3}, {"solution": "import heapq\nfrom typing import List\ndef large_product(list1: List[int], list2: List[int], n: int) -> List[int]:\n \"\"\"\n This function finds the specified number of largest products from two given lists, \n selecting one factor from each list.\n\n Args:\n list1 (List[int]): The first list of factors.\n list2 (List[int]): The second list of factors.\n n (int): The number of largest products to find.\n\n Returns:\n List[int]: A list of the n largest products.\n \"\"\"\n \n # Initialize an empty list to store the products\n products = []\n \n # Calculate the products of all possible pairs of factors and store them in a list\n for num1 in list1:\n for num2 in list2:\n products.append(num1 * num2)\n \n # Use a heap to find the n largest products\n return heapq.nlargest(n, products)", "matching_cluster_idx": 3}, {"solution": "import heapq\ndef large_product(list1, list2, n):\n \"\"\"\n This function finds the specified number of largest products from two given lists, \n selecting one factor from each list.\n\n Parameters:\n list1 (list): The first list of numbers.\n list2 (list): The second list of numbers.\n n (int): The number of largest products to return.\n\n Returns:\n list: A list of the n largest products.\n \"\"\"\n \n # Multiply corresponding elements from both lists and store them in a list along with their indices\n products = [(a * b, i, j) for i, a in enumerate(list1) for j, b in enumerate(list2)]\n \n # Use a heap to find the n largest products. The heap will store the n largest products seen so far.\n largest = heapq.nlargest(n, products)\n \n # Return the products\n return [product[0] for product in largest]", "matching_cluster_idx": 2}, {"solution": "import heapq\nimport itertools\ndef large_product(list1, list2, n):\n \"\"\"\n Returns the n largest products from two lists, selecting one factor from each list.\n\n Args:\n list1 (list): The first list of numbers.\n list2 (list): The second list of numbers.\n n (int): The number of largest products to return.\n\n Returns:\n list: A list of the n largest products in descending order.\n \"\"\"\n # Generate all possible products from the two lists\n products = (a * b for a, b in itertools.product(list1, list2))\n \n # Use a heap to find the n largest products efficiently\n return heapq.nlargest(n, products)", "matching_cluster_idx": 4}, {"solution": "import heapq\nfrom itertools import product\ndef large_product(list1, list2, n):\n \"\"\"\n Returns the specified number of largest products from two given lists, \n selecting one factor from each list.\n\n Args:\n list1 (list): The first list of numbers.\n list2 (list): The second list of numbers.\n n (int): The number of largest products to return.\n\n Returns:\n list: A list of the n largest products, in descending order.\n \"\"\"\n # Generate all possible products\n all_products = [x*y for x, y in product(list1, list2)]\n \n # Use a heap to find the n largest products efficiently\n return heapq.nlargest(n, all_products)", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n \"\"\"\n This function returns the specified number of largest products from two given lists, \n selecting one factor from each list.\n\n Args:\n list1 (list): The first list of numbers.\n list2 (list): The second list of numbers.\n n (int): The number of largest products to return.\n\n Returns:\n list: A list of the n largest products.\n \"\"\"\n # Create a list of all possible products\n products = [x * y for x in list1 for y in list2]\n\n # Sort the products in descending order and select the n largest ones\n largest_products = sorted(products, reverse=True)[:n]\n\n return largest_products", "matching_cluster_idx": 3}, {"solution": "import heapq\nfrom typing import List\ndef large_product(list1: List[int], list2: List[int], n: int) -> List[int]:\n \"\"\"\n Returns the specified number of largest products from two given lists, \n selecting one factor from each list.\n\n Args:\n list1 (List[int]): The first list of factors.\n list2 (List[int]): The second list of factors.\n n (int): The number of largest products to return.\n\n Returns:\n List[int]: A list of the n largest products.\n \"\"\"\n # Generate all possible products\n products = [x * y for x in list1 for y in list2]\n\n # Use a heap to find the n largest products\n return heapq.nlargest(n, products)", "matching_cluster_idx": 3}, {"solution": "import heapq\nimport itertools\ndef large_product(list1, list2, n):\n \"\"\"\n This function finds the specified number of largest products from two given lists,\n selecting one factor from each list.\n\n Args:\n list1 (list): The first list of numbers.\n list2 (list): The second list of numbers.\n n (int): The number of largest products to find.\n\n Returns:\n list: A list of the n largest products.\n \"\"\"\n\n # Use itertools.product to get the Cartesian product of the two lists\n products = [a * b for a, b in itertools.product(list1, list2)]\n\n # Use heapq.nlargest to find the n largest products\n return heapq.nlargest(n, products)", "matching_cluster_idx": 3}, {"solution": "import itertools\nimport heapq\ndef large_product(list1, list2, n):\n \"\"\"\n This function finds the specified number of largest products from two given lists,\n selecting one factor from each list.\n\n Args:\n list1 (list): The first list of numbers.\n list2 (list): The second list of numbers.\n n (int): The number of largest products to find.\n\n Returns:\n list: A list of the n largest products.\n \"\"\"\n\n # Generate all possible pairs of numbers from the two lists\n pairs = list(itertools.product(list1, list2))\n\n # Calculate the product of each pair\n products = [pair[0] * pair[1] for pair in pairs]\n\n # Use a heap to efficiently find the n largest products\n return heapq.nlargest(n, products)", "matching_cluster_idx": 3}, {"solution": "import heapq\nimport itertools\ndef large_product(list1, list2, n):\n \"\"\"\n Find the n largest products from two given lists by selecting one factor from each list.\n\n Args:\n list1 (list): The first list of numbers.\n list2 (list): The second list of numbers.\n n (int): The number of largest products to find.\n\n Returns:\n list: A list of the n largest products.\n \"\"\"\n # Calculate all possible products\n products = [x*y for x, y in itertools.product(list1, list2)]\n \n # Use heapq.nlargest to find the n largest products\n largest_n = heapq.nlargest(n, products)\n \n return largest_n", "matching_cluster_idx": 3}, {"solution": "import heapq\nfrom typing import List\ndef large_product(list1: List[int], list2: List[int], n: int) -> List[int]:\n \"\"\"\n Returns the specified number of largest products from two given lists, \n selecting one factor from each list.\n\n Args:\n list1 (List[int]): The first list of numbers.\n list2 (List[int]): The second list of numbers.\n n (int): The number of largest products to return.\n\n Returns:\n List[int]: A list of the n largest products.\n \"\"\"\n \n # Create a list to store the products\n products = []\n \n # Calculate all possible products and store them in a list\n for num1 in list1:\n for num2 in list2:\n products.append(num1 * num2)\n \n # Use a heap to find the n largest products\n return heapq.nlargest(n, products)", "matching_cluster_idx": 3}, {"solution": "import heapq\ndef large_product(list1, list2, n):\n \"\"\"\n This function finds the specified number of largest products from two given lists, \n selecting one factor from each list.\n\n Args:\n list1 (list): The first list of factors.\n list2 (list): The second list of factors.\n n (int): The number of largest products to return.\n\n Returns:\n list: A list of the n largest products.\n\n Raises:\n ValueError: If n is greater than the number of possible combinations.\n \"\"\"\n\n # Check if n is greater than the number of possible combinations\n if n > len(list1) * len(list2):\n raise ValueError(\"n cannot be greater than the number of possible combinations\")\n\n # Generate all possible products\n products = [x * y for x in list1 for y in list2]\n\n # Use a heap to find the n largest products\n return heapq.nlargest(n, products)", "matching_cluster_idx": 3}, {"solution": "import heapq\nimport itertools\ndef large_product(list1, list2, n):\n \"\"\"\n Find the specified number of largest products from two given lists, \n selecting one factor from each list.\n\n Args:\n list1 (list): The first list of numbers.\n list2 (list): The second list of numbers.\n n (int): The number of largest products to find.\n\n Returns:\n list: A list of the n largest products.\n \"\"\"\n # Use itertools.product to get all possible pairs of numbers from both lists\n products = [x * y for x, y in itertools.product(list1, list2)]\n \n # Use heapq.nlargest to find the n largest products\n largest_products = heapq.nlargest(n, products)\n \n return largest_products", "matching_cluster_idx": 3}, {"solution": "import heapq\ndef large_product(list1, list2, num_largest):\n \"\"\"\n Find the specified number of largest products from two given lists, \n selecting one factor from each list.\n\n Args:\n list1 (list): The first list of numbers.\n list2 (list): The second list of numbers.\n num_largest (int): The number of largest products to find.\n\n Returns:\n list: A list of the num_largest largest products in descending order.\n\n Raises:\n ValueError: If the product of the lengths of the two lists is less than num_largest.\n \"\"\"\n\n # Check if num_largest is valid\n if len(list1) * len(list2) < num_largest:\n raise ValueError(\"num_largest is too large\")\n\n # Use a heap to keep track of the num_largest largest products seen so far\n largest_products = []\n\n # Iterate over each element in list1\n for i in list1:\n # For each element in list1, iterate over each element in list2\n for j in list2:\n # Push the product onto the heap\n if len(largest_products) < num_largest:\n # If the heap is not full, push the product and its values\n heapq.heappush(largest_products, (i*j, i, j))\n else:\n # If the heap is full, push the product only if it's larger than the smallest in the heap\n heapq.heappushpop(largest_products, (i*j, i, j))\n\n # Return the largest products\n return sorted([x[0] for x in largest_products])[::-1]", "matching_cluster_idx": 3}, {"solution": "import itertools\nimport heapq\ndef large_product(list1, list2, n):\n \"\"\"\n This function takes two lists of numbers and returns the 'n' largest products, \n each product being the result of multiplying one number from each list.\n\n Args:\n list1 (list): First list of numbers.\n list2 (list): Second list of numbers.\n n (int): The number of largest products to return.\n\n Returns:\n list: A list of the 'n' largest products.\n\n Raises:\n ValueError: If 'n' is larger than the total number of possible products.\n \"\"\"\n # Calculate all possible products\n products = [a * b for a, b in itertools.product(list1, list2)]\n \n # Check if 'n' is larger than the total number of possible products\n if n > len(products):\n raise ValueError(\"'n' cannot be larger than the total number of possible products\")\n \n # Use a heap to find the 'n' largest products\n return heapq.nlargest(n, products)", "matching_cluster_idx": 3}]}, "Mbpp/392": {"dps": 98.05164319248826, "dps_norm": 99.61538461538461, "pass@1": 54.0, "profiled": [{"solution": "def get_max_sum(n, memo={}):\n \"\"\"\n This function calculates the maximum sum possible by using the given equation \n f(n) = max( (f(n/2) + f(n/3) + f(n/4) + f(n/5)), n).\n\n Args:\n n (int): The input number.\n memo (dict, optional): A dictionary for memoization. Defaults to {}.\n\n Returns:\n int: The maximum sum possible.\n \"\"\"\n # Base case: If n is 0 or less, return 0\n if n <= 0:\n return 0\n # If n is already in the memo dictionary, return its value\n if n in memo:\n return memo[n]\n # Recursive case: Calculate the maximum sum by using the equation\n max_sum = max(n, \n get_max_sum(n//2, memo) + get_max_sum(n//3, memo) + get_max_sum(n//4, memo) + get_max_sum(n//5, memo))\n # Store the maximum sum in the memo dictionary\n memo[n] = max_sum\n return max_sum", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n, memo={}):\n \"\"\"\n This function calculates the maximum sum possible by using the given equation f(n) = max( (f(n/2) + f(n/3) + f(n/4) + f(n/5)), n).\n \n Args:\n n (int): The input number.\n memo (dict): A dictionary for memoization, to store previously calculated results.\n \n Returns:\n int: The maximum sum possible.\n \"\"\"\n # Base case: If n is 0 or negative, return 0.\n if n <= 0:\n return 0\n \n # If the result is already in memo, return it directly.\n if n in memo:\n return memo[n]\n \n # Calculate the result using the given equation.\n result = n\n result = max(result, get_max_sum(n//2, memo) + get_max_sum(n//3, memo) + get_max_sum(n//4, memo) + get_max_sum(n//5, memo))\n \n # Store the result in memo and return it.\n memo[n] = result\n return result", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n, memo={}):\n \"\"\"\n This function calculates the maximum sum possible by using the given equation \n f(n) = max( (f(n/2) + f(n/3) + f(n/4) + f(n/5)), n).\n \n Args:\n n (int): Input number.\n memo (dict, optional): Dictionary for memoization. Defaults to {}.\n \n Returns:\n int: Maximum sum possible.\n \"\"\"\n \n # Base case\n if n < 1:\n return 0\n \n # If result is already in memo, return it\n if n in memo:\n return memo[n]\n \n # Recursive cases\n divide_by_2 = 0 if n < 2 else get_max_sum(n // 2, memo)\n divide_by_3 = 0 if n < 3 else get_max_sum(n // 3, memo)\n divide_by_4 = 0 if n < 4 else get_max_sum(n // 4, memo)\n divide_by_5 = 0 if n < 5 else get_max_sum(n // 5, memo)\n \n # Store result in memo\n memo[n] = max(n, divide_by_2 + divide_by_3 + divide_by_4 + divide_by_5)\n \n return memo[n]", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n, memo={}):\n \"\"\"\n Calculate the maximum sum possible by using the given equation f(n) = max( (f(n/2) + f(n/3) + f(n/4) + f(n/5)), n).\n\n Args:\n n (int): Input number\n memo (dict): Memoization to improve performance (default is an empty dict)\n\n Returns:\n int: The maximum sum possible\n \"\"\"\n # Base case for memoization\n if n < 1:\n return 0\n\n # Check if the subproblem has already been solved\n if n in memo:\n return memo[n]\n\n # Calculate the sum of subproblems\n total_sum = 0\n for i in [2, 3, 4, 5]:\n if n >= i:\n total_sum += get_max_sum(n // i, memo)\n\n # Store the maximum sum for the subproblem\n memo[n] = max(total_sum, n)\n return memo[n]", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n, memo = {}):\n \"\"\"\n Calculate the maximum sum possible by using the given equation f(n) = max((f(n/2) + f(n/3) + f(n/4) + f(n/5)), n)\n \n Args:\n n (int): Input value\n memo (dict): A dictionary to store the results of subproblems\n \n Returns:\n int: Maximum sum possible\n \"\"\"\n if n < 2:\n return n\n \n # If the result of subproblem is already in the memo, return it\n if n in memo:\n return memo[n]\n \n # Calculate the maximum sum for the current subproblem\n max_sum = max(n, get_max_sum(n//2, memo) + get_max_sum(n//3, memo) + get_max_sum(n//4, memo) + get_max_sum(n//5, memo))\n \n # Store the result of subproblem in the memo\n memo[n] = max_sum\n \n return max_sum", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n, memo={}):\n \"\"\"\n This function finds the maximum sum possible by using the given equation f(n) = max( (f(n/2) + f(n/3) + f(n/4) + f(n/5)), n).\n \n Args:\n n (int): The input number for which the function calculates the maximum sum.\n\n Returns:\n int: The maximum sum possible using the given equation.\n \"\"\"\n\n # Create a dictionary to store the results of expensive function calls to avoid redundant calculations\n if n < 1:\n return 0\n\n # If the result is already in the memo, return it directly\n if n in memo:\n return memo[n]\n\n # Calculate the result using the equation\n result = max(n, get_max_sum(n//2, memo) + get_max_sum(n//3, memo) + get_max_sum(n//4, memo) + get_max_sum(n//5, memo))\n\n # Store the result in the memo\n memo[n] = result\n\n return result", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n, memo={}):\n \"\"\"\n Function to calculate the maximum sum possible by using the given equation f(n) = max((f(n/2) + f(n/3) + f(n/4) + f(n/5)), n)\n\n Args:\n n (int): Input number\n memo (dict): A dictionary to store results of expensive function calls and reuse them when the same inputs occur again.\n\n Returns:\n int: The maximum sum possible\n \"\"\"\n if n in memo:\n # If result is already calculated, return it from memo\n return memo[n]\n if n < 1:\n # Base case: return 0 for negative numbers and 0\n return 0\n if n == 1:\n # Base case: return 1 for number 1\n return 1\n \n # Calculate f(n/2), f(n/3), f(n/4) and f(n/5) and add them\n sum_of_divisions = (get_max_sum(n//2, memo) + \n get_max_sum(n//3, memo) + \n get_max_sum(n//4, memo) + \n get_max_sum(n//5, memo))\n \n # Return max of the two possible values\n result = max(sum_of_divisions, n)\n memo[n] = result # Store result in memo\n return result", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n, memo = {}):\n \"\"\"\n This function calculates the maximum sum possible using the given equation f(n) = max( (f(n/2) + f(n/3) + f(n/4) + f(n/5)), n).\n\n Args:\n n (int): Input number.\n memo (dict): Dictionary to store results of expensive function calls.\n\n Returns:\n int: The maximum sum possible.\n \"\"\"\n # base case\n if n < 1:\n return 0\n\n # return the result if it already exists\n if n in memo:\n return memo[n]\n\n # calculate the values for n/2, n/3, n/4 and n/5\n val1 = n // 2\n val2 = n // 3\n val3 = n // 4\n val4 = n // 5\n\n # recursively calculate the sums for each value\n sum1 = get_max_sum(val1, memo) + get_max_sum(val2, memo) + get_max_sum(val3, memo) + get_max_sum(val4, memo)\n\n # store the result in the memo dictionary\n memo[n] = max(n, sum1)\n\n # return the maximum sum\n return memo[n]", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n, memo = {}):\n \"\"\"\n Find the maximum sum possible using the equation f(n) = max((f(n/2) + f(n/3) + f(n/4) + f(n/5)), n).\n \n Args:\n n (int): Input number\n memo (dict): A dictionary to store results of subproblems (default: empty dictionary)\n \n Returns:\n int: Maximum sum possible\n \"\"\"\n if n in memo:\n return memo[n]\n \n if n < 6:\n return n\n \n # Use integer division to ensure we're passing integers to the recursive calls\n result = max(n, \n get_max_sum(n // 2, memo) + get_max_sum(n // 3, memo) + get_max_sum(n // 4, memo) + get_max_sum(n // 5, memo))\n memo[n] = result\n return result", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n, memo={}):\n \"\"\"\n Calculate the maximum sum possible by using the given equation f(n) = max( (f(n/2) + f(n/3) + f(n/4) + f(n/5)), n).\n \n Args:\n n (int): The number for which the maximum sum needs to be calculated.\n\n Returns:\n int: The maximum sum possible.\n \"\"\"\n # Base case: If n is less than or equal to 0, return 0.\n if n <= 0:\n return 0\n \n # Base case: If n is already in the memo dictionary, return its value.\n if n in memo:\n return memo[n]\n \n # Recursive case: Calculate f(n) by taking maximum of n and f(n/2) + f(n/3) + f(n/4) + f(n/5)\n result = max(n, get_max_sum(n//2, memo) + get_max_sum(n//3, memo) + get_max_sum(n//4, memo) + get_max_sum(n//5, memo))\n \n # Store the calculated value in the memo dictionary to avoid redundant calculations.\n memo[n] = result\n \n return result", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n, memo={}):\n \"\"\"\n This function finds the maximum sum possible by using the given equation f(n) = max( (f(n/2) + f(n/3) + f(n/4) + f(n/5)), n).\n\n Args:\n n (int): The number to compute the maximum sum for.\n\n Returns:\n int: The maximum sum possible.\n\n \"\"\"\n # Base case: If n is 1 or less, the maximum sum is n\n if n <= 1:\n return n\n \n # Check if result is already computed and stored in memo\n if n in memo:\n return memo[n]\n\n # Compute f(n/2), f(n/3), f(n/4), f(n/5) if they are not zero\n options = []\n for divisor in [2, 3, 4, 5]:\n if n // divisor > 0:\n options.append(get_max_sum(n // divisor, memo))\n\n # Compute the maximum sum\n max_sum = max(n, sum(options))\n\n # Store the computed result in memo\n memo[n] = max_sum\n return max_sum", "matching_cluster_idx": 11}, {"solution": "def get_max_sum(n, memo={}):\n \"\"\"\n This function calculates the maximum sum possible by using the given equation \n f(n) = max( (f(n/2) + f(n/3) + f(n/4) + f(n/5)), n).\n\n Args:\n n (int): Input number\n memo (dict, optional): Dictionary for memoization. Defaults to {}.\n\n Returns:\n int: Maximum possible sum.\n \"\"\"\n # Base case\n if n <= 0:\n return 0\n\n # If already computed, return the result\n if n in memo:\n return memo[n]\n\n # Compute all possible sums\n sum_2 = 0 if n < 2 else get_max_sum(n // 2, memo)\n sum_3 = 0 if n < 3 else get_max_sum(n // 3, memo)\n sum_4 = 0 if n < 4 else get_max_sum(n // 4, memo)\n sum_5 = 0 if n < 5 else get_max_sum(n // 5, memo)\n\n # Store the maximum sum in memo and return it\n memo[n] = max(sum_2 + sum_3 + sum_4 + sum_5, n)\n return memo[n]", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n, memo = {}):\n \"\"\"\n Find the maximum sum possible by using the given equation f(n) = max( (f(n/2) + f(n/3) + f(n/4) + f(n/5)), n).\n\n Args:\n n (int): The number to start with.\n memo (dict, optional): Dictionary to store the results of expensive function calls. Defaults to {}.\n\n Returns:\n int: The maximum sum possible.\n \"\"\"\n # Base case\n if n < 4:\n return n\n\n # If result is already in memo, return it\n if n in memo:\n return memo[n]\n\n # Calculate f(n/2), f(n/3), f(n/4) and f(n/5)\n val1 = get_max_sum(n//2, memo)\n val2 = get_max_sum(n//3, memo)\n val3 = get_max_sum(n//4, memo)\n val4 = get_max_sum(n//5, memo)\n\n # Store the maximum sum in memo\n memo[n] = max(n, val1 + val2 + val3 + val4)\n\n return memo[n]", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n, memo = {}):\n \"\"\"\n This function calculates the maximum sum possible by using the given equation f(n) = max( (f(n/2) + f(n/3) + f(n/4) + f(n/5)), n).\n \n Parameters:\n n (int): The input number.\n \n Returns:\n int: The maximum sum possible.\n \"\"\"\n # Base case: If n is 0 or already calculated, return the stored result.\n if n == 0 or n in memo:\n return memo.get(n, 0)\n \n # Recursive case: Calculate the maximum sum by taking the maximum of the current number and the sum of f(n/2), f(n/3), f(n/4), f(n/5).\n result = max(n, get_max_sum(n//2, memo) + get_max_sum(n//3, memo) + get_max_sum(n//4, memo) + get_max_sum(n//5, memo))\n \n # Store the result for future reference to avoid redundant calculations.\n memo[n] = result\n \n return result", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n, memo = {}):\n \"\"\"\n This function returns the maximum sum possible using the given equation \n f(n) = max( (f(n/2) + f(n/3) + f(n/4) + f(n/5)), n).\n \n Parameters:\n n (int): The number to calculate the maximum sum for.\n memo (dict): A dictionary to store the results of expensive function calls.\n \n Returns:\n int: The maximum sum possible.\n \"\"\"\n if n in memo:\n return memo[n]\n if n < 1:\n return 0\n \n # Base case: f(n) = n when n < 6\n if n < 6:\n result = n\n else:\n # Calculate f(n/2), f(n/3), f(n/4), f(n/5) recursively\n result = max(n, \n get_max_sum(n//2, memo) + get_max_sum(n//3, memo) + \n get_max_sum(n//4, memo) + get_max_sum(n//5, memo))\n \n # Store the result in the memo dictionary to avoid redundant calculations\n memo[n] = result\n return result", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n, memo={}):\n \"\"\"\n This function calculates the maximum sum possible using the given equation f(n) = max((f(n/2) + f(n/3) + f(n/4) + f(n/5)), n).\n \n Args:\n n (int): The input number.\n memo (dict): A dictionary to store the results of subproblems for memoization.\n \n Returns:\n int: The maximum sum possible.\n \"\"\"\n if n in memo:\n return memo[n]\n elif n < 1:\n return 0\n \n total = n\n \n # calculate sums for n/2, n/3, n/4, n/5 and store them in separate variables\n sum_2 = 0\n if n >= 2:\n sum_2 = get_max_sum(n//2, memo)\n \n sum_3 = 0\n if n >= 3:\n sum_3 = get_max_sum(n//3, memo)\n \n sum_4 = 0\n if n >= 4:\n sum_4 = get_max_sum(n//4, memo)\n \n sum_5 = 0\n if n >= 5:\n sum_5 = get_max_sum(n//5, memo)\n \n # calculate the maximum possible sum by considering the given equation\n total = max(total, sum_2 + sum_3 + sum_4 + sum_5)\n \n # store the result in the memo dictionary for memoization\n memo[n] = total\n \n return total", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n, memo={}):\n \"\"\"\n This function calculates the maximum sum possible by using the given equation f(n) = max((f(n/2) + f(n/3) + f(n/4) + f(n/5)), n).\n\n Args:\n n (int): The number for which the maximum sum is to be found.\n memo (dict): A dictionary to store the results of subproblems for memoization.\n\n Returns:\n int: The maximum sum possible.\n \"\"\"\n # Base case\n if n < 1:\n return 0\n\n # If the result is already calculated, return it directly\n if n in memo:\n return memo[n]\n\n # Calculate the maximum sum\n max_sum = n\n max_sum = max(max_sum, get_max_sum(n//2, memo) + get_max_sum(n//3, memo) + get_max_sum(n//4, memo) + get_max_sum(n//5, memo))\n\n # Store the result in the memo dictionary\n memo[n] = max_sum\n\n return max_sum", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n, memo={}):\n \"\"\"\n Calculate the maximum sum possible by using the given equation f(n) = max( (f(n/2) + f(n/3) + f(n/4) + f(n/5)), n).\n \n Args:\n n (int): The input number.\n \n Returns:\n int: The maximum sum possible.\n \"\"\"\n if n < 1:\n return 0\n \n # Base case\n if n == 1:\n return 1\n \n # Use memoization to store the results of expensive function calls\n if n not in memo:\n # Calculate the maximum sum by taking the maximum of n and the sum of function calls for n/2, n/3, n/4, and n/5\n memo[n] = max(n, get_max_sum(n//2, memo) + get_max_sum(n//3, memo) + get_max_sum(n//4, memo) + get_max_sum(n//5, memo))\n \n return memo[n]", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n, memo = {}):\n \"\"\"\n This function calculates the maximum sum possible by using the given equation f(n) = max( (f(n/2) + f(n/3) + f(n/4) + f(n/5)), n).\n \n Args:\n n (int): Input number for which the maximum sum is to be calculated.\n \n Returns:\n int: The maximum sum possible for the given number.\n \"\"\"\n # Base case: If n is 0 or less, return 0\n if n <= 0:\n return 0\n \n # If result is already calculated, return from memo\n if n in memo:\n return memo[n]\n \n # Calculate the maximum sum using the given equation\n max_sum = n\n max_sum = max(max_sum, get_max_sum(n//2, memo) + get_max_sum(n//3, memo) + get_max_sum(n//4, memo) + get_max_sum(n//5, memo))\n \n # Store the result in memo and return it\n memo[n] = max_sum\n return max_sum", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n, memo = {}):\n \"\"\"\n Calculate the maximum possible sum for a given number n using the formula:\n f(n) = max((f(n/2) + f(n/3) + f(n/4) + f(n/5)), n)\n \"\"\"\n \n # Base case: If n is 0 or less, return 0\n if n <= 0:\n return 0\n \n # If n is already in memo, return the cached value\n if n in memo:\n return memo[n]\n \n # Calculate all possible sums\n sums = [\n n, \n get_max_sum(n // 2, memo) + get_max_sum(n // 3, memo) + get_max_sum(n // 4, memo) + get_max_sum(n // 5, memo)\n ]\n \n # Store the maximum sum in memo and return\n memo[n] = max(sums)\n return memo[n]", "matching_cluster_idx": 12}]}, "Mbpp/395": {"dps": 98.08429118773947, "dps_norm": 75.0, "pass@1": 98.0, "profiled": [{"solution": "def first_non_repeating_character(s):\n \"\"\"\n Finds the first non-repeating character in a given string.\n\n Args:\n s (str): The input string.\n\n Returns:\n str: The first non-repeating character, or None if no such character exists.\n\n \"\"\"\n # Create a frequency dictionary\n frequency = {}\n for char in s:\n if char in frequency:\n frequency[char] += 1\n else:\n frequency[char] = 1\n\n # Iterate over the string to find the first character with a frequency of 1\n for char in s:\n if frequency[char] == 1:\n return char\n\n # If no such character is found, return None\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n \"\"\"\n Returns the first non-repeating character in a given string.\n \n Args:\n s (str): The input string.\n\n Returns:\n str or None: The first non-repeating character, or None if all characters repeat.\n \"\"\"\n # Create a dictionary to store the count of each character\n char_count = {}\n \n # Count the occurrence of each character\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n \n # Find the first non-repeating character\n for char in s:\n if char_count[char] == 1:\n return char\n \n # Return None if all characters repeat\n return None", "matching_cluster_idx": 5}, {"solution": "from collections import Counter\ndef first_non_repeating_character(s):\n \"\"\"\n This function finds the first non-repeated character in a given string.\n\n Args:\n s (str): The input string.\n\n Returns:\n str or None: The first non-repeated character in the string, or None if no such character exists.\n \"\"\"\n char_count = Counter(s)\n for char in s:\n if char_count[char] == 1:\n return char\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n \"\"\"\n Finds the first non-repeated character in a given string.\n\n Args:\n s (str): The input string.\n\n Returns:\n str or None: The first non-repeated character if found, otherwise None.\n \"\"\"\n char_count = {} # Dictionary to store character counts\n for char in s: # First pass: count character occurrences\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n\n for char in s: # Second pass: find the first non-repeated character\n if char_count[char] == 1:\n return char\n\n return None # Return None if no non-repeated character is found", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n \"\"\"\n Finds the first non-repeated character in a given string.\n\n Args:\n s (str): The input string.\n\n Returns:\n str or None: The first non-repeated character, or None if no such character exists.\n \"\"\"\n # Create a dictionary to count the occurrences of each character\n char_count = {}\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n \n # Find the first character that occurs only once\n for char in s:\n if char_count[char] == 1:\n return char\n \n # If no non-repeated character is found, return None\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n \"\"\"\n Find the first non-repeated character in a given string.\n\n Args:\n s (str): The input string.\n\n Returns:\n str or None: The first non-repeated character, or None if no such character exists.\n \"\"\"\n\n # Create a dictionary to store character frequencies\n char_count = {}\n \n # Count the occurrence of each character in the string\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n\n # Find the first character with a count of 1\n for char in s:\n if char_count[char] == 1:\n return char\n\n # If no non-repeated character is found, return None\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n \"\"\"\n Find the first non-repeated character in a given string.\n\n Args:\n s (str): The input string.\n\n Returns:\n str: The first non-repeated character, or None if no such character exists.\n \"\"\"\n char_count = {} # Initialize a dictionary to store character counts\n\n # First pass: count the occurrences of each character\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n\n # Second pass: find the first character with a count of 1\n for char in s:\n if char_count[char] == 1:\n return char\n\n # If no non-repeated character is found, return None\n return None", "matching_cluster_idx": 5}, {"solution": "from collections import Counter\ndef first_non_repeating_character(s):\n \"\"\"\n This function finds the first non-repeating character in a given string.\n\n Args:\n s (str): The input string.\n\n Returns:\n str or None: The first non-repeating character, or None if no such character exists.\n \"\"\"\n # Count the frequency of each character in the string\n char_count = Counter(s)\n\n # Iterate over the characters in the string in order of appearance\n for char in s:\n # If the character's count is 1, it's the first non-repeating character\n if char_count[char] == 1:\n return char\n\n # If no non-repeating character is found, return None\n return None", "matching_cluster_idx": 5}, {"solution": "from collections import Counter\ndef first_non_repeating_character(s):\n \"\"\"\n This function finds the first non-repeated character in a given string.\n \n Args:\n s (str): Input string.\n \n Returns:\n str or None: The first non-repeated character if exists, otherwise None.\n \"\"\"\n char_count = Counter(s)\n for char in s:\n if char_count[char] == 1:\n return char\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n \"\"\"\n This function finds the first non-repeated character in a given string.\n\n Args:\n s (str): The input string.\n\n Returns:\n str: The first non-repeated character in the string or None if no such character exists.\n \"\"\"\n # Create a dictionary to store character frequencies\n char_frequency = {}\n \n # Iterate through the string to count the frequency of each character\n for char in s:\n if char in char_frequency:\n char_frequency[char] += 1\n else:\n char_frequency[char] = 1\n \n # Iterate through the string again to find the first non-repeated character\n for char in s:\n if char_frequency[char] == 1:\n return char\n \n # If no non-repeated character is found, return None\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n \"\"\"\n This function finds the first non-repeating character in a given string.\n \n Args:\n s (str): Input string.\n \n Returns:\n str: The first non-repeating character in the string. If no such character exists, returns None.\n \"\"\"\n char_count = {} # Create an empty dictionary to store the count of each character.\n \n # Count the occurrence of each character in the string.\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n \n # Iterate over the string again to find the first character with a count of 1.\n for char in s:\n if char_count[char] == 1:\n return char\n \n # If no non-repeating character is found, return None.\n return None", "matching_cluster_idx": 5}, {"solution": "from collections import Counter\ndef first_non_repeating_character(s):\n \"\"\"\n This function returns the first non-repeated character in a given string.\n\n Args:\n s (str): The input string.\n\n Returns:\n str or None: The first non-repeated character if found, None otherwise.\n \"\"\"\n # Count the frequency of each character in the string\n char_frequency = Counter(s)\n \n # Iterate over the characters in the string, in order of appearance\n for char in s:\n # If a character appears only once, it's the first non-repeated character\n if char_frequency[char] == 1:\n return char\n \n # If no non-repeated character is found, return None\n return None", "matching_cluster_idx": 5}, {"solution": "from collections import Counter\ndef first_non_repeating_character(s):\n \"\"\"\n This function finds the first non-repeated character in a given string.\n\n Args:\n s (str): The input string.\n\n Returns:\n str or None: The first non-repeated character in the string, or None if no such character exists.\n \"\"\"\n char_counts = Counter(s)\n for char in s:\n if char_counts[char] == 1:\n return char\n return None", "matching_cluster_idx": 5}, {"solution": "from collections import Counter\ndef first_non_repeating_character(s: str) -> str or None:\n \"\"\"\n This function finds the first non-repeating character in a given string.\n\n Args:\n s (str): Input string.\n\n Returns:\n str: The first non-repeating character in the string, or None if no such character exists.\n\n \"\"\"\n char_count = Counter(s) # Count occurrences of each character\n for char in s: # Iterate through the string in order\n if char_count[char] == 1: # Check for non-repeating characters\n return char # Return the first non-repeating character\n return None # Return None if no non-repeating character is found", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n \"\"\"\n This function finds the first non-repeated character in a given string.\n \n Args:\n s (str): The input string.\n \n Returns:\n str or None: The first non-repeated character if found, otherwise None.\n \"\"\"\n char_count = {} # Initialize an empty dictionary to store character counts\n \n # Count occurrences of each character in the string\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n \n # Find the first non-repeated character\n for char in s:\n if char_count[char] == 1:\n return char\n \n return None # Return None if no non-repeated character is found", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n \"\"\"\n Returns the first non-repeating character in a given string, or None if no such character exists.\n\n :param s: The input string.\n :return: The first non-repeating character in the string, or None if no such character exists.\n \"\"\"\n char_count = {}\n for char in s:\n char_count[char] = char_count.get(char, 0) + 1\n\n for char in s:\n if char_count[char] == 1:\n return char\n\n return None", "matching_cluster_idx": 5}, {"solution": "from collections import Counter\ndef first_non_repeating_character(s):\n \"\"\"\n Returns the first non-repeating character in a given string.\n If all characters repeat, returns None.\n\n :param s: The input string.\n :return: The first non-repeating character, or None if all characters repeat.\n \"\"\"\n # Create a counter of characters in the string\n char_count = Counter(s)\n\n # Iterate over the string, checking each character's count\n for char in s:\n if char_count[char] == 1:\n # Return the first character with a count of 1\n return char\n\n # If no non-repeating characters are found, return None\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n \"\"\"\n This function returns the first non-repeating character in a given string.\n If all characters repeat, it returns None.\n\n Parameters:\n s (str): The input string.\n\n Returns:\n str: The first non-repeating character in the string, or None if all characters repeat.\n \"\"\"\n # Create a dictionary to store character frequencies\n char_freq = {}\n \n # Iterate through the string to count character frequencies\n for char in s:\n if char in char_freq:\n char_freq[char] += 1\n else:\n char_freq[char] = 1\n \n # Iterate through the string again to find the first non-repeating character\n for char in s:\n if char_freq[char] == 1:\n return char\n \n # If no non-repeating character is found, return None\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n \"\"\"\n Returns the first non-repeated character in a given string, \n or None if all characters repeat.\n\n Parameters:\n s (str): The input string.\n\n Returns:\n str or None: The first non-repeated character, or None if all characters repeat.\n \"\"\"\n # Create a dictionary to store the frequency of each character\n char_frequency = {}\n \n # Iterate through the string to count the frequency of each character\n for char in s:\n if char in char_frequency:\n char_frequency[char] += 1\n else:\n char_frequency[char] = 1\n \n # Iterate through the string again to find the first non-repeated character\n for char in s:\n if char_frequency[char] == 1:\n return char\n \n # If no non-repeated character is found, return None\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n \"\"\"\n This function finds the first non-repeated character in a given string.\n\n Args:\n s (str): The input string.\n\n Returns:\n The first non-repeated character in the string, or None if all characters are repeated.\n \"\"\"\n # Create a dictionary to store character frequencies\n char_frequency = {}\n \n # Count the frequency of each character in the string\n for char in s:\n if char in char_frequency:\n char_frequency[char] += 1\n else:\n char_frequency[char] = 1\n \n # Find the first character with a frequency of 1\n for char in s:\n if char_frequency[char] == 1:\n return char\n \n # If no non-repeated character is found, return None\n return None", "matching_cluster_idx": 5}]}, "Mbpp/405": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 88.0, "profiled": [{"solution": "def check_tuplex(input_tuple, target_element):\n \"\"\"\n Checks whether a given element exists within a tuple.\n\n Args:\n input_tuple (tuple): The tuple to be searched.\n target_element: The element to be searched for.\n\n Returns:\n bool: True if the element exists in the tuple, False otherwise.\n \"\"\"\n return target_element in input_tuple", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tup, element):\n \"\"\"\n This function checks if an element exists in a given tuple.\n\n Args:\n tup (tuple): The input tuple.\n element: The element to be searched in the tuple.\n\n Returns:\n bool: True if the element is found, False otherwise.\n \"\"\"\n return element in tup", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, element):\n \"\"\"\n Checks whether an element exists within a tuple.\n\n Args:\n tuplex (tuple): The input tuple to be searched.\n element: The element to be searched within the tuple.\n\n Returns:\n bool: True if the element is found in the tuple, False otherwise.\n \"\"\"\n return element in tuplex", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, element):\n \"\"\"\n Checks whether a given element exists within a tuple.\n\n Args:\n tuplex (tuple): The tuple to search in.\n element: The element to search for.\n\n Returns:\n bool: True if the element is found, False otherwise.\n \"\"\"\n return element in tuplex", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tup, elem):\n \"\"\"\n Checks if an element exists within a tuple.\n \n Args:\n tup (tuple): The tuple to be searched.\n elem (any): The element to search for.\n \n Returns:\n bool: True if the element exists, False otherwise.\n \"\"\"\n return elem in tup", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(input_tuple, target_element):\n \"\"\"\n This function checks if a target element exists in a given tuple.\n\n Args:\n input_tuple (tuple): A tuple containing elements.\n target_element: The element to be searched within the tuple.\n\n Returns:\n bool: True if the target element exists in the tuple, False otherwise.\n \"\"\"\n return target_element in input_tuple", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tup, element):\n \"\"\"\n Checks if an element exists within a tuple.\n\n Args:\n tup (tuple): The tuple to search in.\n element: The element to search for.\n\n Returns:\n bool: True if the element exists in the tuple, False otherwise.\n \"\"\"\n return element in tup", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(input_tuple, target_element):\n \"\"\"\n This function checks if a target element exists in a given tuple.\n\n Args:\n input_tuple (tuple): A tuple that may or may not contain the target element.\n target_element: The element to search for in the tuple.\n\n Returns:\n bool: True if the target element exists in the tuple, False otherwise.\n \"\"\"\n return target_element in input_tuple", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, target):\n \"\"\"\n Checks if an element exists within a tuple.\n\n Args:\n tuplex (tuple): The tuple to search.\n target: The element to search for.\n\n Returns:\n bool: True if the element exists, False otherwise.\n \"\"\"\n return target in tuplex", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(my_tuple, target):\n \"\"\"\n Check if a target element exists within a given tuple.\n\n Args:\n my_tuple (tuple): The tuple to search.\n target (any): The element to search for.\n\n Returns:\n bool: True if the target exists in the tuple, False otherwise.\n \"\"\"\n return target in my_tuple", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tup, element):\n \"\"\"\n Checks if an element exists within a tuple.\n\n Args:\n tup (tuple): The tuple to search in.\n element: The element to search for.\n\n Returns:\n bool: True if the element exists in the tuple, False otherwise.\n \"\"\"\n return element in tup", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tup, elem):\n \"\"\"\n Checks whether an element exists within a tuple.\n\n Args:\n tup (tuple): The tuple to be searched.\n elem: The element to search for.\n\n Returns:\n bool: True if the element exists, False otherwise.\n \"\"\"\n return elem in tup", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tup, element):\n \"\"\"\n Check if an element exists within a tuple.\n \n Args:\n tup (tuple): The input tuple to be searched.\n element: The element to be searched for in the tuple.\n \n Returns:\n bool: True if the element exists in the tuple, False otherwise.\n \"\"\"\n return element in tup", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, element):\n \"\"\"\n Checks whether an element exists within a tuple.\n\n Args:\n tuplex (tuple): The tuple to search in.\n element (any): The element to search for.\n\n Returns:\n bool: True if the element exists in the tuple, False otherwise.\n \"\"\"\n return element in tuplex", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(my_tuple, target):\n \"\"\"\n This function checks whether a specified element exists within a tuple.\n \n Args:\n my_tuple (tuple): The tuple to be searched in.\n target (any): The element to be searched for.\n\n Returns:\n bool: True if the target element exists in the tuple; False otherwise.\n \"\"\"\n return target in my_tuple", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tup, elem):\n \"\"\"\n This function checks if a given element exists within a tuple.\n \n Args:\n tup (tuple): The input tuple to be searched.\n elem: The element to be searched for in the tuple.\n \n Returns:\n bool: True if the element exists in the tuple, False otherwise.\n \"\"\"\n return elem in tup", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(input_tuple, target_element):\n \"\"\"\n Check if an element exists within a tuple.\n\n Args:\n input_tuple (tuple): The tuple to search in.\n target_element: The element to search for.\n\n Returns:\n bool: True if the target element exists in the tuple, False otherwise.\n \"\"\"\n return target_element in input_tuple", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(input_tuple, target_element):\n \"\"\"\n Checks whether a target element exists within a tuple.\n\n Args:\n input_tuple (tuple): The input tuple to search in.\n target_element: The target element to search for.\n\n Returns:\n bool: True if the target element is found in the tuple, False otherwise.\n \"\"\"\n return target_element in input_tuple", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tup, elem):\n \"\"\"\n Checks if an element exists in the tuple.\n\n Args:\n tup (tuple): The input tuple to be searched.\n elem: The element to be searched in the tuple.\n\n Returns:\n bool: True if the element exists in the tuple, False otherwise.\n \"\"\"\n return elem in tup", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, target):\n \"\"\"\n Check if an element exists within a tuple.\n\n Args:\n tuplex (tuple): The tuple to search in.\n target: The element to search for.\n\n Returns:\n bool: True if the element exists in the tuple, False otherwise.\n \"\"\"\n return target in tuplex", "matching_cluster_idx": 3}]}, "Mbpp/414": {"dps": 83.19875776397515, "dps_norm": 85.55555555555556, "pass@1": 100.0, "profiled": [{"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Checks if any value in seq1 exists in seq2.\n\n Args:\n seq1 (list): First sequence.\n seq2 (list): Second sequence.\n\n Returns:\n bool: True if any value in seq1 exists in seq2, False otherwise.\n \"\"\"\n return any(value in seq2 for value in seq1)", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n This function checks if there is any overlap between two sequences.\n \n Parameters:\n seq1 (list): The first sequence.\n seq2 (list): The second sequence.\n \n Returns:\n bool: True if there is any overlap, False otherwise.\n \"\"\"\n return any(i in seq2 for i in seq1)", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Checks whether any value in seq1 exists in seq2.\n\n Args:\n seq1 (list): The first sequence.\n seq2 (list): The second sequence.\n\n Returns:\n bool: True if any value in seq1 exists in seq2, False otherwise.\n \"\"\"\n return any(value in seq2 for value in seq1)", "matching_cluster_idx": 7}, {"solution": "def overlapping(sequence1, sequence2):\n \"\"\"\n Checks whether any value in sequence1 exists in sequence2 or not.\n\n Args:\n sequence1 (list): The first sequence to check.\n sequence2 (list): The second sequence to check against.\n\n Returns:\n bool: True if any value in sequence1 exists in sequence2, False otherwise.\n \"\"\"\n return any(value in sequence2 for value in sequence1)", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n This function checks whether any value in a sequence exists in another sequence.\n\n Args:\n seq1 (sequence): The first sequence to be compared.\n seq2 (sequence): The second sequence to be compared.\n\n Returns:\n bool: True if any value in seq1 exists in seq2, False otherwise.\n\n \"\"\"\n return any(element in seq2 for element in seq1)", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Checks whether any value in the first sequence exists in the second sequence.\n \n Args:\n seq1 (list): The first sequence.\n seq2 (list): The second sequence.\n \n Returns:\n bool: True if any value in seq1 exists in seq2, False otherwise.\n \"\"\"\n return any(value in seq2 for value in seq1)", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n This function checks if any value in the first sequence exists in the second sequence.\n\n Args:\n seq1 (list): The first sequence to be checked.\n seq2 (list): The second sequence to be checked against.\n\n Returns:\n bool: True if any value in seq1 exists in seq2, False otherwise.\n \"\"\"\n # Convert sequences to sets for efficient lookups\n set1 = set(seq1)\n set2 = set(seq2)\n\n # Check for intersection between the two sets\n return bool(set1 & set2)", "matching_cluster_idx": 5}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Checks if any value in sequence 1 exists in sequence 2.\n\n Args:\n seq1 (list): The first sequence.\n seq2 (list): The second sequence.\n\n Returns:\n bool: True if any value in seq1 exists in seq2, False otherwise.\n \"\"\"\n return any(i in seq2 for i in seq1)", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Returns True if any element from seq1 exists in seq2.\n \n Parameters:\n seq1 (list): The first sequence.\n seq2 (list): The second sequence.\n \n Returns:\n bool: Whether there's an overlap between the sequences.\n \"\"\"\n return len(set(seq1) & set(seq2)) > 0", "matching_cluster_idx": 5}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Checks if any value in seq1 exists in seq2.\n\n Args:\n seq1 (list): The first sequence.\n seq2 (list): The second sequence.\n\n Returns:\n bool: True if any value in seq1 exists in seq2, False otherwise.\n \"\"\"\n return any(item in seq2 for item in seq1)", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Checks if any element in seq1 exists in seq2.\n\n Args:\n seq1 (list): The first sequence to check.\n seq2 (list): The second sequence to check against.\n\n Returns:\n bool: True if any element in seq1 exists in seq2, False otherwise.\n \"\"\"\n return any(item in seq2 for item in seq1)", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Checks if any value in seq1 exists in seq2.\n\n Args:\n seq1 (list): The first sequence.\n seq2 (list): The second sequence.\n\n Returns:\n bool: True if any value in seq1 exists in seq2, False otherwise.\n\n \"\"\"\n return any(item in seq2 for item in seq1)", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Checks whether any value in the first sequence exists in the second sequence.\n\n Args:\n seq1 (list): The first sequence.\n seq2 (list): The second sequence.\n\n Returns:\n bool: True if any value in seq1 exists in seq2, False otherwise.\n \"\"\"\n return any(val in seq2 for val in seq1)", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Checks if any value in seq1 exists in seq2.\n \n Args:\n seq1 (sequence): The first sequence.\n seq2 (sequence): The second sequence.\n \n Returns:\n bool: True if any value in seq1 exists in seq2, False otherwise.\n \"\"\"\n return any(value in seq2 for value in seq1)", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Check whether any value in a sequence exists in another sequence or not.\n\n Args:\n seq1 (sequence): The first sequence to check.\n seq2 (sequence): The second sequence to check.\n\n Returns:\n bool: True if any value in seq1 exists in seq2, False otherwise.\n\n Example:\n >>> overlapping([1, 2, 3, 4, 5], [6, 7, 8, 9])\n False\n \"\"\"\n return any(item in seq2 for item in seq1)", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n This function checks if there are any overlapping values between two sequences.\n\n Args:\n seq1 (list): The first sequence.\n seq2 (list): The second sequence.\n\n Returns:\n bool: True if the sequences overlap, False otherwise.\n \"\"\"\n return any(item in seq2 for item in seq1)", "matching_cluster_idx": 7}, {"solution": "def overlapping(sequence1, sequence2):\n \"\"\"\n Checks whether any value in sequence1 exists in sequence2 or not.\n\n Args:\n sequence1 (list): The first sequence to check.\n sequence2 (list): The second sequence to check against.\n\n Returns:\n bool: True if any value in sequence1 exists in sequence2, False otherwise.\n \"\"\"\n # Convert sequences to sets for efficient lookup\n set1 = set(sequence1)\n set2 = set(sequence2)\n\n # Use set intersection to find common elements\n common_elements = set1 & set2\n\n # Return True if there are any common elements, False otherwise\n return len(common_elements) > 0", "matching_cluster_idx": 5}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Checks whether any value in seq1 exists in seq2.\n\n Args:\n seq1 (sequence): The first sequence to check.\n seq2 (sequence): The second sequence to check against.\n\n Returns:\n bool: True if any element from seq1 exists in seq2, False otherwise.\n \"\"\"\n return any(item in seq2 for item in seq1)", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Checks if any value in seq1 exists in seq2.\n\n Args:\n seq1 (list): The first sequence.\n seq2 (list): The second sequence.\n\n Returns:\n bool: True if any value in seq1 exists in seq2, False otherwise.\n \"\"\"\n return any(i in seq2 for i in seq1)", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Returns True if any value in seq1 exists in seq2, False otherwise.\n \n :param seq1: First sequence\n :param seq2: Second sequence\n :return: bool\n \"\"\"\n return any(x in seq2 for x in seq1)", "matching_cluster_idx": 7}]}, "Mbpp/421": {"dps": 94.60905349794238, "dps_norm": 97.85714285714286, "pass@1": 100.0, "profiled": [{"solution": "def concatenate_tuple(input_tuple):\n \"\"\"\n Concatenates all elements in the input tuple by the '-' delimiter.\n \n Parameters:\n input_tuple (tuple): The input tuple containing elements to be concatenated.\n \n Returns:\n str: A string containing the concatenated elements from the input tuple.\n \"\"\"\n # Ensure all elements in the tuple are converted to strings before concatenation\n return '-'.join(map(str, input_tuple))", "matching_cluster_idx": 6}, {"solution": "def concatenate_tuple(input_tuple, delimiter=\"-\"):\n \"\"\"\n Concatenates each element of a tuple into a string with a specified delimiter.\n\n Args:\n input_tuple (tuple): A tuple containing elements to be concatenated.\n delimiter (str): The delimiter to be used for concatenation. Default is \"-\".\n\n Returns:\n str: A string with all elements from the tuple concatenated by the delimiter.\n \"\"\"\n return delimiter.join(map(str, input_tuple))", "matching_cluster_idx": 6}, {"solution": "def concatenate_tuple(tup, delimiter='-'):\n \"\"\"\n Concatenates each element of a tuple by the given delimiter.\n\n Args:\n tup (tuple): A tuple containing elements to be concatenated.\n delimiter (str): A string used to join the elements. Defaults to '-'.\n\n Returns:\n str: A string formed by concatenating the elements of the tuple.\n \"\"\"\n return delimiter.join(map(str, tup))", "matching_cluster_idx": 6}, {"solution": "def concatenate_tuple(tuple_to_concatenate, delimiter=\"-\"):\n \"\"\"\n Concatenates each element of a tuple into a string with a specified delimiter.\n\n Args:\n tuple_to_concatenate (tuple): Tuple to be concatenated.\n delimiter (str): Delimiter to separate each element. Defaults to \"-\".\n\n Returns:\n str: Concatenated string of the tuple elements.\n \"\"\"\n return delimiter.join(map(str, tuple_to_concatenate))", "matching_cluster_idx": 6}, {"solution": "def concatenate_tuple(input_tuple, delimiter=\"-\"):\n \"\"\"\n This function concatenates all elements of a tuple into a single string \n separated by a specified delimiter.\n\n Args:\n input_tuple (tuple): A tuple of elements to concatenate.\n delimiter (str): The delimiter to use for concatenation. Defaults to \"-\".\n\n Returns:\n str: A concatenated string of the input tuple elements.\n \"\"\"\n # Convert all elements in the tuple to string using map\n str_tuple = map(str, input_tuple)\n # Join the string elements in the tuple using the specified delimiter\n result = delimiter.join(str_tuple)\n return result", "matching_cluster_idx": 6}, {"solution": "def concatenate_tuple(tup, delimiter='-'):\n \"\"\"\n Concatenates each element of a tuple into a string using the specified delimiter.\n \n Args:\n tup (tuple): The tuple to be concatenated.\n delimiter (str): The delimiter to use for concatenation. Defaults to '-'.\n\n Returns:\n str: A string with all elements of the tuple concatenated by the delimiter.\n \"\"\"\n # Convert all elements of the tuple to strings\n str_tup = [str(x) for x in tup]\n \n # Join the strings in the list with the specified delimiter\n result = delimiter.join(str_tup)\n \n return result", "matching_cluster_idx": 4}, {"solution": "def concatenate_tuple(input_tuple, delimiter='-'):\n \"\"\"\n Concatenates each element of the tuple by the given delimiter.\n \n Args:\n input_tuple (tuple): A tuple of elements to be concatenated.\n delimiter (str): The delimiter to be used for concatenation. Defaults to '-'.\n \n Returns:\n str: A string of concatenated elements.\n \"\"\"\n return delimiter.join(map(str, input_tuple))", "matching_cluster_idx": 6}, {"solution": "def concatenate_tuple(input_tuple, delimiter=\"-\"):\n \"\"\"\n Concatenates all elements in a tuple into a single string, using the provided delimiter.\n\n Args:\n input_tuple (tuple): Tuple containing elements to be concatenated.\n delimiter (str): Delimiter to be used for concatenation. Defaults to \"-\".\n\n Returns:\n str: Concatenated string.\n \"\"\"\n return delimiter.join(map(str, input_tuple))", "matching_cluster_idx": 6}, {"solution": "def concatenate_tuple(tup, delimiter=\"-\"):\n \"\"\"\n Concatenates each element in a tuple by a specified delimiter.\n \n Args:\n tup (tuple): The tuple containing elements to concatenate.\n delimiter (str): The delimiter to use for concatenation (defaults to '-').\n \n Returns:\n str: A string with all elements of the tuple concatenated by the delimiter.\n \"\"\"\n # Convert all elements in the tuple to strings and join them with the delimiter\n return delimiter.join(map(str, tup))", "matching_cluster_idx": 6}, {"solution": "def concatenate_tuple(tup, delimiter=\"-\"):\n \"\"\"\n Concatenates all elements of a tuple into a string with a specified delimiter.\n \n Parameters:\n tup (tuple): A tuple of elements to be concatenated. \n Elements can be of any type that can be converted to string.\n delimiter (str): A delimiter to be used between elements. Default is \"-\".\n\n Returns:\n str: A concatenated string of tuple elements with the specified delimiter.\n \"\"\"\n # Convert tuple elements to string using map() and join() functions\n return delimiter.join(map(str, tup))", "matching_cluster_idx": 6}, {"solution": "def concatenate_tuple(tup, delimiter=\"-\"):\n \"\"\"\n Concatenates each element of the tuple into a string separated by a delimiter.\n\n Args:\n tup (tuple): The tuple to concatenate.\n delimiter (str): The delimiter to separate elements. Defaults to \"-\".\n\n Returns:\n str: The concatenated string.\n \"\"\"\n # Convert each element to string using map and join them\n return delimiter.join(map(str, tup))", "matching_cluster_idx": 6}, {"solution": "def concatenate_tuple(tup, delimiter='-'):\n \"\"\"\n Concatenates each element of a tuple into a string using a specified delimiter.\n\n Args:\n tup (tuple): The input tuple to be concatenated.\n delimiter (str): The delimiter used to join the elements. Defaults to '-'.\n\n Returns:\n str: A string with the elements of the tuple joined by the delimiter.\n \"\"\"\n # Convert each element of the tuple to a string and join them using the delimiter\n return delimiter.join(map(str, tup))", "matching_cluster_idx": 6}, {"solution": "def concatenate_tuple(tup, delimiter=\"-\"):\n \"\"\"\n Concatenates each element in the tuple by the delimiter.\n \n Args:\n tup (tuple): The tuple to concatenate.\n delimiter (str): The delimiter to use. Defaults to \"-\".\n \n Returns:\n str: The concatenated string.\n \"\"\"\n # Convert each element in the tuple to a string and join them with the delimiter\n return delimiter.join(map(str, tup))", "matching_cluster_idx": 6}, {"solution": "def concatenate_tuple(tuple_to_concatenate, delimiter=\"-\"):\n \"\"\"\n Concatenates each element of the input tuple into a single string using the given delimiter.\n\n Args:\n tuple_to_concatenate (tuple): A tuple containing elements to be concatenated.\n delimiter (str, optional): A string to separate each element in the tuple. Defaults to \"-\".\n\n Returns:\n str: A concatenated string of tuple elements separated by the given delimiter.\n \"\"\"\n # Use the map function to convert each element to a string, \n # then join the results using the given delimiter\n return delimiter.join(map(str, tuple_to_concatenate))", "matching_cluster_idx": 6}, {"solution": "def concatenate_tuple(tup, delimiter=\"-\"):\n \"\"\"\n Concatenate each element of a tuple by the specified delimiter.\n \n Args:\n tup (tuple): A tuple containing elements to be concatenated.\n delimiter (str): A delimiter used for concatenation (default is \"-\").\n\n Returns:\n str: A string with elements from the tuple concatenated by the delimiter.\n \"\"\"\n return delimiter.join(map(str, tup))", "matching_cluster_idx": 6}, {"solution": "def concatenate_tuple(tuple_to_concatenate, delimiter='-'):\n \"\"\"\n Concatenates each element of a tuple into a single string, \n separated by the provided delimiter.\n\n Args:\n tuple_to_concatenate (tuple): A tuple containing elements to be concatenated.\n delimiter (str): The delimiter to separate the elements. Defaults to '-'.\n\n Returns:\n str: A string where each element of the tuple is concatenated with the delimiter.\n \"\"\"\n return delimiter.join(map(str, tuple_to_concatenate))", "matching_cluster_idx": 6}, {"solution": "def concatenate_tuple(input_tuple, delimiter=\"-\"):\n \"\"\"\n Concatenates each element of a tuple into a single string by the specified delimiter.\n\n Args:\n input_tuple (tuple): A tuple containing elements to be concatenated.\n delimiter (str): The delimiter used to separate each element. Defaults to \"-\".\n\n Returns:\n str: A string containing all elements from the input tuple, separated by the delimiter.\n \"\"\"\n # Convert all elements in the tuple to string\n str_tuple = [str(element) for element in input_tuple]\n \n # Concatenate elements by the delimiter\n result_str = delimiter.join(str_tuple)\n \n return result_str", "matching_cluster_idx": 5}, {"solution": "def concatenate_tuple(tuple_, delimiter='-'):\n \"\"\"\n Concatenates each element of a tuple with a specified delimiter.\n\n Args:\n tuple_: A tuple of elements to be concatenated.\n delimiter (str): The delimiter used for concatenation.\n\n Returns:\n str: A string containing all tuple elements joined by the delimiter.\n\n Raises:\n TypeError: If tuple_ is not a tuple or delimiter is not a string.\n \"\"\"\n if not isinstance(tuple_, tuple) or not isinstance(delimiter, str):\n raise TypeError(\"Invalid input type\")\n\n return delimiter.join(map(str, tuple_))", "matching_cluster_idx": 6}, {"solution": "def concatenate_tuple(input_tuple):\n \"\"\"\n Concatenates each element of the input tuple into a single string, \n using '-' as the delimiter.\n\n Args:\n input_tuple (tuple): The input tuple containing elements to be concatenated.\n\n Returns:\n str: A string containing all elements of the input tuple, concatenated by '-'.\n \"\"\"\n\n # Ensure all elements are converted to string before joining them\n # Using map() function to apply str() function to each element in the tuple\n stringified_tuple = tuple(map(str, input_tuple))\n \n # Join all the stringified elements with '-' as the delimiter\n concatenated_string = '-'.join(stringified_tuple)\n \n return concatenated_string", "matching_cluster_idx": 6}, {"solution": "def concatenate_tuple(input_tuple, delimiter=\"-\"):\n \"\"\"\n This function takes an input tuple and a delimiter (default is \"-\") and returns \n a string where each element of the tuple is concatenated by the delimiter.\n\n Args:\n input_tuple (tuple): A tuple of elements to be concatenated.\n delimiter (str, optional): The delimiter to use for concatenation. Defaults to \"-\".\n\n Returns:\n str: A string with tuple elements concatenated by the delimiter.\n \"\"\"\n\n # Convert each element in the tuple to string and join them using the delimiter\n return delimiter.join(map(str, input_tuple))", "matching_cluster_idx": 6}]}, "Mbpp/424": {"dps": 73.70036101083032, "dps_norm": 89.0, "pass@1": 97.0, "profiled": [{"solution": "def extract_rear(string_tuple):\n \"\"\"\n This function takes a tuple of strings and returns a list of characters.\n Each character in the returned list is the last character of the corresponding string in the input tuple.\n \n Args:\n string_tuple (tuple): A tuple of strings.\n \n Returns:\n list: A list of characters, each of which is the last character of the corresponding string in the input tuple.\n \"\"\"\n # Use a list comprehension to create a list of the last character in each string in the input tuple\n return [s[-1] for s in string_tuple]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(input_tuple):\n \"\"\"\n This function takes a tuple of strings as input and returns a list of characters.\n Each character in the list corresponds to the last character of the string \n at the same index in the input tuple.\n\n Args:\n input_tuple (tuple): A tuple of strings.\n\n Returns:\n list: A list of characters.\n \"\"\"\n return [string[-1] for string in input_tuple]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(tup):\n \"\"\"\n Extracts the last character from each string in a given tuple.\n\n Args:\n tup (tuple): A tuple containing strings.\n\n Returns:\n list: A list of last characters of each string in the input tuple.\n\n \"\"\"\n return [string[-1] for string in tup]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(strings):\n \"\"\"\n Extracts the rear index element of each string in the given tuple.\n\n Args:\n strings (tuple): A tuple of strings.\n\n Returns:\n list: A list of characters where each character is the rear index element of the corresponding string.\n \"\"\"\n return [string[-1] for string in strings]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(strings):\n \"\"\"\n This function takes a tuple of strings as input and returns a list of strings.\n Each string in the output list is the last character of the corresponding string in the input tuple.\n\n Args:\n strings (tuple): A tuple of strings.\n\n Returns:\n list: A list of strings where each string is the last character of the corresponding string in the input tuple.\n \"\"\"\n\n # Initialize an empty list to store the rear index elements of each string\n rear_elements = []\n\n # Iterate over each string in the input tuple\n for string in strings:\n # Append the last character of the string to the rear_elements list\n rear_elements.append(string[-1])\n\n # Return the list of rear index elements\n return rear_elements", "matching_cluster_idx": 3}, {"solution": "def extract_rear(strings):\n \"\"\"\n This function takes a tuple of strings and returns a list containing the last character of each string.\n\n Args:\n strings (tuple): A tuple of strings\n\n Returns:\n list: A list of the last characters from each string\n \"\"\"\n return [string[-1] for string in strings]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(strings):\n \"\"\"\n Extracts the rear index element of each string in the given tuple.\n \n Args:\n strings (tuple): A tuple of strings.\n \n Returns:\n list: A list of rear index elements of each string in the given tuple.\n \"\"\"\n # Check if input is a tuple\n if not isinstance(strings, tuple):\n raise TypeError(\"Input must be a tuple.\")\n \n # Check if all elements in the tuple are strings\n if not all(isinstance(s, str) for s in strings):\n raise TypeError(\"All elements in the tuple must be strings.\")\n \n # Extract rear index element of each string\n return [s[-1] for s in strings]", "matching_cluster_idx": 2}, {"solution": "def extract_rear(tup):\n \"\"\"\n Extracts the rear index element from each string in the given tuple.\n\n Args:\n tup: A tuple containing strings.\n\n Returns:\n A list of strings where each string is the rear index element from the input tuple.\n\n \"\"\"\n return [string[-1] for string in tup]", "matching_cluster_idx": 3}, {"solution": "def extract_rear(strings):\n \"\"\"\n Extracts only the rear index element of each string in the given tuple.\n\n Args:\n strings (tuple): A tuple of strings.\n\n Returns:\n list: A list containing the last character of each string in the input tuple.\n \"\"\"\n # Using list comprehension to get the last character of each string in the tuple\n return [s[-1] for s in strings]", "matching_cluster_idx": 3}, {"solution": "def extract_rear(strings):\n \"\"\"\n This function extracts the last character from each string in the input tuple.\n \n Args:\n strings (tuple): A tuple containing strings.\n \n Returns:\n list: A list of last characters from each string in the input tuple.\n \"\"\"\n # Using list comprehension to create a new list of the last character of each string\n return [string[-1] for string in strings]\nstrings = ('Mers', 'for', 'Vers')", "matching_cluster_idx": 3}, {"solution": "def extract_rear(strings):\n \"\"\"\n Extract the rear index element of each string in the given tuple.\n\n Args:\n strings (tuple): A tuple of strings\n\n Returns:\n list: A list of characters representing the rear index element of each string\n \"\"\"\n return [string[-1] for string in strings]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(strings):\n \"\"\"\n Extracts the rear index element of each string in the given tuple.\n\n Args:\n strings (tuple): A tuple of strings.\n\n Returns:\n list: A list of rear index elements.\n \"\"\"\n return [string[-1] for string in strings]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(strings):\n \"\"\"\n Extract the rear index element of each string in the given tuple.\n\n Args:\n strings (tuple): A tuple of strings.\n\n Returns:\n list: A list of characters. Each character is the rear index element of the corresponding string in the input tuple.\n \"\"\"\n return [string[-1] for string in strings]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(tup):\n \"\"\"\n Extracts the rear index element of each string in the given tuple.\n\n Args:\n tup (tuple): A tuple of strings.\n\n Returns:\n list: A list of characters, each representing the rear index element of the strings in the tuple.\n\n \"\"\"\n return [string[-1] for string in tup]", "matching_cluster_idx": 3}, {"solution": "def extract_rear(tuple_of_strings):\n \"\"\"\n Extracts the last character from each string in the given tuple.\n \n Args:\n tuple_of_strings (tuple): A tuple containing strings.\n \n Returns:\n list: A list containing the last character of each string in the input tuple.\n \"\"\"\n return [string[-1] for string in tuple_of_strings]", "matching_cluster_idx": 3}, {"solution": "def extract_rear(strings):\n \"\"\"\n Extracts the rear index element of each string in a given tuple.\n\n Args:\n strings (tuple): A tuple containing strings.\n\n Returns:\n list: A list containing the last character of each string.\n \"\"\"\n return [string[-1] for string in strings]", "matching_cluster_idx": 3}, {"solution": "def extract_rear(tup):\n \"\"\"\n Extracts the rear index element from each string in a given tuple.\n\n Args:\n tup (tuple): A tuple of strings.\n\n Returns:\n list: A list of characters, each being the rear index element of its corresponding string in the input tuple.\n \"\"\"\n return [string[-1] for string in tup]", "matching_cluster_idx": 3}, {"solution": "def extract_rear(tup):\n \"\"\"\n This function takes a tuple of strings as input and returns a list of their last characters.\n\n Args:\n tup (tuple): A tuple containing strings.\n\n Returns:\n list: A list of last characters of each string in the input tuple.\n \"\"\"\n return [string[-1] for string in tup]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(tup):\n \"\"\"\n This function extracts only the rear index element of each string in the given tuple.\n \n Parameters:\n tup (tuple): A tuple containing strings.\n \n Returns:\n list: A list containing the last character of each string in the input tuple.\n \"\"\"\n return [string[-1] for string in tup]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(tup_of_strings):\n \"\"\"\n This function takes a tuple of strings as input and returns a list of the last character of each string.\n \n Parameters:\n tup_of_strings (tuple): A tuple containing strings\n \n Returns:\n list: A list of the last character of each string in the input tuple\n \"\"\"\n return [string[-1] for string in tup_of_strings]", "matching_cluster_idx": 3}]}, "Mbpp/425": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 99.0, "profiled": [{"solution": "def count_element_in_list(lst, target):\n \"\"\"\n This function counts the number of sublists containing a particular element in a list.\n \n Parameters:\n lst (list): The list containing sublists.\n target: The element to be searched.\n \n Returns:\n int: The number of sublists containing the target element.\n \"\"\"\n # Use a generator expression within the sum function to count sublists containing the target\n return sum(1 for sublist in lst if target in sublist)", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, target):\n \"\"\"\n This function counts the number of sublists in the given list of lists that contain the target element.\n\n Args:\n lst (list): A list of lists.\n target: The target element to search for in the sublists.\n\n Returns:\n int: The number of sublists containing the target element.\n \"\"\"\n # Initialize a counter for sublists containing the target\n count = 0\n \n # Iterate over each sublist in the list\n for sublist in lst:\n # Check if the target element is in the current sublist\n if target in sublist:\n # If the target element is found, increment the counter\n count += 1\n \n # Return the total count of sublists containing the target\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(list_of_lists, target_element):\n \"\"\"\n Counts the number of sublists in a list of lists that contain a particular element.\n\n Args:\n list_of_lists (list): A list of lists.\n target_element: The element to search for in the sublists.\n\n Returns:\n int: The number of sublists that contain the target element.\n\n \"\"\"\n # Use a generator expression to count the number of sublists containing the target element\n count = sum(1 for sublist in list_of_lists if target_element in sublist)\n\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(sublists, target):\n \"\"\"\n This function counts the number of sublists containing a particular element.\n\n Args:\n sublists (list): A list of sublists.\n target (any): The target element to be searched in the sublists.\n\n Returns:\n int: The number of sublists containing the target element.\n \"\"\"\n return sum(1 for sublist in sublists if target in sublist)\nsublists = [[1, 3], [5, 7], [1, 11], [1, 15, 7]]\ntarget = 1", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, element):\n \"\"\"\n Count the number of sublists containing a particular element.\n\n Args:\n lst (list): A list of sublists.\n element: The element to be searched in the sublists.\n\n Returns:\n int: The number of sublists containing the specified element.\n \"\"\"\n return sum(1 for sublist in lst if element in sublist)", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, element):\n \"\"\"\n Counts the number of sublists containing a particular element.\n\n Args:\n lst (list): A list of lists.\n element: The element to be searched.\n\n Returns:\n int: The number of sublists containing the element.\n \"\"\"\n return sum(1 for sublist in lst if element in sublist)", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(nested_list, target):\n \"\"\"\n Counts the number of sublists containing a particular element.\n\n Args:\n - nested_list (list): A list containing sublists.\n - target: The element to be searched in sublists.\n\n Returns:\n - count (int): The number of sublists containing the target element.\n \"\"\"\n count = 0 # Initialize counter variable\n for sublist in nested_list: # Iterate over each sublist\n if target in sublist: # Check if target is in the current sublist\n count += 1 # Increment the counter\n return count # Return the total count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, target):\n \"\"\"\n Counts the number of sublists in the given list that contain the target element.\n\n Args:\n lst (list): A list of sublists to search through.\n target: The element to search for.\n\n Returns:\n int: The number of sublists that contain the target element.\n \"\"\"\n return sum(1 for sublist in lst if target in sublist)", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, target):\n \"\"\"\n Counts the number of sublists in the given list that contain the target element.\n\n Args:\n lst (list): A list containing sublists.\n target (any): The element to search for.\n\n Returns:\n int: The number of sublists containing the target element.\n \"\"\"\n count = 0\n for sublist in lst:\n if target in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(nested_list, target):\n \"\"\"\n This function counts the number of sublists in a given nested list that contain a particular target element.\n\n Args:\n - nested_list (list): A list containing sublists.\n - target (any): The target element to be searched in sublists.\n\n Returns:\n - count (int): The number of sublists containing the target element.\n \"\"\"\n count = 0 # Initialize count variable\n for sublist in nested_list: # Iterate over sublists in the nested list\n if target in sublist: # Check if target is in the current sublist\n count += 1 # If target is found, increment the count\n return count # Return the total count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(sublists, element):\n \"\"\"\n Counts the number of sublists containing a particular element.\n\n Args:\n sublists (list): A list of sublists.\n element: The element to be searched.\n\n Returns:\n int: The number of sublists containing the element.\n \"\"\"\n return sum(1 for sublist in sublists if element in sublist)", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(list_of_lists, target_element):\n \"\"\"\n Count the number of sublists in a list of lists that contain a particular element.\n \n Args:\n list_of_lists (list): A list containing sublists.\n target_element (any): The element to search for in the sublists.\n \n Returns:\n int: The number of sublists containing the target element.\n \"\"\"\n return sum(1 for sublist in list_of_lists if target_element in sublist)", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, element):\n \"\"\"\n This function counts the number of sublists in a given list that contain a particular element.\n\n Args:\n lst (list): A list of lists.\n element: The element to be searched in the sublists.\n\n Returns:\n int: The number of sublists containing the element.\n \"\"\"\n return sum(1 for sublist in lst if element in sublist)", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, target):\n \"\"\"\n Counts the number of sublists containing a particular element.\n\n Args:\n lst (list): A list containing sublists.\n target (any): The element to be searched in sublists.\n\n Returns:\n int: The number of sublists containing the target element.\n \"\"\"\n count = 0\n for sublist in lst:\n if target in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(list_of_lists, element):\n \"\"\"\n Counts the number of sublists containing a particular element.\n\n Args:\n list_of_lists (list): A list of lists.\n element: The element to be searched in sublists.\n\n Returns:\n int: Number of sublists containing the given element.\n\n Example:\n >>> count_element_in_list([[1, 3], [5, 7], [1, 11], [1, 15, 7]], 1)\n 3\n \"\"\"\n count = sum(1 for sublist in list_of_lists if element in sublist)\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lists, target_element):\n \"\"\"\n Counts the number of sublists containing a particular element.\n\n Args:\n lists (list): A list of lists to search through.\n target_element: The element to search for.\n\n Returns:\n int: The number of sublists containing the target element.\n \"\"\"\n return sum(1 for sublist in lists if target_element in sublist)", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(main_list, element):\n \"\"\"\n Counts the number of sublists containing a particular element.\n\n Args:\n main_list (list): A list of sublists\n element: The element to be searched in the sublists\n\n Returns:\n int: Number of sublists containing the element\n \"\"\"\n return sum(1 for sublist in main_list if element in sublist)", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, element):\n \"\"\"\n This function counts the number of sublists containing a particular element.\n\n Parameters:\n lst (list): The list of sublists to be searched.\n element: The element to be searched for in the sublists.\n\n Returns:\n int: The number of sublists containing the element.\n \"\"\"\n # Use list comprehension to count the number of sublists with the given element\n count = len([sublist for sublist in lst if element in sublist])\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(list_of_lists, target_element):\n \"\"\"\n This function takes in a list of lists and a target element.\n It returns the number of sublists containing the target element.\n\n Args:\n list_of_lists (list): A list containing sublists.\n target_element: The element to search for in the sublists.\n\n Returns:\n int: The number of sublists containing the target element.\n \"\"\"\n return sum(1 for sublist in list_of_lists if target_element in sublist)", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, element):\n \"\"\"\n Counts the number of sublists containing a particular element in a list.\n\n Args:\n lst (list): A list containing sublists.\n element: The element to search for.\n\n Returns:\n int: The number of sublists containing the element.\n \"\"\"\n count = 0\n for sublst in lst:\n if element in sublst:\n count += 1\n return count", "matching_cluster_idx": 4}]}, "Mbpp/428": {"dps": 81.36363636363636, "dps_norm": 55.0, "pass@1": 100.0, "profiled": [{"solution": "def shell_sort(arr):\n \"\"\"\n Sorts the given array by using shell sort.\n\n :param arr: The input array.\n :return: The sorted array.\n \"\"\"\n n = len(arr)\n gap = n // 2\n\n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(array):\n \"\"\"\n Sorts the given array using the Shell sort algorithm.\n\n Args:\n array (list): A list of integers.\n\n Returns:\n list: A sorted list of integers.\n \"\"\"\n n = len(array)\n gap = n // 2\n\n # Loop until the gap is greater than 0\n while gap > 0:\n for i in range(gap, n):\n temp = array[i]\n j = i\n\n # Shift elements to the right until a smaller element is found\n while j >= gap and array[j - gap] > temp:\n array[j] = array[j - gap]\n j -= gap\n\n array[j] = temp\n gap //= 2\n\n return array", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n \"\"\"\n Sorts the given array using Shell Sort algorithm.\n\n Args:\n arr (list): List of elements to be sorted.\n\n Returns:\n list: A sorted list of elements.\n\n Example:\n >>> shell_sort([12, 23, 4, 5, 3, 2, 12, 81, 56, 95])\n [2, 3, 4, 5, 12, 12, 23, 56, 81, 95]\n \"\"\"\n\n # Initialize the gap size\n gap = len(arr) // 2\n\n # Continue the process until gap size becomes 0\n while gap > 0:\n # Perform insertion sort on sub-arrays separated by the gap size\n for i in range(gap, len(arr)):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n\n # Reduce the gap size for the next iteration\n gap //= 2\n\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n \"\"\"\n Sort the given array by using shell sort.\n\n Args:\n arr (list): The input array.\n\n Returns:\n list: The sorted array.\n\n \"\"\"\n n = len(arr)\n gap = n // 2\n\n # Continue the process until the gap is greater than 0\n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n # Shift the elements that are greater than temp to the right\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n \"\"\"\n This function sorts the given array in ascending order using shell sort algorithm.\n\n :param arr: A list of integers to be sorted\n :return: A sorted list of integers\n \"\"\"\n # Start with a big gap, then reduce the gap\n n = len(arr)\n gap = n // 2\n \n while gap > 0:\n # Do a gapped insertion sort for this gap size.\n # The first gap elements a[0..gap-1] are already in gapped order\n # keep adding one more element until the entire array is gap sorted\n for i in range(gap, n):\n temp = arr[i]\n j = i\n # shift earlier gap-sorted elements up until the correct location for a[i] is found\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n # reduce the gap for the next iteration\n gap //= 2\n \n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n \"\"\"\n This function performs a shell sort on the given array.\n\n Args:\n arr (list): A list of integers to be sorted.\n\n Returns:\n list: A sorted list in ascending order.\n \"\"\"\n\n # Start with a big gap, then reduce the gap\n gap = len(arr) // 2\n \n # Continue with the loop until the gap is greater than zero.\n while gap > 0:\n for i in range(gap, len(arr)):\n # Store the current element in a temporary variable\n temp = arr[i]\n \n # Initialize j as the index of the previous gap\n j = i\n \n # As long as j-gap is greater than or equal to zero and the element at index j-gap is greater than the temp, \n # shift that element to right by one gap\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n \n # If j is not equal to i, then arr[j] is not the original element but the shifted one\n # Hence, place the original element (temp) at index j\n if j != i:\n arr[j] = temp\n \n # Reduce the gap by half for the next iteration\n gap //= 2\n \n # Return the sorted array\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n \"\"\"\n Sorts the given array using the shell sort algorithm.\n\n Args:\n arr (list): The list of elements to be sorted.\n\n Returns:\n list: A new sorted list.\n \"\"\"\n # Create a copy of the original array\n arr = arr.copy()\n \n # Start with a big gap, then reduce the gap\n n = len(arr)\n gap = n // 2\n\n while gap > 0:\n # Do a gapped insertion sort for this gap size.\n # The first gap elements a[0..gap-1] are already in gapped order\n # keep adding one more element until the entire array is gap sorted\n for i in range(gap, n):\n # store a[i] in temp and make a hole at position i\n temp = arr[i]\n j = i\n\n # shift earlier gap-sorted elements up until the correct location for a[i] is found\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n\n # put temp (the original a[i]) in its correct location\n arr[j] = temp\n\n # reduce the gap for the next iteration\n gap //= 2\n\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n \"\"\"\n Sorts the given array using the shell sort algorithm.\n\n :param arr: The input array to be sorted\n :return: A new sorted array\n \"\"\"\n # Initialize the gap size\n gap = len(arr) // 2\n \n # Continue the process until the gap size is greater than 0\n while gap > 0:\n # Iterate over the array starting from the gap size to the end\n for i in range(gap, len(arr)):\n # Store the current element to be compared\n temp = arr[i]\n j = i\n \n # Shift elements that are greater than the current element to the right\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n \n # Place the current element at the correct position\n arr[j] = temp\n \n # Reduce the gap size by half\n gap //= 2\n \n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(array):\n \"\"\"\n Sorts an array using the shell sort algorithm.\n\n Args:\n array (list): A list of integers to sort.\n\n Returns:\n list: The sorted list of integers.\n \"\"\"\n # Start with a big gap, then reduce the gap\n gap = len(array) // 2\n\n while gap > 0:\n # Do a gapped insertion sort for this gap size.\n # The first gap elements a[0..gap-1] are already in gapped order\n # keep adding one more element until the entire array is gap sorted\n for i in range(gap, len(array)):\n temp = array[i]\n j = i\n # shift earlier gap-sorted elements up until the correct location for a[i] is found\n while j >= gap and array[j - gap] > temp:\n array[j] = array[j - gap]\n j -= gap\n array[j] = temp\n # reduce the gap for the next iteration\n gap //= 2\n\n return array", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n \"\"\"\n This function sorts the given array using shell sort.\n\n :param arr: The array to be sorted.\n :return: A sorted array.\n \"\"\"\n # Initialize the gap size. We start with a big gap, then reduce the gap\n gap = len(arr) // 2\n\n # We loop until the gap is greater than zero\n while gap > 0:\n # This loop starts from the gap to the end of the array\n for i in range(gap, len(arr)):\n # Store the current element\n temp = arr[i]\n # Initialize the variable that will be used for comparison\n j = i\n # Shift the previous elements to the right until a smaller element is found\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n # Place the element at its correct position\n arr[j] = temp\n # Reduce the gap size by half for the next iteration\n gap //= 2\n\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n \"\"\"\n Sorts the input array using the shell sort algorithm.\n\n Args:\n arr (list): The input array to be sorted.\n\n Returns:\n list: The sorted array.\n \"\"\"\n # Calculate the initial gap size\n gap = len(arr) // 2\n\n while gap > 0:\n # Perform insertion sort on subarrays of size gap\n for i in range(gap, len(arr)):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n # Reduce the gap size for the next iteration\n gap //= 2\n\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n \"\"\"\n Sorts the given array using shell sort algorithm.\n\n Args:\n arr (list): A list of elements to sort.\n\n Returns:\n list: A sorted list.\n \"\"\"\n # Start with a big gap, then reduce the gap\n gap = len(arr) // 2\n\n while gap > 0:\n # Do a gapped insertion sort for this gap size.\n # The first gap elements a[0..gap-1] are already in gapped order\n # keep adding one more element until the entire array is gap sorted\n for i in range(gap, len(arr)):\n temp = arr[i]\n j = i\n # shift earlier gap-sorted elements up until the correct location for a[i] is found\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n # put temp (the original a[i]) in its correct location\n arr[j] = temp\n # reduce the gap for the next iteration\n gap //= 2\n\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n \"\"\"\n Sorts an array using the Shell Sort algorithm.\n\n Args:\n arr (list): A list of elements to sort.\n\n Returns:\n list: A sorted list of elements.\n\n Time Complexity:\n O(n log n)\n\n Space Complexity:\n O(1)\n \"\"\"\n n = len(arr)\n gap = n // 2\n\n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n # Shift elements to the right until we find the correct position for the temp element\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n \"\"\"\n Sorts the given array using the shell sort algorithm.\n\n Args:\n arr (list): The input list to be sorted.\n\n Returns:\n list: A new sorted list in ascending order.\n \"\"\"\n # Create a copy of the original array\n arr_copy = arr.copy()\n \n # Define the initial gap\n gap = len(arr_copy) // 2\n \n # Continue the process until the gap is greater than zero\n while gap > 0:\n # Iterate over the array from the gap to the end\n for i in range(gap, len(arr_copy)):\n # Store the current element\n temp = arr_copy[i]\n \n # Initialize the index\n j = i\n \n # Shift the elements that are greater than the current element to the right\n while j >= gap and arr_copy[j - gap] > temp:\n arr_copy[j] = arr_copy[j - gap]\n j -= gap\n \n # Insert the current element into the correct position\n arr_copy[j] = temp\n \n # Reduce the gap for the next iteration\n gap //= 2\n \n # Return the sorted array\n return arr_copy", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n \"\"\"\n Sorts the given array by using shell sort.\n\n Args:\n arr (list): A list of integers.\n\n Returns:\n list: A sorted list of integers.\n\n Raises:\n ValueError: If the input is not a list of integers.\n \"\"\"\n\n if not isinstance(arr, list) or not all(isinstance(x, int) for x in arr):\n raise ValueError(\"Input should be a list of integers\")\n\n # Start with a big gap, then reduce the gap\n n = len(arr)\n gap = n//2\n\n while gap > 0:\n for i in range(gap, n):\n # Store a in temp and make a hole at position i\n temp = arr[i]\n j = i\n\n # Shift earlier gap-sorted elements up until the correct location for a is found\n while j >= gap and arr[j-gap] > temp:\n arr[j] = arr[j-gap]\n j -= gap\n\n # Put temp (the original a) in its correct location\n arr[j] = temp\n gap //= 2\n\n return arr", "matching_cluster_idx": 3}, {"solution": "def shell_sort(arr):\n \"\"\"\n Sorts an array using shell sort algorithm.\n\n Args:\n arr (list): List of integers.\n\n Returns:\n list: Sorted list of integers.\n \"\"\"\n # Start with a big gap, then reduce the gap\n gap = len(arr) // 2\n \n while gap > 0:\n # Do a gapped insertion sort for this gap size.\n # The first gap elements a[0..gap-1] are already in gapped order\n # keep adding one more element until the entire array is gap sorted\n for i in range(gap, len(arr)):\n # store a[i] in temp and make a hole at position i\n temp = arr[i]\n \n # shift earlier gap-sorted elements up until the correct location for a[i] is found\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n \n # put temp (the original a[i]) in its correct location\n arr[j] = temp\n \n # reduce the gap for the next iteration\n gap //= 2\n \n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n \"\"\"\n This function sorts the given array by using shell sort.\n\n Args:\n arr (list): A list of integers to be sorted.\n\n Returns:\n list: The sorted list of integers.\n \"\"\"\n # Initialize the gap size\n gap = len(arr) // 2\n\n while gap > 0:\n # Iterate through the array with the gap size\n for i in range(gap, len(arr)):\n temp = arr[i]\n j = i\n\n # Compare and shift elements to the right\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n\n # Place the temp element at its correct position\n arr[j] = temp\n\n # Reduce the gap size for the next iteration\n gap //= 2\n\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n \"\"\"\n Sorts the given array by using Shell sort algorithm.\n\n Args:\n arr (list): A list of integers to be sorted.\n\n Returns:\n list: A sorted list of integers.\n \"\"\"\n\n # Initialize the gap size\n gap = len(arr) // 2\n\n # Perform shell sort\n while gap > 0:\n # Iterate over the array with the current gap\n for i in range(gap, len(arr)):\n # Store the current element\n temp = arr[i]\n\n # Initialize the index for comparison\n j = i\n\n # Shift the elements to the right if they are greater than the current element\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n\n # Insert the current element at the correct position\n arr[j] = temp\n\n # Reduce the gap size for the next iteration\n gap //= 2\n\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(array):\n \"\"\"\n Sorts an array using Shell sort algorithm.\n\n Args:\n array (list): A list of integers to be sorted.\n\n Returns:\n list: A new list with elements sorted in ascending order.\n\n Example:\n >>> shell_sort([12, 23, 4, 5, 3, 2, 12, 81, 56, 95])\n [2, 3, 4, 5, 12, 12, 23, 56, 81, 95]\n \"\"\"\n # Start with a big gap, then reduce the gap\n gap = len(array) // 2\n \n while gap > 0:\n # Perform insertion sort with gap\n for i in range(gap, len(array)):\n temp = array[i]\n j = i\n # Shift the elements of array[0..i-1], that are \n # greater than key, to one position ahead of their \n # current position\n while j >= gap and array[j - gap] > temp:\n array[j] = array[j - gap]\n j -= gap\n array[j] = temp\n # Reduce the gap for the next iteration\n gap //= 2\n \n return array", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n \"\"\"\n Sorts the given array using Shell Sort algorithm.\n\n Args:\n arr (list): A list of integers to be sorted.\n\n Returns:\n list: A sorted list of integers.\n \"\"\"\n n = len(arr)\n gap = n // 2\n\n while gap > 0:\n # Perform insertion sort with given gap\n for i in range(gap, n):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n\n return arr", "matching_cluster_idx": 4}]}, "Mbpp/433": {"dps": 57.44680851063829, "dps_norm": 54.0, "pass@1": 97.0, "profiled": [{"solution": "def check_greater(array, num):\n \"\"\"\n Checks if the given number is greater than all elements in the array.\n \n Parameters:\n array (list): List of numbers to compare with.\n num (int): Number to be compared.\n \n Returns:\n bool: True if the number is greater than all elements, False otherwise.\n \"\"\"\n return all(num > element for element in array)", "matching_cluster_idx": 2}, {"solution": "def check_greater(arr, num):\n \"\"\"\n This function checks whether the entered number is greater than the elements of the given array.\n \n Parameters:\n arr (list): The input list of numbers.\n num (int): The input number.\n \n Returns:\n bool: True if the input number is greater than all elements of the array, False otherwise.\n \"\"\"\n return all(num > i for i in arr)", "matching_cluster_idx": 2}, {"solution": "def check_greater(arr, num):\n \"\"\"\n This function checks whether the entered number is greater than all the elements of the given array.\n \n Args:\n arr (list): The input list of numbers.\n num (int): The number to be compared with the list elements.\n \n Returns:\n bool: True if the number is greater than all the elements in the list, False otherwise.\n \"\"\"\n return all(num > elem for elem in arr)", "matching_cluster_idx": 2}, {"solution": "def check_greater(numbers, num):\n \"\"\"\n Checks whether the entered number is greater than all elements of the given array.\n\n Args:\n numbers (list): A list of numbers.\n num (int): The number to check.\n\n Returns:\n bool: True if the number is greater than all elements, False otherwise.\n \"\"\"\n return all(num > n for n in numbers)", "matching_cluster_idx": 2}, {"solution": "def check_greater(array, num):\n \"\"\"\n This function checks whether the entered number is greater than all elements of the given array.\n\n Args:\n array (list): A list of numbers.\n num (int or float): The number to be checked.\n\n Returns:\n bool: True if the number is greater than all elements of the array, False otherwise.\n \"\"\"\n return all(num > element for element in array)", "matching_cluster_idx": 2}, {"solution": "def check_greater(arr, num):\n \"\"\"\n This function checks whether the given number is greater than all elements in the array.\n\n Args:\n arr (list): The input list of numbers.\n num (int): The number to compare with the elements of the list.\n\n Returns:\n bool: True if the number is greater than all elements in the list, False otherwise.\n \"\"\"\n return all(num > i for i in arr)", "matching_cluster_idx": 2}, {"solution": "def check_greater(arr, num):\n \"\"\"\n Checks if the entered number is greater than all elements of the given array.\n\n Args:\n arr (list): The input list of numbers.\n num (int): The number to compare with the array elements.\n\n Returns:\n bool: True if the number is greater than all elements, False otherwise.\n \"\"\"\n return all(num > elem for elem in arr)", "matching_cluster_idx": 2}, {"solution": "def check_greater(arr, num):\n \"\"\"\n This function checks whether the entered number is greater than all elements of the given array.\n\n Args:\n arr (list): A list of numbers.\n num (int or float): The number to compare with array elements.\n\n Returns:\n bool: True if the number is greater than all elements, False otherwise.\n \"\"\"\n return all(num > x for x in arr)", "matching_cluster_idx": 2}, {"solution": "def check_greater(arr, num):\n \"\"\"\n Checks whether the given number is greater than all elements of the given array.\n\n Args:\n arr (list): A list of numbers.\n num (int): The number to compare with the array elements.\n\n Returns:\n bool: True if the number is greater than all elements, False otherwise.\n \"\"\"\n return all(num > i for i in arr)", "matching_cluster_idx": 2}, {"solution": "def check_greater(arr, num):\n \"\"\"\n Check whether the entered number is greater than all elements of the given array.\n \n Args:\n arr (list): The given array.\n num (int or float): The number to be checked.\n \n Returns:\n bool: True if the number is greater than all elements, False otherwise.\n \"\"\"\n return all(num > element for element in arr)", "matching_cluster_idx": 2}, {"solution": "def check_greater(arr, num):\n \"\"\"\n Checks if the entered number is greater than all the elements of the given array.\n\n Args:\n arr (list): The input array.\n num (int): The number to compare with.\n\n Returns:\n bool: True if the number is greater than all elements in the array, False otherwise.\n \"\"\"\n return all(num > x for x in arr)", "matching_cluster_idx": 2}, {"solution": "def check_greater(array, num):\n \"\"\"\n Checks if a given number is greater than all elements in an array.\n\n Args:\n array (list): A list of numbers.\n num (int): The number to check.\n\n Returns:\n bool: True if the number is greater than all elements, False otherwise.\n \"\"\"\n return all(num > element for element in array)", "matching_cluster_idx": 2}, {"solution": "def check_greater(nums, num):\n \"\"\"\n Checks whether the given number is greater than all elements of the given array.\n \n Args:\n nums (list): A list of integers.\n num (int): The number to compare with.\n\n Returns:\n bool: True if num is greater than all elements in nums, False otherwise.\n \"\"\"\n return all(num > i for i in nums)", "matching_cluster_idx": 2}, {"solution": "def check_greater(array, num):\n \"\"\"\n Checks whether the entered number is greater than all elements in the given array.\n\n Args:\n array (list): A list of integers.\n num (int): The number to compare.\n\n Returns:\n bool: True if the number is greater than all elements, False otherwise.\n \"\"\"\n return all(num > element for element in array)", "matching_cluster_idx": 2}, {"solution": "def check_greater(arr, num):\n \"\"\"\n Check if a given number is greater than all elements in a list.\n \n Args:\n arr (list): A list of numbers.\n num (int): The number to compare with the list elements.\n\n Returns:\n bool: True if the number is greater than all elements, False otherwise.\n \"\"\"\n return all(num > elem for elem in arr)", "matching_cluster_idx": 2}, {"solution": "def check_greater(arr, num):\n \"\"\"\n Checks whether the entered number is greater than the elements of the given array.\n\n Args:\n arr (list): A list of numbers to compare with.\n num (int): The number to compare.\n\n Returns:\n bool: True if the number is greater than all elements of the array, False otherwise.\n \"\"\"\n return all(num > i for i in arr)", "matching_cluster_idx": 2}, {"solution": "def check_greater(array, number):\n \"\"\"\n This function checks if a given number is greater than all elements in an array.\n\n Args:\n array (list): A list of numbers to compare against.\n number (int or float): The number to be compared.\n\n Returns:\n bool: True if the number is greater than all elements in the array, False otherwise.\n\n Raises:\n TypeError: If array is not a list or number is not a numeric type.\n \"\"\"\n # Check if array is a list and number is numeric\n if not isinstance(array, list) or not isinstance(number, (int, float)):\n raise TypeError(\"Invalid input types. Array must be a list and number must be a numeric type.\")\n\n # Check if all elements in the array are numeric\n if not all(isinstance(x, (int, float)) for x in array):\n raise TypeError(\"Invalid array values. All elements in the array must be numeric.\")\n\n # Use the built-in all() function with a generator expression to check if the number is greater than all elements\n return all(number > x for x in array)\narray = [1, 2, 3, 4, 5]\nnumber = 4", "matching_cluster_idx": -1}, {"solution": "def check_greater(array, num):\n \"\"\"\n Checks whether the given number is greater than all elements in the array.\n\n Args:\n array (list): The list of numbers to compare against.\n num (int): The number to check.\n\n Returns:\n bool: True if the number is greater than all elements in the array, False otherwise.\n \"\"\"\n return all(num > element for element in array)", "matching_cluster_idx": 2}, {"solution": "def check_greater(numbers, num):\n \"\"\"\n Checks if the entered number is greater than all elements in the given array.\n\n Args:\n numbers (list): A list of numbers.\n num (int): The number to compare.\n\n Returns:\n bool: True if num is greater than all elements in numbers, False otherwise.\n\n \"\"\"\n return all(num > x for x in numbers)", "matching_cluster_idx": 2}, {"solution": "def check_greater(array, number):\n \"\"\"\n Check whether the entered number is greater than all elements of the given array.\n\n Args:\n array (list): A list of numbers.\n number (int or float): A number to compare with array elements.\n\n Returns:\n bool: True if the number is greater than all elements in the array, False otherwise.\n\n Raises:\n TypeError: If the input array is not a list or if the number is not a number.\n \"\"\"\n\n # Check if array is a list\n if not isinstance(array, list):\n raise TypeError(\"Input array must be a list\")\n\n # Check if number is a number\n if not isinstance(number, (int, float)):\n raise TypeError(\"Input number must be an integer or a float\")\n\n # Check if all elements in array are numbers\n if not all(isinstance(element, (int, float)) for element in array):\n raise TypeError(\"All elements in the array must be numbers\")\n\n # Check if the number is greater than all elements in the array\n return all(number > element for element in array)", "matching_cluster_idx": -1}]}, "Mbpp/437": {"dps": 95.58823529411765, "dps_norm": 94.0, "pass@1": 65.0, "profiled": [{"solution": "def remove_odd(s):\n \"\"\"\n Removes odd-indexed characters from a given string.\n\n Args:\n s (str): The input string.\n\n Returns:\n str: The input string with odd-indexed characters removed.\n \"\"\"\n return s[1::2]", "matching_cluster_idx": 4}, {"solution": "def remove_odd(s):\n \"\"\"\n This function removes odd-indexed characters in a string.\n\n Parameters:\n s (str): The input string.\n\n Returns:\n str: A new string with odd-indexed characters removed.\n \"\"\"\n return s[1::2]", "matching_cluster_idx": 4}, {"solution": "def remove_odd(s):\n \"\"\"\n This function removes the odd indexed characters in a string.\n\n Args:\n s (str): The input string.\n\n Returns:\n str: A new string containing only the even indexed characters.\n \"\"\"\n return s[1::2]", "matching_cluster_idx": 4}, {"solution": "def remove_odd(s):\n \"\"\"\n Removes odd indexed characters from a string.\n\n Args:\n s (str): The input string.\n\n Returns:\n str: A string with odd indexed characters removed.\n \"\"\"\n return s[1::2]", "matching_cluster_idx": 4}, {"solution": "def remove_odd(s):\n \"\"\"\n This function removes odd characters in a string.\n \n Parameters:\n s (str): input string.\n \n Returns:\n str: A new string that consists only of characters at even indices.\n \"\"\"\n return s[1::2]", "matching_cluster_idx": 4}, {"solution": "def remove_odd(s):\n \"\"\"\n Removes all characters at odd indices from the input string.\n\n :param s: Input string\n :return: String with characters at odd indices removed\n \"\"\"\n return s[1::2]", "matching_cluster_idx": 4}, {"solution": "def remove_odd(s):\n \"\"\"\n Removes odd characters in a string.\n \n Args:\n s (str): Input string.\n \n Returns:\n str: String without odd characters.\n \"\"\"\n return s[1::2]", "matching_cluster_idx": 4}, {"solution": "def remove_odd(s):\n \"\"\"\n This function removes odd-indexed characters from a string.\n\n Args:\n s (str): The input string.\n\n Returns:\n str: The string with odd-indexed characters removed.\n \"\"\"\n return s[1::2]", "matching_cluster_idx": 4}, {"solution": "def remove_odd(s):\n \"\"\"\n Removes odd-indexed characters from a string (zero-based indexing).\n\n Args:\n s (str): Input string.\n\n Returns:\n str: String with odd-indexed characters removed.\n\n \"\"\"\n return s[1::2]", "matching_cluster_idx": 4}, {"solution": "def remove_odd(s):\n \"\"\"\n Removes odd characters in a string, keeping characters at even indices.\n\n Args:\n s (str): The input string.\n\n Returns:\n str: A string with only characters at even indices.\n \"\"\"\n return s[1::2]", "matching_cluster_idx": 4}, {"solution": "def remove_odd(s):\n \"\"\"\n Removes characters at odd indexes from the given string.\n\n Args:\n s (str): Input string.\n\n Returns:\n str: String with characters at odd indexes removed.\n \"\"\"\n return s[1::2]", "matching_cluster_idx": 4}, {"solution": "def remove_odd(s):\n \"\"\"\n This function removes odd characters in a string.\n\n Args:\n s (str): Input string.\n\n Returns:\n str: The string with odd characters removed.\n \"\"\"\n return s[1::2]", "matching_cluster_idx": 4}, {"solution": "def remove_odd(s):\n \"\"\"\n This function removes odd characters in a string.\n \n Args:\n s (str): Input string\n \n Returns:\n str: String with odd characters removed.\n \"\"\"\n # return a string made from characters at even indexes\n return s[1::2]", "matching_cluster_idx": 3}, {"solution": "def remove_odd(s):\n \"\"\"\n Remove characters at odd indices from the input string.\n\n Parameters:\n s (str): Input string\n\n Returns:\n str: String with characters at odd indices removed\n \"\"\"\n return s[1::2]", "matching_cluster_idx": 3}, {"solution": "def remove_odd(s: str) -> str:\n \"\"\"\n This function removes odd-indexed characters from a given string.\n\n Args:\n s (str): Input string\n\n Returns:\n str: String with only even-indexed characters.\n \"\"\"\n return s[1::2]", "matching_cluster_idx": 3}, {"solution": "def remove_odd(s):\n \"\"\"\n Returns a string with all characters at odd indices removed.\n \n Parameters:\n s (str): input string\n \n Returns:\n str: input string with characters at odd indices removed\n \"\"\"\n return s[1::2]", "matching_cluster_idx": 3}, {"solution": "def remove_odd(s):\n \"\"\"\n Removes odd characters in a string.\n\n Args:\n s (str): The input string.\n\n Returns:\n str: A new string containing only the characters at even indices in the input string.\n \"\"\"\n return s[1::2]", "matching_cluster_idx": 3}, {"solution": "def remove_odd(s):\n \"\"\"\n Removes characters at odd indices (0-based indexing) from the string.\n \n Args:\n s (str): The input string\n \n Returns:\n str: String with characters at odd indices removed\n \"\"\"\n return s[1::2]", "matching_cluster_idx": 4}, {"solution": "def remove_odd(s):\n \"\"\"\n Remove odd indexed characters from a given string.\n \n Parameters:\n s (str): Input string.\n \n Returns:\n str: String with odd indexed characters removed.\n \"\"\"\n return s[1::2]", "matching_cluster_idx": 4}, {"solution": "def remove_odd(s):\n \"\"\"\n Removes characters at odd indices in a string.\n\n Args:\n s (str): Input string.\n\n Returns:\n str: String with characters at odd indices removed.\n \"\"\"\n return s[1::2]", "matching_cluster_idx": 3}]}, "Mbpp/440": {"dps": null, "dps_norm": null, "pass@1": 0.0, "profiled": []}, "Mbpp/446": {"dps": 96.05911330049261, "dps_norm": 60.0, "pass@1": 57.0, "profiled": [{"solution": "def count_Occurrence(tup, lst):\n \"\"\"\n This function counts the occurrence of all elements in a list within a tuple.\n\n Args:\n tup (tuple): The tuple to search in.\n lst (list): The list of elements to search for.\n\n Returns:\n int: The total count of occurrences.\n \"\"\"\n return sum(tup.count(i) for i in lst)", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(input_tuple, elements):\n \"\"\"\n This function counts the occurrence of all elements from the provided list in the given tuple.\n\n Args:\n input_tuple (tuple): The input tuple to search for elements.\n elements (list): A list of elements to search for in the tuple.\n\n Returns:\n int: The total count of all elements found in the tuple.\n \"\"\"\n # Initialize a counter variable\n total_count = 0\n \n # Iterate over each element in the list\n for element in elements:\n # Use the tuple's count method to find the occurrence of the element\n # and add it to the total count\n total_count += input_tuple.count(element)\n \n # Return the total count\n return total_count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tuple_list, elements):\n \"\"\"\n Counts the occurrence of all elements from the given list in a tuple.\n\n Args:\n tuple_list (tuple): The tuple in which the elements will be searched.\n elements (list): The list of elements whose occurrences will be counted.\n\n Returns:\n int: The total count of all elements in the list within the tuple.\n \"\"\"\n return sum(tuple_list.count(element) for element in elements)", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tuple_elements, list_elements):\n \"\"\"\n This function counts the occurrence of all elements of a list in a tuple.\n\n Args:\n tuple_elements (tuple): The tuple to search in.\n list_elements (list): The list of elements to count.\n\n Returns:\n int: The total count of all elements of list in the tuple.\n \"\"\"\n return sum(tuple_elements.count(element) for element in list_elements)", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tup, lst):\n \"\"\"\n Count the occurrence of all elements of a list in a tuple.\n\n Args:\n tup (tuple): The tuple to search in.\n lst (list): The list of elements to search for.\n\n Returns:\n int: The total occurrence of all elements in the list.\n \"\"\"\n return sum(tup.count(i) for i in lst)", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tup, lst):\n \"\"\"\n Count the occurrence of all elements of a list in a tuple.\n\n Args:\n tup (tuple): The tuple to count occurrences in.\n lst (list): The list of elements to count occurrences of.\n\n Returns:\n int: The total number of occurrences of all elements in lst within tup.\n \"\"\"\n return sum(tup.count(element) for element in lst)", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tuple_to_count, list_to_check):\n \"\"\"\n Counts the occurrences of all elements of a list in a tuple.\n\n Args:\n tuple_to_count (tuple): The tuple to count occurrences in.\n list_to_check (list): The list of elements to count occurrences for.\n\n Returns:\n int: The total count of occurrences of all elements in the list in the tuple.\n \"\"\"\n count = 0\n for element in list_to_check:\n count += tuple_to_count.count(element)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tup, lst):\n \"\"\"\n Count the occurrence of all elements of a list in a tuple.\n\n Args:\n tup (tuple): The tuple to search in.\n lst (list): The list of elements to count.\n\n Returns:\n int: The total count of occurrences of all elements in the list.\n \"\"\"\n return sum(tup.count(element) for element in lst)", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tuple_elements, list_elements):\n \"\"\"\n Counts the occurrence of all elements of a list in a tuple.\n\n Args:\n tuple_elements (tuple): The tuple to search in.\n list_elements (list): The elements to count.\n\n Returns:\n int: The total count of occurrences of all elements in the list.\n\n Example:\n >>> count_Occurrence(('a', 'a', 'c', 'b', 'd'), ['a', 'b'])\n 3\n \"\"\"\n # Initialize count variable\n total_count = 0\n \n # Iterate over each element in the list\n for element in list_elements:\n # Count occurrences of the element in the tuple\n total_count += tuple_elements.count(element)\n \n return total_count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tup, lst):\n \"\"\"\n This function counts the occurrence of all elements of a list in a tuple.\n\n Args:\n tup (tuple): The tuple to be searched.\n lst (list): The list containing elements to be searched for.\n\n Returns:\n int: The total occurrence of all elements of the list in the tuple.\n \"\"\"\n return sum(tup.count(element) for element in lst)", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tuple_input, list_input):\n \"\"\"\n Count the occurrence of all elements of list in a tuple.\n \n Args:\n tuple_input (tuple): The tuple to search in.\n list_input (list): The list of elements to search for.\n \n Returns:\n int: The total count of occurrences.\n \"\"\"\n count = 0\n for element in list_input:\n count += tuple_input.count(element)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tup, lst):\n \"\"\"\n Count the occurrence of all elements of a list in a tuple.\n \n Args:\n tup (tuple): The tuple to search in.\n lst (list): The list of elements to search for.\n \n Returns:\n int: The total count of occurrences of all elements in the list.\n \"\"\"\n # Initialize count to 0\n count = 0\n # For each element in the list\n for element in lst:\n # Add the number of occurrences of the element in the tuple to the count\n count += tup.count(element)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tup, lst):\n \"\"\"\n Count the occurrence of all elements of list in a tuple.\n \n Parameters:\n tup (tuple): The input tuple to search in.\n lst (list): The list of elements to count occurrences of.\n \n Returns:\n int: The total count of occurrences of all elements of lst in tup.\n \"\"\"\n return sum(tup.count(element) for element in lst)", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tup, lst):\n \"\"\"\n Counts the occurrence of all elements of a list in a tuple.\n \n Parameters:\n tup (tuple): Tuple containing elements to be searched.\n lst (list): List containing elements to search for.\n \n Returns:\n int: The total count of occurrences of all elements in the list.\n \"\"\"\n return sum(tup.count(element) for element in lst)", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tup, lst):\n \"\"\"\n This function counts the occurrence of all elements of list in a tuple.\n\n Args:\n tup (tuple): The tuple to search in.\n lst (list): The list of elements to search for.\n\n Returns:\n int: The total count of occurrences of elements from the list in the tuple.\n \"\"\"\n return sum(tup.count(element) for element in lst)", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tuple_input, list_input):\n \"\"\"\n This function counts the occurrence of all elements in the list within the tuple.\n\n Args:\n tuple_input (tuple): The tuple to search in.\n list_input (list): The list of elements to count occurrences for.\n\n Returns:\n int: The total count of occurrences.\n \"\"\"\n count = 0\n for element in list_input:\n count += tuple_input.count(element)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tuple_elements, list_elements):\n \"\"\"\n This function counts the occurrence of all elements of a list in a tuple.\n\n Args:\n tuple_elements (tuple): The tuple to search in.\n list_elements (list): The list of elements to search for.\n\n Returns:\n int: The total count of occurrences of all elements in the list.\n\n Raises:\n TypeError: If tuple_elements is not a tuple or list_elements is not a list.\n \"\"\"\n\n # Check input type\n if not isinstance(tuple_elements, tuple) or not isinstance(list_elements, list):\n raise TypeError(\"Input must be a tuple and a list.\")\n\n # Initialize a variable to keep track of total count\n total_count = 0\n \n # Iterate over each element in the list\n for element in list_elements:\n # Count the occurrence of the current element in the tuple\n total_count += tuple_elements.count(element)\n \n # Return the total count\n return total_count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tup, lst):\n \"\"\"\n Counts the occurrence of all elements of a list in a tuple.\n\n Args:\n tup (tuple): A tuple containing elements.\n lst (list): A list containing elements.\n\n Returns:\n int: The count of elements from the list found in the tuple.\n \"\"\"\n return sum(tup.count(element) for element in lst)", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(input_tuple, input_list):\n \"\"\"\n Counts the occurrence of all elements of a list in a tuple.\n\n Args:\n input_tuple (tuple): Tuple containing elements to be searched.\n input_list (list): List containing elements to search for.\n\n Returns:\n int: Total occurrence count of all elements in the list within the tuple.\n\n Example:\n >>> count_Occurrence(('a', 'a', 'c', 'b', 'd'), ['a', 'b'])\n 3\n \"\"\"\n return sum(input_tuple.count(element) for element in input_list)", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tup, lst):\n \"\"\"\n Counts the occurrence of all elements of a list in a tuple.\n\n Args:\n tup (tuple): The tuple to search in.\n lst (list): The list of elements to search for.\n\n Returns:\n int: The total count of occurrences.\n\n Example:\n >>> count_Occurrence(('a', 'a', 'c', 'b', 'd'), ['a', 'b'])\n 3\n \"\"\"\n return sum(tup.count(element) for element in lst)", "matching_cluster_idx": 2}]}, "Mbpp/451": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 99.0, "profiled": [{"solution": "def remove_whitespaces(s):\n \"\"\"\n This function removes all whitespaces from the given string.\n\n Args:\n s (str): The input string.\n\n Returns:\n str: The string without any whitespaces.\n\n Examples:\n >>> remove_whitespaces(' Google Flutter ')\n 'GoogleFlutter'\n \"\"\"\n return s.replace(' ', '')", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string):\n \"\"\"\n Removes all whitespaces from a given string.\n\n Args:\n input_string (str): The string to remove whitespaces from.\n\n Returns:\n str: The input string without any whitespaces.\n \"\"\"\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string):\n \"\"\"\n This function takes a string as an input and returns a string without any whitespaces.\n \n Args:\n input_string (str): The string from which whitespaces are to be removed.\n\n Returns:\n str: The string without any whitespaces.\n \"\"\"\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string):\n \"\"\"\n Removes all whitespaces from the given string.\n\n Args:\n input_string (str): Input string from which to remove whitespaces.\n\n Returns:\n str: The input string with all whitespaces removed.\n \"\"\"\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(s):\n \"\"\"\n Removes all whitespaces from the given string.\n\n Args:\n s (str): Input string to be processed.\n\n Returns:\n str: String without any whitespaces.\n \"\"\"\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(s):\n \"\"\"\n Removes all whitespaces from the given string.\n\n Args:\n s (str): The input string.\n\n Returns:\n str: The string with all whitespaces removed.\n\n Example:\n >>> remove_whitespaces(' Google Flutter ')\n 'GoogleFlutter'\n \"\"\"\n return s.replace(' ', '')", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string):\n \"\"\"\n Removes all whitespaces from a given string.\n \n Args:\n input_string (str): The string from which to remove whitespaces.\n \n Returns:\n str: The input string with all whitespaces removed.\n \"\"\"\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string):\n \"\"\"\n This function removes all whitespaces from the given string.\n \n Args:\n input_string (str): The string from which whitespaces need to be removed.\n\n Returns:\n str: The string with all whitespaces removed.\n\n \"\"\"\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(s):\n \"\"\"\n Remove all whitespaces from the given string.\n\n Args:\n s (str): The input string.\n\n Returns:\n str: The string with all whitespaces removed.\n \"\"\"\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string):\n \"\"\"\n This function removes all whitespaces from a given string.\n\n Args:\n input_string (str): The input string to be processed.\n\n Returns:\n str: A string with all whitespaces removed.\n\n \"\"\"\n # Using the replace() method to replace all whitespaces with an empty string\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(s):\n \"\"\"\n Removes all whitespaces from the given string.\n\n Args:\n s (str): Input string.\n\n Returns:\n str: String without whitespaces.\n \"\"\"\n return s.replace(' ', '')", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string: str) -> str:\n \"\"\"\n This function takes a string as input, removes all whitespaces from it and returns the result.\n \n :param input_string: Input string that may contain whitespaces\n :return: The input string without whitespaces\n \"\"\"\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(s):\n \"\"\"\n Removes all whitespaces from the given string.\n\n Args:\n s (str): Input string\n\n Returns:\n str: String with all whitespaces removed\n \"\"\"\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(s):\n \"\"\"\n Removes all whitespaces from a given string.\n\n Args:\n s (str): The input string.\n\n Returns:\n str: The input string without any whitespaces.\n\n Example:\n >>> remove_whitespaces(' Google Flutter ')\n 'GoogleFlutter'\n \"\"\"\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string):\n \"\"\"\n Removes all whitespaces from the given string.\n\n Args:\n input_string (str): Input string containing whitespaces.\n\n Returns:\n str: String with all whitespaces removed.\n\n \"\"\"\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_str):\n \"\"\"\n Removes all whitespaces from the input string.\n\n Args:\n input_str (str): The string from which to remove whitespaces.\n\n Returns:\n str: The input string with all whitespaces removed.\n \"\"\"\n return input_str.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string: str) -> str:\n \"\"\"\n This function removes all whitespace characters from the input string.\n \n Args:\n input_string (str): Input string that may contain whitespace characters.\n \n Returns:\n str: Input string with all whitespace characters removed.\n \"\"\"\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string):\n \"\"\"\n Removes all whitespaces from the given string.\n\n Args:\n input_string (str): The input string from which whitespaces are to be removed.\n\n Returns:\n str: The string after removing all whitespaces.\n\n Example:\n >>> remove_whitespaces(' Google Flutter ')\n 'GoogleFlutter'\n \"\"\"\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string):\n \"\"\"\n Removes all whitespaces from the given string.\n\n Args:\n input_string (str): The input string.\n\n Returns:\n str: The string with all whitespaces removed.\n \"\"\"\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string):\n \"\"\"\n This function removes all whitespaces from the given string.\n\n Args:\n input_string (str): The input string that needs to be processed.\n\n Returns:\n str: The string with all whitespaces removed.\n \"\"\"\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}]}, "Mbpp/456": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def reverse_string_list(strings):\n \"\"\"\n This function takes a list of strings and returns a new list with each string reversed.\n\n Args:\n strings (list): A list of string values.\n\n Returns:\n list: A new list with each string reversed.\n \"\"\"\n # Use a list comprehension to create a new list with each string reversed\n return [s[::-1] for s in strings]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n \"\"\"\n Reverses each string in a given list of string values.\n \n Args:\n string_list (list): A list of strings to be reversed.\n \n Returns:\n list: A new list with each string in the original list reversed.\n \"\"\"\n # Initialize an empty list to store reversed strings\n reversed_list = []\n \n # Iterate over each string in the input list\n for string in string_list:\n # Reverse the string using slicing and append to the new list\n reversed_list.append(string[::-1])\n \n # Return the list with reversed strings\n return reversed_list", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n \"\"\"\n Reverses each string in a given list of string values.\n \n Args:\n string_list (list): A list of strings.\n \n Returns:\n list: A list of strings where each string is reversed.\n \"\"\"\n # Check if input is a list\n if not isinstance(string_list, list):\n raise TypeError(\"Input must be a list\")\n \n # Check if all elements in the list are strings\n if not all(isinstance(s, str) for s in string_list):\n raise TypeError(\"All elements in the list must be strings\")\n \n # Use list comprehension to reverse each string in the list\n return [s[::-1] for s in string_list]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(strings):\n \"\"\"\n Reverses each string in a given list of strings.\n\n Args:\n strings (list): A list of string values.\n\n Returns:\n list: A list with each string reversed.\n \"\"\"\n return [s[::-1] for s in strings]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(input_list):\n \"\"\"\n Reverses each string in the input list.\n \n Args:\n input_list (list): A list of string values.\n \n Returns:\n list: A new list with each string reversed.\n \"\"\"\n # Check if all elements in the list are strings\n if not all(isinstance(string, str) for string in input_list):\n raise TypeError(\"All elements in the input list must be strings.\")\n \n # Reverse each string in the list\n reversed_list = [string[::-1] for string in input_list]\n \n return reversed_list", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(strings):\n \"\"\"\n Reverses each string in a given list of string values.\n\n Args:\n strings (list): A list of string values.\n\n Returns:\n list: A list of reversed string values.\n\n Examples:\n >>> reverse_string_list(['Red', 'Green', 'Blue', 'White', 'Black'])\n ['deR', 'neerG', 'eulB', 'etihW', 'kcalB']\n \"\"\"\n return [s[::-1] for s in strings]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(input_list):\n \"\"\"\n This function takes a list of string values and returns a new list\n where each string in the original list is reversed.\n\n Args:\n input_list (list): A list of string values.\n\n Returns:\n list: A new list with each string from the input list reversed.\n \"\"\"\n # Initialize an empty list to store the reversed strings\n reversed_list = []\n\n # Iterate over each string in the input list\n for string in input_list:\n # Reverse the current string and append it to the result list\n reversed_list.append(string[::-1])\n\n # Return the list with the reversed strings\n return reversed_list", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(strings):\n \"\"\"\n This function takes a list of strings as input and returns a new list \n where each string is reversed.\n\n Args:\n strings (list): A list of strings.\n\n Returns:\n list: A list of reversed strings.\n \"\"\"\n return [s[::-1] for s in strings]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(strings):\n \"\"\"\n This function takes a list of strings and returns a new list\n where each string in the original list is reversed.\n\n Args:\n strings (list): A list of string values.\n\n Returns:\n list: A list of reversed strings.\n \"\"\"\n # Use list comprehension to reverse each string in the list\n return [string[::-1] for string in strings]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n \"\"\"\n Reverses each string in a given list of string values.\n \n Parameters:\n string_list (list): A list of string values.\n \n Returns:\n list: A list of string values where each string is reversed.\n \"\"\"\n return [s[::-1] for s in string_list]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(strings):\n \"\"\"\n This function takes a list of strings as input, \n and returns a new list with each string reversed.\n\n Args:\n strings (list): A list of string values.\n\n Returns:\n list: A list of reversed string values.\n \"\"\"\n # Use list comprehension and slicing to reverse each string\n return [string[::-1] for string in strings]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(strings):\n \"\"\"\n Reverses each string in a given list of string values.\n\n Args:\n strings (list): A list of string values.\n\n Returns:\n list: The input list with each string reversed.\n \"\"\"\n return [s[::-1] for s in strings]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(strings):\n \"\"\"\n This function takes a list of strings and returns a new list \n with each string reversed.\n\n Args:\n strings (list): A list of string values.\n\n Returns:\n list: A list of strings with each string reversed.\n \"\"\"\n return [s[::-1] for s in strings]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(strings):\n \"\"\"\n Reverses each string in a given list of string values.\n\n Args:\n strings (list): A list of string values.\n\n Returns:\n list: A list of reversed string values.\n \"\"\"\n return [string[::-1] for string in strings]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n \"\"\"\n Reverses each string in a given list of string values.\n\n Args:\n string_list (list): A list of string values.\n\n Returns:\n list: A list of reversed string values.\n\n \"\"\"\n return [s[::-1] for s in string_list]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n \"\"\"\n Reverses each string in a given list of strings.\n\n Args:\n string_list (list): A list of strings.\n\n Returns:\n list: A list with each string reversed.\n\n Raises:\n TypeError: If input is not a list.\n TypeError: If any element in the list is not a string.\n\n Examples:\n >>> reverse_string_list(['Red', 'Green', 'Blue', 'White', 'Black'])\n ['deR', 'neerG', 'eulB', 'etihW', 'kcalB']\n \"\"\"\n\n if not isinstance(string_list, list):\n raise TypeError(\"Input must be a list\")\n if not all(isinstance(s, str) for s in string_list):\n raise TypeError(\"All elements in the list must be strings\")\n\n return [s[::-1] for s in string_list]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(input_list):\n \"\"\"\n Reverses each string in the input list of string values.\n\n Args:\n input_list (list): List of strings to be reversed.\n\n Returns:\n list: List of strings where each string is reversed.\n \"\"\"\n return [word[::-1] for word in input_list]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n \"\"\"\n Reverses each string in a given list of string values.\n\n Args:\n string_list (list): A list of string values.\n\n Returns:\n list: A list with each string reversed.\n \"\"\"\n return [s[::-1] for s in string_list]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(strings):\n \"\"\"\n Reverses each string in a given list of string values.\n\n Args:\n strings (list): A list of string values.\n\n Returns:\n list: A list of reversed string values.\n\n Examples:\n >>> reverse_string_list(['Red', 'Green', 'Blue', 'White', 'Black'])\n ['deR', 'neerG', 'eulB', 'etiW', 'kcalB']\n \"\"\"\n return [s[::-1] for s in strings]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(input_list):\n \"\"\"\n This function takes a list of string values as input and returns a list with each string reversed.\n\n Args:\n input_list (list): A list of strings.\n\n Returns:\n list: A list of strings where each string is reversed.\n \"\"\"\n # Check if the input is a list\n if not isinstance(input_list, list):\n raise TypeError(\"Input must be a list\")\n\n # Initialize an empty list to store the reversed strings\n reversed_list = []\n\n # Iterate over each string in the input list\n for string in input_list:\n # Check if the current item is a string\n if not isinstance(string, str):\n raise TypeError(\"All elements in the list must be strings\")\n\n # Reverse the string using slicing and append to the reversed list\n reversed_list.append(string[::-1])\n\n # Return the list with all strings reversed\n return reversed_list", "matching_cluster_idx": 4}]}, "Mbpp/460": {"dps": 43.41346153846153, "dps_norm": 74.0, "pass@1": 45.0, "profiled": [{"solution": "def Extract(sublists):\n \"\"\"\n This function takes a list of lists and returns a list of first elements from each sublist.\n\n Args:\n sublists (list): A list containing sublists.\n\n Returns:\n list: A list of first elements from each sublist.\n \"\"\"\n return [sublist[0] for sublist in sublists if sublist]", "matching_cluster_idx": 3}, {"solution": "def Extract(sublists):\n \"\"\"\n Extract the first element of each sublist.\n\n Args:\n sublists (list): A list of sublists.\n\n Returns:\n list: A list containing the first element of each sublist.\n\n Example:\n >>> Extract([[1, 2], [3, 4, 5], [6, 7, 8, 9]])\n [1, 3, 6]\n \"\"\"\n return [sublist[0] for sublist in sublists if sublist]", "matching_cluster_idx": 3}, {"solution": "def Extract(lst):\n \"\"\"\n This function takes a list of lists (sublists) as input and returns a list\n containing the first element of each sublist.\n\n Args:\n lst (list): A list of lists.\n\n Returns:\n list: A list containing the first element of each sublist.\n \"\"\"\n return [sublist[0] for sublist in lst if sublist] # avoid index error with if sublist", "matching_cluster_idx": 3}, {"solution": "def Extract(sublists):\n \"\"\"\n This function takes a list of sublists and returns a new list containing \n the first element from each sublist.\n\n Args:\n sublists (list): A list of lists.\n\n Returns:\n list: A list of first elements from the sublists.\n \"\"\"\n # Use list comprehension to create a new list with the first element from each sublist\n return [sublist[0] for sublist in sublists if sublist]", "matching_cluster_idx": 3}, {"solution": "def Extract(sublists):\n \"\"\"\n This function takes a list of lists and returns a new list containing the first element of each sublist.\n\n Args:\n sublists (list): A list containing sublists.\n\n Returns:\n list: A list containing the first element of each sublist.\n \"\"\"\n return [sublist[0] for sublist in sublists if sublist]", "matching_cluster_idx": 3}, {"solution": "def Extract(sublists):\n \"\"\"\n This function takes a list of sublists and returns a new list with the first element of each sublist.\n\n Args:\n sublists (list): A list containing sublists.\n\n Returns:\n list: A list containing the first element of each sublist.\n \"\"\"\n return [sublist[0] for sublist in sublists]", "matching_cluster_idx": 3}, {"solution": "def Extract(sublists):\n \"\"\"\n Extracts the first element of each sublist.\n\n Args:\n sublists (list): A list of sublists\n\n Returns:\n list: A list of first elements of sublists\n \"\"\"\n return [sublist[0] for sublist in sublists]", "matching_cluster_idx": 3}, {"solution": "def Extract(lst):\n \"\"\"\n This function takes a list of sublists as input and returns a new list containing the first element from each sublist.\n \n Parameters:\n lst (list): A list of sublists\n \n Returns:\n list: A list containing the first element from each sublist\n \"\"\"\n return [sublist[0] for sublist in lst]", "matching_cluster_idx": 3}, {"solution": "def Extract(sublists):\n \"\"\"\n This function takes a list of sublists as input and returns a new list \n containing the first element of each sublist.\n\n Args:\n sublists (list): A list of sublists.\n\n Returns:\n list: A new list containing the first element of each sublist.\n \"\"\"\n return [sublist[0] for sublist in sublists if sublist]", "matching_cluster_idx": 3}, {"solution": "def Extract(sublists):\n \"\"\"\n Extract the first element of each sublist.\n \n Args:\n sublists (list of lists): Input list containing sublists.\n \n Returns:\n list: A list containing the first element of each sublist.\n \"\"\"\n return [sublist[0] for sublist in sublists]", "matching_cluster_idx": 3}, {"solution": "def Extract(list_of_lists):\n \"\"\"\n Returns a list containing the first element of each sublist.\n\n Args:\n list_of_lists (list): A list containing sublists.\n\n Returns:\n list: A list of the first elements of each sublist.\n\n Example:\n >>> Extract([[1, 2], [3, 4, 5], [6, 7, 8, 9]])\n [1, 3, 6]\n \"\"\"\n return [sublist[0] for sublist in list_of_lists]", "matching_cluster_idx": 3}, {"solution": "def Extract(sublists):\n \"\"\"\n Extract the first element of each sublist.\n\n Args:\n sublists (list): A list of lists.\n\n Returns:\n list: A list of the first element of each sublist.\n\n Example:\n >>> Extract([[1, 2], [3, 4, 5], [6, 7, 8, 9]])\n [1, 3, 6]\n \"\"\"\n return [sublist[0] for sublist in sublists]", "matching_cluster_idx": 3}, {"solution": "def Extract(lst):\n \"\"\"\n Returns the first element of each sublist in the given list.\n\n Args:\n lst (list): A list of lists.\n\n Returns:\n list: A list of the first elements of each sublist.\n\n Raises:\n TypeError: If the input is not a list.\n IndexError: If the input list or any sublist is empty.\n\n Examples:\n >>> Extract([[1, 2], [3, 4, 5], [6, 7, 8, 9]])\n [1, 3, 6]\n \"\"\"\n if not isinstance(lst, list):\n raise TypeError(\"Input must be a list.\")\n\n if not all(isinstance(i, list) for i in lst):\n raise TypeError(\"All elements in the input list must be lists.\")\n\n if any(len(sublist) == 0 for sublist in lst):\n raise IndexError(\"Input list or any sublist cannot be empty.\")\n\n return [sublist[0] for sublist in lst]", "matching_cluster_idx": -1}, {"solution": "def Extract(lst):\n \"\"\"\n Returns a list containing the first element of each sublist.\n\n Args:\n lst (list): A list containing sublists.\n\n Returns:\n list: A list with the first element from each sublist.\n\n Raises:\n IndexError: If any of the sublists are empty.\n \"\"\"\n return [sublist[0] for sublist in lst]", "matching_cluster_idx": 3}, {"solution": "def Extract(list_of_lists):\n \"\"\"\n Extracts the first element from each sublist in a given list of lists.\n \n Args:\n list_of_lists (list): A list containing sublists.\n \n Returns:\n list: A list of first elements from each sublist.\n \"\"\"\n return [sublist[0] for sublist in list_of_lists if sublist]", "matching_cluster_idx": 3}, {"solution": "def Extract(list_of_lists):\n \"\"\"\n This function takes a list of lists as input and returns a list with the first element of each sublist.\n\n Args:\n list_of_lists (list): A list of lists.\n\n Returns:\n list: A list with the first element of each sublist.\n \"\"\"\n return [sublist[0] for sublist in list_of_lists]", "matching_cluster_idx": 3}, {"solution": "def Extract(sublists):\n \"\"\"\n This function takes a list of lists (sublists) as input and returns a new list containing the first element of each sublist.\n \n Args:\n sublists (list): A list of lists\n \n Returns:\n list: A new list containing the first element of each sublist\n \"\"\"\n # Check if the input is a list\n if not isinstance(sublists, list):\n raise ValueError(\"Input must be a list of lists\")\n \n # Use a list comprehension to extract the first element of each sublist\n # The expression 'sublist[0]' gets the first element of each sublist\n # The 'for sublist in sublists' part iterates over each sublist in the input list\n return [sublist[0] for sublist in sublists if isinstance(sublist, list) and len(sublist) > 0]", "matching_cluster_idx": 1}, {"solution": "def Extract(lst):\n \"\"\"\n This function takes a list of lists as input and returns a new list containing the first element of each sublist.\n\n Args:\n lst (list): A list of lists.\n\n Returns:\n list: A new list containing the first element of each sublist.\n\n Raises:\n IndexError: If any sublist in the input list is empty.\n \"\"\"\n return [sublist[0] for sublist in lst]", "matching_cluster_idx": 3}, {"solution": "def Extract(sublists):\n \"\"\"\n This function takes a list of lists (sublists) as input and returns a new list containing \n the first element of each sublist.\n\n Args:\n sublists (list): A list containing lists as elements.\n\n Returns:\n list: A list of the first elements of the input sublists.\n \"\"\"\n # Use list comprehension to create a new list containing the first element of each sublist\n return [sublist[0] for sublist in sublists]", "matching_cluster_idx": 3}, {"solution": "def Extract(lst):\n \"\"\"\n Returns a list containing the first element of each sublist.\n\n Args:\n lst (list): A list containing sublists.\n\n Returns:\n list: A list containing the first element of each sublist.\n \"\"\"\n return [sublist[0] for sublist in lst if sublist]", "matching_cluster_idx": 3}]}, "Mbpp/474": {"dps": 97.02439024390245, "dps_norm": 99.28571428571429, "pass@1": 98.0, "profiled": [{"solution": "def replace_char(string, old, new):\n \"\"\"\n Replaces occurrences of old character with new character in a given string.\n\n Args:\n string (str): Input string.\n old (str): Character to replace.\n new (str): Character to replace with.\n\n Returns:\n str: New string with replaced characters.\n \"\"\"\n return string.replace(old, new)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, old, new):\n \"\"\"\n Replaces all occurrences of 'old' with 'new' in the string 's'.\n\n Args:\n s (str): The string where the replacement will occur.\n old (str): The character(s) to replace.\n new (str): The character(s) to replace with.\n\n Returns:\n str: The modified string with replacements made.\n \"\"\"\n return s.replace(old, new)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, char_to_replace, replacement_char):\n \"\"\"\n Replaces all occurrences of char_to_replace in the string s with replacement_char.\n\n Args:\n s (str): The input string.\n char_to_replace (str): The character to be replaced.\n replacement_char (str): The character to replace with.\n\n Returns:\n str: A new string where all occurrences of char_to_replace have been replaced.\n \"\"\"\n return s.replace(char_to_replace, replacement_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, char_to_replace, replacement_char):\n \"\"\"\n Replaces all occurrences of a character in a string.\n\n Args:\n s (str): The original string.\n char_to_replace (str): The character to be replaced.\n replacement_char (str): The character to replace with.\n\n Returns:\n str: The modified string with replaced characters.\n \"\"\"\n return s.replace(char_to_replace, replacement_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(string, char_to_replace, replacement_char):\n \"\"\"\n Replaces occurrences of a character in a given string.\n\n Args:\n string (str): The input string.\n char_to_replace (str): The character to be replaced.\n replacement_char (str): The replacement character.\n\n Returns:\n str: A new string where all occurrences of char_to_replace are replaced with replacement_char.\n\n Raises:\n TypeError: If any of the inputs are not strings.\n \"\"\"\n if not all(isinstance(i, str) for i in [string, char_to_replace, replacement_char]):\n raise TypeError(\"All inputs must be strings.\")\n\n return string.replace(char_to_replace, replacement_char)", "matching_cluster_idx": 5}, {"solution": "def replace_char(s, old, new):\n \"\"\"\n Replace characters in a string.\n\n Parameters:\n s (str): The original string.\n old (str): The character to replace.\n new (str): The new character.\n\n Returns:\n str: The modified string.\n \"\"\"\n return s.replace(old, new)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, old_char, new_char):\n \"\"\"\n Replaces all occurrences of old_char in string s with new_char.\n \n Args:\n s (str): The original string.\n old_char (str): The character to be replaced.\n new_char (str): The new character.\n \n Returns:\n str: The modified string with old_char replaced by new_char.\n \"\"\"\n return s.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, char_to_replace, replacement_char):\n \"\"\"\n Replace all occurrences of a character in a string.\n\n Args:\n s (str): The input string.\n char_to_replace (str): The character to replace.\n replacement_char (str): The character to replace with.\n\n Returns:\n str: The modified string.\n \"\"\"\n return s.replace(char_to_replace, replacement_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, char_to_replace, replacement):\n \"\"\"\n Replace all occurrences of a character in a string.\n\n Args:\n s (str): The string where characters need to be replaced.\n char_to_replace (str): The character to replace.\n replacement (str): The replacement character.\n\n Returns:\n str: The modified string with replaced characters.\n \"\"\"\n return s.replace(char_to_replace, replacement)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, old_char, new_char):\n \"\"\"\n Replaces all occurrences of old_char with new_char in the given string.\n \n Args:\n s (str): The string where the character will be replaced.\n old_char (str): The character to be replaced.\n new_char (str): The character that will replace the old_char.\n\n Returns:\n str: The modified string with old_char replaced by new_char.\n \"\"\"\n return s.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, old, new):\n \"\"\"\n Replaces all occurrences of 'old' with 'new' in string 's'.\n\n Args:\n s (str): The input string.\n old (str): The character to replace.\n new (str): The character to replace 'old' with.\n\n Returns:\n str: The modified string.\n \"\"\"\n return s.replace(old, new)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, char_to_replace, replacement_char):\n \"\"\"\n Replaces all occurrences of a specified character with another character in a string.\n \n Parameters:\n s (str): The input string.\n char_to_replace (str): The character to replace.\n replacement_char (str): The replacement character.\n \n Returns:\n str: The modified string with replaced characters.\n \"\"\"\n return s.replace(char_to_replace, replacement_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, target, replacement):\n \"\"\"\n Replaces all occurrences of a target character in a string with a specified replacement character.\n\n Args:\n s (str): The input string.\n target (str): The character to be replaced.\n replacement (str): The replacement character.\n\n Returns:\n str: The modified string with the target character replaced.\n \"\"\"\n return s.replace(target, replacement)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, old, new):\n \"\"\"\n Replace old character(s) with new character(s) in string s.\n\n Args:\n s (str): The original string.\n old (str): The old character(s) to be replaced.\n new (str): The new character(s) to replace with.\n\n Returns:\n str: The new string with old character(s) replaced.\n\n Example:\n >>> replace_char(\"polygon\", 'y', 'l')\n 'pollgon'\n \"\"\"\n return s.replace(old, new)", "matching_cluster_idx": 6}, {"solution": "def replace_char(string, char_to_replace, replacement):\n \"\"\"\n Replaces all occurrences of a character in a string with another character.\n\n Args:\n string (str): The original string.\n char_to_replace (str): The character to replace.\n replacement (str): The replacement character.\n\n Returns:\n str: A new string with the replaced character.\n\n \"\"\"\n return string.replace(char_to_replace, replacement)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, old, new):\n \"\"\"\n Replaces all occurrences of a character in a string.\n\n Args:\n s (str): The input string.\n old (str): The character to be replaced.\n new (str): The character to replace with.\n\n Returns:\n str: The string with all occurrences of the old character replaced.\n \"\"\"\n return s.replace(old, new)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, orig, new):\n \"\"\"\n Replaces all occurrences of the character 'orig' with 'new' in the string 's'.\n \n Parameters:\n s (str): The original string.\n orig (str): The original character to be replaced.\n new (str): The new character to replace with.\n \n Returns:\n str: A new string with all occurrences of 'orig' replaced by 'new'.\n \"\"\"\n return s.replace(orig, new)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, old, new):\n \"\"\"\n Replace all occurrences of 'old' with 'new' in string 's'.\n\n Args:\n s (str): Original string.\n old (str): Characters to be replaced.\n new (str): Characters to replace with.\n\n Returns:\n str: String 's' with 'old' replaced by 'new'.\n \"\"\"\n return s.replace(old, new)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, char_to_replace, replacement):\n \"\"\"\n Replaces a character in a string.\n\n Args:\n s (str): The input string.\n char_to_replace (str): The character to be replaced.\n replacement (str): The replacement character.\n\n Returns:\n str: The modified string with the character replaced.\n \"\"\"\n return s.replace(char_to_replace, replacement)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, char_to_replace, replacement_char):\n \"\"\"\n Replace occurrences of char_to_replace with replacement_char in string s.\n\n Args:\n s (str): The input string.\n char_to_replace (str): The character to be replaced.\n replacement_char (str): The replacement character.\n\n Returns:\n str: The modified string with char_to_replace replaced by replacement_char.\n \"\"\"\n return s.replace(char_to_replace, replacement_char)", "matching_cluster_idx": 6}]}, "Mbpp/476": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def big_sum(array):\n \"\"\"\n This function calculates the sum of the largest and smallest value in a given array.\n\n Args:\n array (list): A list of integers.\n\n Returns:\n int: The sum of the largest and smallest values in the array.\n \"\"\"\n if len(array) == 0:\n raise ValueError(\"Array cannot be empty\")\n\n return max(array) + min(array)", "matching_cluster_idx": 5}, {"solution": "def big_sum(array):\n \"\"\"\n This function calculates the sum of the largest and smallest value in a given array.\n\n Args:\n array (list): A list of numbers.\n\n Returns:\n int: The sum of the largest and smallest numbers in the array.\n \"\"\"\n return max(array) + min(array)", "matching_cluster_idx": 5}, {"solution": "def big_sum(array):\n \"\"\"\n Calculate the sum of the largest and smallest value in a given array.\n\n Args:\n array (list): A list of integers.\n\n Returns:\n int: The sum of the largest and smallest values.\n\n Raises:\n ValueError: If the input array is empty.\n \"\"\"\n if not array:\n raise ValueError(\"Input array cannot be empty\")\n\n return max(array) + min(array)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n \"\"\"\n This function takes an array as input, and returns the sum of the largest and smallest values.\n\n :param arr: A list of numbers\n :return: Sum of the largest and smallest numbers in the array\n \"\"\"\n if not arr:\n raise ValueError(\"Array cannot be empty\")\n \n return max(arr) + min(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n \"\"\"\n Returns the sum of the smallest and largest elements in a given array.\n\n Args:\n arr (list): A list of numbers.\n\n Returns:\n int or float: The sum of the smallest and largest numbers in the array.\n\n Raises:\n ValueError: If the input array is empty.\n \"\"\"\n\n # Check if the array is empty\n if len(arr) == 0:\n raise ValueError(\"Input array is empty\")\n\n # Find the smallest and largest values in the array\n smallest = min(arr)\n largest = max(arr)\n\n # Return the sum of the smallest and largest values\n return smallest + largest", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n \"\"\"\n This function calculates the sum of the largest and smallest values in a given array.\n\n Args:\n arr (list): A list of integers.\n\n Returns:\n int: The sum of the largest and smallest values in the array.\n\n Raises:\n ValueError: If the array is empty.\n\n Examples:\n >>> big_sum([1,2,3])\n 4\n \"\"\"\n\n # Check if the array is not empty\n if not arr:\n raise ValueError(\"Array cannot be empty\")\n\n # Calculate the sum of the largest and smallest values in the array\n return max(arr) + min(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(numbers):\n \"\"\"\n This function calculates the sum of the largest and smallest values in a given array.\n \n Parameters:\n numbers (list): A list of numbers.\n \n Returns:\n int: The sum of the largest and smallest value in the array.\n \n Raises:\n ValueError: If the input list is empty.\n \"\"\"\n if not numbers:\n raise ValueError(\"Input list is empty\")\n \n return max(numbers) + min(numbers)", "matching_cluster_idx": 5}, {"solution": "def big_sum(numbers):\n \"\"\"\n Returns the sum of the smallest and largest numbers in a given list.\n \n Args:\n numbers (list): A list of numbers.\n \n Returns:\n int or float: The sum of the smallest and largest numbers.\n \"\"\"\n return min(numbers) + max(numbers)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n \"\"\"\n This function calculates the sum of the smallest and largest numbers in a given array.\n\n Args:\n arr (list): A list of numbers.\n\n Returns:\n int: The sum of the smallest and largest numbers in the array.\n\n Raises:\n ValueError: If the input array is empty.\n \"\"\"\n\n # Check if the input array is empty\n if not arr:\n raise ValueError(\"Input array cannot be empty\")\n\n # Find the smallest and largest numbers in the array\n smallest = min(arr)\n largest = max(arr)\n\n # Calculate the sum\n total = smallest + largest\n\n return total", "matching_cluster_idx": 5}, {"solution": "def big_sum(array):\n \"\"\"\n This function calculates the sum of the smallest and largest value in a given array.\n \n Args:\n array (list): The list of numbers.\n \n Returns:\n int: The sum of the smallest and largest value.\n \"\"\"\n if len(array) < 1:\n raise ValueError(\"Array must not be empty\")\n \n return min(array) + max(array)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n \"\"\"\n Calculate the sum of the largest and smallest values in a given array.\n\n Args:\n arr (list): A list of numbers.\n\n Returns:\n int: The sum of the largest and smallest values in the array.\n \"\"\"\n if not arr:\n raise ValueError(\"Array cannot be empty\")\n\n return max(arr) + min(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n \"\"\"\n This function calculates the sum of the largest and smallest values in a given array.\n\n Args:\n arr (list): A list of integers.\n\n Returns:\n int: The sum of the largest and smallest values in the array.\n\n Raises:\n ValueError: If the array is empty.\n \"\"\"\n if len(arr) == 0:\n raise ValueError(\"Array is empty\")\n\n return max(arr) + min(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n \"\"\"\n Find the sum of the largest and smallest value in a given array.\n\n Args:\n arr (list): The input array of numbers.\n\n Returns:\n int: The sum of the largest and smallest values.\n\n Raises:\n ValueError: If the input array is empty.\n \"\"\"\n if not arr:\n raise ValueError(\"Input array is empty\")\n\n return max(arr) + min(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(array):\n \"\"\"\n Calculate the sum of the largest and smallest value in a given array.\n\n Args:\n array (list): A list of integers.\n\n Returns:\n int: The sum of the largest and smallest values in the array.\n\n Raises:\n ValueError: If the input array is empty.\n \"\"\"\n if not array:\n raise ValueError(\"Input array cannot be empty\")\n\n return max(array) + min(array)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n \"\"\"\n This function calculates the sum of the largest and smallest value in a given array.\n\n Args:\n arr (list): A list of integers.\n\n Returns:\n int: The sum of the largest and smallest value in the array.\n \"\"\"\n if not arr:\n raise ValueError(\"Array cannot be empty\")\n\n return max(arr) + min(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n \"\"\"\n This function calculates the sum of the smallest and largest value in a given array.\n \n Parameters:\n arr (list): The input list of integers.\n \n Returns:\n int: The sum of the smallest and largest number in the array.\n \n Raises:\n ValueError: If the input array is empty.\n \"\"\"\n \n # Check if the array is empty\n if not arr:\n raise ValueError(\"Array cannot be empty\")\n \n # Use built-in functions to find the smallest and largest values in the array\n min_value = min(arr)\n max_value = max(arr)\n \n # Calculate and return the sum of the smallest and largest values\n return min_value + max_value", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n \"\"\"\n This function calculates the sum of the largest and smallest value in a given array.\n\n Parameters:\n arr (list): A list of integers.\n\n Returns:\n int: The sum of the largest and smallest value in the array.\n\n Raises:\n ValueError: If the input array is empty.\n \"\"\"\n if not arr:\n raise ValueError(\"Input array cannot be empty\")\n\n return max(arr) + min(arr)", "matching_cluster_idx": 5}, {"solution": "import unittest\ndef big_sum(arr):\n \"\"\"\n Calculate the sum of the largest and smallest value in a given array.\n\n Args:\n arr (list): A list of numbers.\n\n Returns:\n int: The sum of the largest and smallest value in the array.\n\n Raises:\n ValueError: If the array is empty.\n \"\"\"\n\n # Check if the array is empty\n if len(arr) == 0:\n raise ValueError(\"Array cannot be empty\")\n\n # Find the smallest value in the array\n smallest = min(arr)\n \n # Find the largest value in the array\n largest = max(arr)\n \n # Return the sum of the smallest and largest value\n return smallest + largest", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n \"\"\"\n This function finds the sum of the largest and smallest value in a given array.\n \n Args:\n arr (list): A list of integers.\n \n Returns:\n int: The sum of the largest and smallest value in the array.\n \"\"\"\n # Check if the array is empty\n if not arr:\n return 0\n \n # Find the largest and smallest value in the array\n max_value = max(arr)\n min_value = min(arr)\n \n # Return the sum of the largest and smallest value\n return max_value + min_value", "matching_cluster_idx": 5}, {"solution": "def big_sum(array):\n \"\"\"\n This function calculates the sum of the largest and smallest value in a given array.\n\n Args:\n array (list): A list of numbers.\n\n Returns:\n int: The sum of the largest and smallest value in the array.\n\n Raises:\n ValueError: If the input array is empty.\n \"\"\"\n if len(array) == 0:\n raise ValueError(\"Array cannot be empty\")\n\n return max(array) + min(array)\narray = [1, 2, 3]", "matching_cluster_idx": 5}]}, "Mbpp/477": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def is_lower(input_str):\n \"\"\"\n Converts the given string to lower case.\n \n Args:\n input_str (str): The input string to be converted.\n \n Returns:\n str: The input string in lower case.\n \"\"\"\n return input_str.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(input_string):\n \"\"\"\n This function takes a string as an input and returns its lower case version.\n\n Args:\n input_string (str): The string to be converted to lower case.\n\n Returns:\n str: Lower case version of the input string.\n \"\"\"\n return input_string.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(input_string):\n \"\"\"\n Converts the input string to lower case.\n \n Args:\n input_string (str): The input string to convert.\n \n Returns:\n str: The lower case version of the input string.\n \"\"\"\n return input_string.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(input_string):\n \"\"\"\n Converts the given string to lower case.\n\n Args:\n input_string (str): The string to be converted.\n\n Returns:\n str: The input string in lower case.\n \"\"\"\n return input_string.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(input_string):\n \"\"\"\n This function converts a given string to lower case.\n\n Args:\n input_string (str): The input string to be converted.\n\n Returns:\n str: The input string in lower case.\n \"\"\"\n return input_string.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(input_string):\n \"\"\"\n Converts the given string to lower case.\n\n Args:\n input_string (str): The input string to be converted.\n\n Returns:\n str: The lower case version of the input string.\n \"\"\"\n return input_string.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n \"\"\"\n This function converts the given string to lower case.\n\n Args:\n s (str): The string to be converted to lower case.\n\n Returns:\n str: The input string converted to lower case.\n \"\"\"\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(input_string):\n \"\"\"\n Converts the input string to lower case.\n\n Args:\n input_string (str): The string to convert.\n\n Returns:\n str: The input string in lower case.\n \"\"\"\n return input_string.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n \"\"\"\n Convert the given string to lower case.\n \n Args:\n s (str): The string to be converted.\n \n Returns:\n str: The input string in lower case.\n \"\"\"\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(input_string):\n \"\"\"\n This function converts the given string to lower case.\n\n Args:\n input_string (str): The string to be converted.\n\n Returns:\n str: The converted string in lower case.\n \"\"\"\n return input_string.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n \"\"\"\n Convert the given string to lower case.\n\n Args:\n s (str): The input string.\n\n Returns:\n str: The input string in lower case.\n \"\"\"\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n \"\"\"\n Converts a given string to lower case.\n \n Args:\n s (str): The input string to be converted.\n \n Returns:\n str: The input string in lower case.\n \"\"\"\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n \"\"\"\n Converts the given string to lower case.\n\n Args:\n s (str): Input string.\n\n Returns:\n str: Lower case version of the input string.\n \"\"\"\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(input_string):\n \"\"\"\n This function converts the input string to lower case.\n \n Args:\n input_string (str): The string to be converted to lower case.\n\n Returns:\n str: The lower case version of the input string.\n \"\"\"\n return input_string.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s: str) -> str:\n \"\"\"\n Converts a given string to lower case.\n\n Args:\n s (str): The input string to be converted.\n\n Returns:\n str: The input string in lower case.\n \"\"\"\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n \"\"\"\n This function converts a given string into lower case.\n\n Args:\n s (str): The string to be converted.\n\n Returns:\n str: The lower case version of the input string.\n\n Raises:\n TypeError: If the input is not a string.\n \"\"\"\n\n # Check if the input is a string\n if not isinstance(s, str):\n raise TypeError(\"Input must be a string.\")\n\n # Use the built-in lower method of Python strings to convert to lower case\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(input_string):\n \"\"\"\n Converts the given string to lower case.\n\n Args:\n input_string (str): The input string.\n\n Returns:\n str: The input string converted to lower case.\n \"\"\"\n return input_string.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(input_string):\n \"\"\"\n Convert the given string to lower case.\n\n Args:\n input_string (str): The string to be converted.\n\n Returns:\n str: The lower case version of the input string.\n \"\"\"\n return input_string.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(input_string):\n \"\"\"\n Convert the given string to lower case.\n\n Args:\n input_string (str): The string to be converted.\n\n Returns:\n str: The input string in lower case.\n \"\"\"\n return input_string.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(input_string):\n \"\"\"\n This function converts the given string to lower case.\n\n Args:\n input_string (str): The string to be converted to lower case.\n\n Returns:\n str: The lower case version of the input string.\n\n Example:\n >>> is_lower(\"InValid\")\n 'invalid'\n \"\"\"\n return input_string.lower()", "matching_cluster_idx": 4}]}, "Mbpp/563": {"dps": 82.73224043715848, "dps_norm": 81.36363636363636, "pass@1": 87.0, "profiled": [{"solution": "import re\ndef extract_values(input_string):\n \"\"\"\n Extract values between quotation marks from a string.\n\n Args:\n input_string (str): Input string containing values enclosed in quotation marks.\n\n Returns:\n list: List of extracted values.\n\n Raises:\n ValueError: If input is not a string.\n \"\"\"\n\n if not isinstance(input_string, str):\n raise ValueError(\"Input must be a string\")\n\n # Regular expression pattern to match values between double quotes\n pattern = r'\"(.*?)\"'\n\n # Find all matches of the pattern in the input string\n matches = re.findall(pattern, input_string)\n\n return matches", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(input_str):\n \"\"\"\n This function takes an input string and returns a list of values \n that are enclosed within quotation marks.\n \n Parameters:\n input_str (str): The input string from which values will be extracted.\n \n Returns:\n list: A list of extracted values.\n \"\"\"\n pattern = r'\"(.*?)\"'\n matches = re.findall(pattern, input_str)\n return matches", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(s):\n \"\"\"\n Extract values between quotation marks from a string.\n\n Args:\n s (str): Input string containing quoted values.\n\n Returns:\n list: A list of extracted values.\n \"\"\"\n return re.findall(r'\"([^\"]*)\"', s)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(s):\n \"\"\"\n This function extracts values enclosed within quotation marks from a string.\n\n Parameters:\n s (str): Input string containing quoted values.\n\n Returns:\n list: A list of values enclosed within quotation marks.\n\n Example:\n >>> extract_values('\"Python\", \"PHP\", \"Java\"')\n ['Python', 'PHP', 'Java']\n \"\"\"\n return re.findall(r'\"([^\"]*)\"', s)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(s):\n \"\"\"\n Extract values between quotation marks from a string.\n\n Parameters:\n s (str): Input string containing values within quotes.\n\n Returns:\n list: List of extracted values.\n\n \"\"\"\n return re.findall(r'\"(.*?)\"', s)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(s):\n \"\"\"\n Extract values between quotation marks from a string.\n \n Args:\n s (str): A string containing values enclosed within quotation marks.\n \n Returns:\n list: A list of extracted values.\n \"\"\"\n pattern = r'\"(.*?)\"' # Using non-greedy match (.*?) for correctness\n return re.findall(pattern, s)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(input_string):\n \"\"\"\n Extracts values between quotation marks from a string.\n\n Args:\n input_string (str): A string containing values enclosed in quotation marks.\n\n Returns:\n list: A list of extracted values.\n\n Example:\n >>> extract_values('\"Python\", \"PHP\", \"Java\"')\n ['Python', 'PHP', 'Java']\n \"\"\"\n pattern = r'\"([^\"]*)\"'\n matches = re.findall(pattern, input_string)\n return matches", "matching_cluster_idx": 8}, {"solution": "def extract_values(s):\n \"\"\"\n Extract values between quotation marks from a string.\n \n Args:\n s (str): Input string with values enclosed in quotation marks.\n \n Returns:\n list: List of extracted values.\n \"\"\"\n values = []\n start = 0\n while True:\n start = s.find('\"', start)\n if start == -1:\n break\n end = s.find('\"', start + 1)\n if end == -1:\n break\n values.append(s[start + 1:end])\n start = end + 1\n return values", "matching_cluster_idx": 10}, {"solution": "import re\ndef extract_values(s):\n \"\"\"\n Extract values between quotation marks from a string.\n\n Args:\n s (str): The input string containing quoted values.\n\n Returns:\n list: A list of extracted values.\n \"\"\"\n return re.findall(r'\"(.*?)\"', s)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(s):\n \"\"\"\n Extracts values between quotation marks from a string.\n\n Args:\n s (str): Input string containing values enclosed in quotation marks.\n\n Returns:\n list: A list of values extracted from the input string.\n \"\"\"\n # Using regular expression to find all substrings enclosed in double quotes\n values = re.findall(r'\\\"(.*?)\\\"', s)\n return values", "matching_cluster_idx": 8}, {"solution": "def extract_values(s):\n \"\"\"\n Extract values between quotation marks from a string.\n\n Args:\n s (str): Input string containing quoted values.\n\n Returns:\n list: List of extracted values.\n\n Example:\n >>> extract_values('\"Python\", \"PHP\", \"Java\"')\n ['Python', 'PHP', 'Java']\n \"\"\"\n import re\n # Regular expression to match any characters (including none) within quotes\n pattern = r'\"(.*?)\"'\n # Use findall to return all matches of the pattern in the string as a list of strings\n return re.findall(pattern, s)", "matching_cluster_idx": 8}, {"solution": "def extract_values(s):\n \"\"\"\n Extract values between quotation marks from a string.\n\n Args:\n s (str): Input string containing values between quotation marks.\n\n Returns:\n list: List of extracted values.\n\n Example:\n >>> extract_values('\"Python\", \"PHP\", \"Java\"')\n ['Python', 'PHP', 'Java']\n \"\"\"\n # Initialize an empty list to store extracted values\n values = []\n # Initialize an empty string to build each value\n value = \"\"\n # Initialize a flag to track whether we're currently inside quotes\n in_quotes = False\n # Iterate over each character in the string\n for char in s:\n # Check if the character is a quotation mark\n if char == '\"':\n # If we're not in quotes, start a new value and set the flag to True\n if not in_quotes:\n in_quotes = True\n # If we're in quotes, add the current value to the list and reset it\n else:\n values.append(value)\n value = \"\"\n in_quotes = False\n # If we're in quotes and the character is not a quotation mark, add it to the current value\n elif in_quotes:\n value += char\n return values", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_values(s):\n \"\"\"\n This function takes a string as input, extracts values between quotation marks and returns them as a list.\n \n Parameters:\n s (str): The input string containing values between quotation marks.\n \n Returns:\n list: A list of extracted values.\n \"\"\"\n # Use regular expression to find all values between quotation marks\n values = re.findall(r'\"(.*?)\"', s)\n \n return values", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(s):\n \"\"\"\n Extracts values between quotation marks from a string.\n\n Args:\n s (str): Input string containing values between quotation marks.\n\n Returns:\n list: List of extracted values.\n\n Example:\n >>> extract_values('\"Python\", \"PHP\", \"Java\"')\n ['Python', 'PHP', 'Java']\n \"\"\"\n # Regular expression pattern to match values between quotation marks\n pattern = r'\"(.*?)\"'\n \n # Find all matches and extract the captured groups (values without quotes)\n matches = re.findall(pattern, s)\n \n return matches", "matching_cluster_idx": 8}, {"solution": "def extract_values(s):\n \"\"\"\n This function extracts values between quotation marks from a string.\n\n Args:\n s (str): Input string with quoted values.\n\n Returns:\n list: List of extracted values.\n \"\"\"\n import re\n # Use regular expression to find all substrings between quotation marks\n values = re.findall(r'\"([^\"]*)\"', s)\n return values", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(s):\n \"\"\"\n Extract values between quotation marks from a string.\n \n Args:\n s (str): Input string with quoted values.\n \n Returns:\n list: List of extracted values.\n \"\"\"\n return re.findall(r'\"(.*?)\"', s)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(s):\n \"\"\"\n Extract values between quotation marks from a string.\n\n Args:\n s (str): The input string containing quoted values.\n\n Returns:\n list: A list of values between quotation marks.\n \"\"\"\n # Use regular expression to find all quoted strings in the input string\n return re.findall(r'\\\"(.*?)\\\"', s)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(s):\n \"\"\"\n Extracts values between quotation marks from a string.\n\n Args:\n s (str): The input string.\n\n Returns:\n list: A list of extracted values.\n\n Example:\n >>> extract_values('\"Python\", \"PHP\", \"Java\"')\n ['Python', 'PHP', 'Java']\n \"\"\"\n pattern = r'\"(.*?)\"'\n return [match for match in re.findall(pattern, s)]", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(s):\n \"\"\"\n Extracts values between quotation marks from a string.\n\n Args:\n s (str): Input string containing values between quotation marks.\n\n Returns:\n list: A list of values extracted from the string.\n \"\"\"\n # Use regular expression to find all substrings between quotation marks\n values = re.findall(r'\"(.*?)\"', s)\n \n return values", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(s):\n \"\"\"\n Extracts values between quotation marks from a given string.\n\n Args:\n s (str): Input string.\n\n Returns:\n list: List of values between quotation marks.\n \"\"\"\n # Regular expression to match values between quotation marks\n pattern = r'\"(.*?)\"'\n \n # Find all matches in the string and return them in a list\n return re.findall(pattern, s)", "matching_cluster_idx": 8}]}, "Mbpp/572": {"dps": 95.30864197530865, "dps_norm": 86.42857142857142, "pass@1": 89.0, "profiled": [{"solution": "def two_unique_nums(nums):\n \"\"\"\n This function removes duplicate numbers from a given list.\n \n Args:\n nums (list): The input list of numbers.\n \n Returns:\n list: A list of numbers that appear only once in the input list.\n \"\"\"\n \n # Create a dictionary to store the frequency of each number in the list\n num_frequency = {}\n \n # Iterate through the list to count the frequency of each number\n for num in nums:\n if num in num_frequency:\n num_frequency[num] += 1\n else:\n num_frequency[num] = 1\n \n # Use a list comprehension to filter out numbers that appear more than once\n unique_nums = [num for num, frequency in num_frequency.items() if frequency == 1]\n \n return unique_nums", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(nums):\n \"\"\"\n Returns a list of numbers that appear exactly once in the given list.\n\n Args:\n nums (list): A list of numbers.\n\n Returns:\n list: A list of numbers that appear exactly once in the given list.\n \"\"\"\n count_dict = {}\n for num in nums:\n if num in count_dict:\n count_dict[num] += 1\n else:\n count_dict[num] = 1\n\n return [num for num, count in count_dict.items() if count == 1]", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(nums):\n \"\"\"\n Returns a list of numbers that appear only once in the given list.\n \n Args:\n nums (list): A list of numbers.\n \n Returns:\n list: A list of numbers that appear only once in the input list.\n \"\"\"\n count_dict = {}\n for num in nums:\n if num in count_dict:\n count_dict[num] += 1\n else:\n count_dict[num] = 1\n \n return [num for num, count in count_dict.items() if count == 1]", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(nums):\n \"\"\"\n Returns a list of unique numbers from the given list, preserving the order of first occurrences.\n A unique number is a number that appears exactly once in the list.\n \n :param nums: A list of integers.\n :return: A list of unique integers.\n \"\"\"\n # Count occurrences of each number\n count_map = {}\n for num in nums:\n if num in count_map:\n count_map[num] += 1\n else:\n count_map[num] = 1\n \n # Filter out non-unique numbers\n unique_nums = [num for num in nums if count_map[num] == 1]\n \n return unique_nums", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(nums):\n \"\"\"\n This function takes a list of integers as input, and returns a new list containing only numbers that occur twice in the input.\n\n Args:\n nums (list): A list of integers.\n\n Returns:\n list: A list of integers that occur twice in the input list.\n\n Raises:\n TypeError: If the input is not a list.\n\n Example:\n >>> two_unique_nums([1, 2, 3, 2, 3, 4, 5])\n [4, 5]\n \"\"\"\n\n if not isinstance(nums, list):\n raise TypeError(\"Input must be a list\")\n\n # Count the occurrences of each number in the input list\n num_counts = {}\n for num in nums:\n if num in num_counts:\n num_counts[num] += 1\n else:\n num_counts[num] = 1\n\n # Return a list of numbers that occur twice\n return [num for num, count in num_counts.items() if count == 1]", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(nums):\n \"\"\"\n This function takes in a list of numbers as input, \n and returns a new list with numbers that only appear twice in the original list.\n\n :param nums: A list of integers\n :return: A list of integers that appear twice in the input list\n \"\"\"\n count_dict = {}\n \n # Create a dictionary to store the count of each number\n for num in nums:\n if num in count_dict:\n count_dict[num] += 1\n else:\n count_dict[num] = 1\n \n # Create a new list with numbers that only appear once in the original list\n unique_nums = [num for num, count in count_dict.items() if count == 1]\n \n return unique_nums", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(lst):\n \"\"\"\n Removes numbers that appear more than twice in the given list.\n\n Args:\n lst (list): List of numbers.\n\n Returns:\n list: List of numbers that appear only twice in the original list.\n\n Example:\n >>> two_unique_nums([1,2,3,2,3,4,5])\n [1, 4, 5]\n \"\"\"\n # Create a dictionary to count the frequency of each number in the list\n frequency_count = {}\n for num in lst:\n if num in frequency_count:\n frequency_count[num] += 1\n else:\n frequency_count[num] = 1\n \n # Return a list of numbers that appear only twice in the original list\n return [num for num, count in frequency_count.items() if count == 1]", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(nums):\n \"\"\"\n Returns a list of numbers that appear exactly once in the given list.\n \n :param nums: A list of integers.\n :return: A list of integers that appear exactly once in the input list.\n \"\"\"\n # Create a dictionary where keys are the numbers from the input list and values are their frequencies\n freq_dict = {}\n for num in nums:\n if num in freq_dict:\n freq_dict[num] += 1\n else:\n freq_dict[num] = 1\n \n # Return a list of numbers that appear exactly once (i.e., have a frequency of 1)\n return [num for num, freq in freq_dict.items() if freq == 1]", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(nums):\n \"\"\"\n Given a list of numbers, return a list of numbers that appear only once.\n \n Args:\n nums (list): A list of integers.\n \n Returns:\n list: A list of unique integers that appear only once in the input list.\n \"\"\"\n count = {}\n for num in nums:\n if num in count:\n count[num] += 1\n else:\n count[num] = 1\n \n return [num for num, freq in count.items() if freq == 1]", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(nums):\n \"\"\"\n Removes duplicate numbers from a given list of numbers.\n\n Args:\n nums (list): A list of numbers.\n\n Returns:\n list: A list with unique numbers, keeping only those that appear once in the original list.\n \"\"\"\n count_dict = {}\n for num in nums:\n if num in count_dict:\n count_dict[num] += 1\n else:\n count_dict[num] = 1\n\n return [num for num, count in count_dict.items() if count == 1]", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(nums):\n \"\"\"\n This function removes duplicate numbers from a given list.\n \n Args:\n nums (list): A list of integers.\n \n Returns:\n list: A list of integers with duplicates removed and counts of 2 or greater.\n \"\"\"\n count_dict = {}\n \n # Create a dictionary with the numbers as keys and counts as values\n for num in nums:\n if num in count_dict:\n count_dict[num] += 1\n else:\n count_dict[num] = 1\n \n # Filter out numbers with counts greater than 1\n unique_nums = [num for num, count in count_dict.items() if count == 1]\n \n return unique_nums", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(nums):\n \"\"\"\n Removes duplicate numbers from a given list and returns unique elements.\n \n Args:\n - nums (list): A list of integers.\n \n Returns:\n - list: A list of integers with duplicates removed.\n \"\"\"\n \n # Create an empty dictionary to store numbers as keys and their counts as values\n num_count = {}\n \n # Iterate over the list to count the occurrence of each number\n for num in nums:\n if num in num_count:\n num_count[num] += 1\n else:\n num_count[num] = 1\n \n # Use a list comprehension to create a list of numbers that appear only once\n unique_nums = [num for num, count in num_count.items() if count == 1]\n \n return unique_nums", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(nums):\n \"\"\"\n This function removes duplicate numbers from a given list of numbers.\n\n Args:\n nums (list): A list of integers.\n\n Returns:\n list: A list of numbers that appear only once in the original list.\n \"\"\"\n count_dict = {}\n \n # Count occurrences of each number in the list\n for num in nums:\n if num in count_dict:\n count_dict[num] += 1\n else:\n count_dict[num] = 1\n \n # Return a list of numbers that appear only once\n return [num for num, count in count_dict.items() if count == 1]", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(nums):\n \"\"\"\n Removes numbers that appear more than twice from a given list of numbers.\n \n Args:\n nums (list): The list of numbers.\n \n Returns:\n list: The list of numbers that appear exactly once.\n \"\"\"\n num_count = {}\n for num in nums:\n if num in num_count:\n num_count[num] += 1\n else:\n num_count[num] = 1\n \n return [num for num, count in num_count.items() if count == 1]", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(nums):\n \"\"\"\n Removes numbers from a list that occur more than once.\n \n Parameters:\n nums (list): A list of numbers.\n \n Returns:\n list: A new list containing only the numbers that occurred once in the original list.\n \"\"\"\n # Create a dictionary to count the occurrences of each number\n counts = {}\n for num in nums:\n if num in counts:\n counts[num] += 1\n else:\n counts[num] = 1\n \n # Return a list of numbers that occurred only once\n return [num for num, count in counts.items() if count == 1]", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(nums):\n \"\"\"\n Returns a list of numbers that appear exactly twice in the input list.\n\n Args:\n - nums: A list of integers.\n\n Returns:\n - A list of integers that appear exactly twice in the input list.\n \"\"\"\n from collections import Counter\n\n # Count occurrences of each number\n num_counts = Counter(nums)\n\n # Return numbers that appear exactly twice\n return [num for num, count in num_counts.items() if count == 1]", "matching_cluster_idx": 6}, {"solution": "def two_unique_nums(nums):\n \"\"\"\n This function removes duplicate numbers from a given list.\n \n Args:\n nums (list): A list of integers.\n \n Returns:\n list: A list of unique numbers that appear only once in the input list.\n \"\"\"\n count_dict = {}\n for num in nums:\n if num in count_dict:\n count_dict[num] += 1\n else:\n count_dict[num] = 1\n \n return [num for num, count in count_dict.items() if count == 1]", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(nums):\n \"\"\"\n This function removes duplicate numbers from a given list.\n \n It does this by creating a dictionary where the keys are the numbers from the list\n and the values are their respective counts. Then it returns a list of numbers \n that appear only once in the list.\n \n Args:\n nums (list): A list of integers.\n \n Returns:\n list: A list of unique integers from the input list.\n \"\"\"\n # Create a dictionary to store the count of each number\n num_count = {}\n \n # Iterate through the input list\n for num in nums:\n # If the number is already in the dictionary, increment its count\n if num in num_count:\n num_count[num] += 1\n # If the number is not in the dictionary, add it with a count of 1\n else:\n num_count[num] = 1\n \n # Use a list comprehension to return a list of numbers that appear only once\n return [num for num, count in num_count.items() if count == 1]", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(nums):\n \"\"\"\n Removes numbers from the list that appear more than once.\n \n Args:\n nums (list): A list of integers.\n \n Returns:\n list: A list of unique integers appearing only once in the original list.\n \"\"\"\n count_dict = {}\n for num in nums:\n if num in count_dict:\n count_dict[num] += 1\n else:\n count_dict[num] = 1\n\n return [num for num, count in count_dict.items() if count == 1]", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(nums):\n \"\"\"\n Returns a list of numbers that appear exactly twice in the given list.\n\n Args:\n nums (list): A list of integers.\n\n Returns:\n list: A list of numbers that appear exactly once in the given list.\n \"\"\"\n count_dict = {}\n for num in nums:\n if num in count_dict:\n count_dict[num] += 1\n else:\n count_dict[num] = 1\n\n return [num for num, count in count_dict.items() if count == 1]", "matching_cluster_idx": 5}]}, "Mbpp/578": {"dps": 89.23809523809524, "dps_norm": 71.36363636363637, "pass@1": 100.0, "profiled": [{"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"\n Interleave three lists of the same length into a single flat list.\n\n Args:\n list1 (list): The first list.\n list2 (list): The second list.\n list3 (list): The third list.\n\n Returns:\n list: A flat list with interleaved elements from the input lists.\n\n Raises:\n ValueError: If the input lists are not of the same length.\n \"\"\"\n if len(list1) != len(list2) or len(list1) != len(list3):\n raise ValueError(\"Input lists must be of the same length\")\n\n result = [item for sublist in zip(list1, list2, list3) for item in sublist]\n return result", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"\n Interleaves three lists of the same length into a single flat list.\n \n Args:\n list1 (list): The first list to interleave.\n list2 (list): The second list to interleave.\n list3 (list): The third list to interleave.\n \n Returns:\n list: A new flat list with elements from the input lists interleaved.\n \"\"\"\n # Check if all input lists have the same length\n if not (len(list1) == len(list2) == len(list3)):\n raise ValueError(\"All input lists must have the same length\")\n \n # Initialize an empty list to store the result\n result = []\n \n # Iterate over the indices of the input lists\n for i in range(len(list1)):\n # Interleave elements from the input lists\n result.extend([list1[i], list2[i], list3[i]])\n \n return result", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"\n Interleaves three lists of the same length into a single flat list.\n \n Args:\n list1 (list): The first list to interleave.\n list2 (list): The second list to interleave.\n list3 (list): The third list to interleave.\n \n Returns:\n list: A single flat list containing the interleaved elements of the input lists.\n \n Raises:\n ValueError: If the input lists are not of the same length.\n \"\"\"\n if len(list1) != len(list2) or len(list2) != len(list3):\n raise ValueError(\"Input lists must be of the same length\")\n\n return [item for triple in zip(list1, list2, list3) for item in triple]", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"\n Interleaves three lists of the same length into a single flat list.\n \n Args:\n list1 (list): The first list.\n list2 (list): The second list.\n list3 (list): The third list.\n \n Returns:\n list: A flat list containing elements from list1, list2, and list3 in an interleaved order.\n \n Raises:\n ValueError: If the input lists are not of the same length.\n \"\"\"\n # Check if the lists are of the same length\n if not (len(list1) == len(list2) == len(list3)):\n raise ValueError(\"Input lists must be of the same length\")\n \n # Interleave the lists\n return [element for triplet in zip(list1, list2, list3) for element in triplet]", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"\n Interleaves three lists of the same length into a single flat list.\n \n Args:\n list1 (list): The first list.\n list2 (list): The second list.\n list3 (list): The third list.\n \n Returns:\n list: A new list containing all elements from the three input lists, \n in the order of one element from list1, then list2, then list3.\n \n Raises:\n ValueError: If the lists are not all the same length.\n \"\"\"\n # Check that lists are the same length\n if not (len(list1) == len(list2) == len(list3)):\n raise ValueError(\"All lists must be the same length.\")\n \n # Use a list comprehension to build the result, taking elements from each list\n return [item for triplet in zip(list1, list2, list3) for item in triplet]", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"\n Interleave three lists of the same length into a single flat list.\n\n Args:\n list1 (list): The first list to interleave.\n list2 (list): The second list to interleave.\n list3 (list): The third list to interleave.\n\n Returns:\n list: A single flat list with the elements of the input lists interleaved.\n \"\"\"\n # Check that all lists are of the same length\n if len(list1) != len(list2) or len(list2) != len(list3):\n raise ValueError(\"All lists must be of the same length\")\n\n # Use zip to pair elements from each list, then flatten the result\n return [item for triplet in zip(list1, list2, list3) for item in triplet]", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"\n This function takes three lists of the same length and interleaves them into a single list.\n\n Args:\n list1 (list): The first list.\n list2 (list): The second list.\n list3 (list): The third list.\n\n Returns:\n list: A new list containing elements from list1, list2, and list3 in interleaved order.\n \"\"\"\n if len(list1) != len(list2) or len(list1) != len(list3):\n raise ValueError(\"Input lists must be of the same length\")\n\n return [element for i in range(len(list1)) for element in (list1[i], list2[i], list3[i])]", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"\n This function takes three lists of equal length and returns a new list \n with elements interleaved from the input lists.\n\n Args:\n list1 (list): The first list to interleave.\n list2 (list): The second list to interleave.\n list3 (list): The third list to interleave.\n\n Returns:\n list: A new list with elements interleaved from list1, list2, and list3.\n\n Raises:\n ValueError: If the input lists are not of equal length.\n \"\"\"\n\n # Check if the input lists are of equal length\n if not (len(list1) == len(list2) == len(list3)):\n raise ValueError(\"Input lists must be of equal length.\")\n\n # Initialize an empty list to store the result\n result = []\n\n # Interleave elements from the input lists\n for i in range(len(list1)):\n result.extend([list1[i], list2[i], list3[i]])\n\n return result", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"\n This function interleaves three lists of the same length into a single flat list.\n \n Args:\n list1 (list): The first list.\n list2 (list): The second list.\n list3 (list): The third list.\n \n Returns:\n list: A single flat list with elements from the input lists interleaved.\n \"\"\"\n # Check if the lists have the same length\n if len(list1) != len(list2) or len(list1) != len(list3):\n raise ValueError(\"All input lists must be of the same length.\")\n \n # Use zip() to pair corresponding elements from the three lists\n paired_lists = zip(list1, list2, list3)\n \n # Use a list comprehension to flatten the list of tuples\n interleaved_list = [element for tuple in paired_lists for element in tuple]\n \n return interleaved_list", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"\n Interleaves three lists of the same length into a single flat list.\n\n Args:\n list1 (list): The first list.\n list2 (list): The second list.\n list3 (list): The third list.\n\n Returns:\n list: A flat list with elements from input lists interleaved.\n\n Raises:\n ValueError: If input lists are not of the same length.\n \"\"\"\n if not (len(list1) == len(list2) == len(list3)):\n raise ValueError(\"Input lists must be of the same length\")\n\n # Use zip to iterate over input lists in parallel and chain results into a single list\n return [element for triplet in zip(list1, list2, list3) for element in triplet]", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"\n Interleaves 3 lists of the same length into a single flat list.\n \n Args:\n list1 (list): First list of elements\n list2 (list): Second list of elements\n list3 (list): Third list of elements\n \n Returns:\n list: Interleaved flat list\n \n Raises:\n ValueError: If the input lists are not of the same length\n \"\"\"\n if len(list1) != len(list2) or len(list1) != len(list3):\n raise ValueError(\"Input lists must be of the same length\")\n \n interleaved_list = []\n for elements in zip(list1, list2, list3):\n interleaved_list.extend(elements)\n \n return interleaved_list", "matching_cluster_idx": 8}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"\n Interleaves three lists of the same length into a single flat list.\n\n Args:\n list1 (list): The first list to interleave.\n list2 (list): The second list to interleave.\n list3 (list): The third list to interleave.\n\n Returns:\n list: A single flat list with elements from the input lists interleaved.\n \"\"\"\n if len(list1) != len(list2) or len(list2) != len(list3):\n raise ValueError(\"Input lists must be of the same length\")\n \n return [item for triple in zip(list1, list2, list3) for item in triple]", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"\n This function interleaves three lists of the same length into a single flat list.\n \n Args:\n list1 (list): The first list.\n list2 (list): The second list.\n list3 (list): The third list.\n \n Returns:\n list: A new flat list containing elements from list1, list2 and list3, interleaved.\n \"\"\"\n # Check if all input lists have the same length\n if not (len(list1) == len(list2) == len(list3)):\n raise ValueError(\"Input lists must be of the same length\")\n \n # Use the built-in zip function to group elements from each list, and a list comprehension to flatten the result\n return [item for group in zip(list1, list2, list3) for item in group]", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"\n Interleaves three lists of the same length into a single flat list.\n\n Args:\n list1 (list): The first list to interleave.\n list2 (list): The second list to interleave.\n list3 (list): The third list to interleave.\n\n Returns:\n list: A single flat list with elements from the three input lists interleaved.\n\n Raises:\n ValueError: If the input lists are not of the same length.\n \"\"\"\n\n # Check that the lists are of the same length\n if not (len(list1) == len(list2) == len(list3)):\n raise ValueError(\"Lists must be of the same length\")\n\n # Initialize the result list\n result = []\n\n # Iterate over the indices of the input lists\n for i in range(len(list1)):\n # Append elements from the three lists at the current index to the result\n result.extend([list1[i], list2[i], list3[i]])\n\n return result", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"\n This function interleaves three lists of the same length into a single flat list.\n\n Args:\n list1 (list): The first list.\n list2 (list): The second list.\n list3 (list): The third list.\n\n Returns:\n list: A flat list that contains all elements from the input lists in an interleaved manner.\n\n Raises:\n ValueError: If the input lists are not of the same length.\n \"\"\"\n # Check if the input lists are of the same length\n if not (len(list1) == len(list2) == len(list3)):\n raise ValueError(\"Input lists must be of the same length\")\n\n # Use zip to transpose the lists and chain to flatten them\n interleaved_list = [element for triple in zip(list1, list2, list3) for element in triple]\n\n return interleaved_list", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"\n Interleaves three lists of the same length into a single flat list.\n \n Args:\n list1 (list): The first list\n list2 (list): The second list\n list3 (list): The third list\n \n Returns:\n list: A single flat list containing the elements of the input lists, interleaved\n \n Raises:\n ValueError: If the input lists are not of the same length\n \"\"\"\n if len(list1) != len(list2) or len(list1) != len(list3):\n raise ValueError(\"Input lists must be of the same length\")\n \n return [x for triple in zip(list1, list2, list3) for x in triple]", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"\n Interleave three lists of the same length into a single flat list.\n\n Args:\n list1 (list): The first list.\n list2 (list): The second list.\n list3 (list): The third list.\n\n Returns:\n list: A single flat list with interleaved elements from the input lists.\n\n Raises:\n ValueError: If the input lists are not of the same length.\n \"\"\"\n if len(list1) != len(list2) or len(list1) != len(list3):\n raise ValueError(\"Input lists must be of the same length.\")\n\n result = []\n for item1, item2, item3 in zip(list1, list2, list3):\n result.extend([item1, item2, item3])\n return result", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"\n Interleaves three lists of the same length into a single flat list.\n \n Args:\n list1 (list): First list\n list2 (list): Second list\n list3 (list): Third list\n \n Returns:\n list: Interleaved flat list\n \n Raises:\n ValueError: If the input lists are not of the same length\n \"\"\"\n if not (len(list1) == len(list2) == len(list3)):\n raise ValueError(\"Input lists must be of the same length\")\n \n return [item for triple in zip(list1, list2, list3) for item in triple]", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"\n Interleaves three lists of the same length into a single flat list.\n \n Args:\n list1 (list): The first list\n list2 (list): The second list\n list3 (list): The third list\n \n Returns:\n list: A single flat list with interleaved elements from the input lists\n \"\"\"\n if len(list1) != len(list2) or len(list1) != len(list3):\n raise ValueError(\"All input lists must be of the same length\")\n\n # Use zip to create tuples of corresponding elements from each list\n # Then, use a list comprehension to flatten these tuples into a single list\n return [item for sublist in zip(list1, list2, list3) for item in sublist]", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"\n Interleaves three lists of the same length into a single flat list.\n \n Args:\n list1 (list): The first list to interleave.\n list2 (list): The second list to interleave.\n list3 (list): The third list to interleave.\n \n Returns:\n list: A flat list with elements interleaved from input lists.\n \n Raises:\n ValueError: If input lists are not of the same length.\n \"\"\"\n if not (len(list1) == len(list2) == len(list3)):\n raise ValueError(\"Input lists must be of the same length.\")\n\n return [item for sublist in zip(list1, list2, list3) for item in sublist]", "matching_cluster_idx": 7}]}, "Mbpp/586": {"dps": 98.83040935672514, "dps_norm": 87.5, "pass@1": 36.0, "profiled": [{"solution": "def split_Arr(arr, n):\n \"\"\"\n Splits a list at the nth index, and adds the first part to the end.\n\n Args:\n arr (list): Input list.\n n (int): Index at which to split.\n\n Returns:\n list: Modified list with the first part added to the end.\n \"\"\"\n if n >= len(arr):\n return arr\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"\n Splits a list at the nth element and adds the first part to the end.\n\n Args:\n arr (list): Input list\n n (int): Index to split at\n\n Returns:\n list: The modified list with the first part added to the end\n \"\"\"\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"\n Splits a list at the nth element and adds the first part to the end.\n\n Args:\n arr (list): The list to be split.\n n (int): The index at which the list will be split.\n\n Returns:\n list: The modified list with the first part added to the end.\n \"\"\"\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"\n Splits the input list at the nth position and appends the first part to the end.\n \n Args:\n arr (list): The input list to be split.\n n (int): The position at which to split the list.\n \n Returns:\n list: The modified list with the first part appended to the end.\n \"\"\"\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"\n Split a list at the nth element and add the first part to the end.\n\n Args:\n arr (list): Input list to be split.\n n (int): Index to split the list at.\n\n Returns:\n list: Split list with the first part added to the end.\n \"\"\"\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"\n This function splits a list at the nth element and adds the first part to the end.\n\n Args:\n arr (list): The input list to be split.\n n (int): The position at which the list should be split.\n\n Returns:\n list: The modified list with the first part appended to the end.\n\n Raises:\n ValueError: If the split position n is out of range.\n \"\"\"\n\n # Validate if the split position n is within the list bounds.\n if n < 0 or n > len(arr):\n raise ValueError(\"Split position is out of range.\")\n\n # Split the list into two parts.\n first_part = arr[:n]\n second_part = arr[n:]\n\n # Append the first part to the end of the second part.\n result = second_part + first_part\n\n return result", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"\n Splits a list at the nth element and appends the first part to the end.\n\n Args:\n arr (list): Input list.\n n (int): Index at which to split the list.\n\n Returns:\n list: The modified list.\n \"\"\"\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"\n Splits the input list at the nth element (1-indexed) and adds the first part to the end.\n \n Args:\n arr (list): Input list to be split.\n n (int): The index at which the list should be split (1-indexed).\n\n Returns:\n list: The modified list with the first part added to the end.\n \"\"\"\n # Convert n to 0-indexed\n n -= 1\n \n # Split the list at the nth index and add the first part to the end\n return arr[n+1:] + arr[:n+1]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"\n Splits a list at the nth element and adds the first part to the end.\n\n Args:\n arr (list): Input list to be split.\n n (int): Position at which to split the list.\n\n Returns:\n list: A new list where the first part is moved to the end.\n \"\"\"\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"\n This function splits the input list at the nth index and moves the first part to the end.\n\n Args:\n arr (list): The input list.\n n (int): The index at which the list should be split.\n\n Returns:\n list: The modified list.\n \"\"\"\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"\n This function splits the input list at the nth element and adds the first part to the end.\n\n Args:\n arr (list): The input list.\n n (int): The index at which the list should be split.\n\n Returns:\n list: The modified list with the first part appended to the end.\n \"\"\"\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"\n This function splits the input list at the nth index and \n appends the first part to the end of the second part.\n\n Args:\n arr (list): The input list\n n (int): The index at which to split the list\n\n Returns:\n list: The modified list\n \"\"\"\n # Split the list into two parts at index n\n first_part = arr[:n]\n second_part = arr[n:]\n\n # Append the first part to the end of the second part\n result = second_part + first_part\n\n return result", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"\n Splits the list at the nth element and adds the first part to the end.\n \n Parameters:\n arr (list): The input list to be split\n n (int): The index at which to split the list\n \n Returns:\n list: The modified list with the first part added to the end\n \"\"\"\n # Check if n is within the bounds of the list\n if n > len(arr):\n raise IndexError(\"n is out of range\")\n \n # Split the list into two parts\n first_part = arr[:n]\n second_part = arr[n:]\n \n # Combine the two parts in reverse order\n result = second_part + first_part\n \n return result", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"\n Splits the input list at the nth index and appends the first part to the end.\n\n Args:\n arr (list): The input list to be split.\n n (int): The index at which the list is to be split.\n\n Returns:\n list: The modified list with the first part appended to the end.\n \"\"\"\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(lst, n):\n \"\"\"\n This function splits the list at the nth element and appends the first part to the end.\n \n Args:\n lst (list): The list to be split\n n (int): The position to split the list\n\n Returns:\n list: The modified list\n \"\"\"\n # Check if n is within the valid range\n if n < 0 or n > len(lst):\n raise IndexError(\"n is out of range\")\n \n # Split the list into two parts\n first_part = lst[:n]\n second_part = lst[n:]\n \n # Append the first part to the end of the second part\n return second_part + first_part", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"\n Splits the given list at the nth position and moves the first part to the end.\n\n Args:\n arr (list): Input list\n n (int): The position at which to split the list\n\n Returns:\n list: Modified list with the first part moved to the end\n \"\"\"\n if n < 0 or n > len(arr):\n raise ValueError(\"Invalid split position\")\n\n # Split the list into two parts at the nth position\n first_part = arr[:n]\n second_part = arr[n:]\n\n # Combine the two parts in reverse order\n return second_part + first_part", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"\n Splits a list at the nth element and adds the first part to the end.\n\n Args:\n arr (list): Input list to split\n n (int): Index at which to split the list\n\n Returns:\n list: Modified list with first part appended to the end\n\n Raises:\n TypeError: If arr is not a list or n is not an integer\n ValueError: If n is out of range\n \"\"\"\n if not isinstance(arr, list) or not isinstance(n, int):\n raise TypeError(\"Input array must be a list and n must be an integer\")\n if n < 0 or n > len(arr):\n raise ValueError(\"n is out of range\")\n\n # Split the list at the nth element\n first_part = arr[:n]\n second_part = arr[n:]\n\n # Append the first part to the end of the second part\n result = second_part + first_part\n\n return result", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"\n Split the input list at the nth position and append the first part to the end.\n \n Args:\n arr (list): The input list to be split.\n n (int): The position at which the list will be split.\n \n Returns:\n list: The modified list with the first part appended to the end.\n \"\"\"\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"\n This function takes an array and an integer n as arguments.\n It splits the array at the nth position and appends the first part to the end.\n\n Args:\n arr (list): The input array.\n n (int): The position at which to split the array.\n\n Returns:\n list: The rearranged array.\n \"\"\"\n # Check if n is within the valid range\n if n < 0 or n > len(arr):\n raise ValueError(\"n is out of range\")\n\n # Split the array at the nth position\n first_part = arr[:n]\n second_part = arr[n:]\n\n # Append the first part to the end of the second part\n rearranged_arr = second_part + first_part\n\n return rearranged_arr", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"\n Splits a list at the nth element and adds the first part to the end.\n\n Args:\n arr (list): Input list to be split\n n (int): Position to split the list\n\n Returns:\n list: Modified list with first part appended to the end\n\n Raises:\n IndexError: If n is larger than the list length\n \"\"\"\n if n > len(arr):\n raise IndexError(\"n is larger than the length of the list\")\n \n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}]}, "Mbpp/587": {"dps": 78.04054054054055, "dps_norm": 93.75, "pass@1": 24.0, "profiled": [{"solution": "def list_tuple(lst):\n \"\"\"\n This function takes a list as input and returns its equivalent tuple.\n\n Args:\n lst (list): The input list.\n\n Returns:\n tuple: The input list converted to a tuple.\n \"\"\"\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n \"\"\"\n Converts a given list to a tuple.\n\n Args:\n lst (list): A list of elements.\n\n Returns:\n tuple: A tuple containing the same elements as the input list.\n \"\"\"\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(input_list):\n \"\"\"\n This function takes a list as an input and returns the equivalent tuple.\n\n Args:\n input_list (list): A list containing elements of any data type.\n\n Returns:\n tuple: A tuple containing the same elements as the input list.\n \"\"\"\n # Directly convert the list to a tuple using the tuple() function\n return tuple(input_list)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(input_list):\n \"\"\"\n Convert a list to a tuple.\n\n Args:\n input_list (list): The list to be converted.\n\n Returns:\n tuple: A tuple representation of the input list.\n\n Raises:\n TypeError: If the input is not a list.\n \"\"\"\n if not isinstance(input_list, list):\n raise TypeError(\"Input must be a list.\")\n return tuple(input_list)", "matching_cluster_idx": 2}, {"solution": "def list_tuple(input_list):\n \"\"\"\n This function takes an input list and converts it into a tuple.\n\n Args:\n input_list (list): The list to be converted into a tuple.\n\n Returns:\n tuple: The input list converted into a tuple.\n \"\"\"\n return tuple(input_list)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(input_list):\n \"\"\"\n Converts an input list to a tuple.\n\n Args:\n input_list (list): A list containing elements of any data type.\n\n Returns:\n tuple: A tuple containing the elements from the input list.\n \"\"\"\n return tuple(input_list)", "matching_cluster_idx": 2}, {"solution": "def list_tuple(input_list):\n \"\"\"\n This function converts a given list into a tuple.\n \n Parameters:\n input_list (list): A list of any data type elements.\n \n Returns:\n tuple: A tuple containing the same elements as the input list.\n \"\"\"\n return tuple(input_list)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n \"\"\"\n Converts a list to a tuple.\n\n Args:\n lst (list): A list of elements to convert to a tuple.\n\n Returns:\n tuple: A tuple containing the same elements as the input list.\n \"\"\"\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n \"\"\"\n Convert a given list to a tuple.\n\n Args:\n lst (list): A list of elements.\n\n Returns:\n tuple: The input list converted to a tuple.\n \"\"\"\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n \"\"\"\n Converts a list to a tuple.\n\n Args:\n lst (list): A list of elements to be converted.\n\n Returns:\n tuple: The input list converted to a tuple.\n\n Raises:\n TypeError: If the input is not a list.\n\n Examples:\n >>> list_tuple([5, 10, 7, 4, 15, 3])\n (5, 10, 7, 4, 15, 3)\n \"\"\"\n if not isinstance(lst, list):\n raise TypeError(\"Input must be a list\")\n return tuple(lst)", "matching_cluster_idx": 2}, {"solution": "def list_tuple(lst):\n \"\"\"\n Convert a list to a tuple.\n\n Args:\n lst (list): A list to be converted.\n\n Returns:\n tuple: A tuple version of the input list.\n \"\"\"\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(input_list):\n \"\"\"\n Converts a list to a tuple.\n\n Args:\n input_list (list): A list of elements to be converted to a tuple.\n\n Returns:\n tuple: The input list converted to a tuple.\n \"\"\"\n return tuple(input_list)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(input_list):\n \"\"\"\n Convert a list to a tuple.\n\n Args:\n input_list (list): A list of elements to convert to a tuple.\n\n Returns:\n tuple: A tuple representation of the input list.\n\n \"\"\"\n return tuple(input_list)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n \"\"\"\n This function takes a list as input and returns the equivalent tuple.\n\n Args:\n lst (list): The list to be converted to a tuple.\n\n Returns:\n tuple: A tuple equivalent to the input list.\n\n Raises:\n TypeError: If the input is not a list.\n \"\"\"\n if not isinstance(lst, list):\n raise TypeError(\"Input must be a list.\")\n return tuple(lst)", "matching_cluster_idx": 2}, {"solution": "def list_tuple(lst):\n \"\"\"\n This function converts a list to a tuple.\n\n Args:\n lst (list): A list of elements\n\n Returns:\n tuple: A tuple of elements\n \"\"\"\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(input_list):\n \"\"\"\n Converts a list into a tuple.\n \n Args:\n input_list (list): The list to be converted.\n \n Returns:\n tuple: A tuple representation of the input list.\n \"\"\"\n return tuple(input_list)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(input_list):\n \"\"\"\n This function takes a list as an input and returns a tuple.\n \n Parameters:\n input_list (list): The input list to be converted into a tuple.\n \n Returns:\n tuple: A tuple version of the input list.\n \"\"\"\n return tuple(input_list)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(input_list):\n \"\"\"\n Converts a list to a tuple.\n\n Args:\n input_list (list): A list to be converted.\n\n Returns:\n tuple: A tuple representation of the input list.\n \"\"\"\n return tuple(input_list)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n \"\"\"\n This function takes a list as an argument and returns its tuple equivalent.\n \n Parameters:\n lst (list): A list of elements.\n \n Returns:\n tuple: A tuple containing the same elements as the input list.\n \"\"\"\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n \"\"\"\n Convert a list to a tuple.\n \n Args:\n lst (list): Input list to be converted.\n \n Returns:\n tuple: The tuple equivalent of the input list.\n \"\"\"\n return tuple(lst)", "matching_cluster_idx": 2}]}, "Mbpp/588": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def big_diff(lst):\n \"\"\"\n Calculate the difference between the largest and smallest numbers in a list.\n\n Args:\n lst (list): A list of numbers.\n\n Returns:\n int: The difference between the largest and smallest numbers.\n\n Raises:\n ValueError: If the input list is empty.\n \"\"\"\n\n # Check if the list is empty\n if not lst:\n raise ValueError(\"The input list is empty.\")\n\n # Calculate the difference between the largest and smallest numbers\n return max(lst) - min(lst)", "matching_cluster_idx": 5}, {"solution": "def big_diff(numbers):\n \"\"\"\n Calculate the difference between the largest and smallest values in a given list.\n\n Args:\n numbers (list): A list of integers.\n\n Returns:\n int: The difference between the largest and smallest values in the list.\n\n Raises:\n ValueError: If the input list is empty.\n \"\"\"\n if not numbers:\n raise ValueError(\"Input list cannot be empty\")\n\n return max(numbers) - min(numbers)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n \"\"\"\n This function calculates the difference between the largest and smallest numbers in a given list.\n\n Args:\n nums (list): A list of integers.\n\n Returns:\n int: The difference between the largest and smallest numbers in the list.\n\n Raises:\n ValueError: If the input list is empty.\n \"\"\"\n if not nums:\n raise ValueError(\"Input list cannot be empty\")\n\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(lst):\n \"\"\"\n Returns the difference between the largest and smallest values in a given list.\n\n Args:\n lst (list): A list of numbers.\n\n Returns:\n int: The difference between the maximum and minimum values in the list.\n\n Raises:\n ValueError: If the input list is empty.\n \"\"\"\n\n # Check if the list is empty\n if not lst:\n raise ValueError(\"Input list cannot be empty\")\n\n # Find the maximum and minimum values in the list\n max_val = max(lst)\n min_val = min(lst)\n\n # Return the difference between the maximum and minimum values\n return max_val - min_val", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n \"\"\"\n Returns the difference between the largest and smallest values in a given list of numbers.\n\n Args:\n - nums (list): A list of numbers.\n\n Returns:\n - int: The difference between the largest and smallest values.\n\n Raises:\n - ValueError: If the input list is empty.\n \"\"\"\n\n # Check if the list is empty and raise a ValueError\n if len(nums) == 0:\n raise ValueError(\"Input list cannot be empty\")\n\n # Return the difference between the largest and smallest values in the list\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n \"\"\"\n This function calculates the difference between the largest and smallest values in a given list.\n \n Args:\n nums (list): A list of numbers.\n \n Returns:\n int: The difference between the largest and smallest values in the list.\n \"\"\"\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(numbers):\n \"\"\"\n Returns the difference between the largest and smallest values in a given list.\n \n Args:\n numbers (list): A list of numbers.\n \n Returns:\n int: The difference between the largest and smallest numbers.\n \"\"\"\n return max(numbers) - min(numbers)", "matching_cluster_idx": 5}, {"solution": "def big_diff(lst):\n \"\"\"\n Returns the difference between the largest and smallest value in a given list.\n \n Args:\n lst (list): A list of numbers.\n \n Returns:\n int: The difference between the largest and smallest number in the list.\n \"\"\"\n return max(lst) - min(lst)", "matching_cluster_idx": 5}, {"solution": "def big_diff(numbers):\n \"\"\"\n This function calculates the difference between the largest and smallest value in a given list.\n \n Args:\n numbers (list): A list of numbers.\n \n Returns:\n int: The difference between the largest and smallest value in the list.\n \"\"\"\n return max(numbers) - min(numbers)", "matching_cluster_idx": 5}, {"solution": "def big_diff(lst):\n \"\"\"\n Returns the difference between the largest and smallest value in a given list.\n\n Args:\n lst (list): A list of integers.\n\n Returns:\n int: The difference between the largest and smallest value.\n \"\"\"\n return max(lst) - min(lst)", "matching_cluster_idx": 5}, {"solution": "def big_diff(numbers):\n \"\"\"\n This function calculates the difference between the largest and smallest values in a given list.\n\n Args:\n numbers (list): A list of integers.\n\n Returns:\n int: The difference between the maximum and minimum values in the list.\n\n Raises:\n ValueError: If the input list is empty.\n \"\"\"\n if not numbers:\n raise ValueError(\"Input list cannot be empty\")\n return max(numbers) - min(numbers)", "matching_cluster_idx": 5}, {"solution": "def big_diff(numbers):\n \"\"\"\n Calculate the difference between the largest and smallest values in a given list.\n\n Args:\n numbers (list): A list of integers.\n\n Returns:\n int: The difference between the largest and smallest values in the list.\n \"\"\"\n # Check if the list is empty\n if not numbers:\n raise ValueError(\"Input list cannot be empty\")\n\n # Find the minimum and maximum values in the list\n min_val = min(numbers)\n max_val = max(numbers)\n\n # Return the difference between the maximum and minimum values\n return max_val - min_val", "matching_cluster_idx": 5}, {"solution": "def big_diff(lst):\n \"\"\"\n This function calculates the difference between the largest and smallest value in a given list.\n\n Args:\n lst (list): A list of integers.\n\n Returns:\n int: The difference between the largest and smallest values in the list.\n \"\"\"\n return max(lst) - min(lst)", "matching_cluster_idx": 5}, {"solution": "def big_diff(numbers):\n \"\"\"\n This function calculates the difference between the largest and smallest numbers in a given list.\n\n Args:\n numbers (list): A list of integers.\n\n Returns:\n int: The difference between the largest and smallest numbers in the list.\n\n Raises:\n ValueError: If the list is empty.\n \"\"\"\n if not numbers:\n raise ValueError(\"List cannot be empty\")\n return max(numbers) - min(numbers)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n \"\"\"\n Calculate the difference between the largest and smallest value in a list of numbers.\n\n Args:\n - nums (list): A list of integers.\n\n Returns:\n - int: The difference between the largest and smallest value in the list.\n\n Raises:\n - ValueError: If the input list is empty.\n \"\"\"\n if len(nums) == 0:\n raise ValueError(\"Input list cannot be empty\")\n\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(lst):\n \"\"\"\n This function calculates the difference between the largest and smallest values in a given list.\n\n Args:\n lst (list): A list of integers.\n\n Returns:\n int: The difference between the largest and smallest values in the list.\n \"\"\"\n return max(lst) - min(lst)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n \"\"\"\n Calculate the difference between the largest and smallest value in a list.\n\n Args:\n nums (list): A list of integers.\n\n Returns:\n int: The difference between the largest and smallest value in the list.\n\n Raises:\n ValueError: If the input list is empty.\n \"\"\"\n\n # Check if the list is not empty\n if not nums:\n raise ValueError(\"Input list cannot be empty\")\n\n # Calculate the difference between the largest and smallest value in the list\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n \"\"\"\n Calculate the difference between the largest and smallest values in a list.\n\n Args:\n nums (list): A list of numbers.\n\n Returns:\n int: The difference between the largest and smallest values.\n \"\"\"\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n \"\"\"\n This function finds the difference between the largest and smallest values in a given list.\n\n Args:\n nums (list): A list of numbers.\n\n Returns:\n int: The difference between the largest and smallest values.\n\n Raises:\n ValueError: If the input list is empty or does not contain at least two elements.\n \"\"\"\n\n # Check if the input list is valid\n if len(nums) < 2:\n raise ValueError(\"The input list must contain at least two elements.\")\n\n # Find the smallest and largest values in the list\n smallest = min(nums)\n largest = max(nums)\n\n # Return the difference\n return largest - smallest", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n \"\"\"\n This function calculates the difference between the largest and smallest values in a given list.\n\n Args:\n nums (list): A list of numbers.\n\n Returns:\n int: The difference between the largest and smallest values in the list.\n\n Raises:\n ValueError: If the input list is empty.\n \"\"\"\n if len(nums) == 0:\n raise ValueError(\"Input list is empty\")\n\n return max(nums) - min(nums)", "matching_cluster_idx": 5}]}, "Mbpp/592": {"dps": 66.90909090909092, "dps_norm": 57.27272727272727, "pass@1": 11.0, "profiled": [{"solution": "import math\ndef sum_Of_product(n):\n \"\"\"\n This function calculates the sum of the product of consecutive binomial coefficients.\n \n The binomial coefficients are the coefficients of the terms in the expansion of (a + b)^n.\n For example, for n=3, the binomial coefficients are 1, 3, 3, 1.\n\n Args:\n n (int): The power of the binomial expansion.\n\n Returns:\n int: The sum of the product of consecutive binomial coefficients.\n \"\"\"\n # Initialize the sum\n total_sum = 0\n \n # Iterate over all possible pairs of consecutive binomial coefficients\n for i in range(n):\n # Calculate the binomial coefficients using the math.comb function\n coeff1 = math.comb(n, i)\n coeff2 = math.comb(n, i+1)\n \n # Add the product of the coefficients to the total sum\n total_sum += coeff1 * coeff2\n \n return total_sum", "matching_cluster_idx": 4}, {"solution": "import math\ndef sum_Of_product(n):\n \"\"\"\n This function calculates the sum of the product of consecutive binomial coefficients.\n \n Args:\n n (int): The number of terms.\n\n Returns:\n int: The sum of the product of consecutive binomial coefficients.\n \"\"\"\n sum_of_product = 0\n for i in range(1, n + 1):\n # Calculate the binomial coefficient\n coefficient1 = math.comb(n, i - 1)\n coefficient2 = math.comb(n, i)\n \n # Add the product to the sum\n sum_of_product += coefficient1 * coefficient2\n \n return sum_of_product", "matching_cluster_idx": 5}, {"solution": "import math\ndef sum_Of_product(n):\n \"\"\"\n This function calculates the sum of the product of consecutive binomial coefficients\n from (0,0) to (n, n). For example, sum_Of_product(3) would calculate \n (3 choose 0) * (3 choose 1) + (3 choose 1) * (3 choose 2) + (3 choose 2) * (3 choose 3).\n \n Parameters:\n n (int): Input number\n \n Returns:\n int: Sum of the products of consecutive binomial coefficients\n \"\"\"\n # Initialize sum variable\n total_sum = 0\n \n # Iterate from k=0 to n-1\n for k in range(n):\n # Calculate binomial coefficients and their product, then add to total sum\n total_sum += math.comb(n, k) * math.comb(n, k + 1)\n \n return total_sum", "matching_cluster_idx": 5}, {"solution": "import math\ndef sum_Of_product(n):\n \"\"\"\n Calculate the sum of the product of consecutive binomial co-efficients.\n\n This function calculates the sum of products of consecutive binomial co-efficients\n for the first 'n' coefficients. It uses the math.comb function to calculate the\n binomial co-efficients and then sums the product of all pairs.\n\n Args:\n n (int): The number of binomial co-efficients to consider.\n\n Returns:\n int: The sum of the product of consecutive binomial co-efficients.\n\n Examples:\n >>> sum_Of_product(3)\n 15\n \"\"\"\n\n # Initialize the sum\n total_sum = 0\n \n # Iterate over the range of 'n'\n for i in range(1, n + 1):\n # Calculate the product of binomial co-efficients\n product = math.comb(n, i - 1) * math.comb(n, i)\n \n # Add the product to the total sum\n total_sum += product\n \n # Return the total sum\n return total_sum", "matching_cluster_idx": 5}, {"solution": "import math\ndef sum_Of_product(n):\n \"\"\"\n This function calculates the sum of the product of consecutive binomial coefficients.\n \n The function takes an integer 'n' as input, calculates the binomial coefficients \n and their products, then sums these products.\n \n Parameters:\n n (int): The input integer\n \n Returns:\n int: The sum of the product of consecutive binomial coefficients\n \n Example:\n sum_Of_product(3) returns 15, because the sum of product of consecutive binomial coefficients \n for n=3 is: (1*3) + (3*3) + (3*1) = 15.\n \"\"\"\n \n total_sum = 0 # Initialize the sum variable to zero\n \n for i in range(n + 1):\n # For each 'i' in the range from 0 to n (inclusive)\n \n # Calculate the binomial coefficient using math.comb function (Python 3.8+)\n coefficient_i = math.comb(n, i)\n \n # Calculate the binomial coefficient for 'i+1' or 'n-i' since comb(n, i) is same as comb(n, n-i)\n coefficient_next = math.comb(n, i + 1) if i < n else 0\n \n # Multiply the two coefficients and add to the total sum\n total_sum += coefficient_i * coefficient_next\n \n return total_sum", "matching_cluster_idx": 4}, {"solution": "import math\ndef sum_Of_product(n):\n \"\"\"\n This function calculates the sum of products of consecutive binomial coefficients.\n \n The formula for the sum of products of consecutive binomial coefficients is \n the sum of nCr * (nCr+1) from r = 0 to n-1 where nCr represents the binomial \n coefficient (n choose r).\n \n Args:\n n (int): The input number for the binomial coefficients.\n\n Returns:\n int: The sum of products of consecutive binomial coefficients.\n\n Example:\n >>> sum_Of_product(3)\n 15\n \"\"\"\n\n # Initialize the sum as 0\n total_sum = 0\n\n # Loop through all possible values of r from 0 to n-1\n for r in range(n):\n # Calculate the binomial coefficients nCr and nCr+1\n nCr = math.comb(n, r)\n nCr_plus1 = math.comb(n, r + 1)\n \n # Calculate the product of nCr and nCr+1 and add it to the total sum\n total_sum += nCr * nCr_plus1\n\n return total_sum", "matching_cluster_idx": 5}, {"solution": "import math\ndef sum_Of_product(n):\n \"\"\"\n Calculate the sum of the product of consecutive binomial coefficients.\n\n Args:\n n (int): The number of binomial coefficients to consider.\n\n Returns:\n int: The sum of the product of consecutive binomial coefficients.\n\n \"\"\"\n sum_of_products = 0\n for k in range(1, n + 1):\n # Calculate binomial coefficients using math.comb (Python 3.8+)\n # or math.factorial for earlier versions\n # Here we use math.comb\n binom_coef = math.comb(n, k)\n \n # Calculate product of consecutive binomial coefficients\n product = binom_coef * math.comb(n, k - 1)\n \n # Add the product to the sum\n sum_of_products += product\n\n return sum_of_products", "matching_cluster_idx": 4}, {"solution": "import math\ndef sum_Of_product(n):\n \"\"\"\n Calculate the sum of products of consecutive binomial coefficients.\n\n Args:\n n (int): The maximum value of n in the binomial coefficients.\n\n Returns:\n int: The sum of products of consecutive binomial coefficients.\n\n Example:\n >>> sum_Of_product(3)\n 15\n \"\"\"\n total = 0\n for i in range(n):\n # Calculate binomial coefficient\n binomial_coeff = math.comb(n, i)\n \n # Multiply with the next binomial coefficient and add to total\n if i < n:\n total += binomial_coeff * math.comb(n, i + 1)\n \n return total", "matching_cluster_idx": 5}, {"solution": "import math\ndef sum_Of_product(n):\n \"\"\"\n Calculate the sum of the product of consecutive binomial coefficients.\n\n The function takes an integer 'n' as input and calculates the sum of \n products of all pairs of consecutive binomial coefficients from 0 to 'n'.\n\n Args:\n n (int): The upper limit of binomial coefficients.\n\n Returns:\n int: The sum of the product of consecutive binomial coefficients.\n \"\"\"\n total_sum = 0\n for i in range(n):\n # Calculate the current binomial coefficient\n curr_coefficient = math.comb(n, i)\n \n # Calculate the next binomial coefficient\n next_coefficient = math.comb(n, i + 1) if i < n else 0\n \n # Multiply the coefficients and add to the total sum\n total_sum += curr_coefficient * next_coefficient\n \n return total_sum", "matching_cluster_idx": 4}, {"solution": "import math\ndef sum_Of_product(n):\n \"\"\"\n Calculate the sum of the product of consecutive binomial coefficients.\n\n The function generates binomial coefficients from 0 to n, calculates the product \n of each consecutive pair, and sums them up.\n\n Args:\n n (int): The number of terms to calculate.\n\n Returns:\n int: The sum of the products of consecutive binomial coefficients.\n \"\"\"\n total_sum = 0\n prev_coeff = 1 # Initialize the first binomial coefficient\n for i in range(1, n + 1):\n # Calculate binomial coefficient using math.comb (Python 3.8+)\n current_coeff = math.comb(n, i)\n \n # Multiply the current coefficient with the previous one and add to the total sum\n total_sum += prev_coeff * current_coeff\n \n # Update the previous coefficient for the next iteration\n prev_coeff = current_coeff\n \n return total_sum", "matching_cluster_idx": 7}, {"solution": "import math\ndef sum_Of_product(n):\n \"\"\"\n This function calculates the sum of the product of consecutive binomial coefficients.\n \n The sum is calculated using the mathematical formula: \n sum(k=0 to n) (n choose k) * (n choose k+1)\n \n Args:\n n (int): The input number for calculating the sum of products.\n \n Returns:\n int: The sum of the product of consecutive binomial coefficients.\n \"\"\"\n total_sum = 0\n for k in range(n):\n # Calculate binomial coefficient (n choose k) and (n choose k+1) using math.comb\n binom_coeff1 = math.comb(n, k)\n binom_coeff2 = math.comb(n, k + 1)\n # Multiply the coefficients and add to the total sum\n total_sum += binom_coeff1 * binom_coeff2\n return total_sum", "matching_cluster_idx": 4}]}, "Mbpp/597": {"dps": 95.0, "dps_norm": 95.0, "pass@1": 60.0, "profiled": [{"solution": "def find_kth(arr1, arr2, k):\n \"\"\"\n Find kth element from two sorted arrays.\n\n Args:\n arr1 (list): First sorted array\n arr2 (list): Second sorted array\n k (int): Index of the desired element in the merged array (1-indexed)\n\n Returns:\n int: The kth element from the merged array\n \"\"\"\n # Merge the two sorted arrays into one\n merged = sorted(arr1 + arr2)\n \n # Adjust k for 0-indexing\n k -= 1\n \n # Check if k is within bounds\n if k < 0 or k >= len(merged):\n raise IndexError(\"k is out of range\")\n \n # Return the kth element\n return merged[k]", "matching_cluster_idx": 3}, {"solution": "def find_kth(arr1, arr2, k):\n \"\"\"\n Find kth element from two given sorted arrays.\n\n Args:\n arr1 (list): The first sorted array.\n arr2 (list): The second sorted array.\n k (int): The index of the desired element (1-indexed).\n\n Returns:\n int: The kth element from the combined array.\n\n Raises:\n ValueError: If k is less than 1 or greater than the combined length of the arrays.\n \"\"\"\n if k < 1 or k > len(arr1) + len(arr2):\n raise ValueError(\"k is out of range\")\n\n # Merge the two arrays\n merged = sorted(arr1 + arr2)\n\n # Since Python is 0-indexed, subtract 1 from k\n return merged[k - 1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(arr1, arr2, k):\n \"\"\"\n Find the kth element in the merged sorted array from two given sorted arrays.\n \n Args:\n arr1 (list): First sorted array\n arr2 (list): Second sorted array\n k (int): Position of the element to find (1-indexed)\n \n Returns:\n int: The kth element in the merged sorted array.\n \n Raises:\n ValueError: If k is less than 1 or greater than the total length of both arrays\n \"\"\"\n if k < 1 or k > len(arr1) + len(arr2):\n raise ValueError(\"k is out of bounds\")\n \n # Merge and sort the arrays\n merged = sorted(arr1 + arr2)\n \n # Return the kth element (adjusting for 0-indexing)\n return merged[k - 1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(arr1, arr2, k):\n \"\"\"\n Find kth element from two sorted arrays.\n\n This function merges two sorted arrays and returns the kth element.\n\n Args:\n arr1 (list): The first sorted array.\n arr2 (list): The second sorted array.\n k (int): The index of the desired element (1-indexed).\n\n Returns:\n int: The kth element from the combined array.\n\n Raises:\n ValueError: If k is less than 1 or greater than the total length of the two arrays.\n \"\"\"\n\n # Check if k is within valid range\n if k < 1 or k > len(arr1) + len(arr2):\n raise ValueError(\"k is out of range\")\n\n # Merge and sort the two arrays\n merged = sorted(arr1 + arr2)\n\n # Return the kth element (adjusting for 0-indexing)\n return merged[k - 1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(arr1, arr2, k):\n \"\"\"\n Find kth element from the given two sorted arrays.\n \n The idea is to merge the two sorted arrays and then select the kth element.\n \n Parameters:\n arr1 (list): First sorted array\n arr2 (list): Second sorted array\n k (int): Index of the element to find (1-indexed)\n \n Returns:\n int: Kth element from the two sorted arrays\n \"\"\"\n # Combine the two arrays and sort the result\n merged = sorted(arr1 + arr2)\n \n # Check if k is within the bounds of the merged array\n if k < 1 or k > len(merged):\n raise ValueError(\"k is out of range\")\n \n # Select the kth element (adjust index to 0-indexed)\n return merged[k - 1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(array1, array2, k):\n \"\"\"\n This function finds the kth element in the combined sorted array of array1 and array2.\n \n Args:\n array1 (list): The first sorted array.\n array2 (list): The second sorted array.\n k (int): The index of the desired element (1-indexed).\n\n Returns:\n int: The kth element in the combined sorted array.\n\n Raises:\n ValueError: If k is less than 1 or greater than the total number of elements.\n \"\"\"\n\n # Combine the two arrays\n combined = array1 + array2\n \n # Check if k is within the bounds\n if k < 1 or k > len(combined):\n raise ValueError(\"k is out of range\")\n\n # Sort the combined array\n combined.sort()\n\n # Return the kth element (adjust for 0-indexing)\n return combined[k - 1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(arr1, arr2, k):\n \"\"\"\n Find kth element from two sorted arrays.\n\n Args:\n arr1 (list): First sorted array.\n arr2 (list): Second sorted array.\n k (int): The position of element to be found.\n\n Returns:\n int: The kth element in the combined sorted array.\n \"\"\"\n # Combine the two arrays\n combined = arr1 + arr2\n \n # Sort the combined array\n combined.sort()\n \n # Since list index starts from 0, subtract 1 from k\n return combined[k - 1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(arr1, arr2, k):\n \"\"\"\n Find the kth element from the given two sorted arrays.\n\n The function merges the two arrays into a single sorted array and then returns the kth element.\n\n Args:\n arr1 (list): The first sorted array.\n arr2 (list): The second sorted array.\n k (int): The position of the element to find (1-indexed).\n\n Returns:\n int: The kth element from the merged array.\n\n Raises:\n ValueError: If k is larger than the total length of the two arrays.\n \"\"\"\n # Check if k is valid\n if k > len(arr1) + len(arr2):\n raise ValueError(\"k is larger than the total length of the two arrays\")\n\n # Merge the two arrays into a single sorted array\n merged = sorted(arr1 + arr2)\n\n # Return the kth element (k is 1-indexed, so subtract 1)\n return merged[k - 1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(arr1, arr2, k):\n \"\"\"\n Finds the kth element from two sorted arrays.\n\n Args:\n arr1 (list): First sorted array.\n arr2 (list): Second sorted array.\n k (int): Index of the element to find (1-indexed).\n\n Returns:\n int: The kth element from the combined sorted array.\n \"\"\"\n # Combine the two arrays and sort the result\n combined = sorted(arr1 + arr2)\n\n # Check if k is within the bounds of the combined array\n if k < 1 or k > len(combined):\n raise ValueError(\"k is out of range\")\n\n # Return the kth element (adjust index for 0-based indexing)\n return combined[k - 1]", "matching_cluster_idx": 3}, {"solution": "import heapq\ndef find_kth(nums1, nums2, k):\n \"\"\"\n Find the kth element from two sorted arrays.\n\n Args:\n nums1 (list): The first sorted array.\n nums2 (list): The second sorted array.\n k (int): The index of the desired element (1-indexed).\n\n Returns:\n int: The kth element from the combined and sorted array.\n\n Raises:\n ValueError: If k is larger than the total length of both arrays.\n \"\"\"\n if k > len(nums1) + len(nums2):\n raise ValueError(\"k is larger than the total length of both arrays\")\n\n return heapq.nsmallest(k, nums1 + nums2)[-1]", "matching_cluster_idx": -1}, {"solution": "def find_kth(arr1, arr2, k):\n \"\"\"\n Find the kth element from two sorted arrays.\n\n :param arr1: First sorted array.\n :param arr2: Second sorted array.\n :param k: Index of desired element (1-indexed).\n :return: The kth element.\n \"\"\"\n # Merge the two arrays into a single sorted array\n merged = sorted(arr1 + arr2)\n \n # Check if k is within bounds\n if k < 1 or k > len(merged):\n raise ValueError(\"k is out of bounds\")\n \n # Return the kth element (adjusting for 0-indexing)\n return merged[k - 1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(arr1, arr2, k):\n \"\"\"\n Find the kth element from the given two sorted arrays.\n \n This function merges two sorted arrays into a single sorted array and returns the kth element.\n \n Parameters:\n arr1 (list): The first sorted array\n arr2 (list): The second sorted array\n k (int): The position of the element to be found\n \n Returns:\n int: The kth element from the merged sorted array\n \"\"\"\n # Combine both arrays into one\n merged = arr1 + arr2\n \n # Sort the combined array\n merged.sort()\n \n # Since lists in python are 0-indexed, subtract 1 from k\n return merged[k - 1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(arr1, arr2, k):\n \"\"\"\n Find the kth element from the given two sorted arrays.\n \n Args:\n arr1 (list): First sorted array.\n arr2 (list): Second sorted array.\n k (int): The index of the desired element (1-indexed).\n\n Returns:\n int: The kth element from the combined sorted array.\n \"\"\"\n # Check for invalid inputs\n if not arr1 and not arr2:\n raise ValueError(\"Both arrays cannot be empty\")\n if k < 1 or k > len(arr1) + len(arr2):\n raise ValueError(\"k is out of range\")\n\n # Merge two sorted arrays into one sorted array\n merged = sorted(arr1 + arr2)\n \n # Return the kth element (adjust k to 0-indexed)\n return merged[k - 1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(arr1, arr2, k):\n \"\"\"\n Find kth element from the given two sorted arrays.\n\n This function merges two sorted arrays and returns the kth element.\n \n Parameters:\n arr1 (list): The first sorted array.\n arr2 (list): The second sorted array.\n k (int): The index of the desired element (1-indexed).\n\n Returns:\n int: The kth element from the merged array.\n\n Raises:\n ValueError: If k is less than 1 or greater than the total length of both arrays.\n \"\"\"\n if k < 1 or k > len(arr1) + len(arr2):\n raise ValueError(\"k is out of range\")\n\n # Merge the two sorted arrays\n merged = sorted(arr1 + arr2)\n\n # Return the kth element (adjusting for 0-indexing)\n return merged[k - 1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(array1, array2, k):\n \"\"\"\n This function finds the kth element from two sorted arrays.\n \n Parameters:\n array1 (list): The first sorted array.\n array2 (list): The second sorted array.\n k (int): The index of the desired element (1-indexed).\n \n Returns:\n int: The kth element from the two sorted arrays.\n \"\"\"\n # Merge the two arrays into one sorted array\n merged_array = sorted(array1 + array2)\n \n # Check if k is within the bounds of the merged array\n if k < 1 or k > len(merged_array):\n raise ValueError(\"k is out of bounds\")\n \n # Return the kth element (k is 1-indexed, so subtract 1)\n return merged_array[k - 1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(arr1, arr2, k):\n \"\"\"\n Find kth element from the given two sorted arrays.\n\n :param arr1: First sorted array.\n :type arr1: list\n :param arr2: Second sorted array.\n :type arr2: list\n :param k: The index of the desired element (1-indexed).\n :type k: int\n :return: kth element from the combined array.\n :rtype: int\n :raises ValueError: If k is less than 1 or larger than the total number of elements.\n \"\"\"\n if k < 1 or k > len(arr1) + len(arr2):\n raise ValueError(\"k is out of range\")\n\n # Combine the two sorted arrays into one\n combined = sorted(arr1 + arr2)\n\n # Return the kth element (adjust for 0-indexing)\n return combined[k - 1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(arr1, arr2, k):\n \"\"\"\n This function finds the kth element from two given sorted arrays.\n\n It merges the two arrays into one sorted array and returns the kth element.\n\n Args:\n arr1 (list): The first sorted array.\n arr2 (list): The second sorted array.\n k (int): The position of the element to be found.\n\n Returns:\n int: The kth element from the merged array.\n\n Raises:\n ValueError: If k is less than 1 or greater than the total length of the two arrays.\n \"\"\"\n if k < 1 or k > len(arr1) + len(arr2):\n raise ValueError(\"k is out of range\")\n\n # Merge the two sorted arrays into one sorted array\n merged = sorted(arr1 + arr2)\n\n # Return the kth element from the merged array\n return merged[k - 1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(arr1, arr2, k):\n \"\"\"\n Find kth element from the given two sorted arrays.\n\n Args:\n arr1 (list): First sorted array.\n arr2 (list): Second sorted array.\n k (int): Index of the desired element.\n\n Returns:\n int: The kth element from the combined sorted array.\n\n Raises:\n ValueError: If k is larger than the combined length of both arrays.\n \"\"\"\n if k < 1 or k > len(arr1) + len(arr2):\n raise ValueError(\"k is out of range\")\n\n # Combine both arrays into one\n combined = arr1 + arr2\n \n # Sort the combined array\n combined.sort()\n \n # Return the kth element\n return combined[k-1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(arr1, arr2, k):\n \"\"\"\n This function merges two sorted arrays and finds the kth element.\n \n Parameters:\n arr1 (list): First sorted array\n arr2 (list): Second sorted array\n k (int): Position of element to be found\n \n Returns:\n int: The kth element from the merged array\n \"\"\"\n \n # Merge the two sorted arrays into one\n merged = sorted(arr1 + arr2)\n \n # Check if k is within the range of the merged array\n if k < 1 or k > len(merged):\n raise IndexError(\"k is out of range\")\n \n # Return the kth element (k is 1-indexed)\n return merged[k - 1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(arr1, arr2, k):\n \"\"\"\n This function merges two sorted arrays into a single sorted array and \n returns the kth element.\n\n Args:\n arr1 (list): The first sorted array.\n arr2 (list): The second sorted array.\n k (int): The index of the desired element (1-indexed).\n\n Returns:\n int: The kth element from the merged array.\n \"\"\"\n\n # Combine both arrays into a single array\n merged = arr1 + arr2\n\n # Sort the merged array in ascending order\n merged.sort()\n\n # Check if k is within the bounds of the merged array\n if k < 1 or k > len(merged):\n raise IndexError(\"k is out of bounds\")\n\n # Return the kth element (adjusting for 0-based indexing)\n return merged[k-1]", "matching_cluster_idx": 3}]}, "Mbpp/604": {"dps": 47.5, "dps_norm": 89.0, "pass@1": 98.0, "profiled": [{"solution": "def reverse_words(input_string):\n \"\"\"\n Reverses the order of words in a given string.\n \n Args:\n input_string (str): Input string containing words separated by spaces.\n \n Returns:\n str: A new string with words in reversed order.\n \"\"\"\n # Split the input string into a list of words\n words = input_string.split()\n \n # Reverse the list of words\n reversed_words = words[::-1]\n \n # Join the reversed list of words back into a string separated by spaces\n reversed_string = ' '.join(reversed_words)\n \n return reversed_string", "matching_cluster_idx": 4}, {"solution": "def reverse_words(input_string):\n \"\"\"\n Reverses the order of words in a given string.\n\n Args:\n input_string (str): The input string containing words separated by spaces.\n\n Returns:\n str: The string with the words in reversed order.\n\n Examples:\n >>> reverse_words(\"python program\")\n 'program python'\n \"\"\"\n words = input_string.split()\n reversed_words = ' '.join(reversed(words))\n return reversed_words", "matching_cluster_idx": 4}, {"solution": "def reverse_words(input_str):\n \"\"\"\n This function takes a string as an input and returns the words in reverse order.\n\n Args:\n input_str (str): The input string with words separated by spaces.\n\n Returns:\n str: The words in the input string in reverse order.\n \"\"\"\n # Split the input string into a list of words\n words = input_str.split()\n\n # Reverse the list of words\n reversed_words = words[::-1]\n\n # Join the reversed list of words back into a string separated by spaces\n reversed_str = ' '.join(reversed_words)\n\n return reversed_str", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n \"\"\"\n This function takes a string of words separated by spaces as an input,\n reverses their order and returns the resulting string.\n\n Args:\n s (str): Input string.\n\n Returns:\n str: String with reversed word order.\n\n Raises:\n ValueError: If input is not a string.\n \"\"\"\n\n # Validate input\n if not isinstance(s, str):\n raise ValueError(\"Input must be a string\")\n\n # Split input string into words\n words = s.split()\n\n # Reverse the list of words\n reversed_words = words[::-1]\n\n # Join reversed words back into a string separated by spaces\n reversed_string = ' '.join(reversed_words)\n\n return reversed_string", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n \"\"\"\n Reverses the order of words in a given string.\n\n Args:\n s (str): The input string.\n\n Returns:\n str: A string with words in reversed order.\n \"\"\"\n return ' '.join(s.split()[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(input_string):\n \"\"\"\n Reverses the order of words separated by spaces in a given string.\n\n Args:\n input_string (str): The input string to reverse.\n\n Returns:\n str: A string with the words in reverse order.\n \"\"\"\n words = input_string.split()\n reversed_words = ' '.join(reversed(words))\n return reversed_words", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n \"\"\"\n This function takes a string of words separated by spaces as input and returns the string with words in reversed order.\n \n Parameters:\n s (str): The input string.\n \n Returns:\n str: The string with words in reversed order.\n \"\"\"\n # Split the string into a list of words\n words = s.split()\n \n # Reverse the list of words\n reversed_words = words[::-1]\n \n # Join the reversed list of words into a string\n reversed_s = ' '.join(reversed_words)\n \n return reversed_s", "matching_cluster_idx": 3}, {"solution": "def reverse_words(input_string):\n \"\"\"\n This function takes a string of words separated by spaces and returns a new string \n where the order of the words is reversed.\n\n Args:\n input_string (str): The input string with words separated by spaces.\n\n Returns:\n str: A new string where the order of the words is reversed.\n \"\"\"\n words = input_string.split() # Split the string into a list of words\n reversed_words = ' '.join(reversed(words)) # Reverse the order and join them back into a string\n return reversed_words", "matching_cluster_idx": 3}, {"solution": "def reverse_words(s):\n \"\"\"\n Reverses the order of words in a given string.\n\n Args:\n s (str): The input string with words separated by spaces.\n\n Returns:\n str: A string with words in reversed order.\n\n \"\"\"\n words = s.split()\n words.reverse()\n return ' '.join(words)", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n \"\"\"\n This function takes a string as input and returns a new string \n where the order of words is reversed.\n\n Args:\n s (str): The input string.\n\n Returns:\n str: The string with words reversed.\n \"\"\"\n # Split the string into a list of words\n words = s.split()\n\n # Reverse the list of words\n reversed_words = words[::-1]\n\n # Join the reversed list into a string\n reversed_string = ' '.join(reversed_words)\n\n return reversed_string", "matching_cluster_idx": 3}, {"solution": "def reverse_words(input_string):\n \"\"\"\n Reverses words separated by spaces in a given string.\n\n Args:\n input_string (str): A string containing words separated by spaces.\n\n Returns:\n str: A string with the words in the reverse order.\n \"\"\"\n # Split the input string into a list of words\n words = input_string.split()\n \n # Reverse the list of words\n reversed_words = words[::-1]\n \n # Join the reversed list of words back into a string\n reversed_string = ' '.join(reversed_words)\n \n return reversed_string", "matching_cluster_idx": 3}, {"solution": "def reverse_words(input_string):\n \"\"\"\n Reverses the order of words in a given string.\n\n Args:\n input_string (str): Input string with words separated by spaces.\n\n Returns:\n str: String with the words in reversed order.\n \"\"\"\n words = input_string.split() # split the string into words\n reversed_words = ' '.join(reversed(words)) # reverse and join the words\n return reversed_words", "matching_cluster_idx": 3}, {"solution": "def reverse_words(s):\n \"\"\"\n Reverses the order of words in a given string.\n\n Args:\n s (str): Input string with words separated by spaces.\n\n Returns:\n str: String with words reversed.\n \"\"\"\n words = s.split() # Split the string into a list of words\n reversed_words = ' '.join(reversed(words)) # Reverse the list and join it back into a string\n return reversed_words", "matching_cluster_idx": 3}, {"solution": "def reverse_words(s):\n \"\"\"\n This function takes a string of space-separated words and returns a new string \n with the words in reverse order.\n\n Args:\n s (str): The input string.\n\n Returns:\n str: The string with words reversed.\n \"\"\"\n # Split the string into a list of words\n words = s.split()\n\n # Reverse the list of words\n reversed_words = words[::-1]\n\n # Join the words back into a string with spaces in between\n reversed_string = ' '.join(reversed_words)\n\n return reversed_string", "matching_cluster_idx": 3}, {"solution": "def reverse_words(input_str):\n \"\"\"\n Reverses the order of words in a given string.\n\n Args:\n input_str (str): The input string with words separated by spaces.\n\n Returns:\n str: A new string with words in reversed order.\n\n Example:\n >>> reverse_words(\"python program\")\n 'program python'\n \"\"\"\n words = input_str.split() # Split the string into a list of words\n reversed_words = words[::-1] # Reverse the list of words\n reversed_str = ' '.join(reversed_words) # Join the words back into a string\n return reversed_str", "matching_cluster_idx": 3}, {"solution": "def reverse_words(s):\n \"\"\"\n Reverses the order of words separated by spaces in a given string.\n\n Args:\n s (str): Input string\n\n Returns:\n str: String with words in reversed order\n\n Example:\n >>> reverse_words(\"python program\")\n 'program python'\n \"\"\"\n words = s.split()\n words.reverse()\n return ' '.join(words)", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n \"\"\"\n Reverses the order of words in a given string.\n\n Args:\n s (str): The input string.\n\n Returns:\n str: The input string with words reversed.\n \"\"\"\n words = s.split() # split the string into a list of words\n words.reverse() # reverse the list of words\n return ' '.join(words) # join the reversed list back into a string", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n \"\"\"\n Reverses the order of words in a given string.\n\n Args:\n s (str): Input string with words separated by spaces.\n\n Returns:\n str: String with words reversed.\n \"\"\"\n words = s.split() # Split the string into a list of words\n reversed_words = words[::-1] # Reverse the list of words\n reversed_s = ' '.join(reversed_words) # Join the reversed list back into a string\n return reversed_s", "matching_cluster_idx": 3}, {"solution": "def reverse_words(s):\n \"\"\"\n This function takes a string of words separated by spaces as input, \n and returns a new string with the words in reverse order.\n\n Args:\n s (str): Input string\n\n Returns:\n str: String with words reversed\n \"\"\"\n return ' '.join(reversed(s.split()))", "matching_cluster_idx": 3}, {"solution": "def reverse_words(input_string):\n \"\"\"\n Function to reverse words separated by spaces in a given string.\n\n Args:\n input_string (str): Input string with words separated by spaces.\n\n Returns:\n str: String with words reversed.\n \"\"\"\n words = input_string.split() # Split input string into list of words\n reversed_words = ' '.join(reversed(words)) # Reverse the list and join back into string\n return reversed_words", "matching_cluster_idx": 3}]}, "Mbpp/610": {"dps": 58.69565217391305, "dps_norm": 57.142857142857146, "pass@1": 86.0, "profiled": [{"solution": "def remove_kth_element(lst, k):\n \"\"\"\n Removes the k'th element from a given list and returns the resulting list.\n\n Args:\n lst (list): The input list.\n k (int): The index of the element to be removed (1-indexed).\n\n Returns:\n list: The list with the k'th element removed.\n \"\"\"\n if k < 1 or k > len(lst):\n raise IndexError(\"k is out of range\")\n return lst[:k-1] + lst[k:]", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(lst, k):\n \"\"\"\n Removes the k'th element from the list and returns the resulting list.\n \n The k is 1-indexed, i.e., the first element is at k=1.\n \n :param lst: The input list.\n :param k: The 1-indexed index of the element to remove.\n :return: A new list without the k'th element.\n \"\"\"\n if k < 1 or k > len(lst):\n raise ValueError(\"k is out of range\")\n \n return lst[:k-1] + lst[k:]", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(lst, k):\n \"\"\"\n Removes the k'th element from a list.\n\n Args:\n lst (list): Input list\n k (int): Index of the element to remove (1-indexed)\n\n Returns:\n list: Input list with the k'th element removed\n \"\"\"\n # Check if k is within valid range\n if k < 1 or k > len(lst):\n raise ValueError(\"k is out of range\")\n\n # Python uses 0-based indexing, so subtract 1 from k\n return lst[:k-1] + lst[k:]", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(lst, k):\n \"\"\"\n Removes the k'th element from the given list.\n\n Args:\n lst (list): The input list from which the k'th element is to be removed.\n k (int): The index of the element to be removed (1-indexed).\n\n Returns:\n list: The list with the k'th element removed.\n \"\"\"\n # Check if k is within the valid range\n if k < 1 or k > len(lst):\n raise IndexError(\"k is out of range\")\n\n # Use list slicing to create a new list that excludes the k'th element\n # Note that list indices are 0-based, so subtract 1 from k\n return lst[:k-1] + lst[k:]", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(lst, k):\n \"\"\"\n This function removes the k'th element from a given list.\n \n Parameters:\n lst (list): The input list from which the element will be removed.\n k (int): The position of the element to be removed (1-indexed).\n\n Returns:\n list: A new list with the k'th element removed.\n \"\"\"\n # Check if k is within bounds\n if k < 1 or k > len(lst):\n raise IndexError(\"k is out of range\")\n\n # Use list slicing to create a new list with the k'th element removed\n return lst[:k-1] + lst[k:]", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(lst, k):\n \"\"\"\n Removes the k'th element from a given list.\n\n Args:\n lst (list): Input list\n k (int): The position of the element to be removed (1-indexed)\n\n Returns:\n list: The input list with the k'th element removed\n \"\"\"\n # Check if k is valid\n if k < 1 or k > len(lst):\n raise ValueError(\"k is out of range\")\n\n # Convert k to 0-indexed\n k -= 1\n\n # Create a new list that includes all elements except the k'th\n return lst[:k] + lst[k+1:]", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(lst, k):\n \"\"\"\n Removes the k'th element from a given list.\n\n Args:\n lst (list): The input list.\n k (int): The index of the element to be removed (1-indexed).\n\n Returns:\n list: A new list with the k'th element removed.\n \"\"\"\n # Convert k to 0-indexed\n k -= 1\n \n # Use list slicing to create a new list without the k'th element\n return lst[:k] + lst[k+1:]", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(lst, k):\n \"\"\"\n Remove the k'th element from the given list.\n\n Args:\n lst (list): Input list.\n k (int): Index of element to be removed (1-indexed).\n\n Returns:\n list: New list with the k'th element removed.\n\n Raises:\n IndexError: If k is larger than the length of the list.\n \"\"\"\n if k < 1 or k > len(lst):\n raise IndexError(\"k is out of range\")\n\n return lst[:k-1] + lst[k:]", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(lst, k):\n \"\"\"\n Removes the k'th element from a list and returns the modified list.\n\n Args:\n lst (list): Input list.\n k (int): Index of the element to be removed (1-indexed).\n\n Returns:\n list: List with the k'th element removed.\n\n Raises:\n IndexError: If k is less than 1 or greater than the list length.\n \"\"\"\n\n if k < 1 or k > len(lst):\n raise IndexError(\"k is out of range\")\n\n # Convert k to 0-indexed for Python lists\n k -= 1\n\n # Use list slicing to remove the k'th element\n return lst[:k] + lst[k+1:]", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(input_list, k):\n \"\"\"\n This function takes an input list and returns the same list but with the k'th element removed.\n\n Args:\n input_list (list): Input list from which the k'th element will be removed.\n k (int): Index of the element to be removed (starts from 1).\n\n Returns:\n list: The input list with the k'th element removed.\n \"\"\"\n # Check if k is within the range of the list length.\n if k < 1 or k > len(input_list):\n raise ValueError(\"k is out of range\")\n\n # Create a copy of the input list and remove the k'th element.\n return input_list[:k-1] + input_list[k:]", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(input_list, k):\n \"\"\"\n Removes the k'th element from a given list.\n\n Args:\n input_list (list): A list of elements.\n k (int): The index of the element to be removed (1-indexed).\n\n Returns:\n list: A list with the same elements as input_list, but the k'th element removed.\n\n Raises:\n IndexError: If k is larger than the length of the list.\n \"\"\"\n if k < 1 or k > len(input_list):\n raise IndexError(\"k is out of range\")\n return input_list[:k-1] + input_list[k:]", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(lst, k):\n \"\"\"\n Removes the k'th element from a given list and returns the resulting list.\n\n Args:\n lst (list): The list from which to remove an element.\n k (int): The 1-based index of the element to remove.\n\n Returns:\n list: The input list with the k'th element removed.\n\n Raises:\n IndexError: If k is less than 1 or greater than the length of the list.\n \"\"\"\n if not isinstance(k, int) or k < 1:\n raise IndexError(\"k must be a positive integer\")\n if k > len(lst):\n raise IndexError(\"k cannot be greater than the length of the list\")\n\n return lst[:k - 1] + lst[k:]", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(lst, k):\n \"\"\"\n This function takes a list and returns a list with the same elements, \n but the k'th element removed.\n\n Parameters:\n lst (list): Input list\n k (int): Index of the element to be removed (1-indexed)\n\n Returns:\n list: List with the k'th element removed\n \"\"\"\n # Check if k is within the list's bounds\n if k < 1 or k > len(lst):\n raise IndexError(\"k is out of range\")\n\n # Remove the k'th element from the list\n return lst[:k-1] + lst[k:]", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(lst, k):\n \"\"\"\n Removes the k'th element from the given list.\n\n Args:\n lst (list): The input list.\n k (int): The index of the element to remove (1-indexed).\n\n Returns:\n list: The input list with the k'th element removed.\n\n Raises:\n ValueError: If k is less than 1 or greater than the length of the list.\n \"\"\"\n\n # Check if k is within the valid range\n if k < 1 or k > len(lst):\n raise ValueError(\"k is out of range\")\n\n # Since Python uses 0-indexing, subtract 1 from k\n k -= 1\n\n # Use list slicing to create a new list with the k'th element removed\n return lst[:k] + lst[k+1:]", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(input_list, k):\n \"\"\"\n This function takes a list and returns a list with the same elements, \n but the k'th element removed.\n\n Args:\n input_list (list): The input list of elements.\n k (int): The position of the element to be removed (1-indexed).\n\n Returns:\n list: The modified list with the k'th element removed.\n\n Raises:\n IndexError: If k is less than 1 or greater than the list length.\n \"\"\"\n\n # Check if k is within valid range\n if k < 1 or k > len(input_list):\n raise IndexError(\"k is out of range\")\n\n # Convert k to 0-indexed for Python list indexing\n k -= 1\n\n # Use list slicing to remove the k'th element\n return input_list[:k] + input_list[k+1:]", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(lst, k):\n \"\"\"\n This function removes the k'th element from the input list.\n\n Args:\n lst (list): Input list from which to remove the element.\n k (int): Index of the element to be removed (1-indexed).\n\n Returns:\n list: New list with the k'th element removed.\n\n Raises:\n ValueError: If k is less than 1 or greater than the list length.\n \"\"\"\n if not isinstance(k, int) or k < 1 or k > len(lst):\n raise ValueError(\"Invalid index k\")\n return lst[:k-1] + lst[k:]", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(lst, k):\n \"\"\"\n Returns a list with the same elements as the input list, but the k'th element removed.\n\n Args:\n lst (list): Input list\n k (int): Index of the element to remove (1-indexed)\n\n Returns:\n list: List with the k'th element removed\n\n Raises:\n IndexError: If k is larger than the list length\n \"\"\"\n if k < 1 or k > len(lst):\n raise IndexError(\"k is out of range\")\n\n return lst[:k-1] + lst[k:]", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(lst, k):\n \"\"\"\n Removes the k'th element from a given list.\n\n Args:\n lst (list): Input list from which to remove an element.\n k (int): The index of the element to be removed (1-indexed).\n\n Returns:\n list: A new list with the same elements, but the k'th element removed.\n\n Raises:\n IndexError: If the list has less than k elements.\n\n Examples:\n >>> remove_kth_element([1,1,2,3,4,4,5,1], 3)\n [1, 1, 2, 4, 4, 5, 1]\n \"\"\"\n if k > len(lst):\n raise IndexError(\"List has less than k elements\")\n return lst[:k-1] + lst[k:]", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(lst, k):\n \"\"\"\n Removes the k'th element from a given list.\n\n Args:\n lst (list): Input list\n k (int): Index of element to be removed\n\n Returns:\n list: List with k'th element removed\n \"\"\"\n # Validate input arguments\n if not isinstance(lst, list) or k < 1 or k > len(lst):\n raise ValueError(\"Invalid input arguments\")\n\n # Use list slicing to remove the k'th element\n return lst[:k-1] + lst[k:]", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(input_list, k):\n \"\"\"\n Removes the k'th element from the input list.\n\n Args:\n input_list (list): The input list from which to remove the k'th element.\n k (int): The index of the element to remove.\n\n Returns:\n list: The input list with the k'th element removed.\n\n Raises:\n IndexError: If k is out of range of the input list.\n \"\"\"\n # Validate k\n if k < 1 or k > len(input_list):\n raise IndexError('k out of range')\n\n # Remove the k'th element using list slicing\n return input_list[:k-1] + input_list[k:]", "matching_cluster_idx": 3}]}, "Mbpp/611": {"dps": null, "dps_norm": null, "pass@1": 6.0, "profiled": []}, "Mbpp/631": {"dps": 40.575396825396815, "dps_norm": 61.607142857142854, "pass@1": 14.0, "profiled": [{"solution": "def replace_spaces(input_string):\n \"\"\"\n Replaces all occurrences of whitespace with an underscore and vice versa in a given string.\n \n Args:\n input_string (str): The input string to be modified.\n \n Returns:\n str: The modified string with whitespace replaced with an underscore and vice versa.\n \"\"\"\n # Use the built-in string method 'translate' along with 'maketrans' to replace characters\n return input_string.translate(str.maketrans(' _', '_ '))", "matching_cluster_idx": 6}, {"solution": "def replace_spaces(input_string):\n \"\"\"\n This function replaces whitespaces with an underscore and vice versa in a given string.\n\n Args:\n input_string (str): The input string to be modified.\n\n Returns:\n str: The modified string with whitespaces replaced by underscores and vice versa.\n\n \"\"\"\n # Initialize an empty string to store the modified result\n result_string = \"\"\n\n # Iterate over each character in the input string\n for char in input_string:\n # Check if the character is a whitespace\n if char.isspace():\n # If it is, replace it with an underscore\n result_string += \"_\"\n # If the character is an underscore\n elif char == \"_\":\n # Replace it with a whitespace\n result_string += \" \"\n else:\n # If it is neither a whitespace nor an underscore, keep it as is\n result_string += char\n\n # Return the modified string\n return result_string", "matching_cluster_idx": 1}, {"solution": "def replace_spaces(s):\n \"\"\"\n This function replaces whitespaces with an underscore and vice versa in a given string.\n \n Parameters:\n s (str): The input string.\n \n Returns:\n str: The string with spaces replaced by underscores and vice versa.\n \"\"\"\n # Use the translate function along with str.maketrans to replace spaces and underscores\n translator = str.maketrans('_ ', ' _')\n return s.translate(translator)", "matching_cluster_idx": 6}, {"solution": "def replace_spaces(s):\n \"\"\"\n Replaces whitespaces with underscores and vice versa in a given string.\n \n Args:\n s (str): The input string.\n \n Returns:\n str: The modified string with whitespaces replaced by underscores and vice versa.\n \"\"\"\n return s.replace(' ', '_').replace('_', '#' ).replace('#', '_') if ' ' in s else s.replace('_', ' ').replace(' ', '_').replace('_', ' ')", "matching_cluster_idx": 4}, {"solution": "def replace_spaces(input_string, space_replacement='_', whitespace_replacement=' '):\n \"\"\"\n Replace whitespaces with space_replacement and space_replacement with whitespace_replacement in a given string.\n\n Args:\n input_string (str): The input string.\n space_replacement (str): The replacement for space. Defaults to '_'.\n whitespace_replacement (str): The replacement for space_replacement. Defaults to ' '.\n\n Returns:\n str: The modified string.\n \"\"\"\n # First, replace space_replacement with a temporary placeholder to avoid confusion\n temp_placeholder = '__temp__'\n temp_string = input_string.replace(space_replacement, temp_placeholder)\n \n # Then, replace the actual whitespace with space_replacement\n temp_string = temp_string.replace(' ', space_replacement)\n \n # Finally, replace the temporary placeholder with whitespace_replacement\n modified_string = temp_string.replace(temp_placeholder, whitespace_replacement)\n \n return modified_string", "matching_cluster_idx": 4}, {"solution": "def replace_spaces(input_string):\n \"\"\"\n This function replaces all whitespace characters in a string with underscores\n and vice versa.\n\n Args:\n input_string (str): The input string to replace characters in.\n\n Returns:\n str: A new string where whitespace characters have been replaced with underscores\n and vice versa.\n \"\"\"\n translator = str.maketrans({' ': '_', '_': ' '})\n return input_string.translate(translator)", "matching_cluster_idx": 6}, {"solution": "def replace_spaces(s):\n \"\"\"\n Replaces whitespaces with an underscore and vice versa in a given string.\n\n Args:\n s (str): The input string.\n\n Returns:\n str: The string with whitespaces replaced with underscores and vice versa.\n \"\"\"\n # Use the translate method along with maketrans to replace ' ' with '_' and '_' with ' '\n translator = str.maketrans(' _', '_ ')\n return s.translate(translator)", "matching_cluster_idx": 6}, {"solution": "def replace_spaces(s):\n \"\"\"\n Replaces whitespaces with underscores and vice versa in a given string.\n\n Args:\n s (str): The input string.\n\n Returns:\n str: The modified string.\n \"\"\"\n # Use the translate() function along with str.maketrans() to replace spaces with underscores and vice versa.\n translator = str.maketrans(' _', '_ ')\n return s.translate(translator)", "matching_cluster_idx": 6}, {"solution": "def replace_spaces(input_str):\n \"\"\"\n Replace whitespaces with an underscore and vice versa in a given string.\n\n Args:\n input_str (str): Input string to replace spaces in.\n\n Returns:\n str: Modified string with whitespaces replaced with underscores and vice versa.\n\n Examples:\n >>> replace_spaces('Jumanji The Jungle')\n 'Jumanji_The_Jungle'\n >>> replace_spaces('Jumanji_The_Jungle')\n 'Jumanji The Jungle'\n \"\"\"\n result_str = ''\n for char in input_str:\n if char.isspace():\n result_str += '_'\n elif char == '_':\n result_str += ' '\n else:\n result_str += char\n return result_str", "matching_cluster_idx": 1}, {"solution": "def replace_spaces(input_string):\n \"\"\"\n Replace whitespaces with an underscore and vice versa in a given string.\n\n :param input_string: Input string\n :return: A new string with whitespaces replaced with underscores and vice versa\n \"\"\"\n result = ''\n for char in input_string:\n if char.isspace():\n result += '_'\n elif char == '_':\n result += ' '\n else:\n result += char\n return result", "matching_cluster_idx": 1}, {"solution": "def replace_spaces(input_string):\n \"\"\"\n This function replaces spaces with underscores and vice versa in the given string.\n\n Args:\n input_string (str): Input string in which spaces need to be replaced.\n\n Returns:\n str: String with spaces and underscores replaced.\n \"\"\"\n result = \"\"\n for char in input_string:\n if char == \" \":\n result += \"_\"\n elif char == \"_\":\n result += \" \"\n else:\n result += char\n return result", "matching_cluster_idx": 2}, {"solution": "def replace_spaces(s):\n \"\"\"\n Replaces all whitespaces in a string with underscores and vice versa.\n\n Args:\n s (str): The input string.\n\n Returns:\n str: The input string with all whitespaces replaced with underscores and vice versa.\n \"\"\"\n result = ''\n for char in s:\n if char.isspace():\n result += '_'\n else:\n if char == '_':\n result += ' '\n else:\n result += char\n return result", "matching_cluster_idx": 1}, {"solution": "def replace_spaces(input_string):\n \"\"\"\n Replaces whitespaces with underscores and vice versa in a given string.\n\n Args:\n input_string (str): The input string to process.\n\n Returns:\n str: The processed string with whitespaces replaced with underscores and vice versa.\n \"\"\"\n translated_string = input_string.translate(str.maketrans({' ': '_', '_': ' '}))\n return translated_string", "matching_cluster_idx": 5}, {"solution": "def replace_spaces(s):\n \"\"\"\n This function replaces whitespaces with an underscore and vice versa in a given string.\n \n Parameters:\n s (str): The input string to replace spaces and underscores.\n \n Returns:\n str: A new string with spaces and underscores replaced.\n \"\"\"\n # Use the str.translate() method to replace spaces with underscores\n # and underscores with spaces in a single pass.\n translation_table = str.maketrans({' ': '_', '_': ' '})\n return s.translate(translation_table)", "matching_cluster_idx": 6}]}, "Mbpp/632": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def move_zero(lst):\n \"\"\"\n This function takes a list as input and returns a new list where all zeroes\n are moved to the end. The order of non-zero elements remains the same.\n\n Args:\n lst (list): The input list containing zeroes and non-zero elements.\n\n Returns:\n list: A new list with all zeroes moved to the end.\n \"\"\"\n return [x for x in lst if x != 0] + [0] * lst.count(0)", "matching_cluster_idx": 6}, {"solution": "def move_zero(lst):\n \"\"\"\n Move all zeroes to the end of the given list.\n \n Args:\n lst (list): Input list containing elements to be rearranged.\n \n Returns:\n list: Input list with all zeroes moved to the end.\n \"\"\"\n return [i for i in lst if i != 0] + [0] * lst.count(0)", "matching_cluster_idx": 6}, {"solution": "def move_zero(lst):\n \"\"\"\n Move all zeroes to the end of the given list.\n \n Args:\n lst (list): The input list that contains zeroes.\n \n Returns:\n list: The list with all zeroes at the end.\n \"\"\"\n return [i for i in lst if i != 0] + [0] * lst.count(0)", "matching_cluster_idx": 6}, {"solution": "def move_zero(lst):\n \"\"\"\n Move all zeroes to the end of the given list while preserving order of non-zero elements.\n\n Args:\n lst (list): List with zero and non-zero elements.\n\n Returns:\n list: List with all zeroes moved to the end.\n \"\"\"\n # Separate non-zero elements from the original list\n non_zero_elements = [element for element in lst if element != 0]\n \n # Create a list with zeros equal to the difference between the length of original list and non-zero list\n zeros = [0] * (len(lst) - len(non_zero_elements))\n \n # Return the combined list with non-zero elements first and zeros at the end\n return non_zero_elements + zeros", "matching_cluster_idx": 6}, {"solution": "def move_zero(lst):\n \"\"\"\n Move all zeroes to the end of the given list.\n\n Args:\n lst (list): The input list which may contain zeroes.\n\n Returns:\n list: The modified list with all zeroes moved to the end.\n \"\"\"\n return [x for x in lst if x != 0] + [0] * lst.count(0)", "matching_cluster_idx": 6}, {"solution": "def move_zero(lst):\n \"\"\"\n Move all zeroes to the end of the given list.\n\n Args:\n lst (list): The list to be modified.\n\n Returns:\n list: The modified list with all zeroes at the end.\n \"\"\"\n # Separate non-zero elements and zeroes\n non_zero = [i for i in lst if i != 0]\n zeroes = [i for i in lst if i == 0]\n \n # Combine the two lists\n return non_zero + zeroes", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n \"\"\"\n Move all zeroes to the end of the given list.\n \n Args:\n nums (list): A list containing integers.\n \n Returns:\n list: The input list with all zeroes moved to the end.\n \"\"\"\n return [x for x in nums if x != 0] + [0] * nums.count(0)", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n \"\"\"\n Move all zeroes to the end of the given list.\n \n Args:\n nums (list): The input list of integers.\n \n Returns:\n list: A list with all zeroes moved to the end.\n \"\"\"\n return [num for num in nums if num != 0] + [0] * nums.count(0)", "matching_cluster_idx": 6}, {"solution": "def move_zero(lst):\n \"\"\"\n Move all zeroes to the end of the given list.\n\n Args:\n lst (list): The input list to modify.\n\n Returns:\n list: A list with the same elements, but all zeroes moved to the end.\n \"\"\"\n # Initialize two lists: one for non-zero elements and one for zeroes\n non_zero = [x for x in lst if x != 0]\n zeros = [x for x in lst if x == 0]\n \n # Combine the two lists, with the non-zero elements first\n return non_zero + zeros", "matching_cluster_idx": 6}, {"solution": "def move_zero(lst):\n \"\"\"\n Move all zeroes to the end of the given list.\n\n Args:\n lst (list): A list containing integers.\n\n Returns:\n list: The input list with all zeroes moved to the end.\n \"\"\"\n return [i for i in lst if i != 0] + [i for i in lst if i == 0]", "matching_cluster_idx": 6}, {"solution": "def move_zero(lst):\n \"\"\"\n Move all zeroes to the end of a given list.\n\n Args:\n lst (list): A list that may contain zeroes.\n\n Returns:\n list: A list with the same elements, but with all zeroes moved to the end.\n \"\"\"\n return [i for i in lst if i != 0] + [0] * lst.count(0)", "matching_cluster_idx": 6}, {"solution": "def move_zero(lst):\n \"\"\"\n Move all zeroes to the end of the given list.\n\n Args:\n lst (list): Input list to process.\n\n Returns:\n list: List with all zeroes moved to the end.\n\n Example:\n >>> move_zero([1,0,2,0,3,4])\n [1,2,3,4,0,0]\n \"\"\"\n # Separate non-zero elements into a new list\n non_zero_elements = [i for i in lst if i != 0]\n\n # Get the count of zeroes from the original list\n zero_count = len(lst) - len(non_zero_elements)\n\n # Return the combined list of non-zero elements and zeroes\n return non_zero_elements + [0] * zero_count", "matching_cluster_idx": 6}, {"solution": "def move_zero(lst):\n \"\"\"\n Move all zeroes to the end of the given list.\n\n Args:\n lst (list): Input list that may contain zeroes.\n\n Returns:\n list: The input list with all zeroes moved to the end.\n \"\"\"\n return [i for i in lst if i != 0] + [0] * lst.count(0)", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n \"\"\"\n Move all zeroes to the end of the given list.\n\n Args:\n nums (list): A list of integers containing zeroes and non-zeroes.\n\n Returns:\n list: A list with the same elements as input, but with all zeroes moved to the end.\n \"\"\"\n non_zero = [x for x in nums if x != 0]\n zero = [x for x in nums if x == 0]\n return non_zero + zero", "matching_cluster_idx": 6}, {"solution": "def move_zero(lst):\n \"\"\"\n Move all zeroes to the end of the given list.\n\n Args:\n lst (list): Input list.\n\n Returns:\n list: List with all zeroes moved to the end.\n \"\"\"\n # Separate non-zero elements and zero elements\n non_zero = [i for i in lst if i != 0]\n zero = [i for i in lst if i == 0]\n\n # Combine the lists to get the desired output\n return non_zero + zero", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n \"\"\"\n Move all zeroes to the end of the given list.\n\n Args:\n nums (list): A list of integers that may contain zeroes.\n\n Returns:\n list: A list of integers with all zeroes at the end.\n \"\"\"\n return [num for num in nums if num != 0] + [0] * nums.count(0)", "matching_cluster_idx": 6}, {"solution": "def move_zero(arr):\n \"\"\"\n Move all zeroes to the end of the given list.\n\n Args:\n arr (list): Input list.\n\n Returns:\n list: Modified list with all zeroes moved to the end.\n\n Example:\n >>> move_zero([1, 0, 2, 0, 3, 4])\n [1, 2, 3, 4, 0, 0]\n \"\"\"\n return [x for x in arr if x != 0] + [0] * arr.count(0)", "matching_cluster_idx": 6}, {"solution": "def move_zero(lst):\n \"\"\"\n Move all zeroes to the end of the given list.\n \n Args:\n lst (list): A list of integers that may contain zeroes.\n \n Returns:\n list: The input list with all zeroes moved to the end.\n \"\"\"\n # Separate non-zero and zero elements\n non_zero = [x for x in lst if x != 0]\n zero = [x for x in lst if x == 0]\n \n # Combine non-zero and zero elements\n return non_zero + zero", "matching_cluster_idx": 6}, {"solution": "def move_zero(lst):\n \"\"\"\n This function moves all zeroes to the end of a given list, preserving the order of the other elements.\n\n Args:\n lst (list): A list containing integers.\n\n Returns:\n list: A list where all zeroes are moved to the end.\n\n Example:\n >>> move_zero([1,0,2,0,3,4])\n [1,2,3,4,0,0]\n \"\"\"\n non_zero_elements = [element for element in lst if element != 0]\n return non_zero_elements + [0] * lst.count(0)", "matching_cluster_idx": 6}, {"solution": "def move_zero(lst):\n \"\"\"\n Move all zeroes to the end of the given list.\n\n Args:\n lst (list): The input list.\n\n Returns:\n list: The list with all zeroes moved to the end.\n\n Example:\n >>> move_zero([1,0,2,0,3,4])\n [1,2,3,4,0,0]\n \"\"\"\n # Separate non-zero and zero elements\n non_zeros = [i for i in lst if i != 0]\n zeros = [i for i in lst if i == 0]\n\n # Combine the non-zero elements with the zeros\n result = non_zeros + zeros\n\n return result", "matching_cluster_idx": 6}]}, "Mbpp/633": {"dps": 94.3089430894309, "dps_norm": 50.0, "pass@1": 60.0, "profiled": [{"solution": "def pair_xor_Sum(nums, n):\n \"\"\"\n Calculate the sum of XOR of all pairs of numbers in the given list.\n\n Args:\n nums (list): A list of integers.\n n (int): Size of the list (for clarity).\n\n Returns:\n int: Sum of XOR of all pairs of numbers.\n \"\"\"\n xor_sum = 0\n for i in range(n):\n for j in range(i + 1, n):\n # Using the XOR operator (^) to get the XOR of two numbers\n # and adding it to the total sum\n xor_sum += nums[i] ^ nums[j]\n return xor_sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(nums, n):\n \"\"\"\n Calculate the sum of XOR of all pairs of numbers in the given list.\n\n Args:\n - nums (list): A list of integers.\n - n (int): Size of the list.\n\n Returns:\n - int: Sum of XOR of all pairs of numbers.\n\n \"\"\"\n xor_sum = 0\n # generate all possible pairs and calculate their xor, then add to sum\n for i in range(n):\n for j in range(i+1, n):\n # XOR operation on each pair of numbers and add the result to xor_sum\n xor_sum += nums[i] ^ nums[j]\n return xor_sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(lst, n):\n \"\"\"\n Calculate the sum of xor of all pairs of numbers in the given list.\n\n Args:\n lst (list): A list of numbers\n n (int): Number of elements to consider in the list\n\n Returns:\n int: Sum of xor of all pairs of numbers in the list.\n \"\"\"\n xor_sum = 0\n # We iterate through each unique pair of numbers in the list\n for i in range(n):\n for j in range(i + 1, n):\n xor_sum += lst[i] ^ lst[j] # XOR operation is performed here\n return xor_sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(arr, n):\n \"\"\"\n This function calculates the sum of xor of all pairs of numbers in the given list.\n\n Args:\n arr (list): A list of integers.\n n (int): The total number of elements in the list.\n\n Returns:\n int: The sum of xor of all pairs of numbers in the list.\n \"\"\"\n total_sum = 0\n # Iterate over all pairs in the list\n for i in range(n):\n for j in range(i + 1, n):\n # Calculate the XOR of the current pair and add it to the total sum\n total_sum += arr[i] ^ arr[j]\n return total_sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(nums, n):\n \"\"\"\n Calculate the sum of xor of all pairs of numbers in the given list.\n\n Args:\n nums (list): A list of numbers.\n n (int): The total number of elements in the list.\n\n Returns:\n int: The sum of xor of all pairs of numbers.\n \"\"\"\n total_sum = 0\n # Calculate xor of each pair and add to total_sum\n for i in range(n):\n for j in range(i+1, n):\n total_sum += nums[i] ^ nums[j]\n return total_sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(nums, n):\n \"\"\"\n This function calculates the sum of XOR of all pairs of numbers in the given list.\n \n Args:\n nums (list): A list of integers.\n n (int): The total number of elements in the list.\n \n Returns:\n int: The sum of XOR of all pairs of numbers in the list.\n \"\"\"\n \n # Initialize the sum of XOR of pairs\n xor_sum = 0\n \n # Iterate over each pair of numbers in the list\n for i in range(n):\n for j in range(i+1, n):\n # Calculate XOR of the current pair and add it to the sum\n xor_sum += nums[i] ^ nums[j]\n \n # Return the sum of XOR of all pairs\n return xor_sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(lst, n):\n \"\"\"\n This function calculates the sum of xor of all pairs of numbers in the given list.\n \n Args:\n lst (list): The list of integers.\n n (int): The total number of elements in the list.\n \n Returns:\n int: The sum of xor of all pairs of numbers in the list.\n \"\"\"\n total_sum = 0\n for i in range(n):\n for j in range(i+1, n):\n # Calculate the XOR of current pair\n xor_result = lst[i] ^ lst[j]\n total_sum += xor_result\n return total_sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(lst, n):\n \"\"\"\n This function calculates the sum of xor of all pairs of numbers in the given list.\n\n Args:\n lst (list): A list of integers.\n n (int): Size of the list.\n\n Returns:\n int: The sum of xor of all pairs of numbers in the list.\n\n \"\"\"\n # Initialize a variable to store the sum of xor of all pairs of numbers.\n xor_sum = 0\n\n # Iterate over the list.\n for i in range(n):\n # For each element, iterate over the rest of the list to form pairs.\n for j in range(i + 1, n):\n # Calculate the xor of the current pair and add it to xor_sum.\n xor_sum += lst[i] ^ lst[j]\n\n # Return the total sum.\n return xor_sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(nums, n):\n \"\"\"\n This function calculates the sum of XOR of all pairs of numbers in the given list.\n\n Args:\n nums (list): A list of integers.\n n (int): The size of the list.\n\n Returns:\n int: The sum of XOR of all pairs of numbers in the list.\n \"\"\"\n # Initialize the result\n xor_sum = 0\n\n # Iterate over each pair of numbers in the list\n for i in range(n):\n for j in range(i + 1, n):\n # Calculate the XOR of the current pair and add it to the result\n xor_sum += nums[i] ^ nums[j]\n\n return xor_sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(nums, n):\n \"\"\"\n Calculate the sum of XOR of all pairs of numbers in the given list.\n\n Args:\n - nums (list): A list of integers.\n - n (int): The size of the list.\n\n Returns:\n - int: The sum of XOR of all pairs of numbers.\n \"\"\"\n xor_sum = 0\n for i in range(n):\n for j in range(i + 1, n):\n xor_sum += nums[i] ^ nums[j]\n return xor_sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(nums, n):\n \"\"\"\n This function calculates the sum of XOR of all pairs of numbers in the given list.\n\n Args:\n nums (list): A list of integers.\n n (int): The maximum number to consider from the list for pairs.\n\n Returns:\n int: The sum of XOR of all pairs of numbers.\n \"\"\"\n xor_sum = 0\n for i in range(len(nums)):\n for j in range(i+1, min(n, len(nums))):\n xor_sum += nums[i] ^ nums[j]\n return xor_sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(nums, n):\n \"\"\"\n Calculate the sum of XOR of all pairs of numbers in the given list.\n\n Args:\n - nums (list): List of numbers to consider for pair XOR operations.\n - n (int): Number of elements in the list, used for XOR operation count.\n\n Returns:\n - The sum of XOR of all pairs of numbers in the list.\n\n \"\"\"\n total_xor_sum = 0\n for i in range(n):\n for j in range(i+1, n):\n # XOR operation on each pair\n total_xor_sum += nums[i] ^ nums[j]\n return total_xor_sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(arr, n):\n \"\"\"\n This function calculates the sum of XOR of all pairs of numbers in the given list.\n\n Parameters:\n arr (list): The list of numbers.\n n (int): The total number of elements in the list.\n\n Returns:\n int: The sum of XOR of all pairs of numbers.\n \"\"\"\n # Initialize sum to 0\n total_xor_sum = 0\n \n # Iterate over each element in the list\n for i in range(n):\n # For each element, XOR it with every other element in the list\n for j in range(i+1, n):\n # Calculate XOR and add it to total_xor_sum\n total_xor_sum += arr[i] ^ arr[j]\n \n # Since XOR of each pair (a, b) is same as XOR of pair (b, a), we've actually calculated sum of 2 * (XOR of all pairs)\n # Hence, we're returning total_xor_sum as it is because the given test case is also considering it in that way\n return total_xor_sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(nums, n):\n \"\"\"\n This function calculates the sum of xor of all pairs of numbers in the given list.\n \n Args:\n nums (list): A list of integers.\n n (int): The total number of elements in the list.\n \n Returns:\n int: The sum of xor of all pairs of numbers in the list.\n \"\"\"\n total_sum = 0\n \n # Iterate over all pairs of numbers in the list\n for i in range(n):\n for j in range(i+1, n):\n # Calculate the xor of each pair and add it to the total sum\n total_sum += nums[i] ^ nums[j]\n \n return total_sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(nums, n):\n \"\"\"\n Calculate the sum of XOR of all pairs of numbers in the given list.\n\n Args:\n nums (list): A list of integers.\n n (int): The number of elements to consider from the list.\n\n Returns:\n int: The sum of XOR of all pairs of numbers.\n \"\"\"\n # Initialize sum variable to 0\n total_sum = 0\n \n # Iterate over the list considering n elements\n for i in range(min(n, len(nums))):\n # For each element, iterate over the rest of the list\n for j in range(i + 1, min(n, len(nums))):\n # Calculate XOR and add it to the total sum\n total_sum += nums[i] ^ nums[j]\n \n return total_sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(lst, n):\n \"\"\"\n Calculate the sum of xor of all pairs of numbers in the given list.\n \n Args:\n lst (list): The input list of integers.\n n (int): The number of elements in the list.\n \n Returns:\n int: The sum of xor of all pairs of numbers in the list.\n \"\"\"\n xor_sum = 0\n for i in range(n):\n for j in range(i+1, n):\n # Calculate the xor of each pair of numbers\n xor_sum += lst[i] ^ lst[j]\n return xor_sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(numbers, length):\n \"\"\"\n Calculate the sum of the bitwise XOR of all pairs of numbers in the given list.\n\n Args:\n numbers (list): A list of integers.\n length (int): The length of the list.\n\n Returns:\n int: The sum of the bitwise XOR of all pairs of numbers.\n\n \"\"\"\n xor_sum = 0\n for i in range(length):\n for j in range(i + 1, length):\n xor_sum += numbers[i] ^ numbers[j]\n return xor_sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(lst, length):\n \"\"\"\n Calculate the sum of xor of all pairs of numbers in the given list.\n \n Parameters:\n lst (list): List of integers.\n length (int): Length of list\n \n Returns:\n int: Sum of xor of all pairs.\n \"\"\"\n xor_sum = 0\n for i in range(length):\n for j in range(i+1, length):\n xor_sum += lst[i] ^ lst[j]\n return xor_sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(nums, n):\n \"\"\"\n This function calculates the sum of the XOR of all pairs of numbers in the given list.\n\n Args:\n nums (list): A list of integers.\n n (int): The total number of pairs is n*(n-1)/2\n\n Returns:\n int: The sum of XOR of all pairs of numbers.\n \"\"\"\n xor_sum = 0\n for i in range(n):\n for j in range(i + 1, n):\n xor_sum += nums[i] ^ nums[j]\n return xor_sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(numbers, length):\n \"\"\"\n Calculate the sum of xor of all pairs of numbers in the given list.\n\n Args:\n numbers (list): A list of numbers.\n length (int): Length of the list.\n\n Returns:\n int: Sum of xor of all pairs of numbers in the list.\n \"\"\"\n n = len(numbers)\n total_sum = 0\n # Iterate through each pair of elements in the list\n for i in range(n):\n for j in range(i + 1, length):\n # Calculate the XOR of the two elements and add to the total sum\n total_sum += numbers[i] ^ numbers[j]\n return total_sum\nnumbers = [5,9,7,6]\nlength = len(numbers)", "matching_cluster_idx": 2}]}, "Mbpp/644": {"dps": 74.25531914893615, "dps_norm": 75.33333333333333, "pass@1": 96.0, "profiled": [{"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n Reverses the given array up to a given position.\n\n Args:\n arr (list): The input array.\n k (int): The position up to which the array needs to be reversed.\n\n Returns:\n list: The modified array with elements reversed up to the given position.\n\n Raises:\n ValueError: If k is larger than the length of the array.\n\n \"\"\"\n if k > len(arr):\n raise ValueError(\"k cannot be larger than the length of the array\")\n\n # Reverse the array up to position k\n return arr[:k][::-1] + arr[k:]", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n Reverses the input array up to a given position k.\n\n Args:\n arr (list): The input array.\n k (int): The position up to which the array should be reversed.\n\n Returns:\n list: The modified array with elements reversed up to position k.\n\n Raises:\n ValueError: If k is larger than the length of the array.\n\n Examples:\n >>> reverse_Array_Upto_K([1, 2, 3, 4, 5, 6], 4)\n [4, 3, 2, 1, 5, 6]\n \"\"\"\n\n # Check if k is not larger than the length of the array\n if k > len(arr):\n raise ValueError(\"k cannot be larger than the length of the array\")\n\n # Reverse the array up to position k\n return arr[:k][::-1] + arr[k:]", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(array, k):\n \"\"\"\n Reverses an array up to the given position k.\n\n Args:\n array (list): The input array to be reversed.\n k (int): The position up to which the array is to be reversed.\n\n Returns:\n list: The array with elements reversed up to the given position.\n \"\"\"\n if k < 0 or k > len(array):\n raise ValueError(\"k is out of range\")\n \n # Reverse the array up to the given position k\n return array[k-1::-1] + array[k:]", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(array, k):\n \"\"\"\n Reverses an array upto a given position.\n\n Args:\n array (list): The input list to reverse.\n k (int): The position up to which the array will be reversed.\n\n Returns:\n list: A new list with the elements reversed up to the given position.\n \"\"\"\n if k > len(array):\n raise ValueError(\"k cannot be greater than the length of the array\")\n \n # Reverse the array up to position k\n reversed_part = array[:k][::-1]\n \n # Combine the reversed part with the rest of the array\n return reversed_part + array[k:]", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n This function takes an array and an integer as inputs.\n It reverses the array elements up to the given position 'k'.\n\n Args:\n arr (list): Input list\n k (int): Position up to which the list needs to be reversed\n\n Returns:\n list: List with elements reversed up to position 'k'\n \"\"\"\n # Validate inputs\n if not isinstance(arr, list):\n raise TypeError(\"Input array must be a list\")\n if not isinstance(k, int):\n raise TypeError(\"Input position must be an integer\")\n if k < 1 or k > len(arr):\n raise ValueError(\"Input position is out of range\")\n\n # Use Python's list slicing feature to reverse the array up to position 'k'\n return arr[:k][::-1] + arr[k:]", "matching_cluster_idx": 10}, {"solution": "import unittest\ndef reverse_Array_Upto_K(arr, k):\n \"\"\"\n Reverses the input array upto the given position k.\n\n Args:\n arr (list): Input array to be reversed.\n k (int): Position upto which the array is reversed.\n\n Returns:\n list: Reversed array.\n \"\"\"\n if k > len(arr):\n raise ValueError(\"k cannot be greater than the length of the array\")\n return arr[k-1::-1] + arr[k:]", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(array, k):\n \"\"\"\n Reverses the given array up to a given position k.\n\n Args:\n array (list): The input list to be reversed.\n k (int): The position up to which the array needs to be reversed.\n\n Returns:\n list: The reversed array up to position k.\n \"\"\"\n # Check if k is within the array bounds\n if k > len(array) or k < 0:\n raise ValueError(\"k should be within the array bounds\")\n\n # Reverse the array up to position k\n array[:k] = array[:k][::-1]\n\n return array", "matching_cluster_idx": 13}, {"solution": "def reverse_Array_Upto_K(array, k):\n \"\"\"\n Reverses the input array upto the given position k.\n\n Args:\n array (list): The input list to be reversed.\n k (int): The position up to which the list is to be reversed.\n\n Returns:\n list: The list with elements reversed up to position k.\n \"\"\"\n if k < 0 or k > len(array):\n raise ValueError(\"k is out of range\")\n \n # Reverse the list up to position k\n return array[k-1::-1] + array[k:]", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(array, k):\n \"\"\"\n Reverses a given array up to a specified position (k) from the beginning.\n \n Args:\n array (list): Input array to be reversed up to position k.\n k (int): Position up to which the array is to be reversed.\n\n Returns:\n list: Array with elements reversed up to the specified position.\n \"\"\"\n if k > len(array):\n raise ValueError(\"k cannot be larger than array length\")\n \n # Slice the array up to position k, reverse it, and concatenate with the rest of the array\n return array[:k][::-1] + array[k:]", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(array, k):\n \"\"\"\n Reverses a given array up to a specified position.\n\n Args:\n array (list): The input array.\n k (int): The position up to which the array should be reversed.\n\n Returns:\n list: The modified array with elements reversed up to position k.\n\n Raises:\n IndexError: If k is larger than the array length.\n \"\"\"\n if k > len(array):\n raise IndexError(\"k cannot be larger than the array length\")\n\n # Reverse the array up to position k\n array[:k] = array[:k][::-1]\n\n return array", "matching_cluster_idx": 13}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n Reverses the input array up to the k-th position.\n\n Args:\n arr (list): The input array to be reversed.\n k (int): The position up to which the array should be reversed.\n\n Returns:\n list: The array with elements reversed up to the k-th position.\n \"\"\"\n if k > len(arr):\n raise ValueError(\"k cannot be greater than the length of the array\")\n\n return arr[:k][::-1] + arr[k:]", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n Reverses a given array up to a specified position k.\n \n Args:\n arr (list): The input array to be reversed.\n k (int): The position up to which the array needs to be reversed.\n \n Returns:\n list: The array with elements reversed up to the given position.\n \"\"\"\n if k > len(arr):\n raise ValueError(\"k cannot be greater than the length of the array\")\n \n return arr[:k][::-1] + arr[k:]", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n Reverses the input array up to the given position k.\n \n Args:\n arr (list): The input list of elements to be reversed.\n k (int): The position up to which the list will be reversed.\n \n Returns:\n list: The modified list with elements reversed up to position k.\n \"\"\"\n \n # Check if k is within bounds\n if k > len(arr):\n raise ValueError(\"k cannot be greater than the length of the array\")\n \n # Reverse the array up to the given position k\n return arr[:k][::-1] + arr[k:]", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(array, k):\n \"\"\"\n Reverses the given array up to the k-th position.\n\n Args:\n array (list): The input array to be reversed.\n k (int): The position up to which the array should be reversed.\n\n Returns:\n list: The array reversed up to the k-th position.\n\n Raises:\n ValueError: If k is greater than the length of the array.\n \"\"\"\n if k > len(array):\n raise ValueError(\"k cannot be greater than the length of the array\")\n \n # Reverse the array up to the k-th position\n reversed_array = array[:k][::-1] + array[k:]\n\n return reversed_array", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n Reverses the array up to a given position k.\n \n Args:\n arr (list): The input array to be reversed.\n k (int): The position up to which the array should be reversed.\n\n Returns:\n list: The reversed array up to the given position.\n \"\"\"\n # Check if k is within the array bounds\n if k > len(arr):\n raise IndexError(\"k is out of range\")\n \n # Reverse the array up to the given position\n return arr[:k][::-1] + arr[k:]", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n Reverses the array up to the given position.\n\n Args:\n arr (list): The input array.\n k (int): The position up to which the array needs to be reversed.\n\n Returns:\n list: The array with elements reversed up to the given position.\n \"\"\"\n if k > len(arr):\n raise ValueError(\"k cannot be greater than the length of the array\")\n\n # Reverse the array up to the given position\n return arr[:k][::-1] + arr[k:]", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n Reverse the elements of an array up to the given position k.\n\n Args:\n arr (list): The input array to be reversed.\n k (int): The position up to which the array should be reversed.\n\n Returns:\n list: The modified array with elements reversed up to position k.\n \"\"\"\n if not isinstance(arr, list) or not arr:\n raise ValueError(\"Input array must be a non-empty list\")\n if not isinstance(k, int) or k < 0 or k > len(arr):\n raise ValueError(\"k must be a non-negative integer within array bounds\")\n\n # Reverse the elements up to position k\n return arr[:k][::-1] + arr[k:]", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(array, k):\n \"\"\"\n Reverses the elements in the given array up to the k-th position.\n \n Args:\n array (list): The input list to be reversed up to k-th position.\n k (int): The position up to which the array needs to be reversed.\n \n Returns:\n list: The modified array where the elements are reversed up to the k-th position.\n \"\"\"\n \n if k > len(array):\n raise IndexError(\"k cannot be larger than the array length\")\n \n return array[:k][::-1] + array[k:]", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n Reverses the input array up to the given position (k).\n\n Args:\n arr (list): Input array.\n k (int): Position up to which array needs to be reversed.\n\n Returns:\n list: Array reversed up to the given position.\n \"\"\"\n if k > len(arr):\n raise ValueError(\"k cannot be greater than the length of the array\")\n \n # Reversing the array up to the given position\n reversed_part = arr[:k][::-1]\n \n # Concatenating the reversed part with the rest of the array\n return reversed_part + arr[k:]", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n Reverses the first 'k' elements in a given array.\n\n Args:\n arr (list): Input array\n k (int): Number of elements to reverse\n\n Returns:\n list: Modified array with first 'k' elements reversed\n \"\"\"\n if k > len(arr):\n raise ValueError(\"k cannot be greater than the array length\")\n\n # Reversing the array up to the kth position using list slicing\n return arr[:k][::-1] + arr[k:]", "matching_cluster_idx": 10}]}, "Mbpp/720": {"dps": 55.19230769230769, "dps_norm": 85.0, "pass@1": 100.0, "profiled": [{"solution": "def add_dict_to_tuple(input_tuple, input_dict):\n \"\"\"\n Adds a dictionary to the input tuple.\n \n Args:\n input_tuple (tuple): The input tuple to be modified.\n input_dict (dict): The dictionary to be added to the tuple.\n \n Returns:\n tuple: A new tuple containing all the elements from the input tuple and the input dictionary.\n \"\"\"\n # Convert the tuple to a list, as tuples are immutable in Python\n list_tuple = list(input_tuple)\n \n # Append the dictionary to the list\n list_tuple.append(input_dict)\n \n # Convert the list back to a tuple\n output_tuple = tuple(list_tuple)\n \n return output_tuple", "matching_cluster_idx": 3}, {"solution": "def add_dict_to_tuple(input_tuple, input_dict):\n \"\"\"\n Adds a dictionary to the input tuple.\n \n Args:\n input_tuple (tuple): The original tuple.\n input_dict (dict): The dictionary to be added.\n \n Returns:\n tuple: A new tuple containing the original elements and the input dictionary.\n \"\"\"\n # Convert the input tuple to a list to allow modifications\n list_tuple = list(input_tuple)\n \n # Append the dictionary to the list\n list_tuple.append(input_dict)\n \n # Convert the list back to a tuple and return it\n return tuple(list_tuple)", "matching_cluster_idx": 3}, {"solution": "def add_dict_to_tuple(tup, dictionary):\n \"\"\"\n Adds a dictionary to a tuple.\n\n Args:\n tup (tuple): The original tuple.\n dictionary (dict): The dictionary to be added.\n\n Returns:\n tuple: A new tuple that includes all elements of the original tuple and the dictionary.\n\n Example:\n >>> add_dict_to_tuple((4, 5, 6), {\"MSAM\" : 1, \"is\" : 2, \"best\" : 3})\n (4, 5, 6, {'MSAM': 1, 'is': 2, 'best': 3})\n \"\"\"\n return tup + (dictionary,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(input_tuple, input_dict):\n \"\"\"\n Add a dictionary to a tuple and return a new tuple.\n\n Args:\n input_tuple (tuple): The input tuple to be extended.\n input_dict (dict): The dictionary to be added to the tuple.\n\n Returns:\n tuple: A new tuple containing all elements from the input tuple and the input dictionary.\n \"\"\"\n # Since tuples are immutable, we need to create a new tuple that includes all elements from the input tuple and the dictionary\n new_tuple = input_tuple + (input_dict,)\n return new_tuple", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(tup, dictionary):\n \"\"\"\n Adds a dictionary to the end of the given tuple.\n\n Args:\n tup (tuple): The input tuple to which the dictionary will be added.\n dictionary (dict): The dictionary to be added to the tuple.\n\n Returns:\n tuple: A new tuple containing all the elements from the original tuple and the dictionary.\n\n Example:\n >>> add_dict_to_tuple((4, 5, 6), {\"MSAM\" : 1, \"is\" : 2, \"best\" : 3} )\n (4, 5, 6, {'MSAM': 1, 'is': 2, 'best': 3})\n \"\"\"\n # Since tuples are immutable in Python, we need to create a new tuple\n # We can do this using the + operator or by converting to a list, appending the dictionary, and converting back to a tuple\n # We'll use the + operator for simplicity\n return tup + (dictionary,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(input_tuple, input_dict):\n \"\"\"\n This function adds a dictionary to the input tuple.\n\n Args:\n input_tuple (tuple): Input tuple.\n input_dict (dict): Input dictionary.\n\n Returns:\n tuple: Tuple containing original elements and added dictionary.\n \"\"\"\n # Convert the input tuple to a list to make it mutable\n list_from_tuple = list(input_tuple)\n \n # Append the dictionary to the list\n list_from_tuple.append(input_dict)\n \n # Convert the list back to a tuple and return\n return tuple(list_from_tuple)", "matching_cluster_idx": 3}, {"solution": "def add_dict_to_tuple(tup, dictionary):\n \"\"\"\n Adds a dictionary to the end of a tuple.\n\n Args:\n tup (tuple): Input tuple to be extended.\n dictionary (dict): Dictionary to be added to the tuple.\n\n Returns:\n tuple: The input tuple with the dictionary added to the end.\n\n \"\"\"\n # Tuples are immutable in Python, so we convert it to a list to append the dictionary\n list_tup = list(tup)\n \n # Append the dictionary to the list\n list_tup.append(dictionary)\n \n # Convert the list back to a tuple\n result_tup = tuple(list_tup)\n \n return result_tup", "matching_cluster_idx": 3}, {"solution": "def add_dict_to_tuple(tup, dictionary):\n \"\"\"\n Adds a dictionary to the tuple.\n \n Args:\n tup (tuple): Input tuple.\n dictionary (dict): Dictionary to be added.\n \n Returns:\n tuple: New tuple containing the original tuple elements and the dictionary.\n \"\"\"\n # Tuples in Python are immutable. So we need to convert it to list first.\n # We use the list function to convert the tuple to a list.\n list_version = list(tup)\n \n # Append the dictionary to the list\n list_version.append(dictionary)\n \n # Now we convert the list back to tuple using tuple function\n new_tuple = tuple(list_version)\n \n return new_tuple", "matching_cluster_idx": 3}, {"solution": "def add_dict_to_tuple(input_tuple, input_dict):\n \"\"\"\n This function takes an input tuple and an input dictionary. It appends the dictionary to the tuple.\n \n Args:\n input_tuple (tuple): The input tuple.\n input_dict (dict): The input dictionary.\n\n Returns:\n tuple: A new tuple containing all elements from the input tuple and the input dictionary.\n \"\"\"\n # We cannot directly add a dictionary to a tuple because tuples are immutable in Python.\n # So, we'll convert the tuple to a list, append the dictionary, and then convert back to a tuple.\n list_version = list(input_tuple) # Convert the tuple to a list\n list_version.append(input_dict) # Append the dictionary to the list\n return tuple(list_version) # Convert the list back to a tuple", "matching_cluster_idx": 3}, {"solution": "def add_dict_to_tuple(input_tuple, input_dict):\n \"\"\"\n This function takes a tuple and a dictionary as input and returns a new tuple \n with the dictionary added as the last element.\n\n Args:\n input_tuple (tuple): Input tuple to be extended.\n input_dict (dict): Input dictionary to be added.\n\n Returns:\n tuple: A new tuple with the dictionary added as the last element.\n \"\"\"\n return input_tuple + (input_dict,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(input_tuple, input_dict):\n \"\"\"\n This function adds a dictionary to the tuple.\n \n Args:\n input_tuple (tuple): Input tuple to add the dictionary to.\n input_dict (dict): Input dictionary to add to the tuple.\n \n Returns:\n tuple: The tuple with the dictionary added.\n \"\"\"\n # Convert the tuple to a list to make it mutable\n temp_list = list(input_tuple)\n \n # Append the dictionary to the list\n temp_list.append(input_dict)\n \n # Convert the list back to a tuple\n result_tuple = tuple(temp_list)\n \n return result_tuple", "matching_cluster_idx": 3}, {"solution": "def add_dict_to_tuple(input_tuple, input_dict):\n \"\"\"\n Adds a dictionary to the tuple and returns the resulting tuple.\n \n Args:\n input_tuple (tuple): Input tuple to be extended.\n input_dict (dict): Dictionary to be added to the tuple.\n \n Returns:\n tuple: Extended tuple with the added dictionary.\n \"\"\"\n # Tuples in Python are immutable, so we convert it to a list, \n # append the dictionary, and then convert it back to a tuple\n list_tuple = list(input_tuple)\n list_tuple.append(input_dict)\n return tuple(list_tuple)", "matching_cluster_idx": 3}, {"solution": "def add_dict_to_tuple(tup, dictionary):\n \"\"\"\n Adds a dictionary to a tuple.\n\n Args:\n tup (tuple): The input tuple.\n dictionary (dict): The dictionary to be added.\n\n Returns:\n tuple: A new tuple containing the original elements and the dictionary.\n\n \"\"\"\n # Convert the tuple to a list since tuples are immutable\n lst = list(tup)\n # Append the dictionary to the list\n lst.append(dictionary)\n # Convert the list back to a tuple\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def add_dict_to_tuple(tup, dictionary):\n \"\"\"\n Adds a dictionary to the end of a tuple.\n\n Args:\n tup (tuple): The input tuple.\n dictionary (dict): The dictionary to be added to the tuple.\n\n Returns:\n tuple: A new tuple with the dictionary appended at the end.\n\n Example:\n >>> add_dict_to_tuple((4, 5, 6), {\"MSAM\" : 1, \"is\" : 2, \"best\" : 3} )\n (4, 5, 6, {'MSAM': 1, 'is': 2, 'best': 3})\n \"\"\"\n return tup + (dictionary,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(tup, dictionary):\n \"\"\"\n This function takes a tuple and a dictionary as input and returns a new tuple.\n The new tuple contains all elements from the original tuple and the dictionary.\n\n Args:\n tup (tuple): The input tuple.\n dictionary (dict): The dictionary to be added.\n\n Returns:\n tuple: A new tuple containing elements from the original tuple and the dictionary.\n \"\"\"\n # We use the '+' operator to concatenate the original tuple with a tuple containing the dictionary\n # However, since tuples are immutable, we first need to convert the original tuple to a list\n # Then we use the '+' operator to concatenate the list with the list containing the dictionary\n # Finally, we convert the resulting list back to a tuple using the tuple() function\n return tuple(list(tup) + [dictionary])", "matching_cluster_idx": 2}, {"solution": "def add_dict_to_tuple(tup, dictionary):\n \"\"\"\n Add a dictionary to a tuple.\n\n Args:\n tup (tuple): Input tuple.\n dictionary (dict): Dictionary to be added to the tuple.\n\n Returns:\n tuple: A new tuple containing all elements from the input tuple and the dictionary.\n \"\"\"\n return tup + (dictionary,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(input_tuple, input_dict):\n \"\"\"\n Adds a dictionary to the end of a tuple.\n\n Args:\n input_tuple (tuple): Input tuple.\n input_dict (dict): Input dictionary.\n\n Returns:\n tuple: A new tuple that contains all elements from the input tuple and the input dictionary.\n \"\"\"\n # Tuples are immutable, so we need to convert it to a list first\n list_from_tuple = list(input_tuple)\n \n # Append the dictionary to the list\n list_from_tuple.append(input_dict)\n \n # Convert the list back to a tuple\n result_tuple = tuple(list_from_tuple)\n \n return result_tuple", "matching_cluster_idx": 3}, {"solution": "def add_dict_to_tuple(input_tuple, input_dict):\n \"\"\"\n Adds a dictionary to the input tuple.\n\n Args:\n input_tuple (tuple): The input tuple to which the dictionary needs to be added.\n input_dict (dict): The dictionary to be added to the tuple.\n\n Returns:\n tuple: A new tuple containing all elements from the input tuple and the input dictionary.\n \"\"\"\n # Since tuples in Python are immutable, we need to convert the tuple to a list\n list_from_tuple = list(input_tuple)\n \n # Append the dictionary to the list\n list_from_tuple.append(input_dict)\n \n # Convert the list back to a tuple and return\n return tuple(list_from_tuple)", "matching_cluster_idx": 3}, {"solution": "def add_dict_to_tuple(input_tuple, dictionary):\n \"\"\"\n This function adds a dictionary to a tuple.\n \n Parameters:\n input_tuple (tuple): Input tuple to which the dictionary is added\n dictionary (dict): Dictionary that needs to be added to the tuple\n \n Returns:\n tuple: A tuple containing all elements from input_tuple and the dictionary\n \"\"\"\n # Convert the input tuple to a list because tuples are immutable in python\n list_representation = list(input_tuple)\n \n # Append the dictionary to the list\n list_representation.append(dictionary)\n \n # Convert the list back to a tuple\n result_tuple = tuple(list_representation)\n \n return result_tuple", "matching_cluster_idx": 3}, {"solution": "def add_dict_to_tuple(tup, dictionary):\n \"\"\"\n This function adds a dictionary to the end of a tuple and returns the resulting tuple.\n\n Args:\n tup (tuple): The input tuple.\n dictionary (dict): The dictionary to add to the tuple.\n\n Returns:\n tuple: A new tuple that includes the original tuple elements and the dictionary.\n\n Example:\n >>> add_dict_to_tuple((4, 5, 6), {\"MSAM\" : 1, \"is\" : 2, \"best\" : 3} )\n (4, 5, 6, {'MSAM': 1, 'is': 2, 'best': 3})\n \"\"\"\n\n # Convert the tuple to a list (since tuples are immutable)\n list_from_tup = list(tup)\n \n # Append the dictionary to the end of the list\n list_from_tup.append(dictionary)\n \n # Convert the list back to a tuple and return it\n return tuple(list_from_tup)", "matching_cluster_idx": 3}]}, "Mbpp/725": {"dps": 46.038251366120214, "dps_norm": 50.625, "pass@1": 67.0, "profiled": [{"solution": "def extract_quotation(s):\n \"\"\"\n Extracts values between quotation marks from a given string.\n \n Args:\n s (str): The input string to extract quotations from.\n \n Returns:\n list: A list of strings extracted between quotation marks.\n \"\"\"\n in_quotation = False\n quotation = ''\n result = []\n for char in s:\n if char == '\"':\n if in_quotation:\n result.append(quotation)\n quotation = ''\n in_quotation = not in_quotation\n elif in_quotation:\n quotation += char\n return result", "matching_cluster_idx": 2}, {"solution": "import re\ndef extract_quotation(text):\n \"\"\"\n This function takes a string as input and returns a list of values enclosed within quotation marks.\n \n Args:\n text (str): The input string containing quoted values.\n \n Returns:\n list: A list of strings extracted from the input string.\n \"\"\"\n # Use regular expression to find all occurrences of quoted strings in the input text\n return re.findall(r'\"(.*?)\"', text)", "matching_cluster_idx": 4}, {"solution": "def extract_quotation(s: str) -> list[str]:\n \"\"\"\n Extract values between quotation marks \" \" of the given string.\n\n Args:\n s (str): The input string that contains values enclosed in quotation marks.\n\n Returns:\n list[str]: A list of values enclosed in quotation marks.\n\n Examples:\n >>> extract_quotation('Cortex \"A53\" Based \"multi\" tasking \"Processor\"')\n ['A53', 'multi', 'Processor']\n \"\"\"\n import re\n return re.findall(r'\"(.*?)\"', s)", "matching_cluster_idx": 4}, {"solution": "import re\ndef extract_quotation(text):\n \"\"\"\n Extracts values between quotation marks from the given string.\n \n Args:\n text (str): The input string containing quoted values.\n \n Returns:\n list: A list of extracted quoted values.\n \"\"\"\n pattern = r'\"(.*?)\"'\n matches = re.findall(pattern, text)\n return matches", "matching_cluster_idx": 4}, {"solution": "import re\ndef extract_quotation(s):\n \"\"\"\n Extracts values between quotation marks from a given string.\n\n Args:\n s (str): Input string\n\n Returns:\n list: List of strings between quotation marks\n \"\"\"\n pattern = r'\"([^\"]*)\"'\n return re.findall(pattern, s)", "matching_cluster_idx": 5}, {"solution": "def extract_quotation(input_str):\n \"\"\"\n Extracts values between quotation marks \" \" of the given string.\n\n Args:\n input_str (str): Input string containing quoted values.\n\n Returns:\n list: List of extracted values.\n \"\"\"\n extracted_values = []\n quote_flag = False\n temp_str = \"\"\n\n for char in input_str:\n if char == '\"':\n quote_flag = not quote_flag\n if not quote_flag:\n extracted_values.append(temp_str)\n temp_str = \"\"\n elif quote_flag:\n temp_str += char\n\n return extracted_values", "matching_cluster_idx": 2}, {"solution": "def extract_quotation(s):\n \"\"\"\n This function extracts values between quotation marks \" \" of the given string.\n\n Args:\n s (str): Input string with values enclosed in double quotes.\n\n Returns:\n list: A list of strings extracted from the input string.\n\n Example:\n >>> extract_quotation('Cortex \"A53\" Based \"multi\" tasking \"Processor\"')\n ['A53', 'multi', 'Processor']\n \"\"\"\n result = []\n in_quotes = False\n current_value = \"\"\n\n # Iterate over each character in the input string\n for char in s:\n # If the character is a double quote\n if char == '\"':\n # If we are not currently inside a quoted value, start a new value\n if not in_quotes:\n in_quotes = True\n # If we are currently inside a quoted value, add the value to the result list\n else:\n result.append(current_value)\n current_value = \"\"\n in_quotes = False\n # If we are inside a quoted value, append the character to the current value\n elif in_quotes:\n current_value += char\n\n return result", "matching_cluster_idx": 2}, {"solution": "def extract_quotation(input_string):\n \"\"\"\n Extracts values between quotation marks from the given string.\n\n Args:\n input_string (str): The string containing quoted values.\n\n Returns:\n list: A list of values between quotation marks.\n\n \"\"\"\n result = []\n is_quoted = False\n current_value = \"\"\n\n for char in input_string:\n if char == '\"':\n if is_quoted:\n result.append(current_value)\n current_value = \"\"\n is_quoted = not is_quoted\n elif is_quoted:\n current_value += char\n\n return result\ninput_string = 'Cortex \"A53\" Based \"multi\" tasking \"Processor\"'", "matching_cluster_idx": 2}, {"solution": "def extract_quotation(input_string):\n \"\"\"\n This function takes an input string and returns a list of values enclosed within quotation marks.\n\n Args:\n input_string (str): Input string containing quoted values.\n\n Returns:\n list: A list of quoted values from the input string.\n \"\"\"\n # Initialize an empty list to store the quoted values\n quoted_values = []\n # Initialize a flag to track if we're currently inside a quoted value\n inside_quote = False\n # Initialize an empty string to build the current quoted value\n current_quote = \"\"\n\n # Iterate over each character in the input string\n for char in input_string:\n # If we encounter a quotation mark and we're not inside a quote, start a new quote\n if char == '\"' and not inside_quote:\n inside_quote = True\n # If we encounter a quotation mark and we are inside a quote, add the current quote to the list and reset\n elif char == '\"' and inside_quote:\n quoted_values.append(current_quote)\n current_quote = \"\"\n inside_quote = False\n # If we're inside a quote, add the current character to the quote\n elif inside_quote:\n current_quote += char\n\n # Return the list of quoted values\n return quoted_values", "matching_cluster_idx": 1}, {"solution": "def extract_quotation(s):\n \"\"\"\n This function takes a string `s` as input, \n and returns a list of strings that are enclosed within double quotes.\n\n Args:\n s (str): The input string.\n\n Returns:\n list: A list of strings extracted between double quotes.\n \"\"\"\n result = []\n quoteStarted = False\n tempStr = \"\"\n \n for char in s:\n if char == '\"':\n quoteStarted = not quoteStarted\n if not quoteStarted:\n result.append(tempStr)\n tempStr = \"\"\n elif quoteStarted:\n tempStr += char\n \n return result", "matching_cluster_idx": 2}, {"solution": "def extract_quotation(s):\n \"\"\"\n This function extracts values between quotation marks \" \" of the given string.\n\n Args:\n s (str): The input string containing values within quotation marks.\n\n Returns:\n list: A list of strings extracted between the quotation marks.\n \"\"\"\n result = []\n is_quoted = False\n current_word = \"\"\n\n for char in s:\n # Check if the character is a quotation mark\n if char == '\"':\n # If already in a quoted section, add the word to the result and reset\n if is_quoted:\n result.append(current_word)\n current_word = \"\"\n # Toggle the is_quoted flag\n is_quoted = not is_quoted\n elif is_quoted:\n # If in a quoted section, add the character to the current word\n current_word += char\n\n return result", "matching_cluster_idx": 2}, {"solution": "import re\ndef extract_quotation(s):\n \"\"\"\n Extract values between quotation marks \" \" of the given string.\n\n Args:\n s (str): The input string.\n\n Returns:\n list: A list of values between quotation marks.\n\n Example:\n >>> extract_quotation('Cortex \"A53\" Based \"multi\" tasking \"Processor\"')\n ['A53', 'multi', 'Processor']\n \"\"\"\n # Regular expression pattern to match values within double quotes\n pattern = r'\\\"(.*?)\\\"'\n \n # Find all matches of the pattern in the string\n matches = re.findall(pattern, s)\n \n # Return the list of matches\n return matches", "matching_cluster_idx": 5}, {"solution": "def extract_quotation(s):\n \"\"\"\n Extracts values between quotation marks from a given string.\n\n Args:\n s (str): Input string.\n\n Returns:\n list: List of extracted values.\n \"\"\"\n result = []\n in_quote = False\n temp = ''\n \n for char in s:\n if char == '\"':\n if in_quote:\n result.append(temp)\n temp = ''\n in_quote = not in_quote\n elif in_quote:\n temp += char\n \n return result", "matching_cluster_idx": 2}, {"solution": "def extract_quotation(s):\n \"\"\"\n This function extracts values between quotation marks \" \" of the given string.\n\n Args:\n s (str): Input string containing quoted substrings.\n\n Returns:\n list: A list of substrings enclosed within quotes.\n\n \"\"\"\n quotation_marks = '\"'\n result = []\n start = None\n\n for i, char in enumerate(s):\n if char == quotation_marks:\n if start is None:\n start = i + 1 # starting index of the quoted substring\n else:\n result.append(s[start:i]) # append quoted substring to the result\n start = None\n\n return result", "matching_cluster_idx": 2}, {"solution": "import re\ndef extract_quotation(input_str):\n \"\"\"\n Extracts values enclosed in quotation marks from a given string.\n\n Args:\n input_str (str): Input string that contains quoted substrings.\n\n Returns:\n list: List of quoted values.\n\n Examples:\n >>> extract_quotation('Cortex \"A53\" Based \"multi\" tasking \"Processor\"')\n ['A53', 'multi', 'Processor']\n \"\"\"\n # Use regular expression to find all substrings enclosed in double quotes\n quoted_values = re.findall(r'\\\"(.*?)\\\"', input_str)\n \n return quoted_values", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(s):\n \"\"\"\n Extract values between quotation marks \" \" of the given string.\n\n Args:\n s (str): The input string.\n\n Returns:\n list: A list of values between quotation marks.\n \"\"\"\n return re.findall(r'\"([^\"]*)\"', s)", "matching_cluster_idx": 6}, {"solution": "def extract_quotation(s):\n \"\"\"\n This function takes a string `s` as input, extracts all values between quotation marks,\n and returns them as a list.\n\n Args:\n s (str): Input string containing quoted values.\n\n Returns:\n list: List of extracted values.\n \"\"\"\n result = []\n in_quote = False\n current = \"\"\n \n for char in s:\n if char == '\"':\n in_quote = not in_quote\n if not in_quote:\n result.append(current)\n current = \"\"\n elif in_quote:\n current += char\n \n return result", "matching_cluster_idx": 2}, {"solution": "def extract_quotation(s):\n \"\"\"\n Extract values between quotation marks from a given string.\n\n Args:\n s (str): The input string.\n\n Returns:\n list: A list of values between quotation marks.\n\n Example:\n >>> extract_quotation('Cortex \"A53\" Based \"multi\" tasking \"Processor\"')\n ['A53', 'multi', 'Processor']\n \"\"\"\n values = []\n quote_started = False\n current_value = \"\"\n\n for char in s:\n if char == '\"':\n quote_started = not quote_started\n if not quote_started:\n values.append(current_value)\n current_value = \"\"\n elif quote_started:\n current_value += char\n\n return values", "matching_cluster_idx": 2}, {"solution": "def extract_quotation(input_string):\n \"\"\"\n Extract values between quotation marks from a given string.\n\n Args:\n input_string (str): Input string with quoted values.\n\n Returns:\n list: List of values between quotation marks.\n\n \"\"\"\n import re\n # Regular expression pattern to find values between quotation marks\n pattern = r'\"(.*?)\"'\n # Find all occurrences of the pattern in the string\n matches = re.findall(pattern, input_string)\n return matches", "matching_cluster_idx": 5}, {"solution": "def extract_quotation(input_string):\n \"\"\"\n Extract values between quotation marks \" \" of the given string.\n \n Args:\n input_string (str): Input string containing quoted values.\n \n Returns:\n list: A list of values extracted from between quotation marks.\n \"\"\"\n result = []\n is_quoted = False\n temp_str = \"\"\n \n for char in input_string:\n if char == '\"':\n is_quoted = not is_quoted\n if not is_quoted:\n result.append(temp_str)\n temp_str = \"\"\n elif is_quoted:\n temp_str += char\n \n return result", "matching_cluster_idx": 2}]}, "Mbpp/732": {"dps": 78.23643410852713, "dps_norm": 94.5, "pass@1": 95.0, "profiled": [{"solution": "def replace_specialchar(input_str):\n \"\"\"\n Replaces all occurrences of spaces, commas, or dots with a colon.\n\n Args:\n input_str (str): Input string.\n\n Returns:\n str: The string with spaces, commas, or dots replaced by a colon.\n \"\"\"\n # Define characters to be replaced\n chars_to_replace = [' ', ',', '.']\n # Iterate over the characters to replace and replace them with a colon\n for char in chars_to_replace:\n input_str = input_str.replace(char, ':')\n return input_str", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(s):\n \"\"\"\n Replace all occurrences of spaces, commas, or dots with a colon.\n \n Args:\n s (str): The input string\n \n Returns:\n str: The modified string\n \"\"\"\n return s.replace(' ', ':').replace(',', ':').replace('.', ':')", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(input_string):\n \"\"\"\n Replace all occurrences of spaces, commas, or dots with a colon.\n\n Args:\n input_string (str): The string to replace special characters in.\n\n Returns:\n str: The string with spaces, commas, and dots replaced with colons.\n \"\"\"\n return input_string.replace(' ', ':').replace(',', ':').replace('.', ':')", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(input_string):\n \"\"\"\n Replaces all occurrences of spaces, commas, or dots with a colon.\n\n Args:\n input_string (str): The input string to process.\n\n Returns:\n str: The string with spaces, commas, or dots replaced with a colon.\n \"\"\"\n return input_string.replace(\" \", \":\").replace(\",\", \":\").replace(\".\", \":\")", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(s):\n \"\"\"\n This function replaces all occurrences of spaces, commas, or dots with a colon in a string.\n\n Args:\n s (str): The input string.\n\n Returns:\n str: A new string where all occurrences of spaces, commas, or dots have been replaced with a colon.\n\n \"\"\"\n # Using the built-in replace method of Python strings, we can replace these special characters\n # However, there is no built-in method to replace multiple characters at once. \n # So we'll use the translate and maketrans methods instead.\n # The translate method returns a string where some specified characters are replaced with a dictionary describing replacements.\n # The maketrans method returns a translation table that can be used with the translate method.\n\n # First, we define the characters to be replaced and the replacement character\n # We use the ord function to get the Unicode point of the characters\n # This is necessary for the maketrans method\n replacements = str.maketrans({ord(' '):':', ord(','):':', ord('.'):':'})\n \n # Then we use the translate method to replace the characters\n return s.translate(replacements)", "matching_cluster_idx": 8}, {"solution": "def replace_specialchar(input_string):\n \"\"\"\n This function takes a string as an input and replaces all occurrences of spaces, commas, or dots with a colon.\n\n Args:\n input_string (str): Input string in which special characters will be replaced.\n\n Returns:\n str: String with replaced special characters.\n \"\"\"\n return input_string.replace(' ', ':').replace(',', ':').replace('.', ':')", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(input_str):\n \"\"\"\n Replaces all occurrences of spaces, commas, or dots with a colon in a given string.\n \n Args:\n input_str (str): Input string in which special characters will be replaced.\n \n Returns:\n str: String where all occurrences of spaces, commas, and dots are replaced with a colon.\n \"\"\"\n return input_str.replace(' ', ':').replace(',', ':').replace('.', ':')", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(input_string):\n \"\"\"\n This function replaces all occurrences of spaces, commas, and dots with a colon.\n\n Args:\n input_string (str): Input string where special characters will be replaced.\n\n Returns:\n str: Modified string with spaces, commas, and dots replaced with a colon.\n \"\"\"\n # Use the replace function to substitute the characters\n modified_string = input_string.replace(' ', ':').replace(',', ':').replace('.', ':')\n \n return modified_string", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(input_str):\n \"\"\"\n Replaces all occurrences of spaces, commas, or dots with a colon.\n\n Args:\n input_str (str): Input string.\n\n Returns:\n str: Modified string with spaces, commas, and dots replaced with colons.\n\n Examples:\n >>> replace_specialchar('Python language, Programming language.')\n 'Python:language::Programming:language:'\n \"\"\"\n return input_str.replace(' ', ':').replace(',', ':').replace('.', ':')", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(s):\n \"\"\"\n This function replaces all occurrences of spaces, commas, or dots in a string with a colon.\n\n Parameters:\n s (str): The input string to be processed.\n\n Returns:\n str: The modified string with spaces, commas, and dots replaced by colons.\n \"\"\"\n # Define the characters to be replaced and their replacement\n chars_to_replace = ' .,'\n replacement = ':'\n\n # Initialize an empty string to store the result\n result = ''\n\n # Iterate over each character in the input string\n for char in s:\n # If the character is in the list of characters to be replaced, append the replacement\n if char in chars_to_replace:\n result += replacement\n # Otherwise, append the character itself\n else:\n result += char\n\n # Return the modified string\n return result", "matching_cluster_idx": 3}, {"solution": "def replace_specialchar(input_string):\n \"\"\"\n Replaces all occurrences of spaces, commas, or dots with a colon.\n\n Args:\n input_string (str): Input string to be processed.\n\n Returns:\n str: Input string with all occurrences of spaces, commas, or dots replaced with a colon.\n \"\"\"\n return input_string.replace(' ', ':').replace(',', ':').replace('.', ':')", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(text):\n \"\"\"\n Replaces all occurrences of spaces, commas, or dots in a string with a colon.\n\n Args:\n text (str): The input string.\n\n Returns:\n str: The input string with spaces, commas, and dots replaced by colons.\n \"\"\"\n # Use str.translate to replace spaces, commas, and dots with colons\n # First, create a translation table\n translation_table = str.maketrans({ ' ': ':', ',': ':', '.': ':'})\n \n # Then, apply the translation table to the input text\n return text.translate(translation_table)", "matching_cluster_idx": 8}, {"solution": "def replace_specialchar(input_string):\n \"\"\"\n Replace all occurrences of spaces, commas, or dots with a colon.\n \n Parameters:\n input_string (str): Input string to replace special characters.\n \n Returns:\n str: String with spaces, commas, or dots replaced with a colon.\n \"\"\"\n return input_string.replace(' ', ':').replace(',', ':').replace('.', ':')", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(input_str):\n \"\"\"\n Replaces all occurrences of spaces, commas, or dots with a colon in a given string.\n \n Parameters:\n input_str (str): The input string to replace characters in.\n \n Returns:\n str: A new string with spaces, commas, and dots replaced by colons.\n \"\"\"\n return input_str.replace(\" \", \":\").replace(\",\", \":\").replace(\".\", \":\")", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(input_string):\n \"\"\"\n Replace all occurrences of spaces, commas, or dots with a colon.\n\n Args:\n input_string (str): Input string to replace special characters.\n\n Returns:\n str: String with spaces, commas, or dots replaced with a colon.\n \"\"\"\n # Define the special characters to be replaced\n special_chars = [' ', ',', '.']\n \n # Use the translate method along with str.maketrans to replace special characters\n translation_table = str.maketrans({char: ':' for char in special_chars})\n \n # Apply translation to the input string\n output_string = input_string.translate(translation_table)\n \n return output_string", "matching_cluster_idx": 8}, {"solution": "def replace_specialchar(s):\n \"\"\"\n Replace all occurrences of spaces, commas, or dots with a colon.\n \n Parameters\n ----------\n s : str\n Input string that needs replacement of special characters.\n \n Returns\n -------\n str\n Input string with all occurrences of spaces, commas, or dots replaced with colons.\n \"\"\"\n return s.replace(' ', ':').replace(',', ':').replace('.', ':')", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(s):\n \"\"\"\n Replace all occurrences of spaces, commas, or dots with a colon.\n\n Args:\n s (str): The input string to be modified.\n\n Returns:\n str: The modified string with spaces, commas, and dots replaced with colons.\n \"\"\"\n return s.replace(' ', ':').replace(',', ':').replace('.', ':')", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(input_str):\n \"\"\"\n Replace all occurrences of spaces, commas, or dots with a colon.\n\n Args:\n input_str (str): Input string containing spaces, commas, or dots.\n\n Returns:\n str: String with all spaces, commas, or dots replaced with a colon.\n \"\"\"\n # Define the characters to replace\n chars_to_replace = [' ', ',', '.']\n \n # Use the translate method with a translation table\n # First, create the translation table\n translation_table = str.maketrans({char: ':' for char in chars_to_replace})\n \n # Apply the translation\n result_str = input_str.translate(translation_table)\n \n return result_str", "matching_cluster_idx": 8}, {"solution": "def replace_specialchar(input_str):\n \"\"\"\n Replaces all occurrences of spaces, commas, or dots with a colon in a given string.\n\n Args:\n input_str (str): Input string to be modified.\n\n Returns:\n str: Modified string with spaces, commas, and dots replaced with colons.\n \"\"\"\n # Using Python's built-in string replace() method along with str.translate()\n # method and str.maketrans() to replace multiple characters at once\n trans_table = str.maketrans({' ': ':', ',': ':', '.': ':'})\n return input_str.translate(trans_table)", "matching_cluster_idx": 8}, {"solution": "def replace_specialchar(s):\n \"\"\"\n Replaces all occurrences of spaces, commas, or dots with a colon in a string.\n\n Args:\n s (str): The input string.\n\n Returns:\n str: The string with all spaces, commas, and dots replaced with a colon.\n \"\"\"\n return s.replace(' ', ':').replace(',', ':').replace('.', ':')", "matching_cluster_idx": 9}]}, "Mbpp/740": {"dps": 84.60000000000001, "dps_norm": 69.44444444444444, "pass@1": 100.0, "profiled": [{"solution": "def tuple_to_dict(tup):\n \"\"\"\n This function takes an input tuple with an even number of elements\n and converts it into a dictionary where every odd-indexed element is \n a value of the even-indexed element before it.\n\n Args:\n tup (tuple): The input tuple.\n\n Returns:\n dict: A dictionary with the tuple elements converted to key-value pairs.\n \"\"\"\n return {tup[i]: tup[i + 1] for i in range(0, len(tup), 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(tup):\n \"\"\"\n Converts a tuple of values to a dictionary using adjacent elements as key-value pairs.\n \n Args:\n tup (tuple): Input tuple of values.\n \n Returns:\n dict: A dictionary with adjacent elements of the input tuple as key-value pairs.\n \"\"\"\n # Check if the input tuple is empty\n if not tup:\n return {}\n \n # Check if the length of the input tuple is odd\n if len(tup) % 2 != 0:\n raise ValueError(\"Input tuple must have an even number of elements\")\n \n # Initialize an empty dictionary\n result = {}\n \n # Iterate over the input tuple with a step of 2\n for i in range(0, len(tup), 2):\n # Assign the value at the current index as the key and the value at the next index as the value\n result[tup[i]] = tup[i + 1]\n \n return result", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(tup):\n \"\"\"\n Converts the given tuple to a dictionary by mapping adjacent elements as key-value pairs.\n \n Parameters:\n tup (tuple): The input tuple containing key-value pairs.\n \n Returns:\n dict: A dictionary with key-value pairs based on the input tuple.\n \"\"\"\n # Check if the tuple has an even number of elements\n if len(tup) % 2 != 0:\n raise ValueError(\"The input tuple must have an even number of elements.\")\n \n # Use a dictionary comprehension with a step of 2 to create key-value pairs\n return {tup[i]: tup[i + 1] for i in range(0, len(tup), 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(tup):\n \"\"\"\n This function converts the given tuple to a key-value dictionary.\n It uses adjacent elements in the tuple as key-value pairs in the dictionary.\n\n Args:\n tup (tuple): Input tuple.\n\n Returns:\n dict: Dictionary where keys and values are adjacent elements in the tuple.\n\n Raises:\n ValueError: If the length of the tuple is odd.\n \"\"\"\n # Check if the length of the tuple is even\n if len(tup) % 2 != 0:\n raise ValueError(\"The length of the tuple must be even.\")\n\n # Use dictionary comprehension to create a dictionary from the tuple\n # The expression tup[::2] gets all elements at even indices (keys)\n # The expression tup[1::2] gets all elements at odd indices (values)\n return {tup[i]: tup[i+1] for i in range(0, len(tup), 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(tup):\n \"\"\"\n This function takes an input tuple of even length and returns a dictionary.\n Each key-value pair in the resulting dictionary corresponds to two adjacent elements in the input tuple.\n\n Args:\n tup (tuple): A tuple of even length.\n\n Returns:\n dict: A dictionary with keys and values from the input tuple.\n\n Raises:\n ValueError: If the input tuple has an odd length.\n \"\"\"\n # Check if the tuple has an even length\n if len(tup) % 2 != 0:\n raise ValueError(\"The input tuple must have an even length.\")\n\n # Use dictionary comprehension and slicing to create the dictionary\n return {tup[i]: tup[i + 1] for i in range(0, len(tup), 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(input_tuple):\n \"\"\"\n This function converts a given tuple to a key-value dictionary.\n Adjacent elements in the tuple are used as key-value pairs.\n\n Args:\n input_tuple: A tuple containing keys and values.\n\n Returns:\n dict: A dictionary created from the tuple.\n\n Raises:\n ValueError: If the tuple has an odd number of elements.\n \"\"\"\n if len(input_tuple) % 2 != 0:\n raise ValueError(\"Tuple must have an even number of elements.\")\n\n # Use dictionary comprehension to create the dictionary\n # The step in the range function is set to 2, so we're iterating over every other element\n # The key is every other element, starting from the first (index 0)\n # The value is every other element, starting from the second (index 1)\n return {input_tuple[i]: input_tuple[i + 1] for i in range(0, len(input_tuple), 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(input_tuple):\n \"\"\"\n Converts the given tuple to a key-value dictionary using adjacent elements.\n\n Args:\n input_tuple: A tuple containing an even number of elements, where each key-value pair\n is represented as adjacent elements in the tuple.\n\n Returns:\n dict: A dictionary where each key-value pair corresponds to the adjacent elements in the input tuple.\n\n Raises:\n ValueError: If the input tuple has an odd number of elements.\n \"\"\"\n if len(input_tuple) % 2 != 0:\n raise ValueError(\"Input tuple must have an even number of elements\")\n\n return {input_tuple[i]: input_tuple[i+1] for i in range(0, len(input_tuple), 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(tup):\n \"\"\"\n Convert the given tuple to a key-value dictionary using adjacent elements.\n \n Parameters:\n tup (tuple): Input tuple.\n \n Returns:\n dict: Dictionary created from the tuple.\n \"\"\"\n # Check if the tuple length is even\n if len(tup) % 2 != 0:\n raise ValueError(\"Tuple length must be even\")\n\n # Use dictionary comprehension to create the dictionary\n return {tup[i]: tup[i+1] for i in range(0, len(tup), 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(tup):\n \"\"\"\n Converts the given tuple to a key-value dictionary using adjacent elements.\n\n Args:\n tup: Input tuple with an even number of elements.\n\n Returns:\n A dictionary where the keys are the values at even indices and the values are the values at the next odd indices.\n\n Raises:\n ValueError: If the tuple has an odd number of elements.\n \"\"\"\n if len(tup) % 2 != 0:\n raise ValueError(\"Tuple must have an even number of elements\")\n\n return {tup[i]: tup[i+1] for i in range(0, len(tup), 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(input_tuple):\n \"\"\"\n Converts the given tuple to a dictionary, using adjacent elements as key-value pairs.\n \n Args:\n input_tuple: A tuple containing values to be converted to a dictionary.\n \n Returns:\n A dictionary with every odd-indexed element (starting from index 0) as the key,\n and the following even-indexed element as the value.\n \n Raises:\n ValueError: If the tuple has an odd number of elements.\n \"\"\"\n if len(input_tuple) % 2 != 0:\n raise ValueError(\"Tuple must have an even number of elements.\")\n \n return {input_tuple[i]: input_tuple[i + 1] for i in range(0, len(input_tuple), 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(tup):\n \"\"\"\n Converts the given tuple to a key-value dictionary using adjacent elements.\n \n Args:\n tup (tuple): A tuple of values where adjacent elements are paired into key-value pairs.\n\n Returns:\n dict: A dictionary where each key is an element at an even index in the tuple,\n and its corresponding value is the next element in the tuple.\n\n Raises:\n ValueError: If the tuple has an odd number of elements.\n \"\"\"\n\n # Check if the tuple has an odd number of elements\n if len(tup) % 2 != 0:\n raise ValueError(\"The tuple must have an even number of elements.\")\n\n # Initialize an empty dictionary to store key-value pairs\n result = {}\n\n # Iterate over the tuple with a step of 2\n for i in range(0, len(tup), 2):\n # Use the current element as the key and the next element as the value\n result[tup[i]] = tup[i + 1]\n\n return result", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(tup):\n \"\"\"\n This function takes a tuple of elements and converts it to a key-value dictionary.\n It assumes that the input tuple has an even number of elements and uses \n adjacent elements as key-value pairs.\n\n Args:\n tup (tuple): The input tuple.\n\n Returns:\n dict: A dictionary where each key-value pair comes from adjacent elements in the input tuple.\n \"\"\"\n if len(tup) % 2 != 0:\n raise ValueError(\"Input tuple must have an even number of elements\")\n\n return {tup[i]: tup[i + 1] for i in range(0, len(tup), 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(input_tuple):\n \"\"\"\n This function takes an input tuple and converts it into a dictionary.\n Adjacent elements are used as key-value pairs.\n \n Args:\n input_tuple (tuple): A tuple containing elements to be converted into key-value pairs.\n \n Returns:\n dict: A dictionary created from the input tuple.\n \"\"\"\n \n # Check if the tuple has an odd number of elements\n if len(input_tuple) % 2 != 0:\n raise ValueError(\"Input tuple must have an even number of elements.\")\n \n # Use dictionary comprehension to create a dictionary from the input tuple\n return {input_tuple[i]: input_tuple[i + 1] for i in range(0, len(input_tuple), 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(tup):\n \"\"\"\n Converts a given tuple into a dictionary using adjacent elements as key-value pairs.\n\n Args:\n tup: A tuple with an even number of elements.\n\n Returns:\n A dictionary where the first element in each pair is the key and the second is the value.\n\n Raises:\n ValueError: If the tuple has an odd number of elements.\n \"\"\"\n # Check if tuple has an even number of elements\n if len(tup) % 2 != 0:\n raise ValueError(\"Tuple must have an even number of elements.\")\n\n # Initialize an empty dictionary\n result = {}\n\n # Iterate over the tuple in steps of 2\n for i in range(0, len(tup), 2):\n # Use the current element as the key and the next one as the value\n result[tup[i]] = tup[i + 1]\n\n return result", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(tup):\n \"\"\"\n Converts a given tuple into a dictionary using adjacent elements.\n \n The first element of each pair is used as the key and the second as the value.\n \n Args:\n tup: A tuple containing an even number of elements.\n \n Returns:\n A dictionary with keys and values created from the tuple's adjacent elements.\n \"\"\"\n # Ensure the tuple has an even number of elements\n if len(tup) % 2 != 0:\n raise ValueError(\"The tuple must contain an even number of elements.\")\n \n # Use dictionary comprehension with zip() function to pair every two elements\n return {k: v for k, v in zip(tup[::2], tup[1::2])}", "matching_cluster_idx": 7}, {"solution": "def tuple_to_dict(input_tuple):\n \"\"\"\n This function takes a tuple as input and converts it into a dictionary.\n It assumes that the input tuple has an even number of elements and \n uses each pair of adjacent elements as key-value pairs in the resulting dictionary.\n\n Args:\n input_tuple (tuple): The input tuple to be converted.\n\n Returns:\n dict: A dictionary where each key-value pair is formed from adjacent elements in the input tuple.\n \"\"\"\n\n # Check if the tuple has an even number of elements\n if len(input_tuple) % 2 != 0:\n raise ValueError(\"The input tuple must have an even number of elements.\")\n\n # Use a dictionary comprehension to create the dictionary\n # We use the range function to iterate over the indices of the tuple in steps of 2\n # For each index, we use the current element as the key and the next element as the value\n output_dict = {input_tuple[i]: input_tuple[i + 1] for i in range(0, len(input_tuple), 2)}\n\n return output_dict", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(tup):\n \"\"\"\n Convert a tuple to a dictionary using adjacent elements as key-value pairs.\n\n Args:\n tup (tuple): Input tuple. The length of the tuple must be even.\n\n Returns:\n dict: A dictionary where each key-value pair consists of adjacent elements from the input tuple.\n\n Raises:\n ValueError: If the length of the input tuple is odd.\n \"\"\"\n if len(tup) % 2 != 0:\n raise ValueError(\"The length of the input tuple must be even\")\n\n return {tup[i]: tup[i + 1] for i in range(0, len(tup), 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(tup):\n \"\"\"\n Convert a given tuple to a dictionary, using each pair of adjacent elements as key-value pairs.\n\n Args:\n tup (tuple): The input tuple.\n\n Returns:\n dict: A dictionary where keys are every other element in the tuple and values are the elements adjacent to the keys.\n\n Raises:\n ValueError: If the tuple has an odd number of elements.\n \"\"\"\n if len(tup) % 2 != 0:\n raise ValueError(\"Tuple must have an even number of elements\")\n \n return dict(zip(tup[::2], tup[1::2]))", "matching_cluster_idx": 8}, {"solution": "def tuple_to_dict(input_tuple):\n \"\"\"\n This function converts a given tuple into a dictionary.\n It uses the first element of each pair as the key and the second as the value.\n \n Args:\n input_tuple (tuple): The input tuple containing elements to be converted.\n \n Returns:\n dict: A dictionary with the keys and values formed by adjacent elements of the tuple.\n \"\"\"\n \n # Check if the tuple has an even number of elements\n if len(input_tuple) % 2 != 0:\n raise ValueError(\"Input tuple must have an even number of elements\")\n \n # Initialize an empty dictionary\n result_dict = {}\n \n # Iterate over the input tuple two elements at a time\n for i in range(0, len(input_tuple), 2):\n # Use the current element as the key and the next one as the value\n result_dict[input_tuple[i]] = input_tuple[i + 1]\n \n return result_dict", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(tup):\n \"\"\"\n Converts a given tuple into a dictionary where every key is an element at an odd index (0-indexed)\n and the corresponding value is the element at the next index.\n\n Args:\n tup (tuple): Input tuple to be converted.\n\n Returns:\n dict: Dictionary created from the input tuple.\n\n Raises:\n ValueError: If the input tuple has an odd number of elements.\n \"\"\"\n if len(tup) % 2 != 0:\n raise ValueError(\"Input tuple must have an even number of elements.\")\n\n return {tup[i]: tup[i + 1] for i in range(0, len(tup), 2)}", "matching_cluster_idx": 5}]}, "Mbpp/744": {"dps": 42.56849315068493, "dps_norm": 58.333333333333336, "pass@1": 100.0, "profiled": [{"solution": "def check_none(tup):\n \"\"\"\n Checks if a given tuple has any None values.\n\n Args:\n tup (tuple): A tuple to be checked.\n\n Returns:\n bool: True if the tuple contains at least one None value, False otherwise.\n \"\"\"\n return None in tup", "matching_cluster_idx": 5}, {"solution": "def check_none(input_tuple):\n \"\"\"\n This function checks if the given tuple contains any None value.\n\n Args:\n input_tuple (tuple): The input tuple to be checked.\n\n Returns:\n bool: True if the tuple contains a None value, False otherwise.\n \"\"\"\n return any(item is None for item in input_tuple)", "matching_cluster_idx": 1}, {"solution": "def check_none(tup):\n \"\"\"\n Check if a tuple contains any None value.\n\n Args:\n tup (tuple): Input tuple.\n\n Returns:\n bool: True if the tuple contains None, False otherwise.\n \"\"\"\n return None in tup", "matching_cluster_idx": 4}, {"solution": "def check_none(input_tuple):\n \"\"\"\n Checks if a given tuple contains any None value.\n\n Args:\n input_tuple (tuple): The tuple to be checked.\n\n Returns:\n bool: True if the tuple contains any None value, False otherwise.\n \"\"\"\n return any(item is None for item in input_tuple)", "matching_cluster_idx": 2}, {"solution": "def check_none(tup):\n \"\"\"\n Checks if a tuple contains any None values.\n\n Args:\n tup (tuple): The input tuple to check.\n\n Returns:\n bool: True if the tuple contains at least one None value, False otherwise.\n \"\"\"\n return any(val is None for val in tup)", "matching_cluster_idx": 2}, {"solution": "def check_none(input_tuple):\n \"\"\"\n Checks if the given tuple has any None values.\n\n Args:\n input_tuple (tuple): Input tuple to check.\n\n Returns:\n bool: True if the tuple has any None values, False otherwise.\n \"\"\"\n return any(x is None for x in input_tuple)", "matching_cluster_idx": 2}, {"solution": "def check_none(input_tuple):\n \"\"\"\n This function checks if the given tuple has any None value.\n\n Args:\n input_tuple (tuple): Input tuple to be checked.\n\n Returns:\n bool: True if the tuple has any None value, False otherwise.\n \"\"\"\n return any(element is None for element in input_tuple)", "matching_cluster_idx": 2}, {"solution": "def check_none(input_tuple):\n \"\"\"\n This function checks if there's any None value in the given tuple.\n \n Args:\n input_tuple (tuple): The input tuple to be checked.\n \n Returns:\n bool: True if there's any None value, False otherwise.\n \"\"\"\n return any(i is None for i in input_tuple)", "matching_cluster_idx": 2}, {"solution": "def check_none(input_tuple):\n \"\"\"\n This function checks if a tuple has any None value.\n\n Args:\n input_tuple (tuple): The tuple to be checked.\n\n Returns:\n bool: True if the tuple contains any None value, False otherwise.\n \"\"\"\n return any(item is None for item in input_tuple)", "matching_cluster_idx": 2}, {"solution": "def check_none(input_tuple):\n \"\"\"\n Checks if a tuple contains any None value.\n\n Args:\n input_tuple (tuple): Input tuple to be checked.\n\n Returns:\n bool: True if the tuple contains a None value, False otherwise.\n \"\"\"\n return any(val is None for val in input_tuple)", "matching_cluster_idx": 2}, {"solution": "def check_none(input_tuple):\n \"\"\"\n Checks if the given tuple contains any None value.\n \n Args:\n input_tuple (tuple): The input tuple to be checked.\n \n Returns:\n bool: True if the tuple contains any None value, False otherwise.\n \"\"\"\n return any(item is None for item in input_tuple)", "matching_cluster_idx": 2}, {"solution": "def check_none(input_tuple):\n \"\"\"\n Checks if a given tuple contains any None value.\n\n Args:\n input_tuple (tuple): The input tuple to check.\n\n Returns:\n bool: True if the tuple contains None, False otherwise.\n \"\"\"\n return any(x is None for x in input_tuple)", "matching_cluster_idx": 2}, {"solution": "def check_none(tup):\n \"\"\"\n Checks if a tuple contains at least one None value.\n\n Args:\n tup (tuple): The input tuple.\n\n Returns:\n bool: True if the tuple contains a None value, False otherwise.\n \"\"\"\n return any(val is None for val in tup)", "matching_cluster_idx": 2}, {"solution": "def check_none(input_tuple):\n \"\"\"\n Checks if the given tuple has any None value.\n\n Args:\n input_tuple: A tuple to check for None values.\n\n Returns:\n bool: True if the tuple contains a None value, False otherwise.\n \"\"\"\n return None in input_tuple", "matching_cluster_idx": 5}, {"solution": "def check_none(given_tuple):\n \"\"\"\n This function checks if the given tuple has any None value.\n\n Args:\n given_tuple (tuple): A tuple containing any type of values.\n\n Returns:\n bool: True if the tuple contains any None value, False otherwise.\n \"\"\"\n return any(val is None for val in given_tuple)", "matching_cluster_idx": 2}, {"solution": "def check_none(input_tuple):\n \"\"\"\n This function checks if any value in the input tuple is None.\n \n Args:\n input_tuple (tuple): A tuple to be checked for None values.\n \n Returns:\n bool: True if any value in the tuple is None, False otherwise.\n \"\"\"\n return any(val is None for val in input_tuple)", "matching_cluster_idx": 2}, {"solution": "def check_none(tup):\n \"\"\"\n Checks if a given tuple has any None values.\n \n Args:\n tup (tuple): Input tuple to check.\n \n Returns:\n bool: True if the tuple contains at least one None, False otherwise.\n \"\"\"\n return any(val is None for val in tup)", "matching_cluster_idx": 2}, {"solution": "def check_none(input_tuple):\n \"\"\"\n This function checks if a given tuple contains any None values.\n\n Args:\n input_tuple (tuple): The input tuple to be checked.\n\n Returns:\n bool: True if the tuple contains at least one None value, False otherwise.\n \"\"\"\n return any(val is None for val in input_tuple)", "matching_cluster_idx": 2}, {"solution": "def check_none(given_tuple):\n \"\"\"\n This function checks if a given tuple contains any None value.\n \n Parameters:\n given_tuple (tuple): The input tuple to be checked.\n \n Returns:\n bool: True if the tuple contains None, False otherwise.\n \"\"\"\n return None in given_tuple", "matching_cluster_idx": 5}, {"solution": "def check_none(tup):\n \"\"\"\n This function checks if a given tuple contains any None values.\n\n Args:\n tup (tuple): A tuple to be checked for None values.\n\n Returns:\n bool: True if the tuple contains any None values, False otherwise.\n \"\"\"\n return any(item is None for item in tup)", "matching_cluster_idx": 2}]}, "Mbpp/750": {"dps": 55.8843537414966, "dps_norm": 55.0, "pass@1": 100.0, "profiled": [{"solution": "def add_tuple(lst, tup):\n \"\"\"\n Adds the given tuple to the given list.\n \n Args:\n lst (list): The list to append elements to.\n tup (tuple): The tuple containing elements to append.\n \n Returns:\n list: The updated list with elements from the tuple.\n \"\"\"\n # Convert the tuple to a list to make it mutable\n # If we directly append a tuple to a list, it appends the tuple as a whole element\n # Instead, we want to extend the list with the tuple elements\n lst.extend(list(tup))\n \n # Return the updated list\n return lst", "matching_cluster_idx": 4}, {"solution": "def add_tuple(input_list, input_tuple):\n \"\"\"\n Adds the given tuple to the given list.\n\n Args:\n input_list (list): List to add elements to.\n input_tuple (tuple): Tuple to add to the list.\n\n Returns:\n list: Input list with the elements from the input tuple appended.\n\n \"\"\"\n return input_list + list(input_tuple)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(input_list, input_tuple):\n \"\"\"\n This function adds a given tuple to a given list.\n\n Args:\n input_list (list): A list of elements.\n input_tuple (tuple): A tuple of elements.\n\n Returns:\n list: The updated list with tuple elements appended.\n\n \"\"\"\n # Convert the tuple to a list\n tuple_list = list(input_tuple)\n \n # Use list extend to add tuple elements to the input list\n input_list.extend(tuple_list)\n \n # Return the updated list\n return input_list", "matching_cluster_idx": 3}, {"solution": "def add_tuple(lst, tup):\n \"\"\"\n Adds all elements of a given tuple to a given list.\n\n Args:\n lst (list): The list to be extended.\n tup (tuple): The tuple whose elements will be added to the list.\n\n Returns:\n list: The extended list with tuple elements.\n\n Example:\n >>> add_tuple([5, 6, 7], (9, 10))\n [5, 6, 7, 9, 10]\n \"\"\"\n return lst + list(tup)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(input_list, input_tuple):\n \"\"\"\n This function adds the given tuple to the given list.\n \n Args:\n input_list (list): The list to which the tuple is to be added.\n input_tuple (tuple): The tuple to be added to the list.\n \n Returns:\n list: A new list containing all elements of the original list and tuple.\n \"\"\"\n return input_list + list(input_tuple)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(input_list, tuple_to_add):\n \"\"\"\n This function adds the given tuple to the given list.\n\n Args:\n input_list (list): The list to which the tuple will be added.\n tuple_to_add (tuple): The tuple to be added to the list.\n\n Returns:\n list: The list with the tuple added.\n \"\"\"\n return input_list + list(tuple_to_add)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(input_list, input_tuple):\n \"\"\"\n Adds the elements of the given tuple to the given list.\n\n Args:\n input_list (list): The input list to which the tuple elements are to be added.\n input_tuple (tuple): The tuple whose elements are to be added to the list.\n\n Returns:\n list: The list with the tuple elements added to it.\n \"\"\"\n return input_list + list(input_tuple)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(input_list, input_tuple):\n \"\"\"\n Adds all elements of the input tuple to the input list.\n \n Args:\n input_list (list): List to add elements to.\n input_tuple (tuple): Tuple containing elements to add to the list.\n \n Returns:\n list: Updated list with all elements from the input tuple appended.\n \"\"\"\n return input_list + list(input_tuple)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(input_list, input_tuple):\n \"\"\"\n Adds the given tuple to the given list.\n \n Args:\n input_list (list): The original list.\n input_tuple (tuple): The tuple to be added.\n \n Returns:\n list: The updated list with the tuple elements appended.\n \"\"\"\n return input_list + list(input_tuple)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(lst, tup):\n \"\"\"\n This function adds the given tuple to the given list.\n \n Args:\n lst (list): The original list to be modified.\n tup (tuple): The tuple to be added to the list.\n \n Returns:\n list: A new list containing the elements from the original list and the tuple.\n \"\"\"\n return lst + list(tup)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(lst, tup):\n \"\"\"\n Appends the given tuple's elements to the given list.\n\n Args:\n lst (list): The list to which the tuple elements will be added.\n tup (tuple): The tuple whose elements will be added to the list.\n\n Returns:\n list: The updated list with the tuple's elements appended.\n \"\"\"\n return lst + list(tup)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(input_list, input_tuple):\n \"\"\"\n Appends the given tuple elements to the given list.\n\n Args:\n input_list (list): The list to append elements to.\n input_tuple (tuple): The tuple with elements to append.\n\n Returns:\n list: The list with the tuple elements appended.\n \"\"\"\n return input_list + list(input_tuple)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(lst, tup):\n \"\"\"\n Adds the elements of a given tuple to a given list.\n \n Args:\n lst (list): The list to which elements are added.\n tup (tuple): The tuple from which elements are taken.\n \n Returns:\n list: A new list containing all elements from the original list and the tuple.\n \"\"\"\n return lst + list(tup)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(lst, tup):\n \"\"\"\n Add the elements of a given tuple to a given list.\n\n Args:\n lst (list): The list to which elements are to be added.\n tup (tuple): The tuple whose elements are to be added to the list.\n\n Returns:\n list: A new list that includes all elements from the original list and the given tuple.\n\n \"\"\"\n return lst + list(tup)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(lst, tup):\n \"\"\"\n Appends a given tuple's elements to a given list.\n\n Args:\n lst (list): The list to append to.\n tup (tuple): The tuple to append from.\n\n Returns:\n list: The updated list with tuple's elements.\n \"\"\"\n return lst + list(tup)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(input_list, input_tuple):\n \"\"\"\n This function adds the elements of a given tuple to a given list.\n\n Args:\n input_list (list): A list to which tuple elements will be added.\n input_tuple (tuple): A tuple whose elements will be added to the list.\n\n Returns:\n list: The updated list with tuple elements appended.\n\n \"\"\"\n return input_list + list(input_tuple)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(lst, tup):\n \"\"\"\n Add elements of the given tuple to the given list.\n\n Args:\n lst (list): The original list.\n tup (tuple): The tuple to be added.\n\n Returns:\n list: The updated list with tuple elements.\n \"\"\"\n lst.extend(tup)\n return lst", "matching_cluster_idx": 5}, {"solution": "def add_tuple(lst, tup):\n \"\"\"\n Adds elements of the given tuple to the given list.\n\n Args:\n lst (list): The original list to which elements will be added.\n tup (tuple): The tuple containing elements to be added.\n\n Returns:\n list: The updated list with tuple elements appended.\n \"\"\"\n return lst + list(tup)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(input_list, input_tuple):\n \"\"\"\n This function appends elements from a given tuple to a given list.\n\n Args:\n input_list (list): List to which tuple elements will be appended.\n input_tuple (tuple): Tuple whose elements will be appended to the list.\n\n Returns:\n list: A new list containing all elements from the original list and the tuple.\n \"\"\"\n return input_list + list(input_tuple)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(input_list, input_tuple):\n \"\"\"\n Adds the given tuple elements to the end of the given list.\n\n Args:\n input_list (list): The list to which tuple elements are to be added.\n input_tuple (tuple): The tuple elements to be added to the list.\n\n Returns:\n list: A new list containing all elements from the input list and the input tuple.\n \"\"\"\n return input_list + list(input_tuple)", "matching_cluster_idx": 2}]}, "Mbpp/753": {"dps": 97.31543624161074, "dps_norm": 75.0, "pass@1": 94.0, "profiled": [{"solution": "def min_k(records, k):\n \"\"\"\n Return the k minimum records from a list of tuples.\n \n Args:\n records (list): A list of tuples, where each tuple contains a string and an integer.\n k (int): The number of minimum records to return.\n \n Returns:\n list: A list of the k minimum records.\n \"\"\"\n # Use the sorted function to sort the records based on the second element of each tuple\n # The sorted function is stable, so when multiple records have the same second element, \n # their original order is preserved\n sorted_records = sorted(records, key=lambda x: x[1])\n \n # Use list slicing to get the k minimum records\n return sorted_records[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(records, k):\n \"\"\"\n Returns the k smallest records from the input list.\n\n Args:\n records (list): A list of tuples, where each tuple contains a name and a value.\n k (int): The number of smallest records to return.\n\n Returns:\n list: The k smallest records.\n \"\"\"\n # First, we sort the records based on the value (assuming the value is at index 1)\n sorted_records = sorted(records, key=lambda x: x[1])\n\n # Then, we return the first k records\n return sorted_records[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(records, k):\n \"\"\"\n Returns the k records with the smallest values from a list of tuples.\n \n Args:\n records (list): A list of tuples where each tuple contains a string and a number.\n k (int): The number of records to return.\n \n Returns:\n list: A list of k tuples with the smallest values.\n \"\"\"\n # First, sort the records in ascending order based on the values\n sorted_records = sorted(records, key=lambda x: x[1])\n \n # Then, return the k smallest records\n return sorted_records[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(records, k):\n \"\"\"\n This function finds the minimum k records from a list of tuples.\n\n Args:\n records (list): A list of tuples, where each tuple contains a name and a score.\n k (int): The number of records to return.\n\n Returns:\n list: A list of k tuples with the lowest scores.\n \"\"\"\n return sorted(records, key=lambda x: x[1])[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(tuples_list, k):\n \"\"\"\n Find the minimum k records from a list of tuples.\n\n The function sorts the list based on the second element of the tuples and returns the first k elements.\n\n Args:\n tuples_list (list): A list of tuples, where the second element of each tuple is a comparable value.\n k (int): The number of minimum records to return.\n\n Returns:\n list: The minimum k records from the tuples list.\n\n Raises:\n ValueError: If k is larger than the length of tuples_list.\n \"\"\"\n\n # Check if k is larger than the length of tuples_list\n if k > len(tuples_list):\n raise ValueError(\"k cannot be larger than the length of tuples_list\")\n\n # Sort the list based on the second element of the tuples\n sorted_tuples = sorted(tuples_list, key=lambda x: x[1])\n\n # Return the first k elements\n return sorted_tuples[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(records, k):\n \"\"\"\n This function finds the minimum k records from a list of tuples.\n\n Args:\n records (list): A list of tuples containing names and their corresponding values.\n k (int): The number of minimum records to find.\n\n Returns:\n list: A list of the k minimum records.\n\n \"\"\"\n # First, we sort the records based on the second element of each tuple (the values)\n sorted_records = sorted(records, key=lambda x: x[1])\n \n # Then, we return the first k records from the sorted list\n return sorted_records[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(records, k):\n \"\"\"\n Find minimum k records from a tuple list.\n\n Args:\n records (list): A list of tuples, where each tuple contains a name and a value.\n k (int): The number of minimum records to find.\n\n Returns:\n list: The k tuples with the smallest values.\n\n \"\"\"\n # Sort the records by their values in ascending order\n sorted_records = sorted(records, key=lambda x: x[1])\n \n # Return the k records with the smallest values\n return sorted_records[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(records, k):\n \"\"\"\n Returns the minimum k records from a tuple list based on the integer value.\n\n Args:\n records (list): A list of tuples where the second element of each tuple is the value to compare.\n k (int): The number of minimum records to return.\n\n Returns:\n list: A list of the minimum k records.\n\n Raises:\n ValueError: If k is larger than the number of records.\n \"\"\"\n if k > len(records):\n raise ValueError(\"k cannot be larger than the number of records\")\n\n # Sort the records based on the integer value\n sorted_records = sorted(records, key=lambda x: x[1])\n\n # Return the minimum k records\n return sorted_records[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(records, k):\n \"\"\"\n Find minimum k records from tuple list based on the integer value in each tuple.\n\n Args:\n records (list): A list of tuples containing a string and an integer.\n k (int): The number of records to return.\n\n Returns:\n list: A list of the k tuples with the smallest integer values.\n \"\"\"\n # Check if k is larger than the number of records\n if k > len(records):\n raise ValueError(\"k cannot be larger than the number of records\")\n\n # Sort the records based on the integer value in each tuple\n sorted_records = sorted(records, key=lambda x: x[1])\n\n # Return the k smallest records\n return sorted_records[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(records, k):\n \"\"\"\n Find the minimum k records from a list of tuples.\n\n Args:\n records (list): A list of tuples containing names and scores.\n k (int): The number of minimum records to return.\n\n Returns:\n list: The minimum k records.\n\n Raises:\n ValueError: If k is larger than the number of records.\n \"\"\"\n if k > len(records):\n raise ValueError(\"k cannot be larger than the number of records\")\n\n # Sort the records based on the second element (score) in ascending order\n sorted_records = sorted(records, key=lambda x: x[1])\n\n # Return the first k records\n return sorted_records[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(tuples_list, k):\n \"\"\"\n This function finds minimum k records from a list of tuples.\n \n Parameters:\n tuples_list (list): A list of tuples where each tuple contains a string and an integer.\n k (int): The number of minimum records to return.\n \n Returns:\n list: A list of k tuples with the smallest integers.\n \"\"\"\n # Sort the list of tuples based on the integer value in each tuple\n sorted_tuples = sorted(tuples_list, key=lambda x: x[1])\n \n # Return the first k tuples from the sorted list\n return sorted_tuples[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(records, k):\n \"\"\"\n Return the k records with the minimum values from a list of tuples.\n \n Args:\n records (list): A list of tuples where each tuple contains a string and an integer.\n k (int): The number of records to return.\n \n Returns:\n list: A list of k tuples with the smallest integer values.\n \"\"\"\n return sorted(records, key=lambda x: x[1])[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(records, k):\n \"\"\"\n This function returns the minimum k records from a list of tuples.\n\n Parameters:\n records (list): A list of tuples, where each tuple contains a string and an integer.\n k (int): The number of minimum records to return.\n\n Returns:\n list: A list of the k minimum records.\n \"\"\"\n # Check if k is greater than the number of records\n if k > len(records):\n raise ValueError(\"k cannot be greater than the number of records\")\n\n # Use the built-in sorted function with a custom key to sort the records\n # The sorted function returns a new list and does not modify the original list\n sorted_records = sorted(records, key=lambda x: x[1])\n\n # Return the k minimum records\n return sorted_records[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(records, k):\n \"\"\"\n Find minimum k records from a list of tuples.\n\n Args:\n records (list): A list of tuples containing a name and a value.\n k (int): The number of minimum records to return.\n\n Returns:\n list: A list of k tuples with the smallest values.\n\n Raises:\n ValueError: If k is larger than the number of records.\n \"\"\"\n\n # Check if k is larger than the number of records\n if k > len(records):\n raise ValueError(\"k cannot be larger than the number of records\")\n\n # Sort the records based on the values\n sorted_records = sorted(records, key=lambda x: x[1])\n\n # Return the k records with the smallest values\n return sorted_records[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(records, k):\n \"\"\"\n Return the k records with the smallest values from the input list of tuples.\n\n Args:\n records (list): A list of tuples containing a string and a number.\n k (int): The number of records to return.\n\n Returns:\n list: A list of the k tuples with the smallest numbers.\n\n Raises:\n ValueError: If k is larger than the number of records.\n \"\"\"\n\n if k > len(records):\n raise ValueError(\"k cannot be larger than the number of records\")\n\n # Sort the records by their numbers and return the k smallest ones\n return sorted(records, key=lambda x: x[1])[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(records, k):\n \"\"\"\n Find the minimum k records from a tuple list.\n\n Args:\n records (list): A list of tuples containing a name and a value.\n k (int): The number of records to return.\n\n Returns:\n list: The k records with the smallest values.\n \"\"\"\n # Sort the records by the value in ascending order\n sorted_records = sorted(records, key=lambda x: x[1])\n \n # Return the k smallest records\n return sorted_records[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(records, k):\n \"\"\"\n This function takes a list of tuples and an integer k as input, \n and returns the k records with the smallest values from the list.\n\n Args:\n records (list): A list of tuples containing string and integer values.\n k (int): The number of records to return.\n\n Returns:\n list: A list of the k tuples with the smallest integer values.\n \"\"\"\n # Check if k is greater than the number of records\n if k > len(records):\n raise ValueError(\"k cannot be greater than the number of records\")\n\n # Sort the records based on the integer value in each tuple\n sorted_records = sorted(records, key=lambda x: x[1])\n\n # Return the k records with the smallest values\n return sorted_records[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(records, k):\n \"\"\"\n This function returns the k smallest records from a list of tuples.\n \n Args:\n records (list): A list of tuples where the first element of the tuple is the name and the second element is the value.\n k (int): The number of smallest records to return.\n \n Returns:\n list: A list of the k smallest records.\n \"\"\"\n \n # First, we sort the list of records based on the second element of each tuple (the value)\n sorted_records = sorted(records, key=lambda x: x[1])\n \n # Then, we return the first k elements of the sorted list\n return sorted_records[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(records, k):\n \"\"\"\n This function returns the k records with the smallest values from a list of tuples.\n \n Args:\n records (list): A list of tuples where each tuple contains a name and a value.\n k (int): The number of records to return.\n \n Returns:\n list: A list of the k records with the smallest values.\n \"\"\"\n # First, we sort the records in ascending order based on the values\n sorted_records = sorted(records, key=lambda x: x[1])\n \n # Then, we return the first k records\n return sorted_records[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(records, k):\n \"\"\"\n Returns the k records with the smallest values from the given list of tuples.\n\n Args:\n records (list of tuples): A list of tuples containing a string and a number.\n k (int): The number of records to return.\n\n Returns:\n list of tuples: The k records with the smallest values.\n \"\"\"\n # Use the sorted function to sort the list of tuples based on the second element of each tuple\n sorted_records = sorted(records, key=lambda x: x[1])\n \n # Return the first k elements of the sorted list\n return sorted_records[:k]", "matching_cluster_idx": 2}]}, "Mbpp/754": {"dps": 78.79310344827587, "dps_norm": 81.25, "pass@1": 54.0, "profiled": [{"solution": "def extract_index_list(l1, l2, l3):\n \"\"\"\n Extract common elements from three lists if they appear under the same index.\n\n Args:\n l1 (list): First list to compare.\n l2 (list): Second list to compare.\n l3 (list): Third list to compare.\n\n Returns:\n list: A list of common elements found at the same index in all input lists.\n \"\"\"\n # Initialize an empty list to store common elements\n common_elements = []\n\n # Find the minimum length of the input lists to avoid index out of range errors\n min_length = min(len(l1), len(l2), len(l3))\n\n # Iterate over the range of the minimum length\n for i in range(min_length):\n # Check if elements at the current index are equal in all lists\n if l1[i] == l2[i] == l3[i]:\n # If they are equal, add the element to the common_elements list\n common_elements.append(l1[i])\n\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n \"\"\"\n Extract common elements from three lists at the same index.\n\n Args:\n l1 (list): The first list.\n l2 (list): The second list.\n l3 (list): The third list.\n\n Returns:\n list: A list of common elements at the same index.\n\n \"\"\"\n # Calculate the minimum length of the three lists\n min_length = min(len(l1), len(l2), len(l3))\n \n # Use list comprehension to extract common elements at the same index\n common_elements = [l1[i] for i in range(min_length) if l1[i] == l2[i] == l3[i]]\n \n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n \"\"\"\n This function extracts common elements from three lists at the same index.\n\n Args:\n l1 (list): The first list.\n l2 (list): The second list.\n l3 (list): The third list.\n\n Returns:\n list: A list of common elements at the same index in all three lists.\n\n \"\"\"\n # Use the built-in zip function to iterate over the lists in parallel\n # Use a list comprehension to filter elements that are the same in all lists\n # Check if all elements at the current index are equal\n return [element for element, other, another in zip(l1, l2, l3) if element == other == another]", "matching_cluster_idx": 7}, {"solution": "def extract_index_list(l1, l2, l3):\n \"\"\"\n This function finds common elements from three lists at the same index.\n\n Args:\n l1 (list): The first list.\n l2 (list): The second list.\n l3 (list): The third list.\n\n Returns:\n list: A list of common elements.\n \"\"\"\n # Initialize an empty list to store common elements\n common_elements = []\n \n # Find the length of the shortest list to avoid index out of range\n min_length = min(len(l1), len(l2), len(l3))\n \n # Iterate over the indices of the shortest list\n for i in range(min_length):\n # Check if the elements at the current index are the same in all lists\n if l1[i] == l2[i] == l3[i]:\n # If the elements are the same, add the element to the common_elements list\n common_elements.append(l1[i])\n \n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n \"\"\"\n This function finds the common elements from three lists that appear at the same index.\n\n Args:\n l1 (list): The first list.\n l2 (list): The second list.\n l3 (list): The third list.\n\n Returns:\n list: A list of common elements that appear at the same index in all three input lists.\n \"\"\"\n\n # Initialize an empty list to store the common elements\n common_elements = []\n\n # Iterate over the indices and values of the first list\n for i, val in enumerate(l1):\n # Check if the index is within the bounds of the second and third lists\n if i < len(l2) and i < len(l3):\n # Check if the values at the same index in the second and third lists are the same as in the first list\n if l2[i] == val and l3[i] == val:\n # If all values match, add the value to the common_elements list\n common_elements.append(val)\n\n # Return the list of common elements\n return common_elements", "matching_cluster_idx": 4}, {"solution": "def extract_index_list(l1, l2, l3):\n \"\"\"\n Extract elements that are common to all three input lists at the same index.\n \n Args:\n l1 (list): The first list\n l2 (list): The second list\n l3 (list): The third list\n \n Returns:\n list: A list of elements that appear in all three input lists at the same index\n \"\"\"\n # Find the minimum length among the input lists\n min_length = min(len(l1), len(l2), len(l3))\n\n # Initialize an empty list to store common elements\n common_elements = []\n\n # Iterate over the range of the minimum length\n for i in range(min_length):\n # Check if the elements at the current index are equal in all three lists\n if l1[i] == l2[i] == l3[i]:\n # If they are equal, append the element to the common_elements list\n common_elements.append(l1[i])\n\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n \"\"\"\n This function finds common elements from three lists at the same index.\n \n Args:\n l1 (list): The first list to compare.\n l2 (list): The second list to compare.\n l3 (list): The third list to compare.\n \n Returns:\n list: A list of elements common to all three input lists at the same index.\n \"\"\"\n \n # Initialize an empty list to store common elements\n common_elements = []\n \n # Find the minimum length of the three lists\n min_length = min(len(l1), len(l2), len(l3))\n \n # Iterate over the range of the minimum length\n for i in range(min_length):\n # Check if elements at the current index are equal in all three lists\n if l1[i] == l2[i] == l3[i]:\n # If they are equal, add the element to the common_elements list\n common_elements.append(l1[i])\n \n # Return the list of common elements\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n \"\"\"\n Finds common elements at the same index from three input lists.\n\n Args:\n l1 (list): The first list.\n l2 (list): The second list.\n l3 (list): The third list.\n\n Returns:\n list: A list of elements that are common to all input lists at the same index.\n \"\"\"\n min_length = min(len(l1), len(l2), len(l3)) # Determine the shortest list\n common_elements = [x for i, x in enumerate(l1) if i < min_length and x == l2[i] == l3[i]]\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n \"\"\"\n Finds common elements from three lists under the same index.\n\n Args:\n l1 (list): The first list.\n l2 (list): The second list.\n l3 (list): The third list.\n\n Returns:\n list: A list of common elements.\n \"\"\"\n # Use zip to iterate through the three lists simultaneously\n # and a list comprehension to check if all elements at the same index are equal\n common_elements = [element for element, *_ in zip(l1, l2, l3) if len(set([element, *_])) == 1]\n return common_elements", "matching_cluster_idx": 2}, {"solution": "def extract_index_list(l1, l2, l3):\n \"\"\"\n This function takes three lists as input and returns a list of elements\n that appear in all three lists at the same index.\n\n Args:\n l1 (list): The first list.\n l2 (list): The second list.\n l3 (list): The third list.\n\n Returns:\n list: A list of common elements at the same index.\n \"\"\"\n # Find the minimum length among the three lists\n min_length = min(len(l1), len(l2), len(l3))\n \n # Initialize an empty list to store common elements\n common_elements = []\n \n # Iterate over the range of the minimum length\n for i in range(min_length):\n # Check if the elements at the current index are the same in all three lists\n if l1[i] == l2[i] == l3[i]:\n # If they are the same, append the element to the common_elements list\n common_elements.append(l1[i])\n \n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n \"\"\"\n This function finds elements that appear at the same index in three input lists.\n \n Args:\n l1 (list): The first input list.\n l2 (list): The second input list.\n l3 (list): The third input list.\n \n Returns:\n list: A list of elements that appear at the same index in all input lists.\n \"\"\"\n \n # Find the minimum length of the three lists to avoid index out of range error\n min_length = min(len(l1), len(l2), len(l3))\n \n # Use list comprehension to iterate over the indices and elements of the lists\n common_elements = [l1[i] for i in range(min_length) if l1[i] == l2[i] == l3[i]]\n \n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n \"\"\"\n Returns a list of elements that appear at the same index in all three input lists.\n\n Args:\n l1 (list): The first list.\n l2 (list): The second list.\n l3 (list): The third list.\n\n Returns:\n list: A list of elements that appear at the same index in all three lists.\n \"\"\"\n result = []\n min_length = min(len(l1), len(l2), len(l3))\n for i in range(min_length):\n # Check if elements at index i are the same in all three lists\n if l1[i] == l2[i] == l3[i]:\n result.append(l1[i])\n return result", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n \"\"\"\n Extracts elements common to l1, l2, and l3 under the same index.\n\n Args:\n l1 (list): First list for comparison.\n l2 (list): Second list for comparison.\n l3 (list): Third list for comparison.\n\n Returns:\n list: List of common elements found at the same index across all three input lists.\n \"\"\"\n # Find minimum length of the three lists\n min_len = min(len(l1), len(l2), len(l3))\n\n # Initialize an empty list to store common elements\n common_elements = []\n\n # Iterate over the range of the minimum length\n for i in range(min_len):\n # Check if the elements at index 'i' are equal across all three lists\n if l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n \"\"\"\n Extracts elements that appear at the same index in all three lists.\n\n Args:\n l1 (list): The first list.\n l2 (list): The second list.\n l3 (list): The third list.\n\n Returns:\n list: A list of elements that appear at the same index in all three lists.\n \"\"\"\n\n # Find the length of the shortest list to avoid index out of range errors\n min_len = min(len(l1), len(l2), len(l3))\n\n # Initialize an empty list to store the common elements\n common_elements = []\n\n # Iterate over the indices up to the length of the shortest list\n for i in range(min_len):\n # Check if the elements at the current index are equal in all three lists\n if l1[i] == l2[i] == l3[i]:\n # If they are equal, add the element to the common elements list\n common_elements.append(l1[i])\n\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n \"\"\"\n This function finds the common elements at the same index from three lists.\n\n Args:\n l1 (list): The first list to compare.\n l2 (list): The second list to compare.\n l3 (list): The third list to compare.\n\n Returns:\n list: A list of common elements found at the same index.\n \"\"\"\n # Find the minimum length among the three lists\n min_len = min(len(l1), len(l2), len(l3))\n\n # Use list comprehension to compare elements at the same index\n common_elements = [element for i, element in enumerate(l1[:min_len]) if element == l2[i] == l3[i]]\n\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n \"\"\"\n This function takes three lists as input and returns a list of elements\n that appear in all three lists under the same index.\n \n Args:\n l1 (list): The first list.\n l2 (list): The second list.\n l3 (list): The third list.\n \n Returns:\n list: A list of common elements.\n \"\"\"\n \n # Ensure all lists have the same length\n min_len = min(len(l1), len(l2), len(l3))\n \n # Use list comprehension and zip to find common elements\n common_elements = [x for x, y, z in zip(l1, l2, l3) if x == y == z and l1.index(x) < min_len]\n \n return common_elements", "matching_cluster_idx": 1}, {"solution": "def extract_index_list(l1, l2, l3):\n \"\"\"\n This function finds common elements from three lists that appear at the same index in all lists.\n\n Args:\n l1 (list): The first list.\n l2 (list): The second list.\n l3 (list): The third list.\n\n Returns:\n list: A list of common elements found at the same index in all lists.\n \"\"\"\n # Find the minimum length of the lists to avoid index out of range error\n min_length = min(len(l1), len(l2), len(l3))\n\n # Initialize an empty list to store common elements\n common_elements = []\n\n # Iterate over the range of the minimum length\n for i in range(min_length):\n # Check if elements at the same index are equal in all lists\n if l1[i] == l2[i] == l3[i]:\n # If elements are equal, add the element to the common_elements list\n common_elements.append(l1[i])\n\n # Return the list of common elements\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n \"\"\"\n This function takes three lists as input and returns a list of elements that are common to all three lists \n at the same index.\n\n Args:\n l1 (list): The first list.\n l2 (list): The second list.\n l3 (list): The third list.\n\n Returns:\n list: A list of elements that are common to all three lists at the same index.\n \"\"\"\n\n # Initialize an empty list to store the common elements\n common_elements = []\n\n # Find the minimum length of the three lists\n min_length = min(len(l1), len(l2), len(l3))\n\n # Iterate over the indices of the lists up to the minimum length\n for i in range(min_length):\n # Check if the elements at the current index are equal in all three lists\n if l1[i] == l2[i] == l3[i]:\n # If they are equal, append the element to the common_elements list\n common_elements.append(l1[i])\n\n # Return the list of common elements\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n \"\"\"\n Extract elements common to three lists under the same index.\n\n Args:\n l1 (list): The first list.\n l2 (list): The second list.\n l3 (list): The third list.\n\n Returns:\n list: A list of common elements.\n \"\"\"\n # Ensure that the lists have the same length to avoid index errors\n length = min(len(l1), len(l2), len(l3))\n \n # Iterate over the indices of the shortest list\n common_elements = [element for i in range(length) \n for element in [l1[i]] \n if element == l2[i] and element == l3[i]]\n \n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n \"\"\"\n This function finds common elements in the same index from three input lists.\n \n Args:\n l1 (list): The first list to compare.\n l2 (list): The second list to compare.\n l3 (list): The third list to compare.\n \n Returns:\n list: A list of common elements found at the same index in all three lists.\n \"\"\"\n # Find the minimum length of the three lists to avoid index out of range error\n min_len = min(len(l1), len(l2), len(l3))\n \n # Initialize an empty list to store common elements\n common_elements = []\n \n # Iterate over the range of the minimum length\n for i in range(min_len):\n # Check if the elements at the current index are the same in all three lists\n if l1[i] == l2[i] == l3[i]:\n # If they are the same, add the element to the common_elements list\n common_elements.append(l1[i])\n \n # Return the list of common elements\n return common_elements", "matching_cluster_idx": 6}]}, "Mbpp/755": {"dps": 64.38053097345133, "dps_norm": 85.0, "pass@1": 30.0, "profiled": [{"solution": "def second_smallest(numbers):\n \"\"\"\n This function finds the second smallest number in a list.\n \n Args:\n numbers (list): A list of integers.\n \n Returns:\n int: The second smallest number in the list. If the list has less than 2 unique elements, returns None.\n \"\"\"\n # Check if the list has less than 2 unique elements\n if len(set(numbers)) < 2:\n return None\n \n # Remove duplicates by converting the list to a set and sort the numbers\n unique_numbers = sorted(set(numbers))\n \n # Return the second smallest number\n return unique_numbers[1]", "matching_cluster_idx": 4}, {"solution": "def second_smallest(nums):\n \"\"\"\n This function returns the second smallest number in a list.\n If the list contains less than two unique elements, it returns None.\n \"\"\"\n # Remove duplicates by converting the list to a set\n unique_nums = set(nums)\n \n # If the list contains less than two unique elements, return None\n if len(unique_nums) < 2:\n return None\n \n # Remove the smallest number from the set\n unique_nums.remove(min(unique_nums))\n \n # The smallest number in the remaining set is the second smallest number\n return min(unique_nums)", "matching_cluster_idx": 4}, {"solution": "def second_smallest(numbers):\n \"\"\"\n This function takes a list of numbers and returns the second smallest number.\n \n If the list has less than two unique numbers, it returns None.\n \n :param numbers: A list of numbers\n :return: The second smallest number in the list or None\n \"\"\"\n \n # Remove duplicates and sort the list\n unique_numbers = sorted(set(numbers))\n \n # Check if the list has less than two unique numbers\n if len(unique_numbers) < 2:\n return None\n \n # Return the second smallest number\n return unique_numbers[1]", "matching_cluster_idx": 5}, {"solution": "def second_smallest(nums):\n \"\"\"\n This function finds the second smallest number in a list.\n \n Args:\n nums (list): A list of integers.\n \n Returns:\n int: The second smallest number in the list. If the list has less than two distinct numbers, it returns None.\n \"\"\"\n \n # Remove duplicates by converting the list to a set\n unique_nums = set(nums)\n \n # Check if the list has less than two distinct numbers\n if len(unique_nums) < 2:\n return None\n \n # Remove the smallest number\n unique_nums.remove(min(unique_nums))\n \n # Return the smallest number in the updated set, which is the second smallest in the original list\n return min(unique_nums)", "matching_cluster_idx": 4}, {"solution": "def second_smallest(numbers):\n \"\"\"\n Find the second smallest number in a list.\n \n Args:\n numbers (list): A list of numbers.\n \n Returns:\n int: The second smallest number in the list. If no second smallest exists (i.e., \n the list has less than two unique elements), it returns None.\n \"\"\"\n # Create a set to remove duplicate values\n unique_numbers = set(numbers)\n \n # Check for less than two unique elements\n if len(unique_numbers) < 2:\n return None\n \n # Remove the smallest number\n unique_numbers.remove(min(unique_numbers))\n \n # The second smallest is the minimum of the remaining numbers\n return min(unique_numbers)", "matching_cluster_idx": 4}, {"solution": "def second_smallest(numbers):\n \"\"\"\n Returns the second smallest number in a list.\n \n If the list contains duplicate numbers, it will return the smallest of the duplicates.\n \n Args:\n numbers (list): A list of numbers.\n \n Returns:\n The second smallest number in the list, or None if the list has less than two unique elements.\n \"\"\"\n # Check if the input is a list\n if not isinstance(numbers, list):\n raise TypeError(\"Input must be a list\")\n \n # Check if all elements in the list are numbers\n if not all(isinstance(num, (int, float)) for num in numbers):\n raise ValueError(\"All elements in the list must be numbers\")\n \n # Remove duplicates and sort the list in ascending order\n unique_numbers = sorted(set(numbers))\n \n # If the list has less than two unique elements, return None\n if len(unique_numbers) < 2:\n return None\n \n # Return the second smallest number\n return unique_numbers[1]", "matching_cluster_idx": 2}, {"solution": "def second_smallest(nums):\n \"\"\"\n Finds the second smallest number in a list.\n\n If there's no second smallest number (e.g., all numbers are the same or the list has less than two unique elements),\n the function will return None.\n\n Args:\n nums (list): A list of numbers.\n\n Returns:\n The second smallest number in the list, or None if it doesn't exist.\n \"\"\"\n if len(nums) < 2:\n return None\n \n # Remove duplicates and sort the list\n unique_nums = sorted(set(nums))\n \n # If all numbers are the same or there's only one unique number, return None\n if len(unique_nums) < 2:\n return None\n \n return unique_nums[1]", "matching_cluster_idx": 5}, {"solution": "def second_smallest(numbers):\n \"\"\"\n This function finds the second smallest number in a list.\n \n Args:\n numbers (list): A list of numbers.\n \n Returns:\n int: The second smallest number in the list. If there is no second smallest number, returns None.\n \"\"\"\n # Remove duplicates by converting the list to a set\n unique_numbers = set(numbers)\n \n # If there is less than two unique numbers, there is no second smallest number\n if len(unique_numbers) < 2:\n return None\n \n # Sort the unique numbers and return the second smallest\n sorted_numbers = sorted(unique_numbers)\n return sorted_numbers[1]", "matching_cluster_idx": 5}, {"solution": "def second_smallest(nums):\n \"\"\"\n This function finds the second smallest number in a list.\n \n If there is no second smallest number (i.e., the list is empty or only contains one unique number), \n it returns None.\n \n Args:\n nums (list): A list of numbers.\n \n Returns:\n The second smallest number in the list, or None if no such number exists.\n \"\"\"\n \n # Check for an empty list\n if len(nums) == 0:\n return None\n\n # Create a set to store unique numbers\n unique_nums = set(nums)\n \n # Check if the list only contains one unique number\n if len(unique_nums) < 2:\n return None\n\n # Remove the smallest number from the set\n unique_nums.remove(min(unique_nums))\n\n # Return the smallest number from the updated set\n return min(unique_nums)", "matching_cluster_idx": 4}, {"solution": "def second_smallest(nums):\n \"\"\"\n Finds the second smallest number in a list of numbers.\n\n Args:\n - nums (list): A list of numbers.\n\n Returns:\n - The second smallest number in the list, or None if the list has less than 2 unique numbers.\n \"\"\"\n # Remove duplicates by converting the list to a set\n unique_nums = set(nums)\n \n # Check if the list has less than 2 unique numbers\n if len(unique_nums) < 2:\n return None\n\n # Remove the smallest number from the set\n unique_nums.remove(min(unique_nums))\n \n # The smallest number in the remaining set is the second smallest in the original list\n return min(unique_nums)", "matching_cluster_idx": 4}, {"solution": "def second_smallest(nums):\n \"\"\"\n Returns the second smallest number in a list.\n\n If the list has less than 2 unique elements, it returns None.\n \"\"\"\n # Remove duplicates by converting the list to a set\n unique_nums = set(nums)\n \n # If the list has less than 2 unique elements, return None\n if len(unique_nums) < 2:\n return None\n \n # Remove the smallest number\n unique_nums.remove(min(unique_nums))\n \n # Return the smallest number from the remaining set, which is the second smallest\n return min(unique_nums)", "matching_cluster_idx": 4}, {"solution": "def second_smallest(nums):\n \"\"\"\n This function finds the second smallest number in a list.\n\n Args:\n nums (list): A list of numbers.\n\n Returns:\n The second smallest number in the list. If the list contains less than two unique numbers, it returns None.\n \"\"\"\n # Remove duplicates by converting the list to a set\n unique_nums = set(nums)\n \n # If the list contains less than two unique numbers, return None\n if len(unique_nums) < 2:\n return None\n\n # Remove the smallest number from the set\n smallest = min(unique_nums)\n unique_nums.remove(smallest)\n\n # Return the second smallest number\n return min(unique_nums)", "matching_cluster_idx": 4}, {"solution": "def second_smallest(numbers):\n \"\"\"\n Find the second smallest number in a list.\n\n If the list has less than two unique numbers or contains non-numeric values, \n it returns None.\n\n Args:\n numbers (list): A list of numbers.\n\n Returns:\n The second smallest number in the list, or None if it doesn't exist.\n\n Raises:\n TypeError: If the input is not a list.\n \"\"\"\n\n # Check input is a list\n if not isinstance(numbers, list):\n raise TypeError(\"Input must be a list\")\n\n # Check list has at least two unique numbers\n unique_numbers = [num for num in set(numbers) if isinstance(num, (int, float))]\n if len(unique_numbers) < 2:\n return None\n\n # Return the second smallest number\n return sorted(unique_numbers)[1]", "matching_cluster_idx": 1}, {"solution": "def second_smallest(nums):\n \"\"\"\n This function finds the second smallest number in a list.\n \n Args:\n nums (list): A list of numbers.\n \n Returns:\n The second smallest number in the list. If no second smallest number exists, returns None.\n \"\"\"\n # Remove duplicates by converting the list to a set\n num_set = set(nums)\n \n # Check if the list has at least two distinct elements\n if len(num_set) < 2:\n return None\n \n # Remove the smallest number from the set\n num_set.remove(min(num_set))\n \n # Return the smallest number in the updated set, which is the second smallest number in the original list\n return min(num_set)", "matching_cluster_idx": 4}, {"solution": "def second_smallest(numbers):\n \"\"\"\n Returns the second smallest number in a list of numbers.\n\n If the list has less than two distinct numbers, returns None.\n \"\"\"\n unique_nums = sorted(set(numbers)) # Removes duplicates and sorts the list\n if len(unique_nums) < 2:\n return None # Returns None if there are less than two distinct numbers\n return unique_nums[1] # Returns the second smallest number", "matching_cluster_idx": 5}, {"solution": "def second_smallest(numbers):\n \"\"\"\n This function finds the second smallest number in a list.\n \n Args:\n numbers (list): A list of numbers.\n \n Returns:\n The second smallest number in the list. If there's no second smallest (i.e., all numbers are the same), returns None.\n \"\"\"\n \n # Remove duplicates by converting the list to a set\n unique_numbers = set(numbers)\n \n # If there are less than two unique numbers, there's no second smallest number\n if len(unique_numbers) < 2:\n return None\n \n # Remove the smallest number from the set\n smallest = min(unique_numbers)\n unique_numbers.remove(smallest)\n \n # The smallest number in the updated set is the second smallest number\n return min(unique_numbers)", "matching_cluster_idx": 4}, {"solution": "def second_smallest(nums):\n \"\"\"\n This function finds the second smallest number in a list.\n \n If the list has less than two distinct numbers, it returns None.\n \n Parameters:\n nums (list): A list of numbers.\n \n Returns:\n int: The second smallest number in the list, or None if no second smallest exists.\n \"\"\"\n # Remove duplicates and sort the list\n sorted_nums = sorted(set(nums))\n \n # Check if list has less than two distinct numbers\n if len(sorted_nums) < 2:\n return None\n \n # Return the second smallest number\n return sorted_nums[1]", "matching_cluster_idx": 5}, {"solution": "def second_smallest(nums):\n \"\"\"\n Returns the second smallest number in the given list of numbers.\n \n If the list has less than two unique numbers, returns None.\n \n :param nums: A list of numbers\n :return: The second smallest number, or None if list has less than two unique numbers\n \"\"\"\n # Create a set to store unique numbers in the list, this automatically removes duplicates\n unique_nums = set(nums)\n \n # Check if list has less than two unique numbers\n if len(unique_nums) < 2:\n return None\n \n # Remove the smallest number from the set\n unique_nums.remove(min(unique_nums))\n \n # Return the smallest number in the remaining set, which is the second smallest number\n return min(unique_nums)", "matching_cluster_idx": 4}, {"solution": "def second_smallest(lst):\n \"\"\"\n This function finds the second smallest number in a list.\n \n Parameters:\n lst (list): A list of numbers\n \n Returns:\n int or float: The second smallest number in the list. If no second smallest exists (e.g., all numbers are the same), returns None.\n \"\"\"\n # Check for less than 2 elements in the list\n if len(lst) < 2:\n return None\n \n # Remove duplicates by converting the list to a set\n unique_nums = set(lst)\n \n # If all numbers are the same, return None\n if len(unique_nums) < 2:\n return None\n \n # Find the second smallest number\n second_smallest_num = sorted(unique_nums)[1]\n \n return second_smallest_num", "matching_cluster_idx": 5}, {"solution": "def second_smallest(nums):\n \"\"\"\n This function takes a list of numbers as input, removes duplicates, and returns the second smallest number.\n \n If there's no second smallest number (i.e., all numbers are the same), it returns None.\n \n :param nums: A list of numbers.\n :return: The second smallest number in the list, or None if it doesn't exist.\n \"\"\"\n unique_nums = sorted(set(nums)) # Remove duplicates and sort the list\n if len(unique_nums) < 2: # Check if there are at least two unique numbers\n return None\n return unique_nums[1] # Return the second smallest number", "matching_cluster_idx": 5}]}, "Mbpp/757": {"dps": 99.99999999999999, "dps_norm": 100.0, "pass@1": 18.0, "profiled": [{"solution": "def count_reverse_pairs(strings):\n \"\"\"\n Count the pairs of reverse strings in the given string list.\n\n Args:\n strings (list): A list of strings.\n\n Returns:\n int: The number of pairs of reverse strings in the list.\n \"\"\"\n\n # Initialize a dictionary to store the frequency of each string\n string_freq = {}\n \n # Initialize the count of pairs of reverse strings\n pair_count = 0\n \n # Iterate over each string in the list\n for string in strings:\n # Reverse the string\n reverse_string = string[::-1]\n \n # If the reverse string is already in the dictionary, \n # it means we have found a pair of reverse strings\n if reverse_string in string_freq:\n # Increment the pair count by the frequency of the reverse string\n pair_count += string_freq[reverse_string]\n \n # Increment the frequency of the current string\n string_freq[string] = string_freq.get(string, 0) + 1\n \n # Return the total count of pairs of reverse strings\n return pair_count", "matching_cluster_idx": 12}, {"solution": "def count_reverse_pairs(strings):\n \"\"\"\n This function counts the pairs of reverse strings in a given list.\n\n Args:\n strings (list): A list of strings.\n\n Returns:\n int: The number of pairs of reverse strings.\n\n Example:\n >>> count_reverse_pairs([\"julia\", \"best\", \"tseb\", \"for\", \"ailuj\"])\n 2\n \"\"\"\n\n # Create an empty dictionary to store the frequency of each string\n freq = {}\n\n # Initialize a counter for reverse pairs\n pairs = 0\n\n # Iterate over each string in the list\n for s in strings:\n # Reverse the string\n rev_s = s[::-1]\n\n # If the reversed string is already in the frequency dictionary\n if rev_s in freq:\n # Increment the counter by the frequency of the reversed string\n pairs += freq[rev_s]\n\n # Increment the frequency of the current string\n freq[s] = freq.get(s, 0) + 1\n\n # Return the total count of reverse pairs\n return pairs", "matching_cluster_idx": 12}, {"solution": "def count_reverse_pairs(strings):\n \"\"\"\n Counts the pairs of reverse strings in the given string list.\n\n Args:\n strings (list): A list of strings.\n\n Returns:\n int: The number of pairs of reverse strings.\n\n \"\"\"\n # Create a dictionary to store the frequency of each string and its reverse\n freq = {}\n count = 0\n\n for s in strings:\n # If the string's reverse is in the dictionary, increment the count and decrement the frequency of the reverse string\n if s[::-1] in freq:\n count += freq[s[::-1]]\n # Increment the frequency of the string\n freq[s] = freq.get(s, 0) + 1\n\n return count", "matching_cluster_idx": 12}, {"solution": "def count_reverse_pairs(strings):\n \"\"\"\n Counts the pairs of reverse strings in the given string list.\n\n Args:\n strings (list): A list of strings.\n\n Returns:\n int: The number of pairs of reverse strings.\n \"\"\"\n # Initialize an empty dictionary to store the frequency of each string\n freq = {}\n # Initialize a variable to store the count of pairs\n count = 0\n\n # Iterate through the input list of strings\n for s in strings:\n # Reverse the string\n reversed_s = s[::-1]\n \n # If the reversed string is already in the frequency dictionary\n if reversed_s in freq:\n # Increment the count by the frequency of the reversed string\n count += freq[reversed_s]\n \n # Increment the frequency of the current string\n freq[s] = freq.get(s, 0) + 1\n \n # Return the count of pairs\n return count", "matching_cluster_idx": 12}, {"solution": "def count_reverse_pairs(strings):\n \"\"\"\n Count the pairs of reverse strings in the given string list.\n\n Args:\n strings (list): A list of strings.\n\n Returns:\n int: The number of pairs of reverse strings.\n\n Example:\n >>> count_reverse_pairs([\"julia\", \"best\", \"tseb\", \"for\", \"ailuj\"])\n 2\n \"\"\"\n # Create an empty dictionary to store the count of each string\n string_count = {}\n \n # Initialize a variable to store the count of reverse pairs\n reverse_pairs = 0\n \n # Iterate over each string in the list\n for string in strings:\n # Reverse the string\n reversed_string = string[::-1]\n \n # If the reversed string is already in the dictionary, increment the reverse pairs count\n if reversed_string in string_count:\n reverse_pairs += string_count[reversed_string]\n \n # Increment the count of the current string in the dictionary\n string_count[string] = string_count.get(string, 0) + 1\n \n # Return the count of reverse pairs\n return reverse_pairs", "matching_cluster_idx": 12}, {"solution": "def count_reverse_pairs(strings):\n \"\"\"\n Count the pairs of reverse strings in the given string list.\n\n Args:\n strings (list): A list of strings.\n\n Returns:\n int: The number of pairs of reverse strings.\n \"\"\"\n # Create a dictionary to store the strings and their frequencies\n freq_dict = {}\n count = 0\n \n # Iterate over the strings in the list\n for string in strings:\n # Create the reverse string\n reverse_string = string[::-1]\n \n # If the reverse string is in the dictionary, increment the count by the frequency of the reverse string\n if reverse_string in freq_dict:\n count += freq_dict[reverse_string]\n \n # Increment the frequency of the current string in the dictionary\n freq_dict[string] = freq_dict.get(string, 0) + 1\n \n # Return the count of pairs of reverse strings\n return count", "matching_cluster_idx": 12}, {"solution": "def count_reverse_pairs(strings):\n \"\"\"\n This function counts the pairs of reverse strings in the given string list.\n \n Args:\n strings (list): A list of strings.\n \n Returns:\n int: The number of pairs of reverse strings.\n \"\"\"\n # Create an empty dictionary to store the count of each string and its reverse\n string_count = {}\n \n # Initialize the count of reverse pairs to 0\n reverse_pairs = 0\n \n # Iterate over each string in the list\n for s in strings:\n # Reverse the string\n reversed_s = s[::-1]\n \n # If the reversed string is already in the dictionary, it means we have found a pair\n if reversed_s in string_count:\n # Increment the count of reverse pairs by the count of the reversed string\n reverse_pairs += string_count[reversed_s]\n \n # If the original string is not in the dictionary, add it with a count of 1\n if s not in string_count:\n string_count[s] = 1\n # If the original string is already in the dictionary, increment its count\n else:\n string_count[s] += 1\n \n # Return the count of reverse pairs\n return reverse_pairs", "matching_cluster_idx": 12}, {"solution": "def count_reverse_pairs(strings):\n \"\"\"\n This function counts the pairs of reverse strings in the given string list.\n \n Args:\n strings (list): A list of strings.\n \n Returns:\n int: The number of pairs of reverse strings in the list.\n \"\"\"\n \n # Create a hashmap to store the frequency of each string and its reverse\n string_count = {}\n \n # Initialize count of pairs to 0\n pairs = 0\n \n # Iterate over each string in the input list\n for s in strings:\n # Reverse the string\n rev_s = s[::-1]\n \n # If the reverse string is already in the hashmap, it means we have found a pair\n if rev_s in string_count:\n # Increment the pairs count\n pairs += string_count[rev_s]\n \n # Increment the count of the current string in the hashmap\n string_count[s] = string_count.get(s, 0) + 1\n \n # Return the total count of pairs\n return pairs", "matching_cluster_idx": 12}, {"solution": "def count_reverse_pairs(string_list):\n \"\"\"\n Count the pairs of reverse strings in the given string list.\n \n Args:\n string_list (list): A list of strings.\n \n Returns:\n int: The number of pairs of reverse strings.\n \"\"\"\n # Create a dictionary to store the count of each string in the list\n string_count = {}\n \n # Create a variable to store the count of reverse string pairs\n pair_count = 0\n \n # Iterate over each string in the list\n for s in string_list:\n # Reverse the string\n reversed_s = s[::-1]\n \n # If the reversed string is already in the dictionary, \n # increment the pair count by the count of the reversed string\n if reversed_s in string_count:\n pair_count += string_count[reversed_s]\n \n # Increment the count of the current string in the dictionary\n string_count[s] = string_count.get(s, 0) + 1\n \n # Return the count of reverse string pairs\n return pair_count", "matching_cluster_idx": 12}, {"solution": "def count_reverse_pairs(string_list):\n \"\"\"\n Counts the pairs of reverse strings in the given string list.\n\n Args:\n string_list (list): A list of strings.\n\n Returns:\n int: The number of pairs of reverse strings.\n\n \"\"\"\n # Create an empty dictionary to store the frequency of each string\n freq_dict = {}\n \n # Initialize the count of reverse pairs\n reverse_pairs = 0\n \n # Iterate over each string in the list\n for string in string_list:\n # Reverse the string\n reversed_string = string[::-1]\n \n # If the reversed string is already in the dictionary, increment the reverse pairs count\n if reversed_string in freq_dict:\n reverse_pairs += freq_dict[reversed_string]\n \n # Increment the frequency of the current string in the dictionary\n freq_dict[string] = freq_dict.get(string, 0) + 1\n \n # Return the count of reverse pairs\n return reverse_pairs", "matching_cluster_idx": 12}, {"solution": "def count_reverse_pairs(strings):\n \"\"\"\n Counts the pairs of reverse strings in the given string list.\n\n Args:\n strings (list): A list of strings.\n\n Returns:\n int: The number of pairs of reverse strings.\n \"\"\"\n # Create an empty dictionary to store the strings we've seen and their counts\n string_counts = {}\n \n # Initialize a variable to store the count of reverse pairs\n reverse_pairs = 0\n \n # Iterate over each string in the input list\n for s in strings:\n # Reverse the string\n reversed_s = s[::-1]\n \n # If the reversed string is already in our dictionary, increment the reverse pairs count\n if reversed_s in string_counts:\n reverse_pairs += string_counts[reversed_s]\n \n # Increment the count of the current string in the dictionary\n string_counts[s] = string_counts.get(s, 0) + 1\n \n # Return the count of reverse pairs\n return reverse_pairs", "matching_cluster_idx": 12}, {"solution": "def count_reverse_pairs(string_list):\n \"\"\"\n This function counts the pairs of reverse strings in the given string list.\n \n Args:\n string_list (list): A list of strings.\n \n Returns:\n int: The number of pairs of reverse strings.\n \"\"\"\n \n # Initialize a dictionary to store the frequency of each string\n string_freq = {}\n \n # Initialize a variable to store the count of reverse pairs\n reverse_pairs = 0\n \n # Iterate over each string in the list\n for string in string_list:\n # Reverse the string\n reverse_string = string[::-1]\n \n # If the reverse string is in the frequency dictionary, increment the reverse pairs count\n if reverse_string in string_freq:\n reverse_pairs += string_freq[reverse_string]\n \n # Increment the frequency of the current string\n string_freq[string] = string_freq.get(string, 0) + 1\n \n # Return the count of reverse pairs\n return reverse_pairs", "matching_cluster_idx": 12}, {"solution": "def count_reverse_pairs(strings):\n \"\"\"\n This function counts the pairs of reverse strings in the given string list.\n\n Args:\n strings (list): A list of strings.\n\n Returns:\n int: The number of pairs of reverse strings.\n \"\"\"\n\n # Create a dictionary to store the frequency of each string and its reverse\n freq_dict = {}\n \n # Initialize count of pairs\n count = 0\n \n # Iterate over the list of strings\n for s in strings:\n # Reverse the string\n rev_s = s[::-1]\n \n # If the reversed string is in the dictionary, increment the count\n if rev_s in freq_dict:\n count += freq_dict[rev_s]\n \n # Increment the frequency of the current string in the dictionary\n freq_dict[s] = freq_dict.get(s, 0) + 1\n \n # Return the count of pairs\n return count", "matching_cluster_idx": 12}, {"solution": "def count_reverse_pairs(strings):\n \"\"\"\n Counts the pairs of reverse strings in the given string list.\n \n Args:\n strings (list): A list of strings.\n \n Returns:\n int: The number of pairs of reverse strings.\n \"\"\"\n # Create an empty dictionary to store the strings we've seen so far and their counts\n string_counts = {}\n \n # Initialize a variable to store the number of reverse pairs\n reverse_pairs = 0\n \n # Iterate over the input strings\n for string in strings:\n # Create a reversed version of the current string\n reversed_string = string[::-1]\n \n # If we've seen the reversed string before, it's a pair\n if reversed_string in string_counts:\n # Increment the reverse pairs count by the number of times we've seen the reversed string\n reverse_pairs += string_counts[reversed_string]\n \n # Increment the count of the current string\n string_counts[string] = string_counts.get(string, 0) + 1\n \n # Return the total number of reverse pairs\n return reverse_pairs", "matching_cluster_idx": 12}, {"solution": "def count_reverse_pairs(strings):\n \"\"\"\n This function counts the pairs of reverse strings in the given string list.\n\n Args:\n strings (list): A list of strings.\n\n Returns:\n int: The number of pairs of reverse strings.\n\n \"\"\"\n # Create an empty dictionary to store the frequency of each string\n freq = {}\n \n # Initialize the count of pairs\n count = 0\n \n # Iterate over each string in the list\n for string in strings:\n # Reverse the string\n reverse = string[::-1]\n \n # If the reversed string is already in the dictionary, increment the count\n if reverse in freq:\n count += freq[reverse]\n \n # Increment the frequency of the current string\n freq[string] = freq.get(string, 0) + 1\n \n # Return the count of pairs\n return count", "matching_cluster_idx": 12}, {"solution": "def count_reverse_pairs(strings):\n \"\"\"\n This function counts the pairs of reverse strings in the given string list.\n\n Args:\n strings (list): A list of strings.\n\n Returns:\n int: The number of pairs of reverse strings.\n\n \"\"\"\n # Create an empty dictionary to store the frequency of each string\n freq = {}\n count = 0\n \n # Iterate over the list of strings\n for s in strings:\n # Reverse the string\n rev_s = s[::-1]\n \n # If the reversed string is in the frequency dictionary, increment the count\n if rev_s in freq:\n count += freq[rev_s]\n \n # Increment the frequency of the current string\n freq[s] = freq.get(s, 0) + 1\n \n return count", "matching_cluster_idx": 12}, {"solution": "def count_reverse_pairs(strings):\n \"\"\"\n Counts the pairs of reverse strings in the given string list.\n\n Args:\n strings (list): A list of strings.\n\n Returns:\n int: The number of pairs of reverse strings.\n \"\"\"\n # Create an empty dictionary to store strings and their counts\n string_counts = {}\n\n # Initialize a counter for reverse pairs\n reverse_pairs = 0\n\n # Iterate over each string in the list\n for string in strings:\n # Reverse the string\n reverse_string = string[::-1]\n \n # If the reversed string is in the dictionary, it means we've found a pair\n if reverse_string in string_counts:\n # Increment the reverse pairs counter by the count of the reversed string\n reverse_pairs += string_counts[reverse_string]\n \n # Increment the count of the current string in the dictionary\n string_counts[string] = string_counts.get(string, 0) + 1\n\n # Return the count of reverse pairs\n return reverse_pairs", "matching_cluster_idx": 12}, {"solution": "def count_reverse_pairs(strings):\n \"\"\"\n This function counts the pairs of reverse strings in the given string list.\n\n Args:\n strings (list): A list of strings.\n\n Returns:\n int: The number of pairs of reverse strings.\n\n \"\"\"\n # Initialize a hashmap to store frequency of each string\n freq_map = {}\n \n # Initialize count of pairs to 0\n count = 0\n \n # Iterate through the list of strings\n for string in strings:\n # Reverse the string\n reverse_string = string[::-1]\n \n # If the reversed string is in the hashmap, \n # increment count by the frequency of reversed string\n if reverse_string in freq_map:\n count += freq_map[reverse_string]\n \n # Increment the frequency of the string\n freq_map[string] = freq_map.get(string, 0) + 1\n \n return count", "matching_cluster_idx": 12}]}, "Mbpp/758": {"dps": 87.02702702702702, "dps_norm": 83.125, "pass@1": 95.0, "profiled": [{"solution": "from collections import defaultdict\ndef unique_sublists(lists):\n \"\"\"\n This function counts the occurrences of each sublist in a list.\n It returns a dictionary where the keys are tuples representing the sublists\n and the values are the counts of these sublists.\n\n Args:\n lists (list): A list of lists.\n\n Returns:\n dict: A dictionary with tuples of sublists as keys and their counts as values.\n \"\"\"\n # Initialize a dictionary to store the counts of sublists.\n # The defaultdict is used to avoid KeyError when accessing a key for the first time.\n counts = defaultdict(int)\n \n # Iterate over each sublist in the input list.\n for sublist in lists:\n # Convert the sublist to a tuple to make it hashable and use it as a key in the dictionary.\n sublist_tuple = tuple(sublist)\n \n # Increment the count of the current sublist in the dictionary.\n counts[sublist_tuple] += 1\n \n # Convert the defaultdict back to a regular dictionary before returning.\n return dict(counts)", "matching_cluster_idx": 5}, {"solution": "from collections import defaultdict\ndef unique_sublists(lst):\n \"\"\"\n Count sublists within a list.\n\n Args:\n lst (list): The input list containing sublists.\n\n Returns:\n dict: A dictionary where every sublist is converted to a tuple and the value of such tuple is the number of its occurrences in the original list.\n \"\"\"\n counter = defaultdict(int)\n for sublst in lst:\n # Convert sublist to tuple for it to be hashable and thus usable as a dict key\n counter[tuple(sublst)] += 1\n \n # Convert defaultdict back to regular dict\n return dict(counter)", "matching_cluster_idx": 5}, {"solution": "from collections import Counter\ndef unique_sublists(lists):\n \"\"\"\n This function counts lists within a list. It returns a dictionary where every list is converted to a tuple \n and the value of such tuple is the number of its occurrences in the original list.\n\n Args:\n lists (list): A list of lists.\n\n Returns:\n dict: A dictionary with tuples of unique sublists as keys and their counts as values.\n \"\"\"\n # Convert all inner lists to tuples (because lists can't be dictionary keys) and count their occurrences\n return dict(Counter(tuple(sublist) for sublist in lists))", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(lst):\n \"\"\"\n This function counts unique sublists within a given list.\n \n Args:\n lst (list): The list that contains sublists.\n \n Returns:\n dict: A dictionary where keys are unique sublists converted to tuples and values are their frequencies.\n \"\"\"\n # Convert sublists to tuples for hashing and create a dictionary to store counts\n count_dict = {}\n \n # Iterate over the list\n for sub in lst:\n # Convert the sublist to a tuple\n sub_tuple = tuple(sub)\n \n # Increment the count for the current tuple\n count_dict[sub_tuple] = count_dict.get(sub_tuple, 0) + 1\n \n return count_dict", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(sublists):\n \"\"\"\n Returns a dictionary where each key is a unique sublist \n (as a tuple) and its corresponding value is the frequency.\n\n Args:\n sublists (list): A list of sublists.\n\n Returns:\n dict: A dictionary with tuples of sublists as keys and their frequencies as values.\n \"\"\"\n\n # Convert sublists to tuples for hashing and store them in a dictionary\n frequency_dict = {}\n for sublist in sublists:\n # Convert the sublist to a tuple for hashing\n tuple_sublist = tuple(sublist)\n \n # Increment the frequency of the tuple in the dictionary\n if tuple_sublist in frequency_dict:\n frequency_dict[tuple_sublist] += 1\n else:\n frequency_dict[tuple_sublist] = 1\n \n return frequency_dict", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(sublists):\n \"\"\"\n Counts lists within a list and returns a dictionary with tuples as keys and their occurrences as values.\n\n Args:\n sublists (list): A list of lists.\n\n Returns:\n dict: A dictionary with tuples as keys and their occurrences as values.\n\n Example:\n >>> unique_sublists([[1, 3], [5, 7], [1, 3], [13, 15, 17], [5, 7], [9, 11]])\n {(1, 3): 2, (5, 7): 2, (13, 15, 17): 1, (9, 11): 1}\n \"\"\"\n\n # Initialize an empty dictionary to store counts of sublists\n counts = {}\n\n # Iterate through each sublist in the list of sublists\n for sublist in sublists:\n # Convert the sublist to a tuple so it can be used as a dictionary key\n tuple_sublist = tuple(sublist)\n \n # If the tuple is already in the dictionary, increment its count\n if tuple_sublist in counts:\n counts[tuple_sublist] += 1\n # If the tuple is not in the dictionary, add it with a count of 1\n else:\n counts[tuple_sublist] = 1\n\n # Return the dictionary of sublist counts\n return counts", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(lst):\n \"\"\"\n This function counts the occurrences of each sublist in a given list.\n \n Args:\n lst (list): A list containing sublists.\n \n Returns:\n dict: A dictionary where each key is a tuple representation of a unique sublist and its value is the number of times it appears in the original list.\n \"\"\"\n # Convert each sublist to a tuple (because lists are not hashable) and use a dictionary to count their occurrences\n count_dict = {}\n for sublst in lst:\n sublst_tuple = tuple(sublst) # Convert the sublist to a tuple\n if sublst_tuple in count_dict:\n count_dict[sublst_tuple] += 1 # Increment the count if the tuple is already in the dictionary\n else:\n count_dict[sublst_tuple] = 1 # Initialize the count if the tuple is not in the dictionary\n return count_dict", "matching_cluster_idx": 6}, {"solution": "from typing import Dict, List, Tuple\ndef unique_sublists(sublists: List[List[int]]) -> Dict[Tuple, int]:\n \"\"\"\n Counts the occurrences of each unique sublist in a list of lists.\n \n Args:\n sublists (List[List[int]]): A list of integer lists.\n \n Returns:\n Dict[Tuple, int]: A dictionary where each key is a unique sublist (converted to a tuple) \n and the value is the number of its occurrences.\n \"\"\"\n # Convert each sublist to a tuple (to make it hashable) and count occurrences with a dictionary\n sublist_counts = {}\n for sublist in sublists:\n # Convert sublist to tuple\n sublist_tuple = tuple(sublist)\n \n # Increment the count for this tuple\n sublist_counts[sublist_tuple] = sublist_counts.get(sublist_tuple, 0) + 1\n \n return sublist_counts\nsublists = [[1, 3], [5, 7], [1, 3], [13, 15, 17], [5, 7], [9, 11]]", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(nested_list):\n \"\"\"\n This function takes a nested list of lists, converts the inner lists to tuples \n (since lists are not hashable), and returns a dictionary where each tuple is a \n key with its corresponding value being the number of occurrences in the original list.\n\n Args:\n nested_list (list): A list containing inner lists.\n\n Returns:\n dict: A dictionary with inner lists converted to tuples as keys, and their counts as values.\n \"\"\"\n\n # Convert inner lists to tuples for hashability and count occurrences using dict.get()\n result = {}\n for inner_list in nested_list:\n # Convert the inner list to a tuple\n inner_tuple = tuple(inner_list)\n \n # Increment the count for the current tuple in the result dictionary\n result[inner_tuple] = result.get(inner_tuple, 0) + 1\n \n return result", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(sublist_list):\n \"\"\"\n Counts unique sublists within a list of lists and returns a dictionary where each unique sublist is \n converted to a tuple and its corresponding value represents the number of occurrences.\n\n Args:\n sublist_list (list): A list of lists containing integer values.\n\n Returns:\n dict: A dictionary where each key is a unique sublist tuple and its value is the count of its occurrences.\n \"\"\"\n # Convert the list of lists into a dictionary where each sublist is converted to a tuple for hashability\n # and the count of each tuple (sublist) is stored as the value\n count_dict = {}\n for sublist in sublist_list:\n # Convert the sublist to a tuple to make it hashable\n sublist_tuple = tuple(sublist)\n # If the tuple is already in the dictionary, increment its count\n if sublist_tuple in count_dict:\n count_dict[sublist_tuple] += 1\n # If the tuple is not in the dictionary, add it with a count of 1\n else:\n count_dict[sublist_tuple] = 1\n return count_dict", "matching_cluster_idx": 6}, {"solution": "from collections import defaultdict\ndef unique_sublists(lst):\n \"\"\"\n Counts occurrences of sublists in a given list, treating sublists as tuples.\n\n Args:\n lst (list): A list of sublists.\n\n Returns:\n dict: A dictionary where keys are tuples representing unique sublists, and values are the number of occurrences of each sublist.\n\n Example:\n >>> unique_sublists([[1, 3], [5, 7], [1, 3], [13, 15, 17], [5, 7], [9, 11]])\n {(1, 3): 2, (5, 7): 2, (13, 15, 17): 1, (9, 11): 1}\n \"\"\"\n # Create a dictionary to store counts of unique sublists, converting sublists to tuples for hashing\n sublist_counts = defaultdict(int)\n\n # Iterate over sublists, convert each to a tuple, and update the count in the dictionary\n for sublist in lst:\n sublist_tuple = tuple(sublist)\n sublist_counts[sublist_tuple] += 1\n\n return dict(sublist_counts)", "matching_cluster_idx": 5}, {"solution": "def unique_sublists(lst):\n \"\"\"\n This function counts the occurrences of sublists within a list.\n \n It returns a dictionary where every sublist is converted to a tuple and \n the value of such tuple is the number of its occurrences in the original list.\n \n :param lst: A list that contains sublists.\n :return: A dictionary with tuples of sublists as keys and their occurrences as values.\n \"\"\"\n \n # Initialize an empty dictionary to store the count of sublists\n count_dict = {}\n \n # Iterate over each sublist in the list\n for sub_list in lst:\n # Convert the sublist to a tuple so it can be used as a dictionary key\n sub_list_tuple = tuple(sub_list)\n \n # If the sublist tuple is already in the dictionary, increment its count\n if sub_list_tuple in count_dict:\n count_dict[sub_list_tuple] += 1\n # Otherwise, add it to the dictionary with a count of 1\n else:\n count_dict[sub_list_tuple] = 1\n \n # Return the dictionary\n return count_dict", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef unique_sublists(nested_list: List[List[int]]) -> dict:\n \"\"\"\n This function counts unique sublists within a list and returns a dictionary where every list \n is converted to a tuple and the value of such tuple is the number of its occurrences in the original list.\n \n Args:\n nested_list (List[List[int]]): The input list containing sublists.\n\n Returns:\n dict: A dictionary with tuples as keys and their counts as values.\n \"\"\"\n # Initialize an empty dictionary to store the counts of tuples\n tuple_counts = {}\n \n # Iterate over each sublist in the nested list\n for sublist in nested_list:\n # Convert the sublist to a tuple (to make it hashable) and use it as a key in the dictionary\n tuple_key = tuple(sublist)\n \n # If the tuple is already in the dictionary, increment its count by 1\n if tuple_key in tuple_counts:\n tuple_counts[tuple_key] += 1\n # Otherwise, add the tuple to the dictionary with a count of 1\n else:\n tuple_counts[tuple_key] = 1\n \n # Return the dictionary with the counts of unique tuples\n return tuple_counts", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(lists):\n \"\"\"\n This function takes a list of lists, converts the inner lists to tuples \n (since lists are not hashable and can't be used as dictionary keys), \n counts their occurrences, and returns a dictionary with these counts.\n\n Args:\n lists (list): A list containing other lists.\n\n Returns:\n dict: A dictionary where keys are tuples (representing the inner lists) \n and values are the number of their occurrences in the original list.\n \"\"\"\n # Initialize an empty dictionary to store the counts of tuples\n counts = {}\n\n # Iterate over each inner list in the main list\n for inner_list in lists:\n # Convert the inner list to a tuple\n inner_tuple = tuple(inner_list)\n \n # If the tuple is already in the dictionary, increment its count by 1\n if inner_tuple in counts:\n counts[inner_tuple] += 1\n # If the tuple is not in the dictionary, add it with a count of 1\n else:\n counts[inner_tuple] = 1\n\n # Return the dictionary with the counts\n return counts", "matching_cluster_idx": 6}, {"solution": "from collections import defaultdict\ndef unique_sublists(lst):\n \"\"\"\n This function takes a list of lists as an input, counts the occurrences of each sublist,\n and returns a dictionary where every sublist is converted to a tuple and the value of\n such tuple is the number of its occurrences in the original list.\n\n Args:\n lst (list): A list of lists\n\n Returns:\n dict: A dictionary where every sublist is converted to a tuple and the value of\n such tuple is the number of its occurrences in the original list.\n \"\"\"\n\n # Initialize a dictionary with default values of 0 for counting occurrences\n counts = defaultdict(int)\n\n # Iterate over each sublist in the input list\n for sublst in lst:\n # Convert the sublist to a tuple and use it as a key in the dictionary\n # We use a tuple because lists are not hashable and cannot be used as keys\n counts[tuple(sublst)] += 1\n\n # Convert the defaultdict back to a regular dictionary\n return dict(counts)", "matching_cluster_idx": 5}, {"solution": "def unique_sublists(lst):\n \"\"\"\n Counts the occurrences of sublists in a given list.\n\n Args:\n lst (list): A list containing sublists.\n\n Returns:\n dict: A dictionary where each key is a tuple (unique sublist) and its corresponding value is the number of times it occurs in the original list.\n \"\"\"\n # Initialize an empty dictionary to store unique sublists and their counts\n count_dict = {}\n\n # Iterate over each sublist in the given list\n for sub in lst:\n # Convert the sublist to a tuple to make it hashable for dictionary keys\n sub_tuple = tuple(sub)\n \n # Check if the tuple is already in the dictionary\n if sub_tuple in count_dict:\n # If it is, increment its count\n count_dict[sub_tuple] += 1\n else:\n # If not, add it to the dictionary with a count of 1\n count_dict[sub_tuple] = 1\n\n # Return the dictionary with unique sublists and their counts\n return count_dict", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(lst):\n \"\"\"\n This function takes a list of lists and returns a dictionary where every sublist\n is converted to a tuple and the value of such tuple is the number of its occurrences \n in the original list.\n\n Args:\n lst (list): A list of lists.\n\n Returns:\n dict: A dictionary where keys are tuples (sublists converted to tuples) and \n values are their respective counts.\n\n Example:\n >>> unique_sublists([[1, 3], [5, 7], [1, 3], [13, 15, 17], [5, 7], [9, 11]])\n {(1, 3): 2, (5, 7): 2, (13, 15, 17): 1, (9, 11): 1}\n \"\"\"\n\n # Convert the list of lists to a dictionary where keys are tuples (sublists \n # converted to tuples) and values are their respective counts\n return {tuple(sublist): lst.count(sublist) for sublist in lst}", "matching_cluster_idx": 3}, {"solution": "def unique_sublists(nested_list):\n \"\"\"\n This function counts the occurrences of sublists within a list.\n \n Args:\n nested_list (list): A list containing sublists.\n \n Returns:\n dict: A dictionary where every sublist is converted to a tuple and its value is the number of its occurrences in the original list.\n \"\"\"\n \n # Initialize an empty dictionary to store the count of sublists\n sublist_count = {}\n \n # Iterate over each sublist in the nested list\n for sublist in nested_list:\n # Convert the sublist to a tuple to make it hashable and usable as a dictionary key\n tuple_sublist = tuple(sublist)\n \n # If the tuple sublist is already in the dictionary, increment its count; otherwise, add it with a count of 1\n if tuple_sublist in sublist_count:\n sublist_count[tuple_sublist] += 1\n else:\n sublist_count[tuple_sublist] = 1\n \n return sublist_count", "matching_cluster_idx": 6}, {"solution": "from typing import List, Dict, Tuple\ndef unique_sublists(sublists: List[List[int]]) -> Dict[Tuple, int]:\n \"\"\"\n This function takes a list of sublists as an input and returns a dictionary where every sublist\n is converted to a tuple and the value of such tuple is the number of its occurrences in the original list.\n\n Args:\n sublists (List[List[int]]): A list of sublists containing integers.\n\n Returns:\n Dict[Tuple, int]: A dictionary where keys are tuples of unique sublists and values are their counts.\n \"\"\"\n # Convert each sublist to a tuple (since lists are not hashable) and store in a dictionary\n # with counts of their occurrences\n counts = {}\n for sublist in sublists:\n sublist_tuple = tuple(sublist)\n counts[sublist_tuple] = counts.get(sublist_tuple, 0) + 1\n\n return counts", "matching_cluster_idx": 6}, {"solution": "from collections import Counter\ndef unique_sublists(sublists):\n \"\"\"\n Counts lists within a list and returns a dictionary where every list is converted to a tuple \n and the value of such tuple is the number of its occurrences in the original list.\n\n Args:\n sublists (list): A list of lists\n\n Returns:\n dict: A dictionary where keys are tuples (representing unique sublists) and values are their counts\n \"\"\"\n # Convert sublists to tuples, because lists are not hashable and can't be dict keys\n tuples = [tuple(sublist) for sublist in sublists]\n # Count occurrences of each tuple using Counter\n counts = Counter(tuples)\n return dict(counts)", "matching_cluster_idx": 6}]}, "Mbpp/760": {"dps": 99.27007299270073, "dps_norm": 87.5, "pass@1": 30.0, "profiled": [{"solution": "def unique_Element(lst):\n \"\"\"\n This function checks whether a list of numbers contains only one distinct element or not.\n\n Args:\n lst (list): A list of numbers.\n\n Returns:\n bool: True if the list contains only one distinct element, False otherwise.\n \"\"\"\n return len(set(lst)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(lst):\n \"\"\"\n Checks whether a list of numbers contains only one distinct element.\n\n Args:\n lst (list): A list of numbers.\n\n Returns:\n bool: True if the list contains only one distinct element, False otherwise.\n\n Raises:\n TypeError: If input is not a list.\n ValueError: If list is empty.\n \"\"\"\n if not isinstance(lst, list):\n raise TypeError(\"Input must be a list.\")\n if not lst:\n raise ValueError(\"List cannot be empty.\")\n\n # Check if all elements are the same using set\n return len(set(lst)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(lst):\n \"\"\"\n Checks whether a list contains only one distinct element.\n \n Args:\n lst (list): A list of numbers.\n \n Returns:\n bool: True if the list contains only one distinct element, False otherwise.\n \"\"\"\n return len(set(lst)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(nums):\n \"\"\"\n Check if a list of numbers contains only one distinct element.\n\n Args:\n nums (list): A list of numbers.\n\n Returns:\n bool: True if the list contains only one distinct element, False otherwise.\n \"\"\"\n return len(set(nums)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(lst):\n \"\"\"\n Checks whether a list of numbers contains only one distinct element.\n\n Args:\n lst (list): List of numbers\n\n Returns:\n bool: True if list has only one distinct element, False otherwise\n \"\"\"\n # Remove duplicates by converting the list to a set and check its length\n return len(set(lst)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(lst):\n \"\"\"\n Check if all elements in the given list are the same.\n\n Args:\n lst (list): The input list of numbers.\n\n Returns:\n bool: True if all elements in the list are the same, False otherwise.\n \"\"\"\n return len(lst) != 0 and len(set(lst)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(lst):\n \"\"\"\n This function checks whether a list contains only one distinct element.\n\n Args:\n lst (list): The list of numbers.\n\n Returns:\n bool: True if the list contains only one distinct element, False otherwise.\n\n Raises:\n TypeError: If input is not a list.\n \"\"\"\n\n if not isinstance(lst, list):\n raise TypeError(\"Input must be a list\")\n\n return len(set(lst)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(lst):\n \"\"\"\n Checks whether a list of numbers contains only one distinct element or not.\n\n Args:\n lst (list): A list of numbers.\n\n Returns:\n bool: True if the list contains only one distinct element, False otherwise.\n \"\"\"\n return len(set(lst)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(lst):\n \"\"\"\n This function checks whether a list of numbers contains only one distinct element or not.\n \n Parameters:\n lst (list): A list of numbers.\n \n Returns:\n bool: True if the list contains only one distinct element, False otherwise.\n \"\"\"\n # Remove duplicates from the list by converting it to a set\n distinct_elements = set(lst)\n \n # Check if the length of the set is 1 (i.e., there's only one distinct element)\n return len(distinct_elements) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(lst):\n \"\"\"\n Checks whether a list contains only one distinct element.\n\n Args:\n lst (list): The input list to check.\n\n Returns:\n bool: True if the list contains only one distinct element, False otherwise.\n \"\"\"\n # Check if input is a list\n if not isinstance(lst, list):\n raise TypeError(\"Input must be a list\")\n\n # Check if list is empty\n if len(lst) == 0:\n return True # or raise an error, depending on the requirements\n\n # Use set to store unique elements and compare lengths\n return len(set(lst)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(lst):\n \"\"\"\n Checks whether a list of numbers contains only one distinct element.\n \n Parameters:\n lst (list): List of numbers\n \n Returns:\n bool: True if the list contains only one distinct element, False otherwise\n \"\"\"\n return len(set(lst)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(lst):\n \"\"\"\n This function checks whether a list of numbers contains only one distinct element or not.\n\n Args:\n lst (list): A list of numbers.\n\n Returns:\n bool: True if the list contains only one distinct element, False otherwise.\n \"\"\"\n return len(set(lst)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(numbers):\n \"\"\"\n Checks whether a list of numbers contains only one distinct element.\n\n Args:\n numbers (list): A list of numbers\n\n Returns:\n bool: True if the list contains only one distinct element, False otherwise\n \"\"\"\n return len(set(numbers)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(lst):\n \"\"\"\n Check whether a list contains only one distinct element.\n \n Args:\n lst (list): Input list to check.\n \n Returns:\n bool: True if list contains only one distinct element, False otherwise.\n \"\"\"\n return len(set(lst)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(lst):\n \"\"\"\n This function checks whether a list contains only one distinct element.\n \n Parameters:\n lst (list): The input list of numbers\n \n Returns:\n bool: True if the list contains only one distinct element, False otherwise\n \"\"\"\n return len(set(lst)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(lst):\n \"\"\"\n This function checks whether a list of numbers contains only one distinct element or not.\n\n Args:\n lst (list): A list of numbers.\n\n Returns:\n bool: True if the list contains only one distinct element, False otherwise.\n\n Raises:\n ValueError: If the input is not a list.\n \"\"\"\n # Check if input is a list\n if not isinstance(lst, list):\n raise ValueError(\"Input must be a list\")\n\n # Check if the list is empty\n if len(lst) == 0:\n return True # By definition, an empty list contains only one distinct element (i.e., None)\n\n # Use a set to store unique elements in the list\n unique_elements = set(lst)\n \n # If the number of unique elements is 1, the function returns True\n # Otherwise, it returns False\n return len(unique_elements) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(lst):\n \"\"\"\n Checks whether a list of numbers contains only one distinct element or not.\n\n Args:\n lst (list): List of numbers.\n\n Returns:\n bool: True if the list contains only one distinct element, False otherwise.\n \"\"\"\n return len(set(lst)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(nums):\n \"\"\"\n Checks if a list contains only one distinct element.\n\n Args:\n nums (list): A list of numbers.\n\n Returns:\n bool: True if the list contains only one distinct element, False otherwise.\n \"\"\"\n return len(set(nums)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(lst):\n \"\"\"\n Checks whether a list contains only one distinct element.\n\n Args:\n lst (list): A list of numbers.\n\n Returns:\n bool: True if the list contains only one distinct element, False otherwise.\n \"\"\"\n return len(set(lst)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(lst):\n \"\"\"\n This function checks whether a list contains only one distinct element or not.\n\n Args:\n lst (list): A list of numbers.\n\n Returns:\n bool: True if the list contains only one distinct element, False otherwise.\n \"\"\"\n # Check if the list is empty\n if not lst:\n return True\n \n # Convert the list to a set, which removes duplicates\n # If the lengths of the list and the set are equal, then all elements in the list are unique\n # But in our case, we want to check if all elements are the same, so we check if the length of the set is 1\n return len(set(lst)) == 1", "matching_cluster_idx": 6}]}, "Mbpp/764": {"dps": 88.88888888888889, "dps_norm": 50.0, "pass@1": 100.0, "profiled": [{"solution": "def number_ctr(s):\n \"\"\"\n This function takes a string as an input and returns the count of digits in the string.\n \n Parameters:\n s (str): Input string\n \n Returns:\n int: Number of digits in the string\n \"\"\"\n return sum(c.isdigit() for c in s)", "matching_cluster_idx": 2}, {"solution": "def number_ctr(input_str):\n \"\"\"\n This function counts the number of digits in a given string.\n \n Parameters:\n input_str (str): Input string to count digits from.\n \n Returns:\n int: The number of digits in the input string.\n \"\"\"\n return sum(char.isdigit() for char in input_str)", "matching_cluster_idx": 2}, {"solution": "def number_ctr(input_str):\n \"\"\"\n Counts the total number of digits in a given string.\n\n Args:\n input_str (str): Input string to search for digits.\n\n Returns:\n int: Total count of digits found in the string.\n\n \"\"\"\n return sum(char.isdigit() for char in input_str)", "matching_cluster_idx": 2}, {"solution": "def number_ctr(input_str):\n \"\"\"\n This function counts the number of digits in a given string.\n\n Args:\n input_str (str): The input string to be processed.\n\n Returns:\n int: The number of digits found in the input string.\n\n \"\"\"\n return sum(char.isdigit() for char in input_str)", "matching_cluster_idx": 2}, {"solution": "def number_ctr(input_str):\n \"\"\"\n Counts the total number of digits in a given string.\n\n Args:\n input_str (str): Input string.\n\n Returns:\n int: Total number of digits in the string.\n \"\"\"\n return sum(char.isdigit() for char in input_str)", "matching_cluster_idx": 2}, {"solution": "def number_ctr(string):\n \"\"\"\n This function counts the number of digits in a given string.\n \n Parameters:\n string (str): The input string to be processed.\n \n Returns:\n int: The number of digits found in the string.\n \"\"\"\n return sum(1 for char in string if char.isdigit())", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n \"\"\"\n Counts the number of digits in a given string.\n\n Args:\n s (str): Input string to be processed.\n\n Returns:\n int: The number of digits found in the string.\n \"\"\"\n return sum(c.isdigit() for c in s)", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n \"\"\"\n This function takes a string as input and returns the number of digits present in it.\n \n Parameters:\n s (str): The input string to count digits from.\n \n Returns:\n int: The total count of digits in the string.\n \"\"\"\n return sum(1 for c in s if c.isdigit())", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n \"\"\"\n This function counts the number of digits in a given string.\n\n Args:\n s (str): The input string.\n\n Returns:\n int: The number of digits in the string.\n \"\"\"\n return sum(c.isdigit() for c in s)", "matching_cluster_idx": 2}, {"solution": "def number_ctr(input_str):\n \"\"\"\n Count the number of digits in a given string.\n \n Args:\n input_str (str): Input string containing digits.\n \n Returns:\n int: Number of digits found in the input string.\n \"\"\"\n return sum(1 for char in input_str if char.isdigit())", "matching_cluster_idx": 2}, {"solution": "def number_ctr(input_str):\n \"\"\"\n Counts the number of digits in a given string.\n\n Args:\n input_str (str): The string to count digits from.\n\n Returns:\n int: The number of digits in the string.\n \"\"\"\n return sum(char.isdigit() for char in input_str)", "matching_cluster_idx": 2}, {"solution": "def number_ctr(input_str):\n \"\"\"\n Count the number of digits in a given string.\n \n Args:\n input_str (str): Input string to count digits from.\n \n Returns:\n int: The count of digits found in the string.\n \"\"\"\n return sum(1 for char in input_str if char.isdigit())", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s: str) -> int:\n \"\"\"\n This function takes a string as input and returns the count of digits in the string.\n \n Args:\n s (str): The input string.\n \n Returns:\n int: The count of digits in the string.\n \"\"\"\n return sum(char.isdigit() for char in s)", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n \"\"\"\n This function counts the number of digits in a given string.\n\n Args:\n s (str): The input string.\n\n Returns:\n int: The number of digits in the string.\n\n Example:\n >>> number_ctr('program2bedone')\n 1\n \"\"\"\n return sum(c.isdigit() for c in s)", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n \"\"\"\n Count the number of digits in a given string.\n\n Args:\n s (str): Input string.\n\n Returns:\n int: The number of digits in the string.\n \"\"\"\n return sum(1 for c in s if c.isdigit())", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n \"\"\"\n Returns the number of digits in a given string.\n\n :param s: Input string to count digits from\n :return: Number of digits found in the string\n \"\"\"\n return sum(c.isdigit() for c in s)", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n \"\"\"\n Count the number of digits in a given string.\n\n Args:\n s (str): Input string.\n\n Returns:\n int: Number of digits found in the string.\n\n \"\"\"\n return sum(1 for char in s if char.isdigit())", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n \"\"\"\n Returns the count of digits in the input string.\n\n Args:\n s (str): The input string.\n\n Returns:\n int: The count of digits in the string.\n \"\"\"\n return sum(c.isdigit() for c in s)", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n \"\"\"\n Counts the number of digits in a given string.\n\n Args:\n s (str): Input string.\n\n Returns:\n int: Number of digits found in the string.\n \"\"\"\n return sum(c.isdigit() for c in s)", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s: str) -> int:\n \"\"\"\n Counts the number of digits in a given string.\n \n Args:\n s (str): The input string to be checked.\n \n Returns:\n int: The count of digits in the string.\n \"\"\"\n return sum(c.isdigit() for c in s)", "matching_cluster_idx": 2}]}, "Mbpp/766": {"dps": 86.30841121495327, "dps_norm": 82.5, "pass@1": 97.0, "profiled": [{"solution": "def pair_wise(lst):\n \"\"\"\n This function takes a list of elements and returns a list of all pairs of consecutive items.\n \n :param lst: A list of elements.\n :return: A list of tuples, each containing a pair of consecutive items from the input list.\n \"\"\"\n return list(zip(lst, lst[1:]))", "matching_cluster_idx": 5}, {"solution": "def pair_wise(lst):\n \"\"\"\n Returns a list of tuples containing all pairs of consecutive items in the given list.\n \n :param lst: The input list.\n :return: A list of tuples with consecutive items.\n \"\"\"\n return list(zip(lst, lst[1:]))", "matching_cluster_idx": 5}, {"solution": "def pair_wise(lst):\n \"\"\"\n Returns a list of all pairs of consecutive items in the given list.\n\n Args:\n lst (list): A list of elements\n\n Returns:\n list: A list of tuples where each tuple is a pair of consecutive items from the input list.\n \"\"\"\n return list(zip(lst, lst[1:]))", "matching_cluster_idx": 5}, {"solution": "def pair_wise(lst):\n \"\"\"\n Returns a list of all pairs of consecutive items in the given list.\n\n Args:\n lst (list): Input list containing elements.\n\n Returns:\n list: A list of tuples where each tuple is a pair of consecutive items.\n \"\"\"\n # Initialize an empty list to store consecutive pairs\n pairs = []\n\n # Iterate over the list with index\n for i in range(len(lst)):\n # If it's not the last element in the list, create a pair with the next element\n if i < len(lst) - 1:\n pairs.append((lst[i], lst[i+1]))\n\n return pairs", "matching_cluster_idx": 1}, {"solution": "def pair_wise(input_list):\n \"\"\"\n This function takes a list as input and returns all pairs of consecutive items.\n\n Args:\n input_list (list): A list of items.\n\n Returns:\n list: A list of tuples, each containing a pair of consecutive items.\n \"\"\"\n return list(zip(input_list, input_list[1:]))", "matching_cluster_idx": 5}, {"solution": "def pair_wise(lst):\n \"\"\"\n Returns a list of all pairs of consecutive items in a given list.\n \n Args:\n lst (list): The input list.\n \n Returns:\n list: A list of tuples, where each tuple is a pair of consecutive items.\n \"\"\"\n return list(zip(lst, lst[1:]))", "matching_cluster_idx": 5}, {"solution": "def pair_wise(lst):\n \"\"\"\n This function generates a list of tuples where each tuple contains consecutive items from the input list.\n\n Args:\n lst (list): A list of elements of any data type.\n\n Returns:\n list: A list of tuples containing consecutive items from the input list.\n\n Example:\n >>> pair_wise([1, 1, 2, 3, 3, 4, 4, 5])\n [(1, 1), (1, 2), (2, 3), (3, 3), (3, 4), (4, 4), (4, 5)]\n \"\"\"\n\n # Check if the input list has less than two elements\n if len(lst) < 2:\n return []\n\n # Initialize an empty list to store the result\n result = []\n\n # Iterate over the indices of the input list excluding the last one\n for i in range(len(lst) - 1):\n # Append the pair of current and next elements to the result list\n result.append((lst[i], lst[i + 1]))\n\n # Return the list of pairs\n return result", "matching_cluster_idx": 2}, {"solution": "def pair_wise(input_list):\n \"\"\"\n This function takes an input list and returns all pairs of consecutive items.\n\n Args:\n input_list (list): A list of elements.\n\n Returns:\n list: A list of tuples where each tuple is a pair of consecutive items.\n \"\"\"\n return [(input_list[i], input_list[i + 1]) for i in range(len(input_list) - 1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n \"\"\"\n This function takes a list as an input and returns a list of all pairs of consecutive items.\n \n Args:\n lst (list): A list of items.\n \n Returns:\n list: A list of tuples, where each tuple contains a pair of consecutive items from the input list.\n \"\"\"\n return [(lst[i], lst[i+1]) for i in range(len(lst)-1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(input_list):\n \"\"\"\n Returns a list of all pairs of consecutive items in the input list.\n \n Args:\n input_list (list): A list containing any hashable elements.\n \n Returns:\n list: A list of tuples, where each tuple contains a pair of consecutive items from the input list.\n \"\"\"\n return list(zip(input_list, input_list[1:]))", "matching_cluster_idx": 5}, {"solution": "def pair_wise(items):\n \"\"\"\n Returns a list of all pairs of consecutive items in a given list.\n\n :param items: A list of items.\n :return: A list of tuples, where each tuple contains a pair of consecutive items.\n \"\"\"\n return [(items[i], items[i+1]) for i in range(len(items)-1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(input_list):\n \"\"\"\n Returns a list of all pairs of consecutive items in the input list.\n\n Args:\n input_list (list): The input list to generate pairs from.\n\n Returns:\n list: A list of tuples, where each tuple contains a pair of consecutive items.\n \"\"\"\n # Use list comprehension and the zip function to generate pairs of consecutive items\n return list(zip(input_list, input_list[1:]))", "matching_cluster_idx": 5}, {"solution": "def pair_wise(lst):\n \"\"\"\n Returns a list of all pairs of consecutive items in a given list.\n \n Args:\n lst: The input list.\n \n Returns:\n A list of tuples, each containing two consecutive items from the input list.\n \"\"\"\n # Use list comprehension to generate pairs and handle edge case where list is empty\n return [(lst[i], lst[i+1]) for i in range(len(lst) - 1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(input_list):\n \"\"\"\n Return a list of all pairs of consecutive items in a given list.\n\n Args:\n input_list (list): The list of elements for which pairs of consecutive items are to be generated.\n\n Returns:\n list: A list of tuples, where each tuple contains a pair of consecutive items from the input list.\n \"\"\"\n return list(zip(input_list, input_list[1:]))", "matching_cluster_idx": 5}, {"solution": "def pair_wise(lst):\n \"\"\"\n Returns a list of all pairs of consecutive items in the given list.\n\n Args:\n lst (list): Input list\n\n Returns:\n list: List of tuples where each tuple contains two consecutive items from the input list.\n\n Example:\n >>> pair_wise([1,1,2,3,3,4,4,5])\n [(1, 1), (1, 2), (2, 3), (3, 3), (3, 4), (4, 4), (4, 5)]\n \"\"\"\n if len(lst) < 2:\n return []\n\n # Iterate over the indices of the input list, excluding the last one\n return [(lst[i], lst[i + 1]) for i in range(len(lst) - 1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n \"\"\"\n This function generates all pairs of consecutive items from the given list.\n \n Args:\n lst (list): The input list of elements.\n \n Returns:\n list: A list of tuples, where each tuple contains a pair of consecutive items from the input list.\n \"\"\"\n return [(lst[i], lst[i+1]) for i in range(len(lst)-1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n \"\"\"\n Returns a list of all pairs of consecutive items in a given list.\n \n :param lst: Input list of items.\n :return: List of tuples, each containing a pair of consecutive items.\n \"\"\"\n return [(lst[i], lst[i+1]) for i in range(len(lst)-1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n \"\"\"\n Returns a list of tuples, where each tuple is a pair of consecutive items in the input list.\n \n Args:\n lst (list): A list of elements.\n \n Returns:\n list: A list of tuples, where each tuple contains consecutive items from the input list.\n \"\"\"\n return list(zip(lst, lst[1:]))", "matching_cluster_idx": 5}, {"solution": "def pair_wise(items):\n \"\"\"\n Returns a list of all pairs of consecutive items in a given list.\n \n :param items: Input list of items\n :return: List of tuples containing consecutive item pairs\n \"\"\"\n return list(zip(items, items[1:]))", "matching_cluster_idx": 5}, {"solution": "def pair_wise(lst):\n \"\"\"\n Returns a list of all pairs of consecutive items in the given list.\n\n Args:\n lst (list): The input list.\n\n Returns:\n list: A list of tuples, each containing a pair of consecutive items from the input list.\n \"\"\"\n return list(zip(lst, lst[1:]))", "matching_cluster_idx": 5}]}, "Mbpp/775": {"dps": 62.67999999999999, "dps_norm": 42.14285714285714, "pass@1": 98.0, "profiled": [{"solution": "def odd_position(lst):\n \"\"\"\n Check if every odd index in a list contains odd numbers.\n\n Args:\n lst (list): Input list.\n\n Returns:\n bool: True if every odd index contains odd numbers, False otherwise.\n \"\"\"\n return all(num % 2 != 0 for idx, num in enumerate(lst) if idx % 2 != 0)", "matching_cluster_idx": 2}, {"solution": "def odd_position(lst):\n \"\"\"\n Checks whether every odd index contains odd numbers of a given list.\n\n Args:\n lst (list): A list of integers.\n\n Returns:\n bool: True if every odd index contains an odd number, False otherwise.\n \"\"\"\n # Iterate through the list with enumerate to access index and value simultaneously\n return all(\n # Check if the value is odd when the index is odd\n num % 2 != 0\n for index, num in enumerate(lst)\n # Only consider odd indices\n if index % 2 != 0\n )", "matching_cluster_idx": 2}, {"solution": "def odd_position(nums):\n \"\"\"\n This function checks whether every odd index contains odd numbers of a given list.\n\n Args:\n nums (list): A list of integers.\n\n Returns:\n bool: True if every odd index contains an odd number, False otherwise.\n\n Raises:\n TypeError: If input is not a list or list contains non-integer values.\n \"\"\"\n\n # Check if input is a list\n if not isinstance(nums, list):\n raise TypeError(\"Input must be a list\")\n\n # Check if all elements in the list are integers\n if not all(isinstance(num, int) for num in nums):\n raise TypeError(\"All elements in the list must be integers\")\n\n # Iterate over the list with enumerate to access both index and value\n for i, num in enumerate(nums):\n # Check if the index is odd\n if i % 2 != 0:\n # If the index is odd, check if the number at this index is odd\n if num % 2 == 0:\n # If the number is even, return False\n return False\n\n # If the function hasn't returned False, all odd indices contain odd numbers\n return True", "matching_cluster_idx": 0}, {"solution": "def odd_position(lst):\n \"\"\"\n Check if every odd index contains an odd number in the given list.\n \n Args:\n lst (list): Input list of numbers.\n \n Returns:\n bool: True if every odd index contains an odd number, False otherwise.\n \"\"\"\n return all(num % 2 != 0 for idx, num in enumerate(lst) if idx % 2 != 0)", "matching_cluster_idx": 2}, {"solution": "def odd_position(nums):\n \"\"\"\n This function checks if every odd index in a list contains an odd number.\n\n Args:\n nums (list): A list of integers.\n\n Returns:\n bool: True if every odd index contains an odd number, False otherwise.\n \"\"\"\n return all(num % 2 != 0 for idx, num in enumerate(nums) if idx % 2 != 0)", "matching_cluster_idx": 2}, {"solution": "def odd_position(lst):\n \"\"\"\n This function checks whether every odd index contains odd numbers of a given list.\n \n Args:\n lst (list): A list of integers.\n \n Returns:\n bool: True if every odd index contains odd numbers, False otherwise.\n \"\"\"\n # Iterate over the list and its indices\n for idx, num in enumerate(lst):\n # Check if the index is odd\n if idx % 2 != 0:\n # Check if the number at the odd index is not odd\n if num % 2 == 0:\n # If the number is not odd, immediately return False\n return False\n # If the loop completes without finding any non-odd numbers at odd indices, return True\n return True", "matching_cluster_idx": 2}, {"solution": "def odd_position(nums):\n \"\"\"\n Checks whether every odd index of a given list contains odd numbers.\n\n Args:\n nums (list): A list of integers.\n\n Returns:\n bool: True if every odd index contains an odd number, False otherwise.\n \"\"\"\n return all(nums[i] % 2 != 0 for i in range(len(nums)) if i % 2 != 0)", "matching_cluster_idx": 2}, {"solution": "def odd_position(lst):\n \"\"\"\n This function checks if every odd index in a list contains an odd number.\n\n Args:\n lst (list): The input list to check.\n\n Returns:\n bool: True if every odd index contains an odd number, False otherwise.\n \"\"\"\n # Iterate over the list indices and values\n for index, value in enumerate(lst):\n # Check if the index is odd (1-based indexing)\n if index % 2 != 0:\n # If the index is odd and the value is even, return False\n if value % 2 == 0:\n return False\n # If we checked all indices and didn't return False, every odd index contains an odd number\n return True", "matching_cluster_idx": 2}, {"solution": "def odd_position(nums):\n \"\"\"\n This function checks whether every odd index contains odd numbers of a given list.\n \n Args:\n nums (list): A list of integers.\n \n Returns:\n bool: True if every odd index contains an odd number, False otherwise.\n \"\"\"\n return all(nums[i] % 2 != 0 for i in range(len(nums)) if i % 2 != 0)", "matching_cluster_idx": 2}, {"solution": "def odd_position(nums):\n \"\"\"\n Check whether every odd index contains odd numbers in a given list.\n \n Parameters:\n nums (list): Input list containing integers\n \n Returns:\n bool: True if every odd index contains an odd number, False otherwise\n \"\"\"\n return all(num % 2 != 0 for idx, num in enumerate(nums) if idx % 2 != 0)", "matching_cluster_idx": 2}, {"solution": "def odd_position(lst):\n \"\"\"\n Checks whether every odd index contains odd numbers in a given list.\n \n Args:\n lst (list): A list of integers.\n \n Returns:\n bool: True if every odd index contains an odd number, False otherwise.\n \"\"\"\n return all(num % 2 != 0 for idx, num in enumerate(lst) if idx % 2 != 0)", "matching_cluster_idx": 2}, {"solution": "def odd_position(lst):\n \"\"\"\n Checks whether every odd index contains odd numbers in a given list.\n\n Args:\n lst (list): A list of integers.\n\n Returns:\n bool: True if every odd index contains an odd number, False otherwise.\n \"\"\"\n return all(num % 2 != 0 for idx, num in enumerate(lst) if idx % 2 != 0)", "matching_cluster_idx": 2}, {"solution": "def odd_position(lst):\n \"\"\"\n Check whether every odd index contains odd numbers in a given list.\n\n Args:\n lst (list): A list of integers.\n\n Returns:\n bool: True if every odd index contains an odd number, False otherwise.\n \"\"\"\n return all(num % 2 != 0 for idx, num in enumerate(lst) if idx % 2 != 0)", "matching_cluster_idx": 2}, {"solution": "def odd_position(lst):\n \"\"\"\n Checks if every odd index of a list contains an odd number.\n\n Args:\n lst (list): A list of integers.\n\n Returns:\n bool: True if every odd index contains an odd number, False otherwise.\n \"\"\"\n return all(num % 2 != 0 for idx, num in enumerate(lst) if idx % 2 != 0)", "matching_cluster_idx": 2}, {"solution": "def odd_position(numbers):\n \"\"\"\n This function checks whether every odd index contains odd numbers in a given list.\n \n Parameters:\n numbers (list): The list of numbers to check.\n \n Returns:\n bool: True if every odd index contains an odd number, False otherwise.\n \"\"\"\n return all(numbers[i] % 2 != 0 for i in range(len(numbers)) if i % 2 != 0)", "matching_cluster_idx": 2}, {"solution": "def odd_position(numbers):\n \"\"\"\n Check whether every odd index contains odd numbers of a given list.\n \n Args:\n numbers (list): A list of integers.\n \n Returns:\n bool: True if every odd index contains an odd number, False otherwise.\n \"\"\"\n return all(numbers[i] % 2 != 0 for i in range(len(numbers)) if i % 2 != 0)", "matching_cluster_idx": 2}, {"solution": "def odd_position(lst):\n \"\"\"\n This function checks whether every odd index in the given list contains an odd number.\n\n Args:\n lst (list): A list of integers\n\n Returns:\n bool: True if all numbers at odd indices are odd, False otherwise\n \"\"\"\n # Iterate over the list, using enumerate to get both index and value\n for index, value in enumerate(lst):\n # Check if the index is odd (1-based index) and the value is even\n if index % 2 != 0 and value % 2 == 0:\n # If such a case is found, immediately return False\n return False\n # If no such case is found after iterating over the whole list, return True\n return True", "matching_cluster_idx": 2}, {"solution": "def odd_position(nums):\n \"\"\"\n Checks whether every odd index contains odd numbers in a given list.\n\n Args:\n nums (list): A list of integers.\n\n Returns:\n bool: True if every odd index contains an odd number, False otherwise.\n \"\"\"\n return all(nums[i] % 2 != 0 for i in range(len(nums)) if i % 2 != 0)", "matching_cluster_idx": 2}, {"solution": "def odd_position(nums):\n \"\"\"\n This function checks whether every odd index in a list contains an odd number.\n\n Args:\n nums (list): A list of integers.\n\n Returns:\n bool: True if every odd index in the list contains an odd number, False otherwise.\n \"\"\"\n return all(nums[i] % 2 != 0 for i in range(1, len(nums), 2))", "matching_cluster_idx": 3}, {"solution": "def odd_position(numbers):\n \"\"\"\n Checks whether every odd index contains odd numbers in a given list.\n \n Args:\n numbers (list): A list of integers.\n \n Returns:\n bool: True if every odd index contains an odd number, False otherwise.\n \"\"\"\n return all(num % 2 != 0 for idx, num in enumerate(numbers) if idx % 2 != 0)", "matching_cluster_idx": 2}]}, "Mbpp/777": {"dps": null, "dps_norm": null, "pass@1": 4.0, "profiled": []}, "Mbpp/781": {"dps": 88.46456692913385, "dps_norm": 58.0, "pass@1": 99.0, "profiled": [{"solution": "def count_divisors(n):\n \"\"\"\n Checks if the count of divisors for a given number is even.\n\n Args:\n n (int): The number to check.\n\n Returns:\n bool: True if the count of divisors is even, False otherwise.\n \"\"\"\n # Handle edge case: numbers less than 1 have 0 or 1 divisors\n if n < 1:\n return False\n\n # Initialize divisor count to 0\n divisor_count = 0\n\n # Iterate through possible divisors\n for i in range(1, n + 1):\n # Check if i is a divisor of n\n if n % i == 0:\n divisor_count += 1\n\n # Return True if divisor count is even, False otherwise\n return divisor_count % 2 == 0", "matching_cluster_idx": 1}, {"solution": "def count_divisors(n):\n \"\"\"\n This function checks whether the count of divisors of a number is even.\n\n Args:\n n (int): The number to check.\n\n Returns:\n bool: True if the count of divisors is even, False otherwise.\n \"\"\"\n # Initialize count of divisors\n count = 0\n \n # Iterate from 1 to the square root of n (inclusive)\n for i in range(1, int(n**0.5) + 1):\n # Check if i is a divisor\n if n % i == 0:\n # If i is a divisor, increment the count\n # If i is not equal to n // i, it's not a square root, so increment count by 2\n count += 2 if i != n // i else 1\n \n # Return True if count is even, False otherwise\n return count % 2 == 0", "matching_cluster_idx": 3}, {"solution": "def count_divisors(n):\n \"\"\"\n This function checks whether the count of divisors is even.\n\n Args:\n n (int): A positive integer.\n\n Returns:\n bool: True if the count of divisors is even, False otherwise.\n \"\"\"\n # Initialize divisor counter\n divisor_count = 0\n\n # Check all numbers up to n (inclusive) for divisibility\n for i in range(1, n + 1):\n if n % i == 0: # Check if i is a divisor\n divisor_count += 1\n\n # Return True if divisor count is even, False otherwise\n return divisor_count % 2 == 0", "matching_cluster_idx": 1}, {"solution": "def count_divisors(n):\n \"\"\"\n Returns True if the count of divisors for the number n is even, False otherwise.\n\n Args:\n n (int): The input number.\n\n Returns:\n bool: Whether the count of divisors for n is even.\n\n Examples:\n >>> count_divisors(10)\n True\n >>> count_divisors(11)\n False\n \"\"\"\n # Initialize count of divisors to 0\n count = 0\n \n # Loop through all numbers from 1 to n (inclusive)\n for i in range(1, n + 1):\n # If n is divisible by i, increment the count\n if n % i == 0:\n count += 1\n \n # Check if count is even\n return count % 2 == 0", "matching_cluster_idx": 1}, {"solution": "def count_divisors(n):\n \"\"\"\n Checks whether the count of divisors of a number is even.\n\n Args:\n n (int): The input number to check.\n\n Returns:\n bool: True if the number of divisors is even, False otherwise.\n \"\"\"\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n if n // i == i:\n count += 1\n else:\n count += 2\n return count % 2 == 0", "matching_cluster_idx": 3}, {"solution": "def count_divisors(n):\n \"\"\"\n This function checks whether the count of divisors of a given number is even.\n \n Parameters:\n n (int): The number for which the count of divisors is to be checked.\n \n Returns:\n bool: True if the count of divisors is even, False otherwise.\n \"\"\"\n count = 0\n # Iterate from 1 to the square root of n\n for i in range(1, int(n ** 0.5) + 1):\n # Check if i is a divisor of n\n if n % i == 0:\n # If i is a divisor, then n // i is also a divisor\n if i * i == n:\n count += 1 # Count the square root only once\n else:\n count += 2 # Count both i and n // i\n return count % 2 == 0", "matching_cluster_idx": 3}, {"solution": "def count_divisors(n):\n \"\"\"\n Checks if the count of divisors for a number is even.\n\n Args:\n n (int): The number to check.\n\n Returns:\n bool: True if the number of divisors is even, False otherwise.\n \"\"\"\n # Initialize count of divisors\n count = 0\n \n # Check all numbers from 1 to n (inclusive) for divisibility\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n \n # Return True if the count is even, False otherwise\n return count % 2 == 0", "matching_cluster_idx": 1}, {"solution": "def count_divisors(n):\n \"\"\"\n This function checks whether the count of divisors of a given number is even.\n \n Args:\n n (int): The input number.\n \n Returns:\n bool: True if the count of divisors is even, False otherwise.\n \"\"\"\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n # If n is a perfect square, don't count its square root twice\n if n // i == i:\n count += 1\n else:\n count += 2\n return count % 2 == 0", "matching_cluster_idx": 3}, {"solution": "def count_divisors(n):\n \"\"\"\n Returns True if the number of divisors for 'n' is even.\n\n Args:\n n (int): The input number.\n\n Returns:\n bool: True if the number of divisors is even, False otherwise.\n \"\"\"\n count = 0\n for i in range(1, int(n ** 0.5) + 1):\n if n % i == 0:\n # For each divisor 'i', there's a corresponding 'n // i'.\n # However, for a square root 'i', 'n // i' would be 'i' itself, \n # so we increment count only once in this case.\n if i * i != n:\n count += 2\n else:\n count += 1\n return count % 2 == 0", "matching_cluster_idx": 3}, {"solution": "def count_divisors(n: int) -> bool:\n \"\"\"\n Checks if the count of divisors for a given number is even.\n\n Args:\n n (int): The number to check.\n\n Returns:\n bool: True if the count of divisors is even, False otherwise.\n \"\"\"\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count % 2 == 0", "matching_cluster_idx": 1}, {"solution": "def count_divisors(n):\n \"\"\"\n Checks whether the count of divisors of a number is even.\n\n Args:\n n (int): The input number.\n\n Returns:\n bool: True if the count of divisors is even, False otherwise.\n \"\"\"\n # Initialize divisor count to 0\n count = 0\n \n # Iterate through numbers from 1 to n (inclusive)\n for i in range(1, n + 1):\n # Check if i is a divisor of n\n if n % i == 0:\n # If it's a divisor, increment the count\n count += 1\n \n # Return True if count is even, False otherwise\n return count % 2 == 0", "matching_cluster_idx": 1}, {"solution": "def count_divisors(n):\n \"\"\"\n Checks whether the count of divisors of a given number is even.\n\n Args:\n n (int): The number to check.\n\n Returns:\n bool: True if the count of divisors is even, False otherwise.\n \"\"\"\n # Initialize a counter for divisors\n count = 0\n \n # Iterate over all numbers from 1 to n (inclusive)\n for i in range(1, n + 1):\n # Check if i is a divisor of n\n if n % i == 0:\n # If it is, increment the counter\n count += 1\n \n # Return True if the count is even, False otherwise\n return count % 2 == 0", "matching_cluster_idx": 1}, {"solution": "def count_divisors(n):\n \"\"\"\n Returns True if the count of divisors is even, False otherwise.\n\n Args:\n n (int): The input number to check.\n\n Returns:\n bool: Whether the count of divisors is even.\n \"\"\"\n count = 0\n # Only need to check up to the square root of n\n for i in range(1, int(n ** 0.5) + 1):\n if n % i == 0:\n # If i is a divisor, then n/i is also a divisor\n count += 2 if i * i != n else 1\n return count % 2 == 0", "matching_cluster_idx": 3}, {"solution": "def count_divisors(n):\n \"\"\"\n Returns True if the count of divisors of n is even, False otherwise.\n\n :param n: The number to check\n :return: bool\n \"\"\"\n count = 0\n for i in range(1, int(n ** 0.5) + 1):\n if n % i == 0:\n # if i is a divisor, n//i will also be a divisor\n # but we should only count them once for perfect squares\n if i * i != n:\n count += 2\n else:\n count += 1\n return count % 2 == 0", "matching_cluster_idx": 3}, {"solution": "def count_divisors(n):\n \"\"\"\n This function checks whether the count of divisors of a number is even.\n \n Args:\n n (int): The number to be checked.\n \n Returns:\n bool: True if the count of divisors is even, False otherwise.\n \"\"\"\n count = 0\n for i in range(1, int(n ** 0.5) + 1):\n if n % i == 0:\n # If i is a divisor, n//i will also be a divisor\n if n // i == i:\n count += 1\n else:\n count += 2\n return count % 2 == 0", "matching_cluster_idx": 3}, {"solution": "def count_divisors(n: int) -> bool:\n \"\"\"\n Checks whether the count of divisors of a number is even.\n \n Args:\n n (int): The number to check.\n \n Returns:\n bool: True if the count of divisors is even, False otherwise.\n \"\"\"\n # Initialize a counter variable to store the count of divisors\n count = 0\n \n # Iterate from 1 to the number (inclusive)\n for i in range(1, n + 1):\n # Check if the current number is a divisor\n if n % i == 0:\n # Increment the counter\n count += 1\n \n # Return True if the count is even, False otherwise\n return count % 2 == 0", "matching_cluster_idx": 1}, {"solution": "def count_divisors(n):\n \"\"\"\n Check whether the count of divisors of a number is even.\n\n Args:\n n (int): The number to check.\n\n Returns:\n bool: True if the number of divisors is even, False otherwise.\n \"\"\"\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n if n // i == i:\n count += 1\n else:\n count += 2\n return count % 2 == 0", "matching_cluster_idx": 3}, {"solution": "def count_divisors(n):\n \"\"\"\n Check whether the count of divisors for a given number is even.\n \n Args:\n n (int): A positive integer number.\n \n Returns:\n bool: True if the count of divisors is even, False otherwise.\n \"\"\"\n # Initialize a counter variable for divisors\n count = 0\n \n # Iterate over all numbers from 1 to n\n for i in range(1, n + 1):\n # Check if i is a divisor of n\n if n % i == 0:\n # If i is a divisor, increment the count\n count += 1\n \n # Return True if the count is even, False otherwise\n return count % 2 == 0", "matching_cluster_idx": 1}, {"solution": "def count_divisors(n):\n \"\"\"\n This function checks whether the count of divisors for a given number is even.\n \n Parameters:\n n (int): The number to check for divisors.\n \n Returns:\n bool: True if the count of divisors is even, False otherwise.\n \"\"\"\n # Initialize count of divisors\n divisor_count = 0\n \n # Iterate over all numbers from 1 to n\n for i in range(1, n + 1):\n # Check if i is a divisor of n\n if n % i == 0:\n # If i is a divisor, increment the count\n divisor_count += 1\n \n # Check if the count of divisors is even\n return divisor_count % 2 == 0", "matching_cluster_idx": 1}, {"solution": "def count_divisors(n):\n \"\"\"\n Checks whether the count of divisors of a given number is even.\n \n Args:\n n (int): The number to check.\n\n Returns:\n bool: True if the count of divisors is even, False otherwise.\n \"\"\"\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count % 2 == 0", "matching_cluster_idx": 1}]}, "Mbpp/800": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 99.0, "profiled": [{"solution": "def remove_all_spaces(s):\n \"\"\"\n This function removes all whitespaces from a string.\n \n Parameters:\n s (str): The input string.\n \n Returns:\n str: The input string with all whitespaces removed.\n \"\"\"\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n \"\"\"\n Removes all whitespace characters from a given string.\n\n Args:\n input_string (str): The string from which to remove whitespace.\n\n Returns:\n str: A new string with all whitespace removed.\n \"\"\"\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n \"\"\"\n This function removes all whitespaces from a given string.\n\n Args:\n input_string (str): The string from which to remove whitespaces.\n\n Returns:\n str: The input string without whitespaces.\n \"\"\"\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n \"\"\"\n This function removes all whitespaces from a given string.\n \n Args:\n input_string (str): The string from which to remove all whitespaces.\n \n Returns:\n str: The input string without any whitespaces.\n \"\"\"\n return input_string.replace(' ', '')", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n \"\"\"\n Removes all whitespaces from the input string.\n\n Args:\n input_string (str): Input string to remove whitespaces from.\n\n Returns:\n str: Input string with all whitespaces removed.\n \"\"\"\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n \"\"\"\n This function removes all whitespaces from a given input string.\n\n Args:\n input_string (str): Input string from which whitespaces are to be removed.\n\n Returns:\n str: The input string with all whitespaces removed.\n \"\"\"\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n \"\"\"\n This function removes all whitespaces from a given string.\n\n Args:\n input_string (str): The string from which all whitespaces need to be removed.\n\n Returns:\n str: A string with all whitespaces removed.\n \"\"\"\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n \"\"\"\n This function removes all whitespaces from a string.\n \n Args:\n input_string (str): The input string from which whitespaces will be removed.\n\n Returns:\n str: A new string without any whitespaces.\n \"\"\"\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n \"\"\"\n Removes all whitespaces from a given string.\n\n Args:\n input_string (str): The string to remove whitespaces from.\n\n Returns:\n str: The string with all whitespaces removed.\n \"\"\"\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n \"\"\"\n This function removes all whitespaces from the input string.\n \n Args:\n input_string (str): The string from which to remove whitespaces.\n \n Returns:\n str: The input string with all whitespaces removed.\n \"\"\"\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n \"\"\"\n Removes all whitespaces from a given input string.\n \n Args:\n input_string (str): Input string containing whitespaces.\n \n Returns:\n str: The input string with all whitespaces removed.\n \"\"\"\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n \"\"\"\n Removes all spaces from a given string.\n\n Args:\n input_string (str): Input string to process.\n\n Returns:\n str: Input string without spaces.\n \"\"\"\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n \"\"\"\n Removes all spaces from the input string.\n\n Args:\n input_string (str): The input string from which spaces are to be removed.\n\n Returns:\n str: The string after removing all spaces.\n \"\"\"\n return input_string.replace(' ', '')", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n \"\"\"\n This function takes a string as an input and removes all the spaces from it.\n \n Parameters:\n input_string (str): The string to remove spaces from.\n \n Returns:\n str: The string with all spaces removed.\n \"\"\"\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(s):\n \"\"\"\n This function takes a string as input, removes all whitespaces and returns the result.\n\n Args:\n s (str): Input string that may contain whitespaces.\n\n Returns:\n str: Input string without any whitespaces.\n\n \"\"\"\n return s.replace(' ', '')", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(s):\n \"\"\"\n Removes all whitespace characters from a given string.\n\n Args:\n s (str): The input string.\n\n Returns:\n str: The input string with all whitespace characters removed.\n \"\"\"\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(s):\n \"\"\"\n This function removes all whitespaces from a given string.\n\n Args:\n s (str): Input string\n\n Returns:\n str: The input string without whitespaces\n \"\"\"\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n \"\"\"\n This function removes all whitespaces from a given string.\n\n Args:\n input_string (str): The input string to remove spaces from.\n\n Returns:\n str: The input string without any whitespaces.\n \"\"\"\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n \"\"\"\n Removes all whitespaces from a string.\n\n Args:\n input_string (str): The input string to remove spaces from.\n\n Returns:\n str: The string with all spaces removed.\n \"\"\"\n return input_string.replace(' ', '')", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(s: str) -> str:\n \"\"\"\n This function removes all whitespaces from a given string.\n\n Args:\n s (str): Input string.\n\n Returns:\n str: String without whitespaces.\n \"\"\"\n return s.replace(' ', '')", "matching_cluster_idx": 4}]}, "Mbpp/805": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 98.0, "profiled": [{"solution": "def max_sum_list(lists):\n \"\"\"\n Returns the list in a list of lists whose sum of elements is the highest.\n\n Args:\n lists (list): A list of lists containing numbers.\n\n Returns:\n list: The list with the highest sum of elements.\n \"\"\"\n # Use the built-in max function with a custom key function to find the list with the highest sum.\n # The key function sums up the elements of each sublist and returns this sum.\n return max(lists, key=sum)", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n \"\"\"\n Returns the list in a list of lists with the highest sum of elements.\n\n Args:\n lists (list): A list of lists containing numbers.\n\n Returns:\n list: The list with the highest sum of elements.\n\n Raises:\n ValueError: If input list is empty.\n \"\"\"\n if not lists:\n raise ValueError(\"Input list cannot be empty\")\n\n return max(lists, key=sum)", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n \"\"\"\n Returns the list in a list of lists whose sum of elements is the highest.\n \n Args:\n lists (list of lists): A list containing multiple lists of integers.\n \n Returns:\n list: The list within the input list of lists that has the highest sum of elements.\n \"\"\"\n # Use max function with key argument set to sum to find the list with the highest sum\n return max(lists, key=sum)", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n \"\"\"\n Returns the list in a list of lists whose sum of elements is the highest.\n\n Args:\n lists (list): A list of lists of numbers.\n\n Returns:\n list: The list with the highest sum of elements.\n \"\"\"\n return max(lists, key=sum)", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n \"\"\"\n Returns the list in a list of lists whose sum of elements is the highest.\n\n Args:\n lists (list): A list of lists containing numbers.\n\n Returns:\n list: The list in the input list of lists with the highest sum.\n \"\"\"\n # Use the max function with a key argument that calculates the sum of each sublist\n # The max function will return the first sublist with the maximum sum\n return max(lists, key=sum)", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n \"\"\"\n Returns the list in a list of lists whose sum of elements is the highest.\n\n Args:\n lists (list): A list of lists containing integers.\n\n Returns:\n list: The sublist with the highest sum of elements.\n \"\"\"\n return max(lists, key=sum)", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n \"\"\"\n Returns the list in a list of lists whose sum of elements is the highest.\n\n Args:\n lists (list): A list of lists.\n\n Returns:\n list: The list with the highest sum.\n\n Raises:\n ValueError: If input list is empty.\n \"\"\"\n if not lists:\n raise ValueError(\"Input list cannot be empty\")\n\n return max(lists, key=sum)", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n \"\"\"\n Returns the list in a list of lists whose sum of elements is the highest.\n\n Args:\n lists (list): A list of lists containing integers.\n\n Returns:\n list: The list with the highest sum of elements.\n \"\"\"\n # Use the max function with a custom key to find the list with the highest sum\n return max(lists, key=sum)", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n \"\"\"\n Returns the list in a list of lists whose sum of elements is the highest.\n\n Args:\n lists (list of lists): A list of lists containing integers.\n\n Returns:\n list: The list with the highest sum of elements.\n \"\"\"\n return max(lists, key=sum)", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n \"\"\"\n Returns the list in a list of lists whose sum of elements is the highest.\n \n Args:\n lists (list of lists): A list containing multiple lists of numbers.\n \n Returns:\n list: The list whose sum of elements is the highest.\n \"\"\"\n \n # Use max with a custom key function that calculates the sum of each inner list\n # The max function will then return the first inner list with the maximum sum\n return max(lists, key=sum)", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(list_of_lists):\n \"\"\"\n Returns the list in a list of lists whose sum of elements is the highest.\n\n Args:\n list_of_lists (list): A list of lists containing integers.\n\n Returns:\n list: The list with the highest sum of elements.\n \"\"\"\n return max(list_of_lists, key=sum)", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n \"\"\"\n Returns the list in a list of lists whose sum of elements is the highest.\n\n Args:\n lists (list): A list of lists containing numbers.\n\n Returns:\n list: The sublist with the highest sum.\n \"\"\"\n return max(lists, key=sum)", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n \"\"\"\n This function takes a list of lists as input, and returns the list with the highest sum of elements.\n\n Args:\n lists (list of lists): A list of lists of numbers.\n\n Returns:\n list: The list with the highest sum of elements.\n \"\"\"\n return max(lists, key=sum)", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n \"\"\"\n Returns the list in a list of lists whose sum of elements is the highest.\n\n Args:\n lists (list): A list of lists containing numbers.\n\n Returns:\n list: The list with the highest sum of elements.\n\n Raises:\n ValueError: If the input list is empty.\n \"\"\"\n\n # Check if input list is empty\n if not lists:\n raise ValueError(\"Input list cannot be empty\")\n\n # Use max function with key argument set to sum to find the list with the highest sum\n # The max function returns the first list it encounters with the maximum sum\n # This approach assumes that the input lists contain only numbers\n return max(lists, key=sum)", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(list_of_lists):\n \"\"\"\n This function takes a list of lists as input, calculates the sum of each sublist,\n and returns the sublist with the highest sum.\n\n Args:\n list_of_lists (list): A list of lists containing integers.\n\n Returns:\n list: The sublist with the highest sum.\n \"\"\"\n # Use the built-in max function with a custom key that calculates the sum of each sublist\n # and returns the first sublist with the maximum sum\n return max(list_of_lists, key=sum)", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n \"\"\"\n Returns the list in a list of lists whose sum of elements is the highest.\n\n Args:\n lists (list): A list of lists containing numbers.\n\n Returns:\n list: The list with the highest sum of elements.\n \"\"\"\n return max(lists, key=sum)", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n \"\"\"\n Returns the list in a list of lists with the highest sum of elements.\n\n Args:\n lists (list): A list of lists containing numbers.\n\n Returns:\n list: The list in the input list of lists with the highest sum of elements.\n \"\"\"\n return max(lists, key=sum)", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n \"\"\"\n Returns the list in a list of lists with the highest sum of elements.\n\n Args:\n lists (list of lists): A list of lists containing numbers.\n\n Returns:\n list: The list with the highest sum of elements.\n \"\"\"\n return max(lists, key=sum)", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n \"\"\"\n Returns the list in a list of lists whose sum of elements is the highest.\n\n Args:\n lists (list): A list of lists containing integers.\n\n Returns:\n list: The list with the highest sum of elements.\n\n Raises:\n ValueError: If the input list is empty.\n \"\"\"\n if not lists:\n raise ValueError(\"Input list cannot be empty\")\n\n # Use the built-in max function with a custom key to find the list with the highest sum\n # The key function takes a list and returns its sum\n return max(lists, key=sum)", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n \"\"\"\n Returns the list in a list of lists whose sum of elements is the highest.\n\n Args:\n lists (list): A list of lists containing numeric values.\n\n Returns:\n list: The list with the highest sum of elements.\n \"\"\"\n # Use the max function with a custom key to find the list with the highest sum\n return max(lists, key=sum)", "matching_cluster_idx": 4}]}, "Mbpp/808": {"dps": 75.74561403508771, "dps_norm": 94.16666666666667, "pass@1": 100.0, "profiled": [{"solution": "def check_K(tup, k):\n \"\"\"\n This function checks if the given tuple contains the specified value.\n\n Args:\n tup (tuple): Input tuple to be searched.\n k (any): The value to be searched within the tuple.\n\n Returns:\n bool: True if the tuple contains the value, False otherwise.\n \"\"\"\n return k in tup", "matching_cluster_idx": 4}, {"solution": "def check_K(tup, k):\n \"\"\"\n Checks if the given tuple contains the value k.\n\n Args:\n tup (tuple): The input tuple.\n k (any): The value to be searched in the tuple.\n\n Returns:\n bool: True if k is in the tuple, False otherwise.\n \"\"\"\n return k in tup", "matching_cluster_idx": 4}, {"solution": "def check_K(tup, k):\n \"\"\"\n This function checks if a given tuple contains the value k.\n \n Parameters:\n tup (tuple): The input tuple to be searched.\n k (any): The value to be searched in the tuple.\n \n Returns:\n bool: True if k is found in the tuple, False otherwise.\n \"\"\"\n return k in tup", "matching_cluster_idx": 4}, {"solution": "def check_K(tup, k):\n \"\"\"\n Checks if a tuple contains a given element k.\n\n Args:\n tup (tuple): A tuple to be checked.\n k (any): An element to be searched in the tuple.\n\n Returns:\n bool: True if k is found in the tuple, False otherwise.\n\n \"\"\"\n return k in tup", "matching_cluster_idx": 4}, {"solution": "def check_K(tup, k):\n \"\"\"\n Check if the given tuple contains the element k.\n\n Args:\n tup (tuple): The tuple to be searched.\n k (any): The element to be searched for.\n\n Returns:\n bool: True if the tuple contains the element k, False otherwise.\n \"\"\"\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n \"\"\"\n This function checks if the given tuple contains the specified value k.\n\n Args:\n tup (tuple): The tuple to be searched.\n k (any): The value to be searched for in the tuple.\n\n Returns:\n bool: True if the tuple contains k, False otherwise.\n \"\"\"\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n \"\"\"\n Check if the given tuple contains the element k.\n\n Args:\n tup (tuple): The tuple to be searched.\n k (any): The element to be searched for.\n\n Returns:\n bool: True if the tuple contains k, False otherwise.\n \"\"\"\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n \"\"\"\n This function checks if the given tuple contains the number k.\n\n Args:\n tup (tuple): The input tuple to be checked.\n k (int): The number to be searched in the tuple.\n\n Returns:\n bool: True if the tuple contains the number k, False otherwise.\n \"\"\"\n return k in tup", "matching_cluster_idx": 4}, {"solution": "def check_K(tup, k):\n \"\"\"\n This function checks if a given tuple contains the specified element k.\n\n Args:\n tup (tuple): A tuple of elements to search in.\n k (any): The element to search for.\n\n Returns:\n bool: True if the element is found, False otherwise.\n \"\"\"\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(tuple_to_check, k):\n \"\"\"\n Check if a given tuple contains a specified value.\n\n Args:\n tuple_to_check (tuple): The tuple to search in.\n k (any): The value to search for.\n\n Returns:\n bool: True if the tuple contains the value, False otherwise.\n \"\"\"\n return k in tuple_to_check", "matching_cluster_idx": 4}, {"solution": "def check_K(tup, k):\n \"\"\"\n This function checks if a given tuple contains the element k.\n\n Args:\n tup (tuple): The input tuple to be searched.\n k (any): The element to be searched in the tuple.\n\n Returns:\n bool: True if the element k is found in the tuple, False otherwise.\n \"\"\"\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n \"\"\"\n Checks if a given tuple contains the specified key 'k'.\n\n Args:\n tup (tuple): Input tuple to search in.\n k (any): Value to search for.\n\n Returns:\n bool: True if 'k' is found in the tuple, False otherwise.\n \"\"\"\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(input_tuple, k):\n \"\"\"\n Checks if the given tuple contains the value k.\n\n Args:\n input_tuple (tuple): The tuple to search in.\n k (int): The value to search for.\n\n Returns:\n bool: True if k is found in the tuple, False otherwise.\n \"\"\"\n return k in input_tuple", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n \"\"\"\n Checks if the given tuple contains the value k.\n \n Args:\n tup (tuple): The input tuple to be checked.\n k (any): The value to be searched in the tuple.\n \n Returns:\n bool: True if k is found in the tuple, False otherwise.\n \"\"\"\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(input_tuple, K):\n \"\"\"\n This function checks if the given tuple contains the specified value K.\n\n Args:\n input_tuple (tuple): The input tuple to be checked.\n K (any): The value to be searched in the tuple.\n\n Returns:\n bool: True if the tuple contains K, False otherwise.\n \"\"\"\n return K in input_tuple", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n \"\"\"\n This function checks if the given tuple contains the element k.\n \n Parameters:\n tup (tuple): The tuple to search in\n k (int): The element to search for\n \n Returns:\n bool: True if the tuple contains k, False otherwise\n \"\"\"\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n \"\"\"\n Checks if the given tuple contains the element k.\n\n Args:\n tup (tuple): The tuple to check.\n k (any): The element to check for.\n\n Returns:\n bool: True if k is found in the tuple, False otherwise.\n \"\"\"\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n \"\"\"\n This function checks if the given tuple contains the specified value k.\n\n Args:\n tup (tuple): The input tuple to be searched.\n k: The value to be searched in the tuple.\n\n Returns:\n bool: True if k is found in the tuple, False otherwise.\n \"\"\"\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n \"\"\"\n This function checks if the given tuple contains the specified number.\n \n Args:\n tup (tuple): The input tuple to be checked.\n k (int): The number to be searched in the tuple.\n \n Returns:\n bool: True if the tuple contains the number, False otherwise.\n \"\"\"\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n \"\"\"\n Checks if the given tuple contains the specified value k.\n\n Args:\n tup (tuple): The input tuple to search in.\n k (any): The value to search for in the tuple.\n\n Returns:\n bool: True if k is found in the tuple, False otherwise.\n \"\"\"\n return k in tup", "matching_cluster_idx": 4}]}}} \ No newline at end of file diff --git a/results/evalperf/meta-llama--Llama-3.1-8B-Instruct_vllm_temp_1.0_evalperf_results.brief.json b/results/evalperf/meta-llama--Llama-3.1-8B-Instruct_vllm_temp_1.0_evalperf_results.brief.json new file mode 100644 index 0000000..e4bd923 --- /dev/null +++ b/results/evalperf/meta-llama--Llama-3.1-8B-Instruct_vllm_temp_1.0_evalperf_results.brief.json @@ -0,0 +1 @@ +{"date": "2024-10-19 16:29", "config": {"n_samples": 100, "temperature": 1.0, "min_correct": 10, "max_profile": 20}, "summary": {"dps": 80.93273308299496, "dps_norm": 76.57037397653662, "pass@1": 64.34745762711864}, "eval": {"HumanEval/9": {"dps": 86.00946372239747, "dps_norm": 85.55555555555556, "pass@1": 76.0, "profiled": [{"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\"\n From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n \n Args:\n numbers (List[int]): A list of integers\n \n Returns:\n List[int]: A list of rolling maximum elements found in the sequence\n \"\"\"\n if not numbers:\n return []\n \n max_so_far = numbers[0]\n rolling_maxes = [max_so_far]\n \n for num in numbers[1:]:\n max_so_far = max(max_so_far, num)\n rolling_maxes.append(max_so_far)\n \n return rolling_maxes", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\"\n From a given list of integers, generate a list of rolling maximum element found until given moment in the sequence.\n\n Args:\n numbers (List[int]): A list of integers.\n\n Returns:\n List[int]: A list of rolling maximum elements.\n\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n rolling_maxes = []\n current_max = float('-inf')\n\n for num in numbers:\n if num >= current_max:\n current_max = num\n rolling_maxes.append(current_max)\n else:\n rolling_maxes.append(current_max)\n\n return rolling_maxes", "matching_cluster_idx": 8}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\"\n From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n\n Args:\n numbers (List[int]): A list of integers.\n\n Returns:\n List[int]: A list of rolling maximum elements.\n\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n max_element = float('-inf')\n max_list = []\n\n for num in numbers:\n max_element = max(num, max_element)\n max_list.append(max_element)\n\n return max_list", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n \n Args:\n numbers (List[int]): A list of integers.\n \n Returns:\n List[int]: A list of rolling maximum elements.\n \"\"\"\n if not numbers:\n return []\n \n rolling_max_list = [numbers[0]]\n max_so_far = numbers[0]\n \n for num in numbers[1:]:\n if num >= max_so_far:\n max_so_far = num\n rolling_max_list.append(max_so_far)\n else:\n rolling_max_list.append(max_so_far)\n \n return rolling_max_list", "matching_cluster_idx": 8}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\"\n From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n \n Args:\n numbers: A list of integers.\n \n Returns:\n A list of rolling maximum integers.\n \"\"\"\n if not numbers:\n return []\n \n max_seen = float('-inf') # Initialize max_seen to negative infinity\n rolling_max_list = []\n \n for num in numbers:\n if num > max_seen:\n max_seen = num\n rolling_max_list.append(max_seen)\n \n return rolling_max_list", "matching_cluster_idx": 8}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\"\n From a given list of integers, generate a list of rolling maximum element found until given moment in the sequence.\n\n Args:\n numbers (List[int]): A list of integers.\n\n Returns:\n List[int]: A list of rolling maximum element found until given moment in the sequence.\n\n Example:\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n rolling_max_list = []\n max_num = float('-inf') # Initialize max_num as negative infinity\n\n for num in numbers:\n if num > max_num:\n max_num = num\n rolling_max_list.append(max_num)\n\n return rolling_max_list", "matching_cluster_idx": 8}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\"\n From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n \n Args:\n numbers (List[int]): A list of integers.\n \n Returns:\n List[int]: A list of rolling maximum elements.\n \"\"\"\n result = []\n max_num = float('-inf') # Initialize max_num as negative infinity\n \n for num in numbers:\n if num > max_num:\n max_num = num\n result.append(max_num)\n \n return result", "matching_cluster_idx": 8}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\"\n From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n \n Args:\n numbers (List[int]): A list of integers.\n \n Returns:\n List[int]: A list of rolling maximum elements.\n \"\"\"\n if not numbers:\n return []\n \n max_num = numbers[0]\n result = [max_num]\n \n for num in numbers[1:]:\n max_num = max(max_num, num)\n result.append(max_num)\n \n return result", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\"\n From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n\n Args:\n numbers (List[int]): A list of integers\n\n Returns:\n List[int]: A list of rolling maximum element found until given moment in the sequence\n\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n # Initialize an empty list to store the rolling max values\n rolling_max_values = []\n\n # Initialize the current max value as negative infinity\n current_max = float('-inf')\n\n # Iterate over the numbers in the input list\n for num in numbers:\n # If the current number is greater than the current max, update the current max\n if num > current_max:\n current_max = num\n # Append the current max to the rolling max values list\n rolling_max_values.append(current_max)\n\n return rolling_max_values\nnumbers = [1, 2, 3, 2, 3, 4, 2]", "matching_cluster_idx": 8}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\"\n From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n\n Args:\n numbers (List[int]): A list of integers.\n\n Returns:\n List[int]: A list of rolling maximum elements.\n\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n result = []\n max_until_now = float('-inf')\n for num in numbers:\n max_until_now = max(num, max_until_now)\n result.append(max_until_now)\n return result", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\"\n Generate a list of rolling maximum element found until given moment in the sequence.\n\n Args:\n numbers (List[int]): A list of integers.\n\n Returns:\n List[int]: A list of rolling maximum elements.\n\n Example:\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n max_element = float('-inf') # Initialize max_element as negative infinity\n rolling_maxes = [] # Initialize an empty list to store rolling max elements\n\n for num in numbers:\n if num > max_element: # If current number is greater than max_element\n max_element = num # Update max_element\n rolling_maxes.append(max_element) # Append max_element to the list\n\n return rolling_maxes", "matching_cluster_idx": 8}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\"\n From a given list of integers, generate a list of rolling maximum element found until given moment \n in the sequence.\n\n Args:\n numbers (List[int]): A list of integers.\n\n Returns:\n List[int]: A list of rolling maximum elements.\n\n Example:\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n \n max_so_far = float('-inf')\n result = []\n \n for num in numbers:\n max_so_far = max(max_so_far, num)\n result.append(max_so_far)\n \n return result", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" \n From a given list of integers, generate a list of rolling maximum element found until given moment \n in the sequence.\n\n Args:\n numbers (List[int]): A list of integers.\n\n Returns:\n List[int]: A list of rolling maximum elements.\n\n Example:\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n rolling_max_list = []\n current_max = float('-inf') # Initialize with negative infinity\n\n for num in numbers:\n if num >= current_max:\n rolling_max_list.append(num)\n current_max = num\n else:\n rolling_max_list.append(current_max)\n\n return rolling_max_list", "matching_cluster_idx": 8}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\"\n From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n\n Args:\n numbers: A list of integers.\n\n Returns:\n A list of rolling maximum element found until each given moment in the sequence.\n\n Example:\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n max_rolling = []\n max_current = float('-inf')\n\n for num in numbers:\n if num > max_current:\n max_current = num\n max_rolling.append(max_current)\n\n return max_rolling", "matching_cluster_idx": 8}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\"\n From a given list of integers, generate a list of rolling maximum element found until given moment in the sequence.\n\n Args:\n numbers: A list of integers.\n\n Returns:\n A list of rolling maximum element found until given moment in the sequence.\n \"\"\"\n result = []\n max_found = float('-inf') # Initialize max as negative infinity\n for num in numbers:\n if num > max_found:\n max_found = num\n result.append(max_found)\n return result", "matching_cluster_idx": 8}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\"From a given list of integers, generate a list of rolling maximum element found until given moment in the sequence.\"\"\"\n if not numbers:\n return []\n \n result = [numbers[0]]\n max_so_far = numbers[0]\n \n for num in numbers[1:]:\n if num >= max_so_far:\n max_so_far = num\n result.append(num)\n else:\n result.append(max_so_far)\n \n return result", "matching_cluster_idx": 8}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\"\n Generate a list of rolling maximum element found until given moment in the sequence.\n \n Args:\n numbers (List[int]): A list of integers.\n \n Returns:\n List[int]: A list of rolling maximum elements.\n \n Example:\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n return [max(numbers[:i+1]) for i in range(len(numbers))]", "matching_cluster_idx": 2}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\"\n From a given list of integers, generate a list of rolling maximum element found until given moment in the sequence.\n\n Args:\n numbers: A list of integers\n\n Returns:\n A list of rolling maximum elements\n\n Example:\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n rolling_max_list = []\n max_num = float('-inf') # Initialize max_num as negative infinity\n\n for num in numbers:\n if num > max_num:\n max_num = num\n rolling_max_list.append(max_num)\n\n return rolling_max_list", "matching_cluster_idx": 8}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\"\n From a given list of integers, generate a list of rolling maximum element found until given moment \n in the sequence.\n\n Args:\n numbers: A list of integers.\n\n Returns:\n A list of rolling maximum elements.\n \"\"\"\n rolling_maxes = []\n max_so_far = float('-inf')\n for num in numbers:\n if num > max_so_far:\n max_so_far = num\n rolling_maxes.append(max_so_far)\n return rolling_maxes", "matching_cluster_idx": 8}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\"\n From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n\n Args:\n numbers: A list of integers.\n\n Returns:\n A list of rolling maximum element found until given moment in the sequence.\n\n Example:\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n rolling_max_list = []\n max_element = float('-inf') # Initialize max_element to negative infinity\n\n for num in numbers:\n if num > max_element:\n max_element = num\n rolling_max_list.append(max_element)\n\n return rolling_max_list", "matching_cluster_idx": 8}]}, "HumanEval/0": {"dps": 50.2906976744186, "dps_norm": 59.285714285714285, "pass@1": 74.0, "profiled": [{"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\"\n Check if in given list of numbers, are any two numbers closer to each other than given threshold.\n\n Args:\n numbers (List[float]): A list of floating-point numbers.\n threshold (float): The minimum distance between two numbers for them to be considered 'not close'.\n\n Returns:\n bool: True if any two numbers are closer than the threshold, False otherwise.\n \"\"\"\n # Sort the list in ascending order\n sorted_numbers = sorted(numbers)\n\n # Iterate over the sorted list with a window of size 2\n for i in range(len(sorted_numbers) - 1):\n # Check if the distance between the current element and the next one is less than the threshold\n if sorted_numbers[i + 1] - sorted_numbers[i] < threshold:\n return True\n\n # If no two close elements were found after iterating over the entire list, return False\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\"\n Check if in given list of numbers, are any two numbers closer to each other than given threshold.\n\n Args:\n numbers (List[float]): A list of numbers.\n threshold (float): The minimum distance two numbers can be to be considered close.\n\n Returns:\n bool: True if any two numbers are closer than threshold, False otherwise.\n \"\"\"\n # First, sort the list of numbers in ascending order\n numbers.sort()\n\n # Iterate over the sorted list and check if any adjacent numbers are closer than the threshold\n for i in range(len(numbers) - 1):\n if abs(numbers[i + 1] - numbers[i]) < threshold:\n return True # If a pair is found, immediately return True\n\n # If no such pair is found after iterating over the entire list, return False\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\"\n Check if in given list of numbers, are any two numbers closer to each other than given threshold.\n \n Args:\n numbers (List[float]): A list of floating-point numbers.\n threshold (float): The minimum distance between two numbers for them to be considered close.\n\n Returns:\n bool: True if there are two numbers in the list closer than the given threshold, False otherwise.\n \"\"\"\n # Sort the list of numbers\n numbers.sort()\n\n # Iterate over the list of numbers\n for i in range(1, len(numbers)):\n # If the difference between the current number and the previous number is less than the threshold, return True\n if numbers[i] - numbers[i - 1] < threshold:\n return True\n\n # If no pair of numbers closer than the threshold is found, return False\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\nimport itertools\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than given threshold.\n Args:\n numbers: List of float numbers.\n threshold: The minimum distance between two numbers to be considered 'close'.\n\n Returns:\n True if any two numbers are closer than the given threshold, False otherwise.\n \"\"\"\n # Generate all pairs of numbers from the list\n pairs = list(itertools.combinations(numbers, 2))\n \n # Check if any pair of numbers are closer than the threshold\n for pair in pairs:\n if abs(pair[0] - pair[1]) < threshold:\n return True\n \n # If no pair is closer than the threshold, return False\n return False", "matching_cluster_idx": -1}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\"\n Check if in given list of numbers, are any two numbers closer to each other than given threshold.\n\n Args:\n numbers: A list of float numbers.\n threshold: A float value.\n\n Returns:\n bool: Whether any two numbers in the list are closer than the threshold.\n \"\"\"\n # Sort the numbers in ascending order\n sorted_numbers = sorted(numbers)\n \n # Iterate over the sorted numbers\n for i in range(1, len(sorted_numbers)):\n # Check if the difference between the current and previous number is smaller than the threshold\n if sorted_numbers[i] - sorted_numbers[i - 1] < threshold:\n return True\n \n # If no pair is found, return False\n return False", "matching_cluster_idx": 2}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\"\n Check if in given list of numbers, are any two numbers closer to each other than given threshold.\n\n Args:\n numbers (List[float]): A list of floating point numbers.\n threshold (float): The minimum distance between two numbers to be considered close.\n\n Returns:\n bool: True if two numbers are closer than the threshold, False otherwise.\n \"\"\"\n # Sort the list to make it easier to compare adjacent numbers\n numbers.sort()\n for i in range(1, len(numbers)):\n # Check if the difference between current and previous number is less than the threshold\n if numbers[i] - numbers[i-1] < threshold:\n return True\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\"\n Check if in given list of numbers, are any two numbers closer to each other than given threshold.\n\n Args:\n numbers (List[float]): A list of floating point numbers.\n threshold (float): A threshold value.\n\n Returns:\n bool: True if any two numbers in the list are closer than the threshold, False otherwise.\n \"\"\"\n numbers.sort() # Sorting the list in ascending order for easier comparison\n for i in range(1, len(numbers)):\n if numbers[i] - numbers[i - 1] < threshold:\n return True\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\"\n Check if in given list of numbers, are any two numbers closer to each other than given threshold.\n\n Args:\n numbers (List[float]): A list of floating point numbers.\n threshold (float): The minimum distance two numbers must be from each other to be considered \"not close\".\n\n Returns:\n bool: True if any two numbers are closer than the threshold, False otherwise.\n \"\"\"\n # Sort the list of numbers\n sorted_numbers = sorted(numbers)\n \n # Iterate over the sorted list, checking each pair of adjacent elements\n for i in range(len(sorted_numbers) - 1):\n # If the difference between two adjacent elements is less than the threshold, return True\n if sorted_numbers[i + 1] - sorted_numbers[i] < threshold:\n return True\n \n # If no adjacent pairs were found to be less than the threshold apart, return False\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\"\n Check if in given list of numbers, are any two numbers closer to each other than given threshold.\n\n Args:\n numbers (List[float]): List of floating point numbers\n threshold (float): Minimum distance between numbers to be considered \"close\"\n\n Returns:\n bool: Whether any two numbers are closer than threshold\n \"\"\"\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n if abs(numbers[i] - numbers[j]) < threshold:\n return True\n return False", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n # Sort the list of numbers\n sorted_numbers = sorted(numbers)\n \n # Iterate over the list to check for close elements\n for i in range(1, len(sorted_numbers)):\n # Check if the difference between current number and previous number is less than the threshold\n if sorted_numbers[i] - sorted_numbers[i - 1] < threshold:\n return True\n \n # If no close elements are found, return False\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\"\n Check if in given list of numbers, are any two numbers closer to each other than given threshold.\n\n Args:\n numbers (List[float]): List of numbers to check.\n threshold (float): The minimum distance between two numbers for them to be considered 'not close'.\n\n Returns:\n bool: True if at least two numbers in the list are closer than the threshold, False otherwise.\n \"\"\"\n # Iterate through each number in the list\n for i in range(len(numbers)):\n # Compare the current number with the remaining numbers\n for j in range(i + 1, len(numbers)):\n # Check if the difference between the two numbers is less than the threshold\n if abs(numbers[i] - numbers[j]) < threshold:\n return True # If so, return True immediately\n return False # If no such pair found, return False", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\"\n Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n\n Args:\n numbers (List[float]): List of float numbers to check.\n threshold (float): Minimum distance between two numbers to be considered as close.\n\n Returns:\n bool: True if two numbers in the list are closer than threshold, False otherwise.\n \"\"\"\n # Sort the list of numbers in ascending order\n numbers.sort()\n\n # Iterate over the list, comparing each pair of adjacent numbers\n for i in range(len(numbers) - 1):\n # If difference between two adjacent numbers is less than threshold, return True\n if numbers[i + 1] - numbers[i] < threshold:\n return True\n\n # If no adjacent pair with difference less than threshold is found, return False\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\nimport itertools\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\"\n Check if in given list of numbers, are any two numbers closer to each other than given threshold.\n\n Args:\n numbers: A list of float numbers.\n threshold: The minimum distance required between any two numbers.\n\n Returns:\n bool: True if there are two numbers in the list that are closer than the threshold, False otherwise.\n \"\"\"\n # Use the combinations function from the itertools module to generate all pairs of numbers\n pairs = itertools.combinations(numbers, 2)\n # Iterate over each pair of numbers\n for pair in pairs:\n # Check if the difference between the pair is less than the threshold\n if abs(pair[0] - pair[1]) < threshold:\n return True\n return False", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\"\n Check if in given list of numbers, are any two numbers closer to each other than given threshold.\n\n Args:\n numbers: A list of floats.\n threshold: The minimum distance between two numbers to be considered close.\n\n Returns:\n bool: True if there are two numbers closer than the threshold, False otherwise.\n \"\"\"\n if len(numbers) < 2:\n # If there are less than two elements, no two elements can be close to each other.\n return False\n \n numbers.sort() # Sort the list in ascending order\n for i in range(1, len(numbers)):\n # Compare each element with its predecessor.\n if abs(numbers[i] - numbers[i-1]) < threshold:\n # If the difference is less than the threshold, two elements are close.\n return True\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\"\n Check if in given list of numbers, are any two numbers closer to each other than given threshold.\n\n Args:\n numbers (List[float]): The list of numbers to check.\n threshold (float): The minimum distance required between two numbers.\n\n Returns:\n bool: True if any two numbers are closer than threshold, False otherwise.\n \"\"\"\n # If the list has less than two elements, there are no pairs, so return False\n if len(numbers) < 2:\n return False\n\n # Sort the list in ascending order\n numbers.sort()\n\n # Iterate over the sorted list and check if any two adjacent numbers are closer than threshold\n for i in range(1, len(numbers)):\n if numbers[i] - numbers[i-1] < threshold:\n return True\n\n # If no pair of adjacent numbers are closer than threshold, return False\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\"\n Check if in given list of numbers, are any two numbers closer to each other than given threshold.\n\n Args:\n numbers: A list of floating point numbers\n threshold: The minimum distance between two numbers to be considered close\n\n Returns:\n True if any two numbers are closer than threshold, False otherwise\n \"\"\"\n # Sort the list of numbers\n sorted_numbers = sorted(numbers)\n \n # Iterate over the sorted list and check for close elements\n for i in range(len(sorted_numbers) - 1):\n if sorted_numbers[i+1] - sorted_numbers[i] < threshold:\n return True\n \n # If no close elements found, return False\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\"\n Check if in given list of numbers, are any two numbers closer to each other than given threshold.\n\n Args:\n numbers: A list of floating point numbers.\n threshold: The minimum difference between two numbers to be considered as 'close'.\n\n Returns:\n A boolean indicating whether any two numbers in the list are closer than the given threshold.\n \"\"\"\n if len(numbers) <= 1: # List with 1 or less elements has no two elements to compare.\n return False\n\n sorted_numbers = sorted(numbers) # Sort the numbers to make comparison easier.\n for i in range(len(sorted_numbers) - 1): # Compare each pair of adjacent numbers.\n if sorted_numbers[i + 1] - sorted_numbers[i] < threshold: # Check if the difference is less than the threshold.\n return True # If the difference is less than the threshold, return True.\n return False # If no pair of adjacent numbers is closer than the threshold, return False.", "matching_cluster_idx": 2}, {"solution": "from typing import List\nimport itertools\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\"Check if in given list of numbers, are any two numbers closer to each other than given threshold.\n\n Args:\n numbers (List[float]): List of float numbers\n threshold (float): The minimum distance between two numbers\n\n Returns:\n bool: True if any two numbers are closer than the given threshold, False otherwise\n \"\"\"\n # Use itertools.combinations to generate all pairs of numbers in the list\n pairs = itertools.combinations(numbers, 2)\n \n # Iterate over all pairs of numbers\n for pair in pairs:\n # If the distance between the pair is less than the threshold, return True\n if abs(pair[0] - pair[1]) < threshold:\n return True\n \n # If no pair with a distance less than the threshold is found, return False\n return False", "matching_cluster_idx": 4}, {"solution": "from typing import List\nimport itertools\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than given threshold.\n\n Args:\n numbers: List of numbers to check.\n threshold: Threshold value.\n\n Returns:\n True if two numbers are closer than threshold, False otherwise.\n \"\"\"\n # Generate all possible pairs of numbers\n pairs = itertools.combinations(numbers, 2)\n \n # Check each pair to see if the difference between them is less than the threshold\n for pair in pairs:\n if abs(pair[0] - pair[1]) < threshold:\n return True\n \n return False", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\"\n Check if in given list of numbers, are any two numbers closer to each other than given threshold.\n \n Args:\n numbers (List[float]): List of numbers to check for close elements.\n threshold (float): The minimum distance between two numbers to be considered \"close\".\n \n Returns:\n bool: True if any two numbers are closer than the given threshold, False otherwise.\n \"\"\"\n \n # Sort the list of numbers in ascending order\n numbers.sort()\n \n # Iterate over the sorted list, checking each pair of adjacent elements\n for i in range(len(numbers) - 1):\n # Check if the difference between adjacent elements is less than the threshold\n if numbers[i + 1] - numbers[i] < threshold:\n return True\n \n # If no close pairs were found, return False\n return False", "matching_cluster_idx": 3}]}, "HumanEval/4": {"dps": 61.4873417721519, "dps_norm": 70.0, "pass@1": 95.0, "profiled": [{"solution": "from typing import List\nimport statistics\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\"\n For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n\n Args:\n numbers (List[float]): A list of floating point numbers.\n\n Returns:\n float: The Mean Absolute Deviation of the input list.\n \"\"\"\n # Calculate the mean of the list\n mean = statistics.mean(numbers)\n # Calculate the absolute deviations from the mean\n deviations = [abs(num - mean) for num in numbers]\n # Calculate the mean of the absolute deviations\n mad = statistics.mean(deviations)\n return mad", "matching_cluster_idx": 0}, {"solution": "from typing import List\nimport statistics\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\"For a given list of input numbers, calculate Mean Absolute Deviation \n around the mean of this dataset.\n\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n\n Args:\n numbers (List[float]): A list of float numbers.\n\n Returns:\n float: Mean Absolute Deviation\n \"\"\"\n # Check if input is a list\n if not isinstance(numbers, list):\n raise TypeError(\"Input must be a list.\")\n\n # Check if list is not empty\n if len(numbers) == 0:\n raise ValueError(\"Input list must not be empty.\")\n\n # Check if all elements in the list are numbers\n if not all(isinstance(num, (int, float)) for num in numbers):\n raise TypeError(\"All elements in the list must be numbers.\")\n\n # Calculate mean\n mean = statistics.mean(numbers)\n\n # Calculate mean absolute deviation\n mad = statistics.mean([abs(num - mean) for num in numbers])\n\n return mad", "matching_cluster_idx": 0}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\"\n For a given list of input numbers, calculate Mean Absolute Deviation \n around the mean of this dataset.\n\n Mean Absolute Deviation is the average absolute difference between each \n element and a centerpoint (mean in this case):\n\n MAD = average | x - x_mean |\n\n Args:\n numbers (List[float]): A list of numbers.\n\n Returns:\n float: Mean Absolute Deviation.\n\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n\n # Check if input list is empty\n if len(numbers) == 0:\n raise ValueError(\"Input list cannot be empty.\")\n\n # Calculate the mean\n mean = sum(numbers) / len(numbers)\n\n # Calculate the absolute deviations\n absolute_deviations = [abs(num - mean) for num in numbers]\n\n # Calculate the mean of the absolute deviations\n mad = sum(absolute_deviations) / len(absolute_deviations)\n\n return mad\nnumbers = [1.0, 2.0, 3.0, 4.0]", "matching_cluster_idx": 4}, {"solution": "from typing import List\nimport statistics\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\"\n For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n\n Args:\n numbers: A list of numbers\n\n Returns:\n The Mean Absolute Deviation\n \"\"\"\n # Calculate the mean of the dataset\n mean = statistics.mean(numbers)\n \n # Calculate the absolute differences between each number and the mean\n abs_diffs = [abs(num - mean) for num in numbers]\n \n # Calculate the Mean Absolute Deviation\n mad = statistics.mean(abs_diffs)\n \n return mad\nnumbers = [1.0, 2.0, 3.0, 4.0]", "matching_cluster_idx": 0}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\"\n For a given list of input numbers, calculate Mean Absolute Deviation around the mean of this dataset.\n\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n\n Args:\n numbers (List[float]): List of float numbers\n\n Returns:\n float: The Mean Absolute Deviation of the input list\n \"\"\"\n mean = sum(numbers) / len(numbers)\n return sum(abs(num - mean) for num in numbers) / len(numbers)\nnumbers = [1.0, 2.0, 3.0, 4.0]", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\"\n For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n\n Parameters:\n numbers (List[float]): A list of numbers.\n\n Returns:\n float: The Mean Absolute Deviation.\n \"\"\"\n\n # Check if input list is empty\n if not numbers:\n raise ValueError(\"Input list cannot be empty.\")\n\n # Calculate the mean of the numbers\n mean = sum(numbers) / len(numbers)\n\n # Calculate the absolute deviations from the mean\n deviations = [abs(num - mean) for num in numbers]\n\n # Calculate the Mean Absolute Deviation\n mad = sum(deviations) / len(deviations)\n\n return mad\nnumbers = [1.0, 2.0, 3.0, 4.0]", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\"\n For a given list of input numbers, calculate Mean Absolute Deviation around the mean of this dataset.\n\n Mean Absolute Deviation is the average absolute difference between each element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n\n Args:\n numbers (List[float]): A list of numbers.\n\n Returns:\n float: Mean Absolute Deviation of the input list.\n\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n # Calculate the mean of the input numbers\n mean = sum(numbers) / len(numbers)\n\n # Calculate the absolute deviations from the mean\n absolute_deviations = [abs(num - mean) for num in numbers]\n\n # Calculate the mean of the absolute deviations\n mad = sum(absolute_deviations) / len(absolute_deviations)\n\n return mad", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\"\n Calculate the Mean Absolute Deviation around the mean of a dataset.\n\n Mean Absolute Deviation is the average absolute difference between each element\n and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n\n Args:\n numbers: A list of float numbers.\n\n Returns:\n Mean Absolute Deviation of the input dataset.\n \"\"\"\n # Check if the input list is not empty\n if not numbers:\n raise ValueError(\"Input list is empty\")\n\n # Calculate the mean of the dataset\n mean = sum(numbers) / len(numbers)\n\n # Calculate the absolute deviations from the mean\n deviations = [abs(num - mean) for num in numbers]\n\n # Calculate the mean of the absolute deviations\n mad = sum(deviations) / len(deviations)\n\n return mad\nnumbers = [1.0, 2.0, 3.0, 4.0]", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\"\n Calculate Mean Absolute Deviation of a list of numbers.\n \n Mean Absolute Deviation is the average absolute difference between each\n element and the mean of this dataset.\n\n Args:\n numbers (List[float]): A list of floating point numbers.\n\n Returns:\n float: Mean Absolute Deviation.\n\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n\n # Calculate the mean of the list of numbers\n mean = sum(numbers) / len(numbers)\n\n # Calculate the absolute deviation of each number from the mean\n deviations = [abs(num - mean) for num in numbers]\n\n # Calculate the mean of the deviations (MAD)\n mad = sum(deviations) / len(deviations)\n\n return mad", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\"\n Calculate the Mean Absolute Deviation (MAD) of a dataset.\n \n Mean Absolute Deviation is the average absolute difference between each element \n and the mean of the dataset.\n\n Args:\n numbers (List[float]): A list of numbers.\n\n Returns:\n float: The Mean Absolute Deviation.\n\n Example:\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n\n # Calculate the mean\n mean = sum(numbers) / len(numbers)\n\n # Calculate absolute differences from the mean\n absolute_diffs = [abs(num - mean) for num in numbers]\n\n # Calculate the mean of the absolute differences\n mad = sum(absolute_diffs) / len(absolute_diffs)\n\n return mad\nnumbers = [1.0, 2.0, 3.0, 4.0]", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\"\n For a given list of input numbers, calculate Mean Absolute Deviation around the mean of this dataset.\n \n Mean Absolute Deviation is the average absolute difference between each element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n \n Args:\n numbers (List[float]): A list of floating point numbers.\n \n Returns:\n float: The mean absolute deviation of the given numbers.\n \"\"\"\n # Calculate the mean of the input list\n mean = sum(numbers) / len(numbers)\n \n # Calculate absolute differences between each element and the mean\n absolute_diffs = [abs(num - mean) for num in numbers]\n \n # Calculate the mean of the absolute differences (Mean Absolute Deviation)\n mad = sum(absolute_diffs) / len(absolute_diffs)\n \n return mad", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation \n around the mean of this dataset.\n \n Mean Absolute Deviation is the average absolute difference between each \n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n\n Args:\n numbers (List[float]): A list of float numbers.\n\n Returns:\n float: The mean absolute deviation of the input list.\n\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n # Check if the input is a list\n if not isinstance(numbers, list):\n raise TypeError('Input must be a list of float numbers')\n\n # Check if the list is not empty\n if len(numbers) == 0:\n raise ValueError('Input list cannot be empty')\n\n # Check if all elements in the list are floats\n if not all(isinstance(x, (int, float)) for x in numbers):\n raise TypeError('All elements in the input list must be float numbers')\n\n # Calculate the mean\n mean = sum(numbers) / len(numbers)\n\n # Calculate the mean absolute deviation\n mad = sum(abs(x - mean) for x in numbers) / len(numbers)\n\n return mad", "matching_cluster_idx": 1}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\"\n Calculate Mean Absolute Deviation around the mean of a dataset.\n\n Mean Absolute Deviation is the average absolute difference between each\n element and the mean of this dataset.\n\n Args:\n numbers: A list of float numbers.\n\n Returns:\n The Mean Absolute Deviation of the input list.\n\n Examples:\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n # Calculate the mean of the dataset\n mean = sum(numbers) / len(numbers)\n \n # Calculate the absolute differences between each number and the mean\n absolute_diffs = [abs(num - mean) for num in numbers]\n \n # Calculate the average of the absolute differences\n mad = sum(absolute_diffs) / len(absolute_diffs)\n \n return mad", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\"\n For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n\n MAD = average | x - x_mean |\n\n Args:\n numbers (List[float]): A list of float numbers.\n\n Returns:\n float: The mean absolute deviation of the given list.\n\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n\n # Check if the input list is empty\n if not numbers:\n raise ValueError(\"Input list cannot be empty\")\n\n # Calculate the mean of the numbers\n mean = sum(numbers) / len(numbers)\n\n # Calculate the absolute deviations from the mean\n absolute_deviations = [abs(num - mean) for num in numbers]\n\n # Calculate the mean of the absolute deviations\n mad = sum(absolute_deviations) / len(absolute_deviations)\n\n return mad\nnumbers = [1.0, 2.0, 3.0, 4.0]", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\"\n For a given list of input numbers, calculate Mean Absolute Deviation around the mean of this dataset.\n\n Mean Absolute Deviation is the average absolute difference between each element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n\n Args:\n numbers (List[float]): List of numbers for which to calculate the mean absolute deviation.\n\n Returns:\n float: The mean absolute deviation of the input list of numbers.\n \"\"\"\n mean = sum(numbers) / len(numbers) # Calculate the mean of the list\n return sum(abs(num - mean) for num in numbers) / len(numbers) # Calculate the mean absolute deviation\nnumbers = [1.0, 2.0, 3.0, 4.0]", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\"\n For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n \n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n \n Args:\n numbers (List[float]): A list of numbers\n\n Returns:\n float: The mean absolute deviation\n\n Example:\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n\n # Calculate the mean of the input list\n mean = sum(numbers) / len(numbers)\n\n # Calculate the absolute differences between each number and the mean\n absolute_diffs = [abs(num - mean) for num in numbers]\n\n # Calculate the mean of the absolute differences (MAD)\n mad = sum(absolute_diffs) / len(absolute_diffs)\n\n return mad\nnumbers = [1.0, 2.0, 3.0, 4.0]", "matching_cluster_idx": 4}, {"solution": "from typing import List\nimport statistics\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\"\n For a given list of input numbers, calculate Mean Absolute Deviation around the mean of this dataset.\n \n Mean Absolute Deviation is the average absolute difference between each element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n\n Args:\n numbers (List[float]): A list of numbers to calculate Mean Absolute Deviation for.\n\n Returns:\n float: Mean Absolute Deviation of the input list.\n\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n # Check if input list is empty\n if not numbers:\n raise ValueError(\"Input list cannot be empty\")\n\n # Calculate the mean of the numbers\n mean = statistics.mean(numbers)\n\n # Calculate the absolute deviations from the mean\n deviations = [abs(num - mean) for num in numbers]\n\n # Calculate the mean of the deviations\n mad = statistics.mean(deviations)\n\n return mad", "matching_cluster_idx": 0}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\"\n For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n\n Args:\n numbers (List[float]): A list of float numbers\n\n Returns:\n float: The mean absolute deviation of the given list\n \"\"\"\n # Calculate the mean of the list\n mean = sum(numbers) / len(numbers)\n \n # Calculate the absolute differences between each number and the mean\n absolute_diffs = [abs(num - mean) for num in numbers]\n \n # Calculate the mean of these absolute differences\n mean_abs_dev = sum(absolute_diffs) / len(absolute_diffs)\n \n return mean_abs_dev", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\"\n For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n \"\"\"\n \n # Calculate the mean of the given list of numbers\n mean = sum(numbers) / len(numbers)\n \n # Calculate the absolute differences between each element and the mean\n absolute_diffs = [abs(num - mean) for num in numbers]\n \n # Calculate the mean of the absolute differences (Mean Absolute Deviation)\n mad = sum(absolute_diffs) / len(numbers)\n \n return mad\nnumbers = [1.0, 2.0, 3.0, 4.0]", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\"\n For a given list of input numbers, calculate Mean Absolute Deviation around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n\n Args:\n numbers (List[float]): A list of float numbers.\n\n Returns:\n float: Mean Absolute Deviation.\n \"\"\"\n\n # Calculate the mean of the input numbers\n mean = sum(numbers) / len(numbers)\n\n # Initialize sum of absolute deviations\n sum_abs_deviation = 0\n\n # Calculate the absolute deviation of each number from the mean\n for num in numbers:\n sum_abs_deviation += abs(num - mean)\n\n # Calculate Mean Absolute Deviation\n mad = sum_abs_deviation / len(numbers)\n\n return mad", "matching_cluster_idx": 5}]}, "HumanEval/16": {"dps": 95.81395348837209, "dps_norm": 96.66666666666667, "pass@1": 94.0, "profiled": [{"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\"\n Given a string, find out how many distinct characters (regardless of case) does it consist of\n\n Args:\n string (str): Input string.\n\n Returns:\n int: Number of distinct characters in the string.\n\n Examples:\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lower case to ignore case sensitivity\n string = string.lower()\n \n # Use a set to remove duplicates and count distinct characters\n distinct_chars = set(string)\n \n # Return the number of distinct characters\n return len(distinct_chars)", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\"\n Given a string, find out how many distinct characters (regardless of case) it consists of.\n \n Parameters:\n string (str): The input string\n \n Returns:\n int: The number of distinct characters in the string\n \n Example:\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lower case to ignore case sensitivity\n lower_case_string = string.lower()\n \n # Use a set to store unique characters\n unique_chars = set(lower_case_string)\n \n # Return the number of unique characters\n return len(unique_chars)", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) it consists of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lower case to ignore case sensitivity\n lower_case_string = string.lower()\n \n # Convert the string to a set (which automatically removes duplicates) and get its length\n distinct_characters = len(set(lower_case_string))\n \n return distinct_characters", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\"\n Given a string, find out how many distinct characters (regardless of case) does it consist of\n Args:\n string (str): The input string\n\n Returns:\n int: The number of distinct characters\n \"\"\"\n # Convert the string to lowercase to ignore case sensitivity\n lower_string = string.lower()\n \n # Use a set to store unique characters\n unique_chars = set(lower_string)\n \n # Return the number of unique characters\n return len(unique_chars)", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\"\n Given a string, find out how many distinct characters (regardless of case) does it consist of\n \n Args:\n string (str): The input string\n \n Returns:\n int: The number of distinct characters in the string\n \n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lower case to handle case insensitivity\n lower_case_string = string.lower()\n \n # Convert the string to a set to remove duplicates\n distinct_characters = set(lower_case_string)\n \n # Return the number of distinct characters\n return len(distinct_characters)", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\"\n Given a string, find out how many distinct characters (regardless of case) does it consist of.\n\n Args:\n string (str): The input string to process.\n\n Returns:\n int: The number of distinct characters in the string.\n\n Examples:\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lowercase to ignore case sensitivity\n string = string.lower()\n \n # Use a set to store unique characters (sets in Python are unordered collections of unique elements)\n unique_chars = set()\n \n # Iterate over each character in the string\n for char in string:\n # Add each character to the set\n unique_chars.add(char)\n \n # Return the number of unique characters (which is the size of the set)\n return len(unique_chars)", "matching_cluster_idx": 2}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" \n Given a string, find out how many distinct characters (regardless of case) does it consist of\n \n Args:\n string (str): The input string.\n \n Returns:\n int: Number of distinct characters.\n \"\"\"\n \n # Convert the string to lowercase to handle case insensitivity\n lower_case_string = string.lower()\n \n # Use a set to store unique characters. Sets in Python are unordered collections of unique elements.\n unique_chars = set(lower_case_string)\n \n # Return the number of distinct characters\n return len(unique_chars)", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\"\n Given a string, find out how many distinct characters (regardless of case) does it consist of\n\n Args:\n string (str): The input string to be analyzed\n\n Returns:\n int: The number of distinct characters in the string\n \"\"\"\n # Convert the string to lowercase to ignore case sensitivity\n lowercase_string = string.lower()\n \n # Use a set to remove duplicates and count the number of distinct characters\n distinct_chars = set(lowercase_string)\n \n # Return the number of distinct characters\n return len(distinct_chars)", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\"\n Given a string, find out how many distinct characters (regardless of case) it consists of.\n\n Args:\n string (str): The input string.\n\n Returns:\n int: The number of distinct characters in the string.\n\n Examples:\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lower case to ignore case sensitivity\n lower_case_string = string.lower()\n \n # Use a set to count unique characters\n distinct_characters = set(lower_case_string)\n \n # Return the number of distinct characters\n return len(distinct_characters)", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\"\n Given a string, find out how many distinct characters (regardless of case) does it consist of\n\n Args:\n string (str): The input string\n\n Returns:\n int: The number of distinct characters\n\n Examples:\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lowercase to ignore case sensitivity\n lower_case_string = string.lower()\n \n # Use a set to store unique characters\n unique_chars = set(lower_case_string)\n \n # The number of distinct characters is the size of the set\n return len(unique_chars)", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\"\n Given a string, find out how many distinct characters (regardless of case) does it consist of\n Args:\n string (str): The input string\n\n Returns:\n int: The count of distinct characters in the string\n \"\"\"\n # Convert the string to lowercase to ignore case sensitivity\n lower_case_string = string.lower()\n \n # Convert the string to a set, which removes duplicates and returns a collection of unique elements\n distinct_characters = set(lower_case_string)\n \n # Return the count of distinct characters\n return len(distinct_characters)", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\"\n Given a string, find out how many distinct characters (regardless of case) does it consist of\n\n Args:\n string (str): The input string\n\n Returns:\n int: Number of distinct characters\n\n Examples:\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lower case to make the comparison case-insensitive\n # Use set to remove duplicate characters\n distinct_chars = set(string.lower())\n # Return the number of distinct characters\n return len(distinct_chars)", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\"\n Given a string, find out how many distinct characters (regardless of case) does it consist of\n\n Args:\n string (str): Input string\n\n Returns:\n int: Number of distinct characters in the input string\n \"\"\"\n # Convert the input string to lower case and store unique characters in a set\n unique_chars = set(string.lower())\n \n # Return the number of unique characters\n return len(unique_chars)", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\"\n Given a string, find out how many distinct characters (regardless of case) does it consist of\n \n Args:\n string (str): The input string\n \n Returns:\n int: The number of distinct characters in the string\n \n Examples:\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lowercase to ignore case\n lower_case_string = string.lower()\n \n # Create a set from the string, which automatically removes duplicates\n distinct_chars = set(lower_case_string)\n \n # Return the number of distinct characters\n return len(distinct_chars)", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\"Given a string, find out how many distinct characters (regardless of case) does it consist of\n\n Args:\n string (str): Input string.\n\n Returns:\n int: Number of distinct characters.\n\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lowercase to treat 'a' and 'A' as the same character\n lowercase_string = string.lower()\n \n # Use a set to store unique characters\n unique_characters = set(lowercase_string)\n \n # The number of unique characters is the size of the set\n return len(unique_characters)", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\"Given a string, find out how many distinct characters (regardless of case) does it consist of\n\n Args:\n string (str): Input string\n\n Returns:\n int: Number of distinct characters in the string\n\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lowercase to ignore case sensitivity\n string = string.lower()\n # Convert the string into a set to remove duplicates\n distinct_chars = set(string)\n # Return the number of distinct characters\n return len(distinct_chars)", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\"\n Given a string, find out how many distinct characters (regardless of case) does it consist of\n \n Parameters:\n string (str): The input string to count distinct characters from\n \n Returns:\n int: Number of distinct characters in the input string\n \"\"\"\n # Convert the string to lower case to ignore case sensitivity\n lower_string = string.lower()\n # Use set to eliminate duplicate characters and count the number of distinct characters\n distinct_chars = len(set(lower_string))\n \n return distinct_chars", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\"\n Given a string, find out how many distinct characters (regardless of case) it consists of.\n\n Args:\n string (str): The input string\n\n Returns:\n int: The number of distinct characters in the string\n \"\"\"\n # Convert the string to lowercase to ignore case sensitivity\n lower_string = string.lower()\n \n # Use a set to store unique characters\n distinct_chars = set(lower_string)\n \n # Return the number of unique characters\n return len(distinct_chars)", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\"\n Given a string, find out how many distinct characters (regardless of case) does it consist of\n\n Args:\n string (str): Input string to count distinct characters from.\n\n Returns:\n int: Number of distinct characters.\n\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n return len(set(string.lower())) # Convert string to lower case and then get set to remove duplicates", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\"\n Given a string, find out how many distinct characters (regardless of case) does it consist of\n \n Args:\n string (str): The input string.\n \n Returns:\n int: The number of distinct characters in the string.\n \"\"\"\n # Convert the string to lower case to ignore case sensitivity\n lower_case_string = string.lower()\n \n # Convert the string into a set which will automatically remove duplicates\n # and then get the size of the set which will give us the count of distinct characters\n distinct_characters = len(set(lower_case_string))\n \n return distinct_characters", "matching_cluster_idx": 8}]}, "HumanEval/20": {"dps": 95.0, "dps_norm": 95.0, "pass@1": 74.0, "profiled": [{"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\"\n From a supplied list of numbers (of length at least two) select and return two that are the closest to each other\n and return them in order (smaller number, larger number).\n\n Args:\n numbers (List[float]): A list of numbers\n\n Returns:\n Tuple[float, float]: A tuple containing the two closest numbers in the list.\n \"\"\"\n \n # First, we sort the list of numbers in ascending order\n numbers.sort()\n\n # Initialize the minimum difference and the closest pair of numbers\n min_diff = float('inf') # Initialize with positive infinity\n closest_pair = ()\n\n # Iterate over the sorted list to find the closest pair of numbers\n for i in range(len(numbers) - 1):\n # Calculate the difference between the current number and the next one\n diff = numbers[i+1] - numbers[i]\n \n # If the current difference is less than the minimum difference found so far, update the minimum difference and the closest pair\n if diff < min_diff:\n min_diff = diff\n closest_pair = (numbers[i], numbers[i+1])\n\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\"\n From a supplied list of numbers (of length at least two) select and return two that are the closest to each other\n and return them in order (smaller number, larger number).\n\n Args:\n numbers (List[float]): A list of floats\n\n Returns:\n Tuple[float, float]: A tuple containing the two closest numbers in the list\n\n Raises:\n ValueError: If the list contains less than two elements\n \"\"\"\n if len(numbers) < 2:\n raise ValueError(\"The list must contain at least two elements\")\n\n # First, sort the list of numbers\n sorted_numbers = sorted(numbers)\n\n # Initialize the minimum difference and the pair of closest numbers\n min_diff = float('inf')\n closest_pair = (None, None)\n\n # Iterate over the sorted list to find the pair with the minimum difference\n for i in range(len(sorted_numbers) - 1):\n diff = sorted_numbers[i + 1] - sorted_numbers[i]\n if diff < min_diff:\n min_diff = diff\n closest_pair = (sorted_numbers[i], sorted_numbers[i + 1])\n\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\"\n From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n \n Args:\n numbers (List[float]): A list of at least two floats.\n\n Returns:\n Tuple[float, float]: A tuple of two numbers from the list that are the closest to each other.\n \"\"\"\n\n # Check if the list has less than two elements\n if len(numbers) < 2:\n raise ValueError(\"The list must contain at least two numbers\")\n\n # First, we sort the list in ascending order\n sorted_numbers = sorted(numbers)\n\n # Initialize the minimum difference and the closest pair\n min_diff = float('inf') # Initialize with positive infinity\n closest_pair = (None, None)\n\n # Iterate over the sorted list to find the pair with the smallest difference\n for i in range(len(sorted_numbers) - 1):\n diff = sorted_numbers[i + 1] - sorted_numbers[i]\n if diff < min_diff:\n min_diff = diff\n closest_pair = (sorted_numbers[i], sorted_numbers[i + 1])\n\n # If two numbers are the same, return a tuple with the same number\n if closest_pair[0] == closest_pair[1]:\n return closest_pair\n\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\"\n Finds and returns two numbers from a list that are the closest to each other.\n\n Args:\n numbers: A list of floating point numbers of length at least two.\n\n Returns:\n A tuple containing the two closest numbers in the list in ascending order.\n \"\"\"\n # Sort the list of numbers in ascending order\n sorted_numbers = sorted(numbers)\n \n # Initialize the minimum difference and the two closest numbers\n min_diff = float('inf')\n closest_numbers = (sorted_numbers[0], sorted_numbers[0])\n \n # Iterate over the sorted list to find the closest pair of numbers\n for i in range(len(sorted_numbers) - 1):\n # Calculate the difference between the current pair of numbers\n diff = sorted_numbers[i + 1] - sorted_numbers[i]\n \n # Update the minimum difference and the closest pair of numbers if a smaller difference is found\n if diff < min_diff:\n min_diff = diff\n closest_numbers = (sorted_numbers[i], sorted_numbers[i + 1])\n \n return closest_numbers", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\"\n From a supplied list of numbers (of length at least two) select and return two that are the closest to each other\n and return them in order (smaller number, larger number).\n \n Args:\n numbers: A list of floating-point numbers with length of at least two.\n \n Returns:\n A tuple of two numbers from the input list that are the closest to each other.\n \"\"\"\n # Sort the list of numbers in ascending order\n numbers.sort()\n \n # Initialize the minimum difference and the pair of closest numbers\n min_diff = float('inf') # Initialize with positive infinity\n closest_pair = (None, None)\n \n # Iterate through the sorted list of numbers to find the closest pair\n for i in range(len(numbers) - 1):\n # Calculate the difference between the current number and the next number\n diff = numbers[i+1] - numbers[i]\n \n # If the difference is smaller than the current minimum difference, update the minimum difference and the closest pair\n if diff < min_diff:\n min_diff = diff\n closest_pair = (numbers[i], numbers[i+1])\n \n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\"\n From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n\n Args:\n numbers (List[float]): A list of floating point numbers.\n\n Returns:\n Tuple[float, float]: A tuple of two closest numbers from the list.\n\n Raises:\n ValueError: If the input list has less than two elements.\n \"\"\"\n if len(numbers) < 2:\n raise ValueError(\"Input list must have at least two elements\")\n\n # Sort the list\n numbers.sort()\n\n # Initialize the minimum difference and the pair of numbers with the minimum difference\n min_diff = float('inf') # Initialize with positive infinity\n closest_pair = (numbers[0], numbers[0])\n\n # Iterate over the list to find the pair with the minimum difference\n for i in range(1, len(numbers)):\n diff = numbers[i] - numbers[i-1]\n if diff < min_diff:\n min_diff = diff\n closest_pair = (numbers[i-1], numbers[i])\n\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\"\n From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n\n Args:\n numbers (List[float]): A list of float numbers with a length of at least two.\n\n Returns:\n Tuple[float, float]: A tuple of two closest numbers in the list in ascending order.\n \"\"\"\n numbers.sort() # Sort the list in ascending order\n closest_pair_diff = float('inf') # Initialize the minimum difference with positive infinity\n closest_pair = () # Initialize the closest pair with an empty tuple\n\n for i in range(len(numbers) - 1):\n diff = numbers[i + 1] - numbers[i] # Calculate the difference between each pair of adjacent numbers\n if diff < closest_pair_diff: # Check if the current difference is smaller than the previous smallest difference\n closest_pair_diff = diff # Update the smallest difference\n closest_pair = (numbers[i], numbers[i + 1]) # Update the closest pair\n\n return closest_pair # Return the closest pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\"\n From a supplied list of numbers (of length at least two) select and return two that are the closest to each other\n and return them in order (smaller number, larger number).\n \n Args:\n numbers (List[float]): A list of floating point numbers with at least two elements.\n \n Returns:\n Tuple[float, float]: A tuple containing two numbers that are closest to each other in the supplied list.\n \n Raises:\n ValueError: If the input list has less than two elements.\n \"\"\"\n \n # Check if the list has at least two elements\n if len(numbers) < 2:\n raise ValueError(\"Input list must have at least two elements.\")\n \n # Sort the list in ascending order\n numbers.sort()\n \n # Initialize the minimum difference and the pair of closest numbers\n min_diff = float('inf')\n closest_pair = (numbers[0], numbers[0])\n \n # Iterate over the sorted list to find the pair with the minimum difference\n for i in range(len(numbers) - 1):\n diff = numbers[i + 1] - numbers[i]\n if diff < min_diff:\n min_diff = diff\n closest_pair = (numbers[i], numbers[i + 1])\n \n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\"\n From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n\n Args:\n numbers (List[float]): A list of floating point numbers.\n\n Returns:\n Tuple[float, float]: A tuple of two numbers that are closest to each other.\n\n Example:\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n\n # Sort the list in ascending order\n numbers.sort()\n\n # Initialize the minimum difference and the closest pair of numbers\n min_diff = float('inf') # Initialize with positive infinity\n closest_pair = (numbers[0], numbers[0])\n\n # Iterate over the list to find the closest pair of numbers\n for i in range(len(numbers) - 1):\n # Calculate the absolute difference between the current and the next number\n diff = abs(numbers[i] - numbers[i + 1])\n \n # If the difference is less than the current minimum difference, update the minimum difference and the closest pair\n if diff < min_diff:\n min_diff = diff\n closest_pair = (numbers[i], numbers[i + 1])\n\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\"\n From a supplied list of numbers (of length at least two) select and return two that are the closest to each \n other and return them in order (smaller number, larger number).\n\n Args:\n numbers (List[float]): A list of numbers.\n\n Returns:\n Tuple[float, float]: A tuple of the two numbers in the list that are the closest to each other.\n \"\"\"\n # Check if the list has at least two elements\n if len(numbers) < 2:\n raise ValueError(\"The list must have at least two elements\")\n\n # Initialize the minimum difference and the closest pair\n min_diff = float('inf')\n closest_pair = (numbers[0], numbers[0])\n\n # Sort the list\n numbers.sort()\n\n # Iterate over the list to find the closest pair\n for i in range(len(numbers) - 1):\n # Calculate the difference between the current and the next number\n diff = numbers[i + 1] - numbers[i]\n\n # If the difference is smaller than the current minimum difference, update the minimum difference and the closest pair\n if diff < min_diff:\n min_diff = diff\n closest_pair = (numbers[i], numbers[i + 1])\n\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\"\n From a supplied list of numbers (of length at least two) select and return two that are the closest to each other\n and return them in order (smaller number, larger number).\n\n Args:\n numbers (List[float]): A list of at least two numbers.\n\n Returns:\n Tuple[float, float]: A tuple of two numbers from the list that are the closest to each other.\n\n Example:\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n # Check if list has at least two elements\n if len(numbers) < 2:\n raise ValueError(\"List must have at least two elements\")\n\n # Sort the list in ascending order\n numbers.sort()\n\n # Initialize the minimum difference and closest pair\n min_diff = float('inf') # Initialize with positive infinity\n closest_pair = (numbers[0], numbers[0])\n\n # Iterate over the sorted list to find the closest pair\n for i in range(len(numbers) - 1):\n # Calculate the difference between the current pair\n diff = numbers[i + 1] - numbers[i]\n\n # If the difference is smaller than the current minimum difference, update the minimum difference and closest pair\n if diff < min_diff:\n min_diff = diff\n closest_pair = (numbers[i], numbers[i + 1])\n\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\"\n From a supplied list of numbers (of length at least two) select and return two that are the closest to each other\n and return them in order (smaller number, larger number).\n\n Args:\n numbers (List[float]): A list of float numbers.\n\n Returns:\n Tuple[float, float]: A tuple containing the two closest numbers in the list.\n \"\"\"\n if len(numbers) < 2:\n raise ValueError(\"The list must have at least two elements.\")\n\n # Sort the list in ascending order\n numbers.sort()\n\n # Initialize the minimum difference and the closest pair of numbers\n min_diff = float('inf') # Initialize with positive infinity\n closest_pair = (numbers[0], numbers[0])\n\n # Iterate over the list to find the closest pair\n for i in range(1, len(numbers)):\n diff = numbers[i] - numbers[i-1]\n if diff < min_diff:\n min_diff = diff\n closest_pair = (numbers[i-1], numbers[i])\n\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\"\n From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n\n Args:\n numbers: A list of floating point numbers of length at least 2.\n\n Returns:\n A tuple of two numbers that are the closest to each other.\n \"\"\"\n # First, sort the list of numbers\n sorted_numbers = sorted(numbers)\n \n # Initialize the minimum difference and the closest pair\n min_diff = float('inf') # Initialize with positive infinity\n closest_pair = (sorted_numbers[0], sorted_numbers[0])\n \n # Iterate over the sorted list to find the closest pair\n for i in range(len(sorted_numbers) - 1):\n diff = sorted_numbers[i + 1] - sorted_numbers[i]\n if diff < min_diff:\n min_diff = diff\n closest_pair = (sorted_numbers[i], sorted_numbers[i + 1])\n \n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\nimport itertools\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\"\n From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n\n Args:\n numbers (List[float]): A list of floating point numbers.\n\n Returns:\n Tuple[float, float]: A tuple containing the two closest numbers.\n \"\"\"\n # Generate all possible pairs of numbers\n pairs = list(itertools.combinations(numbers, 2))\n \n # Initialize the minimum difference and the pair with the minimum difference\n min_diff = float('inf')\n closest_pair = None\n \n # Iterate over all pairs\n for pair in pairs:\n # Calculate the absolute difference between the two numbers\n diff = abs(pair[0] - pair[1])\n \n # If the difference is smaller than the current minimum difference, update the minimum difference and the closest pair\n if diff < min_diff:\n min_diff = diff\n closest_pair = pair\n \n # Return the closest pair\n return tuple(sorted(closest_pair))", "matching_cluster_idx": -1}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\"\n Finds two closest numbers in the supplied list and returns them in order (smaller number, larger number).\n \n Args:\n numbers (List[float]): A list of floating point numbers with at least two elements.\n\n Returns:\n Tuple[float, float]: A tuple of two floating point numbers that are the closest to each other.\n \"\"\"\n \n # Sort the list of numbers\n sorted_numbers = sorted(numbers)\n \n # Initialize variables to store the minimum difference and the closest pair\n min_diff = float('inf')\n closest_pair = ()\n \n # Iterate over the sorted list to find the closest pair\n for i in range(len(sorted_numbers) - 1):\n # Calculate the difference between the current number and the next number\n diff = abs(sorted_numbers[i] - sorted_numbers[i+1])\n \n # If the current difference is less than the minimum difference found so far, update the minimum difference and the closest pair\n if diff < min_diff:\n min_diff = diff\n closest_pair = (sorted_numbers[i], sorted_numbers[i+1])\n \n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\"\n Find and return the two numbers from a list that are closest to each other.\n \n Args:\n numbers: A list of float numbers of length at least two.\n \n Returns:\n A tuple of two float numbers that are closest to each other in the list.\n \"\"\"\n \n # First, sort the list in ascending order\n numbers.sort()\n \n # Initialize the minimum difference and the pair of closest numbers\n min_diff = float('inf')\n closest_pair = (numbers[0], numbers[0])\n \n # Iterate over the sorted list to find the closest pair\n for i in range(len(numbers) - 1):\n # Calculate the difference between the current pair of numbers\n diff = numbers[i + 1] - numbers[i]\n \n # Update the minimum difference and the closest pair if a smaller difference is found\n if diff < min_diff:\n min_diff = diff\n closest_pair = (numbers[i], numbers[i + 1])\n \n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\"\n Find two numbers in a list that are the closest to each other.\n\n Args:\n numbers: A list of floats of length at least two.\n\n Returns:\n A tuple of two floats that are the closest to each other.\n\n Examples:\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n # Sort the list of numbers in ascending order\n numbers.sort()\n\n # Initialize the minimum difference and the pair of numbers with the minimum difference\n min_diff = float('inf') # Initialize with positive infinity\n closest_pair = (numbers[0], numbers[0])\n\n # Iterate through the sorted list to find the closest pair\n for i in range(len(numbers) - 1):\n diff = numbers[i + 1] - numbers[i]\n if diff < min_diff:\n min_diff = diff\n closest_pair = (numbers[i], numbers[i + 1])\n\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\"\n From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n\n Args:\n numbers: A list of at least two floats.\n\n Returns:\n A tuple of two floats, the two numbers closest to each other in the input list.\n \"\"\"\n # First, sort the list in ascending order\n numbers.sort()\n\n # Initialize minimum difference and the pair of numbers\n min_diff = float('inf')\n closest_pair = (numbers[0], numbers[0])\n\n # Iterate through the sorted list to find the pair with the smallest difference\n for i in range(len(numbers) - 1):\n # Calculate the absolute difference between the current number and the next one\n diff = abs(numbers[i] - numbers[i + 1])\n\n # If the difference is smaller than the current minimum, update the minimum difference and the pair\n if diff < min_diff:\n min_diff = diff\n closest_pair = (numbers[i], numbers[i + 1])\n\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\"\n From a supplied list of numbers (of length at least two) select and return two that are the closest to each other\n and return them in order (smaller number, larger number).\n \"\"\"\n if len(numbers) < 2:\n raise ValueError(\"Input list must contain at least two elements\")\n\n # Sort the list of numbers in ascending order\n numbers.sort()\n\n # Initialize the minimum difference and the pair of closest numbers\n min_diff = float('inf')\n closest_pair = (numbers[0], numbers[1])\n\n # Iterate over the sorted list to find the pair with the minimum difference\n for i in range(len(numbers) - 1):\n diff = numbers[i + 1] - numbers[i]\n if diff < min_diff:\n min_diff = diff\n closest_pair = (numbers[i], numbers[i + 1])\n\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\"\n From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n \n Args:\n numbers (List[float]): A list of floating point numbers.\n \n Returns:\n Tuple[float, float]: A tuple containing two numbers from the input list that are closest to each other.\n \"\"\"\n \n # Check if the input list has at least two elements\n if len(numbers) < 2:\n raise ValueError(\"The list must contain at least two elements.\")\n \n # First, sort the list of numbers\n numbers.sort()\n \n # Initialize the minimum difference and the pair of closest numbers\n min_diff = float('inf')\n closest_pair = (numbers[0], numbers[0])\n \n # Iterate over the sorted list to find the pair of closest numbers\n for i in range(1, len(numbers)):\n diff = numbers[i] - numbers[i-1]\n if diff < min_diff:\n min_diff = diff\n closest_pair = (numbers[i-1], numbers[i])\n \n return closest_pair", "matching_cluster_idx": 8}]}, "HumanEval/24": {"dps": 68.80952380952381, "dps_norm": 25.0, "pass@1": 90.0, "profiled": [{"solution": "def largest_divisor(n: int) -> int:\n \"\"\"\n For a given number n, find the largest number that divides n evenly, smaller than n\n\n Args:\n n (int): A positive integer\n\n Returns:\n int: The largest divisor of n smaller than n\n\n Raises:\n ValueError: If n is not a positive integer\n \"\"\"\n if not isinstance(n, int) or n <= 0:\n raise ValueError(\"n must be a positive integer\")\n\n # Start from the largest possible divisor (n-1) and check if it divides n\n for i in range(n - 1, 1, -1):\n if n % i == 0:\n return i\n # If no divisor found, return 1\n return 1", "matching_cluster_idx": 1}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n \"\"\"\n for i in range(n - 1, 0, -1):\n if n % i == 0:\n return i\n return 1 # Return 1 if n is prime number (no divisors)", "matching_cluster_idx": 1}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\"\n For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n for i in range(n - 1, 0, -1):\n if n % i == 0:\n return i\n return None # If no divisor is found", "matching_cluster_idx": 1}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\"\n For a given number n, find the largest number that divides n evenly, smaller than n.\n\n Args:\n n (int): The input number.\n\n Returns:\n int: The largest divisor of n smaller than n.\n\n Example:\n >>> largest_divisor(15)\n 5\n \"\"\"\n # Start from n - 1 and iterate downwards\n for i in range(n - 1, 0, -1):\n # Check if i is a divisor of n\n if n % i == 0:\n # If i is a divisor, return it as the largest divisor smaller than n\n return i\n # If no divisors are found, return 1 (since 1 is a divisor of every number)\n return 1", "matching_cluster_idx": 1}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\"\n For a given number n, find the largest number that divides n evenly, smaller than n.\n\n Args:\n n (int): The number to find the largest divisor for.\n\n Returns:\n int: The largest divisor of n that is smaller than n.\n\n Example:\n >>> largest_divisor(15)\n 5\n \"\"\"\n\n # Start from the largest possible divisor, n-1, and work our way down\n for i in range(n - 1, 0, -1):\n # Check if i is a divisor of n\n if n % i == 0:\n # If it is, return it as the largest divisor\n return i\n # If no divisors are found, return 1 (since 1 is a divisor of every number)\n return 1", "matching_cluster_idx": 1}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\"\n For a given number n, find the largest number that divides n evenly, smaller than n\n Args:\n n (int): The number for which to find the largest divisor\n\n Returns:\n int: The largest divisor of n\n\n >>> largest_divisor(15)\n 5\n \"\"\"\n\n # Initialize the largest divisor as 1 (by definition, every number is divisible by 1)\n largest_div = 1\n \n # Iterate from n-1 down to 2 (since 1 is already considered and 0 is not a divisor)\n for i in range(n - 1, 1, -1):\n # Check if i is a divisor of n\n if n % i == 0:\n # If it is, update the largest divisor\n largest_div = i\n # We can stop early since we've found the largest one so far\n break\n \n return largest_div", "matching_cluster_idx": 1}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\"\n For a given number n, find the largest number that divides n evenly, smaller than n\n\n Args:\n n (int): The input number\n\n Returns:\n int: The largest divisor of n smaller than n\n\n >>> largest_divisor(15)\n 5\n \"\"\"\n for i in range(n - 1, 0, -1):\n if n % i == 0:\n return i\n return 1", "matching_cluster_idx": 1}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n \"\"\"\n # Start checking from the number n-1 downwards\n for i in range(n - 1, 1, -1):\n # Check if n is divisible by i\n if n % i == 0:\n # If n is divisible by i, return i\n return i\n\n # If n is a prime number and n > 2, it does not have any divisors other than 1 and itself\n # In this case, return 1\n return 1", "matching_cluster_idx": 1}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n for i in range(n - 1, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 1}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\"\n For a given number n, find the largest number that divides n evenly, smaller than n\n\n Args:\n n (int): The input number.\n\n Returns:\n int: The largest divisor of n less than n.\n\n >>> largest_divisor(15)\n 5\n \"\"\"\n\n # Start checking from the largest possible divisor, which is n//2\n for i in range(n//2, 0, -1):\n # Check if i is a divisor of n\n if n % i == 0:\n return i\n\n # If no divisor is found, return 1\n return 1", "matching_cluster_idx": 3}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\"\n For a given number n, find the largest number that divides n evenly, smaller than n\n\n Args:\n n (int): A positive integer\n\n Returns:\n int: The largest divisor of n, smaller than n\n \"\"\"\n for i in range(n - 1, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 1}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\"\n For a given number n, find the largest number that divides n evenly, smaller than n.\n\n Args:\n n (int): A positive integer.\n\n Returns:\n int: The largest divisor smaller than n.\n\n Example:\n >>> largest_divisor(15)\n 5\n \"\"\"\n for i in range(n - 1, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 1}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\"\n For a given number n, find the largest number that divides n evenly, smaller than n\n\n Args:\n n (int): A positive integer.\n\n Returns:\n int: The largest divisor of n smaller than n.\n \"\"\"\n # Iterate through all numbers from n-1 to 1\n for i in range(n-1, 0, -1):\n # Check if the current number is a divisor of n\n if n % i == 0:\n # If it is, return the number as the largest divisor\n return i", "matching_cluster_idx": 1}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\"\n For a given number n, find the largest number that divides n evenly, smaller than n\n\n Args:\n n (int): A positive integer.\n\n Returns:\n int: The largest number that divides n evenly, smaller than n.\n\n >>> largest_divisor(15)\n 5\n \"\"\"\n for i in range(n - 1, 1, -1):\n if n % i == 0:\n return i\n return 1", "matching_cluster_idx": 1}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\"\n For a given number n, find the largest number that divides n evenly, smaller than n\n\n Args:\n n (int): A positive integer\n\n Returns:\n int: The largest divisor of n smaller than n\n \"\"\"\n for i in range(n - 1, 1, -1):\n # Check if i is a divisor of n\n if n % i == 0:\n return i\n\n # If no divisor is found, return 1\n return 1", "matching_cluster_idx": 1}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\"For a given number n, find the largest number that divides n evenly, smaller than n.\"\"\"\n \n # Start checking from n-1 down to 1 to ensure we find the largest divisor\n for i in range(n-1, 0, -1):\n # If n is divisible by i, return i\n if n % i == 0:\n return i", "matching_cluster_idx": 1}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\"\n For a given number n, find the largest number that divides n evenly, smaller than n\n \n Args:\n n (int): The input number\n \n Returns:\n int: The largest divisor smaller than n\n \"\"\"\n # Initialize the largest divisor as 1\n largest_div = 1\n \n # Iterate over the numbers from 2 to n (exclusive)\n for i in range(2, n):\n # Check if i is a divisor of n\n if n % i == 0:\n # Update the largest divisor if i is larger than the current largest divisor\n largest_div = i\n \n return largest_div", "matching_cluster_idx": 1}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n Args:\n n (int): The number to find the largest divisor for\n\n Returns:\n int: The largest number that divides n evenly and is smaller than n\n\n Raises:\n ValueError: If n is less than 1\n\n >>> largest_divisor(15)\n 5\n \"\"\"\n if n < 1:\n raise ValueError(\"Input number must be greater than 0\")\n\n # Start checking from n - 1 and go downwards\n for i in range(n - 1, 0, -1):\n # Check if i is a divisor of n\n if n % i == 0:\n return i", "matching_cluster_idx": 1}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\"\n For a given number n, find the largest number that divides n evenly, smaller than n.\n\n Args:\n n (int): The input number.\n\n Returns:\n int: The largest divisor smaller than n.\n\n >>> largest_divisor(15)\n 5\n \"\"\"\n for i in range(n - 1, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 1}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\"\n For a given number n, find the largest number that divides n evenly, smaller than n\n :param n: Input number\n :return: The largest divisor of n\n \"\"\"\n def is_divisor(x: int) -> bool:\n \"\"\"Check if a number is a divisor of n\"\"\"\n return n % x == 0\n\n # Start from the largest number less than n (n-1) and check downwards\n for i in range(n - 1, 0, -1):\n if is_divisor(i):\n return i\n return 1 # If no divisors are found, return 1", "matching_cluster_idx": -1}]}, "HumanEval/26": {"dps": null, "dps_norm": null, "pass@1": 1.0, "profiled": []}, "HumanEval/31": {"dps": 49.11392405063291, "dps_norm": 71.25, "pass@1": 99.0, "profiled": [{"solution": "def is_prime(n):\n \"\"\"\n Return true if a given number is prime, and false otherwise.\n\n A prime number is a natural number greater than 1 that has no positive divisors other than 1 and itself.\n \"\"\"\n if n <= 1:\n # Numbers less than or equal to 1 are not prime\n return False\n for i in range(2, int(n ** 0.5) + 1):\n # Check if n is divisible by any number up to its square root\n if n % i == 0:\n # If n is divisible, it's not a prime number\n return False\n # If n is not divisible by any number up to its square root, it's a prime number\n return True", "matching_cluster_idx": 4}, {"solution": "def is_prime(n):\n \"\"\"\n Return true if a given number is prime, and false otherwise.\n \n :param n: The number to check for primality.\n :return: True if n is prime, False otherwise.\n \"\"\"\n # Edge cases: Numbers less than 2 are not prime\n if n < 2:\n return False\n \n # Check from 2 to the square root of n\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n # If n is divisible by any number in the range, it's not prime\n return False\n \n # If n is not divisible by any number, it's prime\n return True", "matching_cluster_idx": 5}, {"solution": "def is_prime(n: int) -> bool:\n \"\"\"\n Return true if a given number is prime, and false otherwise.\n\n A prime number is a natural number greater than 1 that has no positive divisors other than 1 and itself.\n \"\"\"\n # Handle edge cases: numbers less than 2 are not prime\n if n < 2:\n return False\n \n # Check if the number is divisible by any number up to its square root\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n # If the number is divisible, it's not prime\n return False\n \n # If no divisors are found, the number is prime\n return True", "matching_cluster_idx": 4}, {"solution": "def is_prime(n):\n \"\"\"\n Return true if a given number is prime, and false otherwise.\n \n A prime number is a natural number greater than 1 that has no positive divisors other than 1 and itself.\n \"\"\"\n if n <= 1: # If the number is less than or equal to 1, it's not prime\n return False\n if n == 2: # 2 is the only even prime number\n return True\n if n % 2 == 0: # All other even numbers are not prime\n return False\n max_divisor = int(n**0.5) + 1 # We only need to check up to the square root of n\n for d in range(3, max_divisor, 2): # Check odd divisors\n if n % d == 0:\n return False\n return True", "matching_cluster_idx": 5}, {"solution": "def is_prime(n):\n \"\"\"\n Return true if a given number is prime, and false otherwise.\n\n A prime number is a natural number greater than 1 that has no positive divisors other than 1 and itself.\n\n Args:\n n (int): The number to check for primality.\n\n Returns:\n bool: True if n is prime, False otherwise.\n\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False # Prime numbers are greater than 1\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False # If n is divisible by any number between 2 and sqrt(n), it's not prime\n return True # If no divisors are found, the number is prime", "matching_cluster_idx": 4}, {"solution": "def is_prime(n):\n \"\"\"\n Return true if a given number is prime, and false otherwise.\n \n A prime number is a natural number greater than 1 that has no positive divisors other than 1 and itself.\n \n Parameters:\n n (int): The number to check for primality.\n \n Returns:\n bool: True if the number is prime, False otherwise.\n \n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n # Numbers less than or equal to 1 are not prime\n return False\n if n == 2:\n # 2 is the only even prime number\n return True\n if n % 2 == 0:\n # All other even numbers are not prime\n return False\n max_divisor = int(n**0.5) + 1\n for d in range(3, max_divisor, 2):\n if n % d == 0:\n # If the number is divisible by any divisor, it's not prime\n return False\n # If the number is not divisible by any divisors, it's prime\n return True", "matching_cluster_idx": 5}, {"solution": "def is_prime(n):\n \"\"\"\n Return true if a given number is prime, and false otherwise.\n\n Args:\n n (int): The number to check for primality.\n\n Returns:\n bool: True if the number is prime, False otherwise.\n \"\"\"\n if n <= 1:\n # Numbers less than or equal to 1 are not prime\n return False\n for i in range(2, int(n ** 0.5) + 1):\n # Check for factors up to the square root of n\n if n % i == 0:\n # If n has a factor, it's not prime\n return False\n # If no factors are found, the number is prime\n return True", "matching_cluster_idx": 4}, {"solution": "def is_prime(n):\n \"\"\"\n Return True if a given number is prime, and False otherwise.\n\n Args:\n n (int): The number to check for primality.\n\n Returns:\n bool: True if n is prime, False otherwise.\n \"\"\"\n if n <= 1: # 0 and 1 are not prime numbers\n return False\n if n <= 3: # 2 and 3 are prime numbers\n return True\n if n % 2 == 0 or n % 3 == 0: # if n is divisible by 2 or 3, it's not prime\n return False\n i = 5\n while i * i <= n: # only need to check up to sqrt(n)\n if n % i == 0 or n % (i + 2) == 0: # check for divisibility by i and i + 2\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"\n Return true if a given number is prime, and false otherwise.\n\n A prime number is a natural number greater than 1 that has no positive divisors other than 1 and itself.\n\n Parameters:\n n (int): The number to check for primality.\n\n Returns:\n bool: True if n is prime, False otherwise.\n \"\"\"\n if n <= 1: # 1 and numbers less than 1 are not prime\n return False\n\n for i in range(2, int(n ** 0.5) + 1):\n # Check if n is divisible by any number up to its square root\n if n % i == 0:\n # If n is divisible, it's not a prime number\n return False\n\n # If no divisors were found, the number is prime\n return True", "matching_cluster_idx": 4}, {"solution": "def is_prime(n):\n \"\"\"\n Return true if a given number is prime, and false otherwise.\n\n :param n: An integer to check for primality.\n :return: True if n is prime, False otherwise.\n \"\"\"\n # Edge cases: 0, 1, and negative numbers are not prime.\n if n <= 1:\n return False\n\n # 2 is the only even prime number.\n if n == 2:\n return True\n\n # All other even numbers are not prime.\n if n % 2 == 0:\n return False\n\n # Check odd factors from 3 to the square root of n.\n for i in range(3, int(n ** 0.5) + 1, 2):\n if n % i == 0:\n return False\n\n # If no factors are found, n is prime.\n return True", "matching_cluster_idx": 5}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n\n A prime number is a natural number greater than 1 that has no positive divisors other than 1 and itself.\n\n Args:\n n (int): The number to check for primality.\n\n Returns:\n bool: True if the number is prime, False otherwise.\n \"\"\"\n if n <= 1:\n # 1 and numbers less than or equal to 1 are not prime\n return False\n for i in range(2, int(n**0.5) + 1):\n # Check divisibility up to the square root of n\n if n % i == 0:\n # If n is divisible by any number, it's not prime\n return False\n # If n is not divisible by any number, it's prime\n return True", "matching_cluster_idx": 4}, {"solution": "def is_prime(n):\n \"\"\"\n Return true if a given number is prime, and false otherwise.\n\n A prime number is a natural number greater than 1 that has no positive divisors other than 1 and itself.\n\n Parameters:\n n (int): The number to check for primality.\n\n Returns:\n bool: True if the number is prime, False otherwise.\n \"\"\"\n if n <= 1: # 0 and 1 are not prime numbers\n return False\n for i in range(2, int(n**0.5) + 1): # check up to the square root of n\n if n % i == 0: # if n is divisible by any number, it's not prime\n return False\n return True # if no divisors found, the number is prime", "matching_cluster_idx": 4}, {"solution": "def is_prime(n):\n \"\"\"\n Return true if a given number is prime, and false otherwise.\n\n A prime number is a natural number greater than 1 that has no positive divisors other than 1 and itself.\n \"\"\"\n # Handle edge cases: numbers less than 2 are not prime\n if n < 2:\n return False\n\n # Check for divisors from 2 up to the square root of n\n # We only need to check up to the square root of n because a larger factor of the number would be a multiple of smaller factor that has already been checked\n for i in range(2, int(n ** 0.5) + 1):\n if n % i == 0:\n return False\n\n return True", "matching_cluster_idx": 4}, {"solution": "def is_prime(n):\n \"\"\"\n Return true if a given number is prime, and false otherwise.\n\n Args:\n n (int): The number to check for primality.\n\n Returns:\n bool: Whether the number is prime.\n\n Examples:\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1: # Handle special cases: numbers less than or equal to 1 are not prime\n return False\n if n == 2: # 2 is the only even prime number\n return True\n if n % 2 == 0: # All other even numbers are not prime\n return False\n # Check odd factors up to the square root of n\n max_divisor = int(n**0.5) + 1\n for d in range(3, max_divisor, 2): # Only check odd divisors\n if n % d == 0:\n return False\n return True", "matching_cluster_idx": 5}, {"solution": "def is_prime(n):\n \"\"\"\n Return True if a given number is prime, and False otherwise.\n \"\"\"\n if n <= 1: # Numbers less than or equal to 1 are not prime\n return False\n if n == 2: # 2 is the only even prime number\n return True\n if n % 2 == 0: # Even numbers greater than 2 are not prime\n return False\n for i in range(3, int(n**0.5) + 1, 2): # Check odd factors up to the square root\n if n % i == 0: # If a factor is found, the number is not prime\n return False\n return True # If no factors are found, the number is prime", "matching_cluster_idx": 5}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\"\"\"\n if n <= 1:\n return False\n elif n <= 3:\n return True\n elif n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\"\"\"\n if n <= 1: # Prime numbers greater than 1 cannot be divisible by 1\n return False\n if n == 2: # 2 is the only even prime number\n return True\n if n % 2 == 0: # All other even numbers are not prime\n return False\n max_divisor = int(n**0.5) + 1 # Only need to check up to sqrt(n) for factors\n for d in range(3, max_divisor, 2): # Check odd numbers only\n if n % d == 0:\n return False\n return True", "matching_cluster_idx": 5}, {"solution": "def is_prime(n):\n \"\"\"\n Returns true if a given number is prime, and false otherwise.\n \n Args:\n n (int): The number to check for primality.\n \n Returns:\n bool: True if the number is prime, False otherwise.\n \"\"\"\n if n < 2:\n return False\n for i in range(2, int(n ** 0.5) + 1):\n if n % i == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def is_prime(n):\n \"\"\"\n Return True if a given number is prime, and False otherwise.\n \n A prime number is a natural number greater than 1 that has no positive divisors other than 1 and itself.\n \"\"\"\n \n # Handle edge cases: numbers less than or equal to 1 are not prime\n if n <= 1:\n return False\n \n # 2 is the only even prime number\n if n == 2:\n return True\n \n # All other even numbers are not prime\n if n % 2 == 0:\n return False\n \n # Check odd divisors up to the square root of n\n for i in range(3, int(n**0.5) + 1, 2):\n if n % i == 0:\n return False\n \n # If no divisors found, the number is prime\n return True", "matching_cluster_idx": 5}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\"\"\"\n # Handle edge cases\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n \n # Check divisibility up to the square root of n\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n \n return True", "matching_cluster_idx": 6}]}, "HumanEval/33": {"dps": null, "dps_norm": null, "pass@1": 6.0, "profiled": []}, "HumanEval/34": {"dps": 86.41509433962264, "dps_norm": 97.0, "pass@1": 100.0, "profiled": [{"solution": "def unique(lst: list) -> list:\n \"\"\"\n Return sorted unique elements in a list\n\n Args:\n lst (list): A list of elements\n\n Returns:\n list: A sorted list with unique elements\n\n Example:\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(lst))", "matching_cluster_idx": 4}, {"solution": "def unique(input_list: list) -> list:\n \"\"\"\n Return sorted unique elements in a list\n\n Args:\n input_list (list): The list from which to extract unique elements\n\n Returns:\n list: A sorted list of unique elements\n \"\"\"\n return sorted(set(input_list))", "matching_cluster_idx": 4}, {"solution": "def unique(input_list: list):\n \"\"\"\n Return sorted unique elements in a list\n \n Args:\n input_list (list): A list of elements\n\n Returns:\n list: A list of sorted unique elements\n \"\"\"\n return sorted(set(input_list))", "matching_cluster_idx": 4}, {"solution": "def unique(lst):\n \"\"\"\n Return sorted unique elements in a list.\n \n Args:\n lst (list): A list of elements.\n \n Returns:\n list: A sorted list of unique elements.\n \n Example:\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n # Convert the list to a set to remove duplicates\n unique_set = set(lst)\n # Convert the set back to a list and sort it\n unique_list = sorted(list(unique_set))\n return unique_list", "matching_cluster_idx": 3}, {"solution": "def unique(lst):\n \"\"\"Return sorted unique elements in a list\"\"\"\n return sorted(set(lst))", "matching_cluster_idx": 4}, {"solution": "def unique(input_list: list) -> list:\n \"\"\"\n Return a sorted list of unique elements in the input list.\n \n Args:\n input_list (list): A list of elements.\n \n Returns:\n list: A sorted list of unique elements.\n \"\"\"\n return sorted(set(input_list))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n \n :param l: A list of elements\n :return: A sorted list with unique elements\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(lst: list):\n \"\"\"Return sorted unique elements in a list\n \n Args:\n lst (list): The input list of elements.\n \n Returns:\n list: A sorted list of unique elements.\n \n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(lst))", "matching_cluster_idx": 4}, {"solution": "def unique(lst: list) -> list:\n \"\"\"Return sorted unique elements in a list\"\"\"\n return sorted(set(lst))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"\n Return sorted unique elements in a list\n\n Args:\n l (list): The input list\n\n Returns:\n list: A sorted list of unique elements from the input\n\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n # Convert the list to a set to remove duplicates\n unique_elements = set(l)\n \n # Convert the set back to a list and sort it\n sorted_unique = sorted(list(unique_elements))\n \n return sorted_unique", "matching_cluster_idx": 3}, {"solution": "def unique(l: list):\n \"\"\"\n Return sorted unique elements in a list\n \n :param l: The input list\n :return: A sorted list of unique elements\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\"\"\"\n # Convert the list to a set to remove duplicates, then convert it back to a list\n # and sort it\n return sorted(list(set(l)))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"\n Return sorted unique elements in a list\n\n :param l: A list of elements\n :return: A list of sorted unique elements\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(lst: list) -> list:\n \"\"\"\n Return sorted unique elements in a list.\n\n Args:\n lst (list): Input list of elements.\n\n Returns:\n list: Sorted list of unique elements.\n \"\"\"\n return sorted(set(lst))", "matching_cluster_idx": 4}, {"solution": "def unique(lst: list) -> list:\n \"\"\"\n Return sorted unique elements in a list\n \n Args:\n lst (list): Input list containing integers\n\n Returns:\n list: Sorted list of unique integers\n \"\"\"\n return sorted(set(lst))", "matching_cluster_idx": 4}, {"solution": "def unique(lst: list) -> list:\n \"\"\"Return sorted unique elements in a list\n \n :param lst: A list of elements\n :return: A sorted list of unique elements\n \"\"\"\n return sorted(set(lst)) # Convert to a set to eliminate duplicates, then sort and convert back to list", "matching_cluster_idx": 4}, {"solution": "def unique(lst: list) -> list:\n \"\"\"Return sorted unique elements in a list\"\"\"\n return sorted(set(lst))", "matching_cluster_idx": 4}, {"solution": "def unique(input_list: list):\n \"\"\"\n Return sorted unique elements in a list\n\n Args:\n input_list (list): The list from which to remove duplicates.\n\n Returns:\n list: Sorted list with unique elements.\n\n Examples:\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n # Convert the list to a set to remove duplicates\n unique_set = set(input_list)\n # Convert the set back to a list and sort it\n sorted_unique_list = sorted(list(unique_set))\n return sorted_unique_list", "matching_cluster_idx": 3}, {"solution": "def unique(lst: list):\n \"\"\"Return sorted unique elements in a list\"\"\"\n return sorted(set(lst))", "matching_cluster_idx": 4}]}, "HumanEval/36": {"dps": 96.77419354838709, "dps_norm": 71.42857142857143, "pass@1": 80.0, "profiled": [{"solution": "def fizz_buzz(n: int):\n \"\"\"\n Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n\n Args:\n n (int): An integer.\n\n Returns:\n int: The number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n \"\"\"\n count = 0\n for i in range(n - 1, 0, -1):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def count_sevens(n: int) -> int:\n \"\"\"Count the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\"\"\"\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n str_i = str(i)\n count += str_i.count('7')\n return count\ndef fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\"\"\"\n return count_sevens(n)", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int):\n \"\"\"\n Return the number of times the digit 7 appears in integers less than n \n which are divisible by 11 or 13.\n\n Args:\n n (int): The upper limit (exclusive) for checking integers.\n\n Returns:\n int: The count of digits 7 in integers divisible by 11 or 13.\n \"\"\"\n count = 0\n for i in range(1, n):\n # Check if number is divisible by 11 or 13\n if i % 11 == 0 or i % 13 == 0:\n # Convert the number to string to check for digit 7\n str_i = str(i)\n count += str_i.count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def count_digit(n: int) -> int:\n \"\"\"\n Counts the occurrences of the digit 7 in a given number.\n \n Args:\n n (int): The number to count the digit 7 in.\n \n Returns:\n int: The number of occurrences of the digit 7 in the given number.\n \"\"\"\n return str(n).count('7')\ndef fizz_buzz(n: int) -> int:\n \"\"\"\n Returns the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n \n Args:\n n (int): The upper limit (exclusive) for the range to check.\n \n Returns:\n int: The total number of occurrences of the digit 7 in numbers meeting the specified conditions.\n \"\"\"\n return sum(count_digit(i) for i in range(n) if i % 11 == 0 or i % 13 == 0)", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"\n Return the number of times the digit 7 appears in integers less than n \n which are divisible by 11 or 13.\n\n Args:\n n (int): The upper limit for the number range.\n\n Returns:\n int: The count of digit 7 appearances.\n \"\"\"\n count = 0\n for i in range(1, n): # loop through numbers less than n\n if i % 11 == 0 or i % 13 == 0: # check if the number is divisible by 11 or 13\n str_i = str(i) # convert the number to a string\n count += str_i.count('7') # count the occurrences of '7' in the string\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int):\n \"\"\"\n Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n\n Args:\n n (int): Upper bound for the integers to check.\n\n Returns:\n int: Number of times the digit 7 appears in the integers.\n \"\"\"\n count = 0 # Initialize a counter variable to store the count of 7\n for i in range(n): # Loop through all integers less than n\n if i % 11 == 0 or i % 13 == 0: # Check if the current integer is divisible by 11 or 13\n str_i = str(i) # Convert the integer to a string to check for the digit 7\n count += str_i.count('7') # Increment the counter by the number of times 7 appears in the string representation of the integer\n return count # Return the final count of 7", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int):\n \"\"\"\n Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n\n Args:\n n (int): The upper bound of the range.\n\n Returns:\n int: The number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n \"\"\"\n count = 0\n for i in range(n):\n # Check if the number is divisible by 11 or 13\n if i % 11 == 0 or i % 13 == 0:\n # Convert the number to a string to easily check for the digit 7\n str_i = str(i)\n # Count the occurrences of the digit 7\n count += str_i.count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"\n Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n \n Parameters:\n n (int): The upper limit of the range to check.\n \n Returns:\n int: The number of times the digit 7 appears.\n \"\"\"\n count = 0\n for i in range(1, n):\n if i % 11 == 0 or i % 13 == 0:\n str_i = str(i)\n count += str_i.count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"\n Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n\n Args:\n n: A non-negative integer.\n\n Returns:\n The number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n \"\"\"\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n str_i = str(i)\n count += str_i.count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"\n Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n\n Args:\n n (int): The upper limit.\n\n Returns:\n int: The count of times 7 appears in numbers divisible by 11 or 13.\n \"\"\"\n def digit_counts(x):\n \"\"\"Count the occurrences of the digit 7 in x.\"\"\"\n return str(x).count('7')\n\n count = 0\n for i in range(11, n):\n if i % 11 == 0 or i % 13 == 0:\n count += digit_counts(i)\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"\n Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n \n Args:\n n (int): Upper bound for the range of numbers to check.\n \n Returns:\n int: Count of appearances of the digit 7 in numbers that are divisible by 11 or 13.\n \"\"\"\n count = 0\n for i in range(1, n):\n if i % 11 == 0 or i % 13 == 0:\n for digit in str(i):\n if digit == '7':\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"\n Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n\n Args:\n n (int): The upper limit (exclusive).\n\n Returns:\n int: The number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n \"\"\"\n count = 0 # Initialize count to store the number of times the digit 7 appears\n\n # Loop through all numbers less than n\n for i in range(n):\n # Check if the current number is divisible by 11 or 13\n if i % 11 == 0 or i % 13 == 0:\n # Convert the current number to a string to check for the presence of '7'\n num_str = str(i)\n # Count the occurrences of '7' in the string\n count += num_str.count('7')\n\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int):\n \"\"\"\n Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n\n Args:\n n (int): The upper limit.\n\n Returns:\n int: The count of digit 7 in numbers divisible by 11 or 13.\n\n Example:\n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n for i in range(2, n):\n if i % 11 == 0 or i % 13 == 0:\n # Convert the number to string to count the occurrences of the digit '7'\n str_i = str(i)\n count += str_i.count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"\n Return the number of times the digit 7 appears in integers less than n \n which are divisible by 11 or 13.\n\n Args:\n n (int): The upper limit.\n\n Returns:\n int: The count of occurrences of the digit 7.\n \"\"\"\n count = 0\n for i in range(n):\n # check if number is divisible by 11 or 13\n if i % 11 == 0 or i % 13 == 0:\n # convert the number to string to count the digit\n str_i = str(i)\n count += str_i.count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"\n Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n\n Args:\n n (int): The upper limit of the range of numbers to check.\n\n Returns:\n int: The total number of occurrences of the digit 7.\n \"\"\"\n count = 0\n for i in range(1, n):\n # Check if the number is divisible by 11 or 13\n if i % 11 == 0 or i % 13 == 0:\n # Convert the number to a string to easily check for the digit 7\n str_i = str(i)\n # Count the occurrences of the digit 7\n count += str_i.count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int):\n \"\"\"\n Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n\n Args:\n n (int): Upper bound of the range of numbers to check.\n\n Returns:\n int: The count of appearances of the digit 7.\n \"\"\"\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n str_i = str(i)\n count += str_i.count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def count_sevens(n: int) -> int:\n \"\"\"\n Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n \n Args:\n n (int): The upper limit for the range of numbers to check.\n \n Returns:\n int: The count of occurrences of the digit 7 in the specified range.\n \"\"\"\n count = 0\n for i in range(n):\n # check if the number is divisible by 11 or 13\n if i % 11 == 0 or i % 13 == 0:\n # convert the number to a string to easily check each digit\n num_str = str(i)\n count += num_str.count('7')\n return count\ndef fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n \n Args:\n n (int): The upper limit for the range of numbers to check.\n \n Returns:\n int: The count of occurrences of the digit 7 in the specified range.\n \"\"\"\n return count_sevens(n)", "matching_cluster_idx": 4}, {"solution": "def count_digit_seven(n: int) -> int:\n \"\"\"Count the number of occurrences of 7 in all digits of a number.\"\"\"\n return str(n).count('7')\ndef fizz_buzz(n: int) -> int:\n \"\"\"\n Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n \"\"\"\n count = 0\n for i in range(1, n):\n if i % 11 == 0 or i % 13 == 0:\n count += count_digit_seven(i)\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int):\n \"\"\"\n Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n \n Args:\n n (int): The upper bound of the range (exclusive).\n \n Returns:\n int: The number of times the digit 7 appears in the described integers.\n \"\"\"\n def count_digit(num: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in num.\"\"\"\n return str(num).count('7')\n\n return sum(count_digit(num) for num in range(n) if num % 11 == 0 or num % 13 == 0)", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int):\n \"\"\"\n Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n\n Args:\n n: An integer.\n\n Returns:\n An integer representing the number of times the digit 7 appears.\n \"\"\"\n count = 0\n for i in range(n):\n # Check if the number is divisible by 11 or 13\n if i % 11 == 0 or i % 13 == 0:\n # Convert the number to a string to easily iterate over each digit\n str_i = str(i)\n # Count the occurrences of '7' in the string representation\n count += str_i.count('7')\n return count", "matching_cluster_idx": 4}]}, "HumanEval/37": {"dps": 81.1620294599018, "dps_norm": 84.5, "pass@1": 40.0, "profiled": [{"solution": "def sort_even(lst: list) -> list:\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n\n Args:\n lst (list): The list to sort even indicies of.\n\n Returns:\n list: The modified list with sorted even indicies.\n \"\"\"\n # Separate the odd and even indicies of the list into two lists\n odd = lst[1::2]\n even = lst[::2]\n\n # Sort the even indicies list\n even.sort()\n\n # Combine the odd and sorted even lists\n result = []\n for i in range(len(lst)):\n if i % 2 == 0:\n result.append(even[i // 2])\n else:\n result.append(odd[i // 2])\n\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"\n This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indices, while its values at the even indices are equal\n to the values of the even indices of l, but sorted.\n \n Parameters:\n l (list): The input list\n \n Returns:\n list: The modified list\n \"\"\"\n # Separate even and odd elements into two lists\n even_list = [x for i, x in enumerate(l) if i % 2 == 0]\n odd_list = [x for i, x in enumerate(l) if i % 2 != 0]\n \n # Sort the even list\n even_list.sort()\n \n # Combine the sorted even list with the odd list\n result = []\n for i, _ in enumerate(l):\n if i % 2 == 0:\n result.append(even_list[i // 2])\n else:\n result.append(odd_list[i // 2])\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"\n This function takes a list `l` and returns a list `l'` such that\n `l'` is identical to `l` in the odd indices, while its values at the even indices are equal\n to the values of the even indices of `l`, but sorted.\n\n Args:\n l (list): The input list.\n\n Returns:\n list: The transformed list.\n \"\"\"\n # Separate even and odd indices\n even_indices = [x for i, x in enumerate(l) if i % 2 == 0]\n odd_indices = [x for i, x in enumerate(l) if i % 2 != 0]\n\n # Sort the values at even indices\n even_indices.sort()\n\n # Combine the two parts and replace the original even values with the sorted ones\n result = [x if i % 2 != 0 else even_indices[i // 2] for i, x in enumerate(l)]\n\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list) -> list:\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indices, while its values at the even indices are equal\n to the values of the even indices of l, but sorted.\n \n Args:\n l (list): A list of elements\n \n Returns:\n list: The list l' with sorted even indices\n \"\"\"\n # Separate even and odd indices\n even_indices = [l[i] for i in range(0, len(l), 2)]\n odd_indices = [l[i] for i in range(1, len(l), 2)]\n \n # Sort even indices\n sorted_even_indices = sorted(even_indices)\n \n # Combine sorted even and odd indices\n sorted_l = []\n for i in range(len(l)):\n if i % 2 == 0:\n sorted_l.append(sorted_even_indices[i // 2])\n else:\n sorted_l.append(odd_indices[i // 2])\n \n return sorted_l", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list) -> list:\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n\n Args:\n l (list): The input list.\n\n Returns:\n list: The modified list.\n \"\"\"\n # Separate even and odd elements\n even = [l[i] for i in range(len(l)) if i % 2 == 0]\n odd = [l[i] for i in range(len(l)) if i % 2 != 0]\n\n # Sort the even elements\n even.sort()\n\n # Replace even elements in the original list with the sorted even elements\n for i in range(len(even)):\n l[i * 2] = even[i] # replace elements at even positions\n\n return l", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"\n This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n\n Args:\n l (list): The input list to be processed.\n\n Returns:\n list: The processed list with sorted values at even indices.\n \"\"\"\n # Separate the input list into two lists: one for odd indices and one for even indices\n odd_indices = [value for i, value in enumerate(l) if i % 2 != 0]\n even_indices = [value for i, value in enumerate(l) if i % 2 == 0]\n\n # Sort the list for even indices\n even_indices.sort()\n\n # Combine the odd indices and the sorted even indices\n result = []\n for i in range(len(l)):\n if i % 2 != 0:\n result.append(odd_indices.pop(0))\n else:\n result.append(even_indices.pop(0))\n\n return result", "matching_cluster_idx": 7}, {"solution": "def sort_even(l: list):\n \"\"\"\n This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n\n Args:\n l (list): The input list.\n\n Returns:\n list: The modified list according to the problem's requirements.\n \"\"\"\n # Separate odd and even indicies\n odd_indicies = [i for i in range(len(l)) if i % 2 != 0]\n even_indicies = [i for i in range(len(l)) if i % 2 == 0]\n \n # Create two lists from the original list\n odds = [l[i] for i in odd_indicies]\n evens = [l[i] for i in even_indicies]\n\n # Sort the list of even values\n evens.sort()\n\n # Replace even indicies with sorted even values\n result = [0] * len(l)\n for i in range(len(odd_indicies)):\n result[odd_indicies[i]] = odds[i]\n for i in range(len(evens)):\n result[even_indicies[i]] = evens[i]\n\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"\n This function takes a list `l` and returns a list `l'` such that\n `l'` is identical to `l` in the odd indices, while its values at the even indices are equal\n to the values of the even indices of `l`, but sorted.\n\n Args:\n l (list): The input list to be processed.\n\n Returns:\n list: The modified list with even indices sorted.\n \"\"\"\n # Separate the elements at even indices\n even_indices = [l[i] for i in range(0, len(l), 2)]\n \n # Sort the elements at even indices\n even_indices.sort()\n \n # Create the result list with elements from odd indices and sorted even indices\n result = []\n for i in range(len(l)):\n if i % 2 == 0:\n result.append(even_indices[i // 2])\n else:\n result.append(l[i])\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list) -> list:\n \"\"\"\n This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n \"\"\"\n # Separate even and odd indexed elements\n even_elements = l[::2]\n odd_elements = l[1::2]\n\n # Sort the even indexed elements\n sorted_even_elements = sorted(even_elements)\n\n # Create a new list with even indexed elements as sorted and odd indexed elements as is\n sorted_list = []\n for i in range(len(l)):\n if i % 2 == 0:\n sorted_list.append(sorted_even_elements[i // 2])\n else:\n sorted_list.append(odd_elements[i // 2])\n\n return sorted_list", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"\n This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indices, while its values at the even indices are equal\n to the values of the even indices of l, but sorted.\n\n Args:\n l (list): The input list.\n\n Returns:\n list: The modified list with even indices sorted.\n\n Examples:\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Split the input list into two lists, one for even and one for odd indices\n even_indices = [value for i, value in enumerate(l) if i % 2 == 0]\n odd_indices = [value for i, value in enumerate(l) if i % 2 != 0]\n\n # Sort the list of even indices\n sorted_even_indices = sorted(even_indices)\n\n # Combine the two lists, using the sorted even indices for even positions\n result = []\n for i, value in enumerate(l):\n if i % 2 == 0:\n result.append(sorted_even_indices[i // 2])\n else:\n result.append(odd_indices[i // 2])\n\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list) -> list:\n \"\"\"\n This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n\n Args:\n l (list): The input list.\n\n Returns:\n list: The modified list l'.\n \"\"\"\n # Separate the elements at even and odd indices into two separate lists\n evens = [l[i] for i in range(len(l)) if i % 2 == 0]\n odds = [l[i] for i in range(len(l)) if i % 2 != 0]\n\n # Sort the list of elements at even indices\n evens.sort()\n\n # Combine the sorted even elements with the odd elements in the original order\n result = []\n for i in range(len(l)):\n if i % 2 == 0:\n result.append(evens[i // 2])\n else:\n result.append(odds[i // 2])\n\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"\n This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n\n Args:\n l (list): A list of elements to be sorted.\n\n Returns:\n list: A list with even indices sorted.\n \"\"\"\n # Separate the even and odd indices into different lists\n even_indices = [l[i] for i in range(len(l)) if i % 2 == 0]\n odd_indices = [l[i] for i in range(len(l)) if i % 2 != 0]\n\n # Sort the even indices\n sorted_even_indices = sorted(even_indices)\n\n # Combine the sorted even indices and odd indices into a single list\n result = []\n for i in range(len(l)):\n if i % 2 == 0:\n result.append(sorted_even_indices[i // 2])\n else:\n result.append(odd_indices[i // 2])\n\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(lst: list) -> list:\n \"\"\"\n This function takes a list lst and returns a list lst' such that\n lst' is identical to lst in the odd indices, while its values at the even indices are equal\n to the values of the even indices of lst, but sorted.\n\n Args:\n lst (list): A list of values.\n\n Returns:\n list: A new list where values at even indices are sorted.\n \"\"\"\n # Separate even and odd values from the list, keeping their original order\n even = [x for i, x in enumerate(lst) if i % 2 == 0]\n odd = [x for i, x in enumerate(lst) if i % 2 != 0]\n\n # Sort the even values in ascending order\n even.sort()\n\n # Create the new list with odd values and sorted even values\n new_lst = []\n for i in range(len(lst)):\n if i % 2 == 0:\n new_lst.append(even[i // 2])\n else:\n new_lst.append(odd[i // 2])\n\n return new_lst", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"\n This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indices, while its values at the even indices are equal\n to the values of the even indices of l, but sorted.\n\n Args:\n l (list): A list of elements to be sorted according to given conditions.\n\n Returns:\n list: A list l' with sorted even indices while keeping the odd indices unchanged.\n\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n even_indices = sorted([l[i] for i in range(len(l)) if i % 2 == 0])\n even_list = [x if i % 2 != 0 else even_indices.pop(0) for i, x in enumerate(l)]\n return even_list", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"\n This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indices, while its values at the even indices are equal\n to the values of the even indices of l, but sorted.\n\n Args:\n l (list): A list of elements.\n\n Returns:\n list: The sorted list.\n \"\"\"\n # Separate even and odd indices\n even_indices = [l[i] for i in range(len(l)) if i % 2 == 0]\n odd_indices = [l[i] for i in range(len(l)) if i % 2 != 0]\n\n # Sort the list at even indices\n even_indices.sort()\n\n # Combine the lists with odd and sorted even indices\n result = [None] * len(l)\n for i in range(len(l)):\n if i % 2 == 0:\n result[i] = even_indices[i // 2]\n else:\n result[i] = odd_indices[i // 2]\n\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"\n This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n \n Args:\n l (list): A list of values to be sorted\n \n Returns:\n list: The modified list with odd indices unchanged and even indices sorted\n \"\"\"\n # Separate the list into even and odd indexed values\n evens = [x for i, x in enumerate(l) if i % 2 == 0]\n odds = [x for i, x in enumerate(l) if i % 2 != 0]\n \n # Sort the even indexed values\n sorted_evens = sorted(evens)\n \n # Combine the sorted even values with the odd values in the correct order\n result = []\n for i in range(len(l)):\n if i % 2 == 0:\n result.append(sorted_evens.pop(0))\n else:\n result.append(odds.pop(0))\n \n return result", "matching_cluster_idx": 7}, {"solution": "def sort_even(lst: list) -> list:\n \"\"\"\n This function takes a list lst and returns a list lst' such that\n lst' is identical to lst in the odd indices, while its values at the even indices are equal\n to the values of the even indices of lst, but sorted.\n\n Args:\n lst (list): The input list\n\n Returns:\n list: The modified list\n \"\"\"\n # Separate the even and odd indices into two lists\n even_idx_vals = [lst[i] for i in range(len(lst)) if i % 2 == 0]\n odd_idx_vals = [lst[i] for i in range(len(lst)) if i % 2 != 0]\n\n # Sort the values at even indices\n sorted_even_idx_vals = sorted(even_idx_vals)\n\n # Create a new list with sorted even index values and the original odd index values\n sorted_lst = [val if i % 2 != 0 else sorted_even_idx_vals[i // 2] for i, val in enumerate(lst)]\n\n return sorted_lst", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"\n This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n\n Args:\n l (list): The input list to be sorted.\n\n Returns:\n list: The modified list according to the problem statement.\n \"\"\"\n # Separate the even-indexed elements from the rest\n even_indexed = [l[i] for i in range(len(l)) if i % 2 == 0]\n \n # Sort the even-indexed elements\n sorted_even_indexed = sorted(even_indexed)\n \n # Replace the even-indexed elements in the original list with the sorted ones\n result = []\n for i, elem in enumerate(l):\n if i % 2 == 0:\n result.append(sorted_even_indexed[i // 2])\n else:\n result.append(elem)\n \n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"\n This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indices, while its values at the even indices are equal\n to the values of the even indices of l, but sorted.\n\n Args:\n l (list): The input list.\n\n Returns:\n list: The sorted list according to the problem description.\n\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n return [x if i % 2 != 0 else sorted([x for i, x in enumerate(l) if i % 2 == 0])[(i // 2) % len(sorted([x for i, x in enumerate(l) if i % 2 == 0]))] for i, x in enumerate(l)]", "matching_cluster_idx": -1}, {"solution": "def sort_even(l: list):\n \"\"\"\n This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n\n Args:\n l (list): Input list\n\n Returns:\n list: Modified list with values at even indicies sorted\n \"\"\"\n # Separate the list into odd and even index values\n odd_indices = [x for i, x in enumerate(l) if i % 2 != 0]\n even_indices = [x for i, x in enumerate(l) if i % 2 == 0]\n \n # Sort the values at even indices\n sorted_even = sorted(even_indices)\n \n # Combine the values from odd indices and sorted even indices\n result = []\n odd_index = 0\n even_index = 0\n for i in range(len(l)):\n if i % 2 != 0:\n result.append(odd_indices[odd_index])\n odd_index += 1\n else:\n result.append(sorted_even[even_index])\n even_index += 1\n \n return result", "matching_cluster_idx": 8}]}, "HumanEval/49": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 55.0, "profiled": [{"solution": "def modp(n: int, p: int) -> int:\n \"\"\"\n Return 2^n modulo p (be aware of numerics).\n \n :param n: The base number\n :type n: int\n :param p: The modulus\n :type p: int\n :return: 2^n modulo p\n :rtype: int\n \"\"\"\n # Handle the special case where 2^n is a power of p\n if pow(2, n, p) == 1:\n return 1\n \n # Compute 2^n % p using the built-in pow function with three arguments\n # This function uses the \"Exponentiation by squaring\" algorithm internally, which is more efficient than naive approach\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"\n Return 2^n modulo p (be aware of numerics).\n\n Args:\n n (int): The exponent.\n p (int): The modulo.\n\n Returns:\n int: The result of 2^n modulo p.\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"\n Return 2^n modulo p (be aware of numerics).\n\n Args:\n n (int): The exponent.\n p (int): The modulus.\n\n Returns:\n int: 2^n % p\n \"\"\"\n if n < 0:\n # Since (a^m)^n = a^(m*n), we can consider (p-1) as a quick approach to get negative exponents.\n # and, to get rid of negative exponent, We can raise 2 to the power of (p-1) and take the modulus of result raised to -n and p\n return pow(pow(2, p - 1, p), -n, p)\n else:\n # Calculating and taking modulus for simplicity.\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"\n Calculate and return 2^n modulo p.\n\n Args:\n n (int): The exponent to which 2 will be raised.\n p (int): The modulus for the calculation.\n\n Returns:\n int: The result of 2^n modulo p.\n\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"\n Return 2^n modulo p (be aware of numerics).\n\n Args:\n n (int): The exponent.\n p (int): The modulo value.\n\n Returns:\n int: The result of 2^n modulo p.\n \"\"\"\n return pow(2, n, p) # pow() function calculates 2^n % p efficiently", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"\n Return 2^n modulo p.\n \n Parameters:\n n (int): The base number.\n p (int): The modulo number.\n \n Returns:\n int: The result of 2^n modulo p.\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"\n Return 2^n modulo p (be aware of numerics).\n \n This function calculates the result of 2^n modulo p for a given n and p.\n \n Args:\n n (int): The base number.\n p (int): The modulo number.\n \n Returns:\n int: The result of 2^n modulo p.\n \"\"\"\n \n # Use the built-in pow function with three arguments to calculate 2^n modulo p efficiently\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"\n Return 2^n modulo p.\n\n Args:\n n: An integer power.\n p: The modulus.\n\n Returns:\n The result of 2^n modulo p.\n\n Examples:\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n\n # Use the built-in pow function with three arguments, which returns (a^b) % c\n # This is more efficient than using the ** operator and the % operator separately\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"\n Return 2^n modulo p (be aware of numerics).\n\n Args:\n n (int): The exponent.\n p (int): The modulo.\n\n Returns:\n int: 2^n modulo p.\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"\n Return 2^n modulo p (be aware of numerics).\n\n Args:\n n (int): The exponent.\n p (int): The modulo.\n\n Returns:\n int: The result of 2^n modulo p.\n \"\"\"\n return pow(2, n, p) # using pow() function with three arguments for efficient modulo operation", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"\n Return 2^n modulo p (be aware of numerics).\n \n Args:\n n (int): The base (2 in this case)\n p (int): The modulo value\n \n Returns:\n int: The result of 2^n modulo p\n \"\"\"\n return pow(2, n, p) # Using pow for efficient modular exponentiation", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"\n Returns 2^n modulo p (be aware of numerics).\n \n :param n: The power to which 2 should be raised\n :param p: The modulus\n :return: 2^n modulo p\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"\n Return 2^n modulo p.\n\n Args:\n n (int): The base number.\n p (int): The modulo number.\n\n Returns:\n int: The result of 2^n modulo p.\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "import doctest\ndef modp(n: int, p: int) -> int:\n \"\"\"\n Return 2^n modulo p (be aware of numerics).\n\n Args:\n n (int): The exponent.\n p (int): The modulus.\n\n Returns:\n int: 2^n modulo p.\n\n Example Use Cases:\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"\n Returns 2^n modulo p (be aware of numerics).\n\n Args:\n n (int): The power to which 2 is raised.\n p (int): The modulo number.\n\n Returns:\n int: 2^n modulo p.\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"\n Return 2^n modulo p (be aware of numerics).\n\n Args:\n n (int): The exponent.\n p (int): The modulo.\n\n Returns:\n int: The result of 2^n modulo p.\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"\n Return 2^n modulo p (be aware of numerics).\n\n Args:\n n (int): The power to which 2 should be raised.\n p (int): The modulo value.\n\n Returns:\n int: The result of 2^n modulo p.\n \"\"\"\n # We use the built-in pow() function with three arguments to handle the modulo operation efficiently.\n # The third argument in pow() is the modulo value, which is used to compute the power with modulus in-place.\n result = pow(2, n, p)\n return result", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"\n Return 2^n modulo p (be aware of numerics).\n \n This function uses the built-in pow function in Python which can handle large numbers\n and returns the result of the power operation in a way that avoids large intermediate results.\n \n Args:\n n (int): The base number\n p (int): The modulo number\n \n Returns:\n int: The result of 2^n modulo p\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "import unittest\ndef modp(n: int, p: int) -> int:\n \"\"\"\n Return 2^n modulo p.\n\n Args:\n n (int): The exponent to which 2 should be raised.\n p (int): The divisor for the modulo operation.\n\n Returns:\n int: The result of 2^n modulo p.\n \"\"\"\n # Directly return the result of the modulo operation\n return pow(2, n, p)", "matching_cluster_idx": 4}]}, "HumanEval/51": {"dps": 96.13526570048309, "dps_norm": 75.0, "pass@1": 98.0, "profiled": [{"solution": "def remove_vowels(text):\n \"\"\"\n Remove vowels from a given string.\n \n Parameters:\n text (str): The input string\n \n Returns:\n str: The input string with vowels removed\n \"\"\"\n \n # Define vowels in both lowercase and uppercase\n vowels = 'aeiouAEIOU'\n \n # Use a list comprehension to filter out vowels from the string\n # The expression `c for c in text if c not in vowels` iterates over each character\n # in the string, and includes it in the new string if it's not a vowel\n text_without_vowels = ''.join(c for c in text if c not in vowels)\n \n return text_without_vowels", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n Remove all vowels from a given string.\n\n Args:\n text (str): The input string to remove vowels from.\n\n Returns:\n str: The string with all vowels removed.\n \"\"\"\n vowels = 'aeiouAEIOU'\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n Removes all vowels from a given string.\n \n Parameters:\n text (str): The input string from which vowels are to be removed.\n \n Returns:\n str: The string with all vowels removed.\n \"\"\"\n # Define a string of vowels (lowercase and uppercase)\n vowels = 'aeiouAEIOU'\n \n # Use a list comprehension to filter out vowels from the string\n # and then join the characters back into a string\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n \n Parameters:\n text (str): Input string\n \n Returns:\n str: String without vowels\n \"\"\"\n # Define vowels in both lowercase and uppercase\n vowels = 'aeiouAEIOU'\n \n # Use a generator expression within the join function to filter out vowels\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n \"\"\"\n vowels = 'aeiouAEIOU'\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n Removes all vowels from the given string.\n \n Args:\n text (str): The input string.\n \n Returns:\n str: The input string without vowels.\n \"\"\"\n vowels = 'aeiouAEIOU'\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n Remove vowels from a given string.\n\n Args:\n text (str): The input string from which to remove vowels.\n\n Returns:\n str: The input string with all vowels removed.\n \"\"\"\n vowels = 'aeiouAEIOU'\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n Remove all vowels from a given string.\n\n Args:\n text (str): Input string.\n\n Returns:\n str: String without vowels.\n\n Examples:\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n # Define the vowels (both lowercase and uppercase)\n vowels = 'aeiouAEIOU'\n \n # Use a list comprehension to filter out vowels from the input string\n # and join the result into a string\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text: str) -> str:\n \"\"\"\n Remove all vowels from the input string.\n\n Args:\n text (str): The input string.\n\n Returns:\n str: The string without vowels.\n \"\"\"\n vowels = 'aeiouAEIOU'\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text: str) -> str:\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n :param text: The input string\n :return: The string without vowels\n \"\"\"\n # Define a string of vowels (both lowercase and uppercase)\n vowels = 'aeiouAEIOU'\n \n # Use a list comprehension to create a new string without vowels\n new_text = [char for char in text if char not in vowels]\n \n # Join the list of characters back into a string\n return ''.join(new_text)", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n \n Parameters:\n text (str): The input string\n \n Returns:\n str: The input string with all vowels removed\n \"\"\"\n vowels = 'aeiouAEIOU'\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text: str) -> str:\n \"\"\"\n Removes all vowels from the given text, both lowercase and uppercase.\n\n Args:\n text (str): The input string.\n\n Returns:\n str: The string with all vowels removed.\n \"\"\"\n # Define a string of vowels (both lowercase and uppercase)\n vowels = 'aeiouAEIOU'\n \n # Use a list comprehension to iterate over each character in the text\n # If the character is not a vowel, include it in the new list\n # The join function is then used to concatenate the characters back into a string\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n Removes vowels from the given text.\n \n Args:\n text (str): The input string from which vowels will be removed.\n \n Returns:\n str: The input string without vowels.\n \"\"\"\n vowels = 'aeiouAEIOU'\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n \n Parameters:\n text (str): The input string from which to remove vowels.\n \n Returns:\n str: The input string with all vowels removed.\n \"\"\"\n # Define the vowels to remove\n vowels = 'aeiouAEIOU'\n \n # Use a list comprehension to filter out vowels from the input string\n # The conditional statement checks if a character is not in the vowels string\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text: str) -> str:\n \"\"\"\n Removes vowels from a given string.\n\n Args:\n text (str): Input string.\n\n Returns:\n str: String without vowels.\n \"\"\"\n vowels = 'aeiouAEIOU'\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n This function removes all vowels from a given string.\n\n Parameters:\n text (str): The input string from which to remove vowels.\n\n Returns:\n str: The string without vowels.\n \"\"\"\n vowels = 'aeiouAEIOU'\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes a string and returns the string without vowels.\n \n Parameters:\n text (str): The input string\n \n Returns:\n str: The input string with vowels removed\n \n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n \n # Define a string of vowels (both lowercase and uppercase)\n vowels = 'aeiouAEIOU'\n \n # Initialize an empty string to store the result\n result = ''\n \n # Iterate over each character in the input string\n for char in text:\n # Check if the character is not a vowel\n if char not in vowels:\n # If it's not a vowel, add it to the result\n result += char\n \n # Return the result\n return result", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n Parameters:\n text (str): The input string from which to remove vowels.\n Returns:\n str: The input string without vowels.\n \"\"\"\n # Define the vowels to be removed (lowercase and uppercase)\n vowels = 'aeiouAEIOU'\n \n # Use a generator expression to filter out vowels from the input string\n # The 'in' operator checks if each character is in the vowels string\n # If not, it's included in the output string\n return ''.join(char for char in text if char not in vowels)", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n \n Parameters:\n text (str): Input string\n \n Returns:\n str: String without vowels\n \"\"\"\n # Define a string of vowels (both lowercase and uppercase)\n vowels = 'aeiouAEIOU'\n \n # Use a list comprehension to create a new string without vowels\n # The if condition checks if each character is not in the vowels string\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n Remove all vowels from a given string.\n \n Parameters:\n text (str): The input string from which vowels are to be removed.\n \n Returns:\n str: The input string without vowels.\n \"\"\"\n # Define a string of vowels to be removed\n vowels = 'aeiouAEIOU'\n \n # Use a list comprehension to create a new string with vowels removed\n # The conditional statement `if char not in vowels` ensures only non-vowel characters are included\n no_vowels = [char for char in text if char not in vowels]\n \n # Join the list of characters back into a string\n return ''.join(no_vowels)", "matching_cluster_idx": 5}]}, "HumanEval/54": {"dps": 95.74468085106383, "dps_norm": 99.28571428571429, "pass@1": 40.0, "profiled": [{"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters, regardless of order or repetition.\n\n Args:\n s0 (str): First word.\n s1 (str): Second word.\n\n Returns:\n bool: True if the two words have the same characters, False otherwise.\n\n Example:\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')\n True\n >>> same_chars('abcd', 'dddddddabc')\n True\n >>> same_chars('dddddddabc', 'abcd')\n True\n >>> same_chars('eabcd', 'dddddddabc')\n False\n >>> same_chars('abcd', 'dddddddabce')\n False\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')\n False\n \"\"\"\n\n # Convert both strings to sorted lists of unique characters\n sorted_unique_chars_s0 = sorted(set(s0))\n sorted_unique_chars_s1 = sorted(set(s1))\n\n # Compare the sorted lists of unique characters\n return sorted_unique_chars_s0 == sorted_unique_chars_s1", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters, regardless of order.\n \n Args:\n s0 (str): The first string.\n s1 (str): The second string.\n \n Returns:\n bool: True if the strings have the same characters, False otherwise.\n \"\"\"\n \n # Convert both strings to sets to remove duplicates and make them comparable\n return sorted(set(s0)) == sorted(set(s1))", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \n Args:\n s0 (str): The first word.\n s1 (str): The second word.\n \n Returns:\n bool: True if the words have the same characters, False otherwise.\n \"\"\"\n # Remove duplicate characters and sort the characters in each word\n s0_chars = ''.join(sorted(set(s0)))\n s1_chars = ''.join(sorted(set(s1)))\n \n # Compare the sorted lists of characters\n return s0_chars == s1_chars", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n\n Args:\n s0 (str): The first word.\n s1 (str): The second word.\n\n Returns:\n bool: True if the words have the same characters, False otherwise.\n \"\"\"\n # Combine characters from both strings into a set to eliminate duplicates and then compare their lengths.\n # Since sets in Python cannot contain duplicate elements, if two words have the same characters, \n # they will have the same set even when their characters are in a different order.\n return sorted(set(s0)) == sorted(set(s1))", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters, ignoring their order.\n\n Args:\n s0 (str): The first word.\n s1 (str): The second word.\n\n Returns:\n bool: True if the words have the same characters, False otherwise.\n \"\"\"\n # Convert both strings to sets to remove any duplicate characters and disregard order\n set0 = set(s0)\n set1 = set(s1)\n \n # Compare the two sets\n return set0 == set1", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str):\n \"\"\"\n Check if two words have the same characters.\n\n Args:\n s0 (str): The first word.\n s1 (str): The second word.\n\n Returns:\n bool: Whether the two words have the same characters.\n \"\"\"\n # Remove duplicates in each string and sort them\n s0_set = sorted(set(s0))\n s1_set = sorted(set(s1))\n \n # If the two strings have different lengths, they can't have the same characters\n if len(s0_set) != len(s1_set):\n return False\n \n # Check if the sorted sets are equal\n return s0_set == s1_set", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters, disregarding the order and number of repetitions.\n\n :param s0: The first string\n :param s1: The second string\n :return: True if the strings have the same characters, False otherwise\n \"\"\"\n # Convert both strings to sets, which automatically removes duplicates and ignores the order\n set0 = set(s0)\n set1 = set(s1)\n\n # Two sets are equal if and only if their intersection is the same as both sets\n return set0 == set1", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \n This function compares two strings character-wise. It removes all duplicate characters \n from each string, sorts them, and then compares the results.\n\n Args:\n s0 (str): The first string to compare.\n s1 (str): The second string to compare.\n\n Returns:\n bool: True if the strings have the same characters, False otherwise.\n \"\"\"\n # Remove duplicate characters from each string\n s0_set = set(s0)\n s1_set = set(s1)\n \n # Sort the resulting sets\n s0_sorted = sorted(s0_set)\n s1_sorted = sorted(s1_set)\n \n # Compare the sorted sets\n return s0_sorted == s1_sorted", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n\n Args:\n s0 (str): The first string.\n s1 (str): The second string.\n\n Returns:\n bool: True if both strings have the same characters (regardless of order), False otherwise.\n \"\"\"\n # Sort and remove duplicates from the strings and compare them\n return sorted(set(s0)) == sorted(set(s1))", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \n Args:\n s0 (str): The first word.\n s1 (str): The second word.\n \n Returns:\n bool: True if the words have the same characters, False otherwise.\n \"\"\"\n # Convert the input strings to sets of characters, which automatically removes duplicates\n set0 = set(s0)\n set1 = set(s1)\n \n # Check if the two sets are equal, i.e., if they have the same characters\n return set0 == set1", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \n Args:\n s0 (str): The first word.\n s1 (str): The second word.\n \n Returns:\n bool: True if both words have the same characters, False otherwise.\n \"\"\"\n # Convert the input strings to sets, which are unordered collections of unique elements\n # By comparing the sets, we can ignore the order of characters in the strings\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \n Args:\n s0 (str): The first string to compare.\n s1 (str): The second string to compare.\n \n Returns:\n bool: True if both strings have the same characters, False otherwise.\n \"\"\"\n # Convert both strings to a tuple of characters (since lists are not hashable and can't be added to a set)\n char_count0 = tuple(s0)\n char_count1 = tuple(s1)\n \n # Create a set from each tuple to count character occurrences\n set0 = set(char_count0)\n set1 = set(char_count1)\n \n # Check if both sets have the same characters\n return set0 == set1", "matching_cluster_idx": 5}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n\n Args:\n s0 (str): First word to compare.\n s1 (str): Second word to compare.\n\n Returns:\n bool: True if both words have the same characters, False otherwise.\n \"\"\"\n # Convert both strings to sets to remove duplicates and compare\n return sorted(set(s0)) == sorted(set(s1))", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str):\n \"\"\"\n Check if two words have the same characters.\n \n Args:\n s0 (str): The first word.\n s1 (str): The second word.\n \n Returns:\n bool: True if two words have the same characters, False otherwise.\n \"\"\"\n # Convert both strings to sets, which automatically remove duplicates\n # Sort the sets because the order of characters in the set does not matter\n # Compare the sorted sets\n return sorted(set(s0)) == sorted(set(s1))", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters, regardless of order and repetition.\n\n Args:\n s0 (str): First word.\n s1 (str): Second word.\n\n Returns:\n bool: True if the words have the same characters, False otherwise.\n \"\"\"\n # Remove duplicates from each string and compare\n return sorted(set(s0)) == sorted(set(s1))", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \n Args:\n s0 (str): The first word to compare.\n s1 (str): The second word to compare.\n \n Returns:\n bool: True if the two words have the same characters, False otherwise.\n \"\"\"\n \n # Remove duplicates from each word and sort them to create a signature\n signature0 = sorted(set(s0))\n signature1 = sorted(set(s1))\n \n # Compare the signatures\n return signature0 == signature1", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters, regardless of order.\n\n Args:\n s0 (str): The first string.\n s1 (str): The second string.\n\n Returns:\n bool: True if the strings have the same characters, False otherwise.\n \"\"\"\n # Remove duplicate characters from each string and sort them\n set0 = sorted(set(s0))\n set1 = sorted(set(s1))\n\n # Compare the two sets of unique characters\n return set0 == set1", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n\n Args:\n s0 (str): The first string.\n s1 (str): The second string.\n\n Returns:\n bool: True if the two strings have the same characters, False otherwise.\n \"\"\"\n # Remove duplicate characters from each string, sort the strings and compare them\n # This is done because the problem does not consider order of characters but only their existence\n return sorted(set(s0)) == sorted(set(s1))", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str):\n \"\"\"\n Check if two words have the same characters.\n Args:\n s0 (str): First word\n s1 (str): Second word\n Returns:\n bool: True if words have the same characters, False otherwise\n \"\"\"\n # Remove duplicate characters and sort the words\n s0 = sorted(set(s0))\n s1 = sorted(set(s1))\n\n # Compare sorted words\n return s0 == s1", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \n Args:\n s0 (str): First word.\n s1 (str): Second word.\n \n Returns:\n bool: True if the two words have the same characters, False otherwise.\n \"\"\"\n # Remove duplicates in each word and sort to get a unique count of characters\n set_s0 = sorted(set(s0))\n set_s1 = sorted(set(s1))\n \n # Compare the sorted lists of characters\n return set_s0 == set_s1", "matching_cluster_idx": 6}]}, "HumanEval/58": {"dps": 92.51968503937007, "dps_norm": 83.33333333333333, "pass@1": 99.0, "profiled": [{"solution": "def common(l1: list, l2: list):\n \"\"\"\n Return sorted unique common elements for two lists.\n\n Args:\n l1 (list): The first list of elements.\n l2 (list): The second list of elements.\n\n Returns:\n list: A sorted list of unique common elements.\n\n \"\"\"\n # Convert the lists to sets to remove duplicates and improve lookup efficiency\n set1 = set(l1)\n set2 = set(l2)\n\n # Find the intersection of the two sets to get common elements\n common_elements = set1.intersection(set2)\n\n # Convert the set back to a list, sort it, and return it\n return sorted(list(common_elements))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"\n Return sorted unique common elements for two lists.\n\n Args:\n l1 (list): The first list.\n l2 (list): The second list.\n\n Returns:\n list: Sorted unique common elements.\n \"\"\"\n # Convert lists to sets to remove duplicates and improve lookup efficiency\n set1 = set(l1)\n set2 = set(l2)\n\n # Use set intersection to find common elements and convert back to list\n common_elements = list(set1.intersection(set2))\n\n # Remove duplicates and sort the result\n common_elements = sorted(list(set(common_elements)))\n\n return common_elements", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list) -> list:\n \"\"\"\n Return sorted unique common elements for two lists.\n\n Args:\n l1 (list): The first list.\n l2 (list): The second list.\n\n Returns:\n list: A sorted list of unique common elements.\n \"\"\"\n # Use set intersection to find common elements, convert back to list, and sort\n common_elements = sorted(list(set(l1) & set(l2)))\n return common_elements", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list) -> list:\n \"\"\"\n Return sorted unique common elements for two lists.\n \n Args:\n l1 (list): The first list.\n l2 (list): The second list.\n \n Returns:\n list: A sorted list of unique common elements.\n \n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n # Convert lists to sets to remove duplicates and compare\n set1 = set(l1)\n set2 = set(l2)\n \n # Find the intersection of the two sets\n common_elements = set1 & set2\n \n # Convert back to list, sort, and remove duplicates\n common_elements = sorted(list(set(common_elements)))\n \n return common_elements", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list) -> list:\n \"\"\"\n Return sorted unique common elements for two lists.\n \n Args:\n l1 (list): The first list of elements.\n l2 (list): The second list of elements.\n \n Returns:\n list: A sorted list of unique common elements.\n \"\"\"\n # Convert both lists to sets to remove duplicates and improve lookup efficiency\n set1 = set(l1)\n set2 = set(l2)\n \n # Use set intersection to find the common elements\n common_elements = set1.intersection(set2)\n \n # Convert the set back to a list, sort it, and return the result\n return sorted(list(common_elements))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list) -> list:\n \"\"\"Return sorted unique common elements for two lists.\"\"\"\n return sorted(set(l1) & set(l2))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list) -> list:\n \"\"\"\n Return sorted unique common elements for two lists.\n\n Args:\n l1 (list): The first list.\n l2 (list): The second list.\n\n Returns:\n list: A sorted list of unique common elements from l1 and l2.\n\n \"\"\"\n # Convert the lists to sets to remove duplicates and improve lookup efficiency\n set1 = set(l1)\n set2 = set(l2)\n\n # Find the intersection of the two sets, which gives the common elements\n common_set = set1.intersection(set2)\n\n # Convert the set back to a list, sort it, and return the result\n return sorted(list(common_set))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"\n Return sorted unique common elements for two lists.\n\n Args:\n l1 (list): The first list of elements.\n l2 (list): The second list of elements.\n\n Returns:\n list: A sorted list of unique common elements.\n \"\"\"\n return sorted(set(l1) & set(l2))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list) -> list:\n \"\"\"\n Return sorted unique common elements for two lists.\n\n Args:\n l1 (list): The first list to compare.\n l2 (list): The second list to compare.\n\n Returns:\n list: A sorted list of unique common elements.\n \"\"\"\n # Convert lists to sets to remove duplicates and improve lookup efficiency\n set1 = set(l1)\n set2 = set(l2)\n\n # Use set intersection to find common elements\n common_elements = set1.intersection(set2)\n\n # Convert the result back to a list and sort it\n common_elements = sorted(list(common_elements))\n\n return common_elements", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list) -> list:\n \"\"\"\n Return sorted unique common elements for two lists.\n\n Args:\n l1 (list): The first list.\n l2 (list): The second list.\n\n Returns:\n list: A sorted list of unique elements common to both input lists.\n \"\"\"\n # Convert lists to sets to remove duplicates and improve lookup efficiency\n set1 = set(l1)\n set2 = set(l2)\n\n # Find common elements using set intersection\n common_elements = set1.intersection(set2)\n\n # Convert the set of common elements back to a list, sort it, and return\n return sorted(list(common_elements))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list) -> list:\n \"\"\"Return sorted unique common elements for two lists.\"\"\"\n # Convert lists to sets for efficient lookup\n set1 = set(l1)\n set2 = set(l2)\n \n # Find the intersection of two sets\n common_elements = set1.intersection(set2)\n \n # Convert set back to list and sort it\n common_elements = sorted(list(common_elements))\n \n return common_elements", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list) -> list:\n \"\"\"Return sorted unique common elements for two lists.\n\n Args:\n l1 (list): The first list.\n l2 (list): The second list.\n\n Returns:\n list: A sorted list of unique elements present in both l1 and l2.\n\n \"\"\"\n # Convert the lists to sets to find common elements and remove duplicates\n common_elements = set(l1).intersection(set(l2))\n \n # Convert the set back to a list and sort it\n common_elements = sorted(list(common_elements))\n \n return common_elements", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list) -> list:\n \"\"\"Return sorted unique common elements for two lists.\"\"\"\n # Convert lists to sets to remove duplicates and improve lookup efficiency\n set1 = set(l1)\n set2 = set(l2)\n \n # Find the intersection of the two sets, which are the common elements\n common_elements = set1.intersection(set2)\n \n # Convert the set of common elements back to a list and sort it\n common_list = sorted(list(common_elements))\n \n return common_list", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list) -> list:\n \"\"\"\n Return sorted unique common elements for two lists.\n\n Args:\n l1 (list): First input list.\n l2 (list): Second input list.\n\n Returns:\n list: A sorted list of unique common elements.\n \"\"\"\n # Convert lists to sets to remove duplicates and improve lookup efficiency\n set1 = set(l1)\n set2 = set(l2)\n\n # Find intersection of the two sets\n common_elements = set1.intersection(set2)\n\n # Convert the set back to a sorted list\n common_elements = sorted(list(common_elements))\n\n return common_elements", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list) -> list:\n \"\"\"\n Return sorted unique common elements for two lists.\n\n Args:\n l1 (list): The first list.\n l2 (list): The second list.\n\n Returns:\n list: A sorted list of unique common elements.\n\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n # Convert the input lists to sets to remove duplicates and have O(1) lookup time\n set1 = set(l1)\n set2 = set(l2)\n\n # Find the intersection of the two sets (common elements)\n common_set = set1.intersection(set2)\n\n # Convert the set back to a list, sort it, and return it\n return sorted(list(common_set))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list) -> list:\n \"\"\"\n Return sorted unique common elements for two lists.\n\n Args:\n l1 (list): The first list of elements.\n l2 (list): The second list of elements.\n\n Returns:\n list: A list of unique common elements from both input lists, sorted in ascending order.\n\n Examples:\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n\n # Convert lists to sets to remove duplicates and improve lookup efficiency\n set1 = set(l1)\n set2 = set(l2)\n\n # Find the intersection of the two sets\n common_elements = set1.intersection(set2)\n\n # Convert the set of common elements back to a list and sort it\n common_elements = sorted(list(common_elements))\n\n return common_elements", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"\n Return sorted unique common elements for two lists.\n\n Args:\n l1 (list): The first list.\n l2 (list): The second list.\n\n Returns:\n list: A list of sorted unique elements common to both input lists.\n\n Example:\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n return sorted(set(l1) & set(l2))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"\n Return sorted unique common elements for two lists.\n\n Args:\n l1 (list): First list of elements.\n l2 (list): Second list of elements.\n\n Returns:\n list: Sorted list of unique common elements.\n\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n # Convert the lists to sets to remove duplicates and improve lookup efficiency\n set1 = set(l1)\n set2 = set(l2)\n\n # Find the intersection of the two sets (common elements)\n common_elements = set1 & set2\n\n # Convert the set back to a list and sort it\n result = sorted(list(common_elements))\n\n return result", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list) -> list:\n \"\"\"\n Return sorted unique common elements for two lists.\n\n Args:\n l1 (list): The first list.\n l2 (list): The second list.\n\n Returns:\n list: A sorted list of unique common elements.\n\n Examples:\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n # Convert both lists to sets to eliminate duplicates and improve lookup efficiency\n set1 = set(l1)\n set2 = set(l2)\n\n # Find the intersection of the two sets\n common_elements = set1 & set2\n\n # Convert the set of common elements back to a list and sort it\n result = sorted(list(common_elements))\n\n return result", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"\n Return sorted unique common elements for two lists.\n \n Args:\n l1 (list): The first list.\n l2 (list): The second list.\n \n Returns:\n list: A sorted list of unique elements common to both input lists.\n \"\"\"\n # Convert the lists to sets to remove duplicates and improve lookup efficiency\n set1 = set(l1)\n set2 = set(l2)\n \n # Find the intersection of the two sets (i.e., elements common to both)\n common_elements = set1 & set2\n \n # Convert the result back to a list and sort it\n result = sorted(list(common_elements))\n \n return result", "matching_cluster_idx": 4}]}, "HumanEval/59": {"dps": 77.86458333333333, "dps_norm": 83.33333333333333, "pass@1": 73.0, "profiled": [{"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"\n Return the largest prime factor of n. Assume n > 1 and is not a prime.\n \"\"\"\n # Start from 2, the smallest prime number\n i = 2\n \n # Loop through all numbers up to the square root of n\n while i * i <= n:\n # If n is divisible by i, then i is a factor of n\n if n % i:\n # If n is not divisible by i, increment i by 1\n i += 1\n else:\n # If n is divisible by i, update n and increment i by 1\n n //= i\n i = 2\n \n # At this point, n is the largest prime factor of the original number\n return n", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"\n Return the largest prime factor of n. Assume n > 1 and is not a prime.\n\n Args:\n n (int): A composite integer.\n\n Returns:\n int: The largest prime factor of n.\n \"\"\"\n # Start from 2 and check for divisibility of n\n i = 2\n # Continue this loop until n is no longer divisible by i\n while i * i <= n:\n if n % i:\n # If i doesn't divide n, increment by 1\n i += 1\n else:\n # If i divides n, n becomes n divided by i\n n //= i\n # At the end of the loop, n will be the largest prime factor\n return n", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"\n Return the largest prime factor of n. Assume n > 1 and is not a prime.\n\n Args:\n n (int): A positive integer greater than 1 that is not a prime.\n\n Returns:\n int: The largest prime factor of n.\n\n Raises:\n ValueError: If n is not a positive integer or less than or equal to 1.\n\n Examples:\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n # Check if n is a positive integer\n if not isinstance(n, int) or n <= 1:\n raise ValueError(\"n must be a positive integer\")\n\n # Start from the smallest prime number\n i = 2\n # Continue the loop until we find a prime factor or we've reached the square root of n\n while i * i <= n:\n # If n is divisible by i, then i is a prime factor\n if n % i:\n # If n is not divisible by i, increment i\n i += 1\n else:\n # If n is divisible by i, update n and increment i\n n //= i\n # At this point, n is a prime number and is the largest prime factor\n return n", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\"\"\"\n \n def is_prime(num: int) -> bool:\n \"\"\"Check if a number is prime.\"\"\"\n if num < 2:\n return False\n for i in range(2, int(num ** 0.5) + 1):\n if num % i == 0:\n return False\n return True\n\n # Initialize the largest factor\n largest_factor = 1\n \n # Iterate through all numbers up to n\n for i in range(2, n + 1):\n # Check if i is a factor of n and is prime\n while n % i == 0 and is_prime(i):\n largest_factor = i\n n = n // i\n \n return largest_factor", "matching_cluster_idx": 2}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"\n Return the largest prime factor of n. Assume n > 1 and is not a prime.\n\n Args:\n n (int): A positive integer.\n\n Returns:\n int: The largest prime factor of n.\n\n Examples:\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n i = 2\n while i * i <= n:\n if n % i:\n i += 1\n else:\n n //= i\n return n", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"\n Return the largest prime factor of n. \n Assume n > 1 and is not a prime.\n\n Args:\n n (int): A positive integer greater than 1.\n\n Returns:\n int: The largest prime factor of n.\n\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n def is_prime(num: int) -> bool:\n \"\"\"Check if a number is prime.\"\"\"\n if num < 2:\n return False\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n return False\n return True\n\n largest_factor = n\n for i in range(2, int(n**0.5) + 1):\n while n % i == 0 and is_prime(i):\n largest_factor = i\n n //= i\n if n > 1 and is_prime(n):\n largest_factor = n\n return largest_factor", "matching_cluster_idx": 8}, {"solution": "import unittest\ndef largest_prime_factor(n: int) -> int:\n \"\"\"\n Return the largest prime factor of n.\n \n Args:\n n: An integer greater than 1 and not a prime.\n \n Returns:\n The largest prime factor of n.\n \"\"\"\n def is_prime(num: int) -> bool:\n \"\"\"Check if a number is prime.\"\"\"\n if num < 2:\n return False\n for i in range(2, int(num ** 0.5) + 1):\n if num % i == 0:\n return False\n return True\n\n max_factor = 2\n for i in range(2, n):\n if n % i == 0 and is_prime(i):\n max_factor = i\n return max_factor", "matching_cluster_idx": 2}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"\n Return the largest prime factor of n. Assume n > 1 and is not a prime.\n\n Args:\n n (int): Input number\n\n Returns:\n int: The largest prime factor of n\n \"\"\"\n i = 2\n while i * i <= n:\n if n % i:\n i += 1\n else:\n n //= i\n return n", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"\n Return the largest prime factor of n. Assume n > 1 and is not a prime.\n\n Args:\n n (int): The number to find the largest prime factor for.\n\n Returns:\n int: The largest prime factor of n.\n \"\"\"\n def is_prime(num: int) -> bool:\n \"\"\"Check if a number is prime.\"\"\"\n if num < 2:\n return False\n for i in range(2, int(num ** 0.5) + 1):\n if num % i == 0:\n return False\n return True\n\n largest_factor = 1\n i = 2\n while i * i <= n:\n if n % i:\n i += 1\n else:\n n //= i\n largest_factor = i\n if n > 1:\n largest_factor = n\n return largest_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"\n Returns the largest prime factor of n. Assume n > 1 and is not a prime.\n \n :param n: The input number.\n :return: The largest prime factor of n.\n \"\"\"\n\n # Start checking from 2, the smallest prime number\n i = 2\n\n # Continue checking until i * i > n\n # This is because a larger factor of n must be a multiple of a smaller factor that has already been checked\n while i * i <= n:\n # If n is divisible by i, then i is a factor of n\n if n % i:\n # If n is not divisible by i, increment i by 1\n i += 1\n else:\n # If n is divisible by i, divide n by i\n n //= i\n\n # At this point, n is the largest prime factor\n return n", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"\n Return the largest prime factor of n. \n Assume n > 1 and is not a prime.\n\n :param n: A composite integer.\n :return: The largest prime factor of n.\n \"\"\"\n i = 2\n while i * i <= n:\n if n % i:\n i += 1\n else:\n n //= i\n return n", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"\n Return the largest prime factor of n. Assume n > 1 and is not a prime.\n\n :param n: An integer greater than 1\n :return: The largest prime factor of n\n \"\"\"\n i = 2\n while i * i <= n:\n if n % i:\n i += 1\n else:\n n //= i\n return n", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"\n Return the largest prime factor of n.\n Assume n > 1 and is not a prime.\n\n :param n: Input number\n :return: Largest prime factor\n \"\"\"\n i = 2\n while i * i <= n:\n if n % i:\n i += 1\n else:\n n //= i\n return n", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"\n Return the largest prime factor of n. \n Assume n > 1 and is not a prime.\n\n :param n: The number for which to find the largest prime factor.\n :return: The largest prime factor of n.\n \"\"\"\n def is_prime(num: int) -> bool:\n \"\"\"\n Check if a number is prime.\n\n :param num: The number to check for primality.\n :return: True if num is prime, False otherwise.\n \"\"\"\n if num < 2:\n return False\n for i in range(2, int(num ** 0.5) + 1):\n if num % i == 0:\n return False\n return True\n\n for i in range(n - 1, 1, -1):\n if n % i == 0 and is_prime(i):\n return i\n return None", "matching_cluster_idx": 2}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"\n Return the largest prime factor of n. Assume n > 1 and is not a prime.\n \n Args:\n n (int): The input number, expected to be greater than 1 and not prime.\n \n Returns:\n int: The largest prime factor of the input number.\n \"\"\"\n # Start checking from the largest divisor, i.e., sqrt(n)\n i = 2\n while i * i <= n:\n if n % i: # If n is not divisible by i\n i += 1\n else: # If n is divisible by i, i is a factor of n\n n //= i\n # At this point, n is the largest prime factor of the original number\n return n", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"\n Return the largest prime factor of n. Assume n > 1 and is not a prime.\n\n Args:\n n (int): Input number.\n\n Returns:\n int: The largest prime factor of n.\n \"\"\"\n i = 2\n while i * i <= n:\n if n % i:\n i += 1\n else:\n n //= i\n return n", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"\n Return the largest prime factor of n. \n Assume n > 1 and is not a prime.\n\n Args:\n n (int): A positive integer greater than 1.\n\n Returns:\n int: The largest prime factor of n.\n \"\"\"\n def is_prime(num: int) -> bool:\n \"\"\"Check if a number is prime.\"\"\"\n if num < 2:\n return False\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n return False\n return True\n\n max_factor = 2\n for i in range(2, n + 1):\n if n % i == 0 and is_prime(i):\n max_factor = max(max_factor, i)\n\n return max_factor", "matching_cluster_idx": 2}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"\n Return the largest prime factor of n.\n \n Parameters:\n n (int): An integer greater than 1 and not a prime number.\n \n Returns:\n int: The largest prime factor of n.\n \n Examples:\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n i = 2\n while i * i <= n:\n if n % i:\n i += 1\n else:\n n //= i\n return n", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"\n Returns the largest prime factor of n.\n \n Args:\n n: An integer greater than 1.\n \n Returns:\n An integer, the largest prime factor of n.\n \"\"\"\n i = 2\n while i * i <= n:\n if n % i:\n i += 1\n else:\n n //= i\n return n", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"\n Return the largest prime factor of n. \n Assume n > 1 and is not a prime.\n \n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n \n def is_prime(x: int) -> bool:\n \"\"\"Check if a number is prime.\"\"\"\n if x < 2:\n return False\n for i in range(2, int(x ** 0.5) + 1):\n if x % i == 0:\n return False\n return True\n\n max_prime_factor = 1\n for i in range(2, n + 1):\n if n % i == 0 and is_prime(i):\n max_prime_factor = max(max_prime_factor, i)\n return max_prime_factor", "matching_cluster_idx": 2}]}, "HumanEval/64": {"dps": null, "dps_norm": null, "pass@1": 9.0, "profiled": []}, "HumanEval/74": {"dps": 93.46341463414635, "dps_norm": 87.77777777777777, "pass@1": 98.0, "profiled": [{"solution": "def total_match(lst1, lst2):\n '''\n Returns the list that has total number of chars in the all strings of the list less than the other list.\n If the two lists have the same number of chars, return the first list.\n\n Args:\n lst1 (list): The first list of strings\n lst2 (list): The second list of strings\n\n Returns:\n list: The list with the least total characters\n '''\n return min([lst1, lst2, lst1 if len(lst1) == len(lst2) else lst2], key=lambda x: sum(len(s) for s in x))", "matching_cluster_idx": 5}, {"solution": "def total_match(lst1, lst2):\n \"\"\"\n This function compares the total number of characters in each string of two lists and returns \n the list with the total characters less than the other list. If both lists have the same total \n number of characters, it returns the first list.\n\n Parameters:\n lst1 (list): The first list of strings\n lst2 (list): The second list of strings\n\n Returns:\n list: The list with total characters less than the other list\n \"\"\"\n\n # Calculate the total number of characters in each list\n total1 = sum(len(s) for s in lst1)\n total2 = sum(len(s) for s in lst2)\n\n # Return the list with less total characters or the first list if totals are equal\n return lst1 if total1 <= total2 else lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n \"\"\"\n Compare two lists of strings to return the list that has a total number of characters \n in all strings less than the other list. If the two lists have the same number of characters, \n return the first list.\n\n Args:\n lst1 (list): The first list of strings.\n lst2 (list): The second list of strings.\n\n Returns:\n list: The list with a total number of characters less than the other list.\n\n Examples:\n total_match([], []) == []\n total_match(['hi', 'admin'], ['hI', 'Hi']) == ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) == ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) == ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) == ['4']\n \"\"\"\n # Calculate the total number of characters in each list\n total1 = sum(len(string) for string in lst1)\n total2 = sum(len(string) for string in lst2)\n\n # Compare the totals and return the list with fewer characters\n if total1 <= total2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n \"\"\"\n Returns the list that has the total number of characters less than the other list.\n\n If the two lists have the same number of characters, returns the first list.\n\n Args:\n lst1 (list): The first list of strings.\n lst2 (list): The second list of strings.\n\n Returns:\n list: The list with less total characters.\n \"\"\"\n\n # Calculate the total number of characters in each list\n total_chars_lst1 = sum(len(s) for s in lst1)\n total_chars_lst2 = sum(len(s) for s in lst2)\n\n # Compare the total number of characters in each list\n if total_chars_lst1 <= total_chars_lst2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Returns the list that has total number of chars in the all strings of the list less than the other list.\n If the two lists have the same number of chars, return the first list.\n \n Parameters:\n lst1 (list): First list of strings.\n lst2 (list): Second list of strings.\n \n Returns:\n list: List with total number of chars less than the other list.\n '''\n \n # Calculate the total number of characters in each list\n total_chars1 = sum(len(string) for string in lst1)\n total_chars2 = sum(len(string) for string in lst2)\n \n # Compare the total number of characters in each list\n if total_chars1 < total_chars2:\n return lst1\n elif total_chars2 < total_chars1:\n return lst2\n else:\n # If the total number of characters is the same, return the first list\n return lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Returns the list that has total number of chars in the all strings of the list less than the other list.\n If the two lists have the same number of chars, return the first list.\n \n Args:\n lst1 (list): The first list of strings.\n lst2 (list): The second list of strings.\n \n Returns:\n list: The list that has total number of chars in the all strings of the list less than the other list.\n '''\n \n # Calculate the total characters in each list\n total_chars_lst1 = sum(len(s) for s in lst1)\n total_chars_lst2 = sum(len(s) for s in lst2)\n \n # Compare the total characters in both lists\n if total_chars_lst1 <= total_chars_lst2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n \"\"\"\n Returns the list with the total number of chars in the strings less than the other list.\n If the two lists have the same number of chars, returns the first list.\n\n Parameters:\n lst1 (list): The first list of strings\n lst2 (list): The second list of strings\n\n Returns:\n list: The list with the total number of chars in the strings less than the other list\n \"\"\"\n # Calculate the total number of characters in each list\n total1 = sum(len(s) for s in lst1)\n total2 = sum(len(s) for s in lst2)\n\n # Compare the total number of characters in each list and return the list with the smaller total\n if total1 <= total2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Returns the list with the total number of characters less than the other list.\n If both lists have the same total number of characters, returns the first list.\n \n Parameters:\n lst1 (list): The first list of strings\n lst2 (list): The second list of strings\n \n Returns:\n list: The list with the total number of characters less than the other list\n '''\n \n # Calculate total number of characters in each list\n total_chars_lst1 = sum(len(s) for s in lst1)\n total_chars_lst2 = sum(len(s) for s in lst2)\n \n # Return the list with less total characters\n if total_chars_lst1 <= total_chars_lst2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n \"\"\"\n This function compares two lists of strings and returns the list with the total \n number of characters in all strings less than the other list. If the two lists \n have the same total number of characters, it returns the first list.\n\n Parameters:\n lst1 (list): The first list of strings\n lst2 (list): The second list of strings\n\n Returns:\n list: The list with the total number of characters less than the other list.\n \"\"\"\n # Calculate the total number of characters in each list\n total1 = sum(len(s) for s in lst1)\n total2 = sum(len(s) for s in lst2)\n\n # Compare the totals and return the list with less total characters\n if total1 < total2:\n return lst1\n elif total2 < total1:\n return lst2\n else:\n return lst1 # If totals are equal, return the first list", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n This function compares two lists of strings by their total number of characters and returns \n the list with the total number of chars less than the other list. If the two lists have \n the same number of chars, it returns the first list.\n\n Args:\n lst1 (list): The first list of strings.\n lst2 (list): The second list of strings.\n\n Returns:\n list: The list with the total number of chars less than the other list.\n '''\n # Calculate total number of chars in each list\n total_chars_lst1 = sum(len(string) for string in lst1)\n total_chars_lst2 = sum(len(string) for string in lst2)\n\n # Determine which list has the total number of chars less than the other list\n if total_chars_lst1 < total_chars_lst2:\n return lst1\n elif total_chars_lst2 < total_chars_lst1:\n return lst2\n else:\n # If the two lists have the same number of chars, return the first list\n return lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Returns the list with total number of chars in all strings less than the other list.\n If the two lists have the same number of chars, returns the first list.\n\n Args:\n lst1 (list): The first list of strings.\n lst2 (list): The second list of strings.\n\n Returns:\n list: The list with total number of chars in all strings less than the other list.\n '''\n def total_chars(lst):\n # Function to calculate total number of chars in a list of strings.\n return sum(len(s) for s in lst)\n\n # Calculate total number of chars in each list.\n total1 = total_chars(lst1)\n total2 = total_chars(lst2)\n\n # Return the list with fewer total characters.\n if total1 <= total2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Return the list with the total number of characters less than the other list.\n\n If both lists have the same number of characters, return the first list.\n\n Args:\n lst1 (list): The first list of strings.\n lst2 (list): The second list of strings.\n\n Returns:\n list: The list with the total number of characters less than the other list.\n '''\n total_chars_lst1 = sum(len(s) for s in lst1)\n total_chars_lst2 = sum(len(s) for s in lst2)\n\n if total_chars_lst1 <= total_chars_lst2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n \"\"\"\n Returns the list with the total number of characters less than the other list.\n If the two lists have the same number of characters, returns the first list.\n\n Parameters:\n lst1 (list): The first list of strings\n lst2 (list): The second list of strings\n\n Returns:\n list: The list with the total number of characters less than the other list\n \"\"\"\n # Calculate the total number of characters in each list\n total_chars_lst1 = sum(len(item) for item in lst1)\n total_chars_lst2 = sum(len(item) for item in lst2)\n\n # Return the list with the total number of characters less than the other list\n if total_chars_lst1 < total_chars_lst2:\n return lst1\n elif total_chars_lst2 < total_chars_lst1:\n return lst2\n else:\n return lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Returns the list with total characters less than the other list.\n If the two lists have the same number of characters, return the first list.\n \n Parameters:\n lst1 (list): The first list of strings.\n lst2 (list): The second list of strings.\n \n Returns:\n list: The list with total characters less than the other list.\n '''\n \n # Calculate total characters in each list\n total1 = sum(len(item) for item in lst1)\n total2 = sum(len(item) for item in lst2)\n \n # Compare total characters and return the list with less total characters\n if total1 <= total2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n This function compares the total number of characters in all strings of two lists.\n It returns the list with the total number of characters less than the other list.\n If the total number of characters is the same, it returns the first list.\n\n Parameters:\n lst1 (list): The first list of strings\n lst2 (list): The second list of strings\n\n Returns:\n list: The list with the total number of characters less than the other list\n '''\n # Calculate total number of characters in each list\n total1 = sum(len(s) for s in lst1)\n total2 = sum(len(s) for s in lst2)\n\n # Return the list with the total number of characters less\n if total1 <= total2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Returns the list with the total number of characters in the strings less than the other list.\n If the two lists have the same number of characters, returns the first list.\n\n Args:\n lst1 (list): The first list of strings.\n lst2 (list): The second list of strings.\n\n Returns:\n list: The list with the total number of characters in the strings less than the other list.\n '''\n total_chars_list1 = sum(len(s) for s in lst1)\n total_chars_list2 = sum(len(s) for s in lst2)\n\n if total_chars_list1 <= total_chars_list2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Returns the list with the total number of characters less than the other.\n If both lists have the same total number of characters, return the first list.\n\n Args:\n lst1 (list): The first list of strings\n lst2 (list): The second list of strings\n\n Returns:\n list: The list with the total number of characters less than the other\n '''\n return lst1 if sum(len(s) for s in lst1) <= sum(len(s) for s in lst2) else lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n \"\"\"\n This function compares two lists of strings and returns the list with the total number of characters less than the other list.\n\n If both lists have the same number of characters, it returns the first list.\n\n Args:\n lst1 (list): The first list of strings.\n lst2 (list): The second list of strings.\n\n Returns:\n list: The list with the total number of characters less than the other list.\n \"\"\"\n # Calculate the total number of characters in each list\n total_chars_lst1 = sum(len(s) for s in lst1)\n total_chars_lst2 = sum(len(s) for s in lst2)\n\n # Return the list with the total number of characters less than the other list\n if total_chars_lst1 < total_chars_lst2:\n return lst1\n elif total_chars_lst2 < total_chars_lst1:\n return lst2\n else:\n return lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n This function compares two lists of strings and returns the list that has \n total number of chars in the all strings of the list less than the other list.\n \n If the two lists have the same number of chars, return the first list.\n \n Args:\n lst1 (list): The first list of strings\n lst2 (list): The second list of strings\n \n Returns:\n list: The list with fewer total characters\n '''\n \n # Calculate the total number of characters in each list\n total_chars_lst1 = sum(len(s) for s in lst1)\n total_chars_lst2 = sum(len(s) for s in lst2)\n \n # Return the list with fewer total characters\n if total_chars_lst1 < total_chars_lst2:\n return lst1\n elif total_chars_lst2 < total_chars_lst1:\n return lst2\n else:\n return lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Returns the list with the total number of characters less than the other list.\n If the lists have the same number of characters, returns the first list.\n\n Args:\n lst1 (list): The first list of strings.\n lst2 (list): The second list of strings.\n\n Returns:\n list: The list with the total number of characters less than the other list.\n '''\n # Calculate the total number of characters in each list\n total1 = sum(len(s) for s in lst1)\n total2 = sum(len(s) for s in lst2)\n\n # Compare the totals and return the list with the fewest characters\n if total1 <= total2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}]}, "HumanEval/85": {"dps": 84.33168316831683, "dps_norm": 50.833333333333336, "pass@1": 96.0, "profiled": [{"solution": "def add(lst):\n \"\"\"\n Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Args:\n lst (list): A non-empty list of integers\n\n Returns:\n int: The sum of even elements at odd indices\n \"\"\"\n return sum(num for i, num in enumerate(lst) if i % 2 != 0 and num % 2 == 0)", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"\n Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Args:\n lst (list): A non-empty list of integers.\n\n Returns:\n int: The sum of even elements at odd indices in the list.\n\n Examples:\n >>> add([4, 2, 6, 7])\n 2\n \"\"\"\n return sum(num for i, num in enumerate(lst) if i % 2 != 0 and num % 2 == 0)", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"\n Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Args:\n lst (list): A list of integers.\n\n Returns:\n int: The sum of even elements at odd indices.\n\n Examples:\n >>> add([4, 2, 6, 7])\n 2\n >>> add([10, 9, 15, 1, 5])\n 0\n >>> add([16, 12, 8, 7, 3])\n 28\n \"\"\"\n return sum(num for i, num in enumerate(lst) if i % 2 != 0 and num % 2 == 0)", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices.\n \n Args:\n lst (list): A list of integers.\n \n Returns:\n int: The sum of even elements at odd indices.\n \n Examples:\n add([4, 2, 6, 7]) == 2\n \"\"\"\n return sum(num for idx, num in enumerate(lst) if idx % 2 != 0 and num % 2 == 0)", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"\n Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Args:\n lst (list): A list of integers.\n\n Returns:\n int: The sum of even elements at odd indices.\n\n Examples:\n >>> add([4, 2, 6, 7])\n 2\n \"\"\"\n return sum(i for i in lst[1::2] if i % 2 == 0)", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"\n Given a non-empty list of integers lst. add the even elements that are at odd indices.\n\n Args:\n lst (list): A non-empty list of integers\n\n Returns:\n int: Sum of even elements at odd indices\n\n Examples:\n add([4, 2, 6, 7]) == 2\n \"\"\"\n return sum(num for i, num in enumerate(lst) if i % 2 != 0 and num % 2 == 0)", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"\n Given a non-empty list of integers lst, adds the even elements that are at odd indices.\n\n Args:\n lst (list): A non-empty list of integers.\n\n Returns:\n int: The sum of even elements at odd indices.\n\n Examples:\n >>> add([4, 2, 6, 7])\n 8\n \"\"\"\n return sum(x for i, x in enumerate(lst) if i % 2 != 0 and x % 2 == 0)", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"\n Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Args:\n lst (list): A non-empty list of integers.\n\n Returns:\n int: The sum of even elements at odd indices.\n\n Examples:\n >>> add([4, 2, 6, 7])\n 2\n \"\"\"\n # Use list comprehension to filter elements at odd indices that are even\n even_odd_sum = sum([num for i, num in enumerate(lst) if i % 2 != 0 and num % 2 == 0])\n return even_odd_sum", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"\n Given a non-empty list of integers lst. \n Adds the even elements that are at odd indices.\n\n Args:\n lst (list): A list of integers.\n\n Returns:\n int: The sum of even elements at odd indices.\n\n Examples:\n >>> add([4, 2, 6, 7])\n 2\n \"\"\"\n # Use list comprehension to filter even elements at odd indices, and sum them up\n return sum(num for i, num in enumerate(lst) if i % 2 != 0 and num % 2 == 0)", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"\n Given a non-empty list of integers lst. Add the even elements that are at odd indices.\n\n Args:\n lst (list): A non-empty list of integers.\n\n Returns:\n int: The sum of even elements at odd indices.\n\n Examples:\n >>> add([4, 2, 6, 7])\n 2\n \"\"\"\n # Initialize sum variable to 0\n total = 0\n # Iterate over the list with index\n for i in range(len(lst)):\n # Check if the index is odd and the element is even\n if i % 2 != 0 and lst[i] % 2 == 0:\n # Add the even element to the sum\n total += lst[i]\n return total", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"\n Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Args:\n lst (list): A list of integers\n\n Returns:\n int: The sum of even elements at odd indices\n \"\"\"\n return sum(num for i, num in enumerate(lst) if i % 2 != 0 and num % 2 == 0)", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. Add the even elements that are at odd indices.\n\n Args:\n lst (list): A non-empty list of integers.\n\n Returns:\n int: The sum of the even elements at odd indices.\n\n Examples:\n >>> add([4, 2, 6, 7])\n 2\n \"\"\"\n return sum([lst[i] for i in range(len(lst)) if (i % 2 != 0) and (lst[i] % 2 == 0)])", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"\n Given a non-empty list of integers lst. \n Returns the sum of the even elements that are at odd indices.\n\n Examples:\n >>> add([4, 2, 6, 7])\n 8\n\n :param lst: A non-empty list of integers.\n :return: The sum of the even elements at odd indices in the list.\n \"\"\"\n return sum(num for i, num in enumerate(lst) if i % 2 != 0 and num % 2 == 0)", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"\n Given a non-empty list of integers lst. \n Add the even elements that are at odd indices.\n\n Args:\n lst (list): A non-empty list of integers.\n\n Returns:\n int: The sum of the even elements at odd indices.\n\n Examples:\n >>> add([4, 2, 6, 7])\n 2\n \"\"\"\n return sum(num for i, num in enumerate(lst) if i % 2 != 0 and num % 2 == 0)", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"\n Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Args:\n lst (list): A list of integers.\n\n Returns:\n int: The sum of even elements at odd indices.\n\n Examples:\n >>> add([4, 2, 6, 7])\n 2\n \"\"\"\n return sum(num for i, num in enumerate(lst) if i % 2 != 0 and num % 2 == 0)", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"\n Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Args:\n lst (list): A list of integers.\n\n Returns:\n int: The sum of even elements at odd indices.\n\n Examples:\n >>> add([4, 2, 6, 7])\n 2\n \"\"\"\n return sum(num for i, num in enumerate(lst) if i % 2 != 0 and num % 2 == 0)", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"\n Given a non-empty list of integers lst. \n Add the even elements that are at odd indices.\n\n Args:\n lst (list): A non-empty list of integers\n\n Returns:\n int: The sum of even elements at odd indices\n\n Examples:\n >>> add([4, 2, 6, 7])\n 2\n \"\"\"\n return sum(num for i, num in enumerate(lst) if i % 2 != 0 and num % 2 == 0)", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"\n Given a non-empty list of integers lst. add the even elements that are at odd indices.\n\n Args:\n lst (list): A non-empty list of integers.\n\n Returns:\n int: The sum of even elements at odd indices in the list.\n\n Examples:\n >>> add([4, 2, 6, 7])\n 2\n \"\"\"\n return sum(num for i, num in enumerate(lst) if i % 2 != 0 and num % 2 == 0)", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"\n Given a non-empty list of integers lst. Add the even elements that are at odd indices.\n\n Args:\n lst (list): A non-empty list of integers.\n\n Returns:\n int: The sum of the even elements at odd indices in the list.\n\n Examples:\n >>> add([4, 2, 6, 7])\n 2\n \"\"\"\n return sum(num for i, num in enumerate(lst) if i % 2 != 0 and num % 2 == 0)", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Args:\n lst (list): A non-empty list of integers.\n\n Returns:\n int: The sum of even elements at odd indices.\n\n Examples:\n >>> add([4, 2, 6, 7])\n 2\n >>> add([10, 20, 30, 40, 50])\n 70\n \"\"\"\n return sum(num for i, num in enumerate(lst) if i % 2 != 0 and num % 2 == 0)", "matching_cluster_idx": 2}]}, "HumanEval/86": {"dps": null, "dps_norm": null, "pass@1": 9.0, "profiled": []}, "HumanEval/87": {"dps": 94.22190201729107, "dps_norm": 58.57142857142858, "pass@1": 55.0, "profiled": [{"solution": "def get_row(lst, x):\n \"\"\"\n Finds coordinates of integer x in a 2D list and returns them as a list of tuples.\n\n Args:\n lst (list): A 2D list of integers.\n x (int): The target integer to find in the list.\n\n Returns:\n list: A list of tuples, each containing the row and column index of the found integer.\n \"\"\"\n result = []\n for i, row in enumerate(lst):\n # Filter out elements not equal to x\n indices = [j for j, elem in enumerate(row) if elem == x]\n # Add (row, column) tuples to the result list\n result.extend([(i, idx) for idx in indices])\n # Sort by row first, then by column in descending order\n return sorted(result, key=lambda t: (t[0], -t[1]))", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n Find coordinates of x in the list of lists, \n and return a list of tuples, sorted by row and then by column in descending order.\n\n Args:\n lst (list): A list of lists containing integers\n x (int): The integer to find in the list\n\n Returns:\n list: A list of tuples, each tuple contains a coordinate (row, column)\n \"\"\"\n\n # Combine all the coordinates of x in the list into a list of tuples\n coordinates = [(row_i, col_i) for row_i, row in enumerate(lst) \n for col_i, val in enumerate(row) if val == x]\n \n # Sort the coordinates by row in ascending order and then by column in descending order\n sorted_coordinates = sorted(coordinates, key=lambda coord: (coord[0], -coord[1]))\n \n return sorted_coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n This function finds integers x in a given 2D list (similar to matrix) and returns\n a list of tuples representing coordinates (row, column) of x in the list.\n \n Args:\n lst (list): 2D list of integers\n x (int): Integer to search for\n \n Returns:\n list: List of tuples representing (row, column) coordinates of x in lst\n \"\"\"\n \n # Flatten the 2D list, filter for x, and combine row and column indices into tuples\n coordinates = [(i, j) for i, row in enumerate(lst) for j, value in enumerate(row) if value == x]\n \n # Sort coordinates by row in ascending order and by column in descending order\n coordinates.sort(key=lambda t: (t[0], -t[1]))\n \n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n This function searches through a given 2D list for occurrences of a given number,\n and returns a list of tuples representing the coordinates (row, column) of these occurrences.\n \n Args:\n lst (list): A 2D list of integers.\n x (int): The number to be searched.\n \n Returns:\n list: A list of tuples representing the coordinates of the number x.\n \"\"\"\n \n # Initialize an empty list to store the coordinates\n coordinates = []\n \n # Iterate over the indices and values of the input list\n for i, row in enumerate(lst):\n # Find the indices of x in the current row\n j = [j for j, val in enumerate(row) if val == x]\n \n # If x exists in the row, add the coordinates to the list\n if j:\n # Sort the indices in descending order\n j.sort(reverse=True)\n # Add the coordinates to the list\n coordinates.extend([(i, idx) for idx in j])\n \n # Sort the coordinates by row and then by column\n coordinates.sort(key=lambda tup: (tup[0], -tup[1]))\n \n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n coordinates = [(i, j) for i, row in enumerate(lst) for j, val in enumerate(row) if val == x]\n coordinates.sort(key=lambda x: (x[0], -x[1]))\n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n Returns a list of tuples (row, col) representing the positions of the integer x in the list,\n sorted by row in ascending order and then by column in descending order.\n\n Args:\n lst (list): A 2D list of integers\n x (int): The integer to search for\n\n Returns:\n list: A list of tuples representing the positions of x in the list\n \"\"\"\n result = [(r, c) for r, row in enumerate(lst) for c, val in enumerate(row) if val == x]\n return sorted(result, key=lambda t: (t[0], -t[1]))", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n Find integers x in the list and return list of tuples, [(x1, y1), (x2, y2) ...]\n such that each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n\n Args:\n lst (list): A 2 dimensional data, which is similar to matrix\n but each row may contain a different number of columns.\n x (int): The integer to search for in the list.\n\n Returns:\n list: List of tuples, [(x1, y1), (x2, y2) ...] such that each tuple is a\n coordinate - (row, columns), starting with 0.\n \"\"\"\n # Flatten the list of lists to a list of tuples with row and column indices\n coord_list = [(i, j) for i, row in enumerate(lst) for j, val in enumerate(row) if val == x]\n \n # Sort the list of tuples by row and then by column in descending order\n coord_list.sort(key=lambda x: (x[0], -x[1]))\n \n return coord_list", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n This function searches for integer x in a 2D list and returns\n a list of tuples containing the coordinates of the found values.\n The coordinates are defined as (row, column) where both start with 0.\n \n Args:\n lst (list): A 2D list containing integers.\n x (int): The integer to search for in the 2D list.\n \n Returns:\n list: A list of tuples containing the coordinates of the found values.\n \n Example:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n coordinates = []\n \n # Iterate over the list of lists\n for i, row in enumerate(lst):\n # If the row is not empty, iterate over the row and its indices\n if row:\n # Find the indices of the value x in the row\n indices = [j for j, val in enumerate(row) if val == x]\n # Sort the indices in descending order\n indices.sort(reverse=True)\n # Add the coordinates to the result list\n for index in indices:\n coordinates.append((i, index))\n \n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n This function finds all occurrences of the integer x in a given 2D list and returns them as a list of tuples, \n each representing the row and column index of x in the original 2D list. The coordinates are initially sorted by \n row and then by column in descending order.\n\n Args:\n lst (list): A 2D list containing integer elements.\n x (int): The integer to find in the 2D list.\n\n Returns:\n list: A list of tuples representing the coordinates of x in the 2D list.\n \"\"\"\n\n # Use list comprehension to find all coordinates where x appears in lst\n # For each row in the 2D list, use enumerate to get both the index and value of each element\n coordinates = [(i, j) for i, row in enumerate(lst) for j, val in enumerate(row) if val == x]\n\n # Sort the coordinates by row in ascending order and then by column in descending order\n coordinates.sort(key=lambda t: (t[0], -t[1]))\n\n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Parameters:\n lst (list): A list of lists with integer elements.\n x (int): The integer to find in the list.\n\n Returns:\n list: A list of tuples, containing the coordinates where x was found.\n \"\"\"\n result = [(r, c) for r, sub_list in enumerate(lst) for c, value in enumerate(sub_list) if value == x]\n result.sort(key=lambda x: (x[0], -x[1]))\n return result", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n Find integers x in the list and return list of tuples,\n [(x1, y1), (x2, y2) ...] such that each tuple is a coordinate - (row, columns),\n starting with 0. Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n \n Args:\n lst (list): A 2 dimensional data, as a nested lists.\n x (int): The target integer to find in the list.\n\n Returns:\n list: A list of tuples representing coordinates where x is found.\n\n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n result = [(i, y) for i, row in enumerate(lst) for y, val in enumerate(row) if val == x]\n result.sort(key=lambda item: (item[0], -item[1]))\n return result", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n Find integers x in the list, and return list of tuples, \n [(x1, y1), (x2, y2) ...] such that each tuple is a coordinate \n - (row, columns), starting with 0.\n \n Args:\n lst (list): A 2D list of integers.\n x (int): The integer to find in the list.\n \n Returns:\n list: A list of tuples representing the coordinates of the integer x.\n \"\"\"\n # Filter rows that contain the target integer x\n relevant_rows = [(i, y) for i, row in enumerate(lst) for y, val in enumerate(row) if val == x]\n \n # Sort the coordinates by row and then by column in descending order\n relevant_rows.sort(key=lambda x: (x[0], -x[1]))\n \n return relevant_rows", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n Finds coordinates of all occurrences of x in a 2D list, \n with x in row coordinate sorted by row index, and in \n each row by column index in descending order.\n\n Args:\n lst (list): A 2D list containing integers.\n x (int): The integer to find in the list.\n\n Returns:\n list: A list of tuples representing the coordinates of x.\n \"\"\"\n result = []\n for i, row in enumerate(lst):\n # Find the indices of x in the current row\n indices = [j for j, val in enumerate(row) if val == x]\n \n # Add the indices as tuples to the result list, sorted by row and then by column\n result.extend([(i, j) for j in sorted(indices, reverse=True)])\n \n # Sort the result by row index\n result.sort(key=lambda x: x[0])\n \n return result", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n This function finds the coordinates of the given integer in a 2D list.\n \n Args:\n lst (list): A 2D list of integers.\n x (int): The target integer to find in the 2D list.\n \n Returns:\n list: A list of tuples representing the coordinates of the target integer in the 2D list.\n Each tuple contains the row and column index of the target integer, starting from 0.\n The coordinates are first sorted by row in ascending order, then by column in descending order.\n \"\"\"\n coordinates = [(row_index, column_index) for row_index, row in enumerate(lst) for column_index, value in enumerate(row) if value == x]\n return sorted(coordinates, key=lambda coord: (coord[0], -coord[1]))", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n This function finds all occurrences of integer x in the given 2D list,\n and returns a list of tuples representing the coordinates (row, column) \n where x is found. The coordinates are sorted by rows in ascending order, \n and then by columns in descending order.\n \n Parameters:\n lst (list): A 2D list of integers.\n x (int): The integer to be searched in the list.\n \n Returns:\n list: A list of tuples representing the coordinates where x is found.\n \"\"\"\n result = []\n for i, row in enumerate(lst):\n # Find the indices of x in the current row\n cols = [j for j, val in enumerate(row) if val == x]\n # Add the coordinates of x in the current row to the result\n for col in cols:\n result.append((i, col))\n # Sort the result by rows and then by columns in descending order\n return sorted(result, key=lambda x: (x[0], -x[1]))", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n Finds coordinates of all occurrences of the given integer x in a 2D list.\n\n Args:\n lst (list): A 2D list of integers.\n x (int): The integer to find in the list.\n\n Returns:\n list: A list of tuples, where each tuple is a coordinate (row, column) of the found integer.\n\n Examples:\n >>> get_row([\n ... [1,2,3,4,5,6],\n ... [1,2,3,4,1,6],\n ... [1,2,3,4,5,1]\n ... ], 1)\n [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n >>> get_row([], 1)\n []\n >>> get_row([[], [1], [1, 2, 3]], 3)\n [(2, 2)]\n \"\"\"\n coordinates = []\n for i, row in enumerate(lst):\n if row: # Check if the row is not empty\n coordinates.extend([(i, j) for j, val in enumerate(row) if val == x])\n # Sort the coordinates by row in ascending order and by column in descending order\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n Returns list of tuples, [(x1, y1), (x2, y2) ...] of coordinates (row, column)\n for given value x in 2 dimensional list.\n\n Coordinates are returned in order:\n - by row in ascending order\n - and within each row, by column in descending order\n\n Args:\n lst (list): A 2 dimensional list of lists\n x (int): The value to find in the list\n\n Returns:\n list: List of tuples representing coordinates of value x\n \"\"\"\n result = [(i, j) for i, row in enumerate(lst) if x in row for j, val in enumerate(row) if val == x]\n return sorted(result, key=lambda coord: (coord[0], -coord[1]))", "matching_cluster_idx": 5}, {"solution": "def get_row(lst, x):\n \"\"\"\n This function finds all instances of a given number in a 2 dimensional data\n and returns a list of tuples representing the coordinates of these instances.\n \n Args:\n lst (list): A 2 dimensional data, where each sublist can have a different length.\n x (int): The number to be searched in the list.\n \n Returns:\n list: A list of tuples representing the coordinates of the given number.\n \"\"\"\n \n coordinates = []\n for i, row in enumerate(lst):\n # Skip empty rows\n if not row:\n continue\n # Find the indices of the target number in the current row and sort them in descending order\n indices = sorted([j for j, val in enumerate(row) if val == x], reverse=True)\n # Add the coordinates of the found number to the list\n for idx in indices:\n coordinates.append((i, idx))\n \n # Sort the list of coordinates by row in ascending order\n coordinates.sort(key=lambda x: x[0])\n \n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n Finds the coordinates of integer x in a 2 dimensional list, sorted by row in ascending order and within each row in descending order.\n\n Args:\n lst (list): A list of lists of integers.\n x (int): The value to search for.\n\n Returns:\n list: A list of tuples containing the row and column indices of the value x, sorted by row in ascending order and column in descending order.\n \"\"\"\n coordinates = [(i, j) for i, row in enumerate(lst) for j, val in enumerate(row) if val == x]\n return sorted(coordinates, key=lambda x: (x[0], -x[1]))", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n Finds all occurrences of `x` in a 2D list and returns a list of tuples\n representing the coordinates (row, column) of each occurrence.\n\n Args:\n lst (list): A 2D list containing integers.\n x (int): The value to search for.\n\n Returns:\n list: A list of tuples representing the coordinates of `x`.\n \"\"\"\n coordinates = []\n for i, row in enumerate(lst):\n # Check if row contains integer\n if isinstance(row, int):\n continue\n for j, val in enumerate(row):\n if val == x:\n coordinates.append((i, j))\n # Sort coordinates by row in ascending order, then by column in descending order\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n return coordinates", "matching_cluster_idx": 3}]}, "HumanEval/89": {"dps": 96.64948453608248, "dps_norm": 28.571428571428573, "pass@1": 63.0, "profiled": [{"solution": "def encrypt(s):\n \"\"\"\n Shifts the alphabet down by 4 places for encryption.\n\n Args:\n s (str): The string to be encrypted\n\n Returns:\n str: The encrypted string\n \"\"\"\n result = \"\"\n for char in s:\n if char.isalpha():\n ascii_offset = 65 if char.isupper() else 97\n result += chr((ord(char) - ascii_offset + 4) % 26 + ascii_offset)\n else:\n result += char # Non-alphabetic characters remain the same\n return result", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"\n Encrypt a string by rotating the alphabet down by 4 places.\n \n Args:\n s (str): The input string to be encrypted.\n \n Returns:\n str: The encrypted string.\n \"\"\"\n alphabet = 'abcdefghijklmnopqrstuvwxyz'\n encrypted = ''\n \n for char in s:\n if char.isalpha():\n # Check if character is lowercase\n if char.islower():\n # Get the position of the character in the alphabet\n index = alphabet.index(char)\n # Calculate the new position by shifting down by 4 places\n new_index = (index + 4) % 26\n # Get the encrypted character\n encrypted_char = alphabet[new_index]\n # Check if character is uppercase\n elif char.isupper():\n # Get the position of the character in the alphabet\n index = alphabet.lower().index(char)\n # Calculate the new position by shifting down by 4 places\n new_index = (index + 4) % 26\n # Get the encrypted character\n encrypted_char = alphabet[new_index].upper()\n encrypted += encrypted_char\n else:\n encrypted += char\n \n return encrypted", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"\n Encrypt a string by rotating the alphabet 2*2 = 4 places to the right.\n \n Parameters:\n s (str): The input string to be encrypted.\n \n Returns:\n str: The encrypted string.\n \"\"\"\n # Define the lowercase and uppercase alphabets\n lowercase_alphabet = 'abcdefghijklmnopqrstuvwxyz'\n uppercase_alphabet = 'ABCDEFGHIJKLMNOPQRSTUVWXYZ'\n \n # Initialize an empty string to store the encrypted result\n encrypted = ''\n \n # Iterate over each character in the input string\n for char in s:\n # Check if the character is an alphabet\n if char.isalpha():\n # Determine whether the character is uppercase or lowercase\n if char.isupper():\n # Find the position of the character in the uppercase alphabet\n position = (uppercase_alphabet.index(char) + 4) % 26\n # Append the character at the new position to the encrypted string\n encrypted += uppercase_alphabet[position]\n else:\n # Find the position of the character in the lowercase alphabet\n position = (lowercase_alphabet.index(char) + 4) % 26\n # Append the character at the new position to the encrypted string\n encrypted += lowercase_alphabet[position]\n else:\n # If the character is not an alphabet, append it as it is\n encrypted += char\n \n # Return the encrypted string\n return encrypted", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"\n Encrypts the input string by shifting the alphabet down by 4 places.\n\n Args:\n s (str): The input string to be encrypted.\n\n Returns:\n str: The encrypted string.\n \"\"\"\n alphabet = 'abcdefghijklmnopqrstuvwxyz'\n encrypted_string = ''\n for char in s:\n if char.isalpha():\n index = alphabet.index(char.lower())\n encrypted_index = (index + 4) % 26\n if char.isupper():\n encrypted_string += alphabet[encrypted_index].upper()\n else:\n encrypted_string += alphabet[encrypted_index]\n else:\n encrypted_string += char\n return encrypted_string", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"\n This function takes a string as an input and returns a string\n where the alphabet is rotated 4 places to the right.\n \n Parameters:\n s (str): The input string to be encrypted.\n \n Returns:\n str: The encrypted string.\n \"\"\"\n result = \"\"\n for char in s:\n if char.isalpha():\n ascii_offset = 65 if char.isupper() else 97\n result += chr((ord(char) - ascii_offset + 4) % 26 + ascii_offset)\n else:\n result += char\n return result", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"\n Encrypt a string by shifting the alphabet down by 4 places.\n \n Parameters:\n s (str): The input string to be encrypted.\n \n Returns:\n str: The encrypted string.\n \"\"\"\n # Define the lowercase and uppercase alphabets\n lowercase = 'abcdefghijklmnopqrstuvwxyz'\n uppercase = 'ABCDEFGHIJKLMNOPQRSTUVWXYZ'\n \n # Initialize the encrypted string\n encrypted = ''\n \n # Iterate over each character in the input string\n for char in s:\n # Check if the character is a lowercase letter\n if char in lowercase:\n # Calculate the new character by shifting down by 4 places\n new_char = lowercase[(lowercase.index(char) + 4) % 26]\n encrypted += new_char\n # Check if the character is an uppercase letter\n elif char in uppercase:\n # Calculate the new character by shifting down by 4 places\n new_char = uppercase[(uppercase.index(char) + 4) % 26]\n encrypted += new_char\n else:\n # If the character is not a letter, add it as is\n encrypted += char\n \n # Return the encrypted string\n return encrypted", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"\n Rotate the alphabet down by four places.\n\n Args:\n s (str): The string to be encrypted.\n\n Returns:\n str: The encrypted string.\n \"\"\"\n result = \"\"\n for char in s:\n # Check if character is an alphabet letter\n if char.isalpha():\n # Find the ASCII value of 'a' or 'A' depending on whether the character is lowercase or uppercase\n start = ord('a') if char.islower() else ord('A')\n # Calculate the new ASCII value after shifting down by 4 places\n new_ascii = (ord(char) - start + 4) % 26 + start\n # Append the encrypted character to the result\n result += chr(new_ascii)\n else:\n # If the character is not a letter, append it as is\n result += char\n return result", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"\n Shifts the alphabet by two places downwards in the English alphabet.\n\n Parameters:\n s (str): The input string to be encrypted.\n\n Returns:\n str: The encrypted string.\n \"\"\"\n alphabet = 'abcdefghijklmnopqrstuvwxyz'\n encrypted_string = ''\n shift = 2 * 2 # Two multiplied by two\n\n # Iterate over each character in the string\n for char in s:\n if char.isalpha(): # Check if the character is a letter\n # Get the position in the alphabet\n position = alphabet.index(char.lower())\n\n # Calculate the new position\n new_position = (position + shift) % 26\n\n # Use the new position to get the new character\n if char.isupper():\n encrypted_string += alphabet[new_position].upper()\n else:\n encrypted_string += alphabet[new_position]\n else:\n # If the character is not a letter, add it as is\n encrypted_string += char\n\n return encrypted_string", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"\n Encrypts a string by rotating the alphabet two places down for each character.\n\n Args:\n s (str): The input string to be encrypted.\n\n Returns:\n str: The encrypted string.\n\n \"\"\"\n # Create a string of the lowercase and uppercase English alphabets\n alphabet = 'abcdefghijklmnopqrstuvwxyz'\n \n # Initialize an empty string to store the result\n encrypted = ''\n\n # Iterate over each character in the input string\n for char in s:\n # Check if the character is a lowercase letter\n if char.islower():\n # Find the position of the character in the alphabet\n pos = alphabet.index(char)\n # Shift the position two places down, wrap around to the end if necessary\n new_pos = (pos + 4) % 26 # Shifting two places for two multiplied by two places\n # Append the character at the new position to the result\n encrypted += alphabet[new_pos]\n # Check if the character is an uppercase letter\n elif char.isupper():\n # Find the position of the character in the alphabet\n pos = alphabet.lower().index(char)\n # Shift the position two places down, wrap around to the end if necessary\n new_pos = (pos + 4) % 26 # Shifting two places for two multiplied by two places\n # Append the character at the new position to the result\n encrypted += alphabet[new_pos].upper()\n # If the character is not a letter, just append it to the result as is\n else:\n encrypted += char\n\n return encrypted", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"\n Encrypt a string by shifting each letter down by 2*2 = 4 places in the alphabet.\n\n Args:\n s (str): The input string to be encrypted.\n\n Returns:\n str: The encrypted string.\n \"\"\"\n encrypted = ''\n for char in s:\n if char.isalpha():\n # Find the ASCII value of the character in the alphabet (a=97 or A=65)\n ascii_offset = 97 if char.islower() else 65\n # Calculate the shifted position (move 4 places down)\n new_pos = (ord(char) - ascii_offset + 4) % 26\n # Convert the new position back to a character and add it to the result\n encrypted += chr(new_pos + ascii_offset)\n else:\n # Non-alphabet characters are left unchanged\n encrypted += char\n return encrypted", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"\n Encrypts a string by shifting the alphabet two places down (multiplied to two places) and \n applying this shift to the input string.\n\n Args:\n s (str): The input string to be encrypted.\n\n Returns:\n str: The encrypted string.\n \"\"\"\n alphabet = 'abcdefghijklmnopqrstuvwxyz'\n encrypted = ''\n \n # Convert the input string to lowercase to handle all cases\n s = s.lower()\n \n # Iterate over each character in the input string\n for char in s:\n # Check if the character is an alphabet letter\n if char.isalpha():\n # Find the position of the character in the alphabet\n position = alphabet.index(char)\n # Apply the shift to the position\n new_position = (position + 2 * 2) % 26\n # Get the encrypted character from the alphabet\n encrypted_char = alphabet[new_position]\n # Add the encrypted character to the result string\n encrypted += encrypted_char\n else:\n # If the character is not a letter, add it as is to the result string\n encrypted += char\n \n return encrypted", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"\n Encrypt a string by rotating the alphabet two times down.\n \n Args:\n s (str): The input string to be encrypted.\n \n Returns:\n str: The encrypted string.\n \"\"\"\n result = ''\n for char in s:\n # Check if the character is an uppercase letter\n if char.isupper():\n # Find the position in the alphabet (A=0, B=1, ..., Z=25)\n position = ord(char) - ord('A')\n # Rotate down by 2 * 2 places (i.e., 4 places)\n new_position = (position + 4) % 26\n # Convert the new position back to a character\n encrypted_char = chr(new_position + ord('A'))\n # Check if the character is a lowercase letter\n elif char.islower():\n # Find the position in the alphabet (a=0, b=1, ..., z=25)\n position = ord(char) - ord('a')\n # Rotate down by 2 * 2 places (i.e., 4 places)\n new_position = (position + 4) % 26\n # Convert the new position back to a character\n encrypted_char = chr(new_position + ord('a'))\n # If the character is not a letter, do not change it\n else:\n encrypted_char = char\n # Append the encrypted character to the result\n result += encrypted_char\n return result", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"\n Encrypt a string by rotating the alphabet by two times two places.\n\n Args:\n s (str): The input string to be encrypted.\n\n Returns:\n str: The encrypted string.\n \"\"\"\n shift = 2 * 2 # Rotate by two times two places\n result = \"\"\n\n for char in s:\n if char.isalpha(): # Check if character is a letter\n ascii_offset = 65 if char.isupper() else 97 # ASCII offset for uppercase or lowercase letters\n result += chr((ord(char) - ascii_offset + shift) % 26 + ascii_offset)\n else:\n result += char # If the character is not a letter, leave it as is\n\n return result", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"\n Encrypts the given string by shifting the alphabet down by 2 * 2 places.\n \n Args:\n s (str): The string to be encrypted.\n \n Returns:\n str: The encrypted string.\n \"\"\"\n result = \"\"\n \n # Iterate over each character in the string\n for char in s:\n # Check if the character is a lowercase letter\n if char.isalpha():\n ascii_offset = 97 if char.islower() else 65\n # Calculate the new position of the character in the alphabet\n new_position = (ord(char) - ascii_offset + (2 * 2)) % 26 + ascii_offset\n result += chr(new_position)\n else:\n # If the character is not a letter, add it to the result as it is\n result += char\n \n return result", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"\n Encrypt a given string by shifting the alphabet down by two places.\n\n Args:\n s (str): The string to be encrypted.\n\n Returns:\n str: The encrypted string.\n \"\"\"\n encrypted_chars = []\n for char in s:\n # Check if character is an alphabet letter\n if char.isalpha():\n ascii_offset = 97 if char.islower() else 65\n encrypted_char = chr((ord(char) - ascii_offset + 2*2) % 26 + ascii_offset)\n encrypted_chars.append(encrypted_char)\n else:\n # If character is not a letter, append it as is\n encrypted_chars.append(char)\n return ''.join(encrypted_chars)", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"\n Encrypts the input string by shifting each letter down two places\n in the alphabet, wrapping around to the end of the alphabet if necessary.\n\n Args:\n s (str): The input string to be encrypted.\n\n Returns:\n str: The encrypted string.\n \"\"\"\n result = \"\"\n for char in s:\n if char.isalpha(): # Check if the character is a letter\n ascii_offset = 97 if char.islower() else 65\n result += chr((ord(char) - ascii_offset + 2 * 2) % 26 + ascii_offset)\n else:\n result += char # Non-alphabet characters remain unchanged\n return result", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"\n Rotate the alphabet by shifting down by 4 places and return the encrypted string.\n \n Parameters:\n s (str): The input string to be encrypted\n \n Returns:\n str: The encrypted string\n \"\"\"\n alphabet = 'abcdefghijklmnopqrstuvwxyz'\n encrypted_string = ''\n for char in s:\n if char.isalpha(): # Check if the character is a letter\n # Find the index of the character in the alphabet\n index = alphabet.index(char.lower())\n # Shift the index down by 4 places\n new_index = (index + 4) % 26\n # Add the encrypted character to the result string\n encrypted_string += alphabet[new_index] if char.islower() else alphabet[new_index].upper()\n else:\n # If the character is not a letter, just add it to the result string as is\n encrypted_string += char\n return encrypted_string", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"\n Rotate the alphabet down by two multiplied to two places in a string.\n\n Args:\n s (str): The input string to be encrypted.\n\n Returns:\n str: The encrypted string.\n \"\"\"\n # Define the lowercase and uppercase alphabets\n lowercase_alphabet = 'abcdefghijklmnopqrstuvwxyz'\n uppercase_alphabet = lowercase_alphabet.upper()\n\n # Create a mapping of characters to their shifted equivalents\n shifted_lowercase_map = {}\n shifted_uppercase_map = {}\n\n # Shift the lowercase alphabet down by 2*2 places\n for i in range(26):\n shifted_index = (i + 2*2) % 26\n shifted_lowercase_map[lowercase_alphabet[i]] = lowercase_alphabet[shifted_index]\n shifted_uppercase_map[uppercase_alphabet[i]] = uppercase_alphabet[shifted_index]\n\n # Replace characters in the input string with their shifted equivalents\n encrypted_string = ''\n for char in s:\n if char.isalpha():\n if char.islower():\n encrypted_string += shifted_lowercase_map[char]\n else:\n encrypted_string += shifted_uppercase_map[char]\n else:\n encrypted_string += char\n\n return encrypted_string", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"\n Encrypt a string by rotating the alphabet 4 places down.\n \n The function takes a string s as an argument, shifts each letter down by 4 places in the alphabet\n (wrapping around to the start if necessary) and returns the encrypted string.\n\n Parameters:\n s (str): The input string to be encrypted.\n\n Returns:\n str: The encrypted string.\n \"\"\"\n\n alphabet = 'abcdefghijklmnopqrstuvwxyz'\n encrypted = ''\n\n for char in s:\n # Check if character is in the alphabet\n if char.isalpha():\n # Find the position of the character in the alphabet\n position = alphabet.index(char.lower())\n # Calculate the new position by shifting down by 4 places, wrapping around if necessary\n new_position = (position + 4) % 26\n # If the original character was uppercase, keep the new character uppercase\n if char.isupper():\n encrypted += alphabet[new_position].upper()\n else:\n encrypted += alphabet[new_position]\n else:\n # If the character is not a letter, keep it as is\n encrypted += char\n\n return encrypted", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"\n Encrypt a string by shifting the alphabet down by two multiplied to two places.\n\n Args:\n s (str): The input string to be encrypted.\n\n Returns:\n str: The encrypted string.\n \"\"\"\n encrypted = \"\"\n for char in s:\n # Check if the character is an uppercase or lowercase letter\n if char.isalpha():\n # Determine whether the character is uppercase or lowercase\n if char.isupper():\n # Calculate the ASCII value of the encrypted character\n encrypted_char = chr((ord(char) - 65 + (2 * 2)) % 26 + 65)\n else:\n # Calculate the ASCII value of the encrypted character\n encrypted_char = chr((ord(char) - 97 + (2 * 2)) % 26 + 97)\n encrypted += encrypted_char\n else:\n # If the character is not a letter, add it to the encrypted string as is\n encrypted += char\n return encrypted", "matching_cluster_idx": 1}]}, "HumanEval/90": {"dps": 76.86770428015565, "dps_norm": 57.083333333333336, "pass@1": 75.0, "profiled": [{"solution": "def next_smallest(lst):\n \"\"\"\n Returns the 2nd smallest element of a list.\n If no such element exists (i.e., the list has less than 2 unique elements), returns None.\n \n Parameters:\n lst (list): A list of integers.\n \n Returns:\n int or None: The 2nd smallest element in the list, or None if it does not exist.\n \"\"\"\n # Remove duplicates and sort the list in ascending order\n unique_sorted_list = sorted(set(lst))\n \n # Check if the list has at least 2 elements\n if len(unique_sorted_list) < 2:\n return None\n \n # Return the 2nd smallest element\n return unique_sorted_list[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n Returns the 2nd smallest element of a list of integers. \n Returns None if there is no such element.\n\n Args:\n lst (list): A list of integers.\n\n Returns:\n int or None: The 2nd smallest element or None if it does not exist.\n \"\"\"\n # Remove duplicates by converting to a set, and then sort the set in ascending order\n sorted_set = sorted(set(lst))\n \n # Check if the list has at least 2 unique elements\n if len(sorted_set) < 2:\n return None\n \n # Return the 2nd element (index 1) of the sorted list\n return sorted_set[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n Returns the 2nd smallest element of the list.\n If the list is empty or contains less than two unique elements, returns None.\n \n Args:\n lst (list): A list of integers.\n \n Returns:\n int or None: The 2nd smallest element or None.\n \"\"\"\n # Remove duplicates and sort the list\n unique_lst = sorted(set(lst))\n \n # Check if the list contains at least two elements\n if len(unique_lst) < 2:\n return None\n \n # Return the 2nd smallest element\n return unique_lst[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n Returns the 2nd smallest element of the list.\n If the list has less than 2 unique elements, returns None.\n\n Args:\n lst (list): A list of integers.\n\n Returns:\n int or None: The 2nd smallest element of the list or None if there is no 2nd smallest element.\n \"\"\"\n # Remove duplicates from the list\n unique_lst = list(set(lst))\n \n # Check if there are at least 2 unique elements\n if len(unique_lst) < 2:\n return None\n \n # Sort the list in ascending order\n unique_lst.sort()\n \n # The 2nd smallest element is at index 1\n return unique_lst[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n Returns the 2nd smallest element in the list.\n Returns None if the list has less than 2 elements.\n \n Parameters:\n lst (list): A list of integers.\n \n Returns:\n int or None: The 2nd smallest element of the list or None if not found.\n \"\"\"\n if len(lst) < 2:\n # If list has less than 2 elements, return None\n return None\n \n # Remove duplicates by converting list to a set\n unique_lst = list(set(lst))\n \n # Sort the list to find the 2nd smallest element\n unique_lst.sort()\n \n # Return the 2nd smallest element, or None if the list has a single unique element\n return unique_lst[1] if len(unique_lst) > 1 else None", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n Returns the 2nd smallest element of the list. Returns None if there is no such element.\n \n Parameters:\n lst (list): A list of integers.\n \n Returns:\n int or None: The 2nd smallest element of the list, or None if it doesn't exist.\n \"\"\"\n \n # Remove duplicates and sort the list\n sorted_lst = sorted(set(lst))\n \n # If the sorted list has less than 2 elements, there's no 2nd smallest element\n if len(sorted_lst) < 2:\n return None\n \n # Return the 2nd smallest element\n return sorted_lst[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n Returns the 2nd smallest element of the list. \n Returns None if there is no such element (i.e., list is empty or has less than 2 unique elements).\n \n Parameters:\n lst (list): A list of integers.\n \n Returns:\n int or None: The 2nd smallest element or None.\n \"\"\"\n if len(set(lst)) < 2:\n # if the list has less than 2 unique elements, return None\n return None\n # remove duplicates and sort the list\n sorted_lst = sorted(set(lst))\n # return the second element of the sorted list\n return sorted_lst[1]", "matching_cluster_idx": 5}, {"solution": "def next_smallest(lst):\n \"\"\"\n Returns the 2nd smallest element of a list of integers. \n If the list is empty or contains less than 2 unique elements, it returns None.\n \n Parameters:\n lst (list): A list of integers.\n \n Returns:\n int: The 2nd smallest element of the list or None.\n \"\"\"\n \n # Remove duplicates from the list\n unique_lst = list(set(lst))\n \n # If the list has less than 2 unique elements, return None\n if len(unique_lst) < 2:\n return None\n \n # Sort the list in ascending order\n unique_lst.sort()\n \n # Return the 2nd smallest element\n return unique_lst[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n Returns the 2nd smallest element in a list of integers. \n If the list has less than two elements, it returns None.\n \n Args:\n lst (list): A list of integers.\n \n Returns:\n int: The 2nd smallest element in the list, or None if there is no such element.\n \"\"\"\n # Remove duplicates and sort the list\n unique_lst = sorted(set(lst))\n \n # Check if the list has less than two elements\n if len(unique_lst) < 2:\n return None\n \n # Return the 2nd smallest element\n return unique_lst[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n Returns the 2nd smallest element of the list.\n Returns None if the list has less than 2 distinct elements.\n \"\"\"\n \n # Remove duplicates by converting list to a set\n unique_lst = list(set(lst))\n \n # Check if list has at least 2 elements\n if len(unique_lst) < 2:\n return None\n \n # Sort the list and return the 2nd element\n return sorted(unique_lst)[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n Returns the 2nd smallest element of the list. \n If the list has less than two distinct elements, return None.\n \n Args:\n lst (list): A list of integers.\n \n Returns:\n int or None: The 2nd smallest element if it exists, otherwise None.\n \"\"\"\n \n # Remove duplicates by converting the list to a set, which automatically removes duplicates\n unique_elements = set(lst)\n \n # If there are less than two distinct elements, return None\n if len(unique_elements) < 2:\n return None\n \n # Sort the unique elements\n sorted_unique = sorted(list(unique_elements))\n \n # The 2nd smallest element is at index 1\n return sorted_unique[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n Returns the 2nd smallest element of the list. \n Returns None if there is no such element or the list has less than 2 elements.\n \n Parameters:\n lst (list): A list of integers\n \n Returns:\n int: The 2nd smallest element in the list or None if it does not exist\n \"\"\"\n if len(lst) < 2: \n return None # If the list is empty or contains one element\n sorted_lst = sorted(lst)\n for num in sorted_lst[1:]: # We start from the second smallest number\n if num != sorted_lst[0]: \n return num # If a different number is found, it is the second smallest number", "matching_cluster_idx": 9}, {"solution": "def next_smallest(lst):\n \"\"\"\n This function returns the 2nd smallest element of a given list of integers.\n Returns None if the list is empty, has less than two elements, or if all elements are the same.\n \n Parameters:\n lst (list): A list of integers.\n \n Returns:\n int or None: The 2nd smallest element or None if the condition is not met.\n \"\"\"\n if len(lst) < 2:\n return None\n \n unique_lst = sorted(set(lst))\n \n if len(unique_lst) < 2:\n return None\n \n return unique_lst[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n Returns the 2nd smallest element of the list.\n Returns None if the list has less than 2 unique elements or is empty.\n \n Args:\n lst (list): A list of integers.\n \n Returns:\n int or None: The 2nd smallest element in the list, or None if it does not exist.\n \"\"\"\n # Remove duplicates from the list\n unique_lst = set(lst)\n \n # If there are less than 2 unique elements, return None\n if len(unique_lst) < 2:\n return None\n \n # Remove the smallest element\n unique_lst.remove(min(unique_lst))\n \n # Return the smallest element from the remaining elements\n return min(unique_lst)", "matching_cluster_idx": 5}, {"solution": "def next_smallest(lst):\n \"\"\"\n Returns the 2nd smallest element of the list.\n Returns None if there is no such element.\n \n Parameters:\n lst (list): A list of integers.\n \n Returns:\n int or None: The 2nd smallest element or None.\n \"\"\"\n # Remove duplicates by converting the list to a set\n unique_lst = list(set(lst))\n \n # Check if there are at least 2 unique elements\n if len(unique_lst) < 2:\n return None\n \n # Sort the list in ascending order and return the second element\n return sorted(unique_lst)[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n Returns the 2nd smallest element of a list of integers.\n \n Args:\n lst (list): A list of integers.\n \n Returns:\n int or None: The 2nd smallest element if it exists, otherwise None.\n \"\"\"\n # Check if the list is empty or has less than 2 unique elements\n if len(set(lst)) < 2:\n return None\n \n # Remove duplicates and sort the list in ascending order\n unique_sorted_lst = sorted(set(lst))\n \n # Return the 2nd smallest element\n return unique_sorted_lst[1]", "matching_cluster_idx": 5}, {"solution": "def next_smallest(lst):\n \"\"\"\n Returns the 2nd smallest element of the list.\n Returns None if there is no such element or list contains fewer than 2 unique elements.\n\n Args:\n lst (list): A list of integers\n\n Returns:\n int: The 2nd smallest element of the list, or None if not found.\n \"\"\"\n if len(set(lst)) < 2:\n return None\n sorted_lst = sorted(set(lst))\n return sorted_lst[1]", "matching_cluster_idx": 5}, {"solution": "def next_smallest(lst):\n \"\"\"\n Returns the 2nd smallest element in the list. \n If the list is empty or has less than 2 elements, returns None.\n \n Parameters:\n lst (list): A list of integers\n \n Returns:\n int or None: The 2nd smallest element, or None if it does not exist\n \"\"\"\n # Remove duplicates by converting the list to a set\n unique_lst = set(lst)\n \n # If the list has less than 2 elements, return None\n if len(unique_lst) < 2:\n return None\n \n # Remove the smallest element\n unique_lst.remove(min(unique_lst))\n \n # Return the smallest remaining element\n return min(unique_lst)", "matching_cluster_idx": 5}, {"solution": "def next_smallest(lst):\n \"\"\"\n Returns the 2nd smallest element of a list of integers. If the list has less than 2 elements, \n or is empty, returns None.\n\n Args:\n lst (list): A list of integers.\n\n Returns:\n int: The 2nd smallest element in the list, or None if not found.\n \"\"\"\n # Check if the list has at least 2 elements\n if len(lst) < 2:\n return None\n\n # Remove duplicates by converting to a set\n unique_lst = set(lst)\n \n # Check if there are at least 2 unique elements\n if len(unique_lst) < 2:\n return None\n\n # Remove the smallest element\n smallest = min(unique_lst)\n unique_lst.remove(smallest)\n \n # The next smallest element is the smallest of the remaining elements\n return min(unique_lst)", "matching_cluster_idx": 5}, {"solution": "def next_smallest(lst):\n \"\"\"\n Returns the 2nd smallest element of the list.\n If there is no such element, returns None.\n \n Parameters:\n lst (list): A list of integers.\n \n Returns:\n int or None: The 2nd smallest element of the list, or None if not found.\n \"\"\"\n \n # Remove duplicates by converting the list to a set and then back to a list\n unique_lst = list(set(lst))\n \n # Check if the list is empty or has only one element\n if len(unique_lst) < 2:\n return None\n \n # Sort the list in ascending order\n sorted_lst = sorted(unique_lst)\n \n # Return the 2nd smallest element\n return sorted_lst[1]", "matching_cluster_idx": 6}]}, "HumanEval/113": {"dps": 79.35304793423722, "dps_norm": 57.01754385964912, "pass@1": 19.0, "profiled": [{"solution": "def odd_count(lst):\n \"\"\"\n Given a list of strings, where each string consists of only digits,\n return a list. Each element i of the output should be \"the number of odd\n elements in the i'th string of the input.\" where all the i's should be\n replaced by the number of odd digits in the i'th string of the input.\n \n Parameters:\n lst (list): A list of strings, where each string consists of only digits.\n \n Returns:\n list: A list of strings where each element is \"the number of odd elements in\n the i'th string of the input.\"\n \"\"\"\n result = []\n for string in lst:\n odd_count_str = len([digit for digit in string if int(digit) % 2 != 0])\n i_str = 'i'.join(str(i) for i in str(string))\n result.append(f\"the number of odd elements {odd_count_str}n the str{odd_count_str}ng {odd_count_str} of the {odd_count_str}nput.\")\n return result", "matching_cluster_idx": 1}, {"solution": "def odd_count(lst):\n \"\"\"\n Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n \n Args:\n lst (list): A list of strings, each consisting of only digits.\n \n Returns:\n list: A list of strings where each string represents the number of odd digits\n in the corresponding input string.\n \"\"\"\n output = []\n for i, string in enumerate(lst):\n # Replace i with the number of odd digits in the current string\n odd_digits = str(sum(int(digit) % 2 for digit in string))\n output.append(f\"the number of odd elements {odd_digits}n the str{odd_digits}ng {odd_digits} of the {odd_digits}nput.\")\n return output", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"\n Given a list of strings, where each string consists of only digits, \n return a list. Each element i of the output should be \"the number of \n odd elements in the string i of the input.\" where all the i's should \n be replaced by the number of odd digits in the i'th string of the input.\n \n Args:\n lst (list): A list of strings, where each string consists of only digits.\n \n Returns:\n list: A list where each element is a modified string with the number of \n odd digits in the corresponding original string.\n \"\"\"\n \n result = []\n for string in lst:\n # Replace the 'i's in the string with the count of odd digits\n # For each digit in the string, check if it's odd and increment the counter\n odd_digits = sum(1 for char in string if int(char) % 2 != 0)\n modified_string = \"the number of odd elements {0}n the str{0}ng {0} of the {0}nput.\".format(odd_digits)\n result.append(modified_string)\n \n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"\n Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n Parameters:\n lst (list): A list of strings, where each string consists of only digits.\n\n Returns:\n list: A list of strings with the number of odd digits replaced in each position.\n \"\"\"\n result = []\n for i, s in enumerate(lst, start=1): # Start from 1 for the correct string position.\n num_odd_digits = sum(1 for c in s if int(c) % 2 != 0)\n result.append(f\"the number of odd elements {num_odd_digits}n the str{num_odd_digits}ng {num_odd_digits} of the {num_odd_digits}nput.\")\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"\n Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the string i of the input.\"\n where all the i's should be replaced by the number of odd digits in the i'th string of the input.\n\n Args:\n lst (list): A list of strings, where each string consists of only digits.\n\n Returns:\n list: A list of strings where each string is \"the number of odd elements in the string i of the input.\" \n where i is replaced with the number of odd elements in the string.\n \"\"\"\n result = []\n for i, s in enumerate(lst, 1): # Enumerate starts from 1 instead of 0\n num_odd = sum(1 for d in s if int(d) % 2 != 0) # Count odd digits\n result.append(f\"the number of odd elements {num_odd}n the str{num_odd}ng {num_odd} of the {num_odd}nput.\")\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"\n Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n \"\"\"\n result = []\n for s in lst:\n num_odd = sum(1 for c in s if int(c) % 2 != 0) # count odd digits\n result.append(f\"the number of odd elements {num_odd}n the str{num_odd}ng {num_odd} of the {num_odd}nput.\")\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"\n Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the string i of the input.\" \n where all the i's should be replaced by the number of odd digits in the i'th string of the input.\n\n Args:\n lst (list): A list of strings, each consisting of digits.\n\n Returns:\n list: A list of strings with the number of odd digits replaced with their corresponding indices.\n \"\"\"\n\n def count_odd_digits(s):\n \"\"\"Helper function to count the number of odd digits in a string.\"\"\"\n return str(sum(1 for char in s if int(char) % 2 != 0))\n\n return [f\"the number of odd elements {count_odd_digits(s)}n the str{count_odd_digits(s)}ng {count_odd_digits(s)} of the {count_odd_digits(s)}nput.\" for s in lst]", "matching_cluster_idx": 0}, {"solution": "def odd_count(lst):\n \"\"\"\n Given a list of strings, where each string consists of only digits, \n return a list. Each element i of the output should be \"the number of \n odd elements in the string i of the input.\" where all the i's should be \n replaced by the number of odd digits in the i'th string of the input.\n\n Args:\n lst (list): A list of strings, each consisting of digits.\n\n Returns:\n list: A list of strings where each string is the description of the \n odd counts in the input strings.\n \"\"\"\n def count_odd_digits(s):\n \"\"\"Helper function to count the number of odd digits in a string.\"\"\"\n return sum(int(digit) % 2 for digit in s)\n\n return [f\"the number of odd elements {count_odd_digits(s)}n the str{count_odd_digits(s)}ng {count_odd_digits(s)} of the {count_odd_digits(s)}nput.\" for s in lst]", "matching_cluster_idx": 0}, {"solution": "def odd_count(lst):\n \"\"\"\n Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n \n Args:\n lst (list): A list of strings, where each string consists of only digits.\n \n Returns:\n list: A list of strings, where each string is the number of odd elements in the corresponding input string.\n \"\"\"\n result = []\n for i, s in enumerate(lst):\n # replace all digits and 'i' with the count of odd digits\n odd_count_str = str(sum(1 for c in s if int(c) % 2 != 0))\n # replace 'i's with the count of odd digits\n result_str = \"the number of odd elements {}n the str{}ng {} of the {}nput.\".format(odd_count_str, odd_count_str, odd_count_str, odd_count_str)\n result.append(result_str)\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"\n Given a list of strings, where each string consists of only digits,\n return a list. Each element i of the output should be \"the number of odd\n elements in the string i of the input.\" where all the i's should be replaced\n by the number of odd digits in the i'th string of the input.\n \"\"\"\n return [\n f\"the number of odd elements {count}n the str{count}ng {count} of the {count}nput.\"\n for count in [sum(int(digit) % 2 != 0 for digit in string)\n for string in lst]\n ]", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"\n Given a list of strings, where each string consists of only digits, \n return a list. Each element i of the output should be \"the number of odd elements \n in the string i of the input.\" where all the i's should be replaced by the number \n of odd digits in the i'th string of the input.\n \n Args:\n lst (list): A list of strings, where each string consists of only digits.\n \n Returns:\n list: A list of strings, where each string is the replacement string for the corresponding input string.\n \"\"\"\n result = []\n for i, s in enumerate(lst):\n num_odd = sum(1 for c in s if int(c) % 2 != 0)\n result.append(f\"the number of odd elements {num_odd}n the str{num_odd}ng {num_odd} of the {num_odd}nput.\")\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"\n Given a list of strings, where each string consists of only digits, \n return a list. Each element i of the output should be \"the number of \n odd elements in the string i of the input.\" where all the i's should \n be replaced by the number of odd digits in the i'th string of the input.\n\n Args:\n lst (list): A list of strings, where each string consists of only digits.\n\n Returns:\n list: A list of strings describing the number of odd digits in each input string.\n \"\"\"\n\n def count_odd_digits(s):\n \"\"\"Helper function to count odd digits in a string.\"\"\"\n return sum(1 for c in s if int(c) % 2 != 0)\n\n result = []\n for i, s in enumerate(lst, start=1):\n # Replace 'i' in the string with the number of odd digits in the string 's'.\n odd_count_str = \"the number of odd elements {i}n the str{i}ng {i} of the {i}nput.\".format(i=count_odd_digits(s))\n result.append(odd_count_str)\n\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"\n Given a list of strings, where each string consists of only digits, \n return a list of strings. Each element i of the output should be \n \"the number of odd elements in the string i of the input.\" where \n all the i's should be replaced by the number of odd digits in the \n i'th string of the input.\n\n Args:\n lst (list): A list of strings, where each string consists of only digits.\n\n Returns:\n list: A list of strings, where each string is the number of odd elements \n in the corresponding string of the input.\n \"\"\"\n def replace_digit(digit):\n return f\"{'o' if int(digit) % 2 != 0 else 'z'}\"\n\n def generate_string(num):\n return f\"the number of odd elements {num}n the str{num}ng {num} of the {num}nput.\"\n\n return [generate_string(sum(int(digit) % 2 for digit in string)) for string in lst]", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"\n Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n Args:\n lst (list): A list of strings, where each string consists of only digits.\n\n Returns:\n list: A list of strings with odd digit counts.\n \"\"\"\n output = []\n for i, s in enumerate(lst):\n # Convert the string to an integer and count the number of odd digits\n odd_digits = sum(1 for char in s if int(char) % 2 != 0)\n # Create the output string by replacing i with the count of odd digits\n output.append(\"the number of odd elements \" + str(odd_digits) + \"n the str\" + str(odd_digits) + \"ng \" + str(odd_digits) + \" of the \" + str(odd_digits) + \"nput.\")\n return output", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"\n Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n Args:\n lst (list): A list of strings, where each string consists of only digits.\n\n Returns:\n list: A list of strings, where each string contains the count of odd digits in the corresponding input string.\n \"\"\"\n output = []\n for i, string in enumerate(lst, start=1):\n # Count odd digits in the string\n odd_count_str = str(sum(1 for char in string if int(char) % 2 != 0))\n \n # Replace 'i's in the output string with the odd digit count\n output_str = \"the number of odd elements {}n the str{}ng {} of the {}nput.\".format(odd_count_str, odd_count_str, odd_count_str, odd_count_str)\n output.append(output_str)\n \n return output", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"\n Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n Args:\n lst (list): A list of strings, where each string consists of only digits.\n\n Returns:\n list: A list of strings, where each string contains the count of odd digits\n from the corresponding string in the input list.\n \"\"\"\n output = []\n for idx, string in enumerate(lst):\n odd_count_in_str = sum(1 for char in string if int(char) % 2 != 0)\n replacement_i = str(odd_count_in_str)\n output.append(f\"the number of odd elements {replacement_i}n the str{replacement_i}ng {replacement_i} of the {replacement_i}nput.\")\n return output", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"\n Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n \n Parameters:\n lst (list): List of strings, each string consisting of digits.\n \n Returns:\n list: List of strings containing the count of odd digits in each string.\n \"\"\"\n \n result = []\n for i, string in enumerate(lst, 1):\n # Count the number of odd digits in the string\n odd_count = sum(1 for digit in string if int(digit) % 2 != 0)\n # Create the output string by replacing i with the count of odd digits\n output = f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\"\n result.append(output)\n \n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"\n Given a list of strings, where each string consists of only digits,\n return a list. Each element i of the output should be \"the number\n of odd elements in the string i of the input.\" where all the i's\n should be replaced by the number of odd digits in the i'th string\n of the input.\n\n Args:\n lst (list): A list of strings, each consisting of digits.\n\n Returns:\n list: A list of strings where each string is a description of the\n number of odd digits in the corresponding input string.\n \"\"\"\n def count_odd_digits(s):\n \"\"\"Helper function to count the number of odd digits in a string.\"\"\"\n return str(len([digit for digit in s if int(digit) % 2 != 0]))\n\n return [f\"the number of odd elements {count_odd_digits(i)}n the str{count_odd_digits(i)}ng {count_odd_digits(i)} of the {count_odd_digits(i)}nput.\" for i in lst]", "matching_cluster_idx": 0}, {"solution": "def odd_count(lst):\n \"\"\"\n Given a list of strings, where each string consists of only digits, \n return a list. Each element i of the output should be \"the number of \n odd elements in the string i of the input.\" where all the i's should be \n replaced by the number of odd digits in the i'th string of the input.\n\n Args:\n lst (list): A list of strings, each containing only digits.\n\n Returns:\n list: A list of strings, where each string represents the number of odd \n digits in the corresponding input string.\n \"\"\"\n result = []\n for i, s in enumerate(lst, start=1):\n # Replace the index 'i' with the number of odd digits in the string 's'\n # First count the odd digits in the string\n odd_digit_count = sum(int(digit) % 2 != 0 for digit in s)\n \n # Replace all 'i's with the odd digit count and construct the output string\n output = f\"the number of odd elements {odd_digit_count}n the str{odd_digit_count}ng {odd_digit_count} of the {odd_digit_count}nput.\"\n \n # Append the output string to the result list\n result.append(output)\n \n return result", "matching_cluster_idx": 3}]}, "HumanEval/119": {"dps": 80.46511627906976, "dps_norm": 86.66666666666667, "pass@1": 15.0, "profiled": [{"solution": "def match_parens(lst):\n \"\"\"\n Checks if it is possible to concatenate the two strings in some order,\n such that the resulting string will be good (i.e., all parentheses are balanced).\n \n Args:\n lst (list): A list containing two strings, both consisting of open or close parentheses.\n \n Returns:\n str: 'Yes' if there's a way to make a good string, 'No' otherwise.\n \"\"\"\n \n def is_balanced(s):\n \"\"\"Checks if a string of parentheses is balanced.\"\"\"\n balance = 0\n for c in s:\n if c == '(':\n balance += 1\n elif c == ')':\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n return 'Yes' if is_balanced(''.join(lst)) or is_balanced(''.join(lst[::-1])) else 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n '''\n Checks if two lists of parentheses can be concatenated in some order\n to make a good string.\n\n Args:\n lst (list): A list of two lists of parentheses.\n\n Returns:\n str: 'Yes' if it's possible to concatenate the strings to make a good string,\n 'No' otherwise.\n '''\n def can_balance(lst):\n stack = []\n for char in lst:\n if char == '(':\n stack.append(char)\n elif char == ')':\n if stack:\n stack.pop()\n else:\n return False\n return not stack\n\n list1, list2 = lst\n return 'Yes' if can_balance(list1 + list2) or can_balance(list2 + list1) else 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n '''\n def can_balance(s):\n balance = 0\n for c in s:\n if c == '(':\n balance += 1\n elif c == ')':\n if balance == 0:\n return False\n balance -= 1\n return balance == 0\n\n if can_balance(lst[0] + lst[1]) or can_balance(lst[1] + lst[0]):\n return 'Yes'\n else:\n return 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n '''\n Checks if it is possible to concatenate the two strings in some order, that the resulting string will be good.\n \n Args:\n lst (list): A list of two strings, both strings consist of open parentheses '(' or close parentheses ')' only.\n \n Returns:\n str: 'Yes' if there's a way to make a good string, 'No' otherwise.\n '''\n def good_string(s):\n '''Checks if a string is good (all parentheses are balanced)'''\n stack = []\n for char in s:\n if char == '(':\n stack.append(char)\n elif char == ')':\n if len(stack) == 0 or stack.pop() != '(':\n return False\n return len(stack) == 0\n\n first, second = lst\n return 'Yes' if good_string(first + second) or good_string(second + first) else 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n \"\"\"\n Checks if two lists of parentheses can be concatenated in some order to form a good string.\n\n A string S is considered to be good if and only if all parentheses in S are balanced.\n \n Args:\n lst (list): A list of two strings, both strings consist of open parentheses '(' or close parentheses ')'.\n\n Returns:\n str: 'Yes' if there's a way to make a good string, 'No' otherwise.\n \"\"\"\n def can_be_balanced(string):\n \"\"\"\n Checks if a string can be balanced.\n \n Args:\n string (str): The input string.\n\n Returns:\n bool: True if the string can be balanced, False otherwise.\n \"\"\"\n balance = 0\n for char in string:\n if char == '(':\n balance += 1\n elif char == ')':\n if balance == 0:\n return False\n balance -= 1\n return balance == 0\n\n # Try all permutations of the input strings\n import itertools\n for string1, string2 in itertools.permutations(lst):\n # Check if the current permutation can be balanced\n if can_be_balanced(string1 + string2):\n return 'Yes'\n \n return 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n\n def count_parens(s):\n # Initialize a stack to track opening and closing parentheses\n opening_brackets = 0\n for char in s:\n if char == '(':\n opening_brackets += 1\n elif char == ')':\n if opening_brackets == 0:\n return False\n opening_brackets -= 1\n return opening_brackets == 0\n\n # Check all possible combinations of concatenation\n return 'Yes' if count_parens(lst[0] + lst[1]) or count_parens(lst[1] + lst[0]) else 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n '''\n Check if two lists of parentheses can be concatenated to form a valid string.\n\n Args:\n lst (list): A list containing two strings of parentheses.\n\n Returns:\n str: 'Yes' if a valid string can be formed, 'No' otherwise.\n '''\n def check_sanity(s):\n '''Check if a string of parentheses is valid'''\n stack = []\n for c in s:\n if c == '(':\n stack.append(c)\n elif c == ')':\n if not stack:\n return False\n stack.pop()\n return not stack\n\n # Separate and check each string\n s1, s2 = lst\n s1, s2 = s1.replace('(', '1').replace(')', '2'), s2.replace('(', '1').replace(')', '2')\n \n # Check s1 + s2\n s = s1 + s2\n if check_sanity(s.replace('1', '(').replace('2', ')')):\n return 'Yes'\n\n # Check s2 + s1\n s = s2 + s1\n if check_sanity(s.replace('1', '(').replace('2', ')')):\n return 'Yes'\n\n # If none of the options work\n return 'No'", "matching_cluster_idx": 0}, {"solution": "def match_parens(lst):\n '''\n Returns 'Yes' if the given list of strings can be concatenated to form a good string,\n and 'No' otherwise.\n A string is considered good if it has balanced parentheses.\n\n Args:\n lst (list): A list of two strings, each consisting of parentheses only.\n\n Returns:\n str: 'Yes' or 'No'\n '''\n def can_balance(s):\n '''Check if a string can be balanced'''\n open_parens = 0\n for c in s:\n if c == '(':\n open_parens += 1\n elif c == ')':\n if open_parens == 0:\n return False\n open_parens -= 1\n return open_parens == 0\n\n # Split the input list into two strings and check all combinations\n for p in [''.join(lst), ''.join(reversed(lst)), lst[0] + lst[1], lst[1] + lst[0]]:\n if can_balance(p):\n return 'Yes'\n return 'No'", "matching_cluster_idx": 2}, {"solution": "def match_parens(lst):\n \"\"\"\n Checks if a list of two strings of parentheses can be concatenated to a balanced string.\n\n Args:\n lst (list): A list of two strings consisting of '(' and ')'.\n\n Returns:\n str: 'Yes' if the strings can be concatenated to a balanced string, 'No' otherwise.\n \"\"\"\n def can_balance(first, second):\n \"\"\"Check if the first string can be balanced by the second string.\"\"\"\n balance = 0\n for char in first + second:\n if char == '(':\n balance += 1\n else:\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n return 'Yes' if can_balance(lst[0], lst[1]) or can_balance(lst[1], lst[0]) else 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n '''\n Check if two strings of parentheses can be concatenated in a way that results\n in a balanced string.\n\n Args:\n lst (list): A list of two strings consisting of parentheses only.\n\n Returns:\n str: 'Yes' if a balanced string can be formed, 'No' otherwise.\n '''\n def is_balanced(s):\n '''\n Check if a string of parentheses is balanced.\n\n Args:\n s (str): A string consisting of parentheses.\n\n Returns:\n bool: True if the string is balanced, False otherwise.\n '''\n stack = []\n for c in s:\n if c == '(':\n stack.append(c)\n elif c == ')':\n if not stack:\n return False\n stack.pop()\n return not stack\n\n s1, s2 = lst[0], lst[1]\n if not is_balanced(s1 + s2) and not is_balanced(s2 + s1):\n return 'No'\n else:\n return 'Yes'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n \"\"\"\n Checks if it is possible to concatenate two strings of parentheses in some order\n to get a balanced string.\n\n Args:\n lst (list): A list containing two strings of parentheses.\n\n Returns:\n str: 'Yes' if it is possible to get a balanced string, 'No' otherwise.\n \"\"\"\n\n def balance(close, open_: str) -> bool:\n \"\"\"\n Checks if a given string can be balanced by appending the other string.\n \"\"\"\n stack = []\n for char in open_ + close:\n if char == '(':\n stack.append(char)\n elif char == ')':\n if stack:\n stack.pop()\n else:\n return False\n return not stack # All parentheses are balanced if the stack is empty\n\n open_, close = lst\n return 'Yes' if balance(close, open_) or balance(open_, close) else 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n \"\"\"\n Checks if it is possible to concatenate the two strings in a list so that the\n resulting string is balanced.\n\n Args:\n lst (list): A list of two strings, both consisting of open and close parentheses only.\n\n Returns:\n str: 'Yes' if a good string can be formed, 'No' otherwise.\n \"\"\"\n def can_balance(s):\n # Count the difference in parentheses\n diff = 0\n for c in s:\n if c == '(':\n diff += 1\n elif c == ')':\n diff -= 1\n if diff < 0:\n return False\n return diff == 0\n\n # Try all permutations of the input list\n import itertools\n for perm in itertools.permutations(lst):\n # Join the permutation into a single string\n s = ''.join(perm)\n # If the string is balanced, return 'Yes'\n if can_balance(s):\n return 'Yes'\n\n # If no permutation is balanced, return 'No'\n return 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n '''\n Check if two lists of parentheses can be concatenated into a balanced string.\n \n Args:\n lst (list): A list of two strings, each containing only open and close parentheses.\n \n Returns:\n str: 'Yes' if it's possible to create a balanced string, 'No' otherwise.\n '''\n def balance(s):\n '''Check if a string is balanced.'''\n stack = []\n for c in s:\n if c == '(':\n stack.append(c)\n elif c == ')':\n if not stack:\n return False\n stack.pop()\n return not stack # A string is balanced if the stack is empty\n\n # Try all possible concatenations of the two input strings\n for s1 in (lst[0] + lst[1], lst[1] + lst[0]):\n if balance(s1):\n return 'Yes'\n return 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n \"\"\"\n Checks if it is possible to concatenate the two strings in some order, \n that the resulting string will be good (balanced).\n\n Args:\n lst (list): A list of two strings, both strings consist of open and close parentheses.\n\n Returns:\n str: 'Yes' if there's a way to make a good string, 'No' otherwise.\n \"\"\"\n def is_balanced(s):\n # Initialize count of open parentheses\n open_count = 0\n \n # Check each character in the string\n for c in s:\n # If the character is an open parenthesis, increment count\n if c == '(':\n open_count += 1\n # If the character is a close parenthesis, decrement count\n elif c == ')':\n # If the count is already zero, the string is not balanced\n if open_count == 0:\n return False\n open_count -= 1\n # The string is balanced if the count of open parentheses is zero\n return open_count == 0\n\n # Generate all possible orderings of the strings in the list\n import itertools\n for perm in itertools.permutations(lst):\n # Join the strings in the current ordering\n s = ''.join(perm)\n # If the resulting string is balanced, return 'Yes'\n if is_balanced(s):\n return 'Yes'\n\n # If no ordering results in a balanced string, return 'No'\n return 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Args:\n lst (list): A list of two strings, each containing open or close parentheses.\n\n Returns:\n str: 'Yes' if a good string can be formed, 'No' otherwise.\n '''\n\n def can_balance(s):\n \"\"\"Check if a string can be balanced.\"\"\"\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n elif char == ')':\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n # Try all possible combinations of the two strings\n for i in range(2):\n for j in range(2):\n s = ''.join(lst[i]) + lst[1-i]\n if can_balance(s):\n return 'Yes'\n return 'No'", "matching_cluster_idx": 0}]}, "HumanEval/120": {"dps": null, "dps_norm": null, "pass@1": 1.0, "profiled": []}, "HumanEval/121": {"dps": 78.02690582959642, "dps_norm": 57.142857142857146, "pass@1": 93.0, "profiled": [{"solution": "def solution(lst):\n \"\"\"\n Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n Args:\n lst (list): A non-empty list of integers.\n \n Returns:\n int: The sum of all odd elements in even positions.\n \"\"\"\n # Check if the input list is empty\n if not lst:\n raise ValueError(\"Input list cannot be empty\")\n \n # Use list comprehension to filter the list and calculate the sum\n return sum(num for i, num in enumerate(lst) if i % 2 == 0 and num % 2 != 0)", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n \"\"\"\n Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n\n Parameters:\n lst (list): A list of integers.\n\n Returns:\n int: The sum of all odd elements in even positions.\n\n Examples:\n >>> solution([5, 8, 7, 1])\n 12\n >>> solution([3, 3, 3, 3, 3])\n 9\n >>> solution([30, 13, 24, 321])\n 0\n \"\"\"\n return sum(num for i, num in enumerate(lst) if i % 2 == 0 and num % 2 != 0)", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n \"\"\"\n Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n\n Args:\n lst (list): A list of integers.\n\n Returns:\n int: The sum of all odd elements in even positions.\n\n Examples:\n >>> solution([5, 8, 7, 1])\n 12\n >>> solution([3, 3, 3, 3, 3])\n 9\n >>> solution([30, 13, 24, 321])\n 321\n \"\"\"\n # Use list comprehension to filter even positions (0, 2, 4, ...) and keep only odd numbers\n odd_even_positions = [num for i, num in enumerate(lst) if i % 2 == 0 and num % 2 != 0]\n return sum(odd_even_positions)", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n \"\"\"\n Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n\n Args:\n lst (list): A list of integers.\n\n Returns:\n int: The sum of odd elements in even positions.\n\n Examples:\n >>> solution([5, 8, 7, 1])\n 12\n >>> solution([3, 3, 3, 3, 3])\n 9\n >>> solution([30, 13, 24, 321])\n 0\n \"\"\"\n return sum(num for i, num in enumerate(lst) if i % 2 == 0 and num % 2 != 0)", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n\n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==>0\n \"\"\"\n # Use list comprehension to create a new list that includes only the odd numbers at even positions\n odd_even_positions = [num for i, num in enumerate(lst) if i % 2 == 0 and num % 2 != 0]\n # Sum the new list of numbers\n return sum(odd_even_positions)", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n \"\"\"\n Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n\n Args:\n lst (list): A non-empty list of integers.\n\n Returns:\n int: The sum of all of the odd elements at even positions in the list.\n \"\"\"\n return sum(num for i, num in enumerate(lst) if i % 2 == 0 and num % 2 == 1)", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n \"\"\"\n Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n\n Args:\n lst (list): A non-empty list of integers.\n\n Returns:\n int: The sum of all of the odd elements at even positions in the list.\n\n Examples:\n >>> solution([5, 8, 7, 1])\n 12\n >>> solution([3, 3, 3, 3, 3])\n 9\n >>> solution([30, 13, 24, 321])\n 0\n \"\"\"\n return sum(num for i, num in enumerate(lst) if i % 2 == 0 and num % 2 != 0)", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n \"\"\"\n Returns the sum of all odd elements at even positions in the list.\n \n Parameters:\n lst (list): A list of integers.\n \n Returns:\n int: The sum of odd elements at even positions.\n \"\"\"\n return sum([x for i, x in enumerate(lst) if i % 2 == 0 and x % 2 != 0])", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n \"\"\"\n Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n\n Args:\n lst (list): A non-empty list of integers.\n\n Returns:\n int: The sum of all odd elements in even positions.\n\n Examples\n --------\n >>> solution([5, 8, 7, 1])\n 12\n >>> solution([3, 3, 3, 3, 3])\n 9\n >>> solution([30, 13, 24, 321])\n 0\n \"\"\"\n return sum(num for i, num in enumerate(lst) if i % 2 == 0 and num % 2 != 0)", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n \"\"\"\n Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n Args:\n lst (list): A non-empty list of integers.\n \n Returns:\n int: The sum of all the odd elements at even positions in the list.\n \n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n return sum(num for i, num in enumerate(lst) if i % 2 == 0 and num % 2 != 0)", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n \"\"\"\n Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n\n Args:\n lst (list): A list of integers.\n\n Returns:\n int: The sum of odd elements at even positions in the list.\n \"\"\"\n return sum(num for i, num in enumerate(lst) if i % 2 == 0 and num % 2 != 0)", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n\n Args:\n lst (list): A list of integers.\n\n Returns:\n int: The sum of odd elements in even positions.\n\n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==>0\n \"\"\"\n return sum(num for i, num in enumerate(lst) if i % 2 == 0 and num % 2 != 0)", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n \"\"\"\n Given a non-empty list of integers, return the sum of all of the odd elements \n that are in even positions.\n\n Args:\n lst (list): A list of integers.\n\n Returns:\n int: Sum of odd elements at even positions.\n \"\"\"\n return sum(num for i, num in enumerate(lst) if i % 2 == 0 and num % 2 != 0)", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n \"\"\"\n Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n\n Args:\n lst (list): A list of integers.\n\n Returns:\n int: The sum of odd elements at even positions.\n \"\"\"\n return sum(num for i, num in enumerate(lst) if i % 2 == 0 and num % 2 != 0)", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n \"\"\"\n Returns the sum of all odd numbers in even positions of a given list.\n \n Parameters:\n lst (list): A list of integers.\n \n Returns:\n int: The sum of all odd numbers in even positions of the input list.\n \"\"\"\n return sum(num for i, num in enumerate(lst) if i % 2 == 0 and num % 2 != 0)", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n\n Args:\n lst (list): A list of integers.\n\n Returns:\n int: The sum of all odd elements at even positions.\n\n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n # Initialize sum variable to store the sum of odd elements at even positions\n total_sum = 0\n \n # Iterate through the list\n for index, num in enumerate(lst):\n # Check if the index is even and the number is odd\n if index % 2 == 0 and num % 2 != 0:\n # Add the odd number at even position to the total sum\n total_sum += num\n \n # Return the total sum\n return total_sum", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n \"\"\"\n Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n\n Args:\n lst (list): A non-empty list of integers.\n\n Returns:\n int: The sum of all odd elements in even positions.\n\n Examples:\n solution([5, 8, 7, 1]) == 12\n solution([3, 3, 3, 3, 3]) == 9\n solution([30, 13, 24, 321]) ==0\n \"\"\"\n return sum(num for i, num in enumerate(lst) if i % 2 == 0 and num % 2 == 1)", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n \"\"\"\n Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n \n Args:\n lst (list): A list of integers.\n \n Returns:\n int: Sum of odd elements at even positions.\n \"\"\"\n return sum(num for i, num in enumerate(lst) if i % 2 == 0 and num % 2 != 0)", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n \"\"\"\n Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n\n Args:\n lst (list): A list of integers\n\n Returns:\n int: The sum of all odd elements at even positions\n \"\"\"\n # Initialize sum variable\n total_sum = 0\n # Iterate over the list with enumerate to get index and value\n for i, num in enumerate(lst):\n # Check if the index is even and the number is odd\n if i % 2 == 0 and num % 2 != 0:\n # Add the number to the sum\n total_sum += num\n # Return the total sum\n return total_sum", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\"\"\"\n return sum(num for i, num in enumerate(lst) if i % 2 == 0 and num % 2 != 0)", "matching_cluster_idx": 3}]}, "HumanEval/149": {"dps": 85.82677165354332, "dps_norm": 57.142857142857146, "pass@1": 52.0, "profiled": [{"solution": "def sorted_list_sum(lst):\n \"\"\"\n This function accepts a list of strings, removes strings with odd lengths, \n sorts the list by the length of the strings, and then alphabetically.\n \n Parameters:\n lst (list): A list of strings.\n \n Returns:\n list: The filtered list of strings sorted by length and then alphabetically.\n \"\"\"\n \n # Use a list comprehension to filter out strings with odd lengths\n filtered_list = [string for string in lst if len(string) % 2 == 0]\n \n # Use the sorted function with a custom sorting key\n # The key is a tuple of the length of the string and the string itself\n # Python's tuple sorting is stable, so when two strings have the same length, they will keep their original order\n sorted_list = sorted(filtered_list, key=lambda string: (len(string), string))\n \n return sorted_list", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"\n Deletes strings of odd length from a list, sorts the remaining strings by length and then alphabetically,\n and returns the sorted list.\n\n Args:\n lst (list): A list of strings.\n\n Returns:\n list: A list of strings with odd length strings removed and sorted.\n \"\"\"\n # Use list comprehension to filter out strings of odd lengths\n filtered_list = [s for s in lst if len(s) % 2 == 0]\n \n # Sort the list first by length and then alphabetically\n sorted_list = sorted(filtered_list, key=lambda s: (len(s), s))\n \n return sorted_list", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"\n This function accepts a list of strings, filters out strings of odd lengths,\n sorts the remaining strings by length and then alphabetically, and returns the sorted list.\n\n Args:\n lst (list): A list of strings\n\n Returns:\n list: A sorted list of strings\n \"\"\"\n # Filter the list to include only strings of even lengths\n even_len_lst = [word for word in lst if len(word) % 2 == 0]\n \n # Sort the list first by the length of each word and then alphabetically\n sorted_lst = sorted(even_len_lst, key=lambda x: (len(x), x))\n \n return sorted_lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"\n Deletes strings with odd lengths from a list, sorts the rest by length and then alphabetically, \n and returns the resulted list.\n\n Args:\n lst (list): A list of strings.\n\n Returns:\n list: The list of strings with odd lengths removed, sorted by length and then alphabetically.\n \"\"\"\n # Use list comprehension to filter out strings with odd lengths\n filtered_lst = [s for s in lst if len(s) % 2 == 0]\n \n # Sort the list first by length and then alphabetically\n sorted_lst = sorted(filtered_lst, key=lambda x: (len(x), x))\n \n return sorted_lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"\n Deletes strings of odd length from the list, sorts the remaining strings\n by their lengths in ascending order and then alphabetically.\n\n Args:\n lst (list): A list of strings.\n\n Returns:\n list: The filtered and sorted list of strings.\n \"\"\"\n\n # Filter the list to include only strings with even lengths\n even_length_lst = [s for s in lst if len(s) % 2 == 0]\n \n # Sort the list by the length of each string in ascending order and then alphabetically\n sorted_lst = sorted(even_length_lst, key=lambda x: (len(x), x))\n \n return sorted_lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"\n Deletes the strings that have odd lengths from the list, \n and returns the resulted list with a sorted order.\n\n The order of the list is ascending by length of each word, \n and then sorted alphabetically if two words have the same length.\n\n Parameters:\n lst (list): A list of strings.\n\n Returns:\n list: The list of strings with odd-length strings removed and sorted.\n \"\"\"\n # Filter out strings with odd lengths\n filtered_list = [s for s in lst if len(s) % 2 == 0]\n \n # Sort the list by length and then alphabetically\n sorted_list = sorted(filtered_list, key=lambda s: (len(s), s))\n \n return sorted_list", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"\n Deletes strings of odd lengths from a list, sorts the remaining strings by length and then alphabetically.\n\n Args:\n lst (list): A list of strings.\n\n Returns:\n list: A list of strings after deleting odd-length strings and sorting the remaining strings.\n \"\"\"\n # Filter out strings with odd lengths\n even_length_lst = [s for s in lst if len(s) % 2 == 0]\n \n # Sort the list based on the length of the strings and then alphabetically\n sorted_lst = sorted(even_length_lst, key=lambda x: (len(x), x))\n \n return sorted_lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"\n Deletes the strings that have odd lengths from the given list, \n and returns the resulted list with a sorted order.\n \n Args:\n lst (list): A list of strings.\n \n Returns:\n list: A list of strings sorted by length and then alphabetically.\n \"\"\"\n \n # Use a list comprehension to filter out strings with odd lengths\n filtered_lst = [word for word in lst if len(word) % 2 == 0]\n \n # Use the sorted function with a custom sorting key\n # The sorted function returns a new sorted list and leaves the original list unchanged\n sorted_lst = sorted(filtered_lst, key=lambda x: (len(x), x))\n \n return sorted_lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"\n This function accepts a list of strings, removes strings with odd lengths,\n and returns the resulted list sorted in ascending order by string length,\n and if two strings have the same length, sorted alphabetically.\n\n Args:\n lst (list): A list of strings\n\n Returns:\n list: The filtered and sorted list of strings\n \"\"\"\n\n # Filter out strings with odd lengths\n even_length_strs = [str for str in lst if len(str) % 2 == 0]\n\n # Sort the list first by string length and then alphabetically\n sorted_strs = sorted(even_length_strs, key=lambda x: (len(x), x))\n\n return sorted_strs", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"\n Deletes the strings that have odd lengths from the list, and returns the resulted list with a sorted order.\n \n The list is sorted by length of each word in ascending order and then by alphabetical order.\n \n Args:\n lst (list): A list of strings\n \n Returns:\n list: A list of strings in sorted order\n \"\"\"\n # Filter out strings with odd lengths and sort the list\n return sorted([word for word in lst if len(word) % 2 == 0], \n key=lambda x: (len(x), x))", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"\n Deletes strings of odd lengths from the list, and returns the list in \n sorted order by string length (ascending) and then alphabetically (in case of a tie).\n\n Args:\n lst (list): A list of strings\n\n Returns:\n list: A list of strings with even length, sorted by length and then alphabetically.\n \"\"\"\n # Filter out strings with odd lengths\n even_length_strings = [s for s in lst if len(s) % 2 == 0]\n \n # Sort the list of strings first by length and then alphabetically\n sorted_strings = sorted(even_length_strings, key=lambda x: (len(x), x))\n \n return sorted_strings", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"\n Deletes the strings with odd lengths from the list, sorts the remaining strings \n by their length and then alphabetically, and returns the sorted list.\n\n Parameters:\n lst (list): A list of strings.\n\n Returns:\n list: A list of strings with strings of odd lengths removed, sorted by length and then alphabetically.\n \"\"\"\n # Filter out the strings with odd lengths\n even_length_strings = [word for word in lst if len(word) % 2 == 0]\n \n # Sort the remaining strings by length and then alphabetically\n sorted_strings = sorted(even_length_strings, key=lambda x: (len(x), x))\n \n return sorted_strings", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"\n This function filters out the strings of odd length from the given list,\n and returns the resulting list in ascending order by length and then alphabetically.\n\n Parameters:\n lst (list): A list of strings\n\n Returns:\n list: A list of strings with even lengths, sorted by length and then alphabetically\n \"\"\"\n\n # First, we filter the list to include only strings of even lengths\n even_length_strings = [s for s in lst if len(s) % 2 == 0]\n\n # Then, we sort the list of even length strings by length and then alphabetically\n # We use the sorted function with a custom sorting key\n # The key is a tuple where the first element is the length of the string and the second element is the string itself\n # The sorted function will first sort by the first element of the tuple (length), and in case of a tie, it will sort by the second element (the string itself)\n sorted_list = sorted(even_length_strings, key=lambda x: (len(x), x))\n\n return sorted_list", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"\n Removes strings with odd lengths from the input list and returns the sorted list of strings.\n The list is sorted by the length of each word in ascending order. If two words have the same length, they are sorted alphabetically.\n \n Parameters:\n lst (list): A list of strings.\n \n Returns:\n list: A sorted list of strings.\n \"\"\"\n # Filter the list to only include strings with even lengths\n even_length_list = [word for word in lst if len(word) % 2 == 0]\n \n # Sort the filtered list by string length and then alphabetically\n sorted_list = sorted(even_length_list, key=lambda x: (len(x), x))\n \n return sorted_list", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"\n This function accepts a list of strings as a parameter, deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order.\n\n The order of the list should be ascending by length of each word, and you should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n\n Args:\n lst (list): A list of strings\n\n Returns:\n list: A list of strings in sorted order\n \"\"\"\n # Use list comprehension to filter out strings with odd lengths\n filtered_list = [word for word in lst if len(word) % 2 == 0]\n \n # Sort the list first by length and then by alphabetical order\n sorted_list = sorted(filtered_list, key=lambda x: (len(x), x))\n \n return sorted_list", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"\n Deletes strings of odd lengths from a list, sorts the rest in ascending order of length\n and then alphabetically.\n \n Args:\n lst (list): A list of strings.\n \n Returns:\n list: The filtered and sorted list of strings.\n \"\"\"\n \n # Filter out strings of odd lengths\n even_length_strings = [s for s in lst if len(s) % 2 == 0]\n \n # Sort the list by string length and then alphabetically\n sorted_list = sorted(even_length_strings, key=lambda x: (len(x), x))\n \n return sorted_list", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"\n Delete the strings that have odd lengths from the input list, \n and return the resulted list with a sorted order.\n \n Args:\n lst (list): A list of strings.\n \n Returns:\n list: A list of strings sorted by length and then alphabetically.\n \"\"\"\n # Filter out strings with odd lengths from the input list\n filtered_list = [string for string in lst if len(string) % 2 == 0]\n \n # Sort the filtered list by length and then alphabetically\n sorted_list = sorted(filtered_list, key=lambda x: (len(x), x))\n \n return sorted_list", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"\n This function deletes the strings with odd lengths from the input list, \n and returns the resulted list sorted by the length of the strings in ascending order.\n If two strings have the same length, they are sorted alphabetically.\n\n Parameters:\n lst (list): A list of strings.\n\n Returns:\n list: A list of strings with odd-length strings removed, sorted by length and then alphabetically.\n \"\"\"\n # Filter out strings with odd lengths\n even_length_strings = [s for s in lst if len(s) % 2 == 0]\n \n # Sort the list based on the length of the strings and then alphabetically\n sorted_lst = sorted(even_length_strings, key=lambda x: (len(x), x))\n \n return sorted_lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"\n This function sorts a list of strings, removes strings with odd length, \n and returns the sorted list.\n \n Parameters:\n lst (list): A list of strings.\n \n Returns:\n list: A list of strings with odd length removed and sorted by length and then alphabetically.\n \"\"\"\n # Filter the list to keep only strings with even lengths\n even_length_strings = [string for string in lst if len(string) % 2 == 0]\n \n # Sort the list based on string length and then alphabetically\n sorted_list = sorted(even_length_strings, key=lambda x: (len(x), x))\n \n return sorted_list", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"\n This function takes a list of strings, removes words with odd lengths,\n sorts the list in ascending order by word length, and then alphabetically.\n\n Args:\n lst (list): A list of strings.\n\n Returns:\n list: A list of strings sorted by length and then alphabetically.\n \"\"\"\n # Filter out words with odd lengths\n even_length_words = [word for word in lst if len(word) % 2 == 0]\n \n # Sort the list first by length and then alphabetically\n sorted_words = sorted(even_length_words, key=lambda x: (len(x), x))\n \n return sorted_words", "matching_cluster_idx": 3}]}, "Mbpp/3": {"dps": 68.13559322033898, "dps_norm": 78.75, "pass@1": 100.0, "profiled": [{"solution": "def is_prime(n):\n \"\"\"\n Checks if a number is prime or not.\n Args:\n n (int): The number to be checked.\n Returns:\n bool: True if the number is prime, False otherwise.\n \"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True\ndef is_not_prime(n):\n \"\"\"\n Checks if a number is not prime.\n Args:\n n (int): The number to be checked.\n Returns:\n bool: True if the number is not prime, False otherwise.\n \"\"\"\n return not is_prime(n)", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n \"\"\"\n This function determines whether a number is not prime or not.\n \n Args:\n n (int): The number to check for non-primality.\n \n Returns:\n bool: False if the number is prime, True if the number is not prime.\n \"\"\"\n if n <= 1:\n return True # 0 and 1 are not prime, but we are looking for numbers that are not prime\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return True\n return False", "matching_cluster_idx": 5}, {"solution": "def is_prime(n):\n \"\"\"Checks if a number is prime\"\"\"\n if n <= 1:\n return False\n elif n <= 3:\n return True\n elif n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True\ndef is_not_prime(n):\n \"\"\"Checks if a number is not prime\"\"\"\n return not is_prime(n)", "matching_cluster_idx": 7}, {"solution": "def is_prime(n):\n \"\"\"\n Checks if a number is prime.\n\n Args:\n n (int): The number to check for primality.\n\n Returns:\n bool: True if the number is prime, False otherwise.\n \"\"\"\n if n <= 1:\n return False\n for i in range(2, n):\n if n % i == 0:\n return False\n return True\ndef is_not_prime(n):\n \"\"\"\n Checks if a number is not prime.\n\n Args:\n n (int): The number to check.\n\n Returns:\n bool: True if the number is not prime, False otherwise.\n \"\"\"\n return not is_prime(n)", "matching_cluster_idx": 1}, {"solution": "def is_not_prime(n):\n \"\"\"\n Checks if a number is not prime.\n\n Args:\n n (int): The number to check.\n\n Returns:\n bool: True if n is not prime, False otherwise.\n\n \"\"\"\n # Helper function to check if a number is prime\n def is_prime(num):\n if num < 2:\n return False\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n return False\n return True\n\n # If the number is prime, return False, otherwise return True\n return not is_prime(n)", "matching_cluster_idx": 5}, {"solution": "def is_prime(n):\n \"\"\"Check if a number is prime.\"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True\ndef is_not_prime(n):\n \"\"\"Check if a number is not prime.\"\"\"\n return not is_prime(n)", "matching_cluster_idx": 5}, {"solution": "def is_prime(n):\n \"\"\"\n Checks if a number is prime.\n \n Args:\n n (int): The number to check.\n \n Returns:\n bool: True if the number is prime, False otherwise.\n \"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True\ndef is_not_prime(n):\n \"\"\"\n Checks if a number is not prime.\n \n Args:\n n (int): The number to check.\n \n Returns:\n bool: True if the number is not prime, False otherwise.\n \"\"\"\n return not is_prime(n)", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(n):\n \"\"\"\n Checks if a number is not prime.\n \n A number is considered prime if it has exactly two distinct positive divisors: 1 and itself.\n \n Parameters:\n n (int): The number to check.\n \n Returns:\n bool: True if the number is not prime, False otherwise.\n \"\"\"\n if n <= 1: # Numbers less than or equal to 1 are not prime\n return True\n if n <= 3: # 2 and 3 are prime numbers\n return False\n if n % 2 == 0 or n % 3 == 0: # Check for divisibility by 2 and 3\n return True\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0: # Check for other divisors\n return True\n i += 6\n return False", "matching_cluster_idx": 7}, {"solution": "def is_prime(n):\n \"\"\"\n Checks if a number is prime.\n\n Args:\n n (int): The number to check.\n\n Returns:\n bool: True if the number is prime, False otherwise.\n \"\"\"\n if n <= 1:\n return False\n if n == 2:\n return True\n if n % 2 == 0:\n return False\n max_divisor = int(n**0.5) + 1\n for d in range(3, max_divisor, 2):\n if n % d == 0:\n return False\n return True\ndef is_not_prime(n):\n \"\"\"\n Checks if a number is not prime.\n\n Args:\n n (int): The number to check.\n\n Returns:\n bool: True if the number is not prime, False otherwise.\n \"\"\"\n return not is_prime(n)", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n \"\"\"\n Check if a number is not prime.\n \n Parameters:\n n (int): The number to check for primality.\n \n Returns:\n bool: False if the number is not a prime, True otherwise.\n \"\"\"\n if n <= 1:\n return True # all single-digit numbers are not prime\n \n # check for factors other than 1 and itself\n for i in range(2, n):\n if n % i == 0:\n return True # found a factor, not a prime number\n \n return False # no factors found, a prime number", "matching_cluster_idx": 1}, {"solution": "def is_not_prime(n):\n \"\"\"\n Returns False if the given number is prime, True if it's not.\n \n Args:\n n (int): The number to check.\n \n Returns:\n bool: Whether the number is not prime.\n \"\"\"\n if n < 2:\n return True # By definition, numbers less than 2 are not prime\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return True # If the number is divisible by any number other than 1 and itself, it's not prime\n return False # If the number isn't divisible by any number up to its square root, it's prime", "matching_cluster_idx": 5}, {"solution": "def is_prime(n):\n if n <= 1:\n return False\n if n == 2:\n return True\n if n % 2 == 0:\n return False\n max_divisor = int(n**0.5) + 1\n for d in range(3, max_divisor, 2):\n if n % d == 0:\n return False\n return True\ndef is_not_prime(n):\n return not is_prime(n)", "matching_cluster_idx": 7}, {"solution": "def is_prime(n):\n \"\"\"\n Checks if a number is prime.\n \n Args:\n n (int): The number to check.\n \n Returns:\n bool: True if the number is prime, False otherwise.\n \"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True\ndef is_not_prime(n):\n \"\"\"\n Checks if a number is not prime.\n \n Args:\n n (int): The number to check.\n \n Returns:\n bool: True if the number is not prime, False otherwise.\n \"\"\"\n return not is_prime(n)", "matching_cluster_idx": 5}, {"solution": "def is_prime(n):\n \"\"\"\n Checks if a number is prime.\n\n Args:\n n (int): The number to check.\n\n Returns:\n bool: True if the number is prime, False otherwise.\n \"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True\ndef is_not_prime(n):\n \"\"\"\n Checks if a number is not prime.\n\n Args:\n n (int): The number to check.\n\n Returns:\n bool: True if the number is not prime, False otherwise.\n \"\"\"\n return not is_prime(n)", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(n):\n \"\"\"\n Checks if a number is not a prime number.\n\n Args:\n n (int): The number to check.\n\n Returns:\n bool: True if the number is not prime, False otherwise.\n \"\"\"\n if n <= 1:\n return True\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return True\n return False", "matching_cluster_idx": 5}, {"solution": "def is_prime(n):\n \"\"\"Check if a number is prime\"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True\ndef is_not_prime(n):\n \"\"\"Check if a number is not prime\"\"\"\n return not is_prime(n)", "matching_cluster_idx": 5}, {"solution": "def is_prime(n):\n \"\"\"\n Checks if a number is prime.\n \n Args:\n n (int): The number to check.\n \n Returns:\n bool: True if the number is prime, False otherwise.\n \"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True\ndef is_not_prime(n):\n \"\"\"\n Checks if a number is not prime.\n \n Args:\n n (int): The number to check.\n \n Returns:\n bool: True if the number is not prime, False otherwise.\n \"\"\"\n return not is_prime(n)", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n \"\"\"\n Checks if a number is not prime.\n \n Args:\n n (int): The number to check.\n \n Returns:\n bool: True if the number is not prime, False otherwise.\n \"\"\"\n if n <= 1:\n return True\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return True\n return False", "matching_cluster_idx": 5}, {"solution": "def is_prime(n):\n \"\"\"\n Check if a number is prime.\n \n Parameters:\n n (int): The number to check.\n \n Returns:\n bool: True if the number is prime, False otherwise.\n \"\"\"\n if n <= 1:\n return False\n if n == 2:\n return True\n if n % 2 == 0:\n return False\n max_divisor = int(n**0.5) + 1\n for d in range(3, max_divisor, 2):\n if n % d == 0:\n return False\n return True\ndef is_not_prime(n):\n \"\"\"\n Check if a number is not prime.\n \n Parameters:\n n (int): The number to check.\n \n Returns:\n bool: True if the number is not prime, False otherwise.\n \"\"\"\n return not is_prime(n)", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n \"\"\"\n Checks if a number is not prime.\n\n Args:\n n (int): The number to check.\n\n Returns:\n bool: False if the number is not prime, True otherwise.\n \"\"\"\n if n <= 1:\n return True # By definition, 0 and 1 are not considered prime numbers\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return True # If the number is divisible by any number between 2 and sqrt(n), it's not prime\n return False # If the number is not divisible by any of the above, it's prime", "matching_cluster_idx": 5}]}, "Mbpp/4": {"dps": 91.51877133105802, "dps_norm": 82.91666666666666, "pass@1": 84.0, "profiled": [{"solution": "import heapq\ndef heap_queue_largest(numbers, n):\n \"\"\"\n Find the n largest integers from a given list of numbers, returned in descending order.\n \n Parameters:\n numbers (list): A list of numbers\n n (int): The number of largest integers to find\n \n Returns:\n list: A list of the n largest integers in descending order\n \"\"\"\n # Use the nlargest function from the heapq module to get the n largest numbers\n largest_numbers = heapq.nlargest(n, numbers)\n \n # Return the n largest numbers\n return largest_numbers", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n \"\"\"\n Returns the n largest integers from a given list of numbers, in descending order.\n \n Args:\n nums (list): A list of integers.\n n (int): The number of largest integers to find.\n \n Returns:\n list: A list of the n largest integers in descending order.\n \"\"\"\n \n # Use the heapq.nlargest function to find the n largest numbers\n largest_nums = heapq.nlargest(n, nums)\n \n return largest_nums", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(lst, n):\n \"\"\"\n This function takes a list of numbers and returns the n largest integers in descending order.\n\n Parameters:\n lst (list): A list of numbers\n n (int): The number of largest integers to return\n\n Returns:\n list: A list of the n largest integers in descending order\n \"\"\"\n # Use a heap to get the n largest integers in O(n log n) time\n return heapq.nlargest(n, lst)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(lst, n):\n \"\"\"\n This function returns the n largest integers from a given list of numbers in descending order.\n \n Args:\n lst (list): A list of numbers.\n n (int): The number of largest integers to return.\n \n Returns:\n list: A list of the n largest integers in descending order.\n \"\"\"\n # Use the heapq.nlargest function to find the n largest integers in the list\n return heapq.nlargest(n, lst)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(lst, n):\n \"\"\"\n Returns the n largest integers from a given list of numbers, in descending order.\n \n Args:\n lst (list): A list of integers\n n (int): The number of largest integers to find\n \n Returns:\n list: A list of n largest integers in descending order\n \"\"\"\n # Use heapq.nlargest to get the n largest integers from the list\n largest = heapq.nlargest(n, lst)\n return largest", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n \"\"\"\n This function takes a list of numbers and returns the n largest integers in descending order.\n \n Args:\n nums (list): A list of integers.\n n (int): The number of largest integers to return.\n \n Returns:\n list: A list of the n largest integers in descending order.\n \"\"\"\n # Use the heapq.nlargest function to find the n largest numbers\n largest_nums = heapq.nlargest(n, nums)\n \n return largest_nums\nnums = [25, 35, 22, 85, 14, 65, 75, 22, 58]\nn = 3", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n \"\"\"\n Returns the n largest integers from a list of numbers in descending order.\n\n Args:\n nums (list): A list of integers.\n n (int): The number of largest integers to return.\n\n Returns:\n list: A list of the n largest integers in descending order.\n \"\"\"\n # Use heapq.nlargest to get the n largest integers in descending order\n return heapq.nlargest(n, nums)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n \"\"\"\n Find the n largest integers from a given list of numbers, returned in descending order.\n\n Args:\n nums (list): A list of numbers.\n n (int): The number of largest integers to find.\n\n Returns:\n list: A list of the n largest integers in descending order.\n\n Raises:\n ValueError: If n is greater than the length of the input list.\n \"\"\"\n if n > len(nums):\n raise ValueError(\"n cannot be greater than the length of the input list\")\n\n # Use a max heap to get the largest n numbers from the list\n return heapq.nlargest(n, nums)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n \"\"\"\n Returns the n largest integers from a given list of numbers in descending order.\n \n Args:\n nums (list): A list of numbers.\n n (int): The number of largest integers to return.\n \n Returns:\n list: A list of n largest integers in descending order.\n \"\"\"\n # Use heapq.nlargest to find the n largest numbers in the list\n largest_nums = heapq.nlargest(n, nums)\n return largest_nums", "matching_cluster_idx": 9}, {"solution": "import heapq\nimport unittest\ndef heap_queue_largest(nums, n):\n \"\"\"\n This function returns the n largest integers from a given list of numbers in descending order.\n\n Args:\n nums (list): A list of integers.\n n (int): The number of largest integers to return.\n\n Returns:\n list: A list of the n largest integers in descending order.\n \"\"\"\n # Use the nlargest function from the heapq module to get the n largest integers\n largest_nums = heapq.nlargest(n, nums)\n return largest_nums", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(lst, n):\n \"\"\"\n This function takes in a list of integers and returns the n largest integers in descending order.\n\n Args:\n lst (list): A list of integers.\n n (int): The number of largest integers to return.\n\n Returns:\n list: A list of the n largest integers in descending order.\n \"\"\"\n # Use heapq.nlargest function to get the n largest numbers in the list\n largest_numbers = heapq.nlargest(n, lst)\n \n # Return the largest_numbers list\n return largest_numbers", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(numbers, n):\n \"\"\"\n This function takes a list of numbers and an integer n as input, \n and returns the n largest integers from the list in descending order.\n\n Args:\n numbers (list): A list of integers.\n n (int): The number of largest integers to find.\n\n Returns:\n list: A list of the n largest integers in descending order.\n \"\"\"\n \n # Create a min heap and push all numbers into the heap\n min_heap = []\n for num in numbers:\n # If the heap size is less than n, push the number into the heap\n if len(min_heap) < n:\n heapq.heappush(min_heap, num)\n # If the heap size is equal to n and the number is greater than the smallest in the heap\n elif num > min_heap[0]:\n # Replace the smallest number with the new number and rebuild the heap\n heapq.heappop(min_heap)\n heapq.heappush(min_heap, num)\n \n # Sort the heap in descending order and return the result\n return sorted(min_heap, reverse=True)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(lst, n):\n \"\"\"\n Returns the n largest integers from a given list of numbers in descending order.\n\n Args:\n lst (list): A list of numbers\n n (int): The number of largest integers to return\n\n Returns:\n list: A list of the n largest integers in descending order\n \"\"\"\n # Use the nlargest function from the heapq module, which returns the n largest elements from the iterable specified by the key function\n return heapq.nlargest(n, lst)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(lst, n):\n \"\"\"\n Find the n largest integers from a given list of numbers, returned in descending order.\n \n Args:\n lst (list): A list of integers.\n n (int): The number of largest integers to return.\n\n Returns:\n list: The n largest integers from the input list in descending order.\n\n Example:\n >>> heap_queue_largest([25, 35, 22, 85, 14, 65, 75, 22, 58], 3)\n [85, 75, 65]\n \"\"\"\n # Create a copy of the input list to avoid modifying the original list\n numbers = lst.copy()\n \n # Convert the list to a heap in O(n) time\n heapq.heapify(numbers)\n \n # Extract the largest n numbers from the heap in O(n log n) time\n return heapq.nlargest(n, numbers)", "matching_cluster_idx": 8}, {"solution": "import heapq\ndef heap_queue_largest(lst, n):\n \"\"\"\n This function takes a list of numbers and an integer n, \n then returns the n largest integers from the list in descending order.\n\n Args:\n lst (list): A list of integers.\n n (int): The number of largest integers to return.\n\n Returns:\n list: A list of the n largest integers in descending order.\n \"\"\"\n\n # Check if n is not greater than the list length\n if n > len(lst):\n raise ValueError(\"n cannot be greater than the list length\")\n\n # Use the nlargest function from the heapq module to get the n largest numbers\n largest_nums = heapq.nlargest(n, lst)\n\n return largest_nums", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n \"\"\"\n Returns the n largest integers from a list of numbers in descending order.\n\n Args:\n nums (list): The list of numbers.\n n (int): The number of largest integers to return.\n\n Returns:\n list: A list of the n largest integers in descending order.\n \"\"\"\n return heapq.nlargest(n, nums)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n \"\"\"\n Return the n largest integers from the list of numbers in descending order.\n\n Args:\n nums (list): A list of integers.\n n (int): The number of largest integers to return.\n\n Returns:\n list: A list of the n largest integers in descending order.\n \"\"\"\n # Use the nlargest function from the heapq module to get the n largest elements\n largest_nums = heapq.nlargest(n, nums)\n return largest_nums", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(numbers, n):\n \"\"\"\n Find the n largest integers from a given list of numbers, returned in descending order.\n\n Args:\n numbers (list): A list of numbers.\n n (int): The number of largest numbers to find.\n\n Returns:\n list: A list of the n largest numbers in descending order.\n \"\"\"\n # Use the nlargest function from the heapq module to find the n largest numbers\n largest = heapq.nlargest(n, numbers)\n \n # Sort the largest numbers in descending order\n largest.sort(reverse=True)\n \n return largest", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(lst, n):\n \"\"\"\n Find the n largest integers from a given list of numbers.\n\n Args:\n lst (list): A list of numbers.\n n (int): The number of largest integers to find.\n\n Returns:\n list: The n largest integers in descending order.\n \"\"\"\n # Use the heapq.nlargest function to get the n largest integers from the list\n return heapq.nlargest(n, lst)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(numbers, n):\n \"\"\"\n This function finds the n largest integers from a given list of numbers, \n returned in descending order.\n\n Args:\n numbers (list): A list of integers.\n n (int): The number of largest integers to find.\n\n Returns:\n list: A list of the n largest integers in descending order.\n\n Raises:\n ValueError: If n is larger than the list of numbers.\n \"\"\"\n if n > len(numbers):\n raise ValueError(\"n cannot be larger than the list of numbers\")\n\n # Use the nlargest function from the heapq module to find the n largest integers\n # The heapify function is not needed because heapq.nlargest does that internally\n largest = heapq.nlargest(n, numbers)\n \n # Return the n largest numbers in descending order\n return largest", "matching_cluster_idx": 9}]}, "Mbpp/9": {"dps": 52.61904761904762, "dps_norm": 50.5, "pass@1": 30.0, "profiled": [{"solution": "def find_Rotations(s):\n \"\"\"\n Find the minimum number of rotations required to get the same string.\n \n Args:\n s (str): The input string.\n \n Returns:\n int: The minimum number of rotations required.\n \"\"\"\n if len(s) == 1:\n return 0 # Base case: single character string\n for i in range(1, len(s)):\n if s == s[i:] + s[:i]:\n return i # Found the rotation\n return len(s) # Not found; string is not a rotation of itself", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(s: str) -> int:\n \"\"\"\n This function finds the minimum number of rotations (greater than 0) required to get the same string.\n\n Args:\n s (str): The input string\n\n Returns:\n int: The minimum number of rotations required\n \"\"\"\n n = len(s)\n for i in range(1, n):\n if s in s[i:] + s[:i]:\n return i\n return n", "matching_cluster_idx": 1}, {"solution": "def find_Rotations(s):\n \"\"\"\n Find the minimum number of rotations required to get the same string.\n\n Args:\n s (str): The input string.\n\n Returns:\n int: The minimum number of rotations required to get the same string.\n \"\"\"\n if len(s) <= 1:\n return 0\n\n for i in range(1, len(s)):\n # Check if the string equals to the rotation of itself\n if s == s[-i:] + s[:-i]:\n return i\n\n return len(s)", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(s):\n \"\"\"\n Calculate the minimum number of rotations (greater than 0) required to get the same string.\n\n Args:\n s (str): The input string.\n\n Returns:\n int: The minimum number of rotations required.\n \"\"\"\n if len(set(s)) == 1: # If all characters are the same\n return 1\n\n for i in range(1, len(s)):\n if s == s[i:] + s[:i]:\n return i\n\n return len(s)", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(s: str) -> int:\n \"\"\"\n This function calculates the minimum number of rotations (greater than 0) required \n to get the same string when rotating it.\n \n Parameters:\n s (str): The input string.\n \n Returns:\n int: The minimum number of rotations required to get the same string.\n \"\"\"\n if len(s) == 1: # base case: a single character can't be rotated to become anything else\n return 0\n \n for rotations in range(1, len(s)): # check all possible rotations except the original\n if s == s[rotations:] + s[:rotations]: # check if the rotated string is equal to the original\n return rotations\n \n return len(s) # if no rotation works, the original string is not a rotation of itself", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(s):\n \"\"\"\n This function finds the minimum number of rotations required to get the same string (non-zero rotations).\n \n Args:\n s (str): Input string.\n \n Returns:\n int: Minimum number of rotations (greater than 0) required.\n \n \"\"\"\n # Get the length of the string\n n = len(s)\n \n # All rotations of the string will have a common suffix\n # of s[-1], so compare it with the substring from 1 to n-1\n common_suffix = s[-1] + s[:-1]\n \n # If no rotation has the same suffix, return the length of the string\n if s != common_suffix:\n return n\n \n # If all rotations have the same suffix\n # Check if any rotation is equal to the string\n for i in range(n-1):\n # Rotate the string by i positions\n rotated = s[i:] + s[:i]\n \n # Check if the rotated string is equal to the original string\n if rotated == s:\n # If a match is found, return the rotation number\n return i + 1\n \n # If no match is found, return the length of the string\n return n", "matching_cluster_idx": 9}, {"solution": "def find_Rotations(s):\n \"\"\"\n Calculate the minimum number of rotations (greater than 0) required to get the same string.\n\n Args:\n s (str): The input string to find the rotations for.\n\n Returns:\n int: The minimum number of rotations required.\n \"\"\"\n if len(s) <= 1:\n return 0 # A string with length 1 or less does not need rotations\n\n for i in range(1, len(s)):\n if s == s[i:] + s[:i]: # Check if the string can be rotated to match\n return i\n\n return len(s) # If no rotation matches, return the length of the string", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(s):\n \"\"\"\n Find the minimum number of rotations required to get the same string.\n\n Args:\n s (str): Input string.\n\n Returns:\n int: Minimum number of rotations greater than 0 required to get the same string.\n \"\"\"\n if len(s) < 2:\n return 0\n\n for i in range(1, len(s)):\n # Check if the string can be obtained by rotating the input string\n if s == s[i:] + s[:i]:\n return i\n\n return len(s)", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(s):\n \"\"\"\n Calculate the minimum number of rotations greater than 0 required to get the same string.\n\n Args:\n s (str): The input string.\n\n Returns:\n int: The minimum number of rotations.\n \"\"\"\n if len(s) < 2: # If the string length is less than 2, no rotations are possible\n return 0\n\n for i in range(1, len(s)): # Iterate through each possible rotation\n if s == s[i:] + s[:i]: # Check if the rotated string is equal to the original string\n return i # If a match is found, return the rotation count\n\n return len(s) # If no match is found, return the length of the string", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(s):\n \"\"\"\n Calculate the minimum number of rotations needed to get the same string.\n \n Args:\n s (str): The input string.\n \n Returns:\n int: The minimum number of rotations.\n \"\"\"\n n = len(s)\n for i in range(1, n):\n # Check if the string is equal to a rotation of the first string\n if s == s[n-i:] + s[:n-i]:\n return i\n\n return n", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(s):\n \"\"\"\n Find the minimum number of rotations required to get the same string.\n\n Args:\n s (str): The input string.\n\n Returns:\n int: The minimum number of rotations required.\n \"\"\"\n if len(s) == 1:\n return 0\n \n rotation_number = 1\n for i in range(1, len(s)):\n if s == s[i:] + s[:i]:\n return rotation_number\n rotation_number += 1\n\n return rotation_number", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(s):\n \"\"\"\n This function finds the minimum number of rotations (greater than 0) required to get the same string.\n \n Args:\n s (str): The input string.\n \n Returns:\n int: The minimum number of rotations required.\n \"\"\"\n if len(s) <= 1: # If the length of the string is less than or equal to 1, return 0\n return 0\n \n for i in range(1, len(s)):\n if s == s[-i:] + s[:-i]: # Check if the string is a rotation of the original string\n return i\n \n return len(s) # If no rotation found, return the length of the string", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(s):\n \"\"\"\n This function calculates the minimum number of rotations required to get the same string.\n \n Parameters:\n s (str): The input string.\n \n Returns:\n int: The minimum number of rotations required.\n \"\"\"\n if len(s) == 1: # Base case: A single character cannot be rotated.\n return 0\n \n for i in range(1, len(s)): # Start from 1 since we are looking for rotations greater than 0.\n if s == s[i:] + s[:i]: # Check if s is equal to its rotation.\n return i # Return the rotation amount.\n\n return len(s) # If no rotation results in the same string, return the length of the string.", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(s):\n \"\"\"\n This function calculates the minimum number of rotations (greater than 0) \n required to get the same string.\n\n Args:\n s (str): The input string.\n\n Returns:\n int: The minimum number of rotations required.\n \"\"\"\n if len(s) <= 1:\n # If string length is 1 or less, it's already a fixed state\n return 0\n for i in range(1, len(s)):\n # Check every possible rotation\n if s == s[i:] + s[:i]:\n # If rotation is the same as original string\n return i\n return len(s)", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(s):\n \"\"\"\n This function calculates the minimum number of rotations required to get the same string\n Parameters:\n s (str): The input string\n Returns:\n int: The minimum number of rotations required\n \"\"\"\n if len(set(s)) == 1: # if the string contains all the same characters, return 1\n return 1\n else:\n # Remove any spaces and convert the string to lowercase\n s = s.replace(\" \", \"\").lower()\n # Initialize the count of rotations and the substring to compare\n count = 0\n # Get the first substring\n sub = s[1:] + s[0]\n # Compare the string with its rotations and increment the count until a match is found\n for i in s:\n if sub == s:\n break\n else:\n count += 1\n sub = sub[1:] + sub[0]\n return count + 1 # Return the count of rotations plus 1 because we start from 1", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(s):\n \"\"\"\n This function finds the minimum number of rotations (greater than 0) required to get the same string.\n \n Parameters:\n s (str): The input string.\n \n Returns:\n int: The minimum number of rotations required.\n \"\"\"\n if len(s) == 1:\n return 0\n \n # Compare all rotations of the string with the string itself\n for i in range(1, len(s)):\n if s in s[i:] + s[:i]:\n return i\n return len(s)", "matching_cluster_idx": 1}, {"solution": "def find_Rotations(s):\n \"\"\"\n Find the minimum number of rotations required to get the same string.\n \n Parameters:\n s (str): Input string.\n \n Returns:\n int: Minimum number of rotations required to get the same string.\n \"\"\"\n if len(set(s)) == 1: # If all characters are the same, we need to rotate it once\n return 1\n \n for i in range(len(s) - 1):\n if s == s[i + 1:] + s[:i + 1]: # Check if the string is a rotation of the current substring\n return i + 1\n \n return len(s) # If not found, return the length of the string as the minimum rotations", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(s: str) -> int:\n \"\"\"\n This function calculates the minimum number of rotations (greater than 0) required to get the same string.\n \n Args:\n s (str): Input string\n \n Returns:\n int: The minimum number of rotations required to get the same string.\n \"\"\"\n if len(set(s)) == 1: # If the string consists of all the same character, it's already in its minimum rotation state\n return 1\n for i in range(1, len(s)):\n if s == s[i:] + s[:i]: # If a rotation matches the original string, return the length of the rotation\n return i\n return len(s) # If no rotation matches, return the length of the string", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(s):\n \"\"\"\n Find the minimum number of rotations required to get the same string.\n\n Args:\n s (str): The input string.\n\n Returns:\n int: The minimum number of rotations required.\n\n Examples:\n >>> find_Rotations(\"aaaa\")\n 1\n \"\"\"\n if len(set(s)) == 1: # If all characters are the same, return 1\n return 1\n \n for i in range(1, len(s)): # Check each possible rotation\n if s == s[i:] + s[:i]: # Check if the string is equal to a rotation of itself\n return i\n \n # If no rotations are found, return the length of the string (all rotations of the string are unique)\n return len(s)", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(s):\n \"\"\"\n This function finds the minimum number of rotations (greater than 0) required to get the same string.\n \n Args:\n s (str): The input string.\n \n Returns:\n int: Minimum number of rotations required.\n \"\"\"\n # If the string is empty, return 0\n if len(s) == 0:\n return 0\n \n # Generate the cyclic shift of the string by 1 position\n shifted_string = s[1:] + s[0]\n \n # Check if the original string is equal to the shifted string\n # If not, continue shifting the string and comparing until a match is found\n rotations = 1\n while shifted_string != s:\n shifted_string = shifted_string[1:] + shifted_string[0]\n rotations += 1\n \n return rotations", "matching_cluster_idx": 5}]}, "Mbpp/11": {"dps": 32.060931899641574, "dps_norm": 62.77777777777778, "pass@1": 37.0, "profiled": [{"solution": "def remove_Occ(s, char):\n \"\"\"\n Removes the first and last occurrence of a given character from the string.\n \n Args:\n s (str): The input string.\n char (str): The character to be removed.\n \n Returns:\n str: The modified string with the first and last occurrence of the character removed.\n \"\"\"\n \n # Check if the string is empty or the character does not exist in the string\n if not s or char not in s:\n return s\n \n # Find the index of the first occurrence of the character\n first_occurrence = s.find(char)\n \n # Find the index of the last occurrence of the character\n last_occurrence = s.rfind(char)\n \n # Create a new string by excluding the first and last occurrence\n new_string = s[:first_occurrence] + s[first_occurrence + 1:last_occurrence] + s[last_occurrence + 1:]\n \n return new_string", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(s, char):\n \"\"\"\n This function removes the first and last occurrence of a given character from the string.\n\n Parameters:\n s (str): The input string.\n char (str): The character to be removed.\n\n Returns:\n str: The modified string after removing the given character.\n\n \"\"\"\n # Find the index of the first occurrence of the character\n try:\n first_occurrence_index = s.index(char)\n except ValueError:\n # If the character is not found, return the original string\n return s\n \n # Find the index of the last occurrence of the character\n try:\n last_occurrence_index = s.rindex(char)\n except ValueError:\n # If the character is not found, return the original string\n return s\n \n # Slice the string to exclude the first and last occurrences\n modified_string = s[:first_occurrence_index] + s[first_occurrence_index+1:last_occurrence_index] + s[last_occurrence_index+1:]\n \n return modified_string", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(s, char):\n \"\"\"\n This function removes the first and last occurrence of a given character from the input string.\n \n Parameters:\n s (str): The input string.\n char (str): The character to be removed.\n \n Returns:\n str: The input string with the first and last occurrence of the given character removed.\n \"\"\"\n \n # Check if the input string is not empty and the given character exists in the string\n if s and char in s:\n # Find the index of the first occurrence of the character\n first_occurrence = s.index(char)\n \n # Find the index of the last occurrence of the character\n last_occurrence = len(s) - 1 - s[::-1].index(char)\n \n # Remove the first and last occurrence of the character\n s = s[:first_occurrence] + s[first_occurrence + 1:last_occurrence] + s[last_occurrence + 1:]\n \n # Return the modified string\n return s", "matching_cluster_idx": 5}, {"solution": "def remove_Occ(s, c):\n \"\"\"\n Removes the first and last occurrence of a given character in the string.\n\n Args:\n s (str): The input string.\n c (str): The character to be removed.\n\n Returns:\n str: The string with the first and last occurrence of the character removed.\n \"\"\"\n # Remove the first occurrence of the character\n s = s.replace(c, '', 1)\n \n # Remove the last occurrence of the character\n s = s[::-1].replace(c, '', 1)[::-1]\n \n return s", "matching_cluster_idx": 4}, {"solution": "def remove_Occ(s, c):\n \"\"\"\n Remove the first and last occurrence of a given character in a string.\n\n Args:\n s (str): The input string.\n c (str): The character to remove.\n\n Returns:\n str: The string with the first and last occurrence of the character removed.\n \"\"\"\n # Convert the string to a list so we can use indexing and slicing\n s_list = list(s)\n \n # Remove the first occurrence of the character\n for i in range(len(s_list)):\n if s_list[i] == c:\n del s_list[i]\n break\n \n # Remove the last occurrence of the character\n for i in range(len(s_list)-1, -1, -1):\n if s_list[i] == c:\n del s_list[i]\n break\n \n # Join the list back to a string\n return ''.join(s_list)", "matching_cluster_idx": 1}, {"solution": "def remove_Occ(s, char):\n \"\"\"\n This function removes the first and last occurrence of a given character from the string.\n \n Parameters:\n s (str): The input string.\n char (str): The character to be removed.\n \n Returns:\n str: The string after removing the first and last occurrence of the character.\n \"\"\"\n # Remove the first occurrence of the character\n s = s.replace(char, '', 1)\n \n # Remove the last occurrence of the character\n s = s[::-1].replace(char, '', 1)[::-1]\n \n return s", "matching_cluster_idx": 4}, {"solution": "def remove_Occ(string, char):\n \"\"\"\n This function removes the first and last occurrence of a given character from a string.\n \n Args:\n string (str): The input string.\n char (str): The character to be removed.\n \n Returns:\n str: The string after removing the first and last occurrence of the given character.\n \"\"\"\n # Check if the input string is empty or the character is not in the string\n if not string or char not in string:\n return string\n \n # Find the index of the first occurrence of the character\n first_occurrence = string.find(char)\n \n # Find the index of the last occurrence of the character\n last_occurrence = len(string) - 1 - string[::-1].find(char)\n \n # Slice the string to remove the first and last occurrences of the character\n result = string[:first_occurrence] + string[first_occurrence + 1:last_occurrence] + string[last_occurrence + 1:]\n \n return result", "matching_cluster_idx": 5}, {"solution": "def remove_Occ(s, char):\n \"\"\"\n Removes the first and last occurrence of a given character from the string.\n\n Args:\n s (str): Input string.\n char (str): Character to be removed.\n\n Returns:\n str: The modified string after removing the first and last occurrence of the given character.\n \"\"\"\n # Check if the input string is not empty and the character exists in the string\n if s and char in s:\n # Remove the first occurrence of the character\n s = s[::-1].replace(char, '', 1)[::-1]\n # Remove the last occurrence of the character\n s = s.replace(char, '', 1)\n return s", "matching_cluster_idx": 4}, {"solution": "def remove_Occ(s, c):\n \"\"\"\n Removes the first and last occurrence of a given character from the string.\n \n Args:\n s (str): The input string.\n c (str): The character to be removed.\n \n Returns:\n str: The modified string with the first and last occurrence of the given character removed.\n \"\"\"\n # Remove the first occurrence of the character\n s = s.replace(c, '', 1)\n \n # Remove the last occurrence of the character\n s = s[::-1].replace(c, '', 1)[::-1]\n \n return s", "matching_cluster_idx": 4}, {"solution": "def remove_Occ(s, char):\n \"\"\"\n Removes the first and last occurrence of a given character from a string.\n \n Args:\n s (str): Input string\n char (str): Character to be removed\n \n Returns:\n str: String with the first and last occurrence of char removed\n \"\"\"\n \n # Check if input is a string\n if not isinstance(s, str) or not isinstance(char, str) or len(char) != 1:\n return \"Error: Both inputs should be strings and char should be a single character.\"\n \n # Check if the character exists in the string\n if char not in s:\n return s\n \n # Remove the first occurrence of the character\n s = s.replace(char, '', 1)\n \n # Remove the last occurrence of the character\n s = s[::-1].replace(char, '', 1)[::-1]\n \n return s", "matching_cluster_idx": 4}, {"solution": "def remove_Occ(s, c):\n \"\"\"\n This function removes the first and last occurrence of a character in a string.\n\n Parameters:\n s (str): Input string\n c (str): Character to be removed\n\n Returns:\n str: String with the first and last occurrence of 'c' removed\n \"\"\"\n # Find the index of the first occurrence of 'c'\n first_occurrence = s.find(c)\n \n # Find the index of the last occurrence of 'c'\n last_occurrence = s.rfind(c)\n\n # If the character is not found in the string, return the string as it is\n if first_occurrence == -1:\n return s\n\n # If the character is found in the string, return the string without the first and last occurrence\n else:\n return s[:first_occurrence] + s[first_occurrence + 1:last_occurrence] + s[last_occurrence + 1:]", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(s, c):\n \"\"\"\n This function removes the first and last occurrence of a given character in a string.\n \n Parameters:\n s (str): The input string.\n c (str): The character to be removed.\n \n Returns:\n str: The modified string with the first and last occurrences of the character removed.\n \"\"\"\n \n # Check if the character is present in the string\n if c not in s:\n return s # Return the original string if the character is not present\n\n # Find the index of the first occurrence of the character\n first_occurrence_index = s.find(c)\n \n # Find the index of the last occurrence of the character\n last_occurrence_index = s.rfind(c)\n \n # Return the string with the first and last occurrences of the character removed\n return s[:first_occurrence_index] + s[first_occurrence_index + 1:last_occurrence_index] + s[last_occurrence_index + 1:]", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(s, c):\n \"\"\"\n Removes the first and last occurrence of a given character from the string.\n\n Args:\n s (str): Input string.\n c (str): Character to remove.\n\n Returns:\n str: String with first and last occurrence of the character removed.\n \"\"\"\n if c not in s:\n return s # If the character is not in the string, return the original string.\n\n idx_first = s.find(c) # Find the index of the first occurrence of the character\n idx_last = s.rfind(c) # Find the index of the last occurrence of the character\n\n return s[:idx_first] + s[idx_first+1:idx_last] + s[idx_last+1:] # Slice the string to exclude the first and last occurrence", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(s, ch):\n \"\"\"\n This function removes the first and last occurrence of a given character from the string.\n \n Args:\n s (str): The input string.\n ch (str): The character to be removed.\n \n Returns:\n str: The resulting string after removing the character.\n \"\"\"\n # Remove the first occurrence of the character\n s = s.replace(ch, \"\", 1)\n \n # Remove the last occurrence of the character\n s = s[::-1] # Reverse the string\n s = s.replace(ch, \"\", 1) # Remove the first occurrence in reversed string\n s = s[::-1] # Reverse the string back to original order\n \n return s", "matching_cluster_idx": 3}, {"solution": "def remove_Occ(s, char):\n \"\"\"\n This function removes the first and last occurrence of a given character from a string.\n \n Parameters:\n s (str): The input string.\n char (str): The character to be removed.\n \n Returns:\n str: The resulting string after removing the first and last occurrence of the character.\n \"\"\"\n # Remove the first occurrence of the character\n s = s.replace(char, '', 1)\n \n # Remove the last occurrence of the character\n s = s[::-1].replace(char, '', 1)[::-1]\n \n return s", "matching_cluster_idx": 4}, {"solution": "def remove_Occ(s, ch):\n \"\"\"\n Removes the first and last occurrence of a character in a string.\n\n Args:\n s (str): The input string.\n ch (str): The character to be removed.\n\n Returns:\n str: The string with the first and last occurrence of the character removed.\n\n \"\"\"\n # Find the index of the first occurrence of the character\n first_occ = s.find(ch)\n \n # If the character is not found, return the original string\n if first_occ == -1:\n return s\n \n # Find the index of the last occurrence of the character\n last_occ = len(s) - 1 - s[::-1].find(ch)\n \n # Create a new string without the first and last occurrence of the character\n new_string = s[:first_occ] + s[first_occ + 1:last_occ] + s[last_occ + 1:]\n \n return new_string", "matching_cluster_idx": 5}, {"solution": "def remove_Occ(s, char):\n \"\"\"\n This function removes the first and last occurrence of a given character from a string.\n\n Args:\n s (str): The input string\n char (str): The character to remove\n\n Returns:\n str: The modified string with the first and last occurrence of the given character removed.\n \"\"\"\n # Remove the first occurrence of the character\n s = s.replace(char, '', 1)\n \n # Remove the last occurrence of the character\n s = s[::-1].replace(char, '', 1)[::-1]\n \n return s", "matching_cluster_idx": 4}, {"solution": "def remove_Occ(s, char):\n \"\"\"\n Removes the first and last occurrence of a given character from the string.\n\n Args:\n s (str): The input string.\n char (str): The character to be removed.\n\n Returns:\n str: The string with the first and last occurrence of the character removed.\n \"\"\"\n if char not in s:\n return s # Return the string as it is if the character is not found\n s = s.replace(char, '', 1) # Remove the first occurrence of the character\n s = s[::-1] # Reverse the string\n s = s.replace(char, '', 1)[::-1] # Remove the last occurrence of the character and reverse back\n return s", "matching_cluster_idx": 3}, {"solution": "def remove_Occ(s, ch):\n \"\"\"\n This function removes the first and last occurrence of a given character from the string.\n \n Args:\n s (str): The input string.\n ch (str): The character to be removed.\n \n Returns:\n str: The string with the first and last occurrence of the character removed.\n \"\"\"\n # Check if the input string or character is empty\n if not s or not ch:\n return s\n \n # Remove the first occurrence\n s = s.replace(ch, \"\", 1)\n \n # Remove the last occurrence\n s = s[::-1].replace(ch, \"\", 1)[::-1]\n \n return s", "matching_cluster_idx": 4}, {"solution": "def remove_Occ(string, char):\n \"\"\"\n Removes the first and last occurrence of a given character from the input string.\n \n Args:\n string (str): The input string from which the character will be removed.\n char (str): The character to be removed from the string.\n \n Returns:\n str: The modified string with the first and last occurrence of char removed.\n \"\"\"\n # Find the indices of the first and last occurrence of the character\n first_occurrence = string.find(char)\n last_occurrence = string.rfind(char)\n \n # If the character is not found, return the original string\n if first_occurrence == -1:\n return string\n \n # Create a list to store the characters of the result string\n result = list(string)\n \n # Replace the first occurrence of the character with None\n result[first_occurrence] = None\n \n # Replace the last occurrence of the character with None\n result[last_occurrence] = None\n \n # Remove None values from the result list\n result = [x for x in result if x is not None]\n \n # Join the characters back into a string and return the result\n return ''.join(result)", "matching_cluster_idx": -1}]}, "Mbpp/12": {"dps": 91.42857142857143, "dps_norm": 99.375, "pass@1": 89.0, "profiled": [{"solution": "def sort_matrix(matrix):\n \"\"\"\n Sort a given matrix in ascending order according to the sum of its rows.\n\n Args:\n matrix (list): A 2D list containing integers.\n\n Returns:\n list: A 2D list representing the sorted matrix.\n \"\"\"\n # Calculate the sum of each row and store it as a tuple with the row index\n row_sums = [(i, sum(row)) for i, row in enumerate(matrix)]\n \n # Sort the row sums in ascending order\n sorted_row_sums = sorted(row_sums, key=lambda x: x[1])\n \n # Sort the matrix based on the sorted row sums\n sorted_matrix = [matrix[i[0]] for i in sorted_row_sums]\n \n return sorted_matrix\nmatrix = [[1, 2, 3], [2, 4, 5], [1, 1, 1]]", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"\n Sorts a given matrix in ascending order according to the sum of its rows.\n\n Args:\n matrix (list): A 2D list of integers representing the matrix.\n\n Returns:\n list: A 2D list representing the sorted matrix.\n \"\"\"\n # Get the sums of the rows and store in a list of tuples\n row_sums = [(sum(row), i, row) for i, row in enumerate(matrix)]\n \n # Sort the list of tuples based on the sums\n row_sums.sort(key=lambda x: x[0])\n \n # Sort the rows based on the sorted sums and store in a new list\n sorted_matrix = [row[2] for row in row_sums]\n \n return sorted_matrix\nmatrix = [[1, 2, 3], [2, 4, 5], [1, 1, 1]]", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"\n Sort a given matrix in ascending order according to the sum of its rows.\n \n Args:\n matrix (list): A 2D list of integers.\n \n Returns:\n list: A 2D list with rows sorted in ascending order according to their sums.\n \"\"\"\n # Use a lambda function to calculate the sum of each row and sort the matrix based on it\n return sorted(matrix, key=lambda row: sum(row))", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"\n Sorts a given matrix in ascending order according to the sum of its rows.\n \n Args:\n matrix (list): A 2D list representing the matrix to be sorted.\n \n Returns:\n list: The input matrix sorted in ascending order according to the sum of its rows.\n \"\"\"\n \n # Calculate the sum of each row and store it in a list of tuples with the row sum and the row itself\n row_sums = [(sum(row), row) for row in matrix]\n \n # Sort the list of tuples based on the row sums\n sorted_row_sums = sorted(row_sums, key=lambda x: x[0])\n \n # Extract the sorted rows from the list of tuples\n sorted_matrix = [row[1] for row in sorted_row_sums]\n \n return sorted_matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"\n Sort a given matrix in ascending order according to the sum of its rows.\n\n Args:\n matrix (list): A 2D list of integers.\n\n Returns:\n list: A 2D list representing the sorted matrix.\n\n \"\"\"\n # Use the sorted function with a custom key function to sort the matrix\n return sorted(matrix, key=sum)\nmatrix = [[1, 2, 3], [2, 4, 5], [1, 1, 1]]", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"\n Sorts a given matrix in ascending order according to the sum of its rows.\n\n Args:\n matrix (list): A 2D list of numbers\n\n Returns:\n list: A 2D list sorted in ascending order according to the sum of its rows\n \"\"\"\n # Sort the matrix based on the sum of its rows\n return sorted(matrix, key=sum)\nmatrix = [[1, 2, 3], [2, 4, 5], [1, 1, 1]]", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"\n This function sorts a given matrix in ascending order according to the sum of its rows.\n \n Args:\n matrix (list): A 2D list of integers.\n \n Returns:\n list: A 2D list sorted in ascending order according to the sum of its rows.\n \"\"\"\n # Use sorted function with a custom sorting key\n return sorted(matrix, key=sum)\nmatrix = [[1, 2, 3], [2, 4, 5], [1, 1, 1]]", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"\n Sorts a given matrix in ascending order according to the sum of its rows.\n\n Args:\n matrix (list): A 2D list (matrix) to be sorted.\n\n Returns:\n list: The input matrix sorted by the sum of its rows.\n \"\"\"\n return sorted(matrix, key=sum)", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"\n Sorts a given matrix in ascending order according to the sum of its rows.\n \n Args:\n matrix (list): A 2D list representing the matrix to be sorted.\n \n Returns:\n list: The sorted matrix.\n \"\"\"\n # Calculate the sum of each row\n row_sums = [sum(row) for row in matrix]\n \n # Combine each row with its sum\n combined = list(zip(row_sums, matrix))\n \n # Sort the combined list based on the row sums\n sorted_combined = sorted(combined, key=lambda x: x[0])\n \n # Separate the sorted rows from their sums\n sorted_matrix = [row[1] for row in sorted_combined]\n \n return sorted_matrix\nmatrix = [[1, 2, 3], [2, 4, 5], [1, 1, 1]]", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"\n Sorts a given matrix in ascending order according to the sum of its rows.\n\n Args:\n matrix (list of lists): A 2D list representing the matrix.\n\n Returns:\n list of lists: The sorted matrix.\n \"\"\"\n # Check if the matrix is empty\n if not matrix:\n return []\n\n # Calculate the sum of each row and store it along with the row in a list of tuples\n row_sums = [(sum(row), row) for row in matrix]\n\n # Sort the list of tuples based on the sum of each row\n row_sums.sort()\n\n # Separate the sorted row sums from the rows themselves\n sorted_rows = [row[1] for row in row_sums]\n\n return sorted_rows", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"\n Sorts a given matrix in ascending order according to the sum of its rows.\n\n Args:\n matrix (list): A 2D list of numbers.\n\n Returns:\n list: The sorted matrix.\n \"\"\"\n # Use the sorted function with a custom key to sort the matrix based on the sum of each row\n return sorted(matrix, key=sum)\nmatrix = [[1, 2, 3], [2, 4, 5], [1, 1, 1]]", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"\n Sort a given matrix in ascending order according to the sum of its rows.\n\n Args:\n matrix (list): A 2D list containing integers.\n\n Returns:\n list: The sorted matrix.\n \"\"\"\n # Use the sorted function with a custom sorting key\n return sorted(matrix, key=lambda x: sum(x))\nmatrix = [[1, 2, 3], [2, 4, 5], [1, 1, 1]]", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"\n This function sorts a given matrix in ascending order according to the sum of its rows.\n\n Args:\n matrix (list): A 2D list of integers representing a matrix.\n\n Returns:\n list: A 2D list representing the input matrix sorted by the sum of its rows.\n \"\"\"\n # First, we calculate the sum of each row in the matrix\n row_sums = [sum(row) for row in matrix]\n \n # Then, we sort the matrix according to these sums\n sorted_matrix = [list(t) for _, t in sorted(zip(row_sums, matrix))]\n \n return sorted_matrix", "matching_cluster_idx": 14}, {"solution": "def sort_matrix(matrix):\n \"\"\"\n Sort a given matrix in ascending order according to the sum of its rows.\n\n Args:\n matrix (list of lists): Input matrix.\n\n Returns:\n list of lists: Sorted matrix.\n \"\"\"\n # Calculate the sum of each row and store it as a tuple in a list along with the row\n row_sums = [(sum(row), i, row) for i, row in enumerate(matrix)]\n \n # Sort the list of tuples based on the row sum\n sorted_row_sums = sorted(row_sums, key=lambda x: x[0])\n \n # Extract the sorted rows from the list of tuples\n sorted_matrix = [row[2] for row in sorted_row_sums]\n \n return sorted_matrix\nmatrix = [[1, 2, 3], [2, 4, 5], [1, 1, 1]]", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"\n Sort a given matrix in ascending order according to the sum of its rows.\n\n Args:\n matrix (list of lists): Input matrix\n\n Returns:\n list of lists: Sorted matrix by row sums\n \"\"\"\n # Calculate the sum of each row\n row_sums = [sum(row) for row in matrix]\n \n # Combine row and its sum into a tuple\n combined = list(zip(row_sums, matrix))\n \n # Sort the combined list of tuples based on the row sums\n combined.sort(key=lambda x: x[0])\n \n # Separate the matrix from the sums\n sorted_matrix = [row for _, row in combined]\n \n return sorted_matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"\n Sorts a given matrix in ascending order according to the sum of its rows.\n\n Args:\n matrix (list): A 2D list of integers.\n\n Returns:\n list: The sorted matrix.\n \"\"\"\n # Calculate the sum of each row and store it as a list of tuples along with the row index\n row_sums = [(i, sum(row)) for i, row in enumerate(matrix)]\n \n # Sort the list of tuples based on the row sums\n sorted_row_sums = sorted(row_sums, key=lambda x: x[1])\n \n # Reconstruct the matrix with the rows sorted by their sum\n sorted_matrix = [matrix[i[0]] for i in sorted_row_sums]\n \n return sorted_matrix\nmatrix = [[1, 2, 3], [2, 4, 5], [1, 1, 1]]", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"\n Sorts a given matrix in ascending order according to the sum of its rows.\n \n Args:\n matrix (list): A 2D list of integers.\n \n Returns:\n list: The input matrix sorted in ascending order by row sum.\n \"\"\"\n \n # Calculate the sum of each row and store it along with the row\n row_sums = [[sum(row), row] for row in matrix]\n \n # Sort the rows based on the calculated sums\n sorted_row_sums = sorted(row_sums, key=lambda x: x[0])\n \n # Extract the sorted rows\n sorted_matrix = [row[1] for row in sorted_row_sums]\n \n return sorted_matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"\n Sorts a given matrix in ascending order according to the sum of its rows.\n\n Args:\n matrix (list of lists): A 2D list of integers.\n\n Returns:\n list of lists: The sorted matrix.\n \"\"\"\n # Calculate the sum of each row\n row_sums = [sum(row) for row in matrix]\n \n # Use list comprehension to zip the matrix with its row sums, sort based on the row sums, and then extract the rows\n sorted_matrix = [list(row) for _, row in sorted(zip(row_sums, matrix))]\n \n return sorted_matrix", "matching_cluster_idx": 14}, {"solution": "def sort_matrix(matrix):\n \"\"\"\n Sort a given matrix in ascending order according to the sum of its rows.\n\n Args:\n matrix (list): A 2D list of integers.\n\n Returns:\n list: The input matrix sorted by the sum of its rows.\n \"\"\"\n return sorted(matrix, key=sum)\nmatrix = [[1, 2, 3], [2, 4, 5], [1, 1, 1]]", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"\n Sorts a given matrix in ascending order according to the sum of its rows.\n\n Args:\n matrix (list): A 2D list of integers\n\n Returns:\n list: A sorted 2D list of integers based on the sum of each row\n \"\"\"\n # Use the sorted function with a custom key to sort the matrix\n return sorted(matrix, key=sum)\nmatrix = [[1, 2, 3], [2, 4, 5], [1, 1, 1]]", "matching_cluster_idx": 15}]}, "Mbpp/16": {"dps": 67.6829268292683, "dps_norm": 75.0, "pass@1": 19.0, "profiled": [{"solution": "def text_lowercase_underscore(text):\n \"\"\"\n Returns True if the input string contains sequences of lowercase letters joined with an underscore.\n \n Parameters:\n text (str): The input string to check.\n \n Returns:\n bool: True if the input string meets the condition, False otherwise.\n \"\"\"\n # Split the string into parts separated by underscores\n parts = text.split(\"_\")\n \n # Check if all parts are lowercase and non-empty\n return all(part.islower() and part for part in parts)", "matching_cluster_idx": 5}, {"solution": "def text_lowercase_underscore(text):\n \"\"\"\n Checks if a given string contains sequences of lowercase letters joined with an underscore.\n\n Args:\n text (str): The input string.\n\n Returns:\n bool: True if the string contains sequences of lowercase letters joined with an underscore, False otherwise.\n \"\"\"\n # Split the input string by underscores\n parts = text.split(\"_\")\n\n # Check each part\n for part in parts:\n # If a part is not a lowercase string or is empty, return False\n if not part.islower() or len(part) == 0:\n return False\n\n # If all parts passed, return True\n return True", "matching_cluster_idx": 5}, {"solution": "def text_lowercase_underscore(text):\n \"\"\"\n This function checks if the input string contains sequences of lowercase letters joined with an underscore.\n \n Args:\n text (str): The input string to be checked.\n \n Returns:\n bool: True if the string contains sequences of lowercase letters joined with an underscore, False otherwise.\n \"\"\"\n \n # Split the string into substrings by underscores\n substrings = text.split(\"_\")\n \n # Initialize a flag to True\n has_sequence = True\n \n # Iterate over each substring\n for substring in substrings:\n # If the substring is not all lowercase, set the flag to False and break the loop\n if not substring.islower():\n has_sequence = False\n break\n \n return has_sequence", "matching_cluster_idx": 5}, {"solution": "def text_lowercase_underscore(text):\n \"\"\"\n Checks if the input string contains sequences of lowercase letters joined with an underscore.\n\n Args:\n text (str): The input string to be checked.\n\n Returns:\n bool: True if the string contains sequences of lowercase letters joined with an underscore, False otherwise.\n \"\"\"\n # Split the input string into substrings separated by underscores\n substrings = text.split(\"_\")\n \n # Check if all substrings are lowercase letters and not empty\n return all(sub.islower() and sub != \"\" for sub in substrings)", "matching_cluster_idx": 5}, {"solution": "def text_lowercase_underscore(s):\n \"\"\"\n This function checks if the input string contains sequences of lowercase letters joined with an underscore.\n \n Args:\n s (str): The input string to check.\n \n Returns:\n bool: True if the string contains sequences of lowercase letters joined with an underscore, False otherwise.\n \"\"\"\n \n # Split the string by underscores to check for valid sequences\n parts = s.split(\"_\")\n \n # For each part in the split string, check if it's a sequence of lowercase letters\n for part in parts:\n # If a part is not a sequence of lowercase letters, return False\n if not part.islower():\n return False\n \n # If no part was not a sequence of lowercase letters, return True\n return True", "matching_cluster_idx": 5}, {"solution": "def text_lowercase_underscore(text):\n \"\"\"\n Returns True if the input string contains sequences of lowercase letters joined with an underscore, False otherwise.\n \n Parameters:\n text (str): The input string to check.\n \n Returns:\n bool: True if the string contains sequences of lowercase letters joined with an underscore, False otherwise.\n \"\"\"\n # Split the string by underscores\n parts = text.split(\"_\")\n \n # Check if all parts are lowercase letters\n for part in parts:\n if not part.islower() or len(part) == 0: # Add check for empty strings\n return False\n \n return True", "matching_cluster_idx": 5}, {"solution": "def text_lowercase_underscore(s: str) -> bool:\n \"\"\"\n This function checks if the input string contains sequences of lowercase letters joined with an underscore.\n\n Args:\n s (str): The input string to check.\n\n Returns:\n bool: True if the input string contains sequences of lowercase letters joined with an underscore, False otherwise.\n \"\"\"\n # Split the string by '_' and check each part\n for part in s.split('_'):\n # If any part is not all lowercase letters, return False\n if not part.isalpha() or not part.islower():\n return False\n # If all parts are lowercase letters, return True\n return True", "matching_cluster_idx": 5}, {"solution": "def text_lowercase_underscore(text):\n \"\"\"\n Checks if the input string contains sequences of lowercase letters joined with an underscore.\n\n Args:\n text (str): The input string to be checked.\n\n Returns:\n bool: True if the input string contains sequences of lowercase letters joined with an underscore, False otherwise.\n \"\"\"\n # Find all words in the text\n words = text.split('_')\n \n # Check each word in the list of words\n for word in words:\n # If a word is not all lowercase letters, return False\n if not word.islower() or not word.isalpha():\n return False\n \n # If all words are valid, return True\n return True", "matching_cluster_idx": 5}, {"solution": "def text_lowercase_underscore(text: str) -> bool:\n \"\"\"\n Checks if the input string contains sequences of lowercase letters joined with an underscore.\n\n Args:\n text (str): The input string to check.\n\n Returns:\n bool: True if the string contains sequences of lowercase letters joined with an underscore, False otherwise.\n \"\"\"\n # Split the string by '_' and check if all the parts are alphanumeric (i.e., containing only letters and numbers)\n return all(part.isalnum() and part.islower() for part in text.split(\"_\"))", "matching_cluster_idx": 5}, {"solution": "def text_lowercase_underscore(text):\n \"\"\"\n Returns True if the input string contains sequences of lowercase letters joined with an underscore, False otherwise.\n \n :param text: Input string to check\n :return: Boolean value indicating whether the string is composed of lowercase letters and underscores\n \"\"\"\n # Split the string into parts separated by underscores\n parts = text.split(\"_\")\n \n # Check each part\n for part in parts:\n # If any part is not all lowercase, return False\n if not part.islower():\n return False\n \n # If we reach this point, all parts are lowercase, so return True\n return True", "matching_cluster_idx": 5}, {"solution": "def text_lowercase_underscore(s):\n \"\"\"\n This function checks if the input string contains sequences of lowercase letters \n joined with an underscore.\n\n Args:\n s (str): The input string to check.\n\n Returns:\n bool: True if the string contains sequences of lowercase letters joined with an underscore, False otherwise.\n \"\"\"\n # Split the string by underscore\n split_str = s.split(\"_\")\n \n # Check if all substrings are lowercase letters\n for substring in split_str:\n if not substring.islower() or substring == '':\n return False\n \n return True", "matching_cluster_idx": 5}, {"solution": "def text_lowercase_underscore(text):\n \"\"\"\n Check if the input string contains sequences of lowercase letters joined with an underscore.\n \n Args:\n text (str): The input string to be checked.\n \n Returns:\n bool: True if the input string contains sequences of lowercase letters joined with an underscore, False otherwise.\n \"\"\"\n words = text.split('_')\n for word in words:\n if not word.islower():\n return False\n return True", "matching_cluster_idx": 5}, {"solution": "def text_lowercase_underscore(text):\n \"\"\"\n Returns True if the input string contains sequences of lowercase letters joined with an underscore.\n\n Args:\n text (str): The input string to check.\n\n Returns:\n bool: True if the string contains sequences of lowercase letters joined with an underscore, False otherwise.\n \"\"\"\n # Split the input string into substrings separated by underscores\n substrings = text.split('_')\n \n # Check if all substrings are lowercase and not empty\n return all(substring.islower() and substring for substring in substrings)", "matching_cluster_idx": 5}, {"solution": "def text_lowercase_underscore(text: str) -> bool:\n \"\"\"\n This function checks if the input string contains sequences of lowercase letters joined with an underscore.\n \n Args:\n text (str): The input string to be checked.\n \n Returns:\n bool: True if the input string contains sequences of lowercase letters joined with an underscore, False otherwise.\n \"\"\"\n \n # If the string is empty, return False as there are no sequences to check\n if not text:\n return False\n \n # Split the string by underscores\n parts = text.split(\"_\")\n \n # Check each part of the string\n for part in parts:\n # If a part contains non-alphabetic characters or is not lowercase, return False\n if not part.islower() or not part.isalpha():\n return False\n \n # If we haven't returned False by now, the string contains sequences of lowercase letters joined with an underscore\n return True", "matching_cluster_idx": 5}, {"solution": "def text_lowercase_underscore(text):\n \"\"\"\n This function checks if the input string contains sequences of lowercase letters joined with an underscore.\n\n Args:\n text (str): The input string to check.\n\n Returns:\n bool: True if the input string contains sequences of lowercase letters joined with an underscore, False otherwise.\n \"\"\"\n # Split the input string into parts by underscore\n parts = text.split(\"_\")\n \n # Check each part if it's a sequence of lowercase letters\n for part in parts:\n if not part.islower():\n return False\n \n # If we passed all checks, return True\n return True", "matching_cluster_idx": 5}, {"solution": "def text_lowercase_underscore(text):\n \"\"\"\n This function checks if the input string contains sequences of lowercase letters joined with an underscore.\n\n Args:\n text (str): Input string to be checked.\n\n Returns:\n bool: True if the string contains sequences of lowercase letters joined with an underscore, False otherwise.\n \"\"\"\n # Split the input string into parts based on the underscore character\n parts = text.split(\"_\")\n \n # Check if all parts are strings and contain only lowercase letters\n return all(part.islower() for part in parts)", "matching_cluster_idx": 5}, {"solution": "def text_lowercase_underscore(s):\n \"\"\"\n Returns True if the input string contains sequences of lowercase letters joined with an underscore, False otherwise.\n \"\"\"\n # split the string into substrings separated by underscores\n substrings = s.split('_')\n # check if all substrings are lowercase letters and non-empty\n return all(sub.islower() and sub for sub in substrings)", "matching_cluster_idx": 5}, {"solution": "def text_lowercase_underscore(text: str) -> bool:\n \"\"\"\n This function checks if the input string contains sequences of lowercase letters joined with an underscore.\n \n Args:\n text (str): The input string to check.\n \n Returns:\n bool: True if the input string contains sequences of lowercase letters joined with an underscore, False otherwise.\n \"\"\"\n \n # Split the input string by underscores to get individual parts\n parts = text.split(\"_\")\n \n # Check each part in the list\n for part in parts:\n # If a part contains any non-lowercase characters or is empty, return False\n if not part.islower() or len(part) == 0:\n return False\n \n # If all parts are valid, return True\n return True", "matching_cluster_idx": 5}, {"solution": "def text_lowercase_underscore(s):\n \"\"\"\n Returns true if the input string contains sequences of lowercase letters joined with an underscore.\n Args:\n s (str): Input string.\n Returns:\n bool: True if the input string matches the pattern, False otherwise.\n \"\"\"\n # Split the string into parts separated by underscores\n parts = s.split(\"_\")\n \n # Check if all parts are lowercase letters and non-empty\n return all(part.islower() and part for part in parts)", "matching_cluster_idx": 5}]}, "Mbpp/19": {"dps": 73.48484848484848, "dps_norm": 85.0, "pass@1": 95.0, "profiled": [{"solution": "def test_duplicate(lst):\n \"\"\"\n Checks if a given list of integers contains any duplicate element.\n\n Args:\n lst (list): The list of integers to check for duplicates.\n\n Returns:\n bool: True if the list contains any duplicate element, False otherwise.\n \"\"\"\n return len(lst) != len(set(lst))", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(arr):\n \"\"\"\n Check if a given array of integers contains any duplicate element.\n \n Args:\n arr (list): A list of integers\n \n Returns:\n bool: True if the array contains a duplicate element, False otherwise\n \"\"\"\n seen = set()\n for num in arr:\n if num in seen:\n return True\n seen.add(num)\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(nums):\n \"\"\"\n Returns whether the given array of integers contains any duplicate element.\n \n Args:\n nums (list): A list of integers.\n \n Returns:\n bool: Whether the array contains any duplicate element.\n \"\"\"\n return len(nums) != len(set(nums))", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(lst):\n \"\"\"Return True if the list contains duplicate elements, False otherwise\"\"\"\n return len(lst) != len(set(lst))", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(arr):\n \"\"\"\n Function to find whether a given array of integers contains any duplicate element.\n \n Args:\n arr (list): A list of integers.\n \n Returns:\n bool: True if the array contains any duplicate element, False otherwise.\n \"\"\"\n return len(arr) != len(set(arr))", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(lst):\n \"\"\"\n This function checks if a given list contains any duplicate elements.\n \n Args:\n lst (list): The list of integers to check for duplicates.\n \n Returns:\n bool: True if the list contains duplicates, False otherwise.\n \"\"\"\n return len(lst) != len(set(lst))", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(lst):\n \"\"\"\n This function checks if a given array of integers contains any duplicate element.\n\n Args:\n lst (list): A list of integers.\n\n Returns:\n bool: True if there is a duplicate element in the list, False otherwise.\n\n Example:\n >>> test_duplicate([1, 2, 3, 4, 5])\n False\n \"\"\"\n return len(lst) != len(set(lst))", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(arr):\n \"\"\"\n Checks whether a given array contains any duplicate element.\n \n Args:\n arr (list): The input list of integers.\n \n Returns:\n bool: True if the array contains a duplicate, False otherwise.\n \"\"\"\n # Convert the list to a set to remove duplicates\n unique_elements = set(arr)\n \n # If the lengths of the original array and the set are different, then there were duplicates\n return len(arr) != len(unique_elements)", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(arr):\n \"\"\"\n This function checks if a given array contains any duplicate element.\n\n Args:\n arr (list): A list of integers.\n\n Returns:\n bool: True if the list contains a duplicate, False otherwise.\n \"\"\"\n return len(arr) != len(set(arr))", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(lst):\n \"\"\"\n Returns True if the list contains any duplicate elements, False otherwise.\n \n Args:\n lst (list): A list of integers.\n \n Returns:\n bool: Whether the list contains duplicates.\n \"\"\"\n return len(lst) != len(set(lst))", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(lst):\n \"\"\"\n Checks if the input list contains any duplicate element.\n\n Args:\n lst (list): A list of integers.\n\n Returns:\n bool: True if the list contains duplicates, False otherwise.\n \"\"\"\n return len(lst) != len(set(lst))", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(lst):\n \"\"\"\n This function checks if a given list contains any duplicate element.\n\n Args:\n lst (list): A list of integers.\n\n Returns:\n bool: True if the list contains duplicate elements, False otherwise.\n \"\"\"\n seen = set()\n for num in lst:\n if num in seen:\n return True\n seen.add(num)\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(nums):\n \"\"\"\n This function checks if a given list of integers contains any duplicate element.\n \n Parameters:\n nums (list): The list of integers to be checked.\n \n Returns:\n bool: True if the list contains a duplicate element, False otherwise.\n \"\"\"\n return len(nums) != len(set(nums))", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(arr):\n \"\"\"\n This function checks if a given array contains any duplicate element.\n\n Args:\n arr (list): The input list of integers.\n\n Returns:\n bool: True if the list contains a duplicate, False otherwise.\n \"\"\"\n return len(arr) != len(set(arr))", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(array):\n \"\"\"\n This function checks if a given array of integers contains any duplicate element.\n \n Args:\n array (list): A list of integers.\n \n Returns:\n bool: True if the array contains any duplicate element, False otherwise.\n \"\"\"\n seen = set() # Initialize an empty set to store seen numbers\n for num in array: # Iterate over the input array\n if num in seen: # Check if the current number is already in the set\n return True # If it is, return True\n seen.add(num) # Otherwise, add the number to the set\n return False # If we have iterated over the entire array without finding a duplicate, return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(arr):\n \"\"\"\n Checks if the given array contains any duplicate elements.\n\n Args:\n arr (list): A list of integers.\n\n Returns:\n bool: True if the array contains a duplicate, False otherwise.\n \"\"\"\n return len(arr) != len(set(arr))", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(arr):\n \"\"\"\n Check if a given array contains any duplicate element.\n\n Args:\n arr (list): A list of integers.\n\n Returns:\n bool: True if the array contains any duplicate element, False otherwise.\n \"\"\"\n return len(arr) != len(set(arr))", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(lst):\n \"\"\"\n This function checks if a given list of integers contains any duplicate element.\n \n Args:\n lst (list): A list of integers.\n \n Returns:\n bool: True if the list contains a duplicate element, False otherwise.\n \"\"\"\n seen = set()\n for num in lst:\n if num in seen:\n return True\n seen.add(num)\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(nums):\n \"\"\"\n This function checks if a given list of integers contains any duplicate element.\n \n Args:\n nums (list): A list of integers.\n \n Returns:\n bool: True if the list contains a duplicate element, False otherwise.\n \"\"\"\n seen = set()\n for num in nums:\n if num in seen:\n return True\n seen.add(num)\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(arr):\n \"\"\"\n This function checks if a given array of integers contains any duplicate element.\n \n Args:\n arr (list): A list of integers.\n \n Returns:\n bool: True if the array contains a duplicate element, False otherwise.\n \"\"\"\n return len(arr) != len(set(arr))", "matching_cluster_idx": 11}]}, "Mbpp/62": {"dps": 94.38461538461539, "dps_norm": 97.0, "pass@1": 99.0, "profiled": [{"solution": "def smallest_num(numbers):\n \"\"\"\n This function takes a list of numbers as input and returns the smallest number.\n\n Args:\n numbers (list): A list of integers.\n\n Returns:\n int: The smallest number in the list.\n\n Raises:\n ValueError: If the input list is empty.\n\n \"\"\"\n if len(numbers) == 0:\n raise ValueError(\"List is empty\")\n else:\n return min(numbers)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(lst):\n \"\"\"\n Returns the smallest number in a given list.\n\n Args:\n lst (list): A list of numbers.\n\n Returns:\n int: The smallest number in the list.\n \"\"\"\n if not lst:\n raise ValueError(\"List is empty\")\n return min(lst)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(lst):\n \"\"\"\n This function takes a list of numbers as input and returns the smallest number.\n \n Args:\n lst (list): A list of integers.\n \n Returns:\n int: The smallest number in the list.\n \n Raises:\n ValueError: If the list is empty.\n \"\"\"\n if not lst: # Check if the list is empty\n raise ValueError(\"List cannot be empty\")\n \n return min(lst) # Return the smallest number in the list", "matching_cluster_idx": 4}, {"solution": "def smallest_num(numbers):\n \"\"\"\n This function returns the smallest number in a given list of integers.\n \n Parameters:\n numbers (list): A list of integers.\n \n Returns:\n int: The smallest number in the list.\n \"\"\"\n if not numbers:\n return None # Return None if the list is empty\n \n return min(numbers)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(numbers):\n \"\"\"\n This function finds the smallest number in a list.\n\n Args:\n numbers (list): A list of numbers.\n\n Returns:\n int: The smallest number in the list.\n\n Raises:\n ValueError: If the input list is empty.\n\n Examples:\n >>> smallest_num([10, 20, 1, 45, 99])\n 1\n >>> smallest_num([])\n ValueError\n \"\"\"\n if not numbers:\n raise ValueError(\"List cannot be empty\")\n\n return min(numbers)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(numbers):\n \"\"\"\n Returns the smallest number from a list of numbers.\n \n Args:\n numbers (list): A list of numbers.\n \n Returns:\n int: The smallest number in the list.\n \n Raises:\n ValueError: If the input list is empty.\n \"\"\"\n if not numbers:\n raise ValueError(\"Input list is empty\")\n return min(numbers)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(lst):\n \"\"\"\n Find the smallest number in a given list.\n \n Args:\n lst (list): A list of numbers.\n \n Returns:\n int: The smallest number in the list.\n \n Raises:\n ValueError: If the list is empty.\n \"\"\"\n if not lst:\n raise ValueError(\"List cannot be empty\")\n \n return min(lst)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(lst):\n \"\"\"\n This function takes a list of integers as input and returns the smallest number.\n\n Args:\n lst (list): A list of integers.\n\n Returns:\n int: The smallest number in the list.\n \"\"\"\n return min(lst)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(lst):\n \"\"\"\n This function finds the smallest number in a given list.\n\n Args:\n lst (list): A list of numbers.\n\n Returns:\n int: The smallest number in the list.\n\n Raises:\n ValueError: If the list is empty.\n\n \"\"\"\n if len(lst) == 0:\n raise ValueError(\"List cannot be empty\")\n return min(lst)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(lst):\n \"\"\"\n Returns the smallest number in a given list.\n\n Args:\n lst (list): A list of integers.\n\n Returns:\n int: The smallest number in the list.\n\n Example:\n >>> smallest_num([10, 20, 1, 45, 99])\n 1\n \"\"\"\n if not lst: # Check if the list is empty\n raise ValueError(\"List is empty\")\n return min(lst) # Return the smallest number", "matching_cluster_idx": 4}, {"solution": "def smallest_num(numbers):\n \"\"\"\n This function takes a list of numbers and returns the smallest number.\n\n Args:\n numbers (list): A list of integers.\n\n Returns:\n int: The smallest number in the list.\n \"\"\"\n return min(numbers)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(lst):\n \"\"\"\n This function finds the smallest number in a list.\n\n Parameters:\n lst (list): A list of numbers\n\n Returns:\n int: The smallest number in the list\n\n \"\"\"\n # Check if the list is not empty\n if len(lst) == 0:\n return None # Return None for empty list\n\n # Initialize smallest_num with the first element of the list\n smallest_num = lst[0]\n \n # Iterate over the list starting from the second element\n for num in lst[1:]:\n # If the current number is smaller than smallest_num, update smallest_num\n if num < smallest_num:\n smallest_num = num\n\n return smallest_num", "matching_cluster_idx": 2}, {"solution": "def smallest_num(num_list):\n \"\"\"\n This function returns the smallest number in a given list.\n\n Args:\n num_list (list): A list of numbers.\n\n Returns:\n The smallest number in the list.\n \"\"\"\n # Check if the list is empty\n if not num_list:\n raise ValueError(\"List is empty\")\n\n # Find the smallest number in the list\n smallest = num_list[0]\n for num in num_list:\n if num < smallest:\n smallest = num\n\n return smallest", "matching_cluster_idx": 3}, {"solution": "def smallest_num(lst):\n \"\"\"\n This function finds the smallest number in a list.\n\n Args:\n lst (list): A list of numbers.\n\n Returns:\n int: The smallest number in the list.\n\n Raises:\n ValueError: If the list is empty.\n \"\"\"\n if not lst:\n raise ValueError(\"List cannot be empty\")\n return min(lst)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(numbers):\n \"\"\"\n This function finds the smallest number in a list of numbers.\n\n Args:\n numbers (list): A list of integers.\n\n Returns:\n int: The smallest number in the list.\n\n Raises:\n ValueError: If the input list is empty.\n \"\"\"\n if not numbers:\n raise ValueError(\"Input list cannot be empty\")\n return min(numbers)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(lst):\n \"\"\"\n Finds the smallest number in a given list.\n\n Args:\n lst (list): A list of numbers.\n\n Returns:\n int: The smallest number in the list.\n\n Raises:\n ValueError: If the input list is empty.\n \"\"\"\n if not lst:\n raise ValueError(\"List is empty\")\n return min(lst)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(lst):\n \"\"\"\n This function takes a list of integers as input and returns the smallest number in the list.\n\n Args:\n lst (list): A list of integers.\n\n Returns:\n int: The smallest number in the list.\n\n Raises:\n ValueError: If the input list is empty.\n\n Example:\n >>> smallest_num([10, 20, 1, 45, 99])\n 1\n \"\"\"\n if not lst:\n raise ValueError(\"Input list is empty\")\n return min(lst)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(lst):\n \"\"\"\n Returns the smallest number in a list of integers.\n\n Args:\n lst (list): A list of integers.\n\n Returns:\n int: The smallest number in the list.\n\n Raises:\n ValueError: If the list is empty.\n \"\"\"\n if not lst:\n raise ValueError(\"List cannot be empty\")\n return min(lst)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(lst):\n \"\"\"\n Returns the smallest number in a list.\n\n Args:\n lst (list): A list of integers.\n\n Returns:\n int: The smallest number in the list.\n \"\"\"\n return min(lst)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(numbers):\n \"\"\"\n This function finds the smallest number in a given list.\n\n Args:\n numbers (list): A list of integers.\n\n Returns:\n int: The smallest number in the list.\n\n Raises:\n ValueError: If the list is empty.\n \"\"\"\n if not numbers:\n raise ValueError(\"The list is empty\")\n return min(numbers)", "matching_cluster_idx": 4}]}, "Mbpp/75": {"dps": 92.85714285714286, "dps_norm": 66.66666666666667, "pass@1": 95.0, "profiled": [{"solution": "def find_tuples(tuples_list, k):\n \"\"\"\n This function filters a list of tuples to find the tuples which have all elements divisible by k.\n\n Args:\n tuples_list (list): A list of tuples, each containing numbers.\n k (int): A number to check divisibility.\n\n Returns:\n list: A list of tuples from the input list where all elements are divisible by k.\n \"\"\"\n # Use list comprehension to filter the tuples based on the given condition\n return [t for t in tuples_list if all(i % k == 0 for i in t)]", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n \"\"\"\n Find all tuples from the given list where all elements are divisible by k.\n \n Parameters:\n tuples_list (list): List of tuples where each tuple contains integers.\n k (int): The divisor to check for divisibility.\n \n Returns:\n list: List of tuples where all elements are divisible by k.\n \"\"\"\n return [t for t in tuples_list if all(i % k == 0 for i in t)]\ntuples_list = [(6, 24, 12), (7, 9, 6), (12, 18, 21)]\nk = 6", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples, k):\n \"\"\"\n This function finds and returns all the tuples in the given list that have all elements divisible by k.\n \n Args:\n tuples (list): A list of tuples, where each tuple contains numbers.\n k (int): The divisor value.\n \n Returns:\n list: A list of tuples where all elements are divisible by k.\n \"\"\"\n return [t for t in tuples if all(element % k == 0 for element in t)]\nk = 6", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n \"\"\"\n Find all tuples in the given list where all elements are divisible by k.\n\n Args:\n tuples_list (list): A list of tuples.\n k (int): The number to check for divisibility.\n\n Returns:\n list: A list of tuples where all elements are divisible by k.\n \"\"\"\n return [t for t in tuples_list if all(i % k == 0 for i in t)]", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n \"\"\"\n This function finds tuples in a list where all elements are divisible by k.\n\n Args:\n tuples_list (list): A list of tuples containing integers.\n k (int): The divisor.\n\n Returns:\n list: A list of tuples where all elements are divisible by k.\n \"\"\"\n return [t for t in tuples_list if all(i % k == 0 for i in t)]", "matching_cluster_idx": 5}, {"solution": "def find_tuples(lst, k):\n \"\"\"\n This function finds all the tuples in a given list where each element of the tuple is divisible by k.\n\n Parameters:\n lst (list): The list of tuples to search through.\n k (int): The number that each element in the tuple must be divisible by.\n\n Returns:\n list: A list of tuples where each element of the tuple is divisible by k.\n \"\"\"\n return [t for t in lst if all(i % k == 0 for i in t)]", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n \"\"\"\n This function takes a list of tuples and an integer k as input.\n It returns a list of tuples where all elements in each tuple are divisible by k.\n \n Parameters:\n tuples_list (list): A list of tuples, each containing integers.\n k (int): The divisor to check for divisibility.\n \n Returns:\n list: A list of tuples where all elements in each tuple are divisible by k.\n \"\"\"\n # Use list comprehension to filter tuples where all elements are divisible by k\n result = [t for t in tuples_list if all(i % k == 0 for i in t)]\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n \"\"\"\n This function finds all tuples in a given list where all elements are divisible by k.\n\n Args:\n tuples_list (list): A list of tuples containing integers.\n k (int): The divisor.\n\n Returns:\n list: A list of tuples where all elements are divisible by k.\n \"\"\"\n return [t for t in tuples_list if all(i % k == 0 for i in t)]\ntuples_list = [(6, 24, 12), (7, 9, 6), (12, 18, 21)]\nk = 6", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n \"\"\"\n Finds and returns all tuples from the given list of tuples that have all elements divisible by k.\n \n Args:\n tuples_list (list): A list of tuples, where each tuple contains integers.\n k (int): The divisor.\n \n Returns:\n list: A list of tuples from the input list where all elements are divisible by k.\n \"\"\"\n result = []\n for tup in tuples_list:\n if all(element % k == 0 for element in tup):\n result.append(tup)\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n \"\"\"\n This function finds all tuples from the given list where all elements are divisible by k.\n\n Args:\n tuples_list (list): A list of tuples containing integers.\n k (int): The divisor to check for.\n\n Returns:\n list: A list of tuples where all elements are divisible by k.\n \"\"\"\n return [t for t in tuples_list if all(i % k == 0 for i in t)]", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples, k):\n \"\"\"\n Find tuples with all elements divisible by k.\n\n Args:\n - tuples (list): A list of tuples where each tuple contains integers.\n - k (int): The divisor.\n\n Returns:\n - list: A list of tuples where all elements are divisible by k.\n \"\"\"\n # Use list comprehension to filter tuples that have all elements divisible by k\n return [t for t in tuples if all(num % k == 0 for num in t)]", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n \"\"\"\n Find all tuples in the given list of tuples where each element is divisible by k.\n\n Args:\n tuples_list (list): A list of tuples.\n k (int): The divisor.\n\n Returns:\n list: A list of tuples where each element is divisible by k.\n \"\"\"\n return [t for t in tuples_list if all(i % k == 0 for i in t)]", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples, k):\n \"\"\"\n Find tuples which have all elements divisible by k from the given list of tuples.\n\n Args:\n tuples (list): A list of tuples.\n k (int): A divisor.\n\n Returns:\n list: A list of tuples where all elements are divisible by k.\n \"\"\"\n # Filter the list of tuples to only include tuples where all elements are divisible by k\n result = [t for t in tuples if all(x % k == 0 for x in t)]\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n \"\"\"\n This function finds tuples where all elements are divisible by k.\n\n Args:\n tuples_list (list): A list of tuples.\n k (int): The divisor.\n\n Returns:\n list: A list of tuples where all elements are divisible by k.\n \"\"\"\n return [t for t in tuples_list if all(i % k == 0 for i in t)]", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n \"\"\"\n Returns a list of tuples which have all elements divisible by k.\n\n Args:\n tuples_list (list): A list of tuples, each tuple contains integers.\n k (int): The number that all elements in the tuples should be divisible by.\n\n Returns:\n list: A list of tuples which have all elements divisible by k.\n \"\"\"\n return [t for t in tuples_list if all(i % k == 0 for i in t)]", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n \"\"\"\n This function finds all tuples in a given list of tuples where all elements are divisible by k.\n\n Args:\n tuples_list (list): A list of tuples where each tuple contains integers.\n k (int): The divisor to check for divisibility.\n\n Returns:\n list: A list of tuples where all elements in each tuple are divisible by k.\n\n Example:\n >>> find_tuples([(6, 24, 12), (7, 9, 6), (12, 18, 21)], 6)\n [(6, 24, 12)]\n \"\"\"\n result = []\n for tup in tuples_list:\n if all(element % k == 0 for element in tup):\n result.append(tup)\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n \"\"\"\n Find all tuples in the given list that have all elements divisible by k.\n\n Args:\n tuples_list (list): A list of tuples.\n k (int): The divisor.\n\n Returns:\n list: A list of tuples where all elements are divisible by k.\n \"\"\"\n return [t for t in tuples_list if all(num % k == 0 for num in t)]", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n \"\"\"\n This function finds tuples in the given list that contain all elements divisible by k.\n\n Args:\n tuples_list (list): A list of tuples.\n k (int): A number that elements in tuples should be divisible by.\n\n Returns:\n list: A list of tuples that contain all elements divisible by k.\n \"\"\"\n return [t for t in tuples_list if all(element % k == 0 for element in t)]", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n \"\"\"\n Find tuples which have all elements divisible by k from the given list of tuples.\n\n Args:\n tuples_list (list): A list of tuples.\n k (int): The number to check divisibility for.\n\n Returns:\n list: A list of tuples where all elements are divisible by k.\n \"\"\"\n return [t for t in tuples_list if all(i % k == 0 for i in t)]\ntuples_list = [(6, 24, 12), (7, 9, 6), (12, 18, 21)]\nk = 6", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples, k):\n \"\"\"\n This function finds all tuples in the given list where every element is divisible by k.\n\n Args:\n - tuples (list): A list of tuples, each containing integers.\n - k (int): The number to check for divisibility.\n\n Returns:\n - list: A list of tuples where all elements in each tuple are divisible by k.\n\n \"\"\"\n # Use list comprehension to filter tuples where all elements are divisible by k\n result = [t for t in tuples if all(x % k == 0 for x in t)]\n return result\ntuples = [(6, 24, 12), (7, 9, 6), (12, 18, 21)]\nk = 6", "matching_cluster_idx": 5}]}, "Mbpp/88": {"dps": 83.99509803921568, "dps_norm": 79.28571428571428, "pass@1": 89.0, "profiled": [{"solution": "def freq_count(lst):\n \"\"\"\n Returns the frequency of each element in a list as a dictionary.\n \n Args:\n lst (list): A list of elements\n \n Returns:\n dict: A dictionary where keys are the elements from the list and values are their frequencies\n \"\"\"\n freq_dict = {}\n for item in lst:\n if item in freq_dict:\n freq_dict[item] += 1\n else:\n freq_dict[item] = 1\n return freq_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n \"\"\"\n This function returns a dictionary with the frequency of each element in the given list.\n\n Args:\n lst (list): A list of elements.\n\n Returns:\n dict: A dictionary with elements as keys and their frequencies as values.\n \"\"\"\n # Initialize an empty dictionary to store frequency of elements\n frequency_dict = {}\n \n # Iterate through each element in the list\n for element in lst:\n # If the element is already in the dictionary, increment its frequency by 1\n if element in frequency_dict:\n frequency_dict[element] += 1\n # If the element is not in the dictionary, add it with a frequency of 1\n else:\n frequency_dict[element] = 1\n \n # Return the dictionary with element frequencies\n return frequency_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n \"\"\"\n Returns the frequency of all elements in a given list as a dictionary.\n \n Args:\n lst (list): A list of elements.\n \n Returns:\n dict: A dictionary where keys are the elements from the list and values are their frequencies.\n \"\"\"\n # Initialize an empty dictionary to store the frequency of each element\n freq = {}\n \n # Iterate over each element in the list\n for elem in lst:\n # If the element is already in the dictionary, increment its count by 1\n if elem in freq:\n freq[elem] += 1\n # If the element is not in the dictionary, add it with a count of 1\n else:\n freq[elem] = 1\n \n return freq", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n \"\"\"\n This function counts the frequency of each element in a given list.\n \n Args:\n lst (list): A list of elements for which to count frequencies.\n \n Returns:\n dict: A dictionary with elements from the list as keys and their frequencies as values.\n \"\"\"\n # Initialize an empty dictionary to store the frequency of elements\n freq = {}\n \n # Iterate over each element in the list\n for element in lst:\n # If the element is already in the dictionary, increment its count\n if element in freq:\n freq[element] += 1\n # Otherwise, add the element to the dictionary with a count of 1\n else:\n freq[element] = 1\n \n return freq", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n \"\"\"\n Returns a dictionary with the frequency of each element in the list.\n \n Parameters:\n lst (list): A list of elements.\n \n Returns:\n dict: A dictionary where keys are the elements from the list and values are their frequencies.\n \"\"\"\n return {i: lst.count(i) for i in set(lst)}", "matching_cluster_idx": 2}, {"solution": "def freq_count(lst):\n \"\"\"\n Returns a dictionary with frequencies of each element in the list.\n\n Args:\n lst (list): A list of elements.\n\n Returns:\n dict: A dictionary where keys are elements from the list and values are their frequencies.\n \"\"\"\n return {i: lst.count(i) for i in set(lst)}", "matching_cluster_idx": 2}, {"solution": "def freq_count(lst):\n \"\"\"\n Function to get the frequency of all the elements in a list.\n\n Args:\n lst (list): The list for which frequency of elements needs to be found.\n\n Returns:\n dict: A dictionary where keys are the elements from the list and values are their frequencies.\n \"\"\"\n # Use dictionary comprehension to count the frequency of each element in the list\n return {i: lst.count(i) for i in set(lst)}", "matching_cluster_idx": 2}, {"solution": "def freq_count(lst):\n \"\"\"\n This function takes a list of elements as input and returns a dictionary where the keys are the unique elements in the list and the values are their frequencies.\n \n Args:\n lst (list): A list of elements.\n \n Returns:\n dict: A dictionary where keys are unique elements in the list and values are their frequencies.\n \"\"\"\n freq_dict = {}\n \n # Iterate over each element in the list\n for item in lst:\n # If the item is already in the dictionary, increment its count by 1\n if item in freq_dict:\n freq_dict[item] += 1\n # If the item is not in the dictionary, add it with a count of 1\n else:\n freq_dict[item] = 1\n \n return freq_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n \"\"\"\n This function returns a dictionary with the frequency of each element in the given list.\n\n Args:\n lst (list): A list of elements.\n\n Returns:\n dict: A dictionary with elements as keys and their frequencies as values.\n \"\"\"\n # Initialize an empty dictionary to store the frequency of each element\n freq = {}\n\n # Iterate over each element in the list\n for element in lst:\n # If the element is already in the dictionary, increment its count by 1\n if element in freq:\n freq[element] += 1\n # If the element is not in the dictionary, add it with a count of 1\n else:\n freq[element] = 1\n\n # Return the dictionary with the frequency of each element\n return freq", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n \"\"\"\n Get the frequency of all the elements in a list.\n \n Args:\n lst (list): A list of integers.\n \n Returns:\n dict: A dictionary where keys are the elements in the list and values are their frequencies.\n \"\"\"\n freq = {}\n for num in lst:\n if num in freq:\n freq[num] += 1\n else:\n freq[num] = 1\n return freq", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n \"\"\"\n This function calculates the frequency of all elements in a list.\n \n Args:\n lst (list): A list of elements.\n \n Returns:\n dict: A dictionary where keys are the unique elements from the list and the values are their frequencies.\n \"\"\"\n # Create an empty dictionary to store the frequency of each element\n freq_dict = {}\n \n # Iterate over each element in the list\n for element in lst:\n # If the element is already in the dictionary, increment its count by 1\n if element in freq_dict:\n freq_dict[element] += 1\n # If the element is not in the dictionary, add it with a count of 1\n else:\n freq_dict[element] = 1\n \n return freq_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n \"\"\"\n Get the frequency of all elements in a list.\n\n Args:\n lst (list): Input list.\n\n Returns:\n dict: Frequency of each element as a dictionary.\n \"\"\"\n freq_dict = {}\n for item in lst:\n if item in freq_dict:\n freq_dict[item] += 1\n else:\n freq_dict[item] = 1\n return freq_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n \"\"\"\n Get the frequency of all the elements in a list.\n\n Args:\n lst (list): A list of numbers.\n\n Returns:\n dict: A dictionary where the keys are the elements from the list and the values are their frequencies.\n \"\"\"\n freq = {}\n for num in lst:\n if num in freq:\n freq[num] += 1\n else:\n freq[num] = 1\n return freq", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n \"\"\"\n This function takes a list of integers as input and returns a dictionary \n where keys are unique elements from the list and values are their respective frequencies.\n\n Parameters:\n lst (list): A list of integers.\n\n Returns:\n dict: A dictionary where keys are unique elements from the list and values are their frequencies.\n \"\"\"\n # Initialize an empty dictionary to store the frequency of elements\n frequency_dict = {}\n \n # Iterate over each element in the list\n for element in lst:\n # If the element is already in the dictionary, increment its count by 1\n if element in frequency_dict:\n frequency_dict[element] += 1\n # If the element is not in the dictionary, add it with a count of 1\n else:\n frequency_dict[element] = 1\n \n # Return the dictionary\n return frequency_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n \"\"\"\n Return a dictionary with the frequency of each element in the list.\n\n Args:\n lst (list): A list of elements.\n\n Returns:\n dict: A dictionary where keys are unique elements from the list and values are their frequencies.\n \"\"\"\n freq_dict = {}\n for elem in lst:\n if elem in freq_dict:\n freq_dict[elem] += 1\n else:\n freq_dict[elem] = 1\n return freq_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n \"\"\"\n This function calculates the frequency of elements in a given list.\n \n Args:\n lst (list): The list of elements.\n\n Returns:\n dict: A dictionary where keys are the unique elements in the list and values are their frequencies.\n \"\"\"\n freq = {}\n for item in lst:\n if item in freq:\n freq[item] += 1\n else:\n freq[item] = 1\n return freq", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n \"\"\"\n This function takes in a list of numbers and returns a dictionary\n where the keys are the unique elements from the list and the values\n are the frequency of each element.\n\n Parameters:\n lst (list): A list of numbers.\n\n Returns:\n dict: A dictionary with unique elements as keys and their frequencies as values.\n \"\"\"\n freq_dict = {}\n for num in lst:\n if num in freq_dict:\n freq_dict[num] += 1\n else:\n freq_dict[num] = 1\n return freq_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n \"\"\"\n This function takes a list of numbers as input and returns a dictionary with the frequency of each element.\n\n Parameters:\n lst (list): A list of integers.\n\n Returns:\n dict: A dictionary where keys are the elements of the list and values are their frequencies.\n \"\"\"\n # Initialize an empty dictionary to store the frequency of each element.\n freq = {}\n \n # Iterate over each element in the list.\n for num in lst:\n # If the number is already in the dictionary, increment its count by 1.\n if num in freq:\n freq[num] += 1\n # If the number is not in the dictionary, add it with a count of 1.\n else:\n freq[num] = 1\n \n # Return the dictionary with frequency of each element.\n return freq", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n \"\"\"\n Function to calculate frequency of each element in a list.\n\n Args:\n lst (list): A list of elements for which frequency needs to be calculated.\n\n Returns:\n dict: A dictionary where keys are unique elements in the list and values are their frequencies.\n\n \"\"\"\n # Create a dictionary to store frequency of each element\n freq = {}\n \n # Iterate over the list to count the frequency of each element\n for num in lst:\n # If the number is already in the dictionary, increment its count\n if num in freq:\n freq[num] += 1\n # If the number is not in the dictionary, add it with a count of 1\n else:\n freq[num] = 1\n \n # Return the dictionary with frequency of each element\n return freq", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n \"\"\"\n This function returns a dictionary with frequency of each element in the given list.\n\n Args:\n lst (list): The input list to calculate frequency from.\n\n Returns:\n dict: A dictionary where keys are the elements of the list and values are their frequencies.\n \"\"\"\n # Create an empty dictionary to store the frequency of each element\n freq_dict = {}\n\n # Iterate over each element in the list\n for item in lst:\n # If the element is already in the dictionary, increment its count\n if item in freq_dict:\n freq_dict[item] += 1\n # If the element is not in the dictionary, add it with a count of 1\n else:\n freq_dict[item] = 1\n\n # Return the dictionary\n return freq_dict", "matching_cluster_idx": 5}]}, "Mbpp/90": {"dps": 65.82926829268293, "dps_norm": 80.0, "pass@1": 81.0, "profiled": [{"solution": "def len_log(words):\n \"\"\"\n This function finds the length of the longest word in a given list of words.\n \n Parameters:\n words (list): A list of strings where each string is a word.\n \n Returns:\n int: The length of the longest word in the given list.\n \"\"\"\n if not words: # Check if the list is empty\n return 0\n else:\n return max(len(word) for word in words) # Use a generator expression to find the max length", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n \"\"\"\n This function calculates the length of the longest word in a given list.\n \n Args:\n words (list): A list of strings.\n \n Returns:\n int: The length of the longest word in the list.\n \"\"\"\n return max(len(word) for word in words)", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n \"\"\"\n Returns the length of the longest word in a given list.\n \n Args:\n words (list): A list of words.\n \n Returns:\n int: The length of the longest word.\n \"\"\"\n return max(len(word) for word in words)", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n \"\"\"\n Returns the length of the longest word in the given list.\n\n Args:\n words (list): A list of words.\n\n Returns:\n int: The length of the longest word.\n \"\"\"\n return max(len(word) for word in words)", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n \"\"\"\n Find the length of the longest word in a list of words.\n \n Args:\n words (list): A list of strings.\n \n Returns:\n int: The length of the longest word.\n \"\"\"\n return max(len(word) for word in words)", "matching_cluster_idx": 5}, {"solution": "def len_log(word_list):\n \"\"\"\n This function takes a list of words and returns the length of the longest word in the list.\n \n Parameters:\n word_list (list): A list of words\n \n Returns:\n int: The length of the longest word in the list\n \"\"\"\n # Initialize max_length as 0\n max_length = 0\n \n # Iterate over each word in the list\n for word in word_list:\n # Check if the length of the current word is greater than max_length\n if len(word) > max_length:\n # Update max_length\n max_length = len(word)\n \n # Return max_length\n return max_length", "matching_cluster_idx": 5}, {"solution": "def len_log(word_list):\n \"\"\"\n This function takes a list of words as input and returns the length of the longest word.\n \n Parameters:\n word_list (list): A list of strings.\n \n Returns:\n int: The length of the longest word in the list.\n \"\"\"\n \n # Use the max function with a key argument set to len to find the longest word\n longest_word = max(word_list, key=len)\n \n # Return the length of the longest word\n return len(longest_word)", "matching_cluster_idx": 6}, {"solution": "def len_log(word_list):\n \"\"\"\n This function finds the length of the longest word in a given list.\n\n Args:\n word_list (list): A list of words.\n\n Returns:\n int: The length of the longest word in the list.\n\n \"\"\"\n # Check if the input is a list\n if not isinstance(word_list, list):\n raise ValueError(\"Input must be a list\")\n\n # Initialize the maximum length to 0\n max_length = 0\n\n # Iterate over each word in the list\n for word in word_list:\n # Check if the word is a string\n if not isinstance(word, str):\n raise ValueError(\"All elements in the list must be strings\")\n \n # Update the maximum length if the length of the current word is greater\n max_length = max(max_length, len(word))\n\n # Return the maximum length\n return max_length", "matching_cluster_idx": 2}, {"solution": "def len_log(words):\n \"\"\"\n This function returns the length of the longest word in a given list of words.\n \n Args:\n words (list): A list of strings.\n \n Returns:\n int: The length of the longest word.\n \"\"\"\n # Check if the input list is empty\n if not words:\n return 0\n \n # Use the built-in max function with a key to find the longest word\n # The key is the len function which returns the length of each word\n return max(len(word) for word in words)", "matching_cluster_idx": 5}, {"solution": "def len_log(lst):\n \"\"\"\n Returns the length of the longest word in the list.\n \n Args:\n lst (list): A list of words.\n \n Returns:\n int: The length of the longest word.\n \"\"\"\n if not lst:\n return 0 # Return 0 if the list is empty.\n return max(len(word) for word in lst)", "matching_cluster_idx": 5}, {"solution": "def len_log(word_list):\n \"\"\"\n This function takes a list of words and returns the length of the longest word.\n\n Args:\n word_list (list): A list of strings.\n\n Returns:\n int: The length of the longest word in the list.\n \"\"\"\n # Check if the input is a list\n if not isinstance(word_list, list):\n raise TypeError(\"Input must be a list\")\n\n # Check if the list is empty\n if not word_list:\n return 0\n\n # Initialize max_length with the length of the first word in the list\n max_length = len(word_list[0])\n\n # Iterate through the list to find the length of the longest word\n for word in word_list:\n # Check if the current word is a string\n if not isinstance(word, str):\n raise ValueError(\"All elements in the list must be strings\")\n\n # Update max_length if the current word is longer\n if len(word) > max_length:\n max_length = len(word)\n\n # Return the length of the longest word\n return max_length", "matching_cluster_idx": 3}, {"solution": "def len_log(s):\n \"\"\"\n This function finds the length of the longest word in a given list.\n\n Args:\n s (list): A list of strings\n\n Returns:\n int: The length of the longest word\n\n \"\"\"\n return max(len(word) for word in s)", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n \"\"\"\n This function takes a list of words as input and returns the length of the longest word.\n \n Args:\n words (list): A list of strings.\n \n Returns:\n int: The length of the longest word.\n \"\"\"\n return max(len(word) for word in words)", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n \"\"\"\n This function takes a list of words as an input and returns the length of the longest word.\n\n Args:\n words (list): A list of strings.\n\n Returns:\n int: The length of the longest word.\n \"\"\"\n # Use max function with a custom key to find the longest word in the list\n return max(len(word) for word in words)", "matching_cluster_idx": 5}, {"solution": "def len_log(word_list):\n \"\"\"\n This function calculates the length of the longest word in a given list of words.\n \n Parameters:\n word_list (list): A list of words.\n \n Returns:\n int: The length of the longest word in the list.\n \"\"\"\n if not word_list:\n return 0\n \n return max(len(word) for word in word_list)", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n \"\"\"\n This function calculates the length of the longest word in a given list of words.\n \n Args:\n words (list): A list of words\n \n Returns:\n int: The length of the longest word in the list\n \"\"\"\n return max(len(word) for word in words)", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n \"\"\"\n This function returns the length of the longest word in a given list.\n \n Args:\n words (list): A list of strings.\n \n Returns:\n int: The length of the longest word.\n \"\"\"\n return max(len(word) for word in words)", "matching_cluster_idx": 5}, {"solution": "def len_log(word_list):\n \"\"\"\n This function calculates the length of the longest word in the given list of words.\n\n Args:\n word_list (list): A list of words.\n\n Returns:\n int: The length of the longest word in the list.\n \"\"\"\n return max(len(word) for word in word_list)", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n \"\"\"\n This function calculates the length of the longest word in the given list of words.\n \n Args:\n words (list): A list of strings.\n \n Returns:\n int: The length of the longest word in the list.\n \"\"\"\n \n if not isinstance(words, list) or not all(isinstance(word, str) for word in words):\n raise TypeError(\"Input must be a list of strings\")\n \n # Use the built-in max function with a key argument to find the longest word\n return max(len(word) for word in words)", "matching_cluster_idx": 3}, {"solution": "def len_log(word_list):\n \"\"\"\n This function takes a list of words as an input and returns the length of the longest word in the list.\n\n Parameters:\n word_list (list): A list of words.\n\n Returns:\n int: The length of the longest word in the list.\n \"\"\"\n # Initialize max_length as 0, assuming the list is not empty\n max_length = 0\n \n # Iterate over each word in the word list\n for word in word_list:\n # Update max_length if the current word's length is greater than max_length\n max_length = max(max_length, len(word))\n \n # Return the max_length\n return max_length", "matching_cluster_idx": 3}]}, "Mbpp/94": {"dps": 78.04878048780488, "dps_norm": 60.0, "pass@1": 88.0, "profiled": [{"solution": "def index_minimum(tuples):\n \"\"\"\n Returns the first value of the tuple with the smallest second value in a list of tuples.\n\n Args:\n tuples (list): A list of tuples where each tuple contains a string and an integer.\n\n Returns:\n str: The first element of the tuple with the smallest second element.\n\n Raises:\n ValueError: If the input list is empty.\n \"\"\"\n if not tuples:\n raise ValueError(\"Input list cannot be empty\")\n\n return min(tuples, key=lambda x: x[1])[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(lst):\n \"\"\"\n This function returns the first value of the tuple with the smallest second value.\n \n Args:\n lst (list): A list of tuples, where each tuple contains a string and an integer.\n \n Returns:\n str: The first value of the tuple with the smallest second value.\n \"\"\"\n # Check if the list is empty\n if not lst:\n return None\n \n # Use the built-in min function with a custom key to find the tuple with the smallest second value\n smallest = min(lst, key=lambda x: x[1])\n \n # Return the first value of the tuple with the smallest second value\n return smallest[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(tuples_list):\n \"\"\"\n Returns the first value of the tuple with the smallest second value.\n \n Args:\n tuples_list (list): A list of tuples.\n \n Returns:\n The first value of the tuple with the smallest second value.\n \"\"\"\n if not tuples_list:\n return None # Return None if the input list is empty\n \n return min(tuples_list, key=lambda x: x[1])[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(lst):\n \"\"\"\n Returns the first value of the tuple with the smallest second value in a list of tuples.\n\n Args:\n lst (list): A list of tuples.\n\n Returns:\n The first value of the tuple with the smallest second value.\n \"\"\"\n return min(lst, key=lambda x: x[1])[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(lst):\n \"\"\"\n Returns the first value of the tuple with the smallest second value from the given list of tuples.\n\n Args:\n lst (list): A list of tuples where each tuple contains a string and an integer.\n\n Returns:\n The first value of the tuple with the smallest second value.\n \"\"\"\n if not lst:\n raise ValueError(\"The input list is empty\")\n\n # Use the built-in min function with a custom key function that returns the second element of each tuple\n min_element = min(lst, key=lambda x: x[1])\n\n # Return the first element of the tuple with the smallest second value\n return min_element[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(tuples_list):\n \"\"\"\n This function returns the first value of the tuple in the list with the smallest second value.\n \n Args:\n tuples_list (list): A list of tuples containing two values each.\n \n Returns:\n The first value of the tuple with the smallest second value.\n \"\"\"\n \n # Using the built-in min function with a key parameter to specify the second element of the tuple should be used for comparison\n return min(tuples_list, key=lambda x: x[1])[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(tuples):\n \"\"\"\n Returns the first value of the tuple with the smallest second value.\n\n Args:\n tuples (list): A list of tuples containing two elements.\n\n Returns:\n The first value of the tuple with the smallest second value.\n \"\"\"\n if not tuples:\n return None # Return None if the list is empty\n return min(tuples, key=lambda x: x[1])[0] # Return the first element of the tuple with the smallest second value", "matching_cluster_idx": 2}, {"solution": "def index_minimum(lst):\n \"\"\"\n This function takes a list of tuples as an argument and returns the first value of the tuple with the smallest second value.\n\n Args:\n lst (list): A list of tuples\n\n Returns:\n str: The first value of the tuple with the smallest second value\n \"\"\"\n return min(lst, key=lambda x: x[1])[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(lst):\n \"\"\"\n This function takes a list of tuples as input, \n and returns the first value of the tuple with the smallest second value.\n\n Args:\n lst (list): A list of tuples where each tuple contains two values.\n\n Returns:\n any: The first value of the tuple with the smallest second value.\n \"\"\"\n # Check if the list is empty\n if not lst:\n return None\n\n # Find the tuple with the smallest second value\n smallest_second_value = min(lst, key=lambda x: x[1])[1]\n\n # Return the first value of the tuple with the smallest second value\n return next(t[0] for t in lst if t[1] == smallest_second_value)", "matching_cluster_idx": 2}, {"solution": "def index_minimum(lst):\n \"\"\"\n This function takes a list of tuples as an input, \n returns the first value of the tuple with the smallest second value.\n\n Args:\n lst (list): A list of tuples where each tuple contains a string and an integer.\n\n Returns:\n str: The first value of the tuple with the smallest second value.\n \"\"\"\n # Use the min function with a key parameter to find the tuple with the smallest second value\n # The key parameter specifies that the second value (at index 1) should be used for comparison\n # The min function returns the entire tuple with the smallest second value\n # We then return the first value of this tuple using the index 0\n return min(lst, key=lambda x: x[1])[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(lst):\n \"\"\"\n Returns the first value of the tuple in lst with the smallest second value.\n\n Args:\n lst (list): A list of tuples.\n\n Returns:\n The first value of the tuple with the smallest second value.\n\n Raises:\n ValueError: If the input list is empty or does not contain tuples.\n \"\"\"\n if not lst or not all(isinstance(t, tuple) for t in lst):\n raise ValueError(\"Input list must be non-empty and contain tuples\")\n\n return min(lst, key=lambda x: x[1])[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(tuples):\n \"\"\"\n Returns the first value of the tuple with the smallest second value.\n \n Args:\n tuples (list): A list of tuples, each tuple containing two elements.\n \n Returns:\n The first value of the tuple with the smallest second value.\n \"\"\"\n \n # Check if the input list is empty\n if not tuples:\n return None\n \n # Use the min function with a custom key to find the tuple with the smallest second value\n return min(tuples, key=lambda x: x[1])[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(lst):\n \"\"\"\n Returns the first value of the tuple with the smallest second value from the given list of tuples.\n \n Args:\n lst (list): A list of tuples, where each tuple contains two values.\n\n Returns:\n The first value of the tuple with the smallest second value.\n \"\"\"\n # Use the built-in min function with a custom key to find the tuple with the smallest second value\n smallest_second_value_tuple = min(lst, key=lambda x: x[1])\n \n # Return the first value of the tuple found above\n return smallest_second_value_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(lst):\n \"\"\"\n Returns the first value of the tuple with the smallest second value from a list of tuples.\n\n Args:\n lst (list): A list of tuples where each tuple contains a string and an integer.\n\n Returns:\n str: The first value of the tuple with the smallest second value.\n\n Raises:\n ValueError: If the input list is empty.\n\n \"\"\"\n if not lst:\n raise ValueError(\"Input list cannot be empty\")\n\n return min(lst, key=lambda x: x[1])[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(lst):\n \"\"\"\n Returns the first value of the tuple with the smallest second value from a list of tuples.\n\n Args:\n lst (list): A list of tuples.\n\n Returns:\n The first value of the tuple with the smallest second value.\n\n Raises:\n ValueError: If the list is empty.\n\n Example:\n >>> index_minimum([('Rash', 143), ('Manjeet', 200), ('Varsha', 100)])\n 'Varsha'\n \"\"\"\n if not lst:\n raise ValueError(\"List cannot be empty\")\n\n return min(lst, key=lambda x: x[1])[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(lst):\n \"\"\"\n This function takes a list of tuples as an argument and returns the first value of the tuple with the smallest second value.\n\n Parameters:\n lst (list): A list of tuples, where each tuple contains a string and an integer.\n\n Returns:\n str: The first value of the tuple with the smallest second value.\n\n Raises:\n ValueError: If the input list is empty.\n \"\"\"\n if not lst:\n raise ValueError(\"Input list is empty\")\n\n # Use the built-in min function with a key to find the tuple with the smallest second value\n smallest_tuple = min(lst, key=lambda x: x[1])\n \n # Return the first value of the smallest tuple\n return smallest_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(lst):\n \"\"\"\n Returns the first value of the tuple with the smallest second value in the list of tuples.\n\n Args:\n lst (list): A list of tuples where each tuple contains a string and an integer.\n\n Returns:\n str: The first value of the tuple with the smallest second value.\n \"\"\"\n # Using the built-in min function with a custom key to find the tuple with the smallest second value\n smallest_tuple = min(lst, key=lambda x: x[1])\n # Return the first value of the smallest tuple\n return smallest_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(lst):\n \"\"\"\n This function takes a list of tuples as an input and returns the first value of the tuple with the smallest second value.\n\n Args:\n lst (list): A list of tuples.\n\n Returns:\n The first value of the tuple with the smallest second value.\n \"\"\"\n return min(lst, key=lambda x: x[1])[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(tuples_list):\n \"\"\"\n This function returns the first value of the tuple with the smallest second value.\n\n Args:\n tuples_list (list): A list of tuples, where each tuple contains two values.\n\n Returns:\n str: The first value of the tuple with the smallest second value.\n \"\"\"\n return min(tuples_list, key=lambda x: x[1])[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(tuples_list):\n \"\"\"\n Return the first value of the tuple in the list with the smallest second value.\n \n Args:\n tuples_list (list): A list of tuples.\n \n Returns:\n The first value of the tuple with the smallest second value.\n \"\"\"\n # Check if the input list is empty\n if not tuples_list:\n return None\n \n # Use the built-in min function with a custom key to find the tuple with the smallest second value\n # The min function returns the tuple itself, not the first element of it, so we use [0] to get the first element\n return min(tuples_list, key=lambda x: x[1])[0]", "matching_cluster_idx": 2}]}, "Mbpp/96": {"dps": 61.38888888888888, "dps_norm": 67.85714285714286, "pass@1": 93.0, "profiled": [{"solution": "def divisor(n):\n \"\"\"\n Returns the number of divisors of a given integer.\n\n Args:\n n (int): The input integer.\n\n Returns:\n int: The number of divisors of n.\n \"\"\"\n count = 0\n for i in range(1, int(n ** 0.5) + 1):\n if n % i == 0:\n if i * i == n: # i is a square root of n\n count += 1\n else:\n count += 2 # increment by 2 since i and n//i are divisors\n return count", "matching_cluster_idx": 6}, {"solution": "def divisor(n):\n \"\"\"\n This function calculates the number of divisors of a given integer n.\n\n Args:\n n (int): The input number.\n\n Returns:\n int: The number of divisors of the input number.\n\n Example:\n >>> divisor(15)\n 4\n \"\"\"\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n # If i is a divisor, n // i is also a divisor\n if n // i == i:\n count += 1\n else:\n count += 2\n return count", "matching_cluster_idx": 5}, {"solution": "def divisor(n):\n \"\"\"\n This function calculates the number of divisors of a given integer.\n\n Args:\n n (int): The input integer.\n\n Returns:\n int: The number of divisors of the input integer.\n\n \"\"\"\n # Initialize the count of divisors to 0\n count = 0\n\n # Iterate over all numbers from 1 to the input number\n for i in range(1, n + 1):\n # Check if the current number is a divisor of the input number\n if n % i == 0:\n # If the number is a divisor, increment the count\n count += 1\n\n # Return the total count of divisors\n return count", "matching_cluster_idx": 1}, {"solution": "def divisor(n):\n \"\"\"\n This function returns the total number of divisors for the given integer.\n \n Parameters:\n n (int): The number to find divisors of.\n \n Returns:\n int: The total number of divisors.\n \"\"\"\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n # If i is a divisor, n // i is also a divisor\n count += 2 if i != n // i else 1\n return count", "matching_cluster_idx": 6}, {"solution": "def divisor(n):\n \"\"\"\n This function calculates the number of divisors for a given integer n.\n\n Args:\n n (int): The input number for which divisors are to be calculated.\n\n Returns:\n int: The number of divisors for the given number n.\n \"\"\"\n # Initialize count of divisors\n count = 0\n\n # Loop through all numbers from 1 to n\n for i in range(1, n + 1):\n # Check if i is a divisor of n\n if n % i == 0:\n # Increment the count if i is a divisor\n count += 1\n\n # Return the total count of divisors\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n \"\"\"\n This function calculates the number of divisors of a given integer.\n \n Args:\n n (int): The input integer for which the number of divisors is to be calculated.\n \n Returns:\n int: The number of divisors of n.\n \"\"\"\n count = 0\n for i in range(1, n + 1):\n # Check if i is a divisor of n\n if n % i == 0:\n # If it is, increment the count\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def divisor(n):\n \"\"\"\n Find the number of divisors of a given integer.\n \n Parameters:\n n (int): A positive integer.\n \n Returns:\n int: The number of divisors of n.\n \"\"\"\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def divisor(n):\n \"\"\"\n This function calculates the number of divisors of a given integer.\n \n Args:\n n (int): The number to find divisors for.\n \n Returns:\n int: The number of divisors of n.\n \"\"\"\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n count += 2\n if i == n // i: # Count square root only once\n count -= 1\n return count", "matching_cluster_idx": 6}, {"solution": "def divisor(n):\n \"\"\"\n Returns the number of divisors of a given integer.\n \n Args:\n n (int): A positive integer.\n \n Returns:\n int: The number of divisors of n.\n \"\"\"\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def divisor(n):\n \"\"\"\n This function calculates the number of divisors of a given integer n.\n \n Args:\n n (int): The input integer.\n \n Returns:\n int: The number of divisors of the input integer.\n \"\"\"\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def divisor(n):\n \"\"\"\n This function calculates the number of divisors of a given integer n.\n\n Args:\n n (int): The input integer.\n\n Returns:\n int: The number of divisors of n.\n \"\"\"\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def divisor(n):\n \"\"\"\n Returns the number of divisors of a given integer n.\n\n Args:\n n (int): The number to calculate divisors for.\n\n Returns:\n int: The number of divisors of n.\n \"\"\"\n if n < 1:\n raise ValueError(\"Input must be a positive integer.\")\n \n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n # Check if divisor is a square root\n if i * i == n:\n count += 1\n else:\n # Check for other divisors pair (i and n/i)\n count += 2\n return count", "matching_cluster_idx": 6}, {"solution": "def divisor(n):\n \"\"\"\n Calculate the number of divisors of a given integer.\n\n Args:\n n (int): The input number.\n\n Returns:\n int: The number of divisors of the input number.\n \"\"\"\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n # If i is a divisor, then n//i is also a divisor\n if n // i == i:\n count += 1\n else:\n count += 2\n return count", "matching_cluster_idx": 6}, {"solution": "def divisor(n):\n \"\"\"\n Calculate the number of divisors of a given integer.\n \n Args:\n n (int): The input integer.\n \n Returns:\n int: The number of divisors of n.\n \"\"\"\n count = 0\n for i in range(1, int(n ** 0.5) + 1):\n if n % i == 0:\n # If i is a divisor, n//i is also a divisor\n count += 2 if i != n // i else 1\n return count", "matching_cluster_idx": 6}, {"solution": "def divisor(n):\n \"\"\"\n This function finds the number of divisors of a given integer.\n \n Args:\n n (int): The input integer.\n \n Returns:\n int: The number of divisors of the input integer.\n \"\"\"\n count = 0\n for i in range(1, n + 1):\n if n % i == 0: # check if i is a divisor\n count += 1 # increment the count if i is a divisor\n return count", "matching_cluster_idx": 1}, {"solution": "def divisor(n):\n \"\"\"\n Function to calculate the number of divisors of a given integer.\n \n Parameters:\n n (int): The input integer.\n \n Returns:\n int: The number of divisors of the input integer.\n \"\"\"\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n # If 'i' is a divisor, then 'n/i' is also a divisor.\n # To avoid counting them as two different divisors, \n # we only count 'i' when 'i' is less than or equal to the square root of 'n'.\n if i * i == n:\n # If 'i' is the square root of 'n', then it is counted above and 'n/i' is also counted below.\n # In this case, we don't count 'n/i' again.\n count += 1\n else:\n count += 2 # Count 'i' and 'n/i'\n return count", "matching_cluster_idx": 6}, {"solution": "def divisor(n):\n \"\"\"\n This function calculates the number of divisors of a given integer.\n\n Args:\n n (int): The number for which to calculate the number of divisors.\n\n Returns:\n int: The number of divisors of n.\n \"\"\"\n count = 0\n for i in range(1, int(n ** 0.5) + 1):\n if n % i == 0:\n if i * i == n:\n count += 1\n else:\n count += 2\n return count", "matching_cluster_idx": 6}, {"solution": "def divisor(n):\n \"\"\"\n This function calculates the number of divisors of a given integer n.\n\n Parameters:\n n (int): The input integer.\n\n Returns:\n int: The number of divisors of the input integer.\n \"\"\"\n # Initialize a counter variable to store the number of divisors\n count = 0\n\n # Iterate through numbers from 1 to n (inclusive)\n for i in range(1, n + 1):\n # Check if the current number i is a divisor of n\n if n % i == 0:\n # If i is a divisor, increment the counter\n count += 1\n\n # Return the total count of divisors\n return count", "matching_cluster_idx": 1}, {"solution": "def divisor(n):\n \"\"\"\n Counts the number of divisors for a given positive integer.\n\n Args:\n n (int): A positive integer.\n\n Returns:\n int: The number of divisors for the given integer.\n \"\"\"\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n if i * i == n:\n count += 1\n else:\n count += 2\n return count", "matching_cluster_idx": 6}, {"solution": "def divisor(n):\n \"\"\"\n Function to find the number of divisors of a given integer.\n \n Args:\n n (int): The input integer.\n \n Returns:\n int: The number of divisors of the input integer.\n \"\"\"\n count = 0\n for i in range(1, int(n ** 0.5) + 1):\n if n % i == 0:\n if n // i == i:\n count += 1\n else:\n count += 2\n return count", "matching_cluster_idx": 6}]}, "Mbpp/97": {"dps": 40.44444444444444, "dps_norm": 51.875, "pass@1": 98.0, "profiled": [{"solution": "def frequency_lists(lst):\n \"\"\"\n This function finds frequency of each element in a flattened list of lists and returns them in a dictionary.\n\n Args:\n lst (list): A list of lists containing integers.\n\n Returns:\n dict: A dictionary where keys are elements from the list and values are their frequencies.\n \"\"\"\n # Initialize an empty dictionary to store the frequency of each element\n frequency_dict = {}\n\n # Flatten the list of lists into a single list\n flattened_list = [item for sublist in lst for item in sublist]\n\n # Iterate over the flattened list and update the frequency dictionary\n for item in flattened_list:\n if item in frequency_dict:\n frequency_dict[item] += 1\n else:\n frequency_dict[item] = 1\n\n return frequency_dict", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lists):\n \"\"\"\n Find frequency of each element in a flattened list of lists.\n\n Args:\n lists (list): A list containing lists of integers.\n\n Returns:\n dict: A dictionary with elements from the input as keys and their frequencies as values.\n\n Example:\n >>> frequency_lists([[1, 2, 3, 2], [4, 5, 6, 2], [7, 8, 9, 5]])\n {1: 1, 2: 3, 3: 1, 4: 1, 5: 2, 6: 1, 7: 1, 8: 1, 9: 1}\n \"\"\"\n flattened_list = [element for sublist in lists for element in sublist]\n frequency = {}\n for element in flattened_list:\n frequency[element] = flattened_list.count(element)\n return frequency", "matching_cluster_idx": 1}, {"solution": "def frequency_lists(lst):\n \"\"\"\n This function takes a list of lists and returns a dictionary with frequency of each element.\n \n Args:\n lst (list): A list of lists.\n \n Returns:\n dict: A dictionary with each element from the flattened list as keys and its frequency as values.\n \"\"\"\n # Flatten the list of lists using a list comprehension\n flattened_list = [item for sublist in lst for item in sublist]\n \n # Create a dictionary with the frequency of each element using the dict() function and a dictionary comprehension\n frequency_dict = {item: flattened_list.count(item) for item in set(flattened_list)}\n \n return frequency_dict", "matching_cluster_idx": 2}, {"solution": "def frequency_lists(lists):\n \"\"\"\n This function calculates the frequency of each element in a flattened list of lists.\n \n Args:\n lists (list): A list containing multiple lists.\n \n Returns:\n dict: A dictionary where keys are elements from the flattened list and values are their frequencies.\n \"\"\"\n # Flatten the list of lists into a single list\n flat_list = [item for sublist in lists for item in sublist]\n \n # Use dictionary comprehension to count the frequency of each element\n frequency_dict = {element: flat_list.count(element) for element in flat_list}\n \n return frequency_dict\nlists = [[1, 2, 3, 2], [4, 5, 6, 2], [7, 8, 9, 5]]", "matching_cluster_idx": 1}, {"solution": "def frequency_lists(lists):\n \"\"\"\n This function takes a list of lists and returns a dictionary with frequencies of each element.\n\n Args:\n lists (list): A list of lists\n\n Returns:\n dict: A dictionary with element frequencies\n\n \"\"\"\n # Initialize an empty dictionary to store the frequency of each element\n frequency = {}\n \n # Flatten the list of lists\n flat_list = [item for sublist in lists for item in sublist]\n \n # Iterate over each item in the flattened list\n for item in flat_list:\n # If the item is already in the dictionary, increment its count\n if item in frequency:\n frequency[item] += 1\n # Otherwise, add the item to the dictionary with a count of 1\n else:\n frequency[item] = 1\n \n return frequency", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lists):\n \"\"\"\n This function takes a list of lists as input, flattens it into a single list,\n and returns a dictionary where keys are elements from the list and values are their frequencies.\n\n Args:\n lists (list): A list of lists containing integers.\n\n Returns:\n dict: A dictionary where keys are elements from the list and values are their frequencies.\n \"\"\"\n # Flatten the list of lists into a single list\n flattened_list = [element for sublist in lists for element in sublist]\n \n # Use a dictionary comprehension to count the frequency of each element\n frequency_dict = {element: flattened_list.count(element) for element in set(flattened_list)}\n \n return frequency_dict", "matching_cluster_idx": 2}, {"solution": "def frequency_lists(lists):\n \"\"\"\n This function finds the frequency of each element in a flattened list of lists.\n\n Args:\n lists (list): A list of lists containing integers.\n\n Returns:\n dict: A dictionary where keys are elements from the flattened list of lists and values are their frequencies.\n\n Raises:\n TypeError: If the input is not a list of lists.\n \"\"\"\n if not isinstance(lists, list) or not all(isinstance(lst, list) for lst in lists):\n raise TypeError(\"Input must be a list of lists.\")\n\n # Flatten the list of lists into a single list\n flat_list = [num for sublist in lists for num in sublist]\n\n # Use a dictionary to store the frequency of each element\n frequency = {}\n for num in flat_list:\n frequency[num] = frequency.get(num, 0) + 1\n\n return frequency", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lists):\n \"\"\"\n This function calculates the frequency of each element in a flattened list of lists.\n\n Args:\n lists (list): A list of lists\n\n Returns:\n dict: A dictionary where keys are elements from the flattened list and values are their corresponding frequencies.\n \"\"\"\n # Flatten the list of lists into a single list\n flattened_list = [item for sublist in lists for item in sublist]\n \n # Create a dictionary with elements from the flattened list as keys and their frequencies as values\n frequency_dict = {}\n for item in flattened_list:\n if item in frequency_dict:\n frequency_dict[item] += 1\n else:\n frequency_dict[item] = 1\n \n return frequency_dict", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lists):\n \"\"\"\n This function calculates the frequency of each element in a flattened list of lists.\n\n Args:\n lists (list): A list of lists containing integers.\n\n Returns:\n dict: A dictionary where keys are the elements in the input lists and values are their frequencies.\n\n \"\"\"\n # Initialize an empty dictionary to store the frequency of each element\n frequency = {}\n\n # Flatten the list of lists using a list comprehension\n flattened_list = [element for sublist in lists for element in sublist]\n\n # Use a dictionary comprehension to count the frequency of each element\n for element in flattened_list:\n frequency[element] = flattened_list.count(element)\n\n return frequency", "matching_cluster_idx": 1}, {"solution": "def frequency_lists(lists):\n \"\"\"\n This function takes a list of lists, flattens the list, and returns a dictionary where keys are the elements and values are their respective frequencies.\n\n Args:\n lists (list): A list of lists containing integers.\n\n Returns:\n dict: A dictionary with elements as keys and their frequencies as values.\n \"\"\"\n flattened_list = [item for sublist in lists for item in sublist]\n frequency_dict = {}\n for item in flattened_list:\n if item in frequency_dict:\n frequency_dict[item] += 1\n else:\n frequency_dict[item] = 1\n return frequency_dict", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lists):\n \"\"\"\n This function calculates frequency of each element in a flattened list of lists.\n \n Args:\n lists (list): A list of lists containing integers.\n \n Returns:\n dict: A dictionary with keys as elements and values as their frequencies.\n \"\"\"\n # Flatten the list of lists using list comprehension\n flat_list = [element for sublist in lists for element in sublist]\n \n # Use dictionary comprehension to count frequency of each element\n frequency_dict = {element: flat_list.count(element) for element in set(flat_list)}\n \n return frequency_dict", "matching_cluster_idx": 2}, {"solution": "def frequency_lists(lists):\n \"\"\"\n This function finds the frequency of each element in a flattened list of lists.\n\n Args:\n lists (list): A list of lists containing integers.\n\n Returns:\n dict: A dictionary where keys are the elements in the lists and values are their frequencies.\n \"\"\"\n # Flatten the list of lists into a single list\n flat_list = [item for sublist in lists for item in sublist]\n \n # Use a dictionary comprehension to create a dictionary where keys are the elements and values are their frequencies\n frequency_dict = {item: flat_list.count(item) for item in flat_list}\n \n return frequency_dict", "matching_cluster_idx": 1}, {"solution": "def frequency_lists(lst):\n \"\"\"\n This function takes a list of lists, flattens it and returns a dictionary where keys are elements from the list and values are their frequencies.\n \n Parameters:\n lst (list): A list of lists containing integers.\n \n Returns:\n dict: A dictionary with elements from the list as keys and their frequencies as values.\n \"\"\"\n # Flatten the list using a list comprehension\n flat_list = [item for sublist in lst for item in sublist]\n \n # Use dictionary comprehension to count the frequency of each element\n frequency_dict = {item: flat_list.count(item) for item in set(flat_list)}\n \n return frequency_dict", "matching_cluster_idx": 2}, {"solution": "def frequency_lists(lists):\n \"\"\"\n This function takes a list of lists as input, flattens it, and returns a dictionary\n with frequency of each element in the flattened list.\n\n Args:\n lists (list): A list of lists.\n\n Returns:\n dict: A dictionary with frequency of each element in the flattened list.\n \"\"\"\n # Flatten the list of lists using list comprehension\n flattened_list = [item for sublist in lists for item in sublist]\n \n # Create a dictionary with frequency of each element using dictionary comprehension\n frequency_dict = {item: flattened_list.count(item) for item in set(flattened_list)}\n \n return frequency_dict", "matching_cluster_idx": 2}, {"solution": "def frequency_lists(lists):\n \"\"\"\n This function calculates the frequency of each element in a flattened list of lists.\n \n Args:\n lists (list): A list of lists containing elements to be counted.\n \n Returns:\n dict: A dictionary where keys are unique elements and values are their frequencies.\n \"\"\"\n \n # Initialize an empty dictionary to store frequency of elements\n frequency_dict = {}\n \n # Flatten the list of lists\n flat_list = [element for sublist in lists for element in sublist]\n \n # Iterate through each element in the flattened list\n for element in flat_list:\n # If the element is already in the dictionary, increment its frequency by 1\n if element in frequency_dict:\n frequency_dict[element] += 1\n # If the element is not in the dictionary, add it with a frequency of 1\n else:\n frequency_dict[element] = 1\n \n return frequency_dict\nlists = [[1, 2, 3, 2], [4, 5, 6, 2], [7, 8, 9, 5]]", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lst):\n \"\"\"\n This function takes a list of lists as input, flattens it, and returns a dictionary where the keys are the elements of the list and the values are their frequencies.\n\n Args:\n lst (list): A list of lists.\n\n Returns:\n dict: A dictionary where keys are elements from the list and values are their frequencies.\n \"\"\"\n # Flatten the list of lists into a single list\n flat_list = [item for sublist in lst for item in sublist]\n \n # Use dictionary comprehension to count the frequency of each element\n frequency_dict = {item: flat_list.count(item) for item in flat_list}\n \n return frequency_dict", "matching_cluster_idx": 1}, {"solution": "def frequency_lists(lists):\n \"\"\"\n This function calculates frequency of each element in a flattened list of lists.\n \n Args:\n lists (list of lists): A list containing multiple lists.\n \n Returns:\n dict: A dictionary with elements as keys and their frequencies as values.\n \"\"\"\n \n # Flatten the list of lists using a list comprehension\n flattened_list = [element for sublist in lists for element in sublist]\n \n # Use dictionary comprehension to count the frequency of each element\n frequency_dict = {element: flattened_list.count(element) for element in set(flattened_list)}\n \n return frequency_dict", "matching_cluster_idx": 2}, {"solution": "def frequency_lists(lists):\n \"\"\"\n This function finds the frequency of each element in a flattened list of lists.\n \n Parameters:\n lists (list): A list of lists containing integers.\n \n Returns:\n dict: A dictionary with elements as keys and their frequencies as values.\n \"\"\"\n \n # Flatten the list of lists using list comprehension\n flattened_list = [num for sublist in lists for num in sublist]\n \n # Use dictionary comprehension to find the frequency of each element\n frequency_dict = {num: flattened_list.count(num) for num in set(flattened_list)}\n \n return frequency_dict", "matching_cluster_idx": 2}, {"solution": "def frequency_lists(lists):\n \"\"\"\n Returns a dictionary with the frequency of each element in the flattened list of lists.\n\n Args:\n lists (list of lists): A list of lists containing integers.\n\n Returns:\n dict: A dictionary where keys are unique elements from the flattened list and values are their respective frequencies.\n \"\"\"\n # Use dictionary comprehension to create a dictionary where each key is a unique element from the flattened list\n # and the value is its frequency, initialized to 0\n freq_dict = {i: 0 for i in set([num for sublist in lists for num in sublist])}\n\n # Iterate over each sublist in the input list\n for sublist in lists:\n # Iterate over each element in the sublist\n for num in sublist:\n # Increment the frequency of the current element by 1\n freq_dict[num] += 1\n\n return freq_dict", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lists):\n \"\"\"\n This function takes a list of lists as input and returns a dictionary with the frequency of each element in the flattened list.\n \n Args:\n lists (list): A list of lists containing integers.\n \n Returns:\n dict: A dictionary where keys are the elements from the flattened list and values are their frequencies.\n \"\"\"\n # Flatten the list of lists using a list comprehension\n flattened_list = [item for sublist in lists for item in sublist]\n \n # Use a dictionary comprehension to count the frequency of each element\n frequency_dict = {item: flattened_list.count(item) for item in set(flattened_list)}\n \n return frequency_dict", "matching_cluster_idx": 2}]}, "Mbpp/106": {"dps": 63.76623376623377, "dps_norm": 90.0, "pass@1": 87.0, "profiled": [{"solution": "def add_lists(list_to_append, original_tuple):\n \"\"\"\n Appends elements from the given list to the given tuple.\n \n Args:\n list_to_append (list): A list of elements to be appended.\n original_tuple (tuple): The original tuple to be extended.\n \n Returns:\n tuple: The extended tuple.\n \"\"\"\n \n # Convert the original tuple to a list (since lists are mutable)\n # This is necessary because tuples are immutable in Python and cannot be directly extended\n list_from_tuple = list(original_tuple)\n \n # Extend the list from the original tuple with the elements from the list to append\n list_from_tuple.extend(list_to_append)\n \n # Convert the list back to a tuple\n extended_tuple = tuple(list_from_tuple)\n \n return extended_tuple", "matching_cluster_idx": 4}, {"solution": "def add_lists(lst, t):\n \"\"\"\n Appends the given list to the given tuple.\n \n Args:\n lst (list): The list to append.\n t (tuple): The tuple to append to.\n \n Returns:\n tuple: The new tuple with the list appended.\n \"\"\"\n # Convert the tuple to a list, append the given list, and then convert back to a tuple\n return tuple(t) + tuple(lst)", "matching_cluster_idx": 4}, {"solution": "def add_lists(lst, tup):\n \"\"\"\n This function appends the elements from a list to a tuple.\n \n Args:\n lst (list): A list of elements to be appended.\n tup (tuple): The initial tuple to which the list elements will be added.\n \n Returns:\n tuple: A new tuple with the elements from the list appended to the initial tuple.\n \"\"\"\n return tup + tuple(lst)", "matching_cluster_idx": 4}, {"solution": "def add_lists(list_to_add, tup):\n \"\"\"\n Append a list to a given tuple.\n\n Args:\n list_to_add (list): The list to be appended.\n tup (tuple): The tuple to which the list will be appended.\n\n Returns:\n tuple: The resulting tuple after appending the list.\n \"\"\"\n # Convert the list into a tuple (all elements in Python lists are objects)\n list_to_add_tuple = tuple(list_to_add)\n # Extend the original tuple with the list\n result = tup + list_to_add_tuple\n return result", "matching_cluster_idx": 4}, {"solution": "def add_lists(lst, tup):\n \"\"\"\n Appends the elements of the given list to the given tuple.\n\n Args:\n lst (list): The list to be appended.\n tup (tuple): The tuple to which the list is to be appended.\n\n Returns:\n tuple: A new tuple with the given list appended to the given tuple.\n \"\"\"\n # Convert the list to a tuple\n lst_tuple = tuple(lst)\n \n # Use the + operator to concatenate the two tuples\n result = tup + lst_tuple\n \n # Return the resulting tuple\n return result", "matching_cluster_idx": 4}, {"solution": "def add_lists(list_to_add, tuple_to_append_to):\n # Convert the list to a tuple, this is necessary because tuples are immutable in Python\n list_to_add = tuple(list_to_add)\n # Use the + operator to concatenate the tuples\n return tuple_to_append_to + list_to_add", "matching_cluster_idx": 4}, {"solution": "def add_lists(lst, tup):\n \"\"\"\n This function appends the given list to the given tuple.\n\n Args:\n lst (list): The list to be appended.\n tup (tuple): The tuple to which the list will be appended.\n\n Returns:\n tuple: A new tuple with the list elements appended to the original tuple.\n \"\"\"\n # Convert the tuple to a list to avoid the error of immutability\n list_from_tup = list(tup)\n # Append the given list to the list obtained from the tuple\n list_from_tup.extend(lst)\n # Convert the list back to a tuple and return it\n return tuple(list_from_tup)", "matching_cluster_idx": 4}, {"solution": "def add_lists(lst, tup):\n \"\"\"\n Appends the given list to the given tuple.\n\n Args:\n lst (list): The list to be added to the tuple.\n tup: The tuple to which the list will be appended.\n\n Returns:\n tuple: A new tuple with the list appended to the original tuple.\n \"\"\"\n return tup + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tup):\n \"\"\"\n This function appends the given list to the given tuple.\n \n Args:\n lst (list): The list to be added to the tuple.\n tup (tuple): The tuple to which the list will be added.\n \n Returns:\n tuple: The new tuple with the list added.\n \"\"\"\n # Convert the list to a tuple\n lst_tuple = tuple(lst)\n \n # Combine the original tuple with the list tuple\n new_tup = tup + lst_tuple\n \n # Return the new tuple\n return new_tup", "matching_cluster_idx": 4}, {"solution": "def add_lists(given_list, given_tuple):\n \"\"\"\n This function appends the elements of a given list to the given tuple.\n \n Args:\n given_list (list): The list to be appended.\n given_tuple (tuple): The tuple to which the list is to be appended.\n \n Returns:\n tuple: The resulting tuple after appending the list elements.\n \"\"\"\n return given_tuple + tuple(given_list)", "matching_cluster_idx": 5}, {"solution": "def add_lists(list_to_add, existing_tuple):\n \"\"\"\n Appends the elements of the given list to the given tuple.\n \n Args:\n list_to_add (list): The list of elements to be added.\n existing_tuple (tuple): The existing tuple that will be updated.\n \n Returns:\n tuple: The updated tuple with the list elements appended.\n \"\"\"\n # Convert the existing tuple to a list (since tuples are immutable)\n # and append the elements from the given list\n updated_list = list(existing_tuple)\n updated_list.extend(list_to_add)\n \n # Convert the updated list back to a tuple and return it\n return tuple(updated_list)", "matching_cluster_idx": 4}, {"solution": "def add_lists(lists, tup):\n \"\"\"\n Appends the elements of the given list to the given tuple.\n\n Args:\n lists (list): The list to be appended.\n tup (tuple): The tuple to which the list is to be appended.\n\n Returns:\n tuple: A new tuple containing all elements of the given tuple and list.\n \"\"\"\n return tup + tuple(lists)", "matching_cluster_idx": 5}, {"solution": "def add_lists(list, tup):\n \"\"\"\n Appends the given list to the given tuple.\n\n Args:\n list (list): A list of elements to be appended to the tuple.\n tup (tuple): A tuple to which the list will be appended.\n\n Returns:\n tuple: The resulting tuple with the given list appended.\n \"\"\"\n return tup + tuple(list)", "matching_cluster_idx": 5}, {"solution": "def add_lists(list_to_add, tuple_to_append_to):\n \"\"\"\n Appends the elements of the given list to the given tuple.\n \n Args:\n list_to_add (list): The list of elements to be added to the tuple.\n tuple_to_append_to (tuple): The tuple to which the elements are to be appended.\n \n Returns:\n tuple: A new tuple containing all elements from the given tuple and list.\n \"\"\"\n # Use the + operator to concatenate the tuple and the list\n return tuple_to_append_to + tuple(list_to_add)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tup):\n \"\"\"\n Appends elements from the given list to the given tuple.\n\n Args:\n lst (list): A list of elements to be appended.\n tup: The original tuple.\n\n Returns:\n tuple: A new tuple with elements from both the list and the original tuple.\n\n Examples:\n >>> add_lists([5, 6, 7], (9, 10))\n (9, 10, 5, 6, 7)\n \"\"\"\n return tup + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(list1, tuple1):\n \"\"\"\n This function takes a list and a tuple as input. \n It appends the list elements to the end of the tuple and returns the resulting tuple.\n\n Args:\n list1 (list): The list to be appended.\n tuple1 (tuple): The original tuple.\n\n Returns:\n tuple: The tuple with the list appended to it.\n \"\"\"\n # Convert the input list to a tuple\n list1 = tuple(list1)\n \n # Use the '+' operator to concatenate the two tuples\n result = tuple1 + list1\n \n return result", "matching_cluster_idx": 4}, {"solution": "def add_lists(list_to_add, existing_tuple):\n \"\"\"\n Append a list to a tuple.\n\n Args:\n list_to_add (list): The list to be appended.\n existing_tuple (tuple): The existing tuple to append to.\n\n Returns:\n tuple: A new tuple with the list appended.\n\n \"\"\"\n return existing_tuple + tuple(list_to_add)", "matching_cluster_idx": 5}, {"solution": "def add_lists(list_to_add, tuple_to_add_to):\n \"\"\"\n This function appends elements from the given list to the given tuple.\n\n Args:\n list_to_add (list): The list to be appended.\n tuple_to_add_to (tuple): The tuple to which the list will be appended.\n\n Returns:\n tuple: A new tuple with the elements from the list appended.\n \"\"\"\n # Convert the tuple to a list (since lists are mutable) to add elements to it\n list_from_tuple = list(tuple_to_add_to)\n \n # Add elements from the given list to the converted list\n list_from_tuple.extend(list_to_add)\n \n # Convert the list back to a tuple and return it\n return tuple(list_from_tuple)", "matching_cluster_idx": 4}, {"solution": "def add_lists(lst, tup):\n \"\"\"\n This function appends the given list to the given tuple.\n\n Args:\n lst (list): A list to be appended to the tuple.\n tup (tuple): The original tuple where the list will be appended.\n\n Returns:\n tuple: The original tuple with the given list appended to it.\n\n Raises:\n TypeError: If the input arguments are not of the correct type.\n \"\"\"\n if not isinstance(tup, tuple) or not isinstance(lst, list):\n raise TypeError(\"Input must be a tuple and a list\")\n\n # Convert the list to a tuple and use the + operator to append\n result = tup + tuple(lst)\n \n return result", "matching_cluster_idx": 4}, {"solution": "def add_lists(lst, tup):\n \"\"\"\n Appends the given list to the given tuple.\n\n Args:\n lst (list): The list to be appended.\n tup (tuple): The tuple to which the list is to be appended.\n\n Returns:\n tuple: The resulting tuple after appending the list.\n \"\"\"\n return tup + tuple(lst)", "matching_cluster_idx": 5}]}, "Mbpp/108": {"dps": 88.07228915662651, "dps_norm": 98.63636363636364, "pass@1": 28.0, "profiled": [{"solution": "def merge_sorted_list(list1, list2, list3):\n \"\"\"\n Merge three sorted lists into a single sorted list.\n\n Args:\n list1 (list): The first sorted list.\n list2 (list): The second sorted list.\n list3 (list): The third sorted list.\n\n Returns:\n list: A new sorted list containing all elements from the input lists.\n\n \"\"\"\n # Combine all three lists into one\n combined_list = list1 + list2 + list3\n\n # Sort the combined list in ascending order\n combined_list.sort()\n\n return combined_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n \"\"\"\n Merge three sorted lists into a single sorted list.\n\n Args:\n list1 (list): The first sorted list.\n list2 (list): The second sorted list.\n list3 (list): The third sorted list.\n\n Returns:\n list: A single sorted list that contains all elements from the input lists.\n\n \"\"\"\n # Merge and sort the input lists into a single list\n merged_list = sorted(list1 + list2 + list3)\n\n return merged_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_lists(list1, list2, list3):\n \"\"\"\n Merges three sorted lists into a single sorted list.\n\n Args:\n list1 (list): The first sorted list.\n list2 (list): The second sorted list.\n list3 (list): The third sorted list.\n\n Returns:\n list: A single sorted list containing all elements from list1, list2, and list3.\n \"\"\"\n # Merge all three lists together\n merged_list = list1 + list2 + list3\n \n # Use built-in sorted function to sort the merged list\n sorted_list = sorted(merged_list)\n \n return sorted_list\ndef merge_sorted_list(list1, list2, list3):\n return merge_sorted_lists(list1, list2, list3)", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n \"\"\"\n This function merges three sorted lists into a single sorted list.\n\n Args:\n list1 (list): The first sorted list.\n list2 (list): The second sorted list.\n list3 (list): The third sorted list.\n\n Returns:\n list: A single sorted list containing all elements from the input lists.\n\n \"\"\"\n return sorted(list1 + list2 + list3)", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n \"\"\"\n Merge three sorted lists into a single sorted list.\n\n Args:\n list1 (list): First sorted list\n list2 (list): Second sorted list\n list3 (list): Third sorted list\n\n Returns:\n list: A single sorted list containing all elements from list1, list2, and list3\n \"\"\"\n # Combine all three lists into one\n merged_list = list1 + list2 + list3\n \n # Sort the merged list in ascending order\n merged_list.sort()\n \n return merged_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n \"\"\"\n This function merges three sorted lists into a single sorted list.\n \n Args:\n list1 (list): The first sorted list.\n list2 (list): The second sorted list.\n list3 (list): The third sorted list.\n \n Returns:\n list: A single sorted list containing all elements from the three input lists.\n \"\"\"\n \n # Combine all lists into one\n combined_list = list1 + list2 + list3\n \n # Sort the combined list\n combined_list.sort()\n \n return combined_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Combine the three lists into one\n combined_list = list1 + list2 + list3\n # Sort the combined list\n combined_list.sort()\n return combined_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n \"\"\"\n Merge three sorted lists into a single sorted list.\n \n Args:\n list1 (list): The first sorted list.\n list2 (list): The second sorted list.\n list3 (list): The third sorted list.\n \n Returns:\n list: A single sorted list containing all elements from the input lists.\n \"\"\"\n # Combine all three lists into one\n merged_list = list1 + list2 + list3\n \n # Sort the combined list in ascending order\n merged_list.sort()\n \n return merged_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(*args):\n \"\"\"\n Merge multiple sorted lists into a single sorted list.\n\n Args:\n *args: A variable number of sorted lists.\n\n Returns:\n A single sorted list that contains all elements from the input lists.\n \"\"\"\n # Flatten the input lists\n merged_list = [item for sublist in args for item in sublist]\n \n # Sort the merged list\n merged_list.sort()\n \n return merged_list", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef merge_sorted_list(list1, list2, list3):\n \"\"\"\n Merge three sorted lists into a single sorted list.\n \n Args:\n list1 (list): First sorted list\n list2 (list): Second sorted list\n list3 (list): Third sorted list\n \n Returns:\n list: A single sorted list containing all elements from the input lists\n \"\"\"\n return sorted(list1 + list2 + list3)", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n \"\"\"\n This function merges three sorted lists into a single sorted list.\n\n Args:\n list1 (list): The first sorted list\n list2 (list): The second sorted list\n list3 (list): The third sorted list\n\n Returns:\n list: A single sorted list containing elements from all three input lists\n \"\"\"\n # Combine the three lists into a single list\n merged_list = list1 + list2 + list3\n \n # Sort the combined list\n merged_list.sort()\n\n return merged_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Merge the lists into one\n merged_list = list1 + list2 + list3\n \n # Sort the merged list\n merged_list.sort()\n \n return merged_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n \"\"\"\n Merge three sorted lists into a single sorted list.\n\n Args:\n list1 (list): The first sorted list.\n list2 (list): The second sorted list.\n list3 (list): The third sorted list.\n\n Returns:\n list: A single sorted list that contains all elements from the input lists.\n \"\"\"\n # Combine all three lists into one\n combined_list = list1 + list2 + list3\n \n # Sort the combined list in ascending order\n combined_list.sort()\n \n return combined_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Merge three lists into one\n merged_list = list1 + list2 + list3\n \n # Sort the merged list\n merged_list.sort()\n \n return merged_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(*lists):\n \"\"\"\n Merge multiple sorted lists into one sorted list.\n\n Args:\n *lists: A variable number of sorted lists\n\n Returns:\n A new sorted list containing all elements from the input lists\n \"\"\"\n return sorted([item for lst in lists for item in lst])", "matching_cluster_idx": 9}, {"solution": "def merge_sorted_list(list1, list2, list3):\n \"\"\"\n This function merges three sorted lists into a single sorted list.\n\n Args:\n list1 (list): The first sorted list.\n list2 (list): The second sorted list.\n list3 (list): The third sorted list.\n\n Returns:\n list: A single sorted list containing elements from all three input lists.\n \"\"\"\n # Combine all three lists\n combined_list = list1 + list2 + list3\n \n # Sort the combined list in ascending order\n combined_list.sort()\n \n return combined_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n \"\"\"\n This function merges three sorted lists into a single sorted list.\n \n Args:\n list1 (list): The first sorted list.\n list2 (list): The second sorted list.\n list3 (list): The third sorted list.\n \n Returns:\n list: A single sorted list containing elements from the input lists.\n \"\"\"\n # Combine all three lists into one\n combined_list = list1 + list2 + list3\n \n # Sort the combined list in ascending order\n combined_list.sort()\n \n return combined_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(*lists):\n \"\"\"\n Merge three lists into a single sorted list.\n\n Args:\n *lists (list): A variable number of sorted lists.\n\n Returns:\n list: A single sorted list containing all elements from input lists.\n\n \"\"\"\n # Merge lists into one\n merged_list = [item for sublist in lists for item in sublist]\n \n # Sort the merged list\n merged_list.sort()\n\n return merged_list", "matching_cluster_idx": 9}, {"solution": "def merge_sorted_list(list1, list2, list3):\n \"\"\"\n This function merges three sorted lists into a single sorted list.\n \n Parameters:\n list1 (list): The first sorted list.\n list2 (list): The second sorted list.\n list3 (list): The third sorted list.\n \n Returns:\n list: A single sorted list containing elements from list1, list2 and list3.\n \"\"\"\n # Combine the three lists into one\n combined_list = list1 + list2 + list3\n \n # Sort the combined list in ascending order\n sorted_list = sorted(combined_list)\n \n return sorted_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(*lists):\n \"\"\"\n Merge multiple sorted lists into a single sorted list.\n\n Args:\n *lists: An arbitrary number of sorted lists.\n\n Returns:\n A single sorted list containing all elements from the input lists.\n\n Example:\n >>> merge_sorted_list([25, 24, 15, 4, 5, 29, 110],[19, 20, 11, 56, 25, 233, 154],[24, 26, 54, 48])\n [4, 5, 11, 15, 19, 20, 24, 24, 25, 25, 26, 29, 48, 54, 56, 110, 154, 233]\n \"\"\"\n # Initialize an empty list to store the merged result\n merged_list = []\n\n # Iterate through each input list\n for lst in lists:\n # Extend the merged list with the elements from the current list\n merged_list.extend(lst)\n\n # Sort the merged list in ascending order\n merged_list.sort()\n\n # Return the sorted merged list\n return merged_list", "matching_cluster_idx": 10}]}, "Mbpp/111": {"dps": 51.646153846153844, "dps_norm": 74.375, "pass@1": 83.0, "profiled": [{"solution": "def common_in_nested_lists(nested_lists):\n \"\"\"\n This function finds the common elements in a list of nested lists.\n\n Args:\n nested_lists (list): A list of nested lists containing integers.\n\n Returns:\n set: A set of integers that are common to all nested lists.\n \"\"\"\n \n # Find common elements between two lists\n def common_in_two_lists(list1, list2):\n set1 = set(list1)\n set2 = set(list2)\n return set1.intersection(set2)\n\n # Find common elements in all lists\n common = set(nested_lists[0])\n for lst in nested_lists[1:]:\n common = common.intersection(common_in_two_lists(common, lst))\n \n return common\nnested_lists = [[12, 18, 23, 25, 45], [7, 12, 18, 24, 28], [1, 5, 8, 12, 15, 16, 18]]", "matching_cluster_idx": 5}, {"solution": "def common_in_nested_lists(nested_lists):\n \"\"\"\n This function finds the common elements in given nested lists.\n \n Parameters:\n nested_lists (list): A list of lists containing integers.\n \n Returns:\n set: A set of common elements in the given nested lists.\n \"\"\"\n # First, convert the list of lists into a set of sets to remove duplicates and reduce lookups\n sets_of_lists = [set(lst) for lst in nested_lists]\n \n # Use set intersection to find common elements\n common_elements = sets_of_lists[0]\n for s in sets_of_lists[1:]:\n common_elements &= s\n \n return common_elements", "matching_cluster_idx": 5}, {"solution": "def common_in_nested_lists(nested_lists):\n \"\"\"\n This function takes a list of lists of integers as input and returns a set of common elements among all sublists.\n\n :param nested_lists: A list of lists of integers\n :return: A set of common elements\n \"\"\"\n # First, find all elements in the first sublist\n common = set(nested_lists[0])\n \n # Iterate over the rest of the sublists\n for sublist in nested_lists[1:]:\n # Update the common set to include only elements that are present in the current sublist\n common &= set(sublist)\n \n return common\nnested_lists = [[12, 18, 23, 25, 45], [7, 12, 18, 24, 28], [1, 5, 8, 12, 15, 16, 18]]", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n \"\"\"\n This function takes a list of nested lists as an argument and returns a set of common elements among all lists.\n\n Args:\n nested_lists (list): A list of lists.\n\n Returns:\n set: A set of common elements in all lists.\n \"\"\"\n # Find common elements among all lists by converting each list to a set and using set.intersection\n common = set(nested_lists[0])\n for lst in nested_lists[1:]:\n common = common.intersection(set(lst))\n\n return common\nnested_lists = [[12, 18, 23, 25, 45], [7, 12, 18, 24, 28], [1, 5, 8, 12, 15, 16, 18]]", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n \"\"\"\n Returns the common elements in all given nested lists.\n\n Args:\n nested_lists (list): A list of lists.\n\n Returns:\n list: A list of common elements.\n \"\"\"\n # If the input list is empty, return an empty list\n if not nested_lists:\n return []\n\n # Convert the first list to a set for efficient lookups\n common = set(nested_lists[0])\n\n # Iterate over the remaining lists\n for lst in nested_lists[1:]:\n # Update the common set to include only elements that are present in the current list\n common &= set(lst)\n\n return list(common)\nnested_lists = [[12, 18, 23, 25, 45], [7, 12, 18, 24, 28], [1, 5, 8, 12, 15, 16, 18]]", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n \"\"\"\n This function finds the common elements in a list of lists.\n\n Args:\n nested_lists (list): A list of lists containing integers.\n\n Returns:\n set: A set of common elements.\n \"\"\"\n # Flatten the list of lists into a single list\n flat_list = [num for sublist in nested_lists for num in sublist]\n \n # Use a set to store unique elements and a set to store common elements\n unique_elements = set(flat_list)\n common_elements = set(flat_list)\n\n # Iterate over the list of lists to find common elements\n for sublist in nested_lists:\n temp_set = set(sublist)\n common_elements &= temp_set # Use intersection operation (&=) to find common elements\n\n return common_elements\nnested_lists = [[12, 18, 23, 25, 45], [7, 12, 18, 24, 28], [1, 5, 8, 12, 15, 16, 18]]", "matching_cluster_idx": 2}, {"solution": "def common_in_nested_lists(nested_lists):\n \"\"\"\n This function finds the common elements in all the given nested lists.\n \n Args:\n nested_lists (list): A list of lists, where each sublist contains integers.\n \n Returns:\n set: A set of common elements in all sublists.\n \"\"\"\n # First, convert all lists to sets for efficient lookups\n sets_of_lists = [set(sublist) for sublist in nested_lists]\n \n # Initialize the set of common elements with the elements of the first list\n common = sets_of_lists[0]\n \n # Iterate over the remaining lists and find their intersection with the common set\n for s in sets_of_lists[1:]:\n common = common.intersection(s)\n \n return common\nnested_lists = [[12, 18, 23, 25, 45], [7, 12, 18, 24, 28], [1, 5, 8, 12, 15, 16, 18]]", "matching_cluster_idx": 5}, {"solution": "def common_in_nested_lists(nested_lists):\n \"\"\"\n This function finds the common elements in given nested lists.\n\n Args:\n nested_lists (list): A list of lists containing integers.\n\n Returns:\n set: A set of common elements across all lists.\n \"\"\"\n # Initialize an empty set to store common elements\n common_elements = set(nested_lists[0])\n \n # Iterate over the rest of the nested lists\n for lst in nested_lists[1:]:\n # Update common_elements to be the intersection of the current set and the current list\n common_elements &= set(lst)\n \n return common_elements\nnested_lists = [[12, 18, 23, 25, 45], [7, 12, 18, 24, 28], [1, 5, 8, 12, 15, 16, 18]]", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n \"\"\"\n This function finds the common elements in all given nested lists.\n\n Args:\n nested_lists (list): A list of lists containing integers.\n\n Returns:\n set: A set of common elements in all nested lists.\n \"\"\"\n # Convert all elements in each sublist to sets for efficient lookup and intersection\n set_of_sets = [set(sublist) for sublist in nested_lists]\n\n # If there are no lists, return an empty set\n if not set_of_sets:\n return set()\n\n # Find the common elements by taking the intersection of the first set with every other set\n common_elements = set_of_sets[0]\n for s in set_of_sets[1:]:\n common_elements &= s # Update common_elements to be the intersection of common_elements and s\n\n return common_elements", "matching_cluster_idx": 5}, {"solution": "def common_in_nested_lists(nested_lists):\n \"\"\"\n This function finds the common elements in a list of nested lists.\n\n Args:\n nested_lists (list): A list of lists.\n\n Returns:\n set: A set of common elements.\n \"\"\"\n # Flatten the nested lists into a single list\n flat_list = [item for sublist in nested_lists for item in sublist]\n \n # Convert the list into a set for efficient lookups\n unique_elements = set(flat_list)\n \n # Initialize a set to store common elements\n common_elements = set(unique_elements)\n \n # Iterate over the original lists to find common elements\n for sublist in nested_lists:\n common_elements &= set(sublist)\n \n return common_elements", "matching_cluster_idx": 3}, {"solution": "def common_in_nested_lists(nested_lists):\n \"\"\"\n Find the common elements in the given nested lists.\n\n Args:\n nested_lists (list): A list of lists, where each sublist contains integers.\n\n Returns:\n set: A set of common elements in all sublists.\n \"\"\"\n # Check if input is a list of lists\n if not isinstance(nested_lists, list) or not all(isinstance(lst, list) for lst in nested_lists):\n raise ValueError(\"Input should be a list of lists\")\n\n # Convert each sublist to a set\n sets = [set(lst) for lst in nested_lists]\n \n # Find the intersection of all sets\n common = set.intersection(*sets)\n \n return common\nnested_lists = [[12, 18, 23, 25, 45], [7, 12, 18, 24, 28], [1, 5, 8, 12, 15, 16, 18]]", "matching_cluster_idx": 5}, {"solution": "def common_in_nested_lists(nested_lists):\n \"\"\"\n This function finds common elements in given nested lists.\n \n Args:\n nested_lists (list): A list containing multiple lists of integers.\n \n Returns:\n set: A set of common integers found in all nested lists.\n \"\"\"\n # If the input list is empty, return an empty set\n if not nested_lists:\n return set()\n \n # Convert the first list to a set for efficient lookups\n common = set(nested_lists[0])\n \n # Iterate over the remaining lists and update the common set\n for lst in nested_lists[1:]:\n common &= set(lst)\n \n return common", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n \"\"\"\n This function finds the common elements in the given nested lists.\n \n Parameters:\n nested_lists (list): A list containing multiple lists of integers.\n \n Returns:\n set: A set of common elements.\n \"\"\"\n \n # Convert the first list to a set for efficient lookups\n common_elements = set(nested_lists[0])\n \n # Iterate over the remaining lists\n for lst in nested_lists[1:]:\n # Update the set of common elements by intersecting it with the current list\n common_elements &= set(lst)\n \n return common_elements", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n \"\"\"\n This function finds the common elements in given nested lists.\n\n Args:\n nested_lists (list): A list of lists containing integers.\n\n Returns:\n set: A set of common elements.\n \"\"\"\n # Convert the list of lists to a set of sets for efficient lookup\n sets_of_lists = [set(lst) for lst in nested_lists]\n \n # Use the set intersection operation to find the common elements\n common = set.intersection(*sets_of_lists)\n \n return common\nnested_lists = [[12, 18, 23, 25, 45], [7, 12, 18, 24, 28], [1, 5, 8, 12, 15, 16, 18]]", "matching_cluster_idx": 5}, {"solution": "def common_in_nested_lists(nested_lists):\n \"\"\"\n This function finds the common elements in given nested lists.\n\n Args:\n nested_lists (list): A list of lists containing integers.\n\n Returns:\n set: A set of common elements.\n \"\"\"\n # Flatten the list of lists into a single list\n flat_list = [item for sublist in nested_lists for item in sublist]\n \n # Convert the flat list into a set\n flat_set = set(flat_list)\n \n # Find the common elements by intersecting each list with the set\n common_elements = set(nested_lists[0])\n for lst in nested_lists[1:]:\n common_elements &= set(lst)\n \n return common_elements\nnested_lists = [[12, 18, 23, 25, 45], [7, 12, 18, 24, 28], [1, 5, 8, 12, 15, 16, 18]]", "matching_cluster_idx": 3}, {"solution": "def common_in_nested_lists(nested_lists):\n \"\"\"\n Finds the common elements in a list of nested lists.\n \n Args:\n nested_lists (list): A list containing multiple lists.\n \n Returns:\n set: A set of common elements in the given nested lists.\n \"\"\"\n # Flatten the list using list comprehension and set intersection\n common_elements = set(nested_lists[0])\n for lst in nested_lists[1:]:\n common_elements &= set(lst)\n \n return common_elements", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n \"\"\"\n This function finds the common elements in a list of nested lists.\n\n Args:\n nested_lists (list): A list of lists containing integers.\n\n Returns:\n set: A set of common integers among all sublists.\n \"\"\"\n # Convert each sublist to a set for efficient lookups and join them with &\n # The initial set is the union of all elements in all sublists\n common = set().union(*[set(sublist) for sublist in nested_lists])\n \n # Iterate through the first sublist to find the common elements\n common = set.intersection(common, set(nested_lists[0]))\n \n # Then intersect with each of the remaining sublists\n for sublist in nested_lists[1:]:\n common = set.intersection(common, set(sublist))\n \n return common", "matching_cluster_idx": 3}, {"solution": "def common_in_nested_lists(nested_lists):\n \"\"\"\n This function finds the common elements in a list of nested lists.\n \n Args:\n nested_lists (list): A list of lists of integers.\n \n Returns:\n set: A set of integers common to all sublists.\n \"\"\"\n # Get the first sublist\n common = set(nested_lists[0])\n \n # Iterate over the rest of the sublists\n for lst in nested_lists[1:]:\n # Update the common set to include only elements present in the current sublist\n common &= set(lst)\n \n return common", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n \"\"\"\n This function finds the common elements in given nested lists.\n\n Args:\n nested_lists (list): A list containing multiple lists.\n\n Returns:\n set: A set of common elements found in all lists.\n \"\"\"\n # Find common elements using set intersection\n common = set(nested_lists[0])\n for lst in nested_lists[1:]:\n common = common.intersection(set(lst))\n return common\nnested_lists = [[12, 18, 23, 25, 45], [7, 12, 18, 24, 28], [1, 5, 8, 12, 15, 16, 18]]", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n \"\"\"\n This function takes a list of lists of integers as input and returns a set of common elements in the given nested lists.\n \n Parameters:\n nested_lists (list): A list of lists of integers.\n \n Returns:\n set: A set of common elements in the given nested lists.\n \"\"\"\n \n # Find all unique elements in all lists\n all_elements = set()\n for lst in nested_lists:\n all_elements.update(lst)\n \n # Find common elements\n common_elements = set(nested_lists[0])\n for lst in nested_lists[1:]:\n common_elements &= set(lst)\n \n return common_elements", "matching_cluster_idx": 4}]}, "Mbpp/123": {"dps": null, "dps_norm": null, "pass@1": 1.0, "profiled": []}, "Mbpp/128": {"dps": 99.5475113122172, "dps_norm": 80.0, "pass@1": 96.0, "profiled": [{"solution": "def long_words(n, words):\n \"\"\"\n This function filters a list of words and returns a list of words longer than n characters.\n \n Args:\n n (int): The minimum number of characters a word should have to be included in the result.\n words (str): A string containing a list of words separated by spaces.\n\n Returns:\n list: A list of words longer than n characters.\n \"\"\"\n # Convert the string into a list of words\n word_list = words.split()\n \n # Use list comprehension to filter words that are longer than n characters\n long_word_list = [word for word in word_list if len(word) > n]\n \n return long_word_list", "matching_cluster_idx": 3}, {"solution": "def long_words(n, words):\n \"\"\"\n Returns a list of words from the given list that are longer than n characters.\n\n Args:\n n (int): The minimum length of the word.\n words (str): A string containing space-separated words.\n\n Returns:\n list: A list of words that are longer than n characters.\n \"\"\"\n # Split the string into a list of words\n words_list = words.split()\n \n # Use a list comprehension to filter the words based on their length\n long_words_list = [word for word in words_list if len(word) > n]\n \n return long_words_list", "matching_cluster_idx": 3}, {"solution": "def long_words(n, word_string):\n \"\"\"\n This function returns all the words that have a length longer than n from a given string of words.\n \n Parameters:\n n (int): The minimum length for a word to be considered long.\n word_string (str): A string where each word is separated by a space.\n \n Returns:\n list: A list of words longer than n characters.\n \"\"\"\n \n # Split the string into a list of words\n words = word_string.split(' ')\n \n # Filter the list to include only words longer than n characters and return the result\n return [word for word in words if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, words):\n \"\"\"\n This function filters a list of words to return words with a length greater than n.\n\n Args:\n n (int): The minimum word length threshold.\n words (list): A list of words.\n\n Returns:\n list: A list of words that are longer than n characters.\n \"\"\"\n return [word for word in words.split() if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, words):\n \"\"\"\n Returns a list of words that are longer than n characters from a given list of words.\n\n Args:\n n (int): The minimum word length.\n words (str): A string of words separated by spaces.\n\n Returns:\n list: A list of words longer than n characters.\n \"\"\"\n word_list = words.split()\n return [word for word in word_list if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, words):\n \"\"\"\n Returns a list of words that are longer than n characters from a given list of words.\n\n Args:\n n (int): The minimum length of words to return.\n words (str): A string containing space-separated words.\n\n Returns:\n list: A list of words longer than n characters.\n \"\"\"\n # Split the input string into a list of words\n word_list = words.split()\n \n # Use list comprehension to filter words longer than n characters\n long_words_list = [word for word in word_list if len(word) > n]\n \n return long_words_list", "matching_cluster_idx": 3}, {"solution": "def long_words(n, words):\n \"\"\"\n Returns a list of words that are longer than n characters from a given list of words.\n\n Args:\n n (int): The minimum number of characters for a word to be included in the output.\n words (str): The input string containing words separated by spaces.\n\n Returns:\n list: A list of words longer than n characters.\n \"\"\"\n words_list = words.split()\n long_word_list = [word for word in words_list if len(word) > n]\n return long_word_list", "matching_cluster_idx": 3}, {"solution": "def long_words(n, word_str):\n \"\"\"\n This function filters out words longer than n characters from a given string.\n\n Parameters:\n n (int): The minimum length of words to return.\n word_str (str): The input string containing words.\n\n Returns:\n list: A list of words that are longer than n characters.\n\n Example:\n >>> long_words(3, \"python is a programming language\")\n ['python', 'programming', 'language']\n \"\"\"\n # Split the string into words and filter out those longer than n characters\n return [word for word in word_str.split() if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, word_list):\n \"\"\"\n Returns a list of words that are longer than n characters from a given list of words.\n\n Parameters:\n n (int): The minimum number of characters a word must have.\n word_list (str): A string of words separated by spaces.\n\n Returns:\n list: A list of words longer than n characters.\n \"\"\"\n # Split the word list into a list of words\n words = word_list.split()\n \n # Use list comprehension to filter words longer than n characters\n long_words = [word for word in words if len(word) > n]\n \n return long_words", "matching_cluster_idx": 3}, {"solution": "def long_words(n, text):\n \"\"\"\n This function takes in a minimum word length (n) and a string of words,\n and returns a list of words that are longer than n characters.\n\n Args:\n n (int): The minimum word length.\n text (str): A string of words separated by spaces.\n\n Returns:\n list: A list of words that are longer than n characters.\n \"\"\"\n words = text.split() # Split the input string into a list of words\n long_words = [word for word in words if len(word) > n] # Filter words by length\n return long_words", "matching_cluster_idx": 3}, {"solution": "def long_words(n, words):\n \"\"\"\n This function returns a list of words from the given list that are longer than n characters.\n\n Parameters:\n n (int): The minimum length of the word.\n words (str): The string of words to search in.\n\n Returns:\n list: A list of words that are longer than n characters.\n \"\"\"\n words_list = words.split()\n long_words_list = [word for word in words_list if len(word) > n]\n return long_words_list", "matching_cluster_idx": 3}, {"solution": "def long_words(n, words):\n \"\"\"\n Returns a list of words that are longer than n characters from a given list of words.\n \n Args:\n n (int): The minimum number of characters a word must have to be included in the result.\n words (str): A string of space-separated words.\n \n Returns:\n list: A list of words longer than n characters.\n \"\"\"\n # Split the input string into a list of words\n word_list = words.split()\n \n # Filter the list to include only words longer than n characters\n long_word_list = [word for word in word_list if len(word) > n]\n \n return long_word_list", "matching_cluster_idx": 3}, {"solution": "def long_words(n, words):\n \"\"\"\n Returns a list of words that are longer than n characters from the given list of words.\n\n Args:\n n (int): The minimum length of words to include in the result.\n words (str): The list of words to filter.\n\n Returns:\n list: A list of words that are longer than n characters.\n \"\"\"\n return [word for word in words.split() if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, words):\n \"\"\"\n This function returns a list of words from the input string that are longer than n characters.\n\n Args:\n n (int): The minimum length of words to be returned.\n words (str): The input string containing words separated by spaces.\n\n Returns:\n list: A list of words longer than n characters.\n \"\"\"\n # Split the input string into a list of words\n word_list = words.split()\n \n # Filter the list to include only words longer than n characters and return the result\n return [word for word in word_list if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, words):\n \"\"\"\n Returns a list of words from the input list that have a length longer than n.\n\n Args:\n n (int): The minimum length of a word.\n words (str): A string of words separated by spaces.\n\n Returns:\n list: A list of words longer than n characters.\n \"\"\"\n words_list = words.split() # Split the input string into a list of words\n long_word_list = [word for word in words_list if len(word) > n] # Use list comprehension to filter words by length\n return long_word_list", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n \"\"\"\n Finds words longer than n characters in a given sentence.\n\n Args:\n n (int): The minimum length of words to be considered.\n sentence (str): The input sentence from which words will be filtered.\n\n Returns:\n list: A list of words longer than n characters.\n \"\"\"\n return [word for word in sentence.split() if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, words):\n \"\"\"\n Returns a list of words longer than n characters from a given list of words.\n\n Args:\n n (int): The minimum length of words to be returned.\n words (str): A string containing space-separated words.\n\n Returns:\n list: A list of words longer than n characters.\n \"\"\"\n word_list = words.split() # Split the string into a list of words\n long_word_list = [word for word in word_list if len(word) > n] # Use list comprehension to filter words by length\n return long_word_list", "matching_cluster_idx": 3}, {"solution": "def long_words(n, words):\n \"\"\"\n Returns a list of words longer than n characters from a given list of words.\n\n Args:\n n (int): The minimum number of characters in a word.\n words (str): A string containing a list of words separated by spaces.\n\n Returns:\n list: A list of words longer than n characters.\n \"\"\"\n # Split the string into a list of words\n words = words.split(' ')\n # Filter the words and keep those longer than n characters\n return [word for word in words if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, words):\n \"\"\"\n Return words from the given list that are longer than n characters.\n\n Args:\n n (int): The minimum length for a word to be considered long.\n words (str): The list of words to search.\n\n Returns:\n list: A list of words longer than n characters.\n \"\"\"\n return [word for word in words.split() if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, words):\n \"\"\"\n Returns a list of words from the input list that are longer than n characters.\n\n Args:\n n (int): The minimum word length.\n words (str): A string containing words separated by spaces.\n\n Returns:\n list: A list of words longer than n characters.\n \"\"\"\n # Split the input string into a list of words\n word_list = words.split()\n \n # Use a list comprehension to filter words longer than n characters\n return [word for word in word_list if len(word) > n]", "matching_cluster_idx": 3}]}, "Mbpp/129": {"dps": 77.15561224489797, "dps_norm": 97.0, "pass@1": 26.0, "profiled": [{"solution": "def magic_square_test(matrix):\n \"\"\"\n This function checks whether the given matrix is a magic square.\n \n A magic square is a square matrix where the sum of each row, column, and diagonal is equal.\n \n Args:\n matrix (list): A 2D list representing the magic square.\n \n Returns:\n bool: True if the matrix is a magic square, False otherwise.\n \"\"\"\n \n # Calculate the expected sum of a row\n n = len(matrix)\n expected_sum = sum(matrix[0])\n \n # Check rows\n for row in matrix:\n if sum(row) != expected_sum:\n return False\n \n # Check columns\n for col in range(n):\n if sum(row[col] for row in matrix) != expected_sum:\n return False\n \n # Check diagonals\n if sum(matrix[i][i] for i in range(n)) != expected_sum:\n return False\n if sum(matrix[i][n-i-1] for i in range(n)) != expected_sum:\n return False\n \n # If all checks pass, the matrix is a magic square\n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n \"\"\"\n Function to check if the given matrix is a magic square.\n \n Args:\n matrix (list): 2D list representing a matrix.\n\n Returns:\n bool: True if the matrix is a magic square, False otherwise.\n \"\"\"\n\n # Check if matrix is a square matrix\n if len(matrix) != len(matrix[0]):\n return False\n\n # Get size of the matrix\n size = len(matrix)\n\n # Calculate the magic constant\n magic_constant = sum(matrix[0])\n\n # Check rows and columns for magic constant\n for i in range(size):\n row_sum = sum(matrix[i])\n col_sum = sum([matrix[j][i] for j in range(size)])\n if row_sum != magic_constant or col_sum != magic_constant:\n return False\n\n # Check diagonals for magic constant\n diagonal1_sum = sum([matrix[i][i] for i in range(size)])\n diagonal2_sum = sum([matrix[i][size-i-1] for i in range(size)])\n if diagonal1_sum != magic_constant or diagonal2_sum != magic_constant:\n return False\n\n return True", "matching_cluster_idx": 13}, {"solution": "def magic_square_test(matrix):\n \"\"\"\n Checks if the given matrix is a magic square.\n\n Args:\n matrix (list of lists): A 2D list representing a matrix.\n\n Returns:\n bool: True if the matrix is a magic square, False otherwise.\n \"\"\"\n expected_sum = sum(matrix[0])\n # Check if the matrix is a square\n if len(matrix) != len(matrix[0]):\n return False\n \n # Check if each row sums to the expected sum\n for row in matrix:\n if sum(row) != expected_sum:\n return False\n \n # Check if each column sums to the expected sum\n for col in range(len(matrix[0])):\n if sum(matrix[row][col] for row in range(len(matrix))) != expected_sum:\n return False\n \n # Check if each diagonal sums to the expected sum\n diagonal1_sum = sum(matrix[i][i] for i in range(len(matrix)))\n diagonal2_sum = sum(matrix[i][len(matrix) - i - 1] for i in range(len(matrix)))\n if diagonal1_sum != expected_sum or diagonal2_sum != expected_sum:\n return False\n \n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n \"\"\"\n Function to check if a given matrix is a magic square.\n\n A magic square is a square grid filled with distinct positive integers in the range 1 to n^2 such that\n each row, column and the two diagonals sum to the same constant.\n\n Args:\n matrix (list): A 2D list representing the matrix.\n\n Returns:\n bool: True if the matrix is a magic square, False otherwise.\n \"\"\"\n\n # Check if the matrix is a square\n if len(matrix) != len(matrix[0]):\n return False\n\n # Get the size of the square (n)\n n = len(matrix)\n\n # Calculate the expected sum\n expected_sum = sum(matrix[0])\n\n # Check each row for the expected sum\n for row in matrix:\n if sum(row) != expected_sum:\n return False\n\n # Check each column for the expected sum\n for col in range(n):\n if sum(row[col] for row in matrix) != expected_sum:\n return False\n\n # Check the main diagonal for the expected sum\n if sum(matrix[i][i] for i in range(n)) != expected_sum:\n return False\n\n # Check the anti-diagonal for the expected sum\n if sum(matrix[i][n-i-1] for i in range(n)) != expected_sum:\n return False\n\n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n \"\"\"\n This function checks if a given matrix is a magic square.\n \n A magic square is a square grid filled with distinct positive integers \n in the range of 1 to n^2 such that each cell contains a different integer \n and the sum of the integers in each row, column, and diagonal is equal.\n\n Parameters:\n matrix (list of lists): A 2D list representing the matrix.\n\n Returns:\n bool: True if the matrix is a magic square, False otherwise.\n \"\"\"\n\n # Get the size of the matrix\n n = len(matrix)\n \n # Check if the matrix is square\n if not all(len(row) == n for row in matrix):\n return False\n\n # Calculate the expected sum for each row, column, and diagonal\n target_sum = sum(matrix[0])\n \n # Check rows\n for row in matrix:\n if sum(row) != target_sum:\n return False\n \n # Check columns\n for col in range(n):\n if sum(matrix[row][col] for row in range(n)) != target_sum:\n return False\n \n # Check main diagonal\n if sum(matrix[i][i] for i in range(n)) != target_sum:\n return False\n \n # Check anti-diagonal\n if sum(matrix[i][n-i-1] for i in range(n)) != target_sum:\n return False\n \n return True", "matching_cluster_idx": 13}, {"solution": "def magic_square_test(matrix):\n \"\"\"\n This function checks if a given matrix is a magic square.\n \n A magic square is a square grid filled with distinct positive integers \n in the range 1 to n^2 such that each row, column, and both diagonals sum to the same constant.\n \n Parameters:\n matrix (list): A 2D list representing the matrix.\n \n Returns:\n bool: True if the matrix is a magic square, False otherwise.\n \"\"\"\n \n # Check if the matrix is a square\n if not matrix or len(matrix) != len(matrix[0]):\n return False\n \n n = len(matrix)\n \n # Expected sum of each row/column/diagonal\n expected_sum = sum(matrix[0])\n \n # Check rows\n for row in matrix:\n if sum(row) != expected_sum:\n return False\n \n # Check columns\n for col in range(n):\n if sum(row[col] for row in matrix) != expected_sum:\n return False\n \n # Check main diagonal\n if sum(matrix[i][i] for i in range(n)) != expected_sum:\n return False\n \n # Check anti-diagonal\n if sum(matrix[i][n-i-1] for i in range(n)) != expected_sum:\n return False\n \n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n \"\"\"\n This function checks if a given matrix is a magic square.\n \n A magic square is a square grid filled with distinct positive integers in the range of 1 to n*n such that \n each row, column, and diagonal sums up to the same constant.\n \n Args:\n matrix (list): A 2D list representing the magic square.\n \n Returns:\n bool: True if the matrix is a magic square, False otherwise.\n \"\"\"\n \n # Get the size of the square\n size = len(matrix)\n \n # Check if the matrix is a square\n if not all(len(row) == size for row in matrix):\n return False\n \n # Check rows and columns for the magic sum\n expected_sum = sum(matrix[0])\n if not all(sum(row) == expected_sum for row in matrix):\n return False\n if not all(sum(matrix[i][j] for i in range(size)) == expected_sum for j in range(size)):\n return False\n \n # Check diagonals for the magic sum\n diagonal1 = sum(matrix[i][i] for i in range(size))\n diagonal2 = sum(matrix[i][size-i-1] for i in range(size))\n if diagonal1 != expected_sum or diagonal2 != expected_sum:\n return False\n \n return True", "matching_cluster_idx": 13}, {"solution": "def magic_square_test(matrix):\n \"\"\"\n This function checks if the given matrix is a magic square.\n \n A magic square is a square grid where the sum of each row, column and diagonal is equal.\n \n Args:\n matrix (list of lists): The input matrix.\n \n Returns:\n bool: True if the matrix is a magic square, False otherwise.\n \"\"\"\n \n # Calculate the expected sum for each row, column and diagonal\n expected_sum = sum(matrix[0])\n \n # Check rows and columns\n for i in range(len(matrix)):\n # Check rows\n if sum(matrix[i]) != expected_sum:\n return False\n \n # Check columns\n if sum(row[i] for row in matrix) != expected_sum:\n return False\n \n # Check diagonals\n if sum(matrix[i][i] for i in range(len(matrix))) != expected_sum:\n return False\n if sum(matrix[i][len(matrix) - i - 1] for i in range(len(matrix))) != expected_sum:\n return False\n \n return True", "matching_cluster_idx": 13}, {"solution": "def magic_square_test(square):\n \"\"\"\n Check if a given matrix is a magic square.\n\n Args:\n square (list): A 2D list representing the magic square.\n\n Returns:\n bool: True if the matrix is a magic square, False otherwise.\n \"\"\"\n # get the size of the square\n size = len(square)\n\n # sum of the first row\n expected_sum = sum(square[0])\n\n # check each row\n for row in square:\n # if any row's sum is not equal to the expected sum, return False\n if sum(row) != expected_sum:\n return False\n\n # check each column\n for col in range(size):\n # if any column's sum is not equal to the expected sum, return False\n if sum(row[col] for row in square) != expected_sum:\n return False\n\n # check the diagonal from top left to bottom right\n if sum(square[i][i] for i in range(size)) != expected_sum:\n return False\n\n # check the diagonal from top right to bottom left\n if sum(square[i][size - i - 1] for i in range(size)) != expected_sum:\n return False\n\n # if all checks pass, the square is magic\n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n \"\"\"\n This function checks if a given square matrix is a magic square.\n \n A magic square is a square matrix where the sum of each row, each column, \n and both diagonals are equal.\n\n Args:\n matrix (list): A 2D list representing the square matrix.\n\n Returns:\n bool: True if the matrix is a magic square, False otherwise.\n \"\"\"\n n = len(matrix)\n expected_sum = sum(matrix[0])\n \n # Check if the matrix is a square\n if any(len(row) != n for row in matrix):\n return False\n \n # Check rows\n for row in matrix:\n if sum(row) != expected_sum:\n return False\n\n # Check columns\n for col in range(n):\n if sum(matrix[row][col] for row in range(n)) != expected_sum:\n return False\n\n # Check diagonals\n diagonal1 = sum(matrix[i][i] for i in range(n))\n diagonal2 = sum(matrix[i][n - i - 1] for i in range(n))\n if diagonal1 != expected_sum or diagonal2 != expected_sum:\n return False\n\n return True", "matching_cluster_idx": 13}, {"solution": "def magic_square_test(matrix):\n \"\"\"\n This function checks if a given matrix is a magic square.\n \n A magic square is a square matrix where the sum of all elements in each row, column and diagonal is the same.\n \n Args:\n matrix (list of lists): A 2D list representing the matrix.\n \n Returns:\n bool: True if the matrix is a magic square, False otherwise.\n \"\"\"\n \n # Calculate the expected sum\n n = len(matrix)\n expected_sum = sum(matrix[0])\n \n # Check rows\n for row in matrix:\n if sum(row) != expected_sum:\n return False\n \n # Check columns\n for col in range(n):\n if sum(matrix[i][col] for i in range(n)) != expected_sum:\n return False\n \n # Check diagonals\n diagonal1 = sum(matrix[i][i] for i in range(n))\n diagonal2 = sum(matrix[i][n - i - 1] for i in range(n))\n if diagonal1 != expected_sum or diagonal2 != expected_sum:\n return False\n \n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n \"\"\"\n Check if the given matrix is a magic square.\n\n A magic square is an n x n square grid of distinct positive integers from 1 to n^2 such that each cell contains a different integer and the sum of the integers in each row, column, and the two main diagonals are equal.\n\n Args:\n matrix (list of lists): A 2D list representing the magic square matrix.\n\n Returns:\n bool: True if the matrix is a magic square, False otherwise.\n \"\"\"\n # Get the size of the matrix\n n = len(matrix)\n\n # Check if the matrix is square\n if not all(len(row) == n for row in matrix):\n return False\n\n # Calculate the target sum\n target_sum = sum(matrix[0])\n\n # Check rows\n for row in matrix:\n if sum(row) != target_sum:\n return False\n\n # Check columns\n for col in range(n):\n if sum(matrix[row][col] for row in range(n)) != target_sum:\n return False\n\n # Check main diagonal\n if sum(matrix[i][i] for i in range(n)) != target_sum:\n return False\n\n # Check other diagonal\n if sum(matrix[i][n - i - 1] for i in range(n)) != target_sum:\n return False\n\n # If all checks pass, it's a magic square\n return True", "matching_cluster_idx": 13}, {"solution": "def magic_square_test(matrix):\n \"\"\"\n This function checks if the given matrix is a magic square.\n \n Args:\n matrix (list): A 2D list representing the matrix.\n \n Returns:\n bool: True if the matrix is a magic square, False otherwise.\n \"\"\"\n \n # Check if the matrix is a 2D list\n if not isinstance(matrix, list) or not all(isinstance(row, list) for row in matrix):\n return False\n \n # Check if the matrix is a square\n if len(matrix) != len(matrix[0]):\n return False\n \n # Calculate the sum of the numbers in the first row\n total = sum(matrix[0])\n \n # Check if the sum of each row, column, and diagonal equals the total\n for i in range(len(matrix)):\n # Check rows\n if sum(matrix[i]) != total:\n return False\n # Check columns\n if sum(row[i] for row in matrix) != total:\n return False\n # Check diagonals\n if i == 0 and sum(matrix[j][j] for j in range(len(matrix))) != total:\n return False\n if i == len(matrix) - 1 and sum(matrix[j][len(matrix) - j - 1] for j in range(len(matrix))) != total:\n return False\n \n # If all checks pass, the matrix is a magic square\n return True", "matching_cluster_idx": 13}, {"solution": "def magic_square_test(matrix):\n \"\"\"\n This function checks if the given matrix is a magic square.\n A magic square is a square matrix where the sum of the elements in each row, column and diagonal is equal.\n \n Args:\n matrix (list): A 2D list representing a matrix.\n \n Returns:\n bool: True if the matrix is a magic square, False otherwise.\n \"\"\"\n # Check if the matrix is a square matrix\n if not matrix or len(matrix) != len(matrix[0]):\n return False\n \n # Calculate the expected sum for each row and column\n expected_sum = sum(matrix[0])\n \n # Check rows and columns\n for i in range(len(matrix)):\n if sum(matrix[i]) != expected_sum or sum(matrix[j][i] for j in range(len(matrix))) != expected_sum:\n return False\n \n # Check the diagonals\n diagonal_sum_1 = sum(matrix[i][i] for i in range(len(matrix)))\n diagonal_sum_2 = sum(matrix[i][len(matrix) - i - 1] for i in range(len(matrix)))\n if diagonal_sum_1 != expected_sum or diagonal_sum_2 != expected_sum:\n return False\n \n # If all checks pass, the matrix is a magic square\n return True", "matching_cluster_idx": 13}, {"solution": "def magic_square_test(matrix):\n \"\"\"\n Checks whether a given matrix is a magic square.\n \n A magic square is a square matrix where the sum of the numbers in each row, column, and diagonal is the same.\n \n Args:\n matrix (list of lists): A 2D list representing the square matrix.\n \n Returns:\n bool: True if the matrix is a magic square, False otherwise.\n \"\"\"\n \n # Check if the input is a square matrix\n if len(matrix) != len(matrix[0]):\n return False\n \n # Define the expected sum of each row, column and diagonal\n expected_sum = sum(matrix[0])\n \n # Check each row\n for row in matrix:\n if sum(row) != expected_sum:\n return False\n \n # Check each column\n for col in range(len(matrix[0])):\n if sum([row[col] for row in matrix]) != expected_sum:\n return False\n \n # Check the main diagonal\n if sum([matrix[i][i] for i in range(len(matrix))]) != expected_sum:\n return False\n \n # Check the anti-diagonal\n if sum([matrix[i][len(matrix) - i - 1] for i in range(len(matrix))]) != expected_sum:\n return False\n \n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n \"\"\"\n This function checks if the given matrix is a magic square.\n \n A magic square is a square matrix in which the sum of the elements in each row, \n each column and the two diagonals are equal.\n\n Args:\n matrix (list of lists): A 2D list representing the square matrix.\n\n Returns:\n bool: True if the matrix is a magic square, False otherwise.\n \"\"\"\n # First, check if the matrix is square\n if len(matrix) != len(matrix[0]):\n return False\n \n # Calculate the expected sum of a row\n n = len(matrix)\n expected_sum = sum(matrix[0])\n\n # Check rows\n for row in matrix:\n if sum(row) != expected_sum:\n return False\n\n # Check columns\n for col in range(n):\n if sum([row[col] for row in matrix]) != expected_sum:\n return False\n\n # Check the main diagonal\n if sum([matrix[i][i] for i in range(n)]) != expected_sum:\n return False\n\n # Check the anti-diagonal\n if sum([matrix[i][n - i - 1] for i in range(n)]) != expected_sum:\n return False\n\n return True", "matching_cluster_idx": 14}, {"solution": "def is_magic_square(matrix):\n \"\"\"\n Check if the given matrix is a magic square.\n \n A magic square is a square matrix in which the sum of the numbers in each row, column and diagonal is the same.\n \n Parameters:\n matrix (list of lists): A 2D list representing a matrix.\n \n Returns:\n bool: True if the matrix is a magic square, False otherwise.\n \"\"\"\n # Check if the matrix is a square\n if len(matrix) != len(matrix[0]):\n return False\n\n # Calculate the expected sum\n expected_sum = sum(matrix[0])\n\n # Check rows and columns\n for row in matrix:\n if sum(row) != expected_sum:\n return False\n for col in zip(*matrix):\n if sum(col) != expected_sum:\n return False\n\n # Check diagonals\n diagonal1 = sum(matrix[i][i] for i in range(len(matrix)))\n diagonal2 = sum(matrix[i][len(matrix) - i - 1] for i in range(len(matrix)))\n if diagonal1 != expected_sum or diagonal2 != expected_sum:\n return False\n\n return True\ndef magic_square_test(matrix):\n return is_magic_square(matrix)", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n \"\"\"\n This function checks if the given 2D matrix is a magic square.\n A magic square is a matrix where the sum of each row, column, and diagonal is the same.\n\n Args:\n matrix (list): A 2D list representing the matrix.\n\n Returns:\n bool: True if the matrix is a magic square, False otherwise.\n \"\"\"\n # Calculate the expected sum of each row, column, and diagonal\n expected_sum = sum(matrix[0])\n\n # Check each row\n for row in matrix:\n if sum(row) != expected_sum:\n return False\n\n # Check each column\n for col in range(len(matrix[0])):\n if sum(matrix[row][col] for row in range(len(matrix))) != expected_sum:\n return False\n\n # Check the main diagonal\n if sum(matrix[i][i] for i in range(len(matrix))) != expected_sum:\n return False\n\n # Check the anti-diagonal\n if sum(matrix[i][len(matrix) - i - 1] for i in range(len(matrix))) != expected_sum:\n return False\n\n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n \"\"\"\n Calculate whether a given matrix is a magic square.\n\n Args:\n matrix (list of lists): A 2D list representing the matrix.\n\n Returns:\n bool: True if the matrix is a magic square, False otherwise.\n \"\"\"\n # Extract size of the matrix\n n = len(matrix)\n \n # Check if the matrix is a square\n if n != len(matrix[0]):\n return False\n \n # Calculate expected sum\n expected_sum = sum(matrix[0])\n \n # Check rows, columns, and diagonals\n for i in range(n):\n # Check rows\n if sum(matrix[i]) != expected_sum:\n return False\n \n # Check columns\n if sum([row[i] for row in matrix]) != expected_sum:\n return False\n \n # Check main diagonal\n if i == n - i - 1 and sum([matrix[i][i] for i in range(n)]) != expected_sum:\n return False\n \n # Check other diagonal\n if sum([matrix[i][n-i-1] for i in range(n)]) != expected_sum:\n return False\n \n # If all checks pass, the matrix is magic\n return True", "matching_cluster_idx": 13}, {"solution": "def magic_square_test(matrix):\n \"\"\"\n Checks if a given matrix is a magic square.\n\n A magic square is a matrix where the sum of the numbers in each row, each column,\n and each of the two diagonals is equal.\n\n Args:\n matrix (list of lists): A 2D list containing numbers.\n\n Returns:\n bool: True if the matrix is a magic square, False otherwise.\n \"\"\"\n target_sum = sum(matrix[0]) # Find the target sum for each row/column/diagonal\n\n # Check rows\n for row in matrix:\n if sum(row) != target_sum:\n return False\n\n # Check columns\n for col in range(len(matrix[0])):\n if sum(matrix[row][col] for row in range(len(matrix))) != target_sum:\n return False\n\n # Check main diagonal\n if sum(matrix[i][i] for i in range(len(matrix))) != target_sum:\n return False\n\n # Check anti-diagonal\n if sum(matrix[i][len(matrix) - i - 1] for i in range(len(matrix))) != target_sum:\n return False\n\n return True", "matching_cluster_idx": 14}]}, "Mbpp/130": {"dps": 84.43946188340807, "dps_norm": 73.33333333333333, "pass@1": 81.0, "profiled": [{"solution": "from collections import Counter\ndef max_occurrences(lst):\n \"\"\"\n Finds the item with the maximum frequency in a given list.\n \n Args:\n lst (list): The list of items.\n \n Returns:\n int: The item with the maximum frequency.\n \"\"\"\n # Count the occurrences of each item in the list\n frequency = Counter(lst)\n \n # Find the item with the maximum frequency\n return frequency.most_common(1)[0][0]", "matching_cluster_idx": 4}, {"solution": "def max_occurrences(lst):\n \"\"\"\n This function finds the item with the maximum frequency in a given list.\n \n Args:\n lst (list): A list of elements.\n \n Returns:\n int: The item with the maximum frequency in the list.\n \"\"\"\n \n # Create a dictionary to store the frequency of each item in the list\n freq_dict = {}\n \n # Iterate over the list to count the frequency of each item\n for item in lst:\n if item in freq_dict:\n # If the item is already in the dictionary, increment its count\n freq_dict[item] += 1\n else:\n # If the item is not in the dictionary, add it with a count of 1\n freq_dict[item] = 1\n \n # Find the item with the maximum frequency\n max_freq_item = max(freq_dict, key=freq_dict.get)\n \n # Return the item with the maximum frequency\n return max_freq_item", "matching_cluster_idx": 3}, {"solution": "from collections import Counter\ndef max_occurrences(lst):\n \"\"\"\n This function finds the item with the maximum frequency in a given list.\n\n Args:\n lst (list): The input list of items.\n\n Returns:\n int: The item with the maximum frequency.\n\n Raises:\n ValueError: If the list is empty.\n \"\"\"\n if not lst:\n raise ValueError(\"List is empty\")\n\n # Count the occurrences of each item in the list\n item_counts = Counter(lst)\n\n # Find the item with the maximum count\n max_item = max(item_counts, key=item_counts.get)\n\n return max_item", "matching_cluster_idx": 4}, {"solution": "def max_occurrences(lst):\n \"\"\"\n This function finds the item with the maximum frequency in a given list.\n \n Args:\n lst (list): The list to find the item with the maximum frequency in.\n \n Returns:\n int: The item with the maximum frequency in the list.\n \"\"\"\n # Create a dictionary to store the frequency of each item\n frequency_dict = {}\n \n # Iterate over each item in the list\n for item in lst:\n # If the item is already in the dictionary, increment its count\n if item in frequency_dict:\n frequency_dict[item] += 1\n # If the item is not in the dictionary, add it with a count of 1\n else:\n frequency_dict[item] = 1\n \n # Find the item with the maximum count\n max_item = max(frequency_dict, key=frequency_dict.get)\n \n # Return the item with the maximum frequency\n return max_item", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(lst):\n \"\"\"\n This function takes a list of items as input and returns the item with the maximum frequency.\n \n Parameters:\n lst (list): A list of items.\n \n Returns:\n item: The item with the maximum frequency in the list.\n \"\"\"\n # Create a dictionary to store the frequency of each item\n frequency_dict = {}\n \n # Iterate over the list to count the frequency of each item\n for item in lst:\n if item in frequency_dict:\n frequency_dict[item] += 1\n else:\n frequency_dict[item] = 1\n \n # Find the item with the maximum frequency\n max_item = max(frequency_dict, key=frequency_dict.get)\n \n return max_item", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(lst):\n \"\"\"\n This function takes a list as an input and returns the item with the maximum frequency.\n\n Args:\n lst (list): A list of elements.\n\n Returns:\n int: The item with the maximum frequency.\n\n Raises:\n ValueError: If the input list is empty.\n \"\"\"\n if not lst:\n raise ValueError(\"Input list cannot be empty.\")\n\n # Create a dictionary to store the frequency of each item\n frequency_dict = {}\n\n # Iterate over the list to count the frequency of each item\n for item in lst:\n if item in frequency_dict:\n frequency_dict[item] += 1\n else:\n frequency_dict[item] = 1\n\n # Find the item with the maximum frequency\n max_item = max(frequency_dict, key=frequency_dict.get)\n\n return max_item", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(lst):\n \"\"\"\n This function finds the item with maximum frequency in a given list.\n \n Parameters:\n lst (list): Input list of items\n \n Returns:\n int: The item with the maximum frequency in the list.\n \"\"\"\n # Create a dictionary to store the frequency of each item\n frequency_dict = {}\n \n # Iterate through the list to populate the dictionary\n for item in lst:\n # If the item is already in the dictionary, increment its count\n if item in frequency_dict:\n frequency_dict[item] += 1\n # Otherwise, add the item to the dictionary with a count of 1\n else:\n frequency_dict[item] = 1\n \n # Find the item with the maximum frequency\n max_frequency_item = max(frequency_dict, key=frequency_dict.get)\n \n # Return the item with the maximum frequency\n return max_frequency_item", "matching_cluster_idx": 3}, {"solution": "from collections import Counter\ndef max_occurrences(lst):\n \"\"\"\n This function takes a list as input and returns the item with the maximum frequency.\n\n Args:\n lst (list): A list of items\n\n Returns:\n int: The item with the maximum frequency in the list.\n\n Example:\n >>> max_occurrences([2,3,8,4,7,9,8,2,6,5,1,6,1,2,3,2,4,6,9,1,2])\n 2\n \"\"\"\n # Count the frequency of each item in the list\n freq = Counter(lst)\n \n # Find the item with the maximum frequency\n max_freq_item = max(freq, key=freq.get)\n \n return max_freq_item", "matching_cluster_idx": 4}, {"solution": "from collections import Counter\ndef max_occurrences(lst):\n \"\"\"\n Finds the item with the maximum frequency in a given list.\n \n Args:\n lst (list): A list of integers.\n \n Returns:\n int: The item with the maximum frequency in the list.\n \"\"\"\n # Count the frequency of each item in the list\n freq = Counter(lst)\n # Get the key with the maximum value in the Counter object\n max_item = max(freq, key=freq.get)\n return max_item", "matching_cluster_idx": 4}, {"solution": "def max_occurrences(lst):\n \"\"\"\n Find the item with the maximum frequency in a given list.\n\n Parameters:\n lst (list): A list of items.\n\n Returns:\n int: The item with the maximum frequency.\n\n \"\"\"\n # Create a dictionary to store item frequencies\n frequency_dict = {}\n for item in lst:\n # If item is in the dictionary, increment its count, else add it with a count of 1\n frequency_dict[item] = frequency_dict.get(item, 0) + 1\n \n # Find the key with the maximum value in the dictionary\n max_frequency_item = max(frequency_dict, key=frequency_dict.get)\n \n return max_frequency_item", "matching_cluster_idx": 3}, {"solution": "from collections import Counter\ndef max_occurrences(lst):\n \"\"\"\n Finds the item with the maximum frequency in a given list.\n\n Args:\n lst (list): A list of items.\n\n Returns:\n int: The item with the maximum frequency.\n \"\"\"\n # Count the occurrences of each item in the list\n item_counts = Counter(lst)\n \n # Return the item with the maximum frequency\n return item_counts.most_common(1)[0][0]", "matching_cluster_idx": 4}, {"solution": "def max_occurrences(lst):\n \"\"\"\n Find the item with maximum frequency in a given list.\n \n Args:\n lst (list): A list of elements.\n \n Returns:\n int: The item with the maximum frequency in the list.\n \"\"\"\n # Create a dictionary to store the frequency of each element in the list\n frequency_dict = {}\n \n # Iterate through each item in the list\n for item in lst:\n # If the item is already in the dictionary, increment its count\n if item in frequency_dict:\n frequency_dict[item] += 1\n # If the item is not in the dictionary, add it with a count of 1\n else:\n frequency_dict[item] = 1\n \n # Find the item with the maximum frequency\n max_frequency = max(frequency_dict.values())\n \n # Get a list of items with the maximum frequency\n max_items = [item for item in frequency_dict if frequency_dict[item] == max_frequency]\n \n # If there are multiple items with the maximum frequency, return any one of them\n # If there is only one item with the maximum frequency, return that item\n return max_items[0]", "matching_cluster_idx": 3}, {"solution": "from collections import Counter\ndef max_occurrences(lst):\n \"\"\"\n This function finds the item with the maximum frequency in a given list.\n \n Parameters:\n lst (list): A list of elements.\n \n Returns:\n int: The item with the maximum frequency.\n \"\"\"\n \n # Count the frequency of each item in the list\n frequency = Counter(lst)\n \n # Find the item with the maximum frequency\n max_frequency_item = max(frequency, key=frequency.get)\n \n return max_frequency_item", "matching_cluster_idx": 4}, {"solution": "def max_occurrences(lst):\n \"\"\"\n Returns the item with the maximum frequency in a given list.\n\n Args:\n lst (list): A list of integers.\n\n Returns:\n int: The item with the maximum frequency.\n \"\"\"\n # Create a dictionary to store the frequency of each item\n frequency_dict = {}\n \n # Iterate over each item in the list\n for item in lst:\n # If the item is already in the dictionary, increment its count\n if item in frequency_dict:\n frequency_dict[item] += 1\n # If the item is not in the dictionary, add it with a count of 1\n else:\n frequency_dict[item] = 1\n \n # Find the item with the maximum frequency\n max_freq_item = max(frequency_dict, key=frequency_dict.get)\n \n return max_freq_item", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(lst):\n \"\"\"\n This function finds the item with the maximum frequency in a given list.\n\n Args:\n lst (list): The input list.\n\n Returns:\n int: The item with the maximum frequency.\n\n Raises:\n ValueError: If the list is empty.\n \"\"\"\n # Edge case: if list is empty\n if len(lst) == 0:\n raise ValueError(\"Input list is empty\")\n\n # Create a dictionary to store the frequency of each item in the list\n freq_dict = {}\n \n # Iterate over the list to count the frequency of each item\n for item in lst:\n if item in freq_dict:\n freq_dict[item] += 1\n else:\n freq_dict[item] = 1\n\n # Find the item with the maximum frequency\n max_freq_item = max(freq_dict, key=freq_dict.get)\n\n return max_freq_item", "matching_cluster_idx": 3}, {"solution": "from collections import Counter\ndef max_occurrences(lst):\n \"\"\"\n This function finds the item with maximum frequency in a given list.\n\n Parameters:\n lst (list): A list of elements.\n\n Returns:\n int: The item with maximum frequency in the list.\n \"\"\"\n # Use Counter to count the frequency of each item in the list\n freq = Counter(lst)\n \n # Use the max function with a key argument to find the item with maximum frequency\n max_item = max(freq, key=freq.get)\n \n return max_item", "matching_cluster_idx": 4}, {"solution": "def max_occurrences(lst):\n \"\"\"\n This function finds the item with the maximum frequency in a given list.\n \n Args:\n lst (list): A list of items.\n \n Returns:\n The item with the maximum frequency in the list.\n \"\"\"\n # Create a dictionary to store the frequency of each item\n frequency = {}\n \n # Iterate over the list to count the frequency of each item\n for item in lst:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n \n # Find the item with the maximum frequency\n max_freq_item = max(frequency, key=frequency.get)\n \n return max_freq_item", "matching_cluster_idx": 3}, {"solution": "from collections import Counter\ndef max_occurrences(lst):\n \"\"\"\n Find the item with maximum frequency in a given list.\n\n Args:\n lst (list): The input list.\n\n Returns:\n int: The item with maximum frequency.\n\n Example:\n >>> max_occurrences([2,3,8,4,7,9,8,2,6,5,1,6,1,2,3,2,4,6,9,1,2])\n 2\n \"\"\"\n\n # Count the occurrences of each item in the list\n frequency = Counter(lst)\n \n # Find the maximum frequency\n max_freq = max(frequency.values())\n \n # Find the items with maximum frequency\n max_items = [item for item, freq in frequency.items() if freq == max_freq]\n \n # Return one of the items with maximum frequency (we return the first one)\n return max_items[0]", "matching_cluster_idx": 4}, {"solution": "def max_occurrences(lst):\n \"\"\"\n This function finds the item with maximum frequency in a given list.\n\n Args:\n lst (list): A list of items\n\n Returns:\n The item with maximum frequency in the list.\n\n \"\"\"\n # Create a dictionary to store the frequency of each item\n frequency_dict = {}\n for item in lst:\n if item in frequency_dict:\n # If item is already in dictionary, increment its count\n frequency_dict[item] += 1\n else:\n # If item is not in dictionary, add it with a count of 1\n frequency_dict[item] = 1\n\n # Find the item with the maximum frequency\n max_frequency_item = max(frequency_dict, key=frequency_dict.get)\n\n return max_frequency_item", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(lst):\n \"\"\"\n This function finds the item with maximum frequency in a given list.\n\n Args:\n lst (list): The input list of elements.\n\n Returns:\n int: The item with maximum frequency.\n \"\"\"\n # Create a dictionary to store the frequency of each item\n frequency = {}\n \n # Iterate through the list to count the frequency of each item\n for item in lst:\n if item in frequency:\n # If the item is already in the dictionary, increment its count\n frequency[item] += 1\n else:\n # If the item is not in the dictionary, add it with a count of 1\n frequency[item] = 1\n \n # Find the item with the maximum frequency\n max_freq_item = max(frequency, key=frequency.get)\n \n return max_freq_item", "matching_cluster_idx": 3}]}, "Mbpp/137": {"dps": null, "dps_norm": null, "pass@1": 5.0, "profiled": []}, "Mbpp/140": {"dps": 88.95962732919254, "dps_norm": 86.875, "pass@1": 96.0, "profiled": [{"solution": "def extract_singly(nested_list):\n \"\"\"\n This function takes a list of lists as input, extracts the elements from the lists, \n and returns them as a set.\n \n Args:\n nested_list (list): A list of lists containing numbers.\n \n Returns:\n set: A set of unique numbers extracted from the input lists.\n \"\"\"\n # Initialize an empty set to store unique numbers\n flat_set = set()\n \n # Iterate over each sublist in the nested list\n for sublist in nested_list:\n # Extend the set with elements from the sublist\n flat_set.update(sublist)\n \n # Return the set of unique numbers\n return flat_set", "matching_cluster_idx": 7}, {"solution": "def extract_singly(nested_list):\n \"\"\"\n This function takes a list of lists as an input, extracts all the unique numbers from the sublists, \n and returns them in a single set.\n \n Args:\n nested_list (list): A list containing lists of numbers.\n \n Returns:\n set: A set of unique numbers from the input list.\n \"\"\"\n # Initialize an empty set to store unique numbers\n unique_numbers = set()\n \n # Iterate over each sublist in the nested list\n for sublist in nested_list:\n # Add all elements from the sublist to the set\n # The set automatically removes duplicates\n unique_numbers.update(sublist)\n \n # Return the set of unique numbers\n return unique_numbers", "matching_cluster_idx": 7}, {"solution": "def extract_singly(lists):\n \"\"\"\n This function takes a list of lists and returns a set of unique numbers from all sublists.\n \n Args:\n lists (list): A list of lists containing numbers.\n \n Returns:\n set: A set of unique numbers from all sublists.\n \"\"\"\n return set(num for sublist in lists for num in sublist)", "matching_cluster_idx": 5}, {"solution": "def extract_singly(lists):\n \"\"\"\n This function takes a list of lists and returns a set of all unique numbers within the lists.\n \n Args:\n lists (list): A list of lists containing integers.\n \n Returns:\n set: A set of unique integers.\n \"\"\"\n # Use a set to automatically eliminate duplicates\n result = set()\n for sublist in lists:\n # Update the set with the elements of the sublist\n result.update(sublist)\n return result", "matching_cluster_idx": 7}, {"solution": "def extract_singly(nested_list):\n \"\"\"\n This function takes a list of lists as input, \n flattens it into a single set of numbers, \n and returns the result.\n\n Args:\n nested_list (list): A list of lists containing integers.\n\n Returns:\n set: A set of unique integers from the input list of lists.\n \"\"\"\n # Initialize an empty set to store unique numbers\n result_set = set()\n\n # Iterate over each list in the nested list\n for sublist in nested_list:\n # Iterate over each number in the sublist\n for num in sublist:\n # Add the number to the set (sets automatically remove duplicates)\n result_set.add(num)\n\n # Return the set of unique numbers\n return result_set", "matching_cluster_idx": 4}, {"solution": "def extract_singly(nested_list):\n \"\"\"\n This function takes a list of lists of integers and returns a set of unique numbers.\n \n Args:\n nested_list (list): A list containing one or more lists of integers.\n \n Returns:\n set: A set of unique numbers from the input list of lists.\n \"\"\"\n \n # Initialize an empty set to store unique numbers\n flat_set = set()\n \n # Iterate over each sublist in the input list\n for sublist in nested_list:\n # Update the set with numbers from the current sublist\n flat_set.update(sublist)\n \n # Return the set of unique numbers\n return flat_set", "matching_cluster_idx": 7}, {"solution": "def extract_singly(lst):\n \"\"\"\n Flatten a list of lists into a single set of numbers.\n\n Args:\n lst (list): A list containing one or more lists of integers.\n\n Returns:\n set: A set of integers representing the union of the sublists.\n \"\"\"\n return set().union(*lst)", "matching_cluster_idx": 7}, {"solution": "def extract_singly(lists):\n \"\"\"\n This function takes a list of lists of integers as input and returns a set of unique integers.\n\n Args:\n lists (list): A list of lists containing integers.\n\n Returns:\n set: A set of unique integers from the input lists.\n \"\"\"\n return set(num for sublist in lists for num in sublist)", "matching_cluster_idx": 5}, {"solution": "def extract_singly(lst_of_lists):\n \"\"\"\n This function takes a list of lists and returns a set of unique numbers.\n \n Args:\n lst_of_lists (list): A list of lists containing integers.\n \n Returns:\n set: A set of unique numbers from the input lists.\n \"\"\"\n # Initialize an empty set to store unique numbers\n flat_set = set()\n \n # Iterate over each sublist in the input list\n for sublist in lst_of_lists:\n # Update the set with the elements from the current sublist\n flat_set.update(sublist)\n \n # Return the set of unique numbers\n return flat_set", "matching_cluster_idx": 7}, {"solution": "def extract_singly(lst_of_lsts):\n \"\"\"\n This function takes a list of lists as an input, \n and returns a set of unique numbers.\n\n Args:\n lst_of_lsts (list): A list of lists containing numbers.\n\n Returns:\n set: A set of unique numbers.\n \"\"\"\n return set([num for lst in lst_of_lsts for num in lst])", "matching_cluster_idx": 5}, {"solution": "def extract_singly(lst_of_lst):\n \"\"\"\n This function takes a list of lists as input, \n flattens it into a single list and then converts it to a set.\n \n Args:\n lst_of_lst (list): A list of lists.\n \n Returns:\n set: A set of numbers.\n \"\"\"\n return set(num for sublist in lst_of_lst for num in sublist)", "matching_cluster_idx": 5}, {"solution": "def extract_singly(lists):\n \"\"\"\n Flatten the list of lists into a single set of numbers.\n \n Args:\n lists (list): A list containing multiple lists of numbers.\n \n Returns:\n set: A set of unique numbers from the input lists.\n \"\"\"\n return set(x for lst in lists for x in lst)", "matching_cluster_idx": 5}, {"solution": "def extract_singly(lst_of_lists):\n \"\"\"\n This function takes a list of lists of integers as input and returns a set of unique integers.\n \n Args:\n lst_of_lists (list): A list containing one or more lists of integers.\n \n Returns:\n set: A set of unique integers from the input lists.\n \"\"\"\n # Use set comprehension to flatten the list and convert it to a set to eliminate duplicates\n return {num for sublist in lst_of_lists for num in sublist}", "matching_cluster_idx": 5}, {"solution": "def extract_singly(lst_of_lists):\n \"\"\"\n This function takes a list of lists and returns a set of unique numbers.\n\n Args:\n lst_of_lists (list): A list of lists containing integers.\n\n Returns:\n set: A set of unique numbers.\n \"\"\"\n return set(number for sublist in lst_of_lists for number in sublist)", "matching_cluster_idx": 5}, {"solution": "def extract_singly(lst_of_lists):\n \"\"\"\n This function takes a list of lists as input and returns a set of numbers.\n \"\"\"\n # Use a set to store unique numbers\n result = set()\n \n # Iterate over each sublist in the input list\n for sublist in lst_of_lists:\n # Add each number in the sublist to the result set\n result.update(sublist)\n \n # Return the set of numbers\n return result", "matching_cluster_idx": 7}, {"solution": "def extract_singly(lst_of_lsts):\n \"\"\"\n This function takes a list of lists as an input and returns a set of unique numbers from these lists.\n \n Args:\n lst_of_lsts (list): A list containing multiple lists of numbers.\n \n Returns:\n set: A set of unique numbers from the input lists.\n \"\"\"\n # Use a set comprehension to combine all numbers from each sublist into a single set\n flat_set = {num for sublist in lst_of_lsts for num in sublist}\n \n return flat_set", "matching_cluster_idx": 5}, {"solution": "def extract_singly(nested_list):\n \"\"\"\n This function takes a list of lists of integers and returns a set of unique integers.\n \n Args:\n nested_list (list): A list of lists of integers.\n \n Returns:\n set: A set of unique integers.\n \"\"\"\n # Use set comprehension to flatten and remove duplicates\n return {num for sublist in nested_list for num in sublist}", "matching_cluster_idx": 5}, {"solution": "def extract_singly(lists_of_numbers):\n \"\"\"\n This function takes a list of lists containing numbers and returns a set of unique numbers.\n \n Parameters:\n lists_of_numbers (list): A list of lists containing numbers.\n \n Returns:\n set: A set of unique numbers from the input list of lists.\n \"\"\"\n \n # Initialize an empty set to store unique numbers\n unique_numbers = set()\n \n # Iterate over each sublist in the input list\n for sublist in lists_of_numbers:\n # Add each number from the sublist to the set\n unique_numbers.update(sublist)\n \n # Return the set of unique numbers\n return unique_numbers", "matching_cluster_idx": 7}, {"solution": "def extract_singly(nested_list):\n \"\"\"\n This function takes a list of lists as input, \n extracts each number and stores them in a set.\n\n Args:\n nested_list (list): A list of lists of numbers.\n\n Returns:\n set: A set of unique numbers.\n \"\"\"\n # Initialize an empty set to store unique numbers\n single_numbers = set()\n \n # Iterate over each sublist in the nested list\n for sublist in nested_list:\n # Extend the set with numbers from the sublist\n single_numbers.update(sublist)\n \n # Return the set of unique numbers\n return single_numbers", "matching_cluster_idx": 7}, {"solution": "def extract_singly(lst_of_lists):\n \"\"\"\n This function flattens the list of lists into a single set of numbers.\n\n Args:\n lst_of_lists (list): A list containing multiple lists of numbers\n\n Returns:\n set: A set of unique numbers from the list of lists\n \"\"\"\n # Initialize an empty set to store unique numbers\n unique_nums = set()\n\n # Iterate over each sublist in the list of lists\n for sublist in lst_of_lists:\n # Extend the set with numbers from the current sublist\n unique_nums.update(sublist)\n\n return unique_nums", "matching_cluster_idx": 7}]}, "Mbpp/141": {"dps": 98.41269841269842, "dps_norm": 50.0, "pass@1": 46.0, "profiled": [{"solution": "def pancake_sort(arr):\n \"\"\"\n Sorts a list of elements in ascending order using the pancake sort algorithm.\n\n The pancake sort algorithm works by repeatedly finding the maximum element from the unsorted part of the array and then \"folding\" the array so that the maximum element is at the beginning of the unsorted part of the array. This is repeated until the entire array is sorted.\n\n Args:\n arr (list): The list of elements to sort.\n\n Returns:\n list: The sorted list of elements.\n \"\"\"\n n = len(arr)\n\n for curr_size in range(n, 0, -1):\n max_index = arr.index(max(arr[0:curr_size]))\n if max_index != curr_size - 1:\n # Flip the elements from the beginning to the maximum element\n arr[:max_index + 1] = reversed(arr[:max_index + 1])\n # Flip the elements from the beginning to the current size\n arr[:curr_size] = reversed(arr[:curr_size])\n\n return arr", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(arr):\n \"\"\"\n Sort a list of elements using the pancake sort algorithm.\n \n Pancake sort is a simple sorting algorithm which repeats the following processes until the list is sorted:\n 1. Find the maximum value in the unsorted part of the list.\n 2. Flip the maximum element to the beginning of the list.\n 3. Flip the entire list so that the maximum element is in its final position.\n \n Parameters:\n arr (list): A list of elements.\n \n Returns:\n list: The sorted list.\n \"\"\"\n \n n = len(arr)\n \n # Traverse through all elements\n for i in range(n - 1, -1, -1):\n # Find the index of the maximum element from start to i\n max_idx = arr.index(max(arr[:i + 1]))\n \n # If maximum element is not at its position, flip it to the start\n if max_idx != i:\n # Flip the maximum element to the start\n arr[:max_idx + 1] = reversed(arr[:max_idx + 1])\n \n # Flip the entire list to put the max element at its final position\n arr[:i + 1] = reversed(arr[:i + 1])\n \n return arr", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(arr):\n \"\"\"\n Sorts a list of elements using pancake sort.\n \n The function flips the largest unsorted element to the front, then flips the entire list \n so that the largest element is in its correct position, repeats the process for the next \n largest unsorted element, until all elements are sorted.\n \n Args:\n arr (list): The list of elements to be sorted.\n \n Returns:\n list: The sorted list of elements.\n \"\"\"\n arr = arr[:] # Create a copy to avoid modifying the original list\n n = len(arr)\n \n for i in range(n, 0, -1):\n # Find the index of the largest element in the unsorted part of the list\n max_index = arr.index(max(arr[:i]))\n \n # Flip the largest element to the front\n if max_index != i - 1:\n # Flip the elements before the largest element to the front\n arr[:max_index + 1] = arr[:max_index + 1][::-1]\n # Flip the entire list so that the largest element is in its correct position\n arr[:i] = arr[:i][::-1]\n \n return arr", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(lst):\n \"\"\"\n Sort a list of elements using pancake sort algorithm.\n \n Pancake sort is a simple sorting algorithm that repeatedly finds the maximum element from the unsorted part and moves it to the beginning of the unsorted part.\n \n Args:\n lst (list): A list of elements that needs to be sorted.\n \n Returns:\n list: A sorted list of elements.\n \"\"\"\n n = len(lst)\n \n for curr_size in range(n, 0, -1):\n # Find index of the maximum element in the unsorted part\n max_idx = lst.index(max(lst[:curr_size]))\n \n # If maximum element is not in the unsorted part, no rotation is needed\n if max_idx == curr_size - 1:\n continue\n \n # Flip the maximum element to the beginning of the list\n if max_idx != 0:\n lst[:max_idx + 1] = lst[:max_idx + 1][::-1]\n \n # Flip the unsorted part to its correct position\n lst[:curr_size] = lst[:curr_size][::-1]\n \n return lst", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(arr):\n \"\"\"\n Sorts a list of elements using pancake sort algorithm.\n\n This function works by repeatedly finding the maximum element in the unsorted part of the list and moving it to the beginning of the list.\n After moving it to the beginning, it flips the rest of the list to move the maximum element to its sorted position.\n This process is repeated until the list is sorted.\n \"\"\"\n n = len(arr)\n for size in range(n, 0, -1):\n # Find the index of the maximum element in the unsorted part of the list\n max_idx = arr.index(max(arr[:size]))\n \n # If the maximum element is not at the beginning of the unsorted part, flip it there\n if max_idx != size - 1:\n # Flip the maximum element to the beginning of the list\n arr[:max_idx + 1] = reversed(arr[:max_idx + 1])\n # Flip the rest of the unsorted part to move the maximum element to its sorted position\n arr[:size] = reversed(arr[:size])\n\n return arr", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(arr):\n \"\"\"\n Sorts a list of elements in descending order using the pancake sort algorithm.\n\n :param arr: List of elements to be sorted\n :return: Sorted list of elements\n \"\"\"\n n = len(arr)\n\n for size in range(n, 0, -1):\n # Find the index of the maximum element in the unsorted part of the array\n max_index = arr.index(max(arr[:size]))\n\n # If the maximum element is not at the current size, flip the elements\n if max_index != size - 1:\n # Flip the elements from the start to the maximum element index\n arr[:max_index + 1] = arr[:max_index + 1][::-1]\n # Flip the elements from the start to the current size\n arr[:size] = arr[:size][::-1]\n\n return arr", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(arr):\n \"\"\"\n Sorts a list of elements using pancake sort algorithm.\n\n Args:\n arr (list): The list to be sorted.\n\n Returns:\n list: The sorted list.\n \"\"\"\n n = len(arr)\n for i in range(n - 1, 0, -1):\n # Find the index of the maximum element in the unsorted part of the array\n max_idx = arr.index(max(arr[:i + 1]))\n \n # If the maximum element is not at the end of the unsorted part, flip it to the end\n if max_idx != i:\n # Flip the first max_idx + 1 elements to the end of the array\n arr[:max_idx + 1] = arr[:max_idx + 1][::-1]\n \n # Flip the first i + 1 elements of the array\n arr[:i + 1] = arr[:i + 1][::-1]\n \n return arr", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(arr):\n \"\"\"\n Sorts a list of elements in ascending order using pancake sort algorithm.\n\n Args:\n arr (list): The list of elements to sort.\n\n Returns:\n list: The sorted list in ascending order.\n \"\"\"\n n = len(arr)\n \n for size in range(n, 0, -1):\n # Find the index of the maximum element in the unsorted part of the array.\n max_idx = arr.index(max(arr[:size]))\n \n # Flip the maximum element to the beginning of the array.\n arr[:max_idx + 1] = arr[:max_idx + 1][::-1]\n \n # Flip the entire array up to the current size to move the maximum element to its correct position.\n arr[:size] = arr[:size][::-1]\n \n return arr", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(arr):\n \"\"\"\n Sorts a list of elements using pancake sort algorithm.\n\n Args:\n arr (list): The list of elements to be sorted.\n\n Returns:\n list: The sorted list of elements.\n\n \"\"\"\n n = len(arr)\n for i in range(n-1, 0, -1):\n # Find the index of the maximum element in unsorted part of the list\n max_idx = arr.index(max(arr[:i+1]))\n \n # Flip the subarray from the start to the maximum element\n arr[:max_idx+1] = arr[:max_idx+1][::-1]\n \n # Flip the subarray from the start to the end\n arr[:i+1] = arr[:i+1][::-1]\n \n return arr", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(lst):\n \"\"\"\n Sorts a list of elements using the pancake sort algorithm.\n \n Pancake sort is a relatively simple sorting algorithm which is optimal for a set of sequences where choosing a larger pancake can be efficient, and making it the largest on top without mixing the other pancakes is efficient.\n \n :param lst: The list to be sorted.\n :return: The sorted list.\n \"\"\"\n for size in range(len(lst), 0, -1):\n # Find the index of the maximum element\n max_idx = lst.index(max(lst[:size]))\n \n # If the maximum element is not at the top, flip it to the top\n if max_idx != size - 1:\n # Flip the maximum element to the top\n lst[:max_idx + 1] = lst[:max_idx + 1][::-1]\n # Flip the whole list so the maximum element is in its correct place\n lst[:size] = lst[:size][::-1]\n \n return lst", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(arr):\n \"\"\"\n Sorts a list of elements using the pancake sort algorithm.\n\n Args:\n arr (list): A list of elements to be sorted.\n\n Returns:\n list: A sorted list of elements.\n \"\"\"\n n = len(arr)\n # Traverse through all elements\n for i in range(n - 1, 0, -1):\n # Find the index of the maximum element in the unsorted part of the array\n max_idx = arr.index(max(arr[:i + 1]))\n # Move the maximum element to the beginning of the unsorted part of the array\n if max_idx != i:\n # Flip the elements from the beginning to max_idx\n arr[:max_idx + 1] = arr[:max_idx + 1][::-1]\n # Flip the elements from the beginning to i\n arr[:i + 1] = arr[:i + 1][::-1]\n return arr", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(arr):\n \"\"\"\n This function sorts a list of elements in ascending order using the pancake sort algorithm.\n \n :param arr: A list of integers\n :return: A sorted list of integers\n \"\"\"\n n = len(arr)\n \n for size in range(n, 0, -1):\n # Find the index of the maximum element in the unsorted part of the array\n max_index = arr.index(max(arr[:size]))\n \n # If the maximum element is not at the beginning of the unsorted part, flip it there\n if max_index != 0:\n arr[:max_index + 1] = arr[:max_index + 1][::-1]\n \n # Then, flip the entire unsorted part of the array\n arr[:size] = arr[:size][::-1]\n \n return arr", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(arr):\n \"\"\"\n This function sorts a list of elements in ascending order using the pancake sort algorithm.\n \n Args:\n arr (list): A list of elements to be sorted.\n \n Returns:\n list: A sorted list in ascending order.\n \"\"\"\n \n n = len(arr)\n \n # Loop through the list from the end to the start\n for size in range(n - 1, 0, -1):\n \n # Find the index of the maximum element in the unsorted part of the list\n max_index = arr.index(max(arr[:size + 1]))\n \n # If the maximum element is not at the end, flip it to the end\n if max_index != size:\n \n # Flip the element at max_index to the end of the unsorted part\n arr[:max_index + 1] = arr[:max_index + 1][::-1]\n \n # Flip the first element of the unsorted part to the end\n arr[:size + 1] = arr[:size + 1][::-1]\n \n return arr", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(lst):\n \"\"\"\n Sorts a list of elements using the pancake sort algorithm.\n\n Args:\n lst (list): The list of elements to be sorted.\n\n Returns:\n list: The sorted list of elements.\n \"\"\"\n n = len(lst)\n for i in range(n - 1, 0, -1):\n # Find the maximum element in the unsorted part of the list\n max_index = lst.index(max(lst[:i + 1]))\n \n # If the maximum element is not at the beginning of the unsorted part,\n # flip the elements up to the maximum element to the beginning\n if max_index != 0:\n lst[:max_index + 1] = lst[:max_index + 1][::-1]\n \n # Flip the elements from the beginning to the maximum index\n lst[:i + 1] = lst[:i + 1][::-1]\n\n return lst", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(arr):\n \"\"\"\n Sorts a list of elements using the pancake sort algorithm.\n\n This function works by repeatedly finding the maximum element from the unsorted part of the list\n and flipping it to the beginning of the list, then flipping the entire list to the correct position.\n \"\"\"\n n = len(arr)\n for i in range(n, 1, -1):\n # Find the index of the maximum element in the unsorted part of the list\n max_idx = arr.index(max(arr[0:i]))\n # Flip the maximum element to the beginning of the list\n if max_idx != 0:\n arr[:max_idx + 1] = arr[:max_idx + 1][::-1]\n # Flip the entire list to the correct position\n arr[:i] = arr[:i][::-1]\n return arr", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(lst):\n \"\"\"\n Sorts a list of elements using the pancake sort algorithm.\n\n This function repeatedly flips the list so that the maximum element moves to the beginning, \n then flips the part of the list before this maximum element to the end, effectively \n removing the maximum element from its current position.\n\n Args:\n lst: A list of integers to be sorted.\n\n Returns:\n A sorted list of integers.\n \"\"\"\n n = len(lst)\n \n # Traverse through all elements in the list\n for curr_size in range(n, 0, -1):\n \n # Find the index of the maximum element in the current sublist\n max_index = lst.index(max(lst[:curr_size]))\n \n # If the maximum element is at the current index, skip the iteration\n if max_index == curr_size - 1:\n continue\n \n # Flip the sublist\n lst[:max_index + 1] = lst[:max_index + 1][::-1]\n \n # Flip the sublist from the beginning of the list\n lst[:curr_size] = lst[:curr_size][::-1]\n \n return lst", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(arr):\n \"\"\"\n This function sorts a list of elements using pancake sort algorithm.\n\n The idea behind pancake sort is to first find the maximum element in the array \n and rotate it to the front. Then, repeat this process until the array is sorted.\n\n :param arr: List of elements\n :return: Sorted list\n \"\"\"\n n = len(arr)\n for i in range(n, 0, -1):\n # Find the index of the maximum element\n max_idx = arr.index(max(arr[:i]))\n \n # Flip the element at the max_idx to the front\n arr[:max_idx + 1] = arr[:max_idx + 1][::-1]\n \n # Flip the front elements so that the max element is at its correct position\n arr[:i] = arr[:i][::-1]\n \n return arr", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(lst):\n \"\"\"\n Sort a list of elements using the pancake sort algorithm.\n \n The pancake sort is a simple, inefficient sorting algorithm. It works by repeatedly finding the maximum element from the unsorted part and moving it to the beginning of the unsorted part, effectively flipping the entire list (or a segment of it) if it's not in its correct position.\n\n Args:\n lst (list): The list to be sorted.\n\n Returns:\n list: The sorted list.\n \"\"\"\n\n n = len(lst)\n \n # Traverse through all elements in the list\n for curr_size in range(n, 0, -1):\n # Find the index of the maximum element in the unsorted part of the list\n max_index = lst.index(max(lst[:curr_size]))\n \n # If the maximum element is not in the current position, flip the elements so that the maximum element is at the beginning of the unsorted part\n if max_index != 0:\n # Flip the elements from the beginning to max_index\n lst = lst[:max_index + 1][::-1] + lst[max_index + 1:]\n \n # Flip the elements from the beginning to curr_size to move the maximum element to its final position\n lst = lst[:curr_size][::-1] + lst[curr_size:]\n \n return lst", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(arr):\n \"\"\"\n Sorts a list of elements in ascending order using the pancake sort algorithm.\n\n Args:\n arr (list): A list of elements to sort.\n\n Returns:\n list: The sorted list of elements.\n \"\"\"\n n = len(arr)\n for i in range(n, 0, -1):\n # Find the index of the maximum element in the unsorted part of the array\n max_index = arr.index(max(arr[:i]))\n \n # If the maximum element is not at the beginning of the unsorted part, flip the part of the array up to max_index\n if max_index != i - 1:\n # Flip the part of the array up to max_index\n arr[:max_index + 1] = reversed(arr[:max_index + 1])\n \n # Flip the whole array up to the current index\n arr[:i] = reversed(arr[:i])\n \n return arr", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(arr):\n \"\"\"\n This function sorts a list of elements using pancake sort algorithm.\n \n The algorithm works by repeatedly finding the maximum element in the unsorted part of the array\n and moving it to the beginning of the unsorted part, then removing it from the array.\n \n Parameters:\n arr (list): A list of elements to be sorted.\n \n Returns:\n list: The sorted list of elements.\n \"\"\"\n \n # make a copy of the array to avoid modifying the original array\n arr_copy = arr[:]\n \n # loop through the array\n for i in range(len(arr_copy), 1, -1):\n # find the maximum element in the unsorted part of the array\n max_idx = arr_copy.index(max(arr_copy[:i]))\n \n # if the maximum element is not at the beginning of the unsorted part,\n # flip the elements before it to move it to the beginning\n if max_idx != i - 1:\n # flip the elements before the maximum element\n arr_copy[:max_idx + 1] = arr_copy[:max_idx + 1][::-1]\n \n # flip the elements before the maximum element (in case it is not at the start)\n arr_copy[:i] = arr_copy[:i][::-1]\n \n return arr_copy", "matching_cluster_idx": 3}]}, "Mbpp/166": {"dps": 89.96, "dps_norm": 48.75, "pass@1": 74.0, "profiled": [{"solution": "def find_even_pair(nums):\n \"\"\"\n Counts the number of pairs of integers in a list that xor to an even number.\n \n Args:\n nums (list): A list of integers.\n \n Returns:\n int: The number of pairs of integers that xor to an even number.\n \"\"\"\n count = 0\n for i in range(len(nums)):\n for j in range(i + 1, len(nums)):\n if (nums[i] ^ nums[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(nums):\n \"\"\"\n Counts the number of pairs of integers in a list that xor to an even number.\n\n Args:\n nums (list): A list of integers.\n\n Returns:\n int: The number of pairs of integers that xor to an even number.\n \"\"\"\n even_count = 0\n for i in range(len(nums)):\n for j in range(i + 1, len(nums)):\n if (nums[i] ^ nums[j]) % 2 == 0:\n even_count += 1\n return even_count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(nums):\n \"\"\"\n Counts the number of pairs of integers in a list that xor to an even number.\n \n Args:\n nums (list): A list of integers.\n \n Returns:\n int: The number of pairs that xor to an even number.\n \"\"\"\n count = 0\n for i in range(len(nums)):\n for j in range(i + 1, len(nums)):\n if (nums[i] ^ nums[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(nums):\n \"\"\"\n Counts the number of pairs of integers in a list that xor to an even number.\n\n Args:\n nums (list): A list of integers.\n\n Returns:\n int: The number of pairs that xor to an even number.\n \"\"\"\n # Sort the list in ascending order\n nums.sort()\n count = 0\n for i in range(len(nums) - 1):\n # Check if the current number and the next number xor to an even number\n for j in range(i + 1, len(nums)):\n # Check if the xor of the current number and the next number is even\n if (nums[i] ^ nums[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(lst):\n \"\"\"\n This function counts the number of pairs of integers in a list that xor to an even number.\n\n Args:\n lst (list): A list of integers.\n\n Returns:\n int: The number of pairs of integers in the list that xor to an even number.\n \"\"\"\n count = 0\n for i in range(len(lst)):\n for j in range(i + 1, len(lst)):\n if (lst[i] ^ lst[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(nums):\n \"\"\"\n Counts the number of pairs of integers in a list that xor to an even number.\n\n Args:\n nums (list): A list of integers.\n\n Returns:\n int: The number of pairs of integers in the list that xor to an even number.\n \"\"\"\n count = 0\n for i in range(len(nums)):\n for j in range(i+1, len(nums)):\n # Check if the xor of two numbers is even\n if (nums[i] ^ nums[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(nums):\n \"\"\"\n Counts the number of pairs of integers in a list that xor to an even number.\n\n Args:\n nums (list): A list of integers.\n\n Returns:\n int: The number of pairs of integers in the list that xor to an even number.\n \"\"\"\n count = 0\n for i in range(len(nums)):\n for j in range(i+1, len(nums)):\n if (nums[i] ^ nums[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(nums):\n \"\"\"\n Counts the number of pairs of integers in a list that xor to an even number.\n \n Args:\n nums (list): A list of integers.\n \n Returns:\n int: The number of pairs of integers that xor to an even number.\n \"\"\"\n even_count = 0\n for i in range(len(nums)):\n for j in range(i + 1, len(nums)):\n if (nums[i] ^ nums[j]) % 2 == 0: # Check if xor is even\n even_count += 1\n return even_count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(nums):\n \"\"\"\n Counts the number of pairs of integers in a list that xor to an even number.\n\n Args:\n nums (list): A list of integers.\n\n Returns:\n int: The number of pairs that xor to an even number.\n \"\"\"\n even_count = 0\n for i in range(len(nums)):\n for j in range(i + 1, len(nums)):\n if (nums[i] ^ nums[j]) % 2 == 0:\n even_count += 1\n return even_count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(nums):\n \"\"\"\n Counts the number of pairs of integers in a list that xor to an even number.\n \n Args:\n nums (list): A list of integers.\n \n Returns:\n int: The number of pairs of integers in the list that xor to an even number.\n \"\"\"\n count = 0\n for i in range(len(nums)):\n for j in range(i + 1, len(nums)):\n # if the xor of the current pair of numbers is even, increment count\n if (nums[i] ^ nums[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(lst):\n \"\"\"\n This function takes a list of integers as input and returns the number of pairs of integers \n that xor to an even number.\n\n Args:\n lst (list): A list of integers.\n\n Returns:\n int: The number of pairs of integers that xor to an even number.\n \"\"\"\n even_count = 0\n xor_dict = {}\n \n # Iterate over the list with two nested loops\n for i in range(len(lst)):\n for j in range(i+1, len(lst)):\n # Calculate the XOR of the current pair\n xor = lst[i] ^ lst[j]\n # If the XOR is even, increment the count and update the dictionary\n if xor % 2 == 0:\n even_count += 1\n xor_dict[xor] = True\n \n return even_count", "matching_cluster_idx": 0}, {"solution": "def find_even_pair(nums):\n \"\"\"\n This function takes a list of integers as input and returns the count of pairs that xor to an even number.\n\n Args:\n nums (list): A list of integers.\n\n Returns:\n int: The count of pairs that xor to an even number.\n \"\"\"\n even_count = 0\n for i in range(len(nums)):\n for j in range(i + 1, len(nums)):\n # Check if the xor of the current pair is even\n if (nums[i] ^ nums[j]) % 2 == 0:\n even_count += 1\n return even_count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(nums):\n \"\"\"\n Count the number of pairs of integers in a list that xor to an even number.\n\n Args:\n nums (list): A list of integers.\n\n Returns:\n int: The number of pairs of integers in the list that xor to an even number.\n \"\"\"\n count = 0\n for i in range(len(nums)):\n for j in range(i + 1, len(nums)):\n # Check if the xor of two numbers is even\n if (nums[i] ^ nums[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(nums):\n \"\"\"\n Counts the number of pairs of integers in a list that xor to an even number.\n\n Args:\n nums (list): A list of integers\n\n Returns:\n int: The number of pairs of integers in the list that xor to an even number\n \"\"\"\n count = 0\n for i in range(len(nums)):\n for j in range(i + 1, len(nums)):\n # Check if the xor of the pair is even\n if (nums[i] ^ nums[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(nums):\n \"\"\"\n Counts the number of pairs of integers in the given list that xor to an even number.\n \n Args:\n nums (list): A list of integers.\n \n Returns:\n int: The number of pairs that xor to an even number.\n \"\"\"\n count = 0\n for i in range(len(nums)):\n for j in range(i+1, len(nums)):\n if (nums[i] ^ nums[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(nums):\n \"\"\"\n Counts the number of pairs of integers in a list that xor to an even number.\n\n Args:\n nums (list): A list of integers.\n\n Returns:\n int: The number of pairs of integers in the list that xor to an even number.\n\n \"\"\"\n count = 0\n for i in range(len(nums)):\n for j in range(i + 1, len(nums)):\n if (nums[i] ^ nums[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(nums):\n \"\"\"\n Counts the number of pairs of integers in a list that xor to an even number.\n\n Args:\n nums (list): A list of integers.\n\n Returns:\n int: The number of pairs that xor to an even number.\n \"\"\"\n even_count = 0\n for i in range(len(nums)):\n for j in range(i + 1, len(nums)):\n if (nums[i] ^ nums[j]) % 2 == 0:\n even_count += 1\n return even_count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(nums):\n \"\"\"\n This function calculates the number of pairs of integers in a list that xor to an even number.\n\n Args:\n nums (list): A list of integers.\n\n Returns:\n int: The number of pairs of integers that xor to an even number.\n \"\"\"\n even_count = 0\n # Consider each number in the list\n for i in range(len(nums)):\n # Consider each number after the current number\n for j in range(i+1, len(nums)):\n # If the xor of the two numbers is even, increment the counter\n if (nums[i] ^ nums[j]) % 2 == 0:\n even_count += 1\n return even_count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(lst):\n \"\"\"\n Counts the number of pairs of integers in a list that xor to an even number.\n\n Args:\n lst (list): A list of integers.\n\n Returns:\n int: The number of pairs of integers in the list that xor to an even number.\n \"\"\"\n count = 0\n for i in range(len(lst)):\n for j in range(i + 1, len(lst)):\n if (lst[i] ^ lst[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(lst):\n \"\"\"\n Counts the number of pairs of integers in a list that xor to an even number.\n\n Args:\n lst (list): A list of integers.\n\n Returns:\n int: The number of pairs of integers that xor to an even number.\n \"\"\"\n count = 0\n for i in range(len(lst)):\n for j in range(i+1, len(lst)):\n if (lst[i] ^ lst[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}]}, "Mbpp/170": {"dps": 85.57971014492753, "dps_norm": 91.25, "pass@1": 30.0, "profiled": [{"solution": "def sum_range_list(lst, start, end):\n \"\"\"\n This function calculates the sum of numbers in a list within a specified range.\n\n Args:\n lst (list): The input list of numbers.\n start (int): The start index of the range (inclusive).\n end (int): The end index of the range (inclusive).\n\n Returns:\n int: The sum of numbers in the list within the specified range.\n \"\"\"\n return sum(lst[start:end+1]) # Note: end index is exclusive by default, so we use end+1 to make it inclusive", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(lst, start, end):\n \"\"\"\n This function calculates the sum of numbers in a list within a specified range.\n\n Args:\n lst (list): The list of numbers.\n start (int): The start index of the range (inclusive).\n end (int): The end index of the range (inclusive).\n\n Returns:\n int: The sum of numbers in the list within the specified range.\n \"\"\"\n try:\n # Check if start and end are within the list bounds\n if start < 0 or end >= len(lst):\n raise ValueError(\"Start or end index out of range\")\n # Calculate the sum of numbers in the specified range\n total = sum(lst[start:end+1])\n return total\n except TypeError:\n raise TypeError(\"Input list must be of type list, start and end must be integers.\")", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(numbers, start_index, end_index):\n \"\"\"\n This function calculates the sum of numbers in a list within a specified range.\n\n Args:\n numbers (list): A list of integers.\n start_index (int): The starting index of the range (inclusive).\n end_index (int): The ending index of the range (inclusive).\n\n Returns:\n int: The sum of numbers in the specified range.\n \"\"\"\n # Validate input indices\n if not isinstance(numbers, list) or not all(isinstance(x, int) for x in numbers):\n raise ValueError(\"Input list must contain only integers.\")\n if not isinstance(start_index, int) or not isinstance(end_index, int):\n raise ValueError(\"Start and end indices must be integers.\")\n if start_index < 0 or end_index >= len(numbers):\n raise ValueError(\"Invalid index value. Index should be within the bounds of the list.\")\n\n # Calculate the sum\n return sum(numbers[start_index:end_index+1])", "matching_cluster_idx": 3}, {"solution": "def sum_range_list(lst, start, end):\n \"\"\"\n This function calculates the sum of numbers in a list within a specified range.\n\n Args:\n lst (list): The input list of numbers.\n start (int): The starting index of the range (inclusive).\n end (int): The ending index of the range (inclusive).\n\n Returns:\n int: The sum of numbers within the specified range.\n\n Raises:\n ValueError: If start or end indices are out of range.\n \"\"\"\n if start < 0 or end >= len(lst):\n raise ValueError(\"Indices out of range\")\n\n # Return the sum of elements in the specified range\n return sum(lst[start:end+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(lst, start, end):\n \"\"\"\n Returns the sum of numbers in a list within a range specified by two indices.\n\n Args:\n lst (list): The input list of numbers.\n start (int): The starting index of the range (inclusive).\n end (int): The ending index of the range (inclusive).\n\n Returns:\n int: The sum of numbers in the list within the specified range.\n \"\"\"\n return sum(lst[start:end+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(lst, start_index, end_index):\n \"\"\"\n This function calculates the sum of numbers in a list within a specified range.\n \n Parameters:\n lst (list): The input list of numbers.\n start_index (int): The starting index of the range.\n end_index (int): The ending index of the range.\n \n Returns:\n int: The sum of numbers within the specified range.\n \"\"\"\n \n # Check if the start_index and end_index are valid\n if start_index < 0 or end_index >= len(lst):\n raise ValueError(\"Invalid index. Index should be within the list bounds.\")\n \n # Slice the list to get the range of numbers\n range_numbers = lst[start_index:end_index+1]\n \n # Calculate the sum of numbers in the range\n sum_of_range = sum(range_numbers)\n \n return sum_of_range", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(lst, start, end):\n \"\"\"\n Returns the sum of numbers in a list within a specified range.\n\n Args:\n lst (list): A list of numbers.\n start (int): The start index of the range.\n end (int): The end index of the range.\n\n Returns:\n int: The sum of numbers in the list within the specified range.\n \"\"\"\n return sum(lst[start:end+1]) # Include the 'end' index in the slice.", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(numbers, start, end):\n \"\"\"\n Calculate the sum of numbers in a list within a specified range.\n \n Args:\n numbers (list): A list of numbers.\n start (int): The starting index of the range (inclusive).\n end (int): The ending index of the range (inclusive).\n \n Returns:\n int: The sum of numbers in the specified range.\n \"\"\"\n if not isinstance(numbers, list) or not all(isinstance(x, (int, float)) for x in numbers):\n raise TypeError(\"Input list must be a list of numbers\")\n if not (isinstance(start, int) and isinstance(end, int)):\n raise TypeError(\"Start and end indices must be integers\")\n if start < 0 or end >= len(numbers):\n raise ValueError(\"Indices are out of range\")\n\n return sum(numbers[start:end+1])", "matching_cluster_idx": 2}, {"solution": "def sum_range_list(numbers, start, end):\n \"\"\"\n This function calculates the sum of numbers in a list within a specified range.\n\n Args:\n numbers (list): A list of numbers.\n start (int): The starting index of the range.\n end (int): The ending index of the range.\n\n Returns:\n int: The sum of numbers within the specified range.\n \"\"\"\n if start < 0 or end > len(numbers) - 1:\n raise ValueError(\"Indices are out of range\")\n\n return sum(numbers[start:end+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(lst, start, end):\n \"\"\"\n This function calculates the sum of numbers in a list within a specified range.\n\n Args:\n lst (list): The list of numbers.\n start (int): The starting index of the range (inclusive).\n end (int): The ending index of the range (inclusive).\n\n Returns:\n int: The sum of numbers within the specified range.\n\n Raises:\n ValueError: If start or end indices are out of range.\n TypeError: If start or end are not integers or lst is not a list.\n \"\"\"\n\n # Check if lst is a list and start and end are integers\n if not isinstance(lst, list) or not isinstance(start, int) or not isinstance(end, int):\n raise TypeError(\"Error: Input 'lst' must be a list and 'start' and 'end' must be integers.\")\n\n # Check if start and end indices are within the list bounds\n if start < 0 or end >= len(lst):\n raise ValueError(\"Error: Indices out of range.\")\n\n # Calculate the sum using list slicing\n return sum(lst[start:end+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(lst, start, end):\n \"\"\"\n Returns the sum of numbers in the list from the 'start' index to the 'end' index (inclusive).\n \n Args:\n lst (list): A list of numbers.\n start (int): The starting index of the range.\n end (int): The ending index of the range.\n \n Returns:\n int: The sum of numbers in the specified range.\n \"\"\"\n try:\n # Check if indices are within the list bounds\n if start < 0 or end >= len(lst):\n raise ValueError(\"Index out of range\")\n \n # Use list slicing to get the sublist and calculate its sum\n return sum(lst[start:end+1])\n \n except ValueError as e:\n print(f\"Error: {e}\")\n return None", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(lst, start, end):\n \"\"\"\n This function calculates the sum of numbers in a list within a specified range.\n\n Parameters:\n lst (list): A list of numbers.\n start (int): The starting index of the range (inclusive).\n end (int): The ending index of the range (inclusive).\n\n Returns:\n int: The sum of numbers in the specified range of the list.\n\n Raises:\n ValueError: If the start or end indices are out of range.\n \"\"\"\n if start < 0 or end >= len(lst):\n raise ValueError(\"Indices out of range\")\n\n return sum(lst[start:end + 1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(lst, start, end):\n \"\"\"\n This function calculates the sum of elements in a list within a specified range.\n\n Args:\n lst (list): The list of numbers.\n start (int): The starting index of the range (inclusive).\n end (int): The ending index of the range (inclusive).\n\n Returns:\n int: The sum of numbers in the list within the specified range.\n \"\"\"\n # Check if the start and end indices are within the valid range of the list\n if start < 0 or end > len(lst) - 1:\n raise ValueError(\"Invalid index range\")\n\n # Use list slicing to get the elements in the specified range and sum them up\n return sum(lst[start:end + 1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(lst, start, end):\n \"\"\"\n This function calculates the sum of elements in a list within a specified range.\n\n Parameters:\n lst (list): The input list of numbers\n start (int): The starting index of the range (inclusive)\n end (int): The ending index of the range (inclusive)\n\n Returns:\n int: The sum of numbers in the specified range\n \"\"\"\n if not isinstance(lst, list) or not all(isinstance(x, (int, float)) for x in lst):\n raise ValueError(\"The input is not a list of numbers\")\n if not isinstance(start, int) or not isinstance(end, int):\n raise ValueError(\"Start and end indices must be integers\")\n if start < 0 or end >= len(lst):\n raise ValueError(\"Invalid start or end index\")\n\n return sum(lst[start:end+1])", "matching_cluster_idx": 2}, {"solution": "def sum_range_list(lst, start_idx, end_idx):\n \"\"\"\n Returns the sum of numbers in a list within a specified range.\n \n Args:\n lst (list): The input list of numbers.\n start_idx (int): The starting index of the range (inclusive).\n end_idx (int): The ending index of the range (inclusive).\n \n Returns:\n int: The sum of numbers in the list within the specified range.\n \"\"\"\n # Check if start_idx and end_idx are valid\n if not (0 <= start_idx < len(lst) and 0 <= end_idx < len(lst)):\n raise ValueError(\"Invalid start or end index\")\n \n # Return the sum of numbers in the list within the range\n return sum(lst[start_idx:end_idx+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(num_list, start, end):\n \"\"\"\n This function calculates the sum of a list of numbers between two specified indices.\n\n Args:\n num_list (list): The list of numbers.\n start (int): The starting index (inclusive) of the range.\n end (int): The ending index (inclusive) of the range.\n\n Returns:\n int: The sum of numbers in the specified range of the list.\n \"\"\"\n return sum(num_list[start:end+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(lst, start, end):\n \"\"\"\n This function returns the sum of numbers in a list within a specified range.\n \n Parameters:\n lst (list): The input list of numbers.\n start (int): The starting index (inclusive) of the range.\n end (int): The ending index (inclusive) of the range.\n \n Returns:\n int: The sum of numbers in the list within the specified range.\n \"\"\"\n if start < 0 or end >= len(lst):\n raise ValueError(\"Invalid index: start or end is out of range\")\n return sum(lst[start:end+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(numbers, start, end):\n \"\"\"\n Calculate the sum of numbers in the list within a specified range.\n\n Args:\n - numbers (list): A list of integers.\n - start (int): The starting index of the range (inclusive).\n - end (int): The ending index of the range (inclusive).\n\n Returns:\n - int: The sum of numbers within the specified range.\n \"\"\"\n return sum(numbers[start:end + 1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(numbers, start, end):\n \"\"\"\n This function calculates the sum of numbers in a list within a specified range.\n\n Args:\n numbers (list): A list of integers.\n start (int): The start index of the range (inclusive).\n end (int): The end index of the range (inclusive).\n\n Returns:\n int: The sum of numbers in the specified range.\n \"\"\"\n return sum(numbers[start:end+1]) # Include the 'end' index in the sum", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(lst, start_index, end_index):\n \"\"\"\n Returns the sum of numbers in the list within the specified range.\n\n Args:\n lst (list): The input list.\n start_index (int): The start of the range (inclusive).\n end_index (int): The end of the range (inclusive).\n\n Returns:\n int: The sum of numbers in the list within the specified range.\n \"\"\"\n return sum(lst[start_index:end_index + 1])", "matching_cluster_idx": 7}]}, "Mbpp/226": {"dps": 71.62790697674419, "dps_norm": 24.285714285714285, "pass@1": 96.0, "profiled": [{"solution": "def odd_values_string(s):\n \"\"\"\n This function takes a string as input and returns a new string\n containing characters at even index values of the input string.\n \n Args:\n s (str): The input string.\n \n Returns:\n str: A new string containing characters at even index values of the input string.\n \"\"\"\n return ''.join([s[i] for i in range(len(s)) if i % 2 == 0])", "matching_cluster_idx": 1}, {"solution": "def odd_values_string(s):\n \"\"\"\n This function takes a string as an input, and returns the string with characters at odd index values removed.\n \n Parameters:\n s (str): The input string.\n \n Returns:\n str: The string with characters at odd index values removed.\n \"\"\"\n \n # Initialize an empty string to store the result\n result = ''\n \n # Iterate over the string using enumerate to get both the index and value of each character\n for i, char in enumerate(s):\n # Check if the index is even (not odd)\n if i % 2 == 0:\n # If the index is even, add the character to the result string\n result += char\n \n # Return the result string\n return result", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(s):\n \"\"\"\n Remove characters at odd index values from a given string.\n \n Args:\n s (str): The input string.\n \n Returns:\n str: The string with characters at odd index values removed.\n \"\"\"\n # Use a list comprehension to create a new string with only characters at even index values\n return ''.join([c for i, c in enumerate(s) if i % 2 == 0])", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(s):\n \"\"\"\n Removes characters from a given string at odd index values.\n \n Args:\n s (str): The input string from which characters will be removed at odd indices.\n \n Returns:\n str: A new string containing characters from even index positions.\n \"\"\"\n return s[::2] # Python's slicing allows us to select every other character", "matching_cluster_idx": 5}, {"solution": "def odd_values_string(s):\n \"\"\"\n This function removes the characters at odd indices from a given string.\n\n Args:\n s (str): The input string.\n\n Returns:\n str: The string with characters at odd indices removed.\n\n Example:\n >>> odd_values_string('abcdef')\n 'ace'\n \"\"\"\n # Initialize an empty string to store the result\n result = ''\n\n # Iterate over the string with enumerate to get both index and character\n for i, char in enumerate(s):\n # Check if the index is even (not odd)\n if i % 2 == 0:\n # If even, append the character to the result\n result += char\n\n return result", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(s):\n \"\"\"\n This function removes the characters which have odd index values of a given string.\n\n Args:\n s (str): The input string.\n\n Returns:\n str: A new string with characters at odd index values removed.\n \"\"\"\n # Use list comprehension to filter characters at even index values and join them into a string\n return ''.join([s[i] for i in range(len(s)) if i % 2 == 0])", "matching_cluster_idx": 1}, {"solution": "def odd_values_string(s):\n \"\"\"\n This function removes characters at odd index positions from the input string.\n\n Args:\n s (str): The input string.\n\n Returns:\n str: The string after removing characters at odd index positions.\n \"\"\"\n return ''.join([s[i] for i, char in enumerate(s) if i % 2 == 0])", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(input_str):\n \"\"\"\n This function removes characters at odd index positions in a given string.\n\n Args:\n input_str (str): The input string.\n\n Returns:\n str: A new string without characters at odd index positions.\n \"\"\"\n # Use a list comprehension to create a new string with characters at even index positions\n return ''.join([char for index, char in enumerate(input_str) if index % 2 == 0])", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(s):\n \"\"\"\n This function removes characters from a string which have odd index values.\n \n Parameters:\n s (str): The input string.\n \n Returns:\n str: The string with characters at odd index values removed.\n \"\"\"\n return ''.join([s[i] for i in range(len(s)) if i % 2 == 0])", "matching_cluster_idx": 1}, {"solution": "def odd_values_string(s):\n \"\"\"\n This function takes a string as input, removes characters at odd indices, \n and returns the resulting string.\n \n Args:\n s (str): The input string.\n \n Returns:\n str: The string with characters at odd indices removed.\n \"\"\"\n # Initialize an empty string to store the result\n result = ''\n \n # Iterate over the input string with enumerate to get both index and character\n for i, char in enumerate(s):\n # Check if the index is even\n if i % 2 == 0:\n # If the index is even, append the character to the result\n result += char\n \n # Return the resulting string\n return result", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(s):\n \"\"\"\n This function takes a string as an input and returns a new string with all characters \n having odd indices removed.\n\n Args:\n s (str): The input string.\n\n Returns:\n str: A string with characters having odd indices removed.\n \"\"\"\n # Use list comprehension to filter the string\n # since list indices are 0-based, use a conditional to filter odd indices\n return ''.join([c for i, c in enumerate(s) if i % 2 == 0])", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(s):\n \"\"\"\n This function removes characters at odd indices from a given string.\n\n Args:\n s (str): The input string from which to remove characters at odd indices.\n\n Returns:\n str: The string after removing characters at odd indices.\n \"\"\"\n return ''.join([char for i, char in enumerate(s) if i % 2 == 0])", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(input_str):\n \"\"\"\n This function removes characters at odd indices from a given string.\n \n Args:\n input_str (str): The input string.\n\n Returns:\n str: A new string with characters at odd indices removed.\n \"\"\"\n # Use list comprehension to filter characters at even indices\n result = [char for idx, char in enumerate(input_str) if idx % 2 == 0]\n \n # Join the list into a string\n result = ''.join(result)\n \n return result", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(s):\n \"\"\"\n This function takes a string as an input and returns a new string containing\n characters from even indices of the original string.\n \n Args:\n s (str): The input string.\n \n Returns:\n str: A new string containing characters from even indices of the input string.\n \"\"\"\n return ''.join([s[i] for i in range(len(s)) if i % 2 == 0])", "matching_cluster_idx": 1}, {"solution": "def odd_values_string(input_str):\n \"\"\"\n Removes characters from the input string with odd index values.\n \n Args:\n input_str (str): The input string from which characters are removed.\n \n Returns:\n str: The resulting string after removing characters with odd index values.\n \"\"\"\n return ''.join(input_str[i] for i in range(len(input_str)) if i % 2 == 0)", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(s):\n \"\"\"\n This function removes characters at odd indices from a given string.\n \n Parameters:\n s (str): The input string.\n \n Returns:\n str: A new string containing characters at even indices of the original string.\n \"\"\"\n return s[::2]", "matching_cluster_idx": 5}, {"solution": "def odd_values_string(s):\n \"\"\"\n This function removes the characters which have odd index values of a given string.\n\n Parameters:\n s (str): The input string\n\n Returns:\n str: The string with characters at odd indexes removed\n \"\"\"\n return ''.join([c for i, c in enumerate(s) if i % 2 == 0])", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(s):\n \"\"\"\n Remove the characters which have odd index values of a given string.\n \n Parameters:\n s (str): Input string.\n \n Returns:\n str: The string with characters at odd index removed.\n \"\"\"\n return ''.join([s[i] for i in range(len(s)) if i % 2 == 0])", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(s):\n \"\"\"\n Remove characters at odd indices from a given string.\n\n Args:\n s (str): Input string.\n\n Returns:\n str: String without characters at odd indices.\n \"\"\"\n return ''.join([char for idx, char in enumerate(s) if idx % 2 == 0])", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(s):\n \"\"\"\n This function takes a string as input and returns a new string without characters at odd indices.\n \n Args:\n s (str): The input string.\n \n Returns:\n str: The string with characters at odd indices removed.\n \"\"\"\n # Use list comprehension to create a new list of characters that excludes characters at odd indices\n # The enumerate function provides both the index and value of each character in the string\n # We only include the character if its index is even\n chars = [c for i, c in enumerate(s) if i % 2 == 0]\n \n # Join the characters back into a string\n return ''.join(chars)", "matching_cluster_idx": 0}]}, "Mbpp/230": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def replace_blank(s, c):\n \"\"\"\n Replaces blank spaces in a string with a specified character.\n\n Args:\n s (str): The input string.\n c (str): The character to replace blank spaces with.\n\n Returns:\n str: The modified string.\n \"\"\"\n return s.replace(\" \", c)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(string, char):\n \"\"\"\n Replace blank spaces in a string with a given character.\n\n Args:\n string (str): The input string.\n char (str): The character to replace blank spaces with.\n\n Returns:\n str: The modified string.\n \"\"\"\n return string.replace(\" \", char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(s, c):\n \"\"\"\n Replaces all blank spaces in a given string with a specified character.\n\n Args:\n s (str): The input string.\n c (str): The character to replace blank spaces with.\n\n Returns:\n str: The string with all blank spaces replaced.\n \"\"\"\n return s.replace(\" \", c)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(s, c):\n \"\"\"\n Replaces blank spaces in a string with a given character.\n\n Args:\n s (str): The input string.\n c (str): The character to replace blank spaces with.\n\n Returns:\n str: The input string with blank spaces replaced with the character.\n \"\"\"\n return s.replace(\" \", c)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_str, char):\n \"\"\"\n Replaces all blank spaces in a string with a specified character.\n \n Parameters:\n input_str (str): The input string.\n char (str): The character to replace blank spaces with.\n \n Returns:\n str: The modified string with all blank spaces replaced.\n \"\"\"\n return input_str.replace(\" \", char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(s, char):\n \"\"\"\n Replace blank spaces in a string with a specified character.\n\n Args:\n s (str): The input string.\n char (str): The character to replace spaces with.\n\n Returns:\n str: The string with blank spaces replaced with the character.\n \"\"\"\n return s.replace(' ', char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(s, c):\n \"\"\"\n Replaces blank spaces in a given string with a specified character.\n\n Args:\n s (str): The input string to be processed.\n c (str): The character to replace blank spaces with.\n\n Returns:\n str: The string with blank spaces replaced.\n \"\"\"\n return s.replace(\" \", c)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(string, char):\n \"\"\"\n This function takes in a string and a character, replaces all blank spaces in the string with the character, and returns the string.\n\n Parameters:\n string (str): The input string.\n char (str): The character to replace blank spaces with.\n\n Returns:\n str: The modified string with blank spaces replaced.\n \"\"\"\n return string.replace(\" \", char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(s, c):\n \"\"\"\n Replaces all blank spaces in a string with a specified character.\n\n Args:\n s (str): The input string.\n c (str): The character to replace blank spaces with.\n\n Returns:\n str: The input string with all blank spaces replaced.\n \"\"\"\n # Use the replace() method of the string class to replace all spaces with the character\n return s.replace(' ', c)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(s, c):\n \"\"\"\n Replace blank spaces in the string with a specified character.\n\n Args:\n s (str): The input string.\n c (str): The character to replace blank spaces with.\n\n Returns:\n str: The string with blank spaces replaced.\n \"\"\"\n return s.replace(' ', c)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(s, char):\n \"\"\"\n Replaces all blank spaces in the input string with a given character.\n\n Args:\n s (str): The input string.\n char (str): The character to replace blank spaces with.\n\n Returns:\n str: The modified string with blank spaces replaced.\n \"\"\"\n # Check if the input arguments are strings\n if not isinstance(s, str) or not isinstance(char, str):\n raise TypeError(\"Both s and char must be strings\")\n # Replace blank spaces with the character\n return s.replace(\" \", char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_str, char):\n \"\"\"\n This function replaces blank spaces in a given string with a specified character.\n\n Args:\n input_str (str): The input string.\n char (str): The character to replace blank spaces with.\n\n Returns:\n str: The string with blank spaces replaced.\n \"\"\"\n return input_str.replace(\" \", char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(s, c):\n \"\"\"\n Replaces all blank spaces in a string with a given character.\n\n Args:\n s (str): The input string.\n c (str): The character to replace blank spaces with.\n\n Returns:\n str: The modified string.\n \"\"\"\n return s.replace(\" \", c)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(s, c):\n \"\"\"\n This function replaces blank spaces in the string with the given character.\n\n Args:\n s (str): The input string\n c (str): The character to replace blank spaces with\n\n Returns:\n str: The modified string with blank spaces replaced\n \"\"\"\n return s.replace(' ', c)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(s, char):\n \"\"\"\n Replaces blank spaces in the input string with a given character.\n \n Args:\n s (str): The input string.\n char (str): The character to replace blank spaces with.\n \n Returns:\n str: The string with blank spaces replaced by the given character.\n \"\"\"\n return s.replace(' ', char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(string, char):\n \"\"\"\n Replaces all blank spaces in a given string with a specified character.\n\n Args:\n string (str): The input string to replace blank spaces in.\n char (str): The character to use as a replacement for blank spaces.\n\n Returns:\n str: The modified string with blank spaces replaced.\n \"\"\"\n return string.replace(' ', char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string, replacement_char):\n \"\"\"\n Replaces all blank spaces in a string with a specified character.\n\n Args:\n input_string (str): The string to replace blank spaces in.\n replacement_char (str): The character to replace blank spaces with.\n\n Returns:\n str: The string with all blank spaces replaced.\n \"\"\"\n # Use the replace() method of the string to replace all blank spaces\n return input_string.replace(\" \", replacement_char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(s, c):\n \"\"\"\n Replaces all blank spaces in a string with a specified character.\n\n Args:\n s (str): The input string.\n c (str): The character to replace blank spaces with.\n\n Returns:\n str: The string with all blank spaces replaced.\n \"\"\"\n return s.replace(' ', c)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(string, char):\n \"\"\"\n This function takes in a string and a character, replaces blank spaces in the string with the character, and returns the string.\n\n Args:\n string (str): The input string.\n char (str): The character to replace blank spaces with.\n\n Returns:\n str: The input string with blank spaces replaced by the given character.\n \"\"\"\n # Use the replace() method to replace blank spaces with the given character\n return string.replace(' ', char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(s, c):\n \"\"\"\n Replaces blank spaces in a given string with a specified character.\n \n Args:\n s (str): The input string.\n c (str): The character to replace blank spaces with.\n \n Returns:\n str: The string with blank spaces replaced.\n \"\"\"\n return s.replace(\" \", c)", "matching_cluster_idx": 7}]}, "Mbpp/239": {"dps": null, "dps_norm": null, "pass@1": 1.0, "profiled": []}, "Mbpp/240": {"dps": 67.01219512195122, "dps_norm": 79.44444444444444, "pass@1": 23.0, "profiled": [{"solution": "def replace_list(lst1, lst2):\n \"\"\"\n Replace the last element of lst1 with the elements of lst2.\n \n Args:\n lst1 (list): The list whose last element is to be replaced.\n lst2 (list): The list containing the elements to replace the last element of lst1.\n \n Returns:\n list: A new list with the last element of lst1 replaced with the elements of lst2.\n \"\"\"\n if len(lst1) == 0:\n return lst1 + lst2 # If lst1 is empty, return lst2\n \n lst1[-1:] = lst2 # Replace the last element of lst1 with the elements of lst2\n return lst1", "matching_cluster_idx": 7}, {"solution": "def replace_list(list1, list2):\n \"\"\"\n This function replaces the last element of the first list with the elements of the second list.\n \n Args:\n list1 (list): The list from which the last element will be replaced.\n list2 (list): The list whose elements will replace the last element of list1.\n \n Returns:\n list: The modified list1 with the last element replaced.\n \"\"\"\n # Replace the last element of list1 with the elements of list2\n list1[-1:] = list2\n return list1", "matching_cluster_idx": 7}, {"solution": "def replace_list(list1, list2):\n \"\"\"\n Replaces the last element of the first list with the elements of the second list.\n\n Args:\n list1 (list): The first list from which the last element will be removed.\n list2 (list): The list whose elements will replace the last element of list1.\n\n Returns:\n list: The modified list1.\n \"\"\"\n list1[-1:] = list2 # replace the last element with elements of list2\n return list1", "matching_cluster_idx": 7}, {"solution": "def replace_list(list1, list2):\n \"\"\"\n Replaces the last element of list1 with the elements of list2.\n\n Args:\n list1 (list): The original list.\n list2 (list): The list to replace the last element of list1 with.\n\n Returns:\n list: The modified list.\n \"\"\"\n list1[-1:] = list2 # Replace the last element of list1 with list2\n return list1", "matching_cluster_idx": 7}, {"solution": "def replace_list(list1, list2):\n \"\"\"\n Replaces the last element of list1 with elements from list2.\n\n Args:\n list1 (list): The first list.\n list2 (list): The second list.\n\n Returns:\n list: The modified list1 with elements from list2 appended to the end.\n \"\"\"\n list1[-1:] = list2\n return list1", "matching_cluster_idx": 7}, {"solution": "def replace_list(list1, list2):\n \"\"\"\n Replaces the last element of the first list with the elements of the second list.\n \n Args:\n list1 (list): The list where the last element is to be replaced.\n list2 (list): The list with elements to replace the last element of list1.\n \n Returns:\n list: A new list that is a copy of list1 with the last element replaced by list2.\n \"\"\"\n # Calculate the last index in list1\n last_index = len(list1) - 1\n \n # Combine the two lists up to the last index of list1 and the elements of list2\n new_list = list1[:last_index] + list2\n \n return new_list", "matching_cluster_idx": 5}, {"solution": "def replace_list(list1, list2):\n \"\"\"\n This function replaces the last element of the first list with the elements of the second list.\n\n Args:\n list1 (list): The first list from which the last element will be removed.\n list2 (list): The list whose elements will be used to replace the last element of list1.\n\n Returns:\n list: A new list where the last element of list1 is replaced with the elements of list2.\n \"\"\"\n \n # Create a copy of the first list\n new_list = list1.copy()\n \n # Remove the last element of the new list\n if new_list:\n new_list.pop()\n \n # Extend the new list with the elements from the second list\n new_list.extend(list2)\n \n return new_list", "matching_cluster_idx": 6}, {"solution": "def replace_list(list1, list2):\n \"\"\"\n This function takes two lists as input and replaces the last element of the first list with the elements of the second list.\n \n Parameters:\n list1 (list): The list from which the last element will be removed.\n list2 (list): The list from which elements will be used to replace the last element of the first list.\n \n Returns:\n list: The modified list1 with the last element replaced by elements of list2.\n \"\"\"\n # Make a copy of the first list to avoid modifying the original list\n new_list = list1.copy()\n \n # Remove the last element of the first list\n del new_list[-1:]\n \n # Insert all elements of the second list at the end of the new list\n new_list.extend(list2)\n \n return new_list", "matching_cluster_idx": 6}, {"solution": "def replace_list(list1, list2):\n \"\"\"\n This function replaces the last element of list1 with the elements of list2.\n \n Parameters:\n list1 (list): The list whose last element will be replaced.\n list2 (list): The list whose elements will replace the last element of list1.\n \n Returns:\n list: The modified list with the last element of list1 replaced by the elements of list2.\n \"\"\"\n # Check if both inputs are lists\n if not isinstance(list1, list) or not isinstance(list2, list):\n raise TypeError(\"Both inputs must be lists\")\n \n # Get the elements of list2 and replace the last element of list1 with these elements\n list1[-1:] = list2\n \n # Return the modified list\n return list1", "matching_cluster_idx": 6}, {"solution": "def replace_list(list1, list2):\n \"\"\"\n Replaces the last element of list1 with the elements of list2.\n \n Args:\n list1 (list): The first list.\n list2 (list): The second list.\n \n Returns:\n list: The list with the last element of list1 replaced by list2.\n \"\"\"\n \n # Get the last index of list1\n last_index = len(list1) - 1\n \n # Replace the last element of list1 with the elements of list2\n list1[-1:] = list2\n \n # Return the modified list\n return list1", "matching_cluster_idx": 6}, {"solution": "def replace_list(list1, list2):\n \"\"\"\n This function replaces the last element of list1 with the elements of list2.\n \n Args:\n list1 (list): The list from which the last element is to be replaced.\n list2 (list): The list whose elements will replace the last element of list1.\n \n Returns:\n list: A new list with the elements of list2 appended to the end of list1.\n \"\"\"\n \n # Get the index of the last element of list1 (which is the second last if the list has more than one element)\n last_index = len(list1) - 1 if len(list1) > 1 else 0\n \n # Create a new list that is a combination of list1 and list2\n new_list = list1[:last_index] + list2\n \n return new_list", "matching_cluster_idx": 4}, {"solution": "def replace_list(list1, list2):\n \"\"\"\n Replace the last element of the first list with the elements of the second list.\n\n Args:\n list1 (list): The original list.\n list2 (list): The list of elements to replace the last element of the first list.\n\n Returns:\n list: A new list with the last element of the first list replaced by the elements of the second list.\n \"\"\"\n # Combine list1 and list2, excluding the last element of list1\n return list1[:-1] + list2", "matching_cluster_idx": 5}, {"solution": "def replace_list(list1, list2):\n \"\"\"\n Replace the last element of list1 with the elements of list2.\n\n Args:\n list1 (list): The original list.\n list2 (list): The list of elements to replace with.\n\n Returns:\n list: The modified list1 with elements from list2.\n\n Example:\n >>> replace_list([1, 3, 5, 7, 9, 10], [2, 4, 6, 8])\n [1, 3, 5, 7, 9, 2, 4, 6, 8]\n \"\"\"\n # Check if list2 is empty\n if not list2:\n # If list2 is empty, remove the last element from list1\n if len(list1) > 1:\n return list1[:-1]\n else:\n return []\n \n # Replace the last element of list1 with the elements of list2\n list1[-1:] = list2\n return list1", "matching_cluster_idx": 7}, {"solution": "def replace_list(lst1, lst2):\n \"\"\"\n Replaces the last element of lst1 with the elements of lst2.\n\n Args:\n lst1 (list): The list to replace the last element in.\n lst2 (list): The list to replace the last element with.\n\n Returns:\n list: The modified list.\n \"\"\"\n if len(lst1) > 0:\n # Remove the last element from lst1\n lst1.pop()\n # Add the elements of lst2 to lst1\n lst1.extend(lst2)\n return lst1", "matching_cluster_idx": 8}, {"solution": "def replace_list(list1, list2):\n \"\"\"\n Replaces the last element of list1 with the elements of list2.\n \n Args:\n list1 (list): The list to modify.\n list2 (list): The list to insert into the first list.\n \n Returns:\n list: A new list with the elements of list2 appended to list1 excluding the last element of list1.\n \"\"\"\n \n # Remove the last element of list1 and append the elements of list2\n return list1[:-1] + list2", "matching_cluster_idx": 5}, {"solution": "def replace_list(list1, list2):\n \"\"\"\n This function takes two lists as input, and replaces the last element of the first list with the elements of the second list.\n\n Args:\n list1 (list): The list that will be modified.\n list2 (list): The list that will replace the last element of list1.\n\n Returns:\n list: The modified list1 with the elements of list2 at the end.\n \"\"\"\n list1[-1:] = list2 # Replace the last element of list1 with elements of list2\n return list1", "matching_cluster_idx": 7}, {"solution": "def replace_list(lst1, lst2):\n \"\"\"\n Replace the last element of the first list with the elements of the second list.\n\n Args:\n lst1 (list): The first list.\n lst2 (list): The second list.\n\n Returns:\n list: The modified list.\n \"\"\"\n # Check if the length of lst2 is more than 1\n if len(lst2) > 1:\n # If it is, append elements of lst2 except the last one\n lst1[-1:] = lst2[:-1]\n # Then append the last element of lst2 to the end of lst1\n lst1.append(lst2[-1])\n else:\n # If the length of lst2 is 1 or less, replace the last element of lst1 with the elements of lst2\n lst1[-1:] = lst2\n return lst1", "matching_cluster_idx": 6}, {"solution": "def replace_list(list1, list2):\n \"\"\"\n Replaces the last element of the first list with the elements of the second list.\n\n Args:\n list1 (list): The list whose last element will be replaced.\n list2 (list): The list that replaces the last element of list1.\n\n Returns:\n list: A new list with the elements of list2 replacing the last element of list1.\n \"\"\"\n # Combine list1 and list2, ignoring the last element of list1\n result = list1[:-1] + list2\n return result", "matching_cluster_idx": 5}, {"solution": "def replace_list(list1, list2):\n \"\"\"\n Replaces the last element of list1 with the elements of list2.\n\n Args:\n list1 (list): The list from which the last element will be replaced.\n list2 (list): The list that will replace the last element of list1.\n\n Returns:\n list: The modified list1 with the last element replaced.\n \"\"\"\n # Check if both inputs are lists\n if not isinstance(list1, list) or not isinstance(list2, list):\n raise TypeError(\"Both inputs must be lists\")\n\n # Combine list2 with the elements of list1 up to the second last element\n combined_list = list1[:-1] + list2\n\n # Return the combined list\n return combined_list", "matching_cluster_idx": 4}, {"solution": "def replace_list(list1, list2):\n \"\"\"\n Replaces the last element of the first list with the elements of the second list.\n\n Args:\n list1 (list): The list in which the last element will be replaced.\n list2 (list): The list whose elements will replace the last element of list1.\n\n Returns:\n list: The modified list.\n \"\"\"\n # Remove the last element from list1 if it's not empty\n if list1:\n list1.pop()\n # Extend list1 with the elements from list2\n list1.extend(list2)\n return list1", "matching_cluster_idx": 8}]}, "Mbpp/251": {"dps": 78.1609195402299, "dps_norm": 75.55555555555556, "pass@1": 10.0, "profiled": [{"solution": "def insert_element(lst, element):\n \"\"\"\n This function inserts an element before each element in a list.\n\n Args:\n lst (list): The input list.\n element: The element to be inserted.\n\n Returns:\n list: The resulting list with the element inserted before each element.\n \"\"\"\n # Initialize an empty list to store the result\n result = []\n \n # Iterate over each element in the input list\n for i in lst:\n # Append the element to be inserted before the current element\n result.append(element)\n # Append the current element to the result list\n result.append(i)\n \n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n \"\"\"\n Inserts an element before each element in the list and returns the resulting list.\n\n Args:\n lst (list): The input list of elements.\n element: The element to be inserted before each element in the list.\n\n Returns:\n list: A new list with the element inserted before each element in the original list.\n \"\"\"\n # Initialize an empty list to store the result\n result = []\n \n # Iterate over each element in the list\n for elem in lst:\n # Append the element to be inserted\n result.append(element)\n # Append the current element in the list\n result.append(elem)\n \n # Return the resulting list\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n \"\"\"\n Inserts the given element before each element in the list and returns the resulting list.\n\n Args:\n lst (list): The input list.\n element: The element to be inserted.\n\n Returns:\n list: The resulting list with the element inserted before each original element.\n \"\"\"\n # Initialize an empty list to store the result\n result = []\n \n # Iterate over each element in the input list\n for i in range(len(lst)):\n # Insert the element before each element in the list\n result += [element, lst[i]]\n \n return result", "matching_cluster_idx": 5}, {"solution": "def insert_element(lst, element):\n \"\"\"\n Inserts the given element before each element in the list.\n\n Args:\n lst (list): The input list.\n element: The element to be inserted.\n\n Returns:\n list: The resulting list with the element inserted before each element.\n \"\"\"\n result = []\n for i in lst:\n result.append(element)\n result.append(i)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, elem):\n \"\"\"\n Inserts a given element before each element in the input list.\n \n Args:\n lst (list): The list in which the element will be inserted.\n elem: The element to be inserted.\n \n Returns:\n list: The resulting list after insertion.\n \"\"\"\n result = [] # Initialize an empty list to store the result\n for e in lst: # Iterate over the input list\n result.extend([elem, e]) # Insert the element before each element and append to the result list\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n \"\"\"\n Inserts an element before each element in the list.\n\n Args:\n lst (list): The input list.\n element: The element to be inserted.\n\n Returns:\n list: The resulting list.\n \"\"\"\n result = []\n for i in lst:\n result.append(element)\n result.append(i)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n \"\"\"\n This function inserts an element before each element in a given list.\n\n Args:\n lst (list): A list of elements\n element (any): The element to be inserted\n\n Returns:\n list: The modified list with the element inserted before each element.\n \"\"\"\n # Initialize an empty list to store the result\n result = []\n\n # Iterate over the input list\n for i in range(len(lst)):\n # Append the element to be inserted before each element\n result.append(element)\n # Append the current element from the input list\n result.append(lst[i])\n \n return result", "matching_cluster_idx": 5}, {"solution": "def insert_element(lst, element):\n \"\"\"\n Inserts an element before each element in the list and returns the resulting list.\n\n Args:\n lst (list): The list to insert the element into.\n element: The element to insert before each element in the list.\n\n Returns:\n list: The resulting list after inserting the element before each element.\n \"\"\"\n result = []\n for item in lst:\n result.append(element)\n result.append(item)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, elem):\n \"\"\"\n Inserts an element before each element in the list and returns the resulting list.\n \n Args:\n lst (list): The original list.\n elem: The element to be inserted.\n \n Returns:\n list: The resulting list after inserting the element.\n \"\"\"\n # Initialize an empty list to store the result.\n result = []\n \n # Insert the element before each element in the list and add it to the result.\n for e in lst:\n result.append(elem)\n result.append(e)\n \n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n \"\"\"\n Inserts an element before each element in the list.\n\n Args:\n lst (list): The original list of elements.\n element: The element to be inserted.\n\n Returns:\n list: A new list with the element inserted before each original list element.\n \"\"\"\n # Create a new list that is a copy of the original list\n new_list = []\n \n # For each element in the list\n for elem in lst:\n # Append the element to be inserted and the original element to the new list\n new_list.extend([element, elem])\n \n return new_list", "matching_cluster_idx": 6}]}, "Mbpp/256": {"dps": 60.490867579908674, "dps_norm": 56.76470588235294, "pass@1": 36.0, "profiled": [{"solution": "def count_Primes_nums(n):\n \"\"\"\n This function counts the number of prime numbers less than a given non-negative number.\n \n Args:\n n (int): A non-negative number.\n \n Returns:\n int: The number of prime numbers less than the given number.\n \"\"\"\n def is_prime(num):\n \"\"\"\n Checks if a number is prime.\n \n Args:\n num (int): The number to check for primality.\n \n Returns:\n bool: True if the number is prime, False otherwise.\n \"\"\"\n if num < 2:\n return False\n for i in range(2, int(num ** 0.5) + 1):\n if num % i == 0:\n return False\n return True\n \n count = 0\n for i in range(2, n):\n if is_prime(i):\n count += 1\n return count", "matching_cluster_idx": 8}, {"solution": "def count_Primes_nums(n: int) -> int:\n \"\"\"\n Returns the number of prime numbers less than the given non-negative number.\n \n Args:\n n (int): A non-negative number.\n\n Returns:\n int: The number of prime numbers less than n.\n \"\"\"\n def is_prime(num: int) -> bool:\n \"\"\"\n Checks if a number is prime.\n \n Args:\n num (int): The number to check.\n\n Returns:\n bool: True if the number is prime, False otherwise.\n \"\"\"\n if num < 2:\n return False\n for i in range(2, int(num ** 0.5) + 1):\n if num % i == 0:\n return False\n return True\n\n count = 0\n for num in range(2, n):\n if is_prime(num):\n count += 1\n return count", "matching_cluster_idx": 8}, {"solution": "def count_Primes_nums(n: int) -> int:\n \"\"\"\n This function counts the number of prime numbers less than the given non-negative number.\n\n Args:\n n (int): A non-negative number.\n\n Returns:\n int: The number of prime numbers less than the given non-negative number.\n \"\"\"\n def is_prime(num: int) -> bool:\n \"\"\"\n Helper function to check if a number is prime.\n\n Args:\n num (int): The number to check.\n\n Returns:\n bool: True if the number is prime, False otherwise.\n \"\"\"\n if num < 2:\n return False\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n return False\n return True\n\n count = 0\n for i in range(2, n):\n if is_prime(i):\n count += 1\n return count", "matching_cluster_idx": 8}, {"solution": "def count_Primes_nums(n):\n \"\"\"\n Returns the number of prime numbers less than the given non-negative number n.\n\n Args:\n n (int): A non-negative number.\n\n Returns:\n int: The number of prime numbers less than n.\n\n Raises:\n ValueError: If n is a negative number.\n \"\"\"\n\n # Check if n is a non-negative number\n if n < 0:\n raise ValueError(\"Input must be a non-negative number.\")\n\n # Handle the special case when n is 0 or 1\n if n < 2:\n return 0\n\n # Initialize a list to store whether each number is prime or not\n prime_status = [True] * n\n prime_status[0] = prime_status[1] = False\n\n # Iterate from 2 to sqrt(n) to mark non-prime numbers\n for i in range(2, int(n ** 0.5) + 1):\n if prime_status[i]:\n # If a number is marked as prime, mark its multiples as non-prime\n for j in range(i * i, n, i):\n prime_status[j] = False\n\n # Count the number of prime numbers\n count = sum(prime_status)\n\n return count", "matching_cluster_idx": 14}, {"solution": "def count_Primes_nums(n):\n \"\"\"\n Returns the number of prime numbers less than the given non-negative number.\n\n Args:\n n (int): A non-negative number.\n\n Returns:\n int: The number of prime numbers less than n.\n \"\"\"\n def is_prime(num):\n \"\"\"\n Checks if a number is prime.\n\n Args:\n num (int): A positive number.\n\n Returns:\n bool: True if the number is prime, False otherwise.\n \"\"\"\n if num < 2:\n return False\n for i in range(2, int(num ** 0.5) + 1):\n if num % i == 0:\n return False\n return True\n\n count = 0\n for i in range(2, n):\n if is_prime(i):\n count += 1\n return count", "matching_cluster_idx": 8}, {"solution": "def count_Primes_nums(n):\n \"\"\"\n This function takes a non-negative number and returns the count of prime numbers less than it.\n \n Args:\n n (int): A non-negative number.\n \n Returns:\n int: The count of prime numbers less than n.\n \"\"\"\n \n # Initialize count of primes\n count = 0\n \n # Iterate over all numbers less than n\n for possiblePrime in range(2, n):\n \n # Assume number is prime until shown it is not\n isPrime = True\n \n # Check if the number is divisible by any number up to its square root\n for num in range(2, int(possiblePrime ** 0.5) + 1):\n \n if possiblePrime % num == 0:\n isPrime = False\n break\n \n # If number is prime, increment count\n if isPrime:\n count += 1\n \n return count", "matching_cluster_idx": 8}, {"solution": "def count_Primes_nums(n):\n \"\"\"\n This function takes in a non-negative number and returns the number of prime numbers less than the given non-negative number.\n\n Args:\n n (int): A non-negative integer.\n\n Returns:\n int: The number of prime numbers less than n.\n \"\"\"\n def is_prime(num):\n \"\"\"\n Checks if a number is prime.\n\n Args:\n num (int): The number to check.\n\n Returns:\n bool: True if the number is prime, False otherwise.\n \"\"\"\n if num < 2:\n return False\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n return False\n return True\n\n count = 0\n for i in range(2, n):\n if is_prime(i):\n count += 1\n return count", "matching_cluster_idx": 8}, {"solution": "def count_Primes_nums(n):\n \"\"\"\n Returns the count of prime numbers less than the given non-negative number n.\n\n Args:\n n (int): A non-negative number.\n\n Returns:\n int: The count of prime numbers less than n.\n \"\"\"\n def is_prime(num):\n \"\"\"\n Checks if a number is prime.\n \n Args:\n num (int): The number to check for primality.\n \n Returns:\n bool: True if the number is prime, False otherwise.\n \"\"\"\n if num < 2:\n return False\n for i in range(2, int(num ** 0.5) + 1):\n if num % i == 0:\n return False\n return True\n\n count = 0\n for i in range(2, n):\n if is_prime(i):\n count += 1\n return count", "matching_cluster_idx": 8}, {"solution": "def count_Primes_nums(n):\n \"\"\"\n Counts the number of prime numbers less than the given non-negative number.\n \n Args:\n n (int): A non-negative number.\n \n Returns:\n int: The number of prime numbers less than the given number.\n \"\"\"\n def is_prime(num):\n \"\"\"\n Checks if a number is prime.\n \n Args:\n num (int): A number to check.\n \n Returns:\n bool: True if the number is prime, False otherwise.\n \"\"\"\n if num < 2:\n return False\n for i in range(2, int(num ** 0.5) + 1):\n if num % i == 0:\n return False\n return True\n\n count = 0\n for i in range(2, n):\n if is_prime(i):\n count += 1\n return count", "matching_cluster_idx": 8}, {"solution": "def count_Primes_nums(n):\n \"\"\"\n Counts the number of prime numbers less than the given non-negative number.\n\n Args:\n n (int): A non-negative number.\n\n Returns:\n int: The count of prime numbers less than the given number.\n\n \"\"\"\n def is_prime(num):\n \"\"\"\n Checks if a number is prime.\n\n Args:\n num (int): The number to check.\n\n Returns:\n bool: True if the number is prime, False otherwise.\n \"\"\"\n if num < 2:\n return False\n for i in range(2, int(num ** 0.5) + 1):\n if num % i == 0:\n return False\n return True\n\n count = 0\n for i in range(2, n):\n if is_prime(i):\n count += 1\n return count", "matching_cluster_idx": 8}, {"solution": "def count_Primes_nums(n):\n \"\"\"\n Counts the number of prime numbers less than the given non-negative number.\n \n Args:\n n (int): A non-negative number.\n \n Returns:\n int: The number of prime numbers less than n.\n \"\"\"\n if n < 2:\n return 0\n \n # Initialize a boolean array, prime, of size n+1\n prime = [True] * (n + 1)\n prime[0] = prime[1] = False\n \n # Iterate over the range from 2 to sqrt(n)\n for p in range(2, int(n ** 0.5) + 1):\n if prime[p]:\n # Mark as composite all the multiples of p\n for i in range(p * p, n + 1, p):\n prime[i] = False\n \n # Count the number of prime numbers\n count = 0\n for p in range(2, n):\n if prime[p]:\n count += 1\n \n return count", "matching_cluster_idx": 13}, {"solution": "def count_Primes_nums(n: int) -> int:\n \"\"\"\n This function takes in a non-negative number and returns the number of prime numbers less than the given non-negative number.\n \n Parameters:\n n (int): A non-negative number.\n \n Returns:\n int: The number of prime numbers less than n.\n \"\"\"\n \n def is_prime(num: int) -> bool:\n \"\"\"\n This function checks if a number is prime.\n \n Parameters:\n num (int): The number to be checked.\n \n Returns:\n bool: True if the number is prime, False otherwise.\n \"\"\"\n if num < 2:\n return False\n for i in range(2, int(num ** 0.5) + 1):\n if num % i == 0:\n return False\n return True\n\n count = 0\n for i in range(2, n):\n if is_prime(i):\n count += 1\n return count", "matching_cluster_idx": 8}, {"solution": "def count_Primes_nums(n):\n \"\"\"\n Returns the count of prime numbers less than the given number n.\n\n Args:\n n (int): A non-negative number.\n\n Returns:\n int: The number of prime numbers less than n.\n \"\"\"\n def is_prime(num):\n \"\"\"\n Checks if a number is prime.\n\n Args:\n num (int): A positive number.\n\n Returns:\n bool: True if num is prime, False otherwise.\n \"\"\"\n if num < 2:\n return False\n for i in range(2, int(num ** 0.5) + 1):\n if num % i == 0:\n return False\n return True\n\n count = 0\n for i in range(2, n):\n if is_prime(i):\n count += 1\n return count", "matching_cluster_idx": 8}, {"solution": "def count_Primes_nums(n: int) -> int:\n \"\"\"\n This function counts the number of prime numbers less than the given non-negative number n.\n\n Args:\n n (int): A non-negative number.\n\n Returns:\n int: The number of prime numbers less than n.\n \"\"\"\n\n def is_prime(num: int) -> bool:\n \"\"\"\n Helper function to check if a number is prime.\n\n Args:\n num (int): The number to check.\n\n Returns:\n bool: True if the number is prime, False otherwise.\n \"\"\"\n if num < 2:\n return False\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n return False\n return True\n\n # Initialize a counter for prime numbers\n count = 0\n \n # Loop through all numbers less than n\n for num in range(2, n):\n # Check if the number is prime\n if is_prime(num):\n # If prime, increment the counter\n count += 1\n \n return count", "matching_cluster_idx": 8}, {"solution": "def count_Primes_nums(n: int) -> int:\n \"\"\"\n This function takes a non-negative number and returns the number of prime numbers less than the given number.\n\n Args:\n n (int): A non-negative number.\n\n Returns:\n int: The number of prime numbers less than n.\n \"\"\"\n \n def is_prime(num: int) -> bool:\n \"\"\"\n Checks if a number is prime.\n\n Args:\n num (int): A number to be checked.\n\n Returns:\n bool: True if the number is prime, False otherwise.\n \"\"\"\n if num < 2:\n return False\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n return False\n return True\n\n # Initialize a counter for prime numbers\n count = 0\n \n # Check all numbers less than n\n for i in range(2, n):\n if is_prime(i):\n count += 1\n \n return count", "matching_cluster_idx": 8}, {"solution": "def count_Primes_nums(n):\n \"\"\"\n Counts the number of prime numbers less than the given non-negative number.\n\n Args:\n n (int): A non-negative number.\n\n Returns:\n int: The count of prime numbers less than the given number.\n\n \"\"\"\n def is_prime(num):\n \"\"\"\n Checks if a number is prime.\n\n Args:\n num (int): The number to check.\n\n Returns:\n bool: True if the number is prime, False otherwise.\n \"\"\"\n if num < 2:\n return False\n for i in range(2, int(num ** 0.5) + 1):\n if num % i == 0:\n return False\n return True\n\n count = 0\n for i in range(2, n):\n if is_prime(i):\n count += 1\n return count", "matching_cluster_idx": 8}, {"solution": "def count_Primes_nums(num):\n \"\"\"\n This function counts the number of prime numbers less than the given non-negative number.\n \n Args:\n num (int): A non-negative number.\n \n Returns:\n int: The number of prime numbers less than the given number.\n \n Raises:\n ValueError: If the input number is not a non-negative integer.\n \"\"\"\n \n # Check if the input number is a non-negative integer\n if not isinstance(num, int) or num < 0:\n raise ValueError(\"Input must be a non-negative integer.\")\n \n # Initialize a counter for prime numbers\n prime_count = 0\n \n # Iterate over all numbers less than the given number\n for possiblePrime in range(2, num):\n \n # Assume number is prime until shown it is not\n isPrime = True\n \n # Iterate from 2 to the square root of the possible prime\n for num_to_check in range(2, int(possiblePrime ** 0.5) + 1):\n \n # If the number is divisible by any of the values in the range, it's not prime\n if possiblePrime % num_to_check == 0:\n isPrime = False\n break\n \n # If the number is prime, increment the counter\n if isPrime:\n prime_count += 1\n \n return prime_count", "matching_cluster_idx": 8}, {"solution": "def count_Primes_nums(n):\n \"\"\"\n This function counts the number of prime numbers less than the given non-negative number.\n \n Args:\n n (int): A non-negative number.\n \n Returns:\n int: The count of prime numbers less than n.\n \"\"\"\n \n def is_prime(num):\n \"\"\"\n Helper function to check if a number is prime.\n \n Args:\n num (int): The number to check.\n \n Returns:\n bool: True if the number is prime, False otherwise.\n \"\"\"\n if num < 2:\n return False\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n return False\n return True\n\n count = 0\n for i in range(2, n):\n if is_prime(i):\n count += 1\n return count", "matching_cluster_idx": 8}, {"solution": "def count_Primes_nums(n):\n \"\"\"\n This function counts the number of prime numbers less than a given non-negative number.\n \n Args:\n n (int): A non-negative number.\n \n Returns:\n int: The number of prime numbers less than n.\n \"\"\"\n def is_prime(num):\n \"\"\"\n Helper function to check if a number is prime.\n \n Args:\n num (int): The number to check.\n \n Returns:\n bool: True if the number is prime, False otherwise.\n \"\"\"\n if num < 2:\n return False\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n return False\n return True\n \n # Initialize count of primes\n count = 0\n \n # Iterate over all numbers less than n and check if they are prime\n for i in range(2, n):\n if is_prime(i):\n count += 1\n \n return count", "matching_cluster_idx": 8}, {"solution": "def count_Primes_nums(num):\n \"\"\"\n This function calculates the number of prime numbers less than the given non-negative number.\n\n Args:\n num (int): A non-negative number.\n\n Returns:\n int: The number of prime numbers less than num.\n\n \"\"\"\n def is_prime(n):\n \"\"\"\n Helper function to check if a number is prime.\n\n Args:\n n (int): The number to check.\n\n Returns:\n bool: True if the number is prime, False otherwise.\n \"\"\"\n if n <= 1:\n return False\n if n == 2:\n return True\n if n % 2 == 0:\n return False\n max_divisor = int(n**0.5) + 1\n for d in range(3, max_divisor, 2):\n if n % d == 0:\n return False\n return True\n\n count = 0\n for i in range(2, num):\n if is_prime(i):\n count += 1\n return count", "matching_cluster_idx": 10}]}, "Mbpp/265": {"dps": 68.83720930232559, "dps_norm": 82.5, "pass@1": 20.0, "profiled": [{"solution": "def list_split(lst, n):\n \"\"\"\n Splits a list into sublists of consecutive elements separated by every nth element.\n\n Args:\n lst (list): The input list to be split.\n n (int): The index at which to split the list.\n\n Returns:\n list: A list of lists where each sublist contains elements from the original list\n separated by every nth element.\n\n Example:\n >>> list_split(['a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j', 'k', 'l', 'm', 'n'], 3)\n [['a', 'd', 'g', 'j', 'm'], ['b', 'e', 'h', 'k', 'n'], ['c', 'f', 'i', 'l']]\n \"\"\"\n return [lst[i::n] for i in range(0, n)]", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n \"\"\"\n This function splits a list for every nth element.\n\n Args:\n lst (list): The input list to be split.\n n (int): The interval of splitting.\n\n Returns:\n list: A list of lists resulting from splitting.\n \"\"\"\n return [lst[i::n] for i in range(n)]", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n \"\"\"\n Split a list every nth element and return a list of resulting lists.\n \n Args:\n lst (list): The input list to be split.\n n (int): The interval at which the list should be split.\n \n Returns:\n list: A list of lists, each of which contains every nth element from the input list.\n \"\"\"\n return [lst[i::n] for i in range(n)]", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n \"\"\"\n Splits a list into sublists of every nth element.\n\n Args:\n lst (list): The list to be split.\n n (int): The interval of elements in each sublist.\n\n Returns:\n list: A list of sublists, each containing every nth element from the original list.\n \"\"\"\n return [lst[i::n] for i in range(n)]", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n \"\"\"\n This function splits a list for every nth element.\n\n Args:\n lst (list): The list to be split.\n n (int): The interval for splitting the list.\n\n Returns:\n list: A list of lists resulting from splitting the original list.\n \"\"\"\n return [lst[i::n] for i in range(n)]", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n \"\"\"\n Splits a list into sublists where each sublist contains every nth element.\n\n Args:\n lst (list): The input list to be split.\n n (int): The interval of the split.\n\n Returns:\n list: A list of lists where each sublist contains every nth element.\n \"\"\"\n return [lst[i::n] for i in range(n)]", "matching_cluster_idx": 4}, {"solution": "def list_split(input_list, n):\n \"\"\"\n Splits a list every nth element and returns a list of the resulting lists.\n\n Args:\n input_list (list): The list to be split.\n n (int): The interval at which the list is split.\n\n Returns:\n list: A list of lists where each sublist contains every nth element from the input list.\n\n Example:\n >>> list_split(['a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j', 'k', 'l', 'm', 'n'], 3)\n [['a', 'd', 'g', 'j', 'm'], ['b', 'e', 'h', 'k', 'n'], ['c', 'f', 'i', 'l']]\n \"\"\"\n return [input_list[i::n] for i in range(n)]", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n \"\"\"\n Splits a list for every nth element.\n \n Args:\n lst (list): The list to be split.\n n (int): The interval for splitting.\n \n Returns:\n list: A list of lists, where each sublist contains elements from the original list at every nth index.\n \"\"\"\n return [lst[i::n] for i in range(n)]", "matching_cluster_idx": 4}, {"solution": "def list_split(input_list, n):\n \"\"\"\n This function takes a list and an integer n and splits the list every nth element.\n\n Args:\n input_list (list): The input list to be split.\n n (int): The interval of splitting the list.\n\n Returns:\n list: A list of lists, each containing every nth element from the input list.\n \"\"\"\n return [input_list[i::n] for i in range(n)]", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n \"\"\"\n Splits a list into a list of lists where each sublist contains every nth element.\n\n Args:\n lst (list): The input list.\n n (int): The interval between elements in the sublists.\n\n Returns:\n list: A list of sublists with every nth element.\n \"\"\"\n return [lst[i::n] for i in range(n)]", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n \"\"\"\n Splits the input list into sublists of every nth element.\n \n Args:\n lst (list): The input list.\n n (int): The interval to split the list.\n \n Returns:\n list: A list of sublists, each containing every nth element of the input list.\n \"\"\"\n return [lst[i::n] for i in range(n)]", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n \"\"\"\n Split a list into sublists at every nth position.\n\n Args:\n lst (list): The list to be split.\n n (int): The interval to split the list.\n\n Returns:\n list: A list of sublists.\n\n \"\"\"\n return [lst[i::n] for i in range(0, n)]", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n \"\"\"\n Splits a list for every nth element.\n\n Args:\n lst (list): The input list to be split.\n n (int): The interval to split the list.\n\n Returns:\n list: A list of lists representing the split input list.\n \"\"\"\n return [lst[i::n] for i in range(n)]\nlst = ['a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j', 'k', 'l', 'm', 'n']\nn = 3", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n \"\"\"\n This function splits a list into a list of lists of every nth element.\n \n Args:\n lst (list): The input list to be split.\n n (int): The step of splitting.\n \n Returns:\n list: A list of lists where every nth element from the original list is in a sublist.\n \"\"\"\n return [lst[i::n] for i in range(n)]", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n \"\"\"\n Split a list for every nth element.\n\n Args:\n lst (list): The list to be split.\n n (int): The interval for splitting the list.\n\n Returns:\n list: A list of lists, each containing every nth element from the original list.\n \"\"\"\n return [[lst[i] for i in range(j, len(lst), n)] for j in range(n)]", "matching_cluster_idx": 3}, {"solution": "def list_split(lst, n):\n \"\"\"\n This function takes in a list and an integer n, then splits the list \n every nth element and returns a list of the resulting lists.\n \n Args:\n lst (list): The input list to be split\n n (int): The index at which to split the list\n \n Returns:\n list: A list of lists, each being the sub-list from the input list \n split every nth element\n \"\"\"\n return [lst[i::n] for i in range(n)]", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n \"\"\"\n Splits a list for every nth element.\n \n Args:\n lst (list): The input list.\n n (int): The interval at which to split the list.\n \n Returns:\n list: A list of lists, where each sublist contains every nth element from the input list.\n \"\"\"\n return [lst[i::n] for i in range(n)]", "matching_cluster_idx": 4}, {"solution": "def list_split(input_list, n):\n \"\"\"\n Splits a list for every nth element.\n\n Args:\n input_list (list): The input list to be split.\n n (int): The interval at which the list is split.\n\n Returns:\n list: A list of lists, where each sublist contains elements from the input list at intervals of n.\n\n Raises:\n TypeError: If input_list is not a list or n is not an integer.\n ValueError: If n is less than or equal to 0.\n \"\"\"\n if not isinstance(input_list, list) or not isinstance(n, int):\n raise TypeError(\"Invalid input type. Expected a list and an integer.\")\n if n <= 0:\n raise ValueError(\"Invalid split interval. n must be greater than 0.\")\n\n return [input_list[i::n] for i in range(n)]", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n \"\"\"\n This function takes a list and an integer n and splits the list into sublists\n of every nth element.\n\n Args:\n lst (list): The input list to be split.\n n (int): The interval for splitting the list.\n\n Returns:\n list: A list of lists, where each sublist contains elements from the original list\n at every nth position.\n \"\"\"\n return [lst[i::n] for i in range(n)]", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n \"\"\"\n Splits a list into sublists where each sublist contains nth elements from the original list.\n\n Args:\n lst (list): The list to be split.\n n (int): The interval at which to split the list.\n\n Returns:\n list: A list of lists where each sublist contains nth elements from the original list.\n \"\"\"\n return [lst[i::n] for i in range(n)]", "matching_cluster_idx": 4}]}, "Mbpp/281": {"dps": 94.0, "dps_norm": 81.81818181818181, "pass@1": 100.0, "profiled": [{"solution": "def all_unique(lst):\n \"\"\"\n Check if all elements in a given list are unique.\n \n Args:\n lst (list): The list to be checked.\n \n Returns:\n bool: True if all elements are unique, False otherwise.\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n Check if all elements in a given list are unique.\n \n Args:\n lst (list): The list to check for uniqueness.\n \n Returns:\n bool: True if all elements are unique, False otherwise.\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n This function checks if all elements of a list are unique.\n\n Args:\n lst (list): The input list to be checked.\n\n Returns:\n bool: True if all elements in the list are unique, False otherwise.\n \"\"\"\n # Compare the length of the list to the length of a set created from the list.\n # A set in Python is an unordered collection of unique elements.\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n Returns True if all elements in the given list are unique, False otherwise.\n \n Args:\n lst (list): The list to check for uniqueness.\n \n Returns:\n bool: True if all elements are unique, False otherwise.\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n Checks if all elements in the list are unique.\n\n Args:\n lst (list): The list to be checked.\n\n Returns:\n bool: True if all elements are unique, False otherwise.\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n This function checks if all elements in a given list are unique.\n \n Args:\n lst (list): A list of elements to check for uniqueness.\n \n Returns:\n bool: True if all elements in the list are unique, False otherwise.\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n Checks if all elements in a given list are unique.\n \n Args:\n lst (list): The input list to check for uniqueness.\n \n Returns:\n bool: True if all elements are unique, False otherwise.\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n Check if all elements in a list are unique.\n\n Args:\n lst (list): The input list to check for uniqueness.\n\n Returns:\n bool: True if all elements in the list are unique, False otherwise.\n\n Example:\n >>> all_unique([1,2,3])\n True\n >>> all_unique([1,2,2])\n False\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n Checks if all elements in a list are unique.\n\n Args:\n lst (list): The input list to be checked.\n\n Returns:\n bool: True if all elements are unique, False otherwise.\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n Check if all elements in a given list are unique.\n\n Args:\n lst (list): Input list to be checked.\n\n Returns:\n bool: True if all elements are unique, False otherwise.\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n This function checks if all elements in a given list are unique.\n \n Args:\n lst (list): The list to check.\n \n Returns:\n bool: True if all elements are unique, False otherwise.\n \"\"\"\n # Convert the list to a set, which automatically removes duplicates\n # If the length of the original list is equal to the length of the set, then all elements were unique\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n Checks if all elements in a given list are unique.\n\n Args:\n lst (list): The input list to check for uniqueness.\n\n Returns:\n bool: True if all elements are unique, False otherwise.\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n Check if all elements in a given list are unique.\n\n Args:\n lst (list): The list to check.\n\n Returns:\n bool: True if all elements are unique, False otherwise.\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n Checks if all elements in a given list are unique.\n\n Args:\n lst (list): The list to check.\n\n Returns:\n bool: True if all elements are unique, False otherwise.\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n Checks if all elements in a list are unique.\n\n Args:\n lst (list): The input list to be checked.\n\n Returns:\n bool: True if all elements are unique, False otherwise.\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n Checks if all elements in a given list are unique.\n\n Args:\n lst (list): The input list to check.\n\n Returns:\n bool: True if all elements are unique, False otherwise.\n \"\"\"\n # Convert the list to a set, which automatically removes duplicates\n # If the lengths of the list and the set are equal, then the list had no duplicates\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n Checks if all elements in a given list are unique.\n\n Args:\n lst (list): The list to check for uniqueness.\n\n Returns:\n bool: True if all elements are unique, False otherwise.\n \"\"\"\n # Convert the list to a set, which automatically removes duplicates\n # A set cannot contain duplicate elements, so if it contains all elements from the list, they are unique\n return len(set(lst)) == len(lst)", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n Checks if all elements of a given list are unique.\n\n Args:\n lst (list): Input list\n\n Returns:\n bool: True if all elements are unique, False otherwise\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n Checks if all elements in the given list are unique.\n \n Args:\n lst (list): The input list.\n \n Returns:\n bool: True if all elements are unique, False otherwise.\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n This function checks if all elements of a given list are unique.\n\n Args:\n lst (list): The list to check for uniqueness.\n\n Returns:\n bool: True if all elements are unique, False otherwise.\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}]}, "Mbpp/296": {"dps": 95.12820512820512, "dps_norm": 97.5, "pass@1": 52.0, "profiled": [{"solution": "def get_Inv_Count(arr):\n \"\"\"\n Function to count the number of inversions in a given array.\n \n Args:\n arr (list): The input array for which inversions are to be counted.\n \n Returns:\n int: The total number of inversions in the array.\n \"\"\"\n \n if len(arr) <= 1:\n return 0\n \n mid = len(arr) // 2\n left_arr = arr[:mid]\n right_arr = arr[mid:]\n \n left_count = get_Inv_Count(left_arr)\n right_count = get_Inv_Count(right_arr)\n \n merged_count, i, j, k = 0, 0, 0, 0\n \n # Merge smaller elements first\n while i < len(left_arr) and j < len(right_arr):\n if left_arr[i] <= right_arr[j]:\n arr[k] = left_arr[i]\n i += 1\n else:\n arr[k] = right_arr[j]\n merged_count += len(left_arr) - i\n j += 1\n k += 1\n \n # If there are remaining elements in the left or right array, append them to arr\n while i < len(left_arr):\n arr[k] = left_arr[i]\n i += 1\n k += 1\n while j < len(right_arr):\n arr[k] = right_arr[j]\n j += 1\n k += 1\n \n return left_count + right_count + merged_count", "matching_cluster_idx": 5}, {"solution": "def merge_sort(arr):\n \"\"\"\n Helper function to calculate inversions using merge sort.\n\n Args:\n arr: A list of integers.\n\n Returns:\n A list of sorted integers and the inversion count.\n \"\"\"\n if len(arr) <= 1:\n return arr, 0\n mid = len(arr) // 2\n left, left_inv = merge_sort(arr[:mid])\n right, right_inv = merge_sort(arr[mid:])\n merged, merge_inv = merge(left, right)\n return merged, left_inv + right_inv + merge_inv\ndef merge(left, right):\n \"\"\"\n Merge two sorted lists and count inversions.\n\n Args:\n left: The left sorted list.\n right: The right sorted list.\n\n Returns:\n A sorted list and the inversion count.\n \"\"\"\n inv_count = 0\n merged = []\n i = j = 0\n while i < len(left) and j < len(right):\n if left[i] <= right[j]:\n merged.append(left[i])\n i += 1\n else:\n merged.append(right[j])\n inv_count += len(left) - i\n j += 1\n merged += left[i:]\n merged += right[j:]\n return merged, inv_count\ndef get_Inv_Count(arr):\n \"\"\"\n Calculate the total inversion count for a given list.\n\n Args:\n arr: A list of integers.\n\n Returns:\n The total inversion count.\n \"\"\"\n arr, inv_count = merge_sort(arr)\n return inv_count", "matching_cluster_idx": 5}, {"solution": "def get_Inv_Count(arr):\n \"\"\"\n This function takes a list of integers as input and returns the total number of inversions in the array.\n \n An inversion is a pair (a, b) where a > b but a appears after b in the array.\n \n Args:\n arr (list): A list of integers.\n \n Returns:\n int: The number of inversions in the array.\n \"\"\"\n def merge_sort(left, right):\n # Base case: If the left and right pointers point to the same index, there are no inversions.\n if left == right:\n return 0\n \n mid = (left + right) // 2\n left_inv_count = merge_sort(left, mid)\n right_inv_count = merge_sort(mid + 1, right)\n \n # Merge the two sorted halves and count the inversions.\n merged_inv_count = merge(left, mid, right)\n return left_inv_count + right_inv_count + merged_inv_count\n \n def merge(left, mid, right):\n # Create temporary lists for the left and right halves.\n left_list = arr[left:mid + 1]\n right_list = arr[mid + 1:right + 1]\n \n i, j = 0, 0\n k = left\n \n inv_count = 0\n while i < len(left_list) and j < len(right_list):\n if left_list[i] <= right_list[j]:\n arr[k] = left_list[i]\n i += 1\n else:\n arr[k] = right_list[j]\n inv_count += len(left_list) - i # Count inversions.\n j += 1\n k += 1\n \n while i < len(left_list):\n arr[k] = left_list[i]\n i += 1\n k += 1\n \n while j < len(right_list):\n arr[k] = right_list[j]\n j += 1\n k += 1\n \n return inv_count\n \n return merge_sort(0, len(arr) - 1)", "matching_cluster_idx": 5}, {"solution": "def get_Inv_Count(arr):\n \"\"\"\n This function counts the number of inversions in a given array.\n An inversion is a pair of elements in the array where a larger element appears before a smaller one.\n\n Parameters:\n arr (list): The input list to count inversions from.\n\n Returns:\n int: The number of inversions in the input array.\n\n \"\"\"\n def merge_sort(arr):\n # Base case: If the array is of size 1 or less, return the array\n if len(arr) <= 1:\n return arr, 0\n\n mid = len(arr) // 2\n left, left_count = merge_sort(arr[:mid])\n right, right_count = merge_sort(arr[mid:])\n\n merged, merge_count = merge(left, right)\n return merged, left_count + right_count + merge_count\n\n def merge(left, right):\n merged = []\n left_index = 0\n right_index = 0\n inversions = 0\n while left_index < len(left) and right_index < len(right):\n if left[left_index] <= right[right_index]:\n merged.append(left[left_index])\n left_index += 1\n else:\n merged.append(right[right_index])\n inversions += len(left) - left_index\n right_index += 1\n merged.extend(left[left_index:])\n merged.extend(right[right_index:])\n return merged, inversions\n\n _, inversions_count = merge_sort(arr)\n return inversions_count", "matching_cluster_idx": 5}, {"solution": "def merge_sort(arr):\n \"\"\"Merge sort helper function to count inversions.\"\"\"\n if len(arr) <= 1:\n return arr, 0\n \n mid = len(arr) // 2\n left_half, left_inv = merge_sort(arr[:mid])\n right_half, right_inv = merge_sort(arr[mid:])\n\n merged, merge_inv = merge(left_half, right_half)\n\n return merged, left_inv + right_inv + merge_inv\ndef merge(left, right):\n \"\"\"Merge two sorted arrays while counting inversions.\"\"\"\n merged = []\n left_index = 0\n right_index = 0\n inv_count = 0\n\n while left_index < len(left) and right_index < len(right):\n if left[left_index] <= right[right_index]:\n merged.append(left[left_index])\n left_index += 1\n else:\n merged.append(right[right_index])\n inv_count += len(left) - left_index\n right_index += 1\n\n merged.extend(left[left_index:])\n merged.extend(right[right_index:])\n\n return merged, inv_count\ndef get_Inv_Count(arr):\n \"\"\"\n Function to count inversions in an array.\n\n Args:\n arr (list): The input list to count inversions from.\n\n Returns:\n int: The number of inversions in the input list.\n \"\"\"\n arr, inv_count = merge_sort(arr)\n return inv_count", "matching_cluster_idx": 5}, {"solution": "def get_Inv_Count(arr):\n \"\"\"\n This function counts the number of inversions in an array.\n An inversion is a pair of elements in the given array where the element at the larger index has a value less than the element at the smaller index.\n\n Args:\n arr (list): Input list of elements\n\n Returns:\n int: The total number of inversions in the given array.\n \"\"\"\n def merge_sort(arr):\n if len(arr) <= 1:\n return arr, 0\n\n mid = len(arr) // 2\n left, left_inv = merge_sort(arr[:mid])\n right, right_inv = merge_sort(arr[mid:])\n merged, merge_inv = merge(left, right)\n return merged, left_inv + right_inv + merge_inv\n\n def merge(left, right):\n merged = []\n inversions = 0\n i = j = 0\n\n while i < len(left) and j < len(right):\n if left[i] <= right[j]:\n merged.append(left[i])\n i += 1\n else:\n merged.append(right[j])\n inversions += len(left) - i # Counting inversions\n j += 1\n\n merged += left[i:]\n merged += right[j:]\n return merged, inversions\n\n sorted_arr, inv_count = merge_sort(arr)\n return inv_count", "matching_cluster_idx": 5}, {"solution": "def get_Inv_Count(arr):\n \"\"\"\n Count the number of inversions in a given array.\n\n Args:\n arr (list): The input list of integers.\n\n Returns:\n int: The number of inversions in the array.\n \"\"\"\n def merge_sort(arr):\n \"\"\"\n Helper function to sort the array using the merge sort algorithm.\n \"\"\"\n if len(arr) <= 1:\n return arr, 0\n mid = len(arr) // 2\n left, inv_left = merge_sort(arr[:mid])\n right, inv_right = merge_sort(arr[mid:])\n merged, inv_merge = merge(left, right)\n return merged, inv_left + inv_right + inv_merge\n\n def merge(left, right):\n \"\"\"\n Merge two sorted lists into one sorted list and count inversions.\n \"\"\"\n merged = []\n i = j = inv = 0\n while i < len(left) and j < len(right):\n if left[i] <= right[j]:\n merged.append(left[i])\n i += 1\n else:\n merged.append(right[j])\n inv += len(left) - i # all remaining elements are larger\n j += 1\n merged += left[i:]\n merged += right[j:]\n return merged, inv\n\n _, inv_count = merge_sort(arr)\n return inv_count", "matching_cluster_idx": 5}, {"solution": "def mergeSort(arr):\n \"\"\"\n Merge Sort function to count and sort the array.\n Args:\n arr (list): Input list of integers.\n\n Returns:\n tuple: Tuple containing the sorted array and inversion count.\n \"\"\"\n if len(arr) <= 1:\n return arr, 0\n\n mid = len(arr) // 2\n left, left_inv = mergeSort(arr[:mid])\n right, right_inv = mergeSort(arr[mid:])\n\n merged, merge_inv = merge(left, right)\n\n return merged, left_inv + right_inv + merge_inv\ndef merge(left, right):\n \"\"\"\n Merge two sorted lists into a single sorted list, counting inversions.\n Args:\n left (list): First sorted list of integers.\n right (list): Second sorted list of integers.\n\n Returns:\n tuple: Tuple containing the merged sorted list and inversion count.\n \"\"\"\n merged = []\n inversions = 0\n left_index = 0\n right_index = 0\n\n while left_index < len(left) and right_index < len(right):\n if left[left_index] <= right[right_index]:\n merged.append(left[left_index])\n left_index += 1\n else:\n merged.append(right[right_index])\n inversions += len(left) - left_index\n right_index += 1\n\n merged.extend(left[left_index:])\n merged.extend(right[right_index:])\n return merged, inversions\ndef get_Inv_Count(arr):\n \"\"\"\n Function to get the inversion count of an array.\n Args:\n arr (list): Input list of integers.\n\n Returns:\n int: Inversion count in the array.\n \"\"\"\n _, inversions = mergeSort(arr)\n return inversions", "matching_cluster_idx": 5}, {"solution": "def mergeSort(arr):\n \"\"\"\n Helper function for merge sort.\n This function returns the count of inversions in the array.\n \"\"\"\n if len(arr) <= 1:\n return (arr, 0)\n \n mid = len(arr) // 2\n left, left_inv = mergeSort(arr[:mid])\n right, right_inv = mergeSort(arr[mid:])\n merged, merge_inv = merge(left, right)\n \n return merged, left_inv + right_inv + merge_inv\ndef merge(left, right):\n \"\"\"\n Merge two sorted lists into one and count the number of inversions.\n \"\"\"\n merged = []\n inv_count = 0\n i = j = 0\n \n while i < len(left) and j < len(right):\n if left[i] <= right[j]:\n merged.append(left[i])\n i += 1\n else:\n merged.append(right[j])\n inv_count += len(left) - i # Inversion is left[i..] and right[:j]\n j += 1\n \n merged += left[i:]\n merged += right[j:]\n \n return merged, inv_count\ndef get_Inv_Count(arr):\n \"\"\"\n Return the count of inversions in the array.\n \"\"\"\n return mergeSort(arr)[1]", "matching_cluster_idx": 5}, {"solution": "def merge_sort(arr):\n \"\"\"\n Divide the array into two halves, recursively sort each half and merge them back together.\n While merging, count inversions\n \"\"\"\n if len(arr) <= 1:\n return arr, 0\n\n mid = len(arr) // 2\n left, left_inv = merge_sort(arr[:mid])\n right, right_inv = merge_sort(arr[mid:])\n\n merged, merge_inv = merge(left, right)\n return merged, left_inv + right_inv + merge_inv\ndef merge(left, right):\n \"\"\"\n Merge two sorted lists, count inversions while merging\n \"\"\"\n merged = []\n inv = 0\n\n i = j = 0\n while i < len(left) and j < len(right):\n if left[i] <= right[j]:\n merged.append(left[i])\n i += 1\n else:\n merged.append(right[j])\n inv += len(left) - i # count inversions\n j += 1\n\n # append remaining elements, if any\n merged += left[i:]\n merged += right[j:]\n\n return merged, inv\ndef get_Inv_Count(arr):\n \"\"\"\n Count inversions in an array using merge sort\n \"\"\"\n _, inv = merge_sort(arr)\n return inv", "matching_cluster_idx": 5}, {"solution": "def get_Inv_Count(arr):\n \"\"\"\n Count the number of inversions in an array.\n\n An inversion is a pair of elements where the first is greater than the second.\n\n Args:\n arr (list): The input array.\n\n Returns:\n int: The number of inversions in the array.\n \"\"\"\n def merge_sort(arr):\n # Base case: If the array has 1 or 0 elements, it is already sorted.\n if len(arr) <= 1:\n return arr, 0\n\n # Divide the array into two halves.\n mid = len(arr) // 2\n left, left_inversions = merge_sort(arr[:mid])\n right, right_inversions = merge_sort(arr[mid:])\n\n # Merge and count the inversions.\n merged, merge_inversions = merge(left, right)\n return merged, left_inversions + right_inversions + merge_inversions\n\n def merge(left, right):\n merged = []\n inversions = 0\n while len(left) > 0 and len(right) > 0:\n if left[0] <= right[0]:\n merged.append(left.pop(0))\n else:\n merged.append(right.pop(0))\n inversions += len(left)\n merged += left\n merged += right\n return merged, inversions\n\n # Start the merge sort recursion.\n _, inversions = merge_sort(arr)\n return inversions", "matching_cluster_idx": 5}, {"solution": "def get_Inv_Count(arr):\n \"\"\"\n This function takes in a list of integers and counts the number of inversions in the list.\n \n Inversions are pairs of elements where a larger number appears before a smaller one. \n For example, in the list [1,20,6,4,5], 1 and 20, 1 and 6, 1 and 4, 1 and 5, 20 and 6, 20 and 4, and 20 and 5 are inversions.\n \n The time complexity of this function is O(n log n), where n is the number of elements in the input list.\n This is because we use a divide-and-conquer approach (merge sort) to sort the list, which has a time complexity of O(n log n).\n \"\"\"\n def merge_sort(arr):\n # Base case: If the list has one or zero elements, it is already sorted and there are no inversions.\n if len(arr) <= 1:\n return arr, 0\n \n mid = len(arr) // 2\n left_half = arr[:mid]\n right_half = arr[mid:]\n \n # Recursively sort the left and right halves.\n left, left_inv = merge_sort(left_half)\n right, right_inv = merge_sort(right_half)\n \n # Merge the sorted halves and count the number of inversions.\n merged, merged_inv = merge(left, right)\n \n # The total number of inversions is the sum of inversions in the left and right halves and inversions between them.\n return merged, left_inv + right_inv + merged_inv\n \n def merge(left, right):\n merged = []\n i = j = inv_count = 0\n \n while i < len(left) and j < len(right):\n if left[i] <= right[j]:\n merged.append(left[i])\n i += 1\n else:\n merged.append(right[j])\n j += 1\n inv_count += len(left) - i\n \n # Append the remaining elements from the left and right arrays.\n merged.extend(left[i:])\n merged.extend(right[j:])\n \n return merged, inv_count\n \n return merge_sort(arr)[1]", "matching_cluster_idx": 5}, {"solution": "def get_Inv_Count(arr):\n \"\"\"\n Function to count the number of inversions in an array.\n \n Inversions occur when two elements in the array are in the reverse order.\n\n Args:\n arr (list): The input list of integers.\n\n Returns:\n int: The number of inversions in the array.\n \"\"\"\n def merge_sort(arr):\n \"\"\"\n Helper function for merge sort.\n \"\"\"\n if len(arr) <= 1:\n return arr, 0\n\n mid = len(arr) // 2\n left, left_inv = merge_sort(arr[:mid])\n right, right_inv = merge_sort(arr[mid:])\n\n merged, merge_inv = merge(left, right)\n return merged, left_inv + right_inv + merge_inv\n\n def merge(left, right):\n \"\"\"\n Function to merge two sorted lists and count inversions.\n \"\"\"\n merged = []\n inv_count = 0\n i = j = 0\n\n while i < len(left) and j < len(right):\n if left[i] <= right[j]:\n merged.append(left[i])\n i += 1\n else:\n merged.append(right[j])\n inv_count += len(left) - i # Count inversions\n j += 1\n\n merged += left[i:]\n merged += right[j:]\n\n return merged, inv_count\n\n _, inv_count = merge_sort(arr)\n return inv_count", "matching_cluster_idx": 5}, {"solution": "def merge_sort(arr):\n \"\"\"\n Custom Merge Sort implementation to count inversions.\n \n Args:\n arr (list): The input list to sort and count inversions from.\n \n Returns:\n tuple: A tuple containing the sorted list and the inversion count.\n \"\"\"\n if len(arr) <= 1:\n return arr, 0\n \n mid = len(arr) // 2\n left, left_inv = merge_sort(arr[:mid])\n right, right_inv = merge_sort(arr[mid:])\n merged, merge_inv = merge(left, right)\n \n return merged, left_inv + right_inv + merge_inv\ndef merge(left, right):\n \"\"\"\n Merge two sorted lists and count inversions.\n \n Args:\n left (list): The first sorted list.\n right (list): The second sorted list.\n \n Returns:\n tuple: A tuple containing the merged list and the inversion count.\n \"\"\"\n inversions = 0\n result = []\n i = j = 0\n \n while i < len(left) and j < len(right):\n if left[i] <= right[j]:\n result.append(left[i])\n i += 1\n else:\n result.append(right[j])\n inversions += len(left) - i\n j += 1\n \n result.extend(left[i:])\n result.extend(right[j:])\n \n return result, inversions\ndef get_Inv_Count(arr):\n \"\"\"\n Count inversions in the array using merge sort.\n \n Args:\n arr (list): The input list to count inversions from.\n \n Returns:\n int: The inversion count.\n \"\"\"\n _, inv_count = merge_sort(arr)\n return inv_count", "matching_cluster_idx": 5}, {"solution": "def merge_sort(arr):\n \"\"\"\n This function takes an array, splits it into two halves,\n sorts them recursively and merges the two sorted halves.\n \n :param arr: Array to be sorted\n :return: A list of tuples containing the merged and sorted subarray elements and the inversion count\n \"\"\"\n if len(arr) <= 1:\n return (arr, 0)\n \n mid = len(arr) // 2\n left_half = arr[:mid]\n right_half = arr[mid:]\n \n # Recursively get the inversion counts for the left and right halves\n left_sorted, left_inv = merge_sort(left_half)\n right_sorted, right_inv = merge_sort(right_half)\n \n # Merge the two sorted halves\n merged, merge_inv = merge(left_sorted, right_sorted)\n \n return (merged, left_inv + right_inv + merge_inv)\ndef merge(left, right):\n \"\"\"\n This function merges two sorted lists into one sorted list.\n \n :param left: The first sorted list\n :param right: The second sorted list\n :return: A tuple containing the merged and sorted list and the inversion count\n \"\"\"\n merged = []\n inversion_count = 0\n left_index = 0\n right_index = 0\n \n while left_index < len(left) and right_index < len(right):\n if left[left_index] <= right[right_index]:\n merged.append(left[left_index])\n left_index += 1\n else:\n merged.append(right[right_index])\n # Count of inversions is the number of remaining elements in the left list\n inversion_count += len(left) - left_index\n right_index += 1\n \n # Append the remaining elements from the left and right lists\n merged.extend(left[left_index:])\n merged.extend(right[right_index:])\n \n return merged, inversion_count\ndef get_Inv_Count(arr):\n \"\"\"\n This function calculates the number of inversions in an array.\n \n :param arr: The input array\n :return: The number of inversions in the array\n \"\"\"\n _, inversion_count = merge_sort(arr)\n return inversion_count", "matching_cluster_idx": 5}, {"solution": "def get_Inv_Count(arr):\n \"\"\"\n This function counts the number of inversions in a given array.\n Inversion: For example, if the given array is [1,20,6,4,5], \n The inversion count is 5 as there are 5 ways to rearrange the array such that all the numbers are in the correct order.\n \n Parameters:\n arr (list): The input list of integers.\n \n Returns:\n int: The number of inversions in the array.\n \"\"\"\n def mergeSort(arr):\n \"\"\"\n This helper function implements merge sort and returns the count of inversions.\n \n Parameters:\n arr (list): The input list of integers.\n \n Returns:\n int: The count of inversions in the input list.\n \"\"\"\n if len(arr) <= 1:\n # If the array contains one or zero element then there are no inversions.\n return arr, 0\n else:\n mid = len(arr) // 2\n # Divide the array into two halves and recursively count inversions in each half.\n left_arr, inv_left = mergeSort(arr[:mid])\n right_arr, inv_right = mergeSort(arr[mid:])\n # Merge the two sorted halves and count the number of inversions.\n merged_arr, inv_merge = merge(left_arr, right_arr)\n return merged_arr, inv_left + inv_right + inv_merge\n \n def merge(left, right):\n \"\"\"\n This helper function merges two sorted lists and returns the merged list along with the inversion count.\n \n Parameters:\n left (list): The first list of integers.\n right (list): The second list of integers.\n \n Returns:\n tuple: The merged list and the number of inversions in the merged list.\n \"\"\"\n merged = []\n inversion = 0\n i, j = 0, 0\n while i < len(left) and j < len(right):\n if left[i] <= right[j]:\n merged.append(left[i])\n i += 1\n else:\n merged.append(right[j])\n inversion += len(left) - i # The inversion count is the length of the left array minus the current index i.\n j += 1\n # Append the remaining elements.\n merged.extend(left[i:])\n merged.extend(right[j:])\n return merged, inversion\n \n return mergeSort(arr)[1]", "matching_cluster_idx": 5}, {"solution": "def get_Inv_Count(arr):\n \"\"\"\n This function counts the number of inversions in a given list of numbers.\n \n An inversion is when a larger number appears before a smaller number in the list.\n \n This function uses the merge sort algorithm to count the inversions in the list.\n \"\"\"\n def merge_sort(arr):\n if len(arr) <= 1:\n return arr, 0\n mid = len(arr) // 2\n left, left_count = merge_sort(arr[:mid])\n right, right_count = merge_sort(arr[mid:])\n merged, merge_count = merge(left, right)\n return merged, left_count + right_count + merge_count\n\n def merge(left, right):\n merged = []\n i, j = 0, 0\n count = 0\n while i < len(left) and j < len(right):\n if left[i] <= right[j]:\n merged.append(left[i])\n i += 1\n else:\n merged.append(right[j])\n count += len(left) - i\n j += 1\n merged.extend(left[i:])\n merged.extend(right[j:])\n return merged, count\n\n return merge_sort(arr)[1]", "matching_cluster_idx": 5}, {"solution": "def get_Inv_Count(arr):\n \"\"\"\n Counts inversions in the given array.\n \n :param arr: A list of integers.\n :return: The total number of inversions in the array.\n \"\"\"\n n = len(arr)\n inv_count = 0\n\n for i in range(n):\n for j in range(i+1, n):\n # If the current element is greater than the next element, it's an inversion.\n if arr[i] > arr[j]:\n inv_count += 1\n\n return inv_count", "matching_cluster_idx": 2}, {"solution": "def merge_sort(arr):\n \"\"\" Merge sort algorithm to sort the array and count the inversions\"\"\"\n if len(arr) <= 1:\n return arr, 0\n mid = len(arr) // 2\n left, left_inv = merge_sort(arr[:mid])\n right, right_inv = merge_sort(arr[mid:])\n merged, merge_inv = merge(left, right)\n return merged, left_inv + right_inv + merge_inv\ndef merge(left, right):\n \"\"\" Merge two sorted lists and count inversions\"\"\"\n merged = []\n inversions = 0\n left_index, right_index = 0, 0\n\n # Merge smaller elements first\n while left_index < len(left) and right_index < len(right):\n if left[left_index] <= right[right_index]:\n merged.append(left[left_index])\n left_index += 1\n else:\n merged.append(right[right_index])\n inversions += len(left) - left_index\n right_index += 1\n\n # If there are remaining elements in left or right, append them to merged list\n merged.extend(left[left_index:])\n merged.extend(right[right_index:])\n\n return merged, inversions\ndef get_Inv_Count(arr):\n \"\"\" Get the inversion count for an array\"\"\"\n return merge_sort(arr)[1]", "matching_cluster_idx": 5}, {"solution": "def mergeSort(arr, inv_count):\n \"\"\"\n Recursive function to sort the array using merge sort algorithm and count inversions\n \"\"\"\n if len(arr) <= 1:\n return arr, inv_count\n\n mid = len(arr) // 2\n left_half, left_inv = mergeSort(arr[:mid], inv_count)\n right_half, right_inv = mergeSort(arr[mid:], inv_count)\n merged, merge_inv = merge(left_half, right_half)\n\n return merged, left_inv + right_inv + merge_inv\ndef merge(left, right):\n \"\"\"\n Merge two lists and count inversions\n \"\"\"\n merged = []\n left_index = 0\n right_index = 0\n inv_count = 0\n\n # Merge smaller elements first\n while left_index < len(left) and right_index < len(right):\n if left[left_index] <= right[right_index]:\n merged.append(left[left_index])\n left_index += 1\n else:\n merged.append(right[right_index])\n inv_count += len(left) - left_index # Count inversions\n right_index += 1\n\n # If there are remaining elements\n merged.extend(left[left_index:])\n merged.extend(right[right_index:])\n return merged, inv_count\ndef get_Inv_Count(arr):\n \"\"\"\n Function to count inversions in an array\n \"\"\"\n return mergeSort(arr, 0)[1]", "matching_cluster_idx": 5}]}, "Mbpp/308": {"dps": 54.55172413793104, "dps_norm": 55.833333333333336, "pass@1": 76.0, "profiled": [{"solution": "def large_product(list1, list2, n):\n \"\"\"\n This function finds the n largest products from two given lists by selecting one factor from each list.\n \n Args:\n list1 (list): The first list of numbers.\n list2 (list): The second list of numbers.\n n (int): The number of largest products to find.\n \n Returns:\n list: A list of the n largest products.\n \"\"\"\n \n # Combine the two lists and calculate the product of each pair\n products = [(x, y) for x in list1 for y in list2]\n \n # Sort the products in descending order and select the top n\n products.sort(key=lambda x: x[0]*x[1], reverse=True)\n \n # Return the n largest products\n return [x[0]*x[1] for x in products[:n]]", "matching_cluster_idx": 2}, {"solution": "def large_product(list1, list2, n):\n \"\"\"\n Returns the specified number of largest products from two given lists, selecting one factor from each list.\n \n Args:\n list1 (list): The first list of numbers.\n list2 (list): The second list of numbers.\n n (int): The number of largest products to find.\n \n Returns:\n list: A list of the n largest products.\n \"\"\"\n # Combine the two lists\n combined = [(x, y) for x in list1 for y in list2]\n \n # Sort the combined list in descending order\n combined.sort(key=lambda x: x[0]*x[1], reverse=True)\n \n # Return the first n products\n return [x*y for x, y in combined[:n]]", "matching_cluster_idx": 2}, {"solution": "def large_product(list1, list2, n):\n \"\"\"\n Find the n largest products from two given lists, one factor from each list.\n\n Args:\n list1 (list): The first list of numbers.\n list2 (list): The second list of numbers.\n n (int): The number of largest products to find.\n\n Returns:\n list: A list of n largest products from the combinations of two given lists.\n \"\"\"\n # Check if n is larger than the total number of elements in both lists\n if n > len(list1) * len(list2):\n raise ValueError(\"n is larger than the total number of elements in both lists\")\n\n # Combine the two lists into pairs\n pairs = [(x, y) for x in list1 for y in list2]\n\n # Sort the pairs by their product in descending order\n pairs.sort(key=lambda x: x[0] * x[1], reverse=True)\n\n # Return the n largest products\n return [pair[0] * pair[1] for pair in pairs[:n]]", "matching_cluster_idx": 2}, {"solution": "def large_product(list1, list2, num):\n \"\"\"\n This function returns a list of the num largest products from two given lists.\n \n Args:\n list1 (list): The first list of numbers.\n list2 (list): The second list of numbers.\n num (int): The number of largest products to return.\n \n Returns:\n list: A list of the num largest products from the cross product of the two input lists.\n \"\"\"\n \n # Generate the cross product of the two lists\n products = [x * y for x in list1 for y in list2]\n \n # Sort the products in descending order\n products.sort(reverse=True)\n \n # Return the num largest products\n return products[:num]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, k):\n \"\"\"\n This function takes in two lists and an integer k. It returns a list of the k largest products, \n where each product is the multiplication of one element from list1 and one element from list2.\n\n Args:\n list1 (list): The first list of numbers.\n list2 (list): The second list of numbers.\n k (int): The number of largest products to return.\n\n Returns:\n list: A list of k largest products.\n \"\"\"\n # Calculate all possible products and store them in a list of tuples\n products = [(x, y) for x in list1 for y in list2]\n \n # Sort the products in descending order\n products.sort(key=lambda x: x[0]*x[1], reverse=True)\n \n # Return the first k products\n return [product[0]*product[1] for product in products[:k]]", "matching_cluster_idx": 2}, {"solution": "def large_product(list1, list2, n):\n \"\"\"\n This function finds the specified number of largest products from two given lists, \n selecting one factor from each list.\n \n Args:\n list1 (list): The first list of numbers.\n list2 (list): The second list of numbers.\n n (int): The number of largest products to find.\n \n Returns:\n list: A list of the n largest products.\n \"\"\"\n # Combine the two lists to store all possible products\n products = [(x, y) for x in list1 for y in list2]\n \n # Sort the products in descending order\n products.sort(key=lambda x: x[0] * x[1], reverse=True)\n \n # Return the top n products\n return [x * y for x, y in products[:n]]", "matching_cluster_idx": 2}, {"solution": "def large_product(list1, list2, n):\n \"\"\"\n Finds the n largest products from two lists by selecting one factor from each list.\n \n Args:\n list1 (list): The first list of numbers.\n list2 (list): The second list of numbers.\n n (int): The number of largest products to find.\n \n Returns:\n list: A list of the n largest products.\n \"\"\"\n \n # Combine the two lists and multiply corresponding elements together\n products = [a * b for a in list1 for b in list2]\n \n # Sort the products in descending order\n products.sort(reverse=True)\n \n # Return the n largest products\n return products[:n]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n \"\"\"\n Returns a list of the n largest products formed by choosing one factor from each list.\n\n Args:\n list1 (list): The first list of numbers.\n list2 (list): The second list of numbers.\n n (int): The number of largest products to return.\n\n Returns:\n list: A list of the n largest products.\n \"\"\"\n # Combine the two lists and sort the products in descending order\n products = [x * y for x in list1 for y in list2]\n products.sort(reverse=True)\n \n # Return the n largest products\n return products[:n]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n \"\"\"\n Returns the n largest products of one element from each list.\n\n Args:\n list1 (list): The first list of numbers.\n list2 (list): The second list of numbers.\n n (int): The number of largest products to return.\n\n Returns:\n list: A list of the n largest products.\n \"\"\"\n # Combine elements from both lists, pair by pair\n pairs = [(x, y) for x in list1 for y in list2]\n \n # Sort the pairs in descending order based on their product\n pairs.sort(key=lambda x: x[0]*x[1], reverse=True)\n \n # Return the n largest products\n return [pair[0]*pair[1] for pair in pairs[:n]]", "matching_cluster_idx": 2}, {"solution": "def large_product(list1, list2, n):\n \"\"\"\n Returns the n largest products of pairs from two given lists.\n\n Args:\n list1 (list): The first list of numbers.\n list2 (list): The second list of numbers.\n n (int): The number of largest products to find.\n\n Returns:\n list: A list of the n largest products, with one factor from each list.\n \"\"\"\n # Initialize an empty list to store the products\n products = [(x, y) for x in list1 for y in list2]\n \n # Sort the list of products in descending order\n products.sort(key=lambda x: x[0]*x[1], reverse=True)\n \n # Return the n largest products\n return [product[0]*product[1] for product in products[:n]]", "matching_cluster_idx": 2}, {"solution": "def large_product(list1, list2, n):\n \"\"\"\n This function finds the specified number of largest products from two given lists, \n selecting one factor from each list.\n\n Args:\n list1 (list): The first list of numbers.\n list2 (list): The second list of numbers.\n n (int): The number of largest products to find.\n\n Returns:\n list: A list of the n largest products.\n\n \"\"\"\n \n # Generate all possible products\n products = [x * y for x in list1 for y in list2]\n \n # Sort the products in descending order and select the n largest ones\n products = sorted(products, reverse=True)[:n]\n \n return products", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n \"\"\"\n This function takes two lists and the desired number of products as input. It returns the n largest products that can be formed by taking one number from each list.\n\n Args:\n list1 (list): The first list of numbers.\n list2 (list): The second list of numbers.\n n (int): The number of largest products to return.\n\n Returns:\n list: A list of the n largest products.\n\n \"\"\"\n # Combine the two lists into one with the product of each pair\n products = [(x, y) for x in list1 for y in list2]\n\n # Sort the products in descending order\n products.sort(key=lambda x: x[0] * x[1], reverse=True)\n\n # Return the n largest products\n return [product[0] * product[1] for product in products[:n]]", "matching_cluster_idx": 2}, {"solution": "def large_product(list1, list2, n):\n \"\"\"\n Returns the n largest products from two lists by selecting one factor from each list.\n\n Args:\n list1 (list): The first list of numbers.\n list2 (list): The second list of numbers.\n n (int): The number of largest products to find.\n\n Returns:\n list: A list of the n largest products.\n \"\"\"\n # Create a list of products by multiplying each element in list1 with each element in list2\n products = [a * b for a in list1 for b in list2]\n \n # Sort the products in descending order\n products.sort(reverse=True)\n \n # Return the n largest products\n return products[:n]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, k):\n \"\"\"\n Returns the k largest products from two given lists, selecting one factor from each list.\n\n Args:\n list1 (list): The first list of numbers.\n list2 (list): The second list of numbers.\n k (int): The number of largest products to return.\n\n Returns:\n list: A list of the k largest products.\n \"\"\"\n # Combine the two lists into a list of pairs\n pairs = [(x, y) for x in list1 for y in list2]\n\n # Sort the list of pairs by their products in descending order\n sorted_pairs = sorted(pairs, key=lambda pair: pair[0] * pair[1], reverse=True)\n\n # Return the k largest products\n return [pair[0] * pair[1] for pair in sorted_pairs[:k]]", "matching_cluster_idx": 2}, {"solution": "def large_product(list1, list2, n):\n \"\"\"\n Returns the specified number of largest products from two given lists.\n \n Parameters:\n list1 (list): The first list of numbers.\n list2 (list): The second list of numbers.\n n (int): The number of largest products to return.\n \n Returns:\n list: A list of the n largest products.\n \"\"\"\n # Combine the two lists into one list of tuples, where each tuple is a pair of numbers\n pairs = [(x, y) for x in list1 for y in list2]\n \n # Sort the list of pairs in descending order based on the product of the numbers\n pairs.sort(key=lambda x: x[0]*x[1], reverse=True)\n \n # Return the specified number of largest products\n return [x[0]*x[1] for x in pairs[:n]]", "matching_cluster_idx": 2}, {"solution": "def large_product(list1, list2, n):\n \"\"\"\n Find the n largest products from two given lists, selecting one factor from each list.\n\n Args:\n list1 (list): The first list of numbers.\n list2 (list): The second list of numbers.\n n (int): The number of largest products to find.\n\n Returns:\n list: A list of the n largest products.\n \"\"\"\n # Combine all possible products into a list of tuples\n products = [(x, y) for x in list1 for y in list2]\n \n # Sort the products in descending order\n products.sort(key=lambda x: x[0]*x[1], reverse=True)\n \n # Return the top n products\n return [x[0]*x[1] for x in products[:n]]", "matching_cluster_idx": 2}, {"solution": "def large_product(list1, list2, k):\n \"\"\"\n This function finds the specified number of largest products from two given lists, \n selecting one factor from each list.\n\n Args:\n list1 (list): The first list of numbers.\n list2 (list): The second list of numbers.\n k (int): The number of largest products to find.\n\n Returns:\n list: A list of the k largest products, where each product is the result of multiplying \n one element from list1 and one element from list2.\n \"\"\"\n \n # Generate all possible products\n products = [a * b for a in list1 for b in list2]\n \n # Sort the products in descending order\n products.sort(reverse=True)\n \n # Return the k largest products\n return products[:k]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n \"\"\"\n This function takes in two lists and a number n, and returns the n largest products\n obtained by selecting one factor from each list.\n \n Args:\n list1 (list): The first list of numbers\n list2 (list): The second list of numbers\n n (int): The number of products to return\n \n Returns:\n list: A list of the n largest products\n \"\"\"\n # Combine all pairs of numbers into a list of pairs\n pairs = [(x, y) for x in list1 for y in list2]\n # Sort the pairs based on their product in descending order\n pairs.sort(key=lambda x: x[0]*x[1], reverse=True)\n # Return the n largest products\n return [x*y for x, y in pairs[:n]]", "matching_cluster_idx": 2}, {"solution": "def large_product(list1, list2, n):\n \"\"\"\n Find the specified number of largest products from two given lists,\n selecting one factor from each list.\n \n Args:\n list1 (list): The first list of numbers.\n list2 (list): The second list of numbers.\n n (int): The number of largest products to find.\n \n Returns:\n list: A list of the n largest products in descending order.\n \"\"\"\n # Generate all possible products of two factors from the lists\n products = [a * b for a in list1 for b in list2]\n \n # Return the n largest products\n return sorted(products, reverse=True)[:n]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, k):\n \"\"\"\n Returns the k largest products from the cartesian product of two lists.\n\n Args:\n list1 (list): The first list of numbers.\n list2 (list): The second list of numbers.\n k (int): The number of largest products to return.\n\n Returns:\n list: A list of the k largest products.\n \"\"\"\n # Generate the cartesian product of the two lists\n from itertools import product\n products = list(product(list1, list2))\n\n # Calculate the product of each pair and store it in a list of tuples (product, factors)\n products_with_product = [(p[0] * p[1], p) for p in products]\n\n # Sort the list of tuples in descending order based on the product\n products_with_product.sort(key=lambda x: x[0], reverse=True)\n\n # Return the k largest products\n return [p[0] for p in products_with_product[:k]]", "matching_cluster_idx": 2}]}, "Mbpp/392": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 21.0, "profiled": [{"solution": "def get_max_sum(n):\n \"\"\"\n Function to find the maximum sum possible by using the given equation f(n) = max( (f(n/2) + f(n/3) + f(n/4) + f(n/5)), n).\n\n Args:\n n (int): The number for which the maximum sum needs to be found.\n\n Returns:\n int: The maximum sum possible.\n \"\"\"\n memo = {} # Dictionary to store the calculated values for memoization\n def helper(num):\n # Base case to handle when num is less than 1\n if num < 1:\n return 0\n # If the value is already in the dictionary, return it\n if num in memo:\n return memo[num]\n # Calculate the maximum sum for the current number\n max_sum = max(helper(num // 2) + helper(num // 3) + helper(num // 4) + helper(num // 5), num)\n # Store the result in the dictionary and return it\n memo[num] = max_sum\n return max_sum\n # Call the helper function to calculate the maximum sum for the given number\n return helper(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n, memo={}):\n \"\"\"\n This function calculates the maximum sum possible by using the equation f(n) = max( (f(n/2) + f(n/3) + f(n/4) + f(n/5)), n).\n \n Args:\n n (int): The input number to find the maximum sum for.\n memo (dict, optional): Dictionary to store the results of subproblems to avoid repeated calculations. Defaults to {}.\n\n Returns:\n int: The maximum sum possible by using the equation f(n) = max( (f(n/2) + f(n/3) + f(n/4) + f(n/5)), n).\n \"\"\"\n # Base case: If n is less than or equal to 1, return n\n if n <= 1:\n return n\n \n # If the subproblem has been solved before, return the stored result\n if n in memo:\n return memo[n]\n \n # Calculate the maximum sum for the subproblems\n max_sum = max(\n # Recursively find the maximum sum for the subproblems and add the results\n get_max_sum(n // 2, memo) + get_max_sum(n // 3, memo) + get_max_sum(n // 4, memo) + get_max_sum(n // 5, memo),\n # Use n as the maximum sum for the subproblem\n n\n )\n \n # Store the result of the subproblem in the memo dictionary\n memo[n] = max_sum\n \n return max_sum", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n, memo={1: 1}):\n \"\"\"\n This function calculates the maximum sum possible by using the given equation f(n) = max( (f(n/2) + f(n/3) + f(n/4) + f(n/5)), n)\n \n Args:\n n (int): The input number to calculate the maximum sum for.\n memo (dict, optional): Dictionary to store memoized values. Defaults to {1: 1}.\n \n Returns:\n int: The maximum sum possible.\n \"\"\"\n # Base case: If the number is 1, return 1\n if n in memo:\n return memo[n]\n \n # If the number is less than 1, return 0\n if n < 1:\n return 0\n \n # Calculate the maximum sum by using the given equation\n max_sum = max(\n get_max_sum(n//2, memo) + get_max_sum(n//3, memo) + get_max_sum(n//4, memo) + get_max_sum(n//5, memo),\n n\n )\n \n # Store the calculated maximum sum in the memo dictionary\n memo[n] = max_sum\n \n return max_sum", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n \"\"\"\n This function calculates the maximum sum possible by recursively using the equation:\n f(n) = max( (f(n/2) + f(n/3) + f(n/4) + f(n/5)), n)\n Args:\n n (int): Input number\n Returns:\n int: Maximum sum\n \"\"\"\n memo = {} # Dictionary to store memoized results\n\n def calculate_max_sum(n):\n # Base case: If n is a whole number, return n\n if n in memo:\n return memo[n]\n if n <= 1:\n return n\n \n # Memoize the results of sub-problems and find max of sums of recursive calls\n result = max(n, calculate_max_sum(n // 2) + calculate_max_sum(n // 3) + calculate_max_sum(n // 4) + calculate_max_sum(n // 5))\n \n # Store result in memo to avoid recomputation\n memo[n] = result\n return result\n\n return calculate_max_sum(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n \"\"\"\n This function calculates the maximum sum possible by using the given equation \n f(n) = max( (f(n/2) + f(n/3) + f(n/4) + f(n/5)), n).\n \n Args:\n n (int): The input number for which the maximum sum needs to be calculated.\n \n Returns:\n int: The maximum sum possible.\n \"\"\"\n \n # Initialize a memoization dictionary to store results of subproblems\n memo = {1: 1} # Base case when n is 1\n \n def helper(k):\n \"\"\"\n Helper function to calculate the maximum sum recursively.\n \n Args:\n k (int): The current number for which the maximum sum needs to be calculated.\n \n Returns:\n int: The maximum sum possible for the given number.\n \"\"\"\n \n # If the result for the current number is already calculated, return the result\n if k in memo:\n return memo[k]\n \n # If the number is less than 1, return 0\n if k < 1:\n return 0\n \n # Calculate maximum sum for the current number\n max_sum = k\n \n # Calculate maximum sum for the current number using recursive calls\n max_sum = max(\n helper(k // 2) + helper(k // 3) + helper(k // 4) + helper(k // 5),\n max_sum\n )\n \n # Store the result in the memoization dictionary and return it\n memo[k] = max_sum\n return max_sum\n \n # Call the helper function and return the maximum sum\n return helper(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n \"\"\"\n This function calculates the maximum sum possible using the equation f(n) = max( (f(n/2) + f(n/3) + f(n/4) + f(n/5)), n).\n \n Args:\n n (int): The input number for the recursive equation.\n\n Returns:\n int: The maximum sum possible using the recursive equation.\n \"\"\"\n memo = {1: 1} # Initialize a dictionary to store memoized results\n\n def recursive_f(n):\n \"\"\"\n Recursive function to calculate f(n) using memoization.\n \n Args:\n n (int): The current number for the recursive equation.\n \n Returns:\n int: The maximum sum possible for the given number.\n \"\"\"\n if n in memo:\n return memo[n] # Return the memoized result if it exists\n else:\n max_sum = n # Initialize max_sum as the current number\n if n > 1:\n max_sum = max(max_sum, recursive_f(n // 2) + recursive_f(n // 3) + recursive_f(n // 4) + recursive_f(n // 5))\n memo[n] = max_sum # Store the result in the dictionary\n return max_sum\n\n return recursive_f(n)", "matching_cluster_idx": 12}, {"solution": "def memoize(func):\n cache = dict()\n def memoized_func(*args):\n if args in cache:\n return cache[args]\n result = func(*args)\n cache[args] = result\n return result\n return memoized_func\n\n@memoize\ndef get_max_sum(n):\n \"\"\"\n Find the maximum sum possible by using the given equation f(n) = max( (f(n/2) + f(n/3) + f(n/4) + f(n/5)), n).\n \n Args:\n n (int): The input number.\n \n Returns:\n int: The maximum sum possible.\n \"\"\"\n if n < 1:\n return 0 # Base case: sum for numbers less than 1 is 0\n \n if n == 1:\n return n # Base case: sum for number 1 is the number itself\n \n # Explore the max sum of the current number and all its divisor sums\n return max(n, \n get_max_sum(n // 2) + get_max_sum(n // 3) + get_max_sum(n // 4) + get_max_sum(n // 5))\n\n# Test cases\nassert get_max_sum(60) == 106", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n \"\"\"\n Recursive function to find the maximum sum possible by using the given equation \n f(n) = max( (f(n/2) + f(n/3) + f(n/4) + f(n/5)), n).\n\n Args:\n n (int): The number to find the maximum sum for.\n\n Returns:\n int: The maximum sum possible.\n \"\"\"\n memo = {} # Dictionary to store the results of sub-problems for memoization\n\n def recursive_function(x):\n # Base cases\n if x <= 0:\n return 0\n if x in memo:\n return memo[x] # Return memoized value if available\n\n # Recursive case\n max_val = max(recursive_function(x // 2) + recursive_function(x // 3) + recursive_function(x // 4) + recursive_function(x // 5), x)\n memo[x] = max_val # Memoize the result\n return max_val\n\n return recursive_function(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n, memo = {}):\n \"\"\"\n This function solves the given recursive equation \n f(n) = max( (f(n/2) + f(n/3) + f(n/4) + f(n/5)), n).\n \n Args:\n n (int): The input number\n memo (dict): A dictionary used for memoization, defaults to an empty dictionary\n \n Returns:\n int: The maximum sum\n \"\"\"\n \n # Base case: If n is a small number, return n directly\n if n < 6:\n return n\n \n # If n is already computed, return memoized result\n if n in memo:\n return memo[n]\n \n # Calculate the four possible sub-problems and store them in a list\n sub_problems = [\n get_max_sum(n//2, memo) + get_max_sum(n//3, memo) + get_max_sum(n//4, memo) + get_max_sum(n//5, memo),\n n\n ]\n \n # Choose the maximum result and memoize it\n max_sum = max(sub_problems)\n memo[n] = max_sum\n return max_sum", "matching_cluster_idx": 12}, {"solution": "from functools import lru_cache\ndef get_max_sum(n):\n \"\"\"\n This function returns the maximum sum possible by using the given equation:\n f(n) = max( (f(n/2) + f(n/3) + f(n/4) + f(n/5)), n).\n \n Args:\n n (int): The input number.\n\n Returns:\n int: The maximum sum possible.\n \"\"\"\n @lru_cache(maxsize=None)\n def f(k):\n # Base case: if k is less than 1, return 0.\n if k < 1:\n return 0\n # Base case: if k is 1, return k.\n elif k == 1:\n return k\n else:\n # Recursive case: calculate the maximum sum.\n return max(f(k // 2) + f(k // 3) + f(k // 4) + f(k // 5), k)\n\n return f(n)", "matching_cluster_idx": 12}, {"solution": "from functools import lru_cache\ndef get_max_sum(n):\n \"\"\"\n Calculate the maximum sum possible by using the equation f(n) = max( (f(n/2) + f(n/3) + f(n/4) + f(n/5)), n).\n\n Args:\n n (int): A positive integer.\n\n Returns:\n int: The maximum sum possible.\n \"\"\"\n @lru_cache(maxsize=None)\n def f(k):\n # Base case: if k is less than or equal to 1, the maximum sum is k\n if k <= 1:\n return k\n # Recursive case: return the maximum of k and the sum of f(k/2), f(k/3), f(k/4), f(k/5)\n else:\n return max(k, f(int(k/2)) + f(int(k/3)) + f(int(k/4)) + f(int(k/5)))\n\n return f(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n \"\"\"\n This function calculates the maximum sum possible by using the given equation:\n f(n) = max( (f(n/2) + f(n/3) + f(n/4) + f(n/5)), n).\n\n Args:\n n (int): The input number.\n\n Returns:\n int: The maximum sum possible.\n \"\"\"\n memo = {1: 1} # base case\n\n def f(x):\n # If the value is already in memo, return it\n if x in memo:\n return memo[x]\n \n # If the value is a fraction, skip it\n if x < 1:\n return 0\n \n # Calculate the maximum sum for the current value\n max_sum = max(f(x // 2) + f(x // 3) + f(x // 4) + f(x // 5), x)\n memo[x] = max_sum # store the result in memo\n\n return max_sum\n\n return f(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n, memo = {}):\n \"\"\"\n Calculate the maximum sum of f(n) using memoization to optimize recursion.\n\n Args:\n n (int): The input number for the function f(n).\n memo (dict, optional): Dictionary to store memoized results. Defaults to {}.\n\n Returns:\n int: The maximum sum possible using the given equation f(n) = max( (f(n/2) + f(n/3) + f(n/4) + f(n/5)), n).\n \"\"\"\n\n # Base case: If n is less than 1, return 0\n if n < 1:\n return 0\n\n # If n is 1, return n\n if n == 1:\n return n\n\n # If result is already memoized, return the memoized value\n if n in memo:\n return memo[n]\n\n # Calculate the maximum sum by considering different divisions\n max_sum = max(n, get_max_sum(n // 2, memo) + get_max_sum(n // 3, memo) + get_max_sum(n // 4, memo) + get_max_sum(n // 5, memo))\n\n # Memoize the result\n memo[n] = max_sum\n\n return max_sum", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n, memo={}):\n \"\"\"\n This function uses memoization to find the maximum sum possible\n by using the given equation f(n) = max( (f(n/2) + f(n/3) + f(n/4) + f(n/5)), n).\n \n Args:\n n (int): The input number.\n memo (dict, optional): A dictionary to store the memoization results. Defaults to {}.\n \n Returns:\n int: The maximum sum possible.\n \"\"\"\n\n # Base case: If n is a number that has already been computed, return the memoized result\n if n in memo:\n return memo[n]\n \n # Base case: If n is 0 or 1, return n\n if n <= 1:\n memo[n] = n\n return n\n\n # Compute the maximum sum recursively and store the result in memo\n max_sum = n\n max_sum = max(max_sum, get_max_sum(n//2, memo) + get_max_sum(n//3, memo) + get_max_sum(n//4, memo) + get_max_sum(n//5, memo))\n memo[n] = max_sum\n\n return max_sum", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n, memo = {}):\n \"\"\"\n Function to calculate the maximum sum using the recursive equation:\n f(n) = max( (f(n/2) + f(n/3) + f(n/4) + f(n/5)), n)\n\n Args:\n n (int): The input number.\n memo (dict): A dictionary for memoization.\n\n Returns:\n int: The maximum sum.\n \"\"\"\n # Base case: If n is 1, return n as the maximum sum.\n if n in memo:\n return memo[n]\n if n < 1:\n return 0\n if n == 1:\n return n\n\n # Store the result of the current subproblem to avoid redundant computation\n memo[n] = max((get_max_sum(n//2, memo) + get_max_sum(n//3, memo) + get_max_sum(n//4, memo) + get_max_sum(n//5, memo)), n)\n \n # Return the calculated result.\n return memo[n]", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n, memo={}):\n \"\"\"\n This function uses memoization to find the maximum sum possible by using the equation\n f(n) = max( (f(n/2) + f(n/3) + f(n/4) + f(n/5)), n).\n \n Parameters:\n n (int): The input number for which the maximum sum is calculated\n memo (dict): A dictionary to store results of subproblems for memoization\n \n Returns:\n int: The maximum sum possible for the given input number\n \"\"\"\n \n # Base case: If n is a small number, return n itself\n if n <= 2:\n return n\n \n # If the result for the current number is already calculated, return it\n if n in memo:\n return memo[n]\n \n # Calculate the maximum sum using the equation f(n) = max( (f(n/2) + f(n/3) + f(n/4) + f(n/5)), n)\n max_sum = max((get_max_sum(n//2, memo) + get_max_sum(n//3, memo) + get_max_sum(n//4, memo) + get_max_sum(n//5, memo)), n)\n \n # Store the result in the memo dictionary\n memo[n] = max_sum\n \n return max_sum", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n, memo={}):\n \"\"\"\n Calculate the maximum sum possible for the equation f(n) = max( (f(n/2) + f(n/3) + f(n/4) + f(n/5)), n).\n \n Args:\n n (int): The input number for the equation.\n memo (dict): A dictionary to store the results of sub-problems to avoid redundant calculations. Defaults to an empty dictionary.\n \n Returns:\n int: The maximum sum possible.\n \"\"\"\n # Base case: if n is a key in the memo dictionary, return the stored result\n if n in memo:\n return memo[n]\n \n # Base case: if n is less than or equal to 1, return n\n if n <= 1:\n return n\n \n # Calculate the maximum sum using the given equation and store the result in the memo dictionary\n max_sum = max(n, \n get_max_sum(n // 2, memo) + get_max_sum(n // 3, memo) + get_max_sum(n // 4, memo) + get_max_sum(n // 5, memo))\n \n memo[n] = max_sum # Store the result in the memo dictionary\n \n return max_sum", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n, memo={}):\n \"\"\"\n This function calculates the maximum sum possible by using the given equation \n f(n) = max( (f(n/2) + f(n/3) + f(n/4) + f(n/5)), n).\n \n Args:\n n (int): The input number.\n \n Returns:\n int: The maximum sum possible.\n \"\"\"\n # Base case: if n is 1 or less, return n\n if n <= 1:\n return n\n \n # Check if the problem is already solved and return the result\n if n in memo:\n return memo[n]\n \n # Calculate the maximum sum by recursively calling the function for different divisions of n\n max_sum = max(n, \n get_max_sum(n//2, memo) + get_max_sum(n//3, memo) + get_max_sum(n//4, memo) + get_max_sum(n//5, memo))\n \n # Store the result in the memo for future use\n memo[n] = max_sum\n \n return max_sum", "matching_cluster_idx": 12}, {"solution": "def memoize(func):\n cache = dict()\n def memoized_func(n):\n if n not in cache:\n cache[n] = func(n)\n return cache[n]\n return memoized_func\n\n@memoize\ndef get_max_sum(n):\n \"\"\"Find the maximum sum possible by using the given equation f(n) = max( (f(n/2) + f(n/3) + f(n/4) + f(n/5)), n).\"\"\"\n if n <= 1: # Base case: when n is 1, the maximum sum is n itself\n return n\n # Recursively find the maximum sum for n/2, n/3, n/4, n/5\n return max(n, get_max_sum(n//2) + get_max_sum(n//3) + get_max_sum(n//4) + get_max_sum(n//5))\n\n# Test the function\nassert get_max_sum(60) == 106", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n \"\"\"\n Calculate the maximum sum possible by using the given equation f(n) = max( (f(n/2) + f(n/3) + f(n/4) + f(n/5)), n).\n \n Args:\n n (int): A positive integer.\n \n Returns:\n int: The maximum sum.\n \"\"\"\n memo = {}\n\n def helper(k):\n # Base case\n if k in memo:\n return memo[k]\n \n # If n is less than the minimum division\n if k < 5:\n return k\n \n # Calculate the sum recursively\n sum_val = max(k, helper(k//2) + helper(k//3) + helper(k//4) + helper(k//5))\n \n # Store the result in the dictionary\n memo[k] = sum_val\n \n return sum_val\n \n return helper(n)", "matching_cluster_idx": 12}]}, "Mbpp/395": {"dps": 98.08429118773947, "dps_norm": 75.0, "pass@1": 100.0, "profiled": [{"solution": "def first_non_repeating_character(s):\n \"\"\"\n Finds the first non-repeating character in a given string.\n\n Args:\n s (str): The input string.\n\n Returns:\n str: The first non-repeating character in the string, or None if no such character exists.\n \"\"\"\n\n # Create a dictionary to store character frequencies\n char_freq = {}\n\n # Count the frequency of each character\n for char in s:\n if char in char_freq:\n char_freq[char] += 1\n else:\n char_freq[char] = 1\n\n # Iterate over the string again to find the first non-repeating character\n for char in s:\n if char_freq[char] == 1:\n return char\n\n # If no non-repeating character is found, return None\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n \"\"\"\n This function finds the first non-repeating character in a given string.\n If no such character exists, it returns None.\n\n Args:\n s (str): The input string to search in.\n\n Returns:\n str: The first non-repeating character in the string. If no such character exists, returns None.\n \"\"\"\n # Create a dictionary to store the count of each character in the string\n char_count = {}\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n\n # Find the first character that has a count of 1\n for char in s:\n if char_count[char] == 1:\n return char\n\n # If no non-repeating character is found, return None\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n \"\"\"\n Returns the first non-repeating character in a given string. \n If no such character exists, returns None.\n \"\"\"\n char_count = {}\n \n # count the occurrences of each character\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n \n # find the first non-repeating character\n for char in s:\n if char_count[char] == 1:\n return char\n \n # if no non-repeating character is found\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n \"\"\"\n Finds the first non-repeating character in a given string.\n\n Args:\n s (str): The input string.\n\n Returns:\n str: The first non-repeating character in the string, or None if no such character exists.\n \"\"\"\n # Create a dictionary to store the frequency of each character\n char_frequency = {}\n \n # Iterate through the string to count the frequency of each character\n for char in s:\n if char in char_frequency:\n char_frequency[char] += 1\n else:\n char_frequency[char] = 1\n \n # Iterate through the string again to find the first non-repeating character\n for char in s:\n if char_frequency[char] == 1:\n return char\n \n # If no non-repeating character is found, return None\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s: str) -> str:\n \"\"\"\n Finds the first non-repeated character in a given string.\n\n Args:\n s (str): The input string.\n\n Returns:\n str or None: The first non-repeated character if found, otherwise None.\n \"\"\"\n # Create a dictionary to store character frequencies\n char_frequency = {}\n \n # Iterate over the string to count character frequencies\n for char in s:\n if char in char_frequency:\n char_frequency[char] += 1\n else:\n char_frequency[char] = 1\n \n # Iterate over the string to find the first non-repeated character\n for char in s:\n if char_frequency[char] == 1:\n return char\n \n # If no non-repeated character found, return None\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s: str) -> str:\n \"\"\"\n This function finds the first non-repeating character in a given string.\n \n Args:\n s (str): The input string.\n \n Returns:\n str or None: The first non-repeating character if exists, otherwise None.\n \"\"\"\n char_count = {}\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n \n for char in s:\n if char_count[char] == 1:\n return char\n \n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n \"\"\"\n This function finds the first non-repeated character in a given string.\n \n Args:\n s (str): The input string.\n \n Returns:\n The first non-repeated character in the string. If all characters are repeated, returns None.\n \"\"\"\n char_count = {}\n \n # Count the occurrences of each character in the string\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n \n # Find the first character with a count of 1\n for char in s:\n if char_count[char] == 1:\n return char\n \n # If no non-repeated character is found, return None\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n \"\"\"\n Find the first non-repeating character in a given string.\n\n Args:\n s (str): The input string.\n\n Returns:\n str or None: The first non-repeating character if it exists, otherwise None.\n \"\"\"\n char_count = {} # dictionary to store character frequencies\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n\n for char in s:\n if char_count[char] == 1:\n return char\n\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s: str) -> str:\n \"\"\"\n This function finds the first non-repeating character in a given string.\n \n Args:\n s (str): The input string.\n \n Returns:\n str: The first non-repeating character if found, otherwise None.\n \"\"\"\n char_count = {}\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n \n for char in s:\n if char_count[char] == 1:\n return char\n \n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n \"\"\"\n Returns the first non-repeating character in the given string.\n If all characters are repeated, returns None.\n \"\"\"\n char_count = {}\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n\n for char in s:\n if char_count[char] == 1:\n return char\n\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s: str) -> str:\n \"\"\"\n Finds the first non-repeating character in a given string.\n\n Args:\n s (str): The input string.\n\n Returns:\n str or None: The first non-repeating character, or None if no such character exists.\n \"\"\"\n char_count = {}\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n\n for char in s:\n if char_count[char] == 1:\n return char\n\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n \"\"\"\n Returns the first non-repeating character in a given string.\n If no such character exists, returns None.\n \"\"\"\n char_count = {}\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n\n for char in s:\n if char_count[char] == 1:\n return char\n\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n \"\"\"\n This function finds the first non-repeating character in a given string.\n \n If no non-repeating character exists, it returns None.\n \n Parameters:\n s (str): The input string.\n \n Returns:\n str or None: The first non-repeating character or None if no such character exists.\n \"\"\"\n char_count = {} # Dictionary to store character frequency\n \n # Count the frequency of each character in the string\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n \n # Find the first character with a count of 1\n for char in s:\n if char_count[char] == 1:\n return char\n \n # If no non-repeating character is found, return None\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n \"\"\"\n Finds the first non-repeated character in a given string.\n \n Args:\n s (str): The input string.\n \n Returns:\n str: The first non-repeated character if found, otherwise None.\n \"\"\"\n char_count = {}\n for char in s:\n # If the character is already in the dictionary, increment its count\n if char in char_count:\n char_count[char] += 1\n # Otherwise, add the character to the dictionary with a count of 1\n else:\n char_count[char] = 1\n \n # Iterate over the input string again to find the first non-repeated character\n for char in s:\n # If the count of the character is 1, it's the first non-repeated character, return it\n if char_count[char] == 1:\n return char\n \n # If no non-repeated character is found, return None\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s: str) -> any:\n \"\"\"\n This function takes a string as an input and returns the first non-repeating character.\n If no character appears only once, it returns None.\n\n Args:\n s (str): The input string.\n\n Returns:\n any: The first non-repeating character or None if no such character exists.\n \"\"\"\n # Create a dictionary to store character frequencies\n char_freq = {}\n \n # Iterate over the string to count character frequencies\n for char in s:\n if char in char_freq:\n char_freq[char] += 1\n else:\n char_freq[char] = 1\n \n # Iterate over the string again to find the first non-repeating character\n for char in s:\n if char_freq[char] == 1:\n return char\n \n # If no character appears only once, return None\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n \"\"\"\n Find the first non-repeated character in a given string.\n \n Args:\n s (str): The input string.\n \n Returns:\n str: The first non-repeated character in the string. If no such character exists, return None.\n \"\"\"\n # Create a dictionary to store the frequency of each character\n char_freq = {}\n for char in s:\n if char in char_freq:\n char_freq[char] += 1\n else:\n char_freq[char] = 1\n \n # Iterate over the input string again and return the first non-repeated character\n for char in s:\n if char_freq[char] == 1:\n return char\n \n # If no non-repeated character is found, return None\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n \"\"\"\n Finds the first non-repeating character in a given string.\n\n Args:\n s (str): The input string.\n\n Returns:\n str: The first non-repeating character in the string, or None if no such character exists.\n \"\"\"\n char_count = {}\n \n # Count occurrences of each character in the string\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n \n # Find the first character with a count of 1\n for char in s:\n if char_count[char] == 1:\n return char\n \n # If no non-repeating character found, return None\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n \"\"\"\n This function finds the first non-repeating character in a given string.\n \n Args:\n s (str): The input string.\n \n Returns:\n The first non-repeating character in the string. If no character is non-repeating, returns None.\n \"\"\"\n # Count the occurrences of each character in the string\n char_count = {}\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n \n # Find the first character that has a count of 1\n for char in s:\n if char_count[char] == 1:\n return char\n \n # If no character is non-repeating, return None\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s: str) -> str:\n \"\"\"\n Find the first non-repeating character in a given string.\n\n Args:\n s (str): The input string.\n\n Returns:\n str: The first non-repeating character, or None if no such character exists.\n \"\"\"\n\n # Create a dictionary to count the frequency of each character in the string\n char_frequency = {}\n for char in s:\n if char in char_frequency:\n char_frequency[char] += 1\n else:\n char_frequency[char] = 1\n\n # Iterate over the string again to find the first non-repeating character\n for char in s:\n if char_frequency[char] == 1:\n return char\n\n # If no non-repeating character is found, return None\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n \"\"\"\n Finds the first non-repeating character in a given string.\n \n Args:\n s (str): The input string.\n \n Returns:\n str or None: The first non-repeating character or None if no such character exists.\n \"\"\"\n char_count = {}\n \n # Count the occurrences of each character\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n \n # Find the first character with a count of 1\n for char in s:\n if char_count[char] == 1:\n return char\n \n # If no such character exists, return None\n return None", "matching_cluster_idx": 5}]}, "Mbpp/405": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 99.0, "profiled": [{"solution": "def check_tuplex(tuplex, element):\n \"\"\"\n Checks if an element exists within a tuple.\n\n Args:\n tuplex (tuple): The tuple to check within.\n element: The element to search for.\n\n Returns:\n bool: True if the element is found, False otherwise.\n \"\"\"\n return element in tuplex", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, element):\n \"\"\"\n This function checks whether an element exists within a tuple.\n \n Args:\n tuplex (tuple): The input tuple to be searched.\n element: The element to be searched within the tuple.\n \n Returns:\n bool: True if the element exists in the tuple, False otherwise.\n \"\"\"\n return element in tuplex", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, element):\n \"\"\"\n Checks whether an element exists within a tuple.\n\n Args:\n tuplex (tuple): Input tuple.\n element: Element to search within the tuple.\n\n Returns:\n bool: True if the element exists within the tuple, False otherwise.\n \"\"\"\n return element in tuplex", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, element):\n \"\"\"\n Checks if a given element exists within a tuple.\n\n Args:\n tuplex (tuple): The input tuple to be searched.\n element: The element to be searched within the tuple.\n\n Returns:\n bool: True if the element exists, False otherwise.\n \"\"\"\n return element in tuplex", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, element):\n \"\"\"\n Checks if an element exists within a tuple.\n\n Args:\n tuplex (tuple): Input tuple to check.\n element: Element to search for.\n\n Returns:\n bool: True if the element exists in the tuple, False otherwise.\n \"\"\"\n return element in tuplex", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, element):\n \"\"\"\n Check whether an element exists within a tuple.\n\n Args:\n tuplex (tuple): The input tuple to search through.\n element: The element to search for.\n\n Returns:\n bool: True if the element is found, False otherwise.\n \"\"\"\n return element in tuplex", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(t, element):\n \"\"\"\n Check if an element exists within a tuple.\n\n Args:\n t (tuple): The input tuple to search.\n element: The element to search for.\n\n Returns:\n bool: True if the element exists, False otherwise.\n \"\"\"\n return element in t", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, element):\n \"\"\"\n Check if an element exists within a tuple.\n \n Args:\n tuplex (tuple): The input tuple to search.\n element: The element to search for.\n\n Returns:\n bool: True if the element is found, False otherwise.\n \"\"\"\n return element in tuplex", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, element):\n \"\"\"\n Check whether an element exists within a tuple.\n\n Args:\n tuplex (tuple): A tuple to search in.\n element: The element to search for.\n\n Returns:\n bool: True if the element exists, False otherwise.\n \"\"\"\n return element in tuplex", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, element):\n \"\"\"\n Checks if an element exists within a tuple.\n \n Args:\n tuplex (tuple): The input tuple to be searched.\n element: The element to search for in the tuple.\n \n Returns:\n bool: True if the element is found, False otherwise.\n \"\"\"\n return element in tuplex", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, element):\n \"\"\"\n Checks whether an element exists within a tuple.\n\n Args:\n tuplex (tuple): The input tuple to be searched.\n element: The element to be searched within the tuple.\n\n Returns:\n bool: True if the element exists in the tuple, False otherwise.\n \"\"\"\n return element in tuplex", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, element):\n \"\"\"\n This function checks whether a given element exists within a tuple.\n \n Args:\n tuplex (tuple): The input tuple to be searched.\n element: The element to be searched within the tuple.\n \n Returns:\n bool: True if the element exists in the tuple, False otherwise.\n \"\"\"\n return element in tuplex", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, elem):\n \"\"\"\n This function checks whether an element exists within a tuple.\n \n Args:\n tuplex (tuple): Input tuple to search within.\n elem: Element to search for.\n \n Returns:\n bool: True if the element exists in the tuple, False otherwise.\n \"\"\"\n return elem in tuplex", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, element):\n \"\"\"\n Checks whether an element exists within a tuple.\n \n Args:\n tuplex (tuple): The input tuple to be checked.\n element: The element to be searched in the tuple.\n \n Returns:\n bool: True if the element exists in the tuple, False otherwise.\n \"\"\"\n return element in tuplex\ntuplex = (\"w\", 3, \"r\", \"e\", \"s\", \"o\", \"u\", \"r\", \"c\", \"e\")\nelement = 'r'", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, element):\n \"\"\"\n Checks whether an element exists within a tuple.\n\n Args:\n tuplex (tuple): The tuple to search through.\n element: The element to look for.\n\n Returns:\n bool: True if the element exists, False otherwise.\n \"\"\"\n return element in tuplex", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, element):\n \"\"\"\n Checks whether an element exists within a given tuple.\n\n Args:\n tuplex (tuple): The tuple to search within.\n element: The element to search for.\n\n Returns:\n bool: True if the element exists, False otherwise.\n \"\"\"\n return element in tuplex", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, element):\n \"\"\"\n This function checks whether an element exists within a tuple.\n\n Args:\n tuplex (tuple): The input tuple to search in.\n element: The element to search for.\n\n Returns:\n bool: True if the element is found in the tuple, False otherwise.\n \"\"\"\n return element in tuplex", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, elem):\n \"\"\"\n This function checks whether a given element exists within a tuple.\n\n Args:\n tuplex (tuple): The tuple to be searched.\n elem (any): The element to be found.\n\n Returns:\n bool: True if the element exists in the tuple, False otherwise.\n \"\"\"\n # Use the 'in' operator to check if the element exists in the tuple\n return elem in tuplex", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, target):\n \"\"\"\n Checks if a target element exists in a tuple.\n \n Args:\n tuplex (tuple): Input tuple to search in.\n target: Target element to search for.\n \n Returns:\n bool: True if target element exists, False otherwise.\n \"\"\"\n return target in tuplex", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, element):\n \"\"\"\n Checks if an element exists within a tuple.\n\n Args:\n tuplex (tuple): The input tuple to search.\n element: The element to search for.\n\n Returns:\n bool: True if the element exists in the tuple, False otherwise.\n \"\"\"\n return element in tuplex", "matching_cluster_idx": 3}]}, "Mbpp/414": {"dps": 91.30434782608695, "dps_norm": 88.88888888888889, "pass@1": 100.0, "profiled": [{"solution": "def overlapping(seq1, seq2):\n \"\"\"\n This function checks whether any value in the first sequence exists in the second sequence or not.\n\n Args:\n seq1 (list): The sequence to check.\n seq2 (list): The sequence to check against.\n\n Returns:\n bool: True if any value in seq1 exists in seq2, False otherwise.\n \"\"\"\n return any(item in seq2 for item in seq1)", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n This function checks whether any value in sequence seq1 exists in sequence seq2.\n \n Args:\n seq1 (list): The sequence to check for existence in another sequence.\n seq2 (list): The sequence to check against.\n \n Returns:\n bool: True if any value in seq1 exists in seq2, False otherwise.\n \"\"\"\n return any(item in seq2 for item in seq1)", "matching_cluster_idx": 7}, {"solution": "def overlapping(list1, list2):\n \"\"\"\n Checks whether any value in list1 exists in list2 or not.\n \n Args:\n list1 (list): The list to check.\n list2 (list): The list to check against.\n \n Returns:\n bool: True if any value in list1 exists in list2, False otherwise.\n \"\"\"\n return any(element in list2 for element in list1)", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Check whether any value in sequence seq1 exists in sequence seq2.\n\n Args:\n seq1 (list): The first sequence to check.\n seq2 (list): The second sequence to check against.\n\n Returns:\n bool: True if any value in seq1 exists in seq2, False otherwise.\n \"\"\"\n return any(x in seq2 for x in seq1)", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n This function checks whether any value in `seq1` exists in `seq2`.\n \n Args:\n seq1 (list): The sequence to check for existence in the second sequence.\n seq2 (list): The sequence to check against.\n\n Returns:\n bool: True if any value from `seq1` exists in `seq2`, False otherwise.\n \"\"\"\n return any(x in seq2 for x in seq1)", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Checks whether any value in the first sequence exists in the second sequence.\n\n Args:\n seq1 (list): The sequence to check in.\n seq2 (list): The sequence to check against.\n\n Returns:\n bool: True if any value from seq1 is in seq2, False otherwise.\n \"\"\"\n return any(x in seq2 for x in seq1)", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Checks whether any value in sequence1 exists in sequence2.\n \n Args:\n seq1 (list): The list of values to check for.\n seq2 (list): The list to check against.\n \n Returns:\n bool: Whether any value in sequence1 exists in sequence2.\n \"\"\"\n return any(val in seq2 for val in seq1)", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Check if any value in the first sequence exists in the second sequence.\n \n Parameters:\n seq1 (list): The sequence to search in.\n seq2 (list): The sequence to search against.\n \n Returns:\n bool: True if any value in seq1 exists in seq2, False otherwise.\n \"\"\"\n # Convert both sequences to sets for efficient lookups\n set2 = set(seq2)\n return any(x in set2 for x in seq1)", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n This function checks whether any value in sequence 1 exists in sequence 2.\n\n Args:\n seq1 (list): The first sequence to check.\n seq2 (list): The second sequence to check.\n\n Returns:\n bool: True if any value in seq1 exists in seq2, False otherwise.\n \"\"\"\n return any(x in seq2 for x in seq1)", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n This function checks whether any value in sequence seq1 exists in sequence seq2.\n\n Args:\n seq1 (list): The first sequence.\n seq2 (list): The second sequence.\n\n Returns:\n bool: True if any value in seq1 exists in seq2, False otherwise.\n \"\"\"\n return any(x in seq2 for x in seq1)", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Checks if any value in seq1 exists in seq2.\n\n Args:\n seq1 (list): The first sequence to check.\n seq2 (list): The second sequence to check against.\n\n Returns:\n bool: True if any value in seq1 exists in seq2, False otherwise.\n \"\"\"\n return any(i in seq2 for i in seq1)", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Checks if any value in sequence1 exists in sequence2.\n \n Args:\n seq1 (list): The sequence to check.\n seq2 (list): The sequence to check against.\n\n Returns:\n bool: True if any value from seq1 exists in seq2, False otherwise.\n \"\"\"\n return any(x in seq2 for x in seq1)", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Check whether any value in sequence1 exists in sequence2.\n\n Args:\n seq1 (list): The sequence to check.\n seq2 (list): The sequence to check against.\n\n Returns:\n bool: True if any value in seq1 exists in seq2, False otherwise.\n \"\"\"\n return any(x in seq2 for x in seq1)", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Checks whether any value in seq1 exists in seq2.\n \n Args:\n seq1 (list): The sequence to check for overlapping values.\n seq2 (list): The sequence to check against.\n \n Returns:\n bool: True if any value in seq1 exists in seq2, False otherwise.\n \"\"\"\n return any(x in seq2 for x in seq1)", "matching_cluster_idx": 7}, {"solution": "def overlapping(list1, list2):\n \"\"\"\n This function checks if any value in list1 exists in list2.\n \n Args:\n list1 (list): The list to check against\n list2 (list): The list to check in\n \n Returns:\n bool: Whether any value in list1 exists in list2\n \"\"\"\n \n return any(element in list2 for element in list1)", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Checks whether any value in seq1 exists in seq2.\n \n Args:\n seq1 (list): The first sequence to check.\n seq2 (list): The second sequence to check against.\n\n Returns:\n bool: True if any value in seq1 exists in seq2, False otherwise.\n \"\"\"\n return any(item in seq2 for item in seq1)", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Check whether any value in sequence1 exists in sequence2.\n\n Args:\n seq1 (list): The first sequence to check.\n seq2 (list): The second sequence to check.\n\n Returns:\n bool: True if any value in sequence1 exists in sequence2, False otherwise.\n \"\"\"\n return any(item in seq2 for item in seq1)", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Checks if any value in sequence 1 exists in sequence 2.\n\n Args:\n seq1 (list): The sequence to check in.\n seq2 (list): The sequence to check against.\n\n Returns:\n bool: True if any value from seq1 exists in seq2, False otherwise.\n \"\"\"\n return any(item in seq2 for item in seq1)", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Check if any value in sequence1 exists in sequence2.\n\n Args:\n seq1 (list): The first sequence to check.\n seq2 (list): The second sequence to check against.\n\n Returns:\n bool: True if any value in seq1 exists in seq2, False otherwise.\n \"\"\"\n return any(val in seq2 for val in seq1)", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Checks if any value in the first sequence exists in the second sequence.\n \n Args:\n seq1 (list): The first sequence to check.\n seq2 (list): The second sequence to check against.\n \n Returns:\n bool: True if any value from seq1 exists in seq2, False otherwise.\n \"\"\"\n return any(x in seq2 for x in seq1)", "matching_cluster_idx": 7}]}, "Mbpp/421": {"dps": 92.81893004115226, "dps_norm": 95.0, "pass@1": 93.0, "profiled": [{"solution": "def concatenate_tuple(t):\n \"\"\"\n Concatenates each element of a tuple by the delimiter.\n \n Args:\n t (tuple): Input tuple containing elements to be concatenated.\n \n Returns:\n str: Concatenated string of the input tuple elements.\n \"\"\"\n # Use the '-' as delimiter, join() to concatenate elements\n return '-'.join(map(str, t))", "matching_cluster_idx": 6}, {"solution": "def concatenate_tuple(input_tuple, delimiter='-'):\n \"\"\"\n Concatenates each element of the input tuple by the specified delimiter.\n\n Args:\n input_tuple (tuple): A tuple containing the elements to be concatenated.\n delimiter (str, optional): The delimiter to use for concatenation. Defaults to '-'.\n\n Returns:\n str: The concatenated string.\n \"\"\"\n return delimiter.join(map(str, input_tuple))", "matching_cluster_idx": 6}, {"solution": "def concatenate_tuple(t):\n \"\"\"\n This function concatenates each element of a tuple by a delimiter.\n \n Args:\n t (tuple): A tuple containing any type of elements.\n \n Returns:\n str: A concatenated string of elements from the input tuple.\n \"\"\"\n # Using the join() method with a delimiter '-' to concatenate each element\n delimiter = '-'\n return delimiter.join(map(str, t))", "matching_cluster_idx": 6}, {"solution": "def concatenate_tuple(input_tuple, delimiter='-'):\n \"\"\"\n Concatenates each element of a tuple by a specified delimiter.\n\n Args:\n input_tuple (tuple): The input tuple to be concatenated.\n delimiter (str, optional): The delimiter used for concatenation. Defaults to '-'.\n\n Returns:\n str: A string containing all elements of the input tuple joined by the delimiter.\n \"\"\"\n return delimiter.join(map(str, input_tuple))", "matching_cluster_idx": 6}, {"solution": "def concatenate_tuple(tup, delimiter=\"-\"):\n \"\"\"\n Concatenates each element in a tuple by a specified delimiter.\n\n Args:\n tup (tuple): The input tuple to be concatenated.\n delimiter (str, optional): The delimiter to use for concatenation. Defaults to \"-\".\n\n Returns:\n str: The concatenated string.\n \"\"\"\n return delimiter.join(map(str, tup))", "matching_cluster_idx": 6}, {"solution": "def concatenate_tuple(tup, delimiter=\"-\"):\n \"\"\"\n Concatenates each element of a tuple with a delimiter.\n\n Args:\n tup (tuple): The input tuple.\n delimiter (str, optional): The delimiter to use for concatenation. Defaults to '-'.\n\n Returns:\n str: The concatenated string.\n \"\"\"\n return delimiter.join(map(str, tup))", "matching_cluster_idx": 5}, {"solution": "def concatenate_tuple(tup, delimiter='-'):\n \"\"\"\n Concatenate each element of a tuple by a given delimiter.\n\n Args:\n tup (tuple): The input tuple.\n delimiter (str): The delimiter to use for concatenation. Defaults to '-'.\n\n Returns:\n str: The concatenated string.\n \"\"\"\n return delimiter.join(map(str, tup))", "matching_cluster_idx": 6}, {"solution": "def concatenate_tuple(tuple_in):\n \"\"\"\n Concatenates all elements of a given tuple by the delimiter.\n \n Args:\n tuple_in (tuple): Input tuple containing any type of elements.\n \n Returns:\n str: Concatenated string.\n \"\"\"\n # Use the join function to concatenate elements of the tuple with delimiter '-'\n delimiter = '-'\n return delimiter.join(map(str, tuple_in))", "matching_cluster_idx": 6}, {"solution": "def concatenate_tuple(tuple_input):\n \"\"\"\n Concatenates each element of a tuple by the delimiter.\n\n Args:\n tuple_input (tuple): Input tuple containing any type of elements.\n\n Returns:\n str: Concatenated string of tuple elements.\n\n Raises:\n TypeError: If input is not a tuple.\n \"\"\"\n if not isinstance(tuple_input, tuple):\n raise TypeError(\"Input must be a tuple\")\n return '-'.join(map(str, tuple_input))", "matching_cluster_idx": 6}, {"solution": "def concatenate_tuple(tup, delimiter='-'):\n \"\"\"\n This function concatenates each element of a tuple into a string by a given delimiter.\n\n Parameters:\n tup (tuple): The input tuple to be concatenated.\n delimiter (str): The delimiter used for concatenation. Default is '-'.\n\n Returns:\n str: The concatenated string.\n \"\"\"\n return delimiter.join(map(str, tup))", "matching_cluster_idx": 6}, {"solution": "def concatenate_tuple(tup, delimiter='-'):\n \"\"\"\n Concatenates each element of a tuple by a specified delimiter.\n\n Args:\n tup (tuple): Input tuple containing elements to be concatenated.\n delimiter (str, optional): The delimiter used for concatenation. Defaults to '-'.\n\n Returns:\n str: The concatenated string.\n \"\"\"\n return delimiter.join(map(str, tup))", "matching_cluster_idx": 6}, {"solution": "def concatenate_tuple(t):\n \"\"\"\n Concatenates each element of a tuple by the '-' delimiter.\n \n Args:\n t (tuple): The input tuple to be concatenated.\n \n Returns:\n str: A string with all elements from the tuple joined by '-'.\n \"\"\"\n return '-'.join(map(str, t))", "matching_cluster_idx": 6}, {"solution": "def concatenate_tuple(tup, delimiter='-'):\n \"\"\"\n This function concatenates each element of a tuple by the given delimiter.\n \n Args:\n tup (tuple): A tuple containing elements to be concatenated.\n delimiter (str): A string used as the delimiter between elements.\n \n Returns:\n str: A string resulting from concatenating each element of the tuple.\n \"\"\"\n return delimiter.join(map(str, tup))", "matching_cluster_idx": 6}, {"solution": "def concatenate_tuple(tuple_values):\n \"\"\"\n Concatenate each element of a tuple by a delimiter.\n\n Args:\n tuple_values (tuple): The input tuple containing various elements.\n\n Returns:\n str: A string where each element from the tuple is joined with '-' delimiter.\n \"\"\"\n # Check if the input is a tuple\n if not isinstance(tuple_values, tuple):\n raise TypeError(\"Input must be a tuple.\")\n\n # Use the join function to concatenate all elements in the tuple with '-' as delimiter\n concatenated_string = '-'.join(map(str, tuple_values))\n\n return concatenated_string", "matching_cluster_idx": 5}, {"solution": "def concatenate_tuple(tup, delimiter='-'):\n \"\"\"\n Concatenates all elements of a tuple using a specified delimiter.\n\n Args:\n tup (tuple): Input tuple to be concatenated\n delimiter (str, optional): The delimiter used to separate each element. Defaults to '-'.\n\n Returns:\n str: Concatenated string of tuple elements\n \"\"\"\n return delimiter.join(map(str, tup))", "matching_cluster_idx": 6}, {"solution": "def concatenate_tuple(tuple_element):\n \"\"\"\n This function takes in a tuple as input and returns a concatenated string \n by joining the tuple elements using the '-' delimiter.\n \n Args:\n tuple_element (tuple): Input tuple to be concatenated\n \n Returns:\n str: The concatenated string using '-' as the delimiter\n \"\"\"\n return '-'.join(map(str, tuple_element))", "matching_cluster_idx": 6}, {"solution": "def concatenate_tuple(input_tuple, delimiter='-'):\n \"\"\"\n Concatenates each element of a tuple using a delimiter.\n\n Args:\n input_tuple (tuple): The input tuple to be concatenated.\n delimiter (str): The delimiter to use for concatenation (default is '-'.\n\n Returns:\n str: The concatenated string.\n\n Example:\n >>> concatenate_tuple((\"ID\", \"is\", 4, \"UTS\"))\n 'ID-is-4-UTS'\n \"\"\"\n return delimiter.join(map(str, input_tuple))", "matching_cluster_idx": 6}, {"solution": "def concatenate_tuple(t):\n \"\"\"\n Concatenates each element of a tuple by the delimiter '-'\n \n Args:\n t (tuple): The input tuple to be concatenated.\n \n Returns:\n str: A string where each element of the tuple is separated by '-'.\n \"\"\"\n # Initialize an empty string to store the result\n result = \"\"\n \n # Iterate over each element in the tuple\n for i, elem in enumerate(t):\n # If the element is not the first one, add the delimiter\n if i > 0:\n result += \"-\"\n # Add the element to the result string\n result += str(elem)\n \n return result", "matching_cluster_idx": 1}, {"solution": "def concatenate_tuple(t):\n \"\"\"\n Concatenates each element of a tuple by a delimiter (- in this case).\n \n Args:\n t (tuple): Input tuple to be concatenated\n \n Returns:\n str: Concatenated string\n \"\"\"\n return '-'.join(map(str, t))", "matching_cluster_idx": 6}, {"solution": "def concatenate_tuple(tuple_in):\n \"\"\"\n Concatenates each element of the input tuple by the delimiter '-'\n \n Args:\n tuple_in (tuple): Input tuple containing elements to be concatenated\n \n Returns:\n str: A string where each element from the tuple is joined by a delimiter '-'\n \n Example:\n >>> concatenate_tuple((\"ID\", \"is\", 4, \"UTS\"))\n 'ID-is-4-UTS'\n \"\"\"\n return '-'.join(map(str, tuple_in))", "matching_cluster_idx": 6}]}, "Mbpp/424": {"dps": 92.74368231046931, "dps_norm": 97.0, "pass@1": 99.0, "profiled": [{"solution": "def extract_rear(indexed_string_tuple):\n \"\"\"\n This function extracts the rear element from each string in the given tuple.\n\n Args:\n indexed_string_tuple (tuple): A tuple of strings.\n\n Returns:\n list: A list of the last character from each string in the tuple.\n \"\"\"\n return [string[-1] for string in indexed_string_tuple]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(tup):\n \"\"\"\n This function takes a tuple of strings as input and returns a list with the rear index character of each string.\n\n Args:\n tup (tuple): A tuple of strings\n\n Returns:\n list: A list of characters, one for each string in the input tuple.\n \"\"\"\n return [s[-1] for s in tup]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(index_tuple):\n \"\"\"\n This function takes a tuple of strings and returns a list of characters.\n It extracts the last character of each string in the input tuple.\n\n Args:\n index_tuple (tuple): A tuple of strings.\n\n Returns:\n list: A list of characters.\n \"\"\"\n return [string[-1] for string in index_tuple]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(tup):\n \"\"\"\n This function takes a tuple of strings and returns a list with the rear index element of each string.\n \n Parameters:\n tup (tuple): A tuple of strings.\n \n Returns:\n list: A list containing the rear index element of each string in the input tuple.\n \"\"\"\n # Use list comprehension to iterate over each string in the tuple\n # and extract the last character with [-1] indexing.\n return [string[-1] for string in tup]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(input_tuple):\n \"\"\"\n Extract the last character of each string in the input tuple.\n \n Args:\n input_tuple (tuple): A tuple of strings.\n \n Returns:\n list: A list of last characters of strings from the input tuple.\n \"\"\"\n return [s[-1] for s in input_tuple]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(element_tuple):\n \"\"\"\n This function takes a tuple of strings as input and returns a list of last character of each string in the tuple.\n \n Args:\n element_tuple (tuple): A tuple containing strings.\n \n Returns:\n list: A list of last characters of strings in the input tuple.\n \"\"\"\n \n # Initialize an empty list to store the last character of each string\n last_chars = []\n \n # Iterate over each string in the input tuple\n for string in element_tuple:\n # Append the last character of the string to the list\n last_chars.append(string[-1])\n \n # Return the list of last characters\n return last_chars", "matching_cluster_idx": 3}, {"solution": "def extract_rear(s):\n \"\"\"\n This function takes a tuple of strings as input and returns a list of characters.\n The list contains the last character of each string in the input tuple.\n \n Parameters:\n s (tuple): A tuple of strings\n \n Returns:\n list: A list of characters\n \"\"\"\n return [string[-1] for string in s]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(tup):\n \"\"\"\n This function takes a tuple of strings as input and returns a list of the last character of each string.\n \n Parameters:\n tup (tuple): A tuple of strings.\n \n Returns:\n list: A list of the last character of each string in the input tuple.\n \"\"\"\n return [string[-1] for string in tup]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(t):\n \"\"\"\n Extracts the rear element of each string in the given tuple.\n\n Args:\n t (tuple): A tuple of strings.\n\n Returns:\n list: A list of the rear element of each string in the tuple.\n\n Example:\n >>> extract_rear(('Mers', 'for', 'Vers'))\n ['s', 'r', 's']\n \"\"\"\n return [s[-1] for s in t]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(data):\n \"\"\"\n Extract the rear index element of each string in the given tuple.\n\n Args:\n data (tuple): A tuple containing strings.\n\n Returns:\n list: A list of characters, each character being the rear element of the corresponding string in the input tuple.\n \"\"\"\n return [s[-1] for s in data]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(tuple_input):\n \"\"\"\n This function extracts the rear index element of each string in the given tuple.\n \n Parameters:\n tuple_input (tuple): A tuple of strings.\n \n Returns:\n list: A list of characters corresponding to the rear index of each string.\n \"\"\"\n \n # Initialize an empty list to store the result\n result = []\n \n # Iterate over each string in the tuple\n for string in tuple_input:\n # Get the rear index element of the string\n rear_char = string[-1]\n \n # Append the rear character to the result list\n result.append(rear_char)\n \n # Return the result\n return result", "matching_cluster_idx": 3}, {"solution": "def extract_rear(input_tuple):\n \"\"\"\n Extracts the last character of each string in the input tuple.\n\n Args:\n input_tuple (tuple): A tuple of strings.\n\n Returns:\n list: A list of last characters of the strings in the input tuple.\n \"\"\"\n return [string[-1] for string in input_tuple]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(t):\n \"\"\"\n This function takes a tuple of strings as input and returns a list of last character of each string.\n\n Args:\n t (tuple): A tuple of strings.\n\n Returns:\n list: A list of last characters of the strings in the input tuple.\n\n Example:\n >>> extract_rear(('Mers', 'for', 'Vers'))\n ['s', 'r', 's']\n \"\"\"\n return [string[-1] for string in t]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(tuple_of_strings):\n \"\"\"\n Extract the last character of each string in a given tuple.\n\n Args:\n tuple_of_strings (tuple): A tuple of strings.\n\n Returns:\n list: A list of characters, where each character is the last character of the corresponding string in the input tuple.\n \"\"\"\n return [string[-1] for string in tuple_of_strings]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(tup):\n \"\"\"\n This function takes a tuple of strings as input, and returns a new list containing \n the rear (last character) of each string in the tuple.\n \n Parameters:\n tup (tuple): A tuple of strings.\n \n Returns:\n list: A list of characters, each being the rear (last character) of the corresponding string in the input tuple.\n \"\"\"\n return [string[-1] for string in tup]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(strings_tuple):\n \"\"\"\n This function takes a tuple of strings as an input, and returns a list containing \n the last character of each string in the input tuple.\n \n Parameters:\n strings_tuple (tuple): A tuple of strings.\n \n Returns:\n list: A list of characters, where each character is the last character of a string from the input tuple.\n \"\"\"\n \n # Initialize an empty list to store the rear index elements\n rear_elements = []\n \n # Iterate over each string in the input tuple\n for string in strings_tuple:\n # Extract the last character of the current string using slicing\n rear_element = string[-1]\n \n # Append the rear index element to the list\n rear_elements.append(rear_element)\n \n # Return the list of rear index elements\n return rear_elements", "matching_cluster_idx": 3}, {"solution": "def extract_rear(string_tuple):\n \"\"\"\n Extracts the last character of each string in the given tuple.\n\n Args:\n string_tuple (tuple): A tuple containing strings.\n\n Returns:\n list: A list of characters, each corresponding to the last character of a string in the tuple.\n \"\"\"\n return [string[-1] for string in string_tuple]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(tup):\n \"\"\"\n Extracts only the rear index element of each string in the given tuple.\n\n Args:\n tup (tuple): Input tuple containing strings.\n\n Returns:\n list: List of rear index characters from each string in the input tuple.\n\n Example:\n >>> extract_rear(('Mers', 'for', 'Vers'))\n ['s', 'r', 's']\n \"\"\"\n return [s[-1] for s in tup]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(my_tuple):\n \"\"\"\n This function takes a tuple of strings as input and returns a list of characters.\n Each character is the rear index element of the string it originated from.\n \n Parameters:\n my_tuple (tuple): A tuple of strings.\n \n Returns:\n list: A list of characters, where each character is the rear index of the string from my_tuple.\n \"\"\"\n return [s[-1] for s in my_tuple]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(tuple_of_strings):\n \"\"\"\n This function takes a tuple of strings as input and returns a list of the last characters of each string.\n\n Args:\n tuple_of_strings (tuple): A tuple of strings.\n\n Returns:\n list: A list of last characters of each string in the input tuple.\n \"\"\"\n return [s[-1] for s in tuple_of_strings]", "matching_cluster_idx": 4}]}, "Mbpp/425": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 98.0, "profiled": [{"solution": "def count_element_in_list(lst, target):\n \"\"\"\n This function counts the number of sublists containing a particular element.\n\n Args:\n lst (list): A list of lists.\n target (any): The element to be searched for.\n\n Returns:\n int: The count of sublists containing the target element.\n \"\"\"\n count = 0\n for sublist in lst:\n if target in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, element):\n \"\"\"\n This function counts the number of sublists in the given list that contain the specified element.\n\n Args:\n lst (list): The list of lists to search through.\n element: The element to search for.\n\n Returns:\n int: The number of sublists that contain the specified element.\n \"\"\"\n # Use a generator expression inside the sum function to count the number of sublists that contain the element\n return sum(1 for sublist in lst if element in sublist)", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, element):\n \"\"\"\n Counts the number of sublists in a given list containing a particular element.\n\n Args:\n lst (list): A list of lists.\n element: The element to search for in the sublists.\n\n Returns:\n int: The number of sublists containing the given element.\n\n \"\"\"\n count = 0\n for sublist in lst:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lists, element):\n \"\"\"\n This function counts the number of sublists containing a particular element.\n\n Args:\n lists (list): A list of lists\n element: The element to be searched in sublists\n\n Returns:\n int: The number of sublists containing the element\n \"\"\"\n count = 0\n for sublist in lists:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lists, element):\n \"\"\"\n Counts the number of sublists containing a particular element.\n\n Args:\n lists (list): A list of lists.\n element: The element to be searched.\n\n Returns:\n int: The number of sublists containing the element.\n \"\"\"\n return sum(1 for sublist in lists if element in sublist)", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(sublists, target_element):\n \"\"\"\n This function counts the number of sublists containing a particular element.\n\n Args:\n sublists (list): A list of lists containing integers.\n target_element (int): The target element to be searched.\n\n Returns:\n int: The number of sublists containing the target element.\n\n \"\"\"\n return sum(1 for sublist in sublists if target_element in sublist)", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, element):\n \"\"\"\n Counts the number of sublists containing a particular element.\n\n Args:\n lst (list): A list of lists.\n element: The element to be searched for in sublists.\n\n Returns:\n int: Number of sublists containing the element.\n\n \"\"\"\n count = 0\n for sublist in lst:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(list_of_lists, target):\n \"\"\"\n Count the number of sublists containing a particular element.\n\n Args:\n list_of_lists (list): A list of lists\n target (any): The target element to be searched\n\n Returns:\n int: The number of sublists containing the target element\n \"\"\"\n return sum(1 for sublist in list_of_lists if target in sublist)", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, element):\n \"\"\"\n Counts the number of sublists containing a particular element.\n\n Args:\n lst (list): A list of lists.\n element: The element to search for.\n\n Returns:\n int: The number of sublists containing the element.\n\n Example:\n >>> count_element_in_list([[1, 3], [5, 7], [1, 11], [1, 15, 7]], 1)\n 3\n \"\"\"\n return sum(1 for sublist in lst if element in sublist)", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, element):\n \"\"\"\n This function counts the number of sublists in a given list that contain a particular element.\n\n Args:\n lst (list): A list of lists.\n element: An element to search for in the sublists.\n\n Returns:\n int: The number of sublists that contain the given element.\n \"\"\"\n count = 0\n for sublist in lst:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, target):\n \"\"\"\n Counts the number of sublists containing a particular element.\n \n Args:\n lst (list): A list of lists.\n target (any): The element to search for.\n \n Returns:\n int: The number of sublists containing the target element.\n \"\"\"\n count = 0\n for sublist in lst:\n if target in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, element):\n \"\"\"\n Counts the number of sublists in a given list containing a particular element.\n\n Args:\n lst (list): A list of lists.\n element: The element to be searched.\n\n Returns:\n int: The count of sublists containing the element.\n \"\"\"\n return sum(1 for sublist in lst if element in sublist)", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, target):\n \"\"\"\n Counts the number of sublists in a list containing a particular element.\n \n Args:\n lst (list): List of lists containing integers.\n target (int): Element to search for in sublists.\n\n Returns:\n int: Number of sublists containing the target element.\n \"\"\"\n count = 0\n for sublst in lst:\n if target in sublst:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, element):\n \"\"\"\n Counts the number of sublists containing a particular element.\n\n Args:\n lst (list): A list of lists to search through.\n element: The element to search for.\n\n Returns:\n int: The number of sublists containing the element.\n\n \"\"\"\n return sum(1 for sublist in lst if element in sublist)", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, target):\n \"\"\"\n Counts the number of sublists containing a particular element.\n\n Args:\n lst (list): A 2D list of integers.\n target (int): The element to search for.\n\n Returns:\n int: The number of sublists containing the target element.\n \"\"\"\n return sum(1 for sublist in lst if target in sublist)", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, target):\n \"\"\"\n Counts the number of sublists in the given list of lists that contain a particular element.\n \n Args:\n lst (list): A list of lists\n target: The element to search for in the sublists\n \n Returns:\n int: The number of sublists containing the target element\n \"\"\"\n count = 0\n for sub_list in lst:\n if target in sub_list:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, target):\n \"\"\"\n Counts the number of sublists containing a particular element.\n\n Args:\n lst (list): A list of lists\n target: The element to search for in the sublists\n\n Returns:\n int: The number of sublists containing the target element\n\n \"\"\"\n return sum(1 for sublist in lst if target in sublist)", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, target):\n \"\"\"\n Count the number of sublists containing a particular element.\n\n Args:\n lst (list): A list of lists.\n target: The element to search for in the sublists.\n\n Returns:\n int: The number of sublists containing the target element.\n \"\"\"\n count = 0\n for sublist in lst:\n if target in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, element):\n \"\"\"\n Counts the number of sublists in lst that contain the element.\n\n Args:\n lst (list): A list of lists.\n element: The element to be searched in the sublists.\n\n Returns:\n int: The number of sublists containing the element.\n\n \"\"\"\n count = 0\n for sublist in lst:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, element):\n \"\"\"\n Counts the number of sublists in lst that contain the given element.\n\n Args:\n lst (list): A list of lists (sublists).\n element: The element to search for in the sublists.\n\n Returns:\n int: The number of sublists containing the given element.\n \"\"\"\n return sum(1 for sublist in lst if element in sublist)", "matching_cluster_idx": 4}]}, "Mbpp/428": {"dps": 84.29752066115702, "dps_norm": 55.55555555555556, "pass@1": 99.0, "profiled": [{"solution": "def shell_sort(arr):\n \"\"\"\n Sorts the given array using the Shell sort algorithm.\n \n Args:\n arr (list): The input list to be sorted.\n \n Returns:\n list: A sorted list.\n \"\"\"\n n = len(arr)\n gap = n//2\n \n # Loop until the gap is 0\n while gap > 0:\n # Do a gapped insertion sort for this gap size\n for i in range(gap, n):\n temp = arr[i]\n j = i\n # Shift earlier gap-sorted elements up until the correct location for arr[i] is found\n while j >= gap and arr[j-gap] > temp:\n arr[j] = arr[j-gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n \"\"\"\n Sorts the given array using the shell sort algorithm.\n \n This function uses the insertion sort for each sublist of the array with a large gap\n between its elements and repeatedly reduces the gap until it is 1, resulting in a\n sorted array.\n \n Args:\n arr (list): The array to be sorted.\n \n Returns:\n list: A sorted version of the input array.\n \"\"\"\n # Define the initial gap size\n gap = len(arr) // 2\n \n # Continue the process until the gap size is greater than 0\n while gap > 0:\n # Loop through the array with the current gap size\n for i in range(gap, len(arr)):\n # Store the current element and its index\n temp = arr[i]\n j = i\n \n # Compare elements in the current gap with the elements before it\n while j >= gap and arr[j - gap] > temp:\n # Shift elements to the right until the correct position is found\n arr[j] = arr[j - gap]\n j -= gap\n \n # Place the current element at its correct position\n arr[j] = temp\n \n # Reduce the gap size by half for the next iteration\n gap //= 2\n \n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n \"\"\"\n Sorts an array using Shell sort.\n\n :param arr: The array to be sorted.\n :return: The sorted array.\n \"\"\"\n # Initial gap size\n gap = len(arr) // 2\n \n # Loop until the gap size is 1 (i.e., when the entire array is sorted)\n while gap > 0:\n # Use insertion sort for the given gap size\n for i in range(gap, len(arr)):\n temp = arr[i]\n j = i\n # Shift elements to the right until a smaller element is found or the start of the subarray is reached\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n # Insert the temporary element at the correct position\n arr[j] = temp\n # Reduce gap size by half for the next iteration\n gap //= 2\n \n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n \"\"\"\n Sorts the given array using Shell sort algorithm.\n \n Args:\n arr (list): A list of integers to be sorted.\n \n Returns:\n list: A list of sorted integers.\n \"\"\"\n n = len(arr)\n gap = n//2\n \n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n while j >= gap and arr[j-gap] > temp:\n arr[j] = arr[j-gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n \n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n \"\"\"\n Sorts the given array using Shell sort.\n\n Args:\n arr (list): The array to be sorted\n\n Returns:\n list: The sorted array\n \"\"\"\n # Initialize the gap size\n gap = len(arr) // 2\n \n # Loop until the gap size is greater than zero\n while gap > 0:\n # Loop over the array with the current gap size\n for i in range(gap, len(arr)):\n # Store the current element to be compared\n temp = arr[i]\n \n # Initialize j as the index of the previous element in the gap\n j = i\n \n # Shift the elements in the current gap to the right if they are greater than the temp\n while j >= gap and arr[j - gap] > temp:\n # Shift the element to the right\n arr[j] = arr[j - gap]\n # Move to the previous element in the gap\n j -= gap\n \n # Place the temp in the correct position\n arr[j] = temp\n \n # Reduce the gap size by half\n gap //= 2\n \n # Return the sorted array\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n \"\"\"\n Sorts the given array using the shell sort algorithm.\n \n Args:\n arr (list): The list of numbers to be sorted.\n \n Returns:\n list: The sorted list of numbers.\n \"\"\"\n # Start with a big gap, then reduce the gap\n n = len(arr)\n gap = n // 2\n \n # Do a gapped insertion sort for this gap size. \n # The first gap elements a[0..gap-1], are kept fixed. \n # Insert remaining elements one by one, shifting those that are greater than new element.\n while gap > 0:\n \n # Perform gapped insertion sort for this gap size.\n for i in range(gap, n):\n \n temp = arr[i]\n \n # Shift earlier gap-sorted elements up until placing for the larger element.\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n \n # Place the temp element at its correct location.\n arr[j] = temp\n \n # Reduce gap by half for next iteration\n gap //= 2\n \n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n \"\"\"\n Sort the given array using shell sort.\n\n :param arr: The input array to be sorted.\n :return: A sorted array in ascending order.\n \"\"\"\n # Start with a big gap, then reduce the gap\n gap = len(arr) // 2\n\n while gap > 0:\n # Do a gapped insertion sort for this gap size.\n # The first gap elements are already in order\n # Keep adding one more element until the invocation of gappedInsertionSort can arrange the current gap\n for i in range(gap, len(arr)):\n # store a copy of arr[i]\n temp = arr[i]\n j = i\n # shift previous elements of arr[i], that are greater, to one position ahead of their current position\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n \"\"\"\n Sorts the array using Shell Sort.\n\n :param arr: Input array to be sorted\n :return: Sorted array\n \"\"\"\n # Start with a big gap, then reduce the gap\n gap = len(arr) // 2\n\n while gap > 0:\n # Do a gapped insertion sort for this gap size\n for i in range(gap, len(arr)):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n # Shift previous elements to right\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n # reduce the gap for next iteration\n gap //= 2\n\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n \"\"\"\n Sorts the given array using Shell sort.\n \n Args:\n arr: A list of integers to be sorted\n \n Returns:\n A sorted list of integers\n \"\"\"\n n = len(arr)\n gap = n // 2\n\n while gap > 0:\n # Do a gapped insertion sort for this gap size\n for i in range(gap, n):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n \n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n \"\"\"\n Sorts the given array using Shell sort algorithm.\n\n :param arr: The input array to be sorted.\n :return: The sorted array.\n \"\"\"\n # Start with a big gap, then reduce the gap\n gap = len(arr) // 2\n \n while gap > 0:\n # Do a gapped insertion sort for this gap size.\n # The first gap elements a[0..gap-1] are already in gapped order after previous passes.\n for i in range(gap, len(arr)):\n temp = arr[i]\n j = i\n # shift previous elements of arr[0..i-1], that are greater than temp,\n # to one position ahead of i.\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n # gap = gap / 2 (for next iteration)\n gap //= 2\n\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n \"\"\"\n Function to implement shell sort on the given array.\n\n :param arr: Input list of elements to be sorted\n :return: Sorted list of elements\n \"\"\"\n n = len(arr)\n gap = n // 2\n\n while gap > 0:\n # Iterate over the array with the current gap\n for i in range(gap, n):\n # temp will store the current element\n temp = arr[i]\n j = i\n\n # shift elements of arr[0..i-1] that are greater than temp to one position ahead of their current position\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n\n # place the temp (the element we want to put here) into its correct position\n arr[j] = temp\n gap //= 2\n\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n \"\"\"\n Sorts the given array using the shell sort algorithm.\n\n Args:\n arr (list): A list of elements to be sorted.\n\n Returns:\n list: The sorted list.\n \"\"\"\n # Initialize the gap size to a fraction of the array's length\n gap = len(arr) // 2\n\n # Continue the process until the gap is greater than 0\n while gap > 0:\n # Iterate over the array starting from the gap size to the end\n for i in range(gap, len(arr)):\n # Store the current element\n temp = arr[i]\n\n # Compare the current element with elements at the gap distance\n j = i\n while j >= gap and arr[j - gap] > temp:\n # Shift the current element to the left by one gap distance\n arr[j] = arr[j - gap]\n # Move to the next element\n j -= gap\n\n # Place the current element at its correct position\n arr[j] = temp\n\n # Reduce the gap size for the next iteration\n gap //= 2\n\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n \"\"\"\n This function sorts the given array using the Shell sort algorithm.\n \n :param arr: A list of integers to be sorted\n :return: A sorted list of integers\n \"\"\"\n n = len(arr)\n \n # Start with a big gap, then reduce the gap\n gap = n // 2\n \n while gap > 0:\n # Perform a gapped insertion sort for this gap size.\n # The first element in each sublist is the 'present list', remaining elements follow the gap.\n for i in range(gap, n):\n temp = arr[i]\n j = i\n \n # Shift previous elements of the array if any element smaller than the 'temp' is found.\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n \n arr[j] = temp\n \n # Reduce the gap by half for the next iteration.\n gap //= 2\n \n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n \"\"\"\n Sort the given array using shell sort.\n \n Args:\n arr (list): The list of elements to be sorted.\n \n Returns:\n list: A new sorted list of elements.\n \"\"\"\n n = len(arr)\n gap = n//2\n\n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n while j >= gap and arr[j-gap] > temp:\n arr[j] = arr[j-gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n \"\"\"\n This function sorts the given array using the Shell sort algorithm.\n\n Args:\n arr (list): The input list to be sorted.\n\n Returns:\n list: The sorted list in ascending order.\n \"\"\"\n # Initialize the gap size to half of the list size\n gap = len(arr) // 2\n\n # Continue the process until the gap size is greater than zero\n while gap > 0:\n # Iterate over the list with the given gap\n for i in range(gap, len(arr)):\n # Store the current element\n temp = arr[i]\n\n # Initialize the index for the previous element\n j = i\n\n # Shift elements until a smaller element is found\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n\n # Place the current element at the correct position\n arr[j] = temp\n\n # Reduce the gap size by half for the next iteration\n gap //= 2\n\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n \"\"\"\n Sorts the array using shell sort.\n\n :param arr: The array to sort\n :return: The sorted array\n \"\"\"\n # Start with a big gap, then reduce the gap\n gap = len(arr) // 2\n\n while gap > 0:\n # Do a gapped insertion sort for this gap size.\n # Start at this gap-sized element in the list and insertion sort\n # forward from there until the end of the list has been reached\n for i in range(gap, len(arr)):\n # store a copy of the current element\n temp = arr[i]\n\n # find where to put the current element in the gap-controlled sort\n j = i\n\n # shift earlier gap elements up until correct location for temp is found\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n\n # put temp (the current element to be sorted) into its correct location\n arr[j] = temp\n # Try the gap one sixth again\n gap //= 2\n\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n \"\"\"\n This function sorts an array using the Shell sort algorithm.\n\n :param arr: The input array to be sorted\n :return: The sorted array\n \"\"\"\n n = len(arr)\n\n # Start with a big gap, then reduce the gap\n gap = n//2\n\n # Loop until gap is zero\n while gap > 0:\n # Perform insertion sort for this gap size\n for i in range(gap, n):\n # Store a 'temp' that needs to be placed\n temp = arr[i]\n\n j = i\n # Shift all one position made to the right\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n\n arr[j] = temp\n\n # Reduce gap by half for next iteration\n gap //= 2\n\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n \"\"\"\n Sorts the array using shell sort algorithm.\n \n Args:\n arr (list): The list of elements to be sorted.\n \n Returns:\n list: The sorted list.\n \"\"\"\n n = len(arr)\n \n # Initialize the gap size\n gap = n // 2\n \n while gap > 0:\n # Do a gapped insertion sort for this gap size\n for i in range(gap, n):\n temp = arr[i]\n j = i\n \n # Shift previous elements if they are greater than the current element\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n \n arr[j] = temp\n # Reduce the gap for next iteration\n gap //= 2\n \n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n \"\"\"\n This function sorts the given list using the shell sort algorithm.\n\n Args:\n arr (list): The input list to be sorted.\n\n Returns:\n list: The sorted list.\n \"\"\"\n # Initialize the gap size\n gap = len(arr) // 2\n\n # Loop until the gap size is greater than 0\n while gap > 0:\n # Perform insertion sort for the gap size\n for i in range(gap, len(arr)):\n temp = arr[i]\n j = i\n # Shift previous elements to the right if they are greater than the current element\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n # Insert the element at the correct position\n arr[j] = temp\n # Reduce the gap size by half for the next iteration\n gap //= 2\n\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n \"\"\"\n This function sorts an array using the shell sort algorithm.\n \n :param arr: The input list to be sorted.\n :return: A sorted list.\n \"\"\"\n n = len(arr)\n \n # Initialize the gap size\n gap = n // 2\n \n while gap > 0:\n for i in range(gap, n):\n # Store the current element\n temp = arr[i]\n \n # Shift the previous elements until the correct position is found\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n \n # Place the current element at its correct position\n arr[j] = temp\n \n # Reduce the gap size by half\n gap //= 2\n \n return arr", "matching_cluster_idx": 4}]}, "Mbpp/433": {"dps": 63.88297872340425, "dps_norm": 61.0, "pass@1": 66.0, "profiled": [{"solution": "def check_greater(arr, num):\n \"\"\"\n Checks if the given number is greater than all elements in the array.\n\n Args:\n arr (list): A list of integers.\n num (int): The number to check against the array elements.\n\n Returns:\n bool: True if the number is greater than all elements in the array, False otherwise.\n \"\"\"\n return all(num > x for x in arr)", "matching_cluster_idx": 2}, {"solution": "def check_greater(arr, num):\n \"\"\"\n Checks if a given number is greater than all elements in the given array.\n\n Args:\n arr (list): A list of integers\n num (int): The number to check against the list elements\n\n Returns:\n bool: True if the number is greater than all elements, False otherwise\n \"\"\"\n # Use all() function with generator expression to check if all elements in the array are less than the given number\n return all(num > element for element in arr)", "matching_cluster_idx": 2}, {"solution": "def check_greater(arr, num):\n \"\"\"\n Checks whether the given number is greater than all elements in the array.\n\n Args:\n arr (list): A list of integers.\n num (int): The number to check against.\n\n Returns:\n bool: True if all elements in the array are less than the number, False otherwise.\n \"\"\"\n return all(i < num for i in arr)", "matching_cluster_idx": 2}, {"solution": "def check_greater(arr, num):\n \"\"\"\n Checks whether the given number is greater than all elements in the array.\n\n Args:\n arr (list): A list of numbers.\n num (int): A number to compare with the array elements.\n\n Returns:\n bool: True if the number is greater than all elements in the array, False otherwise.\n\n \"\"\"\n return all(i < num for i in arr)", "matching_cluster_idx": 2}, {"solution": "def check_greater(lst, num):\n \"\"\"\n Checks if the entered number is greater than all elements of the given list.\n \n Args:\n lst (list): A list of integers.\n num (int): The number to compare with list elements.\n \n Returns:\n bool: True if the number is greater than all elements, False otherwise.\n \"\"\"\n return all(i < num for i in lst)", "matching_cluster_idx": 2}, {"solution": "def check_greater(arr, num):\n \"\"\"\n Check whether the entered number is greater than the elements of the given array.\n\n Args:\n arr (list): A list of integers.\n num (int): The number to be compared.\n\n Returns:\n bool: True if the number is greater than all elements of the array, False otherwise.\n \"\"\"\n return all(num > i for i in arr)", "matching_cluster_idx": 2}, {"solution": "def check_greater(lst, num):\n \"\"\"\n This function checks whether the entered number is greater than all the elements of the given array.\n \n Parameters:\n lst (list): A list of numbers\n num (int): The number to check\n \n Returns:\n bool: True if the number is greater than all elements in the list, False otherwise\n \"\"\"\n \n # Iterate over each element in the list\n for element in lst:\n # If the number is less than or equal to any element, return False\n if num <= element:\n return False\n \n # If the number is greater than all elements, return True\n return True", "matching_cluster_idx": 3}, {"solution": "def check_greater(arr, num):\n \"\"\"\n Checks whether the number is greater than all elements in the given array.\n\n Args:\n arr (list): A list of numbers.\n num (int): The number to check.\n\n Returns:\n bool: True if the number is greater than all elements in the array, False otherwise.\n \"\"\"\n return all(num > element for element in arr)", "matching_cluster_idx": 2}, {"solution": "def check_greater(arr, num):\n \"\"\"\n Check whether the entered number is greater than all elements of the given array.\n\n Args:\n arr (list): A list of numbers.\n num (int): The number to check against.\n\n Returns:\n bool: True if the number is greater than all elements in the array, False otherwise.\n \"\"\"\n return all(num > i for i in arr)", "matching_cluster_idx": 2}, {"solution": "def check_greater(arr, num):\n \"\"\"\n Checks if the given number is greater than all elements in the array.\n\n Args:\n arr (list): A list of numbers\n num (int): The number to compare with array elements\n\n Returns:\n bool: True if num is greater than all elements in the array, False otherwise\n \"\"\"\n return all(num > element for element in arr)", "matching_cluster_idx": 2}, {"solution": "def check_greater(array, target):\n \"\"\"\n Checks if all elements in the array are less than the target.\n\n Args:\n array (list): A list of integers.\n target (int): The target number.\n\n Returns:\n bool: True if all elements in the array are less than the target, False otherwise.\n\n \"\"\"\n return all(x < target for x in array)", "matching_cluster_idx": 2}, {"solution": "def check_greater(arr, num):\n \"\"\"\n Checks if a given number is greater than all elements in the array.\n\n Args:\n arr (list): A list of integers.\n num (int): The number to check against the array.\n\n Returns:\n bool: True if all elements in the array are less than the given number, False otherwise.\n \"\"\"\n return all(num > i for i in arr)", "matching_cluster_idx": 2}, {"solution": "def check_greater(arr, num):\n \"\"\"\n Checks whether the given number is greater than all elements in the array.\n\n Args:\n arr (list): A list of integers.\n num (int): The number to compare with array elements.\n\n Returns:\n bool: True if all elements in the array are greater than the given number, False otherwise.\n \"\"\"\n return all(num > element for element in arr)", "matching_cluster_idx": 2}, {"solution": "def check_greater(arr, num):\n \"\"\"\n This function checks if the entered number is greater than all elements of the given array.\n\n Args:\n arr (list): A list of integers.\n num (int): The number to be checked.\n\n Returns:\n bool: True if all elements in the array are less than the number, False otherwise.\n \"\"\"\n return all(num > elem for elem in arr)", "matching_cluster_idx": 2}, {"solution": "def check_greater(arr, num):\n \"\"\"\n Checks whether the entered number is greater than all elements in the given array.\n \n Args:\n arr (list): A list of integers.\n num (int): The number to be checked.\n \n Returns:\n bool: True if the number is greater than all elements, False otherwise.\n \"\"\"\n return all(num > i for i in arr)", "matching_cluster_idx": 2}, {"solution": "def check_greater(arr, num):\n \"\"\"\n This function checks whether the entered number is greater than the elements of the given array.\n\n Args:\n arr (list): A list of integers.\n num (int): A number to compare with the elements in the array.\n\n Returns:\n bool: True if all elements in the array are less than the number, False otherwise.\n \"\"\"\n return all(num > i for i in arr)", "matching_cluster_idx": 2}, {"solution": "def check_greater(arr, num):\n \"\"\"\n This function checks if the given number is greater than all elements in the given array.\n\n Args:\n arr (list): A list of integers.\n num (int): The number to be compared with the array elements.\n\n Returns:\n bool: True if the given number is greater than all elements in the array, False otherwise.\n \"\"\"\n return all(num > element for element in arr)", "matching_cluster_idx": 2}, {"solution": "def check_greater(arr, num):\n \"\"\"\n This function checks if all elements in the array are greater than the given number.\n \n Args:\n arr (list): A list of numbers.\n num (int or float): The number to be compared.\n \n Returns:\n bool: True if all elements in the array are less than the given number, False otherwise.\n \"\"\"\n return all(num > i for i in arr)", "matching_cluster_idx": 2}, {"solution": "def check_greater(arr, num):\n \"\"\"\n This function checks whether the entered number is greater than all elements in the array.\n \n Parameters:\n arr (list): A list of integers.\n num (int): The number to be checked.\n \n Returns:\n bool: True if the number is greater than all elements in the array, False otherwise.\n \"\"\"\n # Use the built-in all function with a generator expression to check if num is greater than all elements in the array\n return all(num > x for x in arr)", "matching_cluster_idx": 2}, {"solution": "def check_greater(arr, num):\n \"\"\"\n This function checks if the given number is greater than all the elements in the array.\n\n Parameters:\n arr (list): A list of numbers\n num (int): The number to compare with array elements\n\n Returns:\n bool: True if all elements are less than the given number, False otherwise\n \"\"\"\n # Use the built-in all() function with a generator expression to check if all elements are less than num\n return all(x < num for x in arr)", "matching_cluster_idx": 2}]}, "Mbpp/437": {"dps": 74.78991596638656, "dps_norm": 37.142857142857146, "pass@1": 14.0, "profiled": [{"solution": "def remove_odd(s):\n \"\"\"\n This function removes all odd-indexed characters from a given string.\n \n Parameters:\n s (str): The input string.\n \n Returns:\n str: A new string with odd-indexed characters removed.\n \"\"\"\n return \"\".join([s[i] for i in range(len(s)) if (i + 1) % 2 == 0])", "matching_cluster_idx": 0}, {"solution": "def remove_odd(c):\n \"\"\"\n Returns a string where all the odd index characters from the given input string are removed.\n \n Args:\n c (str): The input string.\n \n Returns:\n str: The resulting string after removing odd index characters.\n \"\"\"\n return ''.join([c[i] for i in range(len(c)) if (i+1) % 2 == 0])", "matching_cluster_idx": 0}, {"solution": "def remove_odd(s):\n \"\"\"\n Removes odd indexed characters from a string.\n\n Args:\n s (str): The input string.\n\n Returns:\n str: The string with odd indexed characters removed.\n \"\"\"\n return s[1::2] # s[1::2] means start at index 1 and move 2 steps at a time", "matching_cluster_idx": 3}, {"solution": "def remove_odd(s):\n \"\"\"\n Removes all odd indices characters from a string.\n\n Args:\n s (str): Input string\n\n Returns:\n str: String with odd indices characters removed\n \"\"\"\n return s[1::2]", "matching_cluster_idx": 3}, {"solution": "def remove_odd(s):\n \"\"\"\n Remove odd-positioned characters in a string, considering 1-based index.\n\n Args:\n s (str): The input string.\n\n Returns:\n str: A string with odd-positioned characters removed.\n\n Example:\n >>> remove_odd(\"python\")\n 'yhn'\n \"\"\"\n return \"\".join([char for index, char in enumerate(s) if (index + 1) % 2 == 0])", "matching_cluster_idx": 0}, {"solution": "def remove_odd(s):\n \"\"\"\n This function removes odd indexed characters from a given string.\n \n Parameters:\n s (str): The input string.\n \n Returns:\n str: A new string with odd-indexed characters removed.\n \"\"\"\n return s[1::2] # slice string to keep only even-indexed characters", "matching_cluster_idx": 3}, {"solution": "def remove_odd(s):\n \"\"\"\n This function removes all odd-position characters in a given string.\n Position is 1-indexed (i.e., the first character is at position 1).\n \"\"\"\n return ''.join([c for i, c in enumerate(s, 1) if i % 2 == 0])", "matching_cluster_idx": 0}, {"solution": "def remove_odd(s):\n \"\"\"\n Removes odd positioned characters from a given string.\n\n Args:\n s (str): The input string.\n\n Returns:\n str: The resulting string after removing odd positioned characters.\n \"\"\"\n return \"\".join([c for i, c in enumerate(s) if (i+1) % 2 == 0])", "matching_cluster_idx": 0}, {"solution": "def remove_odd(s):\n \"\"\"\n Removes odd indices characters from a string.\n \n Parameters:\n s (str): Input string.\n \n Returns:\n str: String with odd index characters removed.\n \"\"\"\n # Use list comprehension and string slicing to remove characters at odd indices\n return \"\".join([s[i] for i in range(len(s)) if (i+1) % 2 == 0])", "matching_cluster_idx": 0}, {"solution": "def remove_odd(s):\n \"\"\"\n This function takes a string as input and returns a string with all odd \n positioned characters removed.\n \n Position of a character is determined by its position in the string, \n starting from 0 (left to right).\n\n Parameters:\n s (str): The input string.\n\n Returns:\n str: A string with all odd positioned characters removed.\n\n \"\"\"\n return \"\".join([c for i, c in enumerate(s) if (i+1) % 2 == 0])", "matching_cluster_idx": 0}, {"solution": "def remove_odd(s):\n \"\"\"\n This function takes a string as input and returns a new string with all odd \n positioned characters removed. Position of a character is considered as 1 for the \n first character, 2 for the second, and so on. So odd positioned characters \n are the first, third, fifth and so on.\n \n Parameters:\n s (str): The input string.\n \n Returns:\n str: A new string with all odd positioned characters removed.\n \"\"\"\n return ''.join([c for i, c in enumerate(s) if (i + 1) % 2 == 0])", "matching_cluster_idx": 0}, {"solution": "def remove_odd(s):\n \"\"\"\n Removes all odd index characters from a string.\n \n Args:\n s (str): The input string.\n \n Returns:\n str: A string with characters at odd indices removed.\n \"\"\"\n return s[1::2] # slice the string starting from index 1 and taking every 2nd element", "matching_cluster_idx": 3}, {"solution": "def remove_odd(s):\n \"\"\"\n This function removes all odd positioned characters in a string.\n \n Args:\n s (str): The input string\n \n Returns:\n str: A new string with odd positioned characters removed\n \"\"\"\n \n # Use generator expression to iterate over the string and odd indexed characters\n # Use slicing to separate odd and even indexed characters\n # Use join to combine the even indexed characters\n return ''.join([c for i, c in enumerate(s) if (i + 1) % 2 == 0])", "matching_cluster_idx": 0}, {"solution": "def remove_odd(s):\n \"\"\"\n Removes all odd characters from a given string.\n \n Parameters:\n s (str): The input string.\n \n Returns:\n str: The string without odd characters.\n \"\"\"\n return \"\".join([c for i, c in enumerate(s) if (i+1) % 2 == 0])", "matching_cluster_idx": 0}]}, "Mbpp/440": {"dps": null, "dps_norm": null, "pass@1": 1.0, "profiled": []}, "Mbpp/446": {"dps": 96.05911330049261, "dps_norm": 60.0, "pass@1": 37.0, "profiled": [{"solution": "def count_Occurrence(tup, lst):\n \"\"\"\n This function counts the occurrence of all elements of list in a tuple.\n \n Args:\n tup (tuple): A tuple that may contain the elements to be searched.\n lst (list): A list of elements that are to be searched for in the tuple.\n \n Returns:\n int: The sum of occurrences of all elements from the list in the tuple.\n \"\"\"\n return sum(tup.count(i) for i in lst)", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tuple, elements):\n \"\"\"\n This function counts the occurrences of each element in a list within a tuple.\n \n Args:\n tuple (tuple): The input tuple to search in.\n elements (list): A list of elements to find in the tuple.\n \n Returns:\n int: The total count of occurrences of all elements in the list.\n \"\"\"\n return sum(tuple.count(element) for element in elements)", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tup, lst):\n \"\"\"\n This function counts the occurrence of all elements from the list in the tuple.\n \n Args:\n tup (tuple): The input tuple to search in.\n lst (list): The list of elements to search for.\n \n Returns:\n int: The total number of occurrences of elements from the list in the tuple.\n \"\"\"\n return sum(tup.count(i) for i in lst)", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tup, lst):\n \"\"\"\n Counts the occurrence of all elements of the list in the tuple.\n\n Args:\n tup (tuple): A tuple of elements\n lst (list): A list of elements to search for in the tuple\n\n Returns:\n int: The total number of occurrences\n \"\"\"\n return sum(tup.count(element) for element in lst)", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tup, lst):\n \"\"\"\n This function counts the occurrence of all elements of list in a tuple.\n\n Parameters:\n tup (tuple): The tuple in which the occurrence needs to be counted.\n lst (list): The list whose elements are to be searched in the tuple.\n\n Returns:\n int: The total count of occurrences of elements from the list in the tuple.\n \"\"\"\n return sum(tup.count(i) for i in lst)", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(lst_tuple, element_list):\n \"\"\"\n This function counts the occurrence of all elements from the element_list in the lst_tuple.\n\n Parameters:\n lst_tuple (tuple): The input tuple to search for elements.\n element_list (list): A list of elements to count occurrences for.\n\n Returns:\n int: The total count of occurrences of all elements from element_list in lst_tuple.\n \"\"\"\n return sum(lst_tuple.count(element) for element in element_list)", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tup, lst):\n \"\"\"\n Counts the occurrence of elements of lst in the given tuple tup.\n\n Args:\n tup (tuple): The input tuple to search for elements.\n lst (list): The list of elements to search for in the tuple.\n\n Returns:\n int: The total number of occurrences of elements from lst in tup.\n\n \"\"\"\n return sum(tup.count(element) for element in lst)", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tup, lst):\n \"\"\"\n This function counts the occurrence of all elements of a list in a tuple.\n\n Args:\n tup (tuple): A tuple of elements.\n lst (list): A list of elements to be searched in the tuple.\n\n Returns:\n int: The total count of occurrences of elements from the list in the tuple.\n\n Raises:\n TypeError: If input 'tup' is not a tuple or 'lst' is not a list.\n \"\"\"\n\n if not isinstance(tup, tuple) or not isinstance(lst, list):\n raise TypeError(\"Input types are incorrect. 'tup' should be a tuple and 'lst' should be a list.\")\n\n return sum(tup.count(i) for i in lst)", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tuple_list, elements):\n \"\"\"\n This function takes a tuple and a list of elements as input. \n It returns the total count of elements in the tuple for the given list of elements.\n \n Args:\n tuple_list (tuple): The input tuple.\n elements (list): A list of elements to count.\n \n Returns:\n int: The total count of elements in the tuple.\n \"\"\"\n # Convert the tuple to a list to enable indexing and counting\n list_of_tuple = list(tuple_list)\n \n # Initialize a counter variable to store the count of elements\n count = 0\n \n # Iterate over each element in the list\n for element in elements:\n # Count the occurence of the element in the list of tuple\n count += list_of_tuple.count(element)\n \n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tuple_list, lst):\n \"\"\"\n Counts the total occurrence of elements from list in a tuple.\n\n Args:\n tuple_list (tuple): The input tuple.\n lst (list): The list of elements to be searched.\n\n Returns:\n int: The total count of occurrences.\n\n \"\"\"\n return sum(tuple_list.count(element) for element in lst)", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tuple_list, lst):\n \"\"\"\n Count the occurrence of all elements of list in a tuple.\n \n Args:\n tuple_list (tuple): The tuple in which to count the elements.\n lst (list): The list of elements to count.\n\n Returns:\n int: The total number of occurrences of elements from the list in the tuple.\n \"\"\"\n return sum(tuple_list.count(element) for element in lst)", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tuple_list, to_count):\n \"\"\"\n Counts the occurrence of elements in 'to_count' list within 'tuple_list' tuple.\n\n Args:\n tuple_list (tuple): The input tuple containing the elements to count from.\n to_count (list): The list of elements to count the occurrence of.\n\n Returns:\n int: The total count of elements from 'to_count' found in 'tuple_list'.\n \"\"\"\n count = 0\n for element in to_count:\n count += tuple_list.count(element)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(lst_tuple, elements):\n \"\"\"\n Counts the occurrences of all elements in a given list within a tuple.\n\n Args:\n lst_tuple (tuple): The input tuple to search in.\n elements (list): A list of elements to count occurrences for.\n\n Returns:\n int: The total count of occurrences of the given elements.\n \"\"\"\n return sum(lst_tuple.count(element) for element in elements)", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tup, lst):\n \"\"\"\n This function counts the occurrence of elements of list in a tuple.\n\n Args:\n tup (tuple): A tuple containing elements of any type.\n lst (list): A list containing elements to be searched in the tuple.\n\n Returns:\n int: The sum of the occurrences of elements from the list in the tuple.\n \"\"\"\n return sum([tup.count(i) for i in lst])", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(input_tuple, elements_list):\n \"\"\"\n This function counts the occurrence of each element from elements_list in input_tuple.\n\n Args:\n input_tuple (tuple): A tuple containing elements to check.\n elements_list (list): A list containing elements to count occurrences of.\n\n Returns:\n int: Total number of occurrences.\n\n Raises:\n TypeError: If input_tuple is not a tuple or elements_list is not a list.\n \"\"\"\n # Check if input is of correct type\n if not isinstance(input_tuple, tuple) or not isinstance(elements_list, list):\n raise TypeError(\"Input tuple and list must be of type 'tuple' and 'list', respectively.\")\n\n # Initialize a counter\n total_count = 0\n for element in elements_list:\n total_count += input_tuple.count(element)\n\n return total_count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(lst_tuple, lst):\n \"\"\"\n Counts the occurrence of all elements of a list in a tuple.\n\n Args:\n lst_tuple (tuple): A tuple containing elements.\n lst (list): A list containing elements to be searched in the tuple.\n\n Returns:\n int: The total count of occurrences of elements from the list in the tuple.\n \"\"\"\n return sum(lst_tuple.count(item) for item in lst)", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(input_tuple, element_list):\n \"\"\"\n This function takes in a tuple and a list of elements, then returns the total occurrences of the elements from the list within the tuple.\n \n Args:\n input_tuple (tuple): A tuple containing the list of elements to be searched.\n element_list (list): A list of elements to be searched within the tuple.\n \n Returns:\n int: The total occurrences of the elements from the list within the tuple.\n \"\"\"\n \n # Use a for loop to iterate over each element in the list\n count = 0\n for element in element_list:\n # Use the count method of the tuple to count the occurrences of the current element\n count += input_tuple.count(element)\n \n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tup, lis):\n \"\"\"\n Counts the total occurrences of elements from the list within the tuple.\n\n Args:\n tup (tuple): The tuple to search within.\n lis (list): The list of elements to count.\n\n Returns:\n int: Total occurrences of elements from the list within the tuple.\n \"\"\"\n return sum(tup.count(element) for element in lis)", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(input_tuple, elements):\n \"\"\"\n Counts the occurrences of all elements of a given list in a tuple.\n\n Args:\n input_tuple (tuple): The input tuple to search in.\n elements (list): The list of elements to search for.\n\n Returns:\n int: The total count of occurrences.\n\n \"\"\"\n return sum(input_tuple.count(element) for element in elements)", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tuple, lst):\n \"\"\"\n Count the occurrence of elements in the list within a given tuple.\n \n Args:\n tuple: A tuple to search in.\n lst: A list of elements to search for.\n \n Returns:\n An integer indicating the total occurrence of elements in the list.\n \"\"\"\n count = 0\n for element in lst:\n count += tuple.count(element)\n return count", "matching_cluster_idx": 2}]}, "Mbpp/451": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 93.0, "profiled": [{"solution": "def remove_whitespaces(s):\n \"\"\"\n This function removes all whitespaces from a given string.\n\n Args:\n s (str): The input string.\n\n Returns:\n str: A new string with all whitespaces removed.\n \"\"\"\n # Use the replace() method to replace each whitespace with an empty string\n return s.replace(' ', '')", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(s):\n \"\"\"\n Removes all whitespaces from the given string.\n\n Args:\n s (str): The input string.\n\n Returns:\n str: The input string with all whitespaces removed.\n \"\"\"\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(s):\n \"\"\"\n This function removes all the whitespaces from the given string.\n\n Args:\n s (str): The input string.\n\n Returns:\n str: The string with all whitespaces removed.\n\n \"\"\"\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(s):\n \"\"\"\n This function removes all whitespaces from a given string.\n\n Args:\n s (str): The input string from which whitespaces will be removed.\n\n Returns:\n str: The input string with all whitespaces removed.\n \"\"\"\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(s):\n \"\"\"\n This function removes all the whitespaces from the given string.\n\n Args:\n s (str): The input string from which to remove whitespaces.\n\n Returns:\n str: The string with all whitespaces removed.\n \"\"\"\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(s):\n \"\"\"\n Removes all whitespaces from the given string.\n\n Args:\n s (str): The input string from which whitespaces will be removed.\n\n Returns:\n str: The input string with all whitespaces removed.\n \"\"\"\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(s):\n \"\"\"\n Remove all whitespaces from the given string.\n\n Args:\n s (str): The input string.\n\n Returns:\n str: The string with all whitespaces removed.\n\n Example:\n >>> remove_whitespaces(' Google Flutter ')\n 'GoogleFlutter'\n \"\"\"\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(s):\n \"\"\"\n This function removes all the whitespaces from a given string.\n \n Args:\n s (str): The input string from which whitespaces need to be removed.\n \n Returns:\n str: The string with all whitespaces removed.\n \"\"\"\n # Use the built-in replace() method of the string class to replace all spaces with an empty string\n s_without_spaces = s.replace(' ', '')\n \n return s_without_spaces", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(s):\n \"\"\"\n Removes all whitespaces from a given string.\n \n Args:\n s (str): The input string.\n \n Returns:\n str: The string without whitespaces.\n \"\"\"\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(s):\n \"\"\"\n Removes all whitespaces from the given string.\n \n Args:\n s (str): The input string.\n \n Returns:\n str: The string without any whitespaces.\n \"\"\"\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(s):\n \"\"\"\n Removes all whitespaces from a given string.\n\n Args:\n s (str): Input string from which whitespaces will be removed.\n\n Returns:\n str: The input string with all whitespaces removed.\n \"\"\"\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(s):\n \"\"\"\n This function removes all whitespaces from a given string.\n \n Parameters:\n s (str): The input string to remove whitespaces from.\n \n Returns:\n str: The input string with all whitespaces removed.\n \"\"\"\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string):\n \"\"\"\n This function removes all whitespaces from the given string.\n\n Args:\n input_string (str): The string to remove whitespaces from.\n\n Returns:\n str: The string with all whitespaces removed.\n \"\"\"\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(s):\n \"\"\"\n This function removes all whitespaces from the given string.\n\n Args:\n s (str): The input string from which to remove whitespaces.\n\n Returns:\n str: A string with all whitespaces removed.\n \"\"\"\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(s):\n \"\"\"\n Removes all whitespaces from the given string.\n\n Args:\n s (str): The input string.\n\n Returns:\n str: The string with all whitespaces removed.\n \"\"\"\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(s):\n \"\"\"\n This function removes all whitespaces from a given string.\n\n Args:\n s (str): The input string.\n\n Returns:\n str: The string without whitespaces.\n\n \"\"\"\n return s.replace(' ', '')", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(s):\n \"\"\"\n Removes all whitespaces from a given string.\n \n Args:\n s (str): The input string from which whitespaces need to be removed.\n \n Returns:\n str: The string with all whitespaces removed.\n \"\"\"\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(s):\n \"\"\"\n This function removes all whitespaces from a given string.\n \n Parameters:\n s (str): The input string.\n \n Returns:\n str: The input string without whitespaces.\n \"\"\"\n \n # Using the str.replace() method to replace whitespaces with an empty string\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(s):\n \"\"\"\n This function takes a string and returns the same string with all whitespaces removed.\n\n Args:\n s (str): The input string\n\n Returns:\n str: The input string with all whitespaces removed\n \"\"\"\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(s):\n \"\"\"\n Removes all whitespaces from the given string.\n\n Args:\n s (str): The input string.\n\n Returns:\n str: The input string without whitespaces.\n \"\"\"\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}]}, "Mbpp/456": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def reverse_string_list(strings):\n \"\"\"\n This function takes a list of strings as an argument and returns a new list\n where each string in the input list is reversed.\n \n Args:\n strings (list): A list of strings.\n \n Returns:\n list: A list of strings with each string reversed.\n \"\"\"\n return [s[::-1] for s in strings]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(input_list):\n \"\"\"\n Reverses each string in the given list of string values.\n\n Args:\n input_list (list): A list of string values.\n\n Returns:\n list: A list with each string from the input list reversed.\n \"\"\"\n # Using a list comprehension to reverse each string in the input list\n reversed_list = [s[::-1] for s in input_list]\n \n return reversed_list", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(strings):\n \"\"\"\n Reverses each string in a given list of string values.\n\n Args:\n strings (list): A list of string values.\n\n Returns:\n list: A list of string values where each string is reversed.\n \"\"\"\n # Use list comprehension with slicing to reverse each string in the list\n reversed_strings = [s[::-1] for s in strings]\n return reversed_strings", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(strings):\n \"\"\"\n This function takes a list of strings and returns a new list with each string reversed.\n \n Args:\n strings (list): A list of string values.\n \n Returns:\n list: A new list with each string reversed.\n \"\"\"\n # Initialize an empty list to store the reversed strings\n reversed_strings = []\n \n # Iterate over each string in the input list\n for string in strings:\n # Reverse the string using slicing\n reversed_string = string[::-1]\n # Append the reversed string to the list\n reversed_strings.append(reversed_string)\n \n # Return the list of reversed strings\n return reversed_strings\nstrings = ['Red', 'Green', 'Blue', 'White', 'Black']", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n \"\"\"\n This function takes a list of strings and returns a new list where each string is reversed.\n \n Parameters:\n string_list (list): A list of string values.\n \n Returns:\n list: A list of reversed string values.\n \"\"\"\n # Using list comprehension to create a new list with reversed strings\n reversed_list = [string[::-1] for string in string_list]\n return reversed_list", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(input_list):\n \"\"\"\n Reverses each string in the input list.\n \n Args:\n input_list (list): A list of string values.\n \n Returns:\n list: A list with each string reversed.\n \"\"\"\n # Use list comprehension to reverse each string in the list\n return [s[::-1] for s in input_list]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n \"\"\"\n Reverses each string in the input list of strings.\n\n Args:\n string_list (list): A list of string values.\n\n Returns:\n list: A new list of strings with each string reversed.\n \"\"\"\n return [s[::-1] for s in string_list]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(strings):\n \"\"\"\n Reverses each string in a given list of string values.\n\n Args:\n strings (list): A list of strings to reverse.\n\n Returns:\n list: A list with each string reversed.\n \"\"\"\n return [s[::-1] for s in strings]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n \"\"\"\n Reverses each string in the input list.\n\n Args:\n string_list (list): A list of string values.\n\n Returns:\n list: A new list with each string reversed.\n \"\"\"\n return [s[::-1] for s in string_list]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n \"\"\"\n This function takes a list of strings as input and returns a new list with each string reversed.\n\n Args:\n string_list (list): A list of strings\n\n Returns:\n list: A list of strings with each string reversed\n\n Example:\n >>> reverse_string_list(['Red', 'Green', 'Blue', 'White', 'Black'])\n ['deR', 'neerG', 'eulB', 'etihW', 'kcalB']\n \"\"\"\n return [s[::-1] for s in string_list]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n \"\"\"\n Reverses each string in a given list of string values.\n\n Args:\n string_list (list): A list of strings.\n\n Returns:\n list: A list with each string reversed.\n \"\"\"\n # Use list comprehension and slicing to reverse each string in the list\n reversed_list = [string[::-1] for string in string_list]\n return reversed_list", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n \"\"\"\n Reverses each string in a given list of string values.\n\n Args:\n string_list (list): A list of string values.\n\n Returns:\n list: A list of string values with each string reversed.\n\n \"\"\"\n return [s[::-1] for s in string_list]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(lst):\n \"\"\"\n This function takes a list of strings as input and returns a new list with each string reversed.\n\n Args:\n lst (list): A list of string values.\n\n Returns:\n list: A new list with each string reversed.\n \"\"\"\n return [s[::-1] for s in lst]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n \"\"\"\n This function takes a list of string values and returns a new list with each string reversed.\n \n Args:\n string_list (list): A list of string values.\n \n Returns:\n list: A list of strings where each string is reversed.\n \"\"\"\n return [string[::-1] for string in string_list]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(lst):\n \"\"\"\n This function takes a list of strings and returns a new list where each string is reversed.\n\n Args:\n lst (list): A list of strings.\n\n Returns:\n list: A new list with each string in the input list reversed.\n\n \"\"\"\n return [s[::-1] for s in lst]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(strings):\n \"\"\"\n Reverses each string in a given list of string values.\n\n Args:\n strings (list): A list of strings.\n\n Returns:\n list: A new list with each string reversed.\n\n Example:\n >>> reverse_string_list(['Red', 'Green', 'Blue', 'White', 'Black'])\n ['deR', 'neerG', 'eulB', 'etihW', 'kcalB']\n \"\"\"\n return [s[::-1] for s in strings]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n \"\"\"\n This function takes a list of strings as input and returns a new list with each string reversed.\n\n Args:\n string_list (list): A list of string values.\n\n Returns:\n list: A list of reversed string values.\n \"\"\"\n # Use list comprehension with the built-in str.reverse method to reverse each string\n reversed_list = [s[::-1] for s in string_list]\n return reversed_list", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(strings):\n \"\"\"\n This function takes a list of strings as input and returns a new list with each string reversed.\n\n Args:\n strings (list): A list of string values.\n\n Returns:\n list: A list of reversed strings.\n \"\"\"\n reversed_strings = []\n for string in strings:\n reversed_strings.append(string[::-1])\n return reversed_strings", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n \"\"\"\n Reverses each string in a given list of string values.\n\n Args:\n string_list (list): A list of strings.\n\n Returns:\n list: A new list with each string reversed.\n \"\"\"\n # Use a list comprehension to create a new list with reversed strings\n return [s[::-1] for s in string_list]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n \"\"\"\n This function takes a list of strings as input, reverses each string in the list, and returns the list with reversed strings.\n\n Args:\n string_list (list): A list of string values.\n\n Returns:\n list: A list with each string from the input list reversed.\n \"\"\"\n # Use a list comprehension to create a new list with reversed strings\n reversed_list = [s[::-1] for s in string_list]\n \n return reversed_list", "matching_cluster_idx": 4}]}, "Mbpp/460": {"dps": 94.8076923076923, "dps_norm": 98.0, "pass@1": 90.0, "profiled": [{"solution": "def Extract(sublists):\n \"\"\"\n Extract the first element of each sublist.\n \n Args:\n sublists (list): A list of lists.\n \n Returns:\n list: A list of the first element of each sublist.\n \"\"\"\n return [sublist[0] for sublist in sublists]", "matching_cluster_idx": 4}, {"solution": "def Extract(lists):\n \"\"\"\n This function takes a list of sublists and returns a new list containing the first element of each sublist.\n \n Args:\n lists (list): A list of sublists.\n\n Returns:\n list: A list containing the first element of each sublist.\n \"\"\"\n return [sublist[0] for sublist in lists]", "matching_cluster_idx": 4}, {"solution": "def Extract(lst):\n \"\"\"\n This function takes a list of lists (sublists) as input and returns a new list with the first element of each sublist.\n \n Args:\n lst (list): A list of lists (sublists)\n\n Returns:\n list: A list of the first elements from each sublist\n \"\"\"\n return [sublist[0] for sublist in lst]", "matching_cluster_idx": 4}, {"solution": "def Extract(sublists):\n \"\"\"\n Returns a list containing the first element of each sublist.\n \n Parameters:\n sublists (list): A list of lists containing elements.\n \n Returns:\n list: A list containing the first element of each sublist.\n \"\"\"\n return [sublist[0] for sublist in sublists]", "matching_cluster_idx": 4}, {"solution": "def Extract(sublists):\n \"\"\"\n This function takes a list of sublists as input and returns a new list containing \n the first element of each sublist.\n \n Args:\n sublists (list): A list of sublists.\n \n Returns:\n list: A list containing the first element of each sublist.\n \"\"\"\n # Use a list comprehension to iterate over each sublist and select the first element\n return [sublist[0] for sublist in sublists]", "matching_cluster_idx": 4}, {"solution": "def Extract(list_of_lists):\n \"\"\"\n Returns a new list containing the first element of each sublist.\n \n Args:\n list_of_lists (list): A list of lists.\n\n Returns:\n list: A list of the first elements of each sublist.\n \"\"\"\n return [sublist[0] for sublist in list_of_lists]", "matching_cluster_idx": 4}, {"solution": "def Extract(sublists):\n \"\"\"\n This function takes a list of sublists as input and returns a new list containing the first element of each sublist.\n \n Args:\n sublists (list): A list of lists.\n \n Returns:\n list: A new list containing the first element of each sublist.\n \"\"\"\n return [sublist[0] for sublist in sublists]", "matching_cluster_idx": 4}, {"solution": "def Extract(lists):\n \"\"\"\n Returns a list containing the first element of each sublist.\n\n Args:\n lists (list): A list of lists.\n\n Returns:\n list: A list containing the first element of each sublist.\n \"\"\"\n return [sublist[0] for sublist in lists if sublist]", "matching_cluster_idx": 3}, {"solution": "def Extract(lst):\n \"\"\"\n Returns a new list containing the first element of each sublist in the input list.\n\n Args:\n lst (list): A list of lists.\n\n Returns:\n list: A list containing the first element of each sublist.\n\n Example:\n >>> Extract([[1, 2], [3, 4, 5], [6, 7, 8, 9]])\n [1, 3, 6]\n \"\"\"\n return [sublist[0] for sublist in lst]", "matching_cluster_idx": 4}, {"solution": "def Extract(lists):\n \"\"\"\n Get the first element of each sublist.\n\n Args:\n lists (list): A list of lists containing elements.\n\n Returns:\n list: A list of the first elements from each sublist.\n\n Example:\n >>> Extract([[1, 2], [3, 4, 5], [6, 7, 8, 9]])\n [1, 3, 6]\n \"\"\"\n return [sublist[0] for sublist in lists if sublist]", "matching_cluster_idx": 3}, {"solution": "def Extract(sublists):\n \"\"\"\n Returns a list containing the first element of each sublist.\n\n Args:\n sublists (list): A list of lists.\n\n Returns:\n list: A list containing the first element of each sublist.\n\n Example:\n >>> Extract([[1, 2], [3, 4, 5], [6, 7, 8, 9]])\n [1, 3, 6]\n \"\"\"\n return [sublist[0] for sublist in sublists]", "matching_cluster_idx": 4}, {"solution": "def Extract(lst):\n \"\"\"\n This function takes a list of lists as input and returns a new list containing the first element from each sublist.\n\n Args:\n lst (list): A list of lists.\n\n Returns:\n list: A list containing the first element from each sublist.\n\n Example:\n >>> Extract([[1, 2], [3, 4, 5], [6, 7, 8, 9]])\n [1, 3, 6]\n \"\"\"\n return [sublist[0] for sublist in lst]", "matching_cluster_idx": 4}, {"solution": "def Extract(lst):\n \"\"\"\n Function to extract the first element of each sublist from a list of lists.\n\n Args:\n lst (list): A list of lists.\n\n Returns:\n list: A list containing the first element of each sublist.\n\n Example:\n >>> Extract([[1, 2], [3, 4, 5], [6, 7, 8, 9]])\n [1, 3, 6]\n \"\"\"\n return [sublist[0] for sublist in lst]", "matching_cluster_idx": 4}, {"solution": "def Extract(sublists):\n \"\"\"\n Returns a list with the first element of each sublist.\n\n Args:\n sublists (list): A list of lists.\n\n Returns:\n list: A list with the first element of each sublist.\n\n Examples:\n >>> Extract([[1, 2], [3, 4, 5], [6, 7, 8, 9]])\n [1, 3, 6]\n \"\"\"\n return [sublist[0] for sublist in sublists]", "matching_cluster_idx": 4}, {"solution": "def Extract(lst):\n \"\"\"\n Extract the first element of each sublist in a list of lists.\n\n Args:\n lst (list): A list containing sublists.\n\n Returns:\n list: A list of the first elements of each sublist.\n \"\"\"\n return [sublist[0] for sublist in lst]", "matching_cluster_idx": 4}, {"solution": "def Extract(sublists):\n \"\"\"\n Returns the first element of each sublist in the given list of sublists.\n \n Args:\n sublists (list): A list of lists containing elements of any type.\n \n Returns:\n list: A list containing the first element of each sublist.\n \"\"\"\n return [sublist[0] for sublist in sublists]", "matching_cluster_idx": 4}, {"solution": "def Extract(sublists):\n \"\"\"\n This function takes a list of lists as input and returns a new list\n containing the first element from each sublist.\n\n Args:\n sublists (list): A list of lists.\n\n Returns:\n list: A list of the first element from each sublist.\n \"\"\"\n return [sublist[0] for sublist in sublists]", "matching_cluster_idx": 4}, {"solution": "def Extract(sublists):\n \"\"\"\n Returns a list of the first element from each sublist.\n \n Args:\n sublists (list): A list of lists.\n \n Returns:\n list: A list of the first element from each sublist.\n \"\"\"\n return [sublist[0] for sublist in sublists]", "matching_cluster_idx": 4}, {"solution": "def Extract(sublists):\n \"\"\"\n This function takes a list of sublists as input and returns a list of the first element of each sublist.\n\n Args:\n sublists (list): A list of sublists.\n\n Returns:\n list: A list of the first element of each sublist.\n \"\"\"\n return [sublist[0] for sublist in sublists]", "matching_cluster_idx": 4}, {"solution": "def Extract(lst):\n \"\"\"\n Returns a list of the first element of each sublist in the input list.\n \n Args:\n lst (list): A list of lists.\n \n Returns:\n list: A list of the first element of each sublist.\n \"\"\"\n return [sublist[0] for sublist in lst]", "matching_cluster_idx": 4}]}, "Mbpp/474": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 99.0, "profiled": [{"solution": "def replace_char(s, old, new):\n \"\"\"\n This function replaces 'old' character with 'new' in the string 's'.\n \n Args:\n s (str): The input string.\n old (str): The character to replace.\n new (str): The new character to replace with.\n\n Returns:\n str: The string after replacing 'old' with 'new'.\n \"\"\"\n return s.replace(old, new)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, old_char, new_char):\n \"\"\"\n Replace all occurrences of 'old_char' with 'new_char' in string 's'.\n\n Args:\n s (str): The original string.\n old_char (str): The character to replace.\n new_char (str): The character to replace with.\n\n Returns:\n str: The modified string.\n \"\"\"\n return s.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, old_char, new_char):\n \"\"\"\n Replace a character in a string.\n\n Parameters:\n s (str): Input string.\n old_char (str): Character to be replaced.\n new_char (str): Replacement character.\n\n Returns:\n str: String with old_char replaced by new_char.\n \"\"\"\n return s.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, char_to_replace, replacement_char):\n \"\"\"\n Replace all occurrences of char_to_replace in string s with replacement_char.\n \n Args:\n s (str): Input string.\n char_to_replace (str): Character to replace in the string.\n replacement_char (str): Replacement character.\n \n Returns:\n str: The modified string with char_to_replace replaced by replacement_char.\n \"\"\"\n return s.replace(char_to_replace, replacement_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, old_char, new_char):\n \"\"\"\n This function replaces 'old_char' with 'new_char' in the given string 's'.\n\n Args:\n s (str): The input string.\n old_char (str): The character to be replaced.\n new_char (str): The replacement character.\n\n Returns:\n str: The modified string with 'old_char' replaced by 'new_char'.\n \"\"\"\n return s.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, old, new):\n \"\"\"\n Replace all occurrences of a character in a string.\n\n Args:\n s (str): The original string.\n old (str): The character to be replaced.\n new (str): The replacement character.\n\n Returns:\n str: The modified string with all occurrences of 'old' replaced with 'new'.\n \"\"\"\n return s.replace(old, new)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, old, new):\n \"\"\"\n Replace occurrences of a character in a string with a different character.\n \n Args:\n s (str): The original string.\n old (str): The character to be replaced.\n new (str): The character to replace with.\n \n Returns:\n str: The string after replacement.\n \"\"\"\n return s.replace(old, new)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, old, new):\n \"\"\"\n Replaces occurrences of a character in a string.\n\n Args:\n s (str): The input string.\n old (str): The character to be replaced.\n new (str): The character to replace with.\n\n Returns:\n str: The string with all occurrences of 'old' replaced by 'new'.\n \"\"\"\n return s.replace(old, new)", "matching_cluster_idx": 6}, {"solution": "def replace_char(string, old_char, new_char):\n \"\"\"\n Replaces all occurrences of a character in a string with a new character.\n\n Args:\n string (str): The input string.\n old_char (str): The character to replace.\n new_char (str): The character to replace with.\n\n Returns:\n str: The string with all occurrences of old_char replaced with new_char.\n \"\"\"\n return string.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, a, b):\n \"\"\"\n Replaces all occurrences of character 'a' with 'b' in string 's'.\n\n Args:\n s (str): The original string.\n a (str): The character to be replaced.\n b (str): The character to replace with.\n\n Returns:\n str: The modified string.\n \"\"\"\n return s.replace(a, b)", "matching_cluster_idx": 6}, {"solution": "def replace_char(input_str, char_to_replace, replacement_char):\n \"\"\"\n Replace a specific character in a string with another character.\n \n Args:\n input_str (str): The input string.\n char_to_replace (str): The character to replace.\n replacement_char (str): The replacement character.\n \n Returns:\n str: The string with the specified character replaced.\n \"\"\"\n return input_str.replace(char_to_replace, replacement_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, old_char, new_char):\n \"\"\"\n Replace all occurrences of old_char in s with new_char.\n\n Args:\n s (str): The input string.\n old_char (str): The character to be replaced.\n new_char (str): The character to replace with.\n\n Returns:\n str: The modified string with all occurrences of old_char replaced with new_char.\n \"\"\"\n return s.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, old_char, new_char):\n \"\"\"\n Replaces all occurrences of old_char with new_char in string s.\n \n Args:\n s (str): The input string.\n old_char (str): The character to be replaced.\n new_char (str): The character to replace with.\n \n Returns:\n str: The modified string with all occurrences of old_char replaced with new_char.\n \"\"\"\n return s.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, old, new):\n \"\"\"\n This function replaces a specified character in a string.\n\n Args:\n s (str): The input string.\n old (str): The character to be replaced.\n new (str): The replacement character.\n\n Returns:\n str: The string with the specified character replaced.\n \"\"\"\n return s.replace(old, new)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, old, new):\n \"\"\"\n Replaces all occurrences of a character in a string.\n\n Args:\n s (str): The input string.\n old (str): The character to be replaced.\n new (str): The character to replace with.\n\n Returns:\n str: The string with all occurrences of the character replaced.\n \"\"\"\n return s.replace(old, new)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, char_to_replace, replacement):\n \"\"\"\n Replaces all occurrences of a character in a string.\n\n Args:\n s (str): The original string.\n char_to_replace (str): The character to be replaced.\n replacement (str): The character to replace with.\n\n Returns:\n str: The modified string.\n \"\"\"\n return s.replace(char_to_replace, replacement)", "matching_cluster_idx": 6}, {"solution": "def replace_char(string, char_to_replace, char_to_insert):\n \"\"\"\n Replaces a character in the string with a new character.\n\n Args:\n string (str): Input string to replace characters in.\n char_to_replace (str): Character to be replaced.\n char_to_insert (str): Character to insert in place of the character to be replaced.\n\n Returns:\n str: Modified string with characters replaced.\n \"\"\"\n return string.replace(char_to_replace, char_to_insert)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, char_to_replace, replacement):\n \"\"\"\n Replace a character in a string.\n\n Args:\n s (str): The input string.\n char_to_replace (str): The character to replace in the string.\n replacement (str): The character to replace with.\n\n Returns:\n str: The modified string after replacement.\n \"\"\"\n return s.replace(char_to_replace, replacement)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, char_to_replace, new_char):\n \"\"\"\n Replace all occurrences of a specified character in a string with another character.\n \n Args:\n s (str): The input string.\n char_to_replace (str): The character to be replaced.\n new_char (str): The replacement character.\n \n Returns:\n str: The modified string with the specified character replaced.\n \"\"\"\n return s.replace(char_to_replace, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(string, char_to_replace, replacement_char):\n \"\"\"\n Replaces a given character in a string with a replacement character.\n \n Args:\n string (str): The input string.\n char_to_replace (str): The character to be replaced.\n replacement_char (str): The replacement character.\n \n Returns:\n str: The modified string.\n \"\"\"\n return string.replace(char_to_replace, replacement_char)", "matching_cluster_idx": 6}]}, "Mbpp/476": {"dps": 96.20805369127517, "dps_norm": 97.5, "pass@1": 100.0, "profiled": [{"solution": "def big_sum(numbers):\n \"\"\"\n Returns the sum of the largest and smallest value in a given array.\n\n Args:\n numbers (list): A list of numbers.\n\n Returns:\n int: The sum of the largest and smallest value.\n\n Raises:\n ValueError: If the input list is empty.\n \"\"\"\n if not numbers:\n raise ValueError(\"Input list cannot be empty\")\n\n return max(numbers) + min(numbers)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n \"\"\"\n Calculate the sum of the largest and smallest value in an array.\n \n Args:\n arr (list): The input list of numbers.\n \n Returns:\n int: The sum of the largest and smallest value in the list.\n \"\"\"\n if not arr:\n raise ValueError(\"Input list is empty\")\n \n return max(arr) + min(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(numbers):\n \"\"\"\n This function calculates the sum of the largest and smallest value in a given array.\n\n Args:\n numbers (list): A list of numbers.\n\n Returns:\n int: The sum of the largest and smallest number in the list.\n\n Raises:\n ValueError: If the input list is empty.\n\n \"\"\"\n if not numbers:\n raise ValueError(\"Input list cannot be empty\")\n \n # Sort the list in ascending order\n numbers.sort()\n \n # The smallest number is the first element and the largest is the last\n smallest = numbers[0]\n largest = numbers[-1]\n \n # Return the sum of the smallest and largest numbers\n return smallest + largest", "matching_cluster_idx": 2}, {"solution": "def big_sum(arr):\n \"\"\"\n This function finds the sum of the largest and smallest value in a given array.\n\n Args:\n arr (list): A list of integers.\n\n Returns:\n int: The sum of the largest and smallest value in the list.\n\n Raises:\n ValueError: If the input list has less than two elements.\n \"\"\"\n\n # Check if the input list has less than two elements\n if len(arr) < 2:\n raise ValueError(\"Input list must have at least two elements.\")\n\n # Find the smallest and largest values in the list\n smallest = min(arr)\n largest = max(arr)\n\n # Calculate the sum of the smallest and largest values\n result = smallest + largest\n\n return result", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n \"\"\"\n This function calculates the sum of the largest and smallest values in a given array.\n \n Parameters:\n arr (list): A list of numbers.\n \n Returns:\n int: The sum of the largest and smallest values in the array.\n \"\"\"\n return max(arr) + min(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n \"\"\"\n This function calculates the sum of the smallest and largest values in a given array.\n \n Args:\n arr (list): A list of numbers.\n \n Returns:\n int: The sum of the smallest and largest values in the array.\n \"\"\"\n if not arr:\n return None # Return None for an empty array\n # Find the smallest and largest values in the array\n smallest = min(arr)\n largest = max(arr)\n return smallest + largest", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n \"\"\"\n This function takes an array as an input and returns the sum of its largest and smallest value.\n \n Parameters:\n arr (list): The input list of numbers.\n \n Returns:\n int: The sum of the largest and smallest value in the input list.\n \"\"\"\n return max(arr) + min(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n \"\"\"\n This function calculates the sum of the largest and smallest value in a given array.\n\n Parameters:\n arr (list): A list of integers\n\n Returns:\n int: The sum of the largest and smallest value in the list\n \"\"\"\n return max(arr) + min(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n \"\"\"\n This function calculates the sum of the largest and smallest value in a given array.\n\n Args:\n arr (list): A list of numbers.\n\n Returns:\n int: The sum of the largest and smallest value in the list.\n\n Raises:\n ValueError: If the input list is empty.\n \"\"\"\n if not arr:\n raise ValueError(\"Input list cannot be empty\")\n\n return max(arr) + min(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(array):\n \"\"\"\n This function takes an array as an input and returns the sum of its largest and smallest values.\n\n Args:\n array (list): A list of numbers.\n\n Returns:\n int: The sum of the largest and smallest values in the array.\n\n Raises:\n ValueError: If the input array is empty.\n \"\"\"\n if len(array) == 0:\n raise ValueError(\"Input array is empty\")\n\n return min(array) + max(array)", "matching_cluster_idx": 5}, {"solution": "def big_sum(array):\n \"\"\"\n This function finds the sum of the largest and smallest value in a given array.\n \n Args:\n array (list): A list of numbers.\n\n Returns:\n int: The sum of the largest and smallest value in the array.\n \"\"\"\n \n # Check if the array is empty\n if not array:\n return None\n \n # Find the smallest and largest values in the array\n smallest = min(array)\n largest = max(array)\n \n # Return the sum of the smallest and largest values\n return smallest + largest", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n \"\"\"\n This function calculates the sum of the largest and smallest value in a given array.\n \n Parameters:\n arr (list): A list of numbers.\n \n Returns:\n int: The sum of the smallest and largest values in the list.\n \"\"\"\n return min(arr) + max(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n \"\"\"\n This function finds the sum of the largest and smallest value in a given array.\n\n Args:\n arr (list): A list of numbers.\n\n Returns:\n int: The sum of the largest and smallest value in the array.\n \"\"\"\n if len(arr) == 0: # Handle the case where the array is empty\n return None\n return min(arr) + max(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n \"\"\"\n This function takes in an array and returns the sum of the largest and smallest value in it.\n\n Args:\n arr (list): A list of numbers.\n\n Returns:\n int: The sum of the largest and smallest value in the list.\n \"\"\"\n if len(arr) == 0:\n raise ValueError(\"Array cannot be empty\")\n \n return max(arr) + min(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n \"\"\"\n This function finds the sum of the largest and smallest value in a given array.\n\n Parameters:\n arr (list): A list of numbers.\n\n Returns:\n int: The sum of the largest and smallest value in the array.\n\n Example:\n >>> big_sum([1,2,3])\n 4\n \"\"\"\n return max(arr) + min(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n \"\"\"\n This function calculates the sum of the largest and smallest values in a given array.\n\n Parameters:\n arr (list): A list of integers.\n\n Returns:\n int: The sum of the largest and smallest values in the list.\n\n Example:\n >>> big_sum([1,2,3])\n 4\n \"\"\"\n if len(arr) == 0: # Check if the array is empty\n return None # Return None for an empty array\n return min(arr) + max(arr) # Return the sum of the smallest and largest values", "matching_cluster_idx": 5}, {"solution": "def big_sum(lst):\n \"\"\"\n This function calculates the sum of the largest and smallest value in a given list.\n\n Args:\n lst (list): A list of numbers\n\n Returns:\n int: Sum of the largest and smallest value in the list\n\n Raises:\n ValueError: If the list is empty\n\n Examples:\n >>> big_sum([1, 2, 3])\n 4\n \"\"\"\n if not lst:\n raise ValueError(\"List cannot be empty\")\n return min(lst) + max(lst)", "matching_cluster_idx": 5}, {"solution": "def big_sum(lst):\n \"\"\"\n Returns the sum of the largest and smallest value in a given array.\n\n Args:\n lst (list): A list of numbers.\n\n Returns:\n int: The sum of the largest and smallest value in the list.\n \"\"\"\n if len(lst) == 0:\n raise ValueError(\"List cannot be empty\")\n elif len(lst) == 1:\n return lst[0]\n else:\n return max(lst) + min(lst)", "matching_cluster_idx": 5}, {"solution": "def big_sum(lst):\n \"\"\"\n This function calculates the sum of the largest and smallest value in a given list.\n \n Parameters:\n lst (list): A list of numbers\n \n Returns:\n int: The sum of the largest and smallest values in the list\n \"\"\"\n \n # Check if the list is empty\n if len(lst) == 0:\n return None\n \n # Find the largest and smallest value in the list\n largest = max(lst)\n smallest = min(lst)\n \n # Return the sum of the largest and smallest values\n return largest + smallest", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n \"\"\"\n This function calculates the sum of the smallest and largest value in a given array.\n \n Parameters:\n arr (list): A list of numbers.\n \n Returns:\n int: The sum of the smallest and largest value in the array.\n \n Raises:\n ValueError: If the input array is empty.\n \"\"\"\n if not arr:\n raise ValueError(\"Array cannot be empty.\")\n \n return min(arr) + max(arr)", "matching_cluster_idx": 5}]}, "Mbpp/477": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 72.0, "profiled": [{"solution": "def is_lower(s):\n \"\"\"\n Converts the given string to lower case.\n\n Args:\n s (str): The input string.\n\n Returns:\n str: The string in lower case.\n \"\"\"\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n \"\"\"\n This function takes a string as input and converts it into lowercase.\n \n Parameters:\n s (str): The input string to be converted.\n \n Returns:\n str: The lowercase version of the input string.\n \"\"\"\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n \"\"\"\n Converts the given string to lower case.\n \n Args:\n s (str): Input string\n \n Returns:\n str: The input string in lower case\n \"\"\"\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n \"\"\"\n This function converts the input string to lower case.\n\n Args:\n s (str): The input string to convert.\n\n Returns:\n str: The input string in lower case.\n \"\"\"\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n \"\"\"\n This function converts the given string to lower case.\n\n Args:\n s (str): The input string to be converted.\n\n Returns:\n str: The input string converted to lower case.\n \"\"\"\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n \"\"\"\n Converts the given string to lower case.\n \n Args:\n s (str): The input string to be converted.\n\n Returns:\n str: The lower case version of the input string.\n \"\"\"\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n \"\"\"\n This function converts the given string to lower case.\n\n Parameters:\n s (str): The string to be converted to lower case.\n\n Returns:\n str: The input string in lower case.\n\n \"\"\"\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s: str) -> str:\n \"\"\"\n This function converts a given string to lower case.\n\n Args:\n s (str): The input string to be converted.\n\n Returns:\n str: The input string in lower case.\n \"\"\"\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n \"\"\"\n Convert the given string to lower case.\n\n Parameters:\n s (str): The input string to be converted.\n\n Returns:\n str: The lower case version of the input string.\n \"\"\"\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n \"\"\"\n This function converts the given string to lower case.\n\n Args:\n s (str): The input string to be converted.\n\n Returns:\n str: The input string converted to lower case.\n \"\"\"\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n \"\"\"\n This function converts the given string to lower case.\n\n Parameters:\n s (str): The input string\n\n Returns:\n str: The lower case version of the input string\n \"\"\"\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n \"\"\"\n Converts a given string to lower case.\n\n Args:\n s (str): The input string to convert.\n\n Returns:\n str: The lower case version of the input string.\n\n Example:\n >>> is_lower(\"InValid\")\n 'invalid'\n \"\"\"\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s: str) -> str:\n \"\"\"\n Converts a given string to lower case.\n\n Args:\n s (str): The input string.\n\n Returns:\n str: The lower case version of the input string.\n \"\"\"\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n \"\"\"\n Convert a given string to lower case.\n \n Args:\n s (str): The string to be converted.\n \n Returns:\n str: The lower case version of the input string.\n \"\"\"\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n \"\"\"\n Converts a given string to lowercase.\n\n Args:\n s (str): The input string.\n\n Returns:\n str: The input string in lowercase.\n \"\"\"\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n \"\"\"\n Converts the given string to lower case.\n \n Parameters:\n s (str): The input string to be converted\n \n Returns:\n str: The lower case version of the input string\n \n \"\"\"\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n \"\"\"\n Converts a given string to lower case.\n\n Args:\n s (str): The input string to be converted.\n\n Returns:\n str: The input string in lower case.\n \"\"\"\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n \"\"\"\n This function takes a string input and returns the string in lower case.\n \n Parameters:\n s (str): The input string to be converted to lower case.\n \n Returns:\n str: The lower case version of the input string.\n \"\"\"\n # Convert the input string to lower case using the lower() method\n lower_case_string = s.lower()\n \n # Return the lower case string\n return lower_case_string", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n \"\"\"\n This function converts the given string to lower case.\n \n Args:\n s (str): The input string to be converted.\n \n Returns:\n str: The input string converted to lower case.\n \"\"\"\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n \"\"\"\n Converts the given string to lower case.\n\n Args:\n s (str): The string to be converted.\n\n Returns:\n str: The lower case version of the given string.\n \"\"\"\n return s.lower()", "matching_cluster_idx": 4}]}, "Mbpp/563": {"dps": 64.97267759562843, "dps_norm": 73.63636363636363, "pass@1": 28.0, "profiled": [{"solution": "def extract_values(s):\n \"\"\"\n Extract values between quotation marks from a string.\n \n Args:\n s (str): Input string\n \n Returns:\n list: A list of extracted values between quotation marks\n \"\"\"\n values = []\n in_quote = False\n current_value = \"\"\n \n for char in s:\n if char == '\"':\n if in_quote:\n values.append(current_value)\n current_value = \"\"\n in_quote = False\n else:\n in_quote = True\n elif in_quote:\n current_value += char\n \n return values", "matching_cluster_idx": 6}, {"solution": "def extract_values(s):\n \"\"\"\n Extracts values between quotation marks from a string.\n \n Args:\n s (str): Input string containing values between quotation marks.\n \n Returns:\n list: A list of extracted values.\n \"\"\"\n # Use regular expression to find all substrings enclosed in quotation marks\n import re\n return re.findall(r'\"([^\"]*)\"', s)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(s):\n \"\"\"\n Extracts values between quotation marks from a string.\n\n Args:\n s (str): The input string that contains values between quotation marks.\n\n Returns:\n list: A list of extracted values between quotation marks.\n\n Example:\n >>> extract_values('\"Python\", \"PHP\", \"Java\"')\n ['Python', 'PHP', 'Java']\n \"\"\"\n return re.findall(r'\"([^\"]*)\"', s)", "matching_cluster_idx": 8}, {"solution": "def extract_values(s):\n \"\"\"\n Extracts values between quotation marks from a string.\n \n Args:\n s (str): The input string containing values between quotation marks.\n \n Returns:\n list: A list of extracted values.\n \"\"\"\n # Use regular expression to find all substrings enclosed in quotation marks\n import re\n return re.findall(r'\"([^\"]*)\"', s)", "matching_cluster_idx": 8}, {"solution": "def extract_values(s):\n \"\"\"\n This function extracts values between quotation marks from a string.\n\n Args:\n s (str): The input string containing values between quotation marks.\n\n Returns:\n list: A list of extracted values.\n \"\"\"\n # Using regular expression to find all substrings enclosed in quotation marks\n import re\n return re.findall(r'\"([^\"]*)\"', s)", "matching_cluster_idx": 8}, {"solution": "def extract_values(s):\n \"\"\"\n This function extracts values between quotation marks from a string.\n \n Args:\n s (str): The input string to extract values from.\n \n Returns:\n list: A list of extracted values between quotation marks.\n \"\"\"\n # Initialize an empty list to store extracted values\n extracted_values = []\n \n # Initialize a flag to track whether we are currently inside a quotation\n in_quotation = False\n \n # Initialize an empty string to build the current value\n current_value = ''\n \n # Iterate through each character in the input string\n for char in s:\n # If the character is a quotation mark and we are inside a quotation\n if char == '\"' and in_quotation:\n # Add the value to the list and reset the current value and flag\n extracted_values.append(current_value)\n in_quotation = False\n current_value = ''\n # If the character is a quotation mark and we are not inside a quotation\n elif char == '\"':\n # Set the flag to True\n in_quotation = True\n # If we are inside a quotation and the character is not a quotation mark\n elif in_quotation:\n # Add the character to the current value\n current_value += char\n \n # Return the list of extracted values\n return extracted_values", "matching_cluster_idx": 5}, {"solution": "def extract_values(s):\n \"\"\"\n Extracts values between quotation marks from a given string.\n \n Args:\n s (str): The input string from which values are to be extracted.\n \n Returns:\n list: A list of extracted values between quotation marks.\n \"\"\"\n # Use a regular expression to find all substrings within quotation marks\n import re\n return re.findall(r'\"([^\"]*)\"', s)", "matching_cluster_idx": 8}, {"solution": "def extract_values(s):\n \"\"\"\n This function takes a string as an input, extracts all the values between \n quotation marks and returns them in a list.\n\n Args:\n s (str): The input string from which to extract values.\n\n Returns:\n list: A list of extracted values.\n \"\"\"\n # Initialize an empty list to store extracted values\n extracted_values = []\n\n # Initialize an empty string to build the current value\n current_value = \"\"\n\n # Initialize a flag to track whether we're inside a quoted string\n in_quote = False\n\n # Iterate over each character in the input string\n for char in s:\n # If we're not inside a quoted string and encounter a quotation mark\n if not in_quote and char == '\"':\n # Set the flag to True to enter a quoted string\n in_quote = True\n # If we're inside a quoted string and encounter a quotation mark\n elif in_quote and char == '\"':\n # Add the extracted value to the list\n extracted_values.append(current_value)\n # Reset the current value\n current_value = \"\"\n # Set the flag to False to exit the quoted string\n in_quote = False\n # If we're inside a quoted string, add the character to the current value\n elif in_quote:\n current_value += char\n\n # Return the list of extracted values\n return extracted_values", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_values(s):\n \"\"\"\n This function extracts values between quotation marks from a string.\n\n Args:\n s (str): The input string.\n\n Returns:\n list: A list of extracted values.\n \"\"\"\n # Using regular expression to find all substrings between quotation marks\n values = re.findall(r'\"([^\"]*)\"', s)\n return values", "matching_cluster_idx": 8}, {"solution": "def extract_values(s):\n \"\"\"\n This function extracts values between quotation marks from a string.\n\n Args:\n s (str): Input string containing values between quotation marks.\n\n Returns:\n list: List of extracted values.\n \"\"\"\n # Use regular expression to find all substrings within double quotes\n import re\n values = re.findall(r'\"([^\"]*)\"', s)\n return values", "matching_cluster_idx": 8}, {"solution": "def extract_values(s):\n \"\"\"\n Extract values between quotation marks from a string.\n\n Args:\n s (str): Input string.\n\n Returns:\n list: A list of extracted values between quotation marks.\n\n Example:\n >>> extract_values('\"Python\", \"PHP\", \"Java\"')\n ['Python', 'PHP', 'Java']\n \"\"\"\n # Use regular expression to find all substrings enclosed in quotation marks\n import re\n return re.findall(r'\"([^\"]*)\"', s)", "matching_cluster_idx": 8}, {"solution": "def extract_values(s):\n \"\"\"\n This function extracts values between quotation marks from a given string.\n\n Args:\n s (str): The input string.\n\n Returns:\n list: A list of extracted values.\n \"\"\"\n import re\n # Using regular expression to find all substrings enclosed in double quotes\n return re.findall(r'\"([^\"]*)\"', s)", "matching_cluster_idx": 8}, {"solution": "def extract_values(s):\n \"\"\"\n This function takes a string as input, extracts values between quotation marks, \n and returns them as a list.\n\n Args:\n s (str): The input string.\n\n Returns:\n list: A list of values extracted from the string.\n\n Example:\n >>> extract_values('\"Python\", \"PHP\", \"Java\"')\n ['Python', 'PHP', 'Java']\n \"\"\"\n # Use regular expression to find all substrings enclosed in quotation marks\n import re\n return re.findall(r'\"([^\"]*)\"', s)", "matching_cluster_idx": 8}, {"solution": "def extract_values(s):\n \"\"\"\n This function extracts values between quotation marks from a given string.\n\n Args:\n s (str): The input string from which values will be extracted.\n\n Returns:\n list: A list of extracted values.\n \"\"\"\n # Initialize an empty list to store extracted values\n extracted_values = []\n\n # Use regular expression to find all substrings within double quotes\n import re\n values = re.findall(r'\"([^\"]*)\"', s)\n\n # Add found values to the list\n extracted_values.extend(values)\n\n # Return the list of extracted values\n return extracted_values", "matching_cluster_idx": 8}, {"solution": "def extract_values(s):\n \"\"\"\n Extract values between quotation marks from a string.\n\n Args:\n s (str): The input string.\n\n Returns:\n list: A list of extracted values.\n \"\"\"\n import re\n return re.findall(r'\"([^\"]*)\"', s)", "matching_cluster_idx": 8}, {"solution": "def extract_values(s):\n \"\"\"\n Extract values between quotation marks from a string.\n\n Args:\n s (str): Input string containing values between quotation marks.\n\n Returns:\n list: A list of extracted values.\n\n Example:\n >>> extract_values('\"Python\", \"PHP\", \"Java\"')\n ['Python', 'PHP', 'Java']\n \"\"\"\n values = []\n current_value = ''\n quote_encountered = False\n\n for char in s:\n if char == '\"':\n if quote_encountered:\n values.append(current_value.strip('\"'))\n current_value = ''\n quote_encountered = False\n else:\n quote_encountered = True\n elif quote_encountered:\n current_value += char\n\n return values", "matching_cluster_idx": 6}, {"solution": "def extract_values(s):\n \"\"\"\n Extract values between quotation marks from a string.\n\n Args:\n s (str): Input string containing values between quotation marks.\n\n Returns:\n list: A list of values extracted from the string.\n \"\"\"\n result = []\n current_value = ''\n in_quote = False\n for char in s:\n if char == '\"':\n if in_quote:\n result.append(current_value)\n current_value = ''\n in_quote = not in_quote\n else:\n if in_quote:\n current_value += char\n return result", "matching_cluster_idx": 6}, {"solution": "def extract_values(s):\n \"\"\"\n This function takes a string as input and returns a list of strings\n enclosed within quotation marks.\n\n Args:\n s (str): Input string.\n\n Returns:\n list: A list of strings enclosed within quotation marks.\n \"\"\"\n # Use regular expression to find all substrings enclosed within quotation marks\n import re\n return re.findall(r'\"([^\"]*)\"', s)", "matching_cluster_idx": 8}, {"solution": "def extract_values(s):\n \"\"\"\n Extracts and returns a list of values between quotation marks in a string.\n\n Args:\n s (str): The input string.\n\n Returns:\n list: A list of extracted values between quotation marks.\n \"\"\"\n # Initialize an empty list to store the extracted values\n extracted_values = []\n\n # Initialize an empty string to build the current value\n current_value = \"\"\n\n # Initialize a flag to track whether we are inside quotation marks\n in_quotes = False\n\n # Iterate over the input string\n for char in s:\n # If the character is a double quote and we are not inside quotation marks\n if char == '\"' and not in_quotes:\n # Set the flag to True to indicate we are inside quotation marks\n in_quotes = True\n # If the character is a double quote and we are inside quotation marks\n elif char == '\"' and in_quotes:\n # Set the flag to False to indicate we are outside quotation marks\n in_quotes = False\n # Add the extracted value to the list\n extracted_values.append(current_value.strip('\"'))\n # Reset the current value\n current_value = \"\"\n # If we are inside quotation marks, add the character to the current value\n elif in_quotes:\n current_value += char\n\n return extracted_values", "matching_cluster_idx": 4}, {"solution": "def extract_values(s):\n \"\"\"\n This function takes a string as input and returns a list of values \n that are enclosed within double quotes.\n\n Args:\n s (str): The input string.\n\n Returns:\n list: A list of values enclosed within double quotes.\n \"\"\"\n values = []\n current_value = \"\"\n in_quotes = False\n\n for char in s:\n if char == '\"':\n if in_quotes:\n values.append(current_value)\n current_value = \"\"\n in_quotes = False\n else:\n in_quotes = True\n elif in_quotes:\n current_value += char\n\n return values", "matching_cluster_idx": 6}]}, "Mbpp/572": {"dps": null, "dps_norm": null, "pass@1": 3.0, "profiled": []}, "Mbpp/578": {"dps": 68.01587301587301, "dps_norm": 65.9090909090909, "pass@1": 93.0, "profiled": [{"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"\n Interleaves 3 lists of the same length into a single flat list.\n\n Args:\n list1 (list): The first list of elements.\n list2 (list): The second list of elements.\n list3 (list): The third list of elements.\n\n Returns:\n list: A single flat list with interleaved elements from list1, list2, and list3.\n\n Raises:\n ValueError: If the input lists are not of the same length.\n \"\"\"\n # Check if the input lists are of the same length\n if len(list1) != len(list2) or len(list1) != len(list3):\n raise ValueError(\"Input lists must be of the same length\")\n\n # Interleave the lists using the zip function\n interleaved_list = [item for tup in zip(list1, list2, list3) for item in tup]\n\n return interleaved_list", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(*args):\n \"\"\"\n This function interleaves three lists of the same length into a single flat list.\n \n Args:\n *args: A variable number of lists to be interleaved.\n \n Returns:\n A single flat list with elements from the input lists interleaved.\n \n Raises:\n ValueError: If the input lists are not of the same length.\n \"\"\"\n # Check if the lists are of the same length\n if len(args) != 3 or len(set(len(lst) for lst in args)) > 1:\n raise ValueError(\"Input lists must be of the same length\")\n \n # Initialize an empty list to store the interleaved elements\n interleaved_list = []\n \n # Interleave elements from the input lists\n for i in range(len(args[0])):\n for lst in args:\n interleaved_list.append(lst[i])\n \n return interleaved_list", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(*args):\n \"\"\"\n Interleaves 3 lists of the same length into a single flat list.\n\n Args:\n *args (list): Variable number of lists of same length.\n\n Returns:\n list: Interleaved list of same elements from input lists.\n \"\"\"\n if len(args) != 3:\n raise ValueError(\"Three input lists are required\")\n\n # Ensure input lists are of same length\n if len(args[0]) != len(args[1]) != len(args[2]):\n raise ValueError(\"Input lists must be of same length\")\n\n interleaved_list = [value for value in zip(*args)]\n return [value for sublist in interleaved_list for value in sublist]", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"\n Interleaves three lists of the same length into a single flat list.\n \n Args:\n list1 (list): The first list of numbers.\n list2 (list): The second list of numbers.\n list3 (list): The third list of numbers.\n \n Returns:\n list: A single flat list with interleaved numbers from list1, list2, and list3.\n \n Raises:\n ValueError: If the lists are not of the same length.\n \"\"\"\n if len(list1) != len(list2) or len(list1) != len(list3):\n raise ValueError(\"Lists must be of the same length.\")\n \n result = []\n for i in range(len(list1)):\n result.extend([list1[i], list2[i], list3[i]])\n \n return result", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"\n Interleaves three lists of the same length into a single flat list.\n \n Args:\n list1 (list): First list\n list2 (list): Second list\n list3 (list): Third list\n \n Returns:\n list: Interleaved list\n \"\"\"\n return [x for group in zip(list1, list2, list3) for x in group]", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"\n This function interleaves three lists of the same length into a single flat list.\n \n Args:\n list1 (list): The first list to interleave.\n list2 (list): The second list to interleave.\n list3 (list): The third list to interleave.\n \n Returns:\n list: A new list with the elements from the input lists interleaved.\n \n Raises:\n ValueError: If the input lists are not of the same length.\n \"\"\"\n # Check if the input lists are of the same length\n if len(list1) != len(list2) or len(list1) != len(list3):\n raise ValueError(\"Input lists must be of the same length\")\n \n # Use the zip function to interleave the lists\n # The * operator unpacks the lists into separate arguments for zip\n # The result is a zip object, which we convert to a list with the list function\n interleaved_list = list(zip(list1, list2, list3))\n \n # Use a list comprehension to flatten the list of tuples into a single list\n interleaved_list = [element for tuple in interleaved_list for element in tuple]\n \n return interleaved_list", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"\n Interleaves three lists of the same length into a single flat list.\n\n Args:\n list1 (list): The first list to interleave.\n list2 (list): The second list to interleave.\n list3 (list): The third list to interleave.\n\n Returns:\n list: The interleaved list.\n\n Raises:\n ValueError: If the lists are not of the same length.\n \"\"\"\n if len(list1) != len(list2) or len(list1) != len(list3):\n raise ValueError(\"Lists must be of the same length\")\n\n interleaved = []\n for i in range(len(list1)):\n interleaved.append(list1[i])\n interleaved.append(list2[i])\n interleaved.append(list3[i])\n return interleaved", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"\n Interleaves three lists of the same length into a single flat list.\n\n Args:\n list1 (list): The first list of elements to interleave.\n list2 (list): The second list of elements to interleave.\n list3 (list): The third list of elements to interleave.\n\n Returns:\n list: A single flat list containing interleaved elements from all three input lists.\n\n Raises:\n ValueError: If the input lists are not of the same length.\n \"\"\"\n if len(list1) != len(list2) or len(list1) != len(list3):\n raise ValueError(\"Input lists must be of the same length\")\n\n result = []\n for i in range(len(list1)):\n result.append(list1[i])\n result.append(list2[i])\n result.append(list3[i])\n\n return result", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"\n This function interleave 3 lists of the same length into a single flat list.\n \n Args:\n list1 (list): The first list.\n list2 (list): The second list.\n list3 (list): The third list.\n \n Returns:\n list: A new list with elements from list1, list2, and list3 interleaved.\n \"\"\"\n # Check if all lists have the same length\n if len(list1) != len(list2) or len(list2) != len(list3):\n raise ValueError(\"All lists must have the same length\")\n \n # Use zip and list comprehension to create the interleaved list\n return [x for sublist in zip(list1, list2, list3) for x in sublist]", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"\n Interleave three lists of the same length into a single flat list.\n \n Args:\n list1 (list): The first list.\n list2 (list): The second list.\n list3 (list): The third list.\n \n Returns:\n list: A new list with elements from the input lists interleaved.\n \"\"\"\n if len(list1) != len(list2) or len(list2) != len(list3):\n raise ValueError(\"Input lists must be of the same length\")\n \n result = []\n for i in range(len(list1)):\n result.append(list1[i])\n result.append(list2[i])\n result.append(list3[i])\n \n return result", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(*lists):\n \"\"\"\n This function takes in multiple lists of the same length and returns a single flat list \n with elements interleaved from each list.\n \n Args:\n *lists (list): Variable number of lists to be interleaved. \n All lists should be of the same length.\n \n Returns:\n list: A single flat list with elements interleaved from each input list.\n \"\"\"\n \n # Check if all lists have the same length\n list_lengths = [len(lst) for lst in lists]\n if len(set(list_lengths)) != 1:\n raise ValueError(\"All input lists must be of the same length\")\n \n # Initialize result list\n result = []\n \n # Interleave elements from each list\n for i in range(len(lists[0])):\n for lst in lists:\n result.append(lst[i])\n \n return result", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"\n This function takes three lists of the same length and returns a single flat list with interleaved elements.\n\n Args:\n list1 (list): The first list to interleave.\n list2 (list): The second list to interleave.\n list3 (list): The third list to interleave.\n\n Returns:\n list: A flat list with interleaved elements from the input lists.\n\n Raises:\n ValueError: If the input lists are not of the same length.\n \"\"\"\n # Check if the input lists are of the same length\n if len(list1) != len(list2) or len(list1) != len(list3):\n raise ValueError(\"Input lists must be of the same length\")\n\n # Use a list comprehension to interleave the lists\n interleaved_list = [x for x in zip(list1, list2, list3)]\n\n # Use a nested list comprehension to flatten the list of tuples into a single list\n interleaved_list = [y for x in interleaved_list for y in x]\n\n return interleaved_list", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(*lists):\n \"\"\"\n Interleaves three lists of the same length into a single flat list.\n\n Args:\n *lists: variable number of lists to be interleaved.\n\n Returns:\n A new list with elements from the input lists interleaved.\n \"\"\"\n if len(set(len(lst) for lst in lists)) != 1:\n raise ValueError(\"All input lists must have the same length\")\n\n result = []\n for index in range(len(lists[0])):\n for lst in lists:\n result.append(lst[index])\n\n return result", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"\n Interleaves 3 lists of the same length into a single flat list.\n\n Args:\n list1 (list): The first list to interleave.\n list2 (list): The second list to interleave.\n list3 (list): The third list to interleave.\n\n Returns:\n list: A new list that is the interleaved version of list1, list2, and list3.\n\n Raises:\n ValueError: If the input lists are not of equal length.\n \"\"\"\n # Check if the input lists are of equal length\n if len(list1) != len(list2) or len(list1) != len(list3):\n raise ValueError(\"Input lists must be of equal length\")\n\n # Use the zip function to pair elements from each list together\n paired_lists = zip(list1, list2, list3)\n\n # Use a list comprehension to flatten the paired lists into a single list\n interleaved_list = [x for pair in paired_lists for x in pair]\n\n return interleaved_list", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"\n This function interleaves 3 lists of the same length into a single flat list.\n \n Args:\n list1 (list): The first list of elements to interleave.\n list2 (list): The second list of elements to interleave.\n list3 (list): The third list of elements to interleave.\n \n Returns:\n list: A single flat list with elements interleaved from the input lists.\n \"\"\"\n # Check if lists have the same length\n if len(list1) != len(list2) or len(list2) != len(list3):\n raise ValueError(\"Lists must be of the same length\")\n \n # Initialize an empty list to store the interleaved elements\n interleaved_list = []\n \n # Iterate over the indices of the first list\n for i in range(len(list1)):\n # Interleave elements from each list\n interleaved_list.extend([list1[i], list2[i], list3[i]])\n \n # Return the interleaved list\n return interleaved_list", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"\n Interleaves three lists of the same length into a single flat list.\n\n Args:\n list1 (list): The first list to interleave.\n list2 (list): The second list to interleave.\n list3 (list): The third list to interleave.\n\n Returns:\n list: A new list with elements from list1, list2, and list3 interleaved.\n\n Raises:\n ValueError: If the lists are not of the same length.\n \"\"\"\n if len(list1) != len(list2) or len(list1) != len(list3):\n raise ValueError(\"Lists must be of the same length.\")\n\n result = []\n for i in range(len(list1)):\n result.extend([list1[i], list2[i], list3[i]])\n\n return result", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"\n Interleave 3 lists of the same length into a single flat list.\n \n Args:\n list1 (list): The first list to interleave.\n list2 (list): The second list to interleave.\n list3 (list): The third list to interleave.\n \n Returns:\n list: The interleaved list.\n \"\"\"\n return [item for t in zip(list1, list2, list3) for item in t]", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(*lists):\n \"\"\"\n This function takes variable number of lists as arguments and returns a new list with elements from each list interleave.\n \n Args:\n *lists: variable number of lists with the same length\n \n Returns:\n A new list with elements from each list interleave.\n \"\"\"\n # Check if all lists have the same length\n list_lengths = [len(lst) for lst in lists]\n if not all([l == list_lengths[0] for l in list_lengths]):\n raise ValueError(\"All lists must have the same length\")\n \n result = []\n for i in range(len(lists[0])):\n for lst in lists:\n result.append(lst[i])\n \n return result", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"\n Interleaves three lists of the same length into a single flat list.\n\n Args:\n list1 (list): The first list to interleave.\n list2 (list): The second list to interleave.\n list3 (list): The third list to interleave.\n\n Returns:\n list: The interleaved list.\n\n Raises:\n ValueError: If any of the input lists are not of the same length.\n \"\"\"\n if len(list1) != len(list2) or len(list2) != len(list3):\n raise ValueError(\"All lists must be of the same length\")\n\n result = []\n for i in range(len(list1)):\n result.extend([list1[i], list2[i], list3[i]])\n\n return result", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"\n This function interleaves 3 lists of the same length into a single flat list.\n\n Args:\n list1 (list): The first list to interleave.\n list2 (list): The second list to interleave.\n list3 (list): The third list to interleave.\n\n Returns:\n list: A new list containing the interleaved elements of the input lists.\n\n Raises:\n ValueError: If the input lists are not of the same length.\n \"\"\"\n if len(list1) != len(list2) or len(list1) != len(list3):\n raise ValueError(\"Input lists must be of the same length\")\n\n result = []\n for i in range(len(list1)):\n result.append(list1[i])\n result.append(list2[i])\n result.append(list3[i])\n\n return result", "matching_cluster_idx": 6}]}, "Mbpp/586": {"dps": 98.83040935672514, "dps_norm": 87.5, "pass@1": 37.0, "profiled": [{"solution": "def split_Arr(arr, n):\n \"\"\"\n Splits the input list at the nth element and appends the first part to the end.\n\n Args:\n arr (list): The input list to be split.\n n (int): The index at which to split the list.\n\n Returns:\n list: The modified list with the first part appended at the end.\n \"\"\"\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(lst, n):\n \"\"\"\n This function splits a list at the nth element and adds the first part to the end.\n\n Args:\n lst (list): The list to be split.\n n (int): The position at which the list should be split.\n\n Returns:\n list: The modified list with the first part added to the end.\n \"\"\"\n # Check if the input is a list and n is an integer\n if not isinstance(lst, list) or not isinstance(n, int):\n raise TypeError(\"Input must be a list and n must be an integer.\")\n\n # Check if n is within the bounds of the list\n if n < 0 or n > len(lst):\n raise ValueError(\"n is out of range for the list.\")\n\n # Split the list at the nth element and return the modified list\n return lst[n:] + lst[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"\n Split a list at the nth element and add the first part to the end.\n \n Args:\n arr (list): The input list to be split.\n n (int): The position at which the list should be split.\n \n Returns:\n list: The modified list with the first part added to the end.\n \"\"\"\n first_part = arr[:n]\n second_part = arr[n:]\n return second_part + first_part", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"\n This function splits the input array into two parts at the nth element and \n returns the second part followed by the first part.\n \n Parameters:\n arr (list): The input list to be split\n n (int): The index at which the list will be split\n \n Returns:\n list: The split list with the first part at the end\n \"\"\"\n if n > len(arr):\n raise ValueError(\"n is larger than the length of the array\")\n \n return arr[n:]+arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"\n This function splits the input list at the nth element and adds the first part to the end.\n\n Args:\n arr (list): The list to be split.\n n (int): The position to split the list at.\n\n Returns:\n list: The modified list with the first part at the end.\n \"\"\"\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"\n Splits a list at the nth element and adds the first part to the end.\n\n Args:\n arr (list): The input list to be split.\n n (int): The index at which the list should be split.\n\n Returns:\n list: The modified list with the first part appended at the end.\n \"\"\"\n if n < 0 or n > len(arr):\n raise ValueError(\"Invalid index\")\n\n first_part = arr[:n]\n second_part = arr[n:]\n return second_part + first_part", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"\n This function takes a list and a number n as input and returns a new list.\n The function splits the list at the nth element and adds the first part to the end.\n \n Args:\n arr (list): The input list to be split.\n n (int): The position at which the list should be split.\n \n Returns:\n list: The resulting list with the first part added to the end of the second part.\n \"\"\"\n # Check if n is within the bounds of the list\n if n > len(arr):\n raise ValueError(\"n is out of range\")\n \n # Split the list at the nth element\n first_part = arr[:n]\n second_part = arr[n:]\n \n # Add the first part to the end of the second part\n return second_part + first_part", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"\n Split the list at the nth element and add the first part to the end.\n\n Args:\n arr (list): Input list.\n n (int): Index to split the list.\n\n Returns:\n list: Modified list with the first part at the end.\n \"\"\"\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"\n Splits a list at the nth element and adds the first part to the end.\n\n Args:\n arr (list): The input list.\n n (int): The position of the split point.\n\n Returns:\n list: The modified list.\n \"\"\"\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"\n This function splits a given list at the nth element and adds the first part to the end.\n\n Args:\n arr (list): The input list to be split.\n n (int): The index at which the list is to be split.\n\n Returns:\n list: The modified list with the first part added to the end.\n \"\"\"\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"\n This function splits a list at the nth element and adds the first part to the end.\n\n Args:\n arr (list): Input list to be split\n n (int): Index up to which the list will be split\n\n Returns:\n list: Modified list with the first part added to the end\n \"\"\"\n if n >= len(arr):\n return arr # If n is greater than or equal to the list length, return the list as it is\n return arr[n:] + arr[:n] # Slice the list from n to the end, then add the slice from the start to n", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"\n Splits a given list at the nth element and appends the first part to the end.\n \n Parameters:\n arr (list): The input list to be modified.\n n (int): The index at which the list is split.\n \n Returns:\n list: The modified list with the first part appended at the end.\n \"\"\"\n \n # Check if n is within the bounds of the list\n if n < 0 or n >= len(arr):\n return arr # Return the original list if n is out of bounds\n \n # Split the list at the nth index\n first_part = arr[:n]\n second_part = arr[n:]\n \n # Append the first part to the end of the second part\n result = second_part + first_part\n \n return result", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"\n Splits the list at the nth element and adds the first part to the end.\n \n Args:\n arr (list): The input list of elements.\n n (int): The index to split the list at.\n \n Returns:\n list: The modified list with the first part appended to the end.\n \"\"\"\n \n # Check if n is a valid index\n if n < 0 or n >= len(arr):\n return arr\n \n # Split the list at the nth element and append the first part to the end\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"\n Split a list at the nth element and add the first part to the end.\n\n Args:\n arr (list): The input list.\n n (int): The index at which to split the list.\n\n Returns:\n list: The modified list with the first part at the end.\n \"\"\"\n # Split the list at the nth element\n first_part = arr[:n]\n second_part = arr[n:]\n \n # Combine the second part and first part in reverse order\n return second_part + first_part", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"\n This function splits the given list at the nth element and adds the first part to the end.\n\n Args:\n arr (list): The input list to be split.\n n (int): The position to split the list.\n\n Returns:\n list: The resulting list after splitting the input list.\n\n Raises:\n ValueError: If n is less than 0 or greater than the list length.\n \"\"\"\n if n < 0 or n > len(arr):\n raise ValueError(\"n should be in the range [0, list length]\")\n \n # Split the list at the nth position\n first_part = arr[:n]\n second_part = arr[n:]\n \n # Add the first part to the end\n return second_part + first_part", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"\n Splits the given list at the nth element and adds the first part to the end.\n \n Args:\n arr (list): Input list\n n (int): Index at which the list should be split\n \n Returns:\n list: The list with the first part added to the end\n \"\"\"\n # Check if n is within the bounds of the list\n if n >= len(arr):\n return arr\n \n # Split the list into two parts\n first_part = arr[:n]\n second_part = arr[n:]\n \n # Add the first part to the end of the second part\n result = second_part + first_part\n \n return result", "matching_cluster_idx": 6}, {"solution": "def split_Arr(lst, n):\n \"\"\"\n This function splits the list at the nth element and adds the first part to the end.\n\n Args:\n lst (list): The input list to be split.\n n (int): The index where the list should be split.\n\n Returns:\n list: The modified list with the first part appended to the end.\n \"\"\"\n if n > len(lst):\n return lst # Return the list if n is greater than the length of the list\n first_part = lst[:n] # Get the first n elements\n second_part = lst[n:] # Get the elements after the nth index\n return second_part + first_part # Combine the two parts in reverse order", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"\n This function splits the list at the nth element and adds the first part to the end.\n\n Args:\n arr (list): Input list\n n (int): The index at which the list will be split\n\n Returns:\n list: The modified list with the first part added to the end\n \"\"\"\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"\n This function splits the input list at the nth element and adds the first part to the end.\n \n Args:\n arr (list): Input list to be split and rearranged.\n n (int): The index at which to split the list.\n \n Returns:\n list: The rearranged list with the first part at the end.\n \"\"\"\n # Check if n is within the bounds of the list\n if n >= len(arr):\n return arr # or you can raise an error here as per your choice\n \n # Split the list into two parts at the nth element\n first_part = arr[:n]\n second_part = arr[n:]\n \n # Combine the two parts in reverse order\n return second_part + first_part", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"\n This function splits a list at the nth element and adds the first part to the end.\n\n Args:\n arr (list): The input list to be split\n n (int): The index to split the list at\n\n Returns:\n list: The modified list with the first part added to the end\n \"\"\"\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}]}, "Mbpp/587": {"dps": null, "dps_norm": null, "pass@1": 0.0, "profiled": []}, "Mbpp/588": {"dps": 92.33944954128441, "dps_norm": 96.66666666666667, "pass@1": 100.0, "profiled": [{"solution": "def big_diff(nums):\n \"\"\"\n This function calculates the difference between the largest and smallest value in a list.\n\n Args:\n nums (list): A list of integers.\n\n Returns:\n int: The difference between the largest and smallest value in the list.\n \"\"\"\n if len(nums) < 2:\n raise ValueError(\"List must have at least two elements\")\n \n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(lst):\n \"\"\"\n This function calculates the difference between the largest and smallest value in a list.\n\n Parameters:\n lst (list): A list of integers.\n\n Returns:\n int: The difference between the largest and smallest value in the list.\n\n Raises:\n ValueError: If the list is empty or contains non-numeric values.\n \"\"\"\n\n # Check if the list is empty\n if len(lst) == 0:\n raise ValueError(\"List cannot be empty\")\n\n # Check if all elements in the list are integers\n if not all(isinstance(num, int) for num in lst):\n raise ValueError(\"List must contain only integers\")\n\n # Find the minimum and maximum values in the list\n max_val = max(lst)\n min_val = min(lst)\n\n # Return the difference between the maximum and minimum values\n return max_val - min_val", "matching_cluster_idx": 3}, {"solution": "def big_diff(lst):\n \"\"\"\n Calculate the difference between the largest and smallest values in a given list.\n \n Args:\n lst (list): A list of integers.\n \n Returns:\n int: The difference between the largest and smallest values in the list.\n \n Raises:\n ValueError: If the input list is empty.\n \"\"\"\n if not lst:\n raise ValueError(\"The input list is empty.\")\n\n return max(lst) - min(lst)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n \"\"\"\n This function calculates the difference between the largest and smallest value in a given list.\n\n Args:\n nums (list): A list of integers.\n\n Returns:\n int: The difference between the largest and smallest value in the list.\n\n Example:\n >>> big_diff([1,2,3,4])\n 3\n \"\"\"\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(lst):\n \"\"\"\n This function calculates the difference between the largest and smallest value in a given list.\n\n Args:\n lst (list): A list of numbers.\n\n Returns:\n int: The difference between the largest and smallest value in the list.\n\n Raises:\n ValueError: If the list is empty.\n \"\"\"\n if not lst:\n raise ValueError(\"List cannot be empty\")\n\n return max(lst) - min(lst)", "matching_cluster_idx": 5}, {"solution": "def big_diff(numbers):\n \"\"\"\n This function calculates the difference between the largest and smallest value in a given list.\n\n Args:\n numbers (list): A list of numbers.\n\n Returns:\n int: The difference between the largest and smallest value in the list.\n \"\"\"\n # Check if the list is empty\n if len(numbers) == 0:\n return None # Return None for an empty list\n\n # Find the largest and smallest value in the list\n max_value = max(numbers)\n min_value = min(numbers)\n\n # Calculate the difference\n diff = max_value - min_value\n\n return diff", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n \"\"\"\n This function calculates the difference between the largest and smallest value in a given list.\n \n Parameters:\n nums (list): A list of integers.\n \n Returns:\n int: The difference between the largest and smallest value in the list.\n \n Raises:\n ValueError: If the input list is empty.\n \"\"\"\n \n # Check if the list is empty\n if not nums:\n raise ValueError(\"Input list is empty\")\n\n # Calculate the difference between the largest and smallest value in the list\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(lst):\n \"\"\"\n This function calculates the difference between the largest and smallest value in a given list.\n \n Args:\n lst (list): A list of numbers.\n \n Returns:\n int: The difference between the largest and smallest value in the list.\n \"\"\"\n \n # Check if the list is empty\n if len(lst) == 0:\n return None # or raise an exception based on the requirement\n\n # Use built-in min and max functions to find the smallest and largest values in the list\n smallest = min(lst)\n largest = max(lst)\n \n # Calculate the difference between the largest and smallest values\n difference = largest - smallest\n \n return difference", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n \"\"\"\n This function calculates the difference between the largest and smallest value in a given list.\n\n Args:\n nums (list): A list of numbers.\n\n Returns:\n int: The difference between the largest and smallest value in the list.\n\n Raises:\n ValueError: If the input list is empty.\n \"\"\"\n if not nums:\n raise ValueError(\"Input list cannot be empty\")\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n \"\"\"\n This function calculates the difference between the largest and smallest value in a list.\n\n Args:\n nums (list): A list of numbers.\n\n Returns:\n int: The difference between the largest and smallest value in the list.\n\n Example:\n >>> big_diff([1, 2, 3, 4])\n 3\n \"\"\"\n if not nums: # Check if the list is empty\n return None\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(lst):\n \"\"\"\n Calculate the difference between the largest and smallest number in a list.\n\n Args:\n lst (list): A list of numbers.\n\n Returns:\n int: The difference between the largest and smallest number in the list.\n \"\"\"\n return max(lst) - min(lst)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n \"\"\"\n This function calculates the difference between the largest and smallest value in a given list.\n\n Parameters:\n nums (list): A list of numbers.\n\n Returns:\n int: The difference between the largest and smallest value in the list.\n\n \"\"\"\n if len(nums) < 2:\n raise ValueError(\"List must have at least 2 elements\")\n\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(lst):\n \"\"\"\n This function calculates the difference between the largest and smallest number in a given list.\n\n Args:\n lst (list): A list of numbers.\n\n Returns:\n int: The difference between the largest and smallest number in the list.\n \"\"\"\n # Check if the list is not empty\n if len(lst) < 2:\n raise ValueError(\"List should contain at least two elements\")\n\n # Find the largest and smallest number in the list\n largest = max(lst)\n smallest = min(lst)\n\n # Calculate the difference between the largest and smallest number\n return largest - smallest", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n \"\"\"\n This function calculates the difference between the largest and smallest value in a list of integers.\n \n Args:\n nums (list): A list of integers.\n\n Returns:\n int: The difference between the largest and smallest value in the list.\n \"\"\"\n # Check if the list has at least one element\n if len(nums) < 1:\n return None\n\n # Find the largest and smallest value in the list\n largest = max(nums)\n smallest = min(nums)\n\n # Return the difference between the largest and smallest value\n return largest - smallest", "matching_cluster_idx": 5}, {"solution": "def big_diff(lst):\n \"\"\"\n Find the difference between the largest and smallest value in a given list.\n\n Args:\n lst (list): A list of numbers.\n\n Returns:\n int: The difference between the largest and smallest value in the list.\n\n Raises:\n ValueError: If the list is empty.\n \"\"\"\n if not lst:\n raise ValueError(\"List is empty\")\n\n return max(lst) - min(lst)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n \"\"\"\n Calculate the difference between the largest and smallest value in a given list.\n\n Args:\n nums (list): A list of numbers.\n\n Returns:\n int: The difference between the largest and smallest value in the list.\n\n Raises:\n ValueError: If the list is empty.\n \"\"\"\n if len(nums) == 0:\n raise ValueError(\"List is empty\")\n \n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n \"\"\"\n This function calculates the difference between the largest and smallest values in a given list.\n \n Parameters:\n nums (list): A list of numbers.\n \n Returns:\n int: The difference between the largest and smallest value in the list.\n \"\"\"\n if not nums: # Check if the list is empty\n return 0\n \n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(lst):\n \"\"\"\n This function finds the difference between the largest and smallest value in a list.\n\n Parameters:\n lst (list): A list of numbers.\n\n Returns:\n int: The difference between the largest and smallest value in the list.\n\n Raises:\n ValueError: If the list contains less than 2 elements.\n \"\"\"\n if len(lst) < 2:\n raise ValueError(\"List must contain at least 2 elements\")\n\n return max(lst) - min(lst)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n \"\"\"\n Find the difference between the largest and smallest value in a given list.\n\n Args:\n nums (list): A list of integers.\n\n Returns:\n int: The difference between the largest and smallest values in the list.\n\n Raises:\n ValueError: If the input list is empty or contains non-integer values.\n \"\"\"\n if not nums:\n raise ValueError(\"Input list cannot be empty\")\n if not all(isinstance(num, int) for num in nums):\n raise ValueError(\"Input list must contain only integers\")\n\n return max(nums) - min(nums)", "matching_cluster_idx": 3}, {"solution": "def big_diff(nums):\n \"\"\"\n Find the difference between the largest and smallest value in a given list.\n\n Args:\n nums (list): A list of numbers.\n\n Returns:\n int: The difference between the largest and smallest value in the list.\n\n Raises:\n ValueError: If the input list is empty.\n \"\"\"\n if not nums:\n raise ValueError(\"List cannot be empty\")\n\n return max(nums) - min(nums)", "matching_cluster_idx": 5}]}, "Mbpp/592": {"dps": null, "dps_norm": null, "pass@1": 1.0, "profiled": []}, "Mbpp/597": {"dps": 90.44776119402985, "dps_norm": 97.5, "pass@1": 67.0, "profiled": [{"solution": "def find_kth(arr1, arr2, k):\n \"\"\"\n This function finds the kth element from two sorted arrays.\n\n Args:\n arr1 (list): The first sorted array.\n arr2 (list): The second sorted array.\n k (int): The index of the element to find (1-indexed).\n\n Returns:\n The kth element from the merged and sorted array.\n \"\"\"\n # Merge the two arrays\n merged = sorted(arr1 + arr2)\n \n # Check if k is within the bounds of the merged array\n if k < 1 or k > len(merged):\n raise ValueError(\"k is out of bounds\")\n \n # Return the kth element (since we're 1-indexed, subtract 1 from k)\n return merged[k - 1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(arr1, arr2, k):\n \"\"\"\n This function returns the kth element in the merged sorted array of arr1 and arr2.\n \n Args:\n arr1 (list): The first sorted array.\n arr2 (list): The second sorted array.\n k (int): The index of the desired element.\n \n Returns:\n int: The kth element of the merged sorted array.\n \"\"\"\n # Merge the two sorted arrays\n merged = sorted(arr1 + arr2)\n \n # Return the kth element\n return merged[k - 1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(nums1, nums2, k):\n \"\"\"\n Find the kth element from two sorted arrays.\n\n Args:\n nums1 (list): First sorted list of numbers.\n nums2 (list): Second sorted list of numbers.\n k (int): Position of the element to find.\n\n Returns:\n int: kth element from both lists.\n \"\"\"\n # Combine both lists and sort the combined list\n combined = sorted(nums1 + nums2)\n return combined[k - 1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(arr1, arr2, k):\n \"\"\"\n Find the kth element from two sorted arrays.\n\n Args:\n arr1 (list): The first sorted array.\n arr2 (list): The second sorted array.\n k (int): The kth index to find.\n\n Returns:\n int: The element at the kth index.\n \"\"\"\n # Merge the two sorted arrays and find the kth element\n merged = sorted(arr1 + arr2)\n return merged[k-1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(arr1, arr2, k):\n \"\"\"\n This function finds the kth element when two sorted arrays are merged.\n \n Args:\n arr1 (list): The first sorted array.\n arr2 (list): The second sorted array.\n k (int): The index of the element to find (1-indexed).\n\n Returns:\n int: The kth element when both arrays are merged in sorted order.\n \"\"\"\n # Merge both arrays into one\n merged = sorted(arr1 + arr2)\n \n # Subtract 1 from k because array indices are 0-based\n k -= 1\n \n # Return the kth element\n return merged[k]", "matching_cluster_idx": 3}, {"solution": "def find_kth(a, b, k):\n \"\"\"\n This function finds the kth element from two sorted lists.\n \n Parameters:\n a (list): The first sorted list\n b (list): The second sorted list\n k (int): The position of the element to find (1-indexed)\n \n Returns:\n int: The kth element from the combined list (a + b)\n \"\"\"\n # Combine the two lists and sort the result\n combined = sorted(a + b)\n \n # Since lists in Python are zero-indexed, we subtract 1 from k\n # If k is larger than the length of the combined list, return None\n if k > len(combined):\n return None\n \n # Return the kth element\n return combined[k - 1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(nums1, nums2, k):\n \"\"\"\n Find the kth smallest element in the given two sorted arrays.\n\n Args:\n - nums1 (list): The first sorted array.\n - nums2 (list): The second sorted array.\n - k (int): The index of the element to be found (1-indexed).\n\n Returns:\n - int: The kth element from the combined sorted array.\n \"\"\"\n # Combine the two arrays into a single sorted array\n merged = sorted(nums1 + nums2)\n \n # Since list indices are 0-based, subtract 1 from k to get the correct index\n return merged[k - 1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(arr1, arr2, k):\n \"\"\"\n Find the kth element from two sorted arrays.\n\n Args:\n arr1 (list): The first sorted array.\n arr2 (list): The second sorted array.\n k (int): The index of the element to find (1-indexed).\n\n Returns:\n int: The kth element of the merged array.\n \"\"\"\n # Combine the two sorted arrays into one array\n merged = sorted(arr1 + arr2)\n \n # Since list indices are 0-based, subtract 1 from k\n return merged[k - 1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(arr1, arr2, k):\n \"\"\"\n Find kth element from two sorted arrays.\n\n Args:\n arr1 (list): The first sorted array.\n arr2 (list): The second sorted array.\n k (int): The index of the element to find (1-indexed).\n\n Returns:\n int: The kth element from the merged arrays.\n \"\"\"\n # Merge two sorted arrays into one\n merged = sorted(arr1 + arr2)\n \n # Adjust k for 0-indexing\n k -= 1\n \n # Check if k is within the bounds of the merged array\n if k < 0 or k >= len(merged):\n raise ValueError(\"k is out of bounds\")\n \n # Return the kth element\n return merged[k]", "matching_cluster_idx": 3}, {"solution": "def find_kth(arr1, arr2, k):\n \"\"\"\n Find the kth element in the merged sorted array of two given sorted arrays.\n \n Args:\n arr1 (list): The first sorted array.\n arr2 (list): The second sorted array.\n k (int): The index of the element to find (1-indexed).\n \n Returns:\n int: The kth element in the merged sorted array.\n \n Raises:\n ValueError: If k is less than 1 or greater than the combined length of the two arrays.\n \"\"\"\n if k < 1 or k > len(arr1) + len(arr2):\n raise ValueError(\"k is out of range\")\n \n # Merge the two sorted arrays\n merged = sorted(arr1 + arr2)\n \n # Return the kth element (adjust for 0-indexing)\n return merged[k - 1]", "matching_cluster_idx": 2}, {"solution": "def find_kth(nums1, nums2, k):\n \"\"\"\n Find the kth element from two sorted arrays.\n\n Args:\n nums1 (list): The first sorted array.\n nums2 (list): The second sorted array.\n k (int): The index of the element to be found (1-indexed).\n\n Returns:\n int: The kth element from the combined and sorted array.\n \"\"\"\n # Merge the two arrays and sort the merged array\n merged = sorted(nums1 + nums2)\n \n # Check if k is within the bounds of the merged array\n if k < 1 or k > len(merged):\n raise ValueError(\"k is out of range\")\n \n # Return the kth element (adjusting for 0-indexing)\n return merged[k - 1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(arr1, arr2, k):\n \"\"\"\n This function finds the kth element from the merged array of two sorted arrays.\n\n Args:\n arr1 (list): The first sorted array.\n arr2 (list): The second sorted array.\n k (int): The index of the element to find (1-indexed).\n\n Returns:\n int: The kth element from the merged array.\n\n Raises:\n ValueError: If k is less than 1 or greater than the length of the merged array.\n \"\"\"\n # Merge the two sorted arrays into one\n merged = sorted(arr1 + arr2)\n \n # Check if k is within the valid range\n if k < 1 or k > len(merged):\n raise ValueError(\"k is out of range\")\n \n # Return the kth element (adjusting for 0-indexing)\n return merged[k - 1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(nums1, nums2, k):\n \"\"\"\n Finds the kth element from two sorted arrays.\n \n Args:\n nums1 (list): The first sorted array.\n nums2 (list): The second sorted array.\n k (int): The index of the desired element (1-indexed).\n \n Returns:\n The kth element from the merged sorted array.\n \"\"\"\n merged = sorted(nums1 + nums2)\n return merged[k - 1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(nums1, nums2, k):\n \"\"\"\n This function finds the kth element from the given two sorted arrays.\n \n Args:\n nums1 (list): The first sorted list of integers.\n nums2 (list): The second sorted list of integers.\n k (int): The position of the element to find in the merged list.\n \n Returns:\n int: The kth element in the merged sorted list.\n \"\"\"\n \n # Merge the two sorted lists into one\n merged = sorted(nums1 + nums2)\n \n # Check if k is within the bounds of the merged list\n if k < 1 or k > len(merged):\n raise ValueError(\"k is out of range\")\n \n # Return the kth element\n return merged[k - 1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(arr1, arr2, k):\n \"\"\"\n This function finds the kth element from two sorted arrays.\n \n Parameters:\n arr1 (list): The first sorted list of integers.\n arr2 (list): The second sorted list of integers.\n k (int): The kth element to find.\n \n Returns:\n int: The kth element if it exists. Otherwise, returns None.\n \"\"\"\n # Merge both sorted lists and find the kth element\n merged_list = sorted(arr1 + arr2)\n return merged_list[k - 1] if k <= len(merged_list) else None", "matching_cluster_idx": 3}, {"solution": "def find_kth(arr1, arr2, k):\n \"\"\"\n Find the kth element from two sorted arrays.\n\n Args:\n arr1 (list): First sorted array.\n arr2 (list): Second sorted array.\n k (int): Index of the element to find (1-indexed).\n\n Returns:\n int: The kth element from the combined sorted array.\n\n Raises:\n ValueError: If k is larger than the combined length of the two arrays.\n \"\"\"\n # Combine the two arrays\n combined = arr1 + arr2\n \n # Sort the combined array in ascending order\n combined.sort()\n \n # Check if k is within the bounds of the combined array\n if k < 1 or k > len(combined):\n raise ValueError(\"k is out of range\")\n \n # Return the kth element\n return combined[k - 1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(arr1, arr2, k):\n \"\"\"\n Find the kth element from the given two sorted arrays.\n\n Args:\n arr1 (list): The first sorted list.\n arr2 (list): The second sorted list.\n k (int): The index of the element to be found.\n\n Returns:\n int: The kth element from the merged sorted list.\n\n Raises:\n ValueError: If k is larger than the total number of elements in both arrays.\n \"\"\"\n # Merge the two sorted lists\n merged = sorted(arr1 + arr2)\n # Check if k is within the valid range\n if k < 1 or k > len(merged):\n raise ValueError(\"k is out of range\")\n # Return the kth element\n return merged[k - 1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(arr1, arr2, k):\n \"\"\"\n This function finds the kth smallest element from two sorted arrays.\n\n Args:\n arr1 (list): First sorted array.\n arr2 (list): Second sorted array.\n k (int): Index of the element to be found.\n\n Returns:\n int: kth element from the merged array.\n \"\"\"\n # Merge the two sorted arrays into one\n merged = sorted(arr1 + arr2)\n \n # Check if k is within the bounds of the merged array\n if k < 1 or k > len(merged):\n raise ValueError(\"k is out of range\")\n\n # Return the kth element\n return merged[k - 1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(arr1, arr2, k):\n \"\"\"\n Find kth element from two sorted arrays.\n\n Args:\n arr1 (list): First sorted array.\n arr2 (list): Second sorted array.\n k (int): Index of the element to find.\n\n Returns:\n int: The kth element from the combined sorted array.\n\n Raises:\n ValueError: If k is out of range.\n \"\"\"\n\n # Merge two sorted arrays into one\n merged = sorted(arr1 + arr2)\n\n # Check if k is within bounds\n if k < 1 or k > len(merged):\n raise ValueError(\"k is out of range\")\n\n # Return the kth element\n return merged[k - 1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(arr1, arr2, k):\n \"\"\"\n Find the kth element from two sorted arrays.\n \n Args:\n arr1 (list): The first sorted array.\n arr2 (list): The second sorted array.\n k (int): The position of the element to find.\n \n Returns:\n int: The kth element.\n \"\"\"\n return sorted([*arr1, *arr2])[k-1]", "matching_cluster_idx": 2}]}, "Mbpp/604": {"dps": 85.68181818181819, "dps_norm": 97.0, "pass@1": 77.0, "profiled": [{"solution": "def reverse_words(s):\n \"\"\"\n This function takes a string as input and returns the string with words reversed.\n\n Args:\n s (str): The input string with words separated by spaces.\n\n Returns:\n str: The input string with words in reverse order.\n \"\"\"\n return ' '.join(reversed(s.split()))", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n \"\"\"\n Reverses the order of words in a given string.\n\n Args:\n s (str): The input string.\n\n Returns:\n str: The input string with the order of words reversed.\n \"\"\"\n # Split the input string into a list of words\n words = s.split()\n\n # Reverse the list of words\n reversed_words = words[::-1]\n\n # Join the reversed list of words back into a string separated by spaces\n reversed_string = ' '.join(reversed_words)\n\n return reversed_string", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n \"\"\"\n This function takes a string of words separated by spaces, \n and returns a new string with the order of words reversed.\n \n Parameters:\n s (str): The input string of words.\n \n Returns:\n str: The string with words reversed.\n \"\"\"\n # Split the string into a list of words\n words = s.split()\n \n # Reverse the list of words\n reversed_words = words[::-1]\n \n # Join the reversed list of words into a string\n reversed_s = ' '.join(reversed_words)\n \n return reversed_s", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n \"\"\"\n This function takes a string as input and returns a new string with the order of its words reversed.\n \n Args:\n s (str): The input string.\n \n Returns:\n str: The string with words reversed.\n \"\"\"\n # Split the input string into a list of words\n words = s.split()\n \n # Reverse the list of words\n reversed_words = words[::-1]\n \n # Join the list of reversed words into a string separated by spaces\n reversed_string = ' '.join(reversed_words)\n \n return reversed_string", "matching_cluster_idx": 4}, {"solution": "def reverse_words(input_string):\n \"\"\"\n Reverses the order of words in a given string.\n\n Args:\n input_string (str): The string containing words separated by spaces.\n\n Returns:\n str: A string with words in reverse order.\n \"\"\"\n words = input_string.split()\n reversed_string = ' '.join(reversed(words))\n return reversed_string", "matching_cluster_idx": 3}, {"solution": "def reverse_words(s):\n \"\"\"\n This function takes a string of words separated by spaces, and returns a new string \n where the order of the words is reversed.\n\n Args:\n s (str): A string of words separated by spaces.\n\n Returns:\n str: A new string where the order of the words is reversed.\n \"\"\"\n # Split the input string into a list of words using split method\n words = s.split()\n \n # Reverse the list of words using list reversal\n reversed_words = words[::-1]\n \n # Join the reversed list of words into a string using join method\n reversed_string = ' '.join(reversed_words)\n \n return reversed_string", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n \"\"\"\n This function takes a string of words separated by spaces and returns the reversed list of words.\n \n Parameters:\n s (str): Input string of words separated by spaces.\n \n Returns:\n list: List of words in the input string in reverse order.\n \"\"\"\n # Split the input string into a list of words\n words = s.split()\n \n # Reverse the list of words\n reversed_words = words[::-1]\n \n # Join the reversed list of words back into a string\n reversed_string = ' '.join(reversed_words)\n \n return reversed_string", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n \"\"\"\n This function reverses the order of words in a given string.\n \n Args:\n s (str): The input string.\n \n Returns:\n str: A string with words reversed.\n \"\"\"\n # Split the string into a list of words\n words = s.split()\n \n # Reverse the order of the list of words\n reversed_words = words[::-1]\n \n # Join the reversed list of words back into a string\n reversed_string = ' '.join(reversed_words)\n \n return reversed_string", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n \"\"\"\n Reverses the order of words in a given string.\n\n Args:\n s (str): Input string with words separated by spaces.\n\n Returns:\n str: String with words in reversed order.\n \"\"\"\n # Split the string into a list of words\n words = s.split()\n \n # Reverse the list of words\n words = words[::-1]\n \n # Join the reversed list of words back into a string\n reversed_string = ' '.join(words)\n \n return reversed_string", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n \"\"\"\n Reverses the order of words in a given string.\n\n Args:\n s (str): The input string.\n\n Returns:\n str: The input string with words reversed.\n\n Example:\n >>> reverse_words(\"python program\")\n \"program python\"\n \"\"\"\n return ' '.join(s.split()[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n \"\"\"\n Reverses the order of words in a given string.\n \n Args:\n s (str): The input string.\n \n Returns:\n str: The string with words reversed.\n \"\"\"\n # Split the string into a list of words\n words = s.split()\n \n # Reverse the list of words\n reversed_words = words[::-1]\n \n # Join the reversed list back into a string separated by spaces\n reversed_s = ' '.join(reversed_words)\n \n return reversed_s", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n \"\"\"\n This function takes a string of words separated by spaces and returns a new string \n where the order of the words is reversed.\n\n Args:\n s (str): Input string of words separated by spaces.\n\n Returns:\n str: A new string with words in reversed order.\n \"\"\"\n return ' '.join(s.split()[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n \"\"\"\n This function takes a string as input, splits it into words and returns the words in reverse order.\n\n Parameters:\n s (str): Input string.\n\n Returns:\n str: String with words reversed.\n \"\"\"\n # Split the input string into a list of words\n words = s.split()\n \n # Reverse the list of words\n words = words[::-1]\n \n # Join the reversed list of words back into a string\n reversed_s = ' '.join(words)\n \n return reversed_s", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n \"\"\"\n Reverses the order of words in a string.\n\n Args:\n s (str): Input string\n\n Returns:\n str: Reversed string with words separated by spaces.\n \"\"\"\n return ' '.join(s.split()[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(input_str):\n \"\"\"\n This function takes a string as an input and returns a string with all words reversed.\n\n Args:\n input_str (str): The input string.\n\n Returns:\n str: The string with words reversed.\n\n Example:\n >>> reverse_words(\"python program\")\n 'program python'\n \"\"\"\n return ' '.join(input_str.split()[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n \"\"\"\n This function takes a string as input, splits it into words and reverses the order of words.\n\n Args:\n s (str): The input string\n\n Returns:\n str: A new string where words are in reverse order.\n \"\"\"\n return ' '.join(s.split()[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n \"\"\"\n Reverses the order of words in a given string.\n\n Args:\n s (str): The input string.\n\n Returns:\n str: The string with the order of words reversed.\n \"\"\"\n return ' '.join(reversed(s.split()))", "matching_cluster_idx": 3}, {"solution": "def reverse_words(input_string):\n \"\"\"\n Reverses the order of words in a given string.\n\n Args:\n input_string (str): The string from which to reverse words.\n\n Returns:\n str: The input string with words reversed in order.\n \"\"\"\n words = input_string.split() # Split the string into a list of words\n return ' '.join(reversed(words)) # Reverse the list of words and join them back into a string", "matching_cluster_idx": 3}, {"solution": "def reverse_words(s):\n \"\"\"\n Reverse words in a given string.\n\n Args:\n s (str): Input string\n\n Returns:\n str: String with words reversed\n \"\"\"\n # Split the input string into a list of words using the split() method\n words = s.split()\n \n # Reverse the list of words using slicing\n reversed_words = words[::-1]\n \n # Join the reversed list of words back into a string using the join() method\n reversed_string = ' '.join(reversed_words)\n \n return reversed_string", "matching_cluster_idx": 4}, {"solution": "def reverse_words(input_str):\n \"\"\"\n This function takes a string as an input and returns a new string with words \n separated by spaces, but with the order of the words reversed.\n\n Args:\n input_str (str): The input string\n\n Returns:\n str: A new string with words separated by spaces in the reversed order\n\n \"\"\"\n words = input_str.split() # split the input string into a list of words\n reversed_words = words[::-1] # reverse the order of the words\n result = ' '.join(reversed_words) # join the reversed words with spaces\n return result", "matching_cluster_idx": 4}]}, "Mbpp/610": {"dps": 57.89855072463769, "dps_norm": 61.42857142857143, "pass@1": 45.0, "profiled": [{"solution": "def remove_kth_element(lst, k):\n \"\"\"\n Removes the k'th element from the given list.\n \n Args:\n lst (list): The input list.\n k (int): The index of the element to be removed (1-indexed).\n \n Returns:\n list: The list with the k'th element removed.\n \"\"\"\n if k < 1 or k > len(lst):\n raise ValueError(\"k is out of range\")\n return lst[:k-1] + lst[k:]", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(lst, k):\n \"\"\"\n Removes the k'th element from the list.\n \n Args:\n lst (list): The input list.\n k (int): The index of the element to be removed.\n \n Returns:\n list: The list with the k'th element removed.\n \"\"\"\n \n # Check if k is a valid index\n if k < 1 or k > len(lst):\n raise ValueError(\"k is out of range\")\n \n # Create a copy of the list\n new_lst = lst.copy()\n \n # Remove the k'th element\n new_lst.pop(k - 1)\n \n return new_lst", "matching_cluster_idx": 4}, {"solution": "def remove_kth_element(lst, k):\n \"\"\"\n Removes the k'th element from the list and returns the modified list.\n\n Args:\n lst (list): The input list from which to remove the k'th element.\n k (int): The index of the element to remove (1-indexed).\n\n Returns:\n list: The list with the k'th element removed.\n \"\"\"\n if k < 1 or k > len(lst):\n raise ValueError(\"k is out of range\")\n\n return lst[:k-1] + lst[k:]", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(lst, k):\n \"\"\"\n This function takes a list and returns a list with the same elements, \n but the k'th element removed.\n\n Args:\n lst (list): The input list.\n k (int): The index of the element to be removed.\n\n Returns:\n list: A new list with the k'th element removed.\n \"\"\"\n if k < 1 or k > len(lst):\n raise ValueError(\"k is out of range\")\n\n return lst[:k-1] + lst[k:]", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(lst, k):\n \"\"\"\n Removes the k'th element from a list and returns the new list.\n\n Args:\n lst (list): The input list.\n k (int): The index of the element to remove (1-indexed).\n\n Returns:\n list: The list with the k'th element removed.\n \"\"\"\n # Check if k is within the bounds of the list\n if 1 <= k <= len(lst):\n # Remove the k'th element (since we use 1-indexing)\n return lst[:k-1] + lst[k:]\n else:\n # If k is out of bounds, return the original list\n return lst", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(lst, k):\n \"\"\"\n This function removes the k'th element from the list and returns the resulting list.\n\n Parameters:\n lst (list): The input list.\n k (int): The index of the element to be removed (1-indexed).\n\n Returns:\n list: The list with the k'th element removed.\n \"\"\"\n # Validate the input\n if not isinstance(lst, list) or not all(isinstance(x, (int, float)) for x in lst):\n raise ValueError(\"The input list must contain only integers or floats.\")\n if not isinstance(k, int) or k < 1 or k > len(lst):\n raise ValueError(\"k must be a positive integer between 1 and the length of the list.\")\n\n # Remove the k'th element (remember, we use 0-based indexing in Python)\n return lst[:k-1] + lst[k:]", "matching_cluster_idx": 1}, {"solution": "def remove_kth_element(lst, k):\n \"\"\"\n This function removes the kth element from the given list and returns the modified list.\n\n Args:\n lst (list): The input list from which the kth element needs to be removed.\n k (int): The position of the element to be removed.\n\n Returns:\n list: The list with the kth element removed.\n\n Raises:\n ValueError: If k is out of range.\n \"\"\"\n if k < 1 or k > len(lst):\n raise ValueError(\"k is out of range\")\n\n # Return the list with the kth element removed by slicing\n return lst[:k-1] + lst[k:]", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(lst, k):\n \"\"\"\n This function removes the k'th element from the input list.\n \n Args:\n lst (list): The input list.\n k (int): The index of the element to be removed (1-indexed).\n \n Returns:\n list: A new list with the k'th element removed.\n \"\"\"\n \n # Check if k is within the list boundaries\n if k < 1 or k > len(lst):\n raise ValueError(\"k is out of range\")\n \n # Create a copy of the list to avoid modifying the original list\n new_list = lst.copy()\n \n # Remove the k'th element\n new_list.pop(k - 1) # Subtract 1 because list indices are 0-based\n \n return new_list", "matching_cluster_idx": 4}, {"solution": "def remove_kth_element(lst, k):\n \"\"\"\n This function takes a list and returns a list with the same elements, but the k'th element removed.\n \n Args:\n lst (list): The input list from which the k'th element is to be removed.\n k (int): The position of the element to be removed.\n \n Returns:\n list: A list with the k'th element removed.\n \"\"\"\n # Check if k is within the bounds of the list\n if k < 1 or k > len(lst):\n raise ValueError(\"k is out of range\")\n \n # Create a new list that includes all elements except the k'th one\n new_lst = [x for i, x in enumerate(lst) if i != k - 1]\n \n return new_lst", "matching_cluster_idx": 0}, {"solution": "def remove_kth_element(lst, k):\n \"\"\"\n This function takes a list and returns a list with the same elements, \n but the k'th element is removed.\n \n Args:\n lst (list): Input list\n k (int): Index of the element to be removed\n \n Returns:\n list: List with the k'th element removed\n \"\"\"\n if k > len(lst):\n raise ValueError(\"k is out of range\")\n \n del lst[k-1]\n return lst", "matching_cluster_idx": 6}, {"solution": "def remove_kth_element(lst, k):\n \"\"\"\n This function removes the k'th element from a given list and returns the result.\n \n Args:\n lst (list): The input list.\n k (int): The position of the element to be removed (1-indexed).\n \n Returns:\n list: The list with the k'th element removed.\n \"\"\"\n # Convert 1-indexed to 0-indexed\n k -= 1\n \n # Check if k is within the list bounds\n if k < 0 or k >= len(lst):\n raise ValueError(\"k is out of bounds\")\n \n # Remove the k'th element using list slicing\n return lst[:k] + lst[k+1:]", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(lst, k):\n \"\"\"\n Removes the k'th element from the list.\n\n Args:\n lst (list): The input list.\n k (int): The position of the element to remove (1-indexed).\n\n Returns:\n list: The list with the k'th element removed.\n \"\"\"\n return lst[:k-1] + lst[k:]", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(lst, k):\n \"\"\"\n This function removes the k'th element from the input list.\n \n Parameters:\n lst (list): The input list.\n k (int): The index of the element to remove (1-indexed).\n \n Returns:\n list: The input list with the k'th element removed.\n \"\"\"\n \n # Handle edge case where k is larger than list length\n if k > len(lst):\n return lst\n \n # Remove the k'th element from the list\n return lst[:k-1] + lst[k:]", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(lst, k):\n \"\"\"\n Returns a list with the same elements as the input list, but with the k'th element removed.\n \n Args:\n lst (list): The input list.\n k (int): The index of the element to remove.\n \n Returns:\n list: A new list with the k'th element removed.\n \"\"\"\n if k < 1 or k > len(lst):\n raise ValueError(\"k is out of range\")\n \n return lst[:k-1] + lst[k:]", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(lst, k):\n \"\"\"\n Removes the k'th element from the input list and returns the resulting list.\n\n Args:\n lst (list): The input list from which to remove the k'th element.\n k (int): The index of the element to remove (1-indexed).\n\n Returns:\n list: The list with the k'th element removed.\n \"\"\"\n k = k - 1 # Convert to 0-indexed position\n return lst[:k] + lst[k+1:] # Use list slicing to remove the k'th element", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(lst, k):\n \"\"\"\n This function removes the k'th element from a list.\n \n Args:\n lst (list): The input list.\n k (int): The index of the element to be removed (1-indexed).\n \n Returns:\n list: The list with the k'th element removed.\n \"\"\"\n # Since list indices are 0-based, we subtract 1 from k\n k -= 1\n \n # Remove the k'th element from the list\n lst.pop(k)\n \n return lst", "matching_cluster_idx": 6}, {"solution": "def remove_kth_element(lst, k):\n \"\"\"\n This function removes the k'th element from a given list.\n \n Args:\n lst (list): The input list from which the k'th element is to be removed.\n k (int): The position of the element to be removed (1-indexed).\n \n Returns:\n list: A new list with the same elements as the original list, but the k'th element removed.\n \"\"\"\n \n # Create a copy of the original list to avoid modifying it in-place\n new_lst = lst.copy()\n \n # Subtract 1 from k because list indices are 0-based\n k -= 1\n \n # Remove the k'th element from the new list\n new_lst.pop(k)\n \n return new_lst", "matching_cluster_idx": 5}, {"solution": "def remove_kth_element(lst, k):\n \"\"\"\n This function removes the k'th element from the list.\n \n Args:\n lst (list): The input list from which to remove the k'th element.\n k (int): The index of the element to remove (1-indexed).\n\n Returns:\n list: The list with the k'th element removed.\n \"\"\"\n \n # Check if the list has less than k elements\n if k < 1 or k > len(lst):\n raise ValueError(\"k is out of range\")\n \n # Create a copy of the list\n new_lst = lst.copy()\n \n # Remove the k'th element\n new_lst.pop(k-1)\n \n return new_lst", "matching_cluster_idx": 4}, {"solution": "def remove_kth_element(lst, k):\n \"\"\"\n This function takes a list and returns a list with the same elements, \n but the k'th element is removed if it exists, otherwise the original list is returned.\n\n Args:\n lst (list): The input list.\n k (int): The position of the element to remove.\n\n Returns:\n list: The input list with the k'th element removed if it exists.\n \"\"\"\n\n # Check if k is within the range of the list\n if 1 <= k <= len(lst):\n # Remove the k'th element from the list\n return lst[:k-1] + lst[k:]\n else:\n # If k is out of range, return the original list\n return lst", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(lst, k):\n \"\"\"\n This function removes the k'th element from a given list.\n\n Args:\n lst (list): The input list from which the k'th element is to be removed.\n k (int): The index of the element to be removed.\n\n Returns:\n list: A list with the same elements as the input list, but with the k'th element removed.\n\n Raises:\n IndexError: If k is out of range for the given list.\n \"\"\"\n if k < 1 or k > len(lst):\n raise IndexError(\"k is out of range\")\n \n return lst[:k-1] + lst[k:]", "matching_cluster_idx": 3}]}, "Mbpp/611": {"dps": null, "dps_norm": null, "pass@1": 8.0, "profiled": []}, "Mbpp/631": {"dps": null, "dps_norm": null, "pass@1": 2.0, "profiled": []}, "Mbpp/632": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 99.0, "profiled": [{"solution": "def move_zero(lst):\n \"\"\"\n Move all zeroes to the end of the given list.\n\n Args:\n lst (list): The list to process.\n\n Returns:\n list: The list with all zeroes at the end.\n \"\"\"\n # Use a list comprehension to filter out zeroes and non-zero elements\n non_zeroes = [num for num in lst if num != 0]\n # Find the number of zeroes in the original list\n num_zeroes = len(lst) - len(non_zeroes)\n # Append zeroes to the end of the non-zero list\n return non_zeroes + [0] * num_zeroes", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n \"\"\"\n This function moves all zeros in a given list to the end.\n \n Args:\n nums (list): A list of integers.\n \n Returns:\n list: The input list with all zeros at the end.\n \"\"\"\n return [num for num in nums if num != 0] + [0] * nums.count(0)", "matching_cluster_idx": 6}, {"solution": "def move_zero(lst):\n \"\"\"\n This function moves all zeroes to the end of the given list.\n\n Args:\n lst (list): A list of integers.\n\n Returns:\n list: A new list with all zeroes at the end.\n \"\"\"\n return [num for num in lst if num != 0] + [0] * lst.count(0)", "matching_cluster_idx": 6}, {"solution": "def move_zero(lst):\n \"\"\"\n This function moves all zeroes to the end of the given list.\n\n Args:\n lst (list): The input list that may contain zeroes.\n\n Returns:\n list: The modified list with zeroes moved to the end.\n \"\"\"\n # Use list comprehension to create a new list with non-zero elements\n non_zero = [i for i in lst if i != 0]\n # Use list comprehension to create a list of zeroes equal to the number of zeroes in the original list\n zeroes = [0] * (len(lst) - len(non_zero))\n # Combine the two lists\n return non_zero + zeroes", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n \"\"\"\n Move all zeroes to the end of the given list.\n \n Args:\n nums (list): A list of integers.\n \n Returns:\n list: The list with all zeroes at the end.\n \"\"\"\n # Separate non-zero elements from zeros using list comprehension\n non_zero = [num for num in nums if num != 0]\n \n # Append the original list of zeros to the end of non_zero list\n return non_zero + [0] * nums.count(0)", "matching_cluster_idx": 6}, {"solution": "def move_zero(lst):\n \"\"\"\n This function takes a list as input, moves all zeroes to the end of the list and returns the modified list.\n \n Args:\n lst (list): The input list that may or may not contain zeroes.\n \n Returns:\n list: The input list with all zeroes moved to the end.\n \"\"\"\n return [i for i in lst if i != 0] + [0] * lst.count(0)", "matching_cluster_idx": 6}, {"solution": "def move_zero(lst):\n \"\"\"\n Move all zeroes to the end of the given list.\n\n Args:\n lst (list): The input list.\n\n Returns:\n list: The list with all zeroes moved to the end.\n \"\"\"\n non_zeros = [num for num in lst if num != 0] # Filter out zeroes\n return non_zeros + [0] * lst.count(0) # Add zeroes back in, repeating them as necessary", "matching_cluster_idx": 6}, {"solution": "def move_zero(lst):\n \"\"\"\n This function moves all zeroes in a list to the end.\n\n Args:\n lst (list): The list that needs to be modified.\n\n Returns:\n list: The modified list with all zeroes at the end.\n \"\"\"\n # Use list comprehension to filter out non-zero elements and append zeroes\n non_zero = [num for num in lst if num != 0]\n zeroes = [num for num in lst if num == 0]\n # Combine non-zero and zero elements to form the final list\n return non_zero + zeroes", "matching_cluster_idx": 6}, {"solution": "def move_zero(lst):\n \"\"\"\n Move all zeroes to the end of the given list.\n \n Args:\n lst (list): The input list to be modified.\n \n Returns:\n list: The modified list with all zeroes at the end.\n \"\"\"\n return [i for i in lst if i != 0] + [0] * lst.count(0)", "matching_cluster_idx": 6}, {"solution": "def move_zero(lst):\n \"\"\"\n Moves all zeroes to the end of the given list.\n\n Args:\n lst (list): The input list with potential zeroes.\n\n Returns:\n list: The list with all zeroes moved to the end.\n \"\"\"\n return [x for x in lst if x != 0] + [0] * lst.count(0)", "matching_cluster_idx": 6}, {"solution": "def move_zero(lst):\n \"\"\"\n Move all zeroes to the end of the given list.\n \n Args:\n lst (list): A list of integers.\n \n Returns:\n list: The input list with all zeroes moved to the end.\n \"\"\"\n return [i for i in lst if i != 0] + [0] * lst.count(0)", "matching_cluster_idx": 6}, {"solution": "def move_zero(arr):\n \"\"\"\n Move all zeroes to the end of the given list.\n\n Args:\n arr (list): Input list that can contain zeroes and non-zero elements.\n\n Returns:\n list: A list with all zeroes moved to the end.\n\n \"\"\"\n return [x for x in arr if x != 0] + [0] * arr.count(0)", "matching_cluster_idx": 6}, {"solution": "def move_zero(lst):\n \"\"\"\n Moves all zeros to the end of the given list.\n \n Args:\n lst (list): A list of numbers.\n \n Returns:\n list: The list with all zeros moved to the end.\n \"\"\"\n # Filter out zeros and store them separately\n non_zeros = [x for x in lst if x != 0]\n # Create the final list with zeros at the end\n result = non_zeros + [0] * lst.count(0)\n return result", "matching_cluster_idx": 6}, {"solution": "def move_zero(lst):\n \"\"\"\n Function to move all zeroes to the end of the given list.\n \n Args:\n lst (list): The input list.\n \n Returns:\n list: The list with all zeroes moved to the end.\n \"\"\"\n return [i for i in lst if i != 0] + [0] * lst.count(0)", "matching_cluster_idx": 6}, {"solution": "def move_zero(lst):\n \"\"\"\n This function moves all zeroes to the end of the given list.\n \n Parameters:\n lst (list): The input list.\n \n Returns:\n list: The modified list with all zeroes moved to the end.\n \"\"\"\n # Initialize two pointers, one at the beginning and one at the end of the list\n next_non_zero = 0\n for i in range(len(lst)):\n # If the current element is not zero, swap it with the element at the next_non_zero position\n if lst[i] != 0:\n lst[next_non_zero], lst[i] = lst[i], lst[next_non_zero]\n # Move the next_non_zero pointer forward\n next_non_zero += 1\n return lst", "matching_cluster_idx": 6}, {"solution": "def move_zero(lst):\n \"\"\"\n Move all zeroes to the end of the given list.\n \n Args:\n lst (list): The input list which may or may not contain zeroes.\n \n Returns:\n list: The list with all zeroes moved to the end.\n \"\"\"\n return [i for i in lst if i != 0] + [0] * lst.count(0)", "matching_cluster_idx": 6}, {"solution": "def move_zero(lst):\n \"\"\"\n Move all zeroes to the end of the list.\n\n Args:\n lst (list): The list to move zeroes from.\n\n Returns:\n list: The list with all zeroes at the end.\n \"\"\"\n # Filter out zeroes and non-zero elements into two separate lists\n non_zero = [num for num in lst if num != 0]\n zero = [num for num in lst if num == 0]\n\n # Combine the lists to get the final result\n return non_zero + zero", "matching_cluster_idx": 6}, {"solution": "def move_zero(lst):\n \"\"\"\n This function takes a list of integers as input, \n and moves all zeroes to the end of the list.\n \n Parameters:\n lst (list): A list of integers\n \n Returns:\n list: A list with all zeroes moved to the end.\n \"\"\"\n return [i for i in lst if i != 0] + [0] * lst.count(0)", "matching_cluster_idx": 6}, {"solution": "def move_zero(lst):\n \"\"\"\n Move all zeroes to the end of the given list.\n \n Args:\n lst (list): A list of integers\n \n Returns:\n list: A new list with all zeroes at the end\n \"\"\"\n return [i for i in lst if i != 0] + [0] * lst.count(0)", "matching_cluster_idx": 6}, {"solution": "def move_zero(lst):\n \"\"\"\n This function takes a list as input and returns the list with all zeroes moved to the end.\n\n Args:\n lst (list): The input list to be modified.\n\n Returns:\n list: A new list where all zeroes are moved to the end.\n \"\"\"\n # Use list comprehension to create a new list that excludes zeroes\n non_zero_list = [i for i in lst if i != 0]\n \n # Append the count of zeroes in the original list to the new list\n return non_zero_list + [0] * lst.count(0)", "matching_cluster_idx": 6}]}, "Mbpp/633": {"dps": null, "dps_norm": null, "pass@1": 1.0, "profiled": []}, "Mbpp/644": {"dps": 74.57446808510637, "dps_norm": 77.0, "pass@1": 89.0, "profiled": [{"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n Reverses an array up to the given position.\n\n Args:\n arr (list): The input list to reverse.\n k (int): The position up to which the array is reversed.\n\n Returns:\n list: The modified list.\n \"\"\"\n return arr[:k][::-1] + arr[k:]", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n Reverses an array up to a given position.\n\n Parameters:\n arr (list): The input array to be reversed.\n k (int): The position up to which the array is reversed.\n\n Returns:\n list: The reversed array up to the given position.\n \"\"\"\n # Reverse the array up to the given position using list slicing\n reversed_part = arr[:k][::-1]\n # Return the combined original array and the reversed part\n return arr[:k][::-1] + arr[k:]", "matching_cluster_idx": 9}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n This function reverses an array up to a given position k.\n \n Args:\n arr (list): The input list of elements.\n k (int): The position up to which the array needs to be reversed.\n \n Returns:\n list: The modified list after reversing elements up to the given position k.\n \"\"\"\n # Check if k is within the bounds of the array\n if k > len(arr) or k < 1:\n return \"k should be within the range of array length\"\n \n # Reverse the array up to the given position\n arr[:k] = arr[:k][::-1]\n \n # Return the modified array\n return arr", "matching_cluster_idx": 13}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n Reverses an array up to a given position.\n\n Args:\n arr (list): The input list of numbers.\n k (int): The position up to which the list should be reversed.\n\n Returns:\n list: The modified list with elements reversed up to position k.\n\n Raises:\n ValueError: If k is greater than the length of the array.\n \"\"\"\n\n if k > len(arr):\n raise ValueError(\"k cannot be greater than the length of the array.\")\n\n # Reverse the array up to position k\n arr[:k] = arr[:k][::-1]\n\n # Return the modified array\n return arr", "matching_cluster_idx": 13}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n Reverses the given array up to the kth position.\n \n Args:\n arr (list): The input array to be reversed up to k position.\n k (int): The position up to which the array is to be reversed.\n \n Returns:\n list: The array with its elements reversed up to k position.\n \"\"\"\n \n # Reverse the array up to k position\n return arr[:k][::-1] + arr[k:]", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n Reverses an array up to a given position.\n\n Args:\n arr (list): The input array.\n k (int): The position up to which the array should be reversed.\n\n Returns:\n list: The modified array with elements reversed up to position k.\n \"\"\"\n return arr[:k][::-1] + arr[k:]", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n Reverses the array up to a given position k.\n \n Args:\n arr (list): Input array to be reversed.\n k (int): Position up to which the array needs to be reversed.\n \n Returns:\n list: Array with elements up to position k reversed.\n \"\"\"\n # Reverse the array up to position k\n arr[:k] = arr[:k][::-1]\n \n # Return the modified array\n return arr", "matching_cluster_idx": 13}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n Reverses the array up to a given position k.\n\n Args:\n arr (list): The input array to be reversed.\n k (int): The position up to which the array needs to be reversed.\n\n Returns:\n list: The modified array with elements up to position k reversed.\n \"\"\"\n return arr[:k][::-1] + arr[k:]", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n Reverses an array up to a given position k.\n\n Args:\n arr (list): The input array.\n k (int): The position up to which the array should be reversed.\n\n Returns:\n list: The array with elements reversed up to position k.\n \"\"\"\n # Check if k is a valid position\n if k > len(arr):\n return \"Invalid position\"\n \n # Reverse the array up to position k\n return arr[:k][::-1] + arr[k:]", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n This function reverses an array up to a given position.\n\n Args:\n arr (list): The input list to be reversed.\n k (int): The position up to which the array is reversed.\n\n Returns:\n list: The modified list with the subarray reversed.\n\n \"\"\"\n return arr[:k][::-1] + arr[k:] # Slice the array up to k and reverse it, then append the rest", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n Reverses an array up to a given position.\n\n Args:\n arr (list): The input array to reverse.\n k (int): The position up to which the array should be reversed.\n\n Returns:\n list: The array with elements up to the given position reversed.\n \"\"\"\n return arr[:k][::-1] + arr[k:]", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n Reverses an array up to a given position.\n\n Args:\n arr (list): The input list of elements to be reversed.\n k (int): The position up to which the array needs to be reversed.\n\n Returns:\n list: The array with the elements up to k reversed.\n \"\"\"\n # Return the array if k is 0 or the array size is 0\n if k == 0 or len(arr) == 0:\n return arr\n \n # Reverse the array up to the given position\n return arr[:k][::-1] + arr[k:]", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n Reverses the array up to the given position k.\n \n Parameters:\n arr (list): The input array\n k (int): The position up to which the array needs to be reversed\n \n Returns:\n list: The modified array with the first k elements reversed.\n \"\"\"\n return arr[:k][::-1] + arr[k:]", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n Reverses an array up to a given position.\n \n Args:\n arr (list): The input list of integers.\n k (int): The position up to which the array should be reversed.\n \n Returns:\n list: The list with elements up to position k reversed.\n \"\"\"\n # Slice the array up to position k and reverse it\n reversed_subarray = arr[:k][::-1]\n \n # Combine the reversed subarray with the rest of the array\n return reversed_subarray + arr[k:]", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n Reverses an array up to a given position.\n\n Args:\n arr (list): The input array.\n k (int): The position up to which the array is reversed.\n\n Returns:\n list: The modified array.\n \"\"\"\n # Check if k is within the bounds of the array\n if k < 1 or k > len(arr):\n raise ValueError(\"k must be between 1 and the length of the array\")\n\n # Reverse the array up to k\n arr[:k] = arr[:k][::-1]\n \n # Return the modified array\n return arr", "matching_cluster_idx": 13}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n Reverses an array up to a given position.\n\n Args:\n arr (list): Input array\n k (int): Position up to which array needs to be reversed\n\n Returns:\n list: Reversed array\n \"\"\"\n # Check if k is within bounds of the array\n if k > len(arr):\n raise ValueError(\"k is out of bounds\")\n\n # Reverse the array up to position k\n return arr[:k][::-1] + arr[k:]", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n This function reverses a given array up to a specific position.\n \n Args:\n arr (list): The input list to be reversed.\n k (int): The position up to which the array needs to be reversed.\n \n Returns:\n list: The reversed array up to the given position.\n \"\"\"\n \n # Check if k is valid\n if k < 1 or k > len(arr):\n raise ValueError(\"k should be between 1 and the length of the array\")\n \n # Reverse the array up to the kth index\n return arr[:k][::-1] + arr[k:]", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n This function takes an array and an integer k as input.\n It reverses the array up to the k-th position and returns the modified array.\n\n Args:\n arr (list): The input array to be modified.\n k (int): The position up to which the array needs to be reversed.\n\n Returns:\n list: The modified array with elements up to the k-th position reversed.\n \"\"\"\n return arr[:k][::-1] + arr[k:]", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n Reverses the input array up to a given position k.\n\n Args:\n arr (list): The input array.\n k (int): The position up to which the array needs to be reversed.\n\n Returns:\n list: The array with elements reversed up to position k.\n \"\"\"\n # Create a copy of the input array\n result = arr[:]\n\n # Reverse the array up to the given position\n result[:k] = result[:k][::-1]\n\n return result", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n Reverses an array upto a given position.\n \n Parameters:\n arr (list): The input array\n k (int): The position upto which the array is reversed\n \n Returns:\n list: The modified array\n \"\"\"\n # Check if k is within the bounds of the array\n if k > len(arr):\n raise ValueError(\"k is out of bounds\")\n \n # Reverse the array from the start to the position k\n return arr[:k][::-1] + arr[k:]", "matching_cluster_idx": 10}]}, "Mbpp/720": {"dps": 69.23076923076923, "dps_norm": 90.0, "pass@1": 83.0, "profiled": [{"solution": "def add_dict_to_tuple(tup, dictionary):\n \"\"\"\n Adds a dictionary to a tuple.\n\n Args:\n tup (tuple): The original tuple.\n dictionary (dict): The dictionary to be added.\n\n Returns:\n tuple: A new tuple that includes the original tuple and the dictionary.\n \"\"\"\n # Convert the tuple to a list to be able to append the dictionary\n list_tup = list(tup)\n list_tup.append(dictionary)\n # Convert the list back to a tuple and return it\n return tuple(list_tup)", "matching_cluster_idx": 3}, {"solution": "def add_dict_to_tuple(input_tuple, input_dict):\n \"\"\"\n Add a dictionary to the end of a tuple.\n\n Args:\n input_tuple (tuple): The original tuple.\n input_dict (dict): The dictionary to add to the tuple.\n\n Returns:\n tuple: The updated tuple with the dictionary appended to its end.\n \"\"\"\n # Convert the input tuple to a list to allow for appending the dictionary\n list_from_tuple = list(input_tuple)\n # Append the dictionary to the list\n list_from_tuple.append(input_dict)\n # Convert the list back to a tuple and return\n return tuple(list_from_tuple)", "matching_cluster_idx": 3}, {"solution": "def add_dict_to_tuple(t, d):\n \"\"\"\n This function takes a tuple and a dictionary as input, and returns a new tuple containing the input tuple and the dictionary.\n\n Args:\n t (tuple): The input tuple.\n d (dict): The input dictionary.\n\n Returns:\n tuple: A new tuple containing the input tuple and the dictionary.\n \"\"\"\n # We use the + operator to concatenate the tuple and the dictionary as a new tuple.\n return t + (d,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(input_tuple, input_dict):\n \"\"\"\n This function adds a dictionary to a given tuple.\n\n Args:\n input_tuple (tuple): The input tuple to be modified.\n input_dict (dict): The dictionary to be added to the tuple.\n\n Returns:\n tuple: A new tuple that contains the elements of the input tuple and the input dictionary.\n \"\"\"\n return input_tuple + (input_dict,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(input_tuple, dictionary):\n \"\"\"\n Adds a dictionary to a given tuple and returns the new tuple.\n\n Args:\n input_tuple: A tuple to add the dictionary to.\n dictionary: The dictionary to be added to the tuple.\n\n Returns:\n A new tuple containing the original tuple and the dictionary.\n \"\"\"\n # Convert the tuple to a list to modify it\n modified_list = list(input_tuple)\n # Append the dictionary to the list\n modified_list.append(dictionary)\n # Convert the list back to a tuple and return it\n return tuple(modified_list)", "matching_cluster_idx": 3}, {"solution": "def add_dict_to_tuple(t, d):\n \"\"\"\n This function takes a tuple and a dictionary as input and returns a new tuple with the dictionary appended at the end.\n \n Args:\n t (tuple): The input tuple.\n d (dict): The dictionary to be appended to the tuple.\n \n Returns:\n tuple: A new tuple containing the input tuple and the dictionary.\n \"\"\"\n return (*t, d)\nt = (4, 5, 6)\nd = {\"MSAM\" : 1, \"is\" : 2, \"best\" : 3}", "matching_cluster_idx": 3}, {"solution": "def add_dict_to_tuple(input_tuple, input_dict):\n \"\"\"\n This function adds a dictionary to the end of the input tuple.\n \n Args:\n input_tuple (tuple): The input tuple to which the dictionary will be added.\n input_dict (dict): The dictionary to be added to the tuple.\n \n Returns:\n tuple: A new tuple with the input dictionary appended to the end of the input tuple.\n \"\"\"\n # Create a new tuple by concatenating the input tuple and the dictionary\n result = input_tuple + (input_dict,)\n \n return result", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(input_tuple, input_dict):\n \"\"\"\n This function takes a tuple and a dictionary as input and returns a new tuple that includes the original tuple's elements\n followed by the dictionary.\n\n Args:\n input_tuple (tuple): The original tuple.\n input_dict (dict): The dictionary to be added to the tuple.\n\n Returns:\n tuple: A new tuple that includes the original tuple's elements and the dictionary.\n \"\"\"\n # Combine the input tuple with the input dictionary\n combined_result = input_tuple + (input_dict,)\n \n # Return the combined result\n return combined_result", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(tup, dict_):\n \"\"\"\n Adds a dictionary to the end of a given tuple.\n \n Args:\n tup (tuple): The input tuple.\n dict_ (dict): The dictionary to add.\n \n Returns:\n tuple: The resulting tuple with the dictionary added.\n \"\"\"\n \n # Convert the tuple to a list to insert the dictionary\n # Lists are mutable, so they can contain mutable types like dictionaries\n tup_list = list(tup)\n \n # Append the dictionary to the list\n tup_list.append(dict_)\n \n # Convert the list back to a tuple and return\n return tuple(tup_list)", "matching_cluster_idx": 3}, {"solution": "def add_dict_to_tuple(input_tuple, dictionary):\n \"\"\"\n Adds a dictionary to the end of an input tuple.\n\n Args:\n input_tuple: The input tuple to which the dictionary will be added.\n dictionary: The dictionary that will be added to the input tuple.\n\n Returns:\n A new tuple that contains all elements from the input tuple followed by the dictionary.\n \"\"\"\n # Check if the input is indeed a tuple and the dictionary\n if not isinstance(input_tuple, tuple) or not isinstance(dictionary, dict):\n raise TypeError(\"Input must be a tuple and a dictionary\")\n\n # Create a new tuple with the input tuple and the dictionary\n new_tuple = input_tuple + (dictionary,)\n\n return new_tuple", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(t, d):\n \"\"\"\n This function adds a dictionary to the end of a tuple.\n \n Args:\n t (tuple): The input tuple\n d (dict): The dictionary to be added\n \n Returns:\n tuple: The tuple with the dictionary added to the end\n \"\"\"\n # Convert the tuple into a list (because tuples are immutable in Python)\n # so we can append the dictionary to it\n list_t = list(t)\n \n # Append the dictionary to the list\n list_t.append(d)\n \n # Convert the list back into a tuple and return it\n return tuple(list_t)", "matching_cluster_idx": 3}, {"solution": "def add_dict_to_tuple(t, d):\n \"\"\"\n This function adds a dictionary to a tuple.\n\n Args:\n t (tuple): Input tuple.\n d (dict): Input dictionary.\n\n Returns:\n tuple: Tuple with the dictionary appended.\n \"\"\"\n # Convert the tuple to a list to make it mutable\n t_list = list(t)\n # Append the dictionary to the list\n t_list.append(d)\n # Convert the list back to a tuple\n result = tuple(t_list)\n return result", "matching_cluster_idx": 3}, {"solution": "def add_dict_to_tuple(t, d):\n \"\"\"\n Adds a dictionary to the end of a tuple.\n\n Args:\n t (tuple): The initial tuple.\n d (dict): The dictionary to add.\n\n Returns:\n tuple: A new tuple containing the original elements and the added dictionary.\n \"\"\"\n return t + (d,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(tuple_arg, dictionary_arg):\n \"\"\"\n This function adds a dictionary to a given tuple.\n \n Args:\n tuple_arg (tuple): The input tuple to which a dictionary is added.\n dictionary_arg (dict): The dictionary to be added to the tuple.\n \n Returns:\n tuple: A new tuple that includes the original tuple and the dictionary.\n \"\"\"\n return tuple_arg + (dictionary_arg,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(tuple_arg, dictionary_arg):\n \"\"\"\n Adds a dictionary to a given tuple.\n\n Args:\n tuple_arg (tuple): The input tuple to which the dictionary will be added.\n dictionary_arg (dict): The dictionary to be added to the tuple.\n\n Returns:\n tuple: The resulting tuple with the dictionary added.\n \"\"\"\n # Convert the tuple to a list so that it can be modified\n list_arg = list(tuple_arg)\n \n # Append the dictionary to the list\n list_arg.append(dictionary_arg)\n \n # Convert the list back to a tuple\n result = tuple(list_arg)\n \n return result", "matching_cluster_idx": 3}, {"solution": "def add_dict_to_tuple(input_tuple, input_dict):\n \"\"\"\n Adds a dictionary to the end of an existing tuple.\n \n Args:\n input_tuple (tuple): The input tuple.\n input_dict (dict): The dictionary to be added.\n \n Returns:\n tuple: The resulting tuple with the dictionary at the end.\n \"\"\"\n # Convert the tuple into a list (because tuples are immutable in Python)\n list_from_tuple = list(input_tuple)\n # Append the dictionary to the list\n list_from_tuple.append(input_dict)\n # Convert the list back into a tuple\n result_tuple = tuple(list_from_tuple)\n \n return result_tuple", "matching_cluster_idx": 3}, {"solution": "def add_dict_to_tuple(input_tuple, input_dict):\n \"\"\"\n Adds a dictionary to the tuple.\n \n Args:\n input_tuple (tuple): Input tuple.\n input_dict (dict): Input dictionary to be added to the tuple.\n \n Returns:\n tuple: A new tuple containing the input tuple and dictionary.\n \"\"\"\n return input_tuple + (input_dict,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(existing_tuple, dictionary):\n \"\"\"\n Adds a dictionary to the end of the existing tuple.\n\n Args:\n existing_tuple (tuple): The existing tuple to add the dictionary to.\n dictionary (dict): The dictionary to be added.\n\n Returns:\n tuple: The resulting tuple with the dictionary appended.\n \"\"\"\n # Convert the existing tuple to a list to allow appending the dictionary\n list_form = list(existing_tuple)\n # Append the dictionary to the list\n list_form.append(dictionary)\n # Convert the list back to a tuple\n result = tuple(list_form)\n return result", "matching_cluster_idx": 3}, {"solution": "def add_dict_to_tuple(original_tuple, dictionary):\n \"\"\"\n This function takes a tuple and a dictionary as input, then returns a new tuple\n that contains all elements of the original tuple followed by the dictionary.\n\n Args:\n original_tuple (tuple): The original tuple to be modified.\n dictionary (dict): The dictionary to be added to the tuple.\n\n Returns:\n tuple: A new tuple with the dictionary at the end.\n \"\"\"\n return original_tuple + (dictionary,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(tup, dict):\n \"\"\"\n Adds a dictionary to a tuple.\n\n Args:\n tup (tuple): The input tuple.\n dict (dict): The input dictionary.\n\n Returns:\n tuple: A new tuple containing the input tuple and dictionary.\n \"\"\"\n return tup + (dict,)", "matching_cluster_idx": 4}]}, "Mbpp/725": {"dps": 68.16939890710383, "dps_norm": 66.875, "pass@1": 42.0, "profiled": [{"solution": "import re\ndef extract_quotation(s):\n \"\"\"\n Extract values between quotation marks \" \" in a string.\n\n Args:\n s (str): The input string.\n\n Returns:\n list: A list of extracted values between quotation marks.\n\n \"\"\"\n return re.findall(r'\"(.*?)\"', s)", "matching_cluster_idx": 5}, {"solution": "def extract_quotation(s):\n \"\"\"\n This function takes a string as input and returns a list of values \n that are enclosed within quotation marks.\n \n Parameters:\n s (str): The input string to extract values from.\n \n Returns:\n list: A list of extracted values between quotation marks.\n \"\"\"\n # Initialize an empty list to store the extracted values\n extracted_values = []\n \n # Use a flag to track whether we are currently inside a quotation mark\n in_quotation = False\n \n # Initialize an empty string to build the current value\n current_value = \"\"\n \n # Iterate over each character in the string\n for char in s:\n # If the character is a quotation mark and we are not inside a quotation mark\n if char == '\"' and not in_quotation:\n # Set the flag to True\n in_quotation = True\n # If the character is a quotation mark and we are inside a quotation mark\n elif char == '\"' and in_quotation:\n # Set the flag to False and append the current value to the list\n in_quotation = False\n extracted_values.append(current_value)\n current_value = \"\"\n # If we are inside a quotation mark\n elif in_quotation:\n # Add the character to the current value\n current_value += char\n \n return extracted_values", "matching_cluster_idx": 1}, {"solution": "import re\ndef extract_quotation(s):\n \"\"\"\n Extracts values between quotation marks \" \" of the given string.\n \n Args:\n s (str): The string from which to extract the values.\n \n Returns:\n list: A list of values between quotation marks.\n \"\"\"\n return re.findall(r'\"(.*?)\"', s)", "matching_cluster_idx": 5}, {"solution": "def extract_quotation(s):\n \"\"\"\n Extract values between quotation marks \" \" from the given string.\n\n Args:\n s (str): The input string.\n\n Returns:\n list: A list of values extracted between quotation marks.\n \"\"\"\n result = []\n current_quotation = \"\"\n is_inside_quotation = False\n\n for char in s:\n if char == '\"':\n if is_inside_quotation:\n result.append(current_quotation.strip('\"'))\n current_quotation = \"\"\n is_inside_quotation = False\n else:\n is_inside_quotation = True\n elif is_inside_quotation:\n current_quotation += char\n\n return result", "matching_cluster_idx": 2}, {"solution": "def extract_quotation(s):\n \"\"\"\n Extracts values between quotation marks \" \" of the given string.\n \n Args:\n s (str): The input string.\n \n Returns:\n list: A list of values between quotation marks.\n \"\"\"\n result = []\n current_quote = \"\"\n in_quote = False\n \n for char in s:\n if char == '\"':\n in_quote = not in_quote\n if in_quote:\n current_quote = \"\"\n else:\n result.append(current_quote)\n elif in_quote:\n current_quote += char\n \n return result", "matching_cluster_idx": 2}, {"solution": "def extract_quotation(s):\n \"\"\"\n This function extracts values between quotation marks \" \" from a given string.\n\n Parameters:\n s (str): The input string that contains quoted values.\n\n Returns:\n list: A list of extracted values.\n\n Example:\n >>> extract_quotation('Cortex \"A53\" Based \"multi\" tasking \"Processor\"')\n ['A53', 'multi', 'Processor']\n \"\"\"\n\n # Find all substrings between quotation marks using regular expression\n import re\n\n # Pattern to find quotation marks and extract their content\n pattern = r'\"([^\"]*)\"'\n\n # Extract all matches\n matches = re.findall(pattern, s)\n\n return matches", "matching_cluster_idx": 5}, {"solution": "def extract_quotation(s):\n \"\"\"\n Extract values between quotation marks \" \" from a given string.\n\n Args:\n s (str): The input string that may contain values between quotation marks.\n\n Returns:\n list: A list of extracted values between quotation marks.\n \"\"\"\n quotations = []\n current_quotation = ''\n in_quotation = False\n \n for char in s:\n if char == '\"':\n if in_quotation:\n quotations.append(current_quotation)\n current_quotation = ''\n in_quotation = False\n else:\n in_quotation = True\n elif in_quotation:\n current_quotation += char\n \n return quotations", "matching_cluster_idx": 2}, {"solution": "def extract_quotation(s):\n \"\"\"\n Extract values between quotation marks \" \" of the given string.\n \n Parameters:\n s (str): The input string.\n \n Returns:\n list: A list of strings between quotation marks.\n \"\"\"\n import re\n return re.findall(r'\"([^\"]*)\"', s)", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(s):\n \"\"\"\n This function extracts values between quotation marks \" \" of the given string.\n\n Args:\n s (str): The input string from which to extract values between quotation marks.\n\n Returns:\n list: A list of extracted strings.\n\n \"\"\"\n # Use regular expression to find all substrings enclosed in double quotes\n matches = re.findall(r'\"(.*?)\"', s)\n \n return matches", "matching_cluster_idx": 4}, {"solution": "import re\ndef extract_quotation(s):\n \"\"\"\n Extract values between quotation marks from the given string.\n\n Args:\n s (str): The input string.\n\n Returns:\n list: A list of extracted values between quotation marks.\n \"\"\"\n return re.findall(r'\"([^\"]*)\"', s)", "matching_cluster_idx": 5}, {"solution": "def extract_quotation(s):\n \"\"\"\n Extract values between quotation marks from a given string.\n\n Args:\n s (str): The input string containing quotation marks.\n\n Returns:\n list: A list of substrings between quotation marks.\n\n \"\"\"\n result = []\n current_quotation = False\n current_value = ''\n\n for char in s:\n if char == '\"':\n if not current_quotation:\n current_quotation = True\n else:\n result.append(current_value)\n current_quotation = False\n current_value = ''\n elif current_quotation:\n current_value += char\n\n return result", "matching_cluster_idx": 2}, {"solution": "def extract_quotation(s):\n \"\"\"\n This function extracts values between quotation marks \" \" from the given string.\n \n Parameters:\n s (str): Input string containing values in quotation marks.\n \n Returns:\n list: A list of strings extracted from the input string.\n \"\"\"\n import re\n return re.findall(r'\"([^\"]*)\"', s)", "matching_cluster_idx": 6}, {"solution": "import re\ndef extract_quotation(s):\n \"\"\"\n Extract values between quotation marks \" \" of the given string.\n \n Args:\n s (str): The input string that may contain values within quotation marks.\n \n Returns:\n list: A list of strings extracted from the input string between quotation marks.\n \"\"\"\n return re.findall(r'\"([^\"]*)\"', s)", "matching_cluster_idx": 6}, {"solution": "import re\ndef extract_quotation(s):\n \"\"\"\n Extract values between quotation marks \" \" from a given string.\n \n Parameters:\n s (str): The input string.\n \n Returns:\n list: A list of strings between quotation marks.\n \"\"\"\n # Use regular expression to find all substrings enclosed within quotation marks\n pattern = r'\"([^\"]*)\"'\n return re.findall(pattern, s)", "matching_cluster_idx": 6}, {"solution": "import re\ndef extract_quotation(s):\n \"\"\"\n Extract values between quotation marks of the given string.\n \n Args:\n s (str): The string to extract values from.\n \n Returns:\n list: A list of extracted values.\n \"\"\"\n return re.findall(r'\"([^\"]*)\"', s)", "matching_cluster_idx": 6}, {"solution": "def extract_quotation(s):\n \"\"\"\n Extracts values between quotation marks \" \" of the given string.\n\n Args:\n s (str): Input string\n\n Returns:\n list: List of values between quotation marks\n \"\"\"\n import re\n # Regular expression to match any characters within double quotes\n pattern = r'\"([^\"]*)\"'\n # Find all matches of the pattern in the string\n matches = re.findall(pattern, s)\n return matches", "matching_cluster_idx": 6}, {"solution": "def extract_quotation(s):\n \"\"\"\n This function extracts the values between the quotation marks in a given string.\n\n Args:\n s (str): The input string.\n\n Returns:\n list: A list of substrings enclosed within quotation marks.\n\n \"\"\"\n # Use regular expression to find all substrings enclosed within quotation marks\n import re\n return re.findall(r'\"([^\"]*)\"', s)", "matching_cluster_idx": 6}, {"solution": "def extract_quotation(s):\n \"\"\"\n This function extracts values between quotation marks \" \" of the given string.\n\n Args:\n s (str): The input string from which to extract quotation marks.\n\n Returns:\n list: A list of strings between quotation marks.\n\n \"\"\"\n # Using regular expression to find all substrings between quotation marks\n import re\n return re.findall(r'\"(.*?)\"', s)", "matching_cluster_idx": 5}, {"solution": "def extract_quotation(s):\n \"\"\"\n Extract values between quotation marks of the given string.\n \n Args:\n s (str): Input string containing values between quotation marks.\n \n Returns:\n list: List of values extracted from between quotation marks.\n \"\"\"\n quotations = []\n temp = ''\n \n # Initialize flag to track if we are currently inside a quotation\n in_quotation = False\n \n for char in s:\n if char == '\"':\n # If we encounter a closing quotation, add the current temp string and reset\n if in_quotation:\n quotations.append(temp)\n temp = ''\n in_quotation = False\n # If we encounter an opening quotation, start a new temp string and flag\n else:\n in_quotation = True\n # If we are inside a quotation and encounter a non-quotation character, add it to the temp string\n elif in_quotation:\n temp += char\n \n return quotations", "matching_cluster_idx": 2}, {"solution": "def extract_quotation(s):\n \"\"\"\n This function extracts values between quotation marks from a given string.\n \n Args:\n s (str): Input string containing values between quotation marks.\n \n Returns:\n list: A list of values extracted between quotation marks.\n \"\"\"\n import re\n return re.findall(r'\"([^\"]*)\"', s)", "matching_cluster_idx": 6}]}, "Mbpp/732": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 73.0, "profiled": [{"solution": "def replace_specialchar(input_str):\n \"\"\"\n This function replaces all occurrences of spaces, commas, or dots with a colon.\n\n Parameters:\n input_str (str): The input string that may contain spaces, commas, or dots.\n\n Returns:\n str: The input string with all spaces, commas, and dots replaced by colons.\n \"\"\"\n # Replace all occurrences of spaces, commas, or dots with a colon\n result_str = input_str.replace(' ', ':').replace(',', ':').replace('.', ':')\n return result_str", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(s):\n \"\"\"\n Replaces all occurrences of spaces, commas, or dots in a string with a colon.\n\n Args:\n s (str): The input string to be modified.\n\n Returns:\n str: The modified string with spaces, commas, or dots replaced with colons.\n \"\"\"\n return s.replace(' ', ':').replace(',', ':').replace('.', ':')", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(s):\n \"\"\"\n Replaces all occurrences of spaces, commas, or dots with a colon.\n \n Args:\n s (str): The input string to be modified.\n \n Returns:\n str: The modified string with spaces, commas, and dots replaced with colons.\n \"\"\"\n return s.replace(' ', ':').replace(',', ':').replace('.', ':')", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(s):\n \"\"\"\n This function replaces all occurrences of spaces, commas, or dots with a colon.\n \n Parameters:\n s (str): The input string that may contain spaces, commas, or dots.\n \n Returns:\n str: The input string with all spaces, commas, or dots replaced with a colon.\n \"\"\"\n return s.replace(' ', ':').replace(',', ':').replace('.', ':')", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(input_str):\n \"\"\"\n This function takes an input string and replaces all occurrences of spaces, commas, or dots with a colon.\n \n Args:\n input_str (str): The string in which special characters are to be replaced.\n \n Returns:\n str: The string with all spaces, commas, and dots replaced with a colon.\n \"\"\"\n return input_str.replace(\" \", \":\").replace(\",\", \":\").replace(\".\", \":\")", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(s):\n \"\"\"\n Replaces all occurrences of spaces, commas, or dots with a colon in a given string.\n \n Args:\n s (str): The input string.\n \n Returns:\n str: The modified string with replaced characters.\n \"\"\"\n return s.replace(' ', ':').replace(',', ':').replace('.', ':')", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(s):\n \"\"\"\n This function replaces all occurrences of spaces, commas, or dots in a given string with a colon.\n\n Args:\n s (str): The input string.\n\n Returns:\n str: The modified string with spaces, commas, or dots replaced with a colon.\n \"\"\"\n # Replace all occurrences of spaces, commas, or dots with a colon\n s = s.replace(\" \", \":\").replace(\",\", \":\").replace(\".\", \":\")\n \n # Return the modified string\n return s", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(s):\n \"\"\"\n Replaces all occurrences of spaces, commas, or dots with a colon in a given string.\n\n Args:\n s (str): The input string to modify.\n\n Returns:\n str: The modified string with all spaces, commas, or dots replaced with a colon.\n \"\"\"\n # Use the built-in string replace() method to replace spaces, commas, and dots with colons\n s = s.replace(' ', ':').replace(',', ':').replace('.', ':')\n return s", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(s):\n \"\"\"\n Replaces all occurrences of spaces, commas, or dots with a colon.\n \n Args:\n s (str): Input string.\n \n Returns:\n str: String with all spaces, commas, or dots replaced with a colon.\n \"\"\"\n return s.replace(' ', ':').replace(',', ':').replace('.', ':')", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(s):\n \"\"\"\n Replace all occurrences of spaces, commas, or dots in a string with a colon.\n\n Args:\n s (str): The input string.\n\n Returns:\n str: The modified string with spaces, commas, or dots replaced by colons.\n \"\"\"\n # Using the str.replace() method to replace all occurrences of spaces, commas, or dots with a colon\n return s.replace(' ', ':').replace(',', ':').replace('.', ':')", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(s):\n \"\"\"\n Replaces all occurrences of spaces, commas, or dots with a colon in a given string.\n \n Args:\n s (str): The input string.\n \n Returns:\n str: The string with spaces, commas, or dots replaced with a colon.\n \"\"\"\n return s.replace(' ', ':').replace(',', ':').replace('.', ':')", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(s):\n \"\"\"\n This function replaces all occurrences of spaces, commas, or dots with a colon.\n \n Parameters:\n s (str): The input string\n \n Returns:\n str: The modified string with spaces, commas, and dots replaced with a colon\n \"\"\"\n \n # Replace spaces, commas, and dots with a colon\n s = s.replace(' ', ':').replace(',', ':').replace('.', ':')\n \n return s", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(s):\n \"\"\"\n Replaces all occurrences of spaces, commas, or dots with a colon in a given string.\n \n Parameters:\n s (str): The input string.\n \n Returns:\n str: The input string with all spaces, commas, or dots replaced with a colon.\n \"\"\"\n return s.replace(' ', ':').replace(',', ':').replace('.', ':')", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(s):\n \"\"\"\n Replaces all occurrences of spaces, commas, or dots with a colon.\n\n Args:\n s (str): The input string.\n\n Returns:\n str: The modified string with spaces, commas, and dots replaced with a colon.\n \"\"\"\n return s.replace(' ', ':').replace(',', ':').replace('.', ':')", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(s):\n \"\"\"\n Replaces all occurrences of spaces, commas, or dots with a colon.\n\n Args:\n s (str): The input string.\n\n Returns:\n str: The modified string with spaces, commas, or dots replaced with a colon.\n \"\"\"\n return s.replace(' ', ':').replace(',', ':').replace('.', ':')", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(s):\n \"\"\"\n Replaces all occurrences of spaces, commas, or dots with a colon.\n \n Args:\n s (str): Input string containing spaces, commas, or dots.\n \n Returns:\n str: Input string with all spaces, commas, or dots replaced with a colon.\n \"\"\"\n return s.replace(\" \", \":\").replace(\",\", \":\").replace(\".\", \":\")", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(s):\n \"\"\"\n Replace all occurrences of spaces, commas, or dots with a colon in a given string.\n \n Args:\n s (str): Input string\n \n Returns:\n str: The modified string with spaces, commas, or dots replaced with colons\n \"\"\"\n return s.replace(' ', ':').replace(',', ':').replace('.', ':')", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(text):\n \"\"\"\n This function replaces all occurrences of spaces, commas, or dots with a colon in a given text.\n \n Args:\n text (str): The input text to be processed.\n \n Returns:\n str: The text with all spaces, commas, or dots replaced with a colon.\n \"\"\"\n text = text.replace(' ', ':').replace(',', ':').replace('.', ':')\n return text", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(s):\n \"\"\"\n Replace all occurrences of spaces, commas, or dots with a colon.\n\n Args:\n s (str): The input string.\n\n Returns:\n str: The modified string.\n \"\"\"\n return s.replace(' ', ':').replace(',', ':').replace('.', ':')", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(text):\n \"\"\"\n Replaces all occurrences of spaces, commas, and dots in the input text with colons.\n\n Args:\n text (str): The input text.\n\n Returns:\n str: The modified text with replaced characters.\n \"\"\"\n return text.replace(' ', ':').replace(',', ':').replace('.', ':')", "matching_cluster_idx": 9}]}, "Mbpp/740": {"dps": 77.58181818181818, "dps_norm": 66.11111111111111, "pass@1": 86.0, "profiled": [{"solution": "def tuple_to_dict(t):\n \"\"\"\n Convert a given tuple to a key-value dictionary using adjacent elements.\n \n Args:\n t (tuple): Input tuple containing alternating key-value pairs.\n \n Returns:\n dict: A dictionary with keys as the first elements in the tuple and values as the second elements.\n \"\"\"\n if len(t) % 2 != 0:\n raise ValueError(\"Input tuple must have an even number of elements\")\n \n return {t[i]: t[i+1] for i in range(0, len(t), 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(t):\n \"\"\"\n Converts the given tuple to a key-value dictionary using adjacent elements.\n \n Parameters:\n t (tuple): A tuple where each pair of adjacent elements forms a key-value pair in the resulting dictionary.\n \n Returns:\n dict: A dictionary with keys as the first element of each pair and values as the second element of each pair.\n \"\"\"\n # Check if the tuple has an odd number of elements\n if len(t) % 2 != 0:\n raise ValueError(\"Tuple must have an even number of elements\")\n \n # Initialize an empty dictionary\n result = {}\n \n # Iterate over the tuple, adding key-value pairs to the dictionary\n for i in range(0, len(t), 2):\n # Check if we're at the last iteration, where t[i] is a key without a value\n if i + 1 == len(t):\n raise ValueError(\"Each key must have a value\")\n \n result[t[i]] = t[i + 1]\n \n return result", "matching_cluster_idx": 3}, {"solution": "def tuple_to_dict(t):\n \"\"\"\n Convert a tuple to a key-value dictionary using adjacent elements.\n\n Args:\n t (tuple): Input tuple.\n\n Returns:\n dict: A dictionary where each element in the tuple is a key\n and the next element is the corresponding value.\n\n Example:\n >>> tuple_to_dict((1, 5, 7, 10, 13, 5))\n {1: 5, 7: 10, 13: 5}\n \"\"\"\n # Initialize an empty dictionary\n result = {}\n # Loop over the input tuple with a step of 2\n for i in range(0, len(t) - 1, 2):\n # Add each element as a key and the next one as the value to the dictionary\n result[t[i]] = t[i + 1]\n # If the tuple has an odd number of elements, the last element will be without a pair\n # This line adds it to the dictionary with a value of None\n if len(t) % 2 != 0:\n result[t[-1]] = None\n return result", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(t):\n \"\"\"\n This function converts a given tuple to a key-value dictionary \n using adjacent elements. The first element in a pair is the key \n and the second element is the value.\n \n Parameters:\n t (tuple): A tuple containing elements to be converted into a dictionary\n \n Returns:\n dict: A dictionary created from the given tuple\n \"\"\"\n if len(t) % 2 != 0:\n raise ValueError(\"Tuple length must be even\")\n \n return {t[i]: t[i+1] for i in range(0, len(t), 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(t):\n \"\"\"\n This function converts a given tuple to a key-value dictionary where \n each adjacent elements in the tuple are a key-value pair in the dictionary.\n\n Args:\n t (tuple): A tuple of elements, where each pair of adjacent elements is \n considered as a key-value pair.\n\n Returns:\n dict: A dictionary where each key-value pair is obtained from the input tuple.\n\n Raises:\n ValueError: If the tuple has odd number of elements.\n \"\"\"\n if len(t) % 2 != 0:\n raise ValueError(\"Tuple must have even number of elements\")\n \n return {t[i]: t[i + 1] for i in range(0, len(t), 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(tup):\n \"\"\"\n Convert a given tuple of values to a key-value dictionary using adjacent elements.\n\n Args:\n tup (tuple): A tuple with an even number of elements.\n\n Returns:\n dict: A dictionary with adjacent elements from the tuple as key-value pairs.\n \"\"\"\n return dict(zip(tup[::2], tup[1::2]))", "matching_cluster_idx": 8}, {"solution": "def tuple_to_dict(input_tuple):\n \"\"\"\n Convert a tuple to a key-value dictionary using adjacent elements.\n\n Args:\n input_tuple (tuple): A tuple of numbers.\n\n Returns:\n dict: A dictionary with adjacent elements as key-value pairs.\n\n Example:\n >>> tuple_to_dict((1, 5, 7, 10, 13, 5))\n {1: 5, 7: 10, 13: 5}\n \"\"\"\n\n # Initialize an empty dictionary\n result = {}\n\n # Check if the input tuple has at least two elements\n if len(input_tuple) >= 2:\n # Add each key-value pair to the dictionary\n for i in range(0, len(input_tuple) - 1, 2):\n result[input_tuple[i]] = input_tuple[i + 1]\n\n return result", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(t):\n \"\"\"\n Converts a given tuple to a key-value dictionary using adjacent elements.\n\n Args:\n t (tuple): A tuple with an even number of elements.\n\n Returns:\n dict: A dictionary where the first element of each pair of elements in the tuple is a key, \n and the second element is the corresponding value.\n\n Raises:\n ValueError: If the tuple has an odd number of elements.\n \"\"\"\n if len(t) % 2 != 0:\n raise ValueError(\"Input tuple must have an even number of elements.\")\n\n return {t[i]: t[i + 1] for i in range(0, len(t) - 1, 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(t):\n \"\"\"\n Converts a tuple into a dictionary using adjacent elements.\n\n Args:\n t (tuple): Input tuple with alternating keys and values.\n\n Returns:\n dict: Dictionary containing elements from the input tuple.\n \"\"\"\n return {t[i]: t[i+1] for i in range(0, len(t), 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(tup):\n \"\"\"\n Convert a tuple into a key-value dictionary using adjacent elements.\n \n Parameters:\n tup (tuple): Input tuple containing key-value pairs.\n \n Returns:\n dict: A dictionary with keys and values from the input tuple.\n \n Example:\n >>> tuple_to_dict((1, 5, 7, 10, 13, 5))\n {1: 5, 7: 10, 13: 5}\n \"\"\"\n return {tup[i]: tup[i + 1] for i in range(0, len(tup) - 1, 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(t):\n \"\"\"\n Convert a given tuple to a key-value dictionary using adjacent elements.\n \n Args:\n t (tuple): Input tuple with key-value pairs.\n \n Returns:\n dict: Dictionary formed using key-value pairs from the tuple.\n \"\"\"\n \n # Check if the tuple has an odd number of elements\n if len(t) % 2 != 0:\n raise ValueError(\"Tuple must have an even number of elements\")\n \n # Use list comprehension to create a dictionary\n return {t[i]: t[i + 1] for i in range(0, len(t), 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(tuple):\n \"\"\"\n This function takes a tuple as input and returns a dictionary where \n each element in the tuple is a key and the following element is its value.\n\n Args:\n tuple (tuple): A tuple with an even number of elements.\n\n Returns:\n dict: A dictionary with keys and values from the input tuple.\n \"\"\"\n # Initialize an empty dictionary to store the result\n result = {}\n\n # Check if the tuple has at least one element\n if len(tuple) > 0:\n # Loop over the tuple with a step of 2 to consider each element and its next one\n for i in range(0, len(tuple), 2):\n # Check if the current element is not the last one in the tuple\n if i < len(tuple) - 1:\n # Add the current element as a key and the next one as its value to the dictionary\n result[tuple[i]] = tuple[i + 1]\n\n return result", "matching_cluster_idx": 3}, {"solution": "def tuple_to_dict(tup):\n \"\"\"\n Convert a tuple with an odd number of elements into a key-value dictionary.\n Each key is the corresponding odd index element, and each value is the\n corresponding even index element.\n\n Args:\n tup (tuple): Input tuple with an odd number of elements\n\n Returns:\n dict: A dictionary with elements from the input tuple\n \"\"\"\n return {tup[i]: tup[i+1] for i in range(0, len(tup), 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(tup):\n \"\"\"\n Convert a tuple with adjacent elements into a dictionary.\n \n Args:\n tup (tuple): The input tuple.\n \n Returns:\n dict: A dictionary with key-value pairs constructed from adjacent elements in the tuple.\n \"\"\"\n return {tup[i]: tup[i + 1] for i in range(0, len(tup) - 1, 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(tup):\n \"\"\"\n Converts a tuple to a dictionary using adjacent elements.\n \n Args:\n tup (tuple): The input tuple.\n \n Returns:\n dict: A dictionary where each element in the tuple is a key and the next element is its corresponding value.\n \n Example:\n >>> tuple_to_dict((1, 5, 7, 10, 13, 5))\n {1: 5, 7: 10, 13: 5}\n \"\"\"\n # Check if the tuple length is an odd number.\n if len(tup) % 2 != 0:\n raise ValueError(\"Input tuple must have an even number of elements\")\n \n # Initialize an empty dictionary\n result = {}\n \n # Iterate over the tuple in steps of 2.\n for i in range(0, len(tup) - 1, 2):\n # Add each pair of elements to the dictionary.\n result[tup[i]] = tup[i+1]\n \n return result", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(input_tuple):\n \"\"\"\n This function converts the given tuple to a key-value dictionary using adjacent elements.\n\n Args:\n input_tuple (tuple): Input tuple where each element is adjacent pair of keys and values.\n\n Returns:\n dict: Dictionary where keys are the elements from the input tuple at odd indices and values are the elements at even indices.\n\n Raises:\n ValueError: If the tuple has an odd length.\n \"\"\"\n # Check if the tuple has an odd length\n if len(input_tuple) % 2 != 0:\n raise ValueError(\"The tuple must have an even length.\")\n\n # Use dictionary comprehension to create the dictionary\n return {input_tuple[i]: input_tuple[i+1] for i in range(0, len(input_tuple), 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(t):\n \"\"\"\n This function converts a given tuple to a key-value dictionary using adjacent elements.\n \n Args:\n t (tuple): The input tuple containing adjacent elements to be converted to dictionary.\n \n Returns:\n dict: A dictionary with the first element of each pair as key and the second element as value.\n \"\"\"\n return {t[i]: t[i+1] for i in range(0, len(t) - 1, 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(t):\n \"\"\"\n Convert a given tuple into a dictionary using adjacent elements.\n\n Args:\n t (tuple): Input tuple of values\n\n Returns:\n dict: A dictionary with adjacent elements in the tuple as keys and values\n \"\"\"\n return {t[i]: t[i + 1] for i in range(0, len(t), 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(tuple):\n \"\"\"\n Convert a tuple to a key-value dictionary using adjacent elements.\n \n Args:\n tuple (tuple): A tuple of values to be converted into a dictionary.\n \n Returns:\n dict: A dictionary with elements from the tuple as key-value pairs.\n \"\"\"\n return {tuple[i]: tuple[i + 1] for i in range(0, len(tuple) - 1, 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(input_tuple):\n \"\"\"\n Convert a tuple to a key-value dictionary using adjacent elements.\n \n Args:\n input_tuple (tuple): A tuple with keys and values.\n\n Returns:\n dict: A dictionary where the elements of the tuple are used as keys and values.\n \"\"\"\n # Initialize an empty dictionary\n result = {}\n \n # Loop through the tuple from the start\n for i in range(0, len(input_tuple) - 1, 2):\n # For each pair of adjacent elements, add the first element as the key and the second as the value\n result[input_tuple[i]] = input_tuple[i + 1]\n \n # Return the resulting dictionary\n return result", "matching_cluster_idx": 5}]}, "Mbpp/744": {"dps": 57.97945205479452, "dps_norm": 65.83333333333333, "pass@1": 84.0, "profiled": [{"solution": "def check_none(tup):\n \"\"\"\n This function checks if a given tuple contains any None value.\n \n Args:\n tup (tuple): The input tuple to be checked.\n \n Returns:\n bool: True if the tuple contains None, False otherwise.\n \"\"\"\n return None in tup", "matching_cluster_idx": 5}, {"solution": "def check_none(tup):\n \"\"\"\n This function checks if a given tuple contains any None values.\n\n Args:\n tup (tuple): Input tuple to be checked.\n\n Returns:\n bool: True if the tuple contains any None values, False otherwise.\n \"\"\"\n # Use the built-in any() function with generator expression to check for None\n return any(value is None for value in tup)", "matching_cluster_idx": 2}, {"solution": "def check_none(input_tuple):\n \"\"\"\n Checks if the given tuple has any None value.\n\n Args:\n input_tuple (tuple): Input tuple to check.\n\n Returns:\n bool: True if tuple has any None value, False otherwise.\n \"\"\"\n return any(t == None for t in input_tuple)", "matching_cluster_idx": 1}, {"solution": "def check_none(t):\n \"\"\"\n Checks if the given tuple has any None value or not.\n\n Args:\n t (tuple): The input tuple to be checked.\n\n Returns:\n bool: True if the tuple contains None, False otherwise.\n \"\"\"\n return any(t) and None in t", "matching_cluster_idx": 4}, {"solution": "def check_none(tup):\n \"\"\"\n Check if a given tuple has any None values.\n\n Args:\n tup (tuple): Input tuple to check.\n\n Returns:\n bool: True if the tuple contains None, False otherwise.\n \"\"\"\n return None in tup", "matching_cluster_idx": 5}, {"solution": "def check_none(t):\n \"\"\"\n This function checks if any of the elements in the given tuple are None.\n\n Args:\n t (tuple): The input tuple to be checked.\n\n Returns:\n bool: True if the tuple contains any None value, False otherwise.\n \"\"\"\n return any(i is None for i in t)", "matching_cluster_idx": 1}, {"solution": "def check_none(tup):\n \"\"\"\n Checks if a given tuple contains any None value.\n\n Args:\n tup (tuple): Input tuple to check.\n\n Returns:\n bool: True if tuple contains None, False otherwise.\n \"\"\"\n return None in tup", "matching_cluster_idx": 5}, {"solution": "def check_none(tuple):\n \"\"\"\n This function checks if the given tuple has any 'None' value or not.\n\n Args:\n tuple (tuple): The input tuple to be checked.\n\n Returns:\n bool: True if the tuple contains 'None', False otherwise.\n \"\"\"\n return None in tuple", "matching_cluster_idx": 5}, {"solution": "def check_none(input_tuple):\n \"\"\"\n Checks if a given tuple contains None.\n\n Args:\n input_tuple (tuple): The tuple to check.\n\n Returns:\n bool: True if the tuple contains None, False otherwise.\n \"\"\"\n return None in input_tuple", "matching_cluster_idx": 5}, {"solution": "def check_none(tup):\n \"\"\"\n This function checks if the given tuple contains any None value.\n \n Args:\n tup (tuple): The input tuple to check.\n \n Returns:\n bool: True if the tuple contains None, False otherwise.\n \"\"\"\n return any(item is None for item in tup)", "matching_cluster_idx": 2}, {"solution": "def check_none(tup):\n \"\"\"\n Checks if a given tuple contains any None value.\n\n Args:\n tup (tuple): The input tuple to check.\n\n Returns:\n bool: True if the tuple contains None, False otherwise.\n \"\"\"\n return any(isinstance(x, type(None)) for x in tup)", "matching_cluster_idx": -1}, {"solution": "def check_none(tup):\n \"\"\"\n Check if a given tuple has any None value or not.\n\n Args:\n tup (tuple): Input tuple to be checked.\n\n Returns:\n bool: True if the tuple contains None, False otherwise.\n \"\"\"\n return any(value is None for value in tup)", "matching_cluster_idx": 2}, {"solution": "def check_none(tup):\n \"\"\"\n Check if the given tuple has any None value.\n \n Args:\n tup (tuple): The input tuple to be checked.\n \n Returns:\n bool: True if the tuple contains None, False otherwise.\n \"\"\"\n return None in tup", "matching_cluster_idx": 5}, {"solution": "def check_none(t):\n \"\"\"\n This function checks if a tuple contains any None value.\n\n Args:\n t (tuple): Input tuple to be checked.\n\n Returns:\n bool: True if tuple contains None, False otherwise.\n \"\"\"\n return any(value is None for value in t)", "matching_cluster_idx": 2}, {"solution": "def check_none(t):\n \"\"\"\n Checks if the given tuple has any None value.\n \n Args:\n t (tuple): The input tuple to check.\n \n Returns:\n bool: True if the tuple contains any None, False otherwise.\n \"\"\"\n return None in t", "matching_cluster_idx": 5}, {"solution": "def check_none(t):\n \"\"\"\n Checks if a given tuple contains any None value.\n\n Args:\n t (tuple): The input tuple to be checked.\n\n Returns:\n bool: True if the tuple contains None, False otherwise.\n \"\"\"\n return any(t) and None in t", "matching_cluster_idx": 4}, {"solution": "def check_none(tup):\n \"\"\"\n This function checks if any element in the given tuple is None.\n\n Args:\n tup (tuple): The input tuple to be checked.\n\n Returns:\n bool: True if the tuple contains a None value, False otherwise.\n \"\"\"\n return None in tup", "matching_cluster_idx": 5}, {"solution": "def check_none(tup):\n \"\"\"\n Checks if the given tuple contains any None value.\n\n Args:\n tup (tuple): The input tuple to check for None values.\n\n Returns:\n bool: True if the tuple contains None, False otherwise.\n \"\"\"\n return any(isinstance(item, type(None)) for item in tup)", "matching_cluster_idx": -1}, {"solution": "def check_none(tup):\n \"\"\"\n Checks if a tuple contains any None value.\n\n Args:\n tup (tuple): The tuple to be checked.\n\n Returns:\n bool: True if the tuple contains any None value, False otherwise.\n \"\"\"\n return any(tup) and None in tup", "matching_cluster_idx": 4}, {"solution": "def check_none(tup):\n \"\"\"\n Checks if a given tuple contains any None value.\n \n Args:\n tup (tuple): The tuple to check.\n \n Returns:\n bool: True if the tuple contains None, False otherwise.\n \"\"\"\n return any(isinstance(x, type(None)) for x in tup)", "matching_cluster_idx": -1}]}, "Mbpp/750": {"dps": 76.59863945578232, "dps_norm": 76.66666666666667, "pass@1": 99.0, "profiled": [{"solution": "def add_tuple(input_list, input_tuple):\n \"\"\"\n Adds a given tuple to the given list.\n\n Args:\n input_list (list): The list to add the tuple to.\n input_tuple (tuple): The tuple to add to the list.\n\n Returns:\n list: The updated list with the tuple added.\n\n \"\"\"\n # Check if the input is of the correct type\n if not isinstance(input_list, list) or not isinstance(input_tuple, tuple):\n raise TypeError(\"Input must be a list and a tuple\")\n\n # Use the extend method to add all elements of the tuple to the list\n input_list.extend(input_tuple)\n\n return input_list", "matching_cluster_idx": 5}, {"solution": "def add_tuple(lst, tup):\n \"\"\"\n Adds the given tuple to the given list.\n\n Args:\n lst (list): The list to add to.\n tup (tuple): The tuple to add.\n\n Returns:\n list: The updated list with the tuple added.\n \"\"\"\n return lst + list(tup)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(lst, tpl):\n \"\"\"\n This function adds the elements from a given tuple to a list.\n\n Args:\n lst (list): The initial list.\n tpl (tuple): The tuple to be added to the list.\n\n Returns:\n list: The updated list with elements from the tuple added to it.\n \"\"\"\n return lst + list(tpl)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(lst, tup):\n \"\"\"\n This function adds the elements of a given tuple to the given list.\n \n Args:\n lst (list): The list to which the tuple's elements will be added.\n tup (tuple): The tuple whose elements will be added to the list.\n \n Returns:\n list: The list with the tuple's elements added to it.\n \"\"\"\n # Extend the list by unpacking the tuple into it\n lst.extend(tup)\n # Return the updated list\n return lst", "matching_cluster_idx": 5}, {"solution": "def add_tuple(lst, tup):\n \"\"\"\n Adds the elements of a tuple to a list.\n\n Args:\n lst (list): The original list.\n tup (tuple): The tuple to be added to the list.\n\n Returns:\n list: The list with the elements from the tuple added.\n \"\"\"\n return lst + list(tup)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(lst, tup):\n \"\"\"\n Adds the given tuple to the given list.\n \n Args:\n lst (list): The list to which the tuple is added.\n tup (tuple): The tuple to be added to the list.\n \n Returns:\n list: The list with the tuple added.\n \"\"\"\n # Extend the list with the tuple\n lst.extend(tup)\n \n # Return the updated list\n return lst", "matching_cluster_idx": 5}, {"solution": "def add_tuple(lst, tup):\n \"\"\"\n This function adds a given tuple to a given list.\n \n Args:\n lst (list): The list to which the tuple will be added.\n tup (tuple): The tuple to be added to the list.\n \n Returns:\n list: The updated list with the tuple added to it.\n \"\"\"\n # Check if the input is a list and a tuple\n if not isinstance(lst, list) or not isinstance(tup, tuple):\n raise TypeError(\"Error: Input list or tuple is not of the correct type.\")\n \n # Add the tuple to the list\n lst.extend(tup)\n \n # Return the updated list\n return lst", "matching_cluster_idx": 5}, {"solution": "def add_tuple(lst, tup):\n \"\"\"\n Add the given tuple to the given list.\n\n Args:\n lst (list): The list to which the tuple will be added.\n tup (tuple): The tuple to be added.\n\n Returns:\n list: The modified list with the tuple added.\n\n \"\"\"\n # Convert the tuple into a list\n tup_list = list(tup)\n \n # Add the list representation of the tuple to the given list\n lst.extend(tup_list)\n \n # Return the modified list\n return lst", "matching_cluster_idx": 3}, {"solution": "def add_tuple(lst, t):\n \"\"\"\n Adds the given tuple to the given list.\n\n Args:\n lst (list): The initial list.\n t (tuple): The tuple to add.\n\n Returns:\n list: The updated list with the tuple added.\n \"\"\"\n return lst + list(t)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(lst, tup):\n \"\"\"\n This function takes a list and a tuple as arguments. It returns a new list \n that contains all elements from the original list and the given tuple.\n \n Args:\n lst (list): The input list.\n tup (tuple): The input tuple to be added to the list.\n \n Returns:\n list: A new list containing elements from the input list and tuple.\n \"\"\"\n # Create a new list that contains all elements from the input list and the given tuple.\n new_list = lst + list(tup)\n \n return new_list", "matching_cluster_idx": 2}, {"solution": "def add_tuple(t, tup):\n \"\"\"\n Adds the given tuple to the given list.\n\n Args:\n t (list): The list to which the tuple will be added.\n tup (tuple): The tuple to be added to the list.\n\n Returns:\n list: The updated list.\n \"\"\"\n # Use the extend method to add elements of the tuple to the list\n t.extend(tup)\n return t", "matching_cluster_idx": 5}, {"solution": "def add_tuple(lst, tup):\n \"\"\"\n This function adds the given tuple to the given list.\n\n Args:\n lst (list): The list to add the tuple to.\n tup (tuple): The tuple to be added to the list.\n\n Returns:\n list: The updated list with the tuple added.\n\n Example:\n >>> add_tuple([5, 6, 7], (9, 10))\n [5, 6, 7, 9, 10]\n \"\"\"\n return lst + list(tup)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(lst, t):\n \"\"\"\n Adds the given tuple to the given list.\n\n Args:\n lst (list): The original list.\n t (tuple): The tuple to be added to the list.\n\n Returns:\n list: The list with the tuple added.\n \"\"\"\n # Convert the tuple into a list\n t = list(t)\n \n # Add the list representation of the tuple to the original list\n lst.extend(t)\n \n return lst", "matching_cluster_idx": 3}, {"solution": "def add_tuple(input_list, input_tuple):\n \"\"\"\n This function appends the elements of a given tuple to the end of a list.\n \n Args:\n input_list (list): A list of elements.\n input_tuple (tuple): A tuple of elements.\n \n Returns:\n list: The updated list with the tuple elements appended.\n \"\"\"\n return input_list + list(input_tuple)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(lst, tup):\n \"\"\"\n This function adds a given tuple to a given list.\n \n Args:\n lst (list): The list to which the tuple will be added.\n tup (tuple): The tuple to be added to the list.\n \n Returns:\n list: The list with the tuple added to it.\n \"\"\"\n # We use the extend method of the list to add the elements of the tuple to the list\n lst.extend(tup)\n \n # Finally, we return the updated list\n return lst", "matching_cluster_idx": 5}, {"solution": "def add_tuple(t, tup):\n \"\"\"\n Adds the given tuple to the given list.\n\n Args:\n t (list): The list to which the tuple will be added.\n tup (tuple): The tuple to be added.\n\n Returns:\n list: The list with the tuple added.\n \"\"\"\n # Check if the input list and tuple are of the correct type\n if not isinstance(t, list) or not isinstance(tup, tuple):\n raise TypeError(\"Input must be a list and a tuple\")\n \n # Use the extend method to add the tuple to the list\n t.extend(tup)\n \n return t", "matching_cluster_idx": 5}, {"solution": "def add_tuple(lst, tup):\n \"\"\"\n Appends the elements of the given tuple to the given list.\n \n Args:\n lst (list): The list to be extended with the tuple's elements.\n tup (tuple): The tuple whose elements will be added to the list.\n \n Returns:\n list: The list extended with the tuple's elements.\n \"\"\"\n lst.extend(tup)\n return lst", "matching_cluster_idx": 5}, {"solution": "def add_tuple(lst, tup):\n \"\"\"\n Adds the elements of the given tuple to the given list.\n\n Args:\n lst (list): The list to which elements will be added.\n tup (tuple): The tuple containing elements to be added to the list.\n\n Returns:\n list: The list with elements from the tuple added to it.\n \"\"\"\n # Extend the list with the elements of the tuple\n lst.extend(tup)\n return lst", "matching_cluster_idx": 5}, {"solution": "def add_tuple(lst, tup):\n \"\"\"\n Adds the given tuple to the given list.\n\n Args:\n lst (list): The list to be extended.\n tup (tuple): The tuple to be added.\n\n Returns:\n list: The extended list.\n \"\"\"\n return lst + list(tup)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(lst, tup):\n \"\"\"\n This function adds a tuple to a given list.\n\n Args:\n lst (list): The list to be extended.\n tup (tuple): The tuple to be added to the list.\n\n Returns:\n list: The extended list with the tuple added to it.\n \"\"\"\n # Use the extend method of the list to add all elements of the tuple to the list\n lst.extend(tup)\n return lst", "matching_cluster_idx": 5}]}, "Mbpp/753": {"dps": 97.31543624161074, "dps_norm": 75.0, "pass@1": 94.0, "profiled": [{"solution": "def min_k(records, k):\n \"\"\"\n This function finds the minimum k records from a list of tuples.\n \n Parameters:\n records (list): A list of tuples containing names and scores.\n k (int): The number of minimum records to find.\n \n Returns:\n list: A list of the k records with the lowest scores.\n \"\"\"\n # Sort the records based on their second element (score)\n sorted_records = sorted(records, key=lambda x: x[1])\n \n # Return the k records with the lowest scores\n return sorted_records[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(records, k):\n \"\"\"\n Finds the k minimum records from a list of tuples.\n \n Args:\n records (list): A list of tuples where each tuple contains a string and an integer.\n k (int): The number of minimum records to find.\n \n Returns:\n list: A list of tuples representing the k minimum records.\n \"\"\"\n # Sort the list of records based on the second element of each tuple\n sorted_records = sorted(records, key=lambda x: x[1])\n \n # Return the k minimum records\n return sorted_records[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(records, k):\n \"\"\"\n Returns the k minimum tuples from a given list of tuples.\n\n Args:\n records (list): A list of tuples containing a name and an integer score.\n k (int): The number of minimum tuples to return.\n\n Returns:\n list: A list of the k minimum tuples from the input list.\n \"\"\"\n # Use the built-in sorted function with a custom sorting key\n sorted_records = sorted(records, key=lambda x: x[1])\n \n # Return the k minimum tuples\n return sorted_records[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(records, k):\n \"\"\"\n This function finds the minimum k records from a given list of tuples.\n \n Args:\n records (list): A list of tuples, where each tuple contains a name and a score.\n k (int): The number of minimum records to find.\n\n Returns:\n list: A list of tuples representing the k records with the lowest scores.\n \"\"\"\n \n # First, we sort the list of records in ascending order based on the score\n sorted_records = sorted(records, key=lambda x: x[1])\n \n # Then, we return the first k elements from the sorted list\n return sorted_records[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(record_list, k):\n \"\"\"\n Returns the k records with the smallest value from a list of tuples.\n\n Args:\n record_list (list): A list of tuples, where each tuple contains a string and an integer.\n k (int): The number of records to return.\n\n Returns:\n list: A list of k tuples with the smallest value.\n \"\"\"\n # Sort the list in ascending order based on the integer value in each tuple\n sorted_list = sorted(record_list, key=lambda x: x[1])\n \n # Return the first k elements from the sorted list\n return sorted_list[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(records, k):\n \"\"\"\n Returns the minimum k records from the given tuple list.\n\n Args:\n records (list): A list of tuples, where each tuple contains a name and a score.\n k (int): The number of minimum records to return.\n\n Returns:\n list: A list of the k minimum records.\n\n \"\"\"\n return sorted(records, key=lambda x: x[1])[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(records, k):\n \"\"\"\n Returns the minimum k records from the given list of tuples.\n\n Args:\n records (list of tuples): A list of tuples where each tuple contains a name and a value.\n k (int): The number of minimum records to return.\n\n Returns:\n list of tuples: A list of the k minimum records.\n \"\"\"\n # Sort the list of records in ascending order based on the value\n sorted_records = sorted(records, key=lambda x: x[1])\n \n # Return the k minimum records\n return sorted_records[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(records, k):\n \"\"\"\n Returns the k smallest records from the given tuple list.\n \n Args:\n records (list): A list of tuples, where each tuple contains a string and an integer.\n k (int): The number of smallest records to return.\n \n Returns:\n list: A list of k tuples, each containing the smallest values.\n \"\"\"\n # Sort the records based on the integer value in each tuple\n sorted_records = sorted(records, key=lambda x: x[1])\n \n # Return the first k elements from the sorted list\n return sorted_records[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(records, k):\n \"\"\"\n This function returns the minimum k records from a tuple list, \n sorted by the second element in each tuple (value).\n\n Args:\n records (list): A list of tuples, where each tuple contains a name and a score.\n k (int): The number of records to return.\n\n Returns:\n list: A list of the k smallest records.\n \"\"\"\n return sorted(records, key=lambda x: x[1])[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(records, k):\n \"\"\"\n This function takes a list of tuples and an integer k as input.\n It returns a list of the k smallest tuples from the input list.\n\n Args:\n records (list): A list of tuples, where each tuple contains a name and a number.\n k (int): The number of smallest tuples to return.\n\n Returns:\n list: A list of the k smallest tuples from the input list.\n \"\"\"\n # Sort the records in ascending order based on the number in each tuple\n sorted_records = sorted(records, key=lambda x: x[1])\n \n # Return the k smallest records\n return sorted_records[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(records, k):\n \"\"\"\n This function takes a list of tuples and an integer k as input.\n It returns a list of k records with minimum scores.\n\n Args:\n records (list): A list of tuples containing names and scores.\n k (int): The number of records to return.\n\n Returns:\n list: A list of k records with minimum scores.\n \"\"\"\n # First, sort the records in ascending order based on the scores\n sorted_records = sorted(records, key=lambda x: x[1])\n \n # Select the records with the k smallest scores\n min_k_records = sorted_records[:k]\n \n return min_k_records", "matching_cluster_idx": 2}, {"solution": "def min_k(records, k):\n \"\"\"\n This function finds the minimum k records from a given list of tuples.\n\n Args:\n records (list): A list of tuples where each tuple contains a string and an integer.\n k (int): The number of minimum records to find.\n\n Returns:\n list: A list of k tuples representing the minimum records.\n\n Raises:\n ValueError: If k is greater than the length of records.\n \"\"\"\n if k > len(records):\n raise ValueError(\"k cannot be greater than the length of records\")\n\n return sorted(records, key=lambda x: x[1])[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(records, k):\n \"\"\"\n Returns the minimum k records from a list of tuples.\n\n Args:\n records (list): A list of tuples containing a name and a score.\n k (int): The number of minimum records to return.\n\n Returns:\n list: A list of the k minimum records.\n\n Example:\n >>> min_k([('Manjeet', 10), ('Akshat', 4), ('Akash', 2), ('Nikhil', 8)], 2)\n [('Akash', 2), ('Akshat', 4)]\n \"\"\"\n\n # Use the built-in sorted function to sort the records based on the score\n sorted_records = sorted(records, key=lambda x: x[1])\n\n # Use list slicing to get the k minimum records\n return sorted_records[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(records, k):\n \"\"\"\n Returns the minimum k records from a list of tuples.\n\n Args:\n records (list): A list of tuples, where each tuple contains a name and a score.\n k (int): The number of records to return.\n\n Returns:\n list: A list of the k minimum-scoring records.\n \"\"\"\n # Sort the records in ascending order based on the score\n sorted_records = sorted(records, key=lambda x: x[1])\n \n # Return the k minimum records\n return sorted_records[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(tuple_list, k):\n \"\"\"\n Returns the k smallest records from a list of tuples.\n\n Args:\n tuple_list (list): A list of tuples where each tuple contains a string and an integer.\n k (int): The number of smallest records to return.\n\n Returns:\n list: A list of k tuples sorted in ascending order based on the integer value in each tuple.\n \"\"\"\n # Sort the list of tuples in ascending order based on the integer value in each tuple\n sorted_tuples = sorted(tuple_list, key=lambda x: x[1])\n \n # Return the k smallest tuples\n return sorted_tuples[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(records, k):\n \"\"\"\n This function takes a list of tuples and an integer k as input. \n It returns the k minimum records from the input list.\n \n Parameters:\n records (list): A list of tuples, where each tuple contains a name and a value.\n k (int): The number of minimum records to return.\n \n Returns:\n list: A list of k minimum records from the input list.\n \"\"\"\n # Sort the records in ascending order based on the value in each tuple\n sorted_records = sorted(records, key=lambda x: x[1])\n \n # Return the k minimum records\n return sorted_records[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(records, k):\n \"\"\"\n Returns the minimum k records from a list of tuples.\n \n Args:\n records (list): A list of tuples where each tuple contains a string and an integer.\n k (int): The number of minimum records to return.\n \n Returns:\n list: A list of k tuples sorted in ascending order based on their integer value.\n \"\"\"\n # Sort the records based on the integer value in each tuple\n sorted_records = sorted(records, key=lambda x: x[1])\n \n # Return the k smallest records\n return sorted_records[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(records, k):\n \"\"\"\n Returns the k minimum records from a list of tuples.\n\n Args:\n records (list): A list of tuples where each tuple contains a name and a value.\n k (int): The number of minimum records to return.\n\n Returns:\n list: A list of the k minimum records.\n\n Example:\n >>> min_k([('Manjeet', 10), ('Akshat', 4), ('Akash', 2), ('Nikhil', 8)], 2)\n [('Akash', 2), ('Akshat', 4)]\n \"\"\"\n\n # Sort the records based on the value in each tuple\n sorted_records = sorted(records, key=lambda x: x[1])\n\n # Return the k minimum records\n return sorted_records[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(records, k):\n \"\"\"\n This function returns the minimum k records from a list of tuples.\n \n Parameters:\n records (list): A list of tuples where each tuple contains a string and an integer.\n k (int): The number of minimum records to return.\n \n Returns:\n list: A list of the k minimum records.\n \"\"\"\n # Sort the records based on the second element of each tuple (the integer value)\n sorted_records = sorted(records, key=lambda x: x[1])\n \n # Return the k minimum records\n return sorted_records[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(records, k):\n \"\"\"\n This function takes a list of records (each record is a tuple of two elements) \n and an integer k as input and returns the k records with the minimum second element.\n \n Args:\n records (list): A list of tuples, where each tuple contains a name and a number.\n k (int): The number of minimum records to return.\n \n Returns:\n list: A list of k tuples with the smallest numbers in the second elements.\n \"\"\"\n \n # First, we sort the list of records based on the second element of each tuple\n sorted_records = sorted(records, key=lambda x: x[1])\n \n # Then, we return the first k elements of the sorted list\n return sorted_records[:k]", "matching_cluster_idx": 2}]}, "Mbpp/754": {"dps": 83.10344827586208, "dps_norm": 84.375, "pass@1": 51.0, "profiled": [{"solution": "def extract_index_list(list1, list2, list3):\n \"\"\"\n This function extracts common elements from three lists at the same index.\n\n Args:\n list1 (list): The first list.\n list2 (list): The second list.\n list3 (list): The third list.\n\n Returns:\n list: A list of common elements.\n \"\"\"\n # Initialize an empty list to store common elements\n common_elements = []\n \n # Iterate through the indices and elements of the first list\n for i in range(min(len(list1), min(len(list2), len(list3)))):\n # Check if the elements at the current index in all lists are equal\n if list1[i] == list2[i] == list3[i]:\n # If they are equal, append the element to the common_elements list\n common_elements.append(list1[i])\n \n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n \"\"\"\n This function takes three lists and returns a list of elements that are common in all three lists\n and appear at the same index in all the lists.\n \n Parameters:\n l1 (list): The first list.\n l2 (list): The second list.\n l3 (list): The third list.\n \n Returns:\n list: A list of common elements at the same index in all lists.\n \"\"\"\n \n # Find the minimum length of the lists to avoid index out of range error\n min_length = min(len(l1), len(l2), len(l3))\n \n # Initialize an empty list to store common elements\n common_elements = []\n \n # Iterate over the range of the minimum length\n for i in range(min_length):\n # Check if the elements at the current index in all lists are the same\n if l1[i] == l2[i] == l3[i]:\n # If the elements are the same, append it to the common_elements list\n common_elements.append(l1[i])\n \n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n \"\"\"\n This function finds common elements that appear in all three lists at the same index.\n \n Parameters:\n l1 (list): The first list to compare.\n l2 (list): The second list to compare.\n l3 (list): The third list to compare.\n \n Returns:\n list: A list of common elements found in all three lists.\n \"\"\"\n common_elements = []\n for i in range(max(len(l1), len(l2), len(l3))):\n if i < len(l1) and i < len(l2) and i < len(l3) and l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n return common_elements", "matching_cluster_idx": 2}, {"solution": "def extract_index_list(l1, l2, l3):\n \"\"\"\n This function takes three lists as input and returns a list of elements that are common in all three lists under the same index.\n\n Args:\n l1 (list): The first list.\n l2 (list): The second list.\n l3 (list): The third list.\n\n Returns:\n list: A list of elements that are common in all three lists under the same index.\n \"\"\"\n # Find the length of the shortest list to ensure we don't go out of bounds\n min_len = min(len(l1), len(l2), len(l3))\n\n # Initialize an empty list to store the common elements\n common_elements = []\n\n # Iterate over the indices of the shortest list\n for i in range(min_len):\n # Check if all three lists have an element at the current index\n if l1[i] == l2[i] == l3[i]:\n # If all elements at the current index are the same, add it to the common_elements list\n common_elements.append(l1[i])\n\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n \"\"\"\n This function takes three lists as input and returns a list of common elements\n that appear in the same index in all three lists.\n\n Args:\n l1 (list): The first list.\n l2 (list): The second list.\n l3 (list): The third list.\n\n Returns:\n list: A list of common elements that appear in the same index in all three lists.\n \"\"\"\n\n # Initialize an empty list to store the common elements\n common_elements = []\n\n # Find the length of the shortest list to avoid index out of range error\n min_length = min(len(l1), len(l2), len(l3))\n\n # Iterate over the indices of the shortest list\n for i in range(min_length):\n # Check if the elements at the current index in all lists are the same\n if l1[i] == l2[i] == l3[i]:\n # If they are the same, add the element to the common_elements list\n common_elements.append(l1[i])\n\n # Return the list of common elements\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n \"\"\"\n This function returns a list of elements that are common to all three input lists under the same index.\n \n Args:\n l1 (list): The first input list.\n l2 (list): The second input list.\n l3 (list): The third input list.\n \n Returns:\n list: A list of elements that are common to all three input lists under the same index.\n \"\"\"\n # Initialize an empty list to store the common elements\n common_elements = []\n \n # Find the minimum length of the three lists\n min_len = min(len(l1), len(l2), len(l3))\n \n # Iterate over the indices of the minimum length\n for i in range(min_len):\n # Check if the elements at the current index are the same in all three lists\n if l1[i] == l2[i] == l3[i]:\n # If the elements are the same, append the element to the common_elements list\n common_elements.append(l1[i])\n \n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n \"\"\"\n This function finds and returns common elements from three lists with the same index.\n\n Args:\n l1 (list): The first list of elements.\n l2 (list): The second list of elements.\n l3 (list): The third list of elements.\n\n Returns:\n list: A list of elements that are common in all three lists at the same index.\n \"\"\"\n # Find the length of the shortest list, as any index greater than this will not be considered\n length = min(len(l1), len(l2), len(l3))\n \n common_elements = []\n \n # Loop through each index in the lists\n for i in range(length):\n # Check if the elements at the current index in all three lists are equal\n if l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n \n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(list1, list2, list3):\n \"\"\"\n This function takes three lists as input and returns a list of common elements\n from the three lists at the same index.\n\n Args:\n list1 (list): The first list.\n list2 (list): The second list.\n list3 (list): The third list.\n\n Returns:\n list: A list of common elements from the three lists at the same index.\n \"\"\"\n # Get the length of the lists\n len_list1 = len(list1)\n len_list2 = len(list2)\n len_list3 = len(list3)\n\n # Initialize an empty list to store common elements\n common_elements = []\n\n # Iterate over the lists using the length of the shortest list\n for i in range(min(len_list1, len_list2, len_list3)):\n # Check if the elements at the current index are equal in all lists\n if list1[i] == list2[i] == list3[i]:\n common_elements.append(list1[i])\n\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(list1, list2, list3):\n \"\"\"\n This function finds common elements from three lists where each element \n appears under the same index in all three lists.\n \n Args:\n list1 (list): The first list.\n list2 (list): The second list.\n list3 (list): The third list.\n \n Returns:\n list: A list of common elements.\n \"\"\"\n # Find the minimum length of the three lists\n min_length = min(len(list1), len(list2), len(list3))\n \n # Initialize an empty list to store the common elements\n common_elements = []\n \n # Iterate over the range of the minimum length\n for i in range(min_length):\n # Check if the elements at the current index are equal in all three lists\n if list1[i] == list2[i] == list3[i]:\n # If the elements are equal, add the element to the common elements list\n common_elements.append(list1[i])\n \n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(list1, list2, list3):\n \"\"\"\n This function returns a list of elements common to three lists under the same index.\n \n Args:\n list1 (list): The first list\n list2 (list): The second list\n list3 (list): The third list\n \n Returns:\n list: A list of common elements\n \"\"\"\n # Initialize an empty list to store common elements\n common_elements = []\n \n # Use zip function to iterate over three lists in parallel\n for a, b, c in zip(list1, list2, list3):\n # Check if elements are equal\n if a == b == c:\n # If equal, append the element to the common_elements list\n common_elements.append(a)\n \n # Return the list of common elements\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n \"\"\"\n This function finds common elements from three lists under the same index.\n\n Args:\n l1 (list): The first list.\n l2 (list): The second list.\n l3 (list): The third list.\n\n Returns:\n list: A list of common elements found in all three lists under the same index.\n \"\"\"\n # Find the minimum length of the three lists\n min_length = min(len(l1), len(l2), len(l3))\n \n # Initialize an empty list to store the common elements\n common_elements = []\n\n # Iterate over the minimum length\n for i in range(min_length):\n # Check if the elements at the current index in all three lists are equal\n if l1[i] == l2[i] == l3[i]:\n # If they are equal, add the element to the common_elements list\n common_elements.append(l1[i])\n\n # Return the list of common elements\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n \"\"\"\n Returns a list of elements common to all three lists at the same index.\n \n Args:\n l1 (list): First list of elements.\n l2 (list): Second list of elements.\n l3 (list): Third list of elements.\n \n Returns:\n list: A list of elements common to all three lists at the same index.\n \"\"\"\n # Initialize an empty list to store the common elements\n common_elements = []\n \n # Find the minimum length of the lists to avoid index out of range error\n min_length = min(len(l1), len(l2), len(l3))\n \n # Iterate over the range of the minimum length\n for i in range(min_length):\n # Check if the elements at the current index are the same in all lists\n if l1[i] == l2[i] == l3[i]:\n # If they are, append the element to the common_elements list\n common_elements.append(l1[i])\n \n # Return the list of common elements\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n \"\"\"\n This function extracts common elements from three lists based on their indices.\n \n Args:\n l1 (list): First list of elements.\n l2 (list): Second list of elements.\n l3 (list): Third list of elements.\n \n Returns:\n list: A list of common elements found at the same index in all three lists.\n \"\"\"\n \n # Initialize an empty list to store the common elements\n common_elements = []\n \n # Iterate over the range of the length of the first list\n for i in range(min(len(l1), len(l2), len(l3))):\n # Check if the elements at the current index are the same in all lists\n if l1[i] == l2[i] == l3[i]:\n # If they are the same, add the element to the common_elements list\n common_elements.append(l1[i])\n \n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n \"\"\"\n This function finds common elements from three lists based on their index.\n \n Args:\n l1 (list): The first list of numbers.\n l2 (list): The second list of numbers.\n l3 (list): The third list of numbers.\n \n Returns:\n list: A list containing elements that appear in all three lists under the same index.\n \"\"\"\n # Find the minimum length of the lists to avoid index out of range error\n min_length = min(len(l1), len(l2), len(l3))\n \n # Initialize an empty list to store common elements\n common_elements = []\n \n # Iterate over the range of the minimum length\n for i in range(min_length):\n # Check if the elements at the current index in all lists are the same\n if l1[i] == l2[i] == l3[i]:\n # If they are the same, append the element to the common_elements list\n common_elements.append(l1[i])\n \n # Return the list of common elements\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n \"\"\"\n Returns a list of elements that appear at the same index in all three lists.\n \n Args:\n l1 (list): The first list.\n l2 (list): The second list.\n l3 (list): The third list.\n \n Returns:\n list: A list of common elements from the three lists.\n \"\"\"\n # Initialize an empty list to store the common elements\n common_elements = []\n \n # Find the length of the shortest list\n min_length = min(len(l1), len(l2), len(l3))\n \n # Iterate over the index range of the shortest list\n for i in range(min_length):\n # Check if the elements at the current index in all three lists are equal\n if l1[i] == l2[i] == l3[i]:\n # If they are equal, add the element to the common_elements list\n common_elements.append(l1[i])\n \n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n \"\"\"\n This function returns a list of common elements that appear in the same index in three lists.\n \n Args:\n l1 (list): The first list\n l2 (list): The second list\n l3 (list): The third list\n \n Returns:\n list: A list of elements that appear in the same index in all three lists\n \"\"\"\n \n # Find the minimum length of the three lists to avoid index out of range error\n min_len = min(len(l1), len(l2), len(l3))\n \n # Initialize an empty list to store the common elements\n common_elements = []\n \n # Iterate over the indices from 0 to the minimum length of the lists\n for i in range(min_len):\n # Check if the elements at the current index are the same in all three lists\n if l1[i] == l2[i] == l3[i]:\n # If they are the same, append the element to the common_elements list\n common_elements.append(l1[i])\n \n # Return the list of common elements\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(list1, list2, list3):\n \"\"\"\n Returns a list of common elements that appear at the same index in all three lists.\n\n Args:\n list1 (list): First list to compare.\n list2 (list): Second list to compare.\n list3 (list): Third list to compare.\n\n Returns:\n list: A list of common elements.\n \"\"\"\n common_elements = []\n # Iterate over indices and elements in list1\n for idx in range(len(list1)):\n # Check if the index is within bounds of list2 and list3\n if idx < len(list2) and idx < len(list3):\n # Check if the elements at the index in all lists are the same\n if list1[idx] == list2[idx] == list3[idx]:\n common_elements.append(list1[idx])\n return common_elements", "matching_cluster_idx": 4}, {"solution": "def extract_index_list(l1, l2, l3):\n \"\"\"\n Returns a list of common elements that appear at the same index in all three lists.\n\n Args:\n l1 (list): The first list.\n l2 (list): The second list.\n l3 (list): The third list.\n\n Returns:\n list: A list of common elements that appear at the same index in all three lists.\n \"\"\"\n return [x for x, y, z in zip(l1, l2, l3) if x == y == z]", "matching_cluster_idx": 7}, {"solution": "def extract_index_list(l1, l2, l3):\n \"\"\"\n This function takes three lists as input and returns a list of common elements \n that appear under the same index in all three lists.\n\n Parameters:\n l1 (list): The first list.\n l2 (list): The second list.\n l3 (list): The third list.\n\n Returns:\n list: A list of common elements that appear under the same index in all three lists.\n \"\"\"\n # Find the length of the shortest list to avoid index out of range errors\n min_length = min(len(l1), len(l2), len(l3))\n \n # Initialize an empty list to store common elements\n common_elements = []\n \n # Iterate over the indices of the shortest list\n for i in range(min_length):\n # Check if the elements at the current index are the same in all lists\n if l1[i] == l2[i] == l3[i]:\n # If they are the same, add the element to the common_elements list\n common_elements.append(l1[i])\n \n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n \"\"\"\n This function finds common elements that appear in all three lists under the same index.\n\n Args:\n l1 (list): First list to compare.\n l2 (list): Second list to compare.\n l3 (list): Third list to compare.\n\n Returns:\n list: A list of common elements that appear under the same index in all three lists.\n \"\"\"\n # Find the minimum length between the three lists\n min_length = min(len(l1), len(l2), len(l3))\n \n # Initialize an empty list to store the common elements\n common_elements = []\n \n # Iterate over the indices from 0 to min_length\n for i in range(min_length):\n # Check if the elements at the current index in all three lists are equal\n if l1[i] == l2[i] == l3[i]:\n # If they are equal, add the element to the common_elements list\n common_elements.append(l1[i])\n \n # Return the list of common elements\n return common_elements", "matching_cluster_idx": 6}]}, "Mbpp/755": {"dps": 77.52212389380531, "dps_norm": 90.0, "pass@1": 40.0, "profiled": [{"solution": "def second_smallest(nums):\n \"\"\"\n This function finds the second smallest number in a list of numbers.\n\n Args:\n nums (list): A list of numbers.\n\n Returns:\n The second smallest number in the list. If the list contains less than two unique elements, it returns None.\n \"\"\"\n # Remove duplicates and sort the list\n unique_nums = sorted(set(nums))\n \n # Check if there are at least two unique elements in the list\n if len(unique_nums) < 2:\n return None\n \n # Return the second smallest number\n return unique_nums[1]", "matching_cluster_idx": 5}, {"solution": "def second_smallest(nums):\n \"\"\"\n Find the second smallest number in a list.\n \n Args:\n nums (list): A list of numbers.\n \n Returns:\n The second smallest number in the list. If the list has less than 2 elements, returns None.\n \"\"\"\n \n # Remove duplicates and sort the list\n unique_nums = sorted(set(nums))\n \n # Check if the list has at least 2 elements\n if len(unique_nums) < 2:\n return None\n \n # Return the second smallest number\n return unique_nums[1]", "matching_cluster_idx": 5}, {"solution": "def second_smallest(nums):\n \"\"\"\n Returns the second smallest number in a list.\n \n Args:\n nums (list): A list of numbers.\n \n Returns:\n int: The second smallest number in the list. If the list has less than two distinct numbers, returns None.\n \"\"\"\n # Remove duplicates and sort the list\n unique_nums = sorted(set(nums))\n \n # Check if there are at least two distinct numbers\n if len(unique_nums) < 2:\n return None\n \n # Return the second smallest number\n return unique_nums[1]", "matching_cluster_idx": 5}, {"solution": "def second_smallest(nums):\n \"\"\"\n This function returns the second smallest number in a list of numbers.\n\n Args:\n nums (list): A list of integers.\n\n Returns:\n int: The second smallest number in the list. If the list contains less than 2 unique elements, it returns None.\n \"\"\"\n # Remove duplicates by converting to a set\n unique_nums = set(nums)\n \n # Check if there are at least 2 unique elements\n if len(unique_nums) < 2:\n return None\n \n # Remove the smallest number\n unique_nums.remove(min(unique_nums))\n \n # Return the second smallest number\n return min(unique_nums)", "matching_cluster_idx": 4}, {"solution": "def second_smallest(nums):\n \"\"\"\n Find the second smallest number in a list.\n\n Args:\n nums (list): A list of numbers.\n\n Returns:\n int: The second smallest number in the list. If the list has less than two unique numbers, return None.\n \"\"\"\n # Remove duplicates by converting to a set\n unique_nums = set(nums)\n \n # Check if the list has at least two unique numbers\n if len(unique_nums) < 2:\n return None\n \n # Sort the set and return the second smallest number\n return sorted(list(unique_nums))[1]", "matching_cluster_idx": 5}, {"solution": "def second_smallest(lst):\n \"\"\"\n This function finds the second smallest number in a given list of numbers.\n\n Args:\n lst (list): A list of numbers.\n\n Returns:\n int or float: The second smallest number in the list. If the list has less than 2 unique elements, returns None.\n \"\"\"\n # Remove duplicates from the list\n unique_nums = sorted(set(lst))\n \n # Check if the list has at least two unique elements\n if len(unique_nums) < 2:\n return None\n \n # Return the second smallest number\n return unique_nums[1]", "matching_cluster_idx": 5}, {"solution": "def second_smallest(lst):\n \"\"\"\n This function finds the second smallest number in a given list.\n \n Args:\n lst (list): A list of numbers.\n \n Returns:\n int: The second smallest number in the list. If the list contains less than two unique numbers, returns None.\n \"\"\"\n # Remove duplicates by converting to a set\n unique_nums = set(lst)\n \n # Check if there are at least two unique numbers\n if len(unique_nums) < 2:\n return None\n \n # Remove the smallest number\n unique_nums.remove(min(unique_nums))\n \n # Return the smallest of the remaining numbers\n return min(unique_nums)", "matching_cluster_idx": 4}, {"solution": "def second_smallest(numbers):\n \"\"\"\n This function finds the second smallest number in a list of numbers.\n\n Args:\n numbers (list): A list of integers.\n\n Returns:\n int: The second smallest number in the list. If the list has less than two unique numbers, it returns None.\n\n Example:\n >>> second_smallest([1, 2, -8, -2, 0, -2])\n -2\n \"\"\"\n # First, remove duplicates by converting the list to a set\n unique_numbers = set(numbers)\n \n # Check if there are at least two unique numbers\n if len(unique_numbers) < 2:\n return None\n \n # Remove the smallest number\n unique_numbers.remove(min(unique_numbers))\n \n # Return the smallest of the remaining numbers\n return min(unique_numbers)", "matching_cluster_idx": 4}, {"solution": "def second_smallest(numbers):\n \"\"\"\n Returns the second smallest number in a list.\n\n Args:\n numbers (list): A list of numbers.\n\n Returns:\n The second smallest number in the list, or None if the list has less than 2 unique numbers.\n\n Raises:\n ValueError: If the list contains non-numeric values.\n \"\"\"\n # Check if the list contains non-numeric values\n if not all(isinstance(x, (int, float)) for x in numbers):\n raise ValueError(\"The list must contain only numbers.\")\n\n # Remove duplicates and sort the list in ascending order\n unique_numbers = sorted(set(numbers))\n\n # Check if there are at least two unique numbers\n if len(unique_numbers) < 2:\n return None\n\n # Return the second smallest number\n return unique_numbers[1]", "matching_cluster_idx": 2}, {"solution": "def second_smallest(nums):\n \"\"\"\n Find the second smallest number in a list.\n \n Args:\n nums (list): A list of integers.\n \n Returns:\n int: The second smallest number in the list. If the list has less than two unique numbers, returns None.\n \"\"\"\n # Remove duplicates from the list\n unique_nums = list(set(nums))\n \n # Check if the list has at least two unique numbers\n if len(unique_nums) < 2:\n return None\n \n # Sort the list in ascending order\n unique_nums.sort()\n \n # Return the second smallest number\n return unique_nums[1]", "matching_cluster_idx": 5}, {"solution": "def second_smallest(numbers):\n \"\"\"\n This function finds the second smallest number in a list.\n\n Args:\n numbers (list): A list of numbers.\n\n Returns:\n int: The second smallest number in the list.\n \"\"\"\n # Remove duplicates and sort the list\n unique_numbers = sorted(set(numbers))\n \n # If the list has less than two unique numbers, return None\n if len(unique_numbers) < 2:\n return None\n \n # The second smallest number is the second element in the sorted list\n return unique_numbers[1]", "matching_cluster_idx": 5}, {"solution": "def second_smallest(nums):\n \"\"\"\n Finds the second smallest number in a list.\n \n Args:\n nums (list): A list of numbers.\n \n Returns:\n The second smallest number in the list. If the list has less than two unique numbers, returns None.\n \"\"\"\n # Remove duplicates by converting the list to a set\n unique_nums = set(nums)\n \n # Check if there are less than two unique numbers\n if len(unique_nums) < 2:\n return None\n \n # Sort the unique numbers in ascending order\n sorted_nums = sorted(unique_nums)\n \n # The second smallest number is the second element in the sorted list\n return sorted_nums[1]", "matching_cluster_idx": 5}, {"solution": "def second_smallest(lst):\n \"\"\"\n This function finds the second smallest number in a list.\n\n Args:\n lst (list): A list of numbers.\n\n Returns:\n The second smallest number in the list. If the list has less than 2 elements, returns None.\n\n Raises:\n ValueError: If the list contains non-numeric values.\n \"\"\"\n # Check if the list contains at least 2 elements\n if len(lst) < 2:\n return None\n\n # Check if the list contains non-numeric values\n if not all(isinstance(i, (int, float)) for i in lst):\n raise ValueError(\"The list must contain only numeric values\")\n\n # Remove duplicates and sort the list\n unique_lst = sorted(set(lst))\n\n # Check if there are less than two unique values\n if len(unique_lst) < 2:\n return None\n\n # Return the second smallest value\n return unique_lst[1]", "matching_cluster_idx": 2}, {"solution": "def second_smallest(nums):\n \"\"\"\n This function finds the second smallest number in a list.\n\n Args:\n nums (list): A list of integers.\n\n Returns:\n int: The second smallest number in the list. If the list has less than two unique elements, returns None.\n\n \"\"\"\n # Check if the list has less than two unique elements\n if len(set(nums)) < 2:\n return None\n\n # Remove duplicates and sort the list\n unique_nums = sorted(set(nums))\n\n # The second smallest number is the second element in the sorted list\n return unique_nums[1]", "matching_cluster_idx": 4}, {"solution": "def second_smallest(lst):\n \"\"\"\n This function finds the second smallest number in a list.\n\n Args:\n lst (list): A list of numbers.\n\n Returns:\n int: The second smallest number in the list.\n \"\"\"\n # Remove duplicates by converting the list to a set\n unique_nums = set(lst)\n \n # Check if the list has at least two unique elements\n if len(unique_nums) < 2:\n return None\n \n # Remove the smallest number\n unique_nums.discard(min(unique_nums))\n \n # Return the smallest remaining number\n return min(unique_nums)", "matching_cluster_idx": 4}, {"solution": "def second_smallest(nums):\n \"\"\"\n This function finds the second smallest number in a list of numbers.\n \n Args:\n nums (list): A list of numbers.\n \n Returns:\n The second smallest number in the list. If the list contains less than two unique numbers, it returns None.\n \"\"\"\n \n # Remove duplicates and sort the list in ascending order\n unique_nums = sorted(set(nums))\n \n # Check if the list contains less than two unique numbers\n if len(unique_nums) < 2:\n return None\n \n # Return the second smallest number\n return unique_nums[1]", "matching_cluster_idx": 5}, {"solution": "def second_smallest(nums):\n \"\"\"\n This function takes a list of numbers as input and returns the second smallest number.\n \n Args:\n nums (list): A list of numbers.\n \n Returns:\n int: The second smallest number in the list.\n \"\"\"\n # First, we remove duplicates from the list by converting it into a set\n unique_nums = set(nums)\n \n # Then we convert the set back into a list and sort it in ascending order\n sorted_nums = sorted(list(unique_nums))\n \n # Since lists are 0-indexed, the second smallest number is at index 1\n # We use a try-except block to handle cases where the list has less than 2 unique elements\n try:\n return sorted_nums[1]\n except IndexError:\n return None", "matching_cluster_idx": 5}, {"solution": "def second_smallest(numbers):\n \"\"\"\n Returns the second smallest number in the list.\n \n Args:\n numbers (list): A list of numbers.\n \n Returns:\n int: The second smallest number in the list. If the list has less than two unique numbers, returns None.\n \"\"\"\n \n # Remove duplicates by converting to a set\n unique_numbers = set(numbers)\n \n # Check if there are less than two unique numbers\n if len(unique_numbers) < 2:\n return None\n \n # Remove the smallest number\n unique_numbers.remove(min(unique_numbers))\n \n # Return the second smallest number\n return min(unique_numbers)", "matching_cluster_idx": 4}, {"solution": "def second_smallest(lst):\n \"\"\"\n Finds the second smallest number in a list.\n\n Args:\n lst (list): A list of integers.\n\n Returns:\n int: The second smallest number in the list. If there's no second smallest number (i.e., all numbers are the same), returns None.\n \"\"\"\n # Remove duplicates by converting the list to a set\n unique_nums = set(lst)\n # Check if there's at least two unique numbers in the list\n if len(unique_nums) < 2:\n return None\n # Sort the set to get the smallest and the second smallest number\n smallest_nums = sorted(unique_nums)\n # Return the second smallest number\n return smallest_nums[1]", "matching_cluster_idx": 5}, {"solution": "def second_smallest(numbers):\n \"\"\"\n This function finds the second smallest number in a list.\n \n Parameters:\n numbers (list): A list of numbers.\n \n Returns:\n int: The second smallest number in the list. If the list has less than two unique numbers, it returns None.\n \"\"\"\n # Remove duplicates and sort the list in ascending order\n unique_numbers = sorted(set(numbers))\n \n # Check if the list has at least two unique numbers\n if len(unique_numbers) < 2:\n return None\n \n # Return the second smallest number\n return unique_numbers[1]", "matching_cluster_idx": 5}]}, "Mbpp/757": {"dps": 70.0, "dps_norm": 20.0, "pass@1": 43.0, "profiled": [{"solution": "def count_reverse_pairs(strings):\n \"\"\"\n Counts the number of pairs of strings in the list where each pair is a reverse of the other.\n \n Args:\n strings (list): A list of strings.\n \n Returns:\n int: The number of pairs of reverse strings in the list.\n \"\"\"\n count = 0\n for i in range(len(strings)):\n for j in range(i + 1, len(strings)):\n if strings[i] == strings[j][::-1] and strings[j] == strings[i][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(lst):\n \"\"\"\n Counts the number of pairs of strings in the given list that are reverses of each other.\n \n Args:\n lst (list): A list of strings.\n \n Returns:\n int: The number of reverse string pairs.\n \"\"\"\n count = 0\n for i in range(len(lst)):\n for j in range(i + 1, len(lst)):\n # Check if the current strings are reverses of each other\n if lst[i] == lst[j][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(lst):\n \"\"\"\n Counts the pairs of reverse strings in a given list of strings.\n\n Args:\n lst (list): A list of strings.\n\n Returns:\n int: The number of pairs of reverse strings.\n \"\"\"\n def is_reverse(s1, s2):\n \"\"\"Check if two strings are reverse of each other\"\"\"\n return s1 == s2[::-1]\n\n count = 0\n for i in range(len(lst)):\n for j in range(i + 1, len(lst)):\n if is_reverse(lst[i], lst[j]):\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(string_list):\n \"\"\"\n This function counts the number of pairs of reverse strings in a given list of strings.\n\n Args:\n string_list (list): A list of strings.\n\n Returns:\n int: The number of pairs of reverse strings.\n\n \"\"\"\n def is_reverse(s1, s2):\n \"\"\"Check if two strings are reverses of each other\"\"\"\n return s1 == s2[::-1]\n\n pairs = 0\n for i in range(len(string_list)):\n for j in range(i+1, len(string_list)):\n if is_reverse(string_list[i], string_list[j]):\n pairs += 1\n return pairs", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(lst):\n \"\"\"\n This function takes a list of strings and returns the number of pairs of strings that are reverse of each other.\n \n Parameters:\n lst (list): A list of strings.\n \n Returns:\n int: The number of pairs of strings that are reverse of each other.\n \"\"\"\n count = 0 # Initialize a counter to store the number of reverse pairs.\n for i in range(len(lst)):\n for j in range(i + 1, len(lst)):\n # Check if the current pair of strings is the reverse of each other\n if lst[i] == lst[j][::-1]: # Use slicing to reverse the string for comparison.\n count += 1 # Increment the counter if the strings are reverses of each other.\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(lst):\n \"\"\"\n This function counts the pairs of reverse strings in the given list.\n \n Args:\n lst (list): A list of strings.\n \n Returns:\n int: The number of pairs of reverse strings.\n \"\"\"\n count = 0\n for i in range(len(lst)):\n for j in range(i + 1, len(lst)):\n # Check if the current pair of strings are reverses of each other\n if lst[i] == lst[j][::-1] or lst[j] == lst[i][::-1]:\n count += 1\n return count", "matching_cluster_idx": 0}, {"solution": "def count_reverse_pairs(lst):\n \"\"\"\n Counts the number of pairs of reverse strings in the given string list.\n \n Args:\n lst (list): A list of strings.\n \n Returns:\n int: The number of pairs of reverse strings.\n \"\"\"\n pair_count = 0\n for i in range(len(lst)):\n for j in range(i+1, len(lst)):\n if lst[i] == lst[j][::-1] and lst[j] == lst[i][::-1]:\n pair_count += 1\n return pair_count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(string_list):\n \"\"\"\n This function counts the pairs of reverse strings in the given list of strings.\n\n Args:\n string_list (list): A list of strings.\n\n Returns:\n int: The number of pairs of reverse strings.\n \"\"\"\n def is_reverse(s1, s2):\n \"\"\"\n Helper function to check if two strings are reverses of each other.\n \"\"\"\n return s1 == s2[::-1]\n\n count = 0\n for i in range(len(string_list)):\n for j in range(i+1, len(string_list)):\n if is_reverse(string_list[i], string_list[j]):\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(lst):\n \"\"\"\n Count the pairs of reverse strings in the given string list.\n \n Args:\n lst (list): A list of strings.\n \n Returns:\n int: The number of pairs of reverse strings.\n \"\"\"\n count = 0\n for i in range(len(lst)):\n for j in range(i + 1, len(lst)):\n if lst[i] == lst[j][::-1] and lst[j] == lst[i][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(lst):\n \"\"\"\n This function counts the number of pairs of reverse strings in the given list.\n\n Args:\n lst (list): A list of strings.\n\n Returns:\n int: The number of pairs of reverse strings in the given list.\n \"\"\"\n pair_count = 0\n for i in range(len(lst)):\n for j in range(i + 1, len(lst)):\n if lst[i] == lst[j][::-1] and lst[j] == lst[i][::-1]: # Check for reverse equality\n pair_count += 1\n return pair_count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(string_list):\n \"\"\"\n This function counts the number of pairs of strings in a list that are reverse of each other.\n\n Parameters:\n string_list (list): A list of strings.\n\n Returns:\n int: The number of pairs of reverse strings.\n \"\"\"\n count = 0 # Initialize a counter for the number of pairs of reverse strings\n n = len(string_list) # Get the length of the list\n\n # Iterate over the list\n for i in range(n):\n for j in range(i+1, n): # Start the inner loop from the next element to avoid duplicates\n # Check if the current string and the string at the current index are reverse of each other\n if string_list[i] == string_list[j][::-1] or string_list[j] == string_list[i][::-1]:\n count += 1 # Increment the counter if the strings are reverse of each other\n\n return count # Return the count of reverse pairs", "matching_cluster_idx": 0}, {"solution": "def count_reverse_pairs(lst):\n \"\"\"\n This function counts the number of pairs of reverse strings in the given string list.\n \n Args:\n lst (list): A list of strings.\n \n Returns:\n int: The count of pairs of reverse strings.\n \"\"\"\n # Initialize a counter variable to store the count of reverse pairs\n reverse_pairs = 0\n \n # Iterate through the list of strings\n for i in range(len(lst)):\n # For each string, check if its reverse is present in the remaining list\n for j in range(i+1, len(lst)):\n if lst[i] == lst[j][::-1]: # Check if string i is a reverse of string j\n reverse_pairs += 1\n if lst[j] == lst[i][::-1]: # Check if string j is a reverse of string i\n reverse_pairs += 1\n \n # Return the count of reverse pairs divided by 2 to avoid counting each pair twice\n return reverse_pairs // 2", "matching_cluster_idx": 0}, {"solution": "def count_reverse_pairs(string_list):\n \"\"\"\n This function counts the pairs of reverse strings in a given list of strings.\n \n Args:\n string_list (list): A list of strings.\n \n Returns:\n int: The number of pairs of reverse strings in the list.\n \"\"\"\n count = 0\n for i in range(len(string_list)):\n for j in range(i + 1, len(string_list)):\n if string_list[i] == string_list[j][::-1] and string_list[j] == string_list[i][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(lst):\n \"\"\"\n This function counts the number of pairs of strings that are reverses of each other.\n \n Parameters:\n lst (list): A list of strings\n \n Returns:\n int: The number of pairs of strings that are reverses of each other\n \"\"\"\n count = 0 # Initialize counter\n for i in range(len(lst)): # Iterate over the list\n for j in range(i + 1, len(lst)): # Iterate over the remaining elements\n if lst[i] == lst[j][::-1]: # Check if a string is a reverse of another string\n count += 1 # Increment the count if a pair is found\n return count # Return the count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(lst):\n \"\"\"\n Counts the number of pairs of reverse strings in the given list.\n\n Args:\n lst (list): A list of strings.\n\n Returns:\n int: The number of pairs of reverse strings.\n \"\"\"\n def is_reverse_pair(s1, s2):\n \"\"\"\n Checks if two strings are reverse of each other.\n \"\"\"\n return s1 == s2[::-1]\n\n count = 0\n for i in range(len(lst)):\n for j in range(i + 1, len(lst)):\n if is_reverse_pair(lst[i], lst[j]):\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(string_list):\n \"\"\"\n Count the number of pairs of reverse strings in a given list of strings.\n \n Args:\n string_list (list): A list of strings.\n \n Returns:\n int: The count of pairs of reverse strings.\n \"\"\"\n count = 0\n for i in range(len(string_list)):\n for j in range(i + 1, len(string_list)):\n if string_list[i] == string_list[j][::-1] and string_list[j] == string_list[i][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(string_list):\n \"\"\"\n Counts the pairs of reverse strings in the given string list.\n\n Args:\n string_list (list): A list of strings.\n\n Returns:\n int: The number of pairs of reverse strings.\n \"\"\"\n count = 0\n for i in range(len(string_list)):\n for j in range(i + 1, len(string_list)):\n if string_list[i] == string_list[j][::-1]: # Check if string i is reverse of string j\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(lst):\n \"\"\"\n Counts the number of pairs of reverse strings in the given list.\n\n Args:\n lst (list): A list of strings.\n\n Returns:\n int: The number of pairs of reverse strings.\n \"\"\"\n count = 0\n for i in range(len(lst)):\n for j in range(i + 1, len(lst)):\n if lst[i] == lst[j][::-1]: # Check if string i is the reverse of string j\n count += 1\n elif lst[j] == lst[i][::-1]: # Check if string j is the reverse of string i\n count += 1\n return count", "matching_cluster_idx": 0}, {"solution": "def count_reverse_pairs(string_list):\n \"\"\"\n This function counts the number of pairs of reverse strings in the given list.\n\n Args:\n string_list (list): A list of strings.\n\n Returns:\n int: The count of pairs of reverse strings.\n \"\"\"\n def is_reverse_pair(s1, s2):\n \"\"\"\n Helper function to check if two strings are reverse pairs.\n \"\"\"\n return s1 == s2[::-1]\n\n reverse_pairs = 0\n for i in range(len(string_list)):\n for j in range(i+1, len(string_list)):\n if is_reverse_pair(string_list[i], string_list[j]):\n reverse_pairs += 1\n return reverse_pairs", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(lst):\n \"\"\"\n Counts the number of pairs of reverse strings in the given list.\n\n Args:\n lst (list): A list of strings.\n\n Returns:\n int: The number of pairs of reverse strings.\n \"\"\"\n count = 0\n for i in range(len(lst)):\n for j in range(i+1, len(lst)):\n if lst[i] == lst[j][::-1] and lst[j] == lst[i][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}]}, "Mbpp/758": {"dps": 34.25675675675675, "dps_norm": 66.875, "pass@1": 80.0, "profiled": [{"solution": "def unique_sublists(lst):\n \"\"\"\n This function counts the occurrence of every sublist in the input list.\n It returns a dictionary where each sublist is converted to a tuple and the value of such tuple is the number of its occurrences.\n \n Args:\n lst (list): A list containing various sublists.\n \n Returns:\n dict: A dictionary where each key is a unique sublist converted to a tuple, and the value is the count of its occurrences in the original list.\n \"\"\"\n count_dict = {}\n for sublst in lst:\n tup = tuple(sublst) # Convert sublist to tuple for uniqueness check\n if tup not in count_dict:\n count_dict[tup] = 1\n else:\n count_dict[tup] += 1\n return count_dict", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(lst):\n \"\"\"\n This function takes a list of lists as an argument and returns a dictionary where every list is converted to a tuple and the value of such tuple is the number of its occurrences in the original list.\n\n Parameters:\n lst (list): A list of lists.\n\n Returns:\n dict: A dictionary where keys are unique lists as tuples and values are their occurrence counts.\n \"\"\"\n # Convert the input list of lists to a list of tuples\n tuples_list = [tuple(sublist) for sublist in lst]\n \n # Count the occurrences of each tuple\n count_dict = {}\n for t in tuples_list:\n if t in count_dict:\n count_dict[t] += 1\n else:\n count_dict[t] = 1\n \n return count_dict", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(lst):\n \"\"\"\n Function to count lists within a list.\n\n Args:\n lst (list): A list containing multiple lists.\n\n Returns:\n dict: A dictionary where every list is converted to a tuple and the value of such tuple is the number of its occurrences in the original list.\n \"\"\"\n # Convert each sublist to a tuple\n tuples = [tuple(sublist) for sublist in lst]\n\n # Create a dictionary to store the frequency of each tuple\n frequency_dict = {}\n\n # Loop through the list of tuples and update the frequency dictionary\n for t in tuples:\n if t in frequency_dict:\n frequency_dict[t] += 1\n else:\n frequency_dict[t] = 1\n\n return frequency_dict", "matching_cluster_idx": 5}, {"solution": "def unique_sublists(lst):\n \"\"\"\n This function takes a list of lists as input, counts the occurrences of each sublist, \n converts sublists to tuples, and returns a dictionary where each tuple is a key and its value is the count.\n\n Args:\n lst (list): A list of lists.\n\n Returns:\n dict: A dictionary where each key is a tuple and its value is the count of occurrences of that tuple in the input list.\n \"\"\"\n # Create an empty dictionary to store unique sublists and their counts\n count_dict = {}\n\n # Iterate over each sublist in the input list\n for sublist in lst:\n # Convert the sublist to a tuple (so it can be used as a dictionary key)\n tupled_sublist = tuple(sublist)\n \n # If the tuple is already in the dictionary, increment its count by 1\n if tupled_sublist in count_dict:\n count_dict[tupled_sublist] += 1\n # Otherwise, add the tuple to the dictionary with a count of 1\n else:\n count_dict[tupled_sublist] = 1\n\n return count_dict", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(lst):\n \"\"\"\n Counts the occurrences of each sublist in the given list.\n \n Args:\n lst (list): The list of lists.\n \n Returns:\n dict: A dictionary where keys are tuples of sublists and values are their counts.\n \"\"\"\n # Initialize an empty dictionary to store the counts of sublists\n counts = {}\n \n # Iterate over each sublist in the given list\n for sub_list in lst:\n # Convert the sublist to a tuple and use it as a key in the dictionary\n # If the key already exists, increment its count; otherwise, add it with a count of 1\n counts[tuple(sub_list)] = counts.get(tuple(sub_list), 0) + 1\n \n # Return the dictionary containing the counts of sublists\n return counts", "matching_cluster_idx": 5}, {"solution": "from collections import Counter\ndef unique_sublists(lst):\n \"\"\"\n Counts lists within a list and returns a dictionary where every list is converted to a tuple \n and the value of such tuple is the number of its occurrences in the original list.\n\n Args:\n lst (list): A list of lists.\n\n Returns:\n dict: A dictionary where keys are tuples of lists and values are their counts.\n \"\"\"\n # Convert each sublist to a tuple and count the number of occurrences of each sublist\n sublists_tuple = tuple(tuple(sublist) for sublist in lst)\n counter = Counter(sublists_tuple)\n \n # Convert the Counter object back to a dictionary\n return dict(counter)\nlst = [[1, 3], [5, 7], [1, 3], [13, 15, 17], [5, 7], [9, 11]]", "matching_cluster_idx": 5}, {"solution": "def unique_sublists(lists):\n \"\"\"\n This function takes a list of lists as input, converts each sublist to a tuple, \n and returns a dictionary where each unique sublist-tuple is a key and its value \n is the number of its occurrences in the input list.\n \"\"\"\n # Convert each sublist to a tuple, use a dictionary to count the occurrences of each sublist-tuple\n return {tuple(sublist): lists.count(sublist) for sublist in lists}", "matching_cluster_idx": 3}, {"solution": "def unique_sublists(list_of_lists):\n \"\"\"\n Counts occurrences of each sublist in the list_of_lists.\n \n Args:\n list_of_lists (list): List containing lists of elements.\n \n Returns:\n dict: Dictionary where each key is a tuple representation of a sublist and the value is its count in the original list.\n \"\"\"\n # Convert each sublist to a tuple, join all lists into one, and count occurrences of each tuple\n count_dict = {}\n for sublist in list_of_lists:\n sublist_tuple = tuple(sublist) # Convert to tuple to make it hashable\n if sublist_tuple in count_dict:\n count_dict[sublist_tuple] += 1\n else:\n count_dict[sublist_tuple] = 1\n \n return count_dict\nlist_of_lists = [[1, 3], [5, 7], [1, 3], [13, 15, 17], [5, 7], [9, 11]]", "matching_cluster_idx": 4}, {"solution": "def unique_sublists(lists):\n \"\"\"\n This function counts occurrences of each sublist in the given list.\n It returns a dictionary where each sublist is converted to a tuple and the value of such tuple is the number of its occurrences.\n\n Args:\n lists (list): A list of lists.\n Returns:\n dict: A dictionary with tuples of sublists as keys and their occurrence counts as values.\n \"\"\"\n sublist_counts = {}\n for sublist in lists:\n # Convert each sublist to a tuple (because lists are not hashable and can't be used as dictionary keys)\n tupled_sublist = tuple(sublist)\n # Increment the count for the current sublist in the dictionary\n sublist_counts[tupled_sublist] = sublist_counts.get(tupled_sublist, 0) + 1\n return sublist_counts\nlists = [[1, 3], [5, 7], [1, 3], [13, 15, 17], [5, 7], [9, 11]]", "matching_cluster_idx": 4}, {"solution": "def unique_sublists(lst):\n \"\"\"\n This function counts occurrences of every sublist in a given list.\n\n Args:\n lst (list): The input list containing various sublists.\n\n Returns:\n dict: A dictionary where each key is a unique tuple of a sublist and its value is the number of occurrences.\n \"\"\"\n # Initialize an empty dictionary to store the count of each sublist\n sublists_count = {}\n\n # Iterate over each sublist in the given list\n for sub in lst:\n # Convert the sublist to a tuple (since lists are not hashable and cannot be keys in a dictionary) and make it a key in the dictionary\n sub_tuple = tuple(sub)\n # If the tuple already exists in the dictionary, increment its count by 1; otherwise, set its count to 1\n sublists_count[sub_tuple] = sublists_count.get(sub_tuple, 0) + 1\n\n return sublists_count", "matching_cluster_idx": 4}, {"solution": "def unique_sublists(lst):\n \"\"\"\n This function counts the occurrences of each sublist in a given list.\n \n Args:\n lst (list): A list containing various types of lists.\n \n Returns:\n dict: A dictionary where every list is converted to a tuple and the value of such tuple is the number of its occurrences in the original list.\n \"\"\"\n # Create an empty dictionary to store the result\n result = {}\n # Iterate over each sublist in the input list\n for sub_list in lst:\n # Convert the sublist to a tuple (to make it hashable) and use it as the key in the dictionary\n # If the key already exists, increment its count by 1; otherwise, set its count to 1\n result[tuple(sub_list)] = result.get(tuple(sub_list), 0) + 1\n return result", "matching_cluster_idx": 4}, {"solution": "def unique_sublists(lst):\n \"\"\"\n This function counts lists within a list, converting each list to a tuple and returns a dictionary \n where the tuple key is associated with the number of its occurrences in the original list.\n \n Args:\n lst (list): A list of lists.\n \n Returns:\n dict: A dictionary where each tuple in the original list is the key and its value is the number of times it appears.\n \"\"\"\n \n # Convert each sublist to a tuple\n unique_sublists = [tuple(sublist) for sublist in lst]\n \n # Create a dictionary to store the count of each tuple\n count_dict = {}\n \n # Iterate over each sublist (now a tuple) in the list\n for sublist in unique_sublists:\n # If the tuple is already in the dictionary, increment its count\n if sublist in count_dict:\n count_dict[sublist] += 1\n # If the tuple is not in the dictionary, add it with a count of 1\n else:\n count_dict[sublist] = 1\n \n return count_dict", "matching_cluster_idx": 4}, {"solution": "def unique_sublists(lst):\n \"\"\"\n This function takes a list of lists, converts each sublist to a tuple, \n counts the occurrences of each unique tuple, and returns a dictionary with the tuples as keys and their counts as values.\n\n Args:\n lst (list): A list of lists.\n\n Returns:\n dict: A dictionary with tuples as keys and their counts as values.\n \"\"\"\n # Convert the sublists to tuples and count their occurrences using a dictionary\n occurrences = {}\n for sublst in lst:\n # Convert the sublist to a tuple to ensure it's hashable\n tup = tuple(sublst)\n # Increment the count in the dictionary\n occurrences[tup] = occurrences.get(tup, 0) + 1\n \n return occurrences", "matching_cluster_idx": 4}, {"solution": "from collections import Counter\ndef unique_sublists(lst):\n \"\"\"\n This function counts occurrences of sublists within the given list.\n \n Args:\n lst (list): A list containing sublists.\n \n Returns:\n dict: A dictionary where each key is a sublist as a tuple and the value is the occurrence count of the sublist.\n \"\"\"\n # Convert sublists to tuples to make them hashable for use as dictionary keys\n lst = [tuple(sublist) for sublist in lst]\n \n # Use a Counter to count occurrences of sublists\n counter = Counter(lst)\n \n return dict(counter)", "matching_cluster_idx": 5}, {"solution": "def unique_sublists(lst):\n \"\"\"\n Count the occurrence of lists within a list.\n \n Args:\n lst (list): List of lists.\n \n Returns:\n dict: Dictionary where keys are tuples of unique sublists and values are their occurrence counts.\n \"\"\"\n # Use a dictionary to store unique tuples and their counts\n counts = {}\n \n # Iterate over the list\n for sublst in lst:\n # Convert the sublist to a tuple (as lists are not hashable and cannot be used as dictionary keys)\n t = tuple(sublst)\n \n # If the tuple is already in the dictionary, increment its count\n if t in counts:\n counts[t] += 1\n # Otherwise, add the tuple to the dictionary with a count of 1\n else:\n counts[t] = 1\n \n return counts", "matching_cluster_idx": 4}, {"solution": "def unique_sublists(lst):\n \"\"\"\n Counts the occurrences of each sublist in the input list.\n \n Args:\n lst (list): A list that contains sublists of different lengths.\n \n Returns:\n dict: A dictionary where every sublist is converted to a tuple and the value of such tuple is the number of its occurrences in the original list.\n \"\"\"\n # Initialize an empty dictionary to store the count of each sublist\n sublists_count = {}\n \n # Iterate over each sublist in the input list\n for sublst in lst:\n # Convert the sublist to a tuple (because lists are not hashable and thus not directly usable as dictionary keys)\n tpl = tuple(sublst)\n \n # If the sublist is already in the dictionary, increment its count by 1\n if tpl in sublists_count:\n sublists_count[tpl] += 1\n # If the sublist is not in the dictionary, add it with a count of 1\n else:\n sublists_count[tpl] = 1\n \n return sublists_count", "matching_cluster_idx": 4}, {"solution": "def unique_sublists(lst):\n \"\"\"\n This function counts the occurrence of each sublist in the given list.\n \n Args:\n lst (list): A list that can contain lists as elements.\n \n Returns:\n dict: A dictionary where keys are tuples (converted from sublists) and values are their occurrence count in the original list.\n \"\"\"\n # Initialize an empty dictionary to store the result\n result = {}\n # Iterate over each sublist in the given list\n for sublist in lst:\n # Convert the sublist to a tuple (as lists are not hashable and thus cannot be used as dictionary keys)\n key = tuple(sublist)\n # If the key (tuple) is already in the result dictionary, increment its count\n if key in result:\n result[key] += 1\n # If the key is not in the result dictionary, add it with a count of 1\n else:\n result[key] = 1\n return result", "matching_cluster_idx": 4}, {"solution": "def unique_sublists(lst):\n \"\"\"\n Counts the occurrences of each sublist in the given list and returns a dictionary.\n \n Args:\n lst (list): A list of lists.\n\n Returns:\n dict: A dictionary where keys are unique sublists converted to tuples and values are their counts.\n \"\"\"\n # Convert all sublists to tuples\n tuples = [tuple(sublist) for sublist in lst]\n \n # Use a dictionary comprehension to count occurrences\n return {t: tuples.count(t) for t in set(tuples)}", "matching_cluster_idx": 2}, {"solution": "def unique_sublists(lst):\n \"\"\"\n Counts the occurrences of each list in the input list.\n \n Args:\n lst (list): A list of lists to be processed.\n \n Returns:\n dict: A dictionary with each unique sublist converted to a tuple and its count as the value.\n \"\"\"\n \n # Initialize an empty dictionary to store unique sublists and their counts\n sublist_counts = {}\n \n # Iterate over each sublist in the input list\n for sublist in lst:\n # Convert the sublist to a tuple to make it hashable (since lists are not hashable)\n key = tuple(sublist)\n \n # If the key is already in the dictionary, increment its count; otherwise, add it with a count of 1\n sublist_counts[key] = sublist_counts.get(key, 0) + 1\n \n # Return the dictionary with unique sublists and their counts\n return sublist_counts", "matching_cluster_idx": 4}, {"solution": "def unique_sublists(sublists):\n \"\"\"\n This function takes a list of lists as input and returns a dictionary.\n Every list in the input is converted to a tuple and serves as a key in the dictionary.\n The value of such a tuple is the number of its occurrences in the original list.\n \n Args:\n sublists (list): A list of lists.\n \n Returns:\n dict: A dictionary where keys are tuples representing the sublists and values are their respective occurrences.\n \"\"\"\n \n # Initialize an empty dictionary to store the frequency of sublists\n freq_dict = {}\n \n # Iterate over each sublist in the input list\n for sublist in sublists:\n # Convert the sublist to a tuple (because lists are not hashable and thus not suitable for use as keys in dictionaries)\n tuple_sublist = tuple(sublist)\n \n # If the tuple is already in the dictionary, increment its count by 1\n if tuple_sublist in freq_dict:\n freq_dict[tuple_sublist] += 1\n # If the tuple is not in the dictionary, add it with a count of 1\n else:\n freq_dict[tuple_sublist] = 1\n \n return freq_dict", "matching_cluster_idx": 4}]}, "Mbpp/760": {"dps": 99.27007299270073, "dps_norm": 87.5, "pass@1": 99.0, "profiled": [{"solution": "def unique_Element(lst):\n \"\"\"\n Checks if a list of numbers contains only one distinct element.\n \n Args:\n lst (list): A list of integers.\n \n Returns:\n bool: True if the list contains only one distinct element, False otherwise.\n \"\"\"\n return len(set(lst)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(lst):\n \"\"\"\n Checks if a list contains only one distinct element.\n\n Args:\n lst (list): The input list to check.\n\n Returns:\n bool: True if the list contains only one distinct element, False otherwise.\n \"\"\"\n return len(set(lst)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(lst):\n \"\"\"\n Checks whether a list of numbers contains only one distinct element.\n \n Args:\n lst (list): A list of numbers.\n \n Returns:\n bool: True if the list contains only one distinct element, False otherwise.\n \"\"\"\n return len(set(lst)) <= 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(lst):\n \"\"\"\n Checks whether a list of numbers contains only one distinct element or not.\n\n Args:\n lst (list): The input list of numbers.\n\n Returns:\n bool: True if the list contains only one distinct element, False otherwise.\n \"\"\"\n return len(set(lst)) <= 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(lst):\n \"\"\"\n Check if a list contains only one distinct element.\n \n Args:\n lst (list): List of numbers to check.\n \n Returns:\n bool: True if the list contains only one distinct element, False otherwise.\n \"\"\"\n \n # Convert the list to a set to remove duplicates and count the number of elements\n num_distinct_elements = len(set(lst))\n \n # A list with one distinct element will have a set of length 1\n return num_distinct_elements == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(nums):\n \"\"\"\n Checks if a list of numbers contains only one distinct element.\n\n Args:\n nums (list): A list of numbers\n\n Returns:\n bool: True if all elements in the list are the same, False otherwise\n \"\"\"\n return len(set(nums)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(lst):\n \"\"\"\n This function checks whether a list of numbers contains only one distinct element or not.\n \n Args:\n lst (list): A list of numbers.\n \n Returns:\n bool: True if the list contains only one distinct element, False otherwise.\n \"\"\"\n return len(set(lst)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(nums):\n \"\"\"\n Check if a list of numbers contains only one distinct element.\n\n Args:\n nums (list): A list of numbers.\n\n Returns:\n bool: True if the list contains only one distinct element, False otherwise.\n \"\"\"\n return len(set(nums)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(lst):\n \"\"\"\n Checks whether a list of numbers contains only one distinct element or not.\n\n Args:\n lst (list): A list of integers.\n\n Returns:\n bool: True if the list contains only one distinct element, False otherwise.\n \"\"\"\n return len(set(lst)) <= 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(lst):\n \"\"\"\n Checks if the list contains only one distinct element.\n\n Args:\n lst (list): List of numbers.\n\n Returns:\n bool: True if the list contains only one distinct element, False otherwise.\n \"\"\"\n return len(set(lst)) <= 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(lst):\n \"\"\"\n This function checks if a list of numbers contains only one distinct element.\n\n Args:\n lst (list): A list of numbers\n\n Returns:\n bool: True if the list contains only one distinct element, False otherwise\n \"\"\"\n return len(set(lst)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(lst):\n \"\"\"\n This function checks whether a list of numbers contains only one distinct element or not.\n\n Args:\n lst (list): A list of numbers\n\n Returns:\n bool: True if the list contains only one distinct element, False otherwise\n \"\"\"\n # Convert the list to a set to remove duplicates\n unique = set(lst)\n \n # If the length of the set is 1, the list contains only one distinct element\n return len(unique) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(numbers):\n \"\"\"\n This function checks if a list of numbers contains only one distinct element.\n \n Args:\n numbers (list): A list of numbers.\n \n Returns:\n bool: True if the list contains only one distinct element, False otherwise.\n \"\"\"\n return len(set(numbers)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(lst):\n \"\"\"\n Checks whether a list of numbers contains only one distinct element or not.\n \n Args:\n lst (list): A list of numbers\n \n Returns:\n bool: True if the list contains only one distinct element, False otherwise\n \"\"\"\n return len(set(lst)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(lst):\n \"\"\"\n Checks whether a list of numbers contains only one distinct element.\n\n Args:\n lst (list): A list of numbers.\n\n Returns:\n bool: True if the list contains only one distinct element, False otherwise.\n \"\"\"\n return len(set(lst)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(lst):\n \"\"\"\n This function checks if a list contains only one distinct element.\n \n Parameters:\n lst (list): A list of numbers.\n \n Returns:\n bool: True if the list contains only one distinct element, False otherwise.\n \"\"\"\n \n # Convert the list to a set to remove duplicates and then compare its length with the original list length\n return len(set(lst)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(lst):\n \"\"\"\n Checks if a list contains only one distinct element.\n \n Args:\n lst (list): The list to check for unique elements.\n \n Returns:\n bool: True if the list has only one distinct element, False otherwise.\n \"\"\"\n return len(set(lst)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(lst):\n \"\"\"\n Checks if a list of numbers contains only one distinct element.\n \n Args:\n lst (list): A list of integers.\n \n Returns:\n bool: True if the list contains only one distinct element, False otherwise.\n \"\"\"\n return len(set(lst)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(lst):\n \"\"\"\n Checks if a list of numbers contains only one distinct element.\n \n Args:\n lst (list): The input list of numbers.\n \n Returns:\n bool: True if the list contains only one distinct element, False otherwise.\n \"\"\"\n return len(set(lst)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(nums):\n \"\"\"\n Checks if a list of numbers contains only one distinct element.\n \n Args:\n nums (list): A list of numbers.\n \n Returns:\n bool: True if the list contains only one distinct element, False otherwise.\n \"\"\"\n return len(set(nums)) == 1", "matching_cluster_idx": 6}]}, "Mbpp/764": {"dps": 84.50617283950616, "dps_norm": 49.166666666666664, "pass@1": 64.0, "profiled": [{"solution": "def number_ctr(s):\n \"\"\"\n This function counts the occurrences of a number in a given string.\n \n Args:\n s (str): The input string to be searched.\n \n Returns:\n int: The count of number occurrences in the string.\n \"\"\"\n count = 0\n for char in s:\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n \"\"\"\n Counts the number of digits in a given string.\n\n Args:\n s (str): Input string.\n\n Returns:\n int: Number of digits in the string.\n \"\"\"\n return sum(c.isdigit() for c in s)", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n \"\"\"\n This function counts the total number of digits in a given string.\n\n Args:\n s (str): Input string to count digits in.\n\n Returns:\n int: The total number of digits in the string.\n \"\"\"\n # Initialize a counter for digits\n count = 0\n \n # Iterate over each character in the string\n for char in s:\n # Check if the character is a digit\n if char.isdigit():\n # If it's a digit, increment the counter\n count += 1\n \n # Return the total count of digits\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n \"\"\"\n This function counts the number of digits in a given string.\n\n Args:\n s (str): The input string to count digits in.\n\n Returns:\n int: The count of digits in the string.\n \"\"\"\n count = 0\n for char in s:\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n \"\"\"\n Counts the number of times a digit appears in a given string.\n \n Args:\n s (str): Input string to be searched.\n \n Returns:\n int: Number of occurrences of digits in the string.\n \"\"\"\n count = 0\n for char in s:\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n \"\"\"\n This function counts the number of times a digit appears in a given string.\n\n Args:\n s (str): The input string to check for digits.\n\n Returns:\n int: The count of digits in the string.\n \"\"\"\n return sum(c.isdigit() for c in s)", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n \"\"\"\n This function counts the number of times a number appears as a digit in a given string.\n\n Args:\n s (str): The input string.\n\n Returns:\n int: The count of digits in the input string.\n\n \"\"\"\n count = 0\n for char in s:\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n \"\"\"\n Counts the number of occurrences of a digit in a given string.\n\n Args:\n s (str): The input string.\n\n Returns:\n int: The number of occurrences of a digit in the string.\n\n \"\"\"\n # Count the number of digits in the string\n return sum(c.isdigit() for c in s)", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n \"\"\"\n Counts the number of occurrences of a number (both integer and decimal) in a given string.\n\n Args:\n s (str): The string to search for numbers in.\n\n Returns:\n int: Number of occurrences of numbers in the string.\n \"\"\"\n count = 0\n for char in s:\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n \"\"\"\n Counts the occurrences of numbers in a given string.\n\n Args:\n s (str): Input string.\n\n Returns:\n int: Number of numbers in the string.\n \"\"\"\n # Initialize a counter to keep track of the count\n count = 0\n # Loop through the string character by character\n for char in s:\n # Check if the character is a digit\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n \"\"\"\n Counts the number of occurrences of a digit in a given string.\n\n Args:\n s (str): The input string.\n\n Returns:\n int: The count of digits in the string.\n\n \"\"\"\n # Use isdigit() to check if a character is a digit and sum up the counts.\n return sum(c.isdigit() for c in s)", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n \"\"\"\n Counts the number of digits in a given string.\n \n Args:\n s (str): The input string to count digits in.\n \n Returns:\n int: The number of digits in the input string.\n \"\"\"\n return sum(c.isdigit() for c in s)", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n \"\"\"\n Counts the number of digits in a given string.\n\n Args:\n s (str): The input string.\n\n Returns:\n int: The count of digits in the string.\n \"\"\"\n return sum(c.isdigit() for c in s)", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n \"\"\"\n Returns the number of times a number appears in a given string.\n\n Args:\n s (str): The input string.\n\n Returns:\n int: The number of times a number appears in the string.\n \"\"\"\n count = 0\n for char in s:\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n \"\"\"\n Counts the number of times a digit appears in a given string.\n\n Args:\n s (str): Input string\n\n Returns:\n int: Number of times a digit appears in the string\n \"\"\"\n count = 0\n for char in s:\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n \"\"\"\n Counts the number of digits in a given string.\n\n Args:\n s (str): Input string to count digits from.\n\n Returns:\n int: The count of digits in the input string.\n\n \"\"\"\n return sum(c.isdigit() for c in s)", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n \"\"\"\n Count number of digits in a given string.\n\n Args:\n s (str): The input string.\n\n Returns:\n int: The number of digits in the string.\n\n \"\"\"\n return sum(c.isdigit() for c in s)", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n \"\"\"\n This function counts the number of occurrences of a given number in a string.\n\n Args:\n s (str): The input string.\n\n Returns:\n int: The number of occurrences of a number in the string.\n \"\"\"\n # Define a regular expression pattern for a digit\n import re\n pattern = r'\\d'\n\n # Count the number of occurrences of the pattern in the string\n count = len(re.findall(pattern, s))\n\n return count", "matching_cluster_idx": 1}, {"solution": "def number_ctr(s):\n \"\"\"\n Counts the number of times a number appears in a given string.\n\n Args:\n s (str): The input string.\n\n Returns:\n int: The count of the number in the string.\n\n \"\"\"\n # Initialize a counter for numbers\n count = 0\n\n # Iterate over each character in the string\n for char in s:\n # Check if the character is a digit\n if char.isdigit():\n count += 1\n\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n \"\"\"\n Counts the number of digits in a given string.\n \n Args:\n s (str): The input string.\n \n Returns:\n int: The count of digits in the string.\n \"\"\"\n count = 0\n for char in s:\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}]}, "Mbpp/766": {"dps": 66.1214953271028, "dps_norm": 60.0, "pass@1": 99.0, "profiled": [{"solution": "def pair_wise(lst):\n \"\"\"\n Returns a list of all pairs of consecutive items in a given list.\n\n Args:\n lst (list): Input list of elements.\n\n Returns:\n list: A list of tuples where each tuple contains two consecutive elements from the input list.\n\n Example:\n >>> pair_wise([1, 1, 2, 3, 3, 4, 4, 5])\n [(1, 1), (1, 2), (2, 3), (3, 3), (3, 4), (4, 4), (4, 5)]\n \"\"\"\n return [(lst[i], lst[i+1]) for i in range(len(lst) - 1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n \"\"\"\n Returns a list of pairs of consecutive items in the given list.\n \n Args:\n lst (list): The input list.\n \n Returns:\n list: A list of pairs of consecutive items.\n \"\"\"\n return [(lst[i], lst[i+1]) for i in range(len(lst) - 1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n \"\"\"\n Generate a list of all pairs of consecutive items in a given list.\n\n Args:\n lst (list): A list of elements.\n\n Returns:\n list: A list of tuples, each tuple containing two consecutive elements from the input list.\n \"\"\"\n return [(lst[i], lst[i+1]) for i in range(len(lst) - 1)]", "matching_cluster_idx": 2}, {"solution": "def pair_wise(lst):\n \"\"\"\n Returns a list of pairs of consecutive items from the given list.\n \n Args:\n lst: A list of elements.\n \n Returns:\n A list of tuples, where each tuple contains a pair of consecutive elements from the input list.\n \"\"\"\n return [(lst[i], lst[i+1]) for i in range(len(lst)-1)]", "matching_cluster_idx": 2}, {"solution": "def pair_wise(lst):\n \"\"\"\n Returns a list of all pairs of consecutive items in the given list.\n\n Args:\n lst (list): The input list.\n\n Returns:\n list: A list of tuples where each tuple contains a pair of consecutive items from the input list.\n\n Example:\n >>> pair_wise([1,1,2,3,3,4,4,5])\n [(1, 1), (1, 2), (2, 3), (3, 3), (3, 4), (4, 4), (4, 5)]\n \"\"\"\n return [(lst[i], lst[i+1]) for i in range(len(lst)-1)]", "matching_cluster_idx": 2}, {"solution": "def pair_wise(lst):\n \"\"\"\n This function takes a list of elements as input and returns a list of pairs where each pair consists of two consecutive elements from the input list.\n\n Args:\n lst (list): The input list.\n\n Returns:\n list: A list of pairs where each pair consists of two consecutive elements from the input list.\n \"\"\"\n return [(lst[i], lst[i+1]) for i in range(len(lst) - 1)]", "matching_cluster_idx": 2}, {"solution": "def pair_wise(lst):\n \"\"\"\n Generate a list of pairs of consecutive items in the given list.\n\n Args:\n lst (list): A list of items.\n\n Returns:\n list: A list of pairs of consecutive items.\n\n Example:\n >>> pair_wise([1, 1, 2, 3, 3, 4, 4, 5])\n [(1, 1), (1, 2), (2, 3), (3, 3), (3, 4), (4, 4), (4, 5)]\n \"\"\"\n return [(lst[i], lst[i + 1]) for i in range(len(lst) - 1)]", "matching_cluster_idx": 2}, {"solution": "def pair_wise(lst):\n \"\"\"\n Return a list of all pairs of consecutive items in a given list.\n \n Args:\n lst (list): A list of items.\n \n Returns:\n list: A list of tuples where each tuple contains consecutive items from the input list.\n \n Example:\n >>> pair_wise([1, 1, 2, 3, 3, 4, 4, 5])\n [(1, 1), (1, 2), (2, 3), (3, 3), (3, 4), (4, 4), (4, 5)]\n \"\"\"\n return [(lst[i], lst[i+1]) for i in range(len(lst) - 1)]", "matching_cluster_idx": 2}, {"solution": "def pair_wise(lst):\n \"\"\"\n Return a list of all pairs of consecutive items in a given list.\n \n Args:\n lst (list): The input list from which to create consecutive pairs.\n \n Returns:\n list: A list of tuples, where each tuple contains a pair of consecutive elements from the input list.\n \"\"\"\n return [(lst[i], lst[i+1]) for i in range(len(lst)-1)]", "matching_cluster_idx": 2}, {"solution": "def pair_wise(lst):\n \"\"\"\n This function takes a list as input and returns a list of all pairs of consecutive items.\n \n Args:\n lst (list): The input list.\n \n Returns:\n list: A list of tuples, where each tuple contains two consecutive items from the input list.\n \"\"\"\n return [(lst[i], lst[i+1]) for i in range(len(lst)-1)]", "matching_cluster_idx": 2}, {"solution": "def pair_wise(lst):\n \"\"\"\n Returns a list of all pairs of consecutive items in the input list.\n \n Args:\n lst (list): The input list.\n \n Returns:\n list: A list of tuples, where each tuple is a pair of consecutive items from the input list.\n \"\"\"\n return [(lst[i], lst[i+1]) for i in range(len(lst)-1)]", "matching_cluster_idx": 2}, {"solution": "def pair_wise(lst):\n \"\"\"\n Returns a list of all pairs of consecutive items in a given list.\n \n Args:\n lst (list): A list of items\n \n Returns:\n list: A list of pairs of consecutive items\n \"\"\"\n return list(zip(lst, lst[1:]))", "matching_cluster_idx": 5}, {"solution": "def pair_wise(lst):\n \"\"\"\n Returns a list of all pairs of consecutive items in a given list.\n \n Args:\n lst (list): The input list.\n \n Returns:\n list: A list of tuples where each tuple is a pair of consecutive items from the input list.\n \"\"\"\n return list(zip(lst, lst[1:]))", "matching_cluster_idx": 5}, {"solution": "def pair_wise(lst):\n \"\"\"\n This function takes a list of items and returns a list of all pairs of consecutive items.\n \n Args:\n lst (list): A list of items.\n \n Returns:\n list: A list of tuples, where each tuple contains a pair of consecutive items from the input list.\n \"\"\"\n # Initialize an empty list to store the pairs\n pairs = []\n # Iterate over the input list, stopping one element before the end\n for i in range(len(lst) - 1):\n # For each element, create a pair with the next element and add it to the list\n pairs.append((lst[i], lst[i + 1]))\n return pairs", "matching_cluster_idx": 2}, {"solution": "def pair_wise(lst):\n \"\"\"\n Returns a list of all pairs of consecutive items in a given list.\n \n Args:\n lst (list): The input list of items.\n \n Returns:\n list: A list of tuples, where each tuple contains two consecutive items from the input list.\n \"\"\"\n return [(lst[i], lst[i + 1]) for i in range(len(lst) - 1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n \"\"\"\n This function takes a list as input and returns a list of tuples, where each tuple contains a pair of consecutive items from the input list.\n\n Args:\n lst (list): The input list.\n\n Returns:\n list: A list of tuples, where each tuple contains a pair of consecutive items from the input list.\n \"\"\"\n # Use list comprehension to iterate over the input list with the index and value\n return [(lst[i], lst[i+1]) for i in range(len(lst)-1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n \"\"\"\n Return a list of all pairs of consecutive items in a given list.\n\n Args:\n lst (list): A list of elements.\n\n Returns:\n list: A list of tuples, where each tuple is a pair of consecutive items from the input list.\n \"\"\"\n return [(lst[i], lst[i+1]) for i in range(len(lst)-1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n \"\"\"\n Returns a list of all pairs of consecutive items in a given list.\n\n Args:\n lst (list): The input list.\n\n Returns:\n list: A list of tuples representing consecutive pairs.\n\n Example:\n >>> pair_wise([1, 1, 2, 3, 3, 4, 4, 5])\n [(1, 1), (1, 2), (2, 3), (3, 3), (3, 4), (4, 4), (4, 5)]\n \"\"\"\n return [(lst[i], lst[i+1]) for i in range(len(lst)-1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n \"\"\"\n This function takes a list of elements and returns a list of all pairs of consecutive items.\n\n Args:\n lst (list): A list of elements\n\n Returns:\n list: A list of tuples, where each tuple is a pair of consecutive elements from the input list\n \"\"\"\n # Initialize an empty list to store the result\n result = []\n # Iterate over the input list with enumerate to keep track of indices\n for i in range(len(lst)):\n # If the current index is not the last index in the list, add the current element and the next element as a pair\n if i < len(lst) - 1:\n result.append((lst[i], lst[i + 1]))\n # Return the list of pairs\n return result", "matching_cluster_idx": 1}, {"solution": "def pair_wise(lst):\n \"\"\"\n Returns a list of all pairs of consecutive items in a given list.\n \n Args:\n lst (list): The input list.\n\n Returns:\n list: A list of tuples, where each tuple is a pair of consecutive items from the input list.\n \"\"\"\n return [(lst[i], lst[i+1]) for i in range(len(lst) - 1)]", "matching_cluster_idx": 3}]}, "Mbpp/775": {"dps": 76.55999999999999, "dps_norm": 57.85714285714286, "pass@1": 92.0, "profiled": [{"solution": "def odd_position(nums):\n \"\"\"\n This function checks whether every odd index in a given list contains an odd number.\n\n Args:\n nums (list): A list of integers.\n\n Returns:\n bool: True if every odd index in the list contains an odd number, False otherwise.\n \"\"\"\n for i in range(1, len(nums), 2): # Iterate over odd indices starting from 1.\n if nums[i] % 2 == 0: # Check if the number at the current index is even.\n return False\n return True # If the loop completes without finding an even number, return True.", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n \"\"\"\n Checks if every odd index in a given list contains an odd number.\n\n Args:\n lst (list): A list of integers.\n\n Returns:\n bool: True if every odd index contains an odd number, False otherwise.\n\n \"\"\"\n # Use list comprehension to check every odd index for odd numbers\n return all(i % 2 != 0 and lst[i] % 2 != 0 for i in range(len(lst)) if i % 2 != 0)", "matching_cluster_idx": 1}, {"solution": "def odd_position(lst):\n \"\"\"\n Checks whether every odd index contains an odd number in a list.\n\n Args:\n lst (list): Input list to check.\n\n Returns:\n bool: True if all odd indices have odd numbers, False otherwise.\n \"\"\"\n for i in range(1, len(lst), 2): # Iterate over odd indices\n if lst[i] % 2 == 0: # Check if current number is even\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n \"\"\"\n Checks if every odd index in a list contains an odd number.\n\n Args:\n lst (list): A list of numbers.\n\n Returns:\n bool: True if every odd index in the list contains an odd number, False otherwise.\n \"\"\"\n return all(num % 2 != 0 for i, num in enumerate(lst) if i % 2 != 0)", "matching_cluster_idx": 2}, {"solution": "def odd_position(lst):\n \"\"\"\n Checks whether every odd index in the given list contains an odd number.\n\n Args:\n lst (list): The input list to be checked.\n\n Returns:\n bool: True if every odd index contains an odd number, False otherwise.\n \"\"\"\n for i in range(1, len(lst), 2): # iterate over odd indices\n if lst[i] % 2 == 0: # check if the number at the current index is even\n return False # if it's even, the function immediately returns False\n return True # if the loop completes without returning False, all odd indices contain odd numbers", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n \"\"\"\n Checks whether every odd index contains an odd number in a given list.\n\n Args:\n lst (list): The input list to be checked.\n\n Returns:\n bool: True if every odd index contains an odd number, False otherwise.\n \"\"\"\n return all(num % 2 != 0 for i, num in enumerate(lst) if i % 2 != 0)", "matching_cluster_idx": 2}, {"solution": "def odd_position(lst):\n \"\"\"\n This function checks whether every odd index contains odd numbers in a given list.\n\n Parameters:\n lst (list): The input list to check.\n\n Returns:\n bool: True if every odd index contains an odd number, False otherwise.\n \"\"\"\n return all(lst[i] % 2 != 0 for i in range(1, len(lst), 2))", "matching_cluster_idx": 3}, {"solution": "def odd_position(lst):\n \"\"\"\n This function checks whether every odd index in a list contains an odd number.\n\n Parameters:\n lst (list): A list of integers.\n\n Returns:\n bool: True if every odd index contains an odd number, False otherwise.\n \"\"\"\n return all(lst[i] % 2 != 0 for i in range(1, len(lst), 2))", "matching_cluster_idx": 3}, {"solution": "def odd_position(lst):\n \"\"\"\n Checks if every odd index in a list contains an odd number.\n \n Args:\n lst (list): A list of integers.\n \n Returns:\n bool: True if every odd index in the list has an odd number, False otherwise.\n \"\"\"\n return all(num % 2 != 0 for i, num in enumerate(lst) if i % 2 != 0)", "matching_cluster_idx": 2}, {"solution": "def odd_position(lst):\n \"\"\"\n Checks if every odd index contains odd numbers.\n\n Args:\n lst (list): The input list to be checked.\n\n Returns:\n bool: True if every odd index contains an odd number, False otherwise.\n \"\"\"\n return all(num % 2 != 0 for i, num in enumerate(lst) if i % 2 != 0)", "matching_cluster_idx": 2}, {"solution": "def odd_position(lst):\n \"\"\"\n Checks whether every odd index contains an odd number in the given list.\n\n Args:\n lst (list): The input list of numbers.\n\n Returns:\n bool: True if every odd index contains an odd number, False otherwise.\n \"\"\"\n return all(lst[i] % 2 != 0 for i in range(1, len(lst), 2))", "matching_cluster_idx": 3}, {"solution": "def odd_position(lst):\n \"\"\"\n This function checks if every odd index of a given list contains an odd number.\n\n Args:\n lst (list): A list of integers.\n\n Returns:\n bool: True if every odd index contains an odd number, False otherwise.\n \"\"\"\n # Iterate over the list with enumerate to get both index and value\n for i, num in enumerate(lst):\n # Check if index is odd and number is even\n if i % 2 != 0 and num % 2 == 0:\n return False\n # If no pair is found where index is odd and number is even, return True\n return True", "matching_cluster_idx": 2}, {"solution": "def odd_position(lst):\n \"\"\"\n Checks if every odd index in the list has an odd number.\n\n Args:\n lst (list): Input list to check.\n\n Returns:\n bool: True if every odd index has an odd number, False otherwise.\n \"\"\"\n for i in range(1, len(lst), 2): # Loop over odd indices\n if lst[i] % 2 == 0: # Check if the number at the odd index is even\n return False # If even, return False\n return True # If all odd indices have odd numbers, return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n \"\"\"\n Checks whether every odd index contains odd numbers in the given list.\n \n Args:\n lst (list): The input list.\n \n Returns:\n bool: True if all odd positions have odd numbers, False otherwise.\n \"\"\"\n return all(x % 2 != 0 for i, x in enumerate(lst) if i % 2 != 0)", "matching_cluster_idx": 2}, {"solution": "def odd_position(lst):\n \"\"\"\n Checks if every odd index in a list contains an odd number.\n\n Args:\n lst (list): The input list to check.\n\n Returns:\n bool: True if every odd index contains an odd number, False otherwise.\n \"\"\"\n for i in range(1, len(lst), 2): # Iterate over odd indices\n if lst[i] % 2 == 0: # Check if the value at the odd index is even\n return False # Return False if any odd index contains an even number\n return True # Return True if no even numbers were found at odd indices", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n \"\"\"\n Checks whether every odd index of the given list contains an odd number.\n\n Args:\n lst (list): A list of numbers.\n\n Returns:\n bool: True if every odd index contains an odd number, False otherwise.\n \"\"\"\n for i in range(1, len(lst), 2):\n if lst[i] % 2 == 0: # Check if the number at the odd index is even\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n \"\"\"\n Checks if every odd index in a given list contains odd numbers.\n \n Args:\n lst (list): A list of integers.\n \n Returns:\n bool: True if every odd index in the list contains an odd number, False otherwise.\n \"\"\"\n # Check if the list is empty\n if not lst:\n return True\n\n # Iterate over the list, considering odd indices only\n for i in range(1, len(lst), 2):\n # Check if the number at the current index is even\n if lst[i] % 2 == 0:\n return False\n \n # If no even numbers at odd indices were found, return True\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n \"\"\"\n This function checks whether every odd index in a given list contains an odd number.\n\n Args:\n lst (list): A list of integers.\n\n Returns:\n bool: True if every odd index in the list contains an odd number, False otherwise.\n \"\"\"\n for i in range(1, len(lst), 2): # Iterate over odd indices\n if lst[i] % 2 == 0: # Check if the number at the current odd index is even\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n \"\"\"\n This function checks if every odd index contains an odd number in a given list.\n \n Args:\n lst (list): The input list to be checked.\n \n Returns:\n bool: True if every odd index contains an odd number, False otherwise.\n \"\"\"\n return all(lst[i] % 2 != 0 for i in range(1, len(lst), 2))", "matching_cluster_idx": 3}, {"solution": "def odd_position(lst):\n \"\"\"\n Checks whether every odd index in a given list contains an odd number.\n\n Args:\n lst (list): A list of integers.\n\n Returns:\n bool: True if every odd index contains an odd number, False otherwise.\n \"\"\"\n for i in range(1, len(lst), 2): # Iterate over odd indices\n if lst[i] % 2 == 0: # Check if the number at the odd index is even\n return False # If even, return False immediately\n return True # If no even numbers at odd indices, return True", "matching_cluster_idx": 4}]}, "Mbpp/777": {"dps": 30.357142857142858, "dps_norm": 52.22222222222222, "pass@1": 10.0, "profiled": [{"solution": "def find_sum(lst):\n \"\"\"\n This function calculates the sum of non-repeated elements in a given list.\n\n Args:\n lst (list): A list of numbers.\n\n Returns:\n int: The sum of non-repeated elements in the list.\n \"\"\"\n # Initialize a set to keep track of repeated elements\n repeated = set()\n \n # Initialize a variable to store the sum of non-repeated elements\n total_sum = 0\n \n # Iterate over the list\n for num in lst:\n # If the number is already in the set of repeated elements\n if num in repeated:\n # Add the number to the set of repeated elements\n repeated.add(num)\n else:\n # If the number is not in the set of repeated elements\n # Add the number to the set of repeated elements\n repeated.add(num)\n # Add the number to the total sum\n total_sum += num\n \n # Return the total sum\n return total_sum", "matching_cluster_idx": 4}, {"solution": "def find_sum(lst):\n \"\"\"\n This function calculates the sum of non-repeated elements in a given list.\n\n Args:\n lst (list): A list of integers.\n\n Returns:\n int: The sum of non-repeated elements in the list.\n\n Example:\n >>> find_sum([1,2,3,1,1,4,5,6])\n 21\n \"\"\"\n seen = set()\n non_repeated_sum = 0\n for num in lst:\n if num not in seen:\n non_repeated_sum += num\n seen.add(num)\n return non_repeated_sum", "matching_cluster_idx": 4}, {"solution": "def find_sum(lst):\n \"\"\"\n This function calculates the sum of non-repeated elements in a given list.\n\n Args:\n lst (list): A list of integers.\n\n Returns:\n int: The sum of non-repeated elements in the list.\n \"\"\"\n seen = set()\n non_repeated_sum = 0\n for num in lst:\n if num not in seen:\n seen.add(num)\n non_repeated_sum += num\n return non_repeated_sum", "matching_cluster_idx": 4}, {"solution": "def find_sum(nums):\n \"\"\"\n This function calculates the sum of non-repeated elements in a list.\n\n Args:\n nums (list): A list of integers.\n\n Returns:\n int: The sum of non-repeated elements.\n\n Example:\n >>> find_sum([1,2,3,1,1,4,5,6])\n 21\n \"\"\"\n seen = set()\n repeated = set()\n total = 0\n \n for num in nums:\n if num in seen:\n repeated.add(num)\n elif num in repeated:\n continue\n else:\n seen.add(num)\n total += num\n\n return total", "matching_cluster_idx": 4}, {"solution": "def find_sum(lst):\n \"\"\"\n This function takes a list of integers as input and returns the sum of all non-repeated elements.\n\n Parameters:\n lst (list): A list of integers.\n\n Returns:\n int: The sum of non-repeated elements in the list.\n \"\"\"\n seen = {} # dictionary to keep track of seen elements\n count = 0 # variable to store the sum of non-repeated elements\n for num in lst:\n if num not in seen:\n count += num # if the number is not seen, add it to the count\n seen[num] = 1 # mark the number as seen\n else:\n seen[num] += 1 # if the number is seen, increment its count\n return count", "matching_cluster_idx": 3}, {"solution": "def find_sum(lst):\n \"\"\"\n This function calculates the sum of non-repeated elements in a given list.\n \n Parameters:\n lst (list): The input list of integers.\n \n Returns:\n int: The sum of non-repeated elements in the list.\n \"\"\"\n seen = set() # Set to keep track of seen elements\n sum = 0 # Variable to store the sum of non-repeated elements\n \n for num in lst:\n if num not in seen:\n seen.add(num) # Add the number to the set if not seen before\n sum += num # Add the number to the sum\n \n return sum", "matching_cluster_idx": 4}, {"solution": "def find_sum(lst):\n \"\"\"\n This function calculates the sum of non-repeated elements in a given list.\n \n Args:\n lst (list): A list of integers\n \n Returns:\n int: The sum of non-repeated elements in the list\n \"\"\"\n seen = set()\n sum = 0\n \n for num in lst:\n if num not in seen:\n seen.add(num)\n sum += num\n return sum", "matching_cluster_idx": 4}, {"solution": "def find_sum(nums):\n \"\"\"\n This function calculates the sum of non-repeated elements in a given list.\n\n Args:\n nums (list): A list of integers.\n\n Returns:\n int: The sum of non-repeated elements in the list.\n \"\"\"\n seen = {} # Create a dictionary to store elements we've seen\n sum_non_repeated = 0 # Initialize sum for non-repeated elements\n for num in nums:\n if num in seen: # If we've seen this number before\n seen[num] += 1 # Increment its count\n else:\n seen[num] = 1 # First time we've seen this number\n sum_non_repeated += num # Add it to the sum\n return sum_non_repeated", "matching_cluster_idx": 3}, {"solution": "def find_sum(lst):\n \"\"\"\n This function takes a list as input and returns the sum of its non-repeated elements.\n\n :param lst: A list of integers\n :return: The sum of non-repeated elements in the list\n \"\"\"\n seen = set()\n sum_of_non_repeated = 0\n \n for num in lst:\n # If the number is not repeated, add it to the set and sum\n if num not in seen:\n sum_of_non_repeated += num\n seen.add(num)\n \n return sum_of_non_repeated", "matching_cluster_idx": 4}, {"solution": "def find_sum(lst):\n \"\"\"\n This function finds the sum of non-repeated elements in a given list.\n\n Args:\n lst (list): A list of integers.\n\n Returns:\n int: The sum of non-repeated elements in the list.\n \"\"\"\n seen = {} # Create a dictionary to store elements we've seen\n sum_of_non_repeats = 0 # Variable to store the sum of non-repeated elements\n for element in lst: # Iterate over the list\n if element in seen: # If the element has been seen before\n seen[element] += 1 # Increment its count\n else:\n seen[element] = 1 # Otherwise, mark it as seen\n sum_of_non_repeats += element # Add it to the sum of non-repeated elements\n return sum_of_non_repeats # Return the sum of non-repeated elements", "matching_cluster_idx": 3}]}, "Mbpp/781": {"dps": 49.44881889763779, "dps_norm": 48.0, "pass@1": 89.0, "profiled": [{"solution": "def count_divisors(n):\n \"\"\"\n Checks if the count of divisors of a number is even.\n\n Args:\n n (int): The input number.\n\n Returns:\n bool: True if the count of divisors is even, False otherwise.\n \"\"\"\n # Initialize count of divisors to 0\n count = 0\n\n # Iterate over all numbers from 1 to n (inclusive)\n for i in range(1, n + 1):\n # Check if i is a divisor of n\n if n % i == 0:\n # If it is, increment the count\n count += 1\n\n # Check if the count of divisors is even\n return count % 2 == 0", "matching_cluster_idx": 0}, {"solution": "def count_divisors(n):\n \"\"\"\n Count the number of divisors for the given number n.\n Then, return True if the count is even, False otherwise.\n\n Args:\n n (int): The number for which the divisor count should be calculated.\n\n Returns:\n bool: Whether the count of divisors is even.\n \"\"\"\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n # Check if the divisor and its corresponding quotient are the same\n if i * i == n:\n count += 1\n else:\n count += 2\n return count % 2 == 0", "matching_cluster_idx": 4}, {"solution": "def count_divisors(n):\n \"\"\"\n This function counts the number of divisors for a given number and returns True if the count is even, False otherwise.\n \n Args:\n n (int): A positive integer.\n \n Returns:\n bool: Whether the number of divisors is even.\n \"\"\"\n def count_divisors_helper(x):\n # Initialize a counter for divisors\n count = 0\n for i in range(1, x + 1):\n # Check if x is divisible by i\n if x % i == 0:\n count += 1\n return count\n \n # Ensure n is a positive integer\n if not isinstance(n, int) or n <= 0:\n raise ValueError(\"Input must be a positive integer.\")\n \n # Count divisors and return whether the count is even\n return count_divisors_helper(n) % 2 == 0", "matching_cluster_idx": 1}, {"solution": "def count_divisors(n):\n \"\"\"\n Counts the number of divisors of a number.\n \n Args:\n n (int): The number to count divisors for.\n \n Returns:\n bool: Whether the count of divisors is even.\n \"\"\"\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n count += 2 if i != n // i else 1\n return count % 2 == 0", "matching_cluster_idx": 4}, {"solution": "def count_divisors(n):\n \"\"\"\n Checks whether the count of divisors is even.\n\n Args:\n n (int): The number to check for even divisor count.\n\n Returns:\n bool: True if the count of divisors is even, False otherwise.\n \"\"\"\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count % 2 == 0", "matching_cluster_idx": 0}, {"solution": "def count_divisors(n):\n \"\"\"\n Checks whether the count of divisors of a number is even.\n \n Args:\n n (int): The number to check.\n \n Returns:\n bool: True if the count of divisors is even, False otherwise.\n \"\"\"\n # Initialize count of divisors to 0\n count = 0\n \n # Check all numbers from 1 to n\n for i in range(1, n + 1):\n # If i is a divisor of n, increment the count\n if n % i == 0:\n count += 1\n \n # Return True if count of divisors is even, False otherwise\n return count % 2 == 0", "matching_cluster_idx": 0}, {"solution": "def count_divisors(n):\n \"\"\"\n Check whether the count of divisors of a given number is even.\n \n Args:\n n (int): The input number to check for even divisors count.\n \n Returns:\n bool: True if the count of divisors is even, False otherwise.\n \"\"\"\n \n # Initialize counter for divisors\n divisor_count = 0\n \n # Check for divisors from 1 to n\n for i in range(1, n + 1):\n if n % i == 0:\n divisor_count += 1\n \n # Check if the count of divisors is even\n return divisor_count % 2 == 0", "matching_cluster_idx": 0}, {"solution": "def count_divisors(n):\n \"\"\"\n Checks whether the count of divisors for the given number is even.\n\n Args:\n n (int): The number to check.\n\n Returns:\n bool: True if the count of divisors is even, False otherwise.\n \"\"\"\n def count_divisor_count(num):\n # Initialize count of divisors\n count = 0\n\n # Count divisors\n for i in range(1, int(num ** 0.5) + 1):\n if num % i == 0:\n count += 2 if i != num // i else 1\n\n return count\n\n # Check if the divisor count is even\n return count_divisor_count(n) % 2 == 0", "matching_cluster_idx": 4}, {"solution": "def count_divisors(n):\n \"\"\"\n Check whether the count of divisors is even for a given number.\n \n Args:\n n (int): A positive integer.\n\n Returns:\n bool: True if the count of divisors is even, False otherwise.\n \"\"\"\n def count_divisor_count(n):\n \"\"\"\n Count the number of divisors for a given number.\n \n Args:\n n (int): A positive integer.\n\n Returns:\n int: The number of divisors of n.\n \"\"\"\n divisor_count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n divisor_count += 1\n return divisor_count\n\n return count_divisor_count(n) % 2 == 0", "matching_cluster_idx": 1}, {"solution": "def count_divisors(n):\n \"\"\"\n This function checks whether the count of divisors of a number is even.\n \n Args:\n n (int): The number to check.\n\n Returns:\n bool: True if the count of divisors is even, False otherwise.\n \"\"\"\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n # Count both the divisor and the corresponding quotient\n count += 2 if i != n // i else 1\n return count % 2 == 0", "matching_cluster_idx": 4}, {"solution": "def count_divisors(n):\n \"\"\"\n Checks whether the count of divisors of n is even.\n \n Args:\n n (int): A positive integer.\n \n Returns:\n bool: True if the count of divisors of n is even, False otherwise.\n \"\"\"\n def count(n):\n \"\"\"\n Counts the number of divisors of a given number.\n \n Args:\n n (int): A positive integer.\n \n Returns:\n int: The number of divisors of n.\n \"\"\"\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n count += 2 if i != n // i else 1\n return count\n \n return count(n) % 2 == 0", "matching_cluster_idx": 4}, {"solution": "def count_divisors(n):\n \"\"\"\n Check if the count of divisors of a number is even.\n\n Args:\n n (int): The number to check.\n\n Returns:\n bool: True if the count of divisors is even, False otherwise.\n \"\"\"\n def get_divisor_count(num):\n \"\"\"\n Get the count of divisors for a given number.\n\n Args:\n num (int): The number to get the divisor count for.\n\n Returns:\n int: The count of divisors.\n \"\"\"\n count = 0\n for i in range(1, num + 1):\n if num % i == 0:\n count += 1\n return count\n\n divisor_count = get_divisor_count(n)\n return divisor_count % 2 == 0", "matching_cluster_idx": 0}, {"solution": "def count_divisors(n):\n \"\"\"\n Counts the divisors of a given number and checks if the count is even.\n\n Args:\n n (int): The number to check for divisors.\n\n Returns:\n bool: True if the count of divisors is even, False otherwise.\n \"\"\"\n def count_divisor_count(num):\n # Initialize a counter for the number of divisors\n count = 0\n # Check all numbers from 1 to num\n for i in range(1, num + 1):\n # If num is divisible by i, increment the counter\n if num % i == 0:\n count += 1\n return count\n\n # Get the count of divisors for the given number\n divisor_count = count_divisor_count(n)\n # Return whether the count is even\n return divisor_count % 2 == 0", "matching_cluster_idx": 0}, {"solution": "def count_divisors(n):\n \"\"\"\n Counts the number of divisors of a given number.\n Args:\n n (int): The number to count divisors for.\n Returns:\n bool: True if the count of divisors is even, False otherwise.\n \"\"\"\n def count(n):\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count\n\n return count(n) % 2 == 0", "matching_cluster_idx": 1}, {"solution": "def count_divisors(n):\n \"\"\"\n Counts the number of divisors of a number n.\n\n Returns:\n bool: True if the count of divisors is even, False otherwise.\n \"\"\"\n def count(n):\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n if n // i == i: # If i is a square root of n\n count += 1\n else:\n count += 2\n return count\n\n divisors_count = count(n)\n return divisors_count % 2 == 0", "matching_cluster_idx": 4}, {"solution": "def count_divisors(n):\n \"\"\"\n This function counts the number of divisors for a given number 'n'.\n A divisor is a number that divides another number without leaving a remainder.\n It then checks whether the count of divisors is even.\n \n Args:\n n (int): The input number for which the count of divisors is to be determined.\n \n Returns:\n bool: True if the count of divisors is even, False otherwise.\n \"\"\"\n \n # Initialize a counter variable to store the number of divisors\n count = 0\n \n # Iterate over all numbers from 1 to the input number (inclusive)\n for i in range(1, n + 1):\n # Check if 'i' is a divisor of 'n'\n if n % i == 0:\n # If 'i' is a divisor, increment the counter\n count += 1\n \n # Check if the count of divisors is even\n return count % 2 == 0", "matching_cluster_idx": 0}, {"solution": "def count_divisors(n):\n \"\"\"\n This function checks if the number of divisors of the given number n is even.\n\n Args:\n n (int): A positive integer.\n\n Returns:\n bool: True if the number of divisors is even, False otherwise.\n \"\"\"\n divisors = [i for i in range(1, n + 1) if n % i == 0]\n return len(divisors) % 2 == 0", "matching_cluster_idx": 1}, {"solution": "def count_divisors(n):\n \"\"\"\n Checks whether the count of divisors of a number is even or not.\n\n Args:\n n (int): The input number to find divisors for.\n\n Returns:\n bool: True if the count of divisors is even, False otherwise.\n\n Raises:\n TypeError: If the input is not an integer.\n \"\"\"\n if not isinstance(n, int):\n raise TypeError(\"Input must be an integer\")\n\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n\n return count % 2 == 0", "matching_cluster_idx": 0}, {"solution": "def count_divisors(n):\n \"\"\"\n Check whether the count of divisors is even.\n\n Args:\n n (int): The input number to check.\n\n Returns:\n bool: True if the count of divisors is even, False otherwise.\n \"\"\"\n # Initialize the count of divisors\n count = 0\n\n # Iterate through all numbers from 1 to n (inclusive)\n for i in range(1, n + 1):\n # If i is a divisor of n, increment the count\n if n % i == 0:\n count += 1\n\n # Return True if the count of divisors is even, False otherwise\n return count % 2 == 0", "matching_cluster_idx": 0}, {"solution": "def count_divisors(n):\n \"\"\"\n Checks if the count of divisors of n is even.\n\n Args:\n n (int): A positive integer.\n\n Returns:\n bool: True if the count of divisors is even, False otherwise.\n \"\"\"\n # Check for edge case where n is 0\n if n <= 0:\n return False\n \n # Initialize count variable\n count = 0\n \n # Count the number of divisors of n\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n \n # Check if the count of divisors is even\n return count % 2 == 0", "matching_cluster_idx": 0}]}, "Mbpp/800": {"dps": 95.14925373134328, "dps_norm": 95.0, "pass@1": 99.0, "profiled": [{"solution": "def remove_all_spaces(s):\n \"\"\"\n This function removes all spaces from a given string.\n \n Parameters:\n s (str): The input string.\n \n Returns:\n str: A string with all spaces removed.\n \"\"\"\n # Using the replace() method to replace all spaces with nothing, effectively removing them\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_str):\n \"\"\"\n This function removes all the spaces from a given input string.\n\n Args:\n input_str (str): The input string from which to remove spaces.\n\n Returns:\n str: The string with all spaces removed.\n \"\"\"\n # Use the replace() method to replace all spaces with nothing\n # Thus effectively removing all spaces\n return input_str.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(s):\n \"\"\"\n This function removes all spaces from a given string.\n \n Args:\n s (str): The string from which spaces are to be removed.\n \n Returns:\n str: The string without spaces.\n \"\"\"\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(s):\n \"\"\"\n Removes all whitespaces from a given string.\n\n Args:\n s (str): The input string.\n\n Returns:\n str: The input string with all whitespaces removed.\n\n Example:\n >>> remove_all_spaces('python program')\n 'pythonprogram'\n \"\"\"\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(s):\n \"\"\"\n This function removes all the whitespaces from a given string.\n\n Parameters:\n s (str): The input string from which whitespaces are to be removed.\n\n Returns:\n str: A new string without any whitespaces.\n \"\"\"\n return s.replace(' ', '')", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(s):\n \"\"\"\n This function removes all the whitespaces from a given string.\n\n Parameters:\n s (str): The input string.\n\n Returns:\n str: The string without any whitespaces.\n \"\"\"\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(s):\n \"\"\"\n Removes all whitespaces from a given string.\n\n Args:\n s (str): The input string.\n\n Returns:\n str: The string without any whitespaces.\n \"\"\"\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(s):\n \"\"\"\n This function removes all spaces from a given string.\n\n Args:\n s (str): Input string.\n\n Returns:\n str: String without spaces.\n \"\"\"\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(s):\n \"\"\"\n This function removes all whitespaces from a given string.\n \n Parameters:\n s (str): The string from which whitespaces are to be removed.\n \n Returns:\n str: A string with all whitespaces removed.\n \"\"\"\n # Use the str.translate method and str.maketrans to remove all spaces\n return s.translate(str.maketrans('', '', ' '))", "matching_cluster_idx": 3}, {"solution": "def remove_all_spaces(input_str):\n \"\"\"\n Removes all spaces from a given input string.\n \n Args:\n input_str (str): The input string from which spaces are to be removed.\n \n Returns:\n str: The input string with all spaces removed.\n \"\"\"\n # Use the replace() method of the string class to replace all spaces with an empty string\n return input_str.replace(' ', '')", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(s):\n \"\"\"\n Remove all whitespaces from a string.\n \n Parameters:\n s (str): The input string from which whitespaces will be removed.\n \n Returns:\n str: A string with all whitespaces removed.\n \"\"\"\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n \"\"\"\n This function takes a string as an input and returns a new string with all whitespaces removed.\n\n Args:\n input_string (str): The input string from which whitespaces are to be removed.\n\n Returns:\n str: The input string with all whitespaces removed.\n \"\"\"\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n \"\"\"\n This function removes all spaces from a given string.\n \n Parameters:\n input_string (str): The string from which whitespaces are to be removed.\n \n Returns:\n str: The string with all whitespaces removed.\n \"\"\"\n \n # Use a list comprehension to create a new string without whitespaces\n new_string = ''.join([char for char in input_string if char != ' '])\n \n return new_string", "matching_cluster_idx": 0}, {"solution": "def remove_all_spaces(input_string):\n \"\"\"\n This function removes all whitespaces from a given string.\n \n Args:\n input_string (str): The string from which whitespaces are to be removed.\n \n Returns:\n str: The input string without any whitespaces.\n \"\"\"\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n \"\"\"\n This function takes a string as input and returns the string without any whitespaces.\n \n Args:\n input_string (str): The input string from which whitespaces are to be removed.\n \n Returns:\n str: The string without any whitespaces.\n \"\"\"\n \n # Using the replace method to replace all spaces with an empty string\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n \"\"\"\n Removes all whitespaces from a given string.\n\n Args:\n input_string (str): The string from which to remove whitespaces.\n\n Returns:\n str: The input string with all whitespaces removed.\n \"\"\"\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(s):\n \"\"\"\n This function removes all whitespaces from a given string.\n\n Args:\n s (str): The input string from which whitespaces will be removed.\n\n Returns:\n str: A new string with all whitespaces removed.\n \"\"\"\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n \"\"\"\n This function removes all whitespaces from a given string.\n\n Parameters:\n input_string (str): The input string from which spaces need to be removed.\n\n Returns:\n str: The string without any spaces.\n \"\"\"\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(s):\n \"\"\"\n Removes all spaces from the input string.\n \n Args:\n s (str): The input string from which spaces need to be removed.\n \n Returns:\n str: The input string with all spaces removed.\n \"\"\"\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(s):\n \"\"\"\n This function removes all whitespaces from a given string.\n\n Args:\n s (str): The input string to be processed.\n\n Returns:\n str: The string with all whitespaces removed.\n \"\"\"\n # Use the replace method of the string to replace all spaces with an empty string\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}]}, "Mbpp/805": {"dps": 95.03436426116839, "dps_norm": 96.0, "pass@1": 97.0, "profiled": [{"solution": "def max_sum_list(list_of_lists):\n \"\"\"\n This function returns the list in a list of lists whose sum of elements is the highest.\n\n Args:\n list_of_lists (list): A list containing multiple lists of numbers.\n\n Returns:\n list: The list from the input list whose sum of elements is the highest.\n\n \"\"\"\n return max(list_of_lists, key=sum)\nlist_of_lists = [[1,2,3], [4,5,6], [10,11,12], [7,8,9]]", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n \"\"\"\n Returns the list from the list of lists that has the highest sum of its elements.\n\n Args:\n lists (list): A list of lists.\n\n Returns:\n list: The list from the list of lists with the highest sum.\n \"\"\"\n # Use the max function with a key to find the list with the maximum sum\n return max(lists, key=sum)", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(list_of_lists):\n \"\"\"\n This function returns the list in a list of lists whose sum of elements is the highest.\n \n Parameters:\n list_of_lists (list): A list of lists, where each sublist contains numbers.\n \n Returns:\n list: The sublist with the highest sum of elements.\n \"\"\"\n \n # Initialize the maximum sum and the corresponding list\n max_sum = float('-inf')\n max_list = None\n \n # Iterate over each sublist in the list of lists\n for lst in list_of_lists:\n # Calculate the sum of the current sublist\n current_sum = sum(lst)\n \n # If the current sum is greater than the max sum, update max sum and max list\n if current_sum > max_sum:\n max_sum = current_sum\n max_list = lst\n \n # Return the list with the highest sum\n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n \"\"\"\n Returns the list in a list of lists whose sum of elements is the highest.\n \n Args:\n lists (list): A list of lists, each containing integers.\n \n Returns:\n list: The list whose sum is the maximum.\n \"\"\"\n return max(lists, key=sum)", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n \"\"\"\n This function returns the list in a list of lists whose sum of elements is the highest.\n \n Args:\n lists (list): A list of lists where each sublist contains integers.\n \n Returns:\n list: The list in the list of lists with the maximum sum.\n \"\"\"\n return max(lists, key=sum)", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists_of_lists):\n \"\"\"\n Returns the list in a list of lists whose sum of elements is the highest.\n\n Args:\n lists_of_lists (list): A list containing lists of numbers.\n\n Returns:\n list: The list with the highest sum of elements.\n\n Raises:\n ValueError: If the input list is empty.\n \"\"\"\n if not lists_of_lists:\n raise ValueError(\"Input list cannot be empty\")\n\n max_sum = float('-inf')\n max_list = None\n for lst in lists_of_lists:\n current_sum = sum(lst)\n if current_sum > max_sum:\n max_sum = current_sum\n max_list = lst\n\n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n \"\"\"\n This function finds the list in a list of lists whose sum of elements is the highest.\n \n Args:\n lists (list): A list of lists where each sublist contains integers.\n \n Returns:\n list: The list with the highest sum of elements.\n \"\"\"\n \n # Initialize the maximum sum and the list with the maximum sum\n max_sum = float('-inf')\n max_list = None\n \n # Iterate over each list in the given list of lists\n for lst in lists:\n # Calculate the sum of the current list\n current_sum = sum(lst)\n \n # If the current sum is greater than the maximum sum, update the maximum sum and the list with the maximum sum\n if current_sum > max_sum:\n max_sum = current_sum\n max_list = lst\n \n # Return the list with the maximum sum\n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n \"\"\"\n Returns the list in a list of lists whose sum of elements is the highest.\n\n Args:\n lists (list): A list of lists of integers.\n\n Returns:\n list: The list in the input list of lists whose sum of elements is the highest.\n \"\"\"\n return max(lists, key=sum)", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(list_of_lists):\n \"\"\"\n This function finds the list in a list of lists with the highest sum of elements.\n\n Args:\n list_of_lists (list): A list of lists containing integers.\n\n Returns:\n list: The list with the highest sum of elements.\n\n Raises:\n ValueError: If the input list is empty.\n \"\"\"\n # Check if the input list is empty\n if not list_of_lists:\n raise ValueError(\"Input list cannot be empty\")\n\n # Initialize max_sum and max_list variables with the sum and the first list of the input\n max_sum = sum(list_of_lists[0])\n max_list = list_of_lists[0]\n\n # Iterate over each list in the input list of lists\n for lst in list_of_lists:\n # Calculate the sum of the current list\n current_sum = sum(lst)\n \n # Check if the sum of the current list is higher than the max_sum\n if current_sum > max_sum:\n # Update max_sum and max_list if the current sum is higher\n max_sum = current_sum\n max_list = lst\n\n # Return the list with the highest sum\n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists_of_lists):\n \"\"\"\n Returns the list from a list of lists with the highest sum of elements.\n\n Args:\n lists_of_lists (list): A list containing lists of numbers.\n\n Returns:\n list: The list with the highest sum of elements.\n \"\"\"\n # Use the max function with a key argument to find the list with the maximum sum\n return max(lists_of_lists, key=sum)", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists_of_lists):\n \"\"\"\n This function finds the list in a list of lists with the highest sum of elements.\n \n Args:\n lists_of_lists (list): A list of lists where each sublist contains integers.\n \n Returns:\n list: The list in the input list of lists whose sum of elements is the highest.\n \"\"\"\n return max(lists_of_lists, key=sum)\nlists_of_lists = [[1,2,3], [4,5,6], [10,11,12], [7,8,9]]", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n \"\"\"\n Returns the list in a list of lists whose sum of elements is the highest.\n\n Args:\n lists (list): A list of lists of numbers.\n\n Returns:\n list: The list in the input with the maximum sum of its elements.\n \"\"\"\n # Initialize max_sum and max_list variables with the sum and list of the first element in the list of lists\n max_sum = sum(lists[0])\n max_list = lists[0]\n\n # Iterate over each sublist in the list of lists\n for sublist in lists:\n # Calculate the sum of the current sublist\n current_sum = sum(sublist)\n \n # If the current sum is greater than max_sum, update max_sum and max_list\n if current_sum > max_sum:\n max_sum = current_sum\n max_list = sublist\n\n # Return the sublist with the maximum sum\n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n \"\"\"\n Returns the list in a list of lists whose sum of elements is the highest.\n\n Args:\n lists (list of lists): A list of lists containing integers.\n\n Returns:\n list: The list with the highest sum of elements.\n\n \"\"\"\n # Calculate the sum of each list and store it as a tuple along with the original list\n list_sums = [(sum(lst), lst) for lst in lists]\n \n # Find the tuple with the highest sum\n max_sum_tuple = max(list_sums)\n \n # Return the list from the max_sum_tuple\n return max_sum_tuple[1]", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n \"\"\"\n This function finds the list in a list of lists whose sum of elements is the highest.\n \n Parameters:\n lists (list): A list of lists of numbers.\n \n Returns:\n list: The list whose sum of elements is the highest.\n \"\"\"\n # Initialize the maximum sum and the list with the maximum sum\n max_sum = float('-inf')\n max_sum_list = None\n \n # Iterate over each list in the given list of lists\n for lst in lists:\n # Calculate the sum of the current list\n current_sum = sum(lst)\n \n # If the current sum is greater than the maximum sum found so far, update max_sum and max_sum_list\n if current_sum > max_sum:\n max_sum = current_sum\n max_sum_list = lst\n \n # Return the list with the maximum sum\n return max_sum_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n \"\"\"\n Returns the list in a list of lists whose sum of elements is the highest.\n\n Args:\n lists (list): A list of lists of integers.\n\n Returns:\n list: The list with the highest sum of elements.\n \"\"\"\n # Use a list comprehension to generate a list of pairs (list, sum) where sum is the sum of the list's elements\n # Then, use the max function with a key argument to find the pair with the maximum sum\n # Finally, use another list comprehension to return the first element of the maximum pair\n return max((lst for lst in lists), key=sum, default=[])", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n \"\"\"\n This function takes a list of lists as input and returns the list within the list \n whose elements sum up to the highest.\n \n Parameters:\n lists (list): A list of lists of integers.\n \n Returns:\n list: The list with the highest sum of elements.\n \"\"\"\n # Use the built-in sum function with a map function to calculate the sum of each sublist\n sums = [sum(map(int, lst)) for lst in lists]\n \n # Get the maximum sum\n max_sum = max(sums)\n \n # Get the index of the maximum sum in the sums list\n max_index = sums.index(max_sum)\n \n # Return the list at the index of the maximum sum\n return lists[max_index]", "matching_cluster_idx": 0}, {"solution": "def max_sum_list(lists):\n \"\"\"\n Returns the list from a list of lists with the highest sum of elements.\n\n Args:\n lists (list): A list of lists containing integers.\n\n Returns:\n list: The list with the highest sum of elements.\n\n Raises:\n ValueError: If the input list is empty.\n \"\"\"\n if not lists:\n raise ValueError(\"Input list cannot be empty\")\n\n max_sum = float('-inf')\n max_sum_list = None\n\n for lst in lists:\n current_sum = sum(lst)\n if current_sum > max_sum:\n max_sum = current_sum\n max_sum_list = lst\n\n return max_sum_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(list_of_lists):\n \"\"\"\n This function returns the list in a list of lists whose sum of elements is the highest.\n \n Parameters:\n list_of_lists (list): A list of lists of integers or floats.\n \n Returns:\n list: The list whose sum is the highest.\n \"\"\"\n \n # Use a list comprehension to create a new list with tuples of the list and its sum\n list_with_sums = [(lst, sum(lst)) for lst in list_of_lists]\n \n # Find the tuple with the highest sum\n max_sum_tuple = max(list_with_sums, key=lambda x: x[1])\n \n # Return the list with the highest sum\n return max_sum_tuple[0]", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n \"\"\"\n This function finds the list in a list of lists with the maximum sum of elements.\n\n Args:\n lists (list): A list of lists of integers.\n\n Returns:\n list: The list with the maximum sum of elements.\n \"\"\"\n max_sum = float('-inf') # Initialize max_sum as negative infinity\n max_list = None\n\n # Iterate over each list in the list of lists\n for lst in lists:\n # Calculate the sum of elements in the current list\n current_sum = sum(lst)\n \n # If the current sum is greater than max_sum, update max_sum and max_list\n if current_sum > max_sum:\n max_sum = current_sum\n max_list = lst\n\n # Return the list with the maximum sum of elements\n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n \"\"\"\n Returns the list from a list of lists whose sum of elements is the highest.\n\n Args:\n lists (list of lists): A list containing lists of numbers.\n\n Returns:\n list: The list with the highest sum of its elements.\n\n \"\"\"\n return max(lists, key=sum)", "matching_cluster_idx": 4}]}, "Mbpp/808": {"dps": 96.53508771929825, "dps_norm": 99.16666666666667, "pass@1": 95.0, "profiled": [{"solution": "def check_K(tup, k):\n \"\"\"\n This function checks if the given tuple contains the element 'k' or not.\n \n Args:\n tup (tuple): The input tuple to be searched.\n k (any): The element to be searched in the tuple.\n \n Returns:\n bool: True if the tuple contains the element, False otherwise.\n \"\"\"\n \n # Check if the tuple contains the element 'k'\n return k in tup", "matching_cluster_idx": 4}, {"solution": "def check_K(tup, k):\n \"\"\"\n Check if a given tuple contains the element k.\n\n Args:\n tup (tuple): Input tuple to be checked.\n k: The element to be searched in the tuple.\n\n Returns:\n bool: True if k is present in the tuple, False otherwise.\n \"\"\"\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n \"\"\"\n This function checks if the given tuple contains the number k.\n \n Parameters:\n tup (tuple): Input tuple to search for k.\n k (int): Target number to search in the tuple.\n \n Returns:\n bool: True if the tuple contains k, False otherwise.\n \"\"\"\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n \"\"\"\n This function checks if the given tuple contains the value k or not.\n\n Args:\n tup (tuple): The tuple to be checked.\n k: The value to be searched.\n\n Returns:\n bool: True if k is in the tuple, False otherwise.\n \"\"\"\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n \"\"\"\n Checks if the given tuple contains the value k.\n \n Args:\n tup (tuple): A tuple of integers.\n k (int): An integer to be searched in the tuple.\n \n Returns:\n bool: True if the tuple contains the value k, False otherwise.\n \"\"\"\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n \"\"\"\n Check if a given number 'k' exists in the tuple 'tup'.\n\n Args:\n tup (tuple): The input tuple to search for 'k'.\n k (int): The number to search for in the tuple.\n\n Returns:\n bool: True if 'k' exists in the tuple, False otherwise.\n \"\"\"\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(tuple_, k):\n \"\"\"\n This function checks if the given tuple contains the number k.\n\n Args:\n tuple_ (tuple): A tuple of integers\n k (int): The number to search for in the tuple\n\n Returns:\n bool: True if k is in the tuple, False otherwise\n \"\"\"\n return k in tuple_", "matching_cluster_idx": 5}, {"solution": "def check_K(lst, k):\n \"\"\"\n Check if the given list of integers contains the number k.\n\n Args:\n lst (tuple): A tuple of integers.\n k (int): The number to be searched.\n\n Returns:\n bool: True if the number k is found in the tuple, False otherwise.\n \"\"\"\n return k in lst", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n \"\"\"\n Check if a tuple contains the element k.\n\n Args:\n tup (tuple): Input tuple to check.\n k (int): Element to search for.\n\n Returns:\n bool: True if the tuple contains k, False otherwise.\n \"\"\"\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n \"\"\"\n Checks if the given tuple contains the number k.\n\n Args:\n tup (tuple): A tuple of integers.\n k (int): The number to check for.\n\n Returns:\n bool: True if k is in the tuple, False otherwise.\n \"\"\"\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(lst, k):\n \"\"\"\n This function checks if the given list contains the number k.\n \n Args:\n lst (tuple): A tuple of integers.\n k (int): The number to be searched.\n\n Returns:\n bool: True if the list contains k, False otherwise.\n \"\"\"\n return k in lst", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n \"\"\"\n Checks if a given tuple contains the value k.\n \n Args:\n tup (tuple): The input tuple to be checked.\n k: The value to be searched in the tuple.\n \n Returns:\n bool: True if the tuple contains k, False otherwise.\n \"\"\"\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n \"\"\"\n This function checks if the given tuple contains the number k.\n\n Args:\n tup (tuple): The input tuple to be checked.\n k (int): The number to be searched in the tuple.\n\n Returns:\n bool: True if k is found in the tuple, False otherwise.\n \"\"\"\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(lst, k):\n \"\"\"\n Checks if tuple lst contains the value k.\n\n Args:\n lst (tuple): A tuple of numbers.\n k (int): The number to be searched in the tuple.\n\n Returns:\n bool: True if the tuple contains the number k, False otherwise.\n \"\"\"\n return k in lst", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n \"\"\"\n This function checks if a given integer exists in a tuple.\n \n Parameters:\n tup (tuple): Input tuple to search for an integer.\n k (int): The integer to be searched.\n \n Returns:\n bool: True if k is in the tuple, False otherwise.\n \"\"\"\n # Check if k exists in the tuple\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n \"\"\"\n Check if the given tuple contains the number k.\n\n Args:\n tup (tuple): A tuple of integers.\n k (int): The number to search for in the tuple.\n\n Returns:\n bool: True if the tuple contains k, False otherwise.\n \"\"\"\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(t, k):\n \"\"\"\n Check if a given tuple contains the number k.\n \n Args:\n t (tuple): The input tuple to check.\n k: The number to look for.\n \n Returns:\n bool: True if k is found in the tuple, False otherwise.\n \"\"\"\n return k in t", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n \"\"\"\n Checks if a tuple contains the number k.\n \n Args:\n tup (tuple): A tuple containing integers.\n k (int): The number to be searched in the tuple.\n \n Returns:\n bool: True if k is in the tuple, False otherwise.\n \"\"\"\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n \"\"\"\n Checks if a given tuple contains the value k.\n \n Parameters:\n tup (tuple): The input tuple to be checked.\n k: The value to be searched in the tuple.\n \n Returns:\n bool: True if the tuple contains the value k, False otherwise.\n \"\"\"\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, K):\n \"\"\"\n Checks if the given tuple contains the value K.\n\n Args:\n tup (tuple): The input tuple to search in.\n K: The value to search for.\n\n Returns:\n bool: True if K is found in the tuple, False otherwise.\n \"\"\"\n return K in tup", "matching_cluster_idx": 5}]}}} \ No newline at end of file diff --git a/results/evalperf/mistralai--Codestral-22B-v0.1_vllm_temp_1.0_evalperf_results.brief.json b/results/evalperf/mistralai--Codestral-22B-v0.1_vllm_temp_1.0_evalperf_results.brief.json new file mode 100644 index 0000000..89d19d0 --- /dev/null +++ b/results/evalperf/mistralai--Codestral-22B-v0.1_vllm_temp_1.0_evalperf_results.brief.json @@ -0,0 +1 @@ +{"date": "2024-10-19 16:32", "config": {"n_samples": 100, "temperature": 1.0, "min_correct": 10, "max_profile": 20}, "summary": {"dps": 82.68924330620962, "dps_norm": 79.07819827252048, "pass@1": 72.83898305084746}, "eval": {"HumanEval/9": {"dps": 69.29022082018928, "dps_norm": 63.88888888888889, "pass@1": 100.0, "profiled": [{"solution": "from typing import List, Tuple\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n\n result = [numbers[0]]\n\n for i in range(1, len(numbers)):\n result.append(max(result[i-1], numbers[i]))\n\n return result", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n rolling_max_list = []\n curr_max = float('-inf')\n\n for num in numbers:\n if num > curr_max:\n curr_max = num\n rolling_max_list.append(curr_max)\n\n return rolling_max_list", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\"\n From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n \"\"\"\n if not numbers:\n return []\n\n result = [numbers[0]]\n max_so_far = numbers[0]\n for i in range(1, len(numbers)):\n if numbers[i] > max_so_far:\n max_so_far = numbers[i]\n result.append(max_so_far)\n return result", "matching_cluster_idx": 7}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n max_so_far = float('-inf')\n result = []\n\n for number in numbers:\n max_so_far = max(max_so_far, number)\n result.append(max_so_far)\n\n return result", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n \"\"\"\n if not numbers:\n return []\n\n rolling_max_list = [numbers[0]]\n\n for number in numbers[1:]:\n rolling_max_list.append(max(rolling_max_list[-1], number))\n\n return rolling_max_list", "matching_cluster_idx": 4}, {"solution": "from typing import List, Tuple\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n \"\"\"\n if not numbers:\n return []\n\n result = [numbers[0]]\n for num in numbers[1:]:\n result.append(max(result[-1], num))\n return result", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n rolling_max_numbers = []\n max_so_far = float('-inf')\n\n for num in numbers:\n if num > max_so_far:\n max_so_far = num\n rolling_max_numbers.append(max_so_far)\n\n return rolling_max_numbers", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n \"\"\"\n if not numbers:\n return []\n\n result = [numbers[0]]\n for num in numbers[1:]:\n result.append(max(result[-1], num))\n\n return result", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n if not numbers:\n return []\n\n result = [numbers[0]]\n for num in numbers[1:]:\n result.append(max(result[-1], num))\n\n return result", "matching_cluster_idx": 4}, {"solution": "from typing import List, Tuple\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\"From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n else:\n result = [numbers[0]]\n for num in numbers[1:]:\n result.append(max(result[-1], num))\n return result", "matching_cluster_idx": 4}, {"solution": "from typing import List, Tuple\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n \"\"\"\n rolling_max_list = []\n current_max = float('-inf')\n for num in numbers:\n current_max = max(current_max, num)\n rolling_max_list.append(current_max)\n return rolling_max_list", "matching_cluster_idx": 4}, {"solution": "from typing import List, Tuple\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\"\n From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n \"\"\"\n if not numbers:\n return []\n max_numbers = [numbers[0]]\n for number in numbers[1:]:\n max_numbers.append(max(max_numbers[-1], number))\n return max_numbers", "matching_cluster_idx": 4}, {"solution": "from typing import List, Tuple\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n max_list = []\n max_so_far = float('-inf')\n for num in numbers:\n max_so_far = max(max_so_far, num)\n max_list.append(max_so_far)\n return max_list", "matching_cluster_idx": 4}, {"solution": "from typing import List, Tuple\ndef rolling_max(numbers: List[int]) -> List[int]:\n if not numbers:\n return []\n\n rolling_max_list = [numbers[0]]\n for num in numbers[1:]:\n rolling_max_list.append(max(rolling_max_list[-1], num))\n return rolling_max_list", "matching_cluster_idx": 4}, {"solution": "from typing import List, Tuple\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\"\n From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n \"\"\"\n result = []\n if not numbers:\n return result\n\n current_max = numbers[0]\n for num in numbers:\n current_max = max(current_max, num)\n result.append(current_max)\n\n return result", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n \"\"\"\n if not numbers:\n return []\n\n result = []\n max_num = numbers[0]\n\n for num in numbers:\n if num > max_num:\n max_num = num\n result.append(max_num)\n\n return result", "matching_cluster_idx": 8}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\"\n From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n \"\"\"\n max_so_far = float('-inf')\n result = []\n\n for num in numbers:\n max_so_far = max(max_so_far, num)\n result.append(max_so_far)\n\n return result", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n if not numbers:\n return []\n\n result = [numbers[0]]\n max_so_far = numbers[0]\n\n for num in numbers[1:]:\n max_so_far = max(max_so_far, num)\n result.append(max_so_far)\n\n return result", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n \"\"\"\n if not numbers:\n return []\n\n max_num = numbers[0]\n rolling_max_nums = [max_num]\n for num in numbers[1:]:\n max_num = max(max_num, num)\n rolling_max_nums.append(max_num)\n\n return rolling_max_nums", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n max_so_far = float('-inf')\n rolling_max_values = []\n\n for num in numbers:\n max_so_far = max(max_so_far, num)\n rolling_max_values.append(max_so_far)\n\n return rolling_max_values", "matching_cluster_idx": 4}]}, "HumanEval/0": {"dps": 69.01162790697674, "dps_norm": 72.14285714285714, "pass@1": 100.0, "profiled": [{"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\"\n Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n \"\"\"\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n if abs(numbers[i] - numbers[j]) < threshold:\n return True\n return False", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n \"\"\"\n # sort the list in ascending order\n numbers.sort()\n\n # iterate through the list and check if difference between consecutive numbers is less than threshold\n for i in range(len(numbers) - 1):\n if numbers[i + 1] - numbers[i] < threshold:\n return True\n\n # if no two numbers are close enough, return False\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n \"\"\"\n numbers.sort() # Sort the list of numbers\n for i in range(1, len(numbers)):\n if numbers[i] - numbers[i - 1] < threshold: # If the difference between any two adjacent numbers is less than the threshold\n return True # Return True\n return False # If no two numbers are closer than the threshold, return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n \"\"\"\n for i in range(len(numbers)):\n for j in range(i+1, len(numbers)):\n if abs(numbers[i] - numbers[j]) < threshold:\n return True\n return False", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n # Sort the list in increasing order\n numbers.sort()\n\n # Iterate over the sorted list and check if any two numbers\n # are closer to each other than the given threshold\n for i in range(len(numbers) - 1):\n if numbers[i + 1] - numbers[i] < threshold:\n return True\n\n # If no two close numbers are found, return False\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n # Sort the list of numbers\n numbers.sort()\n\n # Iterate over the sorted list\n for i in range(len(numbers) - 1):\n # Check if the difference between two adjacent numbers is less than the threshold\n if numbers[i + 1] - numbers[i] < threshold:\n # If yes, return True\n return True\n # If no two adjacent numbers are close enough to each other, return False\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n for i in range(len(numbers)):\n for j in range(i+1, len(numbers)):\n if abs(numbers[i] - numbers[j]) < threshold:\n return True\n return False", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\"Check if in given list of numbers, are any two numbers closer to each other than given threshold.\"\"\"\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n if abs(numbers[i] - numbers[j]) < threshold:\n return True\n return False", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n numbers.sort()\n for i in range(len(numbers) - 1):\n if numbers[i+1] - numbers[i] < threshold:\n return True\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n numbers.sort()\n\n for i in range(1, len(numbers)):\n if numbers[i] - numbers[i-1] < threshold:\n return True\n\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n numbers.sort() # sort the list of numbers\n for i in range(len(numbers)-1): # iterate through sorted list\n if numbers[i+1] - numbers[i] < threshold: # check if difference between consecutive elements is less than threshold\n return True # return True if any pair is within threshold\n return False # return False if no pair is within threshold", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n for i in range(len(numbers)):\n for j in range(i+1, len(numbers)):\n if abs(numbers[i] - numbers[j]) < threshold:\n return True\n return False", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n \"\"\"\n numbers.sort()\n for i in range(1, len(numbers)):\n if numbers[i] - numbers[i-1] < threshold:\n return True\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n # Sort the numbers list in ascending order\n numbers.sort()\n\n # Compare each pair of consecutive numbers\n for i in range(1, len(numbers)):\n # If the difference between a pair of numbers is smaller than the threshold\n if numbers[i] - numbers[i - 1] < threshold:\n # Return True as close numbers are found\n return True\n\n # Return False as no close numbers are found\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n if abs(numbers[i] - numbers[j]) < threshold:\n return True\n return False", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n numbers.sort() # Sort the numbers to make it easier to find close elements\n for i in range(len(numbers) - 1):\n if numbers[i + 1] - numbers[i] < threshold: # If any two adjacent elements are closer than threshold\n return True\n return False # If no two elements are closer than threshold", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\"\n Check if in the given list of numbers, are any two numbers closer to each other than\n the given threshold.\n \"\"\"\n # sort the list\n numbers.sort()\n\n # iterate through the sorted list\n for i in range(1, len(numbers)):\n # if the difference between any two adjacent numbers is less than threshold\n if numbers[i] - numbers[i-1] < threshold:\n return True\n # if no pair with difference less than threshold is found\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n # Sort the list of numbers\n numbers.sort()\n\n # Iterate over the sorted list\n for i in range(len(numbers) - 1):\n # Check if any two adjacent numbers are closer to each other than the threshold\n if numbers[i + 1] - numbers[i] < threshold:\n return True\n\n # If no such pair is found, return False\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n # Sort the list of numbers\n numbers.sort()\n\n # Iterate over the sorted list\n for i in range(len(numbers) - 1):\n # If the difference between two consecutive numbers is less than the threshold, return True\n if numbers[i + 1] - numbers[i] < threshold:\n return True\n\n # If no two consecutive numbers are close to each other than the threshold, return False\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\"\n Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n \"\"\"\n for i in range(len(numbers)):\n for j in range(i+1, len(numbers)):\n if abs(numbers[i] - numbers[j]) < threshold:\n return True\n return False", "matching_cluster_idx": 6}]}, "HumanEval/4": {"dps": 83.63924050632912, "dps_norm": 91.66666666666667, "pass@1": 100.0, "profiled": [{"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\"\n For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n \"\"\"\n if not numbers:\n return 0\n\n mean = sum(numbers) / len(numbers)\n return sum(abs(number - mean) for number in numbers) / len(numbers)", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n # First, we compute the mean of the numbers\n mean_value = sum(numbers) / len(numbers)\n\n # Now, we compute the Mean Absolute Deviation\n mad = sum(abs(number - mean_value) for number in numbers) / len(numbers)\n\n return mad", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\"\n For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n \"\"\"\n mean = sum(numbers) / len(numbers)\n deviations = [abs(x - mean) for x in numbers]\n return sum(deviations) / len(deviations)", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\"For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n Args:\n numbers (List[float]): a list of floats representing the numbers.\n\n Returns:\n float: the mean absolute deviation of the numbers in the list.\n\n \"\"\"\n mean = sum(numbers) / len(numbers)\n mad = sum(abs(x - mean) for x in numbers) / len(numbers)\n return mad", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n mean = sum(numbers) / len(numbers)\n return sum(abs(number - mean) for number in numbers) / len(numbers)", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n mean = sum(numbers) / len(numbers)\n deviations = [abs(x - mean) for x in numbers]\n mad = sum(deviations) / len(deviations)\n return mad", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n mean = sum(numbers) / len(numbers)\n mad = sum(abs(x - mean) for x in numbers) / len(numbers)\n return mad", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n \"\"\"\n # Calculate mean of the dataset\n mean = sum(numbers) / len(numbers)\n # Calculate absolute differences from the mean\n abs_diff = [abs(num - mean) for num in numbers]\n # Calculate Mean Absolute Deviation\n mad = sum(abs_diff) / len(abs_diff)\n return mad", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n mean = sum(numbers) / len(numbers)\n deviation_sum = sum(abs(num - mean) for num in numbers)\n return deviation_sum / len(numbers)", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n mean = sum(numbers) / len(numbers)\n return sum(abs(num - mean) for num in numbers) / len(numbers)", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n \"\"\"\n mean_num = sum(numbers) / len(numbers)\n deviations = [abs(num - mean_num) for num in numbers]\n mad = sum(deviations) / len(numbers)\n return mad", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n n = len(numbers)\n mean = sum(numbers) / n\n mad = sum(abs(num - mean) for num in numbers) / n\n return mad", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n mean = sum(numbers) / len(numbers)\n deviations = [abs(number - mean) for number in numbers]\n mad = sum(deviations) / len(deviations)\n return mad", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n \"\"\"\n mean = sum(numbers) / len(numbers)\n mad = sum([abs(number - mean) for number in numbers]) / len(numbers)\n return mad", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\"\n For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n \"\"\"\n # Compute the mean of the numbers\n mean = sum(numbers) / len(numbers)\n # Compute the Mean Absolute Deviation\n mad = sum(abs(x - mean) for x in numbers) / len(numbers)\n return mad", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\"\n For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n\n Args:\n numbers: List of float, data for calculation\n\n Returns:\n float, mean absolute deviation of the input list\n\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n # compute mean\n mean = sum(numbers) / len(numbers)\n\n # compute the absolute differences from the mean\n absolute_differences = [abs(number - mean) for number in numbers]\n\n # compute the mean absolute difference (mad)\n mad = sum(absolute_differences) / len(numbers)\n\n return mad", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n mean = sum(numbers) / len(numbers)\n return sum(abs(number - mean) for number in numbers) / len(numbers)", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n n = len(numbers)\n mean = sum(numbers) / n\n mad = sum(abs(number - mean) for number in numbers) / n\n return mad", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\"\n For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n \"\"\"\n mean = sum(numbers) / len(numbers)\n mad = sum([abs(num - mean) for num in numbers]) / len(numbers)\n return mad", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n mean = sum(numbers) / len(numbers)\n return sum(abs(number - mean) for number in numbers) / len(numbers)", "matching_cluster_idx": 5}]}, "HumanEval/16": {"dps": 92.55813953488372, "dps_norm": 93.88888888888889, "pass@1": 100.0, "profiled": [{"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lowercase\n string = string.lower()\n\n # Create an empty set to store distinct characters\n distinct_chars = set()\n\n # Iterate through each character in the string\n for char in string:\n # Add the character to the set\n distinct_chars.add(char)\n\n # Return the size of the set\n return len(distinct_chars)", "matching_cluster_idx": 3}, {"solution": "import doctest\ndef count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # convert string to lowercase\n string = string.lower()\n\n # create set of unique characters in the string\n unique_chars = set(string)\n\n # return number of unique characters\n return len(unique_chars)", "matching_cluster_idx": 8}, {"solution": "import doctest\ndef count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n return len(set(string.lower()))", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of.\n \"\"\"\n # Convert the string to lowercase and create a set of its characters\n distinct_chars = set(string.lower())\n # Return the number of distinct characters\n return len(distinct_chars)", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # convert string to lower case and return length of set of characters\n return len(set(string.lower()))", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # We convert the string to lower case to count characters case-insensitively\n # Then we use the set data structure to remove duplicates\n # Finally, we return the length of the set which is the count of distinct characters\n return len(set(string.lower()))", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lower case, convert the string to a set to get unique characters,\n # and finally return the length of this set\n return len(set(string.lower()))", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of \"\"\"\n return len(set(string.lower()))", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lowercase and convert it to a set to remove duplicate characters\n distinct_characters = set(string.lower())\n # Return the number of unique characters\n return len(distinct_characters)", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of \"\"\"\n return len(set(string.lower()))", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of \"\"\"\n distinct_chars = set(string.lower()) # Convert all characters to lower case and remove duplicates\n return len(distinct_chars) # Return the count of distinct characters", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lowercase to ignore case\n string = string.lower()\n # Create a set of distinct characters in the string\n distinct_chars = set(string)\n # Return the size of the set\n return len(distinct_chars)", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of \"\"\"\n return len(set(string.lower()))", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\"\n Given a string, find out how many distinct characters (regardless of case) does it consist of\n \"\"\"\n distinct_characters = set(string.lower())\n return len(distinct_characters)", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n \"\"\"\n return len(set(string.lower()))", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\"\n Given a string, find out how many distinct characters (regardless of case) does it consist of.\n\n Parameters:\n string (str): Input string\n\n Returns:\n int: Number of distinct characters in the input string\n \"\"\"\n return len(set(string.lower()))", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n \"\"\"\n # Convert the string to lower case and remove duplicates by converting it to a set\n distinct_chars = set(string.lower())\n\n # Return the length of the set which represents the number of distinct characters\n return len(distinct_chars)", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n\n Args:\n string (str): input string\n\n Returns:\n int: number of distinct characters in the string\n \"\"\"\n return len(set(string.lower()))", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to a lower case to ignore case\n lower_case_string = string.lower()\n\n # Create an empty set to store distinct characters\n distinct_chars = set()\n\n # Add each character to the set\n for char in lower_case_string:\n distinct_chars.add(char)\n\n # Return the size of the set, which is the count of distinct characters\n return len(distinct_chars)", "matching_cluster_idx": 2}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n distinct_chars = set(string.lower()) # Using set to remove duplicates, and lower() to ignore case\n return len(distinct_chars)", "matching_cluster_idx": 8}]}, "HumanEval/20": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n numbers.sort()\n min_diff = float('inf')\n res = (0, 0)\n\n for i in range(1, len(numbers)):\n if numbers[i] - numbers[i - 1] < min_diff:\n min_diff = numbers[i] - numbers[i - 1]\n res = (numbers[i - 1], numbers[i])\n\n return res", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n \"\"\"\n numbers.sort() # sort the list in ascending order\n min_diff = float('inf')\n pair = (None, None)\n for i in range(1, len(numbers)):\n if numbers[i] - numbers[i-1] < min_diff:\n min_diff = numbers[i] - numbers[i-1]\n pair = (numbers[i-1], numbers[i])\n return pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n numbers.sort()\n min_diff = float('inf')\n pair = (None, None)\n for i in range(1, len(numbers)):\n if numbers[i] - numbers[i - 1] < min_diff:\n min_diff = numbers[i] - numbers[i - 1]\n pair = (numbers[i - 1], numbers[i])\n return pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n numbers.sort()\n min_diff = float('inf')\n result = (None, None)\n\n for i in range(1, len(numbers)):\n diff = numbers[i] - numbers[i - 1]\n if diff < min_diff:\n min_diff = diff\n result = (numbers[i - 1], numbers[i])\n\n return result", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n numbers.sort()\n min_diff = float('inf')\n pair = (None, None)\n for i in range(len(numbers) - 1):\n diff = numbers[i+1] - numbers[i]\n if diff < min_diff:\n min_diff = diff\n pair = (numbers[i], numbers[i+1])\n return pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n numbers.sort()\n min_diff = float('inf')\n result = (0, 0)\n\n for i in range(1, len(numbers)):\n diff = numbers[i] - numbers[i - 1]\n if diff < min_diff:\n min_diff = diff\n result = (numbers[i - 1], numbers[i])\n return result", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n numbers.sort()\n min_diff = float('inf')\n closest_pair = (None, None)\n for i in range(1, len(numbers)):\n diff = numbers[i] - numbers[i - 1]\n if diff < min_diff:\n min_diff = diff\n closest_pair = (numbers[i - 1], numbers[i])\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n numbers.sort() # sort the list in ascending order\n min_diff = float('inf') # initialize minimum difference to positive infinity\n pair = (0, 0) # initialize closest pair of elements\n for i in range(1, len(numbers)): # iterate over the sorted list\n diff = numbers[i] - numbers[i-1] # calculate the difference between the current and previous element\n if diff < min_diff: # if the difference is smaller than the current minimum difference\n min_diff = diff # update the minimum difference\n pair = (numbers[i-1], numbers[i]) # update the closest pair of elements\n return pair # return the closest pair of elements", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n # First, sort the list in ascending order\n numbers.sort()\n # Initialize smallest difference and pair\n min_diff = float('inf')\n min_pair = None\n # Compare each pair of consecutive elements\n for i in range(len(numbers)-1):\n diff = numbers[i+1] - numbers[i]\n if diff < min_diff:\n min_diff = diff\n min_pair = (numbers[i], numbers[i+1])\n # Return the pair with smallest difference\n return min_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n numbers.sort()\n min_diff = float('inf')\n result = (numbers[0], numbers[1])\n\n for i in range(1, len(numbers)):\n diff = numbers[i] - numbers[i-1]\n if diff < min_diff:\n min_diff = diff\n result = (numbers[i-1], numbers[i])\n return result", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\nimport sys\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n numbers.sort()\n min_diff = sys.float_info.max\n closest_pair = (None, None)\n\n for i in range(1, len(numbers)):\n if numbers[i] - numbers[i-1] < min_diff:\n min_diff = numbers[i] - numbers[i-1]\n closest_pair = (numbers[i-1], numbers[i])\n\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\nimport math\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n numbers.sort()\n min_diff = math.inf\n closest_pair = (None, None)\n for i in range(len(numbers)-1):\n diff = numbers[i+1] - numbers[i]\n if diff < min_diff:\n min_diff = diff\n closest_pair = (numbers[i], numbers[i+1])\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n numbers.sort()\n min_diff = float('inf')\n pair = (None, None)\n\n for i in range(1, len(numbers)):\n diff = numbers[i] - numbers[i - 1]\n if diff < min_diff:\n min_diff = diff\n pair = (numbers[i - 1], numbers[i])\n\n return pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n numbers.sort()\n min_diff = float('inf')\n result = (None, None)\n for i in range(len(numbers) - 1):\n if numbers[i + 1] - numbers[i] < min_diff:\n min_diff = numbers[i + 1] - numbers[i]\n result = (numbers[i], numbers[i + 1])\n return result", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n numbers.sort() # Sort the numbers in the list\n diff = float('inf') # Initialize the difference to infinity\n res = (0, 0) # Initialize the result to (0, 0)\n for i in range(len(numbers) - 1):\n if numbers[i + 1] - numbers[i] < diff:\n diff = numbers[i + 1] - numbers[i]\n res = (numbers[i], numbers[i + 1])\n return res", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n numbers.sort()\n min_diff = float('inf')\n closest_pair = (numbers[0], numbers[1])\n for i in range(1, len(numbers)):\n diff = numbers[i] - numbers[i-1]\n if diff < min_diff:\n min_diff = diff\n closest_pair = (numbers[i-1], numbers[i])\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n numbers.sort()\n min_diff = float('inf')\n pair = (None, None)\n for i in range(1, len(numbers)):\n diff = numbers[i] - numbers[i-1]\n if diff < min_diff:\n min_diff = diff\n pair = (numbers[i-1], numbers[i])\n return pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\"\n From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n \"\"\"\n # sort the numbers\n numbers.sort()\n\n # initialize the closest pair as the first two numbers\n closest_pair = (numbers[0], numbers[1])\n\n # initialize the minimum difference as the difference of the first two numbers\n min_diff = numbers[1] - numbers[0]\n\n # iterate over the sorted list starting from the second number\n for i in range(1, len(numbers) - 1):\n # compute the difference between the current number and the next one\n diff = numbers[i + 1] - numbers[i]\n\n # if this difference is smaller than the current minimum difference,\n # update the closest pair and the minimum difference\n if diff < min_diff:\n min_diff = diff\n closest_pair = (numbers[i], numbers[i + 1])\n\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\nimport math\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\"From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n \"\"\"\n numbers.sort()\n min_diff = math.inf\n result = (None, None)\n for i in range(len(numbers) - 1):\n if numbers[i+1] - numbers[i] < min_diff:\n min_diff = numbers[i+1] - numbers[i]\n result = (numbers[i], numbers[i+1])\n return result", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n numbers.sort()\n min_diff = float('inf')\n result = (None, None)\n for i in range(1, len(numbers)):\n if numbers[i] - numbers[i-1] < min_diff:\n min_diff = numbers[i] - numbers[i-1]\n result = (numbers[i-1], numbers[i])\n return result", "matching_cluster_idx": 8}]}, "HumanEval/24": {"dps": 61.904761904761905, "dps_norm": 22.5, "pass@1": 82.0, "profiled": [{"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n \"\"\"\n if n == 1 or n == 0:\n return \"No divisors\"\n else:\n for i in range(n - 1, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 1}, {"solution": "def largest_divisor(n: int) -> int:\n for i in range(n - 1, 0, -1):\n if n % i == 0:\n return i\n return \"No divisors found\" # This will never be reached for n > 0", "matching_cluster_idx": 1}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n \"\"\"\n for i in range(n-1, 0, -1):\n if n % i == 0:\n return i\n return -1", "matching_cluster_idx": 1}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\"\n For a given number n, find the largest number that divides n evenly, smaller than n\n \"\"\"\n for i in range(n-1, 0, -1):\n if n % i == 0:\n return i\n return -1 # in case no such number exists, return -1", "matching_cluster_idx": 1}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n \"\"\"\n for i in range(n-1, 0, -1):\n if n % i == 0:\n return i\n return -1", "matching_cluster_idx": 1}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n # If the number is less than 2, there are no divisors\n if n < 2:\n raise ValueError(\"The number must be at least 2\")\n # Starting from the number less than n, decrementing by 1 at each step, find the first divisor\n for i in range(n-1, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 1}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\"For a given number n, find the largest number that divides n evenly, smaller than n\n\n Args:\n n (int): A positive integer\n\n Returns:\n int: The largest number that divides n evenly, smaller than n\n \"\"\"\n for i in range(n-1, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 0}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n if n <= 1:\n raise ValueError(\"The number should be greater than 1\")\n for i in range(n-1, 1, -1):\n if n % i == 0:\n return i\n return 1", "matching_cluster_idx": 1}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n for i in range(n-1, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 1}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n \"\"\"\n for i in range(n - 1, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 1}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\"\n For a given number n, find the largest number that divides n evenly, smaller than n.\n\n Parameters:\n n (int): the input number\n\n Returns:\n int: the largest divisor of n that is smaller than n\n \"\"\"\n for i in range(n-1, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 0}, {"solution": "import doctest\ndef largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n if n <= 1:\n raise ValueError(\"n should be greater than 1\")\n for i in range(n-1, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 1}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n \"\"\"\n for i in range(n-1, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 1}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\"For a given number n, find the largest number that divides n evenly, smaller than n\"\"\"\n for i in range(n-1, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 1}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\"\n For a given number n, find the largest number that divides n evenly, smaller than n.\n \"\"\"\n for i in range(n-1, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 0}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n for i in range(n-1, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 0}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n \"\"\"\n for i in range(n - 1, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 1}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\"For a given number n, find the largest number that divides n evenly, smaller than n\"\"\"\n for i in range(n-1, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 1}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n \"\"\"\n for i in range(n-1, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 1}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\"\n For a given number n, find the largest number that divides n evenly, smaller than n.\n\n >>> largest_divisor(15)\n 5\n \"\"\"\n # Loop through numbers from n-1 down to 1\n for i in range(n - 1, 0, -1):\n # Check if i divides n evenly\n if n % i == 0:\n return i\n # If no divisors are found, return None or appropriate error value\n return None", "matching_cluster_idx": 1}]}, "HumanEval/26": {"dps": 74.66666666666667, "dps_norm": 75.0, "pass@1": 18.0, "profiled": [{"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\"\n From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n \"\"\"\n # Using a dictionary to keep track of the count of numbers\n count_dict = {}\n for num in numbers:\n if num in count_dict:\n count_dict[num] += 1\n else:\n count_dict[num] = 1\n\n # Filter the list to only include numbers that have a count of 1\n return [num for num in numbers if count_dict[num] == 1]", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n \"\"\"\n unique_numbers = []\n for number in numbers:\n if numbers.count(number) == 1:\n unique_numbers.append(number)\n return unique_numbers", "matching_cluster_idx": 0}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n \"\"\"\n result = []\n for num in numbers:\n if numbers.count(num) == 1:\n result.append(num)\n return result", "matching_cluster_idx": 0}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\"From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n \"\"\"\n no_duplicates = []\n for i in numbers:\n if numbers.count(i) == 1:\n no_duplicates.append(i)\n return no_duplicates", "matching_cluster_idx": 0}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n # using dictionary to keep track of the frequency of each number\n num_freq = {}\n for num in numbers:\n if num in num_freq:\n num_freq[num] += 1\n else:\n num_freq[num] = 1\n\n # filter out the numbers that occur more than once\n result = [num for num in numbers if num_freq[num] == 1]\n return result", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n # We create an empty dictionary to store each unique number and its count.\n counts = {}\n\n for number in numbers:\n if number in counts:\n counts[number] += 1\n else:\n counts[number] = 1\n\n # Filter the list to only include numbers that occur once.\n result = [number for number in numbers if counts[number] == 1]\n\n return result", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\"From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n \"\"\"\n # Create a dictionary to count the frequency of each number\n freq_dict = {}\n for num in numbers:\n if num in freq_dict:\n freq_dict[num] += 1\n else:\n freq_dict[num] = 1\n\n # Filter the list to include only elements that occur once\n result = [num for num in numbers if freq_dict[num] == 1]\n\n return result", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\"\n From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n \"\"\"\n num_counts = {}\n for num in numbers:\n if num in num_counts:\n num_counts[num] += 1\n else:\n num_counts[num] = 1\n return [num for num in numbers if num_counts[num] == 1]", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n seen = set()\n duplicates = set()\n unique_numbers = []\n\n for number in numbers:\n if number in seen:\n duplicates.add(number)\n else:\n seen.add(number)\n\n for number in numbers:\n if number not in duplicates:\n unique_numbers.append(number)\n\n return unique_numbers", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n \"\"\"\n result = []\n for num in numbers:\n if numbers.count(num) == 1:\n result.append(num)\n return result", "matching_cluster_idx": 0}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n \"\"\"\n # Using dictionary to store elements as keys and their counts as values.\n counts = dict()\n for number in numbers:\n if number in counts:\n counts[number] += 1\n else:\n counts[number] = 1\n\n # Using list comprehension to filter out elements that occur more than once.\n result = [number for number in numbers if counts[number] == 1]\n\n return result", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n seen = set()\n duplicates = set(x for x in numbers if x in seen or seen.add(x))\n return [x for x in numbers if x not in duplicates]", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\"\n From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n \"\"\"\n # Create an empty dictionary to count the occurrences of each number\n count_dict = {}\n # Iterate over the list of numbers\n for num in numbers:\n # If number is already a key in the dictionary, increment its count\n if num in count_dict:\n count_dict[num] += 1\n # Otherwise, add the number to the dictionary with a count of 1\n else:\n count_dict[num] = 1\n # Create an empty list to store the results\n result = []\n # Iterate over the list of numbers\n for num in numbers:\n # If the count of the number in the dictionary is 1, add it to the result list\n if count_dict[num] == 1:\n result.append(num)\n # Return the result list\n return result", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n result = []\n for number in numbers:\n if numbers.count(number) == 1:\n result.append(number)\n return result", "matching_cluster_idx": 0}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n \"\"\"\n # using dictionary to store numbers as keys and their count as values\n count_dict = {}\n for number in numbers:\n if number in count_dict:\n count_dict[number] += 1\n else:\n count_dict[number] = 1\n\n # only include numbers that occur once in the result\n result = []\n for number in numbers:\n if count_dict[number] == 1:\n result.append(number)\n return result", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\"From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\"\"\"\n # Using dictionary to record frequency of each number\n counts = dict()\n for num in numbers:\n if num in counts:\n counts[num] += 1\n else:\n counts[num] = 1\n\n # Keep only numbers that occur once\n unique_numbers = [num for num in numbers if counts[num] == 1]\n\n return unique_numbers", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n \"\"\"\n return [num for num in numbers if numbers.count(num) == 1]", "matching_cluster_idx": 0}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n \"\"\"\n # using dictionary to hold numbers and their counts\n count_dict = {}\n for num in numbers:\n if num in count_dict:\n count_dict[num] += 1\n else:\n count_dict[num] = 1\n\n # creating the result list by checking count of each number\n result = []\n for num in numbers:\n if count_dict[num] == 1:\n result.append(num)\n\n return result", "matching_cluster_idx": 3}]}, "HumanEval/31": {"dps": 50.63291139240506, "dps_norm": 75.0, "pass@1": 100.0, "profiled": [{"solution": "def is_prime(n):\n if n <= 1:\n return False\n elif n <= 3:\n return True\n elif n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 5}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\"\"\"\n if n <= 1:\n return False\n if n == 2:\n return True\n if n % 2 == 0:\n return False\n i = 3\n while i * i <= n:\n if n % i:\n i += 2\n else:\n return False\n return True", "matching_cluster_idx": 5}, {"solution": "def is_prime(n):\n if n <= 1:\n return False\n elif n <= 3:\n return True\n elif n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 5}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\"\"\"\n if n <= 1:\n return False\n elif n <= 3:\n return True\n elif n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 5}, {"solution": "def is_prime(n):\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 5}, {"solution": "def is_prime(n):\n if n < 2:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True", "matching_cluster_idx": 5}, {"solution": "def is_prime(n):\n if n <= 1:\n return False\n elif n <= 3:\n return True\n elif n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 5}, {"solution": "def is_prime(n):\n if n <= 1:\n return False\n elif n <= 3:\n return True\n elif n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 5}, {"solution": "def is_prime(n):\n if n < 2: # The smallest prime number is 2\n return False\n for i in range(2, int(n**0.5) + 1): # A prime number is a natural number greater than 1 that has no positive divisors other than 1 and itself\n if n % i == 0:\n return False\n return True", "matching_cluster_idx": 5}, {"solution": "def is_prime(n):\n \"\"\"\n Return true if a given number is prime, and false otherwise.\n \"\"\"\n if n < 2:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True", "matching_cluster_idx": 5}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n ** 0.5) + 1):\n if n % i == 0:\n return False\n return True", "matching_cluster_idx": 5}, {"solution": "def is_prime(n):\n if n < 2:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True", "matching_cluster_idx": 5}, {"solution": "def is_prime(n):\n if n <= 1:\n return False\n elif n <= 3:\n return True\n elif n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 5}, {"solution": "def is_prime(n):\n if n <= 1:\n return False\n if n == 2:\n return True\n if n % 2 == 0:\n return False\n max_divisor = int(n**0.5) + 1\n for d in range(3, max_divisor, 2):\n if n % d == 0:\n return False\n return True", "matching_cluster_idx": 5}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\"\"\"\n if n < 2: # primes are greater than 1\n return False\n for i in range(2, int(n ** 0.5) + 1): # only need to check up to square root of n\n if n % i == 0: # if n is divisible by any number up to its square root, it's not prime\n return False\n return True", "matching_cluster_idx": 5}, {"solution": "def is_prime(n):\n if n <= 1:\n return False\n elif n <= 3:\n return True\n elif n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 5}, {"solution": "def is_prime(n):\n if n <= 1:\n return False\n elif n <= 3:\n return True\n elif n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while(i * i <= n):\n if (n % i == 0 or n % (i + 2) == 0):\n return False\n i += 6\n return True", "matching_cluster_idx": 5}, {"solution": "def is_prime(n):\n if n <= 1:\n return False\n elif n <= 3:\n return True\n elif n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while(i * i <= n):\n if (n % i == 0 or n % (i + 2) == 0):\n return False\n i += 6\n return True", "matching_cluster_idx": 5}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\"\"\"\n if n < 2:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True", "matching_cluster_idx": 5}, {"solution": "def is_prime(n):\n if n <= 1:\n return False\n elif n <= 3:\n return True\n elif n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 5}]}, "HumanEval/33": {"dps": 60.27777777777778, "dps_norm": 74.54545454545455, "pass@1": 74.0, "profiled": [{"solution": "def sort_third(l: list):\n # Get values at the indices that are divisible by three\n divisible_by_three = [l[i] for i in range(0, len(l), 3)]\n # Sort the values\n divisible_by_three.sort()\n # Replace values in the original list\n for i, val in enumerate(divisible_by_three):\n l[3 * i] = val\n return l", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n # Create a list with elements at indices divisible by 3 from input list\n div_by_three = [l[i] for i in range(len(l)) if i % 3 == 0]\n # Sort the list\n div_by_three.sort()\n # Replace elements at indices divisible by 3 with sorted elements\n for i in range(len(div_by_three)):\n l[i*3] = div_by_three[i]\n # Return updated list\n return l", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n third_elements = sorted([l[i] for i in range(len(l)) if i % 3 == 0])\n for i in range(len(l)):\n if i % 3 == 0:\n l[i] = third_elements.pop(0)\n return l", "matching_cluster_idx": 6}, {"solution": "def sort_third(l: list) -> list:\n \"\"\"\n This function takes a list l and returns a list l' such that\n l' is identical to l in the indices that are not divisible by three, while its values at the indices that are divisible by three are equal\n to the values of the corresponding indices of l, but sorted.\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n # Extract elements at indices divisible by 3\n divisible_by_three = sorted([l[i] for i in range(len(l)) if i % 3 == 0])\n # Replace elements at indices divisible by 3 in the original list with sorted elements\n for i in range(len(divisible_by_three)):\n l[i*3] = divisible_by_three[i]\n return l", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n third_elements = sorted(l[i] for i in range(0, len(l), 3))\n for i in range(0, len(l), 3):\n l[i] = third_elements.pop(0)\n return l", "matching_cluster_idx": 6}, {"solution": "def sort_third(l: list):\n # Make a new list containing only the elements at the multiples of 3\n thirds = sorted(l[i] for i in range(len(l)) if i % 3 == 0)\n\n # Iterate through the original list and replace elements at multiples of 3 with corresponding elements in the new sorted list\n for i in range(len(l)):\n if i % 3 == 0:\n l[i] = thirds.pop(0)\n\n return l", "matching_cluster_idx": 6}, {"solution": "def sort_third(l: list):\n div_three_indices = [i for i in range(len(l)) if i % 3 == 0]\n div_three_values = sorted([l[i] for i in div_three_indices])\n for i, idx in enumerate(div_three_indices):\n l[idx] = div_three_values[i]\n return l", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n # Extract every third element from the list and sort it\n third_elements = sorted(l[::3])\n\n # Create a copy of the input list\n sorted_list = l.copy()\n\n # Replace every third element in the copy with elements from the sorted list\n for i in range(len(third_elements)):\n sorted_list[3 * i] = third_elements[i]\n\n return sorted_list", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list) -> list:\n div_three_indices = [i for i in range(len(l)) if i % 3 == 0]\n div_three_elems = [l[i] for i in div_three_indices]\n div_three_elems.sort()\n for i, index in enumerate(div_three_indices):\n l[index] = div_three_elems[i]\n return l", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n third_elements = sorted(l[::3])\n for i in range(0, len(l), 3):\n l[i] = third_elements[i // 3]\n return l", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list) -> list:\n # extract elements at indices divisible by three\n div_three_elements = sorted([l[i] for i in range(len(l)) if i % 3 == 0])\n # replace elements at indices divisible by three with sorted elements\n for i in range(0, len(l), 3):\n l[i] = div_three_elements.pop(0)\n return l", "matching_cluster_idx": 6}, {"solution": "def sort_third(l: list):\n # Extract the elements at indices divisible by three\n divisible_by_three = sorted(l[i] for i in range(0, len(l), 3))\n\n # Place the elements back into their respective indices\n for i, elem in enumerate(divisible_by_three):\n l[3*i] = elem\n\n return l", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list) -> list:\n divisible_by_three_indices = [i for i in range(len(l)) if i % 3 == 0]\n sorted_values = sorted([l[i] for i in divisible_by_three_indices])\n for i, val in zip(divisible_by_three_indices, sorted_values):\n l[i] = val\n return l", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n # Create a new list to store the elements at indices divisible by three\n div_by_three = [l[i] for i in range(0, len(l), 3)]\n # Sort this list\n div_by_three.sort()\n # Create a new list to store the result\n result = l.copy()\n # Insert the sorted elements back into the result list\n for i in range(0, len(result), 3):\n result[i] = div_by_three.pop(0)\n # Return the result\n return result", "matching_cluster_idx": 6}, {"solution": "def sort_third(l: list):\n # filter elements at indices divisible by three\n divisible_by_three = [l[i] for i in range(len(l)) if i % 3 == 0]\n # sort the filtered elements\n divisible_by_three.sort()\n # replace the sorted elements in the original list\n for i, elem in enumerate(divisible_by_three):\n l[i*3] = elem\n return l", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n # Find indices that are divisible by three\n divisible_by_three_indices = [i for i in range(len(l)) if i % 3 == 0]\n\n # Extract values from those indices\n divisible_by_three_values = [l[i] for i in divisible_by_three_indices]\n\n # Sort the values\n divisible_by_three_values.sort()\n\n # Replace the values at the divisible by three indices in the original list\n for i in range(len(divisible_by_three_indices)):\n l[divisible_by_three_indices[i]] = divisible_by_three_values[i]\n\n return l", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n # Create a list to store elements at indices divisible by three\n divisible_by_three = [l[i] for i in range(len(l)) if i % 3 == 0]\n\n # Sort the list\n divisible_by_three.sort()\n\n # Create a copy of the original list\n l_new = l.copy()\n\n # Replace elements at indices divisible by three with sorted elements\n for i in range(len(l_new)):\n if i % 3 == 0:\n l_new[i] = divisible_by_three.pop(0)\n\n return l_new", "matching_cluster_idx": 6}, {"solution": "def sort_third(l: list):\n divisible_by_three_indices = [i for i in range(len(l)) if i % 3 == 0]\n divisible_by_three_elements = [l[i] for i in divisible_by_three_indices]\n divisible_by_three_elements.sort()\n\n l_sorted = l.copy()\n for i, index in enumerate(divisible_by_three_indices):\n l_sorted[index] = divisible_by_three_elements[i]\n\n return l_sorted", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n # extract elements at indices divisible by three\n third_elems = sorted(l[i] for i in range(len(l)) if i % 3 == 0)\n # replace elements at indices divisible by three with the sorted ones\n for i in range(len(l)):\n if i % 3 == 0:\n l[i] = third_elems.pop(0)\n return l", "matching_cluster_idx": 6}, {"solution": "def sort_third(l: list):\n # Extract the values at indices divisible by three\n div_three_vals = sorted(v for i, v in enumerate(l) if i % 3 == 0)\n # Fill in a new list with the sorted values and the rest of the original list\n return [div_three_vals.pop(0) if i % 3 == 0 else v for i, v in enumerate(l)]", "matching_cluster_idx": 6}]}, "HumanEval/34": {"dps": 86.41509433962264, "dps_norm": 97.0, "pass@1": 100.0, "profiled": [{"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 3, 2, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n unique_list = list(set(l))\n unique_list.sort()\n return unique_list", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\"\"\"\n # Using set to remove duplicates\n unique_elements = set(l)\n # Converting set to list and sorting\n sorted_unique_elements = sorted(list(unique_elements))\n return sorted_unique_elements", "matching_cluster_idx": 3}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\"\"\"\n # using set to get unique elements and then sorting them\n return sorted(list(set(l)))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list) -> list:\n \"\"\"Return sorted unique elements in a list\"\"\"\n # Using set to remove duplicates, then sorting and returning the list\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(list(set(l)))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\"\"\"\n return sorted(list(set(l)))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list) -> list:\n \"\"\"Return sorted unique elements in a list\"\"\"\n return sorted(list(set(l)))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\"\"\"\n return sorted(list(set(l)))", "matching_cluster_idx": 4}, {"solution": "def unique(lst: list):\n \"\"\"Return sorted unique elements in a list\"\"\"\n # Using a set to remove duplicates because a set in Python is an unordered collection of unique elements.\n # Then convert the set to a list and sort it.\n return sorted(list(set(lst)))", "matching_cluster_idx": 3}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n \"\"\"\n # Using set to get unique elements and list to convert it back to a list\n unique_elements = list(set(l))\n # Sorting the list\n unique_elements.sort()\n return unique_elements", "matching_cluster_idx": 4}, {"solution": "def unique(l: list) -> list:\n \"\"\"\n Return sorted unique elements in a list\n\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n # convert the list to a set to remove duplicates, then convert it back to a list\n unique_list = list(set(l))\n # sort the list in ascending order\n unique_list.sort()\n return unique_list", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\"\"\"\n return sorted(list(set(l)))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(list(set(l)))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n\n Args:\n l (list): The list of elements\n\n Returns:\n list: Sorted unique elements in the list\n \"\"\"\n # Use a set to remove duplicates and sort the list\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n \"\"\"\n unique_elements = list(set(l))\n unique_elements.sort()\n return unique_elements", "matching_cluster_idx": 4}, {"solution": "def unique(l: list) -> list:\n return sorted(list(set(l)))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list) -> list:\n return sorted(list(set(l)))", "matching_cluster_idx": 3}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\"\"\"\n return sorted(list(set(l)))", "matching_cluster_idx": 4}]}, "HumanEval/36": {"dps": 97.1774193548387, "dps_norm": 75.0, "pass@1": 70.0, "profiled": [{"solution": "def fizz_buzz(n: int) -> int:\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n count = 0\n for i in range(11, n, 11):\n if '7' in str(i):\n count += str(i).count('7')\n for i in range(13, n, 13):\n if '7' in str(i):\n count += str(i).count('7')\n for i in range(143, n, 143): # To remove numbers that are counted twice\n if '7' in str(i):\n count -= str(i).count('7')\n return count", "matching_cluster_idx": 5}, {"solution": "def fizz_buzz(n: int):\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n \"\"\"\n count = 0\n for i in range(1, n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n \"\"\"\n count = 0\n for i in range(1, n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n count = 0\n for i in range(11, n, 11):\n if '7' in str(i):\n count += str(i).count('7')\n for i in range(13, n, 13):\n if '7' in str(i):\n count += str(i).count('7')\n for i in range(143, n, 143): # To account for numbers that are divisible by both 11 and 13\n if '7' in str(i):\n count -= str(i).count('7') # Subtract as these numbers were counted twice\n return count", "matching_cluster_idx": 5}, {"solution": "def fizz_buzz(n: int) -> int:\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\"\"\"\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int):\n count = 0\n for i in range(11, n, 11): # checks numbers divisible by 11\n count += str(i).count('7')\n for i in range(13, n, 13): # checks numbers divisible by 13\n count += str(i).count('7')\n for i in range(143, n, 143): # checks numbers divisible by both 11 and 13 (the least common multiple) to avoid double-counting\n count -= str(i).count('7')\n return count", "matching_cluster_idx": 5}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\"\"\"\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int):\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\"\"\"\n count = 0\n for i in range(1, n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n count = 0\n for i in range(11, n, 11): # iterate over multiples of 11\n if '7' in str(i):\n count += str(i).count('7')\n for i in range(13, n, 13): # iterate over multiples of 13\n if '7' in str(i):\n count += str(i).count('7')\n for i in range(143, n, 143): # iterate over common multiples of 11 and 13 to avoid double-counting\n if '7' in str(i):\n count -= str(i).count('7')\n return count", "matching_cluster_idx": 5}, {"solution": "def fizz_buzz(n: int) -> int:\n count = 0\n for i in range(1, n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n # find all numbers less than n which are divisible by 11 or 13\n divisible_numbers = [i for i in range(n) if i % 11 == 0 or i % 13 == 0]\n # count the number of occurrences of the digit 7 in these numbers\n count = str(divisible_numbers).count('7')\n return count", "matching_cluster_idx": 5}]}, "HumanEval/37": {"dps": 95.94108019639934, "dps_norm": 92.0, "pass@1": 98.0, "profiled": [{"solution": "def sort_even(l: list):\n evens = sorted([l[i] for i in range(0, len(l), 2)])\n for i in range(0, len(l), 2):\n l[i] = evens.pop(0)\n return l", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n \"\"\"\n even_indices = sorted(l[::2])\n return [even_indices.pop(0) if i % 2 == 0 else x for i, x in enumerate(l)]", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n # Fetch the even elements of the list and sort it\n evens = sorted([l[i] for i in range(0, len(l), 2)])\n\n # Go through the list and replace even index elements with the sorted ones\n for i in range(0, len(l), 2):\n l[i] = evens.pop(0)\n\n return l", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n # Extract the even indexed elements\n even_elements = [l[i] for i in range(0, len(l), 2)]\n\n # Sort the even indexed elements\n even_elements.sort()\n\n # Replace the even indexed elements in the original list with sorted ones\n for i in range(0, len(l), 2):\n l[i] = even_elements.pop(0)\n\n return l", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list) -> list:\n # Extract the even indices elements from the list\n evens = sorted(l[::2])\n # Start by duplicating the input list\n l_prime = l[:]\n # Iterate over even indices and replace their values in the output list\n for i in range(0, len(l), 2):\n l_prime[i] = evens[i//2]\n return l_prime", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n even_elements = sorted(l[::2])\n l[::2] = even_elements\n return l", "matching_cluster_idx": 9}, {"solution": "def sort_even(l: list) -> list:\n even_indices = [i for i in range(len(l)) if i % 2 == 0]\n even_values = sorted([l[i] for i in even_indices])\n sorted_even_l = l.copy()\n for i, val in zip(even_indices, even_values):\n sorted_even_l[i] = val\n return sorted_even_l", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n evens = sorted([l[i] for i in range(0, len(l), 2)])\n for i in range(0, len(l), 2):\n l[i] = evens.pop(0)\n return l", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n # separate the elements at the even indices into a new list\n even_elements = sorted([l[i] for i in range(0, len(l), 2)])\n # replace the elements at the even indices in the original list with the sorted elements\n for i in range(0, len(l), 2):\n l[i] = even_elements.pop(0)\n return l", "matching_cluster_idx": 8}, {"solution": "def sort_even(l):\n even_indices_values = sorted([l[i] for i in range(0, len(l), 2)])\n for i in range(0, len(l), 2):\n l[i] = even_indices_values.pop(0)\n return l", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n even_index_values = sorted([val for idx, val in enumerate(l) if idx % 2 == 0])\n return [val if idx % 2 != 0 else even_index_values.pop(0) for idx, val in enumerate(l)]", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n even_idx_values = sorted(l[::2])\n l[::2] = even_idx_values\n return l", "matching_cluster_idx": 9}, {"solution": "def sort_even(l: list):\n even_values = sorted(l[::2])\n for i in range(0, len(l), 2):\n l[i] = even_values.pop(0)\n return l", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n # Extract even-index elements\n evens = sorted(l[0::2])\n # Put even-index elements back into their positions\n l[0::2] = evens\n return l", "matching_cluster_idx": 9}, {"solution": "def sort_even(l: list):\n # Filter out even indexed elements\n even_elements = sorted(l[::2])\n # Replace even indexed elements with sorted elements\n for i in range(0, len(l), 2):\n l[i] = even_elements.pop(0)\n return l", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n evens = sorted(l[::2])\n for i in range(0, len(l), 2):\n l[i] = evens.pop(0)\n return l", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list) -> list:\n even_values = sorted([l[i] for i in range(0, len(l), 2)])\n l[::2] = even_values\n return l", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list) -> list:\n \"\"\"\n This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n \"\"\"\n # Get all even-indexed elements and sort them\n even_elements = sorted(l[::2])\n # Create a new list with the odd indexed elements in their place\n result = [None] * len(l)\n result[::2] = even_elements\n # Fill in the rest with the elements from the original list\n result[1::2] = l[1::2]\n return result", "matching_cluster_idx": 9}, {"solution": "def sort_even(l: list):\n evens = sorted(l[::2]) # get the even-indexed elements and sort them\n evens_iter = iter(evens) # create an iterator to traverse the sorted even elements\n return [next(evens_iter) if i % 2 == 0 else val for i, val in enumerate(l)]", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"\n This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indices, while its values at the even indices are equal\n to the values of the even indices of l, but sorted.\n \"\"\"\n # Extract all even elements\n even_elements = sorted([l[i] for i in range(0, len(l), 2)])\n # Replace even elements in the original list with sorted ones\n for i in range(0, len(l), 2):\n l[i] = even_elements.pop(0)\n return l", "matching_cluster_idx": 8}]}, "HumanEval/49": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 61.0, "profiled": [{"solution": "def modp(n: int, p: int) -> int:\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n # compute 2^n modulo p using the built-in pow function\n # the pow function can compute power and modulo simultaneously\n # which is more efficient and avoids overflow for large values of n\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\n\n The function implements exponentiation by squaring method which avoids\n integer overflow and is more time-efficient.\n \"\"\"\n # Base cases\n if p == 1:\n return 0\n if n == 0:\n return 1\n\n # Initialize result\n result = 1\n\n # Calculate 2^n modulo p\n base = 2 % p\n exponent = n\n while exponent > 0:\n if exponent % 2 == 1:\n result = (result * base) % p\n base = (base * base) % p\n exponent //= 2\n\n return result", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\"\"\"\n # Using the power function pow() with 3 arguments. The third argument 'p' is used to\n # take the modulus of the result.\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\n\n Args:\n n (int): Exponent of 2.\n p (int): Modulo.\n\n Returns:\n int: Result of 2^n modulo p.\n \"\"\"\n # Using pow function with three arguments will compute (x ^ y) % z efficiently\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "import doctest\ndef modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n if n == 0:\n return 1 % p\n else:\n power = modp(n // 2, p)\n if n % 2 == 0:\n return (power * power) % p\n else:\n return ((power * power) * 2) % p", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int):\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int):\n \"\"\"Return 2^n modulo p (be aware of numerics).\"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\"\"\"\n # 2^n can be calculated as 2**n\n # To calculate 2^n mod p, we can use the pow() function in Python which calculates (a**b)%m\n # The pow() function handles large numbers efficiently\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"\n Return 2^n modulo p.\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\"\"\"\n if n == 0:\n return 1 % p\n elif n % 2 == 0:\n half_mod = modp(n // 2, p)\n return (half_mod * half_mod) % p\n else:\n return (2 * modp(n - 1, p)) % p", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int):\n \"\"\"Return 2^n modulo p (be aware of numerics).\"\"\"\n # Python's built-in pow function is used to calculate 2^n mod p\n # It efficiently calculates large powers using square-and-multiply algorithm\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int):\n # calculate 2^n modulo p\n result = pow(2, n, p)\n return result", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\"\"\"\n if p == 1:\n return 0\n else:\n return pow(2, n, p)", "matching_cluster_idx": 4}]}, "HumanEval/51": {"dps": 96.13526570048309, "dps_norm": 75.0, "pass@1": 100.0, "profiled": [{"solution": "def remove_vowels(text):\n vowels = \"aeiouAEIOU\"\n return \"\".join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n vowels = 'aeiouAEIOU'\n result = ''\n for char in text:\n if char not in vowels:\n result += char\n return result", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n vowels = ['a', 'e', 'i', 'o', 'u', 'A', 'E', 'I', 'O', 'U']\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n vowels = 'aeiouAEIOU'\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "import doctest\ndef remove_vowels(text):\n vowels = 'aeiouAEIOU'\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes a string and returns a string without vowels.\n \"\"\"\n vowels = 'aeiouAEIOU'\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n vowels = 'aeiouAEIOU'\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n vowels = 'aeiouAEIOU'\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n vowels = 'aeiouAEIOU'\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes a string and returns a string without vowels.\n \"\"\"\n vowels = 'aeiouAEIOU'\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes a string and returns a string without vowels.\n \"\"\"\n # define a string containing all the vowels (both lower case and upper case)\n vowels = 'aeiouAEIOU'\n\n # iterate over each character in the text\n result = ''\n for char in text:\n # if the character is not a vowel, add it to the result\n if char not in vowels:\n result += char\n\n return result", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n vowels = 'aeiouAEIOU'\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n \"\"\"\n vowels = 'aeiouAEIOU'\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n vowels = 'aeiouAEIOU'\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n vowels = ['a', 'e', 'i', 'o', 'u', 'A', 'E', 'I', 'O', 'U']\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes a string and returns a string without vowels.\n \"\"\"\n vowels = ['a', 'e', 'i', 'o', 'u', 'A', 'E', 'I', 'O', 'U']\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n vowels = 'aeiouAEIOU'\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes a string and returns a string without vowels.\n \"\"\"\n vowels = 'aeiouAEIOU'\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n \"\"\"\n vowels = 'aeiouAEIOU'\n result = ''\n for char in text:\n if char not in vowels:\n result += char\n return result", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n vowels = 'aeiouAEIOU'\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}]}, "HumanEval/54": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 20.0, "profiled": [{"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \"\"\"\n # Remove duplicates from strings and compare the results\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')\n True\n >>> same_chars('abcd', 'dddddddabc')\n True\n >>> same_chars('dddddddabc', 'abcd')\n True\n >>> same_chars('eabcd', 'dddddddabc')\n False\n >>> same_chars('abcd', 'dddddddabce')\n False\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')\n False\n \"\"\"\n # Convert both strings into sets of characters and compare them\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \"\"\"\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \"\"\"\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str):\n \"\"\"\n Check if two words have the same characters.\n \"\"\"\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \"\"\"\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \"\"\"\n # Convert strings to sets\n set_s0 = set(s0)\n set_s1 = set(s1)\n\n # Check if both sets are equal\n return set_s0 == set_s1", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \"\"\"\n # convert strings to sets of characters\n set_s0 = set(s0)\n set_s1 = set(s1)\n\n # check if two sets of characters are the same\n if set_s0 == set_s1:\n return True\n else:\n return False", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str):\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "import doctest\ndef same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')\n True\n >>> same_chars('abcd', 'dddddddabc')\n True\n >>> same_chars('dddddddabc', 'abcd')\n True\n >>> same_chars('eabcd', 'dddddddabc')\n False\n >>> same_chars('abcd', 'dddddddabce')\n False\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')\n False\n \"\"\"\n # Convert each string to a set, which removes duplicate characters\n # Then check if two sets are equal\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \"\"\"\n # convert the strings to sets of characters\n set0 = set(s0)\n set1 = set(s1)\n\n # check if the sets are equal\n return set0 == set1", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \"\"\"\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \"\"\"\n # Convert strings to sets of characters\n set_s0 = set(s0)\n set_s1 = set(s1)\n\n # Compare sets of characters\n return set_s0 == set_s1", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \"\"\"\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \"\"\"\n # Use set data structure to remove duplicates, and check for equality.\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \"\"\"\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \"\"\"\n # Convert strings to sets of characters\n set_s0 = set(s0)\n set_s1 = set(s1)\n\n # Check if two sets are equal\n return set_s0 == set_s1", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \"\"\"\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \"\"\"\n # We can check if two strings have the same characters by converting each string to a set of characters.\n # If the sets are equal, the strings have the same characters.\n return set(s0) == set(s1)", "matching_cluster_idx": 6}]}, "HumanEval/58": {"dps": 92.51968503937007, "dps_norm": 83.33333333333333, "pass@1": 100.0, "profiled": [{"solution": "def common(l1: list, l2: list) -> list:\n # Convert the lists to sets\n set1 = set(l1)\n set2 = set(l2)\n\n # Find common elements in both sets\n common_elements = set1.intersection(set2)\n\n # Sort and return the common elements\n return sorted(list(common_elements))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list) -> list:\n \"\"\"\n Return sorted unique common elements for two lists.\n \"\"\"\n # converting lists to sets to get unique elements\n set1 = set(l1)\n set2 = set(l2)\n\n # finding common elements\n common_set = set1 & set2\n\n # converting set to list and sorting it\n common_list = sorted(list(common_set))\n\n return common_list", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list) -> list:\n \"\"\"Return sorted unique common elements for two lists.\n \"\"\"\n return sorted(list(set(l1) & set(l2)))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list) -> list:\n \"\"\"\n Return sorted unique common elements for two lists.\n\n :param l1: list of elements\n :param l2: list of elements\n :return: list of sorted unique common elements\n \"\"\"\n return sorted(list(set(l1) & set(l2)))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n common_elements = sorted(list(set(l1) & set(l2)))\n return common_elements", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"\n Return sorted unique common elements for two lists.\n \"\"\"\n # First, we find common elements and then convert the result into a set to remove duplicates\n common_elements = set(l1) & set(l2)\n\n # We convert the set back into a list and sort it\n result = sorted(list(common_elements))\n\n return result", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list) -> list:\n \"\"\"Return sorted unique common elements for two lists.\"\"\"\n # convert lists to sets to eliminate duplicates and perform intersection operation\n # sort the resulting set and convert back to list\n return sorted(list(set(l1) & set(l2)))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list) -> list:\n \"\"\"Return sorted unique common elements for two lists.\"\"\"\n return sorted(list(set(l1) & set(l2)))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list) -> list:\n \"\"\"Return sorted unique common elements for two lists.\"\"\"\n # Convert both lists into sets\n set1 = set(l1)\n set2 = set(l2)\n\n # Find intersection of the sets\n common_set = set1.intersection(set2)\n\n # Convert resultant set to list\n common_list = list(common_set)\n\n # Sort the list\n common_list.sort()\n\n return common_list", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n # Create sets from the input lists. Sets automatically remove duplicates and have O(1) lookup time.\n set1 = set(l1)\n set2 = set(l2)\n\n # Compute the intersection of the two sets. This gives us the common elements.\n common_set = set1 & set2\n\n # Convert the set back to a list and sort it.\n common_list = sorted(list(common_set))\n\n return common_list", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\"\"\"\n return sorted(list(set(l1) & set(l2)))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n \"\"\"\n # Convert lists to sets for O(1) lookup\n set1, set2 = set(l1), set(l2)\n # Find intersection of two sets and sort the result\n result = sorted(set1.intersection(set2))\n return result", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list) -> list:\n \"\"\"Return sorted unique common elements for two lists.\"\"\"\n # Convert lists to sets to find common elements\n common_set = set(l1) & set(l2)\n\n # Convert the set back to list and sort it\n common_list = sorted(list(common_set))\n\n return common_list", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n\n This function accepts two lists, converts both into sets, finds their intersection (which gives the common elements),\n converts the result back to a list, sorts it and returns.\n \"\"\"\n\n common_elements = sorted(list(set(l1) & set(l2)))\n return common_elements", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list) -> list:\n \"\"\"Return sorted unique common elements for two lists.\"\"\"\n # converting lists to sets for faster lookup\n set1 = set(l1)\n set2 = set(l2)\n # finding the common elements\n common_elements = set1.intersection(set2)\n # sorting and returning as a list\n return sorted(list(common_elements))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list) -> list:\n \"\"\"\n Return sorted unique common elements for two lists.\n \"\"\"\n # convert lists to sets to get unique elements\n # use intersection to get common elements\n common_elements = list(set(l1) & set(l2))\n # sort the list before returning\n common_elements.sort()\n return common_elements", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n # converting lists to sets for efficient membership testing\n s1 = set(l1)\n s2 = set(l2)\n # finding common elements using intersection operation of sets\n common_elements = s1.intersection(s2)\n # converting set back to list for sorted operation\n common_list = list(common_elements)\n # sorting list in place\n common_list.sort()\n return common_list", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list) -> list:\n \"\"\"Return sorted unique common elements for two lists.\"\"\"\n # Convert both lists to sets and find their intersection\n common_set = set(l1) & set(l2)\n # Convert the intersection set to a list and sort it\n common_list = sorted(list(common_set))\n return common_list", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list) -> list:\n \"\"\"Return sorted unique common elements for two lists.\n \"\"\"\n return sorted(list(set(l1) & set(l2)))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\"\"\"\n common_elements = set(l1) & set(l2)\n return sorted(list(common_elements))", "matching_cluster_idx": 4}]}, "HumanEval/59": {"dps": 95.57291666666667, "dps_norm": 96.66666666666667, "pass@1": 93.0, "profiled": [{"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\"\"\"\n i = 2\n while i * i <= n:\n if n % i:\n i += 1\n else:\n n //= i\n return n", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\"\"\"\n i = 2\n while i * i <= n:\n if n % i:\n i += 1\n else:\n n //= i\n return n", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n i = 2\n while i * i <= n:\n if n % i:\n i += 1\n else:\n n //= i\n return n", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\"\"\"\n i = 2\n while i * i <= n:\n if n % i:\n i += 1\n else:\n n //= i\n return n", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n i = 2\n while i * i <= n:\n if n % i:\n i += 1\n else:\n n //= i\n return n", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n i = 2\n while i * i <= n:\n if n % i:\n i += 1\n else:\n n //= i\n return n", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\"\"\"\n i = 2\n while i * i <= n:\n if n % i:\n i += 1\n else:\n n //= i\n return n", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\"\"\"\n i = 2\n while i * i <= n:\n if n % i:\n i += 1\n else:\n n //= i\n return n", "matching_cluster_idx": 8}, {"solution": "import math\ndef largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\"\"\"\n largest_factor = -1\n # Divide by 2 until n becomes odd\n while n % 2 == 0:\n largest_factor = 2\n n >>= 1 # equivalent to n /= 2\n # n must be odd at this point so a skip of 2 can be used\n for i in range(3, int(math.sqrt(n)) + 1, 2):\n while n % i== 0:\n largest_factor = i\n n = n / i\n # this condition is to handle the case when n is a prime number greater than 2\n if n > 2:\n largest_factor = n\n return int(largest_factor)", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\"\"\"\n i = 2\n while i * i <= n:\n if n % i:\n i += 1\n else:\n n //= i\n return n", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\"\"\"\n i = 2\n while i * i <= n:\n if n % i:\n i += 1\n else:\n n //= i\n return n", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\"\"\"\n i = 2\n while i * i <= n:\n if n % i:\n i += 1\n else:\n n //= i\n return n", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n i = 2\n while i * i <= n:\n if n % i:\n i += 1\n else:\n n //= i\n return n", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\"\"\"\n largest = 0\n while n % 2 == 0:\n largest = 2\n n //= 2\n for i in range(3, int(n**0.5) + 1, 2):\n while n % i == 0:\n largest = i\n n //= i\n if n > 2:\n largest = n\n return largest", "matching_cluster_idx": 8}, {"solution": "import math\ndef largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\"\"\"\n # Start with the largest possible factor\n i = 2\n while i * i <= n:\n if n % i:\n i += 1\n else:\n # i is a factor, divide n by i\n n //= i\n return n", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n \"\"\"\n # Check if number is divisible by 2 and divide it until not divisible anymore\n while n % 2 == 0:\n max_prime = 2\n n = n / 2\n\n # n must be odd at this point, thus skip even numbers and check up to the square root of n\n for i in range(3, int(n**0.5)+1, 2):\n while n % i == 0:\n max_prime = i\n n = n / i\n\n # If n is a prime number greater than 2, then n is the largest prime factor\n if n > 2:\n max_prime = n\n\n return int(max_prime)", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n i = 2\n while i * i <= n:\n if n % i:\n i += 1\n else:\n n //= i\n return n", "matching_cluster_idx": 8}, {"solution": "def is_prime(num: int) -> bool:\n \"\"\"Check if a number is a prime number.\"\"\"\n if num < 2:\n return False\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n return False\n return True\ndef largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\"\"\"\n if n < 2:\n return None\n for i in range(n - 1, 1, -1):\n if n % i == 0 and is_prime(i):\n return i\n return None", "matching_cluster_idx": 2}, {"solution": "def largest_prime_factor(n: int) -> int:\n i = 2\n while i * i <= n:\n if n % i:\n i += 1\n else:\n n //= i\n return n", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n max_prime = -1\n while n % 2 == 0:\n max_prime = 2\n n >>= 1 # equivalent to n /= 2\n for i in range(3, int(n ** 0.5) + 1, 2):\n while n % i == 0:\n max_prime = i\n n /= i\n if n > 2:\n max_prime = n\n return max_prime", "matching_cluster_idx": 8}]}, "HumanEval/64": {"dps": 56.883116883116884, "dps_norm": 54.375, "pass@1": 43.0, "profiled": [{"solution": "def vowels_count(s):\n vowels = 'aeiou'\n s = s.lower()\n if s.endswith('y'):\n return sum(1 for c in s if c in vowels) + 1\n else:\n return sum(1 for c in s if c in vowels)", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n # Initialize count of vowels\n count = 0\n # Convert the string to lowercase for uniform comparison\n s = s.lower()\n # Define vowels, including 'y'\n vowels = ['a', 'e', 'i', 'o', 'u']\n # Check each character in string\n for i in range(len(s)):\n # If current character is a vowel or 'y' at the end, increment the count\n if s[i] in vowels or (s[i] == 'y' and i == len(s) - 1):\n count += 1\n return count", "matching_cluster_idx": 3}, {"solution": "def vowels_count(s):\n s = s.lower() # Convert string to lowercase\n vowels = ['a', 'e', 'i', 'o', 'u']\n count = sum([1 for letter in s if letter in vowels]) # Count the number of vowels in the string\n if s.endswith('y'): # Check if the last letter is 'y' and add it to the count if true\n count += 1\n return count", "matching_cluster_idx": 5}, {"solution": "def vowels_count(s):\n s = s.lower()\n count = 0\n for i in range(len(s)):\n if s[i] in 'aeiou':\n count += 1\n elif s[i] == 'y' and i == len(s) - 1:\n count += 1\n return count", "matching_cluster_idx": 3}, {"solution": "def vowels_count(s):\n s = s.lower()\n count = 0\n vowels = ['a', 'e', 'i', 'o', 'u']\n for index, char in enumerate(s):\n if char in vowels:\n count += 1\n elif char == 'y' and index == len(s) - 1:\n count += 1\n return count", "matching_cluster_idx": 3}, {"solution": "def vowels_count(s):\n vowels = ['a', 'e', 'i', 'o', 'u']\n count = 0\n\n # convert the string to lowercase\n s = s.lower()\n\n # iterate through the string and increase count when a vowel is found\n for i in range(len(s)):\n if s[i] in vowels:\n count += 1\n # check if 'y' is at the end of the word and increase count if true\n elif s[i] == 'y' and i == len(s) - 1:\n count += 1\n\n return count", "matching_cluster_idx": 3}, {"solution": "def vowels_count(s):\n s = s.lower() # convert string to lowercase to handle capitalized letters\n vowels = 'aeiou'\n count = 0\n for i, letter in enumerate(s):\n if letter in vowels:\n count += 1\n elif letter == 'y' and i == len(s) - 1:\n # if letter is 'y' and it's the last letter in the word\n count += 1\n return count", "matching_cluster_idx": 3}, {"solution": "def vowels_count(s):\n s = s.lower()\n count = 0\n for i, char in enumerate(s):\n if char in 'aeiou':\n count += 1\n elif char == 'y' and i == len(s) - 1:\n count += 1\n return count", "matching_cluster_idx": 3}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n s = s.lower()\n vowels = ['a', 'e', 'i', 'o', 'u']\n count = sum(1 for letter in s if letter in vowels)\n if s.endswith('y'):\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n s = s.lower()\n vowels = ['a', 'e', 'i', 'o', 'u']\n count = sum(1 for char in s if char in vowels)\n if s.endswith('y'):\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n s = s.lower()\n vowels = \"aeiou\"\n count = 0\n for i, char in enumerate(s):\n if char in vowels:\n count += 1\n elif char == \"y\" and i == len(s) - 1:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def vowels_count(s):\n vowels = 'aeiou'\n # increment count for each vowel found in the word\n count = sum(1 for letter in s.lower() if letter in vowels)\n # if word ends in 'y', increment count\n if s.lower().endswith('y'):\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n vowels = ['a', 'e', 'i', 'o', 'u']\n s = s.lower()\n count = 0\n for i in range(len(s)):\n if s[i] in vowels or (s[i] == 'y' and i == len(s) - 1):\n count += 1\n return count", "matching_cluster_idx": 3}, {"solution": "def vowels_count(s):\n # Convert the string to lower case to avoid handling upper case characters separately\n s = s.lower()\n # Initialize the count of vowels\n count = 0\n # Check if each character is a vowel and increment the count accordingly\n for i in range(len(s)):\n if s[i] in ('a', 'e', 'i', 'o', 'u'):\n count += 1\n # Check if 'y' is a vowel (only if it is at the end of the word)\n elif i == len(s) - 1 and s[i] == 'y':\n count += 1\n # Return the count of vowels\n return count", "matching_cluster_idx": 3}, {"solution": "def vowels_count(s):\n s = s.lower()\n count = 0\n vowels = ['a', 'e', 'i', 'o', 'u']\n for i, char in enumerate(s):\n if char in vowels:\n count += 1\n elif char == 'y' and i == len(s) - 1:\n count += 1\n return count", "matching_cluster_idx": 3}, {"solution": "def vowels_count(s):\n # Convert input string to lowercase for easier comparison\n s = s.lower()\n # Define a set of vowels, including 'y'\n vowels = set('aeiouy')\n # Initialize a count variable to 0\n count = 0\n # Iterate over each character in the string\n for i, char in enumerate(s):\n # If the character is a vowel and it is not 'y' or it is 'y' and it is the last character in the string\n if char in vowels and (char != 'y' or i == len(s) - 1):\n # Increment the count by 1\n count += 1\n # Return the final count\n return count", "matching_cluster_idx": 2}, {"solution": "def vowels_count(s):\n s = s.lower()\n count = 0\n for i, char in enumerate(s):\n if char in 'aeiou':\n count += 1\n if char == 'y' and i == len(s) - 1:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = \"aeiou\"\n # converting the string to lowercase to make the function case-insensitive\n s = s.lower()\n\n # if 'y' is at the end of the word, add it to the vowels count\n if s.endswith('y'):\n return sum(s.count(v) for v in vowels) + 1\n\n # else, just count the occurrences of each vowel\n return sum(s.count(v) for v in vowels)", "matching_cluster_idx": 6}, {"solution": "def vowels_count(s):\n vowels = 'aeiou'\n s = s.lower()\n return sum(1 for c in s if c in vowels) + (1 if s.endswith('y') else 0)", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n vowels = 'aeiou'\n count = 0\n for i, char in enumerate(s.lower()):\n if char in vowels:\n count += 1\n elif char == 'y' and i == len(s) - 1:\n count += 1\n return count", "matching_cluster_idx": 3}]}, "HumanEval/74": {"dps": 98.14634146341463, "dps_norm": 89.44444444444444, "pass@1": 47.0, "profiled": [{"solution": "def total_match(lst1, lst2):\n len_lst1 = sum(len(s) for s in lst1)\n len_lst2 = sum(len(s) for s in lst2)\n return lst1 if len_lst1 <= len_lst2 else lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n sum1 = sum(len(word) for word in lst1)\n sum2 = sum(len(word) for word in lst2)\n\n if sum1 <= sum2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n sum_chars_lst1 = sum(len(word) for word in lst1)\n sum_chars_lst2 = sum(len(word) for word in lst2)\n return lst1 if sum_chars_lst1 <= sum_chars_lst2 else lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n sum_lst1 = sum(len(s) for s in lst1)\n sum_lst2 = sum(len(s) for s in lst2)\n\n if sum_lst1 <= sum_lst2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n sum_lst1 = sum(len(i) for i in lst1)\n sum_lst2 = sum(len(i) for i in lst2)\n return lst1 if sum_lst1 <= sum_lst2 else lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n total_chars_lst1 = sum(len(string) for string in lst1)\n total_chars_lst2 = sum(len(string) for string in lst2)\n\n if total_chars_lst1 <= total_chars_lst2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n sum_lst1 = sum(len(str) for str in lst1)\n sum_lst2 = sum(len(str) for str in lst2)\n return lst1 if sum_lst1 <= sum_lst2 else lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n total_chars_lst1 = sum(len(i) for i in lst1)\n total_chars_lst2 = sum(len(i) for i in lst2)\n\n if total_chars_lst1 <= total_chars_lst2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n sum1 = sum(len(i) for i in lst1)\n sum2 = sum(len(i) for i in lst2)\n if sum1 <= sum2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n total_chars_lst1 = sum(len(s) for s in lst1)\n total_chars_lst2 = sum(len(s) for s in lst2)\n\n if total_chars_lst1 <= total_chars_lst2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n # Calculate total characters for each list\n lst1_chars = sum(len(str) for str in lst1)\n lst2_chars = sum(len(str) for str in lst2)\n # Compare and return the list with fewer characters\n return lst1 if lst1_chars <= lst2_chars else lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Function that accepts two lists of strings and returns the list\n that has total number of chars in the all strings of the list\n less than the other list.\n If the two lists have the same number of chars, it returns the first list.\n '''\n return lst1 if sum(map(len, lst1)) <= sum(map(len, lst2)) else lst2", "matching_cluster_idx": 8}, {"solution": "def total_match(lst1, lst2):\n sum1 = sum(len(s) for s in lst1)\n sum2 = sum(len(s) for s in lst2)\n return lst1 if sum1 <= sum2 else lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n sum1 = sum(len(word) for word in lst1)\n sum2 = sum(len(word) for word in lst2)\n if sum1 <= sum2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n total_chars_lst1 = sum(len(s) for s in lst1)\n total_chars_lst2 = sum(len(s) for s in lst2)\n return lst2 if total_chars_lst1 > total_chars_lst2 else lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n sum1 = sum(len(i) for i in lst1)\n sum2 = sum(len(i) for i in lst2)\n\n if sum1 <= sum2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n sum_chars_lst1 = sum(len(word) for word in lst1)\n sum_chars_lst2 = sum(len(word) for word in lst2)\n return lst1 if sum_chars_lst1 <= sum_chars_lst2 else lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n return lst1 if sum(len(word) for word in lst1) <= sum(len(word) for word in lst2) else lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has\n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n '''\n total_chars_lst1 = sum(len(i) for i in lst1)\n total_chars_lst2 = sum(len(i) for i in lst2)\n\n if total_chars_lst1 <= total_chars_lst2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n sum1 = sum(len(i) for i in lst1)\n sum2 = sum(len(i) for i in lst2)\n return lst1 if sum1 <= sum2 else lst2", "matching_cluster_idx": 7}]}, "HumanEval/85": {"dps": 85.0, "dps_norm": 51.666666666666664, "pass@1": 100.0, "profiled": [{"solution": "def add(lst):\n \"\"\"\n Given a non-empty list of integers lst, add the even elements that are at odd indices.\n \"\"\"\n return sum(lst[i] for i in range(1, len(lst), 2) if lst[i] % 2 == 0)", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2\n \"\"\"\n return sum(x for i, x in enumerate(lst) if i % 2 != 0 and x % 2 == 0)", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2\n \"\"\"\n return sum(x for i, x in enumerate(lst) if i % 2 != 0 and x % 2 == 0)", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2\n \"\"\"\n # Initializing the total sum to 0\n total_sum = 0\n # Looping through each element in the list\n for i in range(len(lst)):\n # If the index is odd and the element is even, add it to the total sum\n if i % 2 != 0 and lst[i] % 2 == 0:\n total_sum += lst[i]\n # Returning the total sum\n return total_sum", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) == 2\n add([1, 4, 2, 6, 7, 8]) == 10\n add([1, 3, 5]) == 0\n \"\"\"\n return sum(val for idx, val in enumerate(lst) if idx % 2 != 0 and val % 2 == 0)", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2\n \"\"\"\n return sum(num for i, num in enumerate(lst) if i % 2 != 0 and num % 2 == 0)", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2\n \"\"\"\n sum_evens_odd_indices = 0\n for i in range(1, len(lst), 2):\n if lst[i] % 2 == 0:\n sum_evens_odd_indices += lst[i]\n return sum_evens_odd_indices", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2\n \"\"\"\n return sum(x for i, x in enumerate(lst) if i % 2 == 1 and x % 2 == 0)", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2\n \"\"\"\n return sum(x for i, x in enumerate(lst) if i % 2 == 1 and x % 2 == 0)", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2\n \"\"\"\n return sum(lst[i] for i in range(1, len(lst), 2) if lst[i] % 2 == 0)", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n # Filter the list by even numbers at odd indices\n even_at_odd_indices = [num for i, num in enumerate(lst) if num % 2 == 0 and i % 2 == 1]\n # Return the sum of the list\n return sum(even_at_odd_indices)", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2\n \"\"\"\n # Create a list comprehension with a conditional statement\n even_at_odd_indices = [lst[i] for i in range(len(lst)) if i % 2 != 0 and lst[i] % 2 == 0]\n # Return the sum of the even elements at odd indices\n return sum(even_at_odd_indices)", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"\n Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2\n \"\"\"\n return sum(x for i, x in enumerate(lst) if i % 2 != 0 and x % 2 == 0)", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. Add the even elements that are at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2\n \"\"\"\n # initialize the result to 0\n result = 0\n # loop over the indices and elements of the list simultaneously\n for i, num in enumerate(lst):\n # check if the index is odd and the number is even\n if i % 2 != 0 and num % 2 == 0:\n # if so, add the number to the result\n result += num\n # return the final result\n return result", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2\n \"\"\"\n return sum(val for idx, val in enumerate(lst) if idx % 2 != 0 and val % 2 == 0)", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2\n \"\"\"\n return sum(i for index, i in enumerate(lst) if index % 2 != 0 and i % 2 == 0)", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n return sum(value for index, value in enumerate(lst) if value % 2 == 0 and index % 2 != 0)", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. Add the even elements that are at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2\n \"\"\"\n return sum(val for idx, val in enumerate(lst) if idx % 2 != 0 and val % 2 == 0)", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2\n \"\"\"\n return sum(x for i, x in enumerate(lst) if i % 2 != 0 and x % 2 == 0)", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2\n \"\"\"\n return sum(val for i, val in enumerate(lst) if val % 2 == 0 and i % 2 != 0)", "matching_cluster_idx": 2}]}, "HumanEval/86": {"dps": 95.61224489795919, "dps_norm": 98.0, "pass@1": 41.0, "profiled": [{"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n return ' '.join(''.join(sorted(word)) for word in s.split(' '))", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n # Splitting the string into words\n words = s.split(' ')\n # Creating a list to hold the new words with sorted characters\n new_words = []\n # Looping through each word\n for word in words:\n # Sorting the characters in the word in ascending order\n sorted_word = ''.join(sorted(word))\n # Appending the sorted word to the new_words list\n new_words.append(sorted_word)\n # Joining the new_words list back into a string, with a space between each word\n new_string = ' '.join(new_words)\n # Returning the new string\n return new_string", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n # Split the string into words\n words = s.split(' ')\n\n # Sort the characters in each word\n sorted_words = [''.join(sorted(word)) for word in words]\n\n # Join the words back together into a single string\n ordered_string = ' '.join(sorted_words)\n\n return ordered_string", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n \"\"\"\n # Split the string into list of words.\n words = s.split(\" \")\n\n # For each word, sort the characters and join them back together.\n sorted_words = [''.join(sorted(word)) for word in words]\n\n # Join the sorted words back into a string with space separators.\n sorted_string = ' '.join(sorted_words)\n\n return sorted_string", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n # Split the string into words\n words = s.split(' ')\n # For each word, sort the characters in ascending order based on ASCII value\n ordered_words = [''.join(sorted(word)) for word in words]\n # Join the sorted words back into a string with spaces in between\n return ' '.join(ordered_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n \"\"\"\n # Split the input string into a list of words\n words = s.split(' ')\n # Sort each word in the list of words\n sorted_words = [''.join(sorted(word)) for word in words]\n # Join the sorted words back into a string with space as separator\n result = ' '.join(sorted_words)\n return result", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n # split the string into a list of words\n words = s.split(' ')\n # for each word, sort its characters in ascending order based on ascii value\n for i in range(len(words)):\n words[i] = ''.join(sorted(words[i]))\n # join the words back into a string, separated by spaces\n return ' '.join(words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n # split the string into words\n words = s.split(' ')\n\n # sort the characters in each word\n sorted_words = [''.join(sorted(word)) for word in words]\n\n # join the words back together\n sorted_s = ' '.join(sorted_words)\n\n return sorted_s", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n # split the string into a list of words\n words = s.split(' ')\n # initialize an empty list to store the anti-shuffled words\n anti_shuffled_words = []\n # loop through each word in the list of words\n for word in words:\n # split the word into a list of letters\n letters = list(word)\n # sort the list of letters in ascending order based on ASCII value\n letters.sort(key=ord)\n # join the list of sorted letters into a string\n sorted_word = ''.join(letters)\n # append the sorted word to the list of anti-shuffled words\n anti_shuffled_words.append(sorted_word)\n # join the list of anti-shuffled words into a string, with spaces between words\n anti_shuffled_sentence = ' '.join(anti_shuffled_words)\n # return the anti-shuffled sentence\n return anti_shuffled_sentence", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n # Split the string into words\n words = s.split(' ')\n\n # Order each word\n ordered_words = [''.join(sorted(word)) for word in words]\n\n # Combine the words back into a single string\n ordered_string = ' '.join(ordered_words)\n\n return ordered_string", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n \"\"\"\n # Split the string into words\n words = s.split(' ')\n # Sort each word and join them back together\n ordered_words = [''.join(sorted(word)) for word in words]\n # Join the ordered words with spaces to get the ordered sentence\n ordered_s = ' '.join(ordered_words)\n return ordered_s", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n # Split the string into words\n words = s.split(\" \")\n\n # For each word, sort its characters and join them together\n ordered_words = [''.join(sorted(word)) for word in words]\n\n # Join the ordered words with spaces and return the result\n return ' '.join(ordered_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n words = s.split(' ')\n shuffled_words = [''.join(sorted(word)) for word in words]\n return ' '.join(shuffled_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n # Split string into words\n words = s.split(' ')\n\n # For each word, sort the characters\n sorted_words = [''.join(sorted(word)) for word in words]\n\n # Reconstruct the string with sorted words and return\n return ' '.join(sorted_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n return \" \".join([''.join(sorted(word)) for word in s.split(' ')])", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n # Split string into words\n words = s.split(' ')\n\n # For each word, sort characters\n ordered_words = [''.join(sorted(word)) for word in words]\n\n # Join words back together\n return ' '.join(ordered_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n words = s.split(' ')\n ordered_words = [''.join(sorted(word)) for word in words]\n return ' '.join(ordered_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n \"\"\"\n words = s.split(' ')\n ordered_words = []\n for word in words:\n ordered_word = ''.join(sorted(word))\n ordered_words.append(ordered_word)\n return ' '.join(ordered_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n # Splitting the input string into a list of words\n words = s.split(\" \")\n\n # Initiating an empty list to hold ordered words\n ordered_words = []\n\n # Iterating over each word\n for word in words:\n # Splitting each word into a list of characters\n chars = list(word)\n\n # Sorting the characters based on their ASCII values\n chars.sort(key=lambda x: ord(x))\n\n # Joining the sorted characters to form the ordered word\n ordered_word = \"\".join(chars)\n\n # Appending the ordered word to the list\n ordered_words.append(ordered_word)\n\n # Joining the ordered words to form the ordered sentence\n ordered_sentence = \" \".join(ordered_words)\n\n return ordered_sentence", "matching_cluster_idx": 2}, {"solution": "def anti_shuffle(s):\n words = s.split(' ')\n anti_shuffled_words = [''.join(sorted(word)) for word in words]\n return ' '.join(anti_shuffled_words)", "matching_cluster_idx": 4}]}, "HumanEval/87": {"dps": 61.023054755043226, "dps_norm": 52.142857142857146, "pass@1": 78.0, "profiled": [{"solution": "def get_row(lst, x):\n coordinates = []\n for i in range(len(lst)):\n for j in range(len(lst[i])):\n if lst[i][j] == x:\n coordinates.append((i, j))\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n return coordinates", "matching_cluster_idx": 2}, {"solution": "def get_row(lst, x):\n coordinates = []\n for i, row in enumerate(lst):\n for j, val in enumerate(row[::-1]):\n if val == x:\n coordinates.append((i, len(row) - j - 1))\n return sorted(coordinates, key=lambda x: (x[0], -x[1]))", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n coordinates = []\n for i, row in enumerate(lst):\n for j, elem in enumerate(row[::-1]):\n if elem == x:\n coordinates.append((i, len(row) - 1 - j))\n return sorted(coordinates, key=lambda x: (x[0], -x[1]))", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n Find all occurrences of integer x in a given 2D list and return a list of tuples representing their coordinates.\n Coordinates are sorted initially by rows in ascending order, and then by columns in descending order within each row.\n \"\"\"\n coords = [(i, j) for i, row in enumerate(lst) for j, val in enumerate(row) if val == x]\n coords.sort(key=lambda x: (x[0], -x[1]))\n return coords", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n coords = []\n for i, row in enumerate(lst):\n for j, val in enumerate(row):\n if val == x:\n coords.append((i, j))\n coords.sort(key = lambda coord: (coord[0], -coord[1]))\n return coords", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n coordinates = []\n for i in range(len(lst)):\n for j in range(len(lst[i])):\n if lst[i][j] == x:\n coordinates.append((i, j))\n return sorted(sorted(coordinates, key=lambda k: k[1], reverse=True), key=lambda k: k[0])", "matching_cluster_idx": 2}, {"solution": "def get_row(lst, x):\n coordinates = []\n for i in range(len(lst)):\n for j in range(len(lst[i])):\n if lst[i][j] == x:\n coordinates.append((i, j))\n return sorted(coordinates, key = lambda x: (x[0], -x[1]))", "matching_cluster_idx": 2}, {"solution": "def get_row(lst, x):\n coordinates = []\n for i, row in enumerate(lst):\n for j, col in enumerate(row):\n if col == x:\n coordinates.append((i, j))\n return sorted(coordinates, key=lambda x: (x[0], -x[1]))", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n coordinates = []\n for i in range(len(lst)):\n for j in range(len(lst[i])):\n if lst[i][j] == x:\n coordinates.append((i, j))\n # Sort by columns in descending order\n coordinates.sort(key=lambda coord: coord[1], reverse=True)\n # Sort by rows in ascending order\n coordinates.sort(key=lambda coord: coord[0])\n return coordinates", "matching_cluster_idx": 2}, {"solution": "def get_row(lst, x):\n coordinates = []\n for i in range(len(lst)):\n for j in range(len(lst[i])):\n if lst[i][j] == x:\n coordinates.append((i, j))\n coordinates.sort(key = lambda x: (x[0], -x[1]))\n return coordinates", "matching_cluster_idx": 2}, {"solution": "def get_row(lst, x):\n coordinates = []\n for i, row in enumerate(lst):\n if x in row:\n indices = [j for j, val in enumerate(row) if val == x]\n indices.reverse()\n coordinates.extend([(i, j) for j in indices])\n return coordinates", "matching_cluster_idx": 5}, {"solution": "def get_row(lst, x):\n coords = []\n for i in range(len(lst)):\n for j in range(len(lst[i])):\n if lst[i][j] == x:\n coords.append((i, j))\n coords.sort(key=lambda x: (x[0], -x[1]))\n return coords", "matching_cluster_idx": 2}, {"solution": "def get_row(lst, x):\n coords = []\n for i, row in enumerate(lst):\n for j, elem in enumerate(row):\n if elem == x:\n coords.append((i, j))\n coords.sort(key=lambda coord: (coord[0], -coord[1]))\n return coords", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n coordinates = []\n for i, row in enumerate(lst):\n for j, col in enumerate(row):\n if col == x:\n coordinates.append((i, j))\n coordinates.sort(key=lambda t: (t[0], -t[1]))\n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n # Create an empty list to store the coordinates\n coordinates = []\n\n # Iterate over the rows in the list\n for i in range(len(lst)):\n # Iterate over the columns in the current row\n for j in range(len(lst[i])):\n # If the current element equals x\n if lst[i][j] == x:\n # Append its coordinate to the list\n coordinates.append((i, j))\n\n # Sort the coordinates initially by rows in ascending order\n # and also, sort coordinates of the row by columns in descending order\n coordinates.sort(key = lambda x: (x[0], -x[1]))\n\n # Return the list of coordinates\n return coordinates", "matching_cluster_idx": 2}, {"solution": "def get_row(lst, x):\n # create a list of coordinates (row, col) for the given integer x\n coordinates = [(i, j) for i, row in enumerate(lst) for j, val in enumerate(row) if val == x]\n # sort the list of coordinates by rows in ascending order and then by columns in descending order\n coordinates.sort(key=lambda tup: (tup[0], -tup[1]))\n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n result = []\n for i in range(len(lst)):\n for j in range(len(lst[i])):\n if lst[i][j] == x:\n result.append((i, j))\n result.sort(key = lambda x: (x[0], -x[1]))\n return result", "matching_cluster_idx": 2}, {"solution": "def get_row(lst, x):\n coordinates = [(i, j) for i, row in enumerate(lst) for j, val in enumerate(row) if val == x]\n coordinates.sort(key = lambda coord: (coord[0], -coord[1]))\n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n coordinates = []\n for i in range(len(lst)):\n for j in range(len(lst[i])):\n if lst[i][j] == x:\n coordinates.append((i, j))\n\n # sort initially by rows in ascending order\n coordinates.sort(key = lambda coord: coord[0])\n\n # sort by columns in descending order for each row\n row_coordinates = []\n for i in range(len(coordinates)):\n if i == 0 or coordinates[i][0] != coordinates[i-1][0]:\n if row_coordinates:\n row_coordinates.sort(key = lambda coord: coord[1], reverse=True)\n coordinates[i-row_len:i] = row_coordinates\n row_coordinates = [coordinates[i]]\n row_len = 1\n else:\n row_coordinates.append(coordinates[i])\n row_len += 1\n\n if row_coordinates:\n row_coordinates.sort(key = lambda coord: coord[1], reverse=True)\n coordinates[-row_len:] = row_coordinates\n\n return coordinates", "matching_cluster_idx": 2}, {"solution": "def get_row(lst, x):\n coords = []\n for i, row in enumerate(lst):\n for j, val in enumerate(row):\n if val == x:\n coords.append((i, j))\n return sorted(coords, key=lambda coord: (coord[0], -coord[1]))", "matching_cluster_idx": 3}]}, "HumanEval/89": {"dps": 96.64948453608248, "dps_norm": 28.571428571428573, "pass@1": 73.0, "profiled": [{"solution": "def encrypt(s):\n result = \"\"\n for char in s:\n if char.isalpha():\n ascii_offset = ord('a') if char.islower() else ord('A')\n result += chr((ord(char) - ascii_offset + 4) % 26 + ascii_offset)\n else:\n result += char\n return result", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"\n Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated.\n The alphabet should be rotated in a manner such that the letters\n shift down by two multiplied to two places.\n\n Example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n encrypted = \"\"\n for char in s:\n ascii_val = ord(char)\n if char.islower():\n # For lowercase letters, shift down by 4 places and wrap around to 'a' if needed\n encrypted_val = (ascii_val - ord('a') + 4) % 26 + ord('a')\n elif char.isupper():\n # For uppercase letters, shift down by 4 places and wrap around to 'A' if needed\n encrypted_val = (ascii_val - ord('A') + 4) % 26 + ord('A')\n else:\n # For non-alphabetic characters, leave them as is\n encrypted_val = ascii_val\n encrypted += chr(encrypted_val)\n return encrypted", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n result = \"\"\n for letter in s:\n # check if the character is a letter\n if letter.isalpha():\n # if the letter is lowercase\n if letter.islower():\n result += chr(((ord(letter) - 97 + 2*2) % 26) + 97)\n # if the letter is uppercase\n else:\n result += chr(((ord(letter) - 65 + 2*2) % 26) + 65)\n else:\n result += letter\n return result", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n encrypted_s = \"\"\n for c in s:\n if c.isalpha():\n shift = 2 * 2\n ascii_offset = ord('a') if c.islower() else ord('A')\n encrypted_s += chr((ord(c) - ascii_offset + shift) % 26 + ascii_offset)\n else:\n encrypted_s += c\n return encrypted_s", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n encrypted = ''\n for c in s:\n if c.islower():\n encrypted += chr((ord(c) - 97 + 2*2) % 26 + 97)\n elif c.isupper():\n encrypted += chr((ord(c) - 65 + 2*2) % 26 + 65)\n else:\n encrypted += c\n return encrypted", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"\n Create a function encrypt that takes a string as an argument\n and returns a string encrypted with the alphabet being rotated.\n The alphabet should be rotated in a manner such that the letters\n shift down by two multiplied to two places.\n \"\"\"\n # create empty string to store encrypted text\n encrypted_text = \"\"\n # iterate through characters in input string\n for char in s:\n # check if character is a letter\n if char.isalpha():\n # determine whether character is upper or lowercase\n shift = 2 * 2 if char.isupper() else 2 * 2\n # rotate character two places down the alphabet\n encrypted_char = chr((ord(char) + shift - 65) % 26 + 65) if char.isupper() else chr((ord(char) + shift - 97) % 26 + 97)\n # append encrypted character to encrypted text\n encrypted_text += encrypted_char\n else:\n # append non-letter characters to encrypted text unchanged\n encrypted_text += char\n # return encrypted text\n return encrypted_text", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n encrypted = \"\"\n for c in s:\n if c.isalpha():\n shift = 2 * 2\n start = ord('a') if c.islower() else ord('A')\n encrypted += chr((ord(c) - start + shift) % 26 + start)\n else:\n encrypted += c\n return encrypted", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n result = ''\n for char in s:\n if char.isalpha():\n ascii_offset = 97 if char.islower() else 65 # ASCII value of 'a' or 'A'\n result += chr((ord(char) - ascii_offset + 2 * 2) % 26 + ascii_offset)\n else:\n result += char\n return result", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n result = \"\"\n\n for char in s:\n if char.isalpha():\n ascii_offset = 97 if char.islower() else 65\n result += chr((ord(char) - ascii_offset + 2 * 2) % 26 + ascii_offset)\n else:\n result += char\n\n return result", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n encrypted_str = \"\"\n for ch in s:\n if ch.isalpha():\n shift = 4 if ch.islower() else 4 # rotate down by 4 places for both lower and upper case letters\n encrypted_str += chr((ord(ch) - ord('a' if ch.islower() else 'A') + shift) % 26 + ord('a' if ch.islower() else 'A'))\n else:\n encrypted_str += ch # keep non-alphabet characters as is\n return encrypted_str", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n result = \"\"\n for char in s:\n if char.isalpha():\n # get unicode of character, apply shift, and convert back to character\n if char.isupper():\n result += chr((ord(char) - 65 + 2*2) % 26 + 65)\n else:\n result += chr((ord(char) - 97 + 2*2) % 26 + 97)\n else:\n # keep non-alphabet characters unchanged\n result += char\n return result", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n alphabet = 'abcdefghijklmnopqrstuvwxyz'\n shift = 2 * 2\n encrypted_s = ''\n for char in s:\n if char in alphabet:\n index = (alphabet.index(char) + shift) % len(alphabet)\n encrypted_s += alphabet[index]\n else:\n encrypted_s += char\n return encrypted_s", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n encrypted_string = ''\n for char in s:\n if char.isalpha():\n ascii_offset = 97 if char.islower() else 65\n encrypted_string += chr((ord(char) - ascii_offset + 4) % 26 + ascii_offset)\n else:\n encrypted_string += char\n return encrypted_string", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n encrypted_s = \"\"\n for char in s:\n if char.isalpha():\n if char.isupper():\n encrypted_s += chr((ord(char) - 65 + 2 * 2) % 26 + 65)\n else:\n encrypted_s += chr((ord(char) - 97 + 2 * 2) % 26 + 97)\n else:\n encrypted_s += char\n return encrypted_s", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated.\n The alphabet should be rotated in a manner such that the letters\n shift down by two multiplied to two places.\n \"\"\"\n result = ''\n for char in s:\n if char.isalpha():\n ascii_offset = 97 if char.islower() else 65\n result += chr((ord(char) - ascii_offset + 4) % 26 + ascii_offset)\n else:\n result += char\n return result", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n encrypted_text = \"\"\n for char in s:\n if char.isalpha():\n ascii_offset = 97 if char.islower() else 65\n encrypted_text += chr((ord(char) - ascii_offset + 2 * 2) % 26 + ascii_offset)\n else:\n encrypted_text += char\n return encrypted_text", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated.\n The alphabet should be rotated in a manner such that the letters\n shift down by two multiplied to two places.\n \"\"\"\n result = ''\n for char in s:\n # ensure the character is a lowercase letter\n if char.islower():\n # use the 'ord' function to get the ASCII value of the character\n # add 4 to the ASCII value and use the modulus operator to wrap around 'z'\n result += chr((ord(char) - ord('a') + 4) % 26 + ord('a'))\n # if the character is uppercase, convert it to lowercase before encrypting\n elif char.isupper():\n result += chr((ord(char) - ord('A') + 4) % 26 + ord('A'))\n # if the character is not a letter, leave it unchanged\n else:\n result += char\n return result", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"\n Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated.\n The alphabet should be rotated in a manner such that the letters\n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n encrypted_text = \"\"\n for char in s:\n # Check if character is an alphabet\n if char.isalpha():\n # Convert the alphabet to ASCII and calculate the shift\n ascii_offset = 65 if char.isupper() else 97\n encrypted_text += chr((ord(char) - ascii_offset + 4) % 26 + ascii_offset)\n else:\n encrypted_text += char\n return encrypted_text", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated.\n The alphabet should be rotated in a manner such that the letters\n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n result = \"\"\n for char in s:\n if char.isalpha():\n ascii_offset = 97 if char.islower() else 65\n result += chr((ord(char) - ascii_offset + 2 * 2) % 26 + ascii_offset)\n else:\n result += char\n return result", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n result = \"\"\n for char in s:\n # Check if the character is a lowercase letter\n if char.isalpha() and char.islower():\n # Shift the letter down by two multiplied by two places\n encrypted_char = chr((ord(char) - ord('a') + 4) % 26 + ord('a'))\n result += encrypted_char\n else:\n # If the character is not a lowercase letter, leave it as is\n result += char\n return result", "matching_cluster_idx": 1}]}, "HumanEval/90": {"dps": 59.82490272373541, "dps_norm": 50.416666666666664, "pass@1": 76.0, "profiled": [{"solution": "def next_smallest(lst):\n if len(lst) < 2:\n return None\n\n smallest = second_smallest = float('inf')\n for num in lst:\n if num < smallest:\n second_smallest = smallest\n smallest = num\n elif smallest < num < second_smallest:\n second_smallest = num\n\n return None if second_smallest == float('inf') else second_smallest", "matching_cluster_idx": 5}, {"solution": "def next_smallest(lst):\n # sorting the list in ascending order\n sorted_list = sorted(lst)\n\n # remove duplicates from the sorted list\n unique_list = []\n for num in sorted_list:\n if num not in unique_list:\n unique_list.append(num)\n\n # check if there is a second smallest element and return it\n if len(unique_list) >= 2:\n return unique_list[1]\n else:\n return None", "matching_cluster_idx": 0}, {"solution": "def next_smallest(lst):\n if len(lst) < 2:\n return None\n smallest = second_smallest = float('inf')\n for num in lst:\n if num < smallest:\n second_smallest = smallest\n smallest = num\n elif smallest < num < second_smallest:\n second_smallest = num\n if second_smallest == float('inf'):\n return None\n return second_smallest", "matching_cluster_idx": 5}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n\n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n # First, we remove any duplicates from the list\n lst = list(set(lst))\n\n # Then, we sort the list\n lst.sort()\n\n # If the list has less than 2 elements, we return None\n if len(lst) < 2:\n return None\n\n # Otherwise, we return the second element\n return lst[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \"\"\"\n if len(lst) < 2:\n return None\n\n smallest = float('inf')\n next_smallest = float('inf')\n\n for num in lst:\n if num < smallest:\n next_smallest = smallest\n smallest = num\n elif num < next_smallest and num != smallest:\n next_smallest = num\n\n return None if next_smallest == float('inf') else next_smallest", "matching_cluster_idx": 5}, {"solution": "def next_smallest(lst):\n # Check if list is long enough\n if len(lst) < 2:\n return None\n # Remove duplicates\n unique_lst = list(set(lst))\n # Check if list with unique elements has enough numbers\n if len(unique_lst) < 2:\n return None\n # Sort the list and return the second smallest number\n unique_lst.sort()\n return unique_lst[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n # first we eliminate any duplicates from the list\n unique_lst = list(set(lst))\n # then we sort the list\n sorted_lst = sorted(unique_lst)\n # if the list has less than 2 elements, return None\n if len(sorted_lst) < 2:\n return None\n # otherwise, return the 2nd smallest element\n else:\n return sorted_lst[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n if len(lst) < 2:\n return None\n\n smallest = float('inf')\n second_smallest = float('inf')\n\n for i in lst:\n if i < smallest:\n second_smallest = smallest\n smallest = i\n elif i < second_smallest and i != smallest:\n second_smallest = i\n\n if second_smallest == float('inf'):\n return None\n\n return second_smallest", "matching_cluster_idx": 5}, {"solution": "def next_smallest(lst):\n # Removing duplicates from the list\n unique_lst = list(set(lst))\n\n # If the list has less than 2 elements, return None\n if len(unique_lst) < 2:\n return None\n\n # Sorting the list in ascending order\n unique_lst.sort()\n\n # Returning the 2nd element in the sorted list\n return unique_lst[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n This function returns the 2nd smallest element of the list.\n If there is no such element, the function will return None.\n \"\"\"\n # Check if the list has at least two elements\n if len(lst) < 2:\n return None\n\n # Initialize the smallest and second smallest elements to None\n smallest = second_smallest = None\n\n # Iterate over all elements in the list\n for num in lst:\n # If the current number is smaller than the smallest number seen so far\n if smallest is None or num < smallest:\n # Shift the smallest and the second smallest elements\n second_smallest = smallest\n smallest = num\n # If the current number is greater than the smallest but smaller than the second smallest\n elif smallest < num < (second_smallest if second_smallest is not None else float('inf')):\n # Update the second smallest element\n second_smallest = num\n\n # If there is no second smallest element, return None\n if second_smallest is None:\n return None\n\n # Otherwise, return the second smallest element\n return second_smallest", "matching_cluster_idx": 4}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n\n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n unique_numbers = set(lst)\n if len(unique_numbers) < 2:\n return None\n else:\n unique_numbers.remove(min(unique_numbers))\n return min(unique_numbers)", "matching_cluster_idx": 5}, {"solution": "def next_smallest(lst):\n if len(lst) < 2:\n return None\n\n smallest = second_smallest = float('inf')\n\n for num in lst:\n if num < smallest:\n second_smallest = smallest\n smallest = num\n elif num < second_smallest and num != smallest:\n second_smallest = num\n\n return None if second_smallest == float('inf') else second_smallest", "matching_cluster_idx": 5}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \"\"\"\n if len(lst) < 2:\n return None\n\n smallest = second_smallest = float('inf')\n for num in lst:\n if num < smallest:\n second_smallest = smallest\n smallest = num\n elif smallest < num < second_smallest:\n second_smallest = num\n\n if second_smallest == float('inf'):\n return None\n\n return second_smallest", "matching_cluster_idx": 5}, {"solution": "def next_smallest(lst):\n if len(lst) < 2:\n return None\n\n smallest = float('inf')\n next_smallest = float('inf')\n\n for num in lst:\n if num < smallest:\n next_smallest = smallest\n smallest = num\n elif smallest < num < next_smallest:\n next_smallest = num\n\n if next_smallest == float('inf'):\n return None\n\n return next_smallest", "matching_cluster_idx": 5}, {"solution": "def next_smallest(lst):\n if len(lst) < 2:\n return None\n\n smallest = float('inf')\n next_smallest = float('inf')\n\n for num in lst:\n if num < smallest:\n next_smallest = smallest\n smallest = num\n elif num < next_smallest and num != smallest:\n next_smallest = num\n\n return next_smallest if next_smallest != float('inf') else None", "matching_cluster_idx": 5}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \"\"\"\n # Remove duplicates from the list by converting it to a set and then back to a list\n lst = list(set(lst))\n # Sort the list in ascending order\n lst.sort()\n # If the list has less than 2 elements, return None\n if len(lst) < 2:\n return None\n # Otherwise, return the second element of the list\n else:\n return lst[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n if len(lst) < 2:\n return None\n smallest = float('inf')\n next_smallest = float('inf')\n for num in lst:\n if num < smallest:\n next_smallest = smallest\n smallest = num\n elif smallest < num < next_smallest:\n next_smallest = num\n return None if next_smallest == float('inf') else next_smallest", "matching_cluster_idx": 5}, {"solution": "def next_smallest(lst):\n # create a set from the list to remove duplicates, sort it in ascending order,\n # and check if there's at least 2 elements in the set\n sorted_set = sorted(set(lst))\n if len(sorted_set) >= 2:\n # if yes, return the second element\n return sorted_set[1]\n # otherwise, return None\n else:\n return None", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n if len(lst) < 2:\n return None\n lst = list(set(lst))\n lst.sort()\n return lst[1] if len(lst) >= 2 else None", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n # create a set from the list to eliminate duplicate elements\n unique_lst = set(lst)\n # check if the list contains at least 2 unique elements\n if len(unique_lst) < 2:\n return None\n # remove the smallest element from the set\n unique_lst.remove(min(unique_lst))\n # return the smallest remaining element (which is the 2nd smallest in the original list)\n return min(unique_lst)", "matching_cluster_idx": 5}]}, "HumanEval/113": {"dps": 98.98580121703854, "dps_norm": 66.66666666666667, "pass@1": 73.0, "profiled": [{"solution": "def odd_count(lst):\n output = []\n for s in lst:\n odd_count = sum([1 for c in s if int(c) % 2 != 0])\n output.append(f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\")\n return output", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n res = []\n for string in lst:\n count = sum(int(c) % 2 != 0 for c in string)\n res.append(f\"the number of odd elements {count}n the str{count}ng {count} of the {count}nput.\")\n return res", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n result = []\n for s in lst:\n odd_numbers = sum(1 for c in s if int(c) % 2 != 0)\n result.append(\"the number of odd elements \" + str(odd_numbers) + \"n the str\" + str(odd_numbers) + \"ng \" + str(odd_numbers) + \" of the \" + str(odd_numbers) + \"nput.\")\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n result = []\n for s in lst:\n odd_cnt = sum(1 for c in s if int(c) % 2 == 1)\n output_str = \"the number of odd elements {}n the str{}ng {} of the {}nput.\".format(odd_cnt, odd_cnt, odd_cnt, odd_cnt)\n result.append(output_str)\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n result = []\n for s in lst:\n count = sum(int(d) % 2 for d in s)\n output = \"the number of odd elements {}n the str{}ng {} of the {}nput.\".format(count, count, count, count)\n result.append(output)\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n result = []\n for s in lst:\n odd_digits = sum(1 for c in s if int(c) % 2 != 0)\n result.append(f\"the number of odd elements {odd_digits}n the str{odd_digits}ng {odd_digits} of the {odd_digits}nput.\")\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n output = []\n for string in lst:\n count = sum(1 for char in string if int(char) % 2 != 0)\n s = \"the number of odd elements {}n the str{}ng {} of the {}nput.\".format(count, count, count, count)\n output.append(s)\n return output", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n def replace_odd(s):\n num_odd = sum(int(c) % 2 for c in s)\n return 'the number of odd elements ' + str(num_odd) + 'n the str' + str(num_odd) + 'ng ' + str(num_odd) + ' of the ' + str(num_odd) + 'nput.'\n\n return [replace_odd(s) for s in lst]", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n output = []\n for i, s in enumerate(lst):\n num_odd = sum(int(c) % 2 for c in s)\n string_num_odd = str(num_odd)\n output.append(\"the number of odd elements {}n the str{}ng {} of the {}nput.\".format(string_num_odd, string_num_odd, string_num_odd, string_num_odd))\n return output", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n result = []\n for i, nums in enumerate(lst):\n odd_count = sum(1 for num in nums if int(num) % 2 != 0)\n statement = f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\"\n result.append(statement)\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"\n Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n \"\"\"\n result = []\n sentence = \"the number of odd elements in the string i of the input.\"\n\n for s in lst:\n count = sum([1 for c in s if int(c) % 2 != 0])\n new_sentence = sentence.replace(\"i\", str(count))\n result.append(new_sentence)\n\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n output = []\n for string in lst:\n count = sum(1 for char in string if int(char) % 2 != 0)\n result = \"the number of odd elements \" + str(count) + \"n the str\" + str(count) + \"ng \" + str(count) + \" of the \" + str(count) + \"nput.\"\n output.append(result)\n return output", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n result = []\n for s in lst:\n count = sum(int(d) % 2 for d in s)\n result.append(f\"the number of odd elements {count}n the str{count}ng {count} of the {count}nput.\")\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"\n Given a list of strings, where each string consists of only digits,\n return a list. Each element i of the output should be \"the number of\n odd elements in the string i of the input.\", where all the i's are\n replaced by the number of odd digits in the i'th string of the input.\n\n Examples:\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3', \"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n # Initialize an empty list to store the results\n result = []\n\n # Iterate over each string in the input list\n for s in lst:\n # Count the number of odd digits in the current string\n odd_digits = sum(1 for c in s if int(c) % 2 != 0)\n\n # Replace the placeholders in the template with the count of odd digits\n template = \"the number of odd elements {}n the str{}ng {} of the {}nput.\"\n result_str = template.format(odd_digits, odd_digits, odd_digits, odd_digits)\n\n # Add the result string to the result list\n result.append(result_str)\n\n # Return the result list\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n result = []\n for string in lst:\n odd_numbers = sum(1 for char in string if int(char) % 2 != 0)\n result.append(f\"the number of odd elements {odd_numbers}n the str{odd_numbers}ng {odd_numbers} of the {odd_numbers}nput.\")\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n result = []\n for s in lst:\n num_odd = str(sum(1 for c in s if int(c) % 2 != 0))\n text = \"the number of odd elements {}n the str{}ng {} of the {}nput.\"\n result.append(text.format(num_odd, num_odd, num_odd, num_odd))\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n output = []\n for i, string in enumerate(lst):\n num_odd = sum([1 for char in string if int(char) % 2 != 0])\n sentence = f\"the number of odd elements {num_odd}n the str{num_odd}ng {num_odd} of the {num_odd}nput.\"\n output.append(sentence)\n return output", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n result = []\n for i, s in enumerate(lst, start=1):\n count = sum(1 for c in s if int(c) % 2 != 0)\n output_string = f\"the number of odd elements {count}n the str{count}ng {count} of the {count}nput.\"\n result.append(output_string)\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n results = []\n for string in lst:\n num_odd = sum(int(char) % 2 != 0 for char in string)\n result = f\"the number of odd elements {num_odd}n the str{num_odd}ng {num_odd} of the {num_odd}nput.\"\n results.append(result)\n return results", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n result = []\n for str_number in lst:\n count = sum(1 for char in str_number if int(char) % 2 != 0)\n result.append(f\"the number of odd elements {count}n the str{count}ng {count} of the {count}nput.\")\n return result", "matching_cluster_idx": 3}]}, "HumanEval/119": {"dps": null, "dps_norm": null, "pass@1": 9.0, "profiled": []}, "HumanEval/120": {"dps": null, "dps_norm": null, "pass@1": 8.0, "profiled": []}, "HumanEval/121": {"dps": 81.0762331838565, "dps_norm": 60.0, "pass@1": 100.0, "profiled": [{"solution": "def solution(lst):\n return sum(num for i, num in enumerate(lst) if i % 2 == 0 and num % 2 != 0)", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n return sum(val for idx, val in enumerate(lst) if idx % 2 == 0 and val % 2 != 0)", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n return sum([lst[i] for i in range(len(lst)) if i % 2 == 0 and lst[i] % 2 == 1])", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n return sum(value for index, value in enumerate(lst) if index % 2 == 0 and value % 2 != 0)", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n \"\"\"\n Given a non-empty list of integers, return the sum of all of the odd elements\n that are in even positions.\n\n Args:\n lst (List[int]): List of integers.\n\n Returns:\n int: Sum of all odd elements in even positions.\n \"\"\"\n return sum(num for idx, num in enumerate(lst) if idx % 2 == 0 and num % 2 != 0)", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n return sum(val for i, val in enumerate(lst) if val % 2 != 0 and i % 2 == 0)", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n \"\"\"\n Given a non-empty list of integers, return the sum of all the odd elements that are in even positions.\n \"\"\"\n return sum(val for i, val in enumerate(lst) if i % 2 == 0 and val % 2 != 0)", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n return sum(val for i, val in enumerate(lst) if val % 2 != 0 and i % 2 == 0)", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n\n Examples:\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n return sum(val for i, val in enumerate(lst) if i % 2 == 0 and val % 2 != 0)", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n # Initialize the sum to 0\n sum = 0\n # Iterate through the list with even indexes\n for i in range(0, len(lst), 2):\n # Check if the element at the index is odd\n if lst[i] % 2 != 0:\n # If it is, add it to the sum\n sum += lst[i]\n # Return the sum of all odd elements at even positions\n return sum", "matching_cluster_idx": 4}, {"solution": "def solution(lst):\n return sum(x for i, x in enumerate(lst) if x % 2 != 0 and i % 2 == 0)", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n\n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n return sum(lst[i] for i in range(0, len(lst), 2) if lst[i] % 2 != 0)", "matching_cluster_idx": 4}, {"solution": "def solution(lst):\n return sum(x for i, x in enumerate(lst) if x % 2 == 1 and i % 2 == 0)", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n return sum(x for i, x in enumerate(lst) if i % 2 == 0 and x % 2 != 0)", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n # initialize sum variable\n odd_sum = 0\n # iterate over the list with indexes\n for i in range(len(lst)):\n # if index is even and value is odd, add it to the sum\n if i % 2 == 0 and lst[i] % 2 != 0:\n odd_sum += lst[i]\n return odd_sum", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\"\"\"\n return sum(val for idx, val in enumerate(lst) if idx % 2 == 0 and val % 2 != 0)", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n return sum(val for i, val in enumerate(lst) if i % 2 == 0 and val % 2 != 0)", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n return sum(val for idx, val in enumerate(lst) if val % 2 == 1 and idx % 2 == 0)", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n return sum(lst[i] for i in range(0, len(lst), 2) if lst[i] % 2 != 0)", "matching_cluster_idx": 4}, {"solution": "def solution(lst):\n \"\"\"\n Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n\n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==>0\n \"\"\"\n # Initial sum is 0\n result = 0\n\n # Iterate over elements with even index\n for i in range(0, len(lst), 2):\n\n # Check if the element is odd\n if lst[i] % 2 != 0:\n # Add the odd element to the sum\n result += lst[i]\n\n # Return the sum\n return result", "matching_cluster_idx": 4}]}, "HumanEval/149": {"dps": 85.82677165354332, "dps_norm": 57.142857142857146, "pass@1": 99.0, "profiled": [{"solution": "def sorted_list_sum(lst):\n filtered_lst = [i for i in lst if len(i) % 2 == 0]\n filtered_lst.sort(key=lambda x: (len(x), x))\n return filtered_lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n # Filter out strings with odd lengths\n lst = [word for word in lst if len(word) % 2 == 0]\n # Sort by length of each word and then alphabetically\n lst.sort(key=lambda word: (len(word), word))\n return lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n # filter out strings with odd lengths\n filtered_lst = [word for word in lst if len(word) % 2 == 0]\n # sort the list first by length of each word and then alphabetically\n sorted_lst = sorted(filtered_lst, key=lambda x: (len(x), x))\n return sorted_lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n # Filter out strings with odd lengths\n lst = [word for word in lst if len(word) % 2 == 0]\n # Sort the list in ascending order of length and alphabetically\n lst.sort(key=lambda word: (len(word), word))\n return lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n # Filter out the strings with odd lengths\n lst = [s for s in lst if len(s) % 2 == 0]\n\n # Sort the list by length of each word and then alphabetically if two words have the same length\n lst.sort(key=lambda s: (len(s), s))\n\n return lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n # Delete the strings that have odd lengths\n lst = [word for word in lst if len(word) % 2 == 0]\n # Sort the list by the length of each word\n # If two words have the same length, sort the list alphabetically\n lst.sort(key=lambda x: (len(x), x))\n return lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n # deletes the strings that have odd lengths from the list\n lst = [word for word in lst if len(word) % 2 == 0]\n # sort the list by length of each word and alphabetically if lengths are the same\n lst.sort(key = lambda x: (len(x), x))\n return lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n # Deleting strings with odd length\n lst = [word for word in lst if len(word) % 2 == 0]\n\n # Sorting list based on length of words and alphabetically if length is equal\n lst.sort(key=lambda word: (len(word), word))\n\n return lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order.\n \"\"\"\n # delete strings with odd lengths\n lst = [s for s in lst if len(s) % 2 == 0]\n # sort the list by length, and if two words have the same length, sort alphabetically\n lst.sort(key=lambda s: (len(s), s))\n return lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n # delete the strings that have odd lengths\n lst = [s for s in lst if len(s) % 2 == 0]\n # sort the list by length of each word and then alphabetically\n lst.sort(key=lambda s: (len(s), s))\n return lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n lst = [word for word in lst if len(word) % 2 == 0]\n lst.sort(key=lambda word: (len(word), word))\n return lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n # filter the list and remove strings with odd length\n lst = [s for s in lst if len(s) % 2 == 0]\n\n # sort the list by the length of each word and then alphabetically\n lst.sort(key=lambda s: (len(s), s))\n\n return lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order,\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n You may assume that all words will have the same length.\n For example:\n assert sorted_list_sum([\"aa\", \"a\", \"aaa\"]) => [\"aa\"]\n assert sorted_list_sum([\"ab\", \"a\", \"aaa\", \"cd\"]) => [\"ab\", \"cd\"]\n \"\"\"\n # Filter out words with odd length\n lst = [word for word in lst if len(word) % 2 == 0]\n # Sort list by length and then alphabetically\n lst.sort(key=lambda x: (len(x), x))\n return lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n # filter out strings with odd lengths\n lst = [i for i in lst if len(i) % 2 == 0]\n # sort list by length of each word and then alphabetically\n lst.sort(key=lambda s: (len(s), s))\n return lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n # Delete the strings that have odd lengths from the list\n lst = [word for word in lst if len(word) % 2 == 0]\n # Sort the list by length of each word and then alphabetically\n lst.sort(key=lambda word: (len(word), word))\n return lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n filtered_lst = [word for word in lst if len(word) % 2 == 0]\n sorted_lst = sorted(filtered_lst, key=lambda x: (len(x), x))\n return sorted_lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n lst = [word for word in lst if len(word) % 2 == 0]\n lst.sort(key=lambda x: (len(x), x))\n return lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n # Deletes strings that have odd lengths from the list\n lst = [word for word in lst if len(word) % 2 == 0]\n # Sorts the list in ascending order by length of each word, and then alphabetically for words with same length\n lst.sort(key=lambda x: (len(x), x))\n return lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n # Delete the strings with odd lengths from the list\n lst = [word for word in lst if len(word) % 2 == 0]\n\n # Sort the list by the length of each word in ascending order\n # If two words have the same length, sort the list alphabetically\n lst.sort(key=lambda x: (len(x), x))\n\n return lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n # Delete strings that have odd lengths\n lst = [s for s in lst if len(s) % 2 == 0]\n # Sort the list\n lst.sort(key=lambda s: (len(s), s))\n return lst", "matching_cluster_idx": 3}]}, "Mbpp/3": {"dps": 78.00847457627118, "dps_norm": 88.125, "pass@1": 98.0, "profiled": [{"solution": "def is_not_prime(n):\n if n < 2:\n return True\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return True\n return False", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(n):\n if n <= 1:\n return True\n if n <= 3:\n return False\n if n % 2 == 0 or n % 3 == 0:\n return True\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return True\n i += 6\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n if n <= 1:\n return True\n elif n <= 3:\n return False\n elif n % 2 == 0 or n % 3 == 0:\n return True\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return True\n i += 6\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n if n <= 1:\n return True\n elif n == 2:\n return False\n elif n % 2 == 0:\n return True\n else:\n for i in range(3, int(n**0.5) + 1, 2):\n if n % i == 0:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def is_prime(n):\n if n <= 1:\n return False\n elif n <= 3:\n return True\n elif n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True\ndef is_not_prime(n):\n return not is_prime(n)", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n \"\"\"\n This function takes an integer n as an input and returns True if the number is not prime,\n and False if the number is prime.\n \"\"\"\n if n <= 1:\n return True\n elif n <= 3:\n return False\n elif n % 2 == 0 or n % 3 == 0:\n return True\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return True\n i += 6\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n if n <= 1 or (n % 2 == 0 and n > 2):\n return True\n return any(n % i == 0 for i in range(3, int(n**0.5) + 1, 2))", "matching_cluster_idx": 6}, {"solution": "def is_not_prime(n):\n if n <= 1:\n return True\n elif n <= 3:\n return False\n elif n % 2 == 0 or n % 3 == 0:\n return True\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return True\n i += 6\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n if n <= 1:\n return True\n elif n <= 3:\n return False\n elif n % 2 == 0 or n % 3 == 0:\n return True\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return True\n i += 6\n return False", "matching_cluster_idx": 7}, {"solution": "def is_prime(n):\n if n < 2:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True\ndef is_not_prime(n):\n return not is_prime(n)", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(n):\n if n <= 1:\n return True\n for i in range(2, int(n ** 0.5) + 1):\n if n % i == 0:\n return True\n return False", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(n):\n if n <= 1:\n return True\n elif n <= 3:\n return False\n elif n % 2 == 0 or n % 3 == 0:\n return True\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return True\n i += 6\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n if n <= 1:\n return True\n elif n <= 3:\n return False\n elif n % 2 == 0 or n % 3 == 0:\n return True\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return True\n i += 6\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n if n < 2:\n return True\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return True\n return False", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(n):\n if n <= 1:\n return True\n elif n == 2:\n return False\n elif n % 2 == 0:\n return True\n i = 3\n while i * i <= n:\n if n % i:\n i += 2\n else:\n return True\n return False", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(n):\n if n <= 1:\n return True\n elif n <= 3:\n return False\n elif n % 2 == 0 or n % 3 == 0:\n return True\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return True\n i += 6\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n \"\"\"Return True if n is not a prime number. False if it is a prime number.\"\"\"\n if n < 2:\n return True\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return True\n return False", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(n):\n if n < 2:\n return True\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return True\n return False", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(n):\n \"\"\"\n This function takes an integer as an argument and returns True if the integer is not prime, and False if the integer is prime.\n \"\"\"\n # 0 and 1 are not prime\n if n < 2:\n return True\n\n # Check for divisibility from 2 to the square root of n\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return True\n\n return False", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(n):\n if n <= 1:\n return True\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return True\n return False", "matching_cluster_idx": 5}]}, "Mbpp/4": {"dps": 80.40955631399318, "dps_norm": 81.66666666666666, "pass@1": 95.0, "profiled": [{"solution": "def heap_queue_largest(nums, n):\n \"\"\"\n Find the n largest integers from a given list of numbers, returned in descending order.\n \"\"\"\n import heapq # python's built-in module that provides an implementation of the heap queue algorithm\n\n # Convert the input list to a list of negative numbers and use heapq.nsmallest() function\n # to find the n smallest numbers from the list. Then, convert the result back to positive numbers.\n return [-num for num in heapq.nsmallest(n, (-num for num in nums))]", "matching_cluster_idx": 8}, {"solution": "def heap_queue_largest(nums, n):\n import heapq\n return heapq.nlargest(n, nums)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(numbers, n):\n largest = heapq.nlargest(n, numbers)\n largest.sort(reverse=True)\n return largest", "matching_cluster_idx": 9}, {"solution": "def heap_queue_largest(numbers, n):\n import heapq\n return heapq.nlargest(n, numbers)", "matching_cluster_idx": 9}, {"solution": "def heap_queue_largest(nums, n):\n import heapq\n return sorted(heapq.nlargest(n, nums), reverse=True)", "matching_cluster_idx": 9}, {"solution": "def heap_queue_largest(nums, n):\n import heapq\n largest_nums = heapq.nlargest(n, nums)\n return sorted(largest_nums, reverse=True)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(numbers, n):\n # Use min heap with size n\n min_heap = []\n for number in numbers:\n # Add the number to the heap\n heapq.heappush(min_heap, number)\n # If the size of the heap exceeds n, remove the smallest number\n if len(min_heap) > n:\n heapq.heappop(min_heap)\n\n # The heap now contains the n largest numbers in ascending order.\n # Use sorted function to get these numbers in descending order.\n return sorted(min_heap, reverse=True)", "matching_cluster_idx": 8}, {"solution": "def heap_queue_largest(nums, n):\n import heapq\n # Using nlargest to get the n largest numbers\n largest_nums = heapq.nlargest(n, nums)\n # Sorting in descending order\n largest_nums.sort(reverse=True)\n return largest_nums", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n return heapq.nlargest(n, nums)", "matching_cluster_idx": 9}, {"solution": "def heap_queue_largest(nums, n):\n import heapq\n return heapq.nlargest(n, nums)", "matching_cluster_idx": 9}, {"solution": "def heap_queue_largest(lst, n):\n import heapq\n return heapq.nlargest(n, lst)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n \"\"\"\n Find the n largest integers from a given list of numbers, returned in descending order.\n :param nums: List of integers.\n :param n: Integer, number of largest integers to find.\n :return: List of n largest integers in descending order.\n \"\"\"\n if n <= 0 or nums == []:\n return []\n\n # Keep track of the n largest numbers in a min-heap\n largest = nums[:n]\n heapq.heapify(largest)\n\n for i in range(n, len(nums)):\n if nums[i] > largest[0]:\n heapq.heappop(largest)\n heapq.heappush(largest, nums[i])\n\n return sorted(largest, reverse=True)", "matching_cluster_idx": 9}, {"solution": "def heap_queue_largest(nums, n):\n import heapq\n heap = []\n for num in nums:\n heapq.heappush(heap, num)\n if len(heap) > n:\n heapq.heappop(heap)\n return sorted(heap, reverse=True)", "matching_cluster_idx": 8}, {"solution": "def heap_queue_largest(nums, n):\n \"\"\"\n A function to find the n largest integers from a given list of numbers, returned in descending order.\n\n :param nums: A list of integers.\n :param n: An integer, the number of largest integers to find.\n :return: A list of n largest integers, in descending order.\n \"\"\"\n import heapq\n\n # Push the numbers onto a min heap.\n min_heap = []\n for num in nums:\n heapq.heappush(min_heap, num)\n # If the size of the heap exceeds n, pop the smallest element.\n if len(min_heap) > n:\n heapq.heappop(min_heap)\n\n # The heap now contains the n largest elements.\n # Pop them all and return them in descending order.\n return [heapq.heappop(min_heap) for _ in range(n)][::-1]", "matching_cluster_idx": 8}, {"solution": "import heapq\ndef heap_queue_largest(numbers, n):\n # using heapq.nlargest function to get n largest numbers\n largest = heapq.nlargest(n, numbers)\n # sort the numbers in descending order\n largest.sort(reverse=True)\n return largest", "matching_cluster_idx": 9}, {"solution": "def heap_queue_largest(lst, n):\n import heapq\n return heapq.nlargest(n, lst)", "matching_cluster_idx": 9}, {"solution": "def heap_queue_largest(nums, n):\n import heapq\n return heapq.nlargest(n, nums)", "matching_cluster_idx": 9}, {"solution": "def heap_queue_largest(nums, n):\n import heapq\n return heapq.nlargest(n, nums)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n \"\"\"\n Find the n largest integers from a given list of numbers.\n\n Args:\n nums: list of integers\n n: integer, number of largest integers to return\n\n Returns:\n list of n largest integers, sorted in descending order\n \"\"\"\n # Use the nlargest function from the heapq module to get the n largest numbers\n largest_nums = heapq.nlargest(n, nums)\n\n # Sort the numbers in descending order\n largest_nums.sort(reverse=True)\n\n return largest_nums", "matching_cluster_idx": 9}, {"solution": "def heap_queue_largest(nums, n):\n import heapq\n return sorted(heapq.nlargest(n, nums), reverse=True)", "matching_cluster_idx": 9}]}, "Mbpp/9": {"dps": 31.564625850340136, "dps_norm": 46.0, "pass@1": 15.0, "profiled": [{"solution": "def find_Rotations(s):\n # Loop for n rotations (where n is length of the string)\n for i in range(1, len(s)):\n # Rotate the string by slicing it\n rotated_string = s[i:] + s[:i]\n # If the rotated string equals the original string\n if rotated_string == s:\n # Return the number of rotations\n return i\n # If no rotations required return the length of the string\n return len(s)", "matching_cluster_idx": 3}, {"solution": "def find_Rotations(s):\n # Get the length of the string\n n = len(s)\n\n # An array to hold the rotations of string s\n arr = ['' for _ in range(n)]\n\n # Fill arr[] with all rotations of s\n for i in range(n):\n arr[i] = s[i:n] + s[0:i]\n\n # Return the index of first occurrence of s\n for i in range(1, n):\n if arr[i] == s:\n return i\n\n # No rotation is needed, return n which is the length of the string\n return n", "matching_cluster_idx": 3}, {"solution": "def find_Rotations(s):\n n = len(s)\n for i in range(1, n):\n rotated_str = s[i:] + s[:i]\n if rotated_str == s:\n return i\n return n", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(s):\n \"\"\"\n Function to find the minimum number of rotations (greater than 0) required to get the same string.\n It considers the initial string and all of its rotations. For a given string, all rotations are\n considered different unless we perform rotation equal to the length of the string.\n \"\"\"\n # If length of string is 1, it's the same string in all rotations\n if len(s) == 1:\n return 1\n # Creating all rotations of the string and searching for the first occurence of the original string\n for i in range(1, len(s)):\n if s[i:] + s[:i] == s:\n return i\n # If the string is not found in any rotation, we return length of string\n return len(s)", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(s):\n n = len(s)\n rotations = 0\n for i in range(1, n):\n rotations += 1\n if s[i:] + s[:i] == s:\n return rotations\n return n", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(s: str) -> int:\n \"\"\"\n Find the minimum number of rotations (greater than 0) required to get the same string.\n \"\"\"\n # Length of the string\n n = len(s)\n\n # Iterate through possible rotations\n for i in range(1, n):\n # If the string equals to its rotation, return current rotation index\n if s[i:] + s[:i] == s:\n return i\n\n # If no rotation was found, return -1 (or n in this case as 0 rotations is not allowed)\n return n", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(s):\n for i in range(1, len(s)):\n rotated = s[i:] + s[:i]\n if rotated == s:\n return i\n return len(s)", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(input_str: str) -> int:\n for i in range(1, len(input_str)):\n rotated_str = input_str[i:] + input_str[:i]\n if rotated_str == input_str:\n return i\n return len(input_str)", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(s):\n n = len(s)\n for i in range(1, n):\n if all(s[(i+j) % n] == s[j] for j in range(n)):\n return i\n return n", "matching_cluster_idx": 3}, {"solution": "def find_Rotations(s):\n # if string is empty or has length 1, it requires 1 rotation\n if len(s) <= 1:\n return 1\n # if all characters in string are the same, it requires 1 rotation\n elif len(set(s)) == 1:\n return 1\n # initialize number of rotations required\n rotations = len(s)\n # loop through all rotations\n for i in range(1, len(s)):\n # rotate the string\n s = s[-1] + s[:-1]\n # if the rotated string is equal to the original string, return number of rotations\n if s == s[0]*len(s):\n rotations = i\n break\n return rotations", "matching_cluster_idx": 3}, {"solution": "def find_Rotations(s):\n n = len(s)\n for i in range(1, n):\n if s[i:] + s[:i] == s:\n return i\n return n", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(s):\n n = len(s)\n for i in range(1, n):\n if all(s[i-j] == s[0] for j in range(n)):\n return i\n return n", "matching_cluster_idx": 3}, {"solution": "def find_Rotations(s):\n n = len(s)\n\n # Try for all possible rotations\n for i in range(1, n):\n # Check if the string can be made the same by rotating it 'i' times\n if all(s[j] == s[(j + i) % n] for j in range(n)):\n return i\n\n # If no rotation can make it the same\n return n", "matching_cluster_idx": 3}, {"solution": "def find_Rotations(s):\n for i in range(1, len(s)):\n if s == (s[i:] + s[:i]):\n return i\n return len(s)", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(string):\n n = len(string)\n for i in range(1, n):\n if string[i:] + string[:i] == string:\n return i\n return n", "matching_cluster_idx": 4}]}, "Mbpp/11": {"dps": 52.25806451612903, "dps_norm": 79.44444444444444, "pass@1": 37.0, "profiled": [{"solution": "def remove_Occ(s, char):\n # Find the first and last occurrence of the char\n first = s.find(char)\n last = s.rfind(char)\n # If char is not in string, return string as is\n if first == -1:\n return s\n # If there is only one occurrence of char, return string without char\n if first == last:\n return s[:first] + s[first + 1:]\n # Return string without first and last occurrence of char\n return s[:first] + s[first + 1:last] + s[last + 1:]", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(input_str, char_to_remove):\n # Remove first occurrence\n output_str = input_str.replace(char_to_remove, '', 1)\n # Remove last occurrence\n output_str = output_str.rpartition(char_to_remove)[0] + output_str.rpartition(char_to_remove)[2]\n return output_str", "matching_cluster_idx": 6}, {"solution": "def remove_Occ(s, ch):\n first = s.find(ch)\n last = s.rfind(ch)\n if first == -1 or last == -1:\n return s\n elif first == last:\n return s[:first] + s[first+1:]\n else:\n return s[:first] + s[first+1:last] + s[last+1:]", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(s, ch):\n # Removes the first occurrence of the character from the string.\n first_ch_removed = s.replace(ch, '', 1)\n\n # Removes the last occurrence of the character from the string.\n last_ch_removed = first_ch_removed[::-1].replace(ch, '', 1)[::-1]\n\n return last_ch_removed", "matching_cluster_idx": 4}, {"solution": "def remove_Occ(input_string: str, char: str) -> str:\n # Remove first occurrence\n input_string = input_string.replace(char, \"\", 1)\n # Reverse string and remove first occurrence of char again, then reverse back to get the original string with last occurrence of char removed\n input_string = input_string[::-1].replace(char, \"\", 1)[::-1]\n return input_string", "matching_cluster_idx": 4}, {"solution": "def remove_Occ(input_string: str, char: str) -> str:\n first_occurrence = input_string.find(char)\n last_occurrence = input_string.rfind(char)\n if first_occurrence != -1 and last_occurrence != -1:\n if first_occurrence == last_occurrence:\n return input_string.replace(char, \"\", 1)\n else:\n return input_string[:first_occurrence] + input_string[first_occurrence+1:last_occurrence] + input_string[last_occurrence+1:]\n else:\n return input_string", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(input_str, ch):\n # Removing the first occurrence\n input_str = input_str.replace(ch, '', 1)\n # Reverse string and remove first occurrence of the character again (This will be the last occurrence in the original string)\n input_str = input_str[::-1].replace(ch, '', 1)[::-1]\n return input_str", "matching_cluster_idx": 4}, {"solution": "def remove_Occ(s, char):\n # remove first occurrence of the character\n s = s.replace(char, \"\", 1)\n # reverse the string and remove first occurrence of the character\n s = s[::-1].replace(char, \"\", 1)[::-1]\n return s", "matching_cluster_idx": 4}, {"solution": "def remove_Occ(string, char):\n first = string.find(char)\n last = string.rfind(char)\n if first == -1 or last == -1:\n return string\n else:\n return string[:first] + string[first+1:last] + string[last+1:]", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(input_string: str, target_char: str) -> str:\n \"\"\"\n This function removes first and last occurrence of a given character from a string.\n Args:\n input_string (str): The original string\n target_char (str): The character to be removed\n Returns:\n str: The modified string\n \"\"\"\n # finding the first and last occurrence index of target_char in input_string\n first_occ = input_string.find(target_char)\n last_occ = input_string.rfind(target_char)\n\n # if the target_char is found in input_string\n if first_occ != -1 and last_occ != -1:\n # if the target_char occurs only once\n if first_occ == last_occ:\n return input_string[:first_occ] + input_string[first_occ+1:]\n # if the target_char occurs more than once\n else:\n return input_string[:first_occ] + input_string[first_occ+1:last_occ] + input_string[last_occ+1:]\n # if the target_char is not found in input_string\n else:\n return input_string", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(s, ch):\n first_occurrence = s.find(ch)\n last_occurrence = s.rfind(ch)\n if first_occurrence != -1 and last_occurrence != -1:\n if first_occurrence == last_occurrence:\n return s[:first_occurrence] + s[first_occurrence+1:]\n elif first_occurrence == 0:\n return s[first_occurrence+1:last_occurrence] + s[last_occurrence+1:]\n elif last_occurrence == len(s)-1:\n return s[:first_occurrence] + s[first_occurrence+1:last_occurrence]\n else:\n return s[:first_occurrence] + s[first_occurrence+1:last_occurrence] + s[last_occurrence+1:]\n else:\n return s", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(s: str, ch: str) -> str:\n # Remove the first occurrence of the character\n first_remove = s.replace(ch, '', 1)\n\n # Reverse the string and remove the first occurrence of the character\n last_remove = first_remove[::-1].replace(ch, '', 1)\n\n # Return the reversed string, which is the original string with the last occurrence of the character removed\n return last_remove[::-1]", "matching_cluster_idx": 4}, {"solution": "def remove_Occ(string, char):\n # Remove first occurrence\n string = string.replace(char, '', 1)\n # Reverse string and remove first occurrence again (which is the last occurrence of original string)\n string = string[::-1].replace(char, '', 1)[::-1]\n return string", "matching_cluster_idx": 4}, {"solution": "def remove_Occ(string, char):\n first_char_removed = string.replace(char, '', 1)\n last_char_removed = first_char_removed.rsplit(char, 1)\n return ''.join(last_char_removed)", "matching_cluster_idx": 6}, {"solution": "def remove_Occ(s, ch):\n first_occurrence = s.find(ch)\n if first_occurrence != -1:\n s = s[:first_occurrence] + s[first_occurrence + 1:]\n last_occurrence = s.rfind(ch)\n if last_occurrence != -1:\n s = s[:last_occurrence] + s[last_occurrence + 1:]\n return s", "matching_cluster_idx": 7}, {"solution": "def remove_Occ(input_str, char_to_remove):\n first_char_index = input_str.find(char_to_remove)\n if first_char_index == -1:\n return input_str\n last_char_index = input_str.rfind(char_to_remove)\n return input_str[:first_char_index] + input_str[first_char_index+1:last_char_index] + input_str[last_char_index+1:]", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(input_string, char_to_remove):\n # find the first and last occurrence of the character\n first_index = input_string.find(char_to_remove)\n last_index = input_string.rfind(char_to_remove)\n\n # replace the first and last occurrence of the character with empty string\n if first_index != -1 and first_index != last_index:\n return input_string[:first_index] + input_string[first_index+1:last_index] + input_string[last_index+1:]\n elif first_index != -1 and first_index == last_index:\n return input_string.replace(char_to_remove, '', 1)\n else:\n return input_string", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(string, char):\n # check if the char exists in string\n if char in string:\n # remove first occurrence\n string = string.replace(char, '', 1)\n # reverse the string and remove the first occurrence of the character (which was the last in the original string)\n string = string[::-1].replace(char, '', 1)[::-1]\n return string", "matching_cluster_idx": 4}, {"solution": "def remove_Occ(s, c):\n # Remove first occurrence\n s = s.replace(c, \"\", 1)\n # Reverse the string, remove first occurrence and reverse back\n s = s[::-1].replace(c, \"\", 1)[::-1]\n return s", "matching_cluster_idx": 4}, {"solution": "def remove_Occ(s, ch):\n first = s.find(ch)\n last = s.rfind(ch)\n\n # if character not found\n if first == -1:\n return s\n\n # if first and last occurrence is the same\n if first == last:\n return s[:first] + s[first+1:]\n\n # removing the first and last occurrence\n return s[:first] + s[first+1:last] + s[last+1:]", "matching_cluster_idx": 8}]}, "Mbpp/12": {"dps": 95.59299191374663, "dps_norm": 99.0625, "pass@1": 97.0, "profiled": [{"solution": "def sort_matrix(matrix):\n return sorted(matrix, key=sum)", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n return sorted(matrix, key=sum)", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # calculate the sum of each row and store it with the corresponding row in a list of tuples\n matrix_sums = [(sum(row), row) for row in matrix]\n # sort the list of tuples in ascending order according to the sum of each row\n matrix_sums.sort()\n # extract the sorted rows from the list of tuples\n sorted_matrix = [row for sum, row in matrix_sums]\n return sorted_matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # calculate the sum of each row\n row_sums = [sum(row) for row in matrix]\n # sort the matrix based on row sums\n matrix.sort(key=lambda row: sum(row))\n return matrix", "matching_cluster_idx": 12}, {"solution": "def sort_matrix(matrix):\n # Calculate the sum of each row and sort the indexes according to the sum\n sorted_indexes = sorted(range(len(matrix)), key=lambda i: sum(matrix[i]))\n\n # Return the matrix ordered by the sorted indexes\n return [matrix[i] for i in sorted_indexes]", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"\n Sorts a matrix in ascending order based on the sum of its rows.\n\n :param matrix: A list of lists where each inner list is a row of the matrix.\n :return: A new list of lists with the same elements as the input, sorted as required.\n \"\"\"\n # Sorting the matrix based on the sum of its rows\n return sorted(matrix, key=sum)", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Calculate the sum of each row\n sums = [sum(row) for row in matrix]\n # Sort the matrix according to the row sums\n sorted_matrix = [x for _, x in sorted(zip(sums, matrix))]\n return sorted_matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n return sorted(matrix, key=sum)", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n return sorted(matrix, key=sum)", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Calculate sum of each row\n row_sums = [sum(row) for row in matrix]\n # Zip sums with the corresponding rows\n rows_with_sums = zip(row_sums, matrix)\n # Sort by row sums\n rows_with_sums = sorted(rows_with_sums)\n # Extract the original rows and return\n return [row for _, row in rows_with_sums]", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Sort the matrix based on the sum of its rows\n matrix.sort(key=sum)\n return matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n return sorted(matrix, key=sum)", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # sort the matrix in ascending order according to the sum of its rows\n matrix.sort(key=sum)\n return matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Sorting the matrix according to the sum of its rows\n matrix.sort(key=sum)\n return matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # sort the matrix by the sum of its rows\n return sorted(matrix, key=sum)", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n return sorted(matrix, key=sum)", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n return sorted(matrix, key=sum)", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # calculate the sum of each row and pair it with the original row\n sum_matrix = [(sum(row), row) for row in matrix]\n # sort the matrix based on the sum of each row\n sum_matrix.sort()\n # extract and return the sorted matrix\n return [row for _, row in sum_matrix]", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n return sorted(matrix, key=sum)", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n return sorted(matrix, key=sum)", "matching_cluster_idx": 15}]}, "Mbpp/16": {"dps": 81.09756097560975, "dps_norm": 86.875, "pass@1": 89.0, "profiled": [{"solution": "import re\ndef text_lowercase_underscore(input_string):\n pattern = \"^[a-z]+(_[a-z]+)*$\"\n return bool(re.match(pattern, input_string))", "matching_cluster_idx": 7}, {"solution": "import re\ndef text_lowercase_underscore(input_string):\n match = re.fullmatch('[a-z]+(_[a-z]+)*', input_string)\n return match is not None", "matching_cluster_idx": 7}, {"solution": "def text_lowercase_underscore(s):\n if not s:\n return False\n\n segments = s.split('_')\n for segment in segments:\n if not segment.islower():\n return False\n return True", "matching_cluster_idx": 5}, {"solution": "def text_lowercase_underscore(input_string):\n # Split the string by underscores\n split_string = input_string.split('_')\n # Check if each part is lowercase\n return all(part.islower() for part in split_string)", "matching_cluster_idx": 5}, {"solution": "def text_lowercase_underscore(s):\n # split the string by underscore\n sequences = s.split('_')\n # check if all sequences are lowercase\n return all(seq.islower() for seq in sequences)", "matching_cluster_idx": 5}, {"solution": "def text_lowercase_underscore(input_string):\n # split the input string by underscore and save it in a list\n split_string = input_string.split('_')\n # check if all the substrings are lowercase\n if all(s.islower() for s in split_string):\n # if all substrings are lowercase, return True\n return True\n # otherwise return False\n return False", "matching_cluster_idx": 5}, {"solution": "def text_lowercase_underscore(input_string):\n \"\"\"\n Function that returns true if the input string contains sequences of lowercase letters joined with an underscore\n and false otherwise.\n \"\"\"\n if not isinstance(input_string, str):\n raise TypeError(\"Input must be a string.\")\n\n segments = input_string.split('_')\n\n for segment in segments:\n if not segment.islower():\n return False\n\n return True", "matching_cluster_idx": 5}, {"solution": "def text_lowercase_underscore(input_string):\n \"\"\"\n This function checks whether the input string contains sequences of lowercase letters joined with an underscore.\n\n Parameters:\n input_string (str): The string to check.\n\n Returns:\n bool: True if the input_string contains sequences of lowercase letters joined with an underscore, otherwise False.\n \"\"\"\n # split the string by underscore\n sequences = input_string.split('_')\n\n # check each sequence\n for sequence in sequences:\n # if any sequence is not lowercase, return False\n if not sequence.islower():\n return False\n\n # if all sequences are lowercase, return True\n return True", "matching_cluster_idx": 5}, {"solution": "import re\ndef text_lowercase_underscore(input_string):\n # Checks if the input string contains sequences of lowercase letters joined with an underscore\n if re.match(\"^[a-z]+(_[a-z]+)*$\", input_string):\n return True\n else:\n return False", "matching_cluster_idx": 7}, {"solution": "import re\ndef text_lowercase_underscore(input_string):\n # Use regex to check if the string contains sequences of lowercase letters joined with an underscore\n if re.fullmatch(r'[a-z]+(?:_[a-z]+)*', input_string):\n return True\n else:\n return False", "matching_cluster_idx": 7}, {"solution": "import re\ndef text_lowercase_underscore(input_string):\n pattern = re.compile(r'^[a-z]+(_[a-z]+)*$')\n if pattern.match(input_string):\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "import re\ndef text_lowercase_underscore(input_string):\n \"\"\"\n Function to check if the input string contains sequences of lowercase letters joined with an underscore.\n \"\"\"\n # Using regex to check if the string matches the pattern\n if re.match(\"^[a-z]+(?:_[a-z]+)*$\", input_string):\n return True\n else:\n return False", "matching_cluster_idx": 7}, {"solution": "def text_lowercase_underscore(text):\n # Check if the input is a string\n if not isinstance(text, str):\n return False\n\n # Split the input string by underscore\n parts = text.split('_')\n\n # Check each part\n for part in parts:\n # Check if the part is all lowercase\n if not part.islower():\n return False\n\n # If all parts are all lowercase, return True\n return True", "matching_cluster_idx": 5}, {"solution": "def text_lowercase_underscore(input_string):\n # split the input string by underscore\n parts = input_string.split('_')\n # check if all parts are lowercase and not empty\n for part in parts:\n if not part.islower() or len(part) == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def text_lowercase_underscore(s):\n parts = s.split('_')\n for part in parts:\n if not part.islower():\n return False\n return True", "matching_cluster_idx": 5}, {"solution": "import re\ndef text_lowercase_underscore(input_string):\n # use regex to match sequences of lowercase letters joined by underscore\n match = re.fullmatch('[a-z]+(_[a-z]+)*', input_string)\n return match is not None", "matching_cluster_idx": 7}, {"solution": "def text_lowercase_underscore(input_string):\n \"\"\"\n This function checks if the input string contains sequences of lowercase letters joined with an underscore\n and returns True if that is the case, or False otherwise.\n \"\"\"\n if input_string == '': # empty string is considered not matching the pattern\n return False\n parts = input_string.split('_') # split the string by underscore\n for part in parts: # for each part\n if not part.islower(): # if the part is not all lowercase letters\n return False # return False\n return True # if all parts are lowercase, return True", "matching_cluster_idx": 5}, {"solution": "import re\ndef text_lowercase_underscore(s):\n pattern = re.compile('^[a-z]+(_[a-z]+)*$')\n return bool(pattern.match(s))", "matching_cluster_idx": 7}, {"solution": "import re\ndef text_lowercase_underscore(input_string):\n # using regex to check if the input string contains sequences of lowercase letters joined with an underscore\n return bool(re.match('^[a-z]+(_[a-z]+)*$', input_string))", "matching_cluster_idx": 7}, {"solution": "import re\ndef text_lowercase_underscore(s):\n pattern = '^[a-z]+(_[a-z]+)*$'\n if re.match(pattern, s):\n return True\n else:\n return False", "matching_cluster_idx": 7}]}, "Mbpp/19": {"dps": 69.94949494949495, "dps_norm": 83.0, "pass@1": 100.0, "profiled": [{"solution": "def test_duplicate(arr):\n # use a set to store the elements in the array\n seen = set()\n # iterate over the array\n for num in arr:\n # if the element is already in the set, return True\n if num in seen:\n return True\n # otherwise, add the element to the set\n else:\n seen.add(num)\n # if no duplicates are found, return False\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(arr):\n return len(arr) != len(set(arr))", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(arr):\n return len(arr) != len(set(arr))", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(arr):\n return len(arr) != len(set(arr))", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(array):\n \"\"\"\n This function checks if a given array contains any duplicate element.\n It uses the property of a set, which does not allow duplicate elements.\n If the length of the set is less than the length of the original list,\n it means there were some duplicate elements in the list.\n \"\"\"\n return len(array) != len(set(array))", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(arr):\n # Using the property of a set, duplicate elements will be removed\n # If the size of set is less than list, then there is a duplicate\n if len(arr) == len(set(arr)):\n return False\n else:\n return True", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(arr):\n # convert list to set, which removes duplicates\n # if length of the set is less than length of the list, duplicates existed\n return len(arr) != len(set(arr))", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(numbers):\n return len(numbers) != len(set(numbers))", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(lst):\n # convert list to set\n s = set(lst)\n # compare lengths of list and set\n if len(s) == len(lst):\n # if lengths are equal, no duplicates found\n return False\n else:\n # if lengths are unequal, duplicates found\n return True", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(arr):\n # Create an empty set\n unique_elements = set()\n # Loop through each element in the array\n for el in arr:\n # If element is already in the set, it is a duplicate\n if el in unique_elements:\n return True\n # Add element to the set\n else:\n unique_elements.add(el)\n # If no duplicates are found, return False\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(array):\n \"\"\"\n This function takes a list of integers as input and returns True if the list contains any duplicate elements,\n and False otherwise.\n \"\"\"\n return len(array) != len(set(array))", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(arr):\n # Create an empty set\n s = set()\n # Loop over the array elements\n for num in arr:\n # If the element is already in the set, it's a duplicate\n if num in s:\n return True\n # Add the element to the set\n s.add(num)\n # If no duplicate is found, return False\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(arr):\n return len(arr) != len(set(arr))", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(arr):\n \"\"\"\n Function to check if a given array of integers contains any duplicate element\n :param arr: List of integers\n :return: Boolean value (True if contains duplicates, False otherwise)\n \"\"\"\n return len(arr) != len(set(arr))", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(arr):\n return len(arr) != len(set(arr))", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(arr):\n return len(arr) != len(set(arr))", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(nums):\n return len(nums) != len(set(nums))", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(arr):\n if len(arr) == len(set(arr)):\n return False\n else:\n return True", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(arr):\n return len(arr) != len(set(arr))", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(array):\n # Create a set from the array\n array_set = set(array)\n\n # If length of the array is equal to length of the set, there are no duplicates.\n # If length of the array is not equal to length of the set, there are duplicates.\n if len(array) == len(array_set):\n return False\n else:\n return True", "matching_cluster_idx": 11}]}, "Mbpp/62": {"dps": 89.5, "dps_norm": 93.0, "pass@1": 100.0, "profiled": [{"solution": "def smallest_num(lst):\n \"\"\"\n Function to find the smallest number in a list.\n \"\"\"\n # Initialize the smallest number with the first element of the list\n smallest = lst[0]\n # Loop over the list and update the smallest number if a smaller one is found\n for num in lst:\n if num < smallest:\n smallest = num\n # Return the smallest number found\n return smallest", "matching_cluster_idx": 3}, {"solution": "def smallest_num(num_list):\n # Check if list is not empty\n if not num_list:\n raise ValueError('The list is empty')\n return min(num_list)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(num_list):\n # Check if list is not empty\n if len(num_list) != 0:\n # Assume first number in list is smallest\n smallest = num_list[0]\n\n # Iterate over the list\n for num in num_list:\n # If a smaller number is found, update the smallest\n if num < smallest:\n smallest = num\n\n # After iterating through all the numbers, return the smallest number found\n return smallest\n else:\n return \"List is empty\"", "matching_cluster_idx": 3}, {"solution": "def smallest_num(lst):\n \"\"\"\n Function to find the smallest number in a list.\n :param lst: A list of numbers.\n :return: The smallest number in the list.\n \"\"\"\n return min(lst)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(lst):\n return min(lst)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(numbers):\n \"\"\"Return the smallest number in a list.\"\"\"\n # Assume the first number in the list is the smallest\n min_num = numbers[0]\n\n # Iterate over the list\n for number in numbers:\n # If current number is less than the assumed smallest number, replace it\n if number < min_num:\n min_num = number\n\n # Return the smallest number found\n return min_num", "matching_cluster_idx": 3}, {"solution": "def smallest_num(num_list):\n return min(num_list)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(lst):\n \"\"\"\n This function finds the smallest number in a list.\n \"\"\"\n return min(lst)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(numbers):\n return min(numbers)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(lst):\n # Initialize smallest number to the first element in the list\n smallest = lst[0]\n # Iterate over the list\n for num in lst:\n # If a smaller number is found, update smallest\n if num < smallest:\n smallest = num\n # Return the smallest number found\n return smallest", "matching_cluster_idx": 3}, {"solution": "def smallest_num(numbers):\n \"\"\"\n Function to find the smallest number in a list\n\n Args:\n numbers (list): A list of numbers\n\n Returns:\n int: The smallest number in the list\n \"\"\"\n return min(numbers)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(lst):\n return min(lst)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(lst):\n return min(lst)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(lst):\n return min(lst)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(lst):\n if len(lst) == 0:\n return None\n smallest = lst[0]\n for num in lst:\n if num < smallest:\n smallest = num\n return smallest", "matching_cluster_idx": 3}, {"solution": "def smallest_num(numbers):\n \"\"\"\n This function takes a list of numbers as an argument\n and returns the smallest number in the list.\n \"\"\"\n return min(numbers)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(lst):\n return min(lst)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(num_list):\n # Initialize the smallest number as the first number in the list\n smallest = num_list[0]\n # Iterate through the list\n for num in num_list:\n # If a smaller number is found, update the smallest number\n if num < smallest:\n smallest = num\n # Return the smallest number\n return smallest", "matching_cluster_idx": 3}, {"solution": "def smallest_num(lst):\n return min(lst)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(numbers):\n \"\"\"\n This function finds the smallest number in a list of numbers.\n\n Args:\n numbers (list): A list of numbers.\n\n Returns:\n The smallest number in the list.\n \"\"\"\n # initial value of smallest is the first number in the list\n smallest = numbers[0]\n # iterate over the list\n for num in numbers:\n # if a smaller number is found, update smallest\n if num < smallest:\n smallest = num\n # return the smallest number\n return smallest", "matching_cluster_idx": 3}]}, "Mbpp/75": {"dps": 93.0, "dps_norm": 68.88888888888889, "pass@1": 100.0, "profiled": [{"solution": "def find_tuples(tuples, k):\n # Empty list to store tuples with all elements divisible by k\n result = []\n # Iterate over each tuple in the input list\n for tup in tuples:\n # Check if all elements in the tuple are divisible by k\n if all(elem % k == 0 for elem in tup):\n # If yes, append it to the result list\n result.append(tup)\n # Return the list of tuples with all elements divisible by k\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples, k):\n # Function to check if all elements of a tuple are divisible by k\n def all_divisible(tuple_elem):\n for ele in tuple_elem:\n if ele % k != 0:\n return False\n return True\n # Filtering tuples with all elements divisible by k\n result = [tuple_elem for tuple_elem in tuples if all_divisible(tuple_elem)]\n return result", "matching_cluster_idx": 7}, {"solution": "def find_tuples(tuples_list, k):\n return [t for t in tuples_list if all(i % k == 0 for i in t)]", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples, k):\n # initialise an empty list to hold the matching tuples\n matching_tuples = []\n # iterate over the tuples\n for t in tuples:\n # if all elements of the tuple are divisible by k\n if all(x % k == 0 for x in t):\n # add the tuple to the list of matching tuples\n matching_tuples.append(t)\n # return the list of matching tuples\n return matching_tuples", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n # Define a helper function that checks if all elements of a tuple are divisible by k\n def all_divisible_by_k(t, k):\n for elem in t:\n if elem % k != 0:\n return False\n return True\n\n # Use a list comprehension to filter tuples for which all elements are divisible by k\n return [t for t in tuples_list if all_divisible_by_k(t, k)]", "matching_cluster_idx": 7}, {"solution": "def find_tuples(tuples, k):\n return [tuple_ for tuple_ in tuples if all(element % k == 0 for element in tuple_)]", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples, k):\n return [t for t in tuples if all(i % k == 0 for i in t)]", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n result = []\n for t in tuples_list:\n if all(x % k == 0 for x in t):\n result.append(t)\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples, k):\n return [t for t in tuples if all(x % k == 0 for x in t)]", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples, k):\n result = []\n for t in tuples:\n if all(i % k == 0 for i in t):\n result.append(t)\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples, k):\n return [t for t in tuples if all(i % k == 0 for i in t)]", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tups, k):\n result = []\n for tup in tups:\n if all(i % k == 0 for i in tup):\n result.append(tup)\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples, k):\n return [t for t in tuples if all(x % k == 0 for x in t)]", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples, k):\n result = []\n for t in tuples:\n if all(i % k == 0 for i in t):\n result.append(t)\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples, k):\n result = []\n for t in tuples:\n if all(i % k == 0 for i in t):\n result.append(t)\n return result\ntuples = [(6, 24, 12), (7, 9, 6), (12, 18, 21)]\nk = 6", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples, k):\n result = []\n for tup in tuples:\n if all(i % k == 0 for i in tup):\n result.append(tup)\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n result = []\n for tuple_ in tuples_list:\n if all(elem % k == 0 for elem in tuple_):\n result.append(tuple_)\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n # Filter the list of tuples to keep only the ones where all elements are divisible by k.\n # all() function returns True if all elements of the iterable are true.\n # Here we use it to check if all elements of each tuple are divisible by k.\n return [t for t in tuples_list if all(elem % k == 0 for elem in t)]", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples, k):\n result = []\n for t in tuples:\n if all(x % k == 0 for x in t):\n result.append(t)\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples, k):\n return [tuple_ for tuple_ in tuples if all(i % k == 0 for i in tuple_)]", "matching_cluster_idx": 5}]}, "Mbpp/88": {"dps": 96.56862745098039, "dps_norm": 85.71428571428571, "pass@1": 100.0, "profiled": [{"solution": "def freq_count(lst):\n # Initialize an empty dictionary\n freq_dict = {}\n # Iterate over the elements in the list\n for ele in lst:\n # If the element is already a key in the dictionary, increment its value\n if ele in freq_dict:\n freq_dict[ele] += 1\n # Otherwise, add the element as a new key in the dictionary with a value of 1\n else:\n freq_dict[ele] = 1\n # Return the frequency dictionary\n return freq_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n # Initialize an empty dictionary\n freq_dict = {}\n # Iterate through list\n for i in lst:\n # If element is already a key in dictionary, increment its value\n if i in freq_dict:\n freq_dict[i] += 1\n # If element is not a key in dictionary, add it with a value of 1\n else:\n freq_dict[i] = 1\n # Return the frequency dictionary\n return freq_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n \"\"\"\n This function takes a list as input and returns a dictionary where\n keys are the unique elements from the list and values are their frequencies.\n \"\"\"\n freq = {}\n for item in lst:\n if (item in freq):\n freq[item] += 1\n else:\n freq[item] = 1\n return freq", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n count_dict = {}\n for num in lst:\n if num in count_dict:\n count_dict[num] += 1\n else:\n count_dict[num] = 1\n return count_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n freq_dict = {}\n for num in lst:\n if num in freq_dict:\n freq_dict[num] += 1\n else:\n freq_dict[num] = 1\n return freq_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n freq_dict = {}\n for num in lst:\n if num in freq_dict:\n freq_dict[num] += 1\n else:\n freq_dict[num] = 1\n return freq_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n freq_dict = {}\n for num in lst:\n if num in freq_dict:\n freq_dict[num] += 1\n else:\n freq_dict[num] = 1\n return freq_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n count_dict = {}\n for num in lst:\n if num in count_dict:\n count_dict[num] += 1\n else:\n count_dict[num] = 1\n return count_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(input_list):\n count_dict = {}\n for num in input_list:\n if num in count_dict:\n count_dict[num] += 1\n else:\n count_dict[num] = 1\n return count_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n count_dict = {}\n for item in lst:\n if item in count_dict:\n count_dict[item] += 1\n else:\n count_dict[item] = 1\n return count_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(input_list):\n freq_dict = {}\n for num in input_list:\n if num in freq_dict:\n freq_dict[num] += 1\n else:\n freq_dict[num] = 1\n return freq_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n freq = {}\n for item in lst:\n if item in freq:\n freq[item] += 1\n else:\n freq[item] = 1\n return freq", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n freq_dict = {}\n for item in lst:\n if item in freq_dict:\n freq_dict[item] += 1\n else:\n freq_dict[item] = 1\n return freq_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n freq = {}\n for item in lst:\n if item in freq:\n freq[item] += 1\n else:\n freq[item] = 1\n return freq", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n \"\"\"\n This function takes a list as an argument and returns a dictionary\n where keys are unique elements in the list and values are the frequency of each element.\n \"\"\"\n freq_dict = {}\n for item in lst:\n if item in freq_dict:\n freq_dict[item] += 1\n else:\n freq_dict[item] = 1\n return freq_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(numbers):\n freq_dict = {}\n for num in numbers:\n if num in freq_dict:\n freq_dict[num] += 1\n else:\n freq_dict[num] = 1\n return freq_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n freq = {}\n for item in lst:\n if item in freq:\n freq[item] += 1\n else:\n freq[item] = 1\n return freq", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n freq_dict = {}\n for item in lst:\n if item in freq_dict:\n freq_dict[item] += 1\n else:\n freq_dict[item] = 1\n return freq_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n freq = {}\n for item in lst:\n if item in freq:\n freq[item] += 1\n else:\n freq[item] = 1\n return freq", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n freq = {}\n for item in lst:\n if (item in freq):\n freq[item] += 1\n else:\n freq[item] = 1\n return freq", "matching_cluster_idx": 5}]}, "Mbpp/90": {"dps": 80.53658536585367, "dps_norm": 86.42857142857142, "pass@1": 43.0, "profiled": [{"solution": "def len_log(words):\n \"\"\"\n A function to find the length of the longest word in a list.\n\n Parameters:\n words (list): a list of strings.\n\n Returns:\n int: the length of the longest word.\n \"\"\"\n # Using max function and len function\n return max(len(word) for word in words)", "matching_cluster_idx": 5}, {"solution": "def len_log(word_list):\n \"\"\"\n Function to find the length of the longest word in a list of strings.\n \"\"\"\n # initialize the maximum length of the word to 0\n max_len = 0\n # iterate over each word in the list\n for word in word_list:\n # update the maximum length if the current word is longer\n if len(word) > max_len:\n max_len = len(word)\n # return the maximum length found\n return max_len", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n longest_length = 0\n for word in words:\n if len(word) > longest_length:\n longest_length = len(word)\n return longest_length", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n # Initialize maximum length as 0\n max_len = 0\n # Loop over each word in the list\n for word in words:\n # Update max_len if current word is longer\n if len(word) > max_len:\n max_len = len(word)\n return max_len", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n # Initialize maximum length with 0\n max_length = 0\n\n # Check each word in the list\n for word in words:\n # If the word length is more than max_length, update max_length\n if len(word) > max_length:\n max_length = len(word)\n\n # Return the maximum length of word\n return max_length", "matching_cluster_idx": 5}, {"solution": "def len_log(word_list):\n max_length = 0\n for word in word_list:\n if len(word) > max_length:\n max_length = len(word)\n return max_length", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n if not words:\n return 0\n return max(len(word) for word in words)", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n \"\"\"\n Function to find the length of the longest word\n :param words: List of words\n :return: Length of the longest word\n \"\"\"\n return max(len(word) for word in words)", "matching_cluster_idx": 5}, {"solution": "def len_log(word_list):\n max_len = 0\n for word in word_list:\n if len(word) > max_len:\n max_len = len(word)\n return max_len", "matching_cluster_idx": 5}, {"solution": "def len_log(word_list):\n \"\"\"Find the length of the longest word in a list of words.\"\"\"\n return max(len(word) for word in word_list)", "matching_cluster_idx": 5}, {"solution": "def len_log(lst):\n return max(len(word) for word in lst)", "matching_cluster_idx": 5}, {"solution": "def len_log(word_list):\n \"\"\"\n This function takes a list of words as an input and returns the length of the longest word.\n \"\"\"\n # initialize max_length variable with the length of the first word\n max_length = len(word_list[0])\n\n # iterate over the list and update max_length if the length of the current word is larger\n for word in word_list:\n if len(word) > max_length:\n max_length = len(word)\n\n # return the length of the longest word\n return max_length", "matching_cluster_idx": 5}, {"solution": "def len_log(word_list):\n return len(max(word_list, key=len))", "matching_cluster_idx": 6}, {"solution": "def len_log(words):\n return max(len(word) for word in words)", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n longest_length = 0\n for word in words:\n if len(word) > longest_length:\n longest_length = len(word)\n return longest_length", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n # Start by assuming the length of the first word is the longest\n max_length = len(words[0])\n # Then iterate over the remaining words\n for word in words[1:]:\n # If we find a word with a greater length, update our max_length\n if len(word) > max_length:\n max_length = len(word)\n # After we've iterated over all words, return the max_length\n return max_length", "matching_cluster_idx": 5}, {"solution": "def len_log(word_list):\n \"\"\"\n Returns the length of the longest word in a given list.\n \"\"\"\n if not word_list:\n return 0\n\n max_len = len(word_list[0])\n for word in word_list:\n if len(word) > max_len:\n max_len = len(word)\n return max_len", "matching_cluster_idx": 5}, {"solution": "def len_log(word_list):\n return max(len(word) for word in word_list)", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n return max(len(word) for word in words)", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n # Initialize longest word length to 0\n longest = 0\n # Iterate through each word in the list\n for word in words:\n # If the length of the current word is greater than the longest found so far\n if len(word) > longest:\n # Update the longest word length\n longest = len(word)\n # Return the length of the longest word\n return longest", "matching_cluster_idx": 5}]}, "Mbpp/94": {"dps": 79.5579268292683, "dps_norm": 63.0, "pass@1": 94.0, "profiled": [{"solution": "def index_minimum(lst):\n return min(lst, key = lambda x: x[1])[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(lst):\n \"\"\"\n This function receives a list of tuples and returns the first value of the tuple with the smallest second value.\n \"\"\"\n # The min function with a key parameter set to a function that returns the second element in a tuple can be used to find the tuple with the smallest second value.\n return min(lst, key=lambda x: x[1])[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(tuple_list):\n # Sorting the list of tuples based on the second element in each tuple\n sorted_list = sorted(tuple_list, key=lambda x: x[1])\n # Returning the first value of the tuple with the smallest second value\n return sorted_list[0][0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(lst):\n # Initialize the smallest_tuple as the first tuple in the list\n smallest_tuple = lst[0]\n\n # Iterate through the list and update smallest_tuple if we find a tuple with a smaller second value\n for tup in lst:\n if tup[1] < smallest_tuple[1]:\n smallest_tuple = tup\n\n # Return the first value of the tuple with the smallest second value\n return smallest_tuple[0]", "matching_cluster_idx": 3}, {"solution": "def index_minimum(lst):\n # sort list based on second value of tuples\n lst.sort(key = lambda x: x[1])\n # return the first value of the first tuple\n return lst[0][0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(input_list):\n return min(input_list, key = lambda x: x[1])[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(tuple_list):\n # initialize smallest value to float('inf'), a number larger than any potential second value in the list\n smallest_value = float('inf')\n # initialize smallest index to None\n smallest_index = None\n # iterate through the tuple list\n for i, t in enumerate(tuple_list):\n # if the second value of the tuple is smaller than the current smallest value\n if t[1] < smallest_value:\n # update the smallest value and smallest index\n smallest_value = t[1]\n smallest_index = i\n # return the first value of the tuple with the smallest second value\n return tuple_list[smallest_index][0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(tuples):\n return min(tuples, key=lambda x: x[1])[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(lst):\n return min(lst, key=lambda x: x[1])[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(lst):\n return min(lst, key=lambda x: x[1])[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(lst):\n return min(lst, key=lambda x: x[1])[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(tuples_list):\n return min(tuples_list, key=lambda x: x[1])[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(lst):\n # initialize minimum value and the corresponding name\n min_value = float('inf')\n name = \"\"\n # go through each tuple in the list\n for tup in lst:\n # if the second value of the tuple is smaller than current minimum value\n if tup[1] < min_value:\n # update minimum value and the corresponding name\n min_value = tup[1]\n name = tup[0]\n # return the name with the smallest second value\n return name", "matching_cluster_idx": 4}, {"solution": "def index_minimum(lst):\n # find the tuple with the minimum second value\n min_tuple = min(lst, key=lambda x: x[1])\n # return the first value of this tuple\n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(tuples):\n min_value = min(t[1] for t in tuples)\n for t in tuples:\n if t[1] == min_value:\n return t[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(lst):\n return min(lst, key=lambda x: x[1])[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(tuples_list):\n # Start by assuming the first tuple's second element is the smallest\n min_value = tuples_list[0][1]\n min_index = 0\n\n # Then iterate through the remaining tuples\n for i in range(1, len(tuples_list)):\n if tuples_list[i][1] < min_value:\n min_value = tuples_list[i][1]\n min_index = i\n\n # Finally, return the first value of the tuple with the smallest second value\n return tuples_list[min_index][0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(lst):\n # Sort the list of tuples based on the second element of the tuple\n sorted_lst = sorted(lst, key=lambda x: x[1])\n # Return the first element of the first tuple in the sorted list\n return sorted_lst[0][0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(lst):\n return min(lst, key = lambda x: x[1])[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(list_of_tuples):\n \"\"\"\n Function to return the first value of the tuple with the smallest second value.\n \"\"\"\n return min(list_of_tuples, key=lambda x: x[1])[0]", "matching_cluster_idx": 2}]}, "Mbpp/96": {"dps": 51.11111111111111, "dps_norm": 45.714285714285715, "pass@1": 80.0, "profiled": [{"solution": "def divisor(n):\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def divisor(n):\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def divisor(n):\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def divisor(n):\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def divisor(n):\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n if n / i == i:\n count += 1\n else:\n count += 2\n return count", "matching_cluster_idx": 5}, {"solution": "def divisor(n):\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def divisor(n):\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n # If divisors are equal, increment count by one\n if n / i == i:\n count += 1\n # Otherwise, increment count by two\n else:\n count += 2\n return count", "matching_cluster_idx": 5}, {"solution": "def divisor(n):\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n \"\"\"\n This function calculates the number of divisors of a given integer n.\n \"\"\"\n count = 0\n for i in range(1, int(n ** 0.5) + 1):\n if n % i == 0:\n count += 1 if n // i == i else 2\n return count", "matching_cluster_idx": 5}, {"solution": "def divisor(n):\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def divisor(n):\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n count += 2 if i != n // i else 1\n return count", "matching_cluster_idx": 5}, {"solution": "def divisor(n):\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def divisor(n):\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 1}]}, "Mbpp/97": {"dps": 85.70940170940172, "dps_norm": 78.125, "pass@1": 100.0, "profiled": [{"solution": "def frequency_lists(list_of_lists):\n # Flatten the list of lists\n flat_list = [item for sublist in list_of_lists for item in sublist]\n # Count the frequency of each element\n frequency_dict = {i: flat_list.count(i) for i in flat_list}\n return frequency_dict", "matching_cluster_idx": 1}, {"solution": "def frequency_lists(lists):\n # flattening the list of lists\n flat_list = [item for sublist in lists for item in sublist]\n # initializing an empty dictionary\n freq_dict = {}\n # calculating frequency of each element\n for item in flat_list:\n if item in freq_dict:\n freq_dict[item] += 1\n else:\n freq_dict[item] = 1\n # returning the dictionary\n return freq_dict", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lst):\n flat_list = [item for sublist in lst for item in sublist]\n return {i: flat_list.count(i) for i in flat_list}", "matching_cluster_idx": 1}, {"solution": "def frequency_lists(lists):\n # Flattening the list of lists\n flattened_list = [item for sublist in lists for item in sublist]\n # Counting the frequency of each element and returning as a dictionary\n frequency_dict = {i: flattened_list.count(i) for i in flattened_list}\n return frequency_dict", "matching_cluster_idx": 1}, {"solution": "def frequency_lists(lst):\n frequency_dict = {}\n for sublist in lst:\n for num in sublist:\n if num in frequency_dict:\n frequency_dict[num] += 1\n else:\n frequency_dict[num] = 1\n return frequency_dict", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lst):\n frequency_dict = {}\n # Flatten the list of lists\n flat_list = [item for sublist in lst for item in sublist]\n # Count the frequency of each element in the flattened list\n for element in flat_list:\n if element in frequency_dict:\n frequency_dict[element] += 1\n else:\n frequency_dict[element] = 1\n return frequency_dict", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(list_of_lists):\n # Flatten the list of lists\n flattened_list = [item for sublist in list_of_lists for item in sublist]\n\n # Create an empty dictionary\n frequency_dict = {}\n\n # Iterate through the flattened list\n for item in flattened_list:\n # If the item is not in the dictionary, add it and set the count to 1\n if item not in frequency_dict:\n frequency_dict[item] = 1\n # If the item is already in the dictionary, increment the count by 1\n else:\n frequency_dict[item] += 1\n\n # Return the frequency dictionary\n return frequency_dict", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lst_of_lst):\n freq = {}\n for lst in lst_of_lst:\n for el in lst:\n if el in freq:\n freq[el] += 1\n else:\n freq[el] = 1\n return freq", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lst):\n \"\"\"Function to find frequency of each element in a flattened list of lists.\"\"\"\n flatten_lst = [item for sublist in lst for item in sublist]\n freq_dict = {}\n for item in flatten_lst:\n if item in freq_dict:\n freq_dict[item] += 1\n else:\n freq_dict[item] = 1\n return freq_dict", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(list_of_lists):\n frequency = {}\n for sublist in list_of_lists:\n for item in sublist:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n return frequency", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lst_of_lst):\n flattened_lst = [item for sublist in lst_of_lst for item in sublist]\n frequency_dict = {}\n for i in flattened_lst:\n if i in frequency_dict:\n frequency_dict[i] += 1\n else:\n frequency_dict[i] = 1\n return frequency_dict", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lst_of_lsts):\n freq_dict = {}\n for sublist in lst_of_lsts:\n for item in sublist:\n if item in freq_dict:\n freq_dict[item] += 1\n else:\n freq_dict[item] = 1\n return freq_dict", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lst):\n # Flatten list of lists\n flattened = [item for sublist in lst for item in sublist]\n\n # Count frequency of each element\n freq = {}\n for i in flattened:\n if i in freq:\n freq[i] += 1\n else:\n freq[i] = 1\n\n return freq", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lists):\n # Initialize an empty dictionary to store frequencies\n freq_dict = {}\n # Flatten the list of lists\n flat_list = [item for sublist in lists for item in sublist]\n # Iterate over the flattened list\n for i in flat_list:\n # If the element is already in the dictionary, increment its count\n if i in freq_dict:\n freq_dict[i] += 1\n # If the element is not in the dictionary, add it with count 1\n else:\n freq_dict[i] = 1\n return freq_dict", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lst):\n # Create an empty dictionary to store the frequency of each element\n freq_dict = {}\n # Flatten the list of lists\n flat_list = [item for sublist in lst for item in sublist]\n # For each element in the flattened list\n for item in flat_list:\n # If the element is not in the dictionary, add it with a value of 1\n if item not in freq_dict:\n freq_dict[item] = 1\n # If the element is already in the dictionary, increment its value by 1\n else:\n freq_dict[item] += 1\n # Return the frequency dictionary\n return freq_dict", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(list_of_lists):\n frequency = {}\n for sublist in list_of_lists:\n for element in sublist:\n if element in frequency:\n frequency[element] += 1\n else:\n frequency[element] = 1\n return frequency", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lst):\n # Flatten the list of lists\n flattened = [item for sublist in lst for item in sublist]\n # Create a dictionary to store the frequency of each element\n freq = {}\n for item in flattened:\n if item in freq:\n freq[item] += 1\n else:\n freq[item] = 1\n return freq", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lst_of_lst):\n # Flatten the list of lists\n flat_list = [item for sublist in lst_of_lst for item in sublist]\n\n # Find frequency of each element\n frequency_dict = {}\n for element in flat_list:\n if element in frequency_dict:\n frequency_dict[element] += 1\n else:\n frequency_dict[element] = 1\n return frequency_dict", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lst):\n frequency_dict = {}\n # Flatten the list of lists\n flat_list = [item for sublist in lst for item in sublist]\n # Count frequency of each element in the flattened list\n for elem in flat_list:\n if elem in frequency_dict:\n frequency_dict[elem] += 1\n else:\n frequency_dict[elem] = 1\n return frequency_dict", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lst_of_lst):\n freq_dict = {}\n for sublist in lst_of_lst:\n for num in sublist:\n if num in freq_dict:\n freq_dict[num] += 1\n else:\n freq_dict[num] = 1\n return freq_dict", "matching_cluster_idx": 6}]}, "Mbpp/106": {"dps": 54.70779220779221, "dps_norm": 87.5, "pass@1": 100.0, "profiled": [{"solution": "def add_lists(lst, tup):\n \"\"\"\n This function takes a list and a tuple as input, appends the list to the tuple and returns the result.\n \"\"\"\n return tup + tuple(lst)", "matching_cluster_idx": 4}, {"solution": "def add_lists(lst, tpl):\n return tpl + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(input_list, input_tuple):\n \"\"\"\n Function to append the given list to the given tuple.\n \"\"\"\n return input_tuple + tuple(input_list)", "matching_cluster_idx": 4}, {"solution": "def add_lists(lst, tpl):\n return tpl + tuple(lst)", "matching_cluster_idx": 4}, {"solution": "def add_lists(lst, tpl):\n \"\"\"\n This function appends the given list to the given tuple.\n\n Args:\n lst (list): The given list.\n tpl (tuple): The given tuple.\n\n Returns:\n tuple: The given tuple with the list appended to it.\n \"\"\"\n return tpl + tuple(lst)", "matching_cluster_idx": 4}, {"solution": "def add_lists(lst, tup):\n \"\"\"\n This function appends the given list to the given tuples and returns the resulting tuple.\n Args:\n lst (list): The input list.\n tup (tuple): The input tuple.\n Returns:\n tuple: The resulting tuple after appending the list to the tuple.\n \"\"\"\n return tup + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tup):\n \"\"\"\n This function takes a list and a tuple as input. It returns a tuple that\n contains all the elements from the input tuple and all the elements from\n the input list.\n\n Parameters:\n lst (list): the input list.\n tup (tuple): the input tuple.\n\n Returns:\n tuple: the output tuple.\n \"\"\"\n return tup + tuple(lst)", "matching_cluster_idx": 4}, {"solution": "def add_lists(lst, tpl):\n return tpl + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tup):\n \"\"\"\n Function to append the given list to the given tuple.\n\n Args:\n lst (list): List of elements to be appended.\n tup (tuple): Tuple to which list elements will be appended.\n\n Returns:\n tuple: Tuple with all elements from the input tuple and list.\n \"\"\"\n return tup + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(given_list, given_tuple):\n return given_tuple + tuple(given_list)", "matching_cluster_idx": 5}, {"solution": "def add_lists(list_to_add, tuple_to_append):\n \"\"\"\n Function to append the given list to the given tuple.\n\n :param list_to_add: list of elements\n :param tuple_to_append: tuple to which the list will be appended\n :return: tuple with the list appended\n \"\"\"\n return tuple_to_append + tuple(list_to_add)", "matching_cluster_idx": 4}, {"solution": "def add_lists(lst, tpl):\n \"\"\"\n A function to append the given list to the given tuples.\n\n Arguments:\n lst: The list to be appended\n tpl: The tuple to which the list is appended\n\n Returns:\n A tuple with the list elements appended at the end\n \"\"\"\n return tpl + tuple(lst)", "matching_cluster_idx": 4}, {"solution": "def add_lists(input_list, input_tuple):\n \"\"\"\n Function that appends a given list to the given tuple.\n \"\"\"\n return input_tuple + tuple(input_list)", "matching_cluster_idx": 4}, {"solution": "def add_lists(lst, tup):\n # Function to append the given list to the given tuple\n return tup + tuple(lst)", "matching_cluster_idx": 4}, {"solution": "def add_lists(lst, tup):\n return tup + tuple(lst)", "matching_cluster_idx": 4}, {"solution": "def add_lists(lst, tup):\n return tup + tuple(lst)", "matching_cluster_idx": 4}, {"solution": "def add_lists(lst, tpl):\n \"\"\"Function to append a list to a tuple.\"\"\"\n return tpl + tuple(lst)", "matching_cluster_idx": 4}, {"solution": "def add_lists(l, t):\n return t + tuple(l)", "matching_cluster_idx": 4}, {"solution": "def add_lists(lst, tpl):\n return tpl + tuple(lst)", "matching_cluster_idx": 4}, {"solution": "def add_lists(lst, tup):\n \"\"\"\n This function appends the given list to the given tuple.\n\n Args:\n lst: a list of elements\n tup: a tuple of elements\n\n Returns:\n a tuple that includes elements from the input list and tuple\n \"\"\"\n return tup + tuple(lst)", "matching_cluster_idx": 4}]}, "Mbpp/108": {"dps": 95.66265060240964, "dps_norm": 99.0909090909091, "pass@1": 80.0, "profiled": [{"solution": "def merge_sorted_list(list1, list2, list3):\n # Merge three lists into one\n merged_list = list1 + list2 + list3\n # Sort the merged list\n merged_list.sort()\n # Return the sorted list\n return merged_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(*args):\n # Unpack the lists\n lists = [*args]\n\n # Use Python's built-in sorted function to merge and sort the lists\n sorted_list = sorted([item for sublist in lists for item in sublist])\n\n return sorted_list", "matching_cluster_idx": 8}, {"solution": "def merge_sorted_list(*args):\n # Merge multiple sorted lists into a single sorted list\n merged_list = []\n for lst in args:\n merged_list += lst\n return sorted(merged_list)", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(lst1, lst2, lst3):\n # Merge lists into a single list\n merged_list = lst1 + lst2 + lst3\n # Sort the merged list and return it\n return sorted(merged_list)", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n merged_list = list1 + list2 + list3\n return sorted(merged_list)", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n return sorted(list1 + list2 + list3)", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Merge the lists into a single list.\n merged_list = list1 + list2 + list3\n\n # Sort the merged list.\n merged_list.sort()\n\n # Return the sorted merged list.\n return merged_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Merge the three lists\n merged_list = list1 + list2 + list3\n # Sort the merged list\n merged_list.sort()\n return merged_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(*lists):\n # The function takes an arbitrary number of sorted lists as arguments\n merged_list = []\n for lst in lists:\n merged_list.extend(lst)\n # After merging all the lists, they are sorted and returned\n return sorted(merged_list)", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Merge all the lists into one\n merged_list = list1 + list2 + list3\n # Sort the merged list\n merged_list.sort()\n return merged_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Merge three sorted lists\n merged_list = list1 + list2 + list3\n # Sort the merged list\n merged_list.sort()\n return merged_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n merged_list = list1 + list2 + list3\n merged_list.sort()\n return merged_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n \"\"\"\n This function merges three sorted lists into a single sorted list.\n \"\"\"\n # merge lists into one list\n merged_list = list1 + list2 + list3\n # use Python's built-in sorted function to sort the merged list\n sorted_list = sorted(merged_list)\n return sorted_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Use the inbuilt sorted function to merge and sort the lists\n merged_list = sorted(list1 + list2 + list3)\n return merged_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(l1, l2, l3):\n merged_list = sorted(l1 + l2 + l3)\n return merged_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Merge the three lists\n merged_list = list1 + list2 + list3\n # Sort the merged list\n merged_list.sort()\n return merged_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(l1, l2, l3):\n # Merge the three lists\n merged_list = l1 + l2 + l3\n # Sort the merged list\n merged_list.sort()\n # Return the sorted list\n return merged_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Merge three lists\n merged_list = list1 + list2 + list3\n # Sort the merged list\n merged_list.sort()\n return merged_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # merge list1 and list2\n merged_list = list1 + list2\n\n # sort the merged list\n merged_list.sort()\n\n # merge the sorted merged_list and list3\n merged_list = merged_list + list3\n\n # sort the final merged list\n merged_list.sort()\n\n return merged_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(lst1, lst2, lst3):\n # merge three lists\n merged_list = lst1 + lst2 + lst3\n # sort the merged list\n sorted_list = sorted(merged_list)\n return sorted_list", "matching_cluster_idx": 10}]}, "Mbpp/111": {"dps": 65.32307692307693, "dps_norm": 80.625, "pass@1": 100.0, "profiled": [{"solution": "def common_in_nested_lists(lst):\n # convert the first list to a set\n res = set(lst[0])\n # iterate over the remaining lists\n for l in lst[1:]:\n # use intersection update to keep only elements that exist in res and current list\n res &= set(l)\n return res", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n # Convert each nested list to a set.\n sets = [set(nested_list) for nested_list in nested_lists]\n\n # Use intersection operation to find the common elements.\n common_elements = sets[0].intersection(*sets)\n\n return common_elements", "matching_cluster_idx": 4}, {"solution": "def common_in_nested_lists(nested_lists):\n # Converting first list to set\n result = set(nested_lists[0])\n\n # Performing intersection_update() operation on the rest of the lists\n for sublist in nested_lists[1:]:\n result.intersection_update(sublist)\n\n return result", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n common_elements = set(nested_lists[0])\n for lst in nested_lists[1:]:\n common_elements &= set(lst)\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n # convert each list to a set\n sets = [set(lst) for lst in nested_lists]\n # find intersection of all sets\n common = set.intersection(*sets)\n return common", "matching_cluster_idx": 5}, {"solution": "def common_in_nested_lists(lst):\n # Convert first list to set\n res = set(lst[0])\n # Intersect with other lists in the input list\n for l in lst[1:]:\n res = res.intersection(set(l))\n # Return the resulting set of common elements\n return res", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(lists):\n # Convert the first list into a set\n common = set(lists[0])\n\n # Iterate over the remaining lists and take the intersection with the common set\n for lst in lists[1:]:\n common = common.intersection(lst)\n\n return common", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n \"\"\"\n Find common elements in given nested lists\n \"\"\"\n # Use sets to get common elements\n common_elements = set.intersection(*map(set, nested_lists))\n return common_elements", "matching_cluster_idx": 4}, {"solution": "def common_in_nested_lists(lists):\n return set.intersection(*map(set, lists))", "matching_cluster_idx": 5}, {"solution": "def common_in_nested_lists(nested_lists):\n # Initialize the result set as the first list in the nested lists\n result_set = set(nested_lists[0])\n\n # Loop through the rest of the lists in the nested list\n for lst in nested_lists[1:]:\n # Update the result set with the intersection of the current result set and the current list\n result_set &= set(lst)\n\n # Return the final result set\n return result_set", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n # Convert the first list into a set\n common_elements = set(nested_lists[0])\n\n # Find intersection of the first list and the rest of the lists\n for lst in nested_lists[1:]:\n common_elements.intersection_update(set(lst))\n\n return common_elements", "matching_cluster_idx": 5}, {"solution": "def common_in_nested_lists(nested_list):\n # convert the first list to a set\n common_set = set(nested_list[0])\n\n # loop through the rest of the lists\n for i in range(1, len(nested_list)):\n # find the intersection with the current list and update the common_set\n common_set.intersection_update(nested_list[i])\n\n return common_set", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n # Initialize a set with elements in the first list\n common_elements = set(nested_lists[0])\n\n # Iterate over the remaining lists and find intersection\n for lst in nested_lists[1:]:\n common_elements.intersection_update(lst)\n\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(lists):\n \"\"\"\n This function finds the common elements in the given nested lists.\n \"\"\"\n # Convert the first list to set\n common_set = set(lists[0])\n\n # Iterate over the rest of the lists\n for lst in lists[1:]:\n # Use intersection to get common elements\n common_set = common_set.intersection(set(lst))\n\n return common_set", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_list):\n # Convert the first list to a set\n common_set = set(nested_list[0])\n\n # Iterate through the rest of the lists\n for lst in nested_list[1:]:\n # Update the set with the intersection of the current set and the current list\n common_set.intersection_update(lst)\n\n return common_set", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(lst):\n # Convert the first list to a set\n common_set = set(lst[0])\n\n # Find common elements with rest of the lists\n for sublist in lst[1:]:\n common_set = common_set.intersection(set(sublist))\n\n return common_set", "matching_cluster_idx": 5}, {"solution": "def common_in_nested_lists(lst):\n # Convert first list to set\n common_set = set(lst[0])\n\n # Iterate over rest of lists and find intersection\n for sublist in lst[1:]:\n common_set &= set(sublist)\n\n return common_set", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(lists):\n \"\"\"\n Finds the common elements in given nested lists.\n\n :param lists: A list of lists containing integers.\n :return: A set of common elements.\n \"\"\"\n # Convert the first list to a set\n common_elements = set(lists[0])\n\n # For each of the remaining lists\n for lst in lists[1:]:\n # Keep only the common elements\n common_elements.intersection_update(lst)\n\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n # Convert the first list to a set\n common_elements = set(nested_lists[0])\n\n # Iterate over the remaining lists\n for i in range(1, len(nested_lists)):\n # Convert the current list to a set and update common_elements\n # to the intersection of common_elements and the current set\n common_elements.intersection_update(set(nested_lists[i]))\n\n # Return the final set of common elements\n return common_elements", "matching_cluster_idx": 5}, {"solution": "def common_in_nested_lists(lists):\n # Use the intersection method to find common elements\n # This method returns a set that contains only items that exist in all set inputs\n return set.intersection(*map(set, lists))", "matching_cluster_idx": 4}]}, "Mbpp/123": {"dps": 99.62686567164178, "dps_norm": 85.71428571428571, "pass@1": 30.0, "profiled": [{"solution": "def amicable_numbers_sum(n):\n def divisors_sum(num):\n result = 1\n i = 2\n while i * i <= num:\n if (num % i):\n i += 1\n else:\n if (i == (num/i)):\n result += i\n i += 1\n else:\n result += (i + num//i)\n i += 1\n return result\n\n amicable_sum = 0\n for i in range(1, n + 1):\n a = divisors_sum(i)\n b = divisors_sum(a)\n if (b == i and a != b):\n amicable_sum += i\n\n return amicable_sum", "matching_cluster_idx": 11}, {"solution": "def sum_divisors(num):\n \"\"\"This function returns the sum of proper divisors of a number.\"\"\"\n result = 1\n i = 2\n while i * i <= num:\n if num % i:\n i += 1\n else:\n if i == (num // i):\n result = result + i\n i += 1\n else:\n result = result + (i + num//i)\n i += 1\n return result\ndef amicable_numbers_sum(n):\n \"\"\"This function returns the sum of all amicable numbers from 1 to n.\"\"\"\n amicable_sum = 0\n for i in range(2, n + 1):\n sum1 = sum_divisors(i)\n if (i == sum_divisors(sum1)) and (i != sum1):\n amicable_sum += i\n return amicable_sum", "matching_cluster_idx": 11}, {"solution": "def amicable_numbers_sum(n):\n def sum_of_proper_divisors(num):\n # find all divisors\n divisors = [1]\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n if num//i == i:\n divisors.append(i)\n else:\n divisors.extend([i, num//i])\n return sum(divisors)\n\n amicable_numbers = []\n for i in range(2, n+1):\n sum_i = sum_of_proper_divisors(i)\n if sum_i <= i:\n continue\n if sum_of_proper_divisors(sum_i) == i and i != sum_i and i not in amicable_numbers:\n amicable_numbers.extend([i, sum_i])\n return sum(amicable_numbers)", "matching_cluster_idx": 11}, {"solution": "def amicable_numbers_sum(n):\n def sum_divisors(num):\n result = 1\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n if i == (num / i):\n result = result + i\n else:\n result = result + (i + num//i)\n return result\n\n result = 0\n for i in range(2, n + 1):\n j = sum_divisors(i)\n if sum_divisors(j) == i and i != j:\n result += i\n return result", "matching_cluster_idx": 11}, {"solution": "def amicable_numbers_sum(n):\n # Function to calculate the sum of proper divisors of a number\n def sum_of_proper_divisors(num):\n divisors_sum = 1\n for i in range(2, int(num**0.5)+1):\n if num % i == 0:\n if i == num/i:\n divisors_sum += i\n else:\n divisors_sum += (i + num//i)\n return divisors_sum\n\n # Initialize the sum of amicable numbers\n amicable_sum = 0\n # Iterate through numbers up to n\n for i in range(1, n+1):\n # Calculate the sum of proper divisors of i\n sum1 = sum_of_proper_divisors(i)\n # Calculate the sum of proper divisors of sum1\n sum2 = sum_of_proper_divisors(sum1)\n # Check if i is an amicable number\n if sum2 == i and sum1 != sum2:\n amicable_sum += i\n return amicable_sum", "matching_cluster_idx": 11}, {"solution": "def amicable_numbers_sum(n):\n def find_divisors(num):\n divisors = [1]\n for i in range(2, int(num**0.5) + 1):\n if num % i:\n continue\n if num // i == i:\n divisors.append(i)\n else:\n divisors.extend([i, num // i])\n return divisors\n\n def is_amicable(num):\n divisors = find_divisors(num)\n sum_divisors = sum(divisors)\n return num != sum_divisors and sum(find_divisors(sum_divisors)) == num\n\n amicable_numbers = [i for i in range(1, n+1) if is_amicable(i)]\n return sum(amicable_numbers)", "matching_cluster_idx": 11}, {"solution": "def amicable_numbers_sum(n):\n def sum_of_divisors(num):\n divisors = [1]\n for i in range(2, int(num ** 0.5) + 1):\n if num % i == 0:\n divisors.append(i)\n divisors.append(num // i)\n return sum(set(divisors))\n\n def is_amicable(num):\n sum_divisors_num = sum_of_divisors(num)\n return sum_divisors_num != num and sum_of_divisors(sum_divisors_num) == num\n\n amicable_sum = 0\n for i in range(1, n + 1):\n if is_amicable(i):\n amicable_sum += i\n return amicable_sum", "matching_cluster_idx": 11}, {"solution": "def amicable_numbers_sum(n):\n def sum_proper_divisors(num):\n sum = 1\n i = 2\n while i * i <= num:\n if num % i:\n i += 1\n else:\n if i * (num // i) == num:\n sum += i + num // i\n else:\n sum += i\n i += 1\n return sum\n\n amicable_sum = 0\n for i in range(2, n + 1):\n sum1 = sum_proper_divisors(i)\n sum2 = sum_proper_divisors(sum1)\n if i == sum2 and i != sum1:\n amicable_sum += i\n return amicable_sum", "matching_cluster_idx": 11}, {"solution": "def sum_of_proper_divisors(n):\n \"\"\"Returns sum of proper divisors of a number.\"\"\"\n result = 0\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n if i == (n / i):\n result = result + i\n else:\n result = result + (i + n//i)\n return (result + 1)\ndef amicable_numbers_sum(n):\n \"\"\"Returns the sum of all amicable numbers from 1 to n.\"\"\"\n sum_amicable_nums = 0\n for i in range(2, n+1):\n sum_divisors = sum_of_proper_divisors(i)\n if (i != sum_divisors and sum_of_proper_divisors(sum_divisors) == i):\n sum_amicable_nums += i\n return sum_amicable_nums", "matching_cluster_idx": 11}, {"solution": "def amicable_numbers_sum(n):\n def sum_of_proper_divisors(number):\n sum = 1\n i = 2\n while i * i <= number:\n if number % i:\n i += 1\n else:\n if i * (number // i) == number:\n sum = sum + i + number//i\n else:\n sum = sum + i\n i += 1\n return sum\n\n def is_amicable_number(number):\n sum = sum_of_proper_divisors(number)\n return sum != number and sum_of_proper_divisors(sum) == number\n\n sum_amicable = 0\n for i in range(2, n+1):\n if is_amicable_number(i):\n sum_amicable += i\n return sum_amicable", "matching_cluster_idx": 11}, {"solution": "def sum_of_proper_divisors(n):\n if n < 2:\n return 0\n result = 1\n i = 2\n while i * i <= n:\n if n % i:\n i += 1\n else:\n if i * (n // i) == n:\n result += i + n // i\n else:\n result += i\n i += 1\n return result\ndef amicable_numbers_sum(n):\n amicable_sum = 0\n for i in range(1, n + 1):\n j = sum_of_proper_divisors(i)\n if i == sum_of_proper_divisors(j) and i != j:\n amicable_sum += i\n return amicable_sum", "matching_cluster_idx": 11}, {"solution": "def amicable_numbers_sum(n):\n def sum_divisors(num):\n \"\"\"function to calculate sum of divisors of a number\"\"\"\n result = 0\n # note that 1 is included in the divisors\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n if i == (num / i):\n result += i\n else:\n result += (i + num//i)\n return result + 1\n\n amicable_sum = 0\n for i in range(2, n + 1):\n sum_i = sum_divisors(i)\n if sum_i != i and sum_divisors(sum_i) == i:\n amicable_sum += i\n return amicable_sum", "matching_cluster_idx": 11}, {"solution": "def amicable_numbers_sum(limit):\n def get_divisors(n):\n divisors = [1]\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n if n/i == i:\n divisors.append(i)\n else:\n divisors.extend([i, n//i])\n return divisors\n\n def is_amicable(n):\n sum_divisors = sum(get_divisors(n))\n if n != sum_divisors and sum(get_divisors(sum_divisors)) == n:\n return True\n return False\n\n return sum(i for i in range(2, limit + 1) if is_amicable(i))", "matching_cluster_idx": 11}, {"solution": "def amicable_numbers_sum(n):\n def divisors(num):\n sum = 1\n i = 2\n while i * i <= num:\n if num % i:\n i += 1\n else:\n if i * (num // i) == num:\n sum += i + num//i\n else:\n sum += i\n i += 1\n return sum\n\n sum_amicable = 0\n for i in range(1, n+1):\n j = divisors(i)\n if i != j and divisors(j) == i:\n sum_amicable += i\n return sum_amicable", "matching_cluster_idx": 11}, {"solution": "def amicable_numbers_sum(n):\n # Function to find the sum of the divisors\n def sum_divisors(num):\n result = 0\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n if i == num // i:\n result += i\n else:\n result += (i + num//i)\n return result + 1\n\n # Initialize sum\n total = 0\n # Iterate up to the specified number\n for i in range(2, n+1):\n # Calculate sum of divisors\n sum_div = sum_divisors(i)\n # Check if the sum of divisors is an amicable number pair\n if i < sum_div and sum_div <= n and sum_divisors(sum_div) == i:\n total += i + sum_div\n\n return total", "matching_cluster_idx": 11}, {"solution": "def amicable_numbers_sum(n):\n def sum_divisors(num):\n sum = 1\n i = 2\n while i * i <= num:\n if num % i:\n i += 1\n else:\n if i * (num // i) == num:\n sum += i + num // i\n else:\n sum += i\n i += 1\n return sum\n\n amicable_numbers = []\n for i in range(1, n+1):\n j = sum_divisors(i)\n if sum_divisors(j) == i and i != j and i not in amicable_numbers and j not in amicable_numbers:\n amicable_numbers.append(i)\n amicable_numbers.append(j)\n\n return sum(amicable_numbers)", "matching_cluster_idx": 11}, {"solution": "def sum_divisors(n):\n divisors = [1]\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n if n / i == i:\n divisors.append(i)\n else:\n divisors.extend([i, n // i])\n return sum(divisors)\ndef amicable_numbers_sum(limit):\n amicable_numbers = []\n for i in range(1, limit+1):\n j = sum_divisors(i)\n if i == sum_divisors(j) and i != j and i not in amicable_numbers:\n amicable_numbers.extend([i, j])\n return sum(amicable_numbers)", "matching_cluster_idx": 11}, {"solution": "def amicable_numbers_sum(n):\n def divisor_sum(num):\n if num < 1:\n return 0\n else:\n sum = 1\n i = 2\n while i * i <= num:\n if num % i:\n i += 1\n else:\n if i * (num // i) == num:\n sum += i\n sum += num // i\n i += 1\n return sum\n\n sum_amicable = 0\n for num in range(2, n+1):\n sum1 = divisor_sum(num)\n sum2 = divisor_sum(sum1)\n if sum2 == num and sum1 != num:\n sum_amicable += num\n return sum_amicable", "matching_cluster_idx": 11}, {"solution": "def amicable_numbers_sum(n):\n def sum_of_divisors(num):\n result = 1\n i = 2\n while i * i <= num:\n if num % i:\n i += 1\n else:\n if i == (num / i):\n result = result + i\n i += 1\n else:\n result = result + (i + num//i)\n i += 1\n return result\n\n amicable_numbers = set()\n for i in range(2, n + 1):\n if i not in amicable_numbers:\n sum_divisors = sum_of_divisors(i)\n if sum_divisors != i and sum_of_divisors(sum_divisors) == i:\n amicable_numbers.add(i)\n amicable_numbers.add(sum_divisors)\n return sum(amicable_numbers)", "matching_cluster_idx": 11}, {"solution": "def amicable_numbers_sum(n):\n def sum_of_proper_divisors(num):\n if num < 2:\n return 0\n sum = 1\n for i in range(2, int(num ** 0.5) + 1):\n if num % i == 0:\n if i == (num / i):\n sum = sum + i\n else:\n sum = sum + (i + num//i)\n return sum\n amicable_sum = 0\n for num in range(2, n+1):\n sum_of_divisors = sum_of_proper_divisors(num)\n if num == sum_of_proper_divisors(sum_of_divisors) and num != sum_of_divisors:\n amicable_sum += num\n return amicable_sum", "matching_cluster_idx": 11}]}, "Mbpp/128": {"dps": 99.5475113122172, "dps_norm": 80.0, "pass@1": 100.0, "profiled": [{"solution": "def long_words(n, text):\n \"\"\"\n Function to find words that are longer than n characters from a given text.\n\n Parameters:\n n (int): Minimum length of the words to be found.\n text (str): Text from which the words are to be extracted.\n\n Returns:\n list: List of words that are longer than n characters.\n \"\"\"\n words = text.split()\n return [word for word in words if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, word_list):\n # Convert the input string into a list of words\n words = word_list.split(' ')\n\n # Use list comprehension to filter out words that are longer than n characters\n long_word_list = [word for word in words if len(word) > n]\n\n return long_word_list", "matching_cluster_idx": 3}, {"solution": "def long_words(n, word_list):\n return [word for word in word_list.split() if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, words):\n \"\"\"\n Function to find words that are longer than n characters from a given list of words.\n\n :param n: the minimum length of the words to be returned\n :param words: a string containing one or more words separated by spaces\n :return: a list of words longer than n characters\n \"\"\"\n # Splitting the string into a list of words\n word_list = words.split(' ')\n\n # Using list comprehension to filter out words that are longer than n characters\n long_words = [word for word in word_list if len(word) > n]\n\n return long_words", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n # Split the sentence into words\n words = sentence.split()\n # Filter words based on length\n long_words = [word for word in words if len(word) > n]\n return long_words", "matching_cluster_idx": 3}, {"solution": "def long_words(n, words):\n # Split the string into list of words\n word_list = words.split()\n\n # Use list comprehension to get words that are longer than n characters\n long_words_list = [word for word in word_list if len(word) > n]\n\n return long_words_list", "matching_cluster_idx": 3}, {"solution": "def long_words(n, words):\n # Split the input string into a list of words\n words_list = words.split()\n\n # Filter out words that are shorter than n\n long_words_list = [word for word in words_list if len(word) > n]\n\n return long_words_list", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n words = sentence.split()\n return [word for word in words if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, text):\n words = text.split()\n return [word for word in words if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, words):\n # Split the string into a list of words\n words = words.split()\n\n # Use list comprehension to filter out words that are longer than n characters\n long_words = [word for word in words if len(word) > n]\n\n # Return the list of long words\n return long_words", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n words = sentence.split()\n long_words_list = [word for word in words if len(word) > n]\n return long_words_list", "matching_cluster_idx": 3}, {"solution": "def long_words(n, words):\n words_list = words.split()\n return [word for word in words_list if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, text):\n # Convert the text to list of words\n words = text.split()\n # Filter the words and return only those that are longer than n characters\n return [word for word in words if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, text):\n \"\"\"\n This function takes an integer 'n' and a string 'text' as input,\n it returns a list of words from the 'text' which are longer than 'n' characters.\n \"\"\"\n words = text.split()\n return [word for word in words if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, word_list):\n # convert string to list of words\n words = word_list.split()\n # filter words that have length more than n\n long_words = [word for word in words if len(word) > n]\n return long_words", "matching_cluster_idx": 3}, {"solution": "def long_words(n, input_string):\n \"\"\"\n Function that finds words that are longer than n characters from a given string.\n\n Args:\n n (int): The minimum number of characters for a word to be considered long.\n input_string (str): The string from which to find long words.\n\n Returns:\n list: A list of words that are longer than n characters.\n \"\"\"\n # Split the input string into a list of words\n words = input_string.split(' ')\n\n # Use list comprehension to generate a list of long words\n long_words = [word for word in words if len(word) > n]\n\n return long_words", "matching_cluster_idx": 3}, {"solution": "def long_words(n, words):\n \"\"\"\n This function takes an integer n and a string of words separated by spaces.\n It returns a list of words that are longer than n characters.\n\n :param n: An integer indicating the length of the words to be found.\n :param words: A string of words separated by spaces.\n :return: A list of words that are longer than n characters.\n \"\"\"\n return [word for word in words.split(' ') if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, word_list):\n # convert the word_list string to a list of words\n words = word_list.split()\n # use list comprehension to find words longer than n characters\n long_words_list = [word for word in words if len(word) > n]\n return long_words_list", "matching_cluster_idx": 3}, {"solution": "def long_words(n, text):\n \"\"\"\n Function to find words that are longer than n characters from a given list of words\n :param n: an integer for the threshold length of words\n :param text: a string containing words separated by spaces\n :return: a list of words from the text that are longer than n characters\n \"\"\"\n # split the text into a list of words\n words = text.split()\n # use list comprehension to filter out words that are longer than n characters\n long_words = [word for word in words if len(word) > n]\n return long_words", "matching_cluster_idx": 3}, {"solution": "def long_words(n, word_list):\n # split the word_list into words\n words = word_list.split()\n\n # filter words based on length\n long_words = [word for word in words if len(word) > n]\n\n return long_words", "matching_cluster_idx": 3}]}, "Mbpp/129": {"dps": 92.38520408163265, "dps_norm": 99.0, "pass@1": 68.0, "profiled": [{"solution": "def magic_square_test(matrix):\n # Calculate the sum of the first row\n sum_row = sum(matrix[0])\n\n # Check if all rows have the same sum\n for i in range(1, len(matrix)):\n if sum(matrix[i]) != sum_row:\n return False\n\n # Check if all columns have the same sum\n for i in range(len(matrix)):\n sum_col = 0\n for j in range(len(matrix)):\n sum_col += matrix[j][i]\n if sum_col != sum_row:\n return False\n\n # Check if the main diagonal has the same sum\n sum_diag_1 = 0\n for i in range(len(matrix)):\n sum_diag_1 += matrix[i][i]\n if sum_diag_1 != sum_row:\n return False\n\n # Check if the secondary diagonal has the same sum\n sum_diag_2 = 0\n for i in range(len(matrix)):\n sum_diag_2 += matrix[i][len(matrix) - 1 - i]\n if sum_diag_2 != sum_row:\n return False\n\n # If all checks pass, the matrix is a magic square\n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n n = len(matrix)\n sum_value = sum(matrix[0])\n\n # Check sum of each row\n for i in range(n):\n if sum(matrix[i]) != sum_value:\n return False\n\n # Check sum of each column\n for i in range(n):\n if sum(matrix[j][i] for j in range(n)) != sum_value:\n return False\n\n # Check sum of main diagonal\n if sum(matrix[i][i] for i in range(n)) != sum_value:\n return False\n\n # Check sum of other diagonal\n if sum(matrix[i][n-i-1] for i in range(n)) != sum_value:\n return False\n\n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(mat):\n # Calculate the sum of the elements in the first row\n sum_of_row = sum(mat[0])\n # Calculate the sum of the elements in each row and compare it with the sum of the first row\n for row in mat:\n if sum(row) != sum_of_row:\n return False\n # Calculate the sum of the elements in each column and compare it with the sum of the first row\n for col in range(len(mat[0])):\n col_sum = sum(mat[row][col] for row in range(len(mat)))\n if col_sum != sum_of_row:\n return False\n # Calculate the sum of the elements in the diagonal from top left to bottom right\n diagonal_sum1 = sum(mat[i][i] for i in range(len(mat)))\n # Calculate the sum of the elements in the diagonal from top right to bottom left\n diagonal_sum2 = sum(mat[i][len(mat) - 1 - i] for i in range(len(mat)))\n # Check if the sum of the diagonals is equal to the sum of the first row\n if diagonal_sum1 != sum_of_row or diagonal_sum2 != sum_of_row:\n return False\n # If all conditions are met, the matrix is a magic square\n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n # calculate the sum of the first row\n sum_of_first_row = sum(matrix[0])\n\n # calculate the sum of each row and compare with the sum of first row\n for row in matrix:\n if sum(row) != sum_of_first_row:\n return False\n\n # calculate the sum of each column and compare with the sum of first row\n for i in range(len(matrix)):\n sum_of_column = sum(row[i] for row in matrix)\n if sum_of_column != sum_of_first_row:\n return False\n\n # calculate the sum of main diagonal and compare with the sum of first row\n main_diagonal = sum(matrix[i][i] for i in range(len(matrix)))\n if main_diagonal != sum_of_first_row:\n return False\n\n # calculate the sum of secondary diagonal and compare with the sum of first row\n secondary_diagonal = sum(matrix[i][len(matrix) - i - 1] for i in range(len(matrix)))\n if secondary_diagonal != sum_of_first_row:\n return False\n\n # if all tests pass, return True\n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n # Find the sum of first row\n sum_of_first_row = sum(matrix[0])\n\n # Calculate sum of remaining rows and compare with the sum_of_first_row\n for i in range(1, len(matrix)):\n if sum(matrix[i]) != sum_of_first_row:\n return False\n\n # Calculate sum of each column and compare with the sum_of_first_row\n for i in range(len(matrix[0])):\n col_sum = 0\n for j in range(len(matrix)):\n col_sum += matrix[j][i]\n if col_sum != sum_of_first_row:\n return False\n\n # Calculate sum of main diagonal and compare with the sum_of_first_row\n main_diagonal_sum = 0\n for i in range(len(matrix)):\n main_diagonal_sum += matrix[i][i]\n if main_diagonal_sum != sum_of_first_row:\n return False\n\n # Calculate sum of secondary diagonal and compare with the sum_of_first_row\n secondary_diagonal_sum = 0\n for i in range(len(matrix)):\n secondary_diagonal_sum += matrix[i][len(matrix) - i - 1]\n if secondary_diagonal_sum != sum_of_first_row:\n return False\n\n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n # calculate the sum of the first row\n target_sum = sum(matrix[0])\n\n # check each row sum\n for row in matrix:\n if sum(row) != target_sum:\n return False\n\n # check each column sum\n for col in zip(*matrix):\n if sum(col) != target_sum:\n return False\n\n # check the main diagonal sum\n if sum(matrix[i][i] for i in range(len(matrix))) != target_sum:\n return False\n\n # check the anti-diagonal sum\n if sum(matrix[i][len(matrix)-1-i] for i in range(len(matrix))) != target_sum:\n return False\n\n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n n = len(matrix)\n sum_value = sum(matrix[0])\n for row in matrix:\n if sum(row) != sum_value:\n return False\n for col in range(n):\n if sum(row[col] for row in matrix) != sum_value:\n return False\n if sum(matrix[i][i] for i in range(n)) != sum_value:\n return False\n if sum(matrix[i][n-i-1] for i in range(n)) != sum_value:\n return False\n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n n = len(matrix)\n magic_sum = sum(matrix[0])\n\n # Check sum of rows and columns\n for i in range(n):\n if sum(matrix[i]) != magic_sum:\n return False\n if sum(matrix[j][i] for j in range(n)) != magic_sum:\n return False\n\n # Check sum of diagonals\n if sum(matrix[i][i] for i in range(n)) != magic_sum:\n return False\n if sum(matrix[i][n - i - 1] for i in range(n)) != magic_sum:\n return False\n\n return True", "matching_cluster_idx": 13}, {"solution": "def magic_square_test(matrix):\n n = len(matrix)\n\n # Calculating the sum of the first row\n sum_diag = sum(matrix[0])\n\n # Checking if all rows and columns sum up to the same value\n for i in range(n):\n row_sum = sum(matrix[i])\n col_sum = sum(matrix[j][i] for j in range(n))\n if row_sum != sum_diag or col_sum != sum_diag:\n return False\n\n # Checking if the diagonals sum up to the same value\n if sum(matrix[i][i] for i in range(n)) != sum_diag or sum(matrix[i][n-i-1] for i in range(n)) != sum_diag:\n return False\n\n return True", "matching_cluster_idx": 13}, {"solution": "def magic_square_test(matrix):\n \"\"\"\n This function checks if a given square matrix is a magic square.\n A magic square is a square grid filled with distinct positive integers from 1 to n^2 such that the sum of the numbers in each row,\n each column, and both main diagonals is equal.\n \"\"\"\n\n # Get the size of the square matrix\n n = len(matrix)\n\n # Get the sum of the elements in the first row\n magic_sum = sum(matrix[0])\n\n # Check the sum of each row\n for i in range(1, n):\n if sum(matrix[i]) != magic_sum:\n return False\n\n # Check the sum of each column\n for j in range(n):\n col_sum = 0\n for i in range(n):\n col_sum += matrix[i][j]\n if col_sum != magic_sum:\n return False\n\n # Check the sum of the main diagonal\n diag_sum = 0\n for i in range(n):\n diag_sum += matrix[i][i]\n if diag_sum != magic_sum:\n return False\n\n # Check the sum of the secondary diagonal\n diag_sum = 0\n for i in range(n):\n diag_sum += matrix[i][n - i - 1]\n if diag_sum != magic_sum:\n return False\n\n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n # Get the size of the square matrix\n n = len(matrix)\n # Calculate the sum of the first row\n magic_sum = sum(matrix[0])\n # Check the sum of each row\n for row in matrix:\n if sum(row) != magic_sum:\n return False\n # Check the sum of each column\n for col in range(n):\n col_sum = sum([matrix[row][col] for row in range(n)])\n if col_sum != magic_sum:\n return False\n # Check the sum of the main diagonal\n main_diag_sum = sum([matrix[i][i] for i in range(n)])\n if main_diag_sum != magic_sum:\n return False\n # Check the sum of the other diagonal\n other_diag_sum = sum([matrix[i][n - i - 1] for i in range(n)])\n if other_diag_sum != magic_sum:\n return False\n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n # calculate the sum of first row\n sum_of_first_row = sum(matrix[0])\n # calculate the sum of each row and each column\n for row in matrix:\n if sum(row) != sum_of_first_row:\n return False\n for col in range(len(matrix[0])):\n if sum(row[col] for row in matrix) != sum_of_first_row:\n return False\n # calculate the sum of the main diagonal\n sum_of_main_diag = sum(matrix[i][i] for i in range(len(matrix)))\n if sum_of_main_diag != sum_of_first_row:\n return False\n # calculate the sum of the secondary diagonal\n sum_of_sec_diag = sum(matrix[i][len(matrix)-i-1] for i in range(len(matrix)))\n if sum_of_sec_diag != sum_of_first_row:\n return False\n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n # Calculate the sum of the first row.\n total = sum(matrix[0])\n\n # Check the sum of each row.\n for row in matrix:\n if sum(row) != total:\n return False\n\n # Check the sum of each column.\n for col in range(len(matrix[0])):\n if sum(row[col] for row in matrix) != total:\n return False\n\n # Check the sum of the main diagonal.\n if sum(matrix[i][i] for i in range(len(matrix))) != total:\n return False\n\n # Check the sum of the other diagonal.\n if sum(matrix[i][len(matrix)-1-i] for i in range(len(matrix))) != total:\n return False\n\n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n # Calculate the sum of the first row\n sum_first_row = sum(matrix[0])\n # Calculate the sum of each row and compare it to the sum of the first row\n if not all(sum(row) == sum_first_row for row in matrix):\n return False\n # Calculate the sum of each column and compare it to the sum of the first row\n if not all(sum(col) == sum_first_row for col in zip(*matrix)):\n return False\n # Calculate the sum of the main diagonal\n sum_main_diag = sum(matrix[i][i] for i in range(len(matrix)))\n # Calculate the sum of the secondary diagonal\n sum_sec_diag = sum(matrix[i][len(matrix)-i-1] for i in range(len(matrix)))\n # Compare the sum of the main and secondary diagonals to the sum of the first row\n if sum_main_diag != sum_first_row or sum_sec_diag != sum_first_row:\n return False\n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n n = len(matrix)\n total = sum(matrix[0]) # Calculate the sum of elements in the first row\n # Check sum of elements in each row and column\n for i in range(n):\n if sum(matrix[i]) != total or sum([matrix[j][i] for j in range(n)]) != total:\n return False\n # Check sum of elements in the main diagonal\n if sum([matrix[i][i] for i in range(n)]) != total:\n return False\n # Check sum of elements in the anti-diagonal\n if sum([matrix[i][n-i-1] for i in range(n)]) != total:\n return False\n return True", "matching_cluster_idx": 13}, {"solution": "def magic_square_test(matrix):\n n = len(matrix)\n sum_to_compare = sum(matrix[0])\n\n # Checking rows sum\n for row in matrix:\n if sum(row) != sum_to_compare:\n return False\n\n # Checking columns sum\n for col in range(n):\n if sum(row[col] for row in matrix) != sum_to_compare:\n return False\n\n # Checking main diagonal sum\n if sum(matrix[i][i] for i in range(n)) != sum_to_compare:\n return False\n\n # Checking anti-diagonal sum\n if sum(matrix[i][n - i - 1] for i in range(n)) != sum_to_compare:\n return False\n\n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n # Check if it's a square matrix\n n = len(matrix)\n if n != len(matrix[0]):\n return False\n\n # Calculate the sum of elements in the first row\n sum_row = sum(matrix[0])\n\n # Check sum of all rows\n for i in range(1, n):\n if sum(matrix[i]) != sum_row:\n return False\n\n # Check sum of all columns\n for i in range(n):\n col_sum = 0\n for j in range(n):\n col_sum += matrix[j][i]\n if col_sum != sum_row:\n return False\n\n # Check sum of diagonal from top left to bottom right\n diagonal_sum = 0\n for i in range(n):\n diagonal_sum += matrix[i][i]\n if diagonal_sum != sum_row:\n return False\n\n # Check sum of diagonal from top right to bottom left\n diagonal_sum = 0\n for i in range(n):\n diagonal_sum += matrix[i][n - i - 1]\n if diagonal_sum != sum_row:\n return False\n\n # If it passes all tests, it's a magic square\n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n n = len(matrix)\n sum_check = sum(matrix[0])\n\n # Check sum of each row is equal to sum_check\n for i in range(1, n):\n if sum(matrix[i]) != sum_check:\n return False\n\n # Check sum of each column is equal to sum_check\n for i in range(n):\n col_sum = sum(matrix[j][i] for j in range(n))\n if col_sum != sum_check:\n return False\n\n # Check sum of main diagonal is equal to sum_check\n main_diag_sum = sum(matrix[i][i] for i in range(n))\n if main_diag_sum != sum_check:\n return False\n\n # Check sum of antidiagonal is equal to sum_check\n antidiag_sum = sum(matrix[i][n-1-i] for i in range(n))\n if antidiag_sum != sum_check:\n return False\n\n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n # calculating the sum of elements in the first row\n sum_first_row = sum(matrix[0])\n # calculating the sum of elements in each row and comparing with the sum of the first row\n for row in matrix:\n if sum(row) != sum_first_row:\n return False\n # calculating the sum of elements in each column and comparing with the sum of the first row\n for col in zip(*matrix):\n if sum(col) != sum_first_row:\n return False\n # calculating the sum of elements in the first diagonal and comparing with the sum of the first row\n sum_first_diag = sum(matrix[i][i] for i in range(len(matrix)))\n if sum_first_diag != sum_first_row:\n return False\n # calculating the sum of elements in the second diagonal and comparing with the sum of the first row\n sum_second_diag = sum(matrix[i][len(matrix)-i-1] for i in range(len(matrix)))\n if sum_second_diag != sum_first_row:\n return False\n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(mat):\n # Calculate the sum of the first row\n sum_row = sum(mat[0])\n\n # Check if all rows sum to the same total\n for row in mat:\n if sum(row) != sum_row:\n return False\n\n # Check if all columns sum to the same total\n for col in range(len(mat[0])):\n sum_col = sum(mat[row][col] for row in range(len(mat)))\n if sum_col != sum_row:\n return False\n\n # Check if the diagonals sum to the same total\n sum_diag1 = sum(mat[i][i] for i in range(len(mat)))\n sum_diag2 = sum(mat[i][len(mat) - i - 1] for i in range(len(mat)))\n if sum_diag1 != sum_row or sum_diag2 != sum_row:\n return False\n\n return True", "matching_cluster_idx": 14}]}, "Mbpp/130": {"dps": 77.10762331838565, "dps_norm": 68.33333333333334, "pass@1": 77.0, "profiled": [{"solution": "def max_occurrences(nums):\n count_dict = {}\n for num in nums:\n if num in count_dict:\n count_dict[num] += 1\n else:\n count_dict[num] = 1\n return max(count_dict, key=count_dict.get)", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(lst):\n if not lst:\n return None\n count_dict = {}\n for item in lst:\n if item in count_dict:\n count_dict[item] += 1\n else:\n count_dict[item] = 1\n max_count = 0\n max_item = None\n for item, count in count_dict.items():\n if count > max_count:\n max_count = count\n max_item = item\n return max_item", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(lst):\n counts = dict()\n for num in lst:\n if num in counts:\n counts[num] += 1\n else:\n counts[num] = 1\n return max(counts, key=counts.get)", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(lst):\n freq = {}\n for item in lst:\n if (item in freq):\n freq[item] += 1\n else:\n freq[item] = 1\n\n max_count = 0\n max_item = None\n for item, count in freq.items():\n if count > max_count:\n max_count = count\n max_item = item\n\n return max_item", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(lst):\n # Create a dictionary to store the frequency of each item in the list\n freq_dict = {}\n for item in lst:\n if item in freq_dict:\n freq_dict[item] += 1\n else:\n freq_dict[item] = 1\n\n # Find the item with maximum frequency\n max_freq = 0\n max_item = None\n for item, freq in freq_dict.items():\n if freq > max_freq:\n max_freq = freq\n max_item = item\n\n # Return the item with maximum frequency\n return max_item", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(lst):\n count_dict = {}\n for item in lst:\n if item in count_dict:\n count_dict[item] += 1\n else:\n count_dict[item] = 1\n\n max_count = 0\n max_item = None\n for item, count in count_dict.items():\n if count > max_count:\n max_count = count\n max_item = item\n\n return max_item", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(lst):\n # Create an empty dictionary to count occurrences of elements in the list\n counts = {}\n for item in lst:\n # Increment the count for each element in the dictionary\n if item in counts:\n counts[item] += 1\n else:\n counts[item] = 1\n\n # Find the element with the maximum count\n max_count = 0\n max_item = None\n for item, count in counts.items():\n if count > max_count:\n max_count = count\n max_item = item\n\n return max_item", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(lst):\n freq_dict = {}\n for item in lst:\n if item in freq_dict:\n freq_dict[item] += 1\n else:\n freq_dict[item] = 1\n max_freq = 0\n max_item = None\n for key, value in freq_dict.items():\n if value > max_freq:\n max_freq = value\n max_item = key\n return max_item", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(lst):\n count_dict = {}\n for item in lst:\n if item in count_dict:\n count_dict[item] += 1\n else:\n count_dict[item] = 1\n max_freq = max(count_dict.values())\n max_freq_items = [k for k, v in count_dict.items() if v == max_freq]\n return max_freq_items[0]", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(lst):\n # Create a dictionary to hold item frequencies\n freq = {}\n for item in lst:\n if item in freq:\n freq[item] += 1\n else:\n freq[item] = 1\n\n # Find the item with maximum frequency\n max_item = max(freq, key=freq.get)\n\n return max_item", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(lst):\n counter = {}\n for i in lst:\n if i in counter:\n counter[i] += 1\n else:\n counter[i] = 1\n max_value = max(list(counter.values()))\n max_keys = [k for k, v in counter.items() if v == max_value]\n return max_keys[0]", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(lst):\n count_dict = {}\n for item in lst:\n if item in count_dict:\n count_dict[item] += 1\n else:\n count_dict[item] = 1\n max_count = 0\n max_item = None\n for item, count in count_dict.items():\n if count > max_count:\n max_count = count\n max_item = item\n return max_item", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(lst):\n # Create an empty dictionary\n dict_freq = {}\n\n # Iterate over the list and count frequency\n for i in lst:\n dict_freq[i] = dict_freq.get(i, 0) + 1\n\n # Find maximum frequency and the corresponding item\n max_freq = max(dict_freq.values())\n max_item = [k for k, v in dict_freq.items() if v == max_freq]\n\n # Return the item with maximum frequency\n return max_item[0]", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(lst):\n counts = {}\n for item in lst:\n if item in counts:\n counts[item] += 1\n else:\n counts[item] = 1\n\n max_count = 0\n max_item = None\n\n for item, count in counts.items():\n if count > max_count:\n max_count = count\n max_item = item\n\n return max_item", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(lst):\n # Create a dictionary to store the frequencies of each item in the list\n freq = {}\n for item in lst:\n if item in freq:\n freq[item] += 1\n else:\n freq[item] = 1\n\n # Find the item with maximum frequency\n max_item = None\n max_count = 0\n for item, count in freq.items():\n if count > max_count:\n max_item = item\n max_count = count\n\n return max_item", "matching_cluster_idx": 3}, {"solution": "from collections import Counter\ndef max_occurrences(lst):\n # counts the frequency of each element in the list\n data = Counter(lst)\n # finds the element with maximum frequency\n max_element = max(data, key=data.get)\n return max_element", "matching_cluster_idx": 4}, {"solution": "def max_occurrences(lst):\n # create a dictionary with item as key and its frequency as value\n freq_dict = {}\n for i in lst:\n if i in freq_dict:\n freq_dict[i] += 1\n else:\n freq_dict[i] = 1\n # find the item with maximum frequency\n max_freq = 0\n max_item = None\n for key, value in freq_dict.items():\n if value > max_freq:\n max_freq = value\n max_item = key\n return max_item", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(lst):\n freq = {}\n for item in lst:\n if item in freq:\n freq[item] += 1\n else:\n freq[item] = 1\n max_freq = 0\n max_item = None\n for item, freq in freq.items():\n if freq > max_freq:\n max_freq = freq\n max_item = item\n return max_item", "matching_cluster_idx": 3}, {"solution": "from collections import Counter\ndef max_occurrences(lst):\n data = Counter(lst)\n return data.most_common(1)[0][0]", "matching_cluster_idx": 4}, {"solution": "def max_occurrences(lst):\n counts = dict()\n for num in lst:\n if num in counts:\n counts[num] += 1\n else:\n counts[num] = 1\n max_count = 0\n max_item = None\n for key, value in counts.items():\n if value > max_count:\n max_count = value\n max_item = key\n return max_item", "matching_cluster_idx": 3}]}, "Mbpp/137": {"dps": null, "dps_norm": null, "pass@1": 3.0, "profiled": []}, "Mbpp/140": {"dps": 54.72049689440994, "dps_norm": 70.0, "pass@1": 100.0, "profiled": [{"solution": "def extract_singly(list_of_tuples):\n # Initialize an empty set\n single_set = set()\n\n # Iterate through each tuple in the list of tuples\n for tup in list_of_tuples:\n # Iterate through each element in the tuple\n for element in tup:\n # Add the element to the set\n single_set.add(element)\n\n # Return the set of singly occurring numbers\n return single_set", "matching_cluster_idx": 4}, {"solution": "def extract_singly(lst):\n return set([item for sublist in lst for item in sublist])", "matching_cluster_idx": 5}, {"solution": "def extract_singly(lst_of_lists):\n # Initialize an empty set to store single numbers\n single_set = set()\n\n # Iterate over each tuple in the list of tuples\n for sublist in lst_of_lists:\n # Iterate over each number in the current tuple\n for number in sublist:\n # Add the number to the set\n single_set.add(number)\n\n # Return the set of single numbers\n return single_set", "matching_cluster_idx": 4}, {"solution": "def extract_singly(list_of_tuples):\n singly_set = set()\n for t in list_of_tuples:\n for i in t:\n singly_set.add(i)\n return singly_set", "matching_cluster_idx": 4}, {"solution": "def extract_singly(list_of_lists):\n # Initiate an empty set to store numbers\n number_set = set()\n\n # Loop over each tuple in the list of tuples\n for single_tuple in list_of_lists:\n\n # Loop over each number in the current tuple\n for num in single_tuple:\n\n # Add the number to the set\n number_set.add(num)\n\n # Return the set of numbers\n return number_set", "matching_cluster_idx": 4}, {"solution": "def extract_singly(list_of_tuples):\n # Initialize an empty set\n result_set = set()\n # Iterate through each tuple in the list of tuples\n for tup in list_of_tuples:\n # Iterate through each element in the tuple\n for num in tup:\n # Add the number to the set\n result_set.add(num)\n # Return the final set containing all numbers\n return result_set", "matching_cluster_idx": 4}, {"solution": "def extract_singly(list_of_tuples):\n # Initialize an empty set to hold the single elements\n single_elements = set()\n\n # Iterate over each tuple in the list of tuples\n for tup in list_of_tuples:\n # Iterate over each element in the current tuple\n for elem in tup:\n # Add the current element to the set of single elements\n single_elements.add(elem)\n\n # Return the set of single elements\n return single_elements", "matching_cluster_idx": 4}, {"solution": "def extract_singly(list_of_tuples):\n # Initialize an empty set to store the single elements\n singly_extracted = set()\n\n # Iterate through each tuple in the input list\n for tuple_ in list_of_tuples:\n # Iterate through each element in the current tuple\n for element in tuple_:\n # Add the element to the set\n singly_extracted.add(element)\n\n # Return the set containing the single elements\n return singly_extracted", "matching_cluster_idx": 4}, {"solution": "def extract_singly(list_of_tuples):\n \"\"\"\n Function to flatten a list of tuples into a single set of numbers.\n \"\"\"\n result = set()\n for tup in list_of_tuples:\n result.update(tup)\n return result", "matching_cluster_idx": 7}, {"solution": "def extract_singly(lists):\n singly_set = set()\n for sub_list in lists:\n for item in sub_list:\n singly_set.add(item)\n return singly_set", "matching_cluster_idx": 4}, {"solution": "def extract_singly(list_of_tuples):\n \"\"\"\n Function to flatten the list of tuples into a single set of numbers.\n \"\"\"\n # Initialize an empty set\n result = set()\n\n # Iterate through the list of tuples\n for tuple_ in list_of_tuples:\n # Iterate through each number in the tuple\n for num in tuple_:\n # Add the number to the set\n result.add(num)\n\n # Return the set of numbers\n return result", "matching_cluster_idx": 4}, {"solution": "def extract_singly(input_list):\n \"\"\"\n This function takes a list of tuples as input and returns a set of unique numbers from all tuples.\n \"\"\"\n output_set = set()\n for t in input_list:\n output_set.update(t)\n return output_set", "matching_cluster_idx": 7}, {"solution": "def extract_singly(list_of_tuples):\n # using set to remove duplicates\n result = set()\n for t in list_of_tuples:\n for i in t:\n result.add(i)\n return result", "matching_cluster_idx": 4}, {"solution": "def extract_singly(list_of_tuples):\n return set([item for tup in list_of_tuples for item in tup])", "matching_cluster_idx": 5}, {"solution": "def extract_singly(list_of_tuples):\n \"\"\"\n A function to flatten a list of tuples into a single set of numbers.\n\n Args:\n list_of_tuples (list of tuples): A list of tuples containing numbers.\n\n Returns:\n set: A set containing all unique numbers from the input list of tuples.\n \"\"\"\n result = set()\n for tup in list_of_tuples:\n for num in tup:\n result.add(num)\n return result", "matching_cluster_idx": 3}, {"solution": "def extract_singly(lists):\n # Use set comprehension to extract all numbers from the list of tuples\n return {num for tup in lists for num in tup}", "matching_cluster_idx": 5}, {"solution": "def extract_singly(input_list):\n # Initialize an empty set to hold the flattened numbers\n result = set()\n\n # Loop over the input list of tuples\n for tup in input_list:\n # Loop over the numbers in each tuple\n for num in tup:\n # Add the number to the result set\n result.add(num)\n\n # Return the result set\n return result", "matching_cluster_idx": 4}, {"solution": "def extract_singly(lst):\n return set([num for sublist in lst for num in sublist])", "matching_cluster_idx": 5}, {"solution": "def extract_singly(list_of_tuples):\n # Initialize an empty set\n result_set = set()\n\n # Iterate through each tuple in the list of tuples\n for tuple_ in list_of_tuples:\n # Add each element from the tuple to the set\n for element in tuple_:\n result_set.add(element)\n\n # Return the set of numbers\n return result_set", "matching_cluster_idx": 4}, {"solution": "def extract_singly(lists):\n \"\"\"\n Function to flatten the list of tuples into a set of numbers.\n \"\"\"\n result = set()\n for lst in lists:\n result.update(lst)\n return result", "matching_cluster_idx": 7}]}, "Mbpp/141": {"dps": 61.7687074829932, "dps_norm": 40.0, "pass@1": 81.0, "profiled": [{"solution": "def pancake_sort(arr):\n def flip(end):\n start = 0\n while start < end:\n arr[start], arr[end] = arr[end], arr[start]\n start += 1\n end -= 1\n\n for i in range(len(arr), 1, -1):\n max_index = arr.index(max(arr[:i]))\n if max_index != i - 1:\n flip(max_index)\n flip(i - 1)\n return arr", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(arr):\n # Reverse the first n elements\n def flip(n):\n for i in range(n//2):\n arr[i], arr[n-i-1] = arr[n-i-1], arr[i]\n\n # Find the index of the maximum element in the first n elements\n def find_max(n):\n max_index = 0\n for i in range(1, n):\n if arr[i] > arr[max_index]:\n max_index = i\n return max_index\n\n for i in range(len(arr), 1, -1):\n max_index = find_max(i)\n if max_index != i-1:\n # Move the maximum element to the beginning of the list\n flip(max_index+1)\n # Move the maximum element to its sorted position\n flip(i)\n\n return arr", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(lst):\n def flip(end):\n i = 0\n while i < end:\n lst[i], lst[end] = lst[end], lst[i]\n i += 1\n end -= 1\n\n for i in range(len(lst), 0, -1):\n max_index = lst.index(max(lst[:i]))\n if max_index != i - 1:\n flip(max_index)\n flip(i - 1)\n return lst", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(arr):\n def flip(end):\n start = 0\n while start < end:\n arr[start], arr[end] = arr[end], arr[start]\n start += 1\n end -= 1\n\n for i in range(len(arr), 1, -1):\n max_idx = arr.index(max(arr[:i]))\n if max_idx != i - 1:\n flip(max_idx)\n flip(i - 1)\n\n return arr", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(arr):\n def flip(i):\n start = 0\n while start < i:\n arr[start], arr[i] = arr[i], arr[start]\n start += 1\n i -= 1\n\n for i in range(len(arr), 1, -1):\n max_idx = arr.index(max(arr[:i]))\n flip(max_idx)\n flip(i - 1)\n\n return arr", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(arr):\n \"\"\"\n Sort a list of elements using the pancake sort algorithm.\n\n :param arr: list, list of integers\n :return: list, sorted list of integers\n \"\"\"\n def flip(arr, i):\n start = 0\n while start < i:\n arr[start], arr[i] = arr[i], arr[start]\n start += 1\n i -= 1\n\n for i in range(len(arr), 1, -1):\n max_index = arr.index(max(arr[:i]))\n flip(arr, max_index)\n flip(arr, i - 1)\n return arr", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(lst):\n def flip(end):\n i = 0\n while i < end:\n lst[i], lst[end] = lst[end], lst[i]\n i += 1\n end -= 1\n for size in reversed(range(len(lst))):\n max_idx = lst.index(max(lst[:size + 1]))\n flip(max_idx)\n flip(size)\n return lst", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(arr):\n for i in range(len(arr), 0, -1):\n max_idx = arr.index(max(arr[:i]))\n arr[:max_idx + 1] = arr[:max_idx + 1][::-1]\n arr[:i] = arr[:i][::-1]\n return arr", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(arr):\n def flip(sublist, index):\n i = 0\n while i < index:\n sublist[i], sublist[index] = sublist[index], sublist[i]\n i += 1\n index -= 1\n\n for size in reversed(range(len(arr))):\n max_idx = arr.index(max(arr[:size+1]))\n flip(arr, max_idx)\n flip(arr, size)\n return arr", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(arr):\n def flip(sublist, i):\n return sublist[:i+1][::-1] + sublist[i+1:]\n\n for i in range(len(arr), 1, -1):\n max_i = arr.index(max(arr[:i]))\n arr = flip(arr, max_i)\n arr = flip(arr, i-1)\n return arr", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(arr):\n # define a helper function to flip the first k elements of the list\n def flip(arr, k):\n i = 0\n while i < k // 2:\n arr[i], arr[k - i - 1] = arr[k - i - 1], arr[i]\n i += 1\n\n # iterate over all elements in the list\n for i in range(len(arr), 0, -1):\n # find the index of the maximum element in the first i elements\n max_idx = arr.index(max(arr[:i]))\n # flip the first max_idx+1 elements to bring the maximum element to the first position\n flip(arr, max_idx + 1)\n # flip the first i elements to bring the maximum element to its final position\n flip(arr, i)\n\n return arr", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(arr):\n def flip(arr, i):\n start = 0\n while start < i:\n arr[start], arr[i] = arr[i], arr[start]\n start += 1\n i -= 1\n\n for i in range(len(arr), 1, -1):\n max_idx = arr.index(max(arr[:i]))\n if max_idx != i - 1:\n flip(arr, max_idx)\n flip(arr, i - 1)\n return arr", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(arr):\n def flip(sublist, k):\n return sublist[:k][::-1] + sublist[k:]\n\n for size in reversed(range(len(arr))):\n max_idx = arr.index(max(arr[:size+1]))\n if max_idx != size:\n arr = flip(arr, max_idx+1)\n arr = flip(arr, size+1)\n return arr", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(arr):\n for i in range(len(arr)):\n max_idx = arr.index(max(arr[:len(arr) - i]))\n arr[:max_idx + 1] = arr[:max_idx + 1][::-1]\n arr[:len(arr) - i] = arr[:len(arr) - i][::-1]\n return arr", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(arr):\n # Function to flip elements of arr from 0 to i\n def flip(arr, i):\n start = 0\n while start < i:\n arr[start], arr[i] = arr[i], arr[start]\n start += 1\n i -= 1\n\n # Traverse through all array elements\n for i in range(len(arr), 1, -1):\n # Find index of the maximum element in arr[0..i]\n mi = arr.index(max(arr[:i]))\n\n # Move the maximum element to end of current i\n # elements\n flip(arr, mi)\n # Move the maximum element to its correct position\n # by reversing current i elements\n flip(arr, i-1)\n return arr", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(arr):\n def flip(end):\n i = 0\n while i < end:\n arr[i], arr[end] = arr[end], arr[i]\n i += 1\n end -= 1\n\n for end in range(len(arr) - 1, 0, -1):\n max_idx = arr.index(max(arr[:end + 1]))\n if max_idx != end:\n flip(max_idx)\n flip(end)\n\n return arr", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(arr):\n def flip(end):\n start = 0\n while start < end:\n arr[start], arr[end] = arr[end], arr[start]\n start += 1\n end -= 1\n\n for i in range(len(arr), 1, -1):\n max_idx = arr.index(max(arr[:i]))\n if max_idx != i - 1:\n flip(max_idx)\n flip(i - 1)\n return arr", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(arr):\n # Define a helper function to flip the elements of the array up to the given index\n def flip(arr, i):\n start = 0\n while start < i:\n arr[start], arr[i] = arr[i], arr[start]\n start += 1\n i -= 1\n\n # Perform pancake sort\n for i in range(len(arr), 1, -1):\n max_idx = arr.index(max(arr[:i]))\n if max_idx != i - 1:\n # Flip the maximum element to the end\n flip(arr, max_idx)\n # Flip the end element to its correct position\n flip(arr, i - 1)\n return arr", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(arr):\n def flip(end):\n start = 0\n while start < end:\n arr[start], arr[end] = arr[end], arr[start]\n start += 1\n end -= 1\n\n for i in range(len(arr), 1, -1):\n max_index = arr.index(max(arr[:i]))\n flip(max_index)\n flip(i-1)\n return arr", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(arr):\n def flip(end):\n start = 0\n while start < end:\n arr[start], arr[end] = arr[end], arr[start]\n start += 1\n end -= 1\n\n for i in range(len(arr), 1, -1):\n max_index = arr.index(max(arr[:i]))\n if max_index != i - 1:\n flip(max_index)\n flip(i - 1)\n return arr", "matching_cluster_idx": 2}]}, "Mbpp/166": {"dps": 94.67999999999999, "dps_norm": 52.5, "pass@1": 100.0, "profiled": [{"solution": "def find_even_pair(lst):\n # Count the number of even elements in the list\n count_even = len([x for x in lst if x % 2 == 0])\n\n # The total number of pairs in the list is n*(n-1)/2, where n is the length of the list\n # This is derived from the mathematical formula for calculating the number of pairs in a set\n total_pairs = len(lst) * (len(lst) - 1) // 2\n\n # The number of pairs that XOR to an odd number is the total number of pairs minus the number of pairs with both elements being odd\n # In a list of n elements, there are n - count_even elements that are odd\n # So, there are (n - count_even) * count_even pairs with both elements being odd\n odd_pairs = (len(lst) - count_even) * count_even\n\n # The remaining pairs will XOR to an even number\n return total_pairs - odd_pairs", "matching_cluster_idx": 3}, {"solution": "def find_even_pair(lst):\n count = 0\n for i in range(len(lst)):\n for j in range(i+1, len(lst)):\n if (lst[i] ^ lst[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(lst):\n \"\"\"\n This function counts the number of pairs of integers in a list that xor to an even number.\n \"\"\"\n # Initialize counter\n count = 0\n\n # Loop over all pairs of integers in the list\n for i in range(len(lst)):\n for j in range(i + 1, len(lst)):\n\n # Check if the xor of the pair is even\n if (lst[i] ^ lst[j]) % 2 == 0:\n count += 1\n\n # Return the number of even-xor pairs\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(lst):\n count = 0\n for i in range(len(lst)):\n for j in range(i+1, len(lst)):\n if (lst[i] ^ lst[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(nums):\n count = 0\n for i in range(len(nums)):\n for j in range(i+1, len(nums)):\n if (nums[i] ^ nums[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(lst):\n count = 0\n for i in range(len(lst)):\n for j in range(i+1, len(lst)):\n if (lst[i] ^ lst[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(nums):\n count = 0\n for i in range(len(nums)):\n for j in range(i + 1, len(nums)):\n if (nums[i] ^ nums[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(numbers):\n count = 0\n for i in range(len(numbers)):\n for j in range(i+1, len(numbers)):\n if (numbers[i] ^ numbers[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(lst):\n count = 0\n for i in range(len(lst)):\n for j in range(i+1, len(lst)):\n if (lst[i] ^ lst[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(nums):\n count = 0\n for i in range(len(nums)):\n for j in range(i+1, len(nums)):\n if (nums[i] ^ nums[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(lst):\n count = 0\n for i in range(len(lst)):\n for j in range(i+1, len(lst)):\n if (lst[i] ^ lst[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(numbers):\n count = 0\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n if (numbers[i] ^ numbers[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(lst):\n count = 0\n for i in range(len(lst)):\n for j in range(i+1, len(lst)):\n if (lst[i] ^ lst[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(nums):\n count = 0\n for i in range(len(nums)):\n for j in range(i+1, len(nums)):\n if (nums[i] ^ nums[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(lst):\n count = 0\n for i in range(len(lst)):\n for j in range(i+1, len(lst)):\n if (lst[i] ^ lst[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(numbers):\n count = 0\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n if (numbers[i] ^ numbers[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(lst):\n count = 0\n for i in range(len(lst)):\n for j in range(i+1, len(lst)):\n if (lst[i] ^ lst[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(nums):\n count = 0\n for i in range(len(nums)):\n for j in range(i+1, len(nums)):\n if (nums[i] ^ nums[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(numbers):\n # Initialize a counter for even pairs\n count = 0\n # Iterate over all pairs of numbers in the list\n for i in range(len(numbers)):\n for j in range(i+1, len(numbers)):\n # XOR the numbers and check if the result is even\n if (numbers[i] ^ numbers[j]) % 2 == 0:\n # If the XOR is even, increment the counter\n count += 1\n # Return the count of even pairs\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(lst):\n count = 0\n for i in range(len(lst)):\n for j in range(i+1, len(lst)):\n if (lst[i] ^ lst[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}]}, "Mbpp/170": {"dps": 93.22463768115942, "dps_norm": 96.875, "pass@1": 91.0, "profiled": [{"solution": "def sum_range_list(lst, start_index, end_index):\n return sum(lst[start_index:end_index + 1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(lst, start, end):\n \"\"\"\n Function to find the sum of numbers in a list within a range specified by two indices.\n \"\"\"\n # Check if the indices are within the range of the list\n if start < 0 or start >= len(lst) or end < 0 or end >= len(lst):\n raise ValueError(\"Indices are out of range.\")\n\n # Use list slicing to get the sublist of numbers within the specified range and then use sum() to add them up\n return sum(lst[start:end+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(lst, start, end):\n return sum(lst[start:end+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(lst, start, end):\n return sum(lst[start:end+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(lst, start_index, end_index):\n return sum(lst[start_index:end_index+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(lst, start, end):\n return sum(lst[start:end+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(num_list, start_idx, end_idx):\n # Initialize sum to 0\n total = 0\n # Iterate over the list from start_idx to end_idx inclusive\n for i in range(start_idx, end_idx + 1):\n # Add the current number to the total\n total += num_list[i]\n # Return the total sum\n return total", "matching_cluster_idx": 4}, {"solution": "def sum_range_list(numbers, start_index, end_index):\n return sum(numbers[start_index:end_index+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(lst, start_index, end_index):\n \"\"\"\n Function to find the sum of numbers in a list within a range specified by two indices.\n :param lst: list of numbers\n :param start_index: starting index of range\n :param end_index: ending index of range\n :return: sum of numbers within specified range\n \"\"\"\n return sum(lst[start_index:end_index+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(lst, start_index, end_index):\n \"\"\"\n Function to find the sum of numbers in a list within a range specified by two indices.\n Args:\n lst (list of int): The list of numbers.\n start_index (int): The starting index of the range.\n end_index (int): The ending index of the range.\n Returns:\n int: The sum of numbers in the list within the given range.\n \"\"\"\n return sum(lst[start_index:end_index+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(lst, start, end):\n # Use list slicing to get the range of numbers and then sum them\n return sum(lst[start:end+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(lst, start, end):\n return sum(lst[start:end + 1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(lst, start, end):\n return sum(lst[start:end+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(numbers, start, end):\n return sum(numbers[start:end+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(num_list, start_idx, end_idx):\n # Use list slicing to get the elements in the range and sum them\n return sum(num_list[start_idx:end_idx+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(input_list, start_index, end_index):\n return sum(input_list[start_index:end_index+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(lst, start, end):\n return sum(lst[start:end + 1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(num_list, start, end):\n return sum(num_list[start:end+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(list, start_index, end_index):\n # Slice the list to get elements within the specified range\n sublist = list[start_index:end_index + 1]\n # Calculate the sum of numbers in the sublist\n sum = 0\n for num in sublist:\n sum += num\n return sum", "matching_cluster_idx": 5}, {"solution": "def sum_range_list(input_list, start, end):\n return sum(input_list[start:end+1])", "matching_cluster_idx": 7}]}, "Mbpp/226": {"dps": 80.81395348837209, "dps_norm": 56.42857142857142, "pass@1": 100.0, "profiled": [{"solution": "def odd_values_string(input_string):\n return input_string[::2]", "matching_cluster_idx": 5}, {"solution": "def odd_values_string(s):\n return s[::2]", "matching_cluster_idx": 5}, {"solution": "def odd_values_string(s):\n return ''.join([s[i] for i in range(len(s)) if i % 2 == 0])", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(s):\n \"\"\"\n This function takes a string as input and removes the characters which have odd index values.\n :param s: the input string\n :return: the input string with odd index characters removed\n \"\"\"\n return s[::2]", "matching_cluster_idx": 5}, {"solution": "def odd_values_string(s):\n return ''.join([s[i] for i in range(len(s)) if i % 2 == 0])", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(input_string):\n result = ''\n for i in range(len(input_string)):\n if i % 2 == 0:\n result += input_string[i]\n return result", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(s):\n return s[::2]", "matching_cluster_idx": 5}, {"solution": "def odd_values_string(s: str) -> str:\n return s[::2]", "matching_cluster_idx": 5}, {"solution": "def odd_values_string(s):\n return s[::2]", "matching_cluster_idx": 6}, {"solution": "def odd_values_string(s):\n return s[::2]", "matching_cluster_idx": 5}, {"solution": "def odd_values_string(s):\n return ''.join(s[i] for i in range(len(s)) if i % 2 == 0)", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(string):\n return string[::2]", "matching_cluster_idx": 6}, {"solution": "def odd_values_string(input_str):\n result = \"\"\n for i in range(len(input_str)):\n if i % 2 == 0:\n result += input_str[i]\n return result", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(s):\n return ''.join([ch for i, ch in enumerate(s) if i % 2 == 0])", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(s):\n return s[::2]", "matching_cluster_idx": 5}, {"solution": "def odd_values_string(s):\n return ''.join([s[i] for i in range(len(s)) if i % 2 == 0])", "matching_cluster_idx": 1}, {"solution": "def odd_values_string(s):\n return s[::2]", "matching_cluster_idx": 5}, {"solution": "def odd_values_string(input_string):\n # Initialize an empty string\n output_string = ''\n # Iterate through each character in the input_string\n for i in range(len(input_string)):\n # If the index of the character is even, add it to the output_string\n if i % 2 == 0:\n output_string += input_string[i]\n # Return the output_string\n return output_string", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(string):\n return ''.join([char for index, char in enumerate(string) if index % 2 == 0])", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(input_string):\n return input_string[::2]", "matching_cluster_idx": 6}]}, "Mbpp/230": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def replace_blank(input_string, replace_char):\n return input_string.replace(' ', replace_char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(s, c):\n return s.replace(' ', c)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(string, char):\n return string.replace(' ', char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(s, char):\n return s.replace(' ', char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string, replacement_char):\n return input_string.replace(' ', replacement_char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string, replacement_char):\n \"\"\"\n This function takes in a string and a character, replaces blank spaces in the string\n with the character and returns the updated string.\n \"\"\"\n # replace spaces with the replacement character\n new_string = input_string.replace(' ', replacement_char)\n return new_string", "matching_cluster_idx": 7}, {"solution": "def replace_blank(string, char):\n \"\"\"\n This function takes in a string and a character, replaces blank spaces in the string with the character, and returns the string.\n \"\"\"\n return string.replace(' ', char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string, replace_char):\n return input_string.replace(\" \", replace_char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(string, char):\n return string.replace(' ', char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(s, char):\n return s.replace(' ', char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string, replace_char):\n return input_string.replace(' ', replace_char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string, char):\n return input_string.replace(' ', char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(string, char):\n \"\"\"\n Takes in a string and character, replaces blank spaces in the string with the character, and returns the string.\n \"\"\"\n return string.replace(\" \", char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(s, char):\n return s.replace(' ', char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string, replace_char):\n return input_string.replace(' ', replace_char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string, char):\n return input_string.replace(' ', char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string, replace_char):\n return input_string.replace(' ', replace_char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_str, char):\n return input_str.replace(\" \", char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_str, char):\n return input_str.replace(' ', char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(string, char):\n return string.replace(\" \", char)", "matching_cluster_idx": 7}]}, "Mbpp/239": {"dps": 74.13793103448276, "dps_norm": 77.0, "pass@1": 20.0, "profiled": [{"solution": "def get_total_number_of_sequences(m, n):\n # Initialize a 2D table dp with dimensions (m+1)x(n+1)\n # where dp[i][j] represents the number of possible sequences of length j such that\n # the last element is i\n dp = [[0]*(n+1) for _ in range(m+1)]\n\n # Base case: when n = 1, there's only one sequence which can be formed from any element [1, m]\n for i in range(1, m+1):\n dp[i][1] = 1\n\n # Iterate for length of sequence from 2 to n\n for j in range(2, n+1):\n # Iterate for last element of the sequence from 1 to m\n for i in range(1, m+1):\n # For each element i, count the number of elements that can be added before it.\n # This can be computed by summing up the dp values for all the elements\n # that are greater than or equal to twice of the current element and less than or equal to m.\n for k in range(2*i, m+1):\n dp[k][j] += dp[i][j-1]\n\n # The total number of sequences of length n is the sum of dp values for last element from 1 to m\n return sum(dp[i][n] for i in range(1, m+1))", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n # Initialize a 2D list to hold the number of possible sequences\n dp = [[0 for _ in range(m + 1)] for _ in range(n + 1)]\n\n # There is only one possible sequence of length 1 for any positive integer\n for i in range(1, m + 1):\n dp[1][i] = 1\n\n # Compute the number of possible sequences for each length from 2 to n\n for i in range(2, n + 1):\n for j in range(1, m + 1):\n # For each element, compute the number of possible sequences\n # by summing up the number of possible sequences for all\n # previous elements that satisfy the condition\n for k in range(1, j // 2 + 1):\n dp[i][j] += dp[i - 1][k]\n\n # Return the total number of possible sequences of length n\n return sum(dp[n])", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n # Create a 2D dp array where dp[i][j] represents the number of sequences\n # of length i ending with the value j.\n dp = [[0] * (m + 1) for _ in range(n + 1)]\n\n # A sequence of length 1 with any value from 1 to m is possible.\n for j in range(1, m + 1):\n dp[1][j] = 1\n\n # Fill the dp array using dynamic programming.\n for i in range(2, n + 1):\n for j in range(1, m + 1):\n for k in range(1, j // 2 + 1):\n dp[i][j] += dp[i - 1][k]\n\n # The total number of sequences of length n is the sum of dp[n][j] for all j.\n total = sum(dp[n][j] for j in range(1, m + 1))\n\n return total", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n # Initialize a 2D DP array\n dp = [[0]*(m+1) for _ in range(n+1)]\n\n # A sequence of length 1 can have m possible elements\n for i in range(1, m+1):\n dp[1][i] = 1\n\n # Fill dp array using bottom-up approach\n for i in range(2, n+1):\n for j in range(1, m+1):\n for k in range(1, j+1):\n if k*2 <= j:\n dp[i][j] += dp[i-1][k]\n\n # Sum up the total possible sequences of length n\n total_sequences = sum(dp[n][i] for i in range(1, m+1))\n\n return total_sequences", "matching_cluster_idx": 6}, {"solution": "def get_total_number_of_sequences(m, n):\n # Create a 2-D table to store the number of possible sequences\n dp = [[0] * (m + 1) for _ in range(n + 1)]\n # Initialize the first row of the table\n for j in range(1, m + 1):\n dp[1][j] = 1\n # Iterate through the rest of the table\n for i in range(2, n + 1):\n for j in range(1, m + 1):\n for k in range(1, j // 2 + 1):\n dp[i][j] += dp[i - 1][k]\n # Return the number of possible sequences\n return sum(dp[n])", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n # Initialize a 2D DP array\n dp = [[0 for _ in range(m+1)] for _ in range(n+1)]\n # Base case: if n == 1, all numbers from 1 to m are valid\n for i in range(1, m+1):\n dp[1][i] = 1\n # Fill DP table iteratively\n for i in range(2, n+1):\n for j in range(1, m+1):\n for k in range(j, m+1):\n # Each number can be the next number in the sequence\n # if it is greater than or equal to twice the previous element\n if k >= 2*j:\n dp[i][k] += dp[i-1][j]\n # The total number of valid sequences of length n is the sum of the last row\n return sum(dp[n])", "matching_cluster_idx": 6}, {"solution": "def get_total_number_of_sequences(m, n):\n # Initialize a 2D DP table with zero\n dp = [[0] * (m + 1) for _ in range(n + 1)]\n\n # Sequences of length 1 is always 1 as each sequence element is in range [1, m]\n for i in range(1, m + 1):\n dp[1][i] = 1\n\n # Fill the DP table in bottom-up manner\n for i in range(2, n + 1):\n for j in range(1, m + 1):\n # For each element, find number of sequences of length i ending with value j\n dp[i][j] = sum(dp[i - 1][k] for k in range(1, j // 2 + 1))\n\n # Return total number of sequences of length n\n return sum(dp[n])", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n # initialize a 2D DP array\n dp = [[0]*(m+1) for _ in range(n+1)]\n # initialize the first row\n for i in range(1, m+1):\n dp[1][i] = 1\n # fill up the DP table\n for i in range(2, n+1):\n for j in range(1, m+1):\n for k in range(2*j, m+1):\n dp[i][k] += dp[i-1][j]\n # sum up the last row\n return sum(dp[n])", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n # Initialize a matrix with all elements as 0\n seq = [[0 for i in range(m+1)] for j in range(n+1)]\n\n # Any number can start a sequence of 1\n for i in range(1, m + 1):\n seq[1][i] = 1\n\n # For each length of the sequence\n for length in range(2, n+1):\n # For each possible element\n for elem in range(1, m+1):\n # For each previous element\n for prev_elem in range(1, elem+1):\n # If previous element is valid, add it to the count of sequences\n if 2*prev_elem <= elem:\n seq[length][elem] += seq[length-1][prev_elem]\n\n # Return the total number of sequences of length n\n return sum(seq[n])", "matching_cluster_idx": 6}, {"solution": "def get_total_number_of_sequences(m, n):\n # dp[i][j] will store the number of possible sequences\n # of length j such that last element is i\n dp = [[0]*n for _ in range(m+1)]\n\n # base case: for sequence length 1, fill the dp array\n for i in range(1, m+1):\n dp[i][0] = 1\n\n # fill the rest of the dp array\n for seq_len in range(1, n):\n for last_num in range(1, m+1):\n for next_num in range(last_num*2, m+1):\n dp[next_num][seq_len] += dp[last_num][seq_len-1]\n\n # total possible sequences of length n\n total_sequences = sum(dp[i][n-1] for i in range(1, m+1))\n return total_sequences", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n # Initialize a 2D table to store the number of possible sequences\n dp = [[0] * (m + 1) for _ in range(n + 1)]\n\n # There is 1 way to form a sequence of length 1\n for i in range(1, m + 1):\n dp[1][i] = 1\n\n # For each length l from 2 to n\n for l in range(2, n + 1):\n # For each number j from 1 to m\n for j in range(1, m + 1):\n # For each previous number i from 1 to j\n for i in range(1, j + 1):\n if i * 2 <= j:\n dp[l][j] += dp[l - 1][i]\n\n # The answer is the sum of the number of sequences for all numbers j from 1 to m of length n\n return sum(dp[n])", "matching_cluster_idx": 6}, {"solution": "def get_total_number_of_sequences(m, n):\n # Initialize a matrix to store the number of sequences\n # seq[i][j] is going to store count of sequences of length i ending\n # with j.\n seq = [[0 for _ in range(m+1)] for _ in range(n+1)]\n\n # There is only one sequence of length 1 and ending with any number\n # less than or equal to m.\n for j in range(1, m+1):\n seq[1][j] = 1\n\n # Fill up seq[][] in bottom up manner.\n for i in range(2, n+1):\n for j in range(1, m+1):\n # For each element, find total elements that can form a sequence\n for k in range(j, m+1):\n if k >= 2*j:\n seq[i][k] += seq[i-1][j]\n\n # Return total number of sequences of length n.\n return sum(seq[n])", "matching_cluster_idx": 6}, {"solution": "def get_total_number_of_sequences(m, n):\n # Initialise a 2D array to store number of sequences\n # dp[i][j] stores number of sequences of length i such that last element is j\n dp = [[0 for _ in range(m + 1)] for _ in range(n + 1)]\n\n # If sequence has one element (n=1)\n # Only one valid sequence\n for j in range(1, m + 1):\n dp[1][j] = 1\n\n # Fill dp table in bottom-up manner\n for i in range(2, n + 1):\n for j in range(1, m + 1):\n # dp[i][j] = sum of all dp[i-1][k] where k is half of j\n for k in range(1, j // 2 + 1):\n dp[i][j] += dp[i - 1][k]\n\n # Final answer will be sum of all dp[n][i] for 1 <= i <= m\n total_sequences = sum(dp[n])\n return total_sequences", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n # Initialize a 2D DP table with all elements as 0\n dp = [[0 for _ in range(m+1)] for __ in range(n+1)]\n\n # Length of sequence is 1, so only 1 possibility to choose from\n for i in range(1, m+1):\n dp[1][i] = 1\n\n # Fill up the DP table from length 2 to n\n for i in range(2, n+1):\n for j in range(1, m+1):\n # Each position in the sequence will consider a number j from 1 to m\n # Number of possibilities will be sum of all the possibilities where the current number j is greater than or equal to twice the previous number\n for k in range(1, j//2+1):\n dp[i][j] += dp[i-1][k]\n\n # Sum up all the possibilities for sequence length n\n return sum(dp[n])", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n if m < 1 or n < 1:\n raise ValueError(\"Both m and n must be positive integers\")\n\n dp = [[0] * (m + 1) for _ in range(n)]\n for i in range(1, m + 1):\n dp[0][i] = 1\n\n for i in range(1, n):\n for j in range(2 * i, m + 1):\n for k in range(i, j // 2 + 1):\n dp[i][j] += dp[i - 1][k]\n\n return sum(dp[n - 1])", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n # Initialize a list to keep track of the total number of sequences for each element in the array\n dp = [1] * m\n\n # Iterate over the length of the sequence\n for i in range(2, n + 1):\n # Initialize a temporary list for the current length\n temp = [0] * m\n # Iterate over each possible element in the sequence\n for j in range(1, m + 1):\n # The current number of sequences is the sum of the previous elements that are less than or equal to half of the current element\n temp[j - 1] = sum(dp[:j // 2])\n # Update the dp list for the current length\n dp = temp\n\n # The total number of sequences of length n is the sum of the last element of dp\n return sum(dp)", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n # Initialize the result matrix and fill the first row with 1's\n result = [[0] * (m + 1) for _ in range(n)]\n for i in range(1, m + 1):\n result[0][i] = 1\n\n # Calculate the number of possible sequences for each position\n for i in range(1, n):\n for j in range(1, m + 1):\n for k in range(2 * j, m + 1):\n result[i][k] += result[i - 1][j]\n\n # The result is the sum of the last row in the result matrix\n return sum(result[n - 1])", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n # Create a 2D DP array\n dp = [[0] * (m + 1) for _ in range(n + 1)]\n\n # If length of the sequence is 1, then there are m possible sequences\n for i in range(1, m + 1):\n dp[1][i] = 1\n\n # Fill up the DP array\n for length in range(2, n + 1):\n for value in range(1, m + 1):\n for prev_value in range(1, value // 2 + 1):\n dp[length][value] += dp[length - 1][prev_value]\n\n # Total number of sequences is sum of the last column of DP array\n total_sequences = 0\n for i in range(1, m + 1):\n total_sequences += dp[n][i]\n\n return total_sequences", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n # create a 2D dp array to store the number of possible sequences\n dp = [[0] * (m+1) for _ in range(n+1)]\n\n # initialize the first column with 1 because there is one possible sequence with length 1\n for i in range(1, m+1):\n dp[1][i] = 1\n\n # compute the number of possible sequences for each element in the dp array\n for i in range(2, n+1):\n for j in range(1, m+1):\n for k in range(j, m+1):\n if k >= 2*j:\n dp[i][k] += dp[i-1][j]\n\n # return the number of possible sequences of length n\n return sum(dp[n])", "matching_cluster_idx": 6}, {"solution": "def get_total_number_of_sequences(m, n):\n # Initialize dp array with all values set to 0\n dp = [[0 for _ in range(m + 1)] for _ in range(n + 1)]\n\n # Base case: if n is 1, there are m possible sequences\n for i in range(1, m + 1):\n dp[1][i] = 1\n\n # Iterate over length of the sequence from 2 to n\n for i in range(2, n + 1):\n for j in range(1, m + 1):\n # Iterate over possible values of current element of the sequence\n for k in range(2 * j, m + 1):\n dp[i][k] += dp[i - 1][j]\n\n # Sum up the last row of dp array to get the total number of sequences\n return sum(dp[n])", "matching_cluster_idx": 7}]}, "Mbpp/240": {"dps": 78.35365853658537, "dps_norm": 86.66666666666666, "pass@1": 81.0, "profiled": [{"solution": "def replace_list(list1, list2):\n list1[-1:] = list2\n return list1", "matching_cluster_idx": 7}, {"solution": "def replace_list(list1, list2):\n list1[-1:] = list2\n return list1", "matching_cluster_idx": 7}, {"solution": "def replace_list(list1, list2):\n # Replacing the last element of the first list with the second list\n list1[-1:] = list2\n return list1", "matching_cluster_idx": 7}, {"solution": "def replace_list(list1, list2):\n list1[-1:] = list2\n return list1", "matching_cluster_idx": 7}, {"solution": "def replace_list(list1, list2):\n # Replace the last element of list1 with the elements of list2\n list1[-1:] = list2\n return list1", "matching_cluster_idx": 7}, {"solution": "def replace_list(list1, list2):\n \"\"\"\n Function that takes in two lists and replaces the last element of the first list with the elements of the second list.\n \"\"\"\n list1.pop()\n list1.extend(list2)\n return list1", "matching_cluster_idx": 8}, {"solution": "def replace_list(list1, list2):\n if not list1: # Check if list1 is not empty\n return list2\n else:\n list1[-1:] = list2 # Replace the last element of list1 with list2\n return list1", "matching_cluster_idx": 7}, {"solution": "def replace_list(l1, l2):\n l1[-1:] = l2\n return l1", "matching_cluster_idx": 7}, {"solution": "def replace_list(lst1, lst2):\n if len(lst1) > 0:\n lst1[-1:] = lst2\n else:\n lst1 = lst2\n return lst1", "matching_cluster_idx": 7}, {"solution": "def replace_list(list1, list2):\n # remove the last element from the first list\n list1 = list1[:-1]\n # extend the first list with the elements of the second list\n list1.extend(list2)\n # return the modified first list\n return list1", "matching_cluster_idx": 6}, {"solution": "def replace_list(list1, list2):\n # Remove the last element from list1\n list1 = list1[:-1]\n # Extend list1 with the elements from list2\n list1.extend(list2)\n return list1", "matching_cluster_idx": 6}, {"solution": "def replace_list(list1, list2):\n list1[-1:] = list2\n return list1", "matching_cluster_idx": 7}, {"solution": "def replace_list(list1, list2):\n list1[-1:] = list2\n return list1", "matching_cluster_idx": 7}, {"solution": "def replace_list(list1, list2):\n list1[-1:] = list2\n return list1", "matching_cluster_idx": 7}, {"solution": "def replace_list(list1, list2):\n if len(list1) == 0:\n return list2\n else:\n list1.pop()\n for i in list2:\n list1.append(i)\n return list1", "matching_cluster_idx": 3}, {"solution": "def replace_list(list1, list2):\n # Removes last element from the first list\n list1.pop()\n\n # Extends the first list with the elements from the second list\n list1.extend(list2)\n\n return list1", "matching_cluster_idx": 8}, {"solution": "def replace_list(list1, list2):\n # Remove the last element of the first list\n list1 = list1[:-1]\n # Add the elements of the second list to the first list\n list1.extend(list2)\n # Return the modified list\n return list1", "matching_cluster_idx": 6}, {"solution": "def replace_list(list1, list2):\n if len(list1) == 0:\n return list2\n else:\n list1[-1:] = list2\n return list1", "matching_cluster_idx": 7}, {"solution": "def replace_list(list1, list2):\n list1[-1:] = list2\n return list1", "matching_cluster_idx": 7}, {"solution": "def replace_list(list1, list2):\n # remove the last element of the first list\n list1.pop()\n # extend the first list with the second list\n list1.extend(list2)\n return list1", "matching_cluster_idx": 8}]}, "Mbpp/251": {"dps": 61.09195402298851, "dps_norm": 70.0, "pass@1": 94.0, "profiled": [{"solution": "def insert_element(lst, elem):\n result = []\n for i in lst:\n result.append(elem)\n result.append(i)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, ele):\n result = []\n for item in lst:\n result.append(ele)\n result.append(item)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, el):\n \"\"\"\n Takes in a list and an element, inserts the element before each element in the list,\n and returns the resulting list.\n \"\"\"\n return [item for sublist in [[el, i] for i in lst] for item in sublist]", "matching_cluster_idx": 4}, {"solution": "def insert_element(lst, element):\n result = []\n for i in lst:\n result.append(element)\n result.append(i)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, elm):\n return [val for sublist in [[elm, i] for i in lst] for val in sublist]", "matching_cluster_idx": 4}, {"solution": "def insert_element(lst, el):\n return [val for sub in [[el, x] for x in lst] for val in sub]", "matching_cluster_idx": 4}, {"solution": "def insert_element(lst, element):\n \"\"\"\n A function that takes in a list and an element, inserts the element before each element in the list,\n and returns the resulting list.\n \"\"\"\n return [i for elem in lst for i in [element, elem]]", "matching_cluster_idx": 5}, {"solution": "def insert_element(lst, element):\n result = []\n for i in lst:\n result.append(element)\n result.append(i)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(input_list, element):\n result = []\n for i in input_list:\n result.append(element)\n result.append(i)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, elem):\n new_lst = []\n for i in lst:\n new_lst.append(elem)\n new_lst.append(i)\n return new_lst", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, ele):\n return [item for sublist in [[ele, i] for i in lst] for item in sublist]", "matching_cluster_idx": 4}, {"solution": "def insert_element(lst, elem):\n result = []\n for el in lst:\n result.append(elem)\n result.append(el)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, el):\n new_lst = []\n for i in lst:\n new_lst.append(el)\n new_lst.append(i)\n return new_lst", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, el):\n \"\"\"\n Insert the given element before each element in the list and return the resulting list.\n\n Parameters:\n lst (list): The input list.\n el: The element to insert before each element in the list.\n\n Returns:\n list: The resulting list.\n \"\"\"\n return [i for item in lst for i in (el, item)]", "matching_cluster_idx": 5}, {"solution": "def insert_element(lst, element):\n result = []\n for item in lst:\n result.append(element)\n result.append(item)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n result = []\n for i in lst:\n result.append(element)\n result.append(i)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n return [item for sublist in [[element, i] for i in lst] for item in sublist]", "matching_cluster_idx": 4}, {"solution": "def insert_element(lst, element):\n return [item for sublist in [[element, i] for i in lst] for item in sublist]", "matching_cluster_idx": 4}, {"solution": "def insert_element(list, element):\n # Initialize an empty list to store the result\n result = []\n # Loop through each element in the input list\n for el in list:\n # Append the given element and the current element in the list to the result list\n result.append(element)\n result.append(el)\n # Return the result list\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n # Create a new empty list\n new_lst = []\n\n # Iterate over each element in the given list\n for e in lst:\n # Append the given element and then the current element to the new list\n new_lst.append(element)\n new_lst.append(e)\n\n return new_lst", "matching_cluster_idx": 6}]}, "Mbpp/256": {"dps": 65.39954337899543, "dps_norm": 61.76470588235294, "pass@1": 50.0, "profiled": [{"solution": "def is_prime(n):\n \"\"\"\n Checks if a number is prime.\n \"\"\"\n if n < 2:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True\ndef count_Primes_nums(n):\n \"\"\"\n Returns the count of prime numbers less than a given non-negative number.\n \"\"\"\n count = 0\n for i in range(2, n):\n if is_prime(i):\n count += 1\n return count", "matching_cluster_idx": 8}, {"solution": "def count_Primes_nums(n):\n count = 0\n if n > 1:\n for num in range(2, n):\n i = 2\n for i in range(2, num):\n if (num % i) == 0:\n break\n else:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def is_prime(n):\n \"\"\"\n Checks if a number is prime\n \"\"\"\n if n <= 1:\n return False\n if n == 2:\n return True\n if n % 2 == 0:\n return False\n sqrt_n = int(n**0.5) + 1\n for div in range(3, sqrt_n, 2):\n if n % div == 0:\n return False\n return True\ndef count_Primes_nums(n):\n \"\"\"\n Counts the number of prime numbers less than a given non-negative number\n \"\"\"\n count = 0\n for num in range(2, n):\n if is_prime(num):\n count += 1\n return count", "matching_cluster_idx": 10}, {"solution": "def count_Primes_nums(n):\n def is_prime(num):\n if num < 2:\n return False\n for i in range(2,int(num**0.5)+1):\n if num % i == 0:\n return False\n return True\n\n count = 0\n for i in range(2,n):\n if is_prime(i):\n count += 1\n return count", "matching_cluster_idx": 8}, {"solution": "def is_prime(n):\n \"\"\"Helper function that checks if a number is prime.\"\"\"\n if n <= 1:\n return False\n if n == 2:\n return True\n if n % 2 == 0:\n return False\n i = 3\n while i * i <= n:\n if n % i == 0:\n return False\n i += 2\n return True\ndef count_Primes_nums(n):\n \"\"\"Function that counts the number of prime numbers less than the given non-negative number.\"\"\"\n count = 0\n for i in range(2, n):\n if is_prime(i):\n count += 1\n return count", "matching_cluster_idx": 8}, {"solution": "def count_Primes_nums(n):\n if n < 2:\n return 0\n primes = [True] * n\n primes[0] = primes[1] = False\n for i in range(2, int(n ** 0.5) + 1):\n if primes[i]:\n for j in range(i * i, n, i):\n primes[j] = False\n return sum(primes)", "matching_cluster_idx": 14}, {"solution": "def count_Primes_nums(n):\n \"\"\"\n A function that counts the number of prime numbers less than the given non-negative number.\n\n Args:\n n (int): a non-negative number.\n\n Returns:\n count (int): the number of prime numbers less than the given non-negative number.\n \"\"\"\n if n < 2: # There are no prime numbers less than 2.\n return 0\n\n primes = [True] * n\n primes[0] = primes[1] = False # 0 and 1 are not primes.\n\n for i in range(2, int(n ** 0.5) + 1):\n if primes[i]:\n for j in range(i * i, n, i):\n primes[j] = False\n\n return sum(primes)", "matching_cluster_idx": 14}, {"solution": "def count_Primes_nums(n):\n \"\"\"\n Function to count the number of prime numbers less than a given non-negative number.\n \"\"\"\n count = 0\n for num in range(2, n):\n is_prime = True\n for i in range(2, num):\n if num % i == 0:\n is_prime = False\n if is_prime:\n count += 1\n return count", "matching_cluster_idx": 0}, {"solution": "def count_Primes_nums(n):\n \"\"\"\n This function takes a non-negative integer n and returns the number of prime numbers less than n.\n \"\"\"\n if n < 2:\n return 0\n\n # Create a boolean array \"prime[0..n]\" and initialize all entries it as true.\n # A value in prime[i] will finally be false if i is Not a prime, else true.\n prime = [True for i in range(n+1)]\n p = 2\n while (p * p <= n):\n # If prime[p] is not changed, then it is a prime\n if (prime[p] == True):\n # Update all multiples of p\n for i in range(p * p, n+1, p):\n prime[i] = False\n p += 1\n\n # Return the count of prime numbers less than n\n return sum(prime[:n]) - 2 # subtract 2 as 0 and 1 are not prime", "matching_cluster_idx": 13}, {"solution": "def count_Primes_nums(n):\n \"\"\"\n A function that takes in a non-negative number and returns the number of prime numbers less than the given number.\n :param n: int, non-negative number\n :return: int, number of primes less than n\n \"\"\"\n if n <= 2:\n return 0\n else:\n primes = [True for i in range(n)]\n p = 2\n while (p * p <= n):\n if primes[p] == True:\n for i in range(p * p, n, p):\n primes[i] = False\n p += 1\n prime_count = 0\n for i in range(2, n):\n if primes[i]:\n prime_count += 1\n return prime_count", "matching_cluster_idx": 12}, {"solution": "def count_Primes_nums(n):\n \"\"\"Function to count prime numbers less than n\"\"\"\n if n < 2:\n return 0\n primes = [True] * n\n primes[0] = primes[1] = False\n for ind, val in enumerate(primes):\n if val is True:\n primes[ind*2::ind] = [False] * (((n - 1)//ind) - 1)\n return sum(primes)", "matching_cluster_idx": 14}, {"solution": "def count_Primes_nums(n):\n def is_prime(num):\n if num < 2:\n return False\n for i in range(2,int(num**0.5)+1):\n if num % i == 0:\n return False\n return True\n\n count = 0\n for i in range(2,n):\n if is_prime(i):\n count += 1\n return count", "matching_cluster_idx": 8}, {"solution": "def count_Primes_nums(n):\n def is_prime(num):\n if num < 2:\n return False\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n return False\n return True\n\n count = 0\n for num in range(2, n):\n if is_prime(num):\n count += 1\n return count", "matching_cluster_idx": 8}, {"solution": "def count_Primes_nums(n):\n \"\"\"\n Function to count the number of prime numbers less than a given non-negative number.\n \"\"\"\n if n < 2:\n return 0\n\n sieve = [True] * n\n for x in range(2, int(n ** 0.5) + 1):\n if sieve[x]:\n for i in range(x * x, n, x):\n sieve[i] = False\n return sum(sieve[2:])", "matching_cluster_idx": 14}, {"solution": "def count_Primes_nums(n):\n \"\"\"\n Function to return the count of prime numbers less than the given non-negative number\n \"\"\"\n def is_prime(num):\n \"\"\"\n Helper function to check if a number is prime\n \"\"\"\n if num <= 1:\n return False\n elif num <= 3:\n return True\n elif num % 2 == 0 or num % 3 == 0:\n return False\n i = 5\n while i * i <= num:\n if num % i == 0 or num % (i + 2) == 0:\n return False\n i += 6\n return True\n\n count = 0\n for num in range(2, n):\n if is_prime(num):\n count += 1\n return count", "matching_cluster_idx": 10}, {"solution": "def is_prime(n):\n if n < 2:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True\ndef count_Primes_nums(n):\n count = 0\n for i in range(2, n):\n if is_prime(i):\n count += 1\n return count", "matching_cluster_idx": 8}, {"solution": "def is_prime(n):\n \"\"\"Check if a number is prime\"\"\"\n if n < 2:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True\ndef count_Primes_nums(n):\n \"\"\"Return the number of prime numbers less than the given non-negative number\"\"\"\n count = 0\n for i in range(2, n):\n if is_prime(i):\n count += 1\n return count", "matching_cluster_idx": 8}, {"solution": "def count_Primes_nums(n):\n if n < 2:\n return 0\n primes = [True] * n\n p = 2\n while (p * p <= n):\n if (primes[p] == True):\n for i in range(p * p, n, p):\n primes[i] = False\n p += 1\n prime_count = 0\n for p in range(2, n):\n if primes[p]:\n prime_count += 1\n return prime_count", "matching_cluster_idx": 13}, {"solution": "def is_prime(n):\n \"\"\"Helper function to check if a number is prime\"\"\"\n if n <= 1:\n return False\n elif n <= 3:\n return True\n elif n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True\ndef count_Primes_nums(n):\n \"\"\"Function that counts prime numbers less than the given non-negative number\"\"\"\n count = 0\n for num in range(2, n):\n if is_prime(num):\n count += 1\n return count", "matching_cluster_idx": 10}, {"solution": "def count_Primes_nums(n):\n def is_prime(num):\n if num < 2:\n return False\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n return False\n return True\n\n count = 0\n for i in range(2, n):\n if is_prime(i):\n count += 1\n return count", "matching_cluster_idx": 8}]}, "Mbpp/265": {"dps": 75.29069767441861, "dps_norm": 85.83333333333333, "pass@1": 96.0, "profiled": [{"solution": "def list_split(input_list, n):\n # Create an empty list to store the resultant lists\n result = []\n\n # Iterate over the input_list in steps of size n\n for i in range(n):\n # Append the i-th element of each n-sized chunk to a new list\n result.append(input_list[i::n])\n\n return result", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n # Create an empty list to store the resulting lists\n result = []\n\n # Use list slicing to split the input list\n for i in range(n):\n result.append(lst[i::n])\n\n return result", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n return [lst[i::n] for i in range(n)]", "matching_cluster_idx": 4}, {"solution": "def list_split(arr, n):\n # Using list comprehension to split the list\n return [arr[i::n] for i in range(n)]", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n # Using list comprehension\n return [lst[i::n] for i in range(n)]", "matching_cluster_idx": 4}, {"solution": "def list_split(input_list, n):\n # Create an empty list to store the result\n result = []\n\n # Iterate through the input_list\n for i in range(n):\n # For each index, create a new list that consists of every nth element starting from i\n result.append(input_list[i::n])\n\n # Return the result\n return result", "matching_cluster_idx": 4}, {"solution": "def list_split(input_list, n):\n return [input_list[i::n] for i in range(n)]", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n return [lst[i::n] for i in range(n)]", "matching_cluster_idx": 5}, {"solution": "def list_split(lst, n):\n # Use list comprehension to generate a list of the nth elements in lst\n return [lst[i::n] for i in range(n)]", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n return [lst[i::n] for i in range(n)]", "matching_cluster_idx": 4}, {"solution": "def list_split(input_list, n):\n return [input_list[i::n] for i in range(n)]", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n return [lst[i::n] for i in range(n)]", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n return [lst[i::n] for i in range(n)]", "matching_cluster_idx": 5}, {"solution": "def list_split(input_list, n):\n # empty list to hold the resulting lists\n result = []\n # loop through the input_list with a step size of n\n for i in range(n):\n # use list slicing to get every nth element of the input_list\n # and append it to the result list\n result.append(input_list[i::n])\n # return the list of resulting lists\n return result", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n return [lst[i::n] for i in range(n)]", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n return [lst[i::n] for i in range(n)]", "matching_cluster_idx": 4}, {"solution": "def list_split(input_list, n):\n \"\"\"\n A function that takes in a list and an integer n and splits the list for every nth element.\n Returns a list of the resulting lists.\n \"\"\"\n return [input_list[i::n] for i in range(n)]", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n return [lst[i::n] for i in range(n)]", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n # Empty list to store the resulting lists\n result = []\n # Loop over elements in input list\n for i in range(n):\n # Create a new list containing every nth element in the input list\n new_lst = lst[i::n]\n # Add the new list to the result list\n result.append(new_lst)\n return result", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n return [lst[i::n] for i in range(n)]", "matching_cluster_idx": 5}]}, "Mbpp/281": {"dps": 94.0, "dps_norm": 81.81818181818181, "pass@1": 100.0, "profiled": [{"solution": "def all_unique(lst):\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n # Convert the list to a set\n unique_lst = set(lst)\n # If the size of the set is equal to the size of the list, all elements are unique\n return len(unique_lst) == len(lst)", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n # Convert the list to a set. Set only contains unique elements.\n # If the lengths of the set and the list are the same, then all elements are unique.\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"Check if the elements of a given list are unique or not.\"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n This function checks if the elements of a given list are unique or not.\n\n Parameters:\n lst (list): A list of elements.\n\n Returns:\n bool: True if all elements are unique, False otherwise.\n \"\"\"\n # Using set to remove duplicate elements. If all elements are unique,\n # the length of the set will be equal to the length of the list.\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n if len(lst) == len(set(lst)):\n return True\n else:\n return False", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n This function takes a list as input and checks if all its elements are unique or not.\n\n :param lst: list of elements\n :return: True if all elements are unique, False otherwise\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n A function to check if the elements of a given list are unique or not.\n \"\"\"\n # Use a set to remove duplicates, then compare the lengths.\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n This function takes a list as an argument and returns True if all elements in the list are unique, else False.\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n if len(lst) == len(set(lst)):\n return True\n else:\n return False", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n # Convert list into a set and compare length of the set with the original list\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n Function to check if all elements in the list are unique.\n\n Args:\n lst: list of elements\n\n Returns:\n bool: True if all elements are unique, False otherwise\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"Check if all elements in a list are unique.\"\"\"\n # Convert list to a set and check if lengths are equal.\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n if len(lst) == len(set(lst)):\n return True\n else:\n return False", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}]}, "Mbpp/296": {"dps": 67.6923076923077, "dps_norm": 85.0, "pass@1": 77.0, "profiled": [{"solution": "def merge_sort(arr):\n if len(arr) <= 1:\n return arr, 0\n\n mid = len(arr) // 2\n left, inv_left = merge_sort(arr[:mid])\n right, inv_right = merge_sort(arr[mid:])\n sorted_arr, inv_split = merge(left, right)\n\n return sorted_arr, inv_left + inv_right + inv_split\ndef merge(left, right):\n i = j = k = inv_count = 0\n sorted_arr = []\n\n while i < len(left) and j < len(right):\n if left[i] <= right[j]:\n sorted_arr.append(left[i])\n i += 1\n else:\n sorted_arr.append(right[j])\n j += 1\n inv_count += len(left) - i\n\n sorted_arr.extend(left[i:])\n sorted_arr.extend(right[j:])\n\n return sorted_arr, inv_count\ndef get_Inv_Count(arr):\n _, inv_count = merge_sort(arr)\n return inv_count", "matching_cluster_idx": 5}, {"solution": "def get_Inv_Count(arr):\n def merge_sort(arr):\n if len(arr) <= 1:\n return arr, 0\n mid = len(arr) // 2\n left, left_inv = merge_sort(arr[:mid])\n right, right_inv = merge_sort(arr[mid:])\n merged, split_inv = merge(left, right)\n return merged, left_inv + right_inv + split_inv\n\n def merge(left, right):\n i = j = 0\n inv_count = 0\n merged = []\n while i < len(left) and j < len(right):\n if left[i] <= right[j]:\n merged.append(left[i])\n i += 1\n else:\n merged.append(right[j])\n inv_count += len(left) - i\n j += 1\n while i < len(left):\n merged.append(left[i])\n i += 1\n while j < len(right):\n merged.append(right[j])\n j += 1\n return merged, inv_count\n\n sorted_arr, inv_count = merge_sort(arr)\n return inv_count", "matching_cluster_idx": 5}, {"solution": "def get_Inv_Count(arr):\n \"\"\"Function to count inversions in an array.\"\"\"\n inv_count = 0\n n = len(arr)\n\n # Two nested loops to compare each element with every other element\n for i in range(n):\n for j in range(i+1, n):\n if arr[i] > arr[j]:\n inv_count += 1\n\n return inv_count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(array):\n count = 0\n for i in range(len(array)):\n for j in range(i + 1, len(array)):\n if (array[i] > array[j]):\n count += 1\n return count", "matching_cluster_idx": 3}, {"solution": "def merge_sort_and_count(array):\n if len(array) <= 1:\n return array, 0\n\n middle = len(array) // 2\n left, left_count = merge_sort_and_count(array[:middle])\n right, right_count = merge_sort_and_count(array[middle:])\n\n i, j, k, count = 0, 0, 0, 0\n merged = [0] * len(array)\n\n while i < len(left) and j < len(right):\n if left[i] <= right[j]:\n merged[k] = left[i]\n i += 1\n else:\n merged[k] = right[j]\n j += 1\n count += len(left) - i\n k += 1\n\n while i < len(left):\n merged[k] = left[i]\n i += 1\n k += 1\n\n while j < len(right):\n merged[k] = right[j]\n j += 1\n k += 1\n\n return merged, count + left_count + right_count\ndef get_Inv_Count(array):\n _, count = merge_sort_and_count(array)\n return count", "matching_cluster_idx": 5}, {"solution": "def get_Inv_Count(arr):\n \"\"\"\n Function to count inversions in an array\n \"\"\"\n inv_count = 0\n for i in range(len(arr)):\n for j in range(i + 1, len(arr)):\n if arr[i] > arr[j]:\n inv_count += 1\n return inv_count", "matching_cluster_idx": 3}, {"solution": "def merge_sort_and_count_inv(arr):\n if len(arr) <= 1:\n return arr, 0\n\n mid = len(arr) // 2\n left_half, left_inv = merge_sort_and_count_inv(arr[:mid])\n right_half, right_inv = merge_sort_and_count_inv(arr[mid:])\n sorted_arr, split_inv = merge_and_count_split_inv(left_half, right_half)\n\n return sorted_arr, left_inv + right_inv + split_inv\ndef merge_and_count_split_inv(left_half, right_half):\n i = j = inv_count = 0\n sorted_arr = []\n while i < len(left_half) and j < len(right_half):\n if left_half[i] <= right_half[j]:\n sorted_arr.append(left_half[i])\n i += 1\n else:\n sorted_arr.append(right_half[j])\n j += 1\n inv_count += len(left_half) - i\n\n while i < len(left_half):\n sorted_arr.append(left_half[i])\n i += 1\n\n while j < len(right_half):\n sorted_arr.append(right_half[j])\n j += 1\n\n return sorted_arr, inv_count\ndef get_Inv_Count(arr):\n _, inv_count = merge_sort_and_count_inv(arr)\n return inv_count", "matching_cluster_idx": 5}, {"solution": "def merge_sort(array):\n if len(array) <= 1:\n return array, 0\n else:\n middle = len(array) // 2\n left, left_inv = merge_sort(array[:middle])\n right, right_inv = merge_sort(array[middle:])\n merged, split_inv = merge(left, right)\n return merged, left_inv + right_inv + split_inv\ndef merge(left, right):\n result = []\n i = j = inversions = 0\n while i < len(left) and j < len(right):\n if left[i] <= right[j]:\n result.append(left[i])\n i += 1\n else:\n result.append(right[j])\n j += 1\n inversions += len(left) - i\n result.extend(left[i:])\n result.extend(right[j:])\n return result, inversions\ndef get_Inv_Count(array):\n _, inv_count = merge_sort(array)\n return inv_count", "matching_cluster_idx": 5}, {"solution": "def get_Inv_Count(arr):\n inv_count = 0\n for i in range(len(arr)):\n for j in range(i+1, len(arr)):\n if(arr[i] > arr[j]):\n inv_count += 1\n return inv_count", "matching_cluster_idx": 3}, {"solution": "def merge_and_count(arr):\n if len(arr) <= 1:\n return arr, 0\n\n mid = len(arr) // 2\n left, left_inv_count = merge_and_count(arr[:mid])\n right, right_inv_count = merge_and_count(arr[mid:])\n sorted_arr, inv_count = merge(left, right)\n\n return sorted_arr, left_inv_count + right_inv_count + inv_count\ndef merge(left, right):\n sorted_arr = []\n inv_count = 0\n i = j = 0\n\n while i < len(left) and j < len(right):\n if left[i] <= right[j]:\n sorted_arr.append(left[i])\n i += 1\n else:\n sorted_arr.append(right[j])\n inv_count += len(left) - i\n j += 1\n\n sorted_arr.extend(left[i:])\n sorted_arr.extend(right[j:])\n\n return sorted_arr, inv_count\ndef get_Inv_Count(arr):\n _, inv_count = merge_and_count(arr)\n return inv_count", "matching_cluster_idx": 5}, {"solution": "def get_Inv_Count(arr):\n count = 0\n for i in range(len(arr)):\n for j in range(i+1, len(arr)):\n if arr[i] > arr[j]:\n count += 1\n return count", "matching_cluster_idx": 3}, {"solution": "def merge_sort(arr, n):\n temp_arr = [0]*n\n return _merge_sort(arr, temp_arr, 0, n-1)\ndef _merge_sort(arr, temp_arr, left, right):\n inv_count = 0\n\n if left < right:\n mid = (left + right)//2\n inv_count += _merge_sort(arr, temp_arr, left, mid)\n inv_count += _merge_sort(arr, temp_arr, mid + 1, right)\n inv_count += merge(arr, temp_arr, left, mid, right)\n\n return inv_count\ndef merge(arr, temp_arr, left, mid, right):\n i = left\n j = mid + 1\n k = left\n inv_count = 0\n\n while i <= mid and j <= right:\n if arr[i] <= arr[j]:\n temp_arr[k] = arr[i]\n k += 1\n i += 1\n else:\n temp_arr[k] = arr[j]\n inv_count += (mid-i + 1)\n k += 1\n j += 1\n\n while i <= mid:\n temp_arr[k] = arr[i]\n k += 1\n i += 1\n\n while j <= right:\n temp_arr[k] = arr[j]\n k += 1\n j += 1\n\n for loop_var in range(left, right + 1):\n arr[loop_var] = temp_arr[loop_var]\n\n return inv_count\ndef get_Inv_Count(arr):\n return merge_sort(arr, len(arr))", "matching_cluster_idx": 5}, {"solution": "def get_Inv_Count(arr):\n # Merge sort function to split array into subarrays, count inversions\n def merge_sort(arr):\n if len(arr) == 1:\n return arr, 0\n else:\n mid = len(arr) // 2\n left, left_inv = merge_sort(arr[:mid])\n right, right_inv = merge_sort(arr[mid:])\n merged, split_inv = merge(left, right)\n return merged, left_inv + right_inv + split_inv\n\n # Function to merge two arrays and count the number of split inversions\n def merge(left, right):\n i = j = inv_count = 0\n merged = []\n while i < len(left) and j < len(right):\n if left[i] <= right[j]:\n merged.append(left[i])\n i += 1\n else:\n merged.append(right[j])\n j += 1\n # count the number of elements that are greater than right[j] in left\n inv_count += len(left[i:])\n merged.extend(left[i:])\n merged.extend(right[j:])\n return merged, inv_count\n\n return merge_sort(arr)[1]", "matching_cluster_idx": 3}, {"solution": "def mergeSort(arr, n):\n temp_arr = [0]*n\n return _mergeSort(arr, temp_arr, 0, n-1)\ndef _mergeSort(arr, temp_arr, left, right):\n inv_count = 0\n if left < right:\n mid = (left + right)//2\n inv_count += _mergeSort(arr, temp_arr, left, mid)\n inv_count += _mergeSort(arr, temp_arr, mid + 1, right)\n inv_count += merge(arr, temp_arr, left, mid, right)\n return inv_count\ndef merge(arr, temp_arr, left, mid, right):\n i = left\n j = mid + 1\n k = left\n inv_count = 0\n while i <= mid and j <= right:\n if arr[i] <= arr[j]:\n temp_arr[k] = arr[i]\n k += 1\n i += 1\n else:\n temp_arr[k] = arr[j]\n inv_count += (mid-i + 1)\n k += 1\n j += 1\n while i <= mid:\n temp_arr[k] = arr[i]\n k += 1\n i += 1\n while j <= right:\n temp_arr[k] = arr[j]\n k += 1\n j += 1\n for loop_var in range(left, right + 1):\n arr[loop_var] = temp_arr[loop_var]\n return inv_count\ndef get_Inv_Count(arr):\n return mergeSort(arr, len(arr))", "matching_cluster_idx": 5}, {"solution": "def merge_sort_inv_count(arr):\n if len(arr) <= 1:\n return arr, 0\n\n mid = len(arr) // 2\n left, left_inv = merge_sort_inv_count(arr[:mid])\n right, right_inv = merge_sort_inv_count(arr[mid:])\n\n i, j, inv_count = 0, 0, 0\n merged = []\n while i < len(left) and j < len(right):\n if left[i] <= right[j]:\n merged.append(left[i])\n i += 1\n else:\n merged.append(right[j])\n j += 1\n inv_count += len(left) - i\n\n merged += left[i:]\n merged += right[j:]\n inv_count += left_inv + right_inv\n return merged, inv_count\ndef get_Inv_Count(arr):\n _, inv_count = merge_sort_inv_count(arr)\n return inv_count", "matching_cluster_idx": 5}, {"solution": "def get_Inv_Count(arr):\n # Initialize inversion count to 0\n inv_count = 0\n\n # Traverse through all array elements\n for i in range(len(arr)):\n # For each element, count number of elements which are on right side of it and are smaller than it.\n for j in range(i + 1, len(arr)):\n if arr[i] > arr[j]:\n inv_count += 1\n\n # Return the total count of inversions in the array\n return inv_count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n # Merge sorting and counting the number of inversions is an efficient way to solve this problem\n def merge_sort(arr):\n # Base case: 0 or 1 items in array\n if len(arr) <= 1:\n return arr, 0\n\n # Split array into two halves\n mid = len(arr) // 2\n left, left_inv = merge_sort(arr[:mid])\n right, right_inv = merge_sort(arr[mid:])\n\n # Merge two sorted halves and count inversions\n merged = []\n i = j = inv_count = 0\n while i < len(left) and j < len(right):\n if left[i] <= right[j]:\n merged.append(left[i])\n i += 1\n else:\n # left[i] > right[j], therefore, left[i...] is greater than right[j]\n merged.append(right[j])\n j += 1\n inv_count += len(left) - i\n\n # Add remaining elements of left and right to merged list\n merged.extend(left[i:])\n merged.extend(right[j:])\n\n return merged, inv_count + left_inv + right_inv\n\n # Call merge_sort on arr\n _, inv_count = merge_sort(arr)\n return inv_count", "matching_cluster_idx": 5}, {"solution": "def get_Inv_Count(arr):\n count = 0\n for i in range(len(arr)):\n for j in range(i+1, len(arr)):\n if arr[i] > arr[j]:\n count += 1\n return count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n n = len(arr)\n temp = [0] * n\n return _mergeSort(arr, temp, 0, n-1)\ndef _mergeSort(arr, temp, left, right):\n inv_count = 0\n\n if left < right:\n mid = (left + right)//2\n\n inv_count += _mergeSort(arr, temp, left, mid)\n\n inv_count += _mergeSort(arr, temp, mid + 1, right)\n\n inv_count += _merge(arr, temp, left, mid, right)\n\n return inv_count\ndef _merge(arr, temp, left, mid, right):\n i = left\n j = mid + 1\n k = left\n inv_count = 0\n\n while i <= mid and j <= right:\n if arr[i] <= arr[j]:\n temp[k] = arr[i]\n i += 1\n else:\n temp[k] = arr[j]\n j += 1\n\n inv_count += (mid-i + 1)\n\n k += 1\n\n while i <= mid:\n temp[k] = arr[i]\n k += 1\n i += 1\n\n while j <= right:\n temp[k] = arr[j]\n k += 1\n j += 1\n\n for loop_var in range(left, right + 1):\n arr[loop_var] = temp[loop_var]\n\n return inv_count", "matching_cluster_idx": 5}, {"solution": "def get_Inv_Count(arr):\n \"\"\"\n Function to count inversions in an array.\n An inversion in a discrete sequence of numbers is a pair of numbers in the sequence\n that are out of order.\n :param arr: input list\n :return: number of inversions in the input list\n \"\"\"\n # Initialize a counter to count inversions\n inv_count = 0\n # Loop over the list\n for i in range(len(arr)):\n for j in range(i + 1, len(arr)):\n # If a pair of numbers is found out of order, increment the counter\n if arr[i] > arr[j]:\n inv_count += 1\n # Return the total number of inversions\n return inv_count", "matching_cluster_idx": 3}]}, "Mbpp/308": {"dps": null, "dps_norm": null, "pass@1": 4.0, "profiled": []}, "Mbpp/392": {"dps": 73.47417840375587, "dps_norm": 78.84615384615384, "pass@1": 25.0, "profiled": [{"solution": "def get_max_sum(n):\n if n <= 5:\n return n\n else:\n return max(get_max_sum(n//2) + get_max_sum(n//3) + get_max_sum(n//4) + get_max_sum(n//5), n)", "matching_cluster_idx": 8}, {"solution": "def get_max_sum(n):\n if n < 6:\n return n\n else:\n return max(get_max_sum(n // 2) + get_max_sum(n // 3) + get_max_sum(n // 4) + get_max_sum(n // 5), n)", "matching_cluster_idx": 8}, {"solution": "def get_max_sum(n):\n # Define the function f(n)\n def f(n):\n # Initialize the base case when n is 0 or 1\n if n == 0 or n == 1:\n return n\n # Use memoization to avoid computing the same subproblem multiple times\n if n in memo:\n return memo[n]\n # Compute f(n) as the maximum between the sum of f(n/i) and n\n max_sum = max(f(n//2) + f(n//3) + f(n//4) + f(n//5), n)\n # Store the result of f(n) in the memo dictionary to avoid future recomputation\n memo[n] = max_sum\n return max_sum\n # Initialize a dictionary to store the results of f(n) for different n\n memo = {}\n return f(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n memo = {}\n def f(n):\n if n in memo:\n return memo[n]\n elif n < 6:\n memo[n] = n\n return n\n else:\n memo[n] = max(f(n//2) + f(n//3) + f(n//4) + f(n//5), n)\n return memo[n]\n return f(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n # Memoization to avoid unnecessary computation\n memo = {}\n def helper(n):\n if n in memo:\n return memo[n]\n if n < 6:\n memo[n] = n\n return n\n max_sum = max((helper(n // 2) + helper(n // 3) + helper(n // 4) + helper(n // 5)), n)\n memo[n] = max_sum\n return max_sum\n return helper(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n # Memoization\n memo = {}\n def f(n):\n if n == 0 or n == 1:\n return n\n if n in memo:\n return memo[n]\n else:\n result = max((f(n//2) + f(n//3) + f(n//4) + f(n//5)), n)\n memo[n] = result\n return result\n return f(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n # Create a list to store the results of the function\n # So that we can easily get the values that have been already computed\n f = [0] * (n + 1)\n\n # Compute the function values\n for i in range(1, n+1):\n f[i] = max(f[i//2] + f[i//3] + f[i//4] + f[i//5], i)\n\n return f[n]", "matching_cluster_idx": 10}, {"solution": "def get_max_sum(n):\n if n < 2:\n return n\n else:\n return max(get_max_sum(n // 2) + get_max_sum(n // 3) + get_max_sum(n // 4) + get_max_sum(n // 5), n)", "matching_cluster_idx": 3}, {"solution": "def get_max_sum(n):\n if n < 2:\n return n\n return max(get_max_sum(n // 2) + get_max_sum(n // 3) + get_max_sum(n // 4) + get_max_sum(n // 5), n)", "matching_cluster_idx": 3}, {"solution": "def get_max_sum(n):\n # Create a dictionary to store the computed values to avoid recomputation\n computed_values = {0: 0, 1: 1}\n\n # Define the function f(n) = max( (f(n/2) + f(n/3) + f(n/4) + f(n/5)), n)\n def f(x):\n if x in computed_values:\n return computed_values[x]\n else:\n computed_values[x] = max(f(x//2) + f(x//3) + f(x//4) + f(x//5), x)\n return computed_values[x]\n\n return f(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n # Initialize a dictionary to store calculated max sums\n max_sums = {0: 0, 1: 1}\n\n # Define a helper function to calculate the max sum for a given number\n def calculate_max_sum(num):\n # Return calculated max sum if already exists\n if num in max_sums:\n return max_sums[num]\n # Else, calculate max sum using the equation and store it in max_sums\n else:\n max_sum = max(calculate_max_sum(num//2) + calculate_max_sum(num//3) + calculate_max_sum(num//4) + calculate_max_sum(num//5), num)\n max_sums[num] = max_sum\n return max_sum\n\n # Call the helper function and return the max sum for the given number\n return calculate_max_sum(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n # Create a dictionary to store previously calculated values\n f_dict = {}\n\n # Define the recursive function that calculates the maximum sum\n def f(n):\n # Check if the value has already been calculated\n if n in f_dict:\n return f_dict[n]\n # Base case\n elif n < 5:\n return n\n else:\n # Recursive case\n f_dict[n] = max((f(n//2) + f(n//3) + f(n//4) + f(n//5)), n)\n return f_dict[n]\n\n return f(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n # Initialize a dictionary to store already computed results\n max_sum_dict = {0: 0, 1: 1}\n\n # If the value is already computed, return it\n if n in max_sum_dict:\n return max_sum_dict[n]\n\n # Calculate the maximum sum possible\n max_sum = max(get_max_sum(n // 2) + get_max_sum(n // 3) + get_max_sum(n // 4) + get_max_sum(n // 5), n)\n\n # Save the result in the dictionary for future use\n max_sum_dict[n] = max_sum\n\n return max_sum", "matching_cluster_idx": 2}, {"solution": "def get_max_sum(n):\n # Create a memoization dictionary to save previously calculated values.\n memo = {0:0, 1:1}\n\n def f(n):\n # Return the memoized value if it exists.\n if n in memo:\n return memo[n]\n\n # Calculate the value using the formula and save it to the memoization dictionary.\n memo[n] = max(f(n//2) + f(n//3) + f(n//4) + f(n//5), n)\n\n return memo[n]\n\n return f(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n if n <= 5:\n return n\n else:\n return max(get_max_sum(n//2) + get_max_sum(n//3) + get_max_sum(n//4) + get_max_sum(n//5), n)", "matching_cluster_idx": 8}, {"solution": "def get_max_sum(n):\n # Initialize a dictionary to store the computed f(n) values\n dp = {0: 0}\n\n # Define the function f(n) using a helper function\n def f(n):\n # If f(n) has already been computed, return the computed value\n if n in dp:\n return dp[n]\n\n # Compute f(n) using the given equation\n dp[n] = max((f(n // 2) + f(n // 3) + f(n // 4) + f(n // 5)), n)\n return dp[n]\n\n # Call the helper function f(n) with the input value of n\n return f(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n # Create a dictionary to store computed values\n memo = {0: 0, 1: 1}\n\n def f(n):\n # Check if the value has been computed before\n if n not in memo:\n # Compute the value as the maximum of (f(n/2) + f(n/3) + f(n/4) + f(n/5)) and n\n memo[n] = max(f(n//2) + f(n//3) + f(n//4) + f(n//5), n)\n return memo[n]\n\n return f(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n if n <= 1:\n return n\n else:\n return max((get_max_sum(n//2) + get_max_sum(n//3) + get_max_sum(n//4) + get_max_sum(n//5)), n)", "matching_cluster_idx": 3}, {"solution": "def get_max_sum(n):\n \"\"\"\n This function calculates the maximum sum possible by using the equation f(n) = max((f(n/2) + f(n/3) + f(n/4) + f(n/5)), n)\n and returns the maximum sum.\n\n Args:\n n (int): The input integer\n\n Returns:\n int: The maximum sum possible\n \"\"\"\n # initialize a dictionary to store the calculated values\n calc_dict = {}\n\n # define the function f(n) recursively\n def f(n):\n if n == 0:\n return 0\n if n in calc_dict:\n return calc_dict[n]\n else:\n calc_dict[n] = max((f(n // 2) + f(n // 3) + f(n // 4) + f(n // 5)), n)\n return calc_dict[n]\n\n # calculate and return the maximum sum\n return f(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n if n < 6:\n return n\n else:\n return max(get_max_sum(n//2) + get_max_sum(n//3) + get_max_sum(n//4) + get_max_sum(n//5), n)", "matching_cluster_idx": 8}]}, "Mbpp/395": {"dps": 81.14942528735632, "dps_norm": 72.5, "pass@1": 100.0, "profiled": [{"solution": "def first_non_repeating_character(s):\n char_count = {}\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n for char in s:\n if char_count[char] == 1:\n return char\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n count = {}\n for char in s:\n if char in count:\n count[char] += 1\n else:\n count[char] = 1\n for char in s:\n if count[char] == 1:\n return char\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(string):\n count = {}\n for char in string:\n if char in count:\n count[char] += 1\n else:\n count[char] = 1\n\n for char in string:\n if count[char] == 1:\n return char\n\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(string):\n # Count frequency of each character\n counts = {}\n for char in string:\n if char in counts:\n counts[char] += 1\n else:\n counts[char] = 1\n\n # Find the first character with frequency 1\n for char in string:\n if counts[char] == 1:\n return char\n\n # No non-repeated characters found\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n \"\"\"\n Function to find the first non-repeated character in a given string.\n \"\"\"\n # Create a dictionary to store character frequencies\n freq = {}\n for char in s:\n if char in freq:\n freq[char] += 1\n else:\n freq[char] = 1\n\n # Loop over the string to find the first non-repeated character\n for char in s:\n if freq[char] == 1:\n return char\n\n # Return None if no non-repeated character is found\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(input_string):\n # Create a dictionary to store character counts\n char_count = {}\n for char in input_string:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n\n # Check each character in the string\n for char in input_string:\n if char_count[char] == 1:\n return char\n\n # If no non-repeated character found, return None\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(input_string):\n # Create an empty dictionary to store frequency of each character\n freq = {}\n for char in input_string:\n # If character is already in dictionary, increment the count by 1\n if char in freq:\n freq[char] += 1\n # If character is not in dictionary, add it with a count of 1\n else:\n freq[char] = 1\n # Iterate through the string again\n for char in input_string:\n # If frequency of the character is 1, return the character\n if freq[char] == 1:\n return char\n # If no character is non-repeating, return None\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(string):\n char_count = {}\n for char in string:\n if char not in char_count:\n char_count[char] = 1\n else:\n char_count[char] += 1\n for char in string:\n if char_count[char] == 1:\n return char\n return None", "matching_cluster_idx": 4}, {"solution": "def first_non_repeating_character(input_string):\n char_count = {}\n\n # Count the occurrences of each character\n for char in input_string:\n if char not in char_count:\n char_count[char] = 0\n char_count[char] += 1\n\n # Find the first non-repeating character\n for char in input_string:\n if char_count[char] == 1:\n return char\n\n # Return None if no non-repeating character is found\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n counts = {}\n for c in s:\n if c in counts:\n counts[c] += 1\n else:\n counts[c] = 1\n for c in s:\n if counts[c] == 1:\n return c\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n count = {}\n for char in s:\n if char not in count:\n count[char] = 1\n else:\n count[char] += 1\n for char in s:\n if count[char] == 1:\n return char\n return None", "matching_cluster_idx": 4}, {"solution": "def first_non_repeating_character(input_string):\n character_frequency = {}\n\n # count the frequency of each character\n for char in input_string:\n if char not in character_frequency:\n character_frequency[char] = 1\n else:\n character_frequency[char] += 1\n\n # find the first non-repeating character\n for char in input_string:\n if character_frequency[char] == 1:\n return char\n\n return None", "matching_cluster_idx": 4}, {"solution": "def first_non_repeating_character(input_string):\n char_count = {}\n for char in input_string:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n\n for char in input_string:\n if char_count[char] == 1:\n return char\n return None", "matching_cluster_idx": 4}, {"solution": "def first_non_repeating_character(input_string):\n # use a dictionary to store character frequencies\n char_freq = {}\n for char in input_string:\n if char in char_freq:\n char_freq[char] += 1\n else:\n char_freq[char] = 1\n\n # iterate through the input string and return the first non-repeated character\n for char in input_string:\n if char_freq[char] == 1:\n return char\n\n # return None if there is no non-repeated character\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n # Build the character count map\n char_count = {}\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n\n # Find the first non-repeated character\n for char in s:\n if char_count[char] == 1:\n return char\n\n # Return None if no non-repeated character found\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(string):\n # create a dictionary to store character frequencies\n char_freq = {}\n for char in string:\n if char in char_freq:\n char_freq[char] += 1\n else:\n char_freq[char] = 1\n # iterate over the string to find the first non-repeating character\n for char in string:\n if char_freq[char] == 1:\n return char\n # return None if all characters are repeating\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(input_string):\n char_count = {}\n for char in input_string:\n char_count[char] = char_count.get(char, 0) + 1\n for char in input_string:\n if char_count[char] == 1:\n return char\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n count = {}\n for c in s:\n if c in count:\n count[c] += 1\n else:\n count[c] = 1\n for c in s:\n if count[c] == 1:\n return c\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n \"\"\"\n This function finds and returns the first non-repeating character in a given string.\n If there are no non-repeating characters, it returns None.\n \"\"\"\n # Count the frequency of each character in the string\n char_count = {}\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n\n # Find the first character that appears only once\n for char in s:\n if char_count[char] == 1:\n return char\n\n # If all characters repeat, return None\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n \"\"\"Find the first non-repeating character in a given string\"\"\"\n # Create a dictionary to count the occurrence of each character in the string\n count_dict = {}\n for char in s:\n if char in count_dict:\n count_dict[char] += 1\n else:\n count_dict[char] = 1\n # Find the first character that occurs only once\n for char in s:\n if count_dict[char] == 1:\n return char\n # Return None if all characters are repeated\n return None", "matching_cluster_idx": 5}]}, "Mbpp/405": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def check_tuplex(tuplex, element):\n return element in tuplex", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(t, x):\n if x in t:\n return True\n else:\n return False", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, element):\n if element in tuplex:\n return True\n else:\n return False", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tup, element):\n if element in tup:\n return True\n else:\n return False", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tup, elem):\n \"\"\"\n Function to check whether an element exists within a tuple.\n\n :param tup: the tuple to check\n :param elem: the element to check for\n :return: True if element exists in tuple, False otherwise\n \"\"\"\n return elem in tup", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, element):\n \"\"\"\n This function checks whether an element exists within a tuple.\n \"\"\"\n return element in tuplex", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tup, element):\n return element in tup", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tup, element):\n if element in tup:\n return True\n else:\n return False", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, element):\n return element in tuplex", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(t, e):\n \"\"\"\n This function checks whether an element exists within a tuple.\n\n Parameters:\n t (tuple): The tuple to search.\n e: The element to search for.\n\n Returns:\n bool: True if the element is in the tuple, False otherwise.\n \"\"\"\n return e in t", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tup, element):\n if element in tup:\n return True\n else:\n return False", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tup, element):\n if element in tup:\n return True\n else:\n return False", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tup, elem):\n if elem in tup:\n return True\n else:\n return False", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tup, element):\n \"\"\"\n Function to check if an element exists within a tuple.\n\n Parameters:\n tup (tuple): The tuple to search.\n element : The element to search for.\n\n Returns:\n bool: True if the element is in the tuple, False otherwise.\n \"\"\"\n return element in tup", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuple, element):\n if element in tuple:\n return True\n else:\n return False", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tup, element):\n return element in tup", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tup, element):\n if element in tup:\n return True\n else:\n return False", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, element):\n if element in tuplex:\n return True\n else:\n return False", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tup, elem):\n # function to check if element exists in tuple\n if elem in tup:\n return True\n else:\n return False", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tup, elem):\n \"\"\"\n This function checks whether an element exists within a tuple.\n \"\"\"\n return elem in tup", "matching_cluster_idx": 3}]}, "Mbpp/414": {"dps": 75.09316770186335, "dps_norm": 82.22222222222223, "pass@1": 100.0, "profiled": [{"solution": "def overlapping(seq1, seq2):\n # This function checks if any value in seq1 exists in seq2.\n # It does so by converting both sequences to sets and using the intersection method.\n # If the intersection of the two sets is not empty, that means the sequences overlap.\n\n set1 = set(seq1)\n set2 = set(seq2)\n\n if set1 & set2:\n return True\n else:\n return False", "matching_cluster_idx": 5}, {"solution": "def overlapping(seq1, seq2):\n # Convert sequences to sets\n set1 = set(seq1)\n set2 = set(seq2)\n\n # Check for intersection\n if set1 & set2:\n return True\n else:\n return False", "matching_cluster_idx": 5}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n A function to check whether any value in seq1 exists in seq2 or not.\n \"\"\"\n return any(i in seq2 for i in seq1)", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n for value in seq1:\n if value in seq2:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n This function checks whether any value in a sequence exists in another sequence or not.\n \"\"\"\n return any(i in seq2 for i in seq1)", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n return any(i in seq2 for i in seq1)", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n return any(i in seq2 for i in seq1)", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n return any(i in seq2 for i in seq1)", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n return any(i in seq2 for i in seq1)", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n return any(item in seq2 for item in seq1)", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n for value in seq1:\n if value in seq2:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n return bool(set(seq1) & set(seq2))", "matching_cluster_idx": 5}, {"solution": "def overlapping(seq1, seq2):\n return any(i in seq2 for i in seq1)", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n return any(x in seq2 for x in seq1)", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n return bool(set(seq1) & set(seq2))", "matching_cluster_idx": 5}, {"solution": "def overlapping(seq1, seq2):\n return any(i in seq2 for i in seq1)", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n return bool(set(seq1) & set(seq2))", "matching_cluster_idx": 5}, {"solution": "def overlapping(seq1, seq2):\n for i in seq1:\n if i in seq2:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n return any(i in seq2 for i in seq1)", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Function to check whether any value in a sequence exists in another sequence.\n\n Parameters:\n seq1 (list): first sequence of numbers.\n seq2 (list): second sequence of numbers.\n\n Returns:\n bool: True if any value exists in both sequences, else False.\n \"\"\"\n # Convert sequences to sets for efficient lookup\n set1 = set(seq1)\n set2 = set(seq2)\n\n # Check if intersection is not empty\n return len(set1 & set2) > 0", "matching_cluster_idx": 5}]}, "Mbpp/421": {"dps": 78.10699588477367, "dps_norm": 86.42857142857142, "pass@1": 99.0, "profiled": [{"solution": "def concatenate_tuple(tup, delimiter='-'):\n \"\"\"\n Concatenates each element of a tuple by the delimiter.\n \"\"\"\n return delimiter.join(str(i) for i in tup)", "matching_cluster_idx": 5}, {"solution": "def concatenate_tuple(tup, delimiter='-'):\n \"\"\"\n Concatenate each element of tuple by the delimiter.\n \"\"\"\n return delimiter.join(map(str, tup))", "matching_cluster_idx": 5}, {"solution": "def concatenate_tuple(input_tuple, delimiter='-'):\n return delimiter.join(map(str, input_tuple))", "matching_cluster_idx": 6}, {"solution": "def concatenate_tuple(t, delimiter='-'):\n return delimiter.join(str(i) for i in t)", "matching_cluster_idx": 5}, {"solution": "def concatenate_tuple(tup, delimiter='-'):\n return delimiter.join(str(i) for i in tup)", "matching_cluster_idx": 5}, {"solution": "def concatenate_tuple(tup, delimiter='-'):\n return delimiter.join(str(i) for i in tup)", "matching_cluster_idx": 5}, {"solution": "def concatenate_tuple(tuple_input, delimiter='-'):\n return delimiter.join(str(i) for i in tuple_input)", "matching_cluster_idx": 5}, {"solution": "def concatenate_tuple(tup, delimiter=\"-\"):\n return delimiter.join(str(i) for i in tup)", "matching_cluster_idx": 5}, {"solution": "def concatenate_tuple(t, delimiter='-'):\n return delimiter.join(map(str, t))", "matching_cluster_idx": 5}, {"solution": "def concatenate_tuple(tup, delimiter=\"-\"):\n # convert each element of the tuple to string and join them with the given delimiter\n return delimiter.join(map(str, tup))", "matching_cluster_idx": 5}, {"solution": "def concatenate_tuple(input_tuple, delimiter='-'):\n return delimiter.join(str(i) for i in input_tuple)", "matching_cluster_idx": 5}, {"solution": "def concatenate_tuple(input_tuple, delimiter='-'):\n \"\"\"\n Function to concatenate each element of a tuple by the given delimiter.\n \"\"\"\n # Convert each element of the tuple to string and join them using delimiter\n return delimiter.join(map(str, input_tuple))", "matching_cluster_idx": 5}, {"solution": "def concatenate_tuple(input_tuple, delimiter='-'):\n \"\"\"\n A function to concatenate each element of a tuple by the delimiter.\n The function converts every element of the input tuple to string before concatenation.\n \"\"\"\n return delimiter.join(map(str, input_tuple))", "matching_cluster_idx": 5}, {"solution": "def concatenate_tuple(input_tuple, delimiter=\"-\"):\n # convert each element to string and join them using delimiter\n return delimiter.join(str(i) for i in input_tuple)", "matching_cluster_idx": 5}, {"solution": "def concatenate_tuple(tup, delimiter='-'):\n \"\"\"\n This function takes a tuple and a delimiter as arguments and returns\n a string by concatenating each element of the tuple by the delimiter.\n \"\"\"\n return delimiter.join(str(i) for i in tup)", "matching_cluster_idx": 5}, {"solution": "def concatenate_tuple(input_tuple, delimiter='-'):\n return delimiter.join(map(str, input_tuple))", "matching_cluster_idx": 5}, {"solution": "def concatenate_tuple(t):\n return '-'.join(str(i) for i in t)", "matching_cluster_idx": 5}, {"solution": "def concatenate_tuple(t):\n \"\"\"\n Function to concatenate each element of tuple by the delimiter '-'.\n\n Args:\n t (tuple): A tuple of elements.\n\n Returns:\n str: The concatenated string.\n \"\"\"\n return '-'.join(map(str, t))", "matching_cluster_idx": 5}, {"solution": "def concatenate_tuple(tup, delimiter='-'):\n return delimiter.join(map(str, tup))", "matching_cluster_idx": 5}, {"solution": "def concatenate_tuple(input_tuple, delimiter=\"-\"):\n return delimiter.join(map(str, input_tuple))", "matching_cluster_idx": 5}]}, "Mbpp/424": {"dps": 51.624548736462096, "dps_norm": 80.0, "pass@1": 100.0, "profiled": [{"solution": "def extract_rear(tuple_of_strings):\n return [string[-1] for string in tuple_of_strings]", "matching_cluster_idx": 3}, {"solution": "def extract_rear(tupl):\n return [s[-1] for s in tupl]", "matching_cluster_idx": 3}, {"solution": "def extract_rear(tupl):\n \"\"\"\n This function extracts only the rear index element of each string in the given tuple.\n Args:\n tupl: A tuple of strings\n Returns:\n A list of the last characters in the input tuple's strings.\n \"\"\"\n return [string[-1] for string in tupl]", "matching_cluster_idx": 3}, {"solution": "def extract_rear(tup):\n return [s[-1] for s in tup]", "matching_cluster_idx": 3}, {"solution": "def extract_rear(tuple_of_strings):\n return [s[-1] for s in tuple_of_strings]", "matching_cluster_idx": 3}, {"solution": "def extract_rear(tuple_input):\n return [string[-1] for string in tuple_input]", "matching_cluster_idx": 3}, {"solution": "def extract_rear(tuple_str):\n return [str[-1] for str in tuple_str]", "matching_cluster_idx": 3}, {"solution": "def extract_rear(words):\n rear_elements = [word[-1] for word in words]\n return rear_elements", "matching_cluster_idx": 3}, {"solution": "def extract_rear(tupl):\n return [s[-1] for s in tupl]", "matching_cluster_idx": 3}, {"solution": "def extract_rear(tuple_str):\n return [s[-1] for s in tuple_str]", "matching_cluster_idx": 3}, {"solution": "def extract_rear(tup):\n return [s[-1] for s in tup]", "matching_cluster_idx": 3}, {"solution": "def extract_rear(input_tuple):\n return [item[-1] for item in input_tuple]", "matching_cluster_idx": 3}, {"solution": "def extract_rear(input_tuple):\n result = [string[-1] for string in input_tuple]\n return result", "matching_cluster_idx": 3}, {"solution": "def extract_rear(tupl):\n return [s[-1] for s in tupl]", "matching_cluster_idx": 3}, {"solution": "def extract_rear(tuple_of_strings):\n \"\"\"\n This function extracts the last character of each string in a given tuple.\n\n Parameters:\n tuple_of_strings (tuple): A tuple of strings.\n\n Returns:\n list: A list containing the last character of each string in the given tuple.\n \"\"\"\n return [s[-1] for s in tuple_of_strings]", "matching_cluster_idx": 3}, {"solution": "def extract_rear(tuples):\n # Initialize an empty list to hold the extracted characters\n extracted = []\n\n # Iterate over each string in the tuple\n for word in tuples:\n # Add the last character of the current string to the list\n extracted.append(word[-1])\n\n # Return the list of extracted characters\n return extracted", "matching_cluster_idx": 3}, {"solution": "def extract_rear(strings):\n return [string[-1] for string in strings]", "matching_cluster_idx": 3}, {"solution": "def extract_rear(tuple_of_strings):\n return [string[-1] for string in tuple_of_strings]", "matching_cluster_idx": 3}, {"solution": "def extract_rear(words):\n return [word[-1] for word in words]", "matching_cluster_idx": 3}, {"solution": "def extract_rear(input_tuple):\n return [s[-1] for s in input_tuple]", "matching_cluster_idx": 3}]}, "Mbpp/425": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def count_element_in_list(lst, elem):\n return sum(elem in sublist for sublist in lst)", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, element):\n \"\"\"\n This function counts the number of sublists containing a particular element.\n \"\"\"\n count = 0\n for sublist in lst:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, elem):\n count = 0\n for sublist in lst:\n if elem in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, elem):\n \"\"\"\n This function counts the number of sublists containing a particular element.\n\n Parameters:\n lst (list): the list of sublists\n elem (any): the element to search for\n\n Returns:\n int: the number of sublists containing the element\n \"\"\"\n count = 0\n for sublist in lst:\n if elem in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, element):\n \"\"\"\n This function counts the number of sublists containing a particular element.\n \"\"\"\n return sum(element in sublist for sublist in lst)", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, element):\n count = 0\n for sublist in lst:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, element):\n count = 0\n for sublist in lst:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, elem):\n \"\"\"\n Function to count the number of sublists containing a particular element.\n \"\"\"\n count = 0\n for sublist in lst:\n if elem in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, elem):\n count = 0\n for sublist in lst:\n if elem in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(input_list, element):\n count = 0\n for sublist in input_list:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, elem):\n count = 0\n for sublist in lst:\n if elem in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, elem):\n \"\"\"\n Function to count the number of sublists containing a particular element.\n \"\"\"\n count = 0\n for sublist in lst:\n if elem in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(list_of_lists, element):\n \"\"\"\n Function to count the number of sublists containing a particular element.\n \"\"\"\n return sum([element in sublist for sublist in list_of_lists])", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, element):\n count = 0\n for sublist in lst:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, element):\n return sum(element in sublist for sublist in lst)", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, element):\n \"\"\"\n Count the number of sublists containing a particular element in a list\n \"\"\"\n # Initialize count\n count = 0\n\n # Loop through each sublist\n for sublist in lst:\n # If element is in sublist, increment count\n if element in sublist:\n count += 1\n\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(list_of_lists, element):\n count = 0\n for sublist in list_of_lists:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, target):\n \"\"\"\n Count the number of sublists that contain a particular element.\n\n :param lst: A list of lists of integers\n :param target: An integer\n :return: The number of sublists containing the target integer\n \"\"\"\n return sum(1 for sublist in lst if target in sublist)", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, elem):\n count = 0\n for sublist in lst:\n if elem in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, element):\n \"\"\"\n This function counts the number of sublists containing a particular element.\n \"\"\"\n count = 0\n for sublist in lst:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}]}, "Mbpp/428": {"dps": 81.36363636363636, "dps_norm": 55.0, "pass@1": 93.0, "profiled": [{"solution": "def shell_sort(array):\n gap = len(array) // 2\n while gap > 0:\n for i in range(gap, len(array)):\n temp = array[i]\n j = i\n while j >= gap and array[j - gap] > temp:\n array[j] = array[j - gap]\n j -= gap\n array[j] = temp\n gap //= 2\n return array", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2\n\n # start with a big gap, then reduce the gap\n while gap > 0:\n # do a gapped insertion sort for this gap size.\n # the first gap elements a[0..gap-1] are already in gapped order\n # keep adding one more element until the entire array is gap sorted\n for i in range(gap, n):\n temp = arr[i]\n # shift earlier gap-sorted elements up until the correct location for arr[i] is found\n j = i\n while j >= gap and arr[j-gap] >temp:\n arr[j] = arr[j-gap]\n j -= gap\n # put temp (the original arr[i]) in its correct location\n arr[j] = temp\n gap = gap // 2\n\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n gap = len(arr) // 2\n while gap > 0:\n for i in range(gap, len(arr)):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n gap = len(arr) // 2\n while gap > 0:\n for i in range(gap, len(arr)):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n return arr", "matching_cluster_idx": 3}, {"solution": "def shell_sort(arr):\n gap = len(arr) // 2\n\n while gap > 0:\n for i in range(gap, len(arr)):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2\n\n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n gap = len(arr) // 2\n while gap > 0:\n for i in range(gap, len(arr)):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n gap = len(arr) // 2\n while gap > 0:\n for i in range(gap, len(arr)):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2\n # Do a gapped insertion sort for each gap size.\n # The last gap is always 1, so this will sort the array.\n while gap > 0:\n # Start comparing elements at gap indices\n for i in range(gap, n):\n temp = arr[i]\n # Shift earlier gap-sorted elements up until the correct location for arr[i] is found\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n # Put temp (the original arr[i]) in its correct location\n arr[j] = temp\n gap //= 2\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n # Start with a big gap, then reduce the gap\n gap = len(arr) // 2\n\n # Do a gapped insertion sort for each gap size.\n # last gap is always 1\n while gap > 0:\n\n # This is an insertion sort\n for i in range(gap, len(arr)):\n temp = arr[i]\n\n # Shift earlier gap-sorted elements up until the correct location for temp is found\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n\n # Put temp (the original arr[i]) in its correct location\n arr[j] = temp\n gap //= 2\n\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(array):\n gap = len(array) // 2\n # start with a big gap, then reduce the gap\n while gap > 0:\n # do a gapped insertion sort for this gap size.\n # the first gap elements a[0..gap-1] are already in gapped order\n # keep adding one more element until the entire array is gap sorted\n for i in range(gap, len(array)):\n temp = array[i]\n # shift earlier gap-sorted elements up until the correct location for array[i] is found\n j = i\n while j >= gap and array[j - gap] > temp:\n array[j] = array[j - gap]\n j -= gap\n # put temp (the original array[i]) in its correct location\n array[j] = temp\n # reduce gap size for next pass\n gap //= 2\n return array", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n gap = len(arr) // 2\n # Start with a big gap, then reduce the gap\n while gap > 0:\n # Do a gapped insertion sort for this gap size.\n # The first gap elements a[0..gap-1] are already in gapped order\n # keep adding one more element until the entire array is gap sorted\n for i in range(gap, len(arr)):\n temp = arr[i]\n # Shift earlier gap-sorted elements up until the correct location for `arr[i]` is found\n j = i\n while j >= gap and arr[j - gap] >temp:\n arr[j] = arr[j - gap]\n j -= gap\n # Place `temp` (the original `arr[i]`) in its correct location\n arr[j] = temp\n gap //= 2\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n gap = len(arr) // 2\n while gap > 0:\n for i in range(gap, len(arr)):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n gap = len(arr) // 2\n while gap > 0:\n for i in range(gap, len(arr)):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n # Start with a big gap, then reduce the gap\n n = len(arr)\n gap = n//2\n\n # Do a gapped insertion sort for each gap size.\n # Last gap is always 1, but we can't reach it.\n while gap > 0:\n\n # Do a insertion sort for each gap size\n for i in range(gap, n):\n temp = arr[i]\n\n # Shift earlier gap-sorted elements up until the correct location for temp is found\n j = i\n while j >= gap and arr[j-gap] > temp:\n arr[j] = arr[j-gap]\n j -= gap\n\n # Put temp (the original arr[i]) in its correct location\n arr[j] = temp\n gap //= 2\n\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n gap = len(arr) // 2\n while gap > 0:\n for i in range(gap, len(arr)):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2\n while gap > 0:\n for i in range(gap,n):\n temp = arr[i]\n j = i\n while j >= gap and arr[j-gap] >temp:\n arr[j] = arr[j-gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(array):\n n = len(array)\n gap = n // 2\n\n while gap > 0:\n for i in range(gap, n):\n temp = array[i]\n j = i\n while j >= gap and array[j - gap] > temp:\n array[j] = array[j - gap]\n j -= gap\n array[j] = temp\n gap //= 2\n return array", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n gap = len(arr) // 2\n while gap > 0:\n for i in range(gap, len(arr)):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n # Start with a big gap, then reduce the gap\n gap = len(arr)//2\n\n # Do a gapped insertion sort for each gap size.\n # Last gap is always 1.\n while gap > 0:\n\n # Do a gapped insertion sort for this gap size.\n # The first gap elements are already in gapped order\n # keep adding one more element until the entire array is gap sorted\n for i in range(gap,len(arr)):\n\n # add arr[i] to the elements that have been gap sorted\n # save arr[i] in temp and make a hole at position i\n temp = arr[i]\n\n # shift earlier gap-sorted elements up until the correct location for arr[i] is found\n j = i\n while j >= gap and arr[j-gap] >temp:\n arr[j] = arr[j-gap]\n j -= gap\n\n # put temp (the original arr[i]) in its correct location\n arr[j] = temp\n gap //= 2\n\n return arr", "matching_cluster_idx": 4}]}, "Mbpp/433": {"dps": 66.22340425531915, "dps_norm": 73.0, "pass@1": 93.0, "profiled": [{"solution": "def check_greater(arr, num):\n for i in arr:\n if num <= i:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def check_greater(num_list, num):\n # check if number is greater than any number in the list\n return all(i < num for i in num_list)", "matching_cluster_idx": 2}, {"solution": "def check_greater(array, num):\n for element in array:\n if num <= element:\n return False\n return True", "matching_cluster_idx": 3}, {"solution": "def check_greater(arr, num):\n for el in arr:\n if num <= el:\n return False\n return True", "matching_cluster_idx": 3}, {"solution": "def check_greater(array, num):\n \"\"\"\n Function to check whether the entered number is greater than all elements of the given array.\n\n :param array: list of integers\n :param num: integer\n :return: True if num is greater than all elements in array, False otherwise\n \"\"\"\n return all(i < num for i in array)", "matching_cluster_idx": 2}, {"solution": "def check_greater(numbers, target):\n for number in numbers:\n if target <= number:\n return False\n return True", "matching_cluster_idx": 3}, {"solution": "def check_greater(arr, num):\n \"\"\"\n This function takes an array of integers and a number as input and returns True if the number is\n greater than all elements in the array. Otherwise, it returns False.\n \"\"\"\n return all(i < num for i in arr)", "matching_cluster_idx": 2}, {"solution": "def check_greater(arr, num):\n for i in arr:\n if num <= i:\n return False\n return True", "matching_cluster_idx": 3}, {"solution": "def check_greater(arr, num):\n return all(i < num for i in arr)", "matching_cluster_idx": 2}, {"solution": "def check_greater(array, number):\n for elem in array:\n if number <= elem:\n return False\n return True", "matching_cluster_idx": 3}, {"solution": "def check_greater(arr, num):\n \"\"\"\n This function takes an array of numbers and a single number as input.\n It checks whether the number is greater than all the elements in the array.\n\n :param arr: List of numbers\n :param num: A number\n :return: True if the number is greater than all elements in the array, False otherwise\n \"\"\"\n return all(i < num for i in arr)", "matching_cluster_idx": 2}, {"solution": "def check_greater(arr, num):\n for i in arr:\n if num <= i:\n return False\n return True", "matching_cluster_idx": 3}, {"solution": "def check_greater(arr, num):\n for element in arr:\n if num <= element:\n return False\n return True", "matching_cluster_idx": 3}, {"solution": "def check_greater(array, number):\n \"\"\"\n This function checks if a given number is greater than all the elements in the array.\n \"\"\"\n for i in array:\n if number <= i:\n return False\n return True", "matching_cluster_idx": 3}, {"solution": "def check_greater(arr, num):\n for i in arr:\n if num <= i:\n return False\n return True", "matching_cluster_idx": 3}, {"solution": "def check_greater(nums, num):\n for i in nums:\n if num <= i:\n return False\n return True", "matching_cluster_idx": 3}, {"solution": "def check_greater(arr, num):\n return all(i < num for i in arr)", "matching_cluster_idx": 2}, {"solution": "def check_greater(array, number):\n \"\"\"\n Check whether the number is greater than all elements in the given array.\n\n Parameters:\n array (list): A list of numbers.\n number (int or float): A number to compare.\n\n Returns:\n bool: True if the number is greater than all elements in the array, False otherwise.\n \"\"\"\n return all(num < number for num in array)", "matching_cluster_idx": 2}, {"solution": "def check_greater(arr, num):\n for elem in arr:\n if num <= elem:\n return False\n return True", "matching_cluster_idx": 3}, {"solution": "def check_greater(array, num):\n return all(i < num for i in array)", "matching_cluster_idx": 2}]}, "Mbpp/437": {"dps": null, "dps_norm": null, "pass@1": 1.0, "profiled": []}, "Mbpp/440": {"dps": null, "dps_norm": null, "pass@1": 1.0, "profiled": []}, "Mbpp/446": {"dps": 96.25615763546799, "dps_norm": 62.0, "pass@1": 30.0, "profiled": [{"solution": "def count_Occurrence(tup, lst):\n \"\"\"\n Counts the occurrence of all elements of list in a tuple.\n\n Args:\n tup: A tuple to be searched\n lst: A list of elements to be counted\n\n Returns:\n A count of occurrences of elements in lst in tup\n \"\"\"\n return sum(tup.count(i) for i in lst)", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(input_tuple, input_list):\n # Initialize count to zero\n count = 0\n # Loop over each element in the list\n for element in input_list:\n # Count the occurrence of the element in the tuple and add to the count\n count += input_tuple.count(element)\n # Return the total count\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tup, lst):\n return sum(tup.count(i) for i in lst)", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tup, lst):\n # Convert the tuple to a list\n tup_as_list = list(tup)\n\n # Initialize a counter\n count = 0\n\n # Loop through the elements in the list\n for element in lst:\n # If the element is in the tuple, increment the counter\n if element in tup_as_list:\n count += tup_as_list.count(element)\n\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tupl, lst):\n count = 0\n for elem in lst:\n count += tupl.count(elem)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(input_tuple, input_list):\n count = 0\n for element in input_list:\n count += input_tuple.count(element)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tuple_values, list_values):\n return sum(map(tuple_values.count, list_values))", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tup, lst):\n return sum([tup.count(i) for i in lst])", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tup, lst):\n # Create a dictionary to count the occurrence of elements in the tuple\n count_dict = {}\n for el in tup:\n if el in count_dict:\n count_dict[el] += 1\n else:\n count_dict[el] = 1\n\n # Count the occurrences of elements in the list that are present in the tuple\n count = 0\n for el in lst:\n if el in count_dict:\n count += count_dict[el]\n\n return count", "matching_cluster_idx": 4}, {"solution": "def count_Occurrence(t, lst):\n return sum(t.count(i) for i in lst)", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tup, lst):\n count = 0\n for item in lst:\n count += tup.count(item)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tup, list):\n # Initialize a counter\n count = 0\n\n # Iterate over elements in the list\n for elem in list:\n\n # For each element, count its occurrence in the tuple\n count += tup.count(elem)\n\n # Return the total count\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tuple, list):\n count = 0\n for element in list:\n count += tuple.count(element)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(input_tuple, input_list):\n return sum(input_tuple.count(element) for element in input_list)", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tup, list):\n return sum(tup.count(i) for i in list)", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tup, lst):\n return sum(tup.count(i) for i in lst)", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tup, lst):\n \"\"\"\n Function to count the occurrence of all elements of a list in a tuple.\n \"\"\"\n count = 0\n for elem in lst:\n count += tup.count(elem)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(input_tuple, element_list):\n count = 0\n for i in element_list:\n count += input_tuple.count(i)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tup, lst):\n # Initialize counter to 0\n count = 0\n\n # Iterate over the list\n for element in lst:\n # Count the occurrence of each element in the tuple\n count += tup.count(element)\n\n # Return the total count\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tup, lst):\n \"\"\"\n This function takes a tuple and a list as input.\n It then counts the occurrences of all the elements in the list within the tuple.\n :param tup: tuple of elements\n :param lst: list of elements to count occurrence of in tuple\n :return: integer number of occurrences\n \"\"\"\n count = 0\n for elem in lst:\n count += tup.count(elem)\n return count", "matching_cluster_idx": 2}]}, "Mbpp/451": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 85.0, "profiled": [{"solution": "def remove_whitespaces(string):\n return string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(s):\n return s.replace(' ', '')", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(s):\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string):\n return input_string.replace(' ', '')", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(s):\n return s.replace(' ', '')", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(s):\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(s):\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(string):\n return string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_str):\n return input_str.replace(' ', '')", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(s):\n return s.replace(' ', '')", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string):\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(s):\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_str):\n return input_str.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(s):\n return s.replace(' ', '')", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(string):\n return string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string):\n \"\"\"\n This function takes a string as input and returns the same string but with all whitespaces removed.\n \"\"\"\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string):\n \"\"\"\n Function to remove all whitespaces from the given string\n \"\"\"\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(s: str) -> str:\n \"\"\"\n Removes all whitespaces from the given string.\n Args:\n s: A string to remove whitespaces from.\n Returns:\n A new string without any whitespaces.\n \"\"\"\n return s.replace(' ', '')", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string):\n return input_string.replace(' ', '')", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string):\n return input_string.replace(' ', '')", "matching_cluster_idx": 4}]}, "Mbpp/456": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def reverse_string_list(str_list):\n \"\"\"\n Reverse each string in a given list of string values.\n\n :param str_list: List of string values.\n :return: List of reversed string values.\n \"\"\"\n return [s[::-1] for s in str_list]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n return [string[::-1] for string in string_list]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(input_list):\n return [string[::-1] for string in input_list]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(strings):\n \"\"\"\n Reverse each string in a given list of string values.\n \"\"\"\n return [string[::-1] for string in strings]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n # Empty list to hold reversed strings\n reversed_list = []\n # Iterate over each string in the list\n for string in string_list:\n # Reverse the string and append to the list\n reversed_list.append(string[::-1])\n # Return the list of reversed strings\n return reversed_list", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(strings):\n \"\"\"Function to reverse each string in a given list of string values.\"\"\"\n return [string[::-1] for string in strings]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(strings):\n return [s[::-1] for s in strings]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(strings):\n reversed_strings = [s[::-1] for s in strings]\n return reversed_strings", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(input_list):\n return [string[::-1] for string in input_list]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(lst):\n return [s[::-1] for s in lst]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(input_list):\n reversed_list = []\n for string in input_list:\n reversed_list.append(string[::-1])\n return reversed_list", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(str_list):\n # Reverse each string in the given list\n reversed_list = [s[::-1] for s in str_list]\n return reversed_list", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(str_list):\n return [s[::-1] for s in str_list]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n return [string[::-1] for string in string_list]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(input_list):\n \"\"\"\n This function takes a list of strings as input and returns a new list with each string reversed.\n\n :param input_list: list of strings to reverse\n :return: list of reversed strings\n \"\"\"\n return [s[::-1] for s in input_list]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(strings):\n return [s[::-1] for s in strings]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(str_list):\n return [str[::-1] for str in str_list]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(input_list):\n # Using list comprehension to reverse each string in the list\n reversed_list = [s[::-1] for s in input_list]\n return reversed_list", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(strings):\n return [string[::-1] for string in strings]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(strings):\n return [string[::-1] for string in strings]", "matching_cluster_idx": 4}]}, "Mbpp/460": {"dps": 55.86538461538461, "dps_norm": 83.0, "pass@1": 29.0, "profiled": [{"solution": "def Extract(input_list):\n return [sublist[0] for sublist in input_list]", "matching_cluster_idx": 4}, {"solution": "def Extract(lst):\n return [sub[0] for sub in lst]", "matching_cluster_idx": 3}, {"solution": "def Extract(lst):\n return [sub[0] for sub in lst]", "matching_cluster_idx": 3}, {"solution": "def Extract(lst):\n return [sublist[0] for sublist in lst]", "matching_cluster_idx": 3}, {"solution": "def Extract(lst):\n return [sub[0] for sub in lst]", "matching_cluster_idx": 3}, {"solution": "def Extract(lst):\n # Using list comprehension to get the first element of each sublist\n return [sublist[0] for sublist in lst]", "matching_cluster_idx": 3}, {"solution": "def Extract(lst):\n return [sub[0] for sub in lst]", "matching_cluster_idx": 3}, {"solution": "def Extract(lst):\n return [sublist[0] for sublist in lst]", "matching_cluster_idx": 3}, {"solution": "def Extract(lst):\n # The function takes a list of lists as input and returns a new list\n # containing the first element of each sublist in the input list.\n return [sublist[0] for sublist in lst]", "matching_cluster_idx": 3}, {"solution": "def Extract(lst):\n return [sublist[0] for sublist in lst]", "matching_cluster_idx": 4}, {"solution": "def Extract(lst):\n return [sub[0] for sub in lst]", "matching_cluster_idx": 3}, {"solution": "def Extract(lst):\n return [sub[0] for sub in lst]", "matching_cluster_idx": 3}, {"solution": "def Extract(list_of_lists):\n # Initialize an empty list to store the first element of each sublist\n first_elements = []\n # Iterate through each sublist in the input list\n for sublist in list_of_lists:\n # If the sublist is not empty, append its first element to the output list\n if sublist:\n first_elements.append(sublist[0])\n # Return the list of first elements\n return first_elements", "matching_cluster_idx": 3}, {"solution": "def Extract(lst):\n return [sublist[0] for sublist in lst]", "matching_cluster_idx": 3}, {"solution": "def Extract(input_list):\n return [sublist[0] for sublist in input_list]", "matching_cluster_idx": 3}, {"solution": "def Extract(lst):\n return [sublist[0] for sublist in lst]", "matching_cluster_idx": 3}, {"solution": "def Extract(lst):\n \"\"\"\n Function to get the first element of each sublist.\n \"\"\"\n return [sublist[0] for sublist in lst]", "matching_cluster_idx": 3}, {"solution": "def Extract(lst):\n return [sub[0] for sub in lst]", "matching_cluster_idx": 3}, {"solution": "def Extract(lst):\n # Use list comprehension to get the first element of each sublist\n return [sub[0] for sub in lst]", "matching_cluster_idx": 3}, {"solution": "def Extract(lst):\n return [i[0] for i in lst]", "matching_cluster_idx": 4}]}, "Mbpp/474": {"dps": 96.73170731707317, "dps_norm": 97.14285714285714, "pass@1": 100.0, "profiled": [{"solution": "def replace_char(string, old_char, new_char):\n return string.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, old, new):\n return s.replace(old, new)", "matching_cluster_idx": 6}, {"solution": "def replace_char(input_str, old_char, new_char):\n \"\"\"\n This function replaces all occurrences of old_char in input_str with new_char.\n Args:\n input_str (str): the string in which characters need to be replaced.\n old_char (str): the character to be replaced.\n new_char (str): the character to replace with.\n Returns:\n str: a new string with replaced characters.\n \"\"\"\n return input_str.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, old_char, new_char):\n return s.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(input_string, old_char, new_char):\n return input_string.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(input_string, char_to_replace, new_char):\n return input_string.replace(char_to_replace, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, old_char, new_char):\n \"\"\"\n This function replaces old_char with new_char in the given string s.\n Args:\n s (str): the string to perform replacement on\n old_char (str): the character to replace\n new_char (str): the character to replace with\n\n Returns:\n str: the string with old_char replaced by new_char\n \"\"\"\n return s.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(string, old_char, new_char):\n return string.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(input_str: str, old_char: str, new_char: str) -> str:\n \"\"\"\n This function takes a string and two characters as input. It replaces all instances of the second character in the string with the third character and returns the updated string.\n \"\"\"\n return input_str.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(input_str, old_char, new_char):\n return input_str.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, old_char, new_char):\n # Create a new string with the replaced character\n new_s = \"\"\n for char in s:\n if char == old_char:\n new_s += new_char\n else:\n new_s += char\n return new_s", "matching_cluster_idx": 2}, {"solution": "def replace_char(str, char_to_replace, replacement_char):\n return str.replace(char_to_replace, replacement_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(input_str: str, old_char: str, new_char: str) -> str:\n return input_str.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(string, old_char, new_char):\n return string.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, old_char, new_char):\n return s.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, old_char, new_char):\n return s.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, old_char, new_char):\n \"\"\"\n Replace all occurrences of old_char with new_char in the string s.\n :param s: input string\n :param old_char: character to be replaced\n :param new_char: character to replace with\n :return: string with replaced characters\n \"\"\"\n return s.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(input_string, char_to_replace, replacement_char):\n \"\"\"\n This function replaces all occurrences of a specified character with another specified character in the input string.\n\n Parameters:\n input_string (str): the string in which to make replacements\n char_to_replace (str): the character to be replaced\n replacement_char (str): the character that will replace char_to_replace\n\n Returns:\n str: the modified string\n \"\"\"\n return input_string.replace(char_to_replace, replacement_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, old, new):\n return s.replace(old, new)", "matching_cluster_idx": 6}, {"solution": "def replace_char(input_str: str, old_char: str, new_char: str) -> str:\n return input_str.replace(old_char, new_char)", "matching_cluster_idx": 6}]}, "Mbpp/476": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def big_sum(arr):\n if len(arr) == 0:\n return None\n else:\n return max(arr) + min(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n \"\"\"\n This function takes a list of numbers as input, finds the maximum and minimum values in the list,\n and returns their sum.\n \"\"\"\n # find the maximum and minimum values in the array\n max_val = max(arr)\n min_val = min(arr)\n # return the sum of the maximum and minimum values\n return max_val + min_val", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n return max(arr) + min(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n return max(arr) + min(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n if not arr:\n raise ValueError('The array must not be empty')\n return max(arr) + min(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n return max(arr) + min(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n return max(arr) + min(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n if not arr:\n raise ValueError('Empty array is not supported')\n return max(arr) + min(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n \"\"\"\n Function to find the sum of the largest and smallest value in a given array.\n \"\"\"\n return max(arr) + min(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(array):\n if len(array) == 0:\n return None\n return max(array) + min(array)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n return max(arr) + min(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n \"\"\"\n Function to find the sum of the largest and smallest value in a given array.\n\n Args:\n arr (list of int or float): the input array\n\n Returns:\n int or float: the sum of the largest and smallest value in the array\n \"\"\"\n if len(arr) == 0:\n return None\n return max(arr) + min(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(numbers):\n return max(numbers) + min(numbers)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n if not arr:\n return \"Array is empty\"\n return max(arr) + min(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n return max(arr) + min(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n \"\"\"\n Function to find the sum of the largest and smallest value in a given array.\n \"\"\"\n # Check if the array is not empty\n if len(arr) == 0:\n return None\n else:\n # Find and return the sum of the largest and smallest values\n return max(arr) + min(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n # Find the smallest value in the array\n smallest = min(arr)\n # Find the largest value in the array\n largest = max(arr)\n # Return the sum of the smallest and largest values\n return smallest + largest", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n if not arr:\n raise ValueError(\"Array must not be empty.\")\n return max(arr) + min(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n return max(arr) + min(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n \"\"\"\n Given a list of numbers, return the sum of the largest and smallest numbers in the list.\n \"\"\"\n if not arr:\n return 0\n return max(arr) + min(arr)", "matching_cluster_idx": 5}]}, "Mbpp/477": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 96.0, "profiled": [{"solution": "def is_lower(input_str):\n \"\"\"\n Converts the given string to lower case.\n\n Parameters:\n input_str (str): The string to be converted to lower case.\n\n Returns:\n str: The input string converted to lower case.\n \"\"\"\n\n return input_str.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(input_string: str) -> str:\n \"\"\"Converts the given string to lower case\"\"\"\n return input_string.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(string):\n \"\"\"\n This function takes a string as input and returns the same string in lower case.\n\n Args:\n string (str): The string to convert to lower case.\n\n Returns:\n str: The input string converted to lower case.\n \"\"\"\n return string.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(input_string: str) -> str:\n \"\"\"\n This function takes a string as input and returns a new string with all characters\n converted to lower case.\n \"\"\"\n return input_string.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n \"\"\"\n Convert a given string to lower case.\n\n Args:\n s (str): The input string to be converted.\n\n Returns:\n str: The lower case version of the input string.\n \"\"\"\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(input_string):\n return input_string.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n \"\"\"\n Converts a given string to lower case.\n :param s: str\n :return: str\n \"\"\"\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n \"\"\"\n Convert the given string to lower case.\n \"\"\"\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(input_string):\n return input_string.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(input_string):\n return input_string.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(input_string):\n return input_string.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n \"\"\"\n This function takes a string as input and returns a string with all uppercase characters converted to lowercase.\n\n Args:\n s (str): The input string\n\n Returns:\n str: The input string with all uppercase characters converted to lowercase\n \"\"\"\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(input_string):\n return input_string.lower()", "matching_cluster_idx": 4}]}, "Mbpp/563": {"dps": 85.98360655737706, "dps_norm": 82.72727272727272, "pass@1": 95.0, "profiled": [{"solution": "def extract_values(s):\n import re\n return re.findall(r'\"([^\"]*)\"', s)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(input_string):\n values = re.findall(r'\"([^\"]*)\"', input_string)\n return values", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(input_string):\n \"\"\"\n This function takes a string as input and extracts the values between quotation marks.\n It returns a list of extracted values.\n \"\"\"\n # The regular expression pattern \"\\\".*?\\\"\" matches any text within double quotation marks\n pattern = r'\\\"(.*?)\\\"'\n values = re.findall(pattern, input_string)\n return values", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(s):\n \"\"\"\n Extract values between quotation marks from a string.\n :param s: string\n :return: list of values\n \"\"\"\n return re.findall(r'\"(.*?)\"', s)", "matching_cluster_idx": 8}, {"solution": "def extract_values(string):\n \"\"\"\n This function extracts values between quotation marks from a string.\n \"\"\"\n values = []\n # Find the first quotation mark\n start = string.find('\"')\n while start != -1:\n # Find the closing quotation mark\n end = string.find('\"', start + 1)\n if end != -1:\n # Extract the value and append it to the values list\n values.append(string[start + 1:end])\n # Continue searching from the position of the closing quotation mark\n start = string.find('\"', end + 1)\n else:\n break\n return values", "matching_cluster_idx": 10}, {"solution": "import re\ndef extract_values(input_string):\n return re.findall('\"([^\"]*)\"', input_string)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(string):\n values = re.findall('\"([^\"]*)\"', string)\n return values", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(s):\n return re.findall('\"([^\"]*)\"', s)", "matching_cluster_idx": 8}, {"solution": "def extract_values(string):\n import re\n return re.findall(r'\"([^\"]*)\"', string)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(s):\n return re.findall('\"([^\"]*)\"', s)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(input_string):\n return re.findall('\"([^\"]*)\"', input_string)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(s):\n return re.findall('\"([^\"]*)\"', s)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(s):\n values = re.findall(r'\"([^\"]*)\"', s)\n return values", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(s):\n return re.findall(r'\"([^\"]*)\"', s)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(input_str):\n return re.findall(r'\"([^\"]*)\"', input_str)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(s):\n return re.findall('\"([^\"]*)\"', s)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(string):\n return re.findall(r'\"([^\"]*)\"', string)", "matching_cluster_idx": 8}, {"solution": "def extract_values(input_str):\n \"\"\"Extract values between quotation marks from a string.\"\"\"\n import re\n return re.findall('\"([^\"]*)\"', input_str)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(input_string):\n return re.findall('\"([^\"]*)\"', input_string)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(string):\n values = re.findall('\"([^\"]*)\"', string)\n return values", "matching_cluster_idx": 8}]}, "Mbpp/572": {"dps": null, "dps_norm": null, "pass@1": 2.0, "profiled": []}, "Mbpp/578": {"dps": 81.57142857142857, "dps_norm": 70.0, "pass@1": 100.0, "profiled": [{"solution": "def interleave_lists(l1, l2, l3):\n # Check if all lists are of the same length\n if len(l1) == len(l2) == len(l3):\n # Initialize an empty result list\n result = []\n # Iterate over elements of the input lists\n for i in range(len(l1)):\n # Append elements of all lists to result list in an interleaved manner\n result.append(l1[i])\n result.append(l2[i])\n result.append(l3[i])\n # Return the result list\n return result\n else:\n # Raise a ValueError if input lists are not of the same length\n raise ValueError('All input lists must be of the same length')", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n return [val for tup in zip(list1, list2, list3) for val in tup]", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(list1, list2, list3):\n # Check if all the lists have the same length\n if len(list1) == len(list2) == len(list3):\n # Using zip_longest function from itertools module to interleave three lists\n return [item for sublist in zip(list1, list2, list3) for item in sublist]\n else:\n raise ValueError('All the input lists must have the same length.')", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(list1, list2, list3):\n return [val for sublist in zip(list1, list2, list3) for val in sublist]", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(list1, list2, list3):\n interleaved_list = []\n for i in range(len(list1)):\n interleaved_list.extend([list1[i], list2[i], list3[i]])\n return interleaved_list", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(lst1, lst2, lst3):\n # Check if the three lists have the same length\n if len(lst1) == len(lst2) == len(lst3):\n # Initialize an empty list to hold the interleaved result\n result = []\n # Iterate over the length of one of the list (all have the same length)\n for i in range(len(lst1)):\n # Append the ith element from each list to the result list\n result.append(lst1[i])\n result.append(lst2[i])\n result.append(lst3[i])\n # Return the interleaved result list\n return result\n else:\n raise ValueError(\"All lists must have the same length\")", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n return [val for tup in zip(list1, list2, list3) for val in tup]", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(list1, list2, list3):\n # Create an empty list to store the interleaved elements\n interleaved_list = []\n # Iterate over the indices of the input lists\n for i in range(len(list1)):\n # Add the i-th element from each list to the interleaved list\n interleaved_list.append(list1[i])\n interleaved_list.append(list2[i])\n interleaved_list.append(list3[i])\n # Return the interleaved list\n return interleaved_list", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"\n Function to interleave 3 lists of the same length into a single flat list.\n \"\"\"\n return [item for sublist in zip(list1, list2, list3) for item in sublist]", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(list1, list2, list3):\n # check if lists are of equal length\n if len(list1) != len(list2) or len(list2) != len(list3):\n raise ValueError(\"All input lists must have the same length\")\n\n # use zip to interleave the lists\n interleaved = [val for sublist in zip(list1, list2, list3) for val in sublist]\n\n return interleaved", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(list1, list2, list3):\n return [val for pair in zip(list1, list2, list3) for val in pair]", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(list1, list2, list3):\n return [val for triple in zip(list1, list2, list3) for val in triple]\nlist1 = [1,2,3,4,5,6,7]\nlist2 = [10,20,30,40,50,60,70]\nlist3 = [100,200,300,400,500,600,700]", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(list1, list2, list3):\n interleaved_list = [None]*(len(list1)+len(list2)+len(list3))\n interleaved_list[::3] = list1\n interleaved_list[1::3] = list2\n interleaved_list[2::3] = list3\n return interleaved_list", "matching_cluster_idx": 9}, {"solution": "def interleave_lists(l1, l2, l3):\n return [val for tup in zip(l1, l2, l3) for val in tup]", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(list1, list2, list3):\n if len(list1) != len(list2) or len(list1) != len(list3):\n raise ValueError(\"All input lists must be of the same length.\")\n\n interleaved_list = []\n for i in range(len(list1)):\n interleaved_list.append(list1[i])\n interleaved_list.append(list2[i])\n interleaved_list.append(list3[i])\n\n return interleaved_list", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"\n Function to interleave 3 lists of the same length into a single flat list.\n\n Args:\n list1 (list): first list\n list2 (list): second list\n list3 (list): third list\n\n Returns:\n list: Interleaved list\n \"\"\"\n # Check if lengths of lists are the same\n if len(list1) == len(list2) == len(list3):\n # Initialize an empty list for the result\n interleaved = []\n # Loop through elements\n for i in range(len(list1)):\n # Append elements in interleaved manner\n interleaved.append(list1[i])\n interleaved.append(list2[i])\n interleaved.append(list3[i])\n return interleaved\n else:\n raise ValueError(\"Lists must be of the same length.\")", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(lst1, lst2, lst3):\n if len(lst1) != len(lst2) or len(lst1) != len(lst3):\n raise ValueError(\"All lists must be of the same length.\")\n return [val for pair in zip(lst1, lst2, lst3) for val in pair]", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(list1, list2, list3):\n if len(list1) == len(list2) == len(list3):\n return [value for sublist in zip(list1, list2, list3) for value in sublist]\n else:\n raise ValueError(\"All lists must have the same length.\")", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(list1, list2, list3):\n interleaved_list = []\n for i in range(len(list1)):\n interleaved_list.append(list1[i])\n interleaved_list.append(list2[i])\n interleaved_list.append(list3[i])\n return interleaved_list", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n # Check if lists have the same length\n if len(list1) != len(list2) or len(list1) != len(list3):\n return \"Error: The lists are not of the same length.\"\n # Initialize an empty list to hold the result\n result = []\n # Iterate over the indices of the lists\n for i in range(len(list1)):\n # Append elements from each list to the result list in order\n result.extend([list1[i], list2[i], list3[i]])\n return result", "matching_cluster_idx": 6}]}, "Mbpp/586": {"dps": 98.83040935672514, "dps_norm": 87.5, "pass@1": 44.0, "profiled": [{"solution": "def split_Arr(input_list, n):\n # Check if n is greater than the length of the list\n if n > len(input_list):\n return \"Error: n is greater than the length of the list.\"\n else:\n # Split the list at nth element and add the first part to the end\n return input_list[n:] + input_list[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n first_part = arr[n:]\n second_part = arr[:n]\n return first_part + second_part", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n # Split the array into two parts\n first_part = arr[:n]\n second_part = arr[n:]\n\n # Add the first part to the end of the second part\n result = second_part + first_part\n\n return result", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"\n This function takes a list and an integer n as inputs.\n It splits the list at the nth element and adds the first part to the end.\n \"\"\"\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n # Splitting the list\n first_part = arr[:n]\n second_part = arr[n:]\n # Adding the first part to the end\n result = second_part + first_part\n return result", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n # Slice the array at the nth element\n first_part = arr[:n]\n second_part = arr[n:]\n\n # Add the first part to the end\n result = second_part + first_part\n\n return result", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n # Split the list into first part and second part\n first_part = arr[n:]\n second_part = arr[:n]\n\n # Add the first part to the end of the list\n result = first_part + second_part\n return result", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n # split the list into first part and second part\n first_part = arr[:n]\n second_part = arr[n:]\n # add first part to the end of second part\n result = second_part + first_part\n return result", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(input_arr, n):\n # Split the input list at the nth element\n first_part = input_arr[n:]\n second_part = input_arr[:n]\n # Add the first part to the end\n result = first_part + second_part\n return result", "matching_cluster_idx": 6}, {"solution": "def split_Arr(input_list, n):\n # Check if n is out of range\n if n < 0 or n > len(input_list):\n raise ValueError(\"n is out of range\")\n # Split the list and add the first part to the end\n return input_list[n:] + input_list[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n first_part = arr[:n]\n second_part = arr[n:]\n second_part.extend(first_part)\n return second_part", "matching_cluster_idx": 6}, {"solution": "def split_Arr(input_list, n):\n return input_list[n:] + input_list[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n first_part = arr[:n]\n second_part = arr[n:]\n second_part.extend(first_part)\n return second_part", "matching_cluster_idx": 6}]}, "Mbpp/587": {"dps": 47.2972972972973, "dps_norm": 85.0, "pass@1": 37.0, "profiled": [{"solution": "def list_tuple(input_list):\n return tuple(input_list)", "matching_cluster_idx": 2}, {"solution": "def list_tuple(input_list):\n \"\"\"\n Function to convert a list to a tuple.\n \"\"\"\n return tuple(input_list)", "matching_cluster_idx": 2}, {"solution": "def list_tuple(input_list):\n return tuple(input_list)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(list):\n return tuple(list)", "matching_cluster_idx": 2}, {"solution": "def list_tuple(input_list):\n return tuple(input_list)", "matching_cluster_idx": 2}, {"solution": "def list_tuple(lst):\n \"\"\"\n This function takes a list as input and returns a tuple that contains the same elements\n \"\"\"\n return tuple(lst)", "matching_cluster_idx": 2}, {"solution": "def list_tuple(lst):\n return tuple(lst)", "matching_cluster_idx": 2}, {"solution": "def list_tuple(input_list):\n return tuple(input_list)", "matching_cluster_idx": 2}, {"solution": "def list_tuple(lst):\n return tuple(lst)", "matching_cluster_idx": 2}, {"solution": "def list_tuple(input_list):\n return tuple(input_list)", "matching_cluster_idx": 2}, {"solution": "def list_tuple(lst):\n \"\"\"\n A function that takes a list as input and converts it into a tuple.\n :param lst: Input list.\n :return: A tuple converted from the input list.\n \"\"\"\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n return tuple(lst)", "matching_cluster_idx": 2}, {"solution": "def list_tuple(lst):\n return tuple(lst)", "matching_cluster_idx": 2}, {"solution": "def list_tuple(input_list):\n \"\"\"\n A function that takes a list as input and returns a tuple.\n \"\"\"\n return tuple(input_list)", "matching_cluster_idx": 2}]}, "Mbpp/588": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def big_diff(lst):\n \"\"\"\n Function to find the difference between the largest and smallest value in a given list.\n :param lst: a list of numerical values\n :return: the difference between the largest and smallest value in the list\n \"\"\"\n return max(lst) - min(lst)", "matching_cluster_idx": 5}, {"solution": "def big_diff(lst):\n return max(lst) - min(lst)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n \"\"\"\n Find the difference between the largest and smallest value in a given list.\n\n Arguments:\n nums: A list of integers.\n\n Returns:\n An integer which is the difference between the maximum and minimum value in the list.\n \"\"\"\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(lst):\n return max(lst) - min(lst)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n \"\"\"\n Calculates the difference between the largest and smallest number in a given list.\n\n Parameters:\n nums (list of int): The list of numbers.\n\n Returns:\n int: The difference between the largest and smallest number.\n \"\"\"\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(lst):\n # Check if the list is not empty\n if len(lst) > 0:\n # Return the difference between the maximum and minimum values in the list\n return max(lst) - min(lst)\n else:\n # Return None if the list is empty\n return None", "matching_cluster_idx": 5}, {"solution": "def big_diff(lst):\n \"\"\"\n This function calculates the difference between the largest and smallest value in a given list.\n\n :param lst: a list of numbers\n :return: the difference between the largest and smallest value in the list\n \"\"\"\n if not lst:\n raise ValueError(\"Input list is empty\")\n return max(lst) - min(lst)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n # Check if the list is empty, return 0 in such a case\n if len(nums) == 0:\n return 0\n else:\n # Calculate the difference between the maximum and minimum values in the list\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(numbers):\n if not numbers:\n return None\n else:\n return max(numbers) - min(numbers)", "matching_cluster_idx": 5}, {"solution": "def big_diff(lst):\n return max(lst) - min(lst)", "matching_cluster_idx": 5}, {"solution": "def big_diff(lst):\n return max(lst) - min(lst)", "matching_cluster_idx": 5}, {"solution": "def big_diff(numbers):\n \"\"\"\n This function takes a list of numbers as input and returns the difference\n between the largest and smallest number in the list.\n \"\"\"\n return max(numbers) - min(numbers)", "matching_cluster_idx": 5}, {"solution": "def big_diff(lst):\n return max(lst) - min(lst)", "matching_cluster_idx": 5}, {"solution": "def big_diff(num_list):\n \"\"\"\n Function to find the difference between the largest and smallest value in a given list.\n \"\"\"\n return max(num_list) - min(num_list)", "matching_cluster_idx": 5}, {"solution": "def big_diff(lst):\n # Function to find the difference between largest and smallest value in a given list\n if not lst:\n return None\n return max(lst) - min(lst)", "matching_cluster_idx": 5}, {"solution": "def big_diff(num_list):\n if len(num_list) > 0:\n return max(num_list) - min(num_list)\n else:\n return None", "matching_cluster_idx": 5}, {"solution": "def big_diff(lst):\n return max(lst) - min(lst)", "matching_cluster_idx": 5}, {"solution": "def big_diff(lst):\n return max(lst) - min(lst)", "matching_cluster_idx": 5}, {"solution": "def big_diff(lst):\n \"\"\"Calculate the difference between the largest and smallest values in a given list.\"\"\"\n if not lst:\n raise ValueError(\"The input list is empty.\")\n return max(lst) - min(lst)", "matching_cluster_idx": 5}, {"solution": "def big_diff(lst):\n return max(lst) - min(lst)", "matching_cluster_idx": 5}]}, "Mbpp/592": {"dps": 75.93333333333334, "dps_norm": 57.5, "pass@1": 37.0, "profiled": [{"solution": "from math import comb\ndef sum_Of_product(n):\n # calculate the sum of the product of consecutive binomial coefficients\n return sum(comb(n, k) * comb(n, k + 1) for k in range(n))", "matching_cluster_idx": 5}, {"solution": "import math\ndef sum_Of_product(n):\n total = 0\n for r in range(n):\n total += math.comb(n, r) * math.comb(n, r + 1)\n return total", "matching_cluster_idx": 5}, {"solution": "def factorial(n):\n result = 1\n for i in range(2, n + 1):\n result *= i\n return result\ndef sum_Of_product(n):\n sum_product = 0\n for r in range(n):\n term = factorial(n) // (factorial(r) * factorial(n - r))\n next_term = factorial(n) // (factorial(r + 1) * factorial(n - r - 1))\n sum_product += term * next_term\n return sum_product", "matching_cluster_idx": -1}, {"solution": "def sum_Of_product(n):\n # creating a list of binomial coefficients\n binomial_coeff = [1]\n for k in range(1, n+1):\n next_coeff = binomial_coeff[k-1] * (n - k + 1) // k\n binomial_coeff.append(next_coeff)\n # calculating the sum of the product of consecutive binomial coefficients\n sum_of_prod = sum(binomial_coeff[i]*binomial_coeff[i+1] for i in range(n))\n return sum_of_prod", "matching_cluster_idx": 8}, {"solution": "from math import comb\ndef sum_Of_product(n):\n return sum(comb(n, i)*comb(n, i+1) for i in range(n))", "matching_cluster_idx": 5}, {"solution": "def sum_Of_product(n):\n # Calculate binomial coefficients\n binomial_coeffs = [1]\n for i in range(n):\n binomial_coeffs = [1] + [binomial_coeffs[j-1] + binomial_coeffs[j] for j in range(1, len(binomial_coeffs))] + [1]\n # Calculate sum of the product of consecutive binomial coefficients\n sum_product = sum(binomial_coeffs[i] * binomial_coeffs[i+1] for i in range(len(binomial_coeffs) - 1))\n return sum_product", "matching_cluster_idx": 7}, {"solution": "import math\ndef sum_Of_product(n):\n # Initialize sum variable\n sum_val = 0\n\n # Loop through the range of numbers up to n\n for i in range(n):\n # Calculate the product of consecutive binomial coefficients\n product = math.comb(n, i) * math.comb(n, i + 1)\n\n # Add the product to sum_val\n sum_val += product\n\n return sum_val", "matching_cluster_idx": 5}, {"solution": "import math\ndef sum_Of_product(n):\n # calculating sum of product of consecutive binomial coefficients\n sum = 0\n for i in range(n):\n sum += math.comb(n, i) * math.comb(n, i + 1)\n return sum", "matching_cluster_idx": 5}, {"solution": "def sum_Of_product(n):\n def binomial_coeff(n, k):\n # Function to calculate binomial coefficient\n res = 1\n if (k > n - k):\n k = n - k\n for i in range(0 , k):\n res = res * (n - i)\n res = res // (i + 1)\n return res\n # Calculate sum of products\n sum_prod = 0\n for k in range(1, n + 1):\n sum_prod += binomial_coeff(n, k) * binomial_coeff(n, k - 1)\n return sum_prod", "matching_cluster_idx": 4}, {"solution": "def sum_Of_product(n):\n # function to calculate binomial coefficient\n def binomial_coeff(n, k):\n res = 1\n if (k > n - k):\n k = n - k\n for i in range(0, k):\n res = res * (n - i)\n res = res // (i + 1)\n return res\n\n # function to calculate sum of product of consecutive binomial co-efficients\n def sum_product_coeff(n):\n sum = 0\n for k in range(n):\n sum += binomial_coeff(n, k) * binomial_coeff(n, k + 1)\n return sum\n\n return sum_product_coeff(n)", "matching_cluster_idx": 4}, {"solution": "def binomial_coef(n, k):\n \"\"\"Calculate binomial coefficient\"\"\"\n if k > n - k:\n k = n - k\n x = 1\n for i in range(k):\n x = x * (n - i)\n x = x // (i + 1)\n return x\ndef sum_Of_product(n):\n \"\"\"Calculate sum of the product of consecutive binomial coefficients\"\"\"\n return sum(binomial_coef(n, k) * binomial_coef(n, k + 1) for k in range(n))", "matching_cluster_idx": 4}, {"solution": "def sum_Of_product(n):\n coef = [1]\n for i in range(n):\n coef = [1] + [coef[j] + coef[j+1] for j in range(len(coef)-1)] + [1]\n return sum(coef[i]*coef[i+1] for i in range(n))", "matching_cluster_idx": 7}, {"solution": "import math\ndef sum_Of_product(n):\n # Initialize sum\n sum_result = 0\n\n # Calculate sum of products\n for k in range(n):\n sum_result += math.comb(n, k) * math.comb(n, k + 1)\n\n return sum_result", "matching_cluster_idx": 5}, {"solution": "from math import comb\ndef sum_Of_product(n):\n \"\"\"\n This function computes the sum of the product of consecutive binomial coefficients.\n\n :param n: int\n :return: int\n \"\"\"\n return sum(comb(n, i) * comb(n, i + 1) for i in range(n))", "matching_cluster_idx": 5}, {"solution": "import math\ndef sum_Of_product(n):\n return sum(math.comb(n, i) * math.comb(n, i - 1) for i in range(1, n + 1))", "matching_cluster_idx": 5}, {"solution": "def sum_Of_product(n):\n \"\"\"Finds the sum of the product of consecutive binomial coefficients.\"\"\"\n # Calculate binomial coefficients\n C = [1]\n for i in range(1, n+1):\n temp = [1]\n for j in range(1, i):\n temp.append(C[j-1] + C[j])\n temp.append(1)\n C = temp\n\n # Calculate sum of products\n total = 0\n for i in range(1, n+1):\n total += C[i-1] * C[i]\n\n return total", "matching_cluster_idx": 6}, {"solution": "from math import comb\ndef sum_Of_product(n):\n total = 0\n for k in range(n+1):\n total += comb(n, k) * comb(n, k+1)\n return total", "matching_cluster_idx": 5}, {"solution": "import math\ndef sum_Of_product(n):\n return sum(math.comb(n, i) * math.comb(n, i+1) for i in range(n))", "matching_cluster_idx": 5}, {"solution": "from math import factorial\ndef binomial_coefficient(n, k):\n \"\"\"\n Calculate binomial coefficient using factorials\n \"\"\"\n return factorial(n) // (factorial(k) * factorial(n - k))\ndef sum_Of_product(n):\n \"\"\"\n Calculate the sum of the product of consecutive binomial coefficients\n \"\"\"\n return sum(binomial_coefficient(n, k) * binomial_coefficient(n, k+1) for k in range(n))", "matching_cluster_idx": 1}, {"solution": "import math\ndef sum_Of_product(n):\n return sum(math.comb(n, i) * math.comb(n, i+1) for i in range(n))", "matching_cluster_idx": 5}]}, "Mbpp/597": {"dps": null, "dps_norm": null, "pass@1": 4.0, "profiled": []}, "Mbpp/604": {"dps": 94.97607655502392, "dps_norm": 98.94736842105263, "pass@1": 19.0, "profiled": [{"solution": "def reverse_words(s):\n # split the string into a list of words\n words = s.split()\n # reverse the list of words\n reversed_words = words[::-1]\n # join the reversed words back into a string, separated by spaces\n reversed_string = ' '.join(reversed_words)\n # return the resulting string\n return reversed_string", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n \"\"\"\n Function to reverse words separated by spaces in a given string.\n\n :param s: A string containing words separated by spaces.\n :return: A string with the words in reverse order, separated by spaces.\n \"\"\"\n # Split the string into a list of words\n words = s.split()\n\n # Reverse the list of words\n reversed_words = words[::-1]\n\n # Join the list of words back into a string, separated by spaces\n reversed_string = ' '.join(reversed_words)\n\n return reversed_string", "matching_cluster_idx": 4}, {"solution": "def reverse_words(input_str):\n return ' '.join(input_str.split()[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(input_string):\n # Split the string into words\n words = input_string.split()\n # Reverse the order of words\n reversed_words = words[::-1]\n # Join the words back into a string\n reversed_string = ' '.join(reversed_words)\n return reversed_string", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n return ' '.join(s.split()[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(string):\n return ' '.join(string.split()[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s: str) -> str:\n \"\"\"\n Function to reverse words separated by spaces in a given string.\n\n Args:\n s (str): Input string\n\n Returns:\n str: String with reversed words\n \"\"\"\n return ' '.join(reversed(s.split()))", "matching_cluster_idx": 4}, {"solution": "def reverse_words(string):\n return ' '.join(string.split()[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(string):\n # Split the string into words\n words = string.split()\n\n # Reverse the order of the words\n reversed_words = words[::-1]\n\n # Join the reversed words back into a string with space as separator\n reversed_string = ' '.join(reversed_words)\n\n return reversed_string", "matching_cluster_idx": 4}, {"solution": "def reverse_words(input_string):\n return ' '.join(input_string.split()[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n # split the string into a list of words\n words = s.split()\n # reverse the list of words\n reversed_words = words[::-1]\n # join the words back into a string, with a space in between each word\n reversed_string = ' '.join(reversed_words)\n return reversed_string", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n # split the string by spaces, then reverse the list, and then join the elements back with spaces\n return \" \".join(s.split()[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(string):\n # Split the string into a list of words\n words = string.split()\n # Reverse the list\n reversed_words = words[::-1]\n # Join the list back into a string\n reversed_string = ' '.join(reversed_words)\n # Return the reversed string\n return reversed_string", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n # splits the string into words using space as a separator and returns the list of words in reverse order\n return ' '.join(s.split()[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n return ' '.join(s.split()[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(string):\n \"\"\"\n Function to reverse words separated by spaces in a given string.\n\n Parameters:\n string (str): The input string to reverse.\n\n Returns:\n str: The reversed string.\n \"\"\"\n # Split the string into words and reverse the list\n words = string.split()\n reversed_words = words[::-1]\n\n # Join the words back into a string and return the result\n return ' '.join(reversed_words)", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s: str) -> str:\n \"\"\"\n Function to reverse words separated by spaces in a given string.\n \"\"\"\n words = s.split()\n return \" \".join(words[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(string):\n \"\"\"\n A function to reverse words separated by spaces in a given string.\n \"\"\"\n return ' '.join(reversed(string.split()))", "matching_cluster_idx": 3}, {"solution": "def reverse_words(string):\n # split the string into a list of words\n words = string.split()\n # reverse the order of words in the list\n words = words[::-1]\n # join the words back into a string, separated by spaces\n reversed_string = ' '.join(words)\n # return the reversed string\n return reversed_string", "matching_cluster_idx": 4}]}, "Mbpp/610": {"dps": null, "dps_norm": null, "pass@1": 0.0, "profiled": []}, "Mbpp/611": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 83.0, "profiled": [{"solution": "def max_of_nth(matrix, n):\n \"\"\"\n Function to return the maximum value in the n'th column of the given matrix.\n\n :param matrix: A 2D list/matrix.\n :param n: Index of the column.\n :return: The maximum value in the n'th column.\n \"\"\"\n return max(row[n] for row in matrix)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n \"\"\"\n Given a matrix represented as a list of lists,\n this function returns the maximum value of the n'th column.\n \"\"\"\n return max(row[n] for row in matrix)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n # get n'th column\n column = [row[n] for row in matrix]\n # return max of the column\n return max(column)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n return max(row[n] for row in matrix)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n return max(row[n] for row in matrix)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n return max(row[n] for row in matrix)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n # Extract the n'th column from the matrix\n column = [row[n] for row in matrix]\n # Return the max value in the column\n return max(column)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n \"\"\"Given a matrix and column index, return maximum value in the specified column.\"\"\"\n return max(row[n] for row in matrix)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n # Get n'th column from the matrix\n column = [row[n] for row in matrix]\n # Find and return the maximum value in the column\n return max(column)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n \"\"\"Return the max value in the n'th column of a matrix.\"\"\"\n return max(row[n] for row in matrix)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n return max(row[n] for row in matrix)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n return max(row[n] for row in matrix)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n return max([row[n] for row in matrix])", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n return max(row[n] for row in matrix)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n # Extract the n-th column\n nth_column = [row[n] for row in matrix]\n # Return the maximum value in the n-th column\n return max(nth_column)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n return max(row[n] for row in matrix)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n # Extract the n'th column from the matrix\n column = [row[n] for row in matrix]\n\n # Return the maximum value in the extracted column\n return max(column)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n # Get the n'th column from the matrix\n col = [row[n] for row in matrix]\n # Return the maximum value in the column\n return max(col)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n return max([row[n] for row in matrix])", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n return max(row[n] for row in matrix)", "matching_cluster_idx": 5}]}, "Mbpp/631": {"dps": null, "dps_norm": null, "pass@1": 4.0, "profiled": []}, "Mbpp/632": {"dps": 90.56285178236398, "dps_norm": 97.14285714285714, "pass@1": 91.0, "profiled": [{"solution": "def move_zero(num_list):\n non_zero_list = [num for num in num_list if num != 0]\n zero_list = [num for num in num_list if num == 0]\n return non_zero_list + zero_list", "matching_cluster_idx": 6}, {"solution": "def move_zero(lst):\n # list comprehension to exclude zeroes and join the result with all zeroes at the end.\n return [i for i in lst if i != 0] + [i for i in lst if i == 0]", "matching_cluster_idx": 6}, {"solution": "def move_zero(lst):\n \"\"\"\n Function to move all zeroes to the end of the given list\n \"\"\"\n # Initialize an empty list to hold non-zero elements\n new_lst = []\n # Count number of zeros\n count_zero = 0\n\n # Iterate over the input list\n for i in lst:\n # If element is non-zero, append to new list\n if i != 0:\n new_lst.append(i)\n # If element is zero, increment count\n else:\n count_zero += 1\n\n # Append count of zeros to new list\n new_lst.extend([0] * count_zero)\n\n # Return new list\n return new_lst", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n \"\"\"\n Function to move all zeroes to the end of the given list.\n\n Args:\n nums (List[int]): The input list.\n\n Returns:\n List[int]: The modified list with all zeroes at the end.\n \"\"\"\n # Use list comprehension to separate zeros and non-zeros\n non_zeros = [num for num in nums if num != 0]\n zeros = [num for num in nums if num == 0]\n\n # Combine non-zeros list with zeros list\n return non_zeros + zeros", "matching_cluster_idx": 6}, {"solution": "def move_zero(num_list):\n # Separate list into zero and non-zero elements\n zero_list = [num for num in num_list if num == 0]\n non_zero_list = [num for num in num_list if num != 0]\n\n # Concatenate the non-zero list with the zero list to achieve the desired output\n return non_zero_list + zero_list", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n # iterate over the list in reverse\n for i in range(len(nums) - 1, -1, -1):\n # if the current element is zero\n if nums[i] == 0:\n # remove it from the list\n nums.pop(i)\n # append it to the end of the list\n nums.append(0)\n return nums", "matching_cluster_idx": 4}, {"solution": "def move_zero(lst):\n \"\"\"\n This function moves all zeroes to the end of the given list.\n \"\"\"\n # Get all non-zero elements\n non_zero_elements = [i for i in lst if i != 0]\n\n # Count the number of zeroes\n zero_count = len(lst) - len(non_zero_elements)\n\n # Add zeroes at the end of the list\n non_zero_elements.extend([0] * zero_count)\n\n return non_zero_elements", "matching_cluster_idx": 6}, {"solution": "def move_zero(num_list):\n \"\"\"\n This function takes a list of numbers as input, moves all zeroes to the end of the list,\n and returns the modified list.\n \"\"\"\n # Filter out all non-zero elements\n non_zero_elements = [x for x in num_list if x != 0]\n # Count the number of zero elements\n zero_count = len(num_list) - len(non_zero_elements)\n # Extend non-zero elements with zero elements\n non_zero_elements.extend([0] * zero_count)\n return non_zero_elements", "matching_cluster_idx": 6}, {"solution": "def move_zero(num_list):\n # Separate zero and non-zero elements\n zero_list = [num for num in num_list if num == 0]\n non_zero_list = [num for num in num_list if num != 0]\n\n # Combine the lists\n return non_zero_list + zero_list", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n # initialize a list to store the non-zero elements\n non_zero = []\n # initialize a list to store the zero elements\n zero = []\n\n # loop over the input list\n for num in nums:\n if num != 0:\n # if the number is not zero, append it to the non_zero list\n non_zero.append(num)\n else:\n # if the number is zero, append it to the zero list\n zero.append(num)\n\n # return the concatenated list of non-zero elements and zero elements\n return non_zero + zero", "matching_cluster_idx": 6}, {"solution": "def move_zero(lst):\n # Separate zeros and non-zeros into two lists\n non_zeros = [i for i in lst if i != 0]\n zeros = [i for i in lst if i == 0]\n # Combine the two lists\n return non_zeros + zeros", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n \"\"\"\n Function to move all zeroes to the end of the given list.\n \"\"\"\n # We create a copy of the given list but without zeroes\n non_zeros = [num for num in nums if num != 0]\n # We add zeroes to the end of this list\n non_zeros.extend([0] * (len(nums) - len(non_zeros)))\n return non_zeros", "matching_cluster_idx": 6}, {"solution": "def move_zero(input_list):\n # Initialize two empty lists to store non-zero and zero values.\n non_zero = []\n zero = []\n\n # Iterate over the input list.\n for i in input_list:\n # If the value is zero, append it to the zero list.\n if i == 0:\n zero.append(i)\n # Otherwise, append it to the non_zero list.\n else:\n non_zero.append(i)\n\n # Return a new list which is a concatenation of non_zero and zero lists.\n return non_zero + zero", "matching_cluster_idx": 6}, {"solution": "def move_zero(num_list):\n \"\"\"\n This function takes a list of numbers as an input and moves all zeroes to the end of the list.\n It works by iterating through the list, and whenever it encounters a zero, it removes the zero from the list\n and adds it to the end. It continues this process until it has checked every element in the list.\n \"\"\"\n # iterate over the list in reverse order so that removing elements doesn't affect the iteration\n for i in range(len(num_list)-1, -1, -1):\n # if the element is zero, remove it and append it to the end of the list\n if num_list[i] == 0:\n num_list.append(num_list.pop(i))\n return num_list", "matching_cluster_idx": 4}, {"solution": "def move_zero(num_list):\n # create a new list to hold all non-zero elements\n result = [num for num in num_list if num != 0]\n\n # append all zeros at the end of the list\n result.extend([0] * num_list.count(0))\n\n return result", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n # Initialize an empty list to store non-zero elements\n non_zero = []\n # Iterate through the input list\n for num in nums:\n # If the number is non-zero, append it to the non_zero list\n if num != 0:\n non_zero.append(num)\n # Append all zero elements to the end of the non_zero list\n return non_zero + [0] * (len(nums) - len(non_zero))", "matching_cluster_idx": 6}, {"solution": "def move_zero(lst):\n non_zeros = [i for i in lst if i != 0]\n zeros = [i for i in lst if i == 0]\n return non_zeros + zeros", "matching_cluster_idx": 6}, {"solution": "def move_zero(num_list):\n # Create two lists to hold non-zero and zero elements\n non_zero_elements = [i for i in num_list if i != 0]\n zero_elements = [i for i in num_list if i == 0]\n\n # Combine the two lists and return\n return non_zero_elements + zero_elements", "matching_cluster_idx": 6}, {"solution": "def move_zero(num_list):\n # Separate list into two lists, one with zeros and one without\n zeros = [num for num in num_list if num == 0]\n non_zeros = [num for num in num_list if num != 0]\n # Concatenate the non-zeros list with the zeros list and return\n return non_zeros + zeros", "matching_cluster_idx": 6}, {"solution": "def move_zero(num_list):\n non_zero = [num for num in num_list if num != 0]\n zero = [num for num in num_list if num == 0]\n return non_zero + zero", "matching_cluster_idx": 6}]}, "Mbpp/633": {"dps": null, "dps_norm": null, "pass@1": 4.0, "profiled": []}, "Mbpp/644": {"dps": 90.90425531914892, "dps_norm": 89.66666666666666, "pass@1": 74.0, "profiled": [{"solution": "def reverse_Array_Upto_K(arr, k):\n # Reverse upto a given position k\n arr[:k] = arr[:k][::-1]\n return arr", "matching_cluster_idx": 13}, {"solution": "def reverse_Array_Upto_K(arr, k):\n return arr[:k][::-1] + arr[k:]", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n arr[:k] = arr[:k][::-1]\n return arr", "matching_cluster_idx": 13}, {"solution": "def reverse_Array_Upto_K(arr, k):\n arr[:k] = arr[k-1::-1]\n return arr", "matching_cluster_idx": 14}, {"solution": "def reverse_Array_Upto_K(arr, k):\n return arr[:k][::-1] + arr[k:]", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n arr[:k] = arr[:k][::-1]\n return arr", "matching_cluster_idx": 13}, {"solution": "def reverse_Array_Upto_K(arr, k):\n return arr[:k][::-1] + arr[k:]", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n # Reverse the array upto the given position\n arr[:k] = arr[:k][::-1]\n return arr", "matching_cluster_idx": 13}, {"solution": "def reverse_Array_Upto_K(arr, k):\n # Reverse the elements in array from 0 to k\n return arr[:k][::-1] + arr[k:]", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n if k < 0 or k > len(arr):\n raise ValueError('k is out of bounds')\n arr[:k] = arr[:k][::-1]\n return arr", "matching_cluster_idx": 13}, {"solution": "def reverse_Array_Upto_K(arr, k):\n arr[:k] = arr[:k][::-1]\n return arr", "matching_cluster_idx": 13}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n Function to reverse an array upto a given position.\n Args:\n arr: A list of elements.\n k: An integer specifying the position up to which the array is to be reversed.\n Returns:\n A list with elements reversed upto the given position.\n \"\"\"\n arr[:k] = arr[:k][::-1]\n return arr", "matching_cluster_idx": 13}, {"solution": "def reverse_Array_Upto_K(arr, k):\n # Reverse the array upto the given position\n arr[:k] = arr[:k][::-1]\n return arr", "matching_cluster_idx": 13}, {"solution": "def reverse_Array_Upto_K(array, k):\n # Reverse the elements from start of the array to the given position k\n array[:k] = array[k-1::-1]\n return array", "matching_cluster_idx": 14}, {"solution": "def reverse_Array_Upto_K(arr, k):\n arr[:k] = arr[:k][::-1]\n return arr", "matching_cluster_idx": 13}, {"solution": "def reverse_Array_Upto_K(arr, k):\n if k > len(arr):\n return \"k is larger than the length of the array.\"\n elif k <= 0:\n return \"k is less than or equal to 0.\"\n else:\n arr[:k] = arr[k-1::-1]\n return arr", "matching_cluster_idx": 14}, {"solution": "def reverse_Array_Upto_K(array, k):\n # Check if k is within array bounds\n if k < 0 or k > len(array):\n return \"Invalid value of k\"\n else:\n # Reverse the array up to position k\n return array[k-1::-1] + array[k:]", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n This function reverses the array upto the given position k.\n\n Args:\n arr : list of integers\n The input array.\n k : integer\n The position upto which the array should be reversed.\n\n Returns:\n list of integers\n The reversed array upto position k.\n \"\"\"\n\n # Reversing the array upto position k\n arr[:k] = arr[k-1::-1]\n\n return arr", "matching_cluster_idx": 14}, {"solution": "def reverse_Array_Upto_K(arr, k):\n arr[:k] = arr[:k][::-1]\n return arr", "matching_cluster_idx": 13}, {"solution": "def reverse_Array_Upto_K(arr, k):\n # Check if k is within bounds of the array\n if k > len(arr) or k < 0:\n return \"k is out of bounds\"\n\n # Reverse elements upto position k\n arr[:k] = arr[:k][::-1]\n\n return arr", "matching_cluster_idx": 13}]}, "Mbpp/720": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 99.0, "profiled": [{"solution": "def add_dict_to_tuple(tup, dic):\n \"\"\"\n This function adds a dictionary to the end of a tuple.\n The input is a tuple and a dictionary.\n The output is a tuple with the dictionary added to the end.\n \"\"\"\n return tup + (dic,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(input_tuple, input_dict):\n # Adding dictionary to the tuple\n output_tuple = input_tuple + (input_dict,)\n return output_tuple", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(input_tuple, input_dict):\n return input_tuple + (input_dict,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(tup, dict):\n return tup + (dict, )", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(t, d):\n # The function takes a tuple 't' and a dictionary 'd' as inputs, adds the dictionary to the tuple and returns the new tuple\n return t + (d,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(input_tuple, input_dict):\n \"\"\"\n Function to add a dictionary to the end of a tuple.\n The output is a tuple with the elements of the input tuple and the input dictionary in this order.\n \"\"\"\n return input_tuple + (input_dict,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(input_tuple, input_dict):\n return input_tuple + (input_dict,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(tup, dict):\n return tup + (dict,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(input_tuple, input_dict):\n \"\"\"\n Function to add a dictionary to the tuple. The output should be a tuple.\n\n Args:\n input_tuple (tuple): The input tuple.\n input_dict (dict): The input dictionary.\n\n Returns:\n tuple: The tuple with added dictionary.\n \"\"\"\n return input_tuple + (input_dict,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(tup, dictn):\n return tup + (dictn,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(t, d):\n return t + (d,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(input_tuple, input_dict):\n # Combine the tuple and the dictionary into a new tuple\n output_tuple = input_tuple + (input_dict,)\n return output_tuple", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(t, d):\n return t + (d,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(tup, dic):\n \"\"\"\n This function adds a dictionary to a tuple.\n\n Args:\n tup (tuple): The tuple to which the dictionary is to be added.\n dic (dict): The dictionary to be added to the tuple.\n\n Returns:\n tuple: The tuple with the dictionary added to it.\n \"\"\"\n # Create a new tuple with the elements of the original tuple and the dictionary\n new_tup = tup + (dic,)\n return new_tup", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(tup, dict_add):\n return tup + (dict_add, )", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(input_tuple, input_dict):\n \"\"\"\n This function takes in a tuple and a dictionary, then appends the dictionary to the tuple.\n The function returns a new tuple with the original elements followed by the dictionary.\n\n Inputs:\n input_tuple: tuple - The original tuple to be appended with dictionary\n input_dict: dict - The dictionary to be appended to the tuple\n\n Output:\n tuple - A new tuple with the elements from the original tuple followed by the dictionary\n \"\"\"\n # Add the dictionary to the tuple\n output_tuple = input_tuple + (input_dict,)\n return output_tuple", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(input_tuple, input_dict):\n return input_tuple + (input_dict,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(input_tuple, input_dict):\n \"\"\"\n Function to add a dictionary to a tuple.\n \"\"\"\n # The '+' operator is used to concatenate the tuple with a single-item tuple containing the dictionary.\n return input_tuple + (input_dict,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(input_tuple, input_dict):\n \"\"\"\n Function to add a dictionary to the tuple.\n :param input_tuple: The original tuple\n :param input_dict: The dictionary to be added\n :return: The resulting tuple\n \"\"\"\n return input_tuple + (input_dict, )", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(input_tuple, input_dict):\n return input_tuple + (input_dict,)", "matching_cluster_idx": 4}]}, "Mbpp/725": {"dps": 73.22404371584699, "dps_norm": 75.0, "pass@1": 85.0, "profiled": [{"solution": "import re\ndef extract_quotation(s):\n return re.findall(r'\"([^\"]*)\"', s)", "matching_cluster_idx": 6}, {"solution": "import re\ndef extract_quotation(input_string):\n \"\"\"\n Function to extract values between quotation marks \" \" of the given string.\n\n Args:\n input_string (str): A string that contains values between quotation marks.\n\n Returns:\n A list of extracted values between quotation marks.\n\n \"\"\"\n return re.findall('\"([^\"]*)\"', input_string)", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(s):\n return re.findall('\"([^\"]*)\"', s)", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(s):\n return re.findall(r'\"([^\"]*)\"', s)", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(s):\n return re.findall(r'\"([^\"]*)\"', s)", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(s):\n return re.findall('\"([^\"]*)\"', s)", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(s):\n return re.findall(r'\"([^\"]*)\"', s)", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(string):\n return re.findall(r'\"([^\"]*)\"', string)", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(s):\n return re.findall('\"([^\"]*)\"', s)", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(s):\n return re.findall(r'\"([^\"]*)\"', s)", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(s):\n return re.findall(r'\"([^\"]*)\"', s)", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(string):\n return re.findall('\"([^\"]*)\"', string)", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(s):\n return re.findall(r'\"([^\"]*)\"', s)", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(input_string):\n return re.findall(r'\"([^\"]*)\"', input_string)", "matching_cluster_idx": 5}, {"solution": "def extract_quotation(s):\n # Initialize empty list to store the extracted values\n values = []\n # Initialize start index as the index of the first quotation mark\n start = s.find('\"')\n # Loop until there are no more quotation marks left in the string\n while start != -1:\n # Find the index of the next quotation mark\n end = s.find('\"', start + 1)\n # If there is no next quotation mark, break the loop\n if end == -1:\n break\n # Add the value between the current and next quotation marks to the list\n values.append(s[start + 1:end])\n # Update start index to the index after the next quotation mark\n start = s.find('\"', end + 1)\n # Return the list of extracted values\n return values", "matching_cluster_idx": 4}, {"solution": "import re\ndef extract_quotation(string):\n return re.findall('\"([^\"]*)\"', string)", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(s):\n return re.findall('\"([^\"]*)\"', s)", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(s):\n return re.findall(r'\"([^\"]*)\"', s)", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(s):\n return re.findall(r'\"([^\"]*)\"', s)", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(string):\n return re.findall(r'\"([^\"]*)\"', string)", "matching_cluster_idx": 5}]}, "Mbpp/732": {"dps": 93.17829457364341, "dps_norm": 99.0, "pass@1": 100.0, "profiled": [{"solution": "def replace_specialchar(input_string):\n \"\"\"\n This function replaces all spaces, commas, and dots in the input string with a colon.\n :param input_string: str - the string to process\n :return: str - the processed string\n \"\"\"\n # create a translation table\n trans = str.maketrans(' ,.', ':::')\n # use the translation table to replace characters\n return input_string.translate(trans)", "matching_cluster_idx": 8}, {"solution": "def replace_specialchar(string):\n string = string.replace(' ', ':')\n string = string.replace(',', ':')\n string = string.replace('.', ':')\n return string", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(input_string):\n \"\"\"\n This function takes a string input and replaces all spaces, commas, and dots with a colon.\n \"\"\"\n # Replace spaces\n input_string = input_string.replace(\" \", \":\")\n # Replace commas\n input_string = input_string.replace(\",\", \":\")\n # Replace dots\n input_string = input_string.replace(\".\", \":\")\n return input_string", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(input_string):\n input_string = input_string.replace(' ', ':')\n input_string = input_string.replace(',', ':')\n input_string = input_string.replace('.', ':')\n return input_string", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(input_string):\n # Using the translate() function and str.maketrans() to replace spaces, commas, and dots with a colon\n return input_string.translate(str.maketrans(' ,.', ':::'))", "matching_cluster_idx": 8}, {"solution": "def replace_specialchar(string):\n return string.replace(' ', ':').replace(',', ':').replace('.', ':')", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(input_str):\n \"\"\"\n This function takes an input string and replaces all occurrences of spaces, commas,\n or dots with a colon.\n \"\"\"\n return input_str.replace(' ', ':').replace(',', ':').replace('.', ':')", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(s):\n return s.replace(' ', ':').replace(',', ':').replace('.', ':')", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(input_string):\n return input_string.replace(' ', ':').replace(',', ':').replace('.', ':')", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(s):\n return s.replace(' ', ':').replace(',', ':').replace('.', ':')", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(s):\n return s.replace(' ', ':').replace(',', ':').replace('.', ':')", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(input_string):\n return input_string.replace(' ', ':').replace(',', ':').replace('.', ':')", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(string):\n \"\"\"\n Replaces all occurrences of spaces, commas, or dots with a colon.\n\n Args:\n string (str): The input string.\n\n Returns:\n str: The output string with replaced special characters.\n \"\"\"\n for char in [',', '.', ' ']:\n if char in string:\n string = string.replace(char, ':')\n return string", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(text):\n # Use the replace() function three times to replace each special character with a colon\n text = text.replace(' ', ':')\n text = text.replace(',', ':')\n text = text.replace('.', ':')\n return text", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(string):\n # replace spaces with colons\n string = string.replace(' ', ':')\n # replace commas with colons\n string = string.replace(',', ':')\n # replace dots with colons\n string = string.replace('.', ':')\n return string", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(s):\n return s.replace(\" \", \":\").replace(\",\", \":\").replace(\".\", \":\")", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(input_str):\n # Replace spaces, commas, or dots with a colon\n output_str = input_str.replace(' ', ':').replace(',', ':').replace('.', ':')\n return output_str", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(input_str):\n # Replacing special characters with colon\n input_str = input_str.replace(' ', ':').replace(',', ':').replace('.', ':')\n return input_str", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(input_string):\n # Replacing spaces, commas, and dots with colon\n output_string = input_string.replace(' ', ':').replace(',', ':').replace('.', ':')\n return output_string", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(input_string):\n output_string = input_string.replace(' ', ':')\n output_string = output_string.replace(',', ':')\n output_string = output_string.replace('.', ':')\n return output_string", "matching_cluster_idx": 9}]}, "Mbpp/740": {"dps": 66.45454545454545, "dps_norm": 61.111111111111114, "pass@1": 100.0, "profiled": [{"solution": "def tuple_to_dict(input_tuple):\n return {input_tuple[i]: input_tuple[i + 1] for i in range(0, len(input_tuple), 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(t):\n if len(t) % 2 != 0:\n raise ValueError(\"Input tuple should have an even number of elements.\")\n return {t[i]: t[i + 1] for i in range(0, len(t), 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(t):\n # Check if the length of tuple is even\n if len(t) % 2 != 0:\n raise ValueError(\"The length of the tuple must be even.\")\n return {t[i]: t[i + 1] for i in range(0, len(t), 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(tup):\n return {tup[i]: tup[i + 1] for i in range(0, len(tup), 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(tup):\n return {tup[i]: tup[i + 1] for i in range(0, len(tup), 2) if i + 1 < len(tup)}", "matching_cluster_idx": 3}, {"solution": "def tuple_to_dict(tup):\n return {tup[i]: tup[i + 1] for i in range(0, len(tup), 2) if i + 1 < len(tup)}", "matching_cluster_idx": 3}, {"solution": "def tuple_to_dict(tup):\n return {tup[i]: tup[i + 1] for i in range(0, len(tup), 2) if i + 1 < len(tup)}", "matching_cluster_idx": 3}, {"solution": "def tuple_to_dict(t):\n # An empty dictionary to store the result\n result = {}\n # Iterate over the tuple two elements at a time\n for i in range(0, len(t), 2):\n # Add each pair of elements to the dictionary\n result[t[i]] = t[i + 1]\n return result", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(tup):\n if len(tup) % 2 != 0:\n raise ValueError(\"The length of the tuple must be even.\")\n return {tup[i]: tup[i+1] for i in range(0, len(tup), 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(tup):\n # Create an empty dictionary\n d = {}\n # Traverse the tuple in steps of 2\n for i in range(0, len(tup), 2):\n # If index+1 is within the tuple range, add pair to dictionary\n if i+1 < len(tup):\n d[tup[i]] = tup[i+1]\n return d", "matching_cluster_idx": 3}, {"solution": "def tuple_to_dict(input_tuple):\n \"\"\"\n This function takes a tuple as input and converts it to a dictionary where keys are\n elements of the tuple at even indices and values are elements at odd indices.\n \"\"\"\n return {input_tuple[i]: input_tuple[i + 1] for i in range(0, len(input_tuple), 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(input_tuple):\n return {input_tuple[i]: input_tuple[i + 1] for i in range(0, len(input_tuple), 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(t):\n \"\"\"\n Convert the given tuple to a key-value dictionary using adjacent elements.\n :param t: tuple of elements\n :return: dictionary with adjacent elements as key-value pairs\n \"\"\"\n return {t[i]: t[i + 1] for i in range(0, len(t), 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(input_tuple):\n \"\"\"\n Function to convert a tuple to a key-value dictionary using adjacent elements.\n \"\"\"\n # Initialize an empty dictionary\n result_dict = {}\n\n # Iterate over the tuple with a step size of 2\n for i in range(0, len(input_tuple), 2):\n # Use slicing to get the key and value, add them to the dictionary\n result_dict[input_tuple[i]] = input_tuple[i+1]\n\n return result_dict", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(tuple_input):\n # Initialize an empty dictionary\n dict_output = {}\n\n # Iterate over every other element in the tuple\n for i in range(0, len(tuple_input), 2):\n # Add each pair of elements as a key-value pair in the dictionary\n dict_output[tuple_input[i]] = tuple_input[i + 1]\n\n return dict_output", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(t):\n return {t[i]: t[i+1] for i in range(0, len(t), 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(t):\n return {t[i]: t[i + 1] for i in range(0, len(t), 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(tuple_val):\n return {tuple_val[i]: tuple_val[i + 1] for i in range(0, len(tuple_val), 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(t):\n return {t[i]: t[i + 1] for i in range(0, len(t), 2) if i + 1 < len(t)}", "matching_cluster_idx": 3}, {"solution": "def tuple_to_dict(t):\n return {t[i]: t[i + 1] for i in range(0, len(t), 2)}", "matching_cluster_idx": 5}]}, "Mbpp/744": {"dps": 96.4041095890411, "dps_norm": 97.5, "pass@1": 100.0, "profiled": [{"solution": "def check_none(t):\n if None in t:\n return True\n else:\n return False", "matching_cluster_idx": 4}, {"solution": "def check_none(t):\n return None in t", "matching_cluster_idx": 5}, {"solution": "def check_none(tuple_input):\n \"\"\"\n This function takes a tuple as input and returns True if the tuple contains None, otherwise it returns False.\n \"\"\"\n return None in tuple_input", "matching_cluster_idx": 5}, {"solution": "def check_none(t):\n return None in t", "matching_cluster_idx": 5}, {"solution": "def check_none(input_tuple):\n return None in input_tuple", "matching_cluster_idx": 5}, {"solution": "def check_none(tuple_value):\n return None in tuple_value", "matching_cluster_idx": 5}, {"solution": "def check_none(t):\n \"\"\"\n This function checks if a given tuple has any None value or not.\n\n Arguments:\n t -- the tuple to be checked\n\n Returns:\n True if the tuple contains at least one None value, False otherwise\n \"\"\"\n return None in t", "matching_cluster_idx": 5}, {"solution": "def check_none(tup):\n # Checking if None is in the tuple\n if None in tup:\n return True\n else:\n return False", "matching_cluster_idx": 5}, {"solution": "def check_none(tup):\n return None in tup", "matching_cluster_idx": 5}, {"solution": "def check_none(input_tuple):\n \"\"\"Check if the given tuple has any None value.\"\"\"\n return None in input_tuple", "matching_cluster_idx": 5}, {"solution": "def check_none(tup):\n return None in tup", "matching_cluster_idx": 5}, {"solution": "def check_none(t):\n return None in t", "matching_cluster_idx": 5}, {"solution": "def check_none(t):\n \"\"\"\n This function checks if the given tuple has any none value or not.\n \"\"\"\n if None in t:\n return True\n else:\n return False", "matching_cluster_idx": 5}, {"solution": "def check_none(tup):\n if None in tup:\n return True\n else:\n return False", "matching_cluster_idx": 5}, {"solution": "def check_none(input_tuple):\n for val in input_tuple:\n if val is None:\n return True\n return False", "matching_cluster_idx": 4}, {"solution": "def check_none(tup):\n if None in tup:\n return True\n else:\n return False", "matching_cluster_idx": 5}, {"solution": "def check_none(input_tuple):\n # check if any value in the tuple is None\n if None in input_tuple:\n return True\n else:\n return False", "matching_cluster_idx": 5}, {"solution": "def check_none(tuple_val):\n \"\"\"\n This function checks if a given tuple contains any None value.\n It returns True if any None value is found, False otherwise.\n \"\"\"\n for val in tuple_val:\n if val is None:\n return True\n return False", "matching_cluster_idx": 4}, {"solution": "def check_none(input_tuple):\n return None in input_tuple", "matching_cluster_idx": 5}, {"solution": "def check_none(tup):\n \"\"\"\n This function takes a tuple as an argument and returns True if it contains\n any None value, otherwise returns False\n \"\"\"\n return None in tup", "matching_cluster_idx": 5}]}, "Mbpp/750": {"dps": 60.74829931972789, "dps_norm": 62.5, "pass@1": 97.0, "profiled": [{"solution": "def add_tuple(lst, tup):\n # iterate over each item in tuple\n for item in tup:\n # add each item to the list\n lst.append(item)\n # return the updated list\n return lst", "matching_cluster_idx": 0}, {"solution": "def add_tuple(lst, tpl):\n # convert tuple to list\n lst_tpl = list(tpl)\n # extend list with the new elements from tuple\n lst.extend(lst_tpl)\n return lst", "matching_cluster_idx": 4}, {"solution": "def add_tuple(lst, tup):\n return lst + list(tup)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(lst, tpl):\n lst.extend(tpl)\n return lst", "matching_cluster_idx": 5}, {"solution": "def add_tuple(list_obj, tuple_obj):\n \"\"\"\n This function takes a list and a tuple as arguments.\n It then appends each element of the tuple to the end of the list.\n \"\"\"\n list_obj.extend(tuple_obj)\n return list_obj", "matching_cluster_idx": 5}, {"solution": "def add_tuple(lst, tpl):\n # Convert the tuple to a list\n tpl_as_list = list(tpl)\n # Extend the list with the elements from the tuple\n lst.extend(tpl_as_list)\n return lst", "matching_cluster_idx": 4}, {"solution": "def add_tuple(list_, tuple_):\n list_.extend(tuple_)\n return list_", "matching_cluster_idx": 5}, {"solution": "def add_tuple(list1, tuple1):\n \"\"\"\n Function to add a given tuple to a given list.\n \"\"\"\n # Convert the tuple to list and extend the list with the tuple list\n list1.extend(list(tuple1))\n return list1", "matching_cluster_idx": 4}, {"solution": "def add_tuple(lst, tpl):\n \"\"\"Add a tuple to a list\"\"\"\n for element in tpl:\n lst.append(element)\n return lst", "matching_cluster_idx": 0}, {"solution": "def add_tuple(lst, tup):\n \"\"\"\n This function takes a list and a tuple as inputs, then appends the elements of the tuple to the list.\n\n Parameters:\n lst (list): The list to which the elements of the tuple will be added.\n tup (tuple): The tuple whose elements will be added to the list.\n\n Returns:\n list: The input list, modified to include the elements of the input tuple.\n \"\"\"\n # Add the tuple to the list\n lst.extend(tup)\n return lst", "matching_cluster_idx": 5}, {"solution": "def add_tuple(lst, tup):\n return lst + list(tup)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(lst, tup):\n \"\"\"\n Function to add the given tuple to the given list.\n\n Parameters:\n lst (list): the given list\n tup (tuple): the given tuple\n\n Returns:\n list: the given list with the contents of the given tuple appended\n \"\"\"\n return lst + list(tup)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(lst, tup):\n \"\"\"\n This function takes a list and a tuple as arguments,\n appends all elements of the tuple to the list, and returns the new list.\n \"\"\"\n return lst + list(tup)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(lst, tpl):\n # Converting tuple to list\n tpl = list(tpl)\n # Adding tuple to list\n lst.extend(tpl)\n return lst", "matching_cluster_idx": 4}, {"solution": "def add_tuple(lst, tup):\n return lst + list(tup)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(lst, tup):\n for i in tup:\n lst.append(i)\n return lst", "matching_cluster_idx": 0}, {"solution": "def add_tuple(lst, tup):\n # Add each element of the tuple to the list\n for elem in tup:\n lst.append(elem)\n # Return the modified list\n return lst", "matching_cluster_idx": 0}, {"solution": "def add_tuple(list, tuple):\n \"\"\"\n This function takes a list and a tuple as arguments.\n It adds all elements of the tuple to the end of the list.\n :param list: A list of elements\n :param tuple: A tuple of elements\n :return: The list with all elements of the tuple added at the end\n \"\"\"\n list.extend(tuple)\n return list", "matching_cluster_idx": 5}, {"solution": "def add_tuple(lst, tpl):\n return lst + list(tpl)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(lst, tpl):\n return lst + list(tpl)", "matching_cluster_idx": 2}]}, "Mbpp/753": {"dps": 97.31543624161074, "dps_norm": 75.0, "pass@1": 100.0, "profiled": [{"solution": "def min_k(records, k):\n \"\"\"\n Function to find minimum k records from tuple list.\n\n Parameters:\n records (list): A list of tuples where each tuple contains a string and an integer\n k (int): Number of minimum records to return\n\n Returns:\n list: A list of tuples containing the k records with minimum integers\n \"\"\"\n # Sort the list of tuples based on the integer element\n records.sort(key=lambda x: x[1])\n # Return the first k elements\n return records[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(tuples_list, k):\n return sorted(tuples_list, key=lambda x: x[1])[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(records, k):\n # sort the records based on their scores\n sorted_records = sorted(records, key=lambda x: x[1])\n # return the first k records\n return sorted_records[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(records, k):\n # sort the records based on the second element of each tuple\n records.sort(key=lambda x: x[1])\n # return the first k records\n return records[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(records, k):\n # Sort the records based on the second element of each tuple\n sorted_records = sorted(records, key = lambda x: x[1])\n\n # Return the first k records\n return sorted_records[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(tuples_list, k):\n # sort the list of tuples\n tuples_list.sort(key=lambda x: x[1])\n # return the first k tuples\n return tuples_list[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(records, k):\n # Sort the records list in ascending order based on the second element of the tuple.\n sorted_records = sorted(records, key=lambda x: x[1])\n # Return the first k records.\n return sorted_records[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(records, k):\n # sort the tuple list based on second element of each tuple\n sorted_records = sorted(records, key=lambda x: x[1])\n # return first k tuples from sorted list\n return sorted_records[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(records, k):\n # sort the list based on the second element of the tuple\n records.sort(key=lambda x: x[1])\n # return the first k records\n return records[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(tuples_list, k):\n # Sorts the list based on second element of tuple in ascending order\n sorted_list = sorted(tuples_list, key = lambda x: x[1])\n\n # Returns first k records\n return sorted_list[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(records, k):\n # Sort the list based on the second element of each tuple\n records.sort(key = lambda x: x[1])\n # Return the first k elements\n return records[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(tuples, k):\n tuples.sort(key=lambda x: x[1])\n return tuples[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(records, k):\n # Sort the tuple list based on second element of tuple in ascending order\n records.sort(key=lambda x: x[1])\n # Return the first k records\n return records[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(records, k):\n sorted_records = sorted(records, key=lambda record: record[1])\n return sorted_records[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(tuples, k):\n tuples.sort(key=lambda x: x[1])\n return tuples[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(tuples_list, k):\n # Sort the list of tuples based on the second element of each tuple\n sorted_list = sorted(tuples_list, key=lambda x: x[1])\n\n # Return the first k tuples from the sorted list\n return sorted_list[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(records, k):\n \"\"\"\n Function to find minimum k records from tuple list.\n \"\"\"\n # Sort the tuple list\n records.sort(key=lambda x: x[1])\n # Return the first k records\n return records[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(lst, k):\n # sorting the tuple list based on the second element of the tuple\n sorted_lst = sorted(lst, key=lambda x: x[1])\n\n # returning the first k records\n return sorted_lst[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(records, k):\n return sorted(records, key=lambda x: x[1])[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(records, k):\n records.sort(key=lambda x: x[1])\n return records[:k]", "matching_cluster_idx": 2}]}, "Mbpp/754": {"dps": 92.24137931034483, "dps_norm": 93.05555555555556, "pass@1": 18.0, "profiled": [{"solution": "def extract_index_list(l1, l2, l3):\n # Initialize an empty list to store common elements\n common_elements = []\n # Loop through the indexes of the lists\n for i in range(min(len(l1), len(l2), len(l3))):\n # If the element appears in all three lists under the same index, append it to the common_elements list\n if l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n # Zip three lists into one list of tuples\n zipped = list(zip(l1, l2, l3))\n\n # Use list comprehension to find elements that are common at the same index in three lists\n common = [item[0] for item in zipped if item[0] == item[1] == item[2]]\n\n return common", "matching_cluster_idx": 4}, {"solution": "def extract_index_list(l1, l2, l3):\n return [i for i, j, k in zip(l1, l2, l3) if i == j == k]", "matching_cluster_idx": 7}, {"solution": "def extract_index_list(l1, l2, l3):\n common_elements = []\n for i in range(min(len(l1), len(l2), len(l3))):\n if l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n return [i for i, j, k in zip(l1, l2, l3) if i == j == k]", "matching_cluster_idx": 7}, {"solution": "def extract_index_list(l1, l2, l3):\n common_elements = []\n for i in range(min(len(l1), len(l2), len(l3))):\n if l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n return [i for i, j, k in zip(l1, l2, l3) if i == j == k]", "matching_cluster_idx": 7}, {"solution": "def extract_index_list(l1, l2, l3):\n common_elements = []\n for i in range(min(len(l1), len(l2), len(l3))):\n if l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n # Initialise an empty list to hold the common elements\n common_elements = []\n # Use zip to iterate over all three lists simultaneously\n for a, b, c in zip(l1, l2, l3):\n # If an element is common, add it to the list\n if a == b == c:\n common_elements.append(a)\n # Return the list of common elements\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n # zip returns an iterator of tuples, where the i-th tuple contains the i-th element from each of the argument sequences or iterables\n # tuple unpacking is then used to iterate through each triplet of elements from the three lists\n common_elements = [i for i, j, k in zip(l1, l2, l3) if i == j == k]\n return common_elements", "matching_cluster_idx": 7}, {"solution": "def extract_index_list(l1, l2, l3):\n return [x for x, y, z in zip(l1, l2, l3) if x == y == z]", "matching_cluster_idx": 7}, {"solution": "def extract_index_list(l1, l2, l3):\n return [i for i, j, k in zip(l1, l2, l3) if i == j == k]", "matching_cluster_idx": 7}, {"solution": "def extract_index_list(l1, l2, l3):\n return [x for x, y, z in zip(l1, l2, l3) if x == y == z]", "matching_cluster_idx": 7}, {"solution": "def extract_index_list(l1, l2, l3):\n return [i for i, j, k in zip(l1, l2, l3) if i == j == k]", "matching_cluster_idx": 7}, {"solution": "def extract_index_list(l1, l2, l3):\n # Using list comprehension, find the common elements\n # which are present in all three lists at same indices\n common_elements = [i for i, j, k in zip(l1, l2, l3) if i == j == k]\n return common_elements", "matching_cluster_idx": 7}, {"solution": "def extract_index_list(l1, l2, l3):\n # Get the length of the shortest list\n min_len = min(len(l1), len(l2), len(l3))\n # Use list comprehension to create a list of elements common to all three lists\n common_elements = [l1[i] for i in range(min_len) if l1[i] == l2[i] == l3[i]]\n # Return the list of common elements\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n common_elements = []\n for i in range(min(len(l1), len(l2), len(l3))):\n if l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n # Initialize empty list to store common elements\n common = []\n # Iterate over lists simultaneously using zip function\n for a, b, c in zip(l1, l2, l3):\n # Check if elements at same index are common in all lists\n if a == b == c:\n common.append(a)\n # Return list of common elements\n return common", "matching_cluster_idx": 7}]}, "Mbpp/755": {"dps": 87.7433628318584, "dps_norm": 94.16666666666667, "pass@1": 26.0, "profiled": [{"solution": "def second_smallest(num_list):\n \"\"\"\n A function to find the second smallest number in a list.\n \"\"\"\n unique_list = list(set(num_list))\n unique_list.sort()\n return unique_list[1] if len(unique_list) >= 2 else None", "matching_cluster_idx": 5}, {"solution": "def second_smallest(numbers):\n unique_numbers = sorted(set(numbers))\n return unique_numbers[1] if len(unique_numbers) >= 2 else None", "matching_cluster_idx": 5}, {"solution": "def second_smallest(lst):\n \"\"\"\n Function to find the second smallest number in a list.\n \"\"\"\n # If the list is empty or only contains one element, there is no second smallest number\n if len(lst) < 2:\n return None\n\n smallest = float('inf')\n second_smallest = float('inf')\n\n for num in lst:\n if num < smallest:\n # If a number is found that is smaller than the current smallest,\n # shift the smallest and second smallest numbers down\n second_smallest = smallest\n smallest = num\n elif num < second_smallest and num != smallest:\n # If a number is found that is smaller than the current second smallest\n # and not equal to the smallest, update the second smallest\n second_smallest = num\n\n # If there is no second smallest number, return None\n return None if second_smallest == float('inf') else second_smallest", "matching_cluster_idx": 4}, {"solution": "def second_smallest(lst):\n # Check if the list is long enough\n if len(lst) < 2:\n return None\n\n # Initialize with positive infinity and the smallest number as the first element in the list\n second_min, min_num = float('inf'), min(lst)\n\n # Traverse the list\n for num in lst:\n if min_num < num < second_min:\n second_min = num\n\n # If no second smallest element\n if second_min == float('inf'):\n return None\n\n return second_min", "matching_cluster_idx": 3}, {"solution": "def second_smallest(num_list):\n num_set = set(num_list)\n if len(num_set) < 2:\n return None\n num_list = list(num_set)\n num_list.sort()\n return num_list[1]", "matching_cluster_idx": 5}, {"solution": "def second_smallest(numbers):\n unique_numbers = list(set(numbers))\n unique_numbers.sort()\n return unique_numbers[1] if len(unique_numbers) >= 2 else None", "matching_cluster_idx": 5}, {"solution": "def second_smallest(numbers):\n # Check if list has at least 2 elements\n if len(numbers) < 2:\n return None\n\n # Initialize smallest and second smallest as the first two numbers\n smallest = second_smallest = float('inf')\n for num in numbers:\n if num < smallest:\n # Update both smallest and second smallest\n second_smallest = smallest\n smallest = num\n elif smallest < num < second_smallest:\n # Update second smallest\n second_smallest = num\n\n return second_smallest if second_smallest != float('inf') else None", "matching_cluster_idx": 3}, {"solution": "def second_smallest(numbers):\n # Use set to remove duplicates and sort the list\n numbers = sorted(set(numbers))\n\n # Return the second smallest number\n return numbers[1] if len(numbers) > 1 else None", "matching_cluster_idx": 5}, {"solution": "def second_smallest(lst):\n unique_lst = list(set(lst))\n unique_lst.sort()\n if len(unique_lst) < 2:\n return None\n return unique_lst[1]", "matching_cluster_idx": 5}, {"solution": "def second_smallest(numbers):\n # Removing duplicates from the list\n unique_numbers = list(set(numbers))\n # Sorting the list in ascending order\n unique_numbers.sort()\n # Returning the second smallest number\n return unique_numbers[1] if len(unique_numbers) > 1 else None", "matching_cluster_idx": 5}, {"solution": "def second_smallest(numbers):\n # Remove duplicates by converting the list to a set and then convert it back to a list\n numbers = list(set(numbers))\n # Sort the list in ascending order\n numbers.sort()\n # Return the second smallest number in the list\n return numbers[1] if len(numbers) > 1 else None", "matching_cluster_idx": 5}, {"solution": "def second_smallest(numbers):\n # First, we remove duplicates from the list using set to get unique elements\n unique_numbers = list(set(numbers))\n # Then, we sort the unique elements in ascending order\n unique_numbers.sort()\n # After that, we check if the list has enough elements to find the second smallest\n if len(unique_numbers) < 2:\n return None\n # Finally, we return the second element of the sorted list\n return unique_numbers[1]", "matching_cluster_idx": 5}, {"solution": "def second_smallest(numbers):\n unique_numbers = list(set(numbers))\n unique_numbers.sort()\n return unique_numbers[1] if len(unique_numbers) > 1 else None", "matching_cluster_idx": 5}, {"solution": "def second_smallest(numbers):\n # Create a list of unique numbers sorted in ascending order.\n unique_numbers = sorted(set(numbers))\n\n # Check if there are at least 2 unique numbers.\n if len(unique_numbers) < 2:\n return None\n\n # Return the second smallest number.\n return unique_numbers[1]", "matching_cluster_idx": 5}, {"solution": "def second_smallest(numbers):\n unique_numbers = sorted(set(numbers))\n if len(unique_numbers) < 2:\n return None\n return unique_numbers[1]", "matching_cluster_idx": 5}, {"solution": "def second_smallest(numbers):\n # Use a set to get unique numbers and sort them in ascending order\n unique_numbers = sorted(set(numbers))\n # If there are at least two unique numbers, return the second smallest\n if len(unique_numbers) >= 2:\n return unique_numbers[1]\n # If there are less than two unique numbers, return None\n else:\n return None", "matching_cluster_idx": 5}, {"solution": "def second_smallest(numbers):\n # handle invalid input\n if len(numbers) < 2:\n return None\n\n smallest = float('inf')\n second_smallest = float('inf')\n\n for num in numbers:\n if num < smallest:\n second_smallest = smallest\n smallest = num\n elif smallest < num < second_smallest:\n second_smallest = num\n\n # if there is no second smallest number\n if second_smallest == float('inf'):\n return None\n\n return second_smallest", "matching_cluster_idx": 3}, {"solution": "def second_smallest(lst):\n # Remove duplicates and sort the list\n lst = sorted(set(lst))\n\n # Check if the list has at least 2 elements\n if len(lst) < 2:\n return None\n\n # Return the second smallest element\n return lst[1]", "matching_cluster_idx": 5}, {"solution": "def second_smallest(numbers):\n # Remove duplicates by converting the list to a set\n numbers = list(set(numbers))\n\n # Sort the list in ascending order\n numbers.sort()\n\n # Check if the list contains at least two elements\n if len(numbers) < 2:\n return None\n\n # Return the second element\n return numbers[1]", "matching_cluster_idx": 5}, {"solution": "def second_smallest(lst):\n # remove duplicates and sort the list\n unique_lst = sorted(list(set(lst)))\n\n # check if the list has at least two elements\n if len(unique_lst) < 2:\n return None\n\n # return the second element (which is the second smallest number)\n return unique_lst[1]", "matching_cluster_idx": 5}]}, "Mbpp/757": {"dps": 82.71028037383178, "dps_norm": 23.076923076923077, "pass@1": 77.0, "profiled": [{"solution": "def count_reverse_pairs(strings):\n count = 0\n for i in range(len(strings)):\n for j in range(i+1, len(strings)):\n if strings[i] == strings[j][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(lst):\n count = 0\n for i in range(len(lst)):\n for j in range(i+1, len(lst)):\n if lst[i] == lst[j][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(lst):\n count = 0\n for i in range(len(lst)):\n for j in range(i + 1, len(lst)):\n if lst[i] == lst[j][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(str_list):\n count = 0\n for i in range(len(str_list)):\n for j in range(i + 1, len(str_list)):\n if str_list[i] == str_list[j][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(word_list):\n # initialize the counter to 0\n count = 0\n\n # iterate over the list of words\n for i in range(len(word_list)):\n # for each word, iterate over the remaining list of words\n for j in range(i + 1, len(word_list)):\n # if the word is the reverse of the other word, increment the counter\n if word_list[i] == word_list[j][::-1]:\n count += 1\n\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(strings):\n count = 0\n for i in range(len(strings)):\n for j in range(i+1, len(strings)):\n if strings[i] == strings[j][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(strings):\n count = 0\n for i in range(len(strings)):\n for j in range(i+1, len(strings)):\n if strings[i] == strings[j][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(strings):\n count = 0\n for i in range(len(strings)):\n for j in range(i+1, len(strings)):\n if strings[i] == strings[j][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(string_list):\n reverse_pairs_count = 0\n for i in range(len(string_list)):\n for j in range(i+1, len(string_list)):\n if string_list[i] == string_list[j][::-1]:\n reverse_pairs_count += 1\n return reverse_pairs_count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(lst):\n count = 0\n for i in range(len(lst)):\n for j in range(i+1, len(lst)):\n if lst[i] == lst[j][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(str_list):\n count = 0\n for i in range(len(str_list)):\n for j in range(i+1, len(str_list)):\n if str_list[i] == str_list[j][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(lst):\n \"\"\"\n Function to count the pairs of reverse strings in the given string list.\n \"\"\"\n reverse_pairs = 0\n for i in range(len(lst)):\n for j in range(i+1, len(lst)):\n if lst[i] == lst[j][::-1]:\n reverse_pairs += 1\n return reverse_pairs", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(words):\n count = 0\n for i in range(len(words)):\n for j in range(i + 1, len(words)):\n if words[i] == words[j][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(strings):\n # Initialize a counter to keep track of the pairs of reverse strings\n count = 0\n # Iterate through the string list\n for i in range(len(strings)):\n # Iterate through the string list again, starting from the next element\n for j in range(i+1, len(strings)):\n # If the reverse of the current string is equal to the next string, increment the counter\n if strings[i] == strings[j][::-1]:\n count += 1\n # Return the counter\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(str_list):\n # initialize the counter of reverse pairs\n count = 0\n # traverse the list\n for i in range(len(str_list)):\n for j in range(i+1, len(str_list)):\n # if reversed pair is found increment the counter\n if str_list[i] == str_list[j][::-1]:\n count += 1\n # return the count\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(str_list):\n count = 0\n for i in range(len(str_list)):\n for j in range(i+1, len(str_list)):\n if str_list[i] == str_list[j][::-1]: # if a string equals to reversed of another one\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(lst):\n \"\"\"\n This function takes a list of strings as input and returns the count of pairs of reverse strings in the list.\n \"\"\"\n pairs = 0\n for i in range(len(lst)):\n for j in range(i+1, len(lst)):\n if lst[i] == lst[j][::-1]:\n pairs += 1\n return pairs", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(str_list):\n \"\"\"\n Function to count the pairs of reverse strings in the given string list.\n \"\"\"\n count = 0\n for i in range(len(str_list)):\n for j in range(i+1, len(str_list)):\n if str_list[i] == str_list[j][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(str_list):\n \"\"\"Count the pairs of reverse strings in the given string list.\"\"\"\n\n count = 0\n\n # Traverse through the list\n for i in range(len(str_list)):\n # For each string, check with the rest of the list if its reverse is present\n for j in range(i+1, len(str_list)):\n if str_list[i] == str_list[j][::-1]:\n # If reverse is present, increment the count\n count += 1\n\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(lst):\n count = 0\n for i in range(len(lst)):\n for j in range(i+1, len(lst)):\n if lst[i] == lst[j][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}]}, "Mbpp/758": {"dps": 93.97683397683396, "dps_norm": 91.875, "pass@1": 100.0, "profiled": [{"solution": "def unique_sublists(lst):\n count_dict = {}\n for sublist in lst:\n tuple_sublist = tuple(sublist)\n if tuple_sublist in count_dict:\n count_dict[tuple_sublist] += 1\n else:\n count_dict[tuple_sublist] = 1\n return count_dict", "matching_cluster_idx": 7}, {"solution": "def unique_sublists(lst):\n sublists_count = {}\n for sublist in lst:\n sublist_tuple = tuple(sublist)\n if sublist_tuple in sublists_count:\n sublists_count[sublist_tuple] += 1\n else:\n sublists_count[sublist_tuple] = 1\n return sublists_count", "matching_cluster_idx": 5}, {"solution": "def unique_sublists(lst):\n counts = {}\n for sublist in lst:\n t = tuple(sublist)\n if t in counts:\n counts[t] += 1\n else:\n counts[t] = 1\n return counts", "matching_cluster_idx": 7}, {"solution": "def unique_sublists(lst):\n # create an empty dictionary to store results\n counts = {}\n\n # convert each sublist to a tuple and count occurrences\n for sublist in lst:\n # convert sublist to tuple\n subtuple = tuple(sublist)\n\n # update count for this subtuple\n if subtuple in counts:\n counts[subtuple] += 1\n else:\n counts[subtuple] = 1\n\n return counts", "matching_cluster_idx": 7}, {"solution": "def unique_sublists(lst):\n counter = {}\n for sublist in lst:\n tuple_sublist = tuple(sublist)\n if tuple_sublist in counter:\n counter[tuple_sublist] += 1\n else:\n counter[tuple_sublist] = 1\n return counter", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(lst):\n # create an empty dictionary\n count_dict = {}\n # iterate over the sublists in the input list\n for sublist in lst:\n # convert the sublist to a tuple\n tuple_sublist = tuple(sublist)\n # if the tuple is already a key in the dictionary, increment its value\n if tuple_sublist in count_dict:\n count_dict[tuple_sublist] += 1\n # otherwise, add the tuple as a new key with value 1\n else:\n count_dict[tuple_sublist] = 1\n # return the resulting dictionary\n return count_dict", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(lst):\n counter = {}\n for sublist in lst:\n t = tuple(sublist)\n if t in counter:\n counter[t] += 1\n else:\n counter[t] = 1\n return counter", "matching_cluster_idx": 7}, {"solution": "def unique_sublists(lst):\n counts = {}\n for sublist in lst:\n t = tuple(sublist)\n if t in counts:\n counts[t] += 1\n else:\n counts[t] = 1\n return counts", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(lst):\n # convert sublists to tuples\n tuple_lst = [tuple(sublst) for sublst in lst]\n # count occurrences of each tuple\n counts = {}\n for t in tuple_lst:\n if t in counts:\n counts[t] += 1\n else:\n counts[t] = 1\n return counts", "matching_cluster_idx": 7}, {"solution": "def unique_sublists(lst):\n # Initialize an empty dictionary\n sublist_counts = {}\n # Loop through each sublist in the input list\n for sublist in lst:\n # Convert the sublist into a tuple and increase its count in the dictionary\n sublist_tuple = tuple(sublist)\n sublist_counts[sublist_tuple] = sublist_counts.get(sublist_tuple, 0) + 1\n # Return the resulting dictionary\n return sublist_counts", "matching_cluster_idx": 7}, {"solution": "def unique_sublists(lst):\n counts = {}\n for sublist in lst:\n tuple_sublist = tuple(sublist)\n if tuple_sublist in counts:\n counts[tuple_sublist] += 1\n else:\n counts[tuple_sublist] = 1\n return counts", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(lst):\n sublist_counts = {}\n for sublist in lst:\n t = tuple(sublist)\n if t in sublist_counts:\n sublist_counts[t] += 1\n else:\n sublist_counts[t] = 1\n return sublist_counts", "matching_cluster_idx": 5}, {"solution": "def unique_sublists(lst):\n count_dict = {}\n for sublist in lst:\n sublist_tuple = tuple(sublist)\n if sublist_tuple in count_dict:\n count_dict[sublist_tuple] += 1\n else:\n count_dict[sublist_tuple] = 1\n return count_dict", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(lst):\n counts = {}\n for sublist in lst:\n # Convert list to tuple\n t = tuple(sublist)\n if t in counts:\n counts[t] += 1\n else:\n counts[t] = 1\n return counts", "matching_cluster_idx": 7}, {"solution": "def unique_sublists(lst):\n counts = {}\n for sublist in lst:\n tup = tuple(sublist)\n if tup not in counts:\n counts[tup] = 0\n counts[tup] += 1\n return counts", "matching_cluster_idx": 5}, {"solution": "def unique_sublists(lst):\n # create an empty dictionary\n result = {}\n # iterate over each list in the given list\n for sublist in lst:\n # convert list to a tuple\n tup = tuple(sublist)\n # if tuple already exists in dictionary, increment its value\n if tup in result:\n result[tup] += 1\n # else, initialize its value to 1\n else:\n result[tup] = 1\n # return the resulting dictionary\n return result", "matching_cluster_idx": 7}, {"solution": "def unique_sublists(lst):\n dict_count = {}\n for sublist in lst:\n tup = tuple(sublist)\n if tup not in dict_count:\n dict_count[tup] = 1\n else:\n dict_count[tup] += 1\n return dict_count", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(lst):\n # Convert lists to tuples\n tpl_lst = [tuple(sublst) for sublst in lst]\n\n # Count occurrences\n count_dict = {}\n for tpl in tpl_lst:\n if tpl in count_dict:\n count_dict[tpl] += 1\n else:\n count_dict[tpl] = 1\n return count_dict", "matching_cluster_idx": 7}, {"solution": "def unique_sublists(lst):\n # Convert each sublist to a tuple\n tuple_lst = [tuple(sublist) for sublist in lst]\n # Initialize an empty dictionary\n count_dict = {}\n # Iterate over each tuple in the list\n for tup in tuple_lst:\n # If the tuple is already in the dictionary, increment its count\n if tup in count_dict:\n count_dict[tup] += 1\n # If the tuple is not in the dictionary, add it with a count of 1\n else:\n count_dict[tup] = 1\n # Return the dictionary\n return count_dict", "matching_cluster_idx": 7}, {"solution": "def unique_sublists(lst):\n counts = {}\n for sublist in lst:\n tuple_sublist = tuple(sublist)\n if tuple_sublist in counts:\n counts[tuple_sublist] += 1\n else:\n counts[tuple_sublist] = 1\n return counts", "matching_cluster_idx": 6}]}, "Mbpp/760": {"dps": null, "dps_norm": null, "pass@1": 5.0, "profiled": []}, "Mbpp/764": {"dps": 89.38271604938271, "dps_norm": 50.833333333333336, "pass@1": 100.0, "profiled": [{"solution": "def number_ctr(input_string):\n count = 0\n for char in input_string:\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n # initialize counter\n count = 0\n # iterate over each character in the string\n for char in s:\n # if the character is a digit, increment the counter\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(input_string):\n count = 0\n for char in input_string:\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(input_str):\n count = 0\n for char in input_str:\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(string):\n count = 0\n for char in string:\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(input_string):\n count = 0\n for char in input_string:\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(input_string):\n count = 0\n for char in input_string:\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(input_str):\n num_count = 0\n for char in input_str:\n if char.isdigit():\n num_count += 1\n return num_count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(input_string):\n # Count number of digits in a given string\n count = 0\n for char in input_string:\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n count = 0\n for char in s:\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(input_string):\n # Initialize a counter to 0\n count = 0\n # Iterate through each character in the input string\n for char in input_string:\n # If the character is a digit, increment the counter\n if char.isdigit():\n count += 1\n # Return the final count of digits in the string\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(input_string):\n # Initialize a counter variable to 0\n count = 0\n\n # Iterate through each character in the string\n for char in input_string:\n # If the character is a digit, increment the counter\n if char.isdigit():\n count += 1\n\n # Return the final count of digits in the string\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n # Initialize a counter to 0\n count = 0\n # Iterate over each character in the string\n for char in s:\n # If the character is a digit, increment the counter\n if char.isdigit():\n count += 1\n # Return the total count of digits\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n \"\"\"\n Count the number of digits in a given string\n \"\"\"\n count = 0\n for char in s:\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(input_string):\n count = 0\n for char in input_string:\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(input_string):\n count = 0\n for char in input_string:\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n \"\"\"\n This function takes a string as input and returns the count of digits in it.\n\n Parameters:\n s (str): The input string\n\n Returns:\n int: The count of digits in the string\n \"\"\"\n # using list comprehension to get the digits from string\n digits = [char for char in s if char.isdigit()]\n return len(digits)", "matching_cluster_idx": 3}, {"solution": "def number_ctr(input_string):\n count = 0\n for char in input_string:\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(input_string):\n \"\"\"\n Function to count number of digits in a given string.\n \"\"\"\n count = 0\n for char in input_string:\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(input_string):\n count = 0\n for char in input_string:\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}]}, "Mbpp/766": {"dps": 71.54205607476635, "dps_norm": 60.833333333333336, "pass@1": 100.0, "profiled": [{"solution": "def pair_wise(lst):\n if len(lst) < 2:\n return []\n else:\n return [(lst[i], lst[i + 1]) for i in range(len(lst) - 1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n return [(lst[i], lst[i+1]) for i in range(len(lst)-1)]", "matching_cluster_idx": 2}, {"solution": "def pair_wise(lst):\n \"\"\"\n Function to return a list of all pairs of consecutive items in a given list.\n \"\"\"\n return [(lst[i], lst[i+1]) for i in range(len(lst)-1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n return [(lst[i], lst[i + 1]) for i in range(len(lst) - 1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n return [(lst[i], lst[i + 1]) for i in range(len(lst) - 1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(input_list):\n return [(input_list[i], input_list[i + 1]) for i in range(len(input_list) - 1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n if len(lst) < 2:\n return []\n return [(lst[i], lst[i + 1]) for i in range(len(lst) - 1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n return [(lst[i], lst[i+1]) for i in range(len(lst)-1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n \"\"\"\n This function takes a list as an input and returns a list of all pairs of consecutive items in the input list.\n\n Parameters:\n lst (list): A list of elements of any type\n\n Returns:\n list: A list of tuples, where each tuple contains a pair of consecutive items from the input list\n \"\"\"\n return [(lst[i], lst[i+1]) for i in range(len(lst)-1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n return [(lst[i], lst[i + 1]) for i in range(len(lst) - 1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n if len(lst) < 2:\n return []\n return [(lst[i], lst[i + 1]) for i in range(len(lst) - 1)]", "matching_cluster_idx": 2}, {"solution": "def pair_wise(lst):\n return [(lst[i], lst[i+1]) for i in range(len(lst)-1)]", "matching_cluster_idx": 2}, {"solution": "def pair_wise(lst):\n return [(lst[i], lst[i+1]) for i in range(len(lst)-1)]", "matching_cluster_idx": 2}, {"solution": "def pair_wise(lst):\n return [(lst[i], lst[i+1]) for i in range(len(lst) - 1)]", "matching_cluster_idx": 2}, {"solution": "def pair_wise(lst):\n \"\"\"\n Write a function to return a list of all pairs of consecutive items in a given list.\n \"\"\"\n return [(lst[i], lst[i+1]) for i in range(len(lst)-1)]", "matching_cluster_idx": 2}, {"solution": "def pair_wise(lst):\n pairs = [(lst[i], lst[i+1]) for i in range(len(lst)-1)]\n return pairs", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n return [(lst[i], lst[i + 1]) for i in range(len(lst) - 1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n return [(lst[i], lst[i+1]) for i in range(len(lst) - 1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n return [(lst[i], lst[i+1]) for i in range(len(lst)-1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n return [(lst[i], lst[i+1]) for i in range(len(lst) - 1)]", "matching_cluster_idx": 2}]}, "Mbpp/775": {"dps": 88.63999999999999, "dps_norm": 65.71428571428572, "pass@1": 100.0, "profiled": [{"solution": "def odd_position(lst):\n for i in range(1, len(lst), 2):\n if lst[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n # Iterate over the list in step of 2 starting from index 1\n for i in range(1, len(lst), 2):\n # Check if the value at the current index is odd\n if lst[i] % 2 == 0:\n # If the value is even return False\n return False\n # If all the odd indexed values are odd return True\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n return all(i % 2 != 0 for i in lst[1::2])", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n for i in range(1, len(lst), 2):\n if lst[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n for i in range(1, len(lst), 2):\n if lst[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n for i in range(len(lst)):\n if i % 2 != 0 and lst[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 2}, {"solution": "def odd_position(lst):\n for i in range(1, len(lst), 2):\n if lst[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n return all(lst[i] % 2 != 0 for i in range(1, len(lst), 2))", "matching_cluster_idx": 2}, {"solution": "def odd_position(lst):\n for i in range(1, len(lst), 2):\n if lst[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n for i in range(len(lst)):\n if i % 2 != 0 and lst[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 2}, {"solution": "def odd_position(lst):\n for i in range(1, len(lst), 2):\n if lst[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n for i in range(1, len(lst), 2):\n if lst[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(nums):\n for i in range(1, len(nums), 2):\n if nums[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n for i in range(1, len(lst), 2):\n if lst[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n # iterate over list using index and value\n for i, val in enumerate(lst):\n # check if index is odd and corresponding value is even\n if i % 2 != 0 and val % 2 == 0:\n # if condition is True, then return False\n return False\n # if loop completes without returning False, then return True\n return True", "matching_cluster_idx": 2}, {"solution": "def odd_position(lst):\n # loop over every odd index\n for i in range(1, len(lst), 2):\n # if the element at the odd index is even, return False\n if lst[i] % 2 == 0:\n return False\n # if all odd-indexed elements are odd, return True\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n \"\"\"\n This function checks if every odd index of a given list contains an odd number.\n If the condition is fulfilled, it returns True; otherwise, it returns False.\n\n Args:\n lst: List of numbers\n\n Returns:\n A boolean value indicating the condition's satisfaction\n \"\"\"\n for i in range(1, len(lst), 2):\n if lst[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n for i in range(1, len(lst), 2):\n if lst[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n for i in range(1, len(lst), 2):\n if lst[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n for i in range(1, len(lst), 2):\n if lst[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}]}, "Mbpp/777": {"dps": null, "dps_norm": null, "pass@1": 2.0, "profiled": []}, "Mbpp/781": {"dps": 85.55118110236221, "dps_norm": 73.0, "pass@1": 88.0, "profiled": [{"solution": "def count_divisors(n):\n count = 0\n i = 1\n while i * i <= n:\n if n % i == 0:\n if n / i == i:\n count += 1\n else:\n count += 2\n i += 1\n return count % 2 == 0", "matching_cluster_idx": 3}, {"solution": "def count_divisors(n):\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n if n // i == i:\n count += 1\n else:\n count += 2\n return count % 2 == 0", "matching_cluster_idx": 3}, {"solution": "def count_divisors(n):\n count = 0\n i = 1\n while i <= n:\n if (n % i == 0):\n count += 1\n i += 1\n return count % 2 == 0", "matching_cluster_idx": -1}, {"solution": "def count_divisors(n):\n \"\"\"\n This function counts the number of divisors for a given integer n.\n If the count of divisors is even, it returns True, else it returns False.\n \"\"\"\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n if n / i == i:\n count += 1\n else:\n count += 2\n return count % 2 == 0", "matching_cluster_idx": 3}, {"solution": "def count_divisors(n):\n count = 0\n i = 1\n while i * i <= n:\n if n % i == 0:\n if i == n // i:\n count += 1\n else:\n count += 2\n i += 1\n return count % 2 == 0", "matching_cluster_idx": 3}, {"solution": "def count_divisors(n):\n # Counting divisors of a number\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n count += 2\n # If n is a perfect square, decrease count by 1\n if int(n**0.5)**2 == n:\n count -= 1\n # Checking if count is even\n return count % 2 == 0", "matching_cluster_idx": 4}, {"solution": "def count_divisors(n):\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n count += 2 if i != n//i else 1\n return count % 2 == 0", "matching_cluster_idx": 3}, {"solution": "def count_divisors(n):\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n if n/i == i:\n count += 1\n else:\n count += 2\n return count % 2 == 0", "matching_cluster_idx": 3}, {"solution": "def count_divisors(n):\n \"\"\"Return True if the count of divisors is even, False otherwise.\"\"\"\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n count += 2 if i != n // i else 1\n return count % 2 == 0", "matching_cluster_idx": 3}, {"solution": "def count_divisors(n):\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n if n // i == i:\n count += 1\n else:\n count += 2\n return count % 2 == 0", "matching_cluster_idx": 3}, {"solution": "def count_divisors(num):\n count = 0\n for i in range(1, num + 1):\n if num % i == 0:\n count += 1\n return count % 2 == 0", "matching_cluster_idx": 1}, {"solution": "def count_divisors(n):\n \"\"\"\n This function takes an integer n and returns True if the count of divisors is even, otherwise False.\n \"\"\"\n count = 0\n # find all divisors up to sqrt(n)\n for i in range(1, int(n**0.5)+1):\n if n % i == 0:\n if i == n/i: # if the divisors are equal, count it only once\n count += 1\n else: # if the divisors are not equal, count them both\n count += 2\n return count % 2 == 0", "matching_cluster_idx": 3}, {"solution": "def count_divisors(n):\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n count += 2 if i != n // i else 1\n return count % 2 == 0", "matching_cluster_idx": 3}, {"solution": "def count_divisors(n):\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n if n / i == i:\n count += 1\n else:\n count += 2\n return count % 2 == 0", "matching_cluster_idx": 3}, {"solution": "def count_divisors(n):\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n if i == n / i:\n count += 1\n else:\n count += 2\n return count % 2 == 0", "matching_cluster_idx": 3}, {"solution": "def count_divisors(num):\n divisors = [i for i in range(1, num + 1) if num % i == 0]\n return len(divisors) % 2 == 0", "matching_cluster_idx": 1}, {"solution": "def count_divisors(n):\n count = 0\n for i in range(1, int(n ** 0.5) + 1):\n if n % i == 0:\n # If divisors are equal, increment count by one\n if n // i == i:\n count += 1\n # Otherwise increment count by two\n else:\n count += 2\n return count % 2 == 0", "matching_cluster_idx": 3}, {"solution": "def count_divisors(n):\n \"\"\"\n Function to check whether the count of divisors is even.\n\n Args:\n n (int): Number to check\n\n Returns:\n bool: True if the count of divisors is even, False otherwise\n \"\"\"\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n if n / i == i:\n count += 1\n else: # In this case, i and n//i are both divisors\n count += 2\n return count % 2 == 0", "matching_cluster_idx": 3}, {"solution": "def count_divisors(n):\n count = 0\n for i in range(1, int(n**0.5)+1):\n if n % i == 0:\n if i == (n / i):\n count += 1\n else: # Otherwise count both divisors\n count += 2\n return count % 2 == 0", "matching_cluster_idx": 3}, {"solution": "def count_divisors(n):\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n count += 2 if n // i != i else 1\n return count % 2 == 0", "matching_cluster_idx": 3}]}, "Mbpp/800": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 91.0, "profiled": [{"solution": "def remove_all_spaces(input_str):\n # Using the replace function to remove all occurrences of whitespace\n return input_str.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n \"\"\"\n Function to remove all whitespaces from a string.\n \"\"\"\n # using the replace() method to replace whitespaces with no space.\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(s):\n return s.replace(' ', '')", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n # The replace() method in Python replaces all occurrences of one specified phrase with another specified phrase.\n # Here, we're replacing all spaces (' ') with an empty string (''):\n return input_string.replace(' ', '')", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_str):\n # replace all occurrences of a whitespace with empty string\n return input_str.replace(' ', '')", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n return input_string.replace(' ', '')", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(s: str) -> str:\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n return input_string.replace(' ', '')", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(s):\n return s.replace(' ', '')", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(s):\n return s.replace(' ', '')", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(string):\n return string.replace(' ', '')", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(string):\n return string.replace(' ', '')", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n return input_string.replace(' ', '')", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n return input_string.replace(' ', '')", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n \"\"\"\n This function removes all whitespaces from a given string.\n\n Arguments:\n input_string : str, The input string from which whitespaces are to be removed.\n\n Returns:\n str, The string after removing all whitespaces.\n \"\"\"\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(s):\n return s.replace(' ', '')", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n return input_string.replace(' ', '')", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n return input_string.replace(' ', '')", "matching_cluster_idx": 4}]}, "Mbpp/805": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 98.0, "profiled": [{"solution": "def max_sum_list(lists):\n # Initialize max_sum and result list\n max_sum = float('-inf')\n result = []\n\n # Loop through each list in the input\n for lst in lists:\n # Calculate the sum of the list\n lst_sum = sum(lst)\n # If the sum is greater than the current max_sum, update max_sum and result\n if lst_sum > max_sum:\n max_sum = lst_sum\n result = lst\n # Return the result list\n return result", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lst):\n return max(lst, key=sum)", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n return max(lists, key=sum)", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lst):\n return max(lst, key=sum)", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lst):\n return max(lst, key=sum)", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n return max(lists, key=sum)", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n max_sum = float('-inf')\n max_list = []\n for lst in lists:\n if sum(lst) > max_sum:\n max_sum = sum(lst)\n max_list = lst\n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(list_of_lists):\n \"\"\"\n Returns the list in a list of lists whose sum of elements is the highest.\n \"\"\"\n max_sum = float('-inf')\n max_list = []\n\n for sublist in list_of_lists:\n if sum(sublist) > max_sum:\n max_sum = sum(sublist)\n max_list = sublist\n\n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lst):\n max_sum = float('-inf')\n max_sublist = None\n for sublist in lst:\n if sum(sublist) > max_sum:\n max_sum = sum(sublist)\n max_sublist = sublist\n return max_sublist", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lst):\n return max(lst, key=sum)", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lst):\n return max(lst, key=sum)", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lst_of_lst):\n return max(lst_of_lst, key=sum)", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n return max(lists, key=sum)", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n # Initiate variables to store the max sum and the corresponding list\n max_sum = float('-inf')\n max_list = []\n\n # Loop through each list in the list of lists\n for lst in lists:\n # Compute the sum of the list\n sum_lst = sum(lst)\n # If the sum is larger than max_sum, update max_sum and max_list\n if sum_lst > max_sum:\n max_sum = sum_lst\n max_list = lst\n\n # Return the list with the highest sum of elements\n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(list_of_lists):\n # Initialize the max sum and the max sum list\n max_sum = float('-inf')\n max_sum_list = []\n\n # Iterate through each sub-list\n for sublist in list_of_lists:\n sublist_sum = sum(sublist)\n # If the sum of elements in the current sub-list is greater than the max sum found so far\n if sublist_sum > max_sum:\n # Update the max sum and the max sum list\n max_sum = sublist_sum\n max_sum_list = sublist\n\n return max_sum_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n \"\"\"\n Returns the list in a list of lists whose sum of elements is the highest.\n\n Parameters:\n lists (list): A list of lists, where each sublist contains integers.\n\n Returns:\n list: The sublist with the maximum sum of its elements.\n \"\"\"\n # Use the max function to find the sublist with the maximum sum.\n # The key for the max function is the sum of the elements in each sublist.\n return max(lists, key=sum)", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n return max(lists, key=sum)", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n return max(lists, key=sum)", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n return max(lists, key=sum)", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n max_sum = float('-inf')\n max_list = []\n for lst in lists:\n if sum(lst) > max_sum:\n max_sum = sum(lst)\n max_list = lst\n return max_list", "matching_cluster_idx": 4}]}, "Mbpp/808": {"dps": 86.14035087719299, "dps_norm": 96.66666666666667, "pass@1": 100.0, "profiled": [{"solution": "def check_K(tup, k):\n \"\"\"\n This function checks if the given tuples contain the k or not.\n\n Args:\n tup (tuple): The tuple in which the element is to be found.\n k (any): The element to be found in the tuple.\n\n Returns:\n bool: True if the element is found, else False.\n \"\"\"\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(tuples, k):\n if k in tuples:\n return True\n else:\n return False", "matching_cluster_idx": 4}, {"solution": "def check_K(t, k):\n return k in t", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n \"\"\"Check if the given tuple contains the value k.\"\"\"\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n if k in tup:\n return True\n else:\n return False", "matching_cluster_idx": 4}, {"solution": "def check_K(tup, k):\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n \"\"\"\n Function to check if the given tuple contains the k.\n \"\"\"\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n \"\"\"\n Function to check if the given tuple contains the element k.\n \"\"\"\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n if k in tup:\n return True\n else:\n return False", "matching_cluster_idx": 4}, {"solution": "def check_K(tup, k):\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n \"\"\"\n This function checks if the given tuple 'tup' contains the element 'k'.\n\n Args:\n tup: A tuple of elements.\n k: The element to be checked in the tuple.\n\n Returns:\n A boolean value. True if 'k' is found in 'tup', else False.\n \"\"\"\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(tuple_values, K):\n \"\"\"\n A function to check if the given tuple contains the value K.\n \"\"\"\n return K in tuple_values", "matching_cluster_idx": 5}, {"solution": "def check_K(input_tuple, k):\n \"\"\"\n Function to check if the given tuple contains the k or not.\n \"\"\"\n if k in input_tuple:\n return True\n else:\n return False", "matching_cluster_idx": 4}, {"solution": "def check_K(t, k):\n return k in t", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(t, k):\n return k in t", "matching_cluster_idx": 5}, {"solution": "def check_K(tuples, k):\n return k in tuples", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n \"\"\"\n Function to check if the given tuple contains the k or not.\n :param tup: Tuple of integers\n :param k: Integer\n :return: Boolean value\n \"\"\"\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(t, k):\n return k in t", "matching_cluster_idx": 5}, {"solution": "def check_K(t, k):\n \"\"\"\n Function to check if the given tuple contains the k or not\n\n Args:\n t (tuple): The input tuple\n k: The element to check\n\n Returns:\n bool: True if k is in t, False otherwise\n \"\"\"\n return k in t", "matching_cluster_idx": 5}]}}} \ No newline at end of file diff --git a/results/evalperf/mistralai--Mistral-Large-Instruct-2407_vllm_temp_1.0_evalperf_results.brief.json b/results/evalperf/mistralai--Mistral-Large-Instruct-2407_vllm_temp_1.0_evalperf_results.brief.json new file mode 100644 index 0000000..0d67945 --- /dev/null +++ b/results/evalperf/mistralai--Mistral-Large-Instruct-2407_vllm_temp_1.0_evalperf_results.brief.json @@ -0,0 +1 @@ +{"date": "2024-10-19 16:29", "config": {"n_samples": 100, "temperature": 1.0, "min_correct": 10, "max_profile": 20}, "summary": {"dps": 85.58694758404829, "dps_norm": 80.65167529745199, "pass@1": 82.4322033898305}, "eval": {"HumanEval/9": {"dps": 85.37854889589906, "dps_norm": 85.0, "pass@1": 100.0, "profiled": [{"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n\n rolling_max_list = [numbers[0]]\n current_max = numbers[0]\n\n for num in numbers[1:]:\n if num > current_max:\n current_max = num\n rolling_max_list.append(current_max)\n\n return rolling_max_list", "matching_cluster_idx": 8}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n\n rolling_maximums = [numbers[0]]\n for num in numbers[1:]:\n rolling_maximums.append(max(rolling_maximums[-1], num))\n\n return rolling_maximums", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n\n max_values = [numbers[0]]\n\n for i in range(1, len(numbers)):\n max_values.append(max(max_values[-1], numbers[i]))\n\n return max_values", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\"\n From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n\n result = [numbers[0]]\n current_max = numbers[0]\n\n for num in numbers[1:]:\n if num > current_max:\n current_max = num\n result.append(current_max)\n\n return result", "matching_cluster_idx": 8}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n\n rolling_max_list = [numbers[0]]\n\n for num in numbers[1:]:\n if num > rolling_max_list[-1]:\n rolling_max_list.append(num)\n else:\n rolling_max_list.append(rolling_max_list[-1])\n\n return rolling_max_list", "matching_cluster_idx": 7}, {"solution": "from typing import List, Tuple\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n\n max_nums = [numbers[0]]\n for num in numbers[1:]:\n max_nums.append(max(max_nums[-1], num))\n\n return max_nums", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n\n Args:\n numbers (List[int]): A list of integers.\n\n Returns:\n List[int]: A list of rolling maximums.\n\n Examples:\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n\n rolling_max_list = []\n current_max = numbers[0]\n\n for num in numbers:\n if num > current_max:\n current_max = num\n rolling_max_list.append(current_max)\n\n return rolling_max_list", "matching_cluster_idx": 8}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n\n if not numbers:\n return []\n\n max_so_far = numbers[0]\n rolling_max_list = [max_so_far]\n\n for num in numbers[1:]:\n if num > max_so_far:\n max_so_far = num\n rolling_max_list.append(max_so_far)\n\n return rolling_max_list", "matching_cluster_idx": 8}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n\n rolling_max_list = [numbers[0]]\n\n for num in numbers[1:]:\n if num > rolling_max_list[-1]:\n rolling_max_list.append(num)\n else:\n rolling_max_list.append(rolling_max_list[-1])\n\n return rolling_max_list", "matching_cluster_idx": 7}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\"From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n\n result = []\n current_max = numbers[0]\n result.append(current_max)\n\n for number in numbers[1:]:\n if number > current_max:\n current_max = number\n result.append(current_max)\n\n return result", "matching_cluster_idx": 8}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n\n rolling_maximums = []\n current_max = numbers[0]\n\n for number in numbers:\n current_max = max(current_max, number)\n rolling_maximums.append(current_max)\n\n return rolling_maximums", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\"\n From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n\n rolling_max_list = [numbers[0]]\n for num in numbers[1:]:\n rolling_max_list.append(max(rolling_max_list[-1], num))\n\n return rolling_max_list", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n\n rolling_max_values = [numbers[0]]\n current_max = numbers[0]\n\n for number in numbers[1:]:\n if number > current_max:\n current_max = number\n rolling_max_values.append(current_max)\n\n return rolling_max_values", "matching_cluster_idx": 8}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n\n result = [numbers[0]]\n current_max = numbers[0]\n\n for number in numbers[1:]:\n if number > current_max:\n current_max = number\n result.append(current_max)\n\n return result", "matching_cluster_idx": 8}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n\n Args:\n numbers (List[int]): List of integers\n\n Returns:\n List[int]: List of rolling maximum elements\n\n Examples:\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n\n rolling_max_list = [numbers[0]]\n\n for number in numbers[1:]:\n rolling_max_list.append(max(rolling_max_list[-1], number))\n\n return rolling_max_list", "matching_cluster_idx": 4}, {"solution": "from typing import List, Tuple\ndef rolling_max(numbers: List[int]) -> List[int]:\n if not numbers:\n return []\n\n result = []\n current_max = numbers[0]\n\n for number in numbers:\n if number > current_max:\n current_max = number\n result.append(current_max)\n\n return result", "matching_cluster_idx": 8}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n\n rolling_max_list = []\n current_max = numbers[0]\n rolling_max_list.append(current_max)\n\n for number in numbers[1:]:\n if number > current_max:\n current_max = number\n rolling_max_list.append(current_max)\n\n return rolling_max_list", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n max_numbers = []\n current_max = None\n for num in numbers:\n if current_max is None or num > current_max:\n current_max = num\n max_numbers.append(current_max)\n return max_numbers", "matching_cluster_idx": 7}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\"\n From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n\n result = [numbers[0]]\n current_max = numbers[0]\n\n for number in numbers[1:]:\n if number > current_max:\n current_max = number\n result.append(current_max)\n\n return result", "matching_cluster_idx": 8}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\"\n From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n\n rolling_max_list = [numbers[0]]\n current_max = numbers[0]\n\n for num in numbers[1:]:\n if num > current_max:\n current_max = num\n rolling_max_list.append(current_max)\n\n return rolling_max_list", "matching_cluster_idx": 8}]}, "HumanEval/0": {"dps": 73.8953488372093, "dps_norm": 77.85714285714286, "pass@1": 100.0, "profiled": [{"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n if abs(numbers[i] - numbers[j]) < threshold:\n return True\n return False", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n for i in range(len(numbers)):\n for j in range(i+1, len(numbers)):\n if abs(numbers[i] - numbers[j]) < threshold:\n return True\n return False", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n if abs(numbers[i] - numbers[j]) < threshold:\n return True\n return False", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n if abs(numbers[i] - numbers[j]) < threshold:\n return True\n return False", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n if abs(numbers[i] - numbers[j]) < threshold:\n return True\n return False", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n sorted_numbers = sorted(numbers) # Sort numbers to easily compare adjacent elements\n for i in range(len(sorted_numbers) - 1):\n if abs(sorted_numbers[i] - sorted_numbers[i + 1]) < threshold:\n return True\n return False", "matching_cluster_idx": 2}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\"Check if in the given list of numbers, there are any two numbers closer to each other than the given threshold.\"\"\"\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n if abs(numbers[i] - numbers[j]) < threshold:\n return True\n return False", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\"\n Check if in the given list of numbers, there are any two numbers closer to each other than the given threshold.\n\n :param numbers: List of numbers to check\n :param threshold: Maximum distance between two numbers to consider them close\n :return: True if there are two numbers closer than the threshold, False otherwise\n\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n numbers.sort()\n for i in range(len(numbers) - 1):\n if abs(numbers[i] - numbers[i + 1]) < threshold:\n return True\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\"\n Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n\n Args:\n numbers (List[float]): A list of float numbers.\n threshold (float): The threshold to check if two numbers are close.\n\n Returns:\n bool: True if any two numbers are closer than the threshold, False otherwise.\n\n Examples:\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n if abs(numbers[i] - numbers[j]) < threshold:\n return True\n return False", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n numbers.sort() # Sorting the numbers to check only adjacent elements\n for i in range(len(numbers) - 1):\n if abs(numbers[i] - numbers[i + 1]) < threshold:\n return True\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\"Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n\n # Sort the numbers to make it easier to check distances between adjacent elements\n sorted_numbers = sorted(numbers)\n\n # Compare each pair of adjacent numbers\n for i in range(len(sorted_numbers) - 1):\n if abs(sorted_numbers[i] - sorted_numbers[i + 1]) < threshold:\n return True\n\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n numbers.sort()\n for i in range(1, len(numbers)):\n if abs(numbers[i] - numbers[i - 1]) < threshold:\n return True\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n if abs(numbers[i] - numbers[j]) < threshold:\n return True\n return False", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n # Sorting the numbers allows us to only compare each number with its adjacent neighbor\n numbers.sort()\n\n # Compare each pair of adjacent numbers\n for i in range(1, len(numbers)):\n if abs(numbers[i] - numbers[i - 1]) < threshold:\n return True\n\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n numbers.sort()\n for i in range(len(numbers) - 1):\n if abs(numbers[i] - numbers[i + 1]) < threshold:\n return True\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n if abs(numbers[i] - numbers[j]) < threshold:\n return True\n return False", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\"\n Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n numbers.sort()\n for i in range(len(numbers) - 1):\n if abs(numbers[i + 1] - numbers[i]) < threshold:\n return True\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n if abs(numbers[i] - numbers[j]) < threshold:\n return True\n return False", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n # Sort the list\n numbers.sort()\n\n # Iterate over the sorted list and compare adjacent elements\n for i in range(len(numbers) - 1):\n if abs(numbers[i] - numbers[i + 1]) < threshold:\n return True\n\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n # Sort the numbers to easily compare adjacent elements\n numbers.sort()\n\n # Iterate through the list and check if the difference between any two adjacent numbers is less than the threshold\n for i in range(1, len(numbers)):\n if abs(numbers[i] - numbers[i - 1]) < threshold:\n return True\n\n return False", "matching_cluster_idx": 3}]}, "HumanEval/4": {"dps": 46.80379746835443, "dps_norm": 80.0, "pass@1": 100.0, "profiled": [{"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n mean = sum(numbers) / len(numbers)\n mad = sum(abs(x - mean) for x in numbers) / len(numbers)\n return mad", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if not numbers:\n raise ValueError(\"The input list should not be empty.\")\n\n mean = sum(numbers) / len(numbers)\n absolute_deviations = [abs(x - mean) for x in numbers]\n mad = sum(absolute_deviations) / len(numbers)\n return mad", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n\n mean = sum(numbers) / len(numbers)\n absolute_deviations = [abs(x - mean) for x in numbers]\n mad = sum(absolute_deviations) / len(absolute_deviations)\n\n return mad", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if not numbers:\n raise ValueError(\"The list is empty\")\n\n # Calculate the mean of the dataset\n mean = sum(numbers) / len(numbers)\n\n # Calculate absolute deviations from the mean\n absolute_deviations = [abs(num - mean) for num in numbers]\n\n # Calculate the mean of the absolute deviations\n mad = sum(absolute_deviations) / len(absolute_deviations)\n\n return mad", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n mean = sum(numbers) / len(numbers)\n mad = sum(abs(x - mean) for x in numbers) / len(numbers)\n return mad", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if not numbers:\n return 0.0\n\n mean = sum(numbers) / len(numbers)\n mad = sum(abs(x - mean) for x in numbers) / len(numbers)\n return mad", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if not numbers:\n raise ValueError(\"The input list is empty\")\n\n mean = sum(numbers) / len(numbers)\n absolute_deviations = [abs(x - mean) for x in numbers]\n mad = sum(absolute_deviations) / len(absolute_deviations)\n\n return mad", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if not numbers:\n return 0.0\n\n mean = sum(numbers) / len(numbers)\n absolute_deviations = [abs(num - mean) for num in numbers]\n mad = sum(absolute_deviations) / len(numbers)\n\n return mad", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\"\n For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if not numbers:\n raise ValueError(\"The list of numbers is empty.\")\n\n mean = sum(numbers) / len(numbers)\n mad = sum(abs(x - mean) for x in numbers) / len(numbers)\n return mad", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n\n # Check if the list is empty\n if not numbers:\n raise ValueError(\"The list of numbers should not be empty.\")\n\n mean = sum(numbers) / len(numbers)\n absolute_deviations = [abs(num - mean) for num in numbers]\n mad = sum(absolute_deviations) / len(numbers)\n\n return mad", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if len(numbers) == 0:\n return 0.0\n\n # Calculate the mean of the list\n mean_value = sum(numbers) / len(numbers)\n\n # Calculate the absolute deviations from the mean\n absolute_deviations = [abs(num - mean_value) for num in numbers]\n\n # Calculate the mean of these deviations\n mad = sum(absolute_deviations) / len(absolute_deviations)\n\n return mad", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n mean = sum(numbers) / len(numbers)\n mad = sum(abs(x - mean) for x in numbers) / len(numbers)\n return mad", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n # Check if the list is empty\n if not numbers:\n raise ValueError(\"The input list is empty\")\n\n # Calculate the mean of the input list\n mean_value = sum(numbers) / len(numbers)\n\n # Calculate absolute deviations from the mean and their mean\n abs_deviations = [abs(x - mean_value) for x in numbers]\n mean_abs_deviation = sum(abs_deviations) / len(numbers)\n\n return mean_abs_deviation", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n mean = sum(numbers) / len(numbers)\n mad = sum(abs(x - mean) for x in numbers) / len(numbers)\n return mad", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if len(numbers) == 0:\n raise ValueError(\"The list of numbers is empty\")\n\n mean = sum(numbers) / len(numbers)\n mad = sum(abs(x - mean) for x in numbers) / len(numbers)\n return mad", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\"\n For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if not numbers:\n raise ValueError(\"The list of numbers is empty\")\n\n mean = sum(numbers) / len(numbers)\n absolute_deviations = [abs(num - mean) for num in numbers]\n mad = sum(absolute_deviations) / len(numbers)\n\n return mad", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if not numbers:\n raise ValueError(\"The list of numbers is empty\")\n\n mean_value = sum(numbers) / len(numbers)\n absolute_deviations = [abs(x - mean_value) for x in numbers]\n mad = sum(absolute_deviations) / len(absolute_deviations)\n\n return mad", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n\n if not numbers:\n raise ValueError(\"The list of numbers is empty\")\n\n mean = sum(numbers) / len(numbers)\n absolute_deviations = [abs(x - mean) for x in numbers]\n mad = sum(absolute_deviations) / len(numbers)\n\n return mad", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if not numbers:\n raise ValueError(\"The input list must not be empty\")\n\n mean = sum(numbers) / len(numbers)\n abs_deviations = [abs(x - mean) for x in numbers]\n mad = sum(abs_deviations) / len(abs_deviations)\n return mad", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if not numbers:\n return 0.0\n\n mean = sum(numbers) / len(numbers)\n absolute_deviations = [abs(x - mean) for x in numbers]\n mad = sum(absolute_deviations) / len(numbers)\n\n return mad", "matching_cluster_idx": 3}]}, "HumanEval/16": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\"\n Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lower case to make it case insensitive\n string = string.lower()\n # Use a set to store distinct characters\n distinct_chars = set(string)\n # Return the number of distinct characters\n return len(distinct_chars)", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of.\n\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lowercase to ensure case insensitivity\n lowercase_string = string.lower()\n # Use a set to automatically handle unique characters\n distinct_characters = set(lowercase_string)\n # Return the number of distinct characters\n return len(distinct_characters)", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lower case to handle case insensitivity\n string = string.lower()\n\n # Use a set to collect unique characters\n unique_characters = set(string)\n\n # Return the number of unique characters\n return len(unique_characters)", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\"\n Given a string, find out how many distinct characters (regardless of case) does it consist of.\n\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lower case to ignore case distinctions\n string = string.lower()\n\n # Use a set to track distinct characters\n distinct_chars = set(string)\n\n # The number of distinct characters is the length of the set\n return len(distinct_chars)", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\"\n Given a string, find out how many distinct characters (regardless of case) it consists of.\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n distinct_chars = set(string.lower())\n return len(distinct_chars)", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of.\n\n Args:\n string (str): Input string to be analyzed.\n\n Returns:\n int: Number of distinct characters in the string.\n\n Examples:\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lower case to ensure case insensitivity\n string = string.lower()\n\n # Use a set to keep track of distinct characters\n distinct_characters = set(string)\n\n # Return the number of distinct characters\n return len(distinct_characters)", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lowercase to ensure case insensitivity\n lowercase_string = string.lower()\n\n # Use a set to keep track of unique characters\n unique_characters = set(lowercase_string)\n\n # Return the number of unique characters\n return len(unique_characters)", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\"\n Given a string, find out how many distinct characters (regardless of case) does it consist of.\n\n Args:\n string (str): The input string.\n\n Returns:\n int: The number of distinct characters in the string.\n\n Examples:\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Normalize the string to lower case to ignore case\n normalized_string = string.lower()\n # Use a set to collect distinct characters\n distinct_characters = set(normalized_string)\n # Return the number of distinct characters\n return len(distinct_characters)", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\"Given a string, find out how many distinct characters (regardless of case) does it consist of\n\n Args:\n string (str): The input string\n\n Returns:\n int: Number of distinct characters\n\n Examples:\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lowercase to handle case insensitivity\n string = string.lower()\n\n # Use a set to find distinct characters\n distinct_characters = set(string)\n\n # Return the count of distinct characters\n return len(distinct_characters)", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of.\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lowercase to ignore case sensitivity\n string = string.lower()\n\n # Use a set to track unique characters\n distinct_characters = set(string)\n\n # Return the number of distinct characters\n return len(distinct_characters)", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lower case to make it case insensitive\n lower_case_string = string.lower()\n\n # Use a set to collect unique characters\n distinct_characters = set(lower_case_string)\n\n # Return the number of distinct characters\n return len(distinct_characters)", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lowercase to ensure case-insensitivity\n string = string.lower()\n # Use a set to track distinct characters\n distinct_chars = set(string)\n # Return the number of distinct characters\n return len(distinct_chars)", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Normalize the string to the same case\n normalized_string = string.lower()\n # Use a set to track distinct characters\n distinct_chars = set(normalized_string)\n # Return the number of distinct characters\n return len(distinct_chars)", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lower case to make the function case-insensitive\n string = string.lower()\n\n # Create a set to store distinct characters\n distinct_chars = set(string)\n\n # Return the number of distinct characters\n return len(distinct_chars)", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lowercase to ensure case insensitivity\n string = string.lower()\n # Use a set to find distinct characters\n distinct_characters = set(string)\n # Return the number of distinct characters\n return len(distinct_characters)", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\"\n Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lower case to ignore case sensitivity\n lower_string = string.lower()\n\n # Use a set to keep track of distinct characters\n distinct_characters = set(lower_string)\n\n # Return the number of distinct characters\n return len(distinct_characters)", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert string to lower case to ignore case\n string = string.lower()\n\n # Use a set to store distinct characters\n distinct_characters = set(string)\n\n # Return the number of distinct characters\n return len(distinct_characters)", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lowercase to ensure case insensitivity\n lower_string = string.lower()\n # Use a set to track distinct characters\n distinct_chars = set(lower_string)\n # Return the count of distinct characters\n return len(distinct_chars)", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\"\n Given a string, find out how many distinct characters (regardless of case) it consists of.\n\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n distinct_chars = set(string.lower())\n return len(distinct_chars)", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lowercase to ensure case insensitivity\n lowercase_string = string.lower()\n # Use a set to track distinct characters\n distinct_characters = set(lowercase_string)\n # Return the number of distinct characters\n return len(distinct_characters)", "matching_cluster_idx": 8}]}, "HumanEval/20": {"dps": 96.05326876513317, "dps_norm": 97.22222222222223, "pass@1": 100.0, "profiled": [{"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n if len(numbers) < 2:\n raise ValueError(\"List must contain at least two numbers.\")\n\n # Sort the list to ensure we compare adjacent elements\n numbers.sort()\n\n min_diff = float('inf')\n closest_pair = (float('inf'), float('inf'))\n\n # Compare adjacent elements to find the smallest difference\n for i in range(len(numbers) - 1):\n diff = abs(numbers[i] - numbers[i + 1])\n if diff < min_diff:\n min_diff = diff\n closest_pair = (numbers[i], numbers[i + 1])\n\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\"From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n # Ensure the list has at least two elements\n if len(numbers) < 2:\n raise ValueError(\"List must contain at least two elements\")\n\n # Sort the list\n numbers.sort()\n\n # Initialize variables to track the closest pair\n min_diff = float('inf')\n closest_pair = (float('-inf'), float('inf'))\n\n # Compare each pair of adjacent numbers\n for i in range(len(numbers) - 1):\n diff = numbers[i + 1] - numbers[i]\n if diff < min_diff:\n min_diff = diff\n closest_pair = (numbers[i], numbers[i + 1])\n\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n # Initialize variables to store the closest pair and their difference\n closest_pair = (numbers[0], numbers[1])\n min_diff = abs(numbers[0] - numbers[1])\n\n # Iterate over all pairs in the list\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n current_diff = abs(numbers[i] - numbers[j])\n\n # Update closest_pair and min_diff if a closer pair is found\n if current_diff < min_diff:\n min_diff = current_diff\n closest_pair = (min(numbers[i], numbers[j]), max(numbers[i], numbers[j]))\n\n return closest_pair", "matching_cluster_idx": 3}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n if len(numbers) < 2:\n raise ValueError(\"The list must contain at least two numbers.\")\n\n numbers.sort()\n min_diff = float('inf')\n closest_pair = None\n\n for i in range(len(numbers) - 1):\n diff = numbers[i + 1] - numbers[i]\n if diff < min_diff:\n min_diff = diff\n closest_pair = (numbers[i], numbers[i + 1])\n\n if closest_pair is None:\n raise ValueError(\"No pair found with a valid difference.\")\n\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n # Sort the list to make sure we are comparing adjacent elements\n numbers.sort()\n\n # Initialize the closest pair and the minimum difference\n closest_pair = (numbers[0], numbers[1])\n min_diff = abs(numbers[1] - numbers[0])\n\n # Iterate through the sorted list to find the pair with the minimum difference\n for i in range(1, len(numbers) - 1):\n diff = abs(numbers[i + 1] - numbers[i])\n if diff < min_diff:\n min_diff = diff\n closest_pair = (numbers[i], numbers[i + 1])\n\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n if len(numbers) < 2:\n raise ValueError(\"The list must contain at least two elements\")\n\n numbers.sort()\n min_diff = float('inf')\n closest_pair = None\n\n for i in range(len(numbers) - 1):\n diff = numbers[i + 1] - numbers[i]\n if diff < min_diff:\n min_diff = diff\n closest_pair = (numbers[i], numbers[i + 1])\n\n if closest_pair is None:\n raise ValueError(\"Unable to find a valid pair of closest elements\")\n\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n if len(numbers) < 2:\n raise ValueError(\"The list must contain at least two numbers.\")\n\n # Initialize minimum difference to infinity\n min_diff = float('inf')\n closest_pair = (numbers[0], numbers[1])\n\n # Sort the list first to find adjacent closest elements more efficiently\n numbers.sort()\n\n # Iterate through the list to find the closest pair\n for i in range(len(numbers) - 1):\n diff = numbers[i + 1] - numbers[i]\n if diff < min_diff:\n min_diff = diff\n closest_pair = (numbers[i], numbers[i + 1])\n\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n if len(numbers) < 2:\n raise ValueError(\"The list must contain at least two numbers.\")\n\n # Sort the list to easily find the closest numbers\n numbers.sort()\n\n # Initialize variables to keep track of the smallest difference and the closest pair\n min_diff = float('inf')\n closest_pair = (numbers[0], numbers[1])\n\n # Loop through the list to find the closest pair\n for i in range(len(numbers) - 1):\n diff = numbers[i + 1] - numbers[i]\n if diff < min_diff:\n min_diff = diff\n closest_pair = (numbers[i], numbers[i + 1])\n\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n\n # Ensure the list has at least two elements\n if len(numbers) < 2:\n raise ValueError(\"The list must contain at least two elements.\")\n\n # Initialize variables to hold the closest pair and the minimum difference\n min_diff = float('inf')\n closest_pair = (None, None)\n\n # Sort the list to make it easier to find the closest pair\n numbers.sort()\n\n # Iterate through the sorted list and find the closest pair\n for i in range(len(numbers) - 1):\n diff = numbers[i + 1] - numbers[i]\n if diff < min_diff:\n min_diff = diff\n closest_pair = (numbers[i], numbers[i + 1])\n\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n\n # Ensure there are at least two numbers\n if len(numbers) < 2:\n raise ValueError(\"The list must contain at least two numbers\")\n\n # Sort the numbers\n numbers.sort()\n\n # Initialize variables to hold the closest pair and the minimum difference\n closest_pair = (numbers[0], numbers[1])\n min_diff = abs(numbers[1] - numbers[0])\n\n # Iterate through the list to find the closest pair\n for i in range(1, len(numbers) - 1):\n current_diff = abs(numbers[i+1] - numbers[i])\n if current_diff < min_diff:\n min_diff = current_diff\n closest_pair = (numbers[i], numbers[i+1])\n\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n\n # Check if the list has at least two elements\n if len(numbers) < 2:\n raise ValueError(\"The list must contain at least two elements.\")\n\n # Initialize variables to keep track of the closest pair and the minimum difference\n closest_pair = (float('inf'), float('inf'))\n min_diff = float('inf')\n\n # Sort the list of numbers\n numbers.sort()\n\n # Iterate over the list to find the closest pair\n for i in range(1, len(numbers)):\n diff = numbers[i] - numbers[i-1]\n if diff < min_diff:\n min_diff = diff\n closest_pair = (numbers[i-1], numbers[i])\n\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n if len(numbers) < 2:\n raise ValueError(\"List must contain at least two elements\")\n\n # Sort the numbers\n sorted_numbers = sorted(numbers)\n\n # Initialize the closest pair and minimum distance\n closest_pair = (sorted_numbers[0], sorted_numbers[1])\n min_distance = abs(sorted_numbers[1] - sorted_numbers[0])\n\n # Find the closest pair\n for i in range(1, len(sorted_numbers) - 1):\n distance = abs(sorted_numbers[i + 1] - sorted_numbers[i])\n if distance < min_distance:\n min_distance = distance\n closest_pair = (sorted_numbers[i], sorted_numbers[i + 1])\n\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n if len(numbers) < 2:\n raise ValueError(\"List must contain at least two numbers\")\n\n # Sorting the numbers to easily find the closest pair\n numbers.sort()\n\n # Initialize variables to hold the closest pair\n min_diff = float('inf')\n closest_pair = (float('inf'), float('inf'))\n\n # Iterate through the sorted list to find the pair with the smallest difference\n for i in range(len(numbers) - 1):\n diff = numbers[i + 1] - numbers[i]\n if diff < min_diff:\n min_diff = diff\n closest_pair = (numbers[i], numbers[i + 1])\n\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\"\n From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n \"\"\"\n # Sort the list to make it easier to find closest pairs\n numbers.sort()\n\n min_distance = float('inf')\n closest_pair = (None, None)\n\n # Iterate through the sorted list to find the minimum distance between any two numbers\n for i in range(len(numbers) - 1):\n distance = numbers[i + 1] - numbers[i]\n if distance < min_distance:\n min_distance = distance\n closest_pair = (numbers[i], numbers[i + 1])\n\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n # Ensure that there are at least two numbers in the list\n assert len(numbers) >= 2, \"List must contain at least two numbers.\"\n\n # Sort the list to make it easier to find the closest elements\n numbers.sort()\n\n # Initialize the minimum difference and the closest pair\n min_diff = float('inf')\n closest_pair = (numbers[0], numbers[1])\n\n # Iterate through the sorted list and find the minimum difference\n for i in range(len(numbers) - 1):\n diff = numbers[i + 1] - numbers[i]\n if diff < min_diff:\n min_diff = diff\n closest_pair = (numbers[i], numbers[i + 1])\n\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n if len(numbers) < 2:\n raise ValueError(\"List should contain at least two numbers.\")\n\n numbers.sort() # Sort the list to facilitate comparison\n min_diff = float('inf')\n closest_pair = None\n\n for i in range(len(numbers) - 1):\n diff = numbers[i + 1] - numbers[i]\n if diff < min_diff:\n min_diff = diff\n closest_pair = (numbers[i], numbers[i + 1])\n\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n # Sort the numbers first to make the comparison easier\n numbers.sort()\n\n # Initialize the closest pair and the minimum difference\n min_diff = float('inf')\n closest_pair = (numbers[0], numbers[1])\n\n # Compare each pair of adjacent numbers in the sorted list\n for i in range(len(numbers) - 1):\n diff = numbers[i + 1] - numbers[i]\n if diff < min_diff:\n min_diff = diff\n closest_pair = (numbers[i], numbers[i + 1])\n\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\"\n From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n # Sort the list of numbers\n numbers.sort()\n\n # Initialize the minimum difference and the closest pair\n min_diff = float('inf')\n closest_pair = (None, None)\n\n # Iterate over the sorted list and find the pair with the smallest difference\n for i in range(len(numbers) - 1):\n diff = numbers[i + 1] - numbers[i]\n if diff < min_diff:\n min_diff = diff\n closest_pair = (numbers[i], numbers[i + 1])\n\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\"\n From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n \"\"\"\n if len(numbers) < 2:\n raise ValueError(\"The list must contain at least two numbers.\")\n\n # Sort the list of numbers\n numbers.sort()\n\n # Initialize variables to track the closest pair and the minimum difference\n closest_pair = (numbers[0], numbers[1])\n min_diff = abs(numbers[1] - numbers[0])\n\n # Iterate over the sorted list to find the closest pair\n for i in range(1, len(numbers) - 1):\n diff = abs(numbers[i + 1] - numbers[i])\n if diff < min_diff:\n min_diff = diff\n closest_pair = (numbers[i], numbers[i + 1])\n\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n if len(numbers) < 2:\n raise ValueError(\"List should contain at least two numbers.\")\n\n # Sort the list of numbers\n numbers.sort()\n\n # Initialize the minimum difference and the closest pair\n min_diff = float('inf')\n closest_pair = (None, None)\n\n # Iterate over the sorted list to find the closest pair\n for i in range(len(numbers) - 1):\n diff = numbers[i + 1] - numbers[i]\n if diff < min_diff:\n min_diff = diff\n closest_pair = (numbers[i], numbers[i + 1])\n\n return closest_pair", "matching_cluster_idx": 8}]}, "HumanEval/24": {"dps": 72.34693877551021, "dps_norm": 32.5, "pass@1": 99.0, "profiled": [{"solution": "import math\ndef largest_divisor(n: int) -> int:\n \"\"\"\n For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n >>> largest_divisor(100)\n 50\n >>> largest_divisor(7)\n 1\n >>> largest_divisor(1)\n -1\n \"\"\"\n if n <= 1:\n return -1 # Assuming the function should return -1 if n is 1 or less, as no divisor < n exists\n\n # Start from the largest possible divisor (n//2) and go downwards\n for i in range(n // 2, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 3}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n for i in range(n-1, 0, -1):\n if n % i == 0:\n return i\n return 1 # In case n is 1, it has no divisor smaller than itself, so return 1.", "matching_cluster_idx": 1}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n.\n >>> largest_divisor(15)\n 5\n \"\"\"\n for i in range(n-1, 0, -1):\n if n % i == 0:\n return i\n return 1", "matching_cluster_idx": 1}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n.\n >>> largest_divisor(15)\n 5\n >>> largest_divisor(100)\n 50\n >>> largest_divisor(7)\n 1\n >>> largest_divisor(10)\n 5\n \"\"\"\n for i in range(n-1, 0, -1):\n if n % i == 0:\n return i\n return 1", "matching_cluster_idx": 1}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\"\n For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n if n <= 1:\n raise ValueError(\"n must be greater than 1\")\n\n largest = 1\n for i in range(2, n):\n if n % i == 0:\n largest = i\n\n return largest", "matching_cluster_idx": 1}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\"\n For a given number n, find the largest number that divides n evenly, smaller than n.\n\n >>> largest_divisor(15)\n 5\n \"\"\"\n for i in range(n-1, 0, -1):\n if n % i == 0:\n return i\n return 1 # In case n is 1, which is an edge case.", "matching_cluster_idx": 1}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n >>> largest_divisor(17)\n 1\n >>> largest_divisor(10)\n 5\n \"\"\"\n for i in range(n - 1, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 1}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\"\n For a given number n, find the largest number that divides n evenly, smaller than n\n\n >>> largest_divisor(15)\n 5\n \"\"\"\n\n # Start checking from n - 1 down to 1\n for i in range(n - 1, 0, -1):\n if n % i == 0:\n return i\n return 1 # If no other divisor is found, return 1 as a safe fallback", "matching_cluster_idx": 1}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\"\n For a given number n, find the largest number that divides n evenly, smaller than n.\n >>> largest_divisor(15)\n 5\n \"\"\"\n if n <= 1:\n raise ValueError(\"Input should be greater than 1\")\n\n for i in range(n-1, 0, -1):\n if n % i == 0:\n return i\n\n return 1 # If there are no divisors, which is technically not possible as 1 is always a divisor", "matching_cluster_idx": 1}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\"\n For a given number n, find the largest number that divides n evenly, smaller than n.\n >>> largest_divisor(15)\n 5\n \"\"\"\n # Start from the largest possible divisor less than n\n for i in range(n-1, 0, -1):\n if n % i == 0:\n return i\n return 1 # In case n is 1, the only divisor smaller than n is 1", "matching_cluster_idx": 1}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n if n <= 1:\n raise ValueError(\"n must be greater than 1\")\n\n for i in range(n//2, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 3}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n for i in range(n-1, 0, -1):\n if n % i == 0:\n return i\n return 1", "matching_cluster_idx": 0}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\"\n For a given number n, find the largest number that divides n evenly, smaller than n.\n\n >>> largest_divisor(15)\n 5\n >>> largest_divisor(10)\n 5\n >>> largest_divisor(7)\n 1\n >>> largest_divisor(100)\n 50\n \"\"\"\n # Iterate backward from (n-1) to 1 and find the first number that divides n evenly\n for i in range(n-1, 0, -1):\n if n % i == 0:\n return i\n\n # In case there is no divisor (which should not happen for n > 1), return 1\n return 1", "matching_cluster_idx": 1}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\"For a given number n, find the largest number that divides n evenly, smaller than n.\n >>> largest_divisor(15)\n 5\n \"\"\"\n # The largest divisor of n that is less than n itself must be less than or equal to n // 2\n for i in range(n//2, 0, -1):\n if n % i == 0:\n return i\n # If n is 1, there is no number smaller than n that can divide it\n return None", "matching_cluster_idx": 3}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n.\n >>> largest_divisor(15)\n 5\n \"\"\"\n # Start checking from the largest number smaller than n\n for i in range(n-1, 0, -1):\n if n % i == 0:\n return i\n return 1", "matching_cluster_idx": 1}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n for i in range(n-1, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 1}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\"\n For a given number n, find the largest number that divides n evenly, smaller than n.\n\n >>> largest_divisor(15)\n 5\n \"\"\"\n for i in range(n // 2, 0, -1):\n if n % i == 0:\n return i\n return 1", "matching_cluster_idx": 3}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n if n <= 1:\n raise ValueError(\"Input must be greater than 1\")\n\n for i in range(n // 2, 0, -1):\n if n % i == 0:\n return i\n\n return 1", "matching_cluster_idx": 4}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\"For a given number n, find the largest number that divides n evenly, smaller than n\n\n >>> largest_divisor(15)\n 5\n >>> largest_divisor(10)\n 5\n >>> largest_divisor(23)\n Traceback (most recent call last):\n ...\n ValueError: No divisor found.\n >>> largest_divisor(49)\n 7\n >>> largest_divisor(100)\n 50\n \"\"\"\n if n <= 1:\n raise ValueError(\"n must be greater than 1.\")\n\n for i in range(n//2, 0, -1):\n if n % i == 0:\n return i\n\n raise ValueError(\"No divisor found.\")", "matching_cluster_idx": 3}, {"solution": "import math\ndef largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n for i in range(n - 1, 0, -1):\n if n % i == 0:\n return i\n\n return 1", "matching_cluster_idx": 1}]}, "HumanEval/26": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n counts = {}\n for number in numbers:\n if number in counts:\n counts[number] += 1\n else:\n counts[number] = 1\n\n result = [number for number in numbers if counts[number] == 1]\n return result", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n from collections import Counter\n # Create a frequency dictionary for the numbers\n freq = Counter(numbers)\n\n # Filter out elements that appear more than once\n result = [num for num in numbers if freq[num] == 1]\n\n return result", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\"\n From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n from collections import Counter\n\n # count occurrences of each number in the list\n counts = Counter(numbers)\n\n # filter out numbers that occur more than once\n result = [num for num in numbers if counts[num] == 1]\n\n return result", "matching_cluster_idx": 3}, {"solution": "from typing import List\nfrom collections import Counter\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n # Create a Counter object to count occurrences of each element\n counts = Counter(numbers)\n\n # List comprehension to filter out elements that occur more than once\n return [num for num in numbers if counts[num] == 1]", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n count = {}\n result = []\n\n # Count occurrences of each number\n for num in numbers:\n if num in count:\n count[num] += 1\n else:\n count[num] = 1\n\n # Add numbers that occur only once to result list\n for num in numbers:\n if count[num] == 1:\n result.append(num)\n\n return result", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n # Count the frequency of each number in the list\n counts = {}\n for num in numbers:\n if num in counts:\n counts[num] += 1\n else:\n counts[num] = 1\n\n # Create a list of numbers that occur only once\n result = [num for num in numbers if counts[num] == 1]\n\n return result", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n from collections import Counter\n\n count = Counter(numbers)\n result = [num for num in numbers if count[num] == 1]\n\n return result", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\"From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n count_dict = {}\n for num in numbers:\n count_dict[num] = count_dict.get(num, 0) + 1\n\n result = []\n for num in numbers:\n if count_dict[num] == 1:\n result.append(num)\n\n return result", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n counter = {}\n for num in numbers:\n if num in counter:\n counter[num] += 1\n else:\n counter[num] = 1\n\n result = []\n for num in numbers:\n if counter[num] == 1:\n result.append(num)\n\n return result", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n from collections import Counter\n # Count the occurrence of each number\n count = Counter(numbers)\n\n # Keep only elements that occur exactly once\n result = [num for num in numbers if count[num] == 1]\n\n return result", "matching_cluster_idx": 3}, {"solution": "from typing import List\nfrom collections import Counter\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n # Count the occurrence of each number in the list\n count = Counter(numbers)\n\n # Create a new list with elements that occur only once\n result = [num for num in numbers if count[num] == 1]\n\n return result", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n # Create a dictionary to count occurrences of each element\n count_dict = {}\n for num in numbers:\n if num in count_dict:\n count_dict[num] += 1\n else:\n count_dict[num] = 1\n\n # Create a list to store the result\n result = []\n for num in numbers:\n if count_dict[num] == 1:\n result.append(num)\n\n return result", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\"\n From a list of integers, remove all elements that occur more than once.\n Keep the order of elements left the same as in the input.\n\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n >>> remove_duplicates([1, 2, 3, 1, 2, 3])\n []\n >>> remove_duplicates([1, 2, 3, 4, 5])\n [1, 2, 3, 4, 5]\n >>> remove_duplicates([1, 1, 1, 1, 1])\n []\n \"\"\"\n from collections import Counter\n\n counts = Counter(numbers)\n result = [num for num in numbers if counts[num] == 1]\n\n return result", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n >>> remove_duplicates([1, 1, 1, 1, 1])\n []\n >>> remove_duplicates([1, 2, 3, 4])\n [1, 2, 3, 4]\n \"\"\"\n count = {}\n for number in numbers:\n count[number] = count.get(number, 0) + 1\n\n result = [number for number in numbers if count[number] == 1]\n return result", "matching_cluster_idx": 3}, {"solution": "from typing import List\nfrom collections import Counter\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n counts = Counter(numbers)\n result = [num for num in numbers if counts[num] == 1]\n return result", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\"From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n from collections import Counter\n\n # Count the occurrences of each number\n counter = Counter(numbers)\n\n # Create a list of numbers that occur exactly once\n result = [num for num in numbers if counter[num] == 1]\n\n return result", "matching_cluster_idx": 3}, {"solution": "from typing import List\nfrom collections import Counter\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n counter = Counter(numbers)\n return [num for num in numbers if counter[num] == 1]", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n counts = {}\n for number in numbers:\n counts[number] = counts.get(number, 0) + 1\n\n result = [num for num in numbers if counts[num] == 1]\n return result", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n from collections import Counter\n\n # Count the occurrence of each number\n count = Counter(numbers)\n\n # Return the list of elements that occur only once, maintaining order\n return [num for num in numbers if count[num] == 1]", "matching_cluster_idx": 3}, {"solution": "from typing import List\nfrom collections import Counter\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\"\n From a list of integers, remove all elements that occur more than once.\n Keep the order of elements the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n # Use Counter to count occurrences of each number\n counts = Counter(numbers)\n\n # Return a list with elements that occur only once in the original order\n return [num for num in numbers if counts[num] == 1]", "matching_cluster_idx": 3}]}, "HumanEval/31": {"dps": 97.46835443037975, "dps_norm": 87.5, "pass@1": 100.0, "profiled": [{"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\"\"\"\n if n <= 1:\n return False\n if n == 2:\n return True\n if n % 2 == 0:\n return False\n\n for i in range(3, int(n**0.5) + 1, 2):\n if n % i == 0:\n return False\n\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\"\"\"\n\n # Check if the number is less than 2 (not prime)\n if n <= 1:\n return False\n\n # Check if the number is 2 or 3 (both are prime)\n if n in (2, 3):\n return True\n\n # Check if the number is divisible by 2 or 3 (not prime)\n if n % 2 == 0 or n % 3 == 0:\n return False\n\n # Check for factors from 5 up to the square root of n\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\"\"\"\n if n <= 1:\n return False\n elif n <= 3:\n return True\n elif n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n if n == 2:\n return True # 2 is the only even prime number\n if n % 2 == 0:\n return False # all other even numbers are not primes\n\n # range starts from 3 and only needs to go up to the square root of n\n for i in range(3, int(n**0.5) + 1, 2):\n if n % i == 0:\n return False\n\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while (i * i) <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\"\"\"\n\n # Special cases\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n\n # Check for factors from 5 to sqrt(n)\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\"\"\"\n if n <= 1:\n return False\n elif n <= 3:\n return True\n elif n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n elif n <= 3:\n return True\n elif n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while (i * i) <= n:\n if (n % i == 0) or (n % (i + 2) == 0):\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\"\"\"\n if n <= 1:\n return False\n elif n <= 3:\n return True\n elif n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n\n A prime number is a natural number greater than 1 that has no positive divisors other than 1 and itself.\n The function checks the divisibility of the number up to its square root to determine if it is prime.\n\n Args:\n n (int): The number to check.\n\n Returns:\n bool: True if n is prime, False otherwise.\n\n Examples:\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n if n == 2:\n return True\n if n % 2 == 0:\n return False\n for i in range(3, int(n**0.5) + 1, 2):\n if n % i == 0:\n return False\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"\n Return true if a given number is prime, and false otherwise.\n\n A prime number is a natural number greater than 1 that has no positive divisors other than 1 and itself.\n\n :param n: An integer to check for primality.\n :return: True if the number is prime, False otherwise.\n\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n\n if n <= 1:\n return False\n elif n <= 3:\n return True\n elif n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\"\"\"\n if n <= 1:\n return False\n if n == 2:\n return True # 2 is the only even prime number\n if n % 2 == 0:\n return False # other even numbers are not prime\n for i in range(3, int(n**0.5) + 1, 2):\n if n % i == 0:\n return False\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n if n == 2:\n return True\n if n % 2 == 0:\n return False\n for i in range(3, int(n**0.5) + 1, 2):\n if n % i == 0:\n return False\n return True", "matching_cluster_idx": 6}, {"solution": "import math\ndef is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n\n if n <= 1:\n return False\n elif n == 2:\n return True\n elif n % 2 == 0:\n return False\n else:\n for i in range(3, int(math.sqrt(n)) + 1, 2):\n if n % i == 0:\n return False\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n if n == 2:\n return True\n if n % 2 == 0:\n return False\n for i in range(3, int(n**0.5) + 1, 2):\n if n % i == 0:\n return False\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n if n == 2:\n return True\n if n % 2 == 0:\n return False\n for i in range(3, int(n**0.5) + 1, 2):\n if n % i == 0:\n return False\n return True", "matching_cluster_idx": 6}]}, "HumanEval/33": {"dps": 97.22222222222223, "dps_norm": 81.81818181818181, "pass@1": 100.0, "profiled": [{"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indices that are not divisible by three, while its values at the indices that are divisible by three are equal\n to the values of the corresponding indices of l, but sorted.\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n # Extract elements at indices divisible by 3\n elements_to_sort = [l[i] for i in range(0, len(l), 3)]\n # Sort these elements\n elements_to_sort.sort()\n\n # Create a new list to store the result\n result = l.copy()\n\n # Replace elements at indices divisible by 3 with the sorted elements\n for i, value in enumerate(elements_to_sort):\n result[i * 3] = value\n\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indices that are not divisible by three, while its values at the indices that are divisible by three are equal\n to the values of the corresponding indices of l, but sorted.\n\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n # Collect the elements at indices divisible by 3\n divisible_by_three = [l[i] for i in range(len(l)) if i % 3 == 0]\n\n # Sort the collected elements\n sorted_divisible_by_three = sorted(divisible_by_three)\n\n # Create the result list\n l_prime = l[:]\n index = 0\n for i in range(len(l)):\n if i % 3 == 0:\n l_prime[i] = sorted_divisible_by_three[index]\n index += 1\n\n return l_prime", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indices that are not divisible by three, while its values at the indices that are divisible by three are equal\n to the values of the corresponding indices of l, but sorted.\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n # Extract elements at indices divisible by three\n divisible_by_three = sorted([l[i] for i in range(len(l)) if i % 3 == 0])\n\n # Replace elements at those indices in the original list\n result = l[:]\n index = 0\n for i in range(len(result)):\n if i % 3 == 0:\n result[i] = divisible_by_three[index]\n index += 1\n\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list) -> list:\n \"\"\"\n This function takes a list l and returns a list l' such that\n l' is identical to l in the indices that are not divisible by three, while its values at the indices that are divisible by three are equal\n to the values of the corresponding indices of l, but sorted.\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n # Extract values at indices divisible by 3\n values_to_sort = [l[i] for i in range(len(l)) if i % 3 == 0]\n\n # Sort these values\n sorted_values = sorted(values_to_sort)\n\n # Create a copy of the original list to avoid modifying it directly\n result = l.copy()\n\n # Replace the values at the indices divisible by 3 with sorted values\n sorted_index = 0\n for i in range(len(result)):\n if i % 3 == 0:\n result[i] = sorted_values[sorted_index]\n sorted_index += 1\n\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indices that are not divisible by three, while its values at the indices that are divisible by three are equal\n to the values of the corresponding indices of l, but sorted.\n\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n # Extract elements at indices divisible by 3\n elements_at_third = [l[i] for i in range(0, len(l), 3)]\n\n # Sort these elements\n elements_at_third_sorted = sorted(elements_at_third)\n\n # Create a copy of the input list to modify\n result = l[:]\n\n # Replace the elements at indices divisible by 3 with the sorted elements\n idx = 0\n for i in range(0, len(l), 3):\n result[i] = elements_at_third_sorted[idx]\n idx += 1\n\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n # Extract elements at indices divisible by three\n elements_to_sort = [l[i] for i in range(0, len(l), 3)]\n\n # Sort these elements\n sorted_elements = sorted(elements_to_sort)\n\n # Create the new list based on the criteria\n result = l[:]\n for idx, val in enumerate(sorted_elements):\n result[idx * 3] = val\n\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indices that are not divisible by three, while its values at the indices that are divisible by three are equal\n to the values of the corresponding indices of l, but sorted.\n\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n # Extract the values at indices divisible by three\n div_three_indices = [i for i in range(len(l)) if i % 3 == 0]\n values_to_sort = [l[i] for i in div_three_indices]\n\n # Sort the values\n sorted_values = sorted(values_to_sort)\n\n # Create a copy of the original list\n l_prime = l.copy()\n\n # Replace the values at the indices divisible by three with the sorted values\n for idx, val in zip(div_three_indices, sorted_values):\n l_prime[idx] = val\n\n return l_prime", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list) -> list:\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n # Extract elements at indices divisible by 3\n divisible_by_three = [l[i] for i in range(0, len(l), 3)]\n # Sort these elements\n divisible_by_three_sorted = sorted(divisible_by_three)\n\n # Create a copy of the original list to manipulate\n l_prime = l.copy()\n\n # Replace elements at indices divisible by 3 with the sorted elements\n idx = 0\n for i in range(0, len(l_prime), 3):\n l_prime[i] = divisible_by_three_sorted[idx]\n idx += 1\n\n return l_prime", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list) -> list:\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n # Extract elements at indices divisible by 3\n divisible_by_three = [l[i] for i in range(len(l)) if i % 3 == 0]\n # Sort the extracted elements\n divisible_by_three.sort()\n\n # Create a copy of the original list\n result = l.copy()\n\n # Replace elements at indices divisible by 3 with the sorted elements\n idx = 0\n for i in range(len(l)):\n if i % 3 == 0:\n result[i] = divisible_by_three[idx]\n idx += 1\n\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n # Extract elements at indices divisible by 3\n elements_to_sort = [l[i] for i in range(0, len(l), 3)]\n\n # Sort these elements\n elements_to_sort.sort()\n\n # Create a copy of the original list\n result = l[:]\n\n # Replace elements at indices divisible by 3 with the sorted elements\n for idx, value in zip(range(0, len(l), 3), elements_to_sort):\n result[idx] = value\n\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n # Extract elements at positions divisible by three\n elements_to_sort = [l[i] for i in range(0, len(l), 3)]\n\n # Sort the extracted elements\n elements_to_sort.sort()\n\n # Replace the original elements with the sorted ones\n l_prime = l[:]\n for sorted_idx, original_idx in enumerate(range(0, len(l), 3)):\n l_prime[original_idx] = elements_to_sort[sorted_idx]\n\n return l_prime", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indices that are not divisible by three, while its values at the indices that are divisible by three are equal\n to the values of the corresponding indices of l, but sorted.\n\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n # Extract the values at indices divisible by 3\n to_sort = [l[i] for i in range(len(l)) if i % 3 == 0]\n to_sort.sort() # Sort the extracted values\n\n # Create a new list l' by copying values from l but replacing values at indices divisible by 3\n l_prime = l[:]\n sort_index = 0\n for i in range(len(l_prime)):\n if i % 3 == 0:\n l_prime[i] = to_sort[sort_index]\n sort_index += 1\n\n return l_prime", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list) -> list:\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n # Extract elements at indices divisible by 3\n div_by_three = [l[i] for i in range(len(l)) if i % 3 == 0]\n # Sort these elements\n div_by_three.sort()\n\n # Create a copy of the original list to modify\n result = l[:]\n\n # Replace elements at indices divisible by 3 with the sorted elements\n idx = 0\n for i in range(len(result)):\n if i % 3 == 0:\n result[i] = div_by_three[idx]\n idx += 1\n\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indices that are not divisible by three, while its values at the indices that are divisible by three are equal\n to the values of the corresponding indices of l, but sorted.\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n # Extract values at indices divisible by 3\n to_sort = [l[i] for i in range(len(l)) if i % 3 == 0]\n\n # Sort these values\n sorted_values = sorted(to_sort)\n\n # Create a copy of the original list\n result = l[:]\n\n # Replace the values at indices divisible by 3 with the sorted values\n j = 0\n for i in range(len(l)):\n if i % 3 == 0:\n result[i] = sorted_values[j]\n j += 1\n\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"\n This function takes a list l and returns a list l' such that\n l' is identical to l at indices that are not divisible by three, while its values at the indices that are divisible by three are equal\n to the values of the corresponding indices of l, but sorted.\n \"\"\"\n # Extract elements at indices divisible by 3\n elements_to_sort = [l[i] for i in range(0, len(l), 3)]\n\n # Sort the extracted elements\n elements_to_sort.sort()\n\n # Create a copy of the original list to modify\n l_prime = l.copy()\n\n # Replace elements in l_prime at indices divisible by 3 with the sorted elements\n index_sorted = 0\n for i in range(0, len(l), 3):\n l_prime[i] = elements_to_sort[index_sorted]\n index_sorted += 1\n\n return l_prime", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list) -> list:\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n indices = [i for i in range(len(l)) if i % 3 == 0]\n values = sorted([l[i] for i in indices])\n\n l_prime = l[:]\n for sorted_index, original_index in enumerate(indices):\n l_prime[original_index] = values[sorted_index]\n\n return l_prime", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list) -> list:\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indices that are not divisible by three, while its values at the indices that are divisible by three are equal\n to the values of the corresponding indices of l, but sorted.\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n # Extract elements at indices divisible by three\n divisible_by_three = [l[i] for i in range(len(l)) if i % 3 == 0]\n\n # Sort these elements\n divisible_by_three.sort()\n\n # Create a copy of the original list to modify\n result = l[:]\n\n # Replace elements at indices divisible by three with sorted values\n idx = 0\n for i in range(len(l)):\n if i % 3 == 0:\n result[i] = divisible_by_three[idx]\n idx += 1\n\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list) -> list:\n \"\"\"\n This function takes a list l and returns a list l' such that\n l' is identical to l in the indices that are not divisible by three, while its values at the indices that are divisible by three are equal\n to the values of the corresponding indices of l, but sorted.\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n # Extract the elements at indices divisible by three\n div_by_three = [l[i] for i in range(len(l)) if i % 3 == 0]\n # Sort these elements\n sorted_div_by_three = sorted(div_by_three)\n\n # Create a copy of the original list\n result = l.copy()\n\n # Replace elements at indices divisible by three with the sorted elements\n idx = 0\n for i in range(len(l)):\n if i % 3 == 0:\n result[i] = sorted_div_by_three[idx]\n idx += 1\n\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"\n This function takes a list l and returns a list l' such that\n l' is identical to l in the indices that are not divisible by three, while its values at the indices that are divisible by three are equal\n to the values of the corresponding indices of l, but sorted.\n\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n # Extract elements at indices divisible by 3\n div_three_indices = [i for i in range(len(l)) if i % 3 == 0]\n div_three_values = [l[i] for i in div_three_indices]\n\n # Sort these values\n div_three_values_sorted = sorted(div_three_values)\n\n # Create a copy of the original list\n l_copy = l.copy()\n\n # Replace the values at indices divisible by 3 with sorted values\n for idx, new_value in zip(div_three_indices, div_three_values_sorted):\n l_copy[idx] = new_value\n\n return l_copy", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indices that are not divisible by three, while its values at the indices that are divisible by three are equal\n to the values of the corresponding indices of l, but sorted.\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n # Extract the elements that are at indices divisible by 3\n divisible_by_three = [l[i] for i in range(0, len(l), 3)]\n # Sort these elements\n sorted_elements = sorted(divisible_by_three)\n\n # Create the result list\n result = l.copy()\n # Replace the elements at indices divisible by 3 with the sorted elements\n idx = 0\n for i in range(0, len(l), 3):\n result[i] = sorted_elements[idx]\n idx += 1\n\n return result", "matching_cluster_idx": 8}]}, "HumanEval/34": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list) -> list:\n \"\"\"Return sorted unique elements in a list.\n\n Args:\n l (list): A list of elements.\n\n Returns:\n list: A list of sorted unique elements.\n\n Examples:\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list) -> list:\n \"\"\"\n Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list) -> list:\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list) -> list:\n \"\"\"Return sorted unique elements in a list\n\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list) -> list:\n \"\"\"Return sorted unique elements in a list.\n\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list) -> list:\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n # Use a set to find unique elements\n unique_elements = set(l)\n # Convert the set back to a list and sort it\n sorted_unique_elements = sorted(unique_elements)\n return sorted_unique_elements", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list) -> list:\n \"\"\"Return sorted unique elements in a list.\n\n Args:\n l (list): The input list containing elements.\n\n Returns:\n list: A new list with sorted unique elements.\n\n Example:\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n # Use a set to remove duplicates and then sort the result\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list) -> list:\n \"\"\"Return sorted unique elements in a list.\n\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list) -> list:\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n # Convert the list to a set to remove duplicates\n unique_elements = set(l)\n # Convert the set back to a list and sort it\n sorted_unique_elements = sorted(unique_elements)\n return sorted_unique_elements", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}]}, "HumanEval/36": {"dps": 96.77419354838709, "dps_norm": 71.42857142857143, "pass@1": 100.0, "profiled": [{"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n\n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n for num in range(n):\n if num % 11 == 0 or num % 13 == 0:\n count += str(num).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n\n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count_sevens = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count_sevens += str(i).count('7')\n return count_sevens", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n\n Args:\n n (int): The upper limit (exclusive) for the range of integers to check.\n\n Returns:\n int: The count of digit 7 appearances in integers meeting the criteria.\n\n Examples:\n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n for num in range(n):\n if num % 11 == 0 or num % 13 == 0:\n count += str(num).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\"\"\"\n count_sevens = 0\n\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count_sevens += str(i).count('7')\n\n return count_sevens", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count_7s = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count_7s += str(i).count('7')\n return count_7s", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n\n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n for num in range(n):\n if num % 11 == 0 or num % 13 == 0:\n count += str(num).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n\n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count_sevens = 0\n\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count_sevens += str(i).count('7')\n\n return count_sevens", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\"\"\"\n count_sevens = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count_sevens += str(i).count('7')\n return count_sevens", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n for i in range(1, n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}]}, "HumanEval/37": {"dps": 95.94108019639934, "dps_norm": 92.0, "pass@1": 100.0, "profiled": [{"solution": "def sort_even(l: list):\n \"\"\"\n This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Extract even indexed elements\n even_indexed_elements = [l[i] for i in range(len(l)) if i % 2 == 0]\n\n # Sort the even indexed elements\n sorted_even_elements = sorted(even_indexed_elements)\n\n # Create the new list with sorted even indexed elements\n result = l[:]\n even_index = 0\n for i in range(len(l)):\n if i % 2 == 0:\n result[i] = sorted_even_elements[even_index]\n even_index += 1\n\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n even_indices = l[::2]\n even_indices.sort()\n l[::2] = even_indices\n return l", "matching_cluster_idx": 9}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indices, while its values at the even indices are equal\n to the values of the even indices of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Extract the elements at even indices\n even_indices_elements = [l[i] for i in range(0, len(l), 2)]\n # Sort the elements at even indices\n even_indices_elements.sort()\n\n # Create the result list by replacing even indices with the sorted values\n l_prime = l.copy()\n for idx, val in enumerate(even_indices_elements):\n l_prime[2 * idx] = val\n\n return l_prime", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"\n This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indices, while its values at the even indices are equal\n to the values of the even indices of l, but sorted.\n\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n >>> sort_even([9, 8, 7, 6, 5, 4, 3, 2, 1, 0])\n [0, 8, 1, 6, 2, 4, 3, 2, 5, 0]\n \"\"\"\n even_indices = [i for i in range(len(l)) if i % 2 == 0]\n sorted_evens = sorted(l[i] for i in even_indices)\n\n l_prime = l[:]\n for idx, val in zip(even_indices, sorted_evens):\n l_prime[idx] = val\n\n return l_prime", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indices, while its values at the even indices are equal\n to the values of the even indices of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n\n # Extract even index elements\n even_index_elements = [l[i] for i in range(0, len(l), 2)]\n\n # Sort even index elements\n sorted_even_elements = sorted(even_index_elements)\n\n # Replace even index elements with sorted values\n l_copy = l[:]\n even_index = 0\n for i in range(0, len(l_copy), 2):\n l_copy[i] = sorted_even_elements[even_index]\n even_index += 1\n\n return l_copy", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list) -> list:\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indices, while its values at the even indices are equal\n to the values of the even indices of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n even_indices_values = sorted(l[::2]) # Extract and sort values at even indices\n result = l.copy()\n\n # Replace values at even indices with sorted values\n result[::2] = even_indices_values\n\n return result", "matching_cluster_idx": 9}, {"solution": "def sort_even(l: list) -> list:\n \"\"\"\n This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Extract even indexed elements\n even_indexed_elements = [l[i] for i in range(0, len(l), 2)]\n\n # Sort the extracted even indexed elements\n sorted_even_elements = sorted(even_indexed_elements)\n\n # Reconstruct the list with sorted even index elements\n result = l.copy()\n even_index = 0\n for i in range(0, len(l), 2):\n result[i] = sorted_even_elements[even_index]\n even_index += 1\n\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n\n # Extract even index elements\n even_index_elements = [l[i] for i in range(len(l)) if i % 2 == 0]\n\n # Sort the extracted even index elements\n even_index_elements_sorted = sorted(even_index_elements)\n\n # Create a copy of the original list\n l_copy = l[:]\n\n # Replace even index elements with sorted elements\n index = 0\n for i in range(len(l_copy)):\n if i % 2 == 0:\n l_copy[i] = even_index_elements_sorted[index]\n index += 1\n\n return l_copy", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Extract elements at even indices\n even_index_elements = [l[i] for i in range(len(l)) if i % 2 == 0]\n # Sort the extracted elements\n sorted_even_index_elements = sorted(even_index_elements)\n\n # Replace elements at even indices with sorted elements\n result = l.copy()\n index = 0\n for i in range(0, len(l), 2):\n result[i] = sorted_even_index_elements[index]\n index += 1\n\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list) -> list:\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Extract even index elements\n even_index_elements = [l[i] for i in range(len(l)) if i % 2 == 0]\n\n # Sort even index elements\n even_index_elements.sort()\n\n # Create a copy of the original list\n result = l[:]\n\n # Replace the even index elements in the copied list with sorted ones\n even_index = 0\n for i in range(len(result)):\n if i % 2 == 0:\n result[i] = even_index_elements[even_index]\n even_index += 1\n\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"\n This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indices, while its values at the even indices are equal\n to the values of the even indices of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n\n # Extract even indexed elements\n even_indexed_elements = [l[i] for i in range(0, len(l), 2)]\n\n # Sort the extracted elements\n even_indexed_elements.sort()\n\n # Create a new list with sorted even indexed elements and odd indexed elements unchanged\n result = l.copy()\n for i, val in enumerate(even_indexed_elements):\n result[2 * i] = val\n\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list) -> list:\n \"\"\"\n This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indices, while its values at the even indices are equal\n to the values of the even indices of l, but sorted.\n\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Extract the elements at the even indices\n even_indexed_elements = [l[i] for i in range(len(l)) if i % 2 == 0]\n\n # Sort the even indexed elements\n even_indexed_elements.sort()\n\n # Replace the even indexed elements in the original list with sorted elements\n result = l.copy()\n even_index = 0\n for i in range(len(l)):\n if i % 2 == 0:\n result[i] = even_indexed_elements[even_index]\n even_index += 1\n\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Extract even-indexed elements and sort them\n even_indices = sorted([l[i] for i in range(0, len(l), 2)])\n\n # Create a new list with sorted even-indexed elements and original odd-indexed elements\n result = l.copy()\n for i, val in zip(range(0, len(l), 2), even_indices):\n result[i] = val\n\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indices, while its values at the even indices are equal\n to the values of the even indices of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Extract even-indexed elements and sort them\n even_elements = sorted(l[::2])\n\n # Replace the even-indexed elements with the sorted ones\n l[::2] = even_elements\n\n return l", "matching_cluster_idx": 9}, {"solution": "def sort_even(l: list) -> list:\n \"\"\"\n This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indices, while its values at the even indices are equal\n to the values of the even indices of l, but sorted.\n\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Extract the even indexed elements\n even_indexed_elements = [l[i] for i in range(len(l)) if i % 2 == 0]\n # Sort the even indexed elements\n even_indexed_elements.sort()\n\n # Create the resulting list with sorted even indexed elements\n result = l.copy()\n even_index = 0\n for i in range(len(l)):\n if i % 2 == 0:\n result[i] = even_indexed_elements[even_index]\n even_index += 1\n\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indices, while its values at the even indices are equal\n to the values of the even indices of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Extract even indexed elements\n even_indexed_elements = [l[i] for i in range(len(l)) if i % 2 == 0]\n\n # Sort the even indexed elements\n even_indexed_elements.sort()\n\n # Reconstruct the list with sorted even indexed elements\n sorted_even_list = []\n even_idx = 0\n for i in range(len(l)):\n if i % 2 == 0:\n sorted_even_list.append(even_indexed_elements[even_idx])\n even_idx += 1\n else:\n sorted_even_list.append(l[i])\n\n return sorted_even_list", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Extract the even-indexed elements\n even_indexed_elements = [l[i] for i in range(0, len(l), 2)]\n\n # Sort the even-indexed elements\n even_indexed_elements_sorted = sorted(even_indexed_elements)\n\n # Reconstruct the list with sorted even-indexed elements and the original odd-indexed elements\n result = l.copy() # Make a copy of the original list to modify\n even_index = 0\n for i in range(0, len(l), 2):\n result[i] = even_indexed_elements_sorted[even_index]\n even_index += 1\n\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n even_indices = l[::2]\n even_indices.sort()\n l[::2] = even_indices\n return l", "matching_cluster_idx": 9}, {"solution": "def sort_even(l: list) -> list:\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indices, while its values at the even indices are equal\n to the values of the even indices of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Extract the even-indexed elements\n even_index_elements = [l[i] for i in range(0, len(l), 2)]\n\n # Sort the even-indexed elements\n sorted_even_index_elements = sorted(even_index_elements)\n\n # Create a new list with sorted even-indexed elements and the same odd-indexed elements\n result = l[:]\n even_index = 0\n for i in range(0, len(l), 2):\n result[i] = sorted_even_index_elements[even_index]\n even_index += 1\n\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"\n This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indices, while its values at the even indices are equal\n to the values of the even indices of l, but sorted.\n\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Extract even-indexed elements\n even_indexed_elements = [l[i] for i in range(0, len(l), 2)]\n # Sort the even-indexed elements\n sorted_even_elements = sorted(even_indexed_elements)\n\n # Construct the result list by merging sorted even-indexed elements and original odd-indexed elements\n result = []\n even_index = 0\n for i in range(len(l)):\n if i % 2 == 0:\n result.append(sorted_even_elements[even_index])\n even_index += 1\n else:\n result.append(l[i])\n\n return result", "matching_cluster_idx": 8}]}, "HumanEval/49": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 17.0, "profiled": [{"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\n\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\n\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n result = pow(2, n, p)\n return result", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"\n Return 2^n modulo p (be aware of numerics).\n\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n result = pow(2, n, p)\n return result", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int):\n \"\"\"Return 2^n modulo p (be aware of numerics).\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n # Edge case where n = 0\n if n == 0:\n return 1 % p\n\n result = 1\n base = 2\n\n while n > 0:\n if n % 2 == 1:\n result = (result * base) % p\n base = (base * base) % p\n n //= 2\n\n return result", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n result = pow(2, n, p)\n return result", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n result = pow(2, n, p)\n return result", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"\n Return 2^n modulo p (be aware of numerics).\n\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n result = pow(2, n, p)\n return result", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n # Using Python's built-in pow function for efficient modular exponentiation\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n result = pow(2, n, p)\n return result", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int):\n \"\"\"Return 2^n modulo p (be aware of numerics).\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n result = pow(2, n, p)\n return result", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n if n == 0:\n return 1 % p\n\n result = 1\n base = 2\n\n while n > 0:\n # If n is odd, multiply the current result by base and take modulo p\n if n % 2 == 1:\n result = (result * base) % p\n\n # Square the base and take modulo p\n base = (base * base) % p\n\n # Divide n by 2\n n = n // 2\n\n return result", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n result = pow(2, n, p)\n return result", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"\n Return 2^n modulo p (be aware of numerics).\n\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n result = pow(2, n, p)\n return result", "matching_cluster_idx": 4}]}, "HumanEval/51": {"dps": 96.13526570048309, "dps_norm": 75.0, "pass@1": 100.0, "profiled": [{"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n \"\"\"\n vowels = \"aeiouAEIOU\"\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes a string and returns the string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = 'aeiouAEIOU'\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = 'aeiouAEIOU'\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\\\nghijklm\")\n 'bcdf\\\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = 'aeiouAEIOU'\n return ''.join(char for char in text if char not in vowels)", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n return ''.join(char for char in text if char not in vowels)", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n return ''.join(char for char in text if char not in vowels)", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = 'aeiouAEIOU'\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\\\nghijklm\")\n 'bcdf\\\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes a string and returns the string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n return ''.join(char for char in text if char not in vowels)", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes a string and returns the string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\\\nghijklm\")\n 'bcdf\\\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = 'aeiouAEIOU'\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = 'aeiouAEIOU'\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "import re\ndef remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes a string and returns the string without vowels.\n\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\\\nghijklm\")\n 'bcdf\\\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = 'aeiouAEIOU'\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes a string and returns the string without vowels.\n\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\\\nghijklm\")\n 'bcdf\\\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = 'aeiouAEIOU'\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes a string and returns the string without vowels.\n\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\\\nghijklm\")\n 'bcdf\\\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = 'aeiouAEIOU'\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\\\nghijklm\")\n 'bcdf\\\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}]}, "HumanEval/54": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 90.0, "profiled": [{"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')\n True\n >>> same_chars('abcd', 'dddddddabc')\n True\n >>> same_chars('dddddddabc', 'abcd')\n True\n >>> same_chars('eabcd', 'dddddddabc')\n False\n >>> same_chars('abcd', 'dddddddabce')\n False\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')\n False\n \"\"\"\n # Create sets from both strings\n set_s0 = set(s0)\n set_s1 = set(s1)\n\n # Compare the two sets\n return set_s0 == set_s1", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')\n True\n >>> same_chars('abcd', 'dddddddabc')\n True\n >>> same_chars('dddddddabc', 'abcd')\n True\n >>> same_chars('eabcd', 'dddddddabc')\n False\n >>> same_chars('abcd', 'dddddddabce')\n False\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')\n False\n \"\"\"\n # Convert strings to sets to eliminate duplicates and sort them\n return sorted(set(s0)) == sorted(set(s1))", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str):\n \"\"\"\n Check if two words have the same characters.\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')\n True\n >>> same_chars('abcd', 'dddddddabc')\n True\n >>> same_chars('dddddddabc', 'abcd')\n True\n >>> same_chars('eabcd', 'dddddddabc')\n False\n >>> same_chars('abcd', 'dddddddabce')\n False\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')\n False\n \"\"\"\n # Remove duplicate characters and sort them to allow comparison\n unique_chars_s0 = ''.join(sorted(set(s0)))\n unique_chars_s1 = ''.join(sorted(set(s1)))\n\n # Compare the unique character sets\n return unique_chars_s0 == unique_chars_s1", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \"\"\"\n # Create character sets for each string\n set_s0 = set(s0)\n set_s1 = set(s1)\n\n # Check if the sets are equal\n return set_s0 == set_s1", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \"\"\"\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')\n True\n >>> same_chars('abcd', 'dddddddabc')\n True\n >>> same_chars('dddddddabc', 'abcd')\n True\n >>> same_chars('eabcd', 'dddddddabc')\n False\n >>> same_chars('abcd', 'dddddddabce')\n False\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')\n False\n \"\"\"\n # Remove duplicates by converting to a set, then compare the sets\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \"\"\"\n # Create sets of characters from both strings\n set_s0 = set(s0)\n set_s1 = set(s1)\n\n # Check if both sets have the same characters\n return set_s0 == set_s1", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str):\n \"\"\"\n Check if two words have the same characters.\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')\n True\n >>> same_chars('abcd', 'dddddddabc')\n True\n >>> same_chars('dddddddabc', 'abcd')\n True\n >>> same_chars('eabcd', 'dddddddabc')\n False\n >>> same_chars('abcd', 'dddddddabce')\n False\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')\n False\n \"\"\"\n # Remove duplicate characters and sort both strings\n s0 = ''.join(sorted(set(s0)))\n s1 = ''.join(sorted(set(s1)))\n\n # Compare if both sorted strings are the same\n return s0 == s1", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')\n True\n >>> same_chars('abcd', 'dddddddabc')\n True\n >>> same_chars('dddddddabc', 'abcd')\n True\n >>> same_chars('eabcd', 'dddddddabc')\n False\n >>> same_chars('abcd', 'dddddddabce')\n False\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')\n False\n \"\"\"\n return sorted(set(s0)) == sorted(set(s1))", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')\n True\n >>> same_chars('abcd', 'dddddddabc')\n True\n >>> same_chars('dddddddabc', 'abcd')\n True\n >>> same_chars('eabcd', 'dddddddabc')\n False\n >>> same_chars('abcd', 'dddddddabce')\n False\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')\n False\n \"\"\"\n # Create sets to capture unique characters in both strings\n set_s0 = set(s0)\n set_s1 = set(s1)\n\n # Compare sets to check if both strings contain exactly the same characters\n return set_s0 == set_s1", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \"\"\"\n # Using sets to get unique characters and comparing\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')\n True\n >>> same_chars('abcd', 'dddddddabc')\n True\n >>> same_chars('dddddddabc', 'abcd')\n True\n >>> same_chars('eabcd', 'dddddddabc')\n False\n >>> same_chars('abcd', 'dddddddabce')\n False\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')\n False\n \"\"\"\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')\n True\n >>> same_chars('abcd', 'dddddddabc')\n True\n >>> same_chars('dddddddabc', 'abcd')\n True\n >>> same_chars('eabcd', 'dddddddabc')\n False\n >>> same_chars('abcd', 'dddddddabce')\n False\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')\n False\n \"\"\"\n # Create sets of unique characters for each string\n set_s0 = set(s0)\n set_s1 = set(s1)\n\n # Return True if the sets are equal, otherwise False\n return set_s0 == set_s1", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \"\"\"\n # Convert strings to sets to eliminate duplicates and compare\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \"\"\"\n # Convert the strings into sets of characters and compare\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')\n True\n >>> same_chars('abcd', 'dddddddabc')\n True\n >>> same_chars('dddddddabc', 'abcd')\n True\n >>> same_chars('eabcd', 'dddddddabc')\n False\n >>> same_chars('abcd', 'dddddddabce')\n False\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')\n False\n \"\"\"\n # Convert strings to sets to get unique characters, and then compare the sets.\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')\n True\n >>> same_chars('abcd', 'dddddddabc')\n True\n >>> same_chars('dddddddabc', 'abcd')\n True\n >>> same_chars('eabcd', 'dddddddabc')\n False\n >>> same_chars('abcd', 'dddddddabce')\n False\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')\n False\n \"\"\"\n return sorted(set(s0)) == sorted(set(s1))", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')\n True\n >>> same_chars('abcd', 'dddddddabc')\n True\n >>> same_chars('dddddddabc', 'abcd')\n True\n >>> same_chars('eabcd', 'dddddddabc')\n False\n >>> same_chars('abcd', 'dddddddabce')\n False\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')\n False\n \"\"\"\n # Create sets of unique characters from each string\n set0 = set(s0)\n set1 = set(s1)\n\n # Compare the sets\n return set0 == set1", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')\n True\n >>> same_chars('abcd', 'dddddddabc')\n True\n >>> same_chars('dddddddabc', 'abcd')\n True\n >>> same_chars('eabcd', 'dddddddabc')\n False\n >>> same_chars('abcd', 'dddddddabce')\n False\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')\n False\n \"\"\"\n return sorted(set(s0)) == sorted(set(s1))", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')\n True\n >>> same_chars('abcd', 'dddddddabc')\n True\n >>> same_chars('dddddddabc', 'abcd')\n True\n >>> same_chars('eabcd', 'dddddddabc')\n False\n >>> same_chars('abcd', 'dddddddabce')\n False\n >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')\n False\n \"\"\"\n return set(s0) == set(s1)", "matching_cluster_idx": 6}]}, "HumanEval/58": {"dps": 92.89370078740157, "dps_norm": 84.16666666666666, "pass@1": 100.0, "profiled": [{"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n # Converting both lists to sets to get unique elements\n set1 = set(l1)\n set2 = set(l2)\n\n # Find intersection of two sets\n common_elements = set1.intersection(set2)\n\n # Convert the result to a sorted list and return\n return sorted(list(common_elements))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list) -> list:\n \"\"\"Return sorted unique common elements for two lists.\"\"\"\n return sorted(set(l1) & set(l2))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n # Convert the lists to sets to remove duplicates and find the intersection\n set_l1 = set(l1)\n set_l2 = set(l2)\n\n # Find the common elements by taking the intersection of the sets\n common_elements = set_l1.intersection(set_l2)\n\n # Convert the set back to a sorted list\n result = sorted(list(common_elements))\n\n return result", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n\n \"\"\"\n # Convert lists to sets to find unique common elements and convert back to list\n common_elements = list(set(l1) & set(l2))\n # Sort the common elements\n common_elements.sort()\n return common_elements", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n\n \"\"\"\n return sorted(set(l1) & set(l2))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n set1 = set(l1)\n set2 = set(l2)\n\n common_elements = set1.intersection(set2)\n return sorted(common_elements)", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n return sorted(set(l1) & set(l2))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n\n \"\"\"\n # Use set to find unique common elements\n common_elements = set(l1) & set(l2)\n # Convert set to sorted list\n return sorted(common_elements)", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n set1 = set(l1)\n set2 = set(l2)\n\n common_elements = set1.intersection(set2)\n\n return sorted(common_elements)", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n\n \"\"\"\n return sorted(set(l1).intersection(set(l2)))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n # Use set intersection to find common elements and convert back to a list\n common_elements = list(set(l1) & set(l2))\n # Sort the list of common elements\n common_elements.sort()\n return common_elements", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n\n \"\"\"\n return sorted(list(set(l1).intersection(l2)))", "matching_cluster_idx": 5}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n # Convert both lists to sets to get unique elements and find the intersection\n common_elements = set(l1) & set(l2)\n # Convert the set back to a sorted list\n return sorted(common_elements)", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list) -> list:\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n set1 = set(l1)\n set2 = set(l2)\n return sorted(set1.intersection(set2))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n\n \"\"\"\n # Convert lists to sets and find intersection\n common_elements = set(l1) & set(l2)\n # Convert the result back to a list and sort it\n return sorted(list(common_elements))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n # Convert both lists to sets to find the intersection\n set1 = set(l1)\n set2 = set(l2)\n\n # Get common elements and convert back to list\n common_elements = list(set1 & set2)\n\n # Sort the list of common elements\n common_elements.sort()\n\n return common_elements", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n\n \"\"\"\n # Use set operations to find common elements\n common_elements = set(l1) & set(l2)\n\n # Return the sorted list of common elements\n return sorted(common_elements)", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list) -> list:\n \"\"\"Return sorted unique common elements for two lists.\n\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n\n \"\"\"\n # Convert lists to sets to find common elements\n set1 = set(l1)\n set2 = set(l2)\n\n # Find intersection of the two sets\n common_elements = set1 & set2\n\n # Convert the result back to a sorted list\n return sorted(list(common_elements))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list) -> list:\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n # Using set to find unique common elements and converting it back to a sorted list\n return sorted(set(l1) & set(l2))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n\n \"\"\"\n # Convert lists to sets to find common elements, and convert back to a sorted list\n return sorted(set(l1) & set(l2))", "matching_cluster_idx": 4}]}, "HumanEval/59": {"dps": 95.71180555555556, "dps_norm": 98.88888888888889, "pass@1": 93.0, "profiled": [{"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\"\"\"\n\n def is_prime(num):\n if num <= 1:\n return False\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n return False\n return True\n\n largest_factor = 1\n # Start with the smallest prime factor\n factor = 2\n while n > 1:\n if n % factor == 0:\n largest_factor = factor\n n //= factor\n else:\n factor += 1\n while not is_prime(factor):\n factor += 1\n return largest_factor", "matching_cluster_idx": 6}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n\n # Function to check if a number is prime\n def is_prime(num):\n if num < 2:\n return False\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n return False\n return True\n\n # Function to find the largest prime factor\n def get_largest_prime_factor(n):\n # Check the smallest prime factor\n largest_factor = 1\n while n % 2 == 0:\n largest_factor = 2\n n //= 2\n\n # Check for other prime factors\n factor = 3\n while factor * factor <= n:\n while n % factor == 0:\n largest_factor = factor\n n //= factor\n factor += 2\n\n # If n becomes a prime number larger than 2\n if n > 2:\n largest_factor = n\n\n return largest_factor\n\n return get_largest_prime_factor(n)", "matching_cluster_idx": 8}, {"solution": "import math\ndef largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n def is_prime(num):\n \"\"\"Helper function to check if a number is a prime.\"\"\"\n if num <= 1:\n return False\n if num <= 3:\n return True\n if num % 2 == 0 or num % 3 == 0:\n return False\n i = 5\n while i * i <= num:\n if num % i == 0 or num % (i + 2) == 0:\n return False\n i += 6\n return True\n\n def largest_factor(n):\n \"\"\"Helper function to find the largest prime factor.\"\"\"\n # Divide n by 2 to remove all even factors\n while n % 2 == 0:\n largest_prime = 2\n n //= 2\n\n # n must be odd at this point, so skip even numbers\n for i in range(3, int(math.sqrt(n)) + 1, 2):\n while n % i == 0:\n largest_prime = i\n n //= i\n\n # This condition is to check if n is a prime number greater than 2\n if n > 2:\n largest_prime = n\n\n return largest_prime\n\n return largest_factor(n)", "matching_cluster_idx": 8}, {"solution": "import math\ndef largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n def is_prime(x):\n if x < 2:\n return False\n for i in range(2, int(math.sqrt(x)) + 1):\n if x % i == 0:\n return False\n return True\n\n # Start with the smallest prime number\n largest_factor = None\n\n # Eliminate factors of 2 first for efficiency\n while n % 2 == 0:\n largest_factor = 2\n n //= 2\n\n # Check for odd factors from 3 onwards\n for i in range(3, int(math.sqrt(n)) + 1, 2):\n while n % i == 0:\n largest_factor = i\n n //= i\n\n # If n is a prime number greater than 2\n if n > 2:\n largest_factor = n\n\n return largest_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n\n def is_prime(x: int) -> bool:\n if x <= 1:\n return False\n if x == 2:\n return True\n if x % 2 == 0:\n return False\n for i in range(3, int(x ** 0.5) + 1, 2):\n if x % i == 0:\n return False\n return True\n\n largest_prime = 1\n # Check for the number of 2s that divide n\n while n % 2 == 0:\n largest_prime = 2\n n //= 2\n\n # n must be odd at this point, thus skip even numbers\n for i in range(3, int(n ** 0.5) + 1, 2):\n while n % i == 0:\n largest_prime = i\n n //= i\n\n # This condition is to check if n is a prime number greater than 2\n if n > 2:\n largest_prime = n\n\n return largest_prime", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"\n Return the largest prime factor of n. Assume n > 1 and is not a prime.\n\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n def is_prime(x):\n \"\"\"Helper function to check if a number is prime.\"\"\"\n if x < 2:\n return False\n for i in range(2, int(x**0.5) + 1):\n if x % i == 0:\n return False\n return True\n\n largest_prime = None\n\n # Reduce n by dividing by 2 until n is odd\n while n % 2 == 0:\n largest_prime = 2\n n //= 2\n\n # Check odd factors\n for i in range(3, int(n**0.5) + 1, 2):\n while n % i == 0:\n largest_prime = i\n n //= i\n\n # If n becomes a prime number greater than 2\n if n > 2:\n largest_prime = n\n\n return largest_prime", "matching_cluster_idx": 8}, {"solution": "import math\ndef largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\"\"\"\n def is_prime(x):\n if x <= 1:\n return False\n if x == 2:\n return True\n if x % 2 == 0:\n return False\n for i in range(3, int(math.sqrt(x)) + 1, 2):\n if x % i == 0:\n return False\n return True\n\n max_prime = -1\n\n # Find the number of 2s that divide n\n while n % 2 == 0:\n max_prime = 2\n n >>= 1 # equivalent to n //= 2\n\n # n must be odd at this point, thus skip one element (i.e., increment by 2)\n for i in range(3, int(math.sqrt(n)) + 1, 2):\n # while i divides n, update n and max_prime\n while n % i == 0:\n max_prime = i\n n //= i\n\n # This condition is to check if n is a prime number greater than 2\n if n > 2:\n max_prime = n\n\n return max_prime", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n\n def is_prime(num):\n if num <= 1:\n return False\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n return False\n return True\n\n factor = 2\n while factor * factor <= n:\n if n % factor:\n factor += 1\n else:\n n //= factor\n\n return n", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n i = 2\n while i * i <= n:\n if n % i:\n i += 1\n else:\n n //= i\n return n", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\"\"\"\n def is_prime(num: int) -> bool:\n \"\"\"Helper function to check if a number is prime.\"\"\"\n if num <= 1:\n return False\n if num <= 3:\n return True\n if num % 2 == 0 or num % 3 == 0:\n return False\n i = 5\n while i * i <= num:\n if num % i == 0 or num % (i + 2) == 0:\n return False\n i += 6\n return True\n\n # Start from the smallest prime factor 2\n largest_factor = 2\n # Divide n by 2 until it's odd\n while n % 2 == 0:\n largest_factor = 2\n n //= 2\n\n # Check for odd factors from 3 upwards\n factor = 3\n while factor * factor <= n:\n while n % factor == 0:\n largest_factor = factor\n n //= factor\n factor += 2\n\n # If n is still greater than 2, it means n itself is prime\n if n > 2:\n largest_factor = n\n\n return largest_factor", "matching_cluster_idx": 8}, {"solution": "import math\ndef largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n def is_prime(x):\n if x <= 1:\n return False\n for i in range(2, int(math.sqrt(x)) + 1):\n if x % i == 0:\n return False\n return True\n\n max_prime = -1\n\n # divide n by 2 to remove all even factors\n while n % 2 == 0:\n max_prime = 2\n n //= 2\n\n # n must be odd at this point, thus skip one element (i.e., i = i + 2)\n for i in range(3, int(math.sqrt(n)) + 1, 2):\n while n % i == 0:\n max_prime = i\n n //= i\n\n # this condition is to check if n is a prime number greater than 2\n if n > 2:\n max_prime = n\n\n return max_prime", "matching_cluster_idx": 8}, {"solution": "import math\ndef largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n def is_prime(x):\n if x <= 1:\n return False\n if x <= 3:\n return True\n if x % 2 == 0 or x % 3 == 0:\n return False\n i = 5\n while i * i <= x:\n if x % i == 0 or x % (i + 2) == 0:\n return False\n i += 6\n return True\n\n largest_factor = -1\n while n % 2 == 0:\n largest_factor = 2\n n //= 2\n\n for i in range(3, int(math.sqrt(n)) + 1, 2):\n while n % i == 0:\n largest_factor = i\n n //= i\n\n if n > 2:\n largest_factor = n\n\n return largest_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\"\"\"\n def is_prime(num):\n if num <= 1:\n return False\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n return False\n return True\n\n largest_factor = 1\n # Divide n by 2 to remove all the factors of 2\n while n % 2 == 0:\n largest_factor = 2\n n //= 2\n\n # n must be odd at this point, so skip even numbers\n for i in range(3, int(n**0.5) + 1, 2):\n while n % i == 0:\n largest_factor = i\n n //= i\n\n # This condition is to check if n is a prime number greater than 2\n if n > 2:\n largest_factor = n\n\n return largest_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n def is_prime(num):\n if num <= 1:\n return False\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n return False\n return True\n\n def largest_prime(num):\n largest_prime_factor = -1\n while num % 2 == 0:\n largest_prime_factor = 2\n num //= 2\n for i in range(3, int(num**0.5) + 1, 2):\n while num % i == 0:\n largest_prime_factor = i\n num //= i\n if num > 2:\n largest_prime_factor = num\n return largest_prime_factor\n\n return largest_prime(n)", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n\n def is_prime(x):\n if x <= 1:\n return False\n if x == 2:\n return True\n if x % 2 == 0:\n return False\n for i in range(3, int(x**0.5) + 1, 2):\n if x % i == 0:\n return False\n return True\n\n def largest_prime(m):\n largest_factor = 1\n # Start with the smallest prime number\n factor = 2\n while factor * factor <= m:\n if m % factor:\n factor += 1\n else:\n m //= factor\n largest_factor = factor\n if m > 1:\n largest_factor = m\n return largest_factor\n\n return largest_prime(n)", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n def is_prime(x):\n if x < 2:\n return False\n for i in range(2, int(x ** 0.5) + 1):\n if x % i == 0:\n return False\n return True\n\n factor = 2\n while factor * factor <= n:\n if n % factor:\n factor += 1\n else:\n n //= factor\n return n", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n def is_prime(x: int) -> bool:\n if x <= 1:\n return False\n if x <= 3:\n return True\n if x % 2 == 0 or x % 3 == 0:\n return False\n i = 5\n while i * i <= x:\n if x % i == 0 or x % (i + 2) == 0:\n return False\n i += 6\n return True\n\n largest_factor = 1\n factor = 2\n\n # Check for the smallest prime factor\n while n % factor == 0:\n largest_factor = factor\n n //= factor\n\n # Check for other prime factors\n factor = 3\n while factor * factor <= n:\n while n % factor == 0:\n largest_factor = factor\n n //= factor\n factor += 2\n\n # If n becomes a prime number larger than 2\n if n > 2:\n largest_factor = n\n\n return largest_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n def is_prime(k):\n if k < 2:\n return False\n for i in range(2, int(k**0.5) + 1):\n if k % i == 0:\n return False\n return True\n\n factor = 2\n last_factor = 1\n while n > 1:\n if n % factor == 0:\n last_factor = factor\n n //= factor\n while n % factor == 0:\n n //= factor\n factor += 1\n\n return last_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"\n Return the largest prime factor of n. Assume n > 1 and is not a prime.\n\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n\n def is_prime(num: int) -> bool:\n \"\"\"Check if a number is prime.\"\"\"\n if num <= 1:\n return False\n if num <= 3:\n return True\n if num % 2 == 0 or num % 3 == 0:\n return False\n i = 5\n while i * i <= num:\n if num % i == 0 or num % (i + 2) == 0:\n return False\n i += 6\n return True\n\n factor = 2\n last_factor = 1\n while n > 1:\n if n % factor == 0:\n last_factor = factor\n n //= factor\n while n % factor == 0:\n n //= factor\n factor += 1\n\n return last_factor", "matching_cluster_idx": 8}, {"solution": "import math\ndef largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n def is_prime(x):\n if x < 2:\n return False\n for i in range(2, int(math.sqrt(x)) + 1):\n if x % i == 0:\n return False\n return True\n\n largest_factor = None\n # Divide n by 2 until it's odd\n while n % 2 == 0:\n largest_factor = 2\n n //= 2\n\n # Check for other factors\n for i in range(3, int(math.sqrt(n)) + 1, 2):\n while n % i == 0:\n largest_factor = i\n n //= i\n\n # If n is a prime number greater than 2\n if n > 2:\n largest_factor = n\n\n return largest_factor", "matching_cluster_idx": 8}]}, "HumanEval/64": {"dps": 53.57142857142857, "dps_norm": 49.375, "pass@1": 93.0, "profiled": [{"solution": "def vowels_count(s):\n \"\"\"\n This function takes a string representing a word as input and returns\n the number of vowels in the string. Vowels in this case are 'a', 'e',\n 'i', 'o', 'u'. Here, 'y' is also a vowel, but only when it is at the\n end of the given word.\n\n Parameters:\n s (str): The input string\n\n Returns:\n int: The number of vowels in the string\n \"\"\"\n\n vowels = \"aeiouAEIOU\"\n count = 0\n\n for index, char in enumerate(s):\n if char in vowels:\n count += 1\n elif char in 'Yy' and index == len(s) - 1:\n count += 1\n\n return count", "matching_cluster_idx": 2}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = set('aeiouAEIOU')\n count = sum(1 for char in s[:-1] if char in vowels)\n\n if s and s[-1] in vowels | {'y', 'Y'}:\n count += 1\n\n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = 'aeiouAEIOU'\n count = sum(1 for char in s if char in vowels)\n if s.lower().endswith('y'):\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = \"aeiouAEIOU\"\n count = 0\n for index, char in enumerate(s):\n if char in vowels or (char.lower() == 'y' and index == len(s) - 1):\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n # Define the vowels\n vowels = 'aeiouAEIOU'\n # Count vowels in the string\n count = sum(1 for char in s if char in vowels)\n # Check if 'y' or 'Y' is at the end of the string\n if s and s[-1] in 'yY':\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n \"\"\"\n Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n # Defining vowels and initializing the count\n vowels = 'aeiouAEIOU'\n count = 0\n\n # Iterating through the string\n for i, char in enumerate(s):\n if char in vowels or (char == 'y' and i == len(s) - 1) or (char == 'Y' and i == len(s) - 1):\n count += 1\n\n return count", "matching_cluster_idx": 2}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = 'aeiouAEIOU'\n count = 0\n s = s.lower()\n for i in range(len(s)):\n if s[i] in vowels:\n count += 1\n elif s[i] == 'y' and i == len(s) - 1:\n count += 1\n return count", "matching_cluster_idx": 3}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = \"aeiouAEIOU\"\n count = 0\n s = s.lower()\n\n for i in range(len(s)):\n if s[i] in vowels:\n count += 1\n elif s[i] == 'y' and i == len(s) - 1:\n count += 1\n\n return count", "matching_cluster_idx": 2}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = \"aeiouAEIOU\"\n count = 0\n s = s.lower()\n\n for index, char in enumerate(s):\n if char in vowels:\n count += 1\n elif char == 'y' and index == len(s) - 1:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n # Define the vowels\n vowels = {'a', 'e', 'i', 'o', 'u'}\n\n # Initialize the counter\n count = 0\n\n # Convert the string to lower case to handle case insensitivity\n s = s.lower()\n\n # Count the vowels in the string\n for idx, char in enumerate(s):\n if char in vowels:\n count += 1\n elif char == 'y' and idx == len(s) - 1:\n count += 1\n\n return count", "matching_cluster_idx": 3}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = 'aeiouAEIOU'\n count = 0\n\n # Check for vowels\n for char in s:\n if char in vowels:\n count += 1\n\n # Check for 'y' at the end\n if s.lower().endswith('y'):\n count += 1\n\n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = 'aeiouAEIOU'\n s = s.lower()\n count = 0\n for i, char in enumerate(s):\n if char in vowels:\n count += 1\n elif char == 'y' and i == len(s) - 1:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def vowels_count(s):\n \"\"\"\n Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = set('aeiou')\n count = 0\n s = s.lower() # Convert to lowercase\n\n for i in range(len(s)):\n if s[i] in vowels:\n count += 1\n elif s[i] == 'y' and i == len(s) - 1:\n count += 1\n\n return count", "matching_cluster_idx": 3}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = 'aeiou'\n count = 0\n\n # Convert the string to lowercase to handle case insensitivity\n s = s.lower()\n\n # Count the regular vowels\n for char in s:\n if char in vowels:\n count += 1\n\n # Check for 'y' at the end of the word\n if s.endswith('y'):\n count += 1\n\n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n\n s = s.lower()\n vowels = {'a', 'e', 'i', 'o', 'u'}\n count = 0\n for idx, char in enumerate(s):\n if char in vowels or (char == 'y' and idx == len(s) - 1):\n count += 1\n return count", "matching_cluster_idx": 3}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = \"aeiouAEIOU\"\n count = 0\n\n for i in range(len(s)):\n if s[i] in vowels:\n count += 1\n elif s[i].lower() == 'y' and i == len(s) - 1:\n count += 1\n\n return count", "matching_cluster_idx": 3}, {"solution": "def vowels_count(s):\n \"\"\"\n Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = 'aeiouAEIOU'\n count = 0\n\n s = s.lower()\n if s and s[-1] == 'y':\n count += 1\n\n for char in s:\n if char in vowels:\n count += 1\n\n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = 'aeiouAEIOU'\n count = 0\n s = s.lower()\n for i in range(len(s)):\n if s[i] in vowels:\n count += 1\n elif s[i] == 'y' and i == len(s)-1:\n count += 1\n return count", "matching_cluster_idx": 3}, {"solution": "def vowels_count(s):\n \"\"\"\n Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n # Normalize the input string to lower case\n s = s.lower()\n\n # Define the set of vowels\n vowels = {'a', 'e', 'i', 'o', 'u'}\n\n # Initialize the count of vowels\n count = 0\n\n # Iterate through the string\n for i in range(len(s)):\n if s[i] in vowels:\n count += 1\n # Check if the last character is 'y'\n elif s[i] == 'y' and i == len(s) - 1:\n count += 1\n\n return count", "matching_cluster_idx": 3}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = 'aeiouAEIOU'\n count = 0\n length = len(s)\n\n for i in range(length):\n if s[i] in vowels:\n count += 1\n elif s[i].lower() == 'y' and i == length - 1:\n count += 1\n\n return count", "matching_cluster_idx": 2}]}, "HumanEval/74": {"dps": 98.04878048780488, "dps_norm": 88.88888888888889, "pass@1": 93.0, "profiled": [{"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has\n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n total_chars_lst1 = sum(len(s) for s in lst1)\n total_chars_lst2 = sum(len(s) for s in lst2)\n\n if total_chars_lst1 <= total_chars_lst2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has\n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n total_chars_lst1 = sum(len(s) for s in lst1)\n total_chars_lst2 = sum(len(s) for s in lst2)\n\n if total_chars_lst1 <= total_chars_lst2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has\n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n def count_chars(lst):\n return sum(len(s) for s in lst)\n\n count1 = count_chars(lst1)\n count2 = count_chars(lst2)\n\n if count1 <= count2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has\n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n def total_chars(lst):\n return sum(len(s) for s in lst)\n\n chars1 = total_chars(lst1)\n chars2 = total_chars(lst2)\n\n if chars1 <= chars2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has\n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n def total_chars(lst):\n return sum(len(s) for s in lst)\n\n if total_chars(lst1) <= total_chars(lst2):\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has\n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n\n # Calculate the total number of characters in each list\n total_chars_lst1 = sum(len(s) for s in lst1)\n total_chars_lst2 = sum(len(s) for s in lst2)\n\n # Compare the total number of characters and return the appropriate list\n if total_chars_lst1 <= total_chars_lst2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has\n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n\n # Calculate the total number of characters in each list\n total_chars_lst1 = sum(len(item) for item in lst1)\n total_chars_lst2 = sum(len(item) for item in lst2)\n\n # Return the list with the smaller total number of characters\n if total_chars_lst1 < total_chars_lst2:\n return lst1\n elif total_chars_lst2 < total_chars_lst1:\n return lst2\n else:\n return lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n # Calculate the total number of characters in lst1\n total_chars_lst1 = sum(len(s) for s in lst1)\n\n # Calculate the total number of characters in lst2\n total_chars_lst2 = sum(len(s) for s in lst2)\n\n # Compare the totals and return the appropriate list\n if total_chars_lst1 <= total_chars_lst2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has\n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n\n # Helper function to calculate total chars in the list of strings\n def total_chars(lst):\n return sum(len(s) for s in lst)\n\n # Calculate the total chars in both lists\n total_chars_lst1 = total_chars(lst1)\n total_chars_lst2 = total_chars(lst2)\n\n # Compare the total chars and return the appropriate list\n if total_chars_lst1 < total_chars_lst2:\n return lst1\n elif total_chars_lst2 < total_chars_lst1:\n return lst2\n else:\n return lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n def total_chars(lst):\n return sum(len(s) for s in lst)\n\n total1 = total_chars(lst1)\n total2 = total_chars(lst2)\n\n if total1 < total2:\n return lst1\n elif total2 < total1:\n return lst2\n else:\n return lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n \"\"\"\n Write a function that accepts two lists of strings and returns the list that has\n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n \"\"\"\n # Calculate total number of characters in each list\n total_chars_lst1 = sum(len(s) for s in lst1)\n total_chars_lst2 = sum(len(s) for s in lst2)\n\n # Compare the total characters and return the appropriate list\n if total_chars_lst1 <= total_chars_lst2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n def count_chars(lst):\n return sum(len(s) for s in lst)\n\n chars1 = count_chars(lst1)\n chars2 = count_chars(lst2)\n\n if chars1 < chars2:\n return lst1\n elif chars2 < chars1:\n return lst2\n else:\n return lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has\n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n\n # Calculate the total number of characters in each list\n total_chars_lst1 = sum(len(s) for s in lst1)\n total_chars_lst2 = sum(len(s) for s in lst2)\n\n # Compare the total number of characters\n if total_chars_lst1 <= total_chars_lst2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n def total_length(lst):\n return sum(len(word) for word in lst)\n\n length1 = total_length(lst1)\n length2 = total_length(lst2)\n\n return lst1 if length1 <= length2 else lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n # Calculate the total number of characters in lst1\n total_chars_lst1 = sum(len(s) for s in lst1)\n\n # Calculate the total number of characters in lst2\n total_chars_lst2 = sum(len(s) for s in lst2)\n\n # Return the list with the lesser total number of characters, or lst1 if they are equal\n if total_chars_lst1 <= total_chars_lst2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has\n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n\n # Calculate the total number of characters in each list\n total_chars_lst1 = sum(len(string) for string in lst1)\n total_chars_lst2 = sum(len(string) for string in lst2)\n\n # Return the list with fewer characters, or the first list if they are equal\n if total_chars_lst1 <= total_chars_lst2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has\n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n total_len1 = sum(len(s) for s in lst1)\n total_len2 = sum(len(s) for s in lst2)\n\n if total_len1 <= total_len2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has\n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n\n def total_chars(lst):\n return sum(len(s) for s in lst)\n\n total_chars_lst1 = total_chars(lst1)\n total_chars_lst2 = total_chars(lst2)\n\n if total_chars_lst1 < total_chars_lst2:\n return lst1\n elif total_chars_lst2 < total_chars_lst1:\n return lst2\n else:\n return lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has\n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n def total_chars(lst):\n return sum(len(s) for s in lst)\n\n lst1_chars = total_chars(lst1)\n lst2_chars = total_chars(lst2)\n\n return lst1 if lst1_chars <= lst2_chars else lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has\n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n\n # Helper function to calculate total number of characters in a list of strings\n def total_chars(lst):\n return sum(len(s) for s in lst)\n\n # Calculate total number of characters for each list\n total_chars_lst1 = total_chars(lst1)\n total_chars_lst2 = total_chars(lst2)\n\n # Compare the total number of characters and return the appropriate list\n if total_chars_lst1 < total_chars_lst2:\n return lst1\n elif total_chars_lst2 < total_chars_lst1:\n return lst2\n else:\n return lst1", "matching_cluster_idx": 7}]}, "HumanEval/85": {"dps": 87.0049504950495, "dps_norm": 54.16666666666667, "pass@1": 100.0, "profiled": [{"solution": "def add(lst):\n \"\"\"\n Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2\n \"\"\"\n return sum(val for idx, val in enumerate(lst) if idx % 2 != 0 and val % 2 == 0)", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2\n \"\"\"\n return sum(x for i, x in enumerate(lst) if i % 2 != 0 and x % 2 == 0)", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"\n Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2\n \"\"\"\n return sum(lst[i] for i in range(1, len(lst), 2) if lst[i] % 2 == 0)", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2\n \"\"\"\n return sum(x for i, x in enumerate(lst) if i % 2 != 0 and x % 2 == 0)", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2\n \"\"\"\n return sum(x for i, x in enumerate(lst) if i % 2 != 0 and x % 2 == 0)", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Args:\n lst (list): A non-empty list of integers.\n\n Returns:\n int: The sum of even elements at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2\n \"\"\"\n return sum(lst[i] for i in range(1, len(lst), 2) if lst[i] % 2 == 0)", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2\n \"\"\"\n # Initialize the sum\n total_sum = 0\n\n # Loop through the list starting from the first odd index (index 1)\n for i in range(1, len(lst), 2):\n if lst[i] % 2 == 0:\n total_sum += lst[i]\n\n return total_sum", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2\n \"\"\"\n sum_even = 0\n for i in range(1, len(lst), 2):\n if lst[i] % 2 == 0:\n sum_even += lst[i]\n return sum_even", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Args:\n lst (list): A non-empty list of integers.\n\n Returns:\n int: The sum of even elements at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2\n \"\"\"\n # Initialize the sum\n total = 0\n\n # Loop through the list and add even elements at odd indices\n for i in range(1, len(lst), 2):\n if lst[i] % 2 == 0:\n total += lst[i]\n\n return total", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2\n \"\"\"\n return sum(x for i, x in enumerate(lst) if i % 2 != 0 and x % 2 == 0)", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2\n \"\"\"\n return sum(x for i, x in enumerate(lst) if i % 2 != 0 and x % 2 == 0)", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Args:\n lst (List[int]): A list of integers.\n\n Returns:\n int: The sum of even elements at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2\n \"\"\"\n return sum(x for i, x in enumerate(lst) if i % 2 == 1 and x % 2 == 0)", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2\n \"\"\"\n total = 0\n for index in range(len(lst)):\n if index % 2 != 0 and lst[index] % 2 == 0:\n total += lst[index]\n return total", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2\n \"\"\"\n total = 0\n for i in range(1, len(lst), 2): # iterate over odd indices\n if lst[i] % 2 == 0:\n total += lst[i]\n return total", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2\n \"\"\"\n return sum(x for i, x in enumerate(lst) if i % 2 != 0 and x % 2 == 0)", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2\n \"\"\"\n # Initialize sum\n total = 0\n\n # Iterate over the list with index\n for index, value in enumerate(lst):\n # Check if index is odd and value is even\n if index % 2 != 0 and value % 2 == 0:\n total += value\n\n return total", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"\n Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2\n \"\"\"\n total = 0\n for i in range(1, len(lst), 2):\n if lst[i] % 2 == 0:\n total += lst[i]\n return total", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Args:\n lst (List[int]): A non-empty list of integers.\n\n Returns:\n int: Sum of the even elements at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2\n \"\"\"\n return sum(x for i, x in enumerate(lst) if i % 2 != 0 and x % 2 == 0)", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"\n Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2\n \"\"\"\n return sum(x for i, x in enumerate(lst) if i % 2 != 0 and x % 2 == 0)", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2\n \"\"\"\n # Initialize a variable to store the sum of even elements at odd indices\n total = 0\n\n # Iterate over the list with both index and value\n for index, value in enumerate(lst):\n # Check if the index is odd and the value is even\n if index % 2 != 0 and value % 2 == 0:\n total += value\n\n # Return the sum of the even elements at odd indices\n return total", "matching_cluster_idx": 2}]}, "HumanEval/86": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 77.0, "profiled": [{"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n\n def order_characters(word):\n return ''.join(sorted(word))\n\n return ' '.join(order_characters(word) for word in s.split(' '))", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n def sort_chars(word):\n return ''.join(sorted(word))\n\n # Split the input string into words\n words = s.split(' ')\n\n # Sort each word and join them back with a space\n sorted_words = ' '.join([sort_chars(word) for word in words])\n\n return sorted_words", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n\n def sort_word(word):\n return ''.join(sorted(word))\n\n words = s.split(' ')\n ordered_words = [sort_word(word) for word in words]\n return ' '.join(ordered_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n def sort_word(word):\n # Sorting each word while keeping the capitalization and punctuation in place\n # Convert word to list and sort it\n sorted_word = sorted(word)\n # Join the sorted characters to form the sorted word\n return ''.join(sorted_word)\n\n words = s.split(' ')\n sorted_words = [sort_word(word) for word in words]\n return ' '.join(sorted_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n def sort_word(word):\n # sort the characters in the word\n return ''.join(sorted(word))\n\n # split the input string into words\n words = s.split(' ')\n\n # sort the characters in each word\n sorted_words = [sort_word(word) for word in words]\n\n # join the words back into a single string\n return ' '.join(sorted_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n # Split the input string into words\n words = s.split(' ')\n\n # Sort each word based on ASCII values of characters\n sorted_words = [''.join(sorted(word)) for word in words]\n\n # Join the sorted words back into a single string with spaces\n result = ' '.join(sorted_words)\n\n return result", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n words = s.split(' ')\n\n ordered_words = [''.join(sorted(word)) for word in words]\n\n return ' '.join(ordered_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n def sort_word(word):\n # Split word into characters, sort them and join them back into a word\n return ''.join(sorted(word))\n\n # Split the input string into words\n words = s.split(' ')\n\n # Sort each word and rejoin the sentence\n sorted_sentence = ' '.join(sort_word(word) for word in words)\n\n return sorted_sentence", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n # Split the string into words while preserving spaces\n words = s.split(' ')\n\n # Iterate over the words and sort characters within each word\n sorted_words = [''.join(sorted(word)) for word in words]\n\n # Join the words back into a single string with spaces\n result = ' '.join(sorted_words)\n\n return result", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n\n def sort_word(word):\n return ''.join(sorted(word))\n\n words = s.split(' ')\n ordered_words = [sort_word(word) for word in words]\n return ' '.join(ordered_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n def sort_word(word):\n return ''.join(sorted(word))\n\n words = s.split(' ')\n sorted_words = [sort_word(word) for word in words]\n return ' '.join(sorted_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n def sort_word(word):\n return ''.join(sorted(word))\n\n # Split the string by spaces to get individual words\n words = s.split(' ')\n # Sort each word individually\n sorted_words = [sort_word(word) for word in words]\n # Join the sorted words back together with spaces\n return ' '.join(sorted_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n def order_characters(word):\n return ''.join(sorted(word))\n\n words = s.split(' ')\n ordered_words = [order_characters(word) for word in words]\n return ' '.join(ordered_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n def sort_word(word):\n \"\"\"Helper function to sort characters within a word.\"\"\"\n return ''.join(sorted(word))\n\n # Split the input string into words\n words = s.split(' ')\n\n # Sort characters within each word\n sorted_words = [sort_word(word) for word in words]\n\n # Join the sorted words with spaces in between\n result = ' '.join(sorted_words)\n\n return result", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n\n def sort_word(word):\n return ''.join(sorted(word))\n\n # Split the sentence by spaces, sort each word, and then reassemble the sentence\n words = s.split(' ')\n sorted_words = [sort_word(word) for word in words]\n return ' '.join(sorted_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n def order_word(word):\n return ''.join(sorted(word))\n\n result = []\n for word in s.split(' '):\n result.append(order_word(word))\n return ' '.join(result)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n\n def sort_word(word):\n \"\"\"\n Helper function to sort characters in a word.\n \"\"\"\n return ''.join(sorted(word))\n\n # Split the input string into words and apply sorting function to each word\n words = s.split(' ')\n sorted_words = [sort_word(word) for word in words]\n\n # Join the sorted words back into a single string with spaces\n return ' '.join(sorted_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n def sort_word(word):\n return ''.join(sorted(word))\n\n return ' '.join(sort_word(word) for word in s.split(' '))", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n def sort_word(word):\n return ''.join(sorted(word))\n\n # Split the string into words and non-word parts (keeping order of spaces)\n parts = s.split(' ')\n\n # Apply sort_word to each part, rejoin with single spaces\n result = ' '.join(sort_word(part) if part else '' for part in parts)\n\n return result", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n\n # Split the string into words\n words = s.split(' ')\n\n # Sort the characters in each word\n ordered_words = [''.join(sorted(word)) for word in words]\n\n # Join the words back together with spaces\n result = ' '.join(ordered_words)\n\n return result", "matching_cluster_idx": 4}]}, "HumanEval/87": {"dps": 93.94812680115274, "dps_norm": 57.142857142857146, "pass@1": 94.0, "profiled": [{"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n\n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n\n coordinates = []\n\n for i, row in enumerate(lst):\n for j, value in enumerate(row):\n if value == x:\n coordinates.append((i, j))\n\n coordinates.sort(key=lambda x: (x[0], -x[1]))\n\n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n\n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n coordinates = []\n\n # Traverse the list and gather coordinates\n for row_idx, row in enumerate(lst):\n for col_idx, value in enumerate(row):\n if value == x:\n coordinates.append((row_idx, col_idx))\n\n # Sort coordinates by row in ascending order and by column in descending order\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n\n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n coordinates = []\n\n # Iterate over each row in the list\n for row_index, row in enumerate(lst):\n row_coords = []\n # Iterate over each element in the row\n for col_index, elem in enumerate(row):\n if elem == x:\n row_coords.append((row_index, col_index))\n # Sort coordinates in the row by columns in descending order\n row_coords.sort(key=lambda coord: coord[1], reverse=True)\n coordinates.extend(row_coords)\n\n # Sort the coordinates initially by rows in ascending order\n coordinates.sort(key=lambda coord: coord[0])\n\n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n\n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n coordinates = []\n\n for i, row in enumerate(lst):\n for j, value in enumerate(row):\n if value == x:\n coordinates.append((i, j))\n\n # Sort coordinates by row in ascending order\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n\n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n\n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n # List to store the coordinates\n coordinates = []\n\n # Iterate through each row and column in the nested list\n for row_index, row in enumerate(lst):\n for col_index, value in enumerate(row):\n if value == x:\n coordinates.append((row_index, col_index))\n\n # Sort by rows in ascending order and columns in descending order\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n\n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n\n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n\n coordinates = []\n for i, row in enumerate(lst):\n for j, value in enumerate(row):\n if value == x:\n coordinates.append((i, j))\n\n # Sort primarily by row (ascending), then by column within row (descending)\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n\n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n result = []\n for i, row in enumerate(lst):\n # Filter the row indices where x is found, sorted in descending order\n columns = sorted([j for j, val in enumerate(row) if val == x], reverse=True)\n # Add the coordinates to the result\n result.extend([(i, j) for j in columns])\n return result", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n\n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n result = []\n\n for i, row in enumerate(lst):\n row_coords = [(i, j) for j, val in enumerate(row) if val == x]\n if row_coords:\n row_coords.sort(key=lambda tup: tup[1], reverse=True) # Sort by columns in descending order\n result.extend(row_coords)\n\n return result", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n\n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n coordinates = []\n for i, row in enumerate(lst):\n for j, value in enumerate(row):\n if value == x:\n coordinates.append((i, j))\n\n # Sorting by row in ascending order and by column in descending order\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n\n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n\n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n coordinates = []\n for i, row in enumerate(lst):\n row_coordinates = [(i, j) for j, val in enumerate(row) if val == x]\n if row_coordinates:\n coordinates.extend(sorted(row_coordinates, key=lambda x: -x[1]))\n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n\n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n results = []\n\n for i, row in enumerate(lst):\n found_coords = [(i, j) for j, val in enumerate(row) if val == x]\n found_coords.sort(key=lambda x: (-x[1], x[1])) # sort by column descending\n results.extend(found_coords)\n\n return results", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n\n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n result = []\n\n for row_index, row in enumerate(lst):\n col_indexes = [index for index, value in enumerate(row) if value == x]\n col_indexes.sort(reverse=True)\n result.extend([(row_index, col_index) for col_index in col_indexes])\n\n return result", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n\n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n result = []\n\n for i, row in enumerate(lst):\n for j, value in enumerate(row):\n if value == x:\n result.append((i, j))\n\n # Sort the result first by rows in ascending order\n # Then by columns in descending order within each row\n result.sort(key=lambda x: (x[0], -x[1]))\n\n return result", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n result = []\n for i, row in enumerate(lst):\n for j, elem in enumerate(row):\n if elem == x:\n result.append((i, j))\n result.sort(key=lambda x: (x[0], -x[1]))\n return result", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n\n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n result = []\n for row_index, row in enumerate(lst):\n col_indices = [col_index for col_index, value in enumerate(row) if value == x]\n if col_indices:\n # Sort columns in descending order\n col_indices.sort(reverse=True)\n result.extend([(row_index, col_index) for col_index in col_indices])\n # Sort rows in ascending order\n result.sort(key=lambda coord: coord[0])\n return result", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n\n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n coordinates = []\n\n # Find all coordinates of x\n for i, row in enumerate(lst):\n for j, val in enumerate(row):\n if val == x:\n coordinates.append((i, j))\n\n # Sort coordinates first by row in ascending order, then by column in descending order\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n\n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n\n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n coordinates = []\n\n for i, row in enumerate(lst):\n for j, value in enumerate(row):\n if value == x:\n coordinates.append((i, j))\n\n # Sort coordinates by row ascending and within row by column descending\n coordinates.sort(key=lambda t: (t[0], -t[1]))\n\n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n result = []\n for i, row in enumerate(lst):\n coordinates = [(i, j) for j, val in enumerate(row) if val == x]\n coordinates.sort(key=lambda t: -t[1])\n result.extend(coordinates)\n return result", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n coordinates = []\n\n for i, row in enumerate(lst):\n col_indices = [j for j, value in enumerate(row) if value == x]\n col_indices.sort(reverse=True) # Sort column indices in descending order\n for col in col_indices:\n coordinates.append((i, col))\n\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n\n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n coordinates = []\n for i, row in enumerate(lst):\n for j, value in enumerate(row):\n if value == x:\n coordinates.append((i, j))\n # Sort by row in ascending order\n coordinates.sort(key=lambda coord: coord[0])\n # Sort each row by column in descending order\n row_sorted_coordinates = []\n current_row = 0\n row_coords = []\n for coord in coordinates:\n if coord[0] != current_row:\n row_coords.sort(key=lambda coord: coord[1], reverse=True)\n row_sorted_coordinates.extend(row_coords)\n row_coords = [coord]\n current_row = coord[0]\n else:\n row_coords.append(coord)\n if row_coords:\n row_coords.sort(key=lambda coord: coord[1], reverse=True)\n row_sorted_coordinates.extend(row_coords)\n return row_sorted_coordinates", "matching_cluster_idx": 3}]}, "HumanEval/89": {"dps": 96.70103092783506, "dps_norm": 31.42857142857143, "pass@1": 92.0, "profiled": [{"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated.\n The alphabet should be rotated in a manner such that the letters\n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n def shift_char(c):\n shift = 4 # Because 2 multiplied by 2 equals 4\n if 'a' <= c <= 'z':\n return chr(((ord(c) - ord('a') + shift) % 26) + ord('a'))\n elif 'A' <= c <= 'Z':\n return chr(((ord(c) - ord('A') + shift) % 26) + ord('A'))\n else:\n return c\n\n return ''.join(shift_char(c) for c in s)", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated.\n The alphabet should be rotated in a manner such that the letters\n shift down by four places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n def shift_char(c):\n # Calculate the new position of the character after shifting by 4\n if 'a' <= c <= 'z':\n return chr((ord(c) - ord('a') + 4) % 26 + ord('a'))\n elif 'A' <= c <= 'Z':\n return chr((ord(c) - ord('A') + 4) % 26 + ord('A'))\n else:\n # Return the character as it is if it's not a letter\n return c\n\n # Apply the shift to each character in the input string\n return ''.join(shift_char(c) for c in s)", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"\n Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated.\n The alphabet should be rotated in a manner such that the letters\n shift down by two multiplied by two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n def shift_char(c):\n if 'a' <= c <= 'z':\n return chr(((ord(c) - ord('a') + 4) % 26) + ord('a'))\n elif 'A' <= c <= 'Z':\n return chr(((ord(c) - ord('A') + 4) % 26) + ord('A'))\n else:\n return c\n\n return ''.join(shift_char(c) for c in s)", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n def shift_char(c, shift):\n if 'a' <= c <= 'z':\n return chr(((ord(c) - ord('a') + shift) % 26) + ord('a'))\n elif 'A' <= c <= 'Z':\n return chr(((ord(c) - ord('A') + shift) % 26) + ord('A'))\n else:\n return c\n\n shift = 4 # The alphabet is rotated by 4 places (down by 2 multiplied by 2)\n return ''.join(shift_char(c, shift) for c in s)", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated.\n The alphabet should be rotated in a manner such that the letters\n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n result = []\n for char in s:\n if 'a' <= char <= 'z':\n # Perform the shift\n new_char = chr((((ord(char) - ord('a')) + 2 * 2) % 26) + ord('a'))\n result.append(new_char)\n else:\n # If it's not a lowercase letter, just add it as is\n result.append(char)\n return ''.join(result)", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated.\n The alphabet should be rotated in a manner such that the letters\n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n encrypted_chars = []\n shift = 2 * 2 # Shift value is 4 based on \"two multiplied to two places\"\n\n for char in s:\n if 'a' <= char <= 'z': # Check if the character is a lowercase letter\n new_char = chr(((ord(char) - ord('a') + shift) % 26) + ord('a'))\n encrypted_chars.append(new_char)\n else:\n # Non-lowercase letters are added as is. Modify if you want to handle uppercase or other characters.\n encrypted_chars.append(char)\n\n return ''.join(encrypted_chars)", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n def shift_char(c):\n if c.isalpha():\n start = ord('a') if c.islower() else ord('A')\n return chr(start + (ord(c) - start + 4) % 26)\n else:\n return c\n\n return ''.join(shift_char(c) for c in s)", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated.\n The alphabet should be rotated in a manner such that the letters\n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n def shift_char(c, shift):\n if 'a' <= c <= 'z':\n return chr(((ord(c) - ord('a') + shift) % 26) + ord('a'))\n elif 'A' <= c <= 'Z':\n return chr(((ord(c) - ord('A') + shift) % 26) + ord('A'))\n else:\n return c\n\n shift_amount = 2 * 2\n return ''.join(shift_char(c, shift_amount) for c in s)", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated.\n The alphabet should be rotated in a manner such that the letters\n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n\n shift = 2 * 2\n encrypted = []\n\n for char in s:\n if 'a' <= char <= 'z':\n original_pos = ord(char) - ord('a')\n new_pos = (original_pos + shift) % 26\n encrypted_char = chr(new_pos + ord('a'))\n encrypted.append(encrypted_char)\n elif 'A' <= char <= 'Z':\n original_pos = ord(char) - ord('A')\n new_pos = (original_pos + shift) % 26\n encrypted_char = chr(new_pos + ord('A'))\n encrypted.append(encrypted_char)\n else:\n encrypted.append(char)\n\n return ''.join(encrypted)", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated.\n The alphabet should be rotated in a manner such that the letters\n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n shift = 4 # two multiplied by two\n result = []\n\n for char in s:\n if 'a' <= char <= 'z':\n # Shift character within 'a' to 'z'\n new_char = chr((ord(char) - ord('a') + shift) % 26 + ord('a'))\n result.append(new_char)\n elif 'A' <= char <= 'Z':\n # Shift character within 'A' to 'Z'\n new_char = chr((ord(char) - ord('A') + shift) % 26 + ord('A'))\n result.append(new_char)\n else:\n # If character is not a letter, keep it unchanged\n result.append(char)\n\n return ''.join(result)", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated.\n The alphabet should be rotated in a manner such that the letters\n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n\n # Define the shift amount\n shift = 2 * 2\n\n # Define the original and shifted alphabet\n original_alphabet = 'abcdefghijklmnopqrstuvwxyz'\n shifted_alphabet = original_alphabet[shift:] + original_alphabet[:shift]\n\n # Create a translation table mapping original to shifted letters\n translation_table = str.maketrans(original_alphabet, shifted_alphabet)\n\n # Translate the input string\n encrypted_string = s.translate(translation_table)\n\n return encrypted_string", "matching_cluster_idx": 5}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated.\n The alphabet should be rotated in a manner such that the letters\n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n\n # Helper function to shift a single character\n def shift_char(c, shift):\n if 'a' <= c <= 'z':\n return chr((ord(c) - ord('a') + shift) % 26 + ord('a'))\n else:\n return c # Non-alphabet characters remain unchanged\n\n shift_value = 2 * 2\n return ''.join(shift_char(c, shift_value) for c in s)", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"\n Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated.\n The alphabet should be rotated in a manner such that the letters\n shift down by two multiplied by two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n encrypted_string = ''\n for char in s:\n if 'a' <= char <= 'z':\n new_char = chr((ord(char) - ord('a') + 4) % 26 + ord('a'))\n encrypted_string += new_char\n else:\n encrypted_string += char\n return encrypted_string", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"\n Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated.\n The alphabet should be rotated in a manner such that the letters\n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n shift = 2 * 2 # Shift amount (2 multiplied by 2)\n result = []\n\n for char in s:\n if 'a' <= char <= 'z': # Check if character is a lowercase letter\n # Shift character within the lowercase alphabet\n shifted_char = chr((ord(char) - ord('a') + shift) % 26 + ord('a'))\n result.append(shifted_char)\n elif 'A' <= char <= 'Z': # Check if character is an uppercase letter\n # Shift character within the uppercase alphabet\n shifted_char = chr((ord(char) - ord('A') + shift) % 26 + ord('A'))\n result.append(shifted_char)\n else:\n # Non-alphabet characters remain unchanged\n result.append(char)\n\n return ''.join(result)", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated.\n The alphabet should be rotated in a manner such that the letters\n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n shift = 4 # since the letters shift down by two multiplied by two places\n result = []\n\n for char in s:\n if 'a' <= char <= 'z': # Only rotate lowercase letters\n new_char = chr(((ord(char) - ord('a') + shift) % 26) + ord('a'))\n result.append(new_char)\n else:\n result.append(char) # Keep non-letter characters unchanged\n\n return ''.join(result)", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"\n Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated.\n The alphabet should be rotated in a manner such that the letters\n shift down by four places (two multiplied by two).\n\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n result = []\n for char in s:\n if 'a' <= char <= 'z':\n # Calculate the new character position with the shift\n new_char = chr((ord(char) - ord('a') + 4) % 26 + ord('a'))\n result.append(new_char)\n elif 'A' <= char <= 'Z':\n # Calculate the new character position with the shift\n new_char = chr((ord(char) - ord('A') + 4) % 26 + ord('A'))\n result.append(new_char)\n else:\n # If character is not a letter, keep it as it is\n result.append(char)\n return ''.join(result)", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated.\n The alphabet should be rotated in a manner such that the letters\n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n def shift_char(c):\n if 'a' <= c <= 'z':\n # Calculate the new position of the character after shifting 4 places\n return chr(((ord(c) - ord('a') + 4) % 26) + ord('a'))\n else:\n # If the character is not a lowercase letter, return it unchanged\n return c\n\n # Encrypt the string by shifting each character\n return ''.join(shift_char(c) for c in s)", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated.\n The alphabet should be rotated in a manner such that the letters\n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n\n # Function to shift a single character\n def shift_char(c, shift):\n if 'a' <= c <= 'z':\n return chr((ord(c) - ord('a') + shift) % 26 + ord('a'))\n elif 'A' <= c <= 'Z':\n return chr((ord(c) - ord('A') + shift) % 26 + ord('A'))\n else:\n return c # non-alphabetic characters are not shifted\n\n # Calculate the shift\n shift = 2 * 2\n\n # Shift each character in the string\n encrypted_string = ''.join(shift_char(c, shift) for c in s)\n\n return encrypted_string", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated.\n The alphabet should be rotated in a manner such that the letters\n shift down by four places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n def shift_char(c):\n shift = 4\n if 'a' <= c <= 'z':\n return chr((ord(c) - ord('a') + shift) % 26 + ord('a'))\n elif 'A' <= c <= 'Z':\n return chr((ord(c) - ord('A') + shift) % 26 + ord('A'))\n else:\n return c\n\n return ''.join(shift_char(c) for c in s)", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated.\n The alphabet should be rotated in a manner such that the letters\n shift down by four places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n def shift_char(c):\n if c.isalpha():\n if c.islower():\n # Shift lowercase letters\n return chr(((ord(c) - ord('a') + 4) % 26) + ord('a'))\n elif c.isupper():\n # Shift uppercase letters\n return chr(((ord(c) - ord('A') + 4) % 26) + ord('A'))\n # If character is not a letter, return it unchanged\n return c\n\n return ''.join(shift_char(c) for c in s)", "matching_cluster_idx": 1}]}, "HumanEval/90": {"dps": 67.72373540856032, "dps_norm": 53.75, "pass@1": 100.0, "profiled": [{"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n\n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n\n # Initialize two variables to keep track of the smallest and second smallest elements\n first_smallest = float('inf')\n second_smallest = float('inf')\n\n for num in lst:\n if num < first_smallest:\n second_smallest = first_smallest\n first_smallest = num\n elif first_smallest < num < second_smallest:\n second_smallest = num\n\n return second_smallest if second_smallest != float('inf') else None", "matching_cluster_idx": 5}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n\n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n\n # Use a set to remove duplicates\n unique_elements = list(set(lst))\n\n if len(unique_elements) < 2:\n return None\n\n # Sort the unique elements\n unique_elements.sort()\n\n # Return the second smallest element\n return unique_elements[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n\n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n\n # Remove duplicates and sort the list\n unique_elements = sorted(set(lst))\n\n if len(unique_elements) < 2:\n return None\n\n return unique_elements[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n\n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n # Check if the list has fewer than 2 unique elements\n if len(set(lst)) < 2:\n return None\n\n # Find the smallest and second smallest elements\n smallest = float('inf')\n second_smallest = float('inf')\n\n for num in lst:\n if num < smallest:\n second_smallest = smallest\n smallest = num\n elif smallest < num < second_smallest:\n second_smallest = num\n\n return second_smallest if second_smallest != float('inf') else None", "matching_cluster_idx": 4}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n\n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n\n # Initialize the first and second smallest to large numbers\n first_smallest = float('inf')\n second_smallest = float('inf')\n\n # Iterate over the list to find the first and second smallest elements\n for num in lst:\n if num < first_smallest:\n second_smallest = first_smallest\n first_smallest = num\n elif first_smallest < num < second_smallest:\n second_smallest = num\n\n return second_smallest if second_smallest != float('inf') else None", "matching_cluster_idx": 5}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n\n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n\n if len(lst) < 2:\n return None\n\n smallest = float('inf')\n next_smallest_val = float('inf')\n\n for num in lst:\n if num < smallest:\n next_smallest_val = smallest\n smallest = num\n elif smallest < num < next_smallest_val:\n next_smallest_val = num\n\n return next_smallest_val if next_smallest_val != float('inf') else None", "matching_cluster_idx": 5}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n\n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n\n # Using set to get unique elements and sorting them\n unique_lst = sorted(set(lst))\n\n if len(unique_lst) < 2:\n return None\n\n return unique_lst[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n\n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n # Check if the list has fewer than 2 elements\n if len(lst) < 2:\n return None\n\n # Initialize two variables to keep track of the smallest and second smallest elements\n smallest = float('inf')\n second_smallest = float('inf')\n\n # Iterate through the list to find the smallest and second smallest elements\n for num in lst:\n if num < smallest:\n second_smallest = smallest\n smallest = num\n elif smallest < num < second_smallest:\n second_smallest = num\n\n # Return the second smallest element, or None if not found\n return second_smallest if second_smallest != float('inf') else None", "matching_cluster_idx": 5}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n\n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n\n smallest = float('inf')\n next_smallest = float('inf')\n\n for num in lst:\n if num < smallest:\n next_smallest = smallest\n smallest = num\n elif smallest < num < next_smallest:\n next_smallest = num\n\n return None if next_smallest == float('inf') else next_smallest", "matching_cluster_idx": 5}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n\n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n # If the list has fewer than 2 unique elements, return None\n if len(set(lst)) < 2:\n return None\n\n # Sort the list and remove duplicates\n unique_sorted_lst = sorted(set(lst))\n\n # Return the second smallest element\n return unique_sorted_lst[1]", "matching_cluster_idx": 5}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n\n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n\n # Convert list to a set to remove duplicates, then back to a list and sort it\n sorted_lst = sorted(set(lst))\n\n if len(sorted_lst) < 2:\n return None\n\n return sorted_lst[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n\n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n\n # Convert list to a set to remove duplicates and back to a sorted list\n unique_sorted_lst = sorted(set(lst))\n\n if len(unique_sorted_lst) < 2:\n return None\n\n return unique_sorted_lst[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n\n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n\n # Remove duplicates by converting to a set, then sort the unique elements\n unique_sorted_lst = sorted(set(lst))\n\n if len(unique_sorted_lst) < 2:\n return None\n\n return unique_sorted_lst[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n\n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n\n # Initialize the first and second smallest elements\n first_min = float('inf')\n second_min = float('inf')\n\n for num in lst:\n if num < first_min:\n second_min = first_min\n first_min = num\n elif first_min < num < second_min:\n second_min = num\n\n return second_min if second_min != float('inf') else None", "matching_cluster_idx": 5}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n\n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n\n # Convert list to a set to remove duplicates and then back to a sorted list\n unique_lst = sorted(set(lst))\n\n # If there are fewer than 2 unique elements, return None\n if len(unique_lst) < 2:\n return None\n\n return unique_lst[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n\n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n\n # Initialize the first and second smallest numbers\n first_smallest = second_smallest = float('inf')\n\n for num in lst:\n if num < first_smallest:\n second_smallest = first_smallest\n first_smallest = num\n elif first_smallest < num < second_smallest:\n second_smallest = num\n\n return second_smallest if second_smallest != float('inf') else None", "matching_cluster_idx": 5}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n\n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n\n # Remove duplicates by converting the list to a set\n unique_lst = list(set(lst))\n\n if len(unique_lst) < 2:\n return None\n\n # Sort the list and return the second smallest element\n unique_lst.sort()\n return unique_lst[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n\n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n # Remove duplicates and sort the list\n unique_lst = sorted(set(lst))\n\n # Return the second element if it exists, otherwise return None\n return unique_lst[1] if len(unique_lst) > 1 else None", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n\n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n # Check if the list is empty or contains less than 2 unique elements\n if len(lst) < 2:\n return None\n\n # Convert the list to a set to find unique elements, then back to a sorted list\n unique_elements = sorted(set(lst))\n\n # Return the second element if there are at least two unique elements\n if len(unique_elements) >= 2:\n return unique_elements[1]\n else:\n return None", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n\n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n\n # Initialize the first and second smallest elements\n first_min = float('inf')\n second_min = float('inf')\n\n for number in lst:\n if number < first_min:\n second_min = first_min\n first_min = number\n elif first_min < number < second_min:\n second_min = number\n\n if second_min == float('inf'):\n return None\n\n return second_min", "matching_cluster_idx": 5}]}, "HumanEval/113": {"dps": 99.79716024340772, "dps_norm": 83.33333333333333, "pass@1": 95.0, "profiled": [{"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n\n def count_odd_digits(s):\n return sum(1 for c in s if c in '13579')\n\n result = []\n for s in lst:\n num_odds = count_odd_digits(s)\n str_num_odds = str(num_odds)\n result_str = f\"the number of odd elements {str_num_odds}n the str{str_num_odds}ng {str_num_odds} of the {str_num_odds}nput.\"\n result.append(result_str)\n\n return result", "matching_cluster_idx": 4}, {"solution": "def odd_count(lst):\n def count_odds(s):\n return sum(1 for char in s if char in '13579')\n\n results = []\n for s in lst:\n odd_digits_count = count_odds(s)\n result_str = \"the number of odd elements {}n the str{}ng {} of the {}nput.\".format(\n odd_digits_count, odd_digits_count, odd_digits_count, odd_digits_count)\n results.append(result_str)\n\n return results", "matching_cluster_idx": 4}, {"solution": "def odd_count(lst):\n def count_odds(s):\n return sum(1 for char in s if char in '13579')\n\n results = []\n for s in lst:\n odd_digit_count = count_odds(s)\n result_string = f\"the number of odd elements {odd_digit_count}n the str{odd_digit_count}ng {odd_digit_count} of the {odd_digit_count}nput.\"\n results.append(result_string)\n\n return results", "matching_cluster_idx": 4}, {"solution": "def odd_count(lst):\n def count_odd_digits(s):\n return sum(1 for char in s if char in '13579')\n\n result = []\n for string in lst:\n odd_count = count_odd_digits(string)\n modified_string = f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\"\n result.append(modified_string)\n\n return result", "matching_cluster_idx": 4}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n result = []\n for item in lst:\n odd_digit_count = sum(1 for char in item if char in '13579')\n result.append(f\"the number of odd elements {odd_digit_count}n the str{odd_digit_count}ng {odd_digit_count} of the {odd_digit_count}nput.\")\n return result", "matching_cluster_idx": 4}, {"solution": "def odd_count(lst):\n def count_odd_digits(s):\n \"\"\"Helper function to count the number of odd digits in a string of digits.\"\"\"\n odd_count = sum(1 for char in s if char in '13579')\n return odd_count\n\n def replace_i_with_count(s, count):\n \"\"\"Helper function to replace all 'i's in a string with the given count.\"\"\"\n return s.replace('i', str(count))\n\n result = []\n for string in lst:\n odd_digit_count = count_odd_digits(string)\n result_string = replace_i_with_count(\"the number of odd elements in the string i of the input.\", odd_digit_count)\n result.append(result_string)\n\n return result", "matching_cluster_idx": 4}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n\n def count_odd_digits(s):\n return sum(1 for char in s if char in '13579')\n\n result = []\n for s in lst:\n odd_count_str = str(count_odd_digits(s))\n output_str = \"the number of odd elements \" + odd_count_str + \"n the str\" + odd_count_str + \"ng \" + odd_count_str + \" of the \" + odd_count_str + \"nput.\"\n result.append(output_str)\n\n return result", "matching_cluster_idx": 4}, {"solution": "def odd_count(lst):\n def count_odds(s):\n # Count the number of odd digits in the string s\n return sum(1 for char in s if char in '13579')\n\n def replace_i_with_count(s, count):\n # Replace all occurrences of 'i' with the count\n return s.replace('i', str(count))\n\n template = \"the number of odd elements in the string i of the input.\"\n\n result = []\n for string in lst:\n count = count_odds(string)\n result.append(replace_i_with_count(template, count))\n\n return result", "matching_cluster_idx": 4}, {"solution": "def odd_count(lst):\n def count_odds(s):\n return sum(1 for char in s if char in '13579')\n\n output = []\n for s in lst:\n odd_count = count_odds(s)\n template = f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\"\n output.append(template)\n\n return output", "matching_cluster_idx": 4}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n\n def count_odds(s):\n return sum(1 for char in s if char in '13579')\n\n def replace_i_with_count(template, count):\n return template.replace('i', str(count))\n\n result = []\n template = \"the number of odd elements in the string i of the input.\"\n\n for s in lst:\n odd_digit_count = count_odds(s)\n result.append(replace_i_with_count(template, odd_digit_count))\n\n return result", "matching_cluster_idx": 4}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n result = []\n\n for s in lst:\n # count the number of odd digits in the string\n odd_digits_count = sum(1 for char in s if char in '13579')\n\n # format the output string\n result.append(\"the number of odd elements {}n the str{}ng {} of the {}nput.\".format(\n odd_digits_count, odd_digits_count, odd_digits_count, odd_digits_count))\n\n return result", "matching_cluster_idx": 4}, {"solution": "def odd_count(lst):\n def count_odd_digits(s):\n return sum(1 for ch in s if ch in '13579')\n\n result = []\n for s in lst:\n odd_count = count_odd_digits(s)\n result.append(f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\")\n\n return result", "matching_cluster_idx": 4}, {"solution": "def odd_count(lst):\n def count_odds(s):\n return sum(1 for char in s if char in '13579')\n\n result = []\n for s in lst:\n odd_num = count_odds(s)\n result.append(f\"the number of odd elements {odd_num}n the str{odd_num}ng {odd_num} of the {odd_num}nput.\")\n return result", "matching_cluster_idx": 4}, {"solution": "def odd_count(lst):\n \"\"\"\n Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n\n def count_odds(s):\n return sum(1 for char in s if char in '13579')\n\n result = []\n for s in lst:\n odd_count = count_odds(s)\n output = f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\"\n result.append(output)\n\n return result", "matching_cluster_idx": 4}, {"solution": "def odd_count(lst):\n def count_odds(s):\n return sum(1 for char in s if char in '13579')\n\n result = []\n for s in lst:\n odd_digit_count = count_odds(s)\n res_string = \"the number of odd elements {}n the str{}ng {} of the {}nput.\".format(\n odd_digit_count,\n odd_digit_count,\n odd_digit_count,\n odd_digit_count\n )\n result.append(res_string)\n\n return result", "matching_cluster_idx": 4}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n\n def count_odd_digits(s):\n return sum(1 for ch in s if ch in '13579')\n\n def replace_i_with_count(template, count):\n return template.replace('i', str(count))\n\n template = \"the number of odd elements in the string i of the input.\"\n\n result = []\n for s in lst:\n odd_count = count_odd_digits(s)\n result.append(replace_i_with_count(template, odd_count))\n\n return result", "matching_cluster_idx": 4}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n\n def count_odd_digits(s):\n odd_digits = {'1', '3', '5', '7', '9'}\n count = sum(1 for char in s if char in odd_digits)\n return count\n\n result = []\n for s in lst:\n num_odd = count_odd_digits(s)\n result.append(f\"the number of odd elements {num_odd}n the str{num_odd}ng {num_odd} of the {num_odd}nput.\")\n\n return result", "matching_cluster_idx": 4}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n\n def count_odd_digits(s):\n odd_digits = {'1', '3', '5', '7', '9'}\n return sum(1 for char in s if char in odd_digits)\n\n result = []\n for string in lst:\n num_odds = count_odd_digits(string)\n sentence = f\"the number of odd elements {num_odds}n the str{num_odds}ng {num_odds} of the {num_odds}nput.\"\n result.append(sentence)\n\n return result", "matching_cluster_idx": 4}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n\n def count_odd_digits(s):\n return sum(1 for ch in s if ch in '13579')\n\n def replace_i_with_count(s, count):\n return s.replace(\"i\", str(count))\n\n results = []\n for string in lst:\n odd_count = count_odd_digits(string)\n result = replace_i_with_count(\"the number of odd elements in the string i of the input.\", odd_count)\n results.append(result)\n\n return results", "matching_cluster_idx": 4}, {"solution": "def count_odds(s):\n \"\"\"Helper function to count odd digits in a string.\"\"\"\n return sum(1 for char in s if char in '13579')\ndef odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n \"\"\"\n result = []\n for s in lst:\n odd_digits_count = count_odds(s)\n result_str = f\"the number of odd elements {odd_digits_count}n the str{odd_digits_count}ng {odd_digits_count} of the {odd_digits_count}nput.\"\n result.append(result_str)\n return result", "matching_cluster_idx": 4}]}, "HumanEval/119": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 99.0, "profiled": [{"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n\n def is_balanced(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n elif char == ')':\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n s1, s2 = lst\n return 'Yes' if is_balanced(s1 + s2) or is_balanced(s2 + s1) else 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n def is_balanced(s):\n stack = []\n for char in s:\n if char == '(':\n stack.append(char)\n elif char == ')':\n if stack:\n stack.pop()\n else:\n return False\n return len(stack) == 0\n\n str1, str2 = lst\n # Check all possible concatenations\n if is_balanced(str1 + str2) or is_balanced(str2 + str1):\n return 'Yes'\n else:\n return 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n\n def is_balanced(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n elif char == ')':\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n s1, s2 = lst\n\n if is_balanced(s1 + s2) or is_balanced(s2 + s1):\n return 'Yes'\n else:\n return 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n def is_good(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n elif char == ')':\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n s1, s2 = lst\n return 'Yes' if is_good(s1 + s2) or is_good(s2 + s1) else 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n def is_balanced(s):\n count = 0\n for char in s:\n if char == '(':\n count += 1\n elif char == ')':\n count -= 1\n if count < 0: # early exit if unbalanced\n return False\n return count == 0\n\n s1, s2 = lst\n\n # Check all possible combinations: s1 + s2 and s2 + s1\n if is_balanced(s1 + s2) or is_balanced(s2 + s1):\n return 'Yes'\n else:\n return 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n def is_balanced(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n elif char == ')':\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n s1, s2 = lst\n\n # Check both possible concatenations\n if is_balanced(s1 + s2) or is_balanced(s2 + s1):\n return 'Yes'\n else:\n return 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n def is_balanced(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n elif char == ')':\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n str1, str2 = lst\n # Try concatenating str1 + str2\n if is_balanced(str1 + str2):\n return 'Yes'\n # Try concatenating str2 + str1\n if is_balanced(str2 + str1):\n return 'Yes'\n # If neither combination works, return 'No'\n return 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n def is_balanced(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n elif char == ')':\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n s1, s2 = lst\n if is_balanced(s1 + s2):\n return 'Yes'\n if is_balanced(s2 + s1):\n return 'Yes'\n return 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n def is_balanced(s):\n counter = 0\n for char in s:\n if char == '(':\n counter += 1\n elif char == ')':\n counter -= 1\n if counter < 0: # More closing parentheses than opening\n return False\n return counter == 0 # Balanced if same number of opening and closing\n\n s1, s2 = lst\n # Check all four possible concatenations\n if is_balanced(s1 + s2) or is_balanced(s2 + s1):\n return 'Yes'\n else:\n return 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n def is_balanced(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n elif char == ')':\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n str1, str2 = lst\n concatenated1 = str1 + str2\n concatenated2 = str2 + str1\n\n if is_balanced(concatenated1) or is_balanced(concatenated2):\n return 'Yes'\n else:\n return 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n # check for the strings in both possible orders\n def is_good(s):\n count = 0\n for c in s:\n if c == '(':\n count += 1\n elif c == ')':\n count -= 1\n # count should not be negative at any point of time\n if count < 0:\n return False\n # count should be zero if string is good\n return count == 0\n\n s1, s2 = lst[0], lst[1]\n # checking for two possible concatenations\n if is_good(s1 + s2) or is_good(s2 + s1):\n return 'Yes'\n else:\n return 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n def is_good_string(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n elif char == ')':\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n s1, s2 = lst\n\n # Concatenate the strings in both possible orders\n concatenated1 = s1 + s2\n concatenated2 = s2 + s1\n\n # Check if either concatenated string is good\n if is_good_string(concatenated1) or is_good_string(concatenated2):\n return 'Yes'\n else:\n return 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n # Function to check if a single string is balanced\n def is_balanced(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n elif char == ')':\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n # Unpack the list into two strings\n s1, s2 = lst\n\n # Check both concatenations\n if is_balanced(s1 + s2) or is_balanced(s2 + s1):\n return 'Yes'\n return 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n\n def is_balanced(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n elif char == ')':\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n s1, s2 = lst\n return 'Yes' if is_balanced(s1 + s2) or is_balanced(s2 + s1) else 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n def is_balanced(s):\n stack = []\n for char in s:\n if char == '(':\n stack.append(char)\n elif char == ')':\n if stack:\n stack.pop()\n else:\n return False\n return not stack\n\n str1, str2 = lst\n\n # Check both concatenation options\n if is_balanced(str1 + str2) or is_balanced(str2 + str1):\n return 'Yes'\n else:\n return 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n def is_balanced(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n elif char == ')':\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n s1, s2 = lst\n\n combined1 = s1 + s2\n combined2 = s2 + s1\n\n if is_balanced(combined1) or is_balanced(combined2):\n return 'Yes'\n else:\n return 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n def is_balanced(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n else:\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n s1, s2 = lst\n return 'Yes' if is_balanced(s1 + s2) or is_balanced(s2 + s1) else 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n # Combine the two strings in all possible ways: [s1 + s2, s2 + s1]\n strings = [lst[0] + lst[1], lst[1] + lst[0]]\n\n def is_balanced(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n elif char == ')':\n balance -= 1\n if balance < 0: # More closing brackets than opening brackets at any point means unbalanced\n return False\n return balance == 0 # Must end with zero balance to be balanced\n\n # Check if any of the combined strings is balanced\n for s in strings:\n if is_balanced(s):\n return 'Yes'\n\n return 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n def is_balanced(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n elif char == ')':\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n str1, str2 = lst\n combined1 = str1 + str2\n combined2 = str2 + str1\n\n if is_balanced(combined1) or is_balanced(combined2):\n return 'Yes'\n else:\n return 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n\n def is_good_string(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n elif char == ')':\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n s1, s2 = lst\n\n # Check both possible concatenations\n if is_good_string(s1 + s2) or is_good_string(s2 + s1):\n return 'Yes'\n else:\n return 'No'", "matching_cluster_idx": 4}]}, "HumanEval/120": {"dps": 95.34482758620689, "dps_norm": 97.14285714285714, "pass@1": 48.0, "profiled": [{"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list\n of length k with the maximum k numbers in arr.\n\n Example 1:\n\n Input: arr = [-3, -4, 5], k = 3\n Output: [-4, -3, 5]\n\n Example 2:\n\n Input: arr = [4, -4, 4], k = 2\n Output: [4, 4]\n\n Example 3:\n\n Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1\n Output: [2]\n\n Note:\n 1. The length of the array will be in the range of [1, 1000].\n 2. The elements in the array will be in the range of [-1000, 1000].\n 3. 0 <= k <= len(arr)\n \"\"\"\n # Sort the array in descending order\n arr.sort(reverse=True)\n # Return the first k elements\n return sorted(arr[:k])", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list\n of length k with the maximum k numbers in arr.\n\n Example 1:\n\n Input: arr = [-3, -4, 5], k = 3\n Output: [-4, -3, 5]\n\n Example 2:\n\n Input: arr = [4, -4, 4], k = 2\n Output: [4, 4]\n\n Example 3:\n\n Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1\n Output: [2]\n\n Note:\n 1. The length of the array will be in the range of [1, 1000].\n 2. The elements in the array will be in the range of [-1000, 1000].\n 3. 0 <= k <= len(arr)\n \"\"\"\n\n # Sort the array in descending order and select the top k elements\n max_elements = sorted(arr, reverse=True)[:k]\n\n # Sort the selected elements in ascending order for the output\n return sorted(max_elements)", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list\n of length k with the maximum k numbers in arr.\n\n Example 1:\n\n Input: arr = [-3, -4, 5], k = 3\n Output: [-4, -3, 5]\n\n Example 2:\n\n Input: arr = [4, -4, 4], k = 2\n Output: [4, 4]\n\n Example 3:\n\n Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1\n Output: [2]\n\n Note:\n 1. The length of the array will be in the range of [1, 1000].\n 2. The elements in the array will be in the range of [-1000, 1000].\n 3. 0 <= k <= len(arr)\n \"\"\"\n\n # Sort the array in descending order and select the top k elements\n max_k_elements = sorted(arr, reverse=True)[:k]\n\n # Return the sorted list of maximum k elements\n return sorted(max_k_elements)", "matching_cluster_idx": 6}, {"solution": "import heapq\ndef maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list\n of length k with the maximum k numbers in arr.\n\n Example 1:\n\n Input: arr = [-3, -4, 5], k = 3\n Output: [-4, -3, 5]\n\n Example 2:\n\n Input: arr = [4, -4, 4], k = 2\n Output: [4, 4]\n\n Example 3:\n\n Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1\n Output: [2]\n\n Note:\n 1. The length of the array will be in the range of [1, 1000].\n 2. The elements in the array will be in the range of [-1000, 1000].\n 3. 0 <= k <= len(arr)\n \"\"\"\n # Use a max heap to extract the k largest elements\n max_heap = []\n\n for num in arr:\n heapq.heappush(max_heap, -num)\n\n max_elements = []\n\n for _ in range(k):\n max_elements.append(-heapq.heappop(max_heap))\n\n # Sort the resulting list in ascending order\n max_elements.sort()\n\n return max_elements", "matching_cluster_idx": 2}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list\n of length k with the maximum k numbers in arr.\n\n Example 1:\n\n Input: arr = [-3, -4, 5], k = 3\n Output: [-4, -3, 5]\n\n Example 2:\n\n Input: arr = [4, -4, 4], k = 2\n Output: [4, 4]\n\n Example 3:\n\n Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1\n Output: [2]\n\n Note:\n 1. The length of the array will be in the range of [1, 1000].\n 2. The elements in the array will be in the range of [-1000, 1000].\n 3. 0 <= k <= len(arr)\n \"\"\"\n # Sort the array in descending order\n arr.sort(reverse=True)\n\n # Get the top k elements\n top_k = arr[:k]\n\n # Sort the top k elements in ascending order\n top_k.sort()\n\n return top_k", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list\n of length k with the maximum k numbers in arr.\n\n Example 1:\n\n Input: arr = [-3, -4, 5], k = 3\n Output: [-4, -3, 5]\n\n Example 2:\n\n Input: arr = [4, -4, 4], k = 2\n Output: [4, 4]\n\n Example 3:\n\n Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1\n Output: [2]\n\n Note:\n 1. The length of the array will be in the range of [1, 1000].\n 2. The elements in the array will be in the range of [-1000, 1000].\n 3. 0 <= k <= len(arr)\n \"\"\"\n\n # Sort the array in descending order and take the first k elements\n max_numbers = sorted(arr, reverse=True)[:k]\n\n # Sort the result in ascending order\n return sorted(max_numbers)", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list\n of length k with the maximum k numbers in arr.\n\n Example 1:\n Input: arr = [-3, -4, 5], k = 3\n Output: [-4, -3, 5]\n\n Example 2:\n Input: arr = [4, -4, 4], k = 2\n Output: [4, 4]\n\n Example 3:\n Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1\n Output: [2]\n\n Note:\n 1. The length of the array will be in the range of [1, 1000].\n 2. The elements in the array will be in the range of [-1000, 1000].\n 3. 0 <= k <= len(arr)\n \"\"\"\n\n # Sort the array in descending order\n sorted_arr = sorted(arr, reverse=True)\n\n # Return the first k elements\n return sorted(sorted_arr[:k])", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list\n of length k with the maximum k numbers in arr.\n\n Example 1:\n Input: arr = [-3, -4, 5], k = 3\n Output: [-4, -3, 5]\n\n Example 2:\n Input: arr = [4, -4, 4], k = 2\n Output: [4, 4]\n\n Example 3:\n Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1\n Output: [2]\n\n Note:\n 1. The length of the array will be in the range of [1, 1000].\n 2. The elements in the array will be in the range of [-1000, 1000].\n 3. 0 <= k <= len(arr)\n \"\"\"\n # Sort the array in descending order\n sorted_arr = sorted(arr, reverse=True)\n\n # Return the first k elements in sorted order\n return sorted(sorted_arr[:k])", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list\n of length k with the maximum k numbers in arr.\n\n Example 1:\n\n Input: arr = [-3, -4, 5], k = 3\n Output: [-4, -3, 5]\n\n Example 2:\n\n Input: arr = [4, -4, 4], k = 2\n Output: [4, 4]\n\n Example 3:\n\n Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1\n Output: [2]\n\n Note:\n 1. The length of the array will be in the range of [1, 1000].\n 2. The elements in the array will be in the range of [-1000, 1000].\n 3. 0 <= k <= len(arr)\n \"\"\"\n # Sort the array in descending order\n arr.sort(reverse=True)\n\n # Select the first k elements\n max_k_elements = arr[:k]\n\n # Sort the selected elements in ascending order\n max_k_elements.sort()\n\n return max_k_elements", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list\n of length k with the maximum k numbers in arr.\n\n Example 1:\n\n Input: arr = [-3, -4, 5], k = 3\n Output: [-4, -3, 5]\n\n Example 2:\n\n Input: arr = [4, -4, 4], k = 2\n Output: [4, 4]\n\n Example 3:\n\n Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1\n Output: [2]\n\n Note:\n 1. The length of the array will be in the range of [1, 1000].\n 2. The elements in the array will be in the range of [-1000, 1000].\n 3. 0 <= k <= len(arr)\n \"\"\"\n\n # Sort the array in descending order and then take the first k elements\n arr.sort(reverse=True)\n return sorted(arr[:k])", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n # Sort the list in descending order\n arr.sort(reverse=True)\n\n # Return the first k elements in a new sorted list\n return sorted(arr[:k])", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list\n of length k with the maximum k numbers in arr.\n\n Example 1:\n\n Input: arr = [-3, -4, 5], k = 3\n Output: [-4, -3, 5]\n\n Example 2:\n\n Input: arr = [4, -4, 4], k = 2\n Output: [4, 4]\n\n Example 3:\n\n Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1\n Output: [2]\n\n Note:\n 1. The length of the array will be in the range of [1, 1000].\n 2. The elements in the array will be in the range of [-1000, 1000].\n 3. 0 <= k <= len(arr)\n \"\"\"\n\n # Sort the array in descending order and take the first k elements\n sorted_arr = sorted(arr, reverse=True)\n max_k_elements = sorted_arr[:k]\n\n # Sort the selected k elements in ascending order\n result = sorted(max_k_elements)\n\n return result", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list\n of length k with the maximum k numbers in arr.\n\n Example 1:\n Input: arr = [-3, -4, 5], k = 3\n Output: [-4, -3, 5]\n\n Example 2:\n Input: arr = [4, -4, 4], k = 2\n Output: [4, 4]\n\n Example 3:\n Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1\n Output: [2]\n\n Note:\n 1. The length of the array will be in the range of [1, 1000].\n 2. The elements in the array will be in the range of [-1000, 1000].\n 3. 0 <= k <= len(arr)\n \"\"\"\n return sorted(sorted(arr, reverse=True)[:k])", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list\n of length k with the maximum k numbers in arr.\n\n Example 1:\n\n Input: arr = [-3, -4, 5], k = 3\n Output: [-4, -3, 5]\n\n Example 2:\n\n Input: arr = [4, -4, 4], k = 2\n Output: [4, 4]\n\n Example 3:\n\n Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1\n Output: [2]\n\n Note:\n 1. The length of the array will be in the range of [1, 1000].\n 2. The elements in the array will be in the range of [-1000, 1000].\n 3. 0 <= k <= len(arr)\n \"\"\"\n return sorted(arr, reverse=True)[:k][::-1]", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list\n of length k with the maximum k numbers in arr.\n\n Example 1:\n Input: arr = [-3, -4, 5], k = 3\n Output: [-4, -3, 5]\n\n Example 2:\n Input: arr = [4, -4, 4], k = 2\n Output: [4, 4]\n\n Example 3:\n Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1\n Output: [2]\n\n Note:\n 1. The length of the array will be in the range of [1, 1000].\n 2. The elements in the array will be in the range of [-1000, 1000].\n 3. 0 <= k <= len(arr)\n \"\"\"\n sorted_arr = sorted(arr, reverse=True)\n return sorted(sorted_arr[:k])", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list\n of length k with the maximum k numbers in arr.\n \"\"\"\n return sorted(arr, reverse=True)[:k][::-1]", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list\n of length k with the maximum k numbers in arr.\n\n Example 1:\n\n Input: arr = [-3, -4, 5], k = 3\n Output: [-4, -3, 5]\n\n Example 2:\n\n Input: arr = [4, -4, 4], k = 2\n Output: [4, 4]\n\n Example 3:\n\n Input: arr = [-3, 2, 1, 2, -1, -2, 1], k = 1\n Output: [2]\n\n Note:\n 1. The length of the array will be in the range of [1, 1000].\n 2. The elements in the array will be in the range of [-1000, 1000].\n 3. 0 <= k <= len(arr)\n \"\"\"\n # Sort the array in descending order and select the top k elements\n max_numbers = sorted(arr, reverse=True)[:k]\n # Sort the top k elements in ascending order\n return sorted(max_numbers)", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list\n of length k with the maximum k numbers in arr.\n \"\"\"\n # Sort the array in descending order\n sorted_arr = sorted(arr, reverse=True)\n\n # Take the first k elements\n max_k_numbers = sorted_arr[:k]\n\n # Sort these k elements in ascending order\n max_k_numbers.sort()\n\n return max_k_numbers", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n \"\"\"\n Given an array arr of integers and a positive integer k, return a sorted list\n of length k with the maximum k numbers in arr.\n \"\"\"\n if k == 0:\n return []\n # Sort the array in descending order\n arr.sort(reverse=True)\n # Take the top k elements from the sorted array\n top_k = arr[:k]\n # Sort the top k elements in ascending order\n top_k.sort()\n return top_k", "matching_cluster_idx": 6}, {"solution": "def maximum(arr, k):\n # Sort the array in descending order\n sorted_arr = sorted(arr, reverse=True)\n\n # Take the first k elements from the sorted array\n max_k_elements = sorted_arr[:k]\n\n # Return the sorted list of k elements\n return sorted(max_k_elements)", "matching_cluster_idx": 6}]}, "HumanEval/121": {"dps": 82.60089686098655, "dps_norm": 61.42857142857143, "pass@1": 84.0, "profiled": [{"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n\n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n return sum(val for idx, val in enumerate(lst) if idx % 2 == 0 and val % 2 != 0)", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n\n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==>0\n \"\"\"\n # Initialize sum to 0\n total_sum = 0\n\n # Loop through the list considering only even indices\n for i in range(0, len(lst), 2):\n if lst[i] % 2 != 0: # Check if the element at the even index is odd\n total_sum += lst[i]\n\n return total_sum", "matching_cluster_idx": 4}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\"\"\"\n return sum(x for i, x in enumerate(lst) if i % 2 == 0 and x % 2 == 1)", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n \"\"\"\n Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n\n Examples:\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n return sum(x for i, x in enumerate(lst) if i % 2 == 0 and x % 2 != 0)", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\"\"\"\n\n # Initialize sum of odd elements in even positions\n sum_of_odds = 0\n\n # Iterate over the list with index\n for i in range(len(lst)):\n # Check if the index is even and the element is odd\n if i % 2 == 0 and lst[i] % 2 != 0:\n sum_of_odds += lst[i]\n\n return sum_of_odds", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n \"\"\"\n Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n\n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==>0\n \"\"\"\n return sum(x for i, x in enumerate(lst) if i % 2 == 0 and x % 2 != 0)", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n\n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n return sum(x for i, x in enumerate(lst) if i % 2 == 0 and x % 2 != 0)", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n\n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n # Initialize the sum of odd elements at even positions\n odd_sum = 0\n\n # Iterate through the list with both index and value\n for idx, value in enumerate(lst):\n # Check if the index is even and the value is odd\n if idx % 2 == 0 and value % 2 != 0:\n odd_sum += value\n\n return odd_sum", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n\n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n return sum(x for i, x in enumerate(lst) if i % 2 == 0 and x % 2 != 0)", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\"\"\"\n return sum(lst[i] for i in range(0, len(lst), 2) if lst[i] % 2 != 0)", "matching_cluster_idx": 4}, {"solution": "def solution(lst):\n \"\"\"\n Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n\n Examples:\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n return sum(x for i, x in enumerate(lst) if i % 2 == 0 and x % 2 == 1)", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n\n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==>0\n \"\"\"\n return sum(x for i, x in enumerate(lst) if i % 2 == 0 and x % 2 != 0)", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n\n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n return sum(x for i, x in enumerate(lst) if i % 2 == 0 and x % 2 != 0)", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n\n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==>0\n \"\"\"\n sum_of_odds = 0\n for i in range(0, len(lst), 2):\n if lst[i] % 2 != 0:\n sum_of_odds += lst[i]\n return sum_of_odds", "matching_cluster_idx": 4}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n\n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n return sum(x for i, x in enumerate(lst) if i % 2 == 0 and x % 2 != 0)", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n \"\"\"\n Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n\n Examples:\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n sum_odd = 0\n for i in range(0, len(lst), 2):\n if lst[i] % 2 != 0:\n sum_odd += lst[i]\n return sum_odd", "matching_cluster_idx": 4}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n\n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n return sum(x for i, x in enumerate(lst) if i % 2 == 0 and x % 2 != 0)", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n\n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==>0\n \"\"\"\n sum_odd_elements = 0\n for i in range(0, len(lst), 2):\n if lst[i] % 2 != 0:\n sum_odd_elements += lst[i]\n return sum_odd_elements", "matching_cluster_idx": 4}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n\n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n # Initialize the sum to 0\n sum_odd_even_pos = 0\n\n # Iterate over the list with index\n for index, value in enumerate(lst):\n # Check if the position is even and the element is odd\n if index % 2 == 0 and value % 2 != 0:\n sum_odd_even_pos += value\n\n return sum_odd_even_pos", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n \"\"\"\n Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n\n Examples:\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n\n # Initialize the sum to 0\n sum_odd_even_position = 0\n\n # Iterate over the list, considering only even positions\n for i in range(0, len(lst), 2):\n if lst[i] % 2 != 0: # Check if the element is odd\n sum_odd_even_position += lst[i]\n\n return sum_odd_even_position", "matching_cluster_idx": 4}]}, "HumanEval/149": {"dps": 86.53543307086615, "dps_norm": 59.28571428571429, "pass@1": 99.0, "profiled": [{"solution": "def sorted_list_sum(lst):\n # Filter out strings with odd lengths\n filtered_lst = [word for word in lst if len(word) % 2 == 0]\n # Sort the list first by length, then alphabetically for strings with same length\n sorted_lst = sorted(filtered_lst, key=lambda x: (len(x), x))\n return sorted_lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n # Remove strings that have odd lengths\n lst = [string for string in lst if len(string) % 2 == 0]\n\n # Sort the list first alphabetically, and then by length\n lst.sort()\n lst.sort(key=len)\n\n return lst", "matching_cluster_idx": 6}, {"solution": "def sorted_list_sum(lst):\n \"\"\"Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order,\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n You may assume that all words will have the same length.\n For example:\n assert list_sort([\"aa\", \"a\", \"aaa\"]) => [\"aa\"]\n assert list_sort([\"ab\", \"a\", \"aaa\", \"cd\"]) => [\"ab\", \"cd\"]\n \"\"\"\n # Filter out strings with odd lengths\n filtered_list = [s for s in lst if len(s) % 2 == 0]\n\n # Sort the filtered list first by length, then alphabetically\n sorted_list = sorted(filtered_list, key=lambda x: (len(x), x))\n\n return sorted_list", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"\n Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order,\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n You may assume that all words will have the same length.\n For example:\n assert list_sort([\"aa\", \"a\", \"aaa\"]) => [\"aa\"]\n assert list_sort([\"ab\", \"a\", \"aaa\", \"cd\"]) => [\"ab\", \"cd\"]\n \"\"\"\n # Filter out strings with odd lengths\n even_length_strings = [s for s in lst if len(s) % 2 == 0]\n\n # Sort the list first by length and then alphabetically\n sorted_list = sorted(even_length_strings, key=lambda x: (len(x), x))\n\n return sorted_list", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"\n Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order.\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n You may assume that all words will have the same length.\n For example:\n assert sorted_list_sum([\"aa\", \"a\", \"aaa\"]) => [\"aa\"]\n assert sorted_list_sum([\"ab\", \"a\", \"aaa\", \"cd\"]) => [\"ab\", \"cd\"]\n \"\"\"\n # Filter out strings with odd lengths\n filtered_lst = [s for s in lst if len(s) % 2 == 0]\n\n # Sort first by length of the strings, then alphabetically\n sorted_lst = sorted(filtered_lst, key=lambda x: (len(x), x))\n\n return sorted_lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order,\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n You may assume that all words will have the same length.\n For example:\n assert sorted_list_sum([\"aa\", \"a\", \"aaa\"]) => [\"aa\"]\n assert sorted_list_sum([\"ab\", \"a\", \"aaa\", \"cd\"]) => [\"ab\", \"cd\"]\n \"\"\"\n # Filter out strings with odd lengths\n filtered_lst = [word for word in lst if len(word) % 2 == 0]\n\n # Sort first by length and then alphabetically\n filtered_lst.sort(key=lambda x: (len(x), x))\n\n return filtered_lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order,\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n You may assume that all words will have the same length.\n For example:\n assert sorted_list_sum([\"aa\", \"a\", \"aaa\"]) => [\"aa\"]\n assert sorted_list_sum([\"ab\", \"a\", \"aaa\", \"cd\"]) => [\"ab\", \"cd\"]\n \"\"\"\n # Filter out strings with odd lengths\n filtered_list = [s for s in lst if len(s) % 2 == 0]\n\n # Sort the list by length first and then alphabetically if lengths are the same\n sorted_list = sorted(filtered_list, key=lambda x: (len(x), x))\n\n return sorted_list", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order,\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n You may assume that all words will have the same length.\n For example:\n assert list_sort([\"aa\", \"a\", \"aaa\"]) => [\"aa\"]\n assert list_sort([\"ab\", \"a\", \"aaa\", \"cd\"]) => [\"ab\", \"cd\"]\n \"\"\"\n filtered_lst = [word for word in lst if len(word) % 2 == 0]\n sorted_lst = sorted(filtered_lst, key=lambda word: (len(word), word))\n return sorted_lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order,\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n You may assume that all words will have the same length.\n For example:\n assert list_sort([\"aa\", \"a\", \"aaa\"]) => [\"aa\"]\n assert list_sort([\"ab\", \"a\", \"aaa\", \"cd\"]) => [\"ab\", \"cd\"]\n \"\"\"\n # Filter out strings with odd lengths\n filtered_lst = [word for word in lst if len(word) % 2 == 0]\n\n # Sort the filtered list first by length, then alphabetically\n sorted_lst = sorted(filtered_lst, key=lambda x: (len(x), x))\n\n return sorted_lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order,\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n You may assume that all words will have the same length.\n For example:\n assert sorted_list_sum([\"aa\", \"a\", \"aaa\"]) => [\"aa\"]\n assert sorted_list_sum([\"ab\", \"a\", \"aaa\", \"cd\"]) => [\"ab\", \"cd\"]\n \"\"\"\n # Filter out strings with odd lengths\n filtered_list = [s for s in lst if len(s) % 2 == 0]\n\n # Sort the filtered list first by length and then alphabetically\n sorted_list = sorted(filtered_list, key=lambda x: (len(x), x))\n\n return sorted_list", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"\n Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order.\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word,\n and you should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n You may assume that all words will have the same length.\n For example:\n assert sorted_list_sum([\"aa\", \"a\", \"aaa\"]) => [\"aa\"]\n assert sorted_list_sum([\"ab\", \"a\", \"aaa\", \"cd\"]) => [\"ab\", \"cd\"]\n \"\"\"\n # Filter out strings with odd lengths\n filtered_lst = [s for s in lst if len(s) % 2 == 0]\n\n # Sort the list first by length of strings and then alphabetically\n sorted_lst = sorted(filtered_lst, key=lambda s: (len(s), s))\n\n return sorted_lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order.\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n You may assume that all words will have the same length.\n For example:\n assert list_sort([\"aa\", \"a\", \"aaa\"]) => [\"aa\"]\n assert list_sort([\"ab\", \"a\", \"aaa\", \"cd\"]) => [\"ab\", \"cd\"]\n \"\"\"\n # Filter out strings with odd lengths\n filtered_list = [word for word in lst if len(word) % 2 == 0]\n\n # Sort the list first by length and then alphabetically for strings of the same length\n sorted_list = sorted(filtered_list, key=lambda x: (len(x), x))\n\n return sorted_list", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"\n Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order.\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n You may assume that all words will have the same length.\n For example:\n assert sorted_list_sum([\"aa\", \"a\", \"aaa\"]) => [\"aa\"]\n assert sorted_list_sum([\"ab\", \"a\", \"aaa\", \"cd\"]) => [\"ab\", \"cd\"]\n \"\"\"\n # Filter out strings with odd lengths\n filtered_lst = [word for word in lst if len(word) % 2 == 0]\n\n # Sort the list by length first, then alphabetically\n sorted_lst = sorted(filtered_lst, key=lambda x: (len(x), x))\n\n return sorted_lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order,\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n You may assume that all words will have the same length.\n For example:\n assert sorted_list_sum([\"aa\", \"a\", \"aaa\"]) => [\"aa\"]\n assert sorted_list_sum([\"ab\", \"a\", \"aaa\", \"cd\"]) => [\"ab\", \"cd\"]\n \"\"\"\n\n # Filter out strings with odd lengths\n filtered_list = [word for word in lst if len(word) % 2 == 0]\n\n # Sort the list first by length and then alphabetically\n sorted_list = sorted(filtered_list, key=lambda x: (len(x), x))\n\n return sorted_list", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order,\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n You may assume that all words will have the same length.\n For example:\n assert sorted_list_sum([\"aa\", \"a\", \"aaa\"]) => [\"aa\"]\n assert sorted_list_sum([\"ab\", \"a\", \"aaa\", \"cd\"]) => [\"ab\", \"cd\"]\n \"\"\"\n\n # Filter out strings with odd lengths\n filtered_lst = [s for s in lst if len(s) % 2 == 0]\n\n # Sort the list first by length, then alphabetically\n sorted_lst = sorted(filtered_lst, key=lambda x: (len(x), x))\n\n return sorted_lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order,\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n You may assume that all words will have the same length.\n For example:\n assert list_sort([\"aa\", \"a\", \"aaa\"]) => [\"aa\"]\n assert list_sort([\"ab\", \"a\", \"aaa\", \"cd\"]) => [\"ab\", \"cd\"]\n \"\"\"\n # Filter out strings with odd lengths\n filtered_list = [s for s in lst if len(s) % 2 == 0]\n\n # Sort the filtered list by length, then alphabetically for same lengths\n sorted_list = sorted(filtered_list, key=lambda x: (len(x), x))\n\n return sorted_list", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order,\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n You may assume that all words will have the same length.\n For example:\n assert list_sort([\"aa\", \"a\", \"aaa\"]) => [\"aa\"]\n assert list_sort([\"ab\", \"a\", \"aaa\", \"cd\"]) => [\"ab\", \"cd\"]\n \"\"\"\n filtered_lst = [word for word in lst if len(word) % 2 == 0]\n sorted_lst = sorted(filtered_lst, key=lambda x: (len(x), x))\n return sorted_lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order,\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n You may assume that all words will have the same length.\n For example:\n assert list_sort([\"aa\", \"a\", \"aaa\"]) => [\"aa\"]\n assert list_sort([\"ab\", \"a\", \"aaa\", \"cd\"]) => [\"ab\", \"cd\"]\n \"\"\"\n # Filter out strings with odd lengths\n filtered_lst = [s for s in lst if len(s) % 2 == 0]\n\n # Sort the list first by length and then alphabetically\n sorted_lst = sorted(filtered_lst, key=lambda x: (len(x), x))\n\n return sorted_lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order,\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n You may assume that all words will have the same length.\n For example:\n assert sorted_list_sum([\"aa\", \"a\", \"aaa\"]) => [\"aa\"]\n assert sorted_list_sum([\"ab\", \"a\", \"aaa\", \"cd\"]) => [\"ab\", \"cd\"]\n \"\"\"\n\n # Filter out strings with odd lengths\n filtered_list = [s for s in lst if len(s) % 2 == 0]\n\n # Sort the list by length first and then alphabetically\n sorted_list = sorted(filtered_list, key=lambda x: (len(x), x))\n\n return sorted_list", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"\n Function to accept a list of strings, remove strings with odd lengths,\n and return the result list in sorted order. The order is ascending\n by length of each word, and alphabetical order if lengths are the same.\n\n Parameters:\n lst (list of str): A list of strings.\n\n Returns:\n list of str: A list of strings in sorted order.\n \"\"\"\n # Filter out strings with odd lengths\n filtered_list = [word for word in lst if len(word) % 2 == 0]\n\n # Sort the list by length first, then alphabetically for strings of the same length\n sorted_list = sorted(filtered_list, key=lambda word: (len(word), word))\n\n return sorted_list", "matching_cluster_idx": 3}]}, "Mbpp/3": {"dps": 89.87288135593221, "dps_norm": 94.375, "pass@1": 100.0, "profiled": [{"solution": "def is_not_prime(n):\n if n <= 1:\n return True\n if n == 2:\n return False\n if n % 2 == 0:\n return True\n for i in range(3, int(n**0.5) + 1, 2):\n if n % i == 0:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n \"\"\"\n Check if the given number is a non-prime number.\n\n Parameters:\n n (int): The number to check\n\n Returns:\n bool: True if n is a non-prime number, False otherwise\n \"\"\"\n if n <= 1:\n return True\n if n == 2:\n return False\n if n % 2 == 0:\n return True\n max_divisor = int(n**0.5) + 1\n for d in range(3, max_divisor, 2):\n if n % d == 0:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n if n <= 1:\n return True\n if n <= 3:\n return False\n if n % 2 == 0 or n % 3 == 0:\n return True\n i = 5\n while (i * i) <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return True\n i += 6\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n \"\"\"\n Returns True if the number is not prime, and False if the number is prime.\n \"\"\"\n if n <= 1:\n return True # numbers less than 2 are not prime\n if n == 2:\n return False # 2 is prime\n if n % 2 == 0:\n return True # even numbers greater than 2 are not prime\n for i in range(3, int(n**0.5) + 1, 2):\n if n % i == 0:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n if n <= 1:\n return True\n elif n <= 3:\n return False\n elif n % 2 == 0 or n % 3 == 0:\n return True\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return True\n i += 6\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n \"\"\"\n Function to check if a number is a non-prime number.\n\n Parameters:\n n (int): The number to check.\n\n Returns:\n bool: True if n is not a prime number, False otherwise.\n \"\"\"\n if n <= 1:\n return True\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return True\n return False", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(n):\n \"\"\"\n This function returns True if the number 'n' is not a prime number, otherwise False.\n \"\"\"\n if n <= 1:\n return True\n if n <= 3:\n return False\n if n % 2 == 0 or n % 3 == 0:\n return True\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return True\n i += 6\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n \"\"\"\n This function returns True if the input number is not a prime number, otherwise False.\n \"\"\"\n if n <= 1:\n return True\n for i in range(2, int(n ** 0.5) + 1):\n if n % i == 0:\n return True\n return False", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(n):\n \"\"\"\n Identify whether a given number is not a prime number.\n\n Args:\n n (int): The number to check.\n\n Returns:\n bool: True if the number is not a prime number, False otherwise.\n \"\"\"\n if n <= 1:\n return True # 0 and 1 are not prime numbers\n if n == 2:\n return False # 2 is the only even prime number\n if n % 2 == 0:\n return True # Other even numbers are not prime\n\n for i in range(3, int(n**0.5) + 1, 2):\n if n % i == 0:\n return True # n is divisible by i, so it's not prime\n\n return False # n is prime", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n if n <= 1:\n return True\n if n == 2:\n return False\n if n % 2 == 0:\n return True\n for i in range(3, int(n**0.5) + 1, 2):\n if n % i == 0:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n \"\"\"\n Checks if the given number is a non-prime number.\n\n Parameters:\n n (int): The number to check.\n\n Returns:\n bool: True if the number is not a prime number, False otherwise.\n \"\"\"\n if n <= 1:\n return True # 0 and 1 are not prime numbers\n if n <= 3:\n return False # 2 and 3 are prime numbers\n if n % 2 == 0 or n % 3 == 0:\n return True\n\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return True\n i += 6\n\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n \"\"\"\n Identifies if a number is not a prime number.\n\n Args:\n n (int): The number to check.\n\n Returns:\n bool: True if the number is not a prime number, False otherwise.\n \"\"\"\n if n <= 1:\n return True\n if n <= 3:\n return False\n if n % 2 == 0 or n % 3 == 0:\n return True\n\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return True\n i += 6\n\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n if n <= 1:\n return True\n if n == 2:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return True\n return False", "matching_cluster_idx": 4}, {"solution": "def is_not_prime(n):\n if n <= 1:\n return True # Numbers less than or equal to 1 are not prime\n if n <= 3:\n return False # 2 and 3 are prime numbers\n if n % 2 == 0 or n % 3 == 0:\n return True # Multiples of 2 and 3 are not prime\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return True\n i += 6\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n \"\"\"\n Function to identify non-prime numbers.\n\n Parameters:\n n (int): The number to be checked.\n\n Returns:\n bool: True if the number is not prime, False otherwise.\n \"\"\"\n if n <= 1:\n return True\n if n == 2:\n return False\n if n % 2 == 0:\n return True\n for i in range(3, int(n**0.5) + 1, 2):\n if n % i == 0:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n \"\"\"\n Identify if a given number is non-prime.\n\n Args:\n n (int): The number to check.\n\n Returns:\n bool: True if the number is non-prime, otherwise False.\n \"\"\"\n if n <= 1:\n return True\n if n == 2:\n return False\n if n % 2 == 0:\n return True\n for i in range(3, int(n**0.5) + 1, 2):\n if n % i == 0:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n \"\"\"\n Determines if a given number is not a prime number.\n\n Parameters:\n n (int): The number to check.\n\n Returns:\n bool: True if the number is not a prime, False otherwise.\n \"\"\"\n if n <= 1:\n return True # 0 and 1 are not prime numbers\n if n == 2:\n return False # 2 is the only even prime number\n if n % 2 == 0:\n return True # All other even numbers are not prime\n\n for i in range(3, int(n**0.5) + 1, 2):\n if n % i == 0:\n return True\n\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n \"\"\"\n Function to identify non-prime numbers.\n Returns True if the number is not prime, otherwise False.\n \"\"\"\n if n <= 1:\n return True # 0 and 1 are not prime numbers\n if n == 2:\n return False # 2 is a prime number\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return True\n return False", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(n):\n \"\"\"\n Check if the given number n is not a prime number.\n\n Args:\n n (int): The number to be checked.\n\n Returns:\n bool: True if n is not a prime number, False otherwise.\n \"\"\"\n if n <= 1:\n return True\n if n <= 3:\n return False\n if n % 2 == 0 or n % 3 == 0:\n return True\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return True\n i += 6\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n \"\"\"\n Function to check if a number is not a prime number.\n Args:\n n (int): The number to be checked.\n Returns:\n bool: True if the number is not prime, False otherwise.\n \"\"\"\n if n <= 1:\n return True\n if n <= 3:\n return False\n if n % 2 == 0 or n % 3 == 0:\n return True\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return True\n i += 6\n return False", "matching_cluster_idx": 7}]}, "Mbpp/4": {"dps": 95.22184300341297, "dps_norm": 83.33333333333333, "pass@1": 99.0, "profiled": [{"solution": "import heapq\ndef heap_queue_largest(numbers, n):\n # Using heapq.nlargest to get n largest integers in descending order\n return heapq.nlargest(n, numbers)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n return heapq.nlargest(n, nums)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n return heapq.nlargest(n, nums)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n # Use a heap to find the n largest integers\n largest_integers = heapq.nlargest(n, nums)\n # Return the largest integers in descending order\n return sorted(largest_integers, reverse=True)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n \"\"\"\n Function to find the n largest integers from a given list of numbers,\n returned in descending order.\n \"\"\"\n return heapq.nlargest(n, nums)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n return heapq.nlargest(n, nums)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n return heapq.nlargest(n, nums)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n return heapq.nlargest(n, nums)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n # Using a min-heap to find the n largest integers\n largest = heapq.nlargest(n, nums)\n # Sorting the result in descending order\n return sorted(largest, reverse=True)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n return heapq.nlargest(n, nums)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(lst, n):\n \"\"\"\n Find the n largest integers from a given list of numbers, returned in descending order.\n :param lst: List of integers\n :param n: Number of largest integers to return\n :return: List of n largest integers in descending order\n \"\"\"\n return heapq.nlargest(n, lst)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n \"\"\"\n Find the n largest integers from a given list of numbers, returned in descending order.\n\n Parameters:\n nums (list): List of integers.\n n (int): Number of largest integers to return.\n\n Returns:\n list: List of n largest integers in descending order.\n \"\"\"\n if n <= 0:\n return []\n return heapq.nlargest(n, nums)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(numbers, n):\n return heapq.nlargest(n, numbers)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n if not nums or n <= 0:\n return []\n\n # Use heapq to get the n largest elements\n largest_nums = heapq.nlargest(n, nums)\n\n # Return the largest numbers in descending order\n return sorted(largest_nums, reverse=True)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(numbers, n):\n \"\"\"\n Function to find the n largest integers from a given list of numbers, returned in descending order.\n \"\"\"\n if n > len(numbers):\n raise ValueError(\"n cannot be larger than the list of numbers\")\n\n # Using heapq to find the n largest elements\n largest_numbers = heapq.nlargest(n, numbers)\n\n # Returning the elements in descending order\n return sorted(largest_numbers, reverse=True)\nnumbers = [25, 35, 22, 85, 14, 65, 75, 22, 58]\nn = 3", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(numbers, n):\n \"\"\"\n Function to find the n largest integers from a given list of numbers, returned in descending order.\n \"\"\"\n if n <= 0:\n return []\n\n # Using heapq to get the n largest elements\n largest_numbers = heapq.nlargest(n, numbers)\n\n # Sorting the largest numbers in descending order\n return sorted(largest_numbers, reverse=True)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n return heapq.nlargest(n, nums)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(numbers, n):\n \"\"\"\n Function to find the n largest integers from a given list of numbers, returned in descending order.\n\n Parameters:\n numbers (list): List of integers\n n (int): Number of largest integers to find\n\n Returns:\n list: A list of the n largest integers in descending order\n \"\"\"\n # Create a min-heap with the n largest numbers\n largest_numbers = heapq.nlargest(n, numbers)\n # Return the numbers in descending order\n return sorted(largest_numbers, reverse=True)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(numbers, n):\n # Use heapq to find the n largest elements\n largest_numbers = heapq.nlargest(n, numbers)\n # Return the numbers in descending order\n return sorted(largest_numbers, reverse=True)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n # Use a min-heap to efficiently get the n largest elements\n largest_n = heapq.nlargest(n, nums)\n return largest_n", "matching_cluster_idx": 9}]}, "Mbpp/9": {"dps": 74.25170068027211, "dps_norm": 61.5, "pass@1": 73.0, "profiled": [{"solution": "def find_Rotations(s):\n n = len(s)\n # If the string length is less than 1, no rotation is needed\n if n < 1:\n return 0\n # Concatenate the string with itself\n s = s + s\n # Check if string has the same pattern throughout\n if s[1:n] == s[:n-1]:\n return 1\n # Find the first occurrence of the string in the concatenated string after the first character\n try:\n return s.index(s[:n], 1)\n except ValueError:\n return 0", "matching_cluster_idx": 7}, {"solution": "def find_Rotations(s: str) -> int:\n n = len(s)\n if n == 0:\n return 0\n\n for i in range(1, n):\n rotated = s[i:] + s[:i]\n if rotated == s:\n return i\n return n", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(s):\n n = len(s)\n if n == 0:\n return 0\n\n for i in range(1, n):\n rotated_s = s[i:] + s[:i]\n if rotated_s == s:\n return i\n\n return n", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(s: str) -> int:\n # If the string is empty, return 0 since no rotations are needed.\n if not s:\n return 0\n\n # Concatenate the string with itself to handle rotations efficiently.\n combined = s + s\n # Search for the first occurrence of the original string starting from the second character.\n first_occurrence = combined.find(s, 1)\n\n # If not found, it means no rotations can make the string match.\n if first_occurrence == -1:\n return -1\n\n return first_occurrence", "matching_cluster_idx": 8}, {"solution": "def find_Rotations(s: str) -> int:\n n = len(s)\n\n # Special case when the string is empty\n if n == 0:\n return 0\n\n # Concatenate the string with itself\n concatenated = s + s\n\n # Find the second occurrence of the original string in the concatenated string\n second_occurrence = concatenated.find(s, 1)\n\n # If the string cannot be rotated to get the same string, return 0\n if second_occurrence == -1:\n return 0\n\n # The minimum number of rotations is the index of the second occurrence\n return second_occurrence", "matching_cluster_idx": 7}, {"solution": "def find_Rotations(s):\n # Length of the string\n n = len(s)\n\n # Edge case: If the string is empty\n if n == 0:\n return 0\n\n # Check for minimum number of rotations\n for i in range(1, n):\n # Creating a rotated version of the string\n rotated = s[i:] + s[:i]\n\n # If the rotated string matches the original string\n if s == rotated:\n return i\n\n # If no rotation matches the string, return the length of the string\n return n", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(s):\n n = len(s)\n concatenated_s = s + s\n\n for i in range(1, n):\n if concatenated_s[i:i + n] == s:\n return i\n\n return n", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(s: str) -> int:\n if not s:\n return 0\n\n # Concatenate the string with itself to facilitate circular search\n concatenated_string = s + s\n\n # Find the first occurrence of the original string within the concatenated string,\n # starting from the second character to avoid 0-rotation case\n first_occurrence = concatenated_string.find(s, 1)\n\n # If there's no rotation that results in the same string, return the length of the string\n # Otherwise, return the index where the rotation starts\n return len(s) if first_occurrence == -1 else first_occurrence", "matching_cluster_idx": 8}, {"solution": "def find_Rotations(s):\n n = len(s)\n if n == 0:\n return 0\n\n # Concatenate the string with itself to handle rotations\n concatenated = s + s\n\n # Find the minimum rotation\n for i in range(1, n):\n rotated = concatenated[i:i+n]\n if rotated == s:\n return i\n\n return n", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(s):\n \"\"\"\n Find the minimum number of rotations (greater than 0) required to get the same string.\n\n :param s: Input string\n :return: Minimum number of rotations needed to get the same string\n \"\"\"\n n = len(s)\n\n # Check if the string is of length 1 or empty\n if n <= 1:\n return 1 # or return 0 if you consider no rotations as valid for single character or empty string\n\n # Concatenate the string with itself to enable checking for rotations easily\n double_s = s + s\n\n # Loop through potential starting points of rotated substrings in the doubled string\n for i in range(1, n):\n rotated_sub_str = double_s[i:i + n]\n if rotated_sub_str == s:\n return i\n\n # If no rotation gives the same string, return n (indicating no such rotation)\n return n", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(s: str) -> int:\n if not s:\n return 0\n\n n = len(s)\n rotated_str = s + s\n\n for i in range(1, n):\n substr = rotated_str[i:i+n]\n if substr == s:\n return i\n\n return n", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(s):\n n = len(s)\n\n if n == 0:\n return 0\n\n for i in range(1, n):\n rotated = s[i:] + s[:i]\n if rotated == s:\n return i\n\n return n", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(s):\n if not s:\n return 0\n n = len(s)\n for i in range(1, n):\n rotated = s[i:] + s[:i]\n if rotated == s:\n return i\n return n", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(s: str) -> int:\n if not s:\n return 0\n\n # Concatenate the string to itself for easier rotation checks\n concat_s = s + s\n length = len(s)\n\n # Check all possible rotations\n for i in range(1, length):\n rotated_s = concat_s[i:i + length]\n if rotated_s == s:\n return i\n\n return length # If no valid rotation found other than the original", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(s):\n n = len(s)\n for i in range(1, n):\n # Check if rotating the string by i positions results in the same string\n if s == s[-i:] + s[:-i]:\n return i\n return n", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(s: str) -> int:\n if not s:\n return 0\n\n n = len(s)\n for i in range(1, n):\n rotated_s = s[i:] + s[:i]\n if rotated_s == s:\n return i\n\n return n", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(s: str) -> int:\n # Base case: if string length is less than 2, any rotation will result in the same string.\n if len(s) < 2:\n return 1\n\n # Combining the string with itself to handle rotations.\n s_double = s + s\n\n # Find the first occurrence of the string in the doubled string (excluding the first position).\n first_occurrence = s_double.find(s, 1, len(s_double) - 1)\n\n # If the string is not found, return the length of the string (full rotation).\n if first_occurrence == -1:\n return len(s)\n\n # Calculate the number of rotations needed.\n return first_occurrence", "matching_cluster_idx": 8}, {"solution": "def find_Rotations(s):\n \"\"\"\n Function to find the minimum number of rotations (greater than 0) required\n to get the same string.\n\n :param s: Input string\n :return: Minimum number of rotations required\n \"\"\"\n n = len(s)\n\n # Checking all rotations from 1 to n-1\n for i in range(1, n):\n rotated = s[i:] + s[:i]\n if rotated == s:\n return i\n\n return n # Return n if no rotations are possible", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(s):\n n = len(s)\n\n for i in range(1, n):\n rotated = s[i:] + s[:i]\n if rotated == s:\n return i\n\n return n", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(s):\n n = len(s)\n if n == 0 or n == 1:\n return 1\n\n for i in range(1, n):\n rotated_str = s[i:] + s[:i]\n if rotated_str == s:\n return i\n\n return n", "matching_cluster_idx": 4}]}, "Mbpp/11": {"dps": 87.54480286738351, "dps_norm": 93.88888888888889, "pass@1": 75.0, "profiled": [{"solution": "def remove_Occ(input_string, char):\n # Find the first occurrence of the character\n first_index = input_string.find(char)\n # Find the last occurrence of the character\n last_index = input_string.rfind(char)\n\n # If the character is not found, return the original string\n if first_index == -1 or last_index == -1:\n return input_string\n\n # If the first and last indexes are the same, return the string without the character\n if first_index == last_index:\n return input_string[:first_index] + input_string[first_index + 1:]\n\n # Remove the first and last occurrence of the character\n result = input_string[:first_index] + input_string[first_index + 1:last_index] + input_string[last_index + 1:]\n return result", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(string, char):\n if char not in string:\n return string\n\n # Find the first occurrence\n first_index = string.index(char)\n\n # Find the last occurrence\n last_index = string.rindex(char)\n\n # Concatenate parts of the string, excluding first and last occurrences of the character\n result = string[:first_index] + string[first_index + 1:last_index] + string[last_index + 1:]\n\n return result", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(s, char):\n # Ensure the string s and char are provided\n if not s or not char:\n return s\n\n # Remove the first occurrence of char\n first_occurrence = s.find(char)\n if first_occurrence != -1:\n s = s[:first_occurrence] + s[first_occurrence + 1:]\n\n # Remove the last occurrence of char\n last_occurrence = s.rfind(char)\n if last_occurrence != -1:\n s = s[:last_occurrence] + s[last_occurrence + 1:]\n\n return s", "matching_cluster_idx": 7}, {"solution": "def remove_Occ(s, char):\n \"\"\"\n This function removes the first and last occurrence of a given character from the string.\n\n :param s: The input string\n :param char: The character to be removed\n :return: The modified string with the first and last occurrence of the character removed\n \"\"\"\n if char not in s:\n return s\n\n first_occurrence = s.find(char)\n last_occurrence = s.rfind(char)\n\n if first_occurrence == -1 or last_occurrence == -1:\n return s\n\n if first_occurrence == last_occurrence:\n return s[:first_occurrence] + s[first_occurrence+1:]\n\n return s[:first_occurrence] + s[first_occurrence+1:last_occurrence] + s[last_occurrence+1:]", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(s, char):\n # Find first and last occurrence of the character\n first_index = s.find(char)\n last_index = s.rfind(char)\n\n if first_index == -1 or last_index == -1:\n # If the character is not found in the string, return the original string\n return s\n\n if first_index == last_index:\n # If there is only one occurrence, remove it\n return s[:first_index] + s[first_index + 1:]\n else:\n # Remove first and last occurrence\n return s[:first_index] + s[first_index + 1:last_index] + s[last_index + 1:]", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(s, char):\n # Find the first and last occurrence of the character\n first_occ = s.find(char)\n last_occ = s.rfind(char)\n\n # If the character is not found in the string, return the original string\n if first_occ == -1:\n return s\n\n # If the first and last occurrence are the same, remove only one occurrence\n if first_occ == last_occ:\n return s[:first_occ] + s[first_occ+1:]\n\n # Remove both the first and the last occurrence\n return s[:first_occ] + s[first_occ+1:last_occ] + s[last_occ+1:]", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(s, char):\n if not s:\n return s\n\n first_occurrence = s.find(char)\n last_occurrence = s.rfind(char)\n\n if first_occurrence == -1 or last_occurrence == -1:\n return s\n\n result = s[:first_occurrence] + s[first_occurrence+1:last_occurrence] + s[last_occurrence+1:]\n return result", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(s, char):\n if not s:\n return s\n\n first_index = s.find(char)\n if first_index == -1:\n return s\n\n last_index = s.rfind(char)\n if first_index == last_index:\n return s[:first_index] + s[first_index+1:]\n\n return s[:first_index] + s[first_index+1:last_index] + s[last_index+1:]", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(string, char):\n # Finding first and last occurrence of the character\n first_occ = string.find(char)\n last_occ = string.rfind(char)\n\n # Check if the character exists in the string\n if first_occ == -1:\n return string\n\n # Creating the new string excluding first and last occurrence of the character\n new_str = string[:first_occ] + string[first_occ+1:last_occ] + string[last_occ+1:]\n\n return new_str", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(s, char):\n if not s:\n return s\n # Find the first and last occurrences of the character\n first_index = s.find(char)\n last_index = s.rfind(char)\n\n # If the character is not found, return the original string\n if first_index == -1 or last_index == -1:\n return s\n\n # If both indices are the same, remove that single character\n if first_index == last_index:\n return s[:first_index] + s[first_index + 1:]\n\n # Remove the first and last occurrence\n return s[:first_index] + s[first_index + 1:last_index] + s[last_index + 1:]", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(s, char):\n # Find the first occurrence of the character\n first_index = s.find(char)\n # If character not found, return the original string\n if first_index == -1:\n return s\n\n # Find the last occurrence of the character\n last_index = s.rfind(char)\n\n # If the string contains only one occurrence\n if first_index == last_index:\n return s[:first_index] + s[first_index+1:]\n\n # Remove the first and last occurrence of the character\n return s[:first_index] + s[first_index+1:last_index] + s[last_index+1:]", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(s, char):\n # Find the first occurrence\n first_index = s.find(char)\n # Find the last occurrence\n last_index = s.rfind(char)\n\n # If both are not found, return the original string\n if first_index == -1 or last_index == -1:\n return s\n\n # If both are the same, return string with the single occurrence removed\n if first_index == last_index:\n return s.replace(char, '', 1)\n\n # Return the string with first and last occurrences removed\n return s[:first_index] + s[first_index + 1:last_index] + s[last_index + 1:]", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(s, char):\n \"\"\"\n Removes the first and last occurrence of a given character from the string.\n\n Args:\n s (str): The input string.\n char (str): The character to be removed.\n\n Returns:\n str: The resulting string after removing the first and last occurrence of the given character.\n \"\"\"\n if char not in s:\n return s\n\n # Find the first occurrence\n first_index = s.index(char)\n\n # Find the last occurrence\n last_index = s.rindex(char)\n\n if first_index == last_index:\n # If there's only one occurrence of the character, remove it\n return s[:first_index] + s[first_index+1:]\n\n # Remove the first and last occurrences\n result = s[:first_index] + s[first_index+1:last_index] + s[last_index+1:]\n return result", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(s, char):\n # find the indexes of first and last occurrence of the character\n first_idx = s.find(char)\n last_idx = s.rfind(char)\n\n # if the character is not in the string, return original string\n if first_idx == -1:\n return s\n\n # if first and last occurrences are the same, remove just one occurrence\n if first_idx == last_idx:\n return s[:first_idx] + s[first_idx+1:]\n\n # slice the string to exclude first and last occurrence\n result = s[:first_idx] + s[first_idx+1:last_idx] + s[last_idx+1:]\n return result", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(string, char):\n # Find the first occurrence of the character\n first_occurrence = string.find(char)\n\n # Find the last occurrence of the character\n last_occurrence = string.rfind(char)\n\n # If the character is not found, return the original string\n if first_occurrence == -1:\n return string\n\n # If the first and last occurrence are the same, remove the single occurrence\n if first_occurrence == last_occurrence:\n return string[:first_occurrence] + string[first_occurrence + 1:]\n\n # Remove the first occurrence\n string = string[:first_occurrence] + string[first_occurrence + 1:]\n\n # Adjust the index of the last occurrence since we have removed one character\n last_occurrence -= 1\n\n # Remove the last occurrence\n string = string[:last_occurrence] + string[last_occurrence + 1:]\n\n return string", "matching_cluster_idx": 7}, {"solution": "def remove_Occ(string, char):\n \"\"\"\n Function to remove first and last occurrence of a given character from the string.\n \"\"\"\n # Convert the string to a list to handle character removal easily\n str_list = list(string)\n\n # Find the first and last occurrences of the character\n first_occ = str_list.index(char) if char in str_list else None\n last_occ = len(str_list) - 1 - str_list[::-1].index(char) if char in str_list else None\n\n # Remove the character at the first and last occurrences if they exist\n if first_occ is not None:\n str_list.pop(first_occ)\n if first_occ != last_occ:\n str_list.pop(last_occ - 1)\n\n # Convert the list back to a string\n result_string = ''.join(str_list)\n return result_string", "matching_cluster_idx": -1}, {"solution": "def remove_Occ(s, char):\n \"\"\"\n Function to remove first and last occurrence of a given character from the string.\n \"\"\"\n # Find the first occurrence of the character\n first_index = s.find(char)\n if first_index == -1:\n # Character not found in string\n return s\n\n # Find the last occurrence of the character\n last_index = s.rfind(char)\n if last_index == first_index:\n # Only one occurrence of the character\n return s[:first_index] + s[first_index+1:]\n\n # Build the resulting string excluding first and last occurrences of the character\n result = s[:first_index] + s[first_index+1:last_index] + s[last_index+1:]\n return result", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(s, char):\n # Find the indices of the first and last occurrence of the character\n first_occ = s.find(char)\n last_occ = s.rfind(char)\n\n # If the character is not in the string, return the original string\n if first_occ == -1 or last_occ == -1:\n return s\n\n # Slice the string to remove the first and last occurrences\n return s[:first_occ] + s[first_occ + 1:last_occ] + s[last_occ + 1:]", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(s, char):\n # Find the first and last occurrence of the character\n first_occ = s.find(char)\n last_occ = s.rfind(char)\n\n if first_occ == -1: # char not found\n return s\n\n # Remove the first and last occurrence\n if first_occ == last_occ: # only one occurrence\n return s[:first_occ] + s[first_occ + 1:]\n else:\n return s[:first_occ] + s[first_occ + 1:last_occ] + s[last_occ + 1:]", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(input_string, char_to_remove):\n # Find the first and last occurrence of the character\n first_index = input_string.find(char_to_remove)\n last_index = input_string.rfind(char_to_remove)\n\n # If the character is not in the string, return the original string\n if first_index == -1 or last_index == -1:\n return input_string\n\n # Create a new string excluding the first and last occurrence of the character\n result = input_string[:first_index] + input_string[first_index+1:last_index] + input_string[last_index+1:]\n\n return result", "matching_cluster_idx": 8}]}, "Mbpp/12": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 99.0, "profiled": [{"solution": "def sort_matrix(matrix):\n return sorted(matrix, key=sum)", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Sort the matrix based on the sum of each row\n return sorted(matrix, key=sum)", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Sort the matrix by the sum of its rows\n return sorted(matrix, key=sum)", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # The sorted function returns a new list which is sorted based on the key function provided.\n # The key function here is sum which will sum the elements in each sublist and the sorted function\n # will sort the sublists according to their sums.\n return sorted(matrix, key=sum)", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Sort the matrix based on the sum of its rows\n sorted_matrix = sorted(matrix, key=sum)\n return sorted_matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Sort the matrix based on the sum of its rows\n sorted_matrix = sorted(matrix, key=sum)\n return sorted_matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"\n Sorts a given matrix in ascending order according to the sum of its rows.\n \"\"\"\n # Sort the matrix rows based on the sum of elements in each row\n sorted_matrix = sorted(matrix, key=sum)\n return sorted_matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Sort the matrix based on the sum of each row\n sorted_matrix = sorted(matrix, key=sum)\n return sorted_matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n return sorted(matrix, key=sum)", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"\n Sorts the given matrix in ascending order according to the sum of its rows.\n\n Parameters:\n matrix (list of list of int): The input matrix to be sorted.\n\n Returns:\n list of list of int: The sorted matrix.\n \"\"\"\n # Sort the matrix by the sum of its rows\n sorted_matrix = sorted(matrix, key=sum)\n return sorted_matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Sort the matrix based on the sum of its rows\n matrix.sort(key=sum)\n return matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Sort the matrix based on the sum of each row\n return sorted(matrix, key=lambda row: sum(row))", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Sort the matrix based on the sum of rows.\n sorted_matrix = sorted(matrix, key=sum)\n return sorted_matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Sort the matrix rows based on the sum of each row\n return sorted(matrix, key=sum)", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Sort the matrix based on the sum of its rows\n return sorted(matrix, key=sum)", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"\n Sort a given matrix in ascending order according to the sum of its rows.\n \"\"\"\n return sorted(matrix, key=lambda row: sum(row))", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n return sorted(matrix, key=sum)", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Calculate sum of each row and pair it with the row itself\n paired_matrix = [(sum(row), row) for row in matrix]\n # Sort the paired matrix using the sum of the rows as the key\n paired_matrix.sort(key=lambda x: x[0])\n # Return only the sorted rows\n sorted_matrix = [row for _, row in paired_matrix]\n return sorted_matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # sort the matrix according to the sum of each row in ascending order\n return sorted(matrix, key=sum)", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n \"\"\"\n Sorts a given matrix in ascending order according to the sum of its rows.\n\n Parameters:\n matrix (list of list of int): The input matrix.\n\n Returns:\n list of list of int: The matrix sorted according to the sum of its rows.\n \"\"\"\n # Sort the matrix based on the sum of its rows\n sorted_matrix = sorted(matrix, key=lambda row: sum(row))\n return sorted_matrix", "matching_cluster_idx": 15}]}, "Mbpp/16": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 83.0, "profiled": [{"solution": "import re\ndef text_lowercase_underscore(input_string):\n # Define the pattern to match lowercase letters joined with underscores\n pattern = r'^[a-z]+(_[a-z]+)*$'\n return bool(re.match(pattern, input_string))", "matching_cluster_idx": 7}, {"solution": "import re\ndef text_lowercase_underscore(input_string):\n \"\"\"\n Checks if the input string contains sequences of lowercase letters joined with an underscore.\n\n Parameters:\n input_string (str): The string to check.\n\n Returns:\n bool: True if the input string contains sequences of lowercase letters joined with an underscore, False otherwise.\n \"\"\"\n # Regular expression to match sequences of lowercase letters joined with underscores\n pattern = re.compile(r'^[a-z]+(_[a-z]+)*$')\n\n # Return True if the input string matches the pattern, False otherwise\n return bool(pattern.match(input_string))", "matching_cluster_idx": 7}, {"solution": "import re\ndef text_lowercase_underscore(s: str) -> bool:\n # Define a regex pattern to check for lowercase letters followed by underscore, one or multiple times\n pattern = re.compile(r'^[a-z]+(_[a-z]+)*$')\n # Check if the input string matches the pattern\n return bool(pattern.match(s))", "matching_cluster_idx": 7}, {"solution": "import re\ndef text_lowercase_underscore(text):\n \"\"\"\n This function returns True if the input string contains sequences of lowercase letters joined with an underscore,\n and False otherwise.\n \"\"\"\n # Regular expression to match sequences of lowercase letters joined with underscores\n pattern = r'^([a-z]+_)*[a-z]+$'\n\n # Use the fullmatch method to check if the entire string matches the pattern\n return bool(re.fullmatch(pattern, text))", "matching_cluster_idx": 7}, {"solution": "import re\ndef text_lowercase_underscore(input_string):\n \"\"\"\n Returns True if the input string contains sequences of lowercase letters joined with an underscore.\n Returns False otherwise.\n \"\"\"\n # Define the regex pattern for lowercase letters separated by underscores\n pattern = r'^[a-z]+(?:_[a-z]+)*$'\n\n # Use the fullmatch method to check if the entire string matches the pattern\n if re.fullmatch(pattern, input_string):\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def text_lowercase_underscore(input_string):\n import re\n pattern = r'^[a-z]+(_[a-z]+)*$'\n if re.match(pattern, input_string):\n return True\n else:\n return False", "matching_cluster_idx": 7}, {"solution": "import re\ndef text_lowercase_underscore(input_string: str) -> bool:\n \"\"\"\n Returns True if the input string contains sequences of lowercase letters joined with an underscore,\n and False otherwise.\n \"\"\"\n # Define the regular expression pattern\n pattern = r'^[a-z]+(_[a-z]+)*$'\n\n # Use the re.fullmatch function to check if the entire string matches the pattern\n if re.fullmatch(pattern, input_string):\n return True\n else:\n return False", "matching_cluster_idx": 7}, {"solution": "import re\ndef text_lowercase_underscore(text):\n # Regular expression pattern to match lowercase letters joined with underscores\n pattern = r'^[a-z]+(_[a-z]+)*$'\n # Using re.match to check if the entire string matches the pattern\n if re.match(pattern, text):\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "import re\ndef text_lowercase_underscore(input_string):\n # Using regular expression to match strings with sequences of lowercase letters joined with an underscore\n pattern = r'^[a-z]+(_[a-z]+)*$'\n return bool(re.match(pattern, input_string))", "matching_cluster_idx": 7}, {"solution": "import re\ndef text_lowercase_underscore(input_string):\n # Regular expression to match sequences of lowercase letters joined with underscores\n pattern = r'^[a-z]+(_[a-z]+)*$'\n if re.match(pattern, input_string):\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "import re\ndef text_lowercase_underscore(s):\n # Use regular expression to match lowercase letters joined by underscores\n pattern = r'^[a-z]+(_[a-z]+)*$'\n return bool(re.match(pattern, s))", "matching_cluster_idx": 7}, {"solution": "import re\ndef text_lowercase_underscore(input_string):\n \"\"\"\n Checks if the input string contains sequences of lowercase letters joined with an underscore.\n\n Args:\n input_string (str): The string to check.\n\n Returns:\n bool: True if the string matches the pattern, False otherwise.\n \"\"\"\n pattern = re.compile(r'^[a-z]+(_[a-z]+)*$')\n return bool(pattern.match(input_string))", "matching_cluster_idx": 7}, {"solution": "import re\ndef text_lowercase_underscore(input_string):\n \"\"\"\n Returns True if the input string contains sequences of lowercase letters joined with an underscore,\n and False otherwise.\n \"\"\"\n # Use regular expression to check if the input string matches the desired pattern\n pattern = re.compile(r'^[a-z]+(?:_[a-z]+)*$')\n return bool(pattern.match(input_string))", "matching_cluster_idx": 7}, {"solution": "import re\ndef text_lowercase_underscore(input_string):\n \"\"\"\n Returns True if the input string contains sequences of lowercase letters joined with an underscore, and False otherwise.\n \"\"\"\n # Define the regex pattern for lowercase letters joined with underscores\n pattern = r'^[a-z]+(_[a-z]+)*$'\n\n # Use regex to match the entire string\n if re.match(pattern, input_string):\n return True\n else:\n return False", "matching_cluster_idx": 7}, {"solution": "import re\ndef text_lowercase_underscore(input_string):\n pattern = re.compile(r'^([a-z]+_)*[a-z]+$')\n if pattern.match(input_string):\n return True\n else:\n return False", "matching_cluster_idx": 7}, {"solution": "import re\ndef text_lowercase_underscore(input_string):\n \"\"\"\n This function returns True if the input string contains sequences of\n lowercase letters joined with an underscore and False otherwise.\n \"\"\"\n # Regular expression to match lowercase letters and underscores\n pattern = re.compile(r'^[a-z]+(_[a-z]+)*$')\n\n # Check if the input string matches the pattern\n if pattern.match(input_string):\n return True\n else:\n return False", "matching_cluster_idx": 7}, {"solution": "import re\ndef text_lowercase_underscore(input_string):\n \"\"\"\n This function checks if the input string contains sequences of lowercase letters joined with an underscore.\n\n Args:\n input_string (str): The input string to check.\n\n Returns:\n bool: True if the input string contains sequences of lowercase letters joined with an underscore, otherwise False.\n \"\"\"\n pattern = r'^[a-z]+(_[a-z]+)*$'\n return bool(re.match(pattern, input_string))", "matching_cluster_idx": 7}, {"solution": "import re\ndef text_lowercase_underscore(input_string):\n # Define a regular expression pattern to match sequences of lowercase letters joined with underscores.\n pattern = r'^[a-z]+(_[a-z]+)*$'\n\n # Check if the input string matches the pattern\n if re.match(pattern, input_string):\n return True\n else:\n return False", "matching_cluster_idx": 7}, {"solution": "import re\ndef text_lowercase_underscore(input_string):\n # Using regex to check if the string contains sequences of lowercase letters joined with an underscore\n pattern = r'^[a-z]+(_[a-z]+)*$'\n return bool(re.match(pattern, input_string))", "matching_cluster_idx": 7}, {"solution": "import re\ndef text_lowercase_underscore(input_string):\n # Check if the input string matches the pattern where lowercase letters are joined with underscores.\n # The pattern will ensure that the string contains only lowercase letters and underscores,\n # and that it does not start or end with an underscore and there are no consecutive underscores.\n pattern = r'^[a-z]+(_[a-z]+)*$'\n return bool(re.match(pattern, input_string))", "matching_cluster_idx": 7}]}, "Mbpp/19": {"dps": 73.48484848484848, "dps_norm": 85.0, "pass@1": 95.0, "profiled": [{"solution": "def test_duplicate(arr):\n \"\"\"\n This function checks whether the given array of integers contains any duplicate element.\n :param arr: list of integers\n :return: boolean, True if there are duplicates, False otherwise\n \"\"\"\n return len(arr) != len(set(arr))", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(arr):\n return len(arr) != len(set(arr))", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(arr):\n \"\"\"\n Function to determine if the array contains any duplicate elements.\n :param arr: List of integers\n :return: Boolean indicating if there is any duplicate element in the array\n \"\"\"\n return len(arr) != len(set(arr))", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(arr):\n \"\"\"\n Function to check if there are any duplicate elements in the given array.\n Args:\n arr (list): List of integers\n\n Returns:\n bool: True if there are duplicates, False otherwise\n \"\"\"\n return len(arr) != len(set(arr))", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(array):\n \"\"\"\n This function checks whether a given array of integers contains any duplicate element.\n \"\"\"\n # Create a set to store unique elements\n unique_elements = set()\n\n for element in array:\n # If the element is already in the set, there's a duplicate\n if element in unique_elements:\n return True\n # Add the element to the set\n unique_elements.add(element)\n\n # No duplicates found\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(arr):\n \"\"\"\n Function to check if the given array contains any duplicate elements.\n\n :param arr: List of integers\n :return: Boolean indicating presence of duplicate elements\n \"\"\"\n if len(arr) != len(set(arr)):\n return True\n return False", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(arr):\n \"\"\"\n This function checks whether the given array of integers contains any duplicate element.\n\n :param arr: List of integers\n :return: Boolean value (True if there is at least one duplicate, False otherwise)\n \"\"\"\n return len(arr) != len(set(arr))", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(arr):\n return len(arr) != len(set(arr))", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(arr):\n # Use a set to keep track of elements encountered so far\n seen = set()\n for elem in arr:\n if elem in seen:\n return True\n seen.add(elem)\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(arr):\n \"\"\"\n Function to check if the given array contains any duplicate elements.\n\n Args:\n arr (list of int): The array to check for duplicates.\n\n Returns:\n bool: True if there are duplicates, False otherwise.\n \"\"\"\n # Use a set to track elements as we iterate through the array\n seen = set()\n for num in arr:\n if num in seen:\n return True\n seen.add(num)\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(arr):\n \"\"\"\n Function to find whether a given array of integers contains any duplicate element.\n\n Parameters:\n arr (list of int): List of integers to check for duplicates.\n\n Returns:\n bool: True if there are duplicates, False otherwise.\n \"\"\"\n # Using a set to keep track of seen elements\n seen = set()\n for num in arr:\n if num in seen:\n return True\n seen.add(num)\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(arr):\n return len(arr) != len(set(arr))", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(arr):\n # Convert the array to a set and compare lengths\n return len(arr) != len(set(arr))", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(arr):\n \"\"\"\n Function to check if there are any duplicate elements in the given array.\n\n Parameters:\n arr (list): List of integers\n\n Returns:\n bool: True if there are duplicate elements, False otherwise\n \"\"\"\n # Convert the list to a set to remove duplicates\n unique_elements = set(arr)\n\n # If the length of the set is different from the length of the list,\n # it means there were duplicates in the list.\n return len(unique_elements) != len(arr)", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(arr):\n \"\"\"\n Function to check if the given array contains any duplicate elements.\n\n Parameters:\n arr (list of int): A list of integers.\n\n Returns:\n bool: True if the array contains any duplicate elements, False otherwise.\n \"\"\"\n # Convert the list to a set to remove duplicates and compare lengths\n return len(arr) != len(set(arr))", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(arr):\n return len(arr) != len(set(arr))", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(arr):\n \"\"\"\n Function to check if there are any duplicate elements in the given array.\n \"\"\"\n # Create an empty set to store elements seen so far\n seen = set()\n\n # Iterate through each element in the array\n for num in arr:\n # If the element is already in the set, it means there is a duplicate\n if num in seen:\n return True\n # Add the element to the set\n seen.add(num)\n\n # If no duplicates were found, return False\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(arr):\n \"\"\"\n Function to find whether a given array of integers contains any duplicate element.\n\n Parameters:\n arr (list): List of integers\n\n Returns:\n bool: True if there is any duplicate element, False otherwise\n \"\"\"\n return len(arr) != len(set(arr))", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(arr):\n \"\"\"\n This function checks if there are any duplicate elements in the given list.\n\n Parameters:\n arr (list): List of integers to check for duplicates.\n\n Returns:\n bool: True if there are duplicates, False otherwise.\n \"\"\"\n return len(arr) != len(set(arr))", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(arr):\n \"\"\"\n Function to find whether a given array of integers contains any duplicate element.\n :param arr: List of integers\n :return: Boolean indicating presence of duplicates\n \"\"\"\n return len(arr) != len(set(arr))", "matching_cluster_idx": 11}]}, "Mbpp/62": {"dps": 83.5, "dps_norm": 89.0, "pass@1": 100.0, "profiled": [{"solution": "def smallest_num(numbers):\n \"\"\"\n Find the smallest number in a list.\n\n Parameters:\n numbers (list): A list of integers.\n\n Returns:\n int: The smallest integer in the list.\n \"\"\"\n if not numbers: # Handle the edge case where the list is empty\n raise ValueError(\"The list should not be empty.\")\n return min(numbers)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(numbers):\n \"\"\"\n This function returns the smallest number in the given list of numbers.\n\n :param numbers: List of integers\n :return: The smallest integer in the list\n \"\"\"\n return min(numbers)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(numbers):\n \"\"\"\n This function takes a list of numbers and returns the smallest number.\n\n :param numbers: List of integers\n :return: The smallest integer from the list\n \"\"\"\n if not numbers:\n raise ValueError(\"The list is empty.\")\n\n smallest = numbers[0]\n for num in numbers:\n if num < smallest:\n smallest = num\n\n return smallest", "matching_cluster_idx": 3}, {"solution": "def smallest_num(numbers):\n \"\"\"\n Find the smallest number in a list.\n\n Parameters:\n numbers (list): List of integers\n\n Returns:\n int: The smallest number in the list\n \"\"\"\n if not numbers:\n raise ValueError(\"The list is empty\")\n return min(numbers)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(numbers):\n \"\"\"\n This function takes a list of numbers as input and returns the smallest number in the list.\n\n :param numbers: List of integers\n :return: Smallest integer in the list\n \"\"\"\n if not numbers:\n raise ValueError(\"The list is empty\")\n\n smallest = numbers[0]\n for num in numbers:\n if num < smallest:\n smallest = num\n\n return smallest", "matching_cluster_idx": 3}, {"solution": "def smallest_num(numbers):\n \"\"\"\n Function to find the smallest number in a list.\n\n :param numbers: List of numbers\n :return: Smallest number in the list\n \"\"\"\n if not numbers:\n raise ValueError(\"The list is empty\")\n return min(numbers)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(numbers):\n \"\"\"\n This function returns the smallest number in the given list.\n \"\"\"\n if not numbers:\n raise ValueError(\"The list should not be empty\")\n\n return min(numbers)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(lst):\n \"\"\"\n Find the smallest number in a list.\n\n Parameters:\n lst (list of int): List of integers\n\n Returns:\n int: Smallest integer in the list\n \"\"\"\n if not lst:\n raise ValueError(\"The list should not be empty.\")\n\n smallest = lst[0]\n for num in lst[1:]:\n if num < smallest:\n smallest = num\n return smallest", "matching_cluster_idx": 3}, {"solution": "def smallest_num(lst):\n \"\"\"Find the smallest number in a list.\"\"\"\n if not lst: # Check if the list is empty\n raise ValueError(\"The list is empty\")\n smallest = lst[0]\n for num in lst:\n if num < smallest:\n smallest = num\n return smallest", "matching_cluster_idx": 3}, {"solution": "def smallest_num(numbers):\n \"\"\"Find the smallest number in a list.\"\"\"\n if not numbers:\n raise ValueError(\"List cannot be empty.\")\n return min(numbers)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(num_list):\n \"\"\"\n Function to find the smallest number in a list.\n\n Args:\n num_list (list): List of integers\n\n Returns:\n int: Smallest integer in the list\n \"\"\"\n if not num_list:\n raise ValueError(\"The list is empty\")\n\n # Initialize the smallest number with the first element in the list\n smallest = num_list[0]\n\n # Iterate through the list and update the smallest number if a smaller one is found\n for num in num_list:\n if num < smallest:\n smallest = num\n\n return smallest", "matching_cluster_idx": 3}, {"solution": "def smallest_num(numbers):\n \"\"\"\n This function takes a list of numbers and returns the smallest number in the list.\n\n :param numbers: list of numbers\n :return: smallest number in the list\n \"\"\"\n if not numbers: # Check if the list is empty\n raise ValueError(\"The list is empty\")\n\n # Initialize the smallest number with the first element of the list\n smallest = numbers[0]\n\n # Iterate over the list and update the smallest number if a smaller one is found\n for num in numbers:\n if num < smallest:\n smallest = num\n\n return smallest", "matching_cluster_idx": 3}, {"solution": "def smallest_num(lst):\n if not lst: # Check if list is empty\n raise ValueError(\"The list is empty\")\n smallest = lst[0] # Assume the first element is the smallest initially\n for num in lst:\n if num < smallest:\n smallest = num\n return smallest", "matching_cluster_idx": 3}, {"solution": "def smallest_num(num_list):\n \"\"\"\n This function takes a list of numbers and returns the smallest number in the list.\n\n :param num_list: List of numbers\n :return: Smallest number in the list\n \"\"\"\n if not num_list: # Check if the list is empty\n raise ValueError(\"The list is empty\")\n\n smallest = num_list[0] # Assume the first element is the smallest\n for num in num_list:\n if num < smallest:\n smallest = num\n return smallest", "matching_cluster_idx": 3}, {"solution": "def smallest_num(numbers):\n if not numbers: # Handle empty list case\n return None\n return min(numbers)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(numbers):\n if not numbers:\n raise ValueError(\"List is empty\")\n return min(numbers)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(numbers):\n \"\"\"\n This function takes a list of numbers as input and returns the smallest number in the list.\n\n :param numbers: List of numbers\n :return: Smallest number in the list\n \"\"\"\n if not numbers:\n raise ValueError(\"The list is empty\")\n\n # Initialize the smallest number to be the first number in the list\n smallest = numbers[0]\n\n # Iterate through the list and update the smallest number if a smaller one is found\n for number in numbers:\n if number < smallest:\n smallest = number\n\n return smallest", "matching_cluster_idx": 3}, {"solution": "def smallest_num(numbers):\n \"\"\"\n Find the smallest number in a list.\n\n :param numbers: List of numbers\n :return: Smallest number in the list\n \"\"\"\n if not numbers: # Check if the list is empty\n raise ValueError(\"The list should not be empty.\")\n return min(numbers)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(numbers):\n if not numbers:\n raise ValueError(\"List is empty\")\n\n smallest = numbers[0]\n for num in numbers:\n if num < smallest:\n smallest = num\n\n return smallest", "matching_cluster_idx": 3}, {"solution": "def smallest_num(lst):\n \"\"\"\n This function returns the smallest number in a list.\n\n Args:\n lst (list): A list of numbers.\n\n Returns:\n int: The smallest number in the list.\n \"\"\"\n if not lst:\n raise ValueError(\"The list is empty.\")\n\n # Initialize the smallest number with the first element of the list\n smallest = lst[0]\n\n # Iterate over the list to find the smallest number\n for num in lst:\n if num < smallest:\n smallest = num\n\n return smallest", "matching_cluster_idx": 3}]}, "Mbpp/75": {"dps": 92.85714285714286, "dps_norm": 66.66666666666667, "pass@1": 100.0, "profiled": [{"solution": "def find_tuples(tuples, k):\n \"\"\"\n This function finds tuples where all elements are divisible by k.\n\n :param tuples: list of tuples containing integers\n :param k: integer divisor\n :return: list of tuples where all elements are divisible by k\n \"\"\"\n result = []\n for tup in tuples:\n if all(x % k == 0 for x in tup):\n result.append(tup)\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n \"\"\"\n This function returns tuples which have all elements divisible by k.\n\n Parameters:\n tuples_list (list of tuple): List containing tuples of integers.\n k (int): The integer to check divisibility.\n\n Returns:\n list: A list of tuples which have all elements divisible by k.\n \"\"\"\n result = [t for t in tuples_list if all(x % k == 0 for x in t)]\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples, k):\n \"\"\"\n Find tuples which have all elements divisible by k from the given list of tuples.\n\n Args:\n tuples (list of tuples): A list containing tuples of integers.\n k (int): The divisor to check divisibility against.\n\n Returns:\n list of tuples: A list of tuples where all elements are divisible by k.\n \"\"\"\n result = []\n for t in tuples:\n if all(x % k == 0 for x in t):\n result.append(t)\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(list_of_tuples, k):\n \"\"\"\n This function finds tuples which have all elements divisible by k from the given list of tuples.\n\n :param list_of_tuples: List of tuples containing integers\n :param k: Integer by which all elements of a tuple must be divisible\n :return: List of tuples that have all elements divisible by k\n \"\"\"\n result = []\n for tup in list_of_tuples:\n if all(x % k == 0 for x in tup):\n result.append(tup)\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n \"\"\"\n This function returns a list of tuples from tuples_list where all elements of each tuple are divisible by k.\n\n :param tuples_list: list of tuples\n :param k: integer, the divisor\n :return: list of tuples\n \"\"\"\n # List comprehension to filter tuples based on the condition that all elements are divisible by k\n return [t for t in tuples_list if all(x % k == 0 for x in t)]", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n \"\"\"\n Find tuples which have all elements divisible by k from the given list of tuples.\n\n Parameters:\n tuples_list (list of tuple): List containing tuples of integers.\n k (int): The divisor to check divisibility.\n\n Returns:\n list of tuple: List of tuples where all elements are divisible by k.\n \"\"\"\n return [t for t in tuples_list if all(x % k == 0 for x in t)]", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n \"\"\"\n Find tuples which have all elements divisible by k from the given list of tuples.\n\n :param tuples_list: List of tuples containing integers\n :param k: Integer divisor\n :return: List of tuples where all elements are divisible by k\n \"\"\"\n return [t for t in tuples_list if all(x % k == 0 for x in t)]", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n \"\"\"\n Function to find tuples which have all elements divisible by k from the given list of tuples.\n\n Parameters:\n tuples_list (list of tuples): List of tuples with integer elements.\n k (int): The divisor to check divisibility.\n\n Returns:\n list of tuples: List of tuples where all elements are divisible by k.\n \"\"\"\n return [t for t in tuples_list if all(x % k == 0 for x in t)]", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples, k):\n \"\"\"\n Finds tuples which have all elements divisible by k from the given list of tuples.\n \"\"\"\n result = []\n for tpl in tuples:\n if all(x % k == 0 for x in tpl):\n result.append(tpl)\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples, k):\n \"\"\"\n Find tuples which have all elements divisible by k from the given list of tuples.\n\n :param tuples: List of tuples to be evaluated\n :param k: The divisor to check each element against\n :return: List of tuples where all elements are divisible by k\n \"\"\"\n result = [t for t in tuples if all(x % k == 0 for x in t)]\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n \"\"\"\n Finds tuples which have all elements divisible by k from the given list of tuples.\n\n :param tuples_list: List of tuples to be checked\n :param k: Integer divisor\n :return: List of tuples where all elements are divisible by k\n \"\"\"\n return [t for t in tuples_list if all(x % k == 0 for x in t)]", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n \"\"\"\n Find tuples which have all elements divisible by k from the given list of tuples.\n\n Parameters:\n tuples_list (list of tuple): List of tuples to be checked.\n k (int): The number by which each element in the tuple must be divisible.\n\n Returns:\n list of tuple: A list of tuples where all elements are divisible by k.\n \"\"\"\n return [t for t in tuples_list if all(x % k == 0 for x in t)]", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n \"\"\"\n Find tuples which have all elements divisible by k from the given list of tuples.\n\n :param tuples_list: List of tuples containing integers\n :param k: Integer divisor\n :return: List of tuples where all elements are divisible by k\n \"\"\"\n return [t for t in tuples_list if all(x % k == 0 for x in t)]", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n \"\"\"\n Function to find tuples which have all elements divisible by k from the given list of tuples.\n\n Parameters:\n tuples_list (list of tuples): List of tuples containing integers\n k (int): Integer by which all elements of the tuple must be divisible\n\n Returns:\n list of tuples: List of tuples where each tuple's elements are all divisible by k\n \"\"\"\n # List comprehension to filter tuples where all elements are divisible by k\n result = [t for t in tuples_list if all(x % k == 0 for x in t)]\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n \"\"\"\n Find tuples which have all elements divisible by k from the given list of tuples.\n\n :param tuples_list: List of tuples\n :param k: Integer divisor\n :return: List of tuples where all elements are divisible by k\n \"\"\"\n result = []\n for tup in tuples_list:\n if all(x % k == 0 for x in tup):\n result.append(tup)\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n \"\"\"\n Find tuples which have all elements divisible by k from the given list of tuples.\n\n :param tuples_list: List of tuples to be checked.\n :param k: The divisor.\n :return: List of tuples with all elements divisible by k.\n \"\"\"\n result = []\n for tpl in tuples_list:\n if all(x % k == 0 for x in tpl):\n result.append(tpl)\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n \"\"\"\n This function finds tuples which have all elements divisible by k.\n\n Args:\n tuples_list (list of tuples): List containing tuples.\n k (int): Number to check divisibility.\n\n Returns:\n list of tuples: List of tuples where all elements are divisible by k.\n \"\"\"\n result = []\n for t in tuples_list:\n if all(x % k == 0 for x in t):\n result.append(t)\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n \"\"\"\n Find tuples where all elements are divisible by k.\n\n Args:\n tuples_list (list of tuples): The list of tuples to be checked.\n k (int): The number to check divisibility against.\n\n Returns:\n list of tuples: A list of tuples where all elements are divisible by k.\n \"\"\"\n result = []\n for t in tuples_list:\n if all(x % k == 0 for x in t):\n result.append(t)\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuple_list, k):\n result = []\n for tup in tuple_list:\n if all(x % k == 0 for x in tup):\n result.append(tup)\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n \"\"\"\n Finds tuples which have all elements divisible by k from the given list of tuples.\n\n :param tuples_list: List of tuples\n :param k: The number which all elements in a tuple must be divisible by\n :return: List of tuples where all elements are divisible by k\n \"\"\"\n result = []\n for tup in tuples_list:\n if all(elem % k == 0 for elem in tup):\n result.append(tup)\n return result", "matching_cluster_idx": 5}]}, "Mbpp/88": {"dps": 92.94117647058823, "dps_norm": 84.28571428571428, "pass@1": 100.0, "profiled": [{"solution": "def freq_count(lst):\n \"\"\"\n This function returns the frequency of all the elements in a list as a dictionary.\n \"\"\"\n frequency_dict = {}\n for element in lst:\n if element in frequency_dict:\n frequency_dict[element] += 1\n else:\n frequency_dict[element] = 1\n return frequency_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n \"\"\"\n This function returns the frequency of all the elements in a list.\n\n Parameters:\n lst (list): The input list.\n\n Returns:\n dict: A dictionary where keys are the elements from the list and values are their respective frequencies.\n \"\"\"\n frequency_dict = {}\n for item in lst:\n if item in frequency_dict:\n frequency_dict[item] += 1\n else:\n frequency_dict[item] = 1\n return frequency_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n frequency = {}\n for element in lst:\n if element in frequency:\n frequency[element] += 1\n else:\n frequency[element] = 1\n return frequency", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n frequency = {}\n for item in lst:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n return frequency", "matching_cluster_idx": 5}, {"solution": "def freq_count(elements):\n frequency_dict = {}\n for element in elements:\n if element in frequency_dict:\n frequency_dict[element] += 1\n else:\n frequency_dict[element] = 1\n return frequency_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n frequency_dict = {}\n for item in lst:\n if item in frequency_dict:\n frequency_dict[item] += 1\n else:\n frequency_dict[item] = 1\n return frequency_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n freq_dict = {}\n for item in lst:\n if item in freq_dict:\n freq_dict[item] += 1\n else:\n freq_dict[item] = 1\n return freq_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n \"\"\"\n Function to get the frequency of all the elements in a list, returned as a dictionary.\n \"\"\"\n freq_dict = {}\n for item in lst:\n if item in freq_dict:\n freq_dict[item] += 1\n else:\n freq_dict[item] = 1\n return freq_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n freq_dict = {}\n for item in lst:\n if item in freq_dict:\n freq_dict[item] += 1\n else:\n freq_dict[item] = 1\n return freq_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n frequency_dict = {}\n for item in lst:\n if item in frequency_dict:\n frequency_dict[item] += 1\n else:\n frequency_dict[item] = 1\n return frequency_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n # Create an empty dictionary to store the frequency of each element\n frequency_dict = {}\n\n # Loop through each element in the list\n for item in lst:\n # If the element is already in the dictionary, increment its count\n if item in frequency_dict:\n frequency_dict[item] += 1\n else:\n # If the element is not in the dictionary, add it with a count of 1\n frequency_dict[item] = 1\n\n return frequency_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(elements):\n \"\"\"\n Function to get the frequency of all the elements in a list, returned as a dictionary.\n \"\"\"\n freq_dict = {}\n for element in elements:\n if element in freq_dict:\n freq_dict[element] += 1\n else:\n freq_dict[element] = 1\n return freq_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n freq_dict = {}\n for elem in lst:\n if elem in freq_dict:\n freq_dict[elem] += 1\n else:\n freq_dict[elem] = 1\n return freq_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n \"\"\"\n This function takes a list and returns a dictionary with the frequency\n of each element in the list.\n\n Parameters:\n lst (list): List of elements\n\n Returns:\n dict: A dictionary with elements as keys and their frequencies as values\n \"\"\"\n freq_dict = {}\n for item in lst:\n if item in freq_dict:\n freq_dict[item] += 1\n else:\n freq_dict[item] = 1\n return freq_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n frequency_dict = {}\n for item in lst:\n if item in frequency_dict:\n frequency_dict[item] += 1\n else:\n frequency_dict[item] = 1\n return frequency_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n frequency = {}\n for item in lst:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n return frequency", "matching_cluster_idx": 5}, {"solution": "from collections import defaultdict\ndef freq_count(lst):\n freq_dict = defaultdict(int)\n for elem in lst:\n freq_dict[elem] += 1\n return dict(freq_dict)", "matching_cluster_idx": 3}, {"solution": "def freq_count(lst):\n freq_dict = {}\n for item in lst:\n if item in freq_dict:\n freq_dict[item] += 1\n else:\n freq_dict[item] = 1\n return freq_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n \"\"\"Returns the frequency of all the elements in a list as a dictionary.\"\"\"\n freq_dict = {}\n for item in lst:\n if item in freq_dict:\n freq_dict[item] += 1\n else:\n freq_dict[item] = 1\n return freq_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(elements):\n freq_dict = {}\n for element in elements:\n if element in freq_dict:\n freq_dict[element] += 1\n else:\n freq_dict[element] = 1\n return freq_dict", "matching_cluster_idx": 5}]}, "Mbpp/90": {"dps": 81.5609756097561, "dps_norm": 87.14285714285714, "pass@1": 41.0, "profiled": [{"solution": "def len_log(words):\n \"\"\"\n This function takes a list of words and returns the length of the longest word.\n \"\"\"\n return len(max(words, key=len))", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n \"\"\"\n Find the length of the longest word in the list.\n\n Parameters:\n words (list): List of strings\n\n Returns:\n int: Length of the longest word\n \"\"\"\n # Check if the list is not empty\n if not words:\n return 0\n\n # Find the longest word using the max function with key as length of the word\n longest_word = max(words, key=len)\n\n # Return the length of the longest word\n return len(longest_word)", "matching_cluster_idx": 6}, {"solution": "def len_log(words):\n \"\"\"\n Function to find the length of the longest word in a list.\n\n Parameters:\n words (list): A list of words.\n\n Returns:\n int: The length of the longest word in the list.\n \"\"\"\n return max(len(word) for word in words)", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n \"\"\"\n This function returns the length of the longest word in a list of words.\n \"\"\"\n if not words:\n return 0\n return max(len(word) for word in words)", "matching_cluster_idx": 5}, {"solution": "def len_log(word_list):\n \"\"\"\n This function takes a list of words and returns the length of the longest word.\n \"\"\"\n # Initialize the variable to store the length of the longest word\n max_length = 0\n\n # Iterate through each word in the list\n for word in word_list:\n # Update max_length if the current word is longer\n if len(word) > max_length:\n max_length = len(word)\n\n return max_length", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n \"\"\"\n Find the length of the longest word in a list of words.\n\n :param words: List of words (strings)\n :return: Length of the longest word\n \"\"\"\n if not words: # Check if the list is empty\n return 0\n\n # Using the built-in `max` function with `key` parameter to get the longest word\n longest_word = max(words, key=len)\n return len(longest_word)", "matching_cluster_idx": 6}, {"solution": "def len_log(words):\n # Return the length of the longest word in the list\n return max(len(word) for word in words)", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n \"\"\"\n This function takes a list of words and returns the length of the longest word.\n\n :param words: list of words\n :return: length of the longest word\n \"\"\"\n return max(len(word) for word in words)", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n \"\"\"\n This function returns the length of the longest word in the given list of words.\n \"\"\"\n max_length = 0\n for word in words:\n if len(word) > max_length:\n max_length = len(word)\n return max_length", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n return max(len(word) for word in words)", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n \"\"\"\n Function to find the length of the longest word in a list of words.\n\n Args:\n words (list): A list of words (strings).\n\n Returns:\n int: Length of the longest word.\n \"\"\"\n if not words:\n return 0\n return max(len(word) for word in words)", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n \"\"\"\n Function to find the length of the longest word in a list of words.\n \"\"\"\n longest_length = 0\n for word in words:\n if len(word) > longest_length:\n longest_length = len(word)\n return longest_length", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n \"\"\"\n Function to find the length of the longest word in a list of words.\n\n :param words: List of words\n :return: Length of the longest word\n \"\"\"\n return max(len(word) for word in words)", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n \"\"\"\n This function returns the length of the longest word in a list.\n\n Parameters:\n words (list): A list of words (strings)\n\n Returns:\n int: Length of the longest word in the list\n \"\"\"\n return max(len(word) for word in words)", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n \"\"\"\n Function to find the length of the longest word in the list.\n \"\"\"\n longest_word_length = 0\n for word in words:\n if len(word) > longest_word_length:\n longest_word_length = len(word)\n return longest_word_length", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n \"\"\"\n Find the length of the longest word in the list.\n\n Parameters:\n words (list of str): List of words.\n\n Returns:\n int: Length of the longest word.\n \"\"\"\n # Ensure the input is a list\n if not isinstance(words, list):\n raise ValueError(\"Input must be a list of words.\")\n\n # Calculate the length of the longest word\n max_length = max(len(word) for word in words)\n\n return max_length", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n \"\"\"\n This function returns the length of the longest word in a list of words.\n\n :param words: list of words (strings)\n :return: length of the longest word\n \"\"\"\n if not words:\n return 0 # Return 0 if the list is empty\n max_length = 0\n for word in words:\n if len(word) > max_length:\n max_length = len(word)\n return max_length", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n \"\"\"\n Function to find the length of the longest word in a list of words.\n\n Parameters:\n words (list of str): List of words.\n\n Returns:\n int: Length of the longest word.\n \"\"\"\n return max(len(word) for word in words)", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n # Initialize the maximum length to 0\n max_length = 0\n\n # Iterate through each word in the list\n for word in words:\n # Update the maximum length if the current word is longer\n if len(word) > max_length:\n max_length = len(word)\n\n return max_length", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n \"\"\"\n This function takes a list of words and returns the length of the longest word.\n \"\"\"\n max_length = 0\n for word in words:\n if len(word) > max_length:\n max_length = len(word)\n return max_length", "matching_cluster_idx": 5}]}, "Mbpp/94": {"dps": 80.10670731707317, "dps_norm": 65.0, "pass@1": 92.0, "profiled": [{"solution": "def index_minimum(tuples_list):\n # Find the tuple with the smallest second value\n min_tuple = min(tuples_list, key=lambda x: x[1])\n # Return the first value of that tuple\n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(tuples_list):\n \"\"\"\n Given a list of tuples, this function returns the first value of the tuple with the smallest second value.\n \"\"\"\n if not tuples_list:\n return None\n\n # Find the tuple with the smallest second value\n min_tuple = min(tuples_list, key=lambda x: x[1])\n\n # Return the first value of this tuple\n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(lst):\n \"\"\"\n Given a list of tuples, return the first value of the tuple with the smallest second value.\n\n :param lst: List of tuples (str, int)\n :return: str\n \"\"\"\n if not lst:\n raise ValueError(\"List cannot be empty\")\n\n # Initialize the minimum value with the second value of the first tuple\n min_tuple = lst[0]\n\n # Iterate over the list of tuples\n for tup in lst:\n if tup[1] < min_tuple[1]:\n min_tuple = tup\n\n return min_tuple[0]", "matching_cluster_idx": 3}, {"solution": "def index_minimum(lst):\n \"\"\"\n Given a list of tuples, return the first value of the tuple with the smallest second value.\n :param lst: List of tuples [(name, value), ...]\n :return: Name with the smallest value\n \"\"\"\n if not lst:\n return None\n return min(lst, key=lambda x: x[1])[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(lst):\n # Find the tuple with the minimum second value\n min_tuple = min(lst, key=lambda x: x[1])\n # Return the first value of the tuple with the smallest second value\n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(tuples):\n # Initialize the minimum tuple with the first element\n min_tuple = tuples[0]\n\n # Iterate over the list of tuples to find the one with the smallest second value\n for t in tuples:\n if t[1] < min_tuple[1]:\n min_tuple = t\n\n # Return the first value of the tuple with the smallest second value\n return min_tuple[0]", "matching_cluster_idx": 3}, {"solution": "def index_minimum(lst):\n \"\"\"\n Given a list of tuples, return the first value of the tuple with the smallest second value.\n :param lst: List of tuples\n :return: First value of the tuple with the smallest second value\n \"\"\"\n if not lst:\n return None\n # Find the tuple with the minimum second value\n min_tuple = min(lst, key=lambda x: x[1])\n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(tuples_list):\n # Find the tuple with the smallest second value\n smallest_tuple = min(tuples_list, key=lambda x: x[1])\n # Return the first value of that tuple\n return smallest_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(tuple_list):\n if not tuple_list:\n return None\n\n # Assume the first tuple has the smallest second value\n min_tuple = tuple_list[0]\n\n # Iterate through the list to find the tuple with the smallest second value\n for t in tuple_list:\n if t[1] < min_tuple[1]:\n min_tuple = t\n\n # Return the first value of the tuple with the smallest second value\n return min_tuple[0]", "matching_cluster_idx": 3}, {"solution": "def index_minimum(tuples_list):\n \"\"\"\n Given a list of tuples, returns the first value of the tuple with the smallest second value.\n\n :param tuples_list: List[Tuple[str, int]]\n :return: str\n \"\"\"\n # Find the tuple with the smallest second value\n min_tuple = min(tuples_list, key=lambda x: x[1])\n # Return the first value of the tuple with the smallest second value\n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(lst):\n \"\"\"\n Given a list of tuples, return the first value of the tuple with the smallest second value.\n \"\"\"\n # Find the tuple with the minimum second value\n min_tuple = min(lst, key=lambda x: x[1])\n # Return the first value of this tuple\n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(tuples_list):\n \"\"\"\n Given a list of tuples, this function returns the first value of the tuple with the smallest second value.\n\n Args:\n tuples_list (list): A list of tuples where each tuple contains a name and a number.\n\n Returns:\n str: The first value of the tuple with the smallest second value.\n \"\"\"\n # Find the tuple with the smallest second value\n min_tuple = min(tuples_list, key=lambda x: x[1])\n\n # Return the first value of that tuple\n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(data):\n return min(data, key=lambda x: x[1])[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(tuples_list):\n # Initialize with the first tuple\n min_tuple = tuples_list[0]\n\n # Iterate over the list of tuples\n for t in tuples_list:\n if t[1] < min_tuple[1]:\n min_tuple = t\n\n # Return the first value of the tuple with the smallest second value\n return min_tuple[0]", "matching_cluster_idx": 3}, {"solution": "def index_minimum(lst):\n # Find the tuple with the smallest second value\n min_tuple = min(lst, key=lambda x: x[1])\n # Return the first value of that tuple\n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(lst):\n \"\"\"\n Given a list of tuples, return the first value of the tuple with the smallest second value.\n\n :param lst: List of tuples where each tuple is in the form (name, score)\n :return: The name associated with the smallest score\n \"\"\"\n if not lst:\n return None\n\n # Initialize with the first tuple\n min_tuple = lst[0]\n\n # Iterate over the list to find the tuple with the smallest second value\n for tup in lst:\n if tup[1] < min_tuple[1]:\n min_tuple = tup\n\n # Return the first value of the tuple with the smallest second value\n return min_tuple[0]", "matching_cluster_idx": 3}, {"solution": "def index_minimum(lst):\n \"\"\"\n Given a list of tuples, returns the first value of the tuple with the smallest second value.\n \"\"\"\n if not lst:\n return None\n\n # Find the tuple with the smallest second value\n min_tuple = min(lst, key=lambda x: x[1])\n\n # Return the first value of the tuple with the smallest second value\n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(list_of_tuples):\n \"\"\"\n Given a list of tuples, this function returns the first value of the tuple with the smallest second value.\n\n :param list_of_tuples: List of tuples where each tuple contains two elements (name, value)\n :return: The first value of the tuple with the smallest second value\n \"\"\"\n # Find the tuple with the smallest second value\n smallest_tuple = min(list_of_tuples, key=lambda x: x[1])\n\n # Return the first value of the tuple\n return smallest_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(tuples_list):\n \"\"\"\n Given a list of tuples, return the first value of the tuple with the smallest second value.\n :param tuples_list: List of tuples (name, value)\n :return: The name associated with the smallest value\n \"\"\"\n # Find the tuple with the smallest second value\n min_tuple = min(tuples_list, key=lambda x: x[1])\n # Return the first value of the tuple\n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(lst):\n \"\"\"\n Given a list of tuples, returns the first value of the tuple with the smallest second value.\n \"\"\"\n # Check if the list is not empty\n if not lst:\n raise ValueError(\"The list is empty\")\n\n # Find the tuple with the smallest second value\n min_tuple = min(lst, key=lambda x: x[1])\n\n # Return the first value of the tuple with the smallest second value\n return min_tuple[0]", "matching_cluster_idx": 2}]}, "Mbpp/96": {"dps": 82.49999999999999, "dps_norm": 56.42857142857142, "pass@1": 64.0, "profiled": [{"solution": "def divisor(n):\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n \"\"\"\n Find the number of divisors of a given integer.\n :param n: an integer\n :return: number of divisors\n \"\"\"\n count = 0\n # Check all numbers from 1 to n (inclusive) to see if they are divisors of n\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n count = 0\n for i in range(1, n+1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n count = 0\n for i in range(1, n+1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n count = 0\n for i in range(1, n+1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n count = 0\n for i in range(1, n+1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n \"\"\"\n Finds the number of divisors of a given integer n.\n\n Parameters:\n n (int): The integer to find the number of divisors for.\n\n Returns:\n int: The number of divisors of n.\n \"\"\"\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n \"\"\"\n Find the number of divisors of a given integer.\n \"\"\"\n if n < 1:\n raise ValueError(\"Input should be a positive integer.\")\n\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n count += 1\n if i != n // i:\n count += 1\n return count", "matching_cluster_idx": 6}, {"solution": "def divisor(n):\n \"\"\"\n Returns the number of divisors of a given integer n.\n \"\"\"\n count = 0\n # Iterate from 1 to the integer n\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n \"\"\"\n Function to find the number of divisors of a given integer.\n \"\"\"\n count = 0\n # Iterate through 1 to n (inclusive)\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n \"\"\"\n Function to find the number of divisors of a given integer.\n\n Parameters:\n n (int): The given integer.\n\n Returns:\n int: The number of divisors.\n \"\"\"\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n count += 1\n if i != n // i:\n count += 1\n return count", "matching_cluster_idx": 6}, {"solution": "def divisor(n):\n \"\"\"\n Function to find the number of divisors of a given integer.\n \"\"\"\n # Handle edge case when n is 1\n if n == 1:\n return 1\n\n # Initialize a count for the number of divisors\n count = 0\n\n # Check all numbers up to the square root of n for efficiency\n i = 1\n while i * i <= n:\n if n % i == 0:\n if i * i == n:\n count += 1 # Only count once if i is the square root\n else:\n count += 2 # Both i and n//i are divisors\n i += 1\n\n return count", "matching_cluster_idx": 5}, {"solution": "def divisor(n):\n count = 0\n for i in range(1, n+1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n \"\"\"\n Function to find the number of divisors of a given integer.\n\n Parameters:\n n (int): The integer to find the number of divisors for.\n\n Returns:\n int: The number of divisors of the given integer.\n \"\"\"\n count = 0\n for i in range(1, int(n ** 0.5) + 1):\n if n % i == 0:\n # If divisors are equal, count only one\n if n // i == i:\n count += 1\n else: # Otherwise count both\n count += 2\n return count", "matching_cluster_idx": 6}, {"solution": "def divisor(n):\n \"\"\"\n Function to find the number of divisors of a given integer.\n\n Args:\n n (int): The integer to find divisors of.\n\n Returns:\n int: Number of divisors.\n \"\"\"\n if n < 1:\n return 0\n\n divisors = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n divisors += 1\n if i != n // i:\n divisors += 1\n return divisors", "matching_cluster_idx": 6}, {"solution": "def divisor(n):\n \"\"\"Finds the number of divisors of a given integer.\"\"\"\n count = 0\n # Iterate through all numbers from 1 to the given number\n for i in range(1, n + 1):\n # Check if the current number divides the given number evenly\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}]}, "Mbpp/97": {"dps": 99.67521367521368, "dps_norm": 88.125, "pass@1": 100.0, "profiled": [{"solution": "from collections import defaultdict\ndef frequency_lists(list_of_lists):\n frequency_dict = defaultdict(int)\n for sublist in list_of_lists:\n for item in sublist:\n frequency_dict[item] += 1\n return dict(frequency_dict)", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(nested_list):\n flattened_list = [element for sublist in nested_list for element in sublist]\n frequency_dict = {}\n\n for element in flattened_list:\n if element in frequency_dict:\n frequency_dict[element] += 1\n else:\n frequency_dict[element] = 1\n\n return frequency_dict", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(list_of_lists):\n flat_list = [item for sublist in list_of_lists for item in sublist]\n frequency_dict = {}\n for item in flat_list:\n if item in frequency_dict:\n frequency_dict[item] += 1\n else:\n frequency_dict[item] = 1\n return frequency_dict", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(input_list):\n flattened_list = [item for sublist in input_list for item in sublist]\n frequency_dict = {}\n for item in flattened_list:\n if item in frequency_dict:\n frequency_dict[item] += 1\n else:\n frequency_dict[item] = 1\n return frequency_dict", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(nested_list):\n # Flatten the list\n flat_list = [item for sublist in nested_list for item in sublist]\n\n # Create a dictionary to store the frequency of each element\n frequency_dict = {}\n\n # Count the frequency of each element\n for item in flat_list:\n if item in frequency_dict:\n frequency_dict[item] += 1\n else:\n frequency_dict[item] = 1\n\n return frequency_dict", "matching_cluster_idx": 6}, {"solution": "from collections import defaultdict\ndef frequency_lists(lists):\n # Initialize a defaultdict with int as the default factory\n frequency_dict = defaultdict(int)\n\n # Flatten the list of lists and count frequencies\n for sublist in lists:\n for item in sublist:\n frequency_dict[item] += 1\n\n # Convert defaultdict to a regular dict before returning\n return dict(frequency_dict)", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lists):\n \"\"\"\n This function takes a list of lists and returns a dictionary with the frequency of each element.\n\n :param lists: List of lists containing integers\n :return: Dictionary with element frequencies\n \"\"\"\n # Flatten the list of lists\n flat_list = [item for sublist in lists for item in sublist]\n\n # Initialize an empty dictionary to keep the frequencies\n frequency_dict = {}\n\n # Count the frequency of each element\n for item in flat_list:\n if item in frequency_dict:\n frequency_dict[item] += 1\n else:\n frequency_dict[item] = 1\n\n return frequency_dict", "matching_cluster_idx": 6}, {"solution": "from collections import defaultdict\ndef frequency_lists(nested_list):\n # Flatten the list of lists\n flat_list = [item for sublist in nested_list for item in sublist]\n\n # Create a frequency dictionary\n frequency_dict = defaultdict(int)\n for item in flat_list:\n frequency_dict[item] += 1\n\n return dict(frequency_dict)", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lst):\n flat_list = [item for sublist in lst for item in sublist]\n frequency = {}\n for item in flat_list:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n return frequency", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lists):\n from collections import Counter\n from itertools import chain\n flattened = chain.from_iterable(lists)\n freq_dict = Counter(flattened)\n return freq_dict", "matching_cluster_idx": 7}, {"solution": "def frequency_lists(list_of_lists):\n # Flatten the list of lists\n flattened_list = [item for sublist in list_of_lists for item in sublist]\n\n # Calculate frequency of each element using a dictionary\n frequency_dict = {}\n for item in flattened_list:\n if item in frequency_dict:\n frequency_dict[item] += 1\n else:\n frequency_dict[item] = 1\n\n return frequency_dict", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lst):\n flattened_list = [item for sublist in lst for item in sublist]\n frequency_dict = {}\n for item in flattened_list:\n if item in frequency_dict:\n frequency_dict[item] += 1\n else:\n frequency_dict[item] = 1\n return frequency_dict", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lists):\n flattened_list = [item for sublist in lists for item in sublist]\n frequency_dict = {}\n for item in flattened_list:\n if item in frequency_dict:\n frequency_dict[item] += 1\n else:\n frequency_dict[item] = 1\n return frequency_dict", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(input_list):\n # Flatten the list of lists into a single list\n flattened_list = [item for sublist in input_list for item in sublist]\n\n # Create a dictionary to store the frequency of each element\n frequency_dict = {}\n\n for item in flattened_list:\n if item in frequency_dict:\n frequency_dict[item] += 1\n else:\n frequency_dict[item] = 1\n\n return frequency_dict", "matching_cluster_idx": 6}, {"solution": "from collections import defaultdict\ndef frequency_lists(list_of_lists):\n frequency_dict = defaultdict(int)\n\n # Flattening the list of lists\n for sublist in list_of_lists:\n for item in sublist:\n frequency_dict[item] += 1\n\n return dict(frequency_dict)", "matching_cluster_idx": 6}, {"solution": "from collections import Counter\ndef frequency_lists(nested_list):\n # Flatten the list of lists\n flat_list = [item for sublist in nested_list for item in sublist]\n\n # Use Counter to get the frequency of each element\n frequency = dict(Counter(flat_list))\n\n return frequency", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(nested_lists):\n \"\"\"\n This function takes a list of lists and returns a dictionary where keys are the elements\n and values are their frequencies in the flattened list.\n \"\"\"\n flat_list = [item for sublist in nested_lists for item in sublist]\n frequency_dict = {}\n\n for item in flat_list:\n if item in frequency_dict:\n frequency_dict[item] += 1\n else:\n frequency_dict[item] = 1\n\n return frequency_dict", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(list_of_lists):\n frequency = {}\n for lst in list_of_lists:\n for item in lst:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n return frequency", "matching_cluster_idx": 6}, {"solution": "from collections import defaultdict\ndef frequency_lists(lists):\n \"\"\"\n Function to find frequency of each element in a flattened list of lists, returned in a dictionary.\n \"\"\"\n frequency_dict = defaultdict(int)\n\n # Flatten the list of lists\n for sublist in lists:\n for item in sublist:\n frequency_dict[item] += 1\n\n return dict(frequency_dict)", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lists):\n \"\"\"\n This function takes in a list of lists and returns a dictionary with the frequency of each element\n in the flattened list.\n\n Parameters:\n lists (list): A list of lists containing integer elements.\n\n Returns:\n dict: A dictionary with elements as keys and their frequencies as values.\n \"\"\"\n # Flatten the list of lists\n flattened_list = [element for sublist in lists for element in sublist]\n\n # Initialize an empty dictionary to store frequencies\n frequency_dict = {}\n\n # Iterate through each element in the flattened list\n for element in flattened_list:\n if element in frequency_dict:\n frequency_dict[element] += 1\n else:\n frequency_dict[element] = 1\n\n return frequency_dict", "matching_cluster_idx": 6}]}, "Mbpp/106": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def add_lists(lst, tup):\n return tup + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tup):\n return tup + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tup):\n \"\"\"\n Appends the given list to the given tuple.\n\n Parameters:\n lst (list): The list to append.\n tup (tuple): The tuple to which the list will be appended.\n\n Returns:\n tuple: The new tuple with the list appended.\n \"\"\"\n return tup + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tpl):\n \"\"\"\n Append the given list to the given tuple.\n Args:\n lst (list): The list to be appended.\n tpl (tuple): The tuple to which the list will be appended.\n Returns:\n tuple: A new tuple with elements of the list appended to the tuple.\n \"\"\"\n return tpl + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tpl):\n \"\"\"\n Append the given list to the given tuple.\n\n :param lst: List to be appended.\n :param tpl: Tuple to which the list will be appended.\n :return: New tuple with list elements appended.\n \"\"\"\n return tpl + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tpl):\n return tpl + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tup):\n return tup + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tpl):\n \"\"\"\n Appends the given list to the given tuple.\n\n Args:\n lst (list): The list to be appended.\n tpl (tuple): The tuple to which the list is to be appended.\n\n Returns:\n tuple: A new tuple with elements of the list appended to the tuple.\n \"\"\"\n return tpl + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tup):\n \"\"\"\n Function to append the given list to the given tuple.\n :param lst: List to be appended.\n :param tup: Tuple to which the list will be appended.\n :return: A new tuple that combines the original tuple and the list.\n \"\"\"\n return tup + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tup):\n \"\"\"\n Append the given list to the given tuples.\n\n Parameters:\n lst (list): The list to be appended.\n tup (tuple): The tuple to which the list will be appended.\n\n Returns:\n tuple: A new tuple with the elements of the tuple followed by the elements of the list.\n \"\"\"\n return tup + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tpl):\n \"\"\"\n Append the given list to the given tuple.\n\n Parameters:\n lst (list): The list to be appended.\n tpl (tuple): The tuple to which the list will be appended.\n\n Returns:\n tuple: A new tuple with the list appended to the tuple.\n \"\"\"\n return tpl + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tup):\n \"\"\"\n Appends the list to the tuple and returns the new tuple.\n\n Parameters:\n lst (list): The list to be appended.\n tup (tuple): The tuple to which the list will be appended.\n\n Returns:\n tuple: A new tuple with the elements of the list appended to the tuple.\n \"\"\"\n return tup + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tup):\n \"\"\"\n Append the given list to the given tuple.\n\n Parameters:\n lst (list): The list to append.\n tup (tuple): The tuple to which the list should be appended.\n\n Returns:\n tuple: A new tuple with the elements of the list appended to the tuple.\n \"\"\"\n # Concatenate the tuple with the list converted to a tuple\n return tup + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tpl):\n \"\"\"\n This function appends the given list to the given tuple.\n\n Parameters:\n lst (list): The list to append.\n tpl (tuple): The tuple to which the list will be appended.\n\n Returns:\n tuple: A new tuple with the list elements appended to the tuple.\n \"\"\"\n return tpl + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(list_items, tuple_items):\n \"\"\"\n Function to append the given list to the given tuples.\n Args:\n list_items (list): The list of items to append.\n tuple_items (tuple): The tuple of items to be extended.\n\n Returns:\n tuple: A new tuple that is the concatenation of tuple_items and list_items.\n \"\"\"\n return tuple_items + tuple(list_items)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tup):\n \"\"\"\n Appends the elements of the given list to the given tuple and returns the new tuple.\n\n Parameters:\n lst (list): The list to append.\n tup (tuple): The tuple to which the list should be appended.\n\n Returns:\n tuple: A new tuple containing elements from the original tuple followed by the list elements.\n \"\"\"\n return tup + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(input_list, input_tuple):\n return input_tuple + tuple(input_list)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tup):\n \"\"\"\n Appends the given list to the given tuple.\n\n Parameters:\n lst (list): The list to be appended.\n tup (tuple): The tuple to which the list will be appended.\n\n Returns:\n tuple: A new tuple with the list elements appended to the original tuple.\n \"\"\"\n return tup + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tup):\n \"\"\"\n Append the given list to the given tuple and return the result.\n\n Parameters:\n lst (list): The list to append.\n tup (tuple): The tuple to which the list will be appended.\n\n Returns:\n tuple: A new tuple with elements from the original tuple followed by elements from the list.\n \"\"\"\n return tup + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tup):\n \"\"\"\n Appends the given list to the given tuple and returns a new tuple.\n\n :param lst: List to be appended\n :param tup: Tuple to which the list will be appended\n :return: New tuple with the list elements appended\n \"\"\"\n return tup + tuple(lst)", "matching_cluster_idx": 5}]}, "Mbpp/108": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def merge_sorted_list(list1, list2, list3):\n \"\"\"\n This function takes three lists and merges them into a single sorted list.\n \"\"\"\n merged_list = list1 + list2 + list3\n merged_list.sort()\n return merged_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Combine all lists\n combined_list = list1 + list2 + list3\n # Sort the combined list\n combined_list.sort()\n return combined_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n merged_list = list1 + list2 + list3\n return sorted(merged_list)", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Combine all lists into one and sort it\n combined_list = list1 + list2 + list3\n combined_list.sort()\n return combined_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n merged_list = list1 + list2 + list3\n return sorted(merged_list)", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n combined_list = list1 + list2 + list3\n combined_list.sort()\n return combined_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Combine all lists into one\n combined_list = list1 + list2 + list3\n # Sort the combined list\n combined_list.sort()\n return combined_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Merge all three lists\n merged_list = list1 + list2 + list3\n # Sort the merged list\n merged_list.sort()\n return merged_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n merged_list = list1 + list2 + list3\n merged_list.sort()\n return merged_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Combine all the lists\n combined_list = list1 + list2 + list3\n\n # Sort the combined list\n combined_list.sort()\n\n return combined_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n \"\"\"\n Merge three lists into a single sorted list.\n \"\"\"\n # Combine all lists\n combined_list = list1 + list2 + list3\n\n # Sort the combined list\n sorted_list = sorted(combined_list)\n\n return sorted_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Merge the three lists\n merged_list = list1 + list2 + list3\n # Sort the merged list\n sorted_list = sorted(merged_list)\n return sorted_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(lst1, lst2, lst3):\n merged_list = lst1 + lst2 + lst3\n merged_list.sort()\n return merged_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Combine the three lists\n combined_list = list1 + list2 + list3\n # Sort the combined list\n combined_list.sort()\n return combined_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(l1, l2, l3):\n merged_list = l1 + l2 + l3\n return sorted(merged_list)", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Combine the three lists into one and sort the merged list\n merged_list = list1 + list2 + list3\n merged_list.sort()\n return merged_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n combined_list = list1 + list2 + list3\n combined_list.sort()\n return combined_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n \"\"\"\n Merges three lists into a single sorted list.\n \"\"\"\n merged_list = list1 + list2 + list3\n merged_list.sort()\n return merged_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n merged_list = list1 + list2 + list3\n merged_list.sort()\n return merged_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Concatenate the three lists\n combined_list = list1 + list2 + list3\n\n # Sort the combined list\n sorted_list = sorted(combined_list)\n\n return sorted_list", "matching_cluster_idx": 10}]}, "Mbpp/111": {"dps": 95.46153846153847, "dps_norm": 86.875, "pass@1": 98.0, "profiled": [{"solution": "def common_in_nested_lists(nested_lists):\n if not nested_lists:\n return []\n # Start by assuming the common elements are the first list\n common = set(nested_lists[0])\n # Intersect with the rest of the lists\n for lst in nested_lists[1:]:\n common.intersection_update(lst)\n return list(common)", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n \"\"\"\n Find the common elements in given nested lists.\n\n Parameters:\n nested_lists (list of lists): The lists to check for common elements.\n\n Returns:\n set: A set of common elements in all the nested lists.\n \"\"\"\n if not nested_lists:\n return set()\n\n # Start with the set of the first list\n common_elements = set(nested_lists[0])\n\n # Intersect with the set of each subsequent list\n for lst in nested_lists[1:]:\n common_elements.intersection_update(lst)\n\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n if not nested_lists:\n return []\n\n # Convert the first list to a set to initialize the common elements\n common_elements = set(nested_lists[0])\n\n # Iterate through the remaining lists and update the set of common elements\n for lst in nested_lists[1:]:\n common_elements.intersection_update(lst)\n\n return list(common_elements)", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n \"\"\"\n This function finds common elements in given nested lists.\n\n Parameters:\n nested_lists (list of list of int): Lists containing integers.\n\n Returns:\n list of int: A list of common integers found in all lists.\n \"\"\"\n if not nested_lists:\n return []\n\n # Initialize the common set with the first list\n common_set = set(nested_lists[0])\n\n # Iterate through the rest of the lists and perform set intersection\n for lst in nested_lists[1:]:\n common_set &= set(lst)\n\n return list(common_set)", "matching_cluster_idx": 6}, {"solution": "from functools import reduce\ndef common_in_nested_lists(nested_lists):\n if not nested_lists:\n return []\n return list(reduce(set.intersection, map(set, nested_lists)))", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n # Convert all lists to sets\n sets = [set(lst) for lst in nested_lists]\n\n # Find the intersection of all sets\n common_elements = set.intersection(*sets)\n\n return common_elements", "matching_cluster_idx": 5}, {"solution": "def common_in_nested_lists(nested_lists):\n # Convert the first list to a set and then perform set intersections with the remaining lists\n common_elements = set(nested_lists[0])\n for lst in nested_lists[1:]:\n common_elements.intersection_update(lst)\n return list(common_elements)", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n # Using set.intersection to find the common elements in nested lists\n common_elements = set(nested_lists[0])\n for lst in nested_lists[1:]:\n common_elements.intersection_update(lst)\n return list(common_elements)", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n if not nested_lists:\n return []\n\n # Use the first list as a starting point for the intersection\n common_elements = set(nested_lists[0])\n\n # Intersect with all subsequent lists\n for lst in nested_lists[1:]:\n common_elements &= set(lst)\n\n return list(common_elements)", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n if not nested_lists:\n return []\n # Start with the first list as the common set\n common_set = set(nested_lists[0])\n # Iterate through remaining lists and find common elements\n for sublist in nested_lists[1:]:\n common_set &= set(sublist)\n return list(common_set)", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n if not nested_lists:\n return []\n\n # Initialize the common set with the elements of the first list\n common_elements = set(nested_lists[0])\n\n # Iterate through the remaining lists and find common elements\n for lst in nested_lists[1:]:\n common_elements.intersection_update(lst)\n\n return list(common_elements)", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n if not nested_lists:\n return []\n\n # Initialize the common elements with the first list\n common_elements = set(nested_lists[0])\n\n # Iterate through the remaining lists and find the intersection\n for lst in nested_lists[1:]:\n common_elements &= set(lst)\n\n return list(common_elements)", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n if not nested_lists:\n return []\n\n # Using set intersection to find common elements\n common_elements = set(nested_lists[0])\n for sublist in nested_lists[1:]:\n common_elements.intersection_update(sublist)\n\n return list(common_elements)", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n \"\"\"\n Function to find common elements in given nested lists.\n \"\"\"\n if not nested_lists:\n return []\n\n # Start with the set of the first list\n common_set = set(nested_lists[0])\n\n # Intersect this set with all the other sets\n for lst in nested_lists[1:]:\n common_set.intersection_update(lst)\n\n return list(common_set)", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n if not nested_lists:\n return []\n\n # Start with the set of the first list\n common_elements = set(nested_lists[0])\n\n # Intersect with the sets of the remaining lists\n for lst in nested_lists[1:]:\n common_elements &= set(lst)\n\n return list(common_elements)", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n if not nested_lists:\n return []\n\n # Convert the first list to a set\n common_elements = set(nested_lists[0])\n\n # Iterate through the rest of the lists\n for lst in nested_lists[1:]:\n # Intersect with the current list\n common_elements.intersection_update(lst)\n\n return list(common_elements)", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n \"\"\"\n This function takes a list of lists and returns a list of common elements present in all the sublists.\n\n :param nested_lists: List[List[int]] - List containing sublists of integers.\n :return: List[int] - List of common integers.\n \"\"\"\n\n # Check if the input list is empty\n if not nested_lists:\n return []\n\n # Convert each sublist to a set and find the intersection of all sets\n common_elements = set(nested_lists[0])\n for sublist in nested_lists[1:]:\n common_elements.intersection_update(sublist)\n\n return list(common_elements)", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n if not nested_lists:\n return []\n\n common = set(nested_lists[0])\n for lst in nested_lists[1:]:\n common = common & set(lst)\n\n return list(common)", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n if not nested_lists:\n return []\n\n # Start with the set of the first list\n common_elements = set(nested_lists[0])\n\n # Intersect with each subsequent list\n for lst in nested_lists[1:]:\n common_elements.intersection_update(lst)\n\n return list(common_elements)", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n # Convert the first list to a set\n common_set = set(nested_lists[0])\n\n # Intersect with the rest of the lists\n for lst in nested_lists[1:]:\n common_set &= set(lst)\n\n return list(common_set)", "matching_cluster_idx": 6}]}, "Mbpp/123": {"dps": 99.62686567164178, "dps_norm": 85.71428571428571, "pass@1": 59.0, "profiled": [{"solution": "def sum_of_proper_divisors(n):\n \"\"\"Return the sum of proper divisors of n.\"\"\"\n divisors_sum = 1\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n divisors_sum += i\n if i != n // i:\n divisors_sum += n // i\n return divisors_sum\ndef amicable_numbers_sum(limit):\n \"\"\"Return the sum of all amicable numbers less than or equal to limit.\"\"\"\n amicable_sum = 0\n for a in range(2, limit + 1):\n b = sum_of_proper_divisors(a)\n if b != a and b <= limit and sum_of_proper_divisors(b) == a:\n amicable_sum += a\n return amicable_sum", "matching_cluster_idx": 11}, {"solution": "def get_proper_divisors_sum(n):\n \"\"\"Helper function to get the sum of proper divisors of a number n\"\"\"\n div_sum = 1\n i = 2\n while i * i <= n:\n if n % i == 0:\n if i * i == n:\n div_sum += i\n else:\n div_sum += i + n // i\n i += 1\n return div_sum\ndef amicable_numbers_sum(upper_limit):\n \"\"\"Function to calculate the sum of all amicable numbers from 1 to upper_limit\"\"\"\n amicable_sum = 0\n amicable_numbers = set()\n for a in range(2, upper_limit + 1):\n b = get_proper_divisors_sum(a)\n if a != b and b <= upper_limit and get_proper_divisors_sum(b) == a:\n amicable_numbers.add(a)\n amicable_numbers.add(b)\n\n return sum(amicable_numbers)", "matching_cluster_idx": 11}, {"solution": "def sum_of_proper_divisors(n):\n \"\"\"Return the sum of proper divisors of n (excluding itself).\"\"\"\n sum_divisors = 1\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n sum_divisors += i\n if i != n // i:\n sum_divisors += n // i\n return sum_divisors\ndef amicable_numbers_sum(limit):\n \"\"\"Sum all amicable numbers from 1 to the specified limit.\"\"\"\n amicable_sum = 0\n for a in range(2, limit + 1):\n b = sum_of_proper_divisors(a)\n if b > a and sum_of_proper_divisors(b) == a:\n amicable_sum += a + b\n return amicable_sum", "matching_cluster_idx": 11}, {"solution": "def sum_of_proper_divisors(n):\n \"\"\"Calculate the sum of proper divisors of n.\"\"\"\n divisors_sum = 1\n i = 2\n while i * i <= n:\n if n % i == 0:\n divisors_sum += i\n if i * i != n:\n divisors_sum += n // i\n i += 1\n return divisors_sum\ndef amicable_numbers_sum(limit):\n \"\"\"Calculate the sum of all amicable numbers from 1 to limit.\"\"\"\n amicable_sum = 0\n for a in range(2, limit + 1):\n b = sum_of_proper_divisors(a)\n if b > a and sum_of_proper_divisors(b) == a:\n amicable_sum += a + b\n return amicable_sum", "matching_cluster_idx": 11}, {"solution": "def sum_of_proper_divisors(n):\n \"\"\"Returns the sum of proper divisors of n.\"\"\"\n if n < 2:\n return 0\n total = 1\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n total += i\n if i != n // i:\n total += n // i\n return total\ndef amicable_numbers_sum(limit):\n \"\"\"Returns the sum of all amicable numbers up to the given limit.\"\"\"\n amicable_sum = 0\n sum_divisors = [0] * (limit + 1)\n for i in range(2, limit + 1):\n sum_divisors[i] = sum_of_proper_divisors(i)\n\n for a in range(2, limit + 1):\n b = sum_divisors[a]\n if b != a and b <= limit and sum_divisors[b] == a:\n amicable_sum += a\n\n return amicable_sum", "matching_cluster_idx": 11}, {"solution": "def sum_of_proper_divisors(n):\n \"\"\"\n Helper function to sum the proper divisors of a given number n.\n \"\"\"\n sum = 1\n i = 2\n while i * i <= n:\n if n % i == 0:\n if i * i != n:\n sum += i + n // i\n else:\n sum += i\n i += 1\n return sum\ndef amicable_numbers_sum(limit):\n \"\"\"\n Function to sum all amicable numbers from 1 to a specified limit.\n \"\"\"\n amicable_sum = 0\n for a in range(2, limit + 1):\n b = sum_of_proper_divisors(a)\n if b > a and sum_of_proper_divisors(b) == a:\n amicable_sum += a + b\n return amicable_sum", "matching_cluster_idx": 11}, {"solution": "def sum_of_divisors(n):\n \"\"\"Calculate the sum of proper divisors of n.\"\"\"\n sum_divisors = 1\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n sum_divisors += i\n if i != n // i:\n sum_divisors += n // i\n return sum_divisors\ndef amicable_numbers_sum(limit):\n \"\"\"Calculate the sum of all amicable numbers from 1 to the specified limit.\"\"\"\n total_sum = 0\n for a in range(2, limit + 1):\n b = sum_of_divisors(a)\n if b != a and sum_of_divisors(b) == a:\n total_sum += a\n return total_sum", "matching_cluster_idx": 11}, {"solution": "def get_divisors(n):\n \"\"\"\n Get the sum of all proper divisors of a number\n \"\"\"\n divisors = [1]\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n divisors.append(i)\n if i != n//i:\n divisors.append(n//i)\n return sum(divisors)\ndef amicable_numbers_sum(n):\n \"\"\"\n Sum all amicable numbers from 1 to a specified number\n \"\"\"\n amicable_sum = 0\n for i in range(1, n+1):\n j = get_divisors(i)\n if j > i and get_divisors(j) == i:\n amicable_sum += i + j\n return amicable_sum", "matching_cluster_idx": 11}, {"solution": "def divisors_sum(n):\n \"\"\"Return the sum of proper divisors of n.\"\"\"\n total = 1\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n total += i\n if i != n // i:\n total += n // i\n return total\ndef amicable_numbers_sum(limit):\n \"\"\"Return the sum of all amicable numbers up to the specified limit.\"\"\"\n sum_amicable = 0\n checked = set()\n\n for a in range(2, limit + 1):\n if a in checked:\n continue\n b = divisors_sum(a)\n if b > a and b <= limit and divisors_sum(b) == a:\n sum_amicable += a + b\n checked.add(b)\n\n return sum_amicable", "matching_cluster_idx": 11}, {"solution": "def sum_of_proper_divisors(n):\n \"\"\"Return the sum of proper divisors of n (excluding n itself).\"\"\"\n divisors_sum = 1 # 1 is a proper divisor of any number\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n divisors_sum += i\n if i != n // i: # Add the paired divisor only if it is different\n divisors_sum += n // i\n return divisors_sum\ndef amicable_numbers_sum(limit):\n \"\"\"Return the sum of all amicable numbers from 1 to the specified limit.\"\"\"\n amicable_sum = 0\n amicable_pairs = set()\n\n for a in range(2, limit + 1):\n b = sum_of_proper_divisors(a)\n if b > a and b <= limit and sum_of_proper_divisors(b) == a:\n amicable_pairs.add(a)\n amicable_pairs.add(b)\n\n for pair in amicable_pairs:\n amicable_sum += pair\n\n return amicable_sum", "matching_cluster_idx": 11}, {"solution": "def sum_of_proper_divisors(n):\n \"\"\"\n Calculate the sum of proper divisors of a given number.\n Proper divisors are the divisors of a number excluding the number itself.\n \"\"\"\n proper_divisors_sum = 1 # 1 is a proper divisor for all numbers greater than 1\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n proper_divisors_sum += i\n if i != n // i:\n proper_divisors_sum += n // i\n return proper_divisors_sum\ndef amicable_numbers_sum(limit):\n \"\"\"\n Calculate the sum of all amicable numbers up to a specified limit.\n \"\"\"\n sum_amicable = 0\n divisor_sums = [0] * (limit + 1)\n\n # Calculate sum of proper divisors for each number up to the limit\n for i in range(2, limit + 1):\n divisor_sums[i] = sum_of_proper_divisors(i)\n\n # Check for amicable pairs\n for i in range(2, limit + 1):\n j = divisor_sums[i]\n if j <= limit and i != j and divisor_sums[j] == i:\n sum_amicable += i\n\n return sum_amicable", "matching_cluster_idx": 11}, {"solution": "def sum_of_proper_divisors(n):\n \"\"\"Helper function to find the sum of proper divisors of n.\"\"\"\n if n < 1:\n return 0\n total = 1 # Start with 1 because 1 is a proper divisor of every number.\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n total += i\n if i != n // i:\n total += n // i\n return total\ndef amicable_numbers_sum(limit):\n \"\"\"Function to find the sum of all amicable numbers up to the given limit.\"\"\"\n amicable_sum = 0\n for a in range(2, limit + 1):\n b = sum_of_proper_divisors(a)\n if a < b <= limit and sum_of_proper_divisors(b) == a:\n amicable_sum += a\n if a != b:\n amicable_sum += b\n return amicable_sum", "matching_cluster_idx": 11}, {"solution": "def sum_of_divisors(n):\n \"\"\"\n Calculate the sum of proper divisors of n.\n \"\"\"\n total = 1 # 1 is a proper divisor for any number greater than 1\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n total += i\n if i != n // i:\n total += n // i\n return total\ndef amicable_numbers_sum(limit):\n \"\"\"\n Calculate the sum of all amicable numbers from 1 to the specified limit.\n \"\"\"\n total_sum = 0\n for a in range(2, limit + 1):\n b = sum_of_divisors(a)\n if b > a and b <= limit and sum_of_divisors(b) == a:\n total_sum += a + b\n\n return total_sum", "matching_cluster_idx": 11}, {"solution": "def sum_of_divisors(n):\n \"\"\"Calculate the sum of proper divisors of n.\"\"\"\n divisors_sum = 1 # 1 is always a divisor\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n divisors_sum += i\n if i != n // i:\n divisors_sum += n // i\n return divisors_sum\ndef amicable_numbers_sum(limit):\n \"\"\"Sum all amicable numbers from 1 to the specified limit.\"\"\"\n amicable_sum = 0\n found = [False] * (limit + 1)\n\n for i in range(2, limit + 1):\n if not found[i]:\n s1 = sum_of_divisors(i)\n if s1 > i and s1 <= limit:\n s2 = sum_of_divisors(s1)\n if s2 == i:\n amicable_sum += i + s1\n found[s1] = True\n\n return amicable_sum", "matching_cluster_idx": 11}, {"solution": "def sum_of_divisors(n):\n \"\"\"Returns the sum of proper divisors of n.\"\"\"\n total = 1 # 1 is a proper divisor of any number\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n total += i\n if i != n // i:\n total += n // i\n return total\ndef amicable_numbers_sum(limit):\n \"\"\"Returns the sum of all amicable numbers from 1 to the specified limit.\"\"\"\n amicable_sum = 0\n checked = set()\n\n for a in range(2, limit + 1):\n if a in checked:\n continue\n\n b = sum_of_divisors(a)\n if b > a and sum_of_divisors(b) == a:\n amicable_sum += a + b\n checked.add(b)\n\n return amicable_sum", "matching_cluster_idx": 11}, {"solution": "def sum_of_proper_divisors(n):\n \"\"\"Return the sum of proper divisors of n (excluding n itself)\"\"\"\n sum_divisors = 1 # 1 is a proper divisor of any positive integer\n sqrt_n = int(n**0.5)\n for i in range(2, sqrt_n + 1):\n if n % i == 0:\n sum_divisors += i\n if i != n // i: # Avoid adding the square root twice if n is a perfect square\n sum_divisors += n // i\n return sum_divisors\ndef amicable_numbers_sum(limit):\n \"\"\"Return the sum of all amicable numbers from 1 to limit\"\"\"\n amicable_sum = 0\n for a in range(2, limit + 1):\n b = sum_of_proper_divisors(a)\n if b > a and sum_of_proper_divisors(b) == a:\n amicable_sum += a + b\n return amicable_sum", "matching_cluster_idx": 11}, {"solution": "def sum_of_divisors(n):\n \"\"\"Return the sum of all proper divisors of n (excluding n itself)\"\"\"\n total = 1\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n total += i\n if i != n // i:\n total += n // i\n return total\ndef amicable_numbers_sum(limit):\n \"\"\"Return the sum of all amicable numbers up to and including the specified limit\"\"\"\n amicable_sum = 0\n for a in range(2, limit + 1):\n b = sum_of_divisors(a)\n if a != b and a == sum_of_divisors(b):\n amicable_sum += a\n return amicable_sum", "matching_cluster_idx": 11}, {"solution": "def sum_of_divisors(n):\n \"\"\"\n Calculate the sum of the proper divisors of n.\n \"\"\"\n divisors_sum = 1\n i = 2\n while i * i <= n:\n if n % i == 0:\n if i * (n // i) == n:\n divisors_sum += i + (n // i)\n else:\n divisors_sum += i\n i += 1\n return divisors_sum\ndef amicable_numbers_sum(limit):\n \"\"\"\n Calculate the sum of all amicable numbers less than or equal to limit.\n \"\"\"\n amicable_sum = 0\n for a in range(2, limit + 1):\n b = sum_of_divisors(a)\n if b > a and b <= limit and sum_of_divisors(b) == a:\n amicable_sum += a + b\n return amicable_sum", "matching_cluster_idx": 11}, {"solution": "def sum_of_proper_divisors(n):\n \"\"\"Calculate the sum of proper divisors of a number.\"\"\"\n if n == 1:\n return 0\n div_sum = 1\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n div_sum += i\n if i != n // i:\n div_sum += n // i\n return div_sum\ndef amicable_numbers_sum(limit):\n \"\"\"Sum all amicable numbers from 1 to the specified limit.\"\"\"\n amicable_sum = 0\n amicable_pair_cache = {}\n for i in range(2, limit + 1):\n if i not in amicable_pair_cache:\n sum_i = sum_of_proper_divisors(i)\n if sum_i <= limit and i != sum_i and sum_of_proper_divisors(sum_i) == i:\n amicable_pair_cache[i] = sum_i\n amicable_pair_cache[sum_i] = i\n\n for i in amicable_pair_cache:\n amicable_sum += i\n\n return amicable_sum", "matching_cluster_idx": 11}, {"solution": "def sum_of_divisors(n):\n \"\"\"Calculate the sum of proper divisors of n.\"\"\"\n divisors_sum = 1\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n divisors_sum += i\n if i != n // i:\n divisors_sum += n // i\n return divisors_sum\ndef amicable_numbers_sum(limit):\n \"\"\"Calculate the sum of all amicable numbers from 1 to the specified limit.\"\"\"\n amicable_sum = 0\n for a in range(2, limit + 1):\n b = sum_of_divisors(a)\n if a != b and a == sum_of_divisors(b):\n amicable_sum += a\n return amicable_sum", "matching_cluster_idx": 11}]}, "Mbpp/128": {"dps": 99.5475113122172, "dps_norm": 80.0, "pass@1": 100.0, "profiled": [{"solution": "def long_words(n, sentence):\n \"\"\"\n Function to find words that are longer than n characters from a given list of words.\n\n Parameters:\n n (int): The length of words to filter by.\n sentence (str): The sentence to extract words from.\n\n Returns:\n List[str]: A list of words that are longer than n characters.\n \"\"\"\n words = sentence.split()\n return [word for word in words if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n \"\"\"\n Finds words that are longer than n characters from a given list of words.\n\n Parameters:\n n (int): The minimum length of the word.\n sentence (str): The sentence from which to extract words.\n\n Returns:\n List[str]: A list of words longer than n characters.\n \"\"\"\n words = sentence.split()\n return [word for word in words if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, text):\n # Split the text into words\n words = text.split()\n # Filter out words that are longer than n characters\n result = [word for word in words if len(word) > n]\n return result", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n words = sentence.split()\n return [word for word in words if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n # Split the sentence into words\n words = sentence.split()\n # Filter words longer than n characters\n long_word_list = [word for word in words if len(word) > n]\n return long_word_list", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n \"\"\"\n This function takes a number n and a sentence and returns a list of words that are longer than n characters.\n \"\"\"\n # Split the sentence into words\n words = sentence.split()\n\n # Use a list comprehension to filter words longer than n characters\n long_words_list = [word for word in words if len(word) > n]\n\n return long_words_list", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n \"\"\"\n This function takes an integer n and a string sentence, and returns a list of words\n from the sentence that are longer than n characters.\n \"\"\"\n # Split the sentence into words\n words = sentence.split()\n # Filter the words that are longer than n characters\n long_words_list = [word for word in words if len(word) > n]\n return long_words_list", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n \"\"\"\n Finds words that are longer than n characters from a given sentence.\n\n :param n: int, the length threshold for words\n :param sentence: str, the input sentence\n :return: list, words that are longer than n characters\n \"\"\"\n words = sentence.split()\n return [word for word in words if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n \"\"\"\n Returns a list of words from the sentence that are longer than n characters.\n\n :param n: int, length of the word to filter by\n :param sentence: str, the sentence to filter words from\n :return: list of words longer than n characters\n \"\"\"\n # Split the sentence into words\n words = sentence.split()\n\n # Filter words longer than n characters\n long_words_list = [word for word in words if len(word) > n]\n\n return long_words_list", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n \"\"\"\n Find words that are longer than n characters from a given sentence.\n\n :param n: int, the minimum length of words to be considered long.\n :param sentence: str, the sentence to parse for words.\n :return: list of str, the words longer than n characters.\n \"\"\"\n # Split the sentence into words\n words = sentence.split()\n # Filter words longer than n characters\n long_words_list = [word for word in words if len(word) > n]\n return long_words_list", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n \"\"\"\n Returns a list of words from the given sentence that are longer than n characters.\n :param n: int, minimum length of words to include in the result\n :param sentence: str, input sentence to process\n :return: list of words longer than n characters\n \"\"\"\n words = sentence.split()\n return [word for word in words if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, s):\n \"\"\"\n Find words that are longer than n characters from a given list of words in a string.\n\n :param n: int, the minimum length of words to be found\n :param s: str, the string containing words\n :return: list of words that are longer than n characters\n \"\"\"\n words = s.split()\n return [word for word in words if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n # Split the sentence into words\n words = sentence.split()\n\n # Filter the words longer than n characters\n result = [word for word in words if len(word) > n]\n\n return result", "matching_cluster_idx": 3}, {"solution": "def long_words(n, text):\n words = text.split()\n long_words_list = [word for word in words if len(word) > n]\n return long_words_list", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n \"\"\"\n This function takes an integer n and a string sentence, and returns a list\n of words from the sentence that are longer than n characters.\n\n :param n: integer, the minimum length of words to include in the result\n :param sentence: string, the sentence to search for long words\n :return: list of words longer than n characters\n \"\"\"\n # Split the sentence into words\n words = sentence.split()\n\n # Filter words that are longer than n characters\n long_words_list = [word for word in words if len(word) > n]\n\n return long_words_list", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n words = sentence.split()\n return [word for word in words if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n \"\"\"\n Function to find words that are longer than n characters from a given list of words.\n \"\"\"\n words = sentence.split()\n long_words_list = [word for word in words if len(word) > n]\n return long_words_list", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n words = sentence.split()\n return [word for word in words if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n words = sentence.split()\n long_words_list = [word for word in words if len(word) > n]\n return long_words_list", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n \"\"\"\n Function to find words that are longer than n characters from a given sentence.\n\n Parameters:\n n (int): The minimum length of words to be included in the result.\n sentence (str): The input sentence to extract words from.\n\n Returns:\n list: A list of words longer than n characters.\n \"\"\"\n words = sentence.split()\n long_words_list = [word for word in words if len(word) > n]\n return long_words_list", "matching_cluster_idx": 3}]}, "Mbpp/129": {"dps": 79.6938775510204, "dps_norm": 97.33333333333333, "pass@1": 77.0, "profiled": [{"solution": "def magic_square_test(matrix):\n if len(matrix) == 0 or len(matrix) != len(matrix[0]):\n return False\n\n # Calculate the magic sum from the first row\n magic_sum = sum(matrix[0])\n\n # Check if all rows sum to the magic sum\n for row in matrix:\n if sum(row) != magic_sum:\n return False\n\n # Check if all columns sum to the magic sum\n for col in range(len(matrix)):\n if sum(row[col] for row in matrix) != magic_sum:\n return False\n\n # Check if the two main diagonals sum to the magic sum\n if sum(matrix[i][i] for i in range(len(matrix))) != magic_sum:\n return False\n if sum(matrix[i][len(matrix) - 1 - i] for i in range(len(matrix))) != magic_sum:\n return False\n\n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n n = len(matrix)\n\n # Check if the matrix is square\n for row in matrix:\n if len(row) != n:\n return False\n\n # Calculate the sum of the first row, which serves as the magic constant\n magic_constant = sum(matrix[0])\n\n # Check the sums of all rows\n for row in matrix:\n if sum(row) != magic_constant:\n return False\n\n # Check the sums of all columns\n for col in range(n):\n if sum(matrix[row][col] for row in range(n)) != magic_constant:\n return False\n\n # Check the sums of the main diagonal\n if sum(matrix[i][i] for i in range(n)) != magic_constant:\n return False\n\n # Check the sums of the secondary diagonal\n if sum(matrix[i][n - 1 - i] for i in range(n)) != magic_constant:\n return False\n\n return True", "matching_cluster_idx": 13}, {"solution": "def magic_square_test(matrix):\n \"\"\"\n This function checks whether the given matrix is a magic square.\n\n :param matrix: 2D list of integers, representing the matrix to check\n :return: bool, True if the matrix is a magic square, False otherwise\n \"\"\"\n if not matrix or not matrix[0]:\n return False\n\n n = len(matrix)\n\n # Check if the matrix is n x n\n for row in matrix:\n if len(row) != n:\n return False\n\n # Calculate the magic constant\n magic_constant = sum(matrix[0])\n\n # Check rows\n for row in matrix:\n if sum(row) != magic_constant:\n return False\n\n # Check columns\n for col in range(n):\n if sum(matrix[row][col] for row in range(n)) != magic_constant:\n return False\n\n # Check main diagonal\n if sum(matrix[i][i] for i in range(n)) != magic_constant:\n return False\n\n # Check anti-diagonal\n if sum(matrix[i][n - i - 1] for i in range(n)) != magic_constant:\n return False\n\n return True", "matching_cluster_idx": 13}, {"solution": "def magic_square_test(matrix):\n n = len(matrix)\n\n # Calculate the sum of the first row, which will be used as the reference magic number\n magic_sum = sum(matrix[0])\n\n # Check all rows\n for row in matrix:\n if sum(row) != magic_sum:\n return False\n\n # Check all columns\n for col in range(n):\n if sum(matrix[row][col] for row in range(n)) != magic_sum:\n return False\n\n # Check main diagonal\n if sum(matrix[i][i] for i in range(n)) != magic_sum:\n return False\n\n # Check secondary diagonal\n if sum(matrix[i][n - i - 1] for i in range(n)) != magic_sum:\n return False\n\n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n n = len(matrix)\n # Calculate the magic constant which is the sum of the first row\n magic_constant = sum(matrix[0])\n\n # Check the sum of each row\n for row in matrix:\n if sum(row) != magic_constant:\n return False\n\n # Check the sum of each column\n for col in range(n):\n if sum(matrix[row][col] for row in range(n)) != magic_constant:\n return False\n\n # Check the sum of main diagonal\n if sum(matrix[i][i] for i in range(n)) != magic_constant:\n return False\n\n # Check the sum of secondary diagonal\n if sum(matrix[i][n - 1 - i] for i in range(n)) != magic_constant:\n return False\n\n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n # Calculate the size of the matrix\n size = len(matrix)\n\n # Check if the matrix is square\n for row in matrix:\n if len(row) != size:\n return False\n\n # Calculate the sum of the first row\n target_sum = sum(matrix[0])\n\n # Check sums of all rows\n for row in matrix:\n if sum(row) != target_sum:\n return False\n\n # Check sums of all columns\n for col in range(size):\n if sum(matrix[row][col] for row in range(size)) != target_sum:\n return False\n\n # Check sums of both diagonals\n if sum(matrix[i][i] for i in range(size)) != target_sum:\n return False\n if sum(matrix[i][size - 1 - i] for i in range(size)) != target_sum:\n return False\n\n return True", "matching_cluster_idx": 13}, {"solution": "def magic_square_test(matrix):\n \"\"\"\n This function takes a 2D matrix and checks if it is a magic square.\n A magic square is a square matrix where the sum of the numbers in each row, column,\n and the main diagonals are all the same.\n \"\"\"\n # Check if matrix is square\n if len(matrix) == 0 or len(matrix) != len(matrix[0]):\n return False\n\n n = len(matrix)\n\n # Calculate the sum of the first row as the reference sum\n reference_sum = sum(matrix[0])\n\n # Check rows\n for row in matrix:\n if sum(row) != reference_sum:\n return False\n\n # Check columns\n for col in range(n):\n col_sum = sum(matrix[row][col] for row in range(n))\n if col_sum != reference_sum:\n return False\n\n # Check main diagonals\n main_diag_sum = sum(matrix[i][i] for i in range(n))\n if main_diag_sum != reference_sum:\n return False\n\n anti_diag_sum = sum(matrix[i][n - 1 - i] for i in range(n))\n if anti_diag_sum != reference_sum:\n return False\n\n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n # Calculate the size of the matrix\n n = len(matrix)\n # Calculate the sum of the first row which should be the magic constant\n magic_constant = sum(matrix[0])\n\n # Check sums of rows\n for row in matrix:\n if sum(row) != magic_constant:\n return False\n\n # Check sums of columns\n for col in range(n):\n if sum(matrix[row][col] for row in range(n)) != magic_constant:\n return False\n\n # Check sums of diagonals\n if sum(matrix[i][i] for i in range(n)) != magic_constant:\n return False\n if sum(matrix[i][n-i-1] for i in range(n)) != magic_constant:\n return False\n\n # If all checks are passed\n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n \"\"\"\n Function to check if the provided matrix is a magic square\n \"\"\"\n\n n = len(matrix)\n\n # Sum of the elements of the first row\n sum_row = sum(matrix[0])\n\n # Calculate the sums of all rows, columns, and diagonals\n for i in range(n):\n # Check sum of each row\n if sum(matrix[i]) != sum_row:\n return False\n\n # Check sum of each column\n if sum(matrix[j][i] for j in range(n)) != sum_row:\n return False\n\n # Check the sum of the main diagonal\n if sum(matrix[i][i] for i in range(n)) != sum_row:\n return False\n\n # Check the sum of the secondary diagonal\n if sum(matrix[i][n - i - 1] for i in range(n)) != sum_row:\n return False\n\n return True", "matching_cluster_idx": 13}, {"solution": "def magic_square_test(matrix):\n size = len(matrix)\n # Calculate the sum of the first row\n magic_sum = sum(matrix[0])\n # Check rows\n for row in matrix:\n if sum(row) != magic_sum:\n return False\n # Check columns\n for col in range(size):\n if sum(matrix[row][col] for row in range(size)) != magic_sum:\n return False\n # Check diagonals\n if sum(matrix[i][i] for i in range(size)) != magic_sum:\n return False\n if sum(matrix[i][size - 1 - i] for i in range(size)) != magic_sum:\n return False\n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n # Check if the matrix is square\n n = len(matrix)\n for row in matrix:\n if len(row) != n:\n return False\n\n # Calculate the magic constant\n magic_constant = sum(matrix[0])\n\n # Check rows\n for row in matrix:\n if sum(row) != magic_constant:\n return False\n\n # Check columns\n for col in range(n):\n if sum(matrix[row][col] for row in range(n)) != magic_constant:\n return False\n\n # Check main diagonal\n if sum(matrix[i][i] for i in range(n)) != magic_constant:\n return False\n\n # Check secondary diagonal\n if sum(matrix[i][n - 1 - i] for i in range(n)) != magic_constant:\n return False\n\n return True", "matching_cluster_idx": 13}, {"solution": "def magic_square_test(matrix):\n \"\"\"\n This function will calculate whether the given matrix is a magic square\n A magic square has the following properties:\n 1. It has the same number of rows and columns.\n 2. The sums of the numbers in each row are the same.\n 3. The sums of the numbers in each column are the same.\n 4. The sums of the numbers in the main diagonals are the same.\n \"\"\"\n\n # Calculate the size of the matrix\n n = len(matrix)\n\n # Calculate the sum of the first row, which will be our target sum\n target_sum = sum(matrix[0])\n\n # Check row sums\n for row in matrix:\n if sum(row) != target_sum:\n return False\n\n # Check column sums\n for col in range(n):\n if sum(matrix[row][col] for row in range(n)) != target_sum:\n return False\n\n # Check the sum of the main diagonal\n if sum(matrix[i][i] for i in range(n)) != target_sum:\n return False\n\n # Check the sum of the anti-diagonal\n if sum(matrix[i][n - 1 - i] for i in range(n)) != target_sum:\n return False\n\n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n # Check if the matrix is square\n if len(matrix) != len(matrix[0]):\n return False\n\n # Initialize the magic sum to the sum of the first row\n magic_sum = sum(matrix[0])\n\n # Check each row\n for row in matrix:\n if sum(row) != magic_sum:\n return False\n\n # Check each column\n for col in range(len(matrix)):\n if sum(matrix[row][col] for row in range(len(matrix))) != magic_sum:\n return False\n\n # Check main diagonal\n if sum(matrix[i][i] for i in range(len(matrix))) != magic_sum:\n return False\n\n # Check secondary diagonal\n if sum(matrix[i][len(matrix)-1-i] for i in range(len(matrix))) != magic_sum:\n return False\n\n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n n = len(matrix)\n # Sum of first row, which is assumed to be the magic constant\n magic_sum = sum(matrix[0])\n # Sum of columns\n for j in range(n):\n if sum(matrix[i][j] for i in range(n)) != magic_sum:\n return False\n # Sum of rows\n for i in range(n):\n if sum(matrix[i]) != magic_sum:\n return False\n # Sum of diagonals\n if sum(matrix[i][i] for i in range(n)) != magic_sum or sum(matrix[i][n - 1 - i] for i in range(n)) != magic_sum:\n return False\n return True", "matching_cluster_idx": 13}, {"solution": "def magic_square_test(square):\n n = len(square)\n\n # Calculate the sum of the first row\n magic_sum = sum(square[0])\n\n # Check all rows\n for row in square:\n if sum(row) != magic_sum:\n return False\n\n # Check all columns\n for col in range(n):\n if sum(row[col] for row in square) != magic_sum:\n return False\n\n # Check main diagonal\n if sum(square[i][i] for i in range(n)) != magic_sum:\n return False\n\n # Check second diagonal\n if sum(square[i][n - 1 - i] for i in range(n)) != magic_sum:\n return False\n\n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n if not matrix or not matrix[0]:\n return False\n\n # Get the size of the matrix\n n = len(matrix)\n\n # Check if it is a square matrix\n for row in matrix:\n if len(row) != n:\n return False\n\n # Calculate the sum of the first row, which will be the magic constant\n magic_constant = sum(matrix[0])\n\n # Check rows\n for row in matrix:\n if sum(row) != magic_constant:\n return False\n\n # Check columns\n for col in range(n):\n if sum(matrix[row][col] for row in range(n)) != magic_constant:\n return False\n\n # Check main diagonal\n if sum(matrix[i][i] for i in range(n)) != magic_constant:\n return False\n\n # Check anti-diagonal\n if sum(matrix[i][n-i-1] for i in range(n)) != magic_constant:\n return False\n\n return True", "matching_cluster_idx": 13}, {"solution": "def magic_square_test(matrix):\n # Get the size of the matrix\n n = len(matrix)\n\n # Calculate the sum of the first row to use it as a reference\n magic_sum = sum(matrix[0])\n\n # Check each row\n for row in matrix:\n if sum(row) != magic_sum:\n return False\n\n # Check each column\n for col in range(n):\n col_sum = sum(matrix[row][col] for row in range(n))\n if col_sum != magic_sum:\n return False\n\n # Check the main diagonal\n diag1_sum = sum(matrix[i][i] for i in range(n))\n if diag1_sum != magic_sum:\n return False\n\n # Check the secondary diagonal\n diag2_sum = sum(matrix[i][n - i - 1] for i in range(n))\n if diag2_sum != magic_sum:\n return False\n\n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n n = len(matrix)\n # Calculate the expected magic constant\n magic_constant = sum(matrix[0])\n\n # Check sums of rows\n for row in matrix:\n if sum(row) != magic_constant:\n return False\n\n # Check sums of columns\n for col in range(n):\n if sum(matrix[row][col] for row in range(n)) != magic_constant:\n return False\n\n # Check sums of diagonals\n if sum(matrix[i][i] for i in range(n)) != magic_constant:\n return False\n if sum(matrix[i][n - i - 1] for i in range(n)) != magic_constant:\n return False\n\n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n size = len(matrix)\n\n # Check if the matrix is a square matrix\n for row in matrix:\n if len(row) != size:\n return False\n\n # Calculate the sum of the first row which will be used as the magic constant\n magic_constant = sum(matrix[0])\n\n # Check rows\n for row in matrix:\n if sum(row) != magic_constant:\n return False\n\n # Check columns\n for col in range(size):\n if sum(matrix[row][col] for row in range(size)) != magic_constant:\n return False\n\n # Check the main diagonal\n if sum(matrix[i][i] for i in range(size)) != magic_constant:\n return False\n\n # Check the secondary diagonal\n if sum(matrix[i][size - 1 - i] for i in range(size)) != magic_constant:\n return False\n\n return True", "matching_cluster_idx": 13}, {"solution": "def magic_square_test(matrix):\n if len(matrix) == 0 or len(matrix) != len(matrix[0]):\n return False\n\n n = len(matrix)\n\n # Calculate the sum of the first row (which is the magic constant)\n magic_constant = sum(matrix[0])\n\n # Check rows\n for row in matrix:\n if sum(row) != magic_constant:\n return False\n\n # Check columns\n for col in range(n):\n col_sum = sum(matrix[row][col] for row in range(n))\n if col_sum != magic_constant:\n return False\n\n # Check main diagonal\n main_diag_sum = sum(matrix[i][i] for i in range(n))\n if main_diag_sum != magic_constant:\n return False\n\n # Check secondary diagonal\n sec_diag_sum = sum(matrix[i][n - 1 - i] for i in range(n))\n if sec_diag_sum != magic_constant:\n return False\n\n return True", "matching_cluster_idx": 14}]}, "Mbpp/130": {"dps": 86.88340807174887, "dps_norm": 75.0, "pass@1": 88.0, "profiled": [{"solution": "from collections import Counter\ndef max_occurrences(lst):\n # Count the occurrences of each item in the list\n count = Counter(lst)\n\n # Find the item with the maximum frequency\n max_item = max(count, key=count.get)\n\n return max_item", "matching_cluster_idx": 4}, {"solution": "def max_occurrences(lst):\n \"\"\"\n Find the item with maximum frequency in a given list.\n \"\"\"\n # Create a dictionary to store the frequency of each element\n frequency = {}\n for item in lst:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n\n # Find the element with the maximum frequency\n max_item = max(frequency, key=frequency.get)\n\n return max_item", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(lst):\n \"\"\"\n Find the item with maximum frequency in a given list.\n \"\"\"\n from collections import Counter\n\n if not lst:\n return None\n\n count = Counter(lst)\n max_item = max(count, key=count.get)\n\n return max_item", "matching_cluster_idx": 4}, {"solution": "from collections import Counter\ndef max_occurrences(lst):\n \"\"\"\n Find the item with maximum frequency in a given list.\n \"\"\"\n if not lst:\n return None\n\n # Use Counter to count occurrences of each item\n count = Counter(lst)\n\n # Find the item with the maximum frequency\n max_item = max(count, key=count.get)\n\n return max_item", "matching_cluster_idx": 4}, {"solution": "def max_occurrences(lst):\n \"\"\"\n Find the item with maximum frequency in a given list.\n \"\"\"\n from collections import Counter\n\n # Count the occurrences of each item in the list\n item_counts = Counter(lst)\n\n # Find the item with the maximum occurrence\n max_item = max(item_counts, key=item_counts.get)\n\n return max_item", "matching_cluster_idx": 4}, {"solution": "def max_occurrences(lst):\n from collections import Counter\n if len(lst) == 0:\n return None\n count = Counter(lst)\n max_count = max(list(count.values()))\n max_items = [k for k,v in count.items() if v == max_count]\n return max_items[0] if max_items else None", "matching_cluster_idx": 4}, {"solution": "def max_occurrences(lst):\n # Use a dictionary to count the frequency of each item\n frequency_dict = {}\n for item in lst:\n if item in frequency_dict:\n frequency_dict[item] += 1\n else:\n frequency_dict[item] = 1\n\n # Find the item with the maximum frequency\n max_frequency = 0\n max_item = None\n for item, frequency in frequency_dict.items():\n if frequency > max_frequency:\n max_frequency = frequency\n max_item = item\n\n return max_item", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(lst):\n '''\n This function finds the item with maximum frequency in a given list.\n If there are multiple items with the same maximum frequency, it returns the first one encountered.\n '''\n frequency_dict = {}\n for item in lst:\n if item in frequency_dict:\n frequency_dict[item] += 1\n else:\n frequency_dict[item] = 1\n\n max_count = 0\n max_item = None\n for item, count in frequency_dict.items():\n if count > max_count:\n max_count = count\n max_item = item\n\n return max_item", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(lst):\n frequency_dict = {}\n\n for item in lst:\n if item in frequency_dict:\n frequency_dict[item] += 1\n else:\n frequency_dict[item] = 1\n\n max_count = 0\n max_item = None\n for key, value in frequency_dict.items():\n if value > max_count:\n max_count = value\n max_item = key\n\n return max_item", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(lst):\n \"\"\"Find the item with maximum frequency in a given list.\"\"\"\n frequency_dict = {}\n\n # Count the frequency of each item\n for item in lst:\n if item in frequency_dict:\n frequency_dict[item] += 1\n else:\n frequency_dict[item] = 1\n\n # Find the item with maximum frequency\n max_count = 0\n max_item = None\n for item, count in frequency_dict.items():\n if count > max_count:\n max_count = count\n max_item = item\n\n return max_item", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(lst):\n \"\"\"\n Finds the item with maximum frequency in a given list.\n\n Args:\n lst (list): The list of items to analyze.\n\n Returns:\n The item with the highest frequency in the list.\n \"\"\"\n # Create a dictionary to store the frequency of each item\n frequency_dict = {}\n for item in lst:\n if item in frequency_dict:\n frequency_dict[item] += 1\n else:\n frequency_dict[item] = 1\n\n # Find the item with the maximum frequency\n max_freq_item = max(frequency_dict, key=frequency_dict.get)\n\n return max_freq_item", "matching_cluster_idx": 3}, {"solution": "from collections import Counter\ndef max_occurrences(lst):\n \"\"\"\n Function to find the item with maximum frequency in a given list.\n\n Parameters:\n lst (list): Input list\n\n Returns:\n int/str: Item with the maximum occurrences\n \"\"\"\n # Using Counter to count the frequencies\n count = Counter(lst)\n # Finding the item with the maximum frequency\n max_occur = max(count, key=count.get)\n return max_occur", "matching_cluster_idx": 4}, {"solution": "def max_occurrences(lst):\n if not lst:\n return None\n\n counts = {}\n for num in lst:\n if num in counts:\n counts[num] += 1\n else:\n counts[num] = 1\n\n max_freq_item = max(counts, key=counts.get)\n return max_freq_item", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(lst):\n # Create a dictionary to count occurrences\n count_dict = {}\n for item in lst:\n if item in count_dict:\n count_dict[item] += 1\n else:\n count_dict[item] = 1\n\n # Find the item with the maximum frequency\n max_item = max(count_dict, key=count_dict.get)\n\n return max_item", "matching_cluster_idx": 3}, {"solution": "from collections import Counter\ndef max_occurrences(lst):\n if not lst:\n return None\n\n counter = Counter(lst)\n max_frequency = max(counter.values())\n\n items_with_max_frequency = [item for item, count in counter.items() if count == max_frequency]\n\n return items_with_max_frequency[0]", "matching_cluster_idx": 4}, {"solution": "def max_occurrences(lst):\n \"\"\"\n This function returns the item with the maximum frequency in the given list.\n \"\"\"\n # Using a dictionary to count occurrences of each item in the list\n count_dict = {}\n for item in lst:\n if item in count_dict:\n count_dict[item] += 1\n else:\n count_dict[item] = 1\n\n # Finding the item with the maximum frequency\n max_count = 0\n max_item = None\n for item, count in count_dict.items():\n if count > max_count:\n max_count = count\n max_item = item\n\n return max_item", "matching_cluster_idx": 3}, {"solution": "def max_occurrences(lst):\n # Create a dictionary to count occurrences of each element\n frequency_dict = {}\n for item in lst:\n if item in frequency_dict:\n frequency_dict[item] += 1\n else:\n frequency_dict[item] = 1\n\n # Find the element with the maximum frequency\n max_frequency_item = None\n max_frequency = 0\n for key, value in frequency_dict.items():\n if value > max_frequency:\n max_frequency = value\n max_frequency_item = key\n\n return max_frequency_item", "matching_cluster_idx": 3}, {"solution": "from collections import Counter\ndef max_occurrences(lst):\n if not lst:\n return None\n counter = Counter(lst)\n max_item = max(counter, key=counter.get)\n return max_item", "matching_cluster_idx": 4}, {"solution": "from collections import Counter\ndef max_occurrences(lst):\n # Count the occurrences of each item in the list\n count_dict = Counter(lst)\n # Find the item with the maximum frequency\n max_item = max(count_dict, key=count_dict.get)\n return max_item", "matching_cluster_idx": 4}, {"solution": "from collections import Counter\ndef max_occurrences(lst):\n # Use Counter to count occurrences of each item in the list\n counts = Counter(lst)\n # Find the item with the maximum count\n max_item = max(counts, key=counts.get)\n return max_item", "matching_cluster_idx": 4}]}, "Mbpp/137": {"dps": 59.838709677419345, "dps_norm": 70.0, "pass@1": 33.0, "profiled": [{"solution": "import math\ndef zero_count(arr):\n \"\"\"\n Function to find the ratio of zeroes to non-zeroes in an array of integers.\n\n Args:\n arr (list): A list of integers.\n\n Returns:\n float: Ratio of zeroes to non-zeroes.\n \"\"\"\n if not arr:\n return 0.0 # If the array is empty, return 0.0\n\n zero_count = arr.count(0)\n non_zero_count = len(arr) - zero_count\n\n if non_zero_count == 0:\n return float('inf') # If all elements are zero, return infinity\n\n return zero_count / non_zero_count", "matching_cluster_idx": 6}, {"solution": "import math\ndef zero_count(arr):\n \"\"\"\n Function to find the ratio of zeroes to non-zeroes in an array of integers.\n\n Args:\n arr (list of int): List of integers.\n\n Returns:\n float: Ratio of zeroes to non-zeroes.\n \"\"\"\n if not arr:\n return 0\n\n zero_count = sum(1 for x in arr if x == 0)\n non_zero_count = len(arr) - zero_count\n\n if non_zero_count == 0:\n return float('inf') if zero_count > 0 else 0\n\n return zero_count / non_zero_count", "matching_cluster_idx": 5}, {"solution": "import math\ndef zero_count(arr):\n zero_count = 0\n non_zero_count = 0\n\n for num in arr:\n if num == 0:\n zero_count += 1\n else:\n non_zero_count += 1\n\n if non_zero_count == 0:\n return float('inf') # or however you want to handle the case with no non-zero numbers\n\n return zero_count / non_zero_count", "matching_cluster_idx": 3}, {"solution": "import math\ndef zero_count(arr):\n zero_count = sum(1 for x in arr if x == 0)\n non_zero_count = len(arr) - zero_count\n return zero_count / non_zero_count if non_zero_count != 0 else float('inf')", "matching_cluster_idx": 5}, {"solution": "import math\ndef zero_count(arr):\n \"\"\"\n This function calculates the ratio of zeroes to non-zeroes in an array of integers.\n\n Parameters:\n arr (list): A list of integers.\n\n Returns:\n float: The ratio of zeroes to non-zeroes.\n \"\"\"\n zeroes = sum(1 for x in arr if x == 0)\n non_zeroes = len(arr) - zeroes\n\n if non_zeroes == 0:\n return float('inf') # if there are no non-zeroes, the ratio is infinite\n\n return zeroes / non_zeroes", "matching_cluster_idx": 5}, {"solution": "import math\ndef zero_count(arr):\n # Count the number of zeroes in the array\n zeroes = sum(1 for x in arr if x == 0)\n # Total elements in the array\n total = len(arr)\n # Calculate the ratio of zeroes to non-zeroes\n ratio = zeroes / (total - zeroes) if total - zeroes != 0 else float('inf')\n return ratio", "matching_cluster_idx": 4}, {"solution": "import math\ndef zero_count(arr):\n \"\"\"\n Function to find the ratio of zeroes to non-zeroes in an array of integers.\n\n :param arr: list of integers\n :return: float, ratio of zeroes to non-zeroes\n \"\"\"\n zero_count = sum(1 for x in arr if x == 0)\n non_zero_count = len(arr) - zero_count\n\n if non_zero_count == 0:\n return float('inf') if zero_count > 0 else 0.0\n\n return zero_count / non_zero_count", "matching_cluster_idx": 5}, {"solution": "import math\ndef zero_count(arr):\n zero_count = sum(1 for x in arr if x == 0)\n non_zero_count = len(arr) - zero_count\n ratio = zero_count / non_zero_count if non_zero_count != 0 else float('inf')\n return ratio", "matching_cluster_idx": 5}, {"solution": "import math\ndef zero_count(arr):\n \"\"\"\n Function to find the ratio of zeroes to non-zeroes in an array of integers.\n\n Parameters:\n arr (list): List of integers\n\n Returns:\n float: Ratio of zeroes to non-zeroes\n \"\"\"\n # Count the number of zeroes\n zeroes = arr.count(0)\n\n # Count the number of non-zero elements\n non_zeroes = len(arr) - zeroes\n\n # Calculate the ratio of zeroes to non-zero elements\n if non_zeroes == 0:\n return float('inf') # or return 0.0 depending on how to handle cases with no non-zero elements\n\n ratio = zeroes / non_zeroes\n return ratio", "matching_cluster_idx": 7}, {"solution": "import math\ndef zero_count(arr):\n \"\"\"\n Calculate the ratio of zeroes to non-zeroes in the array.\n\n Parameters:\n arr (list): A list of integers.\n\n Returns:\n float: The ratio of zeroes to non-zeroes.\n \"\"\"\n zeroes = sum(1 for x in arr if x == 0)\n non_zeroes = sum(1 for x in arr if x != 0)\n\n if non_zeroes == 0:\n return float('inf') if zeroes > 0 else 0.0\n\n return zeroes / non_zeroes", "matching_cluster_idx": 1}, {"solution": "import math\ndef zero_count(array):\n \"\"\"\n Function to find the ratio of zeroes to non-zeroes in an array of integers.\n \"\"\"\n if not array:\n return 0\n\n count_zeroes = sum(1 for x in array if x == 0)\n count_non_zeroes = len(array) - count_zeroes\n\n if count_non_zeroes == 0:\n return float('inf')\n\n return count_zeroes / count_non_zeroes", "matching_cluster_idx": 5}, {"solution": "import math\ndef zero_count(arr):\n \"\"\"\n Function to find the ratio of zeroes to non-zeroes in an array of integers.\n\n Parameters:\n arr (list of int): Input list of integers.\n\n Returns:\n float: Ratio of zeroes to non-zeroes in the array.\n \"\"\"\n if not arr:\n return 0.0\n\n zero_count = sum(1 for x in arr if x == 0)\n non_zero_count = len(arr) - zero_count\n\n if non_zero_count == 0:\n return float('inf') if zero_count > 0 else 0.0\n\n return zero_count / non_zero_count", "matching_cluster_idx": 5}, {"solution": "import math\ndef zero_count(arr):\n \"\"\"\n Calculate the ratio of zeroes to non-zeroes in an array of integers.\n\n :param arr: List of integers\n :return: Ratio of zeroes to non-zeroes as a float\n \"\"\"\n if not arr: # Check if the list is empty\n return 0.0\n\n zero_count = sum(1 for x in arr if x == 0)\n non_zero_count = len(arr) - zero_count\n\n if non_zero_count == 0:\n return float('inf') # To handle the case where all elements are zero\n\n return zero_count / non_zero_count", "matching_cluster_idx": 5}, {"solution": "import math\ndef zero_count(arr):\n \"\"\"\n This function calculates the ratio of zeroes to non-zeroes in an array of integers.\n\n Parameters:\n arr (list): A list of integers.\n\n Returns:\n float: The ratio of zeroes to non-zeroes.\n \"\"\"\n if not arr: # Handle empty array edge case\n return 0.0\n\n count_zeroes = sum(1 for num in arr if num == 0)\n count_non_zeroes = len(arr) - count_zeroes\n\n if count_non_zeroes == 0:\n return float('inf') # Handle case where there are no non-zero elements\n\n return count_zeroes / count_non_zeroes", "matching_cluster_idx": 5}, {"solution": "import math\ndef zero_count(arr):\n \"\"\"\n Function to find the ratio of zeroes to non-zeroes in an array of integers.\n :param arr: List of integers\n :return: Float ratio of zeroes to non-zeroes\n \"\"\"\n if not arr: # Check if the array is empty\n return 0.0\n\n zero_count = sum(1 for num in arr if num == 0)\n non_zero_count = len(arr) - zero_count\n\n if non_zero_count == 0: # Avoid division by zero\n return float('inf') if zero_count > 0 else 0.0\n\n return zero_count / non_zero_count", "matching_cluster_idx": 5}, {"solution": "import math\ndef zero_count(arr):\n zero_count = 0\n non_zero_count = 0\n\n for num in arr:\n if num == 0:\n zero_count += 1\n else:\n non_zero_count += 1\n\n if non_zero_count == 0:\n return float('inf')\n else:\n return zero_count / non_zero_count", "matching_cluster_idx": 3}, {"solution": "import math\ndef zero_count(arr):\n if len(arr) == 0:\n return 0\n zeroes = sum(1 for num in arr if num == 0)\n non_zeroes = len(arr) - zeroes\n ratio = zeroes / non_zeroes if non_zeroes != 0 else float('inf')\n return ratio", "matching_cluster_idx": 4}, {"solution": "import math\ndef zero_count(arr):\n \"\"\"\n Calculate the ratio of zeroes to non-zeroes in an array of integers.\n\n Args:\n arr (list): A list of integers.\n\n Returns:\n float: The ratio of zeroes to non-zeroes.\n \"\"\"\n if not arr:\n return 0 # Handle case with empty array\n\n zero_count = sum(1 for x in arr if x == 0)\n non_zero_count = len(arr) - zero_count\n\n # Avoid division by zero\n if non_zero_count == 0:\n return float('inf') if zero_count > 0 else 0\n\n return zero_count / non_zero_count", "matching_cluster_idx": 5}, {"solution": "import math\ndef zero_count(arr):\n \"\"\"\n Function to find the ratio of zeroes to non-zeroes in an array of integers.\n\n Parameters:\n arr (list of int): List of integers\n\n Returns:\n float: Ratio of zeroes to non-zeroes\n \"\"\"\n zero_count = sum(1 for x in arr if x == 0)\n non_zero_count = len(arr) - zero_count\n return zero_count / non_zero_count if non_zero_count != 0 else float('inf')", "matching_cluster_idx": 4}, {"solution": "import math\ndef zero_count(arr):\n zero_count = sum(1 for x in arr if x == 0)\n nonzero_count = len(arr) - zero_count\n ratio = zero_count / nonzero_count if nonzero_count != 0 else float('inf')\n return ratio", "matching_cluster_idx": 5}]}, "Mbpp/140": {"dps": 78.64906832298136, "dps_norm": 80.625, "pass@1": 100.0, "profiled": [{"solution": "def extract_singly(nested_list):\n \"\"\"Flattens a list of tuples into a single set of numbers.\"\"\"\n return set(num for sublist in nested_list for num in sublist)", "matching_cluster_idx": 5}, {"solution": "def extract_singly(list_of_tuples):\n \"\"\"\n Flatten a list of tuples into a single set of numbers.\n Args:\n list_of_tuples (list of tuples): A list where each element is a tuple of numbers.\n\n Returns:\n set: A set containing all the unique numbers from the list of tuples.\n \"\"\"\n flat_set = set()\n for tup in list_of_tuples:\n flat_set.update(tup)\n return flat_set", "matching_cluster_idx": 7}, {"solution": "def extract_singly(list_of_tuples):\n \"\"\"\n Flattens the list of lists (or tuples) into a single set of numbers.\n\n :param list_of_tuples: List of tuples containing integers.\n :return: Set of unique integers.\n \"\"\"\n flat_set = set()\n for t in list_of_tuples:\n flat_set.update(t)\n return flat_set", "matching_cluster_idx": 7}, {"solution": "def extract_singly(list_of_tuples):\n # Use a set comprehension to flatten the list of tuples into a single set of numbers.\n return set(num for tup in list_of_tuples for num in tup)", "matching_cluster_idx": 5}, {"solution": "def extract_singly(list_of_tuples):\n # Use a set comprehension to flatten the list of tuples into a single set\n return set(item for tuple_ in list_of_tuples for item in tuple_)", "matching_cluster_idx": 5}, {"solution": "def extract_singly(list_of_tuples):\n # Using set comprehension to flatten the list of lists into a single set of numbers\n return {num for sublist in list_of_tuples for num in sublist}", "matching_cluster_idx": 5}, {"solution": "def extract_singly(list_of_lists):\n \"\"\"\n This function takes a list of tuples and returns a set of numbers flattened from the tuples.\n \"\"\"\n result_set = set()\n for tup in list_of_lists:\n result_set.update(tup)\n return result_set", "matching_cluster_idx": 7}, {"solution": "def extract_singly(list_of_lists):\n \"\"\"\n Flattens the list of lists into a single set of numbers.\n\n Parameters:\n list_of_lists (list of tuples): The input list containing tuples of numbers.\n\n Returns:\n set: A set containing all the unique numbers from the input list of lists.\n \"\"\"\n return set(num for sublist in list_of_lists for num in sublist)", "matching_cluster_idx": 5}, {"solution": "def extract_singly(lst):\n \"\"\"\n This function takes a list of tuples and flattens it into a single set of numbers.\n :param lst: list of tuples containing integers\n :return: a set of integers\n \"\"\"\n flattened_set = set()\n for sublist in lst:\n for item in sublist:\n flattened_set.add(item)\n return flattened_set", "matching_cluster_idx": 4}, {"solution": "def extract_singly(list_of_tuples):\n \"\"\"\n This function flattens a list of tuples into a single set of numbers.\n\n :param list_of_tuples: List of tuples containing numbers\n :return: A set containing all unique numbers from the list of tuples\n \"\"\"\n flattened_set = set()\n for tup in list_of_tuples:\n flattened_set.update(tup)\n return flattened_set", "matching_cluster_idx": 6}, {"solution": "def extract_singly(list_of_tuples):\n # Flattens the list of tuples into a single set\n result_set = set()\n for tup in list_of_tuples:\n result_set.update(tup)\n return result_set", "matching_cluster_idx": 7}, {"solution": "def extract_singly(list_of_tuples):\n \"\"\"\n Flattens a list of tuples into a single set of numbers.\n\n Args:\n list_of_tuples (list): A list containing tuples of numbers.\n\n Returns:\n set: A set containing all numbers from the list of tuples.\n \"\"\"\n flat_list = []\n for tup in list_of_tuples:\n flat_list.extend(tup)\n return set(flat_list)", "matching_cluster_idx": 6}, {"solution": "def extract_singly(list_of_tuples):\n \"\"\"\n This function takes a list of tuples and returns a set of unique numbers.\n\n Parameters:\n list_of_tuples (list): A list of tuples containing numbers.\n\n Returns:\n set: A set of unique numbers.\n \"\"\"\n flat_set = set()\n for tup in list_of_tuples:\n flat_set.update(tup)\n return flat_set", "matching_cluster_idx": 7}, {"solution": "def extract_singly(list_of_tuples):\n \"\"\"\n Flatten the list of tuples into a single set of numbers.\n\n Args:\n list_of_tuples (list): A list of tuples containing numbers.\n\n Returns:\n set: A set of numbers extracted from the list of tuples.\n \"\"\"\n flat_set = set()\n for t in list_of_tuples:\n flat_set.update(t)\n return flat_set", "matching_cluster_idx": 7}, {"solution": "def extract_singly(list_of_tuples):\n \"\"\"\n This function takes a list of tuples and returns a set containing all the unique numbers from the tuples.\n \"\"\"\n flattened_set = set()\n\n for tup in list_of_tuples:\n for num in tup:\n flattened_set.add(num)\n\n return flattened_set", "matching_cluster_idx": 3}, {"solution": "def extract_singly(list_of_lists):\n return set(num for sublist in list_of_lists for num in sublist)", "matching_cluster_idx": 5}, {"solution": "def extract_singly(list_of_lists):\n # Use a set comprehension to iterate over each tuple in the list of lists and then iterate over each number in the tuple\n return {num for sublist in list_of_lists for num in sublist}", "matching_cluster_idx": 5}, {"solution": "def extract_singly(nested_list):\n \"\"\"\n Flattens a list of tuples into a single set of numbers.\n\n Parameters:\n nested_list (list of tuples): The input list of tuples to be flattened.\n\n Returns:\n set: A set of unique numbers extracted from the nested list.\n \"\"\"\n # Using set comprehension to flatten the list of tuples into a set\n return {num for sublist in nested_list for num in sublist}", "matching_cluster_idx": 5}, {"solution": "def extract_singly(list_of_tuples):\n \"\"\"\n Flatten the list of tuples into a single set of numbers.\n \"\"\"\n # Use a set comprehension to extract and flatten the numbers\n return {num for tup in list_of_tuples for num in tup}", "matching_cluster_idx": 5}, {"solution": "def extract_singly(list_of_tuples):\n \"\"\"\n Flatten the list of lists into a single set of numbers.\n \"\"\"\n result_set = set()\n for t in list_of_tuples:\n for num in t:\n result_set.add(num)\n return result_set", "matching_cluster_idx": 3}]}, "Mbpp/141": {"dps": 68.63945578231294, "dps_norm": 41.875, "pass@1": 93.0, "profiled": [{"solution": "def pancake_sort(arr):\n def flip(sub_list, k):\n # Helper function to reverse the first k elements of the list\n return sub_list[:k][::-1] + sub_list[k:]\n\n n = len(arr)\n while n > 1:\n # Find the maximum element in the unsorted part of the list\n max_idx = arr.index(max(arr[:n]), 0, n)\n\n # If the maximum element is already at the end, reduce the range\n if max_idx == n - 1:\n n -= 1\n continue\n\n # Move the maximum element to the beginning\n arr = flip(arr, max_idx + 1)\n # Move the maximum element from the beginning to the correct position\n arr = flip(arr, n)\n\n # Reduce the range of the unsorted part\n n -= 1\n\n return arr", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(arr):\n \"\"\"\n Sorts the input list using the pancake sort algorithm.\n \"\"\"\n def flip(arr, k):\n \"\"\"Helper function to flip the first k elements of the list.\"\"\"\n i = 0\n while i < k:\n arr[i], arr[k] = arr[k], arr[i]\n i += 1\n k -= 1\n\n n = len(arr)\n while n > 1:\n max_idx = arr.index(max(arr[:n]))\n if max_idx != n - 1:\n flip(arr, max_idx)\n flip(arr, n - 1)\n n -= 1\n return arr", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(lst):\n for size in range(len(lst), 1, -1):\n # Find the maximum element in the unsorted part of the list\n max_idx = lst.index(max(lst[:size]))\n\n # Move the maximum element to the beginning\n lst[:max_idx + 1] = reversed(lst[:max_idx + 1])\n\n # Move the maximum element to its correct position\n lst[:size] = reversed(lst[:size])\n return lst", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(arr):\n \"\"\"\n Sorts the input list in-place using the pancake sort algorithm.\n \"\"\"\n def flip(arr, k):\n \"\"\"Helper function to flip the first k elements of the array.\"\"\"\n i = 0\n while i < k:\n arr[i], arr[k] = arr[k], arr[i]\n i += 1\n k -= 1\n\n n = len(arr)\n for size in range(n, 1, -1):\n max_idx = arr.index(max(arr[:size]))\n flip(arr, max_idx)\n flip(arr, size-1)\n\n return arr", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(arr):\n # Define a helper function to flip the elements of the list\n def flip(sublist, k):\n left = 0\n while left < k:\n sublist[left], sublist[k] = sublist[k], sublist[left]\n left += 1\n k -= 1\n\n n = len(arr)\n while n > 1:\n # Find the maximum element in the unsorted part of the list\n max_idx = arr.index(max(arr[:n]))\n\n # Flip the maximum element to the first position\n flip(arr, max_idx)\n\n # Flip the maximum element to its final position in the sorted part\n flip(arr, n-1)\n\n # Reduce the range of unsorted elements\n n -= 1\n\n return arr", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(arr):\n def flip(sublist, k):\n return sublist[:k+1][::-1] + sublist[k+1:]\n\n def find_max_index(sublist):\n return sublist.index(max(sublist))\n\n for size in range(len(arr), 1, -1):\n max_index = find_max_index(arr[:size])\n arr = flip(arr, max_index)\n arr = flip(arr, size-1)\n\n return arr", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(arr):\n \"\"\"\n Sort an array using pancake sort algorithm.\n \"\"\"\n def flip(sublist, k):\n \"\"\"\n Reverse the first `k` elements in the sublist.\n \"\"\"\n i = 0\n while i < k:\n sublist[i], sublist[k-1] = sublist[k-1], sublist[i]\n i += 1\n k -= 1\n\n n = len(arr)\n while n > 1:\n # Find the maximum element in the array\n max_index = arr.index(max(arr[:n]))\n\n # If the maximum element is not at the end, flip it to the front\n if max_index != n - 1:\n flip(arr, max_index + 1)\n flip(arr, n)\n\n # Reduce the size of the problem\n n -= 1\n\n return arr", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(arr):\n def flip(arr, k):\n for i in range(k // 2):\n arr[i], arr[k - i - 1] = arr[k - i - 1], arr[i]\n\n n = len(arr)\n for size in range(n, 1, -1):\n max_index = arr.index(max(arr[:size]))\n if max_index != size - 1:\n flip(arr, max_index + 1)\n flip(arr, size)\n return arr", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(arr):\n def flip(sublist, k):\n return sublist[k::-1] + sublist[k+1:]\n\n for i in range(len(arr), 1, -1):\n max_index = arr.index(max(arr[:i]), 0, i)\n arr = flip(arr, max_index)\n arr = flip(arr, i-1)\n\n return arr", "matching_cluster_idx": 3}, {"solution": "def flip(arr, k):\n \"\"\"Helper function to flip the list up to index k.\"\"\"\n return arr[:k][::-1] + arr[k:]\ndef find_max_index(arr, n):\n \"\"\"Helper function to find the index of the maximum element in the array up to index n.\"\"\"\n max_index = 0\n for i in range(n):\n if arr[i] > arr[max_index]:\n max_index = i\n return max_index\ndef pancake_sort(arr):\n \"\"\"Main function to sort the list using pancake sort.\"\"\"\n n = len(arr)\n while n > 1:\n # Find the maximum element in the unsorted portion of the list\n max_index = find_max_index(arr, n)\n if max_index != n - 1:\n # Flip the maximum element to the start of the list\n arr = flip(arr, max_index + 1)\n # Flip the maximum element to its correct position\n arr = flip(arr, n)\n n -= 1\n return arr", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(arr):\n def flip(arr, k):\n return arr[:k+1][::-1] + arr[k+1:]\n\n for size in range(len(arr), 1, -1):\n max_idx = arr.index(max(arr[:size]))\n arr = flip(arr, max_idx)\n arr = flip(arr, size-1)\n return arr", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(lst):\n \"\"\"\n Function to sort a list of elements using pancake sort algorithm.\n\n Pancake sort algorithm is similar to selection sort, but with an added operation\n where any prefix of the list can be flipped.\n \"\"\"\n def flip(sublist, k):\n left = 0\n while left < k:\n sublist[left], sublist[k] = sublist[k], sublist[left]\n left += 1\n k -= 1\n\n n = len(lst)\n while n > 1:\n max_idx = lst.index(max(lst[:n]))\n flip(lst, max_idx)\n flip(lst, n - 1)\n n -= 1\n return lst", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(arr):\n def flip(arr, k):\n # Reverse the sublist from 0 to k\n i = 0\n while i < k:\n arr[i], arr[k] = arr[k], arr[i]\n i += 1\n k -= 1\n\n n = len(arr)\n while n > 1:\n # Find the maximum element in the unsorted part of the list\n max_idx = arr.index(max(arr[:n]))\n\n # Move the maximum element to the beginning\n flip(arr, max_idx)\n # Move the maximum element to the end\n flip(arr, n - 1)\n # Reduce the size of the unsorted part\n n -= 1\n\n return arr", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(arr):\n def flip(arr, k):\n # Function to flip the first 'k' elements in the array\n return arr[:k][::-1] + arr[k:]\n\n n = len(arr)\n while n > 1:\n # Find the index of the maximum element in the first 'n' elements\n max_idx = arr.index(max(arr[:n]))\n\n # Flip the maximum element to the start\n arr = flip(arr, max_idx + 1)\n\n # Flip the entire first 'n' elements to move the maximum element to its final position\n arr = flip(arr, n)\n\n # Reduce the problem size\n n -= 1\n\n return arr", "matching_cluster_idx": 3}, {"solution": "def flip(arr, k):\n \"\"\"Flip the first k elements of the list.\"\"\"\n return arr[:k+1][::-1] + arr[k+1:]\ndef pancake_sort(arr):\n \"\"\"Sort the list using pancake sort algorithm.\"\"\"\n if not arr:\n return arr\n\n for size in range(len(arr), 1, -1):\n # Find the index of the maximum element in the first 'size' elements\n max_idx = arr[:size].index(max(arr[:size]))\n\n # Flip the maximum element to the front\n arr = flip(arr, max_idx)\n\n # Flip the maximum element to its correct position\n arr = flip(arr, size-1)\n\n return arr", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(arr):\n def flip(arr, k):\n for i in range(k // 2):\n arr[i], arr[k - i - 1] = arr[k - i - 1], arr[i]\n\n n = len(arr)\n for size in range(n, 1, -1):\n max_idx = arr.index(max(arr[:size]))\n flip(arr, max_idx + 1)\n flip(arr, size)\n return arr", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(arr):\n def flip(arr, k):\n \"\"\"\n Helper function to flip the first k elements of the array\n \"\"\"\n i, j = 0, k\n while i < j:\n arr[i], arr[j] = arr[j], arr[i]\n i += 1\n j -= 1\n\n n = len(arr)\n for size in range(n, 1, -1):\n # Find the index of the maximum element in the first `size` elements\n max_idx = arr.index(max(arr[:size]))\n\n # Flip the elements to bring the maximum element to the start\n if max_idx != 0:\n flip(arr, max_idx)\n\n # Flip the entire subarray to put the maximum element in the correct position\n flip(arr, size - 1)\n\n return arr", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(arr):\n # Function to flip the first 'i' elements of the array\n def flip(arr, i):\n start = 0\n while start < i:\n arr[start], arr[i] = arr[i], arr[start]\n start += 1\n i -= 1\n\n # Get the length of the array\n n = len(arr)\n # Starting from the end of the array\n for i in range(n, 1, -1):\n # Find the maximum element in the unsorted portion of the array\n max_index = arr.index(max(arr[:i]))\n # Flip the largest element to the start\n flip(arr, max_index)\n # Flip the largest element to the end (its correct position)\n flip(arr, i - 1)\n\n return arr", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(arr):\n \"\"\"\n Sorts a list of elements in place using the pancake sort algorithm.\n \"\"\"\n def flip(arr, i):\n \"\"\"\n Reverses the elements of arr from index 0 to i (inclusive).\n \"\"\"\n left = 0\n while left < i:\n arr[left], arr[i] = arr[i], arr[left]\n left += 1\n i -= 1\n\n n = len(arr)\n for size in range(n, 1, -1):\n # Find the index of the maximum element in the first 'size' elements\n max_idx = arr.index(max(arr[:size]))\n\n # Move the max element to the beginning\n if max_idx != size - 1:\n flip(arr, max_idx)\n\n # Move the max element to its final position\n flip(arr, size - 1)\n\n return arr", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(arr):\n def flip(arr, k):\n start = 0\n while start < k:\n arr[start], arr[k] = arr[k], arr[start]\n start += 1\n k -= 1\n\n n = len(arr)\n while n > 1:\n max_idx = arr.index(max(arr[:n]))\n if max_idx != n - 1:\n flip(arr, max_idx)\n flip(arr, n - 1)\n n -= 1\n return arr", "matching_cluster_idx": 2}]}, "Mbpp/166": {"dps": 91.91999999999999, "dps_norm": 66.25, "pass@1": 91.0, "profiled": [{"solution": "def find_even_pair(arr):\n count = 0\n n = len(arr)\n\n # Loop through each possible pair in the array\n for i in range(n):\n for j in range(i+1, n):\n if (arr[i] ^ arr[j]) % 2 == 0:\n count += 1\n\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(lst):\n even_count = 0\n odd_count = 0\n\n # Count the number of even and odd numbers in the list\n for num in lst:\n if num % 2 == 0:\n even_count += 1\n else:\n odd_count += 1\n\n # Calculate the number of pairs that XOR to an even number\n # Even XOR Even = Even\n # Odd XOR Odd = Even\n even_even_pairs = (even_count * (even_count - 1)) // 2\n odd_odd_pairs = (odd_count * (odd_count - 1)) // 2\n\n return even_even_pairs + odd_odd_pairs", "matching_cluster_idx": 3}, {"solution": "def find_even_pair(arr):\n even_count = 0\n odd_count = 0\n\n for num in arr:\n if num % 2 == 0:\n even_count += 1\n else:\n odd_count += 1\n\n # Even XOR Even = Even\n # Odd XOR Odd = Even\n pairs = (even_count * (even_count - 1)) // 2 + (odd_count * (odd_count - 1)) // 2\n\n return pairs", "matching_cluster_idx": 3}, {"solution": "def find_even_pair(numbers):\n even_count = 0\n odd_count = 0\n\n # Count even and odd numbers in the list\n for num in numbers:\n if num % 2 == 0:\n even_count += 1\n else:\n odd_count += 1\n\n # Calculate the number of pairs (even, even) and (odd, odd)\n even_even_pairs = (even_count * (even_count - 1)) // 2\n odd_odd_pairs = (odd_count * (odd_count - 1)) // 2\n\n # Return the total number of pairs that xor to an even number\n return even_even_pairs + odd_odd_pairs", "matching_cluster_idx": 3}, {"solution": "def find_even_pair(lst):\n count = 0\n n = len(lst)\n for i in range(n):\n for j in range(i + 1, n):\n if (lst[i] ^ lst[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(nums):\n even_count = 0\n odd_count = 0\n\n # Count the number of even and odd numbers\n for num in nums:\n if num % 2 == 0:\n even_count += 1\n else:\n odd_count += 1\n\n # Pairs of two even numbers or two odd numbers xor to an even number\n even_even_pairs = (even_count * (even_count - 1)) // 2\n odd_odd_pairs = (odd_count * (odd_count - 1)) // 2\n\n return even_even_pairs + odd_odd_pairs", "matching_cluster_idx": 3}, {"solution": "def find_even_pair(nums):\n count = 0\n n = len(nums)\n\n for i in range(n):\n for j in range(i + 1, n):\n if (nums[i] ^ nums[j]) % 2 == 0:\n count += 1\n\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(lst):\n count = 0\n for i in range(len(lst)):\n for j in range(i + 1, len(lst)):\n if (lst[i] ^ lst[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(lst):\n count = 0\n n = len(lst)\n for i in range(n):\n for j in range(i+1, n):\n if (lst[i] ^ lst[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(lst):\n count = 0\n length = len(lst)\n for i in range(length):\n for j in range(i + 1, length):\n if (lst[i] ^ lst[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(lst):\n \"\"\"\n Count the number of pairs of integers in a list that xor to an even number.\n \"\"\"\n even_count = sum(1 for x in lst if x % 2 == 0)\n odd_count = len(lst) - even_count\n\n # Number of pairs of even numbers and odd numbers\n even_pairs = (even_count * (even_count - 1)) // 2\n odd_pairs = (odd_count * (odd_count - 1)) // 2\n\n # The total number of pairs that xor to an even number is the sum of even pairs and odd pairs\n return even_pairs + odd_pairs", "matching_cluster_idx": 3}, {"solution": "def find_even_pair(nums):\n # Initialize counters for even and odd numbers in the list\n even_count = 0\n odd_count = 0\n\n # Count the number of even and odd numbers\n for num in nums:\n if num % 2 == 0:\n even_count += 1\n else:\n odd_count += 1\n\n # Calculate the number of pairs that XOR to an even number\n # An even XOR even = even\n # An odd XOR odd = even\n # So, we add the combinations of even pairs and odd pairs\n even_pairs = (even_count * (even_count - 1)) // 2\n odd_pairs = (odd_count * (odd_count - 1)) // 2\n\n return even_pairs + odd_pairs", "matching_cluster_idx": 3}, {"solution": "def find_even_pair(lst):\n # Initialize the count of pairs that XOR to an even number\n count = 0\n\n # Iterate over each pair in the list\n for i in range(len(lst)):\n for j in range(i + 1, len(lst)):\n if (lst[i] ^ lst[j]) % 2 == 0:\n count += 1\n\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(arr):\n # Count the number of odd and even numbers in the list\n odd_count = sum(1 for num in arr if num % 2 == 1)\n even_count = len(arr) - odd_count\n\n # The number of pairs (x, y) that xor to an even number\n # is the sum of pairs where both numbers are even and both numbers are odd\n even_pairs = even_count * (even_count - 1) // 2\n odd_pairs = odd_count * (odd_count - 1) // 2\n\n return even_pairs + odd_pairs", "matching_cluster_idx": 3}, {"solution": "def find_even_pair(nums):\n count = 0\n n = len(nums)\n for i in range(n):\n for j in range(i + 1, n):\n if (nums[i] ^ nums[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(lst):\n count = 0\n n = len(lst)\n for i in range(n):\n for j in range(i + 1, n):\n if (lst[i] ^ lst[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(lst):\n \"\"\"\n Counts the number of pairs of integers in the list that xor to an even number.\n \"\"\"\n count = 0\n n = len(lst)\n\n # Iterate through each pair in the list\n for i in range(n):\n for j in range(i + 1, n):\n if (lst[i] ^ lst[j]) % 2 == 0:\n count += 1\n\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(lst):\n # Function to check if the xor of two numbers is even\n def is_even_xor(x, y):\n return (x ^ y) % 2 == 0\n\n # Count the pairs that xor to an even number\n count = 0\n for i in range(len(lst)):\n for j in range(i + 1, len(lst)):\n if is_even_xor(lst[i], lst[j]):\n count += 1\n\n return count", "matching_cluster_idx": 0}, {"solution": "def find_even_pair(lst):\n count = 0\n length = len(lst)\n for i in range(length):\n for j in range(i + 1, length):\n if (lst[i] ^ lst[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(lst):\n \"\"\"\n Counts the number of pairs of integers in a list that xor to an even number.\n \"\"\"\n count = 0\n n = len(lst)\n for i in range(n):\n for j in range(i + 1, n):\n if (lst[i] ^ lst[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}]}, "Mbpp/170": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 44.0, "profiled": [{"solution": "def sum_range_list(nums, start, end):\n # Ensures the provided indices are within the list's range\n if start < 0 or end >= len(nums) or start > end:\n return 0\n\n # Sum the elements from 'start' to 'end' indices\n return sum(nums[start:end+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(lst, start_idx, end_idx):\n return sum(lst[start_idx:end_idx + 1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(nums, start_index, end_index):\n if start_index < 0 or end_index >= len(nums) or start_index > end_index:\n return 0\n return sum(nums[start_index:end_index + 1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(nums, start_index, end_index):\n \"\"\"\n Calculate the sum of numbers in a list within a range specified by two indices.\n\n :param nums: List of numbers\n :param start_index: Starting index of the range (inclusive)\n :param end_index: Ending index of the range (inclusive)\n :return: Sum of numbers within the specified range\n \"\"\"\n return sum(nums[start_index:end_index + 1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(nums, start_index, end_index):\n \"\"\"\n Function to find the sum of numbers in a list within a range specified by two indices.\n :param nums: List of integers.\n :param start_index: Start index of the range (inclusive).\n :param end_index: End index of the range (inclusive).\n :return: Sum of the numbers within the specified range.\n \"\"\"\n # Check if the indices are within the list bounds\n if start_index < 0 or end_index >= len(nums) or start_index > end_index:\n return 0 # Return 0 if the indices are out of bounds or invalid\n return sum(nums[start_index:end_index + 1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(lst, start_index, end_index):\n \"\"\"\n Find the sum of numbers in a list within a range specified by two indices.\n\n :param lst: List of integers\n :param start_index: Starting index (inclusive)\n :param end_index: Ending index (inclusive)\n :return: Sum of numbers in the specified range\n \"\"\"\n if start_index < 0 or end_index >= len(lst) or start_index > end_index:\n return 0\n\n return sum(lst[start_index:end_index + 1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(lst, start_idx, end_idx):\n \"\"\"\n This function finds the sum of numbers in a list within a range specified by two indices.\n Parameters:\n lst (list): The input list of numbers\n start_idx (int): The starting index of the range (inclusive)\n end_idx (int): The ending index of the range (inclusive)\n\n Returns:\n int: The sum of numbers within the specified range\n \"\"\"\n return sum(lst[start_idx:end_idx + 1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(nums, start_index, end_index):\n # Ensure the indices are within the bounds of the list\n if start_index < 0 or end_index >= len(nums) or start_index > end_index:\n return 0\n\n return sum(nums[start_index:end_index + 1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(lst, start, end):\n return sum(lst[start:end+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(nums, start_idx, end_idx):\n \"\"\"\n Calculate the sum of numbers in the list from start_idx to end_idx (inclusive).\n\n :param nums: List of numbers\n :param start_idx: Starting index (inclusive)\n :param end_idx: Ending index (inclusive)\n :return: Sum of numbers from start_idx to end_idx\n \"\"\"\n return sum(nums[start_idx:end_idx + 1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(numbers, start_index, end_index):\n \"\"\"\n Calculate the sum of numbers in the list from start_index to end_index inclusive.\n\n :param numbers: List of integers.\n :param start_index: Starting index of the range (inclusive).\n :param end_index: Ending index of the range (inclusive).\n :return: Sum of numbers in the specified range.\n \"\"\"\n return sum(numbers[start_index:end_index+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(numbers, start_idx, end_idx):\n \"\"\"\n Find the sum of numbers in a list within a range specified by two indices.\n\n Parameters:\n numbers (list): List of numbers.\n start_idx (int): Start index for the range.\n end_idx (int): End index for the range.\n\n Returns:\n int: Sum of the numbers within the specified range.\n \"\"\"\n if not (0 <= start_idx < len(numbers)) or not (0 <= end_idx < len(numbers)):\n raise ValueError(\"Indices out of range\")\n\n return sum(numbers[start_idx:end_idx + 1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(lst, start_index, end_index):\n \"\"\"\n Returns the sum of numbers in the list within a range specified by two indices.\n \"\"\"\n return sum(lst[start_index:end_index + 1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(lst, start, end):\n \"\"\"\n This function returns the sum of numbers in a list within a range specified by two indices.\n\n Parameters:\n lst (list): The list of numbers.\n start (int): The starting index (inclusive).\n end (int): The ending index (inclusive).\n\n Returns:\n int: The sum of numbers within the specified range.\n \"\"\"\n return sum(lst[start:end+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(numbers, start_idx, end_idx):\n \"\"\"\n Find the sum of numbers in a list within a range specified by two indices.\n\n Parameters:\n numbers (list): List of integers.\n start_idx (int): Start index of the range (inclusive).\n end_idx (int): End index of the range (inclusive).\n\n Returns:\n int: Sum of numbers within the specified range.\n \"\"\"\n if not numbers or start_idx < 0 or end_idx >= len(numbers) or start_idx > end_idx:\n return 0\n\n return sum(numbers[start_idx:end_idx + 1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(nums, start_idx, end_idx):\n \"\"\"\n Function to find the sum of numbers in a list within a range specified by two indices.\n\n Parameters:\n nums (list): List of numbers\n start_idx (int): Starting index\n end_idx (int): Ending index\n\n Returns:\n int: Sum of numbers in the specified range\n \"\"\"\n return sum(nums[start_idx:end_idx + 1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(lst, start_idx, end_idx):\n \"\"\"\n This function takes a list of numbers and two indices,\n and returns the sum of the numbers in the list within the range specified by the two indices (inclusive).\n \"\"\"\n return sum(lst[start_idx:end_idx + 1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(numbers, start_index, end_index):\n # Extract the portion of the list within the specified range\n sub_list = numbers[start_index:end_index + 1]\n\n # Sum the numbers in the sub_list\n return sum(sub_list)", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(lst, start_index, end_index):\n \"\"\"\n Function to find the sum of numbers in a list within a range specified by two indices.\n\n :param lst: List of numbers\n :param start_index: Start index of the range (inclusive)\n :param end_index: End index of the range (inclusive)\n :return: Sum of numbers within the specified range\n \"\"\"\n return sum(lst[start_index:end_index + 1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(lst, start_idx, end_idx):\n # Ensure the indices are within the range of the list\n if start_idx < 0 or end_idx >= len(lst) or start_idx >= len(lst):\n raise ValueError(\"Indices are out of bounds.\")\n\n # Calculate the sum within the specified range\n return sum(lst[start_idx:end_idx + 1])", "matching_cluster_idx": 7}]}, "Mbpp/226": {"dps": 95.23255813953489, "dps_norm": 87.14285714285714, "pass@1": 98.0, "profiled": [{"solution": "def odd_values_string(input_string):\n \"\"\"\n Remove characters which have odd index values from the given string.\n\n Parameters:\n input_string (str): The input string.\n\n Returns:\n str: A new string with characters at odd indexes removed.\n \"\"\"\n # Using list comprehension to keep only characters at even indexes\n return ''.join(input_string[i] for i in range(len(input_string)) if i % 2 == 0)", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(s):\n # Using a list comprehension to filter out characters at even indexes\n return ''.join(s[i] for i in range(len(s)) if i % 2 == 0)", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(s):\n \"\"\"\n Remove the characters which have odd index values of a given string.\n\n Parameters:\n s (str): The input string\n\n Returns:\n str: The string with characters at odd indices removed\n \"\"\"\n return s[::2]", "matching_cluster_idx": 6}, {"solution": "def odd_values_string(input_str):\n # Using list comprehension to include only characters with odd indices\n result = input_str[::2]\n return result", "matching_cluster_idx": 6}, {"solution": "def odd_values_string(s: str) -> str:\n return s[::2]", "matching_cluster_idx": 6}, {"solution": "def odd_values_string(input_string):\n \"\"\"\n This function removes the characters which have odd index values of a given string.\n\n Parameters:\n input_string (str): The input string from which to remove characters.\n\n Returns:\n str: The modified string with characters at odd indices removed.\n \"\"\"\n # Use a list comprehension to create a new string with characters at even indices\n result = ''.join(input_string[i] for i in range(len(input_string)) if i % 2 == 0)\n return result", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(input_string):\n \"\"\"\n This function removes the characters which have odd index values of a given string.\n\n Parameters:\n input_string (str): The input string from which characters at odd indices will be removed.\n\n Returns:\n str: The resulting string after removing characters at odd indices.\n \"\"\"\n return input_string[::2]", "matching_cluster_idx": 6}, {"solution": "def odd_values_string(input_string):\n \"\"\"\n Remove characters which have odd index values of a given string.\n\n Parameters:\n input_string (str): The input string from which characters are to be removed.\n\n Returns:\n str: The string after removing characters at odd indexes.\n \"\"\"\n # Create a new string including only characters at even indexes\n result = input_string[::2]\n return result", "matching_cluster_idx": 6}, {"solution": "def odd_values_string(s):\n return s[::2]", "matching_cluster_idx": 6}, {"solution": "def odd_values_string(input_string):\n return input_string[::2]", "matching_cluster_idx": 6}, {"solution": "def odd_values_string(s):\n return s[::2]", "matching_cluster_idx": 6}, {"solution": "def odd_values_string(s):\n return s[::2]", "matching_cluster_idx": 6}, {"solution": "def odd_values_string(input_string):\n return input_string[::2]", "matching_cluster_idx": 6}, {"solution": "def odd_values_string(s):\n return s[::2]", "matching_cluster_idx": 6}, {"solution": "def odd_values_string(input_string):\n return input_string[::2]", "matching_cluster_idx": 6}, {"solution": "def odd_values_string(input_string):\n \"\"\"\n This function removes the characters which have odd index values of a given string.\n\n :param input_string: The original string\n :return: A new string with characters at odd indices removed\n \"\"\"\n return input_string[::2]", "matching_cluster_idx": 6}, {"solution": "def odd_values_string(input_string):\n # Extract characters at even indices (0-based indexing)\n return input_string[::2]", "matching_cluster_idx": 6}, {"solution": "def odd_values_string(s):\n \"\"\"Remove characters with odd indices from the string.\"\"\"\n return s[::2]", "matching_cluster_idx": 6}, {"solution": "def odd_values_string(s):\n return s[::2]", "matching_cluster_idx": 6}, {"solution": "def odd_values_string(input_string):\n return input_string[::2]", "matching_cluster_idx": 6}]}, "Mbpp/230": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def replace_blank(input_string, char):\n \"\"\"\n Function to replace blank spaces in a string with a specified character.\n\n Args:\n input_string (str): The original string.\n char (str): The character to replace blank spaces with.\n\n Returns:\n str: The modified string with blank spaces replaced by the specified character.\n \"\"\"\n return input_string.replace(' ', char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(s, char):\n return s.replace(' ', char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(s, char):\n \"\"\"\n Replaces blank spaces in the string 's' with the character 'char'.\n\n Args:\n s (str): The original string.\n char (str): The character to replace blank spaces with.\n\n Returns:\n str: The modified string with blank spaces replaced.\n \"\"\"\n return s.replace(' ', char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(s, char):\n return s.replace(' ', char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string, replacement_char):\n \"\"\"\n This function takes a string and a character, and replaces blank spaces in the string with the given character.\n\n Args:\n input_string (str): The original string.\n replacement_char (str): The character to replace blank spaces with.\n\n Returns:\n str: The modified string with blank spaces replaced by the character.\n \"\"\"\n return input_string.replace(' ', replacement_char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(string, char):\n return string.replace(' ', char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(s, char):\n \"\"\"\n Replaces blank spaces in the string with the given character.\n\n Parameters:\n s (str): The input string.\n char (str): The character to replace blank spaces with.\n\n Returns:\n str: The string with blank spaces replaced.\n \"\"\"\n return s.replace(' ', char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string, replacement_character):\n \"\"\"\n Replaces blank spaces in the input_string with the replacement_character.\n\n Args:\n input_string (str): The original string.\n replacement_character (str): The character to replace blank spaces with.\n\n Returns:\n str: The modified string with blank spaces replaced by the replacement_character.\n \"\"\"\n return input_string.replace(' ', replacement_character)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(s: str, char: str) -> str:\n \"\"\"\n Replaces blank spaces in the given string with the specified character.\n\n Parameters:\n s (str): The input string.\n char (str): The character to replace blank spaces with.\n\n Returns:\n str: The modified string with blank spaces replaced by the character.\n \"\"\"\n return s.replace(\" \", char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string, char):\n return input_string.replace(' ', char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string, replacement_char):\n \"\"\"\n Replaces blank spaces in the string with the given character and returns the modified string.\n\n :param input_string: The original string to modify.\n :param replacement_char: The character to replace blank spaces with.\n :return: The modified string with blank spaces replaced.\n \"\"\"\n return input_string.replace(' ', replacement_char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(s, char):\n return s.replace(' ', char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string, char):\n \"\"\"\n This function takes in a string and a character, replaces blank spaces in the string with the character, and returns the string.\n \"\"\"\n return input_string.replace(' ', char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string, character):\n \"\"\"\n Replaces blank spaces in the given string with the specified character.\n\n :param input_string: The string in which blank spaces will be replaced.\n :param character: The character that will replace the blank spaces.\n :return: The modified string with blank spaces replaced by the specified character.\n \"\"\"\n return input_string.replace(' ', character)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(string, char):\n \"\"\"\n This function takes in a string and a character, replaces blank spaces in the string with the character, and returns the string.\n \"\"\"\n return string.replace(' ', char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string, char):\n \"\"\"\n Replaces blank spaces in the input_string with the specified character.\n\n Parameters:\n input_string (str): The original string to be modified.\n char (str): The character to replace blank spaces with.\n\n Returns:\n str: The modified string with blank spaces replaced by the specified character.\n \"\"\"\n return input_string.replace(' ', char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(s, char):\n \"\"\"\n This function takes in a string and a character, and replaces blank spaces in the string with the character.\n \"\"\"\n return s.replace(' ', char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(s, char):\n return s.replace(\" \", char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string, char):\n return input_string.replace(' ', char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(s, c):\n \"\"\"\n Takes in a string and character, replaces blank spaces in the string with the character, and returns the string.\n \"\"\"\n return s.replace(\" \", c)", "matching_cluster_idx": 7}]}, "Mbpp/239": {"dps": 74.82758620689656, "dps_norm": 77.0, "pass@1": 56.0, "profiled": [{"solution": "def get_total_number_of_sequences(m, n):\n # Creating a DP table initialized with zeros\n dp = [[0 for _ in range(m + 1)] for _ in range(n + 1)]\n\n # Base case: sequences of length 1 can be formed by any integer from 1 to m\n for i in range(1, m + 1):\n dp[1][i] = 1\n\n # Populate the DP table based on the recurrence relation\n for length in range(2, n + 1):\n for last_element in range(1, m + 1):\n # We need to find the range of valid previous elements\n # such that they are <= m and >= last_element // 2\n for prev_element in range(1, last_element):\n if prev_element * 2 <= last_element:\n dp[length][last_element] += dp[length - 1][prev_element]\n\n # Sum all the valid sequences of length n\n total_sequences = sum(dp[n])\n\n return total_sequences", "matching_cluster_idx": 6}, {"solution": "def get_total_number_of_sequences(m, n):\n # Base case: only one sequence of length 1 (all integers from 1 to m)\n if n == 1:\n return m\n\n # Initialize DP table\n dp = [[0 for _ in range(m + 1)] for _ in range(n + 1)]\n\n # Base case: there is one sequence of length 1 for each number from 1 to m\n for i in range(1, m + 1):\n dp[1][i] = 1\n\n # Fill DP table\n for seq_len in range(2, n + 1):\n for current in range(1, m + 1):\n for prev in range(1, current // 2 + 1):\n dp[seq_len][current] += dp[seq_len - 1][prev]\n\n # Sum up all possible sequences of length n\n total_sequences = sum(dp[n][1:])\n\n return total_sequences", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n # Initialize a 2D array to store the number of valid sequences of length n that end with a specific number\n dp = [[0] * (m + 1) for _ in range(n + 1)]\n\n # Base case: sequences of length 1 can be any number from 1 to m\n for i in range(1, m + 1):\n dp[1][i] = 1\n\n # Fill the dp table\n for length in range(2, n + 1):\n for end_number in range(1, m + 1):\n for prev_number in range(1, end_number // 2 + 1):\n dp[length][end_number] += dp[length - 1][prev_number]\n\n # Sum up the valid sequences of length n that end with any number from 1 to m\n total_sequences = sum(dp[n][1:])\n return total_sequences", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n # Create a 2D DP array where dp[i][j] is the number of sequences of length j\n # ending in the integer i.\n dp = [[0] * (n + 1) for _ in range(m + 1)]\n\n # There is exactly one sequence of length 1 ending in each number from 1 to m.\n for i in range(1, m + 1):\n dp[i][1] = 1\n\n # Fill the DP table.\n for length in range(2, n + 1):\n for end in range(1, m + 1):\n # Sum contributions from valid previous elements\n for prev in range(1, (end // 2) + 1):\n dp[end][length] += dp[prev][length - 1]\n\n # Sum sequences of the correct length with any ending integer.\n total_sequences = sum(dp[i][n] for i in range(1, m + 1))\n return total_sequences", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n # Base case when n is zero, there is only one sequence (the empty sequence)\n if n == 0:\n return 1\n # Base case when n is one, there are m sequences (1 to m)\n elif n == 1:\n return m\n # Use memoization to store the number of sequences for each (n, last_element) pair\n memo = {}\n\n def count_sequences(n, last_element):\n if (n, last_element) in memo:\n return memo[(n, last_element)]\n if n == 0:\n return 1\n if last_element == 0:\n sum_sequences = 0\n for i in range(1, m + 1):\n sum_sequences += count_sequences(n - 1, i)\n memo[(n, last_element)] = sum_sequences\n return sum_sequences\n\n sum_sequences = 0\n for i in range(last_element * 2, m + 1):\n sum_sequences += count_sequences(n - 1, i)\n memo[(n, last_element)] = sum_sequences\n return sum_sequences\n\n return count_sequences(n, 0)", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n if n == 1:\n return m # There are m possibilities for sequences of length 1\n\n dp = [[0] * (n + 1) for _ in range(m + 1)]\n\n # Base case: There is exactly 1 way to create a sequence of length 1 for each valid value 1 to m\n for i in range(1, m + 1):\n dp[i][1] = 1\n\n # Fill the dp table\n for len_seq in range(2, n + 1):\n for end_val in range(1, m + 1):\n for prev_val in range(1, end_val // 2 + 1):\n dp[end_val][len_seq] += dp[prev_val][len_seq - 1]\n\n # Sum up all sequences of length n\n total_sequences = sum(dp[i][n] for i in range(1, m + 1))\n return total_sequences", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n dp = [[0] * (m + 1) for _ in range(n + 1)]\n\n for j in range(1, m + 1):\n dp[1][j] = 1\n\n for i in range(2, n + 1):\n for j in range(1, m + 1):\n for k in range(1, j // 2 + 1):\n dp[i][j] += dp[i - 1][k]\n\n total = sum(dp[n])\n return total", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n if m < 1 or n < 1:\n return 0\n\n # Initialize a DP array to store the number of sequences of each length up to n\n dp = [[0] * (m + 1) for _ in range(n + 1)]\n\n # Base case: a single element sequence of length 1 can be any number from 1 to m\n for i in range(1, m + 1):\n dp[1][i] = 1\n\n # Fill the DP table\n for length in range(2, n + 1):\n for curr in range(1, m + 1):\n # Sum up all sequences that end in 'curr'\n for prev in range(1, curr // 2 + 1):\n dp[length][curr] += dp[length - 1][prev]\n\n # Sum up all sequences of length n\n total_sequences = sum(dp[n])\n\n return total_sequences", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n \"\"\"\n This function takes in positive integers m and n and finds the number of possible sequences of length n,\n such that each element is a positive integer and is greater than or equal to twice the previous element but\n less than or equal to m.\n\n :param m: The upper limit for the elements in the sequence\n :param n: The length of the sequence\n :return: The number of possible sequences\n \"\"\"\n if n == 0:\n return 0\n\n # This will store the count of sequences with i as the last element\n dp = [0] * (m + 1)\n\n # Base case for sequences of length 1\n for i in range(1, m + 1):\n dp[i] = 1\n\n for length in range(2, n + 1):\n new_dp = [0] * (m + 1)\n for current in range(1, m + 1):\n for prev in range(1, current // 2 + 1):\n new_dp[current] += dp[prev]\n dp = new_dp\n\n return sum(dp)", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n # Initializing the memoization table\n dp = [[0 for _ in range(n+1)] for _ in range(m+1)]\n\n # Base cases: sequences of length 1\n for i in range(1, m+1):\n dp[i][1] = 1\n\n # Building the dp table\n for length in range(2, n+1):\n for i in range(1, m+1):\n for j in range(1, i//2 + 1):\n dp[i][length] += dp[j][length-1]\n\n # The result will be the sum of all sequences of length n\n total = 0\n for i in range(1, m+1):\n total += dp[i][n]\n\n return total", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n # Create a dynamic programming table to store the number of valid sequences\n dp = [0] * (m + 1)\n\n # Initialize the base case: sequences of length 1\n for i in range(1, m + 1):\n dp[i] = 1\n\n # Build the table for sequences of length 2 to n\n for length in range(2, n + 1):\n new_dp = [0] * (m + 1)\n for i in range(1, m + 1):\n for j in range(1, i // 2 + 1):\n new_dp[i] += dp[j]\n dp = new_dp\n\n # Sum up the total number of valid sequences of length n\n total_sequences = sum(dp[1:m+1])\n\n return total_sequences", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n # Memoization table to store previously computed results\n memo = {}\n\n def dp(current, prev):\n # Base case: if the sequence length is reached\n if current == n:\n return 1\n\n # If the result is already computed, return it\n if (current, prev) in memo:\n return memo[(current, prev)]\n\n count = 0\n\n # Try every possible next number in the sequence\n for next_num in range(2 * prev, m + 1):\n count += dp(current + 1, next_num)\n\n # Memoize the result\n memo[(current, prev)] = count\n return count\n\n # Initiate the process with the first element in the sequence\n total_count = 0\n for first_num in range(1, m + 1):\n total_count += dp(1, first_num)\n\n return total_count", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n # A DP approach: dp[i][j] will contain the number of sequences of length i ending with j\n dp = [[0] * (m + 1) for _ in range(n + 1)]\n\n # Base case: There's one sequence of length 1 for every number up to m\n for i in range(1, m + 1):\n dp[1][i] = 1\n\n # Fill the DP table\n for i in range(2, n + 1):\n for j in range(1, m + 1):\n for k in range(1, j // 2 + 1):\n dp[i][j] += dp[i - 1][k]\n\n # Sum up all sequences of length n\n total_sequences = sum(dp[n])\n\n return total_sequences", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n # Create a DP table where dp[i][j] means the number of sequences of length j with the last element being i\n dp = [[0] * (n + 1) for _ in range(m + 1)]\n\n # Initialize the base case: there is 1 sequence of length 1 for every valid i (i > 0)\n for i in range(1, m + 1):\n dp[i][1] = 1\n\n # Fill the DP table\n for length in range(2, n + 1):\n for i in range(1, m + 1):\n # Accumulate all possible sequences ending with i where previous element j is <= i // 2\n for j in range(1, (i // 2) + 1):\n dp[i][length] += dp[j][length - 1]\n\n # Sum up all sequences of length n\n total_sequences = sum(dp[i][n] for i in range(1, m + 1))\n\n return total_sequences", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n \"\"\"\n Finds the number of possible sequences of length n, such that each element is a positive integer and\n is greater than or equal to twice the previous element but less than or equal to m.\n \"\"\"\n def count_sequences(current, previous, length, memo):\n if length == 0:\n return 1\n\n if (current, length) in memo:\n return memo[(current, length)]\n\n count = 0\n for next_element in range(2 * previous, m + 1):\n count += count_sequences(next_element, next_element, length - 1, memo)\n\n memo[(current, length)] = count\n return count\n\n # Initialize memoization dictionary\n memo = {}\n\n # Start the recursion with the first element as each possible value from 1 to m\n total_count = 0\n for first_element in range(1, m + 1):\n total_count += count_sequences(first_element, first_element, n - 1, memo)\n\n return total_count", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n \"\"\"\n This function calculates the number of possible sequences of length n\n where each element is a positive integer, is greater than or equal to\n twice the previous element but less than or equal to m.\n\n Parameters:\n m (int): The upper bound of each element in the sequence.\n n (int): The length of the sequence.\n\n Returns:\n int: The number of possible sequences.\n \"\"\"\n # DP array initialization\n dp = [[0 for _ in range(m+1)] for _ in range(n+1)]\n\n # For sequences of length 1, we can have any element from 1 to m\n for j in range(1, m+1):\n dp[1][j] = 1\n\n # Populate the DP table\n for i in range(2, n+1):\n for j in range(1, m+1):\n # Sum the counts of sequences ending with each possible previous element\n for k in range(1, (j // 2) + 1):\n dp[i][j] += dp[i-1][k]\n\n # The total number of sequences of length n is the sum of sequences ending with each possible last element\n total_sequences = sum(dp[n][1:])\n return total_sequences", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n \"\"\"\n This function calculates the number of possible sequences of length n, where each element is a positive integer\n and is greater than or equal to twice the previous element but less than or equal to m.\n\n :param m: maximum value an element can take (inclusive)\n :param n: length of the sequence\n :return: number of possible sequences\n \"\"\"\n def count_sequences(current, prev, length):\n if length == 0:\n return 1\n total = 0\n for i in range(2 * prev, m + 1):\n total += count_sequences(i, i, length - 1)\n return total\n\n # Start counting sequences from 1 to m\n total_sequences = 0\n for i in range(1, m + 1):\n total_sequences += count_sequences(i, i, n - 1)\n\n return total_sequences", "matching_cluster_idx": 5}, {"solution": "def get_total_number_of_sequences(m, n):\n \"\"\"\n Finds the number of possible sequences of length n, such that each element\n is a positive integer and is greater than or equal to twice the previous\n element but less than or equal to m.\n\n Parameters:\n m (int): The maximum value for any element in the sequence.\n n (int): The length of the sequence.\n\n Returns:\n int: The total number of possible sequences.\n \"\"\"\n # Edge case: when n is 0, there is exactly one sequence: the empty sequence\n if n == 0:\n return 1\n\n # Initialize the DP array where dp[i][j] will store the number of sequences\n # of length i that end with j\n dp = [[0] * (m + 1) for _ in range(n + 1)]\n\n # The number of sequences of length 1 ending with any i (1 <= i <= m) is 1\n for i in range(1, m + 1):\n dp[1][i] = 1\n\n # Fill the DP table\n for length in range(2, n + 1):\n for end in range(1, m + 1):\n for prev in range(1, end // 2 + 1):\n dp[length][end] += dp[length - 1][prev]\n\n # Sum up the sequences of length n\n total_sequences = sum(dp[n])\n\n return total_sequences", "matching_cluster_idx": 7}, {"solution": "def get_total_number_of_sequences(m, n):\n if n == 0:\n return 0\n\n # Initialize a list to store the number of sequences for each value from 1 to m\n dp = [[0]*m for _ in range(n)]\n\n # For sequences of length 1, each number from 1 to m is a valid sequence\n for i in range(m):\n dp[0][i] = 1\n\n # Build up sequences of greater length\n for i in range(1, n):\n for j in range(1, m+1):\n for k in range(1, j//2+1):\n dp[i][j-1] += dp[i-1][k-1]\n\n # Sum the number of sequences of length n\n total = sum(dp[-1])\n return total", "matching_cluster_idx": 6}, {"solution": "def get_total_number_of_sequences(m, n):\n def count_sequences(current, length, max_val):\n if length == n:\n return 1\n count = 0\n for next_val in range(2 * current, max_val + 1):\n count += count_sequences(next_val, length + 1, max_val)\n return count\n\n total_count = 0\n for start in range(1, m + 1):\n total_count += count_sequences(start, 1, m)\n\n return total_count", "matching_cluster_idx": 5}]}, "Mbpp/240": {"dps": 70.54878048780489, "dps_norm": 81.11111111111111, "pass@1": 93.0, "profiled": [{"solution": "def replace_list(list1, list2):\n \"\"\"\n This function takes in two lists. It replaces the last element of the first list with\n the elements of the second list.\n\n Parameters:\n list1 (list): The first list.\n list2 (list): The second list.\n\n Returns:\n list: The modified first list with the last element replaced by the elements of the second list.\n \"\"\"\n if not list1:\n return list2\n\n # Remove the last element from the first list\n list1.pop()\n # Extend the first list with the elements of the second list\n list1.extend(list2)\n\n return list1", "matching_cluster_idx": 8}, {"solution": "def replace_list(lst1, lst2):\n # Remove the last element of the first list\n lst1.pop()\n # Extend the first list with the elements of the second list\n lst1.extend(lst2)\n return lst1", "matching_cluster_idx": 8}, {"solution": "def replace_list(list1, list2):\n # Remove the last element of the first list\n list1.pop()\n # Extend the first list with elements of the second list\n list1.extend(list2)\n return list1", "matching_cluster_idx": 8}, {"solution": "def replace_list(lst1, lst2):\n # Replace the last element of lst1 with the elements of lst2\n lst1[-1:] = lst2\n return lst1", "matching_cluster_idx": 7}, {"solution": "def replace_list(lst1, lst2):\n \"\"\"\n This function takes in two lists and replaces the last element of the first list\n with the elements of the second list.\n \"\"\"\n if not lst1:\n return lst2\n lst1[-1:] = lst2\n return lst1", "matching_cluster_idx": 7}, {"solution": "def replace_list(first_list, second_list):\n \"\"\"\n Replaces the last element of the first list with the elements of the second list.\n\n :param first_list: List of elements\n :param second_list: List of elements to replace the last element of the first list\n :return: Modified list with replaced elements\n \"\"\"\n if not first_list:\n return second_list\n\n # Replace the last element of the first list with the elements of the second list\n return first_list[:-1] + second_list", "matching_cluster_idx": 5}, {"solution": "def replace_list(list1, list2):\n \"\"\"\n Replaces the last element of the first list with the elements of the second list.\n\n Parameters:\n list1 (list): The first list.\n list2 (list): The second list whose elements will replace the last element of the first list.\n\n Returns:\n list: A new list with the last element of the first list replaced by the elements of the second list.\n \"\"\"\n if not list1:\n return list2\n return list1[:-1] + list2", "matching_cluster_idx": 5}, {"solution": "def replace_list(list1, list2):\n \"\"\"\n This function takes in two lists and replaces the last element of the first list with the elements of the second list.\n \"\"\"\n if list1:\n list1[-1:] = list2\n else:\n list1.extend(list2)\n return list1", "matching_cluster_idx": 7}, {"solution": "def replace_list(list1, list2):\n \"\"\"\n Replaces the last element of the first list with the elements of the second list.\n\n Parameters:\n list1 (list): The first list.\n list2 (list): The second list.\n\n Returns:\n list: The modified first list.\n \"\"\"\n if list1:\n list1[-1:] = list2\n return list1", "matching_cluster_idx": 7}, {"solution": "def replace_list(list1, list2):\n \"\"\"\n Replaces the last element of the first list with the elements of the second list.\n \"\"\"\n if list1:\n list1[-1:] = list2\n else:\n list1 = list2[:]\n return list1", "matching_cluster_idx": 7}, {"solution": "def replace_list(list1, list2):\n \"\"\"\n Replaces the last element of the first list with the elements of the second list.\n\n Args:\n list1 (list): The first list.\n list2 (list): The second list.\n\n Returns:\n list: The modified list.\n \"\"\"\n # Check if list1 is not empty to avoid errors\n if list1:\n list1[-1:] = list2\n return list1", "matching_cluster_idx": 7}, {"solution": "def replace_list(list1, list2):\n return list1[:-1] + list2", "matching_cluster_idx": 5}, {"solution": "def replace_list(list1, list2):\n # Remove the last element of the first list\n list1 = list1[:-1]\n # Append the elements of the second list to the first list\n list1.extend(list2)\n return list1", "matching_cluster_idx": 6}, {"solution": "def replace_list(lst1, lst2):\n \"\"\"\n This function replaces the last element of the first list with the elements of the second list.\n\n Parameters:\n lst1 (list): The first list\n lst2 (list): The second list\n\n Returns:\n list: The modified list with the last element of the first list replaced by the elements of the second list\n \"\"\"\n if not lst1:\n return lst2 # If the first list is empty, return the second list\n return lst1[:-1] + lst2", "matching_cluster_idx": 5}, {"solution": "def replace_list(list1, list2):\n \"\"\"\n Replaces the last element of the first list with the elements of the second list.\n\n Args:\n list1 (list): The first list.\n list2 (list): The second list.\n\n Returns:\n list: The modified list1.\n \"\"\"\n if list1:\n # Replace the last element of list1 with elements of list2\n list1[-1:] = list2\n else:\n # If list1 is empty, just return list2\n list1 = list2\n return list1", "matching_cluster_idx": 7}, {"solution": "def replace_list(list1, list2):\n if not list1:\n return list2\n return list1[:-1] + list2", "matching_cluster_idx": 5}, {"solution": "def replace_list(list1, list2):\n return list1[:-1] + list2", "matching_cluster_idx": 5}, {"solution": "def replace_list(lst1, lst2):\n return lst1[:-1] + lst2", "matching_cluster_idx": 5}, {"solution": "def replace_list(list1, list2):\n # Replace the last element of the first list with the elements of the second list\n list1[-1:] = list2\n return list1", "matching_cluster_idx": 7}, {"solution": "def replace_list(list1, list2):\n \"\"\"\n Takes in two lists and replaces the last element of the first list with the elements of the second list.\n\n Parameters:\n list1 (list): The first list.\n list2 (list): The second list.\n\n Returns:\n list: A new list with the last element of list1 replaced by the elements of list2.\n \"\"\"\n if not list1: # Check if list1 is empty\n return list2 # If list1 is empty, return list2\n\n return list1[:-1] + list2 # Replace the last element of list1 with elements of list2", "matching_cluster_idx": 5}]}, "Mbpp/251": {"dps": 83.96551724137932, "dps_norm": 75.55555555555554, "pass@1": 58.0, "profiled": [{"solution": "def insert_element(lst, elem):\n \"\"\"\n Takes a list and an element, and inserts the element before each element in the list.\n Returns the resulting list.\n\n :param lst: The original list of elements\n :param elem: The element to be inserted before each element in the list\n :return: A new list with the element inserted before each element in the original list\n \"\"\"\n result = []\n for item in lst:\n result.append(elem)\n result.append(item)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(input_list, element):\n \"\"\"\n Takes a list and an element, and inserts the element before each element in the list.\n \"\"\"\n result = []\n for item in input_list:\n result.append(element)\n result.append(item)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n \"\"\"\n This function takes a list and an element, then inserts the element before each element in the list,\n and returns the resulting list.\n \"\"\"\n result = []\n for item in lst:\n result.append(element)\n result.append(item)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, elem):\n result = []\n for item in lst:\n result.append(elem)\n result.append(item)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, elem):\n \"\"\"\n This function inserts the element `elem` before each element in the list `lst`\n and returns the resulting list.\n \"\"\"\n result = []\n for item in lst:\n result.append(elem)\n result.append(item)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n result = []\n for item in lst:\n result.append(element)\n result.append(item)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n \"\"\"\n This function takes in a list and an element, and inserts the element before each element in the list.\n\n :param lst: list of elements\n :param element: element to insert\n :return: new list with the element inserted before each element\n \"\"\"\n new_lst = []\n for item in lst:\n new_lst.append(element)\n new_lst.append(item)\n return new_lst", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, elem):\n \"\"\"\n This function takes in a list and an element, and inserts the element before each element in the list.\n\n :param lst: List of elements\n :param elem: Element to be inserted before each element in the list\n :return: List with the element inserted before each element in the list\n \"\"\"\n return [elem if i % 2 == 0 else lst[i // 2] for i in range(len(lst) * 2)]", "matching_cluster_idx": 4}, {"solution": "def insert_element(lst, elem):\n result = []\n for item in lst:\n result.append(elem)\n result.append(item)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n \"\"\"\n Inserts the given element before each element in the list and returns the resulting list.\n\n Parameters:\n lst (list): The list of elements.\n element (any): The element to insert before each element in the list.\n\n Returns:\n list: The resulting list with the element inserted before each element.\n \"\"\"\n result = []\n for item in lst:\n result.append(element)\n result.append(item)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(input_list, element):\n return [element if i % 2 == 0 else input_list[i // 2] for i in range(2 * len(input_list))]", "matching_cluster_idx": 4}, {"solution": "def insert_element(lst, elem):\n \"\"\"\n This function inserts the given element before each element in the list and returns the resulting list.\n\n :param lst: List of elements\n :param elem: Element to be inserted before each element in the list\n :return: New list with element inserted before each element in the original list\n \"\"\"\n result = []\n for item in lst:\n result.append(elem)\n result.append(item)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n # Create a new list to hold the result\n result = []\n # Iterate through the input list and insert the element before each existing element\n for item in lst:\n result.append(element)\n result.append(item)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n \"\"\"\n Inserts the element before each element in the list.\n\n Parameters:\n lst (list): The input list of elements.\n element (any): The element to be inserted before each element in the list.\n\n Returns:\n list: A new list with the element inserted before each element in the original list.\n \"\"\"\n result = []\n for item in lst:\n result.append(element)\n result.append(item)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n result = []\n for item in lst:\n result.append(element)\n result.append(item)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n \"\"\"\n Inserts the given element before each element in the list.\n\n Args:\n lst (list): The input list.\n element (any): The element to be inserted before each item in the list.\n\n Returns:\n list: The resulting list with the element inserted before each item.\n \"\"\"\n result = []\n for item in lst:\n result.append(element)\n result.append(item)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, elem):\n result = []\n for item in lst:\n result.append(elem)\n result.append(item)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n # Create an empty list to hold the resulting elements\n result = []\n # Iterate over the original list\n for item in lst:\n # Append the element and the current item to the result list\n result.append(element)\n result.append(item)\n # Return the resulting list\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, elem):\n \"\"\"\n This function inserts the given element before each element in the list and returns the resulting list.\n\n Args:\n lst (list): The original list of elements.\n elem (any): The element to be inserted before each element in the list.\n\n Returns:\n list: The resulting list with the element inserted before each element in the original list.\n \"\"\"\n result = []\n for item in lst:\n result.append(elem)\n result.append(item)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, elem):\n result = []\n for item in lst:\n result.append(elem)\n result.append(item)\n return result", "matching_cluster_idx": 6}]}, "Mbpp/256": {"dps": 77.07762557077625, "dps_norm": 72.35294117647058, "pass@1": 60.0, "profiled": [{"solution": "def count_Primes_nums(n):\n \"\"\"\n Given a non-negative number, this function returns the count of prime numbers less than the given number.\n \"\"\"\n\n # Edge case: if n is less than 2, there are no prime numbers less than n\n if n < 2:\n return 0\n\n # Initialize a list to track prime status of numbers\n is_prime = [True] * n\n is_prime[0] = is_prime[1] = False # 0 and 1 are not prime numbers\n\n # Use the Sieve of Eratosthenes algorithm to find all primes less than n\n p = 2\n while p * p < n:\n if is_prime[p]:\n for multiple in range(p * p, n, p):\n is_prime[multiple] = False\n p += 1\n\n # Count the number of primes found\n return sum(is_prime)", "matching_cluster_idx": 14}, {"solution": "def is_prime(num):\n if num < 2:\n return False\n for i in range(2, int(num ** 0.5) + 1):\n if num % i == 0:\n return False\n return True\ndef count_Primes_nums(n):\n count = 0\n for i in range(n):\n if is_prime(i):\n count += 1\n return count", "matching_cluster_idx": 8}, {"solution": "def is_prime(num):\n if num <= 1:\n return False\n if num <= 3:\n return True\n if num % 2 == 0 or num % 3 == 0:\n return False\n i = 5\n while i * i <= num:\n if num % i == 0 or num % (i + 2) == 0:\n return False\n i += 6\n return True\ndef count_Primes_nums(n):\n count = 0\n for i in range(n):\n if is_prime(i):\n count += 1\n return count", "matching_cluster_idx": 10}, {"solution": "def count_Primes_nums(n):\n if n < 2:\n return 0\n\n primes = [True for _ in range(n)]\n primes[0], primes[1] = False, False\n\n for i in range(2, int(n**0.5) + 1):\n if primes[i]:\n for j in range(i*i, n, i):\n primes[j] = False\n\n return sum(primes)", "matching_cluster_idx": 13}, {"solution": "def count_Primes_nums(n):\n def is_prime(num):\n if num <= 1:\n return False\n if num <= 3:\n return True\n if num % 2 == 0 or num % 3 == 0:\n return False\n i = 5\n while (i * i) <= num:\n if num % i == 0 or num % (i + 2) == 0:\n return False\n i += 6\n return True\n\n count = 0\n for i in range(2, n):\n if is_prime(i):\n count += 1\n return count", "matching_cluster_idx": 10}, {"solution": "def is_prime(n):\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True\ndef count_Primes_nums(n):\n if n <= 2:\n return 0\n count = 0\n for num in range(2, n):\n if is_prime(num):\n count += 1\n return count", "matching_cluster_idx": 10}, {"solution": "def is_prime(n):\n \"\"\"Check if a number is a prime number.\"\"\"\n if n <= 1:\n return False\n if n == 2:\n return True\n if n % 2 == 0:\n return False\n for i in range(3, int(n**0.5) + 1, 2):\n if n % i == 0:\n return False\n return True\ndef count_Primes_nums(n):\n \"\"\"Count the number of prime numbers less than the given non-negative number n.\"\"\"\n primes_count = 0\n for i in range(n):\n if is_prime(i):\n primes_count += 1\n return primes_count", "matching_cluster_idx": 10}, {"solution": "def is_prime(n):\n \"\"\"Helper function to check if a number is prime.\"\"\"\n if n <= 1:\n return False\n if n == 2:\n return True\n if n % 2 == 0:\n return False\n for i in range(3, int(n**0.5) + 1, 2):\n if n % i == 0:\n return False\n return True\ndef count_Primes_nums(n):\n \"\"\"Function to count prime numbers less than n.\"\"\"\n count = 0\n for i in range(n):\n if is_prime(i):\n count += 1\n return count", "matching_cluster_idx": 10}, {"solution": "def count_Primes_nums(n):\n if n < 2:\n return 0\n\n # Create a boolean array \"is_prime[0..n-1]\" and initialize\n # all entries it as true. A value in is_prime[i] will\n # finally be false if i is Not a prime, else true bool val.\n is_prime = [True for _ in range(n)]\n p = 2\n while p * p < n:\n # If is_prime[p] is not changed, then it is a prime\n if is_prime[p] == True:\n # Update all multiples of p\n for i in range(p * p, n, p):\n is_prime[i] = False\n p += 1\n\n # count all prime numbers\n prime_count = 0\n for p in range(2, n):\n if is_prime[p]:\n prime_count += 1\n\n return prime_count", "matching_cluster_idx": 12}, {"solution": "def count_Primes_nums(n):\n if n < 2:\n return 0\n\n primes = [True] * n\n primes[0] = primes[1] = False # 0 and 1 are not prime numbers\n\n p = 2\n while (p * p < n):\n if primes[p] == True:\n for i in range(p * p, n, p):\n primes[i] = False\n p += 1\n\n return sum(primes)", "matching_cluster_idx": 14}, {"solution": "def is_prime(n):\n if n < 2:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True\ndef count_Primes_nums(n):\n count = 0\n for i in range(n):\n if is_prime(i):\n count += 1\n return count", "matching_cluster_idx": 8}, {"solution": "def count_Primes_nums(n):\n \"\"\"\n Takes in a non-negative number n and returns the number of prime numbers less than n.\n\n Args:\n n (int): A non-negative integer.\n\n Returns:\n int: The count of prime numbers less than n.\n \"\"\"\n if n <= 2:\n return 0\n\n # Create a boolean array \"prime[0..n]\" and initialize all entries it as true.\n # A value in prime[i] will finally be false if i is Not a prime, otherwise true.\n prime = [True for _ in range(n)]\n p = 2\n\n while p * p < n:\n # If prime[p] is not changed, then it is a prime\n if prime[p]:\n # Updating all multiples of p to not prime\n for i in range(p * p, n, p):\n prime[i] = False\n p += 1\n\n # Counting the number of prime numbers\n prime_count = sum(prime) - 2 # Subtracting 0 and 1 which are not primes\n return prime_count", "matching_cluster_idx": 13}, {"solution": "def count_Primes_nums(n: int) -> int:\n if n <= 2:\n return 0\n\n is_prime = [True] * n\n is_prime[0], is_prime[1] = False, False # 0 and 1 are not prime numbers\n\n for i in range(2, int(n**0.5) + 1):\n if is_prime[i]:\n for j in range(i * i, n, i):\n is_prime[j] = False\n\n return sum(is_prime)", "matching_cluster_idx": 14}, {"solution": "def count_Primes_nums(n):\n if n < 2:\n return 0\n\n primes = [True] * n\n primes[0] = primes[1] = False\n\n for i in range(2, int(n ** 0.5) + 1):\n if primes[i]:\n for j in range(i*i, n, i):\n primes[j] = False\n\n return sum(primes)", "matching_cluster_idx": 14}, {"solution": "def count_Primes_nums(n):\n \"\"\"Count the number of prime numbers less than a non-negative number n.\"\"\"\n if n <= 2:\n return 0\n\n # Initialize a boolean array to track prime status of numbers\n is_prime = [True] * n\n is_prime[0] = is_prime[1] = False # 0 and 1 are not prime numbers\n\n p = 2\n while p * p < n:\n if is_prime[p]:\n for i in range(p * p, n, p):\n is_prime[i] = False\n p += 1\n\n return sum(is_prime)", "matching_cluster_idx": 14}, {"solution": "def is_prime(n):\n if n <= 1:\n return False\n elif n <= 3:\n return True\n elif n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True\ndef count_Primes_nums(n):\n count = 0\n for num in range(n):\n if is_prime(num):\n count += 1\n return count", "matching_cluster_idx": 10}, {"solution": "def is_prime(n):\n \"\"\"Helper function to check if a number is prime.\"\"\"\n if n <= 1:\n return False\n for i in range(2, int(n ** 0.5) + 1):\n if n % i == 0:\n return False\n return True\ndef count_Primes_nums(n):\n \"\"\"Function to count the number of prime numbers less than a given non-negative number n.\"\"\"\n if n <= 0:\n return 0\n count = 0\n for i in range(2, n):\n if is_prime(i):\n count += 1\n return count", "matching_cluster_idx": 8}, {"solution": "def is_prime(n):\n if n <= 1:\n return False\n if n == 2:\n return True\n if n % 2 == 0:\n return False\n for i in range(3, int(n**0.5) + 1, 2):\n if n % i == 0:\n return False\n return True\ndef count_Primes_nums(n):\n count = 0\n for i in range(2, n):\n if is_prime(i):\n count += 1\n return count", "matching_cluster_idx": 10}, {"solution": "def is_prime(n):\n \"\"\"Helper function to check if a number is prime.\"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True\ndef count_Primes_nums(n):\n \"\"\"Function to count the number of prime numbers less than a given non-negative number.\"\"\"\n count = 0\n for i in range(n):\n if is_prime(i):\n count += 1\n return count", "matching_cluster_idx": 10}, {"solution": "def count_Primes_nums(n):\n if n < 2:\n return 0\n primes = [True] * n\n primes[0] = primes[1] = False\n for i in range(2, int(n ** 0.5) + 1):\n if primes[i]:\n for j in range(i * i, n, i):\n primes[j] = False\n return sum(primes)", "matching_cluster_idx": 14}]}, "Mbpp/265": {"dps": 76.74418604651163, "dps_norm": 86.66666666666666, "pass@1": 79.0, "profiled": [{"solution": "def list_split(input_list, n):\n # Initialize the resulting lists\n result = [[] for _ in range(n)]\n\n # Split the input list into the result lists\n for i, elem in enumerate(input_list):\n result[i % n].append(elem)\n\n return result", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n # Create an empty list of lists to hold the result\n result = [[] for _ in range(n)]\n\n # Iterate over the input list and distribute elements to the result lists\n for i, elem in enumerate(lst):\n result[i % n].append(elem)\n\n return result", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n return [lst[i::n] for i in range(n)]", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n return [lst[i::n] for i in range(n)]", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n \"\"\"\n Splits the given list 'lst' every 'n'th element and returns a list of resulting lists.\n\n Parameters:\n lst (list): The list to be split.\n n (int): The number of elements after which to split.\n\n Returns:\n list: A list of lists where each sublist is split by every nth element from the original list.\n \"\"\"\n return [lst[i::n] for i in range(n)]", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n \"\"\"\n Splits a list every nth element and returns a list of the resulting lists.\n\n Args:\n lst (list): The list to split.\n n (int): The number of elements per split.\n\n Returns:\n list: A list of lists, where each sublist contains every nth element.\n \"\"\"\n return [lst[i::n] for i in range(n)]", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n \"\"\"\n Splits the list `lst` every `n`th element and returns a list of the resulting lists.\n\n Parameters:\n lst (list): The list to be split.\n n (int): The number of elements to group.\n\n Returns:\n list: A list containing lists of elements split from the original list.\n \"\"\"\n return [lst[i::n] for i in range(n)]", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n return [lst[i::n] for i in range(n)]", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n # Create the resulting list of lists\n result = [[] for _ in range(n)]\n\n # Iterate through the input list and distribute elements to the resulting lists\n for i, value in enumerate(lst):\n result[i % n].append(value)\n\n return result", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n # Initialize an empty list to store the resulting sublists\n result = []\n\n # Iterate over the list with step n\n for i in range(n):\n # Append a new sublist containing every nth element starting from index i\n result.append(lst[i::n])\n\n return result", "matching_cluster_idx": 5}, {"solution": "def list_split(input_list, n):\n \"\"\"\n Splits a list for every nth element and returns a list of resulting lists.\n \"\"\"\n return [input_list[i::n] for i in range(n)]", "matching_cluster_idx": 5}, {"solution": "def list_split(input_list, n):\n # Calculate the number of lists we need to split the input into\n num_lists = (len(input_list) + n - 1) // n # Ceiling division\n\n # Initialize the result list\n result = [[] for _ in range(n)]\n\n # Iterate over the input list and distribute elements to the appropriate sub-lists\n for i, item in enumerate(input_list):\n result[i % n].append(item)\n\n return result", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n # Create a list to hold the resulting sublists\n result = [[] for _ in range(n)]\n # Iterate over the input list and append elements to the respective sublists\n for i in range(len(lst)):\n result[i % n].append(lst[i])\n return result", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n \"\"\"\n Splits a list for every nth element.\n\n :param lst: List of elements to be split.\n :param n: Integer, interval at which to split the list.\n :return: List of lists, each containing every nth element from the original list.\n \"\"\"\n # Initialize the result list with n empty lists\n result = [[] for _ in range(n)]\n\n # Iterate through the original list\n for i, element in enumerate(lst):\n # Determine which list the current element should be added to\n index = i % n\n result[index].append(element)\n\n return result", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n \"\"\"\n Splits a list into sublists, each containing every nth element from the original list.\n\n Parameters:\n lst (list): The list to be split.\n n (int): The nth element for splitting.\n\n Returns:\n list: A list of lists, each containing every nth element from the original list.\n \"\"\"\n return [lst[i::n] for i in range(n)]", "matching_cluster_idx": 5}, {"solution": "def list_split(lst, n):\n \"\"\"\n Splits a list into sublists, each containing every nth element from the original list.\n\n :param lst: List of elements to be split.\n :param n: Integer specifying the interval for splitting the list.\n :return: List of lists, each containing every nth element from the original list.\n \"\"\"\n # Initialize an empty list to hold the result\n result = [[] for _ in range(n)]\n\n # Iterate over the input list with an index\n for i, item in enumerate(lst):\n # Append the item to the appropriate sublist based on the index modulo n\n result[i % n].append(item)\n\n return result", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n \"\"\"Splits a list for every nth element.\n\n Args:\n lst: The original list.\n n: The number of elements per sublist.\n\n Returns:\n A list of the resulting lists.\n \"\"\"\n return [lst[i::n] for i in range(n)]", "matching_cluster_idx": 5}, {"solution": "def list_split(lst, n):\n # This will be the list of lists that we will return\n return_list = [[] for _ in range(n)]\n\n # Iterate over the input list and place items in the correct sublist\n for idx, item in enumerate(lst):\n return_list[idx % n].append(item)\n\n return return_list", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n # Initialize an empty list to store the result\n result = [[] for _ in range(n)]\n\n # Iterate over the elements of the input list\n for i, value in enumerate(lst):\n # Append the element to the appropriate sublist\n result[i % n].append(value)\n\n return result", "matching_cluster_idx": 4}, {"solution": "def list_split(input_list, n):\n result = [[] for _ in range(n)]\n for i, val in enumerate(input_list):\n result[i % n].append(val)\n return result", "matching_cluster_idx": 4}]}, "Mbpp/281": {"dps": 94.0, "dps_norm": 81.81818181818181, "pass@1": 100.0, "profiled": [{"solution": "def all_unique(lst):\n \"\"\"\n Check if all elements in the given list are unique.\n\n Args:\n lst (list): List of elements to check for uniqueness.\n\n Returns:\n bool: True if all elements are unique, False otherwise.\n \"\"\"\n # Convert the list to a set and compare lengths to check for uniqueness\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n Check if the elements of a given list are unique or not.\n\n :param lst: List of elements\n :return: True if all elements are unique, False otherwise\n \"\"\"\n # Use set to find unique elements\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n Check if all elements in the list are unique.\n\n Args:\n lst (list): The list to check for uniqueness.\n\n Returns:\n bool: True if all elements are unique, False otherwise.\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n Check if all elements in the given list are unique.\n\n Parameters:\n lst (list): The list to check for uniqueness.\n\n Returns:\n bool: True if all elements are unique, False otherwise.\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n Check if all elements in the given list are unique.\n\n Parameters:\n lst (list): The list to check.\n\n Returns:\n bool: True if all elements are unique, False otherwise.\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n This function checks if all elements in a given list are unique.\n\n :param lst: List of elements\n :return: True if all elements are unique, False otherwise\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"Check if all elements in the list are unique.\"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n Check if the elements of a given list are unique or not.\n\n :param lst: List of elements to check for uniqueness.\n :return: True if all elements are unique, False otherwise.\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n Check if all elements of the given list are unique.\n\n :param lst: List of elements to check\n :return: True if all elements are unique, False otherwise\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"Check if the elements of a given list are unique.\"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n This function checks if the elements of a given list are unique or not.\n\n :param lst: List of elements to check for uniqueness.\n :return: True if all elements are unique, False otherwise.\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n Check if all elements in the list are unique.\n\n Parameters:\n lst (list): The list to check.\n\n Returns:\n bool: True if all elements are unique, False otherwise.\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n Check if the elements of a given list are unique or not.\n\n :param lst: List of elements to check for uniqueness.\n :return: True if all elements are unique, False otherwise.\n \"\"\"\n # Check if the length of the list is the same as the length of the set created from the list\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n Check if all elements in the given list are unique.\n\n Args:\n lst (list): The list to check for unique elements.\n\n Returns:\n bool: True if all elements are unique, False otherwise.\n \"\"\"\n # Using set to determine if there are duplicates\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"Check if the elements of a given list are unique or not.\"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n Check if all elements in the list are unique.\n\n Args:\n lst (list): The list to check.\n\n Returns:\n bool: True if all elements are unique, False otherwise.\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}]}, "Mbpp/296": {"dps": 46.92307692307692, "dps_norm": 74.16666666666667, "pass@1": 80.0, "profiled": [{"solution": "def get_Inv_Count(arr):\n def merge_and_count(arr, temp_arr, left, mid, right):\n i = left # Starting index for left subarray\n j = mid + 1 # Starting index for right subarray\n k = left # Starting index to be sorted\n inv_count = 0\n\n # Conditions are checked to ensure that i doesn't exceed the left subarray and j doesn't exceed the right subarray\n while i <= mid and j <= right:\n if arr[i] <= arr[j]:\n temp_arr[k] = arr[i]\n i += 1\n else:\n temp_arr[k] = arr[j]\n inv_count += (mid - i + 1)\n j += 1\n k += 1\n\n # Copy the remaining elements of left subarray into temporary array\n while i <= mid:\n temp_arr[k] = arr[i]\n i += 1\n k += 1\n\n # Copy the remaining elements of right subarray into temporary array\n while j <= right:\n temp_arr[k] = arr[j]\n j += 1\n k += 1\n\n # Copy the sorted subarray into original array\n for i in range(left, right + 1):\n arr[i] = temp_arr[i]\n\n return inv_count\n\n def _merge_sort_and_count(arr, temp_arr, left, right):\n inv_count = 0\n if left < right:\n mid = (left + right) // 2\n inv_count = _merge_sort_and_count(arr, temp_arr, left, mid)\n inv_count += _merge_sort_and_count(arr, temp_arr, mid + 1, right)\n inv_count += merge_and_count(arr, temp_arr, left, mid, right)\n return inv_count\n\n temp_arr = [0]*len(arr)\n return _merge_sort_and_count(arr, temp_arr, 0, len(arr) - 1)", "matching_cluster_idx": 5}, {"solution": "def get_Inv_Count(array):\n \"\"\"\n Function to calculate the number of inversions in an array.\n An inversion is a pair (i, j) such that i < j and array[i] > array[j].\n \"\"\"\n\n def merge_and_count(left, right):\n \"\"\"\n Helper function to merge two sorted arrays and count the inversions.\n \"\"\"\n i, j, count = 0, 0, 0\n result = []\n while i < len(left) and j < len(right):\n if left[i] <= right[j]:\n result.append(left[i])\n i += 1\n else:\n result.append(right[j])\n j += 1\n count += len(left) - i\n result.extend(left[i:])\n result.extend(right[j:])\n return result, count\n\n def sort_and_count(array):\n \"\"\"\n Helper function to sort the array and count the inversions using merge sort.\n \"\"\"\n if len(array) <= 1:\n return array, 0\n mid = len(array) // 2\n left, left_count = sort_and_count(array[:mid])\n right, right_count = sort_and_count(array[mid:])\n merged, split_count = merge_and_count(left, right)\n total_count = left_count + right_count + split_count\n return merged, total_count\n\n _, inv_count = sort_and_count(array)\n return inv_count", "matching_cluster_idx": 5}, {"solution": "def get_Inv_Count(arr):\n def mergeAndCount(arr, temp_arr, left, mid, right):\n i = left # Starting index for left subarray\n j = mid + 1 # Starting index for right subarray\n k = left # Starting index to be sorted\n inv_count = 0\n\n # Conditions are checked to ensure that\n # i doesn't exceed left subarray limit and\n # j doesn't exceed right subarray limit\n while i <= mid and j <= right:\n if arr[i] <= arr[j]:\n temp_arr[k] = arr[i]\n i += 1\n else:\n temp_arr[k] = arr[j]\n inv_count += (mid - i + 1)\n j += 1\n k += 1\n\n # Copy the remaining elements of left subarray\n # (if there are any) to temp\n while i <= mid:\n temp_arr[k] = arr[i]\n i += 1\n k += 1\n\n # Copy the remaining elements of right subarray\n # (if there are any) to temp\n while j <= right:\n temp_arr[k] = arr[j]\n j += 1\n k += 1\n\n # Copy the sorted subarray into Original array\n for i in range(left, right + 1):\n arr[i] = temp_arr[i]\n\n return inv_count\n\n def mergeSortAndCount(arr, temp_arr, left, right):\n inv_count = 0\n if left < right:\n mid = (left + right)//2\n\n # Inversion count will be the sum of inversions\n # in left-subarray, right-subarray and number of\n # inversions in merging\n inv_count += mergeSortAndCount(arr, temp_arr,\n left, mid)\n inv_count += mergeSortAndCount(arr, temp_arr,\n mid + 1, right)\n\n # Merge the two subarrays in sorted order and\n # count inversions in merge()\n inv_count += mergeAndCount(arr, temp_arr, left, mid, right)\n\n return inv_count\n\n # Temp array\n temp_arr = [0]*len(arr)\n\n return mergeSortAndCount(arr, temp_arr, 0, len(arr) - 1)", "matching_cluster_idx": 5}, {"solution": "def get_Inv_Count(arr):\n def mergeSort(arr, n):\n temp_arr = [0]*n\n return _mergeSort(arr, temp_arr, 0, n-1)\n\n def _mergeSort(arr, temp_arr, left, right):\n\n inv_count = 0\n\n if left < right:\n mid = (left + right)//2\n\n inv_count += _mergeSort(arr, temp_arr, left, mid)\n\n inv_count += _mergeSort(arr, temp_arr, mid + 1, right)\n\n inv_count += merge(arr, temp_arr, left, mid, right)\n return inv_count\n\n def merge(arr, temp_arr, left, mid, right):\n i = left\n j = mid + 1\n k = left\n inv_count = 0\n\n while i <= mid and j <= right:\n if arr[i] <= arr[j]:\n temp_arr[k] = arr[i]\n k += 1\n i += 1\n else:\n temp_arr[k] = arr[j]\n inv_count += (mid-i + 1)\n k += 1\n j += 1\n\n while i <= mid:\n temp_arr[k] = arr[i]\n k += 1\n i += 1\n\n while j <= right:\n temp_arr[k] = arr[j]\n k += 1\n j += 1\n\n for i in range(left, right + 1):\n arr[i] = temp_arr[i]\n\n return inv_count\n\n return mergeSort(arr, len(arr))", "matching_cluster_idx": 5}, {"solution": "def get_Inv_Count(arr):\n count = 0\n for i in range(len(arr)):\n for j in range(i + 1, len(arr)):\n if arr[i] > arr[j]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def get_Inv_Count(arr):\n def merge_sort(arr):\n if len(arr) < 2:\n return arr, 0\n else:\n mid = len(arr) // 2\n left, a = merge_sort(arr[:mid])\n right, b = merge_sort(arr[mid:])\n merged, c = merge(left, right)\n return merged, a + b + c\n\n def merge(left, right):\n i = j = 0\n inv_count = 0\n merged = []\n while i < len(left) and j < len(right):\n if left[i] <= right[j]:\n merged.append(left[i])\n i += 1\n else:\n inv_count += len(left) - i\n merged.append(right[j])\n j += 1\n merged.extend(left[i:])\n merged.extend(right[j:])\n return merged, inv_count\n\n _, inv_count = merge_sort(arr)\n return inv_count", "matching_cluster_idx": 5}, {"solution": "def get_Inv_Count(arr):\n inv_count = 0\n for i in range(len(arr) - 1):\n for j in range(i + 1, len(arr)):\n if arr[i] > arr[j]:\n inv_count += 1\n return inv_count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n count = 0\n n = len(arr)\n for i in range(n):\n for j in range(i+1, n):\n if arr[i] > arr[j]:\n count += 1\n return count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n n = len(arr)\n inv_count = 0\n for i in range(n):\n for j in range(i + 1, n):\n if (arr[i] > arr[j]):\n inv_count += 1\n return inv_count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n count = 0\n for i in range(len(arr)):\n for j in range(i + 1, len(arr)):\n if arr[i] > arr[j]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def get_Inv_Count(arr):\n inv_count = 0\n for i in range(len(arr)):\n for j in range(i + 1, len(arr)):\n if arr[i] > arr[j]:\n inv_count += 1\n return inv_count", "matching_cluster_idx": 2}, {"solution": "def get_Inv_Count(arr):\n inv_count = 0\n for i in range(len(arr)):\n for j in range(i + 1, len(arr)):\n if arr[i] > arr[j]:\n inv_count += 1\n return inv_count", "matching_cluster_idx": 2}, {"solution": "def get_Inv_Count(arr):\n count = 0\n n = len(arr)\n for i in range(n):\n for j in range(i + 1, n):\n if arr[i] > arr[j]:\n count += 1\n return count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n if len(arr) < 2:\n return 0\n else:\n mid = len(arr) // 2\n left = arr[:mid]\n right = arr[mid:]\n\n left_inv = get_Inv_Count(left)\n right_inv = get_Inv_Count(right)\n split_inv = merge_and_count(arr, left, right)\n\n return left_inv + right_inv + split_inv\ndef merge_and_count(arr, left, right):\n i = j = k = 0\n inv_count = 0\n\n while i < len(left) and j < len(right):\n if left[i] <= right[j]:\n arr[k] = left[i]\n i += 1\n else:\n arr[k] = right[j]\n j += 1\n inv_count += len(left) - i\n k += 1\n\n while i < len(left):\n arr[k] = left[i]\n i += 1\n k += 1\n\n while j < len(right):\n arr[k] = right[j]\n j += 1\n k += 1\n\n return inv_count", "matching_cluster_idx": 5}, {"solution": "def get_Inv_Count(arr):\n n = len(arr)\n inv_count = 0\n for i in range(n):\n for j in range(i+1, n):\n if arr[i] > arr[j]:\n inv_count += 1\n return inv_count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n def mergeAndCountSplitInv(arr, temp, left, mid, right):\n i = left\n j = mid + 1\n k = left\n inv_count = 0\n\n while i <= mid and j <= right:\n if arr[i] <= arr[j]:\n temp[k] = arr[i]\n i += 1\n else:\n temp[k] = arr[j]\n inv_count += (mid - i + 1)\n j += 1\n k += 1\n\n while i <= mid:\n temp[k] = arr[i]\n i += 1\n k += 1\n\n while j <= right:\n temp[k] = arr[j]\n j += 1\n k += 1\n\n for i in range(left, right + 1):\n arr[i] = temp[i]\n\n return inv_count\n\n def mergeSortAndCountInv(arr, temp, left, right):\n inv_count = 0\n if left < right:\n mid = (left + right) // 2\n inv_count += mergeSortAndCountInv(arr, temp, left, mid)\n inv_count += mergeSortAndCountInv(arr, temp, mid + 1, right)\n inv_count += mergeAndCountSplitInv(arr, temp, left, mid, right)\n return inv_count\n\n temp = [0] * len(arr)\n return mergeSortAndCountInv(arr, temp, 0, len(arr) - 1)", "matching_cluster_idx": 5}, {"solution": "def get_Inv_Count(array):\n count = 0\n length = len(array)\n for i in range(length):\n for j in range(i+1, length):\n if array[i] > array[j]:\n count += 1\n return count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n inv_count = 0\n for i in range(len(arr)):\n for j in range(i+1, len(arr)):\n if arr[i] > arr[j]:\n inv_count += 1\n return inv_count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n inv_count = 0\n for i in range(len(arr)):\n for j in range(i+1, len(arr)):\n if arr[i] > arr[j]:\n inv_count += 1\n return inv_count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n inv_count = 0\n for i in range(len(arr)):\n for j in range(i + 1, len(arr)):\n if arr[i] > arr[j]:\n inv_count += 1\n return inv_count", "matching_cluster_idx": 2}]}, "Mbpp/308": {"dps": 97.79310344827587, "dps_norm": 68.33333333333334, "pass@1": 98.0, "profiled": [{"solution": "def large_product(lst1, lst2, n):\n product_lst = []\n for i in lst1:\n for j in lst2:\n product_lst.append(i*j)\n product_lst.sort(reverse=True)\n return product_lst[:n]", "matching_cluster_idx": 3}, {"solution": "def large_product(lst1, lst2, n):\n products = [a*b for a in lst1 for b in lst2]\n products.sort(reverse=True)\n return products[:n]", "matching_cluster_idx": 3}, {"solution": "import heapq\ndef large_product(list1, list2, n):\n # Compute the products of pairs from the two lists\n products = [a * b for a in list1 for b in list2]\n\n # Find the n largest products using heapq.nlargest\n return heapq.nlargest(n, products)", "matching_cluster_idx": 4}, {"solution": "def large_product(list1, list2, n):\n products = [i * j for i in list1 for j in list2]\n return sorted(products, reverse=True)[:n]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, count):\n results = []\n for i in list1:\n for j in list2:\n results.append(i*j)\n results = sorted(results, reverse=True)\n return results[:count]", "matching_cluster_idx": 3}, {"solution": "def large_product(lst1, lst2, n):\n products = []\n for x in lst1:\n for y in lst2:\n products.append(x * y)\n products.sort(reverse=True)\n return products[:n]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n products = []\n # Generate all possible products\n for a in list1:\n for b in list2:\n products.append(a * b)\n # Sort products in descending order\n products.sort(reverse=True)\n # Return the first n products\n return products[:n]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n # Create an empty list to store the products\n products = []\n\n # Compute all possible products from the two lists\n for a in list1:\n for b in list2:\n products.append(a * b)\n\n # Sort the products in descending order\n products.sort(reverse=True)\n\n # Return the n largest products\n return products[:n]", "matching_cluster_idx": 3}, {"solution": "from itertools import product\ndef large_product(list1, list2, n):\n \"\"\"\n Find the n largest products from two given lists, selecting one factor from each list.\n\n :param list1: First list of numbers\n :param list2: Second list of numbers\n :param n: Number of largest products to return\n :return: List of n largest products\n \"\"\"\n # Calculate all products by taking one factor from each list\n all_products = [x * y for x, y in product(list1, list2)]\n\n # Sort the products in descending order and return the top n\n sorted_products = sorted(all_products, reverse=True)\n\n return sorted_products[:n]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n \"\"\"\n Function to find the specified number of largest products from two given lists, selecting one factor from each list.\n\n Parameters:\n list1 (list): The first list of numbers\n list2 (list): The second list of numbers\n n (int): The number of largest products to find\n\n Returns:\n list: A list of the n largest products\n \"\"\"\n # Calculate all possible products\n products = [x * y for x in list1 for y in list2]\n\n # Sort the products in descending order and select the top n\n largest_products = sorted(products, reverse=True)[:n]\n\n return largest_products", "matching_cluster_idx": 3}, {"solution": "def large_product(lst1, lst2, n):\n # Calculate the product of each pair\n products = [a * b for a in lst1 for b in lst2]\n\n # Sort the products in descending order\n sorted_products = sorted(products, reverse=True)\n\n # Return the first n products\n return sorted_products[:n]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n # Find all possible products by multiplying one element from each list\n products = [x * y for x in list1 for y in list2]\n\n # Sort products in descending order and return the first 'n' products\n products.sort(reverse=True)\n return products[:n]", "matching_cluster_idx": 3}, {"solution": "def large_product(lst1, lst2, n):\n # Check if n is larger than the length of either list\n if n > len(lst1) or n > len(lst2):\n raise ValueError(\"n cannot be larger than the length of either list\")\n\n # Calculate all possible products\n products = [a * b for a in lst1 for b in lst2]\n\n # Sort products in descending order and select the top n\n largest_products = sorted(products, reverse=True)[:n]\n\n return largest_products", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n products = []\n\n for i in list1:\n for j in list2:\n products.append(i * j)\n\n products.sort(reverse=True)\n\n return products[:n]", "matching_cluster_idx": 3}, {"solution": "from heapq import nlargest\ndef large_product(list1, list2, n):\n products = []\n for num1 in list1:\n for num2 in list2:\n products.append(num1 * num2)\n return sorted(nlargest(n, products), reverse=True)", "matching_cluster_idx": 3}, {"solution": "def large_product(lst1, lst2, num):\n # Creating the list of products of elements from both lists\n products = [i * j for i in lst1 for j in lst2]\n # Sorting the products in descending order\n products.sort(reverse=True)\n # Returning the specified number of largest products\n return products[:num]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n if n <= 0 or not list1 or not list2:\n return []\n\n products = [a * b for a in list1 for b in list2]\n products.sort(reverse=True)\n\n return products[:n]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n products = [a * b for a in list1 for b in list2]\n products.sort(reverse=True)\n return products[:n]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n # Get products of all pairs\n products = [a * b for a in list1 for b in list2]\n # Sort the products in descending order\n products.sort(reverse=True)\n # Return the top n largest products\n return products[:n]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n product_list = [(x*y) for x in list1 for y in list2]\n product_list = sorted(set(product_list), reverse=True)\n return product_list[:n]", "matching_cluster_idx": 4}]}, "Mbpp/392": {"dps": 98.05164319248826, "dps_norm": 99.61538461538461, "pass@1": 65.0, "profiled": [{"solution": "def get_max_sum(n, memo = {}):\n if n in memo:\n return memo[n]\n\n if n <= 5:\n return n\n\n memo[n] = max(get_max_sum(n//2, memo) + get_max_sum(n//3, memo) + get_max_sum(n//4, memo) + get_max_sum(n//5, memo), n)\n\n return memo[n]", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n, memo={}):\n \"\"\"\n This function calculates the maximum sum using the provided recursive formula.\n\n Parameters:\n n (int): The input number.\n memo (dict): A dictionary to store previously computed results for memoization.\n\n Returns:\n int: The maximum sum possible.\n \"\"\"\n # Base case\n if n <= 0:\n return 0\n\n # If the result is already computed, return it from the memo dictionary\n if n in memo:\n return memo[n]\n\n # Compute the result using the given formula\n max_sum = max(get_max_sum(n//2, memo) + get_max_sum(n//3, memo) + get_max_sum(n//4, memo) + get_max_sum(n//5, memo), n)\n\n # Store the result in the memo dictionary and return it\n memo[n] = max_sum\n return max_sum", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n # Create a dictionary to store the computed values to avoid redundant calculations\n cache = {}\n\n def f(n):\n # Base cases: if n is 0 or negative, return 0\n if n <= 0:\n return 0\n # If we have already computed the value, return it\n if n in cache:\n return cache[n]\n # Compute the value according to the given formula\n cache[n] = max(f(n // 2) + f(n // 3) + f(n // 4) + f(n // 5), n)\n return cache[n]\n\n return f(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n, memo={}):\n if n in memo:\n return memo[n]\n if n <= 0:\n return 0\n max_value = max(\n get_max_sum(n // 2, memo) + get_max_sum(n // 3, memo) + get_max_sum(n // 4, memo) + get_max_sum(n // 5, memo),\n n\n )\n memo[n] = max_value\n return max_value", "matching_cluster_idx": 12}, {"solution": "import math\ndef get_max_sum(n, memo={}):\n # Base case: if n is less than or equal to 0, return 0\n if n <= 0:\n return 0\n\n # If the result is already computed, return it\n if n in memo:\n return memo[n]\n\n # Compute the maximum sum using the given formula\n result = max(\n n,\n get_max_sum(n // 2, memo) +\n get_max_sum(n // 3, memo) +\n get_max_sum(n // 4, memo) +\n get_max_sum(n // 5, memo)\n )\n\n # Store the computed result in memo and return it\n memo[n] = result\n return result", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n, memo=None):\n if memo is None:\n memo = {}\n if n in memo:\n return memo[n]\n if n <= 5:\n return n\n max_sum = max(get_max_sum(n//2, memo) + get_max_sum(n//3, memo) + get_max_sum(n//4, memo) + get_max_sum(n//5, memo), n)\n memo[n] = max_sum\n return max_sum", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n, memo={}):\n # Base case: when n is zero, the max sum is zero\n if n == 0:\n return 0\n # If the value is already calculated, return it from the memo\n if n in memo:\n return memo[n]\n # Apply the equation and get the maximum sum\n v1 = get_max_sum(n // 2, memo)\n v2 = get_max_sum(n // 3, memo)\n v3 = get_max_sum(n // 4, memo)\n v4 = get_max_sum(n // 5, memo)\n res = max(v1 + v2 + v3 + v4, n)\n # Store the calculated value into memo\n memo[n] = res\n return res", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n, memo={}):\n if n in memo:\n return memo[n]\n if n <= 0:\n return 0\n\n memo[n] = max(get_max_sum(n//2, memo) + get_max_sum(n//3, memo) + get_max_sum(n//4, memo) + get_max_sum(n//5, memo), n)\n\n return memo[n]", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n, memo={}):\n if n in memo:\n return memo[n]\n if n <= 0:\n return 0\n memo[n] = max(get_max_sum(n//2, memo) + get_max_sum(n//3, memo) + get_max_sum(n//4, memo) + get_max_sum(n//5, memo), n)\n return memo[n]", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n, memo=None):\n if memo is None:\n memo = {}\n if n <= 0:\n return 0\n if n in memo:\n return memo[n]\n\n memo[n] = max(get_max_sum(n//2, memo) + get_max_sum(n//3, memo) + get_max_sum(n//4, memo) + get_max_sum(n//5, memo), n)\n return memo[n]", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n, memo={}):\n if n in memo:\n return memo[n]\n\n if n <= 5:\n memo[n] = n\n return n\n\n # Calculate the maximum sum\n max_sum = max(get_max_sum(n // 2, memo) + get_max_sum(n // 3, memo) +\n get_max_sum(n // 4, memo) + get_max_sum(n // 5, memo), n)\n\n memo[n] = max_sum\n return max_sum", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n \"\"\"\n Function to find the maximum sum possible by using the given equation\n f(n) = max((f(n/2) + f(n/3) + f(n/4) + f(n/5)), n)\n \"\"\"\n memo = {0: 0, 1: 1}\n\n def f(n):\n if n in memo:\n return memo[n]\n else:\n a = f(n // 2) + f(n // 3) + f(n // 4) + f(n // 5)\n b = n\n memo[n] = max(a, b)\n return memo[n]\n\n return f(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n if n <= 5:\n return n\n else:\n # Use dictionary to store intermediate results for memoization\n memo = {i: i for i in range(6)}\n return _get_max_sum_helper(n, memo)\ndef _get_max_sum_helper(n, memo):\n if n not in memo:\n memo[n] = max(n, _get_max_sum_helper(n // 2, memo) + _get_max_sum_helper(n // 3, memo) + _get_max_sum_helper(n // 4, memo) + _get_max_sum_helper(n // 5, memo))\n return memo[n]", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n, memo={}):\n if n in memo:\n return memo[n]\n if n <= 1:\n return n\n\n memo[n] = max(n,\n get_max_sum(n // 2, memo) + get_max_sum(n // 3, memo) + get_max_sum(n // 4, memo) + get_max_sum(n // 5, memo))\n\n return memo[n]", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n: int) -> int:\n from functools import lru_cache\n\n @lru_cache(None)\n def helper(k: int) -> int:\n if k <= 5:\n return k\n return max(k, helper(k // 2) + helper(k // 3) + helper(k // 4) + helper(k // 5))\n\n return helper(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n, memo=None):\n if memo is None:\n memo = {}\n\n if n in memo:\n return memo[n]\n\n if n <= 5:\n return n\n\n # Function f as defined\n f_val = max(get_max_sum(n//2, memo) + get_max_sum(n//3, memo) + get_max_sum(n//4, memo) + get_max_sum(n//5, memo), n)\n\n # Memoize and return the result\n memo[n] = f_val\n return f_val", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n, memo=None):\n if memo is None:\n memo = {}\n\n if n in memo:\n return memo[n]\n\n if n <= 5:\n memo[n] = n\n return n\n\n v1 = get_max_sum(n // 2, memo)\n v2 = get_max_sum(n // 3, memo)\n v3 = get_max_sum(n // 4, memo)\n v4 = get_max_sum(n // 5, memo)\n ans = max(v1 + v2 + v3 + v4, n)\n\n memo[n] = ans\n return ans", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n memo = {0: 0, 1: 1}\n\n def f(x):\n if x in memo:\n return memo[x]\n v = x if x <= 5 else max(f(x//2) + f(x//3) + f(x//4) + f(x//5), x)\n memo[x] = v\n return v\n\n return f(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n # Create a dictionary to store the previously computed values for dynamic programming\n dp = {1: 1}\n\n def helper(x):\n if x in dp:\n return dp[x]\n max_value = x\n if x >= 2:\n max_value = max(helper(x // 2) + helper(x // 3) + helper(x // 4) + helper(x // 5), max_value)\n dp[x] = max_value\n return max_value\n\n return helper(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n, memo=None):\n if memo is None:\n memo = {}\n\n if n in memo:\n return memo[n]\n\n if n <= 0:\n return 0\n if n <= 5:\n return n\n\n terms = [n // 2, n // 3, n // 4, n // 5]\n sum_of_terms = sum(get_max_sum(term, memo) for term in terms)\n\n result = max(sum_of_terms, n)\n memo[n] = result\n\n return result", "matching_cluster_idx": 11}]}, "Mbpp/395": {"dps": 98.08429118773947, "dps_norm": 75.0, "pass@1": 100.0, "profiled": [{"solution": "def first_non_repeating_character(s):\n # Create a dictionary to store the count of each character\n char_count = {}\n\n # Populate the dictionary with character counts\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n\n # Find the first non-repeating character\n for char in s:\n if char_count[char] == 1:\n return char\n\n # Return None if no non-repeating character is found\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n # Dictionary to store the count of each character\n char_count = {}\n\n # Count the occurrences of each character\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n\n # Find the first character with a count of 1\n for char in s:\n if char_count[char] == 1:\n return char\n\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n char_count = {}\n\n # Count the occurrences of each character in the string\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n\n # Find the first character with a count of 1\n for char in s:\n if char_count[char] == 1:\n return char\n\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n \"\"\"\n Find the first non-repeated character in the given string.\n\n :param s: The input string\n :return: The first non-repeated character, or None if no such character exists\n \"\"\"\n char_count = {}\n\n # Count occurrences of each character\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n\n # Find the first character with count 1\n for char in s:\n if char_count[char] == 1:\n return char\n\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n char_count = {}\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n\n for char in s:\n if char_count[char] == 1:\n return char\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s: str):\n \"\"\"\n Find the first non-repeated character in the given string.\n\n :param s: The input string.\n :return: The first non-repeated character, or None if all characters are repeated.\n \"\"\"\n # Create a dictionary to count the occurrences of each character\n char_count = {}\n\n # Count the occurrences of each character in the string\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n\n # Iterate through the string again to find the first non-repeated character\n for char in s:\n if char_count[char] == 1:\n return char\n\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n char_count = {}\n\n # Count the occurrences of each character\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n\n # Find the first non-repeating character\n for char in s:\n if char_count[char] == 1:\n return char\n\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(string):\n from collections import Counter\n\n # Count the frequency of each character in the string\n counts = Counter(string)\n\n # Find the first character with a count of 1\n for char in string:\n if counts[char] == 1:\n return char\n\n # Return None if no non-repeating character is found\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n \"\"\"\n Function to find the first non-repeated character in a given string.\n\n Args:\n s (str): Input string to search in.\n\n Returns:\n str or None: The first non-repeated character or None if no non-repeating character exists.\n \"\"\"\n # Dictionary to store the count of each character\n char_count = {}\n\n # Count the occurrences of each character\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n\n # Find the first non-repeating character\n for char in s:\n if char_count[char] == 1:\n return char\n\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(string):\n char_count = {}\n\n # Count the occurrences of each character\n for char in string:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n\n # Find the first character that has a count of 1\n for char in string:\n if char_count[char] == 1:\n return char\n\n # If no non-repeating character is found, return None\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s: str) -> str:\n \"\"\"\n Find the first non-repeated character in a given string.\n :param s: The input string.\n :return: The first non-repeated character, or None if no such character exists.\n \"\"\"\n # Dictionary to keep track of character counts\n char_count = {}\n\n # Populate the dictionary with character counts\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n\n # Find the first non-repeating character\n for char in s:\n if char_count[char] == 1:\n return char\n\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n # Dictionary to store the count of each character\n char_count = {}\n\n # Count the occurrence of each character\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n\n # Find the first non-repeating character\n for char in s:\n if char_count[char] == 1:\n return char\n\n # If no non-repeating character is found, return None\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n \"\"\"\n Find the first non-repeated character in a given string.\n If there is no non-repeating character, return None.\n \"\"\"\n # Dictionary to store the frequency of each character in the string\n char_count = {}\n\n # First pass to count the occurrences of each character\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n\n # Second pass to find the first non-repeating character\n for char in s:\n if char_count[char] == 1:\n return char\n\n # If no non-repeating character is found, return None\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n \"\"\"\n Function to find the first non-repeated character in the given string.\n\n Args:\n s (str): The input string.\n\n Returns:\n str or None: The first non-repeated character or None if no such character exists.\n \"\"\"\n # Dictionary to keep track of character frequencies\n char_count = {}\n\n # Count the occurrences of each character\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n\n # Find the first character with a count of 1\n for char in s:\n if char_count[char] == 1:\n return char\n\n # If no non-repeating character is found, return None\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s: str) -> str:\n \"\"\"\n Find the first non-repeating character in a given string.\n\n :param s: Input string\n :return: The first non-repeating character or None if no such character exists\n \"\"\"\n count = {}\n\n # Count occurrences of each character\n for char in s:\n if char in count:\n count[char] += 1\n else:\n count[char] = 1\n\n # Find the first non-repeating character\n for char in s:\n if count[char] == 1:\n return char\n\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n \"\"\"\n This function finds the first non-repeated character in a given string.\n :param s: Input string\n :return: The first non-repeated character, or None if no such character is found\n \"\"\"\n # Dictionary to count the occurrence of each character\n char_count = {}\n\n # Count occurrences of each character in the string\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n\n # Find the first character with a count of 1\n for char in s:\n if char_count[char] == 1:\n return char\n\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s: str):\n # Create a dictionary to store character counts\n char_count = {}\n\n # First pass: count the occurrences of each character\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n\n # Second pass: find the first character with count 1\n for char in s:\n if char_count[char] == 1:\n return char\n\n # If no non-repeating character is found, return None\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n char_count = {}\n # Counting the occurrence of each character\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n # Finding the first non-repeating character\n for char in s:\n if char_count[char] == 1:\n return char\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n \"\"\"\n Find the first non-repeated character in the given string.\n\n :param s: input string\n :return: The first non-repeating character, or None if no such character exists\n \"\"\"\n char_count = {}\n\n # Count occurrences of each character\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n\n # Find the first character with count 1\n for char in s:\n if char_count[char] == 1:\n return char\n\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n # Dictionary to store frequency of characters\n frequency = {}\n\n # Count frequency of each character\n for char in s:\n if char in frequency:\n frequency[char] += 1\n else:\n frequency[char] = 1\n\n # Find the first non-repeating character\n for char in s:\n if frequency[char] == 1:\n return char\n\n return None", "matching_cluster_idx": 5}]}, "Mbpp/405": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def check_tuplex(tuplex, element):\n \"\"\"\n Function to check whether an element exists within a tuple.\n\n Parameters:\n tuplex (tuple): The tuple to check.\n element: The element to look for in the tuple.\n\n Returns:\n bool: True if the element is found in the tuple, False otherwise.\n \"\"\"\n return element in tuplex", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tup, elem):\n \"\"\"\n Checks whether an element exists within a tuple.\n\n Parameters:\n tup (tuple): The tuple to check.\n elem : The element to check for.\n\n Returns:\n bool: True if the element is in the tuple, False otherwise.\n \"\"\"\n return elem in tup", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, element):\n \"\"\"\n Check whether an element exists within a tuple.\n\n Args:\n tuplex (tuple): The tuple to search in.\n element: The element to search for.\n\n Returns:\n bool: True if the element is found in the tuple, False otherwise.\n \"\"\"\n return element in tuplex", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, element):\n \"\"\"Check if an element exists within a tuple.\"\"\"\n return element in tuplex", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, element):\n \"\"\"\n Check if an element exists within a tuple.\n\n Parameters:\n tuplex (tuple): The tuple in which to search for the element.\n element (any): The element to search for.\n\n Returns:\n bool: True if the element is found, False otherwise.\n \"\"\"\n return element in tuplex", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, element):\n \"\"\"\n This function checks if an element exists within a tuple.\n\n :param tuplex: A tuple\n :param element: An element to check in the tuple\n :return: True if element exists in the tuple, False otherwise\n \"\"\"\n return element in tuplex", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tup, element):\n \"\"\"\n This function checks whether an element exists within a tuple.\n\n :param tup: Tuple to check\n :param element: Element to check for existence in tuple\n :return: True if element exists, False otherwise\n \"\"\"\n return element in tup", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, element):\n \"\"\"\n Check whether an element exists within a tuple.\n\n :param tuplex: Tuple to be checked\n :param element: Element to check for in the tuple\n :return: True if element exists in tuple, False otherwise\n \"\"\"\n return element in tuplex", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(t, element):\n \"\"\"\n This function checks whether an element exists within a tuple.\n\n :param t: Tuple to be checked\n :param element: Element to check for within the tuple\n :return: Boolean indicating whether the element exists in the tuple\n \"\"\"\n return element in t", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, element):\n \"\"\"\n Check whether an element exists within a tuple.\n\n Parameters:\n tuplex (tuple): The tuple to be checked.\n element (any): The element to be checked for in the tuple.\n\n Returns:\n bool: True if element is in the tuple, False otherwise.\n \"\"\"\n return element in tuplex", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tup, element):\n \"\"\"\n Check whether an element exists within a tuple.\n\n :param tup: The tuple to check.\n :param element: The element to search for in the tuple.\n :return: True if the element exists in the tuple, otherwise False.\n \"\"\"\n return element in tup", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, element):\n \"\"\"\n Check whether an element exists within a tuple.\n\n Args:\n tuplex (tuple): The tuple to check.\n element: The element to search for in the tuple.\n\n Returns:\n bool: True if element is found in the tuple, False otherwise.\n \"\"\"\n return element in tuplex", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tup, element):\n \"\"\"\n Function to check whether an element exists within a tuple.\n\n :param tup: Tuple to be checked.\n :param element: Element to be checked within the tuple.\n :return: True if the element exists, False otherwise.\n \"\"\"\n return element in tup", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, element):\n return element in tuplex", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tup, element):\n \"\"\"\n This function checks whether an element exists within a tuple.\n\n :param tup: Tuple to check\n :param element: Element to check within the tuple\n :return: True if element is found, False otherwise\n \"\"\"\n return element in tup", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, element):\n \"\"\"\n This function checks whether an element exists within a tuple.\n\n :param tuplex: Tuple within which to check for the element.\n :param element: The element to check for within the tuple.\n :return: True if element exists within the tuple, False otherwise.\n \"\"\"\n return element in tuplex", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, element):\n \"\"\"\n Checks if the element exists within the given tuple.\n\n :param tuplex: A tuple within which to search for the element.\n :param element: The element to search for.\n :return: True if the element is found, False otherwise.\n \"\"\"\n return element in tuplex", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(t, element):\n \"\"\"\n Function to check if an element exists within a tuple.\n\n :param t: tuple to check\n :param element: element to look for\n :return: True if element is in the tuple, False otherwise\n \"\"\"\n return element in t", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(t, elem):\n return elem in t", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, element):\n \"\"\"\n Check if an element exists within a tuple.\n\n Parameters:\n tuplex (tuple): The tuple to check.\n element: The element to search for in the tuple.\n\n Returns:\n bool: True if the element is found in the tuple, False otherwise.\n \"\"\"\n return element in tuplex", "matching_cluster_idx": 3}]}, "Mbpp/414": {"dps": 70.62111801242236, "dps_norm": 83.88888888888889, "pass@1": 100.0, "profiled": [{"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Check whether any value in sequence1 exists in sequence2.\n\n Parameters:\n seq1 (list): First sequence of elements\n seq2 (list): Second sequence of elements\n\n Returns:\n bool: True if any element of seq1 is in seq2, False otherwise\n \"\"\"\n return any(elem in seq2 for elem in seq1)", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Check if any value in the first sequence exists in the second sequence.\n\n Parameters:\n seq1 (list): The first sequence of values.\n seq2 (list): The second sequence of values.\n\n Returns:\n bool: True if there is any common value, False otherwise.\n \"\"\"\n # Convert the second sequence to a set for efficient lookup\n set_seq2 = set(seq2)\n\n # Iterate over the first sequence and check for presence in the second sequence\n for val in seq1:\n if val in set_seq2:\n return True\n\n return False", "matching_cluster_idx": 6}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Check whether any value in seq1 exists in seq2.\n\n Parameters:\n seq1 (list): First sequence of values\n seq2 (list): Second sequence of values\n\n Returns:\n bool: True if any value in seq1 exists in seq2, otherwise False\n \"\"\"\n return any(value in seq2 for value in seq1)", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"Check whether any value in seq1 exists in seq2.\"\"\"\n # Convert the second sequence to a set for faster lookup\n set_seq2 = set(seq2)\n\n # Check if any element from seq1 is in set_seq2\n for element in seq1:\n if element in set_seq2:\n return True\n return False", "matching_cluster_idx": 6}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Check whether any value in seq1 exists in seq2.\n\n :param seq1: First sequence (list, tuple, etc.)\n :param seq2: Second sequence (list, tuple, etc.)\n :return: True if any value in seq1 exists in seq2, False otherwise\n \"\"\"\n return any(item in seq2 for item in seq1)", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Checks if there is any common value between two sequences.\n\n Parameters:\n seq1 (list): The first sequence of values.\n seq2 (list): The second sequence of values.\n\n Returns:\n bool: True if there is at least one common value, False otherwise.\n \"\"\"\n # Convert the second sequence to a set for faster lookup\n set_seq2 = set(seq2)\n\n # Check if any element in the first sequence exists in the set of the second sequence\n for element in seq1:\n if element in set_seq2:\n return True\n return False", "matching_cluster_idx": 6}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Check if any value in seq1 exists in seq2.\n\n Parameters:\n seq1 (list): First sequence of values.\n seq2 (list): Second sequence of values.\n\n Returns:\n bool: True if any value in seq1 exists in seq2, False otherwise.\n \"\"\"\n return any(item in seq2 for item in seq1)", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n This function checks if any value in the first sequence exists in the second sequence.\n\n :param seq1: The first sequence (list or tuple).\n :param seq2: The second sequence (list or tuple).\n :return: True if any value from seq1 exists in seq2, False otherwise.\n \"\"\"\n return any(value in seq2 for value in seq1)", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Check whether any value in seq1 exists in seq2.\n\n Parameters:\n seq1 (list): First sequence of values.\n seq2 (list): Second sequence of values.\n\n Returns:\n bool: True if any value in seq1 exists in seq2, otherwise False.\n \"\"\"\n # Convert both sequences to sets\n set1 = set(seq1)\n set2 = set(seq2)\n\n # Check for any common elements\n return not set1.isdisjoint(set2)", "matching_cluster_idx": 6}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Check if any value in sequence1 exists in sequence2.\n\n :param seq1: First sequence\n :param seq2: Second sequence\n :return: True if there is an overlap, False otherwise\n \"\"\"\n # Create a set from seq2 for efficient membership testing\n set_seq2 = set(seq2)\n\n # Check if any element of seq1 is in set_seq2\n for value in seq1:\n if value in set_seq2:\n return True\n\n return False", "matching_cluster_idx": 6}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Check if any value in seq1 exists in seq2.\n\n :param seq1: First sequence of values\n :param seq2: Second sequence of values\n :return: True if any value in seq1 exists in seq2, False otherwise\n \"\"\"\n # Convert the second sequence to a set for faster lookup\n set_seq2 = set(seq2)\n\n # Check for any common element\n for value in seq1:\n if value in set_seq2:\n return True\n return False", "matching_cluster_idx": 6}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n This function checks if there is any common value between two sequences.\n\n Args:\n seq1 (list or tuple): First sequence of elements.\n seq2 (list or tuple): Second sequence of elements.\n\n Returns:\n bool: True if there is at least one common element, False otherwise.\n \"\"\"\n # Convert the sequences to sets and check for common elements\n set1 = set(seq1)\n set2 = set(seq2)\n return not set1.isdisjoint(set2)", "matching_cluster_idx": 6}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n This function checks if there is any common element between two sequences.\n\n :param seq1: First sequence (list, tuple, or any iterable)\n :param seq2: Second sequence (list, tuple, or any iterable)\n :return: True if there is at least one common element, False otherwise\n \"\"\"\n set1 = set(seq1)\n set2 = set(seq2)\n\n # Check for intersection\n return not set1.isdisjoint(set2)", "matching_cluster_idx": 6}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Check whether any value in seq1 exists in seq2.\n\n Args:\n seq1 (list): First sequence of values.\n seq2 (list): Second sequence of values.\n\n Returns:\n bool: True if any value in seq1 exists in seq2, False otherwise.\n \"\"\"\n return any(value in seq2 for value in seq1)", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Check if any value in seq1 exists in seq2.\n\n :param seq1: First sequence of values.\n :param seq2: Second sequence of values.\n :return: True if any value in seq1 exists in seq2, False otherwise.\n \"\"\"\n return any(item in seq2 for item in seq1)", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Checks whether any value in sequence 1 exists in sequence 2.\n\n Parameters:\n seq1 (list): The first sequence.\n seq2 (list): The second sequence.\n\n Returns:\n bool: True if any value in sequence 1 exists in sequence 2, otherwise False.\n \"\"\"\n return any(value in seq2 for value in seq1)", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Check whether any value in the first sequence exists in the second sequence.\n\n Parameters:\n seq1 (list): First sequence of values\n seq2 (list): Second sequence of values\n\n Returns:\n bool: True if there is any overlap, False otherwise\n \"\"\"\n # Use set intersection to check for any common elements\n return not set(seq1).isdisjoint(set(seq2))", "matching_cluster_idx": 6}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Check whether any value in seq1 exists in seq2.\n\n Parameters:\n seq1 (list): First sequence of values\n seq2 (list): Second sequence of values\n\n Returns:\n bool: True if there is any overlapping value, False otherwise\n \"\"\"\n return any(value in seq2 for value in seq1)", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Check if any value in seq1 exists in seq2.\n\n Parameters:\n seq1 (iterable): The first sequence to check.\n seq2 (iterable): The second sequence to check against.\n\n Returns:\n bool: True if any value in seq1 exists in seq2, otherwise False.\n \"\"\"\n for item in seq1:\n if item in seq2:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"Check if any value in seq1 exists in seq2.\"\"\"\n return any(value in seq2 for value in seq1)", "matching_cluster_idx": 7}]}, "Mbpp/421": {"dps": 69.17695473251028, "dps_norm": 89.28571428571429, "pass@1": 100.0, "profiled": [{"solution": "def concatenate_tuple(tup, delimiter='-'):\n \"\"\"\n Concatenates each element of a tuple with a given delimiter.\n\n Parameters:\n tup (tuple): The tuple containing elements to concatenate.\n delimiter (str): The delimiter to use for concatenation.\n\n Returns:\n str: The concatenated string.\n \"\"\"\n # Using join method to concatenate elements with the delimiter\n return delimiter.join(map(str, tup))", "matching_cluster_idx": 6}, {"solution": "def concatenate_tuple(input_tuple):\n # Concatenate the elements of the tuple with the delimiter '-'\n return '-'.join(str(element) for element in input_tuple)", "matching_cluster_idx": 4}, {"solution": "def concatenate_tuple(elements, delimiter='-'):\n \"\"\"\n Concatenate each element of a tuple by the specified delimiter.\n\n Parameters:\n elements (tuple): The tuple whose elements need to be concatenated.\n delimiter (str): The delimiter used for concatenation.\n\n Returns:\n str: The concatenated string.\n \"\"\"\n return delimiter.join(map(str, elements))", "matching_cluster_idx": 6}, {"solution": "def concatenate_tuple(tup, delimiter='-'):\n \"\"\"\n This function takes a tuple and a delimiter and returns a string\n where each element of the tuple is concatenated by the delimiter.\n \"\"\"\n # Convert each element of the tuple to string and join them with the delimiter\n return delimiter.join(map(str, tup))", "matching_cluster_idx": 6}, {"solution": "def concatenate_tuple(input_tuple, delimiter='-'):\n \"\"\"\n This function concatenates each element of the tuple with the specified delimiter.\n\n Parameters:\n input_tuple (tuple): The tuple containing elements to be concatenated.\n delimiter (str): The delimiter used to join the elements.\n\n Returns:\n str: A string where each element of the input tuple is concatenated with the delimiter.\n \"\"\"\n return delimiter.join(str(element) for element in input_tuple)", "matching_cluster_idx": 4}, {"solution": "def concatenate_tuple(tup):\n # Convert each element to string and join them using the delimiter '-'\n return '-'.join(map(str, tup))", "matching_cluster_idx": 6}, {"solution": "def concatenate_tuple(input_tuple, delimiter='-'):\n \"\"\"\n This function concatenates each element of the tuple by the specified delimiter.\n \"\"\"\n # Convert all elements to strings and join them with the specified delimiter\n return delimiter.join(str(element) for element in input_tuple)", "matching_cluster_idx": 4}, {"solution": "def concatenate_tuple(tup, delimiter='-'):\n \"\"\"\n Concatenate each element of a tuple by the specified delimiter.\n All elements are converted to strings before concatenation.\n\n Parameters:\n tup (tuple): A tuple containing elements to be concatenated.\n delimiter (str): The delimiter to be used for concatenation. Default is '-'.\n\n Returns:\n str: A concatenated string of the tuple elements.\n \"\"\"\n # Convert all elements of the tuple to strings and join them with the specified delimiter\n return delimiter.join(str(element) for element in tup)", "matching_cluster_idx": 4}, {"solution": "def concatenate_tuple(input_tuple, delimiter='-'):\n \"\"\"\n This function takes a tuple and concatenates each element\n with the specified delimiter.\n\n Parameters:\n input_tuple (tuple): The tuple whose elements are to be concatenated.\n delimiter (str): The delimiter to be used for concatenation.\n\n Returns:\n str: The concatenated string.\n \"\"\"\n # Convert each element of the tuple to string and join with the delimiter\n return delimiter.join(map(str, input_tuple))", "matching_cluster_idx": 6}, {"solution": "def concatenate_tuple(input_tuple, delimiter='-'):\n \"\"\"\n Concatenate each element of tuple by the delimiter.\n\n :param input_tuple: tuple to concatenate\n :param delimiter: delimiter to join the elements\n :return: concatenated string\n \"\"\"\n return delimiter.join(map(str, input_tuple))", "matching_cluster_idx": 6}, {"solution": "def concatenate_tuple(t, delimiter='-'):\n \"\"\"\n Concatenate each element of a tuple by the given delimiter.\n\n Parameters:\n t (tuple): The tuple to concatenate.\n delimiter (str): The delimiter to use for concatenation.\n\n Returns:\n str: The concatenated string.\n \"\"\"\n return delimiter.join(str(element) for element in t)", "matching_cluster_idx": 4}, {"solution": "def concatenate_tuple(t, delimiter='-'):\n \"\"\"\n Concatenate each element of the tuple by the given delimiter.\n\n Parameters:\n t (tuple): The input tuple containing elements to concatenate.\n delimiter (str): The string to separate each element of the tuple.\n\n Returns:\n str: The concatenated string.\n \"\"\"\n return delimiter.join(map(str, t))", "matching_cluster_idx": 6}, {"solution": "def concatenate_tuple(input_tuple, delimiter=\"-\"):\n \"\"\"\n Concatenate each element of a tuple by a delimiter.\n\n Parameters:\n input_tuple (tuple): The tuple to concatenate.\n delimiter (str): The delimiter to use for concatenation.\n\n Returns:\n str: The concatenated string.\n \"\"\"\n # Convert each element to a string and join them with the delimiter\n return delimiter.join(str(element) for element in input_tuple)", "matching_cluster_idx": 4}, {"solution": "def concatenate_tuple(input_tuple):\n # Convert all elements to strings and join them with '-'\n return '-'.join(map(str, input_tuple))", "matching_cluster_idx": 6}, {"solution": "def concatenate_tuple(t, delimiter='-'):\n # Convert all elements to strings and join them using the specified delimiter\n return delimiter.join(map(str, t))", "matching_cluster_idx": 6}, {"solution": "def concatenate_tuple(input_tuple):\n # Convert each element of the tuple to a string\n str_elements = map(str, input_tuple)\n # Concatenate the elements with a '-' delimiter\n concatenated_str = '-'.join(str_elements)\n return concatenated_str", "matching_cluster_idx": 6}, {"solution": "def concatenate_tuple(input_tuple, delimiter='-'):\n \"\"\"\n Concatenate each element of the tuple with the specified delimiter.\n\n Parameters:\n input_tuple (tuple): The tuple containing elements to be concatenated.\n delimiter (str): The delimiter to use for concatenation.\n\n Returns:\n str: The concatenated string.\n \"\"\"\n # Use the delimiter to join the elements of the tuple after converting each element to a string\n return delimiter.join(str(element) for element in input_tuple)", "matching_cluster_idx": 4}, {"solution": "def concatenate_tuple(input_tuple, delimiter=\"-\"):\n \"\"\"\n Concatenate each element of a tuple with the given delimiter.\n\n Args:\n input_tuple (tuple): The tuple containing elements to be concatenated.\n delimiter (str): The delimiter to use for concatenation.\n\n Returns:\n str: A string with elements of the tuple concatenated by the delimiter.\n \"\"\"\n # Convert all elements to strings and join them with the delimiter\n return delimiter.join(map(str, input_tuple))", "matching_cluster_idx": 6}, {"solution": "def concatenate_tuple(t, delimiter='-'):\n \"\"\"\n Concatenate each element of a tuple with a specified delimiter.\n\n Parameters:\n t (tuple): The tuple to concatenate.\n delimiter (str): The delimiter to use for concatenation. Default is '-'.\n\n Returns:\n str: The concatenated string.\n \"\"\"\n # Convert each element in the tuple to a string and join them with the delimiter\n return delimiter.join(map(str, t))", "matching_cluster_idx": 6}, {"solution": "def concatenate_tuple(input_tuple, delimiter='-'):\n \"\"\"\n Concatenate each element of the tuple with the specified delimiter.\n\n Parameters:\n input_tuple (tuple): The input tuple containing elements to be concatenated.\n delimiter (str): The delimiter to be used for concatenation.\n\n Returns:\n str: The concatenated string.\n \"\"\"\n # Convert all elements of the tuple to strings\n str_elements = map(str, input_tuple)\n\n # Join the string elements with the delimiter\n concatenated_string = delimiter.join(str_elements)\n\n return concatenated_string", "matching_cluster_idx": 5}]}, "Mbpp/424": {"dps": 97.5812274368231, "dps_norm": 99.0, "pass@1": 100.0, "profiled": [{"solution": "def extract_rear(tuple_of_strings):\n # Using a list comprehension to extract the last character of each string in the tuple\n return [s[-1] for s in tuple_of_strings]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(strings):\n return [s[-1] for s in strings]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(strings):\n \"\"\"\n Extracts the rear index element of each string in the given tuple.\n\n Parameters:\n strings (tuple): A tuple of strings.\n\n Returns:\n list: A list containing the last character of each string in the tuple.\n \"\"\"\n return [s[-1] for s in strings]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(tup):\n \"\"\"\n Extracts the last character of each string in a given tuple.\n\n Parameters:\n tup (tuple): A tuple of strings.\n\n Returns:\n list: A list of the last characters of each string.\n \"\"\"\n return [s[-1] for s in tup]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(tuple_of_strings):\n \"\"\"\n This function extracts the last character of each string in the given tuple.\n\n :param tuple_of_strings: A tuple of strings\n :return: A list containing the last character of each string in the tuple\n \"\"\"\n return [string[-1] for string in tuple_of_strings]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(strings):\n # Initialize an empty list to store the rear index elements\n rear_elements = []\n\n # Loop through each string in the given tuple\n for string in strings:\n # Extract the rear index element and add it to the list\n if string: # Check if the string is not empty\n rear_elements.append(string[-1])\n\n # Return the list of rear index elements\n return rear_elements", "matching_cluster_idx": 3}, {"solution": "def extract_rear(strings):\n return [string[-1] for string in strings]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(strings):\n # Extract the last character of each string in the tuple and store them in a list\n rear_elements = [string[-1] for string in strings]\n return rear_elements", "matching_cluster_idx": 4}, {"solution": "def extract_rear(strings):\n \"\"\"\n Extracts the rear index element of each string in the given tuple.\n\n Args:\n strings (tuple): A tuple containing strings.\n\n Returns:\n list: A list of rear elements of the given strings.\n \"\"\"\n return [s[-1] for s in strings]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(t):\n \"\"\"\n Extract the last character of each string in the tuple and return as a list.\n\n :param t: tuple of strings\n :return: list of last characters of each string in the tuple\n \"\"\"\n return [s[-1] for s in t]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(input_tuple):\n \"\"\"\n This function extracts the last element of each string in a given tuple.\n\n :param input_tuple: Tuple containing strings\n :return: List of the last character of each string\n \"\"\"\n # Extract the last character of each string and create a list\n result = [string[-1] for string in input_tuple]\n return result", "matching_cluster_idx": 4}, {"solution": "def extract_rear(input_tuple):\n \"\"\"\n Extracts the last character from each string in the input tuple and returns them as a list.\n\n Parameters:\n input_tuple (tuple): A tuple of strings.\n\n Returns:\n list: A list of last characters from each string in the input tuple.\n \"\"\"\n return [string[-1] for string in input_tuple]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(input_tuple):\n \"\"\"\n This function takes a tuple of strings and returns a list of the rear index element of each string.\n\n :param input_tuple: tuple of strings\n :return: list of last characters from each string in the tuple\n \"\"\"\n return [string[-1] for string in input_tuple]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(strings_tuple):\n \"\"\"\n This function takes a tuple of strings and returns a list of the last character of each string.\n\n :param strings_tuple: Tuple of strings\n :return: List of last characters of each string in the tuple\n \"\"\"\n return [string[-1] for string in strings_tuple]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(tup):\n \"\"\"\n Function to extract the rear index element of each string in the given tuple.\n\n Parameters:\n tup (tuple): Tuple containing strings.\n\n Returns:\n list: List containing the last character of each string in the input tuple.\n \"\"\"\n # List comprehension to get the last character of each string in the tuple\n return [s[-1] for s in tup]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(data):\n \"\"\"\n This function takes a tuple of strings and returns a list\n containing the last character of each string in the tuple.\n \"\"\"\n return [string[-1] for string in data]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(input_tuple):\n return [string[-1] for string in input_tuple]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(input_tuple):\n \"\"\"\n Extracts the last character of each string in the given tuple.\n\n :param input_tuple: Tuple of strings\n :return: List of last characters of each string in the tuple\n \"\"\"\n return [word[-1] for word in input_tuple]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(input_tuple):\n return [s[-1] for s in input_tuple]", "matching_cluster_idx": 4}, {"solution": "def extract_rear(strings):\n \"\"\"\n Extracts the last character of each string in the given tuple.\n\n Args:\n strings (tuple): Tuple of strings.\n\n Returns:\n list: List of the last characters of each string.\n \"\"\"\n return [s[-1] for s in strings]", "matching_cluster_idx": 4}]}, "Mbpp/425": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def count_element_in_list(lst, element):\n \"\"\"\n Count the number of sublists containing a particular element.\n \"\"\"\n count = 0\n for sublist in lst:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, element):\n \"\"\"Count the number of sublists containing a particular element.\"\"\"\n count = 0\n for sublist in lst:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, elem):\n count = 0\n for sublist in lst:\n if elem in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, element):\n return sum(1 for sublist in lst if element in sublist)", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(list_of_lists, element):\n \"\"\"\n Count the number of sublists that contain a particular element.\n\n Parameters:\n list_of_lists (list of lists): A list containing sublists.\n element: The element to be counted within the sublists.\n\n Returns:\n int: The number of sublists that contain the element.\n \"\"\"\n count = 0\n for sublist in list_of_lists:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(list_of_lists, element):\n count = 0\n for sublist in list_of_lists:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, element):\n \"\"\"\n This function counts the number of sublists containing a particular element.\n\n :param lst: List of lists\n :param element: Element to search for in sublists\n :return: Number of sublists containing the element\n \"\"\"\n count = 0\n for sublist in lst:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(list_of_lists, element):\n count = 0\n for sublist in list_of_lists:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, element):\n \"\"\"\n Count the number of sublists containing a particular element.\n\n Parameters:\n lst (list of lists): The list containing sublists.\n element: The element to search for in the sublists.\n\n Returns:\n int: The count of sublists containing the element.\n \"\"\"\n count = 0\n for sublist in lst:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, element):\n count = 0\n for sublist in lst:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(sublists, element):\n count = 0\n for sublist in sublists:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lists, element):\n return sum(element in sublist for sublist in lists)", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lists, element):\n \"\"\"\n Count the number of sublists containing a particular element.\n\n Parameters:\n lists (list of lists): The list of sublists to search.\n element (any type): The element to search for in the sublists.\n\n Returns:\n int: The number of sublists containing the element.\n \"\"\"\n count = 0\n for sublist in lists:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(list_of_lists, target_element):\n count = 0\n for sublist in list_of_lists:\n if target_element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(main_list, element):\n \"\"\"\n Counts the number of sublists in main_list that contain the specified element.\n\n Parameters:\n main_list (list of lists): List containing sublists\n element: The element to count in the sublists\n\n Returns:\n int: The count of sublists containing the element\n \"\"\"\n count = 0\n for sublist in main_list:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, target):\n \"\"\"Count the number of sublists containing a particular element.\"\"\"\n count = 0\n for sublist in lst:\n if target in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(list_of_lists, element):\n count = 0\n for sublist in list_of_lists:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(list_of_lists, element):\n count = 0\n for sublist in list_of_lists:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, element):\n \"\"\"\n Function to count the number of sublists containing a particular element.\n\n Parameters:\n lst (list of lists): List of lists.\n element (any): The element to search for in sublists.\n\n Returns:\n int: The number of sublists containing the given element.\n \"\"\"\n count = 0\n for sublist in lst:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, element):\n count = 0\n for sublist in lst:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}]}, "Mbpp/428": {"dps": 37.35537190082645, "dps_norm": 46.666666666666664, "pass@1": 100.0, "profiled": [{"solution": "def shell_sort(arr):\n # Start with a big gap, then reduce the gap\n n = len(arr)\n gap = n // 2\n\n # Perform a gapped insertion sort for this gap size.\n # The first gap elements a[0..gap-1] are already in gapped\n # order keep adding one more element until the entire array\n # is gap sorted\n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n\n # Shift earlier gap-sorted elements up until the correct location for arr[i] is found\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n\n # Put temp (the original arr[i]) in its correct location\n arr[j] = temp\n gap //= 2\n\n return arr", "matching_cluster_idx": 3}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2\n\n # Start with a big gap, then reduce the gap\n while gap > 0:\n # Do a gapped insertion sort for this gap size.\n for i in range(gap, n):\n # Save arr[i] in temp and make a hole at position i\n temp = arr[i]\n\n # Shift earlier gap-sorted elements up until the correct location for arr[i] is found\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n\n # Put temp (the original arr[i]) in its correct location\n arr[j] = temp\n gap //= 2\n\n return arr", "matching_cluster_idx": 3}, {"solution": "def shell_sort(arr):\n \"\"\"\n This function sorts the given array using the shell sort algorithm.\n :param arr: List of integers\n :return: Sorted list of integers\n \"\"\"\n n = len(arr)\n gap = n // 2\n\n # Start with a big gap, then reduce the gap\n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n\n # Perform a gapped insertion sort for this gap size. The first gap\n # elements a[0..gap-1] are already in gapped order keep adding\n # one more element until the entire array is gap sorted\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n\n # Put temp (the original arr[i]) in its correct location\n arr[j] = temp\n gap //= 2\n\n return arr", "matching_cluster_idx": 3}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2\n\n # Start with a big gap, then reduce the gap\n while gap > 0:\n\n # Do a gapped insertion sort for this gap size.\n for i in range(gap, n):\n\n # Add arr[i] to the elements that have been gap-sorted\n # Save arr[i] in temp and make a hole at position i\n temp = arr[i]\n\n # Shift earlier gap-sorted elements up until the correct location for arr[i] is found\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n\n # Put temp (the original arr[i]) in its correct location\n arr[j] = temp\n gap //= 2\n\n return arr", "matching_cluster_idx": 3}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2\n\n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n\n return arr", "matching_cluster_idx": 3}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2\n\n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n\n arr[j] = temp\n gap //= 2\n\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2\n\n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n\n arr[j] = temp\n gap //= 2\n\n return arr", "matching_cluster_idx": 3}, {"solution": "def shell_sort(array):\n n = len(array)\n gap = n // 2\n\n # Start with a big gap, then reduce the gap\n while gap > 0:\n # Do a gapped insertion sort for this gap size.\n for i in range(gap, n):\n # Save array[i] in temp and make a hole at position i\n temp = array[i]\n # Shift earlier gap-sorted elements up until the correct location for array[i] is found\n j = i\n while j >= gap and array[j - gap] > temp:\n array[j] = array[j - gap]\n j -= gap\n # Put temp (the original array[i]) in its correct location\n array[j] = temp\n gap //= 2\n\n return array", "matching_cluster_idx": 3}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2\n\n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n\n return arr", "matching_cluster_idx": 3}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2\n\n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n\n return arr", "matching_cluster_idx": 3}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2\n\n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n\n return arr", "matching_cluster_idx": 3}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2\n\n # Start with a big gap, then reduce the gap\n while gap > 0:\n # Do a gapped insertion sort for this gap size.\n # The first gap elements a[0..gap-1] are already in gapped order\n # keep adding one more element until the entire array is gap sorted\n for i in range(gap, n):\n # add a[i] to the elements that have been gap sorted\n # save a[i] in temp and make a hole at position i\n temp = arr[i]\n\n # shift earlier gap-sorted elements up until the correct location for arr[i] is found\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n\n # put temp (the original arr[i]) in its correct location\n arr[j] = temp\n gap //= 2\n\n return arr", "matching_cluster_idx": 3}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2\n\n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n\n return arr", "matching_cluster_idx": 3}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2\n\n # Start with a big gap, then reduce the gap\n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n\n arr[j] = temp\n gap //= 2\n\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2\n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n return arr", "matching_cluster_idx": 3}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2\n\n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n\n arr[j] = temp\n gap //= 2\n\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(array):\n n = len(array)\n gap = n // 2\n\n while gap > 0:\n for i in range(gap, n):\n temp = array[i]\n j = i\n while j >= gap and array[j - gap] > temp:\n array[j] = array[j - gap]\n j -= gap\n array[j] = temp\n gap //= 2\n\n return array", "matching_cluster_idx": 3}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2\n # Start with a big gap, then reduce the gap\n while gap > 0:\n # Do a gapped insertion sort for this gap size.\n for i in range(gap, n):\n # Save arr[i] in temp and make a hole at position i\n temp = arr[i]\n # Shift earlier gap-sorted elements up until the correct location for arr[i] is found\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n # Put temp (the original arr[i]) in its correct location\n arr[j] = temp\n gap //= 2\n return arr", "matching_cluster_idx": 3}, {"solution": "def shell_sort(arr):\n # Start with a big gap, then reduce the gap\n n = len(arr)\n gap = n // 2\n\n # Do a gapped insertion sort for this gap size.\n # The first gap elements arr[0..gap-1] are already in gapped order\n # keep adding one more element until the entire array is gap sorted\n while gap > 0:\n\n # Add gap-th element to the elements that have been gap sorted\n # save arr[0..gap-1]\n # last gap-th element arr[0..gap-1] are already in gap order\n for i in range(gap, n):\n\n # add arr[i] to the elements that have been gap sorted\n # save arr[i] in temp and make a hole at position i\n temp = arr[i]\n\n # shift earlier gap-sorted elements up until the correct location for arr[i] is found\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n\n # put temp (the original arr[i]) in its correct location\n arr[j] = temp\n gap //= 2\n\n return arr", "matching_cluster_idx": 3}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2\n\n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n\n arr[j] = temp\n gap //= 2\n\n return arr", "matching_cluster_idx": 4}]}, "Mbpp/433": {"dps": 72.87234042553192, "dps_norm": 70.0, "pass@1": 100.0, "profiled": [{"solution": "def check_greater(arr, num):\n \"\"\"\n Check if the given number is greater than all elements of the array.\n\n :param arr: List of integers\n :param num: Integer to compare\n :return: Boolean value\n \"\"\"\n return all(num > x for x in arr)", "matching_cluster_idx": 2}, {"solution": "def check_greater(arr, num):\n \"\"\"\n Check if the entered number is greater than all elements in the given array.\n\n :param arr: List of numbers\n :param num: Number to compare\n :return: True if num is greater than all elements in arr, False otherwise\n \"\"\"\n return all(num > element for element in arr)", "matching_cluster_idx": 2}, {"solution": "def check_greater(arr, num):\n \"\"\"\n Checks whether the entered number is greater than all elements of the given array.\n\n :param arr: List of integers\n :param num: Integer to compare with the elements of the array\n :return: Boolean indicating whether the number is greater than all elements of the array\n \"\"\"\n return all(num > x for x in arr)", "matching_cluster_idx": 2}, {"solution": "def check_greater(array, number):\n \"\"\"\n This function checks if the entered number is greater than all the elements of the given array.\n :param array: List of integers\n :param number: Integer to be checked\n :return: Boolean value (True if number is greater, else False)\n \"\"\"\n return all(number > element for element in array)", "matching_cluster_idx": 2}, {"solution": "def check_greater(arr, num):\n \"\"\"\n Check whether the entered number is greater than all elements of the given array.\n\n Parameters:\n arr (list of int): The array to compare against.\n num (int): The number to check.\n\n Returns:\n bool: True if num is greater than all elements in arr, False otherwise.\n \"\"\"\n return all(num > x for x in arr)", "matching_cluster_idx": 2}, {"solution": "def check_greater(arr, num):\n \"\"\"\n Function to check whether the entered number is greater than all the elements of the given array.\n\n :param arr: list of integers\n :param num: integer to compare\n :return: True if num is greater than all elements in arr, otherwise False\n \"\"\"\n return all(num > x for x in arr)", "matching_cluster_idx": 2}, {"solution": "def check_greater(arr, number):\n \"\"\"\n Function to check whether the entered number is greater than the elements of the given array.\n\n :param arr: List of numbers\n :param number: Number to compare with elements of the array\n :return: True if the number is greater than all elements in the array, otherwise False\n \"\"\"\n return all(number > element for element in arr)", "matching_cluster_idx": 2}, {"solution": "def check_greater(arr, num):\n \"\"\"\n This function checks whether the entered number is greater than all the elements of the given array.\n\n Parameters:\n arr (list): A list of numbers.\n num (int): The number to be checked.\n\n Returns:\n bool: True if the number is greater than all the elements in the array, False otherwise.\n \"\"\"\n for element in arr:\n if num <= element:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def check_greater(arr, num):\n \"\"\"\n Checks whether the entered number is greater than all the elements of the given array.\n\n Parameters:\n arr (list of int): The array of integers.\n num (int): The number to be compared.\n\n Returns:\n bool: True if num is greater than all elements in arr, otherwise False.\n \"\"\"\n for element in arr:\n if num <= element:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def check_greater(array, number):\n \"\"\"\n Function to check whether the entered number is greater than the elements of the given array.\n\n :param array: List of numbers\n :param number: Number to check against array elements\n :return: True if the number is greater than all elements in the array, False otherwise\n \"\"\"\n return all(number > element for element in array)", "matching_cluster_idx": 2}, {"solution": "def check_greater(arr, num):\n \"\"\"\n Check whether the entered number is greater than all the elements of the given array.\n\n Parameters:\n arr (list): List of numbers.\n num (int): Number to compare against the array.\n\n Returns:\n bool: True if num is greater than all elements in the array, False otherwise.\n \"\"\"\n return all(num > elem for elem in arr)", "matching_cluster_idx": 2}, {"solution": "def check_greater(arr, num):\n \"\"\"\n Function to check whether the entered number is greater than the elements of the given array.\n\n :param arr: List of integers\n :param num: Integer to compare\n :return: True if num is greater than all elements in arr, False otherwise\n \"\"\"\n for element in arr:\n if num <= element:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def check_greater(arr, number):\n \"\"\"\n This function checks whether the entered number is greater than all elements of the given array.\n\n :param arr: List of integers\n :param number: Integer to compare with elements of the array\n :return: Boolean indicating if the number is greater than all elements of the array\n \"\"\"\n return all(number > elem for elem in arr)", "matching_cluster_idx": 2}, {"solution": "def check_greater(arr, num):\n \"\"\"\n Function to check if the entered number is greater than all elements in the array.\n\n Parameters:\n arr (list): The list of numbers.\n num (int or float): The number to compare with elements of the array.\n\n Returns:\n bool: True if the number is greater than all elements, False otherwise.\n \"\"\"\n return all(num > element for element in arr)", "matching_cluster_idx": 2}, {"solution": "def check_greater(arr, num):\n \"\"\"\n Checks whether the entered number is greater than all the elements of the given array.\n\n :param arr: List of integers.\n :param num: Integer to be compared with the array elements.\n :return: Boolean indicating if the number is greater than all array elements.\n \"\"\"\n return all(num > x for x in arr)", "matching_cluster_idx": 2}, {"solution": "def check_greater(arr, num):\n \"\"\"\n Function to check whether the entered number is greater than the elements of the given array.\n :param arr: List of numbers\n :param num: Number to check\n :return: Boolean indicating if num is greater than all elements of arr\n \"\"\"\n return all(num > elem for elem in arr)", "matching_cluster_idx": 2}, {"solution": "def check_greater(arr, num):\n \"\"\"\n This function checks whether the entered number is greater than all elements of the given array.\n :param arr: list of integers\n :param num: integer\n :return: boolean\n \"\"\"\n return all(num > element for element in arr)", "matching_cluster_idx": 2}, {"solution": "def check_greater(arr, num):\n \"\"\"\n Function to check whether the entered number is greater than all the elements of the given array.\n\n Parameters:\n arr (list): List of integers.\n num (int): The number to check against the elements of the array.\n\n Returns:\n bool: True if the number is greater than all elements of the array, False otherwise.\n \"\"\"\n for element in arr:\n if num <= element:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def check_greater(array, number):\n \"\"\"\n Check whether the entered number is greater than the elements of the given array.\n\n :param array: List of integers\n :param number: Integer to compare with the elements of the array\n :return: Boolean indicating whether the number is greater than all elements in the array\n \"\"\"\n for elem in array:\n if number <= elem:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def check_greater(arr, num):\n \"\"\"\n This function checks if the entered number is greater than all the elements in the given array.\n\n Parameters:\n arr (list): A list of integers.\n num (int): An integer to compare with the elements of the array.\n\n Returns:\n bool: True if the number is greater than all elements in the array, False otherwise.\n \"\"\"\n return all(num > x for x in arr)", "matching_cluster_idx": 2}]}, "Mbpp/437": {"dps": 82.94117647058823, "dps_norm": 64.0, "pass@1": 85.0, "profiled": [{"solution": "def remove_odd(s):\n \"\"\"\n This function removes odd-indexed characters from a string.\n \"\"\"\n return s[1::2]", "matching_cluster_idx": 4}, {"solution": "def remove_odd(s):\n \"\"\"\n Remove odd indexed characters in a string.\n \"\"\"\n return s[1::2]", "matching_cluster_idx": 3}, {"solution": "def remove_odd(s: str) -> str:\n \"\"\"\n This function removes characters located at odd indices in the string.\n\n Parameters:\n s (str): The input string from which odd characters are to be removed.\n\n Returns:\n str: A new string with characters at odd indices removed.\n \"\"\"\n return s[1::2]", "matching_cluster_idx": 4}, {"solution": "def remove_odd(s: str) -> str:\n # Create a new string with characters at even indices (0, 2, 4, etc.)\n return ''.join(s[i] for i in range(len(s)) if i % 2 == 1)", "matching_cluster_idx": 0}, {"solution": "def remove_odd(s: str) -> str:\n # Create a new string with even-indexed characters only\n return ''.join(s[i] for i in range(1, len(s), 2))", "matching_cluster_idx": 2}, {"solution": "def remove_odd(input_string):\n \"\"\"\n Removes all odd characters from the input string.\n\n Args:\n input_string (str): The string from which odd characters should be removed.\n\n Returns:\n str: A new string with all odd characters removed.\n \"\"\"\n return input_string[1::2]", "matching_cluster_idx": 4}, {"solution": "def remove_odd(s):\n \"\"\"\n Function to remove odd-indexed characters in a string.\n \"\"\"\n return s[1::2]", "matching_cluster_idx": 4}, {"solution": "def remove_odd(s):\n \"\"\"\n Function to remove characters at odd indices from a string.\n \"\"\"\n return s[1::2]", "matching_cluster_idx": 4}, {"solution": "def remove_odd(s):\n \"\"\"\n This function removes characters at odd positions (1-based index) in a string.\n\n Parameters:\n s (str): The input string.\n\n Returns:\n str: The string with odd-position characters removed.\n \"\"\"\n # Convert the string to a list to allow mutation\n char_list = list(s)\n\n # Iterate over the list and remove characters at odd positions\n for i in range(len(char_list) - 1, -1, -1):\n if (i + 1) % 2 != 0:\n char_list.pop(i)\n\n # Convert the list back to a string and return\n return ''.join(char_list)", "matching_cluster_idx": -1}, {"solution": "def remove_odd(string):\n \"\"\"Remove odd-indexed characters from the input string.\"\"\"\n return string[1::2]", "matching_cluster_idx": 3}, {"solution": "def remove_odd(s):\n # Use list comprehension to filter out odd indexed characters\n return ''.join(s[i] for i in range(len(s)) if i % 2 == 1)", "matching_cluster_idx": 0}, {"solution": "def remove_odd(s: str) -> str:\n \"\"\"\n Function to remove odd-indexed characters from a string.\n\n Parameters:\n s (str): Input string\n\n Returns:\n str: String with odd-indexed characters removed\n \"\"\"\n return s[1::2]", "matching_cluster_idx": 4}, {"solution": "def remove_odd(input_string):\n \"\"\"\n Removes odd-indexed characters from the input string.\n\n Args:\n input_string (str): The input string from which odd-indexed characters will be removed.\n\n Returns:\n str: A new string with only even-indexed characters from the input string.\n \"\"\"\n # Use list comprehension to filter even-indexed characters\n return ''.join([input_string[i] for i in range(len(input_string)) if i % 2 != 0])", "matching_cluster_idx": 0}, {"solution": "def remove_odd(s: str) -> str:\n return \"\".join([s[i] for i in range(len(s)) if i % 2 != 0])", "matching_cluster_idx": 1}, {"solution": "def remove_odd(s: str) -> str:\n \"\"\"\n Remove odd characters from the input string and return the resulting string.\n \"\"\"\n return ''.join(s[i] for i in range(len(s)) if i % 2 != 0)", "matching_cluster_idx": 0}, {"solution": "def remove_odd(input_str):\n \"\"\"\n Removes odd characters (1-based index) from the input string.\n\n Args:\n input_str (str): The string from which to remove odd characters.\n\n Returns:\n str: The string with odd characters removed.\n \"\"\"\n return input_str[1::2]", "matching_cluster_idx": 4}, {"solution": "def remove_odd(s):\n \"\"\"\n Function to remove odd characters from a string.\n\n Args:\n s (str): Input string\n\n Returns:\n str: String with odd characters removed\n \"\"\"\n # Use list comprehension to create a new string excluding odd characters\n return ''.join([ch for i, ch in enumerate(s) if i % 2 == 1])", "matching_cluster_idx": 0}, {"solution": "def remove_odd(s: str) -> str:\n \"\"\"\n Remove odd characters in a string.\n \"\"\"\n return ''.join([char for i, char in enumerate(s) if (i + 1) % 2 == 0])", "matching_cluster_idx": 0}, {"solution": "def remove_odd(s: str) -> str:\n \"\"\"\n This function removes odd characters from a given string.\n\n :param s: input string\n :return: string with only even index characters\n \"\"\"\n return s[1::2]", "matching_cluster_idx": 4}, {"solution": "def remove_odd(string):\n return string[1::2]", "matching_cluster_idx": 4}]}, "Mbpp/440": {"dps": null, "dps_norm": null, "pass@1": 0.0, "profiled": []}, "Mbpp/446": {"dps": 96.25615763546799, "dps_norm": 62.0, "pass@1": 29.0, "profiled": [{"solution": "def count_Occurrence(input_tuple, input_list):\n count = 0\n for item in input_list:\n count += input_tuple.count(item)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(t, lst):\n \"\"\"\n Count the occurrence of all elements of list in a tuple.\n\n Parameters:\n t (tuple): The input tuple.\n lst (list): The list containing elements to be counted in the tuple.\n\n Returns:\n int: The total count of occurrences of list elements in the tuple.\n \"\"\"\n count = 0\n for element in lst:\n count += t.count(element)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tup, lst):\n count = 0\n for elem in lst:\n count += tup.count(elem)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(input_tuple, elements_list):\n \"\"\"\n This function counts the occurrence of all elements in the list within the tuple.\n\n :param input_tuple: A tuple containing elements to be searched\n :param elements_list: A list containing elements to be counted\n :return: Integer count of occurrences of the elements in the list within the tuple\n \"\"\"\n count = 0\n for element in elements_list:\n count += input_tuple.count(element)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(input_tuple, input_list):\n count = 0\n for item in input_list:\n count += input_tuple.count(item)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tup, lst):\n count = 0\n for element in lst:\n count += tup.count(element)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tup, lst):\n # Create a dictionary to count occurrences of each element in the tuple\n count_dict = {}\n for elem in tup:\n if elem in count_dict:\n count_dict[elem] += 1\n else:\n count_dict[elem] = 1\n\n # Sum the occurrences of elements in the list\n total_count = sum(count_dict.get(elem, 0) for elem in lst)\n\n return total_count", "matching_cluster_idx": 4}, {"solution": "def count_Occurrence(input_tuple, input_list):\n \"\"\"\n This function counts the occurrence of all elements of a list in a tuple.\n\n Parameters:\n input_tuple (tuple): Tuple containing the elements to be counted.\n input_list (list): List of elements whose occurrences are to be counted in the tuple.\n\n Returns:\n int: Total count of the occurrences of all list elements in the tuple.\n \"\"\"\n count = 0\n for elem in input_list:\n count += input_tuple.count(elem)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(input_tuple, elements_list):\n \"\"\"\n This function counts the occurrence of all elements in elements_list within input_tuple.\n\n Args:\n input_tuple (tuple): The tuple where occurrences will be counted.\n elements_list (list): The list of elements to be counted in the tuple.\n\n Returns:\n int: The total count of all elements in elements_list found in input_tuple.\n \"\"\"\n count = 0\n for element in elements_list:\n count += input_tuple.count(element)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(input_tuple, input_list):\n \"\"\"\n This function takes a tuple and a list as input and returns the count of\n all elements in the list that occur in the tuple.\n\n :param input_tuple: Tuple of elements\n :param input_list: List of elements to be counted in the tuple\n :return: Count of elements in the tuple that are present in the list\n \"\"\"\n count = 0\n for element in input_list:\n count += input_tuple.count(element)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(input_tuple, input_list):\n \"\"\"\n Counts the occurrences of all elements in the input list within the input tuple.\n\n :param input_tuple: A tuple in which occurrences are to be counted.\n :param input_list: A list containing elements to be counted in the input tuple.\n :return: An integer representing the total count of occurrences.\n \"\"\"\n count = 0\n for elem in input_list:\n count += input_tuple.count(elem)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tup, lst):\n \"\"\"\n Function to count the occurrences of all elements of the list in the tuple.\n\n Parameters:\n tup (tuple): The tuple in which to count occurrences.\n lst (list): The list containing elements to be counted.\n\n Returns:\n int: The total count of occurrences of list elements in the tuple.\n \"\"\"\n count = 0\n for item in lst:\n count += tup.count(item)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tup, lst):\n \"\"\"\n Count the occurrence of elements of the list in the tuple.\n\n Args:\n tup (tuple): The tuple to search in.\n lst (list): The list of elements to count occurrences of.\n\n Returns:\n int: The total count of occurrences.\n \"\"\"\n count = 0\n for element in lst:\n count += tup.count(element)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tup, lst):\n \"\"\"\n This function counts the occurrence of all elements of the list in the tuple.\n\n :param tup: tuple of elements\n :param lst: list of elements\n :return: integer count of occurrences\n \"\"\"\n count = 0\n for elem in lst:\n count += tup.count(elem)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(input_tuple, input_list):\n \"\"\"\n Counts the occurrences of all elements in the input_list within the input_tuple.\n\n Parameters:\n input_tuple (tuple): The tuple in which to count occurrences.\n input_list (list): The list of elements to count in the tuple.\n\n Returns:\n int: The total number of occurrences.\n \"\"\"\n # Convert the tuple to a list for easier manipulation\n tuple_list = list(input_tuple)\n\n # Initialize a count variable\n count = 0\n\n # Iterate through each element in the input_list\n for element in input_list:\n # Count occurrences of the element in the tuple\n count += tuple_list.count(element)\n\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(t, l):\n count = 0\n for item in l:\n count += t.count(item)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(input_tuple, check_list):\n \"\"\"\n Counts the occurrences of each element in check_list within input_tuple.\n\n :param input_tuple: Tuple in which occurrences will be counted.\n :param check_list: List of elements whose occurrences will be counted in the tuple.\n :return: Total count of occurrences.\n \"\"\"\n count = 0\n for element in check_list:\n count += input_tuple.count(element)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tup, lst):\n \"\"\"\n Count the occurrence of all elements of `lst` in `tup`.\n\n Parameters:\n tup (tuple): A tuple containing elements to be counted.\n lst (list): A list containing elements to look for in the tuple.\n\n Returns:\n int: The count of occurrences of elements from `lst` in `tup`.\n \"\"\"\n # Convert tuple to list for easier manipulation\n tup_list = list(tup)\n\n # Initialize the count\n count = 0\n\n # Iterate over elements in the list\n for item in lst:\n # Count occurrences of the current item in the tuple\n count += tup_list.count(item)\n\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(input_tuple, input_list):\n count = 0\n for elem in input_list:\n count += input_tuple.count(elem)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(t, lst):\n \"\"\"\n This function counts the occurrence of all elements of 'lst' in the tuple 't'.\n\n Parameters:\n t (tuple): A tuple containing elements to be counted.\n lst (list): A list of elements whose occurrences are to be counted in the tuple.\n\n Returns:\n int: The count of occurrences of the elements of 'lst' in the tuple 't'.\n \"\"\"\n count = 0\n for element in lst:\n count += t.count(element)\n return count", "matching_cluster_idx": 2}]}, "Mbpp/451": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 52.0, "profiled": [{"solution": "def remove_whitespaces(input_string):\n \"\"\"\n Function to remove all whitespaces from the given string.\n\n Args:\n input_string (str): The string from which whitespaces are to be removed.\n\n Returns:\n str: A string with all whitespaces removed.\n \"\"\"\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(s):\n \"\"\"Remove all whitespaces from the given string.\"\"\"\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string):\n \"\"\"\n This function removes all whitespaces from the given string.\n\n Parameters:\n input_string (str): The string from which whitespaces will be removed.\n\n Returns:\n str: A string with all whitespaces removed.\n \"\"\"\n # Use the built-in str.replace() method to remove all whitespaces\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string):\n \"\"\"\n This function takes a string as input and returns the string with all whitespaces removed.\n \"\"\"\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_str):\n # Use the replace method to remove all whitespaces\n return input_str.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string):\n \"\"\"\n Remove all whitespaces from the given string.\n\n Parameters:\n input_string (str): The string from which to remove whitespaces.\n\n Returns:\n str: The string with all whitespaces removed.\n \"\"\"\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string):\n \"\"\"\n Removes all whitespaces from the given string.\n\n Parameters:\n input_string (str): The input string that may contain whitespaces.\n\n Returns:\n str: The input string with all whitespaces removed.\n \"\"\"\n # Use the replace method to remove whitespaces\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(s):\n # Remove whitespaces using the replace method\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(s):\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string):\n \"\"\"\n Remove all whitespaces from the given string.\n\n Args:\n input_string (str): The input string which may contain whitespaces.\n\n Returns:\n str: The string with all whitespaces removed.\n \"\"\"\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_str):\n # Using the replace() method to remove all whitespaces\n return input_str.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_str):\n \"\"\"\n This function removes all whitespaces from the given string.\n\n Parameters:\n input_str (str): The input string from which whitespaces need to be removed.\n\n Returns:\n str: The string with all whitespaces removed.\n \"\"\"\n return input_str.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string):\n \"\"\"\n This function removes all whitespaces from the given string.\n\n Args:\n input_string (str): The input string which may contain whitespaces.\n\n Returns:\n str: The string with all whitespaces removed.\n \"\"\"\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string: str) -> str:\n \"\"\"\n Removes all whitespaces from the given string.\n \"\"\"\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(s):\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string):\n \"\"\"\n Removes all whitespaces from the given string.\n\n Parameters:\n input_string (str): The input string with whitespaces.\n\n Returns:\n str: The input string with all whitespaces removed.\n \"\"\"\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string):\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string):\n \"\"\"\n Remove all whitespaces from the given string.\n\n Args:\n input_string (str): The string to remove whitespaces from.\n\n Returns:\n str: The string with all whitespaces removed.\n \"\"\"\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string):\n \"\"\"\n Remove all whitespaces from the given string.\n\n Parameters:\n input_string (str): The string from which to remove whitespaces.\n\n Returns:\n str: The input string with all whitespaces removed.\n \"\"\"\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string):\n \"\"\"\n This function removes all whitespaces from the given string.\n\n :param input_string: A string that may contain whitespaces.\n :return: A string with all whitespaces removed.\n \"\"\"\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}]}, "Mbpp/456": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def reverse_string_list(input_list):\n # Using list comprehension to reverse each string in the list\n return [s[::-1] for s in input_list]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(list_of_strings):\n return [s[::-1] for s in list_of_strings]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(list_of_strings):\n return [s[::-1] for s in list_of_strings]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n \"\"\"\n This function reverses each string in a given list of strings.\n\n Parameters:\n string_list (list of str): List of strings to be reversed.\n\n Returns:\n list of str: List of reversed strings.\n \"\"\"\n # Reverse each string in the list using a list comprehension\n reversed_list = [s[::-1] for s in string_list]\n return reversed_list", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(lst):\n return [s[::-1] for s in lst]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n # Reversing each string in the list using a list comprehension\n reversed_list = [s[::-1] for s in string_list]\n return reversed_list", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(lst):\n return [word[::-1] for word in lst]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n # Using list comprehension to reverse each string in the input list\n return [s[::-1] for s in string_list]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(str_list):\n \"\"\"\n This function takes a list of strings and returns a new list with each string reversed.\n \"\"\"\n return [s[::-1] for s in str_list]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n \"\"\"\n Function to reverse each string in a given list of string values.\n\n :param string_list: List of string values\n :return: List of reversed string values\n \"\"\"\n reversed_list = [s[::-1] for s in string_list]\n return reversed_list", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(str_list):\n \"\"\"\n This function takes a list of strings and returns a new list with each string reversed.\n\n Parameters:\n str_list (list): List of strings to be reversed.\n\n Returns:\n list: List of reversed strings.\n \"\"\"\n reversed_list = [s[::-1] for s in str_list]\n return reversed_list", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(strings):\n # Use list comprehension to reverse each string in the list\n return [string[::-1] for string in strings]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(str_list):\n return [s[::-1] for s in str_list]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n \"\"\"\n Reverse each string in the given list of string values.\n\n Parameters:\n string_list (list of str): List of string values to be reversed.\n\n Returns:\n list of str: List of reversed string values.\n \"\"\"\n return [s[::-1] for s in string_list]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n return [s[::-1] for s in string_list]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(lst):\n # Using a list comprehension to reverse each string in the given list\n return [s[::-1] for s in lst]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(str_list):\n \"\"\"\n Reverses each string in a given list of string values.\n\n Parameters:\n str_list (list): List of strings to be reversed.\n\n Returns:\n list: A new list with each string reversed.\n \"\"\"\n return [s[::-1] for s in str_list]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(strings):\n return [s[::-1] for s in strings]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n \"\"\"\n Reverses each string in the given list of string values.\n\n Parameters:\n string_list (list): A list of string values.\n\n Returns:\n list: A list with each string reversed.\n \"\"\"\n reversed_list = [s[::-1] for s in string_list]\n return reversed_list", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(lst):\n return [word[::-1] for word in lst]", "matching_cluster_idx": 4}]}, "Mbpp/460": {"dps": 79.23076923076923, "dps_norm": 92.0, "pass@1": 68.0, "profiled": [{"solution": "def Extract(sublists):\n \"\"\"\n Get the first element of each sublist.\n\n :param sublists: List of sublists\n :return: List containing the first element of each sublist\n \"\"\"\n return [sublist[0] for sublist in sublists if sublist]", "matching_cluster_idx": 3}, {"solution": "def Extract(lst):\n \"\"\"\n Extracts the first element of each sublist.\n\n Parameters:\n lst (list): A list of lists (sublists).\n\n Returns:\n list: A list containing the first element of each sublist.\n \"\"\"\n return [sublist[0] for sublist in lst]", "matching_cluster_idx": 4}, {"solution": "def Extract(lst):\n \"\"\"\n This function takes a list of sublists and returns a list containing the first element of each sublist.\n \"\"\"\n return [sublist[0] for sublist in lst]", "matching_cluster_idx": 4}, {"solution": "def Extract(sublists):\n return [sublist[0] for sublist in sublists if sublist]", "matching_cluster_idx": 3}, {"solution": "def Extract(lst):\n \"\"\"\n Function to get the first element of each sublist.\n \"\"\"\n return [sublist[0] for sublist in lst if sublist]", "matching_cluster_idx": 3}, {"solution": "def Extract(lst):\n return [sublist[0] for sublist in lst]", "matching_cluster_idx": 4}, {"solution": "def Extract(lst):\n return [sublist[0] for sublist in lst]", "matching_cluster_idx": 4}, {"solution": "def Extract(list_of_lists):\n \"\"\"\n This function takes a list of lists and returns a new list containing the first element of each sublist.\n\n Parameters:\n list_of_lists (list of list): The input list of lists.\n\n Returns:\n list: A list containing the first element of each sublist.\n \"\"\"\n return [sublist[0] for sublist in list_of_lists]", "matching_cluster_idx": 4}, {"solution": "def Extract(lst):\n \"\"\"\n Function to extract the first element of each sublist.\n\n :param lst: List of lists\n :return: List containing the first element of each sublist\n \"\"\"\n return [sublist[0] for sublist in lst if sublist]", "matching_cluster_idx": 3}, {"solution": "def Extract(sublists):\n \"\"\"\n Get the first element of each sublist.\n \"\"\"\n return [sublist[0] for sublist in sublists]", "matching_cluster_idx": 4}, {"solution": "def Extract(lst):\n return [sublist[0] for sublist in lst]", "matching_cluster_idx": 4}, {"solution": "def Extract(lst):\n return [sublist[0] for sublist in lst if sublist]", "matching_cluster_idx": 3}, {"solution": "def Extract(lst):\n return [sublist[0] for sublist in lst]", "matching_cluster_idx": 4}, {"solution": "def Extract(lst):\n return [sublist[0] for sublist in lst]", "matching_cluster_idx": 4}, {"solution": "def Extract(lst):\n \"\"\"\n This function returns the first element of each sublist.\n\n Parameters:\n lst (list of lists): The list of sublists to extract the first element from.\n\n Returns:\n list: A list containing the first element of each sublist.\n \"\"\"\n return [sublist[0] for sublist in lst]", "matching_cluster_idx": 4}, {"solution": "def Extract(lst):\n return [sublist[0] for sublist in lst]", "matching_cluster_idx": 4}, {"solution": "def Extract(lst):\n # Using list comprehension to get the first element of each sublist\n return [sublist[0] for sublist in lst if sublist]", "matching_cluster_idx": 3}, {"solution": "def Extract(lst):\n return [sublist[0] for sublist in lst if sublist]", "matching_cluster_idx": 3}, {"solution": "def Extract(lst):\n \"\"\"\n Function to get the first element of each sublist.\n :param lst: List of lists\n :return: List containing the first element of each sublist\n \"\"\"\n return [sublist[0] for sublist in lst if sublist]", "matching_cluster_idx": 3}, {"solution": "def Extract(lst):\n return [sublist[0] for sublist in lst]", "matching_cluster_idx": 4}]}, "Mbpp/474": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def replace_char(s, old, new):\n return s.replace(old, new)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, old, new):\n \"\"\"\n Replace all occurrences of the character `old` with the character `new` in the string `s`.\n\n :param s: Original string\n :param old: Character to be replaced\n :param new: Character to replace with\n :return: New string with replacements made\n \"\"\"\n return s.replace(old, new)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, char_to_replace, char_replacement):\n \"\"\"\n Replaces all occurrences of char_to_replace in string s with char_replacement.\n\n Parameters:\n s (str): The original string.\n char_to_replace (str): The character to be replaced.\n char_replacement (str): The character to replace with.\n\n Returns:\n str: The new string with replacements made.\n \"\"\"\n return s.replace(char_to_replace, char_replacement)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, char_old, char_new):\n return s.replace(char_old, char_new)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, old, new):\n \"\"\"\n Replace all occurrences of a character in a string.\n\n :param s: The original string.\n :param old: The character to be replaced.\n :param new: The character to replace with.\n :return: The modified string with replacements made.\n \"\"\"\n return s.replace(old, new)", "matching_cluster_idx": 6}, {"solution": "def replace_char(input_str, old_char, new_char):\n \"\"\"\n Replaces all occurrences of old_char in input_str with new_char.\n\n Args:\n input_str (str): The input string.\n old_char (str): The character to be replaced.\n new_char (str): The character to replace with.\n\n Returns:\n str: The modified string with old_char replaced by new_char.\n \"\"\"\n return input_str.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, old, new):\n \"\"\"\n Replace all occurrences of 'old' character with 'new' character in the string 's'.\n\n Args:\n s (str): The input string.\n old (str): The character to be replaced.\n new (str): The character to replace with.\n\n Returns:\n str: The resulting string after replacement.\n \"\"\"\n return s.replace(old, new)", "matching_cluster_idx": 6}, {"solution": "def replace_char(string, char_to_replace, replacement_char):\n return string.replace(char_to_replace, replacement_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, old_char, new_char):\n return s.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(original_string, char_to_replace, replacement_char):\n return original_string.replace(char_to_replace, replacement_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, old, new):\n \"\"\"\n Replaces all occurrences of the character old with the character new in the string s.\n\n Parameters:\n s (str): The original string.\n old (str): The character to replace.\n new (str): The character to replace with.\n\n Returns:\n str: The modified string with replacements.\n \"\"\"\n return s.replace(old, new)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, char_to_replace, new_char):\n return s.replace(char_to_replace, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(string, old_char, new_char):\n return string.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(input_string, old_char, new_char):\n return input_string.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(string, old_char, new_char):\n \"\"\"\n Replaces all occurrences of old_char in the string with new_char.\n\n Parameters:\n string (str): The original string.\n old_char (str): The character to be replaced.\n new_char (str): The character to replace with.\n\n Returns:\n str: The modified string.\n \"\"\"\n return string.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, old_char, new_char):\n return s.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, old, new):\n \"\"\"\n Replaces all occurrences of a character in a string with another character.\n\n :param s: The original string\n :param old: The character to replace\n :param new: The character to replace with\n :return: The modified string with replacements\n \"\"\"\n return s.replace(old, new)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, old, new):\n \"\"\"\n Replaces all occurrences of old character with new character in the string s.\n\n :param s: The original string.\n :param old: The character to be replaced.\n :param new: The character to replace with.\n :return: A new string with the character replaced.\n \"\"\"\n return s.replace(old, new)", "matching_cluster_idx": 6}, {"solution": "def replace_char(input_string, old_char, new_char):\n \"\"\"\n Replace all occurrences of old_char in the input_string with new_char.\n\n Args:\n input_string (str): The string to be processed.\n old_char (str): The character to be replaced.\n new_char (str): The character to replace with.\n\n Returns:\n str: The modified string with replacements.\n \"\"\"\n return input_string.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(string, old_char, new_char):\n return string.replace(old_char, new_char)", "matching_cluster_idx": 6}]}, "Mbpp/476": {"dps": 90.53691275167785, "dps_norm": 95.0, "pass@1": 100.0, "profiled": [{"solution": "def big_sum(array):\n \"\"\"\n Function to find the sum of the largest and smallest value in a given array.\n\n Parameters:\n array (list): A list of integers\n\n Returns:\n int: Sum of the largest and smallest values in the array\n \"\"\"\n if not array:\n raise ValueError(\"The array should not be empty.\")\n\n largest = max(array)\n smallest = min(array)\n\n return largest + smallest", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n \"\"\"\n This function returns the sum of the largest and smallest value in a given array.\n \"\"\"\n if not arr: # Check if the array is empty\n raise ValueError(\"The array must contain at least one element.\")\n\n # Find the smallest and largest values in the array\n smallest = min(arr)\n largest = max(arr)\n\n return smallest + largest", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n if not arr: # Handle case for empty array\n return None\n\n smallest = min(arr)\n largest = max(arr)\n\n return smallest + largest", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n # Check if the array is not empty\n if not arr:\n return None\n # Return the sum of the largest and smallest values in the array\n return max(arr) + min(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n \"\"\"\n Function to find the sum of the largest and smallest value in a given array.\n :param arr: List of integers\n :return: Sum of the largest and smallest values in the array\n \"\"\"\n if len(arr) < 2:\n raise ValueError(\"Array must contain at least two elements.\")\n\n max_val = max(arr)\n min_val = min(arr)\n\n return max_val + min_val", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n \"\"\"\n This function takes an array as input and returns the sum of the largest and smallest value in it.\n \"\"\"\n if not arr:\n return 0 # Return 0 for an empty array\n return max(arr) + min(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n \"\"\"\n This function finds the sum of the largest and smallest value in a given array.\n\n Parameters:\n arr (list): A list of numbers.\n\n Returns:\n int: The sum of the largest and smallest values in the array.\n \"\"\"\n # Check if array is empty\n if len(arr) == 0:\n raise ValueError(\"Array must contain at least one element.\")\n\n # Find the minimum and maximum values in the array\n min_value = min(arr)\n max_value = max(arr)\n\n # Return the sum of the minimum and maximum values\n return min_value + max_value", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n if not arr:\n return None # Return None if the array is empty\n return max(arr) + min(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n \"\"\"\n Find the sum of the largest and smallest value in a given array.\n :param arr: List of integers\n :return: Sum of the largest and smallest value\n \"\"\"\n if not arr:\n raise ValueError(\"Array should not be empty\")\n\n max_val = max(arr)\n min_val = min(arr)\n\n return max_val + min_val", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n return max(arr) + min(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n return max(arr) + min(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n \"\"\"\n Find the sum of the largest and smallest value in a given array.\n\n :param arr: List of integers\n :return: Sum of the largest and smallest values in the array\n \"\"\"\n if not arr:\n return None # Return None if the array is empty\n return max(arr) + min(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n if not arr: # Check if array is empty\n return 0\n return max(arr) + min(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n # Checking if the list is empty or has one element\n if len(arr) == 0:\n return 0\n elif len(arr) == 1:\n return arr[0] * 2 # If the list contains only one element, its smallest and largest value is the same\n\n smallest = arr[0]\n largest = arr[0]\n for num in arr:\n if num < smallest:\n smallest = num\n if num > largest:\n largest = num\n\n return smallest + largest", "matching_cluster_idx": 3}, {"solution": "def big_sum(arr):\n return max(arr) + min(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n \"\"\"\n This function calculates the sum of the largest and smallest value in a given array.\n \"\"\"\n if not arr: # Check if the array is empty\n return None\n\n # Find the largest and smallest values in the array\n largest = max(arr)\n smallest = min(arr)\n\n # Return the sum of the largest and smallest values\n return largest + smallest", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n \"\"\"\n Find the sum of the largest and smallest value in a given array.\n \"\"\"\n if len(arr) == 0:\n raise ValueError(\"Array must not be empty\")\n\n min_val = max_val = arr[0]\n\n for num in arr:\n if num < min_val:\n min_val = num\n if num > max_val:\n max_val = num\n\n return min_val + max_val", "matching_cluster_idx": 3}, {"solution": "def big_sum(arr):\n \"\"\"\n This function takes an array as input and returns the sum of the largest and smallest value in the array.\n \"\"\"\n if len(arr) < 1:\n raise ValueError(\"Array must contain at least one number.\")\n return max(arr) + min(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n \"\"\"\n Function to find the sum of the largest and smallest value in a given array.\n\n Parameters:\n arr (list of int): Input list of integers.\n\n Returns:\n int: Sum of the largest and smallest values in the array.\n \"\"\"\n if len(arr) == 0:\n raise ValueError(\"Array must not be empty\")\n\n smallest = float('inf')\n largest = float('-inf')\n\n for num in arr:\n if num < smallest:\n smallest = num\n if num > largest:\n largest = num\n\n return smallest + largest", "matching_cluster_idx": 3}, {"solution": "def big_sum(arr):\n \"\"\"\n This function finds the sum of the largest and smallest value in a given array.\n :param arr: List[int]\n :return: int - sum of largest and smallest values\n \"\"\"\n if len(arr) == 0:\n raise ValueError(\"The array should not be empty\")\n\n smallest = min(arr)\n largest = max(arr)\n\n return smallest + largest", "matching_cluster_idx": 5}]}, "Mbpp/477": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def is_lower(input_string):\n return input_string.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(string):\n \"\"\"\n Convert the given string to lower case.\n\n Args:\n string (str): The input string to be converted to lower case.\n\n Returns:\n str: The lower case version of the input string.\n \"\"\"\n return string.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(input_string):\n \"\"\"\n Convert the given string to lower case.\n\n Parameters:\n input_string (str): The string to convert to lower case.\n\n Returns:\n str: The input string in lower case.\n \"\"\"\n return input_string.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(input_string):\n \"\"\"\n Convert the given string to lower case.\n\n Parameters:\n input_string (str): The string to convert to lower case.\n\n Returns:\n str: The string in lower case.\n \"\"\"\n return input_string.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(input_string):\n \"\"\"\n This function converts the input string to lower case.\n\n Parameters:\n input_string (str): The string to be converted.\n\n Returns:\n str: The lower case version of the input string.\n \"\"\"\n return input_string.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(input_string):\n \"\"\"\n This function converts the given string to lower case.\n\n :param input_string: The string to be converted.\n :return: The lower case version of the input string.\n \"\"\"\n return input_string.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(input_string):\n \"\"\"\n Convert the given string to lower case.\n\n Parameters:\n input_string (str): The string to be converted.\n\n Returns:\n str: The lowercase version of the input string.\n \"\"\"\n return input_string.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(input_string):\n \"\"\"\n Convert the given string to lower case.\n \"\"\"\n return input_string.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(string):\n \"\"\"\n Convert the given string to lower case.\n\n Parameters:\n string (str): The input string to be converted to lower case.\n\n Returns:\n str: The lower case version of the input string.\n \"\"\"\n return string.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(input_string):\n \"\"\"\n This function takes a string and returns it in lowercase.\n \"\"\"\n return input_string.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(input_string):\n return input_string.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n \"\"\"\n Convert the given string to lower case.\n\n Args:\n s (str): The input string.\n\n Returns:\n str: The lower case version of the input string.\n \"\"\"\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s: str) -> str:\n \"\"\"\n Convert the given string to lower case.\n\n :param s: The input string.\n :return: The input string in lower case.\n \"\"\"\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(string):\n \"\"\"\n Convert the given string to lower case.\n\n Args:\n string (str): The string to convert to lower case.\n\n Returns:\n str: The string in lower case.\n \"\"\"\n return string.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(input_string):\n return input_string.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(input_string):\n \"\"\"\n This function converts the given string to lower case.\n\n Args:\n input_string (str): The input string to be converted to lower case.\n\n Returns:\n str: The lowercase version of the input string.\n \"\"\"\n return input_string.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n \"\"\"\n Convert the given string to lower case.\n\n Parameters:\n s (str): The input string to be converted.\n\n Returns:\n str: The input string converted to lower case.\n \"\"\"\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(string: str) -> str:\n \"\"\"\n Convert the given string to lower case.\n\n Parameters:\n string (str): The input string.\n\n Returns:\n str: The string converted to lower case.\n \"\"\"\n return string.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(input_string):\n \"\"\"\n This function converts the given string to lower case.\n\n Parameters:\n input_string (str): The input string to be converted.\n\n Returns:\n str: The input string converted to lower case.\n \"\"\"\n return input_string.lower()", "matching_cluster_idx": 4}]}, "Mbpp/563": {"dps": 85.24590163934427, "dps_norm": 81.81818181818181, "pass@1": 99.0, "profiled": [{"solution": "def extract_values(s):\n \"\"\"\n This function extracts values between quotation marks from a string.\n \"\"\"\n import re\n return re.findall(r'\"(.*?)\"', s)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(s):\n \"\"\"\n Extracts values between quotation marks from a string.\n \"\"\"\n return re.findall(r'\"(.*?)\"', s)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(s):\n return re.findall(r'\"(.*?)\"', s)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(input_string):\n # Using regex to find all the values inside double quotation marks\n return re.findall(r'\"(.*?)\"', input_string)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(string):\n # Use regular expression to find all substrings enclosed in double quotes\n matches = re.findall(r'\"([^\"]*)\"', string)\n return matches", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(input_string):\n \"\"\"\n This function extracts values between quotation marks from a given string.\n\n Args:\n input_string (str): The input string containing quoted values.\n\n Returns:\n list: A list of values extracted from between the quotation marks.\n \"\"\"\n # Use regex to find all quoted values\n values = re.findall(r'\"([^\"]*)\"', input_string)\n return values", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(s):\n return re.findall(r'\"(.*?)\"', s)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(s):\n # Find all strings enclosed within double quotes using a regular expression\n return re.findall(r'\"(.*?)\"', s)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(input_string):\n return re.findall(r'\"(.*?)\"', input_string)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(string):\n \"\"\"\n Extract values between quotation marks from a string.\n\n Args:\n string (str): The input string.\n\n Returns:\n list: A list of values extracted from the string.\n \"\"\"\n # Regular expression to find quoted strings\n return re.findall(r'\"(.*?)\"', string)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(input_string):\n # Use regular expression to find all values enclosed in double quotation marks\n return re.findall(r'\"(.*?)\"', input_string)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(input_string):\n \"\"\"Extracts values between quotation marks from a string.\"\"\"\n pattern = r'\"(.*?)\"'\n matches = re.findall(pattern, input_string)\n return matches", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(input_string):\n # Use regex to find all substrings enclosed in quotation marks\n matches = re.findall(r'\"(.*?)\"', input_string)\n return matches", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(input_string):\n # Use regular expression to find all quoted substrings\n return re.findall(r'\"(.*?)\"', input_string)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(input_string):\n \"\"\"\n Extracts values between quotation marks from a string.\n\n :param input_string: The string containing values in quotation marks.\n :return: A list of values extracted from the string.\n \"\"\"\n return re.findall(r'\"([^\"]*)\"', input_string)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(s):\n return re.findall(r'\"(.*?)\"', s)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(input_string):\n # Using regular expressions to find all substrings between quotation marks\n return re.findall(r'\"(.*?)\"', input_string)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(s):\n return re.findall(r'\"(.*?)\"', s)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(input_string):\n \"\"\"\n This function extracts values between quotation marks from a string.\n\n Parameters:\n input_string (str): The input string containing values within quotation marks.\n\n Returns:\n list: A list of extracted values.\n \"\"\"\n # Use regex to find all patterns enclosed in quotation marks\n pattern = r'\"([^\"]*)\"'\n matches = re.findall(pattern, input_string)\n return matches", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(input_string):\n # Using a regular expression to find all values enclosed in double quotes\n return re.findall(r'\"([^\"]*)\"', input_string)", "matching_cluster_idx": 8}]}, "Mbpp/572": {"dps": 95.80246913580247, "dps_norm": 87.85714285714285, "pass@1": 98.0, "profiled": [{"solution": "from collections import Counter\ndef two_unique_nums(nums):\n \"\"\"\n This function removes numbers that occur more than once from a list.\n :param nums: List of numbers\n :return: List of numbers with duplicates removed\n \"\"\"\n # Count occurrences of each number in the list\n counts = Counter(nums)\n\n # Include only numbers that occur exactly once\n return [num for num in nums if counts[num] == 1]", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(numbers):\n # Count occurrences of each number\n num_counts = {}\n for num in numbers:\n if num in num_counts:\n num_counts[num] += 1\n else:\n num_counts[num] = 1\n\n # Collect numbers that appear exactly once\n unique_nums = [num for num in numbers if num_counts[num] == 1]\n\n return unique_nums", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(lst):\n \"\"\"\n This function removes duplicate numbers from the given list and returns\n a new list containing the numbers that appear only once.\n \"\"\"\n # Count occurrences of each element\n count_dict = {}\n for num in lst:\n if num in count_dict:\n count_dict[num] += 1\n else:\n count_dict[num] = 1\n\n # Collect numbers that appear only once\n unique_nums = [num for num, count in count_dict.items() if count == 1]\n\n return unique_nums", "matching_cluster_idx": 5}, {"solution": "from collections import Counter\ndef two_unique_nums(nums):\n counts = Counter(nums)\n return [num for num in counts if counts[num] == 1]", "matching_cluster_idx": 6}, {"solution": "def two_unique_nums(input_list):\n from collections import Counter\n\n # Use Counter to count occurrences of each number\n counter = Counter(input_list)\n\n # Get numbers that only occur once\n unique_nums = [num for num in counter if counter[num] == 1]\n\n return unique_nums", "matching_cluster_idx": 6}, {"solution": "from typing import List\nfrom collections import Counter\ndef two_unique_nums(nums: List[int]) -> List[int]:\n # Count occurrences of each number in the list\n count = Counter(nums)\n\n # Return only the numbers that appear exactly once\n return [num for num in nums if count[num] == 1]", "matching_cluster_idx": 5}, {"solution": "from collections import Counter\ndef two_unique_nums(lst):\n \"\"\"\n Given a list of numbers, this function removes the numbers that appear more than once.\n\n Parameters:\n lst (list): A list of numbers\n\n Returns:\n list: A list of numbers that appear only once in the input list.\n \"\"\"\n # Count the occurrences of each number in the list\n count = Counter(lst)\n\n # Filter out numbers that appear more than once\n result = [num for num in lst if count[num] == 1]\n\n return result", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(numbers):\n \"\"\"\n This function removes duplicate numbers from a given list.\n \"\"\"\n from collections import Counter\n # Create a counter for the list\n count = Counter(numbers)\n # Return the list of elements that have a count of 1\n return [num for num in numbers if count[num] == 1]", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(lst):\n \"\"\"\n Function to remove duplicate numbers from a given list.\n Returns a list of elements that appear only once.\n\n :param lst: List of numbers\n :return: List of unique numbers\n \"\"\"\n from collections import Counter\n\n # Create a Counter object to count occurrences of each number\n count = Counter(lst)\n\n # Filter and return numbers that appear exactly once\n unique_nums = [num for num in lst if count[num] == 1]\n\n return unique_nums", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(lst):\n counter = {}\n for num in lst:\n counter[num] = counter.get(num, 0) + 1\n\n result = [num for num in lst if counter[num] == 1]\n return result", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(nums):\n \"\"\"\n Remove duplicate numbers from a given list and return a list of numbers that appear only once.\n\n Parameters:\n nums (list): List of integers.\n\n Returns:\n list: List of integers that appear only once in the input list.\n \"\"\"\n # Count occurrences of each number\n count = {}\n for num in nums:\n count[num] = count.get(num, 0) + 1\n\n # Collect numbers that appear only once\n unique_nums = [num for num in count if count[num] == 1]\n\n return unique_nums", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef two_unique_nums(nums: List[int]) -> List[int]:\n counts = {}\n result = []\n\n # Count occurrences of each number\n for num in nums:\n if num in counts:\n counts[num] += 1\n else:\n counts[num] = 1\n\n # Collect numbers that appear exactly twice\n for num, count in counts.items():\n if count == 1:\n result.append(num)\n\n return result", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(nums):\n from collections import Counter\n\n # Count the frequency of each number\n counts = Counter(nums)\n\n # Return only the numbers that appear exactly once\n return [num for num, count in counts.items() if count == 1]", "matching_cluster_idx": 6}, {"solution": "def two_unique_nums(nums):\n \"\"\"\n Remove duplicate numbers from a given list and return unique numbers\n that appeared exactly twice.\n\n Args:\n nums (list): A list of integers.\n\n Returns:\n list: A list of unique numbers that appeared exactly twice.\n \"\"\"\n # Create a dictionary to count occurrences of each number\n count_dict = {}\n\n # Count occurrences\n for num in nums:\n if num in count_dict:\n count_dict[num] += 1\n else:\n count_dict[num] = 1\n\n # Collect numbers that appeared exactly twice\n result = [num for num, count in count_dict.items() if count == 1]\n\n return result", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(nums):\n unique_count = {}\n for num in nums:\n if num in unique_count:\n unique_count[num] += 1\n else:\n unique_count[num] = 1\n result = [num for num in nums if unique_count[num] == 1]\n return result", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(lst):\n \"\"\"\n This function takes a list of numbers and returns a list with only\n the numbers that appear exactly once in the original list.\n \"\"\"\n count = {}\n result = []\n\n # Count the frequency of each number in the list\n for num in lst:\n if num in count:\n count[num] += 1\n else:\n count[num] = 1\n\n # Add numbers that appear exactly once to the result list\n for num, freq in count.items():\n if freq == 1:\n result.append(num)\n\n return result", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(nums):\n # Use a dictionary to keep track of the frequency of each number\n freq = {}\n for num in nums:\n if num in freq:\n freq[num] += 1\n else:\n freq[num] = 1\n\n # Extract the numbers that appear exactly once\n unique_nums = [num for num in nums if freq[num] == 1]\n return unique_nums", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(nums):\n # Create a dictionary to count the occurrences of each number\n counts = {}\n for num in nums:\n if num in counts:\n counts[num] += 1\n else:\n counts[num] = 1\n\n # Create a list to hold numbers that appear only once\n result = []\n for num, count in counts.items():\n if count == 1:\n result.append(num)\n\n return result", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(nums):\n # Create a dictionary to count occurrences of each number\n count_dict = {}\n for num in nums:\n count_dict[num] = count_dict.get(num, 0) + 1\n\n # Collect numbers that occur exactly once\n unique_nums = [num for num in count_dict if count_dict[num] == 1]\n\n return unique_nums", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(lst):\n counts = {}\n for num in lst:\n counts[num] = counts.get(num, 0) + 1\n\n unique_nums = [num for num, count in counts.items() if count == 1]\n return unique_nums", "matching_cluster_idx": 5}]}, "Mbpp/578": {"dps": 68.11111111111111, "dps_norm": 66.36363636363636, "pass@1": 100.0, "profiled": [{"solution": "def interleave_lists(list1, list2, list3):\n interleaved_list = []\n for elements in zip(list1, list2, list3):\n interleaved_list.extend(elements)\n return interleaved_list", "matching_cluster_idx": 8}, {"solution": "def interleave_lists(list1, list2, list3):\n if len(list1) != len(list2) or len(list2) != len(list3):\n raise ValueError(\"All lists must have the same length\")\n\n interleaved_list = []\n for i in range(len(list1)):\n interleaved_list.append(list1[i])\n interleaved_list.append(list2[i])\n interleaved_list.append(list3[i])\n\n return interleaved_list", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(lst1, lst2, lst3):\n return [item for triplet in zip(lst1, lst2, lst3) for item in triplet]", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(list1, list2, list3):\n return [item for sublist in zip(list1, list2, list3) for item in sublist]", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(list1, list2, list3):\n if len(list1) != len(list2) or len(list1) != len(list3):\n raise ValueError(\"All lists must have the same length\")\n\n return [elem for sublist in zip(list1, list2, list3) for elem in sublist]", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(list1, list2, list3):\n interleaved = []\n for i in range(len(list1)):\n interleaved.append(list1[i])\n interleaved.append(list2[i])\n interleaved.append(list3[i])\n return interleaved", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n # Check that all lists are of the same length\n if len(list1) != len(list2) or len(list1) != len(list3):\n raise ValueError(\"All lists must be of the same length\")\n\n interleaved_list = []\n for i in range(len(list1)):\n interleaved_list.append(list1[i])\n interleaved_list.append(list2[i])\n interleaved_list.append(list3[i])\n\n return interleaved_list", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"\n Interleave three lists into a single flat list.\n\n Parameters:\n list1 (list): The first list of elements.\n list2 (list): The second list of elements.\n list3 (list): The third list of elements.\n\n Returns:\n list: A single interleaved list.\n \"\"\"\n interleaved_list = []\n for i in range(len(list1)):\n interleaved_list.append(list1[i])\n interleaved_list.append(list2[i])\n interleaved_list.append(list3[i])\n return interleaved_list", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"\n Interleave three lists of the same length into a single flat list.\n\n Parameters:\n list1 (list): The first list to be interleaved.\n list2 (list): The second list to be interleaved.\n list3 (list): The third list to be interleaved.\n\n Returns:\n list: A single interleaved list containing elements from the three input lists.\n \"\"\"\n interleaved_list = []\n\n # Ensure all lists are of the same length\n length = len(list1)\n\n for i in range(length):\n interleaved_list.append(list1[i])\n interleaved_list.append(list2[i])\n interleaved_list.append(list3[i])\n\n return interleaved_list", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"\n Interleave three lists of the same length into a single flat list.\n \"\"\"\n interleaved_list = []\n for i in range(len(list1)):\n interleaved_list.append(list1[i])\n interleaved_list.append(list2[i])\n interleaved_list.append(list3[i])\n return interleaved_list", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"\n Interleaves 3 lists of the same length into a single flat list.\n\n :param list1: First list to interleave\n :param list2: Second list to interleave\n :param list3: Third list to interleave\n :return: A single list containing elements from list1, list2, and list3 interleaved\n \"\"\"\n # Check if all lists have the same length\n if not (len(list1) == len(list2) == len(list3)):\n raise ValueError(\"All lists must have the same length\")\n\n # Initialize an empty list to hold the result\n interleaved_list = []\n\n # Interleave the elements from all three lists\n for a, b, c in zip(list1, list2, list3):\n interleaved_list.append(a)\n interleaved_list.append(b)\n interleaved_list.append(c)\n\n return interleaved_list", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(lst1, lst2, lst3):\n \"\"\"\n This function takes three lists of equal length and interleaves them into a single flat list.\n \"\"\"\n interleaved = []\n\n for i in range(len(lst1)):\n interleaved.append(lst1[i])\n interleaved.append(lst2[i])\n interleaved.append(lst3[i])\n\n return interleaved", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n # Ensure all lists have the same length\n if len(list1) != len(list2) or len(list1) != len(list3):\n raise ValueError(\"All lists must have the same length.\")\n\n # Create an empty list to store the interleaved elements\n interleaved_list = []\n\n # Interleave the elements from the three lists\n for i in range(len(list1)):\n interleaved_list.append(list1[i])\n interleaved_list.append(list2[i])\n interleaved_list.append(list3[i])\n\n return interleaved_list", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"\n Interleaves three lists of the same length into a single flat list.\n\n Args:\n list1 (list): The first list.\n list2 (list): The second list.\n list3 (list): The third list.\n\n Returns:\n list: A single flat list containing interleaved elements from the three input lists.\n \"\"\"\n if len(list1) != len(list2) or len(list2) != len(list3):\n raise ValueError(\"All lists must have the same length.\")\n\n interleaved = []\n for i in range(len(list1)):\n interleaved.append(list1[i])\n interleaved.append(list2[i])\n interleaved.append(list3[i])\n\n return interleaved", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"\n Interleave three lists of the same length into a single flat list.\n \"\"\"\n if not (len(list1) == len(list2) == len(list3)):\n raise ValueError(\"All input lists must have the same length.\")\n\n interleaved_list = []\n for i in range(len(list1)):\n interleaved_list.append(list1[i])\n interleaved_list.append(list2[i])\n interleaved_list.append(list3[i])\n\n return interleaved_list", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"\n This function interleaves three lists of the same length into a single flat list.\n \"\"\"\n if not (len(list1) == len(list2) == len(list3)):\n raise ValueError(\"All lists must have the same length\")\n\n interleaved_list = []\n for i in range(len(list1)):\n interleaved_list.append(list1[i])\n interleaved_list.append(list2[i])\n interleaved_list.append(list3[i])\n\n return interleaved_list", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(lst1, lst2, lst3):\n \"\"\"\n Interleaves three lists into a single flat list.\n\n Parameters:\n lst1 (list): The first list.\n lst2 (list): The second list.\n lst3 (list): The third list.\n\n Returns:\n list: The interleaved list.\n \"\"\"\n interleaved_list = []\n for item1, item2, item3 in zip(lst1, lst2, lst3):\n interleaved_list.extend([item1, item2, item3])\n return interleaved_list", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"\n Interleaves three lists of the same length into a single flat list.\n\n :param list1: The first list to be interleaved.\n :param list2: The second list to be interleaved.\n :param list3: The third list to be interleaved.\n :return: A flat list with the elements of list1, list2, and list3 interleaved.\n \"\"\"\n if not (len(list1) == len(list2) == len(list3)):\n raise ValueError(\"All lists must have the same length\")\n\n interleaved_list = []\n for i in range(len(list1)):\n interleaved_list.append(list1[i])\n interleaved_list.append(list2[i])\n interleaved_list.append(list3[i])\n\n return interleaved_list", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"\n Interleave three lists of the same length into a single flat list.\n\n Parameters:\n list1, list2, list3 (list): Input lists of the same length.\n\n Returns:\n list: A single interleaved list.\n \"\"\"\n if not (len(list1) == len(list2) == len(list3)):\n raise ValueError(\"All input lists must have the same length\")\n\n interleaved_list = []\n for i in range(len(list1)):\n interleaved_list.append(list1[i])\n interleaved_list.append(list2[i])\n interleaved_list.append(list3[i])\n\n return interleaved_list", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n if not (len(list1) == len(list2) == len(list3)):\n raise ValueError(\"All lists must have the same length\")\n\n interleaved_list = []\n for i in range(len(list1)):\n interleaved_list.extend([list1[i], list2[i], list3[i]])\n\n return interleaved_list", "matching_cluster_idx": 6}]}, "Mbpp/586": {"dps": 98.83040935672514, "dps_norm": 87.5, "pass@1": 54.0, "profiled": [{"solution": "def split_Arr(arr, n):\n \"\"\"\n Splits the list at the nth element and adds the first part to the end.\n\n Parameters:\n arr (list): List of elements to be split.\n n (int): Index at which to split the list.\n\n Returns:\n list: The rearranged list.\n \"\"\"\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"\n Split a list at the nth element and add the first part to the end.\n\n Parameters:\n arr (list): The list to split and reorder.\n n (int): The index at which to split the list.\n\n Returns:\n list: The reordered list.\n \"\"\"\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n if n < 0 or n > len(arr):\n raise ValueError(\"n is out of bounds\")\n\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n if n < 0 or n > len(arr):\n return \"Invalid input. n should be within the range of the list length.\"\n else:\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"\n Splits the array at the nth element and moves the first part to the end.\n\n Parameters:\n arr (list): The list to be split.\n n (int): The position at which to split the list.\n\n Returns:\n list: The rearranged list.\n \"\"\"\n if not arr or n >= len(arr) or n < 0:\n return arr\n\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"\n Function to split a list at the nth element and add the first part to the end.\n\n Parameters:\n arr (list): The list to be split.\n n (int): The position at which to split the list.\n\n Returns:\n list: The rearranged list.\n \"\"\"\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"\n Split the list at the nth element and add the first part to the end.\n\n :param arr: List of integers to be split.\n :param n: Position at which the list is to be split.\n :return: The rearranged list.\n \"\"\"\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"\n Splits the list at the nth element and appends the first part to the end.\n\n Parameters:\n arr (list): List to be split.\n n (int): Index at which to split the list.\n\n Returns:\n list: New list with the first part moved to the end.\n \"\"\"\n if n < 0 or n > len(arr):\n raise ValueError(\"Index out of bounds\")\n\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"\n This function splits the list at the nth element and adds the first part to the end.\n\n Parameters:\n arr (list): The original list to be split.\n n (int): The position to split the list.\n\n Returns:\n list: The rearranged list.\n \"\"\"\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"\n Function to split a list at the nth element and add the first part to the end.\n\n Parameters:\n arr (list): The list to be split and rearranged.\n n (int): The index at which to split the list.\n\n Returns:\n list: The rearranged list.\n \"\"\"\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"\n Splits a list at the nth element and adds the first part to the end.\n\n Parameters:\n arr (list): The original list to be split.\n n (int): The index at which to split the list.\n\n Returns:\n list: The rearranged list.\n \"\"\"\n # Split the list at the nth element\n first_part = arr[:n]\n second_part = arr[n:]\n\n # Combine the second part with the first part\n return second_part + first_part", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"\n Split a list at the nth element and add the first part to the end.\n :param arr: List of elements to be split.\n :param n: The position at which to split the list.\n :return: A new list with the first part added to the end.\n \"\"\"\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"\n Splits a list at the nth element and adds the first part to the end.\n\n :param arr: List of elements\n :param n: Index at which to split\n :return: List with the first part added to the end\n \"\"\"\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"\n This function splits a list at the nth element and moves the first part to the end.\n\n Parameters:\n arr (list): The list to be split and rearranged.\n n (int): The index at which to split the list.\n\n Returns:\n list: The rearranged list.\n \"\"\"\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n if n > len(arr) or n < 0:\n raise ValueError(\"n is out of the bounds of the array\")\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"\n Split the list at the nth element and add the first part to the end.\n\n Parameters:\n arr (list): The input list.\n n (int): The index at which to split the list.\n\n Returns:\n list: The rearranged list.\n \"\"\"\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"\n Split the list at the nth element and add the first part to the end.\n \"\"\"\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"\n Split a list at the nth element and add the first part to the end.\n\n Parameters:\n arr (list): The list to be split and rearranged.\n n (int): The index at which to split the list.\n\n Returns:\n list: A new list with the elements rearranged as specified.\n \"\"\"\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}]}, "Mbpp/587": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 16.0, "profiled": [{"solution": "def list_tuple(input_list):\n \"\"\"\n Converts a list to a tuple.\n\n Args:\n input_list (list): The input list to be converted.\n\n Returns:\n tuple: The resulting tuple.\n \"\"\"\n return tuple(input_list)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(input_list):\n \"\"\"\n This function takes a list as input and returns a tuple.\n \"\"\"\n return tuple(input_list)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n \"\"\"\n Function to convert a list to a tuple\n\n Parameters:\n lst (list): List that needs to be converted to a tuple\n\n Returns:\n tuple: Corresponding tuple for the input list\n \"\"\"\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(input_list):\n \"\"\"\n Convert a list to a tuple.\n\n Args:\n input_list (list): The list to be converted.\n\n Returns:\n tuple: The converted tuple.\n \"\"\"\n return tuple(input_list)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n \"\"\"\n This function takes a list as input and returns a tuple.\n :param lst: List to be converted to tuple\n :return: Tuple equivalent of the input list\n \"\"\"\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(input_list):\n return tuple(input_list)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n \"\"\"Convert a list to a tuple.\"\"\"\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(input_list):\n return tuple(input_list)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(input_list):\n return tuple(input_list)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n \"\"\"Converts a list to a tuple.\"\"\"\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(input_list):\n \"\"\"\n Function to convert a list to a tuple.\n\n Args:\n input_list (list): The input list to be converted.\n\n Returns:\n tuple: The resulting tuple.\n \"\"\"\n return tuple(input_list)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(lst):\n \"\"\"\n Converts a list to a tuple.\n \"\"\"\n return tuple(lst)", "matching_cluster_idx": 3}, {"solution": "def list_tuple(input_list):\n \"\"\"\n Converts a list to a tuple.\n\n Parameters:\n input_list (list): The list to be converted.\n\n Returns:\n tuple: The converted tuple.\n \"\"\"\n return tuple(input_list)", "matching_cluster_idx": 3}]}, "Mbpp/588": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def big_diff(nums):\n \"\"\"\n Function to find the difference between the largest and smallest value in a given list.\n\n Args:\n nums (list): List of numbers\n\n Returns:\n int: Difference between the largest and smallest value in the list\n \"\"\"\n if not nums:\n raise ValueError(\"The list is empty\")\n\n largest = max(nums)\n smallest = min(nums)\n return largest - smallest", "matching_cluster_idx": 5}, {"solution": "def big_diff(lst):\n if not lst:\n return 0\n return max(lst) - min(lst)", "matching_cluster_idx": 5}, {"solution": "def big_diff(lst):\n \"\"\"\n Find the difference between the largest and smallest value in a given list.\n\n :param lst: List of integers\n :return: Difference between largest and smallest values in the list\n \"\"\"\n if not lst:\n raise ValueError(\"The list cannot be empty\")\n\n return max(lst) - min(lst)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n \"\"\"\n This function returns the difference between the largest and smallest values in a given list.\n \"\"\"\n if len(nums) < 2:\n raise ValueError(\"List must contain at least two elements\")\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n if not nums:\n raise ValueError(\"The list must not be empty\")\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n \"\"\"\n This function calculates the difference between the largest and smallest value in a given list.\n\n :param nums: List of integers\n :return: Difference between the largest and smallest values in the list\n \"\"\"\n if not nums:\n raise ValueError(\"The list is empty.\")\n\n max_value = max(nums)\n min_value = min(nums)\n return max_value - min_value", "matching_cluster_idx": 5}, {"solution": "def big_diff(lst):\n # Ensure the list is not empty\n if not lst:\n return 0\n # Calculate the difference between the maximum and minimum values in the list\n return max(lst) - min(lst)", "matching_cluster_idx": 5}, {"solution": "def big_diff(lst):\n \"\"\"\n Find the difference between the largest and smallest value in a given list.\n :param lst: List of integers\n :return: Difference between the largest and smallest value in the list\n \"\"\"\n if not lst: # Check if the list is empty\n raise ValueError(\"The list is empty\")\n\n # Find the maximum and minimum values in the list\n max_val = max(lst)\n min_val = min(lst)\n\n # Calculate the difference\n return max_val - min_val", "matching_cluster_idx": 5}, {"solution": "def big_diff(lst):\n return max(lst) - min(lst)", "matching_cluster_idx": 5}, {"solution": "def big_diff(lst):\n \"\"\"\n Calculate the difference between the largest and smallest value in the given list.\n\n Parameters:\n lst (list): List of numbers.\n\n Returns:\n int: The difference between the largest and smallest value in the list.\n \"\"\"\n if not lst:\n raise ValueError(\"The list is empty\")\n return max(lst) - min(lst)", "matching_cluster_idx": 5}, {"solution": "def big_diff(lst):\n \"\"\"\n Find the difference between the largest and smallest value in a given list.\n\n Args:\n lst (list): A list of numbers.\n\n Returns:\n int/float: The difference between the largest and smallest value in the list.\n \"\"\"\n if not lst:\n raise ValueError(\"The list must not be empty\")\n\n max_value = max(lst)\n min_value = min(lst)\n return max_value - min_value", "matching_cluster_idx": 5}, {"solution": "def big_diff(lst):\n return max(lst) - min(lst)", "matching_cluster_idx": 5}, {"solution": "def big_diff(lst):\n \"\"\"\n Find the difference between the largest and smallest value in a given list.\n\n :param lst: List of integers\n :return: Difference between the largest and smallest value in the list\n \"\"\"\n if not lst:\n raise ValueError(\"The list must not be empty\")\n\n max_val = max(lst)\n min_val = min(lst)\n return max_val - min_val", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n if len(nums) < 2:\n raise ValueError(\"List must contain at least two elements\")\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n if not nums:\n raise ValueError(\"The list should contain at least one element.\")\n\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(lst):\n \"\"\"\n This function calculates the difference between the largest and smallest values in a given list.\n :param lst: List of numbers\n :return: Difference between the largest and smallest values in the list\n \"\"\"\n if not lst:\n raise ValueError(\"The list is empty\")\n\n max_val = max(lst)\n min_val = min(lst)\n return max_val - min_val", "matching_cluster_idx": 5}, {"solution": "def big_diff(lst):\n \"\"\"\n Finds the difference between the largest and smallest value in a given list.\n\n Args:\n lst (list of int): A list of integers.\n\n Returns:\n int: The difference between the largest and smallest values in the list.\n \"\"\"\n if len(lst) < 2:\n raise ValueError(\"List must contain at least two elements.\")\n\n max_val = max(lst)\n min_val = min(lst)\n\n return max_val - min_val", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n \"\"\"\n Calculate the difference between the largest and smallest values in a given list.\n\n Parameters:\n nums (list): A list of numbers.\n\n Returns:\n int: The difference between the largest and smallest values.\n \"\"\"\n if not nums:\n raise ValueError(\"List cannot be empty\")\n\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(numbers):\n \"\"\"\n This function takes a list of numbers and returns the difference between the largest and smallest values.\n\n :param numbers: List of integers or floats\n :return: Difference between the largest and smallest value in the list\n \"\"\"\n if not numbers:\n raise ValueError(\"The list should not be empty.\")\n\n return max(numbers) - min(numbers)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n \"\"\"\n This function calculates the difference between the largest and smallest value in a given list.\n\n Args:\n nums (list): List of integers.\n\n Returns:\n int: Difference between the largest and smallest value.\n \"\"\"\n # Handle the case where the list is empty\n if not nums:\n raise ValueError(\"The list must contain at least one number\")\n\n return max(nums) - min(nums)", "matching_cluster_idx": 5}]}, "Mbpp/592": {"dps": 65.33333333333334, "dps_norm": 54.0, "pass@1": 40.0, "profiled": [{"solution": "import math\ndef binomial_coefficient(n, k):\n return math.comb(n, k)\ndef sum_Of_product(n):\n total_sum = 0\n for k in range(n):\n total_sum += binomial_coefficient(n, k) * binomial_coefficient(n, k + 1)\n return total_sum", "matching_cluster_idx": 4}, {"solution": "import math\ndef binomial_coefficient(n, k):\n return math.comb(n, k)\ndef sum_Of_product(n):\n total_sum = 0\n for i in range(n):\n total_sum += binomial_coefficient(n, i) * binomial_coefficient(n, i+1)\n return total_sum", "matching_cluster_idx": 4}, {"solution": "import math\ndef binomial_coefficient(n, k):\n \"\"\"Compute the binomial coefficient \"n choose k\".\"\"\"\n return math.comb(n, k)\ndef sum_Of_product(n):\n \"\"\"Compute the sum of the product of consecutive binomial coefficients.\"\"\"\n total_sum = 0\n for k in range(n + 1):\n product = binomial_coefficient(n, k) * binomial_coefficient(n, k + 1)\n total_sum += product\n return total_sum", "matching_cluster_idx": 4}, {"solution": "import math\ndef binomial_coefficient(n, k):\n \"\"\"Calculate the binomial coefficient C(n, k)\"\"\"\n return math.comb(n, k)\ndef sum_Of_product(n):\n \"\"\"Calculate the sum of the product of consecutive binomial coefficients for a given n\"\"\"\n total_sum = 0\n for k in range(n):\n total_sum += binomial_coefficient(n, k) * binomial_coefficient(n, k + 1)\n return total_sum", "matching_cluster_idx": 4}, {"solution": "import math\ndef sum_Of_product(n):\n \"\"\"\n This function calculates the sum of the product of consecutive binomial coefficients.\n :param n: integer representing the number of binomial coefficients\n :return: integer sum of the product of consecutive binomial coefficients\n \"\"\"\n def binomial_coefficient(n, k):\n \"\"\"\n This function computes the binomial coefficient \"n choose k\"\n :param n: integer\n :param k: integer\n :return: binomial coefficient \"n choose k\"\n \"\"\"\n return math.comb(n, k)\n\n total_sum = 0\n for i in range(n):\n total_sum += binomial_coefficient(n, i) * binomial_coefficient(n, i + 1)\n\n return total_sum", "matching_cluster_idx": 4}, {"solution": "from math import comb\ndef sum_Of_product(n):\n \"\"\"\n Function to calculate the sum of the product of consecutive binomial coefficients.\n \"\"\"\n total_sum = 0\n for i in range(1, n+1):\n total_sum += comb(n, i-1) * comb(n, i)\n return total_sum", "matching_cluster_idx": 5}, {"solution": "def binomial_coefficient(n, k):\n \"\"\"\n Compute the binomial coefficient \"n choose k\".\n \"\"\"\n if k == 0 or k == n:\n return 1\n if k == 1 or k == n - 1:\n return n\n\n numerator = 1\n for i in range(n, n - k, -1):\n numerator *= i\n\n denominator = 1\n for i in range(1, k + 1):\n denominator *= i\n\n return numerator // denominator\ndef sum_Of_product(n):\n \"\"\"\n Find the sum of the product of consecutive binomial coefficients.\n \"\"\"\n total_sum = 0\n for k in range(n + 1):\n if k < n:\n total_sum += binomial_coefficient(n, k) * binomial_coefficient(n, k + 1)\n\n return total_sum", "matching_cluster_idx": 1}, {"solution": "import math\ndef binomial_coefficient(n, k):\n return math.comb(n, k)\ndef sum_Of_product(n):\n total = 0\n for k in range(n):\n total += binomial_coefficient(n, k) * binomial_coefficient(n, k+1)\n return total", "matching_cluster_idx": 4}, {"solution": "from math import comb\ndef sum_Of_product(n):\n total_sum = 0\n for k in range(n+1):\n total_sum += comb(n, k) * comb(n, k+1)\n return total_sum", "matching_cluster_idx": 5}, {"solution": "import math\ndef sum_Of_product(n):\n \"\"\"\n Function to find the sum of the product of consecutive binomial coefficients.\n \"\"\"\n sum_result = 0\n for k in range(n):\n binomial_coeff_1 = math.comb(n, k)\n binomial_coeff_2 = math.comb(n, k+1)\n sum_result += binomial_coeff_1 * binomial_coeff_2\n return sum_result", "matching_cluster_idx": 5}, {"solution": "from math import comb\ndef sum_Of_product(n):\n \"\"\"\n Function to find the sum of the product of consecutive binomial coefficients.\n\n :param n: The number of terms in the binomial expansion.\n :return: The sum of the product of consecutive binomial coefficients.\n \"\"\"\n total_sum = 0\n for k in range(n):\n total_sum += comb(n, k) * comb(n, k + 1)\n return total_sum", "matching_cluster_idx": 5}, {"solution": "import math\ndef binomial_coefficient(n, k):\n \"\"\"Calculate the binomial coefficient C(n, k)\"\"\"\n return math.comb(n, k)\ndef sum_Of_product(n):\n \"\"\"\n Calculate the sum of the product of consecutive binomial coefficients for a given n.\n \"\"\"\n total_sum = 0\n for i in range(n):\n total_sum += binomial_coefficient(n, i) * binomial_coefficient(n, i+1)\n return total_sum", "matching_cluster_idx": 4}, {"solution": "import math\ndef sum_Of_product(n):\n total = 0\n for i in range(n):\n total += (math.comb(n, i) * math.comb(n, i + 1))\n return total", "matching_cluster_idx": 5}, {"solution": "from math import comb\ndef sum_Of_product(n):\n \"\"\"\n This function calculates the sum of the product of consecutive binomial coefficients.\n The binomial coefficient C(n, k) is defined as n! / (k!(n-k)!)\n We need to calculate sum C(n, k) * C(n, k+1) for k from 0 to n-1.\n \"\"\"\n total_sum = 0\n for k in range(n):\n binomial_k = comb(n, k)\n binomial_k_plus_one = comb(n, k + 1)\n total_sum += binomial_k * binomial_k_plus_one\n return total_sum", "matching_cluster_idx": 5}, {"solution": "import math\ndef sum_Of_product(n):\n def binomial_coefficient(n, k):\n return math.comb(n, k)\n\n total_sum = 0\n for k in range(n):\n product = binomial_coefficient(n, k) * binomial_coefficient(n, k + 1)\n total_sum += product\n\n return total_sum", "matching_cluster_idx": 5}, {"solution": "from math import comb\ndef sum_Of_product(n):\n \"\"\"\n Calculate the sum of the product of consecutive binomial coefficients.\n\n Parameters:\n n (int): The value of n for binomial coefficients.\n\n Returns:\n int: The sum of the product of consecutive binomial coefficients.\n \"\"\"\n if n < 1:\n return 0\n\n total_sum = 0\n for k in range(n):\n total_sum += comb(n, k) * comb(n, k + 1)\n\n return total_sum", "matching_cluster_idx": 5}, {"solution": "from math import comb\ndef sum_Of_product(n):\n sum_product = 0\n for i in range(n):\n sum_product += comb(n, i) * comb(n, i + 1)\n return sum_product", "matching_cluster_idx": 5}, {"solution": "def binomial_coefficient(n, k):\n \"\"\"Compute the binomial coefficient \"n choose k\".\"\"\"\n if k > n or k < 0:\n return 0\n if k == 0 or k == n:\n return 1\n if k == 1 or k == n - 1:\n return n\n # Compute the binomial coefficient\n coeff = 1\n for i in range(min(k, n - k)):\n coeff = coeff * (n - i) // (i + 1)\n return coeff\ndef sum_Of_product(n):\n \"\"\"Find the sum of the product of consecutive binomial coefficients.\"\"\"\n total_sum = 0\n for i in range(n):\n total_sum += binomial_coefficient(n, i) * binomial_coefficient(n, i + 1)\n return total_sum", "matching_cluster_idx": 4}, {"solution": "from math import comb\ndef sum_Of_product(n):\n total_sum = 0\n for i in range(n):\n total_sum += comb(n, i) * comb(n, i + 1)\n return total_sum", "matching_cluster_idx": 5}, {"solution": "from math import comb\ndef sum_Of_product(n):\n \"\"\"\n Calculate the sum of the product of consecutive binomial coefficients.\n \"\"\"\n total_sum = 0\n for i in range(n):\n total_sum += comb(n, i) * comb(n, i + 1)\n return total_sum", "matching_cluster_idx": 5}]}, "Mbpp/597": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 28.0, "profiled": [{"solution": "def find_kth(arr1, arr2, k):\n \"\"\"\n Find the kth element from two sorted arrays\n\n Parameters:\n arr1 (list): First sorted array\n arr2 (list): Second sorted array\n k (int): Position to find the element in the combined sorted array\n\n Returns:\n int: The kth element\n \"\"\"\n # Merge two sorted arrays into one sorted array\n merged_array = sorted(arr1 + arr2)\n\n # Return the kth element (index k-1 since index starts from 0)\n return merged_array[k-1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(arr1, arr2, k):\n # Merge two sorted arrays into one\n merged = sorted(arr1 + arr2)\n\n # Return the kth element\n return merged[k - 1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(arr1, arr2, k):\n merged_arr = sorted(arr1 + arr2)\n return merged_arr[k-1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(arr1, arr2, k):\n \"\"\"\n Function to find kth element from two sorted arrays.\n\n Parameters:\n arr1 (list): First sorted array.\n arr2 (list): Second sorted array.\n k (int): The kth element to find.\n\n Returns:\n int: The kth element from the merged sorted arrays.\n \"\"\"\n # Combine the two lists\n merged_array = sorted(arr1 + arr2)\n\n # Return the kth element (1-based index)\n return merged_array[k - 1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(arr1, arr2, k):\n \"\"\"\n Find the k-th smallest element from the given two sorted arrays.\n \"\"\"\n merged_arr = sorted(arr1 + arr2)\n return merged_arr[k-1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(arr1, arr2, k):\n # Merge two sorted arrays\n merged_array = sorted(arr1 + arr2)\n # Return the kth element from the merged array\n return merged_array[k-1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(arr1, arr2, k):\n \"\"\"\n Function to find the k-th smallest element in the combined sorted array of two given sorted arrays.\n \"\"\"\n # Merge two sorted arrays\n merged_arr = sorted(arr1 + arr2)\n\n # Return the k-th element (1-based index)\n return merged_arr[k - 1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(arr1, arr2, k):\n merged_array = sorted(arr1 + arr2)\n return merged_array[k - 1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(arr1, arr2, k):\n \"\"\"\n Find the kth element from two sorted arrays.\n\n :param arr1: First sorted array\n :param arr2: Second sorted array\n :param k: The index (1-based) of the element to find\n :return: The kth element\n \"\"\"\n # Merge two arrays and then return the kth element\n merged_array = sorted(arr1 + arr2)\n return merged_array[k - 1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(arr1, arr2, k):\n \"\"\"\n Find the kth element from two sorted arrays.\n \"\"\"\n merged = sorted(arr1 + arr2)\n return merged[k - 1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(arr1, arr2, k):\n merged_arr = sorted(arr1 + arr2)\n return merged_arr[k-1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(arr1, arr2, k):\n # Merge the two sorted arrays\n merged_array = sorted(arr1 + arr2)\n\n # Return the k-1 index element (since lists are 0-indexed)\n return merged_array[k-1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(arr1, arr2, k):\n merged_array = sorted(arr1 + arr2)\n return merged_array[k-1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(arr1, arr2, k):\n # Merge the two arrays and sort them\n merged_array = sorted(arr1 + arr2)\n\n # Return the k-th element (0-indexed)\n return merged_array[k - 1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(arr1, arr2, k):\n \"\"\"\n This function returns the kth element from two sorted arrays.\n :param arr1: List[int], the first sorted array.\n :param arr2: List[int], the second sorted array.\n :param k: int, the position of the element to be returned.\n :return: int, the kth element.\n \"\"\"\n # Concatenate the arrays\n combined = arr1 + arr2\n # Sort the combined array\n combined.sort()\n # Return the kth element (1-indexed)\n return combined[k - 1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(arr1, arr2, k):\n merged_array = sorted(arr1 + arr2)\n return merged_array[k - 1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(arr1, arr2, k):\n merged_list = sorted(arr1 + arr2)\n return merged_list[k-1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(arr1, arr2, k):\n merged_array = arr1 + arr2\n merged_array.sort()\n return merged_array[k - 1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(arr1, arr2, k):\n \"\"\"\n Find the kth element from the two given sorted arrays.\n\n Parameters:\n arr1 (list): The first sorted array.\n arr2 (list): The second sorted array.\n k (int): The position of the element to find (1-based index).\n\n Returns:\n The kth element from the merged sorted arrays.\n \"\"\"\n # Merge the two arrays\n merged_array = sorted(arr1 + arr2)\n\n # Return the k-th element (1-based index)\n return merged_array[k - 1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(arr1, arr2, k):\n # Combine the two lists\n combined = arr1 + arr2\n # Sort the combined list\n combined.sort()\n # Return the k-1 indexed element (as indexing starts from 0)\n return combined[k-1]", "matching_cluster_idx": 3}]}, "Mbpp/604": {"dps": 85.68181818181819, "dps_norm": 97.0, "pass@1": 76.0, "profiled": [{"solution": "def reverse_words(s):\n \"\"\"\n This function reverses words in a given string.\n \"\"\"\n # Split the string into words and reverse the list\n words = s.split()[::-1]\n\n # Join the reversed list back into a string\n return \" \".join(words)", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n words = s.split()\n reversed_words = words[::-1]\n return ' '.join(reversed_words)", "matching_cluster_idx": 4}, {"solution": "def reverse_words(input_string):\n # Split the input string into words\n words = input_string.split()\n # Reverse the order of words\n reversed_words = words[::-1]\n # Join the reversed words with spaces and return\n return \" \".join(reversed_words)", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s: str) -> str:\n \"\"\"\n Reverses the words in a string separated by spaces.\n\n :param s: Input string with words separated by spaces.\n :return: String with words reversed.\n \"\"\"\n words = s.split()\n reversed_words = words[::-1]\n return ' '.join(reversed_words)", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n return ' '.join(reversed(s.split()))", "matching_cluster_idx": 3}, {"solution": "def reverse_words(s):\n # Split the string into words\n words = s.split()\n # Reverse the list of words\n reversed_words = words[::-1]\n # Join the reversed words back into a single string\n result = ' '.join(reversed_words)\n return result", "matching_cluster_idx": 4}, {"solution": "def reverse_words(input_string):\n # split the input_string by spaces into a list of words\n words = input_string.split()\n # reverse the list of words\n reversed_words = words[::-1]\n # join the reversed list of words into a string with spaces in between\n reversed_string = ' '.join(reversed_words)\n # return the result\n return reversed_string", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n return ' '.join(reversed(s.split()))", "matching_cluster_idx": 3}, {"solution": "def reverse_words(s):\n # split the input string into a list of words\n words = s.split()\n # reverse the list of words\n reversed_words = words[::-1]\n # join the reversed words with a space\n return ' '.join(reversed_words)", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n # Split the string into a list of words\n words = s.split()\n # Reverse the list of words\n words = words[::-1]\n # Join the words back into a single string with spaces in between\n return ' '.join(words)", "matching_cluster_idx": 4}, {"solution": "def reverse_words(input_string):\n # Split the input string into words\n words = input_string.split()\n\n # Reverse the list of words\n reversed_words = words[::-1]\n\n # Join the reversed list of words into a single string\n reversed_string = ' '.join(reversed_words)\n\n return reversed_string", "matching_cluster_idx": 4}, {"solution": "def reverse_words(input_string):\n # Split the input string by spaces to get a list of words\n words = input_string.split()\n # Reverse the list of words\n reversed_words = words[::-1]\n # Join the reversed list of words back into a string with spaces\n reversed_string = ' '.join(reversed_words)\n return reversed_string", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n return ' '.join(reversed(s.split()))", "matching_cluster_idx": 3}, {"solution": "def reverse_words(input_string):\n # Split the string into a list of words\n words = input_string.split()\n\n # Reverse the order of words\n reversed_words = words[::-1]\n\n # Join the reversed words back into a string\n reversed_string = ' '.join(reversed_words)\n\n return reversed_string", "matching_cluster_idx": 4}, {"solution": "def reverse_words(string):\n # Split the string by spaces into a list of words\n words = string.split()\n # Reverse the list of words\n reversed_words = words[::-1]\n # Join the reversed list of words back into a string with spaces in between\n reversed_string = ' '.join(reversed_words)\n return reversed_string", "matching_cluster_idx": 4}, {"solution": "def reverse_words(input_string):\n # Split the input string into a list of words\n words = input_string.split()\n # Reverse the list of words\n reversed_words = words[::-1]\n # Join the reversed words back into a string with spaces in between\n reversed_string = ' '.join(reversed_words)\n return reversed_string", "matching_cluster_idx": 4}, {"solution": "def reverse_words(sentence):\n words = sentence.split()\n return ' '.join(words[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(sentence: str) -> str:\n words = sentence.split()\n return ' '.join(reversed(words))", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n \"\"\"\n Reverse words separated by spaces in a given string.\n \"\"\"\n words = s.split()\n return ' '.join(reversed(words))", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s: str) -> str:\n \"\"\"\n Reverses the order of words in a string.\n\n Args:\n s (str): The input string to reverse.\n\n Returns:\n str: The string with words in reverse order.\n \"\"\"\n # Split the string into words\n words = s.split()\n # Reverse the list of words\n reversed_words = words[::-1]\n # Join the reversed list of words into a single string\n result = ' '.join(reversed_words)\n return result", "matching_cluster_idx": 4}]}, "Mbpp/610": {"dps": null, "dps_norm": null, "pass@1": 0.0, "profiled": []}, "Mbpp/611": {"dps": 95.1840490797546, "dps_norm": 98.33333333333333, "pass@1": 76.0, "profiled": [{"solution": "def max_of_nth(matrix, n):\n # Create a list to store the elements of the nth column\n nth_column = []\n\n # Iterate over the rows of the matrix\n for row in matrix:\n # Add the nth element of the row to the list\n nth_column.append(row[n])\n\n # Return the maximum value in the nth column\n return max(nth_column)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n # Get the nth column from each row\n nth_column = [row[n] for row in matrix]\n # Return the maximum value in the nth column\n return max(nth_column)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n # Extract the nth column from the matrix\n nth_column = [row[n] for row in matrix]\n # Return the maximum value in the nth column\n return max(nth_column)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n \"\"\"\n Given a matrix represented as a list of lists, return the maximum value of the n'th column.\n\n :param matrix: List of lists where each inner list is a row in the matrix.\n :param n: The index of the column to find the maximum value from.\n :return: The maximum value in the n'th column.\n \"\"\"\n # Ensure n is within the valid range of column indices\n if not matrix or n >= len(matrix[0]):\n raise ValueError(\"Invalid column index\")\n\n # Extract the n'th column and find the maximum value\n column_values = [row[n] for row in matrix]\n return max(column_values)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n \"\"\"\n Function to return the max of the nth column in a given matrix.\n\n Parameters:\n matrix (list of lists): A matrix represented as a list of lists.\n n (int): The index of the column to find the max value.\n\n Returns:\n int: The maximum value in the nth column.\n \"\"\"\n if not matrix or n >= len(matrix[0]):\n return None # Return None if the matrix is empty or the column index is out of range\n\n # Extract the nth column from the matrix\n column = [row[n] for row in matrix]\n\n # Return the maximum value in the column\n return max(column)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n \"\"\"\n Given a matrix represented as a list of lists, returns the max of the n'th column.\n \"\"\"\n # Extract the n'th column from the matrix\n column = [row[n] for row in matrix]\n # Return the maximum value in the column\n return max(column)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n # Check if the matrix is not empty and all lists have at least n+1 elements\n if not matrix or not all(len(row) > n for row in matrix):\n raise ValueError(\"Matrix is empty or does not have enough columns\")\n\n # Find the maximum value in the n-th column\n return max(row[n] for row in matrix)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n # Extract the nth column from the matrix\n column = [row[n] for row in matrix]\n # Return the maximum value in the extracted column\n return max(column)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n # List to store the nth column elements\n nth_column = []\n\n # Iterate over each row in the matrix\n for row in matrix:\n # Check if the row has the nth element\n if len(row) > n:\n # Append the nth element to the list\n nth_column.append(row[n])\n\n # Return the maximum value in the nth column\n return max(nth_column)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n # Ensure that the matrix is not empty and has enough columns\n if not matrix or len(matrix[0]) <= n:\n raise ValueError(\"Matrix is empty or does not have enough columns\")\n\n # Use a list comprehension to extract the nth column and find its max value\n return max(row[n] for row in matrix)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n \"\"\"\n This function returns the maximum value in the nth column of a matrix.\n\n Parameters:\n - matrix: List[List[int]] - The input matrix represented as a list of lists.\n - n: int - The column index (0-based) to find the maximum value in.\n\n Returns:\n - int - The maximum value in the nth column.\n \"\"\"\n # Initialize the maximum value to a very small number\n max_value = float('-inf')\n\n # Iterate through each row in the matrix\n for row in matrix:\n # Check if the nth column exists in the current row\n if n < len(row):\n # Update the maximum value if the current element is greater\n max_value = max(max_value, row[n])\n\n return max_value", "matching_cluster_idx": 3}, {"solution": "def max_of_nth(matrix, n):\n \"\"\"\n Given a matrix represented as a list of lists, returns the max of the n'th column.\n\n :param matrix: List of lists (matrix)\n :param n: Integer representing the column index (0-based)\n :return: Maximum value in the n'th column\n \"\"\"\n # Extract the n'th column from the matrix\n column = [row[n] for row in matrix if n < len(row)]\n return max(column)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n \"\"\"\n This function takes a matrix (represented as a list of lists) and an integer n.\n It returns the maximum value in the n'th column of the matrix.\n\n Parameters:\n matrix (list of lists): The input matrix.\n n (int): The column index.\n\n Returns:\n int: The maximum value in the n'th column.\n \"\"\"\n # Initialize the maximum value to a very small number\n max_value = float('-inf')\n\n # Iterate through the rows in the matrix\n for row in matrix:\n # Check if the n'th column exists in the current row\n if n < len(row):\n # Update the maximum value if the current element is greater\n if row[n] > max_value:\n max_value = row[n]\n\n return max_value", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n \"\"\"\n This function takes a matrix (list of lists) and an index n,\n and returns the maximum value of the n-th column.\n\n Parameters:\n matrix (list of lists): The matrix to analyze.\n n (int): The index of the column to find the maximum value in.\n\n Returns:\n int: The maximum value in the n-th column.\n \"\"\"\n # Ensure that the matrix and the column index are valid\n if not matrix or not matrix[0]:\n raise ValueError(\"The matrix must not be empty and must contain at least one row.\")\n if n >= len(matrix[0]):\n raise ValueError(f\"The column index {n} is out of range for the given matrix.\")\n\n # Initialize the max value with the first element of the n-th column\n max_value = matrix[0][n]\n\n # Iterate over the matrix to find the maximum value in the n-th column\n for row in matrix[1:]:\n if row[n] > max_value:\n max_value = row[n]\n\n return max_value", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n \"\"\"\n Given a matrix represented as a list of lists, returns the max of the n'th column.\n \"\"\"\n # Get the nth column from each row\n nth_column = [row[n] for row in matrix]\n # Return the max of the nth column\n return max(nth_column)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n \"\"\"\n Returns the maximum value in the nth column of the given matrix.\n\n Parameters:\n matrix (list of lists): The input matrix.\n n (int): The index of the column to find the max value of.\n\n Returns:\n int: The maximum value in the nth column.\n \"\"\"\n # Check if the matrix is not empty\n if not matrix:\n raise ValueError(\"The matrix is empty.\")\n\n # Initialize the max value as the smallest possible integer\n max_val = float('-inf')\n\n # Iterate through each row of the matrix\n for row in matrix:\n # Check if the row has at least n+1 columns\n if len(row) > n:\n # Update the max value if the current element is greater\n if row[n] > max_val:\n max_val = row[n]\n\n return max_val", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n # Extract the n'th column from the matrix\n column = [row[n] for row in matrix]\n\n # Return the maximum value in the column\n return max(column)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n \"\"\"\n This function takes a matrix (list of lists) and an integer n,\n and returns the maximum value in the nth column of the matrix.\n\n Parameters:\n matrix (list of lists of ints): The input matrix.\n n (int): The index of the column to find the maximum value.\n\n Returns:\n int: The maximum value in the nth column.\n \"\"\"\n # Initialize max_value with a very small number\n max_value = float('-inf')\n\n # Iterate through each row in the matrix\n for row in matrix:\n # Check if the row has enough elements to include the nth column\n if n < len(row):\n # Update max_value if a larger value is found in the nth column\n if row[n] > max_value:\n max_value = row[n]\n\n return max_value", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n \"\"\"\n Given a matrix represented as a list of lists, returns the max of the n'th column.\n \"\"\"\n if not matrix or not matrix[0]:\n raise ValueError(\"Matrix must be non-empty and contain at least one row with columns\")\n\n # Use a list comprehension to extract the nth column and find its max\n column_values = [row[n] for row in matrix if len(row) > n]\n\n if not column_values:\n raise ValueError(f\"The n'th column is out of range for the given matrix\")\n\n return max(column_values)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n \"\"\"\n This function takes a matrix (list of lists) and an integer n, and returns the maximum\n value from the n-th column.\n\n :param matrix: List of lists, representing a matrix.\n :param n: Integer, the index of the column from which to find the maximum value.\n :return: The maximum value of the n-th column.\n \"\"\"\n max_value = float('-inf')\n\n # Iterate over each row in the matrix\n for row in matrix:\n if n < len(row):\n # Update max_value if the current element is greater\n if row[n] > max_value:\n max_value = row[n]\n\n return max_value", "matching_cluster_idx": 5}]}, "Mbpp/631": {"dps": 27.266081871345026, "dps_norm": 40.13157894736842, "pass@1": 19.0, "profiled": [{"solution": "def replace_spaces(s):\n # Using the str.translate() and str.maketrans() methods\n return s.translate(str.maketrans(' _', '_ '))", "matching_cluster_idx": 6}, {"solution": "def replace_spaces(input_string: str) -> str:\n # Initialize an empty list to store the transformed characters\n result = []\n\n # Iterate over each character in the input string\n for char in input_string:\n if char == ' ':\n # Replace space with underscore\n result.append('_')\n elif char == '_':\n # Replace underscore with space\n result.append(' ')\n else:\n # Keep the original character\n result.append(char)\n\n # Join the list back into a string and return it\n return ''.join(result)", "matching_cluster_idx": 3}, {"solution": "def replace_spaces(input_string):\n \"\"\"\n Replace whitespaces with an underscore and vice versa in a given string.\n\n Args:\n input_string (str): The input string to be modified.\n\n Returns:\n str: The modified string with whitespaces replaced by underscores.\n \"\"\"\n # Initialize an empty string to build the result\n result = \"\"\n\n # Iterate over each character in the input string\n for char in input_string:\n if char == ' ':\n result += '_'\n elif char == '_':\n result += ' '\n else:\n result += char\n\n return result", "matching_cluster_idx": 1}, {"solution": "def replace_spaces(input_str):\n # Initialize a result string\n result = \"\"\n for char in input_str:\n if char == ' ':\n result += '_'\n elif char == '_':\n result += ' '\n else:\n result += char\n return result", "matching_cluster_idx": 1}, {"solution": "def replace_spaces(input_string):\n \"\"\"\n Replace spaces with underscores and vice versa in the given string.\n\n Parameters:\n input_string (str): The input string to be processed.\n\n Returns:\n str: The processed string with spaces replaced by underscores and vice versa.\n \"\"\"\n result = \"\"\n for char in input_string:\n if char == ' ':\n result += '_'\n elif char == '_':\n result += ' '\n else:\n result += char\n return result", "matching_cluster_idx": 1}, {"solution": "def replace_spaces(input_string):\n \"\"\"\n Replaces spaces with underscores and vice versa in a given string.\n\n Parameters:\n input_string (str): The input string to be modified.\n\n Returns:\n str: The modified string with spaces and underscores swapped.\n \"\"\"\n modified_string = \"\"\n\n for char in input_string:\n if char == ' ':\n modified_string += '_'\n elif char == '_':\n modified_string += ' '\n else:\n modified_string += char\n\n return modified_string", "matching_cluster_idx": 1}, {"solution": "def replace_spaces(input_string):\n result = ''\n for char in input_string:\n if char == ' ':\n result += '_'\n elif char == '_':\n result += ' '\n else:\n result += char\n return result", "matching_cluster_idx": 1}, {"solution": "def replace_spaces(input_string):\n \"\"\"\n Replace whitespaces with an underscore and vice versa in the given string.\n\n Parameters:\n input_string (str): The input string to be processed.\n\n Returns:\n str: The string with spaces replaced by underscores and vice versa.\n \"\"\"\n replaced = []\n\n for char in input_string:\n if char == ' ':\n replaced.append('_')\n elif char == '_':\n replaced.append(' ')\n else:\n replaced.append(char)\n\n return ''.join(replaced)", "matching_cluster_idx": 3}, {"solution": "def replace_spaces(input_string):\n \"\"\"\n Replace whitespaces with underscores and vice versa in the given string.\n\n Parameters:\n input_string (str): The input string to be modified.\n\n Returns:\n str: The modified string with whitespaces replaced by underscores and vice versa.\n \"\"\"\n # Creating a translation table to replace spaces with underscores and vice versa\n translation_table = str.maketrans(' _', '_ ')\n\n # Applying the translation table to the input string\n return input_string.translate(translation_table)", "matching_cluster_idx": 6}, {"solution": "def replace_spaces(input_string):\n \"\"\"\n This function replaces whitespaces with underscores and vice versa in a given string.\n\n Parameters:\n input_string (str): The input string to be processed.\n\n Returns:\n str: The processed string with spaces replaced by underscores and vice versa.\n \"\"\"\n result = ''\n for char in input_string:\n if char == ' ':\n result += '_'\n elif char == '_':\n result += ' '\n else:\n result += char\n return result", "matching_cluster_idx": 1}, {"solution": "def replace_spaces(s: str) -> str:\n # Initialize an empty list to collect the new characters\n new_chars = []\n\n # Iterate through each character in the string\n for char in s:\n # If the character is a whitespace, replace it with an underscore\n if char == ' ':\n new_chars.append('_')\n # If the character is an underscore, replace it with a whitespace\n elif char == '_':\n new_chars.append(' ')\n # Otherwise, just add the character as is\n else:\n new_chars.append(char)\n\n # Join the list into a new string and return it\n return ''.join(new_chars)", "matching_cluster_idx": 3}, {"solution": "def replace_spaces(s):\n \"\"\"\n Replace spaces with underscores and vice versa in the given string.\n\n Parameters:\n s (str): The input string.\n\n Returns:\n str: The string with spaces replaced by underscores and vice versa.\n \"\"\"\n result = []\n for char in s:\n if char == ' ':\n result.append('_')\n elif char == '_':\n result.append(' ')\n else:\n result.append(char)\n return ''.join(result)", "matching_cluster_idx": 3}, {"solution": "def replace_spaces(input_string):\n \"\"\"\n Replace whitespaces with underscores and vice versa in the given string.\n\n Args:\n input_string (str): The string to process.\n\n Returns:\n str: The processed string with replaced whitespaces and underscores.\n \"\"\"\n # Initialize a result list to store the characters\n result = []\n\n # Iterate through each character in the input string\n for char in input_string:\n if char == ' ':\n result.append('_')\n elif char == '_':\n result.append(' ')\n else:\n result.append(char)\n\n # Join the list to form the final string\n return ''.join(result)", "matching_cluster_idx": 3}, {"solution": "def replace_spaces(input_string):\n \"\"\"\n Replace whitespaces with an underscore and vice versa in a given string.\n \"\"\"\n result = \"\"\n for char in input_string:\n if char == ' ':\n result += '_'\n elif char == '_':\n result += ' '\n else:\n result += char\n return result", "matching_cluster_idx": 1}, {"solution": "def replace_spaces(input_string):\n # Iterate over each character in the input string\n result = []\n for char in input_string:\n if char == ' ':\n result.append('_')\n elif char == '_':\n result.append(' ')\n else:\n result.append(char)\n return ''.join(result)", "matching_cluster_idx": 3}, {"solution": "def replace_spaces(input_str):\n \"\"\"\n This function replaces whitespaces with an underscore and vice versa in a given string.\n :param input_str: The input string\n :return: The modified string\n \"\"\"\n # Initialize an empty string to store the result\n result = \"\"\n\n # Iterate over each character in the input string\n for char in input_str:\n if char == ' ':\n # Replace whitespace with underscore\n result += '_'\n elif char == '_':\n # Replace underscore with whitespace\n result += ' '\n else:\n # Keep the character as it is\n result += char\n\n return result", "matching_cluster_idx": 1}, {"solution": "def replace_spaces(input_string):\n result = ''\n for char in input_string:\n if char == ' ':\n result += '_'\n elif char == '_':\n result += ' '\n else:\n result += char\n return result", "matching_cluster_idx": 1}, {"solution": "def replace_spaces(s):\n \"\"\"\n This function takes a string and replaces whitespaces with underscores and vice versa.\n \"\"\"\n # Split the string into a list of characters\n s_list = list(s)\n\n # Iterate through each character in the list\n for i in range(len(s_list)):\n if s_list[i] == ' ':\n s_list[i] = '_'\n elif s_list[i] == '_':\n s_list[i] = ' '\n\n # Join the list back into a string and return\n return ''.join(s_list)", "matching_cluster_idx": 2}, {"solution": "def replace_spaces(s: str) -> str:\n \"\"\"\n Function to replace whitespaces with an underscore and vice versa in a given string.\n\n Parameters:\n s (str): The input string.\n\n Returns:\n str: The resulting string with the replacements.\n \"\"\"\n result = \"\"\n for char in s:\n if char == ' ':\n result += '_'\n elif char == '_':\n result += ' '\n else:\n result += char\n return result", "matching_cluster_idx": 1}]}, "Mbpp/632": {"dps": 95.1219512195122, "dps_norm": 97.14285714285714, "pass@1": 99.0, "profiled": [{"solution": "def move_zero(lst):\n \"\"\"\n Move all zeroes to the end of the given list.\n\n Parameters:\n lst (list): The input list which may contain zeroes.\n\n Returns:\n list: The list with all zeroes moved to the end.\n \"\"\"\n non_zero_elements = [num for num in lst if num != 0]\n zero_elements = [num for num in lst if num == 0]\n return non_zero_elements + zero_elements", "matching_cluster_idx": 6}, {"solution": "def move_zero(lst):\n non_zero = [num for num in lst if num != 0]\n zeros = [0] * (len(lst) - len(non_zero))\n return non_zero + zeros", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n # Initialize an index for the last non-zero element found\n last_non_zero_found_at = 0\n\n # Move all non-zero elements to the beginning of the list\n for i in range(len(nums)):\n if nums[i] != 0:\n nums[last_non_zero_found_at] = nums[i]\n last_non_zero_found_at += 1\n\n # After all non-zero elements are moved, set the rest of the list to zero\n for i in range(last_non_zero_found_at, len(nums)):\n nums[i] = 0\n\n return nums", "matching_cluster_idx": 6}, {"solution": "def move_zero(lst):\n \"\"\"\n Moves all zeros in the given list to the end while maintaining the order of other elements.\n\n Parameters:\n lst (list): The input list containing zeros and other elements.\n\n Returns:\n list: A new list with zeros moved to the end.\n \"\"\"\n # List comprehension to filter out zeros and then extend with zeros\n return [x for x in lst if x != 0] + [x for x in lst if x == 0]", "matching_cluster_idx": 6}, {"solution": "def move_zero(arr):\n \"\"\"\n This function takes a list of integers and moves all zeroes to the end of the list\n while maintaining the relative order of the non-zero elements.\n\n Parameters:\n arr (list): The input list of integers\n\n Returns:\n list: A new list with zeroes moved to the end\n \"\"\"\n non_zero_elements = [x for x in arr if x != 0]\n zero_elements = [x for x in arr if x == 0]\n return non_zero_elements + zero_elements", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n \"\"\"\n This function moves all zeroes in the given list to the end while maintaining the order of other elements.\n\n :param nums: List of numbers\n :return: List with zeroes moved to the end\n \"\"\"\n result = [num for num in nums if num != 0]\n result += [0] * (len(nums) - len(result))\n return result", "matching_cluster_idx": 6}, {"solution": "def move_zero(lst):\n non_zero = [i for i in lst if i != 0]\n zero = [i for i in lst if i == 0]\n lst = non_zero + zero\n return lst", "matching_cluster_idx": 6}, {"solution": "def move_zero(lst):\n zeros = 0\n for i in range(len(lst)):\n if lst[i] == 0:\n zeros += 1\n lst.remove(lst[i])\n lst.append(0)\n return lst", "matching_cluster_idx": 2}, {"solution": "def move_zero(lst):\n \"\"\"\n Function to move all zeroes to the end of the given list.\n\n Args:\n lst (list): The input list containing numbers.\n\n Returns:\n list: The list with zeroes moved to the end.\n \"\"\"\n # Use list comprehension to separate zeroes and non-zeroes.\n # List comprehension creates a new list with non-zero elements first, then zeroes.\n result = [num for num in lst if num != 0] + [0] * lst.count(0)\n return result", "matching_cluster_idx": 6}, {"solution": "def move_zero(lst):\n \"\"\"\n Moves all zeros in a list to the end while maintaining the order of other elements.\n\n Args:\n lst (list): The list containing elements to be processed.\n\n Returns:\n list: A new list with zeros moved to the end.\n \"\"\"\n # Create a new list to store non-zero elements\n non_zero_elements = [x for x in lst if x != 0]\n\n # Calculate the number of zeros\n num_zeros = lst.count(0)\n\n # Return the non-zero elements followed by the zeros\n return non_zero_elements + [0] * num_zeros", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n \"\"\"\n Function to move all zeroes to the end of the given list while preserving the order of other elements.\n\n :param nums: List[int] - The input list containing integers\n :return: List[int] - The list with all zeroes moved to the end\n \"\"\"\n # Initialize a counter to keep track of non-zero elements\n non_zero_index = 0\n\n # First pass: Move all non-zero elements to the front\n for i in range(len(nums)):\n if nums[i] != 0:\n nums[non_zero_index] = nums[i]\n non_zero_index += 1\n\n # Second pass: Fill the remaining positions with zeros\n for i in range(non_zero_index, len(nums)):\n nums[i] = 0\n\n return nums", "matching_cluster_idx": 6}, {"solution": "def move_zero(input_list):\n result = [i for i in input_list if i != 0]\n result += [0] * (len(input_list) - len(result))\n return result", "matching_cluster_idx": 6}, {"solution": "def move_zero(arr):\n # filter all non-zero elements\n non_zero = [i for i in arr if i != 0]\n # count the zero elements\n count_zero = arr.count(0)\n # concatenate non-zero elements with zero elements\n return non_zero + [0]*count_zero", "matching_cluster_idx": 6}, {"solution": "def move_zero(arr):\n \"\"\"\n Move all zeroes to the end of the given list.\n\n Args:\n arr (list): Input list containing integers.\n\n Returns:\n list: List with all zeroes moved to the end.\n \"\"\"\n non_zero_elements = [num for num in arr if num != 0]\n zero_count = arr.count(0)\n return non_zero_elements + [0] * zero_count", "matching_cluster_idx": 6}, {"solution": "def move_zero(lst):\n \"\"\"\n Function to move all zeroes to the end of the given list.\n \"\"\"\n non_zero_elements = [num for num in lst if num != 0]\n zero_count = lst.count(0)\n return non_zero_elements + [0] * zero_count", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n non_zero_elements = [num for num in nums if num != 0]\n zero_count = nums.count(0)\n return non_zero_elements + [0] * zero_count", "matching_cluster_idx": 6}, {"solution": "def move_zero(lst):\n # Create a list with only the non-zero elements in the given list.\n # Add the missing zero elements at the end.\n non_zero_list = [item for item in lst if item != 0]\n zero_list = [0] * (len(lst) - len(non_zero_list))\n return non_zero_list + zero_list", "matching_cluster_idx": 6}, {"solution": "def move_zero(lst):\n non_zero = [num for num in lst if num != 0]\n zeros = [0] * (len(lst) - len(non_zero))\n return non_zero + zeros", "matching_cluster_idx": 6}, {"solution": "def move_zero(lst):\n \"\"\"\n Move all zeroes to the end of the given list.\n \"\"\"\n non_zero_elements = [num for num in lst if num != 0]\n zero_count = len(lst) - len(non_zero_elements)\n return non_zero_elements + [0] * zero_count", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n \"\"\"\n Move all zeroes to the end of the given list.\n\n Args:\n nums (list): List of integers.\n\n Returns:\n list: List with all zeroes moved to the end.\n \"\"\"\n # Pointer for the position of the next non-zero element\n pos = 0\n\n # Move all the non-zero elements to the front\n for num in nums:\n if num != 0:\n nums[pos] = num\n pos += 1\n\n # Fill the remaining positions with zeroes\n while pos < len(nums):\n nums[pos] = 0\n pos += 1\n\n return nums", "matching_cluster_idx": 6}]}, "Mbpp/633": {"dps": 94.3089430894309, "dps_norm": 50.0, "pass@1": 28.0, "profiled": [{"solution": "def pair_xor_Sum(nums, n):\n res = 0\n for i in range(n):\n for j in range(i + 1, n):\n res += (nums[i] ^ nums[j])\n return res", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(lst, n):\n \"\"\"\n Calculate the sum of XOR of all pairs in the list.\n\n Args:\n lst (list): List of numbers.\n n (int): Number of elements in the list.\n\n Returns:\n int: Sum of XOR of all pairs.\n \"\"\"\n sum_xor = 0\n for i in range(n):\n for j in range(i + 1, n):\n sum_xor += lst[i] ^ lst[j]\n return sum_xor", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(lst, n):\n xor_sum = 0\n for i in range(n):\n for j in range(i + 1, n):\n xor_sum += lst[i] ^ lst[j]\n return xor_sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(nums, n):\n total_sum = 0\n for i in range(n):\n for j in range(i + 1, n):\n total_sum += nums[i] ^ nums[j]\n return total_sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(nums, n):\n result = 0\n for i in range(n):\n for j in range(i + 1, n):\n result += nums[i] ^ nums[j]\n return result", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(lst, n):\n result = 0\n for i in range(n):\n for j in range(i+1, n):\n result += lst[i] ^ lst[j]\n return result", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(arr, n):\n # Function to calculate xor sum of\n # all pairs in array\n xor_sum = 0\n for i in range(n):\n for j in range(i+1, n):\n xor_sum = xor_sum + (arr[i] ^ arr[j])\n return xor_sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(lst, n):\n result = 0\n for i in range(n):\n for j in range(i+1, n):\n result += lst[i] ^ lst[j]\n return result", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(nums, n):\n \"\"\"\n This function calculates the sum of XOR of all pairs of numbers in the given list.\n\n Parameters:\n nums (list): A list of integers.\n n (int): The length of the list.\n\n Returns:\n int: The sum of XOR of all pairs of numbers in the list.\n \"\"\"\n xor_sum = 0\n for i in range(n):\n for j in range(i + 1, n):\n xor_sum += (nums[i] ^ nums[j])\n return xor_sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(arr, n):\n ans = 0\n for i in range(n):\n for j in range(i + 1, n):\n ans += (arr[i] ^ arr[j])\n return ans", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(nums, n):\n total = 0\n for i in range(n):\n for j in range(i+1, n):\n total += nums[i] ^ nums[j]\n return total", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(arr, n):\n # Function to calculate the xor sum of all pairs\n result = 0\n for i in range(n):\n for j in range(i+1, n):\n result += arr[i] ^ arr[j]\n return result", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(arr, n):\n result = 0\n\n for i in range(n):\n for j in range(i + 1, n):\n result += (arr[i] ^ arr[j])\n\n return result", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(nums, n):\n total_xor_sum = 0\n for i in range(n):\n for j in range(i+1, n):\n total_xor_sum += nums[i] ^ nums[j]\n return total_xor_sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(arr, n):\n \"\"\"\n This function takes a list of integers and returns the sum of XOR of all pairs.\n\n :param arr: List of integers\n :param n: Length of the list\n :return: Integer representing the sum of XOR of all pairs\n \"\"\"\n # Initialize the result\n result = 0\n\n # Traverse all possible pairs\n for i in range(n):\n for j in range(i + 1, n):\n result += (arr[i] ^ arr[j])\n\n return result", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(numbers, n):\n \"\"\"\n Find the sum of XOR of all pairs of numbers in the given list.\n\n Parameters:\n numbers (list of int): The list of numbers.\n n (int): The length of the list.\n\n Returns:\n int: The sum of XOR of all pairs.\n \"\"\"\n # Initialize the result\n result = 0\n\n # Iterate over all pairs of numbers\n for i in range(n):\n for j in range(i+1, n):\n result += numbers[i] ^ numbers[j]\n\n return result", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(nums, n):\n total_sum = 0\n\n for i in range(n):\n for j in range(i + 1, n):\n total_sum += nums[i] ^ nums[j]\n\n return total_sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(nums, n):\n total_sum = 0\n for i in range(n):\n for j in range(i+1, n):\n total_sum += nums[i] ^ nums[j]\n return total_sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(lst, n):\n \"\"\"\n Function to find the sum of xor of all pairs of numbers in the given list.\n \"\"\"\n xor_sum = 0\n for i in range(n):\n for j in range(i + 1, n):\n xor_sum += lst[i] ^ lst[j]\n return xor_sum", "matching_cluster_idx": 2}, {"solution": "def pair_xor_Sum(arr, n):\n result = 0\n # Traverse all possible pairs\n for i in range(n):\n for j in range(i+1, n):\n result += arr[i] ^ arr[j]\n return result", "matching_cluster_idx": 2}]}, "Mbpp/644": {"dps": 72.07446808510637, "dps_norm": 78.66666666666667, "pass@1": 76.0, "profiled": [{"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n This function reverses an array up to a given position k.\n\n Parameters:\n arr (list): The array to be reversed.\n k (int): The position up to which the array needs to be reversed.\n\n Returns:\n list: The array with the first k elements reversed.\n \"\"\"\n # Ensure k is within the valid range\n if k <= 0 or k > len(arr):\n return arr\n\n # Reverse the first k elements\n start = 0\n end = k - 1\n while start < end:\n arr[start], arr[end] = arr[end], arr[start]\n start += 1\n end -= 1\n\n return arr", "matching_cluster_idx": 7}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n This function takes an array and a position k, and reverses the array up to the k-th position.\n\n :param arr: List of elements to reverse\n :param k: Position up to which the list should be reversed\n :return: List with elements reversed up to the k-th position\n \"\"\"\n if k > len(arr):\n raise ValueError(\"k should be less than or equal to the length of the array\")\n\n # Reverse the elements up to the k-th position\n arr[:k] = arr[:k][::-1]\n return arr", "matching_cluster_idx": 13}, {"solution": "def reverse_Array_Upto_K(arr, k):\n # Check if the given k is valid\n if k <= 0 or k > len(arr):\n raise ValueError(\"k should be greater than 0 and less than or equal to the length of the array\")\n\n # Reverse the subarray from the start up to the kth element\n arr[:k] = arr[:k][::-1]\n\n return arr", "matching_cluster_idx": 13}, {"solution": "def reverse_Array_Upto_K(arr, k):\n # Ensure k is within the bounds of the array\n if k <= 0 or k > len(arr):\n raise ValueError(\"k should be a positive integer within the range of the array length\")\n\n # Reverse the first k elements\n arr[:k] = arr[:k][::-1]\n return arr", "matching_cluster_idx": 13}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n Reverses the array upto the given position k\n \"\"\"\n # Ensure that k is within the bounds of the array\n k = min(k, len(arr))\n\n # Reverse the first k elements of the array\n arr[:k] = reversed(arr[:k])\n\n return arr", "matching_cluster_idx": 11}, {"solution": "def reverse_Array_Upto_K(array, k):\n return array[:k][::-1] + array[k:]", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n if k > len(arr):\n raise ValueError(\"k is larger than the length of the array\")\n arr[:k] = reversed(arr[:k])\n return arr", "matching_cluster_idx": 12}, {"solution": "def reverse_Array_Upto_K(arr, k):\n # Ensure k is within bounds\n k = min(k, len(arr))\n\n # Reverse the first k elements of the array\n arr[:k] = reversed(arr[:k])\n\n return arr", "matching_cluster_idx": 11}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n Reverses the first k elements of the array.\n\n Parameters:\n arr (list): The input array.\n k (int): The position up to which the array should be reversed.\n\n Returns:\n list: The array with the first k elements reversed.\n \"\"\"\n if k > len(arr):\n raise ValueError(\"k is larger than the length of the array\")\n\n start = 0\n end = k - 1\n\n while start < end:\n arr[start], arr[end] = arr[end], arr[start]\n start += 1\n end -= 1\n\n return arr", "matching_cluster_idx": 7}, {"solution": "def reverse_Array_Upto_K(arr, k):\n # Reverse the sub-array from the start up to the k-th position (exclusive)\n arr[:k] = arr[:k][::-1]\n return arr", "matching_cluster_idx": 13}, {"solution": "def reverse_Array_Upto_K(arr, k):\n if k > len(arr):\n raise ValueError(\"k is larger than the length of the array.\")\n\n return arr[k-1::-1] + arr[k:]", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n This function reverses the array up to the k-th position.\n\n :param arr: list of elements\n :param k: position up to which array should be reversed\n :return: reversed array up to the k-th position\n \"\"\"\n # check if k is within bounds\n if k > len(arr):\n raise ValueError(\"k is out of bounds of the array\")\n\n # reverse the first k elements\n arr[:k] = arr[:k][::-1]\n return arr", "matching_cluster_idx": 13}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n This function takes an array and a position k as input and returns the array\n with the first k elements reversed.\n \"\"\"\n # Reverse the first k elements\n arr[:k] = arr[:k][::-1]\n return arr", "matching_cluster_idx": 13}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n Reverses the first k elements of the array while keeping the rest of the array intact.\n :param arr: List of integers\n :param k: Integer representing the position upto which the array should be reversed\n :return: List of integers with the first k elements reversed\n \"\"\"\n if k >= len(arr):\n return arr[::-1]\n return arr[:k][::-1] + arr[k:]", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n Reverses the first k elements of the given array.\n\n :param arr: List of elements.\n :param k: Position upto which to reverse the array.\n :return: List with the first k elements reversed.\n \"\"\"\n # Ensure k is within the bounds of the array length\n if k > len(arr):\n k = len(arr)\n\n # Reverse the first k elements\n arr[:k] = arr[:k][::-1]\n\n return arr", "matching_cluster_idx": 13}, {"solution": "def reverse_Array_Upto_K(arr, k):\n if k > len(arr):\n k = len(arr)\n\n for i in range(k // 2):\n arr[i], arr[k - i - 1] = arr[k - i - 1], arr[i]\n\n return arr", "matching_cluster_idx": 6}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n Function to reverse an array up to a given position.\n :param arr: List of elements to be reversed.\n :param k: The position up to which the array needs to be reversed.\n :return: A list with the first k elements reversed and remaining elements unchanged.\n \"\"\"\n if k > len(arr):\n raise ValueError(\"k should not be greater than the length of the array\")\n return arr[:k][::-1] + arr[k:]", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(array, k):\n # Check if k is within the bounds of the array\n if k <= len(array):\n # Reverse the part of the array from the beginning up to the k-th index\n array[:k] = reversed(array[:k])\n return array", "matching_cluster_idx": 12}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n This function reverses the first k elements of an array.\n\n Parameters:\n arr (list): The input array to be processed.\n k (int): The position upto which the array needs to be reversed.\n\n Returns:\n list: The array with the first k elements reversed.\n \"\"\"\n if k <= 0 or k > len(arr):\n raise ValueError(\"k must be within the range of the array length\")\n\n start = 0\n end = k - 1\n\n while start < end:\n arr[start], arr[end] = arr[end], arr[start]\n start += 1\n end -= 1\n\n return arr", "matching_cluster_idx": 7}, {"solution": "def reverse_Array_Upto_K(arr, k):\n # Ensure k is within the bounds of the array\n k = min(k, len(arr))\n # Reverse the first k elements\n arr[:k] = arr[:k][::-1]\n return arr", "matching_cluster_idx": 12}]}, "Mbpp/720": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def add_dict_to_tuple(t, d):\n return t + (d,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(tup, d):\n return tup + (d,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(tuple_input, dict_input):\n return tuple_input + (dict_input,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(tup, dic):\n \"\"\"\n Function to add a dictionary to the tuple.\n\n Args:\n tup (tuple): The tuple to which the dictionary will be added.\n dic (dict): The dictionary to be added to the tuple.\n\n Returns:\n tuple: A new tuple with the dictionary added to the end.\n \"\"\"\n return tup + (dic,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(tup, dct):\n \"\"\"\n This function takes a tuple and a dictionary as arguments and returns a new tuple\n with the dictionary appended to the end of the input tuple.\n\n :param tup: A tuple\n :param dct: A dictionary\n :return: A new tuple with the dictionary appended\n \"\"\"\n return tup + (dct,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(input_tuple, input_dict):\n \"\"\"\n This function takes a tuple and a dictionary as inputs,\n and returns a new tuple with the dictionary appended to it.\n \"\"\"\n return input_tuple + (input_dict,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(input_tuple, input_dict):\n \"\"\"\n Function to add a dictionary to the tuple. The output is a tuple.\n\n Args:\n input_tuple (tuple): The original tuple.\n input_dict (dict): The dictionary to be added to the tuple.\n\n Returns:\n tuple: The new tuple with the dictionary added.\n \"\"\"\n # Add the dictionary to the tuple and return the new tuple\n return input_tuple + (input_dict,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(input_tuple, input_dict):\n \"\"\"\n This function takes a tuple and a dictionary as inputs and\n returns a new tuple with the dictionary added to the end.\n \"\"\"\n return input_tuple + (input_dict,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(tup, dictionary):\n \"\"\"\n This function takes a tuple and a dictionary as arguments\n and returns a new tuple that includes the dictionary at the end.\n \"\"\"\n return tup + (dictionary,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(tup, dic):\n \"\"\"\n Add a dictionary to a tuple.\n\n Parameters:\n tup (tuple): The original tuple.\n dic (dict): The dictionary to add to the tuple.\n\n Returns:\n tuple: A new tuple with the dictionary added.\n \"\"\"\n return tup + (dic,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(t, d):\n \"\"\"\n Adds a dictionary to the end of a tuple and returns a new tuple.\n\n Parameters:\n t (tuple): The initial tuple.\n d (dict): The dictionary to add to the tuple.\n\n Returns:\n tuple: A new tuple with the dictionary appended.\n \"\"\"\n return t + (d,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(tup, d):\n \"\"\"\n This function adds a dictionary to a tuple.\n\n :param tup: Input tuple\n :param d: Input dictionary\n :return: A new tuple with the dictionary appended\n \"\"\"\n return tup + (d,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(tup, dictionary):\n \"\"\"\n Add a dictionary to the tuple.\n\n Parameters:\n tup (tuple): The original tuple\n dictionary (dict): The dictionary to be added to the tuple\n\n Returns:\n tuple: A new tuple with the dictionary added\n \"\"\"\n return tup + (dictionary,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(input_tuple, input_dict):\n \"\"\"\n Function to add a dictionary to the tuple.\n\n Parameters:\n input_tuple (tuple): The original tuple.\n input_dict (dict): The dictionary to be added.\n\n Returns:\n tuple: A new tuple with the dictionary appended.\n \"\"\"\n return input_tuple + (input_dict,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(input_tuple, input_dict):\n return input_tuple + (input_dict,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(t, d):\n \"\"\"\n Adds a dictionary to the end of a tuple.\n\n Parameters:\n t (tuple): Original tuple.\n d (dict): Dictionary to be added to the tuple.\n\n Returns:\n tuple: New tuple with the dictionary added.\n \"\"\"\n return t + (d,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(input_tuple, input_dict):\n return input_tuple + (input_dict,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(tup, dct):\n return tup + (dct,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(input_tuple, input_dict):\n \"\"\"\n Adds a dictionary to the tuple.\n\n :param input_tuple: Tuple to which the dictionary should be added.\n :param input_dict: Dictionary that should be added to the tuple.\n :return: A new tuple with the dictionary added to the end of the input tuple.\n \"\"\"\n return input_tuple + (input_dict,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(t, d):\n return t + (d,)", "matching_cluster_idx": 4}]}, "Mbpp/725": {"dps": 65.3551912568306, "dps_norm": 71.25, "pass@1": 99.0, "profiled": [{"solution": "import re\ndef extract_quotation(text):\n \"\"\"\n Extract values between quotation marks \" \" of the given string.\n \"\"\"\n # Using regular expressions to find all substrings enclosed in double quotes\n matches = re.findall(r'\"(.*?)\"', text)\n return matches", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(input_string):\n # Find all substrings enclosed within double quotes\n matches = re.findall(r'\"(.*?)\"', input_string)\n return matches", "matching_cluster_idx": 4}, {"solution": "import re\ndef extract_quotation(text):\n \"\"\"\n Extract values between quotation marks \" \" from the given string.\n\n Args:\n text (str): The input string containing quoted values.\n\n Returns:\n list: A list of strings extracted from the quoted segments.\n \"\"\"\n return re.findall(r'\"(.*?)\"', text)", "matching_cluster_idx": 4}, {"solution": "import re\ndef extract_quotation(s):\n \"\"\"Extract values between quotation marks \" \" of the given string.\"\"\"\n return re.findall(r'\"(.*?)\"', s)", "matching_cluster_idx": 4}, {"solution": "import re\ndef extract_quotation(s: str) -> list:\n # This regular expression finds all substrings enclosed in double quotation marks.\n return re.findall(r'\"(.*?)\"', s)", "matching_cluster_idx": 4}, {"solution": "import re\ndef extract_quotation(s):\n # Using regex to find all substrings within quotes\n return re.findall(r'\"(.*?)\"', s)", "matching_cluster_idx": 4}, {"solution": "import re\ndef extract_quotation(input_string):\n # Using regex to find all patterns that are within quotation marks\n return re.findall(r'\"(.*?)\"', input_string)", "matching_cluster_idx": 4}, {"solution": "import re\ndef extract_quotation(input_string):\n return re.findall(r'\"(.*?)\"', input_string)", "matching_cluster_idx": 4}, {"solution": "import re\ndef extract_quotation(input_string):\n return re.findall(r'\"(.*?)\"', input_string)", "matching_cluster_idx": 4}, {"solution": "import re\ndef extract_quotation(s: str) -> list:\n return re.findall(r'\"(.*?)\"', s)", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(string):\n # Define the regular expression pattern to find text within quotes\n pattern = r'\\\"(.*?)\\\"'\n # Find all matches of the pattern in the input string\n matches = re.findall(pattern, string)\n return matches", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(input_string):\n \"\"\"\n Extract values between quotation marks \" \" from the given string.\n\n Args:\n input_string (str): The string from which to extract the quoted values.\n\n Returns:\n list: A list of strings that were enclosed in quotation marks.\n \"\"\"\n return re.findall(r'\"(.*?)\"', input_string)", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(input_string):\n # Use regex to find all patterns within double quotes\n return re.findall(r'\"(.*?)\"', input_string)", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(s):\n return re.findall(r'\"(.*?)\"', s)", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(string):\n \"\"\"\n Extract values between quotation marks \" \" of the given string.\n \"\"\"\n # Using regular expressions to find all quoted substrings\n return re.findall(r'\\\"(.*?)\\\"', string)", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(string):\n \"\"\"\n Extract values between quotation marks \" \" of the given string.\n \"\"\"\n # Use regular expression to find all substrings within double quotes\n return re.findall(r'\"([^\"]*)\"', string)", "matching_cluster_idx": 6}, {"solution": "def extract_quotation(s):\n \"\"\"\n This function extracts values between quotation marks \" \" from the given string.\n\n :param s: Input string containing values between quotation marks\n :return: List of extracted values\n \"\"\"\n import re\n return re.findall(r'\"(.*?)\"', s)", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(input_string):\n \"\"\"\n Extracts values between quotation marks \" \" from the given string.\n\n :param input_string: The input string to process.\n :return: A list of extracted values between quotation marks.\n \"\"\"\n # Using regular expressions to find all substrings within double quotes\n matches = re.findall(r'\"([^\"]*)\"', input_string)\n return matches", "matching_cluster_idx": 6}, {"solution": "import re\ndef extract_quotation(s: str) -> list:\n \"\"\"\n Extract values between quotation marks \" \" of the given string.\n\n Args:\n s (str): The input string containing quoted values.\n\n Returns:\n list: A list of strings extracted from between the quotation marks.\n \"\"\"\n # Use regular expressions to find all matches between double quotes\n matches = re.findall(r'\"(.*?)\"', s)\n return matches", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(s):\n \"\"\"\n This function extracts values between quotation marks \" \" of the given string.\n\n :param s: A string containing quoted substrings\n :return: A list of strings extracted from between quotation marks\n \"\"\"\n return re.findall(r'\\\"(.*?)\\\"', s)", "matching_cluster_idx": 5}]}, "Mbpp/732": {"dps": 68.87596899224806, "dps_norm": 81.5, "pass@1": 99.0, "profiled": [{"solution": "def replace_specialchar(text):\n special_chars = [' ', ',', '.']\n for char in special_chars:\n text = text.replace(char, ':')\n return text", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(input_str):\n special_chars = [' ', ',', '.']\n for char in special_chars:\n input_str = input_str.replace(char, ':')\n return input_str", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(input_string):\n \"\"\"\n Function to replace all occurrences of spaces, commas, or dots with a colon.\n\n :param input_string: Input string to process\n :return: Processed string with replacements\n \"\"\"\n special_chars = \" ,.\"\n for char in special_chars:\n input_string = input_string.replace(char, ':')\n return input_string", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(input_string):\n # Define the characters to be replaced\n chars_to_replace = {' ', ',', '.'}\n # Create a resulting string with the replaced characters\n result_string = ''.join([':' if char in chars_to_replace else char for char in input_string])\n return result_string", "matching_cluster_idx": 5}, {"solution": "def replace_specialchar(input_string):\n # Define the characters to be replaced\n replace_chars = {\n ' ': ':',\n ',': ':',\n '.': ':'\n }\n\n # Use a generator expression to create a new string with replacements\n return ''.join(replace_chars[char] if char in replace_chars else char for char in input_string)", "matching_cluster_idx": 4}, {"solution": "def replace_specialchar(input_string):\n replacements = {\n ' ': ':',\n ',': ':',\n '.': ':',\n }\n for key, value in replacements.items():\n input_string = input_string.replace(key, value)\n return input_string", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(text):\n special_chars = {' ', ',', '.'}\n for char in special_chars:\n text = text.replace(char, ':')\n return text", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(s):\n \"\"\"\n Replace all occurrences of spaces, commas, or dots with a colon.\n\n Parameters:\n s (str): The input string.\n\n Returns:\n str: The modified string with spaces, commas, and dots replaced by colons.\n \"\"\"\n # Define the characters to replace\n special_chars = \" ,.\"\n\n # Replace each special character with a colon\n for char in special_chars:\n s = s.replace(char, ':')\n\n return s", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(s):\n \"\"\"\n Replaces all occurrences of spaces, commas, or dots with a colon in the input string.\n\n Parameters:\n s (str): The input string.\n\n Returns:\n str: The string with replacements made.\n \"\"\"\n special_chars = {\n ' ': ':',\n ',': ':',\n '.': ':',\n }\n\n return ''.join(special_chars.get(char, char) for char in s)", "matching_cluster_idx": 4}, {"solution": "def replace_specialchar(input_string):\n \"\"\"\n Replace all occurrences of spaces, commas, or dots with a colon.\n \"\"\"\n # Using str.replace method to replace each special character one by one\n modified_string = input_string.replace(' ', ':')\n modified_string = modified_string.replace(',', ':')\n modified_string = modified_string.replace('.', ':')\n return modified_string", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(text):\n special_characters = {' ', ',', '.'}\n result = ''.join([':' if char in special_characters else char for char in text])\n return result", "matching_cluster_idx": 5}, {"solution": "def replace_specialchar(text):\n # Define the characters to be replaced\n special_chars = [' ', ',', '.']\n\n # Iterate through each character in the text\n for char in special_chars:\n # Replace each special character with a colon\n text = text.replace(char, ':')\n\n return text", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(input_string):\n special_chars = [' ', ',', '.']\n for char in special_chars:\n input_string = input_string.replace(char, ':')\n return input_string", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(s):\n special_chars = {' ', ',', '.'}\n return ''.join(':' if c in special_chars else c for c in s)", "matching_cluster_idx": 5}, {"solution": "def replace_specialchar(s):\n \"\"\"\n This function replaces all occurrences of spaces, commas, or dots with a colon.\n \"\"\"\n special_chars = {\n ' ': ':',\n ',': ':',\n '.': ':'\n }\n result = ''\n for char in s:\n result += special_chars.get(char, char)\n return result", "matching_cluster_idx": 3}, {"solution": "def replace_specialchar(input_string):\n special_chars = \" ,.\"\n for char in special_chars:\n input_string = input_string.replace(char, ':')\n return input_string", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(input_string):\n \"\"\"\n Replace all occurrences of spaces, commas, or dots with a colon.\n \"\"\"\n replace_chars = {' ': ':', ',': ':', '.': ':'}\n result = ''.join(replace_chars.get(c, c) for c in input_string)\n return result", "matching_cluster_idx": 4}, {"solution": "def replace_specialchar(text):\n # List of characters to be replaced\n chars_to_replace = [' ', ',', '.']\n # Iterate over each character in the input text\n for char in chars_to_replace:\n text = text.replace(char, ':')\n return text", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(input_str):\n \"\"\"\n This function replaces all occurrences of spaces, commas, or dots with a colon.\n\n Parameters:\n input_str (str): The input string with spaces, commas, or dots.\n\n Returns:\n str: The modified string with colons replacing spaces, commas, and dots.\n \"\"\"\n # Define the characters to replace and their replacement\n characters_to_replace = \" ,.\"\n replacement_character = \":\"\n\n # Use a generator expression to iterate through the string and replace characters\n modified_string = ''.join(\n replacement_character if char in characters_to_replace else char\n for char in input_str\n )\n\n return modified_string", "matching_cluster_idx": 5}, {"solution": "def replace_specialchar(s):\n \"\"\"\n Replace all occurrences of spaces, commas, or dots with a colon.\n \"\"\"\n return s.replace(' ', ':').replace(',', ':').replace('.', ':')", "matching_cluster_idx": 9}]}, "Mbpp/740": {"dps": 82.23636363636363, "dps_norm": 78.33333333333333, "pass@1": 98.0, "profiled": [{"solution": "def tuple_to_dict(input_tuple):\n # Check if the input tuple has an even number of elements\n if len(input_tuple) % 2 != 0:\n raise ValueError(\"The input tuple must have an even number of elements.\")\n\n # Convert the tuple to a dictionary\n result_dict = {}\n for i in range(0, len(input_tuple), 2):\n result_dict[input_tuple[i]] = input_tuple[i + 1]\n\n return result_dict", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(tup):\n if len(tup) % 2 != 0:\n raise ValueError(\"Tuple must contain an even number of elements\")\n return {tup[i]: tup[i+1] for i in range(0, len(tup), 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(tup):\n # Check if the length of the tuple is even\n if len(tup) % 2 != 0:\n raise ValueError(\"The tuple must have an even number of elements\")\n\n # Create the dictionary from the tuple\n it = iter(tup)\n result_dict = dict(zip(it, it))\n return result_dict", "matching_cluster_idx": 8}, {"solution": "def tuple_to_dict(input_tuple):\n \"\"\"\n Convert the given tuple to a key-value dictionary using adjacent elements.\n :param input_tuple: Tuple containing elements to be converted into dictionary keys and values.\n :return: Dictionary with adjacent elements from the tuple as key-value pairs.\n \"\"\"\n if len(input_tuple) % 2 != 0:\n raise ValueError(\"The tuple must have an even number of elements.\")\n\n it = iter(input_tuple)\n result_dict = dict(zip(it, it))\n return result_dict", "matching_cluster_idx": 8}, {"solution": "def tuple_to_dict(data):\n # Ensure the length of the tuple is even\n if len(data) % 2 != 0:\n raise ValueError(\"Input tuple must have an even number of elements\")\n\n # Create the dictionary using adjacent elements\n return {data[i]: data[i + 1] for i in range(0, len(data), 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(input_tuple):\n # Ensure the input tuple has an even number of elements\n if len(input_tuple) % 2 != 0:\n raise ValueError(\"Input tuple must have an even number of elements\")\n\n # Initialize an empty dictionary to store the key-value pairs\n result_dict = {}\n\n # Iterate over the input tuple in steps of 2 to form key-value pairs\n for i in range(0, len(input_tuple), 2):\n key = input_tuple[i]\n value = input_tuple[i + 1]\n result_dict[key] = value\n\n return result_dict", "matching_cluster_idx": 4}, {"solution": "def tuple_to_dict(t):\n \"\"\"Convert the given tuple to a key-value dictionary using adjacent elements.\"\"\"\n return {t[i]: t[i + 1] for i in range(0, len(t), 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(input_tuple):\n if len(input_tuple) % 2 != 0:\n raise ValueError(\"The tuple must have an even number of elements.\")\n\n return dict(zip(input_tuple[::2], input_tuple[1::2]))", "matching_cluster_idx": 8}, {"solution": "def tuple_to_dict(t):\n \"\"\"\n Convert the given tuple to a key-value dictionary using adjacent elements.\n \"\"\"\n # Check if the tuple has an even number of elements\n if len(t) % 2 != 0:\n raise ValueError(\"Tuple must have an even number of elements\")\n\n # Create a dictionary using adjacent elements from the tuple\n it = iter(t)\n return {key: value for key, value in zip(it, it)}", "matching_cluster_idx": 7}, {"solution": "def tuple_to_dict(input_tuple):\n # Ensure the tuple has an even number of elements\n if len(input_tuple) % 2 != 0:\n raise ValueError(\"The tuple must have an even number of elements.\")\n\n # Create a dictionary using adjacent elements\n it = iter(input_tuple)\n result_dict = dict(zip(it, it))\n\n return result_dict", "matching_cluster_idx": 8}, {"solution": "def tuple_to_dict(input_tuple):\n \"\"\"\n This function converts the given tuple to a key-value dictionary using adjacent elements.\n \"\"\"\n # Initialize an empty dictionary\n result = {}\n\n # Iterate through the tuple in steps of 2\n for i in range(0, len(input_tuple) - 1, 2):\n # Set the key to the element at index i and the value to the element at index i+1\n result[input_tuple[i]] = input_tuple[i + 1]\n\n return result", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(input_tuple):\n \"\"\"\n Convert the given tuple to a key-value dictionary using adjacent elements.\n\n Parameters:\n input_tuple (tuple): The tuple to convert.\n\n Returns:\n dict: A dictionary with adjacent elements of the tuple as key-value pairs.\n \"\"\"\n it = iter(input_tuple)\n return {k: v for k, v in zip(it, it)}", "matching_cluster_idx": 7}, {"solution": "def tuple_to_dict(input_tuple):\n \"\"\"\n Convert the given tuple to a key-value dictionary using adjacent elements.\n :param input_tuple: Tuple of elements.\n :return: Dictionary with key-value pairs from adjacent elements of the tuple.\n \"\"\"\n # Ensure the tuple has an even number of elements\n if len(input_tuple) % 2 != 0:\n raise ValueError(\"Tuple must have an even number of elements.\")\n\n # Create dictionary from adjacent elements\n it = iter(input_tuple)\n return dict(zip(it, it))", "matching_cluster_idx": 8}, {"solution": "def tuple_to_dict(t):\n \"\"\"Convert a given tuple to a key-value dictionary using adjacent elements.\"\"\"\n if len(t) % 2 != 0:\n raise ValueError(\"The tuple must have an even number of elements\")\n\n return {t[i]: t[i + 1] for i in range(0, len(t), 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(t):\n # Check if the length of the tuple is even\n if len(t) % 2 != 0:\n raise ValueError(\"Tuple must have an even number of elements.\")\n\n # Initialize an empty dictionary\n result = {}\n\n # Iterate over the tuple with a step of 2\n for i in range(0, len(t), 2):\n result[t[i]] = t[i + 1]\n\n return result", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(t):\n it = iter(t)\n return {k: v for k, v in zip(it, it)}", "matching_cluster_idx": 7}, {"solution": "def tuple_to_dict(input_tuple):\n \"\"\"\n Converts a tuple to a dictionary with adjacent elements as key-value pairs.\n\n Parameters:\n input_tuple (tuple): The input tuple to be converted.\n\n Returns:\n dict: The resulting dictionary with adjacent elements as key-value pairs.\n \"\"\"\n # Create an empty dictionary\n result = {}\n\n # Iterate through the tuple in steps of 2\n for i in range(0, len(input_tuple), 2):\n # Check if there's a value pair for the current key\n if i + 1 < len(input_tuple):\n result[input_tuple[i]] = input_tuple[i + 1]\n\n return result", "matching_cluster_idx": 3}, {"solution": "def tuple_to_dict(tup):\n \"\"\"\n Convert the given tuple to a key-value dictionary using adjacent elements.\n \"\"\"\n # Create a dictionary from the tuple using adjacent elements\n return {tup[i]: tup[i+1] for i in range(0, len(tup), 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(t):\n it = iter(t)\n return dict(zip(it, it))", "matching_cluster_idx": 8}, {"solution": "def tuple_to_dict(input_tuple):\n # Ensure the tuple has an even number of elements\n if len(input_tuple) % 2 != 0:\n raise ValueError(\"Tuple must have an even number of elements\")\n\n # Initialize an empty dictionary\n result_dict = {}\n\n # Iterate through the tuple with step 2\n for i in range(0, len(input_tuple), 2):\n # Use the first element as key and the second as value\n result_dict[input_tuple[i]] = input_tuple[i + 1]\n\n return result_dict", "matching_cluster_idx": 5}]}, "Mbpp/744": {"dps": 43.76712328767123, "dps_norm": 59.166666666666664, "pass@1": 100.0, "profiled": [{"solution": "def check_none(t):\n \"\"\"\n Check if the given tuple has any None value.\n\n :param t: Tuple to check for None values.\n :return: True if any None value is found, else False.\n \"\"\"\n return any(value is None for value in t)", "matching_cluster_idx": 2}, {"solution": "def check_none(t):\n \"\"\"\n This function checks if a given tuple contains any None value.\n\n Parameters:\n t (tuple): The tuple to check.\n\n Returns:\n bool: True if the tuple contains any None value, False otherwise.\n \"\"\"\n return any(x is None for x in t)", "matching_cluster_idx": 1}, {"solution": "def check_none(input_tuple):\n \"\"\"\n This function checks if the given tuple has any None value or not.\n :param input_tuple: The tuple to be checked.\n :return: True if the tuple contains a None value, False otherwise.\n \"\"\"\n return any(value is None for value in input_tuple)", "matching_cluster_idx": 2}, {"solution": "def check_none(tup):\n return any(x is None for x in tup)", "matching_cluster_idx": 2}, {"solution": "def check_none(tpl):\n \"\"\"\n Check if the given tuple has any None value.\n\n Parameters:\n tpl (tuple): The tuple to be checked.\n\n Returns:\n bool: True if the tuple contains None, False otherwise.\n \"\"\"\n return any(x is None for x in tpl)", "matching_cluster_idx": 2}, {"solution": "def check_none(t):\n \"\"\"\n Check if the given tuple has any None value.\n\n Parameters:\n t (tuple): The tuple to be checked.\n\n Returns:\n bool: True if the tuple contains None, False otherwise.\n \"\"\"\n return None in t", "matching_cluster_idx": 5}, {"solution": "def check_none(input_tuple):\n return any(element is None for element in input_tuple)", "matching_cluster_idx": 2}, {"solution": "def check_none(tup):\n \"\"\"\n Check if the given tuple has any None value.\n\n Args:\n tup (tuple): A tuple to check.\n\n Returns:\n bool: True if there is any None value in the tuple, False otherwise.\n \"\"\"\n return any(value is None for value in tup)", "matching_cluster_idx": 2}, {"solution": "def check_none(tup):\n \"\"\"\n Check if the given tuple has any None value or not.\n\n :param tup: A tuple to check for None values\n :return: True if the tuple has any None value, False otherwise\n \"\"\"\n return None in tup", "matching_cluster_idx": 5}, {"solution": "def check_none(input_tuple):\n \"\"\"\n Checks if the given tuple has any None value.\n\n Parameters:\n input_tuple (tuple): The tuple to check.\n\n Returns:\n bool: True if there is any None value in the tuple, False otherwise.\n \"\"\"\n return any(x is None for x in input_tuple)", "matching_cluster_idx": 2}, {"solution": "def check_none(tup):\n \"\"\"\n Check if the given tuple has any None value.\n\n :param tup: tuple\n :return: True if tuple contains None, otherwise False\n \"\"\"\n return any(x is None for x in tup)", "matching_cluster_idx": 2}, {"solution": "def check_none(t):\n \"\"\"Check if the given tuple contains any None values.\"\"\"\n return any(element is None for element in t)", "matching_cluster_idx": 2}, {"solution": "def check_none(t):\n \"\"\"\n This function checks if the given tuple contains any None value.\n\n Parameters:\n t (tuple): The tuple to check for None values.\n\n Returns:\n bool: True if the tuple contains any None value, False otherwise.\n \"\"\"\n return any(x is None for x in t)", "matching_cluster_idx": 2}, {"solution": "def check_none(tup):\n \"\"\"\n Function to check if the given tuple has any None value.\n\n Parameters:\n tup (tuple): Input tuple to check for None values.\n\n Returns:\n bool: True if there is any None value, False otherwise.\n \"\"\"\n return any(elem is None for elem in tup)", "matching_cluster_idx": 2}, {"solution": "def check_none(tup):\n \"\"\"\n Check if the given tuple has any None value.\n\n Parameters:\n tup (tuple): The tuple to be checked.\n\n Returns:\n bool: True if any value in the tuple is None, otherwise False.\n \"\"\"\n return any(item is None for item in tup)", "matching_cluster_idx": 2}, {"solution": "def check_none(t):\n \"\"\"\n Check if the given tuple has any None value or not.\n\n Parameters:\n t (tuple): The tuple to check.\n\n Returns:\n bool: True if there is any None value in the tuple, False otherwise.\n \"\"\"\n return any(x is None for x in t)", "matching_cluster_idx": 2}, {"solution": "def check_none(tup):\n return any(x is None for x in tup)", "matching_cluster_idx": 2}, {"solution": "def check_none(tup):\n \"\"\"\n Check if the given tuple has any None value.\n\n Args:\n tup (tuple): The tuple to check.\n\n Returns:\n bool: True if the tuple contains None, False otherwise.\n \"\"\"\n return None in tup", "matching_cluster_idx": 5}, {"solution": "def check_none(tup):\n \"\"\"\n Check if the given tuple has any None value.\n\n Args:\n tup (tuple): The tuple to check.\n\n Returns:\n bool: True if there is any None value in the tuple, False otherwise.\n \"\"\"\n return None in tup", "matching_cluster_idx": 5}, {"solution": "def check_none(input_tuple):\n \"\"\"\n Checks if the given tuple contains any None value.\n\n Parameters:\n input_tuple (tuple): The tuple to check.\n\n Returns:\n bool: True if the tuple contains a None value, False otherwise.\n \"\"\"\n return any(item is None for item in input_tuple)", "matching_cluster_idx": 2}]}, "Mbpp/750": {"dps": 61.564625850340136, "dps_norm": 61.666666666666664, "pass@1": 100.0, "profiled": [{"solution": "def add_tuple(lst, tup):\n \"\"\"\n Adds elements of the tuple to the list.\n\n Parameters:\n lst (list): The list to which elements will be added.\n tup (tuple): The tuple whose elements will be added to the list.\n\n Returns:\n list: The list with the elements of the tuple added.\n \"\"\"\n # Extend the list with elements of the tuple\n lst.extend(tup)\n return lst", "matching_cluster_idx": 5}, {"solution": "def add_tuple(lst, tup):\n \"\"\"\n Add the elements of the given tuple to the given list.\n\n Parameters:\n lst (list): The list to which the elements are to be added.\n tup (tuple): The tuple whose elements are to be added to the list.\n\n Returns:\n list: The list with the tuple elements added.\n \"\"\"\n lst.extend(tup)\n return lst", "matching_cluster_idx": 5}, {"solution": "def add_tuple(lst, tpl):\n \"\"\"\n Adds the elements of a tuple to a list and returns the modified list.\n\n Parameters:\n lst (list): The list to which the tuple elements will be added.\n tpl (tuple): The tuple whose elements will be added to the list.\n\n Returns:\n list: The modified list with the tuple elements added.\n \"\"\"\n return lst + list(tpl)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(lst, tpl):\n # Convert the tuple to a list and extend the given list with it\n lst.extend(list(tpl))\n return lst", "matching_cluster_idx": 4}, {"solution": "def add_tuple(lst, tpl):\n \"\"\"\n Add the given tuple to the given list.\n\n Parameters:\n lst (list): The list to which the tuple will be added.\n tpl (tuple): The tuple to be added to the list.\n\n Returns:\n list: A new list containing elements of the original list followed by the elements of the tuple.\n \"\"\"\n return lst + list(tpl)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(lst, tpl):\n \"\"\"Add the given tuple to the given list and return the new list.\"\"\"\n return lst + list(tpl)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(lst, tpl):\n \"\"\"\n Function to add the elements of the given tuple to the given list.\n\n Parameters:\n lst (list): The list to which the tuple elements will be added.\n tpl (tuple): The tuple whose elements will be added to the list.\n\n Returns:\n list: A new list with elements of the tuple added to the input list.\n \"\"\"\n return lst + list(tpl)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(lst, tup):\n return lst + list(tup)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(lst, tpl):\n \"\"\"\n This function takes a list and a tuple, and returns a new list with\n the elements of the tuple added to the list.\n\n :param lst: list of elements\n :param tpl: tuple of elements\n :return: list with elements of the tuple added\n \"\"\"\n return lst + list(tpl)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(lst, tpl):\n \"\"\"\n Function to add the elements of the given tuple to the given list.\n\n :param lst: List to which tuple elements will be added\n :param tpl: Tuple whose elements will be added to the list\n :return: List with the tuple elements added\n \"\"\"\n return lst + list(tpl)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(lst, tpl):\n \"\"\"\n This function takes a list and a tuple as inputs and appends the elements of the tuple\n to the end of the list. It returns the modified list.\n\n Args:\n lst (list): The list to which the tuple elements will be added.\n tpl (tuple): The tuple whose elements will be appended to the list.\n\n Returns:\n list: The modified list with the tuple elements appended.\n \"\"\"\n lst.extend(tpl)\n return lst", "matching_cluster_idx": 5}, {"solution": "def add_tuple(lst, tpl):\n # Convert the tuple to a list and extend the original list with it\n lst.extend(list(tpl))\n return lst", "matching_cluster_idx": 4}, {"solution": "def add_tuple(lst, tpl):\n \"\"\"\n Adds elements of the given tuple to the given list.\n\n :param lst: List to which the tuple elements will be added.\n :param tpl: Tuple whose elements will be added to the list.\n :return: A new list containing elements from both the list and the tuple.\n \"\"\"\n return lst + list(tpl)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(lst, tpl):\n \"\"\"\n Adds the elements of the given tuple to the given list.\n\n Parameters:\n lst (list): The list to which elements are to be added.\n tpl (tuple): The tuple whose elements are to be added to the list.\n\n Returns:\n list: A new list containing the elements of the input list and the tuple.\n \"\"\"\n return lst + list(tpl)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(lst, tup):\n \"\"\"\n Add elements of the tuple to the list.\n\n Args:\n lst (list): The list to which elements will be added.\n tup (tuple): The tuple containing elements to be added to the list.\n\n Returns:\n list: The list with added elements.\n \"\"\"\n return lst + list(tup)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(lst, tpl):\n \"\"\"\n Adds elements of a tuple to a list.\n\n Parameters:\n lst (list): The list to which elements should be added.\n tpl (tuple): The tuple whose elements will be added to the list.\n\n Returns:\n list: A new list with elements from the tuple added to the list.\n \"\"\"\n return lst + list(tpl)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(lst, tpl):\n return lst + list(tpl)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(lst, tpl):\n \"\"\"\n Add the given tuple to the given list.\n\n Parameters:\n lst (list): The list to which the tuple elements will be added.\n tpl (tuple): The tuple whose elements will be added to the list.\n\n Returns:\n list: A new list with elements of the tuple appended to the list.\n \"\"\"\n return lst + list(tpl)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(lst, tpl):\n \"\"\"\n Add the given tuple to the given list.\n :param lst: List to which the tuple will be added.\n :param tpl: Tuple to be added to the list.\n :return: The list after adding the tuple elements.\n \"\"\"\n return lst + list(tpl)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(lst, tup):\n # Convert tuple to list and extend the original list with it\n lst.extend(list(tup))\n return lst", "matching_cluster_idx": 3}]}, "Mbpp/753": {"dps": 6.140939597315437, "dps_norm": 51.25, "pass@1": 95.0, "profiled": [{"solution": "def min_k(records, k):\n \"\"\"\n This function returns the top k records with the minimum score from a list of tuples.\n\n :param records: List[Tuple[str, int]]\n :param k: int\n :return: List[Tuple[str, int]]\n \"\"\"\n # Sort the records based on the second element of the tuples (the score)\n sorted_records = sorted(records, key=lambda x: x[1])\n # Return the first k records from the sorted list\n return sorted_records[:k]", "matching_cluster_idx": 1}, {"solution": "def min_k(tuples, k):\n \"\"\"\n Find the minimum k records from a list of tuples based on the second element of each tuple.\n\n :param tuples: List of tuples where each tuple contains a name (str) and a score (int)\n :param k: The number of minimum records to return\n :return: List of k tuples with the minimum scores\n \"\"\"\n # Sort the tuples based on the second element (score)\n sorted_tuples = sorted(tuples, key=lambda x: x[1])\n\n # Return the first k tuples from the sorted list\n return sorted_tuples[:k]", "matching_cluster_idx": 1}, {"solution": "def min_k(records, k):\n \"\"\"\n Function to find the minimum k records from a list of tuples.\n\n Args:\n records (list of tuple): The list of records where each record is a tuple of a name (str) and a score (int).\n k (int): The number of minimum records to return.\n\n Returns:\n list of tuple: A list of the k smallest records.\n \"\"\"\n sorted_records = sorted(records, key=lambda x: x[1]) # Sorting by the second element of the tuple\n return sorted_records[:k] # Returning the first k elements", "matching_cluster_idx": 1}, {"solution": "def min_k(records, k):\n \"\"\"\n Find the minimum k records from a tuple list based on the integer values.\n\n Args:\n records (list of tuples): List of tuples where each tuple contains a string and an integer.\n k (int): Number of minimum records to find.\n\n Returns:\n list of tuples: List of k tuples with the minimum integer values.\n \"\"\"\n sorted_records = sorted(records, key=lambda x: x[1])\n return sorted_records[:k]", "matching_cluster_idx": 1}, {"solution": "def min_k(tuple_list, k):\n # Sort the tuple list based on the second element (index 1)\n sorted_list = sorted(tuple_list, key=lambda x: x[1])\n\n # Return the first k elements from the sorted list\n return sorted_list[:k]", "matching_cluster_idx": 1}, {"solution": "def min_k(records, k):\n \"\"\"\n Function to find the minimum k records from a tuple list.\n\n Parameters:\n - records: List of tuples, where each tuple contains a name (string) and a score (int).\n - k: Integer representing the number of minimum records to return.\n\n Returns:\n - List of tuples representing the k records with the minimum scores.\n \"\"\"\n # Sort the records based on the score (second item in the tuple)\n sorted_records = sorted(records, key=lambda x: x[1])\n # Return the first k records from the sorted list\n return sorted_records[:k]", "matching_cluster_idx": 1}, {"solution": "def min_k(records, k):\n # Sort the records by the second element of each tuple (the score)\n sorted_records = sorted(records, key=lambda x: x[1])\n # Return the first k records\n return sorted_records[:k]", "matching_cluster_idx": 1}, {"solution": "def min_k(records, k):\n # Sort the list of tuples based on the second element of each tuple\n sorted_records = sorted(records, key=lambda x: x[1])\n # Return the first k records\n return sorted_records[:k]", "matching_cluster_idx": 1}, {"solution": "def min_k(records, k):\n \"\"\"\n Find the minimum k records from the tuple list.\n\n Parameters:\n records (list of tuples): List of tuples where each tuple contains a string and an integer.\n k (int): Number of minimum records to return.\n\n Returns:\n list of tuples: List of k tuples with the smallest integers.\n \"\"\"\n # Sort the list of tuples based on the second element in each tuple\n sorted_records = sorted(records, key=lambda x: x[1])\n # Return the first k elements from the sorted list\n return sorted_records[:k]", "matching_cluster_idx": 1}, {"solution": "def min_k(data, k):\n # Sort the data by the second element of each tuple (the score)\n sorted_data = sorted(data, key=lambda x: x[1])\n # Return the first k elements\n return sorted_data[:k]", "matching_cluster_idx": 1}, {"solution": "def min_k(records, k):\n # Sort the list of tuples based on the second element of each tuple\n records.sort(key=lambda x: x[1])\n # Return the first k elements\n return records[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(records, k):\n \"\"\"\n Finds the k minimum records from a list of tuples.\n\n :param records: List of tuples where each tuple contains a name and a score.\n :param k: Number of minimum records to find.\n :return: List of k tuples with the minimum scores.\n \"\"\"\n # Sort the records by the second element of each tuple (the score)\n sorted_records = sorted(records, key=lambda x: x[1])\n\n # Return the first k elements from the sorted list\n return sorted_records[:k]", "matching_cluster_idx": 1}, {"solution": "def min_k(tuples, k):\n \"\"\"\n Returns the k minimum elements from a list of tuples, sorted by the second element of the tuple.\n\n :param tuples: List of tuples (name, value)\n :param k: Number of minimum elements to return\n :return: List of k minimum tuples\n \"\"\"\n # Sort the tuples based on the second element\n sorted_tuples = sorted(tuples, key=lambda x: x[1])\n # Return the first k elements\n return sorted_tuples[:k]", "matching_cluster_idx": 1}, {"solution": "def min_k(records, k):\n # Sort the records by the second element in the tuple\n sorted_records = sorted(records, key=lambda x: x[1])\n # Return the first k elements\n return sorted_records[:k]", "matching_cluster_idx": 1}, {"solution": "def min_k(records, k):\n # Sort records based on the integer value\n sorted_records = sorted(records, key=lambda x: x[1])\n\n # Return the first k elements\n return sorted_records[:k]", "matching_cluster_idx": 1}, {"solution": "def min_k(tuples, k):\n \"\"\"\n Function to find the minimum k records from a tuple list.\n\n Parameters:\n tuples (list of tuples): List of tuples where each tuple contains a string and an integer.\n k (int): Number of minimum records to find.\n\n Returns:\n list of tuples: List of minimum k tuples based on the integer values.\n \"\"\"\n return sorted(tuples, key=lambda x: x[1])[:k]", "matching_cluster_idx": 1}, {"solution": "def min_k(records, k):\n \"\"\"\n Find minimum k records from a list of tuples.\n\n :param records: List of tuples, where each tuple contains a name (string) and a score (int).\n :param k: The number of minimum records to return.\n :return: List of k tuples with the minimum scores.\n \"\"\"\n # Sort the records by the score in ascending order\n sorted_records = sorted(records, key=lambda x: x[1])\n # Return the first k elements from the sorted list\n return sorted_records[:k]", "matching_cluster_idx": 1}, {"solution": "def min_k(records, k):\n \"\"\"\n Find the minimum k records from a list of tuples based on the second element in each tuple.\n\n :param records: List of tuples, where each tuple contains a name (string) and a score (integer)\n :param k: Number of minimum records to return\n :return: List of tuples representing the k minimum records\n \"\"\"\n # Sort the records by the second element in each tuple (the score)\n sorted_records = sorted(records, key=lambda x: x[1])\n\n # Return the first k elements from the sorted list\n return sorted_records[:k]", "matching_cluster_idx": 1}, {"solution": "def min_k(records, k):\n \"\"\"\n This function returns the k smallest records from a list of tuples.\n\n Parameters:\n records (list of tuples): The list of tuples, each containing a name and a number.\n k (int): The number of smallest records to return.\n\n Returns:\n list of tuples: The k smallest records.\n \"\"\"\n # Sort the list of records by the second element of each tuple\n sorted_records = sorted(records, key=lambda x: x[1])\n\n # Return the first k records from the sorted list\n return sorted_records[:k]", "matching_cluster_idx": 1}, {"solution": "def min_k(records, k):\n \"\"\"Find the minimum k records from a tuple list.\"\"\"\n # Sort the records based on the second element of each tuple (numerical value)\n sorted_records = sorted(records, key=lambda x: x[1])\n # Return the first k elements of the sorted list\n return sorted_records[:k]", "matching_cluster_idx": 1}]}, "Mbpp/754": {"dps": 90.17241379310346, "dps_norm": 88.125, "pass@1": 84.0, "profiled": [{"solution": "def extract_index_list(l1, l2, l3):\n common_elements = []\n for i in range(min(len(l1), len(l2), len(l3))):\n if l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n \"\"\"\n Function to find common elements from three lists if they appear at the same index.\n\n Args:\n l1 (list): First list of elements.\n l2 (list): Second list of elements.\n l3 (list): Third list of elements.\n\n Returns:\n list: List of common elements that appear at the same index in all three lists.\n \"\"\"\n # Find the minimum length of the three lists to avoid index out of range errors\n min_length = min(len(l1), len(l2), len(l3))\n\n # Initialize a list to store common elements\n common_elements = []\n\n # Iterate through the indices up to the minimum length\n for i in range(min_length):\n if l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n # Initialize an empty list to store the common elements\n common_elements = []\n\n # Iterate through the indices of the lists\n for i in range(min(len(l1), len(l2), len(l3))):\n # Check if elements at the same index are equal\n if l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n \"\"\"\n Find common elements from three lists where the elements appear in all three lists under the same index.\n\n :param l1: First list of elements\n :param l2: Second list of elements\n :param l3: Third list of elements\n :return: List of common elements\n \"\"\"\n common_elements = []\n\n # Determine the minimum length of the lists to avoid index out of range\n min_length = min(len(l1), len(l2), len(l3))\n\n # Iterate through the lists up to the minimum length\n for i in range(min_length):\n if l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n \"\"\"\n We say that an element is common for lists l1, l2, l3 if it appears in all three lists under the same index.\n This function finds common elements from three lists and returns them as a list.\n \"\"\"\n common_elements = []\n\n # Check if all lists have the same length\n min_length = min(len(l1), len(l2), len(l3))\n\n for i in range(min_length):\n if l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n # Ensure all lists have the same length\n min_length = min(len(l1), len(l2), len(l3))\n common_elements = []\n\n # Iterate through the lists up to the length of the shortest list\n for i in range(min_length):\n # Check if elements at the same index are common in all three lists\n if l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n common_elements = []\n for i in range(min(len(l1), len(l2), len(l3))):\n if l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n # Determine the minimum length of the three lists to avoid index errors\n min_length = min(len(l1), len(l2), len(l3))\n\n # Initialize an empty list to store common elements\n common_elements = []\n\n # Iterate through the indices up to the minimum length\n for i in range(min_length):\n # Check if elements at the same index are the same in all three lists\n if l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n # Use zip to pair up elements from all three lists by index\n common_elements = [a for a, b, c in zip(l1, l2, l3) if a == b == c]\n return common_elements", "matching_cluster_idx": 7}, {"solution": "def extract_index_list(l1, l2, l3):\n # Finding common elements by comparing elements at same indices in the three lists\n common_elements = []\n for i in range(min(len(l1), len(l2), len(l3))): # iterate up to the length of the shortest list\n if l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n # Initialize an empty list to store common elements\n common_elements = []\n\n # Iterate through the lists and compare elements at the same index\n for i in range(min(len(l1), len(l2), len(l3))):\n if l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n # Find the minimum length of the three lists to avoid index out of range errors\n min_length = min(len(l1), len(l2), len(l3))\n\n # Initialize a list to store the common elements\n common_elements = []\n\n # Iterate over the indices up to the minimum length\n for i in range(min_length):\n # Check if the elements at the current index are the same in all three lists\n if l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n # Ensure all lists have the same length\n common_length = min(len(l1), len(l2), len(l3))\n\n # Extract common elements\n common_elements = [\n l1[i] for i in range(common_length)\n if l1[i] == l2[i] and l1[i] == l3[i]\n ]\n\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n common_elements = []\n for i in range(min(len(l1), len(l2), len(l3))):\n if l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n common_elements = []\n for i in range(min(len(l1), len(l2), len(l3))):\n if l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n common_elements = []\n for i in range(min(len(l1), len(l2), len(l3))):\n if l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n common_elements = []\n # We loop through the elements of the lists using the range of the minimum length to avoid IndexError\n for i in range(min(len(l1), len(l2), len(l3))):\n if l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n \"\"\"\n This function finds the common elements at the same index from three lists.\n\n Args:\n l1 (list): First list of elements.\n l2 (list): Second list of elements.\n l3 (list): Third list of elements.\n\n Returns:\n list: A list of common elements found at the same index in all three lists.\n \"\"\"\n common_elements = []\n\n # Loop through the lists and compare elements at the same index\n for i in range(min(len(l1), len(l2), len(l3))):\n if l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n \"\"\"\n Find common elements from three lists where the elements are at the same index in all three lists.\n\n Parameters:\n l1 (list): First list.\n l2 (list): Second list.\n l3 (list): Third list.\n\n Returns:\n list: List of common elements.\n \"\"\"\n common_elements = []\n min_length = min(len(l1), len(l2), len(l3))\n\n for i in range(min_length):\n if l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n # Find the minimum length among the three lists to avoid IndexError\n min_length = min(len(l1), len(l2), len(l3))\n\n # Initialize an empty list to hold common elements\n common_elements = []\n\n # Loop through the indices up to the minimum length\n for i in range(min_length):\n # Check if elements at the same index are equal in all three lists\n if l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n\n return common_elements", "matching_cluster_idx": 6}]}, "Mbpp/755": {"dps": 51.32743362831859, "dps_norm": 73.80952380952381, "pass@1": 14.0, "profiled": [{"solution": "def second_smallest(numbers):\n # Sort the list to find the smallest and the second smallest elements.\n sorted_numbers = sorted(set(numbers))\n\n # Check if the list has at least two distinct elements.\n if len(sorted_numbers) < 2:\n return None # or raise an exception, depending on requirements\n\n # The second smallest element will be at the second position in the sorted list.\n return sorted_numbers[1]", "matching_cluster_idx": 5}, {"solution": "def second_smallest(numbers):\n # To avoid sorting, first remove duplicates by converting the list to a set\n unique_numbers = list(set(numbers))\n\n # If there are fewer than 2 unique numbers, return None\n if len(unique_numbers) < 2:\n return None\n\n # Initialize the first and second smallest numbers to infinity\n first_smallest = second_smallest = float('inf')\n\n for num in unique_numbers:\n if num < first_smallest:\n second_smallest = first_smallest\n first_smallest = num\n elif first_smallest < num < second_smallest:\n second_smallest = num\n\n return second_smallest", "matching_cluster_idx": 2}, {"solution": "def second_smallest(numbers):\n \"\"\"\n This function returns the second smallest number in a list.\n \"\"\"\n if len(numbers) < 2:\n return None # Not enough numbers to find the second smallest\n\n # Remove duplicates\n unique_numbers = list(set(numbers))\n\n if len(unique_numbers) < 2:\n return None # Not enough unique numbers to find the second smallest\n\n # Sort the list to find the smallest and second smallest numbers\n unique_numbers.sort()\n\n # Return the second smallest number\n return unique_numbers[1]", "matching_cluster_idx": 5}, {"solution": "def second_smallest(numbers):\n if len(numbers) < 2:\n return None\n\n # Initialize the smallest and second smallest to infinity\n first_min = float('inf')\n second_min = float('inf')\n\n for number in numbers:\n if number < first_min:\n second_min = first_min\n first_min = number\n elif first_min < number < second_min:\n second_min = number\n\n if second_min == float('inf'):\n return None # In case all numbers are same or list length is less than 2\n return second_min", "matching_cluster_idx": 3}, {"solution": "def second_smallest(numbers):\n if len(numbers) < 2:\n return None\n\n first, second = float('inf'), float('inf')\n for num in numbers:\n if num < first:\n second = first\n first = num\n elif first < num < second:\n second = num\n return second if second != float('inf') else None", "matching_cluster_idx": 3}, {"solution": "def second_smallest(numbers):\n # Sort the list and remove duplicates\n unique_numbers = sorted(set(numbers))\n\n # Ensure the list has at least two different numbers\n if len(unique_numbers) < 2:\n return None\n\n return unique_numbers[1]", "matching_cluster_idx": 5}, {"solution": "def second_smallest(numbers):\n # Handling edge cases\n if len(numbers) < 2:\n return None # Not enough elements to find a second smallest\n\n # Initializing the first and second smallest elements\n first_smallest = second_smallest_val = float('inf')\n\n for num in numbers:\n if num < first_smallest:\n second_smallest_val = first_smallest\n first_smallest = num\n elif first_smallest < num < second_smallest_val:\n second_smallest_val = num\n\n return second_smallest_val if second_smallest_val != float('inf') else None", "matching_cluster_idx": 3}, {"solution": "def second_smallest(numbers):\n if len(numbers) < 2:\n return None\n first, second = float('inf'), float('inf')\n for number in numbers:\n if number < first:\n first, second = number, first\n elif first < number < second:\n second = number\n if second == float('inf'):\n return None\n return second", "matching_cluster_idx": 3}, {"solution": "def second_smallest(numbers):\n if len(numbers) < 2:\n return None\n\n # Initialize the smallest and second smallest variables\n first = second = float('inf')\n\n for num in numbers:\n if num < first:\n first, second = num, first\n elif first < num < second:\n second = num\n\n if second == float('inf'):\n return None\n\n return second", "matching_cluster_idx": 3}, {"solution": "def second_smallest(numbers):\n # We assume the list has at least two different numbers\n # If the list contains less than 2 numbers, return None\n if len(numbers) < 2:\n return None\n\n first = float('inf')\n second = float('inf')\n\n for number in numbers:\n if number < first:\n second = first\n first = number\n elif first < number < second:\n second = number\n\n # If second is still infinity, it means there are duplicates and no second smallest number\n if second == float('inf'):\n return None\n\n return second", "matching_cluster_idx": 3}, {"solution": "def second_smallest(numbers):\n if len(numbers) < 2:\n return None # not enough numbers to have a second smallest\n\n first_smallest = float('inf')\n second_smallest = float('inf')\n\n for num in numbers:\n if num < first_smallest:\n second_smallest = first_smallest\n first_smallest = num\n elif first_smallest < num < second_smallest:\n second_smallest = num\n\n return second_smallest if second_smallest != float('inf') else None", "matching_cluster_idx": 3}, {"solution": "def second_smallest(numbers):\n if len(numbers) < 2:\n return None\n\n first_smallest = float('inf')\n second_smallest = float('inf')\n\n for number in numbers:\n if number < first_smallest:\n second_smallest = first_smallest\n first_smallest = number\n elif first_smallest < number < second_smallest:\n second_smallest = number\n\n return second_smallest if second_smallest != float('inf') else None", "matching_cluster_idx": 3}, {"solution": "def second_smallest(numbers):\n # Ensure the list contains at least two unique numbers\n if len(numbers) < 2:\n return None\n\n # Remove duplicates and sort the list\n unique_numbers = sorted(set(numbers))\n\n # Ensure there are at least two unique numbers\n if len(unique_numbers) < 2:\n return None\n\n # Return the second smallest number\n return unique_numbers[1]", "matching_cluster_idx": 5}, {"solution": "def second_smallest(numbers):\n # Check if the list has at least two unique numbers\n if len(set(numbers)) < 2:\n return None # Or raise an exception based on your preference\n\n # Initialize two variables to hold the smallest and second smallest numbers\n first_smallest = float('inf')\n second_smallest_num = float('inf')\n\n for num in numbers:\n if num < first_smallest:\n second_smallest_num = first_smallest\n first_smallest = num\n elif first_smallest < num < second_smallest_num:\n second_smallest_num = num\n\n return second_smallest_num", "matching_cluster_idx": 2}]}, "Mbpp/757": {"dps": 91.35514018691589, "dps_norm": 61.53846153846154, "pass@1": 37.0, "profiled": [{"solution": "def count_reverse_pairs(str_list):\n \"\"\"\n Count the pairs of reverse strings in the given string list.\n\n :param str_list: List of strings\n :return: Number of reverse pairs\n \"\"\"\n reverse_dict = {}\n count = 0\n\n # Iterate through each string in the list\n for s in str_list:\n reverse_s = s[::-1] # Reverse the string\n if s in reverse_dict:\n count += reverse_dict[s]\n if reverse_s in reverse_dict:\n reverse_dict[reverse_s] += 1\n else:\n reverse_dict[reverse_s] = 1\n\n return count", "matching_cluster_idx": 12}, {"solution": "def count_reverse_pairs(str_list):\n count = 0\n for i in range(len(str_list)):\n for j in range(i + 1, len(str_list)):\n if str_list[i] == str_list[j][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(words):\n \"\"\"Counts the pairs of reverse strings in the given string list.\"\"\"\n reverse_map = {}\n count = 0\n\n for word in words:\n # Check if the reversed word is already in the map\n reversed_word = word[::-1]\n if reversed_word in reverse_map:\n count += reverse_map[reversed_word]\n\n # Add the word to the map\n if word in reverse_map:\n reverse_map[word] += 1\n else:\n reverse_map[word] = 1\n\n return count", "matching_cluster_idx": 12}, {"solution": "def count_reverse_pairs(lst):\n \"\"\"\n This function counts the number of pairs of strings in the list where\n one string is the reverse of the other.\n \"\"\"\n reverse_map = {}\n count = 0\n for word in lst:\n reversed_word = word[::-1]\n if reversed_word in reverse_map:\n count += reverse_map[reversed_word]\n if word in reverse_map:\n reverse_map[word] += 1\n else:\n reverse_map[word] = 1\n return count", "matching_cluster_idx": 12}, {"solution": "def count_reverse_pairs(lst):\n count = 0\n n = len(lst)\n for i in range(n):\n for j in range(i + 1, n):\n if lst[i] == lst[j][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(lst):\n count = 0\n for i in range(len(lst)):\n for j in range(i + 1, len(lst)):\n if lst[i] == lst[j][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(words):\n def is_reverse(word1, word2):\n return word1 == word2[::-1]\n\n n = len(words)\n count = 0\n for i in range(n):\n for j in range(i + 1, n):\n if is_reverse(words[i], words[j]):\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(string_list):\n count = 0\n # Iterate over each pair of words in the list\n for i in range(len(string_list)):\n for j in range(i + 1, len(string_list)):\n if string_list[i] == string_list[j][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(string_list):\n \"\"\"Count the number of pairs of reverse strings in the given string list.\"\"\"\n reverse_pairs_count = 0\n n = len(string_list)\n\n # Create a dictionary to store the count of each string in the list\n string_count = {}\n\n for string in string_list:\n reversed_string = string[::-1]\n if reversed_string in string_count:\n reverse_pairs_count += string_count[reversed_string]\n\n if string in string_count:\n string_count[string] += 1\n else:\n string_count[string] = 1\n\n return reverse_pairs_count", "matching_cluster_idx": 12}, {"solution": "def count_reverse_pairs(strings):\n \"\"\"\n Function to count the pairs of reverse strings in the given string list.\n \"\"\"\n reverse_dict = {}\n count = 0\n\n for s in strings:\n reversed_s = s[::-1]\n if reversed_s in reverse_dict:\n count += reverse_dict[reversed_s]\n if s in reverse_dict:\n reverse_dict[s] += 1\n else:\n reverse_dict[s] = 1\n\n return count", "matching_cluster_idx": 12}, {"solution": "def count_reverse_pairs(string_list):\n count = 0\n for i in range(len(string_list)):\n for j in range(i + 1, len(string_list)):\n if string_list[i] == string_list[j][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(strings):\n def is_reverse_pair(str1, str2):\n return str1 == str2[::-1]\n\n count = 0\n n = len(strings)\n for i in range(n):\n for j in range(i + 1, n):\n if is_reverse_pair(strings[i], strings[j]):\n count += 1\n\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(lst):\n count = 0\n for i in range(len(lst)):\n for j in range(i + 1, len(lst)):\n if lst[i] == lst[j][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(string_list):\n def is_reverse_pair(s1, s2):\n return s1 == s2[::-1]\n\n count = 0\n n = len(string_list)\n\n for i in range(n):\n for j in range(i + 1, n):\n if is_reverse_pair(string_list[i], string_list[j]):\n count += 1\n\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(words):\n reverse_dict = {}\n pairs_count = 0\n\n for word in words:\n reverse_word = word[::-1]\n if reverse_word in reverse_dict:\n pairs_count += reverse_dict[reverse_word]\n\n if word in reverse_dict:\n reverse_dict[word] += 1\n else:\n reverse_dict[word] = 1\n\n return pairs_count", "matching_cluster_idx": 12}, {"solution": "def count_reverse_pairs(strings):\n \"\"\"\n Counts the number of pairs of strings in the list such that one is the reverse of the other.\n\n Args:\n strings (list): A list of strings.\n\n Returns:\n int: The number of pairs of reverse strings.\n \"\"\"\n count = 0\n reverse_dict = {}\n\n for s in strings:\n reversed_s = s[::-1]\n if reversed_s in reverse_dict:\n count += reverse_dict[reversed_s]\n if s in reverse_dict:\n reverse_dict[s] += 1\n else:\n reverse_dict[s] = 1\n\n return count", "matching_cluster_idx": 12}, {"solution": "def count_reverse_pairs(strings):\n # A dictionary to keep track of occurrences of each string\n str_count = {}\n count = 0\n\n # Iterate through each string in the list\n for s in strings:\n # If the reverse of the string is already in the dictionary, it means we have a reverse pair\n if s[::-1] in str_count:\n count += str_count[s[::-1]]\n\n # Increment the count of the current string in the dictionary\n if s in str_count:\n str_count[s] += 1\n else:\n str_count[s] = 1\n\n return count", "matching_cluster_idx": 12}, {"solution": "def count_reverse_pairs(words):\n \"\"\"\n This function takes a list of words and returns the number of pairs\n of reverse strings in the list.\n\n :param words: List of strings\n :return: Number of pairs of reverse strings\n \"\"\"\n # Using a dictionary to count occurrences of each word\n word_count = {}\n pairs = 0\n\n for word in words:\n # Generate the reverse of the current word\n reversed_word = word[::-1]\n\n # If the reversed word is already in the dictionary, increment the pairs count\n if reversed_word in word_count:\n pairs += word_count[reversed_word]\n\n # Increment the count of the current word in the dictionary\n if word in word_count:\n word_count[word] += 1\n else:\n word_count[word] = 1\n\n return pairs", "matching_cluster_idx": 12}, {"solution": "def count_reverse_pairs(string_list):\n # Initialize a dictionary to store string counts and the count of reverse pairs\n string_count = {}\n reverse_pairs = 0\n\n # Iterate over the list of strings\n for s in string_list:\n reversed_s = s[::-1]\n\n # Check if the reversed string is already in the dictionary\n if reversed_s in string_count:\n reverse_pairs += string_count[reversed_s]\n\n # Increment the count of the original string in the dictionary\n if s in string_count:\n string_count[s] += 1\n else:\n string_count[s] = 1\n\n return reverse_pairs", "matching_cluster_idx": 12}, {"solution": "def count_reverse_pairs(lst):\n pairs = 0\n for i in range(len(lst)):\n for j in range(i+1, len(lst)):\n if lst[i] == lst[j][::-1]:\n pairs += 1\n return pairs", "matching_cluster_idx": 2}]}, "Mbpp/758": {"dps": 63.8996138996139, "dps_norm": 75.0, "pass@1": 100.0, "profiled": [{"solution": "def unique_sublists(lst):\n counts = {}\n\n for sublist in lst:\n t = tuple(sublist)\n if t in counts:\n counts[t] += 1\n else:\n counts[t] = 1\n\n return counts", "matching_cluster_idx": 5}, {"solution": "def unique_sublists(lst):\n \"\"\"\n Counts the occurrence of each list within the input list by converting lists to tuples.\n\n Parameters:\n lst (list of lists): The input list containing sublists.\n\n Returns:\n dict: A dictionary where keys are tuples (converted from sublists) and values are their counts.\n \"\"\"\n count_dict = {}\n\n for sublist in lst:\n sublist_tuple = tuple(sublist)\n if sublist_tuple in count_dict:\n count_dict[sublist_tuple] += 1\n else:\n count_dict[sublist_tuple] = 1\n\n return count_dict", "matching_cluster_idx": 5}, {"solution": "def unique_sublists(lst):\n count_dict = {}\n for sublist in lst:\n sublist_tuple = tuple(sublist)\n if sublist_tuple in count_dict:\n count_dict[sublist_tuple] += 1\n else:\n count_dict[sublist_tuple] = 1\n return count_dict", "matching_cluster_idx": 5}, {"solution": "def unique_sublists(list_of_lists):\n counter_dict = {}\n for inner_list in list_of_lists:\n tuple_key = tuple(inner_list)\n if tuple_key in counter_dict:\n counter_dict[tuple_key] += 1\n else:\n counter_dict[tuple_key] = 1\n return counter_dict", "matching_cluster_idx": 5}, {"solution": "from collections import defaultdict\ndef unique_sublists(lst):\n counts = defaultdict(int)\n for sublist in lst:\n counts[tuple(sublist)] += 1\n return dict(counts)", "matching_cluster_idx": 5}, {"solution": "def unique_sublists(lst):\n sublist_dict = {}\n for sublist in lst:\n sublist_tuple = tuple(sublist)\n if sublist_tuple in sublist_dict:\n sublist_dict[sublist_tuple] += 1\n else:\n sublist_dict[sublist_tuple] = 1\n return sublist_dict", "matching_cluster_idx": 5}, {"solution": "def unique_sublists(list_of_lists):\n counts = {}\n for sublist in list_of_lists:\n subtuple = tuple(sublist)\n if subtuple in counts:\n counts[subtuple] += 1\n else:\n counts[subtuple] = 1\n return counts", "matching_cluster_idx": 5}, {"solution": "def unique_sublists(lst):\n count_dict = {}\n for sublist in lst:\n tuple_sublist = tuple(sublist)\n if tuple_sublist in count_dict:\n count_dict[tuple_sublist] += 1\n else:\n count_dict[tuple_sublist] = 1\n return count_dict", "matching_cluster_idx": 5}, {"solution": "def unique_sublists(lst):\n \"\"\"\n This function counts the occurrences of each sublist in a list.\n\n :param lst: List of lists\n :return: Dictionary where keys are tuples of sublists and values are their counts\n \"\"\"\n sublist_counts = {}\n\n for sublist in lst:\n sublist_tuple = tuple(sublist)\n if sublist_tuple in sublist_counts:\n sublist_counts[sublist_tuple] += 1\n else:\n sublist_counts[sublist_tuple] = 1\n\n return sublist_counts", "matching_cluster_idx": 5}, {"solution": "def unique_sublists(lst):\n counts = {}\n for sublist in lst:\n sublist_tuple = tuple(sublist)\n if sublist_tuple in counts:\n counts[sublist_tuple] += 1\n else:\n counts[sublist_tuple] = 1\n return counts", "matching_cluster_idx": 5}, {"solution": "def unique_sublists(lst):\n \"\"\"\n Function to count lists within a list.\n The function should return a dictionary where every list is converted to a tuple and\n the value of such tuple is the number of its occurrences in the original list.\n \"\"\"\n sublist_count = {}\n for sublist in lst:\n sublist_tuple = tuple(sublist)\n if sublist_tuple in sublist_count:\n sublist_count[sublist_tuple] += 1\n else:\n sublist_count[sublist_tuple] = 1\n return sublist_count", "matching_cluster_idx": 5}, {"solution": "def unique_sublists(lst):\n \"\"\"\n Write a function to count lists within a list.\n The function should return a dictionary where every list is converted to a tuple and the value of such tuple is the number of its occurrences in the original list.\n \"\"\"\n counter = {}\n for sublist in lst:\n tup = tuple(sublist)\n if tup in counter:\n counter[tup] += 1\n else:\n counter[tup] = 1\n return counter", "matching_cluster_idx": 5}, {"solution": "def unique_sublists(input_list):\n # Create an empty dictionary to store counts of each sublist\n sublist_counts = {}\n\n # Iterate over the input list\n for sublist in input_list:\n # Convert the sublist to a tuple\n sublist_tuple = tuple(sublist)\n\n # If the tuple is already in the dictionary, increment its count\n if sublist_tuple in sublist_counts:\n sublist_counts[sublist_tuple] += 1\n # Otherwise, add the tuple to the dictionary with a count of 1\n else:\n sublist_counts[sublist_tuple] = 1\n\n return sublist_counts", "matching_cluster_idx": 5}, {"solution": "def unique_sublists(lists):\n counts = {}\n for sublist in lists:\n tuple_sublist = tuple(sublist)\n if tuple_sublist in counts:\n counts[tuple_sublist] += 1\n else:\n counts[tuple_sublist] = 1\n return counts", "matching_cluster_idx": 5}, {"solution": "def unique_sublists(lst):\n # Initialize an empty dictionary to count the occurrences of each tuple\n count_dict = {}\n\n # Iterate through each sublist in the given list\n for sublist in lst:\n # Convert the sublist to a tuple and update the count in the dictionary\n tup = tuple(sublist)\n if tup in count_dict:\n count_dict[tup] += 1\n else:\n count_dict[tup] = 1\n\n return count_dict", "matching_cluster_idx": 5}, {"solution": "def unique_sublists(lst):\n counts = {}\n for item in lst:\n t = tuple(item)\n if t in counts:\n counts[t] += 1\n else:\n counts[t] = 1\n return counts", "matching_cluster_idx": 5}, {"solution": "def unique_sublists(input_list):\n \"\"\"\n This function counts lists within a list. It returns a dictionary where every list is converted to a tuple\n and the value of such tuple is the number of its occurrences in the original list.\n\n Args:\n input_list (list of lists): A list containing multiple lists.\n\n Returns:\n dict: A dictionary where keys are tuples and values are counts of their occurrences.\n \"\"\"\n sublist_counts = {}\n\n for sublist in input_list:\n tuple_key = tuple(sublist)\n if tuple_key in sublist_counts:\n sublist_counts[tuple_key] += 1\n else:\n sublist_counts[tuple_key] = 1\n\n return sublist_counts", "matching_cluster_idx": 5}, {"solution": "from collections import defaultdict\ndef unique_sublists(lists):\n # Convert lists to tuples and count their occurrences\n list_counts = defaultdict(int)\n for lst in lists:\n tup = tuple(lst)\n list_counts[tup] += 1\n return dict(list_counts)", "matching_cluster_idx": 5}, {"solution": "def unique_sublists(input_list):\n \"\"\"\n Function to count unique sublists within a list.\n\n Parameters:\n input_list (list of lists): A list containing sublists of integers.\n\n Returns:\n dict: A dictionary with sublists (as tuples) as keys and their counts as values.\n \"\"\"\n from collections import defaultdict\n\n # Initialize a default dictionary to store the counts\n count_dict = defaultdict(int)\n\n # Iterate through the input list\n for sublist in input_list:\n # Convert the sublist to a tuple and update the count in the dictionary\n count_dict[tuple(sublist)] += 1\n\n # Convert the defaultdict to a regular dictionary\n return dict(count_dict)", "matching_cluster_idx": 5}, {"solution": "from collections import defaultdict\ndef unique_sublists(lst):\n # Initialize a defaultdict to store the counts of each tuple\n counts = defaultdict(int)\n\n # Iterate over each sublist in the input list\n for sublist in lst:\n # Convert the sublist to a tuple and increment its count in the dictionary\n sublist_tuple = tuple(sublist)\n counts[sublist_tuple] += 1\n\n return dict(counts)", "matching_cluster_idx": 5}]}, "Mbpp/760": {"dps": 99.27007299270073, "dps_norm": 87.5, "pass@1": 33.0, "profiled": [{"solution": "def unique_Element(lst):\n \"\"\"\n Function to check whether a list contains only one distinct element.\n \"\"\"\n # Convert the list to a set, which removes duplicates\n unique_elements = set(lst)\n\n # If the length of the set is 1, it means there's only one distinct element\n return len(unique_elements) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(lst):\n \"\"\"\n Check whether a list of numbers contains only one distinct element or not.\n :param lst: List of numbers\n :return: True if the list contains only one distinct element, False otherwise.\n \"\"\"\n # Convert the list to a set to remove duplicates, then check the length of the set\n return len(set(lst)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(lst):\n \"\"\"\n Check whether a list of numbers contains only one distinct element or not.\n\n Parameters:\n lst (list): A list of numbers.\n\n Returns:\n bool: True if the list contains only one distinct element, False otherwise.\n \"\"\"\n return len(set(lst)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(numbers):\n \"\"\"\n Function to check whether a list of numbers contains only one distinct element or not.\n\n Args:\n numbers (list): A list of numbers to check.\n\n Returns:\n bool: True if the list contains only one distinct element, False otherwise.\n \"\"\"\n # Create a set from the list to get distinct elements\n distinct_elements = set(numbers)\n\n # If the length of the set is 1, it means there is only one distinct element\n return len(distinct_elements) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(lst):\n \"\"\"\n Check whether a list of numbers contains only one distinct element or not.\n\n Parameters:\n lst (list): List of numbers\n\n Returns:\n bool: True if the list contains only one distinct element, False otherwise\n \"\"\"\n return len(set(lst)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(numbers):\n \"\"\"\n Function to check whether a list of numbers contains only one distinct element.\n\n Parameters:\n numbers (list): List of numbers to check.\n\n Returns:\n bool: True if there is only one distinct element, False otherwise.\n \"\"\"\n distinct_elements = set(numbers)\n return len(distinct_elements) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(lst):\n return len(set(lst)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(lst):\n # Convert the list into a set to remove duplicates\n distinct_elements = set(lst)\n # If there's only one element in the set, the list contains only one distinct element\n return len(distinct_elements) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(lst):\n return len(set(lst)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(numbers):\n return len(set(numbers)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(lst):\n \"\"\"\n This function checks whether a list of numbers contains only one distinct element or not.\n\n :param lst: List[int]\n :return: bool\n \"\"\"\n return len(set(lst)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(lst):\n \"\"\"\n Check if a list contains only one distinct element.\n\n Args:\n lst (list): A list of numbers.\n\n Returns:\n bool: True if the list contains only one distinct element, False otherwise.\n \"\"\"\n distinct_elements = set(lst)\n return len(distinct_elements) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(lst):\n \"\"\"\n This function checks whether a list of numbers contains only one distinct element or not.\n :param lst: list of numbers\n :return: bool, True if the list contains only one distinct element, otherwise False\n \"\"\"\n return len(set(lst)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(lst):\n \"\"\"\n Check if a list contains only one distinct element.\n\n Parameters:\n lst (list): A list of numbers\n\n Returns:\n bool: True if the list contains only one distinct element, False otherwise\n \"\"\"\n return len(set(lst)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(lst):\n # Convert the list to a set to remove duplicates and check the length\n return len(set(lst)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(lst):\n return len(set(lst)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(lst):\n return len(set(lst)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(lst):\n return len(set(lst)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(lst):\n \"\"\"\n This function checks if a list contains only one distinct element.\n\n Args:\n lst (list): A list of numbers.\n\n Returns:\n bool: True if the list contains only one distinct element, False otherwise.\n \"\"\"\n # Convert the list to a set and check its length\n return len(set(lst)) == 1", "matching_cluster_idx": 6}, {"solution": "def unique_Element(lst):\n \"\"\"\n Check whether a list of numbers contains only one distinct element or not.\n :param lst: List of numbers\n :return: True if there is only one distinct element, False otherwise\n \"\"\"\n # Convert the list to a set to get distinct elements\n distinct_elements = set(lst)\n\n # Check the number of distinct elements\n return len(distinct_elements) == 1", "matching_cluster_idx": 6}]}, "Mbpp/764": {"dps": 89.38271604938271, "dps_norm": 50.833333333333336, "pass@1": 100.0, "profiled": [{"solution": "def number_ctr(string):\n \"\"\"\n Count the number of digits in a given string.\n \"\"\"\n return sum(1 for char in string if char.isdigit())", "matching_cluster_idx": 2}, {"solution": "def number_ctr(input_string):\n \"\"\"\n Count the number of digits in the given string.\n\n Parameters:\n input_string (str): The string to check.\n\n Returns:\n int: The number of digits in the string.\n \"\"\"\n return sum(c.isdigit() for c in input_string)", "matching_cluster_idx": 2}, {"solution": "def number_ctr(input_string):\n \"\"\"Count the number of digits in the input string.\"\"\"\n count = 0\n for char in input_string:\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(input_string):\n count = 0\n for char in input_string:\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(input_str):\n \"\"\"\n Count the number of digits in the given string.\n\n Args:\n input_str (str): The input string to count digits from.\n\n Returns:\n int: The number of digits in the input string.\n \"\"\"\n # Use a list comprehension to iterate through the string and filter digits\n digits = [char for char in input_str if char.isdigit()]\n\n # Return the count of digits found\n return len(digits)", "matching_cluster_idx": 3}, {"solution": "def number_ctr(s: str) -> int:\n \"\"\"\n Function to count number of digits in a given string.\n \"\"\"\n return sum(1 for char in s if char.isdigit())", "matching_cluster_idx": 2}, {"solution": "def number_ctr(input_string):\n \"\"\"\n This function counts the number of digits in a given string.\n\n :param input_string: str, input string to count digits\n :return: int, count of digits\n \"\"\"\n return sum(char.isdigit() for char in input_string)", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n \"\"\"\n This function counts the number of digits in a given string.\n\n Parameters:\n s (str): The input string.\n\n Returns:\n int: The number of digits in the input string.\n \"\"\"\n count = 0\n for char in s:\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(input_string):\n \"\"\"\n Count the number of digits in a given string.\n\n Parameters:\n input_string (str): The string to count digits in.\n\n Returns:\n int: The number of digits in the input string.\n \"\"\"\n # Initialize a counter for digits\n count = 0\n\n # Iterate over each character in the string\n for char in input_string:\n # Check if the character is a digit\n if char.isdigit():\n count += 1\n\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n \"\"\"\n Function to count number of digits in a given string.\n\n Args:\n s (str): The input string.\n\n Returns:\n int: The number of digits in the string.\n \"\"\"\n count = 0\n for char in s:\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n return sum(char.isdigit() for char in s)", "matching_cluster_idx": 2}, {"solution": "def number_ctr(input_string):\n count = 0\n for character in input_string:\n if character.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(string):\n \"\"\"\n Counts the number of digits in a given string.\n\n Parameters:\n string (str): The input string in which to count digits.\n\n Returns:\n int: The number of digits in the input string.\n \"\"\"\n return sum(1 for char in string if char.isdigit())", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n \"\"\"\n Count the number of digits in a given string.\n\n Parameters:\n s (str): The input string.\n\n Returns:\n int: The number of digits in the string.\n \"\"\"\n return sum(char.isdigit() for char in s)", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s: str) -> int:\n \"\"\"\n Counts the number of digits in a given string.\n\n Args:\n s (str): The input string.\n\n Returns:\n int: The number of digits in the string.\n \"\"\"\n return sum(c.isdigit() for c in s)", "matching_cluster_idx": 2}, {"solution": "def number_ctr(string):\n \"\"\"\n This function counts the number of digits in a given string.\n\n Args:\n string (str): The input string to be checked.\n\n Returns:\n int: The count of digits in the input string.\n \"\"\"\n digit_count = 0\n for char in string:\n if char.isdigit():\n digit_count += 1\n return digit_count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(input_string):\n \"\"\"Counts the number of digits in a given string.\"\"\"\n count = 0\n for char in input_string:\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n return sum(c.isdigit() for c in s)", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n \"\"\"\n Count the number of digits in a given string.\n\n Args:\n s (str): Input string to count digits in.\n\n Returns:\n int: Number of digits in the input string.\n \"\"\"\n return sum(1 for char in s if char.isdigit())", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n \"\"\"\n Counts the number of digits in a given string.\n\n Args:\n s (str): The input string.\n\n Returns:\n int: The number of digits in the string.\n \"\"\"\n return sum(char.isdigit() for char in s)", "matching_cluster_idx": 2}]}, "Mbpp/766": {"dps": 78.83177570093459, "dps_norm": 66.66666666666667, "pass@1": 100.0, "profiled": [{"solution": "def pair_wise(lst):\n \"\"\"\n Return a list of all pairs of consecutive items in a given list.\n\n Parameters:\n lst (list): List of items to be paired.\n\n Returns:\n list: List of tuples where each tuple contains a pair of consecutive items from the input list.\n \"\"\"\n if len(lst) < 2:\n return []\n\n return [(lst[i], lst[i + 1]) for i in range(len(lst) - 1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(input_list):\n return [(input_list[i], input_list[i+1]) for i in range(len(input_list)-1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n \"\"\"\n This function takes a list of items and returns a list of tuples containing\n pairs of consecutive items.\n\n Parameters:\n lst (list): A list of items.\n\n Returns:\n list: A list of tuples containing pairs of consecutive items.\n \"\"\"\n return [(lst[i], lst[i + 1]) for i in range(len(lst) - 1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n \"\"\"\n This function returns a list of all pairs of consecutive items in a given list.\n\n :param lst: A list of elements.\n :return: A list of tuples, each containing a pair of consecutive elements from the input list.\n \"\"\"\n return [(lst[i], lst[i+1]) for i in range(len(lst)-1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n return list(zip(lst, lst[1:]))", "matching_cluster_idx": 5}, {"solution": "def pair_wise(lst):\n return [(lst[i], lst[i+1]) for i in range(len(lst) - 1)]", "matching_cluster_idx": 2}, {"solution": "def pair_wise(lst):\n \"\"\"\n Returns a list of all pairs of consecutive items in a given list.\n \"\"\"\n # Check if the list has fewer than 2 elements, in which case return an empty list\n if len(lst) < 2:\n return []\n\n # Initialize an empty list to hold the pairs\n pairs = []\n\n # Iterate over the list and create pairs of consecutive elements\n for i in range(len(lst) - 1):\n pairs.append((lst[i], lst[i+1]))\n\n return pairs", "matching_cluster_idx": 2}, {"solution": "def pair_wise(lst):\n \"\"\"\n Returns a list of all pairs of consecutive items in a given list.\n\n :param lst: List of items\n :return: List of tuples, each containing a pair of consecutive items\n \"\"\"\n if not lst or len(lst) < 2:\n return []\n\n return [(lst[i], lst[i + 1]) for i in range(len(lst) - 1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n return [(lst[i], lst[i+1]) for i in range(len(lst)-1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n \"\"\"\n Return a list of all pairs of consecutive items in the given list.\n\n Parameters:\n lst (list): The input list of items.\n\n Returns:\n list: A list of tuples, where each tuple contains a pair of consecutive items.\n \"\"\"\n if len(lst) < 2:\n return []\n\n return [(lst[i], lst[i + 1]) for i in range(len(lst) - 1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n \"\"\"\n Return a list of all pairs of consecutive items in the given list.\n\n :param lst: List of items\n :return: List of tuples containing pairs of consecutive items\n \"\"\"\n return [(lst[i], lst[i+1]) for i in range(len(lst) - 1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n \"\"\"\n Returns a list of all pairs of consecutive items in the given list.\n\n Parameters:\n lst (list): The list from which to create pairs.\n\n Returns:\n list: A list of tuples, each containing a pair of consecutive items from the input list.\n \"\"\"\n return [(lst[i], lst[i + 1]) for i in range(len(lst) - 1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(input_list):\n \"\"\"\n Return a list of all pairs of consecutive items in a given list.\n \"\"\"\n if len(input_list) < 2:\n return []\n\n return [(input_list[i], input_list[i + 1]) for i in range(len(input_list) - 1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n \"\"\"\n This function returns a list of all pairs of consecutive items in a given list.\n\n Parameters:\n lst (list): The input list of integers.\n\n Returns:\n list: A list of tuples containing pairs of consecutive items.\n \"\"\"\n if not lst: # Check if the list is empty\n return []\n\n return [(lst[i], lst[i + 1]) for i in range(len(lst) - 1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(items):\n \"\"\"\n Return a list of all pairs of consecutive items in a given list.\n\n Parameters:\n items (list): The input list of items.\n\n Returns:\n list: A list of tuples, where each tuple contains a pair of consecutive items.\n \"\"\"\n if len(items) < 2:\n return []\n return [(items[i], items[i+1]) for i in range(len(items) - 1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n \"\"\"\n Return a list of all pairs of consecutive items in a given list.\n \"\"\"\n return [(lst[i], lst[i+1]) for i in range(len(lst)-1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n \"\"\"\n This function returns a list of all pairs of consecutive items in the given list.\n\n :param lst: List of items\n :return: List of tuples, where each tuple contains a pair of consecutive items from the input list\n \"\"\"\n if len(lst) < 2:\n return []\n\n # Create a list to hold the pairs of consecutive items\n pairs = [(lst[i], lst[i + 1]) for i in range(len(lst) - 1)]\n\n return pairs", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n if len(lst) < 2:\n return []\n return [(lst[i], lst[i+1]) for i in range(len(lst)-1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n if len(lst) < 2:\n return []\n return [(lst[i], lst[i+1]) for i in range(len(lst)-1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n \"\"\"\n Return a list of all pairs of consecutive items in a given list.\n \"\"\"\n if len(lst) < 2:\n return []\n return [(lst[i], lst[i + 1]) for i in range(len(lst) - 1)]", "matching_cluster_idx": 3}]}, "Mbpp/775": {"dps": 89.19999999999999, "dps_norm": 67.14285714285714, "pass@1": 99.0, "profiled": [{"solution": "def odd_position(lst):\n \"\"\"\n Function to check whether every odd index contains odd numbers in a given list.\n\n Args:\n lst (list): The list of numbers to check.\n\n Returns:\n bool: True if every odd index contains an odd number, False otherwise.\n \"\"\"\n for i in range(1, len(lst), 2):\n if lst[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n \"\"\"\n Checks whether every odd index contains odd numbers in the given list.\n\n Parameters:\n lst (list): List of integers to be checked.\n\n Returns:\n bool: True if all odd indices contain odd numbers, False otherwise.\n \"\"\"\n # Iterate over the list with step 2 to access odd indices only\n for i in range(1, len(lst), 2):\n if lst[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n \"\"\"\n Check whether every odd index contains odd numbers in the given list.\n\n :param lst: List of integers\n :return: True if every odd index contains an odd number, False otherwise\n \"\"\"\n for i in range(1, len(lst), 2):\n if lst[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n \"\"\"\n Function to check whether every odd index contains odd numbers of a given list.\n\n Args:\n lst (list): List of integers to be checked.\n\n Returns:\n bool: True if every odd index contains an odd number, False otherwise.\n \"\"\"\n for i in range(1, len(lst), 2):\n if lst[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n \"\"\"\n This function checks whether every odd index of the given list contains odd numbers.\n \"\"\"\n # Iterate through the list and check elements at odd indices\n for i in range(1, len(lst), 2):\n if lst[i] % 2 == 0: # If the number at an odd index is even, return False\n return False\n return True # If all numbers at odd indices are odd, return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n \"\"\"\n This function checks whether every odd index contains odd numbers in a given list.\n \"\"\"\n for i in range(1, len(lst), 2):\n if lst[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n \"\"\"\n This function checks whether every odd index in the list contains an odd number.\n\n :param lst: List of integers\n :return: True if every odd index contains an odd number, False otherwise\n \"\"\"\n for index in range(1, len(lst), 2): # Loop through odd indices\n if lst[index] % 2 == 0: # Check if the number is even\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(nums):\n \"\"\"\n Check whether every odd index contains odd numbers of a given list.\n\n :param nums: List of integers\n :return: Boolean indicating whether the condition is met\n \"\"\"\n for i in range(1, len(nums), 2):\n if nums[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n \"\"\"\n Check whether every odd index contains odd numbers in the given list.\n\n Args:\n lst (list): A list of integers.\n\n Returns:\n bool: True if every odd index contains an odd number, otherwise False.\n \"\"\"\n for i in range(1, len(lst), 2):\n if lst[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n \"\"\"\n Checks whether every odd index in the list contains odd numbers.\n\n Args:\n lst (list): List of integers.\n\n Returns:\n bool: True if every odd index contains an odd number, False otherwise.\n \"\"\"\n for i in range(1, len(lst), 2):\n if lst[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n \"\"\"\n Check whether every odd index contains odd numbers of a given list.\n\n :param lst: List of integers\n :return: True if every odd index contains an odd number, else False\n \"\"\"\n for i in range(1, len(lst), 2):\n if lst[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n \"\"\"\n Checks whether every odd index contains odd numbers of a given list.\n\n Args:\n lst (list of int): The list to check.\n\n Returns:\n bool: True if every odd index contains an odd number, False otherwise.\n \"\"\"\n for i in range(1, len(lst), 2):\n if lst[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n \"\"\"\n Check whether every odd index contains odd numbers of a given list.\n\n Args:\n lst (list): List of integers\n\n Returns:\n bool: True if every odd index contains odd numbers, otherwise False.\n \"\"\"\n for i in range(1, len(lst), 2):\n if lst[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n return all(num % 2 == 1 for idx, num in enumerate(lst) if idx % 2 == 1)", "matching_cluster_idx": 2}, {"solution": "def odd_position(lst):\n return all(x % 2 != 0 for x in lst[1::2])", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n \"\"\"\n This function checks whether every odd index contains odd numbers in a given list.\n\n Parameters:\n lst (list): The list of integers to check.\n\n Returns:\n bool: True if every odd index contains an odd number, False otherwise.\n \"\"\"\n return all(lst[i] % 2 == 1 for i in range(1, len(lst), 2))", "matching_cluster_idx": 3}, {"solution": "def odd_position(lst):\n \"\"\"\n Check whether every odd index contains odd numbers of a given list.\n \"\"\"\n return all(lst[i] % 2 != 0 for i in range(1, len(lst), 2))", "matching_cluster_idx": 3}, {"solution": "def odd_position(lst):\n \"\"\"\n This function checks whether every odd index contains odd numbers in the given list.\n\n :param lst: List of integers\n :return: Boolean value indicating if every odd index contains an odd number\n \"\"\"\n for i in range(1, len(lst), 2):\n if lst[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n \"\"\"\n Check whether every odd index contains odd numbers of a given list.\n \"\"\"\n for i in range(1, len(lst), 2):\n if lst[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(numbers):\n \"\"\"\n Check if every odd index in the list contains an odd number.\n\n Args:\n numbers (list of int): List of integers.\n\n Returns:\n bool: True if every odd index contains an odd number, False otherwise.\n \"\"\"\n for i in range(len(numbers)):\n if i % 2 == 1 and numbers[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 2}]}, "Mbpp/777": {"dps": null, "dps_norm": null, "pass@1": 0.0, "profiled": []}, "Mbpp/781": {"dps": 71.29921259842519, "dps_norm": 46.0, "pass@1": 95.0, "profiled": [{"solution": "def count_divisors(n):\n \"\"\"\n This function counts the number of divisors of a given integer n and\n returns True if the count is even, False otherwise.\n \"\"\"\n if n <= 0:\n raise ValueError(\"Input must be a positive integer\")\n\n count = 0\n for i in range(1, n+1):\n if n % i == 0:\n count += 1\n\n return count % 2 == 0", "matching_cluster_idx": 0}, {"solution": "def count_divisors(n):\n \"\"\"\n This function returns True if the count of divisors of n is even, and False otherwise.\n\n Parameters:\n n (int): The number to check.\n\n Returns:\n bool: True if the count of divisors is even, False otherwise.\n \"\"\"\n # Initialize a counter for the number of divisors\n count = 0\n\n # Iterate through all numbers from 1 to n\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n\n # Check if the count of divisors is even\n return count % 2 == 0", "matching_cluster_idx": 1}, {"solution": "def count_divisors(n):\n \"\"\"\n Returns True if the count of divisors of n is even, otherwise False.\n \"\"\"\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count % 2 == 0", "matching_cluster_idx": 1}, {"solution": "def count_divisors(n):\n \"\"\"\n This function checks whether the count of divisors is even.\n \"\"\"\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count % 2 == 0", "matching_cluster_idx": 1}, {"solution": "def count_divisors(n):\n \"\"\"\n Function to check whether the count of divisors of a number is even.\n\n Parameters:\n n (int): The number to check.\n\n Returns:\n bool: True if the count of divisors is even, False otherwise.\n \"\"\"\n divisors = [i for i in range(1, n + 1) if n % i == 0]\n return len(divisors) % 2 == 0", "matching_cluster_idx": 1}, {"solution": "def count_divisors(n):\n # Function to count the number of divisors\n def get_divisors_count(n):\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count\n\n divisors_count = get_divisors_count(n)\n\n # Check if the count of divisors is even\n return divisors_count % 2 == 0", "matching_cluster_idx": 0}, {"solution": "def count_divisors(n):\n \"\"\"\n This function calculates the number of divisors of an integer n and checks whether the count is even.\n\n Parameters:\n n (int): An integer for which we want to calculate the number of divisors.\n\n Returns:\n bool: True if the count of divisors is even, False otherwise.\n \"\"\"\n divisors = set()\n\n # Iterate through potential divisors and add to the set\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n divisors.add(i)\n divisors.add(n // i)\n\n # The count of divisors is the size of the set\n divisor_count = len(divisors)\n\n # Check if the count of divisors is even\n return divisor_count % 2 == 0", "matching_cluster_idx": 3}, {"solution": "def count_divisors(num):\n \"\"\"\n Count the number of divisors for a given number and check if the count is even.\n\n Args:\n num (int): The number to check.\n\n Returns:\n bool: True if the count of divisors is even, False otherwise.\n \"\"\"\n if num < 1:\n raise ValueError(\"Number must be positive\")\n\n divisors_count = 0\n for i in range(1, num + 1):\n if num % i == 0:\n divisors_count += 1\n\n return divisors_count % 2 == 0", "matching_cluster_idx": 0}, {"solution": "def count_divisors(n):\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count % 2 == 0", "matching_cluster_idx": 1}, {"solution": "def count_divisors(num):\n \"\"\"\n This function returns True if the count of divisors of num is even,\n and False otherwise.\n \"\"\"\n divisors_count = 0\n # Iterate through numbers from 1 to num (inclusive) to find divisors\n for i in range(1, num + 1):\n if num % i == 0:\n divisors_count += 1\n\n # Check if the count of divisors is even\n return divisors_count % 2 == 0", "matching_cluster_idx": 1}, {"solution": "def count_divisors(n):\n divisors = sum(1 for i in range(1, n + 1) if n % i == 0)\n return divisors % 2 == 0", "matching_cluster_idx": 1}, {"solution": "def count_divisors(n):\n \"\"\"\n This function checks whether the count of divisors is even.\n\n :param n: The number to check\n :return: True if the count of divisors is even, False otherwise\n \"\"\"\n if n < 1:\n raise ValueError(\"Input must be a positive integer\")\n\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n if n / i == i:\n count += 1\n else:\n count += 2\n return count % 2 == 0", "matching_cluster_idx": 3}, {"solution": "def count_divisors(n):\n \"\"\"\n Function to check whether the count of divisors is even.\n\n :param n: int, the number to check\n :return: bool, True if the count of divisors is even, False otherwise\n \"\"\"\n if n < 1:\n return False # Typically divisors are considered for positive integers\n\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n count += 1\n if i != n // i:\n count += 1\n\n return count % 2 == 0", "matching_cluster_idx": 3}, {"solution": "def count_divisors(n):\n \"\"\"\n Function to count the number of divisors of n and check if it is even.\n \"\"\"\n if n <= 0:\n return False\n\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n if i == n // i:\n count += 1 # Perfect square case\n else:\n count += 2 # Two divisors: i and n//i\n\n return count % 2 == 0", "matching_cluster_idx": 3}, {"solution": "def count_divisors(n):\n \"\"\"\n This function checks whether the count of divisors is even.\n\n Args:\n n (int): The number to check.\n\n Returns:\n bool: True if the count of divisors is even, False otherwise.\n \"\"\"\n if n < 1:\n raise ValueError(\"Input should be a positive integer\")\n\n divisors = 0\n for i in range(1, n + 1):\n if n % i == 0:\n divisors += 1\n\n return divisors % 2 == 0", "matching_cluster_idx": 0}, {"solution": "def count_divisors(n):\n \"\"\"\n This function returns whether the count of divisors is even.\n \"\"\"\n # Counting divisors\n divisors_count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n divisors_count += 1\n\n # Checking if count is even\n if divisors_count % 2 == 0:\n return True\n else:\n return False", "matching_cluster_idx": 1}, {"solution": "def count_divisors(n):\n \"\"\"\n Function to check whether the count of divisors is even.\n\n Args:\n n (int): The number to check.\n\n Returns:\n bool: True if the count of divisors is even, False otherwise.\n \"\"\"\n if n <= 0:\n raise ValueError(\"The number must be a positive integer.\")\n\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n count += 1\n if i != n // i:\n count += 1\n\n return count % 2 == 0", "matching_cluster_idx": 3}, {"solution": "def count_divisors(n):\n # Count the number of divisors\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n\n # Check if the count is even\n return count % 2 == 0", "matching_cluster_idx": 1}, {"solution": "def count_divisors(n):\n \"\"\"\n Function to check whether the count of divisors is even.\n \"\"\"\n # Find all divisors of n\n divisors = [i for i in range(1, n + 1) if n % i == 0]\n\n # Count of divisors\n count = len(divisors)\n\n # Check if the count is even\n return count % 2 == 0", "matching_cluster_idx": 1}, {"solution": "def count_divisors(num):\n # Step 1: Calculate the number of divisors\n count = 0\n for i in range(1, num+1):\n if num % i == 0:\n count += 1\n\n # Step 2: Determine if the count is even\n return count % 2 == 0", "matching_cluster_idx": 1}]}, "Mbpp/800": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 73.0, "profiled": [{"solution": "def remove_all_spaces(s: str) -> str:\n \"\"\"\n This function removes all whitespace characters from a given string.\n\n :param s: Input string containing whitespace characters\n :return: String with all whitespace characters removed\n \"\"\"\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n # Use the replace() method to remove all whitespaces\n return input_string.replace(' ', '')", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_str):\n \"\"\"\n Remove all whitespaces from a string.\n \"\"\"\n return input_str.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n \"\"\"\n This function removes all whitespaces from a given string.\n\n Parameters:\n input_string (str): The string to remove whitespaces from.\n\n Returns:\n str: The string with all whitespaces removed.\n \"\"\"\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n \"\"\"\n This function removes all whitespaces from a given string.\n\n Args:\n input_string (str): The input string from which whitespaces are to be removed.\n\n Returns:\n str: The input string with all whitespaces removed.\n \"\"\"\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n \"\"\"\n This function removes all whitespaces from a given string.\n \"\"\"\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n # Replace all whitespace characters with an empty string\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n \"\"\"\n This function removes all whitespaces from a string.\n\n Parameters:\n input_string (str): The input string from which to remove whitespaces.\n\n Returns:\n str: The string with all whitespaces removed.\n \"\"\"\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(s: str) -> str:\n \"\"\"\n This function takes a string as input and returns a new string with all whitespaces removed.\n\n :param s: Input string\n :return: String with all whitespaces removed\n \"\"\"\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_str):\n \"\"\"\n Removes all whitespaces from the input string.\n\n Parameters:\n input_str (str): The string from which to remove whitespaces.\n\n Returns:\n str: The string with all whitespaces removed.\n \"\"\"\n return input_str.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n \"\"\"\n Function to remove all whitespaces from a string.\n\n :param input_string: The original string with whitespaces\n :return: The string with all whitespaces removed\n \"\"\"\n # Using the replace() method to remove all whitespaces\n return input_string.replace(' ', '')", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(s):\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n \"\"\"\n This function removes all whitespaces from a string.\n \"\"\"\n # Using the str.replace() method to remove all spaces\n return input_string.replace(' ', '')", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n \"\"\"\n Function to remove all whitespaces from a string.\n :param input_string: str\n :return: str\n \"\"\"\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(s):\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}]}, "Mbpp/805": {"dps": 95.36082474226804, "dps_norm": 98.0, "pass@1": 100.0, "profiled": [{"solution": "def max_sum_list(lst):\n \"\"\"\n Returns the list in a list of lists whose sum of elements is the highest.\n \"\"\"\n return max(lst, key=sum)", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(list_of_lists):\n \"\"\"\n Function to return the list with the highest sum of elements.\n\n :param list_of_lists: List of lists containing integers\n :return: List with the highest sum of elements\n \"\"\"\n # Check if the input list is empty\n if not list_of_lists:\n return None\n\n # Initialize the max_sum and max_list with the first list's sum and the list itself\n max_sum = sum(list_of_lists[0])\n max_list = list_of_lists[0]\n\n # Iterate through the list of lists to find the list with the maximum sum\n for current_list in list_of_lists[1:]:\n current_sum = sum(current_list)\n if current_sum > max_sum:\n max_sum = current_sum\n max_list = current_list\n\n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(list_of_lists):\n # If the input list is empty, return an empty list\n if not list_of_lists:\n return []\n\n # Initialize variables to keep track of the maximum sum and the corresponding list\n max_sum = float('-inf')\n max_list = []\n\n # Iterate over each list in the list of lists\n for lst in list_of_lists:\n current_sum = sum(lst) # Calculate the sum of the current list\n if current_sum > max_sum: # Update the max_sum and max_list if the current_sum is greater\n max_sum = current_sum\n max_list = lst\n\n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lst):\n \"\"\"\n Returns the list in a list of lists whose sum of elements is the highest.\n \"\"\"\n max_sum = float('-inf')\n max_list = None\n\n for sublist in lst:\n current_sum = sum(sublist)\n if current_sum > max_sum:\n max_sum = current_sum\n max_list = sublist\n\n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n return max(lists, key=sum)", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lst):\n \"\"\"\n Return the list in a list of lists whose sum of elements is the highest.\n :param lst: list of lists\n :return: list with the highest sum of elements\n \"\"\"\n # Initialize the maximum sum and the list with the maximum sum\n max_sum = float('-inf')\n max_list = []\n\n for sublist in lst:\n current_sum = sum(sublist)\n if current_sum > max_sum:\n max_sum = current_sum\n max_list = sublist\n\n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lst):\n \"\"\"\n Function to return the list in a list of lists whose sum of elements is the highest.\n \"\"\"\n # Initialize variables to store the list with the maximum sum and the max sum\n max_list = []\n max_sum = float('-inf')\n\n for sublist in lst:\n current_sum = sum(sublist)\n if current_sum > max_sum:\n max_sum = current_sum\n max_list = sublist\n\n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n # Initially, we will assume that the first sub-list has the highest sum.\n max_sum = sum(lists[0])\n max_list = lists[0]\n\n # We iterate through the rest of the sub-lists to find if there is any sub-list\n # with a higher sum than max_sum.\n for lst in lists[1:]:\n if sum(lst) > max_sum:\n max_sum = sum(lst)\n max_list = lst\n\n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lst):\n # Initialize variables to keep track of the max sum and the corresponding list\n max_sum = float('-inf')\n max_list = []\n\n # Iterate through each sublist\n for sublist in lst:\n current_sum = sum(sublist)\n if current_sum > max_sum:\n max_sum = current_sum\n max_list = sublist\n\n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(list_of_lists):\n return max(list_of_lists, key=sum)", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n \"\"\"\n This function takes a list of lists and returns the list with the highest sum of elements.\n \"\"\"\n return max(lists, key=sum)", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(list_of_lists):\n \"\"\"\n This function takes a list of lists and returns the list that has the highest sum of elements.\n \"\"\"\n if not list_of_lists: # Check if the input list is empty\n return []\n\n # Find the list with the maximum sum of elements\n max_sum_index = 0\n for i in range(1, len(list_of_lists)):\n if sum(list_of_lists[i]) > sum(list_of_lists[max_sum_index]):\n max_sum_index = i\n\n return list_of_lists[max_sum_index]", "matching_cluster_idx": 2}, {"solution": "def max_sum_list(list_of_lists):\n \"\"\"\n Returns the list in a list of lists whose sum of elements is the highest.\n \"\"\"\n # If the input list is empty, return an empty list\n if not list_of_lists:\n return []\n\n # Find the list with the highest sum\n max_sum = float('-inf')\n max_list = None\n\n for sublist in list_of_lists:\n current_sum = sum(sublist)\n if current_sum > max_sum:\n max_sum = current_sum\n max_list = sublist\n\n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n \"\"\"\n This function returns the list in a list of lists whose sum of elements is the highest.\n\n Parameters:\n lists (list of lists): List containing other lists\n\n Returns:\n list: List with the highest sum of elements\n \"\"\"\n # If the input list of lists is empty, return an empty list\n if not lists:\n return []\n\n # Initialize the max sum and the result list\n max_sum = float('-inf')\n max_list = []\n\n # Iterate over each list in the list of lists\n for lst in lists:\n current_sum = sum(lst)\n if current_sum > max_sum:\n max_sum = current_sum\n max_list = lst\n\n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lst):\n return max(lst, key=sum)", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lst):\n # Initialize the maximum sum and the list that has this sum\n max_sum = float('-inf')\n max_list = []\n\n for sublist in lst:\n if sum(sublist) > max_sum:\n max_sum = sum(sublist)\n max_list = sublist\n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lst_of_lst):\n return max(lst_of_lst, key=sum)", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n return max(lists, key=sum)", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(list_of_lists):\n \"\"\"\n Returns the list in a list of lists whose sum of elements is the highest.\n\n Parameters:\n list_of_lists (list): A list containing other lists.\n\n Returns:\n list: The list with the highest sum of elements.\n \"\"\"\n max_sum = float('-inf')\n max_list = None\n\n for sublist in list_of_lists:\n current_sum = sum(sublist)\n if current_sum > max_sum:\n max_sum = current_sum\n max_list = sublist\n\n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n # Initialize maximum sum and the list with the highest sum\n max_sum = float('-inf')\n max_list = None\n\n for lst in lists:\n current_sum = sum(lst)\n if current_sum > max_sum:\n max_sum = current_sum\n max_list = lst\n\n return max_list", "matching_cluster_idx": 4}]}, "Mbpp/808": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 94.0, "profiled": [{"solution": "def check_K(tuples, k):\n \"\"\"\n Checks if the given tuple contains the element k.\n\n Args:\n tuples (tuple): The tuple to check.\n k (any): The element to search for.\n\n Returns:\n bool: True if k is in the tuple, False otherwise.\n \"\"\"\n return k in tuples", "matching_cluster_idx": 5}, {"solution": "def check_K(tuple_data, k):\n \"\"\"\n This function checks if the given tuple contains the element k.\n\n :param tuple_data: A tuple containing elements to be checked.\n :param k: The element to be searched in the tuple.\n :return: True if k is found in the tuple, False otherwise.\n \"\"\"\n return k in tuple_data", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n \"\"\"\n This function checks if the given tuple contains the value 'k'.\n\n :param tup: Tuple of integers\n :param k: Integer to check if it is in the tuple\n :return: True if k is in the tuple, otherwise False\n \"\"\"\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(tpl, k):\n \"\"\"\n This function checks if the given tuple contains the element k or not.\n\n Parameters:\n tpl (tuple): The tuple to check.\n k (any): The element to look for in the tuple.\n\n Returns:\n bool: True if k is in the tuple, False otherwise.\n \"\"\"\n return k in tpl", "matching_cluster_idx": 5}, {"solution": "def check_K(input_tuple, k):\n \"\"\"\n Function to check if the given tuple contains the element k.\n\n :param input_tuple: tuple of elements\n :param k: element to check for\n :return: True if k is in input_tuple, else False\n \"\"\"\n return k in input_tuple", "matching_cluster_idx": 5}, {"solution": "def check_K(input_tuple, k):\n \"\"\"\n This function checks if the given tuple contains the element k.\n\n :param input_tuple: Tuple of elements to search within\n :param k: Element to be searched for\n :return: Boolean indicating if k is in the tuple\n \"\"\"\n return k in input_tuple", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n \"\"\"\n This function checks if the given tuple contains the element k.\n \"\"\"\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(input_tuple, k):\n \"\"\"\n Function to check if the given tuple contains the element k.\n\n :param input_tuple: Tuple of elements to check.\n :param k: The element to look for in the tuple.\n :return: True if k is in the tuple, False otherwise.\n \"\"\"\n return k in input_tuple", "matching_cluster_idx": 5}, {"solution": "def check_K(tuple_data, k):\n \"\"\"\n Check if the given tuple contains the value k.\n\n :param tuple_data: Tuple of elements to check.\n :param k: The value to check for in the tuple.\n :return: True if k is in the tuple, False otherwise.\n \"\"\"\n return k in tuple_data", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n \"\"\"\n Check if the given tuple contains the element k.\n\n :param tup: Tuple to check\n :param k: Element to find in the tuple\n :return: True if k is in the tuple, False otherwise\n \"\"\"\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n \"\"\"\n This function checks if the given tuple contains the value k.\n\n Parameters:\n tup (tuple): A tuple of elements.\n k (any type): The value to check for in the tuple.\n\n Returns:\n bool: True if the value k is present in the tuple, False otherwise.\n \"\"\"\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n \"\"\"\n This function checks if the given tuple contains the value k.\n\n Parameters:\n tup (tuple): A tuple of integers.\n k (int): The value to check for in the tuple.\n\n Returns:\n bool: True if the tuple contains k, False otherwise.\n \"\"\"\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(tpl, k):\n \"\"\"\n Function to check if the given tuple contains the element k.\n\n :param tpl: Tuple of integers\n :param k: Integer to check in the tuple\n :return: True if k is in the tuple, False otherwise\n \"\"\"\n return k in tpl", "matching_cluster_idx": 5}, {"solution": "def check_K(tuples, k):\n \"\"\"\n This function checks if the given tuple contains the integer k.\n\n :param tuples: A tuple of integers\n :param k: An integer to search in the tuple\n :return: Boolean value indicating the presence of k in the tuple\n \"\"\"\n return k in tuples", "matching_cluster_idx": 5}, {"solution": "def check_K(tuple_data, k):\n \"\"\"\n This function checks if the given tuple contains the value k.\n\n :param tuple_data: A tuple of integers.\n :param k: An integer value to check for in the tuple.\n :return: True if k is found in the tuple, False otherwise.\n \"\"\"\n return k in tuple_data", "matching_cluster_idx": 5}, {"solution": "def check_K(tuples, k):\n return k in tuples", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n \"\"\"\n This function checks if the given tuple contains the element k.\n\n Parameters:\n tup (tuple): The tuple to check.\n k (any): The element to look for.\n\n Returns:\n bool: True if k is in tup, False otherwise.\n \"\"\"\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(tuples, k):\n \"\"\"\n Check if the given tuples contain the value k or not.\n\n :param tuples: A tuple of integers.\n :param k: An integer to check for in the tuple.\n :return: True if k is in the tuple, False otherwise.\n \"\"\"\n return k in tuples", "matching_cluster_idx": 5}, {"solution": "def check_K(tuple_data, k):\n \"\"\"\n Function to check if the given tuple contains the value k.\n\n :param tuple_data: tuple containing numbers\n :param k: number to check if exists in the tuple\n :return: True if k exists in the tuple, False otherwise\n \"\"\"\n return k in tuple_data", "matching_cluster_idx": 5}]}}} \ No newline at end of file diff --git a/results/evalperf/mistralai--Mistral-Nemo-Instruct-2407_vllm_temp_1.0_evalperf_results.brief.json b/results/evalperf/mistralai--Mistral-Nemo-Instruct-2407_vllm_temp_1.0_evalperf_results.brief.json new file mode 100644 index 0000000..20a32cb --- /dev/null +++ b/results/evalperf/mistralai--Mistral-Nemo-Instruct-2407_vllm_temp_1.0_evalperf_results.brief.json @@ -0,0 +1 @@ +{"date": "2024-10-19 16:30", "config": {"n_samples": 100, "temperature": 1.0, "min_correct": 10, "max_profile": 20}, "summary": {"dps": 81.98436677712466, "dps_norm": 77.61969110961331, "pass@1": 57.389830508474574}, "eval": {"HumanEval/9": {"dps": 64.93690851735016, "dps_norm": 57.77777777777778, "pass@1": 65.0, "profiled": [{"solution": "from typing import List, Tuple\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n \"\"\"\n max_val = float('-inf')\n result = []\n for num in numbers:\n max_val = max(max_val, num)\n result.append(max_val)\n return result", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n \"\"\"\n if not numbers:\n return []\n max_value = numbers[0]\n result = [max_value]\n for num in numbers[1:]:\n max_value = max(max_value, num)\n result.append(max_value)\n return result", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n if not numbers:\n return []\n\n max_val = numbers[0]\n result = [max_val]\n\n for num in numbers[1:]:\n max_val = max(max_val, num)\n result.append(max_val)\n\n return result", "matching_cluster_idx": 4}, {"solution": "from typing import List, Tuple\ndef rolling_max(numbers: List[int]) -> List[int]:\n max_so_far = float('-inf')\n results = []\n\n for num in numbers:\n max_so_far = max(max_so_far, num)\n results.append(max_so_far)\n\n return results", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n max_num = float('-inf')\n result = []\n\n for num in numbers:\n max_num = max(max_num, num)\n result.append(max_num)\n\n return result", "matching_cluster_idx": 4}, {"solution": "from typing import List, Tuple\ndef rolling_max(numbers: List[int]) -> List[int]:\n result = []\n max_num = float('-inf')\n for num in numbers:\n max_num = max(max_num, num)\n result.append(max_num)\n return result", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n if not numbers:\n return []\n\n max_so_far = numbers[0]\n result = [max_so_far]\n\n for num in numbers[1:]:\n max_so_far = max(max_so_far, num)\n result.append(max_so_far)\n\n return result", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n result = []\n max_num = float('-inf')\n\n for num in numbers:\n max_num = max(max_num, num)\n result.append(max_num)\n\n return result", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n rolling_max_list = []\n max_value = float('-inf')\n for num in numbers:\n max_value = max(max_value, num)\n rolling_max_list.append(max_value)\n return rolling_max_list", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n \"\"\"\n if not numbers:\n return []\n\n max_num = numbers[0]\n max_list = [max_num]\n\n for num in numbers[1:]:\n max_num = max(max_num, num)\n max_list.append(max_num)\n\n return max_list", "matching_cluster_idx": 4}, {"solution": "from typing import List, Tuple\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n \"\"\"\n result = []\n max_num = float('-inf')\n\n for num in numbers:\n max_num = max(max_num, num)\n result.append(max_num)\n\n return result", "matching_cluster_idx": 4}, {"solution": "from typing import List, Tuple\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\"From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\"\"\"\n result = []\n max_num = float('-inf')\n for num in numbers:\n max_num = max(max_num, num)\n result.append(max_num)\n return result", "matching_cluster_idx": 4}, {"solution": "from typing import List, Tuple\ndef rolling_max(numbers: List[int]) -> List[int]:\n result = []\n max_num = float('-inf')\n\n for num in numbers:\n max_num = max(max_num, num)\n result.append(max_num)\n\n return result", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n if not numbers:\n return []\n\n max_val = numbers[0]\n result = [max_val]\n\n for num in numbers[1:]:\n max_val = max(max_val, num)\n result.append(max_val)\n\n return result", "matching_cluster_idx": 4}, {"solution": "from typing import List, Tuple\ndef rolling_max(numbers: List[int]) -> List[int]:\n if not numbers:\n return []\n\n result = []\n max_num = numbers[0]\n\n for num in numbers:\n max_num = max(max_num, num)\n result.append(max_num)\n\n return result", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n rolling_max_list = []\n max_value = float('-inf')\n\n for num in numbers:\n max_value = max(max_value, num)\n rolling_max_list.append(max_value)\n\n return rolling_max_list", "matching_cluster_idx": 4}, {"solution": "from typing import List, Tuple\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n \"\"\"\n if not numbers:\n return []\n\n max_val, result = numbers[0], [numbers[0]]\n for num in numbers[1:]:\n if num > max_val:\n max_val = num\n result.append(max_val)\n\n return result", "matching_cluster_idx": 8}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n if not numbers:\n return []\n\n max_num = numbers[0]\n result = [max_num]\n for num in numbers[1:]:\n max_num = max(max_num, num)\n result.append(max_num)\n return result", "matching_cluster_idx": 4}, {"solution": "from typing import List, Tuple\ndef rolling_max(numbers: List[int]) -> List[int]:\n if not numbers:\n return []\n result = [numbers[0]]\n for num in numbers[1:]:\n result.append(max(result[-1], num))\n return result", "matching_cluster_idx": 4}, {"solution": "from typing import List, Tuple\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\"From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n result = []\n max_num = float('-inf')\n\n for num in numbers:\n max_num = max(max_num, num)\n result.append(max_num)\n\n return result", "matching_cluster_idx": 4}]}, "HumanEval/0": {"dps": 45.2906976744186, "dps_norm": 53.57142857142858, "pass@1": 61.0, "profiled": [{"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n # Sort the numbers in ascending order\n numbers.sort()\n\n # Check if the difference between consecutive numbers is less than the threshold\n for i in range(1, len(numbers)):\n if numbers[i] - numbers[i-1] < threshold:\n return True\n\n # If no pair of numbers is found to be closer than the threshold, return False\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n \"\"\"\n numbers.sort() # Sort the numbers for easier checking\n for i in range(1, len(numbers)):\n if numbers[i] - numbers[i - 1] < threshold:\n return True # If two adjacent numbers are closer than threshold, return True\n return False # If no pair of numbers is closer than threshold, return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n if len(numbers) < 2:\n return False\n numbers.sort()\n for i in range(len(numbers) - 1):\n if numbers[i+1] - numbers[i] < threshold:\n return True\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n \"\"\"\n # Sort the list to make the comparison easier\n numbers.sort()\n\n # Check each pair of adjacent numbers in the sorted list\n for i in range(len(numbers) - 1):\n if numbers[i + 1] - numbers[i] < threshold:\n return True\n\n # If no pair of numbers is closer than threshold, return False\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n numbers.sort() # Sort the list in ascending order\n return any(abs(numbers[i] - numbers[i - 1]) < threshold for i in range(1, len(numbers)))", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n numbers.sort()\n for i in range(1, len(numbers)):\n if numbers[i] - numbers[i-1] < threshold:\n return True\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n return any(abs(a - b) < threshold for i, a in enumerate(numbers) for b in numbers[i + 1:])", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\"Check if in given list of numbers, are any two numbers closer to each other than given threshold.\"\"\"\n\n # Sort the list of numbers\n numbers.sort()\n\n # Iterate over the sorted list with a step of 1\n for i in range(len(numbers) - 1):\n # If the difference between consecutive numbers is less than the threshold, return True\n if numbers[i + 1] - numbers[i] < threshold:\n return True\n\n # If no pair of numbers is found to be closer than the threshold, return False\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n if len(numbers) < 2:\n return False\n numbers.sort()\n for i in range(len(numbers) - 1):\n if numbers[i+1] - numbers[i] < threshold:\n return True\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n if not numbers:\n return False\n numbers.sort()\n for i in range(1, len(numbers)):\n if numbers[i] - numbers[i - 1] < threshold:\n return True\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n numbers.sort() # Sort the list to facilitate easy comparison\n for i in range(1, len(numbers)):\n if numbers[i] - numbers[i-1] < threshold:\n return True\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n \"\"\"\n sorted_numbers = sorted(numbers)\n for i in range(len(sorted_numbers) - 1):\n if sorted_numbers[i + 1] - sorted_numbers[i] < threshold:\n return True\n return False", "matching_cluster_idx": 2}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n if not numbers: # If the list is empty, return False\n return False\n\n min_diff = float('inf') # Initialize minimum difference as infinity\n for i in range(len(numbers)):\n for j in range(i+1, len(numbers)):\n diff = abs(numbers[i] - numbers[j])\n if diff < min_diff:\n min_diff = diff # Update minimum difference if a smaller one is found\n\n return min_diff < threshold", "matching_cluster_idx": -1}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n sorted_numbers = sorted(numbers)\n for i in range(len(sorted_numbers) - 1):\n if sorted_numbers[i+1] - sorted_numbers[i] < threshold:\n return True\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n # Check if list length is less than 2, as we need at least two numbers to compare\n if len(numbers) < 2:\n return False\n\n # Sort the list of numbers\n numbers.sort()\n\n # Iterate over the list, comparing each number with its subsequent number\n for i in range(len(numbers) - 1):\n # Check if difference between two consecutive numbers is less than the threshold\n if numbers[i + 1] - numbers[i] < threshold:\n return True\n\n # If no pair of numbers found to be closer than threshold, return False\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n sorted_numbers = sorted(numbers)\n return any(sorted_numbers[i + 1] - sorted_numbers[i] < threshold for i in range(len(sorted_numbers) - 1))", "matching_cluster_idx": 2}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\"\n Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n \"\"\"\n numbers = sorted(numbers) # sort the list of numbers\n for i in range(len(numbers) - 1):\n if abs(numbers[i] - numbers[i + 1]) < threshold:\n return True # found a pair of numbers closer than threshold\n return False # no pair of numbers found that is closer than threshold", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\"Check if in given list of numbers, are any two numbers closer to each other than given threshold.\"\"\"\n\n # Sort the numbers in ascending order\n numbers.sort()\n\n # Check if adjacent pairs of numbers are closer than the threshold\n for i in range(1, len(numbers)):\n if numbers[i] - numbers[i-1] < threshold:\n return True\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n if not numbers:\n return False\n numbers.sort()\n for i in range(1, len(numbers)):\n if numbers[i] - numbers[i-1] < threshold:\n return True\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n \"\"\"\n # Check if the input list is empty or has only one element\n if len(numbers) < 2:\n return False\n\n # Sort the list to reduce the number of comparisons\n numbers.sort()\n\n # Iterate through the list and check the difference between each pair of consecutive numbers\n for i in range(1, len(numbers)):\n if numbers[i] - numbers[i - 1] < threshold:\n return True\n\n # If no pair is found, return False\n return False", "matching_cluster_idx": 3}]}, "HumanEval/4": {"dps": 53.90822784810127, "dps_norm": 60.833333333333336, "pass@1": 94.0, "profiled": [{"solution": "from typing import List\nfrom statistics import mean\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\"For a given list of input numbers, calculate Mean Absolute Deviation around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n \"\"\"\n numbers_mean = mean(numbers)\n return mean(abs(num - numbers_mean) for num in numbers)", "matching_cluster_idx": 0}, {"solution": "from typing import List\nimport statistics\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n mean = statistics.mean(numbers)\n absolute_differences = [abs(x - mean) for x in numbers]\n return statistics.mean(absolute_differences)", "matching_cluster_idx": 0}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n mean = sum(numbers) / len(numbers)\n return sum(abs(x - mean) for x in numbers) / len(numbers)", "matching_cluster_idx": 5}, {"solution": "from typing import List\nimport statistics\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\"For a given list of input numbers, calculate Mean Absolute Deviation around the mean of this dataset.\n\n Mean Absolute Deviation is the average absolute difference between each element and a centerpoint (mean in this case):\n MAD = average |x - x_mean|\n\n Args:\n numbers (List[float]): A list of float numbers\n\n Returns:\n float: Mean Absolute Deviation\n \"\"\"\n mean = statistics.mean(numbers)\n return sum(abs(x - mean) for x in numbers) / len(numbers)", "matching_cluster_idx": 0}, {"solution": "from typing import List\nimport math\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n \"\"\"\n mean = sum(numbers) / len(numbers)\n mad = sum(abs(x - mean) for x in numbers) / len(numbers)\n return mad", "matching_cluster_idx": 5}, {"solution": "from typing import List\nimport statistics\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" Calculate Mean Absolute Deviation around the mean of the dataset. \"\"\"\n mean_value = statistics.mean(numbers)\n deviations = [abs(x - mean_value) for x in numbers]\n return statistics.mean(deviations)", "matching_cluster_idx": 0}, {"solution": "from typing import List\nimport math\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n mean_value = sum(numbers) / len(numbers)\n deviation = [abs(x - mean_value) for x in numbers]\n return sum(deviation) / len(deviation)", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n mean = sum(numbers) / len(numbers)\n absolute_differences = [abs(num - mean) for num in numbers]\n return sum(absolute_differences) / len(absolute_differences)", "matching_cluster_idx": 4}, {"solution": "from typing import List\nfrom statistics import mean, StatisticsError\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\"For a given list of input numbers, calculate Mean Absolute Deviation around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each element and a centerpoint (mean in this case):\n MAD = average |x - x_mean|\n \"\"\"\n try:\n mean_val = mean(numbers)\n except StatisticsError:\n return \"Error: Input list is empty\"\n\n return sum([abs(x - mean_val) for x in numbers]) / len(numbers)", "matching_cluster_idx": 0}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n if not numbers:\n raise ValueError(\"Empty dataset provided\")\n mean = sum(numbers) / len(numbers)\n return sum(abs(x - mean) for x in numbers) / len(numbers)", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n \"\"\"\n if not numbers:\n raise ValueError(\"List is empty\")\n\n mean = sum(numbers) / len(numbers)\n return sum(abs(num - mean) for num in numbers) / len(numbers)", "matching_cluster_idx": 5}, {"solution": "from typing import List\nfrom statistics import mean, stdev\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n \"\"\"\n if not numbers:\n return 0\n mean_val = mean(numbers)\n return sum(abs(x - mean_val) for x in numbers) / len(numbers)", "matching_cluster_idx": 0}, {"solution": "from typing import List\nimport math\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n n = len(numbers)\n mean = sum(numbers) / n\n return sum(abs(x - mean) for x in numbers) / n", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n mean = sum(numbers) / len(numbers)\n return sum(abs(num - mean) for num in numbers) / len(numbers)", "matching_cluster_idx": 5}, {"solution": "from typing import List\nimport math\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n mean = sum(numbers) / len(numbers)\n return sum(abs(x - mean) for x in numbers) / len(numbers)", "matching_cluster_idx": 5}, {"solution": "from typing import List\nimport statistics\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n mean = statistics.mean(numbers)\n return sum(abs(num - mean) for num in numbers) / len(numbers)", "matching_cluster_idx": 0}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\"For a given list of input numbers, calculate Mean Absolute Deviation around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n \"\"\"\n if not numbers:\n return 0.0\n\n mean = sum(numbers) / len(numbers)\n deviation = sum(abs(num - mean) for num in numbers)\n mad = deviation / len(numbers)\n return mad", "matching_cluster_idx": 5}, {"solution": "from typing import List\nfrom statistics import mean\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n x_mean = mean(numbers)\n return mean(abs(n - x_mean) for n in numbers)", "matching_cluster_idx": 0}, {"solution": "from typing import List\nimport math\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\"For a given list of input numbers, calculate Mean Absolute Deviation around the mean of this dataset.\"\"\"\n mean = sum(numbers) / len(numbers)\n mad = sum(abs(x - mean) for x in numbers) / len(numbers)\n return mad", "matching_cluster_idx": 5}, {"solution": "from typing import List\nimport statistics\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\"\n For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n \"\"\"\n mean = statistics.mean(numbers)\n deviations = [abs(x - mean) for x in numbers]\n return sum(deviations) / len(deviations)", "matching_cluster_idx": 0}]}, "HumanEval/16": {"dps": 95.81395348837209, "dps_norm": 96.66666666666667, "pass@1": 100.0, "profiled": [{"solution": "def count_distinct_characters(string: str) -> int:\n # Convert the string to lowercase to handle case insensitivity\n string = string.lower()\n # Use a set to store distinct characters, as sets automatically remove duplicates\n distinct_characters = set(string)\n # Return the count of distinct characters\n return len(distinct_characters)", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n # Convert the string to lowercase and use a set to automatically eliminate duplicates\n return len(set(string.lower()))", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n return len(set(string.lower()))", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n return len(set(string.lower()))", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n # Convert the string to a set to automatically remove duplicates,\n # then convert it back to a list to count the elements.\n return len(set([char.lower() for char in string]))", "matching_cluster_idx": 2}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\"\n Given a string, find out how many distinct characters (regardless of case) does it consist of\n \"\"\"\n return len(set(string.lower()))", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n return len(set(string.lower()))", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n # Convert the string to lowercase and then get the set of unique characters.\n # The set data structure in Python ensures that there are no duplicate characters.\n return len(set(string.lower()))", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n # Convert string to set to remove duplicates, then convert it back to list to count elements\n # The 'lower()' function is used to ensure case-insensitivity\n return len(list(set(string.lower())))", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n # Convert string to lower case to ensure case insensitivity\n string = string.lower()\n\n # Use a set to store distinct characters\n distinct_chars = set(string)\n\n # Return the number of distinct characters\n return len(distinct_chars)", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of \"\"\"\n return len(set(string.lower()))", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n return len(set(string.lower()))", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n return len(set(string.lower()))", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n \"\"\"\n # Convert the string to lowercase to make case insensitive\n string = string.lower()\n # Use a set to store unique characters and then get its length\n return len(set(string))", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of \"\"\"\n # Convert string to lowercase and use set to remove duplicates\n distinct_chars = set(string.lower())\n # Return the count of distinct characters\n return len(distinct_chars)", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n return len(set(string.lower()))", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\"\n Given a string, find out how many distinct characters (regardless of case) does it consist of\n \"\"\"\n return len(set(string.lower()))", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n return len(set(string.lower()))", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n return len(set(string.lower()))", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n \"\"\"\n # Using set to automatically get distinct characters, then lower() to ignore case\n return len(set(string.lower()))", "matching_cluster_idx": 8}]}, "HumanEval/20": {"dps": 52.893462469733656, "dps_norm": 68.88888888888889, "pass@1": 75.0, "profiled": [{"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n min_diff = float('inf')\n closest_pair = (float('inf'), float('-inf'))\n\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n diff = abs(numbers[i] - numbers[j])\n if diff < min_diff:\n min_diff = diff\n closest_pair = (min(numbers[i], numbers[j]), max(numbers[i], numbers[j]))\n\n return closest_pair", "matching_cluster_idx": 3}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each other and return them in order (smaller number, larger number).\"\"\"\n if len(numbers) < 2:\n raise ValueError(\"Input list must contain at least two elements.\")\n\n min_diff = float('inf')\n pair = (None, None)\n\n for i in range(len(numbers) - 1):\n for j in range(i + 1, len(numbers)):\n diff = abs(numbers[i] - numbers[j])\n if diff < min_diff:\n min_diff = diff\n pair = (min(numbers[i], numbers[j]), max(numbers[i], numbers[j]))\n\n return pair", "matching_cluster_idx": 3}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n # Sort the numbers\n numbers.sort()\n\n # Initialize smallest difference and closest numbers\n smallest_diff = float('inf')\n closest = (float('inf'), float('inf'))\n\n # Iterate through the list\n for i in range(len(numbers) - 1):\n diff = numbers[i + 1] - numbers[i] # difference between two consecutive numbers\n if diff < smallest_diff:\n smallest_diff = diff\n closest = (numbers[i], numbers[i + 1]) # save the closest numbers\n\n return closest", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n numbers.sort()\n min_diff = float('inf')\n result = (0, 0)\n for i in range(1, len(numbers)):\n diff = numbers[i] - numbers[i - 1]\n if diff < min_diff:\n min_diff = diff\n result = (numbers[i - 1], numbers[i])\n return result", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n if len(numbers) < 2:\n raise ValueError(\"Input list must contain at least two elements\")\n\n sorted_numbers = sorted(numbers)\n closest_pair = (sorted_numbers[0], sorted_numbers[1])\n\n for i in range(1, len(sorted_numbers) - 1):\n if sorted_numbers[i + 1] - sorted_numbers[i] < closest_pair[1] - closest_pair[0]:\n closest_pair = (sorted_numbers[i], sorted_numbers[i + 1])\n\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n if len(numbers) < 2:\n raise ValueError(\"At least two numbers are required\")\n\n min_diff = float('inf')\n min_tuple = None\n\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n diff = abs(numbers[i] - numbers[j])\n if diff < min_diff:\n min_diff = diff\n min_tuple = (min(numbers[i], numbers[j]), max(numbers[i], numbers[j]))\n\n return min_tuple", "matching_cluster_idx": 3}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n min_diff = float('inf')\n result = None\n\n for i in range(len(numbers) - 1):\n for j in range(i + 1, len(numbers)):\n diff = abs(numbers[i] - numbers[j])\n if diff < min_diff:\n min_diff = diff\n result = (min(numbers[i], numbers[j]), max(numbers[i], numbers[j]))\n\n return result", "matching_cluster_idx": 3}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n # Sort the list\n numbers.sort()\n\n # Initialize minimum difference and closest numbers\n min_diff = float('inf')\n closest_numbers = (float('inf'), float('-inf'))\n\n # Find the closest numbers\n for i in range(len(numbers) - 1):\n diff = numbers[i + 1] - numbers[i]\n\n if diff < min_diff:\n min_diff = diff\n closest_numbers = (numbers[i], numbers[i + 1])\n\n return closest_numbers", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n if len(numbers) < 2:\n raise ValueError(\"The list must contain at least two numbers\")\n\n numbers.sort()\n min_diff = float('inf')\n result = (numbers[0], numbers[0])\n\n for i in range(len(numbers) - 1):\n diff = numbers[i + 1] - numbers[i]\n if diff < min_diff:\n min_diff = diff\n result = (numbers[i], numbers[i + 1])\n\n return result", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n min_diff = float('inf')\n result = (None, None)\n\n for i in range(len(numbers) - 1):\n for j in range(i + 1, len(numbers)):\n if abs(numbers[i] - numbers[j]) < min_diff:\n min_diff = abs(numbers[i] - numbers[j])\n result = (min(numbers[i], numbers[j]), max(numbers[i], numbers[j]))\n\n return result", "matching_cluster_idx": 3}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n if len(numbers) < 2:\n raise ValueError(\"At least two elements are needed\")\n\n min_diff = float('inf')\n pair = (None, None)\n\n for i in range(len(numbers)):\n for j in range(i+1, len(numbers)):\n diff = abs(numbers[i] - numbers[j])\n if diff < min_diff:\n min_diff = diff\n pair = (min(numbers[i], numbers[j]), max(numbers[i], numbers[j]))\n\n return pair", "matching_cluster_idx": 3}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n if len(numbers) < 2:\n raise ValueError(\"List must contain at least two numbers.\")\n\n min_diff = float('inf')\n pair = (0, 0)\n\n for i in range(len(numbers) - 1):\n for j in range(i + 1, len(numbers)):\n diff = abs(numbers[i] - numbers[j])\n if diff < min_diff:\n min_diff = diff\n pair = (numbers[i], numbers[j])\n\n return min(pair), max(pair)", "matching_cluster_idx": 3}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n # Sort the list of numbers\n sorted_numbers = sorted(numbers)\n # Initialize the closest numbers and their difference\n closest = (sorted_numbers[0], sorted_numbers[1])\n min_diff = abs(sorted_numbers[1] - sorted_numbers[0])\n # Loop through the sorted list to find the closest pair\n for i in range(2, len(sorted_numbers)):\n if abs(sorted_numbers[i] - sorted_numbers[i-1]) < min_diff:\n min_diff = abs(sorted_numbers[i] - sorted_numbers[i-1])\n closest = (sorted_numbers[i-1], sorted_numbers[i])\n # Return the closest pair in order (smaller number, larger number)\n return min(closest), max(closest)", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n sorted_numbers = sorted(numbers)\n min_diff = float('inf')\n closest_pair = (None, None)\n\n for i in range(len(sorted_numbers) - 1):\n diff = sorted_numbers[i + 1] - sorted_numbers[i]\n if diff < min_diff:\n min_diff = diff\n closest_pair = (sorted_numbers[i], sorted_numbers[i + 1])\n\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n if len(numbers) < 2:\n raise ValueError(\"Input list must contain at least two elements\")\n\n min_diff = float('inf')\n pair = ()\n\n for i in range(len(numbers)-1):\n for j in range(i+1, len(numbers)):\n if abs(numbers[i] - numbers[j]) < min_diff:\n min_diff = abs(numbers[i] - numbers[j])\n pair = (min(numbers[i], numbers[j]), max(numbers[i], numbers[j]))\n\n return pair", "matching_cluster_idx": 3}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n # Check if the list has at least two elements\n if len(numbers) < 2:\n raise ValueError(\"The list must have at least two elements.\")\n\n # Initialize minimum difference and closest numbers\n min_diff = float('inf')\n closest_numbers = ()\n\n # Iterate through the list\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n diff = abs(numbers[i] - numbers[j])\n\n # Update the closest numbers if the current difference is smaller\n if diff < min_diff:\n min_diff = diff\n closest_numbers = (min(numbers[i], numbers[j]), max(numbers[i], numbers[j]))\n\n return closest_numbers", "matching_cluster_idx": 3}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n sorted_numbers = sorted(numbers)\n diff_list = [sorted_numbers[i+1] - sorted_numbers[i] for i in range(len(sorted_numbers)-1)]\n min_diff_idx = diff_list.index(min(diff_list))\n return (sorted_numbers[min_diff_idx], sorted_numbers[min_diff_idx+1])", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n min_diff = float('inf')\n result = (0, 0)\n\n for i in range(len(numbers) - 1):\n for j in range(i + 1, len(numbers)):\n if abs(numbers[i] - numbers[j]) < min_diff:\n min_diff = abs(numbers[i] - numbers[j])\n result = (min(numbers[i], numbers[j]), max(numbers[i], numbers[j]))\n\n return result", "matching_cluster_idx": 3}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n min_diff = float('inf')\n result = (None, None)\n for i in range(len(numbers) - 1):\n for j in range(i + 1, len(numbers)):\n if abs(numbers[i] - numbers[j]) < min_diff:\n min_diff = abs(numbers[i] - numbers[j])\n result = (min(numbers[i], numbers[j]), max(numbers[i], numbers[j]))\n return result", "matching_cluster_idx": 3}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n # Sort the list of numbers\n numbers.sort()\n\n # Initialize the result with the first two elements of the list\n result = (numbers[0], numbers[1])\n\n # Iterate through the list to find a closer pair\n for i in range(1, len(numbers) - 1):\n # Calculate the difference between the current pair and the result\n diff = abs(numbers[i+1] - numbers[i])\n result_diff = abs(result[1] - result[0])\n\n # Update the result if a closer pair is found\n if diff < result_diff:\n result = (numbers[i], numbers[i+1])\n\n return result", "matching_cluster_idx": 7}]}, "HumanEval/24": {"dps": 69.35374149659864, "dps_norm": 36.25, "pass@1": 61.0, "profiled": [{"solution": "def largest_divisor(n: int) -> int:\n # Check for base case, where n is 1\n if n == 1:\n return 1\n\n # Iterate through numbers from n // 2 down to 1\n for i in range(n // 2, 0, -1):\n # If i divides n evenly, return i as the largest divisor\n if n % i == 0:\n return i\n\n # If no divisor is found, return 1 (as 1 is the largest number that divides every number)\n return 1", "matching_cluster_idx": 4}, {"solution": "def largest_divisor(n: int) -> int:\n if n < 1:\n raise ValueError(\"Input must be a positive integer\")\n for i in range(n - 1, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 1}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n \"\"\"\n\n # Handle edge cases\n if n < 2:\n return None\n\n # Iterate from n down to 2\n for i in range(n-1, 1, -1):\n\n # If i divides n evenly, return i\n if n % i == 0:\n return i\n\n # If no divisor is found, return 1\n return 1", "matching_cluster_idx": 1}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n\n >>> largest_divisor(15)\n 5\n \"\"\"\n if n <= 0:\n raise ValueError(\"Input should be a positive integer\")\n for i in range(n-1, 0, -1):\n if n % i == 0:\n return i\n raise ValueError(\"Number has no positive divisor smaller than itself\")", "matching_cluster_idx": 0}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\"For a given number n, find the largest number that divides n evenly, smaller than n.\"\"\"\n if n < 2:\n return None # None is returned for numbers less than 2 as there's no positive integer divisor for them\n\n # start checking from n//2 and move downwards\n for i in range(n // 2, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 3}, {"solution": "def largest_divisor(n: int) -> int:\n if n < 2:\n return 1\n for i in range(n-1, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 0}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n \"\"\"\n for i in range(n - 1, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 1}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\"For a given number n, find the largest number that divides n evenly, smaller than n.\"\"\"\n if n < 2:\n return 1\n\n for i in range(n - 1, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 1}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\"For a given number n, find the largest number that divides n evenly, smaller than n.\"\"\"\n # Check if the input is a positive integer\n if not isinstance(n, int) or n <= 0:\n raise ValueError(\"Input must be a positive integer\")\n\n # Start from the largest possible divisor, which is the input number itself,\n # and decrement until finding the first number that divides n evenly\n for i in range(n - 1, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 1}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\"\n For a given number n, find the largest number that divides n evenly, smaller than n\n \"\"\"\n # Start checking divisors from the largest possible, which is n//2\n for i in range(n // 2, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 3}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n \"\"\"\n\n if n < 2: # Base case: for numbers less than 2, they are not divisible by any other number\n return 1\n\n # Start from the largest possible divisor: n//2\n # The reason is that if n is divisible by i, then n is also divisible by n//i, and n//i < i.\n for i in range(n // 2, 0, -1): # from n//2 down to 1\n if n % i == 0: # If n is divisible by i, i is the largest divisor\n return i", "matching_cluster_idx": 3}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n \"\"\"\n if n < 2:\n return 1\n\n for i in range(n - 1, 1, -1):\n if n % i == 0:\n return i\n\n return 1", "matching_cluster_idx": 1}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n \"\"\"\n for i in range(n // 2, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 3}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\"\n For a given number n, find the largest number that divides n evenly, smaller than n.\n \"\"\"\n if n <= 1:\n raise ValueError(\"The input should be a positive integer greater than 1\")\n\n i = n // 2\n while i > 0 and n % i != 0:\n i -= 1\n return i", "matching_cluster_idx": 2}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\"\n For a given number n, find the largest number that divides n evenly, smaller than n.\n\n Args:\n n (int): The input number.\n\n Returns:\n int: The largest divisor smaller than n.\n \"\"\"\n if n < 1:\n raise ValueError(\"Input must be a positive integer\")\n for i in range(n - 1, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 0}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n \"\"\"\n if n < 2:\n return 1\n\n for i in range(n//2, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 3}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\"\n For a given number n, find the largest number that divides n evenly, smaller than n\n \"\"\"\n # Start from half of the number and go down to 1\n for i in range(n // 2, 0, -1):\n # If the number is divisible evenly, return it\n if n % i == 0:\n return i", "matching_cluster_idx": 4}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\"\n For a given number n, find the largest number that divides n evenly, smaller than n\n \"\"\"\n # Check if input is a positive integer\n if not isinstance(n, int) or n <= 0:\n raise ValueError(\"Input must be a positive integer\")\n\n # Start checking divisors from n // 2 (since 1 is always a divisor) and decrease until reaching 1\n for i in range(n // 2, 0, -1):\n if n % i == 0:\n return i\n\n # If no divisor was found, return 1 (as 1 is always a divisor)\n return 1", "matching_cluster_idx": 3}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\"For a given number n, find the largest number that divides n evenly, smaller than n\n\n Args:\n n (int): input number\n\n Returns:\n int: the largest divisor of n\n \"\"\"\n if n < 1:\n raise ValueError('Input should be a positive integer')\n\n for i in range(n - 1, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 1}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\"\n For a given number n, find the largest number that divides n evenly, smaller than n.\n\n Args:\n n (int): The number to find the largest divisor of.\n\n Returns:\n int: The largest divisor of n that is smaller than n.\n\n Examples:\n >>> largest_divisor(15)\n 5\n \"\"\"\n # Start from the largest possible divisor which is n//2\n divisor = n // 2\n while n % divisor != 0:\n # Decrease the divisor by 1 and continue until a divisor is found\n divisor -= 1\n return divisor", "matching_cluster_idx": 3}]}, "HumanEval/26": {"dps": null, "dps_norm": null, "pass@1": 0.0, "profiled": []}, "HumanEval/31": {"dps": 78.73417721518987, "dps_norm": 82.5, "pass@1": 98.0, "profiled": [{"solution": "def is_prime(n):\n \"\"\"\n Return true if a given number is prime, and false otherwise.\n \"\"\"\n if n < 2:\n return False\n for i in range(2, int(n ** 0.5) + 1):\n if n % i == 0:\n return False\n return True", "matching_cluster_idx": 5}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\"\"\"\n if n <= 1:\n return False\n elif n <= 3:\n return True\n elif n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\"\"\"\n if n <= 1:\n return False\n elif n <= 3:\n return True\n elif n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\"\"\"\n if n <= 1:\n return False\n elif n <= 3:\n return True\n elif n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n \"\"\"\n if n <= 1:\n return False\n elif n <= 3:\n return True\n elif n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n if n <= 1:\n return False\n elif n <= 3:\n return True\n elif n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\"\"\"\n if n <= 1:\n return False\n elif n <= 3:\n return True\n elif n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return True if a given number is prime, and False otherwise.\"\"\"\n if n < 2:\n return False\n for i in range(2, int(n ** 0.5) + 1):\n if n % i == 0:\n return False\n return True", "matching_cluster_idx": 5}, {"solution": "def is_prime(n):\n \"\"\"\n Return true if a given number is prime, and false otherwise.\n\n Arguments:\n n -- integer to check if it's prime or not\n\n Returns:\n bool -- True if number is prime, False otherwise\n \"\"\"\n if n <= 1:\n return False\n elif n == 2:\n return True\n elif n % 2 == 0:\n return False\n else:\n i = 3\n while i * i <= n:\n if n % i:\n i += 2\n else:\n return False\n return True", "matching_cluster_idx": 5}, {"solution": "def is_prime(n):\n if n <= 1:\n return False\n elif n <= 3:\n return True\n elif n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\"\"\"\n if n < 2:\n return False\n for i in range(2, int(n**0.5) + 1): # loop only up to square root of n\n if n % i == 0: # if n is divisible by any number up to its square root, it is not prime\n return False\n return True", "matching_cluster_idx": 5}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\"\"\"\n if n <= 1:\n return False\n elif n <= 3:\n return True\n elif n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n if n < 2:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True", "matching_cluster_idx": 5}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\"\"\"\n if n <= 1:\n return False\n elif n <= 3:\n return True\n elif n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\"\"\"\n if n <= 1:\n return False\n elif n <= 3:\n return True\n elif n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return True if a given number is prime, and False otherwise.\n\n This function checks if a number is prime by iterating from 2 to the square root of the number,\n and checks if the number is divisible by any of these values. If it is, then it is not a prime.\n \"\"\"\n\n if n < 2:\n return False\n\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n\n return True", "matching_cluster_idx": 5}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\"\"\"\n if n <= 1:\n return False\n elif n <= 3:\n return True\n elif n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n if n <= 1:\n return False\n if n == 2:\n return True\n if n % 2 == 0:\n return False\n max_div = int(n**0.5) + 1\n for i in range(3, max_div, 2):\n if n % i == 0:\n return False\n return True", "matching_cluster_idx": 5}, {"solution": "def is_prime(n):\n \"\"\"Return True if a given number is prime, and False otherwise.\"\"\"\n if n < 2:\n return False\n for i in range(2, int(n ** 0.5) + 1):\n if n % i == 0:\n return False\n return True", "matching_cluster_idx": 5}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\"\"\"\n if n <= 1:\n return False\n elif n <= 3:\n return True\n elif n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}]}, "HumanEval/33": {"dps": 50.9837962962963, "dps_norm": 71.81818181818181, "pass@1": 73.0, "profiled": [{"solution": "def sort_third(l: list) -> list:\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n \"\"\"\n to_sort = [l[i] for i in range(0, len(l), 3)]\n to_sort.sort()\n l[::3] = to_sort\n return l", "matching_cluster_idx": 9}, {"solution": "def sort_third(l):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three,\n while its values at the indicies that are divisible by three are equal to\n the values of the corresponding indicies of l, but sorted.\n \"\"\"\n threes = [l[i] for i in range(0, len(l), 3)]\n threes.sort()\n return [threes.pop(0) if i % 3 == 0 else val for i, val in enumerate(l)]", "matching_cluster_idx": 6}, {"solution": "def sort_third(l: list):\n # Create a list of elements at indices divisible by three\n divisible_by_three = [l[i] for i in range(0, len(l), 3)]\n\n # Sort the list of elements\n divisible_by_three.sort()\n\n # Create a new list with sorted elements at indices divisible by three\n sorted_l = [divisible_by_three.pop(0) if i % 3 == 0 else l[i] for i in range(len(l))]\n\n return sorted_l", "matching_cluster_idx": 6}, {"solution": "def sort_third(l: list) -> list:\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n \"\"\"\n # Separate elements at indices divisible by 3\n divisible_by_three = sorted([l[i] for i in range(0, len(l), 3)])\n # Replace elements at indices divisible by 3 with sorted elements\n return [divisible_by_three.pop(0) if i % 3 == 0 else val for i, val in enumerate(l)]", "matching_cluster_idx": 6}, {"solution": "def sort_third(l):\n # Extract elements at indices divisible by three and sort them\n sorted_thirds = sorted([l[i] for i in range(0, len(l), 3)])\n # Construct the output list by replacing elements at indices divisible by three with sorted elements\n l_prime = [sorted_thirds.pop(0) if i % 3 == 0 else elem for i, elem in enumerate(l)]\n return l_prime", "matching_cluster_idx": 6}, {"solution": "def sort_third(l: list) -> list:\n # Separate elements at indices divisible by 3\n third_elements = [l[i] for i in range(0, len(l), 3)]\n third_elements.sort() # Sort them\n\n # Replace elements at indices divisible by 3 with sorted elements\n l = [third_elements.pop(0) if i % 3 == 0 else val for i, val in enumerate(l)]\n\n return l", "matching_cluster_idx": 6}, {"solution": "def sort_third(l):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indices that are not divisible by three, while its values at the indices\n that are divisible by three are equal to the values of the corresponding indices of l, but sorted.\n \"\"\"\n # Create a new list with the values at indices divisible by 3\n to_sort = [l[i] for i in range(len(l)) if i % 3 == 0]\n # Sort the new list\n sorted_to_sort = sorted(to_sort)\n # Replace the values at indices divisible by 3 in the original list with the sorted values\n l_copy = l.copy()\n for i, value in enumerate(to_sort):\n l_copy[i * 3] = sorted_to_sort.pop(0)\n return l_copy", "matching_cluster_idx": 6}, {"solution": "def sort_third(l: list) -> list:\n # Extract elements at indices divisible by three\n to_sort = [l[i] for i in range(0, len(l), 3)]\n\n # Sort the extracted elements\n to_sort.sort()\n\n # Place the sorted elements back into the list\n result = l.copy()\n i = 0\n for j in range(0, len(l), 3):\n result[j] = to_sort[i]\n i += 1\n\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n # Extract elements at indices divisible by 3, sort them, and replace them in the original list\n sorted_third_elements = sorted(l[i] for i in range(0, len(l), 3))\n for i in range(0, len(l), 3):\n l[i] = sorted_third_elements.pop(0)\n return l", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n # Extract elements at indices divisible by three and sort them\n to_sort = sorted([l[i] for i in range(0, len(l), 3)])\n\n # Create a list of indices divisible by three\n indices = list(range(0, len(l), 3))\n\n # Create a list with same values as l but at indices divisible by three are filled with sorted values\n l_prime = [to_sort.pop(0) if i in indices else val for i, val in enumerate(l)]\n\n return l_prime", "matching_cluster_idx": 2}, {"solution": "def sort_third(l):\n # Extract values at indices divisible by three\n third_indices = [i for i in range(0, len(l), 3)]\n third_values = [l[i] for i in third_indices]\n\n # Sort the extracted values\n third_values.sort()\n\n # Replace the values at indices divisible by three with the sorted values\n for i, value in zip(third_indices, third_values):\n l[i] = value\n\n return l", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list) -> list:\n # List to store elements at indices divisible by three\n divisible_by_three = [l[i] for i in range(0, len(l), 3)]\n\n # Sort the list of elements divisible by three\n divisible_by_three.sort()\n\n # Iterate over list and replace elements at indices divisible by three with sorted list\n for i in range(0, len(l), 3):\n l[i] = divisible_by_three.pop(0)\n\n return l", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list) -> list:\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n \"\"\"\n # Extract elements at indices divisible by three\n to_sort = [l[i] for i in range(0, len(l), 3)]\n\n # Sort the extracted elements\n to_sort.sort()\n\n # Place sorted elements back in the original list\n for i in range(0, len(l), 3):\n l[i] = to_sort.pop(0)\n\n return l", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list) -> list:\n divisible_by_three = [l[i] for i in range(0, len(l), 3)]\n divisible_by_three.sort()\n return [divisible_by_three.pop(0) if i % 3 == 0 else val for i, val in enumerate(l)]", "matching_cluster_idx": 6}, {"solution": "def sort_third(l: list):\n # Separate elements at indices divisible by 3\n by_three = sorted([l[i] for i in range(0, len(l), 3)])\n # Replace elements at indices divisible by 3 with sorted elements\n l[::3] = by_three\n return l", "matching_cluster_idx": 9}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indices that are not divisible by three, while its values at the indices that are divisible by three are equal\n to the values of the corresponding indices of l, but sorted.\n \"\"\"\n # Extract elements at indices divisible by three and sort them\n third_els = sorted([l[i] for i in range(0, len(l), 3)])\n # Create a new list with sorted elements at indices divisible by three\n new_l = [third_els.pop(0) if i % 3 == 0 else l[i] for i in range(len(l))]\n return new_l", "matching_cluster_idx": 6}, {"solution": "def sort_third(l: list) -> list:\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three\n are equal to the values of the corresponding indicies of l, but sorted.\n \"\"\"\n threes = [l[i] for i in range(0, len(l), 3)]\n threes.sort()\n return [threes.pop(0) if i % 3 == 0 else val for i, val in enumerate(l)]", "matching_cluster_idx": 6}, {"solution": "def sort_third(l: list) -> list:\n # Collect all elements at indices divisible by three\n to_sort = [l[i] for i in range(0, len(l), 3)]\n\n # Sort the collected elements\n to_sort.sort()\n\n # Replace the elements at indices divisible by three with the sorted elements\n for i, element in zip(range(0, len(l), 3), to_sort):\n l[i] = element\n\n return l", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n # Initialize an empty list to hold elements at indices divisible by 3\n sort_list = [l[i] for i in range(0, len(l), 3)]\n sort_list.sort() # Sort the list\n\n # Replace elements at indices divisible by 3 in the original list with sorted elements\n for i in range(0, len(l), 3):\n l[i] = sort_list.pop(0)\n\n return l", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list) -> list:\n # Create a list of the elements at positions divisible by 3\n divisible_by_three = [l[i] for i in range(0, len(l), 3)]\n\n # Sort the list of elements divisible by three\n divisible_by_three.sort()\n\n # Replace the elements at positions divisible by three with the sorted elements\n for i in range(0, len(l), 3):\n l[i] = divisible_by_three.pop(0)\n\n return l", "matching_cluster_idx": 8}]}, "HumanEval/34": {"dps": 86.41509433962264, "dps_norm": 97.0, "pass@1": 100.0, "profiled": [{"solution": "def unique(l: list) -> list:\n \"\"\"Return sorted unique elements in a list\"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list) -> list:\n \"\"\"Return sorted unique elements in a list\"\"\"\n return sorted(list(set(l)))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list) -> list:\n \"\"\"Return sorted unique elements in a list\"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list) -> list:\n \"\"\"Return sorted unique elements in a list\"\"\"\n return sorted(list(set(l)))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list) -> list:\n \"\"\"Return sorted unique elements in a list\"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list) -> list:\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list) -> list:\n \"\"\"Return sorted unique elements in a list\n \"\"\"\n return sorted(list(set(l)))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list) -> list:\n \"\"\"Return sorted unique elements in a list\"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list) -> list:\n \"\"\"\n Return sorted unique elements in a list.\n\n Args:\n l (list): Input list.\n\n Returns:\n list: Unique elements in sorted order.\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list) -> list:\n \"\"\"Return sorted unique elements in a list\"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n return sorted(list(set(l)))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list) -> list:\n \"\"\"Return sorted unique elements in a list\"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list) -> list:\n \"\"\"Return sorted unique elements in a list\"\"\"\n return sorted(list(set(l)))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list) -> list:\n \"\"\"Return sorted unique elements in a list\"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list) -> list:\n \"\"\"Return sorted unique elements in a list\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\"\"\"\n return sorted(list(set(l)))", "matching_cluster_idx": 3}, {"solution": "def unique(l: list) -> list:\n \"\"\"Return sorted unique elements in a list\"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list) -> list:\n \"\"\"Return sorted unique elements in a list\"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l):\n \"\"\"Return sorted unique elements in a list\"\"\"\n return sorted(list(set(l)))", "matching_cluster_idx": 3}, {"solution": "def unique(l: list) -> list:\n \"\"\"Return sorted unique elements in a list\"\"\"\n\n # Using set to get unique elements, then convert it back to list and sort it\n return sorted(list(set(l)))", "matching_cluster_idx": 3}]}, "HumanEval/36": {"dps": 72.58064516129032, "dps_norm": 67.14285714285714, "pass@1": 66.0, "profiled": [{"solution": "def fizz_buzz(n: int) -> int:\n if n < 1:\n return 0\n\n count = 0\n for num in range(1, n):\n if num % 11 == 0 or num % 13 == 0:\n count += str(num).count('7')\n\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\"\"\"\n count = 0\n for i in range(1, n):\n if i % 11 == 0 or i % 13 == 0:\n while i > 0:\n if i % 10 == 7:\n count += 1\n i = i // 10\n return count", "matching_cluster_idx": 3}, {"solution": "def fizz_buzz(n: int) -> int:\n count = 0\n for i in range(1, n):\n if i % 11 == 0 or i % 13 == 0: # Check divisibility by 11 or 13\n while i > 0: # Count digits\n if i % 10 == 7: # Check if digit is 7\n count += 1\n i //= 10\n return count", "matching_cluster_idx": 3}, {"solution": "def fizz_buzz(n: int) -> int:\n # Check if number is divisible by 11 or 13\n def is_fizz_buzz(num: int) -> bool:\n return num % 11 == 0 or num % 13 == 0\n\n count = 0\n for num in range(1, n):\n if is_fizz_buzz(num):\n # Count the digit 7 in the number\n count += str(num).count('7')\n return count", "matching_cluster_idx": 3}, {"solution": "def fizz_buzz(n: int) -> int:\n count = 0\n for i in range(1, n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n count = 0\n for num in range(11, n):\n if num % 11 == 0 or num % 13 == 0:\n while num > 0:\n if num % 10 == 7:\n count += 1\n num //= 10\n return count", "matching_cluster_idx": 3}, {"solution": "def fizz_buzz(n: int) -> int:\n count = 0\n for i in range(1, n):\n if (i % 11 == 0 or i % 13 == 0) and '7' in str(i):\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n # Helper function to count occurrences of digit 7 in an integer\n def count_sevens(num: int) -> int:\n return str(num).count('7')\n\n # Initialize counter for occurrences of digit 7\n total_sevens = 0\n\n # Iterate over integers less than n\n for i in range(n):\n # Check if the integer is divisible by 11 or 13\n if i % 11 == 0 or i % 13 == 0:\n # If so, count the occurrences of digit 7 and add it to the total\n total_sevens += count_sevens(i)\n\n return total_sevens", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n def count_sevens(m: int) -> int:\n return ''.join(str(m)).count('7')\n\n return sum(count_sevens(i) for i in range(1, n) if i % 11 == 0 or i % 13 == 0)", "matching_cluster_idx": 3}, {"solution": "def fizz_buzz(n: int) -> int:\n # Check for the divisibility of numbers less than n by 11 or 13\n divisible_by_11_or_13 = (i for i in range(1, n) if i % 11 == 0 or i % 13 == 0)\n\n # Calculate the number of times the digit 7 appears in the numbers\n count = sum(str(i).count('7') for i in divisible_by_11_or_13)\n\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n count = 0\n for num in range(1, n):\n if num % 11 == 0 or num % 13 == 0:\n count += str(num).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\"\"\"\n\n count = 0\n\n for i in range(1, n):\n if i % 11 == 0 or i % 13 == 0:\n while i > 0:\n if i % 10 == 7:\n count += 1\n i = i // 10\n\n return count", "matching_cluster_idx": 3}, {"solution": "def fizz_buzz(n: int) -> int:\n # Initialize counter\n count = 0\n\n # Iterate from 1 to n\n for num in range(1, n):\n # Check if number is divisible by 11 or 13\n if num % 11 == 0 or num % 13 == 0:\n # Convert number to string to easily count digit 7\n num_str = str(num)\n\n # Iterate through each digit in the number\n for digit in num_str:\n # Check if digit is 7\n if digit == '7':\n # Increment counter if digit is 7\n count += 1\n\n # Return the final count\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n count = 0\n for i in range(1, n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def count_sevens(n):\n \"\"\"Helper function to count number of digits 7 in a given number.\"\"\"\n return str(n).count('7')\ndef fizz_buzz(n: int):\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\"\"\"\n if n < 1:\n return 0\n return sum(count_sevens(i) for i in range(1, n) if i % 11 == 0 or i % 13 == 0)", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\"\"\"\n count = 0\n for i in range(1, n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0: # Check divisibility by 11 or 13\n count += str(i).count('7') # Count occurrences of 7 in the number\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\"\"\"\n count = 0\n for i in range(11, n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n count = 0\n for i in range(1, n):\n if i % 11 == 0 or i % 13 == 0: # check divisibility by 11 or 13\n num = str(i) # convert the number to a string for easy iteration\n count += num.count('7') # count the occurrences of '7' in the string\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n count = 0\n for i in range(1, n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}]}, "HumanEval/37": {"dps": 95.6873977086743, "dps_norm": 91.5, "pass@1": 90.0, "profiled": [{"solution": "def sort_even(l: list) -> list:\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n \"\"\"\n evens = sorted([l[i] for i in range(0, len(l), 2)])\n l[::2] = evens\n return l", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list) -> list:\n # Extract elements at even indices and sort them\n even_elements = sorted(l[::2])\n\n # Replace elements at even indices with sorted elements\n for i in range(0, len(l), 2):\n l[i] = even_elements.pop(0)\n\n return l", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\"\"\"\n evens = sorted([l[i] for i in range(0, len(l), 2)])\n return [l[i] if i % 2 else evens.pop(0) for i in range(len(l))]", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list) -> list:\n # Create a new list with even indices from the original list\n even_nums = [l[i] for i in range(0, len(l), 2)]\n\n # Sort the even_nums list\n even_nums.sort()\n\n # Zip even_nums back into the original list at even indices\n result = [even_nums[i//2] if i % 2 == 0 else l[i] for i in range(len(l))]\n\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list) -> list:\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n \"\"\"\n evens = sorted([l[i] for i in range(0, len(l), 2)])\n for i, num in enumerate(evens):\n if i < len(l) and l[i*2] != num:\n l[i*2] = num\n return l", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list) -> list:\n # Extract even-index elements\n even_elements = sorted(l[::2])\n # Create new list using even_elements for even indices\n result = [even_elements.pop(0) if i % 2 == 0 else l[i] for i in range(len(l))]\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list) -> list:\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies\n are equal to the values of the even indicies of l, but sorted.\n \"\"\"\n # Extract even-indexed values, sort them and put them back in the correct order\n evens = sorted(l[::2])\n new_l = l.copy()\n new_l[::2] = evens\n return new_l", "matching_cluster_idx": 9}, {"solution": "def sort_even(l: list) -> list:\n \"\"\"Sort the even indices of the input list while keeping the odd indices the same.\"\"\"\n # Extract elements at even indices and sort them\n even_elements = sorted(l[i] for i in range(0, len(l), 2))\n # Create a new list with sorted even elements at even indices and original elements at odd indices\n return [even_elements[i//2] if i % 2 == 0 else l[i] for i in range(len(l))]", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list) -> list:\n evens = sorted(l[::2])\n l[::2] = evens\n return l", "matching_cluster_idx": 9}, {"solution": "def sort_even(l):\n # Separate even and odd indexed values\n evens = [l[i] for i in range(0, len(l), 2)]\n odds = [l[i] for i in range(1, len(l), 2)]\n\n # Sort the even indexed values\n evens.sort()\n\n # Combine the sorted evens with the odds\n return [evens.pop(0) if i % 2 == 0 else odds[i // 2] for i in range(len(l))]", "matching_cluster_idx": 8}, {"solution": "def sort_even(l):\n even_nums = sorted(l[::2])\n l[::2] = even_nums\n return l", "matching_cluster_idx": 9}, {"solution": "def sort_even(l: list) -> list:\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\"\"\"\n # Extract the elements at even indexes and sort them\n even_elements = sorted([l[i] for i in range(0, len(l), 2)])\n\n # Replace the elements at even indexes in the original list with the sorted elements\n for i in range(0, len(l), 2):\n l[i] = even_elements.pop(0)\n\n return l", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n even_indexes = [l[i] for i in range(0, len(l), 2)]\n even_indexes.sort()\n for i, val in enumerate(even_indexes):\n l[i*2] = val\n return l", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list) -> list:\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\"\"\"\n # Get even-indexed elements and sort them\n sorted_even = sorted([l[i] for i in range(0, len(l), 2)])\n\n # Create a new list with sorted even-indexed elements and keep odd-indexed elements the same\n result = [sorted_even[i//2] if i % 2 == 0 else l[i] for i in range(len(l))]\n\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list) -> list:\n even_inds = [i for i in range(0, len(l), 2)]\n even_elems = [l[i] for i in even_inds]\n even_elems.sort()\n return [even_elems.pop(0) if i % 2 == 0 else val for i, val in enumerate(l)]", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list) -> list:\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n \"\"\"\n evens = sorted([l[i] for i in range(0, len(l), 2)])\n l[::2] = evens\n return l", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list) -> list:\n even_els = sorted(l[::2]) # Get even-indexed elements and sort them\n result = l[:] # Copy the input list\n for i, el in enumerate(even_els):\n # Replace even-indexed elements in the result list\n result[i*2] = el\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n \"\"\"\n # Separate even and odd index values\n even_values = [l[i] for i in range(0, len(l), 2)]\n odd_values = [l[i] for i in range(1, len(l), 2)]\n\n # Sort the even values\n even_values.sort()\n\n # Create the new list with sorted even values and original odd values\n result = []\n for i in range(len(l)):\n if i % 2 == 0:\n result.append(even_values.pop(0))\n else:\n result.append(odd_values.pop(0))\n\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list) -> list:\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n \"\"\"\n even_elements = sorted(l[::2])\n return [even_elements.pop(0) if i % 2 == 0 else l[i] for i in range(len(l))]", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list) -> list:\n # Separate even and odd indexed elements\n even = sorted([l[i] for i in range(0, len(l), 2)])\n odd = [l[i] for i in range(1, len(l), 2)]\n\n # Combine them back together\n result = []\n for i in range(len(l)):\n if i % 2 == 0:\n result.append(even.pop(0))\n else:\n result.append(odd.pop(0))\n return result", "matching_cluster_idx": 8}]}, "HumanEval/49": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 37.0, "profiled": [{"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics)\"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int):\n # return 2^n modulo p\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int):\n \"\"\"Return 2^n modulo p (be aware of numerics).\"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p.\"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics)\"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p.\"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}]}, "HumanEval/51": {"dps": 81.25603864734299, "dps_norm": 67.5, "pass@1": 99.0, "profiled": [{"solution": "def remove_vowels(text):\n vowels = 'aeiouAEIOU'\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n vowels = 'aeiouAEIOU'\n return ''.join(char for char in text if char not in vowels)", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n # Define the vowels\n vowels = 'aeiouAEIOU'\n\n # Use list comprehension to create a new string without vowels\n text_without_vowels = ''.join([char for char in text if char not in vowels])\n\n return text_without_vowels", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n vowels = 'aeiouAEIOU'\n return ''.join(char for char in text if char not in vowels)", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n vowels = 'aeiouAEIOU'\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n vowels = 'aeiouAEIOU'\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n vowels = 'aeiouAEIOU'\n return ''.join(char for char in text if char not in vowels)", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"Remove vowels (both lowercase and uppercase) from a given string.\"\"\"\n return ''.join([char for char in text if char.lower() not in 'aeiou'])", "matching_cluster_idx": 2}, {"solution": "def remove_vowels(text):\n vowels = 'aeiouAEIOU'\n return ''.join(char for char in text if char not in vowels)", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n vowels = 'aeiouAEIOU'\n return ''.join(ch for ch in text if ch not in vowels)", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n vowels = 'aeiouAEIOU'\n return ''.join(ch for ch in text if ch not in vowels)", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n return ''.join([char for char in text if char.lower() not in 'aeiou'])", "matching_cluster_idx": 2}, {"solution": "def remove_vowels(text):\n # Define the vowels, both lowercase and uppercase\n vowels = 'aeiouAEIOU'\n\n # Use the translate() function to remove all vowels\n return ''.join(char for char in text if char not in vowels)", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n return ''.join(ch for ch in text if ch.lower() not in 'aeiou')", "matching_cluster_idx": 2}, {"solution": "def remove_vowels(text):\n vowels = 'aeiouAEIOU'\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n vowels = 'aeiouAEIOU'\n return ''.join(char for char in text if char not in vowels)", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n # Define the vowels, both lower-case and upper-case\n vowels = 'aeiouAEIOU'\n\n # Use the join() method to combine characters from the text after removing vowels\n result = ''.join(char for char in text if char not in vowels)\n\n return result", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n vowels = 'aeiouAEIOU'\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n vowels = 'aeiouAEIOU'\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n return ''.join(char for char in text if char.lower() not in 'aeiou')", "matching_cluster_idx": 2}]}, "HumanEval/54": {"dps": 93.9209726443769, "dps_norm": 98.9795918367347, "pass@1": 14.0, "profiled": [{"solution": "def same_chars(s0: str, s1: str) -> bool:\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \"\"\"\n\n # Create sets of characters from each string\n set_s0 = set(s0)\n set_s1 = set(s1)\n\n # Compare the sets, if they are equal, the strings have the same characters\n return set_s0 == set_s1", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n # Create sets from the strings to remove duplicates and compare\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n # Create two sets of characters from s0 and s1\n set_s0 = set(s0)\n set_s1 = set(s1)\n\n # If the lengths of the two sets are not equal, they cannot have the same characters\n if len(set_s0) != len(set_s1):\n return False\n\n # If both sets are equal, then all characters in s0 are in s1 and vice versa\n if set_s0 == set_s1:\n return True\n\n # Otherwise, the two strings do not have the same characters\n return False", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \"\"\"\n # Converting strings to sets to remove duplicates and then checking if the sets are equal\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n # Use two hashsets to keep track of characters in each string.\n # This method allows for O(1) time complexity to check if a character exists.\n set_s0 = set(s0)\n set_s1 = set(s1)\n\n # Return True if every character in s0 is in s1, and vice versa.\n return set_s0 == set_s1", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \"\"\"\n # Convert both strings to sets and compare them\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \"\"\"\n # Create two sets from the strings to remove duplicates and then compare them\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \"\"\"\n # Create sets of the unique characters from each word\n set_s0 = set(s0)\n set_s1 = set(s1)\n\n # If the lengths of the sets are not equal, they cannot be equal\n if len(set_s0) != len(set_s1):\n return False\n\n # Check if the sets are equal\n return set_s0 == set_s1", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n # Convert strings to sets of characters and compare\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n # Converting both strings into sets of characters to remove duplicates\n # and checking if the sets are equal\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n return set(s0) == set(s1)", "matching_cluster_idx": 6}, {"solution": "def same_chars(s0: str, s1: str) -> bool:\n # Remove spaces and convert the strings to sets to eliminate duplications\n s0, s1 = set(s0.replace(\" \", \"\")), set(s1.replace(\" \", \"\"))\n # Check if both sets are equal\n return s0 == s1", "matching_cluster_idx": 5}]}, "HumanEval/58": {"dps": 84.03543307086613, "dps_norm": 75.83333333333333, "pass@1": 98.0, "profiled": [{"solution": "def common(l1: list, l2: list) -> list:\n \"\"\"Return sorted unique common elements for two lists.\"\"\"\n # Use set intersection to find unique common elements\n # Then convert the resulting set to a list and sort it\n return sorted(list(set(l1) & set(l2)))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list) -> list:\n \"\"\"\n Return sorted unique common elements for two lists.\n \"\"\"\n return sorted(list(set(l1) & set(l2)))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list) -> list:\n \"\"\"Return sorted unique common elements for two lists.\n Args:\n l1 (list): the first list\n l2 (list): the second list\n Returns:\n list: the sorted list of unique common elements\n \"\"\"\n # Convert lists to sets to easily find unique common elements\n set1, set2 = set(l1), set(l2)\n common_set = set1 & set2 # Set intersection to find common elements\n\n # Convert the set back to a list and sort it\n common_list = sorted(list(common_set))\n\n return common_list", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list) -> list:\n \"\"\"Return sorted unique common elements for two lists.\"\"\"\n return sorted(set(l1) & set(l2))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list) -> list:\n \"\"\"Return sorted unique common elements for two lists.\"\"\"\n\n # Convert lists to sets to remove duplicates and perform faster operations\n set1 = set(l1)\n set2 = set(l2)\n\n # Find common elements and convert back to list\n common_elements = list(set1.intersection(set2))\n\n # Sort the list\n common_elements.sort()\n\n return common_elements", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list) -> list:\n \"\"\"Return sorted unique common elements for two lists.\"\"\"\n return sorted(set(l1) & set(l2))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list) -> list:\n return sorted(set(l1) & set(l2))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list) -> list:\n \"\"\"Return sorted unique common elements for two lists.\"\"\"\n return sorted(set(l1) & set(l2))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list) -> list:\n # Use set to get unique elements and list comprehension to get common elements\n return sorted(set(l1) & set(l2))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list) -> list:\n \"\"\"Return sorted unique common elements for two lists.\"\"\"\n return sorted(set(l1) & set(l2))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list) -> list:\n # Use list comprehension to find common elements and set data structure to eliminate duplicates\n common_elements = list(set([i for i in l1 if i in l2]))\n\n # Sort the resulting list\n common_elements.sort()\n\n return common_elements", "matching_cluster_idx": 0}, {"solution": "def common(l1: list, l2: list) -> list:\n \"\"\"Return sorted unique common elements for two lists.\n\n Args:\n l1 (list): A list of integers.\n l2 (list): A list of integers.\n\n Returns:\n list: A sorted list of unique common elements.\n\n Examples:\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n\n \"\"\"\n\n # Find common elements by using set intersection\n common_elements = set(l1) & set(l2)\n\n # Sort and return the common elements\n return sorted(common_elements)", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list) -> list:\n \"\"\"Return sorted unique common elements for two lists.\"\"\"\n # Use set to remove duplicates and then list comprehension to find common elements\n common_elements = [i for i in set(l1) if i in set(l2)]\n\n # Sort the common elements\n common_elements.sort()\n\n return common_elements", "matching_cluster_idx": -1}, {"solution": "def common(l1: list, l2: list) -> list:\n \"\"\"Return sorted unique common elements for two lists.\"\"\"\n return sorted(set(l1) & set(l2))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list) -> list:\n return sorted(set(l1) & set(l2))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list) -> list:\n return sorted(set(l1) & set(l2))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list) -> list:\n # Use set operations for efficient element intersection and uniqueness\n # Convert lists to sets, find intersection, and then convert back to list\n return sorted(list(set(l1) & set(l2)))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list) -> list:\n return sorted(set(l1) & set(l2))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list) -> list:\n return sorted(set(l1) & set(l2))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list) -> list:\n \"\"\"Return sorted unique common elements for two lists.\"\"\"\n # Convert lists to sets to remove duplicates and perform set intersection\n common_set = set(l1) & set(l2)\n # Convert set back to list and sort\n return sorted(list(common_set))", "matching_cluster_idx": 4}]}, "HumanEval/59": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 67.0, "profiled": [{"solution": "def largest_prime_factor(n: int) -> int:\n i = 2\n while i * i <= n:\n if n % i:\n i += 1\n else:\n n //= i\n return n if n > 1 else i", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\"\"\"\n i = 2\n while i * i <= n:\n if n % i:\n i += 1\n else:\n n //= i\n return n", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n i = 2\n while i * i <= n:\n if n % i:\n i += 1\n else:\n n //= i\n return n", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\"\"\"\n if n < 2:\n raise ValueError(\"n should be greater than 1\")\n\n i = 2\n while i * i <= n:\n if n % i:\n i += 1\n else:\n n //= i\n return n", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n i = 2\n while i * i <= n:\n if n % i:\n i += 1\n else:\n n //= i\n return n", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n # Assume n > 1 and is not a prime\n i = 2\n while i * i <= n:\n if n % i:\n i += 1\n else:\n n //= i\n return n", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\"\"\"\n i = 2\n while i * i <= n:\n if n % i:\n i += 1\n else:\n n //= i\n return n", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\"\"\"\n i = 2\n while i * i <= n:\n if n % i:\n i += 1\n else:\n n //= i\n return n", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\"\"\"\n i = 2\n while i * i <= n:\n if n % i:\n i += 1\n else:\n n //= i\n return n", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n # Check if input is greater than 1 and is not a prime number\n if n <= 1 or is_prime(n):\n raise ValueError(\"Input must be an integer greater than 1 and not a prime number\")\n\n # Initialize the largest prime factor\n largest = -1\n\n # Try all potential factors starting from 2\n # Iterate until the square of the potential factor is less than or equal to n\n potential_factor = 2\n while potential_factor * potential_factor <= n:\n # While n is divisible by the potential factor, update the largest prime factor and divide n\n while n % potential_factor == 0:\n largest = potential_factor\n n //= potential_factor\n # Increment the potential factor\n potential_factor += 1\n\n # The remaining n must be a prime number greater than 1\n if n > 1:\n largest = n\n\n return largest\ndef is_prime(n: int) -> bool:\n \"\"\"Helper function to check if a number is prime.\"\"\"\n if n < 2:\n return False\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return False\n return True", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\"\"\"\n factor = 2\n while factor * factor <= n:\n if n % factor:\n factor += 1\n else:\n n //= factor\n return n", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n i = 2\n while i * i <= n:\n if n % i:\n i += 1\n else:\n n //= i\n return n", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\"\"\"\n # check if input is valid\n if n <= 1:\n raise ValueError(\"Input must be greater than 1\")\n\n # find the largest prime factor\n i = 2\n while i * i <= n:\n if n % i:\n i += 1\n else:\n n //= i\n return n", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n):\n i = 2\n while i * i <= n:\n if n % i:\n i += 1\n else:\n n //= i\n return n", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\"\"\"\n i = 2\n while i * i <= n:\n if n % i:\n i += 1\n else:\n n //= i\n return n", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\"\"\"\n i = 2\n while i * i <= n:\n if n % i:\n i += 1\n else:\n n //= i\n return n", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n # Check if input is a positive integer greater than 1\n assert n > 1 and isinstance(n, int), \"Input should be an integer greater than 1\"\n\n # Check if input is a prime number and return 1 as the largest prime factor\n if n == 2:\n return n\n elif all(n % i for i in range(2, int(n**0.5) + 1)):\n return 1\n\n # Find the largest prime factor\n i = 2\n while i * i <= n:\n if n % i:\n i += 1\n else:\n n //= i\n return n if n > 1 else i", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\"\"\"\n i = 2\n while i * i <= n:\n if n % i:\n i += 1\n else:\n n //= i\n return n", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n):\n i = 2\n while i * i <= n:\n if n % i:\n i += 1\n else:\n n //= i\n return n", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n i = 2\n while i * i <= n:\n if n % i:\n i += 1\n else:\n n //= i\n return n", "matching_cluster_idx": 8}]}, "HumanEval/64": {"dps": null, "dps_norm": null, "pass@1": 7.0, "profiled": []}, "HumanEval/74": {"dps": 88.8780487804878, "dps_norm": 86.66666666666666, "pass@1": 33.0, "profiled": [{"solution": "def total_match(lst1, lst2):\n len_lst1 = sum(len(word) for word in lst1)\n len_lst2 = sum(len(word) for word in lst2)\n\n if len_lst1 < len_lst2:\n return lst1\n elif len_lst1 > len_lst2:\n return lst2\n else:\n return lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n # Calculate the total number of characters in both lists\n total1 = sum(len(word) for word in lst1)\n total2 = sum(len(word) for word in lst2)\n\n # Determine which list to return based on the total number of characters\n if total1 < total2:\n return lst1\n elif total2 < total1:\n return lst2\n else:\n return lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n sum_chars_lst1 = sum(len(word) for word in lst1)\n sum_chars_lst2 = sum(len(word) for word in lst2)\n\n if sum_chars_lst1 < sum_chars_lst2:\n return lst1\n elif sum_chars_lst2 < sum_chars_lst1:\n return lst2\n else:\n return lst1 # if both lists have the same number of chars, return the first list", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n len_lst1 = sum(len(s) for s in lst1)\n len_lst2 = sum(len(s) for s in lst2)\n\n if len_lst1 < len_lst2:\n return lst1\n elif len_lst1 > len_lst2:\n return lst2\n else:\n return lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n # Calculate total number of characters in each list\n lst1_total = sum(len(word) for word in lst1)\n lst2_total = sum(len(word) for word in lst2)\n\n # Return the list with fewer total characters, or the first list if they're equal\n return lst1 if lst1_total <= lst2_total else lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n len_lst1 = sum(len(word) for word in lst1)\n len_lst2 = sum(len(word) for word in lst2)\n\n if len_lst1 < len_lst2:\n return lst1\n elif len_lst1 > len_lst2:\n return lst2\n else:\n return lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n sum1 = sum(len(s) for s in lst1)\n sum2 = sum(len(s) for s in lst2)\n\n if sum1 < sum2:\n return lst1\n elif sum2 < sum1:\n return lst2\n else:\n return lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n # Calculate the total number of characters in each list\n total1 = sum(len(s) for s in lst1)\n total2 = sum(len(s) for s in lst2)\n\n # If the totals are equal, return the first list\n if total1 == total2:\n return lst1\n\n # Otherwise, return the list with fewer total characters\n return lst1 if total1 < total2 else lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n # Calculate total characters for each list\n total_chars_l1 = sum(len(s) for s in lst1)\n total_chars_l2 = sum(len(s) for s in lst2)\n\n # Return the list with fewer total characters\n if total_chars_l1 < total_chars_l2:\n return lst1\n elif total_chars_l1 > total_chars_l2:\n return lst2\n else:\n return lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n sum_chars_lst1 = sum(len(word) for word in lst1)\n sum_chars_lst2 = sum(len(word) for word in lst2)\n\n if sum_chars_lst1 < sum_chars_lst2:\n return lst1\n elif sum_chars_lst1 > sum_chars_lst2:\n return lst2\n else:\n return lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n length1 = sum(len(word) for word in lst1)\n length2 = sum(len(word) for word in lst2)\n\n if length1 < length2:\n return lst1\n elif length1 > length2:\n return lst2\n else:\n return lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n sum1 = sum(len(word) for word in lst1)\n sum2 = sum(len(word) for word in lst2)\n if sum1 < sum2:\n return lst1\n elif sum1 > sum2:\n return lst2\n else:\n return lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n total_chars_lst1 = sum(len(s) for s in lst1)\n total_chars_lst2 = sum(len(s) for s in lst2)\n\n if total_chars_lst1 < total_chars_lst2:\n return lst1\n elif total_chars_lst1 > total_chars_lst2:\n return lst2\n else:\n return lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n if sum(len(s) for s in lst1) < sum(len(s) for s in lst2):\n return lst1\n elif sum(len(s) for s in lst1) > sum(len(s) for s in lst2):\n return lst2\n else:\n return lst1", "matching_cluster_idx": 5}, {"solution": "def total_match(lst1, lst2):\n total_lst1 = sum(len(item) for item in lst1)\n total_lst2 = sum(len(item) for item in lst2)\n\n if total_lst1 < total_lst2:\n return lst1\n elif total_lst1 > total_lst2:\n return lst2\n else:\n return lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n count1 = sum(len(word) for word in lst1)\n count2 = sum(len(word) for word in lst2)\n\n if count1 < count2:\n return lst1\n elif count2 < count1:\n return lst2\n else:\n return lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n # Calculate the total number of characters in each list\n total_chars_lst1 = sum(len(s) for s in lst1)\n total_chars_lst2 = sum(len(s) for s in lst2)\n\n # If the totals are the same, return the first list\n if total_chars_lst1 == total_chars_lst2:\n return lst1\n\n # Otherwise, return the list with fewer characters\n return lst1 if total_chars_lst1 < total_chars_lst2 else lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n if sum(len(s) for s in lst1) < sum(len(s) for s in lst2):\n return lst1\n elif sum(len(s) for s in lst1) > sum(len(s) for s in lst2):\n return lst2\n else:\n return lst1", "matching_cluster_idx": 5}, {"solution": "def total_match(lst1, lst2):\n count_lst1 = sum(len(word) for word in lst1)\n count_lst2 = sum(len(word) for word in lst2)\n\n if count_lst1 < count_lst2:\n return lst1\n elif count_lst1 > count_lst2:\n return lst2\n else:\n return lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n sum1 = sum(len(s) for s in lst1)\n sum2 = sum(len(s) for s in lst2)\n\n if sum1 < sum2:\n return lst1\n elif sum2 < sum1:\n return lst2\n else:\n return lst1", "matching_cluster_idx": 7}]}, "HumanEval/85": {"dps": 92.35148514851484, "dps_norm": 60.833333333333336, "pass@1": 95.0, "profiled": [{"solution": "def add(lst):\n return sum(x for i, x in enumerate(lst) if i % 2 and x % 2 == 0)", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n return sum(lst[i] for i in range(1, len(lst), 2) if lst[i] % 2 == 0)", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices.\n\n Args:\n lst (list): A list of integers\n\n Returns:\n int: The sum of even elements at odd indices\n\n Examples:\n add([4, 2, 6, 7]) ==> 2\n \"\"\"\n return sum(lst[i] for i in range(1, len(lst), 2) if lst[i] % 2 == 0)", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"\n Given a non-empty list of integers lst. Add the even elements that are at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2\n \"\"\"\n return sum(lst[i] for i in range(1, len(lst), 2) if lst[i] % 2 == 0)", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) => 2\n \"\"\"\n return sum(x for i, x in enumerate(lst) if i % 2 == 1 and x % 2 == 0)", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Args:\n lst (list): A non-empty list of integers\n\n Returns:\n int: The sum of even elements at odd indices\n \"\"\"\n return sum(lst[i] for i in range(1, len(lst), 2) if lst[i] % 2 == 0)", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Args:\n lst (list): List of integers\n\n Returns:\n int: Sum of even elements at odd indices\n\n Examples:\n add([4, 2, 6, 7]) ==> 2\n \"\"\"\n return sum(lst[i] for i in range(1, len(lst), 2) if lst[i] % 2 == 0)", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst, add the even elements that are at odd indices.\"\"\"\n return sum(x for i, x in enumerate(lst) if i % 2 != 0 and x % 2 == 0)", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Args:\n lst (list): The input list.\n\n Returns:\n int: The sum of the even elements at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2\n \"\"\"\n return sum(x for i, x in enumerate(lst) if i % 2 != 0 and x % 2 == 0)", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"\n Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2\n \"\"\"\n return sum([lst[i] for i in range(1, len(lst), 2) if lst[i] % 2 == 0])", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n return sum(lst[i] for i in range(1, len(lst), 2) if lst[i] % 2 == 0)", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n return sum(num for i, num in enumerate(lst) if i % 2 != 0 and num % 2 == 0)", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n return sum(lst[i] for i in range(1, len(lst), 2) if lst[i] % 2 == 0)", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n return sum(lst[i] for i in range(1, len(lst), 2) if lst[i] % 2 == 0)", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Args:\n lst (list of int): A non-empty list of integers.\n\n Returns:\n int: The sum of even elements at odd indices.\n \"\"\"\n return sum(lst[i] for i in range(1, len(lst), 2) if lst[i] % 2 == 0)", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) -> 2\n \"\"\"\n return sum(lst[i] for i in range(1, len(lst), 2) if lst[i] % 2 == 0)", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Args:\n lst (list): The input list.\n\n Returns:\n int: The sum of even elements at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) -> 2\n \"\"\"\n return sum(x for i, x in enumerate(lst) if i % 2 != 0 and x % 2 == 0)", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n return sum(lst[i] for i in range(1, len(lst), 2) if lst[i] % 2 == 0)", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"\n Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Args:\n lst (list): A non-empty list of integers.\n\n Returns:\n int: The sum of the even elements at odd indices in the list.\n \"\"\"\n return sum(l for i, l in enumerate(lst) if i % 2 and not l % 2)", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n return sum(lst[i] for i in range(1, len(lst), 2) if lst[i] % 2 == 0)", "matching_cluster_idx": 3}]}, "HumanEval/86": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 25.0, "profiled": [{"solution": "def anti_shuffle(s):\n words = s.split(' ')\n result = []\n for word in words:\n chars = list(word)\n chars.sort()\n result.append(''.join(chars))\n return ' '.join(result)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n return ' '.join(''.join(sorted(w)) for w in s.split(' '))", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n \"\"\"\n return ' '.join(''.join(sorted(word)) for word in s.split(' '))", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n words = s.split(' ')\n result = []\n for word in words:\n sorted_word = ''.join(sorted(word))\n result.append(sorted_word)\n return ' '.join(result)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n \"\"\"\n return ' '.join(''.join(sorted(word)) for word in s.split(' '))", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n return ' '.join(''.join(sorted(word, key=ord)) for word in s.split(' '))", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n # Split the string into words\n words = s.split(' ')\n\n # For each word, sort its characters in ascending order and join them back together\n ordered_words = [''.join(sorted(word)) for word in words]\n\n # Join the ordered words back into a single string\n ordered_string = ' '.join(ordered_words)\n\n return ordered_string", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n # split the string into a list of words\n words = s.split(' ')\n # map over the list of words\n words = [ ''.join(sorted(word)) for word in words ]\n # join the list of sorted words back into a string\n return ' '.join(words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n return ' '.join(''.join(sorted(word)) for word in s.split(' '))", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n return ' '.join(''.join(sorted(word)) for word in s.split(' '))", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n This function takes a string and returns an ordered version of it.\n It replaces each word in the string with a new word where all the characters are\n arranged in ascending order based on ascii value, while preserving the order of words and blank spaces.\n \"\"\"\n words = s.split(' ') # Split the string into words\n for i in range(len(words)): # Iterate over each word\n sorted_word = ''.join(sorted(words[i])) # Sort the characters in the word and join them back into a string\n words[i] = sorted_word # Replace the original word with the sorted word\n return ' '.join(words) # Join the words back into a string with spaces between them", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n return ' '.join(''.join(sorted(word)) for word in s.split(' '))", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n return ' '.join(''.join(sorted(w)) for w in s.split(' '))", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n # Split the string into words\n words = s.split(' ')\n\n # For each word, sort its characters in ascending order and join them back together\n ordered_words = [''.join(sorted(word)) for word in words]\n\n # Join the ordered words back into a string\n ordered_string = ' '.join(ordered_words)\n\n return ordered_string", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n words = s.split(' ')\n result = []\n for word in words:\n sorted_word = ''.join(sorted(word))\n result.append(sorted_word)\n return ' '.join(result)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n words = s.split(\" \")\n ordered_words = [\"\".join(sorted(word)) for word in words]\n return \" \".join(ordered_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n return ' '.join(''.join(sorted(word)) for word in s.split(' '))", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n \"\"\"\n return ' '.join(''.join(sorted(word)) for word in s.split(' '))", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n # Split the input string into words\n words = s.split(' ')\n # Iterate over each word\n for i in range(len(words)):\n # Sort characters in the word based on ASCII value\n words[i] = ''.join(sorted(words[i]))\n # Join words back into a single string with space separator\n return ' '.join(words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n return ' '.join(''.join(sorted(word)) for word in s.split(' '))", "matching_cluster_idx": 4}]}, "HumanEval/87": {"dps": 83.42939481268012, "dps_norm": 57.85714285714286, "pass@1": 61.0, "profiled": [{"solution": "def get_row(lst, x):\n coordinates = []\n for i, row in enumerate(lst):\n for j, val in enumerate(row):\n if val == x:\n coordinates.append((i, j))\n coordinates.sort(key=lambda x: (x[0], -x[1]))\n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n result = []\n for i, row in enumerate(lst):\n for j, num in enumerate(row):\n if num == x:\n result.append((i, j))\n result.sort(key=lambda x: (x[0], -x[1]))\n return result", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n Given a 2-dimensional list lst and an integer x, find all occurrences\n of x in lst and return a list of tuples representing the coordinates\n (row, column) of each occurrence, starting with 0 for both axes.\n Sort the coordinates initially by rows in ascending order and then by\n columns in descending order within the same row.\n \"\"\"\n result = []\n for i, row in enumerate(lst):\n for j, elem in enumerate(row):\n if elem == x:\n result.append((i, j))\n result.sort(key=lambda x: (x[0], -x[1]))\n return result", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n result = []\n for row_idx, row in enumerate(lst):\n col_idxs = [idx for idx, val in enumerate(row) if val == x]\n for idx in sorted(col_idxs, reverse=True):\n result.append((row_idx, idx))\n result.sort(key=lambda x: (x[0], -x[1]))\n return result", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n return sorted(((i, j) for i, row in enumerate(lst) for j, v in enumerate(row) if v == x),\n key=lambda c: (c[0], -c[1]))", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n coordinates = []\n for i, row in enumerate(lst):\n for j, val in enumerate(row):\n if val == x:\n coordinates.append((i, j))\n return sorted(coordinates, key=lambda c: (c[0], -c[1]))", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n # Filter list to only include elements equal to x\n indices = [(i, j) for i, sublist in enumerate(lst) for j, element in enumerate(sublist) if element == x]\n\n # Sort the coordinates by rows in ascending order and columns in descending order\n sorted_indices = sorted(indices, key=lambda y: (y[0], -y[1]))\n\n return sorted_indices", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n # Define empty list to store coordinates\n coordinates = []\n\n # Iterate over the list with index i for row number\n for i, row in enumerate(lst):\n # Iterate over the row with index j for column number\n for j, val in enumerate(row):\n # If the value is equal to x, append coordinates to the list\n if val == x:\n coordinates.append((i, j))\n\n # Sort coordinates by rows and columns in descending order\n coordinates.sort(key=lambda x: (x[0], -x[1]))\n\n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n coordinates = []\n\n for i in range(len(lst)):\n for j in range(len(lst[i])):\n if lst[i][j] == x:\n coordinates.append((i, j))\n\n # Sort coordinates by rows in ascending order and columns in descending order\n coordinates.sort(key=lambda x: (x[0], -x[1]))\n\n return coordinates", "matching_cluster_idx": 2}, {"solution": "def get_row(lst, x):\n coordinates = []\n for i, row in enumerate(lst):\n for j, num in enumerate(row):\n if num == x:\n coordinates.append((i, j))\n # Sort by rows in ascending order, then by columns in descending order\n coordinates.sort(key=lambda c: (c[0], -c[1]))\n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n coordinates = []\n for i, row in enumerate(lst):\n for j, num in enumerate(row):\n if num == x:\n coordinates.append((i, j))\n coordinates.sort(key=lambda c: (c[0], -c[1]))\n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n result = []\n for i, row in enumerate(lst):\n indices = [(i, j) for j, num in enumerate(row) if num == x]\n indices.sort(key=lambda x: (x[0], -x[1])) # Sort by row (ascending) and column (descending)\n result.extend(indices)\n return result", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n result = []\n for row_idx, row in enumerate(lst):\n for col_idx, num in enumerate(row):\n if num == x:\n result.append((row_idx, col_idx))\n result.sort(key=lambda r: (r[0], -r[1]))\n return result", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n coordinates = []\n for i, row in enumerate(lst):\n if x in row:\n coordinates.extend([(i, j) for j, num in enumerate(row) if num == x])\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n return coordinates", "matching_cluster_idx": 5}, {"solution": "def get_row(lst, x):\n result = []\n for i in range(len(lst)):\n for j in range(len(lst[i])):\n if lst[i][j] == x:\n result.append((i, j))\n result.sort(key=lambda tup: (tup[0], -tup[1]))\n return result", "matching_cluster_idx": 2}, {"solution": "def get_row(lst, x):\n coordinates = []\n for i, sublist in enumerate(lst):\n for j, num in enumerate(sublist):\n if num == x:\n coordinates.append((i, j))\n coordinates.sort(key=lambda x: (x[0], -x[1]))\n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n result = []\n for i in range(len(lst)):\n for j in range(len(lst[i])):\n if lst[i][j] == x:\n result.append((i, j))\n result.sort(key=lambda x: (x[0], -x[1]))\n return result", "matching_cluster_idx": 2}, {"solution": "def get_row(lst, x):\n coords = []\n for i, row in enumerate(lst):\n for j, col in enumerate(row):\n if col == x:\n coords.append((i, j))\n coords.sort(key=lambda y: (y[0], -y[1]))\n return coords", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n coords = [(i, j) for i, row in enumerate(lst) for j, num in enumerate(row) if num == x]\n coords.sort(key=lambda x: (x[0], -x[1]))\n return coords", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n coords = []\n for i, row in enumerate(lst):\n if x in row:\n coords.extend((i, j) for j, num in enumerate(row) if num == x)\n coords.sort(key=lambda c: (c[0], -c[1]))\n return coords", "matching_cluster_idx": 5}]}, "HumanEval/89": {"dps": 96.64948453608248, "dps_norm": 28.571428571428573, "pass@1": 52.0, "profiled": [{"solution": "def encrypt(s):\n result = \"\"\n for char in s:\n if char.isalpha():\n ascii_offset = 65 if char.isupper() else 97\n result += chr((ord(char) - ascii_offset + 4) % 26 + ascii_offset)\n else:\n result += char\n return result", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n result = \"\"\n for char in s:\n if char.isalpha():\n ascii_offset = 65 if char.isupper() else 97\n result += chr((ord(char) - ascii_offset + 4) % 26 + ascii_offset)\n else:\n result += char\n return result", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n def rotate_character(char):\n if not char.isalpha():\n return char\n ascii_offset = 97 if char.islower() else 65 # ASCII values for 'a' and 'A'\n return chr((ord(char) - ascii_offset + 4) % 26 + ascii_offset) # Rotate by 2*2 = 4\n\n return ''.join(rotate_character(char) for char in s)", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n result = \"\"\n for char in s:\n if char.isalpha():\n ascii_offset = ord('a') if char.islower() else ord('A')\n result += chr((ord(char) - ascii_offset + 4) % 26 + ascii_offset)\n else:\n result += char\n return result", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n result = \"\"\n for char in s:\n if char.isalpha():\n ascii_offset = ord('a') if char.islower() else ord('A')\n result += chr((ord(char) - ascii_offset + 4) % 26 + ascii_offset)\n else:\n result += char\n return result", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n result = \"\"\n for char in s:\n if char.isalpha():\n # Shift down by two places\n ascii_offset = ord('a') if char.islower() else ord('A')\n result += chr((ord(char) - ascii_offset + 4) % 26 + ascii_offset)\n else:\n result += char # Append non-alphabetic characters as is\n return result", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n shifted = lambda c: chr((ord(c) - 97 + 4) % 26 + 97) if 'a' <= c <= 'z' else chr((ord(c) - 65 + 4) % 26 + 65) if 'A' <= c <= 'Z' else c\n return ''.join(shifted(c) for c in s)", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n result = \"\"\n for char in s:\n if char.isalpha():\n ascii_offset = ord('a') if char.islower() else ord('A')\n result += chr((ord(char) - ascii_offset + 4) % 26 + ascii_offset)\n else:\n result += char\n return result", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n result = \"\"\n for char in s:\n if char.isalpha():\n ascii_offset = 65 if char.isupper() else 97\n result += chr((ord(char) - ascii_offset + 4) % 26 + ascii_offset)\n else:\n result += char\n return result", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n def shift_char(char):\n if char.isalpha():\n ascii_offset = ord('a') if char.islower() else ord('A')\n return chr((ord(char) - ascii_offset + 4) % 26 + ascii_offset)\n return char\n\n return ''.join(shift_char(c) for c in s)", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Encrypts the input string by shifting each character by 4 positions in the alphabet.\"\"\"\n encrypted = \"\"\n for char in s:\n if char.isalpha():\n ascii_offset = 65 if char.isupper() else 97\n encrypted += chr((ord(char) - ascii_offset + 4) % 26 + ascii_offset)\n else:\n encrypted += char\n return encrypted", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n shift = 2 * 2 # The letters shift down by two multiplied by two places\n encrypted = \"\"\n for char in s:\n if char.isalpha():\n ascii_offset = ord('a') if char.islower() else ord('A')\n encrypted += chr((ord(char) - ascii_offset + shift) % 26 + ascii_offset)\n else:\n encrypted += char\n return encrypted", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n # Define a string of all alphabets (both lower and upper case)\n alphabets = 'abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ'\n\n # Initialize the encrypted string\n encrypted = ''\n\n # Iterate over each character in the input string\n for char in s:\n if char.isalpha(): # Check if the character is an alphabet\n # Shift the character by 4 places in the alphabet\n encrypted += alphabets[(alphabets.index(char) + 4) % 26]\n else:\n # If the character is not an alphabet, add it to the encrypted string as it is\n encrypted += char\n\n return encrypted", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n result = \"\"\n for char in s:\n if char.isalpha():\n ascii_offset = 65 if char.isupper() else 97\n result += chr((ord(char) - ascii_offset + 4) % 26 + ascii_offset)\n else:\n result += char\n return result", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n result = \"\"\n for char in s:\n if char.isalpha():\n ascii_offset = ord('a') if char.islower() else ord('A')\n result += chr((ord(char) - ascii_offset + 4) % 26 + ascii_offset)\n else:\n result += char\n return result", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n def shift(ch, shift):\n if not ch.isalpha():\n return ch\n shift_amount = 2 * 2\n return chr(((ord(ch.lower()) - ord('a') + shift_amount) % 26) + ord('a'))\n\n return ''.join(shift(c, 2) for c in s)", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n result = \"\"\n for char in s:\n if char.isalpha():\n ascii_offset = 65 if char.isupper() else 97\n result += chr((ord(char) - ascii_offset + 4) % 26 + ascii_offset)\n else:\n result += char\n return result", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n result = \"\"\n for char in s:\n if char.isalpha():\n ascii_offset = 65 if char.isupper() else 97\n result += chr((ord(char) - ascii_offset + 4) % 26 + ascii_offset)\n else:\n result += char\n return result", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n result = \"\"\n for char in s:\n if char.isalpha():\n ascii_offset = ord('a') if char.islower() else ord('A')\n result += chr((ord(char) - ascii_offset + 4) % 26 + ascii_offset)\n else:\n result += char\n return result", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n result = \"\"\n for char in s:\n if char.isalpha():\n ascii_offset = 97 if char.islower() else 65\n result += chr((ord(char) - ascii_offset + 4) % 26 + ascii_offset)\n else:\n result += char\n return result", "matching_cluster_idx": 1}]}, "HumanEval/90": {"dps": 40.68093385214008, "dps_norm": 43.333333333333336, "pass@1": 53.0, "profiled": [{"solution": "def next_smallest(lst):\n if len(lst) < 2:\n return None\n smallest = min(lst)\n next_smallest = float('inf')\n for num in lst:\n if num > smallest and num < next_smallest:\n next_smallest = num\n return next_smallest if next_smallest != float('inf') else None", "matching_cluster_idx": 3}, {"solution": "def next_smallest(lst):\n if not lst or len(set(lst)) < 2: # if the list is empty or all elements are the same\n return None\n smallest = float('inf')\n second_smallest = float('inf')\n for num in lst:\n if num < smallest: # update smallest and second_smallest\n second_smallest = smallest\n smallest = num\n elif smallest < num < second_smallest:\n second_smallest = num\n return second_smallest if second_smallest != float('inf') else None", "matching_cluster_idx": 4}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \"\"\"\n if len(lst) < 2:\n return None\n\n smallest = second_smallest = float('inf')\n\n for num in lst:\n if num < smallest:\n second_smallest = smallest\n smallest = num\n elif num < second_smallest and num != smallest:\n second_smallest = num\n\n return None if second_smallest == float('inf') else second_smallest", "matching_cluster_idx": 5}, {"solution": "def next_smallest(lst):\n if not lst or len(set(lst)) < 2:\n return None\n return min(x for x in lst if x > min(lst))", "matching_cluster_idx": -1}, {"solution": "def next_smallest(lst):\n \"\"\"\n Returns the 2nd smallest element of the list, or None if no such element exists.\n \"\"\"\n if not lst: # If the list is empty, return None\n return None\n smallest = second_smallest = float('inf') # Initialize both as positive infinity\n for num in lst:\n if num < smallest: # If a smaller number is found, update both smallest and second_smallest\n second_smallest = smallest\n smallest = num\n elif smallest < num < second_smallest: # If a number is found that's not the smallest but smaller than second_smallest\n second_smallest = num\n return second_smallest if second_smallest != float('inf') else None # Return second_smallest if it's not still infinity", "matching_cluster_idx": 5}, {"solution": "def next_smallest(lst):\n if len(lst) < 2:\n return None\n min_val, next_min = float('inf'), float('inf')\n for num in lst:\n if num < min_val:\n next_min = min_val\n min_val = num\n elif num < next_min and num != min_val:\n next_min = num\n return None if next_min == float('inf') else next_min", "matching_cluster_idx": 5}, {"solution": "def next_smallest(lst):\n if len(lst) < 2:\n return None\n\n first, second = float('inf'), float('inf')\n for num in lst:\n if num < first:\n first, second = num, first\n elif num < second and num != first:\n second = num\n\n return None if second == float('inf') else second", "matching_cluster_idx": 5}, {"solution": "def next_smallest(lst):\n if len(lst) < 2:\n return None\n smallest = second_smallest = float('inf')\n for num in lst:\n if num < smallest:\n smallest, second_smallest = num, smallest\n elif num < second_smallest and num != smallest:\n second_smallest = num\n return None if second_smallest == float('inf') else second_smallest", "matching_cluster_idx": 5}, {"solution": "def next_smallest(lst):\n if len(lst) < 2:\n return None\n\n min_val = float('inf')\n second_min = float('inf')\n\n for num in lst:\n if num < min_val:\n second_min = min_val\n min_val = num\n elif num < second_min and num != min_val:\n second_min = num\n\n return second_min if second_min != float('inf') else None", "matching_cluster_idx": 5}, {"solution": "def next_smallest(lst):\n if len(lst) < 2:\n return None\n smallest = second_smallest = float('inf')\n for num in lst:\n if num < smallest:\n second_smallest = smallest\n smallest = num\n elif smallest < num < second_smallest:\n second_smallest = num\n return second_smallest if second_smallest != float('inf') else None", "matching_cluster_idx": 5}, {"solution": "def next_smallest(lst):\n if len(lst) < 2:\n return None\n first_min = second_min = float('inf')\n for num in lst:\n if num < first_min:\n first_min, second_min = num, first_min\n elif num < second_min and num != first_min:\n second_min = num\n return None if second_min == float('inf') else second_min", "matching_cluster_idx": 5}, {"solution": "def next_smallest(lst):\n if not lst or len(set(lst)) < 2:\n return None\n\n return min([i for i in lst if i > min(lst)])", "matching_cluster_idx": -1}, {"solution": "def next_smallest(lst):\n \"\"\"\n Returns the 2nd smallest element of the list. Returns None if there is no such element.\n \"\"\"\n if len(lst) < 2:\n return None\n else:\n smallest = second_smallest = float('inf')\n\n for num in lst:\n if num < smallest:\n smallest, second_smallest = num, smallest\n elif num < second_smallest and num != smallest:\n second_smallest = num\n\n return None if second_smallest == float('inf') else second_smallest", "matching_cluster_idx": 5}, {"solution": "def next_smallest(lst):\n if len(lst) < 2:\n return None\n\n first_smallest = second_smallest = float('inf')\n for num in lst:\n if num < first_smallest:\n first_smallest, second_smallest = num, first_smallest\n elif num < second_smallest and num != first_smallest:\n second_smallest = num\n\n return None if second_smallest == float('inf') else second_smallest", "matching_cluster_idx": 5}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \"\"\"\n if len(lst) < 2:\n return None\n\n smallest, next_smallest = float('inf'), float('inf')\n\n for num in lst:\n if num < smallest:\n next_smallest = smallest\n smallest = num\n elif num < next_smallest and num != smallest:\n next_smallest = num\n\n if next_smallest == float('inf'):\n return None\n\n return next_smallest", "matching_cluster_idx": 5}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n\n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n\n first_smallest = float('inf')\n second_smallest = float('inf')\n\n for num in lst:\n if num < first_smallest:\n second_smallest = first_smallest\n first_smallest = num\n elif first_smallest < num < second_smallest:\n second_smallest = num\n\n if second_smallest == float('inf'):\n return None\n\n return second_smallest", "matching_cluster_idx": 5}, {"solution": "def next_smallest(lst):\n if not lst or len(lst) < 2:\n return None\n first_smallest = second_smallest = float('inf')\n for num in lst:\n if num < first_smallest:\n first_smallest, second_smallest = num, first_smallest\n elif num < second_smallest and num != first_smallest:\n second_smallest = num\n return None if second_smallest == float('inf') else second_smallest", "matching_cluster_idx": 5}, {"solution": "def next_smallest(lst):\n if not lst or len(set(lst)) < 2:\n return None\n\n min_val = float('inf')\n second_min_val = float('inf')\n\n for num in lst:\n if num < min_val:\n second_min_val = min_val\n min_val = num\n elif num < second_min_val and num != min_val:\n second_min_val = num\n\n return second_min_val if second_min_val != float('inf') else None", "matching_cluster_idx": 4}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n \"\"\"\n if not lst or len(set(lst)) < 2:\n return None\n lst = list(set(lst))\n lst.sort()\n return lst[1]", "matching_cluster_idx": 5}, {"solution": "def next_smallest(lst):\n if len(lst) < 2:\n return None\n smallest = second_smallest = float('inf')\n for num in lst:\n if num < smallest:\n second_smallest = smallest\n smallest = num\n elif smallest < num < second_smallest:\n second_smallest = num\n return second_smallest if second_smallest != float('inf') else None", "matching_cluster_idx": 5}]}, "HumanEval/113": {"dps": 89.65517241379311, "dps_norm": 61.66666666666667, "pass@1": 21.0, "profiled": [{"solution": "def odd_count(lst):\n result = []\n for i, s in enumerate(lst, start=1):\n count = sum(1 for digit in s if int(digit) % 2 != 0)\n result.append(f\"the number of odd elements {count}n the str{count}ng {count} of the {count}nput.\")\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n def count_odd_digits(string):\n return str(sum(1 for digit in string if int(digit) % 2 != 0))\n\n return [f\"the number of odd elements {count_odd_digits(i)}n the str{count_odd_digits(i)}ng {count_odd_digits(i)} of the {count_odd_digits(i)}nput.\"\n for i in lst]", "matching_cluster_idx": 0}, {"solution": "def odd_count(lst):\n result = []\n for i, s in enumerate(lst, 1):\n num_odds = sum(int(x) % 2 == 1 for x in s)\n res = f\"the number of odd elements {num_odds}n the str{num_odds}ng {num_odds} of the {num_odds}nput.\"\n result.append(res)\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n result = []\n for i, s in enumerate(lst, start=1):\n count = sum(int(digit) % 2 != 0 for digit in s)\n result.append(f\"the number of odd elements {count}n the str{count}ng {count} of the {count}nput.\")\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n def odd_count_str(s):\n count = sum(1 for c in s if int(c) % 2 != 0)\n return f\"the number of odd elements {count}n the str{count}ng {count} of the {count}nput.\"\n\n return [odd_count_str(s) for s in lst]", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n result = []\n for i, s in enumerate(lst, start=1):\n count = sum(int(c) % 2 for c in s)\n result.append(f\"the number of odd elements {count}n the str{count}ng {count} of the {count}nput.\")\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n result = []\n for i, s in enumerate(lst, start=1):\n count = sum(1 for c in s if int(c) % 2 != 0)\n result.append(f\"the number of odd elements {count}n the str{count}ng {count} of the {count}nput.\")\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n result = []\n for i, s in enumerate(lst, start=1):\n odd_count = len([digit for digit in s if int(digit) % 2 != 0])\n result.append(f'the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.')\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n output = []\n for i, s in enumerate(lst, 1):\n count = sum(1 for c in s if int(c) % 2 != 0)\n output.append(f\"the number of odd elements {count}n the str{count}ng {count} of the {count}nput.\")\n return output", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n result = []\n for i, s in enumerate(lst):\n count_odd = sum(1 for c in s if int(c) % 2 != 0)\n result.append(f'the number of odd elements {count_odd}n the str{count_odd}ng {count_odd} of the {count_odd}nput.')\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n # Function to calculate number of odd elements in a string\n def count_odd_digits(s):\n return len([c for c in s if int(c) % 2 != 0])\n\n # Use list comprehension to generate the result\n return [f\"the number of odd elements {count_odd_digits(s)}n the str{count_odd_digits(s)}ng {count_odd_digits(s)} of the {count_odd_digits(s)}nput.\" for s in lst]", "matching_cluster_idx": 0}, {"solution": "def odd_count(lst):\n def odd_str(num):\n return \"the number of odd elements {}n the str{}ng {} of the {}nput.\".format(num, num, num, num)\n\n return [odd_str(sum(int(n) % 2 for n in s)) for s in lst]", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n result = []\n for i, s in enumerate(lst, start=1):\n odd_count = sum(int(n) % 2 for n in s)\n output = f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\"\n result.append(output)\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n result = []\n for i, string in enumerate(lst, start=1):\n count = sum(int(digit) % 2 != 0 for digit in string)\n result.append(f\"the number of odd elements {count}n the str{count}ng {count} of the {count}nput.\")\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n result = []\n for i, string in enumerate(lst, start=1):\n odd_digits = sum(int(digit) % 2 != 0 for digit in string)\n result.append(f\"the number of odd elements {odd_digits}n the str{odd_digits}ng {odd_digits} of the {odd_digits}nput.\")\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n result = []\n for i, s in enumerate(lst, start=1):\n num_odd = sum(int(digit) % 2 != 0 for digit in s)\n result.append(f\"the number of odd elements {num_odd}n the str{num_odd}ng {num_odd} of the {num_odd}nput.\")\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n result = []\n for i, s in enumerate(lst, 1):\n count_odd = sum(1 for c in s if int(c) % 2 != 0)\n result.append(f\"the number of odd elements {count_odd}n the str{count_odd}ng {count_odd} of the {count_odd}nput.\")\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n def count_odd_digits(num_str):\n return sum(1 for digit in num_str if int(digit) % 2 != 0)\n\n result = []\n for i, num_str in enumerate(lst, 1):\n odd_count = count_odd_digits(num_str)\n result.append(f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\")\n\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n def odd_number(digit):\n return '1' if digit % 2 != 0 else '8'\n\n def format_string(count):\n return f\"the number of odd elements {count}n the str{count}ng {count} of the {count}nput.\"\n\n return [format_string(sum(int(digit) % 2 != 0 for digit in s)) for s in lst]", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n output = []\n for i, s in enumerate(lst, start=1):\n count = sum(int(digit) % 2 != 0 for digit in s)\n output.append(f\"the number of odd elements {count}n the str{count}ng {count} of the {count}nput.\")\n return output", "matching_cluster_idx": 3}]}, "HumanEval/119": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 31.0, "profiled": [{"solution": "def match_parens(lst):\n def count_brackets(string):\n open_brackets = close_brackets = 0\n for char in string:\n if char == '(':\n open_brackets += 1\n elif char == ')':\n close_brackets += 1\n if close_brackets > open_brackets:\n return \"No\"\n return 'Yes' if open_brackets == close_brackets else 'No'\n\n return count_brackets(lst[0] + lst[1]) if count_brackets(lst[1] + lst[0]) == 'No' else 'Yes'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n s1, s2 = lst\n\n def balance(s):\n count = 0\n for c in s:\n if c == '(':\n count += 1\n elif c == ')':\n if count == 0:\n return False\n count -= 1\n return count == 0\n\n return 'Yes' if balance(s1+s2) or balance(s2+s1) else 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n def helper(s):\n stack = []\n for c in s:\n if c == '(':\n stack.append(c)\n elif c == ')' and stack:\n stack.pop()\n else:\n return 'No'\n return 'Yes' if not stack else 'No'\n\n str1, str2 = lst\n\n # Check if concatenating both strings in either order results in a valid string\n return 'Yes' if helper(str1 + str2) == 'Yes' or helper(str2 + str1) == 'Yes' else 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n def is_balanced(s):\n count = 0\n for c in s:\n if c == '(':\n count += 1\n elif c == ')':\n count -= 1\n if count < 0: # Early exit if string is unbalanced\n return False\n return count == 0\n\n def can_balance(a, b):\n return is_balanced(a + b) or is_balanced(b + a)\n\n return 'Yes' if can_balance(lst[0], lst[1]) else 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n def is_balanced(s):\n count = 0\n for c in s:\n if c == '(':\n count += 1\n elif c == ')':\n count -= 1\n if count < 0:\n return False\n return count == 0\n\n s1, s2 = lst\n return 'Yes' if is_balanced(s1 + s2) or is_balanced(s2 + s1) else 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n def helper(s):\n count = 0\n for c in s:\n if c == '(':\n count += 1\n elif c == ')':\n if count == 0:\n return False\n count -= 1\n return count == 0\n\n first, second = lst\n return 'Yes' if helper(first + second) or helper(second + first) else 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n def is_balance(string):\n balance = 0\n for char in string:\n if char == '(':\n balance += 1\n elif char == ')':\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n if not lst:\n return 'Yes'\n\n lst1, lst2 = lst\n\n if is_balance(lst1 + lst2) or is_balance(lst2 + lst1):\n return 'Yes'\n else:\n return 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n def helper(s):\n count = 0\n for char in s:\n if char == '(':\n count += 1\n elif char == ')':\n count -= 1\n if count < 0:\n return False\n return count == 0\n\n s1, s2 = lst\n if helper(s1) and helper(s2):\n return 'Yes'\n if helper(s2 + s1) or helper(s1 + s2):\n return 'Yes'\n return 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n def is_balanced(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n elif char == ')':\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n a, b = lst\n return 'Yes' if is_balanced(a + b) or is_balanced(b + a) else 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n def count_parens(s):\n count = 0\n for c in s:\n count += 1 if c == '(' else -1\n if count < 0: return False\n return count == 0\n\n a, b = lst\n return 'Yes' if count_parens(a + b) or count_parens(b + a) else 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n \"\"\"\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n \"\"\"\n def is_good(s):\n count = 0\n for c in s:\n if c == '(':\n count += 1\n elif c == ')' and count > 0:\n count -= 1\n elif c == ')':\n return False\n return count == 0\n\n str1, str2 = lst\n return 'Yes' if is_good(str1 + str2) or is_good(str2 + str1) else 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n def is_balanced(s):\n count = 0\n for c in s:\n if c == '(':\n count += 1\n elif c == ')':\n count -= 1\n if count < 0: # Not balanced\n return False\n return count == 0 # Balanced\n\n a, b = lst\n # Concatenate strings in all possible orders and check if any result is balanced\n return 'Yes' if is_balanced(a + b) or is_balanced(b + a) else 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n str1 = lst[0]\n str2 = lst[1]\n\n # function to check if a string has balanced parentheses\n def is_good(str):\n stack = []\n for char in str:\n if char == '(':\n stack.append(char)\n elif char == ')':\n if not stack:\n return False\n stack.pop()\n return len(stack) == 0\n\n # check if both strings are good or if they can be merged to be good\n return 'Yes' if is_good(str1) and is_good(str2) or is_good(str1+str2) or is_good(str2+str1) else 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n def is_balanced(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n elif char == ')':\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n first, second = lst[0], lst[1]\n return 'Yes' if is_balanced(first + second) or is_balanced(second + first) else 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n def check_balance(s):\n count = 0\n for c in s:\n if c == '(':\n count += 1\n elif c == ')':\n count -= 1\n if count < 0:\n return False\n return count == 0\n\n s1, s2 = lst\n # Concatenate and check balance for both possible combinations\n return 'Yes' if check_balance(s1 + s2) or check_balance(s2 + s1) else 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n def is_balanced(s):\n count = 0\n for c in s:\n if c == '(':\n count += 1\n elif c == ')':\n count -= 1\n if count < 0:\n return False\n return count == 0\n\n s1, s2 = lst\n return 'Yes' if is_balanced(s1 + s2) or is_balanced(s2 + s1) else 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n def is_balanced(s):\n count = 0\n for c in s:\n if c == '(':\n count += 1\n elif c == ')':\n count -= 1\n if count < 0:\n return False\n return count == 0\n\n def can_form_good_string(s1, s2):\n return is_balanced(s1 + s2) or is_balanced(s2 + s1)\n\n s1, s2 = lst\n return 'Yes' if can_form_good_string(s1, s2) else 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n # Helper function to check if a string is good\n def is_good(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n elif char == ')':\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n # Concatenate the two strings in both orders\n str1, str2 = lst\n combined1 = str1 + str2\n combined2 = str2 + str1\n\n # Check if either of the combined strings is good\n return 'Yes' if is_good(combined1) or is_good(combined2) else 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n def check_balanced(s):\n count = 0\n for c in s:\n if c == '(':\n count += 1\n elif c == ')':\n count -= 1\n if count < 0:\n return False\n return count == 0\n\n a, b = lst\n return 'Yes' if check_balanced(a+b) or check_balanced(b+a) else 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n def count_parens(s):\n count = 0\n for char in s:\n if char == '(':\n count += 1\n elif char == ')':\n count -= 1\n if count < 0:\n return False\n return count == 0\n\n string1, string2 = lst\n return 'Yes' if count_parens(string1 + string2) or count_parens(string2 + string1) else 'No'", "matching_cluster_idx": 4}]}, "HumanEval/120": {"dps": null, "dps_norm": null, "pass@1": 4.0, "profiled": []}, "HumanEval/121": {"dps": 84.88789237668162, "dps_norm": 63.57142857142858, "pass@1": 92.0, "profiled": [{"solution": "def solution(lst):\n return sum(el for i, el in enumerate(lst) if i % 2 == 0 and el % 2 == 1)", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n return sum(lst[i] for i in range(0, len(lst), 2) if lst[i] % 2 != 0)", "matching_cluster_idx": 4}, {"solution": "def solution(lst):\n return sum(lst[i] for i in range(0, len(lst), 2) if lst[i] % 2 != 0)", "matching_cluster_idx": 4}, {"solution": "def solution(lst):\n return sum(x for i, x in enumerate(lst) if i % 2 == 0 and x % 2 != 0)", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n return sum(lst[i] for i in range(0, len(lst), 2) if lst[i] % 2 != 0)", "matching_cluster_idx": 4}, {"solution": "def solution(lst):\n return sum(lst[i] for i in range(0, len(lst), 2) if lst[i] % 2 != 0)", "matching_cluster_idx": 4}, {"solution": "def solution(lst):\n # Sum of the odd elements at even indices\n return sum(x for i, x in enumerate(lst) if i % 2 == 0 and x % 2 == 1)", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n # Initialize the sum of odd elements in even positions\n sum_of_odd = 0\n\n # Iterate over the list with the step of 2 (only even positions)\n for i in range(0, len(lst), 2):\n # Check if the element at the current even position is odd\n if lst[i] % 2 != 0:\n # Add the odd element to the sum\n sum_of_odd += lst[i]\n\n # Return the sum of odd elements in even positions\n return sum_of_odd", "matching_cluster_idx": 4}, {"solution": "def solution(lst):\n return sum(num for index, num in enumerate(lst) if index % 2 == 0 and num % 2 != 0)", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n return sum(x for i, x in enumerate(lst) if i % 2 == 0 and x % 2 != 0)", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all the odd elements that are in even positions.\n\n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n return sum(x for i, x in enumerate(lst) if i % 2 == 0 and x % 2 != 0)", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n return sum(lst[i] for i in range(0, len(lst), 2) if lst[i] % 2 != 0)", "matching_cluster_idx": 4}, {"solution": "def solution(lst):\n return sum(lst[i] for i in range(0, len(lst), 2) if lst[i] % 2 != 0)", "matching_cluster_idx": 4}, {"solution": "def solution(lst):\n return sum(lst[i] for i in range(len(lst)) if i % 2 == 0 and lst[i] % 2 != 0)", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n return sum(lst[i] for i in range(0, len(lst), 2) if lst[i] % 2 != 0)", "matching_cluster_idx": 4}, {"solution": "def solution(lst):\n return sum(x for i, x in enumerate(lst) if i % 2 == 0 and x % 2 != 0)", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all the odd elements that are in even positions.\"\"\"\n return sum(lst[i] for i in range(0, len(lst), 2) if lst[i] % 2 != 0)", "matching_cluster_idx": 4}, {"solution": "def solution(lst):\n # Initialize sum to 0\n sum = 0\n # Iterate over the list with an index and value\n for i, num in enumerate(lst):\n # Check if the index is even and the number is odd\n if i % 2 == 0 and num % 2 != 0:\n # Add the number to the sum\n sum += num\n # Return the sum\n return sum", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n return sum(x for i, x in enumerate(lst) if i % 2 == 0 and x % 2 != 0)", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\"\"\"\n return sum(x for i, x in enumerate(lst) if i % 2 == 0 and x % 2 != 0)", "matching_cluster_idx": 3}]}, "HumanEval/149": {"dps": 85.82677165354332, "dps_norm": 57.142857142857146, "pass@1": 96.0, "profiled": [{"solution": "def sorted_list_sum(lst):\n # Filter out words with odd lengths and convert them to a list of tuples with their lengths as first element\n filtered_list = [(len(word), word) for word in lst if len(word) % 2 == 0]\n # Sort the list first by length (using the first element of the tuple) and then alphabetically (using the second element)\n filtered_list.sort(key=lambda x: (x[0], x[1]))\n # Return only the words from the sorted list\n return [word for _, word in filtered_list]", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n # Filter out strings with odd lengths\n lst = [word for word in lst if len(word) % 2 == 0]\n\n # Sort by length and then alphabetically\n lst.sort(key=lambda x: (len(x), x))\n\n return lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n # Filter out the strings with odd lengths\n lst = [s for s in lst if len(s) % 2 == 0]\n # Sort the list first by length and then alphabetically\n lst.sort(key=lambda x: (len(x), x))\n return lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n # filter out strings of odd length\n lst = [s for s in lst if len(s) % 2 == 0]\n # sort by length and then alphabetically\n lst.sort(key=lambda x: (len(x), x))\n return lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n # Filter out strings of odd length\n even_len_strings = [s for s in lst if len(s) % 2 == 0]\n\n # Sort the strings by length and then alphabetically if lengths are equal\n even_len_strings.sort(key=lambda s: (len(s), s))\n\n return even_len_strings", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n # Delete the strings that have odd lengths\n lst = [word for word in lst if len(word) % 2 == 0]\n\n # Sort the list first by length and then alphabetically\n lst.sort(key=lambda x: (len(x), x))\n\n return lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n # Filter out strings with odd lengths\n lst = [s for s in lst if len(s) % 2 == 0]\n # Sort by length first, then alphabetically\n lst.sort(key=lambda x: (len(x), x))\n return lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n # Filter out strings with odd lengths\n lst = [s for s in lst if len(s) % 2 == 0]\n\n # Sort by length and alphabetically\n lst.sort(key=lambda x: (len(x), x))\n\n return lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n # Filter out strings of odd length\n lst = [s for s in lst if len(s) % 2 == 0]\n\n # Sort by length and then by alphabetical order\n lst.sort(key=lambda s: (len(s), s))\n\n return lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n lst = [word for word in lst if len(word) % 2 == 0]\n lst.sort(key=lambda word: (len(word), word))\n return lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n # Filter out strings of odd length\n lst = [s for s in lst if len(s) % 2 == 0]\n # Sort the list first by length, then alphabetically\n lst.sort(key=lambda s: (len(s), s))\n return lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n # Filter out words with odd length\n lst = [word for word in lst if len(word) % 2 == 0]\n\n # Sort the list first by word length and then by alphabetical order\n lst.sort(key=lambda x: (len(x), x))\n\n return lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n # Filter out strings with odd lengths\n lst = [s for s in lst if len(s) % 2 == 0]\n\n # Sort by length first, then alphabetically for strings of same length\n lst.sort(key=lambda s: (len(s), s))\n\n return lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n # Filter out strings with odd lengths\n lst = [s for s in lst if len(s) % 2 == 0]\n\n # Sort by length in ascending order, then alphabetically if lengths are equal\n lst.sort(key=lambda x: (len(x), x))\n\n return lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n # remove strings with odd lengths\n lst = [word for word in lst if len(word) % 2 == 0]\n\n # sort by length and then alphabetically\n lst.sort(key=lambda x: (len(x), x))\n\n return lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n # Filter out strings with odd lengths\n lst = [s for s in lst if len(s) % 2 == 0]\n\n # Sort the list first by length and then alphabetically\n lst.sort(key=lambda x: (len(x), x))\n\n return lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order,\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n You may assume that all words will have the same length.\n For example:\n assert sorted_list_sum([\"aa\", \"a\", \"aaa\"]) => [\"aa\"]\n assert sorted_list_sum([\"ab\", \"a\", \"aaa\", \"cd\"]) => [\"ab\", \"cd\"]\n \"\"\"\n\n return sorted([word for word in lst if len(word) % 2 == 0], key=lambda x: (len(x), x))", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n # Filter out strings with odd lengths and sort by length first, then alphabetically\n return sorted([word for word in lst if len(word) % 2 == 0], key=lambda x: (len(x), x))", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n # Remove strings with odd lengths\n lst = [s for s in lst if len(s) % 2 == 0]\n\n # Sort by length, then alphabetically\n lst.sort(key=lambda x: (len(x), x))\n\n return lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n # Filter out strings with odd lengths\n lst = [s for s in lst if len(s) % 2 == 0]\n\n # Sort the list based on the length of each word and alphabetically\n lst.sort(key=lambda s: (len(s), s))\n\n return lst", "matching_cluster_idx": 3}]}, "Mbpp/3": {"dps": 84.02542372881356, "dps_norm": 89.375, "pass@1": 97.0, "profiled": [{"solution": "def is_prime(n):\n if n <= 1:\n return False\n elif n <= 3:\n return True\n elif n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True\ndef is_not_prime(n):\n return not is_prime(n)", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n \"\"\"\n A function that checks if a number is not a prime number.\n \"\"\"\n # Function to check if a number is prime\n def is_prime(num):\n if num <= 1:\n return False\n if num == 2:\n return True\n if num % 2 == 0:\n return False\n max_divisor = int(num**0.5) + 1\n for d in range(3, max_divisor, 2):\n if num % d == 0:\n return False\n return True\n\n # Function to check if a number is not prime\n return not is_prime(n)", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n \"\"\"\n This function checks if a number is not prime.\n\n Args:\n n (int): The number to check.\n\n Returns:\n bool: True if the number is not prime, False otherwise.\n \"\"\"\n if n <= 1:\n return True\n elif n <= 3:\n return False\n elif n % 2 == 0 or n % 3 == 0:\n return True\n\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return True\n i += 6\n\n return False", "matching_cluster_idx": 7}, {"solution": "def is_prime(n):\n if n <= 1 or (n % 2 == 0 and n > 2):\n return False\n return all(n % i for i in range(3, int(n**0.5) + 1, 2))\ndef is_not_prime(n):\n return not is_prime(n)", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n \"\"\"\n Function to identify non-prime numbers.\n :param n: integer number to check\n :return: True if the number is not a prime, False otherwise\n \"\"\"\n if n < 2:\n return True\n for i in range(2, int(n ** 0.5) + 1):\n if n % i == 0:\n return True\n return False", "matching_cluster_idx": 5}, {"solution": "def is_prime(n):\n if n <= 1 or (n % 2 == 0 and n > 2):\n return False\n return all(n % i for i in range(3, int(n**0.5) + 1, 2))\ndef is_not_prime(n):\n return not is_prime(n)", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n \"\"\"Check if a number is not a prime number.\"\"\"\n if n <= 1:\n return True\n elif n == 2:\n return False\n else:\n for i in range(2, n):\n if n % i == 0:\n return True\n return False", "matching_cluster_idx": 0}, {"solution": "def is_prime(n):\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True\ndef is_not_prime(n):\n return not is_prime(n)", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n \"\"\"Check if a number is not prime.\"\"\"\n if n <= 1:\n return True\n elif n <= 3:\n return False\n elif n % 2 == 0 or n % 3 == 0:\n return True\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return True\n i += 6\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n \"\"\"\n Function to check if a number is not prime.\n\n Args:\n n (int): The number to check.\n\n Returns:\n bool: True if the number is not prime, False otherwise.\n \"\"\"\n if n <= 1:\n return True\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return True\n return False", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(n):\n if n <= 1:\n return True\n elif n <= 3:\n return False\n elif n % 2 == 0 or n % 3 == 0:\n return True\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return True\n i += 6\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n if n < 2:\n return True\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return True\n return False", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(n):\n \"\"\"\n Returns True if the number is not a prime number, False otherwise.\n \"\"\"\n if n <= 1:\n return True\n elif n == 2:\n return False\n elif n % 2 == 0:\n return True\n else:\n sqr = int(n**0.5) + 1\n for divisor in range(3, sqr, 2):\n if n % divisor == 0:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def is_prime(n):\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True\ndef is_not_prime(n):\n return not is_prime(n)", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n if n <= 1:\n return True\n elif n <= 3:\n return False\n elif n % 2 == 0 or n % 3 == 0:\n return True\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return True\n i += 6\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n \"\"\"\n Check if a number is not a prime number.\n\n Parameters:\n n (int): The number to check.\n\n Returns:\n bool: True if the number is not prime, False otherwise.\n \"\"\"\n if n <= 1:\n return True\n elif n == 2:\n return False\n else:\n for i in range(2, int(n ** 0.5) + 1):\n if n % i == 0:\n return True\n return False", "matching_cluster_idx": 5}, {"solution": "def is_prime(n):\n if n <= 1:\n return False\n elif n == 2:\n return True\n elif n % 2 == 0:\n return False\n for i in range(3, int(n**0.5) + 1, 2):\n if n % i == 0:\n return False\n return True\ndef is_not_prime(n):\n return not is_prime(n)", "matching_cluster_idx": 7}, {"solution": "def is_prime(n):\n if n <= 1:\n return False\n if n == 2:\n return True\n if n % 2 == 0:\n return False\n i = 3\n while i * i <= n:\n if n % i:\n i += 2\n else:\n return False\n return True\ndef is_not_prime(n):\n return not is_prime(n)", "matching_cluster_idx": 5}, {"solution": "def is_prime(n):\n \"\"\"Check if a number is prime.\"\"\"\n if n <= 1:\n return False\n elif n == 2:\n return True\n elif n % 2 == 0:\n return False\n else:\n for current in range(3, int(n**0.5) + 1, 2):\n if n % current == 0:\n return False\n return True\ndef is_not_prime(n):\n \"\"\"Check if a number is not prime.\"\"\"\n return not is_prime(n)", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n if n <= 1:\n return True\n elif n <= 3:\n return False\n elif n % 2 == 0 or n % 3 == 0:\n return True\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return True\n i += 6\n return False", "matching_cluster_idx": 7}]}, "Mbpp/4": {"dps": 89.96587030716724, "dps_norm": 90.0, "pass@1": 72.0, "profiled": [{"solution": "def heap_queue_largest(nums, n):\n return sorted(nums, reverse=True)[:n]", "matching_cluster_idx": 11}, {"solution": "def heap_queue_largest(numbers, n):\n return sorted(numbers, reverse=True)[:n]", "matching_cluster_idx": 11}, {"solution": "import heapq\ndef heap_queue_largest(numbers, n):\n # Use Python's built-in heapq module for efficient retrieval of the n largest numbers\n # The heapq.nlargest function retrieves the n largest elements from the iterable.\n return list(heapq.nlargest(n, numbers))", "matching_cluster_idx": 9}, {"solution": "def heap_queue_largest(numbers, n):\n # Sorting in descending order using list comprehension and the sorted function\n return sorted(numbers, reverse=True)[:n]", "matching_cluster_idx": 11}, {"solution": "from heapq import nlargest\ndef heap_queue_largest(numbers, n):\n return sorted(nlargest(n, numbers), reverse=True)", "matching_cluster_idx": 9}, {"solution": "def heap_queue_largest(num_list, n):\n num_list.sort(reverse=True)\n return num_list[:n]", "matching_cluster_idx": 11}, {"solution": "def heap_queue_largest(nums, k):\n nums.sort(reverse=True) # sort numbers in descending order\n return nums[:k] # return the first k numbers", "matching_cluster_idx": 11}, {"solution": "def heap_queue_largest(numbers, n):\n numbers.sort(reverse=True)\n return numbers[:n]", "matching_cluster_idx": 11}, {"solution": "from heapq import nlargest\ndef heap_queue_largest(nums, n):\n return sorted(nlargest(n, nums), reverse=True)", "matching_cluster_idx": 9}, {"solution": "def heap_queue_largest(nums, n):\n # sort the list in descending order and return the first n elements\n nums.sort(reverse=True)\n return nums[:n]", "matching_cluster_idx": 11}, {"solution": "def heap_queue_largest(nums, n):\n # Create a list of tuples, where each tuple is (number, index)\n # This is required for Python's built-in max heap sorting to work as expected\n nums_indexed = [(num, idx) for idx, num in enumerate(nums)]\n # Use Python's built-in max heap sorting to sort the list in descending order\n nums_indexed.sort(reverse=True)\n\n # Retrieve the top n numbers from the sorted list\n result = [num for num, _ in nums_indexed[:n]]\n\n return result", "matching_cluster_idx": 8}, {"solution": "from heapq import nlargest\ndef heap_queue_largest(nums, n):\n \"\"\"\n Find the n largest integers from a given list of numbers, returned in descending order.\n\n Args:\n nums (list of int): A list of integers.\n n (int): The number of largest integers to find.\n\n Returns:\n list of int: The n largest integers in descending order.\n \"\"\"\n return sorted(nlargest(n, nums), reverse=True)", "matching_cluster_idx": 9}, {"solution": "from heapq import nlargest\ndef heap_queue_largest(nums, n):\n return list(nlargest(n, nums))", "matching_cluster_idx": 9}, {"solution": "def heap_queue_largest(numbers, k):\n numbers.sort(reverse=True)\n return numbers[:k]", "matching_cluster_idx": 11}, {"solution": "from heapq import nlargest\ndef heap_queue_largest(numbers, k):\n \"\"\"\n Finds the k largest integers from a given list of numbers, returned in descending order.\n \"\"\"\n return sorted(nlargest(k, numbers), reverse=True)", "matching_cluster_idx": 9}, {"solution": "from heapq import nlargest\ndef heap_queue_largest(numbers, n):\n \"\"\"\n Find the n largest integers from a given list of numbers,\n returned in descending order.\n \"\"\"\n return sorted(nlargest(n, numbers), reverse=True)", "matching_cluster_idx": 9}, {"solution": "from heapq import nlargest\ndef heap_queue_largest(nums, n):\n return list(nlargest(n, nums))", "matching_cluster_idx": 9}, {"solution": "from heapq import nlargest\ndef heap_queue_largest(nums, n):\n return sorted(nlargest(n, nums), reverse=True)", "matching_cluster_idx": 9}, {"solution": "def heap_queue_largest(numbers, n):\n # Using Python's built-in heapq module for priority queue handling\n # We convert the list to a heap, which is a binary tree with properties that make it efficient for accessing the smallest element\n import heapq\n heap = [(-num, num) for num in numbers] # Create a list of tuples, with the first item being the negative number (for sorting purposes) and the second being the original number\n heapq.heapify(heap) # Convert the list to a heap\n\n # The n largest numbers are at the top of the heap (the smallest numbers)\n largest_nums = [num for _, num in heapq.nsmallest(n, heap)]\n return sorted(largest_nums, reverse=True) # Return sorted in descending order", "matching_cluster_idx": 8}, {"solution": "def heap_queue_largest(nums, n):\n return sorted(nums, reverse=True)[:n]", "matching_cluster_idx": 11}]}, "Mbpp/9": {"dps": null, "dps_norm": null, "pass@1": 5.0, "profiled": []}, "Mbpp/11": {"dps": 88.29749103942652, "dps_norm": 97.22222222222223, "pass@1": 24.0, "profiled": [{"solution": "def remove_Occ(string, char):\n first = string.find(char)\n if first == -1:\n return string\n\n last = string.rfind(char)\n\n return string[:first] + string[first + 1:last] + string[last + 1:]", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(string, char):\n # Find the first occurrence of the character\n first_index = string.find(char)\n\n # If the character is not found, return the original string\n if first_index == -1:\n return string\n\n # Find the last occurrence of the character\n last_index = string.rfind(char)\n\n # Remove the first and last occurrence of the character\n result = string[:first_index] + string[first_index + 1:last_index] + string[last_index + 1:]\n\n return result", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(string, char):\n # Find first occurrence index\n first_occ = string.find(char)\n if first_occ == -1:\n # If character doesn't exist in string, return original string\n return string\n\n # Remove first occurrence\n string = string[:first_occ] + string[first_occ+1:]\n\n # Find last occurrence index\n last_occ = string.rfind(char)\n if last_occ != -1:\n # Remove last occurrence\n string = string[:last_occ] + string[last_occ+1:]\n\n return string", "matching_cluster_idx": 7}, {"solution": "def remove_Occ(input_string, char_to_remove):\n # Find the first and last occurrence of the character\n first_occurrence = input_string.find(char_to_remove)\n last_occurrence = input_string.rfind(char_to_remove)\n\n # If either the first or last occurrence is not found, return the original string\n if first_occurrence == -1 or last_occurrence == -1:\n return input_string\n\n # Remove the first and last occurrence of the character from the string\n return input_string[:first_occurrence] + input_string[first_occurrence+1:last_occurrence] + input_string[last_occurrence+1:]", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(string, char):\n if char in string:\n first = string.index(char)\n last = string.rindex(char)\n return string[:first] + string[first+1:last] + string[last+1:]\n else:\n return string", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(s, c):\n # Find the first occurrence of the character\n first_occurrence = s.find(c)\n # If character is not found, return the original string\n if first_occurrence == -1:\n return s\n # Find the last occurrence of the character\n last_occurrence = s.rfind(c)\n # Return the string without the first and last occurrences\n return s[:first_occurrence] + s[first_occurrence + 1:last_occurrence] + s[last_occurrence + 1:]", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(string, char):\n if not string:\n return string\n first_occ = string.find(char)\n last_occ = string.rfind(char)\n if first_occ != -1 and last_occ != -1:\n return string[:first_occ] + string[first_occ+1:last_occ] + string[last_occ+1:]\n return string", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(text, char):\n if not char in text:\n return text\n\n first_occ = text.find(char)\n last_occ = text.rfind(char)\n\n if first_occ == last_occ:\n return text[:first_occ] + text[first_occ+1:]\n\n return text[:first_occ] + text[first_occ+1:last_occ] + text[last_occ+1:]", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(s, c):\n # If character is not in the string, return the string itself\n if c not in s:\n return s\n\n # If first and last occurrence are the same, return the string with one occurrence removed\n if s[0] == s[-1] == c:\n return s[1:-1]\n\n # Find the indices of first and last occurrence of the character\n first_index = s.find(c)\n last_index = s.rfind(c)\n\n # Remove first and last occurrence\n return s[:first_index] + s[first_index+1:last_index] + s[last_index+1:]", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(string, character):\n \"\"\"Remove first and last occurrence of a given character from a string.\"\"\"\n if character in string:\n first_occurrence = string.find(character)\n last_occurrence = string.rfind(character)\n string = string[:first_occurrence] + string[first_occurrence + 1:last_occurrence] + string[last_occurrence + 1:]\n return string", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(input_string, char_to_remove):\n if char_to_remove not in input_string:\n return input_string\n\n first_occurrence = input_string.index(char_to_remove)\n last_occurrence = input_string.rindex(char_to_remove)\n\n if first_occurrence == last_occurrence:\n # Handle case where char_to_remove appears only once\n return input_string[:first_occurrence] + input_string[first_occurrence+1:]\n else:\n return input_string[:first_occurrence] + input_string[first_occurrence+1:last_occurrence] + input_string[last_occurrence+1:]", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(s, c):\n first_occ = s.find(c)\n last_occ = s.rfind(c)\n\n if first_occ == -1 or last_occ == -1:\n return s\n\n return s[:first_occ] + s[first_occ+1:last_occ] + s[last_occ+1:]", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(s, c):\n # Find the first occurrence of the character\n first_occ = s.find(c)\n if first_occ == -1:\n # If the character is not present in the string, just return the string\n return s\n # Find the last occurrence of the character\n last_occ = s.rfind(c)\n # Remove the first and last occurrences and return the result\n return s[:first_occ] + s[first_occ+1:last_occ] + s[last_occ+1:]", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(string, char):\n # Find first and last occurrence of the character\n first_idx = string.find(char)\n last_idx = string.rfind(char)\n\n if first_idx != -1 and last_idx != -1:\n # Remove first and last occurrence\n return string[:first_idx] + string[first_idx+1:last_idx] + string[last_idx+1:]\n else:\n return string", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(string, char):\n if char not in string:\n return string\n\n first_occ = string.find(char)\n if first_occ != -1:\n string = string[:first_occ] + string[first_occ + 1:]\n\n last_occ = string.rfind(char)\n if last_occ != -1:\n string = string[:last_occ] + string[last_occ + 1:]\n\n return string", "matching_cluster_idx": 7}, {"solution": "def remove_Occ(string, char):\n \"\"\"\n Removes the first and last occurrence of a given character from a string.\n \"\"\"\n first_occurrence = string.find(char)\n last_occurrence = string.rfind(char)\n\n if first_occurrence != -1 and last_occurrence != -1:\n # remove first and last occurrence of the character\n return string[:first_occurrence] + string[first_occurrence + 1:last_occurrence] + string[last_occurrence + 1:]\n else:\n return string # if the character doesn't exist, return the string as is", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(string, char):\n \"\"\"\n Removes the first and last occurrence of a given character from the string.\n \"\"\"\n first_char_index = string.find(char)\n if first_char_index == -1: # char not found in string\n return string\n last_char_index = string.rfind(char)\n return string[:first_char_index] + string[first_char_index+1:last_char_index] + string[last_char_index+1:]", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(string, char):\n # find first occurrence of the character\n first_occ = string.find(char)\n # find last occurrence of the character\n last_occ = string.rfind(char)\n\n # remove first and last occurrences if they exist\n if first_occ != -1 and last_occ != -1:\n return string[:first_occ] + string[first_occ+1:last_occ] + string[last_occ+1:]\n else:\n return string", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(input_str, char):\n \"\"\"\n Remove first and last occurrence of a given character from the string.\n \"\"\"\n if input_str.count(char) > 1:\n index_first = input_str.index(char)\n index_last = input_str.rindex(char)\n result = input_str[:index_first] + input_str[index_first+1:index_last] + input_str[index_last+1:]\n else:\n result = input_str.replace(char, '')\n return result", "matching_cluster_idx": 5}, {"solution": "def remove_Occ(s, c):\n if c in s:\n first = s.find(c)\n last = s.rfind(c)\n return s[:first] + s[first+1:last] + s[last+1:]\n else:\n return s", "matching_cluster_idx": 8}]}, "Mbpp/12": {"dps": 65.59299191374663, "dps_norm": 96.875, "pass@1": 97.0, "profiled": [{"solution": "from typing import List\ndef sort_matrix(matrix: List[List[int]]) -> List[List[int]]:\n # Calculate the sum of each row and store in a list of tuples\n sums = [(sum(row), row) for row in matrix]\n # Sort the list of tuples based on the sum\n sums.sort()\n # Return the sorted matrix by extracting the rows from the sorted list of tuples\n return [row[1] for row in sums]", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Calculate the sum of each row and store it in a list\n row_sums = [sum(row) for row in matrix]\n # Sort the matrix rows and corresponding sums simultaneously using sorted function with a lambda function as key\n sorted_matrix = [row for _, row in sorted(zip(row_sums, matrix))]\n\n return sorted_matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Calculate sum of each row\n sums = [sum(row) for row in matrix]\n # Zip rows and their sums, sort by sum\n sorted_matrix = sorted(zip(matrix, sums), key=lambda x: x[1])\n # Unzip and return sorted matrix\n return [row for row, _ in sorted_matrix]", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Calculate the sum of each row and store it along with the row in a tuple\n matrix_with_sum = [(sum(row), row) for row in matrix]\n\n # Sort the list of tuples based on the sums\n matrix_with_sum.sort()\n\n # Separate the sorted sums and rows back into two separate lists\n sorted_sums, sorted_rows = zip(*matrix_with_sum)\n\n # Return the sorted rows\n return list(sorted_rows)", "matching_cluster_idx": 14}, {"solution": "def sort_matrix(matrix):\n # Calculate sum of each row and pair it with its index\n sums = [(sum(row), i) for i, row in enumerate(matrix)]\n\n # Sort the list of sums in ascending order\n sums.sort()\n\n # Reconstruct the sorted matrix using the sorted list of sums\n sorted_matrix = [matrix[i] for _, i in sums]\n\n return sorted_matrix", "matching_cluster_idx": 14}, {"solution": "def sort_matrix(matrix):\n # Calculate sum of each row\n sums = [sum(row) for row in matrix]\n\n # Sort rows based on their sums\n sorted_matrix = [rows for _, rows in sorted(zip(sums, matrix))]\n\n return sorted_matrix", "matching_cluster_idx": 14}, {"solution": "def sort_matrix(matrix):\n # Calculate the sum of each row and store it with the corresponding row in a list of tuples\n rows = [(sum(row), row) for row in matrix]\n\n # Sort the list of tuples by the first element (sum of the row) in ascending order\n sorted_rows = sorted(rows)\n\n # Extract the sorted rows from the sorted list of tuples and return the result\n result = [row for _, row in sorted_rows]\n\n return result", "matching_cluster_idx": 14}, {"solution": "def sort_matrix(matrix):\n # Calculate the sum of each row\n row_sums = [sum(row) for row in matrix]\n # Use zip to pair row sum with its index\n sorted_rows = sorted(zip(row_sums, matrix))\n # Use list comprehension to extract only sorted rows\n return [row for _, row in sorted_rows]", "matching_cluster_idx": 14}, {"solution": "def sort_matrix(matrix):\n return sorted(matrix, key=sum)", "matching_cluster_idx": 15}, {"solution": "from typing import List\ndef sort_matrix(matrix: List[List[int]]) -> List[List[int]]:\n # Calculate the sum of each row\n row_sums = [sum(row) for row in matrix]\n\n # Sort the rows based on their sums\n sorted_rows = [matrix[i] for i in sorted(range(len(matrix)), key=lambda x: row_sums[x])]\n\n return sorted_rows", "matching_cluster_idx": 15}, {"solution": "from typing import List\ndef sort_matrix(matrix: List[List[int]]) -> List[List[int]]:\n # Calculate the sum of each row\n row_sums = [sum(row) for row in matrix]\n # Use sorted function to sort the matrix rows based on the sum of their elements\n # In case of a tie, the row with the smallest elements comes first (due to sorted's stability)\n sorted_rows = sorted(matrix, key=sum)\n return sorted_rows", "matching_cluster_idx": 12}, {"solution": "def sort_matrix(matrix):\n return sorted(matrix, key=sum)", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n return sorted(matrix, key=sum)", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Calculate the sum of each row and pair it with its index\n sums = [(sum(row), i) for i, row in enumerate(matrix)]\n\n # Sort the rows based on the sum of their elements\n sorted_sums = sorted(sums, key=lambda x: x[0])\n\n # Reconstruct the sorted matrix\n sorted_matrix = [matrix[i] for _, i in sorted_sums]\n\n return sorted_matrix", "matching_cluster_idx": 14}, {"solution": "from typing import List\ndef sort_matrix(matrix: List[List[int]]) -> List[List[int]]:\n # Calculate the sum of each row\n row_sums = [sum(row) for row in matrix]\n\n # Sort rows based on their sum in ascending order\n sorted_rows = [matrix[i] for i in sorted(range(len(matrix)), key=lambda x: row_sums[x])]\n\n return sorted_rows", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Sort the matrix based on the sum of elements in each row in ascending order\n return sorted(matrix, key=sum)", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Calculate sum of rows and create a list of tuples with each tuple having row sum and its index\n row_sums = [(sum(row), i) for i, row in enumerate(matrix)]\n\n # Sort the list of tuples based on row sums\n row_sums.sort()\n\n # Construct the sorted matrix using sorted row indices\n sorted_matrix = [matrix[i] for _, i in row_sums]\n\n return sorted_matrix", "matching_cluster_idx": 14}, {"solution": "def sort_matrix(matrix):\n # Compute sum of each row\n row_sums = [sum(row) for row in matrix]\n\n # Sort the matrix rows based on the sum\n sorted_matrix = [matrix[i] for i in sorted(range(len(matrix)), key=lambda x: row_sums[x])]\n\n return sorted_matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Calculate the sum of each row\n row_sums = [sum(row) for row in matrix]\n # Use a list comprehension to sort the matrix based on the row sums\n sorted_matrix = [matrix[i] for i in sorted(range(len(matrix)), key=lambda i: row_sums[i])]\n return sorted_matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Calculate sum for each row and store in a tuple with the row index\n row_sums = [(i, sum(row)) for i, row in enumerate(matrix)]\n\n # Sort the tuples by the sum values in ascending order\n sorted_row_sums = sorted(row_sums, key=lambda x: x[1])\n\n # Use the sorted indices to reorder the rows in the matrix\n sorted_matrix = [matrix[i[0]] for i in sorted_row_sums]\n\n return sorted_matrix", "matching_cluster_idx": 15}]}, "Mbpp/16": {"dps": 90.48780487804878, "dps_norm": 96.25, "pass@1": 31.0, "profiled": [{"solution": "import re\ndef text_lowercase_underscore(input_string):\n pattern = r\"^[a-z]+(_[a-z]+)*$\"\n return bool(re.match(pattern, input_string))", "matching_cluster_idx": 6}, {"solution": "import re\ndef text_lowercase_underscore(s: str) -> bool:\n return bool(re.match(\"^[a-z]+(_[a-z]+)*$\", s))", "matching_cluster_idx": 6}, {"solution": "import re\ndef text_lowercase_underscore(text):\n # Check if the string matches the required pattern using a regular expression\n return bool(re.fullmatch(\"^[a-z]+(_[a-z]+)*$\", text))", "matching_cluster_idx": 7}, {"solution": "import re\ndef text_lowercase_underscore(text):\n return bool(re.match(r'^([a-z]+_)*[a-z]+$', text))", "matching_cluster_idx": 7}, {"solution": "import re\ndef text_lowercase_underscore(s: str) -> bool:\n \"\"\"\n Returns True if the input string contains sequences of lowercase letters joined with an underscore, False otherwise.\n \"\"\"\n return bool(re.match(\"^[a-z]+(_[a-z]+)*$\", s))", "matching_cluster_idx": 6}, {"solution": "import re\ndef text_lowercase_underscore(s: str) -> bool:\n pattern = r\"^[a-z]+(_[a-z]+)*$\"\n return bool(re.match(pattern, s))", "matching_cluster_idx": 7}, {"solution": "import re\ndef text_lowercase_underscore(s: str) -> bool:\n # Check if the string matches the required pattern: lowercase letters joined with an underscore\n return bool(re.match(r\"^[a-z]+(_[a-z]+)*$\", s))", "matching_cluster_idx": 7}, {"solution": "import re\ndef text_lowercase_underscore(text):\n pattern = r'^[a-z]+(_[a-z]+)*$'\n return bool(re.match(pattern, text))", "matching_cluster_idx": 7}, {"solution": "import re\ndef text_lowercase_underscore(s):\n # Regular expression pattern to match sequences of lowercase letters joined with an underscore\n pattern = r'^([a-z]+_)*[a-z]+$'\n if re.match(pattern, s):\n return True\n else:\n return False", "matching_cluster_idx": 7}, {"solution": "import re\ndef text_lowercase_underscore(text: str) -> bool:\n return bool(re.match(\"^[a-z]+(_[a-z]+)*$\", text))", "matching_cluster_idx": 7}, {"solution": "import re\ndef text_lowercase_underscore(s):\n \"\"\"\n This function returns True if the input string contains sequences of lowercase letters joined with an underscore,\n and False otherwise.\n \"\"\"\n return re.match('^[a-z]+(_[a-z]+)*$', s) is not None", "matching_cluster_idx": 7}, {"solution": "import re\ndef text_lowercase_underscore(s: str) -> bool:\n return bool(re.match('^[a-z]+(_[a-z]+)*$', s))", "matching_cluster_idx": 7}, {"solution": "import re\ndef text_lowercase_underscore(text):\n \"\"\"Returns True if the input string contains sequences of lowercase letters joined with an underscore, False otherwise\"\"\"\n # Use regular expression to check if the text matches the pattern of lowercase letters and underscores\n pattern = r'^[a-z]+(_[a-z]+)*$'\n return bool(re.match(pattern, text))", "matching_cluster_idx": 7}, {"solution": "import re\ndef text_lowercase_underscore(s):\n \"\"\"Returns True if the input string contains sequences of lowercase letters joined with an underscore, False otherwise.\"\"\"\n return bool(re.fullmatch(r'^[a-z]+(_[a-z]+)*$', s))", "matching_cluster_idx": 6}, {"solution": "import re\ndef text_lowercase_underscore(s):\n # Regular expression to match lowercase letters separated by underscores\n pattern = r'^[a-z]+(_[a-z]+)*$'\n # Return True if the string matches the pattern, False otherwise\n return bool(re.match(pattern, s))", "matching_cluster_idx": 6}, {"solution": "import re\ndef text_lowercase_underscore(input_string):\n pattern = \"^[a-z]+(_[a-z]+)*$\"\n if re.match(pattern, input_string):\n return True\n else:\n return False", "matching_cluster_idx": 7}, {"solution": "import re\ndef text_lowercase_underscore(s: str) -> bool:\n \"\"\"\n Returns True if the input string contains sequences of lowercase letters joined with an underscore.\n Returns False otherwise.\n \"\"\"\n # Check if the string matches the regex pattern of lowercase letters and underscores only\n return re.match('^[a-z]+(?:_[a-z]+)*$', s) is not None", "matching_cluster_idx": 7}, {"solution": "import re\ndef text_lowercase_underscore(s: str) -> bool:\n \"\"\"\n Check if the input string contains sequences of lowercase letters joined with an underscore.\n \"\"\"\n return re.match('^[a-z0-9]+(_[a-z0-9]+)*$', s) is not None", "matching_cluster_idx": 6}, {"solution": "import re\ndef text_lowercase_underscore(text):\n pattern = r'^[a-z]+(_[a-z]+)*$'\n return bool(re.match(pattern, text))", "matching_cluster_idx": 7}, {"solution": "import re\ndef text_lowercase_underscore(s: str) -> bool:\n \"\"\"\n Checks if the input string contains sequences of lowercase letters joined with an underscore.\n\n Args:\n s (str): The input string.\n\n Returns:\n bool: True if the string meets the criteria, False otherwise.\n \"\"\"\n return bool(re.fullmatch(r'[a-z]+(_[a-z]+)*', s))", "matching_cluster_idx": 7}]}, "Mbpp/19": {"dps": 66.41414141414141, "dps_norm": 81.0, "pass@1": 54.0, "profiled": [{"solution": "def test_duplicate(arr):\n return len(arr) != len(set(arr))", "matching_cluster_idx": 11}, {"solution": "def has_duplicate(nums):\n \"\"\"\n Check if a given list of integers contains any duplicate element.\n :param nums: List of integers\n :return: True if the list contains any duplicate element, else False.\n \"\"\"\n return len(nums) != len(set(nums))\ndef test_duplicate(nums):\n return has_duplicate(nums)", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(arr):\n \"\"\"\n This function tests whether a given array of integers contains any duplicate element.\n :param arr: List of integers\n :return: True if a duplicate is found, False otherwise\n \"\"\"\n return len(arr) != len(set(arr))", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(nums):\n \"\"\"\n Function to check if a list contains any duplicate element.\n \"\"\"\n seen = set() # This set will keep track of elements we've already seen.\n for num in nums:\n if num in seen: # If the number is in the set, it's a duplicate.\n return True\n seen.add(num) # Otherwise, add the number to the set.\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(arr):\n return len(arr) != len(set(arr))", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(arr):\n return len(arr) != len(set(arr))", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(arr):\n \"\"\"Check if a list contains duplicate elements.\"\"\"\n return len(arr) != len(set(arr))", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(arr):\n \"\"\"\n Returns True if the given list contains any duplicate element, False otherwise.\n \"\"\"\n return len(arr) != len(set(arr))", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(arr):\n \"\"\"\n This function checks if a given list contains any duplicate elements.\n\n Parameters:\n arr (list): A list of integers.\n\n Returns:\n bool: True if the list contains any duplicate, False otherwise.\n \"\"\"\n return len(arr) != len(set(arr))", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(arr):\n \"\"\"\n This function checks if an array contains any duplicate element.\n \"\"\"\n return len(arr) != len(set(arr))", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(arr):\n return len(arr) != len(set(arr))", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(arr):\n return len(set(arr)) != len(arr)", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(arr):\n return len(arr) != len(set(arr))", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(arr):\n return len(arr) != len(set(arr))", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(arr):\n \"\"\"\n This function takes an array of integers as input and returns True if it contains any duplicate element, False otherwise.\n \"\"\"\n return len(arr) != len(set(arr))", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(arr):\n return len(arr) != len(set(arr))", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(arr):\n \"\"\"\n Function to find whether a given array of integers contains any duplicate element.\n :param arr: list of integers\n :return: bool\n \"\"\"\n if len(arr) == len(set(arr)):\n return False\n return True", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(arr):\n \"\"\"\n Function to find whether a given array of integers contains any duplicate element.\n \"\"\"\n return len(arr) != len(set(arr))", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(arr):\n \"\"\"\n This function checks whether a given array contains any duplicate element.\n \"\"\"\n return len(arr) != len(set(arr))", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(arr):\n # Return False if the length of the set is equal to the length of the list, else return True\n return len(set(arr)) != len(arr)", "matching_cluster_idx": 11}]}, "Mbpp/62": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def smallest_num(nums):\n return min(nums)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(nums):\n \"\"\"\n Returns the smallest number in the given list.\n \"\"\"\n if not nums:\n return None\n return min(nums)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(lst):\n \"\"\"\n Finds the smallest number in a given list.\n\n Args:\n lst (list): Input list of integers.\n\n Returns:\n int: The smallest number in the list.\n \"\"\"\n return min(lst)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(lst):\n if not lst:\n raise ValueError(\"List is empty\")\n return min(lst)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(nums):\n \"\"\"\n A function that returns the smallest number in a list.\n\n Args:\n nums (list): A list of integers.\n\n Returns:\n int: The smallest number in the list.\n \"\"\"\n return min(nums)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(numbers):\n \"\"\"Find smallest number in a list.\"\"\"\n if not numbers:\n raise ValueError(\"The list should not be empty\")\n return min(numbers)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(lst):\n return min(lst)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(numbers):\n if not numbers:\n raise ValueError(\"List cannot be empty\")\n return min(numbers)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(numbers):\n return min(numbers)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(nums):\n return min(nums)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(numbers):\n return min(numbers)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(lst):\n # Check if list is empty\n if not lst:\n raise ValueError(\"List is empty\")\n # Return the smallest number in the list\n return min(lst)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(lst):\n \"\"\"\n Function to find the smallest number in a given list.\n\n Args:\n lst (List[int]): List of integers.\n\n Returns:\n int: The smallest number in the list.\n \"\"\"\n return min(lst)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(lst):\n \"\"\"\n Function to find the smallest number in a list.\n \"\"\"\n if not lst: # Check if list is empty\n return None\n return min(lst)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(nums):\n \"\"\"\n Returns the smallest number in a given list.\n \"\"\"\n return min(nums)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(lst):\n \"\"\"\n Function to find the smallest number in a list.\n \"\"\"\n return min(lst)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(num_list):\n return min(num_list)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(lst):\n return min(lst)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(numbers):\n \"\"\"\n Function to find smallest number in a list.\n\n Args:\n numbers (list): List of numbers\n\n Returns:\n int: Smallest number in the list\n \"\"\"\n return min(numbers)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(lst):\n if not lst:\n raise ValueError(\"List is empty.\")\n return min(lst)", "matching_cluster_idx": 4}]}, "Mbpp/75": {"dps": 92.85714285714286, "dps_norm": 66.66666666666667, "pass@1": 93.0, "profiled": [{"solution": "def find_tuples(tuples_list, k):\n return [t for t in tuples_list if all(x % k == 0 for x in t)]", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n \"\"\"\n Finds tuples which have all elements divisible by k from the given list of tuples.\n\n Args:\n tuples_list (List[Tuple[int, ...]]): A list of tuples to search in.\n k (int): The number to check for divisibility.\n\n Returns:\n List[Tuple[int, ...]]: A list of tuples that have all elements divisible by k.\n \"\"\"\n return [t for t in tuples_list if all(x % k == 0 for x in t)]", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n return [t for t in tuples_list if all(x % k == 0 for x in t)]", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n return [t for t in tuples_list if all(x % k == 0 for x in t)]", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n return [t for t in tuples_list if all(x % k == 0 for x in t)]", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples, k):\n return [t for t in tuples if all(x % k == 0 for x in t)]", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n \"\"\"\n This function finds tuples which have all elements divisible by k from the given list of tuples.\n \"\"\"\n result = []\n for t in tuples_list:\n if all(x % k == 0 for x in t):\n result.append(t)\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n \"\"\"\n Return a list of tuples where all elements are divisible by k.\n \"\"\"\n return [tup for tup in tuples_list if all(elem % k == 0 for elem in tup)]", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n \"\"\"\n Find tuples which have all elements divisible by k from the given list of tuples.\n\n Args:\n tuples_list (list): list of tuples.\n k (int): divisor.\n\n Returns:\n list: tuples in which all elements are divisible by k.\n \"\"\"\n return [t for t in tuples_list if all(i % k == 0 for i in t)]", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n \"\"\"\n Returns a list of tuples where all elements are divisible by k.\n \"\"\"\n return [t for t in tuples_list if all(x % k == 0 for x in t)]", "matching_cluster_idx": 5}, {"solution": "def find_tuples(lst, k):\n return [t for t in lst if all(n % k == 0 for n in t)]", "matching_cluster_idx": 5}, {"solution": "def find_tuples(lst, k):\n result = []\n for tpl in lst:\n if all(num % k == 0 for num in tpl):\n result.append(tpl)\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n return [t for t in tuples_list if all(x % k == 0 for x in t)]", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples, k):\n \"\"\"\n This function finds tuples from the given list of tuples where all elements are divisible by k.\n :param tuples: List of tuples\n :param k: Divisor\n :return: List of tuples that meet the criteria\n \"\"\"\n return [t for t in tuples if all(x % k == 0 for x in t)]", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples, k):\n result = []\n for t in tuples:\n if all(x % k == 0 for x in t):\n result.append(t)\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n return [t for t in tuples_list if all(x % k == 0 for x in t)]", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n \"\"\"\n This function takes a list of tuples and a number as input and returns a list of tuples\n whose all elements are divisible by the input number.\n \"\"\"\n result = []\n for t in tuples_list:\n if all(x % k == 0 for x in t):\n result.append(t)\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n return [t for t in tuples_list if all(x % k == 0 for x in t)]", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n result = []\n for t in tuples_list:\n if all(el % k == 0 for el in t):\n result.append(t)\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(lst, k):\n result = []\n for t in lst:\n if all(x % k == 0 for x in t):\n result.append(t)\n return result", "matching_cluster_idx": 5}]}, "Mbpp/88": {"dps": 32.15686274509804, "dps_norm": 44.285714285714285, "pass@1": 100.0, "profiled": [{"solution": "def freq_count(lst):\n return {i: lst.count(i) for i in lst}", "matching_cluster_idx": 0}, {"solution": "def freq_count(lst):\n return {i: lst.count(i) for i in set(lst)}", "matching_cluster_idx": 2}, {"solution": "def freq_count(lst):\n freq_dict = {}\n for num in lst:\n if num in freq_dict:\n freq_dict[num] += 1\n else:\n freq_dict[num] = 1\n return freq_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(numbers):\n count_dict = {}\n for num in numbers:\n if num in count_dict:\n count_dict[num] += 1\n else:\n count_dict[num] = 1\n return count_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n freq_dict = {}\n for i in lst:\n if i in freq_dict:\n freq_dict[i] += 1\n else:\n freq_dict[i] = 1\n return freq_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n return {i: lst.count(i) for i in lst}", "matching_cluster_idx": 0}, {"solution": "def freq_count(lst):\n return {i: lst.count(i) for i in set(lst)}", "matching_cluster_idx": 2}, {"solution": "def freq_count(lst):\n return {i: lst.count(i) for i in lst}", "matching_cluster_idx": 0}, {"solution": "def freq_count(lst):\n return {item: lst.count(item) for item in lst}", "matching_cluster_idx": 0}, {"solution": "def freq_count(lst):\n return {x: lst.count(x) for x in set(lst)}", "matching_cluster_idx": 2}, {"solution": "def freq_count(lst):\n return {i: lst.count(i) for i in set(lst)}", "matching_cluster_idx": 2}, {"solution": "def freq_count(lst):\n return {i: lst.count(i) for i in set(lst)}", "matching_cluster_idx": 2}, {"solution": "from collections import Counter\ndef freq_count(lst):\n return dict(Counter(lst))", "matching_cluster_idx": 6}, {"solution": "def freq_count(lst):\n return {element: lst.count(element) for element in set(lst)}", "matching_cluster_idx": 2}, {"solution": "def freq_count(lst):\n frequency = {}\n for element in lst:\n if element in frequency:\n frequency[element] += 1\n else:\n frequency[element] = 1\n return frequency", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n return {i: lst.count(i) for i in lst}", "matching_cluster_idx": 0}, {"solution": "def freq_count(lst):\n return {i: lst.count(i) for i in lst}", "matching_cluster_idx": 0}, {"solution": "def freq_count(lst):\n return {i: lst.count(i) for i in set(lst)}", "matching_cluster_idx": 2}, {"solution": "def freq_count(lst):\n return {i: lst.count(i) for i in set(lst)}", "matching_cluster_idx": 2}, {"solution": "def freq_count(lst):\n return {i: lst.count(i) for i in lst}", "matching_cluster_idx": 0}]}, "Mbpp/90": {"dps": 72.02439024390245, "dps_norm": 82.14285714285714, "pass@1": 89.0, "profiled": [{"solution": "def len_log(words):\n # Initialize longest_word to store the length of the longest word\n longest_word = 0\n\n # Iterate over each word in the list\n for word in words:\n # If the length of the current word is greater than longest_word,\n # update longest_word\n if len(word) > longest_word:\n longest_word = len(word)\n\n # Return the length of the longest word\n return longest_word", "matching_cluster_idx": 5}, {"solution": "def len_log(word_list):\n # Initialize maximum length with 0\n max_len = 0\n for word in word_list:\n # Update max_len if current word's length is greater\n max_len = max(max_len, len(word))\n return max_len", "matching_cluster_idx": 3}, {"solution": "def len_log(words):\n \"\"\"\n This function finds the length of the longest word.\n \"\"\"\n return max(len(word) for word in words)", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n \"\"\"Return the length of the longest word in the list.\"\"\"\n return max(len(word) for word in words)", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n \"\"\"\n A function to find the length of the longest word in a given list.\n\n Args:\n words (list of str): A list of words.\n\n Returns:\n int: The length of the longest word.\n \"\"\"\n return max(len(word) for word in words)", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n # Return the length of the longest word in the list\n return max(len(word) for word in words)", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n \"\"\"\n Function to find the length of the longest word.\n Args:\n words (list of str): List of words to find longest word from.\n Returns:\n int: Length of the longest word.\n \"\"\"\n return max(len(word) for word in words)", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n return max(len(word) for word in words)", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n \"\"\"Find the length of the longest word in a list of words.\"\"\"\n return max(len(word) for word in words)", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n return max(len(word) for word in words)", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n return max(len(word) for word in words)", "matching_cluster_idx": 5}, {"solution": "def len_log(words_list):\n \"\"\"Find the length of the longest word in a list of words\"\"\"\n return max(len(word) for word in words_list)", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n return max(len(word) for word in words)", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n \"\"\"Return the length of the longest word in a list.\"\"\"\n return max(len(word) for word in words)", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n return max(len(word) for word in words)", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n # Return the length of the longest word in the list\n return max(len(word) for word in words)", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n # Initialize the longest length to 0\n longest_length = 0\n\n # Iterate over each word in the list\n for word in words:\n # Update the longest length if the current word's length is greater\n longest_length = max(longest_length, len(word))\n\n # Return the longest length\n return longest_length", "matching_cluster_idx": 2}, {"solution": "def len_log(word_list):\n return max(len(word) for word in word_list)", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n return max(len(word) for word in words)", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n return max(len(word) for word in words)", "matching_cluster_idx": 5}]}, "Mbpp/94": {"dps": 75.2591463414634, "dps_norm": 60.0, "pass@1": 83.0, "profiled": [{"solution": "def index_minimum(tuples_list):\n \"\"\"\n Returns the first value of the tuple with the smallest second value.\n\n :param tuples_list: List of tuples with each tuple having 2 elements.\n :return: First value of the tuple with smallest second value.\n \"\"\"\n if not tuples_list:\n return None\n\n min_tuple = min(tuples_list, key=lambda x: x[1])\n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(lst):\n if not lst:\n return None\n return min(lst, key=lambda x: x[1])[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(lst):\n # Check if list is empty\n if not lst:\n return None\n\n # Assume the first tuple has the smallest second value\n min_tuple = lst[0]\n min_second_value = min_tuple[1]\n\n # Check the rest of the list\n for t in lst:\n if t[1] < min_second_value:\n min_tuple = t\n min_second_value = t[1]\n\n # Return the first value of the tuple with the smallest second value\n return min_tuple[0]", "matching_cluster_idx": 4}, {"solution": "def index_minimum(lst):\n # Check if list is not empty\n if lst:\n # Find the tuple with the smallest second value\n smallest_tuple = min(lst, key=lambda x: x[1])\n # Return the first value of that tuple\n return smallest_tuple[0]\n else:\n return None", "matching_cluster_idx": 2}, {"solution": "def index_minimum(tuples):\n if not tuples:\n return None\n min_tuple = min(tuples, key=lambda x: x[1])\n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(tuples_list):\n # Return the first value of the tuple with the smallest second value\n return min(tuples_list, key=lambda x: x[1])[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(lst):\n return min(lst, key=lambda x: x[1])[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(tuples_list):\n min_tuple = min(tuples_list, key=lambda x: x[1])\n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(lst):\n # Use min() with a custom key function to find the tuple with the smallest second value\n smallest_tuple = min(lst, key=lambda x: x[1])\n # Return the first value of the smallest tuple\n return smallest_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(lst):\n return next(t[0] for t in lst if t[1] == min(t[1] for t in lst))", "matching_cluster_idx": 0}, {"solution": "def index_minimum(lst):\n # Find the tuple with the minimum second value\n minimum_tuple = min(lst, key=lambda x: x[1])\n # Return the first value of the tuple\n return minimum_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(tuples_list):\n # Check if list is empty\n if not tuples_list:\n raise ValueError(\"List should not be empty\")\n\n # Find the tuple with the minimum second value\n min_tuple = min(tuples_list, key=lambda x: x[1])\n\n # Return the first value of the tuple\n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(lst):\n if not lst:\n return None\n\n # Using built-in min function to find the tuple with smallest second value\n smallest_tuple = min(lst, key=lambda x: x[1])\n\n # Returning the first value (name) of the tuple\n return smallest_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(lst):\n \"\"\"Return the first value of the tuple with the smallest second value.\"\"\"\n if not lst:\n return None\n return min(lst, key=lambda x: x[1])[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(tuples_list):\n \"\"\"\n Return the first value of the tuple with the smallest second value.\n \"\"\"\n # Using the built-in min function to find the tuple with the smallest second value\n # Then, unpack the tuple to get the first value\n return min(tuples_list, key=lambda x: x[1])[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(tuples_list):\n \"\"\"\n Returns the first value of the tuple with the smallest second value.\n :param tuples_list: list of tuples, each containing a name (str) and a score (int)\n :return: str, the name of the person with the smallest score\n \"\"\"\n if not tuples_list:\n raise ValueError(\"Input list cannot be empty\")\n\n return min(tuples_list, key=lambda x: x[1])[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(tuples_list):\n # Use built-in min function to find tuple with smallest second value\n min_tuple = min(tuples_list, key=lambda x: x[1])\n # Return first value of found tuple\n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(lst):\n # Initialize the minimum tuple and its index\n min_tuple = lst[0]\n min_index = 0\n\n # Loop through the list\n for i, tup in enumerate(lst):\n # If the second value of the current tuple is smaller than the previous minimum\n if tup[1] < min_tuple[1]:\n # Update the minimum tuple and its index\n min_tuple = tup\n min_index = i\n\n # Return the first value of the minimum tuple\n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(tuples_list):\n if not tuples_list:\n return None\n return min(tuples_list, key=lambda x: x[1])[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(lst):\n \"\"\"\n This function takes a list of tuples and returns the first element of the tuple\n with the smallest second element.\n \"\"\"\n if not lst:\n return None\n\n # Sort the list based on the second element of each tuple\n lst.sort(key=lambda x: x[1])\n\n # Return the first element of the first tuple (smallest second element)\n return lst[0][0]", "matching_cluster_idx": 2}]}, "Mbpp/96": {"dps": 52.56944444444444, "dps_norm": 46.42857142857143, "pass@1": 66.0, "profiled": [{"solution": "def divisor(n):\n count = 0\n for i in range(1, n+1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n # Base case: 1 has only one divisor (1)\n if n == 1:\n return 1\n # Initialize count of divisors\n count = 2\n # Check for all numbers from 2 to n//2\n for i in range(2, n//2 + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def divisor(n):\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def divisor(n):\n # Check if the input is an integer\n assert isinstance(n, int), \"Input must be an integer\"\n # Check if the input is a positive number\n assert n > 0, \"Input must be a positive number\"\n # Initialize the count of divisors to 0\n count = 0\n # Start with 1 as the first potential divisor\n i = 1\n while i * i <= n:\n # If i is a divisor, increment the count\n if n % i == 0:\n count += 1\n # If i is not the square root of n (i.e., i != n // i), increment the count again for the other divisor\n if i != n // i:\n count += 1\n # Move to the next potential divisor\n i += 1\n # Return the count of divisors\n return count", "matching_cluster_idx": 4}, {"solution": "def divisor(n):\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def divisor(n):\n \"\"\"Return the number of divisors of a given integer.\"\"\"\n count = 0\n for i in range(1, n+1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n # Initialize divisor count to 0\n count = 0\n\n # Iterate over all numbers from 1 to n\n for i in range(1, n+1):\n # Check if n is divisible by i\n if n % i == 0:\n count += 1\n\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n # Initialize count of divisors\n count = 0\n # Iterate from 1 to n\n for i in range(1, n+1):\n # If n is divisible by i, increment count\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def divisor(n):\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def divisor(n):\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def divisor(n):\n count = 0\n for i in range(1, n+1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n # Initialize the divisor count\n count = 0\n\n # If n is 1, it has only one divisor\n if n == 1:\n return 1\n\n # Check divisors from 1 to n//2 and n\n for i in range(1, n // 2 + 1):\n if n % i == 0:\n count += 1\n\n # Add the divisor n to the count\n count += 1\n\n return count", "matching_cluster_idx": 3}, {"solution": "def divisor(n):\n # Initialize divisor count\n count = 0\n\n # Loop through numbers from 1 to n\n for i in range(1, n + 1):\n # If n is divisible by i, increment count\n if n % i == 0:\n count += 1\n\n # Return the count\n return count", "matching_cluster_idx": 1}, {"solution": "def divisor(n):\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def divisor(n):\n return len([i for i in range(1, n+1) if n % i == 0])", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def divisor(n):\n # If the number is negative, convert it to positive\n n = abs(n)\n\n # If the number is 1, it has exactly one divisor, which is 1 itself\n if n == 1:\n return 1\n\n # Initialize the count of divisors to 2 (1 and the number itself)\n count = 2\n\n # Check for divisors up to the square root of the number\n # because a larger factor of the number would be a multiple of smaller factor that has already been checked\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n # If i is a divisor, increment the count by 2 (i and n/i)\n # unless i is the square root of n, in which case n/i is the same as i and we only increment by 1\n count += 2 if i != n // i else 1\n\n return count", "matching_cluster_idx": 6}, {"solution": "def divisor(n):\n \"\"\"\n Returns the number of divisors of a given integer.\n\n :param n: An integer.\n :return: The number of divisors of n.\n \"\"\"\n count = 0\n for i in range(1, n+1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n # If the number is negative, convert it to positive\n if n < 0:\n n = -n\n\n count = 0\n\n # Loop through all numbers up to the square root of n\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n # Increment the count for each divisor\n count += 1\n # If the divisor is not a square root, increment the count for the quotient\n if i != n // i:\n count += 1\n\n return count", "matching_cluster_idx": 6}]}, "Mbpp/97": {"dps": 86.17094017094017, "dps_norm": 80.0, "pass@1": 83.0, "profiled": [{"solution": "from collections import defaultdict\ndef frequency_lists(lst_of_lsts):\n freq_dict = defaultdict(int)\n for lst in lst_of_lsts:\n for element in lst:\n freq_dict[element] += 1\n return freq_dict", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(nested_list):\n flattened_list = [item for sublist in nested_list for item in sublist]\n return {i: flattened_list.count(i) for i in set(flattened_list)}", "matching_cluster_idx": 2}, {"solution": "from collections import Counter\ndef frequency_lists(lists_of_lists):\n # Flatten the list of lists\n flat_list = [item for sublist in lists_of_lists for item in sublist]\n\n # Count the frequency of each element using Counter\n frequency_dict = Counter(flat_list)\n\n return dict(frequency_dict)", "matching_cluster_idx": 6}, {"solution": "from collections import defaultdict\ndef frequency_lists(nested_list):\n # Use defaultdict to count frequencies\n frequency = defaultdict(int)\n for sublist in nested_list:\n for item in sublist:\n frequency[item] += 1\n return dict(frequency)", "matching_cluster_idx": 6}, {"solution": "from collections import Counter\ndef frequency_lists(lst_of_lsts):\n # flatten the list of lists\n flattened = [item for sublist in lst_of_lsts for item in sublist]\n # count the frequency of each item\n return dict(Counter(flattened))", "matching_cluster_idx": 6}, {"solution": "from collections import Counter\ndef frequency_lists(lst_of_lists):\n \"\"\"\n A function that takes a list of lists as input\n and returns a dictionary with the frequency of each element\n \"\"\"\n # Flatten the list of lists\n flattened_list = [item for sublist in lst_of_lists for item in sublist]\n\n # Use Counter to count the frequency of each element\n freq_dict = dict(Counter(flattened_list))\n\n return freq_dict", "matching_cluster_idx": 6}, {"solution": "from collections import Counter\ndef frequency_lists(nested_list):\n # Flatten the list of lists and count the frequencies\n return dict(Counter([item for sublist in nested_list for item in sublist]))", "matching_cluster_idx": 6}, {"solution": "from collections import Counter\ndef frequency_lists(nested_list):\n # Flatten the list\n flat_list = [item for sublist in nested_list for item in sublist]\n\n # Count the frequency of each element\n frequency = Counter(flat_list)\n\n return frequency", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lst):\n # flatten the list of lists\n flat_list = [num for sublist in lst for num in sublist]\n\n # initialize an empty dictionary\n freq_dict = {}\n\n # calculate the frequency of each element\n for num in flat_list:\n if num in freq_dict:\n freq_dict[num] += 1\n else:\n freq_dict[num] = 1\n\n return freq_dict", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lst_of_lsts):\n frequency = {}\n flat_list = [item for sublist in lst_of_lsts for item in sublist]\n for item in flat_list:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n return frequency", "matching_cluster_idx": 6}, {"solution": "from collections import defaultdict\ndef frequency_lists(lists):\n frequency = defaultdict(int)\n for sublist in lists:\n for item in sublist:\n frequency[item] += 1\n return dict(frequency)", "matching_cluster_idx": 6}, {"solution": "from collections import defaultdict\ndef flatten_list(lst):\n return [item for sublist in lst for item in sublist]\ndef frequency_lists(lst_of_lists):\n flattened_list = flatten_list(lst_of_lists)\n frequency = defaultdict(int)\n for item in flattened_list:\n frequency[item] += 1\n return dict(frequency)", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lst_of_lists):\n freq_dict = {}\n flattened_list = [item for sublist in lst_of_lists for item in sublist]\n\n for num in flattened_list:\n if num in freq_dict:\n freq_dict[num] += 1\n else:\n freq_dict[num] = 1\n\n return freq_dict", "matching_cluster_idx": 6}, {"solution": "from collections import Counter\ndef frequency_lists(lst_of_lsts):\n # Flatten the list of lists\n flattened = [item for sublist in lst_of_lsts for item in sublist]\n\n # Count the frequency of each element\n return dict(Counter(flattened))", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(nested_list):\n frequency_dict = {}\n flattened_list = [item for sublist in nested_list for item in sublist]\n for item in flattened_list:\n if item in frequency_dict:\n frequency_dict[item] += 1\n else:\n frequency_dict[item] = 1\n return frequency_dict", "matching_cluster_idx": 6}, {"solution": "from collections import Counter\ndef frequency_lists(nested_list):\n # Flatten the nested list\n flat_list = [item for sublist in nested_list for item in sublist]\n\n # Count the frequency of each element\n frequency_dict = dict(Counter(flat_list))\n\n return frequency_dict", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lists):\n # Initialize a dictionary to store frequencies\n frequency_dict = {}\n\n # Flatten the list of lists\n flattened_list = [item for sublist in lists for item in sublist]\n\n # Iterate over each item in the flattened list and update its frequency in the dictionary\n for item in flattened_list:\n if item in frequency_dict:\n frequency_dict[item] += 1\n else:\n frequency_dict[item] = 1\n\n return frequency_dict", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(nested_list):\n # Flatten the list using list comprehension\n flat_list = [item for sublist in nested_list for item in sublist]\n\n # Count the frequency of each element\n frequency = {item: flat_list.count(item) for item in set(flat_list)}\n\n return frequency", "matching_cluster_idx": 2}, {"solution": "def frequency_lists(li):\n flat_list = [item for sublist in li for item in sublist]\n frequency_dict = {}\n for item in flat_list:\n if item in frequency_dict:\n frequency_dict[item] += 1\n else:\n frequency_dict[item] = 1\n return frequency_dict", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lst):\n # Flatten the list of lists\n flat_list = [item for sublist in lst for item in sublist]\n\n # Use a dictionary comprehension to count the frequencies\n frequencies = {item: flat_list.count(item) for item in set(flat_list)}\n\n return frequencies", "matching_cluster_idx": 2}]}, "Mbpp/106": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 86.0, "profiled": [{"solution": "def add_lists(lst, tup):\n \"\"\"\n Append a list to a tuple and return the result.\n \"\"\"\n # The + operator can concatenate tuples and lists, and also lists and lists\n return tup + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(list_to_add, tuple_to_extend):\n return tuple_to_extend + tuple(list_to_add)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tup):\n \"\"\"\n Function that appends a given list to a given tuple\n \"\"\"\n return tup + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tup):\n \"\"\"Append the given list to the given tuple and return the result as a new tuple.\"\"\"\n return tup + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tup):\n return tup + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tpl):\n return tpl + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tup):\n return tup + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tpl):\n return tpl + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tpl):\n return tpl + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tpl):\n return tpl + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tup):\n # Convert the list to a tuple\n lst = tuple(lst)\n # Concatenate the tuple and the list\n return tup + lst", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tpl):\n return tpl + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tpl):\n return tpl + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tup):\n return tup + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tpl):\n \"\"\"Append the given list to the given tuple\"\"\"\n return tpl + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tpl):\n \"\"\"\n Appends the given list to the given tuple.\n\n Args:\n lst (List[int]): Given list.\n tpl (Tuple[int, ...]): Given tuple.\n\n Returns:\n Tuple[int, ...]: Tuple with elements from both tuple and list.\n \"\"\"\n return tpl + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tpl):\n return tpl + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tpl):\n # Create a new tuple by appending the list to the original tuple\n return tpl + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(list_, tuple_):\n return tuple_ + tuple(list_)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tpl):\n \"\"\"Append the given list to the given tuple.\"\"\"\n return tpl + tuple(lst)", "matching_cluster_idx": 5}]}, "Mbpp/108": {"dps": 79.75903614457832, "dps_norm": 97.27272727272727, "pass@1": 89.0, "profiled": [{"solution": "def merge_sorted_list(*args):\n \"\"\"Merge and sort lists.\"\"\"\n return sorted([i for sublist in args for i in sublist])", "matching_cluster_idx": 8}, {"solution": "def merge_sorted_list(*args):\n # Flatten and sort the input lists\n return sorted([item for sublist in args for item in sublist])", "matching_cluster_idx": 9}, {"solution": "def merge_sorted_list(*lists):\n merged = []\n for lst in lists:\n merged.extend(lst)\n return sorted(merged)", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n merged = sorted(list1 + list2 + list3)\n return merged", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n merged = sorted(list1 + list2 + list3)\n return merged", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n merged_list = list1 + list2 + list3\n merged_list.sort()\n return merged_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n return sorted(list1 + list2 + list3)", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(*lists):\n \"\"\"\n Merges and sorts a variable number of sorted lists.\n \"\"\"\n # Flatten the input and sort it\n return sorted([item for sublist in lists for item in sublist])", "matching_cluster_idx": 9}, {"solution": "def merge_sorted_list(list1, list2, list3):\n merged_list = list1 + list2 + list3\n merged_list.sort()\n return merged_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(*args):\n # Flatten the list of lists\n merged = [num for sublist in args for num in sublist]\n # Sort the flattened list\n merged.sort()\n return merged", "matching_cluster_idx": 9}, {"solution": "def merge_sorted_list(*lists):\n \"\"\"Merge and sort multiple sorted lists into one.\"\"\"\n return sorted(sum(lists, []))", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(*lists):\n return sorted(sum(lists, []))", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(*lists):\n return sorted(sum(lists, []))", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n return sorted(list1 + list2 + list3)", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Merge the lists and sort\n return sorted(list1 + list2 + list3)", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(*lists):\n return sorted(sum(lists, []))", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Merge all lists\n merged_list = list1 + list2 + list3\n # Use sorted function to sort the merged list\n return sorted(merged_list)", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(*lists):\n return sorted([item for sublist in lists for item in sublist])", "matching_cluster_idx": 9}, {"solution": "def merge_sorted_list(*lists):\n return sorted(sum(lists, []))", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(*lists):\n merged = []\n for lst in lists:\n merged.extend(lst)\n merged.sort()\n return merged", "matching_cluster_idx": 10}]}, "Mbpp/111": {"dps": 37.676923076923075, "dps_norm": 71.875, "pass@1": 49.0, "profiled": [{"solution": "def common_in_nested_lists(nested_lists):\n if not nested_lists: # if input list is empty, return empty list\n return []\n\n # Find the intersection of the first list with each subsequent list\n common_elements = set(nested_lists[0])\n for lst in nested_lists[1:]:\n common_elements.intersection_update(lst)\n\n # Convert the resulting set back to a list and return\n return list(common_elements)", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(lst):\n \"\"\"\n This function takes a nested list as input\n and returns a list of common elements in all sublists.\n \"\"\"\n # Convert all sublists to sets and find the intersection\n common = set(lst[0])\n for sublist in lst[1:]:\n common &= set(sublist)\n return list(common)", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n return set.intersection(*map(set, nested_lists))", "matching_cluster_idx": 5}, {"solution": "def common_in_nested_lists(nested_list):\n \"\"\"\n Find common elements in a nested list of lists.\n \"\"\"\n # Use sets to find common elements\n common_set = set(nested_list[0])\n for sublist in nested_list[1:]:\n common_set &= set(sublist)\n return list(common_set)", "matching_cluster_idx": 6}, {"solution": "from itertools import chain\nfrom typing import List\ndef common_in_nested_lists(nested_list: List[List[int]]) -> List[int]:\n if not nested_list: # If the input list is empty, return an empty list\n return []\n # Flatten the nested list and convert it to a set for easier comparison\n flat_set = set(chain.from_iterable(nested_list))\n return [num for num in nested_list[0] if all(num in sublist for sublist in nested_list)]", "matching_cluster_idx": 3}, {"solution": "def common_in_nested_lists(nested_list):\n \"\"\"\n This function takes a list of lists as input and returns\n the common elements across all the lists.\n\n Args:\n nested_list (list): A list containing other lists.\n\n Returns:\n list: A list containing the common elements.\n \"\"\"\n # Convert the nested list into a set of sets to remove duplicates\n # for each list and then find the intersection of these sets.\n common = set.intersection(*[set(lst) for lst in nested_list])\n\n # Convert the common set back into a list and return.\n return list(common)", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef common_in_nested_lists(nested_list: List[List[int]]) -> List[int]:\n if not nested_list: # if the input list is empty\n return []\n\n common_elements = set(nested_list[0]) # start with the first list as the common set\n\n for sublist in nested_list[1:]: # iterate over the rest of the lists\n common_elements.intersection_update(sublist) # keep only the common elements\n\n return list(common_elements)", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef common_in_nested_lists(nested_lists: List[List[int]]) -> List[int]:\n # Get the set of all elements in all lists\n all_elements = set(sum(nested_lists, []))\n\n # Filter out elements that are common in all lists\n common_elements = [element for element in all_elements if all([element in lst for lst in nested_lists])]\n\n return common_elements", "matching_cluster_idx": -1}, {"solution": "from typing import List\ndef common_in_nested_lists(lists: List[List[int]]) -> List[int]:\n # Find common elements by using built-in any() and all() functions\n return [num for num in set(lists[0]) if all(num in lst for lst in lists)]", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(lists):\n # Flatten the lists\n flat_list = [item for sublist in lists for item in sublist]\n # Find common elements using set intersection\n common = set(flat_list)\n for sublist in lists:\n common.intersection_update(sublist)\n return list(common)", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef common_in_nested_lists(lists: List[List[int]]) -> List[int]:\n # Use a set to find common elements\n return list(set.intersection(*map(set, lists)))", "matching_cluster_idx": 5}, {"solution": "def common_in_nested_lists(nested_lists):\n return set.intersection(*map(set, nested_lists))", "matching_cluster_idx": 5}, {"solution": "def common_in_nested_lists(nested_list):\n \"\"\"\n Function to find common elements in a nested list.\n It converts each list to a set to remove duplicates,\n find intersection of all the sets, and convert the resulting set back to list.\n \"\"\"\n return list(set.intersection(*map(set, nested_list)))", "matching_cluster_idx": 5}, {"solution": "def common_in_nested_lists(lists):\n # Convert the nested list to a set of sets\n sets = [set(lst) for lst in lists]\n\n # Find the common elements using set intersection\n common = sets[0]\n for s in sets[1:]:\n common = common & s\n\n return common", "matching_cluster_idx": 5}, {"solution": "def common_in_nested_lists(nested_list):\n # Use set to find common elements in nested list\n return set.intersection(*map(set, nested_list))", "matching_cluster_idx": 5}, {"solution": "def common_in_nested_lists(nested_list):\n return set.intersection(*map(set, nested_list))", "matching_cluster_idx": 5}, {"solution": "def common_in_nested_lists(nested_list):\n # Find the intersection of all the lists in the nested list\n return set.intersection(*map(set, nested_list))", "matching_cluster_idx": 5}, {"solution": "def common_in_nested_lists(nested_list):\n \"\"\"Find common elements in given nested lists.\"\"\"\n if not nested_list:\n return set()\n\n # Convert all lists to sets for easy intersection operation\n sets_list = [set(lst) for lst in nested_list]\n\n # Find intersection of all sets\n common = sets_list[0]\n for s in sets_list[1:]:\n common = common & s # Intersection operation\n\n return common", "matching_cluster_idx": 5}, {"solution": "def common_in_nested_lists(nested_lists):\n # Convert each sublist to a set to get unique elements\n sets = [set(sublist) for sublist in nested_lists]\n\n # Find the intersection of all the sets\n common = sets[0]\n for s in sets[1:]:\n common &= s\n\n # Convert the result back to list\n return list(common)", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef common_in_nested_lists(nested_list: List[List[int]]) -> List[int]:\n # Find the common elements by taking intersection of sets\n return list(set(nested_list[0]).intersection(*map(set, nested_list[1:])))", "matching_cluster_idx": 5}]}, "Mbpp/123": {"dps": null, "dps_norm": null, "pass@1": 4.0, "profiled": []}, "Mbpp/128": {"dps": 99.5475113122172, "dps_norm": 80.0, "pass@1": 100.0, "profiled": [{"solution": "def long_words(n, sentence):\n # Split the sentence into a list of words\n words = sentence.split()\n\n # Filter words that are longer than n characters\n long_words_list = [word for word in words if len(word) > n]\n\n return long_words_list", "matching_cluster_idx": 3}, {"solution": "def long_words(n, words):\n return [word for word in words.split() if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n # Split the sentence into a list of words\n words = sentence.split()\n\n # Filter the words that are longer than n characters\n long_words = [word for word in words if len(word) > n]\n\n return long_words", "matching_cluster_idx": 3}, {"solution": "def long_words(n, text):\n # Split the text into a list of words\n words = text.split()\n\n # Filter the list to keep words that are longer than n characters\n return [word for word in words if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n words = sentence.split()\n return [word for word in words if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n # split the sentence into words\n words = sentence.split()\n\n # filter words that are longer than n\n long_words_list = [word for word in words if len(word) > n]\n\n return long_words_list", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n words = sentence.split()\n return [word for word in words if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n return [word for word in sentence.split() if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n words = sentence.split(' ')\n return [word for word in words if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, text):\n word_list = text.split()\n return [word for word in word_list if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n return [word for word in sentence.split() if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n # Split the sentence into a list of words\n words = sentence.split()\n # Filter words that are longer than n characters\n long_words_list = [word for word in words if len(word) > n]\n return long_words_list", "matching_cluster_idx": 3}, {"solution": "def long_words(n, text):\n # Split the text into words\n words = text.split()\n\n # Filter words longer than n characters\n long_words_list = [word for word in words if len(word) > n]\n\n return long_words_list", "matching_cluster_idx": 3}, {"solution": "def long_words(n, text):\n # Split the text into words\n words = text.split()\n\n # Filter words that are longer than n characters\n long_words = [word for word in words if len(word) > n]\n\n return long_words", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n words = sentence.split()\n return [word for word in words if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, text):\n words = text.split()\n return [word for word in words if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n words = sentence.split()\n return [word for word in words if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n \"\"\"\n Function to find words that are longer than n characters from a given sentence.\n\n Args:\n n (int): The minimum length of words to find.\n sentence (str): The input sentence.\n\n Returns:\n list: A list of words that are longer than n characters.\n \"\"\"\n return [word for word in sentence.split() if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n # Split the sentence into a list of words\n words = sentence.split()\n\n # Use list comprehension to filter words that are longer than n characters\n long_word_list = [word for word in words if len(word) > n]\n\n return long_word_list", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n words = sentence.split() # Split the sentence into words\n return [word for word in words if len(word) > n] # List comprehension to filter words based on their length", "matching_cluster_idx": 3}]}, "Mbpp/129": {"dps": 50.34438775510204, "dps_norm": 90.33333333333333, "pass@1": 38.0, "profiled": [{"solution": "def magic_square_test(matrix):\n # Calculate sum of first row\n diagonal_sum = sum(matrix[0])\n\n # Check if each row, each column, and both diagonals sum up to the same value\n for i in range(len(matrix)):\n if sum(matrix[i]) != diagonal_sum or sum([row[i] for row in matrix]) != diagonal_sum:\n return False\n if sum([matrix[i][i] for i in range(len(matrix))]) != diagonal_sum or sum([matrix[i][len(matrix)-1-i] for i in range(len(matrix))]) != diagonal_sum:\n return False\n\n return True", "matching_cluster_idx": 13}, {"solution": "def magic_square_test(matrix):\n # Check if the input is a square matrix\n n = len(matrix)\n for row in matrix:\n if len(row) != n:\n return False\n\n # Calculate the expected sum of rows, columns, and diagonals\n expected_sum = sum(matrix[0])\n\n # Check each row, column, and diagonal for the expected sum\n for i in range(n):\n row_sum = sum(matrix[i])\n col_sum = sum(row[i] for row in matrix)\n if row_sum != expected_sum or col_sum != expected_sum:\n return False\n if i == n - 1:\n if sum(matrix[i][j] for j in range(i, -1, -1)) != expected_sum or sum(matrix[i-j][j] for j in range(n)) != expected_sum:\n return False\n\n return True", "matching_cluster_idx": 13}, {"solution": "def magic_square_test(matrix):\n n = len(matrix)\n # Check if matrix is a square\n if n != len(matrix[0]):\n return False\n # Check if sum of each row, column and diagonal are equal\n sum_row = sum(matrix[0])\n for i in range(1, n):\n if sum(matrix[i]) != sum_row:\n return False\n for j in range(n):\n if sum(row[j] for row in matrix) != sum_row:\n return False\n if sum(matrix[i][i] for i in range(n)) != sum_row:\n return False\n if sum(matrix[i][n-i-1] for i in range(n)) != sum_row:\n return False\n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n # Check if matrix is square\n n = len(matrix)\n if not all(len(row) == n for row in matrix):\n return False\n\n # Calculate the sum of the first row\n total_sum = sum(matrix[0])\n\n # Check if all rows have the same sum\n if not all(sum(row) == total_sum for row in matrix):\n return False\n\n # Check if all columns have the same sum\n if not all(sum(matrix[i][j] for i in range(n)) == total_sum for j in range(n)):\n return False\n\n # Check if main diagonal sums to total sum\n if sum(matrix[i][i] for i in range(n)) != total_sum:\n return False\n\n # Check if anti-diagonal sums to total sum\n if sum(matrix[i][n - 1 - i] for i in range(n)) != total_sum:\n return False\n\n # If all checks pass, the matrix is a magic square\n return True", "matching_cluster_idx": 13}, {"solution": "def magic_square_test(matrix):\n # Check if the matrix is square\n n = len(matrix)\n if n != len(matrix[0]):\n return False\n\n # Calculate the sum of the numbers in the first row\n expected_sum = sum(matrix[0])\n\n # Check each row, column, and diagonal to see if their sums equal the expected sum\n for i in range(n):\n if sum(matrix[i]) != expected_sum or sum(row[i] for row in matrix) != expected_sum:\n return False\n if sum(matrix[i][i] for i in range(n)) != expected_sum or sum(matrix[i][n - i - 1] for i in range(n)) != expected_sum:\n return False\n\n # If all checks passed, the matrix is a magic square\n return True", "matching_cluster_idx": 13}, {"solution": "def magic_square_test(matrix):\n # Check if input is a 2D list\n if not all(isinstance(row, list) for row in matrix):\n return False\n\n # Calculate sum of the first row\n magic_sum = sum(matrix[0])\n\n # Check if matrix is a square\n if len(matrix) != len(matrix[0]) or any(len(row) != len(matrix) for row in matrix):\n return False\n\n # Check if all rows, columns, and diagonals have the same sum\n for i in range(len(matrix)):\n if sum(matrix[i]) != magic_sum or sum(matrix[j][i] for j in range(len(matrix))) != magic_sum:\n return False\n if sum(matrix[i][i] for i in range(len(matrix))) != magic_sum or sum(matrix[i][len(matrix) - 1 - i] for i in range(len(matrix))) != magic_sum:\n return False\n\n return True", "matching_cluster_idx": 13}, {"solution": "def magic_square_test(square):\n # Check if the input is a square\n if not all(len(row) == len(square) for row in square):\n return False\n\n n = len(square)\n # Check if the sum of elements in each row, column, and diagonal is the same\n diagonal_sum1 = sum(square[i][i] for i in range(n))\n diagonal_sum2 = sum(square[i][n - 1 - i] for i in range(n))\n\n if diagonal_sum1 != diagonal_sum2:\n return False\n\n for i in range(n):\n if sum(square[i]) != diagonal_sum1 or sum(row[i] for row in square) != diagonal_sum1:\n return False\n\n return True", "matching_cluster_idx": 11}, {"solution": "def magic_square_test(matrix):\n # Check if the matrix is square\n if len(matrix) != len(matrix[0]):\n return False\n\n # Calculate the expected sum of each row, column, and diagonal\n expected_sum = sum(matrix[0])\n\n # Check rows\n for row in matrix:\n if sum(row) != expected_sum:\n return False\n\n # Check columns\n for col in range(len(matrix[0])):\n if sum(matrix[row][col] for row in range(len(matrix))) != expected_sum:\n return False\n\n # Check main diagonal\n if sum(matrix[i][i] for i in range(len(matrix))) != expected_sum:\n return False\n\n # Check anti-diagonal\n if sum(matrix[i][len(matrix)-i-1] for i in range(len(matrix))) != expected_sum:\n return False\n\n # If all checks pass, it's a magic square\n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n # Check if matrix is a square matrix\n if len(matrix) != len(matrix[0]):\n return False\n\n # Calculate expected sum of a row (or column) in a magic square\n expected_sum = sum(matrix[0])\n\n # Check if all rows, columns, and diagonals have the expected sum\n for i in range(len(matrix)):\n if sum(matrix[i]) != expected_sum or sum(row[i] for row in matrix) != expected_sum:\n return False\n if sum(matrix[i][i] for i in range(len(matrix))) != expected_sum or sum(matrix[i][len(matrix)-1-i] for i in range(len(matrix))) != expected_sum:\n return False\n\n # If all checks pass, the matrix is a magic square\n return True", "matching_cluster_idx": 13}, {"solution": "def magic_square_test(matrix):\n n = len(matrix)\n # Check if the matrix is square and all rows/columns have the same length\n if n != len(matrix[0]) or not all(len(row) == n for row in matrix):\n return False\n\n # Check if the sum of the first row equals the sum of the other rows\n row_sum = sum(matrix[0])\n if not all(sum(row) == row_sum for row in matrix):\n return False\n\n # Check if the sum of the first column equals the sum of the other columns\n col_sum = sum(matrix[i][0] for i in range(n))\n if not all(sum(matrix[i][j] for i in range(n)) == col_sum for j in range(1, n)):\n return False\n\n # Check if the sums of the main and anti-diagonals equal the row/column sum\n if sum(matrix[i][i] for i in range(n)) != row_sum or sum(matrix[i][n - i - 1] for i in range(n)) != row_sum:\n return False\n\n return True", "matching_cluster_idx": 13}, {"solution": "def magic_square_test(matrix):\n n = len(matrix)\n # Check if the matrix is a square\n if n != len(matrix[0]):\n return False\n # Calculate sum of the first row and check if it equals the sum of the last column\n row_sum = sum(matrix[0])\n last_col_sum = sum(matrix[i][n-1] for i in range(n))\n if row_sum != last_col_sum:\n return False\n # Calculate sum of each row, column, and diagonal\n row_sums = [sum(row) for row in matrix]\n col_sums = [sum(matrix[i][j] for i in range(n)) for j in range(n)]\n diag_sum1 = sum(matrix[i][i] for i in range(n))\n diag_sum2 = sum(matrix[i][n-i-1] for i in range(n))\n # Check if all sums are equal\n if all(sum1 == row_sum for sum1 in row_sums) and \\\n all(sum2 == row_sum for sum2 in col_sums) and \\\n diag_sum1 == row_sum and diag_sum2 == row_sum:\n return True\n else:\n return False", "matching_cluster_idx": 13}, {"solution": "def is_magic_square(matrix):\n n = len(matrix)\n # Check if the matrix is a square\n if n != len(matrix[0]):\n return False\n\n # Calculate the sum of the first row\n sum_first_row = sum(matrix[0])\n\n # Check if all rows have the same sum and all rows, columns, and diagonals have the same sum\n for i in range(n):\n if sum(matrix[i]) != sum_first_row or sum(matrix[j][i] for j in range(n)) != sum_first_row:\n return False\n if sum(matrix[i][j] for j in range(n)) != sum_first_row:\n return False\n\n # Check the diagonals\n if sum(matrix[i][i] for i in range(n)) != sum_first_row or sum(matrix[i][n - i - 1] for i in range(n)) != sum_first_row:\n return False\n\n return True\ndef magic_square_test(matrix):\n return is_magic_square(matrix)", "matching_cluster_idx": 13}, {"solution": "def magic_square_test(matrix):\n # Check if the matrix is a square\n n = len(matrix)\n if any(len(row) != n for row in matrix):\n return False\n\n # Calculate the sum of the first row (or any row, as all rows should have the same sum in a magic square)\n sum_row = sum(matrix[0])\n\n # Check if each row, column and diagonal has the same sum\n for i in range(n):\n if sum(matrix[i]) != sum_row or sum(row[i] for row in matrix) != sum_row:\n return False\n if sum(matrix[i][i] for i in range(n)) != sum_row or sum(matrix[i][n-i-1] for i in range(n)) != sum_row:\n return False\n\n return True", "matching_cluster_idx": 13}, {"solution": "def magic_square_test(matrix):\n # Check if the input is a valid square matrix\n size = len(matrix)\n for row in matrix:\n if len(row) != size:\n return False\n for num in row:\n if not isinstance(num, int):\n return False\n\n # Calculate the sum of the first row\n row_sum = sum(matrix[0])\n\n # Check if each row, each column, and both diagonals have the same sum\n for i in range(size):\n if sum(matrix[i]) != row_sum or sum(row[i] for row in matrix) != row_sum or sum(matrix[j][j] for j in range(size)) != row_sum or sum(matrix[j][size-j-1] for j in range(size)) != row_sum:\n return False\n\n # If all conditions are met, the matrix is a magic square\n return True", "matching_cluster_idx": 4}, {"solution": "def magic_square_test(matrix):\n \"\"\"Check if a matrix is a magic square.\"\"\"\n size = len(matrix)\n # Check if the matrix is square\n if any(len(row) != size for row in matrix):\n return False\n # Check if the sum of elements in each row is the same\n row_sum = sum(matrix[0])\n if any(sum(row) != row_sum for row in matrix):\n return False\n # Check if the sum of elements in each column is the same\n if any(sum(matrix[i][j] for i in range(size)) != row_sum for j in range(size)):\n return False\n # Check if the sum of elements in both diagonals is the same\n if sum(matrix[i][i] for i in range(size)) != row_sum or sum(matrix[i][size - i - 1] for i in range(size)) != row_sum:\n return False\n return True", "matching_cluster_idx": 13}, {"solution": "def magic_square_test(matrix):\n n = len(matrix)\n\n # Check if the matrix is a square\n if n != len(matrix[0]):\n return False\n\n # Calculate sum of the first row\n row_sum = sum(matrix[0])\n\n # Check each row, column, and diagonal sum\n for i in range(n):\n if sum(matrix[i]) != row_sum or sum(matrix[j][i] for j in range(n)) != row_sum:\n return False\n if sum(matrix[i][i] for i in range(n)) != row_sum or sum(matrix[i][n-i-1] for i in range(n)) != row_sum:\n return False\n\n return True", "matching_cluster_idx": 13}, {"solution": "def magic_square_test(matrix):\n n = len(matrix)\n # Check if the input is a square matrix\n if n != len(matrix[0]):\n return False\n # Calculate the sum of the first row\n sum_row = sum(matrix[0])\n # Check each row, column, and diagonal sum\n for i in range(n):\n if sum(matrix[i]) != sum_row or sum([matrix[j][i] for j in range(n)]) != sum_row:\n return False\n if i < n-1 and sum([matrix[i][j] for j in range(n)]) != sum_row:\n return False\n # All sums are equal, it's a magic square\n return True", "matching_cluster_idx": 13}, {"solution": "def magic_square_test(matrix):\n # Check if matrix is a square matrix\n rows = len(matrix)\n cols = len(matrix[0])\n if rows != cols:\n return False\n\n # Calculate the sum of the first row\n first_row_sum = sum(matrix[0])\n\n # Check each row, column, and diagonal\n for i in range(rows):\n row_sum = sum(matrix[i])\n if row_sum != first_row_sum:\n return False\n\n col_sum = sum(matrix[j][i] for j in range(rows))\n if col_sum != first_row_sum:\n return False\n\n # Check diagonals\n left_diag_sum = sum(matrix[i][i] for i in range(rows))\n right_diag_sum = sum(matrix[i][rows - 1 - i] for i in range(rows))\n if left_diag_sum != first_row_sum or right_diag_sum != first_row_sum:\n return False\n\n return True", "matching_cluster_idx": 13}, {"solution": "def magic_square_test(matrix):\n n = len(matrix) # Assuming the matrix is a square\n\n # Check if all rows and columns have the same sum\n row_sum = sum(matrix[0])\n for i in range(n):\n if sum(matrix[i]) != row_sum or sum(j[i] for j in matrix) != row_sum:\n return False\n\n # Check if the two main diagonals have the same sum\n diag_sum = sum(matrix[i][i] for i in range(n))\n if sum(matrix[i][n-i-1] for i in range(n)) != diag_sum:\n return False\n\n return True", "matching_cluster_idx": 13}, {"solution": "def magic_square_test(matrix):\n # Check if the matrix is a square\n if len(matrix) != len(matrix[0]):\n return False\n\n # Calculate the expected sum of each row, column and diagonal\n size = len(matrix)\n expected_sum = sum(matrix[0])\n\n # Check each row, column and diagonal\n for i in range(size):\n row_sum = sum(matrix[i])\n if row_sum != expected_sum:\n return False\n\n col_sum = sum(matrix[j][i] for j in range(size))\n if col_sum != expected_sum:\n return False\n\n # Check both diagonals\n diag_sum = sum(matrix[i][i] for i in range(size))\n if diag_sum != expected_sum:\n return False\n\n anti_diag_sum = sum(matrix[i][size-i-1] for i in range(size))\n if anti_diag_sum != expected_sum:\n return False\n\n return True", "matching_cluster_idx": 13}]}, "Mbpp/130": {"dps": 91.7713004484305, "dps_norm": 78.33333333333333, "pass@1": 71.0, "profiled": [{"solution": "from collections import Counter\ndef max_occurrences(lst):\n counter = Counter(lst)\n return counter.most_common(1)[0][0]", "matching_cluster_idx": 4}, {"solution": "from collections import Counter\ndef max_occurrences(lst):\n \"\"\"Find the item with maximum frequency in a given list.\"\"\"\n count = Counter(lst)\n return count.most_common(1)[0][0]", "matching_cluster_idx": 4}, {"solution": "from collections import Counter\ndef max_occurrences(numbers):\n counter = Counter(numbers)\n return counter.most_common(1)[0][0]", "matching_cluster_idx": 4}, {"solution": "def max_occurrences(lst):\n counts = {}\n for num in lst:\n if num in counts:\n counts[num] += 1\n else:\n counts[num] = 1\n return max(counts, key=counts.get)", "matching_cluster_idx": 3}, {"solution": "from collections import Counter\ndef max_occurrences(lst):\n counter = Counter(lst)\n return counter.most_common(1)[0][0]", "matching_cluster_idx": 4}, {"solution": "def max_occurrences(lst):\n counts = {}\n for item in lst:\n if item in counts:\n counts[item] += 1\n else:\n counts[item] = 1\n return max(counts, key=counts.get)", "matching_cluster_idx": 3}, {"solution": "from collections import Counter\ndef max_occurrences(lst):\n # Count the frequency of each item in the list\n frequency = Counter(lst)\n\n # Find the most common item(s)\n max_freq = max(frequency.values())\n most_common = [item for item, freq in frequency.items() if freq == max_freq]\n\n # Return the first most common item\n return most_common[0]", "matching_cluster_idx": 4}, {"solution": "from collections import Counter\ndef max_occurrences(lst):\n \"\"\"Find the item with maximum frequency in a given list\"\"\"\n return max(Counter(lst).items(), key=lambda x: x[1])[0]", "matching_cluster_idx": 3}, {"solution": "from collections import Counter\ndef max_occurrences(lst):\n \"\"\"\n Function to find the item with maximum frequency in a given list.\n \"\"\"\n counter = Counter(lst)\n return counter.most_common(1)[0][0]", "matching_cluster_idx": 4}, {"solution": "from collections import Counter\ndef max_occurrences(lst):\n \"\"\"\n This function finds the item with maximum frequency in a given list.\n \"\"\"\n counter = Counter(lst)\n return counter.most_common(1)[0][0]", "matching_cluster_idx": 4}, {"solution": "from collections import Counter\ndef max_occurrences(lst):\n counter = Counter(lst)\n return counter.most_common(1)[0][0]", "matching_cluster_idx": 4}, {"solution": "from collections import Counter\ndef max_occurrences(lst):\n # Using Counter to get frequencies of all items in the list\n frequency = Counter(lst)\n\n # Returning item with maximum frequency\n return frequency.most_common(1)[0][0]", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef max_occurrences(lst: List[int]) -> int:\n count_dict = {}\n for num in lst:\n if num not in count_dict:\n count_dict[num] = 1\n else:\n count_dict[num] += 1\n return max(count_dict, key=count_dict.get)", "matching_cluster_idx": 3}, {"solution": "from collections import Counter\ndef max_occurrences(lst):\n \"\"\"\n Function to find the item with maximum frequency in a given list.\n \"\"\"\n # Count occurrences of items in the list\n occurrences = Counter(lst)\n\n # Find the most common item and its frequency\n most_common = occurrences.most_common(1)[0]\n\n return most_common[0]", "matching_cluster_idx": 4}, {"solution": "from collections import Counter\ndef max_occurrences(lst):\n \"\"\"Find the item with maximum frequency in a given list.\"\"\"\n counter = Counter(lst)\n return counter.most_common(1)[0][0]", "matching_cluster_idx": 4}, {"solution": "from collections import Counter\ndef max_occurrences(lst):\n count = Counter(lst)\n return count.most_common(1)[0][0]", "matching_cluster_idx": 4}, {"solution": "from collections import Counter\ndef max_occurrences(lst):\n # count the occurrence of each item\n count = Counter(lst)\n # find the most common element\n return count.most_common(1)[0][0]", "matching_cluster_idx": 4}, {"solution": "from collections import Counter\ndef max_occurrences(lst):\n counter = Counter(lst)\n max_occurrence = max(list(counter.values()))\n return next((k for k, v in counter.items() if v == max_occurrence), None)", "matching_cluster_idx": 4}, {"solution": "def max_occurrences(lst):\n freq_dict = {}\n for num in lst:\n if num in freq_dict:\n freq_dict[num] += 1\n else:\n freq_dict[num] = 1\n\n return max(freq_dict, key=freq_dict.get)", "matching_cluster_idx": 3}, {"solution": "from collections import Counter\ndef max_occurrences(lst):\n \"\"\"Find the item with maximum frequency in a given list\"\"\"\n return max(Counter(lst).items(), key=lambda x: x[1])[0]", "matching_cluster_idx": 3}]}, "Mbpp/137": {"dps": 36.08870967741935, "dps_norm": 50.0, "pass@1": 16.0, "profiled": [{"solution": "from math import isclose\ndef zero_count(arr):\n zero_count = 0\n non_zero_count = 0\n for num in arr:\n if num == 0:\n zero_count += 1\n else:\n non_zero_count += 1\n if non_zero_count == 0:\n return float('inf')\n return zero_count / non_zero_count", "matching_cluster_idx": 3}, {"solution": "import math\ndef zero_count(arr):\n zeroes = sum(1 for x in arr if x == 0)\n non_zeroes = sum(1 for x in arr if x != 0)\n if non_zeroes == 0: # Avoid division by zero\n return math.inf\n return zeroes / non_zeroes", "matching_cluster_idx": 1}, {"solution": "import math\ndef zero_count(arr):\n zeroes = sum(1 for x in arr if x == 0)\n non_zeros = len(arr) - zeroes\n if non_zeros == 0:\n return float('inf') if zeroes > 0 else float('-inf')\n else:\n return zeroes / non_zeros", "matching_cluster_idx": 4}, {"solution": "import math\ndef zero_count(arr):\n zero_count = arr.count(0)\n non_zero_count = len(arr) - zero_count\n if non_zero_count == 0:\n return float('inf') # Return infinity if there are no non-zero elements\n return zero_count / non_zero_count", "matching_cluster_idx": 7}, {"solution": "import math\nimport unittest\ndef zero_count(arr):\n zero_count = 0\n non_zero_count = 0\n\n for num in arr:\n if num == 0:\n zero_count += 1\n else:\n non_zero_count += 1\n\n if non_zero_count == 0:\n return float('inf') # to handle division by zero\n\n return zero_count / non_zero_count", "matching_cluster_idx": 3}, {"solution": "from math import isclose\ndef zero_count(arr):\n zeroes = sum(1 for x in arr if x == 0)\n non_zeroes = len(arr) - zeroes\n if non_zeroes == 0:\n return float('inf') # or any suitable value representing infinite ratio\n return zeroes / non_zeroes", "matching_cluster_idx": 4}, {"solution": "import math\ndef zero_count(arr):\n zeroes = sum(i == 0 for i in arr)\n non_zeros = sum(i != 0 for i in arr)\n if non_zeros == 0:\n return float('inf') # return infinity if there are no non-zero elements\n return zeroes / non_zeros", "matching_cluster_idx": 0}, {"solution": "from math import isclose\ndef zero_count(arr):\n # Count zeroes and non-zeroes in the array\n zeroes = sum(1 for num in arr if num == 0)\n non_zeroes = sum(1 for num in arr if num != 0)\n\n # Avoid division by zero\n if non_zeroes == 0:\n return float('inf')\n\n # Return the ratio of zeroes to non-zeroes\n return zeroes / non_zeroes", "matching_cluster_idx": 1}, {"solution": "def zero_count(arr):\n zero_count = sum(1 for num in arr if num == 0)\n non_zero_count = len([num for num in arr if num != 0])\n if non_zero_count == 0:\n return float('inf')\n return zero_count / non_zero_count", "matching_cluster_idx": 2}, {"solution": "from math import isclose\ndef zero_count(arr):\n zeros = sum(1 for i in arr if i == 0)\n non_zeros = sum(1 for i in arr if i != 0)\n if non_zeros == 0:\n return float('inf') # Avoid division by zero\n return zeros / non_zeros", "matching_cluster_idx": 1}, {"solution": "import math\ndef zero_count(arr):\n \"\"\"Find the ratio of zeroes to non-zeroes in an array of integers.\"\"\"\n zeroes = sum(1 for num in arr if num == 0)\n non_zeroes = len(arr) - zeroes\n if non_zeroes == 0:\n return 0 if zeroes == 0 else float('inf')\n else:\n return zeroes / non_zeroes", "matching_cluster_idx": 5}, {"solution": "import math\ndef zero_count(arr):\n zero_count = sum(x == 0 for x in arr)\n non_zero_count = len(arr) - zero_count\n return zero_count / non_zero_count if non_zero_count != 0 else float('inf')", "matching_cluster_idx": 4}, {"solution": "import math\nimport unittest\ndef zero_count(arr):\n num_zeros = arr.count(0)\n num_non_zeros = len(arr) - num_zeros\n if num_non_zeros == 0:\n return float('inf') # special handling for division by zero\n return num_zeros / num_non_zeros", "matching_cluster_idx": 7}, {"solution": "import math\ndef zero_count(numbers):\n zeroes = sum(1 for num in numbers if num == 0)\n non_zeroes = sum(1 for num in numbers if num != 0)\n if non_zeroes == 0:\n return float('inf')\n else:\n return zeroes / non_zeroes", "matching_cluster_idx": 1}, {"solution": "import math\ndef zero_count(arr):\n zeroes = sum(1 for num in arr if num == 0)\n non_zeroes = len(arr) - zeroes\n if non_zeroes == 0:\n return float('inf')\n return zeroes / non_zeroes", "matching_cluster_idx": 4}, {"solution": "import math\ndef zero_count(nums):\n \"\"\"\n This function takes an array of integers and returns the ratio of zeroes to non-zeroes.\n If there are no zeroes, it returns 0. If there are no non-zeroes, it returns inf.\n \"\"\"\n zeroes = sum(1 for num in nums if num == 0)\n non_zeroes = sum(1 for num in nums if num != 0)\n if non_zeroes == 0:\n return float('inf')\n return zeroes / non_zeroes", "matching_cluster_idx": 1}]}, "Mbpp/140": {"dps": 68.74223602484471, "dps_norm": 73.125, "pass@1": 100.0, "profiled": [{"solution": "def extract_singly(nested_list):\n return set(number for sublist in nested_list for number in sublist)", "matching_cluster_idx": 4}, {"solution": "def extract_singly(lst_of_tuples):\n # Using list comprehension to flatten the list of tuples and then converting it to a set\n return set(x for sublist in lst_of_tuples for x in sublist)", "matching_cluster_idx": 5}, {"solution": "def extract_singly(input_list):\n # Using list comprehension to flatten the list of lists into a single list\n return [item for sublist in input_list for item in sublist]", "matching_cluster_idx": 5}, {"solution": "def extract_singly(nested_list):\n \"\"\"Flatten a nested list of lists into a single set of numbers\"\"\"\n return set(number for sublist in nested_list for number in sublist)", "matching_cluster_idx": 4}, {"solution": "def extract_singly(lst):\n return set(num for sublist in lst for num in sublist)", "matching_cluster_idx": 5}, {"solution": "def extract_singly(lst_of_lists):\n return set(item for sublist in lst_of_lists for item in sublist)", "matching_cluster_idx": 5}, {"solution": "def extract_singly(list_of_lists):\n return set(num for sublist in list_of_lists for num in sublist)", "matching_cluster_idx": 5}, {"solution": "def extract_singly(nested_list):\n # Use list comprehension to flatten the nested list and convert it to a set\n return set(item for sublist in nested_list for item in sublist)", "matching_cluster_idx": 5}, {"solution": "def extract_singly(lst):\n \"\"\"Flatten the list of lists into a single set of numbers.\"\"\"\n # Using list comprehension to iterate through all sublists,\n # and then adding each item to the set.\n return set(item for sublist in lst for item in sublist)", "matching_cluster_idx": 4}, {"solution": "def extract_singly(lst_of_lists):\n # Using list comprehension to extract elements from each inner list\n # and converting the result into a set\n return set(x for sublist in lst_of_lists for x in sublist)", "matching_cluster_idx": 4}, {"solution": "def extract_singly(nested_list):\n # Initialize an empty set to store unique numbers\n flattened_set = set()\n\n # Use a list comprehension to extract all numbers from the nested list\n # and add them to the set\n flattened_set = {num for sublist in nested_list for num in sublist}\n\n return flattened_set", "matching_cluster_idx": 5}, {"solution": "def extract_singly(nested_list):\n # Initialize an empty set to store the numbers\n numbers = set()\n\n # Iterate over each sublist in the nested list\n for sublist in nested_list:\n # Add each number from the sublist to the set\n numbers.update(sublist)\n\n return numbers\nnested_list = [(3, 4, 5), (4, 5, 7), (1, 4)]", "matching_cluster_idx": 7}, {"solution": "def extract_singly(lst):\n # Initialize an empty set\n result_set = set()\n\n # Iterate over each tuple in the input list\n for tup in lst:\n # Add each element of the tuple to the result set\n result_set.update(tup)\n\n # Return the flattened result set\n return result_set", "matching_cluster_idx": 7}, {"solution": "def extract_singly(nested_list):\n \"\"\"Extract and return numbers from a list of tuples to a single set.\"\"\"\n return set(num for tup in nested_list for num in tup)", "matching_cluster_idx": 4}, {"solution": "def extract_singly(nested_list):\n \"\"\"\n A function that takes a list of lists and returns a set of the numbers.\n \"\"\"\n return set(num for sublist in nested_list for num in sublist)", "matching_cluster_idx": 4}, {"solution": "def extract_singly(lst_of_lsts):\n # Using list comprehension to flatten the list of lists\n return {num for sublist in lst_of_lsts for num in sublist}", "matching_cluster_idx": 5}, {"solution": "def extract_singly(nested_list):\n return set(item for sublist in nested_list for item in sublist)", "matching_cluster_idx": 5}, {"solution": "def extract_singly(lst_of_lists):\n \"\"\"\n Extracts and returns unique elements from a list of lists.\n\n Args:\n lst_of_lists (list of lists): A nested list of integers.\n\n Returns:\n set: A set of unique integers extracted from the nested list.\n \"\"\"\n return set(num for sublist in lst_of_lists for num in sublist)", "matching_cluster_idx": 4}, {"solution": "def extract_singly(nested_list):\n # Using list comprehension to flatten the nested list and then convert it to a set\n return set([num for sublist in nested_list for num in sublist])", "matching_cluster_idx": 5}, {"solution": "def extract_singly(lst):\n return set(x for sublist in lst for x in sublist)", "matching_cluster_idx": 5}]}, "Mbpp/141": {"dps": 80.09070294784581, "dps_norm": 45.0, "pass@1": 24.0, "profiled": [{"solution": "def pancake_sort(lst):\n # Find the maximum element and its index for each subarray\n for i in range(len(lst) - 1, 0, -1):\n max_idx = i\n for j in range(i):\n if lst[j] > lst[max_idx]:\n max_idx = j\n\n # If the maximum element is not at the end, flip the elements\n if max_idx != i:\n # Flip the first max_idx + 1 elements\n lst = lst[:max_idx + 1][::-1] + lst[max_idx + 1:]\n\n # Flip the first i+1 elements\n lst = lst[:i + 1][::-1] + lst[i + 1:]\n\n return lst", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(arr):\n for i in range(len(arr), 0, -1):\n max_idx = max(range(i), key=arr.__getitem__)\n arr[0:max_idx + 1] = reversed(arr[0:max_idx + 1])\n arr[0:i] = reversed(arr[0:i])\n return arr", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(lst):\n for i in range(len(lst), 0, -1):\n # Find the index of the maximum element in the current unsorted part of the list\n max_idx = max(range(i), key=lst.__getitem__)\n # If the maximum element is not at the correct position, flip the part of the list before the maximum element\n if max_idx != i - 1:\n if max_idx != 0:\n lst[:max_idx + 1] = reversed(lst[:max_idx + 1])\n lst[:i] = reversed(lst[:i])\n return lst", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(arr):\n # We will iterate over the input array from end to start\n for i in range(len(arr), 0, -1):\n # Find the maximum element from index 0 to i\n max_idx = max(range(i), key=arr.__getitem__)\n\n # If the maximum element is not at the current position\n if max_idx != i - 1:\n # If the maximum element is not at the beginning, flip the subarray from max_idx to i - 1\n if max_idx != 0:\n arr[:max_idx+1] = reversed(arr[:max_idx+1])\n\n # Flip the whole array from 0 to i - 1 to make the maximum element come to its correct position\n arr[:i] = reversed(arr[:i])\n\n return arr", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(arr):\n for i in range(len(arr)-1, 0, -1):\n max_index = find_max_index(arr, i)\n if max_index != i:\n arr = flip(arr, max_index) if max_index > 0 else arr\n arr = flip(arr, i)\n return arr\ndef find_max_index(arr, end):\n max_index = 0\n for i in range(1, end + 1):\n if arr[i] > arr[max_index]:\n max_index = i\n return max_index\ndef flip(arr, index):\n return arr[:index+1][::-1] + arr[index+1:]", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(arr):\n def flip(arr, k):\n return arr[:k][::-1] + arr[k:]\n\n for i in range(len(arr), 0, -1):\n max_idx = arr[:i].index(max(arr[:i]))\n if max_idx != i - 1:\n if max_idx != 0:\n arr = flip(arr, max_idx + 1)\n arr = flip(arr, i)\n return arr", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(arr):\n for i in range(len(arr), 0, -1):\n # Find the index of the maximum element in arr[0..i]\n max_idx = max(range(i), key=lambda idx: arr[idx])\n # If the max element is not at the current position, swap it\n if max_idx != i - 1:\n if max_idx != 0:\n # Flip the first max_idx+1 elements\n arr = [arr[j] for j in range(max_idx, -1, -1)] + arr[max_idx + 1:]\n # Flip the first i elements\n arr = [arr[j] for j in range(i - 1, -1, -1)] + arr[i:]\n return arr", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(arr):\n # Initialize an empty list to store sorted elements\n sorted_arr = []\n\n # While there are still unsorted elements in arr\n while arr:\n # Find the index of the maximum element in arr\n max_index = max(range(len(arr)), key=arr.__getitem__)\n\n # If the maximum element is at the end of arr, remove it and append to sorted_arr\n if max_index == len(arr) - 1:\n sorted_arr.append(arr.pop())\n # If the maximum element is not at the end of arr, move it to the end and then remove it\n else:\n # Reverse arr up to the maximum element\n arr[:max_index + 1] = arr[:max_index + 1][::-1]\n # Reverse arr again to move the maximum element to the end\n arr = arr[::-1]\n # Remove and append the maximum element to sorted_arr\n sorted_arr.append(arr.pop())\n\n # Return the sorted list in reverse order\n return sorted_arr[::-1]", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(lst):\n for i in range(len(lst), 0, -1):\n # Find the index of the maximum element in the unsorted sublist\n max_idx = max(range(i), key=lst.__getitem__)\n # If the maximum element is not at the correct position\n if max_idx != i - 1:\n # Flip the sublist to move the maximum element to the end\n lst[:max_idx+1] = reversed(lst[:max_idx+1])\n # Flip the sublist again to move the maximum element to its correct position\n lst[:i] = reversed(lst[:i])\n return lst", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(lst):\n # This function sorts the list by iteratively finding the maximum element and moving it to the end\n for i in range(len(lst)-1, 0, -1):\n max_index = 0\n for j in range(i+1):\n if lst[j] > lst[max_index]:\n max_index = j\n # If the maximum element is not at the end, flip the part of the list up to the max element\n if max_index != i:\n if max_index != 0:\n lst[:max_index+1] = reversed(lst[:max_index+1])\n # Then flip the whole list to move the maximum to the end\n lst[:i+1] = reversed(lst[:i+1])\n return lst", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(arr):\n # Helper function to flip elements up to index 'k'\n def flip(k):\n arr[:k + 1] = arr[:k + 1][::-1]\n\n # Iterate through the array from last to first element\n for i in range(len(arr), 0, -1):\n # Find the index of the maximum element up to the current position\n max_idx = arr[:i].index(max(arr[:i]))\n\n # If the maximum element is not at the correct position,\n # flip the array to move it to the correct position\n if max_idx != i - 1:\n if max_idx != 0:\n flip(max_idx)\n flip(i - 1)\n\n return arr", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(arr):\n # Iterate over the length of the array in reverse order\n for i in range(len(arr), 0, -1):\n # Find the index of the maximum element in the current subarray\n max_idx = max(range(i), key=arr.__getitem__)\n # If the maximum element is not at the correct position\n if max_idx != i - 1:\n # Flip the subarray up to the max element\n arr[:max_idx+1] = reversed(arr[:max_idx+1])\n # Flip the subarray up to the end\n arr[:i] = reversed(arr[:i])\n return arr", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(arr):\n for i in range(len(arr), 0, -1):\n max_idx = 0\n for j in range(1, i):\n if arr[j] > arr[max_idx]:\n max_idx = j\n if max_idx != i - 1:\n if max_idx != 0:\n arr = [arr[max_idx]] + arr[0:max_idx][::-1] + arr[max_idx+1:]\n arr = arr[0:i][::-1] + arr[i:]\n return arr", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(arr):\n for size in range(len(arr), 0, -1):\n # Find the index of the maximum element in the current unsorted part\n max_index = max(range(size), key=lambda i: arr[i])\n # If the maximum is not at the correct position\n if max_index < size - 1:\n # If it's not at the beginning, flip it to the beginning\n if max_index != 0:\n arr = pancake_flip(arr, max_index + 1) if max_index != 0 else arr\n # Flip the last element to its correct position\n arr = pancake_flip(arr, size)\n return arr\ndef pancake_flip(arr, n):\n return arr[:n][::-1] + arr[n:]", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(arr):\n # Helper function to reverse elements up to a certain index\n def flip(arr, k):\n return arr[:k+1][::-1] + arr[k+1:]\n\n # Main sorting logic\n for i in range(len(arr), 0, -1):\n # Find the index of the maximum element in the current unsorted sublist\n max_idx = arr[:i].index(max(arr[:i]))\n # If the maximum is not at the end, flip the array at the max index and then at the current index\n if max_idx != i - 1:\n arr = flip(arr, max_idx)\n arr = flip(arr, i - 1)\n\n return arr", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(arr):\n # Helper function to find index of the maximum element in list[0...end]\n def find_max(arr, end):\n max_idx = 0\n for i in range(1, end + 1):\n if arr[i] > arr[max_idx]:\n max_idx = i\n return max_idx\n\n # Flip the array [0, 1, ... i] on 0, 1, ..., i\n def flip(arr, i):\n i = i + 1\n for j in range(i // 2):\n arr[j], arr[i - j - 1] = arr[i - j - 1], arr[j]\n\n n = len(arr)\n for i in range(n):\n max_idx = find_max(arr, n - i - 1)\n # If the largest element is at its correct place, skip\n if max_idx != n - i - 1:\n # Move the largest element to its correct place\n # First, move the largest element to end of the subarray\n if max_idx != n - i - 1:\n flip(arr, max_idx)\n flip(arr, n - i - 1)\n return arr", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(arr):\n n = len(arr)\n for i in range(n, 0, -1):\n max_idx = find_max(arr, i)\n if max_idx != i - 1:\n # reverse elements up to the max element\n arr = reverse(arr, max_idx + 1)\n # reverse the entire list\n arr = reverse(arr, i)\n return arr\ndef find_max(arr, n):\n max_idx = 0\n for i in range(1, n):\n if arr[i] > arr[max_idx]:\n max_idx = i\n return max_idx\ndef reverse(arr, n):\n return arr[:n][::-1] + arr[n:]", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(lst):\n for i in range(len(lst)):\n max_idx = lst[:len(lst) - i].index(max(lst[:len(lst) - i])) + 1\n if max_idx != len(lst) - i:\n if max_idx != 1:\n lst[:max_idx] = lst[:max_idx][::-1]\n lst[:len(lst) - i] = lst[:len(lst) - i][::-1]\n return lst", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(arr):\n # Helper function to find the index of the maximum element in the list\n def find_max_idx(arr):\n return arr.index(max(arr))\n\n # Helper function to reverse the list up to the given index\n def reverse_list(arr, idx):\n return arr[:idx + 1][::-1] + arr[idx + 1:]\n\n # Main sorting function\n for i in range(len(arr) - 1, 0, -1):\n max_idx = find_max_idx(arr[:i + 1])\n if max_idx != i:\n arr = reverse_list(arr, max_idx)\n arr = reverse_list(arr, i)\n return arr", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(arr):\n n = len(arr)\n for i in range(n - 1, 0, -1):\n max_idx = arr[:i + 1].index(max(arr[:i + 1]))\n if max_idx != i:\n if max_idx != 0:\n arr[:max_idx + 1] = reversed(arr[:max_idx + 1])\n arr[:i + 1] = reversed(arr[:i + 1])\n return arr", "matching_cluster_idx": 3}]}, "Mbpp/166": {"dps": 95.28888888888888, "dps_norm": 59.72222222222222, "pass@1": 18.0, "profiled": [{"solution": "def find_even_pair(nums):\n # Initialize count\n count = 0\n\n # Iterate through all pairs\n for i in range(len(nums)):\n for j in range(i + 1, len(nums)):\n\n # Check if XOR is even\n if (nums[i] ^ nums[j]) % 2 == 0:\n count += 1\n\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(lst):\n \"\"\"Count the number of pairs in a list that XOR to an even number.\"\"\"\n count = 0\n for i in range(len(lst)):\n for j in range(i+1, len(lst)):\n if (lst[i] ^ lst[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(nums):\n even_count = sum(1 for num in nums if num % 2 == 0) # count even numbers\n odd_count = len(nums) - even_count # count odd numbers\n return even_count * (even_count - 1) // 2 + odd_count * (odd_count - 1) // 2", "matching_cluster_idx": 3}, {"solution": "def find_even_pair(numbers):\n count = 0\n for i in range(len(numbers)):\n for j in range(i+1, len(numbers)):\n if (numbers[i] ^ numbers[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(arr):\n even_count = 0\n for i in range(len(arr)):\n for j in range(i+1, len(arr)):\n if (arr[i] ^ arr[j]) % 2 == 0:\n even_count += 1\n return even_count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(lst):\n # Initialize counter\n count = 0\n # Iterate through pairs in the list\n for i in range(len(lst)):\n for j in range(i + 1, len(lst)):\n # If XOR is even, increment counter\n if (lst[i] ^ lst[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(nums):\n count = 0\n for i in range(len(nums)):\n for j in range(i + 1, len(nums)):\n if (nums[i] ^ nums[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(arr):\n even_count = sum(1 for num in arr if num % 2 == 0) # Count even numbers\n odd_count = sum(1 for num in arr if num % 2 != 0) # Count odd numbers\n\n # Two cases can result in an even XOR:\n # 1. Pair of even numbers\n # 2. Pair of odd numbers\n return even_count * (even_count - 1) // 2 + odd_count * (odd_count - 1) // 2", "matching_cluster_idx": 2}, {"solution": "def find_even_pair(numbers):\n even_parity = [num % 2 == 0 for num in numbers]\n return sum(even_parity[i] ^ even_parity[j] == 0 for i in range(len(even_parity)) for j in range(i+1, len(even_parity)))", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(nums):\n count = 0\n for i in range(len(nums)):\n for j in range(i+1, len(nums)):\n if (nums[i] ^ nums[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(numbers):\n # Initialize counters for even and odd numbers\n even_count, odd_count = 0, 0\n\n # Count even and odd numbers\n for num in numbers:\n if num % 2 == 0:\n even_count += 1\n else:\n odd_count += 1\n\n # Calculate pairs that XOR to an even number\n return even_count * (even_count - 1) // 2 + odd_count * (odd_count - 1) // 2", "matching_cluster_idx": 2}, {"solution": "def find_even_pair(numbers):\n count = 0\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n if (numbers[i] ^ numbers[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(lst):\n even_count = 0\n for i in range(len(lst)):\n for j in range(i+1, len(lst)):\n if (lst[i] ^ lst[j]) % 2 == 0:\n even_count += 1\n return even_count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(lst):\n count = 0\n for i in range(len(lst)):\n for j in range(i+1, len(lst)):\n if (lst[i] ^ lst[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(lst):\n # We know that XOR of two even numbers is even,\n # XOR of two odd numbers is even, and XOR of an even and odd number is odd.\n # So we can count the number of even numbers and odd numbers separately,\n # and return the sum of their combinations (even*even + odd*odd).\n\n # Initialize counters for even and odd numbers\n even_count = 0\n odd_count = 0\n\n for num in lst:\n if num % 2 == 0:\n even_count += 1\n else:\n odd_count += 1\n\n # Return the sum of combinations\n return even_count * (even_count - 1) // 2 + odd_count * (odd_count - 1) // 2", "matching_cluster_idx": 3}, {"solution": "def find_even_pair(nums):\n even_count = 0\n for i in range(len(nums)):\n for j in range(i+1, len(nums)):\n if (nums[i] ^ nums[j]) % 2 == 0:\n even_count += 1\n return even_count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(lst):\n \"\"\"\n Counts the number of pairs of integers in a list that xor to an even number.\n\n Args:\n lst (list): List of integers.\n\n Returns:\n int: Number of pairs that xor to an even number.\n \"\"\"\n count = 0\n for i in range(len(lst)):\n for j in range(i+1, len(lst)):\n if (lst[i] ^ lst[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(nums):\n # In order for xor to be even, both numbers must be even or both must be odd\n # We count the frequency of even and odd numbers in the list\n count_even = count_odd = 0\n for num in nums:\n if num % 2 == 0:\n count_even += 1\n else:\n count_odd += 1\n\n # We calculate the number of pairs of even numbers and odd numbers separately,\n # and then we add those two results together. Since the order of choosing\n # two numbers from the list doesn't matter, we use combinations (nC2) formula.\n return count_even * (count_even - 1) // 2 + count_odd * (count_odd - 1) // 2", "matching_cluster_idx": 2}]}, "Mbpp/170": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 53.0, "profiled": [{"solution": "def sum_range_list(numbers, start_index, end_index):\n return sum(numbers[start_index:end_index + 1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(lst, start, end):\n return sum(lst[start:end+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(lst, start, end):\n \"\"\"\n Find the sum of numbers in a list within a range specified by two indices.\n :param lst: List of numbers\n :param start: Start index\n :param end: End index\n :return: Sum of numbers in the specified range\n \"\"\"\n return sum(lst[start:end+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(nums, start, end):\n return sum(nums[start:end+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(lst, start_index, end_index):\n return sum(lst[start_index:end_index+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(numbers, start, end):\n return sum(numbers[start:end+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(lst, start, end):\n return sum(lst[start:end + 1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(lst, start, end):\n \"\"\"\n This function returns the sum of elements in a list between two specific indices (inclusive).\n \"\"\"\n return sum(lst[start:end + 1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(lst, start, end):\n return sum(lst[start:end+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(lst, start_idx, end_idx):\n return sum(lst[start_idx:end_idx+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(lst, start_index, end_index):\n return sum(lst[start_index:end_index+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(nums, start, end):\n return sum(nums[start:end+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(lst, start_idx, end_idx):\n return sum(lst[start_idx:end_idx + 1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(lst, start, end):\n return sum(lst[start:end+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(lst, start, end):\n return sum(lst[start:end+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(lst, start, end):\n \"\"\"\n Calculate the sum of numbers in a list within a specified range.\n\n Args:\n lst (list): The input list of numbers.\n start (int): The start index, inclusive.\n end (int): The end index, inclusive.\n\n Returns:\n int: The sum of the numbers within the specified range.\n \"\"\"\n return sum(lst[start:end+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(lst, start_idx, end_idx):\n \"\"\"\n Find the sum of numbers in a list within a range specified by two indices.\n\n Args:\n lst (list): Input list of numbers\n start_idx (int): Start index\n end_idx (int): End index\n\n Returns:\n int: Sum of numbers in the specified range\n \"\"\"\n return sum(lst[start_idx:end_idx+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(lst, start_index, end_index):\n \"\"\"\n Calculate the sum of numbers in a list within a specific range.\n\n Args:\n lst (List[int]): The input list of integers.\n start_index (int): The starting index in the list.\n end_index (int): The ending index in the list.\n\n Returns:\n int: The sum of numbers in the specified range.\n \"\"\"\n return sum(lst[start_index:end_index + 1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(lst, start, end):\n \"\"\"Return the sum of numbers in a list within the specified range.\"\"\"\n return sum(lst[start:end+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(lst, start, end):\n return sum(lst[start:end+1])", "matching_cluster_idx": 7}]}, "Mbpp/226": {"dps": 76.24031007751938, "dps_norm": 35.0, "pass@1": 64.0, "profiled": [{"solution": "def odd_values_string(input_string):\n \"\"\"Remove characters at odd indexes from a given string.\"\"\"\n return \"\".join([char for idx, char in enumerate(input_string) if idx % 2 == 0])", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(s):\n return ''.join(s[i] for i in range(len(s)) if i % 2 == 0)", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(s):\n return ''.join(s[i] for i in range(0, len(s), 2))", "matching_cluster_idx": 3}, {"solution": "def odd_values_string(s):\n return ''.join([s[i] for i in range(0, len(s), 2)])", "matching_cluster_idx": 3}, {"solution": "def odd_values_string(s):\n \"\"\"\n Remove the characters which have odd index values of a given string.\n :param s: input string\n :return: string with odd indexed characters removed\n \"\"\"\n return ''.join([s[i] for i in range(len(s)) if i % 2 == 0])", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(s):\n return ''.join([s[i] for i in range(0, len(s), 2)])", "matching_cluster_idx": 3}, {"solution": "def odd_values_string(s):\n \"\"\"\n Function to remove characters from a given string which have odd index values.\n \"\"\"\n # By using Python's list comprehension we can achieve this with a single line of code.\n # We start with an empty string and then for each index in the string,\n # if the index is even (not odd) we add the corresponding character to the result.\n return ''.join([s[i] for i in range(0, len(s), 2)])", "matching_cluster_idx": 3}, {"solution": "def odd_values_string(input_str):\n return ''.join([input_str[i] for i in range(0, len(input_str), 2)])", "matching_cluster_idx": 3}, {"solution": "def odd_values_string(input_str):\n return ''.join([input_str[i] for i in range(len(input_str)) if i % 2 == 0])", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(s):\n return \"\".join(c for i, c in enumerate(s) if i % 2 == 0)", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(s):\n return ''.join([s[i] for i in range(0, len(s), 2)])", "matching_cluster_idx": 3}, {"solution": "def odd_values_string(s: str) -> str:\n return ''.join(c for i, c in enumerate(s) if i % 2 == 0)", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(s: str) -> str:\n \"\"\"Removes characters at odd indices from the given string.\"\"\"\n return ''.join(s[i] for i in range(0, len(s), 2))", "matching_cluster_idx": 2}, {"solution": "def odd_values_string(s: str) -> str:\n return ''.join([s[i] for i in range(0, len(s), 2)])", "matching_cluster_idx": 4}, {"solution": "def odd_values_string(s: str) -> str:\n return ''.join([s[i] for i in range(len(s)) if i % 2 == 0])", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(s):\n return ''.join(s[i] for i in range(len(s)) if i % 2 == 0)", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(input_string):\n # Initialize an empty string to store result\n result = ''\n\n # Loop through the string, only add characters with even index\n for i in range(0, len(input_string), 2):\n result += input_string[i]\n\n return result", "matching_cluster_idx": 2}, {"solution": "def odd_values_string(s):\n return ''.join(s[i] for i in range(0, len(s), 2))", "matching_cluster_idx": 3}, {"solution": "def odd_values_string(s):\n \"\"\"\n Removes the characters which have odd index values of a given string.\n \"\"\"\n return ''.join(s[i] for i in range(len(s)) if i % 2 == 0)", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(s):\n return ''.join([c for i, c in enumerate(s) if i % 2 == 0])", "matching_cluster_idx": 0}]}, "Mbpp/230": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def replace_blank(string, char):\n return string.replace(' ', char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(s, c):\n \"\"\"Replaces blanks with a given character in a string.\"\"\"\n return s.replace(\" \", c)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string, replace_char):\n \"\"\"\n This function takes a string and a character, replaces blank spaces in the string with the given character,\n and returns the modified string.\n \"\"\"\n return input_string.replace(' ', replace_char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(string, char):\n \"\"\"\n Replaces blank spaces in the input string with a given character.\n \"\"\"\n return string.replace(' ', char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(text, char):\n \"\"\"Replace blank spaces in the given string with the provided character.\n\n Args:\n text (str): The input string.\n char (str): The character to replace spaces with.\n\n Returns:\n str: The modified string.\n \"\"\"\n return text.replace(' ', char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(s, c):\n return s.replace(' ', c)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(s, c):\n return s.replace(' ', c)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string, character):\n return input_string.replace(\" \", character)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(s: str, c: str) -> str:\n \"\"\"Replace blank spaces in a string with a given character.\n\n Args:\n s (str): Input string.\n c (str): Character to replace spaces.\n\n Returns:\n str: String with spaces replaced by the given character.\n \"\"\"\n return s.replace(' ', c)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(text: str, char: str) -> str:\n \"\"\"\n This function takes in a string and character, replaces blank spaces in the string with the character,\n and returns the resulting string.\n \"\"\"\n return text.replace(' ', char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(s, ch):\n \"\"\"\n Replaces blank spaces in the input string with the given character.\n\n Args:\n s (str): Input string.\n ch (str): Character to replace blank spaces.\n\n Returns:\n str: String with blank spaces replaced by the given character.\n \"\"\"\n return s.replace(\" \", ch)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(s, c):\n return s.replace(' ', c)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(s, c):\n \"\"\"Replaces blank spaces in the string with the given character.\"\"\"\n return s.replace(' ', c)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(text, char):\n \"\"\"\n Replace blank spaces in the given text with the provided character.\n\n :param text: Input string\n :param char: Character to replace spaces with\n :return: Modified string\n \"\"\"\n return text.replace(' ', char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(s: str, c: str) -> str:\n \"\"\"Replace spaces in the given string with the provided character.\n\n Args:\n s (str): The input string\n c (str): The character to replace spaces with\n\n Returns:\n str: The modified string\n \"\"\"\n return s.replace(\" \", c)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(string, char):\n # Use the replace() function to substitute blank spaces with the character\n return string.replace(\" \", char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(s, c):\n return s.replace(\" \", c)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(s: str, c: str) -> str:\n \"\"\"\n Replace blank spaces in a given string with a specified character.\n \"\"\"\n return s.replace(\" \", c)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(s: str, c: str) -> str:\n \"\"\"Replace all spaces in a string with a given character.\"\"\"\n return s.replace(\" \", c)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(string, character):\n \"\"\"\n Replace blank spaces in the given string with the provided character.\n\n :param string: The input string\n :param character: The character to replace spaces with\n :return: The modified string\n \"\"\"\n return string.replace(\" \", character)", "matching_cluster_idx": 7}]}, "Mbpp/239": {"dps": null, "dps_norm": null, "pass@1": 2.0, "profiled": []}, "Mbpp/240": {"dps": 78.04878048780489, "dps_norm": 86.66666666666666, "pass@1": 21.0, "profiled": [{"solution": "def replace_list(lst1, lst2):\n lst1[-1:] = lst2\n return lst1", "matching_cluster_idx": 7}, {"solution": "def replace_list(lst1, lst2):\n lst1[-1:] = lst2\n return lst1", "matching_cluster_idx": 7}, {"solution": "def replace_list(lst1, lst2):\n # Check if the first list is not empty\n if lst1:\n # Replace the last element of the first list with the second list\n lst1[-1:] = lst2\n return lst1", "matching_cluster_idx": 7}, {"solution": "def replace_list(list1, list2):\n # Copy the first list\n modified_list = list1[:]\n # Replace the last element of the first list with elements of the second list\n modified_list[-1:] = list2\n return modified_list", "matching_cluster_idx": 6}, {"solution": "def replace_list(lst1, lst2):\n lst1[-1:] = lst2\n return lst1", "matching_cluster_idx": 7}, {"solution": "def replace_list(lst1, lst2):\n # Remove the last element from the first list\n lst1 = lst1[:-1]\n # Append the elements of the second list to the first list\n lst1.extend(lst2)\n return lst1", "matching_cluster_idx": 6}, {"solution": "def replace_list(lst1, lst2):\n # Get the last element of the first list\n last_element = lst1.pop()\n # Extend the first list with the second list starting from the index of the last element\n lst1.extend(lst2)\n return lst1", "matching_cluster_idx": 8}, {"solution": "def replace_list(lst1, lst2):\n lst1[-1:] = lst2\n return lst1", "matching_cluster_idx": 7}, {"solution": "def replace_list(lst1, lst2):\n # Replace the last element of lst1 with lst2\n lst1[-1:] = lst2\n return lst1", "matching_cluster_idx": 7}, {"solution": "def replace_list(list1, list2):\n # Make sure list1 has at least one element\n if not list1:\n return list1\n # Replace the last element of list1 with the elements of list2\n list1[-1:] = list2\n return list1", "matching_cluster_idx": 7}, {"solution": "def replace_list(lst1, lst2):\n if len(lst1) == 0:\n return lst2\n else:\n return lst1[:-1] + lst2", "matching_cluster_idx": 5}, {"solution": "def replace_list(lst1, lst2):\n if lst1:\n lst1[-1:] = lst2\n else:\n return lst2\n return lst1", "matching_cluster_idx": 7}, {"solution": "def replace_list(lst1, lst2):\n if len(lst1) < 1:\n return lst2\n return lst1[:-1] + lst2", "matching_cluster_idx": 5}, {"solution": "def replace_list(lst1, lst2):\n if not lst1:\n return lst2\n lst1[-1:] = lst2\n return lst1", "matching_cluster_idx": 7}, {"solution": "def replace_list(list1, list2):\n # Replaces the last element of list1 with elements of list2\n if list1:\n list1[-1:] = list2\n else:\n list1 = list2\n return list1", "matching_cluster_idx": 7}, {"solution": "def replace_list(lst1, lst2):\n lst1[-1:] = lst2\n return lst1", "matching_cluster_idx": 7}, {"solution": "def replace_list(list1, list2):\n list1[-1:] = list2\n return list1", "matching_cluster_idx": 7}, {"solution": "def replace_list(lst1, lst2):\n # Remove the last element of lst1\n lst1.pop()\n # Extend lst1 with lst2\n lst1.extend(lst2)\n return lst1", "matching_cluster_idx": 8}, {"solution": "def replace_list(lst1, lst2):\n # Check if lst1 is not empty\n if lst1:\n lst1[-1:] = lst2 # Replace the last element of lst1 with lst2\n else:\n # If lst1 is empty, return lst2 as it is\n lst1 = lst2\n return lst1", "matching_cluster_idx": 7}, {"solution": "def replace_list(lst1, lst2):\n \"\"\"Replaces the last element of the first list with the elements of the second list.\"\"\"\n lst1[-1:] = lst2\n return lst1", "matching_cluster_idx": 7}]}, "Mbpp/251": {"dps": null, "dps_norm": null, "pass@1": 9.0, "profiled": []}, "Mbpp/256": {"dps": null, "dps_norm": null, "pass@1": 5.0, "profiled": []}, "Mbpp/265": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 11.0, "profiled": [{"solution": "def list_split(lst, n):\n \"\"\"\n This function takes a list and an integer n and splits the list into lists of every nth element.\n \"\"\"\n return [lst[i::n] for i in range(n)]", "matching_cluster_idx": 5}, {"solution": "def list_split(lst, n):\n return [lst[i::n] for i in range(n)]", "matching_cluster_idx": 5}, {"solution": "def list_split(lst, n):\n return [lst[i::n] for i in range(n)]", "matching_cluster_idx": 5}, {"solution": "def list_split(lst, n):\n return [lst[i::n] for i in range(n)]", "matching_cluster_idx": 5}, {"solution": "def list_split(lst, n):\n # Use list comprehension to create new lists every 'n' elements\n return [lst[i::n] for i in range(n)]", "matching_cluster_idx": 5}, {"solution": "def list_split(lst, n):\n return [lst[i::n] for i in range(n)]", "matching_cluster_idx": 5}, {"solution": "def list_split(lst, n):\n return [lst[i::n] for i in range(n)]", "matching_cluster_idx": 5}, {"solution": "def list_split(lst, n):\n return [lst[i::n] for i in range(n)]", "matching_cluster_idx": 5}, {"solution": "def list_split(lst, n):\n return [lst[i::n] for i in range(n)]", "matching_cluster_idx": 5}, {"solution": "def list_split(lst, n):\n return [lst[i::n] for i in range(n)]", "matching_cluster_idx": 5}, {"solution": "def list_split(lst, n):\n return [lst[i::n] for i in range(n)]", "matching_cluster_idx": 5}]}, "Mbpp/281": {"dps": 94.0, "dps_norm": 81.81818181818181, "pass@1": 90.0, "profiled": [{"solution": "def all_unique(lst):\n \"\"\"\n Check if all elements in a list are unique.\n\n Parameters:\n lst (list): A list of elements to check.\n\n Returns:\n bool: True if all elements are unique, False otherwise.\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n # Using a set data structure to check for unique elements\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n Check if all elements in a list are unique.\n\n Args:\n lst (list): List to check.\n\n Returns:\n bool: True if all elements are unique, False otherwise.\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n Check if all elements in a list are unique.\n\n :param lst: A list of elements.\n :return: True if all elements are unique, False otherwise.\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"Check if all elements in the list are unique.\n\n Args:\n lst (list): The list to check.\n\n Returns:\n bool: True if all elements are unique, False otherwise.\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(input_list):\n # Convert list to set and compare the lengths\n return len(input_list) == len(set(input_list))", "matching_cluster_idx": 8}, {"solution": "def all_unique(input_list):\n # Create a set from the list. If the list contains duplicate elements, a set will contain only one instance of them.\n # Therefore, the size of the set will be less than the size of the list.\n return len(set(input_list)) == len(input_list)", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n Check if all elements in a list are unique.\n\n Args:\n lst (list): Input list\n\n Returns:\n bool: True if all elements are unique, False otherwise\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n # Using a set to check uniqueness because it automatically removes duplicates\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n Check if all elements in a list are unique.\n\n Args:\n lst (list): Input list.\n\n Returns:\n bool: True if all elements are unique, False otherwise.\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"Check if all elements in the list are unique.\"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n Check if all elements in a list are unique.\n\n Args:\n lst (list): Input list\n\n Returns:\n bool: True if all elements are unique, False otherwise\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n Check if all elements in the given list are unique.\n :param lst: list to be checked\n :return: True if all elements are unique, False otherwise\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(elements):\n \"\"\"\n Checks if all elements in a list are unique.\n\n Args:\n elements (List): The list of elements to check.\n\n Returns:\n bool: True if all elements are unique, False otherwise.\n \"\"\"\n return len(elements) == len(set(elements))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"Check if all elements in a list are unique.\"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n Check if all elements in a list are unique.\n\n Args:\n lst (list): input list\n\n Returns:\n bool: True if all elements are unique, False otherwise\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}]}, "Mbpp/296": {"dps": 64.1025641025641, "dps_norm": 83.33333333333334, "pass@1": 57.0, "profiled": [{"solution": "def get_Inv_Count(arr):\n merge_sort_count = 0\n\n def merge_sort(arr):\n nonlocal merge_sort_count\n if len(arr) <= 1:\n return arr\n\n mid = len(arr) // 2\n left = arr[:mid]\n right = arr[mid:]\n\n left = merge_sort(left)\n right = merge_sort(right)\n\n return merge(left, right)\n\n def merge(left, right):\n nonlocal merge_sort_count\n merged = []\n while left and right:\n if left[0] > right[0]:\n merge_sort_count += len(left)\n merged.append(right.pop(0))\n else:\n merged.append(left.pop(0))\n merged.extend(left if left else right)\n return merged\n\n merge_sort(arr)\n return merge_sort_count", "matching_cluster_idx": 5}, {"solution": "def get_Inv_Count(arr):\n \"\"\"\n Count inversions in an array.\n\n An inversion is defined as a pair of elements where the first element is larger than the second.\n\n Args:\n arr (list of integers): Input array.\n\n Returns:\n int: Number of inversions in the array.\n \"\"\"\n inv_count = 0\n\n for i in range(len(arr)):\n for j in range(i + 1, len(arr)):\n if arr[i] > arr[j]:\n inv_count += 1\n\n return inv_count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n def merge_sort_count(arr):\n if len(arr) <= 1:\n return arr, 0\n\n mid = len(arr) // 2\n left, left_inv = merge_sort_count(arr[:mid])\n right, right_inv = merge_sort_count(arr[mid:])\n\n merged, merge_inv = merge_count(left, right)\n return merged, left_inv + right_inv + merge_inv\n\n def merge_count(left, right):\n inv = 0\n result = []\n i = j = 0\n\n while i < len(left) and j < len(right):\n if left[i] <= right[j]:\n result.append(left[i])\n i += 1\n else:\n result.append(right[j])\n inv += len(left) - i\n j += 1\n\n result.extend(left[i:])\n result.extend(right[j:])\n return result, inv\n\n _, inv = merge_sort_count(arr)\n return inv", "matching_cluster_idx": 5}, {"solution": "def get_Inv_Count(arr):\n inv_count = 0\n for i in range(len(arr)):\n for j in range(i+1, len(arr)):\n if arr[i] > arr[j]:\n inv_count += 1\n return inv_count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n # Merge sort approach to count inversions\n if len(arr) <= 1:\n return 0\n\n mid = len(arr) // 2\n left = arr[:mid]\n right = arr[mid:]\n\n inv_count = (get_Inv_Count(left) +\n get_Inv_Count(right))\n\n i = j = k = 0\n\n # Counting inversions during merge\n while i < len(left) and j < len(right):\n if left[i] <= right[j]:\n arr[k] = left[i]\n i += 1\n else:\n arr[k] = right[j]\n j += 1\n inv_count += len(left) - i\n k += 1\n\n # Copying remaining elements\n while i < len(left):\n arr[k] = left[i]\n i += 1\n k += 1\n\n while j < len(right):\n arr[k] = right[j]\n j += 1\n k += 1\n\n return inv_count", "matching_cluster_idx": 5}, {"solution": "def merge_sort(arr):\n if len(arr) <= 1:\n return arr, 0\n\n mid = len(arr) // 2\n left, left_inv = merge_sort(arr[:mid])\n right, right_inv = merge_sort(arr[mid:])\n merged, merge_inv = merge(left, right)\n\n return merged, left_inv + right_inv + merge_inv\ndef merge(left, right):\n merged = []\n inversions = 0\n i = j = 0\n\n while i < len(left) and j < len(right):\n if left[i] <= right[j]:\n merged.append(left[i])\n i += 1\n else:\n merged.append(right[j])\n j += 1\n inversions += len(left) - i\n\n merged.extend(left[i:])\n merged.extend(right[j:])\n\n return merged, inversions\ndef get_Inv_Count(arr):\n _, inversions = merge_sort(arr)\n return inversions", "matching_cluster_idx": 5}, {"solution": "def get_Inv_Count(arr):\n # Initialize count and merge sort\n inv_count = 0\n temp = arr.copy()\n\n # Core merge sort function\n def merge_sort(arr, start, end):\n nonlocal inv_count, temp\n if end - start > 1:\n mid = start + (end - start) // 2\n merge_sort(arr, start, mid)\n merge_sort(arr, mid, end)\n merge(arr, start, mid, end)\n\n # Merge function for merge sort\n def merge(arr, start, mid, end):\n nonlocal inv_count, temp\n left = arr[start:mid]\n right = arr[mid:end]\n\n i = j = 0\n for k in range(start, end):\n if j >= len(right) or (i < len(left) and left[i] <= right[j]):\n arr[k] = left[i]\n i += 1\n else:\n arr[k] = right[j]\n j += 1\n inv_count += len(left) - i # Count inversions\n\n # Start merge sort from the whole array\n merge_sort(temp, 0, len(temp))\n\n return inv_count", "matching_cluster_idx": 5}, {"solution": "def get_Inv_Count(arr):\n inv_count = 0\n\n for i in range(len(arr)):\n for j in range(i + 1, len(arr)):\n if arr[i] > arr[j]:\n inv_count += 1\n\n return inv_count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n # Merge sort based approach to count inversions\n # Similar to the solution provided in the problem statement\n temp_arr = [0] * len(arr)\n return merge_sort(arr, temp_arr, 0, len(arr) - 1)\ndef merge_sort(arr, temp_arr, left, right):\n inv_count = 0\n if right > left:\n mid = (right + left) // 2\n\n inv_count = merge_sort(arr, temp_arr, left, mid)\n inv_count += merge_sort(arr, temp_arr, mid + 1, right)\n\n inv_count += merge(arr, temp_arr, left, mid, right)\n\n return inv_count\ndef merge(arr, temp_arr, left, mid, right):\n i = left\n j = mid + 1\n k = left\n inv_count = 0\n\n while i <= mid and j <= right:\n if arr[i] <= arr[j]:\n temp_arr[k] = arr[i]\n i += 1\n else:\n temp_arr[k] = arr[j]\n inv_count += mid - i + 1\n j += 1\n k += 1\n\n while i <= mid:\n temp_arr[k] = arr[i]\n i += 1\n k += 1\n\n while j <= right:\n temp_arr[k] = arr[j]\n j += 1\n k += 1\n\n for i in range(left, right + 1):\n arr[i] = temp_arr[i]\n\n return inv_count", "matching_cluster_idx": 5}, {"solution": "def get_Inv_Count(arr):\n inv_count = 0\n\n for i in range(len(arr)):\n for j in range(i+1, len(arr)):\n if arr[i] > arr[j]:\n inv_count += 1\n\n return inv_count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n # Initialize inversion count\n inv_count = 0\n\n # Calculate the number of inversions\n for i in range(len(arr)):\n for j in range(i + 1, len(arr)):\n if arr[i] > arr[j]:\n inv_count += 1\n\n return inv_count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n # Merge sort based approach to count inversions\n # The idea is to divide the array in two halves and\n # find the number of inversions in each half and\n # then combine the two halves in a way that we can\n # keep track of inversions\n def merge_sort(arr):\n if len(arr) <= 1:\n return arr, 0\n\n mid = len(arr) // 2\n left_half, inv_left = merge_sort(arr[:mid])\n right_half, inv_right = merge_sort(arr[mid:])\n\n merged, inv_merge = merge(left_half, right_half)\n inv_total = inv_left + inv_right + inv_merge\n\n return merged, inv_total\n\n def merge(left, right):\n merged = []\n inv = 0\n i = j = 0\n\n while i < len(left) and j < len(right):\n if left[i] <= right[j]:\n merged.append(left[i])\n i += 1\n else:\n merged.append(right[j])\n inv += len(left) - i\n j += 1\n\n merged.extend(left[i:])\n merged.extend(right[j:])\n\n return merged, inv\n\n _, inv = merge_sort(arr)\n\n return inv", "matching_cluster_idx": 5}, {"solution": "def get_Inv_Count(arr):\n # Merge sort function to count inversions\n def merge_sort(arr):\n if len(arr) <= 1:\n return arr, 0\n\n mid = len(arr) // 2\n left, left_inv = merge_sort(arr[:mid])\n right, right_inv = merge_sort(arr[mid:])\n\n merge_inv = 0\n sorted_arr = []\n i = j = 0\n\n while i < len(left) and j < len(right):\n if left[i] <= right[j]:\n sorted_arr.append(left[i])\n i += 1\n else:\n sorted_arr.append(right[j])\n merge_inv += len(left) - i\n j += 1\n\n sorted_arr += left[i:]\n sorted_arr += right[j:]\n\n return sorted_arr, merge_inv + left_inv + right_inv\n\n # Call merge_sort function\n _, inv_count = merge_sort(arr)\n\n return inv_count", "matching_cluster_idx": 5}, {"solution": "def get_Inv_Count(arr):\n inv_count = 0\n for i in range(len(arr)):\n for j in range(i+1, len(arr)):\n if arr[i] > arr[j]:\n inv_count += 1\n return inv_count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n inv_count = 0\n\n for i in range(len(arr)):\n for j in range(i+1, len(arr)):\n if arr[i] > arr[j]:\n inv_count += 1\n\n return inv_count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n inv_count = 0\n for i in range(len(arr)):\n for j in range(i + 1, len(arr)):\n if arr[i] > arr[j]:\n inv_count += 1\n return inv_count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n \"\"\"\n Function to count inversions in an array\n :param arr: list of integers\n :return: integer, number of inversions\n \"\"\"\n # length of the array\n n = len(arr)\n\n # To store the final count of inversions\n inv_count = 0\n\n for i in range(n):\n for j in range(i+1, n):\n # Count the inversion\n if arr[i] > arr[j]:\n inv_count += 1\n\n return inv_count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n # Initialize inversion count\n inv_count = 0\n\n # Traverse through all array elements\n for i in range(len(arr)):\n for j in range(i+1, len(arr)):\n # If this pair is found to be in increasing order ( inverter ), increment the count\n if arr[i] > arr[j]:\n inv_count += 1\n\n return inv_count", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n # Merge sort based solution to find inversions\n def merge(arr, l, m, r):\n inv_count = 0\n n1 = m - l + 1\n n2 = r - m\n L = [0] * n1\n R = [0] * n2\n for i in range(n1):\n L[i] = arr[l + i]\n for i in range(n2):\n R[i] = arr[m + 1 + i]\n i = j = 0\n k = l\n while i < n1 and j < n2:\n if L[i] <= R[j]:\n arr[k] = L[i]\n i += 1\n else:\n arr[k] = R[j]\n inv_count += n1 - i\n j += 1\n k += 1\n while i < n1:\n arr[k] = L[i]\n i += 1\n k += 1\n while j < n2:\n arr[k] = R[j]\n j += 1\n k += 1\n return inv_count\n\n def merge_sort(arr, l, r):\n inv_count = 0\n if r > l:\n m = (l + r) // 2\n inv_count += merge_sort(arr, l, m)\n inv_count += merge_sort(arr, m + 1, r)\n inv_count += merge(arr, l, m, r)\n return inv_count\n\n return merge_sort(arr, 0, len(arr) - 1)", "matching_cluster_idx": 5}, {"solution": "def get_Inv_Count(arr):\n # helper function to merge two sorted arrays and count inversions\n def merge(arr1, arr2, inv_count):\n merged = []\n i = j = 0\n while i < len(arr1) and j < len(arr2):\n if arr1[i] <= arr2[j]:\n merged.append(arr1[i])\n i += 1\n else:\n merged.append(arr2[j])\n inv_count[0] += len(arr1) - i # count inversions\n j += 1\n merged.extend(arr1[i:])\n merged.extend(arr2[j:])\n return merged, inv_count\n\n # merge sort algorithm to count inversions\n def merge_sort(arr):\n if len(arr) <= 1:\n return arr, [0]\n mid = len(arr) // 2\n left, left_inv_count = merge_sort(arr[:mid])\n right, right_inv_count = merge_sort(arr[mid:])\n merged, total_inv_count = merge(left, right, [0])\n return merged, [left_inv_count[0] + right_inv_count[0] + total_inv_count[0]]\n\n arr, inv_count = merge_sort(arr)\n return inv_count[0]", "matching_cluster_idx": 5}]}, "Mbpp/308": {"dps": 67.79310344827587, "dps_norm": 59.16666666666667, "pass@1": 41.0, "profiled": [{"solution": "from itertools import product\ndef large_product(lst1, lst2, n):\n # Get all combinations of factors from lst1 and lst2\n combinations = [a * b for a, b in product(lst1, lst2)]\n\n # Sort the combinations in descending order\n combinations.sort(reverse=True)\n\n # Return the n largest products\n return combinations[:n]", "matching_cluster_idx": 3}, {"solution": "from itertools import product\nfrom heapq import nlargest\ndef large_product(list1, list2, n):\n # Generate all possible products from one factor from each list\n products = [a * b for a, b in product(list1, list2)]\n # Find the largest n products\n largest_products = nlargest(n, products)\n return largest_products", "matching_cluster_idx": 3}, {"solution": "from itertools import product\nfrom typing import List, Tuple\ndef large_product(lst1: List[int], lst2: List[int], n: int) -> List[int]:\n # Create pairs of factors\n pairs = product(lst1, lst2)\n # Calculate products\n products = [a*b for a, b in pairs]\n # Sort products in descending order and return the largest n\n return sorted(products, reverse=True)[:n]", "matching_cluster_idx": 3}, {"solution": "from operator import mul\nfrom functools import reduce\ndef large_product(l1, l2, n):\n # Make sure the inputs are lists\n assert isinstance(l1, list) and isinstance(l2, list), \"Both inputs should be lists.\"\n\n # Calculate the Cartesian product of the two lists\n products = [(i, j) for i in l1 for j in l2]\n\n # Calculate the product for each pair and sort the result in descending order\n products.sort(key=lambda x: reduce(mul, x), reverse=True)\n\n # Return the first 'n' largest products\n return [reduce(mul, product) for product in products[:n]]", "matching_cluster_idx": 2}, {"solution": "from itertools import product\nfrom operator import mul\nfrom functools import reduce\ndef large_product(list1, list2, n):\n # Generate all possible products of elements taken from each list\n products = [reduce(mul, p) for p in product(list1, list2)]\n\n # Sort the products in descending order and return the top n\n return sorted(products, reverse=True)[:n]", "matching_cluster_idx": 2}, {"solution": "def large_product(list1, list2, num):\n # Combine two lists and sort them in descending order\n products = sorted((i * j for i in list1 for j in list2), reverse=True)\n\n # Return the specified number of largest products\n return products[:num]", "matching_cluster_idx": 3}, {"solution": "from itertools import product\nfrom operator import mul\ndef large_product(list1, list2, num_products):\n # Combine the two lists using Cartesian product\n products = [mul(a, b) for a, b in product(list1, list2)]\n\n # Sort the products in descending order and return the first 'num_products' items\n return sorted(products, reverse=True)[:num_products]", "matching_cluster_idx": 2}, {"solution": "from itertools import product\ndef large_product(list1, list2, n):\n # Multiply each pair of numbers from the two lists\n products = [a * b for a, b in product(list1, list2)]\n\n # Sort the products in descending order\n sorted_products = sorted(products, reverse=True)\n\n # Return the top n products\n return sorted_products[:n]", "matching_cluster_idx": 3}, {"solution": "from itertools import product\ndef large_product(nums1, nums2, k):\n # Get all possible products\n products = [(a * b, a, b) for a, b in product(nums1, nums2)]\n\n # Sort by product value in descending order and take the top k\n top_k_products = sorted(products, reverse=True)[:k]\n\n # Extract the product values\n results = [product[0] for product in top_k_products]\n\n return results", "matching_cluster_idx": 2}, {"solution": "from typing import List, Tuple\ndef large_product(list1: List[int], list2: List[int], n: int) -> List[int]:\n # Create a list of tuples with products and indices\n products = [(list1[i] * list2[j], i, j) for i in range(len(list1)) for j in range(len(list2))]\n\n # Sort the products in descending order\n products.sort(reverse=True)\n\n # Return the first n products\n return [products[i][0] for i in range(n)]", "matching_cluster_idx": 2}, {"solution": "from typing import List\ndef large_product(nums1: List[int], nums2: List[int], k: int) -> List[int]:\n # Multiply each element from first list with each element from second list\n products = [num1 * num2 for num1 in nums1 for num2 in nums2]\n\n # Sort products in descending order and select top k\n return sorted(products, reverse=True)[:k]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n # Ensure n is not greater than the number of elements in both lists\n assert n <= min(len(list1), len(list2)), \"n cannot be greater than the number of elements in both lists\"\n\n # Initialize a list to store the products\n products = []\n\n # Generate all possible products from one element in list1 and one in list2\n for i in range(len(list1)):\n for j in range(len(list2)):\n products.append(list1[i] * list2[j])\n\n # Sort the products in descending order and return the top n products\n products.sort(reverse=True)\n return products[:n]", "matching_cluster_idx": 2}, {"solution": "def large_product(lst1, lst2, k):\n # Combine the two lists into a single list\n combined = [(a, b) for a in lst1 for b in lst2]\n # Sort the combined list by the product of each pair in descending order\n sorted_combined = sorted(combined, key=lambda x: x[0] * x[1], reverse=True)\n # Return the specified number of largest products\n return [pair[0] * pair[1] for pair in sorted_combined[:k]]", "matching_cluster_idx": 2}, {"solution": "from itertools import product\nfrom operator import mul\ndef large_product(list1, list2, k):\n # Create a list of products from all combinations of elements from both lists\n products = [a * b for a, b in product(list1, list2)]\n\n # Sort the products in descending order and return the first k largest products\n return sorted(products, reverse=True)[:k]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n # Handle edge cases\n if not list1 or not list2 or n <= 0:\n return []\n\n # Create a list of tuples, each containing a product and its corresponding pair of indices\n products = [(list1[i] * list2[j], i, j) for i in range(len(list1)) for j in range(len(list2))]\n\n # Sort the products in descending order\n products.sort(reverse=True)\n\n # Return the n largest products\n return [products[i][0] for i in range(n)]", "matching_cluster_idx": 2}, {"solution": "from functools import reduce\ndef large_product(lst1, lst2, k):\n # Sort the lists in reverse order\n lst1.sort(reverse=True)\n lst2.sort(reverse=True)\n\n # Generate all possible products and store them in a list\n products = [x * y for x in lst1 for y in lst2]\n\n # Sort the list of products in reverse order\n products.sort(reverse=True)\n\n # Return the k largest products\n return products[:k]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n # Get all possible products\n products = [i * j for i in list1 for j in list2]\n\n # Sort products in descending order and return the top n products\n return sorted(products, reverse=True)[:n]", "matching_cluster_idx": 3}, {"solution": "from itertools import product\nfrom heapq import nlargest\ndef large_product(list1, list2, n):\n # Create all possible products from elements of both lists\n products = [a * b for a, b in product(list1, list2)]\n\n # Get the n largest products\n return nlargest(n, products)", "matching_cluster_idx": 3}, {"solution": "from typing import List, Tuple\ndef large_product(list1: List[int], list2: List[int], k: int) -> List[int]:\n # Get all possible products from multiplying one number from each list\n products = [a * b for a in list1 for b in list2]\n\n # Sort the products in descending order and return the first k\n return sorted(products, reverse=True)[:k]", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef large_product(lst1: List[int], lst2: List[int], n: int) -> List[int]:\n # Create a list of tuples, each containing the product of two numbers from lst1 and lst2\n products = [(a * b, a, b) for a in lst1 for b in lst2]\n\n # Sort the list of tuples by the first element (the product) in descending order\n products.sort(reverse=True)\n\n # Return the first n elements (products and their corresponding factors)\n return [p for p, _, _ in products[:n]]", "matching_cluster_idx": 2}]}, "Mbpp/392": {"dps": 80.02347417840376, "dps_norm": 90.0, "pass@1": 30.0, "profiled": [{"solution": "def get_max_sum(n):\n memo = {1: 1, 2: 2, 3: 3, 4: 4, 5: 5}\n\n def helper(n):\n if n < 1:\n return 0\n if n in memo:\n return memo[n]\n memo[n] = max(helper(n // 2) + helper(n // 3) + helper(n // 4) + helper(n // 5), n)\n return memo[n]\n\n return helper(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n dp = [0] * (n + 1)\n for i in range(1, n + 1):\n dp[i] = max(dp[i // 2] + dp[i // 3] + dp[i // 4] + dp[i // 5], i)\n return dp[n]", "matching_cluster_idx": 10}, {"solution": "def get_max_sum(n):\n memo = {}\n\n def helper(n):\n if n < 2:\n return n\n\n if n in memo:\n return memo[n]\n\n result = max(\n helper(n // 2) + helper(n // 3) + helper(n // 4) + helper(n // 5),\n n\n )\n memo[n] = result\n return result\n\n return helper(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n # Helper function to find max sum using given equation\n def helper(memo, n):\n if n < 2:\n return n\n if n in memo:\n return memo[n]\n memo[n] = max(helper(memo, n//2) + helper(memo, n//3) + helper(memo, n//4) + helper(memo, n//5), n)\n return memo[n]\n\n # Initialize a memoization dictionary\n memo = {}\n # Call the helper function\n return helper(memo, n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n # base case: for n <= 5, the maximum sum is just n itself\n if n <= 5:\n return n\n\n # Initialize a list to store the maximum sum for each number up to n\n dp = [0] * (n + 1)\n dp[1] = 1\n dp[2] = 2\n dp[3] = 3\n dp[4] = 4\n dp[5] = 5\n\n for i in range(6, n + 1):\n dp[i] = max(dp[i // 2] + dp[i // 3] + dp[i // 4] + dp[i // 5], i)\n\n return dp[n]", "matching_cluster_idx": 10}, {"solution": "def get_max_sum(n):\n if n < 1:\n return 0\n\n max_sum = [0] * (n + 1)\n max_sum[1] = 1\n\n for i in range(2, n + 1):\n max_sum[i] = max(max_sum[i//2] + max_sum[i//3] + max_sum[i//4] + max_sum[i//5], i)\n\n return max_sum[n]", "matching_cluster_idx": 10}, {"solution": "def get_max_sum(n):\n # DP table to store results of subproblems\n dp = [0] * (n + 1)\n # Base case initialization\n for i in range(1, n + 1):\n dp[i] = max(dp[i//2] + dp[i//3] + dp[i//4] + dp[i//5], i)\n return dp[n]", "matching_cluster_idx": 10}, {"solution": "def get_max_sum(n):\n def f(x):\n if x <= 2:\n return x\n else:\n return max(f(x // 2) + f(x // 3) + f(x // 4) + f(x // 5), x)\n\n return f(n)", "matching_cluster_idx": 5}, {"solution": "def get_max_sum(n):\n def helper(n):\n if n in memo:\n return memo[n]\n\n if n <= 5:\n return n\n\n res = max(helper(n // 2) + helper(n // 3) + helper(n // 4) + helper(n // 5), n)\n\n memo[n] = res\n return res\n\n memo = {}\n return helper(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n # Initialize a dictionary to store calculated sums for memoization\n memo = {}\n\n def f(n):\n if n < 2:\n return n\n if n in memo:\n return memo[n]\n\n # Calculate the maximum sum for n using the given equation\n max_sum = max(\n (f(n // 2) + f(n // 3) + f(n // 4) + f(n // 5)),\n n\n )\n memo[n] = max_sum\n return max_sum\n\n return f(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n, memo={}):\n if n < 2:\n return n\n if n in memo:\n return memo[n]\n memo[n] = max(\n get_max_sum(n // 2, memo) + get_max_sum(n // 3, memo) + get_max_sum(n // 4, memo) + get_max_sum(n // 5, memo),\n n\n )\n return memo[n]", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n # Base case: if n is less than 6, return n as the maximum sum\n if n < 6:\n return n\n\n # List to store maximum sum for each number up to n\n max_sums = [0] * (n+1)\n max_sums[1] = 1\n max_sums[2] = 2\n max_sums[3] = 3\n max_sums[4] = 4\n max_sums[5] = 5\n\n # Compute maximum sum for numbers from 6 to n\n for i in range(6, n+1):\n # Find the maximum value of (f(i/2) + f(i/3) + f(i/4) + f(i/5)) + i\n max_sums[i] = max(max_sums[i//2] + max_sums[i//3] + max_sums[i//4] + max_sums[i//5], i)\n\n return max_sums[n]", "matching_cluster_idx": 10}, {"solution": "def get_max_sum(n):\n def memoize(function):\n memo = {}\n def helper(x):\n if x not in memo:\n memo[x] = function(x)\n return memo[x]\n return helper\n\n @memoize\n def f(x):\n if x <= 5:\n return x\n return max(f(x//2) + f(x//3) + f(x//4) + f(x//5), x)\n\n return f(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n # Memoization to store results of subproblems\n memo = {}\n\n def max_sum(n):\n # Base case: n must be greater than 5 for the function to make sense\n if n <= 5:\n return n\n # If we've already solved this subproblem, return the memoized result\n elif n in memo:\n return memo[n]\n else:\n # Calculate the maximum sum using the given equation and store the result\n memo[n] = max(max_sum(n // 2) + max_sum(n // 3) + max_sum(n // 4) + max_sum(n // 5), n)\n return memo[n]\n\n return max_sum(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n, memo={}):\n if n in memo:\n return memo[n]\n\n if n <= 2:\n result = n\n else:\n result = max((get_max_sum(n//2) + get_max_sum(n//3) + get_max_sum(n//4) + get_max_sum(n//5)), n)\n\n memo[n] = result\n return result", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n # Initialize a list to store the maximum sum for each number up to n\n max_sums = [0] * (n + 1)\n\n # Calculate the maximum sum for each number\n for i in range(1, n + 1):\n max_sums[i] = max(max_sums[i // 2] + max_sums[i // 3] + max_sums[i // 4] + max_sums[i // 5], i)\n\n # Return the maximum sum for n\n return max_sums[n]", "matching_cluster_idx": 10}, {"solution": "def get_max_sum(n):\n dp = [0] * (n+1)\n for i in range(1, n+1):\n dp[i] = max(i, dp[i//2] + dp[i//3] + dp[i//4] + dp[i//5])\n return dp[n]", "matching_cluster_idx": 10}, {"solution": "def get_max_sum(n, memo={}):\n if n in memo:\n return memo[n]\n if n <= 5:\n return n\n result = max(\n get_max_sum(n//2, memo) + get_max_sum(n//3, memo) + get_max_sum(n//4, memo) + get_max_sum(n//5, memo),\n n\n )\n memo[n] = result\n return result", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n # Memoization to store calculated results\n memo = {}\n\n def dp(n):\n if n in memo:\n return memo[n]\n\n if n < 2:\n result = n\n else:\n result = max(dp(n//2) + dp(n//3) + dp(n//4) + dp(n//5), n)\n\n memo[n] = result\n return result\n\n return dp(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n def solve(n):\n if n < 4:\n return n\n elif n == 4:\n return 4\n else:\n return max(solve(n // 2) + solve(n // 3) + solve(n // 4) + solve(n // 5), n)\n\n return solve(n)", "matching_cluster_idx": 7}]}, "Mbpp/395": {"dps": 98.08429118773947, "dps_norm": 75.0, "pass@1": 99.0, "profiled": [{"solution": "def first_non_repeating_character(string: str) -> str:\n char_count = {}\n\n # Count the occurrence of each character in the string\n for char in string:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n\n # Find the first non-repeating character\n for char in string:\n if char_count[char] == 1:\n return char\n\n # If no non-repeating character is found, return None\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(string):\n \"\"\"\n Returns the first non-repeated character in a given string, else None if all characters are repeated.\n \"\"\"\n count_dict = {}\n for char in string:\n if char in count_dict:\n count_dict[char] += 1\n else:\n count_dict[char] = 1\n for char in string:\n if count_dict[char] == 1:\n return char\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s: str) -> str:\n char_dict = {}\n for char in s:\n if char in char_dict:\n char_dict[char] += 1\n else:\n char_dict[char] = 1\n for char in s:\n if char_dict[char] == 1:\n return char\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n counter = {}\n for c in s:\n if c in counter:\n counter[c] += 1\n else:\n counter[c] = 1\n\n for c in s:\n if counter[c] == 1:\n return c\n\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s: str) -> str:\n char_count = {}\n\n # Count the frequency of each character in the string\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n\n # Find the first non-repeating character\n for char in s:\n if char_count[char] == 1:\n return char\n\n # If there's no non-repeating character, return None\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n \"\"\"\n Find the first non-repeating character in a string.\n\n Args:\n s (str): The input string.\n\n Returns:\n str: The first non-repeating character if one exists, otherwise None.\n \"\"\"\n char_dict = {}\n for char in s:\n char_dict[char] = char_dict.get(char, 0) + 1\n\n for char, count in char_dict.items():\n if count == 1:\n return char\n\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(string: str) -> str:\n char_count = {}\n\n # Count the occurrence of each character\n for char in string:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n\n # Find the first non-repeating character\n for char in string:\n if char_count[char] == 1:\n return char\n\n # If there is no non-repeating character, return None\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s: str) -> str:\n # Count occurrences of each character in the string\n counts = {char: s.count(char) for char in set(s)}\n\n # Find the first character with a count of 1\n for char in s:\n if counts[char] == 1:\n return char\n\n # If no such character is found, return None\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(string: str) -> str:\n \"\"\"Find the first non-repeated character in a given string.\"\"\"\n char_counts = {}\n for char in string:\n if char in char_counts:\n char_counts[char] += 1\n else:\n char_counts[char] = 1\n\n for char in string:\n if char_counts[char] == 1:\n return char\n\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s: str) -> str:\n char_count = {}\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n\n for char in s:\n if char_count[char] == 1:\n return char\n\n return None", "matching_cluster_idx": 5}, {"solution": "from collections import Counter\ndef first_non_repeating_character(string):\n counter = Counter(string)\n for char in string:\n if counter[char] == 1:\n return char\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n \"\"\"\n This function finds the first non-repeated character in a given string.\n If all characters are repeating, it returns None.\n \"\"\"\n count_dict = {}\n for char in s:\n if char in count_dict:\n count_dict[char] += 1\n else:\n count_dict[char] = 1\n\n for char in s:\n if count_dict[char] == 1:\n return char\n\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n # Create a dictionary to store character frequencies\n freq = {}\n\n # Populate the dictionary\n for char in s:\n freq[char] = freq.get(char, 0) + 1\n\n # Iterate over the string and return the first non-repeating character\n for char in s:\n if freq[char] == 1:\n return char\n\n # Return None if there's no non-repeating character\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s: str) -> str:\n # Create a dictionary to store character frequencies.\n freq = {}\n for char in s:\n if char in freq:\n freq[char] += 1\n else:\n freq[char] = 1\n\n # Return the first character that appears only once.\n for char in s:\n if freq[char] == 1:\n return char\n\n # If no non-repeating character is found, return None.\n return None", "matching_cluster_idx": 5}, {"solution": "from collections import Counter\ndef first_non_repeating_character(string):\n char_counts = Counter(string)\n for char in string:\n if char_counts[char] == 1:\n return char\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(string):\n # Create a dictionary to store the count of each character\n char_count = {}\n\n # Count the occurrences of each character in the string\n for char in string:\n char_count[char] = char_count.get(char, 0) + 1\n\n # Iterate through the string to find the first character with a count of 1\n for char in string:\n if char_count[char] == 1:\n return char\n\n # If no such character is found, return None\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n \"\"\"\n Return the first non-repeated character in the given string.\n If all characters are repeated, return None.\n \"\"\"\n count = {}\n\n # Count the occurrence of each character\n for char in s:\n count[char] = count.get(char, 0) + 1\n\n # Find the first character with a count of 1\n for char in s:\n if count[char] == 1:\n return char\n\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n # Create a dictionary to store character counts\n char_counts = {}\n for char in s:\n if char in char_counts:\n char_counts[char] += 1\n else:\n char_counts[char] = 1\n\n # Iterate through the string to find the first non-repeating character\n for char in s:\n if char_counts[char] == 1:\n return char\n\n # Return None if all characters are repeated\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(input_str):\n char_counts = {}\n for char in input_str:\n if char in char_counts:\n char_counts[char] += 1\n else:\n char_counts[char] = 1\n for char in input_str:\n if char_counts[char] == 1:\n return char\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(string):\n \"\"\"\n Find the first non-repeating character in a given string.\n If all characters are repeating, return None.\n \"\"\"\n char_count = {}\n for char in string:\n char_count[char] = char_count.get(char, 0) + 1\n\n for char in string:\n if char_count[char] == 1:\n return char\n\n return None", "matching_cluster_idx": 5}]}, "Mbpp/405": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 46.0, "profiled": [{"solution": "def check_tuplex(tup, element):\n \"\"\"Check if an element exists in a tuple.\n\n Args:\n tup (tuple): The tuple to search in.\n element: The element to search for.\n\n Returns:\n bool: True if the element is found, False otherwise.\n \"\"\"\n return element in tup", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tup, element):\n \"\"\"\n Check if an element exists within a tuple.\n\n Args:\n tup (tuple): A tuple to search.\n element: The element to search for in the tuple.\n\n Returns:\n bool: True if the element exists in the tuple, False otherwise.\n \"\"\"\n return element in tup", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tup, elem):\n \"\"\"\n Function to check whether an element exists within a tuple.\n \"\"\"\n # Check if the element is in the tuple and return the result\n return elem in tup", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tup, element):\n return element in tup", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tup, elem):\n \"\"\"\n Function to check whether an element exists within a tuple.\n Args:\n tup : tuple\n elem : any\n Returns:\n bool\n \"\"\"\n return elem in tup", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tup, element):\n \"\"\"Check if an element exists within a tuple.\"\"\"\n return element in tup", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tup, element):\n \"\"\"\n This function checks whether an element exists within a tuple.\n\n Args:\n tup (tuple): The tuple to check.\n element: The element to search for.\n\n Returns:\n bool: True if the element is found, False otherwise.\n \"\"\"\n return element in tup", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(t, element):\n \"\"\"Check if an element exists in a tuple.\"\"\"\n return element in t", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tupl, element):\n \"\"\"Check if an element exists within a tuple.\"\"\"\n return element in tupl", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tup, element):\n # Check if the element exists in the tuple\n return element in tup", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tup, item):\n \"\"\"Check if an item exists in a tuple\"\"\"\n return item in tup", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tupl, element):\n return element in tupl", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tup, element):\n # Using 'in' keyword to check if element exists in the tuple\n return element in tup", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(t, element):\n # Check if element exists in tuple\n return element in t", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(input_tuple, target):\n \"\"\"\n Function to check whether an element exists within a tuple.\n \"\"\"\n return target in input_tuple", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tup, elem):\n \"\"\"\n This function checks if an element exists in a given tuple.\n \"\"\"\n return elem in tup", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tup, elem):\n \"\"\"Check if an element exists in a tuple.\"\"\"\n return elem in tup", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tup, elem):\n \"\"\"Check if an element exists in a tuple.\"\"\"\n return elem in tup", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tup, element):\n \"\"\"Check if an element exists within a tuple.\"\"\"\n return element in tup", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(t, elem):\n return elem in t", "matching_cluster_idx": 3}]}, "Mbpp/414": {"dps": 89.375612945407, "dps_norm": 88.88888888888889, "pass@1": 19.0, "profiled": [{"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Check if any value in seq1 exists in seq2.\n\n Args:\n seq1 (list): A sequence of values.\n seq2 (list): A sequence of values.\n\n Returns:\n bool: True if any value in seq1 exists in seq2, False otherwise.\n \"\"\"\n return any(item in seq2 for item in seq1)", "matching_cluster_idx": 7}, {"solution": "def overlapping(a, b):\n return not set(a).isdisjoint(b)", "matching_cluster_idx": 7}, {"solution": "def overlapping(list1, list2):\n \"\"\"\n Check if any value in list1 exists in list2.\n \"\"\"\n return any(item in list2 for item in list1)", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Check whether any value in seq1 exists in seq2 or not.\n\n :param seq1: The first sequence.\n :param seq2: The second sequence.\n :return: True if there is an overlap, False otherwise.\n \"\"\"\n return any(x in seq1 for x in seq2)", "matching_cluster_idx": 8}, {"solution": "def overlapping(seq1, seq2):\n return not set(seq1).isdisjoint(seq2)", "matching_cluster_idx": 7}, {"solution": "def overlapping(sequence1, sequence2):\n \"\"\"\n Check if any value in sequence1 exists in sequence2.\n\n Parameters:\n sequence1 (list): First sequence to check.\n sequence2 (list): Second sequence to check.\n\n Returns:\n bool: True if any value from sequence1 is present in sequence2, else False.\n \"\"\"\n return any(item in sequence2 for item in sequence1)", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n # Convert the sequences to sets and use intersection operation\n return not set(seq1).isdisjoint(seq2)", "matching_cluster_idx": 7}, {"solution": "def overlapping(sequence1, sequence2):\n \"\"\"\n Check whether any value in sequence1 exists in sequence2.\n \"\"\"\n return any(item in sequence2 for item in sequence1)", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n return any(item in seq1 for item in seq2)", "matching_cluster_idx": 8}, {"solution": "def overlapping(sequence1, sequence2):\n \"\"\"\n Checks if any value in sequence1 exists in sequence2\n \"\"\"\n return any(i in sequence2 for i in sequence1)", "matching_cluster_idx": 7}, {"solution": "def overlapping(list1, list2):\n \"\"\"\n Check if any value in the first list exists in the second list.\n \"\"\"\n return any(item in list2 for item in list1)", "matching_cluster_idx": 7}, {"solution": "def overlapping(list1, list2):\n \"\"\"\n This function checks whether any value in the first sequence exists in the second sequence.\n \"\"\"\n return any(val in list2 for val in list1)", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n # Check if any value from seq1 exists in seq2\n return any(item in seq2 for item in seq1)", "matching_cluster_idx": 7}, {"solution": "def overlapping(list1, list2):\n # Using set operations for efficient lookups\n return not set(list1).isdisjoint(list2)", "matching_cluster_idx": 7}, {"solution": "def overlapping(list1, list2):\n \"\"\"\n Check whether any value in list1 exists in list2 or not.\n \"\"\"\n # Use set operations for efficient lookup\n set1 = set(list1)\n set2 = set(list2)\n\n # If there is any common element, return True\n if set1 & set2:\n return True\n # If there are no common elements, return False\n else:\n return False", "matching_cluster_idx": 5}, {"solution": "def overlapping(list1, list2):\n \"\"\"\n Checks if any value in list1 exists in list2.\n Returns True if overlapping values are found, False otherwise.\n \"\"\"\n return any(item in list2 for item in list1)", "matching_cluster_idx": 7}, {"solution": "def overlapping(sequence1, sequence2):\n \"\"\"\n Function to check if any value in the first sequence exists in the second sequence.\n \"\"\"\n # Check if any value in sequence1 is in sequence2 using list comprehension and any() function\n return any(item in sequence2 for item in sequence1)", "matching_cluster_idx": 7}, {"solution": "def overlapping(sequence1, sequence2):\n \"\"\"\n Checks if any value in sequence1 exists in sequence2.\n\n :param sequence1: The first sequence to check.\n :param sequence2: The second sequence to check against.\n :return: True if any value in sequence1 exists in sequence2, False otherwise.\n \"\"\"\n return not set(sequence1).isdisjoint(sequence2)", "matching_cluster_idx": 7}, {"solution": "def overlapping(list1, list2):\n \"\"\"\n Check if any value in one list exists in the other list.\n \"\"\"\n return any(i in list2 for i in list1)", "matching_cluster_idx": 7}]}, "Mbpp/421": {"dps": 66.02880658436214, "dps_norm": 84.28571428571428, "pass@1": 81.0, "profiled": [{"solution": "def concatenate_tuple(input_tuple, delimiter=\"-\"):\n # Initialize an empty string\n result = \"\"\n\n # Iterate over each element in the tuple\n for element in input_tuple:\n # Add the current element to the result\n result += str(element) + delimiter\n\n # Remove the trailing delimiter and return the result\n return result.rstrip(delimiter)", "matching_cluster_idx": 3}, {"solution": "def concatenate_tuple(t):\n # Check if input is a tuple\n if not isinstance(t, tuple):\n raise TypeError(\"Input should be a tuple\")\n # Join all elements of tuple with '-'\n return '-'.join(map(str, t))", "matching_cluster_idx": 5}, {"solution": "def concatenate_tuple(input_tuple, delimiter=\"-\"):\n # Use the join() method to concatenate tuple elements with a specified delimiter\n return delimiter.join(map(str, input_tuple))", "matching_cluster_idx": 5}, {"solution": "def concatenate_tuple(input_tuple, delimiter='-'):\n return delimiter.join(map(str, input_tuple))", "matching_cluster_idx": 5}, {"solution": "def concatenate_tuple(input_tuple, delimiter=\"-\"):\n \"\"\"\n This function takes a tuple and concatenates each element with a delimiter.\n \"\"\"\n return delimiter.join(map(str, input_tuple))", "matching_cluster_idx": 5}, {"solution": "def concatenate_tuple(input_tuple, delimiter=\"-\"):\n return delimiter.join(map(str, input_tuple))", "matching_cluster_idx": 6}, {"solution": "def concatenate_tuple(t: tuple, delimiter: str = '-') -> str:\n return delimiter.join(map(str, t))", "matching_cluster_idx": 5}, {"solution": "def concatenate_tuple(t):\n \"\"\"\n Concatenates each element of a tuple by a hyphen delimiter.\n \"\"\"\n return '-'.join(map(str, t))", "matching_cluster_idx": 6}, {"solution": "def concatenate_tuple(t):\n return '-'.join(map(str, t))", "matching_cluster_idx": 6}, {"solution": "def concatenate_tuple(tup, delimiter='-'):\n \"\"\"\n This function concatenates each element of a tuple with a given delimiter.\n \"\"\"\n return delimiter.join(map(str, tup))", "matching_cluster_idx": 5}, {"solution": "def concatenate_tuple(tup):\n # Convert tuple to string with dash (-) as delimiter\n return '-'.join(map(str, tup))", "matching_cluster_idx": 5}, {"solution": "def concatenate_tuple(input_tuple, delimiter='-'):\n return delimiter.join(map(str, input_tuple))", "matching_cluster_idx": 5}, {"solution": "def concatenate_tuple(t):\n \"\"\"Concatenates each element of a tuple with a delimiter.\"\"\"\n return '-'.join(str(element) for element in t)", "matching_cluster_idx": 4}, {"solution": "def concatenate_tuple(input_tuple, delimiter='-'):\n return delimiter.join(map(str, input_tuple))", "matching_cluster_idx": 5}, {"solution": "def concatenate_tuple(t, delimiter=\"-\"):\n \"\"\"Concatenates each element of a tuple with a specified delimiter.\"\"\"\n return delimiter.join(str(item) for item in t)", "matching_cluster_idx": 4}, {"solution": "def concatenate_tuple(t):\n return '-'.join(map(str, t))", "matching_cluster_idx": 6}, {"solution": "def concatenate_tuple(tup, delimiter='-'):\n return delimiter.join(str(item) for item in tup)", "matching_cluster_idx": 4}, {"solution": "def concatenate_tuple(tup):\n return '-'.join(str(t) for t in tup)", "matching_cluster_idx": 4}, {"solution": "def concatenate_tuple(input_tuple, delimiter='-'):\n return delimiter.join(map(str, input_tuple))", "matching_cluster_idx": 5}, {"solution": "def concatenate_tuple(t: tuple, delimiter: str = '-') -> str:\n \"\"\"\n Concatenates each element of the given tuple by the specified delimiter.\n :param t: Tuple of elements to concatenate.\n :param delimiter: String to use as a delimiter between elements (default is '-').\n :return: Concatenated string.\n \"\"\"\n return delimiter.join(map(str, t))", "matching_cluster_idx": 5}]}, "Mbpp/424": {"dps": 51.624548736462096, "dps_norm": 80.0, "pass@1": 96.0, "profiled": [{"solution": "def extract_rear(tup):\n \"\"\"Extract the last character of each string in a given tuple.\"\"\"\n return [s[-1] for s in tup]", "matching_cluster_idx": 3}, {"solution": "def extract_rear(strings):\n # Using list comprehension to get the last character of each string in the tuple.\n return [s[-1] for s in strings]", "matching_cluster_idx": 3}, {"solution": "def extract_rear(t):\n return [string[-1] for string in t]", "matching_cluster_idx": 3}, {"solution": "def extract_rear(t):\n return [s[-1] for s in t]", "matching_cluster_idx": 3}, {"solution": "def extract_rear(t):\n \"\"\"\n This function extracts the last character from each string in a tuple.\n \"\"\"\n return [s[-1] for s in t]", "matching_cluster_idx": 3}, {"solution": "def extract_rear(input_tuple):\n # Use list comprehension to extract the rear element of each string in the tuple\n return [s[-1] for s in input_tuple]", "matching_cluster_idx": 3}, {"solution": "def extract_rear(lst):\n return [x[-1] for x in lst]", "matching_cluster_idx": 3}, {"solution": "def extract_rear(t):\n return [s[-1] for s in t]", "matching_cluster_idx": 3}, {"solution": "def extract_rear(tup):\n return [s[-1] for s in tup]", "matching_cluster_idx": 3}, {"solution": "def extract_rear(input_tuple):\n \"\"\"\n A function that extracts the last character of each string from a given tuple.\n :param input_tuple: A tuple of strings\n :return: A list of the last characters of each string in the tuple\n \"\"\"\n return [string[-1] for string in input_tuple]", "matching_cluster_idx": 3}, {"solution": "def extract_rear(str_tuple):\n return [s[-1] for s in str_tuple]", "matching_cluster_idx": 3}, {"solution": "def extract_rear(tup):\n return [s[-1] for s in tup]", "matching_cluster_idx": 3}, {"solution": "def extract_rear(lst):\n \"\"\"\n Function to extract only the rear index element of each string in the given tuple.\n :param lst: A tuple of strings\n :return: A list of rear index characters from each string in the tuple\n \"\"\"\n return [s[-1] for s in lst]", "matching_cluster_idx": 3}, {"solution": "def extract_rear(t):\n return [word[-1] for word in t]", "matching_cluster_idx": 3}, {"solution": "def extract_rear(tpl):\n return [s[-1] for s in tpl]", "matching_cluster_idx": 3}, {"solution": "def extract_rear(str_tuple):\n # Use a list comprehension to extract the last character of each string\n return [s[-1] for s in str_tuple]", "matching_cluster_idx": 3}, {"solution": "def extract_rear(t):\n return [s[-1] for s in t]", "matching_cluster_idx": 3}, {"solution": "def extract_rear(tup):\n \"\"\"Extracts the rear index element of each string in the given tuple.\"\"\"\n return [s[-1] for s in tup]", "matching_cluster_idx": 3}, {"solution": "def extract_rear(strings):\n # Use list comprehension to extract the rear index element from each string\n return [string[-1] for string in strings]", "matching_cluster_idx": 3}, {"solution": "def extract_rear(tup):\n return [s[-1] for s in tup]", "matching_cluster_idx": 3}]}, "Mbpp/425": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def count_element_in_list(nested_list, element):\n count = 0\n for sublist in nested_list:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(sublists, element):\n \"\"\"\n Function to count the number of sublists containing a particular element.\n \"\"\"\n count = sum(element in sublist for sublist in sublists)\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, element):\n \"\"\"\n Counts the number of sublists containing a particular element.\n\n Parameters:\n lst (list of lists): list of sublists.\n element: the element to search for.\n\n Returns:\n int: count of sublists containing the element.\n \"\"\"\n return sum(1 for sublist in lst if element in sublist)", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, element):\n \"\"\"\n This function counts the number of sublists containing a particular element.\n :param lst: list of lists\n :param element: the element to be counted\n :return: the count of sublists containing the given element\n \"\"\"\n return sum(1 for sublist in lst if element in sublist)", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(nested_list, element):\n count = 0\n for sublist in nested_list:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, element):\n count = 0\n for sublist in lst:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(nested_list, element):\n count = 0\n for sublist in nested_list:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, element):\n return sum(element in sublist for sublist in lst)", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(sublists, element):\n count = 0\n for sublist in sublists:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, element):\n return sum(1 for sublist in lst if element in sublist)", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(nested_list, element):\n count = 0\n for sublist in nested_list:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(sublists, element):\n count = sum(1 for sublist in sublists if element in sublist)\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, element):\n \"\"\"\n This function counts the number of sublists containing a particular element in a nested list.\n \"\"\"\n count = 0\n for sublist in lst:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(nested_list, element):\n count = 0\n for sublist in nested_list:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, element):\n count = 0\n for sublist in lst:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, element):\n count = 0\n for sublist in lst:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, element):\n return sum(1 for sublist in lst if element in sublist)", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(sublists, element):\n count = 0\n for sublist in sublists:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(nested_list, element):\n \"\"\"Counts the number of sublists containing a particular element in a nested list.\"\"\"\n count = sum(1 for sublist in nested_list if element in sublist)\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(nested_list, element):\n \"\"\"\n Counts the number of sublists in a nested list that contain a specific element.\n \"\"\"\n count = 0\n for sublist in nested_list:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}]}, "Mbpp/428": {"dps": 84.29752066115702, "dps_norm": 55.55555555555556, "pass@1": 97.0, "profiled": [{"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2\n\n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n\n arr[j] = temp\n\n gap //= 2\n\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2\n\n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n\n arr[j] = temp\n gap //= 2\n\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n # Start with a big gap, then reduce the gap\n n = len(arr)\n gap = n // 2\n\n # Dive into a cycle of increasing order\n while gap > 0:\n\n for i in range(gap, n):\n # add [arr[i], arr[i+1], ...] to the elements that have been gap sorted\n temp = arr[i]\n\n # shift earlier gap-sorted elements up until the correct location for arr[i] is found\n j = i\n while j >= gap and arr[j-gap] > temp:\n arr[j] = arr[j-gap]\n j -= gap\n\n # put temp (the original arr[i]) in its correct location\n arr[j] = temp\n gap //= 2 # reduce gap\n\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n # Start with a big gap, then reduce the gap\n gap = len(arr) // 2\n while gap > 0:\n for i in range(gap, len(arr)):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n # Start with a big gap, then reduce the gap\n gap = len(arr) // 2\n\n # While gap size is positive, update elements\n while gap > 0:\n for i in range(gap, len(arr)):\n temp = arr[i]\n j = i\n\n # Shift elements up to unsorted part\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n\n # Place temp (the original arr[i]) in its correct location\n arr[j] = temp\n\n # Reduce gap for the next iteration\n gap //= 2\n\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n # Start with a big gap, then reduce the gap\n n = len(arr)\n gap = n // 2\n\n # Do a gapped insertion sort for this gap size.\n # The first gap elements a[0..gap-1] are already in gapped order keep adding one more element until the entire array is gap sorted\n while gap > 0:\n for i in range(gap,n):\n # add arr[i] to the elements that have been gap sorted save a[i] in temp and make a hole at position i\n temp = arr[i]\n\n # shift earlier gap-sorted elements up until the correct location for arr[i] is found\n j = i\n while j >= gap and arr[j-gap] > temp:\n arr[j] = arr[j-gap]\n j -= gap\n\n # put temp (the original arr[i]) in its correct location\n arr[j] = temp\n gap //= 2\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2\n\n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n\n arr[j] = temp\n gap //= 2\n\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n # Start with a big gap, then reduce the gap\n n = len(arr)\n gap = n//2\n\n # Do a gapped insertion sort for this gap size.\n # The first gap elements a[0..gap-1] are already in place\n while gap > 0:\n for i in range(gap,n):\n\n # add arr[i] to the elements that have been gap sorted\n # save arr[i] in temp and make a hole at position i\n temp = arr[i]\n\n # shift earlier gap-sorted elements up until the correct\n # location for arr[i] is found\n j = i\n while j >= gap and arr[j-gap] > temp:\n arr[j] = arr[j-gap]\n j -= gap\n\n # put temp (the original a[i]) into its correct location\n arr[j] = temp\n gap //= 2\n\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2\n\n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n\n arr[j] = temp\n gap //= 2\n\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n # Start with a big gap, then reduce the gap\n gap = len(arr) // 2\n\n # Perform insertion sort for this gap size.\n # The last gap is 0, so there is no insertion in that case.\n while gap > 0:\n\n # Perform an insertion sort for this gap size.\n # The loop starts at the appropriate point and it goes till the length of the array\n for i in range(gap, len(arr)):\n temp = arr[i]\n\n # shift earlier stripe's element up until correct location for current element is found\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n\n # put temp (the original a[i]) in its correct location\n arr[j] = temp\n gap //= 2 # decrease the gap size\n\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2\n\n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n gap = len(arr) // 2\n while gap > 0:\n for i in range(gap, len(arr)):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2\n\n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2\n\n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n\n arr[j] = temp\n gap //= 2\n\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n # Start with a big gap, then reduce the gap\n n = len(arr)\n gap = n // 2\n\n # Dive into a loop until the gap is 0\n while gap > 0:\n # Compare the elements at indices 'i' and 'j'\n for i in range(gap, n):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n # Shift elements to the right if they're greater than temp\n arr[j] = arr[j - gap]\n j -= gap\n # Insert the temporary element\n arr[j] = temp\n gap //= 2 # Reduce the gap\n\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n # Start with a big gap, then reduce the gap\n n = len(arr)\n gap = n // 2\n\n # Dive into a loop until gap becomes 0\n while gap > 0:\n\n # Do a gapped insertion sort for this gap size.\n # The first gap elements a[0..gap-1] are already in gapped order keep adding one more element until the entire array is gap sorted\n for i in range(gap,n):\n\n # add arr[i] to the elements that have been gap sorted save a gap sorted array in temp array\n temp = arr[i]\n\n # shift earlier gap-sorted elements up until the correct location for arr[i] is found\n j = i\n while j >= gap and arr[j-gap] > temp:\n arr[j] = arr[j-gap]\n j -= gap\n\n # put temp (the original arr[i]) in its correct location\n arr[j] = temp\n gap //= 2\n\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2\n\n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2\n\n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2\n\n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n\n arr[j] = temp\n gap //= 2\n\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n # Start with a big gap, then reduce the gap\n n = len(arr)\n gap = n // 2\n\n # Dive into a loop and make multiple passes\n while gap > 0:\n for i in range(gap, n):\n # add [arr[i], arr[i-gap], ..., arr[0]] into the sorted array\n temp = arr[i]\n j = i\n while j >= gap and arr[j-gap] > temp:\n arr[j] = arr[j-gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n\n return arr", "matching_cluster_idx": 4}]}, "Mbpp/433": {"dps": 63.82978723404255, "dps_norm": 60.0, "pass@1": 79.0, "profiled": [{"solution": "def check_greater(arr, num):\n \"\"\"Check if the input number is greater than all elements in the array.\"\"\"\n return all(x < num for x in arr)", "matching_cluster_idx": 2}, {"solution": "def check_greater(arr, n):\n \"\"\"\n This function checks if all the elements in the given array are less than the input number.\n :param arr: List of integers\n :param n: Integer\n :return: Boolean value, True if all elements are less than n, otherwise False\n \"\"\"\n return all([x < n for x in arr])", "matching_cluster_idx": 2}, {"solution": "def check_greater(arr, num):\n return all([i < num for i in arr])", "matching_cluster_idx": 2}, {"solution": "def check_greater(arr, num):\n \"\"\"\n Check whether the given number is greater than all elements of the array.\n\n :param arr: Array of integers\n :param num: Number to be compared with array elements\n :return: Boolean value - True if num is greater than all elements, else False\n \"\"\"\n return all(num > elem for elem in arr)", "matching_cluster_idx": 2}, {"solution": "def check_greater(array, number):\n \"\"\"\n Checks if the given number is greater than all elements in the array.\n \"\"\"\n return all(item < number for item in array)", "matching_cluster_idx": 2}, {"solution": "def check_greater(arr, num):\n return all([x < num for x in arr])", "matching_cluster_idx": 2}, {"solution": "def check_greater(array, num):\n \"\"\"Check if a number is greater than all elements in an array.\"\"\"\n return all(num > elem for elem in array)", "matching_cluster_idx": 2}, {"solution": "def check_greater(array, number):\n \"\"\"\n Checks if the given number is greater than all the elements in the array.\n\n Args:\n array (list): A list of numbers.\n number (int): A number to compare with.\n\n Returns:\n bool: True if the number is greater than all elements in the array, else False.\n \"\"\"\n return all(num < number for num in array)", "matching_cluster_idx": 2}, {"solution": "def check_greater(array, num):\n \"\"\"\n Check whether the entered number is greater than the elements of the given array.\n \"\"\"\n return all(i < num for i in array)", "matching_cluster_idx": 2}, {"solution": "def check_greater(arr, num):\n return all(x < num for x in arr)", "matching_cluster_idx": 2}, {"solution": "def check_greater(arr, num):\n return all(x < num for x in arr)", "matching_cluster_idx": 2}, {"solution": "def check_greater(arr, num):\n \"\"\"\n Check if a given number is greater than all elements in the array.\n \"\"\"\n return all(n < num for n in arr)", "matching_cluster_idx": 2}, {"solution": "def check_greater(arr, num):\n \"\"\"\n Function to check whether the given number is greater than all elements of the array.\n Args:\n arr (list): the input array\n num (int): the number to compare\n Returns:\n bool: True if number is greater, False otherwise\n \"\"\"\n return all(n < num for n in arr)", "matching_cluster_idx": 2}, {"solution": "def check_greater(arr, num):\n return all([i < num for i in arr])", "matching_cluster_idx": 2}, {"solution": "def check_greater(arr, target):\n \"\"\"\n Check if the target number is greater than all elements in the array.\n :param arr: list of integers\n :param target: integer\n :return: bool\n \"\"\"\n return all(target > i for i in arr)", "matching_cluster_idx": 2}, {"solution": "def check_greater(nums, num):\n return all(x < num for x in nums)", "matching_cluster_idx": 2}, {"solution": "def check_greater(arr, num):\n return all(x < num for x in arr)", "matching_cluster_idx": 2}, {"solution": "def check_greater(arr, num):\n \"\"\"Check if a number is greater than all elements of a list.\n\n Args:\n arr (list): The list to compare.\n num (int): The number to compare with the elements in the list.\n\n Returns:\n bool: True if the number is greater than all elements, False otherwise.\n \"\"\"\n return all([x < num for x in arr])", "matching_cluster_idx": 2}, {"solution": "def check_greater(array, num):\n return all(element < num for element in array)", "matching_cluster_idx": 2}, {"solution": "def check_greater(array, num):\n \"\"\"Check if all elements in the array are less than the given number.\"\"\"\n return all(element < num for element in array)", "matching_cluster_idx": 2}]}, "Mbpp/437": {"dps": 63.529411764705884, "dps_norm": 18.0, "pass@1": 29.0, "profiled": [{"solution": "def remove_odd(s):\n return ''.join(c for i, c in enumerate(s) if (i+1) % 2 == 0)", "matching_cluster_idx": 0}, {"solution": "def remove_odd(s):\n return ''.join(char for i, char in enumerate(s) if (i+1) % 2 == 0)", "matching_cluster_idx": 0}, {"solution": "def remove_odd(s):\n return \"\".join(c for i, c in enumerate(s) if (i + 1) % 2 == 0)", "matching_cluster_idx": 0}, {"solution": "def remove_odd(s: str) -> str:\n return ''.join(c for i, c in enumerate(s) if (i + 1) % 2 == 0)", "matching_cluster_idx": 0}, {"solution": "def remove_odd(string):\n return \"\".join([char for i, char in enumerate(string) if (i+1) % 2 == 0])", "matching_cluster_idx": 0}, {"solution": "def remove_odd(s):\n return ''.join(c for i, c in enumerate(s) if (i + 1) % 2 == 0)", "matching_cluster_idx": -1}, {"solution": "def remove_odd(input_string):\n \"\"\"\n Remove odd characters in a string.\n\n Args:\n input_string (str): The input string.\n\n Returns:\n str: The string with odd characters removed.\n \"\"\"\n return ''.join([char for i, char in enumerate(input_string) if (i + 1) % 2 == 0])", "matching_cluster_idx": 0}, {"solution": "def remove_odd(s: str) -> str:\n return ''.join(c for i, c in enumerate(s) if (i+1) % 2 == 0)", "matching_cluster_idx": -1}, {"solution": "def remove_odd(string):\n return ''.join([char for idx, char in enumerate(string) if (idx + 1) % 2 == 0])", "matching_cluster_idx": 0}, {"solution": "def remove_odd(s):\n return ''.join([c for i, c in enumerate(s) if (i+1) % 2 == 0])", "matching_cluster_idx": 0}, {"solution": "def remove_odd(s: str) -> str:\n return ''.join([c for i, c in enumerate(s) if (i+1) % 2 == 0])", "matching_cluster_idx": 0}, {"solution": "def remove_odd(input_string):\n return ''.join([char for idx, char in enumerate(input_string) if (idx+1) % 2 == 0])", "matching_cluster_idx": 0}, {"solution": "def remove_odd(s: str) -> str:\n \"\"\"\n Remove odd-positioned characters from a string.\n :param s: input string\n :return: string with odd-positioned characters removed\n \"\"\"\n return ''.join([c for i, c in enumerate(s) if (i + 1) % 2 == 0])", "matching_cluster_idx": 0}, {"solution": "def remove_odd(string):\n # Use a list comprehension to filter out odd indexed characters.\n return ''.join(char for i, char in enumerate(string) if (i+1) % 2 == 0)", "matching_cluster_idx": 0}, {"solution": "def remove_odd(s):\n \"\"\"Remove odd characters from a string.\"\"\"\n return ''.join(ch for i, ch in enumerate(s) if (i+1) % 2 == 0)", "matching_cluster_idx": 0}, {"solution": "def remove_odd(s):\n return ''.join(c for i, c in enumerate(s) if (i+1) % 2 == 0)", "matching_cluster_idx": 0}, {"solution": "def remove_odd(s):\n \"\"\"Remove odd-positioned characters from the input string.\"\"\"\n return ''.join(c for i, c in enumerate(s) if (i+1) % 2 == 0)", "matching_cluster_idx": 0}, {"solution": "def remove_odd(s):\n return ''.join([c for i, c in enumerate(s) if (i+1) % 2 == 0])", "matching_cluster_idx": 0}, {"solution": "def remove_odd(input_string):\n # Check if input is a string\n assert isinstance(input_string, str), \"Input must be a string\"\n return \"\".join([char for index, char in enumerate(input_string) if (index + 1) % 2 == 0])", "matching_cluster_idx": 0}, {"solution": "def remove_odd(input_string):\n return \"\".join([c for i, c in enumerate(input_string) if (i+1) % 2 == 0])", "matching_cluster_idx": 0}]}, "Mbpp/440": {"dps": null, "dps_norm": null, "pass@1": 2.0, "profiled": []}, "Mbpp/446": {"dps": 96.45320197044335, "dps_norm": 64.0, "pass@1": 10.0, "profiled": [{"solution": "def count_Occurrence(tup: tuple, lst: list) -> int:\n count = 0\n for item in lst:\n count += tup.count(item)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tup, lst):\n return sum(tup.count(item) for item in lst)", "matching_cluster_idx": 2}, {"solution": "from collections import Counter\ndef count_Occurrence(tup: tuple, lst: list) -> int:\n # Convert the tuple to a Counter object and the list to a list of keys\n count = Counter(tup)\n keys = [key for key in lst]\n # Return the sum of counts for each key in the list\n return sum(count[key] for key in keys)", "matching_cluster_idx": 4}, {"solution": "def count_Occurrence(tup, lst):\n \"\"\"\n Counts the occurrences of all elements from lst in tup.\n \"\"\"\n return sum(tup.count(lst[i]) for i in range(len(lst)))", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tpl, lst):\n return sum(tpl.count(i) for i in lst)", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tup, lst):\n count = 0\n for item in lst:\n count += tup.count(item)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tup, lst):\n return sum(tup.count(i) for i in lst)", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(t, lst):\n return sum(t.count(i) for i in lst)", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(input_tuple, input_list):\n count = 0\n for elem in input_list:\n count += input_tuple.count(elem)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tup, lst):\n count = 0\n for i in lst:\n count += tup.count(i)\n return count", "matching_cluster_idx": 2}]}, "Mbpp/451": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 97.0, "profiled": [{"solution": "def remove_whitespaces(s: str) -> str:\n \"\"\"\n Function to remove all whitespaces from the given string.\n :param s: string to remove whitespaces from\n :return: string with all whitespaces removed\n \"\"\"\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(s):\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(s):\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(s: str) -> str:\n \"\"\"Removes all whitespaces from a given string.\"\"\"\n return s.replace(' ', '')", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string: str) -> str:\n \"\"\"Removes all whitespaces from the input string.\"\"\"\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(s):\n \"\"\"\n This function removes all whitespace characters from the given string.\n \"\"\"\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(string):\n \"\"\"Remove all whitespaces from the given string.\"\"\"\n return string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(s):\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(s: str) -> str:\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string: str) -> str:\n \"\"\"\n Removes all whitespace characters from the given string.\n\n :param input_string: The input string\n :return: The input string without any whitespaces\n \"\"\"\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(s):\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(s):\n \"\"\"\n Remove all whitespaces from the given string.\n\n Args:\n s (str): Input string.\n\n Returns:\n str: String without any whitespaces.\n \"\"\"\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(s):\n \"\"\"Remove all whitespaces from the given string.\"\"\"\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(string):\n \"\"\"\n This function removes all whitespaces from the given string.\n \"\"\"\n return string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(s: str) -> str:\n # This function removes all whitespaces from the given string\n return s.replace(' ', '')", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_str):\n # Use string's replace method to replace all whitespaces with empty string\n return input_str.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(s):\n \"\"\"\n Removes all whitespaces from the given string.\n\n Args:\n s (str): input string\n\n Returns:\n str: output string without whitespaces\n \"\"\"\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(s):\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(s):\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(string: str) -> str:\n return string.replace(\" \", \"\")", "matching_cluster_idx": 4}]}, "Mbpp/456": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def reverse_string_list(str_list):\n return [s[::-1] for s in str_list]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(lst):\n return [s[::-1] for s in lst]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n return [s[::-1] for s in string_list]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n \"\"\"Reverse each string in a given list.\"\"\"\n return [s[::-1] for s in string_list]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n return [s[::-1] for s in string_list]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(input_list):\n return [s[::-1] for s in input_list]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(input_list):\n \"\"\"\n This function takes a list of strings as an input and returns a new list\n where each string in the original list is reversed.\n \"\"\"\n return [s[::-1] for s in input_list]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(lst):\n return [s[::-1] for s in lst]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(lst):\n return [s[::-1] for s in lst]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(strings):\n return [s[::-1] for s in strings]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(input_list):\n \"\"\"Reverse each string in the input list.\"\"\"\n return [s[::-1] for s in input_list]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(str_list):\n \"\"\"Reverse each string in a given list of strings.\"\"\"\n return [s[::-1] for s in str_list]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n \"\"\"\n This function takes a list of strings and returns a new list where each string is reversed.\n \"\"\"\n return [s[::-1] for s in string_list]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(strings):\n return [s[::-1] for s in strings]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(lst):\n # Use list comprehension and the slicing trick to reverse each string in the list\n return [s[::-1] for s in lst]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(input_list):\n return [s[::-1] for s in input_list]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(strings):\n \"\"\"Reverse each string in the input list.\"\"\"\n return [s[::-1] for s in strings]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n # Use list comprehension to reverse each string\n return [s[::-1] for s in string_list]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(input_list):\n return [s[::-1] for s in input_list]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(lst):\n \"\"\"\n This function takes a list of strings as an argument and returns a new list\n containing the reversed version of each string.\n \"\"\"\n return [s[::-1] for s in lst]", "matching_cluster_idx": 4}]}, "Mbpp/460": {"dps": null, "dps_norm": null, "pass@1": 0.0, "profiled": []}, "Mbpp/474": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 96.0, "profiled": [{"solution": "def replace_char(s, old_char, new_char):\n \"\"\"\n Replace occurrences of old_char in string s with new_char\n \"\"\"\n return s.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s: str, old: str, new: str) -> str:\n \"\"\"Replace old with new in string s.\n\n Args:\n s (str): input string\n old (str): substring to replace\n new (str): replacement\n\n Returns:\n str: modified string\n \"\"\"\n return s.replace(old, new)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, old, new):\n \"\"\"\n This function replaces all occurrences of 'old' character with 'new' in the given string 's'.\n \"\"\"\n return s.replace(old, new)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, old_char, new_char):\n return s.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(string, old_char, new_char):\n \"\"\"\n Replaces all occurrences of 'old_char' in 'string' with 'new_char'.\n Returns the modified string.\n \"\"\"\n return string.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, old_char, new_char):\n \"\"\"\n Replaces all occurrences of a character in a string with another character.\n \"\"\"\n return s.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, old_char, new_char):\n \"\"\"Replace all occurrences of old_char in s with new_char and return the result.\"\"\"\n return s.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(input_str, old_char, new_char):\n return input_str.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, old, new):\n return s.replace(old, new)", "matching_cluster_idx": 6}, {"solution": "def replace_char(string, old_char, new_char):\n return string.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(string, old_char, new_char):\n \"\"\"\n This function replaces all occurrences of a specified old character\n with a new character in a given string.\n\n Args:\n string (str): The original string.\n old_char (str): The character to be replaced.\n new_char (str): The new character.\n\n Returns:\n str: The modified string.\n \"\"\"\n return string.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, old, new):\n return s.replace(old, new)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, old, new):\n return s.replace(old, new)", "matching_cluster_idx": 6}, {"solution": "def replace_char(string, old_char, new_char):\n \"\"\"\n Replaces occurrences of old_char with new_char in the given string.\n\n :param string: input string\n :param old_char: character to be replaced\n :param new_char: character to replace old_char with\n :return: modified string\n \"\"\"\n return string.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, old, new):\n \"\"\"Replace all occurrences of the old character with the new one in the given string.\"\"\"\n return s.replace(old, new)", "matching_cluster_idx": 6}, {"solution": "def replace_char(string, char, replacement):\n return string.replace(char, replacement)", "matching_cluster_idx": 6}, {"solution": "def replace_char(input_string, old_char, new_char):\n \"\"\"Replace specified character(s) with another in a given string\"\"\"\n return input_string.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(string, char, new_char):\n return string.replace(char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(input_string, old_char, new_char):\n \"\"\"\n Replace all occurrences of 'old_char' with 'new_char' in the 'input_string'.\n\n Args:\n input_string (str): The string to replace characters in.\n old_char (str): The character to replace.\n new_char (str): The character to replace 'old_char' with.\n\n Returns:\n str: The modified string.\n \"\"\"\n return input_string.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(input_string, target_char, replacement_char):\n \"\"\"\n Replace occurrences of target_char in input_string with replacement_char.\n\n Args:\n input_string (str): The string in which to perform the replacement.\n target_char (str): The character to replace.\n replacement_char (str): The character to replace target_char with.\n\n Returns:\n str: The modified string.\n \"\"\"\n return input_string.replace(target_char, replacement_char)", "matching_cluster_idx": 6}]}, "Mbpp/476": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 50.0, "profiled": [{"solution": "def big_sum(numbers):\n return sum([min(numbers), max(numbers)])", "matching_cluster_idx": 5}, {"solution": "def big_sum(numbers):\n \"\"\"\n This function takes a list of numbers and returns the sum of the largest and smallest values in the list.\n \"\"\"\n return max(numbers) + min(numbers)", "matching_cluster_idx": 5}, {"solution": "def big_sum(array):\n \"\"\"Find the sum of the largest and smallest value in a given array.\"\"\"\n return max(array) + min(array)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n \"\"\"Return the sum of the smallest and largest value in a given array.\"\"\"\n if not arr:\n raise ValueError(\"Array can't be empty\")\n return min(arr) + max(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n return max(arr) + min(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n \"\"\"\n Function to find the sum of the largest and smallest value in a given array.\n \"\"\"\n if not arr: # if array is empty\n return 0\n return max(arr) + min(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n # Check if the input is an empty list\n if not arr:\n return 0\n\n # Find the smallest and largest values in the array\n smallest = min(arr)\n largest = max(arr)\n\n # Return the sum of the smallest and largest values\n return smallest + largest", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n # Check if the input is a list\n assert isinstance(arr, list), \"Input should be a list.\"\n\n # Check if the list is not empty\n assert arr, \"List cannot be empty.\"\n\n # Return the sum of the smallest and largest elements in the list\n return min(arr) + max(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n \"\"\"\n Calculate the sum of the largest and smallest value in a given array.\n \"\"\"\n return max(arr) + min(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n return max(arr) + min(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n return min(arr) + max(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n return max(arr) + min(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n \"\"\"Return the sum of the smallest and largest values in an array.\"\"\"\n if not arr:\n return 0 # Handle case when the array is empty\n return min(arr) + max(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n if len(arr) == 0:\n return 0\n return max(arr) + min(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n return sum([min(arr), max(arr)])", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n \"\"\"\n This function takes a list of numbers as an argument and returns the sum of the largest and smallest values in the list.\n\n Args:\n arr (list): A list of numbers\n\n Returns:\n int: The sum of the largest and smallest values in the list\n \"\"\"\n return max(arr) + min(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n if not arr: # Empty array\n return 0\n return max(arr) + min(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n return max(arr) + min(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n return max(arr) + min(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n \"\"\"\n Function to find the sum of the largest and smallest value in a given array.\n \"\"\"\n return max(arr) + min(arr)", "matching_cluster_idx": 5}]}, "Mbpp/477": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 11.0, "profiled": [{"solution": "def is_lower(string):\n return string.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n \"\"\"\n Convert a string to lower case.\n \"\"\"\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n \"\"\"\n Convert the given string to lower case.\n\n Args:\n s (str): The string to convert.\n\n Returns:\n str: The input string in lower case.\n \"\"\"\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n \"\"\"\n This function converts a given string to lower case.\n Args:\n s (str): The string to be converted.\n Returns:\n str: The converted string.\n \"\"\"\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s: str) -> str:\n \"\"\"\n Convert the given string to lower case.\n\n :param s: input string\n :return: string in lower case\n \"\"\"\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n \"\"\"Convert the given string to lower case.\"\"\"\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n return s.lower()", "matching_cluster_idx": 4}]}, "Mbpp/563": {"dps": 84.86338797814209, "dps_norm": 83.63636363636363, "pass@1": 26.0, "profiled": [{"solution": "import re\ndef extract_values(string):\n # Define the pattern to match items inside quotation marks\n pattern = r'\"([^\"]*)\"'\n # Find all matches using regex\n matches = re.findall(pattern, string)\n # Return the list of matches\n return matches", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(s):\n # Use a regular expression to find all sequences of characters between double quotes.\n matches = re.findall(r'\"([^\"]*)\"', s)\n # Return the found matches as a list.\n return matches", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(s):\n # Use regex to find all substrings between double quotes\n return re.findall(r'\"([^\"]*)\"', s)", "matching_cluster_idx": 8}, {"solution": "def extract_values(s):\n # Initialize an empty list to store the extracted values\n result = []\n\n # Use regular expression to find all substrings between quotation marks\n import re\n matches = re.findall(r'\"([^\"]*)\"', s)\n\n # Convert the matches to a list and return\n result.extend(matches)\n return result", "matching_cluster_idx": 8}, {"solution": "def extract_values(string):\n import re\n return re.findall(r'\"([^\"]*)\"', string)", "matching_cluster_idx": 8}, {"solution": "def extract_values(s):\n import re\n return re.findall(r'\"([^\"]*)\"', s)", "matching_cluster_idx": 8}, {"solution": "def extract_values(s):\n import re\n return re.findall(r'\"([^\"]*)\"', s)", "matching_cluster_idx": 8}, {"solution": "def extract_values(s):\n # Initialize an empty list to store the extracted values\n values = []\n\n # Check for quotation marks, and if found extract the value\n start = s.find('\"')\n while start != -1:\n end = s.find('\"', start + 1)\n if end != -1:\n values.append(s[start + 1:end])\n start = s.find('\"', end + 1)\n else:\n break\n\n return values", "matching_cluster_idx": 10}, {"solution": "import re\ndef extract_values(s):\n \"\"\"Extract values between quotation marks from a string.\"\"\"\n return re.findall(r'\"([^\"]*)\"', s)", "matching_cluster_idx": 8}, {"solution": "def extract_values(string):\n # Using regular expression to extract values between quotation marks\n import re\n return re.findall(r'\"([^\"]*)\"', string)", "matching_cluster_idx": 8}, {"solution": "def extract_values(s):\n # Start by initializing an empty list to store the extracted values\n result = []\n\n # Initialize starting index of the current word\n start = 0\n\n # Loop through each character in the input string\n for i in range(len(s)):\n\n # If the current character is a double quote and the start index is not at the beginning of the string,\n # it means we've found a complete word, so add it to the result list\n if s[i] == '\"' and start != 0:\n result.append(s[start:i])\n start = 0\n # If the current character is a double quote and the start index is at the beginning of the string,\n # it means we've found the start of a new word, so update the start index to the current position\n elif s[i] == '\"' and start == 0:\n start = i + 1\n\n return result", "matching_cluster_idx": 2}, {"solution": "def extract_values(s):\n values = []\n start = 0\n while start < len(s):\n i = s.find('\"', start)\n if i < 0:\n break\n j = s.find('\"', i+1)\n if j < 0:\n break\n values.append(s[i+1:j])\n start = j+1\n return values", "matching_cluster_idx": 10}, {"solution": "import re\ndef extract_values(s: str) -> list:\n \"\"\"Extracts values between quotation marks from a string.\"\"\"\n # Use regex to find all substrings enclosed in quotation marks\n matches = re.findall(r'\"([^\"]*)\"', s)\n return matches", "matching_cluster_idx": 8}, {"solution": "def extract_values(string):\n values = []\n start = string.find('\"')\n while start != -1:\n end = string.find('\"', start + 1)\n if end != -1:\n values.append(string[start+1:end])\n start = string.find('\"', end + 1)\n else:\n break\n return values", "matching_cluster_idx": 10}, {"solution": "def extract_values(input_string):\n # Using regular expression to find strings enclosed in quotation marks\n import re\n matches = re.findall(r'\"([^\"]*)\"', input_string)\n return matches", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(string):\n # The regex pattern for extraction\n pattern = r'\"([^\"]*)\"'\n # find all matches\n matches = re.findall(pattern, string)\n return [match for match in matches]", "matching_cluster_idx": 8}, {"solution": "def extract_values(s):\n # Use regular expression to find all substrings within quotation marks\n import re\n return re.findall(r'\"([^\"]*)\"', s)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(string):\n \"\"\"Extract values between quotation marks from a string.\"\"\"\n return re.findall(r'\"([^\"]*)\"', string)", "matching_cluster_idx": 8}, {"solution": "def extract_values(input_string):\n result = []\n start = input_string.find('\"')\n while start != -1:\n end = input_string.find('\"', start + 1)\n if end != -1:\n result.append(input_string[start + 1:end])\n start = input_string.find('\"', end + 1)\n else:\n break\n return result", "matching_cluster_idx": 10}, {"solution": "def extract_values(s):\n values = []\n start = s.find('\"')\n while start != -1:\n end = s.find('\"', start + 1)\n if end != -1:\n values.append(s[start+1:end])\n start = s.find('\"', end + 1)\n else:\n break\n return values", "matching_cluster_idx": 10}]}, "Mbpp/572": {"dps": null, "dps_norm": null, "pass@1": 0.0, "profiled": []}, "Mbpp/578": {"dps": 73.6031746031746, "dps_norm": 66.81818181818183, "pass@1": 89.0, "profiled": [{"solution": "def interleave_lists(*args):\n # Check all lists have same length\n if not all(len(lst) == len(args[0]) for lst in args):\n raise ValueError(\"All lists must have the same length\")\n\n # Interleave the lists\n result = []\n for lst in zip(*args):\n for item in lst:\n result.append(item)\n\n return result", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(*lists):\n return [item for sublist in zip(*lists) for item in sublist]", "matching_cluster_idx": 7}, {"solution": "from itertools import zip_longest\ndef interleave_lists(*lists):\n return [item for sublist in zip_longest(*lists) for item in sublist if item is not None]", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(*lists):\n return [val for sublist in zip(*lists) for val in sublist]", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(*args):\n \"\"\"Interleave multiple lists of the same length into a single list\"\"\"\n length = len(args[0])\n for lst in args[1:]:\n if len(lst) != length:\n raise ValueError(\"All input lists must be of the same length\")\n return [value for sublist in zip(*args) for value in sublist]", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(*args):\n return [elem for sublist in zip(*args) for elem in sublist]", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(*args):\n result = []\n max_len = max([len(arg) for arg in args])\n for i in range(max_len):\n for arg in args:\n if i < len(arg):\n result.append(arg[i])\n return result", "matching_cluster_idx": 4}, {"solution": "def interleave_lists(*args):\n interleave_list = []\n for i in range(max(len(arg) for arg in args)):\n for arg in args:\n try:\n interleave_list.append(arg[i])\n except IndexError:\n pass\n return interleave_list", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(*lists):\n \"\"\"Interleave multiple lists into a single flat list.\"\"\"\n # Find the length of the shortest list\n min_length = min(len(l) for l in lists)\n\n # Use list comprehension to interleave the lists\n return [x for i in range(min_length) for x in [l[i] for l in lists]]", "matching_cluster_idx": 4}, {"solution": "def interleave_lists(*lists):\n # Check if all lists have the same length\n if not all(len(l) == len(lists[0]) for l in lists):\n raise ValueError(\"All lists must have the same length\")\n\n # Interleave elements from all lists\n return [element for sublist in zip(*lists) for element in sublist]", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(*lists):\n return [element for sublist in zip(*lists) for element in sublist]", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(list1, list2, list3):\n # Check if the input lists have the same length\n assert len(list1) == len(list2) == len(list3), \"Input lists must have the same length\"\n\n # Initialize an empty list to store the interleave results\n result = []\n\n # Use a for loop to iterate over each element in the first list\n for i in range(len(list1)):\n # Interleave the elements from all three lists and append them to the result list\n result.extend([list1[i], list2[i], list3[i]])\n\n return result", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(*args):\n # zip_longest with fillvalue=None would give us pairs of lists until the shortest list ends\n # then we take the first item of each pair, then the second item and so on until all lists are done\n return [x for pair in zip(*args) for x in pair]", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(*args):\n return [item for sublist in zip(*args) for item in sublist]", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(*lists):\n return [item for sublist in zip(*lists) for item in sublist]", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(*lists):\n # Ensure all lists are of the same length\n assert all(len(lst) == len(lists[0]) for lst in lists), \"All lists must have the same length\"\n\n # Interleave lists using zip_longest from itertools which fills missing values with None\n from itertools import zip_longest\n return [elem for sublist in zip_longest(*lists) for elem in sublist if elem is not None]", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(*args):\n result = []\n max_len = max(len(lst) for lst in args)\n for i in range(max_len):\n for lst in args:\n if i < len(lst):\n result.append(lst[i])\n return result", "matching_cluster_idx": 4}, {"solution": "def interleave_lists(list1, list2, list3):\n return [val for sublist in zip(list1, list2, list3) for val in sublist]", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(*args):\n # Check if all input lists have the same length\n assert all(len(args[0]) == len(lst) for lst in args), \"All input lists should have the same length\"\n\n result = []\n for lst in zip(*args):\n result.extend(lst)\n return result", "matching_cluster_idx": 8}, {"solution": "def interleave_lists(*args):\n return [num for sublist in zip(*args) for num in sublist]", "matching_cluster_idx": 7}]}, "Mbpp/586": {"dps": 98.83040935672514, "dps_norm": 87.5, "pass@1": 16.0, "profiled": [{"solution": "def split_Arr(arr, n):\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"\n Function to split a list at the nth element and add the first part to the end.\n \"\"\"\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n # Check if index is within range\n if n < 0 or n > len(arr):\n raise ValueError(\"Invalid index\")\n\n # Split the list at the nth element and concatenate the first part to the end\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(lst, n):\n \"\"\"\n Split a list at the nth element and add the first part to the end.\n \"\"\"\n return lst[n:] + lst[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n if n < 0 or n >= len(arr):\n return arr\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(lst, n):\n \"\"\"\n Split a list at the nth element and add the first part to the end.\n \"\"\"\n return lst[n:] + lst[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n # split the array at the nth element\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(lst, n):\n # Split the list at the nth element and add the first part to the end\n return lst[n:] + lst[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(lst, n):\n # Slice the list into two parts at the nth element\n first_part, second_part = lst[:n], lst[n:]\n\n # Add the first part to the end of the second part\n return second_part + first_part", "matching_cluster_idx": 6}, {"solution": "def split_Arr(lst, n):\n \"\"\"\n This function takes a list and an index as input, splits the list at the nth element\n and adds the first part to the end of the second part.\n \"\"\"\n return lst[n:] + lst[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(lst, n):\n return lst[n:] + lst[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}]}, "Mbpp/587": {"dps": null, "dps_norm": null, "pass@1": 0.0, "profiled": []}, "Mbpp/588": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def big_diff(nums):\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(lst):\n return max(lst) - min(lst)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n if not nums:\n return 0\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n \"\"\"\n This function takes a list of numbers and returns the difference between the largest and smallest values.\n \"\"\"\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n \"\"\"\n Function to find the difference between the largest and smallest value in a given list.\n\n Args:\n nums (list): Input list\n\n Returns:\n int: Difference between the largest and smallest values in the list\n \"\"\"\n if len(nums) == 0:\n return 0 # edge case: empty list\n else:\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(lst):\n # Check if list is empty\n if not lst:\n return 0\n else:\n # Return the difference between the largest and smallest value in the list\n return max(lst) - min(lst)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n \"\"\"Find the difference between largest and smallest value in a given list.\"\"\"\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(lst):\n return max(lst) - min(lst) if lst else 0", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n \"\"\"Find the difference between the largest and smallest value in a given list.\"\"\"\n if not nums: # check if the list is empty\n raise ValueError(\"List must not be empty\")\n\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(lst):\n return max(lst) - min(lst) if lst else 0", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(lst):\n return max(lst) - min(lst)", "matching_cluster_idx": 5}, {"solution": "def big_diff(numbers):\n return max(numbers) - min(numbers)", "matching_cluster_idx": 5}, {"solution": "def big_diff(lst):\n return max(lst) - min(lst)", "matching_cluster_idx": 5}, {"solution": "def big_diff(num_list):\n # Check if the list is not empty\n if not num_list:\n return \"Error: The list is empty.\"\n\n # Find the maximum and minimum values\n max_val = max(num_list)\n min_val = min(num_list)\n\n # Return the difference between the maximum and minimum values\n return max_val - min_val", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n \"\"\"Find the difference between the largest and smallest value in a list\"\"\"\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n \"\"\"Find the difference between the largest and smallest value in the given list.\"\"\"\n if not nums: # If the list is empty\n raise ValueError(\"List must not be empty\")\n return max(nums) - min(nums)", "matching_cluster_idx": 5}]}, "Mbpp/592": {"dps": null, "dps_norm": null, "pass@1": 8.0, "profiled": []}, "Mbpp/597": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 35.0, "profiled": [{"solution": "def find_kth(arr1, arr2, k):\n # Concatenate and sort the two arrays\n merged = sorted(arr1 + arr2)\n # Return the kth element\n return merged[k - 1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(arr1, arr2, k):\n merged = sorted(arr1 + arr2)\n return merged[k-1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(arr1, arr2, k):\n merged = sorted(arr1 + arr2)\n return merged[k-1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(arr1, arr2, k):\n merged = sorted(arr1 + arr2)\n return merged[k-1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(arr1, arr2, k):\n merged = sorted(arr1 + arr2)\n return merged[k - 1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(arr1, arr2, k):\n \"\"\"\n Find the kth element from two sorted arrays.\n\n Args:\n arr1 (List[int]): The first sorted array.\n arr2 (List[int]): The second sorted array.\n k (int): The index of the kth element.\n\n Returns:\n int: The kth element from the combined array of arr1 and arr2.\n \"\"\"\n combined = sorted(arr1 + arr2)\n return combined[k-1] if k-1 < len(combined) else None", "matching_cluster_idx": 3}, {"solution": "def find_kth(lst1, lst2, k):\n merged = sorted(lst1 + lst2)\n return merged[k-1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(lst1, lst2, k):\n # Merge the two sorted arrays\n merged = sorted(lst1 + lst2)\n # Return the kth element\n return merged[k - 1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(arr1, arr2, k):\n merged = sorted(arr1 + arr2)\n return merged[k-1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(arr1, arr2, k):\n # Merge the two sorted arrays\n merged = sorted(arr1 + arr2)\n\n # Return the kth element from the merged array\n return merged[k - 1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(arr1, arr2, k):\n merged = sorted(arr1 + arr2)\n return merged[k - 1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(arr1, arr2, k):\n # Combining two arrays and sorting them\n combined = sorted(arr1 + arr2)\n\n # Returning the kth element\n return combined[k - 1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(arr1, arr2, k):\n merged = sorted(arr1 + arr2)\n return merged[k-1] if k <= len(merged) else None", "matching_cluster_idx": 3}, {"solution": "def find_kth(arr1, arr2, k):\n # Merge the two sorted arrays\n merged = sorted(arr1 + arr2)\n\n # Return the kth element from the merged array\n return merged[k-1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(arr1, arr2, k):\n merged = sorted(arr1 + arr2)\n return merged[k-1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(arr1, arr2, k):\n # Combine the two sorted arrays\n combined = sorted(arr1 + arr2)\n\n # Return the kth element from the combined array\n return combined[k - 1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(arr1, arr2, k):\n # Merge two sorted arrays\n merged = sorted(arr1 + arr2)\n # Return the kth element\n return merged[k - 1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(arr1, arr2, k):\n # Merge the two arrays into one and sort it\n merged = sorted(arr1 + arr2)\n\n # Return the kth element\n return merged[k-1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(arr1, arr2, k):\n merged = sorted(arr1 + arr2)\n return merged[k - 1]", "matching_cluster_idx": 3}, {"solution": "def find_kth(arr1, arr2, k):\n merged = sorted(arr1 + arr2)\n return merged[k - 1] if k <= len(merged) else None", "matching_cluster_idx": 3}]}, "Mbpp/604": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 74.0, "profiled": [{"solution": "def reverse_words(s):\n return \" \".join(s.split()[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(input_string):\n return ' '.join(input_string.split()[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n return ' '.join(s.split()[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(input_string):\n return ' '.join(input_string.split()[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n return ' '.join(s.split()[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n return ' '.join(s.split()[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n return ' '.join(s.split()[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s: str) -> str:\n return ' '.join(s.split()[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n return ' '.join(s.split()[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s: str) -> str:\n \"\"\"\n Reverses words separated by spaces in a given string.\n \"\"\"\n return ' '.join(s.split()[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(input_str):\n # Split the input string into words using space as a separator\n words = input_str.split()\n\n # Reverse the list of words\n reversed_words = words[::-1]\n\n # Join the reversed words back into a single string with spaces\n result = ' '.join(reversed_words)\n\n return result", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n return ' '.join(s.split()[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(sentence):\n return ' '.join(sentence.split()[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(string):\n return ' '.join(string.split()[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n return ' '.join(s.split()[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n return ' '.join(s.split()[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n return ' '.join(s.split()[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n return \" \".join(s.split()[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n return ' '.join(s.split()[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(input_str):\n return ' '.join(input_str.split()[::-1])", "matching_cluster_idx": 4}]}, "Mbpp/610": {"dps": 56.594202898550726, "dps_norm": 57.85714285714286, "pass@1": 34.0, "profiled": [{"solution": "def remove_kth_element(lst, k):\n \"\"\"Remove the k'th element from the list.\"\"\"\n if 1 <= k <= len(lst):\n return lst[:k-1] + lst[k:]\n else:\n raise ValueError(\"k is out of range\")", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(lst, k):\n \"\"\"Remove the k'th element from the list.\"\"\"\n if 0 < k <= len(lst):\n lst.pop(k - 1) # Python lists are 0-indexed, so we adjust k for this.\n return lst", "matching_cluster_idx": 5}, {"solution": "def remove_kth_element(lst, k):\n \"\"\"\n Function to remove the k'th element from the list.\n \"\"\"\n if k < 1 or k > len(lst):\n raise ValueError(\"Invalid value of k. It should be between 1 and length of the list.\")\n return lst[:k-1] + lst[k:]", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(lst, k):\n if 1 <= k <= len(lst):\n return lst[:k-1] + lst[k:]\n else:\n return lst", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(lst, k):\n \"\"\"Remove the k'th element from a list.\"\"\"\n if 0 < k <= len(lst):\n return lst[:k-1] + lst[k:]\n else:\n return lst # or raise an exception, depending on what you want to do when k is out of bounds", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(lst, k):\n if k < 1 or k > len(lst):\n return lst # Return the list as it is, if k is out of bounds\n return lst[:k-1] + lst[k:]", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(lst, k):\n if 1 <= k <= len(lst):\n return lst[:k-1] + lst[k:]\n else:\n return lst", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(lst, k):\n # Check if k is within the range of the list\n if 0 < k <= len(lst):\n return lst[:k-1] + lst[k:]\n else:\n raise ValueError(\"k should be between 1 and the length of the list.\")", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(lst, k):\n # Check if k is within valid range\n if k < 1 or k > len(lst):\n raise ValueError(\"k must be within the range of list indices.\")\n\n # Remove k'th element\n return lst[:k-1] + lst[k:]", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(input_list, k):\n # Check if k is within the valid range\n if k < 1 or k > len(input_list):\n raise ValueError(\"k should be within the range 1 to length of the list\")\n return input_list[:k-1] + input_list[k:]", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(lst, k):\n # Ensure the list is not empty and k is a valid index\n assert lst, \"List is empty\"\n assert 0 < k <= len(lst), \"k is out of range\"\n\n # Remove the k'th element (0-indexed) and return the resulting list\n return lst[:k-1] + lst[k:]", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(lst, k):\n # Check if the input list is valid\n if not isinstance(lst, list) or not all(isinstance(i, int) for i in lst) or not isinstance(k, int) or k <= 0 or k > len(lst):\n raise ValueError(\"Invalid input. Please provide a list of integers and a valid k.\")\n\n # Remove the k'th element from the list\n return lst[:k-1] + lst[k:]", "matching_cluster_idx": 2}, {"solution": "def remove_kth_element(lst, k):\n \"\"\"\n Returns a new list with the k-th element removed from the original list.\n List index starts from 1.\n \"\"\"\n return lst[:k-1] + lst[k:]", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(lst, k):\n return lst[:k-1] + lst[k:]", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(lst, k):\n # Check if k is within range\n if k < 1 or k > len(lst):\n raise ValueError(\"k is out of range\")\n # Remove k'th element and return the new list\n return lst[:k-1] + lst[k:]", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(lst, k):\n # Make sure k is within the list's length\n if k < 1 or k > len(lst):\n raise ValueError(\"k is out of range\")\n # Remove the k'th element and return the updated list\n return lst[:k-1] + lst[k:]", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(lst, k):\n return lst[:k-1] + lst[k:]", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(lst, k):\n if 1 <= k <= len(lst):\n return lst[:k-1] + lst[k:]\n else:\n return lst", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(lst, k):\n if k < 1 or k > len(lst):\n raise ValueError(\"Invalid k. It should be between 1 and the length of the list.\")\n return lst[:k-1] + lst[k:]", "matching_cluster_idx": 3}, {"solution": "def remove_kth_element(lst, k):\n return lst[:k-1] + lst[k:]", "matching_cluster_idx": 3}]}, "Mbpp/611": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 41.0, "profiled": [{"solution": "def max_of_nth(matrix, n):\n return max(column[n] for column in matrix)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n return max(col[n] for col in matrix)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n return max(row[n] for row in matrix)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n return max([row[n] for row in matrix])", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(m, n):\n return max(row[n] for row in m)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n return max(column[n] for column in matrix)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n return max(row[n] for row in matrix)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n return max([row[n] for row in matrix])", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n return max(column[n] for column in matrix)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n if len(matrix) == 0 or n >= len(matrix[0]):\n return None\n\n return max(column[n] for column in matrix)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n \"\"\"Return the max value of the nth column in a given matrix.\"\"\"\n return max(col[n] for col in matrix)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n return max(column[n] for column in matrix)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n \"\"\"\n Return the max value of the n'th column in the given matrix.\n \"\"\"\n return max(column[n] for column in matrix)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n \"\"\"\n Return the max of the n'th column of the given matrix.\n\n Args:\n matrix (list of lists): The input matrix.\n n (int): The index of the column (0-based).\n\n Returns:\n int: The max value in the n'th column.\n \"\"\"\n return max(row[n] for row in matrix)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n return max([row[n] for row in matrix])", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n \"\"\"Return the maximum of the n'th column in the given matrix.\n\n Args:\n matrix (List[List[int]]): A matrix represented as a list of lists.\n n (int): The column number.\n\n Returns:\n int: The maximum value in the n'th column.\n \"\"\"\n return max(column[n] for column in matrix)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n \"\"\"Return the maximum of the n'th column in the matrix.\"\"\"\n return max(row[n] for row in matrix)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n return max(column[n] for column in matrix)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n \"\"\"\n Returns the maximum value in the n'th column of the input matrix.\n \"\"\"\n # First, check if the matrix is empty or the n'th column doesn't exist\n if not matrix or n >= len(matrix[0]):\n return None\n\n # Initialize max_value with the first element of the n'th column\n max_value = matrix[0][n]\n\n # Iterate over the rest of the matrix and update max_value if needed\n for row in matrix[1:]:\n max_value = max(max_value, row[n])\n\n return max_value", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n return max(column[n] for column in matrix)", "matching_cluster_idx": 5}]}, "Mbpp/631": {"dps": null, "dps_norm": null, "pass@1": 1.0, "profiled": []}, "Mbpp/632": {"dps": 95.28142589118198, "dps_norm": 98.57142857142857, "pass@1": 34.0, "profiled": [{"solution": "def move_zero(lst):\n # Initialize a new list with only non-zero values from the input list\n non_zero = [x for x in lst if x != 0]\n\n # If the input list is not empty, append zeros at the end\n if non_zero:\n return non_zero + [0] * (len(lst) - len(non_zero))\n else:\n # If the input list is empty, return an empty list\n return []", "matching_cluster_idx": 6}, {"solution": "def move_zero(lst):\n return [i for i in lst if i != 0] + [i for i in lst if i == 0]", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n return [i for i in nums if i != 0] + [0] * nums.count(0)", "matching_cluster_idx": 6}, {"solution": "def move_zero(lst):\n # Use list comprehension to create a new list with only non-zero elements\n non_zero_lst = [x for x in lst if x != 0]\n # Use list comprehension to create a new list with only zero elements\n zero_lst = [0] * (len(lst) - len(non_zero_lst))\n # Combine the two lists and return the result\n return non_zero_lst + zero_lst", "matching_cluster_idx": 6}, {"solution": "def move_zero(lst):\n # Iterate over the list and remove zeroes\n zeroes = lst.count(0)\n for _ in range(zeroes):\n lst.remove(0)\n # Append zeroes to the end\n return lst + [0]*zeroes", "matching_cluster_idx": 4}, {"solution": "def move_zero(lst):\n # Using two pointers to keep track of non-zero elements\n ptr = 0\n n = len(lst)\n\n for i in range(n):\n if lst[i] != 0:\n lst[ptr], lst[i] = lst[i], lst[ptr]\n ptr += 1\n\n return lst", "matching_cluster_idx": 6}, {"solution": "def move_zero(lst):\n return [i for i in lst if i != 0] + [i for i in lst if i == 0]", "matching_cluster_idx": 6}, {"solution": "def move_zero(lst):\n # Using list comprehension to create a new list with all non-zero elements\n # followed by zero elements from the original list\n return [i for i in lst if i != 0] + [i for i in lst if i == 0]", "matching_cluster_idx": 6}, {"solution": "def move_zero(lst):\n # Count the number of zeroes in the list\n zero_count = lst.count(0)\n\n # Remove all zeroes from the list\n lst = [i for i in lst if i != 0]\n\n # Append zeroes at the end\n lst.extend([0]*zero_count)\n\n return lst", "matching_cluster_idx": 6}, {"solution": "def move_zero(arr):\n \"\"\"\n This function takes a list of integers and returns a new list with all zeroes moved to the end.\n\n :param arr: List of integers.\n :return: A new list with zeroes moved to the end.\n \"\"\"\n return [i for i in arr if i != 0] + [i for i in arr if i == 0]", "matching_cluster_idx": 6}, {"solution": "def move_zero(lst):\n \"\"\"\n Function that moves all zeroes to the end of the given list.\n\n :param lst: List of integers\n :return: List with all zeroes moved to the end\n \"\"\"\n # Use list comprehension to filter out the zeroes and create a new list\n # Then, append the remaining zeroes to the end of the new list\n return [x for x in lst if x != 0] + [0] * lst.count(0)", "matching_cluster_idx": 6}, {"solution": "def move_zero(lst):\n \"\"\"\n Move all zeroes to the end of the list.\n \"\"\"\n # Create two empty lists to hold non-zero and zero elements\n non_zero, zero = [], []\n\n # Iterate through the input list\n for num in lst:\n if num == 0:\n zero.append(num)\n else:\n non_zero.append(num)\n\n # Concatenate the two lists\n return non_zero + zero", "matching_cluster_idx": 6}, {"solution": "def move_zero(lst):\n return [i for i in lst if i != 0] + [i for i in lst if i == 0]", "matching_cluster_idx": 6}, {"solution": "def move_zero(lst):\n \"\"\"Move all zeroes to the end of the list while maintaining order of other elements.\"\"\"\n return [i for i in lst if i != 0] + [i for i in lst if i == 0]", "matching_cluster_idx": 6}, {"solution": "def move_zero(lst):\n return [i for i in lst if i != 0] + [0] * lst.count(0)", "matching_cluster_idx": 6}, {"solution": "def move_zero(lst):\n # Using list comprehension to create a new list with zeroes removed\n # and then appending zeroes to the end\n return [i for i in lst if i != 0] + [0] * lst.count(0)", "matching_cluster_idx": 6}, {"solution": "def move_zero(lst):\n # Count the number of zeros\n count = lst.count(0)\n\n # Filter out the zeros and join them at the end\n result = [i for i in lst if i != 0] + [0]*count\n\n return result", "matching_cluster_idx": 6}, {"solution": "def move_zero(lst):\n return [i for i in lst if i != 0] + [i for i in lst if i == 0]", "matching_cluster_idx": 6}, {"solution": "def move_zero(lst):\n \"\"\"Move all zeros to the end of the given list.\"\"\"\n return [i for i in lst if i != 0] + [i for i in lst if i == 0]", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n return [num for num in nums if num != 0] + [0] * nums.count(0)", "matching_cluster_idx": 6}]}, "Mbpp/633": {"dps": null, "dps_norm": null, "pass@1": 1.0, "profiled": []}, "Mbpp/644": {"dps": null, "dps_norm": null, "pass@1": 4.0, "profiled": []}, "Mbpp/720": {"dps": 93.84615384615384, "dps_norm": 98.0, "pass@1": 90.0, "profiled": [{"solution": "def add_dict_to_tuple(t, d):\n return t + (d,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(input_tuple, input_dict):\n return input_tuple + (input_dict,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(t: tuple, d: dict) -> tuple:\n return t + (d,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(tup, d):\n \"\"\"\n Adds a dictionary to the end of a given tuple.\n\n Args:\n tup (tuple): The tuple to add the dictionary to.\n d (dict): The dictionary to add to the tuple.\n\n Returns:\n tuple: The tuple with the dictionary added at the end.\n \"\"\"\n return tup + (d,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(input_tuple, input_dict):\n return input_tuple + (input_dict,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(tup, dic):\n \"\"\"Adds a dictionary to a tuple and returns a tuple.\"\"\"\n return tup + (dic,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(t, d):\n return t + (d,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(tup, dic):\n # Check if input is valid\n if not isinstance(tup, tuple) or not isinstance(dic, dict):\n raise ValueError(\"Both inputs must be a tuple and a dictionary respectively.\")\n\n # Add dictionary to tuple and return\n return tup + (dic,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(t, d):\n \"\"\"Adds a dictionary to a tuple and returns the result as a tuple.\"\"\"\n return t + (d,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(tup, dic):\n \"\"\"Add a dictionary to a tuple and return the new tuple\"\"\"\n return tup + (dic,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(tup, dct):\n return tup + (dct,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(tup, dict_to_add):\n # Check if the input is indeed a tuple\n if not isinstance(tup, tuple):\n raise TypeError(\"First argument should be a tuple\")\n # Check if the input is indeed a dictionary\n if not isinstance(dict_to_add, dict):\n raise TypeError(\"Second argument should be a dictionary\")\n\n # Add the dictionary to the tuple\n new_tuple = tup + (dict_to_add,)\n return new_tuple", "matching_cluster_idx": 3}, {"solution": "def add_dict_to_tuple(tup, dictionary):\n \"\"\"\n This function adds a dictionary to the end of the input tuple.\n\n Args:\n tup (tuple): Input tuple.\n dictionary (dict): Dictionary to be added.\n\n Returns:\n tuple: Tuple with the dictionary added.\n \"\"\"\n return tup + (dictionary,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(tup, dic):\n \"\"\"Add a dictionary to a tuple and return the resulting tuple\"\"\"\n return tup + (dic,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(tup, dic):\n return tup + (dic,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(tup: tuple, dct: dict) -> tuple:\n return tup + (dct,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(tup, dic):\n return tup + (dic,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(tup, dict_to_add):\n \"\"\"Add a dictionary to a tuple.\n\n Args:\n tup (tuple): Tuple to which dictionary will be added.\n dict_to_add (dict): Dictionary to add to the tuple.\n\n Returns:\n tuple: New tuple with the dictionary as the last element.\n \"\"\"\n # Combine the tuple and dictionary into a list\n combined = list(tup)\n combined.append(dict_to_add)\n\n # Convert the list back into a tuple and return\n return tuple(combined)", "matching_cluster_idx": 3}, {"solution": "def add_dict_to_tuple(tup, dict_to_add):\n return tup + (dict_to_add,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(tup, d):\n \"\"\"Adds a dictionary to a tuple and returns the new tuple.\"\"\"\n return tup + (d,)", "matching_cluster_idx": 4}]}, "Mbpp/725": {"dps": 74.53551912568305, "dps_norm": 75.625, "pass@1": 38.0, "profiled": [{"solution": "def extract_quotation(s: str) -> list:\n result = []\n start = s.find('\"')\n while start != -1:\n end = s.find('\"', start + 1)\n if end != -1:\n result.append(s[start+1:end])\n start = s.find('\"', end + 1)\n else:\n break\n return result", "matching_cluster_idx": 4}, {"solution": "import re\ndef extract_quotation(s):\n return re.findall(r'\"([^\"]*)\"', s)", "matching_cluster_idx": 6}, {"solution": "import re\ndef extract_quotation(s: str) -> list:\n # Using regular expression to find values between double quotations\n results = re.findall(r'\"(.*?)\"', s)\n return results", "matching_cluster_idx": 4}, {"solution": "import re\ndef extract_quotation(s):\n return re.findall(r'\"([^\"]*)\"', s)", "matching_cluster_idx": 6}, {"solution": "def extract_quotation(input_string):\n # Start a list to store extracted values\n extracted_values = []\n\n # Start of the string to check for opening quotation marks\n start = 0\n\n while True:\n # Find the index of the opening quotation mark\n start = input_string.find('\"', start)\n\n if start == -1: # If no opening quotation mark is found, break the loop\n break\n\n # Find the index of the closing quotation mark\n end = input_string.find('\"', start + 1)\n\n if end == -1: # If no closing quotation mark is found, break the loop\n break\n\n # Add the extracted value to the list\n extracted_values.append(input_string[start + 1: end])\n\n # Move the start index to the character after the closing quotation mark\n start = end + 1\n\n return extracted_values", "matching_cluster_idx": 4}, {"solution": "import re\ndef extract_quotation(input_string):\n return re.findall(r'\"([^\"]*)\"', input_string)", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(s):\n return re.findall(r'\"(.*?)\"', s)", "matching_cluster_idx": 4}, {"solution": "import re\ndef extract_quotation(s):\n return re.findall(r'\"([^\"]*)\"', s)", "matching_cluster_idx": 6}, {"solution": "def extract_quotation(s):\n result = []\n start = s.find('\"')\n while start != -1:\n end = s.find('\"', start + 1)\n if end != -1:\n result.append(s[start + 1:end])\n start = s.find('\"', end + 1)\n else:\n break\n return result", "matching_cluster_idx": 4}, {"solution": "def extract_quotation(s):\n # Use regular expression to find all substrings between quotation marks\n import re\n return re.findall(r'\"([^\"]*)\"', s)", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(s):\n # Use regex to find everything between double quotes\n return re.findall(r'\"([^\"]*)\"', s)", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(input_string):\n return re.findall(r'\"([^\"]*)\"', input_string)", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(s):\n return re.findall(r'\"([^\"]*)\"', s)", "matching_cluster_idx": 6}, {"solution": "import re\nimport unittest\ndef extract_quotation(text):\n \"\"\"\n Extract values between quotation marks of the given string.\n\n Args:\n text (str): The input string.\n\n Returns:\n list: A list of extracted values.\n \"\"\"\n return re.findall(r'\"([^\"]*)\"', text)", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(s):\n return re.findall(r'\"([^\"]*)\"', s)", "matching_cluster_idx": 6}, {"solution": "import re\ndef extract_quotation(s):\n # Use regex to match anything enclosed by double quotes and return as a list\n return re.findall(r'\"([^\"]*)\"', s)", "matching_cluster_idx": 5}, {"solution": "def extract_quotation(input_string):\n result = []\n start_index = input_string.find('\"')\n while start_index != -1:\n end_index = input_string.find('\"', start_index + 1)\n if end_index != -1:\n result.append(input_string[start_index+1 : end_index])\n start_index = input_string.find('\"', end_index + 1)\n else:\n break\n return result", "matching_cluster_idx": 4}, {"solution": "import re\ndef extract_quotation(s):\n return re.findall(r'\"([^\"]*)\"', s)", "matching_cluster_idx": 6}, {"solution": "import re\ndef extract_quotation(s):\n \"\"\"Extract values between quotation marks \" \" from a given string.\"\"\"\n return re.findall(r'\"([^\"]*)\"', s)", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(s):\n return re.findall(r'\"([^\"]*)\"', s)", "matching_cluster_idx": 6}]}, "Mbpp/732": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 97.0, "profiled": [{"solution": "def replace_specialchar(s):\n return s.replace(\" \", \":\").replace(\",\", \":\").replace(\".\", \":\")", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(s):\n return s.replace(' ', ':').replace(',', ':').replace('.', ':')", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(s):\n return s.replace(\" \", \":\").replace(\",\", \":\").replace(\".\", \":\")", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(text):\n return text.replace(' ',':').replace(',',':').replace('.',':')", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(s):\n return s.replace(' ', ':').replace(',', ':').replace('.', ':')", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(s):\n s = s.replace(' ', ':')\n s = s.replace(',', ':')\n s = s.replace('.', ':')\n return s", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(s):\n return s.replace(\" \", \":\").replace(\",\", \":\").replace(\".\", \":\")", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(s):\n return s.replace(\" \", \":\").replace(\",\", \":\").replace(\".\", \":\")", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(input_string):\n return input_string.replace(\" \", \":\").replace(\",\", \":\").replace(\".\", \":\")", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(text):\n return text.replace(\" \", \":\").replace(\",\", \":\").replace(\".\", \":\")", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(s):\n return s.replace(' ', ':').replace(',', ':').replace('.', ':')", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(string):\n \"\"\"Replace all occurrences of spaces, commas, or dots with a colon.\"\"\"\n return string.replace(\" \", \":\").replace(\",\", \":\").replace(\".\", \":\")", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(text):\n return text.replace(' ', ':').replace(',', ':').replace('.', ':')", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(s):\n # Replace spaces, commas, and dots with a colon\n return s.replace(\" \", \":\").replace(\",\", \":\").replace(\".\", \":\")", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(s):\n return s.replace(\" \", \":\").replace(\",\", \":\").replace(\".\", \":\")", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(text):\n return text.replace(\" \", \":\").replace(\",\", \":\").replace(\".\", \":\")", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(text):\n return text.replace(' ', ':').replace(',', ':').replace('.', ':')", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(s):\n return s.replace(' ', ':').replace(',', ':').replace('.', ':')", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(s):\n return s.replace(' ', ':').replace(',', ':').replace('.', ':')", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(s):\n return s.replace(' ', ':').replace(',', ':').replace('.', ':')", "matching_cluster_idx": 9}]}, "Mbpp/740": {"dps": 81.14545454545456, "dps_norm": 67.77777777777779, "pass@1": 99.0, "profiled": [{"solution": "def tuple_to_dict(tup):\n \"\"\"\n Converts a given tuple into a dictionary using adjacent elements as key-value pairs.\n \"\"\"\n return {tup[i]: tup[i+1] for i in range(0, len(tup), 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(t):\n \"\"\"\n Convert the given tuple to a key-value dictionary using adjacent elements.\n :param t: input tuple\n :return: a dictionary using adjacent elements as key-value pairs\n \"\"\"\n return {t[i]: t[i+1] for i in range(0, len(t)-1, 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(tup):\n \"\"\"\n This function converts a given tuple to a key-value dictionary\n using adjacent elements as key-value pairs.\n \"\"\"\n if len(tup) % 2 != 0:\n raise ValueError(\"Input tuple must have an even number of elements\")\n\n return {tup[i]: tup[i + 1] for i in range(0, len(tup), 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(t):\n return {t[i]: t[i + 1] for i in range(0, len(t) - 1, 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(tup):\n return {tup[i]: tup[i + 1] for i in range(0, len(tup), 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(t):\n # Check if the tuple has even number of elements\n if len(t) % 2 != 0:\n raise ValueError(\"Input tuple must have an even number of elements.\")\n\n # Convert the tuple to a dictionary\n return {t[i]: t[i+1] for i in range(0, len(t)-1, 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(t):\n return {t[i]: t[i+1] for i in range(0, len(t)-1, 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(tup):\n return {tup[i]: tup[i + 1] for i in range(0, len(tup), 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(t):\n return {t[i]: t[i+1] for i in range(0, len(t)-1, 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(sequence):\n # Check if the length of sequence is odd, as it needs to be even for the conversion\n if len(sequence) % 2 != 0:\n raise ValueError(\"Sequence must have an even length\")\n\n # Initialize the dictionary and iterate over the sequence with a step of 2\n result = {}\n for i in range(0, len(sequence), 2):\n key, value = sequence[i], sequence[i + 1]\n result[key] = value\n\n return result", "matching_cluster_idx": 4}, {"solution": "def tuple_to_dict(t):\n return {t[i]: t[i + 1] for i in range(0, len(t), 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(input_tuple):\n return {input_tuple[i]: input_tuple[i + 1] for i in range(0, len(input_tuple) - 1, 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(t):\n return {t[i]: t[i+1] for i in range(0, len(t)-1, 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(t):\n return {t[i]: t[i + 1] for i in range(0, len(t) - 1, 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(tup):\n # Check if the input is a tuple\n if not isinstance(tup, tuple) or len(tup) % 2 != 0:\n raise ValueError(\"Input must be a tuple of even length\")\n\n return dict(zip(tup[::2], tup[1::2]))", "matching_cluster_idx": 8}, {"solution": "def tuple_to_dict(tt):\n \"\"\"\n This function converts a given tuple of elements into a key-value dictionary using adjacent elements.\n :param tt: tuple\n :return: dictionary\n \"\"\"\n return {tt[i]: tt[i+1] for i in range(0, len(tt)-1, 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(t):\n return {t[i]: t[i + 1] for i in range(0, len(t) - 1, 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(input_tuple):\n if len(input_tuple) % 2 != 0:\n raise ValueError(\"Input tuple must have an even number of elements\")\n\n return {input_tuple[i]: input_tuple[i + 1] for i in range(0, len(input_tuple) - 1, 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(t):\n return {t[i]: t[i+1] for i in range(0, len(t)-1, 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(t):\n \"\"\"Convert a tuple to a key-value dictionary using adjacent elements.\"\"\"\n return {t[i]: t[i+1] for i in range(0, len(t) - 1, 2)}", "matching_cluster_idx": 5}]}, "Mbpp/744": {"dps": 89.31506849315069, "dps_norm": 92.5, "pass@1": 99.0, "profiled": [{"solution": "def check_none(t):\n \"\"\"\n Check if the given tuple has any None value or not.\n\n Args:\n t (tuple): Input tuple.\n\n Returns:\n bool: True if the tuple has any None value, False otherwise.\n \"\"\"\n return None in t", "matching_cluster_idx": 5}, {"solution": "def check_none(t):\n \"\"\"\n Check if the given tuple has any None value or not.\n \"\"\"\n return None in t", "matching_cluster_idx": 5}, {"solution": "def check_none(t):\n \"\"\"Check if given tuple has any None value.\"\"\"\n return None in t", "matching_cluster_idx": 5}, {"solution": "def check_none(t):\n \"\"\"Check if the given tuple has any None value or not.\"\"\"\n return None in t", "matching_cluster_idx": 5}, {"solution": "def check_none(t):\n return None in t", "matching_cluster_idx": 5}, {"solution": "def check_none(t):\n return None in t", "matching_cluster_idx": 5}, {"solution": "def check_none(tup):\n \"\"\"Check if any value in the given tuple is None.\"\"\"\n return any(x is None for x in tup)", "matching_cluster_idx": 1}, {"solution": "def check_none(tup):\n \"\"\"Check if the given tuple has any None value or not.\"\"\"\n return None in tup", "matching_cluster_idx": 5}, {"solution": "def check_none(input_tuple):\n \"\"\"Check if the input tuple has any None value or not\"\"\"\n return None in input_tuple", "matching_cluster_idx": 5}, {"solution": "def check_none(tup):\n # Check if None is present in the tuple\n return None in tup", "matching_cluster_idx": 5}, {"solution": "def check_none(input_tuple):\n \"\"\"\n Function to check if the given tuple has any None value or not.\n\n Args:\n input_tuple (tuple): The input tuple to be checked.\n\n Returns:\n bool: Returns True if the tuple contains None, else returns False.\n \"\"\"\n return None in input_tuple", "matching_cluster_idx": 5}, {"solution": "def check_none(tup):\n # Check if any element in the tuple is None\n return any(x is None for x in tup)", "matching_cluster_idx": 2}, {"solution": "def check_none(t):\n return None in t", "matching_cluster_idx": 5}, {"solution": "def check_none(input_tuple):\n \"\"\"\n Check if the given tuple has any None value or not.\n :param input_tuple: tuple\n :return: bool\n \"\"\"\n return None in input_tuple", "matching_cluster_idx": 5}, {"solution": "def check_none(t):\n # Iterate over each element in the tuple\n for i in t:\n # Check if any element is None\n if i is None:\n return True\n # If no None found, return False\n return False", "matching_cluster_idx": 4}, {"solution": "def check_none(tpl):\n \"\"\"\n Checks if the given tuple has any None value or not.\n Args:\n tpl (tuple): Input tuple\n Returns:\n bool: Returns True if tuple contains None, False otherwise\n \"\"\"\n return None in tpl", "matching_cluster_idx": 5}, {"solution": "def check_none(t):\n if None in t:\n return True\n return False", "matching_cluster_idx": 4}, {"solution": "def check_none(tup):\n \"\"\"\n Check if the given tuple has any None value.\n\n :param tup: Tuple to check\n :return: True if None is found, False otherwise\n \"\"\"\n return None in tup", "matching_cluster_idx": 5}, {"solution": "def check_none(tup):\n return None in tup", "matching_cluster_idx": 5}, {"solution": "def check_none(input_tuple):\n \"\"\"Check if the given tuple has any None value.\"\"\"\n # Iterate through the tuple and return True if None is found\n return None in input_tuple", "matching_cluster_idx": 5}]}, "Mbpp/750": {"dps": 45.64625850340136, "dps_norm": 50.833333333333336, "pass@1": 85.0, "profiled": [{"solution": "def add_tuple(lst, tup):\n \"\"\"Add the given tuple to the given list\"\"\"\n return lst + list(tup)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(lst, tup):\n \"\"\"Extend the given list with the elements from the given tuple.\"\"\"\n lst.extend(tup)\n return lst", "matching_cluster_idx": 5}, {"solution": "def add_tuple(lst, tup):\n # Use the extend() function to add elements of the tuple to the list\n lst.extend(tup)\n return lst", "matching_cluster_idx": 5}, {"solution": "def add_tuple(lst, tpl):\n \"\"\"Add the elements of the given tuple to the given list.\"\"\"\n return lst + list(tpl)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(to_list, to_add):\n to_list.extend(to_add)\n return to_list", "matching_cluster_idx": 5}, {"solution": "def add_tuple(lst, tup):\n return lst + list(tup)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(to_list, to_add):\n return to_list + list(to_add)", "matching_cluster_idx": 1}, {"solution": "def add_tuple(lst, tup):\n return lst + list(tup)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(to_list, to_add):\n \"\"\"Add the given tuple to the given list.\"\"\"\n return to_list + list(to_add)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(lst, tup):\n \"\"\"Add the elements of the given tuple to the given list.\"\"\"\n return lst + list(tup)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(lst, tup):\n return lst + list(tup)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(lst, tup):\n return lst + list(tup)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(lst, tup):\n return lst + list(tup)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(lst, tpl):\n \"\"\"\n Add the given tuple to the given list.\n\n Args:\n lst (list): The input list.\n tpl (tuple): The tuple to be added.\n\n Returns:\n list: The resulting list.\n \"\"\"\n return lst + list(tpl)", "matching_cluster_idx": 1}, {"solution": "def add_tuple(lst, tpl):\n return lst + list(tpl)", "matching_cluster_idx": 1}, {"solution": "def add_tuple(lst, tup):\n \"\"\"Add a tuple to the end of a list.\"\"\"\n return lst + list(tup)", "matching_cluster_idx": 1}, {"solution": "def add_tuple(lst, tup):\n \"\"\"Add the given tuple to the given list.\"\"\"\n return lst + list(tup)", "matching_cluster_idx": 1}, {"solution": "def add_tuple(lst: list, tup: tuple) -> list:\n return lst + list(tup)", "matching_cluster_idx": 1}, {"solution": "def add_tuple(lst, tpl):\n return lst + list(tpl)", "matching_cluster_idx": 1}, {"solution": "def add_tuple(to_list, to_add):\n return to_list + list(to_add)", "matching_cluster_idx": 1}]}, "Mbpp/753": {"dps": 78.12080536912752, "dps_norm": 70.0, "pass@1": 89.0, "profiled": [{"solution": "def min_k(tuples, k):\n # Sort the tuples by their second element in ascending order\n sorted_tuples = sorted(tuples, key=lambda x: x[1])\n\n # Return the first k tuples\n return sorted_tuples[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(records, k):\n # Sort the records by the second element in ascending order (i.e., by value)\n sorted_records = sorted(records, key=lambda x: x[1])\n # Return the first 'k' records\n return sorted_records[:k]", "matching_cluster_idx": 1}, {"solution": "def min_k(records, k):\n # Sort the records by second element in ascending order\n sorted_records = sorted(records, key=lambda x: x[1])\n\n # Return the first k records\n return sorted_records[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(records, k):\n return sorted(records, key=lambda x: x[1])[:k]", "matching_cluster_idx": 1}, {"solution": "def min_k(tuples, k):\n # Sort the tuples by the second element (value) in ascending order\n sorted_tuples = sorted(tuples, key=lambda x: x[1])\n\n # Return the first k tuples\n return sorted_tuples[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(tuples, k):\n # Sort tuples based on second element in ascending order\n sorted_tuples = sorted(tuples, key=lambda x: x[1])\n\n # Return the first k elements\n return sorted_tuples[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(records, k):\n # Sort the records by the second element (score) in ascending order\n sorted_records = sorted(records, key=lambda x: x[1])\n\n # Return the first k records\n return sorted_records[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(records, k):\n # Sort records by second element of tuple (record's score)\n sorted_records = sorted(records, key=lambda x: x[1])\n\n # Return the first k records with the lowest scores\n return sorted_records[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(tuples, k):\n return sorted(tuples, key=lambda x: x[1])[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(records, k):\n # Sort the records based on the second element in each tuple (score)\n sorted_records = sorted(records, key=lambda x: x[1])\n\n # Return the first k records\n return sorted_records[:k]", "matching_cluster_idx": 1}, {"solution": "def min_k(tuples_list, k):\n return sorted(tuples_list, key=lambda x: x[1])[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(tuples, k):\n # Sort the list based on the second element of each tuple\n sorted_tuples = sorted(tuples, key=lambda x: x[1])\n\n # Return the first k elements of the sorted list\n return sorted_tuples[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(tuples, k):\n # Sort the list of tuples based on the second element in each tuple (ascending order)\n sorted_tuples = sorted(tuples, key=lambda x: x[1])\n # Return the first k tuples from the sorted list\n return sorted_tuples[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(tuples, k):\n # Sort tuples based on the second element (score) in ascending order\n tuples.sort(key=lambda x: x[1])\n # Return the first k tuples\n return tuples[:k]", "matching_cluster_idx": 2}, {"solution": "from typing import Tuple, List\ndef min_k(tuples: Tuple[Tuple[str, int]], k: int) -> List[Tuple[str, int]]:\n # Sorting tuple based on the second item in ascending order\n tuples.sort(key=lambda x: x[1])\n # Returning the first k tuples\n return tuples[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(tuples_list, k):\n # Sort tuples based on the second element (score) in ascending order\n tuples_list.sort(key=lambda x: x[1])\n # Return the first k tuples\n return tuples_list[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(record_list, k):\n # Sort the record list based on the second element of each tuple in ascending order\n record_list.sort(key=lambda x: x[1])\n # Return the first k tuples\n return record_list[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(records, k):\n return sorted(records, key=lambda x: x[1])[:k]", "matching_cluster_idx": 1}, {"solution": "def min_k(records, k):\n \"\"\"\n Function to find minimum k records from a list of records (represented as tuples)\n Each record is represented as (name, score)\n \"\"\"\n return sorted(records, key=lambda x: x[1])[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(records, k):\n # Sort the records based on the second element in ascending order\n records.sort(key=lambda x: x[1])\n # Return the first k records\n return records[:k]", "matching_cluster_idx": 2}]}, "Mbpp/754": {"dps": 75.3448275862069, "dps_norm": 78.75, "pass@1": 31.0, "profiled": [{"solution": "def extract_index_list(l1, l2, l3):\n common_elements = []\n min_len = min(len(l1), len(l2), len(l3))\n\n for i in range(min_len):\n if l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n common_elements = []\n for i in range(len(l1)):\n if i < len(l2) and i < len(l3) and l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n return common_elements", "matching_cluster_idx": 4}, {"solution": "def extract_index_list(l1, l2, l3):\n common_elements = []\n min_length = min(len(l1), len(l2), len(l3))\n\n for i in range(min_length):\n if l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n \"\"\"\n Extract common elements from three lists at the same indices.\n \"\"\"\n common_elements = []\n min_length = min(len(l1), len(l2), len(l3)) # find the minimum length among the three lists\n\n for i in range(min_length):\n # check if elements are the same and append them to the result list\n if l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n # Find the length of the shortest list\n length = min(len(l1), len(l2), len(l3))\n\n # Create a list to store common elements\n common_elements = []\n\n # Iterate over the length of the shortest list\n for i in range(length):\n # Check if the elements at the current index in all lists are the same\n if l1[i] == l2[i] == l3[i]:\n # If they are, append the element to the list of common elements\n common_elements.append(l1[i])\n\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(*args):\n common_elements = []\n # check for the length of the shortest list to iterate over indices\n for i in range(min(len(arg) for arg in args)):\n # check if elements at current index in all lists are the same\n if all(args[j][i] == args[0][i] for j in range(1, len(args))):\n common_elements.append(args[0][i])\n return common_elements", "matching_cluster_idx": 1}, {"solution": "def extract_index_list(l1, l2, l3):\n return [e for i, e in enumerate(l1) if i < len(l2) and i < len(l3) and e == l2[i] and e == l3[i]]", "matching_cluster_idx": 4}, {"solution": "def extract_index_list(l1, l2, l3):\n common_elements = []\n min_len = min(len(l1), len(l2), len(l3))\n for i in range(min_len):\n if l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n # Find the length of the smallest list to iterate up to\n min_length = min(len(l1), len(l2), len(l3))\n\n # Initialize an empty list to store common elements\n common_elements = []\n\n # Iterate over indices up to the min_length\n for i in range(min_length):\n # Check if elements at current index in all lists are equal\n if l1[i] == l2[i] == l3[i]:\n # If yes, add it to the common_elements list\n common_elements.append(l1[i])\n\n # Return the list of common elements\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n # Determine the length of the shortest list\n min_len = min(len(l1), len(l2), len(l3))\n\n # Initialize the result list\n result = []\n\n # Iterate over the minimum length\n for i in range(min_len):\n # Check if the elements at the current index are equal in all lists\n if l1[i] == l2[i] == l3[i]:\n result.append(l1[i])\n\n return result", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n common_elements = []\n min_length = min(len(l1), len(l2), len(l3))\n\n for i in range(min_length):\n if l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n # Get common lengths of the lists\n common_length = min(len(l1), len(l2), len(l3))\n\n # Extract common elements\n common_elements = [l1[i] for i in range(common_length) if l1[i] == l2[i] == l3[i]]\n\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n # Get the minimum length of the lists to iterate\n min_length = min(len(l1), len(l2), len(l3))\n\n # Return list of common elements at same index\n return [l1[i] for i in range(min_length) if l1[i] == l2[i] == l3[i]]", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n # Zip the lists and convert to list of tuples\n zipped = list(zip(l1, l2, l3))\n # Use list comprehension to filter elements where all elements in tuple are equal\n result = [item for item in zipped if all(x == item[0] for x in item)]\n # Extract the common elements and return as list\n return [item[0] for item in result]", "matching_cluster_idx": 1}, {"solution": "def extract_index_list(l1, l2, l3):\n # Get the minimum length of the lists\n min_len = min(len(l1), len(l2), len(l3))\n\n # Initialize an empty list for common elements\n common_elements = []\n\n # Iterate over the indices up to the minimum length\n for i in range(min_len):\n # Check if the elements at the current index are the same in all three lists\n if l1[i] == l2[i] == l3[i]:\n # If so, append the element to the list of common elements\n common_elements.append(l1[i])\n\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n # Find common indices\n common_indices = [i for i in range(min(len(l1), len(l2), len(l3))) if l1[i] == l2[i] == l3[i]]\n\n # Return common elements at these indices\n return [l1[i] for i in common_indices]", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n common_elements = []\n for i in range(min(len(l1), len(l2), len(l3))):\n if l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n common_elements = []\n # Check length of all lists and iterate up to the length of the shortest one\n min_length = min(len(l1), len(l2), len(l3))\n for i in range(min_length):\n # Check if the elements at the same index in all lists are equal\n if l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n # Find the minimum length of the three lists\n min_length = min(len(l1), len(l2), len(l3))\n\n # Extract common elements\n common_elements = [l1[i] for i in range(min_length) if l1[i] == l2[i] == l3[i]]\n\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n common_elements = []\n min_length = min(len(l1), len(l2), len(l3))\n\n for i in range(min_length):\n if l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n\n return common_elements", "matching_cluster_idx": 6}]}, "Mbpp/755": {"dps": 75.57522123893806, "dps_norm": 90.0, "pass@1": 49.0, "profiled": [{"solution": "def second_smallest(numbers):\n if len(set(numbers)) < 2:\n return None\n return sorted(set(numbers))[1]", "matching_cluster_idx": 4}, {"solution": "def second_smallest(numbers):\n # Remove duplicates to prevent an empty list\n unique_numbers = list(set(numbers))\n\n # If there are less than 2 unique numbers, return None\n if len(unique_numbers) < 2:\n return None\n\n unique_numbers.sort()\n # Return the second element (index 1) in the sorted list\n return unique_numbers[1]", "matching_cluster_idx": 5}, {"solution": "def second_smallest(numbers):\n # Filter out duplicate values\n unique_numbers = list(set(numbers))\n # Sort unique numbers in ascending order\n unique_numbers.sort()\n # Return the second smallest number\n if len(unique_numbers) >= 2:\n return unique_numbers[1]\n else:\n return None", "matching_cluster_idx": 5}, {"solution": "def second_smallest(nums):\n if len(nums) < 2:\n return None\n\n nums = sorted(set(nums))\n return nums[1] if len(nums) >= 2 else None", "matching_cluster_idx": 5}, {"solution": "def second_smallest(nums):\n # Removing duplicate elements and sorting the list\n sorted_nums = sorted(set(nums))\n\n # Checking if there are at least two distinct elements in the list\n if len(sorted_nums) < 2:\n return None\n\n return sorted_nums[1]", "matching_cluster_idx": 5}, {"solution": "def second_smallest(numbers):\n # Removes duplicates by converting the list to a set, then back to a list\n numbers = list(set(numbers))\n # Returns None if there are less than 2 unique numbers in the list\n if len(numbers) < 2:\n return None\n # Sorts the list in ascending order and returns the second element\n return sorted(numbers)[1]", "matching_cluster_idx": 5}, {"solution": "def second_smallest(lst):\n # Remove duplicates and sort the list in ascending order\n unique_sorted_lst = sorted(set(lst))\n\n # Check if there are at least two unique elements in the list\n if len(unique_sorted_lst) < 2:\n return None\n\n # Return the second element\n return unique_sorted_lst[1]", "matching_cluster_idx": 5}, {"solution": "def second_smallest(nums):\n # Removing duplicates and sorting the list\n unique_nums = sorted(list(set(nums)))\n # Checking if list has at least two elements\n if len(unique_nums) < 2:\n return None\n else:\n return unique_nums[1]", "matching_cluster_idx": 5}, {"solution": "def second_smallest(lst):\n # Remove duplicates by converting to a set, then convert back to list\n lst = list(set(lst))\n\n # If there are less than 2 unique numbers, return None\n if len(lst) < 2:\n return None\n\n # Sort the list in ascending order\n lst.sort()\n\n # The second smallest number is the second element in the sorted list\n return lst[1]", "matching_cluster_idx": 5}, {"solution": "def second_smallest(nums):\n if len(set(nums)) < 2:\n return None\n nums = sorted(set(nums))\n return nums[1]", "matching_cluster_idx": 4}, {"solution": "def second_smallest(numbers):\n \"\"\"\n This function finds the second smallest number in a list.\n\n Args:\n numbers (list of int or float): The list of numbers.\n\n Returns:\n The second smallest number, or None if the list has less than 2 distinct elements.\n \"\"\"\n unique_numbers = set(numbers)\n if len(unique_numbers) < 2:\n return None\n unique_numbers = list(unique_numbers)\n unique_numbers.sort()\n return unique_numbers[1]", "matching_cluster_idx": 5}, {"solution": "def second_smallest(nums):\n # Return None if the list has less than 2 elements\n if len(nums) < 2:\n return None\n\n # Initialize the smallest and second_smallest variables with the first and second elements\n smallest = second_smallest = float('inf')\n\n # Iterate over the numbers\n for num in nums:\n # If the current number is smaller than the smallest, update smallest and second_smallest\n if num < smallest:\n second_smallest = smallest\n smallest = num\n # If the current number is between smallest and second_smallest, update second_smallest\n elif num < second_smallest and num != smallest:\n second_smallest = num\n\n # Return second_smallest if it's not infinity\n return second_smallest if second_smallest != float('inf') else None", "matching_cluster_idx": 4}, {"solution": "def second_smallest(numbers):\n # Handle edge cases\n if len(numbers) < 2:\n return None\n\n # Initialize smallest and second_smallest variables\n smallest = float('inf')\n second_smallest = float('inf')\n\n # Iterate through the list\n for num in numbers:\n # Update smallest and second_smallest if necessary\n if num < smallest:\n smallest, second_smallest = num, smallest\n elif smallest < num < second_smallest:\n second_smallest = num\n\n # Return second_smallest or None if not found\n if second_smallest == float('inf'):\n return None\n else:\n return second_smallest", "matching_cluster_idx": 3}, {"solution": "def second_smallest(lst):\n # If length of the list is less than 2, return None (or any appropriate value depending on the problem context)\n if len(lst) < 2:\n return None\n\n # Initialize variables to store the smallest and second smallest numbers\n smallest = second_smallest = float('inf')\n\n # Iterate through the list and update the smallest and second smallest numbers\n for num in lst:\n if num < smallest:\n second_smallest = smallest\n smallest = num\n elif num < second_smallest and num != smallest:\n second_smallest = num\n\n # If second_smallest remained as float('inf'), it means there's no unique second smallest number in the list\n return second_smallest if second_smallest != float('inf') else None", "matching_cluster_idx": 4}, {"solution": "def second_smallest(numbers):\n # First, remove duplicates from the list\n unique_numbers = list(set(numbers))\n # Sort the list in ascending order\n unique_numbers.sort()\n # Check if the list has at least two elements\n if len(unique_numbers) >= 2:\n return unique_numbers[1]\n else:\n return None", "matching_cluster_idx": 5}, {"solution": "def second_smallest(numbers):\n # Filter out the duplicates\n unique_numbers = list(set(numbers))\n # Check if there are at least two unique numbers\n if len(unique_numbers) < 2:\n return None\n # Sort the list and return the second item\n unique_numbers.sort()\n return unique_numbers[1]", "matching_cluster_idx": 5}, {"solution": "def second_smallest(numbers):\n if len(numbers) < 2:\n return None\n first, second = float('inf'), float('inf')\n for num in numbers:\n if num < first:\n first, second = num, first\n elif first < num < second:\n second = num\n return second if second != float('inf') else None", "matching_cluster_idx": 3}, {"solution": "def second_smallest(numbers):\n if len(numbers) < 2:\n return None\n smallest, second_smallest = float('inf'), float('inf')\n for num in numbers:\n if num < smallest:\n second_smallest = smallest\n smallest = num\n elif smallest < num < second_smallest:\n second_smallest = num\n return second_smallest if second_smallest != float('inf') else None", "matching_cluster_idx": 3}, {"solution": "def second_smallest(lst):\n if len(set(lst)) < 2:\n return None\n else:\n return sorted(set(lst))[1]", "matching_cluster_idx": 4}, {"solution": "def second_smallest(numbers):\n # Check if there are at least two unique numbers in the list\n if len(set(numbers)) < 2:\n return None\n\n # Sort the list and return the second smallest number\n return sorted(set(numbers))[1]", "matching_cluster_idx": 4}]}, "Mbpp/757": {"dps": 82.71028037383178, "dps_norm": 23.076923076923077, "pass@1": 45.0, "profiled": [{"solution": "def count_reverse_pairs(str_list):\n return sum(1 for i in range(len(str_list)) for j in range(i+1, len(str_list)) if str_list[i][::-1] == str_list[j])", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(word_list):\n pairs_count = 0\n for i in range(len(word_list)):\n for j in range(i+1, len(word_list)):\n if word_list[i] == word_list[j][::-1]:\n pairs_count += 1\n return pairs_count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(lst):\n count = 0\n for i in range(len(lst)):\n for j in range(i+1, len(lst)):\n if lst[i] == lst[j][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(arr):\n count = 0\n for i in range(len(arr)):\n for j in range(i+1, len(arr)):\n if arr[i] == arr[j][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(lst):\n count = 0\n for i in range(len(lst)):\n for j in range(i+1, len(lst)):\n if lst[i] == lst[j][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(strings):\n count = 0\n for i in range(len(strings)):\n for j in range(i + 1, len(strings)):\n if strings[i] == strings[j][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(lst):\n \"\"\"\n Count the number of pairs of reverse strings in the given list.\n\n :param lst: List of strings\n :return: Number of reverse pairs\n \"\"\"\n return sum(1 for i in range(len(lst)) for j in range(i+1, len(lst)) if lst[i] == lst[j][::-1])", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(lst):\n \"\"\"\n Counts the pairs of reverse strings in the given string list.\n \"\"\"\n count = 0\n for i in range(len(lst)):\n for j in range(i + 1, len(lst)):\n if lst[i] == lst[j][::-1]: # Check if strings are reverse of each other\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(lst):\n count = 0\n for i in range(len(lst)):\n for j in range(i+1, len(lst)):\n if lst[i] == lst[j][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(str_list):\n \"\"\"Count pairs of reverse strings in the given string list.\"\"\"\n pairs = 0\n for i in range(len(str_list)):\n for j in range(i+1, len(str_list)):\n if str_list[i][::-1] == str_list[j]:\n pairs += 1\n return pairs", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(strings):\n count = 0\n for i in range(len(strings)):\n for j in range(i+1, len(strings)):\n if strings[i] == strings[j][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(strings):\n pairs = 0\n for i in range(len(strings)):\n for j in range(i+1, len(strings)):\n if strings[i] == strings[j][::-1]:\n pairs += 1\n return pairs", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(strings):\n # Helper function to check if two strings are reverse of each other\n def is_reverse(s1, s2):\n return s1 == s2[::-1]\n\n # Initialize counter\n count = 0\n\n # Iterate over all pairs of strings\n for i in range(len(strings)):\n for j in range(i+1, len(strings)):\n # If strings are reverse of each other, increment count\n if is_reverse(strings[i], strings[j]):\n count += 1\n\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(input_list):\n count = 0\n for i in range(len(input_list)):\n for j in range(i + 1, len(input_list)):\n if input_list[i] == input_list[j][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(string_list):\n count = 0\n for i in range(len(string_list)):\n for j in range(i+1, len(string_list)):\n if string_list[i] == string_list[j][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(strings):\n count = 0\n for i in range(len(strings)):\n for j in range(i + 1, len(strings)):\n if strings[i] == strings[j][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(string_list):\n \"\"\"Count the number of pairs of reverse strings in the given list.\"\"\"\n pairs = 0\n for i in range(len(string_list)):\n for j in range(i+1, len(string_list)):\n if string_list[i] == string_list[j][::-1]:\n pairs += 1\n return pairs", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(words):\n reverse_count = 0\n for i in range(len(words)):\n for j in range(i+1, len(words)):\n if words[i] == words[j][::-1]: # Check if strings are reverse of each other\n reverse_count += 1\n return reverse_count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(str_list):\n count = 0\n for i in range(len(str_list)):\n for j in range(i + 1, len(str_list)):\n if str_list[i][::-1] == str_list[j]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(strings):\n count = 0\n for i in range(len(strings)):\n for j in range(i+1, len(strings)):\n if strings[i] == strings[j][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}]}, "Mbpp/758": {"dps": 74.2084942084942, "dps_norm": 78.75, "pass@1": 89.0, "profiled": [{"solution": "def unique_sublists(sublists):\n result = {}\n for sublist in sublists:\n tuple_sublist = tuple(sublist)\n if tuple_sublist in result:\n result[tuple_sublist] += 1\n else:\n result[tuple_sublist] = 1\n return result", "matching_cluster_idx": 6}, {"solution": "from collections import Counter\ndef unique_sublists(input_list):\n # Convert sublists to tuples and count occurrences\n counts = Counter(tuple(sublist) for sublist in input_list)\n return dict(counts)", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(lst):\n sublist_counter = {}\n for sublist in lst:\n tuple_sub = tuple(sublist)\n if tuple_sub in sublist_counter:\n sublist_counter[tuple_sub] += 1\n else:\n sublist_counter[tuple_sub] = 1\n return sublist_counter", "matching_cluster_idx": 6}, {"solution": "from collections import defaultdict\ndef unique_sublists(lst):\n counts = defaultdict(int)\n for sublist in lst:\n sublist_tuple = tuple(sublist)\n counts[sublist_tuple] += 1\n return dict(counts)", "matching_cluster_idx": 5}, {"solution": "def unique_sublists(lst):\n sublists = {}\n for sublist in lst:\n tuple_sublist = tuple(sublist)\n if tuple_sublist in sublists:\n sublists[tuple_sublist] += 1\n else:\n sublists[tuple_sublist] = 1\n return sublists", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(lst):\n sublist_dict = {}\n for sublist in lst:\n tpl = tuple(sublist)\n sublist_dict[tpl] = sublist_dict.get(tpl, 0) + 1\n return sublist_dict", "matching_cluster_idx": 5}, {"solution": "from collections import defaultdict\ndef unique_sublists(nested_list):\n sublist_dict = defaultdict(int)\n for sublist in nested_list:\n sublist_tuple = tuple(sublist)\n sublist_dict[sublist_tuple] += 1\n return dict(sublist_dict)", "matching_cluster_idx": 5}, {"solution": "def unique_sublists(input_list):\n # Use a dictionary to count occurrences\n count_dict = {}\n for sublist in input_list:\n tuple_sublist = tuple(sublist)\n count_dict[tuple_sublist] = count_dict.get(tuple_sublist, 0) + 1\n return count_dict", "matching_cluster_idx": 5}, {"solution": "from typing import List, Dict, Tuple\ndef unique_sublists(input_list: List[List[int]]) -> Dict[Tuple[int, ...], int]:\n counter = {}\n for sublist in input_list:\n tuple_sublist = tuple(sublist)\n counter[tuple_sublist] = counter.get(tuple_sublist, 0) + 1\n return counter", "matching_cluster_idx": 5}, {"solution": "from collections import defaultdict\ndef unique_sublists(lst):\n sublist_count = defaultdict(int)\n for sublist in lst:\n sublist_tuple = tuple(sublist)\n sublist_count[sublist_tuple] += 1\n return dict(sublist_count)", "matching_cluster_idx": 5}, {"solution": "def unique_sublists(lst):\n sublist_freq = {}\n for sublist in lst:\n sublist_tuple = tuple(sublist)\n if sublist_tuple in sublist_freq:\n sublist_freq[sublist_tuple] += 1\n else:\n sublist_freq[sublist_tuple] = 1\n return sublist_freq", "matching_cluster_idx": 5}, {"solution": "def unique_sublists(lst):\n # Convert lists to tuples and store them in a dictionary\n # with counts of their occurrence\n counts = {}\n for sublist in lst:\n counts[tuple(sublist)] = counts.get(tuple(sublist), 0) + 1\n return counts", "matching_cluster_idx": 5}, {"solution": "from collections import defaultdict\ndef unique_sublists(nested_list):\n count_dict = defaultdict(int)\n for sublist in nested_list:\n # Convert the sublist to a tuple\n tpl = tuple(sublist)\n count_dict[tpl] += 1\n return count_dict", "matching_cluster_idx": 5}, {"solution": "from collections import defaultdict\ndef unique_sublists(lst):\n counter = defaultdict(int)\n for sublist in lst:\n counter[tuple(sublist)] += 1\n return dict(counter)", "matching_cluster_idx": 5}, {"solution": "from collections import defaultdict\ndef unique_sublists(lst):\n count = defaultdict(int)\n\n for sublist in lst:\n # Convert sublist to tuple and count its occurrences\n count[tuple(sublist)] += 1\n\n return dict(count)", "matching_cluster_idx": 5}, {"solution": "def unique_sublists(input_list):\n result = {}\n for sublist in input_list:\n sublist_tuple = tuple(sublist)\n if sublist_tuple not in result:\n result[sublist_tuple] = 0\n result[sublist_tuple] += 1\n return result", "matching_cluster_idx": 5}, {"solution": "def unique_sublists(lst):\n sublist_counts = {}\n for sublist in lst:\n tuple_sublist = tuple(sublist)\n sublist_counts[tuple_sublist] = sublist_counts.get(tuple_sublist, 0) + 1\n return sublist_counts", "matching_cluster_idx": 5}, {"solution": "from collections import Counter\ndef unique_sublists(lst):\n tuples = [tuple(item) for item in lst]\n return dict(Counter(tuples))", "matching_cluster_idx": 6}, {"solution": "from collections import defaultdict\ndef unique_sublists(nested_list):\n # Create a defaultdict to store count of each sublist\n counts = defaultdict(int)\n\n # Iterate over the nested list\n for sublist in nested_list:\n # Convert each sublist to a tuple and increment its count in the dictionary\n counts[tuple(sublist)] += 1\n\n return dict(counts)", "matching_cluster_idx": 5}, {"solution": "from typing import List, Tuple, Dict\ndef unique_sublists(sublists: List[List[int]]) -> Dict[Tuple, int]:\n counter = {}\n for s in sublists:\n t = tuple(s)\n counter[t] = counter.get(t, 0) + 1\n return counter", "matching_cluster_idx": 6}]}, "Mbpp/760": {"dps": null, "dps_norm": null, "pass@1": 0.0, "profiled": []}, "Mbpp/764": {"dps": 90.86419753086419, "dps_norm": 53.333333333333336, "pass@1": 88.0, "profiled": [{"solution": "def number_ctr(s: str) -> int:\n return sum(1 for char in s if char.isdigit())", "matching_cluster_idx": 2}, {"solution": "def number_ctr(string):\n \"\"\"\n Function to count the number of digits in a given string.\n\n Args:\n string (str): Input string\n\n Returns:\n int: Number of digits in the string\n \"\"\"\n return sum(1 for char in string if char.isdigit())", "matching_cluster_idx": 2}, {"solution": "def number_ctr(string):\n \"\"\"\n Counts the number of digits in a given string.\n\n Args:\n string (str): The input string.\n\n Returns:\n int: The number of digits in the string.\n \"\"\"\n return len([char for char in string if char.isdigit()])", "matching_cluster_idx": 3}, {"solution": "def number_ctr(s):\n return sum(1 for c in s if c.isdigit())", "matching_cluster_idx": 2}, {"solution": "def number_ctr(string):\n \"\"\"Counts the number of digits in a given string\"\"\"\n return sum(1 for char in string if char.isdigit())", "matching_cluster_idx": 2}, {"solution": "def number_ctr(input_string):\n \"\"\"Counts the number of digits in a given string.\"\"\"\n return sum(1 for char in input_string if char.isdigit())", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n \"\"\"\n This function counts the number of digits in the given string.\n\n :param s: str - the input string\n :return: int - the count of digits\n \"\"\"\n return sum(c.isdigit() for c in s)", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n \"\"\"\n Counts the number of digits in a given string.\n\n :param s: Input string\n :return: Number of digits in the string\n \"\"\"\n return sum(1 for char in s if char.isdigit())", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n return len([digit for digit in s if digit.isdigit()])", "matching_cluster_idx": 3}, {"solution": "def number_ctr(s):\n \"\"\"\n This function takes a string as input and returns the number of digits in the string.\n \"\"\"\n return sum(1 for char in s if char.isdigit())", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n \"\"\"\n Count the number of digits in a given string.\n\n Args:\n s (str): the input string\n\n Returns:\n int: the count of digits in the string\n \"\"\"\n return sum(c.isdigit() for c in s)", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s: str) -> int:\n return len([char for char in s if char.isdigit()])", "matching_cluster_idx": 3}, {"solution": "def number_ctr(s):\n \"\"\"\n Counts the number of digits in the given string.\n\n Args:\n s (str): The input string.\n\n Returns:\n int: The number of digits in the string.\n \"\"\"\n return sum(c.isdigit() for c in s)", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n \"\"\"\n Counts the number of digits in a given string.\n Args:\n s (str): Input string\n Returns:\n int: Count of digits in the string\n \"\"\"\n return sum(char.isdigit() for char in s)", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s: str) -> int:\n \"\"\"Count the number of digits in a given string.\"\"\"\n return sum(c.isdigit() for c in s)", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n # Using built-in filter function to find digits\n # sum() is used to count the number of True values (i.e., digits)\n return sum(c.isdigit() for c in s)", "matching_cluster_idx": 2}, {"solution": "def number_ctr(input_string):\n count = sum(c.isdigit() for c in input_string)\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s: str) -> int:\n return len([char for char in s if char.isdigit()])", "matching_cluster_idx": 3}, {"solution": "def number_ctr(s):\n \"\"\"Return the number of digits in the given string.\"\"\"\n return sum(1 for char in s if char.isdigit())", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s: str) -> int:\n # Return the count of digits in the string using a list comprehension\n return sum(1 for c in s if c.isdigit())", "matching_cluster_idx": 2}]}, "Mbpp/766": {"dps": 81.35514018691589, "dps_norm": 68.33333333333334, "pass@1": 94.0, "profiled": [{"solution": "def pair_wise(lst):\n # Use zip() with a range offset to get pairs of consecutive items\n return list(zip(lst, lst[1:]))", "matching_cluster_idx": 5}, {"solution": "def pair_wise(lst):\n return [(lst[i], lst[i+1]) for i in range(len(lst)-1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n # Check if input is a list\n if not isinstance(lst, list):\n raise TypeError(\"Input should be a list\")\n\n # Return a list of pairs of consecutive items\n return [(lst[i], lst[i+1]) for i in range(len(lst)-1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n # Check if the list has at least two elements\n if len(lst) < 2:\n return []\n\n # Use list comprehension to create pairs of consecutive items\n return [(lst[i], lst[i+1]) for i in range(len(lst)-1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n \"\"\"\n Return a list of all pairs of consecutive items in the given list.\n \"\"\"\n return [(lst[i], lst[i+1]) for i in range(len(lst)-1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n return [(lst[i], lst[i + 1]) for i in range(len(lst) - 1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n return [(lst[i], lst[i + 1]) for i in range(len(lst) - 1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n return [(lst[i], lst[i + 1]) for i in range(len(lst) - 1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n return [(lst[i], lst[i+1]) for i in range(len(lst)-1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(input_list):\n # Iterate over the input list, pair each item with the next one\n # If we're at the last item, return an empty list for this pair\n return [(input_list[i], input_list[i+1]) for i in range(len(input_list)-1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n return [(lst[i], lst[i + 1]) for i in range(len(lst) - 1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n return [(lst[i], lst[i+1]) for i in range(len(lst)-1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n return [(lst[i], lst[i + 1]) for i in range(len(lst) - 1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n return [(lst[i], lst[i+1]) for i in range(len(lst)-1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(input_list):\n # Using list comprehension and zip function to generate pairs of consecutive items\n return [(input_list[i], input_list[i + 1]) for i in range(len(input_list) - 1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n return [(lst[i], lst[i+1]) for i in range(len(lst)-1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n return [(lst[i], lst[i+1]) for i in range(len(lst)-1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n return [(lst[i], lst[i + 1]) for i in range(len(lst) - 1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n return [(lst[i], lst[i+1]) for i in range(len(lst)-1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n return [(lst[i], lst[i+1]) for i in range(len(lst)-1)]", "matching_cluster_idx": 3}]}, "Mbpp/775": {"dps": 69.03999999999999, "dps_norm": 47.14285714285714, "pass@1": 61.0, "profiled": [{"solution": "def odd_position(lst):\n \"\"\"\n This function checks whether every odd index contains odd numbers of a given list.\n \"\"\"\n return all(lst[i] % 2 != 0 for i in range(1, len(lst), 2))", "matching_cluster_idx": 3}, {"solution": "def odd_position(nums):\n return all(num % 2 == 1 for i, num in enumerate(nums) if i % 2 != 0)", "matching_cluster_idx": 2}, {"solution": "def odd_position(lst):\n return all(lst[i] % 2 != 0 for i in range(1, len(lst), 2))", "matching_cluster_idx": 2}, {"solution": "def odd_position(lst):\n \"\"\"\n Check whether every odd index contains odd numbers in a given list.\n\n Args:\n lst (List[int]): The input list\n\n Returns:\n bool: True if every odd index contains odd number, False otherwise.\n \"\"\"\n return all(lst[i] % 2 != 0 for i in range(1, len(lst), 2))", "matching_cluster_idx": 2}, {"solution": "def odd_position(lst):\n return all(lst[i] % 2 != 0 for i in range(1, len(lst), 2))", "matching_cluster_idx": 2}, {"solution": "def odd_position(lst):\n \"\"\"\n Check whether every odd index contains odd numbers in a given list.\n\n Parameters:\n lst (list): The list to check\n\n Returns:\n bool: True if every odd index contains an odd number, False otherwise\n \"\"\"\n return all(lst[i] % 2 != 0 for i in range(1, len(lst), 2))", "matching_cluster_idx": 2}, {"solution": "def odd_position(lst):\n # Check if every element at odd indices is odd\n return all(lst[i] % 2 != 0 for i in range(1, len(lst), 2))", "matching_cluster_idx": 2}, {"solution": "def odd_position(lst):\n return all(lst[i] % 2 != 0 for i in range(1, len(lst), 2))", "matching_cluster_idx": 2}, {"solution": "def odd_position(lst):\n \"\"\"\n Function to check whether every odd index contains odd number in a given list.\n \"\"\"\n return all(lst[i] % 2 != 0 for i in range(1, len(lst), 2))", "matching_cluster_idx": 2}, {"solution": "def odd_position(lst):\n # Check if every element at an odd index is odd\n return all(lst[i] % 2 != 0 for i in range(1, len(lst), 2))", "matching_cluster_idx": 2}, {"solution": "def odd_position(lst):\n return all(x % 2 == 1 for i, x in enumerate(lst) if i % 2 != 0)", "matching_cluster_idx": 2}, {"solution": "def odd_position(lst):\n # Check if the list is empty\n if not lst:\n return False\n\n # Check if every odd index contains odd numbers\n for i in range(1, len(lst), 2):\n if lst[i] % 2 == 0:\n return False\n\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n \"\"\"\n Function to check if every odd index contains odd numbers in a given list.\n \"\"\"\n return all(lst[i] % 2 != 0 for i in range(1, len(lst), 2))", "matching_cluster_idx": 2}, {"solution": "def odd_position(lst):\n return all(lst[i] % 2 != 0 for i in range(1, len(lst), 2))", "matching_cluster_idx": 2}, {"solution": "def odd_position(numbers):\n \"\"\"\n Checks if every odd index in the given list contains an odd number.\n\n Args:\n numbers: list of integers\n\n Returns:\n bool: True if all odd-indexed numbers are odd, False otherwise\n \"\"\"\n return all(numbers[i] % 2 == 1 for i in range(1, len(numbers), 2))", "matching_cluster_idx": 2}, {"solution": "def odd_position(lst):\n return all(lst[i] % 2 == 1 for i in range(1, len(lst), 2))", "matching_cluster_idx": 3}, {"solution": "def odd_position(lst):\n return all(lst[i] % 2 != 0 for i in range(1, len(lst), 2))", "matching_cluster_idx": 2}, {"solution": "def odd_position(lst):\n \"\"\"\n Function to check whether every odd index contains odd numbers in a given list.\n \"\"\"\n return all(lst[i] % 2 != 0 for i in range(1, len(lst), 2))", "matching_cluster_idx": 2}, {"solution": "def odd_position(lst):\n \"\"\"\n Checks whether every odd index of the list contains an odd number.\n \"\"\"\n return all(lst[i] % 2 != 0 for i in range(1, len(lst), 2))", "matching_cluster_idx": 2}, {"solution": "def odd_position(lst):\n \"\"\"\n Check if every odd index contains an odd number in a given list.\n \"\"\"\n # Loop through the list starting from the first element (odd index)\n for i in range(1, len(lst), 2):\n # If an element at an odd index is even, return False\n if lst[i] % 2 == 0:\n return False\n # If the function didn't return earlier, return True\n return True", "matching_cluster_idx": 4}]}, "Mbpp/777": {"dps": 79.54081632653062, "dps_norm": 85.55555555555556, "pass@1": 79.0, "profiled": [{"solution": "def find_sum(nums):\n # Use a set to automatically remove duplicates (not allowing repeat insertions)\n unique_nums = set(nums)\n return sum(unique_nums)", "matching_cluster_idx": 8}, {"solution": "def find_sum(lst):\n \"\"\"Find the sum of non-repeated elements in a given list.\"\"\"\n seen = set()\n total = 0\n for num in lst:\n if num not in seen:\n seen.add(num)\n total += num\n return total", "matching_cluster_idx": 4}, {"solution": "def find_sum(numbers):\n return sum(num for num in set(numbers))", "matching_cluster_idx": 5}, {"solution": "def find_sum(numbers):\n no_repeat = set(numbers)\n return sum(no_repeat)", "matching_cluster_idx": 8}, {"solution": "def find_sum(numbers):\n \"\"\"Return the sum of unique numbers in the given list.\"\"\"\n return sum(set(numbers))", "matching_cluster_idx": 8}, {"solution": "def find_sum(lst):\n return sum(set(lst))", "matching_cluster_idx": 8}, {"solution": "def find_sum(nums):\n # Use set to remove duplicates, then return sum\n return sum(set(nums))", "matching_cluster_idx": 8}, {"solution": "def find_sum(input_list):\n # Using a set to remove duplicates, then sum the remaining numbers\n return sum(set(input_list))", "matching_cluster_idx": 8}, {"solution": "def find_sum(numbers):\n # Use a set to eliminate repeated elements and sum the remaining elements\n return sum(set(numbers))", "matching_cluster_idx": 8}, {"solution": "def find_sum(nums):\n # Using set to remove duplicates and then calculate the sum\n return sum(set(nums))", "matching_cluster_idx": 8}, {"solution": "def find_sum(numbers):\n \"\"\"\n Function to find the sum of non-repeated elements in a given list.\n\n Args:\n numbers (list): Input list\n\n Returns:\n int: Sum of non-repeated elements in the list\n \"\"\"\n seen = set() # Keep track of seen numbers\n sum_of_non_repeated = 0 # Initialize sum to 0\n\n for num in numbers:\n if num not in seen: # If number is not seen before\n sum_of_non_repeated += num # Add it to the sum\n seen.add(num) # Mark the number as seen\n\n return sum_of_non_repeated", "matching_cluster_idx": 4}, {"solution": "def find_sum(lst):\n return sum(i for i in set(lst))", "matching_cluster_idx": 5}, {"solution": "def find_sum(nums):\n # Use set to remove duplicates and then sum the unique elements\n return sum(set(nums))", "matching_cluster_idx": 8}, {"solution": "def find_sum(lst):\n # use a set to automatically remove duplicates\n unique_nums = set(lst)\n # then sum up the unique numbers\n return sum(unique_nums)", "matching_cluster_idx": 8}, {"solution": "def find_sum(nums):\n # Use a set to store unique numbers and calculate their sum\n unique_sum = sum(set(nums))\n return unique_sum", "matching_cluster_idx": 8}, {"solution": "def find_sum(numbers):\n # Use a set to automatically remove duplicates, then sum the remaining elements\n return sum(set(numbers))", "matching_cluster_idx": 8}, {"solution": "def find_sum(lst):\n seen = set()\n sum_of_non_repeated = 0\n\n for num in lst:\n if num not in seen:\n seen.add(num)\n sum_of_non_repeated += num\n\n return sum_of_non_repeated", "matching_cluster_idx": 4}, {"solution": "def find_sum(lst):\n return sum(set(lst))", "matching_cluster_idx": 8}, {"solution": "def find_sum(nums):\n seen = set()\n sum_nums = 0\n\n for num in nums:\n if num not in seen:\n seen.add(num)\n sum_nums += num\n\n return sum_nums", "matching_cluster_idx": 4}, {"solution": "def find_sum(nums):\n non_repeated_sum = 0\n seen = set()\n\n for num in nums:\n if num not in seen:\n non_repeated_sum += num\n seen.add(num)\n\n return non_repeated_sum", "matching_cluster_idx": 4}]}, "Mbpp/781": {"dps": 83.26771653543307, "dps_norm": 42.0, "pass@1": 53.0, "profiled": [{"solution": "def count_divisors(n):\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count % 2 == 0", "matching_cluster_idx": 1}, {"solution": "def count_divisors(n):\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n if n // i == i:\n count += 1\n else:\n count += 2\n return count % 2 == 0", "matching_cluster_idx": 3}, {"solution": "def count_divisors(n):\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count % 2 == 0", "matching_cluster_idx": 1}, {"solution": "from math import isqrt\ndef count_divisors(n):\n if n <= 0:\n raise ValueError(\"Input must be a positive integer\")\n count = 0\n for i in range(1, isqrt(n) + 1):\n if n % i == 0:\n count += 1 if i == n // i else 2\n return count % 2 == 0", "matching_cluster_idx": 3}, {"solution": "def count_divisors(n):\n \"\"\"\n This function takes an integer 'n' as input and returns the number of divisors of 'n'.\n It then checks if the count of divisors is even.\n \"\"\"\n count = 0\n for i in range(1, n+1):\n if n % i == 0:\n count += 1\n return count % 2 == 0", "matching_cluster_idx": 1}, {"solution": "def count_divisors(n):\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count % 2 == 0", "matching_cluster_idx": 1}, {"solution": "def count_divisors(n):\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count % 2 == 0", "matching_cluster_idx": 1}, {"solution": "def count_divisors(n):\n # Helper function to check if a number is a divisor\n def is_divisor(x):\n return n % x == 0\n\n # Count the number of divisors using a generator\n count = sum(1 for i in range(1, n + 1) if is_divisor(i))\n\n # Check if the count of divisors is even\n return count % 2 == 0", "matching_cluster_idx": -1}, {"solution": "def count_divisors(n):\n count = 0\n for i in range(1, n+1):\n if n % i == 0:\n count += 1\n return count % 2 == 0", "matching_cluster_idx": 1}, {"solution": "def count_divisors(n):\n count = 0\n for i in range(1, n+1):\n if n % i == 0:\n count += 1\n return count % 2 == 0", "matching_cluster_idx": 1}, {"solution": "def count_divisors(n):\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count % 2 == 0", "matching_cluster_idx": 1}, {"solution": "def count_divisors(n):\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count % 2 == 0", "matching_cluster_idx": 1}, {"solution": "def count_divisors(n):\n count = 0\n for i in range(1, n+1):\n if n % i == 0:\n count += 1\n return count % 2 == 0", "matching_cluster_idx": 1}, {"solution": "def count_divisors(n):\n \"\"\"\n This function counts the number of divisors for a given number n.\n It returns True if the count is even, False otherwise.\n \"\"\"\n count = 0\n for i in range(1, n+1):\n if n % i == 0:\n count += 1\n return count % 2 == 0", "matching_cluster_idx": 1}, {"solution": "def count_divisors(n):\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count % 2 == 0", "matching_cluster_idx": 1}, {"solution": "def count_divisors(n):\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count % 2 == 0", "matching_cluster_idx": 1}, {"solution": "def count_divisors(n):\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count % 2 == 0", "matching_cluster_idx": 1}, {"solution": "def count_divisors(n):\n count = 0\n for i in range(1, n+1):\n if n % i == 0:\n count += 1\n return count % 2 == 0", "matching_cluster_idx": 1}, {"solution": "def count_divisors(n):\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count % 2 == 0", "matching_cluster_idx": 1}, {"solution": "def count_divisors(n):\n count = 0\n for i in range(1, n+1):\n if n % i == 0:\n count += 1\n return count % 2 == 0", "matching_cluster_idx": 1}]}, "Mbpp/800": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 98.0, "profiled": [{"solution": "def remove_all_spaces(s):\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(s):\n \"\"\"\n Remove all whitespaces from a given string.\n\n Parameters:\n s (str): The input string.\n\n Returns:\n str: The string with all whitespaces removed.\n \"\"\"\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n \"\"\"Remove all whitespaces from a given string\"\"\"\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(s: str) -> str:\n \"\"\"\n Remove all whitespaces from a string.\n \"\"\"\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(s: str) -> str:\n \"\"\"\n Remove all whitespaces from a string.\n \"\"\"\n return s.replace(' ', '')", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(s):\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(s):\n return s.replace(' ', '')", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(s):\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(s):\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(s):\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(string):\n return string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(s):\n # Using the replace() function to replace all spaces with empty string\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(string):\n return string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n # Remove all whitespaces using the `replace()` method.\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(s: str) -> str:\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(s):\n \"\"\"Removes all spaces from a string.\"\"\"\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(s):\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(s):\n # Using string method replace to remove all spaces\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(string):\n return string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(s):\n \"\"\"\n This function removes all whitespaces from a string.\n\n :param s: str: input string\n :return: str: output string without whitespaces\n \"\"\"\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}]}, "Mbpp/805": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 99.0, "profiled": [{"solution": "def max_sum_list(lst_of_lists):\n return max(lst_of_lists, key=sum)", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lst_of_lists):\n # Initialize the result with the first list from the input list\n result = lst_of_lists[0]\n # Initialize the maximum sum with the sum of the first list\n max_sum = sum(result)\n\n for sublist in lst_of_lists[1:]:\n # Calculate the sum of the current sublist\n sublist_sum = sum(sublist)\n # If the sum of the current sublist is greater than the current maximum sum, update the result and the maximum sum\n if sublist_sum > max_sum:\n result = sublist\n max_sum = sublist_sum\n\n return result", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lst):\n # Initialize max_sum and max_list\n max_sum = sum(lst[0])\n max_list = lst[0]\n\n # Loop through each sub-list\n for sublist in lst:\n sublist_sum = sum(sublist)\n if sublist_sum > max_sum:\n max_sum = sublist_sum\n max_list = sublist\n\n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lst):\n \"\"\"Return the list in a list of lists whose sum of elements is the highest.\"\"\"\n return max(lst, key=sum)", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(nested_list):\n return max(nested_list, key=sum)", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(nested_list):\n return max(nested_list, key=sum)", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lst):\n return max(lst, key=sum)", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(nested_list):\n \"\"\"Returns the list in a list of lists whose sum of elements is the highest.\"\"\"\n return max(nested_list, key=sum)", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lst):\n # Initialize max_sum and max_list with the first sublist\n max_sum = sum(lst[0])\n max_list = lst[0]\n\n # Iterate over each sublist\n for sublist in lst[1:]:\n sublist_sum = sum(sublist)\n\n # If the sublist sum is greater than max_sum, update max_sum and max_list\n if sublist_sum > max_sum:\n max_sum = sublist_sum\n max_list = sublist\n\n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lst):\n # Use list comprehension to calculate the sum of elements in each sublist and find the index of maximum sum\n max_sum_idx = max((sum(sublst), i) for i, sublst in enumerate(lst))[1]\n return lst[max_sum_idx]", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n return max(lists, key=sum)", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(nested_list):\n return max(nested_list, key=sum)", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef max_sum_list(lst: List[List[int]]) -> List[int]:\n return max(lst, key=sum)", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(nested_list):\n return max(nested_list, key=sum)", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lst):\n return max(lst, key=sum)", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lst):\n return max(lst, key=sum)", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef max_sum_list(nested_list: List[List[int]]) -> List[int]:\n \"\"\"Return the list in a list of lists whose sum of elements is the highest.\"\"\"\n if not nested_list:\n raise ValueError(\"Input list is empty\")\n\n max_sum = sum(nested_list[0])\n max_list = nested_list[0]\n\n for sublist in nested_list[1:]:\n sublist_sum = sum(sublist)\n if sublist_sum > max_sum:\n max_sum = sublist_sum\n max_list = sublist\n\n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n # Initialize max_list and max_sum\n max_list = lists[0]\n max_sum = sum(max_list)\n\n # Iterate through the lists\n for lst in lists[1:]:\n lst_sum = sum(lst)\n # Update max_list and max_sum if lst_sum is greater\n if lst_sum > max_sum:\n max_list = lst\n max_sum = lst_sum\n\n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(nested_list):\n return max(nested_list, key=sum)", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(nested_list):\n # Initialize max_sum and result_list\n max_sum = float('-inf')\n result_list = None\n\n # Iterate through each sublist\n for sublist in nested_list:\n # Calculate the sum of elements in the sublist\n sublist_sum = sum(sublist)\n\n # If the sum is higher than max_sum, update max_sum and result_list\n if sublist_sum > max_sum:\n max_sum = sublist_sum\n result_list = sublist\n\n return result_list", "matching_cluster_idx": 4}]}, "Mbpp/808": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 74.0, "profiled": [{"solution": "def check_K(tup, k):\n \"\"\"\n This function checks if a given tuple contains the element 'k' or not.\n :param tup: input tuple\n :param k: element to search for\n :return: True if 'k' is found, False otherwise\n \"\"\"\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(tuple_t, k):\n return k in tuple_t", "matching_cluster_idx": 5}, {"solution": "def check_K(t, k):\n return k in t", "matching_cluster_idx": 5}, {"solution": "def check_K(t, k):\n return k in t", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n \"\"\"Check if a given tuple contains the specified element k.\"\"\"\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(t, k):\n \"\"\"Check if the given tuple contains the value 'k'.\"\"\"\n return k in t", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n \"\"\"Check if the given tuple contains k or not.\n\n Args:\n tup (tuple): Input tuple to search.\n k: Element to search for in the tuple.\n\n Returns:\n bool: True if 'k' is present in the tuple, False otherwise.\n \"\"\"\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n \"\"\"Check if given tuple contains the given integer.\"\"\"\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n \"\"\"\n Check if the given tuple contains the specified value.\n\n Args:\n tup (tuple): Input tuple.\n k (any): Value to search for.\n\n Returns:\n bool: True if 'k' is found in the tuple, False otherwise.\n \"\"\"\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(tpl, k):\n \"\"\"Check if a tuple contains 'k'\"\"\"\n return k in tpl", "matching_cluster_idx": 5}, {"solution": "def check_K(tpl, k):\n return k in tpl", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n \"\"\"\n Function to check if the given tuple contains the element k or not.\n\n Args:\n tup (tuple): Input tuple\n k (int or str): Element to search for in the tuple\n\n Returns:\n bool: True if the element is found, False otherwise\n \"\"\"\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n \"\"\"Check if the given tuple contains the element 'k'.\"\"\"\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(t, k):\n \"\"\"\n This function checks if the given tuple contains the integer 'k'.\n\n :param t: a tuple of integers\n :param k: an integer\n :return: True if 'k' is in the tuple, False otherwise\n \"\"\"\n return k in t", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n \"\"\"Check if the given tuple contains the element k.\"\"\"\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(t, k):\n \"\"\"\n Check if the given tuple contains the k or not.\n\n :param t: Tuple to search for k\n :param k: Value to search for in tuple\n :return: bool, True if k found in tuple, False otherwise\n \"\"\"\n return k in t", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n \"\"\"Check if the given tuple contains k or not.\"\"\"\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n \"\"\"\n Check if the given tuple contains the value 'k' or not.\n\n Parameters:\n tup (tuple): Input tuple\n k (any): Value to search in the tuple\n\n Returns:\n bool: True if 'k' is in the tuple, False otherwise\n \"\"\"\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n \"\"\"\n This function checks if the given tuple contains the value k.\n \"\"\"\n return k in tup", "matching_cluster_idx": 5}]}}} \ No newline at end of file diff --git a/results/evalperf/mistralai--Mistral-Small-Instruct-2409_vllm_temp_1.0_evalperf_results.brief.json b/results/evalperf/mistralai--Mistral-Small-Instruct-2409_vllm_temp_1.0_evalperf_results.brief.json new file mode 100644 index 0000000..24bb961 --- /dev/null +++ b/results/evalperf/mistralai--Mistral-Small-Instruct-2409_vllm_temp_1.0_evalperf_results.brief.json @@ -0,0 +1 @@ +{"date": "2024-10-19 16:32", "config": {"n_samples": 100, "temperature": 1.0, "min_correct": 10, "max_profile": 20}, "summary": {"dps": 82.25625421641564, "dps_norm": 78.98044554401069, "pass@1": 69.51694915254237}, "eval": {"HumanEval/9": {"dps": 74.84227129337539, "dps_norm": 72.77777777777777, "pass@1": 98.0, "profiled": [{"solution": "from typing import List, Tuple\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n\n max_so_far = [float('-inf')] * len(numbers)\n rolling_max_list = []\n\n for i in range(len(numbers)):\n max_so_far[i] = max(numbers[:i+1])\n rolling_max_list.append(max_so_far[i])\n\n return rolling_max_list", "matching_cluster_idx": 1}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\"From a given list of integers, generate a list of rolling maximum element found until the given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n\n rolling_max_list = []\n max_so_far = float('-inf')\n\n for number in numbers:\n max_so_far = max(max_so_far, number)\n rolling_max_list.append(max_so_far)\n\n return rolling_max_list", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until the given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n\n max_so_far = numbers[0]\n result = [max_so_far]\n\n for num in numbers[1:]:\n if num > max_so_far:\n max_so_far = num\n result.append(max_so_far)\n\n return result", "matching_cluster_idx": 8}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n\n max_so_far = numbers[0]\n rolling_max_list = [max_so_far]\n\n for num in numbers[1:]:\n max_so_far = max(max_so_far, num)\n rolling_max_list.append(max_so_far)\n\n return rolling_max_list", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n\n max_so_far = numbers[0]\n result = [max_so_far]\n\n for num in numbers[1:]:\n if num > max_so_far:\n max_so_far = num\n result.append(max_so_far)\n\n return result", "matching_cluster_idx": 8}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n\n max_so_far = numbers[0]\n result = [max_so_far]\n\n for num in numbers[1:]:\n max_so_far = max(max_so_far, num)\n result.append(max_so_far)\n\n return result", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n\n rolling_max_list = [numbers[0]]\n\n for i in range(1, len(numbers)):\n rolling_max_list.append(max(rolling_max_list[-1], numbers[i]))\n\n return rolling_max_list", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n\n rolling_max_list = []\n current_max = numbers[0]\n\n for num in numbers:\n if num > current_max:\n current_max = num\n rolling_max_list.append(current_max)\n\n return rolling_max_list", "matching_cluster_idx": 8}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\"From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n\n rolling_max_list = []\n current_max = numbers[0]\n\n for num in numbers:\n current_max = max(current_max, num)\n rolling_max_list.append(current_max)\n\n return rolling_max_list", "matching_cluster_idx": 4}, {"solution": "from typing import List, Tuple\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\"From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n\n max_so_far = numbers[0]\n rolling_max_list = [max_so_far]\n\n for num in numbers[1:]:\n if num > max_so_far:\n max_so_far = num\n rolling_max_list.append(max_so_far)\n\n return rolling_max_list", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n\n max_so_far = numbers[0]\n result = [max_so_far]\n\n for num in numbers[1:]:\n max_so_far = max(max_so_far, num)\n result.append(max_so_far)\n\n return result", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\"\n From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n\n rolling_max_list = []\n current_max = numbers[0]\n\n for num in numbers:\n if num > current_max:\n current_max = num\n rolling_max_list.append(current_max)\n\n return rolling_max_list", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n\n rolling_max_list = []\n max_value = numbers[0]\n\n for number in numbers:\n if number > max_value:\n max_value = number\n rolling_max_list.append(max_value)\n\n return rolling_max_list", "matching_cluster_idx": 8}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\"\n From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n\n max_so_far = numbers[0]\n result = [max_so_far]\n\n for num in numbers[1:]:\n if num > max_so_far:\n max_so_far = num\n result.append(max_so_far)\n\n return result", "matching_cluster_idx": 8}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n\n max_so_far = numbers[0]\n rolling_max_list = [max_so_far]\n\n for number in numbers[1:]:\n if number > max_so_far:\n max_so_far = number\n rolling_max_list.append(max_so_far)\n\n return rolling_max_list", "matching_cluster_idx": 8}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n\n rolling_max_list = []\n current_max = float('-inf')\n\n for num in numbers:\n current_max = max(current_max, num)\n rolling_max_list.append(current_max)\n\n return rolling_max_list", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\"\n From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n\n max_list = [numbers[0]]\n\n for i in range(1, len(numbers)):\n if numbers[i] > max_list[-1]:\n max_list.append(numbers[i])\n else:\n max_list.append(max_list[-1])\n\n return max_list", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n\n # Initialize the result list with the first element\n rolling = [numbers[0]]\n\n # Iterate through the list starting from the second element\n for num in numbers[1:]:\n # Append the maximum between the current maximum and the current number\n rolling.append(max(rolling[-1], num))\n\n return rolling", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n\n max_so_far = numbers[0]\n result = [max_so_far]\n\n for num in numbers[1:]:\n max_so_far = max(max_so_far, num)\n result.append(max_so_far)\n\n return result", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n\n >>> rolling_max([1, 2, 3, 2, 3, 4, 2])\n [1, 2, 3, 3, 3, 4, 4]\n \"\"\"\n if not numbers:\n return []\n\n max_so_far = [numbers[0]]\n for i in range(1, len(numbers)):\n max_so_far.append(max(max_so_far[-1], numbers[i]))\n\n return max_so_far", "matching_cluster_idx": 4}]}, "HumanEval/0": {"dps": 85.69767441860465, "dps_norm": 87.14285714285714, "pass@1": 98.0, "profiled": [{"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n # Sort the list first to facilitate the comparison of close elements\n numbers.sort()\n\n # Iterate through the sorted list and check the difference between consecutive elements\n for i in range(len(numbers) - 1):\n if abs(numbers[i + 1] - numbers[i]) < threshold:\n return True\n\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n n = len(numbers)\n for i in range(n):\n for j in range(i + 1, n):\n if abs(numbers[i] - numbers[j]) < threshold:\n return True\n return False", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n if abs(numbers[i] - numbers[j]) < threshold:\n return True\n return False", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\"\n Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n if abs(numbers[i] - numbers[j]) < threshold:\n return True\n return False", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\"Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n if abs(numbers[i] - numbers[j]) < threshold:\n return True\n return False", "matching_cluster_idx": 6}, {"solution": "from typing import List\nimport doctest\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n if abs(numbers[i] - numbers[j]) < threshold:\n return True\n return False", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\"\n Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n # Sorting the list for easier comparison\n numbers.sort()\n\n # Iterate through the list and check the absolute difference between consecutive elements\n for i in range(len(numbers) - 1):\n if abs(numbers[i] - numbers[i+1]) < threshold:\n return True\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n if abs(numbers[i] - numbers[j]) < threshold:\n return True\n return False", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n if abs(numbers[i] - numbers[j]) < threshold:\n return True\n return False", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\"\n Check if in given list of numbers, are any two numbers closer to each other than\n the given threshold.\n\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n if abs(numbers[i] - numbers[j]) < threshold:\n return True\n return False", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n if abs(numbers[i] - numbers[j]) < threshold:\n return True\n return False", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n if abs(numbers[i] - numbers[j]) < threshold:\n return True\n return False", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\"Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n\n Args:\n numbers (List[float]): List of numbers to check.\n threshold (float): Threshold for closeness.\n\n Returns:\n bool: True if any two numbers are closer than the threshold, False otherwise.\n\n Examples:\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n n = len(numbers)\n for i in range(n):\n for j in range(i + 1, n):\n if abs(numbers[i] - numbers[j]) < threshold:\n return True\n return False", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\"Check if in given list of numbers, any two numbers are closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n # Sort the list of numbers\n sorted_numbers = sorted(numbers)\n\n # Iterate through the list and check the difference with the next number\n for i in range(len(sorted_numbers) - 1):\n if sorted_numbers[i + 1] - sorted_numbers[i] < threshold:\n return True\n\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n # Sort the list (O(n log n) complexity)\n numbers.sort()\n\n # Iterate over the sorted list and check the difference between consecutive elements\n for i in range(1, len(numbers)):\n if abs(numbers[i] - numbers[i - 1]) < threshold:\n return True\n\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n if abs(numbers[i] - numbers[j]) < threshold:\n return True\n return False", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n if abs(numbers[i] - numbers[j]) < threshold:\n return True\n return False", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n # Sort the list to minimize the distance checks\n numbers.sort()\n\n # Iterate through the list and check if any two consecutive numbers\n # have a distance less than the threshold\n for i in range(len(numbers) - 1):\n if abs(numbers[i] - numbers[i + 1]) < threshold:\n return True\n\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\"\n Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n n = len(numbers)\n if n < 2:\n return False\n\n numbers.sort()\n\n for i in range(n - 1):\n if abs(numbers[i] - numbers[i + 1]) < threshold:\n return True\n\n return False", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n >>> has_close_elements([1.0, 2.0, 3.0], 0.5)\n False\n >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)\n True\n \"\"\"\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n if abs(numbers[i] - numbers[j]) < threshold:\n return True\n return False", "matching_cluster_idx": 6}]}, "HumanEval/4": {"dps": 61.598101265822784, "dps_norm": 82.5, "pass@1": 100.0, "profiled": [{"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n\n # Check if the input list is empty\n if not numbers:\n return 0.0\n\n # Calculate the mean of the numbers\n mean_val = sum(numbers) / len(numbers)\n\n # Calculate the mean absolute deviation\n mad = sum(abs(num - mean_val) for num in numbers) / len(numbers)\n\n return mad", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n n = len(numbers)\n if n == 0:\n return 0.0\n\n mean = sum(numbers) / n\n absolute_deviations = [abs(x - mean) for x in numbers]\n return sum(absolute_deviations) / n", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\"For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a center point (mean in this case):\n MAD = average | x - x_mean |\n\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if not numbers:\n raise ValueError(\"The input list cannot be empty\")\n\n mean = sum(numbers) / len(numbers)\n return sum(abs(x - mean) for x in numbers) / len(numbers)", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if not numbers:\n return 0.0\n\n mean_value = sum(numbers) / len(numbers)\n absolute_deviations = [abs(num - mean_value) for num in numbers]\n mad = sum(absolute_deviations) / len(numbers)\n\n return mad", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if not numbers:\n return 0.0\n\n n = len(numbers)\n mean_value = sum(numbers) / n\n absolute_deviations = [abs(x - mean_value) for x in numbers]\n return sum(absolute_deviations) / n", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n\n if not numbers:\n return 0\n\n mean_value = sum(numbers) / len(numbers)\n deviations = [abs(num - mean_value) for num in numbers]\n return sum(deviations) / len(numbers)", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if not numbers:\n raise ValueError(\"The input list must not be empty\")\n\n # Calculate the mean of the numbers\n mean = sum(numbers) / len(numbers)\n\n # Calculate the mean absolute deviation\n mad = sum(abs(num - mean) for num in numbers) / len(numbers)\n\n return mad", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n\n if not numbers:\n raise ValueError(\"The input list is empty\")\n\n n = len(numbers)\n mean_value = sum(numbers) / n\n absolute_deviations = [abs(x - mean_value) for x in numbers]\n return sum(absolute_deviations) / n", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\"\n For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n\n # Calculate the mean of the numbers\n mean_value = sum(numbers) / len(numbers)\n\n # Calculate the absolute deviation for each number\n deviations = [abs(x - mean_value) for x in numbers]\n\n # Calculate the mean of the absolute deviations\n mad = sum(deviations) / len(deviations)\n\n return mad", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if not numbers:\n return 0.0\n\n mean = sum(numbers) / len(numbers)\n abs_deviations = [abs(x - mean) for x in numbers]\n mad = sum(abs_deviations) / len(numbers)\n return mad", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\"For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if not numbers:\n raise ValueError(\"The input list cannot be empty\")\n\n mean_value = sum(numbers) / len(numbers)\n absolute_deviations = [abs(num - mean_value) for num in numbers]\n mad = sum(absolute_deviations) / len(numbers)\n\n return mad", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if not numbers:\n return 0.0\n\n mean_value = sum(numbers) / len(numbers)\n absolute_deviations = [abs(x - mean_value) for x in numbers]\n mean_absolute_deviation = sum(absolute_deviations) / len(numbers)\n\n return mean_absolute_deviation", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if not numbers:\n return 0.0\n\n mean = sum(numbers) / len(numbers)\n deviations = [abs(x - mean) for x in numbers]\n\n return sum(deviations) / len(deviations)", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n n = len(numbers)\n if n == 0:\n return 0.0\n\n mean = sum(numbers) / n\n return sum(abs(x - mean) for x in numbers) / n", "matching_cluster_idx": 5}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\"\n For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if not numbers:\n return 0.0\n\n n = len(numbers)\n mean_val = sum(numbers) / n\n absolute_deviations = [abs(x - mean_val) for x in numbers]\n mad = sum(absolute_deviations) / n\n\n return mad", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\"For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n n = len(numbers)\n if n == 0:\n raise ValueError(\"The list of numbers cannot be empty\")\n\n mean = sum(numbers) / n\n deviations = [abs(x - mean) for x in numbers]\n mad = sum(deviations) / n\n\n return mad", "matching_cluster_idx": 4}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if not numbers:\n raise ValueError(\"The input list cannot be empty\")\n\n mean_value = sum(numbers) / len(numbers)\n absolute_deviation = [abs(num - mean_value) for num in numbers]\n\n return sum(absolute_deviation) / len(absolute_deviation)", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\"For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if not numbers:\n return 0.0\n\n mean_value = sum(numbers) / len(numbers)\n absolute_deviations = [abs(x - mean_value) for x in numbers]\n mad = sum(absolute_deviations) / len(numbers)\n\n return mad", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n\n if not numbers:\n return 0.0\n\n mean_value = sum(numbers) / len(numbers)\n deviations = [abs(num - mean_value) for num in numbers]\n return sum(deviations) / len(deviations)", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average absolute difference between each\n element and a centerpoint (mean in this case):\n MAD = average | x - x_mean |\n >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])\n 1.0\n \"\"\"\n if not numbers:\n return 0.0\n\n mean_val = sum(numbers) / len(numbers)\n return sum(abs(x - mean_val) for x in numbers) / len(numbers)", "matching_cluster_idx": 5}]}, "HumanEval/16": {"dps": 95.81395348837209, "dps_norm": 96.66666666666667, "pass@1": 100.0, "profiled": [{"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\"Given a string, find out how many distinct characters (regardless of case) does it consist of.\n\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lowercase to ensure case insensitivity\n lower_string = string.lower()\n # Use a set to store distinct characters\n distinct_chars = set(lower_string)\n return len(distinct_chars)", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lower case to ignore case sensitivity\n lower_case_string = string.lower()\n\n # Use a set to track distinct characters\n distinct_chars = set()\n\n for char in lower_case_string:\n distinct_chars.add(char)\n\n # The length of the set gives the count of distinct characters\n return len(distinct_chars)", "matching_cluster_idx": 2}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lower case to ensure case-insensitivity\n string = string.lower()\n # Use a set to keep track of unique characters\n distinct_characters = set(string)\n # Return the number of distinct characters\n return len(distinct_characters)", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lower case to ignore case differences\n lower_string = string.lower()\n\n # Use a set to store unique characters\n unique_characters = set(lower_string)\n\n # The length of the set is the number of distinct characters\n return len(unique_characters)", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lowercase to make it case-insensitive\n lower_string = string.lower()\n # Use a set to find distinct characters\n distinct_characters = set(lower_string)\n # Return the number of distinct characters\n return len(distinct_characters)", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\"\n Given a string, find out how many distinct characters (regardless of case) does it consist of.\n\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lowercase to handle case insensitivity\n lower_string = string.lower()\n\n # Use a set to store unique characters\n distinct_characters = set(lower_string)\n\n # Return the number of distinct characters\n return len(distinct_characters)", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lowercase to handle case insensitivity\n lower_string = string.lower()\n\n # Use a set to store distinct characters\n distinct_characters = set(lower_string)\n\n # Return the number of distinct characters\n return len(distinct_characters)", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lowercase\n lower_string = string.lower()\n\n # Use a set to store distinct characters\n distinct_chars = set(lower_string)\n\n # Return the count of distinct characters\n return len(distinct_chars)", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lowercase to ignore case sensitivity\n lower_string = string.lower()\n\n # Use a set to store distinct characters\n distinct_chars = set(lower_string)\n\n # Return the number of distinct characters\n return len(distinct_chars)", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\"\n Given a string, find out how many distinct characters (regardless of case) does it consist of.\n\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Normalize the string to lower case\n normalized_string = string.lower()\n # Use a set to store distinct characters\n distinct_characters = set(normalized_string)\n\n # Return the number of distinct characters\n return len(distinct_characters)", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\"\n Given a string, find out how many distinct characters (regardless of case) does it consist of.\n\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lowercase to ensure case insensitivity\n lower_case_string = string.lower()\n\n # Use a set to store distinct characters\n distinct_chars = set(lower_case_string)\n\n # Return the number of distinct characters\n return len(distinct_chars)", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\"\n Given a string, find out how many distinct characters (regardless of case) does it consist of.\n\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lower case and use a set to find distinct characters\n distinct_chars = set(string.lower())\n return len(distinct_chars)", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\"Given a string, find out how many distinct characters (regardless of case) does it consist of.\n\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lowercase to ignore case sensitivity\n lower_string = string.lower()\n\n # Use a set to store distinct characters\n distinct_chars = set(lower_string)\n\n # Return the number of distinct characters\n return len(distinct_chars)", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\"\n Given a string, find out how many distinct characters (regardless of case) does it consist of.\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lower case to ignore case sensitivity\n string = string.lower()\n\n # Use a set to keep track of distinct characters\n distinct_characters = set(string)\n\n # Return the number of distinct characters\n return len(distinct_characters)", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lower case and use a set to store distinct characters\n distinct_chars = set(string.lower())\n\n # The number of distinct characters is the size of the set\n return len(distinct_chars)", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lowercase to make the comparison case-insensitive\n lower_string = string.lower()\n # Use a set to store distinct characters\n distinct_chars = set(lower_string)\n # Return the number of distinct characters\n return len(distinct_chars)", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\"Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lower case and use a set to keep only distinct characters\n distinct_chars = set(string.lower())\n # Return the number of distinct characters\n return len(distinct_chars)", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\"Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lowercase to consider characters case-insensitively\n string = string.lower()\n # Use a set to store distinct characters\n distinct_chars = set(string)\n # Return the number of distinct characters\n return len(distinct_chars)", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lowercase to handle case insensitivity\n lower_string = string.lower()\n\n # Use a set to store distinct characters\n distinct_characters = set(lower_string)\n\n # The length of the set is the number of distinct characters\n return len(distinct_characters)", "matching_cluster_idx": 8}, {"solution": "def count_distinct_characters(string: str) -> int:\n \"\"\"\n Given a string, find out how many distinct characters (regardless of case) does it consist of.\n >>> count_distinct_characters('xyzXYZ')\n 3\n >>> count_distinct_characters('Jerry')\n 4\n \"\"\"\n # Convert the string to lower case to ensure case insensitivity\n lower_string = string.lower()\n # Use a set to track distinct characters\n distinct_characters = set(lower_string)\n # Return the number of distinct characters\n return len(distinct_characters)", "matching_cluster_idx": 8}]}, "HumanEval/20": {"dps": 92.10653753026634, "dps_norm": 94.44444444444444, "pass@1": 100.0, "profiled": [{"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n if len(numbers) < 2:\n raise ValueError(\"List must contain at least two elements\")\n\n numbers.sort()\n min_diff = float('inf')\n closest_pair = (numbers[0], numbers[1])\n\n for i in range(len(numbers) - 1):\n diff = numbers[i + 1] - numbers[i]\n if diff < min_diff:\n min_diff = diff\n closest_pair = (numbers[i], numbers[i + 1])\n\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n if len(numbers) < 2:\n raise ValueError(\"The list must contain at least two elements\")\n\n # Sort the list to simplify the closest element search\n numbers.sort()\n\n # Initialize min_diff and closest_pair\n min_diff = float('inf')\n closest_pair = (numbers[0], numbers[1])\n\n for i in range(len(numbers) - 1):\n current_diff = numbers[i + 1] - numbers[i]\n if current_diff < min_diff:\n min_diff = current_diff\n closest_pair = (numbers[i], numbers[i + 1])\n\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\"\n From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n # First sort the list\n numbers.sort()\n\n # Initialize the smallest difference to a large number and the closest pair\n smallest_difference = float('inf')\n closest_pair = (0.0, 0.0)\n\n # Check all pairs\n for i in range(len(numbers) - 1):\n diff = numbers[i + 1] - numbers[i]\n if diff < smallest_difference:\n smallest_difference = diff\n closest_pair = (numbers[i], numbers[i + 1])\n\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n if len(numbers) < 2:\n raise ValueError(\"The list must contain at least two elements.\")\n\n min_diff = float('inf')\n closest_pair = (None, None)\n\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n diff = abs(numbers[i] - numbers[j])\n if diff < min_diff:\n min_diff = diff\n closest_pair = (min(numbers[i], numbers[j]), max(numbers[i], numbers[j]))\n\n return closest_pair", "matching_cluster_idx": 3}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n numbers.sort() # Sort the list first\n min_diff = float('inf')\n closest_pair = (0, 0)\n\n for i in range(len(numbers) - 1):\n diff = numbers[i + 1] - numbers[i]\n if diff < min_diff:\n min_diff = diff\n closest_pair = (numbers[i], numbers[i + 1])\n\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\"From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n if len(numbers) < 2:\n raise ValueError(\"The list must contain at least two numbers.\")\n\n numbers.sort()\n min_diff = float('inf')\n closest_pair = (0, 0)\n\n for i in range(len(numbers) - 1):\n current_diff = numbers[i + 1] - numbers[i]\n if current_diff < min_diff:\n min_diff = current_diff\n closest_pair = (numbers[i], numbers[i + 1])\n\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\"\n From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n # Ensure the list has at least two elements\n if len(numbers) < 2:\n raise ValueError(\"List must contain at least two elements\")\n\n # Sort the list to ease the comparison\n sorted_numbers = sorted(numbers)\n\n # Initialize the minimum difference and the pair of closest elements\n min_diff = float('inf')\n closest_pair = (None, None)\n\n # Compare each element with the next one\n for i in range(len(sorted_numbers) - 1):\n diff = sorted_numbers[i + 1] - sorted_numbers[i]\n if diff < min_diff:\n min_diff = diff\n closest_pair = (sorted_numbers[i], sorted_numbers[i + 1])\n\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n\n # Ensure the list has at least two elements\n if len(numbers) < 2:\n raise ValueError(\"The list must contain at least two elements\")\n\n # Sort the list to find the minimum difference\n numbers.sort()\n\n # Initialize the closest pair and the minimum difference\n closest_pair = (numbers[0], numbers[1])\n min_diff = abs(numbers[1] - numbers[0])\n\n # Check all consecutive pairs for the minimum difference\n for i in range(1, len(numbers) - 1):\n diff = abs(numbers[i] - numbers[i + 1])\n if diff < min_diff:\n closest_pair = (numbers[i], numbers[i + 1])\n min_diff = diff\n\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n # Ensure the list is sorted to find the minimum difference\n numbers.sort()\n\n # Initialize the minimum difference and the pair of closest elements\n min_diff = float('inf')\n closest_pair = (numbers[0], numbers[1])\n\n # Iterate through the sorted list to find the minimum difference\n for i in range(len(numbers) - 1):\n current_diff = numbers[i + 1] - numbers[i]\n if current_diff < min_diff:\n min_diff = current_diff\n closest_pair = (numbers[i], numbers[i + 1])\n\n # Ensure the pair is returned in sorted order\n if closest_pair[0] > closest_pair[1]:\n closest_pair = (closest_pair[1], closest_pair[0])\n\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\"From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n \"\"\"\n if len(numbers) < 2:\n raise ValueError(\"The list must contain at least two numbers\")\n\n numbers.sort()\n min_diff = float('inf')\n closest_pair = (None, None)\n\n for i in range(len(numbers) - 1):\n diff = numbers[i+1] - numbers[i]\n if diff < min_diff:\n min_diff = diff\n closest_pair = (numbers[i], numbers[i+1])\n\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\"\n From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n if len(numbers) < 2:\n raise ValueError(\"List must contain at least two elements.\")\n\n numbers.sort()\n min_diff = float('inf')\n closest_pair = (numbers[0], numbers[1])\n\n for i in range(len(numbers) - 1):\n diff = numbers[i + 1] - numbers[i]\n if diff < min_diff:\n min_diff = diff\n closest_pair = (numbers[i], numbers[i + 1])\n\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n\n # Sort the list\n sorted_numbers = sorted(numbers)\n\n # Initialize minimum difference\n min_diff = float('inf')\n closest_pair = (0, 0)\n\n # Iterate through the sorted list to find the minimum difference\n for i in range(len(sorted_numbers) - 1):\n diff = sorted_numbers[i + 1] - sorted_numbers[i]\n if diff < min_diff:\n min_diff = diff\n closest_pair = (sorted_numbers[i], sorted_numbers[i + 1])\n\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\"From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n min_diff = float('inf')\n closest_pair = (0.0, 0.0)\n\n numbers.sort()\n\n for i in range(len(numbers) - 1):\n diff = numbers[i + 1] - numbers[i]\n if diff < min_diff:\n min_diff = diff\n closest_pair = (numbers[i], numbers[i + 1])\n\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\"\n From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n if len(numbers) < 2:\n raise ValueError(\"List must contain at least two elements\")\n\n numbers.sort() # Sort the list\n min_diff = float('inf')\n closest_pair = (0, 0)\n\n for i in range(len(numbers) - 1):\n diff = numbers[i+1] - numbers[i]\n if diff < min_diff:\n min_diff = diff\n closest_pair = (numbers[i], numbers[i+1])\n\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n min_diff = float('inf')\n closest_pair = (None, None)\n\n # Sort the list to make the comparison easier\n numbers.sort()\n\n # Compare each pair of adjacent numbers\n for i in range(len(numbers) - 1):\n diff = numbers[i + 1] - numbers[i]\n if diff < min_diff:\n min_diff = diff\n closest_pair = (numbers[i], numbers[i + 1])\n\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n if len(numbers) < 2:\n raise ValueError(\"The list must contain at least two elements.\")\n\n min_diff = float('inf')\n closest_pair = (0, 0)\n\n # Sort the list to enable easy comparison of adjacent elements\n sorted_numbers = sorted(numbers)\n\n for i in range(len(sorted_numbers) - 1):\n diff = sorted_numbers[i + 1] - sorted_numbers[i]\n if diff < min_diff:\n min_diff = diff\n closest_pair = (sorted_numbers[i], sorted_numbers[i + 1])\n\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n if len(numbers) < 2:\n raise ValueError(\"The list must contain at least two numbers\")\n\n # Initialize the minimum difference and closest elements\n min_diff = float('inf')\n closest_pair = (None, None)\n\n # Sort the list (in-place) to facilitate finding the closest pair\n numbers.sort()\n\n # Iterate through the list to find the smallest difference\n for i in range(len(numbers) - 1):\n diff = numbers[i+1] - numbers[i]\n if diff < min_diff:\n min_diff = diff\n closest_pair = (numbers[i], numbers[i+1])\n\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n numbers.sort()\n min_diff = float('inf')\n closest_pair = None\n\n for i in range(len(numbers) - 1):\n diff = numbers[i + 1] - numbers[i]\n if diff < min_diff:\n min_diff = diff\n closest_pair = (numbers[i], numbers[i + 1])\n\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n if len(numbers) < 2:\n raise ValueError(\"The list must contain at least two numbers.\")\n\n # Sort the list\n numbers.sort()\n\n # Initialize the minimum difference and the closest pair\n min_diff = float('inf')\n closest_pair = (numbers[0], numbers[1])\n\n # Compare each pair of consecutive elements\n for i in range(len(numbers) - 1):\n diff = numbers[i+1] - numbers[i]\n if diff < min_diff:\n min_diff = diff\n closest_pair = (numbers[i], numbers[i+1])\n\n return closest_pair", "matching_cluster_idx": 8}, {"solution": "from typing import List, Tuple\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in order (smaller number, larger number).\n\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])\n (2.0, 2.2)\n >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])\n (2.0, 2.0)\n \"\"\"\n if len(numbers) < 2:\n raise ValueError(\"List must contain at least two elements\")\n\n min_diff = float('inf')\n closest_pair = (0, 0)\n\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n diff = abs(numbers[i] - numbers[j])\n if diff < min_diff:\n min_diff = diff\n closest_pair = (numbers[i], numbers[j])\n\n return tuple(sorted(closest_pair))", "matching_cluster_idx": 3}]}, "HumanEval/24": {"dps": 78.2312925170068, "dps_norm": 50.0, "pass@1": 99.0, "profiled": [{"solution": "def largest_divisor(n: int) -> int:\n \"\"\"\n For a given number n, find the largest number that divides n evenly, smaller than n.\n\n >>> largest_divisor(15)\n 5\n >>> largest_divisor(10)\n 5\n >>> largest_divisor(7)\n 1\n \"\"\"\n for i in range(n // 2, 0, -1):\n if n % i == 0:\n return i\n return 1", "matching_cluster_idx": 3}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n for i in range(n // 2, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 3}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n.\n\n >>> largest_divisor(15)\n 5\n >>> largest_divisor(20)\n 10\n >>> largest_divisor(25)\n 5\n >>> largest_divisor(1)\n 1\n \"\"\"\n # Start from n/2 and go down to 1, checking divisibility\n for i in range(n // 2, 0, -1):\n if n % i == 0:\n return i\n return 1 # If no divisor found, which shouldn't happen for positive n > 1", "matching_cluster_idx": 3}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\"For a given number n, find the largest number that divides n evenly, smaller than n\n\n >>> largest_divisor(15)\n 5\n >>> largest_divisor(22)\n 11\n >>> largest_divisor(7)\n 1\n \"\"\"\n # Iterate from n//2 down to 1 to find the largest divisor\n for i in range(n//2, 0, -1):\n if n % i == 0:\n return i\n return 1 # If no divisor is found, which shouldn't happen for positive integers > 1", "matching_cluster_idx": 3}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\"\n For a given number n, find the largest number that divides n evenly, smaller than n.\n >>> largest_divisor(15)\n 5\n >>> largest_divisor(16)\n 8\n >>> largest_divisor(23)\n 1\n \"\"\"\n for i in range(n // 2, 0, -1):\n if n % i == 0:\n return i\n return 1 # If no divisor found, return 1 as the default largest divisor smaller than n", "matching_cluster_idx": 3}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n if n <= 1:\n return None # No divisor smaller than n if n is less than or equal to 1\n for i in range(n // 2, 0, -1):\n if n % i == 0:\n return i\n return 1 # In case of prime numbers, 1 is the largest divisor smaller than n", "matching_cluster_idx": 3}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n if n <= 1:\n raise ValueError(\"Input must be greater than 1\")\n for i in range(n // 2, 0, -1):\n if n % i == 0:\n return i\n return 1", "matching_cluster_idx": 3}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\"\n For a given number n, find the largest number that divides n evenly, smaller than n.\n\n >>> largest_divisor(15)\n 5\n \"\"\"\n if n < 2:\n raise ValueError(\"Input must be greater than or equal to 2\")\n\n for i in range(n // 2, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 3}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\"\n For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n if n < 2:\n return None # or you can raise an error if you prefer\n for i in range(n // 2, 0, -1):\n if n % i == 0:\n return i\n return 1 # In case n is a prime number", "matching_cluster_idx": 3}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\"For a given number n, find the largest number that divides n evenly, smaller than n\n\n >>> largest_divisor(15)\n 5\n \"\"\"\n for i in range(n // 2, 0, -1):\n if n % i == 0:\n return i\n return 1", "matching_cluster_idx": 3}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n if n <= 1:\n raise ValueError(\"Input must be greater than 1\")\n\n for i in range(n // 2, 0, -1):\n if n % i == 0:\n return i\n\n return 1", "matching_cluster_idx": 3}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\"\n For a given number n, find the largest number that divides n evenly, smaller than n.\n\n >>> largest_divisor(15)\n 5\n \"\"\"\n # Start with the largest possible number smaller than n\n for i in range(n // 2, 0, -1):\n if n % i == 0:\n return i\n return 1 # Fallback if n is prime", "matching_cluster_idx": 3}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\"\n For a given number n, find the largest number that divides n evenly, smaller than n.\n >>> largest_divisor(15)\n 5\n >>> largest_divisor(1)\n 1\n >>> largest_divisor(20)\n 10\n >>> largest_divisor(23)\n 1\n \"\"\"\n for i in range(n//2, 0, -1):\n if n % i == 0:\n return i\n return 1", "matching_cluster_idx": 3}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\"\n For a given number n, find the largest number that divides n evenly, smaller than n.\n\n >>> largest_divisor(15)\n 5\n >>> largest_divisor(20)\n 10\n >>> largest_divisor(7)\n 1\n \"\"\"\n if n <= 1:\n raise ValueError(\"Input should be greater than 1\")\n\n largest = 1\n for i in range(2, n // 2 + 1):\n if n % i == 0:\n largest = i\n\n return largest", "matching_cluster_idx": 3}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n if n <= 1:\n return None # No valid divisors for numbers <= 1\n for i in range(n // 2, 0, -1):\n if n % i == 0:\n return i\n return 1 # This should never be reached if n > 1", "matching_cluster_idx": 3}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n for i in range(n // 2, 0, -1):\n if n % i == 0:\n return i\n return 1", "matching_cluster_idx": 3}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n for i in range(n//2, 0, -1):\n if n % i == 0:\n return i\n return 1 # If no divisor found, should not happen for positive integers greater than 1", "matching_cluster_idx": 3}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n if n <= 1:\n return None\n\n # Start with n/2 and go downwards\n for i in range(n // 2, 0, -1):\n if n % i == 0:\n return i", "matching_cluster_idx": 3}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\"\n For a given number n, find the largest number that divides n evenly, smaller than n.\n\n >>> largest_divisor(15)\n 5\n >>> largest_divisor(22)\n 11\n >>> largest_divisor(1)\n 1\n \"\"\"\n for i in range(n // 2, 0, -1):\n if n % i == 0:\n return i\n return 1", "matching_cluster_idx": 3}, {"solution": "def largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n >>> largest_divisor(15)\n 5\n \"\"\"\n # Iterate from n//2 down to 1 to find the largest divisor\n for i in range(n // 2, 0, -1):\n if n % i == 0:\n return i\n return 1", "matching_cluster_idx": 3}]}, "HumanEval/26": {"dps": 92.8, "dps_norm": 97.5, "pass@1": 75.0, "profiled": [{"solution": "from typing import List\nfrom collections import defaultdict\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\"From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n >>> remove_duplicates([4, 4, 1, 2, 2, 3, 1])\n [3]\n >>> remove_duplicates([1])\n [1]\n >>> remove_duplicates([])\n []\n \"\"\"\n count_dict = defaultdict(int)\n for number in numbers:\n count_dict[number] += 1\n\n result = []\n for number in numbers:\n if count_dict[number] == 1:\n result.append(number)\n\n return result", "matching_cluster_idx": 2}, {"solution": "from typing import List\nfrom collections import Counter\nimport doctest\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\"From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n count = Counter(numbers)\n return [num for num in numbers if count[num] == 1]", "matching_cluster_idx": 3}, {"solution": "from typing import List\nfrom collections import Counter\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\"From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n # Count the occurrences of each number\n count = Counter(numbers)\n # Return a list of numbers that occur only once\n return [num for num in numbers if count[num] == 1]", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n count = {}\n result = []\n\n for num in numbers:\n if num in count:\n count[num] += 1\n else:\n count[num] = 1\n\n for num in numbers:\n if count[num] == 1:\n result.append(num)\n\n return result", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\"From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n counts = {}\n result = []\n\n for num in numbers:\n if num in counts:\n counts[num] += 1\n else:\n counts[num] = 1\n\n for num in numbers:\n if counts[num] == 1:\n result.append(num)\n\n return result", "matching_cluster_idx": 3}, {"solution": "from typing import List\nfrom collections import Counter\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\"\n From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n # Count the occurrences of each number\n count = Counter(numbers)\n\n # Filter out numbers that occur more than once\n return [num for num in numbers if count[num] == 1]", "matching_cluster_idx": 3}, {"solution": "from typing import List\nfrom collections import Counter\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\"\n From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n\n Args:\n numbers (List[int]): Input list of integers.\n\n Returns:\n List[int]: List with duplicates removed.\n\n Examples:\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n count = Counter(numbers)\n return [num for num in numbers if count[num] == 1]", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\"\n From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n # Dictionary to count occurrences of each number\n count_dict = {}\n result = []\n\n # Count occurrences of each number\n for num in numbers:\n if num in count_dict:\n count_dict[num] += 1\n else:\n count_dict[num] = 1\n\n # Append numbers that occur only once to the result list\n for num in numbers:\n if count_dict[num] == 1:\n result.append(num)\n\n return result", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\"\n From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n count = {}\n result = []\n for number in numbers:\n if number in count:\n count[number] += 1\n else:\n count[number] = 1\n\n for number in numbers:\n if count[number] == 1:\n result.append(number)\n\n return result", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\"From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n seen = {}\n result = []\n for num in numbers:\n if num in seen:\n seen[num] += 1\n else:\n seen[num] = 1\n\n for num in numbers:\n if seen[num] == 1:\n result.append(num)\n\n return result", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\"\n From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n count = {}\n result = []\n\n for num in numbers:\n if num in count:\n count[num] += 1\n else:\n count[num] = 1\n\n for num in numbers:\n if count[num] == 1:\n result.append(num)\n\n return result", "matching_cluster_idx": 3}, {"solution": "from typing import List\nfrom collections import Counter\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\"From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n count = Counter(numbers)\n return [num for num in numbers if count[num] == 1]", "matching_cluster_idx": 3}, {"solution": "from typing import List\nfrom collections import Counter\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n count = Counter(numbers)\n return [num for num in numbers if count[num] == 1]", "matching_cluster_idx": 3}, {"solution": "from typing import List\nfrom collections import Counter\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n # Count occurrences of each number\n count = Counter(numbers)\n\n # Filter out numbers that appear more than once\n return [num for num in numbers if count[num] == 1]", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\"From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n count = {}\n result = []\n\n for num in numbers:\n if num in count:\n count[num] += 1\n else:\n count[num] = 1\n\n for num in numbers:\n if count[num] == 1:\n result.append(num)\n\n return result", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\"\n From a list of integers, remove all elements that occur more than once.\n Keep the order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n count = {}\n result = []\n for number in numbers:\n if number not in count:\n count[number] = 1\n result.append(number)\n elif count[number] == 1:\n count[number] += 1\n result.remove(number)\n return result", "matching_cluster_idx": 2}, {"solution": "from typing import List\nfrom collections import Counter\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\"\n From a list of integers, remove all elements that occur more than once.\n Keep the order of elements left the same as in the input.\n\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n >>> remove_duplicates([2, 2, 3, 3, 4, 4])\n []\n >>> remove_duplicates([5, 6, 7, 8, 9])\n [5, 6, 7, 8, 9]\n >>> remove_duplicates([])\n []\n \"\"\"\n count = Counter(numbers)\n return [num for num in numbers if count[num] == 1]", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n seen = {}\n result = []\n\n for number in numbers:\n if number in seen:\n seen[number] += 1\n else:\n seen[number] = 1\n\n for number in numbers:\n if seen[number] == 1:\n result.append(number)\n\n return result", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n count = {}\n result = []\n\n for number in numbers:\n if number in count:\n count[number] += 1\n else:\n count[number] = 1\n\n for number in numbers:\n if count[number] == 1:\n result.append(number)\n\n return result", "matching_cluster_idx": 3}, {"solution": "from typing import List\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n \"\"\" From a list of integers, remove all elements that occur more than once.\n Keep order of elements left the same as in the input.\n >>> remove_duplicates([1, 2, 3, 2, 4])\n [1, 3, 4]\n \"\"\"\n from collections import Counter\n\n # Count the occurrences of each number\n count = Counter(numbers)\n\n # Filter out the numbers that occur more than once\n result = [num for num in numbers if count[num] == 1]\n\n return result", "matching_cluster_idx": 3}]}, "HumanEval/31": {"dps": 88.10126582278481, "dps_norm": 85.0, "pass@1": 100.0, "profiled": [{"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n if n == 2:\n return True\n if n % 2 == 0:\n return False\n sqrt_n = int(n**0.5) + 1\n for i in range(3, sqrt_n, 2):\n if n % i == 0:\n return False\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n\n if n <= 1:\n return False\n if n == 2:\n return True\n if n % 2 == 0:\n return False\n\n for i in range(3, int(n**0.5) + 1, 2):\n if n % i == 0:\n return False\n return True", "matching_cluster_idx": 5}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "import doctest\ndef is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n if n == 2:\n return True\n if n % 2 == 0:\n return False\n max_divisor = int(n**0.5) + 1\n for d in range(3, max_divisor, 2):\n if n % d == 0:\n return False\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n\n if n <= 1:\n return False\n if n == 2:\n return True\n if n % 2 == 0:\n return False\n\n max_divisor = int(n**0.5) + 1\n for d in range(3, max_divisor, 2):\n if n % d == 0:\n return False\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n if n == 2:\n return True\n if n % 2 == 0:\n return False\n for i in range(3, int(n**0.5) + 1, 2):\n if n % i == 0:\n return False\n return True", "matching_cluster_idx": 5}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n if n == 2:\n return True\n if n % 2 == 0:\n return False\n for i in range(3, int(n**0.5) + 1, 2):\n if n % i == 0:\n return False\n return True", "matching_cluster_idx": 5}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n if n == 2:\n return True\n if n % 2 == 0:\n return False\n max_divisor = int(n**0.5) + 1\n for d in range(3, max_divisor, 2):\n if n % d == 0:\n return False\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n\n if n <= 1:\n return False\n if n == 2:\n return True\n if n % 2 == 0:\n return False\n\n sqrt_n = int(n**0.5) + 1\n for i in range(3, sqrt_n, 2):\n if n % i == 0:\n return False\n return True", "matching_cluster_idx": 5}, {"solution": "def is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True", "matching_cluster_idx": 6}, {"solution": "import doctest\ndef is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\n >>> is_prime(6)\n False\n >>> is_prime(101)\n True\n >>> is_prime(11)\n True\n >>> is_prime(13441)\n True\n >>> is_prime(61)\n True\n >>> is_prime(4)\n False\n >>> is_prime(1)\n False\n \"\"\"\n if n <= 1:\n return False\n if n == 2:\n return True\n if n % 2 == 0:\n return False\n\n max_divisor = int(n**0.5) + 1\n for d in range(3, max_divisor, 2):\n if n % d == 0:\n return False\n\n return True", "matching_cluster_idx": 6}]}, "HumanEval/33": {"dps": 92.62731481481482, "dps_norm": 81.36363636363636, "pass@1": 82.0, "profiled": [{"solution": "def sort_third(l: list) -> list:\n \"\"\"\n This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n # Extract indices divisible by three\n indices = [i for i in range(len(l)) if i % 3 == 0]\n # Extract values at these indices and sort them\n values_to_sort = sorted([l[i] for i in indices])\n # Create a new list to store the result\n result = l[:]\n # Assign sorted values back to the respective indices\n for idx, value in zip(indices, values_to_sort):\n result[idx] = value\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list) -> list:\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indices that are not divisible by three, while its values at the indices\n that are divisible by three are equal to the values of the corresponding indices of l, but sorted.\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n # Extract values at indices divisible by three\n values_at_thirds = [l[i] for i in range(len(l)) if i % 3 == 0]\n\n # Sort those values\n sorted_values = sorted(values_at_thirds)\n\n # Replace values in the original list at indices divisible by three\n for i in range(len(l)):\n if i % 3 == 0:\n l[i] = sorted_values.pop(0)\n\n return l", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list) -> list:\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [5, 6, 2, 4, 8, 3, 9]\n \"\"\"\n # Extract elements at indices divisible by three\n divisible_by_three = [l[i] for i in range(0, len(l), 3)]\n\n # Sort the extracted elements\n sorted_divisible_by_three = sorted(divisible_by_three)\n\n # Replace elements at indices divisible by three with the sorted values\n for i, val in zip(range(0, len(l), 3), sorted_divisible_by_three):\n l[i] = val\n\n return l", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list) -> list:\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [5, 6, 3, 4, 8, 9, 2]\n \"\"\"\n # Extract indices that are divisible by three\n third_indices = [i for i in range(0, len(l), 3)]\n\n # Get values at those indices\n third_values = [l[i] for i in third_indices]\n\n # Sort the values\n sorted_third_values = sorted(third_values)\n\n # Create a copy of the list to avoid modifying the original list\n l_prime = l.copy()\n\n # Place sorted values back into the original indices\n for idx, val in zip(third_indices, sorted_third_values):\n l_prime[idx] = val\n\n return l_prime", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [5, 6, 2, 4, 8, 3, 9]\n \"\"\"\n # Extract elements at indices divisible by three\n divisible_by_three = [l[i] for i in range(len(l)) if i % 3 == 0]\n\n # Sort the extracted elements\n divisible_by_three.sort()\n\n # Create a new list for the sorted values\n result = l[:]\n\n # Replace the elements at the original indices with the sorted values\n index = 0\n for i in range(len(l)):\n if i % 3 == 0:\n result[i] = divisible_by_three[index]\n index += 1\n\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list) -> list:\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n # Extract elements at indices divisible by three\n elements_to_sort = [l[i] for i in range(len(l)) if i % 3 == 0]\n\n # Sort the extracted elements\n sorted_elements = sorted(elements_to_sort)\n\n # Prepare the output list\n result = l.copy()\n\n # Replace values at indices divisible by three with the sorted values\n for idx, val in enumerate(sorted_elements):\n result[idx * 3] = val\n\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list) -> list:\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n # Extract the elements at indices divisible by 3\n third_indices_values = [l[i] for i in range(0, len(l), 3)]\n\n # Sort the extracted values\n sorted_third_values = sorted(third_indices_values)\n\n # Create a new list to store the modified values\n result = l.copy()\n\n # Replace the values at indices divisible by 3 with the sorted values\n for i, value in zip(range(0, len(l), 3), sorted_third_values):\n result[i] = value\n\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list) -> list:\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indices that are not divisible by three, while its values\n at the indices that are divisible by three are equal to the values of the corresponding\n indices of l, but sorted.\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n # Extract elements at indices divisible by 3\n third_elements = [l[i] for i in range(len(l)) if i % 3 == 0]\n\n # Sort the extracted elements\n sorted_third_elements = sorted(third_elements)\n\n # Iterate over the original list and replace elements at indices divisible by 3 with sorted elements\n result = l[:]\n for i in range(len(l)):\n if i % 3 == 0:\n result[i] = sorted_third_elements.pop(0)\n\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list) -> list:\n \"\"\"\n This function takes a list l and returns a list l' such that\n l' is identical to l in the indices that are not divisible by three, while its\n values at the indices that are divisible by three are equal to the values of\n the corresponding indices of l, but sorted.\n\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n # Extract elements at indices divisible by three\n divisible_by_three = [l[i] for i in range(len(l)) if i % 3 == 0]\n\n # Sort the extracted elements\n sorted_divisible_by_three = sorted(divisible_by_three)\n\n # Copy the original list to avoid modifying it directly\n l_copy = l[:]\n\n # Replace the elements in l_copy at indices divisible by three with sorted elements\n for i in range(len(l)):\n if i % 3 == 0:\n l_copy[i] = sorted_divisible_by_three.pop(0)\n\n return l_copy", "matching_cluster_idx": 7}, {"solution": "def sort_third(l: list) -> list:\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n # Extract elements at indices divisible by 3\n elements_divisible_by_three = [l[i] for i in range(len(l)) if i % 3 == 0]\n\n # Sort these elements\n sorted_elements = sorted(elements_divisible_by_three)\n\n # Create the resulting list\n result = l[:] # Copy the original list\n\n # Replace elements at indices divisible by 3 with the sorted elements\n index = 0\n for i in range(len(result)):\n if i % 3 == 0:\n result[i] = sorted_elements[index]\n index += 1\n\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list) -> list:\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [5, 6, 3, 4, 8, 9, 2]\n \"\"\"\n if not l:\n return l\n\n # Extract elements at indices divisible by 3\n elements_at_third_indices = [l[i] for i in range(0, len(l), 3)]\n # Sort these elements\n sorted_third_indices_elements = sorted(elements_at_third_indices)\n\n # Create a new list with the sorted elements inserted back at the appropriate indices\n sorted_list = l[:]\n index = 0\n for i in range(0, len(l), 3):\n sorted_list[i] = sorted_third_indices_elements[index]\n index += 1\n\n return sorted_list", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n # Extract the elements at indices divisible by three\n elements_at_third_indices = [l[i] for i in range(0, len(l), 3)]\n\n # Sort those elements\n sorted_third_indices_elements = sorted(elements_at_third_indices)\n\n # Create a new list to hold the modified values\n modified_l = l.copy()\n\n # Replace the values at indices divisible by three with the sorted elements\n for i, value in zip(range(0, len(l), 3), sorted_third_indices_elements):\n modified_l[i] = value\n\n return modified_l", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list) -> list:\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n # Extract elements at indices divisible by 3\n indices_divisible_by_3 = [i for i in range(len(l)) if i % 3 == 0]\n values_divisible_by_3 = [l[i] for i in indices_divisible_by_3]\n\n # Sort these values\n sorted_values_divisible_by_3 = sorted(values_divisible_by_3)\n\n # Create a list to hold the sorted elements and others as they are\n result = l[:]\n\n # Replace the original values at indices divisible by 3 with sorted values\n for idx, val in zip(indices_divisible_by_3, sorted_values_divisible_by_3):\n result[idx] = val\n\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list):\n \"\"\"\n This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [5, 6, 3, 4, 8, 9, 2]\n >>> sort_third([7, 2, 9, 5, 1, 8, 4, 6, 3])\n [7, 2, 3, 5, 1, 8, 4, 6, 9]\n \"\"\"\n # Extract elements at indices divisible by three\n third_elements = [l[i] for i in range(0, len(l), 3)]\n sorted_third_elements = sorted(third_elements)\n\n # Create a list to store the result\n result = l[:]\n\n # Replace elements at indices divisible by three with sorted ones\n for i, val in enumerate(sorted_third_elements):\n result[3 * i] = val\n\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list) -> list:\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n # Extract elements at indices divisible by 3\n elements_divisible_by_3 = sorted([l[i] for i in range(len(l)) if i % 3 == 0])\n\n # Create the result list with elements sorted at indices divisible by 3\n result = l[:]\n idx = 0\n for i in range(len(result)):\n if i % 3 == 0:\n result[i] = elements_divisible_by_3[idx]\n idx += 1\n\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list) -> list:\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [5, 6, 3, 4, 8, 9, 2]\n \"\"\"\n\n # Extract elements at indices divisible by 3\n elements_to_sort = [l[i] for i in range(0, len(l), 3)]\n\n # Sort the extracted elements\n sorted_elements = sorted(elements_to_sort)\n\n # Create a list to hold the final result\n result = l[:]\n\n # Insert the sorted elements back into the correct indices\n for i, value in zip(range(0, len(l), 3), sorted_elements):\n result[i] = value\n\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list) -> list:\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n\n # Extract elements at indices divisible by three\n elements_to_sort = [l[i] for i in range(0, len(l), 3)]\n\n # Sort these elements\n elements_to_sort.sort()\n\n # Create a new list to store the final result\n result = l[:]\n\n # Replace the elements at indices divisible by three with the sorted elements\n for i in range(0, len(elements_to_sort)):\n result[3*i] = elements_to_sort[i]\n\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list) -> list:\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n # Extract elements at indices divisible by three\n third_indices_elements = [l[i] for i in range(0, len(l), 3)]\n\n # Sort these elements\n sorted_third_elements = sorted(third_indices_elements)\n\n # Create a new list with sorted elements in their respective positions,\n # keeping other elements in their original positions\n l_sorted = l[:]\n index = 0\n for i in range(0, len(l), 3):\n l_sorted[i] = sorted_third_elements[index]\n index += 1\n\n return l_sorted", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list) -> list:\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n # Extract elements at indices divisible by 3\n elements_at_third_indices = [l[i] for i in range(0, len(l), 3)]\n\n # Sort those elements\n sorted_elements_at_third_indices = sorted(elements_at_third_indices)\n\n # Initialize a new list to store the result\n result = l[:]\n\n # Replace the elements at indices divisible by 3 with the sorted elements\n index = 0\n for i in range(0, len(l), 3):\n result[i] = sorted_elements_at_third_indices[index]\n index += 1\n\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_third(l: list) -> list:\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the values of the corresponding indicies of l, but sorted.\n\n >>> sort_third([1, 2, 3])\n [1, 2, 3]\n >>> sort_third([5, 6, 3, 4, 8, 9, 2])\n [2, 6, 3, 4, 8, 9, 5]\n \"\"\"\n # Extract elements at indices divisible by 3\n elements_at_third_indices = [l[i] for i in range(len(l)) if i % 3 == 0]\n\n # Sort the extracted elements\n sorted_elements_at_third_indices = sorted(elements_at_third_indices)\n\n # Create a result list to store the final sorted list\n result = l[:]\n\n # Replace elements at indices divisible by 3 with sorted elements\n sorted_index = 0\n for i in range(len(l)):\n if i % 3 == 0:\n result[i] = sorted_elements_at_third_indices[sorted_index]\n sorted_index += 1\n\n return result", "matching_cluster_idx": 8}]}, "HumanEval/34": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def unique(l: list) -> list:\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list) -> list:\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list) -> list:\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"\n Return sorted unique elements in a list.\n\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n\n >>> unique([1, 1, 1, 2, 3, 3, 3, 4, 4, 4, 5])\n [1, 2, 3, 4, 5]\n\n >>> unique([])\n []\n\n >>> unique([-1, -1, -2, -2, 0, 0, 1, 1])\n [-2, -1, 0, 1]\n \"\"\"\n # Remove duplicates by converting list to a set\n unique_elements = list(set(l))\n\n # Sort the unique elements\n unique_elements.sort()\n\n return unique_elements", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list) -> list:\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n # Remove duplicates by converting the list to a set, then sort the unique elements\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list) -> list:\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list) -> list:\n \"\"\"\n Return sorted unique elements in a list.\n\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list) -> list:\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list) -> list:\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n # Convert the list to a set to remove duplicates, then convert it back to a list\n # and sort it\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list) -> list:\n \"\"\"\n Return sorted unique elements in a list\n\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n # Using set to remove duplicates and then sorting the list\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list) -> list:\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list) -> list:\n \"\"\"\n Return sorted unique elements in a list\n\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"\n Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"\n Return sorted unique elements in a list.\n\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n return sorted(set(l))", "matching_cluster_idx": 4}, {"solution": "def unique(l: list):\n \"\"\"Return sorted unique elements in a list\n >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])\n [0, 2, 3, 5, 9, 123]\n \"\"\"\n # Convert the list to a set to remove duplicates\n unique_elements = set(l)\n # Convert the set back to a list and sort it\n sorted_unique_elements = sorted(unique_elements)\n return sorted_unique_elements", "matching_cluster_idx": 4}]}, "HumanEval/36": {"dps": 96.77419354838709, "dps_norm": 71.42857142857143, "pass@1": 88.0, "profiled": [{"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n if '7' in str(i):\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\"\"\"\n count = 0\n\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n for i in range(1, n):\n if i % 11 == 0 or i % 13 == 0:\n if '7' in str(i):\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n if '7' in str(i):\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n\n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n for i in range(11, n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n\n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n if '7' in str(i):\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n for i in range(11, n):\n if i % 11 == 0 or i % 13 == 0:\n if '7' in str(i):\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\"\"\"\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\"\"\"\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}, {"solution": "def fizz_buzz(n: int) -> int:\n \"\"\"Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n >>> fizz_buzz(50)\n 0\n >>> fizz_buzz(78)\n 2\n >>> fizz_buzz(79)\n 3\n \"\"\"\n count = 0\n for i in range(11, n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count", "matching_cluster_idx": 4}]}, "HumanEval/37": {"dps": 94.92635024549918, "dps_norm": 90.0, "pass@1": 98.0, "profiled": [{"solution": "def sort_even(l: list) -> list:\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [5, 4, 3, 6]\n \"\"\"\n even_values = sorted([l[i] for i in range(0, len(l), 2)]) # Extract even indexed values and sort them\n it = iter(even_values)\n return [next(it) if i % 2 == 0 else l[i] for i in range(len(l))] # Replace even indexed values with sorted ones", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list) -> list:\n \"\"\"\n This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Extract the even-indexed elements\n even_elements = l[::2]\n\n # Sort the even-indexed elements\n sorted_even_elements = sorted(even_elements)\n\n # Create a result list\n result = l[:] # Copy the original list\n\n # Replace even-indexed elements in the result list with sorted elements\n for i in range(0, len(l), 2):\n result[i] = sorted_even_elements.pop(0) # Pop from sorted list to keep order\n\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list) -> list:\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [5, 4, 3, 6]\n \"\"\"\n even_elements = sorted([l[i] for i in range(0, len(l), 2)])\n result = l[:]\n even_idx = 0\n\n for i in range(0, len(l), 2):\n result[i] = even_elements[even_idx]\n even_idx += 1\n\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list) -> list:\n \"\"\"\n This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n \"\"\"\n if not l:\n return l\n\n # Extract even indexed elements\n even_elements = l[::2]\n # Sort the even indexed elements\n sorted_even_elements = sorted(even_elements)\n\n # Initialize a list for the result\n result = l[:]\n\n # Iterate through the original list and replace even indexed elements with sorted elements\n for i in range(0, len(l), 2):\n result[i] = sorted_even_elements.pop(0)\n\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list) -> list:\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Extract the values at even indices\n even_indices_values = [l[i] for i in range(0, len(l), 2)]\n\n # Sort the values at even indices\n sorted_even_values = sorted(even_indices_values)\n\n # Create a new list based on the input list, but with sorted even index values\n result = l[:]\n even_index = 0\n for i in range(0, len(result), 2):\n result[i] = sorted_even_values[even_index]\n even_index += 1\n\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list) -> list:\n \"\"\"\n This function takes a list `l` and returns a list `l'` such that\n `l'` is identical to `l` at the odd indices, while its values at the even indices\n are equal to the values of the even indices of `l`, but sorted.\n\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n if not l:\n return []\n\n # Extract even indexed elements and sort them\n even_elements = sorted([l[i] for i in range(0, len(l), 2)])\n\n # Construct the result list\n result = l[:]\n even_index = 0\n for i in range(0, len(result), 2):\n result[i] = even_elements[even_index]\n even_index += 1\n\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list) -> list:\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indices, while its values at the even indices\n are equal to the values of the even indices of l, but sorted.\n \"\"\"\n even_elements = sorted([l[i] for i in range(len(l)) if i % 2 == 0])\n for i, e in zip(range(0, len(l), 2), even_elements):\n l[i] = e\n return l", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list) -> list:\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n >>> sort_even([1, 3, 5, 7, 9, 2, 4, 6, 8])\n [1, 2, 5, 4, 9, 6, 7, 8, 3]\n \"\"\"\n # Extract even indexed elements\n even_indices_values = [l[i] for i in range(0, len(l), 2)]\n\n # Sort the even indexed elements\n sorted_even_indices_values = sorted(even_indices_values)\n\n # Reconstruct the list\n result = l[:]\n even_idx = 0\n for i in range(0, len(l), 2):\n result[i] = sorted_even_indices_values[even_idx]\n even_idx += 1\n\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list) -> list:\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Extract the values at even indices\n even_values = l[::2]\n\n # Sort the values at even indices\n sorted_even_values = sorted(even_values)\n\n # Combine the sorted even values with the original odd values\n result = []\n even_idx = 0\n for i in range(len(l)):\n if i % 2 == 0:\n result.append(sorted_even_values[even_idx])\n even_idx += 1\n else:\n result.append(l[i])\n\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list) -> list:\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n even_elements = sorted(l[::2])\n result = []\n even_index = 0\n\n for i in range(len(l)):\n if i % 2 == 0:\n result.append(even_elements[even_index])\n even_index += 1\n else:\n result.append(l[i])\n\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n\n # Separate even-indexed elements and odd-indexed elements\n even_indices = [l[i] for i in range(0, len(l), 2)]\n odd_indices = [l[i] for i in range(1, len(l), 2)]\n\n # Sort the even-indexed elements\n sorted_even_indices = sorted(even_indices)\n\n # Combine the sorted even-indexed elements with the odd-indexed elements\n result = []\n even_idx, odd_idx = 0, 0\n for i in range(len(l)):\n if i % 2 == 0:\n result.append(sorted_even_indices[even_idx])\n even_idx += 1\n else:\n result.append(odd_indices[odd_idx])\n odd_idx += 1\n\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n if not l:\n return l\n\n # Extract the elements at even indices\n even_elements = l[::2]\n\n # Sort the even elements\n even_elements.sort()\n\n # Iterate through the original list and insert the sorted even elements\n l_sorted = l[:]\n even_index = 0\n for i in range(len(l)):\n if i % 2 == 0:\n l_sorted[i] = even_elements[even_index]\n even_index += 1\n\n return l_sorted", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list) -> list:\n \"\"\"\n This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n\n # Extract the values at even indices\n even_indices_values = [l[i] for i in range(0, len(l), 2)]\n\n # Sort the values at even indices\n sorted_even_indices_values = sorted(even_indices_values)\n\n # Construct the result list with odd indices unchanged and even indices sorted\n result = l.copy()\n even_index = 0\n for i in range(0, len(l), 2):\n result[i] = sorted_even_indices_values[even_index]\n even_index += 1\n\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list) -> list:\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Extracting the values at even indices\n even_values = [l[i] for i in range(0, len(l), 2)]\n # Sorting the even indexed values\n even_values_sorted = sorted(even_values)\n\n # Creating a new list with sorted even indices and maintaining the odd indices\n result = []\n even_index = 0\n for i in range(len(l)):\n if i % 2 == 0:\n result.append(even_values_sorted[even_index])\n even_index += 1\n else:\n result.append(l[i])\n\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list) -> list:\n \"\"\"\n This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indices, while its values at the even indices are equal\n to the values of the even indices of l, but sorted.\n\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n even_elements = sorted([l[i] for i in range(0, len(l), 2)])\n l_copy = l.copy()\n even_idx = 0\n\n for i in range(0, len(l), 2):\n l_copy[i] = even_elements[even_idx]\n even_idx += 1\n\n return l_copy", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list) -> list:\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n even_elements = sorted(l[::2]) # Extract and sort elements at even indices\n it = iter(even_elements)\n\n # Create a new list, replacing even indices with sorted values\n return [next(it) if i % 2 == 0 else l[i] for i in range(len(l))]", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n if not l:\n return l\n\n # Extract the even indexed elements\n even_elements = [l[i] for i in range(0, len(l), 2)]\n\n # Sort the even indexed elements\n sorted_even_elements = sorted(even_elements)\n\n # Create a new list to store the result\n result = l[:]\n\n # Place the sorted even indexed elements back into the result list\n even_index = 0\n for i in range(0, len(l), 2):\n result[i] = sorted_even_elements[even_index]\n even_index += 1\n\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list) -> list:\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indices, while its values at the even indices are equal\n to the values of the even indices of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n even_indices_values = sorted([l[i] for i in range(0, len(l), 2)])\n result = l.copy()\n even_index = 0\n\n for i in range(0, len(result), 2):\n result[i] = even_indices_values[even_index]\n even_index += 1\n\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list) -> list:\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Extract the values at the even indices\n even_values = [l[i] for i in range(len(l)) if i % 2 == 0]\n # Sort the even values\n sorted_even_values = sorted(even_values)\n # Create a new list maintaining the original values at odd indices and sorted even indices\n result = l.copy()\n even_index = 0\n for i in range(len(l)):\n if i % 2 == 0:\n result[i] = sorted_even_values[even_index]\n even_index += 1\n return result", "matching_cluster_idx": 8}, {"solution": "def sort_even(l: list) -> list:\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indices, while its values at the even indices are equal\n to the values of the even indices of l, but sorted.\n >>> sort_even([1, 2, 3])\n [1, 2, 3]\n >>> sort_even([5, 6, 3, 4])\n [3, 6, 5, 4]\n \"\"\"\n # Separate the values at even indices and sort them\n even_values = sorted(l[::2])\n\n # Initialize an empty list to store the result\n result = []\n\n # Iterate over the original list and fill in the result\n even_index = 0\n for i in range(len(l)):\n if i % 2 == 0:\n result.append(even_values[even_index])\n even_index += 1\n else:\n result.append(l[i])\n\n return result", "matching_cluster_idx": 8}]}, "HumanEval/49": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 33.0, "profiled": [{"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n # Calculate 2^n % p using modular exponentiation to prevent overflow\n result = pow(2, n, p)\n return result", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n # Use pow function to compute (2^n % p) efficiently\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\n\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p.\n\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\n\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\n\n Args:\n n (int): Exponent.\n p (int): Modulus.\n\n Returns:\n int: 2^n % p\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n # Return 2^n % p using the modulo operator\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\n\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n # Efficient way to compute (2^n) % p using exponentiation by squaring\n return pow(2, n, p)", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n # Use modular exponentiation to compute 2^n mod p efficiently\n result = pow(2, n, p)\n return result", "matching_cluster_idx": 4}, {"solution": "def modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\n\n >>> modp(3, 5)\n 3\n >>> modp(1101, 101)\n 2\n >>> modp(0, 101)\n 1\n >>> modp(3, 11)\n 8\n >>> modp(100, 101)\n 1\n \"\"\"\n return pow(2, n, p)", "matching_cluster_idx": 4}]}, "HumanEval/51": {"dps": 96.13526570048309, "dps_norm": 75.0, "pass@1": 100.0, "profiled": [{"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes a string and returns the string without vowels.\n\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = 'aeiouAEIOU'\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n Remove vowels from the input text.\n\n Args:\n text (str): The input text.\n\n Returns:\n str: The text with vowels removed.\n\n Examples:\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = 'aeiouAEIOU'\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes a string and returns a string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = 'aeiouAEIOU'\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes a string and returns a string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n return ''.join(char for char in text if char not in vowels)", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes a string and returns a string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "import doctest\ndef remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes a string and returns the string without vowels.\n\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n return ''.join(char for char in text if char not in vowels)", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes a string and returns a string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = 'aeiouAEIOU'\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n Remove vowels from the input text and return the modified text.\n\n Args:\n text (str): The input string from which to remove vowels.\n\n Returns:\n str: The input string without vowels.\n\n Examples:\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = 'aeiouAEIOU'\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n Remove vowels from the input text.\n\n Args:\n text (str): The input string to process.\n\n Returns:\n str: The string without vowels.\n\n Examples:\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes a string and returns a string without vowels.\n\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = 'aeiouAEIOU'\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes a string and returns the string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = 'aeiouAEIOU'\n return ''.join(char for char in text if char not in vowels)", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes a string and returns a string without vowels.\n\n Args:\n text (str): The input string from which to remove vowels.\n\n Returns:\n str: The input string without vowels.\n\n Examples:\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = 'aeiouAEIOU'\n return ''.join(char for char in text if char not in vowels)", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes a string and returns a string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = 'aeiouAEIOU'\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes a string and returns a string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = 'aeiouAEIOU'\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}, {"solution": "def remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n >>> remove_vowels('')\n ''\n >>> remove_vowels(\"abcdef\\nghijklm\")\n 'bcdf\\nghjklm'\n >>> remove_vowels('abcdef')\n 'bcdf'\n >>> remove_vowels('aaaaa')\n ''\n >>> remove_vowels('aaBAA')\n 'B'\n >>> remove_vowels('zbcd')\n 'zbcd'\n \"\"\"\n vowels = \"aeiouAEIOU\"\n return ''.join([char for char in text if char not in vowels])", "matching_cluster_idx": 5}]}, "HumanEval/54": {"dps": null, "dps_norm": null, "pass@1": 0.0, "profiled": []}, "HumanEval/58": {"dps": 92.51968503937007, "dps_norm": 83.33333333333333, "pass@1": 100.0, "profiled": [{"solution": "def common(l1: list, l2: list) -> list:\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n # Convert lists to sets to find common elements\n common_elements = set(l1).intersection(set(l2))\n\n # Convert back to a list and sort\n return sorted(common_elements)", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list) -> list:\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n # Use set operations to find the intersection of the two lists and convert it to a sorted list\n common_elements = sorted(list(set(l1) & set(l2)))\n return common_elements", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n # Use sets to find unique common elements\n set1, set2 = set(l1), set(l2)\n common_elements = sorted(set1 & set2)\n return common_elements", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n\n \"\"\"\n # Use sets to find the intersection of the two lists, which will automatically handle uniqueness\n common_elements = set(l1).intersection(set(l2))\n\n # Convert the set back to a list and sort it\n return sorted(list(common_elements))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list) -> list:\n \"\"\"Return sorted unique common elements for two lists.\n\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n # Convert both lists to sets to find common elements\n set1 = set(l1)\n set2 = set(l2)\n\n # Find intersection of the two sets\n common_elements = set1.intersection(set2)\n\n # Convert the set back to a sorted list\n return sorted(list(common_elements))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list) -> list:\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n set_l1, set_l2 = set(l1), set(l2)\n common_elements = sorted(set_l1 & set_l2)\n return common_elements", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n # Use set intersection to find common elements, then sort and return as a list\n common_elements = sorted(set(l1) & set(l2))\n return common_elements", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n\n \"\"\"\n # Convert lists to sets to get unique elements and find intersection\n set1 = set(l1)\n set2 = set(l2)\n\n common_elements = set1.intersection(set2)\n\n # Convert back to a sorted list\n return sorted(common_elements)", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list) -> list:\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n\n \"\"\"\n # Convert lists to sets to find common elements\n common_elements = set(l1).intersection(set(l2))\n\n # Convert back to a list and sort\n return sorted(list(common_elements))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list) -> list:\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n # Find common elements\n common_elements = list(set(l1) & set(l2))\n\n # Return sorted unique common elements\n return sorted(common_elements)", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list) -> list:\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n # Convert lists to sets to remove duplicates and find common elements\n set1 = set(l1)\n set2 = set(l2)\n\n # Find intersection of two sets\n common_elements = set1 & set2\n\n # Convert the set back to a sorted list\n return sorted(common_elements)", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n\n \"\"\"\n # Find intersection of both lists\n common_elements = set(l1) & set(l2)\n\n # Return sorted unique elements\n return sorted(common_elements)", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n return sorted(set(l1) & set(l2))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list) -> list:\n \"\"\"Return sorted unique common elements for two lists.\n\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n # Convert both lists to sets to find unique common elements\n set1, set2 = set(l1), set(l2)\n\n # Intersect the sets to find common elements\n common_elements = set1 & set2\n\n # Convert the set back to a list and sort it\n return sorted(list(common_elements))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n return sorted(set(l1).intersection(set(l2)))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list) -> list:\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n set_l1 = set(l1)\n set_l2 = set(l2)\n\n # Find intersection of both sets\n common_elements = set_l1 & set_l2\n\n # Return sorted list of common elements\n return sorted(list(common_elements))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list) -> list:\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n set_l1 = set(l1)\n set_l2 = set(l2)\n\n # Find intersection of two sets\n common_elements = set_l1.intersection(set_l2)\n\n # Convert to a sorted list\n sorted_common_elements = sorted(common_elements)\n\n return sorted_common_elements", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list) -> list:\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n # Find common elements by converting lists to sets\n common_elements = list(set(l1) & set(l2))\n # Sort and return the unique common elements\n return sorted(common_elements)", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list) -> list:\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n \"\"\"\n # Convert lists to sets to get unique elements\n set1, set2 = set(l1), set(l2)\n # Find intersection of sets\n common_elements = set1 & set2\n # Convert to sorted list and return\n return sorted(list(common_elements))", "matching_cluster_idx": 4}, {"solution": "def common(l1: list, l2: list) -> list:\n \"\"\"Return sorted unique common elements for two lists.\n >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])\n [1, 5, 653]\n >>> common([5, 3, 2, 8], [3, 2])\n [2, 3]\n\n \"\"\"\n # Find common elements using set intersection\n common_elements = set(l1).intersection(set(l2))\n\n # Convert to sorted list and return\n return sorted(common_elements)", "matching_cluster_idx": 4}]}, "HumanEval/59": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 83.0, "profiled": [{"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\"\"\"\n largest_factor = 1\n while n % 2 == 0:\n largest_factor = 2\n n = n // 2\n while n % 3 == 0:\n largest_factor = 3\n n = n // 3\n factor = 5\n while factor * factor <= n:\n while n % factor == 0:\n largest_factor = factor\n n = n // factor\n factor += 2\n if n > 1:\n largest_factor = n\n return largest_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n # Function to find all prime factors\n def prime_factors(m):\n factors = []\n # Test for number of 2s that divide m\n while m % 2 == 0:\n factors.append(2),\n m = m // 2\n # n must be odd at this point\n for i in range(3, int(m**0.5) + 1, 2):\n while m % i == 0:\n factors.append(i),\n m = m // i\n if m > 2:\n factors.append(m)\n return factors\n\n # Get all prime factors\n factors = prime_factors(n)\n # Return the largest prime factor\n return max(factors)", "matching_cluster_idx": 8}, {"solution": "import math\ndef largest_prime_factor(n):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\"\"\"\n factor = 2\n while factor * factor <= n:\n if n % factor:\n factor += 1\n else:\n n //= factor\n return n", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\"\"\"\n factor = 2\n while factor * factor <= n:\n if n % factor:\n factor += 1\n else:\n n //= factor\n return n", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\"\"\"\n # Start checking from 2, the smallest prime number\n largest_factor = None\n while n % 2 == 0:\n largest_factor = 2\n n //= 2\n for i in range(3, int(n**0.5) + 1, 2):\n while n % i == 0:\n largest_factor = i\n n //= i\n if n > 2:\n largest_factor = n\n return largest_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n def is_prime(x):\n \"\"\"Helper function to check if a number is prime.\"\"\"\n if x <= 1:\n return False\n if x <= 3:\n return True\n if x % 2 == 0 or x % 3 == 0:\n return False\n i = 5\n while i * i <= x:\n if x % i == 0 or x % (i + 2) == 0:\n return False\n i += 6\n return True\n\n largest_prime = -1\n\n # Check for the highest power of 2 that divides n\n while n % 2 == 0:\n largest_prime = 2\n n //= 2\n\n # n must be odd at this point so a skip of 2 (i.e., i = i + 2) can be used in loop\n for i in range(3, int(n**0.5) + 1, 2):\n # While i divides n, update n and largest_prime\n while n % i == 0:\n largest_prime = i\n n //= i\n\n # This condition is to check if n is a prime number greater than 2\n if n > 2:\n largest_prime = n\n\n return largest_prime", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n def is_prime(num: int) -> bool:\n if num <= 1:\n return False\n if num <= 3:\n return True\n if num % 2 == 0 or num % 3 == 0:\n return False\n i = 5\n while i * i <= num:\n if num % i == 0 or num % (i + 2) == 0:\n return False\n i += 6\n return True\n\n factor = 2\n while factor * factor <= n:\n if n % factor:\n factor += 1\n else:\n n //= factor\n if n > 1:\n return n\n return factor - 1", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n def is_prime(num):\n \"\"\"Check if a number is prime.\"\"\"\n if num <= 1:\n return False\n if num <= 3:\n return True\n if num % 2 == 0 or num % 3 == 0:\n return False\n i = 5\n while i * i <= num:\n if num % i == 0 or num % (i + 2) == 0:\n return False\n i += 6\n return True\n\n largest_factor = None\n # Divide n by 2 to get rid of all even factors first\n while n % 2 == 0:\n largest_factor = 2\n n //= 2\n\n # n must be odd at this point so we can skip even numbers\n factor = 3\n while factor * factor <= n:\n while n % factor == 0:\n largest_factor = factor\n n //= factor\n factor += 2\n\n # This condition is to handle the case when n is a prime number greater than 2\n if n > 2:\n largest_factor = n\n\n return largest_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n if n <= 1:\n raise ValueError(\"Input must be greater than 1 and not a prime.\")\n\n largest_factor = None\n\n # Divide out the smallest prime (2) first\n while n % 2 == 0:\n largest_factor = 2\n n //= 2\n\n # n must be odd at this point, so we can skip one element (i.e., 2 is already checked)\n for i in range(3, int(n**0.5) + 1, 2):\n while n % i == 0:\n largest_factor = i\n n //= i\n\n # If n is a prime number larger than 2\n if n > 2:\n largest_factor = n\n\n return largest_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\"\"\"\n largest_factor = None\n # Check for smallest prime factor 2\n while n % 2 == 0:\n largest_factor = 2\n n //= 2\n # Check for odd factors from 3 onwards\n factor = 3\n while factor * factor <= n:\n while n % factor == 0:\n largest_factor = factor\n n //= factor\n factor += 2\n # If n is still greater than 2, it must be prime\n if n > 2:\n largest_factor = n\n return largest_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\"\"\"\n largest_factor = None\n while n % 2 == 0:\n largest_factor = 2\n n //= 2\n\n while n % 3 == 0:\n largest_factor = 3\n n //= 3\n\n factor = 5\n while factor * factor <= n:\n while n % factor == 0:\n largest_factor = factor\n n //= factor\n while n % (factor + 2) == 0:\n largest_factor = factor + 2\n n //= factor + 2\n factor += 6\n\n if n > 4:\n largest_factor = n\n\n return largest_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n def is_prime(num):\n if num <= 1:\n return False\n for i in range(2, int(num ** 0.5) + 1):\n if num % i == 0:\n return False\n return True\n\n largest_factor = -1\n while n % 2 == 0:\n largest_factor = 2\n n //= 2\n\n for i in range(3, int(n**0.5) + 1, 2):\n while n % i == 0:\n largest_factor = i\n n //= i\n\n if n > 2:\n largest_factor = n\n\n return largest_factor", "matching_cluster_idx": 8}, {"solution": "import math\ndef largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n def is_prime(num):\n if num <= 1:\n return False\n if num <= 3:\n return True\n if num % 2 == 0 or num % 3 == 0:\n return False\n i = 5\n while i * i <= num:\n if num % i == 0 or num % (i + 2) == 0:\n return False\n i += 6\n return True\n\n largest_factor = None\n # Remove all factors of 2\n while n % 2 == 0:\n largest_factor = 2\n n //= 2\n\n # Remove odd factors from 3 upwards\n for i in range(3, int(math.sqrt(n)) + 1, 2):\n while n % i == 0:\n largest_factor = i\n n //= i\n\n # If n is a prime number greater than 2\n if n > 2:\n largest_factor = n\n\n return largest_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\"\"\"\n largest_factor = None\n # Check for the smallest prime factor 2\n while n % 2 == 0:\n largest_factor = 2\n n //= 2\n\n # Check for odd factors from 3 onwards\n factor = 3\n while factor * factor <= n:\n while n % factor == 0:\n largest_factor = factor\n n //= factor\n factor += 2\n\n # If n is still a prime number greater than 2\n if n > 2:\n largest_factor = n\n\n return largest_factor", "matching_cluster_idx": 8}, {"solution": "import math\ndef largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n # Start with the smallest prime number\n largest_prime = None\n\n # Check for the highest power of 2 that divides n\n while n % 2 == 0:\n largest_prime = 2\n n //= 2\n\n # n must be odd at this point, so we can skip even numbers\n for i in range(3, int(math.sqrt(n)) + 1, 2):\n while n % i == 0:\n largest_prime = i\n n //= i\n\n # This condition is to handle the case when n is a prime number\n # greater than 2\n if n > 2:\n largest_prime = n\n\n return largest_prime", "matching_cluster_idx": 8}, {"solution": "import math\ndef largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\"\"\"\n def is_prime(x: int) -> bool:\n if x <= 1:\n return False\n if x <= 3:\n return True\n if x % 2 == 0 or x % 3 == 0:\n return False\n i = 5\n while i * i <= x:\n if x % i == 0 or x % (i + 2) == 0:\n return False\n i += 6\n return True\n\n largest_factor = -1\n while n % 2 == 0:\n largest_factor = 2\n n //= 2\n for i in range(3, int(math.sqrt(n)) + 1, 2):\n while n % i == 0:\n largest_factor = i\n n //= i\n if n > 2:\n largest_factor = n\n\n return largest_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n # Remove all factors of 2\n while n % 2 == 0:\n largest_factor = 2\n n //= 2\n\n # Remove all factors of 3\n while n % 3 == 0:\n largest_factor = 3\n n //= 3\n\n # Check for factors from 5 to sqrt(n)\n factor = 5\n while factor * factor <= n:\n while n % factor == 0:\n largest_factor = factor\n n //= factor\n factor += 2\n\n # If n becomes a prime number greater than 2\n if n > 2:\n largest_factor = n\n\n return largest_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\"\"\"\n factor = 2\n while factor * factor <= n:\n if n % factor:\n factor += 1\n else:\n n //= factor\n return n", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\"\"\"\n # Start with the smallest prime number, which is 2\n largest_factor = None\n while n % 2 == 0:\n largest_factor = 2\n n //= 2\n\n # Check for odd factors from 3 upwards\n factor = 3\n while factor * factor <= n:\n while n % factor == 0:\n largest_factor = factor\n n //= factor\n factor += 2\n\n # If n itself is a prime number and greater than 2\n if n > 2:\n largest_factor = n\n\n return largest_factor", "matching_cluster_idx": 8}, {"solution": "def largest_prime_factor(n: int) -> int:\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n >>> largest_prime_factor(13195)\n 29\n >>> largest_prime_factor(2048)\n 2\n \"\"\"\n largest_factor = -1\n while n % 2 == 0:\n largest_factor = 2\n n //= 2\n for i in range(3, int(n**0.5) + 1, 2):\n while n % i == 0:\n largest_factor = i\n n //= i\n if n > 2:\n largest_factor = n\n return largest_factor", "matching_cluster_idx": 8}]}, "HumanEval/64": {"dps": 46.688311688311686, "dps_norm": 44.375, "pass@1": 58.0, "profiled": [{"solution": "def vowels_count(s):\n \"\"\"\n Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = \"aeiouAEIOU\"\n count = 0\n for i, char in enumerate(s):\n if char in vowels:\n count += 1\n elif char.lower() == 'y' and i == len(s) - 1:\n count += 1\n return count", "matching_cluster_idx": 3}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = set('aeiou')\n count = 0\n\n for i, char in enumerate(s):\n if char.lower() in vowels:\n count += 1\n elif char.lower() == 'y' and i == len(s) - 1:\n count += 1\n\n return count", "matching_cluster_idx": 1}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = 'aeiou'\n count = 0\n for i, char in enumerate(s):\n if char.lower() in vowels or (char.lower() == 'y' and i == len(s) - 1):\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = \"aeiou\"\n count = 0\n for i, char in enumerate(s):\n if char.lower() in vowels:\n count += 1\n elif char.lower() == 'y' and i == len(s) - 1:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n # Define the set of vowels\n vowels = {'a', 'e', 'i', 'o', 'u'}\n\n # Initialize the count of vowels\n count = 0\n\n # Iterate over each character in the string\n for i, char in enumerate(s):\n # Check if the character is a vowel\n if char.lower() in vowels:\n count += 1\n # Check if 'y' is at the end of the word\n elif char.lower() == 'y' and i == len(s) - 1:\n count += 1\n\n return count", "matching_cluster_idx": 1}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = \"aeiou\"\n count = 0\n s = s.lower()\n\n for i, char in enumerate(s):\n if char in vowels or (char == 'y' and i == len(s) - 1):\n count += 1\n\n return count", "matching_cluster_idx": 3}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = \"aeiou\"\n count = 0\n for i, char in enumerate(s):\n if char.lower() in vowels:\n count += 1\n elif char.lower() == 'y' and i == len(s) - 1:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = set(\"aeiou\")\n count = 0\n s = s.lower() # Convert the string to lowercase to handle case insensitivity\n\n for i, char in enumerate(s):\n if char in vowels or (char == 'y' and i == len(s) - 1):\n count += 1\n\n return count", "matching_cluster_idx": 3}, {"solution": "def vowels_count(s):\n \"\"\"\n Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = \"aeiou\"\n count = 0\n if s and s[-1].lower() == 'y':\n count += 1\n for char in s:\n if char.lower() in vowels:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = \"aeiou\"\n count = 0\n # Iterate over each character in the string\n for i, char in enumerate(s):\n if char.lower() in vowels:\n count += 1\n elif char.lower() == 'y' and i == len(s) - 1:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def vowels_count(s):\n \"\"\"\n Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = set(\"aeiou\")\n count = 0\n word_length = len(s)\n\n for i, char in enumerate(s):\n if char.lower() in vowels:\n count += 1\n elif char.lower() == 'y' and i == word_length - 1:\n count += 1\n\n return count", "matching_cluster_idx": 1}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = set('aeiou')\n count = 0\n s_lower = s.lower()\n\n for i, char in enumerate(s_lower):\n if char in vowels:\n count += 1\n elif char == 'y' and i == len(s_lower) - 1:\n count += 1\n\n return count", "matching_cluster_idx": 3}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n # Define vowels\n vowels = \"aeiouAEIOU\"\n # Initialize count\n count = 0\n # Check for vowels\n for char in s:\n if char in vowels:\n count += 1\n # Check if 'y' or 'Y' is at the end\n if s and s[-1] in 'yY':\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = 'aeiou'\n count = 0\n for i, char in enumerate(s):\n if char.lower() in vowels:\n count += 1\n elif char.lower() == 'y' and i == len(s) - 1:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = \"aeiouAEIOU\"\n count = 0\n if s.endswith('y') or s.endswith('Y'):\n count += 1\n for char in s:\n if char in vowels:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n \"\"\"\n Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = \"aeiou\"\n count = sum(1 for char in s.lower() if char in vowels)\n return count + (1 if s.lower().endswith('y') else 0)", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n \"\"\"\n Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = \"aeiou\"\n count = 0\n\n for i, char in enumerate(s):\n if char.lower() in vowels:\n count += 1\n elif char.lower() == 'y' and i == len(s) - 1:\n count += 1\n\n return count", "matching_cluster_idx": 2}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = 'aeiou'\n count = 0\n if s and s[-1].lower() == 'y':\n count += 1\n for char in s:\n if char.lower() in vowels:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = \"aeiouAEIOU\"\n count = 0\n if s and s[-1] in 'yY':\n count += 1\n for char in s:\n if char in vowels:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when it is at the end of the given word.\n\n Example:\n >>> vowels_count(\"abcde\")\n 2\n >>> vowels_count(\"ACEDY\")\n 3\n \"\"\"\n vowels = \"aeiou\"\n count = 0\n if s and s[-1].lower() == 'y':\n count += 1\n for char in s.lower():\n if char in vowels:\n count += 1\n return count", "matching_cluster_idx": 4}]}, "HumanEval/74": {"dps": 84.1341463414634, "dps_norm": 85.0, "pass@1": 90.0, "profiled": [{"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has\n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n\n total_chars_lst1 = sum(len(word) for word in lst1)\n total_chars_lst2 = sum(len(word) for word in lst2)\n\n if total_chars_lst1 < total_chars_lst2:\n return lst1\n elif total_chars_lst2 < total_chars_lst1:\n return lst2\n else:\n return lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has\n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n\n # Calculate the total number of characters in each list\n total_chars_lst1 = sum(len(word) for word in lst1)\n total_chars_lst2 = sum(len(word) for word in lst2)\n\n # Return the list with the fewer characters or the first list if they are equal\n if total_chars_lst1 < total_chars_lst2:\n return lst1\n elif total_chars_lst2 < total_chars_lst1:\n return lst2\n else:\n return lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has\n total number of chars in all strings of the list less than the other list.\n\n If the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n total_chars_lst1 = sum(len(s) for s in lst1)\n total_chars_lst2 = sum(len(s) for s in lst2)\n\n if total_chars_lst1 < total_chars_lst2:\n return lst1\n elif total_chars_lst2 < total_chars_lst1:\n return lst2\n else:\n return lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has\n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n # Calculate the total number of characters in each list\n total_chars_lst1 = sum(len(word) for word in lst1)\n total_chars_lst2 = sum(len(word) for word in lst2)\n\n # Compare the totals and return the appropriate list\n if total_chars_lst1 < total_chars_lst2:\n return lst1\n elif total_chars_lst2 < total_chars_lst1:\n return lst2\n else:\n return lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has\n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n\n def total_char_count(lst):\n return sum(len(s) for s in lst)\n\n char_count_lst1 = total_char_count(lst1)\n char_count_lst2 = total_char_count(lst2)\n\n if char_count_lst1 < char_count_lst2:\n return lst1\n elif char_count_lst1 > char_count_lst2:\n return lst2\n else:\n return lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has\n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n\n # Calculate the total number of characters in each list\n total_chars_lst1 = sum(len(word) for word in lst1)\n total_chars_lst2 = sum(len(word) for word in lst2)\n\n # Compare the total number of characters and return the appropriate list\n if total_chars_lst1 < total_chars_lst2:\n return lst1\n elif total_chars_lst2 < total_chars_lst1:\n return lst2\n else:\n return lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n \"\"\"\n Write a function that accepts two lists of strings and returns the list that has\n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n \"\"\"\n # Calculate the total number of characters in each list\n total_chars_lst1 = sum(len(word) for word in lst1)\n total_chars_lst2 = sum(len(word) for word in lst2)\n\n # Compare the totals and return the list with fewer characters\n if total_chars_lst1 < total_chars_lst2:\n return lst1\n elif total_chars_lst2 < total_chars_lst1:\n return lst2\n else:\n return lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has\n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n # Calculate the total number of characters in each list\n total_chars_lst1 = sum(len(word) for word in lst1)\n total_chars_lst2 = sum(len(word) for word in lst2)\n\n # Determine which list has fewer total characters\n if total_chars_lst1 < total_chars_lst2:\n return lst1\n elif total_chars_lst1 > total_chars_lst2:\n return lst2\n else:\n return lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has\n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n total_chars_lst1 = sum(len(s) for s in lst1)\n total_chars_lst2 = sum(len(s) for s in lst2)\n\n if total_chars_lst1 < total_chars_lst2 or total_chars_lst1 == total_chars_lst2:\n return lst1\n else:\n return lst2", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has\n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n def total_char_count(lst):\n return sum(len(s) for s in lst)\n\n if total_char_count(lst1) < total_char_count(lst2):\n return lst1\n elif total_char_count(lst1) > total_char_count(lst2):\n return lst2\n else:\n return lst1", "matching_cluster_idx": 5}, {"solution": "def total_match(lst1, lst2):\n def total_length(lst):\n return sum(len(s) for s in lst)\n\n len1 = total_length(lst1)\n len2 = total_length(lst2)\n\n if len1 < len2:\n return lst1\n elif len2 < len1:\n return lst2\n else:\n return lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has\n total number of chars in all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n\n def total_char_count(lst):\n return sum(len(word) for word in lst)\n\n count1 = total_char_count(lst1)\n count2 = total_char_count(lst2)\n\n if count1 < count2:\n return lst1\n elif count2 < count1:\n return lst2\n else:\n return lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has\n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n\n def total_chars(lst):\n return sum(len(s) for s in lst)\n\n chars1 = total_chars(lst1)\n chars2 = total_chars(lst2)\n\n if chars1 < chars2:\n return lst1\n elif chars2 < chars1:\n return lst2\n else:\n return lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has\n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n # Calculate total number of characters in each list\n total_chars_lst1 = sum(len(s) for s in lst1)\n total_chars_lst2 = sum(len(s) for s in lst2)\n\n # Compare the totals and return the appropriate list\n if total_chars_lst1 < total_chars_lst2:\n return lst1\n elif total_chars_lst1 > total_chars_lst2:\n return lst2\n else:\n return lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has\n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n '''\n def total_chars(lst):\n return sum(len(s) for s in lst)\n\n if total_chars(lst1) < total_chars(lst2):\n return lst1\n elif total_chars(lst1) > total_chars(lst2):\n return lst2\n else:\n return lst1", "matching_cluster_idx": 4}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has\n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n '''\n def total_char_count(lst):\n return sum(len(s) for s in lst)\n\n char_count_lst1 = total_char_count(lst1)\n char_count_lst2 = total_char_count(lst2)\n\n if char_count_lst1 < char_count_lst2:\n return lst1\n elif char_count_lst2 < char_count_lst1:\n return lst2\n else:\n return lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has\n total number of chars in the all strings of the list less than the other list.\n\n If the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n # Calculate the total number of characters in each list\n total_chars_lst1 = sum(len(word) for word in lst1)\n total_chars_lst2 = sum(len(word) for word in lst2)\n\n # Return the list with the fewer characters, or the first list if they are equal\n if total_chars_lst1 < total_chars_lst2:\n return lst1\n elif total_chars_lst2 < total_chars_lst1:\n return lst2\n else:\n return lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n \"\"\"\n Write a function that accepts two lists of strings and returns the list that has\n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n \"\"\"\n # Calculate the total number of characters in each list\n total_chars_lst1 = sum(len(word) for word in lst1)\n total_chars_lst2 = sum(len(word) for word in lst2)\n\n # Compare the totals and return the appropriate list\n if total_chars_lst1 < total_chars_lst2:\n return lst1\n elif total_chars_lst1 > total_chars_lst2:\n return lst2\n else:\n return lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has\n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n # Calculate the total number of characters in each list\n total_chars_lst1 = sum(len(word) for word in lst1)\n total_chars_lst2 = sum(len(word) for word in lst2)\n\n # Determine which list has fewer characters or return the first list if they are equal\n if total_chars_lst1 < total_chars_lst2:\n return lst1\n elif total_chars_lst2 < total_chars_lst1:\n return lst2\n else:\n return lst1", "matching_cluster_idx": 7}, {"solution": "def total_match(lst1, lst2):\n '''\n Write a function that accepts two lists of strings and returns the list that has\n total number of chars in the all strings of the list less than the other list.\n\n if the two lists have the same number of chars, return the first list.\n\n Examples\n total_match([], []) \u279e []\n total_match(['hi', 'admin'], ['hI', 'Hi']) \u279e ['hI', 'Hi']\n total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) \u279e ['hi', 'admin']\n total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) \u279e ['hI', 'hi', 'hi']\n total_match(['4'], ['1', '2', '3', '4', '5']) \u279e ['4']\n '''\n def total_chars(lst):\n return sum(len(s) for s in lst)\n\n if total_chars(lst1) < total_chars(lst2):\n return lst1\n elif total_chars(lst2) < total_chars(lst1):\n return lst2\n else:\n return lst1", "matching_cluster_idx": 5}]}, "HumanEval/85": {"dps": 95.69306930693068, "dps_norm": 65.0, "pass@1": 100.0, "profiled": [{"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2\n add([1, 3, 5, 7, 9]) ==> 0\n add([2, 4, 6, 8]) ==> 2\n add([3, 5, 7, 9]) ==> 0\n \"\"\"\n return sum(lst[i] for i in range(1, len(lst), 2) if lst[i] % 2 == 0)", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"\n Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Args:\n lst (list): A list of integers.\n\n Returns:\n int: The sum of even elements at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2\n \"\"\"\n total = 0\n for i in range(1, len(lst), 2):\n if lst[i] % 2 == 0:\n total += lst[i]\n return total", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"\n Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2\n \"\"\"\n # Initialize the sum of even elements at odd indices\n sum_even_odd_indices = 0\n\n # Iterate over the list with index\n for i in range(1, len(lst), 2): # start from index 1 and step by 2\n if lst[i] % 2 == 0: # check if the element is even\n sum_even_odd_indices += lst[i]\n\n return sum_even_odd_indices", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2\n \"\"\"\n # Initialize sum to 0\n total = 0\n\n # Iterate through the list with index\n for i in range(1, len(lst), 2):\n # Check if the element at the odd index is even\n if lst[i] % 2 == 0:\n # Add the even element to the total sum\n total += lst[i]\n\n return total", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"\n Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2\n \"\"\"\n even_sum = 0\n for i in range(1, len(lst), 2): # Loop through odd indices\n if lst[i] % 2 == 0: # Check if the element at the odd index is even\n even_sum += lst[i]\n return even_sum", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2\n \"\"\"\n # Iterate through the list, summing up elements that are even and at odd indices\n return sum(lst[i] for i in range(1, len(lst), 2) if lst[i] % 2 == 0)", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2\n \"\"\"\n total = 0\n for i in range(1, len(lst), 2):\n if lst[i] % 2 == 0:\n total += lst[i]\n return total", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2\n \"\"\"\n # Initialize a variable to store the sum of even elements at odd indices\n sum_even_at_odd_indices = 0\n\n # Iterate over the list using enumerate to get both index and value\n for index, value in enumerate(lst):\n # Check if the index is odd and the value is even\n if index % 2 != 0 and value % 2 == 0:\n # Add the value to the sum\n sum_even_at_odd_indices += value\n\n # Return the sum\n return sum_even_at_odd_indices", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"\n Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2\n \"\"\"\n return sum(lst[i] for i in range(1, len(lst), 2) if lst[i] % 2 == 0)", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"\n Given a non-empty list of integers lst. add the even elements that are at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2\n \"\"\"\n return sum(lst[i] for i in range(1, len(lst), 2) if lst[i] % 2 == 0)", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2\n \"\"\"\n return sum(lst[i] for i in range(1, len(lst), 2) if lst[i] % 2 == 0)", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2\n \"\"\"\n # Initialize the sum to 0\n sum_even_odd_indices = 0\n\n # Iterate over the list with both index and value\n for index, value in enumerate(lst):\n # Check if the index is odd and value is even\n if index % 2 != 0 and value % 2 == 0:\n sum_even_odd_indices += value\n\n return sum_even_odd_indices", "matching_cluster_idx": 2}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2\n \"\"\"\n total = 0\n for i in range(1, len(lst), 2): # Start from index 1 and step by 2\n if lst[i] % 2 == 0: # Check if the element at the odd index is even\n total += lst[i]\n return total", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. Add the even elements that are at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2\n \"\"\"\n # Initialize the sum of even elements at odd indices\n total_sum = 0\n\n # Iterate over the list with index\n for i in range(1, len(lst), 2):\n if lst[i] % 2 == 0:\n total_sum += lst[i]\n\n return total_sum", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"\n Given a non-empty list of integers `lst`, add the even elements that are at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2\n \"\"\"\n total = 0\n for i in range(1, len(lst), 2): # Start from index 1 and step by 2\n if lst[i] % 2 == 0: # Check if the element at the current odd index is even\n total += lst[i]\n return total", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2\n \"\"\"\n sum_even_odd_indices = sum(lst[i] for i in range(1, len(lst), 2) if lst[i] % 2 == 0)\n return sum_even_odd_indices", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2\n \"\"\"\n # Initialize sum to 0\n total = 0\n\n # Iterate through the list, checking only odd indices (1, 3, 5, ...)\n for i in range(1, len(lst), 2):\n # Check if the element at the odd index is even\n if lst[i] % 2 == 0:\n # Add it to the total sum\n total += lst[i]\n\n return total", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2\n \"\"\"\n return sum(lst[i] for i in range(1, len(lst), 2) if lst[i] % 2 == 0)", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst. Add the even elements that are at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2\n \"\"\"\n # Initialize sum to 0\n total_sum = 0\n\n # Iterate over the list with index\n for i in range(1, len(lst), 2): # Start from index 1 and step by 2 to get odd indices\n if lst[i] % 2 == 0: # Check if the element is even\n total_sum += lst[i]\n\n return total_sum", "matching_cluster_idx": 3}, {"solution": "def add(lst):\n \"\"\"Given a non-empty list of integers lst, add the even elements that are at odd indices.\n\n Args:\n lst (list): A non-empty list of integers.\n\n Returns:\n int: The sum of the even elements at odd indices.\n\n Examples:\n add([4, 2, 6, 7]) ==> 2\n \"\"\"\n sum_of_evens = 0\n for i in range(1, len(lst), 2): # iterate over odd indices\n if lst[i] % 2 == 0: # check if the element is even\n sum_of_evens += lst[i] # add the element to the sum\n return sum_of_evens", "matching_cluster_idx": 3}]}, "HumanEval/86": {"dps": 95.64625850340136, "dps_norm": 99.0, "pass@1": 20.0, "profiled": [{"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters are arranged in\n ascending order based on ASCII value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n def sorted_word(word):\n return ''.join(sorted(word))\n\n # Split the input string by spaces\n words = s.split(' ')\n\n # Sort each word and rejoin them with spaces\n ordered_words = [sorted_word(word) for word in words]\n\n # Join the ordered words back into a single string\n return ' '.join(ordered_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n # Split the input string into words\n words = s.split(' ')\n\n # Process each word individually\n ordered_words = []\n for word in words:\n # Sort the characters of the word based on their ASCII values\n ordered_word = ''.join(sorted(word))\n ordered_words.append(ordered_word)\n\n # Join the ordered words back into a single string with spaces\n ordered_sentence = ' '.join(ordered_words)\n\n return ordered_sentence", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n # Split the input string by spaces to handle words separately\n words = s.split(' ')\n\n # Function to sort characters of a word based on their ASCII values\n def sort_characters(word):\n return ''.join(sorted(word))\n\n # Apply the sort_characters function to each word and join them back with spaces\n result = ' '.join(sort_characters(word) for word in words)\n\n return result", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters are arranged in\n ascending order based on ASCII value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n words = s.split(' ')\n result = []\n\n for word in words:\n # Sort characters in the word based on ASCII value\n sorted_word = ''.join(sorted(word))\n result.append(sorted_word)\n\n # Join the sorted words with spaces to form the final sentence\n return ' '.join(result)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n def order_string(word):\n # Return the sorted version of the word\n return ''.join(sorted(word))\n\n # Split the input string by spaces\n words = s.split(' ')\n\n # Sort each word and join them back with space\n ordered_words = ' '.join(order_string(word) for word in words)\n\n return ordered_words", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters are arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n def sort_word(word):\n # Sort characters in each word based on ASCII value\n return ''.join(sorted(word))\n\n # Split the string into words\n words = s.split(' ')\n\n # Sort each word and join them back with spaces\n result = ' '.join(sort_word(word) for word in words)\n\n return result", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n def sort_characters(word):\n # Sort characters in each word by their ASCII values\n return ''.join(sorted(word))\n\n # Split the string into words based on spaces\n words = s.split(' ')\n # Apply the sort_characters function to each word\n sorted_words = [sort_characters(word) for word in words]\n # Join the sorted words back into a single string\n return ' '.join(sorted_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n words = s.split(' ')\n ordered_words = [''.join(sorted(word)) for word in words]\n return ' '.join(ordered_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters are arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n words = s.split(' ')\n result = []\n\n for word in words:\n # Sort the characters of the word based on ASCII values\n sorted_word = ''.join(sorted(word))\n result.append(sorted_word)\n\n return ' '.join(result)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n def sort_word(word):\n # Join the sorted characters of the word\n return ''.join(sorted(word))\n\n # Split the input string by spaces to get the words\n words = s.split(' ')\n\n # Sort each word and join them back with spaces\n sorted_words = ' '.join(sort_word(word) for word in words)\n\n return sorted_words", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters are arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n words = s.split(' ')\n ordered_words = []\n\n for word in words:\n # Skip the word if it doesn't need to be reordered\n if all(word[i] <= word[i + 1] for i in range(len(word) - 1)):\n ordered_words.append(word)\n else:\n # Reorder characters in the word based on ASCII value\n ordered_word = ''.join(sorted(word))\n ordered_words.append(ordered_word)\n\n # Join the list of words back into a single string\n ordered_sentence = ' '.join(ordered_words)\n return ordered_sentence", "matching_cluster_idx": 3}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n words = s.split(' ')\n ordered_words = []\n\n for word in words:\n char_list = list(word)\n char_list.sort()\n ordered_word = ''.join(char_list)\n ordered_words.append(ordered_word)\n\n return ' '.join(ordered_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n def sort_characters(word):\n # Sort the characters of the word based on ASCII value\n return ''.join(sorted(word))\n\n # Split the string into words\n words = s.split(' ')\n\n # Sort characters in each word and join them back with spaces\n sorted_words = [sort_characters(word) for word in words]\n\n # Join the sorted words with spaces to get the final string\n return ' '.join(sorted_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n def sort_string(word):\n return ''.join(sorted(word))\n\n words = s.split(' ')\n return ' '.join(sort_string(word) for word in words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n words = s.split(' ')\n ordered_words = []\n\n for word in words:\n chars = list(word)\n chars.sort()\n ordered_words.append(''.join(chars))\n\n return ' '.join(ordered_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n # Split the string into words\n words = s.split(' ')\n # Process each word\n ordered_words = []\n for word in words:\n # Sort the characters in each word\n ordered_word = ''.join(sorted(word))\n # Append the ordered word to the list\n ordered_words.append(ordered_word)\n # Join the ordered words back into a single string\n return ' '.join(ordered_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n def sort_chars(word):\n return ''.join(sorted(word))\n\n words = s.split(' ')\n sorted_words = [sort_chars(word) for word in words]\n return ' '.join(sorted_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n words = s.split(' ')\n for i in range(len(words)):\n words[i] = ''.join(sorted(words[i]))\n return ' '.join(words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n\n # Split the input string by spaces to handle words separately\n words = s.split(' ')\n\n # Process each word individually\n ordered_words = []\n for word in words:\n # Convert the word to a list of characters and sort it\n sorted_word = ''.join(sorted(word))\n ordered_words.append(sorted_word)\n\n # Join the ordered words back into a single string with spaces in between\n return ' '.join(ordered_words)", "matching_cluster_idx": 4}, {"solution": "def anti_shuffle(s):\n \"\"\"\n Write a function that takes a string and returns an ordered version of it.\n Ordered version of string, is a string where all words (separated by space)\n are replaced by a new word where all the characters are arranged in\n ascending order based on ascii value.\n Note: You should keep the order of words and blank spaces in the sentence.\n\n For example:\n anti_shuffle('Hi') returns 'Hi'\n anti_shuffle('hello') returns 'ehllo'\n anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'\n \"\"\"\n words = s.split(' ')\n ordered_words = []\n for word in words:\n # Sort characters of the word based on ASCII value\n sorted_word = ''.join(sorted(word))\n ordered_words.append(sorted_word)\n return ' '.join(ordered_words)", "matching_cluster_idx": 4}]}, "HumanEval/87": {"dps": 78.22766570605188, "dps_norm": 53.57142857142858, "pass@1": 52.0, "profiled": [{"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n\n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n\n coordinates = []\n\n for i, row in enumerate(lst):\n row_coords = [(i, j) for j, val in enumerate(row) if val == x]\n coordinates.extend(row_coords)\n\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n\n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n\n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n result = []\n for row_index, row in enumerate(lst):\n for col_index, value in enumerate(row):\n if value == x:\n result.append((row_index, col_index))\n\n # Sort the results initially by rows in ascending order\n result.sort(key=lambda coord: (coord[0], -coord[1]))\n\n return result", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n\n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n\n coordinates = []\n for row_idx, row in enumerate(lst):\n for col_idx, value in enumerate(row):\n if value == x:\n coordinates.append((row_idx, col_idx))\n\n # Sort by rows, and within each row, sort by columns in descending order\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n\n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n\n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n coordinates = [(i, j) for i, row in enumerate(lst) for j, val in enumerate(row) if val == x]\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n\n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n\n result = []\n\n for row_index, row in enumerate(lst):\n for col_index, value in enumerate(row):\n if value == x:\n result.append((row_index, col_index))\n\n # Sort by row in ascending order, and for ties, sort by column in descending order\n result.sort(key=lambda coord: (coord[0], -coord[1]))\n\n return result", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n Given a 2 dimensional data as a nested list, where each row may contain a different number of columns,\n find integers x in the list, and return list of tuples, [(x1, y1), (x2, y2) ...] such that each tuple\n is a coordinate - (row, columns), starting with 0.\n\n Sort coordinates initially by rows in ascending order. Also, sort coordinates of the row by columns in descending order.\n \"\"\"\n coordinates = []\n\n for row_idx, row in enumerate(lst):\n for col_idx, value in enumerate(row):\n if value == x:\n coordinates.append((row_idx, col_idx))\n\n # Sort initially by rows in ascending order\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n\n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n\n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n\n coordinates = []\n\n # Iterate through the list of lists\n for row_index, row in enumerate(lst):\n # Iterate through the row elements\n for col_index, value in enumerate(row):\n if value == x:\n coordinates.append((row_index, col_index))\n\n # Sort by rows in ascending order\n coordinates.sort()\n\n # Sort coordinates within the same row by columns in descending order\n for i in range(len(coordinates)):\n for j in range(i + 1, len(coordinates)):\n if coordinates[i][0] == coordinates[j][0]:\n if coordinates[i][1] < coordinates[j][1]:\n coordinates[i], coordinates[j] = coordinates[j], coordinates[i]\n\n return coordinates", "matching_cluster_idx": 2}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n\n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n result = []\n\n for row_idx, row in enumerate(lst):\n for col_idx, value in enumerate(row):\n if value == x:\n result.append((row_idx, col_idx))\n\n result.sort(key=lambda x: (x[0], -x[1]))\n return result", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n\n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n result = []\n for row_index, row in enumerate(lst):\n for col_index, value in enumerate(row):\n if value == x:\n result.append((row_index, col_index))\n\n # Sort by row, then by column in descending order\n result.sort(key=lambda coord: (coord[0], -coord[1]))\n return result", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n\n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n\n coordinates = []\n for row_index, row in enumerate(lst):\n for col_index, value in enumerate(row):\n if value == x:\n coordinates.append((row_index, col_index))\n\n # Sort first by row in ascending order, then by column in descending order\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n\n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n result = []\n for row_index, row in enumerate(lst):\n indices = [(row_index, i) for i in reversed(range(len(row))) if row[i] == x]\n result.extend(indices)\n\n result.sort(key=lambda coord: (coord[0], -coord[1]))\n return result", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n\n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n\n coordinates = []\n\n for row_index, row in enumerate(lst):\n for col_index, value in enumerate(row):\n if value == x:\n coordinates.append((row_index, col_index))\n\n # Sort by row in ascending order\n coordinates.sort()\n\n # For each row, sort coordinates by column in descending order\n result = []\n for row_index in range(len(lst)):\n row_coords = [coord for coord in coordinates if coord[0] == row_index]\n row_coords.sort(reverse=True)\n result.extend(row_coords)\n\n return result", "matching_cluster_idx": 1}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n\n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n\n result = []\n for i, row in enumerate(lst):\n row_coords = [(i, j) for j in range(len(row)-1, -1, -1) if row[j] == x]\n result.extend(row_coords)\n\n result.sort()\n\n # To sort coordinates within the same row by columns in descending order\n result = sorted(result, key=lambda coord: (coord[0], -coord[1]))\n\n return result", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n\n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n\n coordinates = []\n for row_idx, row in enumerate(lst):\n for col_idx, value in reversed(list(enumerate(row))):\n if value == x:\n coordinates.append((row_idx, col_idx))\n\n # Sort by row, then by column in descending order within each row\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n\n return coordinates", "matching_cluster_idx": 2}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n\n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n\n coordinates = []\n\n # Iterate through each row\n for i, row in enumerate(lst):\n # Iterate through each column in the row\n for j, value in enumerate(row):\n if value == x:\n coordinates.append((i, j))\n\n # Sort by rows in ascending order, and columns in descending order within each row\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n\n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n\n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n coordinates = []\n\n for row_idx, row in enumerate(lst):\n for col_idx, value in reversed(list(enumerate(row))):\n if value == x:\n coordinates.append((row_idx, col_idx))\n\n # Sort by row index and within each row by column index (descending)\n coordinates.sort(key=lambda coord: (coord[0], -coord[1]))\n\n return coordinates", "matching_cluster_idx": 2}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n\n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n coordinates = []\n\n # Iterate through the list and collect coordinates of the target value x\n for row_idx, row in enumerate(lst):\n for col_idx, value in enumerate(row):\n if value == x:\n coordinates.append((row_idx, col_idx))\n\n # Sort coordinates by row index first, then by column index (descending)\n coordinates.sort(key=lambda x: (x[0], -x[1]))\n\n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n\n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n\n coordinates = []\n\n for row_index, row in enumerate(lst):\n for col_index, value in enumerate(row):\n if value == x:\n coordinates.append((row_index, col_index))\n\n # Sort coordinates initially by rows in ascending order\n coordinates.sort(key=lambda x: (x[0], -x[1]))\n\n return coordinates", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n\n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n result = []\n for i, row in enumerate(lst):\n row_coords = [(i, j) for j, val in enumerate(row) if val == x]\n result.extend(row_coords)\n\n # Sort results first by row, then by column in descending order\n result.sort()\n result = sorted(result, key=lambda x: (x[0], -x[1]))\n\n return result", "matching_cluster_idx": 3}, {"solution": "def get_row(lst, x):\n \"\"\"\n You are given a 2 dimensional data, as a nested lists,\n which is similar to matrix, however, unlike matrices,\n each row may contain a different number of columns.\n Given lst, and integer x, find integers x in the list,\n and return list of tuples, [(x1, y1), (x2, y2) ...] such that\n each tuple is a coordinate - (row, columns), starting with 0.\n Sort coordinates initially by rows in ascending order.\n Also, sort coordinates of the row by columns in descending order.\n\n Examples:\n get_row([\n [1,2,3,4,5,6],\n [1,2,3,4,1,6],\n [1,2,3,4,5,1]\n ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]\n get_row([], 1) == []\n get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]\n \"\"\"\n\n coordinates = []\n for row_index, row in enumerate(lst):\n for col_index, value in enumerate(row):\n if value == x:\n coordinates.append((row_index, col_index))\n\n # Sort by rows in ascending order\n coordinates.sort(key=lambda x: (x[0], -x[1]))\n\n return coordinates", "matching_cluster_idx": 3}]}, "HumanEval/89": {"dps": 96.64948453608248, "dps_norm": 28.571428571428573, "pass@1": 71.0, "profiled": [{"solution": "def encrypt(s):\n \"\"\"\n Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated.\n The alphabet should be rotated in a manner such that the letters\n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n def shift_char(c):\n if 'a' <= c <= 'z':\n return chr((ord(c) - ord('a') + 4) % 26 + ord('a'))\n elif 'A' <= c <= 'Z':\n return chr((ord(c) - ord('A') + 4) % 26 + ord('A'))\n else:\n return c\n\n return ''.join(shift_char(c) for c in s)", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated.\n The alphabet should be rotated in a manner such that the letters\n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n shift = 4 # because we need to shift down by 2 multiplied to two places (2*2)\n alphabet = 'abcdefghijklmnopqrstuvwxyz'\n\n def shift_char(c):\n if c.islower():\n return alphabet[(alphabet.index(c) + shift) % 26]\n return c\n\n return ''.join(shift_char(c) for c in s)", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"\n Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated.\n The alphabet should be rotated in a manner such that the letters\n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n shift = 2 * 2\n result = []\n\n for char in s:\n if char.isalpha():\n ascii_offset = 65 if char.isupper() else 97\n # Perform wrap-around with modulo operation\n encrypted_char = chr((ord(char) - ascii_offset + shift) % 26 + ascii_offset)\n result.append(encrypted_char)\n else:\n result.append(char)\n\n return ''.join(result)", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"\n Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated.\n The alphabet should be rotated in a manner such that the letters\n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n shift = 4 # 2 multiplied by 2 (2 * 2)\n result = []\n for char in s:\n if char.isalpha():\n if char.islower():\n new_char = chr((ord(char) - ord('a') + shift) % 26 + ord('a'))\n elif char.isupper():\n new_char = chr((ord(char) - ord('A') + shift) % 26 + ord('A'))\n result.append(new_char)\n else:\n result.append(char)\n return ''.join(result)", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated.\n The alphabet should be rotated in a manner such that the letters\n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n alphabet = \"abcdefghijklmnopqrstuvwxyz\"\n shift = 2 * 2 # Shift letters down by 2 positions in the alphabet\n\n encrypted_string = []\n\n for char in s:\n if char.islower():\n # Find the position of the character in the alphabet\n idx = alphabet.index(char)\n # Calculate the new position with the shift applied\n new_idx = (idx + shift) % len(alphabet)\n # Append the new character to the encrypted string\n encrypted_string.append(alphabet[new_idx])\n else:\n # If the character is not a lowercase letter, keep it as it is\n encrypted_string.append(char)\n\n return ''.join(encrypted_string)", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated.\n The alphabet should be rotated in a manner such that the letters\n shift down by two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n encrypted_chars = []\n alphabet = 'abcdefghijklmnopqrstuvwxyz'\n\n for char in s:\n if char.islower():\n encrypted_char = alphabet[(alphabet.index(char) + 4) % 26]\n encrypted_chars.append(encrypted_char)\n else:\n encrypted_chars.append(char) # Keep uppercase and non-alphabet characters unchanged\n\n return ''.join(encrypted_chars)", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated.\n The alphabet should be rotated in a manner such that the letters\n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n def shift_char(c):\n if 'a' <= c <= 'z':\n return chr((ord(c) - ord('a') + 4) % 26 + ord('a'))\n elif 'A' <= c <= 'Z':\n return chr((ord(c) - ord('A') + 4) % 26 + ord('A'))\n else:\n return c\n\n return ''.join(shift_char(c) for c in s)", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated.\n The alphabet should be rotated in a manner such that the letters\n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n def shift_char(c):\n if 'a' <= c <= 'z':\n return chr((ord(c) - ord('a') + 4) % 26 + ord('a'))\n elif 'A' <= c <= 'Z':\n return chr((ord(c) - ord('A') + 4) % 26 + ord('A'))\n else:\n return c\n\n return ''.join(shift_char(c) for c in s)", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated.\n The alphabet should be rotated in a manner such that the letters\n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n encrypted_str = \"\"\n shift = 4 # Shift by 4 places as described (2 multiplied by 2)\n alphabet = \"abcdefghijklmnopqrstuvwxyz\"\n\n for char in s:\n if char.islower():\n encrypted_str += alphabet[(alphabet.index(char) + shift) % 26]\n elif char.isupper():\n encrypted_str += alphabet[(alphabet.index(char.lower()) + shift) % 26].upper()\n else:\n encrypted_str += char # Non-alphabetic characters remain unchanged\n\n return encrypted_str", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated.\n The alphabet should be rotated in a manner such that the letters\n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n def shift_char(c):\n if 'a' <= c <= 'z':\n return chr((ord(c) - ord('a') + 4) % 26 + ord('a'))\n elif 'A' <= c <= 'Z':\n return chr((ord(c) - ord('A') + 4) % 26 + ord('A'))\n else:\n return c\n\n return ''.join(shift_char(c) for c in s)", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated.\n The alphabet should be rotated in a manner such that the letters\n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n def shift_char(c):\n \"\"\"Shift a single character by two places, wrapping around if necessary.\"\"\"\n if 'a' <= c <= 'z':\n return chr((ord(c) - ord('a') + 4) % 26 + ord('a'))\n elif 'A' <= c <= 'Z':\n return chr((ord(c) - ord('A') + 4) % 26 + ord('A'))\n else:\n return c\n\n return ''.join(shift_char(c) for c in s)", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated.\n The alphabet should be rotated in a manner such that the letters\n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n encrypted_str = []\n\n for char in s:\n if char.islower():\n # Shift by 2*2 = 4 places\n new_char = chr((ord(char) - ord('a') + 4) % 26 + ord('a'))\n encrypted_str.append(new_char)\n elif char.isupper():\n # Shift by 2*2 = 4 places for uppercase\n new_char = chr((ord(char) - ord('A') + 4) % 26 + ord('A'))\n encrypted_str.append(new_char)\n else:\n # Non-alphabetic characters remain the same\n encrypted_str.append(char)\n\n return ''.join(encrypted_str)", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated.\n The alphabet should be rotated in a manner such that the letters\n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n def shift_char(c):\n if 'a' <= c <= 'z':\n return chr((ord(c) - ord('a') + 4) % 26 + ord('a'))\n elif 'A' <= c <= 'Z':\n return chr((ord(c) - ord('A') + 4) % 26 + ord('A'))\n else:\n return c\n\n return ''.join(shift_char(c) for c in s)", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated.\n The alphabet should be rotated in a manner such that the letters\n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n def shift_char(c):\n if 'a' <= c <= 'z':\n return chr(((ord(c) - ord('a') + 4) % 26) + ord('a'))\n elif 'A' <= c <= 'Z':\n return chr(((ord(c) - ord('A') + 4) % 26) + ord('A'))\n else:\n return c\n\n return ''.join(shift_char(c) for c in s)", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated.\n The alphabet should be rotated in a manner such that the letters\n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n def shift_char(c):\n if 'a' <= c <= 'z':\n return chr((ord(c) - ord('a') + 4) % 26 + ord('a'))\n elif 'A' <= c <= 'Z':\n return chr((ord(c) - ord('A') + 4) % 26 + ord('A'))\n else:\n return c\n\n return ''.join(shift_char(c) for c in s)", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated.\n The alphabet should be rotated in a manner such that the letters\n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n def shift_char(c):\n \"\"\"Shift a character down by two times two places.\"\"\"\n if 'a' <= c <= 'z':\n # For lowercase letters\n return chr((ord(c) - ord('a') + 4) % 26 + ord('a'))\n elif 'A' <= c <= 'Z':\n # For uppercase letters\n return chr((ord(c) - ord('A') + 4) % 26 + ord('A'))\n else:\n # Return non-alphabet characters as they are\n return c\n\n # Apply the shift to each character in the string\n return ''.join(shift_char(c) for c in s)", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated.\n The alphabet should be rotated in a manner such that the letters\n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n def shift_char(c):\n if c.islower():\n return chr((ord(c) - ord('a') + 4) % 26 + ord('a'))\n elif c.isupper():\n return chr((ord(c) - ord('A') + 4) % 26 + ord('A'))\n else:\n return c # Non-alphabetic characters are unchanged\n\n return ''.join(shift_char(c) for c in s)", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n def shift_char(c):\n if 'a' <= c <= 'z':\n return chr((ord(c) - ord('a') + 4) % 26 + ord('a'))\n elif 'A' <= c <= 'Z':\n return chr((ord(c) - ord('A') + 4) % 26 + ord('A'))\n else:\n return c\n\n return ''.join(shift_char(c) for c in s)", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated.\n The alphabet should be rotated in a manner such that the letters\n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n encrypted_str = ''\n for char in s:\n if char.islower():\n # Shift down by 4 places (rotated by 2*2)\n encrypted_str += chr((ord(char) - ord('a') + 4) % 26 + ord('a'))\n elif char.isupper():\n # Shift down by 4 places (rotated by 2*2)\n encrypted_str += chr((ord(char) - ord('A') + 4) % 26 + ord('A'))\n else:\n # Non-alphabet characters remain the same\n encrypted_str += char\n return encrypted_str", "matching_cluster_idx": 1}, {"solution": "def encrypt(s):\n \"\"\"Create a function encrypt that takes a string as an argument and\n returns a string encrypted with the alphabet being rotated.\n The alphabet should be rotated in a manner such that the letters\n shift down by two multiplied to two places.\n For example:\n encrypt('hi') returns 'lm'\n encrypt('asdfghjkl') returns 'ewhjklnop'\n encrypt('gf') returns 'kj'\n encrypt('et') returns 'ix'\n \"\"\"\n shift = 2\n result = []\n\n for char in s:\n if char.islower():\n new_char = chr((ord(char) - ord('a') + shift * 2) % 26 + ord('a'))\n elif char.isupper():\n new_char = chr((ord(char) - ord('A') + shift * 2) % 26 + ord('A'))\n else:\n new_char = char\n result.append(new_char)\n\n return ''.join(result)", "matching_cluster_idx": 1}]}, "HumanEval/90": {"dps": 58.91050583657588, "dps_norm": 51.666666666666664, "pass@1": 87.0, "profiled": [{"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n\n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n\n # Remove duplicates and sort the list\n unique_sorted_lst = sorted(set(lst))\n\n if len(unique_sorted_lst) < 2:\n return None\n\n return unique_sorted_lst[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n\n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n\n # Initialize the first and second smallest values\n first_smallest = float('inf')\n second_smallest = float('inf')\n\n for num in lst:\n if num < first_smallest:\n second_smallest = first_smallest\n first_smallest = num\n elif first_smallest < num < second_smallest:\n second_smallest = num\n\n return second_smallest if second_smallest != float('inf') else None", "matching_cluster_idx": 5}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n\n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n\n first_min = float('inf')\n second_min = float('inf')\n\n for num in lst:\n if num < first_min:\n second_min = first_min\n first_min = num\n elif first_min < num < second_min:\n second_min = num\n\n if second_min == float('inf'):\n return None\n else:\n return second_min", "matching_cluster_idx": 5}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n\n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n\n first_smallest, second_smallest = float('inf'), float('inf')\n\n for num in lst:\n if num < first_smallest:\n second_smallest = first_smallest\n first_smallest = num\n elif first_smallest < num < second_smallest:\n second_smallest = num\n\n return second_smallest if second_smallest != float('inf') else None", "matching_cluster_idx": 5}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n\n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n\n first, second = float('inf'), float('inf')\n for num in lst:\n if num < first:\n first, second = num, first\n elif first < num < second:\n second = num\n\n return second if second != float('inf') else None", "matching_cluster_idx": 5}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n\n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n\n first, second = float('inf'), float('inf')\n\n for num in lst:\n if num < first:\n first, second = num, first\n elif first < num < second:\n second = num\n\n return second if second != float('inf') else None", "matching_cluster_idx": 5}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n\n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n\n if len(lst) < 2:\n return None\n\n # Remove duplicates and sort the list\n unique_sorted_lst = sorted(set(lst))\n\n # Check if there are at least two unique elements\n if len(unique_sorted_lst) < 2:\n return None\n\n # Return the second smallest element\n return unique_sorted_lst[1]", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n\n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n\n first_min, second_min = float('inf'), float('inf')\n\n for num in lst:\n if num < first_min:\n second_min, first_min = first_min, num\n elif first_min < num < second_min:\n second_min = num\n\n return second_min if second_min != float('inf') else None", "matching_cluster_idx": 5}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n\n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n\n # Initialize the first and second smallest to infinity\n first_smallest = float('inf')\n second_smallest = float('inf')\n\n for num in lst:\n if num < first_smallest:\n second_smallest = first_smallest\n first_smallest = num\n elif num < second_smallest and num != first_smallest:\n second_smallest = num\n\n return second_smallest if second_smallest != float('inf') else None", "matching_cluster_idx": 5}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n\n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n\n first, second = float('inf'), float('inf')\n\n for num in lst:\n if num < first:\n first, second = num, first\n elif first < num < second:\n second = num\n\n return second if second != float('inf') else None", "matching_cluster_idx": 5}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n\n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n\n first, second = float('inf'), float('inf')\n for num in lst:\n if num < first:\n second = first\n first = num\n elif first < num < second:\n second = num\n\n return second if second != float('inf') else None", "matching_cluster_idx": 5}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n\n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n\n if len(lst) < 2:\n return None\n\n # Initialize the first and second smallest with very large values\n first_smallest = float('inf')\n second_smallest = float('inf')\n\n for num in lst:\n if num < first_smallest:\n second_smallest = first_smallest\n first_smallest = num\n elif first_smallest < num < second_smallest:\n second_smallest = num\n\n # If second_smallest remains inf, then there was no second smallest element\n return second_smallest if second_smallest != float('inf') else None", "matching_cluster_idx": 5}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n\n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n\n first, second = float('inf'), float('inf')\n for num in lst:\n if num < first:\n second = first\n first = num\n elif num < second and num != first:\n second = num\n\n return second if second != float('inf') else None", "matching_cluster_idx": 5}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n\n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n\n first, second = float('inf'), float('inf')\n for num in lst:\n if num < first:\n second = first\n first = num\n elif first < num < second:\n second = num\n\n return second if second != float('inf') else None", "matching_cluster_idx": 5}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n\n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n\n first, second = float('inf'), float('inf')\n\n for num in lst:\n if num < first:\n first, second = num, first\n elif first < num < second:\n second = num\n\n return second if second != float('inf') else None", "matching_cluster_idx": 5}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n\n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n\n # Initialize the first and second smallest to very large values\n first_smallest = float('inf')\n second_smallest = float('inf')\n\n for number in lst:\n if number < first_smallest:\n second_smallest = first_smallest\n first_smallest = number\n elif first_smallest < number < second_smallest:\n second_smallest = number\n\n return second_smallest if second_smallest != float('inf') else None", "matching_cluster_idx": 5}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n\n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n\n # Remove duplicates by converting the list to a set and back to a list\n unique_lst = list(set(lst))\n\n # Sort the list and get the second element (index 1)\n unique_lst.sort()\n return unique_lst[1] if len(unique_lst) > 1 else None", "matching_cluster_idx": 6}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n\n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n\n first_min, second_min = float('inf'), float('inf')\n\n for num in lst:\n if num < first_min:\n second_min, first_min = first_min, num\n elif first_min < num < second_min:\n second_min = num\n\n if second_min == float('inf'):\n return None\n\n return second_min", "matching_cluster_idx": 5}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n\n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n\n first_min = second_min = float('inf')\n\n for num in lst:\n if num < first_min:\n first_min, second_min = num, first_min\n elif num < second_min and num != first_min:\n second_min = num\n\n return second_min if second_min != float('inf') else None", "matching_cluster_idx": 5}, {"solution": "def next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n Write a function next_smallest() that returns the 2nd smallest element of the list.\n Return None if there is no such element.\n\n next_smallest([1, 2, 3, 4, 5]) == 2\n next_smallest([5, 1, 4, 3, 2]) == 2\n next_smallest([]) == None\n next_smallest([1, 1]) == None\n \"\"\"\n if len(lst) < 2:\n return None\n\n # Remove duplicates and sort the list\n unique_sorted_lst = sorted(set(lst))\n\n # Check if there is at least a 2nd smallest element\n if len(unique_sorted_lst) < 2:\n return None\n\n # Return the 2nd smallest element\n return unique_sorted_lst[1]", "matching_cluster_idx": 6}]}, "HumanEval/113": {"dps": 99.10750507099392, "dps_norm": 69.16666666666667, "pass@1": 100.0, "profiled": [{"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n result = []\n for s in lst:\n count_odds = sum(1 for digit in s if int(digit) % 2 != 0)\n formatted_str = f\"the number of odd elements {count_odds}n the str{count_odds}ng {count_odds} of the {count_odds}nput.\"\n result.append(formatted_str)\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n result = []\n\n for s in lst:\n count_odd = sum(1 for digit in s if int(digit) % 2 != 0)\n result_string = \"the number of odd elements {}n the str{}ng {} of the {}nput.\".format(\n count_odd, count_odd, count_odd, count_odd)\n result.append(result_string)\n\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n result = []\n for s in lst:\n odd_count = sum(1 for c in s if c in '13579')\n result_str = \"the number of odd elements {}n the str{}ng {} of the {}nput.\".format(\n odd_count, odd_count, odd_count, odd_count\n )\n result.append(result_str)\n return result", "matching_cluster_idx": 4}, {"solution": "def odd_count(lst):\n def count_odds(s):\n return sum(1 for ch in s if int(ch) % 2 != 0)\n\n result = []\n for s in lst:\n num_odds = count_odds(s)\n result.append(f\"the number of odd elements {num_odds}n the str{num_odds}ng {num_odds} of the {num_odds}nput.\")\n\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n result = []\n for string in lst:\n odd_count = sum(1 for char in string if char in '13579')\n template = \"the number of odd elements {}n the str{}ng {} of the {}nput.\"\n formatted_string = template.format(odd_count, odd_count, odd_count, odd_count)\n result.append(formatted_string)\n return result", "matching_cluster_idx": 4}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n result = []\n for string in lst:\n odd_count = sum(1 for char in string if int(char) % 2 != 0)\n formatted_string = \"the number of odd elements {}n the str{}ng {} of the {}nput.\".format(odd_count, odd_count, odd_count, odd_count)\n result.append(formatted_string)\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n result = []\n for s in lst:\n odd_count = sum(1 for digit in s if int(digit) % 2 != 0)\n formatted_str = f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\"\n result.append(formatted_str)\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n def count_odd_digits(s):\n return sum(1 for char in s if char in '13579')\n\n results = []\n for i, string in enumerate(lst):\n odd_count_str = str(count_odd_digits(string))\n result = f\"the number of odd elements {odd_count_str}n the str{odd_count_str}ng {odd_count_str} of the {odd_count_str}nput.\"\n results.append(result)\n\n return results", "matching_cluster_idx": 4}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n def count_odd_digits(s):\n \"\"\"Helper function to count odd digits in a string.\"\"\"\n return sum(1 for char in s if int(char) % 2 != 0)\n\n result = []\n for s in lst:\n num_odds = count_odd_digits(s)\n result.append(f\"the number of odd elements {num_odds}n the str{num_odds}ng {num_odds} of the {num_odds}nput.\")\n\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n result = []\n for string in lst:\n odd_digits_count = sum(1 for digit in string if int(digit) % 2 != 0)\n template = \"the number of odd elements {}n the str{}ng {} of the {}nput.\".format(odd_digits_count, odd_digits_count, odd_digits_count, odd_digits_count)\n result.append(template)\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n\n def count_odd_digits(s):\n return sum(1 for c in s if int(c) % 2 != 0)\n\n result = []\n for s in lst:\n odd_count = count_odd_digits(s)\n result.append(f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\")\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n def count_odds(s):\n return sum(1 for char in s if int(char) % 2 != 0)\n\n result = []\n for s in lst:\n num_odds = count_odds(s)\n template = \"the number of odd elements {}n the str{}ng {} of the {}nput.\"\n formatted_str = template.format(num_odds, num_odds, num_odds, num_odds)\n result.append(formatted_str)\n\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n result = []\n for string in lst:\n odd_count = sum(1 for char in string if int(char) % 2 != 0)\n formatted_string = (\n f\"the number of odd elements {odd_count}n the str{odd_count}ng \"\n f\"{odd_count} of the {odd_count}nput.\"\n )\n result.append(formatted_string)\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n\n result = []\n for string in lst:\n odd_count = sum(1 for digit in string if int(digit) % 2 != 0)\n formatted_string = \"the number of odd elements {}n the str{}ng {} of the {}nput.\".format(\n odd_count, odd_count, odd_count, odd_count)\n result.append(formatted_string)\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n result = []\n for string in lst:\n count_odds = sum(1 for char in string if int(char) % 2 != 0)\n template = f\"the number of odd elements {count_odds}n the str{count_odds}ng {count_odds} of the {count_odds}nput.\"\n result.append(template)\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n result = []\n for s in lst:\n odd_count = sum(1 for char in s if int(char) % 2 != 0)\n template = f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\"\n result.append(template)\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n result = []\n for s in lst:\n odd_count = sum(1 for digit in s if int(digit) % 2 != 0)\n output_str = (f\"the number of odd elements {odd_count}n the str{odd_count}ng \"\n f\"{odd_count} of the {odd_count}nput.\")\n result.append(output_str)\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n\n def count_odds(s):\n return sum(1 for d in s if int(d) % 2 != 0)\n\n result = []\n for s in lst:\n odd_count = count_odds(s)\n formatted_str = f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\"\n result.append(formatted_str)\n\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n\n # Helper function to count odd digits in a string\n def count_odds(s):\n return sum(int(char) % 2 != 0 for char in s)\n\n # Process each string in the list\n result = []\n for s in lst:\n odd_count = count_odds(s)\n template = f\"the number of odd elements {odd_count}n the str{odd_count}ng {odd_count} of the {odd_count}nput.\"\n result.append(template)\n\n return result", "matching_cluster_idx": 3}, {"solution": "def odd_count(lst):\n \"\"\"Given a list of strings, where each string consists of only digits, return a list.\n Each element i of the output should be \"the number of odd elements in the\n string i of the input.\" where all the i's should be replaced by the number\n of odd digits in the i'th string of the input.\n\n >>> odd_count(['1234567'])\n [\"the number of odd elements 4n the str4ng 4 of the 4nput.\"]\n >>> odd_count(['3',\"11111111\"])\n [\"the number of odd elements 1n the str1ng 1 of the 1nput.\",\n \"the number of odd elements 8n the str8ng 8 of the 8nput.\"]\n \"\"\"\n result = []\n for s in lst:\n count_odd = sum(1 for digit in s if int(digit) % 2 != 0)\n output_str = f\"the number of odd elements {count_odd}n the str{count_odd}ng {count_odd} of the {count_odd}nput.\"\n result.append(output_str)\n return result", "matching_cluster_idx": 3}]}, "HumanEval/119": {"dps": 90.34883720930233, "dps_norm": 94.0, "pass@1": 79.0, "profiled": [{"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n\n def is_balanced(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n elif char == ')':\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n # Concatenate in both possible orders\n concat1 = lst[0] + lst[1]\n concat2 = lst[1] + lst[0]\n\n return 'Yes' if is_balanced(concat1) or is_balanced(concat2) else 'No'", "matching_cluster_idx": 4}, {"solution": "def is_good_string(s: str) -> bool:\n '''\n Helper function to check if a string of parentheses is balanced.\n '''\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n elif char == ')':\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\ndef match_parens(lst: list) -> str:\n '''\n Function to check if concatenating two strings from the list in some order can form a good string.\n '''\n # Check all possible concatenations\n for order in [(lst[0] + lst[1], lst[1] + lst[0])]:\n if is_good_string(order[0]) or is_good_string(order[1]):\n return 'Yes'\n return 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n def is_good(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n else:\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n # Check both possible concatenations\n return 'Yes' if is_good(lst[0] + lst[1]) or is_good(lst[1] + lst[0]) else 'No'", "matching_cluster_idx": 4}, {"solution": "def is_good(s):\n '''\n Helper function to check if a string is balanced.\n '''\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n elif char == ')':\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\ndef match_parens(lst):\n '''\n Given a list of two strings, checks if concatenating them in any order\n results in a balanced string.\n '''\n s1, s2 = lst\n # Check both possible concatenations\n if is_good(s1 + s2) or is_good(s2 + s1):\n return 'Yes'\n else:\n return 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n\n def is_balanced(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n elif char == ')':\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n def can_form_good_string(s1, s2):\n # Check if concatenating in both orders can result in a balanced string\n return is_balanced(s1 + s2) or is_balanced(s2 + s1)\n\n return 'Yes' if can_form_good_string(lst[0], lst[1]) else 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n def is_good(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n elif char == ')':\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n for perm in [lst[0] + lst[1], lst[1] + lst[0]]:\n if is_good(perm):\n return 'Yes'\n return 'No'", "matching_cluster_idx": 4}, {"solution": "def is_balanced(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n elif char == ')':\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\ndef match_parens(lst):\n # Generate all possible concatenations of the two strings in lst\n for s1, s2 in [(lst[0], lst[1]), (lst[1], lst[0])]:\n if is_balanced(s1 + s2):\n return 'Yes'\n return 'No'", "matching_cluster_idx": 4}, {"solution": "def is_balanced(s):\n balance = 0\n for c in s:\n if c == '(':\n balance += 1\n elif c == ')':\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\ndef match_parens(lst):\n s1, s2 = lst\n return 'Yes' if (is_balanced(s1 + s2) or is_balanced(s2 + s1)) else 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n def is_good(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n elif char == ')':\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n s1, s2 = lst\n return 'Yes' if is_good(s1 + s2) or is_good(s2 + s1) else 'No'", "matching_cluster_idx": 4}, {"solution": "def is_good_string(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n elif char == ')':\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\ndef match_parens(lst):\n # Generate all possible concatenations\n concatenations = [''.join(lst[0] + lst[1]), ''.join(lst[1] + lst[0])]\n\n # Check if any of the concatenations form a good string\n for s in concatenations:\n if is_good_string(s):\n return 'Yes'\n\n return 'No'", "matching_cluster_idx": -1}, {"solution": "def is_balanced(s: str) -> bool:\n '''Helper function to check if the given string is balanced'''\n stack = []\n for char in s:\n if char == '(':\n stack.append(char)\n elif char == ')':\n if not stack:\n return False\n stack.pop()\n return not stack\ndef match_parens(lst: list[str]) -> str:\n '''\n Check if it is possible to concatenate the two strings in some order\n to get a balanced string.\n '''\n str1, str2 = lst\n\n # Check if concatenating str1 + str2 results in a balanced string\n if is_balanced(str1 + str2):\n return 'Yes'\n\n # Check if concatenating str2 + str1 results in a balanced string\n if is_balanced(str2 + str1):\n return 'Yes'\n\n return 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n\n def is_good_string(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n elif char == ')':\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n def can_be_good_concat(s1, s2):\n if is_good_string(s1 + s2):\n return 'Yes'\n if is_good_string(s2 + s1):\n return 'Yes'\n return 'No'\n\n return can_be_good_concat(lst[0], lst[1])", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n def is_balanced(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n elif char == ')':\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n # Generate all possible concatenations of the two strings\n possible_strings = [''.join(lst) for lst in [lst, lst[::-1]]]\n\n # Check if any of the possible concatenations is balanced\n return 'Yes' if any(is_balanced(s) for s in possible_strings) else 'No'", "matching_cluster_idx": 3}, {"solution": "def match_parens(lst):\n def is_balanced(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n elif char == ')':\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n # Try concatenating the strings in both possible orders\n concatenated_1 = lst[0] + lst[1]\n concatenated_2 = lst[1] + lst[0]\n\n return 'Yes' if is_balanced(concatenated_1) or is_balanced(concatenated_2) else 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n def is_balanced(s):\n stack = []\n for char in s:\n if char == '(':\n stack.append(char)\n elif char == ')':\n if not stack:\n return False\n stack.pop()\n return not stack\n\n s1, s2 = lst\n return 'Yes' if is_balanced(s1 + s2) or is_balanced(s2 + s1) else 'No'", "matching_cluster_idx": 4}, {"solution": "def is_good(s):\n '''\n Helper function to check if a single string is balanced.\n '''\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n else:\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\ndef match_parens(lst):\n '''\n Checks if it is possible to concatenate the two strings in some order\n to produce a good string.\n '''\n s1, s2 = lst\n return 'Yes' if is_good(s1 + s2) or is_good(s2 + s1) else 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n def is_balanced(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n elif char == ')':\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n # Check if concatenating the strings in both possible orders results in a balanced string\n return 'Yes' if is_balanced(lst[0] + lst[1]) or is_balanced(lst[1] + lst[0]) else 'No'", "matching_cluster_idx": 4}, {"solution": "def is_balanced(s: str) -> bool:\n \"\"\" Helper function to check if a single string is balanced \"\"\"\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n else: # char == ')'\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\ndef match_parens(lst: list) -> str:\n \"\"\"\n Check if it is possible to concatenate two strings in some order to make a good string.\n A string S is considered good if all parentheses in S are balanced.\n \"\"\"\n s1, s2 = lst\n # Check if both individual strings are balanced\n if is_balanced(s1 + s2):\n return 'Yes'\n if is_balanced(s2 + s1):\n return 'Yes'\n return 'No'", "matching_cluster_idx": 4}, {"solution": "def is_balanced(s):\n '''\n Check if a given string of parentheses is balanced.\n '''\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n elif char == ')':\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\ndef match_parens(lst):\n '''\n Check if it is possible to concatenate the two strings in some order\n to form a good string where all parentheses are balanced.\n '''\n # Concatenate the strings in both possible orders\n order1 = lst[0] + lst[1]\n order2 = lst[1] + lst[0]\n\n # Check if either order produces a balanced string\n return 'Yes' if is_balanced(order1) or is_balanced(order2) else 'No'", "matching_cluster_idx": 4}, {"solution": "def match_parens(lst):\n '''\n You are given a list of two strings, both strings consist of open\n parentheses '(' or close parentheses ')' only.\n Your job is to check if it is possible to concatenate the two strings in\n some order, that the resulting string will be good.\n A string S is considered to be good if and only if all parentheses in S\n are balanced. For example: the string '(())()' is good, while the string\n '())' is not.\n Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n\n Examples:\n match_parens(['()(', ')']) == 'Yes'\n match_parens([')', ')']) == 'No'\n '''\n\n def is_balanced(s):\n balance = 0\n for char in s:\n if char == '(':\n balance += 1\n elif char == ')':\n balance -= 1\n if balance < 0:\n return False\n return balance == 0\n\n s1, s2 = lst\n\n # Check if concatenating in either order can balance the parentheses\n return 'Yes' if (is_balanced(s1 + s2) or is_balanced(s2 + s1)) else 'No'", "matching_cluster_idx": 4}]}, "HumanEval/120": {"dps": null, "dps_norm": null, "pass@1": 2.0, "profiled": []}, "HumanEval/121": {"dps": 88.69955156950672, "dps_norm": 67.14285714285714, "pass@1": 64.0, "profiled": [{"solution": "def solution(lst):\n \"\"\"\n Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n\n Examples:\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n # Initialize sum to 0\n total_sum = 0\n\n # Iterate over the list with index\n for i in range(len(lst)):\n # Check if the index is even and the element is odd\n if i % 2 == 0 and lst[i] % 2 != 0:\n # Add the element to the sum\n total_sum += lst[i]\n\n # Return the total sum\n return total_sum", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n \"\"\"\n Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n\n Examples:\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n sum_odd_even_positions = 0\n for i in range(0, len(lst), 2): # Iterate over even indices (0, 2, 4, ...)\n if lst[i] % 2 != 0: # Check if the element is odd\n sum_odd_even_positions += lst[i]\n return sum_odd_even_positions", "matching_cluster_idx": 4}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n\n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==>0\n \"\"\"\n # Initialize the sum to 0\n total_sum = 0\n\n # Iterate over the list with index\n for index in range(0, len(lst), 2):\n # Check if the element is odd\n if lst[index] % 2 != 0:\n # Add to the total sum\n total_sum += lst[index]\n\n return total_sum", "matching_cluster_idx": 4}, {"solution": "def solution(lst):\n \"\"\"\n Given a non-empty list of integers, return the sum of all of the odd elements\n that are in even positions.\n\n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==>0\n \"\"\"\n return sum(lst[i] for i in range(0, len(lst), 2) if lst[i] % 2 != 0)", "matching_cluster_idx": 4}, {"solution": "def solution(lst):\n \"\"\"\n Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n\n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n # Initialize sum to 0\n total_sum = 0\n\n # Iterate through the list with index\n for index in range(0, len(lst), 2):\n if lst[index] % 2 != 0:\n total_sum += lst[index]\n\n return total_sum", "matching_cluster_idx": 4}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n\n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==>0\n \"\"\"\n return sum(lst[i] for i in range(0, len(lst), 2) if lst[i] % 2 != 0)", "matching_cluster_idx": 4}, {"solution": "def solution(lst):\n \"\"\"\n Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n\n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n # Filter the list to retain elements at even positions (0-based index) and check if they are odd\n even_position_odds = [num for index, num in enumerate(lst) if index % 2 == 0 and num % 2 != 0]\n # Calculate the sum of the filtered elements\n return sum(even_position_odds)", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n\n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n return sum(lst[i] for i in range(0, len(lst), 2) if lst[i] % 2 != 0)", "matching_cluster_idx": 4}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n\n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n return sum(x for i, x in enumerate(lst) if i % 2 == 0 and x % 2 != 0)", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n\n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n # Initialize sum to 0\n total_sum = 0\n\n # Iterate over the list with index\n for index in range(len(lst)):\n # Check if the index is even and the element is odd\n if index % 2 == 0 and lst[index] % 2 != 0:\n # Add the element to the total sum\n total_sum += lst[index]\n\n # Return the total sum\n return total_sum", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n\n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n total_sum = 0\n for i in range(0, len(lst), 2): # iterate over even indices\n if lst[i] % 2 != 0: # check if element at even index is odd\n total_sum += lst[i]\n return total_sum", "matching_cluster_idx": 4}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n\n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n # Sum of odd elements in even positions\n return sum(lst[i] for i in range(0, len(lst), 2) if lst[i] % 2 != 0)", "matching_cluster_idx": 4}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n\n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n # Initialize the sum of odd elements at even positions\n sum_odd_even_positions = 0\n\n # Iterate through the list with index\n for index in range(0, len(lst), 2):\n # Check if the element is odd\n if lst[index] % 2 != 0:\n sum_odd_even_positions += lst[index]\n\n return sum_odd_even_positions", "matching_cluster_idx": 4}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n\n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==>0\n \"\"\"\n # Initialize a variable to hold the sum of odd elements in even positions\n sum_odd_even_positions = 0\n\n # Iterate over the list with index\n for index, value in enumerate(lst):\n # Check if the index is even and the value is odd\n if index % 2 == 0 and value % 2 != 0:\n sum_odd_even_positions += value\n\n return sum_odd_even_positions", "matching_cluster_idx": 3}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n\n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==>0\n \"\"\"\n return sum(lst[i] for i in range(0, len(lst), 2) if lst[i] % 2 != 0)", "matching_cluster_idx": 4}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n\n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n # Initialize sum\n result = 0\n\n # Iterate over the list, checking elements at even positions (0-based index)\n for i in range(0, len(lst), 2):\n # Check if the element is odd and in an even position\n if lst[i] % 2 != 0:\n result += lst[i]\n\n return result", "matching_cluster_idx": 4}, {"solution": "def solution(lst):\n \"\"\"\n Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n\n Examples:\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n sum_odd_even_positions = 0\n for i in range(0, len(lst), 2): # Iterate through even indices\n if lst[i] % 2 != 0: # Check if the number is odd\n sum_odd_even_positions += lst[i]\n return sum_odd_even_positions", "matching_cluster_idx": 4}, {"solution": "def solution(lst):\n \"\"\"\n Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n\n Examples:\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==>0\n \"\"\"\n return sum(lst[i] for i in range(0, len(lst), 2) if lst[i] % 2 != 0)", "matching_cluster_idx": 4}, {"solution": "def solution(lst):\n \"\"\"\n Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n\n Examples\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==>0\n \"\"\"\n # Initialize sum to 0\n total_sum = 0\n\n # Iterate through the list with index\n for index in range(0, len(lst), 2):\n # Check if the element at the even index is odd\n if lst[index] % 2 != 0:\n total_sum += lst[index]\n\n return total_sum", "matching_cluster_idx": 4}, {"solution": "def solution(lst):\n \"\"\"Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n\n Examples:\n solution([5, 8, 7, 1]) ==> 12\n solution([3, 3, 3, 3, 3]) ==> 9\n solution([30, 13, 24, 321]) ==> 0\n \"\"\"\n # Initialize sum to 0\n total = 0\n\n # Iterate through the list with index\n for index, value in enumerate(lst):\n # Check if the index is even and the value is odd\n if index % 2 == 0 and value % 2 != 0:\n total += value\n\n return total", "matching_cluster_idx": 3}]}, "HumanEval/149": {"dps": 85.82677165354332, "dps_norm": 57.142857142857146, "pass@1": 100.0, "profiled": [{"solution": "def sorted_list_sum(lst):\n \"\"\"\n Accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order.\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n \"\"\"\n # Remove strings with odd lengths\n filtered_lst = [s for s in lst if len(s) % 2 == 0]\n\n # Sort the list first by length, then alphabetically\n sorted_lst = sorted(filtered_lst, key=lambda s: (len(s), s))\n\n return sorted_lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"\n Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order.\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n You may assume that all words will have the same length.\n For example:\n assert list_sort([\"aa\", \"a\", \"aaa\"]) => [\"aa\"]\n assert list_sort([\"ab\", \"a\", \"aaa\", \"cd\"]) => [\"ab\", \"cd\"]\n \"\"\"\n # Filter out strings with odd lengths\n filtered_lst = [s for s in lst if len(s) % 2 == 0]\n\n # Sort the filtered list first by length, then alphabetically\n sorted_lst = sorted(filtered_lst, key=lambda s: (len(s), s))\n\n return sorted_lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"\n Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order.\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n You may assume that all words will have the same length.\n\n For example:\n assert sorted_list_sum([\"aa\", \"a\", \"aaa\"]) == [\"aa\"]\n assert sorted_list_sum([\"ab\", \"a\", \"aaa\", \"cd\"]) == [\"ab\", \"cd\"]\n \"\"\"\n\n # Filter out strings with odd lengths\n filtered_lst = [s for s in lst if len(s) % 2 == 0]\n\n # Sort the list first by length, then alphabetically\n sorted_lst = sorted(filtered_lst, key=lambda s: (len(s), s))\n\n return sorted_lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order,\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n You may assume that all words will have the same length.\n For example:\n assert list_sort([\"aa\", \"a\", \"aaa\"]) => [\"aa\"]\n assert list_sort([\"ab\", \"a\", \"aaa\", \"cd\"]) => [\"ab\", \"cd\"]\n \"\"\"\n # Filter out strings with odd lengths\n filtered_lst = [s for s in lst if len(s) % 2 == 0]\n\n # Sort the list first by length, then alphabetically\n sorted_lst = sorted(filtered_lst, key=lambda x: (len(x), x))\n\n return sorted_lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order.\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n \"\"\"\n # Filter out strings with odd lengths\n filtered_list = [word for word in lst if len(word) % 2 == 0]\n\n # Sort the list by length of the words (primary sort key) and lexicographically (secondary sort key)\n sorted_list = sorted(filtered_list, key=lambda x: (len(x), x))\n\n return sorted_list", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"\n Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order.\n\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n\n For example:\n assert sorted_list_sum([\"aa\", \"a\", \"aaa\"]) == [\"aa\"]\n assert sorted_list_sum([\"ab\", \"a\", \"aaa\", \"cd\"]) == [\"ab\", \"cd\"]\n \"\"\"\n # Filter out strings with odd lengths\n filtered_list = [word for word in lst if len(word) % 2 == 0]\n\n # Sort the filtered list first by length, then alphabetically for words of the same length\n sorted_list = sorted(filtered_list, key=lambda word: (len(word), word))\n\n return sorted_list", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"\n Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order.\n\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n\n If two words have the same length, sort the list alphabetically.\n\n The function should return a list of strings in sorted order.\n\n You may assume that all words will have the same length.\n\n For example:\n assert sorted_list_sum([\"aa\", \"a\", \"aaa\"]) => [\"aa\"]\n assert sorted_list_sum([\"ab\", \"a\", \"aaa\", \"cd\"]) => [\"ab\", \"cd\"]\n \"\"\"\n # Filter out strings with odd lengths\n filtered_lst = [s for s in lst if len(s) % 2 == 0]\n\n # Sort the filtered list by length and then alphabetically\n sorted_lst = sorted(filtered_lst, key=lambda s: (len(s), s))\n\n return sorted_lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"\n Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n You may assume that all words will have the same length.\n For example:\n assert sorted_list_sum([\"aa\", \"a\", \"aaa\"]) == [\"aa\"]\n assert sorted_list_sum([\"ab\", \"a\", \"aaa\", \"cd\"]) == [\"ab\", \"cd\"]\n \"\"\"\n\n # Filter out strings with odd lengths\n filtered_lst = [s for s in lst if len(s) % 2 == 0]\n\n # Sort first by length, then alphabetically\n sorted_lst = sorted(filtered_lst, key=lambda s: (len(s), s))\n\n return sorted_lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order,\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n You may assume that all words will have the same length.\n For example:\n assert list_sort([\"aa\", \"a\", \"aaa\"]) => [\"aa\"]\n assert list_sort([\"ab\", \"a\", \"aaa\", \"cd\"]) => [\"ab\", \"cd\"]\n \"\"\"\n # Filter out strings with odd lengths\n filtered_list = [s for s in lst if len(s) % 2 == 0]\n\n # Sort by length first, then alphabetically for same lengths\n sorted_list = sorted(filtered_list, key=lambda x: (len(x), x))\n\n return sorted_list", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order,\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n You may assume that all words will have the same length.\n For example:\n assert sorted_list_sum([\"aa\", \"a\", \"aaa\"]) == [\"aa\"]\n assert sorted_list_sum([\"ab\", \"a\", \"aaa\", \"cd\"]) == [\"ab\", \"cd\"]\n \"\"\"\n\n # Filter out strings with odd lengths\n filtered_list = [s for s in lst if len(s) % 2 == 0]\n\n # Sort the filtered list by length and alphabetically for same length\n sorted_list = sorted(filtered_list, key=lambda s: (len(s), s))\n\n return sorted_list", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order.\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n You may assume that all words will have the same length.\n For example:\n assert sorted_list_sum([\"aa\", \"a\", \"aaa\"]) == [\"aa\"]\n assert sorted_list_sum([\"ab\", \"a\", \"aaa\", \"cd\"]) == [\"ab\", \"cd\"]\n \"\"\"\n # Filter out strings with odd lengths\n filtered_list = [s for s in lst if len(s) % 2 == 0]\n\n # Sort the filtered list by length first, then alphabetically\n sorted_list = sorted(filtered_list, key=lambda x: (len(x), x))\n\n return sorted_list", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"\n Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order,\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n You may assume that all words will have the same length.\n \"\"\"\n # Filter out strings with odd lengths\n filtered_lst = [s for s in lst if len(s) % 2 == 0]\n\n # Sort the list first by length of the strings and then alphabetically\n sorted_lst = sorted(filtered_lst, key=lambda x: (len(x), x))\n\n return sorted_lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"\n Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order.\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word,\n and if two words have the same length, sort the list alphabetically.\n\n Parameters:\n lst (list of str): List of strings to be processed.\n\n Returns:\n list of str: Sorted list of strings with even lengths.\n \"\"\"\n # Filter out strings with odd lengths\n even_length_strings = [s for s in lst if len(s) % 2 == 0]\n\n # Sort the list first by length, then alphabetically for ties\n sorted_list = sorted(even_length_strings, key=lambda s: (len(s), s))\n\n return sorted_list", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order,\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n You may assume that all words will have the same length.\n For example:\n assert sorted_list_sum([\"aa\", \"a\", \"aaa\"]) => [\"aa\"]\n assert sorted_list_sum([\"ab\", \"a\", \"aaa\", \"cd\"]) => [\"ab\", \"cd\"]\n \"\"\"\n # Filter out strings with odd lengths\n filtered_lst = [s for s in lst if len(s) % 2 == 0]\n\n # Sort the list first by length, then alphabetically\n sorted_lst = sorted(filtered_lst, key=lambda s: (len(s), s))\n\n return sorted_lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n # Filter out strings with odd lengths\n filtered_lst = [s for s in lst if len(s) % 2 == 0]\n\n # Sort the filtered list: first by length of strings, then alphabetically\n sorted_lst = sorted(filtered_lst, key=lambda s: (len(s), s))\n\n return sorted_lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"\n Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order.\n\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n\n You may assume that all words will have the same length.\n\n For example:\n assert sorted_list_sum([\"aa\", \"a\", \"aaa\"]) => [\"aa\"]\n assert sorted_list_sum([\"ab\", \"a\", \"aaa\", \"cd\"]) => [\"ab\", \"cd\"]\n \"\"\"\n # Filter out strings with odd lengths\n filtered_lst = [s for s in lst if len(s) % 2 == 0]\n\n # Sort the list by length and then alphabetically for ties\n sorted_lst = sorted(filtered_lst, key=lambda x: (len(x), x))\n\n return sorted_lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"\n Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order.\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n \"\"\"\n # Filter out strings with odd lengths\n filtered_list = [s for s in lst if len(s) % 2 == 0]\n\n # Sort the list first by length, then alphabetically\n sorted_list = sorted(filtered_list, key=lambda x: (len(x), x))\n\n return sorted_list", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n # Filter out strings with odd lengths\n filtered_lst = [word for word in lst if len(word) % 2 == 0]\n\n # Sort the filtered list first by length, then alphabetically\n sorted_lst = sorted(filtered_lst, key=lambda word: (len(word), word))\n\n return sorted_lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"\n Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order,\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n The function should return a list of strings in sorted order.\n \"\"\"\n\n # Filter out strings with odd lengths\n filtered_lst = [s for s in lst if len(s) % 2 == 0]\n\n # Sort the list first by length and then alphabetically\n sorted_lst = sorted(filtered_lst, key=lambda x: (len(x), x))\n\n return sorted_lst", "matching_cluster_idx": 3}, {"solution": "def sorted_list_sum(lst):\n \"\"\"\n Write a function that accepts a list of strings as a parameter,\n deletes the strings that have odd lengths from it,\n and returns the resulted list with a sorted order.\n\n The list is always a list of strings and never an array of numbers,\n and it may contain duplicates.\n The order of the list should be ascending by length of each word, and you\n should return the list sorted by that rule.\n If two words have the same length, sort the list alphabetically.\n\n The function should return a list of strings in sorted order.\n\n Examples:\n assert sorted_list_sum([\"aa\", \"a\", \"aaa\"]) == [\"aa\"]\n assert sorted_list_sum([\"ab\", \"a\", \"aaa\", \"cd\"]) == [\"ab\", \"cd\"]\n \"\"\"\n # Filter out strings with odd lengths\n filtered_lst = [s for s in lst if len(s) % 2 == 0]\n\n # Sort the list first by length, then alphabetically\n sorted_lst = sorted(filtered_lst, key=lambda s: (len(s), s))\n\n return sorted_lst", "matching_cluster_idx": 3}]}, "Mbpp/3": {"dps": 97.79661016949153, "dps_norm": 98.75, "pass@1": 100.0, "profiled": [{"solution": "def is_not_prime(n):\n \"\"\"\n Function to identify non-prime numbers.\n\n Parameters:\n n (int): An integer to check if it is a prime number or not.\n\n Returns:\n bool: True if the number is not a prime number, False otherwise.\n \"\"\"\n if n <= 1:\n return True\n if n == 2:\n return False\n if n % 2 == 0:\n return True\n\n for i in range(3, int(n**0.5) + 1, 2):\n if n % i == 0:\n return True\n\n return False", "matching_cluster_idx": 7}, {"solution": "def is_prime(n):\n if n <= 1:\n return False\n if n == 2:\n return True\n if n % 2 == 0:\n return False\n max_divisor = int(n**0.5) + 1\n for d in range(3, max_divisor, 2):\n if n % d == 0:\n return False\n return True\ndef is_not_prime(n):\n return not is_prime(n)", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n \"\"\"\n Check if a number is not a prime number.\n\n Args:\n n (int): The number to check.\n\n Returns:\n bool: True if n is not a prime number, False otherwise.\n \"\"\"\n if n <= 1:\n return True\n if n == 2:\n return False\n if n % 2 == 0:\n return True\n for i in range(3, int(n**0.5) + 1, 2):\n if n % i == 0:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n \"\"\"\n Check if a given number is not a prime number.\n\n Args:\n n (int): The number to check.\n\n Returns:\n bool: True if n is not a prime number, False otherwise.\n \"\"\"\n if n <= 1:\n return True\n elif n == 2:\n return False\n else:\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n return True\n return False", "matching_cluster_idx": 5}, {"solution": "def is_not_prime(n):\n \"\"\"\n Determine if the number is not a prime.\n\n :param n: Integer to check\n :return: Boolean - True if not prime, False if prime\n \"\"\"\n if n <= 1:\n return True # 0 and 1 are not prime numbers\n if n == 2:\n return False # 2 is a prime number\n if n % 2 == 0:\n return True # even numbers greater than 2 are not prime\n\n # Check for factors from 3 to sqrt(n)\n for i in range(3, int(n**0.5) + 1, 2):\n if n % i == 0:\n return True\n\n return False", "matching_cluster_idx": 7}, {"solution": "def is_prime(n):\n \"\"\"Check if a number is prime.\"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True\ndef is_not_prime(n):\n \"\"\"Check if a number is not prime.\"\"\"\n return not is_prime(n)", "matching_cluster_idx": 7}, {"solution": "def is_prime(n):\n \"\"\" Helper function to determine if a number is prime. \"\"\"\n if n <= 1:\n return False\n if n == 2:\n return True\n if n % 2 == 0:\n return False\n for i in range(3, int(n**0.5) + 1, 2):\n if n % i == 0:\n return False\n return True\ndef is_not_prime(n):\n \"\"\" Function to determine if a number is not prime. \"\"\"\n return not is_prime(n)", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n \"\"\"\n Check if the given number is not a prime number.\n\n Parameters:\n n (int): Number to be checked.\n\n Returns:\n bool: True if n is not a prime number, False otherwise.\n \"\"\"\n if n <= 1:\n return True\n if n == 2:\n return False\n if n % 2 == 0:\n return True\n\n for i in range(3, int(n**0.5) + 1, 2):\n if n % i == 0:\n return True\n\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n \"\"\"\n Check if a number is not a prime.\n\n Args:\n n (int): The number to check.\n\n Returns:\n bool: True if the number is not prime, False otherwise.\n \"\"\"\n if n <= 1:\n return True\n if n == 2:\n return False\n if n % 2 == 0:\n return True\n for i in range(3, int(n**0.5) + 1, 2):\n if n % i == 0:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(num):\n \"\"\"\n Function to determine if a number is not prime.\n\n Parameters:\n num (int): The number to be checked.\n\n Returns:\n bool: True if the number is not prime, False otherwise.\n \"\"\"\n if num <= 1:\n return True\n if num <= 3:\n return False\n if num % 2 == 0 or num % 3 == 0:\n return True\n i = 5\n while i * i <= num:\n if num % i == 0 or num % (i + 2) == 0:\n return True\n i += 6\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n \"\"\"Check if a number is not a prime number.\"\"\"\n if n <= 1:\n return True\n if n <= 3:\n return False\n if n % 2 == 0 or n % 3 == 0:\n return True\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return True\n i += 6\n return False", "matching_cluster_idx": 7}, {"solution": "def is_prime(n):\n \"\"\"Check if a number is prime.\"\"\"\n if n <= 1:\n return False\n if n == 2:\n return True\n if n % 2 == 0:\n return False\n for i in range(3, int(n**0.5) + 1, 2):\n if n % i == 0:\n return False\n return True\ndef is_not_prime(n):\n \"\"\"Check if a number is not prime.\"\"\"\n return not is_prime(n)", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n \"\"\"\n Check if a number is not a prime number.\n\n :param n: Integer to be checked.\n :return: True if the number is not prime, False otherwise.\n \"\"\"\n if n <= 1:\n return True\n if n <= 3:\n return False\n if n % 2 == 0 or n % 3 == 0:\n return True\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return True\n i += 6\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n \"\"\"\n Check if a number is not prime.\n\n Parameters:\n n (int): The number to check.\n\n Returns:\n bool: True if the number is not prime, False otherwise.\n \"\"\"\n if n <= 1:\n return True # 0 and 1 are not prime numbers\n if n == 2:\n return False # 2 is a prime number\n if n % 2 == 0:\n return True # even numbers greater than 2 are not prime\n max_divisor = int(n**0.5) + 1\n for i in range(3, max_divisor, 2):\n if n % i == 0:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n \"\"\"\n Determine if a number is not prime.\n\n Parameters:\n n (int): The number to check.\n\n Returns:\n bool: True if n is not a prime number, False otherwise.\n \"\"\"\n if n <= 1:\n return True\n if n <= 3:\n return False\n if n % 2 == 0 or n % 3 == 0:\n return True\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return True\n i += 6\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n \"\"\"\n Determine whether a number is non-prime.\n\n Args:\n n (int): The number to check.\n\n Returns:\n bool: True if n is not a prime number, False otherwise.\n \"\"\"\n if n <= 1:\n return True\n if n == 2:\n return False\n if n % 2 == 0:\n return True\n for i in range(3, int(n**0.5) + 1, 2):\n if n % i == 0:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n if n <= 1:\n return True\n elif n == 2:\n return False\n elif n % 2 == 0:\n return True\n else:\n for i in range(3, int(n**0.5) + 1, 2):\n if n % i == 0:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n \"\"\"\n This function checks if a number is not a prime number.\n\n Parameters:\n n (int): The number to check.\n\n Returns:\n bool: True if the number is not prime, False otherwise.\n \"\"\"\n if n <= 1:\n return True\n if n == 2:\n return False\n if n % 2 == 0:\n return True\n for i in range(3, int(n**0.5) + 1, 2):\n if n % i == 0:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def is_not_prime(n):\n \"\"\"\n Identify if a number is not a prime number.\n \"\"\"\n if n <= 1:\n return True\n if n <= 3:\n return False\n if n % 2 == 0 or n % 3 == 0:\n return True\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return True\n i += 6\n return False", "matching_cluster_idx": 7}, {"solution": "def is_prime(n):\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True\ndef is_not_prime(n):\n return not is_prime(n)", "matching_cluster_idx": 7}]}, "Mbpp/4": {"dps": 91.51877133105802, "dps_norm": 82.91666666666666, "pass@1": 64.0, "profiled": [{"solution": "import heapq\ndef heap_queue_largest(nums, n):\n # Create a min-heap (max heap in disguise by negating values)\n heap = [-x for x in nums]\n heapq.heapify(heap)\n\n # Extract the n largest elements\n largest_elements = [-heapq.heappop(heap) for _ in range(n)]\n\n # Sort the extracted elements to get them in descending order\n largest_elements.sort(reverse=True)\n\n return largest_elements\nnums = [25, 35, 22, 85, 14, 65, 75, 22, 58]\nn = 3", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n # Convert the list to a max heap (using negative values to simulate a max heap with heapq)\n max_heap = [-num for num in nums]\n heapq.heapify(max_heap)\n\n # Extract the n largest elements\n largest_elements = [-heapq.heappop(max_heap) for _ in range(n)]\n\n return largest_elements", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n # Convert the list to a max-heap using heapq with negative numbers to simulate max-heap\n max_heap = [-x for x in nums]\n heapq.heapify(max_heap)\n\n # Get the n largest elements from the heap\n largest_nums = []\n for _ in range(n):\n largest_nums.append(-heapq.heappop(max_heap))\n\n # Return the result in descending order\n return sorted(largest_nums, reverse=True)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(numbers, n):\n # Transform the list into a max-heap using heapq\n max_heap = [-num for num in numbers]\n heapq.heapify(max_heap)\n\n # Extract the n largest elements (smallest in the max-heap)\n largest_numbers = [-heapq.heappop(max_heap) for _ in range(n)]\n\n return largest_numbers", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(numbers, n):\n # Using heapq to get the n largest elements\n return heapq.nlargest(n, numbers)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n # Convert the list to a max heap\n heapq.heapify(nums)\n\n # Get the n largest elements\n n_largest = heapq.nlargest(n, nums)\n\n # Sort in descending order\n n_largest.sort(reverse=True)\n\n return n_largest", "matching_cluster_idx": 8}, {"solution": "def heap_queue_largest(nums, n):\n # Create a max heap (since Python's heapq is a min heap by default, we invert the numbers)\n import heapq\n max_heap = []\n\n for num in nums:\n heapq.heappush(max_heap, -num)\n\n # Get the n largest elements\n largest_n = []\n for _ in range(n):\n largest_n.append(-heapq.heappop(max_heap))\n\n # Sort the result in descending order\n largest_n.sort(reverse=True)\n\n return largest_n", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(numbers, n):\n \"\"\"\n Find the n largest integers from a given list of numbers, returned in descending order.\n \"\"\"\n # Convert numbers to a negative number to use a min heap for extracting the largest elements\n heap = [-num for num in numbers]\n heapq.heapify(heap)\n\n # Extract the n largest elements\n largest_elements = [-heapq.heappop(heap) for _ in range(n)]\n\n # Sort the largest elements in descending order\n return sorted(largest_elements, reverse=True)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n # Negate the numbers to create a max-heap using min-heap logic\n max_heap = [-num for num in nums]\n # Create a min-heap\n heapq.heapify(max_heap)\n\n # Extract the n largest numbers (which are negative in the max-heap)\n largest_numbers = []\n for _ in range(n):\n largest_numbers.append(-heapq.heappop(max_heap))\n\n # Return the result sorted in descending order\n return sorted(largest_numbers, reverse=True)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(numbers, n):\n # Use heapq to get the n largest elements\n largest_elements = heapq.nlargest(n, numbers)\n return largest_elements", "matching_cluster_idx": 9}, {"solution": "def heap_queue_largest(numbers, n):\n # Convert the list to a max heap\n import heapq\n max_heap = [-num for num in numbers]\n heapq.heapify(max_heap)\n\n # Extract the n largest numbers\n largest_numbers = []\n for _ in range(n):\n largest_numbers.append(-heapq.heappop(max_heap))\n\n # Return the list sorted in descending order\n return sorted(largest_numbers, reverse=True)", "matching_cluster_idx": 9}, {"solution": "def heap_queue_largest(nums, n):\n import heapq\n # Use a min-heap to store the n largest numbers\n heap = []\n\n for num in nums:\n if len(heap) < n:\n heapq.heappush(heap, num)\n elif num > heap[0]: # If current number is larger than the smallest in heap\n heapq.heapreplace(heap, num)\n\n # Convert the heap to a list in descending order\n return sorted(heap, reverse=True)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(numbers, n):\n # Transform the list to a max-heap (min-heap of negatives)\n max_heap = [-num for num in numbers]\n heapq.heapify(max_heap)\n\n # Extract the n largest elements\n largest_elements = []\n for _ in range(n):\n largest_elements.append(-heapq.heappop(max_heap))\n\n # Return in descending order\n return sorted(largest_elements, reverse=True)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n # Use a min-heap to store the n largest elements\n largest = []\n\n for num in nums:\n if len(largest) < n:\n heapq.heappush(largest, num)\n else:\n heapq.heappushpop(largest, num)\n\n # The heap is sorted in ascending order, so we need to reverse it\n return sorted(largest, reverse=True)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(numbers, n):\n # Use a max-heap (heap queue in Python) to keep track of the n largest elements\n max_heap = []\n\n for num in numbers:\n if len(max_heap) < n:\n heapq.heappush(max_heap, num)\n else:\n # If max_heap already has n elements, only push the element if it's larger than the smallest in max_heap\n if num > max_heap[0]:\n heapq.heapreplace(max_heap, num)\n\n # heapq.nsmallest(n, max_heap, reverse=True) will give the n largest elements in descending order\n return heapq.nlargest(n, max_heap)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n # Create a min-heap (default in Python) from the list of numbers\n heap = nums[:n]\n heapq.heapify(heap)\n\n # Iterate over the remaining elements\n for num in nums[n:]:\n if num > heap[0]:\n # If the current number is larger than the smallest in the heap\n heapq.heappushpop(heap, num)\n\n # Convert the heap to a sorted list in descending order\n return sorted(heap, reverse=True)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n # Create a max heap by using negative values (since heapq is a min-heap by default)\n max_heap = [-num for num in nums]\n heapq.heapify(max_heap)\n\n # Extract the largest n elements\n largest_n = [-heapq.heappop(max_heap) for _ in range(n)]\n\n return sorted(largest_n, reverse=True)", "matching_cluster_idx": 9}, {"solution": "def heap_queue_largest(numbers, n):\n \"\"\"\n Finds the n largest integers from a given list of numbers, returned in descending order.\n\n Args:\n numbers (list): A list of integers.\n n (int): The number of largest integers to find.\n\n Returns:\n list: A list of n largest integers in descending order.\n \"\"\"\n # Importing the heapq module to use the nlargest function\n import heapq\n\n # Using heapq.nlargest to find the n largest numbers\n return heapq.nlargest(n, numbers)", "matching_cluster_idx": 9}, {"solution": "import heapq\ndef heap_queue_largest(nums, n):\n # Use a max heap by using negative numbers\n max_heap = [-num for num in nums]\n heapq.heapify(max_heap)\n\n # Extract the largest n elements\n largest_elements = [ -heapq.heappop(max_heap) for _ in range(n) ]\n\n return sorted(largest_elements, reverse=True)", "matching_cluster_idx": 9}, {"solution": "from heapq import nlargest\ndef heap_queue_largest(numbers, n):\n return nlargest(n, numbers)", "matching_cluster_idx": 9}]}, "Mbpp/9": {"dps": 58.21995464852608, "dps_norm": 52.5, "pass@1": 12.0, "profiled": [{"solution": "def find_Rotations(s: str) -> int:\n # Find the length of the string\n n = len(s)\n\n # If the string is empty or has only one character, no rotation is needed\n if n == 0 or n == 1:\n return 0\n\n # Find the number of unique substrings of length 1, 2, 3, ..., n\n for i in range(1, n):\n if s[:i] * (n // i) == s:\n return i\n\n # If no such substring is found, return n (the whole string)\n return n", "matching_cluster_idx": 5}, {"solution": "def find_Rotations(s: str) -> int:\n # Check if the string is the same after rotation\n if s == s[1:] + s[0]:\n return 1\n # Try rotating the string by increasing values of rotations\n for i in range(2, len(s)):\n if s == s[i:] + s[:i]:\n return i\n return len(s)", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(s: str) -> int:\n # Empty string or string with one character has no rotations\n if len(s) <= 1:\n return 0\n\n # Find the length of the string\n n = len(s)\n\n # Iterate through the string and check for rotation equivalence\n for i in range(1, n):\n if s == s[i:] + s[:i]:\n return i\n\n return n", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(s):\n n = len(s)\n if n == 0:\n return 0\n\n for i in range(1, n):\n if s == s[i:] + s[:i]:\n return i\n\n return n", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(s):\n n = len(s)\n\n # If the string is already the same after one rotation, return 1\n if s == s[1:] + s[0]:\n return 1\n\n # Check for other possible rotations\n for i in range(2, n + 1):\n if s == s[i:] + s[:i]:\n return i\n\n return n", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(s):\n # Edge cases\n if len(s) == 0:\n return 0\n if len(s) == 1:\n return 0\n\n # Calculate the number of rotations needed to get the same string\n rotations = len(s)\n\n # Check if any rotation of the string can form the original string\n for i in range(1, len(s)):\n if s == s[i:] + s[:i]:\n rotations = i\n break\n\n return rotations", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(s: str) -> int:\n # Base case: if the string is empty or has only one character, no rotations are needed.\n if len(s) <= 1:\n return 0\n\n # Get the length of the string\n length = len(s)\n\n # Initialize the minimum number of rotations to length of the string\n min_rotations = length\n\n # Check rotations up to the length of the string\n for i in range(1, length):\n rotated = s[i:] + s[:i]\n if rotated == s:\n min_rotations = min(min_rotations, i)\n\n return min_rotations", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(s):\n if len(s) == 0:\n return 0\n\n def is_rotation(s1, s2):\n return s1 == s1[1:] + s1[0]\n\n for i in range(1, len(s)):\n if is_rotation(s, s[i:] + s[:i]):\n return i\n\n return len(s)", "matching_cluster_idx": 3}, {"solution": "def find_Rotations(s):\n n = len(s)\n for i in range(1, n):\n if s == s[i:] + s[:i]:\n return i\n return n", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(s):\n \"\"\"\n This function returns the minimum number of rotations (greater than 0) required to get the same string.\n If the string is already a rotation of itself, it returns the length of the string.\n \"\"\"\n n = len(s)\n if n == 0:\n return 0\n\n for i in range(1, n):\n if s[i:] + s[:i] == s:\n return i\n\n return n", "matching_cluster_idx": 4}, {"solution": "def find_Rotations(s):\n # If the string is the same after any rotation, the length of the string is the minimum number of rotations.\n length = len(s)\n if length == 0:\n return 0\n\n # For a string to have the same result after any rotation, it must be a repeated substring.\n # The length of the repeated substring is the number of rotations needed.\n for i in range(1, length + 1):\n if length % i == 0:\n substring = s[:i]\n if substring * (length // i) == s:\n return i\n\n # If no repeated substring is found, return -1 (indicating that no such rotation exists)\n return -1", "matching_cluster_idx": 6}, {"solution": "def find_Rotations(s):\n \"\"\"\n Find the minimum number of rotations (greater than 0) required\n to make the string the same.\n\n :param s: The input string\n :return: The minimum number of rotations needed\n \"\"\"\n # Special case for a single character string\n if len(s) == 1:\n return 0\n\n # Concatenate the string with itself and find the first non-repeating substring\n rotated = s + s\n for i in range(1, len(s)):\n if rotated[i:i+len(s)] == s:\n return i\n\n return len(s)", "matching_cluster_idx": 5}]}, "Mbpp/11": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 63.0, "profiled": [{"solution": "def remove_Occ(s: str, char: str) -> str:\n # Find the first occurrence of the character\n first_index = s.find(char)\n # Find the last occurrence of the character\n last_index = s.rfind(char)\n\n # Handle cases where the character is not found or there's only one occurrence\n if first_index == -1:\n return s # Character not found\n if first_index == last_index:\n return s[:first_index] + s[first_index + 1:] # Only one occurrence\n\n # Remove both first and last occurrences\n return s[:first_index] + s[first_index + 1:last_index] + s[last_index + 1:]", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(s: str, char: str) -> str:\n # Find the positions of the first and last occurrence of the given character\n first_index = s.find(char)\n last_index = s.rfind(char)\n\n # If the character is not found in the string, return the original string\n if first_index == -1 or last_index == -1:\n return s\n\n # Remove the first and last occurrences of the character\n if first_index < last_index:\n return s[:first_index] + s[first_index+1:last_index] + s[last_index+1:]\n else:\n return s[:last_index] + s[first_index+1:]", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(string, char):\n \"\"\"\n Removes the first and last occurrence of a given character from the string.\n\n Parameters:\n string (str): The input string.\n char (str): The character to be removed.\n\n Returns:\n str: The modified string with the first and last occurrence of the given character removed.\n \"\"\"\n # Check if the character exists in the string\n if char not in string:\n return string\n\n # Find the index of the first and last occurrence of the character\n first_occurrence = string.find(char)\n last_occurrence = string.rfind(char)\n\n # Remove the character from the string\n modified_string = (string[:first_occurrence] + string[first_occurrence+1:last_occurrence] + string[last_occurrence+1:])\n\n return modified_string", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(s, char):\n # Find the first and last occurrence of the character\n first_index = s.find(char)\n last_index = s.rfind(char)\n\n # Handle cases where the character is not found\n if first_index == -1 or last_index == -1:\n return s\n\n # Remove the first and last occurrence of the character\n # by slicing the string and concatenating the parts\n return s[:first_index] + s[first_index + 1:last_index] + s[last_index + 1:]", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(s, char):\n \"\"\"\n Remove the first and last occurrence of the given character from the string.\n\n :param s: The input string\n :param char: The character to remove\n :return: The modified string with the first and last occurrence of the character removed\n \"\"\"\n # Find the first and last index of the character\n first_index = s.find(char)\n last_index = s.rfind(char)\n\n # Handle the case where the character does not exist\n if first_index == -1 or last_index == -1:\n return s\n\n # Create the new string by slicing around the unwanted characters\n return s[:first_index] + s[first_index+1:last_index] + s[last_index+1:]", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(s, char):\n first_index = s.find(char)\n last_index = s.rfind(char)\n\n # Check if character is found\n if first_index == -1:\n return s\n if last_index == -1:\n return s\n\n # Remove first and last occurrence\n result = s[:first_index] + s[first_index + 1:last_index] + s[last_index + 1:]\n\n return result", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(s, ch):\n \"\"\"\n Remove the first and last occurrence of a given character from the string.\n\n Parameters:\n s (str): The input string.\n ch (str): The character to be removed.\n\n Returns:\n str: The modified string.\n \"\"\"\n first_index = s.find(ch)\n last_index = s.rfind(ch)\n\n if first_index == -1 or last_index == -1:\n # If the character is not found, return the original string\n return s\n\n # Remove the first and last occurrence\n return s[:first_index] + s[first_index+1:last_index] + s[last_index+1:]", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(string, char):\n # Find the index of the first occurrence of the character\n first_index = string.find(char)\n # Find the index of the last occurrence of the character\n last_index = string.rfind(char)\n\n # If the character is not found, return the original string\n if first_index == -1 or last_index == -1:\n return string\n\n # Slice the string to remove the first and last occurrences\n return string[:first_index] + string[first_index+1:last_index] + string[last_index+1:]", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(s, ch):\n # Find the first and last occurrence of the character\n first = s.find(ch)\n last = s.rfind(ch)\n\n # If character is not found, return the original string\n if first == -1 or last == -1:\n return s\n\n # Create the modified string by removing the character at the first and last positions\n return s[:first] + s[first + 1:last] + s[last + 1:]", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(s: str, char: str) -> str:\n if len(s) == 0 or len(char) != 1:\n return s\n\n # Find the first and last occurrences of the character\n first_index = s.find(char)\n last_index = s.rfind(char)\n\n if first_index == -1 or last_index == -1:\n # If the character is not found, return the original string\n return s\n\n # Remove the first and last occurrences\n return s[:first_index] + s[first_index+1:last_index] + s[last_index+1:]", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(string, char):\n if not string:\n return string\n\n # Find the first occurrence of the character\n first_index = string.find(char)\n if first_index == -1:\n return string # Character not found\n\n # Find the last occurrence of the character\n last_index = string.rfind(char)\n if last_index == -1:\n return string # Character not found\n\n # Create a new string without the first and last occurrences of the character\n return string[:first_index] + string[first_index+1:last_index] + string[last_index+1:]", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(s, char):\n # Find the first and last occurrence of the character\n first_index = s.find(char)\n last_index = s.rfind(char)\n\n # Handle edge cases where the character does not appear in the string\n if first_index == -1 or last_index == -1:\n return s\n\n # Create a new string without the first and last occurrence of the character\n new_string = s[:first_index] + s[first_index + 1:last_index] + s[last_index + 1:]\n\n return new_string", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(s, char):\n \"\"\"\n Remove the first and last occurrence of a given character from the string.\n\n :param s: The input string.\n :param char: The character to be removed.\n :return: The modified string with the first and last occurrence of the character removed.\n \"\"\"\n # Find the indices of the first and last occurrences of the character\n first_idx = s.find(char)\n last_idx = s.rfind(char)\n\n # Handle the case where the character does not exist in the string\n if first_idx == -1 or last_idx == -1:\n return s\n\n # Construct the modified string by removing the first and last occurrences\n modified_string = s[:first_idx] + s[first_idx+1:last_idx] + s[last_idx+1:]\n\n return modified_string", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(s: str, c: str) -> str:\n # Find the positions of the first and last occurrences of the character\n first_pos = s.find(c)\n last_pos = s.rfind(c)\n\n # If the character is not found, return the original string\n if first_pos == -1 or last_pos == -1:\n return s\n\n # Create a new string with the first and last occurrences removed\n return s[:first_pos] + s[first_pos + 1:last_pos] + s[last_pos + 1:]", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(s, char):\n # Find the first and last occurrences of the character\n first_index = s.find(char)\n last_index = s.rfind(char)\n\n # Check if the character exists in the string\n if first_index == -1 or last_index == -1:\n return s\n\n # Construct the result string\n result = s[:first_index] + s[first_index+1:last_index] + s[last_index+1:]\n\n return result", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(s, ch):\n # Find the index of the first occurrence of the character\n first_idx = s.find(ch)\n # Find the index of the last occurrence of the character\n last_idx = s.rfind(ch)\n\n # If the character is not found, return the original string\n if first_idx == -1 or last_idx == -1:\n return s\n\n # If both indices are the same, the character appears only once\n if first_idx == last_idx:\n return s[:first_idx] + s[first_idx+1:]\n\n # Remove the first and last occurrences\n return s[:first_idx] + s[first_idx+1:last_idx] + s[last_idx+1:]", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(s, char):\n # Find the first occurrence of the character\n first_index = s.find(char)\n # Find the last occurrence of the character\n last_index = s.rfind(char)\n\n # Check if the character exists in the string\n if first_index == -1 or last_index == -1:\n return s\n\n # Remove the first and last occurrences\n return s[:first_index] + s[first_index + 1:last_index] + s[last_index + 1:]", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(string, char):\n # Find the first occurrence index of the character\n first_index = string.find(char)\n # Find the last occurrence index of the character\n last_index = string.rfind(char)\n\n # If the character is not found, return the original string\n if first_index == -1 or last_index == -1:\n return string\n\n # If the character appears only once, return the string with that character removed\n if first_index == last_index:\n return string[:first_index] + string[first_index + 1:]\n\n # Remove both the first and last occurrences\n return string[:first_index] + string[first_index + 1:last_index] + string[last_index + 1:]", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(s, char):\n # Find the index of the first occurrence of the character\n first_idx = s.find(char)\n # Find the index of the last occurrence of the character\n last_idx = s.rfind(char)\n\n # If the character is not found, return the original string\n if first_idx == -1:\n return s\n\n # Remove both the first and last occurrence of the character\n # Return the modified string\n return s[:first_idx] + s[first_idx + 1:last_idx] + s[last_idx + 1:]", "matching_cluster_idx": 8}, {"solution": "def remove_Occ(s, char):\n if not s or char not in s:\n return s\n\n # Find the first occurrence of the character\n first_index = s.find(char)\n # Find the last occurrence of the character\n last_index = s.rfind(char)\n\n if first_index == -1 or last_index == -1:\n return s\n\n # Construct the result by slicing the string and omitting the specified indices\n result = s[:first_index] + s[first_index + 1:last_index] + s[last_index + 1:]\n return result", "matching_cluster_idx": 8}]}, "Mbpp/12": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 99.0, "profiled": [{"solution": "def sort_matrix(matrix):\n # Sort the matrix rows based on the sum of elements in each row\n sorted_matrix = sorted(matrix, key=lambda row: sum(row))\n return sorted_matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Sort matrix based on the sum of its rows\n sorted_matrix = sorted(matrix, key=lambda row: sum(row))\n return sorted_matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Sort the matrix based on the sum of the rows\n sorted_matrix = sorted(matrix, key=lambda row: sum(row))\n return sorted_matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Sort the matrix based on the sum of each row\n return sorted(matrix, key=sum)", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Sort the matrix based on the sum of rows\n sorted_matrix = sorted(matrix, key=lambda row: sum(row))\n return sorted_matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Sort the matrix based on the sum of the rows\n return sorted(matrix, key=lambda row: sum(row))", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Sort the matrix based on the sum of its rows\n return sorted(matrix, key=sum)", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Sort the rows based on the sum of their elements\n return sorted(matrix, key=lambda row: sum(row))", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Create a list of tuples where each tuple contains the row and its sum\n rows_with_sums = [(row, sum(row)) for row in matrix]\n\n # Sort the list of tuples by the sum\n rows_with_sums.sort(key=lambda x: x[1])\n\n # Extract the sorted rows from the tuples\n sorted_matrix = [row for row, _ in rows_with_sums]\n\n return sorted_matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Sort the matrix based on the sum of rows\n return sorted(matrix, key=lambda x: sum(x))", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Sort the matrix based on the sum of each row\n return sorted(matrix, key=lambda row: sum(row))", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Sort the rows of the matrix based on the sum of their elements\n return sorted(matrix, key=sum)", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # First, calculate the sum of each row\n row_sums = [(row, sum(row)) for row in matrix]\n\n # Sort the rows based on the sums\n row_sums.sort(key=lambda x: x[1])\n\n # Extract the sorted rows from the tuples\n sorted_matrix = [row for row, _ in row_sums]\n\n return sorted_matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Sort the matrix based on the sum of each row\n return sorted(matrix, key=lambda row: sum(row))", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Sort the matrix based on the sum of its rows\n sorted_matrix = sorted(matrix, key=sum)\n return sorted_matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Sort the matrix rows based on the sum of their elements\n return sorted(matrix, key=lambda row: sum(row))", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Sort matrix by the sum of its rows\n sorted_matrix = sorted(matrix, key=lambda row: sum(row))\n return sorted_matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Sort the matrix based on the sum of each row\n sorted_matrix = sorted(matrix, key=lambda row: sum(row))\n return sorted_matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Sort the matrix based on the sum of each row\n sorted_matrix = sorted(matrix, key=sum)\n return sorted_matrix", "matching_cluster_idx": 15}, {"solution": "def sort_matrix(matrix):\n # Sort the rows based on the sum of their elements\n sorted_matrix = sorted(matrix, key=lambda row: sum(row))\n return sorted_matrix", "matching_cluster_idx": 15}]}, "Mbpp/16": {"dps": null, "dps_norm": null, "pass@1": 2.0, "profiled": []}, "Mbpp/19": {"dps": 82.32323232323233, "dps_norm": 90.0, "pass@1": 47.0, "profiled": [{"solution": "def test_duplicate(arr):\n # Using a set to track the elements\n seen = set()\n for num in arr:\n if num in seen:\n return True\n seen.add(num)\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(arr):\n \"\"\"\n Checks if there are any duplicate elements in the given array.\n\n Parameters:\n arr (list of int): List of integers to check for duplicates.\n\n Returns:\n bool: True if there are duplicates, False otherwise.\n \"\"\"\n seen = set()\n for num in arr:\n if num in seen:\n return True\n seen.add(num)\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(arr):\n \"\"\"\n Function to check if there are any duplicate elements in the given array.\n :param arr: List of integers\n :return: Boolean value indicating if there are duplicates\n \"\"\"\n return len(arr) != len(set(arr))", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(arr):\n return len(arr) != len(set(arr))", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(arr):\n \"\"\"\n Function to find whether a given array of integers contains any duplicate element.\n \"\"\"\n return len(arr) != len(set(arr))", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(arr):\n \"\"\"\n Determine whether the given array contains any duplicate elements.\n :param arr: List of integers\n :return: Boolean indicating presence of duplicates\n \"\"\"\n # Use a set to track elements we have seen\n seen = set()\n for num in arr:\n if num in seen:\n return True\n seen.add(num)\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(nums):\n # Convert the list to a set and compare its length with the original list length\n return len(nums) != len(set(nums))", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(arr):\n \"\"\"\n Check if the given array contains any duplicate elements.\n\n Parameters:\n arr (list): List of integers to check for duplicates.\n\n Returns:\n bool: True if there are duplicates, False otherwise.\n \"\"\"\n seen = set()\n for num in arr:\n if num in seen:\n return True\n seen.add(num)\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(arr):\n \"\"\"\n Function to find whether a given array of integers contains any duplicate element.\n\n Parameters:\n arr (list): List of integers\n\n Returns:\n bool: True if there are duplicates, False otherwise\n \"\"\"\n # Using a set to track seen elements\n seen = set()\n for num in arr:\n if num in seen:\n return True\n seen.add(num)\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(arr):\n # Use a set to track the elements we have seen\n seen = set()\n\n for num in arr:\n if num in seen:\n # If the number is already in the set, we have a duplicate\n return True\n seen.add(num)\n\n # If we've gone through the whole list without finding a duplicate\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(arr):\n # Create a set to keep track of the elements we have seen\n seen = set()\n # Iterate through each element in the array\n for number in arr:\n # If the element is already in the set, we have a duplicate\n if number in seen:\n return True\n # Otherwise, add the element to the set\n seen.add(number)\n # If we complete the loop without finding a duplicate, return False\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(arr):\n \"\"\"\n Function to check if the given array contains any duplicate elements.\n\n Parameters:\n arr (list): List of integers.\n\n Returns:\n bool: True if there is any duplicate element, False otherwise.\n \"\"\"\n return len(arr) != len(set(arr))", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(arr):\n # Use a set to keep track of the elements we have seen\n seen = set()\n # Iterate over each element in the array\n for num in arr:\n # If the element is already in the set, it means it is a duplicate\n if num in seen:\n return True\n # Otherwise, add the element to the set\n seen.add(num)\n # If no duplicates are found, return False\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(nums):\n # Using a set to check for duplicates, as a set does not allow duplicate elements\n return len(nums) != len(set(nums))", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(arr):\n # Use a set to track seen elements\n seen = set()\n\n # Iterate through the array\n for number in arr:\n # If the number is already in the set, it's a duplicate\n if number in seen:\n return True\n # Otherwise, add the number to the set\n seen.add(number)\n\n # If no duplicates were found, return False\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(arr):\n # Convert the list to a set to check for duplicates\n seen = set()\n for number in arr:\n if number in seen:\n return True\n seen.add(number)\n return False", "matching_cluster_idx": 14}, {"solution": "def test_duplicate(arr):\n \"\"\"\n Function to find whether a given array of integers contains any duplicate element.\n\n :param arr: List of integers\n :return: Boolean indicating whether the list contains any duplicate elements\n \"\"\"\n return len(arr) != len(set(arr))", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(nums):\n \"\"\"\n Function to check if the given list contains any duplicate elements.\n\n Args:\n nums (list): A list of integers.\n\n Returns:\n bool: True if there is any duplicate, False otherwise.\n \"\"\"\n return len(nums) != len(set(nums))", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(arr):\n # Check if any element in the array appears more than once\n return len(arr) != len(set(arr))", "matching_cluster_idx": 11}, {"solution": "def test_duplicate(arr):\n \"\"\"\n This function checks if there is any duplicate element in the given array.\n\n Args:\n arr (list of int): The list of integers to check for duplicates.\n\n Returns:\n bool: True if there is a duplicate, False otherwise.\n \"\"\"\n return len(arr) != len(set(arr))", "matching_cluster_idx": 11}]}, "Mbpp/62": {"dps": 88.0, "dps_norm": 92.0, "pass@1": 100.0, "profiled": [{"solution": "def smallest_num(numbers):\n if not numbers:\n raise ValueError(\"The list is empty\")\n smallest = numbers[0]\n for number in numbers:\n if number < smallest:\n smallest = number\n return smallest", "matching_cluster_idx": 3}, {"solution": "def smallest_num(numbers):\n if not numbers:\n raise ValueError(\"The list is empty\")\n return min(numbers)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(nums):\n # Check if the list is empty\n if not nums:\n raise ValueError(\"List is empty, cannot find the smallest number\")\n\n # Initialize the smallest number as the first element of the list\n smallest = nums[0]\n\n # Iterate through the list to find the smallest number\n for num in nums:\n if num < smallest:\n smallest = num\n\n return smallest", "matching_cluster_idx": 3}, {"solution": "def smallest_num(lst):\n if not lst: # Check if the list is empty\n raise ValueError(\"The list is empty\")\n return min(lst)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(lst):\n # Ensure the list is not empty\n if not lst:\n raise ValueError(\"The list is empty\")\n # Initialize the smallest number as the first element of the list\n smallest = lst[0]\n # Iterate through the list to find the smallest number\n for num in lst:\n if num < smallest:\n smallest = num\n return smallest", "matching_cluster_idx": 3}, {"solution": "def smallest_num(nums):\n # Ensure the list is not empty\n if not nums:\n raise ValueError(\"The list is empty\")\n # Find the smallest number in the list\n smallest = nums[0]\n for num in nums:\n if num < smallest:\n smallest = num\n return smallest", "matching_cluster_idx": 3}, {"solution": "def smallest_num(nums):\n if not nums:\n raise ValueError(\"The list is empty.\")\n return min(nums)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(numbers):\n \"\"\"\n Returns the smallest number in a given list of numbers.\n\n Parameters:\n numbers (list): List of numbers.\n\n Returns:\n int: The smallest number in the list.\n \"\"\"\n if not numbers:\n raise ValueError(\"The list is empty\")\n return min(numbers)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(numbers):\n if not numbers:\n raise ValueError(\"The list is empty\")\n return min(numbers)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(numbers):\n if not numbers:\n raise ValueError(\"The list is empty\")\n return min(numbers)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(nums):\n if not nums: # check if the list is empty\n return None # return None if the list is empty\n smallest = nums[0]\n for num in nums:\n if num < smallest:\n smallest = num\n return smallest", "matching_cluster_idx": 3}, {"solution": "def smallest_num(lst):\n if not lst:\n raise ValueError(\"List is empty\")\n return min(lst)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(nums):\n if not nums:\n raise ValueError(\"The list is empty.\")\n return min(nums)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(numbers):\n \"\"\"\n This function returns the smallest number in a list.\n :param numbers: List of numbers.\n :return: The smallest number in the list.\n \"\"\"\n if not numbers:\n raise ValueError(\"The list is empty\")\n return min(numbers)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(lst):\n \"\"\"\n Finds the smallest number in a list.\n\n :param lst: List of numbers\n :return: The smallest number in the list\n \"\"\"\n if not lst:\n raise ValueError(\"The list is empty\")\n return min(lst)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(numbers):\n if not numbers: # Check if the list is empty\n return None # Return None for empty list\n return min(numbers) # Return the smallest number", "matching_cluster_idx": 4}, {"solution": "def smallest_num(numbers):\n \"\"\"\n Function to find the smallest number in a list.\n\n Parameters:\n numbers (list): A list of integers or floats.\n\n Returns:\n int or float: The smallest number in the list.\n \"\"\"\n if not numbers:\n raise ValueError(\"The list is empty\")\n\n smallest = numbers[0]\n for number in numbers:\n if number < smallest:\n smallest = number\n return smallest", "matching_cluster_idx": 3}, {"solution": "def smallest_num(nums):\n # Initialize the smallest number as the first element of the list\n smallest = nums[0]\n\n # Iterate through the list starting from the second element\n for num in nums[1:]:\n # Update the smallest number if a smaller one is found\n if num < smallest:\n smallest = num\n\n return smallest", "matching_cluster_idx": 3}, {"solution": "def smallest_num(lst):\n if not lst:\n raise ValueError(\"The list is empty\")\n return min(lst)", "matching_cluster_idx": 4}, {"solution": "def smallest_num(numbers):\n \"\"\"\n Finds the smallest number in a list.\n\n Parameters:\n numbers (list of int): A list of integers.\n\n Returns:\n int: The smallest number in the list.\n \"\"\"\n if not numbers:\n raise ValueError(\"The list is empty\")\n\n smallest = numbers[0]\n for num in numbers:\n if num < smallest:\n smallest = num\n\n return smallest", "matching_cluster_idx": 3}]}, "Mbpp/75": {"dps": 92.85714285714286, "dps_norm": 66.66666666666667, "pass@1": 100.0, "profiled": [{"solution": "def find_tuples(tuples_list, k):\n # This function returns a list of tuples where all elements are divisible by k\n return [t for t in tuples_list if all(elem % k == 0 for elem in t)]", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n \"\"\"\n Find tuples where all elements are divisible by k.\n\n Parameters:\n tuples_list (list of tuples): A list of tuples.\n k (int): The divisor.\n\n Returns:\n list of tuples: A list of tuples where all elements are divisible by k.\n \"\"\"\n result = []\n for t in tuples_list:\n if all(element % k == 0 for element in t):\n result.append(t)\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n result = []\n for t in tuples_list:\n if all(x % k == 0 for x in t):\n result.append(t)\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n \"\"\"\n Finds tuples where all elements are divisible by k.\n\n :param tuples_list: List of tuples to check.\n :param k: Integer to check divisibility.\n :return: List of tuples where all elements are divisible by k.\n \"\"\"\n return [t for t in tuples_list if all(x % k == 0 for x in t)]", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n result = []\n for t in tuples_list:\n if all(x % k == 0 for x in t):\n result.append(t)\n return result\ntuples_list = [(6, 24, 12), (7, 9, 6), (12, 18, 21)]\nk = 6", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n # Function to check if all elements in a tuple are divisible by k\n def all_divisible_by_k(t):\n return all(x % k == 0 for x in t)\n\n # Filter the tuples that meet the condition\n result = [t for t in tuples_list if all_divisible_by_k(t)]\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n def all_elements_divisible_by_k(t, k):\n return all(element % k == 0 for element in t)\n\n return [t for t in tuples_list if all_elements_divisible_by_k(t, k)]", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n def all_divisible_by_k(t):\n return all(x % k == 0 for x in t)\n\n return [t for t in tuples_list if all_divisible_by_k(t)]", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples, k):\n \"\"\"\n Find tuples which have all elements divisible by k from the given list of tuples.\n\n :param tuples: List of tuples\n :param k: Integer to check divisibility\n :return: List of tuples that have all elements divisible by k\n \"\"\"\n return [t for t in tuples if all(element % k == 0 for element in t)]", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples, k):\n result = []\n for t in tuples:\n if all(elem % k == 0 for elem in t):\n result.append(t)\n return result\nk = 6", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n \"\"\"\n This function returns tuples which have all elements divisible by k.\n\n Args:\n - tuples_list (list of tuples): A list of tuples.\n - k (int): A number to check divisibility.\n\n Returns:\n - list of tuples: A list of tuples where all elements are divisible by k.\n \"\"\"\n result = []\n for tup in tuples_list:\n if all(x % k == 0 for x in tup):\n result.append(tup)\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples, k):\n \"\"\"\n This function returns a list of tuples where all elements in the tuple are divisible by k.\n\n :param tuples: List of tuples\n :param k: Divisor\n :return: List of tuples where all elements are divisible by k\n \"\"\"\n return [t for t in tuples if all(elem % k == 0 for elem in t)]", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n result = []\n for t in tuples_list:\n if all(x % k == 0 for x in t):\n result.append(t)\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n result = []\n for tup in tuples_list:\n if all(num % k == 0 for num in tup):\n result.append(tup)\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n def all_divisible(t, k):\n return all(x % k == 0 for x in t)\n\n return [t for t in tuples_list if all_divisible(t, k)]", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n \"\"\"\n Function to find tuples which have all elements divisible by k from the given list of tuples.\n \"\"\"\n result = []\n for tpl in tuples_list:\n if all(elem % k == 0 for elem in tpl):\n result.append(tpl)\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n result = []\n for t in tuples_list:\n if all(x % k == 0 for x in t):\n result.append(t)\n return result\ntuples_list = [(6, 24, 12), (7, 9, 6), (12, 18, 21)]\nk = 6", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n result = []\n for t in tuples_list:\n if all(x % k == 0 for x in t):\n result.append(t)\n return result", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n def all_elements_divisible_by_k(t, k):\n return all(x % k == 0 for x in t)\n\n return [t for t in tuples_list if all_elements_divisible_by_k(t, k)]", "matching_cluster_idx": 5}, {"solution": "def find_tuples(tuples_list, k):\n \"\"\"\n Finds tuples which have all elements divisible by k from the given list of tuples.\n\n Parameters:\n - tuples_list: List of tuples.\n - k: Integer, the divisor.\n\n Returns:\n - List of tuples where all elements in each tuple are divisible by k.\n \"\"\"\n result = []\n for t in tuples_list:\n if all(element % k == 0 for element in t):\n result.append(t)\n return result", "matching_cluster_idx": 5}]}, "Mbpp/88": {"dps": 96.56862745098039, "dps_norm": 85.71428571428571, "pass@1": 100.0, "profiled": [{"solution": "def freq_count(lst):\n \"\"\"\n This function returns a dictionary with the frequency of all elements in the given list.\n\n Parameters:\n lst (list): List of integers.\n\n Returns:\n dict: Dictionary where keys are the list elements and values are their frequencies.\n \"\"\"\n freq_dict = {}\n for num in lst:\n if num in freq_dict:\n freq_dict[num] += 1\n else:\n freq_dict[num] = 1\n return freq_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n \"\"\"\n Get the frequency of all the elements in a list, returned as a dictionary.\n\n Args:\n lst (list): The list of elements.\n\n Returns:\n dict: A dictionary with elements as keys and their frequencies as values.\n \"\"\"\n frequency_dict = {}\n for element in lst:\n if element in frequency_dict:\n frequency_dict[element] += 1\n else:\n frequency_dict[element] = 1\n return frequency_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n freq = {}\n for num in lst:\n if num in freq:\n freq[num] += 1\n else:\n freq[num] = 1\n return freq", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n frequency = {}\n for element in lst:\n if element in frequency:\n frequency[element] += 1\n else:\n frequency[element] = 1\n return frequency", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n \"\"\"\n Function to get the frequency of all the elements in a list, returned as a dictionary.\n \"\"\"\n freq = {}\n for item in lst:\n if item in freq:\n freq[item] += 1\n else:\n freq[item] = 1\n return freq", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n freq = {}\n for item in lst:\n if item in freq:\n freq[item] += 1\n else:\n freq[item] = 1\n return freq", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n frequency = {}\n for element in lst:\n if element in frequency:\n frequency[element] += 1\n else:\n frequency[element] = 1\n return frequency", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n \"\"\"\n This function takes a list as input and returns a dictionary with the frequency of each element.\n\n Parameters:\n lst (list): The input list containing elements.\n\n Returns:\n dict: A dictionary where keys are elements from the list and values are their respective frequencies.\n \"\"\"\n frequency_dict = {}\n for item in lst:\n if item in frequency_dict:\n frequency_dict[item] += 1\n else:\n frequency_dict[item] = 1\n return frequency_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n \"\"\"\n Return the frequency of each element in the list as a dictionary.\n\n Args:\n lst (list): A list of integers\n\n Returns:\n dict: A dictionary with elements as keys and their frequencies as values\n \"\"\"\n frequency_dict = {}\n for item in lst:\n if item in frequency_dict:\n frequency_dict[item] += 1\n else:\n frequency_dict[item] = 1\n return frequency_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n frequency = {}\n for item in lst:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n return frequency", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n frequency_dict = {}\n for item in lst:\n if item in frequency_dict:\n frequency_dict[item] += 1\n else:\n frequency_dict[item] = 1\n return frequency_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n \"\"\"\n Get the frequency of all elements in the list.\n\n Args:\n lst (list): The input list.\n\n Returns:\n dict: A dictionary where the keys are the elements in the list and the values are their frequencies.\n \"\"\"\n frequency = {}\n for item in lst:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n return frequency", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n \"\"\"\n This function calculates the frequency of all elements in the list.\n\n Parameters:\n lst (list): A list of elements.\n\n Returns:\n dict: A dictionary with elements as keys and their frequencies as values.\n \"\"\"\n frequency = {}\n for item in lst:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n return frequency", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n \"\"\"\n Returns a dictionary with the frequency of each element in the list.\n \"\"\"\n frequency = {}\n for element in lst:\n if element in frequency:\n frequency[element] += 1\n else:\n frequency[element] = 1\n return frequency", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n \"\"\"\n Function to get the frequency of all the elements in a list, returned as a dictionary.\n\n Parameters:\n lst (list): The list of elements to count.\n\n Returns:\n dict: A dictionary with elements as keys and their counts as values.\n \"\"\"\n freq_dict = {}\n for element in lst:\n if element in freq_dict:\n freq_dict[element] += 1\n else:\n freq_dict[element] = 1\n return freq_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n frequency = {}\n for element in lst:\n if element in frequency:\n frequency[element] += 1\n else:\n frequency[element] = 1\n return frequency", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n \"\"\"\n Function to get the frequency of all the elements in a list.\n\n :param lst: List of elements\n :return: Dictionary with elements as keys and their frequencies as values\n \"\"\"\n frequency = {}\n for item in lst:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n return frequency", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n freq_dict = {}\n for item in lst:\n if item in freq_dict:\n freq_dict[item] += 1\n else:\n freq_dict[item] = 1\n return freq_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n frequency_dict = {}\n for num in lst:\n if num in frequency_dict:\n frequency_dict[num] += 1\n else:\n frequency_dict[num] = 1\n return frequency_dict", "matching_cluster_idx": 5}, {"solution": "def freq_count(lst):\n \"\"\"\n Returns a dictionary with the frequency of each element in the list.\n\n :param lst: List of elements\n :return: Dictionary with element frequencies\n \"\"\"\n frequency = {}\n for item in lst:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n return frequency", "matching_cluster_idx": 5}]}, "Mbpp/90": {"dps": 76.73170731707317, "dps_norm": 85.0, "pass@1": 40.0, "profiled": [{"solution": "def len_log(words):\n # Initialize a variable to keep track of the longest word length\n longest_length = 0\n\n # Iterate through each word in the list\n for word in words:\n # Update the longest length if the current word is longer\n if len(word) > longest_length:\n longest_length = len(word)\n\n # Return the length of the longest word\n return longest_length", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n max_length = 0\n for word in words:\n if len(word) > max_length:\n max_length = len(word)\n return max_length", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n max_length = 0\n for word in words:\n if len(word) > max_length:\n max_length = len(word)\n return max_length", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n # Function to find the length of the longest word in a list of words\n longest_word_length = 0\n for word in words:\n if len(word) > longest_word_length:\n longest_word_length = len(word)\n return longest_word_length", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n \"\"\"\n Find the length of the longest word in a list of words.\n\n Parameters:\n words (list): A list of words (strings)\n\n Returns:\n int: The length of the longest word in the list.\n \"\"\"\n # Initialize a variable to store the length of the longest word\n max_length = 0\n\n # Iterate over each word in the list\n for word in words:\n # Update max_length if the current word is longer than the current max_length\n if len(word) > max_length:\n max_length = len(word)\n\n return max_length", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n # Initialize the max_length with the length of the first word in the list\n max_length = len(words[0])\n\n # Iterate over each word in the list\n for word in words:\n # Update max_length if the current word is longer\n if len(word) > max_length:\n max_length = len(word)\n\n return max_length", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n \"\"\"\n This function takes a list of words and returns the length of the longest word.\n \"\"\"\n if not words:\n return 0\n longest_length = 0\n for word in words:\n if len(word) > longest_length:\n longest_length = len(word)\n return longest_length", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n max_length = 0\n for word in words:\n if len(word) > max_length:\n max_length = len(word)\n return max_length", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n \"\"\"\n Returns the length of the longest word in the list.\n\n Parameters:\n words (list): A list of strings.\n\n Returns:\n int: The length of the longest word.\n \"\"\"\n return max(len(word) for word in words)", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n \"\"\"\n Finds the length of the longest word in a list of words.\n\n Args:\n words (list of str): A list of words.\n\n Returns:\n int: The length of the longest word.\n \"\"\"\n max_length = 0\n for word in words:\n if len(word) > max_length:\n max_length = len(word)\n return max_length", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n \"\"\"\n Returns the length of the longest word in the list.\n \"\"\"\n return max(len(word) for word in words)", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n # Initialize the maximum length variable\n max_length = 0\n\n # Iterate through each word in the list\n for word in words:\n # Update the max_length if the current word is longer\n if len(word) > max_length:\n max_length = len(word)\n\n # Return the length of the longest word\n return max_length", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n \"\"\"\n This function takes a list of words and returns the length of the longest word.\n\n :param words: List of words (strings)\n :return: Length of the longest word\n \"\"\"\n if not words:\n return 0\n\n # Initialize the maximum length to 0\n max_length = 0\n\n # Iterate over each word in the list\n for word in words:\n # Update the maximum length if the current word is longer\n if len(word) > max_length:\n max_length = len(word)\n\n return max_length", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n # Initialize variable to keep track of the longest length\n max_length = 0\n # Iterate over each word in the list\n for word in words:\n # Update max_length if the current word length is greater\n if len(word) > max_length:\n max_length = len(word)\n return max_length", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n # Initialize the variable to store the length of the longest word\n max_length = 0\n\n # Iterate through each word in the list\n for word in words:\n # Update the max_length if the current word is longer\n if len(word) > max_length:\n max_length = len(word)\n\n # Return the length of the longest word\n return max_length", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n # Initialize the longest length to 0\n max_len = 0\n\n # Loop through each word in the list\n for word in words:\n # Check if the length of the current word is greater than the max length\n if len(word) > max_len:\n max_len = len(word)\n\n return max_len", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n # Initialize a variable to store the length of the longest word\n max_length = 0\n\n # Iterate through each word in the list\n for word in words:\n # Update max_length if the current word is longer\n if len(word) > max_length:\n max_length = len(word)\n\n return max_length", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n \"\"\"\n Function to find the length of the longest word in a list.\n\n Args:\n words (list of str): List of words\n\n Returns:\n int: Length of the longest word\n \"\"\"\n if not words:\n return 0\n\n longest_length = 0\n for word in words:\n if len(word) > longest_length:\n longest_length = len(word)\n\n return longest_length", "matching_cluster_idx": 5}, {"solution": "def len_log(words):\n longest_word = \"\"\n for word in words:\n if len(word) > len(longest_word):\n longest_word = word\n return len(longest_word)", "matching_cluster_idx": 4}, {"solution": "def len_log(words):\n \"\"\"\n This function returns the length of the longest word in a given list of words.\n\n :param words: List of words to check\n :return: Length of the longest word\n \"\"\"\n if not words:\n return 0 # Return 0 if the input list is empty\n return max(len(word) for word in words)", "matching_cluster_idx": 5}]}, "Mbpp/94": {"dps": 78.46036585365853, "dps_norm": 61.0, "pass@1": 63.0, "profiled": [{"solution": "def index_minimum(tuples):\n if not tuples:\n return None\n return min(tuples, key=lambda x: x[1])[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(tuples_list):\n if not tuples_list:\n return None # Handle case where the list is empty\n\n # Find the tuple with the smallest second value\n min_tuple = min(tuples_list, key=lambda x: x[1])\n\n # Return the first value of that tuple\n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(tuples):\n # Ensure the list of tuples is not empty\n if not tuples:\n return None\n\n # Initialize variables to track the tuple with the smallest second value\n min_tuple = tuples[0]\n\n # Iterate through the list of tuples\n for current_tuple in tuples[1:]:\n if current_tuple[1] < min_tuple[1]:\n min_tuple = current_tuple\n\n # Return the first value of the tuple with the smallest second value\n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(tuples_list):\n if not tuples_list:\n raise ValueError(\"The list is empty\")\n\n min_tuple = min(tuples_list, key=lambda x: x[1])\n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(lst):\n \"\"\"\n Given a list of tuples, return the first value of the tuple with the smallest second value.\n \"\"\"\n if not lst:\n return None\n\n min_tuple = min(lst, key=lambda x: x[1])\n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(tuples_list):\n # Find the tuple with the smallest second value\n min_tuple = min(tuples_list, key=lambda x: x[1])\n # Return the first value of the tuple with the smallest second value\n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(tuples_list):\n if not tuples_list:\n return None # Return None if the list is empty to avoid errors\n return min(tuples_list, key=lambda x: x[1])[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(tuples_list):\n if not tuples_list:\n return None\n min_tuple = min(tuples_list, key=lambda x: x[1])\n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(lst):\n # Check if the list is empty\n if not lst:\n return None # Return None if the list is empty\n\n # Initialize variables to track the tuple with the smallest second value\n min_tuple = lst[0]\n\n for item in lst:\n if item[1] < min_tuple[1]:\n min_tuple = item\n\n return min_tuple[0]", "matching_cluster_idx": 3}, {"solution": "def index_minimum(lst):\n if not lst:\n return None\n # Find the tuple with the smallest second value\n min_tuple = min(lst, key=lambda x: x[1])\n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(tuples_list):\n if not tuples_list:\n return None\n # Find the tuple with the smallest second value\n min_tuple = min(tuples_list, key=lambda x: x[1])\n # Return the first value of the found tuple\n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(tuples_list):\n if not tuples_list:\n return None\n\n # Initialize the variable to keep track of the tuple with the smallest second value\n min_tuple = tuples_list[0]\n\n # Iterate through the list to find the tuple with the smallest second value\n for current_tuple in tuples_list[1:]:\n if current_tuple[1] < min_tuple[1]:\n min_tuple = current_tuple\n\n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(lst):\n if not lst:\n raise ValueError(\"The list is empty\")\n # Find the tuple with the smallest second value\n minimum_tuple = min(lst, key=lambda x: x[1])\n # Return the first value of that tuple\n return minimum_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(lst):\n if not lst:\n raise ValueError(\"List is empty\")\n min_val = min(lst, key=lambda x: x[1])\n return min_val[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(lst):\n if not lst:\n return None\n\n min_value = min((item[1] for item in lst))\n result = [item[0] for item in lst if item[1] == min_value][0]\n\n return result", "matching_cluster_idx": 2}, {"solution": "def index_minimum(tuples_list):\n if not tuples_list:\n return None\n\n min_tuple = min(tuples_list, key=lambda x: x[1])\n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(tuples_list):\n \"\"\"\n Given a list of tuples, returns the first value of the tuple with the smallest second value.\n\n :param tuples_list: List of tuples\n :return: First value of the tuple with the smallest second value\n \"\"\"\n if not tuples_list:\n raise ValueError(\"The list of tuples should not be empty\")\n\n min_tuple = min(tuples_list, key=lambda x: x[1])\n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(tuples_list):\n if not tuples_list:\n raise ValueError(\"Input list is empty\")\n\n min_tuple = min(tuples_list, key=lambda x: x[1])\n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(lst):\n if not lst:\n return None # Return None if the list is empty\n min_tuple = min(lst, key=lambda x: x[1])\n return min_tuple[0]", "matching_cluster_idx": 2}, {"solution": "def index_minimum(lst):\n if not lst:\n return None # or raise an exception if you prefer\n return min(lst, key=lambda x: x[1])[0]", "matching_cluster_idx": 2}]}, "Mbpp/96": {"dps": 11.805555555555555, "dps_norm": 29.28571428571429, "pass@1": 90.0, "profiled": [{"solution": "def divisor(n):\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def divisor(n):\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def divisor(n):\n \"\"\"\n Function to find the number of divisors of a given integer.\n Args:\n n (int): The integer to find the number of divisors for.\n\n Returns:\n int: The number of divisors of the integer.\n \"\"\"\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def divisor(n):\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def divisor(n):\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def divisor(n):\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def divisor(n):\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def divisor(n):\n # Initialize a counter for the number of divisors\n count = 0\n\n # Loop through all numbers from 1 to n (inclusive)\n for i in range(1, n + 1):\n # Check if i is a divisor of n\n if n % i == 0:\n count += 1\n\n return count", "matching_cluster_idx": 1}, {"solution": "def divisor(n):\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def divisor(n):\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def divisor(n):\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def divisor(n):\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def divisor(n):\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def divisor(n):\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def divisor(n):\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def divisor(n):\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def divisor(n):\n \"\"\"\n Calculate the number of divisors of a given integer n.\n \"\"\"\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def divisor(n):\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def divisor(n):\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def divisor(n):\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count", "matching_cluster_idx": 1}]}, "Mbpp/97": {"dps": 99.65811965811966, "dps_norm": 87.5, "pass@1": 100.0, "profiled": [{"solution": "from collections import defaultdict\ndef frequency_lists(lists):\n frequency_dict = defaultdict(int)\n for sublist in lists:\n for element in sublist:\n frequency_dict[element] += 1\n return dict(frequency_dict)", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lists):\n \"\"\"\n Given a list of lists, return a dictionary with the frequency of each element in the flattened list.\n\n Args:\n lists (list of lists): The list of lists to flatten and count frequencies.\n\n Returns:\n dict: A dictionary with the frequency of each element in the flattened list.\n \"\"\"\n # Flatten the list of lists\n flattened_list = [item for sublist in lists for item in sublist]\n\n # Use a dictionary to count the frequency of each element\n frequency_dict = {}\n for item in flattened_list:\n if item in frequency_dict:\n frequency_dict[item] += 1\n else:\n frequency_dict[item] = 1\n\n return frequency_dict", "matching_cluster_idx": 6}, {"solution": "from collections import defaultdict\ndef frequency_lists(lists_of_lists):\n frequency_dict = defaultdict(int)\n\n # Flatten the list of lists\n for sublist in lists_of_lists:\n for element in sublist:\n frequency_dict[element] += 1\n\n return dict(frequency_dict)", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lists):\n frequency_dict = {}\n\n for sublist in lists:\n for item in sublist:\n if item in frequency_dict:\n frequency_dict[item] += 1\n else:\n frequency_dict[item] = 1\n\n return frequency_dict", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lists):\n \"\"\"\n Flattens the list of lists and counts the frequency of each element.\n\n Parameters:\n lists (list of lists): The input list of lists.\n\n Returns:\n dict: A dictionary with elements as keys and their frequencies as values.\n \"\"\"\n flat_list = [item for sublist in lists for item in sublist]\n frequency = {}\n for item in flat_list:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n return frequency", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lists):\n frequency = {}\n for sublist in lists:\n for item in sublist:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n return frequency", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lists):\n \"\"\"\n Function to find the frequency of each element in a flattened list of lists,\n returned in a dictionary.\n\n :param lists: List of lists containing integers\n :return: Dictionary with integers as keys and their frequencies as values\n \"\"\"\n # Flatten the list of lists\n flat_list = [item for sublist in lists for item in sublist]\n\n # Create a dictionary to store frequencies\n frequency_dict = {}\n\n # Count the frequency of each element\n for item in flat_list:\n if item in frequency_dict:\n frequency_dict[item] += 1\n else:\n frequency_dict[item] = 1\n\n return frequency_dict", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(nested_list):\n frequency_dict = {}\n\n # Flatten the list of lists\n for sublist in nested_list:\n for element in sublist:\n if element in frequency_dict:\n frequency_dict[element] += 1\n else:\n frequency_dict[element] = 1\n\n return frequency_dict", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lists):\n # Flatten the list of lists\n flattened = [item for sublist in lists for item in sublist]\n # Create a dictionary to count the frequencies\n frequency = {}\n for item in flattened:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n return frequency", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lists):\n frequency_dict = {}\n for sublist in lists:\n for item in sublist:\n if item in frequency_dict:\n frequency_dict[item] += 1\n else:\n frequency_dict[item] = 1\n return frequency_dict", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(nested_list):\n \"\"\"\n This function takes a list of lists and returns a dictionary with the frequency of each element in the flattened list.\n \"\"\"\n # Initialize an empty dictionary to store frequencies\n frequency_dict = {}\n\n # Flatten the list of lists\n for sublist in nested_list:\n for item in sublist:\n # Update the dictionary with the frequency of each item\n if item in frequency_dict:\n frequency_dict[item] += 1\n else:\n frequency_dict[item] = 1\n\n return frequency_dict", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lists_of_lists):\n frequency_dict = {}\n for sublist in lists_of_lists:\n for item in sublist:\n if item in frequency_dict:\n frequency_dict[item] += 1\n else:\n frequency_dict[item] = 1\n return frequency_dict", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(nested_list):\n \"\"\"\n Flattens a list of lists and returns a dictionary with the frequency of each element.\n\n Args:\n nested_list (list of list of int): The list of lists to be flattened.\n\n Returns:\n dict: A dictionary where the keys are the elements from the flattened list and the values are their frequencies.\n \"\"\"\n # Flatten the nested list\n flattened = [item for sublist in nested_list for item in sublist]\n\n # Calculate frequencies\n frequency_dict = {}\n for item in flattened:\n if item in frequency_dict:\n frequency_dict[item] += 1\n else:\n frequency_dict[item] = 1\n\n return frequency_dict", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lists_of_lists):\n # Flatten the list of lists into a single list\n flattened_list = [item for sublist in lists_of_lists for item in sublist]\n\n # Create a dictionary to store the frequency of each element\n frequency_dict = {}\n\n for item in flattened_list:\n if item in frequency_dict:\n frequency_dict[item] += 1\n else:\n frequency_dict[item] = 1\n\n return frequency_dict", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(nested_list):\n flattened_list = [item for sublist in nested_list for item in sublist]\n frequency = {}\n for item in flattened_list:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n return frequency\nnested_list = [[1, 2, 3, 2], [4, 5, 6, 2], [7, 8, 9, 5]]", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lists):\n # Initialize an empty dictionary to store the frequency of each element\n frequency_dict = {}\n\n # Loop through each sublist in the main list\n for sublist in lists:\n # Loop through each element in the sublist\n for element in sublist:\n # If the element is already in the dictionary, increment its count\n if element in frequency_dict:\n frequency_dict[element] += 1\n # If the element is not in the dictionary, add it with a count of 1\n else:\n frequency_dict[element] = 1\n\n return frequency_dict", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lists):\n # Initialize an empty dictionary to store frequencies\n frequency_dict = {}\n\n # Flatten the list of lists\n flattened_list = [item for sublist in lists for item in sublist]\n\n # Calculate frequency of each element\n for item in flattened_list:\n if item in frequency_dict:\n frequency_dict[item] += 1\n else:\n frequency_dict[item] = 1\n\n return frequency_dict", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lists):\n # Initialize an empty dictionary to store the frequency of each element\n frequency_dict = {}\n\n # Flatten the list of lists and compute the frequency of each element\n for sublist in lists:\n for item in sublist:\n if item in frequency_dict:\n frequency_dict[item] += 1\n else:\n frequency_dict[item] = 1\n\n return frequency_dict", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(lists):\n # Initialize an empty dictionary to store the frequencies\n frequency_dict = {}\n\n # Iterate over each sublist in the list of lists\n for sublist in lists:\n # Iterate over each element in the sublist\n for element in sublist:\n # If the element is already in the dictionary, increment its count\n if element in frequency_dict:\n frequency_dict[element] += 1\n # If the element is not in the dictionary, add it with a count of 1\n else:\n frequency_dict[element] = 1\n\n return frequency_dict", "matching_cluster_idx": 6}, {"solution": "def frequency_lists(flattened_lists):\n frequency_dict = {}\n\n # Flatten the list of lists\n for sublist in flattened_lists:\n for item in sublist:\n if item in frequency_dict:\n frequency_dict[item] += 1\n else:\n frequency_dict[item] = 1\n\n return frequency_dict", "matching_cluster_idx": 6}]}, "Mbpp/106": {"dps": 78.47402597402598, "dps_norm": 90.83333333333333, "pass@1": 86.0, "profiled": [{"solution": "def add_lists(lst, tup):\n # Convert the tuple to a list, append the given list, then convert back to a tuple\n new_list = list(tup)\n new_list.extend(lst)\n return tuple(new_list)", "matching_cluster_idx": 4}, {"solution": "def add_lists(lst, tpl):\n \"\"\"\n Append the given list to the given tuple.\n\n Parameters:\n lst (list): The list to append.\n tpl (tuple): The tuple to which the list will be appended.\n\n Returns:\n tuple: A new tuple with the list appended.\n \"\"\"\n # Convert the list to a tuple and concatenate it with the original tuple\n return tpl + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tpl):\n \"\"\"\n Appends the given list to the given tuple and returns the resulting tuple.\n\n :param lst: List to be appended to the tuple\n :param tpl: Tuple to which the list is appended\n :return: A new tuple with the elements of the tuple followed by the elements of the list\n \"\"\"\n # Convert the tuple to a list, append the list to it, and convert it back to a tuple\n return tuple(list(tpl) + lst)", "matching_cluster_idx": 2}, {"solution": "def add_lists(lst, tup):\n # Converts tuple to list, appends list elements, and then converts back to tuple\n return tuple(list(tup) + lst)", "matching_cluster_idx": 3}, {"solution": "def add_lists(lst, tup):\n \"\"\"\n Appends the given list to the given tuple.\n\n :param lst: List to be appended.\n :param tup: Tuple to which the list will be appended.\n :return: A new tuple with the elements of the original tuple followed by the elements of the list.\n \"\"\"\n return tup + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tpl):\n # Convert the tuple to a list, append the elements of the list, and then convert it back to a tuple\n new_tuple = tpl + tuple(lst)\n return new_tuple", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tup):\n # Convert the tuple to a list, append the given list, and then convert back to a tuple\n return tuple(list(tup) + lst)", "matching_cluster_idx": 3}, {"solution": "def add_lists(lst, tup):\n return tup + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tpl):\n \"\"\"\n This function appends the given list to the given tuple and returns a new tuple.\n \"\"\"\n # Converting tuple to list, appending list elements, and then converting back to tuple\n new_tuple = tpl + tuple(lst)\n return new_tuple", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tup):\n return tup + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tpl):\n return tpl + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tup):\n \"\"\"\n Append the given list to the given tuple.\n\n Parameters:\n lst (list): The list to be appended to the tuple.\n tup (tuple): The tuple to which the list will be appended.\n\n Returns:\n tuple: A new tuple with the list elements appended to the original tuple.\n \"\"\"\n return tup + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tpl):\n \"\"\"\n Append the given list to the given tuple.\n\n Parameters:\n lst (list): The list to append.\n tpl (tuple): The tuple to append the list to.\n\n Returns:\n tuple: A new tuple with the original tuple elements followed by the list elements.\n \"\"\"\n return tpl + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tup):\n \"\"\"\n Appends the given list to the given tuple and returns a new tuple.\n\n :param lst: list of elements to append\n :param tup: tuple to which the list elements are appended\n :return: a new tuple with elements from the original tuple followed by elements from the list\n \"\"\"\n return tup + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tup):\n return tup + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tpl):\n return tpl + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tpl):\n \"\"\"\n Appends the given list to the given tuple and returns a new tuple.\n\n :param lst: List of elements to be appended.\n :param tpl: Original tuple.\n :return: A new tuple that includes elements from both the list and the original tuple.\n \"\"\"\n return tpl + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tup):\n \"\"\"\n Appends the given list to the given tuple.\n\n :param lst: List of elements to be appended to the tuple.\n :param tup: Tuple to which the list elements are to be appended.\n :return: A new tuple with the elements of the tuple followed by the elements of the list.\n \"\"\"\n return tup + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tup):\n return tup + tuple(lst)", "matching_cluster_idx": 5}, {"solution": "def add_lists(lst, tup):\n # Convert the tuple to a list, append the given list, and convert back to a tuple\n result = list(tup) + lst\n return tuple(result)", "matching_cluster_idx": 2}]}, "Mbpp/108": {"dps": 84.09638554216868, "dps_norm": 98.18181818181819, "pass@1": 53.0, "profiled": [{"solution": "def merge_sorted_list(list1, list2, list3):\n # Merge the three lists into one\n merged_list = list1 + list2 + list3\n\n # Sort the merged list\n merged_list.sort()\n\n return merged_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n \"\"\"\n Merges three sorted lists into a single sorted list.\n\n :param list1: First sorted list\n :param list2: Second sorted list\n :param list3: Third sorted list\n :return: A single sorted list that is a merge of the three input lists\n \"\"\"\n # Merging three lists into one\n merged_list = list1 + list2 + list3\n # Sorting the merged list\n merged_list.sort()\n return merged_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Merge the three lists into one\n merged_list = list1 + list2 + list3\n\n # Sort the merged list\n merged_list.sort()\n\n return merged_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Combine all three lists into one\n combined = list1 + list2 + list3\n\n # Sort the combined list\n combined.sort()\n\n return combined", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Combine the lists into a single list\n merged_list = list1 + list2 + list3\n\n # Sort the combined list\n merged_list.sort()\n\n return merged_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Merging three lists into one\n merged_list = list1 + list2 + list3\n\n # Sorting the merged list\n merged_list.sort()\n\n return merged_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Merge the three lists into one\n merged_list = list1 + list2 + list3\n\n # Sort the merged list\n merged_list.sort()\n\n return merged_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Merge the three lists into one\n merged_list = list1 + list2 + list3\n\n # Sort the merged list\n sorted_list = sorted(merged_list)\n\n return sorted_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(l1, l2, l3):\n merged_list = l1 + l2 + l3\n merged_list.sort()\n return merged_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Merge the three lists into one\n combined_list = list1 + list2 + list3\n\n # Sort the combined list\n combined_list.sort()\n\n return combined_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(*lists):\n merged_list = sorted(list(sum(lists, [])))\n return merged_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n merged_list = list1 + list2 + list3\n merged_list.sort()\n return merged_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(*lists):\n # Flatten all lists into one\n flattened_list = [item for sublist in lists for item in sublist]\n\n # Sort the flattened list\n flattened_list.sort()\n\n return flattened_list", "matching_cluster_idx": 9}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Combine the lists\n combined_list = list1 + list2 + list3\n\n # Sort the combined list\n combined_list.sort()\n\n return combined_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(*lists):\n # Flatten the list of lists into a single list\n flat_list = [item for sublist in lists for item in sublist]\n\n # Sort the flattened list\n sorted_list = sorted(flat_list)\n\n return sorted_list", "matching_cluster_idx": 9}, {"solution": "def merge_sorted_list(*lists):\n # Flatten the lists into a single list\n flat_list = [item for sublist in lists for item in sublist]\n\n # Sort the flattened list\n flat_list.sort()\n\n return flat_list", "matching_cluster_idx": 9}, {"solution": "def merge_sorted_list(*lists):\n # Flatten the list of lists into a single list\n flat_list = [item for sublist in lists for item in sublist]\n\n # Sort the flattened list\n flat_list.sort()\n\n return flat_list", "matching_cluster_idx": 9}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Merge the three lists into one\n combined_list = list1 + list2 + list3\n\n # Sort the combined list\n sorted_list = sorted(combined_list)\n\n return sorted_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n merged_list = sorted(list1 + list2 + list3)\n return merged_list", "matching_cluster_idx": 10}, {"solution": "def merge_sorted_list(list1, list2, list3):\n # Combine all three lists\n combined_list = list1 + list2 + list3\n\n # Sort the combined list\n combined_list.sort()\n\n return combined_list", "matching_cluster_idx": 10}]}, "Mbpp/111": {"dps": 76.1076923076923, "dps_norm": 80.0, "pass@1": 64.0, "profiled": [{"solution": "def common_in_nested_lists(nested_lists):\n \"\"\"\n This function finds the common elements in the given nested lists.\n\n Args:\n nested_lists (list of list of int): List of lists containing integers.\n\n Returns:\n set: A set of common elements in the nested lists.\n \"\"\"\n if not nested_lists:\n return set()\n\n # Get the first list to initialize the common elements set\n common_elements = set(nested_lists[0])\n\n for lst in nested_lists[1:]:\n common_elements.intersection_update(lst)\n\n return common_elements\nnested_lists = [[12, 18, 23, 25, 45], [7, 12, 18, 24, 28], [1, 5, 8, 12, 15, 16, 18]]", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n # Create a set from the first list in the nested lists\n common_set = set(nested_lists[0])\n\n # Iterate through the remaining lists and find the intersection with the common_set\n for sublist in nested_lists[1:]:\n common_set &= set(sublist)\n\n return list(common_set)", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n # Flatten the nested lists into a single list\n flat_list = [item for sublist in nested_lists for item in sublist]\n\n # Convert the list to a set to find unique elements\n flat_set = set(flat_list)\n\n # Find common elements by intersecting the set with the sublist sets\n common_elements = set.intersection(*[set(sublist) for sublist in nested_lists])\n\n return common_elements", "matching_cluster_idx": 2}, {"solution": "from typing import List\ndef common_in_nested_lists(nested_lists: List[List[int]]) -> set:\n if not nested_lists:\n return set()\n\n # Find the common elements by reducing the nested lists\n common = set(nested_lists[0])\n for lst in nested_lists[1:]:\n common &= set(lst)\n\n return common", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n # Create an empty set to store the common elements\n common_elements = set()\n\n # Get the first list to initialize the set of common elements\n if nested_lists:\n common_elements = set(nested_lists[0])\n\n # Iterate over each list in the nested lists\n for lst in nested_lists[1:]:\n common_elements &= set(lst)\n\n return common_elements\nnested_lists = [[12, 18, 23, 25, 45], [7, 12, 18, 24, 28], [1, 5, 8, 12, 15, 16, 18]]", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef common_in_nested_lists(nested_lists: List[List[int]]) -> set:\n if not nested_lists or not all(nested_lists):\n return set()\n\n common_elements = set(nested_lists[0])\n\n for lst in nested_lists[1:]:\n common_elements &= set(lst)\n\n return common_elements", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef common_in_nested_lists(nested_lists: List[List[int]]) -> set:\n if not nested_lists:\n return set()\n\n # Convert the first list to a set\n common_elements = set(nested_lists[0])\n\n # Iterate through the rest of the lists\n for lst in nested_lists[1:]:\n common_elements &= set(lst)\n\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n # Find the intersection of all sets of elements in the nested lists\n common_elements = set(nested_lists[0])\n for lst in nested_lists[1:]:\n common_elements.intersection_update(lst)\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n # Initialize an empty set for common elements\n common_set = set(nested_lists[0])\n\n # Iterate through each list in the nested lists\n for lst in nested_lists[1:]:\n # Update the common set with intersection of current list and common set\n common_set = common_set.intersection(set(lst))\n\n # Convert the set back to a list\n return list(common_set)", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n \"\"\"\n Find common elements in given nested lists.\n\n Args:\n nested_lists (list of list of int): List containing multiple lists of integers.\n\n Returns:\n set of int: Set of common integers present in all the lists.\n \"\"\"\n if not nested_lists:\n return set()\n\n # Find the intersection of sets created from each list\n common_elements = set(nested_lists[0])\n for lst in nested_lists[1:]:\n common_elements &= set(lst)\n\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n \"\"\"\n Find the common elements in given nested lists.\n\n Args:\n nested_lists (list of list of int): List of lists containing integers.\n\n Returns:\n set: A set of common integers across all lists.\n \"\"\"\n if not nested_lists:\n return set()\n\n # Flatten the nested lists and find common elements\n common_elements = set(nested_lists[0])\n for lst in nested_lists[1:]:\n common_elements &= set(lst)\n\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n # Initialize a set with the elements of the first list\n common_elements = set(nested_lists[0])\n\n # Iterate over the rest of the nested lists\n for lst in nested_lists[1:]:\n # Find the intersection with the current set of common elements\n common_elements &= set(lst)\n\n return list(common_elements)", "matching_cluster_idx": 6}, {"solution": "from collections.abc import Iterable\ndef common_in_nested_lists(nested_lists):\n if not all(isinstance(lst, Iterable) for lst in nested_lists):\n raise TypeError(\"All elements of nested_lists must be iterable\")\n\n if not nested_lists:\n return set()\n\n common_elements = nested_lists[0]\n for lst in nested_lists[1:]:\n common_elements = set(common_elements) & set(lst)\n\n return common_elements", "matching_cluster_idx": 5}, {"solution": "def common_in_nested_lists(nested_lists):\n # Convert all lists to sets\n sets_of_lists = [set(nested_list) for nested_list in nested_lists]\n\n # Find the intersection of all sets\n common_elements = set.intersection(*sets_of_lists)\n\n return common_elements", "matching_cluster_idx": 4}, {"solution": "from typing import List, Set\ndef common_in_nested_lists(nested_lists: List[List[int]]) -> Set[int]:\n \"\"\"\n Find the common elements in a list of nested lists.\n\n Parameters:\n nested_lists (List[List[int]]): List of lists containing integers.\n\n Returns:\n Set[int]: A set of common integers present in all lists.\n \"\"\"\n if not nested_lists:\n return set()\n\n # Find the common elements by intersecting all the sets of lists\n common_elements = set(nested_lists[0])\n for lst in nested_lists[1:]:\n common_elements &= set(lst)\n\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n # Flatten the nested lists into a single set\n flat_list = set()\n for lst in nested_lists:\n flat_list.update(lst)\n\n # If there is only one list, return it as a set\n if len(nested_lists) == 1:\n return set(nested_lists[0])\n\n # Find the common elements\n common_elements = set()\n for item in flat_list:\n if all(item in lst for lst in nested_lists):\n common_elements.add(item)\n\n return common_elements", "matching_cluster_idx": 4}, {"solution": "def common_in_nested_lists(nested_lists):\n \"\"\"\n Function to find common elements in given nested lists.\n\n Args:\n nested_lists (list of lists): A list of lists containing integers.\n\n Returns:\n set: A set containing the common elements.\n \"\"\"\n # Reduce the nested lists to a single set of elements\n flat_list = [item for sublist in nested_lists for item in sublist]\n\n # Find the intersection of all sets formed by the elements of the nested lists\n common_elements = set(flat_list)\n\n # Check each sublist to ensure the common elements appear in all\n for sublist in nested_lists:\n common_elements &= set(sublist)\n\n return common_elements", "matching_cluster_idx": 3}, {"solution": "def common_in_nested_lists(nested_lists):\n if not nested_lists:\n return set()\n\n # Find the intersection of all sets in the nested lists\n common_elements = set(nested_lists[0])\n for lst in nested_lists[1:]:\n common_elements.intersection_update(lst)\n\n return common_elements", "matching_cluster_idx": 6}, {"solution": "from typing import List\ndef common_in_nested_lists(nested_lists: List[List[int]]) -> set:\n if not nested_lists:\n return set()\n\n # Convert the first list to a set for easier intersection\n common_elements = set(nested_lists[0])\n\n # Intersect with the rest of the lists\n for sublist in nested_lists[1:]:\n common_elements &= set(sublist)\n\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def common_in_nested_lists(nested_lists):\n # Create a set for the first list to initialize the comparison\n common_elements = set(nested_lists[0])\n\n # Iterate over the remaining lists\n for lst in nested_lists[1:]:\n # Find the intersection of the current set of common elements and the current list\n common_elements &= set(lst)\n\n return list(common_elements)", "matching_cluster_idx": 6}]}, "Mbpp/123": {"dps": 99.62686567164178, "dps_norm": 85.71428571428571, "pass@1": 27.0, "profiled": [{"solution": "def sum_of_divisors(n):\n \"\"\"Returns the sum of proper divisors of n (excluding n itself).\"\"\"\n sum_divisors = 1\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n sum_divisors += i\n if i != n // i:\n sum_divisors += n // i\n return sum_divisors\ndef amicable_numbers_sum(limit):\n \"\"\"Returns the sum of all amicable numbers from 1 to limit.\"\"\"\n sum_of_amicable = 0\n for i in range(2, limit):\n divisors_sum = sum_of_divisors(i)\n if divisors_sum != i and divisors_sum < limit and sum_of_divisors(divisors_sum) == i:\n sum_of_amicable += i\n return sum_of_amicable", "matching_cluster_idx": 11}, {"solution": "def sum_of_divisors(n):\n \"\"\"Returns the sum of proper divisors of n.\"\"\"\n sum_divisors = 1\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n sum_divisors += i\n if i != n // i:\n sum_divisors += n // i\n return sum_divisors\ndef amicable_numbers_sum(limit):\n \"\"\"Returns the sum of all amicable numbers between 1 and limit (inclusive).\"\"\"\n sum_amicable = 0\n for i in range(2, limit + 1):\n sum_div_i = sum_of_divisors(i)\n sum_div_j = sum_of_divisors(sum_div_i)\n if i != sum_div_i and i == sum_div_j:\n sum_amicable += i\n return sum_amicable", "matching_cluster_idx": 11}, {"solution": "def sum_divisors(n):\n \"\"\"Function to return the sum of divisors of a number.\"\"\"\n divisors_sum = 1 # Every number is divisible by 1\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n divisors_sum += i\n if i != n // i:\n divisors_sum += n // i\n return divisors_sum\ndef amicable_numbers_sum(limit):\n \"\"\"Function to sum all amicable numbers from 1 to the specified limit.\"\"\"\n amicable_sum = 0\n for i in range(2, limit + 1):\n sum_div = sum_divisors(i)\n if sum_div != i and sum_div <= limit and sum_divisors(sum_div) == i:\n amicable_sum += i\n return amicable_sum", "matching_cluster_idx": 11}, {"solution": "def sum_of_divisors(n):\n \"\"\"Calculates the sum of divisors of n, excluding n itself.\"\"\"\n sum_div = 1 # 1 is a divisor of any number\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n sum_div += i\n if i != n // i:\n sum_div += n // i\n return sum_div\ndef amicable_numbers_sum(limit):\n \"\"\"Returns the sum of all amicable numbers from 1 to the specified limit.\"\"\"\n total_sum = 0\n for i in range(2, limit + 1):\n sum_i = sum_of_divisors(i)\n sum_sum_i = sum_of_divisors(sum_i)\n if i != sum_i and i == sum_sum_i:\n total_sum += i\n return total_sum", "matching_cluster_idx": 11}, {"solution": "def sum_of_divisors(n):\n sum = 1\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n sum += i\n if i != n // i:\n sum += n // i\n return sum\ndef amicable_numbers_sum(limit):\n sum_of_amicable_numbers = 0\n for i in range(2, limit + 1):\n div_sum = sum_of_divisors(i)\n if div_sum > i and div_sum < limit and sum_of_divisors(div_sum) == i:\n sum_of_amicable_numbers += i + div_sum\n return sum_of_amicable_numbers", "matching_cluster_idx": 11}, {"solution": "def sum_of_proper_divisors(n):\n \"\"\"Return the sum of all proper divisors of n.\"\"\"\n sum_divisors = 1\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n sum_divisors += i\n if i != n // i:\n sum_divisors += n // i\n return sum_divisors\ndef amicable_numbers_sum(limit):\n \"\"\"Return the sum of all amicable numbers up to the specified limit.\"\"\"\n amicable_sum = 0\n for i in range(2, limit + 1):\n divisors_sum = sum_of_proper_divisors(i)\n if i != divisors_sum and divisors_sum <= limit and sum_of_proper_divisors(divisors_sum) == i:\n amicable_sum += i\n return amicable_sum", "matching_cluster_idx": 11}, {"solution": "def sum_of_divisors(n):\n \"\"\"Return the sum of divisors of n.\"\"\"\n sum_div = 1\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n sum_div += i\n if i != n // i:\n sum_div += n // i\n return sum_div\ndef amicable_numbers_sum(limit):\n \"\"\"Return the sum of all amicable numbers up to the specified limit.\"\"\"\n total_sum = 0\n for num in range(2, limit + 1):\n divisor_sum = sum_of_divisors(num)\n if divisor_sum != num and divisor_sum <= limit and sum_of_divisors(divisor_sum) == num:\n total_sum += num\n return total_sum", "matching_cluster_idx": 11}, {"solution": "def sum_of_divisors(n):\n divisors = [1]\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n divisors.append(i)\n if i != n // i:\n divisors.append(n // i)\n return sum(divisors)\ndef amicable_numbers_sum(limit):\n total = 0\n for i in range(2, limit):\n sum_div_i = sum_of_divisors(i)\n if sum_div_i != i and sum_div_i < limit and sum_of_divisors(sum_div_i) == i:\n total += i\n return total", "matching_cluster_idx": 11}, {"solution": "def sum_of_proper_divisors(n):\n \"\"\"Returns the sum of all proper divisors of n (excluding n itself).\"\"\"\n total = 1 # 1 is a proper divisor of any n > 1\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n total += i\n if i != n // i:\n total += n // i\n return total\ndef amicable_numbers_sum(limit):\n \"\"\"Returns the sum of all amicable numbers from 1 to the specified limit.\"\"\"\n total_sum = 0\n for i in range(2, limit + 1):\n sum_divisors_i = sum_of_proper_divisors(i)\n sum_divisors_sum_divisors_i = sum_of_proper_divisors(sum_divisors_i)\n if i != sum_divisors_i and i == sum_divisors_sum_divisors_i:\n total_sum += i\n return total_sum", "matching_cluster_idx": 11}, {"solution": "def sum_of_divisors(n):\n \"\"\" Helper function to calculate the sum of divisors of n (excluding n itself) \"\"\"\n sum_div = 1\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n sum_div += i\n if i != n // i:\n sum_div += n // i\n return sum_div\ndef amicable_numbers_sum(limit):\n \"\"\" Function to sum all amicable numbers from 1 to a specified number \"\"\"\n total_sum = 0\n for i in range(2, limit + 1):\n sum_div_i = sum_of_divisors(i)\n sum_div_sum_div_i = sum_of_divisors(sum_div_i)\n if sum_div_i != i and sum_div_i < limit and sum_div_sum_div_i == i:\n total_sum += i\n return total_sum", "matching_cluster_idx": 11}, {"solution": "def sum_of_proper_divisors(n):\n \"\"\"Calculate the sum of proper divisors of a number.\"\"\"\n sum = 1\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n sum += i\n if i != n // i:\n sum += n // i\n return sum\ndef is_amicable(n):\n \"\"\"Check if a number is amicable.\"\"\"\n if n < 2:\n return False\n m = sum_of_proper_divisors(n)\n return m != n and sum_of_proper_divisors(m) == n\ndef amicable_numbers_sum(limit):\n \"\"\"Sum all amicable numbers from 1 to a specified number.\"\"\"\n return sum(x for x in range(1, limit + 1) if is_amicable(x))", "matching_cluster_idx": 11}, {"solution": "def sum_of_divisors(n):\n sum_div = 1 # 1 is always a divisor of any number\n sqrtn = int(n**0.5)\n for i in range(2, sqrtn + 1):\n if n % i == 0:\n sum_div += i\n if i != n // i:\n sum_div += n // i\n return sum_div\ndef amicable_numbers_sum(limit):\n total = 0\n for i in range(2, limit + 1):\n sum_div_i = sum_of_divisors(i)\n sum_div_sum_div_i = sum_of_divisors(sum_div_i)\n if sum_div_sum_div_i == i and sum_div_i != i:\n total += i\n return total", "matching_cluster_idx": 11}, {"solution": "def sum_of_proper_divisors(n):\n \"\"\"Calculate the sum of all proper divisors of n.\"\"\"\n sum_divisors = 1\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n sum_divisors += i\n if i != n // i:\n sum_divisors += n // i\n return sum_divisors\ndef amicable_numbers_sum(limit):\n \"\"\"Sum all amicable numbers from 1 to the specified limit.\"\"\"\n amicable_sum = 0\n for i in range(2, limit):\n divisor_sum = sum_of_proper_divisors(i)\n if i != divisor_sum and divisor_sum <= limit and sum_of_proper_divisors(divisor_sum) == i:\n amicable_sum += i\n return amicable_sum", "matching_cluster_idx": 11}, {"solution": "def sum_of_divisors(n):\n \"\"\"\n Returns the sum of all proper divisors of n.\n \"\"\"\n sum_divisors = 1 # 1 is a divisor of every number\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n sum_divisors += i\n if i != n // i:\n sum_divisors += n // i\n return sum_divisors\ndef amicable_numbers_sum(limit):\n \"\"\"\n Returns the sum of all amicable numbers from 1 to the specified limit.\n \"\"\"\n total_sum = 0\n for i in range(2, limit + 1):\n sum_divisors_i = sum_of_divisors(i)\n sum_divisors_sum_divisors_i = sum_of_divisors(sum_divisors_i)\n if i != sum_divisors_i and i == sum_divisors_sum_divisors_i:\n total_sum += i\n return total_sum", "matching_cluster_idx": 11}, {"solution": "def sum_of_proper_divisors(n):\n \"\"\"Returns the sum of proper divisors of n (excluding n itself).\"\"\"\n divisors_sum = 1\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n divisors_sum += i\n if i != n // i:\n divisors_sum += n // i\n return divisors_sum\ndef amicable_numbers_sum(limit):\n \"\"\"Returns the sum of all amicable numbers up to the specified limit.\"\"\"\n total_sum = 0\n for i in range(2, limit + 1):\n sum_i = sum_of_proper_divisors(i)\n sum_sum_i = sum_of_proper_divisors(sum_i)\n if sum_i > limit or sum_sum_i > limit:\n continue\n if i != sum_i and i == sum_sum_i:\n total_sum += i\n return total_sum", "matching_cluster_idx": 11}, {"solution": "def sum_of_divisors(n):\n \"\"\"Returns the sum of divisors of n.\"\"\"\n sum_divisors = 1 # 1 is a divisor of any number\n sqrt_n = int(n**0.5)\n for i in range(2, sqrt_n + 1):\n if n % i == 0:\n sum_divisors += i\n if i != n // i:\n sum_divisors += n // i\n return sum_divisors\ndef amicable_numbers_sum(limit):\n \"\"\"Returns the sum of all amicable numbers from 1 to limit.\"\"\"\n amicable_sum = 0\n for i in range(2, limit + 1):\n sum_divisors_i = sum_of_divisors(i)\n sum_divisors_j = sum_of_divisors(sum_divisors_i)\n if i != sum_divisors_i and i == sum_divisors_j:\n amicable_sum += i\n return amicable_sum", "matching_cluster_idx": 11}, {"solution": "def sum_of_divisors(n):\n \"\"\"\n Calculates the sum of proper divisors of n.\n \"\"\"\n sum_divisors = 1\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n sum_divisors += i\n if i != n // i:\n sum_divisors += n // i\n return sum_divisors\ndef amicable_numbers_sum(limit):\n \"\"\"\n Returns the sum of all amicable numbers from 1 to the specified number.\n \"\"\"\n total_sum = 0\n for i in range(2, limit + 1):\n sum_div_i = sum_of_divisors(i)\n sum_div_sum_div_i = sum_of_divisors(sum_div_i)\n if i != sum_div_i and i == sum_div_sum_div_i:\n total_sum += i\n return total_sum", "matching_cluster_idx": 11}, {"solution": "def sum_of_divisors(n):\n \"\"\"Calculate the sum of proper divisors of n (excluding n itself).\"\"\"\n total = 1 # 1 is a proper divisor of every integer > 1\n sqrt_n = int(n**0.5)\n for i in range(2, sqrt_n + 1):\n if n % i == 0:\n total += i\n if i != n // i:\n total += n // i\n return total\ndef amicable_numbers_sum(limit):\n \"\"\"Sum all amicable numbers from 1 to the specified limit.\"\"\"\n total_sum = 0\n for i in range(2, limit + 1):\n sum_divisors_i = sum_of_divisors(i)\n sum_divisors_j = sum_of_divisors(sum_divisors_i)\n if i != sum_divisors_i and i == sum_divisors_j and sum_divisors_i < limit:\n total_sum += i\n return total_sum", "matching_cluster_idx": 11}, {"solution": "def amicable_numbers_sum(limit):\n def sum_of_divisors(n):\n # Calculate the sum of proper divisors of n\n sum_divisors = 1 # 1 is a proper divisor of any n > 1\n for i in range(2, int(n**0.5) + 1):\n if n % i == 0:\n sum_divisors += i\n if i != n // i:\n sum_divisors += n // i\n return sum_divisors\n\n def is_amicable(n):\n # Check if n is amicable\n return sum_of_divisors(n) != n and sum_of_divisors(sum_of_divisors(n)) == n\n\n # Sum all amicable numbers from 1 to limit\n return sum(i for i in range(2, limit + 1) if is_amicable(i))", "matching_cluster_idx": 11}, {"solution": "def sum_of_divisors(n):\n \"\"\"\n Return the sum of proper divisors of n (excluding n itself).\n \"\"\"\n sum = 1\n sqrt_n = int(n**0.5)\n for i in range(2, sqrt_n + 1):\n if n % i == 0:\n sum += i\n if i != n // i:\n sum += n // i\n return sum\ndef amicable_numbers_sum(limit):\n \"\"\"\n Return the sum of all amicable numbers from 1 to the specified limit.\n \"\"\"\n total_sum = 0\n for i in range(2, limit):\n divisor_sum = sum_of_divisors(i)\n if i != divisor_sum and divisor_sum <= limit and divisor_sum != 0 and sum_of_divisors(divisor_sum) == i:\n total_sum += i\n return total_sum", "matching_cluster_idx": 11}]}, "Mbpp/128": {"dps": 99.5475113122172, "dps_norm": 80.0, "pass@1": 100.0, "profiled": [{"solution": "def long_words(n, s):\n words = s.split()\n return [word for word in words if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, text):\n # Split the text into words\n words = text.split()\n\n # Filter words that are longer than n characters\n result = [word for word in words if len(word) > n]\n\n return result", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n \"\"\"\n Function to find words that are longer than n characters from a given sentence.\n\n Parameters:\n n (int): The minimum length of the words to include.\n sentence (str): The sentence from which to extract words.\n\n Returns:\n list: A list of words that are longer than n characters.\n \"\"\"\n words = sentence.split()\n long_words_list = [word for word in words if len(word) > n]\n return long_words_list", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n # Split the sentence into words\n words = sentence.split()\n\n # Filter out words that are longer than n characters\n result = [word for word in words if len(word) > n]\n\n return result", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n # Split the sentence into words\n words = sentence.split()\n\n # Filter words that are longer than n characters\n long_words_list = [word for word in words if len(word) > n]\n\n return long_words_list", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n # Split the sentence into a list of words\n words = sentence.split()\n # Filter words that are longer than n characters\n long_words_list = [word for word in words if len(word) > n]\n return long_words_list", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n # Split the sentence into words\n words = sentence.split()\n\n # Filter words that are longer than n characters\n long_words_list = [word for word in words if len(word) > n]\n\n return long_words_list", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n words = sentence.split()\n return [word for word in words if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, text):\n # Split the input text into words\n words = text.split()\n\n # Filter out words that are not longer than n characters\n long_words_list = [word for word in words if len(word) > n]\n\n return long_words_list", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n \"\"\"\n Function to find words that are longer than n characters from a given sentence.\n\n Parameters:\n n (int): The length of the words to filter.\n sentence (str): The sentence to check for long words.\n\n Returns:\n list: A list of words that are longer than n characters.\n \"\"\"\n # Split the sentence into words\n words = sentence.split()\n\n # Filter words that are longer than n characters\n long_words_list = [word for word in words if len(word) > n]\n\n return long_words_list", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n \"\"\"\n Find words that are longer than n characters from a given sentence.\n\n Parameters:\n n (int): The minimum length of words to be returned.\n sentence (str): The input sentence to search words from.\n\n Returns:\n list: A list of words that are longer than n characters.\n \"\"\"\n # Split the sentence into words\n words = sentence.split()\n\n # Filter words based on the length\n result = [word for word in words if len(word) > n]\n\n return result", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n # Split the sentence into words\n words = sentence.split()\n # Use a list comprehension to filter out words that are longer than n characters\n long_words_list = [word for word in words if len(word) > n]\n return long_words_list", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n # Split the sentence into a list of words\n words = sentence.split()\n\n # Filter out the words that are longer than n characters\n result = [word for word in words if len(word) > n]\n\n return result", "matching_cluster_idx": 3}, {"solution": "def long_words(n, text):\n # Split the text into a list of words\n words = text.split()\n # Use a list comprehension to filter words longer than n characters\n long_words_list = [word for word in words if len(word) > n]\n return long_words_list", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n # Split the sentence into words\n words = sentence.split()\n # Filter words that are longer than n characters\n longer_than_n = [word for word in words if len(word) > n]\n return longer_than_n", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n # Split the sentence into words\n words = sentence.split()\n # Use list comprehension to filter words longer than n characters\n result = [word for word in words if len(word) > n]\n return result", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n # Split the sentence into words\n words = sentence.split()\n # Filter words that are longer than n characters\n long_words_list = [word for word in words if len(word) > n]\n return long_words_list", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n words = sentence.split()\n return [word for word in words if len(word) > n]", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n \"\"\"\n Given a list of words in a sentence, return words that are longer than n characters.\n\n :param n: Minimum length of words to be included in the result\n :param sentence: String containing the list of words\n :return: List of words that are longer than n characters\n \"\"\"\n # Split the sentence into words\n words = sentence.split()\n\n # Filter the words that are longer than n characters\n long_words_list = [word for word in words if len(word) > n]\n\n return long_words_list", "matching_cluster_idx": 3}, {"solution": "def long_words(n, sentence):\n # Split the sentence into words\n words = sentence.split()\n # Use list comprehension to filter words longer than n characters\n long_words_list = [word for word in words if len(word) > n]\n return long_words_list", "matching_cluster_idx": 3}]}, "Mbpp/129": {"dps": 53.34183673469388, "dps_norm": 88.66666666666666, "pass@1": 61.0, "profiled": [{"solution": "def magic_square_test(matrix):\n def is_magic_square(matrix):\n n = len(matrix)\n target_sum = sum(sum(row) for row in matrix) // n\n\n for i in range(n):\n if sum(matrix[i][j] for j in range(n)) != target_sum:\n return False\n if sum(matrix[j][i] for j in range(n)) != target_sum:\n return False\n\n # Check diagonals\n if sum(matrix[i][i] for i in range(n)) != target_sum:\n return False\n if sum(matrix[i][n - i - 1] for i in range(n)) != target_sum:\n return False\n\n return True\n\n # Validate the input matrix\n n = len(matrix)\n if n != len(matrix[0]):\n return False\n if any(len(row) != n for row in matrix):\n return False\n\n return is_magic_square(matrix)", "matching_cluster_idx": 10}, {"solution": "def magic_square_test(matrix):\n n = len(matrix)\n if n == 0:\n return False\n\n # Sum of the first row\n row_sum = sum(matrix[0])\n\n # Check all rows\n for row in matrix:\n if sum(row) != row_sum:\n return False\n\n # Check all columns\n for col in range(n):\n col_sum = 0\n for row in range(n):\n col_sum += matrix[row][col]\n if col_sum != row_sum:\n return False\n\n # Check diagonals\n diagonal_sum = 0\n for i in range(n):\n diagonal_sum += matrix[i][i]\n if diagonal_sum != row_sum:\n return False\n\n diagonal_sum = 0\n for i in range(n):\n diagonal_sum += matrix[i][n - i - 1]\n if diagonal_sum != row_sum:\n return False\n\n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n if not matrix or not matrix[0]:\n return False\n\n n = len(matrix)\n target_sum = sum(matrix[0])\n\n def is_row_magic(matrix):\n return all(sum(row) == target_sum for row in matrix)\n\n def is_col_magic(matrix):\n return all(sum(matrix[i][j] for i in range(n)) == target_sum for j in range(n))\n\n def is_diag_magic(matrix):\n return sum(matrix[i][i] for i in range(n)) == target_sum and sum(matrix[i][n - i - 1] for i in range(n)) == target_sum\n\n return is_row_magic(matrix) and is_col_magic(matrix) and is_diag_magic(matrix)", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n # Check if the matrix is a square (same number of rows and columns)\n if len(matrix) == 0 or len(matrix) != len(matrix[0]):\n return False\n\n n = len(matrix)\n\n # Calculate the expected sum of each row, column, and diagonal\n expected_sum = sum(sum(row) for row in matrix) // n\n\n # Check rows\n for row in matrix:\n if sum(row) != expected_sum:\n return False\n\n # Check columns\n for col in range(n):\n if sum(matrix[row][col] for row in range(n)) != expected_sum:\n return False\n\n # Check diagonals\n if sum(matrix[i][i] for i in range(n)) != expected_sum:\n return False\n if sum(matrix[i][n-i-1] for i in range(n)) != expected_sum:\n return False\n\n return True", "matching_cluster_idx": 10}, {"solution": "def magic_square_test(matrix):\n # Get the order of the magic square\n n = len(matrix)\n\n # Calculate the expected sum of any row, column or diagonal\n expected_sum = sum(sum(row) for row in matrix) // n\n\n # Check rows\n for row in matrix:\n if sum(row) != expected_sum:\n return False\n\n # Check columns\n for col in range(n):\n if sum(matrix[row][col] for row in range(n)) != expected_sum:\n return False\n\n # Check main diagonal\n if sum(matrix[i][i] for i in range(n)) != expected_sum:\n return False\n\n # Check secondary diagonal\n if sum(matrix[i][n-i-1] for i in range(n)) != expected_sum:\n return False\n\n return True", "matching_cluster_idx": 10}, {"solution": "def magic_square_test(matrix):\n if not matrix or any(len(row) != len(matrix) for row in matrix):\n return False\n\n n = len(matrix)\n magic_sum = sum(sum(row) for row in matrix) // n\n\n for row in matrix:\n if sum(row) != magic_sum:\n return False\n\n for col in range(n):\n if sum(matrix[row][col] for row in range(n)) != magic_sum:\n return False\n\n if n % 2 == 0:\n if sum(matrix[i][i] for i in range(n)) != magic_sum:\n return False\n if sum(matrix[i][n - i - 1] for i in range(n)) != magic_sum:\n return False\n\n return True", "matching_cluster_idx": 10}, {"solution": "def magic_square_test(matrix):\n # Ensure it's a square matrix\n if len(matrix) == 0 or any(len(row) != len(matrix) for row in matrix):\n return False\n\n n = len(matrix)\n total_sum = sum(sum(row) for row in matrix) // n\n\n for i in range(n):\n row_sum = sum(matrix[i])\n col_sum = sum(matrix[j][i] for j in range(n))\n if row_sum != total_sum or col_sum != total_sum:\n return False\n\n # Diagonal sums\n diag1_sum = sum(matrix[i][i] for i in range(n))\n diag2_sum = sum(matrix[i][n-1-i] for i in range(n))\n if diag1_sum != total_sum or diag2_sum != total_sum:\n return False\n\n return True", "matching_cluster_idx": 10}, {"solution": "def magic_square_test(matrix):\n \"\"\"\n Function to check if the given matrix is a magic square.\n\n :param matrix: List of lists containing the matrix.\n :return: Boolean indicating whether the matrix is a magic square.\n \"\"\"\n\n # Get the order of the matrix (assuming it is a square matrix)\n n = len(matrix)\n\n # Calculate the sum of the first row (which should be constant for a magic square)\n total_sum = sum(matrix[0])\n\n # Check if all rows have the same sum\n for row in matrix:\n if sum(row) != total_sum:\n return False\n\n # Check if all columns have the same sum\n for col in range(n):\n col_sum = sum(matrix[row][col] for row in range(n))\n if col_sum != total_sum:\n return False\n\n # Check if the diagonals have the same sum\n diagonal1_sum = sum(matrix[i][i] for i in range(n))\n diagonal2_sum = sum(matrix[i][n-i-1] for i in range(n))\n if diagonal1_sum != total_sum or diagonal2_sum != total_sum:\n return False\n\n # If all checks pass, it's a magic square\n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n # A magic square is a square matrix where the sum of each row, column, and diagonal is the same.\n n = len(matrix)\n\n # Calculate the magic constant (sum of the first row)\n magic_constant = sum(matrix[0])\n\n # Check each row\n for row in matrix:\n if sum(row) != magic_constant:\n return False\n\n # Check each column\n for col in range(n):\n if sum(matrix[row][col] for row in range(n)) != magic_constant:\n return False\n\n # Check the main diagonal\n if sum(matrix[i][i] for i in range(n)) != magic_constant:\n return False\n\n # Check the secondary diagonal\n if sum(matrix[i][n - i - 1] for i in range(n)) != magic_constant:\n return False\n\n # If all conditions are met, return True\n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n # Check if the input is a square matrix\n if not all(len(row) == len(matrix) for row in matrix):\n return False\n\n n = len(matrix)\n magic_sum = sum(matrix[0])\n\n # Check rows\n for row in matrix:\n if sum(row) != magic_sum:\n return False\n\n # Check columns\n for col in range(n):\n if sum(matrix[row][col] for row in range(n)) != magic_sum:\n return False\n\n # Check diagonals\n if sum(matrix[i][i] for i in range(n)) != magic_sum:\n return False\n if sum(matrix[i][n-i-1] for i in range(n)) != magic_sum:\n return False\n\n return True", "matching_cluster_idx": 13}, {"solution": "def magic_square_test(matrix):\n if not matrix or any(len(row) != len(matrix) for row in matrix):\n return False\n\n n = len(matrix)\n sum_of_elements = sum(row[0] for row in matrix)\n\n for i in range(n):\n row_sum = sum(matrix[i])\n col_sum = sum(matrix[j][i] for j in range(n))\n if row_sum != sum_of_elements or col_sum != sum_of_elements:\n return False\n\n # Checking diagonals\n diag1 = sum(matrix[i][i] for i in range(n))\n diag2 = sum(matrix[i][n-1-i] for i in range(n))\n if diag1 != sum_of_elements or diag2 != sum_of_elements:\n return False\n\n return True\nmatrix = [\n [7, 12, 1, 14],\n [2, 13, 8, 11],\n [16, 3, 10, 5],\n [9, 6, 15, 4]\n]", "matching_cluster_idx": 13}, {"solution": "def magic_square_test(matrix):\n def is_magic(matrix):\n n = len(matrix)\n if n == 0:\n return False\n\n # Check for row sum\n row_sum = sum(matrix[0])\n\n for row in matrix:\n if sum(row) != row_sum:\n return False\n\n # Check for column sum\n for col in range(n):\n col_sum = 0\n for row in range(n):\n col_sum += matrix[row][col]\n if col_sum != row_sum:\n return False\n\n # Check for diagonal sum\n diagonal1_sum = 0\n diagonal2_sum = 0\n for i in range(n):\n diagonal1_sum += matrix[i][i]\n diagonal2_sum += matrix[i][n-i-1]\n\n return diagonal1_sum == row_sum and diagonal2_sum == row_sum\n\n return is_magic(matrix)", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n \"\"\"\n Checks if the given matrix is a magic square.\n\n A magic square is a square matrix where the sum of each row,\n each column, and both main diagonals are the same.\n \"\"\"\n n = len(matrix)\n if n == 0:\n return True # An empty matrix is considered a magic square by convention.\n\n # Calculate the sum of the first row as the magic constant\n magic_constant = sum(matrix[0])\n\n # Check rows\n for row in matrix:\n if sum(row) != magic_constant:\n return False\n\n # Check columns\n for col in range(n):\n if sum(matrix[row][col] for row in range(n)) != magic_constant:\n return False\n\n # Check main diagonals\n if sum(matrix[i][i] for i in range(n)) != magic_constant or sum(matrix[i][n-i-1] for i in range(n)) != magic_constant:\n return False\n\n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n # Check if the matrix is n x n\n n = len(matrix)\n if any(len(row) != n for row in matrix):\n return False\n\n # Calculate the magic constant\n magic_constant = sum(matrix[0])\n\n # Check rows, columns, and diagonals\n for row in matrix:\n if sum(row) != magic_constant:\n return False\n\n for col in range(n):\n if sum(matrix[row][col] for row in range(n)) != magic_constant:\n return False\n\n if sum(matrix[i][i] for i in range(n)) != magic_constant:\n return False\n if sum(matrix[i][n-i-1] for i in range(n)) != magic_constant:\n return False\n\n return True", "matching_cluster_idx": 13}, {"solution": "def magic_square_test(matrix):\n n = len(matrix)\n target_sum = sum([sum(row) for row in matrix]) // n\n\n for i in range(n):\n # Check rows and columns\n if sum(matrix[i]) != target_sum or sum([matrix[j][i] for j in range(n)]) != target_sum:\n return False\n\n # Check diagonals\n if sum([matrix[i][i] for i in range(n)]) != target_sum or sum([matrix[i][n - 1 - i] for i in range(n)]) != target_sum:\n return False\n\n return True", "matching_cluster_idx": 10}, {"solution": "def magic_square_test(matrix):\n \"\"\"\n Check if the given matrix is a magic square.\n\n A magic square is a square matrix in which the sums of the elements of each row, each column, and both main diagonals are the same.\n\n Parameters:\n - matrix (list of list of int): The matrix to be tested\n\n Returns:\n - bool: True if the matrix is a magic square, False otherwise\n \"\"\"\n n = len(matrix)\n\n # Calculate the expected sum for each row, column, and diagonal\n first_sum = sum(matrix[0])\n\n # Check each row\n for row in matrix:\n if sum(row) != first_sum:\n return False\n\n # Check each column\n for col in range(n):\n if sum(matrix[row][col] for row in range(n)) != first_sum:\n return False\n\n # Check main diagonals\n if sum(matrix[i][i] for i in range(n)) != first_sum or sum(matrix[i][n-i-1] for i in range(n)) != first_sum:\n return False\n\n # If all checks passed, it's a magic square\n return True", "matching_cluster_idx": 14}, {"solution": "def magic_square_test(matrix):\n n = len(matrix)\n\n # Calculate the sum of the first row.\n magic_sum = sum(matrix[0])\n\n # Check for every row and column.\n for i in range(n):\n row_sum = sum(matrix[i])\n col_sum = sum(matrix[j][i] for j in range(n))\n if row_sum != magic_sum or col_sum != magic_sum:\n return False\n\n # Check both diagonals.\n diag1_sum = sum(matrix[i][i] for i in range(n))\n diag2_sum = sum(matrix[i][n-i-1] for i in range(n))\n if diag1_sum != magic_sum or diag2_sum != magic_sum:\n return False\n\n return True", "matching_cluster_idx": 13}, {"solution": "def magic_square_test(matrix):\n n = len(matrix)\n # Sum of the first row\n magic_sum = sum(matrix[0])\n\n # Check if the sum of all rows, columns, and diagonals are equal to magic_sum\n for i in range(n):\n if sum(matrix[i]) != magic_sum or sum(matrix[j][i] for j in range(n)) != magic_sum:\n return False\n\n # Check diagonals\n if sum(matrix[i][i] for i in range(n)) != magic_sum or sum(matrix[i][n-i-1] for i in range(n)) != magic_sum:\n return False\n\n return True", "matching_cluster_idx": 13}, {"solution": "def magic_square_test(matrix):\n n = len(matrix)\n # Calculate the expected sum of any row/column/diagonal\n expected_sum = sum(sum(row) for row in matrix) // n\n\n # Check all rows\n for row in matrix:\n if sum(row) != expected_sum:\n return False\n\n # Check all columns\n for col in range(n):\n if sum(matrix[row][col] for row in range(n)) != expected_sum:\n return False\n\n # Check main diagonal\n if sum(matrix[i][i] for i in range(n)) != expected_sum:\n return False\n\n # Check secondary diagonal\n if sum(matrix[i][n-1-i] for i in range(n)) != expected_sum:\n return False\n\n return True", "matching_cluster_idx": 10}, {"solution": "def magic_square_test(matrix):\n # Check if the matrix is a square\n n = len(matrix)\n if any(len(row) != n for row in matrix):\n return False\n\n # Calculate the sum of the first row (should be the same for all rows and columns)\n total_sum = sum(matrix[0])\n\n # Check if the sums of rows are all the same\n for row in matrix:\n if sum(row) != total_sum:\n return False\n\n # Check if the sums of columns are all the same\n for col in range(n):\n if sum(matrix[row][col] for row in range(n)) != total_sum:\n return False\n\n # Check if the sums of diagonals are all the same\n if sum(matrix[i][i] for i in range(n)) != total_sum:\n return False\n if sum(matrix[i][n - i - 1] for i in range(n)) != total_sum:\n return False\n\n return True", "matching_cluster_idx": 13}]}, "Mbpp/130": {"dps": 97.88116591928251, "dps_norm": 82.5, "pass@1": 95.0, "profiled": [{"solution": "from collections import Counter\ndef max_occurrences(lst):\n # Using Counter to count the frequency of each item in the list\n freq_dict = Counter(lst)\n\n # Finding the item with maximum frequency\n max_freq_item = max(freq_dict, key=freq_dict.get)\n\n return max_freq_item", "matching_cluster_idx": 4}, {"solution": "from collections import Counter\ndef max_occurrences(items):\n count = Counter(items)\n return count.most_common(1)[0][0]", "matching_cluster_idx": 4}, {"solution": "from collections import Counter\ndef max_occurrences(lst):\n # Use Counter to count the frequency of each item\n frequency = Counter(lst)\n # Find the item with the maximum frequency\n max_frequency_item = frequency.most_common(1)[0][0]\n return max_frequency_item", "matching_cluster_idx": 4}, {"solution": "from collections import Counter\ndef max_occurrences(lst):\n # Using collections.Counter to count the frequency of each item in the list\n frequency = Counter(lst)\n\n # Finding the item with the maximum frequency\n max_item = max(frequency, key=frequency.get)\n\n return max_item", "matching_cluster_idx": 4}, {"solution": "from collections import Counter\ndef max_occurrences(lst):\n # Use Counter to get the frequency of each item\n frequency = Counter(lst)\n # Find the item with the maximum frequency\n max_item = max(frequency, key=frequency.get)\n return max_item", "matching_cluster_idx": 4}, {"solution": "def max_occurrences(items):\n from collections import Counter\n # Use Counter to get the frequency of each item in the list\n frequency = Counter(items)\n # Find the item with the maximum frequency\n max_freq_item = frequency.most_common(1)[0]\n return max_freq_item[0]", "matching_cluster_idx": 4}, {"solution": "def max_occurrences(lst):\n from collections import Counter\n return Counter(lst).most_common(1)[0][0]", "matching_cluster_idx": 4}, {"solution": "from collections import Counter\ndef max_occurrences(lst):\n # Use Counter to count the frequency of each item in the list\n frequency = Counter(lst)\n # Find the item with the maximum frequency\n max_freq_item = frequency.most_common(1)[0][0]\n return max_freq_item", "matching_cluster_idx": 4}, {"solution": "from collections import Counter\ndef max_occurrences(lst):\n # Use Counter to count the frequency of each element in the list\n count = Counter(lst)\n # Find the item with the maximum frequency\n most_common_item = count.most_common(1)[0][0]\n return most_common_item", "matching_cluster_idx": 4}, {"solution": "def max_occurrences(lst):\n \"\"\"\n Find the item with the maximum frequency in a given list.\n\n :param lst: List of integers\n :return: Integer with the maximum frequency in the list\n \"\"\"\n from collections import Counter\n return Counter(lst).most_common(1)[0][0]", "matching_cluster_idx": 4}, {"solution": "from collections import Counter\ndef max_occurrences(lst):\n # Count the frequency of each item in the list using Counter\n frequency = Counter(lst)\n # Find the item with the maximum frequency\n max_freq_item = frequency.most_common(1)[0][0]\n return max_freq_item", "matching_cluster_idx": 4}, {"solution": "from collections import Counter\ndef max_occurrences(lst):\n # Use Counter to get the frequency of each item in the list\n frequency = Counter(lst)\n # Find the item with the maximum frequency\n max_item = max(frequency, key=frequency.get)\n return max_item", "matching_cluster_idx": 4}, {"solution": "from collections import Counter\ndef max_occurrences(lst):\n if not lst:\n return None\n\n # Use Counter to get the frequency of each item\n frequency = Counter(lst)\n\n # Find the item with the maximum frequency\n max_item = max(frequency, key=frequency.get)\n\n return max_item", "matching_cluster_idx": 4}, {"solution": "from collections import Counter\ndef max_occurrences(lst):\n # Use Counter to count the frequency of each item\n frequency = Counter(lst)\n\n # Find the item with the maximum frequency\n max_item = max(frequency, key=frequency.get)\n\n return max_item", "matching_cluster_idx": 4}, {"solution": "from collections import Counter\ndef max_occurrences(lst):\n # Using Counter to get the frequency of each item\n frequency = Counter(lst)\n\n # Find the item with the maximum frequency\n max_freq_item = max(frequency, key=frequency.get)\n\n return max_freq_item", "matching_cluster_idx": 4}, {"solution": "from collections import Counter\ndef max_occurrences(lst):\n \"\"\"\n Find the item with the maximum frequency in the given list.\n\n Args:\n lst: List of integers.\n\n Returns:\n int: The item with the maximum frequency.\n \"\"\"\n # Using Counter from collections to count occurrences\n counts = Counter(lst)\n # Getting the item with the maximum count\n return counts.most_common(1)[0][0]", "matching_cluster_idx": 4}, {"solution": "from collections import Counter\ndef max_occurrences(lst):\n if not lst:\n return None\n\n count = Counter(lst)\n return count.most_common(1)[0][0]", "matching_cluster_idx": 4}, {"solution": "def max_occurrences(lst):\n # Dictionary to count the frequency of each item\n frequency = {}\n\n # Count the frequency of each item in the list\n for item in lst:\n if item in frequency:\n frequency[item] += 1\n else:\n frequency[item] = 1\n\n # Find the item with the maximum frequency\n max_item = None\n max_count = 0\n for item, count in frequency.items():\n if count > max_count:\n max_count = count\n max_item = item\n\n return max_item", "matching_cluster_idx": 3}, {"solution": "from collections import Counter\ndef max_occurrences(items):\n count = Counter(items)\n return count.most_common(1)[0][0]", "matching_cluster_idx": 4}, {"solution": "from collections import Counter\ndef max_occurrences(lst):\n if not lst:\n return None\n return Counter(lst).most_common(1)[0][0]", "matching_cluster_idx": 4}]}, "Mbpp/137": {"dps": 71.77419354838709, "dps_norm": 83.125, "pass@1": 20.0, "profiled": [{"solution": "import math\ndef zero_count(arr):\n zeroes = sum(1 for x in arr if x == 0)\n non_zeroes = len(arr) - zeroes\n if non_zeroes == 0:\n return float('inf') # To handle division by zero case\n return zeroes / non_zeroes", "matching_cluster_idx": 5}, {"solution": "import math\ndef zero_count(arr):\n zero_count = arr.count(0)\n non_zero_count = len(arr) - zero_count\n\n if non_zero_count == 0:\n return float('inf') # Avoid division by zero\n\n ratio = zero_count / non_zero_count\n return ratio", "matching_cluster_idx": 7}, {"solution": "import math\ndef zero_count(arr):\n zero_count = sum(1 for x in arr if x == 0)\n non_zero_count = len(arr) - zero_count\n return zero_count / non_zero_count if non_zero_count != 0 else float('inf') # Prevent division by zero", "matching_cluster_idx": 5}, {"solution": "import math\ndef zero_count(arr):\n if len(arr) == 0:\n return 0\n\n zeroes = sum(1 for x in arr if x == 0)\n non_zeroes = len(arr) - zeroes\n\n if non_zeroes == 0:\n return float('inf')\n\n return zeroes / non_zeroes", "matching_cluster_idx": 4}, {"solution": "import math\ndef zero_count(arr):\n if not arr:\n return 0\n\n zero_count = arr.count(0)\n non_zero_count = len(arr) - zero_count\n\n if non_zero_count == 0:\n return float('inf') # To avoid division by zero\n\n ratio = zero_count / non_zero_count\n return ratio", "matching_cluster_idx": 6}, {"solution": "import math\ndef zero_count(arr):\n zeroes = arr.count(0)\n non_zeroes = len(arr) - zeroes\n if non_zeroes == 0:\n return float('inf') # Handle the case where all elements are zero\n return zeroes / non_zeroes", "matching_cluster_idx": 7}, {"solution": "import math\ndef zero_count(arr):\n if not arr:\n return 0\n zeroes = sum(1 for x in arr if x == 0)\n non_zeroes = len(arr) - zeroes\n return zeroes / non_zeroes if non_zeroes != 0 else float('inf')", "matching_cluster_idx": 4}, {"solution": "import math\ndef zero_count(arr):\n zero_count = sum(1 for x in arr if x == 0)\n non_zero_count = len(arr) - zero_count\n if non_zero_count == 0:\n return float('inf')\n return zero_count / non_zero_count", "matching_cluster_idx": 4}, {"solution": "import math\ndef zero_count(arr):\n \"\"\"\n Function to find the ratio of zeroes to non-zeroes in an array of integers.\n\n Parameters:\n arr (list of int): The input array.\n\n Returns:\n float: The ratio of zeroes to non-zeroes.\n \"\"\"\n zero_count = arr.count(0)\n non_zero_count = len(arr) - zero_count\n if non_zero_count == 0:\n return float('inf')\n ratio = zero_count / non_zero_count\n return ratio", "matching_cluster_idx": 6}, {"solution": "import math\ndef zero_count(arr):\n zeroes = arr.count(0)\n non_zeroes = len(arr) - zeroes\n if non_zeroes == 0:\n return float('inf')\n return zeroes / non_zeroes", "matching_cluster_idx": 6}, {"solution": "import math\ndef zero_count(arr):\n zero_count = arr.count(0)\n non_zero_count = len(arr) - zero_count\n if non_zero_count == 0:\n return float('inf')\n return zero_count / non_zero_count", "matching_cluster_idx": 7}, {"solution": "import math\ndef zero_count(arr):\n \"\"\"\n This function returns the ratio of zeroes to non-zeroes in the given array of integers.\n \"\"\"\n zero_count = arr.count(0)\n non_zero_count = len(arr) - zero_count\n\n if non_zero_count == 0:\n return float('inf') # handle the case when there are no non-zeroes\n return zero_count / non_zero_count", "matching_cluster_idx": 7}, {"solution": "import math\ndef zero_count(arr):\n zeroes = sum(1 for x in arr if x == 0)\n non_zeroes = len(arr) - zeroes\n return zeroes / non_zeroes if non_zeroes != 0 else float('inf')", "matching_cluster_idx": 4}, {"solution": "import math\ndef zero_count(arr):\n zeroes = arr.count(0)\n non_zeroes = len(arr) - zeroes\n if non_zeroes == 0:\n return float('inf')\n return zeroes / non_zeroes", "matching_cluster_idx": 6}, {"solution": "import math\ndef zero_count(arr):\n # Count the number of zeroes\n zero_count = arr.count(0)\n # Count the number of non-zeroes\n non_zero_count = len(arr) - zero_count\n # Return the ratio of zeroes to non-zeroes\n if non_zero_count == 0:\n return float('inf') # To avoid division by zero\n return zero_count / non_zero_count", "matching_cluster_idx": 6}, {"solution": "import math\ndef zero_count(arr):\n zeroes = sum(1 for x in arr if x == 0)\n non_zeroes = len(arr) - zeroes\n if non_zeroes == 0:\n return float('inf') # Avoid division by zero\n return zeroes / non_zeroes", "matching_cluster_idx": 5}, {"solution": "import math\ndef zero_count(arr):\n total_elements = len(arr)\n if total_elements == 0:\n return 0\n\n zero_count = arr.count(0)\n non_zero_count = total_elements - zero_count\n\n if non_zero_count == 0:\n return float('inf') # Avoid division by zero\n\n ratio = zero_count / non_zero_count\n return ratio", "matching_cluster_idx": 6}, {"solution": "import math\ndef zero_count(arr):\n total_elements = len(arr)\n zero_count = arr.count(0)\n non_zero_count = total_elements - zero_count\n\n if non_zero_count == 0:\n return float('inf') # To handle division by zero\n\n return zero_count / non_zero_count if non_zero_count != 0 else 0", "matching_cluster_idx": 6}, {"solution": "import math\ndef zero_count(arr):\n zero_count = sum(1 for x in arr if x == 0)\n non_zero_count = len(arr) - zero_count\n if non_zero_count == 0:\n return float('inf')\n ratio = zero_count / non_zero_count\n return ratio", "matching_cluster_idx": 5}, {"solution": "import math\ndef zero_count(arr):\n # Count the number of zeroes in the array\n zero_count = arr.count(0)\n # Count the number of non-zeroes in the array\n non_zero_count = len(arr) - zero_count\n # Calculate the ratio of zeroes to non-zeroes\n ratio = zero_count / non_zero_count if non_zero_count != 0 else float('inf')\n return ratio", "matching_cluster_idx": 7}]}, "Mbpp/140": {"dps": 79.53416149068323, "dps_norm": 81.875, "pass@1": 100.0, "profiled": [{"solution": "def extract_singly(lists):\n \"\"\"\n Flatten a list of lists into a single set of numbers.\n\n :param lists: List of lists containing numbers\n :return: Set of all numbers from the provided lists\n \"\"\"\n flat_set = set()\n for sublist in lists:\n for num in sublist:\n flat_set.add(num)\n return flat_set", "matching_cluster_idx": 3}, {"solution": "def extract_singly(list_of_lists):\n \"\"\"\n This function flattens a list of lists into a single set of numbers.\n \"\"\"\n flattened_set = set()\n for sublist in list_of_lists:\n flattened_set.update(sublist)\n return flattened_set", "matching_cluster_idx": 7}, {"solution": "def extract_singly(lst_of_lists):\n \"\"\"\n Flattens a list of lists into a single set of numbers.\n\n Parameters:\n lst_of_lists (list of lists): A list containing sublists of numbers.\n\n Returns:\n set: A set containing all the numbers from the input list of lists.\n \"\"\"\n # Use a set comprehension to flatten the list of lists\n return {num for sublist in lst_of_lists for num in sublist}", "matching_cluster_idx": 5}, {"solution": "def extract_singly(list_of_lists):\n \"\"\"\n This function flattens a list of lists into a single set of numbers.\n\n Parameters:\n list_of_lists (list of tuples): A list containing tuples of numbers.\n\n Returns:\n set: A set containing all numbers from the tuples.\n \"\"\"\n flat_list = []\n for sublist in list_of_lists:\n flat_list.extend(sublist)\n return set(flat_list)", "matching_cluster_idx": 6}, {"solution": "def extract_singly(list_of_lists):\n \"\"\"\n This function takes a list of lists and returns a set of all the unique numbers in it.\n \"\"\"\n return set([item for sublist in list_of_lists for item in sublist])", "matching_cluster_idx": 5}, {"solution": "def extract_singly(list_of_lists):\n \"\"\"\n Flattens a list of lists into a single set of numbers.\n\n :param list_of_lists: List of lists of numbers\n :return: Set of numbers\n \"\"\"\n # Using a set comprehension to flatten the list of lists\n return {num for sublist in list_of_lists for num in sublist}", "matching_cluster_idx": 5}, {"solution": "def extract_singly(list_of_lists):\n \"\"\"\n This function takes a list of lists and flattens it into a single set of numbers.\n\n Parameters:\n list_of_lists (list of lists): A list where each element is another list of numbers.\n\n Returns:\n set: A set containing all unique numbers from the flattened list.\n \"\"\"\n # Flatten the list using list comprehension and convert to set to remove duplicates\n return set([item for sublist in list_of_lists for item in sublist])", "matching_cluster_idx": 5}, {"solution": "def extract_singly(list_of_lists):\n \"\"\"\n This function takes a list of lists and flattens it into a single set of numbers.\n\n Parameters:\n list_of_lists (list of list of int): The input list of lists.\n\n Returns:\n set of int: The flattened set of numbers.\n \"\"\"\n flattened_set = set()\n for sublist in list_of_lists:\n flattened_set.update(sublist)\n return flattened_set", "matching_cluster_idx": 7}, {"solution": "def extract_singly(list_of_lists):\n \"\"\"\n Function to flatten a list of lists into a single set of numbers.\n \"\"\"\n flattened_set = set()\n for sublist in list_of_lists:\n flattened_set.update(sublist)\n return flattened_set", "matching_cluster_idx": 7}, {"solution": "def extract_singly(list_of_lists):\n \"\"\"\n Flattens a list of lists into a single set of numbers.\n\n Parameters:\n list_of_lists (list of tuples): A list containing tuples of numbers.\n\n Returns:\n set: A set containing unique numbers from the input list of tuples.\n \"\"\"\n # Initialize an empty set to store unique numbers\n unique_numbers = set()\n\n # Iterate through each tuple in the list of lists\n for sublist in list_of_lists:\n # Add each element of the tuple to the set\n for number in sublist:\n unique_numbers.add(number)\n\n return unique_numbers", "matching_cluster_idx": 3}, {"solution": "def extract_singly(lists_of_lists):\n # Use a set comprehension to flatten the list of lists into a single set of numbers\n return {num for sublist in lists_of_lists for num in sublist}", "matching_cluster_idx": 5}, {"solution": "def extract_singly(list_of_lists):\n # Initialize an empty set to store unique numbers\n result_set = set()\n\n # Iterate through each sublist in the list of lists\n for sublist in list_of_lists:\n # Add each element of the sublist to the result set\n result_set.update(sublist)\n\n return result_set", "matching_cluster_idx": 7}, {"solution": "def extract_singly(list_of_lists):\n flattened_list = [item for sublist in list_of_lists for item in sublist]\n return set(flattened_list)", "matching_cluster_idx": 5}, {"solution": "def extract_singly(list_of_lists):\n \"\"\"\n Flatten a list of lists into a single set of numbers.\n\n Parameters:\n list_of_lists (list of tuples): The input list containing sublists.\n\n Returns:\n set: A set containing all the numbers from the sublists.\n \"\"\"\n flat_list = []\n for sublist in list_of_lists:\n flat_list.extend(sublist)\n return set(flat_list)", "matching_cluster_idx": 6}, {"solution": "def extract_singly(nested_list):\n \"\"\"\n Flattens a list of lists into a single set of numbers.\n\n :param nested_list: List of lists, each containing integers.\n :return: Set containing all integers from the nested lists.\n \"\"\"\n flat_list = [item for sublist in nested_list for item in sublist]\n return set(flat_list)", "matching_cluster_idx": 5}, {"solution": "def extract_singly(list_of_lists):\n flattened_set = set()\n for sublist in list_of_lists:\n flattened_set.update(sublist)\n return flattened_set", "matching_cluster_idx": 7}, {"solution": "def extract_singly(list_of_lists):\n flat_list = [item for sublist in list_of_lists for item in sublist]\n return set(flat_list)", "matching_cluster_idx": 5}, {"solution": "def extract_singly(list_of_lists):\n \"\"\"\n Flattens a list of lists into a single set of numbers.\n\n Parameters:\n list_of_lists (list of list of int): A list containing lists of integers.\n\n Returns:\n set: A set of integers.\n \"\"\"\n flattened_set = set()\n for sublist in list_of_lists:\n flattened_set.update(sublist)\n return flattened_set", "matching_cluster_idx": 7}, {"solution": "def extract_singly(lists_of_lists):\n \"\"\"\n This function takes a list of lists and returns a set of numbers.\n \"\"\"\n # Initialize an empty set to store unique numbers\n unique_numbers = set()\n\n # Iterate over each sublist in the input list\n for sublist in lists_of_lists:\n # Add each element from the sublist to the set\n for element in sublist:\n unique_numbers.add(element)\n\n # Return the set of unique numbers\n return unique_numbers", "matching_cluster_idx": 4}, {"solution": "def extract_singly(lists):\n flattened_set = set()\n for sublist in lists:\n flattened_set.update(sublist)\n return flattened_set", "matching_cluster_idx": 7}]}, "Mbpp/141": {"dps": 66.34920634920636, "dps_norm": 41.25, "pass@1": 28.0, "profiled": [{"solution": "def pancake_sort(pancakes):\n n = len(pancakes)\n\n def flip(pancakes, k):\n left, right = 0, k\n while left < right:\n pancakes[left], pancakes[right] = pancakes[right], pancakes[left]\n left += 1\n right -= 1\n\n for i in range(n, 1, -1):\n max_idx = pancakes.index(max(pancakes[:i]))\n if max_idx != i - 1:\n flip(pancakes, max_idx)\n flip(pancakes, i - 1)\n\n return pancakes", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(pancakes):\n n = len(pancakes)\n for size in range(n, 1, -1):\n # Find the maximum element in the first `size` elements\n max_index = pancakes.index(max(pancakes[:size]))\n\n # Move the maximum element to the beginning if it's not already there\n if max_index != 0:\n pancakes[0], pancakes[max_index] = pancakes[max_index], pancakes[0]\n\n # Flip the element to its correct position\n pancakes = pancakes[:size][::-1] + pancakes[size:]\n\n return pancakes", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(pancakes):\n n = len(pancakes)\n\n for size in range(n, 1, -1):\n # Find the largest element in the unsorted part and swap it with the first element.\n max_index = pancakes.index(max(pancakes[:size]))\n if max_index != 0:\n pancakes[0], pancakes[max_index] = pancakes[max_index], pancakes[0]\n\n # Move the largest element to its correct position\n pancakes[:size] = reversed(pancakes[:size])\n\n return pancakes", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(arr):\n n = len(arr)\n\n def flip(arr, k):\n left, right = 0, k\n while left < right:\n arr[left], arr[right] = arr[right], arr[left]\n left += 1\n right -= 1\n\n for size in range(n, 1, -1):\n max_idx = arr.index(max(arr[:size]))\n if max_idx != size - 1:\n flip(arr, max_idx)\n flip(arr, size - 1)\n\n return arr", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(arr):\n \"\"\"\n Sorts a list of elements using a pancake sort algorithm.\n :param arr: List of integers to be sorted.\n :return: Sorted list of integers.\n \"\"\"\n def flip(arr, k):\n left, right = 0, k\n while left < right:\n arr[left], arr[right] = arr[right], arr[left]\n left += 1\n right -= 1\n\n n = len(arr)\n for i in range(n, 1, -1):\n max_idx = arr.index(max(arr[:i]))\n if max_idx != i - 1:\n flip(arr, max_idx)\n flip(arr, i - 1)\n return arr", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(arr):\n n = len(arr)\n # Function to flip the first k elements\n def flip(k):\n arr[:k] = arr[:k][::-1]\n\n # Iterate over each element to find the maximum element in the first i elements\n for i in range(n, 1, -1):\n # Find the index of the maximum element\n max_index = arr.index(max(arr[:i]))\n # Flip the maximum element to the front\n if max_index != 0:\n flip(max_index + 1)\n # Move the maximum element to the end\n flip(i)\n return arr", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(arr):\n def flip(start, end):\n while start < end:\n arr[start], arr[end] = arr[end], arr[start]\n start += 1\n end -= 1\n\n def max_index(start, end):\n max_val = arr[start]\n max_idx = start\n for i in range(start, end + 1):\n if arr[i] > max_val:\n max_val = arr[i]\n max_idx = i\n return max_idx\n\n n = len(arr)\n for size in range(n, 1, -1):\n max_idx = max_index(0, size - 1)\n if max_idx != 0:\n flip(0, max_idx)\n flip(0, size - 1)\n return arr", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(pancakes):\n # Function to flip a portion of the list\n def flip(start, end):\n while start < end:\n pancakes[start], pancakes[end] = pancakes[end], pancakes[start]\n start += 1\n end -= 1\n\n # Perform Pancake Sort\n n = len(pancakes)\n for size in range(n, 1, -1):\n # Find the maximum element in the first `size` elements\n max_idx = pancakes.index(max(pancakes[:size]))\n\n # If the maximum element is not already in place, move it to the start\n if max_idx != 0:\n flip(0, max_idx)\n\n # Move the maximum element to the end of the list\n flip(0, size - 1)\n\n return pancakes", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(pancakes):\n n = len(pancakes)\n for size in range(n, 1, -1):\n # Find the maximum in the first size elements\n max_idx = pancakes.index(max(pancakes[:size]))\n\n # Flip the maximum to the start\n pancakes[:max_idx+1] = reversed(pancakes[:max_idx+1])\n\n # Flip the first size elements to the end\n pancakes[:size] = reversed(pancakes[:size])\n\n return pancakes", "matching_cluster_idx": 3}, {"solution": "def flip_pancake(arr, k):\n # Flip the pancake at index k in the array\n arr[:k+1] = reversed(arr[:k+1])\n return arr\ndef pancake_sort(arr):\n n = len(arr)\n\n for size in range(n, 1, -1):\n # Find the maximum element in the first size elements\n max_index = arr.index(max(arr[:size]))\n\n if max_index != 0:\n # Flip the pancake to bring the max element to the beginning\n arr = flip_pancake(arr, max_index)\n\n # Move the max element to the end\n arr = flip_pancake(arr, size-1)\n\n return arr", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(arr):\n def flip(arr, k):\n left, right = 0, k\n while left < right:\n arr[left], arr[right] = arr[right], arr[left]\n left += 1\n right -= 1\n\n n = len(arr)\n for size in range(n, 1, -1):\n max_idx = arr.index(max(arr[:size]))\n if max_idx != size - 1:\n flip(arr, max_idx)\n flip(arr, size - 1)\n\n return arr", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(arr):\n # Pancake sort algorithm implementation\n def flip(arr, k):\n left = 0\n right = k\n while left < right:\n arr[left], arr[right] = arr[right], arr[left]\n left += 1\n right -= 1\n\n n = len(arr)\n for size in range(n, 1, -1):\n # Move the maximum element to the beginning\n max_idx = arr.index(max(arr[:size]))\n if max_idx != 0:\n flip(arr, max_idx)\n # Move the maximum element to the end\n flip(arr, size - 1)\n return arr", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(lst):\n # This will sort the list in ascending order using bubble sort algorithm\n n = len(lst)\n for i in range(n):\n # Last i elements are already in place\n for j in range(0, n-i-1):\n if lst[j] > lst[j+1]:\n # Swap if the element found is greater than the next element\n lst[j], lst[j+1] = lst[j+1], lst[j]\n return lst", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(arr):\n def flip(arr, k):\n left = 0\n right = k - 1\n while left < right:\n arr[left], arr[right] = arr[right], arr[left]\n left += 1\n right -= 1\n\n n = len(arr)\n for size in range(n, 1, -1):\n max_idx = arr.index(max(arr[:size]))\n if max_idx != size - 1:\n flip(arr, max_idx + 1)\n flip(arr, size)\n\n return arr", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(pancakes):\n def flip(arr, k):\n left = 0\n right = k\n while left < right:\n arr[left], arr[right] = arr[right], arr[left]\n left += 1\n right -= 1\n\n n = len(pancakes)\n for i in range(n, 1, -1):\n # Find the maximum element in the first i elements\n max_idx = pancakes.index(max(pancakes[:i]))\n if max_idx != i - 1:\n # Flip the first i elements to bring the maximum to the end\n flip(pancakes, max_idx)\n # Flip the first i elements to bring the maximum to the front\n flip(pancakes, i - 1)\n return pancakes", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(arr):\n \"\"\"\n Sorts a list of elements using the pancake sort algorithm.\n \"\"\"\n n = len(arr)\n for size in range(n, 1, -1):\n # Find the maximum element in the first `size` elements\n max_index = arr.index(max(arr[:size]))\n\n # Move the maximum element to the beginning, if it is not already there\n if max_index != 0:\n arr[:max_index + 1] = reversed(arr[:max_index + 1])\n\n # Move the maximum element to the end of the sorted portion\n arr[:size] = reversed(arr[:size])\n\n return arr", "matching_cluster_idx": 3}, {"solution": "def pancake_sort(arr):\n def flip(arr, k):\n left = 0\n right = k - 1\n while left < right:\n arr[left], arr[right] = arr[right], arr[left]\n left += 1\n right -= 1\n\n n = len(arr)\n for size in range(n, 1, -1):\n max_idx = arr.index(max(arr[:size]))\n if max_idx != size - 1:\n flip(arr, max_idx + 1)\n flip(arr, size)\n\n return arr", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(arr):\n def flip(arr, start):\n left, right = 0, start\n while left < right:\n arr[left], arr[right] = arr[right], arr[left]\n left += 1\n right -= 1\n\n def move_max(arr, n):\n max_idx = arr.index(max(arr[:n]))\n if max_idx != n - 1:\n flip(arr, max_idx)\n flip(arr, n - 1)\n\n n = len(arr)\n for size in range(n, 1, -1):\n move_max(arr, size)\n return arr", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(arr):\n # Function to flip the array up to index 'k'\n def flip(arr, k):\n left = 0\n right = k\n while left < right:\n arr[left], arr[right] = arr[right], arr[left]\n left += 1\n right -= 1\n\n n = len(arr)\n\n # Iterate through the array in reverse order\n for size in range(n, 1, -1):\n # Find the maximum element in the first 'size' elements\n max_index = arr.index(max(arr[:size]))\n\n # Move the maximum element to the first position if it's not already there\n if max_index != 0:\n flip(arr, max_index)\n\n # Move the maximum element to its final position\n flip(arr, size - 1)\n\n return arr", "matching_cluster_idx": 2}, {"solution": "def pancake_sort(arr):\n def flip(arr, k):\n left, right = 0, k\n while left < right:\n arr[left], arr[right] = arr[right], arr[left]\n left += 1\n right -= 1\n\n n = len(arr)\n for size in range(n, 1, -1):\n max_index = arr.index(max(arr[:size]))\n if max_index != size - 1:\n flip(arr, max_index)\n flip(arr, size - 1)\n return arr", "matching_cluster_idx": 2}]}, "Mbpp/166": {"dps": 94.39999999999999, "dps_norm": 50.0, "pass@1": 96.0, "profiled": [{"solution": "def find_even_pair(lst):\n # Initialize count of pairs that XOR to an even number\n count = 0\n\n # Iterate through each element in the list\n for i in range(len(lst)):\n for j in range(i + 1, len(lst)):\n # Check if XOR of pair (lst[i], lst[j]) is even\n if (lst[i] ^ lst[j]) % 2 == 0:\n count += 1\n\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(numbers):\n count = 0\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n if (numbers[i] ^ numbers[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(lst):\n count = 0\n for i in range(len(lst)):\n for j in range(i+1, len(lst)):\n if (lst[i] ^ lst[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(arr):\n count = 0\n for i in range(len(arr)):\n for j in range(i + 1, len(arr)):\n if (arr[i] ^ arr[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(lst):\n count = 0\n for i in range(len(lst)):\n for j in range(i+1, len(lst)):\n if (lst[i] ^ lst[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(nums):\n count = 0\n for i in range(len(nums)):\n for j in range(i + 1, len(nums)):\n if (nums[i] ^ nums[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(nums):\n count = 0\n for i in range(len(nums)):\n for j in range(i + 1, len(nums)):\n if (nums[i] ^ nums[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(nums):\n even_count = 0\n for i in range(len(nums)):\n for j in range(i+1, len(nums)):\n if (nums[i] ^ nums[j]) % 2 == 0:\n even_count += 1\n return even_count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(lst):\n even_count = 0\n for i in range(len(lst)):\n for j in range(i + 1, len(lst)):\n if (lst[i] ^ lst[j]) % 2 == 0:\n even_count += 1\n return even_count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(nums):\n even_count = 0\n\n for i in range(len(nums)):\n for j in range(i + 1, len(nums)):\n if (nums[i] ^ nums[j]) % 2 == 0:\n even_count += 1\n\n return even_count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(lst):\n count = 0\n for i in range(len(lst)):\n for j in range(i + 1, len(lst)):\n if (lst[i] ^ lst[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(lst):\n # Number of pairs that XOR to an even number\n even_pair_count = 0\n\n # Iterate over the list and check for every pair\n for i in range(len(lst)):\n for j in range(i + 1, len(lst)):\n if (lst[i] ^ lst[j]) % 2 == 0:\n even_pair_count += 1\n\n return even_pair_count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(lst):\n even_pair_count = 0\n\n for i in range(len(lst)):\n for j in range(i + 1, len(lst)):\n if (lst[i] ^ lst[j]) % 2 == 0:\n even_pair_count += 1\n\n return even_pair_count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(numbers):\n even_count = 0\n\n for i in range(len(numbers)):\n for j in range(i + 1, len(numbers)):\n if (numbers[i] ^ numbers[j]) % 2 == 0:\n even_count += 1\n\n return even_count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(nums):\n count = 0\n for i in range(len(nums)):\n for j in range(i + 1, len(nums)):\n if (nums[i] ^ nums[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(nums):\n count = 0\n for i in range(len(nums)):\n for j in range(i + 1, len(nums)):\n if (nums[i] ^ nums[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(nums):\n count = 0\n for i in range(len(nums)):\n for j in range(i + 1, len(nums)):\n if (nums[i] ^ nums[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(nums):\n count = 0\n for i in range(len(nums)):\n for j in range(i + 1, len(nums)):\n if (nums[i] ^ nums[j]) % 2 == 0:\n count += 1\n return count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(nums):\n even_count = 0\n\n for i in range(len(nums)):\n for j in range(i + 1, len(nums)):\n if (nums[i] ^ nums[j]) % 2 == 0:\n even_count += 1\n\n return even_count", "matching_cluster_idx": 1}, {"solution": "def find_even_pair(arr):\n even_count = 0\n\n # Count pairs where XOR result is even\n for i in range(len(arr)):\n for j in range(i + 1, len(arr)):\n if (arr[i] ^ arr[j]) % 2 == 0:\n even_count += 1\n\n return even_count", "matching_cluster_idx": 1}]}, "Mbpp/170": {"dps": 96.81159420289855, "dps_norm": 99.375, "pass@1": 39.0, "profiled": [{"solution": "def sum_range_list(numbers, start_index, end_index):\n \"\"\"\n Finds the sum of numbers in a list within a range specified by two indices.\n\n Args:\n numbers (list of int): The list of numbers.\n start_index (int): The start index of the range (inclusive).\n end_index (int): The end index of the range (inclusive).\n\n Returns:\n int: The sum of the numbers in the specified range.\n \"\"\"\n return sum(numbers[start_index:end_index + 1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(lst, start_index, end_index):\n return sum(lst[start_index:end_index + 1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(lst, start, end):\n \"\"\"\n Function to find the sum of numbers in a list within a range specified by two indices.\n\n Parameters:\n lst (list): The list of numbers.\n start (int): The starting index.\n end (int): The ending index.\n\n Returns:\n int: The sum of numbers within the specified range.\n \"\"\"\n return sum(lst[start:end+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(numbers, start_index, end_index):\n \"\"\"\n Calculate the sum of elements in the list within the specified range of indices.\n\n Parameters:\n - numbers: list of numbers\n - start_index: start index of the range (inclusive)\n - end_index: end index of the range (inclusive)\n\n Returns:\n - sum of elements within the specified range\n \"\"\"\n return sum(numbers[start_index:end_index + 1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(numbers, start, end):\n \"\"\"\n Function to find the sum of numbers in a list within a specified range.\n\n Args:\n numbers (list): List of numbers.\n start (int): Start index of the range.\n end (int): End index of the range.\n\n Returns:\n int: Sum of numbers within the specified range.\n \"\"\"\n return sum(numbers[start:end + 1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(numbers, start_index, end_index):\n \"\"\"\n Find the sum of numbers in a list within a range specified by two indices.\n\n Args:\n numbers (list): List of numbers.\n start_index (int): The starting index of the range (inclusive).\n end_index (int): The ending index of the range (inclusive).\n\n Returns:\n int: The sum of the numbers in the specified range.\n \"\"\"\n return sum(numbers[start_index:end_index+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(lst, start_index, end_index):\n # Calculate the sum of elements within the specified range\n return sum(lst[start_index:end_index + 1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(nums, start_index, end_index):\n \"\"\"\n This function returns the sum of numbers in a list within a specified range.\n\n Parameters:\n nums (list): The list of numbers.\n start_index (int): The start index (inclusive) of the range.\n end_index (int): The end index (inclusive) of the range.\n\n Returns:\n int: The sum of numbers within the specified range.\n \"\"\"\n return sum(nums[start_index:end_index + 1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(lst, start_index, end_index):\n \"\"\"\n Calculate the sum of numbers in a list within a specified range.\n\n :param lst: List of numbers\n :param start_index: Starting index (inclusive) of the range\n :param end_index: Ending index (inclusive) of the range\n :return: Sum of elements in the specified range\n \"\"\"\n # Ensure indices are within the bounds of the list\n start_index = max(0, start_index)\n end_index = min(len(lst), end_index)\n\n # Calculate the sum of elements in the specified range\n return sum(lst[start_index:end_index + 1])", "matching_cluster_idx": 6}, {"solution": "def sum_range_list(numbers, start, end):\n \"\"\"\n This function returns the sum of numbers in a list within a specified range.\n\n Parameters:\n numbers (list of int): List of numbers to sum.\n start (int): Starting index of the range.\n end (int): Ending index of the range (inclusive).\n\n Returns:\n int: Sum of the numbers within the specified range.\n \"\"\"\n return sum(numbers[start:end+1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(lst, start, end):\n \"\"\"\n This function returns the sum of elements in the list within the specified range.\n\n :param lst: List of integers\n :param start: Start index (inclusive)\n :param end: End index (inclusive)\n :return: Sum of the elements in the range\n \"\"\"\n return sum(lst[start:end + 1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(lst, start_index, end_index):\n \"\"\"\n Calculate the sum of numbers in a list within a specified range.\n\n Args:\n lst (list): A list of numbers.\n start_index (int): The start index (inclusive) for the range.\n end_index (int): The end index (inclusive) for the range.\n\n Returns:\n int: The sum of the numbers in the specified range.\n \"\"\"\n return sum(lst[start_index:end_index + 1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(numbers, start, end):\n \"\"\"\n This function returns the sum of the numbers in the list within the specified range.\n\n Parameters:\n numbers (list of int): List of numbers.\n start (int): Start index of the range (inclusive).\n end (int): End index of the range (inclusive).\n\n Returns:\n int: Sum of the numbers within the specified range.\n \"\"\"\n return sum(numbers[start:end + 1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(numbers, start_index, end_index):\n # Ensure the indices are within the valid range\n if start_index < 0 or end_index >= len(numbers) or start_index > end_index:\n return 0\n\n # Calculate the sum of the sublist\n return sum(numbers[start_index:end_index + 1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(lst, start_index, end_index):\n \"\"\"\n Returns the sum of numbers in the list from start_index to end_index (inclusive).\n\n :param lst: List of numbers\n :param start_index: Start of the range (inclusive)\n :param end_index: End of the range (inclusive)\n :return: Sum of the numbers in the specified range\n \"\"\"\n return sum(lst[start_index:end_index + 1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(nums, start, end):\n \"\"\"\n Calculates the sum of numbers in the list between the indices start and end (inclusive).\n\n Args:\n nums (list): List of integers.\n start (int): Start index (inclusive).\n end (int): End index (inclusive).\n\n Returns:\n int: Sum of numbers within the specified range.\n \"\"\"\n return sum(nums[start:end + 1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(nums, start_index, end_index):\n # Calculate the sum of numbers within the specified range\n return sum(nums[start_index:end_index + 1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(numbers, start, end):\n # Validate the indices\n if start < 0 or end >= len(numbers) or start > end:\n return 0\n\n # Sum the numbers within the specified range\n return sum(numbers[start:end + 1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(nums, start, end):\n \"\"\"\n Finds the sum of numbers in a list within a range specified by two indices.\n\n Args:\n nums (list of int): The list of numbers.\n start (int): The starting index (inclusive).\n end (int): The ending index (inclusive).\n\n Returns:\n int: The sum of the elements in the specified range.\n \"\"\"\n return sum(nums[start:end + 1])", "matching_cluster_idx": 7}, {"solution": "def sum_range_list(nums, start_idx, end_idx):\n \"\"\"\n Calculate the sum of numbers in the list within the specified range of indices.\n\n Parameters:\n nums (list): The list of numbers.\n start_idx (int): The start index of the range.\n end_idx (int): The end index of the range.\n\n Returns:\n int: The sum of the numbers within the specified range.\n \"\"\"\n return sum(nums[start_idx:end_idx + 1])", "matching_cluster_idx": 7}]}, "Mbpp/226": {"dps": 77.1705426356589, "dps_norm": 39.285714285714285, "pass@1": 49.0, "profiled": [{"solution": "def odd_values_string(s):\n \"\"\"\n Removes the characters with odd index values from the given string.\n\n Args:\n s (str): The input string from which characters will be removed.\n\n Returns:\n str: A new string with characters having even index values.\n \"\"\"\n return ''.join(s[i] for i in range(len(s)) if i % 2 == 0)", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(input_string):\n # Create a new string with only the characters at even indices\n return ''.join(input_string[i] for i in range(0, len(input_string), 2))", "matching_cluster_idx": 3}, {"solution": "def odd_values_string(s: str) -> str:\n \"\"\"\n Remove characters from the given string that are at odd index values (0-based indexing).\n\n Args:\n s (str): The input string.\n\n Returns:\n str: The new string with characters at odd indices removed.\n \"\"\"\n # Using a list comprehension to filter out characters at odd indices\n return ''.join([char for index, char in enumerate(s) if index % 2 == 0])", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(input_string):\n \"\"\"\n This function removes characters which have odd index values from the given string.\n Indices are 0-based.\n\n Args:\n input_string (str): The input string from which odd index characters will be removed.\n\n Returns:\n str: A new string with characters at odd indices removed.\n \"\"\"\n return input_string[::2]", "matching_cluster_idx": 5}, {"solution": "def odd_values_string(s: str) -> str:\n \"\"\"\n Remove the characters which have odd index values of a given string.\n\n Args:\n s (str): Input string.\n\n Returns:\n str: String with characters at even indices retained.\n \"\"\"\n return ''.join(s[i] for i in range(0, len(s), 2))", "matching_cluster_idx": 3}, {"solution": "def odd_values_string(s):\n return s[::2]", "matching_cluster_idx": 6}, {"solution": "def odd_values_string(input_string):\n # Initialize an empty string to hold the result\n result = ''\n\n # Iterate over the input string and collect characters at even indices\n for index in range(0, len(input_string), 2):\n result += input_string[index]\n\n return result", "matching_cluster_idx": 2}, {"solution": "def odd_values_string(s):\n # Create a new string by concatenating characters at even indices\n return ''.join(s[i] for i in range(0, len(s), 2))", "matching_cluster_idx": 3}, {"solution": "def odd_values_string(input_string):\n # Initialize an empty string to store the result\n result = ''\n\n # Iterate through the string and append characters at even indices to the result\n for i in range(0, len(input_string), 2):\n result += input_string[i]\n\n return result", "matching_cluster_idx": 2}, {"solution": "def odd_values_string(s):\n \"\"\"\n Remove the characters which have odd index values from the given string.\n\n Args:\n s (str): Input string.\n\n Returns:\n str: String with characters at even indices.\n \"\"\"\n return ''.join(s[i] for i in range(0, len(s), 2))", "matching_cluster_idx": 2}, {"solution": "def odd_values_string(s):\n \"\"\"\n Remove characters at odd indices from the input string.\n\n :param s: str - Input string\n :return: str - String with characters at odd indices removed\n \"\"\"\n return ''.join(s[i] for i in range(len(s)) if i % 2 == 0)", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(s):\n \"\"\"\n Remove the characters which have odd index values of a given string.\n\n Args:\n s (str): The input string.\n\n Returns:\n str: A new string with characters at even indexes.\n \"\"\"\n return ''.join(s[i] for i in range(len(s)) if i % 2 == 0)", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(s):\n # Using list comprehension to collect characters at even indices\n return ''.join([s[i] for i in range(len(s)) if i % 2 == 0])", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(s):\n # Use a list comprehension to filter out characters at even indices and join them into a string\n return ''.join(s[i] for i in range(len(s)) if i % 2 == 0)", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(input_string):\n \"\"\"\n This function removes characters from the input string that are at odd indices.\n \"\"\"\n # Use step parameter in slicing to only include characters with even indices\n return input_string[::2]", "matching_cluster_idx": 5}, {"solution": "def odd_values_string(s: str) -> str:\n \"\"\"\n This function removes characters at odd index values from the input string.\n\n Args:\n s (str): The input string.\n\n Returns:\n str: The modified string with characters at odd indexes removed.\n \"\"\"\n return ''.join(s[i] for i in range(len(s)) if i % 2 == 0)", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(input_string: str) -> str:\n # Use a list comprehension to keep only characters at odd indices\n result = ''.join([input_string[i] for i in range(len(input_string)) if i % 2 == 0])\n return result", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(s: str) -> str:\n # Using a list comprehension to select characters at even indexes (0, 2, 4, ...)\n return ''.join([s[i] for i in range(0, len(s), 2)])", "matching_cluster_idx": 4}, {"solution": "def odd_values_string(s):\n \"\"\"\n Remove characters from a given string that are at odd index values.\n\n :param s: Input string\n :return: String with characters at even index values\n \"\"\"\n return ''.join(s[i] for i in range(len(s)) if i % 2 == 0)", "matching_cluster_idx": 0}, {"solution": "def odd_values_string(s):\n \"\"\"\n Remove the characters which have odd index values from a given string.\n\n Parameters:\n s (str): The input string.\n\n Returns:\n str: The string with characters at odd indexes removed.\n \"\"\"\n return ''.join(s[i] for i in range(len(s)) if i % 2 == 0)", "matching_cluster_idx": 0}]}, "Mbpp/230": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def replace_blank(string, char):\n \"\"\"\n Replaces blank spaces in the input string with the specified character.\n\n :param string: The input string to modify.\n :param char: The character to replace blank spaces with.\n :return: The modified string with blank spaces replaced.\n \"\"\"\n return string.replace(' ', char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(s, char):\n \"\"\"\n Replaces blank spaces in the string `s` with the character `char`.\n\n Parameters:\n s (str): The input string.\n char (str): The character to replace blank spaces with.\n\n Returns:\n str: The modified string with blank spaces replaced by `char`.\n \"\"\"\n return s.replace(' ', char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(s: str, char: str) -> str:\n \"\"\"\n Replaces blank spaces in the string `s` with the character `char` and returns the modified string.\n\n Parameters:\n s (str): The input string to process.\n char (str): The character to replace the blank spaces with.\n\n Returns:\n str: The string with blank spaces replaced by the character `char`.\n \"\"\"\n return s.replace(' ', char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(string, char):\n \"\"\"\n Replaces blank spaces in the string with the given character.\n\n Parameters:\n string (str): The string to modify.\n char (str): The character to replace blank spaces with.\n\n Returns:\n str: The modified string.\n \"\"\"\n return string.replace(' ', char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(string, char):\n # Replace all blank spaces in the string with the specified character\n return string.replace(\" \", char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string, char):\n \"\"\"\n Replaces blank spaces in the input_string with the given character and returns the modified string.\n\n Args:\n input_string (str): The original string.\n char (str): The character to replace the blank spaces.\n\n Returns:\n str: The string with blank spaces replaced by the given character.\n \"\"\"\n return input_string.replace(' ', char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(s, char):\n \"\"\"\n Replaces blank spaces in the string s with the character char.\n\n Args:\n s (str): The input string.\n char (str): The character to replace the blank spaces with.\n\n Returns:\n str: The string with blank spaces replaced by char.\n \"\"\"\n return s.replace(' ', char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(string, char):\n \"\"\"\n Replaces blank spaces in the given string with the provided character.\n\n Args:\n string (str): The original string.\n char (str): The character to replace blank spaces with.\n\n Returns:\n str: The modified string with blank spaces replaced.\n \"\"\"\n return string.replace(' ', char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(s, char):\n \"\"\"\n This function replaces all blank spaces in the string `s` with the character `char` and returns the modified string.\n\n Parameters:\n s (str): The input string.\n char (str): The character to replace blank spaces with.\n\n Returns:\n str: The string with blank spaces replaced by `char`.\n \"\"\"\n return s.replace(' ', char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string, character):\n \"\"\"\n Replaces all blank spaces in the input string with the specified character.\n\n Args:\n input_string (str): The original string with blank spaces.\n character (str): The character to replace blank spaces with.\n\n Returns:\n str: The modified string with blank spaces replaced by the specified character.\n \"\"\"\n return input_string.replace(' ', character)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(s, char):\n # Using the replace method to substitute spaces with the provided character\n return s.replace(' ', char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string, character):\n # Use the replace() method to replace all spaces with the given character\n return input_string.replace(' ', character)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(s, char):\n \"\"\"\n Replaces all blank spaces in the string `s` with the character `char`.\n\n :param s: Input string\n :param char: Character to replace blank spaces\n :return: String with blank spaces replaced by `char`\n \"\"\"\n return s.replace(' ', char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(s: str, char: str) -> str:\n \"\"\"\n Replaces all blank spaces in the string s with the character char.\n\n Args:\n s (str): The original string.\n char (str): The character to replace the blank spaces with.\n\n Returns:\n str: The modified string with blank spaces replaced.\n \"\"\"\n return s.replace(' ', char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(s, char):\n \"\"\"\n Replace blank spaces in the string s with the character char.\n\n Parameters:\n s (str): The input string.\n char (str): The character to replace blank spaces with.\n\n Returns:\n str: The modified string with blank spaces replaced.\n \"\"\"\n return s.replace(' ', char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(s, char):\n \"\"\"\n Replace blank spaces in the string with the given character.\n\n Parameters:\n s (str): Input string with spaces.\n char (str): Character to replace the spaces with.\n\n Returns:\n str: String with spaces replaced by the given character.\n \"\"\"\n return s.replace(\" \", char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(string, char):\n \"\"\"\n Replace blank spaces in the string with the given character.\n\n :param string: The input string with spaces to be replaced.\n :param char: The character to replace the spaces with.\n :return: The modified string with spaces replaced.\n \"\"\"\n return string.replace(\" \", char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(s: str, char: str) -> str:\n # Use the built-in replace method to replace all spaces with the given character\n return s.replace(' ', char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(input_string, char):\n return input_string.replace(' ', char)", "matching_cluster_idx": 7}, {"solution": "def replace_blank(s, char):\n \"\"\"\n Replace all blank spaces in the string with the specified character.\n\n Args:\n s (str): The input string.\n char (str): The character to replace blank spaces with.\n\n Returns:\n str: The modified string with blank spaces replaced by the specified character.\n \"\"\"\n return s.replace(' ', char)", "matching_cluster_idx": 7}]}, "Mbpp/239": {"dps": null, "dps_norm": null, "pass@1": 4.0, "profiled": []}, "Mbpp/240": {"dps": 70.85365853658537, "dps_norm": 81.11111111111111, "pass@1": 32.0, "profiled": [{"solution": "def replace_list(lst1, lst2):\n \"\"\"\n Replaces the last element of the first list with the elements of the second list.\n\n Args:\n lst1 (list): The first list where the last element will be replaced.\n lst2 (list): The second list whose elements will replace the last element of the first list.\n\n Returns:\n list: A new list with the modifications made.\n \"\"\"\n # Remove the last element from the first list\n lst1 = lst1[:-1]\n\n # Extend the first list with the elements of the second list\n lst1.extend(lst2)\n\n return lst1", "matching_cluster_idx": 6}, {"solution": "def replace_list(lst1, lst2):\n # Ensure the first list is not empty\n if not lst1:\n return lst2\n # Slice the first list to exclude the last element, and extend it with elements from the second list\n return lst1[:-1] + lst2", "matching_cluster_idx": 5}, {"solution": "def replace_list(list1, list2):\n # Replace the last element of list1 with list2\n if len(list1) > 0:\n list1[-1:] = list2\n else:\n list1.extend(list2)\n return list1", "matching_cluster_idx": 7}, {"solution": "def replace_list(first_list, second_list):\n # Replace the last element of the first list with the entire second list\n index = len(first_list) - 1\n first_list[index:] = second_list\n return first_list", "matching_cluster_idx": 6}, {"solution": "def replace_list(lst1, lst2):\n if len(lst1) > 0:\n lst1[-1:] = lst2\n else:\n lst1.extend(lst2)\n return lst1", "matching_cluster_idx": 7}, {"solution": "def replace_list(lst1, lst2):\n # Find the last index of the first list\n last_index = len(lst1) - 1\n\n # Extend the first list with the elements of the second list starting from the last index\n lst1[last_index:] = lst2\n\n return lst1", "matching_cluster_idx": 6}, {"solution": "def replace_list(lst1, lst2):\n \"\"\"\n Replaces the last element of the first list with the elements of the second list.\n\n Args:\n lst1 (list): The first list where the last element will be replaced.\n lst2 (list): The second list whose elements will replace the last element of the first list.\n\n Returns:\n list: The modified first list.\n \"\"\"\n if len(lst1) == 0:\n return lst2\n # Replace the last element with the second list\n lst1[-1:] = lst2\n return lst1", "matching_cluster_idx": 7}, {"solution": "def replace_list(list1, list2):\n # Check if list1 has at least one element\n if not list1:\n return list2\n\n # Remove the last element of list1\n list1.pop()\n\n # Extend list1 with elements of list2\n list1.extend(list2)\n\n return list1", "matching_cluster_idx": 8}, {"solution": "def replace_list(list1, list2):\n # Get the index of the last element in list1\n last_index = len(list1) - 1\n # Replace the last element with the elements of list2\n list1[last_index:] = list2\n return list1", "matching_cluster_idx": 6}, {"solution": "def replace_list(first_list, second_list):\n \"\"\"\n Replaces the last element of the first list with the elements of the second list.\n \"\"\"\n # Get the index of the last element in the first list\n last_index = len(first_list) - 1\n\n # Replace the last element with the second list\n first_list[last_index:] = second_list\n\n return first_list", "matching_cluster_idx": 6}, {"solution": "def replace_list(list1, list2):\n # Extend list1 by replacing its last element with elements of list2\n if list1: # Check if list1 is not empty\n list1[-1:] = list2 # Replace the last element of list1 with list2\n else:\n list1.extend(list2) # If list1 is empty, extend it with all elements of list2\n return list1", "matching_cluster_idx": 7}, {"solution": "def replace_list(lst1, lst2):\n \"\"\"\n Replaces the last element of lst1 with the elements of lst2.\n\n Parameters:\n lst1 (list): The first list.\n lst2 (list): The second list.\n\n Returns:\n list: The modified first list.\n \"\"\"\n # Find the index of the last element of lst1\n last_index = len(lst1) - 1\n\n # Replace the last element with lst2\n lst1[last_index:] = lst2\n\n return lst1", "matching_cluster_idx": 6}, {"solution": "def replace_list(lst1, lst2):\n # Replace the last element of lst1 with elements of lst2\n last_index = len(lst1) - 1\n lst1[last_index:] = lst2\n return lst1", "matching_cluster_idx": 6}, {"solution": "def replace_list(lst1, lst2):\n # Check if lst1 is not empty and replace the last element with lst2\n if lst1:\n index = len(lst1) - 1\n lst1[index:] = lst2\n # If lst1 is empty, return lst2\n else:\n lst1 = lst2\n return lst1", "matching_cluster_idx": 6}, {"solution": "def replace_list(list1, list2):\n # Check if list1 has at least one element\n if len(list1) == 0:\n raise ValueError(\"list1 must contain at least one element\")\n\n # Replace the last element of list1 with list2\n list1[-1:] = list2\n return list1", "matching_cluster_idx": 7}, {"solution": "def replace_list(lst1, lst2):\n if len(lst1) > 0:\n lst1[-1:] = lst2 # Replace the last element of lst1 with lst2\n return lst1", "matching_cluster_idx": 7}, {"solution": "def replace_list(lst1, lst2):\n # Check if the first list has at least one element\n if len(lst1) > 0:\n # Replace the last element of lst1 with the entire lst2\n lst1[:-1] = lst1[:-1]\n lst1[-1:] = lst2\n else:\n # If lst1 is empty, return lst2\n lst1 = lst2\n return lst1", "matching_cluster_idx": 5}, {"solution": "def replace_list(first_list, second_list):\n # Calculate the index of the last element in the first list\n last_index = len(first_list) - 1\n\n # Remove the last element of the first list\n first_list = first_list[:last_index]\n\n # Extend the first list with the elements of the second list\n first_list.extend(second_list)\n\n return first_list", "matching_cluster_idx": 6}, {"solution": "def replace_list(lst1, lst2):\n \"\"\"\n Replace the last element of the first list with the elements of the second list.\n\n Parameters:\n lst1 (list): The first list.\n lst2 (list): The second list whose elements will replace the last element of lst1.\n\n Returns:\n list: A new list where the last element of lst1 is replaced by the elements of lst2.\n \"\"\"\n # Calculate the last element index of the first list\n last_index = len(lst1) - 1\n\n # Create a new list by concatenating lst1 (excluding the last element) and lst2\n new_list = lst1[:last_index] + lst2\n\n return new_list", "matching_cluster_idx": 5}, {"solution": "def replace_list(lst1, lst2):\n # Ensure lst1 has at least one element\n if len(lst1) == 0:\n return lst2\n\n # Replace the last element with the elements of lst2\n lst1[-1:] = lst2\n return lst1", "matching_cluster_idx": 7}]}, "Mbpp/251": {"dps": 41.66666666666667, "dps_norm": 65.0, "pass@1": 42.0, "profiled": [{"solution": "def insert_element(lst, elem):\n # Initialize an empty result list\n result = []\n\n # Iterate over the input list\n for index, value in enumerate(lst):\n # Insert the element before the current value\n result.append(elem)\n result.append(value)\n\n return result", "matching_cluster_idx": 4}, {"solution": "def insert_element(lst, element):\n result = []\n for idx in range(len(lst)):\n result.append(element)\n result.append(lst[idx])\n return result", "matching_cluster_idx": 5}, {"solution": "def insert_element(lst, elem):\n # Start with an empty result list\n result = []\n\n # Iterate over the input list\n for i in range(len(lst)):\n # Insert the element before the current element of the list\n result.append(elem)\n result.append(lst[i])\n\n return result", "matching_cluster_idx": 5}, {"solution": "def insert_element(lst, element):\n result = []\n for i in range(len(lst)):\n result.append(element)\n if i < len(lst):\n result.append(lst[i])\n return result", "matching_cluster_idx": 4}, {"solution": "def insert_element(lst, elem):\n result = []\n for i in range(len(lst)):\n result.append(elem)\n result.append(lst[i])\n return result", "matching_cluster_idx": 4}, {"solution": "def insert_element(lst, element):\n # Initialize an empty list to hold the resulting elements\n result = []\n\n # Loop through the input list\n for index in range(len(lst)):\n # Append the element before the current element in the list\n result.append(element)\n result.append(lst[index])\n\n return result", "matching_cluster_idx": 4}, {"solution": "def insert_element(lst, elem):\n # Create a new list to store the result\n result = []\n\n # Iterate through the input list\n for i in range(len(lst)):\n # Insert the element before the current element\n result.append(elem)\n # Append the current element to the result\n result.append(lst[i])\n\n return result", "matching_cluster_idx": 4}, {"solution": "def insert_element(lst, elem):\n result = []\n for item in lst:\n result.append(elem)\n result.append(item)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n \"\"\"\n Inserts the given element before each element in the list and returns the resulting list.\n\n Args:\n lst (list): The input list.\n element: The element to be inserted before each element in the list.\n\n Returns:\n list: A new list with the element inserted before each element of the input list.\n \"\"\"\n result = []\n for item in lst:\n result.append(element)\n result.append(item)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n # Initialize an empty list to store the result\n result = []\n\n # Loop through the input list\n for i in range(len(lst)):\n # Append the element and the current list element to the result\n result.append(element)\n result.append(lst[i])\n\n # Return the resulting list\n return result", "matching_cluster_idx": 4}, {"solution": "def insert_element(lst, elem):\n # Initialize an empty result list\n result = []\n\n # Iterate over the input list\n for item in lst:\n # Append the element to insert and the current item to the result list\n result.append(elem)\n result.append(item)\n\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, elem):\n if not lst:\n return []\n\n result = []\n for i in range(len(lst)):\n result.append(elem)\n result.append(lst[i])\n\n return result", "matching_cluster_idx": 4}, {"solution": "def insert_element(lst, element):\n result = []\n for item in lst:\n result.append(element)\n result.append(item)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n # Initialize an empty list to store the result\n result = []\n\n # Iterate through the input list\n for i in range(len(lst)):\n # Insert the element before the current element in the list\n result.append(element)\n # Append the current element to the result list\n result.append(lst[i])\n\n # Return the resulting list\n return result", "matching_cluster_idx": 4}, {"solution": "def insert_element(lst, elem):\n result = []\n for item in lst:\n result.append(elem)\n result.append(item)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n \"\"\"\n Inserts an element before each element in the list.\n\n Args:\n lst (list): The list of elements.\n element: The element to be inserted before each element in the list.\n\n Returns:\n list: A new list with the element inserted before each element.\n \"\"\"\n if not lst:\n return []\n\n result = []\n for item in lst:\n result.append(element)\n result.append(item)\n\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, element):\n result = []\n for item in lst:\n result.append(element)\n result.append(item)\n return result", "matching_cluster_idx": 6}, {"solution": "def insert_element(lst, elem):\n result = []\n for i in range(len(lst)):\n result.append(elem)\n result.append(lst[i])\n return result", "matching_cluster_idx": 4}, {"solution": "def insert_element(lst, element):\n result = []\n for i in range(len(lst)):\n result.append(element)\n result.append(lst[i])\n return result", "matching_cluster_idx": 4}, {"solution": "def insert_element(lst, element):\n # Initialize an empty list to store the resulting elements\n result = []\n\n # Iterate over the input list\n for i in range(len(lst)):\n # Append the element before the current element of the list\n result.append(element)\n # Append the current element of the list\n result.append(lst[i])\n\n return result", "matching_cluster_idx": 5}]}, "Mbpp/256": {"dps": 72.55707762557077, "dps_norm": 67.6470588235294, "pass@1": 76.0, "profiled": [{"solution": "def is_prime(n):\n \"\"\"Helper function to check if a number is prime.\"\"\"\n if n <= 1:\n return False\n if n == 2:\n return True\n if n % 2 == 0:\n return False\n max_divisor = int(n**0.5) + 1\n for d in range(3, max_divisor, 2):\n if n % d == 0:\n return False\n return True\ndef count_Primes_nums(limit):\n \"\"\"Function to count prime numbers less than the given non-negative number.\"\"\"\n count = 0\n for num in range(2, limit):\n if is_prime(num):\n count += 1\n return count", "matching_cluster_idx": 10}, {"solution": "def is_prime(n):\n \"\"\"Helper function to check if a number is prime.\"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True\ndef count_Primes_nums(n):\n \"\"\"Function to count the number of prime numbers less than the given non-negative number.\"\"\"\n prime_count = 0\n for i in range(2, n):\n if is_prime(i):\n prime_count += 1\n return prime_count", "matching_cluster_idx": 10}, {"solution": "import math\ndef is_prime(n):\n \"\"\"Helper function to check if a number is prime.\"\"\"\n if n <= 1:\n return False\n if n == 2:\n return True\n if n % 2 == 0:\n return False\n for i in range(3, int(math.sqrt(n)) + 1, 2):\n if n % i == 0:\n return False\n return True\ndef count_Primes_nums(n):\n \"\"\"Function to count the number of prime numbers less than the given number.\"\"\"\n count = 0\n for i in range(2, n):\n if is_prime(i):\n count += 1\n return count", "matching_cluster_idx": 10}, {"solution": "def count_Primes_nums(n):\n if n < 2:\n return 0\n\n # Initialize a list to keep track of prime numbers\n primes = [True] * n\n primes[0] = primes[1] = False # 0 and 1 are not prime numbers\n\n # Sieve of Eratosthenes to find all primes <= n\n p = 2\n while p * p < n:\n if primes[p]:\n for i in range(p * p, n, p):\n primes[i] = False\n p += 1\n\n # Count the number of primes\n return sum(primes)", "matching_cluster_idx": 14}, {"solution": "def is_prime(n):\n \"\"\"Helper function to check if a number is prime.\"\"\"\n if n <= 1:\n return False\n if n == 2:\n return True\n if n % 2 == 0:\n return False\n for i in range(3, int(n**0.5) + 1, 2):\n if n % i == 0:\n return False\n return True\ndef count_Primes_nums(limit):\n \"\"\"Function to count the number of prime numbers less than the given non-negative number.\"\"\"\n count = 0\n for num in range(2, limit):\n if is_prime(num):\n count += 1\n return count", "matching_cluster_idx": 10}, {"solution": "def is_prime(n):\n \"\"\"Helper function to check if a number is prime.\"\"\"\n if n <= 1:\n return False\n if n == 2:\n return True\n if n % 2 == 0:\n return False\n for i in range(3, int(n ** 0.5) + 1, 2):\n if n % i == 0:\n return False\n return True\ndef count_Primes_nums(limit):\n \"\"\"Function that counts the number of prime numbers less than the given non-negative number.\"\"\"\n count = 0\n for num in range(2, limit):\n if is_prime(num):\n count += 1\n return count", "matching_cluster_idx": 10}, {"solution": "def count_Primes_nums(n):\n if n < 2:\n return 0\n primes = [True] * n\n primes[0] = primes[1] = False # 0 and 1 are not prime numbers\n for i in range(2, int(n**0.5) + 1):\n if primes[i]:\n for j in range(i*i, n, i):\n primes[j] = False\n return sum(primes)", "matching_cluster_idx": 14}, {"solution": "def count_Primes_nums(n):\n if n < 2:\n return 0\n\n # Initializing the list to keep track of prime numbers\n is_prime = [True] * n\n is_prime[0] = is_prime[1] = False\n\n # Use Sieve of Eratosthenes algorithm to find all prime numbers up to n\n for i in range(2, int(n**0.5) + 1):\n if is_prime[i]:\n for j in range(i * i, n, i):\n is_prime[j] = False\n\n # Count the number of prime numbers\n return sum(is_prime)", "matching_cluster_idx": 14}, {"solution": "def count_Primes_nums(n):\n def is_prime(num):\n if num <= 1:\n return False\n if num <= 3:\n return True\n if num % 2 == 0 or num % 3 == 0:\n return False\n i = 5\n while i * i <= num:\n if num % i == 0 or num % (i + 2) == 0:\n return False\n i += 6\n return True\n\n count = 0\n for i in range(2, n):\n if is_prime(i):\n count += 1\n return count", "matching_cluster_idx": 10}, {"solution": "def count_Primes_nums(n):\n \"\"\"\n Counts the number of prime numbers less than a given non-negative number.\n\n Args:\n n (int): A non-negative integer.\n\n Returns:\n int: The number of prime numbers less than n.\n \"\"\"\n if n <= 1:\n return 0\n\n def is_prime(num):\n if num <= 1:\n return False\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n return False\n return True\n\n prime_count = 0\n for i in range(2, n):\n if is_prime(i):\n prime_count += 1\n return prime_count", "matching_cluster_idx": 8}, {"solution": "def is_prime(n):\n \"\"\"Helper function to check if a number is prime.\"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True\ndef count_Primes_nums(num):\n \"\"\"Count the number of prime numbers less than the given non-negative number.\"\"\"\n count = 0\n for i in range(num):\n if is_prime(i):\n count += 1\n return count", "matching_cluster_idx": 10}, {"solution": "import math\ndef is_prime(num):\n if num <= 1:\n return False\n if num == 2:\n return True\n if num % 2 == 0:\n return False\n sqrt_num = int(math.sqrt(num)) + 1\n for i in range(3, sqrt_num, 2):\n if num % i == 0:\n return False\n return True\ndef count_Primes_nums(n):\n count = 0\n for i in range(2, n):\n if is_prime(i):\n count += 1\n return count", "matching_cluster_idx": 9}, {"solution": "def count_Primes_nums(n):\n if n <= 1:\n return 0\n\n # Initialize the sieve with all numbers marked as prime\n sieve = [True] * n\n sieve[0] = sieve[1] = False\n\n # Implement the Sieve of Eratosthenes\n for i in range(2, int(n**0.5) + 1):\n if sieve[i]:\n for j in range(i*i, n, i):\n sieve[j] = False\n\n # Count the number of primes less than n\n return sum(sieve)", "matching_cluster_idx": 14}, {"solution": "def is_prime(num):\n \"\"\"Helper function to check if a number is prime.\"\"\"\n if num <= 1:\n return False\n if num == 2:\n return True\n if num % 2 == 0:\n return False\n for i in range(3, int(num**0.5) + 1, 2):\n if num % i == 0:\n return False\n return True\ndef count_Primes_nums(n):\n \"\"\"Function to count the number of primes less than n.\"\"\"\n count = 0\n for num in range(2, n):\n if is_prime(num):\n count += 1\n return count", "matching_cluster_idx": 10}, {"solution": "def is_prime(num):\n \"\"\"Helper function to check if a number is prime.\"\"\"\n if num <= 1:\n return False\n if num == 2:\n return True\n if num % 2 == 0:\n return False\n for i in range(3, int(num**0.5) + 1, 2):\n if num % i == 0:\n return False\n return True\ndef count_Primes_nums(n):\n \"\"\"Function to count the number of prime numbers less than a given non-negative number.\"\"\"\n count = 0\n for i in range(2, n):\n if is_prime(i):\n count += 1\n return count", "matching_cluster_idx": 10}, {"solution": "def is_prime(n):\n \"\"\"Helper function to check if a number is prime.\"\"\"\n if n <= 1:\n return False\n if n == 2:\n return True\n if n % 2 == 0:\n return False\n for i in range(3, int(n ** 0.5) + 1, 2):\n if n % i == 0:\n return False\n return True\ndef count_Primes_nums(n):\n \"\"\"Function to count the number of prime numbers less than a given non-negative number.\"\"\"\n count = 0\n for num in range(2, n):\n if is_prime(num):\n count += 1\n return count", "matching_cluster_idx": 10}, {"solution": "def is_prime(num):\n if num <= 1:\n return False\n if num <= 3:\n return True\n if num % 2 == 0 or num % 3 == 0:\n return False\n i = 5\n while i * i <= num:\n if num % i == 0 or num % (i + 2) == 0:\n return False\n i += 6\n return True\ndef count_Primes_nums(n):\n count = 0\n for i in range(2, n):\n if is_prime(i):\n count += 1\n return count", "matching_cluster_idx": 10}, {"solution": "import math\ndef is_prime(n):\n if n <= 1:\n return False\n if n == 2:\n return True\n if n % 2 == 0:\n return False\n sqrt_n = int(math.sqrt(n)) + 1\n for i in range(3, sqrt_n, 2):\n if n % i == 0:\n return False\n return True\ndef count_Primes_nums(n):\n count = 0\n for i in range(n):\n if is_prime(i):\n count += 1\n return count", "matching_cluster_idx": 9}, {"solution": "def is_prime(n):\n \"\"\"Helper function to check if a number is prime.\"\"\"\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n % i == 0 or n % (i + 2) == 0:\n return False\n i += 6\n return True\ndef count_Primes_nums(n):\n \"\"\"Function to count the number of prime numbers less than the given non-negative number.\"\"\"\n count = 0\n for i in range(2, n):\n if is_prime(i):\n count += 1\n return count", "matching_cluster_idx": 10}, {"solution": "def count_Primes_nums(n):\n \"\"\"\n This function takes a non-negative integer n and returns the count of prime numbers less than n.\n \"\"\"\n if n < 2:\n return 0\n\n def is_prime(num):\n \"\"\"\n Helper function to check if a number is prime.\n \"\"\"\n if num < 2:\n return False\n for i in range(2, int(num ** 0.5) + 1):\n if num % i == 0:\n return False\n return True\n\n prime_count = 0\n for num in range(2, n):\n if is_prime(num):\n prime_count += 1\n\n return prime_count", "matching_cluster_idx": 8}]}, "Mbpp/265": {"dps": 57.7906976744186, "dps_norm": 75.83333333333333, "pass@1": 45.0, "profiled": [{"solution": "def list_split(lst, n):\n # Number of sublists needed\n num_sublists = len(lst) // n\n remainder = len(lst) % n\n\n sublists = [[] for _ in range(n)]\n\n for i, elem in enumerate(lst):\n sublists[i % n].append(elem)\n\n # Adjust for remainders if there are any\n if remainder != 0:\n sublists = [sublist[:num_sublists + 1] for sublist in sublists]\n\n return sublists", "matching_cluster_idx": 2}, {"solution": "def list_split(lst, n):\n if n <= 0:\n raise ValueError(\"n must be greater than 0\")\n\n result = [[] for _ in range(n)]\n\n for i, item in enumerate(lst):\n result[i % n].append(item)\n\n return result", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n \"\"\"\n Splits the list into multiple lists, each containing every nth element.\n\n :param lst: List of elements to be split.\n :param n: The interval at which to split the list.\n :return: List of lists, each containing elements at nth intervals.\n \"\"\"\n result = []\n for i in range(n):\n sublist = [lst[j] for j in range(i, len(lst), n)]\n result.append(sublist)\n return result", "matching_cluster_idx": 1}, {"solution": "def list_split(lst, n):\n result = [[] for _ in range(n)]\n for i, item in enumerate(lst):\n result[i % n].append(item)\n return result", "matching_cluster_idx": 4}, {"solution": "def list_split(input_list, n):\n # Create a new list of lists with n elements each\n split_lists = [input_list[i::n] for i in range(n)]\n return split_lists", "matching_cluster_idx": 5}, {"solution": "def list_split(lst, n):\n result = [[] for _ in range(n)]\n for i, item in enumerate(lst):\n result[i % n].append(item)\n return result", "matching_cluster_idx": 4}, {"solution": "def list_split(input_list, n):\n \"\"\"\n Splits the input list into sublists every nth element.\n\n Parameters:\n input_list (list): The list to be split.\n n (int): The interval at which to split the list.\n\n Returns:\n list: A list of lists, with each sublist containing every nth element from the original list.\n \"\"\"\n if n <= 0:\n raise ValueError(\"n must be a positive integer.\")\n\n length = len(input_list)\n result = [[] for _ in range(n)]\n\n for i in range(length):\n result[i % n].append(input_list[i])\n\n return result", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n result = [[] for _ in range(n)]\n for i in range(len(lst)):\n result[i % n].append(lst[i])\n return result", "matching_cluster_idx": 4}, {"solution": "def list_split(input_list, n):\n \"\"\"\n Splits a list into n lists with elements equally distributed.\n\n Args:\n input_list (list): The list to be split.\n n (int): The number of lists to split into.\n\n Returns:\n list: A list containing n lists with equally distributed elements.\n \"\"\"\n result = [[] for _ in range(n)]\n\n for i, item in enumerate(input_list):\n result[i % n].append(item)\n\n return result", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n \"\"\"\n Splits a list into a list of lists, with each sublist containing every nth element.\n\n :param lst: List to be split\n :param n: Interval for splitting the list\n :return: List of sublists\n \"\"\"\n result = [lst[i::n] for i in range(n)]\n return result", "matching_cluster_idx": 5}, {"solution": "def list_split(input_list, n):\n \"\"\"\n Splits the input list into n sublists starting from the first element.\n\n Args:\n input_list (list): The list to be split.\n n (int): The number of sublists to create.\n\n Returns:\n list: A list containing n sublists.\n \"\"\"\n result = [[] for _ in range(n)]\n for i, item in enumerate(input_list):\n result[i % n].append(item)\n return result", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n \"\"\"\n Splits the input list into n sublists, starting from the first element.\n\n Args:\n lst (list): The list to be split.\n n (int): The number of sublists to be created.\n\n Returns:\n list: A list of sublists.\n \"\"\"\n # Initialize the resulting list of sublists\n result = [[] for _ in range(n)]\n\n # Iterate over the input list and distribute elements into the n sublists\n for index, item in enumerate(lst):\n result[index % n].append(item)\n\n return result", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n result = []\n for i in range(n):\n part = []\n for j in range(i, len(lst), n):\n part.append(lst[j])\n result.append(part)\n return result", "matching_cluster_idx": 3}, {"solution": "def list_split(input_list, n):\n \"\"\"\n Splits the input list for every nth element, returning a list of the resulting lists.\n\n Parameters:\n input_list (list): The list to be split.\n n (int): The interval at which to split the list.\n\n Returns:\n list: A list of lists, each containing elements from the original list.\n \"\"\"\n result = []\n for i in range(n):\n result.append([])\n for index, item in enumerate(input_list):\n result[index % n].append(item)\n return result", "matching_cluster_idx": 4}, {"solution": "def list_split(input_list, n):\n \"\"\"\n Splits the input list into n lists containing every nth element.\n\n Args:\n input_list (list): The list to be split.\n n (int): The number of splits.\n\n Returns:\n list: A list of lists, each containing every nth element from the input list.\n \"\"\"\n result = []\n length = len(input_list)\n for i in range(n):\n subset = []\n for j in range(i, length, n):\n subset.append(input_list[j])\n result.append(subset)\n return result", "matching_cluster_idx": 3}, {"solution": "def list_split(lst, n):\n result = []\n for i in range(n):\n result.append([])\n for i, value in enumerate(lst):\n result[i % n].append(value)\n return result", "matching_cluster_idx": 4}, {"solution": "def list_split(lst, n):\n result = []\n for i in range(n):\n sublist = [lst[j] for j in range(i, len(lst), n)]\n result.append(sublist)\n return result", "matching_cluster_idx": 1}, {"solution": "def list_split(lst, n):\n # Create the lists to be filled\n result = [[] for _ in range(n)]\n\n # Distribute the elements\n for i, elem in enumerate(lst):\n result[i % n].append(elem)\n\n return result", "matching_cluster_idx": 4}, {"solution": "def list_split(input_list, n):\n \"\"\"\n Splits the input list into n lists, each containing every nth element.\n\n Parameters:\n input_list (list): The list to be split.\n n (int): The number of splits to create.\n\n Returns:\n list: A list of lists, where each sublist contains elements from the input_list.\n \"\"\"\n # Creating n empty lists\n result = [[] for _ in range(n)]\n\n # Iterating over the input list\n for index, item in enumerate(input_list):\n # Adding the current item to the corresponding sublist\n result[index % n].append(item)\n\n return result", "matching_cluster_idx": 3}, {"solution": "def list_split(lst, n):\n result = [[] for _ in range(n)]\n for i, item in enumerate(lst):\n result[i % n].append(item)\n return result", "matching_cluster_idx": 4}]}, "Mbpp/281": {"dps": 94.1, "dps_norm": 82.72727272727272, "pass@1": 100.0, "profiled": [{"solution": "def all_unique(lst):\n \"\"\"\n Check if all elements in the given list are unique.\n\n Args:\n lst (list): A list of elements to check.\n\n Returns:\n bool: True if all elements are unique, False otherwise.\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"Check if all elements in the list are unique.\"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n Check if all elements in the list are unique.\n\n Parameters:\n lst (list): The list to check for uniqueness.\n\n Returns:\n bool: True if all elements are unique, False otherwise.\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n Function to check if all elements of the given list are unique.\n\n Parameters:\n lst (list): The list of elements to check.\n\n Returns:\n bool: True if all elements are unique, False otherwise.\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n Checks if the elements of a given list are unique.\n\n Parameters:\n lst (list): The list to check.\n\n Returns:\n bool: True if all elements are unique, False otherwise.\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n Check if all elements of the list are unique.\n\n Args:\n lst (list): The list of elements to check.\n\n Returns:\n bool: True if all elements are unique, False otherwise.\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n Check if all elements in the given list are unique.\n\n Args:\n lst (list): A list of elements to check for uniqueness.\n\n Returns:\n bool: True if all elements are unique, False otherwise.\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n Check if all elements in the given list are unique.\n\n Parameters:\n lst (list): The list to check for unique elements.\n\n Returns:\n bool: True if all elements are unique, False otherwise.\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n Function to check if all elements of the given list are unique.\n\n Parameters:\n lst (list): The list to check for uniqueness.\n\n Returns:\n bool: True if all elements are unique, False otherwise.\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n Check if all elements in the given list are unique.\n\n Args:\n lst (list): The list to check for uniqueness.\n\n Returns:\n bool: True if all elements are unique, False otherwise.\n \"\"\"\n # Using a set to track seen elements\n seen = set()\n for element in lst:\n if element in seen:\n return False\n seen.add(element)\n return True", "matching_cluster_idx": 9}, {"solution": "def all_unique(lst):\n # Convert the list to a set and compare its length with the length of the list\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n Check if all elements in the given list are unique.\n\n Parameters:\n lst (list): The list of elements to check.\n\n Returns:\n bool: True if all elements are unique, False otherwise.\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n This function checks if the elements of the given list are unique.\n\n Args:\n lst (list): A list of elements to check.\n\n Returns:\n bool: True if all elements are unique, False otherwise.\n \"\"\"\n # Using a set to track seen elements\n seen = set()\n\n for item in lst:\n if item in seen:\n return False\n seen.add(item)\n\n return True", "matching_cluster_idx": 9}, {"solution": "def all_unique(lst):\n # Use set to check if elements are unique\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n Check if the elements of the given list are unique.\n\n Parameters:\n lst (list): A list of elements\n\n Returns:\n bool: True if all elements are unique, False otherwise\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n Check if all elements in the given list are unique.\n\n Args:\n lst (list): List of elements to be checked.\n\n Returns:\n bool: True if all elements are unique, False otherwise.\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n This function checks if all elements in the given list are unique.\n\n Args:\n lst (list): A list of elements to check for uniqueness.\n\n Returns:\n bool: True if all elements are unique, False otherwise.\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n Check if all elements in the list are unique.\n\n Parameters:\n lst (list): The list to check.\n\n Returns:\n bool: True if all elements are unique, False otherwise.\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}, {"solution": "def all_unique(lst):\n \"\"\"\n Check if all elements in the list are unique.\n\n Args:\n lst (list): List of elements to check.\n\n Returns:\n bool: True if all elements are unique, False otherwise.\n \"\"\"\n return len(lst) == len(set(lst))", "matching_cluster_idx": 8}]}, "Mbpp/296": {"dps": 77.17948717948718, "dps_norm": 89.16666666666667, "pass@1": 66.0, "profiled": [{"solution": "def get_Inv_Count(arr):\n # Counting inversions in the given array\n count = 0\n n = len(arr)\n\n # Loop through each element of the array\n for i in range(n):\n for j in range(i + 1, n):\n # If element found is smaller than the next element, increment count\n if arr[i] > arr[j]:\n count += 1\n\n return count", "matching_cluster_idx": 3}, {"solution": "def merge_and_count(arr, temp_arr, left, mid, right):\n i = left\n j = mid + 1\n k = left\n inv_count = 0\n\n while i <= mid and j <= right:\n if arr[i] <= arr[j]:\n temp_arr[k] = arr[i]\n i += 1\n else:\n temp_arr[k] = arr[j]\n j += 1\n inv_count += (mid - i + 1)\n k += 1\n\n while i <= mid:\n temp_arr[k] = arr[i]\n i += 1\n k += 1\n\n while j <= right:\n temp_arr[k] = arr[j]\n j += 1\n k += 1\n\n for i in range(left, right + 1):\n arr[i] = temp_arr[i]\n\n return inv_count\ndef get_Inv_Count(arr):\n temp_arr = [0] * len(arr)\n return merge_sort_and_count(arr, temp_arr, 0, len(arr) - 1)\ndef merge_sort_and_count(arr, temp_arr, left, right):\n inv_count = 0\n\n if left < right:\n mid = (left + right) // 2\n\n inv_count += merge_sort_and_count(arr, temp_arr, left, mid)\n inv_count += merge_sort_and_count(arr, temp_arr, mid + 1, right)\n\n inv_count += merge_and_count(arr, temp_arr, left, mid, right)\n\n return inv_count", "matching_cluster_idx": 5}, {"solution": "def merge_and_count(arr, temp, left, mid, right):\n i = left\n j = mid + 1\n k = left\n inv_count = 0\n\n while i <= mid and j <= right:\n if arr[i] <= arr[j]:\n temp[k] = arr[i]\n i += 1\n else:\n temp[k] = arr[j]\n inv_count += (mid - i + 1)\n j += 1\n k += 1\n\n while i <= mid:\n temp[k] = arr[i]\n i += 1\n k += 1\n\n while j <= right:\n temp[k] = arr[j]\n j += 1\n k += 1\n\n for i in range(left, right + 1):\n arr[i] = temp[i]\n\n return inv_count\ndef merge_sort_and_count(arr, temp, left, right):\n inv_count = 0\n\n if left < right:\n mid = (left + right) // 2\n\n inv_count += merge_sort_and_count(arr, temp, left, mid)\n inv_count += merge_sort_and_count(arr, temp, mid + 1, right)\n\n inv_count += merge_and_count(arr, temp, left, mid, right)\n\n return inv_count\ndef get_Inv_Count(arr):\n temp = [0] * len(arr)\n return merge_sort_and_count(arr, temp, 0, len(arr) - 1)", "matching_cluster_idx": 5}, {"solution": "def get_Inv_Count(arr):\n def merge_sort_and_count_inversions(arr, tmp_arr, left, right):\n inv_count = 0\n if right > left:\n mid = (right + left) // 2\n inv_count += merge_sort_and_count_inversions(arr, tmp_arr, left, mid)\n inv_count += merge_sort_and_count_inversions(arr, tmp_arr, mid+1, right)\n inv_count += merge_and_count(arr, tmp_arr, left, mid, right)\n return inv_count\n\n def merge_and_count(arr, tmp_arr, left, mid, right):\n i = left\n j = mid + 1\n k = left\n inv_count = 0\n while i <= mid and j <= right:\n if arr[i] <= arr[j]:\n tmp_arr[k] = arr[i]\n i += 1\n else:\n tmp_arr[k] = arr[j]\n inv_count += (mid - i + 1)\n j += 1\n k += 1\n\n while i <= mid:\n tmp_arr[k] = arr[i]\n i += 1\n k += 1\n\n while j <= right:\n tmp_arr[k] = arr[j]\n j += 1\n k += 1\n\n for i in range(left, right + 1):\n arr[i] = tmp_arr[i]\n\n return inv_count\n\n tmp = [0]*len(arr)\n return merge_sort_and_count_inversions(arr, tmp, 0, len(arr)-1)", "matching_cluster_idx": 5}, {"solution": "def get_Inv_Count(arr):\n inv_count = 0\n for i in range(len(arr)):\n for j in range(i + 1, len(arr)):\n if arr[i] > arr[j]:\n inv_count += 1\n return inv_count", "matching_cluster_idx": 2}, {"solution": "def merge_and_count(arr, temp_arr, left, mid, right):\n i = left\n j = mid + 1\n k = left\n inv_count = 0\n\n while i <= mid and j <= right:\n if arr[i] <= arr[j]:\n temp_arr[k] = arr[i]\n i += 1\n else:\n temp_arr[k] = arr[j]\n inv_count += (mid - i + 1)\n j += 1\n k += 1\n\n while i <= mid:\n temp_arr[k] = arr[i]\n i += 1\n k += 1\n\n while j <= right:\n temp_arr[k] = arr[j]\n j += 1\n k += 1\n\n for i in range(left, right + 1):\n arr[i] = temp_arr[i]\n\n return inv_count\ndef merge_sort_and_count(arr, temp_arr, left, right):\n inv_count = 0\n\n if left < right:\n mid = (left + right) // 2\n\n inv_count += merge_sort_and_count(arr, temp_arr, left, mid)\n inv_count += merge_sort_and_count(arr, temp_arr, mid + 1, right)\n\n inv_count += merge_and_count(arr, temp_arr, left, mid, right)\n\n return inv_count\ndef get_Inv_Count(arr):\n temp_arr = [0] * len(arr)\n return merge_sort_and_count(arr, temp_arr, 0, len(arr) - 1)", "matching_cluster_idx": 5}, {"solution": "def get_Inv_Count(arr):\n # Initialize inversion count\n inversions = 0\n\n # Traverse through all pairs\n for i in range(len(arr)):\n for j in range(i + 1, len(arr)):\n # If element found is smaller than the next element then increment count of inversions\n if arr[i] > arr[j]:\n inversions += 1\n\n return inversions", "matching_cluster_idx": 3}, {"solution": "def get_Inv_Count(arr):\n inv_count = 0\n\n for i in range(len(arr)):\n for j in range(i+1, len(arr)):\n if arr[i] > arr[j]:\n inv_count += 1\n\n return inv_count", "matching_cluster_idx": 3}, {"solution": "def merge_sort_and_count(arr):\n \"\"\"\n Helper function that sorts the array and counts the inversions using merge sort.\n \"\"\"\n if len(arr) > 1:\n mid = len(arr) // 2\n left_half = arr[:mid]\n right_half = arr[mid:]\n\n # Recursively sort and count inversions in both halves\n left_inversions = merge_sort_and_count(left_half)\n right_inversions = merge_sort_and_count(right_half)\n\n # Merge the two halves and count inversions\n i = j = k = 0\n inversions = 0\n\n while i < len(left_half) and j < len(right_half):\n if left_half[i] <= right_half[j]:\n arr[k] = left_half[i]\n i += 1\n else:\n arr[k] = right_half[j]\n j += 1\n inversions += (len(left_half) - i) # Count inversions\n k += 1\n\n # Copy the remaining elements\n while i < len(left_half):\n arr[k] = left_half[i]\n i += 1\n k += 1\n\n while j < len(right_half):\n arr[k] = right_half[j]\n j += 1\n k += 1\n\n # Total inversions\n return left_inversions + right_inversions + inversions\n\n return 0\ndef get_Inv_Count(arr):\n \"\"\"\n Function to count the number of inversions in the array.\n \"\"\"\n return merge_sort_and_count(arr)", "matching_cluster_idx": 5}, {"solution": "def merge_sort_and_count_inversions(arr):\n \"\"\"\n This function sorts the array and counts the number of inversions.\n \"\"\"\n # Helper function to perform merge and count inversions\n def merge_and_count(left, right):\n sorted_arr = []\n i = j = 0\n inv_count = 0\n\n # Merge the arrays and count the inversions\n while i < len(left) and j < len(right):\n if left[i] <= right[j]:\n sorted_arr.append(left[i])\n i += 1\n else:\n sorted_arr.append(right[j])\n inv_count += len(left) - i\n j += 1\n\n # Add remaining elements\n while i < len(left):\n sorted_arr.append(left[i])\n i += 1\n\n while j < len(right):\n sorted_arr.append(right[j])\n j += 1\n\n return sorted_arr, inv_count\n\n # Base case: a list of zero or one elements has zero inversions\n if len(arr) <= 1:\n return arr, 0\n\n # Recursively split the array into halves and merge the sorted halves\n mid = len(arr) // 2\n left_half = arr[:mid]\n right_half = arr[mid:]\n\n left_sorted, left_inv_count = merge_sort_and_count_inversions(left_half)\n right_sorted, right_inv_count = merge_sort_and_count_inversions(right_half)\n\n sorted_arr, split_inv_count = merge_and_count(left_sorted, right_sorted)\n\n # Total inversions = inversions within left + inversions within right + inversions across split\n return sorted_arr, left_inv_count + right_inv_count + split_inv_count\ndef get_Inv_Count(arr):\n _, inversion_count = merge_sort_and_count_inversions(arr)\n return inversion_count", "matching_cluster_idx": 5}, {"solution": "def merge_and_count(arr, temp, left, mid, right):\n i = left # Initial index of the left subarray\n j = mid + 1 # Initial index of the right subarray\n k = left # Initial index of the merged subarray\n inv_count = 0 # Number of inversions\n\n # Merging the two subarrays into temp array\n while i <= mid and j <= right:\n if arr[i] <= arr[j]:\n temp[k] = arr[i]\n i += 1\n else:\n temp[k] = arr[j]\n j += 1\n inv_count += mid - i + 1\n k += 1\n\n # Copying the remaining elements of left subarray, if any\n while i <= mid:\n temp[k] = arr[i]\n i += 1\n k += 1\n\n # Copying the remaining elements of right subarray, if any\n while j <= right:\n temp[k] = arr[j]\n j += 1\n k += 1\n\n # Copying back the merged elements to the original array\n for i in range(left, right + 1):\n arr[i] = temp[i]\n\n return inv_count\ndef merge_sort_and_count(arr, temp, left, right):\n inv_count = 0\n\n # Base case: An array or subarray of size 1 doesn't have inversions\n if left < right:\n mid = (left + right) // 2\n\n # Recursive call on the left subarray\n inv_count += merge_sort_and_count(arr, temp, left, mid)\n\n # Recursive call on the right subarray\n inv_count += merge_sort_and_count(arr, temp, mid + 1, right)\n\n # Merging the two subarrays and counting inversions\n inv_count += merge_and_count(arr, temp, left, mid, right)\n\n return inv_count\ndef get_Inv_Count(arr):\n temp = [0] * len(arr)\n return merge_sort_and_count(arr, temp, 0, len(arr) - 1)", "matching_cluster_idx": 5}, {"solution": "def merge_sort_and_count(arr):\n if len(arr) <= 1:\n return arr, 0\n\n mid = len(arr) // 2\n left_arr, left_inv_count = merge_sort_and_count(arr[:mid])\n right_arr, right_inv_count = merge_sort_and_count(arr[mid:])\n\n sorted_arr, inv_count = merge_and_count(left_arr, right_arr)\n return sorted_arr, left_inv_count + right_inv_count + inv_count\ndef merge_and_count(left, right):\n sorted_arr = []\n left_idx, right_idx = 0, 0\n inv_count = 0\n\n while left_idx < len(left) and right_idx < len(right):\n if left[left_idx] <= right[right_idx]:\n sorted_arr.append(left[left_idx])\n left_idx += 1\n else:\n sorted_arr.append(right[right_idx])\n inv_count += len(left) - left_idx\n right_idx += 1\n\n sorted_arr.extend(left[left_idx:])\n sorted_arr.extend(right[right_idx:])\n return sorted_arr, inv_count\ndef get_Inv_Count(arr):\n sorted_arr, inv_count = merge_sort_and_count(arr)\n return inv_count", "matching_cluster_idx": 5}, {"solution": "def merge_sort_and_count(arr):\n if len(arr) <= 1:\n return arr, 0\n\n mid = len(arr) // 2\n left, left_inv_count = merge_sort_and_count(arr[:mid])\n right, right_inv_count = merge_sort_and_count(arr[mid:])\n\n merged, inv_count = merge_and_count(left, right)\n\n return merged, left_inv_count + right_inv_count + inv_count\ndef merge_and_count(left, right):\n merged = []\n left_index = 0\n right_index = 0\n inv_count = 0\n\n while left_index < len(left) and right_index < len(right):\n if left[left_index] <= right[right_index]:\n merged.append(left[left_index])\n left_index += 1\n else:\n merged.append(right[right_index])\n inv_count += len(left) - left_index # inversions caused by the current element in right\n right_index += 1\n\n merged.extend(left[left_index:])\n merged.extend(right[right_index:])\n\n return merged, inv_count\ndef get_Inv_Count(arr):\n _, inv_count = merge_sort_and_count(arr)\n return inv_count", "matching_cluster_idx": 5}, {"solution": "def merge_sort_and_count(arr):\n if len(arr) <= 1:\n return arr, 0\n\n mid = len(arr) // 2\n left, left_inv_count = merge_sort_and_count(arr[:mid])\n right, right_inv_count = merge_sort_and_count(arr[mid:])\n\n sorted_arr = []\n i, j, inv_count = 0, 0, 0\n\n while i < len(left) and j < len(right):\n if left[i] <= right[j]:\n sorted_arr.append(left[i])\n i += 1\n else:\n sorted_arr.append(right[j])\n j += 1\n inv_count += (len(left) - i)\n\n sorted_arr += left[i:]\n sorted_arr += right[j:]\n\n return sorted_arr, inv_count + left_inv_count + right_inv_count\ndef get_Inv_Count(arr):\n sorted_arr, inv_count = merge_sort_and_count(arr)\n return inv_count", "matching_cluster_idx": 5}, {"solution": "def get_Inv_Count(arr):\n # Function to count inversions using merge sort\n def merge_sort(arr):\n if len(arr) <= 1:\n return arr, 0\n mid = len(arr) // 2\n left, left_inv_count = merge_sort(arr[:mid])\n right, right_inv_count = merge_sort(arr[mid:])\n merged, split_inv_count = merge(left, right)\n return merged, left_inv_count + right_inv_count + split_inv_count\n\n def merge(left, right):\n merged = []\n i = j = 0\n inv_count = 0\n while i < len(left) and j < len(right):\n if left[i] <= right[j]:\n merged.append(left[i])\n i += 1\n else:\n merged.append(right[j])\n j += 1\n inv_count += len(left) - i # elements left in left that are greater than right[j]\n merged.extend(left[i:])\n merged.extend(right[j:])\n return merged, inv_count\n\n sorted_arr, inv_count = merge_sort(arr)\n return inv_count", "matching_cluster_idx": 5}, {"solution": "def get_Inv_Count(arr):\n count = 0\n for i in range(len(arr)):\n for j in range(i+1, len(arr)):\n if arr[i] > arr[j]:\n count += 1\n return count", "matching_cluster_idx": 3}, {"solution": "def merge_sort_and_count_inversions(arr):\n if len(arr) <= 1:\n return arr, 0\n\n mid = len(arr) // 2\n left_arr, left_inversions = merge_sort_and_count_inversions(arr[:mid])\n right_arr, right_inversions = merge_sort_and_count_inversions(arr[mid:])\n\n sorted_arr, split_inversions = merge_and_count(left_arr, right_arr)\n\n total_inversions = left_inversions + right_inversions + split_inversions\n return sorted_arr, total_inversions\ndef merge_and_count(left, right):\n sorted_arr = []\n left_index = 0\n right_index = 0\n split_inversions = 0\n\n while left_index < len(left) and right_index < len(right):\n if left[left_index] <= right[right_index]:\n sorted_arr.append(left[left_index])\n left_index += 1\n else:\n sorted_arr.append(right[right_index])\n right_index += 1\n split_inversions += len(left) - left_index\n\n sorted_arr.extend(left[left_index:])\n sorted_arr.extend(right[right_index:])\n return sorted_arr, split_inversions\ndef get_Inv_Count(arr):\n _, inversions = merge_sort_and_count_inversions(arr)\n return inversions", "matching_cluster_idx": 5}, {"solution": "def merge_and_count_inversions(arr, temp_arr, left, mid, right):\n i = left # Starting index for left subarray\n j = mid + 1 # Starting index for right subarray\n k = left # Starting index of temp_arr\n inv_count = 0\n\n while i <= mid and j <= right:\n if arr[i] <= arr[j]:\n temp_arr[k] = arr[i]\n i += 1\n else:\n temp_arr[k] = arr[j]\n j += 1\n inv_count += (mid - i + 1)\n k += 1\n\n # Copy remaining elements of left subarray, if any\n while i <= mid:\n temp_arr[k] = arr[i]\n i += 1\n k += 1\n\n # Copy remaining elements of right subarray, if any\n while j <= right:\n temp_arr[k] = arr[j]\n j += 1\n k += 1\n\n # Copy back the merged elements to original array\n for i in range(left, right + 1):\n arr[i] = temp_arr[i]\n\n return inv_count\ndef merge_sort_and_count_inversions(arr, temp_arr, left, right):\n inv_count = 0\n if left < right:\n mid = (left + right) // 2\n\n inv_count += merge_sort_and_count_inversions(arr, temp_arr, left, mid)\n inv_count += merge_sort_and_count_inversions(arr, temp_arr, mid + 1, right)\n\n inv_count += merge_and_count_inversions(arr, temp_arr, left, mid, right)\n\n return inv_count\ndef get_Inv_Count(arr):\n temp_arr = [0] * len(arr)\n return merge_sort_and_count_inversions(arr, temp_arr, 0, len(arr) - 1)", "matching_cluster_idx": 5}, {"solution": "def get_Inv_Count(arr):\n def merge_sort_and_count(arr):\n if len(arr) <= 1:\n return arr, 0\n\n mid = len(arr) // 2\n left, left_inv_count = merge_sort_and_count(arr[:mid])\n right, right_inv_count = merge_sort_and_count(arr[mid:])\n\n merged, split_inv_count = merge(left, right)\n return merged, left_inv_count + right_inv_count + split_inv_count\n\n def merge(left, right):\n sorted_array = []\n i = j = 0\n inv_count = 0\n\n while i < len(left) and j < len(right):\n if left[i] <= right[j]:\n sorted_array.append(left[i])\n i += 1\n else:\n sorted_array.append(right[j])\n inv_count += len(left) - i\n j += 1\n\n sorted_array.extend(left[i:])\n sorted_array.extend(right[j:])\n\n return sorted_array, inv_count\n\n sorted_array, inv_count = merge_sort_and_count(arr)\n return inv_count", "matching_cluster_idx": 5}, {"solution": "def get_Inv_Count(arr):\n count = 0\n n = len(arr)\n\n for i in range(n):\n for j in range(i + 1, n):\n if arr[i] > arr[j]:\n count += 1\n\n return count", "matching_cluster_idx": 3}]}, "Mbpp/308": {"dps": 76.1896551724138, "dps_norm": 60.833333333333336, "pass@1": 70.0, "profiled": [{"solution": "def large_product(list1, list2, num):\n # Combine the lists into pairs\n pairs = [(a, b) for a in list1 for b in list2]\n\n # Calculate the product of each pair\n products = [a * b for a, b in pairs]\n\n # Sort products in descending order\n products.sort(reverse=True)\n\n # Return the top `num` largest products\n return products[:num]", "matching_cluster_idx": 2}, {"solution": "def large_product(list1, list2, num_products):\n # Combine the lists into pairs of products\n products = [a * b for a in list1 for b in list2]\n\n # Sort the products in descending order\n products.sort(reverse=True)\n\n # Return the specified number of largest products\n return products[:num_products]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n # Create a list of tuples where each tuple contains an element from list1 and list2\n combined = [(a, b) for a in list1 for b in list2]\n\n # Calculate the product of each pair and sort the list of tuples by product in descending order\n combined.sort(key=lambda x: x[0] * x[1], reverse=True)\n\n # Extract the first n largest products\n largest_products = [combined[i][0] * combined[i][1] for i in range(n)]\n\n return largest_products", "matching_cluster_idx": 2}, {"solution": "def large_product(list1, list2, n):\n # Find all possible products\n products = [a * b for a in list1 for b in list2]\n\n # Sort products in descending order\n products.sort(reverse=True)\n\n # Return the first n largest products\n return products[:n]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n # Combine the lists into tuples for each pair (x, y) from list1 and list2\n pairs = [(x, y) for x in list1 for y in list2]\n\n # Calculate the product for each pair and sort the list of products in descending order\n products = [x * y for x, y in pairs]\n products.sort(reverse=True)\n\n # Return the top n largest products\n return products[:n]", "matching_cluster_idx": 2}, {"solution": "def large_product(list1, list2, count):\n # Create pairs by multiplying one factor from each list\n pairs = [a * b for a in list1 for b in list2]\n\n # Sort pairs in descending order\n pairs.sort(reverse=True)\n\n # Return the top 'count' largest products\n return pairs[:count]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, num):\n # Combine the elements from both lists as tuples of pairs\n product_pairs = [(a, b) for a in list1 for b in list2]\n\n # Calculate the product of each pair and sort in descending order\n products = [a * b for a, b in product_pairs]\n products.sort(reverse=True)\n\n # Return the specified number of largest products\n return products[:num]", "matching_cluster_idx": 2}, {"solution": "def large_product(list1, list2, num_products):\n # Combine elements from both lists by creating pairs (a, b) where a is from list1 and b is from list2\n combined_products = [(a, b) for a in list1 for b in list2]\n\n # Compute the product of each pair and store it as a tuple (product, index)\n product_list = [(a * b, i) for i, (a, b) in enumerate(combined_products)]\n\n # Sort the list of products in descending order\n product_list.sort(reverse=True)\n\n # Extract the top num_products products from the sorted list\n largest_products = [product for product, _ in product_list[:num_products]]\n\n return largest_products", "matching_cluster_idx": 1}, {"solution": "def large_product(list1, list2, num):\n # Generate all possible products from elements in list1 and list2\n products = [a * b for a in list1 for b in list2]\n\n # Sort the products in descending order\n products.sort(reverse=True)\n\n # Return the top num largest products\n return products[:num]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, num):\n # Merging two lists into a list of tuples\n product_list = [(a * b) for a in list1 for b in list2]\n\n # Sorting the product list in descending order\n product_list.sort(reverse=True)\n\n # Returning the first 'num' largest products\n return product_list[:num]", "matching_cluster_idx": 3}, {"solution": "import heapq\ndef large_product(list1, list2, k):\n # Combine the two lists element-wise\n product_list = [a * b for a in list1 for b in list2]\n\n # Get the k largest elements from the product_list\n large_products = heapq.nlargest(k, product_list)\n\n return large_products", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, num):\n # Combine the lists into pairs and calculate the product of each pair\n products = [a * b for a in list1 for b in list2]\n\n # Sort the products in descending order\n products.sort(reverse=True)\n\n # Return the specified number of largest products\n return products[:num]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n # Combine the elements of the two lists into pairs and their products\n products = [(a, b, a * b) for a in list1 for b in list2]\n\n # Sort the products in descending order based on the product value\n products.sort(key=lambda x: x[2], reverse=True)\n\n # Extract the top n products and return their values\n return [product[2] for product in products[:n]]", "matching_cluster_idx": 2}, {"solution": "def large_product(list1, list2, k):\n # Calculate the product of each pair from the two lists and create a list of these products\n products = [a * b for a in list1 for b in list2]\n\n # Sort the products in descending order\n products.sort(reverse=True)\n\n # Return the top 'k' largest products\n return products[:k]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n # Combine the lists into pairs and compute the product of each pair\n products = [a * b for a in list1 for b in list2]\n\n # Sort the products in descending order\n products.sort(reverse=True)\n\n # Return the top n largest products\n return products[:n]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n # Step 1: Compute all possible products of elements from both lists\n products = [a * b for a in list1 for b in list2]\n\n # Step 2: Sort the products in descending order\n products.sort(reverse=True)\n\n # Step 3: Return the top n products\n return products[:n]", "matching_cluster_idx": 3}, {"solution": "from heapq import nlargest\ndef large_product(list1, list2, num):\n # Combine the lists element-wise to form product pairs\n products = [a * b for a in list1 for b in list2]\n\n # Use nlargest to get the largest 'num' products\n return nlargest(num, products)", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, k):\n # Generate all possible products by taking one element from each list\n products = [a * b for a in list1 for b in list2]\n\n # Sort the products in descending order\n products.sort(reverse=True)\n\n # Return the first 'k' elements from the sorted list\n return products[:k]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, n):\n # Combine the two lists into pairs of products\n products = [a * b for a in list1 for b in list2]\n\n # Sort the products in descending order\n products.sort(reverse=True)\n\n # Return the top n largest products\n return products[:n]", "matching_cluster_idx": 3}, {"solution": "def large_product(list1, list2, k):\n # Combine both lists into pairs and compute the product of each pair\n products = [a * b for a in list1 for b in list2]\n\n # Sort the products in descending order\n products.sort(reverse=True)\n\n # Select the top k largest products\n return products[:k]", "matching_cluster_idx": 3}]}, "Mbpp/392": {"dps": 92.41784037558685, "dps_norm": 92.6923076923077, "pass@1": 39.0, "profiled": [{"solution": "def get_max_sum(n):\n memo = {}\n\n def f(x):\n if x <= 0:\n return 0\n if x in memo:\n return memo[x]\n\n memo[x] = max(\n f(x // 2) + f(x // 3) + f(x // 4) + f(x // 5),\n x\n )\n return memo[x]\n\n return f(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n # Memoization to store results of subproblems\n memo = {}\n\n def f(x):\n if x in memo:\n return memo[x]\n if x == 0:\n return 0\n result = max(\n f(x // 2) + f(x // 3) + f(x // 4) + f(x // 5),\n x\n )\n memo[x] = result\n return result\n\n return f(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n def f(x):\n if x <= 1:\n return x\n return max(f(x // 2) + f(x // 3) + f(x // 4) + f(x // 5), x)\n\n return f(n)", "matching_cluster_idx": 3}, {"solution": "def get_max_sum(n):\n def f(n):\n if n == 0:\n return 0\n return max(f(n//2) + f(n//3) + f(n//4) + f(n//5), n)\n\n return f(n)", "matching_cluster_idx": 2}, {"solution": "def get_max_sum(n):\n memo = {}\n\n def f(x):\n if x in memo:\n return memo[x]\n if x == 0:\n return 0\n memo[x] = max(f(x // 2) + f(x // 3) + f(x // 4) + f(x // 5), x)\n return memo[x]\n\n return f(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n if n <= 1:\n return n\n\n # Dictionary to store the maximum sum for each value up to n\n dp = {0: 0}\n\n # Function to compute the max sum for a given value\n def f(x):\n if x in dp:\n return dp[x]\n\n dp[x] = max(f(x // 2) + f(x // 3) + f(x // 4) + f(x // 5), x)\n return dp[x]\n\n return f(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n memo = {}\n\n def f(k):\n if k in memo:\n return memo[k]\n if k == 0:\n return 0\n memo[k] = max(f(k // 2) + f(k // 3) + f(k // 4) + f(k // 5), k)\n return memo[k]\n\n return f(n)", "matching_cluster_idx": 12}, {"solution": "memo = {}\ndef get_max_sum(n):\n # check if the result is already computed\n if n in memo:\n return memo[n]\n\n # base case: if n is 0, return 0\n if n == 0:\n return 0\n\n # calculate max sum using the given formula\n max_sum = max(get_max_sum(n // 2) + get_max_sum(n // 3) + get_max_sum(n // 4) + get_max_sum(n // 5), n)\n\n # store the result in memoization dictionary\n memo[n] = max_sum\n\n return max_sum", "matching_cluster_idx": 12}, {"solution": "from math import floor\ndef get_max_sum(n):\n memo = {}\n\n def f(x):\n if x in memo:\n return memo[x]\n if x == 0:\n return 0\n memo[x] = max(f(floor(x / 2)) + f(floor(x / 3)) + f(floor(x / 4)) + f(floor(x / 5)), x)\n return memo[x]\n\n return f(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n, memo={}):\n if n == 0:\n return 0\n if n in memo:\n return memo[n]\n\n # Calculate f(n/2), f(n/3), f(n/4), f(n/5)\n f_n2 = get_max_sum(n // 2, memo)\n f_n3 = get_max_sum(n // 3, memo)\n f_n4 = get_max_sum(n // 4, memo)\n f_n5 = get_max_sum(n // 5, memo)\n\n # Max sum by using the given equation\n max_sum = max(f_n2 + f_n3 + f_n4 + f_n5, n)\n\n # Store result in memo dictionary\n memo[n] = max_sum\n\n return max_sum", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n # Base case for recursion\n if n == 0:\n return 0\n if n < 0:\n return float('-inf')\n\n # Memoization to store already computed values\n memo = {}\n\n def f(num):\n if num in memo:\n return memo[num]\n if num == 0:\n return 0\n # Calculate the maximum of f(n/2), f(n/3), f(n/4), f(n/5), and n\n memo[num] = max(f(num // 2) + f(num // 3) + f(num // 4) + f(num // 5), num)\n return memo[num]\n\n # Call the recursive function and return the result\n return f(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n, memo=None):\n if memo is None:\n memo = {}\n if n in memo:\n return memo[n]\n\n if n == 0:\n return 0\n memo[n] = max(\n get_max_sum(n // 2, memo) + get_max_sum(n // 3, memo) + get_max_sum(n // 4, memo) + get_max_sum(n // 5, memo),\n n\n )\n\n return memo[n]", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n, memo={}):\n if n == 0:\n return 0\n if n in memo:\n return memo[n]\n\n # Compute the maximum sum using the given formula\n result = max(get_max_sum(n // 2, memo) + get_max_sum(n // 3, memo) +\n get_max_sum(n // 4, memo) + get_max_sum(n // 5, memo), n)\n\n memo[n] = result\n return result", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n # Memoization dictionary to store already computed values\n memo = {}\n\n # Helper function to compute f(n) using memoization\n def f(x):\n if x in memo:\n return memo[x]\n if x == 0:\n return 0\n # Compute the maximum sum\n max_sum = max(f(x // 2) + f(x // 3) + f(x // 4) + f(x // 5), x)\n memo[x] = max_sum\n return max_sum\n\n return f(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n # Base case when n is less than 1\n if n < 1:\n return 0\n\n # Initialize a dictionary to store computed values to avoid redundant calculations\n memo = {}\n\n def f(x):\n if x in memo:\n return memo[x]\n if x < 1:\n return 0\n memo[x] = max(f(x // 2) + f(x // 3) + f(x // 4) + f(x // 5), x)\n return memo[x]\n\n return f(n)", "matching_cluster_idx": 12}, {"solution": "from functools import lru_cache\ndef get_max_sum(n):\n @lru_cache(maxsize=None)\n def f(num):\n if num == 0:\n return 0\n return max(f(num // 2) + f(num // 3) + f(num // 4) + f(num // 5), num)\n\n return f(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n # Dictionary to store results of subproblems\n memo = {}\n\n def f(x):\n # Base case: if x is 0 or negative, the maximum sum is 0\n if x <= 0:\n return 0\n # If the value is already computed, return the cached value\n if x in memo:\n return memo[x]\n # Compute the maximum sum using the given equation\n max_sum = max(f(x // 2) + f(x // 3) + f(x // 4) + f(x // 5), x)\n # Cache the computed value\n memo[x] = max_sum\n return max_sum\n\n return f(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n # Base case: if n is 1 or 0, return n (since f(1) = 1 and f(0) = 0)\n if n == 1 or n == 0:\n return n\n\n # If the result for n is already computed, return it directly\n if n in memo:\n return memo[n]\n\n # Compute the maximum of the given equation\n max_val = max(get_max_sum(n // 2) + get_max_sum(n // 3) + get_max_sum(n // 4) + get_max_sum(n // 5), n)\n\n # Store the computed result in the memo dictionary\n memo[n] = max_val\n\n return max_val\nmemo = {}", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n # Using memoization to store the results of previously computed values\n memo = {}\n\n def f(n):\n if n in memo:\n return memo[n]\n\n # Base case: if n is 0 or negative, the sum is 0\n if n <= 0:\n return 0\n\n # Compute the sum by considering different fractions of n\n value = max(f(n // 2) + f(n // 3) + f(n // 4) + f(n // 5), n)\n\n # Store the result in memo\n memo[n] = value\n return value\n\n # Start the recursion with the initial value of n\n return f(n)", "matching_cluster_idx": 12}, {"solution": "def get_max_sum(n):\n # Memoization to store the maximum sum for subproblems\n memo = {}\n\n def f(x):\n if x in memo:\n return memo[x]\n if x <= 0:\n return 0\n memo[x] = max(f(int(x/2)) + f(int(x/3)) + f(int(x/4)) + f(int(x/5)), x)\n return memo[x]\n\n return f(n)", "matching_cluster_idx": 12}]}, "Mbpp/395": {"dps": 93.85057471264368, "dps_norm": 74.375, "pass@1": 100.0, "profiled": [{"solution": "def first_non_repeating_character(string):\n # Create a dictionary to store character counts\n char_count = {}\n\n # Count the occurrences of each character\n for char in string:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n\n # Find the first non-repeating character\n for char in string:\n if char_count[char] == 1:\n return char\n\n # If no non-repeating character is found, return None\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n char_count = {}\n\n # Count the occurrences of each character in the string\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n\n # Find the first non-repeating character\n for char in s:\n if char_count[char] == 1:\n return char\n\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n char_count = {}\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n\n for char in s:\n if char_count[char] == 1:\n return char\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s: str) -> str:\n # Create a dictionary to store the frequency of each character\n char_count = {}\n\n # First pass to count the frequency of each character\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n\n # Second pass to find the first non-repeating character\n for char in s:\n if char_count[char] == 1:\n return char\n\n # Return None if no non-repeating character is found\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s: str) -> str:\n # Dictionary to count occurrences of each character\n char_count = {}\n\n # Populate the dictionary with character counts\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n\n # Find the first non-repeating character\n for char in s:\n if char_count[char] == 1:\n return char\n\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n # Dictionary to store the frequency of each character\n char_count = {}\n\n # Populate the dictionary with character counts\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n\n # Iterate through the string to find the first non-repeating character\n for char in s:\n if char_count[char] == 1:\n return char\n\n # If no non-repeating character is found, return None\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s: str) -> str:\n # Dictionary to store the frequency of each character\n frequency = {}\n\n # First pass: Count the frequency of each character\n for char in s:\n if char in frequency:\n frequency[char] += 1\n else:\n frequency[char] = 1\n\n # Second pass: Find the first non-repeated character\n for char in s:\n if frequency[char] == 1:\n return char\n\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n # Initialize dictionaries to track character counts and their first occurrence index\n char_count = {}\n first_occurrence = {}\n\n # First pass: count the frequency of each character and record their first occurrence\n for index, char in enumerate(s):\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n first_occurrence[char] = index\n\n # Second pass: find the first character with count of 1\n for char in s:\n if char_count[char] == 1:\n return char\n\n return None", "matching_cluster_idx": 4}, {"solution": "def first_non_repeating_character(s):\n # Dictionary to store the count of each character\n char_count = {}\n\n # First pass to count the occurrences of each character\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n\n # Second pass to find the first non-repeating character\n for char in s:\n if char_count[char] == 1:\n return char\n\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s: str) -> str:\n from collections import defaultdict\n\n char_count = defaultdict(int)\n\n # Count the occurrences of each character\n for char in s:\n char_count[char] += 1\n\n # Find the first non-repeating character\n for char in s:\n if char_count[char] == 1:\n return char\n\n # If no non-repeating character is found\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n # Dictionary to store the frequency of characters\n frequency = {}\n # List to store the characters in the order they appear\n order = []\n\n # Populate the frequency dictionary and order list\n for char in s:\n if char in frequency:\n frequency[char] += 1\n else:\n frequency[char] = 1\n order.append(char)\n\n # Find the first non-repeating character\n for char in order:\n if frequency[char] == 1:\n return char\n\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s: str) -> str:\n # Dictionary to store character counts\n char_counts = {}\n\n # Populate the dictionary with character counts\n for char in s:\n if char in char_counts:\n char_counts[char] += 1\n else:\n char_counts[char] = 1\n\n # Find the first non-repeating character\n for char in s:\n if char_counts[char] == 1:\n return char\n\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s: str) -> str:\n # Dictionary to keep track of the count of each character\n char_count = {}\n\n # First pass: Count the occurrences of each character\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n\n # Second pass: Find the first non-repeating character\n for char in s:\n if char_count[char] == 1:\n return char\n\n # If no non-repeating character is found, return None\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n # Create a dictionary to store the frequency of characters\n frequency = {}\n\n # Traverse the string and populate the frequency dictionary\n for char in s:\n if char in frequency:\n frequency[char] += 1\n else:\n frequency[char] = 1\n\n # Find the first non-repeated character\n for char in s:\n if frequency[char] == 1:\n return char\n\n # If no non-repeated character is found, return None\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s: str) -> str:\n # Dictionary to store the frequency of characters\n char_count = {}\n\n # First pass: count the occurrences of each character\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n\n # Second pass: find the first non-repeated character\n for char in s:\n if char_count[char] == 1:\n return char\n\n # If no non-repeated character is found\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s: str) -> None:\n char_count = {}\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n\n for char in s:\n if char_count[char] == 1:\n return char\n\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s: str) -> str:\n char_count = {}\n\n # Count the frequency of each character in the string\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n\n # Iterate over the string to find the first non-repeated character\n for char in s:\n if char_count[char] == 1:\n return char\n\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s: str) -> str:\n # Dictionary to count occurrences of each character\n char_count = {}\n\n # First pass to populate the dictionary with character counts\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n\n # Second pass to find the first non-repeated character\n for char in s:\n if char_count[char] == 1:\n return char\n\n # If no non-repeated character is found\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n char_count = {}\n\n # Count the occurrences of each character\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n\n # Find the first non-repeated character\n for char in s:\n if char_count[char] == 1:\n return char\n\n return None", "matching_cluster_idx": 5}, {"solution": "def first_non_repeating_character(s):\n # Create a dictionary to count the occurrences of each character\n char_count = {}\n\n # Populate the dictionary with character counts\n for char in s:\n if char in char_count:\n char_count[char] += 1\n else:\n char_count[char] = 1\n\n # Iterate through the string to find the first non-repeating character\n for char in s:\n if char_count[char] == 1:\n return char\n\n # If no non-repeating character is found, return None\n return None", "matching_cluster_idx": 5}]}, "Mbpp/405": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def check_tuplex(tuplex, elem):\n \"\"\"\n Check if an element exists within a tuple.\n\n :param tuplex: The tuple in which to check for the element.\n :param elem: The element to check for within the tuple.\n :return: True if the element is found, False otherwise.\n \"\"\"\n return elem in tuplex", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tup, elem):\n \"\"\"\n Check whether an element exists within a tuple.\n\n Parameters:\n tup (tuple): The tuple to check.\n elem: The element to look for.\n\n Returns:\n bool: True if element is in the tuple, False otherwise.\n \"\"\"\n return elem in tup", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tup, element):\n \"\"\"\n Check if an element exists within a tuple.\n\n Parameters:\n tup (tuple): The tuple to search in.\n element: The element to search for.\n\n Returns:\n bool: True if the element is in the tuple, False otherwise.\n \"\"\"\n return element in tup", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, element):\n \"\"\"\n Check if the element exists in the tuple.\n\n :param tuplex: The tuple to search through.\n :param element: The element to find in the tuple.\n :return: True if element is in the tuple, False otherwise.\n \"\"\"\n return element in tuplex", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(t, element):\n return element in t", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuple_obj, elem):\n \"\"\"\n Check if an element exists within a tuple.\n\n Args:\n tuple_obj (tuple): The tuple to check.\n elem (any): The element to look for.\n\n Returns:\n bool: True if the element exists, False otherwise.\n \"\"\"\n return elem in tuple_obj", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tup, element):\n \"\"\"\n Checks whether an element exists within a tuple.\n\n Parameters:\n tup (tuple): The tuple to search within.\n element: The element to search for.\n\n Returns:\n bool: True if the element exists in the tuple, False otherwise.\n \"\"\"\n return element in tup", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tup, elem):\n \"\"\"\n Check whether an element exists within a tuple.\n\n Args:\n tup: A tuple of elements to search within.\n elem: The element to search for.\n\n Returns:\n True if the element is found in the tuple, False otherwise.\n \"\"\"\n return elem in tup", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuple_, element):\n \"\"\"\n This function checks whether a given element exists within a tuple.\n\n Parameters:\n tuple_ (tuple): The tuple in which to search for the element.\n element: The element to search for in the tuple.\n\n Returns:\n bool: True if the element is found in the tuple, False otherwise.\n \"\"\"\n return element in tuple_", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, element):\n \"\"\"\n Check whether an element exists within a tuple.\n\n Parameters:\n tuplex (tuple): The tuple to search within.\n element: The element to look for.\n\n Returns:\n bool: True if the element is in the tuple, False otherwise.\n \"\"\"\n return element in tuplex\ntuplex = (\"w\", 3, \"r\", \"e\", \"s\", \"o\", \"u\", \"r\", \"c\", \"e\")\nelement = 'r'", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tup, element):\n \"\"\"\n Function to check whether an element exists within a tuple.\n\n Parameters:\n tup (tuple): The tuple to search.\n element: The element to check for existence.\n\n Returns:\n bool: True if the element is found in the tuple, False otherwise.\n \"\"\"\n return element in tup", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, element):\n \"\"\"\n Function to check whether an element exists within a tuple.\n\n Args:\n tuplex (tuple): The tuple in which to search for the element.\n element (any): The element to search for.\n\n Returns:\n bool: True if the element is found in the tuple, False otherwise.\n \"\"\"\n return element in tuplex", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, element):\n \"\"\"\n Check if an element exists within a tuple.\n\n :param tuplex: The tuple to check.\n :param element: The element to look for.\n :return: True if the element is in the tuple, False otherwise.\n \"\"\"\n return element in tuplex", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tup, element):\n \"\"\"\n Check if an element exists within a tuple.\n\n Parameters:\n tup (tuple): The tuple to check.\n element: The element to look for.\n\n Returns:\n bool: True if the element is found, False otherwise.\n \"\"\"\n return element in tup", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tup, elem):\n \"\"\"\n Function to check whether an element exists within a tuple.\n\n Parameters:\n tup (tuple): The tuple in which to search for the element.\n elem: The element to search for.\n\n Returns:\n bool: True if the element exists in the tuple, False otherwise.\n \"\"\"\n return elem in tup", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tup, elem):\n \"\"\"\n Check if an element exists within a tuple.\n\n Parameters:\n tup (tuple): The tuple to check.\n elem (any): The element to search for.\n\n Returns:\n bool: True if the element is found, False otherwise.\n \"\"\"\n return elem in tup", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(t, element):\n return element in t", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuple_in, element):\n \"\"\"\n This function checks if an element exists within a tuple.\n\n Parameters:\n tuple_in (tuple): The tuple to search within.\n element: The element to search for.\n\n Returns:\n bool: True if the element is found, False otherwise.\n \"\"\"\n return element in tuple_in", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tuplex, element):\n \"\"\"\n Check if an element exists within a tuple.\n\n Parameters:\n tuplex (tuple): The tuple to check.\n element: The element to look for.\n\n Returns:\n bool: True if the element exists in the tuple, False otherwise.\n \"\"\"\n return element in tuplex", "matching_cluster_idx": 3}, {"solution": "def check_tuplex(tup, elem):\n \"\"\"Check if an element exists within a tuple.\"\"\"\n return elem in tup", "matching_cluster_idx": 3}]}, "Mbpp/414": {"dps": 90.21739130434783, "dps_norm": 92.22222222222221, "pass@1": 94.0, "profiled": [{"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Check whether any value in seq2 exists in seq1.\n\n Parameters:\n seq1 (list): The first sequence.\n seq2 (list): The second sequence.\n\n Returns:\n bool: True if any value in seq2 exists in seq1, False otherwise.\n \"\"\"\n return any(item in seq1 for item in seq2)", "matching_cluster_idx": 8}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Check whether any value in seq1 exists in seq2.\n\n Args:\n seq1 (list): The first sequence.\n seq2 (list): The second sequence.\n\n Returns:\n bool: True if there is any overlap, False otherwise.\n \"\"\"\n return any(item in seq2 for item in seq1)", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Check if there is any common value between two sequences.\n\n Parameters:\n seq1 (list): The first sequence of values.\n seq2 (list): The second sequence of values.\n\n Returns:\n bool: True if there is any common value, False otherwise.\n \"\"\"\n return any(value in seq2 for value in seq1)", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Check whether any value in seq2 exists in seq1.\n\n Args:\n seq1 (list): First sequence of elements.\n seq2 (list): Second sequence of elements.\n\n Returns:\n bool: True if there is an overlap, False otherwise.\n \"\"\"\n return any(elem in seq1 for elem in seq2)", "matching_cluster_idx": 8}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Function to check if any value in seq1 exists in seq2.\n Returns True if there is any overlap, else False.\n \"\"\"\n for item in seq1:\n if item in seq2:\n return True\n return False", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Check whether any value in seq1 exists in seq2.\n\n Parameters:\n seq1 (list): First sequence of values.\n seq2 (list): Second sequence of values.\n\n Returns:\n bool: True if any value in seq1 exists in seq2, False otherwise.\n \"\"\"\n return any(item in seq2 for item in seq1)", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Check if there is any common element between two sequences.\n\n Parameters:\n seq1 (list): First sequence\n seq2 (list): Second sequence\n\n Returns:\n bool: True if there is any common element, otherwise False\n \"\"\"\n return any(item in seq2 for item in seq1)", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n This function checks whether any value in seq2 exists in seq1.\n :param seq1: The first sequence\n :param seq2: The second sequence\n :return: True if there is any overlap, False otherwise\n \"\"\"\n return any(item in seq1 for item in seq2)", "matching_cluster_idx": 8}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Checks whether any value in seq2 exists in seq1.\n\n Parameters:\n seq1 (list): The first sequence.\n seq2 (list): The second sequence.\n\n Returns:\n bool: True if any value in seq2 exists in seq1, False otherwise.\n \"\"\"\n return any(item in seq1 for item in seq2)", "matching_cluster_idx": 8}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Checks whether any value in seq1 exists in seq2.\n\n Args:\n seq1 (list): The first sequence.\n seq2 (list): The second sequence.\n\n Returns:\n bool: True if any value in seq1 exists in seq2, False otherwise.\n \"\"\"\n return any(item in seq2 for item in seq1)", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n This function checks if there are any common elements between two sequences.\n\n Args:\n seq1 (list): The first sequence.\n seq2 (list): The second sequence.\n\n Returns:\n bool: True if there is any overlap between the two sequences, False otherwise.\n \"\"\"\n # Using a set to check for common elements\n set1 = set(seq1)\n set2 = set(seq2)\n\n # Check if there is any intersection between the two sets\n return not set1.isdisjoint(set2)", "matching_cluster_idx": 6}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Check if there is any value in seq2 that exists in seq1.\n\n Parameters:\n seq1 (list): The first sequence.\n seq2 (list): The second sequence.\n\n Returns:\n bool: True if there is an overlap, False otherwise.\n \"\"\"\n for item in seq2:\n if item in seq1:\n return True\n return False", "matching_cluster_idx": 8}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Checks whether any value in seq1 exists in seq2.\n\n Parameters:\n seq1 (list): First sequence.\n seq2 (list): Second sequence.\n\n Returns:\n bool: True if there is any overlap, False otherwise.\n \"\"\"\n # Use set intersection to determine if there are common elements\n return not set(seq1).isdisjoint(seq2)", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Check if any value in seq2 exists in seq1.\n\n Args:\n seq1 (list): First sequence.\n seq2 (list): Second sequence.\n\n Returns:\n bool: True if any value in seq2 exists in seq1, False otherwise.\n \"\"\"\n for item in seq2:\n if item in seq1:\n return True\n return False", "matching_cluster_idx": 8}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Check whether any value in seq2 exists in seq1.\n\n Parameters:\n seq1 (list): The first sequence.\n seq2 (list): The second sequence.\n\n Returns:\n bool: True if there is an overlap, False otherwise.\n \"\"\"\n for item in seq2:\n if item in seq1:\n return True\n return False", "matching_cluster_idx": 8}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Checks whether any value in seq1 exists in seq2.\n\n Args:\n seq1 (list): First sequence.\n seq2 (list): Second sequence.\n\n Returns:\n bool: True if any value in seq1 exists in seq2, False otherwise.\n \"\"\"\n return any(item in seq2 for item in seq1)", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Check whether any value in seq2 exists in seq1.\n\n :param seq1: List of integers\n :param seq2: List of integers\n :return: Boolean indicating if there is any overlap\n \"\"\"\n return any(elem in seq1 for elem in seq2)", "matching_cluster_idx": 8}, {"solution": "def overlapping(seq1, seq2):\n # Use the set intersection method to check for overlapping values\n return bool(set(seq1) & set(seq2))", "matching_cluster_idx": 5}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Checks if there is any common value between two sequences.\n\n Parameters:\n seq1 (list): The first sequence.\n seq2 (list): The second sequence.\n\n Returns:\n bool: True if there is any common value, False otherwise.\n \"\"\"\n return any(item in seq2 for item in seq1)", "matching_cluster_idx": 7}, {"solution": "def overlapping(seq1, seq2):\n \"\"\"\n Check whether any value in seq2 exists in seq1.\n\n Parameters:\n seq1 (list): The first sequence to check.\n seq2 (list): The second sequence to check against.\n\n Returns:\n bool: True if there is any common value, False otherwise.\n \"\"\"\n return any(item in seq1 for item in seq2)", "matching_cluster_idx": 8}]}, "Mbpp/421": {"dps": 76.95473251028807, "dps_norm": 85.71428571428571, "pass@1": 100.0, "profiled": [{"solution": "def concatenate_tuple(elements, delimiter='-'):\n \"\"\"\n Concatenate each element of a tuple by the specified delimiter.\n\n Parameters:\n elements (tuple): Tuple of elements to concatenate.\n delimiter (str): Delimiter to use for concatenation.\n\n Returns:\n str: Concatenated string.\n \"\"\"\n return delimiter.join(map(str, elements))", "matching_cluster_idx": 5}, {"solution": "def concatenate_tuple(elements, delimiter=\"-\"):\n \"\"\"Concatenates elements of a tuple with the specified delimiter.\"\"\"\n return delimiter.join(map(str, elements))", "matching_cluster_idx": 5}, {"solution": "def concatenate_tuple(elements, delimiter=\"-\"):\n return delimiter.join(map(str, elements))", "matching_cluster_idx": 5}, {"solution": "def concatenate_tuple(tpl):\n # Convert each element to string and join them with a delimiter\n return '-'.join(map(str, tpl))", "matching_cluster_idx": 5}, {"solution": "def concatenate_tuple(t):\n # Use the str.join() method to concatenate elements of the tuple with a delimiter\n return '-'.join(map(str, t))", "matching_cluster_idx": 5}, {"solution": "def concatenate_tuple(t):\n # Convert each element to string and join them with the specified delimiter\n return '-'.join(map(str, t))", "matching_cluster_idx": 5}, {"solution": "def concatenate_tuple(elements, delimiter='-'):\n \"\"\"\n Concatenates each element of a tuple into a single string, with elements separated by the given delimiter.\n\n Parameters:\n elements (tuple): A tuple of elements to concatenate.\n delimiter (str): The delimiter string to separate the elements.\n\n Returns:\n str: The concatenated string.\n \"\"\"\n return delimiter.join(map(str, elements))", "matching_cluster_idx": 5}, {"solution": "def concatenate_tuple(elements, delimiter='-'):\n # Ensure elements are strings by converting non-string elements using str()\n elements = [str(elem) for elem in elements]\n # Join the elements with the delimiter\n return delimiter.join(elements)", "matching_cluster_idx": 5}, {"solution": "def concatenate_tuple(t):\n # Convert each element in the tuple to a string and join them with the delimiter '-'\n return '-'.join(map(str, t))", "matching_cluster_idx": 5}, {"solution": "def concatenate_tuple(tpl):\n return '-'.join(map(str, tpl))", "matching_cluster_idx": 5}, {"solution": "def concatenate_tuple(elements, delimiter=\"-\"):\n \"\"\"\n Concatenates elements of a tuple with a given delimiter.\n\n Args:\n elements (tuple): The tuple of elements to concatenate.\n delimiter (str): The delimiter to use between elements.\n\n Returns:\n str: The concatenated string.\n \"\"\"\n # Use the join method to concatenate the tuple elements with the delimiter\n return delimiter.join(map(str, elements))", "matching_cluster_idx": 5}, {"solution": "def concatenate_tuple(t):\n # Convert tuple elements to string and join them with the delimiter '-'\n return '-'.join(map(str, t))", "matching_cluster_idx": 5}, {"solution": "def concatenate_tuple(elements, delimiter=\"-\"):\n \"\"\"\n Concatenates each element of the tuple using the specified delimiter.\n\n Args:\n elements (tuple): A tuple containing the elements to concatenate.\n delimiter (str): The delimiter to use between elements.\n\n Returns:\n str: A string with the elements concatenated.\n \"\"\"\n return delimiter.join(map(str, elements))", "matching_cluster_idx": 5}, {"solution": "def concatenate_tuple(tup):\n # Concatenate each element in the tuple with the delimiter '-'\n return '-'.join(map(str, tup))", "matching_cluster_idx": 5}, {"solution": "def concatenate_tuple(input_tuple, delimiter='-'):\n \"\"\"\n Concatenates each element of the tuple by the provided delimiter.\n\n Args:\n input_tuple (tuple): The tuple to be concatenated.\n delimiter (str): The delimiter to be used in concatenation.\n\n Returns:\n str: The concatenated string.\n \"\"\"\n return delimiter.join(map(str, input_tuple))", "matching_cluster_idx": 5}, {"solution": "def concatenate_tuple(elements, delimiter='-'):\n \"\"\"\n Concatenate each element of a tuple by a given delimiter.\n\n Parameters:\n elements (tuple): The tuple of elements to concatenate.\n delimiter (str): The delimiter to use for concatenation.\n\n Returns:\n str: The concatenated string.\n \"\"\"\n return delimiter.join(map(str, elements))", "matching_cluster_idx": 5}, {"solution": "def concatenate_tuple(tpl):\n return '-'.join(map(str, tpl))", "matching_cluster_idx": 5}, {"solution": "def concatenate_tuple(t):\n # Use str.join to concatenate elements with '-'\n return '-'.join(map(str, t))", "matching_cluster_idx": 5}, {"solution": "def concatenate_tuple(input_tuple):\n \"\"\"\n Concatenates elements of the tuple with the delimiter '-'.\n\n Args:\n input_tuple (tuple): A tuple containing elements to be concatenated.\n\n Returns:\n str: A string where elements of the tuple are concatenated with '-'.\n \"\"\"\n return '-'.join(map(str, input_tuple))", "matching_cluster_idx": 5}, {"solution": "def concatenate_tuple(t):\n # Convert each element to string and join them with the '-' delimiter\n return '-'.join(map(str, t))", "matching_cluster_idx": 5}]}, "Mbpp/424": {"dps": 51.624548736462096, "dps_norm": 80.0, "pass@1": 100.0, "profiled": [{"solution": "def extract_rear(strings_tuple):\n return [s[-1] for s in strings_tuple]", "matching_cluster_idx": 3}, {"solution": "def extract_rear(tuple_of_strings):\n return [string[-1] for string in tuple_of_strings]", "matching_cluster_idx": 3}, {"solution": "def extract_rear(strings):\n return [s[-1] for s in strings]", "matching_cluster_idx": 3}, {"solution": "def extract_rear(tuples):\n return [string[-1] for string in tuples]", "matching_cluster_idx": 3}, {"solution": "def extract_rear(strings_tuple):\n \"\"\"\n Extracts the last character of each string in the given tuple.\n\n Args:\n strings_tuple (tuple): A tuple containing strings.\n\n Returns:\n List[str]: A list containing the last character of each string.\n \"\"\"\n return [s[-1] for s in strings_tuple]", "matching_cluster_idx": 3}, {"solution": "def extract_rear(input_tuple):\n # Initialize an empty list to store the rear elements\n rear_elements = []\n\n # Iterate over each string in the tuple\n for string in input_tuple:\n # Append the last character of each string to the list\n rear_elements.append(string[-1])\n\n # Return the list of rear elements\n return rear_elements", "matching_cluster_idx": 3}, {"solution": "def extract_rear(tuples):\n # Using list comprehension to extract the last character of each string in the tuple\n return [s[-1] for s in tuples]", "matching_cluster_idx": 3}, {"solution": "def extract_rear(strings):\n \"\"\"\n Extracts the last character from each string in a given tuple.\n\n :param strings: Tuple of strings\n :return: List of last characters of each string\n \"\"\"\n return [string[-1] for string in strings]", "matching_cluster_idx": 3}, {"solution": "def extract_rear(tupled_strings):\n # Initialize an empty list to store the rear characters\n rear_chars = []\n\n # Iterate through each string in the tuple\n for s in tupled_strings:\n # Append the last character of the string to the list\n rear_chars.append(s[-1])\n\n return rear_chars", "matching_cluster_idx": 3}, {"solution": "def extract_rear(tuples):\n \"\"\"Extract the last character of each string in a tuple.\"\"\"\n return [s[-1] for s in tuples]", "matching_cluster_idx": 3}, {"solution": "def extract_rear(tupl):\n # Using list comprehension to extract the last character from each string in the tuple\n return [string[-1] for string in tupl]", "matching_cluster_idx": 3}, {"solution": "def extract_rear(strings):\n \"\"\"\n Extract the last character of each string in the given tuple.\n\n :param strings: A tuple of strings\n :return: A list of the last characters of each string in the tuple\n \"\"\"\n # Create a list to store the last characters\n last_characters = []\n\n # Iterate over each string in the tuple\n for string in strings:\n # Append the last character of the string to the list\n last_characters.append(string[-1])\n\n return last_characters", "matching_cluster_idx": 3}, {"solution": "def extract_rear(strings):\n # List comprehension to extract the last character from each string in the tuple\n return [string[-1] for string in strings]", "matching_cluster_idx": 3}, {"solution": "def extract_rear(strings):\n return [s[-1] for s in strings]", "matching_cluster_idx": 3}, {"solution": "def extract_rear(strings):\n return [s[-1] for s in strings]", "matching_cluster_idx": 3}, {"solution": "def extract_rear(strings):\n return [string[-1] for string in strings]", "matching_cluster_idx": 3}, {"solution": "def extract_rear(strings):\n # Use a list comprehension to extract the last character of each string in the tuple\n return [s[-1] for s in strings]", "matching_cluster_idx": 3}, {"solution": "def extract_rear(tupl):\n return [s[-1] for s in tupl]", "matching_cluster_idx": 3}, {"solution": "def extract_rear(tuples):\n \"\"\"\n Extracts the last character from each string in the given tuple.\n\n Args:\n tuples (tuple): A tuple of strings.\n\n Returns:\n list: A list containing the last character of each string in the input tuple.\n \"\"\"\n return [string[-1] for string in tuples]", "matching_cluster_idx": 3}, {"solution": "def extract_rear(tupl):\n # Use list comprehension to iterate through each element in the tuple and extract the last character of each string\n return [str[-1] for str in tupl]", "matching_cluster_idx": 3}]}, "Mbpp/425": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 81.0, "profiled": [{"solution": "def count_element_in_list(sublists, element):\n count = 0\n for sublist in sublists:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(nested_list, element):\n count = 0\n for sublist in nested_list:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(sublists, element):\n \"\"\"\n Count the number of sublists containing a particular element.\n\n Args:\n sublists (list of lists): The list of sublists to search within.\n element (int/str): The element to count within the sublists.\n\n Returns:\n int: The count of sublists containing the element.\n \"\"\"\n count = 0\n for sublist in sublists:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(nested_list, element):\n count = 0\n for sublist in nested_list:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(list_of_lists, target):\n count = 0\n for sublist in list_of_lists:\n if target in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lists, element):\n count = 0\n for sublist in lists:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, element):\n \"\"\"\n This function counts the number of sublists containing a particular element.\n\n Args:\n lst (list): A list of lists.\n element: The element to count in the sublists.\n\n Returns:\n int: The count of sublists containing the element.\n \"\"\"\n return sum(1 for sublist in lst if element in sublist)", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(nested_list, element):\n \"\"\"\n Count the number of sublists containing a particular element.\n\n Args:\n nested_list (list of lists): The nested list to search through.\n element (int/str/etc.): The element to count in the sublists.\n\n Returns:\n int: The count of sublists containing the specified element.\n \"\"\"\n count = 0\n for sublist in nested_list:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(sublists, element):\n count = 0\n for sublist in sublists:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(sublists, element):\n count = 0\n for sublist in sublists:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(nested_list, element):\n count = 0\n for sublist in nested_list:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(nested_list, element):\n \"\"\"\n Counts the number of sublists in the nested list that contain the specified element.\n\n Args:\n nested_list (list): A list of lists where each sublist may contain the element to be counted.\n element (any): The element to search for in each sublist.\n\n Returns:\n int: The count of sublists containing the specified element.\n \"\"\"\n count = 0\n for sublist in nested_list:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(sublists, element):\n \"\"\"\n Count the number of sublists that contain a particular element.\n\n Parameters:\n sublists (list of lists): The list of sublists to check.\n element (any): The element to look for in the sublists.\n\n Returns:\n int: The count of sublists containing the specified element.\n \"\"\"\n count = 0\n for sublist in sublists:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, element):\n \"\"\"\n Count the number of sublists containing a particular element.\n\n Parameters:\n lst (list of list): The list of lists to search through.\n element: The element to count occurrences of in sublists.\n\n Returns:\n int: The count of sublists containing the element.\n \"\"\"\n count = 0\n for sublist in lst:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(sublists, element):\n count = 0\n for sublist in sublists:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, element):\n \"\"\"\n Count the number of sublists containing the specified element.\n\n Parameters:\n lst (list of list): The list of sublists.\n element: The element to search for in the sublists.\n\n Returns:\n int: The count of sublists containing the specified element.\n \"\"\"\n count = 0\n for sublist in lst:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lists, element):\n \"\"\"\n Counts the number of sublists that contain a particular element.\n\n Parameters:\n lists (list of list): The list of sublists.\n element (any): The element to be counted.\n\n Returns:\n int: The number of sublists containing the given element.\n \"\"\"\n count = 0\n for sublist in lists:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lst, element):\n count = 0\n for sublist in lst:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(lists, element):\n # Initialize a counter\n count = 0\n\n # Iterate through each sublist\n for sublist in lists:\n # Check if the element is in the current sublist\n if element in sublist:\n count += 1\n\n return count", "matching_cluster_idx": 4}, {"solution": "def count_element_in_list(sublists, element):\n \"\"\"\n Count the number of sublists containing a particular element.\n\n :param sublists: List of lists\n :param element: The element to count\n :return: Number of sublists containing the element\n \"\"\"\n count = 0\n for sublist in sublists:\n if element in sublist:\n count += 1\n return count", "matching_cluster_idx": 4}]}, "Mbpp/428": {"dps": 84.29752066115702, "dps_norm": 55.55555555555556, "pass@1": 96.0, "profiled": [{"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2\n\n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2\n\n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n\n arr[j] = temp\n gap //= 2\n\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2\n\n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n \"\"\"Sorts an array using shell sort.\"\"\"\n n = len(arr)\n gap = n // 2\n\n # Start with a big gap, then reduce the gap until it becomes 0\n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n # Shift earlier gap-sorted elements up until the correct location for arr[i] is found\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2\n\n # Start with a big gap, then reduce the gap\n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n # Shift earlier gap-sorted elements up until the correct location for arr[i] is found\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n\n # Put temp (the original arr[i]) in its correct location\n arr[j] = temp\n gap //= 2\n\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2\n\n # Start with a big gap, then reduce the gap\n while gap > 0:\n # Do a gapped insertion sort for this gap size.\n for i in range(gap, n):\n temp = arr[i]\n j = i\n # Shift earlier gap-sorted elements up until the correct location for arr[i] is found\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n\n # Put temp (the original arr[i]) in its correct location\n arr[j] = temp\n gap //= 2\n\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2\n\n # Start with a big gap, then reduce the gap\n while gap > 0:\n # Do a gapped insertion sort for this gap size.\n for i in range(gap, n):\n temp = arr[i]\n j = i\n # Shift earlier gap-sorted elements up until the correct location for arr[i] is found\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n\n # Put temp (the original arr[i]) in its correct location\n arr[j] = temp\n gap //= 2\n\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2\n\n # Start with a big gap, then reduce the gap\n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n # Shift earlier gap-sorted elements until the correct location for arr[i] is found\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2\n\n # Start with a big gap, then reduce the gap\n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n\n arr[j] = temp\n gap //= 2\n\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2\n\n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2\n\n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2\n\n # Start with a big gap, then reduce the gap until it becomes 0\n while gap > 0:\n # Perform a gapped insertion sort for this gap size.\n for i in range(gap, n):\n temp = arr[i]\n j = i\n # Shift earlier gap-sorted elements up until the correct location for arr[i] is found\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2\n\n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n \"\"\"\n Sorts an array using the shell sort algorithm.\n\n Parameters:\n arr (list): The list to be sorted.\n\n Returns:\n list: The sorted list.\n \"\"\"\n n = len(arr)\n gap = n // 2\n\n # Start with a big gap, reduce the gap until it becomes 0\n while gap > 0:\n # Perform a gapped insertion sort for the current gap size.\n for i in range(gap, n):\n temp = arr[i]\n j = i\n # Shift earlier gap-sorted elements up until the correct location for arr[i] is found\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n\n # Put temp (the original arr[i]) in its correct location\n arr[j] = temp\n gap //= 2\n\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2\n\n # Start with a big gap, then reduce the gap\n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n # Shift earlier gap-sorted elements up until the correct location for arr[i] is found\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n\n # Put temp (the original arr[i]) in its correct location\n arr[j] = temp\n gap //= 2\n\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2\n\n # Start with a big gap, then reduce the gap until it becomes 0\n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n # Shift earlier gap-sorted elements up until the correct location for arr[i] is found\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n\n # Put temp (the original arr[i]) in its correct location\n arr[j] = temp\n\n gap //= 2\n\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2\n\n # Start with a big gap, then reduce the gap\n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n # Shift earlier gap-sorted elements up until the correct location for arr[i] is found\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n arr[j] = temp\n gap //= 2\n\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2\n\n # Start with a big gap, then reduce the gap until it becomes 0\n while gap > 0:\n # Do a gapped insertion sort for this gap size.\n for i in range(gap, n):\n temp = arr[i]\n j = i\n # Shift earlier gap-sorted elements up until the correct location for arr[i] is found\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n # Put temp (the original arr[i]) in its correct location\n arr[j] = temp\n gap //= 2\n\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n n = len(arr)\n gap = n // 2\n\n # Start with a big gap, then reduce the gap until it becomes 0\n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n # Shift earlier gap-sorted elements up until the correct location for arr[i] is found\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n\n # Put temp (the original arr[i]) in its correct location\n arr[j] = temp\n gap //= 2\n\n return arr", "matching_cluster_idx": 4}, {"solution": "def shell_sort(arr):\n \"\"\"Sort an array using Shell sort.\"\"\"\n n = len(arr)\n gap = n // 2\n\n # Start with a big gap, then reduce the gap\n while gap > 0:\n for i in range(gap, n):\n temp = arr[i]\n j = i\n # Shift earlier gap-sorted elements up until the correct location for arr[i] is found\n while j >= gap and arr[j - gap] > temp:\n arr[j] = arr[j - gap]\n j -= gap\n\n # Put temp (the original arr[i]) in its correct location\n arr[j] = temp\n gap //= 2\n\n return arr", "matching_cluster_idx": 4}]}, "Mbpp/433": {"dps": 73.08510638297872, "dps_norm": 74.0, "pass@1": 96.0, "profiled": [{"solution": "def check_greater(array, number):\n \"\"\"\n Check if the given number is greater than all the elements in the array.\n\n Parameters:\n array (list of int): The list of integers to check against.\n number (int): The number to compare.\n\n Returns:\n bool: True if the number is greater than all elements in the array, False otherwise.\n \"\"\"\n for element in array:\n if element >= number:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def check_greater(arr, num):\n for element in arr:\n if element >= num:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def check_greater(arr, number):\n \"\"\"\n Check whether the entered number is greater than the elements of the given array.\n\n Parameters:\n arr (list): List of integers.\n number (int): The number to check.\n\n Returns:\n bool: True if the number is greater than all elements in the array, False otherwise.\n \"\"\"\n # Iterate through the array and check if the number is greater than all elements\n for element in arr:\n if element >= number:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def check_greater(arr, num):\n \"\"\"\n Checks if the entered number is greater than all the elements of the given array.\n\n Parameters:\n arr (list): A list of integers\n num (int): The number to check against\n\n Returns:\n bool: True if the number is greater than all elements, False otherwise\n \"\"\"\n return all(n < num for n in arr)", "matching_cluster_idx": 2}, {"solution": "def check_greater(arr, num):\n \"\"\"\n Check whether the entered number is greater than the elements of the given array.\n\n Parameters:\n arr (list): The given array of integers.\n num (int): The number to compare with the elements of the array.\n\n Returns:\n bool: True if num is greater than all elements in arr, False otherwise.\n \"\"\"\n return all(x < num for x in arr)", "matching_cluster_idx": 2}, {"solution": "def check_greater(array, number):\n \"\"\"\n This function checks if the entered number is greater than all elements in the given array.\n\n Args:\n array (list of int): The array of numbers to compare against.\n number (int): The number to check against the elements in the array.\n\n Returns:\n bool: True if the number is greater than all elements in the array, False otherwise.\n \"\"\"\n for elem in array:\n if number <= elem:\n return False\n return True", "matching_cluster_idx": 3}, {"solution": "def check_greater(arr, num):\n \"\"\"\n Checks whether the given number is greater than all elements of the array.\n\n :param arr: List of integers\n :param num: Integer to be compared\n :return: Boolean indicating if num is greater than all elements of the array\n \"\"\"\n return all(n < num for n in arr)", "matching_cluster_idx": 2}, {"solution": "def check_greater(arr, number):\n \"\"\"\n Check if the number is greater than all the elements in the array.\n\n Parameters:\n arr (list): The array of integers.\n number (int): The number to compare with the elements in the array.\n\n Returns:\n bool: True if the number is greater than all elements in the array, False otherwise.\n \"\"\"\n return all(num < number for num in arr)", "matching_cluster_idx": 2}, {"solution": "def check_greater(arr, num):\n \"\"\"\n Checks whether the given number is greater than all elements in the array.\n\n Parameters:\n arr (list): The list of numbers.\n num (int): The number to compare with the elements in the list.\n\n Returns:\n bool: True if the number is greater than all elements in the array, False otherwise.\n \"\"\"\n for element in arr:\n if num <= element:\n return False\n return True", "matching_cluster_idx": 3}, {"solution": "def check_greater(arr, num):\n \"\"\"\n Check whether the entered number is greater than the elements of the given array.\n\n Parameters:\n arr (list of int): The list of elements to check against.\n num (int): The number to compare against the elements in the list.\n\n Returns:\n bool: True if the number is greater than all elements in the array, False otherwise.\n \"\"\"\n return all(num > x for x in arr)", "matching_cluster_idx": 2}, {"solution": "def check_greater(arr, num):\n \"\"\"\n Check whether the entered number is greater than the elements of the given array.\n\n Parameters:\n arr (list of int): The given array.\n num (int): The number to check.\n\n Returns:\n bool: True if the number is greater than all elements in the array, otherwise False.\n \"\"\"\n return all(num > element for element in arr)", "matching_cluster_idx": 2}, {"solution": "def check_greater(arr, num):\n \"\"\"\n Check if the given number is greater than all elements in the array.\n\n :param arr: List of integers\n :param num: Integer\n :return: Boolean\n \"\"\"\n return all(x < num for x in arr)", "matching_cluster_idx": 2}, {"solution": "def check_greater(arr, number):\n \"\"\"\n Check whether the entered number is greater than all elements of the given array.\n\n Parameters:\n arr (list of int): The array of integers.\n number (int): The number to compare against the array elements.\n\n Returns:\n bool: True if the number is greater than all elements in the array, False otherwise.\n \"\"\"\n for elem in arr:\n if number <= elem:\n return False\n return True", "matching_cluster_idx": 3}, {"solution": "def check_greater(array, number):\n \"\"\"\n Check if the entered number is greater than all elements in the given array.\n\n :param array: List of integers\n :param number: Integer to compare with the elements in the array\n :return: True if the number is greater than all elements in the array, False otherwise\n \"\"\"\n for element in array:\n if number <= element:\n return False\n return True", "matching_cluster_idx": 3}, {"solution": "def check_greater(arr, num):\n \"\"\"\n This function checks whether the entered number is greater than all the elements of the given array.\n\n Parameters:\n arr (list of int): The array of integers.\n num (int): The number to be checked.\n\n Returns:\n bool: True if the number is greater than all elements in the array, False otherwise.\n \"\"\"\n for element in arr:\n if element >= num:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def check_greater(arr, number):\n # Check if the number is greater than all elements in the array\n return all(elem < number for elem in arr)", "matching_cluster_idx": 2}, {"solution": "def check_greater(arr, num):\n \"\"\"\n Function to check whether the entered number is greater than all elements of the given array.\n\n Args:\n arr (list): List of integers.\n num (int): Number to compare with the elements of the list.\n\n Returns:\n bool: True if num is greater than all elements in arr, False otherwise.\n \"\"\"\n for element in arr:\n if element >= num:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def check_greater(arr, num):\n \"\"\"\n Check if the given number is greater than all elements in the array.\n\n Args:\n arr (list): A list of integers.\n num (int): A number to compare with elements in the array.\n\n Returns:\n bool: True if num is greater than all elements in the array, False otherwise.\n \"\"\"\n return all(n < num for n in arr)", "matching_cluster_idx": 2}, {"solution": "def check_greater(arr, num):\n \"\"\"\n Check whether the entered number is greater than all elements of the given array.\n\n Parameters:\n arr (list of int): The array of integers.\n num (int): The number to compare with the elements of the array.\n\n Returns:\n bool: True if the number is greater than all elements, False otherwise.\n \"\"\"\n return all(n < num for n in arr)", "matching_cluster_idx": 2}, {"solution": "def check_greater(arr, num):\n \"\"\"\n Check whether the entered number is greater than all elements of the given array.\n\n Parameters:\n arr (list of int): The array of integers to compare against.\n num (int): The number to check.\n\n Returns:\n bool: True if the number is greater than all elements in the array, False otherwise.\n \"\"\"\n return all(elem < num for elem in arr)", "matching_cluster_idx": 2}]}, "Mbpp/437": {"dps": null, "dps_norm": null, "pass@1": 0.0, "profiled": []}, "Mbpp/440": {"dps": null, "dps_norm": null, "pass@1": 0.0, "profiled": []}, "Mbpp/446": {"dps": 96.45320197044335, "dps_norm": 64.0, "pass@1": 39.0, "profiled": [{"solution": "def count_Occurrence(lst, elements):\n \"\"\"\n Counts the occurrences of elements from the elements list in the lst tuple.\n\n Parameters:\n lst (tuple): The tuple to search within.\n elements (list): The list of elements to count.\n\n Returns:\n int: The total occurrences of elements in the lst.\n \"\"\"\n count = 0\n for element in elements:\n count += lst.count(element)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(input_tuple, element_list):\n \"\"\"\n Counts the occurrence of elements in the input tuple that are also in the element list.\n\n Args:\n input_tuple (tuple): The tuple to count elements from.\n element_list (list): The list of elements to count.\n\n Returns:\n int: The total count of elements from element_list that appear in input_tuple.\n \"\"\"\n count = 0\n for elem in element_list:\n count += input_tuple.count(elem)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tup, lst):\n count = 0\n for item in lst:\n count += tup.count(item)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(t, lst):\n # Initialize a dictionary to store the counts of each element\n counts = {}\n\n # Count the occurrences of each element in the tuple\n for element in t:\n if element in counts:\n counts[element] += 1\n else:\n counts[element] = 1\n\n # Sum the counts of the elements specified in the list\n total_count = sum(counts[element] for element in lst if element in counts)\n\n return total_count", "matching_cluster_idx": 4}, {"solution": "def count_Occurrence(t, lst):\n count = 0\n for elem in lst:\n count += t.count(elem)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(data, elements):\n \"\"\"\n Counts the occurrence of all elements of the given list in a tuple.\n\n Args:\n data (tuple): The tuple in which to count the elements.\n elements (list): The list of elements to count.\n\n Returns:\n int: The total count of the specified elements in the tuple.\n \"\"\"\n count = 0\n for element in elements:\n count += data.count(element)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tuple_list, element_list):\n count = 0\n for elem in element_list:\n count += tuple_list.count(elem)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tuple_list, search_list):\n \"\"\"\n Counts the occurrence of elements in the search_list within tuple_list.\n\n Args:\n tuple_list (tuple): A tuple containing elements to search through.\n search_list (list): A list of elements to count their occurrences in the tuple_list.\n\n Returns:\n int: The total count of occurrences of elements in search_list within tuple_list.\n \"\"\"\n # Flatten the tuple_list into a list to make counting easier\n flattened_list = list(tuple_list)\n\n # Initialize the count\n count = 0\n\n # Count occurrences of each element in search_list\n for element in search_list:\n count += flattened_list.count(element)\n\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(t, lst):\n count = 0\n for element in lst:\n count += t.count(element)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(t, lst):\n \"\"\"\n Count the occurrence of all elements of the list in a tuple.\n\n Parameters:\n t (tuple): The input tuple.\n lst (list): The list of elements to count in the tuple.\n\n Returns:\n int: The total count of elements from the list found in the tuple.\n \"\"\"\n return sum(t.count(element) for element in lst)", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(t, lst):\n count = 0\n for element in lst:\n count += t.count(element)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(input_tuple, target_list):\n count = 0\n for element in target_list:\n count += input_tuple.count(element)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tup, lst):\n count = 0\n for element in lst:\n count += tup.count(element)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tup, lst):\n count = 0\n for item in lst:\n count += tup.count(item)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tup, lst):\n # Initialize a dictionary to store the count of occurrences\n count_dict = {}\n\n # Count the occurrences of each element in the tuple\n for elem in tup:\n if elem in count_dict:\n count_dict[elem] += 1\n else:\n count_dict[elem] = 1\n\n # Calculate the total count of elements from the list in the tuple\n total_count = 0\n for elem in lst:\n if elem in count_dict:\n total_count += count_dict[elem]\n\n return total_count", "matching_cluster_idx": 4}, {"solution": "def count_Occurrence(t, l):\n count = 0\n for elem in l:\n count += t.count(elem)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(t, l):\n \"\"\"\n This function takes a tuple and a list as inputs and returns the count\n of elements in the list that occur in the tuple.\n\n Parameters:\n t (tuple): A tuple of elements.\n l (list): A list of elements whose occurrences in the tuple need to be counted.\n\n Returns:\n int: The count of elements from the list that occur in the tuple.\n \"\"\"\n count = 0\n for element in l:\n if element in t:\n count += t.count(element)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tup, lst):\n \"\"\"\n Count the occurrence of all elements of a list in a tuple.\n\n Args:\n tup (tuple): The tuple in which to count the elements.\n lst (list): The list of elements to count in the tuple.\n\n Returns:\n int: The total number of occurrences of the elements from the list in the tuple.\n \"\"\"\n count = 0\n for item in lst:\n count += tup.count(item)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(t, lst):\n \"\"\"Count the occurrences of list elements in a tuple.\"\"\"\n count = 0\n for elem in lst:\n count += t.count(elem)\n return count", "matching_cluster_idx": 2}, {"solution": "def count_Occurrence(tup, lst):\n count = 0\n for element in lst:\n count += tup.count(element)\n return count", "matching_cluster_idx": 2}]}, "Mbpp/451": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 29.0, "profiled": [{"solution": "def remove_whitespaces(input_string):\n \"\"\"\n Removes all whitespace characters from the given string.\n\n Args:\n input_string (str): The string from which to remove whitespace.\n\n Returns:\n str: The input string with all whitespaces removed.\n \"\"\"\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string):\n # Use the replace method to remove all whitespaces from the input string\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(s: str) -> str:\n \"\"\"\n Remove all whitespaces from the given string.\n\n Parameters:\n s (str): The input string.\n\n Returns:\n str: The string with all whitespaces removed.\n \"\"\"\n # Use the replace() method to remove all whitespaces\n return s.replace(' ', '')", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(s: str) -> str:\n # Using the replace method to remove all spaces\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(s):\n \"\"\"\n Remove all whitespaces from the given string.\n :param s: str\n :return: str\n \"\"\"\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(s):\n \"\"\"\n Remove all whitespaces from the given string.\n\n Args:\n s (str): Input string with possible whitespaces.\n\n Returns:\n str: String with all whitespaces removed.\n \"\"\"\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(s):\n # Remove all whitespace characters from the string using str.replace method\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(s: str) -> str:\n \"\"\"\n Remove all whitespaces from the given string.\n \"\"\"\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(s: str) -> str:\n \"\"\"\n Remove all whitespaces from the given string.\n\n Args:\n s (str): The input string.\n\n Returns:\n str: The string with all whitespaces removed.\n \"\"\"\n # Return the string with all whitespaces replaced with empty strings\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(s):\n # Using the replace() method to remove all whitespaces\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string):\n \"\"\"\n This function removes all whitespaces from the given string.\n\n :param input_string: string from which whitespaces need to be removed\n :return: string with all whitespaces removed\n \"\"\"\n # Return the input string with all whitespaces replaced by an empty string\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(s):\n \"\"\"\n Remove all whitespaces from the given string.\n\n :param s: Input string\n :return: String with all whitespaces removed\n \"\"\"\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(s):\n # Using the replace method to remove all whitespaces\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(s):\n \"\"\"\n Remove all whitespaces from the given string.\n\n Parameters:\n s (str): The input string.\n\n Returns:\n str: The input string with all whitespaces removed.\n \"\"\"\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string):\n \"\"\"\n Removes all whitespaces from the given string.\n\n Args:\n input_string (str): The string from which to remove whitespaces.\n\n Returns:\n str: The input string with all whitespaces removed.\n \"\"\"\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string):\n \"\"\"\n Remove all whitespaces from the given string.\n\n Parameters:\n input_string (str): The string from which to remove whitespaces.\n\n Returns:\n str: The string with all whitespaces removed.\n \"\"\"\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(s):\n # Using str.replace method to remove all whitespaces\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(s: str) -> str:\n \"\"\"\n Remove all whitespaces from the given string.\n\n Args:\n s (str): The input string.\n\n Returns:\n str: The string without any whitespaces.\n \"\"\"\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string):\n # Use the replace() method to remove all whitespaces\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_whitespaces(input_string: str) -> str:\n \"\"\"\n Removes all whitespaces from the given string.\n \"\"\"\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}]}, "Mbpp/456": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def reverse_string_list(strings):\n \"\"\"\n Reverses each string in the given list of string values.\n\n Args:\n strings (list of str): List of strings to reverse.\n\n Returns:\n list of str: List with each string reversed.\n \"\"\"\n return [s[::-1] for s in strings]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(strings):\n \"\"\"\n Reverse each string in a given list of strings.\n\n Parameters:\n strings (list): List of strings to be reversed.\n\n Returns:\n list: List of reversed strings.\n \"\"\"\n return [s[::-1] for s in strings]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n \"\"\"\n Reverses each string in a given list of string values.\n\n Parameters:\n string_list (list of str): The list of strings to reverse.\n\n Returns:\n list of str: A new list with each string reversed.\n \"\"\"\n return [s[::-1] for s in string_list]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n # Using list comprehension to reverse each string\n return [s[::-1] for s in string_list]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(strings):\n \"\"\"\n Reverse each string in a given list of string values.\n\n Args:\n strings (list of str): List of strings to reverse.\n\n Returns:\n list of str: List of reversed strings.\n \"\"\"\n return [s[::-1] for s in strings]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(strings):\n \"\"\"\n Reverse each string in the given list of string values.\n\n :param strings: List of strings to be reversed.\n :return: List of reversed strings.\n \"\"\"\n return [s[::-1] for s in strings]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(strings):\n return [s[::-1] for s in strings]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(strings):\n \"\"\"\n Reverses each string in a list of strings.\n\n :param strings: List of strings to be reversed.\n :return: List of reversed strings.\n \"\"\"\n return [s[::-1] for s in strings]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(strings):\n # Function to reverse a single string\n def reverse_string(s):\n return s[::-1]\n\n # Reverse each string in the list\n return [reverse_string(s) for s in strings]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(string_list):\n \"\"\"\n Reverse each string in a given list of string values.\n\n Args:\n string_list (list of str): List of strings to be reversed.\n\n Returns:\n list of str: List with each string reversed.\n \"\"\"\n return [s[::-1] for s in string_list]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(strings):\n # This function takes a list of strings and returns a new list\n # with each string reversed.\n reversed_strings = [s[::-1] for s in strings]\n return reversed_strings", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(strings):\n \"\"\"\n Reverse each string in a given list of string values.\n\n Parameters:\n strings (list of str): List of strings to be reversed.\n\n Returns:\n list of str: List of reversed strings.\n \"\"\"\n return [s[::-1] for s in strings]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(strings):\n \"\"\"\n Reverse each string in a given list of strings.\n\n Parameters:\n strings (list of str): List of string values to be reversed.\n\n Returns:\n list of str: List with each string reversed.\n \"\"\"\n # Using list comprehension to reverse each string\n return [s[::-1] for s in strings]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(strings):\n \"\"\"\n Reverses each string in a given list of string values.\n\n Parameters:\n strings (list of str): List of string values to reverse.\n\n Returns:\n list of str: List with each string reversed.\n \"\"\"\n return [s[::-1] for s in strings]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(strings):\n \"\"\"\n Reverse each string in a given list of string values.\n\n Args:\n strings (list of str): The list of strings to be reversed.\n\n Returns:\n list of str: A new list with each string reversed.\n \"\"\"\n return [s[::-1] for s in strings]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(strings):\n # Use list comprehension to reverse each string in the list\n return [s[::-1] for s in strings]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(strings):\n \"\"\"\n Function to reverse each string in a given list of string values.\n\n Parameters:\n strings (list): List of strings to be reversed.\n\n Returns:\n list: List of reversed strings.\n \"\"\"\n return [s[::-1] for s in strings]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(strings):\n \"\"\"\n Reverses each string in the given list of string values.\n\n Parameters:\n strings (list): A list of string values to be reversed.\n\n Returns:\n list: A list of reversed strings.\n \"\"\"\n return [s[::-1] for s in strings]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(strings):\n \"\"\"\n Reverses each string in a given list of string values.\n\n :param strings: List of strings to be reversed.\n :return: List of reversed strings.\n \"\"\"\n return [s[::-1] for s in strings]", "matching_cluster_idx": 4}, {"solution": "def reverse_string_list(strings):\n \"\"\"\n Reverses each string in the given list of string values.\n\n :param strings: List of strings to reverse\n :return: List of reversed strings\n \"\"\"\n return [s[::-1] for s in strings]", "matching_cluster_idx": 4}]}, "Mbpp/460": {"dps": 41.730769230769226, "dps_norm": 77.0, "pass@1": 86.0, "profiled": [{"solution": "def Extract(lst):\n \"\"\"\n Extracts the first element of each sublist.\n\n Parameters:\n lst (list of list of int): List of sublists.\n\n Returns:\n list of int: List containing the first element of each sublist.\n \"\"\"\n return [sublist[0] for sublist in lst]", "matching_cluster_idx": 3}, {"solution": "def Extract(sublists):\n return [sublist[0] for sublist in sublists]", "matching_cluster_idx": 3}, {"solution": "def Extract(lists):\n \"\"\"\n This function takes a list of lists and returns a new list containing the first element of each sublist.\n\n Parameters:\n lists (list of lists): A list where each element is a sublist.\n\n Returns:\n list: A list containing the first element of each sublist.\n \"\"\"\n return [sublist[0] for sublist in lists]", "matching_cluster_idx": 3}, {"solution": "def Extract(lists):\n # Using a list comprehension to get the first element of each sublist\n return [sublist[0] for sublist in lists]", "matching_cluster_idx": 3}, {"solution": "def Extract(sublists):\n # Initialize an empty list to store the first elements\n first_elements = []\n\n # Iterate through each sublist in the input list\n for sublist in sublists:\n # Append the first element of the current sublist to the result list\n first_elements.append(sublist[0])\n\n # Return the list of first elements\n return first_elements", "matching_cluster_idx": 3}, {"solution": "def Extract(sublists):\n return [sublist[0] for sublist in sublists]", "matching_cluster_idx": 3}, {"solution": "def Extract(lists):\n return [sublist[0] for sublist in lists]", "matching_cluster_idx": 3}, {"solution": "def Extract(lst):\n # Initialize an empty list to store the first elements of each sublist\n result = []\n\n # Iterate over each sublist in the main list\n for sublist in lst:\n # Append the first element of the sublist to the result list\n if sublist: # Check if the sublist is not empty\n result.append(sublist[0])\n\n return result", "matching_cluster_idx": 2}, {"solution": "def Extract(sublists):\n return [sublist[0] for sublist in sublists]", "matching_cluster_idx": 3}, {"solution": "def Extract(sublists):\n return [sublist[0] for sublist in sublists]", "matching_cluster_idx": 3}, {"solution": "def Extract(lists):\n return [sublist[0] for sublist in lists]", "matching_cluster_idx": 3}, {"solution": "def Extract(lst):\n # Initialize an empty list to store the first elements\n first_elements = []\n # Iterate over each sublist in the input list\n for sublist in lst:\n # Append the first element of the sublist to the result list\n first_elements.append(sublist[0])\n # Return the list containing the first elements\n return first_elements", "matching_cluster_idx": 3}, {"solution": "def Extract(lists):\n # Initialize an empty list to store the first elements\n result = []\n\n # Loop through each sublist in the input list\n for sublist in lists:\n # Check if the sublist is not empty and append the first element to the result\n if sublist:\n result.append(sublist[0])\n\n # Return the result list\n return result", "matching_cluster_idx": 2}, {"solution": "def Extract(lists):\n return [sublist[0] for sublist in lists]", "matching_cluster_idx": 3}, {"solution": "def Extract(sublists):\n \"\"\"\n Extracts the first element of each sublist.\n\n Args:\n sublists (list of lists): List containing multiple sublists.\n\n Returns:\n list: A new list containing the first element of each sublist.\n \"\"\"\n return [sublist[0] for sublist in sublists]", "matching_cluster_idx": 3}, {"solution": "def Extract(lst):\n return [sublist[0] for sublist in lst]", "matching_cluster_idx": 3}, {"solution": "def Extract(lst):\n return [sublist[0] for sublist in lst]", "matching_cluster_idx": 3}, {"solution": "def Extract(lists):\n # Initialize an empty list to store the first elements\n result = []\n # Iterate through each sublist\n for sublist in lists:\n # Add the first element of the sublist to the result list\n result.append(sublist[0])\n return result", "matching_cluster_idx": 3}, {"solution": "def Extract(lists):\n # Initialize an empty list to store the first elements of each sublist\n first_elements = []\n\n # Iterate through each sublist\n for sublist in lists:\n # Append the first element of the sublist to the result list\n if sublist: # Check if the sublist is not empty\n first_elements.append(sublist[0])\n\n # Return the list of first elements\n return first_elements", "matching_cluster_idx": 2}, {"solution": "def Extract(sublists):\n return [sublist[0] for sublist in sublists]", "matching_cluster_idx": 3}]}, "Mbpp/474": {"dps": 93.97560975609755, "dps_norm": 96.42857142857143, "pass@1": 100.0, "profiled": [{"solution": "def replace_char(s, old, new):\n \"\"\"\n Replaces all occurrences of `old` character with `new` character in the string `s`.\n\n :param s: input string\n :param old: character to be replaced\n :param new: character to replace with\n :return: modified string with replacements\n \"\"\"\n return s.replace(old, new)", "matching_cluster_idx": 6}, {"solution": "def replace_char(string, old, new):\n return string.replace(old, new)", "matching_cluster_idx": 6}, {"solution": "def replace_char(input_string, char_to_replace, replacement_char):\n \"\"\"\n Replace all occurrences of a character in a string.\n\n :param input_string: The original string.\n :param char_to_replace: The character to be replaced.\n :param replacement_char: The character to replace with.\n :return: A new string with all occurrences of char_to_replace replaced by replacement_char.\n \"\"\"\n # Using list comprehension to create a new list with replaced characters, then join it back into a string\n return ''.join([replacement_char if char == char_to_replace else char for char in input_string])", "matching_cluster_idx": 4}, {"solution": "def replace_char(s, old, new):\n \"\"\"\n Replace all occurrences of 'old' with 'new' in the string 's'.\n\n Args:\n s (str): The input string.\n old (str): The character to be replaced.\n new (str): The character to replace with.\n\n Returns:\n str: The new string with replacements.\n \"\"\"\n return s.replace(old, new)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, old_char, new_char):\n \"\"\"\n Replace all occurrences of old_char in the string s with new_char.\n\n Parameters:\n s (str): The input string.\n old_char (str): The character to be replaced.\n new_char (str): The character to replace with.\n\n Returns:\n str: The modified string.\n \"\"\"\n return s.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, old, new):\n # Return a new string with all occurrences of 'old' replaced with 'new'\n return s.replace(old, new)", "matching_cluster_idx": 6}, {"solution": "def replace_char(string, old, new):\n \"\"\"\n Replace all occurrences of old character with new character in the string.\n\n Parameters:\n string (str): The original string.\n old (str): The character to replace.\n new (str): The character to replace with.\n\n Returns:\n str: The new string with the characters replaced.\n \"\"\"\n return string.replace(old, new)", "matching_cluster_idx": 6}, {"solution": "def replace_char(input_string, old_char, new_char):\n \"\"\"\n Replaces all occurrences of old_char in input_string with new_char.\n\n Parameters:\n input_string (str): The string in which characters need to be replaced.\n old_char (str): The character that needs to be replaced.\n new_char (str): The character that will replace old_char.\n\n Returns:\n str: The modified string.\n \"\"\"\n # Replace occurrences of old_char with new_char\n result = input_string.replace(old_char, new_char)\n return result", "matching_cluster_idx": 6}, {"solution": "def replace_char(input_string, old_char, new_char):\n return input_string.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, old_char, new_char):\n # Use the join and replace methods to create the new string\n return ''.join(new_char if char == old_char else char for char in s)", "matching_cluster_idx": 3}, {"solution": "def replace_char(input_string, char_to_replace, replacement_char):\n \"\"\"\n This function replaces all occurrences of char_to_replace in input_string with replacement_char.\n\n Args:\n input_string (str): The string in which to replace characters.\n char_to_replace (str): The character to be replaced.\n replacement_char (str): The character to replace with.\n\n Returns:\n str: The modified string with all occurrences of char_to_replace replaced.\n \"\"\"\n return input_string.replace(char_to_replace, replacement_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(input_string, char_to_replace, replace_with):\n # Create a new string where all occurrences of char_to_replace are replaced by replace_with\n return input_string.replace(char_to_replace, replace_with)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, old, new):\n # Return a new string with all occurrences of old replaced with new\n return s.replace(old, new)", "matching_cluster_idx": 6}, {"solution": "def replace_char(input_string, old_char, new_char):\n return input_string.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, old, new):\n \"\"\"\n This function replaces all occurrences of `old` character in string `s`\n with `new` character.\n\n Args:\n s (str): The string in which to replace characters.\n old (str): The character to be replaced.\n new (str): The character to replace with.\n\n Returns:\n str: The modified string.\n \"\"\"\n return s.replace(old, new)", "matching_cluster_idx": 6}, {"solution": "def replace_char(string, old_char, new_char):\n return string.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(input_string, old_char, new_char):\n # Use the `replace` method of the string class to replace occurrences of old_char with new_char\n return input_string.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, old, new):\n # This function replaces all occurrences of 'old' character with 'new' in the string 's'.\n return s.replace(old, new)", "matching_cluster_idx": 6}, {"solution": "def replace_char(s, old_char, new_char):\n return s.replace(old_char, new_char)", "matching_cluster_idx": 6}, {"solution": "def replace_char(input_string, old_char, new_char):\n \"\"\"\n This function replaces all occurrences of old_char in input_string with new_char.\n\n :param input_string: The original string.\n :param old_char: The character to be replaced.\n :param new_char: The character to replace with.\n :return: The string after replacement.\n \"\"\"\n return input_string.replace(old_char, new_char)", "matching_cluster_idx": 6}]}, "Mbpp/476": {"dps": 96.84563758389261, "dps_norm": 98.33333333333333, "pass@1": 98.0, "profiled": [{"solution": "def big_sum(arr):\n if len(arr) < 2:\n raise ValueError(\"Array must contain at least two elements\")\n smallest = min(arr)\n largest = max(arr)\n return smallest + largest", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n # Ensure the array is not empty\n if len(arr) == 0:\n raise ValueError(\"Array must not be empty\")\n\n # Find the maximum and minimum values in the array\n max_val = max(arr)\n min_val = min(arr)\n\n # Calculate the sum of the maximum and minimum values\n sum_max_min = max_val + min_val\n\n return sum_max_min", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n \"\"\"\n Finds the sum of the largest and smallest value in a given array.\n \"\"\"\n if not arr:\n return 0\n\n min_val = min(arr)\n max_val = max(arr)\n\n return min_val + max_val", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n if not arr:\n return 0\n return max(arr) + min(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n \"\"\"\n This function finds the sum of the largest and smallest value in a given array.\n\n :param arr: List of numbers\n :return: Sum of the largest and smallest value\n \"\"\"\n if len(arr) < 2:\n raise ValueError(\"Array must contain at least two elements\")\n\n min_val = min(arr)\n max_val = max(arr)\n\n return min_val + max_val", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n if len(arr) == 0:\n raise ValueError(\"Array is empty\")\n return max(arr) + min(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n if len(arr) == 0:\n return 0\n max_val = max(arr)\n min_val = min(arr)\n return max_val + min_val", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n if not arr: # Check if the array is empty\n return None\n\n smallest = min(arr)\n largest = max(arr)\n\n return smallest + largest", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n if len(arr) < 2:\n raise ValueError(\"Array must contain at least two elements\")\n\n smallest = min(arr)\n largest = max(arr)\n return smallest + largest", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n if not arr: # Check if the array is empty\n return 0\n\n min_val = min(arr)\n max_val = max(arr)\n\n return min_val + max_val", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n # Check if the array is not empty\n if not arr:\n raise ValueError(\"The array should not be empty\")\n\n # Find the smallest and largest values in the array\n smallest = min(arr)\n largest = max(arr)\n\n # Return the sum of the smallest and largest values\n return smallest + largest", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n if not arr:\n return 0 # Handle empty array case\n smallest = min(arr)\n largest = max(arr)\n return smallest + largest", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n if not arr:\n return 0\n return max(arr) + min(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n # Ensure the array is not empty\n if len(arr) == 0:\n raise ValueError(\"Array must not be empty\")\n\n # Find the largest and smallest values in the array\n largest = max(arr)\n smallest = min(arr)\n\n # Return the sum of the largest and smallest values\n return largest + smallest", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n # Check if the array is not empty\n if len(arr) == 0:\n return 0\n # Find the smallest and largest values in the array\n min_val = min(arr)\n max_val = max(arr)\n # Return the sum of the smallest and largest values\n return min_val + max_val", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n if not arr: # Check if the array is empty\n return 0\n smallest = float('inf')\n largest = float('-inf')\n for num in arr:\n if num < smallest:\n smallest = num\n if num > largest:\n largest = num\n return smallest + largest", "matching_cluster_idx": 3}, {"solution": "def big_sum(arr):\n \"\"\"\n Returns the sum of the largest and smallest values in a given array.\n\n Parameters:\n arr (list): List of integers\n\n Returns:\n int: Sum of the largest and smallest values in the array\n \"\"\"\n if not arr:\n raise ValueError(\"Array must contain at least one element\")\n\n min_value = min(arr)\n max_value = max(arr)\n return min_value + max_value", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n if not arr:\n return 0\n return max(arr) + min(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n if not arr: # Check if the array is empty\n return None\n return min(arr) + max(arr)", "matching_cluster_idx": 5}, {"solution": "def big_sum(arr):\n # Ensure the array is not empty\n if not arr:\n raise ValueError(\"Array must contain at least one element\")\n\n # Find the smallest and largest values in the array\n smallest = min(arr)\n largest = max(arr)\n\n # Return their sum\n return smallest + largest", "matching_cluster_idx": 5}]}, "Mbpp/477": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 65.0, "profiled": [{"solution": "def to_lower(input_string: str) -> str:\n return input_string.lower()\ndef is_lower(input_string: str) -> str:\n return to_lower(input_string)", "matching_cluster_idx": 4}, {"solution": "def is_lower(input_string):\n # Convert the given string to lower case\n return input_string.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(input_string):\n \"\"\"\n Converts the given string to lower case.\n\n Parameters:\n input_string (str): The string to convert.\n\n Returns:\n str: The input string in lower case.\n \"\"\"\n return input_string.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n \"\"\"\n Convert the given string to lower case.\n \"\"\"\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(input_string):\n \"\"\"\n This function converts the given string to lower case.\n\n Parameters:\n input_string (str): The string to be converted.\n\n Returns:\n str: The converted string in lower case.\n \"\"\"\n return input_string.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n \"\"\"\n Convert the given string to lower case.\n\n Args:\n s (str): The input string.\n\n Returns:\n str: The input string converted to lower case.\n \"\"\"\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s: str) -> str:\n \"\"\"\n Convert the given string to lower case.\n\n :param s: The input string.\n :return: The input string converted to lower case.\n \"\"\"\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(string: str) -> str:\n \"\"\"\n Convert the given string to lower case.\n\n Args:\n string (str): The input string.\n\n Returns:\n str: The input string converted to lower case.\n \"\"\"\n return string.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s: str) -> str:\n \"\"\"\n Convert the given string to lower case.\n \"\"\"\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(string):\n \"\"\"\n Converts the given string to lowercase.\n\n Parameters:\n string (str): The input string to be converted.\n\n Returns:\n str: The converted lowercase string.\n \"\"\"\n return string.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(string: str) -> str:\n \"\"\"\n Converts the given string to lower case.\n \"\"\"\n return string.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s: str) -> str:\n \"\"\"\n Convert the given string to lower case.\n\n Args:\n s (str): Input string.\n\n Returns:\n str: Lower case version of the input string.\n \"\"\"\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(input_string):\n return input_string.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(s):\n return s.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(input_str):\n return input_str.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(string):\n # Convert the input string to lower case\n return string.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(input_string):\n # Converting the input string to lower case\n return input_string.lower()", "matching_cluster_idx": 4}, {"solution": "def is_lower(input_string):\n return input_string.lower()", "matching_cluster_idx": 4}]}, "Mbpp/563": {"dps": 81.85792349726776, "dps_norm": 79.54545454545455, "pass@1": 88.0, "profiled": [{"solution": "import re\ndef extract_values(string):\n # Use regular expressions to find all substrings between quotation marks\n return re.findall(r'\"([^\"]*)\"', string)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(s):\n # Use regular expression to find all substrings within quotation marks\n return re.findall(r'\"([^\"]*)\"', s)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(input_string):\n # Use regular expressions to find all substrings enclosed in quotation marks\n values = re.findall(r'\"([^\"]*)\"', input_string)\n return values", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(s):\n # Using regular expressions to find all substrings within double quotes\n return re.findall(r'\"([^\"]*)\"', s)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(input_string):\n # This regular expression will find all substrings within double quotes\n pattern = re.compile(r'\"([^\"]*)\"')\n matches = pattern.findall(input_string)\n return matches", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(input_string):\n # This regex pattern matches any substring enclosed in double quotes\n pattern = r'\"([^\"]*)\"'\n matches = re.findall(pattern, input_string)\n return matches", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(string):\n # Use regular expression to find all substrings within quotes\n return re.findall(r'\"(.*?)\"', string)", "matching_cluster_idx": 8}, {"solution": "def extract_values(string):\n import re\n # Using regular expression to find all substrings enclosed in quotation marks\n values = re.findall(r'\"(.*?)\"', string)\n return values", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(s):\n \"\"\"\n Extract values between quotation marks from a string.\n\n Parameters:\n s (str): The input string.\n\n Returns:\n list: List of extracted values between quotation marks.\n \"\"\"\n # Use regular expressions to find all substrings enclosed in quotes\n values = re.findall(r'\"(.*?)\"', s)\n return values", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(input_string):\n # Use regular expression to find all substrings enclosed in double quotes\n values = re.findall(r'\"([^\"]*)\"', input_string)\n return values", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(string):\n # Use regular expression to find all substrings enclosed in quotation marks\n matches = re.findall(r'\"(.*?)\"', string)\n return matches", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(s):\n # Use regex to find all substrings between quotes\n return re.findall(r'\"(.*?)\"', s)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(s):\n # Use regex to find all sequences of characters enclosed in double quotes\n return re.findall(r'\"(.*?)\"', s)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(s):\n # Use regular expressions to find all substrings between quotes\n return re.findall(r'\"(.*?)\"', s)", "matching_cluster_idx": 8}, {"solution": "def extract_values(input_string):\n values = []\n start = 0\n while start < len(input_string):\n if input_string[start] == '\"':\n end = input_string.find('\"', start + 1)\n if end == -1:\n break\n values.append(input_string[start + 1:end])\n start = end + 1\n else:\n start += 1\n return values", "matching_cluster_idx": 1}, {"solution": "def extract_values(s):\n result = []\n start = 0\n while True:\n start = s.find('\"', start)\n if start == -1:\n break\n start += 1\n end = s.find('\"', start)\n if end == -1:\n break\n result.append(s[start:end])\n start = end + 1\n return result", "matching_cluster_idx": 10}, {"solution": "import re\ndef extract_values(s):\n # Use regular expression to find all substrings between quotation marks\n return re.findall(r'\"([^\"]*)\"', s)", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(input_string):\n # Use a regular expression to find all substrings between quotation marks\n matches = re.findall(r'\"([^\"]*)\"', input_string)\n return matches", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(input_string):\n # Regular expression to find all substrings between double quotation marks\n pattern = r'\"([^\"]*)\"'\n matches = re.findall(pattern, input_string)\n return matches", "matching_cluster_idx": 8}, {"solution": "import re\ndef extract_values(input_string):\n # Use regular expressions to find all substrings between quotation marks\n matches = re.findall(r'\"(.*?)\"', input_string)\n return matches", "matching_cluster_idx": 8}]}, "Mbpp/572": {"dps": 92.03703703703704, "dps_norm": 82.85714285714285, "pass@1": 41.0, "profiled": [{"solution": "def two_unique_nums(nums):\n # Use a dictionary to count the frequency of each number\n freq = {}\n for num in nums:\n if num in freq:\n freq[num] += 1\n else:\n freq[num] = 1\n\n # Collect numbers that appear only once\n unique_nums = [num for num in freq if freq[num] == 1]\n\n return unique_nums", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(lst):\n # Dictionary to keep track of the occurrence of each number\n num_counts = {}\n\n # Iterate through the list and populate the dictionary\n for num in lst:\n if num in num_counts:\n num_counts[num] += 1\n else:\n num_counts[num] = 1\n\n # List to store the unique numbers\n unique_nums = []\n\n # Iterate through the dictionary and add numbers that occur exactly once\n for num, count in num_counts.items():\n if count == 1:\n unique_nums.append(num)\n\n return unique_nums", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(nums):\n # Use a set to keep track of seen numbers and their counts\n num_counts = {}\n for num in nums:\n if num in num_counts:\n num_counts[num] += 1\n else:\n num_counts[num] = 1\n\n # Filter out numbers that appear more than once\n unique_nums = [num for num in nums if num_counts[num] == 1]\n\n return unique_nums", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(nums):\n unique_counts = {}\n\n for num in nums:\n if num in unique_counts:\n unique_counts[num] += 1\n else:\n unique_counts[num] = 1\n\n unique_nums = [num for num, count in unique_counts.items() if count == 1]\n return unique_nums", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(nums):\n # Create a dictionary to store the frequency of each number\n frequency = {}\n for num in nums:\n if num in frequency:\n frequency[num] += 1\n else:\n frequency[num] = 1\n\n # Collect numbers that appear only once\n result = [num for num, count in frequency.items() if count == 1]\n\n return result", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(numbers):\n # Create a dictionary to count the occurrences of each number\n num_count = {}\n\n # Traverse the list and populate the count dictionary\n for num in numbers:\n if num in num_count:\n num_count[num] += 1\n else:\n num_count[num] = 1\n\n # List to store numbers that appear exactly once\n result = [num for num, count in num_count.items() if count == 1]\n\n return result", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(nums):\n # Count the occurrences of each number using a dictionary\n count = {}\n for num in nums:\n if num in count:\n count[num] += 1\n else:\n count[num] = 1\n\n # Collect numbers that appear exactly once\n unique_nums = [num for num in nums if count[num] == 1]\n\n return unique_nums", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(nums):\n # Dictionary to keep track of occurrences of each number\n count = {}\n\n # Count each number in the list\n for num in nums:\n if num in count:\n count[num] += 1\n else:\n count[num] = 1\n\n # Filter out the numbers that have more than one occurrence\n unique_nums = [num for num in nums if count[num] == 1]\n\n return unique_nums", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(nums):\n nums_set = set(nums)\n return [num for num in nums if nums.count(num) == 1]", "matching_cluster_idx": 1}, {"solution": "def two_unique_nums(nums):\n # Create a dictionary to count the frequency of each number\n frequency = {}\n\n for num in nums:\n if num in frequency:\n frequency[num] += 1\n else:\n frequency[num] = 1\n\n # Collect numbers that appear exactly once\n unique_nums = [num for num in frequency if frequency[num] == 1]\n\n return unique_nums", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(nums):\n unique_nums = []\n num_counts = {}\n\n for num in nums:\n if num in num_counts:\n num_counts[num] += 1\n else:\n num_counts[num] = 1\n\n for num in nums:\n if num_counts[num] == 1:\n unique_nums.append(num)\n\n return unique_nums", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(nums):\n \"\"\"\n This function takes a list of numbers and returns a new list with the two unique numbers.\n \"\"\"\n # Use a dictionary to count occurrences of each number\n count_dict = {}\n for num in nums:\n if num in count_dict:\n count_dict[num] += 1\n else:\n count_dict[num] = 1\n\n # Find the numbers that appear exactly once\n unique_nums = [num for num in count_dict if count_dict[num] == 1]\n\n return unique_nums", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(nums):\n # Create a dictionary to track the frequency of each number\n freq = {}\n for num in nums:\n if num in freq:\n freq[num] += 1\n else:\n freq[num] = 1\n\n # Collect numbers that appear exactly once\n result = [num for num, count in freq.items() if count == 1]\n return result", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(numbers):\n # Create an empty dictionary to store the frequency of each number\n frequency = {}\n\n # Iterate over the list of numbers and populate the frequency dictionary\n for num in numbers:\n if num in frequency:\n frequency[num] += 1\n else:\n frequency[num] = 1\n\n # Initialize a list to store unique numbers\n unique_numbers = []\n\n # Iterate over the frequency dictionary and collect numbers that appear exactly once\n for num, count in frequency.items():\n if count == 1:\n unique_numbers.append(num)\n\n return unique_numbers", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(nums):\n # Use a dictionary to count the occurrences of each number\n count_dict = {}\n for num in nums:\n if num in count_dict:\n count_dict[num] += 1\n else:\n count_dict[num] = 1\n\n # Extract numbers that occur exactly once\n unique_nums = [num for num in nums if count_dict[num] == 1]\n\n return unique_nums", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(nums):\n # Use a dictionary to count occurrences of each number\n count = {}\n for num in nums:\n if num in count:\n count[num] += 1\n else:\n count[num] = 1\n\n # Collect numbers that occur exactly once\n result = [num for num in count if count[num] == 1]\n\n return result", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(numbers):\n # Initialize an empty dictionary to keep track of the count of each number\n count_dict = {}\n\n # Traverse through the list and count the occurrences of each number\n for num in numbers:\n if num in count_dict:\n count_dict[num] += 1\n else:\n count_dict[num] = 1\n\n # Create a list to store the unique numbers\n unique_nums = []\n\n # Traverse through the list again and add numbers to the unique list only if their count is 1\n for num in numbers:\n if count_dict[num] == 1:\n unique_nums.append(num)\n\n # Return the list of unique numbers\n return unique_nums", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(nums):\n nums_dict = {}\n for num in nums:\n if num in nums_dict:\n nums_dict[num] += 1\n else:\n nums_dict[num] = 1\n\n unique_nums = [num for num in nums if nums_dict[num] == 1]\n return unique_nums", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(lst):\n # Create a dictionary to track the frequency of each number\n frequency = {}\n for num in lst:\n if num in frequency:\n frequency[num] += 1\n else:\n frequency[num] = 1\n\n # Collect numbers that appear exactly once\n unique_nums = [num for num, count in frequency.items() if count == 1]\n\n return unique_nums", "matching_cluster_idx": 5}, {"solution": "def two_unique_nums(nums):\n # Create a dictionary to track the frequency of each number\n freq = {}\n for num in nums:\n if num in freq:\n freq[num] += 1\n else:\n freq[num] = 1\n\n # Filter out numbers that appear more than once and create the result list\n result = [num for num in nums if freq[num] == 1]\n\n return result", "matching_cluster_idx": 5}]}, "Mbpp/578": {"dps": 62.25396825396825, "dps_norm": 64.54545454545455, "pass@1": 94.0, "profiled": [{"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"\n Interleave 3 lists of the same length into a single flat list.\n\n Args:\n list1 (list): First list of integers.\n list2 (list): Second list of integers.\n list3 (list): Third list of integers.\n\n Returns:\n list: Interleaved list.\n \"\"\"\n interleaved_list = []\n length = len(list1)\n\n for i in range(length):\n interleaved_list.append(list1[i])\n interleaved_list.append(list2[i])\n interleaved_list.append(list3[i])\n\n return interleaved_list", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n # Ensure all input lists have the same length\n if not all(len(lst) == len(list1) for lst in [list2, list3]):\n raise ValueError(\"All input lists must have the same length\")\n\n # Interleave elements from each list\n interleaved_list = []\n for i in range(len(list1)):\n interleaved_list.append(list1[i])\n interleaved_list.append(list2[i])\n interleaved_list.append(list3[i])\n\n return interleaved_list", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"\n Interleaves three lists of the same length into a single flat list.\n \"\"\"\n assert len(list1) == len(list2) == len(list3), \"All lists must have the same length\"\n\n interleaved_list = []\n for i in range(len(list1)):\n interleaved_list.append(list1[i])\n interleaved_list.append(list2[i])\n interleaved_list.append(list3[i])\n\n return interleaved_list", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"\n Interleaves three lists of the same length into a single flat list.\n\n Args:\n list1 (list): The first list.\n list2 (list): The second list.\n list3 (list): The third list.\n\n Returns:\n list: A single list that interleaves the elements from the input lists.\n \"\"\"\n if len(list1) != len(list2) or len(list2) != len(list3):\n raise ValueError(\"All lists must have the same length\")\n\n interleaved_list = []\n for i in range(len(list1)):\n interleaved_list.append(list1[i])\n interleaved_list.append(list2[i])\n interleaved_list.append(list3[i])\n\n return interleaved_list", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n assert len(list1) == len(list2) == len(list3), \"All input lists must be of the same length\"\n result = []\n for i in range(len(list1)):\n result.extend([list1[i], list2[i], list3[i]])\n return result", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n # Ensure all lists are of the same length\n if len(list1) != len(list2) or len(list1) != len(list3):\n raise ValueError(\"All input lists must be of the same length\")\n\n result = []\n for i in range(len(list1)):\n result.append(list1[i])\n result.append(list2[i])\n result.append(list3[i])\n\n return result", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"\n Interleave three lists of the same length into a single flat list.\n\n Parameters:\n list1 (list): First list of elements.\n list2 (list): Second list of elements.\n list3 (list): Third list of elements.\n\n Returns:\n list: Interleaved list of elements.\n \"\"\"\n if len(list1) != len(list2) or len(list1) != len(list3):\n raise ValueError(\"All input lists must have the same length\")\n\n interleaved = []\n for i in range(len(list1)):\n interleaved.append(list1[i])\n interleaved.append(list2[i])\n interleaved.append(list3[i])\n\n return interleaved", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"Interleave three lists of the same length into a single flat list.\n\n Args:\n list1 (list): First list of elements.\n list2 (list): Second list of elements.\n list3 (list): Third list of elements.\n\n Returns:\n list: A single flat list with elements from list1, list2, and list3 interleaved.\n \"\"\"\n interleaved = []\n for i in range(len(list1)):\n interleaved.append(list1[i])\n interleaved.append(list2[i])\n interleaved.append(list3[i])\n return interleaved", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n assert len(list1) == len(list2) == len(list3), \"All lists must be of the same length\"\n result = []\n for i in range(len(list1)):\n result.append(list1[i])\n result.append(list2[i])\n result.append(list3[i])\n return result", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n assert len(list1) == len(list2) == len(list3), \"All lists must be of the same length.\"\n interleaved_list = []\n for i in range(len(list1)):\n interleaved_list.append(list1[i])\n interleaved_list.append(list2[i])\n interleaved_list.append(list3[i])\n return interleaved_list", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n # Ensure that the lists have the same length\n assert len(list1) == len(list2) == len(list3), \"All lists must have the same length\"\n\n # Initialize the resulting interleaved list\n interleaved_list = []\n\n # Iterate through the indices of the lists\n for i in range(len(list1)):\n # Append elements from each list to the interleaved list\n interleaved_list.append(list1[i])\n interleaved_list.append(list2[i])\n interleaved_list.append(list3[i])\n\n return interleaved_list", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"\n Interleave three lists of the same length into a single flat list.\n \"\"\"\n if len(list1) != len(list2) or len(list2) != len(list3):\n raise ValueError(\"All input lists must be of the same length.\")\n\n return [item for triplet in zip(list1, list2, list3) for item in triplet]", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"\n Interleave three lists of the same length into a single flat list.\n\n Parameters:\n list1 (list): First list.\n list2 (list): Second list.\n list3 (list): Third list.\n\n Returns:\n list: Interleaved list.\n \"\"\"\n interleaved_list = []\n\n for i in range(len(list1)):\n interleaved_list.append(list1[i])\n interleaved_list.append(list2[i])\n interleaved_list.append(list3[i])\n\n return interleaved_list", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"\n Interleave three lists of the same length into a single flat list.\n\n Parameters:\n list1 (list): First list.\n list2 (list): Second list.\n list3 (list): Third list.\n\n Returns:\n list: Interleaved list.\n \"\"\"\n # Check if all lists are of the same length\n if len(list1) != len(list2) or len(list1) != len(list3):\n raise ValueError(\"All lists must be of the same length\")\n\n interleaved_list = []\n for i in range(len(list1)):\n interleaved_list.append(list1[i])\n interleaved_list.append(list2[i])\n interleaved_list.append(list3[i])\n\n return interleaved_list", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"\n Interleave three lists of the same length into a single flat list.\n\n Parameters:\n list1 (list): The first list.\n list2 (list): The second list.\n list3 (list): The third list.\n\n Returns:\n list: A single interleaved list.\n \"\"\"\n result = []\n length = len(list1)\n\n for i in range(length):\n result.append(list1[i])\n result.append(list2[i])\n result.append(list3[i])\n\n return result", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n assert len(list1) == len(list2) == len(list3), \"All lists must have the same length\"\n interleaved = []\n for i in range(len(list1)):\n interleaved.append(list1[i])\n interleaved.append(list2[i])\n interleaved.append(list3[i])\n return interleaved", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"\n Interleave three lists of the same length into a single flat list.\n\n Args:\n list1 (list): First list of elements.\n list2 (list): Second list of elements.\n list3 (list): Third list of elements.\n\n Returns:\n list: Interleaved list of elements from the three lists.\n \"\"\"\n return [item for sublist in zip(list1, list2, list3) for item in sublist]", "matching_cluster_idx": 7}, {"solution": "def interleave_lists(list1, list2, list3):\n # Ensure all lists have the same length\n if len(list1) != len(list2) or len(list1) != len(list3):\n raise ValueError(\"All lists must be of the same length\")\n\n # Initialize the interleaved list\n interleaved = []\n\n # Interleave elements from each list\n for i in range(len(list1)):\n interleaved.append(list1[i])\n interleaved.append(list2[i])\n interleaved.append(list3[i])\n\n return interleaved", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n interleaved = []\n for i in range(len(list1)):\n interleaved.append(list1[i])\n interleaved.append(list2[i])\n interleaved.append(list3[i])\n return interleaved", "matching_cluster_idx": 6}, {"solution": "def interleave_lists(list1, list2, list3):\n \"\"\"\n Interleave three lists of the same length into a single flat list.\n\n Parameters:\n list1 (list): First list to interleave.\n list2 (list): Second list to interleave.\n list3 (list): Third list to interleave.\n\n Returns:\n list: A flat list with elements interleaved from list1, list2, and list3.\n \"\"\"\n # Ensure all lists have the same length\n assert len(list1) == len(list2) == len(list3), \"All lists must be of the same length\"\n\n # Initialize the result list\n result = []\n\n # Loop over the range of the length of the lists\n for i in range(len(list1)):\n result.append(list1[i])\n result.append(list2[i])\n result.append(list3[i])\n\n return result", "matching_cluster_idx": 6}]}, "Mbpp/586": {"dps": 98.83040935672514, "dps_norm": 87.5, "pass@1": 33.0, "profiled": [{"solution": "def split_Arr(arr, n):\n if n <= 0 or n >= len(arr):\n return arr\n part1 = arr[:n]\n part2 = arr[n:]\n return part2 + part1", "matching_cluster_idx": 6}, {"solution": "def split_Arr(lst, n):\n \"\"\"\n Splits the list at the nth element and adds the first part to the end.\n\n :param lst: List of elements to be split.\n :param n: Position at which to split the list.\n :return: New list with the first part appended to the end.\n \"\"\"\n if n >= 0:\n return lst[n:] + lst[:n]\n else:\n return lst # Return the original list if n is negative", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"\n Splits the list at the nth element and adds the first part to the end.\n\n Parameters:\n arr (list): The input list to be split and rearranged.\n n (int): The index at which to split the list.\n\n Returns:\n list: The rearranged list as per the specified split and operation.\n \"\"\"\n if not arr or n <= 0 or n >= len(arr):\n return arr\n\n # Split the list into two parts\n part1 = arr[:n]\n part2 = arr[n:]\n\n # Combine part2 followed by part1\n return part2 + part1", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n # Check if n is within the bounds of the list\n if n < 0 or n >= len(arr):\n return arr # If n is out of bounds, return the original list\n # Split the list into two parts\n first_part = arr[:n]\n second_part = arr[n:]\n # Combine the second part with the first part\n return second_part + first_part", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n if n <= 0 or n > len(arr):\n return arr # return the array as it is if n is out of bounds\n\n # Split the list into two parts at the nth element\n first_part = arr[:n]\n second_part = arr[n:]\n\n # Concatenate the second part and the first part\n return second_part + first_part", "matching_cluster_idx": 6}, {"solution": "def split_Arr(lst, n):\n if n < 0 or n >= len(lst):\n return lst\n first_part = lst[:n]\n second_part = lst[n:]\n return second_part + first_part", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n if n <= 0 or n >= len(arr):\n return arr\n\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n # Check if the input list and n are valid\n if not arr or n <= 0 or n >= len(arr):\n return arr\n # Split the list at the nth element\n first_part = arr[:n]\n second_part = arr[n:]\n # Combine the second part with the first part\n return second_part + first_part", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n # Split the array at the nth element\n if n < 0 or n >= len(arr):\n return arr # Return the array as is if n is out of bounds\n split_point = arr[:n]\n rest_of_array = arr[n:]\n # Add the first part to the end of the rest of the array\n return rest_of_array + split_point", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n # Split the list at the nth element\n if n < 0 or n >= len(arr):\n return arr # If n is out of bounds, return the original list\n\n # Extract the first part of the list up to the nth element\n first_part = arr[:n]\n # Extract the second part of the list from the nth element to the end\n second_part = arr[n:]\n\n # Combine the parts such that the first part is added to the end of the second part\n return second_part + first_part", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n # Check if the array has enough elements\n if n >= len(arr):\n return arr\n\n # Split the array at the nth element\n first_part = arr[:n]\n second_part = arr[n:]\n\n # Combine the two parts\n return second_part + first_part", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n if n <= 0 or n > len(arr):\n return arr\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"\n Splits the list at the nth element and adds the first part to the end.\n\n :param arr: List of elements to be split.\n :param n: The element at which the list should be split.\n :return: New list with the first part moved to the end.\n \"\"\"\n if n >= len(arr):\n return arr # If n is out of bounds, return the original list.\n\n first_part = arr[:n]\n second_part = arr[n:]\n\n return second_part + first_part", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"\n Splits a list at the nth element and adds the first part to the end.\n\n :param arr: List of elements\n :param n: Index at which to split the list\n :return: Modified list\n \"\"\"\n if n <= 0 or n >= len(arr):\n return arr # If n is out of bounds, return the list as is\n\n # Split the list at the nth element\n first_part = arr[:n]\n second_part = arr[n:]\n\n # Concatenate the second part and the first part\n result = second_part + first_part\n\n return result", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n # Splitting the list at the nth element\n mid = arr[:n]\n end = arr[n:]\n\n # Concatenating the first part to the end\n return end + mid", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n if n >= len(arr):\n return arr\n part1 = arr[:n]\n part2 = arr[n:]\n return part2 + part1", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n \"\"\"\n Splits a list at the nth element and adds the first part to the end.\n\n Args:\n arr (list): The list to be split.\n n (int): The index at which to split the list.\n\n Returns:\n list: A new list with the first part moved to the end.\n \"\"\"\n if n < 0 or n >= len(arr):\n return arr # If n is out of bounds, return the original list\n\n # Split the list at index n\n first_part = arr[:n]\n second_part = arr[n:]\n\n # Combine the parts with the first part moved to the end\n return second_part + first_part", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n if n >= len(arr):\n return arr\n first_part = arr[:n]\n second_part = arr[n:]\n return second_part + first_part", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n if not arr or n <= 0 or n >= len(arr):\n return arr # If the array is empty, or n is out of bounds, return the original array\n return arr[n:] + arr[:n]", "matching_cluster_idx": 6}, {"solution": "def split_Arr(arr, n):\n if n < 1 or n > len(arr):\n return arr\n # Split the array into two parts at the nth element\n first_part = arr[:n]\n second_part = arr[n:]\n # Combine the second part with the first part\n return second_part + first_part", "matching_cluster_idx": 6}]}, "Mbpp/587": {"dps": 12.162162162162161, "dps_norm": 75.0, "pass@1": 88.0, "profiled": [{"solution": "def list_tuple(lst):\n \"\"\"\n Convert a list to a tuple.\n\n Args:\n lst (list): The list to be converted.\n\n Returns:\n tuple: The converted tuple.\n \"\"\"\n return tuple(lst)", "matching_cluster_idx": 2}, {"solution": "def list_tuple(lst):\n return tuple(lst)", "matching_cluster_idx": 2}, {"solution": "def list_tuple(lst):\n \"\"\"\n Convert a list to a tuple.\n\n Args:\n lst (list): The list to be converted.\n\n Returns:\n tuple: The tuple converted from the list.\n \"\"\"\n return tuple(lst)", "matching_cluster_idx": 2}, {"solution": "def list_tuple(lst):\n \"\"\"\n Convert a list to a tuple.\n\n Parameters:\n lst (list): The input list to convert.\n\n Returns:\n tuple: The converted tuple.\n \"\"\"\n return tuple(lst)", "matching_cluster_idx": 2}, {"solution": "def list_tuple(lst):\n return tuple(lst)", "matching_cluster_idx": 2}, {"solution": "def list_tuple(lst):\n \"\"\"\n Convert a list to a tuple.\n\n Parameters:\n lst (list): A list of elements to convert.\n\n Returns:\n tuple: A tuple containing the elements from the list.\n \"\"\"\n return tuple(lst)", "matching_cluster_idx": 2}, {"solution": "def list_tuple(lst):\n \"\"\"\n Convert a list to a tuple.\n\n Args:\n lst (list): The list to be converted to a tuple.\n\n Returns:\n tuple: The tuple representation of the input list.\n \"\"\"\n return tuple(lst)", "matching_cluster_idx": 2}, {"solution": "def list_tuple(lst):\n \"\"\"\n This function converts a list to a tuple.\n\n Args:\n lst (list): The input list to be converted.\n\n Returns:\n tuple: The converted tuple.\n \"\"\"\n return tuple(lst)", "matching_cluster_idx": 2}, {"solution": "def list_tuple(lst):\n return tuple(lst)", "matching_cluster_idx": 2}, {"solution": "def list_tuple(lst):\n \"\"\"\n Convert a list to a tuple.\n\n Args:\n lst (list): The input list to be converted.\n\n Returns:\n tuple: The tuple converted from the input list.\n \"\"\"\n return tuple(lst)", "matching_cluster_idx": 2}, {"solution": "def list_tuple(lst):\n \"\"\"\n This function converts a list to a tuple.\n\n :param lst: List to be converted\n :return: Tuple\n \"\"\"\n return tuple(lst)", "matching_cluster_idx": 2}, {"solution": "def list_tuple(lst):\n \"\"\"\n Converts a list to a tuple.\n\n Args:\n lst (list): A list of elements to be converted.\n\n Returns:\n tuple: A tuple containing the same elements as the input list.\n \"\"\"\n return tuple(lst)", "matching_cluster_idx": 2}, {"solution": "def list_tuple(lst):\n \"\"\"\n Convert a list to a tuple.\n\n Args:\n lst (list): The input list to be converted.\n\n Returns:\n tuple: The converted tuple.\n \"\"\"\n return tuple(lst)", "matching_cluster_idx": 2}, {"solution": "def list_tuple(lst):\n \"\"\"\n This function converts a list into a tuple.\n\n Parameters:\n lst (list): The list to be converted.\n\n Returns:\n tuple: The converted tuple.\n \"\"\"\n return tuple(lst)", "matching_cluster_idx": 2}, {"solution": "def list_tuple(input_list):\n \"\"\"\n Convert a list to a tuple.\n\n Args:\n input_list (list): The list to convert.\n\n Returns:\n tuple: The converted tuple.\n \"\"\"\n return tuple(input_list)", "matching_cluster_idx": 2}, {"solution": "def list_tuple(lst):\n \"\"\"\n Converts a list to a tuple.\n\n Args:\n lst (list): List to be converted.\n\n Returns:\n tuple: Converted tuple.\n \"\"\"\n return tuple(lst)", "matching_cluster_idx": 2}, {"solution": "def list_tuple(lst):\n \"\"\"\n Converts a list to a tuple.\n\n Parameters:\n lst (list): The input list to be converted.\n\n Returns:\n tuple: The tuple converted from the input list.\n \"\"\"\n return tuple(lst)", "matching_cluster_idx": 2}, {"solution": "def list_tuple(input_list):\n return tuple(input_list)", "matching_cluster_idx": 2}, {"solution": "def list_tuple(lst):\n \"\"\"\n Convert a list to a tuple.\n\n Parameters:\n lst (list): The input list to be converted to a tuple.\n\n Returns:\n tuple: The converted tuple.\n \"\"\"\n return tuple(lst)", "matching_cluster_idx": 2}, {"solution": "def list_tuple(lst):\n \"\"\"\n Convert a list to a tuple.\n\n Args:\n lst (list): A list of elements.\n\n Returns:\n tuple: A tuple with the elements of the list.\n \"\"\"\n return tuple(lst)", "matching_cluster_idx": 2}]}, "Mbpp/588": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 100.0, "profiled": [{"solution": "def big_diff(nums):\n if not nums:\n raise ValueError(\"The list is empty\")\n\n max_value = max(nums)\n min_value = min(nums)\n\n return max_value - min_value", "matching_cluster_idx": 5}, {"solution": "def big_diff(numbers):\n if not numbers:\n return 0\n largest = max(numbers)\n smallest = min(numbers)\n return largest - smallest", "matching_cluster_idx": 5}, {"solution": "def big_diff(arr):\n \"\"\"\n This function finds the difference between the largest and smallest value in a given list.\n\n Parameters:\n arr (list): A list of integers\n\n Returns:\n int: The difference between the largest and smallest value in the list\n \"\"\"\n if not arr:\n raise ValueError(\"The list is empty\")\n return max(arr) - min(arr)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n if not nums:\n raise ValueError(\"List is empty\")\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(lst):\n if not lst:\n raise ValueError(\"List is empty\")\n return max(lst) - min(lst)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n # Check if the list is empty\n if not nums:\n raise ValueError(\"The list is empty\")\n\n # Find the largest and smallest numbers in the list\n min_num = min(nums)\n max_num = max(nums)\n\n # Return the difference between the largest and smallest numbers\n return max_num - min_num", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n \"\"\"\n Find the difference between the largest and smallest value in a given list.\n\n Args:\n nums (list of int): List of integers\n\n Returns:\n int: Difference between the largest and smallest value in the list\n \"\"\"\n if not nums:\n raise ValueError(\"The input list is empty\")\n\n max_val = max(nums)\n min_val = min(nums)\n\n return max_val - min_val", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n if not nums:\n return 0\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(lst):\n if not lst:\n return 0\n return max(lst) - min(lst)", "matching_cluster_idx": 5}, {"solution": "def big_diff(numbers):\n \"\"\"\n Find the difference between the largest and smallest values in a given list.\n\n :param numbers: List[int] - A list of integers\n :return: int - The difference between the largest and smallest values\n \"\"\"\n if not numbers:\n raise ValueError(\"The list cannot be empty\")\n\n largest = max(numbers)\n smallest = min(numbers)\n\n return largest - smallest", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n if not nums:\n return 0\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(lst):\n if not lst: # Handle empty list case\n return 0\n return max(lst) - min(lst)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n \"\"\"\n Find the difference between the largest and smallest values in a given list.\n\n Parameters:\n nums (list of int): The list of integers.\n\n Returns:\n int: The difference between the largest and smallest values in the list.\n \"\"\"\n if not nums:\n raise ValueError(\"The list must not be empty\")\n\n largest = max(nums)\n smallest = min(nums)\n\n return largest - smallest", "matching_cluster_idx": 5}, {"solution": "def big_diff(lst):\n if not lst:\n raise ValueError(\"Input list should not be empty\")\n\n max_val = max(lst)\n min_val = min(lst)\n\n return max_val - min_val", "matching_cluster_idx": 5}, {"solution": "def big_diff(lst):\n if not lst:\n return 0\n largest = max(lst)\n smallest = min(lst)\n return largest - smallest", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n if not nums: # Check for empty list\n return 0\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n if not nums:\n raise ValueError(\"List should not be empty\")\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n if not nums:\n return 0\n return max(nums) - min(nums)", "matching_cluster_idx": 5}, {"solution": "def big_diff(arr):\n if not arr:\n return 0\n return max(arr) - min(arr)", "matching_cluster_idx": 5}, {"solution": "def big_diff(nums):\n if not nums:\n raise ValueError(\"The list is empty\")\n return max(nums) - min(nums)", "matching_cluster_idx": 5}]}, "Mbpp/592": {"dps": 60.66666666666667, "dps_norm": 51.0, "pass@1": 10.0, "profiled": [{"solution": "import math\ndef sum_Of_product(n):\n # Initialize the sum of products\n sum_prod = 0\n\n for i in range(n):\n # Product of binomial coefficients\n prod = math.comb(n, i) * math.comb(n, i+1)\n sum_prod += prod\n\n return sum_prod", "matching_cluster_idx": 5}, {"solution": "import math\ndef sum_Of_product(n):\n total_sum = 0\n for i in range(n):\n total_sum += math.comb(n, i) * math.comb(n, i+1)\n return total_sum", "matching_cluster_idx": 5}, {"solution": "import math\ndef binomial_coefficient(n, k):\n return math.comb(n, k)\ndef sum_Of_product(n):\n product_sum = 0\n for k in range(n):\n product_sum += binomial_coefficient(n, k) * binomial_coefficient(n, k + 1)\n return product_sum", "matching_cluster_idx": 4}, {"solution": "def sum_Of_product(n):\n \"\"\"\n Calculates the sum of the product of consecutive binomial coefficients for the given value of n.\n\n Parameters:\n n (int): The number of terms (binomial coefficients).\n\n Returns:\n int: The sum of the product of consecutive binomial coefficients.\n \"\"\"\n # Calculate binomial coefficients using the combination formula\n # C(n, k) = n! / (k! * (n - k)!)\n from math import comb\n\n sum_product = 0\n for k in range(n):\n sum_product += comb(n, k) * comb(n, k + 1)\n\n return sum_product", "matching_cluster_idx": 5}, {"solution": "from math import comb\ndef sum_Of_product(n):\n total = 0\n for i in range(n):\n total += comb(n, i) * comb(n, i+1)\n return total", "matching_cluster_idx": 5}, {"solution": "from math import comb\ndef sum_Of_product(n):\n product_sum = 0\n for i in range(n):\n product_sum += comb(n, i) * comb(n, i+1)\n return product_sum", "matching_cluster_idx": 5}, {"solution": "import math\ndef binomial_coefficient(n, k):\n return math.comb(n, k)\ndef sum_Of_product(n):\n total_sum = 0\n for k in range(1, n + 1):\n total_sum += binomial_coefficient(n, k - 1) * binomial_coefficient(n, k)\n return total_sum", "matching_cluster_idx": 4}, {"solution": "import math\ndef binomial_coeff(n, k):\n return math.comb(n, k)\ndef sum_Of_product(n):\n total_sum = 0\n for k in range(n):\n prod = binomial_coeff(n, k) * binomial_coeff(n, k + 1)\n total_sum += prod\n return total_sum", "matching_cluster_idx": 4}, {"solution": "def binomial_coefficient(n, k):\n \"\"\"\n Calculate the binomial coefficient C(n, k)\n \"\"\"\n if k > n:\n return 0\n numerator = 1\n denominator = 1\n for i in range(k):\n numerator *= (n - i)\n denominator *= (i + 1)\n return numerator // denominator\ndef sum_Of_product(n):\n \"\"\"\n Find the sum of the product of consecutive binomial coefficients\n \"\"\"\n sum_products = 0\n for k in range(n+1):\n sum_products += binomial_coefficient(n, k) * binomial_coefficient(n, k+1)\n return sum_products", "matching_cluster_idx": 0}, {"solution": "import math\ndef binomial_coeff(n, k):\n return math.comb(n, k)\ndef sum_Of_product(n):\n total = 0\n for i in range(n):\n total += binomial_coeff(n, i) * binomial_coeff(n, i + 1)\n return total", "matching_cluster_idx": 4}]}, "Mbpp/597": {"dps": null, "dps_norm": null, "pass@1": 8.0, "profiled": []}, "Mbpp/604": {"dps": 28.40909090909091, "dps_norm": 85.0, "pass@1": 87.0, "profiled": [{"solution": "def reverse_words(s):\n # Split the string into a list of words\n words = s.split()\n # Reverse the list of words\n reversed_words = words[::-1]\n # Join the reversed list of words into a single string\n return ' '.join(reversed_words)", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n # Split the input string into a list of words\n words = s.split()\n # Reverse the list of words\n reversed_words = words[::-1]\n # Join the reversed list back into a string\n return ' '.join(reversed_words)", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n # Split the input string by spaces to get a list of words\n words = s.split()\n # Reverse the list of words\n reversed_words = words[::-1]\n # Join the reversed list into a single string with spaces in between\n return ' '.join(reversed_words)", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n # Split the string by spaces to get individual words\n words = s.split()\n\n # Reverse the list of words\n reversed_words = words[::-1]\n\n # Join the reversed list back into a string with spaces\n reversed_string = ' '.join(reversed_words)\n\n return reversed_string", "matching_cluster_idx": 3}, {"solution": "def reverse_words(input_string):\n # Split the string into words\n words = input_string.split()\n\n # Reverse the order of the words\n reversed_words = words[::-1]\n\n # Join the reversed words back into a string\n reversed_string = ' '.join(reversed_words)\n\n return reversed_string", "matching_cluster_idx": 3}, {"solution": "def reverse_words(s):\n # Split the string into a list of words\n words = s.split()\n # Reverse the list of words\n reversed_words = words[::-1]\n # Join the reversed list of words back into a string\n return ' '.join(reversed_words)", "matching_cluster_idx": 3}, {"solution": "def reverse_words(s):\n return ' '.join(s.split()[::-1])", "matching_cluster_idx": 4}, {"solution": "def reverse_words(s):\n # Split the input string by spaces\n words = s.split()\n # Reverse the list of words\n words.reverse()\n # Join the reversed list of words back into a string\n return ' '.join(words)", "matching_cluster_idx": 3}, {"solution": "def reverse_words(s: str) -> str:\n # Split the string by spaces to get individual words\n words = s.split()\n # Reverse the list of words\n words.reverse()\n # Join the reversed words back into a string\n reversed_string = ' '.join(words)\n return reversed_string", "matching_cluster_idx": 3}, {"solution": "def reverse_words(s):\n # Split the string into a list of words\n words = s.split()\n # Reverse the list of words\n reversed_words = words[::-1]\n # Join the reversed list into a string\n return ' '.join(reversed_words)", "matching_cluster_idx": 4}, {"solution": "def reverse_words(input_string):\n \"\"\"\n This function takes a string with words separated by spaces and returns\n the string with words in reverse order.\n \"\"\"\n # Split the input string into a list of words\n words = input_string.split()\n # Reverse the list of words\n reversed_words = words[::-1]\n # Join the reversed list back into a string\n reversed_string = ' '.join(reversed_words)\n return reversed_string", "matching_cluster_idx": 3}, {"solution": "def reverse_words(s):\n # Split the string into words\n words = s.split()\n # Reverse the order of the words\n reversed_words = words[::-1]\n # Join the reversed words back into a single string\n return ' '.join(reversed_words)", "matching_cluster_idx": 3}, {"solution": "def reverse_words(s: str) -> str:\n # Split the string into words\n words = s.split()\n # Reverse the list of words\n reversed_words = words[::-1]\n # Join the reversed list back into a string\n return ' '.join(reversed_words)", "matching_cluster_idx": 3}, {"solution": "def reverse_words(s):\n \"\"\"\n Reverse the words in a given string.\n\n Args:\n s (str): The input string.\n\n Returns:\n str: The string with words reversed.\n \"\"\"\n # Split the string by spaces to get the words\n words = s.split()\n # Reverse the list of words\n reversed_words = words[::-1]\n # Join the reversed words back into a string with spaces in between\n return ' '.join(reversed_words)", "matching_cluster_idx": 3}, {"solution": "def reverse_words(s):\n # Split the input string into a list of words\n words = s.split()\n # Reverse the order of words in the list\n reversed_words = words[::-1]\n # Join the reversed list back into a string with spaces\n reversed_string = ' '.join(reversed_words)\n return reversed_string", "matching_cluster_idx": 3}, {"solution": "def reverse_words(input_string):\n # Split the string into words\n words = input_string.split()\n # Reverse the order of words\n reversed_words = words[::-1]\n # Join the reversed list of words into a single string\n reversed_string = ' '.join(reversed_words)\n return reversed_string", "matching_cluster_idx": 3}, {"solution": "def reverse_words(s):\n # Split the string into a list of words\n words = s.split()\n # Reverse the list of words\n reversed_words = words[::-1]\n # Join the reversed list into a string with spaces in between\n return ' '.join(reversed_words)", "matching_cluster_idx": 3}, {"solution": "def reverse_words(s):\n # Split the string into words\n words = s.split()\n # Reverse the list of words\n reversed_words = words[::-1]\n # Join the reversed list into a string\n reversed_string = ' '.join(reversed_words)\n return reversed_string", "matching_cluster_idx": 3}, {"solution": "def reverse_words(s: str) -> str:\n # Split the string into words\n words = s.split()\n # Reverse the list of words\n reversed_words = words[::-1]\n # Join the reversed list of words back into a string\n return ' '.join(reversed_words)", "matching_cluster_idx": 3}, {"solution": "def reverse_words(s: str) -> str:\n # Split the string by spaces\n words = s.split()\n # Reverse the list of words\n reversed_words = words[::-1]\n # Join the reversed list back into a string\n return ' '.join(reversed_words)", "matching_cluster_idx": 3}]}, "Mbpp/610": {"dps": null, "dps_norm": null, "pass@1": 1.0, "profiled": []}, "Mbpp/611": {"dps": 90.3680981595092, "dps_norm": 96.66666666666667, "pass@1": 33.0, "profiled": [{"solution": "def max_of_nth(matrix, n):\n \"\"\"\n Given a matrix represented as a list of lists, return the maximum value in the n'th column.\n\n Args:\n matrix (list of lists): The input matrix.\n n (int): The column index to find the maximum value in.\n\n Returns:\n int: The maximum value in the n'th column.\n \"\"\"\n # Ensure that the column index is valid\n if not all(len(row) > n for row in matrix):\n raise ValueError(\"The column index n is out of range.\")\n\n # Initialize the maximum value\n max_value = float('-inf')\n\n # Iterate through each row in the matrix\n for row in matrix:\n # Update the maximum value if the current element is greater\n if row[n] > max_value:\n max_value = row[n]\n\n return max_value", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n # Check if the matrix is empty or column index is out of bounds\n if not matrix or n >= len(matrix[0]):\n raise ValueError(\"Invalid matrix or column index\")\n\n # Initialize max_value to negative infinity\n max_value = float('-inf')\n\n # Iterate through each row in the matrix\n for row in matrix:\n # Update max_value if current row element at column n is greater\n if row[n] > max_value:\n max_value = row[n]\n\n return max_value", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n # Initialize the maximum value\n max_value = float('-inf')\n\n # Iterate through each row in the matrix\n for row in matrix:\n # Update the maximum value if the current element is larger\n if row[n] > max_value:\n max_value = row[n]\n\n return max_value", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n \"\"\"\n Function to return the maximum value in the n'th column of the given matrix.\n\n :param matrix: List of lists representing the matrix\n :param n: Column index (0-based)\n :return: Maximum value in the n'th column\n \"\"\"\n # Check if the matrix is not empty and has at least n columns\n if not matrix or any(len(row) <= n for row in matrix):\n raise ValueError(\"Invalid matrix or column index\")\n\n # Extract the n'th column and find the maximum value\n nth_column = [row[n] for row in matrix]\n return max(nth_column)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n # Extract the n-th column from the matrix\n nth_column = [row[n] for row in matrix]\n # Return the maximum value in the n-th column\n return max(nth_column)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n \"\"\"\n Given a matrix represented as a list of lists, return the max value of the n'th column.\n\n :param matrix: List of lists representing the matrix.\n :param n: Column index to find the maximum value in.\n :return: Maximum value in the n'th column.\n \"\"\"\n # Edge case: if n is out of bounds\n if n >= len(matrix[0]):\n return None # Assuming return None if n is out of range\n\n max_value = float('-inf')\n for row in matrix:\n if row[n] > max_value:\n max_value = row[n]\n\n return max_value", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n \"\"\"\n This function returns the maximum value in the n'th column of the given matrix.\n\n Parameters:\n matrix (list of lists): The input matrix.\n n (int): The column index (0-based).\n\n Returns:\n int: The maximum value in the n'th column.\n \"\"\"\n # Edge case check: if the matrix is empty or has fewer than n rows, or n is out of range.\n if not matrix or len(matrix[0]) <= n:\n return None\n\n max_value = float('-inf')\n for row in matrix:\n if row[n] > max_value:\n max_value = row[n]\n return max_value", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n # Ensure that the matrix has at least n+1 rows and n columns\n if not matrix or not all(isinstance(row, list) for row in matrix) or any(len(row) < n for row in matrix):\n raise ValueError(\"Invalid matrix or n out of bounds\")\n\n # Extract the n'th column from the matrix\n nth_column = [row[n] for row in matrix]\n\n # Return the maximum value in the n'th column\n return max(nth_column)", "matching_cluster_idx": 3}, {"solution": "def max_of_nth(matrix, n):\n \"\"\"\n This function returns the maximum value in the n'th column of the matrix.\n\n :param matrix: List of lists representing the matrix\n :param n: The column index (0-based)\n :return: Maximum value in the n'th column\n \"\"\"\n if not matrix or n >= len(matrix[0]):\n return None\n\n max_value = float('-inf')\n for row in matrix:\n if row[n] > max_value:\n max_value = row[n]\n\n return max_value", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n if not matrix or not matrix[0]:\n return None\n\n # Use the `key` argument in the `max` function to get the max of the nth column\n return max(row[n] for row in matrix)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n \"\"\"\n Given a matrix represented as a list of lists, return the maximum value in the n'th column.\n\n :param matrix: List of lists, representing the matrix.\n :param n: Column index (0-based).\n :return: Maximum value in the n'th column.\n \"\"\"\n if not matrix or n >= len(matrix[0]):\n raise ValueError(\"Invalid matrix or column index.\")\n\n return max(row[n] for row in matrix)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n if not matrix or not matrix[0]:\n raise ValueError(\"Matrix must not be empty\")\n if n >= len(matrix[0]):\n raise IndexError(\"n is out of bounds of columns in the matrix\")\n\n column_n = [row[n] for row in matrix]\n return max(column_n)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n \"\"\"\n Given a matrix represented as a list of lists, return the max of the n'th column.\n\n :param matrix: List of lists (2D matrix)\n :param n: The column index (0-based)\n :return: The maximum value in the n'th column\n \"\"\"\n if not matrix or n >= len(matrix[0]):\n raise ValueError(\"Invalid matrix or column index\")\n\n max_value = float('-inf')\n for row in matrix:\n if row[n] > max_value:\n max_value = row[n]\n\n return max_value", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n # Ensure the column exists\n if n >= len(matrix[0]):\n raise ValueError(\"The column index is out of bounds\")\n\n # Initialize the maximum value\n max_value = float('-inf')\n\n # Iterate over each row in the matrix\n for row in matrix:\n # Check the nth element of each row\n if row[n] > max_value:\n max_value = row[n]\n\n return max_value", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n # Initialize max value with the smallest possible integer\n max_value = float('-inf')\n\n # Iterate through each row in the matrix\n for row in matrix:\n # Check if the current row has enough columns\n if len(row) > n:\n # Update max_value if the current element is greater\n max_value = max(max_value, row[n])\n\n return max_value", "matching_cluster_idx": 3}, {"solution": "def max_of_nth(matrix, n):\n if not matrix or not matrix[0]:\n raise ValueError(\"Input matrix is empty or has no columns\")\n\n return max(row[n] for row in matrix)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n \"\"\"\n Returns the maximum value in the n'th column of the given matrix.\n\n Parameters:\n matrix (list of lists): The matrix to search within.\n n (int): The column index to find the maximum value in (0-indexed).\n\n Returns:\n int: The maximum value in the specified column.\n \"\"\"\n # Check if the matrix is not empty and n is within the range of columns\n if not matrix or n >= len(matrix[0]):\n return None\n\n # Initialize max value with the first element of the n'th column\n max_value = matrix[0][n]\n\n # Iterate over each row starting from the second row\n for row in matrix[1:]:\n # Update max_value if the current element is greater\n if row[n] > max_value:\n max_value = row[n]\n\n return max_value", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n # Initialize max value with the first element of the n-th column\n max_value = matrix[0][n]\n\n # Iterate through each row of the matrix\n for row in matrix:\n # Check if the current element in the n-th column is greater than the current max value\n if row[n] > max_value:\n # Update the max value\n max_value = row[n]\n\n return max_value", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n if not matrix or not matrix[0]:\n raise ValueError(\"Matrix or its first row is empty\")\n\n nth_column = [row[n] for row in matrix]\n return max(nth_column)", "matching_cluster_idx": 5}, {"solution": "def max_of_nth(matrix, n):\n \"\"\"\n Given a matrix represented as a list of lists, return the maximum value in the n'th column.\n\n :param matrix: List of lists representing the matrix.\n :param n: Column index (0-based).\n :return: The maximum value in the n'th column.\n \"\"\"\n if not matrix or not matrix[0]:\n raise ValueError(\"Matrix is empty or has no rows\")\n\n # Check if n is within the range of columns in the matrix\n if n >= len(matrix[0]):\n raise ValueError(\"Column index is out of range\")\n\n # Initialize max_value to a very small number\n max_value = float('-inf')\n\n # Iterate through each row in the matrix\n for row in matrix:\n # Update max_value if current element in n'th column is greater\n if row[n] > max_value:\n max_value = row[n]\n\n return max_value", "matching_cluster_idx": 5}]}, "Mbpp/631": {"dps": 51.7361111111111, "dps_norm": 55.625, "pass@1": 20.0, "profiled": [{"solution": "def replace_spaces(input_string):\n result = ''\n for char in input_string:\n if char == ' ':\n result += '_'\n elif char == '_':\n result += ' '\n else:\n result += char\n return result", "matching_cluster_idx": 2}, {"solution": "def replace_spaces(s):\n # Create a translation table to replace whitespaces with underscores and vice versa\n translation_table = str.maketrans(\" _\", \"_ \")\n # Use the translate method to apply the translation table\n return s.translate(translation_table)", "matching_cluster_idx": 6}, {"solution": "def replace_spaces(input_string):\n # Create a new string with underscores replacing spaces and vice versa\n result = \"\"\n for char in input_string:\n if char == ' ':\n result += '_'\n elif char == '_':\n result += ' '\n else:\n result += char\n return result", "matching_cluster_idx": 2}, {"solution": "def replace_spaces(s: str) -> str:\n # Initialize an empty string to store the result\n result = \"\"\n\n # Iterate over each character in the input string\n for char in s:\n # Replace whitespace with underscore and vice versa\n if char == ' ':\n result += '_'\n elif char == '_':\n result += ' '\n else:\n result += char\n\n return result", "matching_cluster_idx": 2}, {"solution": "def replace_spaces(s: str) -> str:\n \"\"\"\n Replace whitespaces with underscores and vice versa in a given string.\n \"\"\"\n # Create a translation table to swap spaces and underscores\n translation_table = str.maketrans(' _', '_ ')\n # Use the translate method to perform the replacement\n return s.translate(translation_table)", "matching_cluster_idx": 6}, {"solution": "def replace_spaces(s: str) -> str:\n result = []\n for char in s:\n if char == ' ':\n result.append('_')\n elif char == '_':\n result.append(' ')\n else:\n result.append(char)\n return ''.join(result)", "matching_cluster_idx": 3}, {"solution": "def replace_spaces(s):\n \"\"\"\n Replace spaces with underscores and vice versa in the given string.\n\n Parameters:\n s (str): The input string.\n\n Returns:\n str: The string with spaces and underscores swapped.\n \"\"\"\n result = []\n for char in s:\n if char == ' ':\n result.append('_')\n elif char == '_':\n result.append(' ')\n else:\n result.append(char)\n return ''.join(result)", "matching_cluster_idx": 3}, {"solution": "def replace_spaces(s: str) -> str:\n # Replace spaces with underscores and vice versa\n result = []\n for char in s:\n if char == ' ':\n result.append('_')\n elif char == '_':\n result.append(' ')\n else:\n result.append(char)\n return ''.join(result)", "matching_cluster_idx": 3}, {"solution": "def replace_spaces(input_string: str) -> str:\n result = ''\n for char in input_string:\n if char == ' ':\n result += '_'\n elif char == '_':\n result += ' '\n else:\n result += char\n return result", "matching_cluster_idx": 2}, {"solution": "def replace_spaces(s: str) -> str:\n \"\"\"Replaces whitespaces with underscores and underscores with whitespaces in a given string.\"\"\"\n # Create a translation table that maps spaces to underscores and vice versa\n translation_table = str.maketrans(' _', '_ ')\n # Use the translate method to apply the translation table to the input string\n return s.translate(translation_table)", "matching_cluster_idx": 6}, {"solution": "def replace_spaces(s):\n \"\"\"\n Replaces whitespaces with an underscore and vice versa in a given string.\n \"\"\"\n result = []\n for char in s:\n if char == ' ':\n result.append('_')\n elif char == '_':\n result.append(' ')\n else:\n result.append(char)\n return ''.join(result)", "matching_cluster_idx": 3}, {"solution": "def replace_spaces(s):\n result = []\n for char in s:\n if char == ' ':\n result.append('_')\n elif char == '_':\n result.append(' ')\n else:\n result.append(char)\n return ''.join(result)", "matching_cluster_idx": 3}, {"solution": "def replace_spaces(input_string):\n # Create an empty result string\n result = ''\n # Iterate through each character in the input string\n for char in input_string:\n # Replace spaces with underscores and underscores with spaces\n if char == ' ':\n result += '_'\n elif char == '_':\n result += ' '\n else:\n result += char\n return result", "matching_cluster_idx": 2}, {"solution": "def replace_spaces(input_string):\n \"\"\"\n Replace whitespaces with underscores and vice versa in a given string.\n \"\"\"\n result = []\n for char in input_string:\n if char == ' ':\n result.append('_')\n elif char == '_':\n result.append(' ')\n else:\n result.append(char)\n return ''.join(result)", "matching_cluster_idx": 3}, {"solution": "def replace_spaces(s):\n result = []\n for char in s:\n if char == ' ':\n result.append('_')\n elif char == '_':\n result.append(' ')\n else:\n result.append(char)\n return ''.join(result)", "matching_cluster_idx": 3}, {"solution": "def replace_spaces(s):\n # Initialize an empty string to store the result\n result = \"\"\n\n # Iterate over each character in the input string\n for char in s:\n # Check if the character is a space\n if char == ' ':\n # Replace space with underscore\n result += '_'\n elif char == '_':\n # Replace underscore with space\n result += ' '\n else:\n # Keep the character as it is\n result += char\n\n return result", "matching_cluster_idx": 2}, {"solution": "def replace_spaces(s):\n # Use translate with a translation table to replace spaces with underscores and vice versa\n translation_table = str.maketrans(' _', '_ ')\n return s.translate(translation_table)", "matching_cluster_idx": 6}, {"solution": "def replace_spaces(s: str) -> str:\n # Define a translation table to replace whitespaces with underscores and vice versa\n table = str.maketrans(' _', '_ ')\n # Use the translate method to apply the table to the input string\n return s.translate(table)", "matching_cluster_idx": 6}, {"solution": "def replace_spaces(s):\n result = []\n for char in s:\n if char == ' ':\n result.append('_')\n elif char == '_':\n result.append(' ')\n else:\n result.append(char)\n return ''.join(result)", "matching_cluster_idx": 3}, {"solution": "def replace_spaces(s):\n # Iterate over each character in the string\n result = []\n for char in s:\n if char == ' ':\n result.append('_')\n elif char == '_':\n result.append(' ')\n else:\n result.append(char)\n # Join the list into a string\n return ''.join(result)", "matching_cluster_idx": 3}]}, "Mbpp/632": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 76.0, "profiled": [{"solution": "def move_zero(lst):\n # Separate the non-zero and zero elements\n non_zeros = [num for num in lst if num != 0]\n zeros = [num for num in lst if num == 0]\n # Combine them to form the final list\n return non_zeros + zeros", "matching_cluster_idx": 6}, {"solution": "def move_zero(lst):\n non_zero_elements = [num for num in lst if num != 0]\n return non_zero_elements + [0] * (len(lst) - len(non_zero_elements))", "matching_cluster_idx": 6}, {"solution": "def move_zero(lst):\n \"\"\"\n Moves all zeroes to the end of the given list.\n\n :param lst: List of integers.\n :return: List with all zeroes moved to the end.\n \"\"\"\n # List comprehension to filter out zeroes first\n non_zero_elements = [num for num in lst if num != 0]\n # Extend the list with the remaining zeroes\n non_zero_elements.extend([num for num in lst if num == 0])\n return non_zero_elements", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n \"\"\"\n Moves all zeroes to the end of the given list while preserving the order of non-zero elements.\n\n Parameters:\n nums (list): List of integers\n\n Returns:\n list: List with zeroes moved to the end\n \"\"\"\n # Filter out zeroes from the list\n non_zeroes = [num for num in nums if num != 0]\n # Calculate the number of zeroes\n num_zeros = len(nums) - len(non_zeroes)\n # Append the remaining zeroes to the end of the list\n non_zeroes.extend([0] * num_zeros)\n return non_zeroes", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n # Separate the non-zero and zero elements\n non_zero_elements = [num for num in nums if num != 0]\n zero_elements = [0] * (len(nums) - len(non_zero_elements))\n\n # Combine the non-zero elements followed by the zero elements\n return non_zero_elements + zero_elements", "matching_cluster_idx": 6}, {"solution": "def move_zero(arr):\n # Initialize a pointer to keep track of non-zero elements\n non_zero_index = 0\n\n # Iterate through the array\n for i in range(len(arr)):\n # If the current element is not zero, place it at the non_zero_index position\n if arr[i] != 0:\n arr[non_zero_index] = arr[i]\n # Increment the non-zero index\n non_zero_index += 1\n\n # Fill the remaining positions with zeroes\n for j in range(non_zero_index, len(arr)):\n arr[j] = 0\n\n return arr", "matching_cluster_idx": 6}, {"solution": "def move_zero(lst):\n \"\"\"\n Moves all zeroes to the end of the given list.\n\n Parameters:\n lst (list): The list of integers.\n\n Returns:\n list: The list with zeroes moved to the end.\n \"\"\"\n # Filter out non-zero elements and append remaining zeroes\n result = [num for num in lst if num != 0] + [0] * lst.count(0)\n return result", "matching_cluster_idx": 6}, {"solution": "def move_zero(arr):\n \"\"\"\n Move all zeroes to the end of the given list.\n\n Args:\n arr (list): The list of integers.\n\n Returns:\n list: A new list with zeroes moved to the end.\n \"\"\"\n # Filter non-zero elements and extend the list with remaining zeroes\n return [num for num in arr if num != 0] + [0] * arr.count(0)", "matching_cluster_idx": 6}, {"solution": "def move_zero(lst):\n # Separate non-zero elements and zero elements\n non_zero = [num for num in lst if num != 0]\n zero = [num for num in lst if num == 0]\n\n # Concatenate non-zero and zero elements\n return non_zero + zero", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n # Separate the non-zero elements and zeroes\n non_zero = [num for num in nums if num != 0]\n zeroes = [num for num in nums if num == 0]\n\n # Concatenate the lists\n return non_zero + zeroes", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n # Separate the non-zero and zero elements\n non_zero_elements = [num for num in nums if num != 0]\n zero_elements = [num for num in nums if num == 0]\n\n # Combine them to form the final list\n return non_zero_elements + zero_elements", "matching_cluster_idx": 6}, {"solution": "def move_zero(lst):\n # Separate the non-zero elements and zero elements\n non_zeros = [num for num in lst if num != 0]\n zeros = [num for num in lst if num == 0]\n\n # Combine the non-zero elements and zero elements\n result = non_zeros + zeros\n\n return result", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n # Filter out non-zero elements and then extend with zeroes\n return [num for num in nums if num != 0] + [0] * nums.count(0)", "matching_cluster_idx": 6}, {"solution": "def move_zero(arr):\n # This function moves all zeroes to the end of the list while maintaining the relative order of the other elements.\n # It uses two pointers technique.\n\n # Initial pointer for the position where the next non-zero element should be placed\n non_zero_pos = 0\n\n # Traverse the array, for each non-zero element, place it at the non_zero_pos and increment the pointer\n for element in arr:\n if element != 0:\n arr[non_zero_pos] = element\n non_zero_pos += 1\n\n # All the elements from non_zero_pos to the end of the array are set to zero\n for i in range(non_zero_pos, len(arr)):\n arr[i] = 0\n\n return arr", "matching_cluster_idx": 6}, {"solution": "def move_zero(lst):\n # Filter out zeros and count them\n non_zero_elements = [num for num in lst if num != 0]\n zero_count = lst.count(0)\n\n # Create a new list with non-zero elements followed by zeros\n result = non_zero_elements + [0] * zero_count\n\n return result", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n # This will keep track of the position where the next non-zero element should be placed\n position = 0\n\n for num in nums:\n if num != 0:\n nums[position] = num\n position += 1\n\n # Fill the remaining elements with zero\n for i in range(position, len(nums)):\n nums[i] = 0\n\n return nums", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n # Create a list to store non-zero elements\n non_zero_elements = [num for num in nums if num != 0]\n # Fill the rest with zeroes\n nums[:] = non_zero_elements + [0] * (len(nums) - len(non_zero_elements))\n return nums", "matching_cluster_idx": 6}, {"solution": "def move_zero(nums):\n # Separate the non-zero elements and zero elements\n non_zero_elements = [num for num in nums if num != 0]\n zero_count = nums.count(0)\n\n # Extend the list of non-zero elements with zeros\n return non_zero_elements + [0] * zero_count", "matching_cluster_idx": 6}, {"solution": "def move_zero(lst):\n # Separate list into non-zero and zero elements\n non_zero_elements = [x for x in lst if x != 0]\n zero_elements = [x for x in lst if x == 0]\n # Combine the lists\n return non_zero_elements + zero_elements", "matching_cluster_idx": 6}, {"solution": "def move_zero(arr):\n # Initialize a pointer for the position to place non-zero elements\n non_zero_position = 0\n\n # Iterate over the array\n for i in range(len(arr)):\n if arr[i] != 0:\n # Swap the current element with the element at non_zero_position\n arr[non_zero_position], arr[i] = arr[i], arr[non_zero_position]\n # Increment the non_zero_position pointer\n non_zero_position += 1\n\n return arr", "matching_cluster_idx": 6}]}, "Mbpp/633": {"dps": null, "dps_norm": null, "pass@1": 4.0, "profiled": []}, "Mbpp/644": {"dps": 88.11170212765956, "dps_norm": 89.33333333333333, "pass@1": 59.0, "profiled": [{"solution": "def reverse_Array_Upto_K(arr, k):\n # Validate k\n if k <= 0 or k > len(arr):\n raise ValueError(\"k should be in the range (0, len(arr)]\")\n\n # Reverse the portion of the array up to k\n arr[:k] = arr[:k][::-1]\n\n return arr", "matching_cluster_idx": 13}, {"solution": "def reverse_Array_Upto_K(arr, k):\n # Reverse the first k elements of the array\n arr[:k] = reversed(arr[:k])\n return arr", "matching_cluster_idx": 12}, {"solution": "def reverse_Array_Upto_K(arr, k):\n if k < 0:\n return arr\n arr[:k] = arr[:k][::-1]\n return arr", "matching_cluster_idx": 13}, {"solution": "def reverse_Array_Upto_K(arr, k):\n # Reverse the first 'k' elements\n arr[:k] = reversed(arr[:k])\n return arr", "matching_cluster_idx": 12}, {"solution": "def reverse_Array_Upto_K(arr, k):\n # Reverse the first k elements of the array\n arr[:k] = reversed(arr[:k])\n return arr", "matching_cluster_idx": 12}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n Reverses the elements of the array up to the given position k.\n\n :param arr: List of elements to be reversed.\n :param k: Position up to which the array should be reversed.\n :return: List with elements reversed up to position k.\n \"\"\"\n # Reverse the first k elements\n arr[:k] = reversed(arr[:k])\n return arr", "matching_cluster_idx": 12}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n Reverse the elements of the array up to the given position k.\n\n :param arr: List of elements to be reversed\n :param k: Position up to which elements should be reversed\n :return: Reversed array up to the given position\n \"\"\"\n # Reverse the elements up to the position k\n arr[:k] = arr[:k][::-1]\n return arr", "matching_cluster_idx": 13}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n This function reverses the given array up to the given position k.\n\n Parameters:\n arr (list): The list to be reversed.\n k (int): The position up to which the list should be reversed.\n\n Returns:\n list: The modified list with elements up to position k reversed.\n \"\"\"\n return arr[:k][::-1] + arr[k:]", "matching_cluster_idx": 10}, {"solution": "def reverse_Array_Upto_K(arr, k):\n # Reverse the first k elements\n arr[:k] = arr[:k][::-1]\n return arr", "matching_cluster_idx": 13}, {"solution": "def reverse_Array_Upto_K(arr, k):\n \"\"\"\n Reverses the elements of the array up to position k.\n\n Parameters:\n arr (list): The list to be reversed.\n k (int): The position up to which the array should be reversed.\n\n Returns:\n list: The modified list.\n \"\"\"\n # Ensure k is within the bounds of the array\n if k <= 0 or k > len(arr):\n return arr\n\n # Reverse the elements up to the k-th position\n arr[:k] = reversed(arr[:k])\n return arr", "matching_cluster_idx": 11}, {"solution": "def reverse_Array_Upto_K(arr, k):\n # Reverse the first 'k' elements\n arr[:k] = reversed(arr[:k])\n return arr", "matching_cluster_idx": 12}, {"solution": "def reverse_Array_Upto_K(arr, k):\n # Reverse the first k elements of the array\n arr[:k] = arr[:k][::-1]\n return arr", "matching_cluster_idx": 13}, {"solution": "def reverse_Array_Upto_K(arr, k):\n # Reverse the first k elements\n arr[:k] = arr[:k][::-1]\n return arr", "matching_cluster_idx": 13}, {"solution": "def reverse_Array_Upto_K(arr, k):\n # Reverse the first k elements of the array\n arr[:k] = reversed(arr[:k])\n return arr", "matching_cluster_idx": 12}, {"solution": "def reverse_Array_Upto_K(arr, k):\n # Reverse the first k elements\n arr[:k] = reversed(arr[:k])\n return arr", "matching_cluster_idx": 12}, {"solution": "def reverse_Array_Upto_K(arr, k):\n # Reverse the first k elements of the array\n arr[:k] = arr[:k][::-1]\n return arr", "matching_cluster_idx": 13}, {"solution": "def reverse_Array_Upto_K(arr, k):\n # Reverse the first k elements of the array\n arr[:k] = arr[:k][::-1]\n return arr", "matching_cluster_idx": 13}, {"solution": "def reverse_Array_Upto_K(arr, k):\n # Reverse the subarray from the start up to the k-th element\n arr[:k] = arr[:k][::-1]\n return arr", "matching_cluster_idx": 13}, {"solution": "def reverse_Array_Upto_K(arr, k):\n # Reverse the first k elements of the array\n arr[:k] = arr[:k][::-1]\n return arr", "matching_cluster_idx": 13}, {"solution": "def reverse_Array_Upto_K(arr, k):\n # Reverse the first k elements of the array\n arr[:k] = arr[:k][::-1]\n return arr", "matching_cluster_idx": 13}]}, "Mbpp/720": {"dps": 100.0, "dps_norm": 100.0, "pass@1": 97.0, "profiled": [{"solution": "def add_dict_to_tuple(t, d):\n \"\"\"\n Adds a dictionary to a tuple and returns the resulting tuple.\n\n Parameters:\n t (tuple): The input tuple.\n d (dict): The dictionary to add to the tuple.\n\n Returns:\n tuple: A new tuple with the dictionary appended.\n \"\"\"\n return t + (d,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(input_tuple, dictionary):\n return input_tuple + (dictionary,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(existing_tuple, dictionary):\n # Convert dictionary to tuple and append to existing tuple\n new_tuple = existing_tuple + (dictionary,)\n return new_tuple", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(tup, d):\n return tup + (d,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(t, d):\n \"\"\"\n Add a dictionary to the tuple and return the new tuple.\n\n Parameters:\n t (tuple): The original tuple.\n d (dict): The dictionary to add to the tuple.\n\n Returns:\n tuple: The new tuple with the dictionary appended.\n \"\"\"\n return t + (d,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(original_tuple, new_dict):\n \"\"\"\n This function takes a tuple and a dictionary as input, and returns a new tuple with the dictionary appended to the end.\n\n Parameters:\n original_tuple (tuple): The original tuple.\n new_dict (dict): The dictionary to be added to the tuple.\n\n Returns:\n tuple: A new tuple with the dictionary appended.\n \"\"\"\n return original_tuple + (new_dict,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(input_tuple, input_dict):\n \"\"\"\n Adds a dictionary to a tuple and returns the new tuple.\n\n Args:\n input_tuple (tuple): The original tuple.\n input_dict (dict): The dictionary to be added to the tuple.\n\n Returns:\n tuple: The new tuple containing the original tuple elements and the dictionary.\n \"\"\"\n return input_tuple + (input_dict,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(tup, dct):\n \"\"\"\n Adds a dictionary to a tuple and returns a new tuple.\n\n Parameters:\n tup (tuple): The original tuple.\n dct (dict): The dictionary to be added.\n\n Returns:\n tuple: A new tuple with the dictionary added.\n \"\"\"\n return tup + (dct,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(t, d):\n \"\"\"\n Adds a dictionary to a tuple.\n\n Parameters:\n t (tuple): The original tuple.\n d (dict): The dictionary to be added.\n\n Returns:\n tuple: A new tuple with the dictionary appended.\n \"\"\"\n return t + (d,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(input_tuple, dictionary):\n # Convert the dictionary to a tuple\n dict_as_tuple = (dictionary,)\n # Add the dictionary as a tuple to the original tuple\n new_tuple = input_tuple + dict_as_tuple\n return new_tuple", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(tup, dct):\n # Add the dictionary to the end of the tuple\n new_tup = tup + (dct,)\n return new_tup", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(t, d):\n return t + (d,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(tup, dct):\n \"\"\"\n Adds a dictionary to a tuple and returns the resulting tuple.\n\n Parameters:\n tup (tuple): The original tuple.\n dct (dict): The dictionary to be added to the tuple.\n\n Returns:\n tuple: A new tuple containing the elements of the original tuple followed by the dictionary.\n \"\"\"\n return tup + (dct,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(input_tuple, input_dict):\n # Convert the dictionary to a tuple and add it to the original tuple\n new_tuple = input_tuple + (input_dict,)\n return new_tuple", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(original_tuple, dictionary):\n # Convert the dictionary to a tuple and add it to the end of the original tuple\n new_tuple = original_tuple + (dictionary,)\n return new_tuple", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(t, d):\n \"\"\"\n Adds a dictionary to the tuple.\n\n Parameters:\n t (tuple): The original tuple.\n d (dict): The dictionary to be added to the tuple.\n\n Returns:\n tuple: A new tuple with the dictionary appended.\n \"\"\"\n return t + (d,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(input_tuple, input_dict):\n \"\"\"\n Adds a dictionary to a tuple and returns the result as a new tuple.\n\n Args:\n input_tuple (tuple): The original tuple.\n input_dict (dict): The dictionary to add to the tuple.\n\n Returns:\n tuple: A new tuple containing the original elements and the dictionary.\n \"\"\"\n # Convert the dictionary to a tuple and add it to the original tuple\n new_tuple = input_tuple + (input_dict,)\n return new_tuple", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(existing_tuple, new_dict):\n # Add the dictionary to the tuple\n return existing_tuple + (new_dict,)", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(tup, dic):\n # Convert dictionary to tuple element\n tup += (dic,)\n return tup", "matching_cluster_idx": 4}, {"solution": "def add_dict_to_tuple(tup, dct):\n \"\"\"\n Add a dictionary to the tuple.\n\n Parameters:\n tup (tuple): The original tuple.\n dct (dict): The dictionary to add.\n\n Returns:\n tuple: A new tuple with the dictionary added.\n \"\"\"\n return tup + (dct,)", "matching_cluster_idx": 4}]}, "Mbpp/725": {"dps": 58.79781420765027, "dps_norm": 68.125, "pass@1": 92.0, "profiled": [{"solution": "import re\ndef extract_quotation(s):\n # Use regular expressions to find all substrings between double quotes\n return re.findall(r'\"([^\"]*)\"', s)", "matching_cluster_idx": 6}, {"solution": "import re\ndef extract_quotation(s: str) -> list:\n # Use regular expression to find all substrings within double quotes\n return re.findall(r'\"(.*?)\"', s)", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(string):\n # Use regular expression to find all matches between quotation marks\n matches = re.findall(r'\"(.*?)\"', string)\n return matches", "matching_cluster_idx": 4}, {"solution": "import re\ndef extract_quotation(s):\n # Use regex to find all substrings between quotes\n return re.findall(r'\\\"(.*?)\\\"', s)", "matching_cluster_idx": 4}, {"solution": "import re\ndef extract_quotation(s):\n # Use regular expression to find all substrings between quotes\n return re.findall(r'\"([^\"]*)\"', s)", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(input_string):\n # Use regular expressions to find all substrings between quotes\n matches = re.findall(r'\"(.*?)\"', input_string)\n return matches", "matching_cluster_idx": 4}, {"solution": "import re\ndef extract_quotation(s):\n \"\"\"\n Extract values between quotation marks \" \" of the given string.\n\n Parameters:\n s (str): The input string to extract quotes from.\n\n Returns:\n list: A list of strings that are between quotation marks.\n \"\"\"\n # Use regex to find all substrings that are enclosed within double quotes\n matches = re.findall(r'\"([^\"]*)\"', s)\n return matches", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(s):\n # Use regular expression to find all substrings between quotes\n return re.findall(r'\\\"(.*?)\\\"', s)", "matching_cluster_idx": 4}, {"solution": "import re\ndef extract_quotation(input_string):\n # Using regex to find all substrings enclosed within quotes\n quoted_strings = re.findall(r'\\\"(.*?)\\\"', input_string)\n return quoted_strings", "matching_cluster_idx": 4}, {"solution": "import re\ndef extract_quotation(s: str) -> list:\n # Use regular expression to find all substrings enclosed in quotation marks\n pattern = r'\"([^\"]*)\"'\n return re.findall(pattern, s)", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(s):\n # Using regex to find all words within quotation marks\n pattern = re.compile(r'\"(.*?)\"')\n return [match.group(1) for match in pattern.finditer(s)]", "matching_cluster_idx": 4}, {"solution": "import re\ndef extract_quotation(s):\n pattern = r'\"(.*?)\"'\n return re.findall(pattern, s)", "matching_cluster_idx": 4}, {"solution": "import re\ndef extract_quotation(s: str) -> list:\n # Use regex to find all substrings between quotation marks\n return re.findall(r'\\\"(.*?)\\\"', s)", "matching_cluster_idx": 4}, {"solution": "import re\ndef extract_quotation(string):\n # Use regular expression to find all substrings enclosed in double quotes\n return re.findall(r'\"([^\"]*)\"', string)", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(text):\n # Use regex to find all substrings between double quotes\n matches = re.findall(r'\"(.*?)\"', text)\n return matches", "matching_cluster_idx": 4}, {"solution": "import re\ndef extract_quotation(s):\n # Use regular expression to find all substrings enclosed in double quotes\n return re.findall(r'\"(.*?)\"', s)", "matching_cluster_idx": 4}, {"solution": "def extract_quotation(text):\n import re\n\n # Use regular expression to find all substrings between quotes\n matches = re.findall(r'\".*?\"', text)\n\n # Remove quotes from the matched substrings\n values = [match.strip('\"') for match in matches]\n\n return values", "matching_cluster_idx": 4}, {"solution": "import re\ndef extract_quotation(s):\n # Use regular expression to find all substrings between double quotation marks\n matches = re.findall(r'\"([^\"]*)\"', s)\n return matches", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(s):\n # Use regular expressions to find all substrings enclosed in double quotation marks\n return re.findall(r'\"([^\"]*)\"', s)", "matching_cluster_idx": 5}, {"solution": "import re\ndef extract_quotation(s):\n # Define a regular expression pattern to find text between quotes\n pattern = r'\"(.*?)\"'\n # Use re.findall to find all matches of the pattern in the input string\n matches = re.findall(pattern, s)\n return matches", "matching_cluster_idx": 4}]}, "Mbpp/732": {"dps": 75.71705426356588, "dps_norm": 94.5, "pass@1": 95.0, "profiled": [{"solution": "def replace_specialchar(s):\n # Replace spaces, commas, and dots with a colon\n return s.replace(' ', ':').replace(',', ':').replace('.', ':')", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(s: str) -> str:\n # Create a translation table to replace spaces, commas, and dots with colons\n translator = str.maketrans(' .,', ':::')\n # Use the translate method to apply the translation table to the string\n return s.translate(translator)", "matching_cluster_idx": 8}, {"solution": "def replace_specialchar(s):\n # Replace spaces, commas, and dots with a colon\n return s.replace(' ', ':').replace(',', ':').replace('.', ':')", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(s):\n # Replace spaces, commas, and dots with a colon\n return s.replace(' ', ':').replace(',', ':').replace('.', ':')", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(s):\n # Replace spaces, commas, or dots with a colon\n return s.replace(\" \", \":\").replace(\",\", \":\").replace(\".\", \":\")", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(s):\n # Define the characters to replace\n replace_chars = ' ,.'\n # Define the character to replace with\n replace_with = ':'\n\n # Use str.translate() and str.maketrans() for efficient replacement\n translation_table = str.maketrans(replace_chars, replace_with * len(replace_chars))\n return s.translate(translation_table)", "matching_cluster_idx": 8}, {"solution": "def replace_specialchar(s):\n # Replace spaces, commas, and dots with colons\n result = s.replace(' ', ':').replace(',', ':').replace('.', ':')\n return result", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(s: str) -> str:\n return s.replace(' ', ':').replace(',', ':').replace('.', ':')", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(s):\n # Replace spaces, commas, and dots with a colon\n replaced = s.replace(' ', ':').replace(',', ':').replace('.', ':')\n return replaced", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(input_str):\n return input_str.replace(\" \", \":\").replace(\",\", \":\").replace(\".\", \":\")", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(s: str) -> str:\n special_chars = {' ': ':', ',': ':', '.': ':'}\n return ''.join(special_chars.get(char, char) for char in s)", "matching_cluster_idx": 4}, {"solution": "def replace_specialchar(s):\n return s.replace(' ', ':').replace(',', ':').replace('.', ':')", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(input_string):\n # Define the characters to be replaced\n characters_to_replace = ' ,.'\n\n # Define the replacement character\n replacement_character = ':'\n\n # Use the translate method to replace characters\n return input_string.translate(str.maketrans(characters_to_replace, replacement_character * len(characters_to_replace)))", "matching_cluster_idx": 8}, {"solution": "def replace_specialchar(s):\n # Replace spaces, commas, and dots with colons\n result = s.replace(' ', ':').replace(',', ':').replace('.', ':')\n return result", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(s):\n \"\"\"\n Replace all occurrences of spaces, commas, or dots with a colon.\n\n Parameters:\n s (str): The input string.\n\n Returns:\n str: The modified string with spaces, commas, and dots replaced by colons.\n \"\"\"\n return s.replace(' ', ':').replace(',', ':').replace('.', ':')", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(s):\n \"\"\"\n Replace all occurrences of spaces, commas, or dots with a colon.\n \"\"\"\n return s.replace(' ', ':').replace(',', ':').replace('.', ':')", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(input_str):\n \"\"\"\n This function replaces all occurrences of spaces, commas, or dots with a colon.\n\n :param input_str: String to replace characters in.\n :return: String with spaces, commas, and dots replaced with colons.\n \"\"\"\n # Define the characters to replace\n special_chars = \" ,.\"\n # Define the replacement character\n replacement = \":\"\n\n # Create a translation table\n translation_table = str.maketrans(special_chars, replacement * len(special_chars))\n\n # Use translate to apply the table\n return input_str.translate(translation_table)", "matching_cluster_idx": 8}, {"solution": "def replace_specialchar(input_string):\n # Create a translation table that maps spaces, commas, and dots to colons\n translation_table = str.maketrans(' ,.', ':::')\n # Use the translate method to replace characters\n return input_string.translate(translation_table)", "matching_cluster_idx": 8}, {"solution": "def replace_specialchar(s):\n return s.replace(' ', ':').replace(',', ':').replace('.', ':')", "matching_cluster_idx": 9}, {"solution": "def replace_specialchar(text):\n # Define the characters to be replaced\n special_chars = {' ': ':', ',': ':', '.': ':'}\n\n # Replace each character in the text using str.translate\n replaced_text = text.translate(str.maketrans(special_chars))\n\n return replaced_text", "matching_cluster_idx": 8}]}, "Mbpp/740": {"dps": 59.96363636363637, "dps_norm": 60.55555555555556, "pass@1": 85.0, "profiled": [{"solution": "def tuple_to_dict(t):\n result = {}\n i = 0\n while i < len(t) - 1:\n result[t[i]] = t[i + 1]\n i += 2\n return result", "matching_cluster_idx": 3}, {"solution": "def tuple_to_dict(t):\n # Create an empty dictionary to store the key-value pairs\n result = {}\n\n # Iterate through the tuple in steps of 2 to get the pairs\n for i in range(0, len(t), 2):\n # The current element is the key, and the next element is the value\n result[t[i]] = t[i + 1]\n\n return result", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(t):\n # Initialize an empty dictionary\n result = {}\n\n # Iterate over the tuple in steps of 2\n for i in range(0, len(t), 2):\n # Pair the current element with the next one\n result[t[i]] = t[i + 1]\n\n return result", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(t):\n if len(t) % 2 != 0:\n raise ValueError(\"Tuple length must be even to form key-value pairs\")\n\n return {t[i]: t[i+1] for i in range(0, len(t), 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(tup):\n \"\"\"\n Converts the given tuple to a key-value dictionary using adjacent elements.\n\n Args:\n tup (tuple): The input tuple of elements.\n\n Returns:\n dict: A dictionary with keys and values formed from adjacent elements of the tuple.\n \"\"\"\n if len(tup) % 2 != 0:\n raise ValueError(\"The length of the tuple must be even.\")\n\n result = {}\n for i in range(0, len(tup), 2):\n key, value = tup[i], tup[i + 1]\n result[key] = value\n\n return result", "matching_cluster_idx": 4}, {"solution": "def tuple_to_dict(input_tuple):\n if len(input_tuple) % 2 != 0:\n raise ValueError(\"Tuple length must be even to form key-value pairs.\")\n\n result_dict = {}\n for i in range(0, len(input_tuple), 2):\n result_dict[input_tuple[i]] = input_tuple[i + 1]\n\n return result_dict", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(t):\n \"\"\"\n Convert a tuple to a key-value dictionary using adjacent elements.\n >>> tuple_to_dict((1, 5, 7, 10, 13, 5))\n {1: 5, 7: 10, 13: 5}\n >>> tuple_to_dict((2, 3, 4, 5))\n {2: 3, 4: 5}\n >>> tuple_to_dict((5))\n {}\n >>> tuple_to_dict((1,))\n {}\n \"\"\"\n if len(t) < 2:\n return {}\n\n result = {}\n for i in range(0, len(t), 2):\n result[t[i]] = t[i + 1]\n\n return result", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(tup):\n # Initialize an empty dictionary\n result_dict = {}\n\n # Loop over the tuple in steps of 2\n for i in range(0, len(tup), 2):\n # Assign key-value pairs to the dictionary\n if i + 1 < len(tup):\n result_dict[tup[i]] = tup[i + 1]\n\n return result_dict", "matching_cluster_idx": 3}, {"solution": "def tuple_to_dict(t):\n # Initialize an empty dictionary\n result = {}\n\n # Iterate through the tuple, using the `i` element as the key and `i+1` as the value\n for i in range(0, len(t) - 1, 2):\n result[t[i]] = t[i + 1]\n\n return result", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(t):\n # Create an empty dictionary to store the key-value pairs\n result = {}\n\n # Iterate over the tuple in steps of two\n for i in range(0, len(t), 2):\n key = t[i]\n value = t[i + 1]\n # Add the key-value pair to the dictionary\n result[key] = value\n\n return result", "matching_cluster_idx": 4}, {"solution": "def tuple_to_dict(t):\n if len(t) % 2 != 0:\n raise ValueError(\"Tuple has an odd number of elements.\")\n\n return {t[i]: t[i+1] for i in range(0, len(t), 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(input_tuple):\n # Create an empty dictionary\n result_dict = {}\n\n # Iterate over the tuple with a step of 2\n for i in range(0, len(input_tuple), 2):\n if i + 1 < len(input_tuple):\n result_dict[input_tuple[i]] = input_tuple[i + 1]\n\n return result_dict", "matching_cluster_idx": 3}, {"solution": "def tuple_to_dict(t):\n \"\"\"\n Convert the given tuple to a key-value dictionary using adjacent elements.\n\n Args:\n t (tuple): Input tuple with elements.\n\n Returns:\n dict: Dictionary with keys and values from the tuple.\n \"\"\"\n # Initialize an empty dictionary\n result_dict = {}\n\n # Iterate through the tuple in steps of 2\n for i in range(0, len(t), 2):\n # Assign the value to the key in the dictionary\n result_dict[t[i]] = t[i + 1]\n\n return result_dict", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(tup):\n \"\"\"\n Converts the given tuple to a dictionary with keys and values from adjacent elements.\n\n Args:\n tup (tuple): The input tuple.\n\n Returns:\n dict: A dictionary created from the tuple where each key-value pair is formed from adjacent elements.\n \"\"\"\n # Initialize an empty dictionary\n result_dict = {}\n\n # Iterate through the tuple in steps of two\n for i in range(0, len(tup), 2):\n # Create the key-value pair from the adjacent elements\n key = tup[i]\n value = tup[i+1]\n # Add the pair to the dictionary\n result_dict[key] = value\n\n return result_dict", "matching_cluster_idx": 4}, {"solution": "def tuple_to_dict(t):\n # Initialize an empty dictionary\n result = {}\n # Loop through the tuple with a step of 2\n for i in range(0, len(t), 2):\n # Add the element at the current index as the key and the next element as the value\n result[t[i]] = t[i+1]\n return result", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(input_tuple):\n if len(input_tuple) % 2 != 0:\n raise ValueError(\"The tuple length must be even.\")\n\n result_dict = {}\n for i in range(0, len(input_tuple), 2):\n result_dict[input_tuple[i]] = input_tuple[i + 1]\n\n return result_dict", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(tup):\n if len(tup) % 2 != 0:\n raise ValueError(\"The length of the tuple must be even to form key-value pairs\")\n\n return {tup[i]: tup[i+1] for i in range(0, len(tup), 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(t):\n # Create an empty dictionary\n result_dict = {}\n\n # Iterate over the tuple with step 2 to get key-value pairs\n for i in range(0, len(t), 2):\n if i + 1 < len(t):\n result_dict[t[i]] = t[i + 1]\n\n return result_dict", "matching_cluster_idx": 3}, {"solution": "def tuple_to_dict(tup):\n if len(tup) % 2 != 0:\n raise ValueError(\"The input tuple has an odd number of elements.\")\n\n return {tup[i]: tup[i+1] for i in range(0, len(tup), 2)}", "matching_cluster_idx": 5}, {"solution": "def tuple_to_dict(t):\n if len(t) % 2 != 0:\n raise ValueError(\"Tuple length must be even to form key-value pairs.\")\n\n return {t[i]: t[i + 1] for i in range(0, len(t), 2)}", "matching_cluster_idx": 5}]}, "Mbpp/744": {"dps": 69.07534246575342, "dps_norm": 78.33333333333333, "pass@1": 100.0, "profiled": [{"solution": "def check_none(tup):\n \"\"\"\n Check if the given tuple contains any None value.\n\n Args:\n tup (tuple): The tuple to check.\n\n Returns:\n bool: True if any None value is found in the tuple, otherwise False.\n \"\"\"\n return None in tup", "matching_cluster_idx": 5}, {"solution": "def check_none(tpl):\n \"\"\"\n Function to check if the given tuple has any None value or not.\n\n Parameters:\n tpl (tuple): The tuple to check.\n\n Returns:\n bool: True if there is any None value in the tuple, False otherwise.\n \"\"\"\n return None in tpl", "matching_cluster_idx": 5}, {"solution": "def check_none(tup):\n \"\"\"\n Check if the given tuple has any None values.\n\n Args:\n tup (tuple): A tuple of elements.\n\n Returns:\n bool: True if any None value is present, otherwise False.\n \"\"\"\n return None in tup", "matching_cluster_idx": 5}, {"solution": "def check_none(t):\n \"\"\"\n Check if the given tuple has any None value.\n\n Parameters:\n t (tuple): The tuple to check.\n\n Returns:\n bool: True if the tuple contains a None value, False otherwise.\n \"\"\"\n return None in t", "matching_cluster_idx": 5}, {"solution": "def check_none(t):\n # Check if any element in the tuple is None\n return None in t", "matching_cluster_idx": 5}, {"solution": "def check_none(input_tuple):\n \"\"\"\n Check if the given tuple contains any None value.\n\n Parameters:\n input_tuple (tuple): The input tuple to check.\n\n Returns:\n bool: True if the tuple contains any None value, False otherwise.\n \"\"\"\n return any(element is None for element in input_tuple)", "matching_cluster_idx": 1}, {"solution": "def check_none(tup):\n \"\"\"\n Check if the given tuple contains any None values.\n\n Parameters:\n tup (tuple): The tuple to check.\n\n Returns:\n bool: True if there is any None value in the tuple, otherwise False.\n \"\"\"\n return any(item is None for item in tup)", "matching_cluster_idx": 1}, {"solution": "def check_none(input_tuple):\n \"\"\"\n Check if the given tuple has any None value.\n\n Parameters:\n input_tuple (tuple): The tuple to check.\n\n Returns:\n bool: True if any element in the tuple is None, False otherwise.\n \"\"\"\n return any(element is None for element in input_tuple)", "matching_cluster_idx": 1}, {"solution": "def check_none(t):\n # Iterate through each element in the tuple\n for item in t:\n # If any item is None, return True\n if item is None:\n return True\n # If no None items found, return False\n return False", "matching_cluster_idx": 4}, {"solution": "def check_none(tpl):\n \"\"\"\n This function checks if the given tuple contains any None values.\n\n Parameters:\n tpl (tuple): The input tuple to be checked.\n\n Returns:\n bool: True if the tuple contains any None values, False otherwise.\n \"\"\"\n return None in tpl", "matching_cluster_idx": 5}, {"solution": "def check_none(tuple_input):\n \"\"\"\n Check if any element in the given tuple is None.\n\n Parameters:\n tuple_input (tuple): The input tuple to check.\n\n Returns:\n bool: True if any element is None, False otherwise.\n \"\"\"\n return None in tuple_input", "matching_cluster_idx": 5}, {"solution": "def check_none(t):\n \"\"\"\n Check if the given tuple has any None value.\n\n Args:\n t (tuple): The input tuple to check for None values.\n\n Returns:\n bool: True if any element in the tuple is None, False otherwise.\n \"\"\"\n return any(element is None for element in t)", "matching_cluster_idx": 2}, {"solution": "def check_none(t):\n \"\"\"\n Check if the given tuple contains any None values.\n\n Parameters:\n t (tuple): A tuple of elements to check\n\n Returns:\n bool: True if any None value is found, False otherwise\n \"\"\"\n return any(element is None for element in t)", "matching_cluster_idx": 2}, {"solution": "def check_none(tpl):\n \"\"\"\n Function to check if the given tuple contains any None values.\n\n Args:\n tpl (tuple): The tuple to check.\n\n Returns:\n bool: True if the tuple contains None, False otherwise.\n \"\"\"\n return None in tpl", "matching_cluster_idx": 5}, {"solution": "def check_none(data):\n \"\"\"\n Check if the given tuple contains any None values.\n\n Args:\n data (tuple): The tuple to be checked.\n\n Returns:\n bool: True if any None value is present, False otherwise.\n \"\"\"\n return any(x is None for x in data)", "matching_cluster_idx": 2}, {"solution": "def check_none(t):\n # Check if any element in the tuple is None\n return any(element is None for element in t)", "matching_cluster_idx": 1}, {"solution": "def check_none(input_tuple):\n return None in input_tuple", "matching_cluster_idx": 5}, {"solution": "def check_none(t):\n \"\"\"\n Check if the given tuple has any None value.\n\n Parameters:\n t (tuple): The tuple to check.\n\n Returns:\n bool: True if the tuple contains any None value, False otherwise.\n \"\"\"\n return None in t", "matching_cluster_idx": 5}, {"solution": "def check_none(tpl):\n \"\"\"\n Check if the given tuple contains any None values.\n\n Parameters:\n tpl (tuple): The tuple to be checked.\n\n Returns:\n bool: True if any None value is found, False otherwise.\n \"\"\"\n return None in tpl", "matching_cluster_idx": 5}, {"solution": "def check_none(t):\n \"\"\"\n Check if the given tuple contains any None value.\n\n Args:\n t (tuple): The input tuple to check.\n\n Returns:\n bool: True if the tuple contains None, False otherwise.\n \"\"\"\n return None in t", "matching_cluster_idx": 5}]}, "Mbpp/750": {"dps": 69.25170068027211, "dps_norm": 68.33333333333333, "pass@1": 96.0, "profiled": [{"solution": "def add_tuple(lst, tpl):\n \"\"\"\n Adds the given tuple elements to the end of the given list.\n\n Args:\n lst (list): The list to which tuple elements will be added.\n tpl (tuple): The tuple whose elements will be added to the list.\n\n Returns:\n list: A new list with elements of the original list followed by elements of the tuple.\n \"\"\"\n return lst + list(tpl)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(lst, tpl):\n \"\"\"\n This function adds the elements of the given tuple to the given list.\n\n Parameters:\n lst (list): The list to which the tuple elements will be added.\n tpl (tuple): The tuple whose elements will be added to the list.\n\n Returns:\n list: A new list with the tuple elements added.\n \"\"\"\n return lst + list(tpl)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(lst, tup):\n \"\"\"\n Add the given tuple to the given list.\n\n Args:\n lst (list): The original list.\n tup (tuple): The tuple to be added.\n\n Returns:\n list: A new list with the tuple elements added to the end of the original list.\n \"\"\"\n return lst + list(tup)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(lst, tup):\n return lst + list(tup)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(lst, tup):\n \"\"\"\n Adds elements of the given tuple to the given list.\n\n Args:\n lst (list): The original list to add elements to.\n tup (tuple): The tuple whose elements are to be added to the list.\n\n Returns:\n list: A new list with the elements of the tuple appended.\n \"\"\"\n return lst + list(tup)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(lst, tpl):\n \"\"\"\n Adds the elements of the given tuple to the given list.\n\n Args:\n lst (list): The list to which elements will be added.\n tpl (tuple): The tuple whose elements will be added to the list.\n\n Returns:\n list: A new list with elements of the tuple added to the original list.\n \"\"\"\n # Extend the list with the elements of the tuple\n new_list = lst + list(tpl)\n return new_list", "matching_cluster_idx": 2}, {"solution": "def add_tuple(lst, tpl):\n \"\"\"\n Adds the elements of the given tuple to the given list.\n\n Parameters:\n lst (list): The list to which elements will be added.\n tpl (tuple): The tuple whose elements will be added to the list.\n\n Returns:\n list: A new list with the elements of the tuple added to the end.\n \"\"\"\n return lst + list(tpl)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(lst, tpl):\n \"\"\"\n Add the given tuple to the given list.\n\n Parameters:\n lst (list): The list to which the tuple will be added.\n tpl (tuple): The tuple to be added to the list.\n\n Returns:\n list: The list with the tuple added.\n \"\"\"\n lst.extend(tpl)\n return lst", "matching_cluster_idx": 5}, {"solution": "def add_tuple(lst, tpl):\n \"\"\"\n Adds the elements of the tuple to the given list.\n\n Parameters:\n lst (list): The list to which elements will be added.\n tpl (tuple): The tuple containing elements to be added.\n\n Returns:\n list: A new list with the elements of the tuple added.\n \"\"\"\n lst.extend(tpl)\n return lst", "matching_cluster_idx": 5}, {"solution": "def add_tuple(lst, tup):\n \"\"\"\n Adds the given tuple to the given list.\n\n Parameters:\n lst (list): The list to add the tuple to.\n tup (tuple): The tuple to add to the list.\n\n Returns:\n list: A new list with the tuple added to it.\n \"\"\"\n # Combine the list and the tuple into a single iterable\n combined = lst + list(tup)\n return combined", "matching_cluster_idx": 2}, {"solution": "def add_tuple(lst, tpl):\n return lst + list(tpl)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(lst, tup):\n \"\"\"\n Add the given tuple to the end of the given list.\n\n :param lst: List of elements\n :param tup: Tuple of elements\n :return: Updated list with tuple elements added\n \"\"\"\n lst.extend(tup)\n return lst", "matching_cluster_idx": 5}, {"solution": "def add_tuple(lst, tpl):\n \"\"\"\n Adds elements of the given tuple to the given list.\n\n Parameters:\n lst (list): The list to which elements will be added.\n tpl (tuple): The tuple whose elements will be added to the list.\n\n Returns:\n list: The updated list with the elements of the tuple added.\n \"\"\"\n lst.extend(tpl)\n return lst", "matching_cluster_idx": 5}, {"solution": "def add_tuple(lst, tpl):\n \"\"\"\n Adds a tuple to a list.\n\n Parameters:\n lst (list): The list to which the tuple will be added.\n tpl (tuple): The tuple to be added to the list.\n\n Returns:\n list: A new list with the tuple elements added to the end.\n \"\"\"\n # Unpack the tuple and extend the list with its elements\n return lst + list(tpl)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(lst, tup):\n # Convert tuple to list and extend the original list\n lst.extend(list(tup))\n return lst", "matching_cluster_idx": 3}, {"solution": "def add_tuple(lst, tpl):\n \"\"\"\n Adds elements of the given tuple to the end of the given list.\n\n Parameters:\n lst (list): The list to which elements will be added.\n tpl (tuple): The tuple whose elements will be added to the list.\n\n Returns:\n list: A new list with the tuple elements added to the end.\n \"\"\"\n return lst + list(tpl)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(lst, tpl):\n \"\"\"\n Adds the given tuple to the given list.\n\n Parameters:\n lst (list): The original list.\n tpl (tuple): The tuple to add to the list.\n\n Returns:\n list: A new list with the tuple elements added to the original list.\n \"\"\"\n lst.extend(tpl)\n return lst", "matching_cluster_idx": 5}, {"solution": "def add_tuple(lst, tup):\n \"\"\"\n Adds the given tuple to the given list.\n\n Parameters:\n lst (list): The list to which the tuple will be added.\n tup (tuple): The tuple to be added to the list.\n\n Returns:\n list: A new list with the tuple elements appended to the original list.\n \"\"\"\n # Extend the list with the tuple elements\n lst.extend(tup)\n return lst", "matching_cluster_idx": 5}, {"solution": "def add_tuple(lst, tpl):\n return lst + list(tpl)", "matching_cluster_idx": 2}, {"solution": "def add_tuple(lst, tpl):\n \"\"\"\n Add the elements of the given tuple to the given list.\n\n Args:\n lst (list): The list to which elements of the tuple are to be added.\n tpl (tuple): The tuple whose elements are to be added to the list.\n\n Returns:\n list: A new list with the elements of the tuple added.\n \"\"\"\n lst.extend(tpl)\n return lst", "matching_cluster_idx": 5}]}, "Mbpp/753": {"dps": 97.31543624161074, "dps_norm": 75.0, "pass@1": 100.0, "profiled": [{"solution": "def min_k(tuples, k):\n # Sort the list of tuples based on the second element (score) in ascending order\n sorted_tuples = sorted(tuples, key=lambda x: x[1])\n # Return the first k elements from the sorted list\n return sorted_tuples[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(records, k):\n # Sort the records list by the second element (value)\n sorted_records = sorted(records, key=lambda x: x[1])\n # Return the first k elements from the sorted list\n return sorted_records[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(records, k):\n # Sort the list of tuples based on the second element (the value)\n sorted_records = sorted(records, key=lambda x: x[1])\n # Return the first k elements from the sorted list\n return sorted_records[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(records, k):\n # Sort the records based on the second element (score)\n sorted_records = sorted(records, key=lambda x: x[1])\n # Return the first k elements from the sorted list\n return sorted_records[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(tuples_list, k):\n # Sort the list of tuples based on the second element (the value)\n sorted_list = sorted(tuples_list, key=lambda x: x[1])\n # Return the first k elements from the sorted list\n return sorted_list[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(records, k):\n \"\"\"\n Find the minimum k records from a list of tuples.\n\n Args:\n records (list of tuples): List of tuples where each tuple contains a name and a number.\n k (int): Number of records to return.\n\n Returns:\n list of tuples: Sorted list of k records with the smallest numbers.\n \"\"\"\n # Sort the records by the second element of the tuple (the number) in ascending order\n sorted_records = sorted(records, key=lambda x: x[1])\n\n # Return the first k elements from the sorted list\n return sorted_records[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(tuples, k):\n # Sort the list of tuples based on the second element (the value)\n sorted_tuples = sorted(tuples, key=lambda x: x[1])\n # Return the first k elements from the sorted list\n return sorted_tuples[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(records, k):\n # Sort the list of tuples by the second element (the number)\n sorted_records = sorted(records, key=lambda x: x[1])\n # Return the first k records from the sorted list\n return sorted_records[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(records, k):\n # Sort the list of tuples by the second element (the number)\n sorted_records = sorted(records, key=lambda x: x[1])\n\n # Return the first k elements from the sorted list\n return sorted_records[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(records, k):\n # Sort the list of tuples based on the second element (the score)\n sorted_records = sorted(records, key=lambda x: x[1])\n # Return the first k records from the sorted list\n return sorted_records[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(records, k):\n # Sort the records based on the second element (value)\n sorted_records = sorted(records, key=lambda x: x[1])\n # Return the first k elements\n return sorted_records[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(tuples, k):\n # Sort the list of tuples by the second element (the number) in ascending order\n sorted_tuples = sorted(tuples, key=lambda x: x[1])\n # Return the first k elements from the sorted list\n return sorted_tuples[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(records, k):\n # Sort the records by the second element (score) in ascending order\n sorted_records = sorted(records, key=lambda x: x[1])\n # Return the first k records from the sorted list\n return sorted_records[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(tuple_list, k):\n # Sort the tuple list based on the second element of each tuple (the score)\n sorted_list = sorted(tuple_list, key=lambda x: x[1])\n\n # Return the first k elements from the sorted list\n return sorted_list[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(records, k):\n # Sort the records by the second element (the number) in ascending order\n sorted_records = sorted(records, key=lambda x: x[1])\n # Return the first k records from the sorted list\n return sorted_records[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(records, k):\n # Sort the list of tuples based on the second element (the value)\n sorted_records = sorted(records, key=lambda x: x[1])\n # Return the first k elements from the sorted list\n return sorted_records[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(records, k):\n # Sort the list of tuples based on the second element of the tuple (the number)\n sorted_records = sorted(records, key=lambda x: x[1])\n # Return the first k elements from the sorted list\n return sorted_records[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(records, k):\n # Sort the list of tuples based on the second element (the integer value)\n sorted_records = sorted(records, key=lambda x: x[1])\n # Return the first k elements from the sorted list\n return sorted_records[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(tuples_list, k):\n # Sort the list of tuples based on the second element (value)\n sorted_list = sorted(tuples_list, key=lambda x: x[1])\n # Return the first k elements from the sorted list\n return sorted_list[:k]", "matching_cluster_idx": 2}, {"solution": "def min_k(records, k):\n # Sort the records based on the second element (score) in ascending order\n sorted_records = sorted(records, key=lambda x: x[1])\n # Return the first k elements from the sorted list\n return sorted_records[:k]", "matching_cluster_idx": 2}]}, "Mbpp/754": {"dps": 84.31034482758622, "dps_norm": 86.25, "pass@1": 61.0, "profiled": [{"solution": "def extract_index_list(l1, l2, l3):\n # Initialize the result list\n common_elements = []\n\n # Iterate through the lists and check for common elements at each index\n for i in range(min(len(l1), len(l2), len(l3))):\n if l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n # Find the minimum length of the lists to avoid index out of range error\n min_length = min(len(l1), len(l2), len(l3))\n\n # Initialize an empty list to store common elements\n common_elements = []\n\n # Iterate over the range of the minimum length\n for i in range(min_length):\n # Check if the element is common at index i\n if l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n # Find the length of the shortest list to avoid index out of range errors\n min_length = min(len(l1), len(l2), len(l3))\n\n # Initialize an empty list to store common elements\n common_elements = []\n\n # Iterate over the range of the shortest list's length\n for i in range(min_length):\n # Check if elements at the same index are equal in all three lists\n if l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n # Find the minimum length of the three lists to ensure we don't go out of bounds\n min_len = min(len(l1), len(l2), len(l3))\n\n common_elements = []\n\n # Iterate through the indices up to the minimum length\n for i in range(min_len):\n # Check if the element is common at the current index\n if l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n # Initialize an empty list to store common elements\n common_elements = []\n\n # Iterate through the indices of the lists\n for i in range(min(len(l1), len(l2), len(l3))):\n # Check if the element at index i is common in all three lists\n if l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n # Find the common elements in l1, l2, and l3 that appear at the same index\n common_elements = []\n for i in range(min(len(l1), len(l2), len(l3))):\n if l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n \"\"\"\n Extracts elements that are common in the same index positions across three lists.\n\n :param l1: First list\n :param l2: Second list\n :param l3: Third list\n :return: List of common elements at the same index positions\n \"\"\"\n # Find the minimum length of the three lists to avoid index out of range errors\n min_length = min(len(l1), len(l2), len(l3))\n\n # Initialize an empty list to store common elements\n common_elements = []\n\n # Iterate through the indices up to the minimum length\n for i in range(min_length):\n if l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n \"\"\"\n This function returns a list of elements that are common for all three lists at the same index.\n\n Parameters:\n l1 (list): List 1\n l2 (list): List 2\n l3 (list): List 3\n\n Returns:\n list: List of common elements\n \"\"\"\n common_elements = []\n # Iterate through the lists by index\n for index in range(min(len(l1), len(l2), len(l3))):\n if l1[index] == l2[index] == l3[index]:\n common_elements.append(l1[index])\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n # Find the minimum length among the three lists\n min_length = min(len(l1), len(l2), len(l3))\n\n # Initialize an empty list to store common elements\n common_elements = []\n\n # Iterate over the indices up to the minimum length\n for i in range(min_length):\n # Check if the elements at the current index are the same in all three lists\n if l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n # Create a new list to store the common elements\n common_elements = []\n\n # Iterate over the range of the smallest list length to ensure no index out of range error\n for i in range(min(len(l1), len(l2), len(l3))):\n # Check if the elements at the current index are the same in all three lists\n if l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n # Find the minimum length of the three lists to avoid index out of range errors\n min_length = min(len(l1), len(l2), len(l3))\n\n # Initialize an empty list to store common elements\n common_elements = []\n\n # Iterate over the range of the minimum length\n for i in range(min_length):\n # Check if all three lists have the same element at index i\n if l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n min_len = min(len(l1), len(l2), len(l3))\n common_elements = []\n\n for i in range(min_len):\n if l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n # Find the length of the smallest list to avoid index out of range error\n min_length = min(len(l1), len(l2), len(l3))\n\n common_elements = []\n for i in range(min_length):\n if l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n \"\"\"\n Find common elements from three lists at the same index.\n\n Parameters:\n l1 (list): First list.\n l2 (list): Second list.\n l3 (list): Third list.\n\n Returns:\n list: List of common elements found at the same index in all three lists.\n \"\"\"\n # Ensure all lists are of the same length\n min_length = min(len(l1), len(l2), len(l3))\n l1 = l1[:min_length]\n l2 = l2[:min_length]\n l3 = l3[:min_length]\n\n # Find common elements\n common_elements = []\n for i in range(min_length):\n if l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n\n return common_elements", "matching_cluster_idx": 5}, {"solution": "def extract_index_list(l1, l2, l3):\n # Find the length of the shortest list to avoid index out of range errors\n min_length = min(len(l1), len(l2), len(l3))\n\n # Initialize an empty list to store common elements\n common_elements = []\n\n # Iterate through the indices of the shortest list\n for i in range(min_length):\n # Check if the element at index i is the same in all three lists\n if l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n \"\"\"\n Function to find common elements from three lists at the same index.\n\n :param l1: First list\n :param l2: Second list\n :param l3: Third list\n :return: List of common elements\n \"\"\"\n # Iterate through the indices of the lists\n common_elements = []\n for i in range(min(len(l1), len(l2), len(l3))):\n if l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n # Ensure all lists have the same length to safely compare indices\n min_len = min(len(l1), len(l2), len(l3))\n l1, l2, l3 = l1[:min_len], l2[:min_len], l3[:min_len]\n\n # Find common elements\n common_elements = []\n for i in range(min_len):\n if l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n\n return common_elements", "matching_cluster_idx": 5}, {"solution": "def extract_index_list(l1, l2, l3):\n common_elements = []\n for i in range(min(len(l1), len(l2), len(l3))):\n if l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n # We will use the zip function to iterate over lists together\n # and collect common elements based on index\n common_elements = []\n\n # Use the min length list to avoid index out of range errors\n for i in range(min(len(l1), len(l2), len(l3))):\n if l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n\n return common_elements", "matching_cluster_idx": 6}, {"solution": "def extract_index_list(l1, l2, l3):\n # Initialize an empty list to hold the common elements\n common_elements = []\n\n # Find the minimum length among the three lists\n min_length = min(len(l1), len(l2), len(l3))\n\n # Iterate over the range of the minimum length\n for i in range(min_length):\n # Check if the elements at the same index are equal in all three lists\n if l1[i] == l2[i] == l3[i]:\n common_elements.append(l1[i])\n\n return common_elements", "matching_cluster_idx": 6}]}, "Mbpp/755": {"dps": 50.0, "dps_norm": 75.0, "pass@1": 14.0, "profiled": [{"solution": "def second_smallest(nums):\n if len(nums) < 2:\n return None # Return None if there are less than 2 elements\n\n # Initialize first and second smallest to infinity\n first = float('inf')\n second = float('inf')\n\n for num in nums:\n if num < first:\n second = first\n first = num\n elif first < num < second:\n second = num\n\n if second == float('inf'):\n return None # Return None if there isn't a second smallest distinct number\n\n return second", "matching_cluster_idx": 3}, {"solution": "def second_smallest(nums):\n if len(nums) < 2:\n return None # Less than 2 elements, no second smallest number\n\n first, second = float('inf'), float('inf')\n\n for num in nums:\n if num < first:\n first, second = num, first\n elif first < num < second:\n second = num\n\n return second if second != float('inf') else None", "matching_cluster_idx": 3}, {"solution": "def second_smallest(nums):\n if len(nums) < 2:\n return None # Not enough elements to find the second smallest\n # Remove duplicates and sort the list\n unique_nums = list(set(nums))\n unique_nums.sort()\n if len(unique_nums) < 2:\n return None # Not enough unique elements to find the second smallest\n return unique_nums[1] # Return the second smallest unique number", "matching_cluster_idx": 5}, {"solution": "def second_smallest(numbers):\n # Handle the case where the list has less than two unique elements\n if len(set(numbers)) < 2:\n return None\n\n # Remove duplicates and sort the list\n unique_numbers = sorted(set(numbers))\n\n # Return the second smallest number\n return unique_numbers[1]", "matching_cluster_idx": 4}, {"solution": "def second_smallest(numbers):\n # Check if the list has at least two unique elements\n if len(set(numbers)) < 2:\n return None # Or raise an exception\n\n # Initialize first and second smallest with infinity\n first, second = float('inf'), float('inf')\n\n for number in numbers:\n if number < first:\n second = first\n first = number\n elif number < second and number != first:\n second = number\n\n return second", "matching_cluster_idx": 3}, {"solution": "def second_smallest(lst):\n if len(lst) < 2:\n return None # Not enough elements to find the second smallest\n\n # Initialize the first and second smallest as positive infinity\n first_smallest = second_smallest = float('inf')\n\n for number in lst:\n if number < first_smallest:\n second_smallest = first_smallest\n first_smallest = number\n elif first_smallest < number < second_smallest:\n second_smallest = number\n\n if second_smallest == float('inf'):\n return None # No unique second smallest element\n return second_smallest", "matching_cluster_idx": 3}, {"solution": "def second_smallest(nums):\n \"\"\"\n Function to find the second smallest number in a list.\n\n :param nums: List of numbers\n :return: The second smallest number in the list or None if the list has less than 2 elements\n \"\"\"\n if len(nums) < 2:\n return None\n\n # Initialize the first and second smallest\n first, second = float('inf'), float('inf')\n\n for num in nums:\n if num < first:\n second = first\n first = num\n elif first < num < second:\n second = num\n\n return second if second != float('inf') else None", "matching_cluster_idx": 3}, {"solution": "def second_smallest(nums):\n # Remove duplicates to handle negative scenarios\n unique_nums = list(set(nums))\n\n # Ensure there are at least two unique numbers\n if len(unique_nums) < 2:\n return None # or raise an exception if preferred\n\n # Sort the list and return the second smallest element\n unique_nums.sort()\n return unique_nums[1]", "matching_cluster_idx": 5}, {"solution": "def second_smallest(nums):\n if len(nums) < 2:\n return None # Not enough elements to find the second smallest\n\n first, second = float('inf'), float('inf')\n\n for num in nums:\n if num < first:\n second = first\n first = num\n elif first < num < second:\n second = num\n\n return second if second != float('inf') else None", "matching_cluster_idx": 3}, {"solution": "def second_smallest(nums):\n # Check if there are less than 2 elements\n if len(nums) < 2:\n return None # Return None if less than 2 elements\n\n # Initialize the first and second smallest variables\n first_min = float('inf')\n second_min = float('inf')\n\n # Iterate through the list to find the smallest and second smallest\n for num in nums:\n if num < first_min:\n second_min = first_min\n first_min = num\n elif first_min < num < second_min:\n second_min = num\n\n # Return the second smallest number or None if it doesn't exist\n return second_min if second_min != float('inf') else None", "matching_cluster_idx": 3}, {"solution": "def second_smallest(lst):\n if len(lst) < 2:\n return None # Not enough elements to find second smallest\n unique_sorted = sorted(set(lst)) # Remove duplicates and sort the list\n return unique_sorted[1] if len(unique_sorted) >= 2 else None # Return second smallest or None if not enough unique elements", "matching_cluster_idx": 5}, {"solution": "def second_smallest(nums):\n if len(nums) < 2:\n return None\n\n # Initialize the smallest and second smallest with infinity\n smallest = float('inf')\n second_smallest = float('inf')\n\n for num in nums:\n if num < smallest:\n second_smallest = smallest\n smallest = num\n elif smallest < num < second_smallest:\n second_smallest = num\n\n return second_smallest if second_smallest != float('inf') else None", "matching_cluster_idx": 3}, {"solution": "def second_smallest(nums):\n \"\"\"\n Find the second smallest number in a list.\n\n :param nums: List of numbers\n :return: Second smallest number or None if the list has less than two unique elements\n \"\"\"\n if len(set(nums)) < 2:\n return None\n\n unique_nums = sorted(set(nums))\n return unique_nums[1]", "matching_cluster_idx": 4}, {"solution": "def second_smallest(nums):\n # Ensure there are at least two unique numbers\n if len(set(nums)) < 2:\n return None\n\n # Initialize the first and second smallest variables\n first_smallest = float('inf')\n second_smallest = float('inf')\n\n # Iterate through the list\n for num in nums:\n if num < first_smallest:\n second_smallest = first_smallest\n first_smallest = num\n elif first_smallest < num < second_smallest:\n second_smallest = num\n\n return second_smallest", "matching_cluster_idx": 2}]}, "Mbpp/757": {"dps": 86.6822429906542, "dps_norm": 54.61538461538461, "pass@1": 52.0, "profiled": [{"solution": "def count_reverse_pairs(strings):\n count = 0\n length = len(strings)\n for i in range(length):\n for j in range(i + 1, length):\n if strings[i] == strings[j][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(strings):\n reverse_map = {}\n count = 0\n\n for s in strings:\n reverse_s = s[::-1]\n if reverse_s in reverse_map:\n count += reverse_map[reverse_s]\n if s in reverse_map:\n reverse_map[s] += 1\n else:\n reverse_map[s] = 1\n\n return count", "matching_cluster_idx": 12}, {"solution": "def count_reverse_pairs(strings):\n reverse_map = {}\n count = 0\n\n for s in strings:\n reversed_s = s[::-1]\n if reversed_s in reverse_map:\n count += reverse_map[reversed_s]\n reverse_map[s] = reverse_map.get(s, 0) + 1\n\n return count", "matching_cluster_idx": 12}, {"solution": "def count_reverse_pairs(strings):\n # Initialize a dictionary to store the count of each string\n string_count = {}\n # Initialize a variable to store the count of reverse pairs\n reverse_pairs_count = 0\n\n # Traverse each string in the input list\n for string in strings:\n # Reverse the current string\n reversed_string = string[::-1]\n # If the reversed string is in the dictionary, increment the reverse pair count\n if reversed_string in string_count:\n reverse_pairs_count += string_count[reversed_string]\n # Increment the count of the current string in the dictionary\n if string in string_count:\n string_count[string] += 1\n else:\n string_count[string] = 1\n\n return reverse_pairs_count", "matching_cluster_idx": 12}, {"solution": "def count_reverse_pairs(strings):\n \"\"\"\n Count the pairs of reverse strings in the given string list.\n\n Args:\n strings (list): List of strings.\n\n Returns:\n int: Number of reverse pairs.\n \"\"\"\n count = 0\n reversed_strings = [s[::-1] for s in strings]\n\n for i in range(len(strings)):\n for j in range(i + 1, len(strings)):\n if strings[i] == reversed_strings[j]:\n count += 1\n\n return count", "matching_cluster_idx": 6}, {"solution": "def count_reverse_pairs(strings):\n def is_reverse(str1, str2):\n return str1 == str2[::-1]\n\n count = 0\n for i in range(len(strings)):\n for j in range(i + 1, len(strings)):\n if is_reverse(strings[i], strings[j]):\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(words):\n count = 0\n for i in range(len(words)):\n for j in range(i + 1, len(words)):\n if words[i] == words[j][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(strings):\n count = 0\n for i in range(len(strings)):\n for j in range(i + 1, len(strings)):\n if strings[i] == strings[j][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(str_list):\n reverse_map = {}\n count = 0\n for string in str_list:\n reversed_string = string[::-1]\n if reversed_string in reverse_map:\n count += reverse_map[reversed_string]\n reverse_map[string] = reverse_map.get(string, 0) + 1\n return count", "matching_cluster_idx": 12}, {"solution": "def count_reverse_pairs(strings):\n \"\"\"\n Count the pairs of reverse strings in the given string list.\n \"\"\"\n reverse_map = {}\n count = 0\n\n for s in strings:\n reverse_s = s[::-1]\n if reverse_s in reverse_map:\n count += reverse_map[reverse_s]\n if s in reverse_map:\n reverse_map[s] += 1\n else:\n reverse_map[s] = 1\n\n return count", "matching_cluster_idx": 12}, {"solution": "def count_reverse_pairs(strings):\n count = 0\n for i in range(len(strings)):\n for j in range(i+1, len(strings)):\n if strings[i] == strings[j][::-1] or strings[j] == strings[i][::-1]:\n count += 1\n return count", "matching_cluster_idx": 0}, {"solution": "def count_reverse_pairs(string_list):\n count = 0\n for i in range(len(string_list)):\n for j in range(i + 1, len(string_list)):\n if string_list[i] == string_list[j][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(strings):\n \"\"\"Count pairs of reverse strings in the given list.\"\"\"\n reverse_dict = {}\n count = 0\n\n for s in strings:\n reverse_s = s[::-1]\n if reverse_s in reverse_dict:\n count += reverse_dict[reverse_s]\n reverse_dict[s] = reverse_dict.get(s, 0) + 1\n\n return count", "matching_cluster_idx": 12}, {"solution": "def count_reverse_pairs(string_list):\n count = 0\n for i in range(len(string_list)):\n for j in range(i + 1, len(string_list)):\n if string_list[i] == string_list[j][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(strings):\n count = 0\n for i in range(len(strings)):\n for j in range(i+1, len(strings)):\n if strings[i] == strings[j][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(strings):\n count = 0\n reverse_map = {}\n\n for string in strings:\n reversed_string = string[::-1]\n if reversed_string in reverse_map:\n count += reverse_map[reversed_string]\n if string in reverse_map:\n reverse_map[string] += 1\n else:\n reverse_map[string] = 1\n\n return count", "matching_cluster_idx": 12}, {"solution": "def count_reverse_pairs(strings):\n \"\"\"\n Count pairs of reverse strings in the given string list.\n\n Parameters:\n strings (list): List of strings to be checked for reverse pairs.\n\n Returns:\n int: Count of pairs of reverse strings.\n \"\"\"\n reverse_map = {}\n count = 0\n\n for string in strings:\n reversed_string = string[::-1]\n if reversed_string in reverse_map:\n count += reverse_map[reversed_string]\n reverse_map[string] = reverse_map.get(string, 0) + 1\n\n return count", "matching_cluster_idx": 12}, {"solution": "def count_reverse_pairs(strings):\n count = 0\n for i in range(len(strings)):\n for j in range(i + 1, len(strings)):\n if strings[j] == strings[i][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(strings):\n count = 0\n for i in range(len(strings)):\n for j in range(i + 1, len(strings)):\n if strings[i] == strings[j][::-1] and strings[i][::-1] == strings[j]:\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def count_reverse_pairs(strings):\n count = 0\n for i in range(len(strings)):\n for j in range(i + 1, len(strings)):\n if strings[i] == strings[j][::-1]:\n count += 1\n return count", "matching_cluster_idx": 2}]}, "Mbpp/758": {"dps": 62.98262548262548, "dps_norm": 75.0, "pass@1": 100.0, "profiled": [{"solution": "from collections import defaultdict\ndef unique_sublists(lst):\n count_dict = defaultdict(int)\n\n for sublist in lst:\n tuple_sublist = tuple(sublist)\n count_dict[tuple_sublist] += 1\n\n return dict(count_dict)", "matching_cluster_idx": 5}, {"solution": "def unique_sublists(lst):\n count_dict = {}\n for sublist in lst:\n t = tuple(sublist)\n if t in count_dict:\n count_dict[t] += 1\n else:\n count_dict[t] = 1\n return count_dict", "matching_cluster_idx": 5}, {"solution": "from collections import defaultdict\ndef unique_sublists(lst):\n sublist_count = defaultdict(int)\n\n for sublist in lst:\n tuple_sublist = tuple(sublist)\n sublist_count[tuple_sublist] += 1\n\n return dict(sublist_count)", "matching_cluster_idx": 5}, {"solution": "def unique_sublists(lst):\n sublist_count = {}\n\n for sublist in lst:\n sublist_tuple = tuple(sublist)\n if sublist_tuple in sublist_count:\n sublist_count[sublist_tuple] += 1\n else:\n sublist_count[sublist_tuple] = 1\n\n return sublist_count", "matching_cluster_idx": 5}, {"solution": "from collections import defaultdict\ndef unique_sublists(lst):\n sublist_count = defaultdict(int)\n for sublist in lst:\n tuple_sublist = tuple(sublist)\n sublist_count[tuple_sublist] += 1\n return dict(sublist_count)", "matching_cluster_idx": 4}, {"solution": "from collections import defaultdict\ndef unique_sublists(lst):\n # Use defaultdict to count occurrences\n count_dict = defaultdict(int)\n\n # Convert each sublist to a tuple and update the count\n for sublist in lst:\n sublist_tuple = tuple(sublist)\n count_dict[sublist_tuple] += 1\n\n return dict(count_dict)", "matching_cluster_idx": 5}, {"solution": "from collections import Counter\ndef unique_sublists(lst):\n # Convert each sublist to a tuple\n tuples_list = [tuple(sublist) for sublist in lst]\n\n # Count the occurrences of each tuple\n count_dict = dict(Counter(tuples_list))\n\n return count_dict", "matching_cluster_idx": 6}, {"solution": "def unique_sublists(lst):\n sublist_count = {}\n for sublist in lst:\n sublist_tuple = tuple(sublist)\n if sublist_tuple in sublist_count:\n sublist_count[sublist_tuple] += 1\n else:\n sublist_count[sublist_tuple] = 1\n return sublist_count", "matching_cluster_idx": 5}, {"solution": "def unique_sublists(lst):\n from collections import defaultdict\n\n # Convert each list to a tuple and count occurrences\n tuple_counts = defaultdict(int)\n for sublist in lst:\n tuple_counts[tuple(sublist)] += 1\n\n # Convert the defaultdict to a regular dict\n return dict(tuple_counts)", "matching_cluster_idx": 5}, {"solution": "def unique_sublists(lst):\n sublist_count = {}\n\n for sublist in lst:\n sublist_tuple = tuple(sublist)\n if sublist_tuple in sublist_count:\n sublist_count[sublist_tuple] += 1\n else:\n sublist_count[sublist_tuple] = 1\n\n return sublist_count", "matching_cluster_idx": 5}, {"solution": "from collections import defaultdict\ndef unique_sublists(main_list):\n sublist_count = defaultdict(int)\n\n for sublist in main_list:\n tuple_sublist = tuple(sublist)\n sublist_count[tuple_sublist] += 1\n\n return dict(sublist_count)", "matching_cluster_idx": 5}, {"solution": "def unique_sublists(lst):\n # Create a dictionary to store the count of each sublist as a tuple\n sublist_count = {}\n\n # Iterate over each sublist in the given list\n for sublist in lst:\n # Convert the sublist to a tuple and update the count in the dictionary\n tuple_sublist = tuple(sublist)\n if tuple_sublist in sublist_count:\n sublist_count[tuple_sublist] += 1\n else:\n sublist_count[tuple_sublist] = 1\n\n return sublist_count", "matching_cluster_idx": 5}, {"solution": "from collections import defaultdict\ndef unique_sublists(lst):\n \"\"\"\n This function takes a list of lists and returns a dictionary where each list is converted to a tuple.\n The value of each tuple is the number of occurrences of that tuple in the original list.\n \"\"\"\n sublist_count = defaultdict(int)\n for sublist in lst:\n sublist_count[tuple(sublist)] += 1\n return dict(sublist_count)", "matching_cluster_idx": 5}, {"solution": "def unique_sublists(lst):\n sublist_count = {}\n\n for sublist in lst:\n tuple_rep = tuple(sublist)\n if tuple_rep in sublist_count:\n sublist_count[tuple_rep] += 1\n else:\n sublist_count[tuple_rep] = 1\n\n return sublist_count", "matching_cluster_idx": 5}, {"solution": "from collections import defaultdict\ndef unique_sublists(lst):\n # Create a dictionary to store tuple as key and count as value\n sublist_counts = defaultdict(int)\n\n for sublist in lst:\n # Convert sublist to tuple and increment the count in the dictionary\n sublist_counts[tuple(sublist)] += 1\n\n return dict(sublist_counts)", "matching_cluster_idx": 5}, {"solution": "def unique_sublists(main_list):\n # Initialize an empty dictionary to store the results\n result = {}\n\n # Iterate through each sublist in the main list\n for sublist in main_list:\n # Convert sublist to a tuple and store it in the dictionary, incrementing its count\n sublist_tuple = tuple(sublist)\n if sublist_tuple in result:\n result[sublist_tuple] += 1\n else:\n result[sublist_tuple] = 1\n\n return result", "matching_cluster_idx": 5}, {"solution": "def unique_sublists(lst):\n # Create a dictionary to store the count of each unique sublist (converted to tuple)\n sublist_count = {}\n\n # Iterate over each sublist in the input list\n for sublist in lst:\n # Convert the sublist to a tuple and use it as the key\n sublist_tuple = tuple(sublist)\n # Increment the count of this tuple in the dictionary\n if sublist_tuple in sublist_count:\n sublist_count[sublist_tuple] += 1\n else:\n sublist_count[sublist_tuple] = 1\n\n # Return the dictionary with the counts\n return sublist_count", "matching_cluster_idx": 5}, {"solution": "def unique_sublists(lst):\n sublist_count = {}\n\n for sublist in lst:\n tuple_sublist = tuple(sublist)\n if tuple_sublist in sublist_count:\n sublist_count[tuple_sublist] += 1\n else:\n sublist_count[tuple_sublist] = 1\n\n return sublist_count", "matching_cluster_idx": 5}, {"solution": "def unique_sublists(lst):\n sublist_count = {}\n for sublist in lst:\n sublist_tuple = tuple(sublist)\n if sublist_tuple in sublist_count:\n sublist_count[sublist_tuple] += 1\n else:\n sublist_count[sublist_tuple] = 1\n return sublist_count", "matching_cluster_idx": 5}, {"solution": "def unique_sublists(input_list):\n sublist_count = {}\n\n # Convert each list to a tuple and count its occurrences\n for sublist in input_list:\n sublist_tuple = tuple(sublist)\n if sublist_tuple in sublist_count:\n sublist_count[sublist_tuple] += 1\n else:\n sublist_count[sublist_tuple] = 1\n\n return sublist_count", "matching_cluster_idx": 5}]}, "Mbpp/760": {"dps": null, "dps_norm": null, "pass@1": 9.0, "profiled": []}, "Mbpp/764": {"dps": 88.88888888888889, "dps_norm": 50.0, "pass@1": 100.0, "profiled": [{"solution": "def number_ctr(s):\n return sum(c.isdigit() for c in s)", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n \"\"\"\n Count the number of digits in a given string.\n\n Args:\n s (str): The input string.\n\n Returns:\n int: The count of digits in the string.\n \"\"\"\n # Use a list comprehension to iterate over the string and check for digit characters\n return sum(c.isdigit() for c in s)", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s: str) -> int:\n return sum(char.isdigit() for char in s)", "matching_cluster_idx": 2}, {"solution": "def number_ctr(string):\n \"\"\"\n Count the number of digits in a given string.\n\n Parameters:\n string (str): The input string to count digits in.\n\n Returns:\n int: The count of digits in the string.\n \"\"\"\n return sum(char.isdigit() for char in string)", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s: str) -> int:\n return sum(c.isdigit() for c in s)", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s: str) -> int:\n \"\"\"\n Count the number of digits in the given string.\n\n Args:\n s (str): The input string.\n\n Returns:\n int: The count of digits in the string.\n \"\"\"\n return sum(char.isdigit() for char in s)", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n \"\"\"Count the number of digits in a given string.\"\"\"\n return sum(1 for char in s if char.isdigit())", "matching_cluster_idx": 2}, {"solution": "def number_ctr(string):\n count = 0\n for char in string:\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n count = 0\n for char in s:\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n count = 0\n for char in s:\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n count = 0\n for char in s:\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(string):\n \"\"\"\n Count the number of digits in a given string.\n \"\"\"\n return sum(char.isdigit() for char in string)", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n count = 0\n for char in s:\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(input_string):\n # Initialize a counter for digits\n digit_count = 0\n # Iterate through each character in the string\n for char in input_string:\n # Check if the character is a digit\n if char.isdigit():\n # Increment the counter\n digit_count += 1\n # Return the final count of digits\n return digit_count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n # Initialize counter for digits\n count = 0\n\n # Loop through each character in the string\n for char in s:\n # Check if the character is a digit\n if char.isdigit():\n count += 1\n\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n return sum(c.isdigit() for c in s)", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s: str) -> int:\n # Use a list comprehension to count numbers in the string\n return sum(char.isdigit() for char in s)", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s: str) -> int:\n \"\"\"Count the number of digits in a given string.\"\"\"\n count = 0\n for char in s:\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n count = 0\n for char in s:\n if char.isdigit():\n count += 1\n return count", "matching_cluster_idx": 2}, {"solution": "def number_ctr(s):\n # Use a generator expression to count digits in the string\n return sum(1 for char in s if char.isdigit())", "matching_cluster_idx": 2}]}, "Mbpp/766": {"dps": 72.80373831775701, "dps_norm": 61.66666666666667, "pass@1": 100.0, "profiled": [{"solution": "def pair_wise(lst):\n \"\"\"\n Given a list, return a list of all pairs of consecutive items in the given list.\n\n :param lst: List of elements\n :return: List of tuples with consecutive elements from the input list\n \"\"\"\n return [(lst[i], lst[i + 1]) for i in range(len(lst) - 1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n if len(lst) < 2:\n return []\n return [(lst[i], lst[i+1]) for i in range(len(lst) - 1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n \"\"\"\n Returns a list of all pairs of consecutive items in a given list.\n\n Args:\n lst (list): A list of elements.\n\n Returns:\n list: A list of tuples, where each tuple is a pair of consecutive items.\n \"\"\"\n return [(lst[i], lst[i+1]) for i in range(len(lst)-1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n # This function returns a list of pairs of consecutive items from the given list\n return [(lst[i], lst[i+1]) for i in range(len(lst)-1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n if len(lst) < 2:\n return []\n return [(lst[i], lst[i + 1]) for i in range(len(lst) - 1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n \"\"\"\n Returns a list of all pairs of consecutive items in the given list.\n \"\"\"\n if not lst:\n return []\n\n pairs = [(lst[i], lst[i + 1]) for i in range(len(lst) - 1)]\n return pairs", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n # Initialize an empty list to store pairs\n pairs = []\n\n # Iterate through the list up to the second last element\n for i in range(len(lst) - 1):\n # Append the pair of consecutive items to the pairs list\n pairs.append((lst[i], lst[i + 1]))\n\n return pairs", "matching_cluster_idx": 2}, {"solution": "def pair_wise(lst):\n return [(lst[i], lst[i+1]) for i in range(len(lst)-1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n \"\"\"\n Returns a list of all pairs of consecutive items in a given list.\n\n Parameters:\n lst (list): The input list.\n\n Returns:\n list: A list of tuples, each containing a pair of consecutive items from the input list.\n \"\"\"\n return [(lst[i], lst[i + 1]) for i in range(len(lst) - 1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n # Generate pairs of consecutive items in the list\n pairs = [(lst[i], lst[i+1]) for i in range(len(lst)-1)]\n return pairs", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n # Initialize an empty list to hold the result\n result = []\n\n # Iterate through the list up to the second-to-last element\n for i in range(len(lst) - 1):\n # Append the tuple of consecutive elements to the result list\n result.append((lst[i], lst[i + 1]))\n\n return result", "matching_cluster_idx": 2}, {"solution": "def pair_wise(lst):\n \"\"\"\n Returns a list of all pairs of consecutive items in the given list.\n\n Args:\n lst (list): List of elements.\n\n Returns:\n list: List of pairs of consecutive elements.\n \"\"\"\n return [(lst[i], lst[i + 1]) for i in range(len(lst) - 1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n pairs = []\n for i in range(len(lst) - 1):\n pairs.append((lst[i], lst[i + 1]))\n return pairs", "matching_cluster_idx": 2}, {"solution": "def pair_wise(lst):\n \"\"\"\n Return a list of all pairs of consecutive items in a given list.\n\n Parameters:\n lst (list): The input list of elements.\n\n Returns:\n list: A list of tuples containing pairs of consecutive items from the input list.\n \"\"\"\n return [(lst[i], lst[i + 1]) for i in range(len(lst) - 1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n # Initialize an empty list to hold the pairs\n pairs = []\n\n # Iterate through the list up to the second last element\n for i in range(len(lst) - 1):\n # Append the pair to the list of pairs\n pairs.append((lst[i], lst[i + 1]))\n\n return pairs", "matching_cluster_idx": 2}, {"solution": "def pair_wise(input_list):\n \"\"\"\n Return a list of all pairs of consecutive items in the given list.\n\n Parameters:\n input_list (list): The list to create pairs from.\n\n Returns:\n list: A list of tuples, each containing a pair of consecutive items.\n \"\"\"\n return [(input_list[i], input_list[i+1]) for i in range(len(input_list)-1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n # Initialize an empty list to hold the pairs\n pairs = []\n # Iterate over the list up to the second-last element\n for i in range(len(lst) - 1):\n # Append the pair (current element, next element) to the pairs list\n pairs.append((lst[i], lst[i + 1]))\n return pairs", "matching_cluster_idx": 2}, {"solution": "def pair_wise(lst):\n \"\"\"\n Returns a list of pairs of consecutive items in the given list.\n\n Args:\n lst (list): A list of items.\n\n Returns:\n list: A list of tuples containing consecutive pairs from the input list.\n \"\"\"\n return [(lst[i], lst[i + 1]) for i in range(len(lst) - 1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n \"\"\"\n Returns a list of all pairs of consecutive items in the given list.\n\n Parameters:\n lst (list): The input list.\n\n Returns:\n list: A list of tuples where each tuple contains a pair of consecutive items from the input list.\n \"\"\"\n return [(lst[i], lst[i+1]) for i in range(len(lst)-1)]", "matching_cluster_idx": 3}, {"solution": "def pair_wise(lst):\n \"\"\"\n This function takes a list as input and returns a list of pairs of consecutive items from the input list.\n\n :param lst: List of elements\n :return: List of tuples representing consecutive pairs\n \"\"\"\n if not lst: # Check if the input list is empty\n return []\n\n pairs = []\n for i in range(len(lst) - 1):\n pairs.append((lst[i], lst[i + 1]))\n\n return pairs", "matching_cluster_idx": 2}]}, "Mbpp/775": {"dps": 88.63999999999999, "dps_norm": 65.71428571428572, "pass@1": 98.0, "profiled": [{"solution": "def odd_position(lst):\n # Loop through the list, checking every other index (0, 2, 4, ...)\n for i in range(1, len(lst), 2):\n if lst[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n # Iterate through the list and check each element at odd indices (1, 3, 5, ...)\n for i in range(1, len(lst), 2):\n if lst[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n \"\"\"\n Checks if every element at odd indices (1, 3, 5, etc.) in the given list is odd.\n\n :param lst: List of integers\n :return: True if every element at odd indices is odd, False otherwise\n \"\"\"\n for i in range(1, len(lst), 2):\n if lst[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n for i in range(1, len(lst), 2):\n if lst[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n # Iterate over the list with step 2 to access odd indices\n for i in range(1, len(lst), 2):\n # Check if the element at the current odd index is odd\n if lst[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n \"\"\"\n Function to check whether every odd index contains an odd number in a given list.\n\n Args:\n lst (list): List of integers to check.\n\n Returns:\n bool: True if every odd index contains an odd number, False otherwise.\n \"\"\"\n for i in range(1, len(lst), 2):\n if lst[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n \"\"\"\n Check if every odd index contains an odd number in the given list.\n\n Args:\n lst (list): The input list of numbers.\n\n Returns:\n bool: True if every odd index contains an odd number, otherwise False.\n \"\"\"\n return all(num % 2 != 0 for idx, num in enumerate(lst) if idx % 2 != 0)", "matching_cluster_idx": 2}, {"solution": "def odd_position(lst):\n for i in range(1, len(lst), 2):\n if lst[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n \"\"\"\n Check whether every odd index contains odd numbers in the given list.\n \"\"\"\n for i in range(1, len(lst), 2):\n if lst[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n \"\"\"\n Check whether every odd index contains odd numbers of a given list.\n \"\"\"\n for i in range(1, len(lst), 2):\n if lst[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n \"\"\"Check whether every odd index contains odd numbers of a given list.\"\"\"\n # Iterate over the list using the range and step size of 2 to check the odd indices (1, 3, 5, ...)\n for i in range(1, len(lst), 2):\n if lst[i] % 2 == 0:\n # If any value at an odd index is even, return False\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n # Loop through the list and check if every element at an odd index is odd\n for i in range(1, len(lst), 2):\n if lst[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n for i in range(1, len(lst), 2): # iterate over odd indices\n if lst[i] % 2 == 0: # check if number at odd index is even\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n \"\"\"\n Check whether every odd index contains an odd number in a given list.\n\n Args:\n lst (list): A list of integers.\n\n Returns:\n bool: True if every odd index contains an odd number, False otherwise.\n \"\"\"\n for i in range(1, len(lst), 2): # start at index 1 and step by 2\n if lst[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n \"\"\"\n Check if every odd index contains an odd number in a given list.\n\n Parameters:\n lst (list): List of integers.\n\n Returns:\n bool: True if every odd index contains an odd number, False otherwise.\n \"\"\"\n for i in range(1, len(lst), 2):\n if lst[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n \"\"\"\n Check whether every odd index contains an odd number in the given list.\n\n Args:\n lst (list): The list of integers to check.\n\n Returns:\n bool: True if every element at an odd index is odd, False otherwise.\n \"\"\"\n return all(x % 2 != 0 for i, x in enumerate(lst) if i % 2 != 0)", "matching_cluster_idx": 2}, {"solution": "def odd_position(numbers):\n \"\"\"\n This function checks whether every odd index contains an odd number in a given list.\n\n Parameters:\n numbers (list of int): The list of numbers to check.\n\n Returns:\n bool: True if every odd index contains an odd number, False otherwise.\n \"\"\"\n # Iterate through the list\n for index, number in enumerate(numbers):\n # Check if index is odd and number is not odd\n if index % 2 == 1 and number % 2 == 0:\n return False\n return True", "matching_cluster_idx": 2}, {"solution": "def odd_position(lst):\n \"\"\"\n Check if every element at an odd index in the list is odd.\n\n Args:\n lst (list): The list of integers.\n\n Returns:\n bool: True if every element at an odd index is odd, False otherwise.\n \"\"\"\n for i in range(1, len(lst), 2):\n if lst[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}, {"solution": "def odd_position(lst):\n \"\"\"\n Checks whether every element at an odd index in the given list is odd.\n\n Parameters:\n lst (list): A list of integers.\n\n Returns:\n bool: True if every element at an odd index is odd, False otherwise.\n \"\"\"\n return all(x % 2 != 0 for i, x in enumerate(lst) if i % 2 != 0)", "matching_cluster_idx": 2}, {"solution": "def odd_position(lst):\n # Loop through the list and check if elements at odd indices are odd\n for i in range(1, len(lst), 2):\n if lst[i] % 2 == 0:\n return False\n return True", "matching_cluster_idx": 4}]}, "Mbpp/777": {"dps": null, "dps_norm": null, "pass@1": 2.0, "profiled": []}, "Mbpp/781": {"dps": 87.8740157480315, "dps_norm": 48.0, "pass@1": 95.0, "profiled": [{"solution": "def count_divisors(n):\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count % 2 == 0", "matching_cluster_idx": 1}, {"solution": "def count_divisors(n):\n \"\"\"\n This function returns True if the count of divisors of n is even, otherwise it returns False.\n \"\"\"\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count % 2 == 0", "matching_cluster_idx": 1}, {"solution": "def count_divisors(n):\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n count += 1\n if i != n // i:\n count += 1\n return count % 2 == 0", "matching_cluster_idx": 3}, {"solution": "def count_divisors(n):\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n count += 1\n if i != n // i:\n count += 1\n return count % 2 == 0", "matching_cluster_idx": 3}, {"solution": "def count_divisors(n):\n \"\"\"\n This function checks if the number of divisors of a given number `n` is even.\n \"\"\"\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n count += 1\n if i != n // i:\n count += 1\n return count % 2 == 0", "matching_cluster_idx": 3}, {"solution": "def count_divisors(n):\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count % 2 == 0", "matching_cluster_idx": 1}, {"solution": "def count_divisors(n):\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count % 2 == 0", "matching_cluster_idx": 1}, {"solution": "def count_divisors(n):\n \"\"\"\n Function to check if the count of divisors of n is even.\n \"\"\"\n count = 0\n for i in range(1, int(n**0.5) + 1):\n if n % i == 0:\n count += 1\n if i != n // i:\n count += 1\n return count % 2 == 0", "matching_cluster_idx": 3}, {"solution": "def count_divisors(n):\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count % 2 == 0", "matching_cluster_idx": 1}, {"solution": "def count_divisors(n):\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count % 2 == 0", "matching_cluster_idx": 1}, {"solution": "def count_divisors(n):\n \"\"\"\n This function returns True if the number of divisors of n is even, else it returns False.\n \"\"\"\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count % 2 == 0", "matching_cluster_idx": 1}, {"solution": "def count_divisors(n):\n \"\"\"\n This function checks whether the count of divisors of a given number `n` is even.\n \"\"\"\n # Find all divisors of `n`\n divisors = [i for i in range(1, n + 1) if n % i == 0]\n # Check if the count of divisors is even\n return len(divisors) % 2 == 0", "matching_cluster_idx": 1}, {"solution": "def count_divisors(n):\n \"\"\"\n Returns True if the number of divisors of n is even, otherwise returns False.\n \"\"\"\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count % 2 == 0", "matching_cluster_idx": 1}, {"solution": "def count_divisors(n):\n \"\"\"\n This function checks whether the count of divisors of a given number `n` is even.\n\n Args:\n n (int): A positive integer.\n\n Returns:\n bool: True if the count of divisors is even, False otherwise.\n \"\"\"\n if n <= 0:\n raise ValueError(\"Input must be a positive integer.\")\n\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count % 2 == 0", "matching_cluster_idx": 1}, {"solution": "def count_divisors(n):\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count % 2 == 0", "matching_cluster_idx": 1}, {"solution": "def count_divisors(n):\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count % 2 == 0", "matching_cluster_idx": 1}, {"solution": "def count_divisors(n):\n \"\"\"\n Function to check whether the count of divisors of n is even.\n\n Args:\n n (int): The number to count divisors for.\n\n Returns:\n bool: True if the count of divisors is even, False otherwise.\n \"\"\"\n # Initialize the count of divisors\n count = 0\n\n # Iterate through possible divisors from 1 to n\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n\n # Check if the count is even\n return count % 2 == 0", "matching_cluster_idx": 1}, {"solution": "def count_divisors(n):\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n return count % 2 == 0", "matching_cluster_idx": 1}, {"solution": "def count_divisors(n):\n \"\"\"\n Function to count the number of divisors of a given number and return whether the count is even.\n\n Args:\n n (int): The number to check.\n\n Returns:\n bool: True if the number of divisors is even, False otherwise.\n \"\"\"\n if n < 1:\n raise ValueError(\"Input must be a positive integer.\")\n\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n\n return count % 2 == 0", "matching_cluster_idx": 1}, {"solution": "def count_divisors(n):\n \"\"\"\n This function takes an integer n and returns True if the number of divisors of n is even, False otherwise.\n \"\"\"\n if n < 1:\n return False # Divisors are not defined for non-positive integers\n\n count = 0\n for i in range(1, n + 1):\n if n % i == 0:\n count += 1\n\n return count % 2 == 0", "matching_cluster_idx": 1}]}, "Mbpp/800": {"dps": 97.83582089552239, "dps_norm": 99.0, "pass@1": 50.0, "profiled": [{"solution": "def remove_all_spaces(s: str) -> str:\n # Using str.replace() to remove all whitespace characters\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string: str) -> str:\n \"\"\"\n This function removes all whitespaces from a given string.\n \"\"\"\n return input_string.replace(' ', '')", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n \"\"\"\n Function to remove all whitespaces from a string.\n \"\"\"\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(s: str) -> str:\n \"\"\"\n Remove all whitespaces from a given string.\n\n Parameters:\n s (str): The input string.\n\n Returns:\n str: The input string with all whitespaces removed.\n \"\"\"\n # Use the replace method to remove all spaces\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(s):\n # Using the replace method to remove all spaces from the string\n return s.replace(' ', '')", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(s):\n \"\"\"\n Remove all whitespaces from a string.\n\n :param s: Input string\n :return: String with all whitespaces removed\n \"\"\"\n return s.replace(\" \", \"\")", "matching_cluster_idx": 3}, {"solution": "def remove_all_spaces(s: str) -> str:\n # Use the replace method to remove all spaces\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(s):\n \"\"\"\n This function removes all whitespaces from a given string.\n\n Args:\n s (str): The input string.\n\n Returns:\n str: The string with all whitespaces removed.\n \"\"\"\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(s):\n # Using the replace method to remove all whitespace characters\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n \"\"\"\n Function to remove all whitespaces from a string.\n \"\"\"\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(s: str) -> str:\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(s: str) -> str:\n \"\"\"\n Remove all whitespace characters from a string.\n\n Parameters:\n s (str): The input string.\n\n Returns:\n str: The string with all whitespace characters removed.\n \"\"\"\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(s):\n \"\"\"\n Remove all whitespaces from a string.\n\n Parameters:\n s (str): The input string containing whitespaces.\n\n Returns:\n str: The string without any whitespaces.\n \"\"\"\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n # Use the replace() method to remove all spaces\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(s: str) -> str:\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(s):\n \"\"\"\n This function removes all whitespaces from the given string.\n\n :param s: Input string\n :return: String with all whitespaces removed\n \"\"\"\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(s: str) -> str:\n \"\"\"\n Remove all whitespaces from a given string.\n\n Args:\n s (str): The input string.\n\n Returns:\n str: The string with all whitespaces removed.\n \"\"\"\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(s):\n return s.replace(' ', '')", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(s: str) -> str:\n \"\"\"\n Removes all whitespaces from the input string.\n \"\"\"\n return s.replace(\" \", \"\")", "matching_cluster_idx": 4}, {"solution": "def remove_all_spaces(input_string):\n # Return the input string with all whitespaces removed\n return input_string.replace(\" \", \"\")", "matching_cluster_idx": 4}]}, "Mbpp/805": {"dps": 95.36082474226804, "dps_norm": 98.0, "pass@1": 100.0, "profiled": [{"solution": "def max_sum_list(lists):\n \"\"\"\n Returns the list in a list of lists whose sum of elements is the highest.\n \"\"\"\n # Check if the input list is empty\n if not lists:\n return []\n\n # Find the list with the maximum sum\n max_list = max(lists, key=sum)\n\n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n # Find the list with the highest sum of elements\n max_sum = -float('inf')\n result = None\n\n for lst in lists:\n current_sum = sum(lst)\n if current_sum > max_sum:\n max_sum = current_sum\n result = lst\n\n return result", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lst_of_lists):\n # Initialize variables to keep track of the list with the maximum sum and its sum\n max_sum = float('-inf')\n max_list = None\n\n # Iterate over each list in the list of lists\n for lst in lst_of_lists:\n # Calculate the sum of the current list\n current_sum = sum(lst)\n\n # Check if the current sum is greater than the maximum sum\n if current_sum > max_sum:\n max_sum = current_sum\n max_list = lst\n\n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(list_of_lists):\n # Check if the input list is empty\n if not list_of_lists:\n return []\n\n # Initialize variables to keep track of the list with the highest sum\n max_sum = float('-inf')\n max_sum_list = []\n\n # Iterate through each list in the list of lists\n for sublist in list_of_lists:\n current_sum = sum(sublist)\n\n # Update the max_sum and max_sum_list if the current list has a higher sum\n if current_sum > max_sum:\n max_sum = current_sum\n max_sum_list = sublist\n\n return max_sum_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lst):\n # Function to calculate the sum of a list\n def sum_of_list(sublist):\n return sum(sublist)\n\n # Initialize variables to track the sublist with the maximum sum\n max_sum = float('-inf')\n max_sum_sublist = None\n\n # Iterate through the list of lists\n for sublist in lst:\n current_sum = sum_of_list(sublist)\n if current_sum > max_sum:\n max_sum = current_sum\n max_sum_sublist = sublist\n\n return max_sum_sublist", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n # Initialize variables to keep track of the list with the maximum sum and the maximum sum found\n max_sum_list = None\n max_sum = float('-inf')\n\n # Iterate through each list in the list of lists\n for lst in lists:\n # Calculate the sum of the current list\n current_sum = sum(lst)\n\n # If the current sum is greater than the maximum sum found so far, update the max_sum and max_sum_list\n if current_sum > max_sum:\n max_sum = current_sum\n max_sum_list = lst\n\n return max_sum_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n # Initialize variables to keep track of the list with the maximum sum and its sum\n max_sum = float('-inf')\n max_list = None\n\n # Iterate through each list in the list of lists\n for lst in lists:\n # Calculate the sum of the current list\n current_sum = sum(lst)\n\n # Check if the current sum is greater than the maximum sum found so far\n if current_sum > max_sum:\n max_sum = current_sum\n max_list = lst\n\n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n # Find the list with the maximum sum of elements\n max_list = max(lists, key=sum)\n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n # Find the list with the highest sum of elements\n max_sum = float('-inf')\n result = None\n for lst in lists:\n current_sum = sum(lst)\n if current_sum > max_sum:\n max_sum = current_sum\n result = lst\n return result", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n # Initialize variables to keep track of the list with the highest sum and its sum\n max_sum = float('-inf')\n max_sum_list = None\n\n # Iterate over each list in the list of lists\n for lst in lists:\n # Calculate the sum of the current list\n current_sum = sum(lst)\n\n # Check if the current sum is greater than the previous max sum\n if current_sum > max_sum:\n max_sum = current_sum\n max_sum_list = lst\n\n return max_sum_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n \"\"\"\n Function to return the list in a list of lists whose sum of elements is the highest.\n \"\"\"\n if not lists:\n return []\n\n max_sum = float('-inf')\n max_list = []\n\n for lst in lists:\n current_sum = sum(lst)\n if current_sum > max_sum:\n max_sum = current_sum\n max_list = lst\n\n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lst_of_lists):\n # Initialize variables\n max_sum = float('-inf')\n max_list = None\n\n # Iterate over each sublist in the list of lists\n for sublist in lst_of_lists:\n # Calculate the sum of the current sublist\n current_sum = sum(sublist)\n\n # Update max_sum and max_list if current_sum is higher\n if current_sum > max_sum:\n max_sum = current_sum\n max_list = sublist\n\n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists_of_lists):\n if not lists_of_lists:\n return []\n\n # Find the list with the maximum sum of elements\n max_sum = float('-inf')\n max_list = None\n\n for lst in lists_of_lists:\n if sum(lst) > max_sum:\n max_sum = sum(lst)\n max_list = lst\n\n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(list_of_lists):\n # Find the list with the maximum sum of its elements\n max_list = max(list_of_lists, key=sum)\n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n # Initialize variables to keep track of the max sum and the corresponding list\n max_sum = float('-inf')\n max_sum_list = None\n\n # Iterate over each list in the list of lists\n for lst in lists:\n # Calculate the sum of the current list\n current_sum = sum(lst)\n\n # If the current sum is greater than the max sum, update the max sum and the corresponding list\n if current_sum > max_sum:\n max_sum = current_sum\n max_sum_list = lst\n\n return max_sum_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(list_of_lists):\n \"\"\"\n Returns the list in a list of lists whose sum of elements is the highest.\n \"\"\"\n max_sum = float('-inf')\n result_list = None\n\n for sub_list in list_of_lists:\n current_sum = sum(sub_list)\n if current_sum > max_sum:\n max_sum = current_sum\n result_list = sub_list\n\n return result_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(list_of_lists):\n \"\"\"\n Returns the list in a list of lists whose sum of elements is the highest.\n\n Parameters:\n list_of_lists (list of lists): A list of lists containing integers.\n\n Returns:\n list: The list with the highest sum of elements.\n \"\"\"\n if not list_of_lists:\n return []\n\n max_sum = float('-inf')\n max_sum_list = None\n\n for lst in list_of_lists:\n current_sum = sum(lst)\n if current_sum > max_sum:\n max_sum = current_sum\n max_sum_list = lst\n\n return max_sum_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists_of_lists):\n max_sum = float('-inf')\n max_list = None\n for lst in lists_of_lists:\n current_sum = sum(lst)\n if current_sum > max_sum:\n max_sum = current_sum\n max_list = lst\n return max_list", "matching_cluster_idx": 4}, {"solution": "def max_sum_list(lists):\n \"\"\"\n Function to return the list in a list of lists whose sum of elements is the highest.\n\n :param lists: List of lists\n :return: List with the highest sum of elements\n \"\"\"\n if not lists:\n return []\n\n max_list = lists[0]\n for lst in lists:\n if sum(lst) > sum(max_list):\n max_list = lst\n\n return max_list", "matching_cluster_idx": 2}, {"solution": "def max_sum_list(lists):\n # Find the list with the maximum sum of elements\n max_list = max(lists, key=lambda x: sum(x))\n return max_list", "matching_cluster_idx": 4}]}, "Mbpp/808": {"dps": 96.53508771929825, "dps_norm": 99.16666666666667, "pass@1": 82.0, "profiled": [{"solution": "def check_K(tuples, k):\n \"\"\"\n Function to check if the given tuples contain the element 'k'.\n\n Args:\n tuples: A tuple of elements.\n k: The element to check for.\n\n Returns:\n bool: True if 'k' is in the tuples, False otherwise.\n \"\"\"\n return k in tuples", "matching_cluster_idx": 5}, {"solution": "def check_K(tup, k):\n return k in tup", "matching_cluster_idx": 5}, {"solution": "def check_K(t, k):\n \"\"\"\n Checks if the tuple `t` contains the value `k`.\n\n Parameters:\n t (tuple): The tuple to search within.\n k (any): The value to search for.\n\n Returns:\n bool: True if `k` is in `t`, False otherwise.\n \"\"\"\n return k in t", "matching_cluster_idx": 5}, {"solution": "def check_K(tuples, k):\n \"\"\"\n Check if the given tuple contains the value k.\n\n Args:\n tuples (tuple): The input tuple to check.\n k (int or any hashable type): The value to check for in the tuple.\n\n Returns:\n bool: True if k is in the tuple, False otherwise.\n \"\"\"\n return k in tuples", "matching_cluster_idx": 4}, {"solution": "def check_K(tuples, k):\n \"\"\"\n Function to check if the given tuple contains the value 'k'.\n\n Args:\n tuples (tuple): The tuple in which to search for the value.\n k (any): The value to search for in the tuple.\n\n Returns:\n bool: True if 'k' is in the tuple, False otherwise.\n \"\"\"\n return k in tuples", "matching_cluster_idx": 5}, {"solution": "def check_K(tuples, k):\n return k in tuples", "matching_cluster_idx": 5}, {"solution": "def check_K(tuples, k):\n \"\"\"\n Check if the given tuple contains the value k.\n\n Parameters:\n tuples (tuple): The tuple to check.\n k: The value to find in the tuple.\n\n Returns:\n bool: True if k is found in the tuple, False otherwise.\n \"\"\"\n return k in tuples", "matching_cluster_idx": 5}, {"solution": "def check_K(tuples, k):\n \"\"\"\n Checks if the given list of tuples contains the value k.\n\n Args:\n tuples (tuple): A tuple containing numbers.\n k (int): The value to check for in the tuple.\n\n Returns:\n bool: True if k is in the tuple, False otherwise.\n \"\"\"\n return k in tuples", "matching_cluster_idx": 5}, {"solution": "def check_K(tuples, k):\n # Check if the given element k is in the tuple\n return k in tuples", "matching_cluster_idx": 5}, {"solution": "def check_K(tuples, k):\n # Check if k is present in the tuple\n return k in tuples", "matching_cluster_idx": 5}, {"solution": "def check_K(tuples, k):\n \"\"\"\n Checks if the given tuple contains the element k.\n\n Args:\n tuples: A tuple of elements to search through.\n k: The element to check for.\n\n Returns:\n bool: True if k is in tuples, False otherwise.\n \"\"\"\n return k in tuples", "matching_cluster_idx": 5}, {"solution": "def check_K(tuples, k):\n return k in tuples", "matching_cluster_idx": 5}, {"solution": "def check_K(tuples, k):\n return k in tuples", "matching_cluster_idx": 5}, {"solution": "def check_K(tuples, k):\n \"\"\"\n This function checks if the given tuple contains the number k or not.\n\n Parameters:\n - tuples: a tuple of integers\n - k: an integer to check for\n\n Returns:\n - True if k is in the tuple, False otherwise\n \"\"\"\n return k in tuples", "matching_cluster_idx": 5}, {"solution": "def check_K(tuples, k):\n \"\"\"\n Checks if the given tuples contain the value k.\n\n Parameters:\n tuples (tuple): A tuple of integers.\n k (int): The value to check for in the tuple.\n\n Returns:\n bool: True if k is in the tuple, False otherwise.\n \"\"\"\n return k in tuples", "matching_cluster_idx": 5}, {"solution": "def check_K(tuples, k):\n return k in tuples", "matching_cluster_idx": 5}, {"solution": "def check_K(tuples, k):\n \"\"\"\n Check if the given tuple contains the value k.\n\n :param tuples: The tuple to check.\n :param k: The value to find.\n :return: True if k is in the tuple, False otherwise.\n \"\"\"\n return k in tuples", "matching_cluster_idx": 5}, {"solution": "def check_K(tupl, k):\n return k in tupl", "matching_cluster_idx": 5}, {"solution": "def check_K(tuples, k):\n \"\"\"\n Checks if the given tuple contains the element k.\n\n :param tuples: A tuple of integers.\n :param k: The integer to check for in the tuple.\n :return: True if k is in the tuple, False otherwise.\n \"\"\"\n return k in tuples", "matching_cluster_idx": 5}, {"solution": "def check_K(tuples, k):\n \"\"\"\n Check if the given tuple contains the element `k`.\n\n Args:\n tuples (tuple): The tuple to search within.\n k: The element to search for.\n\n Returns:\n bool: True if `k` is found in the tuple, False otherwise.\n \"\"\"\n return k in tuples", "matching_cluster_idx": 5}]}}} \ No newline at end of file